ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<dd_two_diff>:
  endbr64
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm3
  movapd %xmm2,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm4
  addsd  %xmm3,%xmm1
  subsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
double dd_two_diff(double a, double b, double *err) {
  double s = a - b;
  double bb = s - a;
  *err = (a - (s - bb)) - (b + bb);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printswitch>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xc,%edi
  ja     L64
  mov    %edi,%eax
  lea    D111(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D120(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L119:
  add    $0x8,%rsp
  ret
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D77(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D79(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D128(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D94(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
L64:
  mov    %edi,%esi
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L119
```

tool_calls: name: read_data
arguments: tag: D120
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D77
datatype: string
name: read_data
arguments: tag: D2
datatype: string
name: read_data
arguments: tag: D64
datatype: string
name: read_data
arguments: tag: D79
datatype: string
name: read_data
arguments: tag: D128
datatype: string
name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D94
datatype: string
name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D61
datatype: string

tool: D120: HAPLOID

tool: D24: DIPLOID

tool: D77: TRIPLOID

tool: D2: TETRAPLOID

tool: D64: PENTAPLOID

tool: D79: HEXAPLOID

tool: D128: SEPTAPLOID

tool: D4: OCTAPLOID

tool: D46: NONAPLOID

tool: D9: DECAPLOID

tool: D94: HENDECAPLOID

tool: D12: DODECAPLOID

tool: D61: %d-PLOID

assistant: ```c
void printswitch(int ploidy) {
  switch (ploidy) {
  case 1:
    printf("HAPLOID");
    break;
  case 2:
    printf("DIPLOID");
    break;
  case 3:
    printf("TRIPLOID");
    break;
  case 4:
    printf("TETRAPLOID");
    break;
  case 5:
    printf("PENTAPLOID");
    break;
  case 6:
    printf("HEXAPLOID");
    break;
  case 7:
    printf("SEPTAPLOID");
    break;
  case 8:
    printf("OCTAPLOID");
    break;
  case 9:
    printf("NONAPLOID");
    break;
  case 10:
    printf("DECAPLOID");
    break;
  case 11:
    printf("HENDECAPLOID");
    break;
  case 12:
    printf("DODECAPLOID");
    break;
  default:
    printf("%d-PLOID", ploidy);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clear_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unpost_menu@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free_menu@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free_item@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void clear_menu(MENU *my_menu, ITEM **my_items) {
  unpost_menu(my_menu);
  free_menu(my_menu);
  for (int i = 0; my_items[i]; ++i)
    free_item(my_items[i]);
  free(my_items);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_menu>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <unpost_menu@plt>
  mov    %rbx,%rdi
  call   <free_menu@plt>
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L1
  lea    0x8(%rbp),%rbx
L6:
  call   <free_item@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L6
L1:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void clear_menu(MENU *my_menu, ITEM **my_items) {
  unpost_menu(my_menu);
  free_menu(my_menu);
  for (int i = 0; my_items[i]; ++i)
    free_item(my_items[i]);
  free(my_items);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clear_menu>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <unpost_menu@plt>
  mov    %r12,%rdi
  call   <free_menu@plt>
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L19
  lea    0x8(%rbp),%rbx
  nopl   0x0(%rax,%rax,1)
L7:
  call   <free_item@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L7
L19:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
```

assistant: ```c
void clear_menu(MENU *my_menu, ITEM **my_items) {
  unpost_menu(my_menu);
  free_menu(my_menu);
  for (int i = 0; my_items[i]; ++i)
    free_item(my_items[i]);
  free(my_items);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear_menu>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <unpost_menu@plt>
  mov    %r12,%rdi
  call   <free_menu@plt>
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L12
  lea    0x8(%rbp),%rbx
  nopl   0x0(%rax,%rax,1)
L13:
  call   <free_item@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L13
L12:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <free@plt>
```

assistant: ```c
void clear_menu(MENU *my_menu, ITEM **my_items) {
  unpost_menu(my_menu);
  free_menu(my_menu);
  for (int i = 0; my_items[i]; ++i)
    free_item(my_items[i]);
  free(my_items);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_and@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_neg@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_or@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_xor@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_shift_left@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <bit_shift_right@plt>
  nop
  leave
  ret
```

assistant: ```c
void main(int argc, char *argv[]) {
  int flag = strtol(argv[1], NULL, 0);
  int mask = strtol(argv[2], NULL, 0);
  bit_and(flag, mask);
  bit_neg(flag, mask);
  bit_or(flag, mask);
  bit_xor(flag, mask);
  bit_shift_left(flag, mask);
  bit_shift_right(flag, mask);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebx
  mov    0x10(%rbp),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <bit_and@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bit_neg@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bit_or@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bit_xor@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bit_shift_left@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bit_shift_right@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main(int argc, char *argv[]) {
  int flag = strtol(argv[1], NULL, 0);
  int mask = strtol(argv[2], NULL, 0);
  bit_and(flag, mask);
  bit_neg(flag, mask);
  bit_or(flag, mask);
  bit_xor(flag, mask);
  bit_shift_left(flag, mask);
  bit_shift_right(flag, mask);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    0x10(%r12),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%ebp
  call   <strtol@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <bit_and@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_neg@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_or@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_xor@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_shift_left@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <bit_shift_right@plt>
```

assistant: ```c
void main(int argc, char *argv[]) {
  int flag = strtol(argv[1], NULL, 0);
  int mask = strtol(argv[2], NULL, 0);
  bit_and(flag, mask);
  bit_neg(flag, mask);
  bit_or(flag, mask);
  bit_xor(flag, mask);
  bit_shift_left(flag, mask);
  bit_shift_right(flag, mask);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    0x10(%r12),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %eax,%ebp
  call   <strtol@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    %eax,%esi
  call   <bit_and@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_neg@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_or@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_xor@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <bit_shift_left@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <bit_shift_right@plt>
```

assistant: ```c
void main(int argc, char *argv[]) {
  int flag = strtol(argv[1], NULL, 0);
  int mask = strtol(argv[2], NULL, 0);
  bit_and(flag, mask);
  bit_neg(flag, mask);
  bit_or(flag, mask);
  bit_xor(flag, mask);
  bit_shift_left(flag, mask);
  bit_shift_right(flag, mask);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x460,%rsp
  mov    %rdi,-0x448(%rbp)
  mov    %rsi,-0x450(%rbp)
  mov    %rdx,-0x458(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x438(%rbp)
  mov    -0x448(%rbp),%rax
  mov    %rax,-0x430(%rbp)
  mov    -0x450(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x428(%rbp)
  mov    -0x458(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x420(%rbp)
L5:
  mov    -0x450(%rbp),%rdx
  mov    -0x430(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L32
  mov    -0x430(%rbp),%rdx
  mov    -0x438(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  lea    -0x410(%rbp),%rdx
  mov    -0x448(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  jmp    L16
L32:
  mov    -0x418(%rbp),%rax
  sub    -0x430(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x430(%rbp),%rcx
  mov    -0x438(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x430(%rbp),%rax
  add    %rax,-0x438(%rbp)
  mov    -0x420(%rbp),%rdx
  mov    -0x458(%rbp),%rcx
  mov    -0x438(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x420(%rbp),%rax
  add    %rax,-0x438(%rbp)
  mov    -0x418(%rbp),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x430(%rbp)
  jmp    L5
L16:
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
void str_replace(char *target, const char *needle, const char *replacement) {
  char buffer[1024] = {0};
  char *insert_point = &buffer[0];
  const char *tmp = target;
  size_t needle_len = strlen(needle);
  size_t repl_len = strlen(replacement);
  while (1) {
    const char *p = strstr(tmp, needle);
    if (p == NULL) {
      strcpy(insert_point, tmp);
      break;
    }
    memcpy(insert_point, tmp, p - tmp);
    insert_point += p - tmp;
    memcpy(insert_point, replacement, repl_len);
    insert_point += repl_len;
    tmp = p + needle_len;
  }
  strcpy(target, buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rdi,%r12
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%rbx
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  lea    0x30(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,0x10(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  lea    0x20(%rsp),%r13
  jmp    L2
L13:
  mov    %rax,%rbp
  sub    %r12,%rbp
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  add    %rbp,%r13
  mov    %r14,%rdx
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  add    %r14,%r13
  mov    0x10(%rsp),%rax
  lea    (%rbx,%rax,1),%r12
L2:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L13
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  lea    0x20(%rsp),%rsi
  mov    0x18(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void str_replace(char *target, const char *needle, const char *replacement) {
  char buffer[1024] = {0};
  char *insert_point = &buffer[0];
  const char *tmp = target;
  size_t needle_len = strlen(needle);
  size_t repl_len = strlen(replacement);
  while (1) {
    const char *p = strstr(tmp, needle);
    if (p == NULL) {
      strcpy(insert_point, tmp);
      break;
    }
    memcpy(insert_point, tmp, p - tmp);
    insert_point += p - tmp;
    memcpy(insert_point, replacement, repl_len);
    insert_point += repl_len;
    tmp = p + needle_len;
  }
  strcpy(target, buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  mov    $0x7e,%ecx
  mov    %rdi,%r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x438,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x30(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbp,0x18(%rsp)
  mov    %rax,%rbx
  jmp    L2
  nopl   0x0(%rax)
L29:
  mov    %rax,%r13
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r13
  mov    %r13,%rdx
  add    %r13,%rbp
  call   <memcpy@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  add    %rbx,%rbp
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  lea    (%r14,%rax,1),%r15
L2:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L29
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void str_replace(char *target, const char *needle, const char *replacement) {
  char buffer[1024] = {0};
  char *insert_point = &buffer[0];
  const char *tmp = target;
  size_t needle_len = strlen(needle);
  size_t repl_len = strlen(replacement);
  while (1) {
    const char *p = strstr(tmp, needle);
    if (p == NULL) {
      strcpy(insert_point, tmp);
      break;
    }
    memcpy(insert_point, tmp, p - tmp);
    insert_point += p - tmp;
    memcpy(insert_point, replacement, repl_len);
    insert_point += repl_len;
    tmp = p + needle_len;
  }
  strcpy(target, buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_replace>:
  endbr64
  push   %r15
  mov    $0x7e,%ecx
  mov    %rdi,%r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x438,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x30(%rsp),%rdi
  lea    0x20(%rsp),%rbp
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbp,0x18(%rsp)
  mov    %rax,%rbx
  jmp    L3
  nopl   0x0(%rax)
L27:
  mov    %rax,%r13
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%r13
  mov    %r13,%rdx
  add    %r13,%rbp
  call   <memcpy@plt>
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  mov    %rbx,%rdx
  add    %rbx,%rbp
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  lea    (%r14,%rax,1),%r15
L3:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L27
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void str_replace(char *target, const char *needle, const char *replacement) {
  char buffer[1024] = {0};
  char *insert_point = &buffer[0];
  const char *tmp = target;
  size_t needle_len = strlen(needle);
  size_t repl_len = strlen(replacement);
  while (1) {
    const char *p = strstr(tmp, needle);
    if (p == NULL) {
      strcpy(insert_point, tmp);
      break;
    }
    memcpy(insert_point, tmp, p - tmp);
    insert_point += p - tmp;
    memcpy(insert_point, replacement, repl_len);
    insert_point += repl_len;
    tmp = p + needle_len;
  }
  strcpy(target, buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cMRightTrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L64:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L71
  mov    -0x18(%rbp),%rax
  jmp    L41
L71:
  subq   $0x1,-0x8(%rbp)
  jmp    L4
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L78
L42:
  subq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L28
L78:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L41:
  pop    %rbp
  ret
```

assistant: ```c
char *cMRightTrim(char *str) {
  char *s = str;
  while (*s)
    ++s;
  if (s == str)
    return str;
  --s;
  while (s >= str)
    if ((*s == ' ') || (*s == '\t') || (*s == '\r') || (*s == '\n'))
      --s;
    else
      break;
  *(s + 1) = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cMRightTrim>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L7
  mov    %rdi,%rcx
L52:
  mov    %rcx,%rdx
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L52
  cmp    %rcx,%rax
  je     L7
  cmp    %rdx,%rax
  ja     L1
  movabs $0x100002600,%rsi
  jmp    L25
L22:
  bt     %rcx,%rsi
  jae    L1
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  ja     L1
L25:
  movzbl (%rdx),%ecx
  cmp    $0x20,%cl
  jbe    L22
L1:
  movb   $0x0,0x1(%rdx)
L7:
  ret
```

assistant: ```c
char *cMRightTrim(char *str) {
  char *s = str;
  while (*s)
    ++s;
  if (s == str)
    return str;
  --s;
  while (s >= str)
    if ((*s == ' ') || (*s == '\t') || (*s == '\r') || (*s == '\n'))
      --s;
    else
      break;
  *(s + 1) = 0;
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cMRightTrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L50
  mov    %rdi,%rcx
  nop
L44:
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,0x1(%rdx)
  jne    L44
  cmp    %rcx,%rax
  je     L50
  cmp    %rdx,%rax
  ja     L2
  movabs $0xfffffffeffffd9ff,%rsi
  nopl   0x0(%rax)
L22:
  movzbl (%rdx),%ecx
  cmp    $0x20,%cl
  jbe    L62
L2:
  movb   $0x0,0x1(%rdx)
L50:
  ret
  nopl   (%rax)
L62:
  bt     %rcx,%rsi
  jb     L2
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jbe    L22
  jmp    L2
```

assistant: ```c
char *cMRightTrim(char *str) {
  char *s = str;
  while (*s)
    ++s;
  if (s == str)
    return str;
  --s;
  while (s >= str)
    if ((*s == ' ') || (*s == '\t') || (*s == '\r') || (*s == '\n'))
      --s;
    else
      break;
  *(s + 1) = 0;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cMRightTrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L65
  mov    %rdi,%rcx
  nop
L66:
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,0x1(%rdx)
  jne    L66
  cmp    %rcx,%rax
  je     L65
  cmp    %rdx,%rax
  ja     L26
  movabs $0xfffffffeffffd9ff,%rsi
  nopl   0x0(%rax)
L79:
  movzbl (%rdx),%ecx
  cmp    $0x20,%cl
  jbe    L49
L26:
  movb   $0x0,0x1(%rdx)
L65:
  ret
  nopl   (%rax)
L49:
  bt     %rcx,%rsi
  jb     L26
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jbe    L79
  jmp    L26
```

assistant: ```c
char *cMRightTrim(char *str) {
  char *s = str;
  while (*s)
    ++s;
  if (s == str)
    return str;
  --s;
  while (s >= str)
    if ((*s == ' ') || (*s == '\t') || (*s == '\r') || (*s == '\n'))
      --s;
    else
      break;
  *(s + 1) = 0;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fillTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L13
  mov    $0xffffffff,%eax
  jmp    L2
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int fillTable(int inode, int *pos, int *table) {
  int i;
  for (i = 0; i < (*pos); i++) {
    if (inode == table[(i)])
      ;
    return -1;
  }
  table[(*pos)] = inode;
  *pos++;
  return 0;
}
```