ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<partition>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r8d
  lea    -0x1(%rsi),%r10d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r12
  mov    (%r12),%esi
  movslq %r8d,%rax
  lea    (%rdi,%rax,4),%r9
  jmp    L37
L0:
  cmp    %edx,%r10d
  jge    L28
  mov    %ecx,(%rbx)
  mov    %r11d,(%rdi)
L38:
  add    $0x4,%r9
L37:
  add    $0x1,%r10d
  mov    %r9,%rbx
  mov    (%r9),%r11d
  cmp    %esi,%r11d
  jl     L38
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L10:
  sub    $0x1,%edx
  mov    %rax,%rdi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  cmp    %edx,%r8d
  je     L0
  cmp    %esi,%ecx
  jg     L10
  jmp    L0
L28:
  mov    (%r12),%eax
  mov    %eax,(%rbx)
  mov    %r11d,(%r12)
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int partition(int *a, int l, int r) {
  int v;
  int t;
  int i, j;
  i = l - 1;
  j = r;
  v = a[r];
  while (1) {
    while (a[++i] < v)
      ;
    while (a[--j] > v) {
      if (j == l)
        break;
    }
    if (i >= j)
      break;
    {
      (t) = (a[i]);
      (a[i]) = (a[j]);
      (a[j]) = (t);
    };
  }
  {
    (t) = (a[i]);
    (a[i]) = (a[r]);
    (a[r]) = (t);
  };
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  movslq %edx,%rax
  push   %rbp
  movslq %esi,%rcx
  lea    -0x1(%rsi),%r10d
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x0(%rbp),%edi
  lea    (%rbx,%rcx,4),%r9
  xchg   %ax,%ax
L35:
  mov    (%r9),%r11d
  add    $0x1,%r10d
  cmp    %edi,%r11d
  jl     L16
  lea    -0x4(%rbx,%rax,4),%rax
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L3:
  cmp    %edi,%ecx
  jle    L18
L19:
  sub    $0x1,%edx
  mov    (%rax),%ecx
  mov    %rax,%r8
  sub    $0x4,%rax
  cmp    %edx,%esi
  jne    L3
L18:
  cmp    %edx,%r10d
  jge    L25
  mov    %ecx,(%r9)
  movslq %edx,%rax
  mov    %r11d,(%r8)
L16:
  add    $0x4,%r9
  jmp    L35
L25:
  mov    0x0(%rbp),%eax
  mov    %eax,(%r9)
  mov    %r10d,%eax
  mov    %r11d,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int partition(int *a, int l, int r) {
  int v;
  int t;
  int i, j;
  i = l - 1;
  j = r;
  v = a[r];
  while (1) {
    while (a[++i] < v)
      ;
    while (a[--j] > v) {
      if (j == l)
        break;
    }
    if (i >= j)
      break;
    {
      (t) = (a[i]);
      (a[i]) = (a[j]);
      (a[j]) = (t);
    };
  }
  {
    (t) = (a[i]);
    (a[i]) = (a[r]);
    (a[r]) = (t);
  };
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  movslq %edx,%rax
  push   %rbp
  movslq %esi,%rcx
  lea    -0x1(%rsi),%r10d
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x0(%rbp),%edi
  lea    (%rbx,%rcx,4),%r9
  xchg   %ax,%ax
L30:
  mov    (%r9),%r11d
  add    $0x1,%r10d
  cmp    %edi,%r11d
  jl     L59
  lea    -0x4(%rbx,%rax,4),%rax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    %edi,%ecx
  jle    L38
L34:
  sub    $0x1,%edx
  mov    (%rax),%ecx
  mov    %rax,%r8
  sub    $0x4,%rax
  cmp    %edx,%esi
  jne    L19
L38:
  cmp    %edx,%r10d
  jge    L28
  mov    %ecx,(%r9)
  movslq %edx,%rax
  mov    %r11d,(%r8)
L59:
  add    $0x4,%r9
  jmp    L30
L28:
  mov    0x0(%rbp),%eax
  mov    %eax,(%r9)
  mov    %r10d,%eax
  mov    %r11d,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int partition(int *a, int l, int r) {
  int v;
  int t;
  int i, j;
  i = l - 1;
  j = r;
  v = a[r];
  while (1) {
    while (a[++i] < v)
      ;
    while (a[--j] > v) {
      if (j == l)
        break;
    }
    if (i >= j)
      break;
    {
      (t) = (a[i]);
      (a[i]) = (a[j]);
      (a[j]) = (t);
    };
  }
  {
    (t) = (a[i]);
    (a[i]) = (a[r]);
    (a[r]) = (t);
  };
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fifo_get_fifo_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D26(%rip),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9: /tmp/fifo_%d

assistant: ```c
char *fifo_get_fifo_filename(pid_t pid) {
  static char fifo_filename[128];
  sprintf(fifo_filename, "/tmp/fifo_%d", pid);
  return fifo_filename;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fifo_get_fifo_filename>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  lea    D7(%rip),%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: /tmp/fifo_%d

assistant: ```c
char *fifo_get_fifo_filename(pid_t pid) {
  static char fifo_filename[128];
  sprintf(fifo_filename, "/tmp/fifo_%d", pid);
  return fifo_filename;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fifo_get_fifo_filename>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    %edi,%edx
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: string

tool: D14: /tmp/fifo_%d

assistant: ```c
char *fifo_get_fifo_filename(pid_t pid) {
  static char fifo_filename[128];
  sprintf(fifo_filename, "/tmp/fifo_%d", pid);
  return fifo_filename;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fifo_get_fifo_filename>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  mov    %edi,%edx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: /tmp/fifo_%d

assistant: ```c
char *fifo_get_fifo_filename(pid_t pid) {
  static char fifo_filename[128];
  sprintf(fifo_filename, "/tmp/fifo_%d", pid);
  return fifo_filename;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L6:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xff,-0x4(%rbp)
  jle    L6
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: %d.	%c


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 256; i++)
    printf("%d.\t%c\n", i, i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: %d.	%c


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 256; i++)
    printf("%d.\t%c\n", i, i);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: %d.	%c


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 256; i++)
    printf("%d.\t%c\n", i, i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: %d.	%c


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 256; i++)
    printf("%d.\t%c\n", i, i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<timespec_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  add    %rax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x10(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  movsd  D1(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: f64

tool: D1: 1000000000

assistant: ```c
double timespec_diff(struct timespec const *ts0, struct timespec const *ts1) {
  time_t diff_sec;
  long diff_nsec;
  diff_sec = ts1->tv_sec - ts0->tv_sec;
  diff_nsec += ts1->tv_nsec - ts0->tv_nsec;
  return ((double)diff_sec) + (((double)diff_nsec) / 1.0e9);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timespec_diff>:
  endbr64
  mov    (%rsi),%rax
  sub    (%rdi),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D8(%rip),%xmm0
  mov    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: f64

tool: D8: 1000000000

assistant: ```c
double timespec_diff(struct timespec const *ts0, struct timespec const *ts1) {
  time_t diff_sec;
  long diff_nsec;
  diff_sec = ts1->tv_sec - ts0->tv_sec;
  diff_nsec += ts1->tv_nsec - ts0->tv_nsec;
  return ((double)diff_sec) + (((double)diff_nsec) / 1.0e9);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<timespec_diff>:
  endbr64
  mov    (%rsi),%rax
  pxor   %xmm0,%xmm0
  sub    (%rdi),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mov    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  divsd  D6(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: f64

tool: D6: 1000000000

assistant: ```c
double timespec_diff(struct timespec const *ts0, struct timespec const *ts1) {
  time_t diff_sec;
  long diff_nsec;
  diff_sec = ts1->tv_sec - ts0->tv_sec;
  diff_nsec += ts1->tv_nsec - ts0->tv_nsec;
  return ((double)diff_sec) + (((double)diff_nsec) / 1.0e9);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<timespec_diff>:
  endbr64
  mov    (%rsi),%rax
  pxor   %xmm0,%xmm0
  sub    (%rdi),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mov    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  divsd  D5(%rip),%xmm0
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: f64

tool: D5: 1000000000

assistant: ```c
double timespec_diff(struct timespec const *ts0, struct timespec const *ts1) {
  time_t diff_sec;
  long diff_nsec;
  diff_sec = ts1->tv_sec - ts0->tv_sec;
  diff_nsec += ts1->tv_nsec - ts0->tv_nsec;
  return ((double)diff_sec) + (((double)diff_nsec) / 1.0e9);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ho2roLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  movq   $0x3,-0x20(%rbp)
  movq   $0x4,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L10
L13:
  mov    -0x28(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <ho2ro@plt>
  mov    %eax,-0x2c(%rbp)
  addq   $0x1,-0x28(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L13
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int ho2roLoop(double *ho, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, hostep = 3, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(hostep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * hostep;
    iOut = i * rostep;
    trash = ho2ro(&(ho[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ho2roLoop>:
  endbr64
  test   %rdx,%rdx
  je     L19
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%r14d
L6:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <ho2ro@plt>
  add    $0x1,%r14
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L6
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ho2roLoop(double *ho, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, hostep = 3, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(hostep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * hostep;
    iOut = i * rostep;
    trash = ho2ro(&(ho[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ho2roLoop>:
  endbr64
  test   %rdx,%rdx
  je     L3
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  call   <ho2ro@plt>
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L0
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ho2roLoop(double *ho, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, hostep = 3, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(hostep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * hostep;
    iOut = i * rostep;
    trash = ho2ro(&(ho[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ho2roLoop>:
  endbr64
  test   %rdx,%rdx
  je     L16
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  call   <ho2ro@plt>
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L14
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ho2roLoop(double *ho, double *ro, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, hostep = 3, rostep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(hostep, rostep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * hostep;
    iOut = i * rostep;
    trash = ho2ro(&(ho[iIn]), &(ro[iOut]), p);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basic_test>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <pd_random@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pd_write_doubles@plt>
  lea    0x30(%rsp),%r13
  mov    %r13,%rdi
  call   <pd_random@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <pd_write_doubles@plt>
  lea    0x60(%rsp),%rbx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <pd_add@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pd_write_doubles@plt>
  lea    0x90(%rsp),%r12
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pd_sub@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <pd_write_doubles@plt>
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <pd_mul@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pd_write_doubles@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pd_div@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <pd_write_doubles@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
datatype: string
name: read_data
arguments: tag: D33
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D51
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D64
datatype: string
name: read_data
arguments: tag: D42
datatype: string

tool: D19: Testing some basic operations ...


tool: D33: the first random number a :


tool: D18: the second random number b :


tool: D51: a+b :


tool: D22: a+b-a :


tool: D64: a*b :


tool: D42: a*b/a :


assistant: ```c
int basic_test(void) {
  double a[5], b[5], c[5], d[5];
  printf("Testing some basic operations ...\n");
  srand(time(NULL));
  pd_random(a);
  printf("the first random number a :\n");
  pd_write_doubles(a);
  pd_random(b);
  printf("the second random number b :\n");
  pd_write_doubles(b);
  pd_add(a, b, c);
  printf("a+b :\n");
  pd_write_doubles(c);
  pd_sub(c, a, d);
  printf("a+b-a :\n");
  pd_write_doubles(d);
  pd_mul(a, b, c);
  printf("a*b :\n");
  pd_write_doubles(c);
  pd_div(c, a, d);
  printf("a*b/a :\n");
  pd_write_doubles(d);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<basic_test>:
  endbr64
  push   %r14
  lea    D60(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%r14
  lea    0x60(%rsp),%rbp
  call   <printf@plt>
  xor    %edi,%edi
  lea    0x90(%rsp),%r13
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %r12,%rdi
  call   <pd_random@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <pd_write_doubles@plt>
  mov    %r14,%rdi
  call   <pd_random@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <pd_write_doubles@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <pd_add@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pd_write_doubles@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pd_sub@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <pd_write_doubles@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <pd_mul@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pd_write_doubles@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pd_div@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <pd_write_doubles@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D60
type_infered: string
name: read_data
arguments: data_tag: D47
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D49
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string

tool: D60: Testing some basic operations ...


tool: D47: the first random number a :


tool: D2: the second random number b :


tool: D20: a+b :


tool: D21: a+b-a :


tool: D49: a*b :


tool: D14: a*b/a :


assistant: ```c
int basic_test(void) {
  double a[5], b[5], c[5], d[5];
  printf("Testing some basic operations ...\n");
  srand(time(NULL));
  pd_random(a);
  printf("the first random number a :\n");
  pd_write_doubles(a);
  pd_random(b);
  printf("the second random number b :\n");
  pd_write_doubles(b);
  pd_add(a, b, c);
  printf("a+b :\n");
  pd_write_doubles(c);
  pd_sub(c, a, d);
  printf("a+b-a :\n");
  pd_write_doubles(d);
  pd_mul(a, b, c);
  printf("a*b :\n");
  pd_write_doubles(c);
  pd_div(c, a, d);
  printf("a*b/a :\n");
  pd_write_doubles(d);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<basic_test>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%r14
  lea    0x60(%rsp),%rbp
  call   <printf@plt>
  xor    %edi,%edi
  lea    0x90(%rsp),%r13
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %r12,%rdi
  call   <pd_random@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <pd_write_doubles@plt>
  mov    %r14,%rdi
  call   <pd_random@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <pd_write_doubles@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <pd_add@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pd_write_doubles@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pd_sub@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <pd_write_doubles@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <pd_mul@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pd_write_doubles@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <pd_div@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <pd_write_doubles@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D69
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D60
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D15: Testing some basic operations ...


tool: D69: the first random number a :


tool: D5: the second random number b :


tool: D7: a+b :


tool: D60: a+b-a :


tool: D24: a*b :


tool: D11: a*b/a :


assistant: ```c
int basic_test(void) {
  double a[5], b[5], c[5], d[5];
  printf("Testing some basic operations ...\n");
  srand(time(NULL));
  pd_random(a);
  printf("the first random number a :\n");
  pd_write_doubles(a);
  pd_random(b);
  printf("the second random number b :\n");
  pd_write_doubles(b);
  pd_add(a, b, c);
  printf("a+b :\n");
  pd_write_doubles(c);
  pd_sub(c, a, d);
  printf("a+b-a :\n");
  pd_write_doubles(d);
  pd_mul(a, b, c);
  printf("a*b :\n");
  pd_write_doubles(c);
  pd_div(c, a, d);
  printf("a*b/a :\n");
  pd_write_doubles(d);
  return 0;
}
```