ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cms_cb>:
  endbr64
  test   %rsi,%rsi
  je     L42
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x82,%edi
  je     L43
  jg     L19
  cmp    $0x80,%edi
  je     L31
  cmp    $0x81,%edi
  jne    L22
L20:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <CMS_dataFinal@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L19:
  cmp    $0x83,%edi
  je     L20
L22:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L31:
  lea    0x8(%rcx),%rdi
  mov    %rbp,%rsi
  call   <CMS_stream@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jle    L62
L43:
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <CMS_dataInit@plt>
  test   %eax,%eax
  mov    %eax,(%rbx)
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cms_cb(int operation, ASN1_VALUE **pval, const ASN1_ITEM *it, void *exarg) {
  ASN1_STREAM_ARG *sarg = exarg;
  CMS_ContentInfo *cms = NULL;
  if (pval)
    cms = (CMS_ContentInfo *)*pval;
  else
    return 1;
  switch (operation) {
  case ASN1_OP_STREAM_PRE:
    if (CMS_stream(&sarg->boundary, cms) <= 0)
      return 0;
  case ASN1_OP_DETACHED_PRE:
    sarg->ndef_bio = CMS_dataInit(cms, sarg->out);
    if (!sarg->ndef_bio)
      return 0;
    break;
  case ASN1_OP_STREAM_POST:
  case ASN1_OP_DETACHED_POST:
    if (CMS_dataFinal(cms, sarg->ndef_bio) <= 0)
      return 0;
    break;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_atom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <skip_spaces@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L56:
  movzbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
  movzbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <isspecial@plt>
  test   %rax,%rax
  jne    L29
  movzbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L29
  addq   $0x1,-0x28(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpb   $0x0,-0x15(%rbp)
  jne    L56
L29:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L57
  mov    $0x0,%eax
  jmp    L68
L57:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L50
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L50:
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
L68:
  leave
  ret
```

assistant: ```c
const char *parse_atom(const char *atom, char **pbuf) {
  const char *atom_start;
  char *buf;
  unsigned char c;
  int len;
  atom_start = atom = skip_spaces(atom);
  while ((c = *atom)) {
    if (isspace(c) || isspecial(c) || iscntrl(c))
      break;
    atom++;
  }
  len = atom - atom_start;
  if (!len)
    return NULL;
  if ((buf = (char *)malloc(len + 1))) {
    strncpy(buf, atom_start, len);
    buf[len] = 0;
  }
  *pbuf = buf;
  return atom;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_atom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  call   <skip_spaces@plt>
  movzbl (%rax),%ebx
  test   %bl,%bl
  je     L86
  mov    %rax,%r12
  mov    %rax,%rbp
L42:
  movzbl %bl,%ebx
  mov    %ebx,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    %ebx,%edi
  call   <isspecial@plt>
  test   %rax,%rax
  jne    L9
  mov    %ebx,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L9
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  jne    L42
L9:
  mov    %rbp,%rbx
  sub    %r12,%rbx
  test   %ebx,%ebx
  je     L36
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L33
L48:
  mov    %r14,0x0(%r13)
L56:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r14,%rbx,1)
  jmp    L48
L86:
  mov    $0x0,%ebp
  jmp    L56
L36:
  mov    $0x0,%ebp
  jmp    L56
```

assistant: ```c
const char *parse_atom(const char *atom, char **pbuf) {
  const char *atom_start;
  char *buf;
  unsigned char c;
  int len;
  atom_start = atom = skip_spaces(atom);
  while ((c = *atom)) {
    if (isspace(c) || isspecial(c) || iscntrl(c))
      break;
    atom++;
  }
  len = atom - atom_start;
  if (!len)
    return NULL;
  if ((buf = (char *)malloc(len + 1))) {
    strncpy(buf, atom_start, len);
    buf[len] = 0;
  }
  *pbuf = buf;
  return atom;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_atom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip_spaces@plt>
  movzbl (%rax),%ebp
  mov    %rax,%r13
  mov    %rax,%r12
  test   %bpl,%bpl
  jne    L46
  jmp    L18
  nopl   (%rax)
L12:
  mov    %ebp,%edi
  call   <isspecial@plt>
  test   %rax,%rax
  jne    L45
  mov    %ebp,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L45
  movzbl 0x1(%r12),%ebp
  add    $0x1,%r12
  test   %bpl,%bpl
  je     L45
L46:
  mov    %ebp,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L12
L45:
  mov    %r12,%rbp
  sub    %r13,%rbp
  test   %ebp,%ebp
  je     L18
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L86
L43:
  mov    %r14,(%rbx)
L57:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r14,%rbp,1)
  jmp    L43
  nop
L18:
  xor    %r12d,%r12d
  jmp    L57
```

assistant: ```c
const char *parse_atom(const char *atom, char **pbuf) {
  const char *atom_start;
  char *buf;
  unsigned char c;
  int len;
  atom_start = atom = skip_spaces(atom);
  while ((c = *atom)) {
    if (isspace(c) || isspecial(c) || iscntrl(c))
      break;
    atom++;
  }
  len = atom - atom_start;
  if (!len)
    return NULL;
  if ((buf = (char *)malloc(len + 1))) {
    strncpy(buf, atom_start, len);
    buf[len] = 0;
  }
  *pbuf = buf;
  return atom;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_atom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip_spaces@plt>
  movzbl (%rax),%ebp
  mov    %rax,%r13
  mov    %rax,%r12
  test   %bpl,%bpl
  jne    L27
  jmp    L57
  nopl   (%rax)
L69:
  mov    %ebp,%edi
  call   <isspecial@plt>
  test   %rax,%rax
  jne    L36
  mov    %ebp,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L36
  movzbl 0x1(%r12),%ebp
  add    $0x1,%r12
  test   %bpl,%bpl
  je     L36
L27:
  mov    %ebp,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L69
L36:
  mov    %r12,%rbp
  sub    %r13,%rbp
  test   %ebp,%ebp
  je     L57
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L66
L50:
  mov    %r14,(%rbx)
L30:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r14,%rbp,1)
  jmp    L50
  nop
L57:
  xor    %r12d,%r12d
  jmp    L30
```

assistant: ```c
const char *parse_atom(const char *atom, char **pbuf) {
  const char *atom_start;
  char *buf;
  unsigned char c;
  int len;
  atom_start = atom = skip_spaces(atom);
  while ((c = *atom)) {
    if (isspace(c) || isspecial(c) || iscntrl(c))
      break;
    atom++;
  }
  len = atom - atom_start;
  if (!len)
    return NULL;
  if ((buf = (char *)malloc(len + 1))) {
    strncpy(buf, atom_start, len);
    buf[len] = 0;
  }
  *pbuf = buf;
  return atom;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fExists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x1,%eax
  jmp    L7
L10:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int fExists(char *fn, int AccessMode) {
  if ((access(fn, AccessMode)) == 0)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fExists>:
  endbr64
  sub    $0x8,%rsp
  call   <access@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fExists(char *fn, int AccessMode) {
  if ((access(fn, AccessMode)) == 0)
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fExists>:
  endbr64
  sub    $0x8,%rsp
  call   <access@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int fExists(char *fn, int AccessMode) {
  if ((access(fn, AccessMode)) == 0)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fExists>:
  endbr64
  sub    $0x8,%rsp
  call   <access@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int fExists(char *fn, int AccessMode) {
  if ((access(fn, AccessMode)) == 0)
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SysExcIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7a,%edi
  call   <IntRegister@plt>
  mov    $0x7a,%edi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void SysExcIntRegister(void (*pfnHandler)(void)) {
  IntRegister(122, pfnHandler);
  IntEnable(122);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SysExcIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x7a,%edi
  call   <IntRegister@plt>
  mov    $0x7a,%edi
  call   <IntEnable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void SysExcIntRegister(void (*pfnHandler)(void)) {
  IntRegister(122, pfnHandler);
  IntEnable(122);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SysExcIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x7a,%edi
  call   <IntRegister@plt>
  mov    $0x7a,%edi
  add    $0x8,%rsp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void SysExcIntRegister(void (*pfnHandler)(void)) {
  IntRegister(122, pfnHandler);
  IntEnable(122);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SysExcIntRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x7a,%edi
  call   <IntRegister@plt>
  mov    $0x7a,%edi
  add    $0x8,%rsp
  jmp    1070 <IntEnable@plt>
```

assistant: ```c
void SysExcIntRegister(void (*pfnHandler)(void)) {
  IntRegister(122, pfnHandler);
  IntEnable(122);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<http_split_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L71
L94:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L19
  mov    -0x28(%rbp),%rax
  movb   $0x20,(%rax)
  jmp    L96
L19:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L30
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L30
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L30
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hextoi@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hextoi@plt>
  or     %eax,%ebx
  mov    %ebx,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  jmp    L96
L30:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  je     L63
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L96
L63:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L96:
  addq   $0x1,-0x28(%rbp)
L71:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L94
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int http_split_args(char *argstr) {
  int count;
  for (count = 1; *argstr; ++argstr) {
    if (*argstr == '+') {
      *argstr = ' ';
    } else if (*argstr == '%' && isxdigit(argstr[1]) && isxdigit(argstr[2])) {
      *argstr = (hextoi(argstr[1]) << 4) | hextoi(argstr[2]);
      memmove(argstr + 1, argstr + 3, strlen(argstr + 3) + 1);
    } else if (*argstr == '&' || *argstr == '?') {
      *argstr = '\0';
      ++count;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<http_split_args>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  lea    0x1(%rdi),%rbx
  mov    $0x1,%ebp
  jmp    L46
L10:
  movb   $0x20,-0x1(%rbx)
L65:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L93
L46:
  cmp    $0x2b,%al
  je     L10
  cmp    $0x25,%al
  je     L56
L61:
  mov    %rbx,%rdx
  movzbl -0x1(%rbx),%eax
  cmp    $0x26,%al
  je     L50
  cmp    $0x3f,%al
  jne    L65
L50:
  movb   $0x0,-0x1(%rdx)
  add    $0x1,%ebp
  jmp    L65
L56:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L61
  movsbl (%rbx),%edi
  call   <hextoi@plt>
  mov    %eax,%r13d
  movsbl 0x1(%rbx),%edi
  call   <hextoi@plt>
  shl    $0x4,%r13d
  or     %eax,%r13d
  mov    %r13b,-0x1(%rbx)
  lea    0x2(%rbx),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  jmp    L65
L18:
  mov    $0x1,%ebp
L93:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int http_split_args(char *argstr) {
  int count;
  for (count = 1; *argstr; ++argstr) {
    if (*argstr == '+') {
      *argstr = ' ';
    } else if (*argstr == '%' && isxdigit(argstr[1]) && isxdigit(argstr[2])) {
      *argstr = (hextoi(argstr[1]) << 4) | hextoi(argstr[2]);
      memmove(argstr + 1, argstr + 3, strlen(argstr + 3) + 1);
    } else if (*argstr == '&' || *argstr == '?') {
      *argstr = '\0';
      ++count;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<http_split_args>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L78
  mov    %rdi,%rbx
  mov    $0x1,%r12d
  jmp    L38
  xchg   %ax,%ax
L109:
  cmp    $0x25,%al
  je     L119
L28:
  movzbl -0x1(%rbx),%eax
  cmp    $0x26,%al
  je     L29
  cmp    $0x3f,%al
  je     L29
L84:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L58
L38:
  add    $0x1,%rbx
  cmp    $0x2b,%al
  jne    L109
  movzbl (%rbx),%eax
  movb   $0x20,-0x1(%rbx)
  test   %al,%al
  jne    L38
L58:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  movb   $0x0,-0x1(%rbx)
  add    $0x1,%r12d
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L119:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L28
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L28
  movsbl (%rbx),%edi
  call   <hextoi@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <hextoi@plt>
  shl    $0x4,%ebp
  or     %eax,%ebp
  mov    %bpl,-0x1(%rbx)
  lea    0x2(%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  jmp    L84
  nop
L78:
  mov    $0x1,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int http_split_args(char *argstr) {
  int count;
  for (count = 1; *argstr; ++argstr) {
    if (*argstr == '+') {
      *argstr = ' ';
    } else if (*argstr == '%' && isxdigit(argstr[1]) && isxdigit(argstr[2])) {
      *argstr = (hextoi(argstr[1]) << 4) | hextoi(argstr[2]);
      memmove(argstr + 1, argstr + 3, strlen(argstr + 3) + 1);
    } else if (*argstr == '&' || *argstr == '?') {
      *argstr = '\0';
      ++count;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<http_split_args>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L122
  mov    %rdi,%rbx
  mov    $0x1,%r12d
  jmp    L24
  xchg   %ax,%ax
L6:
  cmp    $0x25,%al
  je     L43
L117:
  cmp    $0x26,%al
  je     L78
  cmp    $0x3f,%al
  je     L78
L57:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L83
L24:
  add    $0x1,%rbx
  cmp    $0x2b,%al
  jne    L6
  movzbl (%rbx),%eax
  movb   $0x20,-0x1(%rbx)
  test   %al,%al
  jne    L24
L83:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L78:
  movb   $0x0,-0x1(%rbx)
  add    $0x1,%r12d
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L43:
  movsbl (%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L87
L1:
  movzbl -0x1(%rbx),%eax
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L87:
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L1
  movsbl (%rbx),%edi
  call   <hextoi@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <hextoi@plt>
  shl    $0x4,%ebp
  or     %eax,%ebp
  mov    %bpl,-0x1(%rbx)
  lea    0x2(%rbx),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L122:
  mov    $0x1,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int http_split_args(char *argstr) {
  int count;
  for (count = 1; *argstr; ++argstr) {
    if (*argstr == '+') {
      *argstr = ' ';
    } else if (*argstr == '%' && isxdigit(argstr[1]) && isxdigit(argstr[2])) {
      *argstr = (hextoi(argstr[1]) << 4) | hextoi(argstr[2]);
      memmove(argstr + 1, argstr + 3, strlen(argstr + 3) + 1);
    } else if (*argstr == '&' || *argstr == '?') {
      *argstr = '\0';
      ++count;
    }
  }
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<flipAndInvertImage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  je     L6
  cmpq   $0x0,-0x38(%rbp)
  jne    L24
L6:
  mov    $0x0,%eax
  jmp    L3
L24:
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x58(%rbp),%rax
  mov    -0x3c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x28(%rbp)
  jmp    L61
L16:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L43
L2:
  mov    -0x20(%rbp),%eax
  sub    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %cl
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x24(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L2
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x28(%rbp)
L61:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
int **flipAndInvertImage(int **A, int ARowSize, int *AColSizes, int **columnSizes, int *returnSize) {
  if (ARowSize == 0 || A == NULL) {
    return NULL;
  }
  int **retval = (int **)malloc(sizeof(int *) * ARowSize);
  *returnSize = ARowSize;
  *columnSizes = (int *)malloc(sizeof(int) * ARowSize);
  for (int nrow = 0; nrow < ARowSize; nrow++) {
    int *srcRow = A[nrow];
    int rowSize = AColSizes[nrow];
    (*columnSizes)[nrow] = rowSize;
    int *dstRow = (int *)malloc(sizeof(int) * rowSize);
    for (int ncol = 0; ncol < rowSize; ncol++) {
      int index = rowSize - ncol - 1;
      dstRow[ncol] = !(srcRow[index]);
    }
    retval[nrow] = dstRow;
  }
  return retval;
}
```