ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fib_memoization2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  jle    L155
  movslq %edi,%r12
  mov    %edi,%ebp
  mov    %rsi,%r13
  shl    $0x2,%r12
  lea    -0x4(%rsi,%r12,1),%r14
  mov    (%r14),%ebx
  test   %ebx,%ebx
  je     L110
  lea    -0x8(%r13,%r12,1),%r15
  mov    (%r15),%r12d
  test   %r12d,%r12d
  je     L47
L52:
  add    %ebx,%r12d
  xor    %edi,%edi
  test   %r12d,%r12d
  setg   %dil
  call   <assert@plt>
L155:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  lea    -0x2(%rbp),%eax
  mov    $0x1,%r12d
  cmp    $0x1,%eax
  jle    L130
  cltq
  lea    0x0(,%rax,4),%rbx
  lea    -0x4(%r13,%rbx,1),%rdx
  mov    (%rdx),%r12d
  test   %r12d,%r12d
  je     L116
L152:
  lea    -0x8(%r13,%rbx,1),%rbx
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L74
L79:
  add    %eax,%r12d
  xor    %edi,%edi
  test   %r12d,%r12d
  setg   %dil
  call   <assert@plt>
L130:
  mov    %r12d,(%r15)
  mov    (%r14),%ebx
  jmp    L52
  nopl   0x0(%rax)
L110:
  lea    -0x1(%rdi),%ebx
  cmp    $0x2,%edi
  je     L67
  movslq %ebx,%rbx
  lea    0x0(,%rbx,4),%r15
  lea    -0x4(%rsi,%r15,1),%rdx
  mov    (%rdx),%ebx
  test   %ebx,%ebx
  je     L62
L12:
  lea    -0x8(%r13,%r15,1),%r15
  mov    (%r15),%eax
  test   %eax,%eax
  je     L159
L149:
  add    %eax,%ebx
  xor    %edi,%edi
  test   %ebx,%ebx
  setg   %dil
  call   <assert@plt>
L67:
  lea    -0x8(%r13,%r12,1),%r15
  mov    %ebx,(%r14)
  mov    (%r15),%r12d
  test   %r12d,%r12d
  jne    L52
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L159:
  lea    -0x3(%rbp),%edi
  mov    %r13,%rsi
  mov    %rdx,0x8(%rsp)
  call   <fib_memoization2>
  mov    0x8(%rsp),%rdx
  mov    %eax,(%r15)
  mov    (%rdx),%ebx
  jmp    L149
  nopl   0x0(%rax)
L62:
  lea    -0x2(%rdi),%edi
  mov    %rdx,0x8(%rsp)
  call   <fib_memoization2>
  mov    0x8(%rsp),%rdx
  mov    %eax,%ebx
  mov    %eax,(%rdx)
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L74:
  lea    -0x4(%rbp),%edi
  mov    %r13,%rsi
  mov    %rdx,0x8(%rsp)
  call   <fib_memoization2>
  mov    0x8(%rsp),%rdx
  mov    %eax,(%rbx)
  mov    (%rdx),%r12d
  jmp    L79
  nop
L116:
  lea    -0x3(%rbp),%edi
  mov    %r13,%rsi
  mov    %rdx,0x8(%rsp)
  call   <fib_memoization2>
  mov    0x8(%rsp),%rdx
  mov    %eax,%r12d
  mov    %eax,(%rdx)
  jmp    L152
```

assistant: ```c
int64_t fib_memoization2(int n, int64_t *cache) {
  if (n < 2)
    return 1;
  if (!cache[n - 1]) {
    cache[n - 1] = fib_memoization2(n - 1, cache);
  }
  if (!cache[n - 2]) {
    cache[n - 2] = fib_memoization2(n - 2, cache);
  }
  int64_t ret = cache[n - 1] + cache[n - 2];
  assert(ret > 0);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ByteReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ByteReverse(unsigned char *buf, unsigned longs) {
  unsigned int t;
  do {
    t = (unsigned int)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(unsigned int *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ByteReverse>:
  endbr64
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L7:
  movzbl 0x3(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  or     %edx,%eax
  shl    $0x10,%eax
  movzbl 0x1(%rdi),%edx
  shl    $0x8,%edx
  movzbl (%rdi),%ecx
  or     %ecx,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  jne    L7
  ret
```

assistant: ```c
void ByteReverse(unsigned char *buf, unsigned longs) {
  unsigned int t;
  do {
    t = (unsigned int)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(unsigned int *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ByteReverse>:
  endbr64
  ret
```

assistant: ```c
void ByteReverse(unsigned char *buf, unsigned longs) {
  unsigned int t;
  do {
    t = (unsigned int)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(unsigned int *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ByteReverse>:
  endbr64
  ret
```

assistant: ```c
void ByteReverse(unsigned char *buf, unsigned longs) {
  unsigned int t;
  do {
    t = (unsigned int)((unsigned)buf[3] << 8 | buf[2]) << 16 | ((unsigned)buf[1] << 8 | buf[0]);
    *(unsigned int *)buf = t;
    buf += 4;
  } while (--longs);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<autohelperowl_attackpat136>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <owl_big_eyespace@plt>
  test   %rax,%rax
  je     L17
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  je     L17
  mov    $0x1,%eax
  jmp    L10
L17:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat136(struct pattern *patt, int transformation, int move, int color, int action) {
  int b, A;
  (void)patt;
  (void)color;
  (void)action;
  b = offset(1, 1, move, transformation);
  A = offset(1, 0, move, transformation);
  return owl_big_eyespace(A, b) && play_attack_defend_n(color, 1, 1, move, b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<autohelperowl_attackpat136>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <owl_big_eyespace@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L18
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L19
```

assistant: ```c
int autohelperowl_attackpat136(struct pattern *patt, int transformation, int move, int color, int action) {
  int b, A;
  (void)patt;
  (void)color;
  (void)action;
  b = offset(1, 1, move, transformation);
  A = offset(1, 0, move, transformation);
  return owl_big_eyespace(A, b) && play_attack_defend_n(color, 1, 1, move, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<autohelperowl_attackpat136>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <owl_big_eyespace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat136(struct pattern *patt, int transformation, int move, int color, int action) {
  int b, A;
  (void)patt;
  (void)color;
  (void)action;
  b = offset(1, 1, move, transformation);
  A = offset(1, 0, move, transformation);
  return owl_big_eyespace(A, b) && play_attack_defend_n(color, 1, 1, move, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<autohelperowl_attackpat136>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <owl_big_eyespace@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <play_attack_defend_n@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat136(struct pattern *patt, int transformation, int move, int color, int action) {
  int b, A;
  (void)patt;
  (void)color;
  (void)action;
  b = offset(1, 1, move, transformation);
  A = offset(1, 0, move, transformation);
  return owl_big_eyespace(A, b) && play_attack_defend_n(color, 1, 1, move, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__u32_mul_even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L14
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L28
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L28
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L28:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __u32_mul_even(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else if (!(*(uint32_t *)v % 2)) {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__u32_mul_even>:
  endbr64
  test   %ecx,%ecx
  je     L0
  movl   $0x1,(%rdx)
  ret
L0:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L5
  imul   (%rdi),%eax
  mov    %eax,(%rdx)
L5:
  ret
```

assistant: ```c
void __u32_mul_even(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else if (!(*(uint32_t *)v % 2)) {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__u32_mul_even>:
  endbr64
  test   %ecx,%ecx
  je     L4
  movl   $0x1,(%rdx)
  ret
  nop
L4:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L3
  imul   (%rdi),%eax
  mov    %eax,(%rdx)
L3:
  ret
```

assistant: ```c
void __u32_mul_even(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else if (!(*(uint32_t *)v % 2)) {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__u32_mul_even>:
  endbr64
  test   %ecx,%ecx
  je     L0
  movl   $0x1,(%rdx)
  ret
  nop
L0:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L13
  imul   (%rdi),%eax
  mov    %eax,(%rdx)
L13:
  ret
```

assistant: ```c
void __u32_mul_even(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else if (!(*(uint32_t *)v % 2)) {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x41,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
  mov    $0x42,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
  movb   $0x0,-0x1(%rbp)
L1:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
  jmp    L1
```

assistant: ```c
main() {
  z80_outp(0x01, 'A');
  z80_outp(0x01, 'B');
  unsigned char a = 0;
  while (1) {
    a++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
  mov    $0x42,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
L4:
  jmp    L4
```

assistant: ```c
main() {
  z80_outp(0x01, 'A');
  z80_outp(0x01, 'B');
  unsigned char a = 0;
  while (1) {
    a++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x41,%esi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <z80_outp@plt>
  mov    $0x42,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
L1:
  jmp    L1
```

assistant: ```c
main() {
  z80_outp(0x01, 'A');
  z80_outp(0x01, 'B');
  unsigned char a = 0;
  while (1) {
    a++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x41,%esi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <z80_outp@plt>
  mov    $0x42,%esi
  mov    $0x1,%edi
  call   <z80_outp@plt>
L3:
  jmp    L3
```

assistant: ```c
main() {
  z80_outp(0x01, 'A');
  z80_outp(0x01, 'B');
  unsigned char a = 0;
  while (1) {
    a++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
long usecs(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec * 1000000 + t.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usecs>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long usecs(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec * 1000000 + t.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usecs>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long usecs(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec * 1000000 + t.tv_usec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usecs>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long usecs(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec * 1000000 + t.tv_usec;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<selLet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x7a,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L81
  movl   $0x31,-0x4(%rbp)
L81:
  cmpl   $0x2,-0x14(%rbp)
  jne    L64
  movl   $0x32,-0x4(%rbp)
L64:
  cmpl   $0x3,-0x14(%rbp)
  jne    L88
  movl   $0x33,-0x4(%rbp)
L88:
  cmpl   $0x4,-0x14(%rbp)
  jne    L76
  movl   $0x34,-0x4(%rbp)
L76:
  cmpl   $0x5,-0x14(%rbp)
  jne    L14
  movl   $0x35,-0x4(%rbp)
L14:
  cmpl   $0x6,-0x14(%rbp)
  jne    L96
  movl   $0x36,-0x4(%rbp)
L96:
  cmpl   $0x7,-0x14(%rbp)
  jne    L61
  movl   $0x37,-0x4(%rbp)
L61:
  cmpl   $0x8,-0x14(%rbp)
  jne    L86
  movl   $0x38,-0x4(%rbp)
L86:
  cmpl   $0x9,-0x14(%rbp)
  jne    L8
  movl   $0x39,-0x4(%rbp)
L8:
  cmpl   $0x0,-0x14(%rbp)
  jne    L53
  movl   $0x30,-0x4(%rbp)
L53:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char selLet(int a) {
  int ris = 'z';
  if (a == 1)
    ris = '1';
  if (a == 2)
    ris = '2';
  if (a == 3)
    ris = '3';
  if (a == 4)
    ris = '4';
  if (a == 5)
    ris = '5';
  if (a == 6)
    ris = '6';
  if (a == 7)
    ris = '7';
  if (a == 8)
    ris = '8';
  if (a == 9)
    ris = '9';
  if (a == 0)
    ris = '0';
  return ris;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<selLet>:
  endbr64
  cmp    $0x1,%edi
  je     L42
  mov    $0x32,%eax
  cmp    $0x2,%edi
  jne    L7
L10:
  cmp    $0x5,%edi
  jne    L12
  mov    $0x35,%eax
L22:
  cmp    $0x8,%edi
  jne    L97
  mov    $0x38,%eax
  ret
L7:
  cmp    $0x3,%edi
  jne    L52
  mov    $0x33,%eax
L12:
  cmp    $0x6,%edi
  jne    L0
  mov    $0x36,%eax
L97:
  cmp    $0x9,%edi
  jne    L19
  mov    $0x39,%eax
  ret
L52:
  mov    $0x7a,%eax
  jmp    L27
L42:
  mov    $0x31,%eax
L27:
  cmp    $0x4,%edi
  jne    L10
  mov    $0x34,%eax
L0:
  cmp    $0x7,%edi
  jne    L22
  mov    $0x37,%eax
L19:
  test   %edi,%edi
  mov    $0x30,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
char selLet(int a) {
  int ris = 'z';
  if (a == 1)
    ris = '1';
  if (a == 2)
    ris = '2';
  if (a == 3)
    ris = '3';
  if (a == 4)
    ris = '4';
  if (a == 5)
    ris = '5';
  if (a == 6)
    ris = '6';
  if (a == 7)
    ris = '7';
  if (a == 8)
    ris = '8';
  if (a == 9)
    ris = '9';
  if (a == 0)
    ris = '0';
  return ris;
}
```
user: Translate the below assembly code into C programming language:

```asm
<selLet>:
  endbr64
  cmp    $0x1,%edi
  je     L2
  mov    $0x32,%eax
  cmp    $0x2,%edi
  jne    L97
  ret
  nopl   0x0(%rax)
L97:
  cmp    $0x3,%edi
  jne    L56
  mov    $0x33,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x31,%eax
  ret
L56:
  cmp    $0x4,%edi
  jne    L31
  mov    $0x34,%eax
  ret
L31:
  cmp    $0x5,%edi
  jne    L60
  mov    $0x35,%eax
  ret
L60:
  mov    $0x7a,%eax
  cmp    $0x6,%edi
  jne    L69
  mov    $0x36,%eax
  ret
L69:
  cmp    $0x7,%edi
  jne    L48
  mov    $0x37,%eax
  ret
L48:
  cmp    $0x8,%edi
  jne    L70
  mov    $0x38,%eax
  ret
L70:
  cmp    $0x9,%edi
  jne    L20
  mov    $0x39,%eax
  ret
L20:
  test   %edi,%edi
  jne    L96
  mov    $0x30,%eax
  ret
L96:
  ret
```

assistant: ```c
char selLet(int a) {
  int ris = 'z';
  if (a == 1)
    ris = '1';
  if (a == 2)
    ris = '2';
  if (a == 3)
    ris = '3';
  if (a == 4)
    ris = '4';
  if (a == 5)
    ris = '5';
  if (a == 6)
    ris = '6';
  if (a == 7)
    ris = '7';
  if (a == 8)
    ris = '8';
  if (a == 9)
    ris = '9';
  if (a == 0)
    ris = '0';
  return ris;
}
```
user: Translate the below assembly code into C programming language:

```asm
<selLet>:
  endbr64
  cmp    $0x1,%edi
  je     L87
  mov    $0x32,%eax
  cmp    $0x2,%edi
  jne    L72
  ret
  nopl   0x0(%rax)
L72:
  cmp    $0x3,%edi
  jne    L12
  mov    $0x33,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L87:
  mov    $0x31,%eax
  ret
L12:
  cmp    $0x4,%edi
  jne    L0
  mov    $0x34,%eax
  ret
L0:
  cmp    $0x5,%edi
  jne    L65
  mov    $0x35,%eax
  ret
L65:
  mov    $0x7a,%eax
  cmp    $0x6,%edi
  jne    L30
  mov    $0x36,%eax
  ret
L30:
  cmp    $0x7,%edi
  jne    L86
  mov    $0x37,%eax
  ret
L86:
  cmp    $0x8,%edi
  jne    L99
  mov    $0x38,%eax
  ret
L99:
  cmp    $0x9,%edi
  jne    L21
  mov    $0x39,%eax
  ret
L21:
  test   %edi,%edi
  jne    L82
  mov    $0x30,%eax
  ret
L82:
  ret
```

assistant: ```c
char selLet(int a) {
  int ris = 'z';
  if (a == 1)
    ris = '1';
  if (a == 2)
    ris = '2';
  if (a == 3)
    ris = '3';
  if (a == 4)
    ris = '4';
  if (a == 5)
    ris = '5';
  if (a == 6)
    ris = '6';
  if (a == 7)
    ris = '7';
  if (a == 8)
    ris = '8';
  if (a == 9)
    ris = '9';
  if (a == 0)
    ris = '0';
  return ris;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ilog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  test   %eax,%eax
  je     L54
  mov    $0x8,%eax
  jmp    L35
L54:
  mov    $0x0,%eax
L35:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  test   %eax,%eax
  je     L47
  mov    $0x4,%eax
  jmp    L11
L47:
  mov    $0x0,%eax
L11:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  test   %eax,%eax
  je     L36
  mov    $0x2,%eax
  jmp    L59
L36:
  mov    $0x0,%eax
L59:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    %eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ilog2(uint16_t x) {
  uint8_t result = 0;
  uint8_t num;
  num = (!!(x >> 8)) << 3;
  result = result + num;
  x = x >> num;
  num = (!!(x >> 4)) << 2;
  result = result + num;
  x = x >> num;
  num = (!!(x >> 2)) << 1;
  result = result + num;
  x = x >> num;
  num = !!(x >> 1);
  return result + num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ilog2>:
  endbr64
  mov    %edi,%eax
  shr    $0x8,%eax
  setne  %al
  movzbl %al,%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  sar    %cl,%edi
  mov    %edi,%esi
  shr    $0x4,%esi
  setne  %cl
  movzbl %cl,%ecx
  shl    $0x2,%ecx
  add    %ecx,%eax
  sar    %cl,%edi
  mov    %edi,%edx
  shr    $0x2,%edx
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%ecx
  sar    %cl,%edi
  shr    %edi
  setne  %dl
  movzbl %dl,%edx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int ilog2(uint16_t x) {
  uint8_t result = 0;
  uint8_t num;
  num = (!!(x >> 8)) << 3;
  result = result + num;
  x = x >> num;
  num = (!!(x >> 4)) << 2;
  result = result + num;
  x = x >> num;
  num = (!!(x >> 2)) << 1;
  result = result + num;
  x = x >> num;
  num = !!(x >> 1);
  return result + num;
}
```