ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<branchfree_search2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L94
  jmp    L112
L90:
  mov    -0x30(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L3
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L115
L3:
  mov    -0x18(%rbp),%rax
L115:
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x38(%rbp)
  jle    L8
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L78
L8:
  mov    -0x10(%rbp),%rax
L78:
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x30(%rbp)
L112:
  cmpq   $0x1,-0x30(%rbp)
  ja     L90
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L10
  mov    $0x4,%edx
  jmp    L71
L10:
  mov    $0x0,%edx
L71:
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x38(%rbp)
  jle    L57
  mov    $0x4,%edx
  jmp    L13
L57:
  mov    $0x0,%edx
L13:
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L114
L94:
  nop
L114:
  pop    %rbp
  ret
```

assistant: ```c
void branchfree_search2(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<branchfree_search2>:
  endbr64
  test   %rsi,%rsi
  je     L22
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%ebx
  mov    %ecx,%r11d
  cmp    $0x1,%rsi
  jbe    L37
  mov    %rdi,%rdx
  mov    %rdi,%rcx
L21:
  mov    %rsi,%rdi
  shr    %rdi
  lea    0x0(,%rdi,4),%rax
  lea    (%rcx,%rax,1),%r10
  cmp    %ebx,(%r10)
  cmovl  %r10,%rcx
  add    %rdx,%rax
  cmp    %r11d,(%rax)
  cmovl  %rax,%rdx
  sub    %rdi,%rsi
  cmp    $0x1,%rsi
  ja     L21
L39:
  cmp    %ebx,(%rcx)
  setl   %al
  movzbl %al,%eax
  lea    (%rcx,%rax,4),%rax
  sub    %rbp,%rax
  sar    $0x2,%rax
  mov    %rax,(%r8)
  cmp    %r11d,(%rdx)
  setl   %al
  movzbl %al,%eax
  lea    (%rdx,%rax,4),%rax
  sub    %rbp,%rax
  sar    $0x2,%rax
  mov    %rax,(%r9)
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    %rdi,%rdx
  mov    %rdi,%rcx
  jmp    L39
L22:
  ret
```

assistant: ```c
void branchfree_search2(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<branchfree_search2>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %rbp
  mov    %ecx,%r11d
  mov    %rdi,%rbp
  mov    %rdi,%rcx
  push   %rbx
  mov    %edx,%ebx
  mov    %rdi,%rdx
  cmp    $0x1,%rsi
  je     L2
  nop
L11:
  mov    %rsi,%rdi
  shr    %rdi
  lea    0x0(,%rdi,4),%rax
  lea    (%rcx,%rax,1),%r10
  cmp    %ebx,(%r10)
  cmovl  %r10,%rcx
  add    %rdx,%rax
  cmp    %r11d,(%rax)
  cmovl  %rax,%rdx
  sub    %rdi,%rsi
  cmp    $0x1,%rsi
  ja     L11
L2:
  xor    %eax,%eax
  cmp    %ebx,(%rcx)
  pop    %rbx
  setl   %al
  lea    (%rcx,%rax,4),%rax
  sub    %rbp,%rax
  sar    $0x2,%rax
  mov    %rax,(%r8)
  xor    %eax,%eax
  cmp    %r11d,(%rdx)
  setl   %al
  lea    (%rdx,%rax,4),%rax
  sub    %rbp,%rax
  pop    %rbp
  sar    $0x2,%rax
  mov    %rax,(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void branchfree_search2(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<branchfree_search2>:
  endbr64
  test   %rsi,%rsi
  je     L10
  push   %rbp
  mov    %ecx,%r11d
  mov    %rdi,%rbp
  mov    %rdi,%rcx
  push   %rbx
  mov    %edx,%ebx
  mov    %rdi,%rdx
  cmp    $0x1,%rsi
  je     L26
  nop
L3:
  mov    %rsi,%rdi
  shr    %rdi
  lea    0x0(,%rdi,4),%rax
  lea    (%rcx,%rax,1),%r10
  cmp    (%r10),%ebx
  cmovg  %r10,%rcx
  add    %rdx,%rax
  cmp    (%rax),%r11d
  cmovg  %rax,%rdx
  sub    %rdi,%rsi
  cmp    $0x1,%rsi
  ja     L3
L26:
  xor    %eax,%eax
  cmp    %ebx,(%rcx)
  pop    %rbx
  setl   %al
  lea    (%rcx,%rax,4),%rax
  sub    %rbp,%rax
  sar    $0x2,%rax
  mov    %rax,(%r8)
  xor    %eax,%eax
  cmp    %r11d,(%rdx)
  setl   %al
  lea    (%rdx,%rax,4),%rax
  sub    %rbp,%rax
  pop    %rbp
  sar    $0x2,%rax
  mov    %rax,(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void branchfree_search2(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<longestPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L69
L68:
  lea    -0x28(%rbp),%rdi
  lea    -0x2c(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <expand@plt>
  mov    -0x28(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  sub    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jg     L52
  mov    -0x28(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L52:
  addl   $0x1,-0x1c(%rbp)
L69:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L68
  cmpl   $0x0,-0x20(%rbp)
  je     L27
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L63
L42:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L63:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L42
L27:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  int start = 0, end = 0;
  int m_start = 0, m_end = 0;
  int max = 0;
  int i = 0;
  char *result = NULL;
  for (i = 0; i < len; i++) {
    expand(s, len, i, &start, &end);
    if (max < (end - start + 1)) {
      max = end - start + 1;
      m_start = start;
      m_end = end;
    }
  }
  if (max) {
    result = calloc(max + 1, sizeof(char));
    for (i = 0; i < max; i++) {
      result[i] = s[m_start++];
    }
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<longestPalindrome>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %eax,%eax
  jle    L3
  mov    %eax,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%r15d
  lea    0x4(%rsp),%r14
  jmp    L43
L22:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L18
L43:
  mov    %rsp,%rcx
  mov    %r14,%r8
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <expand@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  sub    %edx,%eax
  cmp    %ebp,%eax
  jl     L22
  lea    0x1(%rax),%ebp
  mov    %edx,%r15d
  jmp    L22
L18:
  mov    $0x0,%eax
  test   %ebp,%ebp
  je     L89
  lea    0x1(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L89
  mov    %ebp,%ebp
  mov    $0x0,%edx
  movslq %r15d,%r15
  add    %r15,%r13
L4:
  movzbl 0x0(%r13,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbp
  jne    L4
L89:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  mov    $0x0,%eax
  jmp    L89
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  int start = 0, end = 0;
  int m_start = 0, m_end = 0;
  int max = 0;
  int i = 0;
  char *result = NULL;
  for (i = 0; i < len; i++) {
    expand(s, len, i, &start, &end);
    if (max < (end - start + 1)) {
      max = end - start + 1;
      m_start = start;
      m_end = end;
    }
  }
  if (max) {
    result = calloc(max + 1, sizeof(char));
    for (i = 0; i < max; i++) {
      result[i] = s[m_start++];
    }
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<longestPalindrome>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  test   %eax,%eax
  jle    L63
  movl   $0x0,0xc(%rsp)
  mov    %eax,%r13d
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  lea    0x14(%rsp),%r15
  lea    0x10(%rsp),%r14
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <expand@plt>
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%eax
  sub    %edx,%eax
  cmp    %ebp,%eax
  jl     L65
  mov    %edx,0xc(%rsp)
  lea    0x1(%rax),%ebp
L65:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L20
  test   %ebp,%ebp
  je     L63
  lea    0x1(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %ebp,%ebp
  jle    L24
  movslq 0xc(%rsp),%r13
  movslq %ebp,%rbp
  xor    %edx,%edx
  add    %r13,%r12
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbp
  jne    L5
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  xor    %eax,%eax
  jmp    L24
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  int start = 0, end = 0;
  int m_start = 0, m_end = 0;
  int max = 0;
  int i = 0;
  char *result = NULL;
  for (i = 0; i < len; i++) {
    expand(s, len, i, &start, &end);
    if (max < (end - start + 1)) {
      max = end - start + 1;
      m_start = start;
      m_end = end;
    }
  }
  if (max) {
    result = calloc(max + 1, sizeof(char));
    for (i = 0; i < max; i++) {
      result[i] = s[m_start++];
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_box>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L62
L24:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L94
  addl   $0x1,-0x10(%rbp)
  cmpb   $0x45,-0x20(%rbp)
  jne    L94
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x45,%al
  jne    L94
  movl   $0x1,-0xc(%rbp)
L94:
  addl   $0x1,-0x8(%rbp)
L62:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  cmpb   $0x41,-0x20(%rbp)
  jne    L142
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L142
  mov    $0x1,%eax
  jmp    L74
L142:
  cmpb   $0x42,-0x20(%rbp)
  jne    L136
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L136
  mov    $0x1,%eax
  jmp    L74
L136:
  cmpb   $0x45,-0x20(%rbp)
  jne    L26
  cmpl   $0x2,-0x10(%rbp)
  jne    L26
  cmpl   $0x0,-0xc(%rbp)
  je     L26
  mov    $0x1,%eax
  jmp    L74
L26:
  mov    $0x0,%eax
L74:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t check_box(const char arr[], uint64_t sz, char c) {
  uint64_t N = sz / 2;
  uint64_t count = 0;
  uint8_t isAdjecent = 0;
  for (uint64_t i = 0; i < sz; i++) {
    if (arr[i] == c) {
      count++;
      if (c == 'E' && arr[i + 1] == 'E')
        isAdjecent = 1;
    }
  }
  if (c == 'A' && count == (N - 1))
    return 1;
  else if (c == 'B' && count == (N - 1))
    return 1;
  else if (c == 'E' && count == 2 && isAdjecent)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_box>:
  endbr64
  mov    %edx,%r9d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  mov    %eax,%r8d
  test   %esi,%esi
  jle    L75
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%rsi
  mov    $0x0,%r10d
  mov    $0x0,%edi
  mov    $0x1,%r11d
  jmp    L104
L67:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L68
L104:
  cmp    %dl,(%rax)
  jne    L67
  add    $0x1,%edi
  cmp    $0x45,%dl
  jne    L67
  cmpb   $0x45,0x1(%rax)
  cmove  %r11d,%r10d
  jmp    L67
L75:
  mov    $0x0,%r10d
  mov    $0x0,%edi
L68:
  cmp    $0x41,%r9b
  je     L58
  cmp    $0x42,%r9b
  je     L105
L52:
  cmp    $0x2,%edi
  sete   %dl
  test   %r10d,%r10d
  setne  %al
  and    %eax,%edx
  cmp    $0x45,%r9b
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
L72:
  ret
L58:
  sub    $0x1,%r8d
  mov    $0x1,%eax
  cmp    %edi,%r8d
  jne    L52
  ret
L105:
  sub    $0x1,%r8d
  mov    $0x1,%eax
  cmp    %edi,%r8d
  jne    L52
  jmp    L72
```

assistant: ```c
uint8_t check_box(const char arr[], uint64_t sz, char c) {
  uint64_t N = sz / 2;
  uint64_t count = 0;
  uint8_t isAdjecent = 0;
  for (uint64_t i = 0; i < sz; i++) {
    if (arr[i] == c) {
      count++;
      if (c == 'E' && arr[i + 1] == 'E')
        isAdjecent = 1;
    }
  }
  if (c == 'A' && count == (N - 1))
    return 1;
  else if (c == 'B' && count == (N - 1))
    return 1;
  else if (c == 'E' && count == 2 && isAdjecent)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_box>:
  endbr64
  mov    %edx,%r9d
  mov    %edx,%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L43
  lea    -0x1(%rsi),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0x1,%r10d
  lea    0x1(%rdi,%rdx,1),%rdx
  jmp    L83
  nopl   0x0(%rax)
L66:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L96
L83:
  cmp    %al,(%rdi)
  jne    L66
  add    $0x1,%ecx
  cmp    $0x45,%al
  jne    L66
  cmpb   $0x45,0x1(%rdi)
  cmove  %r10d,%esi
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L83
  nopl   (%rax)
L96:
  cmp    $0x41,%r9b
  je     L46
  cmp    $0x42,%r9b
  je     L65
L10:
  cmp    $0x2,%ecx
  sete   %dl
  xor    %eax,%eax
  and    %esi,%edx
  cmp    $0x45,%r9b
  sete   %al
  and    %edx,%eax
  ret
L65:
  lea    -0x1(%r8),%edx
  xor    %eax,%eax
  cmp    %ecx,%edx
  sete   %al
  ret
  nopl   0x0(%rax)
L46:
  lea    -0x1(%r8),%edx
  mov    $0x1,%eax
  cmp    %ecx,%edx
  jne    L10
  ret
  xchg   %ax,%ax
L43:
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L96
```

assistant: ```c
uint8_t check_box(const char arr[], uint64_t sz, char c) {
  uint64_t N = sz / 2;
  uint64_t count = 0;
  uint8_t isAdjecent = 0;
  for (uint64_t i = 0; i < sz; i++) {
    if (arr[i] == c) {
      count++;
      if (c == 'E' && arr[i + 1] == 'E')
        isAdjecent = 1;
    }
  }
  if (c == 'A' && count == (N - 1))
    return 1;
  else if (c == 'B' && count == (N - 1))
    return 1;
  else if (c == 'E' && count == 2 && isAdjecent)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
L11:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  jmp    L17
L16:
  mov    $0x2e,%eax
L17:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  cmpl   $0x0,-0xc(%rbp)
  jg     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<psf_sanitize_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movslq %esi,%rbx
  mov    $0x2e,%r12d
  jmp    L3
L20:
  movzbl -0x1(%rbp,%rbx,1),%eax
L36:
  mov    %al,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jle    L10
L3:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <isprint@plt>
  mov    %rax,%rdx
  mov    %r12d,%eax
  test   %rdx,%rdx
  je     L36
  jmp    L20
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
L6:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <isprint@plt>
  mov    %rax,%r8
  mov    $0x2e,%eax
  test   %r8,%r8
  je     L14
  movzbl -0x1(%rbp,%rbx,1),%eax
L14:
  mov    %al,-0x1(%rbp,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<psf_sanitize_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
L8:
  movsbl -0x1(%rbp,%rbx,1),%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L12
  movb   $0x2e,-0x1(%rbp,%rbx,1)
L12:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void psf_sanitize_string(char *cptr, int len) {
  do {
    len--;
    cptr[len] = isprint(cptr[len]) ? cptr[len] : '.';
  } while (len > 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pbl_LongToBuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sar    $0x18,%rax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  sar    $0x10,%rax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  sar    $0x8,%rax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pbl_LongToBuf(unsigned char *buf, long l) {
  *buf++ = (unsigned char)((l >> 24));
  *buf++ = (unsigned char)((l >> 16));
  *buf++ = (unsigned char)((l >> 8));
  *buf = (unsigned char)(l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pbl_LongToBuf>:
  endbr64
  mov    %rsi,%rax
  mov    %rsi,%rdx
  sar    $0x18,%rdx
  mov    %dl,(%rdi)
  mov    %rsi,%rdx
  sar    $0x10,%rdx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %sil,0x3(%rdi)
  ret
```

assistant: ```c
void pbl_LongToBuf(unsigned char *buf, long l) {
  *buf++ = (unsigned char)((l >> 24));
  *buf++ = (unsigned char)((l >> 16));
  *buf++ = (unsigned char)((l >> 8));
  *buf = (unsigned char)(l);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pbl_LongToBuf>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void pbl_LongToBuf(unsigned char *buf, long l) {
  *buf++ = (unsigned char)((l >> 24));
  *buf++ = (unsigned char)((l >> 16));
  *buf++ = (unsigned char)((l >> 8));
  *buf = (unsigned char)(l);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pbl_LongToBuf>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void pbl_LongToBuf(unsigned char *buf, long l) {
  *buf++ = (unsigned char)((l >> 24));
  *buf++ = (unsigned char)((l >> 16));
  *buf++ = (unsigned char)((l >> 8));
  *buf = (unsigned char)(l);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cuftpd_parse_args@plt>
  mov    $0x0,%eax
  call   <cuftpd_init@plt>
  mov    $0x0,%eax
  call   <cuftpd_create_srv@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cuftpd_do_loop@plt>
L3:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int listenfd;
  cuftpd_parse_args(argc, argv);
  cuftpd_init();
  listenfd = cuftpd_create_srv();
  if (listenfd >= 0)
    cuftpd_do_loop(listenfd);
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <cuftpd_parse_args@plt>
  mov    $0x0,%eax
  call   <cuftpd_init@plt>
  mov    $0x0,%eax
  call   <cuftpd_create_srv@plt>
  test   %eax,%eax
  jns    L9
L6:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L9:
  mov    %eax,%edi
  call   <cuftpd_do_loop@plt>
  jmp    L6
```

assistant: ```c
int main(int argc, char *argv[]) {
  int listenfd;
  cuftpd_parse_args(argc, argv);
  cuftpd_init();
  listenfd = cuftpd_create_srv();
  if (listenfd >= 0)
    cuftpd_do_loop(listenfd);
  exit(0);
}
```