ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L28
L10:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpq   $0x1800,0x10(%rsp)
  je     L6
L40:
  mov    0x10(%rsp),%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    $0x1,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L10
L6:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L40
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string

tool: D21: %lu


tool: D24: Call this program with %i arguments


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6144UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L17
  lea    D12(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L17:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x1800,%rsi
  je     L27
L1:
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L1
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D26
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string

tool: D12: Call this program with %i arguments


tool: D26: %lu


tool: D27: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6144UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L37
  lea    D20(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L37:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  cmp    $0x1800,%rsi
  je     L27
L35:
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L35
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string

tool: D20: Call this program with %i arguments


tool: D21: %lu


tool: D17: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6144UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<construct_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rsi
  mov    -0x7c(%rbp),%ecx
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rsi,%r8
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: %s%d%s

assistant: ```c
void construct_path(const char *path, int proc_id, char *rest) {
  char str_temp[100];
  sprintf(str_temp, "%s%d%s", path, proc_id, rest);
  strcpy(rest, str_temp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<construct_path>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %esi,%ecx
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rdx,%r8
  mov    %rdi,%rdx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %s%d%s

assistant: ```c
void construct_path(const char *path, int proc_id, char *rest) {
  char str_temp[100];
  sprintf(str_temp, "%s%d%s", path, proc_id, rest);
  strcpy(rest, str_temp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<construct_path>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %rdx,%r8
  lea    D0(%rip),%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: %s%d%s

assistant: ```c
void construct_path(const char *path, int proc_id, char *rest) {
  char str_temp[100];
  sprintf(str_temp, "%s%d%s", path, proc_id, rest);
  strcpy(rest, str_temp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<construct_path>:
  endbr64
  push   %r12
  mov    %esi,%ecx
  mov    %rdx,%r8
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %s%d%s

assistant: ```c
void construct_path(const char *path, int proc_id, char *rest) {
  char str_temp[100];
  sprintf(str_temp, "%s%d%s", path, proc_id, rest);
  strcpy(rest, str_temp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    $0x1,%ebx
  jmp    L6
L16:
  add    $0x1,%ebx
L6:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  cmp    $0xa,%dl
  jne    L16
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
length(line) register char *line;
{
  register int i = 1;
  while (*line++ != '\n')
    i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<length>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0xa,(%rdi)
  je     L28
  mov    %rcx,%rax
  mov    $0x2,%edx
  sub    %ecx,%edx
L26:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L26
L25:
  mov    %ecx,%eax
  ret
L28:
  mov    $0x1,%ecx
  jmp    L25
```

assistant: ```c
length(line) register char *line;
{
  register int i = 1;
  while (*line++ != '\n')
    i++;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<length>:
  endbr64
  cmpb   $0xa,(%rdi)
  lea    0x1(%rdi),%rax
  je     L5
  mov    $0x2,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L14:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
length(line) register char *line;
{
  register int i = 1;
  while (*line++ != '\n')
    i++;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<length>:
  endbr64
  cmpb   $0xa,(%rdi)
  lea    0x1(%rdi),%rax
  je     L0
  mov    $0x2,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L6:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rax)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
length(line) register char *line;
{
  register int i = 1;
  while (*line++ != '\n')
    i++;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<devo_setbuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void devo_setbuf(void *stream, char *buf) {
  (void)stream;
  (void)buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<devo_setbuf>:
  endbr64
  ret
```

assistant: ```c
void devo_setbuf(void *stream, char *buf) {
  (void)stream;
  (void)buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<devo_setbuf>:
  endbr64
  ret
```

assistant: ```c
void devo_setbuf(void *stream, char *buf) {
  (void)stream;
  (void)buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<devo_setbuf>:
  endbr64
  ret
```

assistant: ```c
void devo_setbuf(void *stream, char *buf) {
  (void)stream;
  (void)buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<distanciaPercorrida>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movss  D6(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D12(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x260,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x8(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  divss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: f32
name: read_data
arguments: data_label: D12
data_type: f32

tool: D6: 3.14

tool: D12: 5.75

assistant: ```c
int distanciaPercorrida(int rotation) {
  float pi = 3.14;
  float radius = 5.75;
  int holes = 608;
  int distance = (2 * pi * (radius / holes) * rotation);
  return distance;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<distanciaPercorrida>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D7(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: byte[4]

tool: {"D7": [0x73,0x44,0x73,0x3d]}

assistant: ```c
int distanciaPercorrida(int rotation) {
  float pi = 3.14;
  float radius = 5.75;
  int holes = 608;
  int distance = (2 * pi * (radius / holes) * rotation);
  return distance;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<distanciaPercorrida>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D5(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: byte[4]

tool: {"D5": [0x73,0x44,0x73,0x3d]}

assistant: ```c
int distanciaPercorrida(int rotation) {
  float pi = 3.14;
  float radius = 5.75;
  int holes = 608;
  int distance = (2 * pi * (radius / holes) * rotation);
  return distance;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<distanciaPercorrida>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D3(%rip),%xmm0
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: byte[4]

tool: {"D3": [0x73,0x44,0x73,0x3d]}

assistant: ```c
int distanciaPercorrida(int rotation) {
  float pi = 3.14;
  float radius = 5.75;
  int holes = 608;
  int distance = (2 * pi * (radius / holes) * rotation);
  return distance;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <example1@plt>
  mov    $0x0,%eax
  call   <example2@plt>
  mov    $0x0,%eax
  call   <example3@plt>
  mov    $0x0,%eax
  call   <example4@plt>
  mov    $0x0,%eax
  call   <example4a@plt>
  mov    $0x0,%eax
  call   <example4b@plt>
  mov    $0x0,%eax
  call   <example4c@plt>
  mov    $0x0,%eax
  call   <example5@plt>
  mov    $0x0,%eax
  call   <example6@plt>
  mov    $0x0,%eax
  call   <example7@plt>
  mov    $0x0,%eax
  call   <example8@plt>
  mov    $0x0,%eax
  call   <mineEx1@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  example1();
  example2();
  example3();
  example4();
  example4a();
  example4b();
  example4c();
  example5();
  example6();
  example7();
  example8();
  mineEx1();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <example1@plt>
  mov    $0x0,%eax
  call   <example2@plt>
  mov    $0x0,%eax
  call   <example3@plt>
  mov    $0x0,%eax
  call   <example4@plt>
  mov    $0x0,%eax
  call   <example4a@plt>
  mov    $0x0,%eax
  call   <example4b@plt>
  mov    $0x0,%eax
  call   <example4c@plt>
  mov    $0x0,%eax
  call   <example5@plt>
  mov    $0x0,%eax
  call   <example6@plt>
  mov    $0x0,%eax
  call   <example7@plt>
  mov    $0x0,%eax
  call   <example8@plt>
  mov    $0x0,%eax
  call   <mineEx1@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  example1();
  example2();
  example3();
  example4();
  example4a();
  example4b();
  example4c();
  example5();
  example6();
  example7();
  example8();
  mineEx1();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <example1@plt>
  xor    %eax,%eax
  call   <example2@plt>
  xor    %eax,%eax
  call   <example3@plt>
  xor    %eax,%eax
  call   <example4@plt>
  xor    %eax,%eax
  call   <example4a@plt>
  xor    %eax,%eax
  call   <example4b@plt>
  xor    %eax,%eax
  call   <example4c@plt>
  xor    %eax,%eax
  call   <example5@plt>
  xor    %eax,%eax
  call   <example6@plt>
  xor    %eax,%eax
  call   <example7@plt>
  xor    %eax,%eax
  call   <example8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1150 <mineEx1@plt>
```

assistant: ```c
void main(void) {
  example1();
  example2();
  example3();
  example4();
  example4a();
  example4b();
  example4c();
  example5();
  example6();
  example7();
  example8();
  mineEx1();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <example1@plt>
  xor    %eax,%eax
  call   <example2@plt>
  xor    %eax,%eax
  call   <example3@plt>
  xor    %eax,%eax
  call   <example4@plt>
  xor    %eax,%eax
  call   <example4a@plt>
  xor    %eax,%eax
  call   <example4b@plt>
  xor    %eax,%eax
  call   <example4c@plt>
  xor    %eax,%eax
  call   <example5@plt>
  xor    %eax,%eax
  call   <example6@plt>
  xor    %eax,%eax
  call   <example7@plt>
  xor    %eax,%eax
  call   <example8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1150 <mineEx1@plt>
```

assistant: ```c
void main(void) {
  example1();
  example2();
  example3();
  example4();
  example4a();
  example4b();
  example4c();
  example5();
  example6();
  example7();
  example8();
  mineEx1();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readTagCharacter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  movzbl (%rax),%ebp
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  cmp    $0x5c,%ebp
  je     L78
L43:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L78:
  mov    %rdi,%rbx
  movzbl 0x1(%rax),%esi
  lea    -0x5c(%rsi),%edx
  cmp    $0x1c,%dl
  ja     L43
  movzbl %dl,%edx
  lea    D7(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0x9,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0xd,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0xa,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0x7,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0x8,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0xb,%ebp
  jmp    L43
  add    $0x2,%rax
  mov    %rax,(%rdi)
  mov    $0xc,%ebp
  jmp    L43
  movsbl 0x2(%rax),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L43
  mov    (%rbx),%rax
  movsbl 0x2(%rax),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L43
  mov    (%rbx),%rax
  movsbl 0x1(%rax),%edi
  call   <xdigitValue@plt>
  mov    %eax,%r12d
  mov    (%rbx),%rax
  movsbl 0x2(%rax),%edi
  call   <xdigitValue@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  cmp    $0x7f,%eax
  jg     L43
  addq   $0x3,(%rbx)
  mov    %eax,%ebp
  jmp    L43
```

assistant: ```c
int readTagCharacter(const char **s) {
  int c = **(const unsigned char **)s;
  (*s)++;
  if (c == '\\') {
    switch (**s) {
    case 't':
      c = '\t';
      (*s)++;
      break;
    case 'r':
      c = '\r';
      (*s)++;
      break;
    case 'n':
      c = '\n';
      (*s)++;
      break;
    case '\\':
      c = '\\';
      (*s)++;
      break;
    case 'a':
      c = '\a';
      (*s)++;
      break;
    case 'b':
      c = '\b';
      (*s)++;
      break;
    case 'v':
      c = '\v';
      (*s)++;
      break;
    case 'f':
      c = '\f';
      (*s)++;
      break;
    case 'x':
      if (isxdigit((*s)[1]) && isxdigit((*s)[2])) {
        int val = (xdigitValue((*s)[1]) << 4) | xdigitValue((*s)[2]);
        if (val < 0x80) {
          (*s) += 3;
          c = val;
        }
      }
      break;
    }
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readTagCharacter>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  movzbl (%rax),%r12d
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  cmp    $0x5c,%r12d
  je     L96
L118:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L96:
  movzbl 0x1(%rax),%esi
  lea    -0x5c(%rsi),%edx
  cmp    $0x1c,%dl
  ja     L118
  lea    D6(%rip),%rcx
  movzbl %dl,%edx
  mov    %rdi,%rbx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  movsbl 0x2(%rax),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L118
  mov    (%rbx),%rax
  movsbl 0x2(%rax),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L118
  mov    (%rbx),%rax
  movsbl 0x1(%rax),%edi
  call   <xdigitValue@plt>
  mov    %eax,%ebp
  mov    (%rbx),%rax
  movsbl 0x2(%rax),%edi
  call   <xdigitValue@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  shl    $0x4,%eax
  or     %r8d,%eax
  cmp    $0x7f,%eax
  jg     L118
  addq   $0x3,(%rbx)
  mov    %eax,%r12d
  jmp    L118
  nopl   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    %rax,(%rdi)
  jmp    L118
  nopl   0x0(%rax)
  add    $0x2,%rax
  mov    $0x7,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0x8,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0xc,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0xa,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0xd,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0x9,%r12d
  mov    %rax,(%rdi)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
  add    $0x2,%rax
  mov    $0xb,%r12d
  mov    %rax,(%rdi)
  jmp    L118
```

assistant: ```c
int readTagCharacter(const char **s) {
  int c = **(const unsigned char **)s;
  (*s)++;
  if (c == '\\') {
    switch (**s) {
    case 't':
      c = '\t';
      (*s)++;
      break;
    case 'r':
      c = '\r';
      (*s)++;
      break;
    case 'n':
      c = '\n';
      (*s)++;
      break;
    case '\\':
      c = '\\';
      (*s)++;
      break;
    case 'a':
      c = '\a';
      (*s)++;
      break;
    case 'b':
      c = '\b';
      (*s)++;
      break;
    case 'v':
      c = '\v';
      (*s)++;
      break;
    case 'f':
      c = '\f';
      (*s)++;
      break;
    case 'x':
      if (isxdigit((*s)[1]) && isxdigit((*s)[2])) {
        int val = (xdigitValue((*s)[1]) << 4) | xdigitValue((*s)[2]);
        if (val < 0x80) {
          (*s) += 3;
          c = val;
        }
      }
      break;
    }
  }
  return c;
}
```