ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strindexv2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L12:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L14:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L14
L23:
  cmpl   $0x0,-0x4(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  jmp    L10
L1:
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0xffffffff,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int strindexv2(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return (j - 1);
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strindexv2>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L50
  movzbl (%rsi),%r10d
  mov    $0x0,%r9d
  jmp    L34
L63:
  movzbl 0x1(%rdi,%r9,1),%eax
  add    $0x1,%r9
  sub    $0x1,%rsi
  test   %al,%al
  je     L45
L34:
  mov    %r9,%rax
  mov    %r10d,%edx
  mov    $0x0,%ecx
  test   %r10b,%r10b
  je     L63
L36:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  jne    L7
  lea    0x1(%rax),%r8d
  add    $0x1,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L36
L7:
  test   %dl,%dl
  jne    L63
  test   %ecx,%ecx
  jle    L63
  lea    -0x1(%r8),%eax
  ret
L50:
  mov    $0xffffffff,%eax
  ret
L45:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strindexv2(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return (j - 1);
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindexv2>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L40
  movzbl (%rsi),%r9d
  xor    %ecx,%ecx
  nop
L33:
  mov    %rcx,%rax
  mov    %r9d,%edx
  test   %r9b,%r9b
  jne    L30
  jmp    L7
  nopl   (%rax)
L42:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L28
L30:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  je     L42
L7:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L33
L40:
  mov    $0xffffffff,%r8d
L28:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strindexv2(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return (j - 1);
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strindexv2>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L35
  movzbl (%rsi),%r9d
  xor    %ecx,%ecx
  nop
L59:
  mov    %rcx,%rax
  mov    %r9d,%edx
  test   %r9b,%r9b
  jne    L40
  jmp    L50
  nopl   (%rax)
L48:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L9
L40:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  je     L48
L50:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L59
L35:
  mov    $0xffffffff,%r8d
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strindexv2(char s[], char t[]) {
  int i, j, k;
  for (i = 0; s[i] != '\0'; i++) {
    for (j = i, k = 0; t[k] != '\0' && s[j] == t[k]; j++, k++)
      ;
    if (k > 0 && t[k] == '\0')
      return (j - 1);
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ComputeSimpleChecksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ComputeSimpleChecksum(const unsigned char *dataPointer, int dataLength) {
  unsigned int checksum = 0;
  for (int i = 1; i <= dataLength; i++) {
    checksum += (*dataPointer) * i;
    ++dataPointer;
  }
  return checksum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ComputeSimpleChecksum>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%r8
  mov    %rdi,%rax
  mov    $0x0,%ecx
  mov    $0x1,%r9d
  sub    %edi,%r9d
L11:
  lea    (%r9,%rax,1),%edx
  movzbl (%rax),%esi
  imul   %esi,%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L11
L1:
  mov    %ecx,%eax
  ret
L7:
  mov    $0x0,%ecx
  jmp    L1
```

assistant: ```c
unsigned int ComputeSimpleChecksum(const unsigned char *dataPointer, int dataLength) {
  unsigned int checksum = 0;
  for (int i = 1; i <= dataLength; i++) {
    checksum += (*dataPointer) * i;
    ++dataPointer;
  }
  return checksum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ComputeSimpleChecksum>:
  endbr64
  test   %esi,%esi
  jle    L19
  movslq %esi,%rsi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,1),%rcx
  mov    $0x1,%esi
  sub    %edi,%esi
  nopl   0x0(%rax)
L11:
  movzbl (%rdi),%edx
  lea    (%rsi,%rdi,1),%eax
  add    $0x1,%rdi
  imul   %edx,%eax
  add    %eax,%r8d
  cmp    %rcx,%rdi
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ComputeSimpleChecksum(const unsigned char *dataPointer, int dataLength) {
  unsigned int checksum = 0;
  for (int i = 1; i <= dataLength; i++) {
    checksum += (*dataPointer) * i;
    ++dataPointer;
  }
  return checksum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_region_name_FJ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  ja     L47
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D41(%rip),%rax
  jmp    L14
  lea    D37(%rip),%rax
  jmp    L14
  lea    D40(%rip),%rax
  jmp    L14
  lea    D46(%rip),%rax
  jmp    L14
  lea    D39(%rip),%rax
  jmp    L14
L47:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D41
datatype: string
name: retrieve_data
arguments: label: D37
datatype: string
name: retrieve_data
arguments: label: D40
datatype: string
name: retrieve_data
arguments: label: D46
datatype: string
name: retrieve_data
arguments: label: D39
datatype: string

tool: D41: Central

tool: D37: Eastern

tool: D40: Northern

tool: D46: Rotuma

tool: D39: Western

assistant: ```c
const char *get_region_name_FJ(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 2:
    return "Eastern";
  case 3:
    return "Northern";
  case 4:
    return "Rotuma";
  case 5:
    return "Western";
  default:
    return NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_region_name_FJ>:
  endbr64
  cmp    $0x5,%edi
  ja     L8
  mov    %edi,%edi
  lea    D0(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D33(%rip),%rax
  ret
  lea    D27(%rip),%rax
  ret
  lea    D49(%rip),%rax
  ret
  lea    D5(%rip),%rax
  ret
L8:
  mov    $0x0,%eax
  ret
  lea    D36(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D49
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string

tool: D33: Eastern

tool: D27: Northern

tool: D49: Rotuma

tool: D5: Western

tool: D36: Central

assistant: ```c
const char *get_region_name_FJ(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 2:
    return "Eastern";
  case 3:
    return "Northern";
  case 4:
    return "Rotuma";
  case 5:
    return "Western";
  default:
    return NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_region_name_FJ>:
  endbr64
  cmp    $0x5,%edi
  ja     L9
  lea    D23(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D11(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D1(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D24(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D47(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D39(%rip),%rax
  ret
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D39
type_guessed: string

tool: D11: Eastern

tool: D1: Central

tool: D24: Western

tool: D47: Northern

tool: D39: Rotuma

assistant: ```c
const char *get_region_name_FJ(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 2:
    return "Eastern";
  case 3:
    return "Northern";
  case 4:
    return "Rotuma";
  case 5:
    return "Western";
  default:
    return NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_region_name_FJ>:
  endbr64
  cmp    $0x5,%edi
  ja     L5
  lea    D22(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D3(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D14(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D27(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D43(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D26(%rip),%rax
  ret
L5:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D43
datatype: string
name: disassemble_data
arguments: tag: D26
datatype: string

tool: D3: Eastern

tool: D14: Central

tool: D27: Western

tool: D43: Northern

tool: D26: Rotuma

assistant: ```c
const char *get_region_name_FJ(int region_code) {
  switch (region_code) {
  case 1:
    return "Central";
  case 2:
    return "Eastern";
  case 3:
    return "Northern";
  case 4:
    return "Rotuma";
  case 5:
    return "Western";
  default:
    return NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<binary_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x2b,-0x17(%rbp)
  movb   $0x0,-0x15(%rbp)
  movw   $0x2d,-0x14(%rbp)
  movb   $0x0,-0x12(%rbp)
  movw   $0x2a,-0x11(%rbp)
  movb   $0x0,-0xf(%rbp)
  movw   $0x25,-0xe(%rbp)
  movb   $0x0,-0xc(%rbp)
  movw   $0x21,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L43
  mov    $0x0,%eax
  jmp    L38
L43:
  movl   $0x0,-0x1c(%rbp)
  jmp    L0
L50:
  lea    -0x17(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x1,%eax
  jmp    L38
L17:
  addl   $0x1,-0x1c(%rbp)
L0:
  cmpl   $0x4,-0x1c(%rbp)
  jle    L50
  mov    $0x0,%eax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int binary_check(char *symbol) {
  char operations[5][3] = {"+", "-", "*", "%", "!"};
  int j = 0;
  if (strcmp(symbol, "") == 0)
    return 0;
  for (j = 0; j < 5; j++)
    if (strcmp(symbol, operations[j]) == 0)
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary_check>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x2b,0x9(%rsp)
  movb   $0x0,0xb(%rsp)
  movw   $0x2d,0xc(%rsp)
  movb   $0x0,0xe(%rsp)
  movw   $0x2a,0xf(%rsp)
  movb   $0x0,0x11(%rsp)
  movw   $0x25,0x12(%rsp)
  movb   $0x0,0x14(%rsp)
  movw   $0x21,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  cmpb   $0x0,(%rdi)
  je     L9
  mov    %rdi,%rbp
  lea    0x9(%rsp),%rbx
  lea    0x18(%rsp),%r12
L49:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L44
  add    $0x3,%rbx
  cmp    %r12,%rbx
  jne    L49
  mov    $0x0,%eax
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0x1,%eax
  jmp    L9
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binary_check(char *symbol) {
  char operations[5][3] = {"+", "-", "*", "%", "!"};
  int j = 0;
  if (strcmp(symbol, "") == 0)
    return 0;
  for (j = 0; j < 5; j++)
    if (strcmp(symbol, operations[j]) == 0)
      return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_check>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2a00002d00002b,%rax
  movl   $0x2500,0x11(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0x9(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %rdi,%rbp
  lea    0x9(%rsp),%rbx
  lea    0x18(%rsp),%r12
L6:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L39
  add    $0x3,%rbx
  cmp    %r12,%rbx
  jne    L6
  xor    %eax,%eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  jmp    L16
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binary_check(char *symbol) {
  char operations[5][3] = {"+", "-", "*", "%", "!"};
  int j = 0;
  if (strcmp(symbol, "") == 0)
    return 0;
  for (j = 0; j < 5; j++)
    if (strcmp(symbol, operations[j]) == 0)
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_check>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2a00002d00002b,%rax
  movl   $0x2500,0x11(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,0x9(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L40
  lea    0x9(%rsp),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %eax,%eax
  je     L58
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L58
  lea    0xf(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L58
  lea    0x12(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L58
  lea    0x15(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L40:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    $0x1,%eax
  jmp    L40
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binary_check(char *symbol) {
  char operations[5][3] = {"+", "-", "*", "%", "!"};
  int j = 0;
  if (strcmp(symbol, "") == 0)
    return 0;
  for (j = 0; j < 5; j++)
    if (strcmp(symbol, operations[j]) == 0)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  do {
    *dest++ = *src;
  } while (*src++ != '\0');
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
L5:
  add    $0x1,%rax
  movzbl (%rsi),%edx
  mov    %dl,-0x1(%rax)
  add    $0x1,%rsi
  test   %dl,%dl
  jne    L5
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  do {
    *dest++ = *src;
  } while (*src++ != '\0');
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L3:
  movzbl (%rsi),%edx
  add    $0x1,%rax
  add    $0x1,%rsi
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L3
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  do {
    *dest++ = *src;
  } while (*src++ != '\0');
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L1:
  movzbl (%rsi),%edx
  add    $0x1,%rax
  add    $0x1,%rsi
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L1
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  do {
    *dest++ = *src;
  } while (*src++ != '\0');
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count_bitarray_AND3_SSE2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %edx,%eax
  mov    %eax,%edi
  call   <bitcount_SSE2@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x7ffff,-0x4(%rbp)
  jle    L19
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t count_bitarray_AND3_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i]);
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count_bitarray_AND3_SSE2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x10,%esi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r14
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r13
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L4:
  mov    (%r14,%rbx,1),%edi
  and    0x0(%r13,%rbx,1),%edi
  and    (%r12,%rbx,1),%edi
  call   <bitcount_SSE2@plt>
  add    %eax,%ebp
  add    $0x4,%rbx
  cmp    $0x200000,%rbx
  jne    L4
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t count_bitarray_AND3_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i]);
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count_bitarray_AND3_SSE2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x10,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <__builtin_assume_aligned@plt>
  mov    %r12,%rdi
  mov    $0x10,%esi
  xor    %r12d,%r12d
  mov    %rax,%r14
  call   <__builtin_assume_aligned@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  mov    %rax,%r13
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L7:
  mov    (%r14,%rbx,1),%edi
  and    0x0(%r13,%rbx,1),%edi
  and    0x0(%rbp,%rbx,1),%edi
  add    $0x4,%rbx
  call   <bitcount_SSE2@plt>
  add    %eax,%r12d
  cmp    $0x200000,%rbx
  jne    L7
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t count_bitarray_AND3_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i]);
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_bitarray_AND3_SSE2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x10,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <__builtin_assume_aligned@plt>
  mov    %r12,%rdi
  mov    $0x10,%esi
  xor    %r12d,%r12d
  mov    %rax,%r14
  call   <__builtin_assume_aligned@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  mov    %rax,%r13
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L5:
  mov    (%r14,%rbx,1),%edi
  and    0x0(%r13,%rbx,1),%edi
  and    0x0(%rbp,%rbx,1),%edi
  add    $0x4,%rbx
  call   <bitcount_SSE2@plt>
  add    %eax,%r12d
  cmp    $0x200000,%rbx
  jne    L5
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint32_t count_bitarray_AND3_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i]);
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L0
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long fib(int n) {
  long long curr = 0;
  long long next = 1;
  int i;
  for (i = 0; i < n; i++) {
    long long prev = curr;
    curr = next;
    next += prev;
  }
  return curr;
}
```