ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log_fn>:
  endbr64
  push   %r12
  mov    %r8,%rsi
  lea    D1(%rip),%rdi
  push   %rbp
  mov    %r9,%rbp
  sub    $0x8,%rsp
  mov    0x20(%rsp),%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    %r12d,%esi
  pop    %rbp
  pop    %r12
  jmp    1070 <vprintf@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: test-libudev: %s %s:%d 

assistant: ```c
void log_fn(struct udev *udev, int priority, const char *file, int line, const char *fn, const char *format, va_list args) {
  printf("test-libudev: %s %s:%d ", fn, file, line);
  vprintf(format, args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<loulou>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: LOULOU !


assistant: ```c
void loulou(void) {
  printf("LOULOU !\n");
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<loulou>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: LOULOU !


assistant: ```c
void loulou(void) {
  printf("LOULOU !\n");
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<loulou>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: LOULOU !


assistant: ```c
void loulou(void) {
  printf("LOULOU !\n");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<loulou>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: LOULOU !


assistant: ```c
void loulou(void) {
  printf("LOULOU !\n");
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<export>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L25:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L42
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L42
  cmpl   $0x2,-0x4(%rbp)
  je     L42
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    %eax,-0x8(%rbp)
L42:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L25
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int export(char **args) {
  int state = -1;
  int i = 1;
  while (args[i]) {
    if (strlen(args[i - 1]) == 1 && args[i - 1][0] == '=' && i != 2) {
      state = setenv(args[i - 2], args[i], 1);
    }
    i++;
  }
  return state;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<export>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,0x8(%rdi)
  je     L61
  lea    0x8(%rdi),%rbx
  mov    $0x1,%ebp
  mov    $0xffffffff,%r12d
  jmp    L29
L43:
  add    $0x1,%ebp
  add    $0x8,%rbx
  cmpq   $0x0,(%rbx)
  je     L30
L29:
  mov    -0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L43
  mov    -0x8(%rbx),%rax
  cmpb   $0x3d,(%rax)
  jne    L43
  cmp    $0x2,%ebp
  je     L43
  mov    -0x10(%rbx),%rdi
  mov    $0x1,%edx
  mov    (%rbx),%rsi
  call   <setenv@plt>
  mov    %eax,%r12d
  jmp    L43
L61:
  mov    $0xffffffff,%r12d
L30:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int export(char **args) {
  int state = -1;
  int i = 1;
  while (args[i]) {
    if (strlen(args[i - 1]) == 1 && args[i - 1][0] == '=' && i != 2) {
      state = setenv(args[i - 2], args[i], 1);
    }
    i++;
  }
  return state;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<export>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,0x8(%rdi)
  je     L52
  lea    0x8(%rdi),%rbx
  mov    $0x1,%ebp
  mov    $0xffffffff,%r12d
  jmp    L2
L32:
  add    $0x8,%rbx
  add    $0x1,%ebp
  cmpq   $0x0,(%rbx)
  je     L28
L2:
  mov    -0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L32
  mov    -0x8(%rbx),%rax
  cmpb   $0x3d,(%rax)
  jne    L32
  cmp    $0x2,%ebp
  je     L32
  mov    -0x10(%rbx),%rdi
  mov    (%rbx),%rsi
  mov    $0x1,%edx
  add    $0x8,%rbx
  add    $0x1,%ebp
  call   <setenv@plt>
  cmpq   $0x0,(%rbx)
  mov    %eax,%r12d
  jne    L2
L28:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int export(char **args) {
  int state = -1;
  int i = 1;
  while (args[i]) {
    if (strlen(args[i - 1]) == 1 && args[i - 1][0] == '=' && i != 2) {
      state = setenv(args[i - 2], args[i], 1);
    }
    i++;
  }
  return state;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<export>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,0x8(%rdi)
  je     L50
  lea    0x8(%rdi),%rbx
  mov    $0x1,%ebp
  mov    $0xffffffff,%r12d
  jmp    L48
L26:
  add    $0x8,%rbx
  add    $0x1,%ebp
  cmpq   $0x0,(%rbx)
  je     L66
L48:
  mov    -0x8(%rbx),%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L26
  mov    -0x8(%rbx),%rax
  cmpb   $0x3d,(%rax)
  jne    L26
  cmp    $0x2,%ebp
  je     L26
  mov    -0x10(%rbx),%rdi
  mov    (%rbx),%rsi
  mov    $0x1,%edx
  add    $0x8,%rbx
  add    $0x1,%ebp
  call   <setenv@plt>
  cmpq   $0x0,(%rbx)
  mov    %eax,%r12d
  jne    L48
L66:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int export(char **args) {
  int state = -1;
  int i = 1;
  while (args[i]) {
    if (strlen(args[i - 1]) == 1 && args[i - 1][0] == '=' && i != 2) {
      state = setenv(args[i - 2], args[i], 1);
    }
    i++;
  }
  return state;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<realtek_mst_i2c_spi_write_register>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%ecx
  mov    $0x4a,%esi
  mov    %eax,%edi
  call   <realtek_mst_i2c_spi_write_data@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int realtek_mst_i2c_spi_write_register(int fd, uint8_t reg, uint8_t value) {
  uint8_t command[] = {reg, value};
  return realtek_mst_i2c_spi_write_data(fd, (0x94 >> 1), command, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<realtek_mst_i2c_spi_write_register>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %rsp,%rdx
  mov    $0x2,%ecx
  mov    $0x4a,%esi
  call   <realtek_mst_i2c_spi_write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int realtek_mst_i2c_spi_write_register(int fd, uint8_t reg, uint8_t value) {
  uint8_t command[] = {reg, value};
  return realtek_mst_i2c_spi_write_data(fd, (0x94 >> 1), command, 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<realtek_mst_i2c_spi_write_register>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    $0x4a,%esi
  mov    %edx,0x4(%rsp)
  mov    %rsp,%rdx
  call   <realtek_mst_i2c_spi_write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int realtek_mst_i2c_spi_write_register(int fd, uint8_t reg, uint8_t value) {
  uint8_t command[] = {reg, value};
  return realtek_mst_i2c_spi_write_data(fd, (0x94 >> 1), command, 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<realtek_mst_i2c_spi_write_register>:
  endbr64
  sub    $0x18,%rsp
  movd   %esi,%xmm0
  movd   %edx,%xmm1
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rdx
  mov    $0x4a,%esi
  movq   %xmm0,(%rsp)
  call   <realtek_mst_i2c_spi_write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int realtek_mst_i2c_spi_write_register(int fd, uint8_t reg, uint8_t value) {
  uint8_t command[] = {reg, value};
  return realtek_mst_i2c_spi_write_data(fd, (0x94 >> 1), command, 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findPairs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L31:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L20
L4:
  subl   $0x1,-0x8(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L31
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findPairs(int array[], int n, int x) {
  int l = 0;
  int r = n - 1;
  int result = 0;
  while (l < r) {
    if (array[l] + array[r] < x) {
      result += (r - 1);
      l++;
    } else
      r--;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findPairs>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L26
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  jmp    L38
L39:
  sub    $0x1,%esi
L43:
  cmp    %r8d,%esi
  jle    L34
L38:
  movslq %r8d,%rcx
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%eax
  add    (%rdi,%rcx,4),%eax
  cmp    %edx,%eax
  jge    L39
  lea    -0x1(%rsi,%r9,1),%r9d
  add    $0x1,%r8d
  jmp    L43
L26:
  mov    $0x0,%r9d
L34:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int findPairs(int array[], int n, int x) {
  int l = 0;
  int r = n - 1;
  int result = 0;
  while (l < r) {
    if (array[l] + array[r] < x) {
      result += (r - 1);
      l++;
    } else
      r--;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findPairs>:
  endbr64
  sub    $0x1,%esi
  xor    %r10d,%r10d
  test   %esi,%esi
  jle    L24
  xor    %r8d,%r8d
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r8d
  add    %r9d,%r10d
  cmp    %r8d,%esi
  jle    L24
L19:
  movslq %r8d,%rcx
  movslq %esi,%rax
  lea    -0x1(%rsi),%r9d
  mov    (%rdi,%rax,4),%eax
  add    (%rdi,%rcx,4),%eax
  cmp    %edx,%eax
  jl     L18
  mov    %r9d,%esi
  cmp    %r8d,%esi
  jg     L19
L24:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int findPairs(int array[], int n, int x) {
  int l = 0;
  int r = n - 1;
  int result = 0;
  while (l < r) {
    if (array[l] + array[r] < x) {
      result += (r - 1);
      l++;
    } else
      r--;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findPairs>:
  endbr64
  lea    -0x1(%rsi),%r11d
  push   %r12
  test   %r11d,%r11d
  jle    L27
  mov    %rdi,%r8
  lea    -0x2(%rsi),%ecx
  xor    %r12d,%r12d
  xor    %edi,%edi
  movslq %r11d,%r9
  xor    %esi,%esi
  nop
L23:
  mov    (%r8,%rsi,4),%eax
  add    (%r8,%r9,4),%eax
  mov    %ecx,%r10d
  cmp    %eax,%edx
  jle    L11
L39:
  add    $0x1,%edi
  add    %ecx,%r12d
  cmp    %r11d,%edi
  jge    L17
  movslq %edi,%rsi
  mov    %ecx,%r10d
  mov    (%r8,%rsi,4),%eax
  add    (%r8,%r9,4),%eax
  cmp    %eax,%edx
  jg     L39
L11:
  cmp    %edi,%ecx
  jle    L17
  mov    %ecx,%r11d
  movslq %r10d,%r9
  sub    $0x1,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %r12d,%r12d
L17:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int findPairs(int array[], int n, int x) {
  int l = 0;
  int r = n - 1;
  int result = 0;
  while (l < r) {
    if (array[l] + array[r] < x) {
      result += (r - 1);
      l++;
    } else
      r--;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_an_allocation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int do_an_allocation() {
  int *a = malloc(sizeof(int));
  int *b = a;
  *a = 4;
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_an_allocation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x4,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_an_allocation() {
  int *a = malloc(sizeof(int));
  int *b = a;
  *a = 4;
  return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_an_allocation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x4,(%rax)
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_an_allocation() {
  int *a = malloc(sizeof(int));
  int *b = a;
  *a = 4;
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x61,-0x1(%rbp)
  jmp    L18
L1:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L18:
  cmpb   $0x7a,-0x1(%rbp)
  jle    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z') {
    ft_putchar(c);
    c++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
L0:
  mov    %ebx,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z') {
    ft_putchar(c);
    c++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z') {
    ft_putchar(c);
    c++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  char c;
  c = 'a';
  while (c <= 'z') {
    ft_putchar(c);
    c++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBDevLPMConfig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x362,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBDevLPMConfig(uint32_t ui32Base, uint32_t ui32Config) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) = ui32Config;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<USBDevLPMConfig>:
  endbr64
  mov    %rsi,0x362(%rdi)
  ret
```

assistant: ```c
void USBDevLPMConfig(uint32_t ui32Base, uint32_t ui32Config) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) = ui32Config;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<USBDevLPMConfig>:
  endbr64
  mov    %rsi,0x362(%rdi)
  ret
```

assistant: ```c
void USBDevLPMConfig(uint32_t ui32Base, uint32_t ui32Config) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) = ui32Config;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBDevLPMConfig>:
  endbr64
  mov    %rsi,0x362(%rdi)
  ret
```

assistant: ```c
void USBDevLPMConfig(uint32_t ui32Base, uint32_t ui32Config) {
  ;
  (*((volatile uint8_t *)(ui32Base + 0x00000362))) = ui32Config;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int *f(void) {
  int x;
  return &x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int *f(void) {
  int x;
  return &x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int *f(void) {
  int x;
  return &x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int *f(void) {
  int x;
  return &x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0xb,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x16,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x17,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D46
type: string

tool: D13: Pow(2, 11) = %lld


tool: D34: Pow(2, 22) = %lld


tool: D11: Pow(2, 23) = %lld


tool: D33: Pow(2, 24) = %lld


tool: D46: Pow(2, 25) = %lld


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Pow(2, 11) = %lld\n", high_pow(2, 11));
  printf("Pow(2, 22) = %lld\n", high_pow(2, 22));
  printf("Pow(2, 23) = %lld\n", high_pow(2, 23));
  printf("Pow(2, 24) = %lld\n", high_pow(2, 24));
  printf("Pow(2, 25) = %lld\n", high_pow(2, 31));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x16,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type: string
name: parse_data
arguments: tag: D48
type: string
name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D33
type: string

tool: D17: Pow(2, 11) = %lld


tool: D48: Pow(2, 22) = %lld


tool: D6: Pow(2, 23) = %lld


tool: D15: Pow(2, 24) = %lld


tool: D33: Pow(2, 25) = %lld


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Pow(2, 11) = %lld\n", high_pow(2, 11));
  printf("Pow(2, 22) = %lld\n", high_pow(2, 22));
  printf("Pow(2, 23) = %lld\n", high_pow(2, 23));
  printf("Pow(2, 24) = %lld\n", high_pow(2, 24));
  printf("Pow(2, 25) = %lld\n", high_pow(2, 31));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x16,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x17,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  lea    D47(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x18,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1f,%esi
  mov    $0x2,%edi
  call   <high_pow@plt>
  lea    D45(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D23
type_guessed: string
name: unpack_data
arguments: label: D45
type_guessed: string

tool: D0: Pow(2, 11) = %lld


tool: D6: Pow(2, 22) = %lld


tool: D47: Pow(2, 23) = %lld


tool: D23: Pow(2, 24) = %lld


tool: D45: Pow(2, 25) = %lld


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Pow(2, 11) = %lld\n", high_pow(2, 11));
  printf("Pow(2, 22) = %lld\n", high_pow(2, 22));
  printf("Pow(2, 23) = %lld\n", high_pow(2, 23));
  printf("Pow(2, 24) = %lld\n", high_pow(2, 24));
  printf("Pow(2, 25) = %lld\n", high_pow(2, 31));
  return 0;
}
```