ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D20
type: string

tool: D15: x = [%d]


tool: D8: (x << 1) = [%d]


tool: D20: (x << 0) = [%d]


assistant: ```c
int main(void) {
  unsigned x = 2;
  printf("x = [%d]\n", x);
  printf("(x << 1) = [%d]\n", x << 1);
  printf("(x << 0) = [%d]\n", x << 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string
name: extract_symbolic_data
arguments: label: D11
type_infered: string

tool: D28: x = [%d]


tool: D1: (x << 1) = [%d]


tool: D11: (x << 0) = [%d]


assistant: ```c
int main(void) {
  unsigned x = 2;
  printf("x = [%d]\n", x);
  printf("(x << 1) = [%d]\n", x << 1);
  printf("(x << 0) = [%d]\n", x << 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ref_idx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x41,-0x14(%rbp)
  je     L77
  cmpb   $0x61,-0x14(%rbp)
  jne    L118
L77:
  movq   $0x0,-0x8(%rbp)
  jmp    L115
L118:
  cmpb   $0x47,-0x14(%rbp)
  je     L164
  cmpb   $0x67,-0x14(%rbp)
  jne    L97
L164:
  movq   $0x1,-0x8(%rbp)
  jmp    L115
L97:
  cmpb   $0x43,-0x14(%rbp)
  je     L50
  cmpb   $0x63,-0x14(%rbp)
  jne    L153
L50:
  movq   $0x2,-0x8(%rbp)
  jmp    L115
L153:
  cmpb   $0x55,-0x14(%rbp)
  je     L76
  cmpb   $0x75,-0x14(%rbp)
  jne    L0
L76:
  movq   $0x3,-0x8(%rbp)
  jmp    L115
L0:
  cmpb   $0x54,-0x14(%rbp)
  je     L75
  cmpb   $0x74,-0x14(%rbp)
  jne    L8
L75:
  movq   $0x4,-0x8(%rbp)
  jmp    L115
L8:
  cmpb   $0x49,-0x14(%rbp)
  jne    L99
  movq   $0x5,-0x8(%rbp)
  jmp    L115
L99:
  cmpb   $0x50,-0x14(%rbp)
  jne    L115
  movq   $0x6,-0x8(%rbp)
L115:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long ref_idx(char resnam) {
  long ii;
  if (resnam == 'A' || resnam == 'a')
    ii = 0;
  else if (resnam == 'G' || resnam == 'g')
    ii = 1;
  else if (resnam == 'C' || resnam == 'c')
    ii = 2;
  else if (resnam == 'U' || resnam == 'u')
    ii = 3;
  else if (resnam == 'T' || resnam == 't')
    ii = 4;
  else if (resnam == 'I')
    ii = 5;
  else if (resnam == 'P')
    ii = 6;
  return ii;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ref_idx>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x34,%dil
  ja     L4
  movzbl %dil,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%ecx
  jmp    L4
  mov    $0x1,%ecx
L4:
  mov    %rcx,%rax
  ret
  mov    $0x2,%ecx
  jmp    L4
  mov    $0x3,%ecx
  jmp    L4
  mov    $0x4,%ecx
  jmp    L4
  mov    $0x5,%ecx
  jmp    L4
  mov    $0x6,%ecx
  jmp    L4
```

assistant: ```c
long ref_idx(char resnam) {
  long ii;
  if (resnam == 'A' || resnam == 'a')
    ii = 0;
  else if (resnam == 'G' || resnam == 'g')
    ii = 1;
  else if (resnam == 'C' || resnam == 'c')
    ii = 2;
  else if (resnam == 'U' || resnam == 'u')
    ii = 3;
  else if (resnam == 'T' || resnam == 't')
    ii = 4;
  else if (resnam == 'I')
    ii = 5;
  else if (resnam == 'P')
    ii = 6;
  return ii;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ref_idx>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x34,%dil
  ja     L9
  lea    D3(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%r8d
L9:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x5,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x6,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %r8d,%r8d
  jmp    L9
```

assistant: ```c
long ref_idx(char resnam) {
  long ii;
  if (resnam == 'A' || resnam == 'a')
    ii = 0;
  else if (resnam == 'G' || resnam == 'g')
    ii = 1;
  else if (resnam == 'C' || resnam == 'c')
    ii = 2;
  else if (resnam == 'U' || resnam == 'u')
    ii = 3;
  else if (resnam == 'T' || resnam == 't')
    ii = 4;
  else if (resnam == 'I')
    ii = 5;
  else if (resnam == 'P')
    ii = 6;
  return ii;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ref_idx>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x34,%dil
  ja     L6
  lea    D0(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%r8d
L6:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x5,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x6,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %r8d,%r8d
  jmp    L6
```

assistant: ```c
long ref_idx(char resnam) {
  long ii;
  if (resnam == 'A' || resnam == 'a')
    ii = 0;
  else if (resnam == 'G' || resnam == 'g')
    ii = 1;
  else if (resnam == 'C' || resnam == 'c')
    ii = 2;
  else if (resnam == 'U' || resnam == 'u')
    ii = 3;
  else if (resnam == 'T' || resnam == 't')
    ii = 4;
  else if (resnam == 'I')
    ii = 5;
  else if (resnam == 'P')
    ii = 6;
  return ii;
}
```
user: What is the c source code of the assembly code below:

```asm
<Ordenar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L35
L25:
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L17
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L29
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  lea    -0x8(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  movl   $0x1,-0xc(%rbp)
L29:
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L12
L35:
  cmpl   $0x1,-0xc(%rbp)
  jne    L21
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L25
L21:
  nop
  leave
  ret
```

assistant: ```c
Ordenar(char *pcad[], int nc) {
  char *aux = NULL;
  int i = 0, s = 1;
  while ((s == 1) && (--nc > 0)) {
    s = 0;
    for (i = 1; i <= nc; i++)
      if (strcmp(pcad[i - 1], pcad[i]) > 0) {
        aux = pcad[i - 1];
        pcad[i - 1] = pcad[i];
        pcad[i] = aux;
        s = 1;
      }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Ordenar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    -0x1(%rsi),%r14d
  mov    $0x0,%r15d
  mov    $0x1,%ebx
  test   %r14d,%r14d
  jg     L59
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jl     L12
L59:
  movslq %ebx,%rax
  shl    $0x3,%rax
  lea    0x0(%r13,%rax,1),%rbp
  lea    -0x8(%r13,%rax,1),%r12
  mov    0x0(%rbp),%rsi
  mov    (%r12),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L39
  mov    (%r12),%rax
  mov    0x0(%rbp),%rdx
  mov    %rdx,(%r12)
  mov    %rax,0x0(%rbp)
  add    $0x1,%ebx
  mov    $0x1,%r15d
  cmp    %ebx,%r14d
  jge    L59
L47:
  lea    -0x1(%r14),%eax
  cmp    $0x1,%r14d
  jle    L7
  mov    %eax,%r14d
  mov    $0x0,%r15d
  mov    $0x1,%ebx
  jmp    L59
L12:
  cmp    $0x1,%r15d
  je     L47
  jmp    L7
```

assistant: ```c
Ordenar(char *pcad[], int nc) {
  char *aux = NULL;
  int i = 0, s = 1;
  while ((s == 1) && (--nc > 0)) {
    s = 0;
    for (i = 1; i <= nc; i++)
      if (strcmp(pcad[i - 1], pcad[i]) > 0) {
        aux = pcad[i - 1];
        pcad[i - 1] = pcad[i];
        pcad[i] = aux;
        s = 1;
      }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Ordenar>:
  endbr64
  push   %r15
  lea    0x8(%rdi),%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    %r13d,%eax
  sub    $0x1,%r13d
  test   %r13d,%r13d
  jle    L6
  sub    $0x2,%eax
  mov    %r14,%rbx
  xor    %r12d,%r12d
  lea    (%r15,%rax,8),%rbp
  nopl   0x0(%rax)
L0:
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L31
  mov    (%rbx),%rax
  mov    0x8(%rbx),%rdx
  mov    $0x1,%r12d
  mov    %rdx,(%rbx)
  mov    %rax,0x8(%rbx)
L31:
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L0
  cmp    $0x1,%r12d
  je     L7
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
Ordenar(char *pcad[], int nc) {
  char *aux = NULL;
  int i = 0, s = 1;
  while ((s == 1) && (--nc > 0)) {
    s = 0;
    for (i = 1; i <= nc; i++)
      if (strcmp(pcad[i - 1], pcad[i]) > 0) {
        aux = pcad[i - 1];
        pcad[i - 1] = pcad[i];
        pcad[i] = aux;
        s = 1;
      }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Ordenar>:
  endbr64
  push   %r15
  lea    0x8(%rdi),%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    %r13d,%eax
  sub    $0x1,%r13d
  test   %r13d,%r13d
  jle    L32
  sub    $0x2,%eax
  mov    %r14,%rbx
  xor    %r12d,%r12d
  lea    (%r15,%rax,8),%rbp
  nopl   0x0(%rax)
L12:
  mov    0x8(%rbx),%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L29
  movdqu (%rbx),%xmm0
  mov    $0x1,%r12d
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%rbx)
L29:
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L12
  cmp    $0x1,%r12d
  je     L0
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
Ordenar(char *pcad[], int nc) {
  char *aux = NULL;
  int i = 0, s = 1;
  while ((s == 1) && (--nc > 0)) {
    s = 0;
    for (i = 1; i <= nc; i++)
      if (strcmp(pcad[i - 1], pcad[i]) > 0) {
        aux = pcad[i - 1];
        pcad[i - 1] = pcad[i];
        pcad[i] = aux;
        s = 1;
      }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L12
L9:
  mov    -0x4(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int abs(int a) {
  if (a < 0) {
    return a * (-1);
  } else {
    return a;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int a) {
  if (a < 0) {
    return a * (-1);
  } else {
    return a;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int a) {
  if (a < 0) {
    return a * (-1);
  } else {
    return a;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int a) {
  if (a < 0) {
    return a * (-1);
  } else {
    return a;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RemoveUselessBraces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <GetMemoryBlock@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L42
L54:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7b,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7d,%al
  jne    L12
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L42
L12:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L42:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L54
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L5
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FreeMemoryBlock@plt>
  nop
  leave
  ret
```

assistant: ```c
void RemoveUselessBraces(char *OldBuf) {
  char *p, *q, *n, *NewBuf;
  p = OldBuf;
  NewBuf = GetMemoryBlock(strlen(p) + 1);
  q = NewBuf;
  while (*p) {
    n = p;
    ++n;
    if (*p == '{' && *n == '}') {
      ++p;
      ++p;
    } else {
      *q = *p;
      ++q;
      ++p;
    }
  }
  *q = 0;
  *OldBuf = 0;
  if (strlen(NewBuf) > 0)
    strcpy(OldBuf, NewBuf);
  FreeMemoryBlock(NewBuf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RemoveUselessBraces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <GetMemoryBlock@plt>
  mov    %rax,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  je     L51
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  jmp    L0
L9:
  mov    %al,(%rcx)
  add    $0x1,%rcx
  add    $0x1,%rdx
L49:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L30
L0:
  cmp    $0x7b,%al
  jne    L9
  cmpb   $0x7d,0x1(%rdx)
  jne    L9
  add    $0x2,%rdx
  jmp    L49
L51:
  mov    %rbp,%rcx
L30:
  movb   $0x0,(%rcx)
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jg     L38
L68:
  mov    %rbp,%rdi
  call   <FreeMemoryBlock@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L68
```

assistant: ```c
void RemoveUselessBraces(char *OldBuf) {
  char *p, *q, *n, *NewBuf;
  p = OldBuf;
  NewBuf = GetMemoryBlock(strlen(p) + 1);
  q = NewBuf;
  while (*p) {
    n = p;
    ++n;
    if (*p == '{' && *n == '}') {
      ++p;
      ++p;
    } else {
      *q = *p;
      ++q;
      ++p;
    }
  }
  *q = 0;
  *OldBuf = 0;
  if (strlen(NewBuf) > 0)
    strcpy(OldBuf, NewBuf);
  FreeMemoryBlock(NewBuf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RemoveUselessBraces>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <GetMemoryBlock@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%eax
  mov    %r12,%rcx
  test   %al,%al
  je     L27
  mov    %rbp,%rdx
  jmp    L42
  nop
L20:
  add    $0x1,%rdx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L27
L42:
  cmp    $0x7b,%al
  jne    L20
  cmpb   $0x7d,0x1(%rdx)
  jne    L20
  movzbl 0x2(%rdx),%eax
  add    $0x2,%rdx
  test   %al,%al
  jne    L42
  nopw   0x0(%rax,%rax,1)
L27:
  movb   $0x0,(%rcx)
  mov    %r12,%rdi
  movb   $0x0,0x0(%rbp)
  call   <strlen@plt>
  test   %rax,%rax
  jne    L67
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <FreeMemoryBlock@plt>
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <FreeMemoryBlock@plt>
```

assistant: ```c
void RemoveUselessBraces(char *OldBuf) {
  char *p, *q, *n, *NewBuf;
  p = OldBuf;
  NewBuf = GetMemoryBlock(strlen(p) + 1);
  q = NewBuf;
  while (*p) {
    n = p;
    ++n;
    if (*p == '{' && *n == '}') {
      ++p;
      ++p;
    } else {
      *q = *p;
      ++q;
      ++p;
    }
  }
  *q = 0;
  *OldBuf = 0;
  if (strlen(NewBuf) > 0)
    strcpy(OldBuf, NewBuf);
  FreeMemoryBlock(NewBuf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RemoveUselessBraces>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <GetMemoryBlock@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%eax
  mov    %r12,%rcx
  test   %al,%al
  je     L64
  mov    %rbp,%rdx
  jmp    L3
  nop
L58:
  add    $0x1,%rdx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L64
L3:
  cmp    $0x7b,%al
  jne    L58
  cmpb   $0x7d,0x1(%rdx)
  jne    L58
  movzbl 0x2(%rdx),%eax
  add    $0x2,%rdx
  test   %al,%al
  jne    L3
  nopw   0x0(%rax,%rax,1)
L64:
  movb   $0x0,(%rcx)
  mov    %r12,%rdi
  movb   $0x0,0x0(%rbp)
  call   <strlen@plt>
  test   %rax,%rax
  jne    L28
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <FreeMemoryBlock@plt>
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <FreeMemoryBlock@plt>
```

assistant: ```c
void RemoveUselessBraces(char *OldBuf) {
  char *p, *q, *n, *NewBuf;
  p = OldBuf;
  NewBuf = GetMemoryBlock(strlen(p) + 1);
  q = NewBuf;
  while (*p) {
    n = p;
    ++n;
    if (*p == '{' && *n == '}') {
      ++p;
      ++p;
    } else {
      *q = *p;
      ++q;
      ++p;
    }
  }
  *q = 0;
  *OldBuf = 0;
  if (strlen(NewBuf) > 0)
    strcpy(OldBuf, NewBuf);
  FreeMemoryBlock(NewBuf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<store2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x640(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x648(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x650(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x658(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store2a(long long *array, long long a) {
  array[200] = a;
  array[201] = a;
  array[202] = a;
  array[203] = a;
}
```
user: What is the c source code of the assembly code below:

```asm
<store2a>:
  endbr64
  mov    %rsi,0x640(%rdi)
  mov    %rsi,0x648(%rdi)
  mov    %rsi,0x650(%rdi)
  mov    %rsi,0x658(%rdi)
  ret
```

assistant: ```c
void store2a(long long *array, long long a) {
  array[200] = a;
  array[201] = a;
  array[202] = a;
  array[203] = a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<store2a>:
  endbr64
  mov    %rsi,0x640(%rdi)
  mov    %rsi,0x648(%rdi)
  mov    %rsi,0x650(%rdi)
  mov    %rsi,0x658(%rdi)
  ret
```

assistant: ```c
void store2a(long long *array, long long a) {
  array[200] = a;
  array[201] = a;
  array[202] = a;
  array[203] = a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<store2a>:
  endbr64
  movq   %rsi,%xmm0
  punpcklqdq %xmm0,%xmm0
  movups %xmm0,0x640(%rdi)
  movups %xmm0,0x650(%rdi)
  ret
```

assistant: ```c
void store2a(long long *array, long long a) {
  array[200] = a;
  array[201] = a;
  array[202] = a;
  array[203] = a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Bind@plt>
L11:
  cmpl   $0x0,-0x8(%rbp)
  je     L18
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Draw@plt>
L18:
  cmpl   $0x0,-0xc(%rbp)
  je     L26
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Unbind@plt>
L26:
  nop
  leave
  ret
```

assistant: ```c
void Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw(int bindVBO, int drawQuad, int unbindVBO) {
  if (bindVBO)
    ScreenQuadVBO_Bind();
  if (drawQuad)
    ScreenQuadVBO_Draw();
  if (unbindVBO)
    ScreenQuadVBO_Unbind();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  test   %edi,%edi
  jne    L8
L55:
  test   %ebp,%ebp
  jne    L33
L3:
  test   %ebx,%ebx
  jne    L40
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Bind@plt>
  jmp    L55
L33:
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Draw@plt>
  jmp    L3
L40:
  mov    $0x0,%eax
  call   <ScreenQuadVBO_Unbind@plt>
  jmp    L43
```

assistant: ```c
void Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw(int bindVBO, int drawQuad, int unbindVBO) {
  if (bindVBO)
    ScreenQuadVBO_Bind();
  if (drawQuad)
    ScreenQuadVBO_Draw();
  if (unbindVBO)
    ScreenQuadVBO_Unbind();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L4
  test   %ebp,%ebp
  jne    L46
L44:
  test   %ebx,%ebx
  jne    L43
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <ScreenQuadVBO_Bind@plt>
  test   %ebp,%ebp
  je     L44
L46:
  xor    %eax,%eax
  call   <ScreenQuadVBO_Draw@plt>
  test   %ebx,%ebx
  je     L49
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <ScreenQuadVBO_Unbind@plt>
```

assistant: ```c
void Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw(int bindVBO, int drawQuad, int unbindVBO) {
  if (bindVBO)
    ScreenQuadVBO_Bind();
  if (drawQuad)
    ScreenQuadVBO_Draw();
  if (unbindVBO)
    ScreenQuadVBO_Unbind();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L19
  test   %ebp,%ebp
  jne    L42
L26:
  test   %ebx,%ebx
  jne    L30
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  call   <ScreenQuadVBO_Bind@plt>
  test   %ebp,%ebp
  je     L26
L42:
  xor    %eax,%eax
  call   <ScreenQuadVBO_Draw@plt>
  test   %ebx,%ebx
  je     L11
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <ScreenQuadVBO_Unbind@plt>
```

assistant: ```c
void Dynamic_Resolution_LowLevel_FullScreenQuadVBO_Draw(int bindVBO, int drawQuad, int unbindVBO) {
  if (bindVBO)
    ScreenQuadVBO_Bind();
  if (drawQuad)
    ScreenQuadVBO_Draw();
  if (unbindVBO)
    ScreenQuadVBO_Unbind();
}
```