ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rax
  lea    0x8(%rsp),%r12
  movl   $0x5,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r12,0x10(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    D27(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x8,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D45
data_type: string
name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D25
data_type: string
name: extract_symbolic_data
arguments: tag: D20
data_type: string

tool: D5: %d


tool: D34: b %x


tool: D45: c %x


tool: D27: %x


tool: D25: &b %x


tool: D20: &c %x


assistant: ```c
int main(int argc, char *argv[]) {
  int x;
  int *b;
  int **c;
  x = 5;
  b = &x;
  c = &b;
  printf("%d\n", x);
  printf("b %x\n", b);
  printf("c %x\n", c);
  printf("%x\n", *b);
  printf("&b %x\n", &b);
  printf("&c %x\n", &c);
  printf("%d\n", sizeof(int));
  printf("%d\n", sizeof(double));
  printf("%d\n", sizeof(float));
  printf("%d\n", sizeof(x));
  printf("%d\n", sizeof(b));
  printf("%d\n", sizeof(c));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<the_litlest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x7fffffff,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L16
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L22
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L22:
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int *the_litlest(int *tab, int size, int pos) {
  int loop;
  int *var;
  int var2;
  loop = 0 + pos;
  var2 = 2147483647;
  var = &var2;
  while (loop < size) {
    if (tab[loop] < *var)
      var = &tab[loop];
    ++loop;
  }
  return (var);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<the_litlest>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7fffffff,0x4(%rsp)
  cmp    %esi,%edx
  jge    L19
  movslq %edx,%rcx
  lea    (%rdi,%rcx,4),%rax
  sub    $0x1,%esi
  sub    %edx,%esi
  add    %rcx,%rsi
  lea    0x4(%rdi,%rsi,4),%rcx
  lea    0x4(%rsp),%rdx
L28:
  mov    (%rdx),%edi
  cmp    %edi,(%rax)
  cmovl  %rax,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rdx,%rax
  add    $0x18,%rsp
  ret
L19:
  lea    0x4(%rsp),%rdx
  jmp    L39
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *the_litlest(int *tab, int size, int pos) {
  int loop;
  int *var;
  int var2;
  loop = 0 + pos;
  var2 = 2147483647;
  var = &var2;
  while (loop < size) {
    if (tab[loop] < *var)
      var = &tab[loop];
    ++loop;
  }
  return (var);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<the_litlest>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x7fffffff,0x4(%rsp)
  cmp    %esi,%edx
  jge    1060 <the_litlest.cold>
  sub    $0x1,%esi
  movslq %edx,%rcx
  lea    0x4(%rsp),%r8
  sub    %edx,%esi
  lea    (%rdi,%rcx,4),%rax
  mov    $0x7fffffff,%edx
  add    %rcx,%rsi
  lea    (%rdi,%rsi,4),%rcx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%r8),%edx
  add    $0x4,%rax
L19:
  cmp    %edx,(%rax)
  cmovl  %rax,%r8
  cmp    %rcx,%rax
  jne    L28
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %r8,%rax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *the_litlest(int *tab, int size, int pos) {
  int loop;
  int *var;
  int var2;
  loop = 0 + pos;
  var2 = 2147483647;
  var = &var2;
  while (loop < size) {
    if (tab[loop] < *var)
      var = &tab[loop];
    ++loop;
  }
  return (var);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<the_litlest>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    %esi,%edx
  jge    1060 <the_litlest.cold>
  sub    $0x1,%esi
  movslq %edx,%rcx
  lea    0x4(%rsp),%r8
  sub    %edx,%esi
  lea    (%rdi,%rcx,4),%rax
  add    %rcx,%rsi
  mov    $0x7fffffff,%ecx
  lea    0x4(%rdi,%rsi,4),%rsi
  xchg   %ax,%ax
L25:
  mov    (%rax),%edx
  cmp    %edx,%ecx
  jle    L11
  mov    %edx,%ecx
  mov    %rax,%r8
L11:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L25
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %r8,%rax
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int *the_litlest(int *tab, int size, int pos) {
  int loop;
  int *var;
  int var2;
  loop = 0 + pos;
  var2 = 2147483647;
  var = &var2;
  while (loop < size) {
    if (tab[loop] < *var)
      var = &tab[loop];
    ++loop;
  }
  return (var);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NormalizeSeqName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L92:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L92
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L8:
  cmpb   $0x2f,-0x11(%rbp)
  jle    L174
  cmpb   $0x39,-0x11(%rbp)
  jle    L23
L174:
  cmpb   $0x40,-0x11(%rbp)
  jle    L47
  cmpb   $0x5a,-0x11(%rbp)
  jle    L23
L47:
  cmpb   $0x60,-0x11(%rbp)
  jle    L56
  cmpb   $0x7a,-0x11(%rbp)
  jg     L56
L23:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L25
L56:
  cmpl   $0x0,-0x2c(%rbp)
  je     L25
  cmpl   $0x1,-0x2c(%rbp)
  jne    L31
  cmpl   $0x0,-0x10(%rbp)
  je     L179
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L25
L179:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  jmp    L25
L31:
  cmpb   $0x20,-0x11(%rbp)
  jle    L25
  cmpb   $0x7f,-0x11(%rbp)
  je     L25
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
L25:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L8
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *NormalizeSeqName(char *name, int mode) {
  char c, *newname;
  int i, n;
  n = 0;
  while (name[n] != '\0')
    n++;
  newname = (char *)malloc((n + 1) * sizeof(char));
  i = 0;
  n = 0;
  while ((c = name[n++]) != '\0') {
    if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
      newname[i++] = c;
    else if (mode != 0) {
      if (mode == 1) {
        if (i == 0 || newname[(i - 1)] != '_')
          newname[i++] = '_';
      } else if (c >= '!' && c <= '~')
        newname[i++] = c;
    }
  }
  newname[i] = '\0';
  return newname;
}
```
user: Translate the below assembly code into C programming language:

```asm
<NormalizeSeqName>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  cmpb   $0x0,(%rdi)
  je     L6
  mov    $0x1,%eax
L117:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L117
L111:
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movzbl (%rbx),%eax
  test   %al,%al
  je     L107
  lea    0x1(%rbx),%rdx
  mov    $0x0,%esi
  jmp    L98
L6:
  mov    $0x0,%edi
  jmp    L111
L40:
  movslq %esi,%rcx
  mov    %al,(%rdi,%rcx,1)
  lea    0x1(%rsi),%esi
L53:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L17
L98:
  mov    %eax,%r8d
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x19,%cl
  jbe    L40
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L40
  test   %ebp,%ebp
  je     L53
  cmp    $0x1,%ebp
  je     L133
  sub    $0x21,%r8d
  cmp    $0x5d,%r8b
  ja     L53
  movslq %esi,%rcx
  mov    %al,(%rdi,%rcx,1)
  lea    0x1(%rsi),%esi
  jmp    L53
L133:
  test   %esi,%esi
  je     L118
  movslq %esi,%rax
  cmpb   $0x5f,-0x1(%rdi,%rax,1)
  je     L53
L118:
  movslq %esi,%rax
  movb   $0x5f,(%rdi,%rax,1)
  lea    0x1(%rsi),%esi
  jmp    L53
L107:
  mov    $0x0,%esi
L17:
  movslq %esi,%rsi
  movb   $0x0,(%rdi,%rsi,1)
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *NormalizeSeqName(char *name, int mode) {
  char c, *newname;
  int i, n;
  n = 0;
  while (name[n] != '\0')
    n++;
  newname = (char *)malloc((n + 1) * sizeof(char));
  i = 0;
  n = 0;
  while ((c = name[n++]) != '\0') {
    if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
      newname[i++] = c;
    else if (mode != 0) {
      if (mode == 1) {
        if (i == 0 || newname[(i - 1)] != '_')
          newname[i++] = '_';
      } else if (c >= '!' && c <= '~')
        newname[i++] = c;
    }
  }
  newname[i] = '\0';
  return newname;
}
```
user: What is the c source code of the assembly code below?

```asm
<NormalizeSeqName>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L130
  mov    $0x1,%eax
  nopl   (%rax)
L54:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L54
  add    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L74
L114:
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L117:
  mov    %edx,%ecx
  lea    (%rax,%r8,1),%r9
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x19,%cl
  jbe    L110
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L110
  test   %ebp,%ebp
  je     L75
  cmp    $0x1,%ebp
  je     L5
  lea    -0x21(%rdx),%ecx
  cmp    $0x5d,%cl
  ja     L75
  nopw   0x0(%rax,%rax,1)
L110:
  mov    %dl,(%r9)
  add    $0x1,%esi
  movslq %esi,%r8
L75:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L117
L73:
  add    %rax,%r8
  movb   $0x0,(%r8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  test   %esi,%esi
  jne    L126
  movb   $0x5f,(%r9)
  add    $0x1,%esi
  movslq %esi,%r8
L6:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L117
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L126:
  cmpb   $0x5f,-0x1(%rax,%r8,1)
  je     L75
  add    $0x1,%esi
  movb   $0x5f,(%r9)
  movslq %esi,%r8
  jmp    L6
  nopl   0x0(%rax)
L130:
  mov    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L114
L74:
  mov    %rax,%r8
  movb   $0x0,(%r8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *NormalizeSeqName(char *name, int mode) {
  char c, *newname;
  int i, n;
  n = 0;
  while (name[n] != '\0')
    n++;
  newname = (char *)malloc((n + 1) * sizeof(char));
  i = 0;
  n = 0;
  while ((c = name[n++]) != '\0') {
    if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
      newname[i++] = c;
    else if (mode != 0) {
      if (mode == 1) {
        if (i == 0 || newname[(i - 1)] != '_')
          newname[i++] = '_';
      } else if (c >= '!' && c <= '~')
        newname[i++] = c;
    }
  }
  newname[i] = '\0';
  return newname;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<NormalizeSeqName>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L217
  mov    $0x1,%eax
  nopl   (%rax)
L115:
  mov    %eax,%edi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L115
  add    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%r8
  test   %dl,%dl
  je     L178
L114:
  lea    0x1(%rbx),%rax
  test   %ebp,%ebp
  jne    L100
  xor    %edi,%edi
  nopl   (%rax)
L76:
  mov    %edx,%esi
  lea    (%r8,%rdi,1),%rcx
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x19,%sil
  jbe    L122
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L122
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L76
  jmp    L112
L100:
  xor    %edi,%edi
  xor    %r9d,%r9d
  cmp    $0x1,%ebp
  je     L52
  nopw   0x0(%rax,%rax,1)
L120:
  mov    %edx,%esi
  lea    (%r8,%r9,1),%rcx
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x19,%sil
  jbe    L145
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L145
  lea    -0x21(%rdx),%esi
  cmp    $0x5d,%sil
  ja     L190
  nopl   0x0(%rax)
L145:
  mov    %dl,(%rcx)
  add    $0x1,%edi
  movslq %edi,%r9
L190:
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L120
L109:
  lea    (%r8,%r9,1),%rcx
L112:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L83:
  mov    %dl,(%rcx)
  add    $0x1,%edi
  movslq %edi,%r9
L151:
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L109
L52:
  mov    %edx,%esi
  lea    (%r8,%r9,1),%rcx
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x19,%sil
  jbe    L83
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%sil
  jbe    L83
  test   %edi,%edi
  jne    L160
L153:
  add    $0x1,%edi
  movb   $0x5f,(%rcx)
  movslq %edi,%r9
  jmp    L151
  nopl   (%rax)
L122:
  add    $0x1,%rax
  mov    %dl,(%rcx)
  add    $0x1,%ebp
  movzbl -0x1(%rax),%edx
  movslq %ebp,%rdi
  test   %dl,%dl
  jne    L76
  lea    (%r8,%rdi,1),%rcx
  mov    %r8,%rax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L217:
  mov    $0x1,%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%r8
  test   %dl,%dl
  jne    L114
L178:
  mov    %rax,%rcx
  mov    %r8,%rax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L160:
  cmpb   $0x5f,-0x1(%r8,%r9,1)
  jne    L153
  jmp    L151
```

assistant: ```c
char *NormalizeSeqName(char *name, int mode) {
  char c, *newname;
  int i, n;
  n = 0;
  while (name[n] != '\0')
    n++;
  newname = (char *)malloc((n + 1) * sizeof(char));
  i = 0;
  n = 0;
  while ((c = name[n++]) != '\0') {
    if ((c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z'))
      newname[i++] = c;
    else if (mode != 0) {
      if (mode == 1) {
        if (i == 0 || newname[(i - 1)] != '_')
          newname[i++] = '_';
      } else if (c >= '!' && c <= '~')
        newname[i++] = c;
    }
  }
  newname[i] = '\0';
  return newname;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L16:
  movl   $0x1,-0x8(%rbp)
  jmp    L26
L2:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L2
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    for (j = 1; j <= argv[1][0]; j++) {
      sum += j;
    }
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L36
  mov    0x8(%rsi),%rax
  movzbl (%rax),%r8d
  mov    $0x0,%esi
  mov    $0x0,%ecx
  movsbl %r8b,%edx
  add    $0x1,%edx
  jmp    L58
L47:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L47
L13:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L3
L58:
  mov    $0x1,%eax
  test   %r8b,%r8b
  jg     L47
  jmp    L13
L36:
  mov    $0x0,%esi
L3:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    for (j = 1; j <= argv[1][0]; j++) {
      sum += j;
    }
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L26
  mov    0x8(%rsi),%rax
  xor    %ecx,%ecx
  xor    %esi,%esi
  movsbl (%rax),%edx
  mov    %edx,%r8d
  add    $0x1,%edx
  nopl   (%rax)
L5:
  mov    $0x1,%eax
  test   %r8b,%r8b
  jle    L47
  nopw   0x0(%rax,%rax,1)
L9:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L9
L47:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L5
L8:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L26:
  xor    %esi,%esi
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    for (j = 1; j <= argv[1][0]; j++) {
      sum += j;
    }
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  test   %edi,%edi
  jle    L116
  mov    0x8(%rsi),%rax
  movdqa D29(%rip),%xmm3
  mov    %edi,%r9d
  xor    %esi,%esi
  xor    %edi,%edi
  movsbl (%rax),%edx
  mov    %edx,%r10d
  mov    %edx,%ecx
  lea    -0x1(%rdx),%r11d
  and    $0xfffffffc,%r10d
  shr    $0x2,%ecx
  lea    0x1(%r10),%ebx
  nopw   0x0(%rax,%rax,1)
L72:
  test   %edx,%edx
  jle    L156
  cmp    $0x9,%r11d
  jbe    L64
  movdqa D23(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
L14:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L14
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%esi
  mov    %ebx,%eax
  cmp    %r10d,%edx
  je     L156
L3:
  lea    0x1(%rax),%r8d
  add    %eax,%esi
  cmp    %edx,%r8d
  jg     L156
  add    %r8d,%esi
  lea    0x2(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x3(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x4(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x5(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x6(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x7(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  lea    0x8(%rax),%r8d
  cmp    %r8d,%edx
  jl     L156
  add    %r8d,%esi
  add    $0x9,%eax
  lea    (%rsi,%rax,1),%r8d
  cmp    %eax,%edx
  cmovge %r8d,%esi
L156:
  add    $0x1,%edi
  cmp    %edi,%r9d
  jne    L72
L94:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L64:
  mov    $0x1,%eax
  jmp    L3
L116:
  xor    %esi,%esi
  jmp    L94
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: byte[16]
name: unpack_data
arguments: tag: D23
datatype: byte[16]
name: unpack_data
arguments: tag: D3
datatype: string

tool: {"D29": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D23": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D3: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    for (j = 1; j <= argv[1][0]; j++) {
      sum += j;
    }
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BASM_PP_Expand2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x1028(%rbp)
  mov    %rsi,-0x1030(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1028(%rbp),%rdx
  lea    -0x1010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x1,-0x1018(%rbp)
  movl   $0x0,-0x1014(%rbp)
  jmp    L33
L22:
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rdi
  call   <BASM_PP_Line@plt>
  mov    %eax,-0x1018(%rbp)
  cmpl   $0x0,-0x1018(%rbp)
  jle    L33
  addl   $0x1,-0x1014(%rbp)
L33:
  cmpl   $0x0,-0x1018(%rbp)
  jg     L22
  lea    -0x1010(%rbp),%rdx
  mov    -0x1030(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1014(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int BASM_PP_Expand2(char *src, char *dst) {
  char lbuf[4096];
  int i, ni;
  strcpy(lbuf, src);
  i = 1;
  ni = 0;
  while (i > 0) {
    i = BASM_PP_Line(lbuf);
    if (i > 0)
      ni++;
  }
  strcpy(dst, lbuf);
  return (ni);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BASM_PP_Expand2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L3
L8:
  add    $0x1,%ebx
L3:
  mov    %rbp,%rdi
  call   <BASM_PP_Line@plt>
  test   %eax,%eax
  jg     L8
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %ebx,%eax
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BASM_PP_Expand2(char *src, char *dst) {
  char lbuf[4096];
  int i, ni;
  strcpy(lbuf, src);
  i = 1;
  ni = 0;
  while (i > 0) {
    i = BASM_PP_Line(lbuf);
    if (i > 0)
      ni++;
  }
  strcpy(dst, lbuf);
  return (ni);
}
```