ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bin_setbits>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%r8d
  or     %ecx,%eax
  test   $0x7,%al
  je     L16
  lea    -0x1(%rcx),%eax
  mov    $0x1,%r9d
  add    %eax,%esi
  test   %ecx,%ecx
  jle    L7
  xchg   %ax,%ax
L34:
  bt     %eax,%r8d
  jae    L2
  mov    %esi,%ecx
  mov    %r9d,%r10d
  sub    %eax,%ecx
  lea    0x7(%rcx),%edx
  cmovns %ecx,%edx
  not    %ecx
  and    $0x7,%ecx
  sar    $0x3,%edx
  shl    %cl,%r10d
  movslq %edx,%rdx
  or     %r10d,(%rdi,%rdx,4)
L2:
  sub    $0x1,%eax
  jae    L34
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  or     %edx,(%rdi,%rax,4)
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
void bin_setbits(uint8_t *buf, int offset, uint8_t val, int len) {
  if (offset % 8 == 0 && len % 8 == 0) {
    buf[offset / 8] |= val;
  } else {
    int i;
    for (i = 0; i < len; i++) {
      if (val & (1 << (len - i - 1)))
        ((buf)[(offset + i) / 8] |= 1 << (7 - ((offset + i) & 7)));
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin_setbits>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%r8d
  or     %ecx,%eax
  test   $0x7,%al
  je     L24
  lea    -0x1(%rcx),%eax
  mov    $0x1,%r9d
  add    %eax,%esi
  test   %ecx,%ecx
  jle    L23
  xchg   %ax,%ax
L1:
  bt     %eax,%r8d
  jae    L31
  mov    %esi,%ecx
  mov    %r9d,%r10d
  sub    %eax,%ecx
  lea    0x7(%rcx),%edx
  cmovns %ecx,%edx
  not    %ecx
  and    $0x7,%ecx
  sar    $0x3,%edx
  shl    %cl,%r10d
  movslq %edx,%rdx
  or     %r10d,(%rdi,%rdx,4)
L31:
  sub    $0x1,%eax
  jae    L1
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  or     %edx,(%rdi,%rax,4)
  ret
  nopl   0x0(%rax)
L23:
  ret
```

assistant: ```c
void bin_setbits(uint8_t *buf, int offset, uint8_t val, int len) {
  if (offset % 8 == 0 && len % 8 == 0) {
    buf[offset / 8] |= val;
  } else {
    int i;
    for (i = 0; i < len; i++) {
      if (val & (1 << (len - i - 1)))
        ((buf)[(offset + i) / 8] |= 1 << (7 - ((offset + i) & 7)));
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    $0x5,%edi
  call   <stack_init@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <stack_push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <stack_push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xfffffffb,%esi
  mov    %rax,%rdi
  call   <stack_push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <stack_push@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <stack_push@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_min@plt>
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_min@plt>
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D32
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D32: stack min %d


tool: D3: stack pop %d 


assistant: ```c
int main() {
  struct node_stack *head = NULL;
  head = stack_init(5);
  stack_push(&head, 5);
  stack_push(&head, 8);
  stack_push(&head, -5);
  stack_push(&head, 10);
  stack_push(&head, 15);
  printf("stack min %d\n", stack_min(head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack min %d\n", stack_min(head));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x5,%edi
  call   <stack_init@plt>
  mov    %rax,(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    $0xfffffffb,%esi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    $0xf,%esi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %eax,%esi
  lea    D12(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stack_pop@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D12: stack min %d


tool: D9: stack pop %d 


assistant: ```c
int main() {
  struct node_stack *head = NULL;
  head = stack_init(5);
  stack_push(&head, 5);
  stack_push(&head, 8);
  stack_push(&head, -5);
  stack_push(&head, 10);
  stack_push(&head, 15);
  printf("stack min %d\n", stack_min(head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack min %d\n", stack_min(head));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x5,%edi
  lea    D2(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  call   <stack_init@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <stack_push@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xfffffffb,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xf,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D2: stack min %d


tool: D10: stack pop %d 


assistant: ```c
int main() {
  struct node_stack *head = NULL;
  head = stack_init(5);
  stack_push(&head, 5);
  stack_push(&head, 8);
  stack_push(&head, -5);
  stack_push(&head, 10);
  stack_push(&head, 15);
  printf("stack min %d\n", stack_min(head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack min %d\n", stack_min(head));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x5,%edi
  lea    D0(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  call   <stack_init@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <stack_push@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xfffffffb,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    $0xf,%esi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <stack_min@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D0: stack min %d


tool: D2: stack pop %d 


assistant: ```c
int main() {
  struct node_stack *head = NULL;
  head = stack_init(5);
  stack_push(&head, 5);
  stack_push(&head, 8);
  stack_push(&head, -5);
  stack_push(&head, 10);
  stack_push(&head, 15);
  printf("stack min %d\n", stack_min(head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack pop %d \n", stack_pop(&head));
  printf("stack min %d\n", stack_min(head));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extractinttypes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void extractinttypes() {
  extern int check_extract_result_int;
  extern __typeof(_mm_extract_epi8(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi16(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi32(_mm_setzero_si128(), 3)) check_result_int;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extractinttypes>:
  endbr64
  ret
```

assistant: ```c
void extractinttypes() {
  extern int check_extract_result_int;
  extern __typeof(_mm_extract_epi8(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi16(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi32(_mm_setzero_si128(), 3)) check_result_int;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extractinttypes>:
  endbr64
  ret
```

assistant: ```c
void extractinttypes() {
  extern int check_extract_result_int;
  extern __typeof(_mm_extract_epi8(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi16(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi32(_mm_setzero_si128(), 3)) check_result_int;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extractinttypes>:
  endbr64
  ret
```

assistant: ```c
void extractinttypes() {
  extern int check_extract_result_int;
  extern __typeof(_mm_extract_epi8(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi16(_mm_setzero_si128(), 3)) check_result_int;
  extern __typeof(_mm_extract_epi32(_mm_setzero_si128(), 3)) check_result_int;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_random_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L12:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void get_random_bytes(u_int8_t seed[], int num) {
  int i;
  for (i = 0; i < num; i++)
    seed[i] = random();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L14:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
void get_random_bytes(u_int8_t seed[], int num) {
  int i;
  for (i = 0; i < num; i++)
    seed[i] = random();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <random@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void get_random_bytes(u_int8_t seed[], int num) {
  int i;
  for (i = 0; i < num; i++)
    seed[i] = random();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <random@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void get_random_bytes(u_int8_t seed[], int num) {
  int i;
  for (i = 0; i < num; i++)
    seed[i] = random();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <v3_open@plt>
  mov    $0xf,%edi
  call   <v3_analog_inputs_enable@plt>
  movss  D37(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
L9:
  mov    $0x0,%eax
  call   <v3_work@plt>
  mov    $0x0,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%ebx
  mov    $0x0,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  cvttsd2si %xmm0,%eax
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7a120,%edi
  call   <usleep@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: label: D37
datatype: f32
name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D9
datatype: byte[8]
name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D38
datatype: string

tool: D37: 1.1172

tool: D17: D0=%f (raw v=%d)


tool: {"D9": [0xb2,0x10,0x6c,0xe8,0x5a,0xaa,0xec,0x3f]}

tool: D8: D1=%f (raw v=%d)


tool: D6: D2 (raw v=%d)


tool: D38: D3 (raw v=%d)


assistant: ```c
int main() {
  v3_open();
  v3_analog_inputs_enable((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  const float angle = 1.1172;
  do {
    v3_work();
    printf("D0=%f (raw v=%d)\n", distance(v3_analog_read(0)), v3_analog_read(0));
    printf("D1=%f (raw v=%d)\n", (distance(v3_analog_read(1)) * cos(0.460579)), v3_analog_read(1));
    printf("D2 (raw v=%d)\n", v3_analog_read(2));
    printf("D3 (raw v=%d)\n", v3_analog_read(3));
    usleep(500000);
  } while (1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <v3_open@plt>
  mov    $0xf,%edi
  call   <v3_analog_inputs_enable@plt>
  lea    D43(%rip),%r12
  lea    D17(%rip),%rbp
  lea    D20(%rip),%rbx
L3:
  mov    $0x0,%eax
  call   <v3_work@plt>
  mov    $0x0,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%r13d
  mov    $0x0,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  cvttsd2si %xmm0,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%r13d
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  mulsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <v3_analog_read@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7a120,%edi
  call   <usleep@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D43
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string
name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D43: D0=%f (raw v=%d)


tool: D17: D1=%f (raw v=%d)


tool: D20: D2 (raw v=%d)


tool: {"D6": [0xb2,0x10,0x6c,0xe8,0x5a,0xaa,0xec,0x3f]}

tool: D15: D3 (raw v=%d)


assistant: ```c
int main() {
  v3_open();
  v3_analog_inputs_enable((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  const float angle = 1.1172;
  do {
    v3_work();
    printf("D0=%f (raw v=%d)\n", distance(v3_analog_read(0)), v3_analog_read(0));
    printf("D1=%f (raw v=%d)\n", (distance(v3_analog_read(1)) * cos(0.460579)), v3_analog_read(1));
    printf("D2 (raw v=%d)\n", v3_analog_read(2));
    printf("D3 (raw v=%d)\n", v3_analog_read(3));
    usleep(500000);
  } while (1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  lea    D30(%rip),%rbx
  call   <v3_open@plt>
  mov    $0xf,%edi
  call   <v3_analog_inputs_enable@plt>
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <v3_work@plt>
  xor    %edi,%edi
  call   <v3_analog_read@plt>
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  mov    %r14d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    $0x1,%edi
  mov    %eax,%r14d
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  mov    %r14d,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mulsd  D21(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <v3_analog_read@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <v3_analog_read@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7a120,%edi
  call   <usleep@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D44
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D21
data_type: byte[8]

tool: D16: D0=%f (raw v=%d)


tool: D1: D1=%f (raw v=%d)


tool: D44: D2 (raw v=%d)


tool: D30: D3 (raw v=%d)


tool: {"D21": [0xb2,0x10,0x6c,0xe8,0x5a,0xaa,0xec,0x3f]}

assistant: ```c
int main() {
  v3_open();
  v3_analog_inputs_enable((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  const float angle = 1.1172;
  do {
    v3_work();
    printf("D0=%f (raw v=%d)\n", distance(v3_analog_read(0)), v3_analog_read(0));
    printf("D1=%f (raw v=%d)\n", (distance(v3_analog_read(1)) * cos(0.460579)), v3_analog_read(1));
    printf("D2 (raw v=%d)\n", v3_analog_read(2));
    printf("D3 (raw v=%d)\n", v3_analog_read(3));
    usleep(500000);
  } while (1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  lea    D25(%rip),%rbx
  call   <v3_open@plt>
  mov    $0xf,%edi
  call   <v3_analog_inputs_enable@plt>
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <v3_work@plt>
  xor    %edi,%edi
  call   <v3_analog_read@plt>
  xor    %edi,%edi
  mov    %eax,%r14d
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  mov    %r14d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <v3_analog_read@plt>
  mov    $0x1,%edi
  mov    %eax,%r14d
  call   <v3_analog_read@plt>
  mov    %eax,%edi
  call   <distance@plt>
  mov    %r14d,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mulsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <v3_analog_read@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edi
  call   <v3_analog_read@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7a120,%edi
  call   <usleep@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D32
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D25
type_infered: string
name: disassemble_data
arguments: data_tag: D26
type_infered: byte[8]

tool: D12: D0=%f (raw v=%d)


tool: D32: D1=%f (raw v=%d)


tool: D23: D2 (raw v=%d)


tool: D25: D3 (raw v=%d)


tool: {"D26": [0xb2,0x10,0x6c,0xe8,0x5a,0xaa,0xec,0x3f]}

assistant: ```c
int main() {
  v3_open();
  v3_analog_inputs_enable((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  const float angle = 1.1172;
  do {
    v3_work();
    printf("D0=%f (raw v=%d)\n", distance(v3_analog_read(0)), v3_analog_read(0));
    printf("D1=%f (raw v=%d)\n", (distance(v3_analog_read(1)) * cos(0.460579)), v3_analog_read(1));
    printf("D2 (raw v=%d)\n", v3_analog_read(2));
    printf("D3 (raw v=%d)\n", v3_analog_read(3));
    usleep(500000);
  } while (1);
  return 0;
}
```