ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bno_delay_ms>:
  endbr64
  test   %edi,%edi
  je     L12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: Delay

assistant: ```c
void bno_delay_ms(uint32_t delay_time) {
  while (delay_time--)
    printf("Delay");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: O tipo de 123.4 tem %ld bytes.


assistant: ```c
int main() {
  printf("O tipo de 123.4 tem %ld bytes.\n", sizeof(typeof(123.4)));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: O tipo de 123.4 tem %ld bytes.


assistant: ```c
int main() {
  printf("O tipo de 123.4 tem %ld bytes.\n", sizeof(typeof(123.4)));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: O tipo de 123.4 tem %ld bytes.


assistant: ```c
int main() {
  printf("O tipo de 123.4 tem %ld bytes.\n", sizeof(typeof(123.4)));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: O tipo de 123.4 tem %ld bytes.


assistant: ```c
int main() {
  printf("O tipo de 123.4 tem %ld bytes.\n", sizeof(typeof(123.4)));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L14
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L14:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type: string
name: unpack_data
arguments: label: D5
type: string

tool: D11: TAK


tool: D5: NIE


assistant: ```c
int main() {
  int a = 2, b = 4;
  if ((a = 2) & (b = 4))
    printf("TAK\n");
  else
    printf("NIE\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: NIE


assistant: ```c
int main() {
  int a = 2, b = 4;
  if ((a = 2) & (b = 4))
    printf("TAK\n");
  else
    printf("NIE\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: NIE


assistant: ```c
int main() {
  int a = 2, b = 4;
  if ((a = 2) & (b = 4))
    printf("TAK\n");
  else
    printf("NIE\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: NIE


assistant: ```c
int main() {
  int a = 2, b = 4;
  if ((a = 2) & (b = 4))
    printf("TAK\n");
  else
    printf("NIE\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bedToRangeTree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rangeTreeNew@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bedIntoRangeTree@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct rbTree *bedToRangeTree(struct bed *bed) {
  struct rbTree *rangeTree = rangeTreeNew();
  bedIntoRangeTree(bed, rangeTree);
  return rangeTree;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bedToRangeTree>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <rangeTreeNew@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <bedIntoRangeTree@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct rbTree *bedToRangeTree(struct bed *bed) {
  struct rbTree *rangeTree = rangeTreeNew();
  bedIntoRangeTree(bed, rangeTree);
  return rangeTree;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bedToRangeTree>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <rangeTreeNew@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <bedIntoRangeTree@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct rbTree *bedToRangeTree(struct bed *bed) {
  struct rbTree *rangeTree = rangeTreeNew();
  bedIntoRangeTree(bed, rangeTree);
  return rangeTree;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bedToRangeTree>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <rangeTreeNew@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <bedIntoRangeTree@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct rbTree *bedToRangeTree(struct bed *bed) {
  struct rbTree *rangeTree = rangeTreeNew();
  bedIntoRangeTree(bed, rangeTree);
  return rangeTree;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dest>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L191
  cmp    $0x4d,%dl
  je     L221
  cmp    $0x44,%dl
  je     L6
  cmp    $0x41,%dl
  je     L161
L218:
  add    $0x8,%rsp
  ret
L191:
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <init3Bits@plt>
  jmp    L218
L221:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L214
  cmp    $0x44,%dl
  jne    L218
  cmpb   $0x0,0x2(%rax)
  jne    L218
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <init3Bits@plt>
  jmp    L218
L214:
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <init3Bits@plt>
  jmp    L218
L6:
  cmpb   $0x0,0x1(%rax)
  jne    L218
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <init3Bits@plt>
  jmp    L218
L161:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L173
  cmp    $0x4d,%dl
  je     L128
  cmp    $0x44,%dl
  jne    L218
  cmpb   $0x0,0x2(%rax)
  jne    L218
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <init3Bits@plt>
  jmp    L218
L173:
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <init3Bits@plt>
  jmp    L218
L128:
  cmpb   $0x0,0x2(%rax)
  je     L16
  cmp    $0x4d,%dl
  jne    L218
  cmpb   $0x44,0x2(%rax)
  jne    L218
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <init3Bits@plt>
  jmp    L218
L16:
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <init3Bits@plt>
  jmp    L218
```

assistant: ```c
void dest(const char *string, int bits[3]) {
  if (string[0] == '\0')
    init3Bits(bits, 0, 0, 0);
  else if (string[0] == 'M' && string[1] == '\0')
    init3Bits(bits, 0, 0, 1);
  else if (string[0] == 'D' && string[1] == '\0')
    init3Bits(bits, 0, 1, 0);
  else if (string[0] == 'M' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 0, 1, 1);
  else if (string[0] == 'A' && string[1] == '\0')
    init3Bits(bits, 1, 0, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == '\0')
    init3Bits(bits, 1, 0, 1);
  else if (string[0] == 'A' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 1, 1, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == 'D')
    init3Bits(bits, 1, 1, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dest>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L37
  cmp    $0x4d,%dl
  je     L90
  cmp    $0x44,%dl
  je     L104
  cmp    $0x41,%dl
  je     L68
L63:
  ret
  nopl   0x0(%rax)
L90:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L55
  cmp    $0x44,%dl
  jne    L63
  cmpb   $0x0,0x2(%rax)
  jne    L63
  mov    $0x1,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L37:
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax,%rax,1)
L104:
  cmpb   $0x0,0x1(%rax)
  jne    L63
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L68:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L22
  cmp    $0x4d,%dl
  je     L40
  cmp    $0x44,%dl
  jne    L63
  cmpb   $0x0,0x2(%rax)
  jne    L63
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L55:
  mov    $0x1,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  cs nopw 0x0(%rax,%rax,1)
L22:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  xchg   %ax,%ax
L40:
  cmpb   $0x0,0x2(%rax)
  je     L131
  cmpb   $0x44,0x2(%rax)
  jne    L63
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L131:
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
```

assistant: ```c
void dest(const char *string, int bits[3]) {
  if (string[0] == '\0')
    init3Bits(bits, 0, 0, 0);
  else if (string[0] == 'M' && string[1] == '\0')
    init3Bits(bits, 0, 0, 1);
  else if (string[0] == 'D' && string[1] == '\0')
    init3Bits(bits, 0, 1, 0);
  else if (string[0] == 'M' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 0, 1, 1);
  else if (string[0] == 'A' && string[1] == '\0')
    init3Bits(bits, 1, 0, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == '\0')
    init3Bits(bits, 1, 0, 1);
  else if (string[0] == 'A' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 1, 1, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == 'D')
    init3Bits(bits, 1, 1, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dest>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L34
  cmp    $0x4d,%dl
  je     L85
  cmp    $0x44,%dl
  je     L86
  cmp    $0x41,%dl
  je     L16
L109:
  ret
  nopl   0x0(%rax)
L85:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L13
  cmp    $0x44,%dl
  jne    L109
  cmpb   $0x0,0x2(%rax)
  jne    L109
  mov    $0x1,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L34:
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax,%rax,1)
L86:
  cmpb   $0x0,0x1(%rax)
  jne    L109
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L16:
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L18
  cmp    $0x4d,%dl
  je     L6
  cmp    $0x44,%dl
  jne    L109
  cmpb   $0x0,0x2(%rax)
  jne    L109
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L13:
  mov    $0x1,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  jmp    1050 <init3Bits@plt>
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  xchg   %ax,%ax
L6:
  cmpb   $0x0,0x2(%rax)
  je     L92
  cmpb   $0x44,0x2(%rax)
  jne    L109
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
  nopl   0x0(%rax)
L92:
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  jmp    1050 <init3Bits@plt>
```

assistant: ```c
void dest(const char *string, int bits[3]) {
  if (string[0] == '\0')
    init3Bits(bits, 0, 0, 0);
  else if (string[0] == 'M' && string[1] == '\0')
    init3Bits(bits, 0, 0, 1);
  else if (string[0] == 'D' && string[1] == '\0')
    init3Bits(bits, 0, 1, 0);
  else if (string[0] == 'M' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 0, 1, 1);
  else if (string[0] == 'A' && string[1] == '\0')
    init3Bits(bits, 1, 0, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == '\0')
    init3Bits(bits, 1, 0, 1);
  else if (string[0] == 'A' && string[1] == 'D' && string[2] == '\0')
    init3Bits(bits, 1, 1, 0);
  else if (string[0] == 'A' && string[1] == 'M' && string[2] == 'D')
    init3Bits(bits, 1, 1, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_hello>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x21646c72,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  movq   $0xb8000,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L41
L4:
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    $0x0,%eax
  mov    %al,(%rdx)
  mov    -0x24(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addl   $0x1,-0x24(%rbp)
L41:
  cmpl   $0x7cf,-0x24(%rbp)
  jle    L4
  movl   $0x0,-0x24(%rbp)
  jmp    L30
L47:
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x7,(%rax)
  addl   $0x1,-0x24(%rbp)
L30:
  cmpl   $0xc,-0x24(%rbp)
  jle    L47
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void print_hello() {
  int i;
  char hello[] = "Hello World!";
  volatile char *video = ((volatile char *)0x000B8000);
  for (i = 0; i < 80 * 25; i++)
    video[i * 2] = video[i * 2 + 1] = 0;
  for (i = 0; i < 13; i++) {
    video[i * 2] = hello[i];
    video[i * 2 + 1] = 7;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_hello>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6f57206f6c6c6548,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x21646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    $0xb8001,%eax
L23:
  movb   $0x0,(%rax)
  movb   $0x0,-0x1(%rax)
  add    $0x2,%rax
  cmp    $0xb8fa1,%rax
  jne    L23
  lea    0xb(%rsp),%rdx
  mov    $0xb8000,%eax
L29:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  movb   $0x7,0x1(%rax)
  add    $0x1,%rdx
  add    $0x2,%rax
  cmp    $0xb801a,%rax
  jne    L29
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_hello() {
  int i;
  char hello[] = "Hello World!";
  volatile char *video = ((volatile char *)0x000B8000);
  for (i = 0; i < 80 * 25; i++)
    video[i * 2] = video[i * 2 + 1] = 0;
  for (i = 0; i < 13; i++) {
    video[i * 2] = hello[i];
    video[i * 2 + 1] = 7;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_hello>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  movl   $0x21646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  mov    $0xb8001,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  movb   $0x0,(%rax)
  add    $0x2,%rax
  movb   $0x0,-0x3(%rax)
  cmp    $0xb8fa1,%rax
  jne    L6
  lea    0xc(%rsp),%rdx
  mov    $0xb8000,%eax
  mov    $0x48,%ecx
  jmp    L16
  nopl   0x0(%rax)
L11:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
L16:
  mov    %cl,(%rax)
  add    $0x2,%rax
  movb   $0x7,-0x1(%rax)
  cmp    $0xb801a,%rax
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_hello() {
  int i;
  char hello[] = "Hello World!";
  volatile char *video = ((volatile char *)0x000B8000);
  for (i = 0; i < 80 * 25; i++)
    video[i * 2] = video[i * 2 + 1] = 0;
  for (i = 0; i < 13; i++) {
    video[i * 2] = hello[i];
    video[i * 2 + 1] = 7;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_hello>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6f57206f6c6c6548,%rax
  movl   $0x21646c72,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  mov    $0xb8001,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%rax)
  add    $0x2,%rax
  movb   $0x0,-0x3(%rax)
  cmp    $0xb8fa1,%rax
  jne    L1
  movb   $0x48,0xb8000
  movb   $0x7,0xb8001
  movzbl 0xc(%rsp),%eax
  mov    %al,0xb8002
  movb   $0x7,0xb8003
  movzbl 0xd(%rsp),%eax
  mov    %al,0xb8004
  movb   $0x7,0xb8005
  movzbl 0xe(%rsp),%eax
  mov    %al,0xb8006
  movb   $0x7,0xb8007
  movzbl 0xf(%rsp),%eax
  mov    %al,0xb8008
  movb   $0x7,0xb8009
  movzbl 0x10(%rsp),%eax
  mov    %al,0xb800a
  movb   $0x7,0xb800b
  movzbl 0x11(%rsp),%eax
  mov    %al,0xb800c
  movb   $0x7,0xb800d
  movzbl 0x12(%rsp),%eax
  mov    %al,0xb800e
  movb   $0x7,0xb800f
  movzbl 0x13(%rsp),%eax
  mov    %al,0xb8010
  movb   $0x7,0xb8011
  movzbl 0x14(%rsp),%eax
  mov    %al,0xb8012
  movb   $0x7,0xb8013
  movzbl 0x15(%rsp),%eax
  mov    %al,0xb8014
  movb   $0x7,0xb8015
  movzbl 0x16(%rsp),%eax
  mov    %al,0xb8016
  movb   $0x7,0xb8017
  movzbl 0x17(%rsp),%eax
  mov    %al,0xb8018
  movb   $0x7,0xb8019
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_hello() {
  int i;
  char hello[] = "Hello World!";
  volatile char *video = ((volatile char *)0x000B8000);
  for (i = 0; i < 80 * 25; i++)
    video[i * 2] = video[i * 2 + 1] = 0;
  for (i = 0; i < 13; i++) {
    video[i * 2] = hello[i];
    video[i * 2 + 1] = 7;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<preshift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L5:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x7,-0x8(%rbp)
  jle    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t preshift(uint32_t val, int bits) {
  int i;
  uint32_t o;
  o = 0;
  for (i = 0; i < 8; i++) {
    o |= (val & (1U << i)) << (i + bits);
  }
  return o;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<preshift>:
  endbr64
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x1,%r9d
L9:
  mov    %r9d,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  and    %edi,%eax
  lea    (%rsi,%rdx,1),%ecx
  shl    %cl,%eax
  or     %eax,%r8d
  add    $0x1,%edx
  cmp    $0x8,%edx
  jne    L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t preshift(uint32_t val, int bits) {
  int i;
  uint32_t o;
  o = 0;
  for (i = 0; i < 8; i++) {
    o |= (val & (1U << i)) << (i + bits);
  }
  return o;
}
```
user: What is the c source code of the assembly code below?

```asm
<preshift>:
  endbr64
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    $0x1,%r9d
  nop
L0:
  mov    %edx,%ecx
  mov    %r9d,%eax
  shl    %cl,%eax
  lea    (%rdx,%rsi,1),%ecx
  add    $0x1,%edx
  and    %edi,%eax
  shl    %cl,%eax
  or     %eax,%r8d
  cmp    $0x8,%edx
  jne    L0
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t preshift(uint32_t val, int bits) {
  int i;
  uint32_t o;
  o = 0;
  for (i = 0; i < 8; i++) {
    o |= (val & (1U << i)) << (i + bits);
  }
  return o;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<preshift>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  lea    0x1(%rsi),%ecx
  and    $0x2,%edi
  mov    %eax,%esi
  shl    %cl,%edi
  mov    %edx,%ecx
  and    $0x1,%esi
  shl    %cl,%esi
  lea    0x2(%rdx),%ecx
  or     %esi,%edi
  mov    %eax,%esi
  and    $0x4,%esi
  shl    %cl,%esi
  lea    0x3(%rdx),%ecx
  or     %edi,%esi
  mov    %eax,%edi
  and    $0x8,%edi
  shl    %cl,%edi
  lea    0x4(%rdx),%ecx
  or     %esi,%edi
  mov    %eax,%esi
  and    $0x10,%esi
  shl    %cl,%esi
  lea    0x5(%rdx),%ecx
  or     %edi,%esi
  mov    %eax,%edi
  and    $0x20,%edi
  shl    %cl,%edi
  lea    0x6(%rdx),%ecx
  or     %esi,%edi
  mov    %eax,%esi
  and    $0x80,%eax
  and    $0x40,%esi
  shl    %cl,%esi
  lea    0x7(%rdx),%ecx
  or     %edi,%esi
  shl    %cl,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
uint32_t preshift(uint32_t val, int bits) {
  int i;
  uint32_t o;
  o = 0;
  for (i = 0; i < 8; i++) {
    o |= (val & (1U << i)) << (i + bits);
  }
  return o;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xstrtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L24
  mov    D17(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L24
L41:
  mov    $0xffffffff,%eax
  jmp    L27
L24:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int xstrtoul(const char *str, unsigned long *valuep) {
  unsigned long value;
  char *endp;
  value = strtoul(str, &endp, 0);
  if (*endp || (value == ULONG_MAX && errno == ERANGE))
    return -1;
  *valuep = value;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xstrtoul>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L23
  mov    D25(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L32
L57:
  mov    %rax,(%rbx)
  mov    $0x0,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  ret
L32:
  mov    D3(%rip),%rcx
  mov    D5(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L57
  mov    $0xffffffff,%eax
  jmp    L18
L23:
  mov    $0xffffffff,%eax
  jmp    L18
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int xstrtoul(const char *str, unsigned long *valuep) {
  unsigned long value;
  char *endp;
  value = strtoul(str, &endp, 0);
  if (*endp || (value == ULONG_MAX && errno == ERANGE))
    return -1;
  *valuep = value;
  return 0;
}
```