ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <occurrences@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jg     L42
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L14
L42:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  imul   -0x34(%rbp),%eax
  sub    %eax,%ebx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  imul   -0x34(%rbp),%eax
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L14
L31:
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L3
L11:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x58(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
L3:
  mov    -0x50(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  je     L62
  mov    -0x48(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
L62:
  mov    -0x20(%rbp),%rax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *str_replace(const char *str, const char *sub, const char *replace) {
  char *pos = (char *)str;
  int count = occurrences(sub, str);
  if (0 >= count)
    return strdup(str);
  int size = (strlen(str) - (strlen(sub) * count) + strlen(replace) * count) + 1;
  char *result = (char *)malloc(size);
  if (NULL == result)
    return NULL;
  memset(result, '\0', size);
  char *current;
  while ((current = strstr(pos, sub))) {
    int len = current - pos;
    strncat(result, pos, len);
    strncat(result, replace, strlen(replace));
    pos = current + strlen(sub);
  }
  if (pos != (str + strlen(str))) {
    strncat(result, pos, (str - pos));
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <occurrences@plt>
  test   %eax,%eax
  jle    L10
  mov    %eax,%ebx
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  imul   %ebx,%eax
  sub    %eax,%ebp
  mov    %r13,%rdi
  call   <strlen@plt>
  imul   %ebx,%eax
  lea    0x1(%rbp,%rax,1),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r14d
  test   %rax,%rax
  je     L50
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r15,%rbx
  jmp    L55
L10:
  mov    %r15,%rdi
  call   <strdup@plt>
  mov    %rax,%r14
  jmp    L50
L11:
  mov    %ebp,%edx
  sub    %ebx,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strncat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strncat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
L55:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L11
  mov    %r15,%rdi
  call   <strlen@plt>
  cltq
  add    %r15,%rax
  cmp    %rax,%rbx
  je     L50
  mov    %r15d,%edx
  sub    %ebx,%edx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <strncat@plt>
L50:
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *str_replace(const char *str, const char *sub, const char *replace) {
  char *pos = (char *)str;
  int count = occurrences(sub, str);
  if (0 >= count)
    return strdup(str);
  int size = (strlen(str) - (strlen(sub) * count) + strlen(replace) * count) + 1;
  char *result = (char *)malloc(size);
  if (NULL == result)
    return NULL;
  memset(result, '\0', size);
  char *current;
  while ((current = strstr(pos, sub))) {
    int len = current - pos;
    strncat(result, pos, len);
    strncat(result, replace, strlen(replace));
    pos = current + strlen(sub);
  }
  if (pos != (str + strlen(str))) {
    strncat(result, pos, (str - pos));
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  call   <occurrences@plt>
  test   %eax,%eax
  jle    L21
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r13,%rdi
  imul   %ebp,%eax
  sub    %eax,%r12d
  call   <strlen@plt>
  imul   %ebp,%eax
  lea    0x1(%r12,%rax,1),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  movq   $0x0,0x8(%rsp)
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <memset@plt>
  mov    %r14,%rbp
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  call   <strncat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  add    %r15,%rbp
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L43
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  add    %r14,%rax
  cmp    %rax,%rbp
  je     L11
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  call   <strncat@plt>
L11:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1100 <strdup@plt>
```

assistant: ```c
char *str_replace(const char *str, const char *sub, const char *replace) {
  char *pos = (char *)str;
  int count = occurrences(sub, str);
  if (0 >= count)
    return strdup(str);
  int size = (strlen(str) - (strlen(sub) * count) + strlen(replace) * count) + 1;
  char *result = (char *)malloc(size);
  if (NULL == result)
    return NULL;
  memset(result, '\0', size);
  char *current;
  while ((current = strstr(pos, sub))) {
    int len = current - pos;
    strncat(result, pos, len);
    strncat(result, replace, strlen(replace));
    pos = current + strlen(sub);
  }
  if (pos != (str + strlen(str))) {
    strncat(result, pos, (str - pos));
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  call   <occurrences@plt>
  test   %eax,%eax
  jle    L8
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r13,%rdi
  imul   %ebp,%eax
  sub    %eax,%r12d
  call   <strlen@plt>
  imul   %ebp,%eax
  lea    0x1(%r12,%rax,1),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  movq   $0x0,0x8(%rsp)
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <memset@plt>
  mov    %r14,%rbp
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  call   <strncat@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  add    %r15,%rbp
L22:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L20
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  add    %r14,%rax
  cmp    %rax,%rbp
  je     L16
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    %ebp,%edx
  call   <strncat@plt>
L16:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1100 <strdup@plt>
```

assistant: ```c
char *str_replace(const char *str, const char *sub, const char *replace) {
  char *pos = (char *)str;
  int count = occurrences(sub, str);
  if (0 >= count)
    return strdup(str);
  int size = (strlen(str) - (strlen(sub) * count) + strlen(replace) * count) + 1;
  char *result = (char *)malloc(size);
  if (NULL == result)
    return NULL;
  memset(result, '\0', size);
  char *current;
  while ((current = strstr(pos, sub))) {
    int len = current - pos;
    strncat(result, pos, len);
    strncat(result, replace, strlen(replace));
    pos = current + strlen(sub);
  }
  if (pos != (str + strlen(str))) {
    strncat(result, pos, (str - pos));
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dgettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *dgettext(const char *domainname, const char *msgid) {
  (void)domainname;
  return (char *)msgid;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dgettext>:
  endbr64
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *dgettext(const char *domainname, const char *msgid) {
  (void)domainname;
  return (char *)msgid;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dgettext>:
  endbr64
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *dgettext(const char *domainname, const char *msgid) {
  (void)domainname;
  return (char *)msgid;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dgettext>:
  endbr64
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *dgettext(const char *domainname, const char *msgid) {
  (void)domainname;
  return (char *)msgid;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1505,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L10:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  xor    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L10
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x20(%rbp)
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t hash1(char *key, size_t num, size_t last) {
  size_t hashVal = 5381 + last;
  int c;
  while ((c = *key++) != '\0')
    hashVal = ((hashVal << 5) + hashVal) ^ c;
  return hashVal % num;
}
```
user: What is the c source code of the assembly code below?

```asm
<hash1>:
  endbr64
  lea    0x1505(%rdx),%rax
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L10
L6:
  mov    %rax,%rdi
  shl    $0x5,%rdi
  add    %rdi,%rax
  movsbq %dl,%rdx
  xor    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L6
L10:
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
```

assistant: ```c
size_t hash1(char *key, size_t num, size_t last) {
  size_t hashVal = 5381 + last;
  int c;
  while ((c = *key++) != '\0')
    hashVal = ((hashVal << 5) + hashVal) ^ c;
  return hashVal % num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash1>:
  endbr64
  lea    0x1505(%rdx),%rax
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L0
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  xor    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L8
L0:
  xor    %edx,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
```

assistant: ```c
size_t hash1(char *key, size_t num, size_t last) {
  size_t hashVal = 5381 + last;
  int c;
  while ((c = *key++) != '\0')
    hashVal = ((hashVal << 5) + hashVal) ^ c;
  return hashVal % num;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash1>:
  endbr64
  lea    0x1505(%rdx),%rax
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L10
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rax,%rdi
  add    $0x1,%rcx
  shl    $0x5,%rdi
  add    %rdi,%rax
  xor    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L8
L10:
  xor    %edx,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
```

assistant: ```c
size_t hash1(char *key, size_t num, size_t last) {
  size_t hashVal = 5381 + last;
  int c;
  while ((c = *key++) != '\0')
    hashVal = ((hashVal << 5) + hashVal) ^ c;
  return hashVal % num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D40(%rip),%rdx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <make_message@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: string
name: unpack_data
arguments: data_tag: D40
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D30
type_infered: string
name: unpack_data
arguments: data_tag: D52
type_infered: string
name: unpack_data
arguments: data_tag: D56
type_infered: string

tool: D17: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

tool: D40: %s %s

tool: D43: buf = %s


tool: D30: hello world

tool: D52: %s

tool: D56: s = %s


assistant: ```c
int main() {
  char buf[10];
  char *p = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  memset(buf, 0x11, sizeof(buf));
  snprintf(buf, sizeof(buf), "%s %s", p, p);
  printf("buf = %s\n", buf);
  printf("hello world\n");
  char *s = make_message("%s", p);
  printf("s = %s\n", s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    $0xa,%edx
  mov    $0x11,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    D22(%rip),%r8
  mov    %r8,%rbp
  mov    %r8,%rcx
  lea    D41(%rip),%rdx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  call   <make_message@plt>
  mov    %rax,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D35
type_infered: string
name: retrieve_data
arguments: data_tag: D39
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D22: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

tool: D41: %s %s

tool: D28: buf = %s


tool: D35: hello world

tool: D39: %s

tool: D11: s = %s


assistant: ```c
int main() {
  char buf[10];
  char *p = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  memset(buf, 0x11, sizeof(buf));
  snprintf(buf, sizeof(buf), "%s %s", p, p);
  printf("buf = %s\n", buf);
  printf("hello world\n");
  char *s = make_message("%s", p);
  printf("s = %s\n", s);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  mov    $0x11,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D51(%rip),%r8
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    %r8,%rcx
  lea    D46(%rip),%rdx
  mov    %r8,%r12
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <make_message@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D51
type_infered: string
name: unpack_data
arguments: tag: D46
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D7
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D51: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

tool: D46: %s %s

tool: D12: buf = %s


tool: D10: hello world

tool: D7: %s

tool: D3: s = %s


assistant: ```c
int main() {
  char buf[10];
  char *p = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  memset(buf, 0x11, sizeof(buf));
  snprintf(buf, sizeof(buf), "%s %s", p, p);
  printf("buf = %s\n", buf);
  printf("hello world\n");
  char *s = make_message("%s", p);
  printf("s = %s\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  mov    $0x11,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D57(%rip),%r8
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    %r8,%rcx
  lea    D18(%rip),%rdx
  mov    %r8,%r12
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  lea    D47(%rip),%rdi
  call   <make_message@plt>
  lea    D49(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D57
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D47
datatype: string
name: parse_data
arguments: data_tag: D49
datatype: string

tool: D57: XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

tool: D18: %s %s

tool: D12: buf = %s


tool: D7: hello world

tool: D47: %s

tool: D49: s = %s


assistant: ```c
int main() {
  char buf[10];
  char *p = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  memset(buf, 0x11, sizeof(buf));
  snprintf(buf, sizeof(buf), "%s %s", p, p);
  printf("buf = %s\n", buf);
  printf("hello world\n");
  char *s = make_message("%s", p);
  printf("s = %s\n", s);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gator_annotate_visual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  shl    $0x10,%eax
  or     $0x11c,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x20,%rax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <kannotate_write@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <kannotate_write@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <kannotate_write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void gator_annotate_visual(char *data, unsigned int length, char *string) {
  long long visual_annotation = 0x011c | (strlen(string) << 16) | ((long long)length << 32);
  kannotate_write((char *)&visual_annotation, 8);
  kannotate_write(string, strlen(string));
  kannotate_write(data, length);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gator_annotate_visual>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rdi
  call   <strlen@plt>
  shl    $0x10,%eax
  or     $0x11c,%eax
  mov    %rbp,%rdx
  shl    $0x20,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <kannotate_write@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <kannotate_write@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <kannotate_write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gator_annotate_visual(char *data, unsigned int length, char *string) {
  long long visual_annotation = 0x011c | (strlen(string) << 16) | ((long long)length << 32);
  kannotate_write((char *)&visual_annotation, 8);
  kannotate_write(string, strlen(string));
  kannotate_write(data, length);
}
```