ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x14(%rsp)
  xor    %eax,%eax
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    (%rsp,%rbx,4),%eax
L10:
  mov    %ebx,%edx
  add    %eax,%ebp
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L14
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D2: thread %d suma a[%d] / 

tool: D21: 
* thread %d suma= %d

tool: D16: 
 suma = %d


assistant: ```c
main() {
  int i, n = 7;
  int a[n], suma;
  for (i = 0; i < n; i++)
    a[i] = i;
#pragma omp parallel private(suma)
  {
    suma = 0;
#pragma omp for
    for (i = 0; i < n; i++) {
      suma = suma + a[i];
      printf("thread %d suma a[%d] / ", 0, i);
    }
    printf("\n* thread %d suma= %d", 0, suma);
  }
  printf("\n suma = %d\n", suma);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  movl   $0x6,0x18(%rsp)
  mov    %rsp,%r13
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax)
L8:
  add    0x0(%r13,%rbx,4),%ebp
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L8
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%edx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D14
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D38
type_guessed: string

tool: D7: thread %d suma a[%d] / 

tool: {"D22": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D14": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D16: 
* thread %d suma= %d

tool: D38: 
 suma = %d


assistant: ```c
main() {
  int i, n = 7;
  int a[n], suma;
  for (i = 0; i < n; i++)
    a[i] = i;
#pragma omp parallel private(suma)
  {
    suma = 0;
#pragma omp for
    for (i = 0; i < n; i++) {
      suma = suma + a[i];
      printf("thread %d suma a[%d] / ", 0, i);
    }
    printf("\n* thread %d suma= %d", 0, suma);
  }
  printf("\n suma = %d\n", suma);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rangeBitwiseAnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L24:
  shll   -0xc(%rbp)
  sarl   -0x18(%rbp)
  sarl   -0x14(%rbp)
L25:
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  cmpl   $0x0,-0x18(%rbp)
  jne    L24
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L33
L49:
  mov    -0x8(%rbp),%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L33
  mov    -0xc(%rbp),%eax
  or     %eax,-0x10(%rbp)
L33:
  shrl   -0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  ja     L49
  mov    -0x10(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: %u


assistant: ```c
int rangeBitwiseAnd(int m, int n) {
  unsigned result = 0, mask = 1;
  int tmp = m & n, diff = n - m;
  for (; m || n; mask <<= 1, n >>= 1, m >>= 1)
    ;
  printf("%u\n", mask);
  while ((mask >>= 1) > diff) {
    if (mask & tmp)
      result |= mask;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rangeBitwiseAnd>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  and    %esi,%r12d
  mov    %esi,%ebp
  sub    %edi,%ebp
  mov    %edi,%eax
  or     %esi,%eax
  je     L30
  mov    $0x1,%eax
L12:
  mov    %eax,%ebx
  add    %eax,%eax
  sar    %esi
  sar    %edi
  mov    %esi,%edx
  or     %edi,%edx
  jne    L12
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  cmp    %ebp,%eax
  jbe    L34
  mov    $0x0,%edx
L1:
  mov    %edx,%ecx
  or     %eax,%ecx
  test   %eax,%r12d
  cmovne %ecx,%edx
  shr    %eax
  cmp    %ebp,%eax
  ja     L1
L15:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0x0,%edx
  jmp    L15
L30:
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  jmp    L15
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %u


assistant: ```c
int rangeBitwiseAnd(int m, int n) {
  unsigned result = 0, mask = 1;
  int tmp = m & n, diff = n - m;
  for (; m || n; mask <<= 1, n >>= 1, m >>= 1)
    ;
  printf("%u\n", mask);
  while ((mask >>= 1) > diff) {
    if (mask & tmp)
      result |= mask;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rangeBitwiseAnd>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edi,%r12d
  and    %esi,%r13d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    %edi,%ebp
  sub    $0x8,%rsp
  or     %esi,%r12d
  je     L11
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L17:
  sar    %esi
  sar    %edi
  mov    %r8d,%ebx
  add    %r8d,%r8d
  mov    %esi,%r12d
  or     %edi,%r12d
  jne    L17
  mov    %r8d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  cmp    %eax,%ebp
  jae    L8
  xor    %edx,%edx
  xchg   %ax,%ax
L5:
  mov    %edx,%ecx
  or     %eax,%ecx
  test   %eax,%r13d
  cmovne %ecx,%edx
  shr    %eax
  cmp    %ebp,%eax
  ja     L5
  mov    %edx,%r12d
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string

tool: D12: %u


assistant: ```c
int rangeBitwiseAnd(int m, int n) {
  unsigned result = 0, mask = 1;
  int tmp = m & n, diff = n - m;
  for (; m || n; mask <<= 1, n >>= 1, m >>= 1)
    ;
  printf("%u\n", mask);
  while ((mask >>= 1) > diff) {
    if (mask & tmp)
      result |= mask;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rangeBitwiseAnd>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edi,%r12d
  and    %esi,%r13d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    %edi,%ebp
  sub    $0x8,%rsp
  or     %esi,%r12d
  je     L2
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L28:
  sar    %esi
  sar    %edi
  mov    %r8d,%ebx
  add    %r8d,%r8d
  mov    %esi,%r12d
  or     %edi,%r12d
  jne    L28
  mov    %r8d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x7fffffff,%eax
  cmp    %eax,%ebp
  jae    L25
  xor    %edx,%edx
  xchg   %ax,%ax
L15:
  mov    %edx,%ecx
  or     %eax,%ecx
  test   %r13d,%eax
  cmovne %ecx,%edx
  shr    %eax
  cmp    %ebp,%eax
  ja     L15
  mov    %edx,%r12d
L25:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %u


assistant: ```c
int rangeBitwiseAnd(int m, int n) {
  unsigned result = 0, mask = 1;
  int tmp = m & n, diff = n - m;
  for (; m || n; mask <<= 1, n >>= 1, m >>= 1)
    ;
  printf("%u\n", mask);
  while ((mask >>= 1) > diff) {
    if (mask & tmp)
      result |= mask;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L1
L23:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L37:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L25:
  cmpl   $0x2,-0x14(%rbp)
  jle    L37
  addl   $0x1,-0x18(%rbp)
L1:
  cmpl   $0x6,-0x18(%rbp)
  jle    L23
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D29
datatype: string

tool: D8: smin

tool: D9: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D16(%rip),%r15
  jmp    L21
L18:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L24
L21:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L3:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L3
  jmp    L18
L24:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D4
type: string

tool: D16: smin

tool: D24: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D18(%rip),%r15
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L18:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L1:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L1
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L18
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D18: smin

tool: D12: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D13(%rip),%r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L5:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L9:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L9
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L5
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D29
type_guessed: string

tool: D13: smin

tool: D16: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smin", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flip_authors_names>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0xff,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0xff,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    D68(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L53
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L44
L22:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  lea    D63(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D63(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
L44:
  cmpq   $0x0,-0x18(%rbp)
  je     L52
  mov    -0x18(%rbp),%rax
  lea    D45(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
L52:
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x28(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L1:
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
L53:
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D68
type: string
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D63
type: string
name: unpack_data
arguments: label: D45
type: string
name: unpack_data
arguments: label: D33
type: string

tool: D68: ,

tool: D39: ., 

tool: D63: . 

tool: D45: and

tool: D33: , 

assistant: ```c
void flip_authors_names(char *flipped_names, const char *authors_names) {
  char *tmpstr = malloc(255 * sizeof(char));
  char *tmpLastname = malloc(255 * sizeof(char));
  strcpy(tmpstr, authors_names);
  flipped_names[0] = '\0';
  char *token = strtok(tmpstr, ",");
  while (token != NULL) {
    strcpy(tmpLastname, token);
    token = strtok(NULL, "., ");
    while (token != NULL && strcmp(token, "and") != 0) {
      strcat(flipped_names, token);
      strcat(flipped_names, ". ");
      token = strtok(NULL, ". ");
    }
    strcat(flipped_names, tmpLastname);
    if (token != NULL) {
      strcat(flipped_names, ", ");
    }
    token = strtok(NULL, ",");
  }
  free(tmpstr);
  free(tmpLastname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<flip_authors_names>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0xff,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  mov    $0xff,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  movb   $0x0,0x0(%rbp)
  lea    D50(%rip),%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L71
  mov    %rax,%rsi
  lea    D12(%rip),%r15
  lea    D57(%rip),%r13
  lea    D30(%rip),%r12
  jmp    L5
L49:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  test   %rbx,%rbx
  je     L69
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L69:
  lea    D50(%rip),%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L71
L5:
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r15,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L35
L41:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L49
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L41
L35:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L69
L71:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D50
type_infered: string
name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D57
type_infered: string
name: disassemble_data
arguments: tag: D30
type_infered: string
name: disassemble_data
arguments: tag: D47
type_infered: string

tool: D50: ,

tool: D12: ., 

tool: D57: and

tool: D30: . 

tool: D47: , 

assistant: ```c
void flip_authors_names(char *flipped_names, const char *authors_names) {
  char *tmpstr = malloc(255 * sizeof(char));
  char *tmpLastname = malloc(255 * sizeof(char));
  strcpy(tmpstr, authors_names);
  flipped_names[0] = '\0';
  char *token = strtok(tmpstr, ",");
  while (token != NULL) {
    strcpy(tmpLastname, token);
    token = strtok(NULL, "., ");
    while (token != NULL && strcmp(token, "and") != 0) {
      strcat(flipped_names, token);
      strcat(flipped_names, ". ");
      token = strtok(NULL, ". ");
    }
    strcat(flipped_names, tmpLastname);
    if (token != NULL) {
      strcat(flipped_names, ", ");
    }
    token = strtok(NULL, ",");
  }
  free(tmpstr);
  free(tmpLastname);
}
```