ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<Tui_Getch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  movdqa (%rsp),%xmm0
  movaps %xmm0,0x10(%rsp)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    D32(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x10(%rsp)
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    0x18(%rsp),%rax
  movl   $0x0,(%rax,%rdx,4)
  mov    D41(%rip),%rax
  mov    (%rax),%rdx
  mov    0x18(%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  lea    0x10(%rsp),%rdx
  mov    D13(%rip),%r12
  mov    (%r12),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdx
  mov    (%r12),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Tui_Getch(void) {
  struct termios old;
  struct termios new;
  int ch;
  tcgetattr(0, &old);
  new = old;
  new.c_lflag &= ~(ICANON | ECHO);
  new.c_cc[VTIME] = 0;
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  ch = getchar();
  tcsetattr(0, TCSANOW, &old);
  return (ch);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Tui_Getch>:
  endbr64
  push   %r13
  xor    %edi,%edi
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    D19(%rip),%rdx
  xor    %edi,%edi
  mov    D23(%rip),%rax
  movdqa (%rsp),%xmm0
  mov    D13(%rip),%rbx
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D39(%rip),%rdx
  movaps %xmm0,0x10(%rsp)
  not    %eax
  and    %eax,0x10(%rsp)
  mov    0x18(%rsp),%rax
  mov    (%rdx),%rdx
  movl   $0x0,(%rax,%rdx,4)
  mov    D46(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x1,(%rax,%rdx,4)
  mov    (%rbx),%esi
  lea    0x10(%rsp),%rdx
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    (%rbx),%esi
  xor    %edi,%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Tui_Getch(void) {
  struct termios old;
  struct termios new;
  int ch;
  tcgetattr(0, &old);
  new = old;
  new.c_lflag &= ~(ICANON | ECHO);
  new.c_cc[VTIME] = 0;
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  ch = getchar();
  tcsetattr(0, TCSANOW, &old);
  return (ch);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Tui_Getch>:
  endbr64
  push   %r13
  xor    %edi,%edi
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    D5(%rip),%rdx
  xor    %edi,%edi
  mov    D33(%rip),%rax
  movdqa (%rsp),%xmm0
  mov    D8(%rip),%rbx
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D42(%rip),%rdx
  movaps %xmm0,0x10(%rsp)
  not    %eax
  and    %eax,0x10(%rsp)
  mov    0x18(%rsp),%rax
  mov    (%rdx),%rdx
  movl   $0x0,(%rax,%rdx,4)
  mov    D28(%rip),%rdx
  mov    (%rdx),%rdx
  movl   $0x1,(%rax,%rdx,4)
  mov    (%rbx),%esi
  lea    0x10(%rsp),%rdx
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    (%rbx),%esi
  xor    %edi,%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Tui_Getch(void) {
  struct termios old;
  struct termios new;
  int ch;
  tcgetattr(0, &old);
  new = old;
  new.c_lflag &= ~(ICANON | ECHO);
  new.c_cc[VTIME] = 0;
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  ch = getchar();
  tcsetattr(0, TCSANOW, &old);
  return (ch);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<time_stamp_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x19,%edi
  call   <MALLOC@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  lea    D6(%rip),%rdx
  mov    $0x15,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d-%b-%Y_%H-%M-%S

assistant: ```c
char *time_stamp_dir(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 21, "%d-%b-%Y_%H-%M-%S", localtime(&t));
  return t_stamp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<time_stamp_dir>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x19,%edi
  call   <MALLOC@plt>
  mov    %rax,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  lea    D3(%rip),%rdx
  mov    $0x15,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: %d-%b-%Y_%H-%M-%S

assistant: ```c
char *time_stamp_dir(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 21, "%d-%b-%Y_%H-%M-%S", localtime(&t));
  return t_stamp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<time_stamp_dir>:
  endbr64
  push   %r12
  mov    $0x19,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MALLOC@plt>
  xor    %edi,%edi
  mov    %rax,%r12
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D0(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: %d-%b-%Y_%H-%M-%S

assistant: ```c
char *time_stamp_dir(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 21, "%d-%b-%Y_%H-%M-%S", localtime(&t));
  return t_stamp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<time_stamp_dir>:
  endbr64
  push   %r12
  mov    $0x19,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <MALLOC@plt>
  xor    %edi,%edi
  mov    %rax,%r12
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D2(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: %d-%b-%Y_%H-%M-%S

assistant: ```c
char *time_stamp_dir(void) {
  time_t t;
  char *t_stamp;
  t_stamp = (char *)MALLOC(25 * sizeof(char));
  t = time(NULL);
  strftime(t_stamp, 21, "%d-%b-%Y_%H-%M-%S", localtime(&t));
  return t_stamp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string

tool: D6:  enter the number

tool: D13:  %d

assistant: ```c
int main() {
  int i;
  printf(" enter the number");
  scanf(" %d", &i);
  printf(" %d", i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D18:  enter the number

tool: D9:  %d

assistant: ```c
int main() {
  int i;
  printf(" enter the number");
  scanf(" %d", &i);
  printf(" %d", i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  lea    D14(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D16:  enter the number

tool: D14:  %d

assistant: ```c
int main() {
  int i;
  printf(" enter the number");
  scanf(" %d", &i);
  printf(" %d", i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  lea    D14(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string

tool: D8:  enter the number

tool: D14:  %d

assistant: ```c
int main() {
  int i;
  printf(" enter the number");
  scanf(" %d", &i);
  printf(" %d", i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cfib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L4
L9:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L9
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long cfib(long n) {
  long i;
  long a = 0;
  long b = 1;
  long tmp;
  for (i = 0; i < n; ++i) {
    tmp = b;
    b = a + b;
    a = tmp;
  }
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<cfib>:
  endbr64
  test   %rdi,%rdi
  jle    L8
  mov    $0x1,%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  jmp    L11
L21:
  mov    %rsi,%rax
L11:
  lea    (%rcx,%rax,1),%rsi
  add    $0x1,%rdx
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jne    L21
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long cfib(long n) {
  long i;
  long a = 0;
  long b = 1;
  long tmp;
  for (i = 0; i < n; ++i) {
    tmp = b;
    b = a + b;
    a = tmp;
  }
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cfib>:
  endbr64
  test   %rdi,%rdi
  jle    L23
  mov    $0x1,%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L26
  nopl   0x0(%rax)
L12:
  mov    %rsi,%rax
L26:
  add    $0x1,%rdx
  lea    (%rcx,%rax,1),%rsi
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jne    L12
  ret
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
long cfib(long n) {
  long i;
  long a = 0;
  long b = 1;
  long tmp;
  for (i = 0; i < n; ++i) {
    tmp = b;
    b = a + b;
    a = tmp;
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cfib>:
  endbr64
  test   %rdi,%rdi
  jle    L10
  mov    $0x1,%eax
  xor    %ecx,%ecx
  xor    %edx,%edx
  jmp    L17
  nopl   0x0(%rax)
L29:
  mov    %rsi,%rax
L17:
  add    $0x1,%rdx
  lea    (%rcx,%rax,1),%rsi
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jne    L29
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
long cfib(long n) {
  long i;
  long a = 0;
  long b = 1;
  long tmp;
  for (i = 0; i < n; ++i) {
    tmp = b;
    b = a + b;
    a = tmp;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L39
  mov    -0x10(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L20
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x2,%rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L39:
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L56
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x2,%rax
  and    $0x3c,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L56:
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x2,%rax
  and    $0x1c,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%rax
  rol    $0x3,%rax
  mov    %rax,%rdx
  movabs $0xcc00000000753d6d,%rax
  or     %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    if (state[0UL] & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        state[0UL] <<= ((state[0UL] >> 2UL) & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 2UL) & 1UL) {
      state[0UL] |= (state[0UL] & 15UL) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 7UL) << 2UL;
    }
    output[0UL] = ((state[0UL] << 3UL) | (state[0UL] >> 61UL)) | 0xcc00000000753d6dUL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x3686696a,%rdx
  mov    %rdx,%rax
  xor    $0xffffffffce5d000b,%rax
  test   $0x1,%dl
  jne    L43
  test   $0x2,%al
  je     L6
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L6:
  rol    $0x3,%rax
  movabs $0xcc00000000753d6d,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
L43:
  test   $0x4,%al
  je     L2
  lea    0x0(,%rax,4),%rdx
  and    $0x3c,%edx
  or     %rdx,%rax
  jmp    L6
L2:
  lea    0x0(,%rax,4),%rdx
  and    $0x1c,%edx
  or     %rdx,%rax
  jmp    L6
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    if (state[0UL] & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        state[0UL] <<= ((state[0UL] >> 2UL) & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 2UL) & 1UL) {
      state[0UL] |= (state[0UL] & 15UL) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 7UL) << 2UL;
    }
    output[0UL] = ((state[0UL] << 3UL) | (state[0UL] >> 61UL)) | 0xcc00000000753d6dUL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x3686696a,%rdx
  mov    %rdx,%rax
  xor    $0xffffffffce5d000b,%rax
  and    $0x1,%edx
  jne    L44
  test   $0x2,%al
  je     L12
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L12:
  movabs $0xcc00000000753d6d,%rdx
  rol    $0x3,%rax
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
  nopl   (%rax)
L44:
  lea    0x0(,%rax,4),%rdx
  test   $0x4,%al
  je     L21
  and    $0x3c,%edx
  or     %rdx,%rax
  jmp    L12
  nopl   0x0(%rax)
L21:
  and    $0x1c,%edx
  or     %rdx,%rax
  jmp    L12
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    if (state[0UL] & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        state[0UL] <<= ((state[0UL] >> 2UL) & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 2UL) & 1UL) {
      state[0UL] |= (state[0UL] & 15UL) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 7UL) << 2UL;
    }
    output[0UL] = ((state[0UL] << 3UL) | (state[0UL] >> 61UL)) | 0xcc00000000753d6dUL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x3686696a,%rdx
  mov    %rdx,%rax
  xor    $0xffffffffce5d000b,%rax
  and    $0x1,%edx
  jne    L49
  test   $0x2,%al
  je     L39
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L39:
  movabs $0xcc00000000753d6d,%rdx
  rol    $0x3,%rax
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
  nopl   (%rax)
L49:
  lea    0x0(,%rax,4),%rdx
  test   $0x4,%al
  je     L48
  and    $0x3c,%edx
  or     %rdx,%rax
  jmp    L39
  nopl   0x0(%rax)
L48:
  and    $0x1c,%edx
  or     %rdx,%rax
  jmp    L39
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    if (state[0UL] & 1UL) {
      if ((state[0UL] >> 1UL) & 1UL) {
        state[0UL] <<= ((state[0UL] >> 2UL) & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 2UL) & 1UL) {
      state[0UL] |= (state[0UL] & 15UL) << 2UL;
    } else {
      state[0UL] |= (state[0UL] & 7UL) << 2UL;
    }
    output[0UL] = ((state[0UL] << 3UL) | (state[0UL] >> 61UL)) | 0xcc00000000753d6dUL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compara_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L38
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L27
L38:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compara_score(int vetor_possibilidades[2], int x_pacman, int y_pacman) {
  int x, y;
  if (vetor_possibilidades[0] > y_pacman) {
    y = vetor_possibilidades[0] - y_pacman;
  } else {
    y = y_pacman - vetor_possibilidades[0];
  }
  if (vetor_possibilidades[1] > x_pacman) {
    x = vetor_possibilidades[1] - x_pacman;
  } else {
    x = x_pacman - vetor_possibilidades[1];
  }
  return x + y;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compara_score>:
  endbr64
  mov    (%rdi),%ecx
  mov    %ecx,%r8d
  sub    %edx,%r8d
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %edx,%ecx
  mov    %r8d,%edx
  cmovle %eax,%edx
  mov    0x4(%rdi),%ecx
  mov    %ecx,%edi
  sub    %esi,%edi
  mov    %esi,%eax
  sub    %ecx,%eax
  cmp    %esi,%ecx
  cmovg  %edi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int compara_score(int vetor_possibilidades[2], int x_pacman, int y_pacman) {
  int x, y;
  if (vetor_possibilidades[0] > y_pacman) {
    y = vetor_possibilidades[0] - y_pacman;
  } else {
    y = y_pacman - vetor_possibilidades[0];
  }
  if (vetor_possibilidades[1] > x_pacman) {
    x = vetor_possibilidades[1] - x_pacman;
  } else {
    x = x_pacman - vetor_possibilidades[1];
  }
  return x + y;
}
```
user: What is the c source code of the assembly code below:

```asm
<compara_score>:
  endbr64
  mov    (%rdi),%ecx
  mov    %edx,%eax
  mov    %ecx,%r8d
  sub    %ecx,%eax
  sub    %edx,%r8d
  cmp    %edx,%ecx
  mov    0x4(%rdi),%ecx
  mov    %r8d,%edx
  cmovle %eax,%edx
  mov    %ecx,%edi
  mov    %esi,%eax
  sub    %esi,%edi
  sub    %ecx,%eax
  cmp    %esi,%ecx
  cmovg  %edi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int compara_score(int vetor_possibilidades[2], int x_pacman, int y_pacman) {
  int x, y;
  if (vetor_possibilidades[0] > y_pacman) {
    y = vetor_possibilidades[0] - y_pacman;
  } else {
    y = y_pacman - vetor_possibilidades[0];
  }
  if (vetor_possibilidades[1] > x_pacman) {
    x = vetor_possibilidades[1] - x_pacman;
  } else {
    x = x_pacman - vetor_possibilidades[1];
  }
  return x + y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compara_score>:
  endbr64
  mov    (%rdi),%ecx
  mov    %edx,%eax
  mov    %ecx,%r8d
  sub    %ecx,%eax
  sub    %edx,%r8d
  cmp    %edx,%ecx
  mov    0x4(%rdi),%ecx
  mov    %r8d,%edx
  cmovle %eax,%edx
  mov    %ecx,%edi
  mov    %esi,%eax
  sub    %esi,%edi
  sub    %ecx,%eax
  cmp    %esi,%ecx
  cmovg  %edi,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int compara_score(int vetor_possibilidades[2], int x_pacman, int y_pacman) {
  int x, y;
  if (vetor_possibilidades[0] > y_pacman) {
    y = vetor_possibilidades[0] - y_pacman;
  } else {
    y = y_pacman - vetor_possibilidades[0];
  }
  if (vetor_possibilidades[1] > x_pacman) {
    x = vetor_possibilidades[1] - x_pacman;
  } else {
    x = x_pacman - vetor_possibilidades[1];
  }
  return x + y;
}
```