ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<util_resolve_sys_link>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    $0x400,%edx
  mov    %r12,%rdi
  call   <readlink@plt>
  test   %eax,%eax
  jle    L19
  cltq
  movb   $0x0,0x10(%rsp,%rax,1)
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rcx
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <udev_log_null@plt>
  mov    $0x0,%ebp
  lea    D28(%rip),%r14
  jmp    L30
L28:
  add    $0x1,%ebp
L30:
  mov    %rbx,%r13
  mov    $0x3,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  add    $0x3,%rbx
  test   %rax,%rax
  je     L28
  mov    %ebp,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D42(%rip),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <udev_log_null@plt>
  test   %ebp,%ebp
  js     L6
  mov    $0x0,%ebx
L79:
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L52
  movb   $0x0,(%rax)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L79
L6:
  mov    %r12,%rdx
  lea    D13(%rip),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <udev_log_null@plt>
  mov    0x8(%rsp),%rbx
  mov    %rbx,%rdx
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  call   <util_strlcat@plt>
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <util_strlcat@plt>
  mov    $0x0,%eax
L71:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L71
L52:
  mov    $0xffffffff,%eax
  jmp    L71
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D42
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string

tool: D10: path link '%s' points to '%s'


tool: D28: ../

tool: D42: base '%s', tail '%s', back %i


tool: D13: after moving back '%s'


tool: D18: /

assistant: ```c
int util_resolve_sys_link(struct udev *udev, char *syspath, size_t size) {
  char link_target[1024];
  int len;
  int i;
  int back;
  len = readlink(syspath, link_target, sizeof(link_target));
  if (len <= 0)
    return -1;
  link_target[len] = '\0';
  udev_log_null(udev, "path link '%s' points to '%s'\n", syspath, link_target);
  for (back = 0; strncmp(&link_target[back * 3], "../", 3) == 0; back++)
    ;
  udev_log_null(udev, "base '%s', tail '%s', back %i\n", syspath, &link_target[back * 3], back);
  for (i = 0; i <= back; i++) {
    char *pos = strrchr(syspath, '/');
    if (pos == NULL)
      return -1;
    pos[0] = '\0';
  }
  udev_log_null(udev, "after moving back '%s'\n", syspath);
  util_strlcat(syspath, "/", size);
  util_strlcat(syspath, &link_target[back * 3], size);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<util_resolve_sys_link>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x400,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <readlink@plt>
  test   %eax,%eax
  jle    L29
  cltq
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rax,1)
  lea    D4(%rip),%rsi
  xor    %eax,%eax
  lea    D25(%rip),%r15
  call   <udev_log_null@plt>
  mov    %rbx,%rax
  xor    %ebx,%ebx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L50:
  add    $0x1,%ebx
L11:
  mov    $0x3,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <strncmp@plt>
  mov    %rax,%r8
  lea    0x3(%r14),%rax
  test   %r8,%r8
  je     L50
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  lea    D14(%rip),%rsi
  xor    %eax,%eax
  add    $0x1,%ebx
  xor    %r15d,%r15d
  call   <udev_log_null@plt>
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L29
  add    $0x1,%r15d
  movb   $0x0,(%rax)
  cmp    %ebx,%r15d
  jne    L41
  mov    %rbp,%rdx
  lea    D27(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <udev_log_null@plt>
  mov    %r13,%rdx
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <util_strlcat@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <util_strlcat@plt>
  xor    %eax,%eax
L37:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  jmp    L37
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D4: path link '%s' points to '%s'


tool: D25: ../

tool: D14: base '%s', tail '%s', back %i


tool: D27: after moving back '%s'


tool: D20: /

assistant: ```c
int util_resolve_sys_link(struct udev *udev, char *syspath, size_t size) {
  char link_target[1024];
  int len;
  int i;
  int back;
  len = readlink(syspath, link_target, sizeof(link_target));
  if (len <= 0)
    return -1;
  link_target[len] = '\0';
  udev_log_null(udev, "path link '%s' points to '%s'\n", syspath, link_target);
  for (back = 0; strncmp(&link_target[back * 3], "../", 3) == 0; back++)
    ;
  udev_log_null(udev, "base '%s', tail '%s', back %i\n", syspath, &link_target[back * 3], back);
  for (i = 0; i <= back; i++) {
    char *pos = strrchr(syspath, '/');
    if (pos == NULL)
      return -1;
    pos[0] = '\0';
  }
  udev_log_null(udev, "after moving back '%s'\n", syspath);
  util_strlcat(syspath, "/", size);
  util_strlcat(syspath, &link_target[back * 3], size);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<util_resolve_sys_link>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  mov    $0x400,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <readlink@plt>
  test   %eax,%eax
  jle    L13
  cltq
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  movb   $0x0,(%rsp,%rax,1)
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  lea    D20(%rip),%r15
  call   <udev_log_null@plt>
  mov    %rbx,%rax
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%ebx
L9:
  mov    $0x3,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <strncmp@plt>
  mov    %rax,%r8
  lea    0x3(%r14),%rax
  test   %r8,%r8
  je     L4
  mov    %ebx,%r8d
  mov    %r14,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rdi
  lea    D30(%rip),%rsi
  xor    %eax,%eax
  add    $0x1,%ebx
  xor    %r15d,%r15d
  call   <udev_log_null@plt>
  nopw   0x0(%rax,%rax,1)
L62:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L13
  add    $0x1,%r15d
  movb   $0x0,(%rax)
  cmp    %ebx,%r15d
  jne    L62
  mov    %rbp,%rdx
  lea    D18(%rip),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <udev_log_null@plt>
  mov    %r13,%rdx
  lea    D42(%rip),%rsi
  mov    %rbp,%rdi
  call   <util_strlcat@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <util_strlcat@plt>
  xor    %eax,%eax
L52:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L13:
  mov    $0xffffffff,%eax
  jmp    L52
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D20
type_infered: string
name: parse_data
arguments: tag: D30
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D42
type_infered: string

tool: D8: path link '%s' points to '%s'


tool: D20: ../

tool: D30: base '%s', tail '%s', back %i


tool: D18: after moving back '%s'


tool: D42: /

assistant: ```c
int util_resolve_sys_link(struct udev *udev, char *syspath, size_t size) {
  char link_target[1024];
  int len;
  int i;
  int back;
  len = readlink(syspath, link_target, sizeof(link_target));
  if (len <= 0)
    return -1;
  link_target[len] = '\0';
  udev_log_null(udev, "path link '%s' points to '%s'\n", syspath, link_target);
  for (back = 0; strncmp(&link_target[back * 3], "../", 3) == 0; back++)
    ;
  udev_log_null(udev, "base '%s', tail '%s', back %i\n", syspath, &link_target[back * 3], back);
  for (i = 0; i <= back; i++) {
    char *pos = strrchr(syspath, '/');
    if (pos == NULL)
      return -1;
    pos[0] = '\0';
  }
  udev_log_null(udev, "after moving back '%s'\n", syspath);
  util_strlcat(syspath, "/", size);
  util_strlcat(syspath, &link_target[back * 3], size);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <topla@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main() {
  int toplam = 0;
  toplam = topla(3, 4);
  printf("%d\n", toplam);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <topla@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main() {
  int toplam = 0;
  toplam = topla(3, 4);
  printf("%d\n", toplam);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <topla@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: %d


assistant: ```c
int main() {
  int toplam = 0;
  toplam = topla(3, 4);
  printf("%d\n", toplam);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <topla@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int toplam = 0;
  toplam = topla(3, 4);
  printf("%d\n", toplam);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_unknown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <hexdump_data@plt>
  nop
  leave
  ret
```

assistant: ```c
void dump_unknown(uint8_t type, const uint8_t *data, size_t n) {
  (void)type;
  hexdump_data(0, data, n, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dump_unknown>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x0,%edi
  call   <hexdump_data@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dump_unknown(uint8_t type, const uint8_t *data, size_t n) {
  (void)type;
  hexdump_data(0, data, n, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dump_unknown>:
  endbr64
  mov    %rdx,%rcx
  xor    %edi,%edi
  jmp    1050 <hexdump_data@plt>
```

assistant: ```c
void dump_unknown(uint8_t type, const uint8_t *data, size_t n) {
  (void)type;
  hexdump_data(0, data, n, n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dump_unknown>:
  endbr64
  mov    %rdx,%rcx
  xor    %edi,%edi
  jmp    1050 <hexdump_data@plt>
```

assistant: ```c
void dump_unknown(uint8_t type, const uint8_t *data, size_t n) {
  (void)type;
  hexdump_data(0, data, n, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_wrap_Swig_free_dbr_f2dad429834b4b9b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Swig_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void _wrap_Swig_free_dbr_f2dad429834b4b9b(void *_swig_go_0) {
  void *arg1 = (void *)0;
  arg1 = *(void **)&_swig_go_0;
  Swig_free(arg1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_wrap_Swig_free_dbr_f2dad429834b4b9b>:
  endbr64
  sub    $0x8,%rsp
  call   <Swig_free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _wrap_Swig_free_dbr_f2dad429834b4b9b(void *_swig_go_0) {
  void *arg1 = (void *)0;
  arg1 = *(void **)&_swig_go_0;
  Swig_free(arg1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_wrap_Swig_free_dbr_f2dad429834b4b9b>:
  endbr64
  jmp    1050 <Swig_free@plt>
```

assistant: ```c
void _wrap_Swig_free_dbr_f2dad429834b4b9b(void *_swig_go_0) {
  void *arg1 = (void *)0;
  arg1 = *(void **)&_swig_go_0;
  Swig_free(arg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_wrap_Swig_free_dbr_f2dad429834b4b9b>:
  endbr64
  jmp    1050 <Swig_free@plt>
```

assistant: ```c
void _wrap_Swig_free_dbr_f2dad429834b4b9b(void *_swig_go_0) {
  void *arg1 = (void *)0;
  arg1 = *(void **)&_swig_go_0;
  Swig_free(arg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<indx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L33
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L39
L33:
  cmpl   $0x0,-0x18(%rbp)
  js     L9
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L31
L9:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   %edx,%eax
  mov    -0x18(%rbp),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int indx(int n, int m) {
  int i;
  if (m == 0) {
    i = (n - 1) * (n + 1) + 1;
    return i - 1;
  }
  if (m >= 0)
    i = (n - 1) * (n + 1) + m * 2;
  else
    i = (n - 1) * (n + 1) - m * 2 + 1;
  return i - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<indx>:
  endbr64
  test   %esi,%esi
  je     L27
  js     L19
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  imul   %edi,%eax
  lea    (%rax,%rsi,2),%eax
L26:
  sub    $0x1,%eax
  ret
L27:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  imul   %edi,%eax
  ret
L19:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  imul   %edi,%eax
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x1,%eax
  jmp    L26
```

assistant: ```c
int indx(int n, int m) {
  int i;
  if (m == 0) {
    i = (n - 1) * (n + 1) + 1;
    return i - 1;
  }
  if (m >= 0)
    i = (n - 1) * (n + 1) + m * 2;
  else
    i = (n - 1) * (n + 1) - m * 2 + 1;
  return i - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<indx>:
  endbr64
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  imul   %edi,%eax
  test   %esi,%esi
  je     L9
  lea    (%rsi,%rsi,1),%edx
  lea    -0x1(%rdx,%rax,1),%ecx
  sub    %edx,%eax
  test   %esi,%esi
  cmovns %ecx,%eax
L9:
  ret
```

assistant: ```c
int indx(int n, int m) {
  int i;
  if (m == 0) {
    i = (n - 1) * (n + 1) + 1;
    return i - 1;
  }
  if (m >= 0)
    i = (n - 1) * (n + 1) + m * 2;
  else
    i = (n - 1) * (n + 1) - m * 2 + 1;
  return i - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<indx>:
  endbr64
  lea    -0x1(%rdi),%eax
  add    $0x1,%edi
  imul   %edi,%eax
  test   %esi,%esi
  je     L8
  lea    (%rsi,%rsi,1),%edx
  lea    -0x1(%rdx,%rax,1),%ecx
  sub    %edx,%eax
  test   %esi,%esi
  cmovns %ecx,%eax
L8:
  ret
```

assistant: ```c
int indx(int n, int m) {
  int i;
  if (m == 0) {
    i = (n - 1) * (n + 1) + 1;
    return i - 1;
  }
  if (m >= 0)
    i = (n - 1) * (n + 1) + m * 2;
  else
    i = (n - 1) * (n + 1) - m * 2 + 1;
  return i - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<update_accept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  ja     L3
  jmp    L16
L3:
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x3,-0x10(%rbp)
L16:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_accept(design, iteration, accept_flag, column, update, step_eval, best_eval, current_eval) struct Design *design;
int iteration, accept_flag, *column, *update;
double *step_eval, *best_eval, current_eval;
{
  void write_step();
  if (accept_flag == 2) {
  }
  if (*step_eval < *best_eval) {
    *best_eval = *step_eval;
    accept_flag = 3;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<update_accept>:
  endbr64
  mov    0x8(%rsp),%rax
  movsd  (%r9),%xmm0
  movsd  (%rax),%xmm1
  comisd %xmm0,%xmm1
  jbe    L1
  movsd  %xmm0,(%rax)
L1:
  ret
```

assistant: ```c
void update_accept(design, iteration, accept_flag, column, update, step_eval, best_eval, current_eval) struct Design *design;
int iteration, accept_flag, *column, *update;
double *step_eval, *best_eval, current_eval;
{
  void write_step();
  if (accept_flag == 2) {
  }
  if (*step_eval < *best_eval) {
    *best_eval = *step_eval;
    accept_flag = 3;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<update_accept>:
  endbr64
  mov    0x8(%rsp),%rax
  movsd  (%r9),%xmm0
  movsd  (%rax),%xmm1
  comisd %xmm0,%xmm1
  jbe    L4
  movsd  %xmm0,(%rax)
L4:
  ret
```

assistant: ```c
void update_accept(design, iteration, accept_flag, column, update, step_eval, best_eval, current_eval) struct Design *design;
int iteration, accept_flag, *column, *update;
double *step_eval, *best_eval, current_eval;
{
  void write_step();
  if (accept_flag == 2) {
  }
  if (*step_eval < *best_eval) {
    *best_eval = *step_eval;
    accept_flag = 3;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<update_accept>:
  endbr64
  mov    0x8(%rsp),%rax
  movsd  (%r9),%xmm0
  movsd  (%rax),%xmm1
  comisd %xmm0,%xmm1
  jbe    L1
  movsd  %xmm0,(%rax)
L1:
  ret
```

assistant: ```c
void update_accept(design, iteration, accept_flag, column, update, step_eval, best_eval, current_eval) struct Design *design;
int iteration, accept_flag, *column, *update;
double *step_eval, *best_eval, current_eval;
{
  void write_step();
  if (accept_flag == 2) {
  }
  if (*step_eval < *best_eval) {
    *best_eval = *step_eval;
    accept_flag = 3;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_vsofont_billboard_spherical_cheat_apply>:
  endbr64
  push   %rbp
  sub    $0x60,%rsp
  movss  %xmm0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm2,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  movss  0x4(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  call   <glTranslatef@plt>
  mov    D6(%rip),%rax
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <glGetFloatv@plt>
  mov    %rbp,%rdi
  movabs $0x3f80000000000000,%rax
  movq   $0x3f800000,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movl   $0x3f800000,0x38(%rsp)
  call   <glLoadMatrixf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x60,%rsp
  mov    $0x1,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _vsofont_billboard_spherical_cheat_apply(float x, float y, float z) {
  GLfloat m[4 * 4];
  int i;
  glPushMatrix();
  glTranslatef(x, y, z);
  glGetFloatv(GL_MODELVIEW_MATRIX, m);
  i = 0;
  m[i++] = 1.0f;
  m[i++] = 0.0f;
  m[i++] = 0.0f;
  i++;
  m[i++] = 0.0f;
  m[i++] = 1.0f;
  m[i++] = 0.0f;
  i++;
  m[i++] = 0.0f;
  m[i++] = 0.0f;
  m[i] = 1.0f;
  glLoadMatrixf(m);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<zwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L113:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L85
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L115
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L15
  movl   $0x1,-0x20(%rbp)
  jmp    L63
L85:
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L113
L115:
  nop
  jmp    L113
L14:
  nop
  jmp    L113
L15:
  nop
L63:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x38(%rbp)
  jbe    L5
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  sub    %rdx,%rax
  jmp    L77
L5:
  cmpl   $0x0,-0x20(%rbp)
  je     L112
  mov    $0x0,%eax
  jmp    L77
L112:
  mov    $0xffffffffffffffff,%rax
L77:
  leave
  ret
```

assistant: ```c
ssize_t zwrite(int fd, const void *buf, size_t count) {
  ssize_t ret;
  int ec, is_closed = 0;
  const char *ptr = (const char *)buf;
  long left = count;
  for (;;) {
    ret = write(fd, ptr, left);
    if (ret < 0) {
      ec = errno;
      if (ec == EINTR) {
        continue;
      }
      if (ec == EPIPE) {
        is_closed = 1;
        break;
      }
      break;
    } else if (ret == 0) {
      continue;
    } else {
      left -= ret;
      ptr += ret;
    }
  }
  if (count > left) {
    return count - left;
  }
  if (is_closed) {
    return 0;
  }
  return -1;
}
```