ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L12:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L47
L46:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L47:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L46
L32:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L3
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L27
L3:
  addq   $0x1,-0x28(%rbp)
L42:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    $0xffffffff,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  char *stmp, *ttmp;
  char *sf = s;
  for (; *s != '\0'; s++) {
    for (stmp = s, ttmp = t; *ttmp != '\0' && *stmp == *ttmp; stmp++, ttmp++)
      ;
    if (ttmp > t && *ttmp == '\0')
      return s - sf;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
  jmp    L64
L71:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  je     L13
L64:
  mov    %rsi,%r8
  mov    %rax,%rcx
  mov    %r9d,%edx
  test   %r9b,%r9b
  je     L71
L34:
  cmp    %dl,(%rcx)
  jne    L33
  add    $0x1,%rcx
  add    $0x1,%r8
  movzbl (%r8),%edx
  test   %dl,%dl
  jne    L34
L33:
  test   %dl,%dl
  jne    L71
  cmp    %r8,%rsi
  jae    L71
  sub    %edi,%eax
  ret
L37:
  mov    $0xffffffff,%eax
  ret
L13:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  char *stmp, *ttmp;
  char *sf = s;
  for (; *s != '\0'; s++) {
    for (stmp = s, ttmp = t; *ttmp != '\0' && *stmp == *ttmp; stmp++, ttmp++)
      ;
    if (ttmp > t && *ttmp == '\0')
      return s - sf;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L62
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
L66:
  mov    %rsi,%r8
  mov    %rax,%rcx
  mov    %r9d,%edx
  test   %r9b,%r9b
  jne    L55
  jmp    L35
L27:
  movzbl 0x1(%r8),%edx
  add    $0x1,%r8
  add    $0x1,%rcx
  test   %dl,%dl
  je     L52
L55:
  cmp    %dl,(%rcx)
  je     L27
L35:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L66
L62:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L52:
  cmp    %r8,%rsi
  jae    L35
  sub    %edi,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  char *stmp, *ttmp;
  char *sf = s;
  for (; *s != '\0'; s++) {
    for (stmp = s, ttmp = t; *ttmp != '\0' && *stmp == *ttmp; stmp++, ttmp++)
      ;
    if (ttmp > t && *ttmp == '\0')
      return s - sf;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strindex>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L50
  movzbl (%rsi),%r9d
  mov    %rdi,%rax
L12:
  mov    %rsi,%r8
  mov    %rax,%rcx
  mov    %r9d,%edx
  test   %r9b,%r9b
  jne    L17
  jmp    L13
L61:
  movzbl 0x1(%r8),%edx
  add    $0x1,%r8
  add    $0x1,%rcx
  test   %dl,%dl
  je     L38
L17:
  cmp    %dl,(%rcx)
  je     L61
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L12
L50:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L38:
  cmp    %r8,%rsi
  jae    L13
  sub    %edi,%eax
  ret
```

assistant: ```c
int strindex(char *s, char *t) {
  char *stmp, *ttmp;
  char *sf = s;
  for (; *s != '\0'; s++) {
    for (stmp = s, ttmp = t; *ttmp != '\0' && *stmp == *ttmp; stmp++, ttmp++)
      ;
    if (ttmp > t && *ttmp == '\0')
      return s - sf;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L44
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L44
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L44:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L2
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L2:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D30
datatype: string
name: disassemble_data
arguments: tag: D36
datatype: string

tool: D34: %d

tool: D30: yes


tool: D36: no


assistant: ```c
int main(void) {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0 && year % 100 != 0)
    printf("yes\n");
  else if (year % 400 == 0)
    printf("yes\n");
  else
    printf("no\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  jne    L44
  mov    $0x64,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L27
L44:
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%ecx
  jne    L12
  lea    D25(%rip),%rdi
  call   <printf@plt>
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L27:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L12:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D25
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D0: %d

tool: D25: yes


tool: D4: no


assistant: ```c
int main(void) {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0 && year % 100 != 0)
    printf("yes\n");
  else if (year % 400 == 0)
    printf("yes\n");
  else
    printf("no\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  jne    L7
  mov    %ecx,%eax
  mov    $0x64,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L34
L7:
  imul   $0xc28f5c29,%ecx,%ecx
  add    $0x51eb850,%ecx
  ror    $0x4,%ecx
  cmp    $0xa3d70a,%ecx
  ja     L37
L34:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D9
type: string

tool: D17: %d

tool: D4: yes


tool: D9: no


assistant: ```c
int main(void) {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0 && year % 100 != 0)
    printf("yes\n");
  else if (year % 400 == 0)
    printf("yes\n");
  else
    printf("no\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   $0x3,%cl
  jne    L35
  mov    %ecx,%eax
  mov    $0x64,%esi
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L19
L35:
  imul   $0xc28f5c29,%ecx,%ecx
  add    $0x51eb850,%ecx
  ror    $0x4,%ecx
  cmp    $0xa3d70a,%ecx
  ja     L13
L19:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D13
data_type: string
name: read_data
arguments: data_label: D10
data_type: string

tool: D16: %d

tool: D13: yes


tool: D10: no


assistant: ```c
int main(void) {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0 && year % 100 != 0)
    printf("yes\n");
  else if (year % 400 == 0)
    printf("yes\n");
  else
    printf("no\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L11:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L35
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <test@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L11
  jmp    L45
L35:
  nop
L45:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D2: f91(%d) = %d


tool: D9: %d

assistant: ```c
int main() {
  int i, ans;
  unsigned int n = 0;
  while (scanf("%d", &n)) {
    if (n == 0)
      break;
    ans = test(n);
    printf("f91(%d) = %d\n", n, ans);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  lea    D5(%rip),%rbx
  lea    D7(%rip),%r12
  jmp    L27
L6:
  call   <test@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
L27:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L36
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jne    L6
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D7
type: string

tool: D5: %d

tool: D7: f91(%d) = %d


assistant: ```c
int main() {
  int i, ans;
  unsigned int n = 0;
  while (scanf("%d", &n)) {
    if (n == 0)
      break;
    ans = test(n);
    printf("f91(%d) = %d\n", n, ans);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L5
  nopl   0x0(%rax)
L29:
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L0
  call   <test@plt>
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <printf@plt>
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L29
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: D13: f91(%d) = %d


tool: D9: %d

assistant: ```c
int main() {
  int i, ans;
  unsigned int n = 0;
  while (scanf("%d", &n)) {
    if (n == 0)
      break;
    ans = test(n);
    printf("f91(%d) = %d\n", n, ans);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  jmp    L20
  nopl   0x0(%rax)
L28:
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  je     L37
  call   <test@plt>
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <printf@plt>
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L28
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string

tool: D2: f91(%d) = %d


tool: D12: %d

assistant: ```c
int main() {
  int i, ans;
  unsigned int n = 0;
  while (scanf("%d", &n)) {
    if (n == 0)
      break;
    ans = test(n);
    printf("f91(%d) = %d\n", n, ans);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: False

assistant: ```c
int main() {
  if (sizeof(int) > -1) {
    printf("True");
  } else {
    printf("False");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: False

assistant: ```c
int main() {
  if (sizeof(int) > -1) {
    printf("True");
  } else {
    printf("False");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: False

assistant: ```c
int main() {
  if (sizeof(int) > -1) {
    printf("True");
  } else {
    printf("False");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: False

assistant: ```c
int main() {
  if (sizeof(int) > -1) {
    printf("True");
  } else {
    printf("False");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  jne    L15
  mov    -0x8(%rbp),%rax
  jmp    L32
L15:
  subq   $0x1,-0x8(%rbp)
L34:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L29
  mov    $0x0,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  const unsigned char *sp = (const unsigned char *)s + n - 1;
  while (n--) {
    if (*sp == (unsigned char)c)
      return (void *)sp;
    sp--;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memrchr>:
  endbr64
  lea    -0x1(%rdi,%rdx,1),%rax
  test   %rdx,%rdx
  je     L2
  sub    $0x1,%rdi
L22:
  cmp    %sil,(%rax)
  je     L6
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L22
  mov    $0x0,%eax
  ret
L2:
  mov    $0x0,%eax
L6:
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  const unsigned char *sp = (const unsigned char *)s + n - 1;
  while (n--) {
    if (*sp == (unsigned char)c)
      return (void *)sp;
    sp--;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memrchr>:
  endbr64
  lea    -0x1(%rdi,%rdx,1),%rax
  test   %rdx,%rdx
  je     L34
  sub    $0x1,%rdi
  jmp    L9
  nopl   0x0(%rax)
L13:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  je     L34
L9:
  cmp    %sil,(%rax)
  jne    L13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  const unsigned char *sp = (const unsigned char *)s + n - 1;
  while (n--) {
    if (*sp == (unsigned char)c)
      return (void *)sp;
    sp--;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memrchr>:
  endbr64
  lea    -0x1(%rdi,%rdx,1),%rax
  test   %rdx,%rdx
  je     L14
  sub    $0x1,%rdi
  jmp    L29
  nopl   0x0(%rax)
L10:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  je     L14
L29:
  cmp    %sil,(%rax)
  jne    L10
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  const unsigned char *sp = (const unsigned char *)s + n - 1;
  while (n--) {
    if (*sp == (unsigned char)c)
      return (void *)sp;
    sp--;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L33
L17:
  movl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L29
L38:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  subl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0x0,-0x4(%rbp)
  jg     L38
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L33:
  cmpl   $0xa,-0x8(%rbp)
  jle    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D2:   n      n!

tool: D9: ---- ---------

tool: D19:  %-2d   %-7d 


assistant: ```c
int main(void) {
  int curFac;
  printf("  n      n!\n");
  printf("---- ---------\n");
  for (int i = 1; i <= 10; i++) {
    curFac = 1;
    for (int j = i; j >= 1; j--) {
      curFac *= j;
    }
    printf(" %-2d   %-7d \n", i, curFac);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D7(%rip),%rbp
  jmp    L38
L7:
  imul   %eax,%edx
  sub    $0x1,%eax
  jne    L7
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  je     L44
L38:
  mov    %ebx,%eax
  mov    $0x1,%edx
  test   %ebx,%ebx
  jg     L7
  jmp    L5
L44:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D7
datatype: string

tool: D5:   n      n!

tool: D4: ---- ---------

tool: D7:  %-2d   %-7d 


assistant: ```c
int main(void) {
  int curFac;
  printf("  n      n!\n");
  printf("---- ---------\n");
  for (int i = 1; i <= 10; i++) {
    curFac = 1;
    for (int j = i; j >= 1; j--) {
      curFac *= j;
    }
    printf(" %-2d   %-7d \n", i, curFac);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  lea    D17(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L3:
  mov    %ebx,%eax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L11:
  imul   %eax,%edx
  sub    $0x1,%eax
  jne    L11
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D23
datatype: string

tool: D3:   n      n!

tool: D17:  %-2d   %-7d 


tool: D23: ---- ---------

assistant: ```c
int main(void) {
  int curFac;
  printf("  n      n!\n");
  printf("---- ---------\n");
  for (int i = 1; i <= 10; i++) {
    curFac = 1;
    for (int j = i; j >= 1; j--) {
      curFac *= j;
    }
    printf(" %-2d   %-7d \n", i, curFac);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  lea    D0(%rip),%r12
  push   %rbp
  mov    $0xfffffff7,%ebp
  push   %rbx
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0x1(%rax),%ebx
  test   %eax,%eax
  je     L69
  nopl   (%rax)
L26:
  mov    %eax,%edx
  mov    %eax,%ecx
  imul   %ebx,%edx
  sub    $0x1,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x2,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x3,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x4,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x5,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x6,%ecx
  je     L104
  imul   %ecx,%edx
  mov    %eax,%ecx
  sub    $0x7,%ecx
  je     L104
  imul   %ecx,%edx
  cmp    $0x8,%eax
  je     L104
  test   %ebp,%ebp
  je     L45
  imul   %ebp,%edx
L45:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    $0xa,%ebx
  je     L41
  mov    %ebx,%eax
L52:
  lea    0x1(%rax),%ebx
  test   %eax,%eax
  jne    L26
L69:
  mov    %ebx,%edx
  xchg   %ax,%ax
L104:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    %ebx,%eax
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L41:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string

tool: D6:   n      n!

tool: D0:  %-2d   %-7d 


tool: D13: ---- ---------

assistant: ```c
int main(void) {
  int curFac;
  printf("  n      n!\n");
  printf("---- ---------\n");
  for (int i = 1; i <= 10; i++) {
    curFac = 1;
    for (int j = i; j >= 1; j--) {
      curFac *= j;
    }
    printf(" %-2d   %-7d \n", i, curFac);
  }
  return 0;
}
```