ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  movsbl -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movzbl -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D57
data_type: string
name: read_data
arguments: tag: D25
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D57: %c

tool: D25: %hhu

tool: D9: %hhi

assistant: ```c
void check_char(unsigned char x, signed char y) {
  printf("%c", y);
  printf("%hhu", x);
  printf("%hhi", y);
  printf("%hhi", x);
  printf("%c", x);
  printf("%hhu", y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_char>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movsbl %sil,%ebp
  mov    %ebp,%esi
  lea    D9(%rip),%r13
  mov    %r13,%rdi
  call   <printf@plt>
  movsbl %bl,%ebx
  mov    %ebx,%esi
  lea    D27(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%r14
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string
name: retrieve_data
arguments: tag: D27
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D9: %c

tool: D27: %hhu

tool: D0: %hhi

assistant: ```c
void check_char(unsigned char x, signed char y) {
  printf("%c", y);
  printf("%hhu", x);
  printf("%hhi", y);
  printf("%hhi", x);
  printf("%c", x);
  printf("%hhu", y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_char>:
  endbr64
  push   %r15
  lea    D9(%rip),%r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%esi
  mov    %r14,%rdi
  movsbl %bpl,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  pop    %rbp
  mov    %r12d,%esi
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D9: %hhi

tool: D6: %c

tool: D16: %hhu

assistant: ```c
void check_char(unsigned char x, signed char y) {
  printf("%c", y);
  printf("%hhu", x);
  printf("%hhi", y);
  printf("%hhi", x);
  printf("%c", x);
  printf("%hhu", y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_char>:
  endbr64
  push   %r15
  lea    D14(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%esi
  mov    %r14,%rdi
  movsbl %bpl,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  pop    %rbp
  mov    %r12d,%esi
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D28
type: string

tool: D14: %hhi

tool: D8: %c

tool: D28: %hhu

assistant: ```c
void check_char(unsigned char x, signed char y) {
  printf("%c", y);
  printf("%hhu", x);
  printf("%hhi", y);
  printf("%hhi", x);
  printf("%c", x);
  printf("%hhu", y);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    $0x1,%eax
  je     L7
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L7:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int main() {
  int A[10];
  A[1] = 0;
#pragma scop
  int i = 1;
  i = i * i;
  A[i] = 1;
  A[0] = 0;
#pragma endscop
  if (A[1] != 1)
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  int A[10];
  A[1] = 0;
#pragma scop
  int i = 1;
  i = i * i;
  A[i] = 1;
  A[0] = 0;
#pragma endscop
  if (A[1] != 1)
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  int A[10];
  A[1] = 0;
#pragma scop
  int i = 1;
  i = i * i;
  A[i] = 1;
  A[0] = 0;
#pragma endscop
  if (A[1] != 1)
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  int A[10];
  A[1] = 0;
#pragma scop
  int i = 1;
  i = i * i;
  A[i] = 1;
  A[0] = 0;
#pragma endscop
  if (A[1] != 1)
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stable_mixed_volume_by_demics>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x34c,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int stable_mixed_volume_by_demics(int *mv, int *smv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(844, mv, smv, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stable_mixed_volume_by_demics>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rsi
  mov    $0x34c,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int stable_mixed_volume_by_demics(int *mv, int *smv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(844, mv, smv, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stable_mixed_volume_by_demics>:
  endbr64
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    $0x34c,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int stable_mixed_volume_by_demics(int *mv, int *smv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(844, mv, smv, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stable_mixed_volume_by_demics>:
  endbr64
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    $0x34c,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int stable_mixed_volume_by_demics(int *mv, int *smv) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(844, mv, smv, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ldiv@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D36
type_guessed: string

tool: D9: %lf%lf


tool: D19: %d


tool: D18: %ld


tool: D36: %lf


assistant: ```c
int main() {
  double a, b;
  scanf("%lf%lf\n", &a, &b);
  printf("%d\n", (int)(a / b));
  printf("%ld\n", ldiv((int)a, (int)b).rem);
  printf("%lf\n", a / b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  lea    D12(%rip),%rdi
  call   <printf@plt>
  cvttsd2si 0x10(%rsp),%esi
  cvttsd2si 0x8(%rsp),%edi
  call   <ldiv@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D36
type_infered: string

tool: D9: %lf%lf


tool: D12: %d


tool: D18: %ld


tool: D36: %lf


assistant: ```c
int main() {
  double a, b;
  scanf("%lf%lf\n", &a, &b);
  printf("%d\n", (int)(a / b));
  printf("%ld\n", ldiv((int)a, (int)b).rem);
  printf("%lf\n", a / b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  lea    D3(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  call   <printf@plt>
  cvttsd2si 0x10(%rsp),%esi
  cvttsd2si 0x8(%rsp),%edi
  call   <ldiv@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string

tool: D37: %lf%lf


tool: D3: %d


tool: D30: %ld


tool: D28: %lf


assistant: ```c
int main() {
  double a, b;
  scanf("%lf%lf\n", &a, &b);
  printf("%d\n", (int)(a / b));
  printf("%ld\n", ldiv((int)a, (int)b).rem);
  printf("%lf\n", a / b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  call   <printf@plt>
  cvttsd2si 0x10(%rsp),%esi
  cvttsd2si 0x8(%rsp),%edi
  call   <ldiv@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  movsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D13: %lf%lf


tool: D16: %d


tool: D4: %ld


tool: D0: %lf


assistant: ```c
int main() {
  double a, b;
  scanf("%lf%lf\n", &a, &b);
  printf("%d\n", (int)(a / b));
  printf("%ld\n", ldiv((int)a, (int)b).rem);
  printf("%lf\n", a / b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_strmapi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L43
  cmpq   $0x0,-0x40(%rbp)
  je     L43
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L8
L15:
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%rdx
  mov    %edx,%ecx
  mov    -0x18(%rbp),%rsi
  mov    -0x28(%rbp),%rdx
  lea    (%rsi,%rdx,1),%rbx
  mov    -0x40(%rbp),%rdx
  mov    %eax,%esi
  mov    %ecx,%edi
  call   *%rdx
  mov    %al,(%rbx)
  addq   $0x1,-0x28(%rbp)
L32:
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L8
L43:
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  size_t i;
  size_t len;
  char *new;
  i = 0;
  if (s != NULL && f != NULL) {
    len = ft_strlen(s);
    new = (char *)malloc(sizeof(char) * len + 1);
    if (new == NULL)
      return (NULL);
    while (s[i] != '\0') {
      new[i] = (*f)(i, s[i]);
      i++;
    }
    new[i] = '\0';
    return (new);
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L60
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L60
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%r14d
  test   %rax,%rax
  je     L20
  mov    %rax,%r14
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L53
  mov    $0x0,%ebx
L15:
  movsbl %sil,%esi
  mov    %ebx,%edi
  call   *%r12
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  jne    L15
L6:
  movb   $0x0,0x0(%r13,%rbx,1)
  jmp    L20
L53:
  mov    $0x0,%ebx
  jmp    L6
L60:
  mov    $0x0,%r14d
L20:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  size_t i;
  size_t len;
  char *new;
  i = 0;
  if (s != NULL && f != NULL) {
    len = ft_strlen(s);
    new = (char *)malloc(sizeof(char) * len + 1);
    if (new == NULL)
      return (NULL);
    while (s[i] != '\0') {
      new[i] = (*f)(i, s[i]);
      i++;
    }
    new[i] = '\0';
    return (new);
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L2
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L2
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  movsbl (%rbx),%esi
  mov    %rax,%r13
  test   %sil,%sil
  je     L21
  xor    %r14d,%r14d
  nop
L23:
  mov    %r14d,%edi
  call   *%rbp
  mov    %al,(%r12,%r14,1)
  add    $0x1,%r14
  movsbl (%rbx,%r14,1),%esi
  test   %sil,%sil
  jne    L23
  add    %r14,%r12
L21:
  movb   $0x0,(%r12)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  size_t i;
  size_t len;
  char *new;
  i = 0;
  if (s != NULL && f != NULL) {
    len = ft_strlen(s);
    new = (char *)malloc(sizeof(char) * len + 1);
    if (new == NULL)
      return (NULL);
    while (s[i] != '\0') {
      new[i] = (*f)(i, s[i]);
      i++;
    }
    new[i] = '\0';
    return (new);
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strmapi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L47
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L47
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L47
  movsbl (%rbx),%esi
  mov    %rax,%r13
  test   %sil,%sil
  je     L38
  xor    %r14d,%r14d
  nop
L11:
  mov    %r14d,%edi
  call   *%rbp
  mov    %al,(%r12,%r14,1)
  add    $0x1,%r14
  movsbl (%rbx,%r14,1),%esi
  test   %sil,%sil
  jne    L11
  add    %r14,%r12
L38:
  movb   $0x0,(%r12)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ft_strmapi(char const *s, char (*f)(unsigned int, char)) {
  size_t i;
  size_t len;
  char *new;
  i = 0;
  if (s != NULL && f != NULL) {
    len = ft_strlen(s);
    new = (char *)malloc(sizeof(char) * len + 1);
    if (new == NULL)
      return (NULL);
    while (s[i] != '\0') {
      new[i] = (*f)(i, s[i]);
      i++;
    }
    new[i] = '\0';
    return (new);
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cd_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L12
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L12:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D2
type: string

tool: D18: cd: wrong number of parameters

tool: D2: cd: new working directory = %s


assistant: ```c
int cd_main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("cd: wrong number of parameters\n");
    return -1;
  }
  char *path = argv[1];
  printf("cd: new working directory = %s\n", path);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cd_main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L13
  mov    0x8(%rsi),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L5:
  add    $0x8,%rsp
  ret
L13:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D19
datatype: string

tool: D1: cd: new working directory = %s


tool: D19: cd: wrong number of parameters

assistant: ```c
int cd_main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("cd: wrong number of parameters\n");
    return -1;
  }
  char *path = argv[1];
  printf("cd: new working directory = %s\n", path);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cd_main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L4
  mov    0x8(%rsi),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L13:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D0: cd: new working directory = %s


tool: D5: cd: wrong number of parameters

assistant: ```c
int cd_main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("cd: wrong number of parameters\n");
    return -1;
  }
  char *path = argv[1];
  printf("cd: new working directory = %s\n", path);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cd_main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L10
  mov    0x8(%rsi),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L18:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D6: cd: new working directory = %s


tool: D15: cd: wrong number of parameters

assistant: ```c
int cd_main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("cd: wrong number of parameters\n");
    return -1;
  }
  char *path = argv[1];
  printf("cd: new working directory = %s\n", path);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isnumeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L46
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L5
L23:
  mov    $0x0,%eax
  jmp    L9
L5:
  addq   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0x1,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int isnumeric(char *s) {
  char *p;
  for (p = s; *p; p++)
    if (*p < '0' || *p > '9')
      return 0;
  return 1;
}
```