ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x38(%rbp)
  movl   $0xc,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L53
L58:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x3c(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x3c(%rbp)
L53:
  cmpl   $0xb,-0x3c(%rbp)
  jle    L58
  movl   $0x0,-0x3c(%rbp)
  jmp    L48
L29:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x5,-0x3c(%rbp)
  jne    L57
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L57:
  addl   $0x1,-0x3c(%rbp)
L48:
  cmpl   $0x9,-0x3c(%rbp)
  jle    L29
  movss  -0x40(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D51
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D16: %d


tool: D11: Enter a new number: 

tool: D51: %d

tool: D15: hey it's a four

tool: D23: Number Entered was %d


assistant: ```c
int main(void) {
  int number = 10;
  int next_number = 12;
  float new_number;
  printf("%d\n", next_number);
  printf("%d\n", number);
  printf("%d\n", number + next_number);
  printf("Enter a new number: ");
  scanf("%d", &new_number);
  int a[10];
  int i;
  for (i = 0; i < 12; ++i) {
    a[i] = i;
  }
  for (i = 0; i < 10; ++i) {
    printf("%d\n", a[i]);
    if (i == 5) {
      printf("hey it's a four\n");
    }
  }
  printf("Number Entered was %d\n", new_number);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0xc,%esi
  lea    D41(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x16,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
L11:
  mov    %eax,0x10(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xc,%rax
  jne    L11
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  lea    D41(%rip),%r12
  lea    D52(%rip),%r13
  jmp    L15
L12:
  mov    %r13,%rdi
  call   <puts@plt>
L48:
  add    $0x1,%rbx
  add    $0x1,%ebp
L15:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  je     L12
  cmp    $0x9,%ebp
  jle    L48
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
data_type: string
name: retrieve_data
arguments: data_tag: D48
data_type: string
name: retrieve_data
arguments: data_tag: D21
data_type: string
name: retrieve_data
arguments: data_tag: D52
data_type: string
name: retrieve_data
arguments: data_tag: D55
data_type: string

tool: D41: %d


tool: D48: Enter a new number: 

tool: D21: %d

tool: D52: hey it's a four

tool: D55: Number Entered was %d


assistant: ```c
int main(void) {
  int number = 10;
  int next_number = 12;
  float new_number;
  printf("%d\n", next_number);
  printf("%d\n", number);
  printf("%d\n", number + next_number);
  printf("Enter a new number: ");
  scanf("%d", &new_number);
  int a[10];
  int i;
  for (i = 0; i < 12; ++i) {
    a[i] = i;
  }
  for (i = 0; i < 10; ++i) {
    printf("%d\n", a[i]);
    if (i == 5) {
      printf("hey it's a four\n");
    }
  }
  printf("Number Entered was %d\n", new_number);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%esi
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x16,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0xc,%rax
  jne    L31
  xor    %ebx,%ebx
  lea    D13(%rip),%r13
  jmp    L30
  nopl   0x0(%rax)
L47:
  cmp    $0x9,%rbx
  je     L32
L51:
  add    $0x1,%rbx
L30:
  mov    0x0(%rbp,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L47
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L32:
  pxor   %xmm0,%xmm0
  lea    D44(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D27
type_infered: string
name: read_data
arguments: data_tag: D6
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D44
type_infered: string

tool: D28: %d


tool: D27: Enter a new number: 

tool: D6: %d

tool: D13: hey it's a four

tool: D44: Number Entered was %d


assistant: ```c
int main(void) {
  int number = 10;
  int next_number = 12;
  float new_number;
  printf("%d\n", next_number);
  printf("%d\n", number);
  printf("%d\n", number + next_number);
  printf("Enter a new number: ");
  scanf("%d", &new_number);
  int a[10];
  int i;
  for (i = 0; i < 12; ++i) {
    a[i] = i;
  }
  for (i = 0; i < 10; ++i) {
    printf("%d\n", a[i]);
    if (i == 5) {
      printf("hey it's a four\n");
    }
  }
  printf("Number Entered was %d\n", new_number);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%esi
  lea    D42(%rip),%r13
  push   %r12
  push   %rbp
  lea    D76(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x16,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D28(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D40(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L35:
  cmp    $0x9,%rbx
  je     L48
L46:
  add    $0x1,%rbx
L23:
  mov    (%r12,%rbx,4),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L35
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L48:
  pxor   %xmm0,%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D42
data_type: string
name: parse_data
arguments: data_label: D76
data_type: string
name: parse_data
arguments: data_label: D51
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D23
data_type: byte[16]
name: parse_data
arguments: data_label: D28
data_type: byte[16]
name: parse_data
arguments: data_label: D40
data_type: byte[16]
name: parse_data
arguments: data_label: D0
data_type: string

tool: D42: hey it's a four

tool: D76: %d


tool: D51: Enter a new number: 

tool: D20: %d

tool: {"D23": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D28": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D40": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: D0: Number Entered was %d


assistant: ```c
int main(void) {
  int number = 10;
  int next_number = 12;
  float new_number;
  printf("%d\n", next_number);
  printf("%d\n", number);
  printf("%d\n", number + next_number);
  printf("Enter a new number: ");
  scanf("%d", &new_number);
  int a[10];
  int i;
  for (i = 0; i < 12; ++i) {
    a[i] = i;
  }
  for (i = 0; i < 10; ++i) {
    printf("%d\n", a[i]);
    if (i == 5) {
      printf("hey it's a four\n");
    }
  }
  printf("Number Entered was %d\n", new_number);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  movl   $0x7,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  lea    -0x14(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recvmsg@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
ssize_t test(void) {
  int sockfd = 4;
  struct msghdr msg;
  int flags = 7;
  return recvmsg(sockfd, &msg, flags);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x7,%edx
  mov    $0x4,%edi
  call   <recvmsg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t test(void) {
  int sockfd = 4;
  struct msghdr msg;
  int flags = 7;
  return recvmsg(sockfd, &msg, flags);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x7,%edx
  mov    $0x4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <recvmsg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t test(void) {
  int sockfd = 4;
  struct msghdr msg;
  int flags = 7;
  return recvmsg(sockfd, &msg, flags);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x7,%edx
  mov    $0x4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <recvmsg@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t test(void) {
  int sockfd = 4;
  struct msghdr msg;
  int flags = 7;
  return recvmsg(sockfd, &msg, flags);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cbm_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cbmarch_close@plt>
  leave
  ret
```

assistant: ```c
int cbm_close(int HandleDevice, __u_char DeviceAddress, __u_char SecondaryAddress) {
  ;
  return cbmarch_close(HandleDevice, DeviceAddress, SecondaryAddress);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cbm_close>:
  endbr64
  sub    $0x8,%rsp
  call   <cbmarch_close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cbm_close(int HandleDevice, __u_char DeviceAddress, __u_char SecondaryAddress) {
  ;
  return cbmarch_close(HandleDevice, DeviceAddress, SecondaryAddress);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cbm_close>:
  endbr64
  jmp    1050 <cbmarch_close@plt>
```

assistant: ```c
int cbm_close(int HandleDevice, __u_char DeviceAddress, __u_char SecondaryAddress) {
  ;
  return cbmarch_close(HandleDevice, DeviceAddress, SecondaryAddress);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cbm_close>:
  endbr64
  jmp    1050 <cbmarch_close@plt>
```

assistant: ```c
int cbm_close(int HandleDevice, __u_char DeviceAddress, __u_char SecondaryAddress) {
  ;
  return cbmarch_close(HandleDevice, DeviceAddress, SecondaryAddress);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fn_ii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <abort@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fn_ii(int i) {
  abort();
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fn_ii>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <abort@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fn_ii(int i) {
  abort();
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_ii>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <abort@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fn_ii(int i) {
  abort();
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn_ii>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <abort@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fn_ii(int i) {
  abort();
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<recurser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L9
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <recurser>
L9:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void recurser(x) int x;
{
  int local_x;
  if (x > 0)
    recurser(x - 1);
  local_x = x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<recurser>:
  endbr64
  test   %edi,%edi
  jg     L8
  ret
L8:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  mov    $0x0,%eax
  call   <recurser>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void recurser(x) int x;
{
  int local_x;
  if (x > 0)
    recurser(x - 1);
  local_x = x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<recurser>:
  endbr64
  ret
```

assistant: ```c
void recurser(x) int x;
{
  int local_x;
  if (x > 0)
    recurser(x - 1);
  local_x = x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recurser>:
  endbr64
  ret
```

assistant: ```c
void recurser(x) int x;
{
  int local_x;
  if (x > 0)
    recurser(x - 1);
  local_x = x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ELMErrLocBitAddrGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x220,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x1fff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ELMErrLocBitAddrGet(unsigned int baseAddr, unsigned int errNum) {
  unsigned int bitAddr;
  bitAddr = ((*((volatile unsigned int *)(baseAddr + (0x880 + (errNum * 4))))) & (0x00001FFFu));
  return (bitAddr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ELMErrLocBitAddrGet>:
  endbr64
  lea    0x880(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  and    $0x1fff,%eax
  ret
```

assistant: ```c
unsigned int ELMErrLocBitAddrGet(unsigned int baseAddr, unsigned int errNum) {
  unsigned int bitAddr;
  bitAddr = ((*((volatile unsigned int *)(baseAddr + (0x880 + (errNum * 4))))) & (0x00001FFFu));
  return (bitAddr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ELMErrLocBitAddrGet>:
  endbr64
  lea    0x880(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  and    $0x1fff,%eax
  ret
```

assistant: ```c
unsigned int ELMErrLocBitAddrGet(unsigned int baseAddr, unsigned int errNum) {
  unsigned int bitAddr;
  bitAddr = ((*((volatile unsigned int *)(baseAddr + (0x880 + (errNum * 4))))) & (0x00001FFFu));
  return (bitAddr);
}
```
user: What is the c source code of the assembly code below?

```asm
<ELMErrLocBitAddrGet>:
  endbr64
  lea    0x880(%rdi,%rsi,4),%eax
  mov    (%eax),%eax
  and    $0x1fff,%eax
  ret
```

assistant: ```c
unsigned int ELMErrLocBitAddrGet(unsigned int baseAddr, unsigned int errNum) {
  unsigned int bitAddr;
  bitAddr = ((*((volatile unsigned int *)(baseAddr + (0x880 + (errNum * 4))))) & (0x00001FFFu));
  return (bitAddr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L76:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L62
  mov    -0xc(%rbp),%eax
  cmp    $0x64,%eax
  jle    L0
L62:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0xa,%eax
  jg     L83
  cmp    $0x9,%eax
  jge    L122
  cmp    $0x8,%eax
  je     L143
  cmp    $0x8,%eax
  jg     L83
  cmp    $0x6,%eax
  je     L95
  cmp    $0x7,%eax
  je     L12
  jmp    L83
L122:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L143:
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L12:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L95:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L46
L83:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L46:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L156
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L76
L156:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L111
  call   <__stack_chk_fail@plt>
L111:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D48
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D79
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string
name: parse_data
arguments: label: D43
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D30
type_infered: string

tool: D13: input your score:

tool: D48: input error

tool: D37: A

tool: D79: B

tool: D34: C

tool: D43: D

tool: D16: NO PASS!

tool: D30: %d

assistant: ```c
int main() {
  int score;
  puts("input your score:");
  while (scanf("%d", &score) && score) {
    if (score < 0 || score > 100) {
      puts("input error");
      continue;
    }
    switch (score / 10) {
    case 10:
    case 9:
      puts("A");
      break;
    case 8:
      puts("B");
      break;
    case 7:
      puts("C");
      break;
    case 6:
      puts("D");
      break;
    default:
      puts("NO PASS!");
      break;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rbx
  lea    D75(%rip),%r13
  lea    D61(%rip),%rbp
  lea    D41(%rip),%r12
  jmp    L107
L97:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L107
L139:
  mov    %rbp,%rdi
  call   <puts@plt>
L107:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L4
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L4
  cmp    $0x64,%edx
  ja     L97
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  cmp    $0x8,%eax
  je     L34
  cmp    $0x59,%edx
  jg     L139
  cmp    $0x6,%eax
  je     L22
  cmp    $0x7,%eax
  jne    L116
  lea    D31(%rip),%rdi
  call   <puts@plt>
  jmp    L107
L34:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L107
L22:
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L107
L116:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L107
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D32
data_type: string
name: parse_data
arguments: tag: D57
data_type: string
name: parse_data
arguments: tag: D75
data_type: string
name: parse_data
arguments: tag: D61
data_type: string
name: parse_data
arguments: tag: D41
data_type: string
name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D31
data_type: string
name: parse_data
arguments: tag: D15
data_type: string

tool: D32: input your score:

tool: D57: %d

tool: D75: B

tool: D61: A

tool: D41: D

tool: D24: input error

tool: D31: C

tool: D15: NO PASS!

assistant: ```c
int main() {
  int score;
  puts("input your score:");
  while (scanf("%d", &score) && score) {
    if (score < 0 || score > 100) {
      puts("input error");
      continue;
    }
    switch (score / 10) {
    case 10:
    case 9:
      puts("A");
      break;
    case 8:
      puts("B");
      break;
    case 7:
      puts("C");
      break;
    case 6:
      puts("D");
      break;
    default:
      puts("NO PASS!");
      break;
    }
  }
  return 0;
}
```