ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<product>:
  endbr64
  test   %ecx,%ecx
  je     L17
  mov    %ecx,%ecx
  mov    $0x0,%eax
L5:
  movslq (%rdi,%rax,4),%r8
  mov    -0x4(%rsi,%r8,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L5
L17:
  ret
```

assistant: ```c
void product(int *p1, int *p2, int *p, int n) {
  while (n--)
    *(p++) = *(p2 - 1 + *(p1++));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<product>:
  endbr64
  test   %ecx,%ecx
  je     L14
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  movslq (%rdi,%rax,4),%r8
  mov    -0x4(%rsi,%r8,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L4
L14:
  ret
```

assistant: ```c
void product(int *p1, int *p2, int *p, int n) {
  while (n--)
    *(p++) = *(p2 - 1 + *(p1++));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<product>:
  endbr64
  test   %ecx,%ecx
  je     L15
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L14:
  movslq (%rdi,%rax,4),%r8
  mov    -0x4(%rsi,%r8,4),%r8d
  mov    %r8d,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L14
L15:
  ret
```

assistant: ```c
void product(int *p1, int *p2, int *p, int n) {
  while (n--)
    *(p++) = *(p2 - 1 + *(p1++));
}
```
user: What is the c source code of the assembly code below?

```asm
<dvbpsi_get_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L14
  addl   $0x1,-0x10(%rbp)
L14:
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L13:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L13
  mov    $0x4,%eax
  sub    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    -0x10(%rbp),%eax
  shl    $0x3,%eax
  sub    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t dvbpsi_get_bits(unsigned char *b, int offbits, int nbits) {
  int i, nbytes;
  unsigned int ret = 0;
  unsigned char *buf;
  buf = b + (offbits / 8);
  offbits %= 8;
  nbytes = (offbits + nbits) / 8;
  if (((offbits + nbits) % 8) > 0)
    nbytes++;
  for (i = 0; i < nbytes; i++)
    ret += buf[i] << ((nbytes - i - 1) * 8);
  i = (4 - nbytes) * 8 + offbits;
  ret = ((ret << i) >> i) >> ((nbytes * 8) - nbits - offbits);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dvbpsi_get_bits>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%r9d
  lea    0x7(%rsi),%edx
  test   %esi,%esi
  cmovns %esi,%edx
  sar    $0x3,%edx
  movslq %edx,%rcx
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rsi,%rdx,1),%r8d
  and    $0x7,%r8d
  sub    %edx,%r8d
  lea    (%r8,%r9,1),%edx
  lea    0x7(%rdx),%edi
  test   %edx,%edx
  cmovns %edx,%edi
  sar    $0x3,%edi
  mov    %edx,%esi
  sar    $0x1f,%esi
  shr    $0x1d,%esi
  add    %esi,%edx
  and    $0x7,%edx
  sub    %esi,%edx
  test   %edx,%edx
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%edi
  test   %edi,%edi
  jle    L2
  lea    (%rax,%rcx,1),%rsi
  lea    -0x8(,%rdi,8),%ecx
  mov    $0x0,%eax
L8:
  movzbl (%rsi),%edx
  shl    %cl,%edx
  add    %edx,%eax
  add    $0x1,%rsi
  sub    $0x8,%ecx
  cmp    $0xfffffff8,%ecx
  jne    L8
L9:
  mov    $0x4,%edx
  sub    %edi,%edx
  lea    (%r8,%rdx,8),%ecx
  shl    %cl,%eax
  shr    %cl,%eax
  lea    0x0(,%rdi,8),%ecx
  sub    %r9d,%ecx
  sub    %r8d,%ecx
  shr    %cl,%eax
  ret
L2:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
uint32_t dvbpsi_get_bits(unsigned char *b, int offbits, int nbits) {
  int i, nbytes;
  unsigned int ret = 0;
  unsigned char *buf;
  buf = b + (offbits / 8);
  offbits %= 8;
  nbytes = (offbits + nbits) / 8;
  if (((offbits + nbits) % 8) > 0)
    nbytes++;
  for (i = 0; i < nbytes; i++)
    ret += buf[i] << ((nbytes - i - 1) * 8);
  i = (4 - nbytes) * 8 + offbits;
  ret = ((ret << i) >> i) >> ((nbytes * 8) - nbits - offbits);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dvbpsi_get_bits>:
  endbr64
  test   %esi,%esi
  lea    0x7(%rsi),%r8d
  mov    %esi,%eax
  mov    %edx,%r9d
  cmovns %esi,%r8d
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%esi
  sar    $0x3,%r8d
  and    $0x7,%esi
  movslq %r8d,%r8
  sub    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  test   %eax,%eax
  lea    0x7(%rax),%edx
  mov    %eax,%ecx
  cmovns %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%eax
  sar    $0x3,%edx
  and    $0x7,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  add    %eax,%edx
  lea    0x0(,%rdx,8),%eax
  mov    %eax,%r10d
  sub    %r9d,%r10d
  mov    $0x4,%r9d
  sub    %edx,%r9d
  sub    %esi,%r10d
  lea    (%rsi,%r9,8),%r9d
  test   %edx,%edx
  jle    L7
  lea    -0x8(%rax),%ecx
  lea    (%rdi,%r8,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  shl    %cl,%edx
  sub    $0x8,%ecx
  add    %edx,%eax
  cmp    $0xfffffff8,%ecx
  jne    L3
  mov    %r9d,%ecx
  shl    %cl,%eax
  shr    %cl,%eax
  mov    %r10d,%ecx
  shr    %cl,%eax
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t dvbpsi_get_bits(unsigned char *b, int offbits, int nbits) {
  int i, nbytes;
  unsigned int ret = 0;
  unsigned char *buf;
  buf = b + (offbits / 8);
  offbits %= 8;
  nbytes = (offbits + nbits) / 8;
  if (((offbits + nbits) % 8) > 0)
    nbytes++;
  for (i = 0; i < nbytes; i++)
    ret += buf[i] << ((nbytes - i - 1) * 8);
  i = (4 - nbytes) * 8 + offbits;
  ret = ((ret << i) >> i) >> ((nbytes * 8) - nbits - offbits);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<dvbpsi_get_bits>:
  endbr64
  test   %esi,%esi
  lea    0x7(%rsi),%r8d
  mov    %esi,%eax
  mov    %edx,%r9d
  cmovns %esi,%r8d
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%esi
  sar    $0x3,%r8d
  and    $0x7,%esi
  movslq %r8d,%r8
  sub    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  test   %eax,%eax
  lea    0x7(%rax),%edx
  mov    %eax,%ecx
  cmovns %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%eax
  sar    $0x3,%edx
  and    $0x7,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  add    %eax,%edx
  lea    0x0(,%rdx,8),%eax
  mov    %eax,%r10d
  sub    %r9d,%r10d
  mov    $0x4,%r9d
  sub    %edx,%r9d
  sub    %esi,%r10d
  lea    (%rsi,%r9,8),%r9d
  test   %edx,%edx
  jle    L14
  lea    -0x8(%rax),%ecx
  lea    (%rdi,%r8,1),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  shl    %cl,%edx
  sub    $0x8,%ecx
  add    %edx,%eax
  cmp    $0xfffffff8,%ecx
  jne    L13
  mov    %r9d,%ecx
  shl    %cl,%eax
  shr    %cl,%eax
  mov    %r10d,%ecx
  shr    %cl,%eax
  ret
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t dvbpsi_get_bits(unsigned char *b, int offbits, int nbits) {
  int i, nbytes;
  unsigned int ret = 0;
  unsigned char *buf;
  buf = b + (offbits / 8);
  offbits %= 8;
  nbytes = (offbits + nbits) / 8;
  if (((offbits + nbits) % 8) > 0)
    nbytes++;
  for (i = 0; i < nbytes; i++)
    ret += buf[i] << ((nbytes - i - 1) * 8);
  i = (4 - nbytes) * 8 + offbits;
  ret = ((ret << i) >> i) >> ((nbytes * 8) - nbits - offbits);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<maskBoxExceptRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x2c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <otherLinesInBox@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L2:
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x18(%rbp),%esi
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <recursiveMask@plt>
  or     %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x14(%rbp),%esi
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <recursiveMask@plt>
  or     %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L27:
  cmpl   $0x2,-0x10(%rbp)
  jle    L2
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int maskBoxExceptRow(struct Board *board, int row, int box, unsigned int mask) {
  int row1, row2, i, change;
  change = 0;
  otherLinesInBox(row, &row1, &row2);
  for (i = 0; i < 3; i++) {
    change |= recursiveMask(board, row1, 3 * box + i, mask);
    change |= recursiveMask(board, row2, 3 * box + i, mask);
  }
  return change;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maskBoxExceptRow>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%edi
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <otherLinesInBox@plt>
  lea    (%rbx,%rbx,2),%r15d
  mov    %r15d,%ebp
  add    $0x3,%r15d
  mov    $0x0,%r14d
L5:
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  call   <recursiveMask@plt>
  mov    %eax,%ebx
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    0x4(%rsp),%esi
  mov    %r13,%rdi
  call   <recursiveMask@plt>
  or     %eax,%ebx
  or     %ebx,%r14d
  add    $0x1,%ebp
  cmp    %r15d,%ebp
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maskBoxExceptRow(struct Board *board, int row, int box, unsigned int mask) {
  int row1, row2, i, change;
  change = 0;
  otherLinesInBox(row, &row1, &row2);
  for (i = 0; i < 3; i++) {
    change |= recursiveMask(board, row1, 3 * box + i, mask);
    change |= recursiveMask(board, row2, 3 * box + i, mask);
  }
  return change;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maskBoxExceptRow>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  lea    (%rbx,%rbx,2),%ebp
  lea    0x3(%rbp),%r14d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <otherLinesInBox@plt>
L11:
  mov    (%rsp),%esi
  mov    %ebp,%edx
  mov    %r12d,%ecx
  mov    %r13,%rdi
  call   <recursiveMask@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edx
  mov    %r12d,%ecx
  mov    %r13,%rdi
  mov    %eax,%ebx
  add    $0x1,%ebp
  call   <recursiveMask@plt>
  or     %eax,%ebx
  or     %ebx,%r15d
  cmp    %ebp,%r14d
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maskBoxExceptRow(struct Board *board, int row, int box, unsigned int mask) {
  int row1, row2, i, change;
  change = 0;
  otherLinesInBox(row, &row1, &row2);
  for (i = 0; i < 3; i++) {
    change |= recursiveMask(board, row1, 3 * box + i, mask);
    change |= recursiveMask(board, row2, 3 * box + i, mask);
  }
  return change;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maskBoxExceptRow>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  lea    (%rbx,%rbx,2),%ebp
  lea    0x3(%rbp),%r14d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <otherLinesInBox@plt>
L8:
  mov    (%rsp),%esi
  mov    %ebp,%edx
  mov    %r12d,%ecx
  mov    %r13,%rdi
  call   <recursiveMask@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edx
  mov    %r12d,%ecx
  mov    %r13,%rdi
  mov    %eax,%ebx
  add    $0x1,%ebp
  call   <recursiveMask@plt>
  or     %eax,%ebx
  or     %ebx,%r15d
  cmp    %ebp,%r14d
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maskBoxExceptRow(struct Board *board, int row, int box, unsigned int mask) {
  int row1, row2, i, change;
  change = 0;
  otherLinesInBox(row, &row1, &row2);
  for (i = 0; i < 3; i++) {
    change |= recursiveMask(board, row1, 3 * box + i, mask);
    change |= recursiveMask(board, row2, 3 * box + i, mask);
  }
  return change;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %edx,-0xd4(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xe0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edi
  mov    -0xe0(%rbp),%rcx
  mov    -0xd4(%rbp),%edx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <vexpect@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int expect(const char *expected, const char *text, int ty, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vexpect(expected, text, ty, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<expect>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <vexpect@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int expect(const char *expected, const char *text, int ty, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vexpect(expected, text, ty, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expect>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rsi,%r14
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vexpect@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int expect(const char *expected, const char *text, int ty, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vexpect(expected, text, ty, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expect>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rsi,%r14
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vexpect@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int expect(const char *expected, const char *text, int ty, const char *fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vexpect(expected, text, ty, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L36
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L33
L36:
  movl   $0x0,-0x8(%rbp)
L6:
  mov    $0x0,%eax
  call   <uart_rxChar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L29
  cmpl   $0xa,-0x4(%rbp)
  jne    L6
L29:
  mov    -0x8(%rbp),%eax
L33:
  leave
  ret
```

assistant: ```c
__attribute__((__weak__)) int _read(int file, char *ptr, int len) {
  if (file != STDIN_FILENO) {
    errno = EBADF;
    return -1;
  }
  int done = 0;
  int ch;
  do {
    ch = uart_rxChar();
    *ptr++ = ch;
  } while ((++done < len) && (ch != '\n'));
  return done;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D10(%rip),%rax
  cmp    %edi,(%rax)
  jne    L19
  mov    %edx,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
L33:
  mov    $0x0,%eax
  call   <uart_rxChar@plt>
  mov    %al,(%rbx)
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L20
  cmp    %r12d,%ebp
  jl     L33
L20:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%ebp
  jmp    L20
```

assistant: ```c
__attribute__((__weak__)) int _read(int file, char *ptr, int len) {
  if (file != STDIN_FILENO) {
    errno = EBADF;
    return -1;
  }
  int done = 0;
  int ch;
  do {
    ch = uart_rxChar();
    *ptr++ = ch;
  } while ((++done < len) && (ch != '\n'));
  return done;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_read>:
  endbr64
  mov    D18(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %edi,(%rax)
  jne    L11
  mov    %edx,%ebp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L40
  nopl   (%rax)
L14:
  cmp    $0xa,%eax
  je     L23
L40:
  xor    %eax,%eax
  add    $0x1,%r12d
  add    $0x1,%rbx
  call   <uart_rxChar@plt>
  mov    %al,-0x1(%rbx)
  cmp    %ebp,%r12d
  jl     L14
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    D4(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  jmp    L23
```

assistant: ```c
__attribute__((__weak__)) int _read(int file, char *ptr, int len) {
  if (file != STDIN_FILENO) {
    errno = EBADF;
    return -1;
  }
  int done = 0;
  int ch;
  do {
    ch = uart_rxChar();
    *ptr++ = ch;
  } while ((++done < len) && (ch != '\n'));
  return done;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_read>:
  endbr64
  mov    D20(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %edi,(%rax)
  jne    L2
  mov    %edx,%ebp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L7
  nopl   (%rax)
L22:
  cmp    $0xa,%eax
  je     L17
L7:
  xor    %eax,%eax
  add    $0x1,%r12d
  add    $0x1,%rbx
  call   <uart_rxChar@plt>
  mov    %al,-0x1(%rbx)
  cmp    %ebp,%r12d
  jl     L22
L17:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    D16(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  jmp    L17
```

assistant: ```c
__attribute__((__weak__)) int _read(int file, char *ptr, int len) {
  if (file != STDIN_FILENO) {
    errno = EBADF;
    return -1;
  }
  int done = 0;
  int ch;
  do {
    ch = uart_rxChar();
    *ptr++ = ch;
  } while ((++done < len) && (ch != '\n'));
  return done;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udcGetChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <udcMustRead@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int udcGetChar(struct udcFile *file) {
  unsigned char b;
  udcMustRead(file, &b, 1);
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<udcGetChar>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <udcMustRead@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcGetChar(struct udcFile *file) {
  unsigned char b;
  udcMustRead(file, &b, 1);
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<udcGetChar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <udcMustRead@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcGetChar(struct udcFile *file) {
  unsigned char b;
  udcMustRead(file, &b, 1);
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<udcGetChar>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <udcMustRead@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcGetChar(struct udcFile *file) {
  unsigned char b;
  udcMustRead(file, &b, 1);
  return b;
}
```