ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<vec_swap_>:
  endbr64
  mov    %ecx,%r10d
  cmp    %r9d,%r8d
  je     L99
  imul   %ecx,%r9d
  mov    (%rdi),%r11
  imul   %ecx,%r8d
  movslq %r9d,%rdi
  lea    -0x1(%r10),%r9d
  movslq %r8d,%rsi
  lea    (%r11,%rdi,1),%rcx
  lea    (%r11,%rsi,1),%rdx
  test   %r10d,%r10d
  je     L99
  lea    0x10(%rsi),%rax
  lea    0x10(%rdi),%r8
  cmp    %rdi,%rax
  setle  %al
  cmp    %rsi,%r8
  setle  %r8b
  or     %r8b,%al
  je     L163
  cmp    $0x6,%r9d
  jbe    L163
  cmp    $0xe,%r9d
  jbe    L39
  mov    %r10d,%r8d
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L5:
  movdqu (%rdx,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L5
  mov    %r10d,%r8d
  and    $0xfffffff0,%r8d
  mov    %r8d,%eax
  sub    %r8d,%r9d
  add    %rax,%rdx
  add    %rax,%rcx
  cmp    %r8d,%r10d
  je     L25
L166:
  mov    %r10d,%eax
  sub    %r8d,%eax
  lea    -0x1(%rax),%r10d
  cmp    $0x6,%r10d
  jbe    L64
  add    %r8,%rdi
  add    %r8,%rsi
  add    %r11,%rdi
  add    %r11,%rsi
  mov    (%rdi),%r10
  mov    (%rsi),%r8
  mov    %r10,(%rsi)
  mov    %eax,%esi
  and    $0xfffffff8,%esi
  mov    %r8,(%rdi)
  mov    %esi,%edi
  sub    %esi,%r9d
  add    %rdi,%rdx
  add    %rdi,%rcx
  cmp    %esi,%eax
  je     L99
L64:
  movzbl (%rdx),%eax
  movzbl (%rcx),%esi
  mov    %sil,(%rdx)
  mov    %al,(%rcx)
  test   %r9d,%r9d
  je     L99
  movzbl 0x1(%rdx),%eax
  movzbl 0x1(%rcx),%esi
  mov    %sil,0x1(%rdx)
  mov    %al,0x1(%rcx)
  cmp    $0x1,%r9d
  je     L99
  movzbl 0x2(%rdx),%eax
  movzbl 0x2(%rcx),%esi
  mov    %sil,0x2(%rdx)
  mov    %al,0x2(%rcx)
  cmp    $0x2,%r9d
  je     L99
  movzbl 0x3(%rdx),%eax
  movzbl 0x3(%rcx),%esi
  mov    %sil,0x3(%rdx)
  mov    %al,0x3(%rcx)
  cmp    $0x3,%r9d
  je     L99
  movzbl 0x4(%rdx),%eax
  movzbl 0x4(%rcx),%esi
  mov    %sil,0x4(%rdx)
  mov    %al,0x4(%rcx)
  cmp    $0x4,%r9d
  je     L99
  movzbl 0x5(%rdx),%eax
  movzbl 0x5(%rcx),%esi
  mov    %sil,0x5(%rdx)
  mov    %al,0x5(%rcx)
  cmp    $0x5,%r9d
  je     L99
  movzbl 0x6(%rdx),%eax
  movzbl 0x6(%rcx),%esi
  mov    %sil,0x6(%rdx)
  mov    %al,0x6(%rcx)
  ret
L163:
  mov    %r10d,%eax
  add    %rdx,%rax
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl (%rcx),%edi
  movzbl (%rdx),%esi
  add    $0x1,%rdx
  add    $0x1,%rcx
  mov    %dil,-0x1(%rdx)
  mov    %sil,-0x1(%rcx)
  cmp    %rax,%rdx
  jne    L17
L99:
  ret
L39:
  xor    %r8d,%r8d
  jmp    L166
L25:
  ret
```

assistant: ```c
void vec_swap_(char **data, int *length, int *capacity, int memsz, int idx1, int idx2) {
  unsigned char *a, *b, tmp;
  int count;
  (void)length;
  (void)capacity;
  if (idx1 == idx2)
    return;
  a = (unsigned char *)*data + idx1 * memsz;
  b = (unsigned char *)*data + idx2 * memsz;
  count = memsz;
  while (count--) {
    tmp = *a;
    *a = *b;
    *b = tmp;
    a++, b++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<numa_available>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <get_mempolicy@plt>
  test   %rax,%rax
  jns    L2
  mov    D7(%rip),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L10
L2:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int numa_available(void) {
  if (get_mempolicy(NULL, NULL, 0, 0, 0) < 0 && errno == ENOSYS)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<numa_available>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <get_mempolicy@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L6
L5:
  add    $0x8,%rsp
  ret
L6:
  mov    D13(%rip),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L5
```

assistant: ```c
int numa_available(void) {
  if (get_mempolicy(NULL, NULL, 0, 0, 0) < 0 && errno == ENOSYS)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numa_available>:
  endbr64
  xor    %r8d,%r8d
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <get_mempolicy@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jns    L5
  mov    D9(%rip),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  movzbl %al,%eax
  neg    %eax
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int numa_available(void) {
  if (get_mempolicy(NULL, NULL, 0, 0, 0) < 0 && errno == ENOSYS)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numa_available>:
  endbr64
  xor    %r8d,%r8d
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <get_mempolicy@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jns    L3
  mov    D19(%rip),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  movzbl %al,%eax
  neg    %eax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int numa_available(void) {
  if (get_mempolicy(NULL, NULL, 0, 0, 0) < 0 && errno == ENOSYS)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<f_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x24(%rbp)
  jmp    L15
L20:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  jmp    L40
L39:
  nop
L40:
  addl   $0x1,-0x24(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: .t

assistant: ```c
void f_delete(int argc, char **argv) {
  int i;
  char fname[20];
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '\0')
      continue;
    strncpy(fname, argv[i], 8);
    fname[8] = '\0';
    strcat(fname, ".t");
    unlink(fname);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f_delete>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L50
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D1(%rip),%r13
  jmp    L8
L1:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L50
L8:
  mov    (%rbx),%rsi
  cmpb   $0x0,(%rsi)
  je     L1
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x8(%rsp)
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  jmp    L1
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: .t

assistant: ```c
void f_delete(int argc, char **argv) {
  int i;
  char fname[20];
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '\0')
      continue;
    strncpy(fname, argv[i], 8);
    fname[8] = '\0';
    strcat(fname, ".t");
    unlink(fname);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_delete>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L23
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    D8(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    (%rbx),%rsi
  cmpb   $0x0,(%rsi)
  je     L26
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  movb   $0x0,0x8(%rsp)
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
L26:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L21
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: .t

assistant: ```c
void f_delete(int argc, char **argv) {
  int i;
  char fname[20];
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '\0')
      continue;
    strncpy(fname, argv[i], 8);
    fname[8] = '\0';
    strcat(fname, ".t");
    unlink(fname);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f_delete>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L5
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    D6(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    (%rbx),%rsi
  cmpb   $0x0,(%rsi)
  je     L21
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  mov    %r13,%rsi
  movb   $0x0,0x8(%rsp)
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
L21:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L37
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: D6: .t

assistant: ```c
void f_delete(int argc, char **argv) {
  int i;
  char fname[20];
  for (i = 1; i < argc; i++) {
    if (*argv[i] == '\0')
      continue;
    strncpy(fname, argv[i], 8);
    fname[8] = '\0';
    strcat(fname, ".t");
    unlink(fname);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L12:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x63,-0xc(%rbp)
  jle    L12
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D9
type_infered: string

tool: D6: result[1-100] = %d


tool: D9: result[1-250] = %d


assistant: ```c
int main(void) {
  int i;
  long result = 0;
  for (i = 1; i < 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x63,%eax
L8:
  sub    $0x1,%eax
  jne    L8
  mov    $0x1356,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D15: result[1-100] = %d


tool: D9: result[1-250] = %d


assistant: ```c
int main(void) {
  int i;
  long result = 0;
  for (i = 1; i < 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1356,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D17: result[1-100] = %d


tool: D19: result[1-250] = %d


assistant: ```c
int main(void) {
  int i;
  long result = 0;
  for (i = 1; i < 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1356,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xfa,%edi
  call   <func@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D9
type: string

tool: D12: result[1-100] = %d


tool: D9: result[1-250] = %d


assistant: ```c
int main(void) {
  int i;
  long result = 0;
  for (i = 1; i < 100; i++) {
    result += i;
  }
  printf("result[1-100] = %d\n", result);
  printf("result[1-250] = %d\n", func(250));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<indx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x20(%rbp),%r12
  jmp    L13
L65:
  mov    %r12,%r13
  mov    -0x28(%rbp),%rbx
  jmp    L30
L32:
  add    $0x1,%rbx
  add    $0x1,%r13
L30:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L56
  movzbl (%rbx),%edx
  movzbl 0x0(%r13),%eax
  cmp    %al,%dl
  je     L32
L56:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L44
  mov    %r12,%rax
  sub    -0x20(%rbp),%rax
  jmp    L14
L44:
  add    $0x1,%r12
L13:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L65
  mov    $0xffffffff,%eax
L14:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int indx(s1, s2)
char *s1;
char *s2;
{
  register char *t;
  register char *p;
  register char *m;
  for (p = s1; *p; p++) {
    for (t = p, m = s2; *m && *m == *t; m++, t++)
      ;
    if (!*m)
      return (p - s1);
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<indx>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L42
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  jmp    L53
L67:
  test   %cl,%cl
  je     L2
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  je     L30
L53:
  test   %r8b,%r8b
  je     L2
  mov    %r8d,%ecx
  mov    $0x0,%edx
L56:
  cmp    %cl,(%rax,%rdx,1)
  jne    L67
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L56
L2:
  sub    %edi,%eax
  ret
L42:
  mov    $0xffffffff,%eax
  ret
L30:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int indx(s1, s2)
char *s1;
char *s2;
{
  register char *t;
  register char *p;
  register char *m;
  for (p = s1; *p; p++) {
    for (t = p, m = s2; *m && *m == *t; m++, t++)
      ;
    if (!*m)
      return (p - s1);
  }
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<indx>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L59
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
L20:
  test   %r8b,%r8b
  je     L38
  mov    %r8d,%ecx
  xor    %edx,%edx
  jmp    L39
  nopl   0x0(%rax)
L46:
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  je     L38
L39:
  cmp    %cl,(%rax,%rdx,1)
  je     L46
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L20
L59:
  mov    $0xffffffff,%eax
  ret
L38:
  sub    %edi,%eax
  ret
```

assistant: ```c
int indx(s1, s2)
char *s1;
char *s2;
{
  register char *t;
  register char *p;
  register char *m;
  for (p = s1; *p; p++) {
    for (t = p, m = s2; *m && *m == *t; m++, t++)
      ;
    if (!*m)
      return (p - s1);
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<indx>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
L10:
  test   %r8b,%r8b
  je     L57
  mov    %r8d,%ecx
  xor    %edx,%edx
  jmp    L15
  nopl   0x0(%rax)
L28:
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  je     L57
L15:
  cmp    %cl,(%rax,%rdx,1)
  je     L28
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L10
L6:
  mov    $0xffffffff,%eax
  ret
L57:
  sub    %edi,%eax
  ret
```

assistant: ```c
int indx(s1, s2)
char *s1;
char *s2;
{
  register char *t;
  register char *p;
  register char *m;
  for (p = s1; *p; p++) {
    for (t = p, m = s2; *m && *m == *t; m++, t++)
      ;
    if (!*m)
      return (p - s1);
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L30
  mov    $0x1,%eax
  jmp    L23
L30:
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L8
  mov    $0xffffffff,%eax
  jmp    L23
L8:
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  float x = *(const float *)a;
  float y = *(const float *)b;
  if (x > y)
    return 1;
  else if (x < y)
    return -1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L4
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  neg    %eax
L4:
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  float x = *(const float *)a;
  float y = *(const float *)b;
  if (x > y)
    return 1;
  else if (x < y)
    return -1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L3
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L3:
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  float x = *(const float *)a;
  float y = *(const float *)b;
  if (x > y)
    return 1;
  else if (x < y)
    return -1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L0
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L0:
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  float x = *(const float *)a;
  float y = *(const float *)b;
  if (x > y)
    return 1;
  else if (x < y)
    return -1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cpystr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L11
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
char *cpystr(const char *str) {
  char *s = calloc(strlen(str) + 1, sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, str);
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpystr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *cpystr(const char *str) {
  char *s = calloc(strlen(str) + 1, sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, str);
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cpystr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cpystr(const char *str) {
  char *s = calloc(strlen(str) + 1, sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, str);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cpystr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *cpystr(const char *str) {
  char *s = calloc(strlen(str) + 1, sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, str);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L32
L38:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L0:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x2,-0x14(%rbp)
  jle    L0
  addl   $0x1,-0x18(%rbp)
L32:
  cmpl   $0x6,-0x18(%rbp)
  jle    L38
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D24
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D24: sapxsumpw

tool: D22: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "sapxsumpw", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```