ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<_get_sysfs_numeric>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <get_sysfs_str@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  mov    D6(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x0,(%rax)
  call   <sscanf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L1:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int _get_sysfs_numeric(char *sysfs_attr, char *fmt, void *value) {
  char *string;
  if ((string = get_sysfs_str(sysfs_attr)) == NULL)
    return -1;
  errno = 0;
  sscanf(string, fmt, value);
  free(string);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_get_sysfs_numeric>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <get_sysfs_str@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbp
  mov    D2(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movq   $0x0,(%rax)
  call   <sscanf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L10:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int _get_sysfs_numeric(char *sysfs_attr, char *fmt, void *value) {
  char *string;
  if ((string = get_sysfs_str(sysfs_attr)) == NULL)
    return -1;
  errno = 0;
  sscanf(string, fmt, value);
  free(string);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<system_call_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: 
 #####> Exiting on syscall !!


assistant: ```c
void system_call_handler() {
  printf("\n #####> Exiting on syscall !!\n");
  exit(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<system_call_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string

tool: D3: 
 #####> Exiting on syscall !!


assistant: ```c
void system_call_handler() {
  printf("\n #####> Exiting on syscall !!\n");
  exit(-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<system_call_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: 
 #####> Exiting on syscall !!


assistant: ```c
void system_call_handler() {
  printf("\n #####> Exiting on syscall !!\n");
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<system_call_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: 
 #####> Exiting on syscall !!


assistant: ```c
void system_call_handler() {
  printf("\n #####> Exiting on syscall !!\n");
  exit(-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tablero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L52
L51:
  cmpl   $0x1,-0x4(%rbp)
  jg     L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  addl   $0x1,-0x4(%rbp)
L52:
  cmpl   $0x2,-0x4(%rbp)
  jle    L51
  cmpl   $0x1,-0x8(%rbp)
  jg     L66
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L66:
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x2,-0x8(%rbp)
  jle    L10
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D21:  %c |

tool: D23:  %c 

tool: D7: 
-----------

tool: D9: 


assistant: ```c
void tablero(char c[3][3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (j < 2) {
        printf(" %c |", c[i][j]);
      } else {
        printf(" %c ", c[i][j]);
      }
    }
    if (i < 2) {
      printf("\n-----------\n");
    }
  }
  printf("\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tablero>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%ebp
  lea    D31(%rip),%r12
  lea    D32(%rip),%r13
  lea    D4(%rip),%r14
  jmp    L4
L11:
  cmp    $0x2,%ebp
  jle    L24
  lea    D38(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  add    $0x3,%rbx
  add    $0x1,%ebp
L4:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x1(%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl 0x2(%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbp),%eax
  cmp    $0x1,%eax
  jg     L11
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: label: D31
type_infered: string
name: disassemble_data
arguments: label: D32
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string
name: disassemble_data
arguments: label: D38
type_infered: string

tool: D31:  %c |

tool: D32:  %c 

tool: D4: 
-----------

tool: D38: 


assistant: ```c
void tablero(char c[3][3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (j < 2) {
        printf(" %c |", c[i][j]);
      } else {
        printf(" %c ", c[i][j]);
      }
    }
    if (i < 2) {
      printf("\n-----------\n");
    }
  }
  printf("\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tablero>:
  endbr64
  push   %r15
  lea    0x9(%rdi),%r15
  push   %r14
  lea    D35(%rip),%r14
  push   %r13
  lea    0x6(%rdi),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L16:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x1(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x2(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L1
  mov    %r14,%rdi
  add    $0x3,%rbx
  call   <puts@plt>
  cmp    %r15,%rbx
  jne    L16
L1:
  add    $0x8,%rsp
  lea    D28(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: D35: 
-----------

tool: D15:  %c 

tool: D11:  %c |

tool: D28: 


assistant: ```c
void tablero(char c[3][3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (j < 2) {
        printf(" %c |", c[i][j]);
      } else {
        printf(" %c ", c[i][j]);
      }
    }
    if (i < 2) {
      printf("\n-----------\n");
    }
  }
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tablero>:
  endbr64
  push   %r15
  lea    0x9(%rdi),%r15
  push   %r14
  lea    D33(%rip),%r14
  push   %r13
  lea    0x6(%rdi),%r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L10:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x1(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x2(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L9
  mov    %r14,%rdi
  add    $0x3,%rbx
  call   <puts@plt>
  cmp    %r15,%rbx
  jne    L10
L9:
  add    $0x8,%rsp
  lea    D25(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D25
datatype: string

tool: D33: 
-----------

tool: D27:  %c 

tool: D1:  %c |

tool: D25: 


assistant: ```c
void tablero(char c[3][3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (j < 2) {
        printf(" %c |", c[i][j]);
      } else {
        printf(" %c ", c[i][j]);
      }
    }
    if (i < 2) {
      printf("\n-----------\n");
    }
  }
  printf("\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ckalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy_string(const char *const str) {
  char *copy = ckalloc(strlen(str) + 1);
  strcpy(copy, str);
  return copy;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <ckalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *copy_string(const char *const str) {
  char *copy = ckalloc(strlen(str) + 1);
  strcpy(copy, str);
  return copy;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <ckalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(const char *const str) {
  char *copy = ckalloc(strlen(str) + 1);
  strcpy(copy, str);
  return copy;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <ckalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(const char *const str) {
  char *copy = ckalloc(strlen(str) + 1);
  strcpy(copy, str);
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<refocus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <getfronttask@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cfocusapp@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct client *refocus(Time time) {
  struct client *c = getfronttask();
  if (c != NULL)
    cfocusapp(c, time);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<refocus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <getfronttask@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <cfocusapp@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct client *refocus(Time time) {
  struct client *c = getfronttask();
  if (c != NULL)
    cfocusapp(c, time);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<refocus>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <getfronttask@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <cfocusapp@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct client *refocus(Time time) {
  struct client *c = getfronttask();
  if (c != NULL)
    cfocusapp(c, time);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<refocus>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <getfronttask@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <cfocusapp@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct client *refocus(Time time) {
  struct client *c = getfronttask();
  if (c != NULL)
    cfocusapp(c, time);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<p264_sub16x16_dct_mmxext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x18(%rbp),%edi
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <p264_sub8x8_dct_mmxext@plt>
  mov    -0x20(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x20(%rax),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x100(%rax),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %eax,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x200(%rax),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %eax,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  cltq
  add    $0x8,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  cltq
  add    $0x8,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x8(%rbp),%rax
  lea    0x300(%rax),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %eax,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  nop
  leave
  ret
```

assistant: ```c
void p264_sub16x16_dct_mmxext(int16_t dct[16][4][4], uint8_t *pix1, int i_pix1, uint8_t *pix2, int i_pix2) {
  p264_sub8x8_dct_mmxext(&dct[0], &pix1[0], i_pix1, &pix2[0], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[4], &pix1[8], i_pix1, &pix2[8], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[8], &pix1[8 * i_pix1], i_pix1, &pix2[8 * i_pix2], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[12], &pix1[8 * i_pix1 + 8], i_pix1, &pix2[8 * i_pix2 + 8], i_pix2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p264_sub16x16_dct_mmxext>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %rcx,%r15
  mov    %r8d,%r12d
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    0x20(%r15),%rcx
  lea    0x20(%r13),%rsi
  lea    0x100(%rbx),%rdi
  mov    %r12d,%r8d
  mov    %ebp,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    0x0(,%r12,8),%r14d
  movslq %r14d,%r14
  shl    $0x2,%r14
  lea    0x0(,%rbp,8),%eax
  cltq
  shl    $0x2,%rax
  lea    (%r15,%r14,1),%rcx
  mov    %rax,0x8(%rsp)
  lea    0x0(%r13,%rax,1),%rsi
  lea    0x200(%rbx),%rdi
  mov    %r12d,%r8d
  mov    %ebp,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    0x20(%r15,%r14,1),%rcx
  mov    0x8(%rsp),%rax
  lea    0x20(%r13,%rax,1),%rsi
  lea    0x300(%rbx),%rdi
  mov    %r12d,%r8d
  mov    %ebp,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void p264_sub16x16_dct_mmxext(int16_t dct[16][4][4], uint8_t *pix1, int i_pix1, uint8_t *pix2, int i_pix2) {
  p264_sub8x8_dct_mmxext(&dct[0], &pix1[0], i_pix1, &pix2[0], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[4], &pix1[8], i_pix1, &pix2[8], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[8], &pix1[8 * i_pix1], i_pix1, &pix2[8 * i_pix2], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[12], &pix1[8 * i_pix1 + 8], i_pix1, &pix2[8 * i_pix2 + 8], i_pix2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<p264_sub16x16_dct_mmxext>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  lea    0x0(,%r12,8),%r13d
  push   %rbx
  mov    %rdi,%rbx
  movslq %r13d,%r13
  shl    $0x2,%r13
  sub    $0x18,%rsp
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    0x20(%r15),%rcx
  lea    0x20(%r14),%rsi
  mov    %ebp,%r8d
  lea    0x100(%rbx),%rdi
  mov    %r12d,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    (%r14,%r13,1),%rsi
  mov    %ebp,%r8d
  mov    %r12d,%edx
  lea    0x0(,%rbp,8),%r9d
  lea    0x200(%rbx),%rdi
  movslq %r9d,%r9
  shl    $0x2,%r9
  lea    (%r15,%r9,1),%rcx
  mov    %r9,0x8(%rsp)
  call   <p264_sub8x8_dct_mmxext@plt>
  mov    0x8(%rsp),%r9
  mov    %ebp,%r8d
  mov    %r12d,%edx
  add    $0x18,%rsp
  lea    0x20(%r14,%r13,1),%rsi
  lea    0x300(%rbx),%rdi
  lea    0x20(%r15,%r9,1),%rcx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <p264_sub8x8_dct_mmxext@plt>
```

assistant: ```c
void p264_sub16x16_dct_mmxext(int16_t dct[16][4][4], uint8_t *pix1, int i_pix1, uint8_t *pix2, int i_pix2) {
  p264_sub8x8_dct_mmxext(&dct[0], &pix1[0], i_pix1, &pix2[0], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[4], &pix1[8], i_pix1, &pix2[8], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[8], &pix1[8 * i_pix1], i_pix1, &pix2[8 * i_pix2], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[12], &pix1[8 * i_pix1 + 8], i_pix1, &pix2[8 * i_pix2 + 8], i_pix2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<p264_sub16x16_dct_mmxext>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %r8d,%ebp
  lea    0x0(,%r12,8),%r13d
  push   %rbx
  mov    %rdi,%rbx
  movslq %r13d,%r13
  shl    $0x2,%r13
  sub    $0x18,%rsp
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    0x20(%r15),%rcx
  lea    0x20(%r14),%rsi
  mov    %ebp,%r8d
  lea    0x100(%rbx),%rdi
  mov    %r12d,%edx
  call   <p264_sub8x8_dct_mmxext@plt>
  lea    (%r14,%r13,1),%rsi
  mov    %ebp,%r8d
  mov    %r12d,%edx
  lea    0x0(,%rbp,8),%r9d
  lea    0x200(%rbx),%rdi
  movslq %r9d,%r9
  shl    $0x2,%r9
  lea    (%r15,%r9,1),%rcx
  mov    %r9,0x8(%rsp)
  call   <p264_sub8x8_dct_mmxext@plt>
  mov    0x8(%rsp),%r9
  mov    %ebp,%r8d
  mov    %r12d,%edx
  add    $0x18,%rsp
  lea    0x20(%r14,%r13,1),%rsi
  lea    0x300(%rbx),%rdi
  lea    0x20(%r15,%r9,1),%rcx
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <p264_sub8x8_dct_mmxext@plt>
```

assistant: ```c
void p264_sub16x16_dct_mmxext(int16_t dct[16][4][4], uint8_t *pix1, int i_pix1, uint8_t *pix2, int i_pix2) {
  p264_sub8x8_dct_mmxext(&dct[0], &pix1[0], i_pix1, &pix2[0], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[4], &pix1[8], i_pix1, &pix2[8], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[8], &pix1[8 * i_pix1], i_pix1, &pix2[8 * i_pix2], i_pix2);
  p264_sub8x8_dct_mmxext(&dct[12], &pix1[8 * i_pix1 + 8], i_pix1, &pix2[8 * i_pix2 + 8], i_pix2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alloc_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L23
L26:
  movq   $0x0,-0x20(%rbp)
  jmp    L9
L5:
  mov    -0x40(%rbp),%rax
  imul   -0x48(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  movl   $0x0,-0x24(%rbp)
  jmp    L19
L27:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x24(%rbp)
L19:
  mov    -0x24(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L27
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L23
L49:
  addq   $0x1,-0x20(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L5
  mov    -0x18(%rbp),%rax
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void **alloc_matrix(size_t height, size_t width, size_t elem_size) {
  size_t i;
  int j;
  void **result = calloc(height, sizeof(void *));
  if (result == NULL) {
    return NULL;
  }
  for (i = 0; i < height; i++) {
    result[i] = malloc(width * elem_size);
    if (result[i] == NULL) {
      for (j = 0; j < i; j++) {
        free(result[j]);
      }
      free(result);
      return NULL;
    }
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alloc_matrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  test   %r13,%r13
  je     L3
  imul   %rbx,%r14
  mov    $0x0,%ebp
L45:
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,(%r12,%rbp,8)
  test   %rax,%rax
  je     L49
  add    $0x1,%rbp
  cmp    %rbp,%r13
  jne    L45
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  test   %rbp,%rbp
  je     L18
  mov    $0x0,%r13d
L50:
  mov    (%r12,%r13,8),%rdi
  call   <free@plt>
  add    $0x1,%r13
  cmp    %rbp,%r13
  jne    L50
L18:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbx,%r12
  jmp    L3
```

assistant: ```c
void **alloc_matrix(size_t height, size_t width, size_t elem_size) {
  size_t i;
  int j;
  void **result = calloc(height, sizeof(void *));
  if (result == NULL) {
    return NULL;
  }
  for (i = 0; i < height; i++) {
    result[i] = malloc(width * elem_size);
    if (result[i] == NULL) {
      for (j = 0; j < i; j++) {
        free(result[j]);
      }
      free(result);
      return NULL;
    }
  }
  return result;
}
```