user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jg     L18
  mov    $0x0,%eax
  jmp    L37
L18:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L92
L88:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
L92:
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L88
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <QuickSort@plt>
  movl   $0x0,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L23
  mov    $0x0,%eax
  jmp    L37
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L26
L79:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L14
  subl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L69
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L69
  addl   $0x1,-0x1c(%rbp)
L69:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L61
  mov    $0x0,%eax
  jmp    L37
L61:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L79
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L105
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  jmp    L37
L105:
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  if (numsSize < 2) {
    return NULL;
  }
  int *mIndex = (int *)malloc(numsSize * sizeof(int));
  for (int i = 0; i < numsSize; i++) {
    mIndex[i] = i;
  }
  QuickSort(nums, mIndex, 0, numsSize - 1);
  int mLeft = 0, mRight = numsSize - 1;
  if (mLeft == mRight) {
    return NULL;
  }
  int mNum = nums[mLeft] + nums[mRight];
  while (mNum != target) {
    if (mNum > target && --mRight > mLeft) {
    } else if (mNum < target && ++mLeft < mRight) {
    }
    if (mLeft == mRight) {
      return NULL;
    }
    mNum = nums[mLeft] + nums[mRight];
  }
  if (mNum == target) {
    int *mResult = malloc(2 * sizeof(int));
    mResult[0] = mIndex[mLeft];
    mResult[1] = mIndex[mRight];
    return mResult;
  }
  return NULL;
}
```