ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  cltq
  mov    %rax,%rcx
  mov    $0x0,%ebx
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L18:
  mov    -0x30(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: %d: %d


assistant: ```c
int foo(n, a)
int n;
int a[][n];
{
  int i;
  for (i = 0; i < n; ++i)
    printf("%d: %d\n", i, a[0][i]);
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  test   %edi,%edi
  jle    L10
  mov    %rsi,%rbp
  mov    %edi,%r14d
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L2:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L2
L10:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: %d: %d


assistant: ```c
int foo(n, a)
int n;
int a[][n];
{
  int i;
  for (i = 0; i < n; ++i)
    printf("%d: %d\n", i, a[0][i]);
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L17
  mov    %rsi,%r14
  movslq %edi,%r12
  lea    D4(%rip),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%r14,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
L17:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: %d: %d


assistant: ```c
int foo(n, a)
int n;
int a[][n];
{
  int i;
  for (i = 0; i < n; ++i)
    printf("%d: %d\n", i, a[0][i]);
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<foo>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L14
  mov    %rsi,%r14
  movslq %edi,%r12
  lea    D2(%rip),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%r14,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
L14:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: %d: %d


assistant: ```c
int foo(n, a)
int n;
int a[][n];
{
  int i;
  for (i = 0; i < n; ++i)
    printf("%d: %d\n", i, a[0][i]);
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L27:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x5d0,%eax
  jne    L13
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L8
L13:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x4,-0xc(%rbp)
  jle    L27
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D35
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D35: %d

tool: D1: accepted


tool: D13: incorrect password


tool: D17: denied


assistant: ```c
int main() {
  int password;
  for (int i = 0; i < 5; i++) {
    scanf("%d", &password);
    if (password == 1488) {
      printf("accepted\n");
      return 0;
    } else {
      printf("incorrect password\n");
    }
  }
  printf("denied\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x5,%ebx
  lea    0x4(%rsp),%r12
  lea    D0(%rip),%rbp
  lea    D26(%rip),%r13
L3:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x5d0,0x4(%rsp)
  je     L11
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  lea    D2(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D26
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D0: %d

tool: D26: incorrect password


tool: D2: denied


tool: D3: accepted


assistant: ```c
int main() {
  int password;
  for (int i = 0; i < 5; i++) {
    scanf("%d", &password);
    if (password == 1488) {
      printf("accepted\n");
      return 0;
    } else {
      printf("incorrect password\n");
    }
  }
  printf("denied\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x5d0,0x4(%rsp)
  je     L10
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L18
  lea    D25(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
type_infered: string
name: read_data
arguments: tag: D22
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string

tool: D28: incorrect password


tool: D22: %d

tool: D25: denied


tool: D15: accepted


assistant: ```c
int main() {
  int password;
  for (int i = 0; i < 5; i++) {
    scanf("%d", &password);
    if (password == 1488) {
      printf("accepted\n");
      return 0;
    } else {
      printf("incorrect password\n");
    }
  }
  printf("denied\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x5d0,0x4(%rsp)
  je     L13
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L33
  lea    D23(%rip),%rdi
  call   <printf@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string

tool: D13: incorrect password


tool: D12: %d

tool: D23: denied


tool: D24: accepted


assistant: ```c
int main() {
  int password;
  for (int i = 0; i < 5; i++) {
    scanf("%d", &password);
    if (password == 1488) {
      printf("accepted\n");
      return 0;
    } else {
      printf("incorrect password\n");
    }
  }
  printf("denied\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_oid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movslq %edx,%r15
  add    %rdi,%r15
  lea    0xc(%rsp),%rsi
  call   <read_byte@plt>
  mov    %rax,%rbx
  mov    0xc(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x24,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,0x10(%rsp)
  lea    (%rax,%rax,4),%eax
  shl    $0x3,%eax
  sub    %eax,%edx
  mov    %edx,0x14(%rsp)
  cmp    %rbx,%r15
  jbe    L14
  lea    0x18(%rsp),%r12
  mov    $0x2,%ebp
L7:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <read_oid_part@plt>
  mov    %rax,%rbx
  mov    %ebp,%r13d
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    %rax,%r15
  ja     L7
  test   %ebp,%ebp
  jle    L15
L73:
  mov    $0x0,%r12d
  lea    D4(%rip),%r15
L66:
  mov    0x10(%rsp,%r12,4),%ecx
  mov    %r15,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <snprintf@plt>
  add    %eax,%r13d
  add    $0x1,%r12
  cmp    %r12d,%ebp
  jg     L66
L15:
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,(%r14)
  mov    0x10(%rsp),%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,%r13
  cmp    $0x1,%ebp
  jle    L44
  lea    0x14(%rsp),%r12
  lea    -0x2(%rbp),%eax
  lea    0x18(%rsp,%rax,4),%r14
  lea    D27(%rip),%rbp
L46:
  mov    (%r12),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,%r13
  add    $0x4,%r12
  cmp    %r14,%r12
  jne    L46
L44:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %rbx,%rax
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    $0x2,%ebp
  mov    $0x1,%r13d
  jmp    L73
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string

tool: D4: %d

tool: D27: .%d

assistant: ```c
void *read_oid(void *src, char **oid, int size) {
  int parts[256 + 1];
  int first_byte;
  int i;
  void *endp = (unsigned char *)src + size;
  int num_parts;
  int len;
  char *p;
  src = read_byte(src, &first_byte);
  parts[0] = first_byte / 40;
  parts[1] = first_byte % 40;
  i = 2;
  while (src < endp) {
    src = read_oid_part(src, &parts[i]);
    i++;
  }
  num_parts = i;
  len = num_parts - 1;
  for (i = 0; i < num_parts; i++) {
    len += snprintf(NULL, 0, "%d", parts[i]);
  }
  *oid = (char *)malloc(len + 1);
  p = *oid;
  p += sprintf(p, "%d", parts[0]);
  for (i = 1; i < num_parts; i++) {
    p += sprintf(p, ".%d", parts[i]);
  }
  return src;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_oid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edx,%rbx
  add    %rdi,%rbx
  sub    $0x448,%rsp
  mov    %rsi,0x10(%rsp)
  lea    0x2c(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x438(%rsp)
  xor    %eax,%eax
  call   <read_byte@plt>
  movslq 0x2c(%rsp),%rcx
  mov    %rax,%rbp
  mov    %rcx,%rax
  imul   $0x66666667,%rcx,%rcx
  cltd
  sar    $0x24,%rcx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  mov    %ecx,0x30(%rsp)
  shl    $0x3,%edx
  sub    %edx,%eax
  mov    %eax,0x34(%rsp)
  cmp    %rbp,%rbx
  jbe    L41
  lea    0x38(%rsp),%r13
  mov    $0x2,%r12d
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r12d,%r15d
  add    $0x4,%r13
  call   <read_oid_part@plt>
  add    $0x1,%r12d
  mov    %rax,%rbp
  cmp    %rax,%rbx
  ja     L14
  mov    0x30(%rsp),%ecx
L57:
  lea    0x30(%rsp),%rax
  lea    0x34(%rsp),%rbx
  mov    %rax,0x18(%rsp)
  lea    -0x1(%r12),%eax
  mov    %rbx,%r14
  lea    D10(%rip),%r13
  lea    (%rbx,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L53:
  mov    (%r14),%ecx
  add    $0x4,%r14
L0:
  mov    %r13,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <snprintf@plt>
  add    %eax,%r15d
  cmp    0x8(%rsp),%r14
  jne    L53
  lea    0x1(%r15),%edi
  call   <malloc@plt>
  mov    0x30(%rsp),%edx
  mov    %r13,%rsi
  mov    %rax,%r14
  mov    0x10(%rsp),%rax
  mov    %r14,%rdi
  mov    %r14,(%rax)
  call   <sprintf@plt>
  mov    0x18(%rsp),%rdx
  cltq
  add    %rax,%r14
  lea    -0x2(%r12),%eax
  lea    D0(%rip),%r12
  lea    0x8(%rdx,%rax,4),%r13
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edx
  mov    %r14,%rdi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <sprintf@plt>
  cltq
  add    %rax,%r14
  cmp    %r13,%rbx
  jne    L8
  mov    0x438(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x448,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%r15d
  mov    $0x2,%r12d
  jmp    L57
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string

tool: D10: %d

tool: D0: .%d

assistant: ```c
void *read_oid(void *src, char **oid, int size) {
  int parts[256 + 1];
  int first_byte;
  int i;
  void *endp = (unsigned char *)src + size;
  int num_parts;
  int len;
  char *p;
  src = read_byte(src, &first_byte);
  parts[0] = first_byte / 40;
  parts[1] = first_byte % 40;
  i = 2;
  while (src < endp) {
    src = read_oid_part(src, &parts[i]);
    i++;
  }
  num_parts = i;
  len = num_parts - 1;
  for (i = 0; i < num_parts; i++) {
    len += snprintf(NULL, 0, "%d", parts[i]);
  }
  *oid = (char *)malloc(len + 1);
  p = *oid;
  p += sprintf(p, "%d", parts[0]);
  for (i = 1; i < num_parts; i++) {
    p += sprintf(p, ".%d", parts[i]);
  }
  return src;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_oid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  add    %rdi,%r13
  push   %rbp
  push   %rbx
  sub    $0x448,%rsp
  mov    %rsi,0x10(%rsp)
  lea    0x2c(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x438(%rsp)
  xor    %eax,%eax
  call   <read_byte@plt>
  mov    %rax,%rbp
  movslq 0x2c(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  movd   %eax,%xmm0
  shl    $0x3,%ecx
  sub    %ecx,%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x30(%rsp)
  cmp    %rbp,%r13
  jbe    L9
  lea    0x38(%rsp),%rbx
  mov    $0x2,%r12d
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r12d,%r14d
  add    $0x4,%rbx
  call   <read_oid_part@plt>
  add    $0x1,%r12d
  mov    %rax,%rbp
  cmp    %rax,%r13
  ja     L58
L15:
  lea    0x34(%rsp),%rcx
  lea    0x30(%rsp),%rbx
  mov    %rbx,0x8(%rsp)
  lea    -0x1(%r12),%eax
  lea    D14(%rip),%r15
  mov    %rcx,0x18(%rsp)
  lea    (%rcx,%rax,4),%r13
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%ecx
  mov    %r15,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x4,%rbx
  call   <snprintf@plt>
  add    %eax,%r14d
  cmp    %r13,%rbx
  jne    L16
  lea    0x1(%r14),%edi
  call   <malloc@plt>
  mov    0x30(%rsp),%edx
  mov    %r15,%rsi
  mov    %rax,%r13
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  mov    %r13,(%rax)
  call   <sprintf@plt>
  mov    0x8(%rsp),%rcx
  mov    0x18(%rsp),%rbx
  cltq
  lea    0x0(%r13,%rax,1),%r15
  lea    -0x2(%r12),%eax
  lea    0x8(%rcx,%rax,4),%r13
  lea    D12(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edx
  mov    %r15,%rdi
  mov    %r12,%rsi
  add    $0x4,%rbx
  call   <sprintf@plt>
  cltq
  add    %rax,%r15
  cmp    %rbx,%r13
  jne    L8
  mov    0x438(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x448,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%r14d
  mov    $0x2,%r12d
  jmp    L15
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: string

tool: D14: %d

tool: D12: .%d

assistant: ```c
void *read_oid(void *src, char **oid, int size) {
  int parts[256 + 1];
  int first_byte;
  int i;
  void *endp = (unsigned char *)src + size;
  int num_parts;
  int len;
  char *p;
  src = read_byte(src, &first_byte);
  parts[0] = first_byte / 40;
  parts[1] = first_byte % 40;
  i = 2;
  while (src < endp) {
    src = read_oid_part(src, &parts[i]);
    i++;
  }
  num_parts = i;
  len = num_parts - 1;
  for (i = 0; i < num_parts; i++) {
    len += snprintf(NULL, 0, "%d", parts[i]);
  }
  *oid = (char *)malloc(len + 1);
  p = *oid;
  p += sprintf(p, "%d", parts[0]);
  for (i = 1; i < num_parts; i++) {
    p += sprintf(p, ".%d", parts[i]);
  }
  return src;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<iki_boyutlu_dizi_yazdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L2:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0x5,-0x4(%rbp)
  jle    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x5,-0x8(%rbp)
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string

tool: D20: 	1	2	3	4	5	6


tool: D4: %d	

tool: D29: %-4d	

assistant: ```c
void iki_boyutlu_dizi_yazdir(int yazilcak_dizi[][6]) {
  int satir, sutun;
  printf("\t1\t2\t3\t4\t5\t6\n\n");
  for (satir = 0; satir <= 6 - 1; satir++) {
    printf("%d\t", satir + 1);
    for (sutun = 0; sutun <= 6 - 1; sutun++) {
      printf("%-4d\t", yazilcak_dizi[satir][sutun]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<iki_boyutlu_dizi_yazdir>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rbp
  mov    $0x0,%r13d
  lea    D29(%rip),%r14
  lea    D12(%rip),%r12
L13:
  add    $0x1,%r13d
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rbx
L7:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rbp
  cmp    $0x6,%r13d
  jne    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D0: 	1	2	3	4	5	6


tool: D29: %d	

tool: D12: %-4d	

assistant: ```c
void iki_boyutlu_dizi_yazdir(int yazilcak_dizi[][6]) {
  int satir, sutun;
  printf("\t1\t2\t3\t4\t5\t6\n\n");
  for (satir = 0; satir <= 6 - 1; satir++) {
    printf("%d\t", satir + 1);
    for (sutun = 0; sutun <= 6 - 1; sutun++) {
      printf("%-4d\t", yazilcak_dizi[satir][sutun]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<iki_boyutlu_dizi_yazdir>:
  endbr64
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D27(%rip),%rdi
  push   %rbx
  add    $0x18,%rbp
  call   <puts@plt>
L7:
  add    $0x1,%r13d
  mov    %r14,%rdi
  lea    -0x18(%rbp),%rbx
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <printf@plt>
  nopl   (%rax)
L6:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L6
  mov    $0xa,%edi
  lea    0x18(%rbx),%rbp
  call   <putchar@plt>
  cmp    $0x6,%r13d
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
datatype: string
name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D27
datatype: string

tool: D20: %d	

tool: D16: %-4d	

tool: D27: 	1	2	3	4	5	6


assistant: ```c
void iki_boyutlu_dizi_yazdir(int yazilcak_dizi[][6]) {
  int satir, sutun;
  printf("\t1\t2\t3\t4\t5\t6\n\n");
  for (satir = 0; satir <= 6 - 1; satir++) {
    printf("%d\t", satir + 1);
    for (sutun = 0; sutun <= 6 - 1; sutun++) {
      printf("%-4d\t", yazilcak_dizi[satir][sutun]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<iki_boyutlu_dizi_yazdir>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D23(%rip),%rdi
  push   %rbx
  add    $0x18,%rbp
  call   <puts@plt>
L8:
  add    $0x1,%r13d
  mov    %r14,%rdi
  lea    -0x18(%rbp),%rbx
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <printf@plt>
  nopl   (%rax)
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L0
  mov    $0xa,%edi
  lea    0x18(%rbx),%rbp
  call   <putchar@plt>
  cmp    $0x6,%r13d
  jne    L8
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D23
datatype: string

tool: D9: %d	

tool: D15: %-4d	

tool: D23: 	1	2	3	4	5	6


assistant: ```c
void iki_boyutlu_dizi_yazdir(int yazilcak_dizi[][6]) {
  int satir, sutun;
  printf("\t1\t2\t3\t4\t5\t6\n\n");
  for (satir = 0; satir <= 6 - 1; satir++) {
    printf("%d\t", satir + 1);
    for (sutun = 0; sutun <= 6 - 1; sutun++) {
      printf("%-4d\t", yazilcak_dizi[satir][sutun]);
    }
    printf("\n");
  }
  printf("\n");
}
```