ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L43
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L43:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  jne    L23
  jmp    L28
  nopl   0x0(%rax)
L33:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L28
L23:
  cmp    $0x2f,%al
  je     L75
  cmp    $0x5c,%al
  jne    L33
L75:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L23
L28:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L35
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L35:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  je     L67
  nopw   0x0(%rax,%rax,1)
L63:
  cmp    $0x2f,%al
  je     L74
  cmp    $0x5c,%al
  je     L74
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L63
L67:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L74:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L63
  jmp    L67
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_buffer_hex@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_push_aligned@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_push@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_realloc@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_slice@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_sha@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_hmac@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_pbkdf@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_buffer_hex();
  _memory_assert_empty();
  test_buffer_push_aligned();
  _memory_assert_empty();
  test_buffer_push();
  _memory_assert_empty();
  test_buffer_realloc();
  _memory_assert_empty();
  test_buffer_slice();
  _memory_assert_empty();
  test_sha();
  _memory_assert_empty();
  test_hmac();
  _memory_assert_empty();
  test_pbkdf();
  _memory_assert_empty();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_buffer_hex@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_push_aligned@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_push@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_realloc@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_buffer_slice@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_sha@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_hmac@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  call   <test_pbkdf@plt>
  mov    $0x0,%eax
  call   <_memory_assert_empty@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_buffer_hex();
  _memory_assert_empty();
  test_buffer_push_aligned();
  _memory_assert_empty();
  test_buffer_push();
  _memory_assert_empty();
  test_buffer_realloc();
  _memory_assert_empty();
  test_buffer_slice();
  _memory_assert_empty();
  test_sha();
  _memory_assert_empty();
  test_hmac();
  _memory_assert_empty();
  test_pbkdf();
  _memory_assert_empty();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_buffer_hex@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_push_aligned@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_push@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_realloc@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_slice@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_sha@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_hmac@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_pbkdf@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_buffer_hex();
  _memory_assert_empty();
  test_buffer_push_aligned();
  _memory_assert_empty();
  test_buffer_push();
  _memory_assert_empty();
  test_buffer_realloc();
  _memory_assert_empty();
  test_buffer_slice();
  _memory_assert_empty();
  test_sha();
  _memory_assert_empty();
  test_hmac();
  _memory_assert_empty();
  test_pbkdf();
  _memory_assert_empty();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_buffer_hex@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_push_aligned@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_push@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_realloc@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_buffer_slice@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_sha@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_hmac@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  call   <test_pbkdf@plt>
  xor    %eax,%eax
  call   <_memory_assert_empty@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_buffer_hex();
  _memory_assert_empty();
  test_buffer_push_aligned();
  _memory_assert_empty();
  test_buffer_push();
  _memory_assert_empty();
  test_buffer_realloc();
  _memory_assert_empty();
  test_buffer_slice();
  _memory_assert_empty();
  test_sha();
  _memory_assert_empty();
  test_hmac();
  _memory_assert_empty();
  test_pbkdf();
  _memory_assert_empty();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<radix_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L3:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int radix_len(int num) {
  int i;
  for (i = 1; num % (int)pow(10, i) != num; i++)
    ;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<radix_len>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%ebp
  jmp    L7
L4:
  add    $0x1,%ebp
L7:
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cmp    %ebx,%edx
  jne    L4
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int radix_len(int num) {
  int i;
  for (i = 1; num % (int)pow(10, i) != num; i++)
    ;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<radix_len>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopl   (%rax)
L14:
  add    $0x1,%r12d
L19:
  mov    %r12d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  cmp    %ebx,%edx
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int radix_len(int num) {
  int i;
  for (i = 1; num % (int)pow(10, i) != num; i++)
    ;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<radix_len>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L5
  nopl   (%rax)
L4:
  add    $0x1,%r12d
L5:
  mov    %r12d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  cmp    %ebx,%edx
  jne    L4
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int radix_len(int num) {
  int i;
  for (i = 1; num % (int)pow(10, i) != num; i++)
    ;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_elias_gamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L23
L37:
  mov    $0x0,%edi
  call   <write_bit@plt>
  shll   -0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L37
  jmp    L35
L26:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <write_bit@plt>
L35:
  sarl   -0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L26
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_elias_gamma(int value) {
  int i;
  for (i = 2; i <= value; i <<= 1) {
    write_bit(0);
  }
  while ((i >>= 1) > 0) {
    write_bit(value & i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_elias_gamma>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  cmp    $0x1,%edi
  jle    L1
  mov    $0x2,%ebx
L14:
  mov    $0x0,%edi
  call   <write_bit@plt>
  add    %ebx,%ebx
  cmp    %ebx,%ebp
  jge    L14
  sar    %ebx
L33:
  mov    %ebp,%edi
  and    %ebx,%edi
  call   <write_bit@plt>
  sar    %ebx
  test   %ebx,%ebx
  jg     L33
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  and    $0x1,%edi
  call   <write_bit@plt>
  jmp    L9
```

assistant: ```c
void write_elias_gamma(int value) {
  int i;
  for (i = 2; i <= value; i <<= 1) {
    write_bit(0);
  }
  while ((i >>= 1) > 0) {
    write_bit(value & i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_elias_gamma>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L18
  mov    $0x2,%ebx
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %edi,%edi
  add    %ebx,%ebx
  call   <write_bit@plt>
  cmp    %ebx,%ebp
  jge    L16
  sar    %ebx
  nop
L13:
  mov    %ebp,%edi
  and    %ebx,%edi
  call   <write_bit@plt>
  sar    %ebx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  and    $0x1,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <write_bit@plt>
```

assistant: ```c
void write_elias_gamma(int value) {
  int i;
  for (i = 2; i <= value; i <<= 1) {
    write_bit(0);
  }
  while ((i >>= 1) > 0) {
    write_bit(value & i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_elias_gamma>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L21
  mov    $0x2,%ebx
  cs nopw 0x0(%rax,%rax,1)
L22:
  xor    %edi,%edi
  add    %ebx,%ebx
  call   <write_bit@plt>
  cmp    %ebx,%ebp
  jge    L22
  sar    %ebx
  nop
L10:
  mov    %ebp,%edi
  and    %ebx,%edi
  call   <write_bit@plt>
  sar    %ebx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L21:
  add    $0x8,%rsp
  and    $0x1,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <write_bit@plt>
```

assistant: ```c
void write_elias_gamma(int value) {
  int i;
  for (i = 2; i <= value; i <<= 1) {
    write_bit(0);
  }
  while ((i >>= 1) > 0) {
    write_bit(value & i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x2,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L10
L11:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L10:
  cmpl   $0x31,-0x14(%rbp)
  jle    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D16: %lu, %lu

tool: D10: , %lu, %lu

assistant: ```c
int main() {
  unsigned long int f_prev = 2;
  unsigned long int s_prev = 1;
  int count;
  printf("%lu, %lu", f_prev, s_prev);
  for (count = 1; count <= 49; count++) {
    f_prev = f_prev + s_prev;
    s_prev = f_prev + s_prev;
    printf(", %lu, %lu", f_prev, s_prev);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x31,%r12d
  mov    $0x1,%ebp
  mov    $0x2,%ebx
  lea    D2(%rip),%r13
L6:
  add    %rbp,%rbx
  add    %rbx,%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string

tool: D1: %lu, %lu

tool: D2: , %lu, %lu

assistant: ```c
int main() {
  unsigned long int f_prev = 2;
  unsigned long int s_prev = 1;
  int count;
  printf("%lu, %lu", f_prev, s_prev);
  for (count = 1; count <= 49; count++) {
    f_prev = f_prev + s_prev;
    s_prev = f_prev + s_prev;
    printf(", %lu, %lu", f_prev, s_prev);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %r12
  lea    D10(%rip),%rdi
  mov    $0x31,%r12d
  lea    D15(%rip),%r13
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   (%rax)
L9:
  add    %rbp,%rbx
  xor    %eax,%eax
  mov    %r13,%rdi
  add    %rbx,%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D10: %lu, %lu

tool: D15: , %lu, %lu

assistant: ```c
int main() {
  unsigned long int f_prev = 2;
  unsigned long int s_prev = 1;
  int count;
  printf("%lu, %lu", f_prev, s_prev);
  for (count = 1; count <= 49; count++) {
    f_prev = f_prev + s_prev;
    s_prev = f_prev + s_prev;
    printf(", %lu, %lu", f_prev, s_prev);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %r12
  lea    D9(%rip),%rdi
  mov    $0x31,%r12d
  lea    D3(%rip),%r13
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   (%rax)
L2:
  add    %rbp,%rbx
  xor    %eax,%eax
  mov    %r13,%rdi
  add    %rbx,%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdx
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D9: %lu, %lu

tool: D3: , %lu, %lu

assistant: ```c
int main() {
  unsigned long int f_prev = 2;
  unsigned long int s_prev = 1;
  int count;
  printf("%lu, %lu", f_prev, s_prev);
  for (count = 1; count <= 49; count++) {
    f_prev = f_prev + s_prev;
    s_prev = f_prev + s_prev;
    printf(", %lu, %lu", f_prev, s_prev);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1000000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L15:
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x1000fff,-0xc(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(4096 * 4096);
  int i;
  for (i = 0; i < 4096 * 4097; i++) {
    x[i];
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000000,%edi
  call   <malloc@plt>
  mov    $0x1001000,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(4096 * 4096);
  int i;
  for (i = 0; i < 4096 * 4097; i++) {
    x[i];
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000000,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(4096 * 4096);
  int i;
  for (i = 0; i < 4096 * 4097; i++) {
    x[i];
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1000000,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(4096 * 4096);
  int i;
  for (i = 0; i < 4096 * 4097; i++) {
    x[i];
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L3:
  subl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x0,-0x10(%rbp)
  jne    L3
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L29
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
L29:
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int i, j;
  i = __VERIFIER_nondet_int();
  j = __VERIFIER_nondet_int();
  int x = i;
  int y = j;
  while (x != 0) {
    x--;
    y--;
  }
  if (i == j) {
    __VERIFIER_assert(y == 0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  je     L40
  mov    %ebx,%edx
L35:
  sub    $0x1,%edx
  jne    L35
  mov    %eax,%edx
  sub    %ebx,%edx
L44:
  cmp    %eax,%ebx
  je     L21
L6:
  pop    %rbx
  ret
L40:
  mov    %eax,%edx
  jmp    L44
L21:
  test   %edx,%edx
  sete   %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assert@plt>
  jmp    L6
```

assistant: ```c
void main() {
  int i, j;
  i = __VERIFIER_nondet_int();
  j = __VERIFIER_nondet_int();
  int x = i;
  int y = j;
  while (x != 0) {
    x--;
    y--;
  }
  if (i == j) {
    __VERIFIER_assert(y == 0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edx
  sub    %ebx,%edx
  test   %ebx,%ebx
  cmove  %eax,%edx
  cmp    %eax,%ebx
  je     L0
  pop    %rbx
  ret
L0:
  xor    %edi,%edi
  test   %edx,%edx
  pop    %rbx
  sete   %dil
  jmp    1060 <__VERIFIER_assert@plt>
```

assistant: ```c
void main() {
  int i, j;
  i = __VERIFIER_nondet_int();
  j = __VERIFIER_nondet_int();
  int x = i;
  int y = j;
  while (x != 0) {
    x--;
    y--;
  }
  if (i == j) {
    __VERIFIER_assert(y == 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edx
  sub    %ebx,%edx
  test   %ebx,%ebx
  cmove  %eax,%edx
  cmp    %eax,%ebx
  je     L0
  pop    %rbx
  ret
L0:
  xor    %edi,%edi
  test   %edx,%edx
  pop    %rbx
  sete   %dil
  jmp    1060 <__VERIFIER_assert@plt>
```

assistant: ```c
void main() {
  int i, j;
  i = __VERIFIER_nondet_int();
  j = __VERIFIER_nondet_int();
  int x = i;
  int y = j;
  while (x != 0) {
    x--;
    y--;
  }
  if (i == j) {
    __VERIFIER_assert(y == 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<TtlMarshal_uint16_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  movzbl %al,%eax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TtlMarshal_uint16_t(uint8_t **cursor, const uint16_t *x) {
  uint8_t *buffer = *cursor;
  uint16_t y = *x;
  buffer[0] = (uint8_t)(y >> 8);
  buffer[1] = (uint8_t)((y >> 0) & 0xff);
  *cursor += 2;
}
```