ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebp
  mov    %rsp,%rbx
  jmp    L27
L24:
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
L27:
  mov    $0x1000,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L24
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void copy(int fd) {
  char buf[4096];
  int c;
  while (c = read(fd, buf, sizeof(buf)))
    write(2, buf, c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L75
L38:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  movl   $0x1,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L3:
  cmpb   $0x20,-0x15(%rbp)
  jne    L64
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L64:
  movl   $0x1,-0x10(%rbp)
L16:
  cmpl   $0x13,-0x14(%rbp)
  jg     L36
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L17
L36:
  cmpl   $0x0,-0x10(%rbp)
  je     L65
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L65:
  cmpl   $0x0,-0xc(%rbp)
  je     L17
  subl   $0x14,-0x14(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L17:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
L75:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x15(%rbp)
  mov    D4(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x15(%rbp)
  jne    L38
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  char c;
  int current_char = 0;
  int is_char = 0;
  int is_blank = 0;
  int is_first = 0;
  int word_length = 0;
  while ((c = getchar()) != EOF) {
    current_char++;
    word_length++;
    if (is_first == 0) {
      is_first = 1;
      putchar('\n');
    }
    if (c == ' ') {
      is_blank = 1;
      word_length = 0;
    } else {
      is_char = 1;
    }
    if (current_char < 20) {
      putchar(c);
    } else {
      if (is_char) {
        putchar(c);
      }
      if (is_blank) {
        current_char -= 20;
        putchar('\n');
      }
    }
    is_blank = 0;
    is_char = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  mov    $0x1,%r12d
  jmp    L43
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L85
L78:
  movsbl %bl,%edi
  call   <putchar@plt>
  mov    %ebp,%r14d
L5:
  mov    %r12d,%r13d
L43:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %bl,(%rax)
  je     L10
  lea    0x1(%r14),%ebp
  test   %r13d,%r13d
  je     L32
L85:
  cmp    $0x20,%bl
  je     L64
  cmp    $0x13,%ebp
  jg     L78
L65:
  movsbl %bl,%edi
  call   <putchar@plt>
  mov    %ebp,%r14d
  jmp    L5
L64:
  cmp    $0x13,%ebp
  jle    L65
  sub    $0x13,%r14d
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L5
L10:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main() {
  char c;
  int current_char = 0;
  int is_char = 0;
  int is_blank = 0;
  int is_first = 0;
  int word_length = 0;
  while ((c = getchar()) != EOF) {
    current_char++;
    word_length++;
    if (is_first == 0) {
      is_first = 1;
      putchar('\n');
    }
    if (c == ' ') {
      is_blank = 1;
      word_length = 0;
    } else {
      is_char = 1;
    }
    if (current_char < 20) {
      putchar(c);
    } else {
      if (is_char) {
        putchar(c);
      }
      if (is_blank) {
        current_char -= 20;
        putchar('\n');
      }
    }
    is_blank = 0;
    is_char = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    D6(%rip),%r12
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r12)
  je     L36
  nopl   0x0(%rax,%rax,1)
L65:
  lea    0x1(%r13),%ebp
  test   %r14d,%r14d
  je     L37
L11:
  cmp    $0x20,%bl
  je     L12
L52:
  movsbl %bl,%edi
  mov    %ebp,%r13d
  call   <putchar@plt>
L8:
  xor    %eax,%eax
  mov    $0x1,%r14d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r12)
  jne    L65
L36:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L12:
  cmp    $0x13,%ebp
  jle    L52
  mov    $0xa,%edi
  sub    $0x13,%r13d
  call   <putchar@plt>
  jmp    L8
  nopl   (%rax)
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L11
```

assistant: ```c
int main() {
  char c;
  int current_char = 0;
  int is_char = 0;
  int is_blank = 0;
  int is_first = 0;
  int word_length = 0;
  while ((c = getchar()) != EOF) {
    current_char++;
    word_length++;
    if (is_first == 0) {
      is_first = 1;
      putchar('\n');
    }
    if (c == ' ') {
      is_blank = 1;
      word_length = 0;
    } else {
      is_char = 1;
    }
    if (current_char < 20) {
      putchar(c);
    } else {
      if (is_char) {
        putchar(c);
      }
      if (is_blank) {
        current_char -= 20;
        putchar('\n');
      }
    }
    is_blank = 0;
    is_char = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    D6(%rip),%r12
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r12)
  je     L47
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x1(%r13),%ebp
  test   %r14d,%r14d
  je     L5
L10:
  cmp    $0x20,%bl
  je     L18
L49:
  movsbl %bl,%edi
  mov    %ebp,%r13d
  call   <putchar@plt>
L1:
  xor    %eax,%eax
  mov    $0x1,%r14d
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %al,(%r12)
  jne    L0
L47:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  cmp    $0x13,%ebp
  jle    L49
  mov    $0xa,%edi
  sub    $0x13,%r13d
  call   <putchar@plt>
  jmp    L1
  nopl   (%rax)
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L10
```

assistant: ```c
int main() {
  char c;
  int current_char = 0;
  int is_char = 0;
  int is_blank = 0;
  int is_first = 0;
  int word_length = 0;
  while ((c = getchar()) != EOF) {
    current_char++;
    word_length++;
    if (is_first == 0) {
      is_first = 1;
      putchar('\n');
    }
    if (c == ' ') {
      is_blank = 1;
      word_length = 0;
    } else {
      is_char = 1;
    }
    if (current_char < 20) {
      putchar(c);
    } else {
      if (is_char) {
        putchar(c);
      }
      if (is_blank) {
        current_char -= 20;
        putchar('\n');
      }
    }
    is_blank = 0;
    is_char = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transfer_RGB888_to_ABGR8888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0xff,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl 0x2(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl 0x1(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_RGB888_to_ABGR8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = 0xff;
  *(*output)++ = input[2];
  *(*output)++ = input[1];
  *(*output)++ = input[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transfer_RGB888_to_ABGR8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void transfer_RGB888_to_ABGR8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = 0xff;
  *(*output)++ = input[2];
  *(*output)++ = input[1];
  *(*output)++ = input[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transfer_RGB888_to_ABGR8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void transfer_RGB888_to_ABGR8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = 0xff;
  *(*output)++ = input[2];
  *(*output)++ = input[1];
  *(*output)++ = input[0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<transfer_RGB888_to_ABGR8888>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movb   $0xff,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl 0x1(%rsi),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void transfer_RGB888_to_ABGR8888(unsigned char *(*output), unsigned char *input) {
  *(*output)++ = 0xff;
  *(*output)++ = input[2];
  *(*output)++ = input[1];
  *(*output)++ = input[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<ex2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x94(%rbp)
  jmp    L18
L14:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x60(%rbp),%rdx
  mov    -0x94(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x90(%rbp,%rax,4),%xmm0
  mov    -0x94(%rbp),%eax
  cltq
  movss  -0x60(%rbp,%rax,4),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x94(%rbp),%eax
  cltq
  movss  %xmm0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L18:
  cmpl   $0x9,-0x94(%rbp)
  jle    L14
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    -0x60(%rbp),%rcx
  lea    -0x90(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <printSub@plt>
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D43
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string

tool: D48: Digite um numero(VETOR A): 

tool: D43: %f

tool: D15: Digite um numero(VETOR B): 

tool: D9: clear

assistant: ```c
void ex2() {
  float a[10], b[10], dif[10];
  for (int k = 0; k < 10; k++) {
    printf("Digite um numero(VETOR A): ");
    scanf("%f", &a[k]);
    printf("Digite um numero(VETOR B): ");
    scanf("%f", &b[k]);
    dif[k] = a[k] - b[k];
  }
  system("clear");
  printSub(a, b, 10);
  printArray(dif, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ex2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D12(%rip),%r15
  lea    D26(%rip),%r13
  lea    D21(%rip),%r14
  lea    0x30(%rsp),%r12
L7:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  lea    (%r12,%rbx,1),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movss  0x0(%rbp),%xmm0
  subss  (%rbx,%r12,1),%xmm0
  movss  %xmm0,0x60(%rsp,%rbx,1)
  add    $0x4,%rbp
  add    $0x4,%rbx
  cmp    $0x28,%rbx
  jne    L7
  lea    D20(%rip),%rdi
  call   <system@plt>
  lea    0x30(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0xa,%edx
  call   <printSub@plt>
  lea    0x60(%rsp),%rdi
  mov    $0xa,%esi
  call   <printArray@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
datatype: string
name: read_data
arguments: data_label: D26
datatype: string
name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D20
datatype: string

tool: D12: Digite um numero(VETOR A): 

tool: D26: %f

tool: D21: Digite um numero(VETOR B): 

tool: D20: clear

assistant: ```c
void ex2() {
  float a[10], b[10], dif[10];
  for (int k = 0; k < 10; k++) {
    printf("Digite um numero(VETOR A): ");
    scanf("%f", &a[k]);
    printf("Digite um numero(VETOR B): ");
    scanf("%f", &b[k]);
    dif[k] = a[k] - b[k];
  }
  system("clear");
  printSub(a, b, 10);
  printArray(dif, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ex2>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  lea    D32(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x70(%rsp),%rax
  mov    %r12,0x8(%rsp)
  lea    0x40(%rsp),%rbp
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%r15,1),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  -0x4(%r12),%xmm0
  mov    (%rsp),%rax
  subss  0x0(%rbp,%r15,1),%xmm0
  movss  %xmm0,(%rax,%r15,1)
  add    $0x4,%r15
  cmp    $0x28,%r15
  jne    L14
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  mov    $0xa,%edx
  call   <printSub@plt>
  mov    (%rsp),%rdi
  mov    $0xa,%esi
  call   <printArray@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D32
type: string
name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D9
type: string
name: parse_data
arguments: tag: D14
type: string

tool: D32: Digite um numero(VETOR A): 

tool: D13: Digite um numero(VETOR B): 

tool: D9: %f

tool: D14: clear

assistant: ```c
void ex2() {
  float a[10], b[10], dif[10];
  for (int k = 0; k < 10; k++) {
    printf("Digite um numero(VETOR A): ");
    scanf("%f", &a[k]);
    printf("Digite um numero(VETOR B): ");
    scanf("%f", &b[k]);
    dif[k] = a[k] - b[k];
  }
  system("clear");
  printSub(a, b, 10);
  printArray(dif, 10);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ex2>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D20(%rip),%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x70(%rsp),%rax
  mov    %r12,0x8(%rsp)
  lea    0x40(%rsp),%rbp
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%r15,1),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  -0x4(%r12),%xmm0
  mov    (%rsp),%rax
  subss  0x0(%rbp,%r15,1),%xmm0
  movss  %xmm0,(%rax,%r15,1)
  add    $0x4,%r15
  cmp    $0x28,%r15
  jne    L11
  lea    D33(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  mov    $0xa,%edx
  call   <printSub@plt>
  mov    (%rsp),%rdi
  mov    $0xa,%esi
  call   <printArray@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D20
data_type: string
name: unpack_data
arguments: data_tag: D33
data_type: string

tool: D13: Digite um numero(VETOR A): 

tool: D26: Digite um numero(VETOR B): 

tool: D20: %f

tool: D33: clear

assistant: ```c
void ex2() {
  float a[10], b[10], dif[10];
  for (int k = 0; k < 10; k++) {
    printf("Digite um numero(VETOR A): ");
    scanf("%f", &a[k]);
    printf("Digite um numero(VETOR B): ");
    scanf("%f", &b[k]);
    dif[k] = a[k] - b[k];
  }
  system("clear");
  printSub(a, b, 10);
  printArray(dif, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sigandset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L19:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  and    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x20(%rbp)
L12:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  shr    $0x3,%rax
  cmp    %rax,-0x20(%rbp)
  jb     L19
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sigandset(sigset_t *dest, const sigset_t *left, const sigset_t *right) {
  unsigned long i = 0, *d = (void *)dest, *l = (void *)left, *r = (void *)right;
  for (; i < (_NSIG / 8 / sizeof(long)); i++)
    d[i] = l[i] & r[i];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sigandset>:
  endbr64
  mov    %rdx,%r8
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  lea    0x7(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x3,%eax
  cltq
  cmp    $0x7,%rax
  jbe    L2
  mov    $0x0,%edx
  mov    D17(%rip),%r9
L3:
  mov    (%rsi,%rdx,8),%rax
  and    (%r8,%rdx,8),%rax
  mov    %rax,(%rdi,%rdx,8)
  add    $0x1,%rdx
  mov    (%r9),%ecx
  lea    0x7(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x3,%eax
  cltq
  shr    $0x3,%rax
  cmp    %rdx,%rax
  ja     L3
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sigandset(sigset_t *dest, const sigset_t *left, const sigset_t *right) {
  unsigned long i = 0, *d = (void *)dest, *l = (void *)left, *r = (void *)right;
  for (; i < (_NSIG / 8 / sizeof(long)); i++)
    d[i] = l[i] & r[i];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sigandset>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rdi,%r8
  mov    (%rax),%eax
  test   %eax,%eax
  lea    0x7(%rax),%edi
  cmovns %eax,%edi
  sar    $0x3,%edi
  movslq %edi,%rdi
  shr    $0x3,%rdi
  je     L13
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rsi,%rax,8),%rcx
  and    (%rdx,%rax,8),%rcx
  mov    %rcx,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L15
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sigandset(sigset_t *dest, const sigset_t *left, const sigset_t *right) {
  unsigned long i = 0, *d = (void *)dest, *l = (void *)left, *r = (void *)right;
  for (; i < (_NSIG / 8 / sizeof(long)); i++)
    d[i] = l[i] & r[i];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sigandset>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rdx,%r8
  mov    (%rax),%eax
  test   %eax,%eax
  lea    0x7(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x3,%ecx
  movslq %ecx,%rcx
  mov    %rcx,%r9
  shr    $0x3,%r9
  je     L23
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %dl
  cmp    %rax,%rdi
  setne  %al
  test   %al,%dl
  je     L42
  lea    -0x1(%r9),%rax
  cmp    $0x1,%rax
  jbe    L42
  mov    %rcx,%rdx
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rcx
  shr    $0x4,%rdx
  cs nopw 0x0(%rax,%rax,1)
L11:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%r8,%rax,1),%xmm1
  pand   %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L11
  lea    (%rdx,%rdx,1),%rax
  cmp    %rax,%r9
  je     L23
  mov    %rdx,%rax
  shl    $0x4,%rax
  mov    (%rsi,%rax,1),%rdx
  and    (%r8,%rax,1),%rdx
  mov    %rdx,(%rdi,%rax,1)
L23:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rsi,%rax,8),%rdx
  and    (%r8,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L15
  xor    %eax,%eax
  ret
```

assistant: ```c
int sigandset(sigset_t *dest, const sigset_t *left, const sigset_t *right) {
  unsigned long i = 0, *d = (void *)dest, *l = (void *)left, *r = (void *)right;
  for (; i < (_NSIG / 8 / sizeof(long)); i++)
    d[i] = l[i] & r[i];
  return 0;
}
```