ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<makefilename>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *makefilename(const char *prefix, const char *suffix) {
  char *filename;
  filename = (char *)malloc((strlen(prefix) + strlen(suffix) + 1) * sizeof(char));
  strcpy(filename, prefix);
  strcat(filename, suffix);
  return (filename);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int2string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L39
L58:
  cmpl   $0x0,-0x14(%rbp)
  jns    L10
  negl   -0x14(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
L10:
  movl   $0x3b9aca00,-0x4(%rbp)
  jmp    L78
L8:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  test   %eax,%eax
  jne    L88
  cmpl   $0x0,-0x8(%rbp)
  jne    L88
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x30,(%rax)
  jmp    L34
L88:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  test   %eax,%eax
  je     L34
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L78:
  cmpl   $0x0,-0x4(%rbp)
  jg     L8
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
L39:
  pop    %rbp
  ret
```

assistant: ```c
void int2string(int n, char *s) {
  bool first = true;
  if (n == 0) {
    s[0] = '0';
    s[1] = 0;
    return;
  }
  if (n & (1u << 31)) {
    n = ~n + 1;
    *(s++) = '-';
  }
  for (int i = 1000000000; i > 0; i /= 10) {
    if (n / i == 0 && !first)
      *(s++) = '0';
    else if (n / i != 0) {
      *(s++) = '0' + n / i;
      n %= i;
      first = false;
    }
  }
  *s = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<int2string>:
  endbr64
  mov    %rsi,%r9
  test   %edi,%edi
  je     L36
  js     L48
L55:
  mov    $0xa,%r8d
  mov    $0x3b9aca00,%esi
  mov    $0x1,%r10d
  mov    $0x0,%r11d
  jmp    L20
L36:
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
  ret
L48:
  neg    %edi
  movb   $0x2d,(%rsi)
  lea    0x1(%rsi),%r9
  jmp    L55
L17:
  movb   $0x30,(%r9)
  mov    %edx,%r10d
  lea    0x1(%r9),%r9
L5:
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %esi,%eax
  sar    $0x1f,%eax
  mov    %ecx,%esi
  sub    %eax,%esi
  sub    $0x1,%r8d
  je     L9
L20:
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edx
  or     %r10d,%edx
  je     L17
  test   %eax,%eax
  je     L5
  add    $0x30,%eax
  mov    %al,(%r9)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%edi
  lea    0x1(%r9),%r9
  mov    %r11d,%r10d
  jmp    L5
L9:
  movb   $0x0,(%r9)
  ret
```

assistant: ```c
void int2string(int n, char *s) {
  bool first = true;
  if (n == 0) {
    s[0] = '0';
    s[1] = 0;
    return;
  }
  if (n & (1u << 31)) {
    n = ~n + 1;
    *(s++) = '-';
  }
  for (int i = 1000000000; i > 0; i /= 10) {
    if (n / i == 0 && !first)
      *(s++) = '0';
    else if (n / i != 0) {
      *(s++) = '0' + n / i;
      n %= i;
      first = false;
    }
  }
  *s = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<int2string>:
  endbr64
  test   %edi,%edi
  je     L2
  js     L5
L21:
  mov    $0xa,%r8d
  mov    $0x3b9aca00,%ecx
  mov    $0x1,%r9d
  jmp    L10
  nopl   (%rax)
L69:
  add    $0x30,%eax
  mov    %edx,%edi
  add    $0x1,%rsi
  xor    %r9d,%r9d
  mov    %al,-0x1(%rsi)
L66:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  mov    %edx,%ecx
  sub    %eax,%ecx
  sub    $0x1,%r8d
  je     L20
L10:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  jne    L69
  test   %r9d,%r9d
  jne    L66
  movb   $0x30,(%rsi)
  add    $0x1,%rsi
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L20:
  movb   $0x0,(%rsi)
  ret
  nopl   0x0(%rax)
L5:
  movb   $0x2d,(%rsi)
  neg    %edi
  add    $0x1,%rsi
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void int2string(int n, char *s) {
  bool first = true;
  if (n == 0) {
    s[0] = '0';
    s[1] = 0;
    return;
  }
  if (n & (1u << 31)) {
    n = ~n + 1;
    *(s++) = '-';
  }
  for (int i = 1000000000; i > 0; i /= 10) {
    if (n / i == 0 && !first)
      *(s++) = '0';
    else if (n / i != 0) {
      *(s++) = '0' + n / i;
      n %= i;
      first = false;
    }
  }
  *s = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sleep_then_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x34(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D25
datatype: string
name: read_data
arguments: data_label: D16
datatype: string

tool: D21: sleep

tool: D25: sleep done, reading

tool: D16: read(): %d -> '%s'


assistant: ```c
void sleep_then_read(void) {
  char buf[32] = {0};
  int rc;
  printf("sleep\n");
  sleep(2);
  printf("sleep done, reading\n");
  rc = read(0, buf, sizeof(buf));
  printf("read(): %d -> '%s'\n", rc, buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sleep_then_read>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D25: sleep

tool: D16: sleep done, reading

tool: D9: read(): %d -> '%s'


assistant: ```c
void sleep_then_read(void) {
  char buf[32] = {0};
  int rc;
  printf("sleep\n");
  sleep(2);
  printf("sleep done, reading\n");
  rc = read(0, buf, sizeof(buf));
  printf("read(): %d -> '%s'\n", rc, buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<sleep_then_read>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D12(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  mov    $0x20,%edx
  mov    %r12,%rsi
  call   <read@plt>
  mov    %r12,%rdx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D12: sleep

tool: D5: sleep done, reading

tool: D19: read(): %d -> '%s'


assistant: ```c
void sleep_then_read(void) {
  char buf[32] = {0};
  int rc;
  printf("sleep\n");
  sleep(2);
  printf("sleep done, reading\n");
  rc = read(0, buf, sizeof(buf));
  printf("read(): %d -> '%s'\n", rc, buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sleep_then_read>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  mov    $0x20,%edx
  mov    %r12,%rsi
  call   <read@plt>
  mov    %r12,%rdx
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string

tool: D14: sleep

tool: D26: sleep done, reading

tool: D20: read(): %d -> '%s'


assistant: ```c
void sleep_then_read(void) {
  char buf[32] = {0};
  int rc;
  printf("sleep\n");
  sleep(2);
  printf("sleep done, reading\n");
  rc = read(0, buf, sizeof(buf));
  printf("read(): %d -> '%s'\n", rc, buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readNBT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L9
L12:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <__recurReadNBT@plt>
L9:
  leave
  ret
```

assistant: ```c
int readNBT(struct nbt_tag **root, unsigned char *buffer, size_t buflen) {
  if (buflen == 0)
    return 0;
  return __recurReadNBT(root, buffer, buflen, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readNBT>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L5
  ret
L5:
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  call   <__recurReadNBT@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int readNBT(struct nbt_tag **root, unsigned char *buffer, size_t buflen) {
  if (buflen == 0)
    return 0;
  return __recurReadNBT(root, buffer, buflen, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readNBT>:
  endbr64
  test   %rdx,%rdx
  jne    L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L8:
  xor    %ecx,%ecx
  jmp    1050 <__recurReadNBT@plt>
```

assistant: ```c
int readNBT(struct nbt_tag **root, unsigned char *buffer, size_t buflen) {
  if (buflen == 0)
    return 0;
  return __recurReadNBT(root, buffer, buflen, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readNBT>:
  endbr64
  test   %rdx,%rdx
  jne    L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %ecx,%ecx
  jmp    1050 <__recurReadNBT@plt>
```

assistant: ```c
int readNBT(struct nbt_tag **root, unsigned char *buffer, size_t buflen) {
  if (buflen == 0)
    return 0;
  return __recurReadNBT(root, buffer, buflen, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RKMath_Clamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movss  %xmm1,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x20(%rbp),%xmm0
  jbe    L2
  movss  -0x20(%rbp),%xmm0
  jmp    L40
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L40:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  -0x1c(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L4
  movss  -0x1c(%rbp),%xmm0
  jmp    L10
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L51:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L50
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void RKMath_Clamp(float vec[], const float min, const float max, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = (vec[i] > max) ? max : vec[i];
    vec[i] = (vec[i] < min) ? min : vec[i];
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RKMath_Clamp>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L9:
  movaps %xmm1,%xmm2
  minss  (%rax),%xmm2
  movaps %xmm0,%xmm3
  maxss  %xmm2,%xmm3
  movss  %xmm3,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
L7:
  ret
```

assistant: ```c
void RKMath_Clamp(float vec[], const float min, const float max, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = (vec[i] > max) ? max : vec[i];
    vec[i] = (vec[i] < min) ? min : vec[i];
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RKMath_Clamp>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
L9:
  movaps %xmm1,%xmm2
  minss  (%rdi),%xmm2
  movaps %xmm0,%xmm3
  add    $0x4,%rdi
  maxss  %xmm2,%xmm3
  movss  %xmm3,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L9
L2:
  ret
```

assistant: ```c
void RKMath_Clamp(float vec[], const float min, const float max, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = (vec[i] > max) ? max : vec[i];
    vec[i] = (vec[i] < min) ? min : vec[i];
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RKMath_Clamp>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  test   %esi,%esi
  jle    L36
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L4
  shr    $0x2,%esi
  movaps %xmm1,%xmm5
  movaps %xmm0,%xmm4
  mov    %rdi,%rax
  sub    $0x1,%esi
  shufps $0x0,%xmm5,%xmm5
  shufps $0x0,%xmm4,%xmm4
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   (%rax)
L30:
  movups (%rax),%xmm6
  movaps %xmm5,%xmm3
  movaps %xmm4,%xmm2
  add    $0x10,%rax
  minps  %xmm6,%xmm3
  maxps  %xmm3,%xmm2
  movups %xmm2,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L30
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L60
L54:
  movslq %eax,%rsi
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm7
  shl    $0x2,%rsi
  lea    (%rcx,%rsi,1),%rdi
  minss  (%rdi),%xmm2
  maxss  %xmm2,%xmm7
  movss  %xmm7,(%rdi)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L36
  lea    0x4(%rcx,%rsi,1),%rdi
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm7
  add    $0x2,%eax
  minss  (%rdi),%xmm2
  maxss  %xmm2,%xmm7
  movss  %xmm7,(%rdi)
  cmp    %eax,%edx
  jle    L36
  lea    0x8(%rcx,%rsi,1),%rax
  minss  (%rax),%xmm1
  maxss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
L36:
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  ret
L4:
  xor    %eax,%eax
  jmp    L54
```

assistant: ```c
void RKMath_Clamp(float vec[], const float min, const float max, const int size) {
  int i = 0;
  while (i < size) {
    vec[i] = (vec[i] > max) ? max : vec[i];
    vec[i] = (vec[i] < min) ? min : vec[i];
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bitmap_find_first_bit@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L53
L28:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bitmap_find_next_zero_bit@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L77
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L48
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  jmp    L36
L48:
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <snprintf@plt>
  add    %eax,-0x8(%rbp)
L77:
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L7
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  jmp    L1
L7:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  call   <print_range@plt>
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bitmap_find_next_bit@plt>
  mov    %eax,-0xc(%rbp)
L53:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L28
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: ,

assistant: ```c
int bitmap_snprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int a, b;
  unsigned int len = 0;
  if (buflen > 0)
    buf[0] = '\0';
  a = bitmap_find_first_bit(maskp, nmaskbits);
  while (a < nmaskbits) {
    b = bitmap_find_next_zero_bit(maskp, nmaskbits, a + 1) - 1;
    if (len > 0)
      len += snprintf(buf + len, buflen > len ? buflen - len : 0, ",");
    len += print_range(buf + len, buflen > len ? buflen - len : 0, a, b);
    a = bitmap_find_next_bit(maskp, nmaskbits, b + 1);
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bitmap_snprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%r14d
  mov    %rdx,(%rsp)
  mov    %ecx,%r13d
  test   %esi,%esi
  je     L41
  movb   $0x0,(%rdi)
L41:
  mov    %r13d,%esi
  mov    (%rsp),%rdi
  call   <bitmap_find_first_bit@plt>
  mov    %eax,%ebp
  mov    $0x0,%ebx
  cmp    %eax,%r13d
  jle    L32
  lea    0x1(%rax),%edx
  mov    %r13d,%esi
  mov    (%rsp),%rdi
  call   <bitmap_find_next_zero_bit@plt>
  mov    %eax,%r12d
  lea    -0x1(%rax),%r15d
  mov    $0x0,%ebx
L42:
  mov    %r14d,%esi
  sub    %ebx,%esi
  cmp    %r14d,%ebx
  mov    $0x0,%eax
  cmovae %eax,%esi
  mov    %ebx,%edi
  add    0x8(%rsp),%rdi
  mov    %r15d,%ecx
  mov    %ebp,%edx
  call   <print_range@plt>
  add    %eax,%ebx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    (%rsp),%rdi
  call   <bitmap_find_next_bit@plt>
  mov    %eax,%ebp
  cmp    %eax,%r13d
  jle    L32
  lea    0x1(%rbp),%edx
  mov    %r13d,%esi
  mov    (%rsp),%rdi
  call   <bitmap_find_next_zero_bit@plt>
  mov    %eax,%r12d
  lea    -0x1(%rax),%r15d
  test   %ebx,%ebx
  je     L42
  mov    %r14d,%esi
  sub    %ebx,%esi
  cmp    %ebx,%r14d
  mov    $0x0,%eax
  cmovbe %eax,%esi
  mov    %ebx,%edi
  add    0x8(%rsp),%rdi
  lea    D3(%rip),%rdx
  call   <snprintf@plt>
  add    %eax,%ebx
  jmp    L42
L32:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: ,

assistant: ```c
int bitmap_snprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int a, b;
  unsigned int len = 0;
  if (buflen > 0)
    buf[0] = '\0';
  a = bitmap_find_first_bit(maskp, nmaskbits);
  while (a < nmaskbits) {
    b = bitmap_find_next_zero_bit(maskp, nmaskbits, a + 1) - 1;
    if (len > 0)
      len += snprintf(buf + len, buflen > len ? buflen - len : 0, ",");
    len += print_range(buf + len, buflen > len ? buflen - len : 0, a, b);
    a = bitmap_find_next_bit(maskp, nmaskbits, b + 1);
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_snprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  test   %esi,%esi
  je     L16
  movb   $0x0,(%rdi)
L16:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <bitmap_find_first_bit@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  cmp    %r12d,%ebx
  jle    L24
  lea    0x1(%r12),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %r15d,%r15d
  call   <bitmap_find_next_zero_bit@plt>
  mov    %eax,%r14d
  lea    -0x1(%rax),%ecx
  nopl   0x0(%rax)
L44:
  mov    %ebp,%esi
  xor    %eax,%eax
  mov    %r12d,%edx
  mov    %r15d,%edi
  sub    %r15d,%esi
  cmp    %ebp,%r15d
  cmovae %eax,%esi
  add    (%rsp),%rdi
  call   <print_range@plt>
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    %eax,%r15d
  call   <bitmap_find_next_bit@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jle    L43
  lea    0x1(%r12),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <bitmap_find_next_zero_bit@plt>
  mov    %eax,%r14d
  lea    -0x1(%rax),%ecx
  test   %r15d,%r15d
  je     L44
  mov    %ebp,%esi
  xor    %eax,%eax
  mov    %r15d,%edi
  mov    %ecx,0xc(%rsp)
  sub    %r15d,%esi
  cmp    %r15d,%ebp
  lea    D3(%rip),%rdx
  cmovbe %eax,%esi
  add    (%rsp),%rdi
  call   <snprintf@plt>
  mov    0xc(%rsp),%ecx
  add    %eax,%r15d
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %r15d,%eax
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: ,

assistant: ```c
int bitmap_snprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int a, b;
  unsigned int len = 0;
  if (buflen > 0)
    buf[0] = '\0';
  a = bitmap_find_first_bit(maskp, nmaskbits);
  while (a < nmaskbits) {
    b = bitmap_find_next_zero_bit(maskp, nmaskbits, a + 1) - 1;
    if (len > 0)
      len += snprintf(buf + len, buflen > len ? buflen - len : 0, ",");
    len += print_range(buf + len, buflen > len ? buflen - len : 0, a, b);
    a = bitmap_find_next_bit(maskp, nmaskbits, b + 1);
  }
  return len;
}
```