ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<list_remove_destroy>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <list_remove@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rdi
  call   *%rbx
  mov    $0x0,%eax
L7:
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int list_remove_destroy(struct list *list, void *value, int (*cmp)(const void *, const void *), void (*free_func)(void *)) {
  void *result;
  result = list_remove(list, value, cmp);
  if (!(result)) {
    goto error;
  };
  free_func(result);
  return 0;
error:
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_remove_destroy>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <list_remove@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   *%rbx
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int list_remove_destroy(struct list *list, void *value, int (*cmp)(const void *, const void *), void (*free_func)(void *)) {
  void *result;
  result = list_remove(list, value, cmp);
  if (!(result)) {
    goto error;
  };
  free_func(result);
  return 0;
error:
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<list_remove_destroy>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <list_remove@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  call   *%rbx
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int list_remove_destroy(struct list *list, void *value, int (*cmp)(const void *, const void *), void (*free_func)(void *)) {
  void *result;
  result = list_remove(list, value, cmp);
  if (!(result)) {
    goto error;
  };
  free_func(result);
  return 0;
error:
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L4:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_doubles(double *buf, size_t count, double value) {
  for (size_t i = 0; i < (size_t)count; i++) {
    buf[i] = value;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_doubles>:
  endbr64
  test   %rsi,%rsi
  je     L6
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
L17:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L17
L6:
  ret
```

assistant: ```c
void set_doubles(double *buf, size_t count, double value) {
  for (size_t i = 0; i < (size_t)count; i++) {
    buf[i] = value;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_doubles>:
  endbr64
  test   %rsi,%rsi
  je     L2
  lea    (%rdi,%rsi,8),%rax
  nopl   (%rax)
L4:
  movsd  %xmm0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L4
L2:
  ret
```

assistant: ```c
void set_doubles(double *buf, size_t count, double value) {
  for (size_t i = 0; i < (size_t)count; i++) {
    buf[i] = value;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_doubles>:
  endbr64
  test   %rsi,%rsi
  je     L33
  cmp    $0x1,%rsi
  je     L32
  mov    %rsi,%rdx
  movapd %xmm0,%xmm1
  mov    %rdi,%rax
  shr    %rdx
  unpcklpd %xmm1,%xmm1
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L48:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L48
  mov    %rsi,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%esi
  je     L9
L25:
  movsd  %xmm0,(%rdi,%rax,8)
L33:
  ret
  xchg   %ax,%ax
L9:
  ret
L32:
  xor    %eax,%eax
  jmp    L25
```

assistant: ```c
void set_doubles(double *buf, size_t count, double value) {
  for (size_t i = 0; i < (size_t)count; i++) {
    buf[i] = value;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zero_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L0:
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L35:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zero_image(image, nx, ny) float *image;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      image[i * nx + j] = 0.0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zero_image>:
  endbr64
  test   %edx,%edx
  jle    L29
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  lea    -0x1(%rsi),%r11d
  lea    0x4(%rdi),%r10
  jmp    L3
L31:
  movslq %r9d,%rcx
  lea    (%rdi,%rcx,4),%rax
  add    %r11,%rcx
  lea    (%r10,%rcx,4),%rcx
L50:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L50
L16:
  add    $0x1,%r8d
  add    %esi,%r9d
  cmp    %r8d,%edx
  je     L29
L3:
  test   %esi,%esi
  jg     L31
  jmp    L16
L29:
  ret
```

assistant: ```c
void zero_image(image, nx, ny) float *image;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      image[i * nx + j] = 0.0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zero_image>:
  endbr64
  test   %edx,%edx
  jle    L21
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    0x4(,%rax,4),%r15
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L12:
  test   %r12d,%r12d
  jle    L17
  movslq %ebp,%rax
  mov    %r15,%rdx
  xor    %esi,%esi
  lea    (%r14,%rax,4),%rdi
  call   <memset@plt>
L17:
  add    $0x1,%ebx
  add    %r12d,%ebp
  cmp    %ebx,%r13d
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  ret
```

assistant: ```c
void zero_image(image, nx, ny) float *image;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      image[i * nx + j] = 0.0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<zero_image>:
  endbr64
  test   %edx,%edx
  jle    L7
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    0x0(,%rsi,4),%rbp
  push   %rbx
  xor    %ebx,%ebx
L9:
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %rbp,%rdi
  cmp    %ebx,%r12d
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  ret
```

assistant: ```c
void zero_image(image, nx, ny) float *image;
int nx, ny;
{
  int i, j;
  for (i = 0; i < ny; i++) {
    for (j = 0; j < nx; j++) {
      image[i * nx + j] = 0.0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<round_f>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  lea    0x4(%rdi),%r14
  lea    0x4(%rsi),%r13
  mov    (%rdx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x0(%rbp),%edx
  mov    %edx,%eax
  shl    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x18,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  xor    (%rbx),%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  mov    %edx,%esi
  shl    $0x18,%esi
  or     %esi,%ecx
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey(b0_l, b0_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey(b1_l, b1_r);
  temp = *left;
  *right ^= *left ^ (((*left) << (8)) | ((*left) >> (32 - 8))) ^ (((*left) >> (8)) | ((*left) << (32 - 8)));
  *left = *right;
  *right = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<round_f>:
  endbr64
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  lea    0x4(%rsi),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdx),%edi
  mov    %rsi,%rbx
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x0(%rbp),%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x18,%ecx
  shl    $0x8,%eax
  or     %ecx,%eax
  mov    (%rbx),%ecx
  shl    $0x18,%esi
  xor    %edx,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  or     %esi,%ecx
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey(b0_l, b0_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey(b1_l, b1_r);
  temp = *left;
  *right ^= *left ^ (((*left) << (8)) | ((*left) >> (32 - 8))) ^ (((*left) >> (8)) | ((*left) << (32 - 8)));
  *left = *right;
  *right = temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<round_f>:
  endbr64
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  lea    0x4(%rsi),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdx),%edi
  mov    %rsi,%rbx
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x4(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0x8(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey@plt>
  mov    0xc(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x10(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x14(%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <speckey@plt>
  mov    0x0(%rbp),%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x18,%ecx
  shl    $0x8,%eax
  or     %ecx,%eax
  mov    (%rbx),%ecx
  shl    $0x18,%esi
  xor    %edx,%ecx
  xor    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x8,%ecx
  or     %esi,%ecx
  xor    %ecx,%eax
  mov    %eax,0x0(%rbp)
  mov    %edx,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void round_f(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  uint32_t temp;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[0]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[1]);
  speckey(b0_l, b0_r);
  *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[2]);
  speckey(b0_l, b0_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[3]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[4]);
  speckey(b1_l, b1_r);
  *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[5]);
  speckey(b1_l, b1_r);
  temp = *left;
  *right ^= *left ^ (((*left) << (8)) | ((*left) >> (32 - 8))) ^ (((*left) >> (8)) | ((*left) << (32 - 8)));
  *left = *right;
  *right = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L20:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L20
  cmp    $0x20,%al
  je     L20
  movb   $0x0,0x1(%rbp)
  movsbl %al,%r12d
  mov    %r12d,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L43
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L103
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%eax
  ja     L133
L103:
  cmp    $0x2d,%ebx
  je     L145
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L96:
  mov    $0x1,%ebx
  jmp    L141
L43:
  add    $0x1,%rbp
L72:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %rbp,%rbx
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isalpha@plt>
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L72
  movb   $0x0,(%rbx)
  mov    $0x31,%ebx
  mov    D4(%rip),%rax
  cmp    %r12d,(%rax)
  je     L133
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L133
L145:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  movsbl %al,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r12d
  je     L96
  test   %rax,%rax
  jne    L96
  jmp    L133
L97:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L141:
  mov    %ebx,%r13d
  mov    %r12b,0x0(%rbp,%rbx,1)
  movsbl %r12b,%edi
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L97
  cmp    $0x2e,%r12d
  je     L93
L127:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    $0x30,%ebx
  mov    D4(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L123
L133:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L93:
  lea    0x1(%r13),%ebx
  movslq %ebx,%rbx
L105:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  mov    %ebx,%r13d
  mov    %al,0x0(%rbp,%rbx,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L105
  jmp    L127
L123:
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L133
```

assistant: ```c
int getop(char s[]) {
  int i = 0;
  int c, next_ch;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (isalpha(c)) {
    while (isalpha(s[++i] = c = getch()))
      ;
    s[i] = '\0';
    if (c != EOF)
      ungetch(c);
    return '1';
  }
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-') {
    next_ch = getch();
    if (!isdigit(next_ch) && next_ch != '.')
      return c;
    c = next_ch;
  } else
    c = getch();
  while (isdigit(s[++i] = c))
    c = getch();
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L152:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L152
  cmp    $0x20,%al
  je     L152
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L108
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L158
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L177
L158:
  xor    %eax,%eax
  cmp    $0x2d,%r12d
  je     L150
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L115:
  mov    %ebx,%r14d
  lea    0x1(%rbx),%r12
  neg    %r14d
  jmp    L3
  nopl   0x0(%rax)
L50:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L3:
  mov    %bpl,(%r12)
  lea    (%r14,%r12,1),%r15d
  mov    %r12,%r13
  add    $0x1,%r12
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L50
  cmp    $0x2e,%ebp
  je     L39
L63:
  mov    D2(%rip),%rax
  movb   $0x0,0x0(%r13)
  mov    $0x30,%r12d
  cmp    %ebp,(%rax)
  je     L177
L157:
  mov    %ebp,%edi
  call   <ungetch@plt>
L177:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L108:
  add    $0x1,%rbx
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%ebp
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L35
  mov    D2(%rip),%rax
  movb   $0x0,(%r12)
  mov    $0x31,%r12d
  cmp    %ebp,(%rax)
  je     L177
  jmp    L157
L150:
  call   <getch@plt>
  movsbl %al,%edi
  mov    %eax,%ebp
  mov    %edi,0xc(%rsp)
  call   <isdigit@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  jne    L115
  cmp    $0x2e,%ebp
  je     L115
  jmp    L177
  nopl   0x0(%rax,%rax,1)
L39:
  movslq %r15d,%r15
  lea    0x1(%rbx,%r15,1),%rbx
  nopl   0x0(%rax,%rax,1)
L91:
  xor    %eax,%eax
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L91
  jmp    L63
```

assistant: ```c
int getop(char s[]) {
  int i = 0;
  int c, next_ch;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (isalpha(c)) {
    while (isalpha(s[++i] = c = getch()))
      ;
    s[i] = '\0';
    if (c != EOF)
      ungetch(c);
    return '1';
  }
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-') {
    next_ch = getch();
    if (!isdigit(next_ch) && next_ch != '.')
      return c;
    c = next_ch;
  } else
    c = getch();
  while (isdigit(s[++i] = c))
    c = getch();
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  nopl   (%rax)
L120:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L120
  cmp    $0x20,%al
  je     L120
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L87
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L170
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L171
L170:
  xor    %eax,%eax
  cmp    $0x2d,%r12d
  je     L110
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L168:
  mov    %ebx,%r14d
  lea    0x1(%rbx),%r12
  neg    %r14d
  jmp    L12
  nopl   0x0(%rax)
L58:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%ebp
  movsbl %al,%edi
L12:
  mov    %bpl,(%r12)
  lea    (%r14,%r12,1),%r15d
  mov    %r12,%r13
  add    $0x1,%r12
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L58
  cmp    $0x2e,%ebp
  je     L109
L101:
  mov    D7(%rip),%rax
  movb   $0x0,0x0(%r13)
  mov    $0x30,%r12d
  cmp    %ebp,(%rax)
  je     L171
L140:
  mov    %ebp,%edi
  call   <ungetch@plt>
L171:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L87:
  add    $0x1,%rbx
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%ebp
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L43
  mov    D7(%rip),%rax
  movb   $0x0,(%r12)
  mov    $0x31,%r12d
  cmp    %ebp,(%rax)
  je     L171
  jmp    L140
L110:
  call   <getch@plt>
  movsbl %al,%edi
  mov    %eax,%ebp
  mov    %edi,0xc(%rsp)
  call   <isdigit@plt>
  mov    0xc(%rsp),%edi
  test   %rax,%rax
  jne    L168
  cmp    $0x2e,%ebp
  je     L168
  jmp    L171
  nopl   0x0(%rax,%rax,1)
L109:
  movslq %r15d,%r15
  lea    0x1(%rbx,%r15,1),%rbx
  nopl   0x0(%rax,%rax,1)
L132:
  xor    %eax,%eax
  mov    %rbx,%r13
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L132
  jmp    L101
```

assistant: ```c
int getop(char s[]) {
  int i = 0;
  int c, next_ch;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (isalpha(c)) {
    while (isalpha(s[++i] = c = getch()))
      ;
    s[i] = '\0';
    if (c != EOF)
      ungetch(c);
    return '1';
  }
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-') {
    next_ch = getch();
    if (!isdigit(next_ch) && next_ch != '.')
      return c;
    c = next_ch;
  } else
    c = getch();
  while (isdigit(s[++i] = c))
    c = getch();
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: linux


assistant: ```c
int main(int argc, char *argv[]) {
  printf("linux\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: linux


assistant: ```c
int main(int argc, char *argv[]) {
  printf("linux\n");
  return 0;
}
```