ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L105
  mov    $0x1,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D24(%rip),%r12
  lea    D23(%rip),%rbp
  jmp    L18
L122:
  mov    0x14(%rsp),%edx
L96:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jl     L105
L18:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  cmp    $0x1,%edx
  je     L122
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L96
  cmp    $0x2,%edx
  je     L40
  cmp    $0x2,%eax
  je     L112
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  jmp    L96
L40:
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  and    $0xfffffffc,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0x3,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L47
  lea    0x4(%rdx),%ecx
  cmovg  %ecx,%edx
  jmp    L96
L47:
  add    $0x2,%edx
  jmp    L96
L112:
  lea    0x3(%rdx),%ecx
  test   %edx,%edx
  cmovns %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    %edx,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  lea    (%rdx,%rsi,1),%eax
  and    $0x3,%eax
  sub    %esi,%eax
  cmp    $0x1,%eax
  lea    0x2(%rcx),%edx
  je     L96
  mov    %ecx,%edx
  jle    L96
  lea    0x4(%rcx),%edx
  jmp    L96
L105:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D23
datatype: string

tool: D16: %d

tool: D24: %d %d

tool: D23: Case %d: %d


assistant: ```c
int main() {
  int t;
  int n, m;
  int res;
  int i;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d", &n, &m);
    if (n == 1) {
      res = m;
    } else if (m == 1) {
      res = n;
    } else if (n == 2) {
      res = (m / 4) * 4;
      if (m % 4 == 1)
        res += 2;
      else if (m % 4 > 1)
        res += 4;
    } else if (m == 2) {
      res = (n / 4) * 4;
      if (n % 4 == 1)
        res += 2;
      else if (n % 4 > 1)
        res += 4;
    } else {
      res = ((n * m) + 1) / 2;
    }
    printf("Case %d: %d\n", i, res);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L71
  mov    $0x1,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D2(%rip),%rbx
  jmp    L50
  nopl   (%rax)
L94:
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L151
  cmp    $0x2,%edx
  je     L8
  cmp    $0x2,%eax
  je     L36
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cs nopw 0x0(%rax,%rax,1)
L151:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jl     L71
L50:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  cmp    $0x1,%edx
  jne    L94
  mov    0x14(%rsp),%edx
  jmp    L151
  nopl   (%rax)
L8:
  test   %eax,%eax
  lea    0x3(%rax),%edx
  mov    %eax,%ecx
  cmovns %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0xfffffffc,%edx
  and    $0x3,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L95
  lea    0x4(%rdx),%ecx
  cmovg  %ecx,%edx
  jmp    L151
  nop
L71:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L117
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L36:
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  mov    %edx,%ecx
  cmovns %edx,%eax
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%edx
  and    $0xfffffffc,%eax
  and    $0x3,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L145
  mov    %eax,%edx
  jle    L151
  add    $0x4,%edx
  jmp    L151
L95:
  add    $0x2,%edx
  jmp    L151
L145:
  lea    0x2(%rax),%edx
  jmp    L151
L117:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D12: %d

tool: D18: %d %d

tool: D2: Case %d: %d


assistant: ```c
int main() {
  int t;
  int n, m;
  int res;
  int i;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d", &n, &m);
    if (n == 1) {
      res = m;
    } else if (m == 1) {
      res = n;
    } else if (n == 2) {
      res = (m / 4) * 4;
      if (m % 4 == 1)
        res += 2;
      else if (m % 4 > 1)
        res += 4;
    } else if (m == 2) {
      res = (n / 4) * 4;
      if (n % 4 == 1)
        res += 2;
      else if (n % 4 > 1)
        res += 4;
    } else {
      res = ((n * m) + 1) / 2;
    }
    printf("Case %d: %d\n", i, res);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L109
  mov    $0x1,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D20(%rip),%rbp
  lea    D26(%rip),%rbx
  jmp    L134
  nopl   (%rax)
L91:
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L5
  cmp    $0x2,%edx
  je     L21
  cmp    $0x2,%eax
  je     L32
  imul   %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jl     L109
L134:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  cmp    $0x1,%edx
  jne    L91
  mov    0x14(%rsp),%edx
  jmp    L5
  nopl   (%rax)
L21:
  test   %eax,%eax
  lea    0x3(%rax),%edx
  mov    %eax,%ecx
  cmovns %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0xfffffffc,%edx
  and    $0x3,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L7
  lea    0x4(%rdx),%ecx
  cmovg  %ecx,%edx
  jmp    L5
  nop
L109:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L32:
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  mov    %edx,%ecx
  cmovns %edx,%eax
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%edx
  and    $0xfffffffc,%eax
  and    $0x3,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L140
  mov    %eax,%edx
  jle    L5
  add    $0x4,%edx
  jmp    L5
L7:
  add    $0x2,%edx
  jmp    L5
L140:
  lea    0x2(%rax),%edx
  jmp    L5
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string

tool: D10: %d

tool: D20: %d %d

tool: D26: Case %d: %d


assistant: ```c
int main() {
  int t;
  int n, m;
  int res;
  int i;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%d %d", &n, &m);
    if (n == 1) {
      res = m;
    } else if (m == 1) {
      res = n;
    } else if (n == 2) {
      res = (m / 4) * 4;
      if (m % 4 == 1)
        res += 2;
      else if (m % 4 > 1)
        res += 4;
    } else if (m == 2) {
      res = (n / 4) * 4;
      if (n % 4 == 1)
        res += 2;
      else if (n % 4 > 1)
        res += 4;
    } else {
      res = ((n * m) + 1) / 2;
    }
    printf("Case %d: %d\n", i, res);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3c,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  lea    -0x1fc(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x1f4(%rbp)
  mov    -0x1f4(%rbp),%eax
  mov    %eax,-0x1c0(%rbp)
  jmp    L77
L42:
  movl   $0x1,-0x1f8(%rbp)
  jmp    L1
L33:
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x1f0(%rbp,%rax,4),%ecx
  mov    -0x1f4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1f8(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rsi
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    -0x1f0(%rbp,%rax,4),%esi
  mov    -0x1f4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rdi
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rdi,%rax
  mov    -0x1f0(%rbp,%rax,4),%eax
  add    %esi,%eax
  add    %eax,%ecx
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x1f0(%rbp,%rax,4)
  addl   $0x1,-0x1f8(%rbp)
L1:
  mov    -0x1f8(%rbp),%eax
  cmp    -0x1f4(%rbp),%eax
  jle    L33
  addl   $0x1,-0x1f4(%rbp)
L77:
  mov    -0x1fc(%rbp),%eax
  cmp    %eax,-0x1f4(%rbp)
  jle    L42
  mov    -0x1fc(%rbp),%eax
  mov    %eax,-0x1f4(%rbp)
  jmp    L18
L45:
  movl   $0x1,-0x1f8(%rbp)
  jmp    L23
L35:
  mov    -0x1f8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1f4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x1f0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1f8(%rbp)
L23:
  mov    -0x1f8(%rbp),%eax
  cmp    -0x1f4(%rbp),%eax
  jle    L35
  subl   $0x1,-0x1f4(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L18:
  cmpl   $0x0,-0x1f4(%rbp)
  jg     L45
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D19
type: string

tool: D16: %d

tool: D19: %d 

assistant: ```c
int main() {
  int x, y, n, a[11][11] = {0};
  for (scanf("%d", &n), a[1][1] = y = 1; y <= n; y++)
    for (x = 1; x <= y; x++)
      a[y][x] += a[y - 1][x - 1] + a[y - 1][x];
  for (y = n; y >= 1; y--, printf("\n"))
    for (x = 1; x <= y; x++)
      printf("%d ", a[y][x]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x3c,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    0xc(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movl   $0x1,0x40(%rsp)
  mov    0xc(%rsp),%ebp
  test   %ebp,%ebp
  jle    L61
  lea    0x40(%rsp),%rdi
  lea    0x44(%rsp),%rcx
  lea    0x1(%rbp),%r8d
  mov    $0x1,%esi
  jmp    L104
L97:
  mov    -0x2c(%rax),%edx
  add    -0x30(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L97
L106:
  add    $0x1,%esi
  add    $0x2c,%rdi
  add    $0x30,%rcx
  cmp    %r8d,%esi
  je     L37
L104:
  mov    %rdi,%rax
  test   %esi,%esi
  jg     L97
  jmp    L106
L37:
  movslq %ebp,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rax,%rdx,2),%rax
  lea    0x10(%rsp,%rax,4),%r12
  lea    D15(%rip),%r13
  jmp    L27
L32:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L32
L51:
  sub    $0x1,%ebp
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x2c,%r12
  test   %ebp,%ebp
  je     L61
L27:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L32
  jmp    L51
L61:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D9: %d

tool: D15: %d 

assistant: ```c
int main() {
  int x, y, n, a[11][11] = {0};
  for (scanf("%d", &n), a[1][1] = y = 1; y <= n; y++)
    for (x = 1; x <= y; x++)
      a[y][x] += a[y - 1][x - 1] + a[y - 1][x];
  for (y = n; y >= 1; y--, printf("\n"))
    for (x = 1; x <= y; x++)
      printf("%d ", a[y][x]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x3c,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebx
  movl   $0x1,0x40(%rsp)
  test   %ebx,%ebx
  jle    L84
  lea    -0x1(%rbx),%eax
  lea    0x3c(%rsp),%r10
  xor    %esi,%esi
  xor    %ecx,%ecx
  lea    (%rax,%rax,4),%rdx
  mov    %rax,%rbp
  mov    %r10,%r8
  mov    $0x1,%edi
  lea    (%rax,%rdx,2),%r11
  mov    $0xffffffffffffffd4,%r9
  xor    %eax,%eax
  shl    $0x2,%r11
  nopl   (%rax)
L37:
  mov    %r10,%rdx
  jmp    L60
  nopl   (%rax)
L65:
  lea    (%rdx,%r9,1),%rcx
  mov    0x8(%rdx),%edi
  add    $0x4,%rdx
  mov    0x4(%rcx,%rsi,1),%eax
  mov    0x8(%rcx,%rsi,1),%ecx
L60:
  add    %ecx,%eax
  add    %edi,%eax
  mov    %eax,0x4(%rdx)
  cmp    %r8,%rdx
  jne    L65
  add    $0x30,%r8
  sub    $0x2c,%r9
  cmp    %r11,%rsi
  je     L16
  mov    0x30(%r10),%edi
  mov    (%r10),%eax
  add    $0x2c,%rsi
  add    $0x2c,%r10
  mov    -0x28(%r10),%ecx
  jmp    L37
  nopl   0x0(%rax)
L84:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L16:
  movslq %ebx,%rax
  lea    D10(%rip),%r14
  lea    (%rax,%rax,4),%rdx
  lea    (%rax,%rdx,2),%rax
  lea    (%r12,%rax,4),%r13
  xchg   %ax,%ax
L38:
  mov    $0x1,%r12d
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    0x0(%r13,%r12,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,%ebx
  jge    L52
  mov    $0xa,%edi
  mov    %ebp,%ebx
  sub    $0x2c,%r13
  call   <putchar@plt>
  test   %ebp,%ebp
  je     L84
  sub    $0x1,%ebp
  jmp    L38
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string

tool: D8: %d

tool: D10: %d 

assistant: ```c
int main() {
  int x, y, n, a[11][11] = {0};
  for (scanf("%d", &n), a[1][1] = y = 1; y <= n; y++)
    for (x = 1; x <= y; x++)
      a[y][x] += a[y - 1][x - 1] + a[y - 1][x];
  for (y = n; y >= 1; y--, printf("\n"))
    for (x = 1; x <= y; x++)
      printf("%d ", a[y][x]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3c,%ecx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebp
  movl   $0x1,0x40(%rsp)
  test   %ebp,%ebp
  jle    L52
  lea    0x40(%rsp),%rdi
  lea    0x1(%rbp),%r10d
  mov    $0xb,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%esi
  cs nopw 0x0(%rax,%rax,1)
L82:
  cmp    $0x2,%r8d
  jbe    L75
  movdqu -0x2c(%rdi),%xmm0
  movdqu -0x30(%rdi),%xmm2
  mov    %esi,%eax
  movdqu (%rdi),%xmm3
  shr    $0x2,%eax
  paddd  %xmm2,%xmm0
  paddd  %xmm3,%xmm0
  movups %xmm0,(%rdi)
  cmp    $0x2,%eax
  jne    L104
  movdqu -0x1c(%rdi),%xmm0
  movdqu -0x20(%rdi),%xmm1
  movdqu 0x10(%rdi),%xmm4
  paddd  %xmm1,%xmm0
  paddd  %xmm4,%xmm0
  movups %xmm0,0x10(%rdi)
L104:
  mov    %esi,%edx
  and    $0xfffffffc,%edx
  lea    0x1(%rdx),%eax
  cmp    %esi,%edx
  je     L58
L71:
  mov    %esi,%ecx
  sub    %edx,%ecx
  cmp    $0x1,%ecx
  je     L1
  lea    0x1(%r9,%rdx,1),%rdx
  shl    $0x2,%rdx
  movq   -0x1c(%rsp,%rdx,1),%xmm1
  movq   -0x20(%rsp,%rdx,1),%xmm0
  lea    (%rbx,%rdx,1),%r11
  mov    %ecx,%edx
  and    $0xfffffffe,%edx
  paddd  %xmm1,%xmm0
  movq   (%r11),%xmm1
  add    %edx,%eax
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%r11)
  cmp    %edx,%ecx
  je     L58
L1:
  movslq %esi,%rdx
  movslq %eax,%r11
  sub    $0x1,%eax
  lea    (%rdx,%rdx,4),%rcx
  cltq
  lea    (%rdx,%rcx,2),%rdx
  movslq %r8d,%rcx
  lea    (%rcx,%rcx,4),%r12
  add    %r11,%rdx
  lea    (%rcx,%r12,2),%rcx
  add    %rcx,%rax
  add    %r11,%rcx
  mov    0x10(%rsp,%rcx,4),%ecx
  add    0x10(%rsp,%rax,4),%ecx
  add    %ecx,0x10(%rsp,%rdx,4)
L58:
  add    $0x1,%esi
  add    $0x1,%r8d
  add    $0x2c,%rdi
  add    $0xb,%r9
  cmp    %r10d,%esi
  jne    L82
  movslq %ebp,%rax
  lea    D0(%rip),%r13
  lea    (%rax,%rax,4),%rdx
  lea    (%rax,%rdx,2),%rax
  lea    (%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L88:
  mov    $0x1,%ebx
  nopl   (%rax)
L50:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L50
  mov    $0xa,%edi
  sub    $0x1,%ebp
  sub    $0x2c,%r12
  call   <putchar@plt>
  test   %ebp,%ebp
  jne    L88
L52:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x208,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L75:
  xor    %edx,%edx
  mov    $0x1,%eax
  jmp    L71
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D1: %d

tool: D0: %d 

assistant: ```c
int main() {
  int x, y, n, a[11][11] = {0};
  for (scanf("%d", &n), a[1][1] = y = 1; y <= n; y++)
    for (x = 1; x <= y; x++)
      a[y][x] += a[y - 1][x - 1] + a[y - 1][x];
  for (y = n; y >= 1; y--, printf("\n"))
    for (x = 1; x <= y; x++)
      printf("%d ", a[y][x]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetClockTimeInNanoSec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int GetClockTimeInNanoSec() {
  struct timeval t2;
  gettimeofday(&t2, NULL);
  return t2.tv_sec + t2.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetClockTimeInNanoSec>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetClockTimeInNanoSec() {
  struct timeval t2;
  gettimeofday(&t2, NULL);
  return t2.tv_sec + t2.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GetClockTimeInNanoSec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetClockTimeInNanoSec() {
  struct timeval t2;
  gettimeofday(&t2, NULL);
  return t2.tv_sec + t2.tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetClockTimeInNanoSec>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int GetClockTimeInNanoSec() {
  struct timeval t2;
  gettimeofday(&t2, NULL);
  return t2.tv_sec + t2.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<subString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L30:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L30
  cmpl   $0x1,-0x24(%rbp)
  jne    L54
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L68
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L50
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L42
L50:
  movl   $0xffffffff,-0xc(%rbp)
L42:
  subl   $0x1,-0xc(%rbp)
L68:
  cmpl   $0x0,-0xc(%rbp)
  jns    L20
L54:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *subString(char *text, int first, int length, int spcKill) {
  char *ret = (char *)calloc(length + 1, sizeof(char));
  int i;
  ret[length] = 0;
  for (i = 0; i < length; i++) {
    ret[i] = text[i + first];
  }
  if (spcKill == 1) {
    for (i = length - 1; i >= 0; i--) {
      if (ret[i] == 32)
        ret[i] = 0;
      else
        i = -1;
    }
  }
  return ret;
}
```