ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_map_sub>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_map_lakes@plt>
  xor    %eax,%eax
  call   <init_map_types4@plt>
  xor    %eax,%eax
  call   <init_map_desert@plt>
  xor    %eax,%eax
  call   <init_map_desert_2@plt>
  xor    %eax,%eax
  call   <init_map_crosses@plt>
  xor    %eax,%eax
  call   <init_map_trees_1@plt>
  xor    %eax,%eax
  call   <init_map_trees_2@plt>
  xor    %eax,%eax
  call   <init_map_trees_3@plt>
  xor    %eax,%eax
  call   <init_map_trees_4@plt>
  xor    %eax,%eax
  call   <init_map_stone_1@plt>
  xor    %eax,%eax
  call   <init_map_stone_2@plt>
  xor    %eax,%eax
  call   <init_map_dead_trees@plt>
  xor    %eax,%eax
  call   <init_map_large_boulders@plt>
  xor    %eax,%eax
  call   <init_map_water_trees@plt>
  xor    %eax,%eax
  call   <init_map_stubs@plt>
  xor    %eax,%eax
  call   <init_map_small_boulders@plt>
  xor    %eax,%eax
  call   <init_map_cadavers@plt>
  xor    %eax,%eax
  call   <init_map_cacti@plt>
  xor    %eax,%eax
  call   <init_map_water_stones@plt>
  xor    %eax,%eax
  call   <init_map_palms@plt>
  xor    %eax,%eax
  call   <init_map_resources@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11c0 <init_map_clean_up@plt>
```

assistant: ```c
void init_map_sub() {
  init_map_lakes();
  init_map_types4();
  init_map_desert();
  init_map_desert_2();
  init_map_crosses();
  init_map_trees_1();
  init_map_trees_2();
  init_map_trees_3();
  init_map_trees_4();
  init_map_stone_1();
  init_map_stone_2();
  init_map_dead_trees();
  init_map_large_boulders();
  init_map_water_trees();
  init_map_stubs();
  init_map_small_boulders();
  init_map_cadavers();
  init_map_cacti();
  init_map_water_stones();
  init_map_palms();
  init_map_resources();
  init_map_clean_up();
}
```
user: What is the c source code of the assembly code below?

```asm
<init_map_sub>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_map_lakes@plt>
  xor    %eax,%eax
  call   <init_map_types4@plt>
  xor    %eax,%eax
  call   <init_map_desert@plt>
  xor    %eax,%eax
  call   <init_map_desert_2@plt>
  xor    %eax,%eax
  call   <init_map_crosses@plt>
  xor    %eax,%eax
  call   <init_map_trees_1@plt>
  xor    %eax,%eax
  call   <init_map_trees_2@plt>
  xor    %eax,%eax
  call   <init_map_trees_3@plt>
  xor    %eax,%eax
  call   <init_map_trees_4@plt>
  xor    %eax,%eax
  call   <init_map_stone_1@plt>
  xor    %eax,%eax
  call   <init_map_stone_2@plt>
  xor    %eax,%eax
  call   <init_map_dead_trees@plt>
  xor    %eax,%eax
  call   <init_map_large_boulders@plt>
  xor    %eax,%eax
  call   <init_map_water_trees@plt>
  xor    %eax,%eax
  call   <init_map_stubs@plt>
  xor    %eax,%eax
  call   <init_map_small_boulders@plt>
  xor    %eax,%eax
  call   <init_map_cadavers@plt>
  xor    %eax,%eax
  call   <init_map_cacti@plt>
  xor    %eax,%eax
  call   <init_map_water_stones@plt>
  xor    %eax,%eax
  call   <init_map_palms@plt>
  xor    %eax,%eax
  call   <init_map_resources@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11c0 <init_map_clean_up@plt>
```

assistant: ```c
void init_map_sub() {
  init_map_lakes();
  init_map_types4();
  init_map_desert();
  init_map_desert_2();
  init_map_crosses();
  init_map_trees_1();
  init_map_trees_2();
  init_map_trees_3();
  init_map_trees_4();
  init_map_stone_1();
  init_map_stone_2();
  init_map_dead_trees();
  init_map_large_boulders();
  init_map_water_trees();
  init_map_stubs();
  init_map_small_boulders();
  init_map_cadavers();
  init_map_cacti();
  init_map_water_stones();
  init_map_palms();
  init_map_resources();
  init_map_clean_up();
}
```
user: What is the c source code of the assembly code below?

```asm
<atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  jmp    L70
L24:
  add    $0x1,%rax
L70:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L24
  movzbl (%rax),%edx
  cmp    $0x9,%dl
  je     L24
  movq   $0x0,-0x8(%rbp)
  movb   $0x0,-0x9(%rbp)
  movzbl (%rax),%edx
  cmp    $0x2d,%dl
  jne    L2
  movzbl -0x9(%rbp),%edx
  add    $0x1,%edx
  mov    %dl,-0x9(%rbp)
  add    $0x1,%rax
  jmp    L2
L31:
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    %rdx,%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    $0x30,%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  mov    %rdx,-0x8(%rbp)
L2:
  movzbl (%rax),%edx
  movsbl %dl,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L31
  cmpb   $0x0,-0x9(%rbp)
  je     L23
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L52
L23:
  mov    -0x8(%rbp),%rax
L52:
  pop    %rbp
  ret
```

assistant: ```c
long atol(s)
register char *s;
{
  long a;
  unsigned char sign;
  while (*s == ' ' || *s == '\t')
    s++;
  a = 0;
  sign = 0;
  if (*s == '-') {
    sign++;
    s++;
  }
  while (isdigit(*s))
    a = a * 10L + (*s++ - '0');
  if (sign)
    return -a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L43
  cmp    $0x9,%al
  jne    L73
L43:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L43
  cmp    $0x9,%al
  je     L43
L73:
  mov    $0x0,%esi
  cmp    $0x2d,%al
  je     L30
L57:
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  mov    $0x0,%ecx
  cmp    $0x9,%edx
  ja     L9
L58:
  lea    (%rcx,%rcx,4),%rdx
  add    $0x1,%rdi
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rcx
  movzbl (%rdi),%eax
  movsbl %al,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  jbe    L58
L9:
  mov    %rcx,%rax
  neg    %rax
  test   %sil,%sil
  cmovne %rax,%rcx
  mov    %rcx,%rax
  ret
L30:
  add    $0x1,%rdi
  mov    $0x1,%esi
  jmp    L57
```

assistant: ```c
long atol(s)
register char *s;
{
  long a;
  unsigned char sign;
  while (*s == ' ' || *s == '\t')
    s++;
  a = 0;
  sign = 0;
  if (*s == '-') {
    sign++;
    s++;
  }
  while (isdigit(*s))
    a = a * 10L + (*s++ - '0');
  if (sign)
    return -a;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atol>:
  endbr64
  jmp    L75
  cs nopw 0x0(%rax,%rax,1)
L57:
  add    $0x1,%rdi
L75:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L57
  cmp    $0x9,%al
  je     L57
  cmp    $0x2d,%al
  je     L68
  movsbl (%rdi),%eax
  xor    %ecx,%ecx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L64
L44:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L25:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  cltq
  lea    (%rax,%rdx,2),%r8
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L25
  mov    %r8,%rax
  neg    %rax
  test   %cl,%cl
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L68:
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L64
  mov    %rcx,%rdi
  mov    $0x1,%ecx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L64:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long atol(s)
register char *s;
{
  long a;
  unsigned char sign;
  while (*s == ' ' || *s == '\t')
    s++;
  a = 0;
  sign = 0;
  if (*s == '-') {
    sign++;
    s++;
  }
  while (isdigit(*s))
    a = a * 10L + (*s++ - '0');
  if (sign)
    return -a;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atol>:
  endbr64
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L68:
  add    $0x1,%rdi
L37:
  movsbl (%rdi),%eax
  cmp    $0x20,%al
  je     L68
  cmp    $0x9,%al
  je     L68
  cmp    $0x2d,%al
  je     L3
  lea    -0x30(%rax),%edx
  xor    %ecx,%ecx
  cmp    $0x9,%edx
  ja     L57
L45:
  xor    %r8d,%r8d
L41:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rdx
  add    $0x1,%rdi
  cltq
  lea    (%rax,%rdx,2),%r8
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L41
  mov    %r8,%rax
  neg    %rax
  test   %cl,%cl
  cmovne %rax,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L3:
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L57
  mov    %rcx,%rdi
  mov    $0x1,%ecx
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L57:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long atol(s)
register char *s;
{
  long a;
  unsigned char sign;
  while (*s == ' ' || *s == '\t')
    s++;
  a = 0;
  sign = 0;
  if (*s == '-') {
    sign++;
    s++;
  }
  while (isdigit(*s))
    a = a * 10L + (*s++ - '0');
  if (sign)
    return -a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ninety_degree_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L16
L36:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L30:
  mov    -0x2c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L30
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L36
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **ninety_degree_conv(char **before, int n) {
  char **p;
  char *tem;
  int i, j;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * (n));
    for (j = 0; j < n; ++j) {
      tem[j] = before[n - j - 1][i];
    }
    p[i] = tem;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ninety_degree_conv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  movslq %esi,%r14
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %r13d,%r13d
  jle    L11
  mov    %rax,%rbp
  mov    %r13d,%r12d
  lea    (%rbx,%r14,8),%r14
  mov    $0x0,%ebx
L12:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  lea    (%rax,%r12,1),%rdi
  mov    %r14,%rcx
L22:
  mov    -0x8(%rcx),%rsi
  movzbl (%rsi,%rbx,1),%esi
  mov    %sil,(%rdx)
  sub    $0x8,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L22
  mov    %rax,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L12
L11:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ninety_degree_conv(char **before, int n) {
  char **p;
  char *tem;
  int i, j;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * (n));
    for (j = 0; j < n; ++j) {
      tem[j] = before[n - j - 1][i];
    }
    p[i] = tem;
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ninety_degree_conv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  lea    0x0(,%rbx,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L24
  mov    %rbx,%rbp
  mov    %rax,%r15
  lea    (%r12,%rbx,8),%r12
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%rdi
  nopl   0x0(%rax)
L11:
  mov    -0x8(%rcx),%rsi
  add    $0x1,%rdx
  sub    $0x8,%rcx
  movzbl (%rsi,%r14,1),%esi
  mov    %sil,-0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L11
  add    $0x1,%r14
  mov    %rax,(%r15)
  add    $0x8,%r15
  cmp    %rbx,%r14
  jne    L7
L24:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ninety_degree_conv(char **before, int n) {
  char **p;
  char *tem;
  int i, j;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * (n));
    for (j = 0; j < n; ++j) {
      tem[j] = before[n - j - 1][i];
    }
    p[i] = tem;
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ninety_degree_conv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  lea    0x0(,%rbx,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L15
  mov    %rbx,%rbp
  mov    %rax,%r15
  lea    (%r12,%rbx,8),%r12
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%rdi
  nopl   0x0(%rax)
L2:
  mov    -0x8(%rcx),%rsi
  add    $0x1,%rdx
  sub    $0x8,%rcx
  movzbl (%rsi,%r14,1),%esi
  mov    %sil,-0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L2
  add    $0x1,%r14
  mov    %rax,(%r15)
  add    $0x8,%r15
  cmp    %rbx,%r14
  jne    L20
L15:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ninety_degree_conv(char **before, int n) {
  char **p;
  char *tem;
  int i, j;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * (n));
    for (j = 0; j < n; ++j) {
      tem[j] = before[n - j - 1][i];
    }
    p[i] = tem;
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <append_filter_prefix@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_stdio_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_open_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_memory_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_rpath_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_cpath_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_dpath_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_inet_filter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <append_dns_filter@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <append_filter_suffix@plt>
  nop
  leave
  ret
```

assistant: ```c
void fill_filter(unsigned int scopes, struct sock_fprog *prog) {
  append_filter_prefix(prog);
  append_stdio_filter(scopes, prog);
  append_open_filter(scopes, prog);
  append_memory_filter(scopes, prog);
  append_rpath_filter(scopes, prog);
  append_cpath_filter(scopes, prog);
  append_dpath_filter(scopes, prog);
  append_inet_filter(scopes, prog);
  append_dns_filter(scopes, prog);
  append_filter_suffix(prog);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fill_filter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <append_filter_prefix@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_stdio_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_open_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_memory_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_rpath_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_cpath_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_dpath_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_inet_filter@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <append_dns_filter@plt>
  mov    %rbx,%rdi
  call   <append_filter_suffix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void fill_filter(unsigned int scopes, struct sock_fprog *prog) {
  append_filter_prefix(prog);
  append_stdio_filter(scopes, prog);
  append_open_filter(scopes, prog);
  append_memory_filter(scopes, prog);
  append_rpath_filter(scopes, prog);
  append_cpath_filter(scopes, prog);
  append_dpath_filter(scopes, prog);
  append_inet_filter(scopes, prog);
  append_dns_filter(scopes, prog);
  append_filter_suffix(prog);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_filter>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <append_filter_prefix@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_stdio_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_open_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_memory_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_rpath_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_cpath_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_dpath_filter@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <append_inet_filter@plt>
  mov    %r12d,%edi
  mov    %rbp,%rsi
  call   <append_dns_filter@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1170 <append_filter_suffix@plt>
```

assistant: ```c
void fill_filter(unsigned int scopes, struct sock_fprog *prog) {
  append_filter_prefix(prog);
  append_stdio_filter(scopes, prog);
  append_open_filter(scopes, prog);
  append_memory_filter(scopes, prog);
  append_rpath_filter(scopes, prog);
  append_cpath_filter(scopes, prog);
  append_dpath_filter(scopes, prog);
  append_inet_filter(scopes, prog);
  append_dns_filter(scopes, prog);
  append_filter_suffix(prog);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<theta_of_accel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x18(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  movq   %xmm0,%rax
  movq   D3(%rip),%xmm0
  movq   %rax,%xmm3
  xorpd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
extern double theta_of_accel(double an, double ae, double ad) {
  const double g2 = an * an + ae * ae + ad * ad;
  return -asin(an / sqrt(g2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<theta_of_accel>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L9
  sqrtsd %xmm2,%xmm2
L5:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm2,%xmm0
  call   <asin@plt>
  xorpd  D7(%rip),%xmm0
  add    $0x18,%rsp
  ret
L9:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L5
```

tool_calls: name: read_data
arguments: tag: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
extern double theta_of_accel(double an, double ae, double ad) {
  const double g2 = an * an + ae * ae + ad * ad;
  return -asin(an / sqrt(g2));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<theta_of_accel>:
  endbr64
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  sub    $0x18,%rsp
  mulsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm0
  ja     L7
  sqrtsd %xmm2,%xmm2
L10:
  divsd  %xmm2,%xmm4
  movapd %xmm4,%xmm0
  call   <asin@plt>
  xorpd  D5(%rip),%xmm0
  add    $0x18,%rsp
  ret
L7:
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movapd %xmm0,%xmm2
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
extern double theta_of_accel(double an, double ae, double ad) {
  const double g2 = an * an + ae * ae + ad * ad;
  return -asin(an / sqrt(g2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<theta_of_accel>:
  endbr64
  mulsd  %xmm1,%xmm1
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  sub    $0x18,%rsp
  mulsd  %xmm0,%xmm3
  pxor   %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm1,%xmm3
  addsd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm0
  ja     L6
  sqrtsd %xmm2,%xmm2
L16:
  divsd  %xmm2,%xmm4
  movapd %xmm4,%xmm0
  call   <asin@plt>
  xorpd  D7(%rip),%xmm0
  add    $0x18,%rsp
  ret
L6:
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  movapd %xmm0,%xmm2
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
extern double theta_of_accel(double an, double ae, double ad) {
  const double g2 = an * an + ae * ae + ad * ad;
  return -asin(an / sqrt(g2));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  D21(%rip),%xmm1
  movsd  D21(%rip),%xmm0
  mov    D100(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fabd_d@plt>
  movsd  D21(%rip),%xmm1
  movsd  D100(%rip),%xmm0
  mov    D21(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fabd_d@plt>
  movsd  D21(%rip),%xmm1
  movsd  D21(%rip),%xmm0
  mov    D100(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fabd_f@plt>
  movsd  D21(%rip),%xmm1
  movsd  D100(%rip),%xmm0
  mov    D21(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fabd_f@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: f64
name: retrieve_data
arguments: data_label: D100
type_guessed: f64

tool: D21: 5

tool: D100: 10

assistant: ```c
int main() {
  fabd_d(10.0, 5.0, 5.0);
  fabd_d(5.0, 10.0, 5.0);
  fabd_f(10.0, 5.0, 5.0);
  fabd_f(5.0, 10.0, 5.0);
  return 0;
}
```