ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getAssr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,0x18(%rsp)
  call   <sincos@plt>
  movsd  (%rsp),%xmm2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  D66(%rip),%xmm0
  movsd  0x20(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm4
  mulsd  %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  subsd  %xmm1,%xmm0
  andpd  D20(%rip),%xmm0
  call   <tan@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D35(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <atan@plt>
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm4
  mulsd  0x28(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  mulsd  0x20(%rsp),%xmm3
  movsd  D4(%rip),%xmm1
  subsd  %xmm4,%xmm0
  divsd  %xmm3,%xmm0
  comisd %xmm0,%xmm1
  movsd  D60(%rip),%xmm1
  ja     L7
  comisd D35(%rip),%xmm0
  jbe    L18
L7:
  add    $0x30,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L18:
  call   <acos@plt>
  movapd %xmm0,%xmm1
  divsd  D66(%rip),%xmm1
  mulsd  D71(%rip),%xmm1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D66
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D20
type_infered: qword[2]
name: retrieve_data
arguments: data_tag: D35
type_infered: f64[2]
name: retrieve_data
arguments: data_tag: D4
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D60
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D71
type_infered: byte[8]

tool: {"D66": [0x44,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D20": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D35": [1.0,-1.0]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0xc0,0x58,0x40]}

tool: {"D71": [0x11,0x11,0x11,0x11,0x11,0x11,0xb1,0x3f]}

assistant: ```c
double getAssr(double lat, double dec, int mathhab) {
  double part1, part2, part3, part4;
  double rlat = ((lat) * (3.1415926535898 / 180.0));
  part1 = mathhab + tan(fabs(rlat - dec));
  part2 = atan(1.0 / part1);
  part3 = sin(part2) - (sin(rlat) * sin(dec));
  part4 = (part3 / (cos(rlat) * cos(dec)));
  if (part4 < -1 || part4 > 1) {
    return 99;
  }
  return 1 / 15.0 * ((acos(part4)) / (3.1415926535898 / 180.0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getAssr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,0x18(%rsp)
  call   <sincos@plt>
  movsd  (%rsp),%xmm2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  D58(%rip),%xmm0
  movsd  0x20(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm4
  mulsd  %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  subsd  %xmm1,%xmm0
  andpd  D77(%rip),%xmm0
  call   <tan@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <atan@plt>
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm4
  mulsd  0x28(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  mulsd  0x20(%rsp),%xmm3
  movsd  D18(%rip),%xmm1
  subsd  %xmm4,%xmm0
  divsd  %xmm3,%xmm0
  comisd %xmm0,%xmm1
  movsd  D1(%rip),%xmm1
  ja     L6
  comisd D7(%rip),%xmm0
  jbe    L13
L6:
  add    $0x30,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L13:
  call   <acos@plt>
  movapd %xmm0,%xmm1
  divsd  D58(%rip),%xmm1
  mulsd  D53(%rip),%xmm1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D58
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D77
type_guessed: qword[2]
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: f64[2]
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D53
type_guessed: byte[8]

tool: {"D58": [0x44,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D77": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D7": [1.0,-1.0]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0xc0,0x58,0x40]}

tool: {"D53": [0x11,0x11,0x11,0x11,0x11,0x11,0xb1,0x3f]}

assistant: ```c
double getAssr(double lat, double dec, int mathhab) {
  double part1, part2, part3, part4;
  double rlat = ((lat) * (3.1415926535898 / 180.0));
  part1 = mathhab + tan(fabs(rlat - dec));
  part2 = atan(1.0 / part1);
  part3 = sin(part2) - (sin(rlat) * sin(dec));
  part4 = (part3 / (cos(rlat) * cos(dec)));
  if (part4 < -1 || part4 > 1) {
    return 99;
  }
  return 1 / 15.0 * ((acos(part4)) / (3.1415926535898 / 180.0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<autohelperowl_attackpat170>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <safe_move@plt>
  test   %eax,%eax
  jne    L21
  mov    -0x8(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    -0x4(%rbp),%ecx
  push   %rcx
  mov    -0x8(%rbp),%ecx
  push   %rcx
  mov    %esi,%r9d
  mov    $0x0,%r8d
  mov    %edx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L21
  mov    $0x1,%eax
  jmp    L14
L21:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat170(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  c = offset(1, 2, move, transformation);
  return !safe_move(a, color) && !play_attack_defend2_n(color, 1, 3, move, 0, a, a, c);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<autohelperowl_attackpat170>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  mov    %esi,%ecx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <safe_move@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L17
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  push   %rbp
  push   %r12
  mov    %r12d,%r9d
  mov    $0x0,%r8d
  mov    %ebx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L8
```

assistant: ```c
int autohelperowl_attackpat170(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  c = offset(1, 2, move, transformation);
  return !safe_move(a, color) && !play_attack_defend2_n(color, 1, 3, move, 0, a, a, c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<autohelperowl_attackpat170>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x2,%esi
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <safe_move@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  push   %r13
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    $0x3,%edx
  push   %rbx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend2_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat170(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  c = offset(1, 2, move, transformation);
  return !safe_move(a, color) && !play_attack_defend2_n(color, 1, 3, move, 0, a, a, c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<autohelperowl_attackpat170>:
  endbr64
  push   %r13
  xor    %edi,%edi
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x2,%esi
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <safe_move@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  push   %r13
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    $0x3,%edx
  push   %rbx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend2_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int autohelperowl_attackpat170(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, 1, move, transformation);
  c = offset(1, 2, move, transformation);
  return !safe_move(a, color) && !play_attack_defend2_n(color, 1, 3, move, 0, a, a, c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<coinChange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x18(%rbp)
  jmp    L56
L19:
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L7:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L23
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L23
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jbe    L23
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
L23:
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  addl   $0x1,-0x18(%rbp)
L56:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L19
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  unsigned int *dp = (unsigned int *)malloc(sizeof(int) * (amount + 1));
  int i, j, ans, t;
  memset(dp, 0xff, sizeof(int) * (amount + 1));
  dp[0] = 0;
  for (i = 1; i <= amount; i++) {
    for (j = 0; j < coinsSize; j++) {
      if (coins[j] <= i) {
        t = dp[i - coins[j]] + 1;
        if (t > 0 && t < dp[i]) {
          dp[i] = t;
        }
      }
    }
  }
  ans = dp[amount];
  free(dp);
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<coinChange>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  lea    0x4(,%rdx,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r14d,%edx
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,(%rbx)
  test   %r13d,%r13d
  jle    L8
  lea    0x4(%rbx),%r9
  lea    0x1(%r13),%r10d
  lea    -0x1(%r12),%eax
  lea    0x4(%rbp,%rax,4),%rdi
  mov    $0x1,%esi
  jmp    L94
L53:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L11
L43:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jg     L53
  mov    %esi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  mov    (%rbx,%rdx,4),%edx
  add    $0x1,%edx
  test   %edx,%edx
  jle    L53
  cmp    (%r8),%edx
  jae    L53
  mov    %edx,(%r8)
  jmp    L53
L11:
  add    $0x1,%esi
  add    $0x4,%r9
  cmp    %r10d,%esi
  je     L8
L94:
  mov    %r9,%r8
  mov    %rbp,%rax
  test   %r12d,%r12d
  jg     L43
  jmp    L11
L8:
  movslq %r13d,%r13
  mov    (%rbx,%r13,4),%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  unsigned int *dp = (unsigned int *)malloc(sizeof(int) * (amount + 1));
  int i, j, ans, t;
  memset(dp, 0xff, sizeof(int) * (amount + 1));
  dp[0] = 0;
  for (i = 1; i <= amount; i++) {
    for (j = 0; j < coinsSize; j++) {
      if (coins[j] <= i) {
        t = dp[i - coins[j]] + 1;
        if (t > 0 && t < dp[i]) {
          dp[i] = t;
        }
      }
    }
  }
  ans = dp[amount];
  free(dp);
  return ans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<coinChange>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x4(,%rbx,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    $0xff,%esi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,0x0(%r13)
  test   %ebx,%ebx
  jle    L77
  lea    -0x1(%r12),%eax
  lea    0x4(%r13),%r8
  mov    $0x1,%esi
  lea    0x4(%rbp,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %rbp,%rax
  test   %r12d,%r12d
  jle    L44
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jg     L22
  mov    %esi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  mov    0x0(%r13,%rdx,4),%edx
  add    $0x1,%edx
  test   %edx,%edx
  jle    L22
  cmp    (%r8),%edx
  jae    L22
  mov    %edx,(%r8)
  nopl   0x0(%rax)
L22:
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L25
L44:
  lea    0x1(%rsi),%eax
  add    $0x4,%r8
  cmp    %esi,%ebx
  je     L77
  mov    %eax,%esi
  jmp    L66
L77:
  mov    0x0(%r13,%rbx,4),%r12d
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  unsigned int *dp = (unsigned int *)malloc(sizeof(int) * (amount + 1));
  int i, j, ans, t;
  memset(dp, 0xff, sizeof(int) * (amount + 1));
  dp[0] = 0;
  for (i = 1; i <= amount; i++) {
    for (j = 0; j < coinsSize; j++) {
      if (coins[j] <= i) {
        t = dp[i - coins[j]] + 1;
        if (t > 0 && t < dp[i]) {
          dp[i] = t;
        }
      }
    }
  }
  ans = dp[amount];
  free(dp);
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<coinChange>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  lea    0x4(,%rbx,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    $0xff,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,(%r12)
  test   %ebx,%ebx
  jle    L25
  test   %r13d,%r13d
  jle    L25
  lea    -0x1(%r13),%eax
  lea    0x4(%r12),%r8
  mov    $0x1,%esi
  lea    0x4(%rbp,%rax,4),%rdi
  nopl   0x0(%rax)
L20:
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L66:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jg     L61
  mov    %esi,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  mov    (%r12,%rdx,4),%edx
  add    $0x1,%edx
  test   %edx,%edx
  jle    L61
  cmp    (%r8),%edx
  jae    L61
  mov    %edx,(%r8)
  nopl   0x0(%rax,%rax,1)
L61:
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L66
  lea    0x1(%rsi),%eax
  add    $0x4,%r8
  cmp    %esi,%ebx
  je     L25
  mov    %eax,%esi
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%r12,%rbx,4),%r13d
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int coinChange(int *coins, int coinsSize, int amount) {
  unsigned int *dp = (unsigned int *)malloc(sizeof(int) * (amount + 1));
  int i, j, ans, t;
  memset(dp, 0xff, sizeof(int) * (amount + 1));
  dp[0] = 0;
  for (i = 1; i <= amount; i++) {
    for (j = 0; j < coinsSize; j++) {
      if (coins[j] <= i) {
        t = dp[i - coins[j]] + 1;
        if (t > 0 && t < dp[i]) {
          dp[i] = t;
        }
      }
    }
  }
  ans = dp[amount];
  free(dp);
  return ans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L4
L1:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
L4:
  cmpl   $0x0,-0xc(%rbp)
  jg     L1
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z = z + x;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L17
L9:
  add    %ebp,%ebx
  add    %eax,%ebp
  add    %ebx,%eax
  test   %ebx,%ebx
  jg     L9
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z = z + x;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L3
  nopw   0x0(%rax,%rax,1)
L9:
  add    %ebp,%ebx
  add    %eax,%ebp
  add    %ebx,%eax
  test   %ebx,%ebx
  jg     L9
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z = z + x;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L5
  nopw   0x0(%rax,%rax,1)
L9:
  add    %ebp,%ebx
  add    %eax,%ebp
  add    %ebx,%eax
  test   %ebx,%ebx
  jg     L9
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x, y, z;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  z = __VERIFIER_nondet_int();
  while (x > 0) {
    x = x + y;
    y = y + z;
    z = z + x;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  mov    $0x0,%eax
  call   <a@plt>
  jmp    L9
```

assistant: ```c
int main() {
  for (;;) {
    a();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0x0,%eax
  call   <a@plt>
  jmp    L9
```

assistant: ```c
int main() {
  for (;;) {
    a();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <a@plt>
  jmp    L2
```

assistant: ```c
int main() {
  for (;;) {
    a();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <a@plt>
  jmp    L3
```

assistant: ```c
int main() {
  for (;;) {
    a();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <prompt_list@plt>
  mov    %rax,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_list@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rmEvens@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_list@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_list@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string

tool: D9: Got the following list: 

tool: D16: Removing evens: 

assistant: ```c
int main(void) {
  struct element *l = prompt_list();
  printf("Got the following list: ");
  print_list(l);
  printf("Removing evens: ");
  l = rmEvens(l);
  print_list(l);
  free_list(l);
  return 0;
}
```