ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mktime>:
  endbr64
  mov    %edx,%r10d
  lea    -0x2(%rsi),%edx
  test   %edx,%edx
  jg     L5
  lea    0xa(%rsi),%edx
  sub    $0x1,%edi
L5:
  mov    %edi,%esi
  mov    %edi,%eax
  mov    %ecx,%ecx
  mov    %r8d,%r8d
  imul   $0x51eb851f,%rsi,%rsi
  shr    $0x2,%eax
  mov    %r9d,%r9d
  imul   $0x16f,%edx,%edx
  imul   $0x16d,%edi,%edi
  mov    %rsi,%r11
  shr    $0x25,%rsi
  shr    $0x27,%r11
  add    %r11d,%eax
  add    %r10d,%eax
  mov    $0xaaaaaaab,%r10d
  imul   %r10,%rdx
  shr    $0x23,%rdx
  add    %edx,%eax
  sub    %esi,%eax
  add    %rdi,%rax
  lea    (%rax,%rax,2),%rax
  lea    (%rcx,%rax,8),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    (%r8,%rax,4),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  movabs $0xfffffff186b1bf80,%rdx
  add    %rdx,%r9
  lea    (%r9,%rax,4),%rax
  ret
```

assistant: ```c
unsigned long mktime(unsigned int year, unsigned int mon, unsigned int day, unsigned int hour, unsigned int min, unsigned int sec) {
  if (0 >= (int)(mon -= 2)) {
    mon += 12;
    year -= 1;
  }
  return ((((unsigned long)(year / 4 - year / 100 + year / 400 + 367 * mon / 12 + day) + year * 365 - 719499) * 24 + hour) * 60 + min) * 60 + sec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mktime>:
  endbr64
  mov    %edx,%r10d
  lea    -0x2(%rsi),%edx
  test   %edx,%edx
  jg     L9
  lea    0xa(%rsi),%edx
  sub    $0x1,%edi
L9:
  mov    %edi,%esi
  mov    %edi,%eax
  mov    %ecx,%ecx
  mov    %r8d,%r8d
  imul   $0x51eb851f,%rsi,%rsi
  shr    $0x2,%eax
  mov    %r9d,%r9d
  imul   $0x16f,%edx,%edx
  imul   $0x16d,%edi,%edi
  mov    %rsi,%r11
  shr    $0x25,%rsi
  shr    $0x27,%r11
  add    %r11d,%eax
  add    %r10d,%eax
  mov    $0xaaaaaaab,%r10d
  imul   %r10,%rdx
  shr    $0x23,%rdx
  add    %edx,%eax
  sub    %esi,%eax
  add    %rdi,%rax
  lea    (%rax,%rax,2),%rax
  lea    (%rcx,%rax,8),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    (%r8,%rax,4),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  movabs $0xfffffff186b1bf80,%rdx
  add    %rdx,%r9
  lea    (%r9,%rax,4),%rax
  ret
```

assistant: ```c
unsigned long mktime(unsigned int year, unsigned int mon, unsigned int day, unsigned int hour, unsigned int min, unsigned int sec) {
  if (0 >= (int)(mon -= 2)) {
    mon += 12;
    year -= 1;
  }
  return ((((unsigned long)(year / 4 - year / 100 + year / 400 + 367 * mon / 12 + day) + year * 365 - 719499) * 24 + hour) * 60 + min) * 60 + sec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage_and_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: %s: %s [01]  (0 = no locks, 1 = locks)


assistant: ```c
void usage_and_exit(char *s) {
  printf("%s: %s [01]  (0 = no locks, 1 = locks)\n", s, s);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %s: %s [01]  (0 = no locks, 1 = locks)


assistant: ```c
void usage_and_exit(char *s) {
  printf("%s: %s [01]  (0 = no locks, 1 = locks)\n", s, s);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %s: %s [01]  (0 = no locks, 1 = locks)


assistant: ```c
void usage_and_exit(char *s) {
  printf("%s: %s [01]  (0 = no locks, 1 = locks)\n", s, s);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage_and_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: %s: %s [01]  (0 = no locks, 1 = locks)


assistant: ```c
void usage_and_exit(char *s) {
  printf("%s: %s [01]  (0 = no locks, 1 = locks)\n", s, s);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpb   $0x4f,-0x1c(%rbp)
  jne    L47
  mov    $0x40,%eax
  jmp    L18
L47:
  mov    $0x4f,%eax
L18:
  mov    %al,-0xd(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L56
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L49
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    %al,-0xd(%rbp)
  sete   %al
  movzbl %al,%eax
  sub    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    %al,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L49:
  cmpl   $0x5,-0x4(%rbp)
  jle    L44
  addl   $0x1,-0x8(%rbp)
L56:
  cmpl   $0x5,-0x8(%rbp)
  jle    L2
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_score(char board[][6], char player) {
  int score = 0;
  int row = 0;
  int col = 0;
  char opponent = player == 'O' ? '@' : 'O';
  for (row = 0; row < 6; row++)
    for (col = 0; col < 6; col++) {
      score -= board[row][col] == opponent;
      score += board[row][col] == player;
    }
  return score;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_score>:
  endbr64
  mov    %esi,%r10d
  cmp    $0x4f,%sil
  mov    $0x40,%r9d
  mov    $0x4f,%eax
  cmovne %eax,%r9d
  lea    0x6(%rdi),%r8
  add    $0x2a,%rdi
  mov    $0x0,%eax
L19:
  lea    -0x6(%r8),%rdx
L5:
  movzbl (%rdx),%ecx
  cmp    %r9b,%cl
  sete   %sil
  movzbl %sil,%esi
  sub    %esi,%eax
  cmp    %r10b,%cl
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L5
  add    $0x6,%r8
  cmp    %rdi,%r8
  jne    L19
  ret
```

assistant: ```c
int get_score(char board[][6], char player) {
  int score = 0;
  int row = 0;
  int col = 0;
  char opponent = player == 'O' ? '@' : 'O';
  for (row = 0; row < 6; row++)
    for (col = 0; col < 6; col++) {
      score -= board[row][col] == opponent;
      score += board[row][col] == player;
    }
  return score;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_score>:
  endbr64
  cmp    $0x4f,%sil
  mov    $0x4f,%eax
  lea    0x6(%rdi),%r8
  mov    %esi,%r10d
  mov    $0x40,%r9d
  cmovne %eax,%r9d
  add    $0x2a,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  lea    -0x6(%r8),%rdx
  nopl   0x0(%rax)
L3:
  movzbl (%rdx),%ecx
  xor    %esi,%esi
  cmp    %r9b,%cl
  sete   %sil
  sub    %esi,%eax
  cmp    %r10b,%cl
  sete   %cl
  add    $0x1,%rdx
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    %rdx,%r8
  jne    L3
  add    $0x6,%r8
  cmp    %r8,%rdi
  jne    L9
  ret
```

assistant: ```c
int get_score(char board[][6], char player) {
  int score = 0;
  int row = 0;
  int col = 0;
  char opponent = player == 'O' ? '@' : 'O';
  for (row = 0; row < 6; row++)
    for (col = 0; col < 6; col++) {
      score -= board[row][col] == opponent;
      score += board[row][col] == player;
    }
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<event_get_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: 4.1

assistant: ```c
const char *event_get_version(void) {
  return "4"
         "."
         "1";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<event_get_version>:
  endbr64
  lea    D9(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: 4.1

assistant: ```c
const char *event_get_version(void) {
  return "4"
         "."
         "1";
}
```
user: What is the c source code of the assembly code below:

```asm
<event_get_version>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: 4.1

assistant: ```c
const char *event_get_version(void) {
  return "4"
         "."
         "1";
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<event_get_version>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: 4.1

assistant: ```c
const char *event_get_version(void) {
  return "4"
         "."
         "1";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tag_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L41
  movb   $0x58,-0x1(%rbp)
  jmp    L75
L41:
  mov    -0x18(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L21
  movb   $0x43,-0x1(%rbp)
  jmp    L75
L21:
  mov    -0x18(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L58
  movb   $0x41,-0x1(%rbp)
  jmp    L75
L58:
  mov    -0x18(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L86
  movb   $0x42,-0x1(%rbp)
  jmp    L75
L86:
  mov    -0x18(%rbp),%eax
  and    $0x2000,%eax
  test   %eax,%eax
  je     L74
  movb   $0x50,-0x1(%rbp)
  jmp    L75
L74:
  movb   $0x44,-0x1(%rbp)
L75:
  movsbl -0x1(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D7(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type: string

tool: D27: _%c%03d

assistant: ```c
char *tag_string(int tag, int type) {
  static char str[16];
  char t;
  if (type & (1 << 7))
    t = 'X';
  else if (type & (1 << 4))
    t = 'C';
  else if (type & (1 << 3))
    t = 'A';
  else if (type & (1 << 5))
    t = 'B';
  else if (type & (1 << 13))
    t = 'P';
  else
    t = 'D';
  sprintf(str, "_%c%03d", t, tag);
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tag_string>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  mov    $0x58,%edx
  test   $0x80,%sil
  jne    L30
  mov    $0x43,%edx
  test   $0x10,%sil
  jne    L30
  mov    $0x41,%edx
  test   $0x8,%sil
  jne    L30
  mov    $0x42,%edx
  test   $0x20,%sil
  jne    L30
  and    $0x2000,%esi
  cmp    $0x1,%esi
  sbb    %edx,%edx
  and    $0xfffffff4,%edx
  add    $0x50,%edx
L30:
  movsbl %dl,%edx
  lea    D18(%rip),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D18: _%c%03d

assistant: ```c
char *tag_string(int tag, int type) {
  static char str[16];
  char t;
  if (type & (1 << 7))
    t = 'X';
  else if (type & (1 << 4))
    t = 'C';
  else if (type & (1 << 3))
    t = 'A';
  else if (type & (1 << 5))
    t = 'B';
  else if (type & (1 << 13))
    t = 'P';
  else
    t = 'D';
  sprintf(str, "_%c%03d", t, tag);
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tag_string>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    $0x58,%edx
  test   $0x80,%sil
  jne    L6
  mov    $0x43,%edx
  test   $0x10,%sil
  je     L28
L6:
  lea    D19(%rip),%r12
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x41,%edx
  test   $0x8,%sil
  jne    L6
  mov    $0x42,%edx
  test   $0x20,%sil
  jne    L6
  and    $0x2000,%esi
  cmp    $0x1,%esi
  sbb    %edx,%edx
  and    $0xfffffff4,%edx
  add    $0x50,%edx
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: _%c%03d

assistant: ```c
char *tag_string(int tag, int type) {
  static char str[16];
  char t;
  if (type & (1 << 7))
    t = 'X';
  else if (type & (1 << 4))
    t = 'C';
  else if (type & (1 << 3))
    t = 'A';
  else if (type & (1 << 5))
    t = 'B';
  else if (type & (1 << 13))
    t = 'P';
  else
    t = 'D';
  sprintf(str, "_%c%03d", t, tag);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tag_string>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    $0x58,%edx
  test   $0x80,%sil
  jne    L14
  mov    $0x43,%edx
  test   $0x10,%sil
  je     L17
L14:
  lea    D9(%rip),%r12
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x41,%edx
  test   $0x8,%sil
  jne    L14
  mov    $0x42,%edx
  test   $0x20,%sil
  jne    L14
  and    $0x2000,%esi
  cmp    $0x1,%esi
  sbb    %edx,%edx
  and    $0xfffffff4,%edx
  add    $0x50,%edx
  jmp    L14
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string

tool: D16: _%c%03d

assistant: ```c
char *tag_string(int tag, int type) {
  static char str[16];
  char t;
  if (type & (1 << 7))
    t = 'X';
  else if (type & (1 << 4))
    t = 'C';
  else if (type & (1 << 3))
    t = 'A';
  else if (type & (1 << 5))
    t = 'B';
  else if (type & (1 << 13))
    t = 'P';
  else
    t = 'D';
  sprintf(str, "_%c%03d", t, tag);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fp_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x30(%rbp)
  movsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <int_to_str@plt>
  mov    %rax,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x38(%rbp),%xmm0
  jbe    L5
  movsd  -0x38(%rbp),%xmm0
  movq   D21(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
L5:
  movsd  -0x38(%rbp),%xmm1
  movsd  D25(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x38(%rbp),%xmm1
  cvttsd2si %xmm1,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D32(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <int_to_str@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  cltq
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L14
  addq   $0x1,-0x30(%rbp)
L14:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L10
  mov    -0x28(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L10:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D25
datatype: f64
name: retrieve_data
arguments: data_tag: D32
datatype: f64
name: retrieve_data
arguments: data_tag: D46
datatype: string
name: retrieve_data
arguments: data_tag: D36
datatype: string

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D25: 0.005

tool: D32: 100

tool: D46: .

tool: D36: 0

assistant: ```c
char *fp_to_str(double x) {
  char *str = NULL;
  char *integral = NULL;
  char *fraction = NULL;
  size_t length = 0;
  integral = int_to_str((int)x);
  if (x < 0)
    x = -x;
  fraction = int_to_str((int)(100.0 * (x + 0.005 - (int)x)));
  length = strlen(integral) + strlen(fraction) + 2;
  if (strlen(fraction) < 2)
    ++length;
  str = (char *)malloc(length);
  strcpy(str, integral);
  strcat(str, ".");
  if (strlen(fraction) < 2)
    strcat(str, "0");
  strcat(str, fraction);
  free(integral);
  free(fraction);
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fp_to_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  cvttsd2si %xmm0,%edi
  call   <int_to_str@plt>
  mov    %rax,%r12
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  comisd %xmm2,%xmm0
  ja     L1
L11:
  movsd  0x8(%rsp),%xmm3
  movapd %xmm3,%xmm0
  addsd  D33(%rip),%xmm0
  cvttsd2si %xmm3,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D42(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <int_to_str@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%ebp
  movslq %ebp,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  add    %rax,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L21
L34:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  xorpd  D35(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  jmp    L11
L21:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_label: D33
type: f64
name: unpack_data
arguments: data_label: D42
type: f64
name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D35
type: byte[16]
name: unpack_data
arguments: data_label: D3
type: string

tool: D33: 0.005

tool: D42: 100

tool: D11: .

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D3: 0

assistant: ```c
char *fp_to_str(double x) {
  char *str = NULL;
  char *integral = NULL;
  char *fraction = NULL;
  size_t length = 0;
  integral = int_to_str((int)x);
  if (x < 0)
    x = -x;
  fraction = int_to_str((int)(100.0 * (x + 0.005 - (int)x)));
  length = strlen(integral) + strlen(fraction) + 2;
  if (strlen(fraction) < 2)
    ++length;
  str = (char *)malloc(length);
  strcpy(str, integral);
  strcat(str, ".");
  if (strlen(fraction) < 2)
    strcat(str, "0");
  strcat(str, fraction);
  free(integral);
  free(fraction);
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<fp_to_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  cvttsd2si %xmm0,%ebp
  sub    $0x10,%rsp
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <int_to_str@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    %rax,%r13
  comisd %xmm0,%xmm1
  jbe    L12
  xorpd  D33(%rip),%xmm0
  cvttsd2si %xmm0,%ebp
L12:
  pxor   %xmm1,%xmm1
  addsd  D17(%rip),%xmm0
  cvtsi2sd %ebp,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D43(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <int_to_str@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x2(%r12,%rax,1),%r12d
  call   <strlen@plt>
  movslq %r12d,%r12
  cmp    $0x1,%eax
  setle  %al
  movzbl %al,%eax
  add    %rax,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D11(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L0
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L0:
  lea    D47(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D17
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D43
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D47
type_infered: string

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D17: 0.005

tool: D43: 100

tool: D11: .

tool: D47: 0

assistant: ```c
char *fp_to_str(double x) {
  char *str = NULL;
  char *integral = NULL;
  char *fraction = NULL;
  size_t length = 0;
  integral = int_to_str((int)x);
  if (x < 0)
    x = -x;
  fraction = int_to_str((int)(100.0 * (x + 0.005 - (int)x)));
  length = strlen(integral) + strlen(fraction) + 2;
  if (strlen(fraction) < 2)
    ++length;
  str = (char *)malloc(length);
  strcpy(str, integral);
  strcat(str, ".");
  if (strlen(fraction) < 2)
    strcat(str, "0");
  strcat(str, fraction);
  free(integral);
  free(fraction);
  return str;
}
```