ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<addToDict>:
  endbr64
  movslq %r9d,%rax
  mov    %edi,%r10d
  movss  %xmm0,(%rdx,%rax,4)
  test   %esi,%esi
  jle    L61
  mov    (%rcx,%rax,8),%rcx
  lea    0x4(%r8),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L9
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L9
  mov    %esi,%edi
  xor    %edx,%edx
  shr    $0x2,%edi
  shl    $0x4,%rdi
  xchg   %ax,%ax
L2:
  movups (%r8,%rdx,1),%xmm1
  movups %xmm1,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdi,%rdx
  jne    L2
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L61
  mov    %eax,%edi
  movss  (%r8,%rdi,4),%xmm0
  lea    0x0(,%rdi,4),%rdx
  movss  %xmm0,(%rcx,%rdi,4)
  lea    0x1(%rax),%edi
  cmp    %edi,%esi
  jle    L61
  movss  0x4(%r8,%rdx,1),%xmm0
  add    $0x2,%eax
  movss  %xmm0,0x4(%rcx,%rdx,1)
  cmp    %eax,%esi
  jle    L61
  movss  0x8(%r8,%rdx,1),%xmm0
  movss  %xmm0,0x8(%rcx,%rdx,1)
L61:
  lea    0x1(%r9),%eax
  cltd
  idiv   %r10d
  mov    %edx,%eax
  ret
  nopl   (%rax)
L9:
  mov    %esi,%esi
  xor    %edx,%edx
  nopl   0x0(%rax)
L41:
  movss  (%r8,%rdx,4),%xmm0
  movss  %xmm0,(%rcx,%rdx,4)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L41
  lea    0x1(%r9),%eax
  cltd
  idiv   %r10d
  mov    %edx,%eax
  ret
```

assistant: ```c
int addToDict(int dictSize, int features, float *weights, float **dict, float *x, float newWeight, int idx) {
  weights[idx] = newWeight;
  int i;
  for (i = 0; i < features; i++)
    dict[idx][i] = x[i];
  return (idx + 1) % dictSize;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x34353132,-0xe(%rbp)
  movw   $0x33,-0xa(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x2,-0x18(%rbp)
  jmp    L22
L18:
  mov    -0x18(%rbp),%edx
  lea    -0xe(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <string_permutation_dict@plt>
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D6: str = %s


tool: D8: %s


assistant: ```c
void main() {
  char str[] = "21543";
  int len = strlen(str);
  int i;
  printf("str = %s\n", str);
  for (i = 2; i < len; i++) {
    string_permutation_dict(str, i);
    printf("%s\n", str);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x34353132,0x2(%rsp)
  movw   $0x33,0x6(%rsp)
  lea    0x2(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  cmp    $0x2,%r12d
  jle    L0
  mov    $0x2,%ebx
  lea    D9(%rip),%r13
L6:
  lea    0x2(%rsp),%rbp
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <string_permutation_dict@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L6
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D9
data_type: string

tool: D8: str = %s


tool: D9: %s


assistant: ```c
void main() {
  char str[] = "21543";
  int len = strlen(str);
  int i;
  printf("str = %s\n", str);
  for (i = 2; i < len; i++) {
    string_permutation_dict(str, i);
    printf("%s\n", str);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  mov    $0x33,%eax
  movl   $0x34353132,0x2(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  cmp    $0x2,%r12d
  jle    L20
  mov    $0x2,%ebx
  lea    D15(%rip),%r13
  nopl   0x0(%rax)
L23:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <string_permutation_dict@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L23
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D18: str = %s


tool: D15: %s


assistant: ```c
void main() {
  char str[] = "21543";
  int len = strlen(str);
  int i;
  printf("str = %s\n", str);
  for (i = 2; i < len; i++) {
    string_permutation_dict(str, i);
    printf("%s\n", str);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  mov    $0x33,%eax
  movl   $0x34353132,0x2(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x6(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  cmp    $0x2,%r12d
  jle    L2
  mov    $0x2,%ebx
  lea    D17(%rip),%r13
  nopl   0x0(%rax)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <string_permutation_dict@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L16
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string

tool: D12: str = %s


tool: D17: %s


assistant: ```c
void main() {
  char str[] = "21543";
  int len = strlen(str);
  int i;
  printf("str = %s\n", str);
  for (i = 2; i < len; i++) {
    string_permutation_dict(str, i);
    printf("%s\n", str);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sagetv_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sagetv_malloc(int size) {
  char *p = (char *)malloc(size);
  if (p)
    memset(p, 0, size);
  return (void *)p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sagetv_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L15
L11:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L11
```

assistant: ```c
void *sagetv_malloc(int size) {
  char *p = (char *)malloc(size);
  if (p)
    memset(p, 0, size);
  return (void *)p;
}
```
user: What is the c source code of the assembly code below:

```asm
<sagetv_malloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sagetv_malloc(int size) {
  char *p = (char *)malloc(size);
  if (p)
    memset(p, 0, size);
  return (void *)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sagetv_malloc>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sagetv_malloc(int size) {
  char *p = (char *)malloc(size);
  if (p)
    memset(p, 0, size);
  return (void *)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L43
L19:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L7
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x78(%rbp)
  jmp    L40
L7:
  addl   $0x1,-0x74(%rbp)
L43:
  cmpl   $0x63,-0x74(%rbp)
  jle    L19
L40:
  mov    -0x78(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: %s

assistant: ```c
int main() {
  char s[100];
  int x = 0;
  scanf("%s", s);
  for (int j = 0; j < 100; j++) {
    if (s[j] == '\0') {
      x = j;
      break;
    }
  }
  swap(s, x);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  mov    %rsp,%rdx
L19:
  mov    %eax,%esi
  cmpb   $0x0,(%rax,%rdx,1)
  je     L0
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L19
  mov    $0x0,%esi
L0:
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: %s

assistant: ```c
int main() {
  char s[100];
  int x = 0;
  scanf("%s", s);
  for (int j = 0; j < 100; j++) {
    if (s[j] == '\0') {
      x = j;
      break;
    }
  }
  swap(s, x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  jmp    L11
  nop
L32:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L37
L11:
  cmpb   $0x0,0x0(%rbp,%rax,1)
  mov    %eax,%esi
  jne    L32
L43:
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L37:
  xor    %esi,%esi
  jmp    L43
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D9: %s

assistant: ```c
int main() {
  char s[100];
  int x = 0;
  scanf("%s", s);
  for (int j = 0; j < 100; j++) {
    if (s[j] == '\0') {
      x = j;
      break;
    }
  }
  swap(s, x);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  jmp    L4
  nop
L28:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L18
L4:
  cmpb   $0x0,0x0(%rbp,%rax,1)
  mov    %eax,%esi
  jne    L28
L5:
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L18:
  xor    %esi,%esi
  jmp    L5
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: %s

assistant: ```c
int main() {
  char s[100];
  int x = 0;
  scanf("%s", s);
  for (int j = 0; j < 100; j++) {
    if (s[j] == '\0') {
      x = j;
      break;
    }
  }
  swap(s, x);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basefilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L17
  cmp    $0x2f,%eax
  jne    L22
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L5
L17:
  mov    -0x10(%rbp),%rax
  jmp    L35
L5:
  jmp    L22
L35:
  pop    %rbp
  ret
```

assistant: ```c
char const *basefilename(const char *const p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basefilename>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
  jmp    L18
L4:
  cmp    $0x2f,%cl
  cmove  %rdx,%rax
L18:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  jne    L4
  ret
```

assistant: ```c
char const *basefilename(const char *const p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basefilename>:
  endbr64
  mov    %rdi,%r8
  jmp    L6
  nopl   0x0(%rax)
L12:
  cmp    $0x2f,%al
  cmove  %rdi,%r8
L6:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L12
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *basefilename(const char *const p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<basefilename>:
  endbr64
  mov    %rdi,%r8
  jmp    L1
  nopl   0x0(%rax)
L18:
  cmp    $0x2f,%al
  cmove  %rdi,%r8
L1:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L18
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *basefilename(const char *const p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<revcomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L112
  mov    $0x0,%eax
  jmp    L71
L112:
  cmpq   $0x0,-0x20(%rbp)
  jne    L144
  mov    $0x0,%eax
  jmp    L71
L144:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <StrReverse@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L118
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <sre_toupper@plt>
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x18,%eax
  ja     L97
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D13(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movb   $0x54,-0x9(%rbp)
  jmp    L137
  movb   $0x47,-0x9(%rbp)
  jmp    L137
  movb   $0x43,-0x9(%rbp)
  jmp    L137
  movb   $0x41,-0x9(%rbp)
  jmp    L137
  movb   $0x41,-0x9(%rbp)
  jmp    L137
  movb   $0x59,-0x9(%rbp)
  jmp    L137
  movb   $0x52,-0x9(%rbp)
  jmp    L137
  movb   $0x4b,-0x9(%rbp)
  jmp    L137
  movb   $0x4d,-0x9(%rbp)
  jmp    L137
  movb   $0x53,-0x9(%rbp)
  jmp    L137
  movb   $0x57,-0x9(%rbp)
  jmp    L137
  movb   $0x44,-0x9(%rbp)
  jmp    L137
  movb   $0x48,-0x9(%rbp)
  jmp    L137
  movb   $0x56,-0x9(%rbp)
  jmp    L137
  movb   $0x42,-0x9(%rbp)
  jmp    L137
L97:
  nop
L137:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L81
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <sre_tolower@plt>
  mov    %al,-0x9(%rbp)
L81:
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L118:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  mov    -0x18(%rbp),%rax
L71:
  leave
  ret
```

assistant: ```c
char *revcomp(char *comp, char *seq) {
  char *s;
  char c;
  if (comp == NULL)
    return NULL;
  if (seq == NULL)
    return NULL;
  StrReverse(comp, seq);
  for (s = comp; *s != '\0'; s++) {
    c = *s;
    c = sre_toupper(c);
    switch (c) {
    case 'A':
      c = 'T';
      break;
    case 'C':
      c = 'G';
      break;
    case 'G':
      c = 'C';
      break;
    case 'T':
      c = 'A';
      break;
    case 'U':
      c = 'A';
      break;
    case 'R':
      c = 'Y';
      break;
    case 'Y':
      c = 'R';
      break;
    case 'M':
      c = 'K';
      break;
    case 'K':
      c = 'M';
      break;
    case 'S':
      c = 'S';
      break;
    case 'W':
      c = 'W';
      break;
    case 'H':
      c = 'D';
      break;
    case 'D':
      c = 'H';
      break;
    case 'B':
      c = 'V';
      break;
    case 'V':
      c = 'B';
      break;
    default:
      break;
    }
    if (islower((int)*s))
      c = (char)sre_tolower((int)c);
    *s = c;
  }
  return comp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<revcomp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L71
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L71
  call   <StrReverse@plt>
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L155
  mov    %r13,%rbp
  lea    D7(%rip),%r12
  jmp    L136
  mov    $0x54,%ebx
  jmp    L93
  mov    $0x47,%ebx
L93:
  movsbl 0x0(%rbp),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L131
L135:
  mov    %bl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L155
L136:
  movsbl %dil,%edi
  call   <sre_toupper@plt>
  mov    %eax,%ebx
  lea    -0x41(%rbx),%eax
  cmp    $0x18,%al
  ja     L93
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  mov    $0x43,%ebx
  jmp    L93
  mov    $0x41,%ebx
  jmp    L93
  mov    $0x41,%ebx
  jmp    L93
  mov    $0x59,%ebx
  jmp    L93
  mov    $0x52,%ebx
  jmp    L93
  mov    $0x4b,%ebx
  jmp    L93
  mov    $0x4d,%ebx
  jmp    L93
  mov    $0x44,%ebx
  jmp    L93
  mov    $0x48,%ebx
  jmp    L93
  mov    $0x56,%ebx
  jmp    L93
  mov    $0x42,%ebx
  jmp    L93
L131:
  movsbl %bl,%edi
  call   <sre_tolower@plt>
  mov    %eax,%ebx
  jmp    L135
L71:
  mov    $0x0,%r13d
L155:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *revcomp(char *comp, char *seq) {
  char *s;
  char c;
  if (comp == NULL)
    return NULL;
  if (seq == NULL)
    return NULL;
  StrReverse(comp, seq);
  for (s = comp; *s != '\0'; s++) {
    c = *s;
    c = sre_toupper(c);
    switch (c) {
    case 'A':
      c = 'T';
      break;
    case 'C':
      c = 'G';
      break;
    case 'G':
      c = 'C';
      break;
    case 'T':
      c = 'A';
      break;
    case 'U':
      c = 'A';
      break;
    case 'R':
      c = 'Y';
      break;
    case 'Y':
      c = 'R';
      break;
    case 'M':
      c = 'K';
      break;
    case 'K':
      c = 'M';
      break;
    case 'S':
      c = 'S';
      break;
    case 'W':
      c = 'W';
      break;
    case 'H':
      c = 'D';
      break;
    case 'D':
      c = 'H';
      break;
    case 'B':
      c = 'V';
      break;
    case 'V':
      c = 'B';
      break;
    default:
      break;
    }
    if (islower((int)*s))
      c = (char)sre_tolower((int)c);
    *s = c;
  }
  return comp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<revcomp>:
  endbr64
  test   %rsi,%rsi
  je     L110
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L74
  call   <StrReverse@plt>
  movsbl (%r12),%edi
  mov    %r12,%r13
  lea    D3(%rip),%rbp
  test   %dil,%dil
  je     L158
  nopl   0x0(%rax)
L76:
  call   <sre_toupper@plt>
  mov    %eax,%ebx
  lea    -0x41(%rbx),%eax
  cmp    $0x18,%al
  ja     L114
  movzbl %al,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  mov    $0x41,%ebx
  nopl   (%rax)
L114:
  movsbl 0x0(%r13),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L24
L146:
  mov    %bl,0x0(%r13)
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  test   %dil,%dil
  jne    L76
L158:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  movsbl %bl,%edi
  call   <sre_tolower@plt>
  mov    %eax,%ebx
  jmp    L146
  nopl   0x0(%rax)
  mov    $0x42,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x52,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x59,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x4b,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x4d,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x44,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x43,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x48,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x47,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x56,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
  mov    $0x54,%ebx
  jmp    L114
  nopw   0x0(%rax,%rax,1)
L74:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L110:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *revcomp(char *comp, char *seq) {
  char *s;
  char c;
  if (comp == NULL)
    return NULL;
  if (seq == NULL)
    return NULL;
  StrReverse(comp, seq);
  for (s = comp; *s != '\0'; s++) {
    c = *s;
    c = sre_toupper(c);
    switch (c) {
    case 'A':
      c = 'T';
      break;
    case 'C':
      c = 'G';
      break;
    case 'G':
      c = 'C';
      break;
    case 'T':
      c = 'A';
      break;
    case 'U':
      c = 'A';
      break;
    case 'R':
      c = 'Y';
      break;
    case 'Y':
      c = 'R';
      break;
    case 'M':
      c = 'K';
      break;
    case 'K':
      c = 'M';
      break;
    case 'S':
      c = 'S';
      break;
    case 'W':
      c = 'W';
      break;
    case 'H':
      c = 'D';
      break;
    case 'D':
      c = 'H';
      break;
    case 'B':
      c = 'V';
      break;
    case 'V':
      c = 'B';
      break;
    default:
      break;
    }
    if (islower((int)*s))
      c = (char)sre_tolower((int)c);
    *s = c;
  }
  return comp;
}
```