ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rdx
  lea    0x6(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  movsbl 0x6(%rsp),%edi
  call   <compactaCaracteres@plt>
  movsbl 0x7(%rsp),%edx
  movsbl 0x6(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D22
type_infered: string

tool: D9: Informe 2 caracteres: 

tool: D14: %c%c

tool: D22: %d %d %d


assistant: ```c
int main() {
  char char1, char2;
  unsigned int compactado;
  printf("Informe 2 caracteres: ");
  scanf("%c%c", &char1, &char2);
  compactado = compactaCaracteres(char1, char2);
  printf("%d %d %d\n", ((int)char1), ((int)char2), compactado);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <show_stackframe@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D0: usage: %s [-h] [ -i file]


tool: D10: -i file			the input file

tool: D1: -h 			help

assistant: ```c
void usage(char *prog) {
  show_stackframe();
  printf("usage: %s [-h] [ -i file]\n", prog);
  printf("-i file\t\t\tthe input file\n");
  printf("-h \t\t\thelp\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <show_stackframe@plt>
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D18: usage: %s [-h] [ -i file]


tool: D0: -i file			the input file

tool: D11: -h 			help

assistant: ```c
void usage(char *prog) {
  show_stackframe();
  printf("usage: %s [-h] [ -i file]\n", prog);
  printf("-i file\t\t\tthe input file\n");
  printf("-h \t\t\thelp\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <show_stackframe@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string

tool: D14: usage: %s [-h] [ -i file]


tool: D21: -i file			the input file

tool: D29: -h 			help

assistant: ```c
void usage(char *prog) {
  show_stackframe();
  printf("usage: %s [-h] [ -i file]\n", prog);
  printf("-i file\t\t\tthe input file\n");
  printf("-h \t\t\thelp\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <show_stackframe@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
data_type: string
name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: D19: usage: %s [-h] [ -i file]


tool: D5: -i file			the input file

tool: D12: -h 			help

assistant: ```c
void usage(char *prog) {
  show_stackframe();
  printf("usage: %s [-h] [ -i file]\n", prog);
  printf("-i file\t\t\tthe input file\n");
  printf("-h \t\t\thelp\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D22(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  push   %rdx
  lea    D46(%rip),%rdx
  push   %rdx
  lea    D65(%rip),%r9
  mov    %rcx,%r8
  lea    D11(%rip),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_guessed: string
name: retrieve_data
arguments: data_tag: D48
type_guessed: string
name: retrieve_data
arguments: data_tag: D46
type_guessed: string
name: retrieve_data
arguments: data_tag: D65
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: string
name: retrieve_data
arguments: data_tag: D54
type_guessed: string
name: retrieve_data
arguments: data_tag: D26
type_guessed: string

tool: D22: The value is 3.14159

tool: D48: aehi lsTuv

tool: D46: containing only characters from string2 = 

tool: D65: The length of the initial segment of string1

tool: D11: string2 = 

tool: D54: string1 = 

tool: D26: %s%s
%s%s

%s
%s%u


assistant: ```c
int main(void) {
  const char *string1 = "The value is 3.14159";
  const char *string2 = "aehi lsTuv";
  printf("%s%s\n%s%s\n\n%s\n%s%u\n", "string1 = ", string1, "string2 = ", string2, "The length of the initial segment of string1", "containing only characters from string2 = ", strspn(string1, string2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D24(%rip),%rbp
  mov    %rbp,%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <strspn@plt>
  push   %rax
  lea    D31(%rip),%rax
  push   %rax
  lea    D53(%rip),%r9
  mov    %rbp,%r8
  lea    D48(%rip),%rcx
  mov    %rbx,%rdx
  lea    D59(%rip),%rsi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D53
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D59
type_infered: string
name: read_data
arguments: data_label: D46
type_infered: string

tool: D24: aehi lsTuv

tool: D3: The value is 3.14159

tool: D31: containing only characters from string2 = 

tool: D53: The length of the initial segment of string1

tool: D48: string2 = 

tool: D59: string1 = 

tool: D46: %s%s
%s%s

%s
%s%u


assistant: ```c
int main(void) {
  const char *string1 = "The value is 3.14159";
  const char *string2 = "aehi lsTuv";
  printf("%s%s\n%s%s\n\n%s\n%s%u\n", "string1 = ", string1, "string2 = ", string2, "The length of the initial segment of string1", "containing only characters from string2 = ", strspn(string1, string2));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D37(%rip),%r12
  push   %rbx
  lea    D40(%rip),%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  sub    $0x8,%rsp
  call   <strspn@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D63(%rip),%r9
  push   %rax
  lea    D5(%rip),%rax
  lea    D21(%rip),%rcx
  push   %rax
  lea    D7(%rip),%rsi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D40
type: string
name: parse_data
arguments: data_tag: D63
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D53
type: string

tool: D37: The value is 3.14159

tool: D40: aehi lsTuv

tool: D63: The length of the initial segment of string1

tool: D5: containing only characters from string2 = 

tool: D21: string2 = 

tool: D7: string1 = 

tool: D53: %s%s
%s%s

%s
%s%u


assistant: ```c
int main(void) {
  const char *string1 = "The value is 3.14159";
  const char *string2 = "aehi lsTuv";
  printf("%s%s\n%s%s\n\n%s\n%s%u\n", "string1 = ", string1, "string2 = ", string2, "The length of the initial segment of string1", "containing only characters from string2 = ", strspn(string1, string2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%r12
  push   %rbx
  lea    D67(%rip),%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  sub    $0x8,%rsp
  call   <strspn@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D26(%rip),%r9
  push   %rax
  lea    D22(%rip),%rax
  lea    D5(%rip),%rcx
  push   %rax
  lea    D0(%rip),%rsi
  lea    D53(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_guessed: string
name: disassemble_data
arguments: tag: D67
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string
name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D53
type_guessed: string

tool: D29: The value is 3.14159

tool: D67: aehi lsTuv

tool: D26: The length of the initial segment of string1

tool: D22: containing only characters from string2 = 

tool: D5: string2 = 

tool: D0: string1 = 

tool: D53: %s%s
%s%s

%s
%s%u


assistant: ```c
int main(void) {
  const char *string1 = "The value is 3.14159";
  const char *string2 = "aehi lsTuv";
  printf("%s%s\n%s%s\n\n%s\n%s%u\n", "string1 = ", string1, "string2 = ", string2, "The length of the initial segment of string1", "containing only characters from string2 = ", strspn(string1, string2));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cbstdiobin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cbstdiobin(void) {
  if ((0) == -1 || (0) == -1 || (0) == -1)
    cbmyfatal("setmode failed");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cbstdiobin>:
  endbr64
  ret
```

assistant: ```c
void cbstdiobin(void) {
  if ((0) == -1 || (0) == -1 || (0) == -1)
    cbmyfatal("setmode failed");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cbstdiobin>:
  endbr64
  ret
```

assistant: ```c
void cbstdiobin(void) {
  if ((0) == -1 || (0) == -1 || (0) == -1)
    cbmyfatal("setmode failed");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<onTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x30(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <event_add@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: Hello, world!


assistant: ```c
void onTime(int sock, short event, void *arg) {
  printf("Hello, world!\n");
  struct timeval tv;
  tv.tv_sec = 1;
  tv.tv_usec = 0;
  event_add((struct event *)arg, &tv);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<onTime>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movl   $0x1,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <event_add@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: Hello, world!


assistant: ```c
void onTime(int sock, short event, void *arg) {
  printf("Hello, world!\n");
  struct timeval tv;
  tv.tv_sec = 1;
  tv.tv_usec = 0;
  event_add((struct event *)arg, &tv);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<onTime>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  mov    %rdx,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  movl   $0x1,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <event_add@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: Hello, world!


assistant: ```c
void onTime(int sock, short event, void *arg) {
  printf("Hello, world!\n");
  struct timeval tv;
  tv.tv_sec = 1;
  tv.tv_usec = 0;
  event_add((struct event *)arg, &tv);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<onTime>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  mov    %rdx,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  movl   $0x1,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <event_add@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: Hello, world!


assistant: ```c
void onTime(int sock, short event, void *arg) {
  printf("Hello, world!\n");
  struct timeval tv;
  tv.tv_sec = 1;
  tv.tv_usec = 0;
  event_add((struct event *)arg, &tv);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msplot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edi,-0x24(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D49(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D38(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  movapd %xmm1,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  D41(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D38(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xfffffffd,-0x24(%rbp)
  jne    L19
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <moveTo@plt>
  jmp    L28
L19:
  cmpl   $0xfffffffe,-0x24(%rbp)
  jne    L51
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <lineTo@plt>
  jmp    L28
L51:
  cmpl   $0x3,-0x24(%rbp)
  jne    L59
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <moveTo@plt>
  jmp    L28
L59:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <lineTo@plt>
L28:
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: f64
name: read_data
arguments: data_tag: D49
type_infered: byte[8]
name: read_data
arguments: data_tag: D38
type_infered: f64
name: read_data
arguments: data_tag: D41
type_infered: f64

tool: D3: 29

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D38: 0.5

tool: D41: 340

assistant: ```c
int msplot(x, y, n)
double x, y;
int n;
{
  int ix, iy;
  ix = (int)((29.0 * x) + 5 + 0.5);
  iy = (int)((340.0 - (29.0 * (y))) + 0.5);
  if (n == -3) {
    moveTo(ix, iy);
  } else if (n == -2) {
    lineTo(ix, iy);
  } else if (n == 3) {
    moveTo(ix, iy);
  } else {
    lineTo(ix, iy);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msplot>:
  endbr64
  sub    $0x8,%rsp
  movsd  D24(%rip),%xmm3
  mulsd  %xmm3,%xmm0
  addsd  D1(%rip),%xmm0
  movsd  D26(%rip),%xmm2
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%eax
  mulsd  %xmm3,%xmm1
  movsd  D16(%rip),%xmm0
  subsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%esi
  cmp    $0xfffffffd,%edi
  je     L2
  cmp    $0xfffffffe,%edi
  je     L40
  cmp    $0x3,%edi
  je     L9
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <lineTo@plt>
L3:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L2:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <moveTo@plt>
  jmp    L3
L40:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <lineTo@plt>
  jmp    L3
L9:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <moveTo@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_infered: f64
name: disassemble_data
arguments: data_label: D1
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D26
type_infered: f64
name: disassemble_data
arguments: data_label: D16
type_infered: f64

tool: D24: 29

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D26: 0.5

tool: D16: 340

assistant: ```c
int msplot(x, y, n)
double x, y;
int n;
{
  int ix, iy;
  ix = (int)((29.0 * x) + 5 + 0.5);
  iy = (int)((340.0 - (29.0 * (y))) + 0.5);
  if (n == -3) {
    moveTo(ix, iy);
  } else if (n == -2) {
    lineTo(ix, iy);
  } else if (n == 3) {
    moveTo(ix, iy);
  } else {
    lineTo(ix, iy);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msplot>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm3
  movsd  D2(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  addsd  D33(%rip),%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%r8d
  movsd  D15(%rip),%xmm0
  subsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%esi
  cmp    $0xfffffffd,%edi
  je     L7
  cmp    $0xfffffffe,%edi
  je     L26
  cmp    $0x3,%edi
  mov    $0x0,%eax
  mov    %r8d,%edi
  je     L11
  call   <lineTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  call   <moveTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nop
L7:
  mov    %r8d,%edi
  xor    %eax,%eax
  call   <moveTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L26:
  mov    %r8d,%edi
  xor    %eax,%eax
  call   <lineTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: f64
name: read_data
arguments: tag: D2
type_guessed: f64
name: read_data
arguments: tag: D33
type_guessed: byte[8]
name: read_data
arguments: tag: D15
type_guessed: f64

tool: D14: 29

tool: D2: 0.5

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D15: 340

assistant: ```c
int msplot(x, y, n)
double x, y;
int n;
{
  int ix, iy;
  ix = (int)((29.0 * x) + 5 + 0.5);
  iy = (int)((340.0 - (29.0 * (y))) + 0.5);
  if (n == -3) {
    moveTo(ix, iy);
  } else if (n == -2) {
    lineTo(ix, iy);
  } else if (n == 3) {
    moveTo(ix, iy);
  } else {
    lineTo(ix, iy);
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<msplot>:
  endbr64
  sub    $0x8,%rsp
  movsd  D2(%rip),%xmm3
  movsd  D27(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  addsd  D3(%rip),%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%r8d
  movsd  D24(%rip),%xmm0
  subsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%esi
  cmp    $0xfffffffd,%edi
  je     L29
  cmp    $0xfffffffe,%edi
  je     L16
  cmp    $0x3,%edi
  mov    $0x0,%eax
  mov    %r8d,%edi
  je     L7
  call   <lineTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  call   <moveTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nop
L29:
  mov    %r8d,%edi
  xor    %eax,%eax
  call   <moveTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L16:
  mov    %r8d,%edi
  xor    %eax,%eax
  call   <lineTo@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: f64
name: unpack_data
arguments: data_tag: D27
datatype: f64
name: unpack_data
arguments: data_tag: D3
datatype: byte[8]
name: unpack_data
arguments: data_tag: D24
datatype: f64

tool: D2: 29

tool: D27: 0.5

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: D24: 340

assistant: ```c
int msplot(x, y, n)
double x, y;
int n;
{
  int ix, iy;
  ix = (int)((29.0 * x) + 5 + 0.5);
  iy = (int)((340.0 - (29.0 * (y))) + 0.5);
  if (n == -3) {
    moveTo(ix, iy);
  } else if (n == -2) {
    lineTo(ix, iy);
  } else if (n == 3) {
    moveTo(ix, iy);
  } else {
    lineTo(ix, iy);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reset_candidates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_exponential_buffer_data@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_exponential_buffer_size@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L2:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void reset_candidates(struct binary_exponential_buffer *candidates) {
  unsigned int *p = (unsigned int *)binary_exponential_buffer_data(candidates);
  unsigned int num_candidates = binary_exponential_buffer_size(candidates);
  unsigned int i;
  for (i = 0; i < num_candidates; i++) {
    p[i] = 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reset_candidates>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <binary_exponential_buffer_data@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <binary_exponential_buffer_size@plt>
  test   %eax,%eax
  je     L3
  mov    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x4(%rbp,%rax,4),%rax
L17:
  movl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L17
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void reset_candidates(struct binary_exponential_buffer *candidates) {
  unsigned int *p = (unsigned int *)binary_exponential_buffer_data(candidates);
  unsigned int num_candidates = binary_exponential_buffer_size(candidates);
  unsigned int i;
  for (i = 0; i < num_candidates; i++) {
    p[i] = 1;
  }
}
```