ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_ltrim>:
  endbr64
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L173
  cmpb   $0x20,(%rdi)
  jne    L177
  mov    $0x1,%eax
L109:
  mov    %eax,%ecx
  add    $0x1,%rax
  cmpb   $0x20,-0x1(%rdx,%rax,1)
  je     L109
  mov    %esi,%r8d
  sub    %ecx,%r8d
  cmp    %ecx,%esi
  jl     L173
  movslq %ecx,%rdi
  cmp    $0x6,%r8d
  jbe    L121
  lea    0x1(%r8),%r10d
  cmp    $0xe,%r8d
  jbe    L139
  mov    %r10d,%r9d
  add    %rdx,%rdi
  xor    %eax,%eax
  shr    $0x4,%r9d
  shl    $0x4,%r9
  cs nopw 0x0(%rax,%rax,1)
L194:
  movdqu (%rdi,%rax,1),%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L194
  mov    %r10d,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r9d
  add    %eax,%ecx
  cmp    %eax,%r10d
  je     L173
  mov    %r8d,%r11d
  sub    %eax,%r11d
  lea    0x1(%r11),%r10d
  cmp    $0x6,%r11d
  jbe    L43
L103:
  mov    (%rdi,%rax,1),%rdi
  mov    %rdi,(%rdx,%rax,1)
  mov    %r10d,%eax
  and    $0xfffffff8,%eax
  add    %eax,%ecx
  add    %eax,%r9d
  cmp    %eax,%r10d
  je     L173
L43:
  movslq %ecx,%rax
  movzbl (%rdx,%rax,1),%edi
  movslq %r9d,%rax
  mov    %dil,(%rdx,%rax,1)
  lea    0x1(%rcx),%eax
  lea    0x1(%r9),%edi
  cmp    %eax,%esi
  jl     L173
  cltq
  movslq %edi,%rdi
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdx,%rdi,1)
  lea    0x2(%rcx),%eax
  lea    0x2(%r9),%edi
  cmp    %eax,%esi
  jl     L173
  cltq
  movslq %edi,%rdi
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdx,%rdi,1)
  lea    0x3(%rcx),%eax
  lea    0x3(%r9),%edi
  cmp    %eax,%esi
  jl     L173
  cltq
  movslq %edi,%rdi
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdx,%rdi,1)
  lea    0x4(%rcx),%eax
  lea    0x4(%r9),%edi
  cmp    %eax,%esi
  jl     L173
  cltq
  movslq %edi,%rdi
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdx,%rdi,1)
  lea    0x5(%rcx),%eax
  lea    0x5(%r9),%edi
  cmp    %eax,%esi
  jl     L173
  cltq
  movslq %edi,%rdi
  add    $0x6,%ecx
  add    $0x6,%r9d
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rdx,%rdi,1)
  cmp    %ecx,%esi
  jl     L173
  movslq %ecx,%rcx
  movslq %r9d,%r9
  movzbl (%rdx,%rcx,1),%eax
  mov    %al,(%rdx,%r9,1)
L173:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L121:
  mov    %r8d,%eax
  lea    0x1(%rdx,%rax,1),%rcx
L106:
  movzbl (%rdx,%rdi,1),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L106
  jmp    L173
  nopw   0x0(%rax,%rax,1)
L177:
  mov    %esi,%r8d
  jmp    L173
L139:
  xor    %eax,%eax
  xor    %r9d,%r9d
  add    %rdx,%rdi
  jmp    L103
```

assistant: ```c
int str_ltrim(char *const buf, int len) {
  int i, j, ret_len = len;
  if (len == 0)
    return len;
  for (i = 0; buf[i] == ' ';)
    i++;
  if (i) {
    ret_len = len - i;
    for (j = 0; i <= len; i++, j++)
      buf[j] = buf[i];
  }
  return ret_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pass1@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pass2@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *filename = argv[1];
  pass1(filename);
  pass2(filename);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rbx
  mov    %rbx,%rdi
  call   <pass1@plt>
  mov    %rbx,%rdi
  call   <pass2@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *filename = argv[1];
  pass1(filename);
  pass2(filename);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <pass1@plt>
  mov    %rbp,%rdi
  call   <pass2@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *filename = argv[1];
  pass1(filename);
  pass2(filename);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <pass1@plt>
  mov    %rbp,%rdi
  call   <pass2@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *filename = argv[1];
  pass1(filename);
  pass2(filename);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reed_sol_vandermonde_coding_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <reed_sol_big_vandermonde_distribution_matrix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L35
L26:
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L35
L2:
  mov    -0x24(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L54:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x28(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L54
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
int *reed_sol_vandermonde_coding_matrix(int k, int m, int w) {
  int i, j;
  int *vdm, *dist;
  vdm = reed_sol_big_vandermonde_distribution_matrix(k + m, k, w);
  if (vdm == NULL)
    return NULL;
  dist = (int *)malloc(sizeof(int) * (m * k));
  if (dist == NULL) {
    free(vdm);
    return NULL;
  }
  i = k * k;
  for (j = 0; j < m * k; j++) {
    dist[j] = vdm[i];
    i++;
  }
  free(vdm);
  return dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reed_sol_vandermonde_coding_matrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  lea    (%rdi,%rsi,1),%edi
  mov    %ebx,%esi
  call   <reed_sol_big_vandermonde_distribution_matrix@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L24
  imul   %ebx,%r13d
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  imul   %ebx,%ebx
  test   %r13d,%r13d
  jle    L21
  mov    %rax,%rdx
  mov    %r13d,%r13d
  lea    (%rax,%r13,4),%rsi
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,4),%rcx
  sub    %rax,%rcx
L45:
  mov    (%rcx,%rdx,1),%eax
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L45
L21:
  mov    %rbp,%rdi
  call   <free@plt>
L12:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
  jmp    L12
L24:
  mov    %rax,%r12
  jmp    L12
```

assistant: ```c
int *reed_sol_vandermonde_coding_matrix(int k, int m, int w) {
  int i, j;
  int *vdm, *dist;
  vdm = reed_sol_big_vandermonde_distribution_matrix(k + m, k, w);
  if (vdm == NULL)
    return NULL;
  dist = (int *)malloc(sizeof(int) * (m * k));
  if (dist == NULL) {
    free(vdm);
    return NULL;
  }
  i = k * k;
  for (j = 0; j < m * k; j++) {
    dist[j] = vdm[i];
    i++;
  }
  free(vdm);
  return dist;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reed_sol_vandermonde_coding_matrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  add    %esi,%edi
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <reed_sol_big_vandermonde_distribution_matrix@plt>
  test   %rax,%rax
  je     L22
  imul   %ebx,%ebp
  mov    %rax,%r13
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  imul   %ebx,%ebx
  test   %ebp,%ebp
  jle    L16
  movslq %ebx,%rbx
  lea    (%rax,%rbp,4),%rsi
  lea    0x0(%r13,%rbx,4),%rcx
  sub    %rax,%rcx
L17:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L17
L16:
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L22:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *reed_sol_vandermonde_coding_matrix(int k, int m, int w) {
  int i, j;
  int *vdm, *dist;
  vdm = reed_sol_big_vandermonde_distribution_matrix(k + m, k, w);
  if (vdm == NULL)
    return NULL;
  dist = (int *)malloc(sizeof(int) * (m * k));
  if (dist == NULL) {
    free(vdm);
    return NULL;
  }
  i = k * k;
  for (j = 0; j < m * k; j++) {
    dist[j] = vdm[i];
    i++;
  }
  free(vdm);
  return dist;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reed_sol_vandermonde_coding_matrix>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  add    %esi,%edi
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <reed_sol_big_vandermonde_distribution_matrix@plt>
  test   %rax,%rax
  je     L36
  imul   %ebx,%r13d
  mov    %rax,%rbp
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L102
  imul   %ebx,%ebx
  test   %r13d,%r13d
  jle    L102
  movslq %ebx,%rax
  lea    0x4(,%rax,4),%rcx
  mov    %r12,%rax
  lea    0x0(%rbp,%rcx,1),%rdx
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L50
  lea    -0x1(%r13),%eax
  cmp    $0x2,%eax
  jbe    L50
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rax
  shr    $0x2,%edx
  sub    %r12,%rsi
  shl    $0x4,%rdx
  lea    -0x4(%rsi,%rcx,1),%rcx
  add    %r12,%rdx
  nopl   0x0(%rax)
L37:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L37
  mov    %r13d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%ebx
  cmp    %eax,%r13d
  je     L102
  movslq %ebx,%rsi
  mov    %eax,%edx
  add    $0x1,%ebx
  mov    0x0(%rbp,%rsi,4),%esi
  lea    0x0(,%rdx,4),%rcx
  mov    %esi,(%r12,%rdx,4)
  lea    0x1(%rax),%edx
  cmp    %edx,%r13d
  jle    L102
  movslq %ebx,%rbx
  add    $0x2,%eax
  mov    0x0(%rbp,%rbx,4),%edx
  lea    0x0(,%rbx,4),%rsi
  mov    %edx,0x4(%r12,%rcx,1)
  cmp    %eax,%r13d
  jle    L102
  mov    0x4(%rbp,%rsi,1),%eax
  mov    %eax,0x8(%r12,%rcx,1)
L102:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L50:
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r12,%rax
  sub    %r12,%rdx
  lea    (%r12,%rsi,4),%rsi
  lea    -0x4(%rdx,%rcx,1),%rcx
  nopl   (%rax)
L95:
  mov    (%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L95
  jmp    L102
```

assistant: ```c
int *reed_sol_vandermonde_coding_matrix(int k, int m, int w) {
  int i, j;
  int *vdm, *dist;
  vdm = reed_sol_big_vandermonde_distribution_matrix(k + m, k, w);
  if (vdm == NULL)
    return NULL;
  dist = (int *)malloc(sizeof(int) * (m * k));
  if (dist == NULL) {
    free(vdm);
    return NULL;
  }
  i = k * k;
  for (j = 0; j < m * k; j++) {
    dist[j] = vdm[i];
    i++;
  }
  free(vdm);
  return dist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L7
L18:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L18
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return ((unsigned char)*s1 - (unsigned char)*s2);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
L20:
  cmp    %al,(%rsi)
  jne    L17
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
L17:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return ((unsigned char)*s1 - (unsigned char)*s2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
  jmp    L21
  nopl   (%rax)
L44:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L17
  mov    %rdx,%rsi
L9:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  je     L44
L5:
  sub    %edx,%eax
  ret
  nopl   (%rax)
L17:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L21:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return ((unsigned char)*s1 - (unsigned char)*s2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L24
  jmp    L11
  nopl   (%rax)
L44:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L39
  mov    %rdx,%rsi
L24:
  movzbl (%rsi),%edx
  cmp    %al,%dl
  je     L44
L29:
  sub    %edx,%eax
  ret
  nopl   (%rax)
L39:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L11:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return ((unsigned char)*s1 - (unsigned char)*s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <doubleAdd@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: r = %d


assistant: ```c
int main(void) {
  int r = doubleAdd(2, 3);
  printf("r = %d\n", r);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <doubleAdd@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: r = %d


assistant: ```c
int main(void) {
  int r = doubleAdd(2, 3);
  printf("r = %d\n", r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <doubleAdd@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: r = %d


assistant: ```c
int main(void) {
  int r = doubleAdd(2, 3);
  printf("r = %d\n", r);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <doubleAdd@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: r = %d


assistant: ```c
int main(void) {
  int r = doubleAdd(2, 3);
  printf("r = %d\n", r);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L33
  mov    -0x18(%rbp),%rax
  movb   $0x35,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L33
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x35,(%rax)
L33:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L7
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x35,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L7
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x35,(%rax)
L7:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L77
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L44:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L71
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x35,(%rax)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L71
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x35,(%rax)
L71:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L44
  nop
L77:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void destroy(char *str, int n) {
  int i;
  if (str[0] == '1') {
    str[0] = '5';
    if (str[1] != '1') {
      str[1] = '5';
    }
  }
  if (str[n - 1] == '1') {
    str[n - 1] = '5';
    if (str[n - 2] != '1') {
      str[n - 2] = '5';
    }
  }
  if (n > 1) {
    for (i = 1; i < n - 1; i++) {
      if (str[i] == '1') {
        str[i - 1] = str[i] = '5';
        if (str[i + 1] != '1') {
          str[i + 1] = '5';
        }
      }
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<destroy>:
  endbr64
  cmpb   $0x31,(%rdi)
  je     L71
L57:
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0x31,(%rdx)
  je     L72
L92:
  cmp    $0x2,%esi
  jle    L98
  mov    %rdi,%rax
  lea    -0x3(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  jmp    L117
L71:
  movb   $0x35,(%rdi)
  cmpb   $0x31,0x1(%rdi)
  je     L57
  movb   $0x35,0x1(%rdi)
  jmp    L57
L72:
  movb   $0x35,(%rdx)
  lea    -0x2(%rdi,%rax,1),%rax
  cmpb   $0x31,(%rax)
  je     L92
  movb   $0x35,(%rax)
  jmp    L92
L3:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L98
L117:
  cmpb   $0x31,0x1(%rax)
  jne    L3
  movb   $0x35,0x1(%rax)
  movb   $0x35,(%rax)
  cmpb   $0x31,0x2(%rax)
  je     L3
  movb   $0x35,0x2(%rax)
  jmp    L3
L98:
  ret
```

assistant: ```c
void destroy(char *str, int n) {
  int i;
  if (str[0] == '1') {
    str[0] = '5';
    if (str[1] != '1') {
      str[1] = '5';
    }
  }
  if (str[n - 1] == '1') {
    str[n - 1] = '5';
    if (str[n - 2] != '1') {
      str[n - 2] = '5';
    }
  }
  if (n > 1) {
    for (i = 1; i < n - 1; i++) {
      if (str[i] == '1') {
        str[i - 1] = str[i] = '5';
        if (str[i + 1] != '1') {
          str[i + 1] = '5';
        }
      }
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<destroy>:
  endbr64
  cmpb   $0x31,(%rdi)
  je     L37
L40:
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0x31,(%rdx)
  je     L70
L116:
  cmp    $0x2,%esi
  jle    L13
  lea    -0x3(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L3
  nopl   (%rax)
L57:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L13
L3:
  cmpb   $0x31,0x1(%rdi)
  jne    L57
  cmpb   $0x31,0x2(%rdi)
  movb   $0x35,0x1(%rdi)
  movb   $0x35,(%rdi)
  je     L57
  movb   $0x35,0x2(%rdi)
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L3
L13:
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  cmpb   $0x31,0x1(%rdi)
  movb   $0x35,(%rdi)
  je     L40
  movslq %esi,%rax
  movb   $0x35,0x1(%rdi)
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0x31,(%rdx)
  jne    L116
L70:
  lea    -0x2(%rdi,%rax,1),%rax
  movb   $0x35,(%rdx)
  cmpb   $0x31,(%rax)
  je     L116
  movb   $0x35,(%rax)
  jmp    L116
```

assistant: ```c
void destroy(char *str, int n) {
  int i;
  if (str[0] == '1') {
    str[0] = '5';
    if (str[1] != '1') {
      str[1] = '5';
    }
  }
  if (str[n - 1] == '1') {
    str[n - 1] = '5';
    if (str[n - 2] != '1') {
      str[n - 2] = '5';
    }
  }
  if (n > 1) {
    for (i = 1; i < n - 1; i++) {
      if (str[i] == '1') {
        str[i - 1] = str[i] = '5';
        if (str[i + 1] != '1') {
          str[i + 1] = '5';
        }
      }
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<destroy>:
  endbr64
  cmpb   $0x31,(%rdi)
  je     L75
L106:
  movslq %esi,%rax
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0x31,(%rdx)
  je     L9
L60:
  cmp    $0x2,%esi
  jle    L28
  lea    -0x3(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
  jmp    L101
  nopl   (%rax)
L92:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L28
L101:
  cmpb   $0x31,0x1(%rdi)
  jne    L92
  cmpb   $0x31,0x2(%rdi)
  movb   $0x35,0x1(%rdi)
  movb   $0x35,(%rdi)
  je     L92
  movb   $0x35,0x2(%rdi)
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L101
L28:
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  cmpb   $0x31,0x1(%rdi)
  movb   $0x35,(%rdi)
  je     L106
  movslq %esi,%rax
  movb   $0x35,0x1(%rdi)
  lea    -0x1(%rdi,%rax,1),%rdx
  cmpb   $0x31,(%rdx)
  jne    L60
L9:
  lea    -0x2(%rdi,%rax,1),%rax
  movb   $0x35,(%rdx)
  cmpb   $0x31,(%rax)
  je     L60
  movb   $0x35,(%rax)
  jmp    L60
```

assistant: ```c
void destroy(char *str, int n) {
  int i;
  if (str[0] == '1') {
    str[0] = '5';
    if (str[1] != '1') {
      str[1] = '5';
    }
  }
  if (str[n - 1] == '1') {
    str[n - 1] = '5';
    if (str[n - 2] != '1') {
      str[n - 2] = '5';
    }
  }
  if (n > 1) {
    for (i = 1; i < n - 1; i++) {
      if (str[i] == '1') {
        str[i - 1] = str[i] = '5';
        if (str[i + 1] != '1') {
          str[i + 1] = '5';
        }
      }
    }
  }
  return;
}
```