user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%r13
  lea    0x10(%rsp),%rbp
  lea    0x50(%rsp),%r14
  mov    %rbp,%r12
L230:
  lea    -0x10(%r12),%rbx
L227:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L227
  add    $0x10,%r12
  cmp    %r14,%r12
  jne    L230
  lea    D19(%rip),%r12
L128:
  lea    -0x10(%rbp),%rbx
L147:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L147
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%rbp
  cmp    %r14,%rbp
  jne    L128
  mov    %r13,%rbx
  mov    $0x0,%ebp
  lea    D28(%rip),%r12
  jmp    L203
L142:
  mov    $0x2,%ecx
  jmp    L218
L1:
  mov    %ebp,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x10,%rbx
  cmp    $0x4,%ebp
  je     L63
L203:
  mov    %rbx,%rdx
  mov    (%rbx),%esi
  mov    0x4(%rbx),%eax
  mov    $0x1,%ecx
  cmp    %eax,%esi
  jl     L49
  mov    %esi,%eax
  mov    $0x0,%ecx
L49:
  mov    0x8(%rdx),%esi
  cmp    %esi,%eax
  jl     L142
  mov    %eax,%esi
L218:
  mov    0xc(%rdx),%eax
  cmp    %esi,%eax
  jle    L1
  mov    %eax,%esi
  mov    $0x3,%ecx
  jmp    L1
L63:
  mov    $0x0,%ebx
  lea    D28(%rip),%rbp
  jmp    L8
L250:
  mov    $0x2,%edx
  jmp    L219
L254:
  mov    %ebx,%ecx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    $0x4,%ebx
  je     L253
L8:
  mov    %r13,%rcx
  mov    0x0(%r13),%esi
  mov    0x10(%r13),%eax
  mov    $0x1,%edx
  cmp    %eax,%esi
  jl     L40
  mov    %esi,%eax
  mov    $0x0,%edx
L40:
  mov    0x20(%rcx),%esi
  cmp    %esi,%eax
  jl     L250
  mov    %eax,%esi
L219:
  mov    0x30(%rcx),%eax
  cmp    %esi,%eax
  jle    L254
  mov    %eax,%esi
  mov    $0x3,%edx
  jmp    L254
L253:
  mov    (%rsp),%ecx
  mov    0x14(%rsp),%eax
  mov    $0x1,%edx
  cmp    %eax,%ecx
  jl     L167
  mov    %ecx,%eax
  mov    $0x0,%edx
L167:
  mov    0x28(%rsp),%esi
  cmp    %eax,%esi
  jg     L197
  mov    %eax,%esi
L136:
  mov    0x3c(%rsp),%eax
  cmp    %esi,%eax
  jle    L60
  mov    %eax,%esi
  mov    $0x3,%edx
L60:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%ecx
  mov    0x18(%rsp),%eax
  mov    $0x1,%edx
  cmp    %ecx,%eax
  jg     L120
  mov    %ecx,%eax
  mov    $0x0,%edx
L120:
  mov    0x24(%rsp),%esi
  cmp    %esi,%eax
  jl     L237
  mov    %eax,%esi
L188:
  mov    0x30(%rsp),%eax
  cmp    %esi,%eax
  jle    L163
  mov    %eax,%esi
  mov    $0x3,%edx
L163:
  mov    $0x3,%ecx
  sub    %edx,%ecx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L197:
  mov    $0x2,%edx
  jmp    L136
L237:
  mov    $0x2,%edx
  jmp    L188
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string

tool: D19: %6d

tool: D28: max:%d, row:%d, column:%d


tool: D24: max:%d, row=column:%d


assistant: ```c
int main() {
  int a[4][4];
  int i, j, k, max, m, n;
  srand(time(NULL));
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++)
      a[i][j] = rand() % 100;
  }
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++)
      printf("%6d", a[i][j]);
    putchar('\n');
  }
  for (i = 0; i < 4; i++) {
    max = a[i][0];
    n = 0;
    for (j = 1; j < 4; j++) {
      if (a[i][j] > max) {
        max = a[i][j];
        n = j;
      }
    }
    printf("max:%d, row:%d, column:%d\n", max, i, n);
  }
  for (i = 0; i < 4; i++) {
    max = a[0][i];
    n = 0;
    for (j = 1; j < 4; j++) {
      if (a[j][i] > max) {
        max = a[j][i];
        n = j;
      }
    }
    printf("max:%d, row:%d, column:%d\n", max, n, i);
  }
  max = a[0][0];
  n = 0;
  for (i = 1; i < 4; i++) {
    if (a[i][i] > max) {
      max = a[i][i];
      n = i;
    }
  }
  printf("max:%d, row=column:%d\n", max, n);
  max = a[0][3];
  n = 0;
  for (i = 1; i < 4; i++) {
    if (a[i][3 - i] > max) {
      max = a[i][3 - i];
      n = i;
    }
  }
  printf("max:%d, row:%d, column:%d\n", max, n, 3 - n);
}
```