ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<isSubsequence>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  push   %rbp
  mov    $0xffffffff,%eax
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L32
  nop
L13:
  movsbl 0x0(%rbp),%edx
  add    $0x1,%rbp
  test   %dl,%dl
  je     L26
L32:
  lea    0x1(%rax),%esi
  mov    %rbx,%rdi
  call   <findFirstCharInd@plt>
  test   %eax,%eax
  jns    L13
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isSubsequence(char strOne[], char strTwo[]) {
  int indOne, indTwo;
  for (indOne = 0, indTwo = -1; strOne[indOne] != '\0'; indOne++) {
    indTwo = findFirstCharInd(strTwo, indTwo + 1, strOne[indOne]);
    if (indTwo < 0)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Epoch_Time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <Calendar_Date@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x38(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <Frac@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x40(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <DOY@plt>
  addsd  -0x40(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: f64
name: parse_data
arguments: tag: D4
type_guessed: byte[8]

tool: D7: 0.5

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
double Epoch_Time(double jd) {
  double yr, _time, epoch_time;
  struct tm edate;
  Calendar_Date(jd, &edate);
  yr = edate.tm_year - 100 * (edate.tm_year / 100);
  _time = Frac(jd + 0.5);
  epoch_time = yr * 1000 + DOY(edate.tm_year, edate.tm_mon, edate.tm_mday) + _time;
  return (epoch_time);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Epoch_Time>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdi
  call   <Calendar_Date@plt>
  mov    0x1c(%rsp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  pxor   %xmm2,%xmm2
  cvtsi2sd %edx,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movq   %rbx,%xmm3
  addsd  D19(%rip),%xmm3
  movapd %xmm3,%xmm0
  call   <Frac@plt>
  movq   %xmm0,%rbx
  mov    0x20(%rsp),%edx
  mov    0x24(%rsp),%esi
  mov    0x1c(%rsp),%edi
  call   <DOY@plt>
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movq   %rbx,%xmm4
  addsd  %xmm4,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: f64
name: retrieve_data
arguments: data_tag: D18
type_guessed: byte[8]

tool: D19: 0.5

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
double Epoch_Time(double jd) {
  double yr, _time, epoch_time;
  struct tm edate;
  Calendar_Date(jd, &edate);
  yr = edate.tm_year - 100 * (edate.tm_year / 100);
  _time = Frac(jd + 0.5);
  epoch_time = yr * 1000 + DOY(edate.tm_year, edate.tm_mon, edate.tm_mday) + _time;
  return (epoch_time);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Epoch_Time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdi
  movsd  %xmm0,(%rsp)
  call   <Calendar_Date@plt>
  movslq 0x1c(%rsp),%rax
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  addsd  D14(%rip),%xmm0
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rax
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Frac@plt>
  mov    0x20(%rsp),%edx
  mov    0x24(%rsp),%esi
  mov    0x1c(%rsp),%edi
  movsd  %xmm0,(%rsp)
  call   <DOY@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D4(%rip),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  (%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_infered: f64
name: disassemble_data
arguments: tag: D4
type_infered: byte[8]

tool: D14: 0.5

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
double Epoch_Time(double jd) {
  double yr, _time, epoch_time;
  struct tm edate;
  Calendar_Date(jd, &edate);
  yr = edate.tm_year - 100 * (edate.tm_year / 100);
  _time = Frac(jd + 0.5);
  epoch_time = yr * 1000 + DOY(edate.tm_year, edate.tm_mon, edate.tm_mday) + _time;
  return (epoch_time);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Epoch_Time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdi
  movsd  %xmm0,(%rsp)
  call   <Calendar_Date@plt>
  movslq 0x1c(%rsp),%rax
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  addsd  D18(%rip),%xmm0
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x25,%rax
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Frac@plt>
  mov    0x20(%rsp),%edx
  mov    0x24(%rsp),%esi
  mov    0x1c(%rsp),%edi
  movsd  %xmm0,(%rsp)
  call   <DOY@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D4(%rip),%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  (%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: f64
name: retrieve_data
arguments: data_label: D4
type: byte[8]

tool: D18: 0.5

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
double Epoch_Time(double jd) {
  double yr, _time, epoch_time;
  struct tm edate;
  Calendar_Date(jd, &edate);
  yr = edate.tm_year - 100 * (edate.tm_year / 100);
  _time = Frac(jd + 0.5);
  epoch_time = yr * 1000 + DOY(edate.tm_year, edate.tm_mon, edate.tm_mday) + _time;
  return (epoch_time);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned long get_time_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000 + tv.tv_usec / 1000);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_time_ms>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  cltq
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_time_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000 + tv.tv_usec / 1000);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_time_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  cltq
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_time_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000 + tv.tv_usec / 1000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_time_ms>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  cltq
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_time_ms(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (tv.tv_sec * 1000 + tv.tv_usec / 1000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kstrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int kstrlen(const char *s) {
  int n;
  for (n = 0; s[n]; n++)
    ;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kstrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
L23:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L23
L24:
  mov    %edx,%eax
  ret
L1:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int kstrlen(const char *s) {
  int n;
  for (n = 0; s[n]; n++)
    ;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kstrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L8
  mov    $0x1,%eax
  xchg   %ax,%ax
L4:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L4
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int kstrlen(const char *s) {
  int n;
  for (n = 0; s[n]; n++)
    ;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kstrlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  xchg   %ax,%ax
L18:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int kstrlen(const char *s) {
  int n;
  for (n = 0; s[n]; n++)
    ;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<expt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jg     L16
  mov    $0x1,%eax
  jmp    L31
L16:
  cmpl   $0x1,-0x18(%rbp)
  jne    L45
  mov    -0x14(%rbp),%eax
  jmp    L31
L45:
  mov    -0x18(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <expt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
L31:
  leave
  ret
```

assistant: ```c
intmax_t expt(intmax_t base, intmax_t power) {
  if (power <= 0) {
    return 1;
  } else if (power == 1) {
    return base;
  } else {
    intmax_t tmp = expt(base, power >> 1);
    tmp *= tmp;
    if (power & 1) {
      tmp *= base;
    }
    return tmp;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<expt>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jle    L29
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%esi
  jne    L11
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  sar    %esi
  call   <expt>
  imul   %eax,%eax
  test   $0x1,%bl
  je     L13
  imul   %ebp,%eax
  jmp    L13
L29:
  ret
```

assistant: ```c
intmax_t expt(intmax_t base, intmax_t power) {
  if (power <= 0) {
    return 1;
  } else if (power == 1) {
    return base;
  } else {
    intmax_t tmp = expt(base, power >> 1);
    tmp *= tmp;
    if (power & 1) {
      tmp *= base;
    }
    return tmp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<expt>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jle    L70
  push   %r13
  mov    %edi,%eax
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jne    L23
L80:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L23:
  mov    %esi,%r12d
  sar    %r12d
  cmp    $0x1,%r12d
  jne    L0
L82:
  imul   %eax,%eax
  and    $0x1,%ebx
  je     L80
  add    $0x10,%rsp
  imul   %edi,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L70:
  ret
  nopl   0x0(%rax)
L0:
  mov    %esi,%r13d
  sar    $0x2,%r13d
  cmp    $0x1,%r13d
  je     L34
  sar    $0x3,%esi
  mov    %edi,0xc(%rsp)
  call   <expt>
  mov    0xc(%rsp),%edi
  imul   %eax,%eax
  and    $0x1,%r13d
  jne    L32
L34:
  imul   %eax,%eax
  and    $0x1,%r12d
  je     L82
  imul   %edi,%eax
  jmp    L82
  nopl   0x0(%rax)
L32:
  imul   %edi,%eax
  jmp    L34
```

assistant: ```c
intmax_t expt(intmax_t base, intmax_t power) {
  if (power <= 0) {
    return 1;
  } else if (power == 1) {
    return base;
  } else {
    intmax_t tmp = expt(base, power >> 1);
    tmp *= tmp;
    if (power & 1) {
      tmp *= base;
    }
    return tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<expt>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jle    L44
  push   %r13
  mov    %edi,%eax
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jne    L70
L0:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L70:
  mov    %esi,%r12d
  sar    %r12d
  cmp    $0x1,%r12d
  jne    L71
L87:
  imul   %eax,%eax
  and    $0x1,%ebx
  je     L0
  add    $0x10,%rsp
  imul   %edi,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L44:
  ret
  nopl   0x0(%rax)
L71:
  mov    %esi,%r13d
  sar    $0x2,%r13d
  cmp    $0x1,%r13d
  je     L80
  sar    $0x3,%esi
  mov    %edi,0xc(%rsp)
  call   <expt>
  mov    0xc(%rsp),%edi
  imul   %eax,%eax
  and    $0x1,%r13d
  jne    L76
L80:
  imul   %eax,%eax
  and    $0x1,%r12d
  je     L87
  imul   %edi,%eax
  jmp    L87
  nopl   0x0(%rax)
L76:
  imul   %edi,%eax
  jmp    L80
```

assistant: ```c
intmax_t expt(intmax_t base, intmax_t power) {
  if (power <= 0) {
    return 1;
  } else if (power == 1) {
    return base;
  } else {
    intmax_t tmp = expt(base, power >> 1);
    tmp *= tmp;
    if (power & 1) {
      tmp *= base;
    }
    return tmp;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<set_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  movabs $0x842108421084211,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x4,%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  movabs $0x842108421084211,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x4,%rax
  mov    %rax,%rdx
  shl    $0x5,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L4
  cmpl   $0x0,-0xc(%rbp)
  jg     L4
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_mask(unsigned int *mask, int e) {
  int w;
  unsigned int m, n;
  w = e / (8 * sizeof(int) - 1);
  n = 1;
  m = (n << e % (8 * sizeof(int) - 1));
  if (w >= 0 && w < (((2 * (12) + 2)) / (4 * 8) + 1)) {
    mask[w] |= m;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_mask>:
  endbr64
  movslq %esi,%rcx
  movabs $0x842108421084211,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x4,%rdx
  test   %edx,%edx
  jne    L5
  movabs $0x842108421084211,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x4,%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,(%rdi)
L5:
  ret
```

assistant: ```c
void set_mask(unsigned int *mask, int e) {
  int w;
  unsigned int m, n;
  w = e / (8 * sizeof(int) - 1);
  n = 1;
  m = (n << e % (8 * sizeof(int) - 1));
  if (w >= 0 && w < (((2 * (12) + 2)) / (4 * 8) + 1)) {
    mask[w] |= m;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_mask>:
  endbr64
  movabs $0x842108421084211,%rdx
  movslq %esi,%rcx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x4,%rdx
  test   %edx,%edx
  jne    L5
  mov    %rdx,%rax
  shl    $0x5,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,(%rdi)
L5:
  ret
```

assistant: ```c
void set_mask(unsigned int *mask, int e) {
  int w;
  unsigned int m, n;
  w = e / (8 * sizeof(int) - 1);
  n = 1;
  m = (n << e % (8 * sizeof(int) - 1));
  if (w >= 0 && w < (((2 * (12) + 2)) / (4 * 8) + 1)) {
    mask[w] |= m;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_mask>:
  endbr64
  movabs $0x842108421084211,%rdx
  movslq %esi,%rcx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x4,%rdx
  test   %edx,%edx
  jne    L1
  mov    %rdx,%rax
  shl    $0x5,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    $0x1,%eax
  shl    %cl,%eax
  or     %eax,(%rdi)
L1:
  ret
```

assistant: ```c
void set_mask(unsigned int *mask, int e) {
  int w;
  unsigned int m, n;
  w = e / (8 * sizeof(int) - 1);
  n = 1;
  m = (n << e % (8 * sizeof(int) - 1));
  if (w >= 0 && w < (((2 * (12) + 2)) / (4 * 8) + 1)) {
    mask[w] |= m;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x1c0(%rbp)
  movl   $0xb,-0x1bc(%rbp)
  movl   $0x2,-0x1b8(%rbp)
  movl   $0x9,-0x1b4(%rbp)
  movl   $0x1,-0x1b0(%rbp)
  movl   $0x5,-0x1ac(%rbp)
  movl   $0x0,-0x1c4(%rbp)
  jmp    L77
L71:
  mov    -0x1c4(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1c4(%rbp)
L77:
  cmpl   $0x63,-0x1c4(%rbp)
  jle    L71
  movl   $0x0,-0x1c4(%rbp)
  jmp    L79
L0:
  mov    -0x1c4(%rbp),%eax
  cltq
  mov    -0x1c0(%rbp,%rax,4),%eax
  cltq
  movl   $0x1,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1c4(%rbp)
L79:
  cmpl   $0x5,-0x1c4(%rbp)
  jle    L0
  movl   $0x0,-0x1c4(%rbp)
  jmp    L1
L26:
  mov    -0x1c4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L38
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  addl   $0x1,-0x1c4(%rbp)
L1:
  cmpl   $0x63,-0x1c4(%rbp)
  jle    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D9:  %d

assistant: ```c
int main() {
  int a[6] = {3, 11, 2, 9, 1, 5};
  int b[100];
  int i;
  for (i = 0; i < 100; i++) {
    b[i] = 0;
  }
  for (i = 0; i < 6; i++) {
    b[a[i]] = 1;
  }
  for (i = 0; i < 100; i++) {
    if (b[i] == 1)
      printf(" %d", i);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  lea    0x20(%rsp),%rax
  lea    0x1b0(%rsp),%rdx
L47:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L47
  mov    %rsp,%rax
  lea    0x18(%rsp),%rcx
L41:
  movslq (%rax),%rdx
  movl   $0x1,0x20(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L41
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
  jmp    L34
L27:
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L38
L34:
  mov    %ebx,%esi
  cmpl   $0x1,0x20(%rsp,%rbx,4)
  jne    L27
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L38:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5:  %d

assistant: ```c
int main() {
  int a[6] = {3, 11, 2, 9, 1, 5};
  int b[100];
  int i;
  for (i = 0; i < 100; i++) {
    b[i] = 0;
  }
  for (i = 0; i < 6; i++) {
    b[a[i]] = 1;
  }
  for (i = 0; i < 100; i++) {
    if (b[i] == 1)
      printf(" %d", i);
  }
  printf("\n");
  return 0;
}
```