user: Translate the below assembly code into C programming language:

```asm
<encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x54(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L26
L1:
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x54(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x54(%rbp)
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  movl   $0x1,-0x5c(%rbp)
  jmp    L46
L57:
  addl   $0x1,-0x5c(%rbp)
  addl   $0x1,-0x58(%rbp)
L46:
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4c(%rbp)
  jle    L61
  mov    -0x58(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x68(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L57
L61:
  mov    -0x5c(%rbp),%edx
  lea    -0x40(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  movl   $0x0,-0x50(%rbp)
  jmp    L67
L24:
  mov    -0x50(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    -0x54(%rbp),%esi
  lea    -0x40(%rbp),%rcx
  mov    -0x50(%rbp),%edx
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x50(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x50(%rbp)
  addl   $0x1,-0x54(%rbp)
L67:
  mov    -0x50(%rbp),%eax
  cltq
  lea    -0x40(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  addl   $0x1,-0x58(%rbp)
L26:
  mov    -0x58(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L1
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D5: %d

tool: D2: Copying %c k= %d, count = %c j=%d


assistant: ```c
char *encode(char *src) {
  int rLen;
  char count[50];
  int len = strlen(src);
  char *dest = (char *)malloc(sizeof(char) * (len * 2 + 1));
  int i, j = 0, k;
  for (i = 0; i < len; i++) {
    dest[j++] = src[i];
    rLen = 1;
    while (i + 1 < len && src[i] == src[i + 1]) {
      rLen++;
      i++;
    }
    sprintf(count, "%d", rLen);
    for (k = 0; *(count + k); k++, j++) {
      printf("Copying %c k= %d, count = %c j=%d\n", count[k], k, count, j);
      dest[j] = count[k];
    }
  }
  dest[j] = '\0';
  return dest;
}
```