ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<con_box>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <con_xy@plt>
  mov    %r13d,%edi
  call   <con_color@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L48
  jmp    L70
L68:
  cmp    $0xa,%dil
  je     L15
  call   <con_put_char@plt>
L79:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L70
L48:
  cmp    $0x5b,%dil
  je     L63
  cmp    $0x5d,%dil
  jne    L68
  mov    $0x5d,%edi
  add    $0x1,%rbx
  call   <con_put_char@plt>
  xor    %eax,%eax
  call   <con_unbold@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L48
L70:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <con_uncol@plt>
  nopw   0x0(%rax,%rax,1)
L63:
  xor    %eax,%eax
  call   <con_bold@plt>
  movsbl (%rbx),%edi
  call   <con_put_char@plt>
  jmp    L79
  nopl   0x0(%rax)
L15:
  add    $0x1,%ebp
  mov    %r12d,%edi
  mov    %ebp,%esi
  call   <con_xy@plt>
  jmp    L79
```

assistant: ```c
void con_box(int x, int y, int color, char const *text) {
  con_xy(x, y);
  con_color(color);
  for (char const *i = text; *i; ++i)
    switch (*i) {
    case '\n':
      con_xy(x, ++y);
      break;
    case '[':
      con_bold();
      con_put_char(*i);
      break;
    case ']':
      con_put_char(*i);
      con_unbold();
      break;
    default:
      con_put_char(*i);
    }
  con_uncol();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<busquedaBin2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L63
  mov    $0xffffffff,%eax
  jmp    L66
L63:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x28(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L59
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L10
L59:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L63
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jp     L36
  ucomisd -0x28(%rbp),%xmm0
  jne    L36
  mov    -0xc(%rbp),%eax
  jmp    L66
L36:
  mov    $0xffffffff,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int busquedaBin2(double m[], int n, double v) {
  int mitad, inf = 0, sup = n - 1;
  if (n == 0)
    return -1;
  do {
    mitad = (inf + sup) / 2;
    if (v > m[mitad])
      inf = mitad + 1;
    else
      sup = mitad;
  } while (inf < sup);
  if (m[inf] == v)
    return inf;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<busquedaBin2>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  je     L41
  mov    $0x0,%ecx
  jmp    L54
L2:
  lea    0x1(%rax),%ecx
L50:
  cmp    %r8d,%ecx
  jge    L34
L54:
  lea    (%rcx,%r8,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  comisd (%rdi,%rdx,8),%xmm0
  ja     L2
  mov    %eax,%r8d
  jmp    L50
L34:
  movslq %ecx,%rax
  ucomisd (%rdi,%rax,8),%xmm0
  jp     L42
  jne    L42
L9:
  mov    %ecx,%eax
  ret
L42:
  mov    $0xffffffff,%ecx
  jmp    L9
L41:
  mov    $0xffffffff,%ecx
  jmp    L9
```

assistant: ```c
int busquedaBin2(double m[], int n, double v) {
  int mitad, inf = 0, sup = n - 1;
  if (n == 0)
    return -1;
  do {
    mitad = (inf + sup) / 2;
    if (v > m[mitad])
      inf = mitad + 1;
    else
      sup = mitad;
  } while (inf < sup);
  if (m[inf] == v)
    return inf;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<busquedaBin2>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L26
  xor    %r8d,%r8d
  jmp    L0
L18:
  lea    0x1(%rax),%r8d
  cmp    %ecx,%r8d
  jge    L79
L0:
  lea    (%r8,%rcx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  comisd (%rdi,%rdx,8),%xmm0
  ja     L18
  mov    %eax,%ecx
  cmp    %ecx,%r8d
  jl     L0
L79:
  movslq %r8d,%rax
  ucomisd (%rdi,%rax,8),%xmm0
  jp     L26
  jne    L26
L61:
  mov    %r8d,%eax
  ret
L26:
  mov    $0xffffffff,%r8d
  jmp    L61
```

assistant: ```c
int busquedaBin2(double m[], int n, double v) {
  int mitad, inf = 0, sup = n - 1;
  if (n == 0)
    return -1;
  do {
    mitad = (inf + sup) / 2;
    if (v > m[mitad])
      inf = mitad + 1;
    else
      sup = mitad;
  } while (inf < sup);
  if (m[inf] == v)
    return inf;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<busquedaBin2>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  je     L34
  xor    %r8d,%r8d
  xchg   %ax,%ax
L75:
  lea    (%rcx,%r8,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  comisd (%rdi,%rdx,8),%xmm0
  jbe    L52
  lea    0x1(%rax),%r8d
  cmp    %ecx,%r8d
  jl     L75
L32:
  movslq %r8d,%rax
  ucomisd (%rdi,%rax,8),%xmm0
  jp     L34
  jne    L34
L38:
  mov    %r8d,%eax
  ret
L52:
  cmp    %r8d,%eax
  jle    L32
  mov    %eax,%ecx
  jmp    L75
L34:
  mov    $0xffffffff,%r8d
  jmp    L38
```

assistant: ```c
int busquedaBin2(double m[], int n, double v) {
  int mitad, inf = 0, sup = n - 1;
  if (n == 0)
    return -1;
  do {
    mitad = (inf + sup) / 2;
    if (v > m[mitad])
      inf = mitad + 1;
    else
      sup = mitad;
  } while (inf < sup);
  if (m[inf] == v)
    return inf;
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usbcandump_null_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: Received unexpected callback with %u messages %u/%u


assistant: ```c
void usbcandump_null_callback(uint32_t dev, uint32_t bus, struct usbcan_msg *msgs, uint32_t n, void *arg) {
#pragma unused(msgs)
#pragma unused(arg)
  printf("Received unexpected callback with %u messages %u/%u\n", n, dev, bus);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usbcandump_null_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %ecx,%esi
  mov    %eax,%ecx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: Received unexpected callback with %u messages %u/%u


assistant: ```c
void usbcandump_null_callback(uint32_t dev, uint32_t bus, struct usbcan_msg *msgs, uint32_t n, void *arg) {
#pragma unused(msgs)
#pragma unused(arg)
  printf("Received unexpected callback with %u messages %u/%u\n", n, dev, bus);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usbcandump_null_callback>:
  endbr64
  mov    %esi,%r8d
  mov    %edi,%edx
  lea    D3(%rip),%rdi
  mov    %ecx,%esi
  mov    %r8d,%ecx
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: Received unexpected callback with %u messages %u/%u


assistant: ```c
void usbcandump_null_callback(uint32_t dev, uint32_t bus, struct usbcan_msg *msgs, uint32_t n, void *arg) {
#pragma unused(msgs)
#pragma unused(arg)
  printf("Received unexpected callback with %u messages %u/%u\n", n, dev, bus);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usbcandump_null_callback>:
  endbr64
  mov    %esi,%r8d
  mov    %edi,%edx
  lea    D7(%rip),%rdi
  mov    %ecx,%esi
  mov    %r8d,%ecx
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: Received unexpected callback with %u messages %u/%u


assistant: ```c
void usbcandump_null_callback(uint32_t dev, uint32_t bus, struct usbcan_msg *msgs, uint32_t n, void *arg) {
#pragma unused(msgs)
#pragma unused(arg)
  printf("Received unexpected callback with %u messages %u/%u\n", n, dev, bus);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertionsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L35:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L49
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L49:
  cmpl   $0x0,-0x8(%rbp)
  jle    L18
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L13
L18:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertionsort(int array[], int length) {
  int i, temp;
  for (i = 0; i < length; i++) {
    int index = i;
    while (index > 0 && array[index] < array[index - 1]) {
      temp = array[index];
      array[index] = array[index - 1];
      array[index - 1] = temp;
      index--;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertionsort>:
  endbr64
  test   %esi,%esi
  jle    L32
  lea    0x4(%rdi),%r9
  mov    $0x0,%r8d
  jmp    L19
L65:
  add    $0x4,%r9
L19:
  add    $0x1,%r8d
  cmp    %r8d,%esi
  je     L32
  test   %r8d,%r8d
  jle    L65
  mov    %r9,%rax
L50:
  mov    (%rax),%ecx
  mov    -0x4(%rax),%edx
  cmp    %edx,%ecx
  jge    L65
  mov    %edx,(%rax)
  mov    %ecx,-0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L50
  jmp    L65
L32:
  ret
```

assistant: ```c
void insertionsort(int array[], int length) {
  int i, temp;
  for (i = 0; i < length; i++) {
    int index = i;
    while (index > 0 && array[index] < array[index - 1]) {
      temp = array[index];
      array[index] = array[index - 1];
      array[index - 1] = temp;
      index--;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertionsort>:
  endbr64
  test   %esi,%esi
  jle    L36
  xor    %r8d,%r8d
  lea    0x4(%rdi),%r9
  add    $0x1,%r8d
  cmp    %r8d,%esi
  je     L36
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r9,%rax
  jmp    L24
  nopl   (%rax)
L35:
  mov    %edx,(%rax)
  sub    $0x4,%rax
  mov    %ecx,(%rax)
  cmp    %rax,%rdi
  je     L55
L24:
  mov    (%rax),%ecx
  mov    -0x4(%rax),%edx
  cmp    %edx,%ecx
  jl     L35
L55:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L30
L36:
  ret
```

assistant: ```c
void insertionsort(int array[], int length) {
  int i, temp;
  for (i = 0; i < length; i++) {
    int index = i;
    while (index > 0 && array[index] < array[index - 1]) {
      temp = array[index];
      array[index] = array[index - 1];
      array[index - 1] = temp;
      index--;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insertionsort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L12
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r9,%rdx
  jmp    L8
  nopl   (%rax)
L16:
  movq   %xmm1,-0x4(%rdx)
  sub    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L1
L8:
  movq   -0x4(%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jg     L16
L1:
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r8d,%esi
  jne    L21
  ret
L12:
  ret
```

assistant: ```c
void insertionsort(int array[], int length) {
  int i, temp;
  for (i = 0; i < length; i++) {
    int index = i;
    while (index > 0 && array[index] < array[index - 1]) {
      temp = array[index];
      array[index] = array[index - 1];
      array[index - 1] = temp;
      index--;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L18:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  int i, len;
  long asc = 42;
  len = strlen(word) - 1;
  for (i = 0; i <= len; i++) {
    asc += word[i] * (i + 1);
  }
  return asc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L0
  lea    0x1(%rax),%esi
  mov    $0x1,%edx
  mov    $0x2a,%ecx
L7:
  movsbl -0x1(%rbx,%rdx,1),%eax
  imul   %edx,%eax
  cltq
  add    %rax,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L7
L2:
  mov    %rcx,%rax
  pop    %rbx
  ret
L0:
  mov    $0x2a,%ecx
  jmp    L2
```

assistant: ```c
long hash(char *word) {
  int i, len;
  long asc = 42;
  len = strlen(word) - 1;
  for (i = 0; i <= len; i++) {
    asc += word[i] * (i + 1);
  }
  return asc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  lea    0x1(%rax),%ecx
  mov    $0x1,%edx
  mov    $0x2a,%r8d
  nop
L17:
  movsbl -0x1(%rbx,%rdx,1),%eax
  imul   %edx,%eax
  add    $0x1,%rdx
  cltq
  add    %rax,%r8
  cmp    %rdx,%rcx
  jne    L17
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x2a,%r8d
  pop    %rbx
  mov    %r8,%rax
  ret
```

assistant: ```c
long hash(char *word) {
  int i, len;
  long asc = 42;
  len = strlen(word) - 1;
  for (i = 0; i <= len; i++) {
    asc += word[i] * (i + 1);
  }
  return asc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<flatten_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x50(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    %rax,%r12
  mov    $0x0,%r13d
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L32:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L33:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L17
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L17:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x50(%rbp),%rdx
  movq   $0x1,(%rax,%rdx,8)
  mov    -0x50(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x30(%rbp)
L3:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax,%rdx,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x60(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rcx
  imul   %rax,%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rcx,(%rax,%rdx,8)
  subq   $0x1,-0x30(%rbp)
  jmp    L3
```

assistant: ```c
void flatten_index(const char *array_name, size_t dims, const char *const idx_names[dims], size_t dims_vals[dims], char *out) {
  assert(dims > 0);
  unsigned long long cum_prod[dims + 1];
  cum_prod[dims] = 1;
  ssize_t i;
  for (i = dims - 1; i >= 0; i--) {
    cum_prod[i] = cum_prod[i + 1] * dims_vals[i];
  }
  size_t out_i = 0;
  out_i += sprintf(&out[out_i], "%s", array_name);
  out_i += sprintf(&out[out_i], "[%s*%llu", idx_names[0], cum_prod[1]);
  for (i = 1; i < dims; i++) {
    out_i += sprintf(&out[out_i], "+%s*%llu", idx_names[i], cum_prod[i + 1]);
  }
  out[out_i++] = ']';
  out[out_i++] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flatten_index>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
L5:
  jmp    L5
```

assistant: ```c
void flatten_index(const char *array_name, size_t dims, const char *const idx_names[dims], size_t dims_vals[dims], char *out) {
  assert(dims > 0);
  unsigned long long cum_prod[dims + 1];
  cum_prod[dims] = 1;
  ssize_t i;
  for (i = dims - 1; i >= 0; i--) {
    cum_prod[i] = cum_prod[i + 1] * dims_vals[i];
  }
  size_t out_i = 0;
  out_i += sprintf(&out[out_i], "%s", array_name);
  out_i += sprintf(&out[out_i], "[%s*%llu", idx_names[0], cum_prod[1]);
  for (i = 1; i < dims; i++) {
    out_i += sprintf(&out[out_i], "+%s*%llu", idx_names[i], cum_prod[i + 1]);
  }
  out[out_i++] = ']';
  out[out_i++] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<flatten_index>:
  endbr64
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
L5:
  jmp    L5
```

assistant: ```c
void flatten_index(const char *array_name, size_t dims, const char *const idx_names[dims], size_t dims_vals[dims], char *out) {
  assert(dims > 0);
  unsigned long long cum_prod[dims + 1];
  cum_prod[dims] = 1;
  ssize_t i;
  for (i = dims - 1; i >= 0; i--) {
    cum_prod[i] = cum_prod[i + 1] * dims_vals[i];
  }
  size_t out_i = 0;
  out_i += sprintf(&out[out_i], "%s", array_name);
  out_i += sprintf(&out[out_i], "[%s*%llu", idx_names[0], cum_prod[1]);
  for (i = 1; i < dims; i++) {
    out_i += sprintf(&out[out_i], "+%s*%llu", idx_names[i], cum_prod[i + 1]);
  }
  out[out_i++] = ']';
  out[out_i++] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flatten_index>:
  endbr64
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
L6:
  jmp    L6
```

assistant: ```c
void flatten_index(const char *array_name, size_t dims, const char *const idx_names[dims], size_t dims_vals[dims], char *out) {
  assert(dims > 0);
  unsigned long long cum_prod[dims + 1];
  cum_prod[dims] = 1;
  ssize_t i;
  for (i = dims - 1; i >= 0; i--) {
    cum_prod[i] = cum_prod[i + 1] * dims_vals[i];
  }
  size_t out_i = 0;
  out_i += sprintf(&out[out_i], "%s", array_name);
  out_i += sprintf(&out[out_i], "[%s*%llu", idx_names[0], cum_prod[1]);
  for (i = 1; i < dims; i++) {
    out_i += sprintf(&out[out_i], "+%s*%llu", idx_names[i], cum_prod[i + 1]);
  }
  out[out_i++] = ']';
  out[out_i++] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<c_regfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void c_regfree(void *preg) {
  if (preg != NULL) {
    regfree((regex_t *)preg);
    free(preg);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<c_regfree>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    %rdi,%rbx
  call   <regfree@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void c_regfree(void *preg) {
  if (preg != NULL) {
    regfree((regex_t *)preg);
    free(preg);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_regfree>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbp
  mov    %rdi,%rbp
  call   <regfree@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void c_regfree(void *preg) {
  if (preg != NULL) {
    regfree((regex_t *)preg);
    free(preg);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<c_regfree>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <regfree@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void c_regfree(void *preg) {
  if (preg != NULL) {
    regfree((regex_t *)preg);
    free(preg);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mysmpte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    $0x0,%eax
  call   <prtime@plt>
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: SMPTE %d %d %d %d %d


assistant: ```c
mysmpte(hr, mn, se, fr, ff) int hr, mn, se, fr, ff;
{
  prtime();
  printf("SMPTE %d %d %d %d %d\n", hr, mn, se, fr, ff);
}
```
user: What is the c source code of the assembly code below?

```asm
<mysmpte>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    $0x0,%eax
  call   <prtime@plt>
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: SMPTE %d %d %d %d %d


assistant: ```c
mysmpte(hr, mn, se, fr, ff) int hr, mn, se, fr, ff;
{
  prtime();
  printf("SMPTE %d %d %d %d %d\n", hr, mn, se, fr, ff);
}
```
user: What is the c source code of the assembly code below:

```asm
<mysmpte>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %r8d,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  call   <prtime@plt>
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  pop    %rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  pop    %rbp
  lea    D3(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: SMPTE %d %d %d %d %d


assistant: ```c
mysmpte(hr, mn, se, fr, ff) int hr, mn, se, fr, ff;
{
  prtime();
  printf("SMPTE %d %d %d %d %d\n", hr, mn, se, fr, ff);
}
```