ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_ctl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movsbl (%rsi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x23,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L20
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mixer_get_control@plt>
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %rbx,%rdi
  call   <atoi@plt>
  lea    -0x1(%rax),%esi
  mov    %rbp,%rdi
  call   <mixer_get_nth_control@plt>
  jmp    L17
```

assistant: ```c
struct mixer_ctl *get_ctl(struct mixer *mixer, char *name) {
  char *p;
  unsigned idx = 0;
  if (isdigit(name[0]))
    return mixer_get_nth_control(mixer, atoi(name) - 1);
  p = strrchr(name, '#');
  if (p) {
    *p++ = 0;
    idx = atoi(p);
  }
  return mixer_get_control(mixer, name, idx);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_ctl>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x23,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
L8:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <mixer_get_control@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  lea    -0x1(%rax),%esi
  pop    %r12
  jmp    10b0 <mixer_get_nth_control@plt>
```

assistant: ```c
struct mixer_ctl *get_ctl(struct mixer *mixer, char *name) {
  char *p;
  unsigned idx = 0;
  if (isdigit(name[0]))
    return mixer_get_nth_control(mixer, atoi(name) - 1);
  p = strrchr(name, '#');
  if (p) {
    *p++ = 0;
    idx = atoi(p);
  }
  return mixer_get_control(mixer, name, idx);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_ctl>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x23,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  xor    %edx,%edx
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
L2:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10d0 <mixer_get_control@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  call   <atoi@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  lea    -0x1(%rax),%esi
  pop    %r12
  jmp    10b0 <mixer_get_nth_control@plt>
```

assistant: ```c
struct mixer_ctl *get_ctl(struct mixer *mixer, char *name) {
  char *p;
  unsigned idx = 0;
  if (isdigit(name[0]))
    return mixer_get_nth_control(mixer, atoi(name) - 1);
  p = strrchr(name, '#');
  if (p) {
    *p++ = 0;
    idx = atoi(p);
  }
  return mixer_get_control(mixer, name, idx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writeessidsweeped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x2,D84(%rip)
  jmp    L15
L8:
  movl   $0x0,D37(%rip)
  jmp    L19
L5:
  mov    $0x40,%edx
  mov    $0x0,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D84(%rip),%eax
  mov    D37(%rip),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    D84(%rip),%ecx
  mov    -0x8(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <writeessidremoved@plt>
  mov    D37(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D74(%rip)
L19:
  mov    D84(%rip),%ecx
  mov    -0xc(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    D74(%rip),%eax
  cmp    %eax,%edx
  jge    L5
  mov    D84(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D74(%rip)
L15:
  mov    D74(%rip),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L8
  nop
  leave
  ret
```

assistant: ```c
void writeessidsweeped(FILE *fhout, uint8_t essidlen, uint8_t *essid) {
  static int l1, l2;
  static uint8_t sweepstring[64] = {};
  for (l1 = 2; l1 <= essidlen; l1++) {
    for (l2 = 0; l2 <= essidlen - l1; l2++) {
      memset(&sweepstring, 0, 64);
      memcpy(&sweepstring, &essid[l2], l1);
      writeessidremoved(fhout, l1, sweepstring);
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<writeessidsweeped>:
  endbr64
  movl   $0x2,D57(%rip)
  cmp    $0x1,%esi
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%r13
  lea    D3(%rip),%rbx
L8:
  movl   $0x0,D5(%rip)
  mov    D57(%rip),%edx
  cmp    %edx,%ebp
  jl     L16
L28:
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movslq D5(%rip),%rax
  lea    0x0(%r13,%rax,4),%rsi
  mov    D57(%rip),%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    D57(%rip),%esi
  mov    %r12,%rdi
  call   <writeessidremoved@plt>
  mov    D5(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D6(%rip)
  mov    D57(%rip),%edx
  mov    %ebp,%ecx
  sub    %edx,%ecx
  cmp    %ecx,%eax
  jle    L28
L16:
  add    $0x1,%edx
  mov    %edx,D6(%rip)
  cmp    %ebp,%edx
  jle    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  ret
```

assistant: ```c
void writeessidsweeped(FILE *fhout, uint8_t essidlen, uint8_t *essid) {
  static int l1, l2;
  static uint8_t sweepstring[64] = {};
  for (l1 = 2; l1 <= essidlen; l1++) {
    for (l2 = 0; l2 <= essidlen - l1; l2++) {
      memset(&sweepstring, 0, 64);
      memcpy(&sweepstring, &essid[l2], l1);
      writeessidremoved(fhout, l1, sweepstring);
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writeessidsweeped>:
  endbr64
  movl   $0x2,D47(%rip)
  cmp    $0x1,%esi
  jle    L11
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    $0x2,%edx
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    D93(%rip),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  movl   $0x0,D69(%rip)
  cmp    %edx,%ebp
  jl     L25
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movslq D69(%rip),%rax
  mov    D47(%rip),%edx
  mov    %rbx,%rdi
  lea    (%r12,%rax,4),%rsi
  call   <memcpy@plt>
  mov    D47(%rip),%esi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <writeessidremoved@plt>
  mov    D69(%rip),%eax
  mov    D47(%rip),%edx
  mov    %ebp,%ecx
  add    $0x1,%eax
  sub    %edx,%ecx
  mov    %eax,D15(%rip)
  cmp    %ecx,%eax
  jle    L19
L25:
  add    $0x1,%edx
  mov    %edx,D15(%rip)
  cmp    %ebp,%edx
  jle    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  ret
```

assistant: ```c
void writeessidsweeped(FILE *fhout, uint8_t essidlen, uint8_t *essid) {
  static int l1, l2;
  static uint8_t sweepstring[64] = {};
  for (l1 = 2; l1 <= essidlen; l1++) {
    for (l2 = 0; l2 <= essidlen - l1; l2++) {
      memset(&sweepstring, 0, 64);
      memcpy(&sweepstring, &essid[l2], l1);
      writeessidremoved(fhout, l1, sweepstring);
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeessidsweeped>:
  endbr64
  movl   $0x2,D43(%rip)
  cmp    $0x1,%esi
  jle    L31
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  mov    $0x2,%edx
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    D58(%rip),%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L25:
  movl   $0x0,D62(%rip)
  cmp    %edx,%ebp
  jl     L22
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    $0x40,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movslq D62(%rip),%rax
  mov    D43(%rip),%edx
  mov    %rbx,%rdi
  lea    (%r12,%rax,4),%rsi
  call   <memcpy@plt>
  mov    D43(%rip),%esi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <writeessidremoved@plt>
  mov    D62(%rip),%eax
  mov    D43(%rip),%edx
  mov    %ebp,%ecx
  add    $0x1,%eax
  sub    %edx,%ecx
  mov    %eax,D89(%rip)
  cmp    %ecx,%eax
  jle    L34
L22:
  add    $0x1,%edx
  mov    %edx,D89(%rip)
  cmp    %ebp,%edx
  jle    L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  ret
```

assistant: ```c
void writeessidsweeped(FILE *fhout, uint8_t essidlen, uint8_t *essid) {
  static int l1, l2;
  static uint8_t sweepstring[64] = {};
  for (l1 = 2; l1 <= essidlen; l1++) {
    for (l2 = 0; l2 <= essidlen - l1; l2++) {
      memset(&sweepstring, 0, 64);
      memcpy(&sweepstring, &essid[l2], l1);
      writeessidremoved(fhout, l1, sweepstring);
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<d2uc_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L3
  movsd  D12(%rip),%xmm0
  jmp    L8
L3:
  movsd  D9(%rip),%xmm0
L8:
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L25:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <lrint@plt>
  mov    %eax,%ecx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  lea    -0x80(%rcx),%edx
  mov    %dl,(%rax)
L18:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L25
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: byte[8]
name: parse_data
arguments: data_tag: D9
type_infered: f64

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0xc0,0x5f,0x40]}

tool: D9: 1

assistant: ```c
void d2uc_array(double *src, unsigned char *dest, int count, int normalize) {
  double normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrint(src[count] * normfact) + 128;
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<d2uc_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    D9(%rip),%r13
  test   %ecx,%ecx
  jne    L25
  mov    D11(%rip),%r13
L25:
  sub    $0x1,%ebx
  js     L23
  movslq %ebx,%rbx
L5:
  movq   %r13,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  add    $0xffffff80,%eax
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L5
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: byte[8]
name: unpack_data
arguments: tag: D11
type_infered: f64

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0xc0,0x5f,0x40]}

tool: D11: 1

assistant: ```c
void d2uc_array(double *src, unsigned char *dest, int count, int normalize) {
  double normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrint(src[count] * normfact) + 128;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d2uc_array>:
  endbr64
  push   %r14
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  movsd  D0(%rip),%xmm1
  movq   %xmm1,%r14
  test   %ecx,%ecx
  jne    L25
  movsd  D19(%rip),%xmm2
  movq   %xmm2,%r14
L25:
  sub    $0x1,%ebx
  js     L2
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L17:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  add    $0xffffff80,%eax
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L17
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: byte[8]
name: parse_data
arguments: data_label: D19
datatype: f64

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0xc0,0x5f,0x40]}

tool: D19: 1

assistant: ```c
void d2uc_array(double *src, unsigned char *dest, int count, int normalize) {
  double normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrint(src[count] * normfact) + 128;
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<d2uc_array>:
  endbr64
  push   %r14
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm1
  movq   %xmm1,%r14
  test   %ecx,%ecx
  jne    L2
  movsd  D17(%rip),%xmm2
  movq   %xmm2,%r14
L2:
  sub    $0x1,%ebx
  js     L16
  movslq %ebx,%rbx
  nopl   0x0(%rax)
L15:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  add    $0xffffff80,%eax
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L15
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D17
type_guessed: f64

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0xc0,0x5f,0x40]}

tool: D17: 1

assistant: ```c
void d2uc_array(double *src, unsigned char *dest, int count, int normalize) {
  double normfact;
  normfact = normalize ? (1.0 * 0x7F) : 1.0;
  while (--count >= 0) {
    dest[count] = lrint(src[count] * normfact) + 128;
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minCostClimbingStairs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  movl   $0x2,-0x1c(%rbp)
  jmp    L16
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    %ebx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L0
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int minCostClimbingStairs(int *cost, int costSize) {
  int *result = malloc(sizeof(int) * costSize);
  result[0] = cost[0];
  result[1] = cost[1];
  for (int i = 2; i < costSize; i++) {
    result[i] = cost[i] + min(result[i - 2], result[i - 1]);
  }
  return min(result[costSize - 1], result[costSize - 2]);
}
```
user: What is the c source code of the assembly code below?

```asm
<minCostClimbingStairs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  movslq %esi,%r15
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x0(%r13),%eax
  mov    %eax,(%r14)
  mov    0x4(%r13),%eax
  mov    %eax,0x4(%r14)
  cmp    $0x2,%r12d
  jle    L15
  lea    0x8(%r13),%rbp
  mov    %r14,%rbx
  lea    -0x3(%r12),%eax
  lea    0xc(%r13,%rax,4),%r13
L9:
  mov    0x0(%rbp),%r12d
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  call   <min@plt>
  add    %eax,%r12d
  mov    %r12d,0x8(%rbx)
  add    $0x4,%rbp
  add    $0x4,%rbx
  cmp    %r13,%rbp
  jne    L9
L15:
  shl    $0x2,%r15
  mov    -0x8(%r14,%r15,1),%esi
  mov    -0x4(%r14,%r15,1),%edi
  call   <min@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minCostClimbingStairs(int *cost, int costSize) {
  int *result = malloc(sizeof(int) * costSize);
  result[0] = cost[0];
  result[1] = cost[1];
  for (int i = 2; i < costSize; i++) {
    result[i] = cost[i] + min(result[i - 2], result[i - 1]);
  }
  return min(result[costSize - 1], result[costSize - 2]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minCostClimbingStairs>:
  endbr64
  push   %r15
  movslq %esi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%r15,4),%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    0x0(%r13),%edi
  mov    %rax,%r14
  mov    %edi,(%rax)
  mov    0x4(%r13),%eax
  mov    %eax,0x4(%r14)
  cmp    $0x2,%r15d
  jle    L19
  lea    -0x3(%r15),%eax
  lea    0x8(%r13),%rbp
  lea    0x4(%r14),%rbx
  lea    0xc(%r13,%rax,4),%r13
  jmp    L0
  nop
L28:
  mov    (%rbx),%edi
  add    $0x4,%rbx
L0:
  mov    (%rbx),%esi
  mov    0x0(%rbp),%r12d
  add    $0x4,%rbp
  call   <min@plt>
  add    %eax,%r12d
  mov    %r12d,0x4(%rbx)
  cmp    %r13,%rbp
  jne    L28
L19:
  shl    $0x2,%r15
  mov    -0x8(%r14,%r15,1),%esi
  mov    -0x4(%r14,%r15,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <min@plt>
```

assistant: ```c
int minCostClimbingStairs(int *cost, int costSize) {
  int *result = malloc(sizeof(int) * costSize);
  result[0] = cost[0];
  result[1] = cost[1];
  for (int i = 2; i < costSize; i++) {
    result[i] = cost[i] + min(result[i - 2], result[i - 1]);
  }
  return min(result[costSize - 1], result[costSize - 2]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minCostClimbingStairs>:
  endbr64
  push   %r15
  movslq %esi,%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  lea    0x0(,%r15,4),%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x0(%r13),%eax
  mov    %eax,(%r14)
  mov    0x4(%r13),%eax
  mov    %eax,0x4(%r14)
  cmp    $0x2,%r15d
  jle    L7
  lea    -0x3(%r15),%eax
  lea    0x8(%r13),%rbp
  mov    %r14,%rbx
  lea    0xc(%r13,%rax,4),%r13
  nopl   (%rax)
L11:
  mov    0x4(%rbx),%esi
  mov    (%rbx),%edi
  add    $0x4,%rbp
  add    $0x4,%rbx
  mov    -0x4(%rbp),%r12d
  call   <min@plt>
  add    %eax,%r12d
  mov    %r12d,0x4(%rbx)
  cmp    %rbp,%r13
  jne    L11
L7:
  shl    $0x2,%r15
  mov    -0x8(%r14,%r15,1),%esi
  mov    -0x4(%r14,%r15,1),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <min@plt>
```

assistant: ```c
int minCostClimbingStairs(int *cost, int costSize) {
  int *result = malloc(sizeof(int) * costSize);
  result[0] = cost[0];
  result[1] = cost[1];
  for (int i = 2; i < costSize; i++) {
    result[i] = cost[i] + min(result[i - 2], result[i - 1]);
  }
  return min(result[costSize - 1], result[costSize - 2]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f_worleyFF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x98(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x90(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x88(%rbp)
  mov    -0x90(%rbp),%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x60(%rbp)
  mov    -0x88(%rbp),%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  lea    -0x70(%rbp),%rsi
  lea    -0x40(%rbp),%rcx
  lea    -0x80(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rsi,%r8
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <Worley@plt>
  movsd  -0x80(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x98(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int f_worleyFF(void *initdata, int argc, void **argv) {
  float *result = (float *)argv[0];
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *result = (float)F[0];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f_worleyFF>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    (%rdx),%rbx
  mov    0x10(%rdx),%rax
  mov    0x8(%rdx),%rdx
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx),%xmm0
  movsd  %xmm0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  movsd  %xmm0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  mov    $0x2,%esi
  call   <Worley@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rsp),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f_worleyFF(void *initdata, int argc, void **argv) {
  float *result = (float *)argv[0];
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *result = (float)F[0];
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f_worleyFF>:
  endbr64
  push   %rbx
  pxor   %xmm0,%xmm0
  mov    $0x2,%esi
  add    $0xffffffffffffff80,%rsp
  mov    (%rdx),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    0x10(%rdx),%rax
  mov    0x8(%rdx),%rdx
  lea    0x40(%rsp),%rcx
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r8
  cvtss2sd (%rdx),%xmm0
  mov    %rsp,%rdx
  movsd  %xmm0,0x20(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax),%xmm0
  movsd  %xmm0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  call   <Worley@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss (%rsp),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int f_worleyFF(void *initdata, int argc, void **argv) {
  float *result = (float *)argv[0];
  float *x = (float *)argv[1];
  float *y = (float *)argv[2];
  double at[3];
  at[0] = *x;
  at[1] = *y;
  at[2] = 0.0;
  double F[2];
  double delta[2][3];
  unsigned long ID[2];
  Worley(at, 2, F, delta, ID);
  *result = (float)F[0];
  return 0;
}
```