ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movl   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%r12
  movq   $0x3e8,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <pru_bridge_init@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <pru_channel_open@plt>
  nopl   (%rax)
L6:
  mov    %r12,%rsi
  mov    $0x1,%edi
  mov    $0x4,%edx
  call   <pru_read@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x1,%edi
  call   <pru_channel_close@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  int size[5] = {1000, 0, 0, 0, 0};
  pru_bridge_init(size);
  pru_channel_open(1, 0);
  int pru_data, i = 0;
  while (i < 1000) {
    pru_read(1, (uint8_t *)(&pru_data), 4);
    printf("%d\n", pru_data);
    i++;
  }
  pru_channel_close(1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x30,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movl   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%r12
  movaps %xmm0,0x10(%rsp)
  call   <pru_bridge_init@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <pru_channel_open@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rsi
  mov    $0x1,%edi
  mov    $0x4,%edx
  call   <pru_read@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    $0x1,%edi
  call   <pru_channel_close@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: byte[16]

tool: D16: %d


tool: {"D4": [0xe8,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int size[5] = {1000, 0, 0, 0, 0};
  pru_bridge_init(size);
  pru_channel_open(1, 0);
  int pru_data, i = 0;
  while (i < 1000) {
    pru_read(1, (uint8_t *)(&pru_data), 4);
    printf("%d\n", pru_data);
    i++;
  }
  pru_channel_close(1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expRecordConnectAndLoadTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlConnect@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expRecordLoadTable@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlDisconnect@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
struct expRecord *expRecordConnectAndLoadTable(char *database, char *table) {
  struct sqlConnection *conn = sqlConnect(database);
  struct expRecord *ers = expRecordLoadTable(conn, table);
  sqlDisconnect(&conn);
  return ers;
}
```
user: Translate the below assembly code into C programming language:

```asm
<expRecordConnectAndLoadTable>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sqlConnect@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    %rbx,%rsi
  call   <expRecordLoadTable@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  call   <sqlDisconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct expRecord *expRecordConnectAndLoadTable(char *database, char *table) {
  struct sqlConnection *conn = sqlConnect(database);
  struct expRecord *ers = expRecordLoadTable(conn, table);
  sqlDisconnect(&conn);
  return ers;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expRecordConnectAndLoadTable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sqlConnect@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <expRecordLoadTable@plt>
  mov    %rsp,%rdi
  mov    %rax,%r12
  call   <sqlDisconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct expRecord *expRecordConnectAndLoadTable(char *database, char *table) {
  struct sqlConnection *conn = sqlConnect(database);
  struct expRecord *ers = expRecordLoadTable(conn, table);
  sqlDisconnect(&conn);
  return ers;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expRecordConnectAndLoadTable>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sqlConnect@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <expRecordLoadTable@plt>
  mov    %rsp,%rdi
  mov    %rax,%r12
  call   <sqlDisconnect@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct expRecord *expRecordConnectAndLoadTable(char *database, char *table) {
  struct sqlConnection *conn = sqlConnect(database);
  struct expRecord *ers = expRecordLoadTable(conn, table);
  sqlDisconnect(&conn);
  return ers;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Div0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <Log@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: Divison by zero

assistant: ```c
void Div0() {
  Log("Divison by zero");
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Div0>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <Log@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: Divison by zero

assistant: ```c
void Div0() {
  Log("Divison by zero");
  abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Div0>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <Log@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: Divison by zero

assistant: ```c
void Div0() {
  Log("Divison by zero");
  abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<Div0>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <Log@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: Divison by zero

assistant: ```c
void Div0() {
  Log("Divison by zero");
  abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CE_pHP_CO2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D3(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D22(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D15(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x38(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movq   D15(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x28(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: byte[8]
name: disassemble_data
arguments: tag: D22
type: byte[8]
name: disassemble_data
arguments: tag: D15
type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHP_CO2(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -H3O * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O);
  return t0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CE_pHP_CO2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movapd %xmm0,%xmm6
  movq   %xmm1,%rbx
  movq   %xmm2,%r12
  movq   %xmm3,%rbp
  movq   %xmm4,%r13
  movq   %xmm5,%r14
  movsd  D3(%rip),%xmm0
  subsd  %xmm6,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D16(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm7
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm7
  movsd  %xmm7,0x8(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %r12,%xmm6
  divsd  %xmm0,%xmm6
  movsd  %xmm6,0x10(%rsp)
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rsp)
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm3
  movsd  0x8(%rsp),%xmm7
  movapd %xmm7,%xmm2
  mulsd  %xmm7,%xmm2
  movq   %rbx,%xmm0
  mulsd  %xmm7,%xmm0
  movq   %r13,%xmm4
  divsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  movapd %xmm7,%xmm1
  xorpd  D15(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  0x18(%rsp),%xmm1
  mulsd  0x10(%rsp),%xmm1
  subsd  %xmm1,%xmm2
  divsd  %xmm2,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: byte[8]
name: read_data
arguments: label: D16
type_infered: byte[8]
name: read_data
arguments: label: D15
type_infered: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO2(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -H3O * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O);
  return t0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CE_pHP_CO2>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D8(%rip),%xmm0
  movsd  %xmm1,0x38(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x30(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D22(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm6
  divsd  %xmm5,%xmm6
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x20(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm6
  movapd %xmm0,%xmm2
  movsd  0x38(%rsp),%xmm1
  divsd  %xmm2,%xmm4
  movapd %xmm6,%xmm0
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm0
  xorpd  D15(%rip),%xmm6
  mulsd  0x8(%rsp),%xmm2
  add    $0x48,%rsp
  subsd  %xmm4,%xmm1
  addsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: byte[8]
name: retrieve_data
arguments: label: D22
datatype: byte[8]
name: retrieve_data
arguments: label: D15
datatype: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO2(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -H3O * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O);
  return t0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CE_pHP_CO2>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D17(%rip),%xmm0
  movsd  %xmm1,0x38(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x30(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D9(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm6
  divsd  %xmm5,%xmm6
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x20(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm6
  movapd %xmm0,%xmm2
  movsd  0x38(%rsp),%xmm1
  divsd  %xmm2,%xmm4
  movapd %xmm6,%xmm0
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm0
  xorpd  D15(%rip),%xmm6
  mulsd  0x8(%rsp),%xmm2
  add    $0x48,%rsp
  subsd  %xmm4,%xmm1
  addsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D9
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D15
type_infered: byte[16]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO2(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -H3O * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O);
  return t0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<InvSqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x14(%rbp),%xmm1
  movss  D2(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    $0x5f375a86,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0xc(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  D7(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D7
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

tool: {"D7": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float InvSqrt(float x) {
  float xhalf = 0.5f * x;
  int i = *(int *)&x;
  i = 0x5f375a86 - (i >> 1);
  x = *(float *)&i;
  x = x * (1.5f - xhalf * x * x);
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<InvSqrt>:
  endbr64
  movd   %xmm0,%edx
  sar    %edx
  mov    $0x5f375a86,%eax
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  D2(%rip),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  movss  D10(%rip),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: byte[4]
name: extract_symbolic_data
arguments: tag: D10
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

tool: {"D10": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float InvSqrt(float x) {
  float xhalf = 0.5f * x;
  int i = *(int *)&x;
  i = 0x5f375a86 - (i >> 1);
  x = *(float *)&i;
  x = x * (1.5f - xhalf * x * x);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<InvSqrt>:
  endbr64
  movd   %xmm0,%edx
  mov    $0x5f375a86,%eax
  movss  D1(%rip),%xmm1
  mulss  D16(%rip),%xmm0
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: byte[4]
name: disassemble_data
arguments: label: D16
data_type: byte[4]

tool: {"D1": [0x00,0x00,0xc0,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float InvSqrt(float x) {
  float xhalf = 0.5f * x;
  int i = *(int *)&x;
  i = 0x5f375a86 - (i >> 1);
  x = *(float *)&i;
  x = x * (1.5f - xhalf * x * x);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<InvSqrt>:
  endbr64
  movd   %xmm0,%edx
  mov    $0x5f375a86,%eax
  movss  D6(%rip),%xmm1
  mulss  D13(%rip),%xmm0
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D13
datatype: byte[4]

tool: {"D6": [0x00,0x00,0xc0,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float InvSqrt(float x) {
  float xhalf = 0.5f * x;
  int i = *(int *)&x;
  i = 0x5f375a86 - (i >> 1);
  x = *(float *)&i;
  x = x * (1.5f - xhalf * x * x);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  struct serial_struct serial;
  (void)serial;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  struct serial_struct serial;
  (void)serial;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  struct serial_struct serial;
  (void)serial;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  struct serial_struct serial;
  (void)serial;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  movl   $0x1,-0x18(%rbp)
  jmp    L44
L24:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x18(%rbp)
L44:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L24
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L38
L42:
  movsbl -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L42
  jmp    L3
L4:
  nop
L3:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int str_split(char *const str, const char separator, char **const fields, const int max_fields) {
  fields[0] = str;
  for (int i = 1; i < max_fields; ++i)
    fields[i] = NULL;
  char *search_pos = str;
  int count = 1;
  while (count < max_fields) {
    char *sep = strchr(search_pos, separator);
    if (sep == NULL)
      break;
    *sep = '\0';
    fields[count] = search_pos = (sep + 1);
    count += 1;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,(%rdx)
  cmp    $0x1,%ecx
  jle    L27
  mov    %ecx,%r12d
  lea    0x8(%rdx),%rbp
  lea    -0x2(%rcx),%eax
  lea    0x10(%rdx,%rax,8),%rdx
  mov    %rbp,%rax
L11:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
  mov    $0x1,%ebx
  movsbl %sil,%r13d
L25:
  mov    %r13d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L31
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  mov    %rdi,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  jne    L25
  mov    %r12d,%ebx
L31:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x1,%ebx
  jmp    L31
```

assistant: ```c
int str_split(char *const str, const char separator, char **const fields, const int max_fields) {
  fields[0] = str;
  for (int i = 1; i < max_fields; ++i)
    fields[i] = NULL;
  char *search_pos = str;
  int count = 1;
  while (count < max_fields) {
    char *sep = strchr(search_pos, separator);
    if (sep == NULL)
      break;
    *sep = '\0';
    fields[count] = search_pos = (sep + 1);
    count += 1;
  }
  return count;
}
```