ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L42
  mov    $0x4,%ebx
  mov    $0x1,%ebp
  lea    D3(%rip),%r12
L37:
  lea    0x1a0(%rsp,%rbx,1),%rdx
  lea    0x10(%rsp,%rbx,1),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0xc(%rsp),%eax
  add    $0x4,%rbx
  cmp    %ebp,%eax
  jge    L37
  test   %eax,%eax
  jle    L42
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    D42(%rip),%r12
L27:
  movss  0x10(%rsp,%rbx,4),%xmm1
  subss  0x4(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %ebp,%xmm2
  movaps %xmm1,%xmm0
  divss  %xmm2,%xmm0
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  movd   %xmm3,%r14d
  movss  0x1a0(%rsp,%rbx,4),%xmm1
  subss  0x8(%rsp),%xmm1
  movaps %xmm1,%xmm0
  divss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  movd   %xmm0,%r15d
  movaps %xmm3,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    %ebp,%ebp
  movd   %r14d,%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  movd   %r15d,%xmm0
  addss  0x8(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L27
L42:
  movss  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x340,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D42
type: string
name: read_data
arguments: label: D16
type: string

tool: D17: %d

tool: D3: %f %f

tool: D42: %.1f %.1f 


tool: D16: %.1f %.1f


assistant: ```c
int main() {
  float pacman_coordinate_x = 0, pacman_coordinate_y = 0, nacepin_x[100], nacepin_y[100], vector_x, vector_y;
  int counter, pacman_mas = 1, number_of_nacepin;
  scanf("%d", &number_of_nacepin);
  scanf("%f %f", &pacman_coordinate_x, &pacman_coordinate_y);
  for (counter = 1; counter <= number_of_nacepin; counter++) {
    scanf("%f %f", &nacepin_x[counter], &nacepin_y[counter]);
  }
  for (counter = 1; counter <= number_of_nacepin; counter++) {
    vector_x = (nacepin_x[counter] - pacman_coordinate_x) + (nacepin_x[counter] - pacman_coordinate_x) / pacman_mas;
    vector_y = (nacepin_y[counter] - pacman_coordinate_y) + (nacepin_y[counter] - pacman_coordinate_y) / pacman_mas;
    printf("%.1f %.1f \n", vector_x, vector_y);
    pacman_mas *= 2;
    pacman_coordinate_x += vector_x;
    pacman_coordinate_y += vector_y;
  }
  printf("%.1f %.1f\n", pacman_coordinate_x, pacman_coordinate_y);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cleanup_game>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  call   <cleanup_player@plt>
  mov    $0x0,%eax
  call   <cleanup_zombies@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cleanup_game(void) {
  cleanup_screen();
  cleanup_player();
  cleanup_zombies();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cleanup_game>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  call   <cleanup_player@plt>
  mov    $0x0,%eax
  call   <cleanup_zombies@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cleanup_game(void) {
  cleanup_screen();
  cleanup_player();
  cleanup_zombies();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cleanup_game>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  call   <cleanup_player@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cleanup_zombies@plt>
```

assistant: ```c
void cleanup_game(void) {
  cleanup_screen();
  cleanup_player();
  cleanup_zombies();
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup_game>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  call   <cleanup_player@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cleanup_zombies@plt>
```

assistant: ```c
void cleanup_game(void) {
  cleanup_screen();
  cleanup_player();
  cleanup_zombies();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BFS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%esi
  mov    %r8d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%r15
  shl    $0x2,%r15
  lea    0xf(%r15),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L24:
  cmp    %rdx,%rsp
  je     L154
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L154:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L162
  orq    $0x0,-0x8(%rsp,%rax,1)
L162:
  mov    %rsp,%rdx
  lea    0xf(%r15),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdi
  sub    %rax,%rdi
L167:
  cmp    %rdi,%rsp
  je     L92
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L167
L92:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L134
  orq    $0x0,-0x8(%rsp,%rax,1)
L134:
  lea    0x3(%rsp),%r14
  mov    %r14,%rdi
  shr    $0x2,%rdi
  and    $0xfffffffffffffffc,%r14
  test   %ebx,%ebx
  jle    L69
  mov    %rdx,%rax
  mov    %ebx,%ecx
  lea    (%rdx,%rcx,4),%rcx
L41:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L41
L69:
  mov    %esi,0x0(,%rdi,4)
  movslq %esi,%rsi
  movl   $0x0,(%rdx,%rsi,4)
  movl   $0xffffffff,0x0(%r13,%rsi,4)
  mov    $0xffffffffffffffff,%r11
  mov    $0x0,%edi
  mov    %ebx,%r8d
  jmp    L141
L3:
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L107
L35:
  cmpl   $0x0,(%rdx,%rax,4)
  je     L3
  cmpl   $0x0,(%rsi,%rax,4)
  jle    L3
  add    $0x1,%edi
  movslq %edi,%r9
  mov    %eax,(%r14,%r9,4)
  movl   $0x0,(%rdx,%rax,4)
  mov    %r10d,0x0(%r13,%rax,4)
  jmp    L3
L107:
  add    $0x1,%r11
  cmp    %r11d,%edi
  jle    L127
L141:
  mov    0x4(%r14,%r11,4),%r10d
  test   %ebx,%ebx
  jle    L107
  movslq %r10d,%rsi
  imul   %r15,%rsi
  add    %r12,%rsi
  mov    $0x0,%eax
  jmp    L35
L127:
  movslq -0x44(%rbp),%rax
  cmpl   $0x0,(%rdx,%rax,4)
  sete   %al
  movzbl %al,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BFS(int n, int rG[n][n], int parent[n], int S, int T) {
  int visited[n], Queue[n], front = -1, rear = -1;
  for (int i = 0; i < n; i++) {
    visited[i] = 1;
  }
  Queue[++rear] = S;
  visited[S] = 0;
  parent[S] = -1;
  while (front < rear) {
    int u = Queue[++front];
    for (int v = 0; v < n; v++) {
      if (visited[v] && rG[u][v] > 0) {
        Queue[++rear] = v;
        visited[v] = 0;
        parent[v] = u;
      }
    }
  }
  return !visited[T];
}
```
user: Translate the below assembly code into C programming language:

```asm
<BFS>:
  endbr64
  push   %rbp
  mov    %ecx,%r9d
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  movslq %edi,%rsi
  push   %rbx
  lea    0x0(,%rsi,4),%r8
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(%r8),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rcx
  cmp    %rcx,%rsp
  je     L96
L119:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L119
L96:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L154
L125:
  mov    %rax,%rcx
  mov    %rsp,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L11
L74:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L74
L11:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L24
L0:
  lea    0x3(%rsp),%r11
  mov    %r11,%rdi
  and    $0xfffffffffffffffc,%r11
  shr    $0x2,%rdi
  test   %ebx,%ebx
  jle    L100
  mov    %ebx,%ecx
  mov    %rdx,%rax
  lea    (%rdx,%rcx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L14:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L14
L100:
  movslq %r9d,%rax
  mov    %r9d,0x0(,%rdi,4)
  xor    %r10d,%r10d
  xor    %edi,%edi
  movl   $0x0,(%rdx,%rax,4)
  movl   $0xffffffff,0x0(%r13,%rax,4)
  nopw   0x0(%rax,%rax,1)
L34:
  test   %ebx,%ebx
  jle    L147
  movslq %r9d,%rcx
  xor    %eax,%eax
  imul   %r8,%rcx
  add    %r12,%rcx
L60:
  mov    (%rdx,%rax,4),%r15d
  test   %r15d,%r15d
  je     L138
  mov    (%rcx,%rax,4),%r15d
  test   %r15d,%r15d
  jle    L138
  add    $0x1,%edi
  movl   $0x0,(%rdx,%rax,4)
  movslq %edi,%r15
  mov    %r9d,0x0(%r13,%rax,4)
  mov    %eax,(%r11,%r15,4)
L138:
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L60
L147:
  cmp    %r10d,%edi
  jle    L149
  mov    0x4(%r11,%r10,4),%r9d
  add    $0x1,%r10
  jmp    L34
L154:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L125
  nopl   0x0(%rax)
L149:
  mov    (%rdx,%r14,4),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L114
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L24:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L0
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BFS(int n, int rG[n][n], int parent[n], int S, int T) {
  int visited[n], Queue[n], front = -1, rear = -1;
  for (int i = 0; i < n; i++) {
    visited[i] = 1;
  }
  Queue[++rear] = S;
  visited[S] = 0;
  parent[S] = -1;
  while (front < rear) {
    int u = Queue[++front];
    for (int v = 0; v < n; v++) {
      if (visited[v] && rG[u][v] > 0) {
        Queue[++rear] = v;
        visited[v] = 0;
        parent[v] = u;
      }
    }
  }
  return !visited[T];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  unsigned int nbytes = nmemb * size;
  void *p = malloc(nbytes);
  memset(p, 0, nbytes);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  imul   %esi,%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  unsigned int nbytes = nmemb * size;
  void *p = malloc(nbytes);
  memset(p, 0, nbytes);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  imul   %esi,%r13d
  sub    $0x8,%rsp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  unsigned int nbytes = nmemb * size;
  void *p = malloc(nbytes);
  memset(p, 0, nbytes);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  imul   %esi,%r13d
  sub    $0x8,%rsp
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  unsigned int nbytes = nmemb * size;
  void *p = malloc(nbytes);
  memset(p, 0, nbytes);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverseString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x20,-0x1(%rbp)
  jmp    L0
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverseString(char *a, char *b) {
  char temp = ' ';
  while (a < b) {
    temp = *a;
    *a = *b;
    *b = temp;
    a++;
    b--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverseString>:
  endbr64
  cmp    %rsi,%rdi
  jae    L13
L2:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmp    %rsi,%rdi
  jb     L2
L13:
  ret
```

assistant: ```c
void reverseString(char *a, char *b) {
  char temp = ' ';
  while (a < b) {
    temp = *a;
    *a = *b;
    *b = temp;
    a++;
    b--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverseString>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L0:
  cmp    %rsi,%rdi
  jb     L17
  ret
```

assistant: ```c
void reverseString(char *a, char *b) {
  char temp = ' ';
  while (a < b) {
    temp = *a;
    *a = *b;
    *b = temp;
    a++;
    b--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverseString>:
  endbr64
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L14:
  cmp    %rsi,%rdi
  jb     L18
  ret
```

assistant: ```c
void reverseString(char *a, char *b) {
  char temp = ' ';
  while (a < b) {
    temp = *a;
    *a = *b;
    *b = temp;
    a++;
    b--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simplify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L65
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L81
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x1(%rax),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L121
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L90
  mov    %rbx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  test   %rax,%rax
  jne    L110
L102:
  movb   $0x0,(%rcx)
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L6
  mov    %rbx,%rdi
  call   <free@plt>
L81:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    %rdi,%rbp
  jmp    L81
L121:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rbp
  jmp    L81
L90:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L81
L59:
  lea    -0x1(%rsi),%edx
L21:
  add    $0x1,%edx
  movslq %edx,%rsi
  cmp    %rax,%rsi
  jae    L102
L110:
  add    $0x1,%rcx
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,-0x1(%rcx)
  cmp    $0x2f,%sil
  jne    L21
  lea    0x1(%rdx),%esi
  movslq %esi,%rdi
  cmpb   $0x2f,(%rbx,%rdi,1)
  jne    L59
  add    $0x2,%edx
  movslq %edx,%rdx
L108:
  mov    %edx,%esi
  add    $0x1,%rdx
  cmpb   $0x2f,-0x1(%rbx,%rdx,1)
  je     L108
  jmp    L59
L6:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L81
```

assistant: ```c
char *simplify(const char *str) {
  int i;
  size_t mbPathlen;
  size_t wcPathlen;
  wchar_t *wptr;
  wchar_t *wcPath;
  char *mbPath;
  if (!str) {
    errno = ENOENT;
    return (NULL);
  }
  if ((mbPath = strdup(str)) == NULL) {
    return (NULL);
  }
  mbPathlen = strlen(mbPath);
  if ((wcPath = calloc(sizeof(wchar_t), mbPathlen + 1)) == NULL) {
    free(mbPath);
    return (NULL);
  }
  if ((wcPathlen = mbstowcs(wcPath, mbPath, mbPathlen)) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  for (wptr = wcPath, i = 0; i < wcPathlen; i++) {
    *wptr++ = wcPath[i];
    if (wcPath[i] == '/') {
      i++;
      while (wcPath[i] == '/') {
        i++;
      }
      i--;
    }
  }
  *wptr = '\0';
  if (wcstombs(mbPath, wcPath, mbPathlen) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  free(wcPath);
  return (mbPath);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<simplify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L62
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L60
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%rsi
  mov    %rax,%r13
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L93
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L119
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %ecx,%ecx
  test   %rax,%rax
  jne    L86
  jmp    L83
  xchg   %ax,%ax
L98:
  mov    %r8d,%esi
  cmp    %rcx,%rax
  jbe    L83
L86:
  movzbl 0x0(%rbp,%rcx,1),%edx
  lea    0x1(%rsi),%r8d
  add    $0x1,%rdi
  movslq %r8d,%rcx
  mov    %dl,-0x1(%rdi)
  cmp    $0x2f,%dl
  jne    L98
  cmpb   $0x2f,0x0(%rbp,%rcx,1)
  jne    L98
  add    $0x2,%esi
  movslq %esi,%rdx
  nopl   (%rax)
L46:
  mov    %edx,%esi
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x2f,-0x1(%rbp,%rdx,1)
  je     L46
  cmp    %rcx,%rax
  ja     L86
  nopl   (%rax)
L83:
  movb   $0x0,(%rdi)
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L119
  mov    %rbp,%rdi
  call   <free@plt>
L60:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  mov    D14(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L119:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L93:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L60
```

assistant: ```c
char *simplify(const char *str) {
  int i;
  size_t mbPathlen;
  size_t wcPathlen;
  wchar_t *wptr;
  wchar_t *wcPath;
  char *mbPath;
  if (!str) {
    errno = ENOENT;
    return (NULL);
  }
  if ((mbPath = strdup(str)) == NULL) {
    return (NULL);
  }
  mbPathlen = strlen(mbPath);
  if ((wcPath = calloc(sizeof(wchar_t), mbPathlen + 1)) == NULL) {
    free(mbPath);
    return (NULL);
  }
  if ((wcPathlen = mbstowcs(wcPath, mbPath, mbPathlen)) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  for (wptr = wcPath, i = 0; i < wcPathlen; i++) {
    *wptr++ = wcPath[i];
    if (wcPath[i] == '/') {
      i++;
      while (wcPath[i] == '/') {
        i++;
      }
      i--;
    }
  }
  *wptr = '\0';
  if (wcstombs(mbPath, wcPath, mbPathlen) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  free(wcPath);
  return (mbPath);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simplify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L102
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%rsi
  mov    %rax,%r13
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L33
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <mbstowcs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L58
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %ecx,%ecx
  test   %rax,%rax
  jne    L1
  jmp    L35
  xchg   %ax,%ax
L27:
  mov    %r8d,%esi
  cmp    %rcx,%rax
  jbe    L35
L1:
  movzbl 0x0(%rbp,%rcx,1),%edx
  lea    0x1(%rsi),%r8d
  add    $0x1,%rdi
  movslq %r8d,%rcx
  mov    %dl,-0x1(%rdi)
  cmp    $0x2f,%dl
  jne    L27
  cmpb   $0x2f,0x0(%rbp,%rcx,1)
  jne    L27
  add    $0x2,%esi
  movslq %esi,%rdx
  nopl   (%rax)
L87:
  mov    %edx,%esi
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x2f,-0x1(%rbp,%rdx,1)
  je     L87
  cmp    %rcx,%rax
  ja     L1
  nopl   (%rax)
L35:
  movb   $0x0,(%rdi)
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <wcstombs@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L58
  mov    %rbp,%rdi
  call   <free@plt>
L0:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L102:
  mov    D12(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L58:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L0
```

assistant: ```c
char *simplify(const char *str) {
  int i;
  size_t mbPathlen;
  size_t wcPathlen;
  wchar_t *wptr;
  wchar_t *wcPath;
  char *mbPath;
  if (!str) {
    errno = ENOENT;
    return (NULL);
  }
  if ((mbPath = strdup(str)) == NULL) {
    return (NULL);
  }
  mbPathlen = strlen(mbPath);
  if ((wcPath = calloc(sizeof(wchar_t), mbPathlen + 1)) == NULL) {
    free(mbPath);
    return (NULL);
  }
  if ((wcPathlen = mbstowcs(wcPath, mbPath, mbPathlen)) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  for (wptr = wcPath, i = 0; i < wcPathlen; i++) {
    *wptr++ = wcPath[i];
    if (wcPath[i] == '/') {
      i++;
      while (wcPath[i] == '/') {
        i++;
      }
      i--;
    }
  }
  *wptr = '\0';
  if (wcstombs(mbPath, wcPath, mbPathlen) == (size_t)-1) {
    free(mbPath);
    free(wcPath);
    return (NULL);
  }
  free(wcPath);
  return (mbPath);
}
```