ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x1f,-0x4(%rbp)
  jg     L29
  movsbl -0x4(%rbp),%eax
  add    $0x40,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L29:
  cmpb   $0x7f,-0x4(%rbp)
  jne    L9
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L9:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string
name: read_data
arguments: tag: D2
type_infered: string

tool: D3: ^%c

tool: D2: ^?

assistant: ```c
void prctl(c) char c;
{
  if (c < ' ')
    printf("^%c", 'A' + c - 1);
  else if (c == 0177)
    printf("^?");
  else
    printf("%c", c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prctl>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1f,%dil
  jle    L9
  cmp    $0x7f,%dil
  je     L6
  movsbl %dil,%edi
  call   <putchar@plt>
L8:
  add    $0x8,%rsp
  ret
L9:
  movsbl %dil,%edi
  lea    0x40(%rdi),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L6:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D10
data_type: string

tool: D6: ^%c

tool: D10: ^?

assistant: ```c
void prctl(c) char c;
{
  if (c < ' ')
    printf("^%c", 'A' + c - 1);
  else if (c == 0177)
    printf("^?");
  else
    printf("%c", c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prctl>:
  endbr64
  cmp    $0x1f,%dil
  jle    L2
  cmp    $0x7f,%dil
  je     L13
  movsbl %dil,%edi
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L13:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L2:
  add    $0x40,%edi
  xor    %eax,%eax
  movsbl %dil,%esi
  lea    D12(%rip),%rdi
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D12
datatype: string

tool: D10: ^?

tool: D12: ^%c

assistant: ```c
void prctl(c) char c;
{
  if (c < ' ')
    printf("^%c", 'A' + c - 1);
  else if (c == 0177)
    printf("^?");
  else
    printf("%c", c);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<prctl>:
  endbr64
  cmp    $0x1f,%dil
  jle    L18
  cmp    $0x7f,%dil
  je     L8
  movsbl %dil,%edi
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L8:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
  xchg   %ax,%ax
L18:
  add    $0x40,%edi
  xor    %eax,%eax
  movsbl %dil,%esi
  lea    D3(%rip),%rdi
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D2: ^?

tool: D3: ^%c

assistant: ```c
void prctl(c) char c;
{
  if (c < ' ')
    printf("^%c", 'A' + c - 1);
  else if (c == 0177)
    printf("^?");
  else
    printf("%c", c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ASN1_item_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L35
L34:
  mov    -0x38(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ASN1_item_i2d@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L25
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ASN1error@plt>
  mov    $0x0,%eax
  jmp    L35
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <ASN1_item_d2i@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASN1_item_dup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L28
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdx
  call   <ASN1_item_i2d@plt>
  mov    %rax,%rdx
  mov    0x8(%rsp),%rbx
  test   %rbx,%rbx
  je     L24
  mov    %rbx,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rcx
  mov    $0x0,%edi
  call   <ASN1_item_d2i@plt>
  mov    %rax,%rbx
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L22
L28:
  mov    %rsi,%rbx
  jmp    L22
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ASN1_item_dup>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L22
  mov    %rdi,%r13
  mov    %rsi,%rdi
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdx
  call   <ASN1_item_i2d@plt>
  mov    0x8(%rsp),%r12
  mov    %rax,%rdx
  test   %r12,%r12
  je     L40
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,0x10(%rsp)
  call   <ASN1_item_d2i@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  call   <free@plt>
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %r12d,%r12d
  jmp    L15
  nopl   (%rax)
L40:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ASN1_item_dup>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L42
  mov    %rdi,%r13
  mov    %rsi,%rdi
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdx
  call   <ASN1_item_i2d@plt>
  mov    0x8(%rsp),%r12
  mov    %rax,%rdx
  test   %r12,%r12
  je     L0
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,0x10(%rsp)
  call   <ASN1_item_d2i@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  call   <free@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  xor    %r12d,%r12d
  jmp    L19
  nopl   (%rax)
L0:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L19
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   %edx,%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L15
L13:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x3,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **dmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  double **m, *p;
  m = (double **)malloc((maxx - minx + 1) * sizeof(double *));
  assert(m);
  m -= minx;
  p = (double *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(double));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,0xc(%rsp)
  mov    %ecx,%r13d
  mov    %esi,%r14d
  sub    %edi,%r14d
  add    $0x1,%r14d
  movslq %r14d,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  movslq %r12d,%r15
  lea    0x0(,%r15,8),%rax
  mov    %rbx,%rcx
  sub    %rax,%rcx
  mov    %rcx,(%rsp)
  sub    0xc(%rsp),%r13d
  lea    0x1(%r13),%edi
  imul   %r14d,%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %r12d,%ebp
  jl     L10
  movslq %r13d,%r13
  lea    0x8(,%r13,8),%rdx
  movslq 0xc(%rsp),%rax
  shl    $0x3,%rax
  sub    %rax,%r14
  sub    %r12d,%ebp
  lea    0x1(%r15,%rbp,1),%rax
  mov    (%rsp),%rcx
  lea    (%rcx,%rax,8),%rax
L19:
  mov    %r14,(%rbx)
  add    %rdx,%r14
  add    $0x8,%rbx
  cmp    %rax,%rbx
  jne    L19
L10:
  mov    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **dmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  double **m, *p;
  m = (double **)malloc((maxx - minx + 1) * sizeof(double *));
  assert(m);
  m -= minx;
  p = (double *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(double));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dmatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  sub    %edi,%r14d
  mov    %edi,%r13d
  push   %r12
  movslq %edx,%r12
  push   %rbp
  lea    0x1(%r14),%ebp
  push   %rbx
  movslq %ebp,%rdi
  shl    $0x3,%rdi
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %ecx,(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rsp),%edx
  movslq %r13d,%rcx
  mov    %rbx,%r15
  lea    0x0(,%rcx,8),%rax
  mov    %rcx,0x8(%rsp)
  sub    %r12d,%edx
  sub    %rax,%r15
  lea    0x1(%rdx),%edi
  mov    %edx,(%rsp)
  imul   %ebp,%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  cmp    %r13d,%esi
  jl     L16
  mov    0x8(%rsp),%rcx
  movslq (%rsp),%rdx
  shl    $0x3,%r12
  mov    %rbp,%rax
  sub    %r12,%rax
  lea    0x1(%rcx,%r14,1),%rcx
  lea    0x8(,%rdx,8),%rsi
  mov    %rbx,%rdx
  lea    (%r15,%rcx,8),%rcx
L6:
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  add    %rsi,%rax
  cmp    %rcx,%rdx
  jne    L6
L16:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **dmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  double **m, *p;
  m = (double **)malloc((maxx - minx + 1) * sizeof(double *));
  assert(m);
  m -= minx;
  p = (double *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(double));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dmatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movslq %edx,%r13
  mov    %esi,%edx
  push   %r12
  sub    %edi,%edx
  mov    %ecx,%r12d
  push   %rbp
  add    $0x1,%edx
  sub    %r13d,%r12d
  push   %rbx
  movslq %edx,%rdi
  shl    $0x3,%rdi
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %edx,(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <assert@plt>
  mov    (%rsp),%edx
  lea    0x1(%r12),%edi
  movslq %r14d,%rcx
  lea    0x0(,%rcx,8),%rax
  mov    %rbx,%r15
  mov    %rcx,0x8(%rsp)
  imul   %edx,%edi
  sub    %rax,%r15
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  cmp    %r14d,%esi
  jl     L30
  shl    $0x3,%r13
  movslq %r12d,%r12
  mov    0x8(%rsp),%rcx
  add    $0x1,%r12
  neg    %r13
  cmp    %r14d,%esi
  lea    0x0(,%r12,8),%rdi
  je     L38
  mov    (%rsp),%edx
  lea    (%rdi,%rbp,1),%rax
  shl    $0x4,%r12
  movq   %rbp,%xmm1
  movq   %rax,%xmm4
  movq   %r12,%xmm2
  movq   %r13,%xmm3
  mov    %rbx,%rax
  punpcklqdq %xmm4,%xmm1
  punpcklqdq %xmm2,%xmm2
  punpcklqdq %xmm3,%xmm3
  mov    %edx,%ecx
  shr    %ecx
  shl    $0x4,%rcx
  add    %rbx,%rcx
  nopl   (%rax)
L35:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddq  %xmm2,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L35
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  mov    %eax,%ecx
  add    %eax,%r14d
  imul   %rdi,%rcx
  add    %rcx,%rbp
  cmp    %eax,%edx
  je     L30
  movslq %r14d,%rcx
L38:
  lea    0x0(%rbp,%r13,1),%rax
  mov    %rax,(%r15,%rcx,8)
L30:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **dmatrix(int minx, int maxx, int miny, int maxy) {
  int i;
  double **m, *p;
  m = (double **)malloc((maxx - minx + 1) * sizeof(double *));
  assert(m);
  m -= minx;
  p = (double *)malloc((maxx - minx + 1) * (maxy - miny + 1) * sizeof(double));
  assert(p);
  for (i = minx; i <= maxx; i++) {
    m[i] = p - miny;
    p += (maxy - miny + 1);
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cosapprox>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D12(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  D11(%rip),%xmm1
  subss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  D14(%rip),%xmm0
  addss  %xmm1,%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  D31(%rip),%xmm1
  subss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  D28(%rip),%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: byte[4]
name: read_data
arguments: data_label: D11
type_infered: byte[4]
name: read_data
arguments: data_label: D14
type_infered: byte[4]
name: read_data
arguments: data_label: D31
type_infered: byte[4]
name: read_data
arguments: data_label: D28
type_infered: byte[4]

tool: {"D12": [0xe3,0xa2,0x9d,0x37]}

tool: {"D11": [0x36,0x8a,0xaf,0x3a]}

tool: {"D14": [0xb6,0xf7,0x29,0x3d]}

tool: {"D31": [0xe1,0xe4,0xff,0x3e]}

tool: {"D28": [0x5d,0xfd,0x7f,0x3f]}

assistant: ```c
float cosapprox(float val) {
  float val2 = val * val;
  return 0.999959766864776611328125f + val2 * (-0.4997930824756622314453125f + val2 * (4.1496001183986663818359375e-2f + val2 * (-1.33926304988563060760498046875e-3f + val2 * 1.8791708498611114919185638427734375e-5f)));
}
```
user: What is the c source code of the assembly code below:

```asm
<cosapprox>:
  endbr64
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  mulss  D16(%rip),%xmm1
  subss  D49(%rip),%xmm1
  mulss  %xmm0,%xmm1
  addss  D26(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D6(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D34(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D49
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D26
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D6
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D34
type_guessed: byte[4]

tool: {"D16": [0xe3,0xa2,0x9d,0x37]}

tool: {"D49": [0x36,0x8a,0xaf,0x3a]}

tool: {"D26": [0xb6,0xf7,0x29,0x3d]}

tool: {"D6": [0xe1,0xe4,0xff,0x3e]}

tool: {"D34": [0x5d,0xfd,0x7f,0x3f]}

assistant: ```c
float cosapprox(float val) {
  float val2 = val * val;
  return 0.999959766864776611328125f + val2 * (-0.4997930824756622314453125f + val2 * (4.1496001183986663818359375e-2f + val2 * (-1.33926304988563060760498046875e-3f + val2 * 1.8791708498611114919185638427734375e-5f)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cosapprox>:
  endbr64
  mulss  %xmm0,%xmm0
  movss  D12(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D29(%rip),%xmm1
  mulss  %xmm0,%xmm1
  addss  D25(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D5(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D39(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D12
datatype: byte[4]
name: read_data
arguments: tag: D29
datatype: byte[4]
name: read_data
arguments: tag: D25
datatype: byte[4]
name: read_data
arguments: tag: D5
datatype: byte[4]
name: read_data
arguments: tag: D39
datatype: byte[4]

tool: {"D12": [0xe3,0xa2,0x9d,0x37]}

tool: {"D29": [0x36,0x8a,0xaf,0x3a]}

tool: {"D25": [0xb6,0xf7,0x29,0x3d]}

tool: {"D5": [0xe1,0xe4,0xff,0x3e]}

tool: {"D39": [0x5d,0xfd,0x7f,0x3f]}

assistant: ```c
float cosapprox(float val) {
  float val2 = val * val;
  return 0.999959766864776611328125f + val2 * (-0.4997930824756622314453125f + val2 * (4.1496001183986663818359375e-2f + val2 * (-1.33926304988563060760498046875e-3f + val2 * 1.8791708498611114919185638427734375e-5f)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cosapprox>:
  endbr64
  mulss  %xmm0,%xmm0
  movss  D18(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D48(%rip),%xmm1
  mulss  %xmm0,%xmm1
  addss  D17(%rip),%xmm1
  mulss  %xmm0,%xmm1
  subss  D23(%rip),%xmm1
  mulss  %xmm1,%xmm0
  addss  D15(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D18
datatype: byte[4]
name: disassemble_data
arguments: tag: D48
datatype: byte[4]
name: disassemble_data
arguments: tag: D17
datatype: byte[4]
name: disassemble_data
arguments: tag: D23
datatype: byte[4]
name: disassemble_data
arguments: tag: D15
datatype: byte[4]

tool: {"D18": [0xe3,0xa2,0x9d,0x37]}

tool: {"D48": [0x36,0x8a,0xaf,0x3a]}

tool: {"D17": [0xb6,0xf7,0x29,0x3d]}

tool: {"D23": [0xe1,0xe4,0xff,0x3e]}

tool: {"D15": [0x5d,0xfd,0x7f,0x3f]}

assistant: ```c
float cosapprox(float val) {
  float val2 = val * val;
  return 0.999959766864776611328125f + val2 * (-0.4997930824756622314453125f + val2 * (4.1496001183986663818359375e-2f + val2 * (-1.33926304988563060760498046875e-3f + val2 * 1.8791708498611114919185638427734375e-5f)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char a[], int n) {
  int i, j;
  for (i = 0, j = n - 1; i < j; ++i, --j) {
    char t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L11
  movslq %esi,%rsi
  mov    $0x0,%eax
L4:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L4
L11:
  ret
```

assistant: ```c
void reverse(char a[], int n) {
  int i, j;
  for (i = 0, j = n - 1; i < j; ++i, --j) {
    char t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L9
  movslq %esi,%rsi
  xor    %eax,%eax
L13:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L13
L9:
  ret
```

assistant: ```c
void reverse(char a[], int n) {
  int i, j;
  for (i = 0, j = n - 1; i < j; ++i, --j) {
    char t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  xor    %eax,%eax
L1:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L1
L6:
  ret
```

assistant: ```c
void reverse(char a[], int n) {
  int i, j;
  for (i = 0, j = n - 1; i < j; ++i, --j) {
    char t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy@plt>
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void delete (void *obj) {
  if (obj)
    destroy(obj);
  free(obj);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delete>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L9
  call   <destroy@plt>
L9:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void delete (void *obj) {
  if (obj)
    destroy(obj);
  free(obj);
}
```