ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  mov    %eax,%ebx
  call   <vassert@plt>
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <vassert@plt>
  jmp    L46
  xchg   %ax,%ax
L61:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r12
  add    $0x1,%r13
  call   <tolower@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  mov    %eax,%ebx
L46:
  test   %bl,%bl
  setne  %al
  mov    %eax,%edx
  test   %bpl,%bpl
  je     L18
  test   %al,%al
  je     L18
  cmp    %bl,%bpl
  je     L61
  cmp    %bl,%bpl
  jg     L72
L62:
  mov    $0xffffffff,%eax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  or     %bpl,%bl
  je     L33
  test   %bpl,%bpl
  jne    L72
  test   %dl,%dl
  jne    L62
L72:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D2: str1 == NULL

tool: D0: str2 == NULL

assistant: ```c
int strcasecmp(const char *str1, const char *str2) {
  char c1 = tolower(*str1), c2 = tolower(*str2);
  vassert(str1 != NULL, "str1 == NULL");
  vassert(str2 != NULL, "str2 == NULL");
  while (c1 && c2) {
    if (c1 != c2) {
      if (c1 > c2)
        return 1;
      return -1;
    }
    c1 = tolower(*++str1);
    c2 = tolower(*++str2);
  }
  if (!c1 && !c2)
    return 0;
  if (!c1 && c2)
    return -1;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L13:
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x2,-0xc(%rbp)
  jle    L13
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string

tool: D14: erf

tool: D11: # c::%s


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "erf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D2(%rip),%r13
  lea    D11(%rip),%r12
  lea    D9(%rip),%rbp
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D2: erf

tool: D11: # c::%s


tool: D9: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "erf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D12(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D12: erf

tool: D0: # c::%s


tool: D2: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "erf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D16(%rip),%r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D25
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D16: erf

tool: D25: # c::%s


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "erf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<draw_frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: draw_frame() called!!!!!!

assistant: ```c
int draw_frame(unsigned char *src[]) {
  printf("draw_frame() called!!!!!!");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<draw_frame>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string

tool: D7: draw_frame() called!!!!!!

assistant: ```c
int draw_frame(unsigned char *src[]) {
  printf("draw_frame() called!!!!!!");
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<draw_frame>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: draw_frame() called!!!!!!

assistant: ```c
int draw_frame(unsigned char *src[]) {
  printf("draw_frame() called!!!!!!");
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<draw_frame>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: draw_frame() called!!!!!!

assistant: ```c
int draw_frame(unsigned char *src[]) {
  printf("draw_frame() called!!!!!!");
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L7
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ultoa@plt>
  jmp    L14
L7:
  mov    -0x10(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x8(%rbp),%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <ultoa@plt>
  mov    -0x10(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *ltoa(long val, char *buf, int radix) {
  if (val >= 0) {
    return ultoa(val, buf, radix);
  } else {
    buf[0] = '-';
    ultoa(-val, buf + 1, radix);
    return buf;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ltoa>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  js     L19
  call   <ultoa@plt>
L12:
  pop    %rbx
  ret
L19:
  movb   $0x2d,(%rsi)
  lea    0x1(%rsi),%rsi
  neg    %rdi
  call   <ultoa@plt>
  mov    %rbx,%rax
  jmp    L12
```

assistant: ```c
char *ltoa(long val, char *buf, int radix) {
  if (val >= 0) {
    return ultoa(val, buf, radix);
  } else {
    buf[0] = '-';
    ultoa(-val, buf + 1, radix);
    return buf;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  js     L6
  pop    %rbp
  jmp    1050 <ultoa@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  movb   $0x2d,(%rsi)
  neg    %rdi
  lea    0x1(%rsi),%rsi
  call   <ultoa@plt>
  mov    %rbp,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ltoa(long val, char *buf, int radix) {
  if (val >= 0) {
    return ultoa(val, buf, radix);
  } else {
    buf[0] = '-';
    ultoa(-val, buf + 1, radix);
    return buf;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  js     L6
  pop    %rbp
  jmp    1050 <ultoa@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  movb   $0x2d,(%rsi)
  neg    %rdi
  lea    0x1(%rsi),%rsi
  call   <ultoa@plt>
  mov    %rbp,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ltoa(long val, char *buf, int radix) {
  if (val >= 0) {
    return ultoa(val, buf, radix);
  } else {
    buf[0] = '-';
    ultoa(-val, buf + 1, radix);
    return buf;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L14
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  negq   -0x8(%rbp)
L14:
  cmpq   $0x9,-0x8(%rbp)
  jle    L12
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %eax,%edi
  call   <ft_putnbr>
L12:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  lea    0x30(%rdx),%rax
  mov    %rax,%rdi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr(int n) {
  long nb;
  nb = n;
  if (nb < 0) {
    ft_putchar('-');
    nb = nb * -1;
  }
  if (nb > 9)
    ft_putnbr(nb / 10);
  ft_putchar(nb % 10 + 48);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_putnbr>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  test   %rbx,%rbx
  js     L19
L21:
  cmp    $0x9,%rbx
  jg     L16
L11:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  call   <ft_putchar@plt>
  pop    %rbx
  ret
L19:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  neg    %rbx
  jmp    L21
L16:
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  mov    %edx,%edi
  sub    %eax,%edi
  call   <ft_putnbr>
  jmp    L11
```

assistant: ```c
void ft_putnbr(int n) {
  long nb;
  nb = n;
  if (nb < 0) {
    ft_putchar('-');
    nb = nb * -1;
  }
  if (nb > 9)
    ft_putnbr(nb / 10);
  ft_putchar(nb % 10 + 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_putnbr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  test   %rbx,%rbx
  js     L54
L27:
  cmp    $0x9,%rbx
  jg     L71
L14:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  nopl   (%rax)
L71:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rbx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%rbp
  cmp    $0x63,%rbx
  jg     L65
L66:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbp,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbp
  lea    0x30(%rbp),%rdi
  call   <ft_putchar@plt>
  jmp    L14
  xchg   %ax,%ax
L54:
  mov    $0x2d,%edi
  neg    %rbx
  call   <ft_putchar@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %rbp,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r12
  cmp    $0x3e7,%rbx
  jg     L9
L4:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <ft_putchar@plt>
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rax
  mul    %rcx
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  mov    %ecx,%edi
  call   <ft_putnbr>
  jmp    L4
```

assistant: ```c
void ft_putnbr(int n) {
  long nb;
  nb = n;
  if (nb < 0) {
    ft_putchar('-');
    nb = nb * -1;
  }
  if (nb > 9)
    ft_putnbr(nb / 10);
  ft_putchar(nb % 10 + 48);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_putnbr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  test   %rbx,%rbx
  js     L28
L8:
  cmp    $0x9,%rbx
  jg     L3
L47:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbx
  lea    0x30(%rbx),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_putchar@plt>
  nopl   (%rax)
L3:
  movabs $0xcccccccccccccccd,%rcx
  mov    %rbx,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%rbp
  cmp    $0x63,%rbx
  jg     L75
L14:
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbp,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rbp
  lea    0x30(%rbp),%rdi
  call   <ft_putchar@plt>
  jmp    L47
  xchg   %ax,%ax
L28:
  mov    $0x2d,%edi
  neg    %rbx
  call   <ft_putchar@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L75:
  mov    %rbp,%rax
  mul    %rcx
  shr    $0x3,%rdx
  mov    %rdx,%r12
  cmp    $0x3e7,%rbx
  jg     L51
L54:
  movabs $0xcccccccccccccccd,%rdx
  mov    %r12,%rax
  mul    %rdx
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r12
  lea    0x30(%r12),%rdi
  call   <ft_putchar@plt>
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %r12,%rax
  mul    %rcx
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  mov    %ecx,%edi
  call   <ft_putnbr>
  jmp    L54
```

assistant: ```c
void ft_putnbr(int n) {
  long nb;
  nb = n;
  if (nb < 0) {
    ft_putchar('-');
    nb = nb * -1;
  }
  if (nb > 9)
    ft_putnbr(nb / 10);
  ft_putchar(nb % 10 + 48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L6
L21:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  add    %eax,-0x24(%rbp)
  addl   $0x1,-0x28(%rbp)
L6:
  cmpl   $0x4,-0x28(%rbp)
  jle    L21
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movsd  D21(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D21
type_infered: f64
name: parse_data
arguments: tag: D23
type_infered: string

tool: D9: Vetor[%d] = %d


tool: D25: Total = %d


tool: D21: 5

tool: D23: Media = %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  int vetor[5];
  int i, c = 0;
  vetor[0] = 8;
  vetor[1] = 5;
  vetor[2] = 4;
  vetor[3] = 3;
  vetor[4] = 2;
  for (i = 0; i < 5; i++) {
    printf("Vetor[%d] = %d\n", i, vetor[i]);
    c += vetor[i];
  }
  printf("Total = %d\n", c);
  printf("Media = %.2f\n", c / 5.0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D12(%rip),%r13
L6:
  mov    (%rsp,%rbx,4),%ebp
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %ebp,%r12d
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L6
  mov    %r12d,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  divsd  D31(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D12: Vetor[%d] = %d


tool: D29: Total = %d


tool: D31: 5

tool: D17: Media = %.2f


assistant: ```c
int main(int argc, char *argv[]) {
  int vetor[5];
  int i, c = 0;
  vetor[0] = 8;
  vetor[1] = 5;
  vetor[2] = 4;
  vetor[3] = 3;
  vetor[4] = 2;
  for (i = 0; i < 5; i++) {
    printf("Vetor[%d] = %d\n", i, vetor[i]);
    c += vetor[i];
  }
  printf("Total = %d\n", c);
  printf("Media = %.2f\n", c / 5.0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D38(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000005,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x200000003,%rax
  mov    %rax,0xc(%rsp)
L12:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  add    %ebp,%r12d
  cmp    $0x5,%rbx
  je     L24
  mov    (%rsp,%rbx,4),%ebp
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  cvtsi2sd %r12d,%xmm0
  divsd  D21(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D38
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D21
datatype: f64

tool: D38: Vetor[%d] = %d


tool: D19: Total = %d


tool: D16: Media = %.2f


tool: D21: 5

assistant: ```c
int main(int argc, char *argv[]) {
  int vetor[5];
  int i, c = 0;
  vetor[0] = 8;
  vetor[1] = 5;
  vetor[2] = 4;
  vetor[3] = 3;
  vetor[4] = 2;
  for (i = 0; i < 5; i++) {
    printf("Vetor[%d] = %d\n", i, vetor[i]);
    c += vetor[i];
  }
  printf("Total = %d\n", c);
  printf("Media = %.2f\n", c / 5.0);
}
```