ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wv_p_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1088(%rsp)
  xor    %eax,%eax
L50:
  mov    %eax,0x80(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L50
  mov    %rsp,%rsi
  lea    0x100(%rsp),%rbx
  lea    0x80(%rsp),%r8
  mov    %rbx,%rcx
  mov    $0x0,%edi
L44:
  lea    -0x80(%rcx),%rax
  mov    %edi,%edx
L0:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L0
  mov    %edx,(%rsi)
  add    $0x4,%rsi
  sub    $0xffffffffffffff80,%rcx
  cmp    %r8,%rsi
  jne    L44
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L52:
  lea    -0x80(%rbx),%rax
  mov    %r12d,%edx
L10:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L10
  cmp    %edx,(%rsp,%rbp,4)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x1,%rbp
  sub    $0xffffffffffffff80,%rbx
  cmp    $0x20,%rbp
  jne    L52
  mov    0x1088(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x1090,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wv_p_1() {
  int i, j, arr[1024], out[32], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) private(res) copyout(out)
  {
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
      res = 0;
#pragma acc loop worker vector reduction(+ : res)
      for (i = 0; i < 32; i++)
        res += arr[j * 32 + i];
      out[j] = res;
    }
  }
  for (j = 0; j < 32; j++) {
    hres = 0;
    for (i = 0; i < 32; i++)
      hres += arr[j * 32 + i];
    assert(out[j] == hres);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wv_p_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1088(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rdi
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L21
  mov    %rsp,%rbp
  lea    0x100(%rsp),%rcx
  mov    %rbp,%r8
  mov    %rcx,%rsi
L11:
  lea    -0x80(%rsi),%rax
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L13
  mov    %edx,(%r8)
  add    $0x4,%r8
  lea    0x80(%rax),%rsi
  cmp    %rdi,%r8
  jne    L11
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L22:
  lea    -0x80(%rcx),%rbx
  xor    %eax,%eax
  xchg   %ax,%ax
L7:
  add    (%rbx),%eax
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  jne    L7
  xor    %edi,%edi
  cmp    %eax,0x0(%rbp,%r12,4)
  sete   %dil
  add    $0x1,%r12
  call   <assert@plt>
  lea    0x80(%rbx),%rcx
  cmp    $0x20,%r12
  jne    L22
  mov    0x1088(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x1090,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wv_p_1() {
  int i, j, arr[1024], out[32], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) private(res) copyout(out)
  {
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
      res = 0;
#pragma acc loop worker vector reduction(+ : res)
      for (i = 0; i < 32; i++)
        res += arr[j * 32 + i];
      out[j] = res;
    }
  }
  for (j = 0; j < 32; j++) {
    hres = 0;
    for (i = 0; i < 32; i++)
      hres += arr[j * 32 + i];
    assert(out[j] == hres);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<wv_p_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x90,%rsp
  movdqa D9(%rip),%xmm0
  movdqa D6(%rip),%xmm2
  lea    0x80(%rsp),%rbx
  lea    0x1080(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1088(%rsp)
  xor    %eax,%eax
  mov    %rbx,%rax
  nopl   0x0(%rax)
L37:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %r12,%rax
  jne    L37
  mov    %rsp,%rbp
  mov    %rbx,%rax
  mov    %rbp,%rdx
  cs nopw 0x0(%rax,%rax,1)
L35:
  movdqa (%rax),%xmm0
  paddd  0x10(%rax),%xmm0
  sub    $0xffffffffffffff80,%rax
  add    $0x4,%rdx
  paddd  -0x60(%rax),%xmm0
  paddd  -0x50(%rax),%xmm0
  paddd  -0x40(%rax),%xmm0
  paddd  -0x30(%rax),%xmm0
  paddd  -0x20(%rax),%xmm0
  paddd  -0x10(%rax),%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,-0x4(%rdx)
  cmp    %r12,%rax
  jne    L35
  nopl   0x0(%rax,%rax,1)
L4:
  movdqa 0x10(%rbx),%xmm0
  paddd  (%rbx),%xmm0
  xor    %edi,%edi
  paddd  0x20(%rbx),%xmm0
  paddd  0x30(%rbx),%xmm0
  paddd  0x40(%rbx),%xmm0
  paddd  0x50(%rbx),%xmm0
  paddd  0x60(%rbx),%xmm0
  paddd  0x70(%rbx),%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    0x0(%rbp),%eax
  sete   %dil
  sub    $0xffffffffffffff80,%rbx
  add    $0x4,%rbp
  call   <assert@plt>
  cmp    %r12,%rbx
  jne    L4
  mov    0x1088(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x1090,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void wv_p_1() {
  int i, j, arr[1024], out[32], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32) private(res) copyout(out)
  {
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
      res = 0;
#pragma acc loop worker vector reduction(+ : res)
      for (i = 0; i < 32; i++)
        res += arr[j * 32 + i];
      out[j] = res;
    }
  }
  for (j = 0; j < 32; j++) {
    hres = 0;
    for (i = 0; i < 32; i++)
      hres += arr[j * 32 + i];
    assert(out[j] == hres);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L16
L4:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <xalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L16:
  leave
  ret
```

assistant: ```c
void *memdup(void *mem, size_t len) {
  void *ret;
  if (!mem)
    return NULL;
  ret = xalloc(len);
  return memcpy(ret, mem, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <xalloc@plt>
  mov    %rax,%rdi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rdi,%rax
  jmp    L2
```

assistant: ```c
void *memdup(void *mem, size_t len) {
  void *ret;
  if (!mem)
    return NULL;
  ret = xalloc(len);
  return memcpy(ret, mem, len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memdup>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <xalloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memdup(void *mem, size_t len) {
  void *ret;
  if (!mem)
    return NULL;
  ret = xalloc(len);
  return memcpy(ret, mem, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memdup>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <xalloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memdup(void *mem, size_t len) {
  void *ret;
  if (!mem)
    return NULL;
  ret = xalloc(len);
  return memcpy(ret, mem, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x4(%rbp),%eax
  jmp    L0
L4:
  mov    $0xffffffff,%eax
L0:
  leave
  ret
```

assistant: ```c
int cmp_cb(void *src, void *param) {
  int res = 0;
  if (strcmp(src, param) == 0)
    return res;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmp_cb(void *src, void *param) {
  int res = 0;
  if (strcmp(src, param) == 0)
    return res;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmp_cb(void *src, void *param) {
  int res = 0;
  if (strcmp(src, param) == 0)
    return res;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cmp_cb(void *src, void *param) {
  int res = 0;
  if (strcmp(src, param) == 0)
    return res;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  imul   $0x161f319d,%rax,%rax
  lea    -0x31f75b0d(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - 838294285UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   $0x161f319d,%rax,%rax
  sub    $0x31f75b0d,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - 838294285UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   $0x161f319d,%rax,%rax
  sub    $0x31f75b0d,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      state[0UL] += state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 371143069UL - 838294285UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c;
  c = 0;
  do
    ;
  while (0);
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int c;
  c = 0;
  do
    ;
  while (0);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int c;
  c = 0;
  do
    ;
  while (0);
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int c;
  c = 0;
  do
    ;
  while (0);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_cpy(char *begin, size_t len, char buffer[len + 1]) {
  memcpy(buffer, begin, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_cpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_cpy(char *begin, size_t len, char buffer[len + 1]) {
  memcpy(buffer, begin, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_cpy>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  mov    %rsi,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_cpy(char *begin, size_t len, char buffer[len + 1]) {
  memcpy(buffer, begin, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_cpy>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  mov    %rsi,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_cpy(char *begin, size_t len, char buffer[len + 1]) {
  memcpy(buffer, begin, len);
  buffer[len] = '\0';
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D16(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <num_jewels_in_stones@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D7
type: string

tool: D16: aA

tool: D8: aAAbbbb

tool: D7: %d


assistant: ```c
int main(void) {
  const char *J = "aA";
  const char *S = "aAAbbbb";
  int result = num_jewels_in_stones(J, S);
  printf("%d\n", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <num_jewels_in_stones@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D29
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D19: aAAbbbb

tool: D29: aA

tool: D3: %d


assistant: ```c
int main(void) {
  const char *J = "aA";
  const char *S = "aAAbbbb";
  int result = num_jewels_in_stones(J, S);
  printf("%d\n", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <num_jewels_in_stones@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D18: aAAbbbb

tool: D29: aA

tool: D7: %d


assistant: ```c
int main(void) {
  const char *J = "aA";
  const char *S = "aAAbbbb";
  int result = num_jewels_in_stones(J, S);
  printf("%d\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <num_jewels_in_stones@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string

tool: D19: aAAbbbb

tool: D23: aA

tool: D25: %d


assistant: ```c
int main(void) {
  const char *J = "aA";
  const char *S = "aAAbbbb";
  int result = num_jewels_in_stones(J, S);
  printf("%d\n", result);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_proc_error_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L50
  cmpl   $0x3,-0x4(%rbp)
  jg     L69
  cmpl   $0x2,-0x4(%rbp)
  je     L52
  cmpl   $0x2,-0x4(%rbp)
  jg     L69
  cmpl   $0x0,-0x4(%rbp)
  je     L68
  cmpl   $0x1,-0x4(%rbp)
  je     L97
  jmp    L69
L68:
  lea    D1(%rip),%rax
  jmp    L80
L97:
  lea    D41(%rip),%rax
  jmp    L80
L52:
  lea    D27(%rip),%rax
  jmp    L80
L50:
  lea    D17(%rip),%rax
  jmp    L80
L69:
  lea    D37(%rip),%rax
L80:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D41
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D37
datatype: string

tool: D1: No error

tool: D41: Invalid format

tool: D27: Invalid arguments

tool: D17: User not found

tool: D37: Unknown error

assistant: ```c
const char *get_proc_error_str(int error) {
  switch (error) {
  case 0:
    return "No error";
  case 1:
    return "Invalid format";
  case 2:
    return "Invalid arguments";
  case 3:
    return "User not found";
  }
  return "Unknown error";
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_proc_error_str>:
  endbr64
  lea    D57(%rip),%rax
  cmp    $0x2,%edi
  je     L1
  jg     L4
  lea    D41(%rip),%rax
  test   %edi,%edi
  je     L1
  cmp    $0x1,%edi
  lea    D52(%rip),%rax
  lea    D36(%rip),%rdx
  cmove  %rdx,%rax
  ret
L4:
  cmp    $0x3,%edi
  lea    D52(%rip),%rax
  lea    D11(%rip),%rdx
  cmove  %rdx,%rax
L1:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D57
data_type: string
name: extract_symbolic_data
arguments: data_label: D41
data_type: string
name: extract_symbolic_data
arguments: data_label: D52
data_type: string
name: extract_symbolic_data
arguments: data_label: D36
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D57: Invalid arguments

tool: D41: No error

tool: D52: Unknown error

tool: D36: Invalid format

tool: D11: User not found

assistant: ```c
const char *get_proc_error_str(int error) {
  switch (error) {
  case 0:
    return "No error";
  case 1:
    return "Invalid format";
  case 2:
    return "Invalid arguments";
  case 3:
    return "User not found";
  }
  return "Unknown error";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_proc_error_str>:
  endbr64
  lea    D27(%rip),%rax
  cmp    $0x2,%edi
  je     L14
  jg     L13
  lea    D41(%rip),%rax
  test   %edi,%edi
  je     L14
  cmp    $0x1,%edi
  lea    D48(%rip),%rdx
  lea    D36(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  cmp    $0x3,%edi
  lea    D36(%rip),%rax
  lea    D59(%rip),%rdx
  cmove  %rdx,%rax
L14:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
data_type: string
name: retrieve_data
arguments: data_tag: D41
data_type: string
name: retrieve_data
arguments: data_tag: D48
data_type: string
name: retrieve_data
arguments: data_tag: D36
data_type: string
name: retrieve_data
arguments: data_tag: D59
data_type: string

tool: D27: Invalid arguments

tool: D41: No error

tool: D48: Invalid format

tool: D36: Unknown error

tool: D59: User not found

assistant: ```c
const char *get_proc_error_str(int error) {
  switch (error) {
  case 0:
    return "No error";
  case 1:
    return "Invalid format";
  case 2:
    return "Invalid arguments";
  case 3:
    return "User not found";
  }
  return "Unknown error";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_proc_error_str>:
  endbr64
  lea    D35(%rip),%rax
  cmp    $0x2,%edi
  je     L27
  jg     L17
  lea    D29(%rip),%rax
  test   %edi,%edi
  je     L27
  cmp    $0x1,%edi
  lea    D3(%rip),%rdx
  lea    D5(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    $0x3,%edi
  lea    D5(%rip),%rax
  lea    D1(%rip),%rdx
  cmove  %rdx,%rax
L27:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D29
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D1
type: string

tool: D35: Invalid arguments

tool: D29: No error

tool: D3: Invalid format

tool: D5: Unknown error

tool: D1: User not found

assistant: ```c
const char *get_proc_error_str(int error) {
  switch (error) {
  case 0:
    return "No error";
  case 1:
    return "Invalid format";
  case 2:
    return "Invalid arguments";
  case 3:
    return "User not found";
  }
  return "Unknown error";
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__moddi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__you_should_not_divide_ll_in_debugger_sw@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
long long __moddi3(long long A, long long B) {
  __you_should_not_divide_ll_in_debugger_sw();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__moddi3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__you_should_not_divide_ll_in_debugger_sw@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long __moddi3(long long A, long long B) {
  __you_should_not_divide_ll_in_debugger_sw();
  return 0;
}
```