ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<autohelperowl_attackpat146>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%ecx
  mov    $0xffffffff,%edi
  mov    $0xfffffffe,%esi
  call   <offset@plt>
  mov    %eax,%edi
  call   <countlib@plt>
  cmp    $0x2,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int autohelperowl_attackpat146(struct pattern *patt, int transformation, int move, int color, int action) {
  int A;
  (void)patt;
  (void)color;
  (void)action;
  A = offset(-1, -2, move, transformation);
  return countlib(A) > 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<autohelperowl_attackpat146>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%ecx
  mov    $0xffffffff,%edi
  mov    $0xfffffffe,%esi
  call   <offset@plt>
  mov    %eax,%edi
  call   <countlib@plt>
  cmp    $0x2,%eax
  setg   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int autohelperowl_attackpat146(struct pattern *patt, int transformation, int move, int color, int action) {
  int A;
  (void)patt;
  (void)color;
  (void)action;
  A = offset(-1, -2, move, transformation);
  return countlib(A) > 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L22
  mov    $0x0,%eax
  call   <abort@plt>
L22:
  cmpl   $0x1,-0x18(%rbp)
  jne    L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L13
  mov    $0x0,%eax
  call   <abort@plt>
L13:
  nop
  leave
  ret
```

assistant: ```c
void test(int x, int y) {
  int c;
  if (x == 1)
    abort();
  if (y == 1)
    abort();
  c = x / y;
  if (c != 1)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x1,%edi
  je     L1
L24:
  cmp    $0x1,%ebp
  je     L59
L54:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  cmp    $0x1,%eax
  jne    L10
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L24
L59:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L54
L10:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L34
```

assistant: ```c
void test(int x, int y) {
  int c;
  if (x == 1)
    abort();
  if (y == 1)
    abort();
  c = x / y;
  if (c != 1)
    abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L15
L39:
  cmp    $0x1,%ebp
  je     L46
L42:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  cmp    $0x1,%eax
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <abort@plt>
  nopl   (%rax)
L46:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L42
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L39
```

assistant: ```c
void test(int x, int y) {
  int c;
  if (x == 1)
    abort();
  if (y == 1)
    abort();
  c = x / y;
  if (c != 1)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L15
L44:
  cmp    $0x1,%ebp
  je     L1
L3:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  cmp    $0x1,%eax
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1050 <abort@plt>
  nopl   (%rax)
L1:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L3
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L44
```

assistant: ```c
void test(int x, int y) {
  int c;
  if (x == 1)
    abort();
  if (y == 1)
    abort();
  c = x / y;
  if (c != 1)
    abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CreateContext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int CreateContext(cl_context *ctx, cl_platform_id platform) {
  cl_context_properties prop[3] = {CL_CONTEXT_PLATFORM, (cl_context_properties)platform, 0};
  assert(*ctx != NULL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CreateContext>:
  endbr64
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CreateContext(cl_context *ctx, cl_platform_id platform) {
  cl_context_properties prop[3] = {CL_CONTEXT_PLATFORM, (cl_context_properties)platform, 0};
  assert(*ctx != NULL);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CreateContext>:
  endbr64
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CreateContext(cl_context *ctx, cl_platform_id platform) {
  cl_context_properties prop[3] = {CL_CONTEXT_PLATFORM, (cl_context_properties)platform, 0};
  assert(*ctx != NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CreateContext>:
  endbr64
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CreateContext(cl_context *ctx, cl_platform_id platform) {
  cl_context_properties prop[3] = {CL_CONTEXT_PLATFORM, (cl_context_properties)platform, 0};
  assert(*ctx != NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_sorted_arr_good>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L35
L39:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L2
  mov    $0x0,%eax
  jmp    L3
L2:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L39
  mov    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int check_sorted_arr_good(int a[], int length) {
  for (int i = 1; i < length; i++) {
    if (a[i] < a[i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_sorted_arr_good>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L29:
  mov    (%rax),%ecx
  cmp    %ecx,0x4(%rax)
  jl     L28
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L29
  mov    $0x1,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int check_sorted_arr_good(int a[], int length) {
  for (int i = 1; i < length; i++) {
    if (a[i] < a[i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_sorted_arr_good>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L0
L13:
  mov    (%rdi),%edx
  cmp    %edx,0x4(%rdi)
  jge    L26
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_sorted_arr_good(int a[], int length) {
  for (int i = 1; i < length; i++) {
    if (a[i] < a[i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_sorted_arr_good>:
  endbr64
  cmp    $0x1,%esi
  jle    L32
  lea    -0x2(%rsi),%ecx
  mov    (%rdi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rcx,4),%rsi
  jmp    L17
  nopl   0x0(%rax)
L20:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L32
L17:
  mov    %edx,%ecx
  mov    (%rax),%edx
  cmp    %ecx,%edx
  jge    L20
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_sorted_arr_good(int a[], int length) {
  for (int i = 1; i < length; i++) {
    if (a[i] < a[i - 1]) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x410(%rbp),%rax
  mov    %rax,-0x3f8(%rbp)
  movl   $0x0,-0x400(%rbp)
  jmp    L62
L21:
  cmpl   $0x1387,-0x400(%rbp)
  jg     L20
  mov    -0x3f8(%rbp),%rax
  lea    0x4c4b40(%rax),%rdx
  mov    -0x3fc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x410(%rbp),%rax
  add    %rcx,%rax
  cmp    %rax,%rdx
  jbe    L20
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x408(%rbp),%rax
  add    %rax,%rdx
  mov    -0x410(%rbp),%rax
  mov    %rax,(%rdx)
  lea    -0x3f0(%rbp),%rdx
  mov    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,-0x410(%rbp)
  addq   $0x1,-0x410(%rbp)
  jmp    L62
L20:
  mov    $0xffffffff,%eax
  jmp    L37
L62:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <get_line@plt>
  mov    %eax,-0x3fc(%rbp)
  cmpl   $0x0,-0x3fc(%rbp)
  jne    L21
  mov    -0x400(%rbp),%eax
L37:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
int read_lines(char *line_pointer_array[], char *lines_buffer) {
  char line[1000], *lines_buffer_start = lines_buffer;
  int line_length, lines_count = 0;
  while (line_length = get_line(line, 1000)) {
    if (lines_count < 5000 && lines_buffer_start + 5000 * 1000 > lines_buffer + line_length) {
      line_pointer_array[lines_count++] = lines_buffer;
      lines_buffer = stpcpy(lines_buffer, line);
      ++lines_buffer;
    } else
      return -1;
  }
  return lines_count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_lines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %rsp,%r12
L37:
  mov    %ebp,%r15d
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <get_line@plt>
  test   %eax,%eax
  je     L53
  cmp    $0x1388,%rbp
  je     L27
  lea    0x4c4b40(%r13),%rdx
  cltq
  add    %rbx,%rax
  cmp    %rax,%rdx
  jbe    L32
  mov    %rbx,(%r14,%rbp,8)
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <stpcpy@plt>
  lea    0x1(%rax),%rbx
  add    $0x1,%rbp
  jmp    L37
L27:
  mov    $0xffffffff,%r15d
  jmp    L53
L32:
  mov    $0xffffffff,%r15d
L53:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    %r15d,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_lines(char *line_pointer_array[], char *lines_buffer) {
  char line[1000], *lines_buffer_start = lines_buffer;
  int line_length, lines_count = 0;
  while (line_length = get_line(line, 1000)) {
    if (lines_count < 5000 && lines_buffer_start + 5000 * 1000 > lines_buffer + line_length) {
      line_pointer_array[lines_count++] = lines_buffer;
      lines_buffer = stpcpy(lines_buffer, line);
      ++lines_buffer;
    } else
      return -1;
  }
  return lines_count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_lines>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    0x4c4b40(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L2
  nopl   (%rax)
L12:
  cmp    $0x1388,%r15
  je     L42
  cltq
  add    %r14,%rax
  cmp    %rax,%r12
  jbe    L42
  mov    %r14,0x0(%rbp,%r15,8)
  mov    %r14,%rdi
  mov    %rbx,%rsi
  add    $0x1,%r15
  call   <stpcpy@plt>
  lea    0x1(%rax),%r14
L2:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  mov    %r15d,%r13d
  call   <get_line@plt>
  test   %eax,%eax
  jne    L12
L10:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x3f8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0xffffffff,%r13d
  jmp    L10
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_lines(char *line_pointer_array[], char *lines_buffer) {
  char line[1000], *lines_buffer_start = lines_buffer;
  int line_length, lines_count = 0;
  while (line_length = get_line(line, 1000)) {
    if (lines_count < 5000 && lines_buffer_start + 5000 * 1000 > lines_buffer + line_length) {
      line_pointer_array[lines_count++] = lines_buffer;
      lines_buffer = stpcpy(lines_buffer, line);
      ++lines_buffer;
    } else
      return -1;
  }
  return lines_count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_lines>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  lea    0x4c4b40(%rsi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L13
  nopl   (%rax)
L3:
  cmp    $0x1388,%r15
  je     L41
  cltq
  add    %r14,%rax
  cmp    %rax,%r12
  jbe    L41
  mov    %r14,0x0(%rbp,%r15,8)
  mov    %r14,%rdi
  mov    %rbx,%rsi
  add    $0x1,%r15
  call   <stpcpy@plt>
  lea    0x1(%rax),%r14
L13:
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  mov    %r15d,%r13d
  call   <get_line@plt>
  test   %eax,%eax
  jne    L3
L35:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x3f8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0xffffffff,%r13d
  jmp    L35
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_lines(char *line_pointer_array[], char *lines_buffer) {
  char line[1000], *lines_buffer_start = lines_buffer;
  int line_length, lines_count = 0;
  while (line_length = get_line(line, 1000)) {
    if (lines_count < 5000 && lines_buffer_start + 5000 * 1000 > lines_buffer + line_length) {
      line_pointer_array[lines_count++] = lines_buffer;
      lines_buffer = stpcpy(lines_buffer, line);
      ++lines_buffer;
    } else
      return -1;
  }
  return lines_count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GenWordAlignment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf2@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: 	align($2)


assistant: ```c
void GenWordAlignment(int bss) {
  (void)bss;
  printf2("\talign($2)\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<GenWordAlignment>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf2@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 	align($2)


assistant: ```c
void GenWordAlignment(int bss) {
  (void)bss;
  printf2("\talign($2)\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GenWordAlignment>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf2@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: 	align($2)


assistant: ```c
void GenWordAlignment(int bss) {
  (void)bss;
  printf2("\talign($2)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GenWordAlignment>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf2@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: 	align($2)


assistant: ```c
void GenWordAlignment(int bss) {
  (void)bss;
  printf2("\talign($2)\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hoare_select_f>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %ecx,%r14d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r15
  movss  (%r15),%xmm4
  movss  %xmm4,0x8(%rsp)
  mov    %edx,%eax
  sub    %esi,%eax
  mov    $0x0,%edi
  cmp    $0x1,%eax
  jle    L118
  cmp    %ecx,%esi
  setl   %al
  cmp    %ecx,%edx
  setg   %dil
  movzbl %dil,%edi
  and    %eax,%edi
L118:
  call   <assert@plt>
  lea    -0x1(%r13),%eax
  mov    %eax,0xc(%rsp)
  cmp    %eax,%r12d
  jge    L93
  lea    0x1(%r12),%eax
  cltq
  mov    %r13d,%ecx
  jmp    L79
L80:
  add    $0x1,%rax
  lea    -0x1(%rcx),%esi
  lea    -0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L64
L79:
  mov    %eax,%ebp
  movss  (%rbx,%rax,4),%xmm1
  comiss 0x8(%rsp),%xmm1
  jbe    L80
  movslq %ecx,%rdx
  lea    -0x4(%rbx,%rdx,4),%rdx
L54:
  sub    $0x1,%ecx
  cmp    %eax,%ecx
  jle    L127
  mov    %rdx,%rsi
  sub    $0x4,%rdx
  movss  0x4(%rdx),%xmm0
  movss  0x8(%rsp),%xmm2
  comiss %xmm0,%xmm2
  jb     L54
  movss  %xmm0,(%rbx,%rax,4)
  movss  %xmm1,(%rsi)
  jmp    L80
L64:
  mov    %ecx,%ebp
L127:
  cmp    %r12d,%ebp
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r13d,%ebp
  je     L39
L50:
  cmp    %r14d,%ebp
  je     L110
  jle    L0
  mov    %r14d,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <hoare_select_f>
L110:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <hoare_select_f>
  jmp    L110
L93:
  cmp    %r13d,%r12d
  setl   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L39:
  movss  (%r15),%xmm0
  movslq %r13d,%rax
  lea    -0x4(%rbx,%rax,4),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,(%r15)
  movss  %xmm0,(%rax)
  mov    0xc(%rsp),%ebp
  jmp    L50
```

assistant: ```c
void hoare_select_f(float *f, int i0, int i1, int q) {
  float pivot = f[i0];
  int j0, j1, lim;
  assert(i1 - i0 > 1 && q > i0 && q < i1);
  for (j0 = i0, j1 = i1; 1;) {
    while (j0 < j1 - 1) {
      j0++;
      if (f[j0] > pivot)
        goto endseginf;
    }
    lim = j1;
    break;
  endseginf:
    while (j1 - 1 > j0) {
      j1--;
      if (f[j1] <= pivot)
        goto endsegsup;
    }
    lim = j0;
    break;
  endsegsup : {
    float tmp = f[j0];
    f[j0] = f[j1];
    f[j1] = tmp;
  };
  }
  assert(lim > i0);
  if (lim == i1) {
    {
      float tmp = f[i0];
      f[i0] = f[i1 - 1];
      f[i1 - 1] = tmp;
    };
    lim = i1 - 1;
  }
  if (lim == q)
    return;
  if (q < lim)
    hoare_select_f(f, i0, lim, q);
  else
    hoare_select_f(f, lim, i1, q);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hoare_select_f>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %rax,%r15
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%eax
  mov    %eax,0x4(%rsp)
  nopl   0x0(%rax)
L90:
  mov    0x8(%rsp),%rax
  xor    %edi,%edi
  lea    (%r14,%rax,4),%rbx
  mov    %r13d,%eax
  sub    %r15d,%eax
  movss  (%rbx),%xmm1
  cmp    $0x1,%eax
  jle    L6
  cmp    %ebp,%r15d
  setl   %al
  xor    %edi,%edi
  cmp    %ebp,%r13d
  setg   %dil
  and    %eax,%edi
L6:
  movss  %xmm1,(%rsp)
  call   <assert@plt>
  cmp    0x4(%rsp),%r15d
  jge    L42
  lea    0x1(%r15),%edx
  movss  (%rsp),%xmm1
  movslq %r13d,%rsi
  lea    -0x1(%r13),%eax
  movslq %edx,%rdx
  jmp    L30
  nopl   (%rax)
L61:
  add    $0x1,%rdx
  lea    -0x1(%rdx),%ecx
  cmp    %ecx,%eax
  jle    L70
L30:
  movss  (%r14,%rdx,4),%xmm2
  mov    %edx,%r12d
  comiss %xmm1,%xmm2
  jbe    L61
  lea    -0x4(%r14,%rsi,4),%rcx
  jmp    L60
  nopl   0x0(%rax)
L89:
  mov    %rcx,%rdi
  movss  (%rcx),%xmm0
  sub    $0x4,%rcx
  comiss %xmm0,%xmm1
  jae    L0
  sub    $0x1,%eax
L60:
  movslq %eax,%rsi
  cmp    %edx,%eax
  jg     L89
L78:
  xor    %edi,%edi
  cmp    %r15d,%r12d
  setg   %dil
  call   <assert@plt>
  cmp    %r13d,%r12d
  je     L93
  cmp    %ebp,%r12d
  je     L16
L87:
  jg     L75
  movslq %r12d,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%r15
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L0:
  movss  %xmm0,(%r14,%rdx,4)
  add    $0x1,%rdx
  sub    $0x1,%eax
  lea    -0x1(%rdx),%ecx
  movss  %xmm2,(%rdi)
  cmp    %ecx,%eax
  jg     L30
  nopl   0x0(%rax)
L70:
  mov    %esi,%r12d
  jmp    L78
  nopl   (%rax)
L75:
  lea    -0x1(%r12),%eax
  mov    %r12d,%r13d
  mov    %eax,0x4(%rsp)
  jmp    L90
L42:
  xor    %edi,%edi
  cmp    %r13d,%r15d
  setl   %dil
  call   <assert@plt>
  nopw   0x0(%rax,%rax,1)
L93:
  movslq %r13d,%rax
  movss  (%rbx),%xmm0
  mov    0x4(%rsp),%r12d
  lea    -0x4(%r14,%rax,4),%rax
  movss  (%rax),%xmm1
  movss  %xmm1,(%rbx)
  movss  %xmm0,(%rax)
  cmp    %ebp,%r12d
  jne    L87
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void hoare_select_f(float *f, int i0, int i1, int q) {
  float pivot = f[i0];
  int j0, j1, lim;
  assert(i1 - i0 > 1 && q > i0 && q < i1);
  for (j0 = i0, j1 = i1; 1;) {
    while (j0 < j1 - 1) {
      j0++;
      if (f[j0] > pivot)
        goto endseginf;
    }
    lim = j1;
    break;
  endseginf:
    while (j1 - 1 > j0) {
      j1--;
      if (f[j1] <= pivot)
        goto endsegsup;
    }
    lim = j0;
    break;
  endsegsup : {
    float tmp = f[j0];
    f[j0] = f[j1];
    f[j1] = tmp;
  };
  }
  assert(lim > i0);
  if (lim == i1) {
    {
      float tmp = f[i0];
      f[i0] = f[i1 - 1];
      f[i1 - 1] = tmp;
    };
    lim = i1 - 1;
  }
  if (lim == q)
    return;
  if (q < lim)
    hoare_select_f(f, i0, lim, q);
  else
    hoare_select_f(f, lim, i1, q);
}
```