user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    D57(%rip),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L54
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L72
L54:
  lea    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D69(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    $0xff,%esi
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L3:
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%esi
  lea    (%rcx,%rdx,1),%eax
  mov    %esi,%edx
  mov    %eax,-0x20(%rbp,%rdx,4)
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%eax
  shr    $0x8,%eax
  mov    %eax,%esi
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%eax
  movzbl %al,%edx
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%ecx
  lea    (%rsi,%rdx,1),%eax
  mov    %ecx,%edx
  mov    %eax,-0x20(%rbp,%rdx,4)
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%eax
  shr    $0x8,%eax
  mov    %eax,%esi
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rsi,1),%eax
  mov    %ecx,%edx
  mov    %eax,-0x20(%rbp,%rdx,4)
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%eax
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x30(%rbp),%eax
  mov    -0x2c(%rbp),%ecx
  lea    0x1(%rcx),%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2c,-0x2c(%rbp)
  je     L10
  addl   $0x1,-0x2c(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
L29:
  lea    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D69(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
L76:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L3
  jmp    L25
L10:
  nop
L25:
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,%edi
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L72:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D57
type_guessed: string
name: extract_symbolic_data
arguments: tag: D64
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D69
type_guessed: string
name: extract_symbolic_data
arguments: tag: D77
type_guessed: string
name: extract_symbolic_data
arguments: tag: D54
type_guessed: string
name: extract_symbolic_data
arguments: tag: D41
type_guessed: string

tool: D57: r

tool: D64: header.txt

tool: D31: error opening header.txt

tool: D69: %x

tool: D77: test %d


tool: D54: %02x: %02x sum(%x) 

tool: D41: 
hlen = %d,sum[0-3] %02x-%02x-%02x-%02x 


assistant: ```c
int main() {
  unsigned int sum[4] = {0};
  unsigned int hdata, hlen = 0;
  FILE *fp = fopen("header.txt", "r");
  if (fp == NULL) {
    printf("error opening header.txt\n");
    return -1;
  }
  fscanf(fp, "%x", &hdata);
  printf("test %d\n", 0 + 0xff);
  while (!feof(fp)) {
    sum[hlen % 4] += hdata;
    sum[hlen % 4] = (sum[hlen % 4] >> 8) + (sum[hlen % 4] & 0xff);
    sum[hlen % 4] += (sum[hlen % 4] >> 8);
    printf("%02x: %02x sum(%x) ", (hlen + 1), hdata, sum[hlen % 4]);
    if (hlen == 44)
      break;
    hlen++;
    if (hlen % 10 == 0)
      printf("\n");
    fscanf(fp, "%x", &hdata);
  }
  printf("\nhlen = %d,sum[0-3] %02x-%02x-%02x-%02x \n", hlen, ~sum[0], ~sum[1], ~sum[2], ~sum[3]);
  return 0;
}
```