ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<fgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L26
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L58
L26:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L23
L35:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L51
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0xc(%rbp)
  je     L9
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L35
  jmp    L23
L51:
  nop
  jmp    L23
L9:
  nop
L23:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L58:
  leave
  ret
```

assistant: ```c
char *fgets(char *s, int n, FILE *stream) {
  char *s0 = s;
  int c;
  if (feof(stream)) {
    *s = '\0';
    return NULL;
  }
  n--;
  if (n > 0) {
    do {
      c = fgetc(stream);
      if (c == EOF)
        break;
      *s++ = c;
      if (c == '\n')
        break;
    } while (--n > 0);
  }
  *s = '\0';
  return s0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fgets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L22
  mov    %r12,%rbx
  cmp    $0x1,%r13d
  jle    L5
  lea    -0x2(%r13),%eax
  lea    0x1(%r12,%rax,1),%r13
L36:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L5
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%eax
  je     L5
  cmp    %r13,%rbx
  jne    L36
  mov    %r13,%rbx
L5:
  movb   $0x0,(%rbx)
  mov    %r12,%rax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  movb   $0x0,(%r12)
  mov    $0x0,%eax
  jmp    L42
```

assistant: ```c
char *fgets(char *s, int n, FILE *stream) {
  char *s0 = s;
  int c;
  if (feof(stream)) {
    *s = '\0';
    return NULL;
  }
  n--;
  if (n > 0) {
    do {
      c = fgetc(stream);
      if (c == EOF)
        break;
      *s++ = c;
      if (c == '\n')
        break;
    } while (--n > 0);
  }
  *s = '\0';
  return s0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fgets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <feof@plt>
  test   %rax,%rax
  jne    L43
  mov    %rbp,%r14
  cmp    $0x1,%r12d
  jle    L25
  lea    -0x2(%r12),%eax
  mov    D5(%rip),%r12
  lea    0x1(%rbp,%rax,1),%r13
  jmp    L30
  xchg   %ax,%ax
L36:
  add    $0x1,%r14
  mov    %al,-0x1(%r14)
  cmp    $0xa,%eax
  je     L25
  cmp    %r13,%r14
  je     L25
L30:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  jne    L36
L25:
  movb   $0x0,(%r14)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *fgets(char *s, int n, FILE *stream) {
  char *s0 = s;
  int c;
  if (feof(stream)) {
    *s = '\0';
    return NULL;
  }
  n--;
  if (n > 0) {
    do {
      c = fgetc(stream);
      if (c == EOF)
        break;
      *s++ = c;
      if (c == '\n')
        break;
    } while (--n > 0);
  }
  *s = '\0';
  return s0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fgets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <feof@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbp,%r14
  cmp    $0x1,%r12d
  jle    L1
  lea    -0x2(%r12),%eax
  mov    D9(%rip),%r12
  lea    0x1(%rbp,%rax,1),%r13
  jmp    L54
  xchg   %ax,%ax
L0:
  add    $0x1,%r14
  mov    %al,-0x1(%r14)
  cmp    $0xa,%eax
  je     L1
  cmp    %r13,%r14
  je     L1
L54:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  jne    L0
L1:
  movb   $0x0,(%r14)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *fgets(char *s, int n, FILE *stream) {
  char *s0 = s;
  int c;
  if (feof(stream)) {
    *s = '\0';
    return NULL;
  }
  n--;
  if (n > 0) {
    do {
      c = fgetc(stream);
      if (c == EOF)
        break;
      *s++ = c;
      if (c == '\n')
        break;
    } while (--n > 0);
  }
  *s = '\0';
  return s0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  lea    0x1(%rdx),%eax
  mov    %eax,-0x4(%rbp)
  mov    D27(%rip),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,D28(%rip)
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
type_infered: string

tool: D28: x = %d, y = %d


assistant: ```c
void func1(void) {
  static int x = 0;
  int y = 0;
  printf("x = %d, y = %d\n", x++, y++);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<func1>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%esi
  lea    0x1(%rsi),%eax
  mov    %eax,D23(%rip)
  mov    $0x0,%edx
  lea    D23(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
type: string

tool: D23: x = %d, y = %d


assistant: ```c
void func1(void) {
  static int x = 0;
  int y = 0;
  printf("x = %d, y = %d\n", x++, y++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_checkstrto32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    D38(%rip),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L73
  mov    D62(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L78
L73:
  mov    D22(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jg     L21
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jge    L79
L21:
  mov    D52(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L78
L79:
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L58
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L78
L58:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L78:
  leave
  ret
```

assistant: ```c
int _checkstrto32(const char *str, int32_t *ret, char **endptr) {
  long long ll;
  errno = 0;
  ll = strtoll(str, endptr, 10);
  if (*endptr == str)
    return -EINVAL;
  if (ll > INT32_MAX || ll < INT32_MIN)
    return -ERANGE;
  if (!ll && errno != 0)
    return -errno;
  *ret = (int32_t)ll;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_checkstrto32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    D11(%rip),%rax
  movl   $0x0,(%rax)
  mov    $0xa,%edx
  mov    %rbp,%rsi
  call   <strtoll@plt>
  cmp    %rbx,0x0(%rbp)
  je     L50
  mov    D51(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L0
  mov    D1(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L0
  test   %rax,%rax
  jne    L48
  mov    D11(%rip),%rdx
  mov    (%rdx),%edx
  test   %edx,%edx
  jne    L47
L48:
  mov    %rax,(%r12)
  mov    $0x0,%eax
  jmp    L20
L50:
  mov    D52(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L20
L0:
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %edx,%eax
  neg    %eax
  jmp    L20
```

assistant: ```c
int _checkstrto32(const char *str, int32_t *ret, char **endptr) {
  long long ll;
  errno = 0;
  ll = strtoll(str, endptr, 10);
  if (*endptr == str)
    return -EINVAL;
  if (ll > INT32_MAX || ll < INT32_MIN)
    return -ERANGE;
  if (!ll && errno != 0)
    return -errno;
  *ret = (int32_t)ll;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_checkstrto32>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rbp,%rsi
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D35(%rip),%r13
  movl   $0x0,0x0(%r13)
  call   <strtoll@plt>
  cmp    %rbx,0x0(%rbp)
  je     L49
  mov    D14(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L9
  mov    D24(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L9
  test   %rax,%rax
  jne    L21
  mov    0x0(%r13),%edx
  test   %edx,%edx
  je     L21
  mov    %edx,%eax
  neg    %eax
  jmp    L3
  nopl   0x0(%rax)
L9:
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L21:
  mov    %rax,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L49:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _checkstrto32(const char *str, int32_t *ret, char **endptr) {
  long long ll;
  errno = 0;
  ll = strtoll(str, endptr, 10);
  if (*endptr == str)
    return -EINVAL;
  if (ll > INT32_MAX || ll < INT32_MIN)
    return -ERANGE;
  if (!ll && errno != 0)
    return -errno;
  *ret = (int32_t)ll;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_checkstrto32>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0xa,%edx
  push   %rbx
  mov    %rbp,%rsi
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D17(%rip),%r13
  movl   $0x0,0x0(%r13)
  call   <strtoll@plt>
  cmp    %rbx,0x0(%rbp)
  je     L9
  mov    D1(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L26
  mov    D10(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L26
  test   %rax,%rax
  jne    L39
  mov    0x0(%r13),%edx
  test   %edx,%edx
  je     L39
  mov    %edx,%eax
  neg    %eax
  jmp    L30
  nopl   0x0(%rax)
L26:
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L39:
  mov    %rax,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _checkstrto32(const char *str, int32_t *ret, char **endptr) {
  long long ll;
  errno = 0;
  ll = strtoll(str, endptr, 10);
  if (*endptr == str)
    return -EINVAL;
  if (ll > INT32_MAX || ll < INT32_MIN)
    return -ERANGE;
  if (!ll && errno != 0)
    return -errno;
  *ret = (int32_t)ll;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<format_extension_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L53
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
L53:
  mov    $0x0,%eax
  jmp    L113
L58:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L94
L52:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L47
  addl   $0x1,-0xc(%rbp)
L47:
  addq   $0x1,-0x8(%rbp)
L94:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L95
  mov    $0x0,%eax
  jmp    L113
L95:
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L124:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L92
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2c,(%rax)
L92:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L121
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L124
L121:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L80
L54:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L80:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L54
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L54
  mov    -0x8(%rbp),%rax
L113:
  leave
  ret
```

assistant: ```c
char *format_extension_list(const char *ext) {
  int i;
  char *extTmp = NULL;
  if (!ext || !ext[0])
    return NULL;
  i = 0;
  extTmp = (char *)ext;
  while (*extTmp != '\0') {
    if (*extTmp == ' ') {
      i++;
    }
    extTmp++;
  }
  extTmp = (char *)malloc((strlen(ext) + i + 1) * sizeof(char));
  if (extTmp == NULL) {
    return NULL;
  }
  i = 0;
  while (*ext != '\0' && *ext != '\n') {
    if (*ext == ' ') {
      extTmp[i++] = ',';
    }
    extTmp[i++] = *ext;
    ext++;
  }
  extTmp[i] = '\0';
  while (extTmp[strlen(extTmp) - 1] == ' ' || extTmp[strlen(extTmp) - 1] == ',') {
    extTmp[strlen(extTmp) - 1] = '\0';
  }
  return extTmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<format_extension_list>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L124
  movzbl (%rdi),%eax
  test   %al,%al
  je     L156
  mov    %rdi,%rdx
  mov    $0x0,%ebx
L4:
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L4
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L122
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L116
  cmp    $0xa,%dl
  je     L116
  mov    $0x0,%ecx
  jmp    L99
L83:
  lea    0x1(%rax),%ecx
  movzbl 0x0(%rbp),%edx
  cltq
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L13
  cmp    $0xa,%dl
  je     L13
L99:
  mov    %ecx,%eax
  cmp    $0x20,%dl
  jne    L83
  lea    0x1(%rcx),%eax
  movslq %ecx,%rcx
  movb   $0x2c,(%rbx,%rcx,1)
  jmp    L83
L116:
  mov    $0x0,%ecx
L13:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  jmp    L96
L65:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
L96:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x20,-0x1(%rbx,%rax,1)
  je     L65
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2c,-0x1(%rbx,%rax,1)
  je     L65
L125:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L124:
  mov    %rdi,%rbx
  jmp    L125
L156:
  mov    $0x0,%ebx
  jmp    L125
L122:
  mov    $0x0,%ebx
  jmp    L125
```

assistant: ```c
char *format_extension_list(const char *ext) {
  int i;
  char *extTmp = NULL;
  if (!ext || !ext[0])
    return NULL;
  i = 0;
  extTmp = (char *)ext;
  while (*extTmp != '\0') {
    if (*extTmp == ' ') {
      i++;
    }
    extTmp++;
  }
  extTmp = (char *)malloc((strlen(ext) + i + 1) * sizeof(char));
  if (extTmp == NULL) {
    return NULL;
  }
  i = 0;
  while (*ext != '\0' && *ext != '\n') {
    if (*ext == ' ') {
      extTmp[i++] = ',';
    }
    extTmp[i++] = *ext;
    ext++;
  }
  extTmp[i] = '\0';
  while (extTmp[strlen(extTmp) - 1] == ' ' || extTmp[strlen(extTmp) - 1] == ',') {
    extTmp[strlen(extTmp) - 1] = '\0';
  }
  return extTmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<format_extension_list>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L102
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L102
  mov    %rdi,%rdx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L74:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%r12d
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L74
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L102
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L99
  cmp    $0xa,%dl
  je     L99
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %ecx,%eax
  cmp    $0x20,%dl
  jne    L80
  movslq %ecx,%rcx
  add    $0x1,%eax
  movb   $0x2c,(%r12,%rcx,1)
L80:
  movzbl (%rbx),%edx
  lea    0x1(%rax),%ecx
  add    $0x1,%rbx
  cltq
  mov    %dl,(%r12,%rax,1)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L91
  cmp    $0xa,%dl
  jne    L86
L91:
  movslq %ecx,%rcx
  add    %r12,%rcx
L9:
  movb   $0x0,(%rcx)
  jmp    L56
  nopl   0x0(%rax)
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
L56:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x20,-0x1(%r12,%rax,1)
  je     L13
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2c,-0x1(%r12,%rax,1)
  je     L13
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L102:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L99:
  mov    %r12,%rcx
  jmp    L9
```

assistant: ```c
char *format_extension_list(const char *ext) {
  int i;
  char *extTmp = NULL;
  if (!ext || !ext[0])
    return NULL;
  i = 0;
  extTmp = (char *)ext;
  while (*extTmp != '\0') {
    if (*extTmp == ' ') {
      i++;
    }
    extTmp++;
  }
  extTmp = (char *)malloc((strlen(ext) + i + 1) * sizeof(char));
  if (extTmp == NULL) {
    return NULL;
  }
  i = 0;
  while (*ext != '\0' && *ext != '\n') {
    if (*ext == ' ') {
      extTmp[i++] = ',';
    }
    extTmp[i++] = *ext;
    ext++;
  }
  extTmp[i] = '\0';
  while (extTmp[strlen(extTmp) - 1] == ' ' || extTmp[strlen(extTmp) - 1] == ',') {
    extTmp[strlen(extTmp) - 1] = '\0';
  }
  return extTmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<format_extension_list>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L89
  movzbl (%rdi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L89
  mov    %rdi,%rdx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L97:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%r12d
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L97
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L89
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L98
  cmp    $0xa,%dl
  je     L98
  xor    %eax,%eax
  jmp    L106
  nopl   0x0(%rax)
L78:
  movslq %ecx,%rax
L106:
  lea    0x1(%rax),%ecx
  cmp    $0x20,%dl
  jne    L127
  movslq %eax,%rdx
  lea    0x2(%rax),%ecx
  add    $0x1,%eax
  movb   $0x2c,(%r12,%rdx,1)
  movzbl (%rbx),%edx
  cltq
L127:
  add    $0x1,%rbx
  mov    %dl,(%r12,%rax,1)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L5
  cmp    $0xa,%dl
  jne    L78
L5:
  movslq %ecx,%rcx
  add    %r12,%rcx
L65:
  movb   $0x0,(%rcx)
  jmp    L105
  nopl   (%rax)
L51:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
L105:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x20,-0x1(%r12,%rax,1)
  je     L51
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x2c,-0x1(%r12,%rax,1)
  je     L51
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L89:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L98:
  mov    %r12,%rcx
  jmp    L65
```

assistant: ```c
char *format_extension_list(const char *ext) {
  int i;
  char *extTmp = NULL;
  if (!ext || !ext[0])
    return NULL;
  i = 0;
  extTmp = (char *)ext;
  while (*extTmp != '\0') {
    if (*extTmp == ' ') {
      i++;
    }
    extTmp++;
  }
  extTmp = (char *)malloc((strlen(ext) + i + 1) * sizeof(char));
  if (extTmp == NULL) {
    return NULL;
  }
  i = 0;
  while (*ext != '\0' && *ext != '\n') {
    if (*ext == ' ') {
      extTmp[i++] = ',';
    }
    extTmp[i++] = *ext;
    ext++;
  }
  extTmp[i] = '\0';
  while (extTmp[strlen(extTmp) - 1] == ' ' || extTmp[strlen(extTmp) - 1] == ',') {
    extTmp[strlen(extTmp) - 1] = '\0';
  }
  return extTmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<dsh_check_prompt_buf_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L52:
  addl   $0x2,-0x1c(%rbp)
L56:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L52
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L36:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  mov    $0x0,%eax
  jmp    L29
L49:
  mov    -0x1c(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int dsh_check_prompt_buf_len(char **prompt, int buffsize, int needed) {
  char *backup = NULL;
  int init_prompt_len = strlen(*prompt), i = 0;
  if (init_prompt_len + needed >= buffsize) {
    backup = *prompt;
    while (init_prompt_len + needed >= buffsize) {
      buffsize += 2;
    }
    *prompt = realloc(*prompt, buffsize);
    for (i = init_prompt_len; i < buffsize; i++)
      (*prompt)[i] = '\0';
    if (!(*prompt)) {
      free(backup);
      prompt = NULL;
      return 0;
    }
  }
  return buffsize;
}
```