ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<verif_delim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L25
L35:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int verif_delim(char caract, char *delim) {
  int i;
  i = 0;
  while (delim[i] != '\0') {
    if (caract == delim[i])
      return (-1);
    ++i;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<verif_delim>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L23
  add    $0x1,%rsi
L28:
  cmp    %al,%dil
  je     L24
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
L24:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int verif_delim(char caract, char *delim) {
  int i;
  i = 0;
  while (delim[i] != '\0') {
    if (caract == delim[i])
      return (-1);
    ++i;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<verif_delim>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L3
  add    $0x1,%rsi
  jmp    L38
  nopl   0x0(%rax)
L1:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L3
L38:
  cmp    %al,%dil
  jne    L1
  mov    $0xffffffff,%eax
  ret
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int verif_delim(char caract, char *delim) {
  int i;
  i = 0;
  while (delim[i] != '\0') {
    if (caract == delim[i])
      return (-1);
    ++i;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<verif_delim>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L11
  add    $0x1,%rsi
  jmp    L39
  nopl   0x0(%rax)
L19:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L11
L39:
  cmp    %al,%dil
  jne    L19
  mov    $0xffffffff,%eax
  ret
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int verif_delim(char caract, char *delim) {
  int i;
  i = 0;
  while (delim[i] != '\0') {
    if (caract == delim[i])
      return (-1);
    ++i;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_buffers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <str_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L17
L16:
  nop
L17:
  leave
  ret
```

assistant: ```c
void swap_buffers(char *fst, char *snd) {
  char *tmp;
  if (fst == snd)
    return;
  tmp = str_alloc(strlen(fst) + 1);
  strcpy(tmp, fst);
  strcpy(fst, snd);
  strcpy(snd, tmp);
  free(tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_buffers>:
  endbr64
  cmp    %rsi,%rdi
  je     L0
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <str_alloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  ret
```

assistant: ```c
void swap_buffers(char *fst, char *snd) {
  char *tmp;
  if (fst == snd)
    return;
  tmp = str_alloc(strlen(fst) + 1);
  strcpy(tmp, fst);
  strcpy(fst, snd);
  strcpy(snd, tmp);
  free(tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_buffers>:
  endbr64
  cmp    %rsi,%rdi
  je     L5
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <str_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbp
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void swap_buffers(char *fst, char *snd) {
  char *tmp;
  if (fst == snd)
    return;
  tmp = str_alloc(strlen(fst) + 1);
  strcpy(tmp, fst);
  strcpy(fst, snd);
  strcpy(snd, tmp);
  free(tmp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap_buffers>:
  endbr64
  cmp    %rsi,%rdi
  je     L5
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <str_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  pop    %rbp
  mov    %r13,%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <free@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void swap_buffers(char *fst, char *snd) {
  char *tmp;
  if (fst == snd)
    return;
  tmp = str_alloc(strlen(fst) + 1);
  strcpy(tmp, fst);
  strcpy(fst, snd);
  strcpy(snd, tmp);
  free(tmp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assignment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x4,-0x24(%rbp)
  jg     L106
  cmpl   $0x9,-0x24(%rbp)
  jg     L128
L106:
  mov    $0x1,%eax
  jmp    L29
L128:
  mov    $0x0,%eax
L29:
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L33
  cmpl   $0x5,-0x24(%rbp)
  jle    L33
  mov    $0x1,%eax
  jmp    L70
L33:
  mov    $0x0,%eax
L70:
  mov    %eax,-0x10(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L26
  cmpl   $0x3,-0x24(%rbp)
  je     L117
L26:
  mov    $0x1,%eax
  jmp    L103
L117:
  mov    $0x0,%eax
L103:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L45
  cmpl   $0x2,-0x24(%rbp)
  jne    L45
  mov    $0x1,%eax
  jmp    L57
L45:
  mov    $0x0,%eax
L57:
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L13
  cmpl   $0x0,-0x24(%rbp)
  je     L122
L13:
  mov    $0x1,%eax
  jmp    L39
L122:
  mov    $0x0,%eax
L39:
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void assignment(int x) {
  int a = x > 4 || x < 10;
  int b = x < 2 && x > 5;
  int c = x != 1 || x != 3;
  int d = x == 1 && x == 2;
  int e = x < 1 || x != 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<assignment>:
  endbr64
  ret
```

assistant: ```c
void assignment(int x) {
  int a = x > 4 || x < 10;
  int b = x < 2 && x > 5;
  int c = x != 1 || x != 3;
  int d = x == 1 && x == 2;
  int e = x < 1 || x != 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<assignment>:
  endbr64
  ret
```

assistant: ```c
void assignment(int x) {
  int a = x > 4 || x < 10;
  int b = x < 2 && x > 5;
  int c = x != 1 || x != 3;
  int d = x == 1 && x == 2;
  int e = x < 1 || x != 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assignment>:
  endbr64
  ret
```

assistant: ```c
void assignment(int x) {
  int a = x > 4 || x < 10;
  int b = x < 2 && x > 5;
  int c = x != 1 || x != 3;
  int d = x == 1 && x == 2;
  int e = x < 1 || x != 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_blank_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <chomp@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <front_chomp@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x1,%eax
  jmp    L1
L18:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int is_blank_line(char *s) {
  chomp(s);
  front_chomp(s);
  if (strlen(s) == 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <chomp@plt>
  mov    %rbx,%rdi
  call   <front_chomp@plt>
  cmpb   $0x0,(%rbx)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_blank_line(char *s) {
  chomp(s);
  front_chomp(s);
  if (strlen(s) == 0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <chomp@plt>
  mov    %rbx,%rdi
  call   <front_chomp@plt>
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int is_blank_line(char *s) {
  chomp(s);
  front_chomp(s);
  if (strlen(s) == 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_blank_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <chomp@plt>
  mov    %rbx,%rdi
  call   <front_chomp@plt>
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
int is_blank_line(char *s) {
  chomp(s);
  front_chomp(s);
  if (strlen(s) == 0)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<d2s_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  jmp    L5
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <lrint@plt>
  mov    %ax,(%rbx)
L5:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L15
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void d2s_array(const double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movq   %xmm0,%r13
  movslq %esi,%rbx
L14:
  movq   %r13,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void d2s_array(const double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L17
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L17:
  ret
```

assistant: ```c
void d2s_array(const double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d2s_array>:
  endbr64
  sub    $0x1,%esi
  js     L11
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  movq   %r14,%xmm0
  mulsd  0x0(%rbp,%rbx,8),%xmm0
  call   <lrint@plt>
  mov    %ax,(%r12,%rbx,2)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L11:
  ret
```

assistant: ```c
void d2s_array(const double *src, int count, short *dest, double scale) {
  while (--count >= 0) {
    dest[count] = lrint(scale * src[count]);
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string

tool: D16: %d

assistant: ```c
int main() {
  int **a, n, c;
  scanf("%d", n);
  int *b;
  b = (int *)malloc(n * sizeof(int));
  a = (int **)malloc(n * sizeof(int *));
  for (int p = 0; p < n; p++) {
    a[p] = (int *)malloc(n * sizeof(int));
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      scanf("%d", a[i][j]);
    }
  }
  scanf("%d", &c);
  for (int q = 0; q < n; q++) {
    for (int r = 0; r < n; r++) {
      if (a[q][r] == 0) {
        b[q] = r + 1;
        break;
      }
    }
  }
  for (int j = 0; j < n; j++) {
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main() {
  int **a, n, c;
  scanf("%d", n);
  int *b;
  b = (int *)malloc(n * sizeof(int));
  a = (int **)malloc(n * sizeof(int *));
  for (int p = 0; p < n; p++) {
    a[p] = (int *)malloc(n * sizeof(int));
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      scanf("%d", a[i][j]);
    }
  }
  scanf("%d", &c);
  for (int q = 0; q < n; q++) {
    for (int r = 0; r < n; r++) {
      if (a[q][r] == 0) {
        b[q] = r + 1;
        break;
      }
    }
  }
  for (int j = 0; j < n; j++) {
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main() {
  int **a, n, c;
  scanf("%d", n);
  int *b;
  b = (int *)malloc(n * sizeof(int));
  a = (int **)malloc(n * sizeof(int *));
  for (int p = 0; p < n; p++) {
    a[p] = (int *)malloc(n * sizeof(int));
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      scanf("%d", a[i][j]);
    }
  }
  scanf("%d", &c);
  for (int q = 0; q < n; q++) {
    for (int r = 0; r < n; r++) {
      if (a[q][r] == 0) {
        b[q] = r + 1;
        break;
      }
    }
  }
  for (int j = 0; j < n; j++) {
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0xb,-0x18(%rbp)
  movl   $0xf,-0x14(%rbp)
  movl   $0x9,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <twoSum@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  add    %edx,%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L14
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L14:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string

tool: D15: WORKS!!


tool: D10: :(


assistant: ```c
int main() {
  int nums[] = {2, 7, 11, 15};
  int target = 9;
  int *result = twoSum(nums, 4, target);
  if (result != NULL && (nums[result[0]] + nums[result[1]] == target)) {
    printf("WORKS!!\n");
  } else {
    printf(":(\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0xb,0x8(%rsp)
  movl   $0xf,0xc(%rsp)
  mov    %rsp,%rdi
  mov    $0x9,%edx
  mov    $0x4,%esi
  call   <twoSum@plt>
  test   %rax,%rax
  je     L3
  movslq (%rax),%rdx
  movslq 0x4(%rax),%rax
  mov    (%rsp,%rax,4),%eax
  add    (%rsp,%rdx,4),%eax
  cmp    $0x9,%eax
  je     L14
L3:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L14:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D14
type: string

tool: D12: :(


tool: D14: WORKS!!


assistant: ```c
int main() {
  int nums[] = {2, 7, 11, 15};
  int target = 9;
  int *result = twoSum(nums, 4, target);
  if (result != NULL && (nums[result[0]] + nums[result[1]] == target)) {
    printf("WORKS!!\n");
  } else {
    printf(":(\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x9,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000002,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0xf0000000b,%rax
  mov    %rax,0x8(%rsp)
  call   <twoSum@plt>
  test   %rax,%rax
  je     L16
  movslq (%rax),%rdx
  movslq 0x4(%rax),%rax
  mov    (%rsp,%rax,4),%eax
  add    (%rsp,%rdx,4),%eax
  cmp    $0x9,%eax
  je     L9
L16:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D15: :(


tool: D5: WORKS!!


assistant: ```c
int main() {
  int nums[] = {2, 7, 11, 15};
  int target = 9;
  int *result = twoSum(nums, 4, target);
  if (result != NULL && (nums[result[0]] + nums[result[1]] == target)) {
    printf("WORKS!!\n");
  } else {
    printf(":(\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x9,%edx
  mov    $0x4,%esi
  movdqa D24(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <twoSum@plt>
  test   %rax,%rax
  je     L11
  movslq (%rax),%rdx
  movslq 0x4(%rax),%rax
  mov    (%rsp,%rax,4),%eax
  add    (%rsp,%rdx,4),%eax
  cmp    $0x9,%eax
  je     L33
L11:
  lea    D22(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L33:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: tag: D21
type_guessed: string

tool: {"D24": [0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: D22: :(


tool: D21: WORKS!!


assistant: ```c
int main() {
  int nums[] = {2, 7, 11, 15};
  int target = 9;
  int *result = twoSum(nums, 4, target);
  if (result != NULL && (nums[result[0]] + nums[result[1]] == target)) {
    printf("WORKS!!\n");
  } else {
    printf(":(\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_ternary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x33,%ecx
  mov    $0x33,%edx
  mov    $0x44,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x45,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  mov    $0x1a,%ecx
  mov    $0x1a,%edx
  mov    $0x46,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  mov    $0x11,%ecx
  mov    $0x11,%edx
  mov    $0x47,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x49,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x4a,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D46
type: string

tool: D46: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c

assistant: ```c
void test_ternary() {
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 68, 51, (1 + 2) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 69, 52, (1 - 1) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 70, 26, (1 - 1) ? 51 : 52 / 2);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 71, 17, (1 - 0) ? 51 / 3 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 73, 52, 0 ?: 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 74, 3, (1 + 2) ?: 52);
  ;
}
```