ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_mulhf_use_in1fft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %esi,%r15d
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r12
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    0x60(%rsp),%r14d
  mov    %r14d,%ebx
  sar    %ebx
  add    $0x1,%ebx
  cmp    %edi,%ebx
  jge    L33
  movslq %ebx,%rax
L29:
  mov    %eax,%ebx
  cmpw   $0x0,0x8(%r12,%rax,2)
  jne    L33
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L29
L33:
  mov    %ebp,%r13d
  shr    $0x1f,%r13d
  add    %ebp,%r13d
  sar    %r13d
  add    $0x1,%r13d
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  mov    0x68(%rsp),%r9
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    0x68(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%edi
  call   <mp_mul_cmul_nt_d1@plt>
  mov    0x10(%rsp),%r8
  mov    0x68(%rsp),%rcx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_d2i@plt>
  mov    0x68(%rsp),%r9
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    0x68(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%edi
  call   <mp_mul_cmul_nt_d1@plt>
  mov    0x18(%rsp),%rbx
  mov    %rbx,%r8
  mov    0x68(%rsp),%rcx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %r13d,%edi
  call   <mp_mul_d2i@plt>
  cmpl   $0x0,(%rbx)
  je     L34
  mov    %rbx,%r8
  mov    0x10(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_add@plt>
L37:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_copy@plt>
  jmp    L37
```

assistant: ```c
void mp_mulhf_use_in1fft(int n, int radix, double in1fft[], int in2[], int out[], int tmp[], int nfft, double tmpfft[]) {
  void mp_copy(int n, int radix, int in[], int out[]);
  void mp_add(int n, int radix, int in1[], int in2[], int out[]);
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul_nt_d1(int nfft, double d1[], double d2[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  int n_h, shift;
  short int *in2dgt;
  in2dgt = (short int *)&in2[2];
  shift = (nfft >> 1) + 1;
  while (n > shift) {
    if (in2dgt[shift] != 0) {
      break;
    }
    shift++;
  }
  n_h = n / 2 + 1;
  if (n_h < n - shift) {
    n_h = n - shift;
  }
  mp_mul_i2d(n, radix, nfft, 0, in2, tmpfft);
  mp_mul_cmul_nt_d1(nfft, in1fft, tmpfft);
  mp_mul_d2i(n, radix, nfft, tmpfft, tmp);
  mp_mul_i2d(n, radix, nfft, shift, in2, tmpfft);
  mp_mul_cmul_nt_d1(nfft, in1fft, tmpfft);
  mp_mul_d2i(n_h, radix, nfft, tmpfft, out);
  if (out[0] != 0) {
    mp_add(n, radix, out, tmp, out);
  } else {
    mp_copy(n, radix, tmp, out);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x8(%rbp),%eax
  jmp    L33
L8:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    $0xffffffff,%eax
L33:
  leave
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  uint16_t i, n;
  n = strlen(t);
  for (i = 0; *(s + i); i++) {
    if (strncmp(s + i, t, n) == 0)
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strindex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L6
  mov    %eax,%r13d
  mov    $0x0,%ebp
L32:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L28
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L32
  mov    $0xffffffff,%ebp
L28:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    $0xffffffff,%ebp
  jmp    L28
```

assistant: ```c
int strindex(char *s, char *t) {
  uint16_t i, n;
  n = strlen(t);
  for (i = 0; *(s + i); i++) {
    if (strncmp(s + i, t, n) == 0)
      return i;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L35
  mov    %eax,%r13d
  xor    %r12d,%r12d
  jmp    L2
  nopl   0x0(%rax)
L24:
  add    $0x1,%rbx
  add    $0x1,%r12d
  cmpb   $0x0,(%rbx)
  je     L35
L2:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L24
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L35:
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  uint16_t i, n;
  n = strlen(t);
  for (i = 0; *(s + i); i++) {
    if (strncmp(s + i, t, n) == 0)
      return i;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strindex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L2
  mov    %eax,%r13d
  xor    %r12d,%r12d
  jmp    L21
  nopl   0x0(%rax)
L6:
  add    $0x1,%rbx
  add    $0x1,%r12d
  cmpb   $0x0,(%rbx)
  je     L2
L21:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  uint16_t i, n;
  n = strlen(t);
  for (i = 0; *(s + i); i++) {
    if (strncmp(s + i, t, n) == 0)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strcpy_pwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x7,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L21
L3:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L21:
  leave
  ret
```

assistant: ```c
char *my_strcpy_pwd(char *src) {
  char *dest;
  int i;
  int j;
  j = 0;
  i = 7;
  dest = NULL;
  if ((dest = malloc(sizeof(char) * my_strlen(src) + 1)) == NULL)
    return (NULL);
  while (src[i] != '\0') {
    dest[j] = src[i];
    i++;
    j++;
  }
  dest[j] = '\0';
  return (dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strcpy_pwd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L20
  movzbl 0x7(%rbx),%ecx
  test   %cl,%cl
  je     L30
  mov    $0x1,%edx
L35:
  mov    %cl,-0x1(%rax,%rdx,1)
  mov    %edx,%esi
  add    $0x1,%rdx
  movzbl 0x6(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L35
L22:
  movslq %esi,%rsi
  movb   $0x0,(%rax,%rsi,1)
L20:
  pop    %rbx
  ret
L30:
  mov    $0x0,%esi
  jmp    L22
```

assistant: ```c
char *my_strcpy_pwd(char *src) {
  char *dest;
  int i;
  int j;
  j = 0;
  i = 7;
  dest = NULL;
  if ((dest = malloc(sizeof(char) * my_strlen(src) + 1)) == NULL)
    return (NULL);
  while (src[i] != '\0') {
    dest[j] = src[i];
    i++;
    j++;
  }
  dest[j] = '\0';
  return (dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strcpy_pwd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L32
  movzbl 0x7(%rbx),%ecx
  test   %cl,%cl
  je     L38
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%rsi
  add    $0x1,%rdx
  movzbl 0x6(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L31
  add    %rax,%rsi
L20:
  movb   $0x0,(%rsi)
L32:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L38:
  mov    %rax,%rsi
  jmp    L20
```

assistant: ```c
char *my_strcpy_pwd(char *src) {
  char *dest;
  int i;
  int j;
  j = 0;
  i = 7;
  dest = NULL;
  if ((dest = malloc(sizeof(char) * my_strlen(src) + 1)) == NULL)
    return (NULL);
  while (src[i] != '\0') {
    dest[j] = src[i];
    i++;
    j++;
  }
  dest[j] = '\0';
  return (dest);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcpy_pwd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L1
  movzbl 0x7(%rbx),%ecx
  test   %cl,%cl
  je     L8
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%rsi
  add    $0x1,%rdx
  movzbl 0x6(%rbx,%rdx,1),%ecx
  test   %cl,%cl
  jne    L3
  add    %rax,%rsi
L15:
  movb   $0x0,(%rsi)
L1:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  mov    %rax,%rsi
  jmp    L15
```

assistant: ```c
char *my_strcpy_pwd(char *src) {
  char *dest;
  int i;
  int j;
  j = 0;
  i = 7;
  dest = NULL;
  if ((dest = malloc(sizeof(char) * my_strlen(src) + 1)) == NULL)
    return (NULL);
  while (src[i] != '\0') {
    dest[j] = src[i];
    i++;
    j++;
  }
  dest[j] = '\0';
  return (dest);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L7
L21:
  mov    -0x18(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  jmp    L17
L11:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L21
  mov    -0x10(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
size_t split(char *s, char *x[], size_t len) {
  size_t n;
  for (n = 0; n < len; n++) {
    char *y;
    y = strchr(s, '\t');
    if (y == NULL) {
      x[n] = s;
      return n + 1;
    }
    *y = '\0';
    x[n] = s;
    s = y + 1;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L22
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x0,%ebx
L34:
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,(%rax)
  mov    %rbp,0x0(%r13,%rbx,8)
  lea    0x1(%rax),%rbp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L34
  jmp    L22
L5:
  mov    %rbp,0x0(%r13,%rbx,8)
  lea    0x1(%rbx),%r12
L22:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t split(char *s, char *x[], size_t len) {
  size_t n;
  for (n = 0; n < len; n++) {
    char *y;
    y = strchr(s, '\t');
    if (y == NULL) {
      x[n] = s;
      return n + 1;
    }
    *y = '\0';
    x[n] = s;
    s = y + 1;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L27
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r13d,%r13d
  jmp    L21
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rax)
  add    $0x8,%rbx
  mov    %rbp,-0x8(%rbx)
  lea    0x1(%rax),%rbp
  cmp    %r13,%r12
  je     L27
L21:
  mov    $0x9,%esi
  mov    %rbp,%rdi
  add    $0x1,%r13
  call   <strchr@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbp,(%rbx)
  mov    %r13,%r12
L27:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t split(char *s, char *x[], size_t len) {
  size_t n;
  for (n = 0; n < len; n++) {
    char *y;
    y = strchr(s, '\t');
    if (y == NULL) {
      x[n] = s;
      return n + 1;
    }
    *y = '\0';
    x[n] = s;
    s = y + 1;
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L34
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r13d,%r13d
  jmp    L9
  nopl   0x0(%rax)
L18:
  movb   $0x0,(%rax)
  add    $0x8,%rbx
  mov    %rbp,-0x8(%rbx)
  lea    0x1(%rax),%rbp
  cmp    %r13,%r12
  je     L34
L9:
  mov    $0x9,%esi
  mov    %rbp,%rdi
  add    $0x1,%r13
  call   <strchr@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbp,(%rbx)
  mov    %r13,%r12
L34:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t split(char *s, char *x[], size_t len) {
  size_t n;
  for (n = 0; n < len; n++) {
    char *y;
    y = strchr(s, '\t');
    if (y == NULL) {
      x[n] = s;
      return n + 1;
    }
    *y = '\0';
    x[n] = s;
    s = y + 1;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trim_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  nop
L4:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void trim_right(char *szString) {
  unsigned int i = strlen(szString);
  while (isspace(szString[--i]))
    ;
  szString[i + 1] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim_right>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
L3:
  mov    %ebx,%r12d
  sub    $0x1,%ebx
  mov    %ebx,%eax
  movsbl 0x0(%rbp,%rax,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  mov    %r12d,%r12d
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_right(char *szString) {
  unsigned int i = strlen(szString);
  while (isspace(szString[--i]))
    ;
  szString[i + 1] = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim_right>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rbx),%eax
  mov    %ebx,%r12d
  movsbl 0x0(%rbp,%rax,1),%edi
  mov    %rax,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_right(char *szString) {
  unsigned int i = strlen(szString);
  while (isspace(szString[--i]))
    ;
  szString[i + 1] = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim_right>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  lea    -0x1(%rbx),%eax
  mov    %ebx,%r12d
  movsbl 0x0(%rbp,%rax,1),%edi
  mov    %rax,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trim_right(char *szString) {
  unsigned int i = strlen(szString);
  while (isspace(szString[--i]))
    ;
  szString[i + 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<formaTriangulo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jg     L6
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    $0xffffffff,%ecx
  mov    %rax,%rdi
  call   <verificarAltura@plt>
  test   %rax,%rax
  je     L47
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <verificarAltura@plt>
  test   %rax,%rax
  je     L47
  mov    $0x1,%eax
  jmp    L22
L47:
  mov    $0x0,%eax
  jmp    L22
L6:
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int formaTriangulo(const int *COLUNAS, int indice, int tamanho) {
  if (COLUNAS[indice] >= tamanho) {
    return verificarAltura(COLUNAS, indice - 1, tamanho - 1, -1) && verificarAltura(COLUNAS, indice + 1, tamanho - 1, 1);
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<formaTriangulo>:
  endbr64
  movslq %esi,%rcx
  mov    $0x0,%eax
  cmp    %edx,(%rdi,%rcx,4)
  jge    L10
  ret
L10:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    -0x1(%rdx),%ebx
  lea    -0x1(%rsi),%esi
  mov    $0xffffffff,%ecx
  mov    %ebx,%edx
  call   <verificarAltura@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L3
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  lea    0x1(%rbp),%esi
  mov    $0x1,%ecx
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <verificarAltura@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L26
```

assistant: ```c
int formaTriangulo(const int *COLUNAS, int indice, int tamanho) {
  if (COLUNAS[indice] >= tamanho) {
    return verificarAltura(COLUNAS, indice - 1, tamanho - 1, -1) && verificarAltura(COLUNAS, indice + 1, tamanho - 1, 1);
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<formaTriangulo>:
  endbr64
  movslq %esi,%rax
  cmp    %edx,(%rdi,%rax,4)
  jge    L5
  xor    %eax,%eax
  ret
  nop
L5:
  push   %r12
  lea    -0x1(%rdx),%r12d
  lea    -0x1(%rax),%esi
  mov    $0xffffffff,%ecx
  push   %rbp
  mov    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rax,%rbx
  call   <verificarAltura@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0x1,%ecx
  call   <verificarAltura@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int formaTriangulo(const int *COLUNAS, int indice, int tamanho) {
  if (COLUNAS[indice] >= tamanho) {
    return verificarAltura(COLUNAS, indice - 1, tamanho - 1, -1) && verificarAltura(COLUNAS, indice + 1, tamanho - 1, 1);
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<formaTriangulo>:
  endbr64
  movslq %esi,%rax
  cmp    %edx,(%rdi,%rax,4)
  jge    L3
  xor    %eax,%eax
  ret
  nop
L3:
  push   %r12
  lea    -0x1(%rdx),%r12d
  lea    -0x1(%rax),%esi
  mov    $0xffffffff,%ecx
  push   %rbp
  mov    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rax,%rbx
  call   <verificarAltura@plt>
  test   %rax,%rax
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0x1,%ecx
  call   <verificarAltura@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int formaTriangulo(const int *COLUNAS, int indice, int tamanho) {
  if (COLUNAS[indice] >= tamanho) {
    return verificarAltura(COLUNAS, indice - 1, tamanho - 1, -1) && verificarAltura(COLUNAS, indice + 1, tamanho - 1, 1);
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <err_init@plt>
  mov    $0x2,%edi
  call   <err_set_flags@plt>
  mov    $0x0,%eax
  call   <_init_ipmidetect@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <_cmdline_parse@plt>
  mov    $0x0,%eax
  call   <_output_data@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <_cleanup_ipmidetect@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int exit_val;
  err_init(argv[0]);
  err_set_flags(0x0002);
  _init_ipmidetect();
  _cmdline_parse(argc, argv);
  exit_val = _output_data();
  _cleanup_ipmidetect();
  exit(exit_val);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    (%rsi),%rdi
  call   <err_init@plt>
  mov    $0x2,%edi
  call   <err_set_flags@plt>
  mov    $0x0,%eax
  call   <_init_ipmidetect@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <_cmdline_parse@plt>
  mov    $0x0,%eax
  call   <_output_data@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <_cleanup_ipmidetect@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int exit_val;
  err_init(argv[0]);
  err_set_flags(0x0002);
  _init_ipmidetect();
  _cmdline_parse(argc, argv);
  exit_val = _output_data();
  _cleanup_ipmidetect();
  exit(exit_val);
}
```