ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L159
  mov    $0x0,%ebp
  lea    D29(%rip),%r13
  movabs $0x241000000000000,%rbx
  movabs $0x2c000000000000,%r12
  jmp    L124
L142:
  add    $0x4,%esi
L75:
  lea    0x7(%rsi),%eax
  cmp    $0x38,%cl
  cmove  %eax,%esi
L169:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L96
L99:
  movzbl (%rdx),%ecx
  cmp    $0x31,%cl
  je     L177
  cmp    $0x34,%cl
  je     L177
  cmp    $0x39,%cl
  ja     L169
  mov    %r8,%rax
  shl    %cl,%rax
  test   %rbx,%rax
  jne    L148
  test   %r12,%rax
  jne    L135
  test   %r9,%rax
  jne    L126
  jmp    L169
L135:
  add    $0x5,%esi
  jmp    L169
L148:
  add    $0x6,%esi
  jmp    L169
L79:
  mov    $0x0,%esi
L96:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jle    L159
L124:
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L79
  mov    %r14,%rdx
  lea    -0x1(%rax),%eax
  lea    0x11(%rsp,%rax,1),%rdi
  mov    $0x0,%esi
  mov    $0x1,%r8d
  movabs $0x180000000000000,%r9
  jmp    L99
L159:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L177:
  cmp    $0x31,%cl
  jne    L142
  add    $0x2,%esi
L126:
  cmp    $0x37,%cl
  jne    L75
  add    $0x3,%esi
  jmp    L169
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
type_infered: string
name: unpack_data
arguments: tag: D29
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string

tool: D22: %d

tool: D29: %s

tool: D23: %d leds


assistant: ```c
int main() {
  char Num[105];
  int N, cont, Led, cont2, Tam;
  scanf("%d", &N);
  for (cont = 0; cont < N; cont++) {
    scanf("%s", Num);
    Tam = strlen(Num);
    Led = 0;
    for (cont2 = 0; cont2 < Tam; cont2++) {
      if (Num[cont2] == '1' || Num[cont2] == '4' || Num[cont2] == '7' || Num[cont2] == '8') {
        if (Num[cont2] == '1')
          Led = Led + 2;
        if (Num[cont2] == '4')
          Led = Led + 4;
        if (Num[cont2] == '7')
          Led = Led + 3;
        if (Num[cont2] == '8')
          Led = Led + 7;
      } else {
        if (Num[cont2] == '2' || Num[cont2] == '3' || Num[cont2] == '5')
          Led = Led + 5;
        else if (Num[cont2] == '6' || Num[cont2] == '9' || Num[cont2] == '0')
          Led = Led + 6;
      }
    }
    printf("%d leds\n", Led);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D15(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L116
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  lea    D4(%rip),%r15
  movabs $0x241000000000000,%rbx
  lea    D1(%rip),%r14
  movabs $0x2c000000000000,%r13
  xchg   %ax,%ax
L67:
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L94
  sub    $0x1,%eax
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    $0x1,%r8d
  lea    0x11(%rsp,%rax,1),%rdi
  jmp    L167
  nopw   0x0(%rax,%rax,1)
L154:
  cmp    $0x39,%cl
  ja     L109
  mov    %r8,%rax
  shl    %cl,%rax
  test   %rbx,%rax
  jne    L182
  test   %r13,%rax
  jne    L149
  movabs $0x180000000000000,%r9
  test   %r9,%rax
  je     L109
  cmp    $0x37,%cl
  jne    L129
  add    $0x3,%esi
L109:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L19
L167:
  movzbl (%rdx),%ecx
  cmp    $0x31,%cl
  je     L136
  cmp    $0x34,%cl
  jne    L154
L136:
  lea    0x2(%rsi),%eax
  add    $0x4,%esi
  cmp    $0x31,%cl
  cmove  %eax,%esi
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L167
L19:
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L67
L116:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L129:
  cmp    $0x38,%cl
  jne    L109
  add    $0x7,%esi
  jmp    L109
  nopl   (%rax)
L149:
  add    $0x5,%esi
  jmp    L109
  nopl   (%rax)
L182:
  add    $0x6,%esi
  jmp    L109
L94:
  xor    %esi,%esi
  jmp    L19
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D15: %d

tool: D4: %s

tool: D1: %d leds


assistant: ```c
int main() {
  char Num[105];
  int N, cont, Led, cont2, Tam;
  scanf("%d", &N);
  for (cont = 0; cont < N; cont++) {
    scanf("%s", Num);
    Tam = strlen(Num);
    Led = 0;
    for (cont2 = 0; cont2 < Tam; cont2++) {
      if (Num[cont2] == '1' || Num[cont2] == '4' || Num[cont2] == '7' || Num[cont2] == '8') {
        if (Num[cont2] == '1')
          Led = Led + 2;
        if (Num[cont2] == '4')
          Led = Led + 4;
        if (Num[cont2] == '7')
          Led = Led + 3;
        if (Num[cont2] == '8')
          Led = Led + 7;
      } else {
        if (Num[cont2] == '2' || Num[cont2] == '3' || Num[cont2] == '5')
          Led = Led + 5;
        else if (Num[cont2] == '6' || Num[cont2] == '9' || Num[cont2] == '0')
          Led = Led + 6;
      }
    }
    printf("%d leds\n", Led);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L161
  xor    %ebp,%ebp
  lea    0x10(%rsp),%r12
  lea    D24(%rip),%r15
  movabs $0x241000000000000,%rbx
  lea    D25(%rip),%r14
  movabs $0x2c000000000000,%r13
  xchg   %ax,%ax
L107:
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L30
  sub    $0x1,%eax
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    $0x1,%r8d
  lea    0x11(%rsp,%rax,1),%rdi
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L26:
  cmp    $0x39,%cl
  ja     L98
  mov    %r8,%rax
  shl    %cl,%rax
  test   %rbx,%rax
  jne    L123
  test   %r13,%rax
  jne    L130
  movabs $0x180000000000000,%r9
  test   %r9,%rax
  je     L98
  cmp    $0x37,%cl
  jne    L15
  add    $0x3,%esi
L98:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L170
L92:
  movzbl (%rdx),%ecx
  cmp    $0x31,%cl
  je     L111
  cmp    $0x34,%cl
  jne    L26
L111:
  lea    0x2(%rsi),%eax
  add    $0x4,%esi
  cmp    $0x31,%cl
  cmove  %eax,%esi
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L92
L170:
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,0xc(%rsp)
  jg     L107
L161:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L175
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  cmp    $0x38,%cl
  jne    L98
  add    $0x7,%esi
  jmp    L98
  nopl   (%rax)
L130:
  add    $0x5,%esi
  jmp    L98
  nopl   (%rax)
L123:
  add    $0x6,%esi
  jmp    L98
L30:
  xor    %esi,%esi
  jmp    L170
L175:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D25
type_guessed: string

tool: D17: %d

tool: D24: %s

tool: D25: %d leds


assistant: ```c
int main() {
  char Num[105];
  int N, cont, Led, cont2, Tam;
  scanf("%d", &N);
  for (cont = 0; cont < N; cont++) {
    scanf("%s", Num);
    Tam = strlen(Num);
    Led = 0;
    for (cont2 = 0; cont2 < Tam; cont2++) {
      if (Num[cont2] == '1' || Num[cont2] == '4' || Num[cont2] == '7' || Num[cont2] == '8') {
        if (Num[cont2] == '1')
          Led = Led + 2;
        if (Num[cont2] == '4')
          Led = Led + 4;
        if (Num[cont2] == '7')
          Led = Led + 3;
        if (Num[cont2] == '8')
          Led = Led + 7;
      } else {
        if (Num[cont2] == '2' || Num[cont2] == '3' || Num[cont2] == '5')
          Led = Led + 5;
        else if (Num[cont2] == '6' || Num[cont2] == '9' || Num[cont2] == '0')
          Led = Led + 6;
      }
    }
    printf("%d leds\n", Led);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<revert_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <initialize_array@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L13:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void revert_array(double v[], double out[], int n) {
  initialize_array(out, n);
  int i;
  for (i = 0; i < n; i++) {
    out[i] = v[n - i - 1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<revert_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %edx,%esi
  mov    %rbp,%rdi
  call   <initialize_array@plt>
  test   %ebx,%ebx
  jle    L13
  movslq %ebx,%rax
  lea    -0x8(%r12,%rax,8),%rdx
  mov    %rbp,%rax
  lea    -0x1(%rbx),%ecx
  lea    0x8(%rbp,%rcx,8),%rcx
L9:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  sub    $0x8,%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L9
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void revert_array(double v[], double out[], int n) {
  initialize_array(out, n);
  int i;
  for (i = 0; i < n; i++) {
    out[i] = v[n - i - 1];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<revert_array>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %rbx,%rdi
  call   <initialize_array@plt>
  test   %ebp,%ebp
  jle    L2
  movslq %ebp,%rax
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rsi
  lea    -0x8(%r12,%rax,8),%rax
  lea    0x8(%rbx,%rdx,8),%rdx
  nopl   0x0(%rax)
L11:
  movsd  (%rax),%xmm0
  add    $0x8,%rsi
  sub    $0x8,%rax
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rdx,%rsi
  jne    L11
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void revert_array(double v[], double out[], int n) {
  initialize_array(out, n);
  int i;
  for (i = 0; i < n; i++) {
    out[i] = v[n - i - 1];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<revert_array>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  mov    %rbp,%rdi
  mov    %edx,%ebx
  call   <initialize_array@plt>
  test   %ebx,%ebx
  jle    L59
  movslq %ebx,%rax
  lea    -0x1(%rbx),%ecx
  shl    $0x3,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  lea    (%r12,%rax,1),%rsi
  cmp    %r12,%rdx
  setbe  %dl
  cmp    %rsi,%rbp
  setae  %sil
  or     %sil,%dl
  je     L69
  cmp    $0x2,%ecx
  jbe    L69
  mov    %ebx,%esi
  lea    -0x10(%r12,%rax,1),%rcx
  mov    %rbp,%rdx
  shr    %esi
  lea    -0x10(%rcx),%rax
  lea    -0x1(%rsi),%edi
  mov    %rax,%rsi
  shl    $0x4,%rdi
  sub    %rdi,%rsi
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L45:
  sub    $0x10,%rax
L1:
  movupd (%rcx),%xmm0
  add    $0x10,%rdx
  mov    %rax,%rcx
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rax
  jne    L45
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bl
  je     L59
  sub    %eax,%ebx
  movslq %ebx,%rbx
  movsd  -0x8(%r12,%rbx,8),%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,8)
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L69:
  lea    -0x8(%r12,%rax,1),%rax
  lea    0x8(%rbp,%rcx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L4:
  movsd  (%rax),%xmm0
  add    $0x8,%rbp
  sub    $0x8,%rax
  movsd  %xmm0,-0x8(%rbp)
  cmp    %rbp,%rdx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void revert_array(double v[], double out[], int n) {
  initialize_array(out, n);
  int i;
  for (i = 0; i < n; i++) {
    out[i] = v[n - i - 1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_max_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L24:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L26
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L24
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_max_int(int *arr, int len) {
  int max = 0;
  while (len--)
    if (max < arr[len])
      max = arr[len];
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_max_int>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %esi,%esi
  je     L18
  cltq
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rdx
  lea    -0x4(%rdi,%rax,1),%rax
  lea    -0x1(%rsi),%ecx
  shl    $0x2,%rcx
  sub    %rcx,%rax
  mov    %rax,%rsi
  mov    $0x0,%eax
L14:
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  sub    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L14
  ret
L18:
  mov    %esi,%eax
  ret
```

assistant: ```c
int find_max_int(int *arr, int len) {
  int max = 0;
  while (len--)
    if (max < arr[len])
      max = arr[len];
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_max_int>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L19
  movslq %edx,%rcx
  mov    %edx,%edx
  xor    %r8d,%r8d
  shl    $0x2,%rcx
  shl    $0x2,%rdx
  lea    (%rdi,%rcx,1),%rax
  lea    -0x4(%rdi,%rcx,1),%rcx
  sub    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L6
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_max_int(int *arr, int len) {
  int max = 0;
  while (len--)
    if (max < arr[len])
      max = arr[len];
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_max_int>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  je     L11
  cmp    $0x2,%r8d
  jbe    L46
  movslq %esi,%rax
  pxor   %xmm2,%xmm2
  lea    -0x10(%rdi,%rax,4),%rdx
  mov    %esi,%edi
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  lea    -0x1(%rdi),%r9d
  mov    %rax,%rdi
  shl    $0x4,%r9
  sub    %r9,%rdi
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L36:
  sub    $0x10,%rax
L49:
  movdqu (%rdx),%xmm0
  mov    %rax,%rdx
  pshufd $0x1b,%xmm0,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdi,%rax
  jne    L36
  movdqa %xmm2,%xmm0
  mov    %esi,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  movdqa %xmm0,%xmm1
  sub    %edx,%r8d
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%esi
  je     L54
L69:
  movslq %r8d,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    (%rcx,%rdx,4),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  test   %r8d,%r8d
  je     L76
  mov    -0x4(%rcx,%rsi,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  cmp    $0x1,%r8d
  je     L76
  mov    -0x8(%rcx,%rsi,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L11:
  xor    %eax,%eax
L76:
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  ret
L46:
  xor    %eax,%eax
  jmp    L69
```

assistant: ```c
int find_max_int(int *arr, int len) {
  int max = 0;
  while (len--)
    if (max < arr[len])
      max = arr[len];
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<gridroweliminate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ecx
  mov    %edx,%esi
  mov    %ecx,%r9d
  mov    $0x56,%edx
  mov    %ecx,%eax
  imul   %dl
  shr    $0x8,%ax
  mov    %ecx,%edi
  sar    $0x7,%dil
  sub    %edi,%eax
  lea    (%rax,%rax,2),%ebx
  mov    %bl,-0xe(%rsp)
  movsbl %bl,%r14d
  add    $0x1,%eax
  movsbl %al,%eax
  lea    (%rax,%rax,2),%ebx
  mov    %edx,%eax
  imul   %sil
  shr    $0x8,%ax
  sar    $0x7,%sil
  sub    %esi,%eax
  lea    (%rax,%rax,2),%r12d
  movsbl %r12b,%r11d
  lea    0x1(%rax),%edx
  movsbl %dl,%edx
  lea    (%rdx,%rdx,2),%r8d
  movsbl %al,%eax
  lea    (%rax,%rax,2),%r15d
  lea    0x3(%r15),%eax
  mov    %eax,-0xc(%rsp)
  movsbq %cl,%rax
  imul   $0x5a,%rax,%rax
  add    %rbp,%rax
  mov    %rax,-0x8(%rsp)
  mov    $0x1,%r13d
  movb   $0x0,-0xd(%rsp)
  jmp    L153
L93:
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,2),%rax
  cmpb   $0x1,(%rax,%r10,1)
  adc    $0x0,%sil
L38:
  add    $0x1,%edx
  movsbl %dl,%eax
  cmp    %r8d,%eax
  jge    L55
L1:
  cmp    %cl,%r9b
  jne    L93
  jmp    L38
L55:
  add    $0x1,%ecx
  movsbl %cl,%eax
  cmp    %ebx,%eax
  jge    L104
L35:
  cmp    %r8d,%r11d
  jge    L55
  movsbq %cl,%rdi
  imul   $0x5a,%rdi,%rdi
  add    %rbp,%rdi
  mov    %r12d,%edx
  mov    %r11d,%eax
  jmp    L1
L104:
  cmp    $0x6,%sil
  je     L116
L58:
  add    $0x1,%r13
  cmp    $0xa,%r13
  je     L120
L153:
  cmp    %ebx,%r14d
  jge    L58
  movzbl -0xe(%rsp),%ecx
  mov    $0x0,%esi
  movslq %r13d,%r10
  jmp    L35
L116:
  mov    -0x8(%rsp),%rax
  lea    (%rax,%r13,1),%rdx
  mov    $0x0,%eax
  mov    -0xc(%rsp),%ecx
  jmp    L136
L48:
  cmpb   $0x0,(%rdx)
  je     L130
  movb   $0x0,(%rdx)
  movb   $0x1,-0xd(%rsp)
L130:
  add    $0x1,%eax
  add    $0xa,%rdx
  cmp    $0x9,%eax
  je     L58
L136:
  cmp    %eax,%r15d
  jg     L48
  cmp    %eax,%ecx
  jg     L130
  jmp    L48
L120:
  movsbl -0xd(%rsp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int gridroweliminate(char grid[9][9][10], char m, char n) {
  char i, j, k, l, f = 0;
  for (k = 1; k < 10; ++k) {
    l = 0;
    for (i = 3 * (m / 3); i < 3 * (m / 3 + 1); ++i)
      for (j = 3 * (n / 3); j < 3 * (n / 3 + 1); ++j)
        if (i != m)
          if (!grid[i][j][k])
            ++l;
    if (l == 6)
      for (j = 0; j < 9; ++j)
        if (j < 3 * (n / 3) || j >= 3 * (n / 3 + 1))
          if (grid[m][j][k])
            grid[m][j][k] = 0, f = 1;
  }
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gridroweliminate>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  mov    $0x56,%edx
  push   %r15
  mov    %ecx,%eax
  push   %r14
  mov    %ecx,%r9d
  imul   %dl
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %ecx,%edi
  shr    $0x8,%ax
  sar    $0x7,%dil
  push   %rbx
  sub    %edi,%eax
  lea    (%rax,%rax,2),%r14d
  add    $0x1,%eax
  movsbl %r14b,%ebx
  movsbl %al,%eax
  movb   $0x0,-0xd(%rsp)
  mov    %ebx,-0x14(%rsp)
  lea    (%rax,%rax,2),%ebx
  mov    %edx,%eax
  imul   %sil
  sar    $0x7,%sil
  shr    $0x8,%ax
  sub    %esi,%eax
  lea    (%rax,%rax,2),%r12d
  lea    0x1(%rax),%edx
  movsbl %al,%eax
  lea    (%rax,%rax,2),%r15d
  movsbl %dl,%edx
  movsbl %r12b,%r11d
  lea    0x3(%r15),%eax
  lea    (%rdx,%rdx,2),%r8d
  mov    %eax,-0xc(%rsp)
  movsbq %cl,%rax
  imul   $0x5a,%rax,%rax
  add    %rbp,%rax
  mov    %rax,-0x8(%rsp)
  nopl   (%rax)
L109:
  cmp    -0x14(%rsp),%ebx
  jle    L117
  mov    %r14d,%ecx
  xor    %esi,%esi
  movslq %r13d,%r10
  xchg   %ax,%ax
L59:
  cmp    %r11d,%r8d
  jle    L113
  movsbq %cl,%rdi
  mov    %r12d,%edx
  movslq %r11d,%rax
  imul   $0x5a,%rdi,%rdi
  add    %rbp,%rdi
  cs nopw 0x0(%rax,%rax,1)
L35:
  cmp    %r9b,%cl
  je     L105
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rax,2),%rax
  cmpb   $0x1,(%rax,%r10,1)
  adc    $0x0,%sil
L105:
  add    $0x1,%edx
  movsbq %dl,%rax
  cmp    %r8d,%eax
  jl     L35
L113:
  add    $0x1,%ecx
  movsbl %cl,%eax
  cmp    %ebx,%eax
  jl     L59
  cmp    $0x6,%sil
  je     L98
L117:
  add    $0x1,%r13
  cmp    $0xa,%r13
  jne    L109
  movsbl -0xd(%rsp),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  mov    -0x8(%rsp),%rax
  mov    -0xc(%rsp),%ecx
  movzbl -0xd(%rsp),%esi
  lea    (%rax,%r13,1),%rdx
  xor    %eax,%eax
L60:
  cmp    %eax,%r15d
  jg     L70
  cmp    %ecx,%eax
  jl     L74
L70:
  cmpb   $0x0,(%rdx)
  je     L74
  movb   $0x0,(%rdx)
  mov    $0x1,%esi
L74:
  add    $0x1,%eax
  add    $0xa,%rdx
  cmp    $0x9,%eax
  jne    L60
  mov    %sil,-0xd(%rsp)
  jmp    L117
```

assistant: ```c
int gridroweliminate(char grid[9][9][10], char m, char n) {
  char i, j, k, l, f = 0;
  for (k = 1; k < 10; ++k) {
    l = 0;
    for (i = 3 * (m / 3); i < 3 * (m / 3 + 1); ++i)
      for (j = 3 * (n / 3); j < 3 * (n / 3 + 1); ++j)
        if (i != m)
          if (!grid[i][j][k])
            ++l;
    if (l == 6)
      for (j = 0; j < 9; ++j)
        if (j < 3 * (n / 3) || j >= 3 * (n / 3 + 1))
          if (grid[m][j][k])
            grid[m][j][k] = 0, f = 1;
  }
  return f;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uninitvar_wcsspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wcsspn@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_wcsspn(void) {
  wchar_t *ds;
  wchar_t *ss;
  (void)wcsspn(ds, ss);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uninitvar_wcsspn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <wcsspn@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_wcsspn(void) {
  wchar_t *ds;
  wchar_t *ss;
  (void)wcsspn(ds, ss);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninitvar_wcsspn>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcsspn@plt>
```

assistant: ```c
void uninitvar_wcsspn(void) {
  wchar_t *ds;
  wchar_t *ss;
  (void)wcsspn(ds, ss);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_wcsspn>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcsspn@plt>
```

assistant: ```c
void uninitvar_wcsspn(void) {
  wchar_t *ds;
  wchar_t *ss;
  (void)wcsspn(ds, ss);
}
```