ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <split_get_size@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  cmpb   $0x0,0x0(%rbp)
  mov    %rax,%r9
  je     L19
  mov    %rax,%r10
  mov    %rbp,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L32:
  lea    0x1(%rbp,%rax,1),%rax
  mov    %rdx,(%r10)
  add    $0x1,%r8d
  sub    %eax,%ecx
  jmp    L15
L17:
  add    $0x1,%rax
  cmp    %ebx,%edx
  je     L54
L15:
  movsbl (%rax),%edx
  lea    (%rcx,%rax,1),%esi
  mov    %rax,%rdi
  test   %dl,%dl
  jne    L17
L47:
  movslq %r8d,%r8
  lea    (%r9,%r8,8),%rax
L19:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L54:
  lea    0x2(%rsi),%ecx
  movb   $0x0,(%rdi)
  add    $0x8,%r10
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  cmpb   $0x0,(%rdx)
  jne    L32
  jmp    L47
```

assistant: ```c
char **split(char *buffer, int delimeter) {
  int size = split_get_size(buffer, delimeter);
  char **res = (char **)malloc(sizeof(char *) * (size + 1));
  int i = 0;
  int p = 0;
  while (buffer[i] != 0) {
    res[p++] = buffer + i;
    do {
      i++;
    } while (buffer[i] != 0 && buffer[i] != delimeter);
    if (buffer[i] != 0) {
      buffer[i] = 0;
      i++;
    }
  }
  res[p] = 0;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <split_get_size@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  cmpb   $0x0,0x0(%rbp)
  mov    %rax,%r9
  je     L39
  mov    %rax,%r10
  mov    %rbp,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    0x1(%rbp,%rax,1),%rax
  mov    %rdx,(%r10)
  add    $0x1,%r8d
  sub    %eax,%ecx
  jmp    L52
L16:
  add    $0x1,%rax
  cmp    %ebx,%edx
  je     L27
L52:
  movsbl (%rax),%edx
  lea    (%rcx,%rax,1),%esi
  mov    %rax,%rdi
  test   %dl,%dl
  jne    L16
L0:
  movslq %r8d,%r8
  lea    (%r9,%r8,8),%rax
L39:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L27:
  lea    0x2(%rsi),%ecx
  movb   $0x0,(%rdi)
  add    $0x8,%r10
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  cmpb   $0x0,(%rdx)
  jne    L10
  jmp    L0
```

assistant: ```c
char **split(char *buffer, int delimeter) {
  int size = split_get_size(buffer, delimeter);
  char **res = (char **)malloc(sizeof(char *) * (size + 1));
  int i = 0;
  int p = 0;
  while (buffer[i] != 0) {
    res[p++] = buffer + i;
    do {
      i++;
    } while (buffer[i] != 0 && buffer[i] != delimeter);
    if (buffer[i] != 0) {
      buffer[i] = 0;
      i++;
    }
  }
  res[p] = 0;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toUpperCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <initString@plt>
  cmpl   $0x0,-0x14(%rbp)
  jg     L13
  mov    -0x30(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L23
L13:
  movl   $0x0,-0x18(%rbp)
  jmp    L30
L15:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L23:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: <empty>

assistant: ```c
void toUpperCase(char src[20], char dst[20]) {
  int len = strlen(src);
  int i;
  initString(dst);
  if (len <= 0) {
    strcpy(dst, "<empty>");
  } else {
    for (i = 0; i < len; i++)
      dst[i] = toupper(src[i]);
    dst[i] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toUpperCase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  call   <initString@plt>
  mov    %r13d,%r14d
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jle    L28
L0:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L0
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: <empty>

assistant: ```c
void toUpperCase(char src[20], char dst[20]) {
  int len = strlen(src);
  int i;
  initString(dst);
  if (len <= 0) {
    strcpy(dst, "<empty>");
  } else {
    for (i = 0; i < len; i++)
      dst[i] = toupper(src[i]);
    dst[i] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toUpperCase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r13
  call   <initString@plt>
  test   %r13d,%r13d
  jle    L17
  nopl   0x0(%rax)
L1:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L1
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r13,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  pop    %rbx
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <strcpy@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: <empty>

assistant: ```c
void toUpperCase(char src[20], char dst[20]) {
  int len = strlen(src);
  int i;
  initString(dst);
  if (len <= 0) {
    strcpy(dst, "<empty>");
  } else {
    for (i = 0; i < len; i++)
      dst[i] = toupper(src[i]);
    dst[i] = '\0';
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<toUpperCase>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r13
  call   <initString@plt>
  test   %r13d,%r13d
  jle    L4
  nopl   0x0(%rax)
L5:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L5
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r13,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  pop    %rbx
  mov    %rbp,%rdi
  lea    D6(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <strcpy@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: <empty>

assistant: ```c
void toUpperCase(char src[20], char dst[20]) {
  int len = strlen(src);
  int i;
  initString(dst);
  if (len <= 0) {
    strcpy(dst, "<empty>");
  } else {
    for (i = 0; i < len; i++)
      dst[i] = toupper(src[i]);
    dst[i] = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bpsconv>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%rsi
  mov    0x30(%rsp),%r10
  mov    0x38(%rsp),%r11
  mov    %r9d,%eax
  sub    $0x1,%eax
  js     L30
  cltq
  movslq %ebp,%rdx
  shl    $0x3,%rdx
  lea    (%r10,%rdx,1),%rdi
  add    %r11,%rdx
L77:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%r11,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L77
L30:
  test   %ebp,%ebp
  jle    L39
  movslq %r8d,%r8
  lea    0x0(,%r8,8),%r13
  mov    %r9d,%eax
  add    %rax,%rax
  sub    %rax,%r8
  shl    $0x3,%r8
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  pxor   %xmm5,%xmm5
  jmp    L32
L38:
  mov    %r12,%rdx
  mov    %r13,%rax
  movapd %xmm5,%xmm3
  movapd %xmm5,%xmm2
L71:
  movsd  (%r10,%rdx,1),%xmm1
  movapd %xmm1,%xmm0
  mulsd  -0x8(%rsi,%rax,1),%xmm0
  addsd  %xmm0,%xmm2
  movsd  (%r11,%rdx,1),%xmm0
  movapd %xmm0,%xmm4
  mulsd  -0x8(%rcx,%rax,1),%xmm4
  addsd  %xmm4,%xmm2
  mulsd  (%rsi,%rax,1),%xmm1
  addsd  %xmm1,%xmm3
  mulsd  (%rcx,%rax,1),%xmm0
  addsd  %xmm0,%xmm3
  mov    %rax,%rdi
  sub    $0x10,%rax
  add    $0x8,%rdx
  cmp    %r8,%rdi
  jne    L71
L19:
  movsd  %xmm2,(%rbx,%r12,2)
  movsd  %xmm3,0x8(%rbx,%r12,2)
  add    $0x1,%r14d
  add    $0x8,%r12
  cmp    %r14d,%ebp
  je     L39
L32:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  test   %r9d,%r9d
  jns    L38
  jmp    L19
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bpsconv(double *x_out, int lx, double *g0, double *g1, int lhm1, int lhhm1, double *x_inl, double *x_inh) {
  int i, j, ind, tj;
  double x0, x1;
  for (i = lhhm1 - 1; i > -1; i--) {
    x_inl[i] = x_inl[lx + i];
    x_inh[i] = x_inh[lx + i];
  }
  ind = 0;
  for (i = 0; i < (lx); i++) {
    x0 = 0;
    x1 = 0;
    tj = -2;
    for (j = 0; j <= lhhm1; j++) {
      tj += 2;
      x0 = x0 + x_inl[i + j] * g0[lhm1 - 1 - tj] + x_inh[i + j] * g1[lhm1 - 1 - tj];
      x1 = x1 + x_inl[i + j] * g0[lhm1 - tj] + x_inh[i + j] * g1[lhm1 - tj];
    }
    x_out[ind++] = x0;
    x_out[ind++] = x1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bpsconv>:
  endbr64
  mov    %r9d,%eax
  push   %r13
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    0x28(%rsp),%r10
  mov    0x30(%rsp),%r11
  sub    $0x1,%eax
  js     L58
  movslq %ebp,%rdx
  cltq
  shl    $0x3,%rdx
  lea    (%r10,%rdx,1),%rdi
  add    %r11,%rdx
  nopw   0x0(%rax,%rax,1)
L29:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%r10,%rax,8)
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%r11,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L29
L58:
  test   %ebp,%ebp
  jle    L35
  mov    %r12d,%edx
  lea    -0x1(%r8),%eax
  movslq %ebp,%r13
  xor    %r8d,%r8d
  lea    0x8(,%rdx,8),%rdi
  shl    $0x4,%rdx
  cltq
  sub    %rdx,%rbx
  lea    0x0(,%rax,8),%rbp
  pxor   %xmm5,%xmm5
  mov    %rbx,%r9
  nopl   0x0(%rax,%rax,1)
L36:
  movapd %xmm5,%xmm3
  movapd %xmm5,%xmm2
  test   %r12d,%r12d
  js     L1
  lea    0x0(,%r8,8),%rdx
  movapd %xmm5,%xmm3
  movapd %xmm5,%xmm2
  mov    %rbp,%rax
  nopl   0x0(%rax,%rax,1)
L22:
  movsd  (%r10,%rdx,1),%xmm1
  movsd  (%rsi,%rax,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm4
  mulsd  %xmm1,%xmm0
  mulsd  0x8(%rsi,%rax,1),%xmm1
  addsd  %xmm0,%xmm2
  movsd  (%r11,%rdx,1),%xmm0
  add    $0x8,%rdx
  addsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm4
  mulsd  0x8(%rcx,%rax,1),%xmm0
  sub    $0x10,%rax
  addsd  %xmm4,%xmm2
  addsd  %xmm0,%xmm3
  cmp    %rdx,%rdi
  jne    L22
L1:
  add    $0x1,%r8
  movsd  %xmm2,-0x10(%r9,%rdi,2)
  movsd  %xmm3,-0x8(%r9,%rdi,2)
  add    $0x8,%rdi
  cmp    %r8,%r13
  jne    L36
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bpsconv(double *x_out, int lx, double *g0, double *g1, int lhm1, int lhhm1, double *x_inl, double *x_inh) {
  int i, j, ind, tj;
  double x0, x1;
  for (i = lhhm1 - 1; i > -1; i--) {
    x_inl[i] = x_inl[lx + i];
    x_inh[i] = x_inh[lx + i];
  }
  ind = 0;
  for (i = 0; i < (lx); i++) {
    x0 = 0;
    x1 = 0;
    tj = -2;
    for (j = 0; j <= lhhm1; j++) {
      tj += 2;
      x0 = x0 + x_inl[i + j] * g0[lhm1 - 1 - tj] + x_inh[i + j] * g1[lhm1 - 1 - tj];
      x1 = x1 + x_inl[i + j] * g0[lhm1 - tj] + x_inh[i + j] * g1[lhm1 - tj];
    }
    x_out[ind++] = x0;
    x_out[ind++] = x1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: Failed xmalloc: 

assistant: ```c
void *xmalloc(size_t sz) {
  void *out;
  out = malloc(sz);
  if (!out) {
    perror("Failed xmalloc: ");
    abort();
  }
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xmalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
L10:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: Failed xmalloc: 

assistant: ```c
void *xmalloc(size_t sz) {
  void *out;
  out = malloc(sz);
  if (!out) {
    perror("Failed xmalloc: ");
    abort();
  }
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L8:
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: Failed xmalloc: 

assistant: ```c
void *xmalloc(size_t sz) {
  void *out;
  out = malloc(sz);
  if (!out) {
    perror("Failed xmalloc: ");
    abort();
  }
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L11:
  mov    %r12,%rax
  pop    %r12
  ret
L19:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: Failed xmalloc: 

assistant: ```c
void *xmalloc(size_t sz) {
  void *out;
  out = malloc(sz);
  if (!out) {
    perror("Failed xmalloc: ");
    abort();
  }
  return out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mod_N_pm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  cmpw   $0x26f,-0x4(%rbp)
  jbe    L2
  movzwl -0x4(%rbp),%eax
  sub    $0x270,%ax
  jmp    L13
L2:
  movzwl -0x4(%rbp),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short mod_N_pm(unsigned short a) {
  if (a > 624 - 1)
    return a - 624;
  else
    return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mod_N_pm>:
  endbr64
  lea    -0x270(%rdi),%eax
  cmp    $0x26f,%di
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned short mod_N_pm(unsigned short a) {
  if (a > 624 - 1)
    return a - 624;
  else
    return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mod_N_pm>:
  endbr64
  lea    -0x270(%rdi),%eax
  cmp    $0x26f,%di
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned short mod_N_pm(unsigned short a) {
  if (a > 624 - 1)
    return a - 624;
  else
    return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mod_N_pm>:
  endbr64
  lea    -0x270(%rdi),%eax
  cmp    $0x26f,%di
  cmovbe %edi,%eax
  ret
```

assistant: ```c
unsigned short mod_N_pm(unsigned short a) {
  if (a > 624 - 1)
    return a - 624;
  else
    return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<myexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <freework@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <plexit@plt>
  nop
  leave
  ret
```

assistant: ```c
void myexit(const char *msg) {
  freework();
  plexit(msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<myexit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <freework@plt>
  mov    %rbx,%rdi
  call   <plexit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void myexit(const char *msg) {
  freework();
  plexit(msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<myexit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <freework@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <plexit@plt>
```

assistant: ```c
void myexit(const char *msg) {
  freework();
  plexit(msg);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<myexit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <freework@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <plexit@plt>
```

assistant: ```c
void myexit(const char *msg) {
  freework();
  plexit(msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tanh>:
  endbr64
  push   %rbx
  ucomisd %xmm0,%xmm0
  movq   %xmm0,%rbx
  jp     L76
  movapd %xmm0,%xmm3
  andpd  D15(%rip),%xmm3
  orpd   D110(%rip),%xmm3
  movq   %xmm3,%rbx
  movapd %xmm0,%xmm1
  andpd  D81(%rip),%xmm1
  movsd  D71(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L21
  comisd D110(%rip),%xmm1
  ja     L64
  comisd D93(%rip),%xmm1
  ja     L39
  movapd %xmm3,%xmm4
  andpd  D15(%rip),%xmm4
  andpd  D81(%rip),%xmm0
  orpd   %xmm4,%xmm0
  movq   %xmm0,%rbx
L76:
  movq   %rbx,%xmm0
  pop    %rbx
  ret
L64:
  addsd  %xmm1,%xmm1
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movsd  D151(%rip),%xmm1
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D110(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %rbx,%xmm7
  andpd  D15(%rip),%xmm7
  andpd  D81(%rip),%xmm0
  orpd   %xmm7,%xmm0
  movq   %xmm0,%rbx
  jmp    L76
L39:
  addsd  %xmm1,%xmm1
  xorpd  D15(%rip),%xmm1
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movapd %xmm0,%xmm1
  addsd  D151(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %rbx,%xmm6
  andpd  D15(%rip),%xmm6
  andpd  D81(%rip),%xmm0
  orpd   %xmm6,%xmm0
  movq   %xmm0,%rbx
  jmp    L76
L21:
  movsd  D131(%rip),%xmm0
  ucomisd %xmm1,%xmm0
  jb     L76
  movapd %xmm3,%xmm5
  addsd  D17(%rip),%xmm5
  movq   %xmm5,%rbx
  jmp    L76
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: byte[16]
name: retrieve_data
arguments: tag: D110
type_infered: f64[2]
name: retrieve_data
arguments: tag: D81
type_infered: byte[16]
name: retrieve_data
arguments: tag: D71
type_infered: f64
name: retrieve_data
arguments: tag: D93
type_infered: byte[16]
name: retrieve_data
arguments: tag: D151
type_infered: f64
name: retrieve_data
arguments: tag: D131
type_infered: byte[8]
name: retrieve_data
arguments: tag: D17
type_infered: byte[8]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D110": [1.0,0.0]}

tool: {"D81": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D71: 22

tool: {"D93": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d,0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: D151: 2

tool: {"D131": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D17": [0x8f,0x8b,0x8a,0x42,0x9d,0x03,0x41,0x38]}

assistant: ```c
double tanh(x)
double x;
{
  static double one = 1.0, two = 2.0, small = 1.0e-10, big = 1.0e10;
  double expm1(), t, copysign(), sign;
  int finite(), isnan();
  if (x != x)
    return (x);
  sign = copysign(one, x);
  x = copysign(x, one);
  if (x < 22.0)
    if (x > one)
      return (copysign(one - two / (expm1(x + x) + two), sign));
    else if (x > small) {
      t = -expm1(-(x + x));
      return (copysign(t / (two - t), sign));
    } else {
      t = big + x;
      return (copysign(x, sign));
    }
  else if (finite(x))
    return (sign + 1.0E-37);
  else
    return (sign);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tanh>:
  endbr64
  ucomisd %xmm0,%xmm0
  jp     L11
  movq   D101(%rip),%xmm4
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movsd  D45(%rip),%xmm5
  movq   D74(%rip),%xmm3
  andpd  %xmm4,%xmm1
  comisd %xmm1,%xmm5
  andpd  %xmm3,%xmm2
  orpd   D121(%rip),%xmm2
  jbe    L43
  sub    $0x18,%rsp
  comisd D121(%rip),%xmm1
  ja     L27
  comisd D131(%rip),%xmm1
  ja     L19
L53:
  andpd  %xmm2,%xmm3
  andpd  %xmm4,%xmm0
  add    $0x18,%rsp
  orpd   %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L43:
  movsd  D76(%rip),%xmm0
  ucomisd %xmm1,%xmm0
  jb     L59
  addsd  D52(%rip),%xmm2
L59:
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movapd %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  addsd  %xmm1,%xmm1
  movsd  %xmm2,0x8(%rsp)
  xorpd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movsd  D138(%rip),%xmm1
  movq   D74(%rip),%xmm3
  movsd  0x8(%rsp),%xmm2
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
L42:
  movq   D101(%rip),%xmm4
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L27:
  addsd  %xmm1,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movsd  D138(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  movq   D74(%rip),%xmm3
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D121(%rip),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L42
```

tool_calls: name: read_data
arguments: data_label: D101
type_guessed: byte[8]
name: read_data
arguments: data_label: D45
type_guessed: f64
name: read_data
arguments: data_label: D74
type_guessed: byte[8]
name: read_data
arguments: data_label: D121
type_guessed: f64[2]
name: read_data
arguments: data_label: D131
type_guessed: byte[16]
name: read_data
arguments: data_label: D76
type_guessed: byte[8]
name: read_data
arguments: data_label: D52
type_guessed: byte[8]
name: read_data
arguments: data_label: D138
type_guessed: f64

tool: {"D101": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: D45: 22

tool: {"D74": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D121": [1.0,0.0]}

tool: {"D131": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d,0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D76": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D52": [0x8f,0x8b,0x8a,0x42,0x9d,0x03,0x41,0x38]}

tool: D138: 2

assistant: ```c
double tanh(x)
double x;
{
  static double one = 1.0, two = 2.0, small = 1.0e-10, big = 1.0e10;
  double expm1(), t, copysign(), sign;
  int finite(), isnan();
  if (x != x)
    return (x);
  sign = copysign(one, x);
  x = copysign(x, one);
  if (x < 22.0)
    if (x > one)
      return (copysign(one - two / (expm1(x + x) + two), sign));
    else if (x > small) {
      t = -expm1(-(x + x));
      return (copysign(t / (two - t), sign));
    } else {
      t = big + x;
      return (copysign(x, sign));
    }
  else if (finite(x))
    return (sign + 1.0E-37);
  else
    return (sign);
}
```