ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tmodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x10(%rbp),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ltgetstr@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L20
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L28
L20:
  mov    -0x10(%rbp),%rax
  mov    0x10(%rbp),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ltgetstr@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L9
  mov    0x10(%rbp),%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ltgetstr@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L9:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L28
  mov    -0x20(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,(%rax)
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D10: me

tool: 

assistant: ```c
void tmodes(incap, outcap, instr, outstr, def_instr, def_outstr, spp) char *incap;
char *outcap;
char **instr;
char **outstr;
char *def_instr;
char *def_outstr;
char **spp;
{
  *instr = ltgetstr(incap, spp);
  if (*instr == 0) {
    *instr = def_instr;
    *outstr = def_outstr;
    return;
  }
  *outstr = ltgetstr(outcap, spp);
  if (*outstr == 0)
    *outstr = ltgetstr("me", spp);
  if (*outstr == 0)
    *outstr = "";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tmodes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %r8,%r14
  mov    %r9,%r13
  mov    0x40(%rsp),%r15
  mov    %r15,%rsi
  mov    $0x0,%eax
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,0x0(%rbp)
  test   %eax,%eax
  je     L17
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rbx)
  test   %eax,%eax
  je     L59
L39:
  cmpq   $0x0,(%rbx)
  je     L43
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %r14,0x0(%rbp)
  mov    %r13,(%rbx)
  jmp    L26
L59:
  mov    %r15,%rsi
  lea    D7(%rip),%rdi
  call   <ltgetstr@plt>
  cltq
  mov    %rax,(%rbx)
  jmp    L39
L43:
  lea    D5(%rip),%rax
  mov    %rax,(%rbx)
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D5
data_type: string

tool: D7: me

tool: 

assistant: ```c
void tmodes(incap, outcap, instr, outstr, def_instr, def_outstr, spp) char *incap;
char *outcap;
char **instr;
char **outstr;
char *def_instr;
char *def_outstr;
char **spp;
{
  *instr = ltgetstr(incap, spp);
  if (*instr == 0) {
    *instr = def_instr;
    *outstr = def_outstr;
    return;
  }
  *outstr = ltgetstr(outcap, spp);
  if (*outstr == 0)
    *outstr = ltgetstr("me", spp);
  if (*outstr == 0)
    *outstr = "";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tmodes>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13
  mov    %r13,%rsi
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%r14)
  test   %eax,%eax
  je     L17
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rbx)
  test   %eax,%eax
  je     L27
L28:
  test   %rdx,%rdx
  je     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L10:
  lea    D0(%rip),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L17:
  mov    %r12,(%r14)
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L27:
  mov    %r13,%rsi
  lea    D6(%rip),%rdi
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rbx)
  jmp    L28
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string

tool: 

tool: D6: me

assistant: ```c
void tmodes(incap, outcap, instr, outstr, def_instr, def_outstr, spp) char *incap;
char *outcap;
char **instr;
char **outstr;
char *def_instr;
char *def_outstr;
char **spp;
{
  *instr = ltgetstr(incap, spp);
  if (*instr == 0) {
    *instr = def_instr;
    *outstr = def_outstr;
    return;
  }
  *outstr = ltgetstr(outcap, spp);
  if (*outstr == 0)
    *outstr = ltgetstr("me", spp);
  if (*outstr == 0)
    *outstr = "";
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tmodes>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%r13
  mov    %r13,%rsi
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%r14)
  test   %eax,%eax
  je     L6
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rbx)
  test   %eax,%eax
  je     L34
L26:
  test   %rdx,%rdx
  je     L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L11:
  lea    D18(%rip),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L6:
  mov    %r12,(%r14)
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L34:
  mov    %r13,%rsi
  lea    D8(%rip),%rdi
  call   <ltgetstr@plt>
  movslq %eax,%rdx
  mov    %rdx,(%rbx)
  jmp    L26
```

tool_calls: name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D8
type_infered: string

tool: 

tool: D8: me

assistant: ```c
void tmodes(incap, outcap, instr, outstr, def_instr, def_outstr, spp) char *incap;
char *outcap;
char **instr;
char **outstr;
char *def_instr;
char *def_outstr;
char **spp;
{
  *instr = ltgetstr(incap, spp);
  if (*instr == 0) {
    *instr = def_instr;
    *outstr = def_outstr;
    return;
  }
  *outstr = ltgetstr(outcap, spp);
  if (*outstr == 0)
    *outstr = ltgetstr("me", spp);
  if (*outstr == 0)
    *outstr = "";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sign_extend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x20,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sign_extend(int val, unsigned bits) {
  unsigned shift = 8 * sizeof(int) - bits;
  union {
    unsigned u;
    int s;
  } v = {(unsigned)val << shift};
  return v.s >> shift;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sign_extend>:
  endbr64
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int sign_extend(int val, unsigned bits) {
  unsigned shift = 8 * sizeof(int) - bits;
  union {
    unsigned u;
    int s;
  } v = {(unsigned)val << shift};
  return v.s >> shift;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sign_extend>:
  endbr64
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int sign_extend(int val, unsigned bits) {
  unsigned shift = 8 * sizeof(int) - bits;
  union {
    unsigned u;
    int s;
  } v = {(unsigned)val << shift};
  return v.s >> shift;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sign_extend>:
  endbr64
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int sign_extend(int val, unsigned bits) {
  unsigned shift = 8 * sizeof(int) - bits;
  union {
    unsigned u;
    int s;
  } v = {(unsigned)val << shift};
  return v.s >> shift;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D19: Enter character: 

tool: D9: Character entered: %i


assistant: ```c
int main() {
  char c;
  printf("Enter character: ");
  c = getchar();
  printf("Character entered: %i\n", c);
  putchar(c);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%ebx
  mov    %ebx,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string

tool: D5: Enter character: 

tool: D14: Character entered: %i


assistant: ```c
int main() {
  char c;
  printf("Enter character: ");
  c = getchar();
  printf("Character entered: %i\n", c);
  putchar(c);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D12(%rip),%rdi
  movsbl %al,%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D5: Enter character: 

tool: D12: Character entered: %i


assistant: ```c
int main() {
  char c;
  printf("Enter character: ");
  c = getchar();
  printf("Character entered: %i\n", c);
  putchar(c);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D2(%rip),%rdi
  movsbl %al,%ebp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string

tool: D10: Enter character: 

tool: D2: Character entered: %i


assistant: ```c
int main() {
  char c;
  printf("Enter character: ");
  c = getchar();
  printf("Character entered: %i\n", c);
  putchar(c);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x8,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L18
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: [ sum()] array size: %zu byte


assistant: ```c
int sum(int data[], int len) {
  printf("[ sum()] array size: %zu byte\n", sizeof(data));
  int res = *data;
  for (int *p = data + 1; p < data + len; p++)
    res += *p;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x8,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%edx
  lea    0x4(%rbx),%rax
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,4),%rcx
  cmp    %rcx,%rax
  jae    L10
L0:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jb     L0
L10:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: [ sum()] array size: %zu byte


assistant: ```c
int sum(int data[], int len) {
  printf("[ sum()] array size: %zu byte\n", sizeof(data));
  int res = *data;
  for (int *p = data + 1; p < data + len; p++)
    res += *p;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum>:
  endbr64
  push   %rbp
  movslq %esi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    0x4(%rbx),%rax
  lea    (%rbx,%rbp,4),%rdx
  mov    (%rbx),%r8d
  cmp    %rdx,%rax
  jae    L2
  nopl   0x0(%rax)
L1:
  add    (%rax),%r8d
  add    $0x4,%rax
  cmp    %rdx,%rax
  jb     L1
L2:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: [ sum()] array size: %zu byte


assistant: ```c
int sum(int data[], int len) {
  printf("[ sum()] array size: %zu byte\n", sizeof(data));
  int res = *data;
  for (int *p = data + 1; p < data + len; p++)
    res += *p;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  movslq %ebp,%rax
  lea    0x4(%rbx),%rdx
  mov    (%rbx),%r8d
  shl    $0x2,%rax
  lea    (%rbx,%rax,1),%rsi
  cmp    %rsi,%rdx
  jae    L24
  sub    $0x5,%rax
  mov    %rbx,%rdi
  mov    %rax,%rcx
  shr    $0x2,%rcx
  add    $0x1,%rcx
  cmp    $0xb,%rax
  jbe    L36
  mov    %rcx,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%rax
  shl    $0x4,%rax
  add    %rbx,%rax
  nopl   (%rax)
L37:
  movdqu 0x4(%rdi),%xmm2
  add    $0x10,%rdi
  paddd  %xmm2,%xmm0
  cmp    %rdi,%rax
  jne    L37
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%r8d
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rax
  lea    (%rdx,%rax,4),%rdx
  cmp    %rax,%rcx
  je     L24
L36:
  lea    0x4(%rdx),%rax
  add    (%rdx),%r8d
  cmp    %rax,%rsi
  jbe    L24
  lea    0x8(%rdx),%rax
  add    0x4(%rdx),%r8d
  cmp    %rax,%rsi
  jbe    L24
  add    0x8(%rdx),%r8d
L24:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: [ sum()] array size: %zu byte


assistant: ```c
int sum(int data[], int len) {
  printf("[ sum()] array size: %zu byte\n", sizeof(data));
  int res = *data;
  for (int *p = data + 1; p < data + len; p++)
    res += *p;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<show>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D3: vet = '%s'


tool: D8: x = %d

assistant: ```c
void show() {
  int x = 0;
  char vet[12];
  printf("vet = '%s'\n", vet);
  printf("x = %d", x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<show>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D4
type: string

tool: D17: vet = '%s'


tool: D4: x = %d

assistant: ```c
void show() {
  int x = 0;
  char vet[12];
  printf("vet = '%s'\n", vet);
  printf("x = %d", x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<show>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <printf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D12: vet = '%s'


tool: D18: x = %d

assistant: ```c
void show() {
  int x = 0;
  char vet[12];
  printf("vet = '%s'\n", vet);
  printf("x = %d", x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <printf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D17
type: string

tool: D12: vet = '%s'


tool: D17: x = %d

assistant: ```c
void show() {
  int x = 0;
  char vet[12];
  printf("vet = '%s'\n", vet);
  printf("x = %d", x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striteri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L13
  cmpq   $0x0,-0x18(%rbp)
  je     L13
  jmp    L36
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   *%rdx
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L13:
  nop
  leave
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (f)
    if (s)
      while (s[i]) {
        f(i, s + i);
        i++;
      }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L22
  cmpb   $0x0,(%rdi)
  je     L22
  mov    %rdi,%rsi
  mov    $0x0,%ebx
L3:
  mov    %ebx,%edi
  call   *%r12
  add    $0x1,%ebx
  mov    %ebx,%esi
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L3
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (f)
    if (s)
      while (s[i]) {
        f(i, s + i);
        i++;
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L36
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L18
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L18
  mov    %rdi,%rsi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %ebx,%edi
  call   *%r12
  lea    0x1(%rbx),%esi
  mov    %rsi,%rbx
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L32
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (f)
    if (s)
      while (s[i]) {
        f(i, s + i);
        i++;
      }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L39
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L39
  mov    %rdi,%rsi
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %ebx,%edi
  call   *%r12
  lea    0x1(%rbx),%esi
  mov    %rsi,%rbx
  add    %rbp,%rsi
  cmpb   $0x0,(%rsi)
  jne    L38
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  unsigned int i;
  i = 0;
  if (f)
    if (s)
      while (s[i]) {
        f(i, s + i);
        i++;
      }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: 9


assistant: ```c
void error(const char *msg) {
  printf("9\n");
  perror(msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: 9


assistant: ```c
void error(const char *msg) {
  printf("9\n");
  perror(msg);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: 9


assistant: ```c
void error(const char *msg) {
  printf("9\n");
  perror(msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: 9


assistant: ```c
void error(const char *msg) {
  printf("9\n");
  perror(msg);
  exit(1);
}
```