ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<append_pid_filter>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    D14(%rip),%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    (%rax,%rax,2),%eax
  lea    0x1(%rbx,%rax,1),%ebp
  test   %r13,%r13
  je     L8
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x0(%rbp,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L29
L10:
  mov    %r12,%r9
  mov    %r12,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %r13,%rdi
  lea    D39(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L8:
  mov    %ebp,%edi
  call   <malloc_or_die@plt>
  mov    %r12,%r8
  mov    %r12,%rcx
  mov    %r12,%rdx
  mov    %rax,%r13
  mov    %rax,%rdi
  lea    D31(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  lea    D12(%rip),%rdi
  call   <die@plt>
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string

tool: D14: .*:(common_pid==)||(pid==)||(next_pid==)

tool: D39: %s||(common_pid==%s)||(pid==%s)||(next_pid==%s)

tool: D31: .*:(common_pid==%s)||(pid==%s)||(next_pid==%s)

tool: D12: realloc

assistant: ```c
char *append_pid_filter(char *curr_filter, char *pid) {
  char *filter;
  int len;
  len = strlen(".*:"
               "(common_pid=="
               ""
               ")||(pid=="
               ""
               ")||(next_pid=="
               ""
               ")") +
        strlen(pid) * 3 + 1;
  if (!curr_filter) {
    filter = malloc_or_die(len);
    sprintf(filter,
            ".*:"
            "(common_pid=="
            "%s"
            ")||(pid=="
            "%s"
            ")||(next_pid=="
            "%s"
            ")",
            pid, pid, pid);
  } else {
    len += strlen(curr_filter);
    filter = realloc(curr_filter, len);
    if (!filter)
      die("realloc");
    sprintf(filter,
            "%s||"
            "(common_pid=="
            "%s"
            ")||(pid=="
            "%s"
            ")||(next_pid=="
            "%s"
            ")",
            filter, pid, pid, pid);
  }
  return filter;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L3:
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x18(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x9,-0xc(%rbp)
  jle    L3
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: f64

tool: D0: 2

assistant: ```c
double sqrt(double x) {
  double z = x / 2.;
  for (int i = 0; i < 10; i++) {
    z -= (z * z - x) / (2. * z);
  }
  return z;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sqrt>:
  endbr64
  movapd %xmm0,%xmm3
  mulsd  D1(%rip),%xmm0
  mov    $0xa,%eax
L9:
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L9
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sqrt(double x) {
  double z = x / 2.;
  for (int i = 0; i < 10; i++) {
    z -= (z * z - x) / (2. * z);
  }
  return z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqrt>:
  endbr64
  movapd %xmm0,%xmm3
  movsd  D5(%rip),%xmm0
  mov    $0xa,%eax
  mulsd  %xmm3,%xmm0
  nopl   0x0(%rax)
L9:
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm2
  subsd  %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  sub    $0x1,%eax
  jne    L9
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sqrt(double x) {
  double z = x / 2.;
  for (int i = 0; i < 10; i++) {
    z -= (z * z - x) / (2. * z);
  }
  return z;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqrt>:
  endbr64
  movapd %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  divsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sqrt(double x) {
  double z = x / 2.;
  for (int i = 0; i < 10; i++) {
    z -= (z * z - x) / (2. * z);
  }
  return z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<luaI_growvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L21
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lua_error@plt>
L21:
  cmpq   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  jmp    L22
L38:
  mov    $0x14,%eax
L22:
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L33
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <luaI_realloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int luaI_growvector(void **block, unsigned long nelems, int size, char *errormsg, unsigned long limit) {
  if (nelems >= limit)
    lua_error(errormsg);
  nelems = (nelems == 0) ? 20 : nelems * 2;
  if (nelems > limit)
    nelems = limit;
  *block = luaI_realloc(*block, nelems * size);
  return (int)nelems;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<luaI_growvector>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %edx,%ebp
  mov    %r8,%r13
  cmp    %r8,%rsi
  jae    L18
L10:
  lea    (%r14,%r14,1),%rbx
  test   %r14,%r14
  mov    $0x14,%eax
  cmove  %rax,%rbx
  cmp    %r13,%rbx
  cmova  %r13,%rbx
  movslq %ebp,%rsi
  imul   %rbx,%rsi
  mov    (%r12),%rdi
  call   <luaI_realloc@plt>
  mov    %rax,(%r12)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    %rcx,%rdi
  call   <lua_error@plt>
  jmp    L10
```

assistant: ```c
int luaI_growvector(void **block, unsigned long nelems, int size, char *errormsg, unsigned long limit) {
  if (nelems >= limit)
    lua_error(errormsg);
  nelems = (nelems == 0) ? 20 : nelems * 2;
  if (nelems > limit)
    nelems = limit;
  *block = luaI_realloc(*block, nelems * size);
  return (int)nelems;
}
```
user: What is the c source code of the assembly code below:

```asm
<luaI_growvector>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  cmp    %r8,%rsi
  jae    L16
L9:
  test   %r14,%r14
  lea    (%r14,%r14,1),%rbx
  mov    $0x14,%eax
  movslq %ebp,%rsi
  cmove  %rax,%rbx
  mov    0x0(%r13),%rdi
  cmp    %r12,%rbx
  cmova  %r12,%rbx
  imul   %rbx,%rsi
  call   <luaI_realloc@plt>
  mov    %rax,0x0(%r13)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rcx,%rdi
  call   <lua_error@plt>
  jmp    L9
```

assistant: ```c
int luaI_growvector(void **block, unsigned long nelems, int size, char *errormsg, unsigned long limit) {
  if (nelems >= limit)
    lua_error(errormsg);
  nelems = (nelems == 0) ? 20 : nelems * 2;
  if (nelems > limit)
    nelems = limit;
  *block = luaI_realloc(*block, nelems * size);
  return (int)nelems;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<luaI_growvector>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  cmp    %r8,%rsi
  jae    L5
L0:
  test   %r14,%r14
  lea    (%r14,%r14,1),%rbx
  mov    $0x14,%eax
  movslq %ebp,%rsi
  cmove  %rax,%rbx
  mov    0x0(%r13),%rdi
  cmp    %r12,%rbx
  cmova  %r12,%rbx
  imul   %rbx,%rsi
  call   <luaI_realloc@plt>
  mov    %rax,0x0(%r13)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rcx,%rdi
  call   <lua_error@plt>
  jmp    L0
```

assistant: ```c
int luaI_growvector(void **block, unsigned long nelems, int size, char *errormsg, unsigned long limit) {
  if (nelems >= limit)
    lua_error(errormsg);
  nelems = (nelems == 0) ? 20 : nelems * 2;
  if (nelems > limit)
    nelems = limit;
  *block = luaI_realloc(*block, nelems * size);
  return (int)nelems;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ch_signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x3,%eax
  ja     L3
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L8
L3:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L8:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: signal %d is sent to process %d


assistant: ```c
void ch_signal_handler(int signum) {
  switch (signum) {
  case SIGTERM:
  case SIGINT:
  case SIGQUIT:
  case SIGHUP:
    exit(-1);
    break;
  default:
    printf("signal %d is sent to process %d\n", signum, getpid());
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ch_signal_handler>:
  endbr64
  push   %rbx
  lea    -0x80(%rdi),%eax
  cmp    $0x3,%eax
  ja     L1
  mov    $0xffffffff,%edi
  call   <exit@plt>
L8:
  pop    %rbx
  ret
L1:
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: signal %d is sent to process %d


assistant: ```c
void ch_signal_handler(int signum) {
  switch (signum) {
  case SIGTERM:
  case SIGINT:
  case SIGQUIT:
  case SIGHUP:
    exit(-1);
    break;
  default:
    printf("signal %d is sent to process %d\n", signum, getpid());
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ch_signal_handler>:
  endbr64
  lea    -0x80(%rdi),%eax
  cmp    $0x3,%eax
  ja     L8
  mov    $0xffffffff,%edi
  jmp    1090 <exit@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <getpid@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: signal %d is sent to process %d


assistant: ```c
void ch_signal_handler(int signum) {
  switch (signum) {
  case SIGTERM:
  case SIGINT:
  case SIGQUIT:
  case SIGHUP:
    exit(-1);
    break;
  default:
    printf("signal %d is sent to process %d\n", signum, getpid());
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ch_signal_handler>:
  endbr64
  lea    -0x80(%rdi),%eax
  cmp    $0x3,%eax
  ja     L1
  mov    $0xffffffff,%edi
  jmp    1090 <exit@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <getpid@plt>
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: signal %d is sent to process %d


assistant: ```c
void ch_signal_handler(int signum) {
  switch (signum) {
  case SIGTERM:
  case SIGINT:
  case SIGQUIT:
  case SIGHUP:
    exit(-1);
    break;
  default:
    printf("signal %d is sent to process %d\n", signum, getpid());
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fir_stereo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rcx,%rbx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rdx,%rax,1),%r11d
  and    $0x7,%r11d
  sub    %eax,%r11d
  lea    0x7(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  and    $0xfffffff8,%eax
  cltq
  lea    (%rsi,%rax,4),%rdi
  cmp    %rdi,%rsi
  je     L20
  mov    %rsi,%r10
  mov    %rsi,%rdx
  mov    %r9,%rax
  mov    $0x0,%ecx
  mov    $0x0,%ebp
L22:
  mov    (%rdx),%esi
  mov    %esi,%r12d
  imul   (%rax),%r12d
  add    %ebp,%r12d
  imul   0x4(%rax),%esi
  add    %ecx,%esi
  mov    0x4(%rdx),%ecx
  mov    %ecx,%ebp
  imul   0x8(%rax),%ebp
  add    %r12d,%ebp
  imul   0xc(%rax),%ecx
  add    %ecx,%esi
  mov    0x8(%rdx),%ecx
  mov    %ecx,%r12d
  imul   0x10(%rax),%r12d
  add    %ebp,%r12d
  imul   0x14(%rax),%ecx
  add    %ecx,%esi
  mov    0xc(%rdx),%ecx
  mov    %ecx,%ebp
  imul   0x18(%rax),%ebp
  add    %r12d,%ebp
  imul   0x1c(%rax),%ecx
  add    %ecx,%esi
  mov    0x10(%rdx),%ecx
  mov    %ecx,%r12d
  imul   0x20(%rax),%r12d
  add    %ebp,%r12d
  imul   0x24(%rax),%ecx
  add    %ecx,%esi
  mov    0x14(%rdx),%ecx
  mov    %ecx,%ebp
  imul   0x28(%rax),%ebp
  add    %r12d,%ebp
  imul   0x2c(%rax),%ecx
  add    %ecx,%esi
  mov    0x18(%rdx),%ecx
  mov    %ecx,%r12d
  imul   0x30(%rax),%r12d
  add    %ebp,%r12d
  imul   0x34(%rax),%ecx
  add    %ecx,%esi
  mov    0x1c(%rdx),%ecx
  mov    %ecx,%ebp
  imul   0x38(%rax),%ebp
  add    %r12d,%ebp
  add    $0x40,%rax
  lea    0x20(%rdx),%r12
  mov    %r12,%rdx
  imul   -0x4(%rax),%ecx
  add    %esi,%ecx
  cmp    %r12,%rdi
  jne    L22
  sub    %r10,%r12
  lea    -0x20(%r12),%rax
  shr    $0x5,%rax
  add    $0x1,%rax
  shl    $0x6,%rax
  add    %rax,%r9
L37:
  movslq %r11d,%r11
  lea    (%rdi,%r11,4),%rsi
  cmp    %rsi,%rdi
  je     L33
L43:
  mov    (%rdi),%eax
  mov    %eax,%edx
  imul   (%r9),%edx
  add    %edx,%ebp
  add    $0x8,%r9
  add    $0x4,%rdi
  imul   -0x4(%r9),%eax
  add    %eax,%ecx
  cmp    %rdi,%rsi
  jne    L43
L33:
  mov    %ebp,(%rbx)
  mov    %ecx,(%r8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x0,%ecx
  mov    $0x0,%ebp
  jmp    L37
```

assistant: ```c
void fir_stereo(int *inp, int *coep, int firlen, int *out1p, int *out2p) {
  register int akku1 = 0, akku2 = 0, *endp;
  int n1 = (firlen / 8) * 8, n0 = firlen % 8;
  endp = coep + n1;
  while (coep != endp) {
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
  }
  endp = coep + n0;
  while (coep != endp) {
    akku1 += *inp++ * *coep;
    akku2 += *inp++ * *coep++;
  }
  *out1p = akku1;
  *out2p = akku2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ldq_le_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ldl_le_p@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,%rdi
  call   <ldl_le_p@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t ldq_le_p(const void *ptr) {
  const uint8_t *p = ptr;
  uint32_t v1, v2;
  v1 = ldl_le_p(p);
  v2 = ldl_le_p(p + 4);
  return v1 | ((uint64_t)v2 << 32);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ldq_le_p>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <ldl_le_p@plt>
  mov    %eax,%ebp
  lea    0x10(%rbx),%rdi
  call   <ldl_le_p@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ldq_le_p(const void *ptr) {
  const uint8_t *p = ptr;
  uint32_t v1, v2;
  v1 = ldl_le_p(p);
  v2 = ldl_le_p(p + 4);
  return v1 | ((uint64_t)v2 << 32);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ldq_le_p>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ldl_le_p@plt>
  lea    0x10(%rbx),%rdi
  mov    %eax,%r12d
  call   <ldl_le_p@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
uint64_t ldq_le_p(const void *ptr) {
  const uint8_t *p = ptr;
  uint32_t v1, v2;
  v1 = ldl_le_p(p);
  v2 = ldl_le_p(p + 4);
  return v1 | ((uint64_t)v2 << 32);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ldq_le_p>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <ldl_le_p@plt>
  lea    0x10(%rbx),%rdi
  mov    %eax,%r12d
  call   <ldl_le_p@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
uint64_t ldq_le_p(const void *ptr) {
  const uint8_t *p = ptr;
  uint32_t v1, v2;
  v1 = ldl_le_p(p);
  v2 = ldl_le_p(p + 4);
  return v1 | ((uint64_t)v2 << 32);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L87
L124:
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x10(%rbp)
  cmpq   $0x4,-0x10(%rbp)
  je     L16
  cmpq   $0x7,-0x10(%rbp)
  jne    L125
L16:
  addq   $0x1,-0x30(%rbp)
L125:
  mov    -0x38(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x38(%rbp)
L87:
  cmpq   $0x0,-0x38(%rbp)
  jg     L124
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L102
L65:
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x4,-0x18(%rbp)
  je     L63
  cmpq   $0x7,-0x18(%rbp)
  je     L63
  movq   $0x1,-0x20(%rbp)
  jmp    L19
L63:
  mov    -0x28(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
L102:
  cmpq   $0x0,-0x28(%rbp)
  jg     L65
L19:
  cmpq   $0x0,-0x20(%rbp)
  jne    L54
  cmpq   $0x0,-0x30(%rbp)
  je     L54
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L97
L54:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L97:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D26
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D1: %lld

tool: D26: YES


tool: D16: NO


assistant: ```c
int main() {
  long long int a;
  scanf("%lld", &a);
  long long int b = a;
  long long int c = 0;
  long long int temp;
  while (b > 0) {
    temp = b % 10;
    if ((temp == 4) || (temp == 7))
      c++;
    b = b / 10;
  }
  long long int d = c;
  long long t;
  long long int x = 0;
  while (d > 0) {
    t = d % 10;
    if ((t != 4) && (t != 7)) {
      x = 1;
      break;
    }
    d = d / 10;
  }
  if (x == 0 && c != 0)
    printf("YES\n");
  else
    printf("NO\n");
  return (0);
}
```