ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<flipiarr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L60
L18:
  test   %r12d,%r12d
  jle    L8
  movslq %r12d,%rax
  lea    -0x1(%r12),%ecx
  shl    $0x2,%rax
  lea    (%rbx,%rax,1),%rdx
  lea    0x0(%rbp,%rax,1),%rsi
  cmp    %rbp,%rdx
  setbe  %al
  cmp    %rsi,%rbx
  setae  %dil
  or     %dil,%al
  je     L52
  cmp    $0x2,%ecx
  jbe    L52
  mov    %r12d,%eax
  lea    -0x10(%rbx,%rsi,1),%rsi
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rbx,%rax,1),%rdi
  mov    %rbx,%rax
  cs nopw 0x0(%rax,%rax,1)
L53:
  movdqu (%rax),%xmm1
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    $0x10,%rax
  pshufd $0x1b,%xmm1,%xmm0
  movups %xmm0,(%rdx)
  cmp    %rdi,%rax
  jne    L53
  mov    %r12d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r12b
  je     L8
  mov    %eax,%edx
  mov    (%rbx,%rdx,4),%esi
  lea    0x0(,%rdx,4),%rdi
  mov    %ecx,%edx
  sub    %eax,%edx
  movslq %edx,%rdx
  mov    %esi,0x0(%rbp,%rdx,4)
  lea    0x1(%rax),%esi
  cmp    %esi,%r12d
  jle    L8
  mov    %ecx,%edx
  mov    0x4(%rbx,%rdi,1),%r8d
  add    $0x2,%eax
  sub    %esi,%edx
  movslq %edx,%rdx
  mov    %r8d,0x0(%rbp,%rdx,4)
  cmp    %eax,%r12d
  jle    L8
  mov    0x8(%rbx,%rdi,1),%edx
  sub    %eax,%ecx
  movslq %ecx,%rcx
  mov    %edx,0x0(%rbp,%rcx,4)
L8:
  mov    %rbp,%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <copyiarr@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   (%rax)
L60:
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <fatalx@plt>
  jmp    L18
  nopl   0x0(%rax)
L52:
  mov    %rbx,%rax
  lea    0x4(%rbx,%rcx,4),%rdi
  lea    -0x4(%rbp,%rdx,1),%rsi
  nopl   (%rax)
L7:
  mov    (%rax),%ecx
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    $0x4,%rax
  mov    %ecx,(%rdx)
  cmp    %rdi,%rax
  jne    L7
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: Unable to allocate %d unit(s) for item 


assistant: ```c
void flipiarr(int *a, int *b, int n) {
  int *x, k;
  if ((x = (int *)calloc((n), sizeof(int))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", n);
  for (k = 0; k < n; ++k) {
    x[n - 1 - k] = b[k];
  }
  copyiarr(x, a, n);
  free(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xe,%edi
  call   <GPIOexport@plt>
  mov    $0xf,%edi
  call   <GPIOexport@plt>
  mov    $0x12,%edi
  call   <GPIOexport@plt>
  mov    $0x17,%edi
  call   <GPIOexport@plt>
  mov    $0x19,%edi
  call   <GPIOexport@plt>
  mov    $0x0,%esi
  mov    $0xe,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0xf,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0x12,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <GPIOdirection@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <GPIOdirection@plt>
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x24(%rbp)
L9:
  movl   $0x0,-0x2c(%rbp)
  jmp    L54
L59:
  mov    -0x2c(%rbp),%eax
  cltq
  movl   $0x0,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x2c(%rbp)
L54:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L59
  movl   $0x0,-0x28(%rbp)
  jmp    L24
L45:
  mov    -0x30(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  setne  %al
  movzbl %al,%edx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x30(%rbp)
  addl   $0x1,-0x28(%rbp)
L24:
  cmpl   $0x0,-0x30(%rbp)
  jne    L45
  mov    $0x19,%edi
  call   <GPIORead@plt>
  cmp    $0x1,%eax
  jne    L9
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  mov    $0xe,%edi
  call   <GPIOWrite@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0xf,%edi
  call   <GPIOWrite@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x12,%edi
  call   <GPIOWrite@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x17,%edi
  call   <GPIOWrite@plt>
  addl   $0x1,-0x30(%rbp)
  jmp    L9
```

assistant: ```c
int main(void) {
  GPIOexport(14);
  GPIOexport(15);
  GPIOexport(18);
  GPIOexport(23);
  GPIOexport(25);
  GPIOdirection(14, 0);
  GPIOdirection(15, 0);
  GPIOdirection(18, 0);
  GPIOdirection(23, 0);
  GPIOdirection(25, 1);
  int decimal = 0, binario[4], resto = 0;
  while (1) {
    for (int cont = 0; cont < 4; cont++)
      binario[cont] = 0;
    int cont = 0;
    while (decimal != 0) {
      resto = decimal % 2;
      binario[cont] = resto == 0 ? 0 : 1;
      decimal = decimal / 2;
      cont++;
    }
    if (GPIORead(25) == 1) {
      GPIOWrite(14, binario[0]);
      GPIOWrite(15, binario[1]);
      GPIOWrite(18, binario[2]);
      GPIOWrite(23, binario[3]);
      decimal++;
    }
  }
  GPIOUnexport(14);
  GPIOUnexport(15);
  GPIOUnexport(18);
  GPIOUnexport(23);
  GPIOUnexport(25);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xe,%edi
  call   <GPIOexport@plt>
  mov    $0xf,%edi
  call   <GPIOexport@plt>
  mov    $0x12,%edi
  call   <GPIOexport@plt>
  mov    $0x17,%edi
  call   <GPIOexport@plt>
  mov    $0x19,%edi
  call   <GPIOexport@plt>
  mov    $0x0,%esi
  mov    $0xe,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0xf,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0x12,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <GPIOdirection@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <GPIOdirection@plt>
  mov    $0x0,%ebx
L28:
  mov    %ebx,%eax
L6:
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  test   %eax,%eax
  je     L26
  movl   $0x1,(%rsp)
L26:
  mov    $0x19,%edi
  call   <GPIORead@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  cmp    $0x1,%ebx
  jne    L6
  mov    (%rsp),%esi
  mov    $0xe,%edi
  call   <GPIOWrite@plt>
  mov    0x4(%rsp),%esi
  mov    $0xf,%edi
  call   <GPIOWrite@plt>
  mov    0x8(%rsp),%esi
  mov    $0x12,%edi
  call   <GPIOWrite@plt>
  mov    0xc(%rsp),%esi
  mov    $0x17,%edi
  call   <GPIOWrite@plt>
  jmp    L28
```

assistant: ```c
int main(void) {
  GPIOexport(14);
  GPIOexport(15);
  GPIOexport(18);
  GPIOexport(23);
  GPIOexport(25);
  GPIOdirection(14, 0);
  GPIOdirection(15, 0);
  GPIOdirection(18, 0);
  GPIOdirection(23, 0);
  GPIOdirection(25, 1);
  int decimal = 0, binario[4], resto = 0;
  while (1) {
    for (int cont = 0; cont < 4; cont++)
      binario[cont] = 0;
    int cont = 0;
    while (decimal != 0) {
      resto = decimal % 2;
      binario[cont] = resto == 0 ? 0 : 1;
      decimal = decimal / 2;
      cont++;
    }
    if (GPIORead(25) == 1) {
      GPIOWrite(14, binario[0]);
      GPIOWrite(15, binario[1]);
      GPIOWrite(18, binario[2]);
      GPIOWrite(23, binario[3]);
      decimal++;
    }
  }
  GPIOUnexport(14);
  GPIOUnexport(15);
  GPIOUnexport(18);
  GPIOUnexport(23);
  GPIOUnexport(25);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xe,%edi
  call   <GPIOexport@plt>
  mov    $0xf,%edi
  call   <GPIOexport@plt>
  mov    $0x12,%edi
  call   <GPIOexport@plt>
  mov    $0x17,%edi
  call   <GPIOexport@plt>
  mov    $0x19,%edi
  call   <GPIOexport@plt>
  xor    %esi,%esi
  mov    $0xe,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0x12,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  call   <GPIOdirection@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <GPIOdirection@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x19,%edi
  call   <GPIORead@plt>
  cmp    $0x1,%eax
  jne    L19
  mov    %ebx,%esi
  mov    $0xe,%edi
  mov    $0x1,%ebx
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0x12,%edi
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  call   <GPIOWrite@plt>
  jmp    L17
```

assistant: ```c
int main(void) {
  GPIOexport(14);
  GPIOexport(15);
  GPIOexport(18);
  GPIOexport(23);
  GPIOexport(25);
  GPIOdirection(14, 0);
  GPIOdirection(15, 0);
  GPIOdirection(18, 0);
  GPIOdirection(23, 0);
  GPIOdirection(25, 1);
  int decimal = 0, binario[4], resto = 0;
  while (1) {
    for (int cont = 0; cont < 4; cont++)
      binario[cont] = 0;
    int cont = 0;
    while (decimal != 0) {
      resto = decimal % 2;
      binario[cont] = resto == 0 ? 0 : 1;
      decimal = decimal / 2;
      cont++;
    }
    if (GPIORead(25) == 1) {
      GPIOWrite(14, binario[0]);
      GPIOWrite(15, binario[1]);
      GPIOWrite(18, binario[2]);
      GPIOWrite(23, binario[3]);
      decimal++;
    }
  }
  GPIOUnexport(14);
  GPIOUnexport(15);
  GPIOUnexport(18);
  GPIOUnexport(23);
  GPIOUnexport(25);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xe,%edi
  call   <GPIOexport@plt>
  mov    $0xf,%edi
  call   <GPIOexport@plt>
  mov    $0x12,%edi
  call   <GPIOexport@plt>
  mov    $0x17,%edi
  call   <GPIOexport@plt>
  mov    $0x19,%edi
  call   <GPIOexport@plt>
  xor    %esi,%esi
  mov    $0xe,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0x12,%edi
  call   <GPIOdirection@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  call   <GPIOdirection@plt>
  mov    $0x1,%esi
  mov    $0x19,%edi
  call   <GPIOdirection@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x19,%edi
  call   <GPIORead@plt>
  cmp    $0x1,%eax
  jne    L16
  mov    %ebx,%esi
  mov    $0xe,%edi
  mov    $0x1,%ebx
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0xf,%edi
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0x12,%edi
  call   <GPIOWrite@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  call   <GPIOWrite@plt>
  jmp    L11
```

assistant: ```c
int main(void) {
  GPIOexport(14);
  GPIOexport(15);
  GPIOexport(18);
  GPIOexport(23);
  GPIOexport(25);
  GPIOdirection(14, 0);
  GPIOdirection(15, 0);
  GPIOdirection(18, 0);
  GPIOdirection(23, 0);
  GPIOdirection(25, 1);
  int decimal = 0, binario[4], resto = 0;
  while (1) {
    for (int cont = 0; cont < 4; cont++)
      binario[cont] = 0;
    int cont = 0;
    while (decimal != 0) {
      resto = decimal % 2;
      binario[cont] = resto == 0 ? 0 : 1;
      decimal = decimal / 2;
      cont++;
    }
    if (GPIORead(25) == 1) {
      GPIOWrite(14, binario[0]);
      GPIOWrite(15, binario[1]);
      GPIOWrite(18, binario[2]);
      GPIOWrite(23, binario[3]);
      decimal++;
    }
  }
  GPIOUnexport(14);
  GPIOUnexport(15);
  GPIOUnexport(18);
  GPIOUnexport(23);
  GPIOUnexport(25);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int range(int *arr, int len, int step) {
  int i = 0;
  for (i = 0; i < len; i++) {
    *(arr + i) = i * step;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<range>:
  endbr64
  test   %esi,%esi
  jle    L0
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rsi
  mov    $0x0,%ecx
L3:
  mov    %ecx,(%rax)
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L3
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int range(int *arr, int len, int step) {
  int i = 0;
  for (i = 0; i < len; i++) {
    *(arr + i) = i * step;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<range>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L16
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int range(int *arr, int len, int step) {
  int i = 0;
  for (i = 0; i < len; i++) {
    *(arr + i) = i * step;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<range>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L62
  movd   %edx,%xmm6
  shr    $0x2,%esi
  mov    %rdi,%rax
  movdqa D6(%rip),%xmm2
  pshufd $0x0,%xmm6,%xmm3
  sub    $0x1,%esi
  movdqa D2(%rip),%xmm5
  shl    $0x4,%rsi
  movdqa %xmm3,%xmm4
  lea    0x10(%rdi,%rsi,1),%rsi
  psrlq  $0x20,%xmm4
  xchg   %ax,%ax
L46:
  movdqa %xmm2,%xmm0
  add    $0x10,%rax
  paddd  %xmm5,%xmm2
  movdqa %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm3,%xmm1
  pmuludq %xmm4,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L46
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%cl
  je     L24
L58:
  mov    %edx,%esi
  movslq %eax,%r8
  imul   %eax,%esi
  lea    0x0(,%r8,4),%r9
  mov    %esi,(%rdi,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%ecx
  jle    L24
  add    %edx,%esi
  add    $0x2,%eax
  mov    %esi,0x4(%rdi,%r9,1)
  cmp    %eax,%ecx
  jle    L24
  add    %esi,%edx
  mov    %edx,0x8(%rdi,%r9,1)
L24:
  xor    %eax,%eax
  ret
L62:
  xor    %eax,%eax
  jmp    L58
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: byte[16]
name: parse_data
arguments: tag: D2
type_infered: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D2": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int range(int *arr, int len, int step) {
  int i = 0;
  for (i = 0; i < len; i++) {
    *(arr + i) = i * step;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Ket_FeedAssociatedDataBlocks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <KeccakP200_AddByte@plt>
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <KeccakP200_AddByte@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <Ket_Step@plt>
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void Ket_FeedAssociatedDataBlocks(void *state, const unsigned char *data, unsigned int nBlocks) {
  do {
    KeccakP200_AddByte(state, *(data++), 0);
    KeccakP200_AddByte(state, *(data++), 1);
    Ket_Step(state, (2 * 200 / 8 / 25), 0x04);
  } while (--nBlocks != 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Ket_FeedAssociatedDataBlocks>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x2(%rsi,%rax,2),%r12
L1:
  movzbl (%rbx),%esi
  mov    $0x0,%edx
  mov    %rbp,%rdi
  call   <KeccakP200_AddByte@plt>
  add    $0x2,%rbx
  movzbl -0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <KeccakP200_AddByte@plt>
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <Ket_Step@plt>
  cmp    %rbx,%r12
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Ket_FeedAssociatedDataBlocks(void *state, const unsigned char *data, unsigned int nBlocks) {
  do {
    KeccakP200_AddByte(state, *(data++), 0);
    KeccakP200_AddByte(state, *(data++), 1);
    Ket_Step(state, (2 * 200 / 8 / 25), 0x04);
  } while (--nBlocks != 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Ket_FeedAssociatedDataBlocks>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x2(%rsi,%rax,2),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rbx),%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  add    $0x2,%rbx
  call   <KeccakP200_AddByte@plt>
  movzbl -0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <KeccakP200_AddByte@plt>
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <Ket_Step@plt>
  cmp    %rbx,%r12
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Ket_FeedAssociatedDataBlocks(void *state, const unsigned char *data, unsigned int nBlocks) {
  do {
    KeccakP200_AddByte(state, *(data++), 0);
    KeccakP200_AddByte(state, *(data++), 1);
    Ket_Step(state, (2 * 200 / 8 / 25), 0x04);
  } while (--nBlocks != 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Ket_FeedAssociatedDataBlocks>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x2(%rsi,%rax,2),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl (%rbx),%esi
  xor    %edx,%edx
  mov    %rbp,%rdi
  add    $0x2,%rbx
  call   <KeccakP200_AddByte@plt>
  movzbl -0x1(%rbx),%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <KeccakP200_AddByte@plt>
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <Ket_Step@plt>
  cmp    %rbx,%r12
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Ket_FeedAssociatedDataBlocks(void *state, const unsigned char *data, unsigned int nBlocks) {
  do {
    KeccakP200_AddByte(state, *(data++), 0);
    KeccakP200_AddByte(state, *(data++), 1);
    Ket_Step(state, (2 * 200 / 8 / 25), 0x04);
  } while (--nBlocks != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<many_ints>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r15d
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8d,%r12d
  mov    %r9d,%ebp
  mov    %edi,%ecx
  mov    $0x1,%edx
  mov    $0x6,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    %r15d,%ecx
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    %r14d,%ecx
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    %r13d,%ecx
  mov    $0x4,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    %r12d,%ecx
  mov    $0x5,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    %ebp,%ecx
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    0x40(%rsp),%ecx
  mov    $0x7,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    0x48(%rsp),%ecx
  mov    $0x8,%edx
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    0x50(%rsp),%ecx
  mov    $0x9,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c

assistant: ```c
void many_ints(int v1, int v2, int v3, int v4, int v5, int v6, int v7, int v8, int v9) {
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 6, 1, v1);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 6, 2, v2);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 6, 3, v3);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 6, 4, v4);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 7, 5, v5);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 7, 6, v6);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 7, 7, v7);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 7, 8, v8);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/funcargs.c", 8, 9, v9);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L28
L32:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  call   <output_widgets@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L4
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  call   <output_config@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L4:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D6: --widgets

tool: D15: --config

assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++) {
    if (!strcmp(argv[i], "--widgets")) {
      output_widgets();
      exit(0);
    } else if (!strcmp(argv[i], "--config")) {
      output_config();
      exit(0);
    }
  }
  usage();
  return 0;
}
```