ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<SysCtlPWMClockGet>:
  endbr64
  sub    $0x8,%rsp
  mov    0x400fe010,%rdi
  and    $0x100000,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x400fe060,%rax
  and    $0x100000,%eax
  je     L0
  mov    0x400fe060,%rax
  and    $0x1e0000,%eax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long SysCtlPWMClockGet(void) {
  DEBUG_ASSERT((*((volatile unsigned long *)(0x400FE010))) & 0x00100000);
  if (!((*((volatile unsigned long *)(0x400FE060))) & 0x00100000)) {
    return (0x00000000);
  } else {
    return ((*((volatile unsigned long *)(0x400FE060))) & (0x00100000 | 0x000E0000));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SysCtlPWMClockGet>:
  endbr64
  sub    $0x8,%rsp
  mov    0x400fe010,%rdi
  and    $0x100000,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x400fe060,%rax
  and    $0x100000,%eax
  je     L5
  mov    0x400fe060,%rax
  and    $0x1e0000,%eax
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long SysCtlPWMClockGet(void) {
  DEBUG_ASSERT((*((volatile unsigned long *)(0x400FE010))) & 0x00100000);
  if (!((*((volatile unsigned long *)(0x400FE060))) & 0x00100000)) {
    return (0x00000000);
  } else {
    return ((*((volatile unsigned long *)(0x400FE060))) & (0x00100000 | 0x000E0000));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SysCtlPWMClockGet>:
  endbr64
  sub    $0x8,%rsp
  mov    0x400fe010,%rdi
  and    $0x100000,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x400fe060,%rax
  and    $0x100000,%eax
  je     L2
  mov    0x400fe060,%rax
  and    $0x1e0000,%eax
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long SysCtlPWMClockGet(void) {
  DEBUG_ASSERT((*((volatile unsigned long *)(0x400FE010))) & 0x00100000);
  if (!((*((volatile unsigned long *)(0x400FE060))) & 0x00100000)) {
    return (0x00000000);
  } else {
    return ((*((volatile unsigned long *)(0x400FE060))) & (0x00100000 | 0x000E0000));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_get_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L14
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x3c,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L13
L14:
  movl   $0x30,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else {
    rval = '0';
  }
  return (char)(rval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L1
  sub    $0x1,%edx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  mov    $0x3c,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L1:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else {
    rval = '0';
  }
  return (char)(rval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L1
  sub    $0x1,%edx
  mov    $0x3c,%ecx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L1:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else {
    rval = '0';
  }
  return (char)(rval);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_get_digit>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x30,%eax
  test   %edx,%edx
  jle    L3
  sub    $0x1,%edx
  mov    $0x3c,%ecx
  mov    %edx,(%rsi)
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,(%rdi)
  sar    %cl,%eax
  and    $0xf,%eax
  add    $0x30,%eax
L3:
  ret
```

assistant: ```c
char _get_digit(uint64_t *fr, int *digit_count) {
  int rval;
  if (*digit_count > 0) {
    *digit_count -= 1;
    *fr = *fr * 10;
    rval = ((*fr >> 60) & 0xF) + '0';
    *fr &= 0x0FFFFFFFFFFFFFFFull;
  } else {
    rval = '0';
  }
  return (char)(rval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <__print_float@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: f32

tool: D4: 9.13

assistant: ```c
int main() {
  float a;
  a = 9.13;
  __print_float(a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D0(%rip),%xmm0
  call   <__print_float@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: f32

tool: D0: 9.13

assistant: ```c
int main() {
  float a;
  a = 9.13;
  __print_float(a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D3(%rip),%xmm0
  call   <__print_float@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: f32

tool: D3: 9.13

assistant: ```c
int main() {
  float a;
  a = 9.13;
  __print_float(a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D0(%rip),%xmm0
  call   <__print_float@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: f32

tool: D0: 9.13

assistant: ```c
int main() {
  float a;
  a = 9.13;
  __print_float(a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x30(%rbp),%eax
  mov    $0x1,%r8d
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <dcopy@plt>
  cmpl   $0x1,-0x1c(%rbp)
  jle    L28
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x30(%rbp),%eax
  mov    $0x1,%r8d
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <dcopy@plt>
L28:
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L2:
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r8d
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <dcopy@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void pack(const double *datain, const int nzin, double *dataout, const int nzout, const int nrep, const int psize) {
  const int nmode = nzin >> 1;
  const int msize = psize << 1;
  int i;
  dcopy(psize, datain, 1, dataout, 1);
  if (nzin > 1)
    dcopy(psize, datain + psize, 1, dataout + psize, 1);
  for (i = 1; i < nmode; i++)
    dcopy(msize, datain + i * msize, 1, dataout + i * nrep * msize, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %r8d,0x8(%rsp)
  mov    %r9d,%r12d
  mov    %esi,%r15d
  sar    %r15d
  lea    (%r9,%r9,1),%r14d
  mov    $0x1,%r8d
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rdi,%rsi
  mov    %r9d,%edi
  call   <dcopy@plt>
  cmp    $0x1,%r13d
  jg     L37
L23:
  cmp    $0x1,%r15d
  jle    L9
  movslq %r14d,%r13
  shl    $0x3,%r13
  add    %r13,%rbp
  mov    0x8(%rsp),%eax
  imul   %r14d,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  add    %rax,%rbx
  mov    $0x1,%r12d
L4:
  mov    $0x1,%r8d
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  call   <dcopy@plt>
  add    $0x1,%r12d
  add    %r13,%rbp
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r15d
  jne    L4
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  movslq %r12d,%rsi
  shl    $0x3,%rsi
  lea    (%rbx,%rsi,1),%rcx
  add    %rbp,%rsi
  mov    $0x1,%r8d
  mov    $0x1,%edx
  mov    %r12d,%edi
  call   <dcopy@plt>
  jmp    L23
```

assistant: ```c
void pack(const double *datain, const int nzin, double *dataout, const int nzout, const int nrep, const int psize) {
  const int nmode = nzin >> 1;
  const int msize = psize << 1;
  int i;
  dcopy(psize, datain, 1, dataout, 1);
  if (nzin > 1)
    dcopy(psize, datain + psize, 1, dataout + psize, 1);
  for (i = 1; i < nmode; i++)
    dcopy(msize, datain + i * msize, 1, dataout + i * nrep * msize, 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pack>:
  endbr64
  push   %r15
  mov    %esi,%eax
  mov    %esi,%r15d
  mov    %rdx,%rcx
  push   %r14
  sar    %eax
  mov    %rdi,%rsi
  lea    (%r9,%r9,1),%r14d
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %r8d,%r12d
  mov    $0x1,%r8d
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x1,%edx
  push   %rbx
  mov    %rdi,%rbx
  mov    %r9d,%edi
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  call   <dcopy@plt>
  cmp    $0x1,%r15d
  jle    L10
  movslq %r13d,%rsi
  mov    $0x1,%r8d
  mov    $0x1,%edx
  mov    %r13d,%edi
  shl    $0x3,%rsi
  lea    0x0(%rbp,%rsi,1),%rcx
  add    %rbx,%rsi
  call   <dcopy@plt>
L10:
  cmpl   $0x1,0xc(%rsp)
  jle    L2
  imul   %r14d,%r12d
  movslq %r14d,%r13
  mov    $0x1,%r15d
  shl    $0x3,%r13
  add    %r13,%rbx
  movslq %r12d,%r12
  shl    $0x3,%r12
  add    %r12,%rbp
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    $0x1,%r8d
  mov    %r14d,%edi
  mov    $0x1,%edx
  add    $0x1,%r15d
  add    %r13,%rbx
  add    %r12,%rbp
  call   <dcopy@plt>
  cmp    %r15d,0xc(%rsp)
  jne    L28
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pack(const double *datain, const int nzin, double *dataout, const int nzout, const int nrep, const int psize) {
  const int nmode = nzin >> 1;
  const int msize = psize << 1;
  int i;
  dcopy(psize, datain, 1, dataout, 1);
  if (nzin > 1)
    dcopy(psize, datain + psize, 1, dataout + psize, 1);
  for (i = 1; i < nmode; i++)
    dcopy(msize, datain + i * msize, 1, dataout + i * nrep * msize, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pack>:
  endbr64
  push   %r15
  mov    %esi,%eax
  mov    %esi,%r15d
  mov    %rdx,%rcx
  push   %r14
  sar    %eax
  mov    %rdi,%rsi
  lea    (%r9,%r9,1),%r14d
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %r8d,%r12d
  mov    $0x1,%r8d
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x1,%edx
  push   %rbx
  mov    %rdi,%rbx
  mov    %r9d,%edi
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  call   <dcopy@plt>
  cmp    $0x1,%r15d
  jle    L19
  movslq %r13d,%rsi
  mov    $0x1,%r8d
  mov    $0x1,%edx
  mov    %r13d,%edi
  shl    $0x3,%rsi
  lea    0x0(%rbp,%rsi,1),%rcx
  add    %rbx,%rsi
  call   <dcopy@plt>
L19:
  cmpl   $0x1,0xc(%rsp)
  jle    L2
  imul   %r14d,%r12d
  movslq %r14d,%r13
  mov    $0x1,%r15d
  shl    $0x3,%r13
  add    %r13,%rbx
  movslq %r12d,%r12
  shl    $0x3,%r12
  add    %r12,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    $0x1,%r8d
  mov    %r14d,%edi
  mov    $0x1,%edx
  add    $0x1,%r15d
  add    %r13,%rbx
  add    %r12,%rbp
  call   <dcopy@plt>
  cmp    %r15d,0xc(%rsp)
  jne    L18
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pack(const double *datain, const int nzin, double *dataout, const int nzout, const int nrep, const int psize) {
  const int nmode = nzin >> 1;
  const int msize = psize << 1;
  int i;
  dcopy(psize, datain, 1, dataout, 1);
  if (nzin > 1)
    dcopy(psize, datain + psize, 1, dataout + psize, 1);
  for (i = 1; i < nmode; i++)
    dcopy(msize, datain + i * msize, 1, dataout + i * nrep * msize, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gf8mul_00011101>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm2
  pxor   %xmm6,%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm1
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm0
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm2
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gf8mul_00011101(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm6, %xmm1\n"
                       "\tpxor    %xmm6, %xmm0\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm2\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gf8mul_00011101>:
  endbr64
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm2
  pxor   %xmm6,%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm1
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm0
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm2
  ret
```

assistant: ```c
void gf8mul_00011101(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm6, %xmm1\n"
                       "\tpxor    %xmm6, %xmm0\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm2\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<gf8mul_00011101>:
  endbr64
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm2
  pxor   %xmm6,%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm1
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm0
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm2
  ret
```

assistant: ```c
void gf8mul_00011101(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm6, %xmm1\n"
                       "\tpxor    %xmm6, %xmm0\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm2\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gf8mul_00011101>:
  endbr64
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm2
  pxor   %xmm7,%xmm1
  pxor   %xmm6,%xmm2
  pxor   %xmm6,%xmm1
  pxor   %xmm6,%xmm0
  pxor   %xmm5,%xmm7
  pxor   %xmm5,%xmm1
  pxor   %xmm5,%xmm0
  pxor   %xmm4,%xmm7
  pxor   %xmm4,%xmm6
  pxor   %xmm4,%xmm0
  pxor   %xmm3,%xmm7
  pxor   %xmm3,%xmm6
  pxor   %xmm3,%xmm5
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm4
  pxor   %xmm1,%xmm5
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm3
  pxor   %xmm0,%xmm4
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm2
  ret
```

assistant: ```c
void gf8mul_00011101(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm2\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm6, %xmm2\n"
                       "\tpxor    %xmm6, %xmm1\n"
                       "\tpxor    %xmm6, %xmm0\n"
                       "\tpxor    %xmm5, %xmm7\n"
                       "\tpxor    %xmm5, %xmm1\n"
                       "\tpxor    %xmm5, %xmm0\n"
                       "\tpxor    %xmm4, %xmm7\n"
                       "\tpxor    %xmm4, %xmm6\n"
                       "\tpxor    %xmm4, %xmm0\n"
                       "\tpxor    %xmm3, %xmm7\n"
                       "\tpxor    %xmm3, %xmm6\n"
                       "\tpxor    %xmm3, %xmm5\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm4\n"
                       "\tpxor    %xmm1, %xmm5\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm3\n"
                       "\tpxor    %xmm0, %xmm4\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm2\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <isEmptyDynArr@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <topDynArr@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <popDynArr@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <topDynArr@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <popDynArr@plt>
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <pushDynArr@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: Solution: %f


assistant: ```c
void divide(struct DynArr *stack) {
  assert(!isEmptyDynArr(stack));
  double num1, num2, sum;
  num1 = topDynArr(stack);
  popDynArr(stack);
  num2 = topDynArr(stack);
  popDynArr(stack);
  sum = num2 / num1;
  pushDynArr(stack, sum);
  printf("Solution: %f\n", sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<divide>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <isEmptyDynArr@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <topDynArr@plt>
  movq   %xmm0,%r14
  mov    %rbx,%rdi
  call   <popDynArr@plt>
  mov    %rbx,%rdi
  call   <topDynArr@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rdi
  call   <popDynArr@plt>
  movq   %rbp,%xmm1
  movq   %r14,%xmm2
  divsd  %xmm2,%xmm1
  movq   %xmm1,%rbp
  movapd %xmm1,%xmm0
  mov    %rbx,%rdi
  call   <pushDynArr@plt>
  movq   %rbp,%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D0: Solution: %f


assistant: ```c
void divide(struct DynArr *stack) {
  assert(!isEmptyDynArr(stack));
  double num1, num2, sum;
  num1 = topDynArr(stack);
  popDynArr(stack);
  num2 = topDynArr(stack);
  popDynArr(stack);
  sum = num2 / num1;
  pushDynArr(stack, sum);
  printf("Solution: %f\n", sum);
}
```