ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrEncode>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdx),%edi
  test   %dil,%dil
  je     L66
  mov    %rsi,%rbp
  cmp    $0x4,%rsi
  jbe    L66
  mov    %rdx,%r14
  xor    %ebx,%ebx
  lea    D15(%rip),%r12
  lea    D14(%rip),%r13
  jmp    L3
  nop
L58:
  movzbl (%r14),%eax
  add    $0x1,%r14
  add    $0x1,%r15
  add    $0x1,%ebx
  mov    %al,-0x1(%r15)
  movsbl (%r14),%edi
  test   %dil,%dil
  je     L66
L25:
  lea    0x4(%rbx),%eax
  cltq
  cmp    %rbp,%rax
  jae    L66
L3:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L58
  movsbl (%r14),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L58
  movzbl (%r14),%edx
  mov    %r15,%rdi
  mov    %r13,%rsi
  add    $0x1,%r14
  add    $0x3,%r15
  add    $0x3,%ebx
  call   <sprintf@plt>
  movsbl (%r14),%edi
  test   %dil,%dil
  jne    L25
L66:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string

tool: D15: /_.-~

tool: D14: %%%02x

assistant: ```c
void StrEncode(char *to, size_t tosize, const char *from) {
  int tolen;
  for (tolen = 0; *from != '\0' && tolen + 4 < tosize; ++from) {
    if (isalnum(*from) || strchr("/_.-~", *from) != (char *)0) {
      *to = *from;
      ++to;
      ++tolen;
    } else {
      (void)sprintf(to, "%%%02x", (int)*from & 0xff);
      to += 3;
      tolen += 3;
    }
  }
  *to = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<StrEncode>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdx),%edi
  test   %dil,%dil
  je     L41
  mov    %rsi,%rbp
  cmp    $0x4,%rsi
  jbe    L41
  mov    %rdx,%r14
  xor    %ebx,%ebx
  lea    D16(%rip),%r12
  lea    D10(%rip),%r13
  jmp    L29
  nop
L21:
  movzbl (%r14),%eax
  add    $0x1,%r14
  add    $0x1,%r15
  add    $0x1,%ebx
  mov    %al,-0x1(%r15)
  movsbl (%r14),%edi
  test   %dil,%dil
  je     L41
L38:
  lea    0x4(%rbx),%eax
  cltq
  cmp    %rbp,%rax
  jae    L41
L29:
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L21
  movsbl (%r14),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L21
  movzbl (%r14),%edx
  mov    %r15,%rdi
  mov    %r13,%rsi
  add    $0x1,%r14
  add    $0x3,%r15
  add    $0x3,%ebx
  call   <sprintf@plt>
  movsbl (%r14),%edi
  test   %dil,%dil
  jne    L38
L41:
  movb   $0x0,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D10
type: string

tool: D16: /_.-~

tool: D10: %%%02x

assistant: ```c
void StrEncode(char *to, size_t tosize, const char *from) {
  int tolen;
  for (tolen = 0; *from != '\0' && tolen + 4 < tosize; ++from) {
    if (isalnum(*from) || strchr("/_.-~", *from) != (char *)0) {
      *to = *from;
      ++to;
      ++tolen;
    } else {
      (void)sprintf(to, "%%%02x", (int)*from & 0xff);
      to += 3;
      tolen += 3;
    }
  }
  *to = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wdcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L0
L57:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L39
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L57
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L44
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L44
  mov    $0x0,%eax
  jmp    L37
L44:
  mov    $0x1,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int wdcmp(char *s1, char *s2) {
  for (; *s1 > ' ' && *s1 == *s2; s1++, s2++)
    ;
  if (*s1 <= ' ' && *s2 <= ' ')
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wdcmp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L3
L38:
  cmp    %al,(%rsi)
  jne    L15
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jg     L38
L3:
  cmpb   $0x20,(%rsi)
  setg   %al
  movzbl %al,%eax
  ret
L15:
  cmp    $0x20,%al
  jle    L3
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wdcmp(char *s1, char *s2) {
  for (; *s1 > ' ' && *s1 == *s2; s1++, s2++)
    ;
  if (*s1 <= ' ' && *s2 <= ' ')
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wdcmp>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L4:
  cmp    (%rsi),%al
  jne    L23
  add    $0x1,%rdi
  add    $0x1,%rsi
L13:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jg     L4
  xor    %eax,%eax
  cmpb   $0x20,(%rsi)
  setg   %al
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wdcmp(char *s1, char *s2) {
  for (; *s1 > ' ' && *s1 == *s2; s1++, s2++)
    ;
  if (*s1 <= ' ' && *s2 <= ' ')
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wdcmp>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L19:
  cmp    (%rsi),%al
  jne    L7
  add    $0x1,%rdi
  add    $0x1,%rsi
L11:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jg     L19
  xor    %eax,%eax
  cmpb   $0x20,(%rsi)
  setg   %al
  ret
  nopl   0x0(%rax)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wdcmp(char *s1, char *s2) {
  for (; *s1 > ' ' && *s1 == *s2; s1++, s2++)
    ;
  if (*s1 <= ' ' && *s2 <= ' ')
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L51
L24:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L49
L55:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L55
  mov    $0xa,%edi
  call   <putchar@plt>
L51:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D0: %d

tool: D2: %d %d

tool: D5: %d


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    int m, n;
    scanf("%d %d", &m, &n);
    int i;
    for (i = m; i <= n; ++i)
      if (isPrime(i))
        printf("%d\n", i);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L64
  lea    0x14(%rsp),%r13
  lea    D23(%rip),%r12
  lea    D3(%rip),%rbp
  jmp    L53
L15:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jl     L66
L50:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L15
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L66:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L64
L53:
  lea    0x10(%rsp),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  cmp    0x14(%rsp),%ebx
  jle    L50
  jmp    L66
L64:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D15: %d

tool: D23: %d %d

tool: D3: %d


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    int m, n;
    scanf("%d %d", &m, &n);
    int i;
    for (i = m; i <= n; ++i)
      if (isPrime(i))
        printf("%d\n", i);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D16(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L17
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D26(%rip),%r12
  lea    D18(%rip),%rbp
  nopl   0x0(%rax)
L15:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  cmp    0x14(%rsp),%ebx
  jle    L49
  jmp    L54
  nopl   0x0(%rax)
L77:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jl     L54
L49:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L77
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jge    L49
L54:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L15
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string
name: unpack_data
arguments: tag: D18
type_infered: string

tool: D16: %d

tool: D26: %d %d

tool: D18: %d


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    int m, n;
    scanf("%d %d", &m, &n);
    int i;
    for (i = m; i <= n; ++i)
      if (isPrime(i))
        printf("%d\n", i);
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L60
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D8(%rip),%r12
  lea    D5(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  cmp    0x14(%rsp),%ebx
  jg     L32
  nopw   0x0(%rax,%rax,1)
L75:
  mov    %ebx,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  jne    L29
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jge    L75
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L38
L60:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L29:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x14(%rsp)
  jge    L75
  jmp    L32
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D5
datatype: string

tool: D0: %d

tool: D8: %d %d

tool: D5: %d


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    int m, n;
    scanf("%d %d", &m, &n);
    int i;
    for (i = m; i <= n; ++i)
      if (isPrime(i))
        printf("%d\n", i);
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<already_solved>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L21
L48:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  xor    $0x1,%eax
  test   %al,%al
  je     L107
  mov    $0x0,%eax
  jmp    L87
L107:
  add    $0x1,%ebx
L21:
  cmp    $0x2,%ebx
  jle    L48
  mov    $0x0,%ebx
  jmp    L105
L9:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  xor    $0x1,%eax
  test   %al,%al
  je     L111
  mov    $0x0,%eax
  jmp    L87
L111:
  add    $0x1,%ebx
L105:
  cmp    $0x2,%ebx
  jle    L9
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L55
L42:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  add    $0x1,%ebx
L55:
  cmp    $0x2,%ebx
  jle    L42
  movsd  -0x10(%rbp),%xmm0
  ucomisd D7(%rip),%xmm0
  jp     L15
  movsd  -0x10(%rbp),%xmm0
  ucomisd D7(%rip),%xmm0
  je     L17
L15:
  mov    $0xffffffff,%eax
  jmp    L87
L17:
  mov    $0x1,%eax
L87:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
int already_solved(double *angles, double *sides) {
  double sum_of_all_angles;
  register int i;
  for (i = 0; i < 3; i++)
    if (!((angles[i]) > 0))
      return 0;
  for (i = 0; i < 3; i++)
    if (!((sides[i]) > 0))
      return 0;
  sum_of_all_angles = 0;
  for (i = 0; i < 3; i++)
    sum_of_all_angles += angles[i];
  if (sum_of_all_angles != (180 * ((3) - 2)))
    return -1;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<already_solved>:
  endbr64
  movsd  (%rdi),%xmm0
  comisd D58(%rip),%xmm0
  jbe    L59
  movsd  0x8(%rdi),%xmm2
  comisd D58(%rip),%xmm2
  jbe    L52
  movsd  0x10(%rdi),%xmm1
  comisd D58(%rip),%xmm1
  jbe    L5
  movsd  (%rsi),%xmm3
  comisd D58(%rip),%xmm3
  jbe    L6
  movsd  0x8(%rsi),%xmm3
  comisd D58(%rip),%xmm3
  jbe    L0
  movsd  0x10(%rsi),%xmm3
  comisd D58(%rip),%xmm3
  jbe    L28
  addsd  D58(%rip),%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  ucomisd D0(%rip),%xmm1
  jp     L62
  mov    $0x1,%eax
  jne    L62
L26:
  ret
L62:
  mov    $0xffffffff,%eax
  ret
L59:
  mov    $0x0,%eax
  ret
L52:
  mov    $0x0,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  jmp    L26
```

tool_calls: name: disassemble_data
arguments: data_tag: D58
type: byte[16]
name: disassemble_data
arguments: data_tag: D0
type: byte[8]

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
int already_solved(double *angles, double *sides) {
  double sum_of_all_angles;
  register int i;
  for (i = 0; i < 3; i++)
    if (!((angles[i]) > 0))
      return 0;
  for (i = 0; i < 3; i++)
    if (!((sides[i]) > 0))
      return 0;
  sum_of_all_angles = 0;
  for (i = 0; i < 3; i++)
    sum_of_all_angles += angles[i];
  if (sum_of_all_angles != (180 * ((3) - 2)))
    return -1;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<already_solved>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L40
  movsd  0x8(%rdi),%xmm2
  comisd %xmm1,%xmm2
  jbe    L40
  movsd  0x10(%rdi),%xmm3
  comisd %xmm1,%xmm3
  jbe    L40
  movsd  (%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L40
  movsd  0x8(%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L40
  movsd  0x10(%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L40
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ucomisd D4(%rip),%xmm0
  jp     L79
  mov    $0x1,%eax
  jne    L79
  ret
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L40:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
int already_solved(double *angles, double *sides) {
  double sum_of_all_angles;
  register int i;
  for (i = 0; i < 3; i++)
    if (!((angles[i]) > 0))
      return 0;
  for (i = 0; i < 3; i++)
    if (!((sides[i]) > 0))
      return 0;
  sum_of_all_angles = 0;
  for (i = 0; i < 3; i++)
    sum_of_all_angles += angles[i];
  if (sum_of_all_angles != (180 * ((3) - 2)))
    return -1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<already_solved>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L52
  movsd  0x8(%rdi),%xmm2
  comisd %xmm1,%xmm2
  jbe    L52
  movsd  0x10(%rdi),%xmm3
  comisd %xmm1,%xmm3
  jbe    L52
  movsd  (%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L52
  movsd  0x8(%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L52
  movsd  0x10(%rsi),%xmm4
  comisd %xmm1,%xmm4
  jbe    L52
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  ucomisd D6(%rip),%xmm0
  jp     L25
  mov    $0x1,%eax
  jne    L25
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x80,0x66,0x40]}

assistant: ```c
int already_solved(double *angles, double *sides) {
  double sum_of_all_angles;
  register int i;
  for (i = 0; i < 3; i++)
    if (!((angles[i]) > 0))
      return 0;
  for (i = 0; i < 3; i++)
    if (!((sides[i]) > 0))
      return 0;
  sum_of_all_angles = 0;
  for (i = 0; i < 3; i++)
    sum_of_all_angles += angles[i];
  if (sum_of_all_angles != (180 * ((3) - 2)))
    return -1;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UARTIntPendingStatusGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x7f,%esi
  mov    %eax,%edi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L4
  movl   $0x0,-0x8(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int UARTIntPendingStatusGet(unsigned int baseAdd) {
  unsigned int retVal = (1);
  unsigned int lcrRegValue = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  if (!((*((volatile unsigned int *)(baseAdd + (0x8)))) & (0x00000001u))) {
    retVal = (0);
  }
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTIntPendingStatusGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x7f,%esi
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x8(%ebx),%eax
  mov    %edx,0xc(%ebx)
  and    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int UARTIntPendingStatusGet(unsigned int baseAdd) {
  unsigned int retVal = (1);
  unsigned int lcrRegValue = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  if (!((*((volatile unsigned int *)(baseAdd + (0x8)))) & (0x00000001u))) {
    retVal = (0);
  }
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UARTIntPendingStatusGet>:
  endbr64
  push   %rbx
  mov    $0x7f,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x8(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned int UARTIntPendingStatusGet(unsigned int baseAdd) {
  unsigned int retVal = (1);
  unsigned int lcrRegValue = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  if (!((*((volatile unsigned int *)(baseAdd + (0x8)))) & (0x00000001u))) {
    retVal = (0);
  }
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UARTIntPendingStatusGet>:
  endbr64
  push   %rbx
  mov    $0x7f,%esi
  mov    %edi,%ebx
  call   <UARTRegConfigModeEnable@plt>
  mov    %eax,%edx
  mov    0x8(%ebx),%eax
  mov    %edx,0xc(%ebx)
  pop    %rbx
  and    $0x1,%eax
  ret
```

assistant: ```c
unsigned int UARTIntPendingStatusGet(unsigned int baseAdd) {
  unsigned int retVal = (1);
  unsigned int lcrRegValue = 0;
  lcrRegValue = UARTRegConfigModeEnable(baseAdd, (0x007F));
  if (!((*((volatile unsigned int *)(baseAdd + (0x8)))) & (0x00000001u))) {
    retVal = (0);
  }
  (*((volatile unsigned int *)(baseAdd + (0xC)))) = lcrRegValue;
  return retVal;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L34
L39:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L31
  mov    $0x0,%eax
  jmp    L21
L31:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jle    L39
  mov    $0x1,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i <= num / 2; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L4
  test   $0x1,%dil
  je     L7
  mov    $0x2,%ecx
L44:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L21
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L44
L10:
  ret
L21:
  mov    $0x1,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i <= num / 2; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_prime>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x3,%edi
  jle    L49
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L8
  nop
L1:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L15
L8:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jle    L1
L49:
  mov    $0x1,%edx
L15:
  mov    %edx,%eax
  ret
L22:
  xor    %edx,%edx
  jmp    L15
```

assistant: ```c
int check_prime(int num) {
  int i;
  for (i = 2; i <= num / 2; i++) {
    if (num % i == 0) {
      return 0;
    }
  }
  return 1;
}
```