ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<midi_mem_alloc>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *midi_mem_alloc(long nbytes, const char *file, int line) {
  void *p;
  assert(nbytes > 0);
  p = malloc(nbytes);
  assert(p != NULL);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<midi_mem_alloc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %r12,%r12
  setg   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *midi_mem_alloc(long nbytes, const char *file, int line) {
  void *p;
  assert(nbytes > 0);
  p = malloc(nbytes);
  assert(p != NULL);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<midi_mem_alloc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %r12,%r12
  setg   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *midi_mem_alloc(long nbytes, const char *file, int line) {
  void *p;
  assert(nbytes > 0);
  p = malloc(nbytes);
  assert(p != NULL);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cgen_ifelse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <print_instr@plt>
  mov    -0x74(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <print_instr@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D15
data_type: string

tool: D11: li $t0 0

tool: D15: beq $a0 $t0 ELSE%d

assistant: ```c
void cgen_ifelse(int num) {
  print_instr("li $t0 0");
  char str[100];
  sprintf(str, "beq $a0 $t0 ELSE%d", num);
  print_instr(str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cgen_ifelse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <print_instr@plt>
  mov    %rsp,%rbp
  mov    %ebx,%edx
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <print_instr@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D18
data_type: string

tool: D10: li $t0 0

tool: D18: beq $a0 $t0 ELSE%d

assistant: ```c
void cgen_ifelse(int num) {
  print_instr("li $t0 0");
  char str[100];
  sprintf(str, "beq $a0 $t0 ELSE%d", num);
  print_instr(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cgen_ifelse>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D16(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <print_instr@plt>
  mov    %rbp,%rdi
  mov    %r12d,%edx
  lea    D10(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <print_instr@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D16: li $t0 0

tool: D10: beq $a0 $t0 ELSE%d

assistant: ```c
void cgen_ifelse(int num) {
  print_instr("li $t0 0");
  char str[100];
  sprintf(str, "beq $a0 $t0 ELSE%d", num);
  print_instr(str);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cgen_ifelse>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D4(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <print_instr@plt>
  mov    %rbp,%rdi
  mov    %r12d,%edx
  lea    D12(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <print_instr@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D4: li $t0 0

tool: D12: beq $a0 $t0 ELSE%d

assistant: ```c
void cgen_ifelse(int num) {
  print_instr("li $t0 0");
  char str[100];
  sprintf(str, "beq $a0 $t0 ELSE%d", num);
  print_instr(str);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uioPrintChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0xa,%eax
  je     L46
  cmp    $0x7f,%eax
  je     L40
  jmp    L3
L46:
  mov    $0x0,%eax
  call   <scrBreakLine@plt>
  jmp    L32
L40:
  mov    $0x0,%eax
  call   <scrDelete@plt>
  jmp    L32
L3:
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <scrPutGlyph@plt>
  nop
L32:
  nop
  leave
  ret
```

assistant: ```c
void uioPrintChar(const char c) {
  switch (c) {
  case '\n':
    scrBreakLine();
    break;
  case 0x7F:
    scrDelete();
    break;
  default:
    scrPutGlyph(c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uioPrintChar>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xa,%dil
  je     L19
  cmp    $0x7f,%dil
  je     L6
  movsbl %dil,%edi
  call   <scrPutGlyph@plt>
  jmp    L15
L19:
  mov    $0x0,%eax
  call   <scrBreakLine@plt>
L15:
  add    $0x8,%rsp
  ret
L6:
  mov    $0x0,%eax
  call   <scrDelete@plt>
  jmp    L15
```

assistant: ```c
void uioPrintChar(const char c) {
  switch (c) {
  case '\n':
    scrBreakLine();
    break;
  case 0x7F:
    scrDelete();
    break;
  default:
    scrPutGlyph(c);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uioPrintChar>:
  endbr64
  cmp    $0xa,%dil
  je     L11
  cmp    $0x7f,%dil
  je     L19
  movsbl %dil,%edi
  jmp    1070 <scrPutGlyph@plt>
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  jmp    1090 <scrBreakLine@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  jmp    1080 <scrDelete@plt>
```

assistant: ```c
void uioPrintChar(const char c) {
  switch (c) {
  case '\n':
    scrBreakLine();
    break;
  case 0x7F:
    scrDelete();
    break;
  default:
    scrPutGlyph(c);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uioPrintChar>:
  endbr64
  cmp    $0xa,%dil
  je     L12
  cmp    $0x7f,%dil
  je     L10
  movsbl %dil,%edi
  jmp    1070 <scrPutGlyph@plt>
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  jmp    1090 <scrBreakLine@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  jmp    1080 <scrDelete@plt>
```

assistant: ```c
void uioPrintChar(const char c) {
  switch (c) {
  case '\n':
    scrBreakLine();
    break;
  case 0x7F:
    scrDelete();
    break;
  default:
    scrPutGlyph(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<math_vector_subtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L59
  cmpq   $0x0,-0x20(%rbp)
  je     L59
  cmpq   $0x0,-0x30(%rbp)
  je     L59
  mov    $0x1,%eax
  jmp    L45
L59:
  mov    $0x0,%eax
L45:
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L35
L41:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L41
  nop
  nop
  leave
  ret
```

assistant: ```c
void math_vector_subtract(const double *vec_i, const double *vec_j, size_t size, double *result) {
  assert(vec_i && vec_j && result);
  for (size_t i = 0; i != size; ++i) {
    result[i] = vec_i[i] - vec_j[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<math_vector_subtract>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  test   %rsi,%rsi
  setne  %al
  test   %rcx,%rcx
  setne  %dl
  and    %edx,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L12
  mov    $0x0,%eax
L4:
  movsd  (%rbx,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,0x0(%r13,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L4
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void math_vector_subtract(const double *vec_i, const double *vec_j, size_t size, double *result) {
  assert(vec_i && vec_j && result);
  for (size_t i = 0; i != size; ++i) {
    result[i] = vec_i[i] - vec_j[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<math_vector_subtract>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %al
  test   %rcx,%rcx
  setne  %dl
  and    %edx,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %r12,%r12
  je     L1
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  movsd  (%rbx,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,0x0(%r13,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L8
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void math_vector_subtract(const double *vec_i, const double *vec_j, size_t size, double *result) {
  assert(vec_i && vec_j && result);
  for (size_t i = 0; i != size; ++i) {
    result[i] = vec_i[i] - vec_j[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<math_vector_subtract>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %al
  test   %rcx,%rcx
  setne  %dl
  and    %edx,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %r13,%r13
  je     L31
  lea    0x8(%rbp),%rax
  cmp    %rax,%rbx
  lea    -0x1(%r13),%rax
  setne  %dl
  cmp    $0x1,%rax
  seta   %al
  test   %al,%dl
  je     L30
  lea    0x8(%r12),%rax
  cmp    %rax,%rbx
  je     L30
  mov    %r13,%rdx
  xor    %eax,%eax
  shr    %rdx
  shl    $0x4,%rdx
  xchg   %ax,%ax
L13:
  movupd (%r12,%rax,1),%xmm0
  movupd 0x0(%rbp,%rax,1),%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L13
  mov    %r13,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%r13d
  je     L31
  movsd  (%r12,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  movsd  (%r12,%rax,8),%xmm0
  subsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void math_vector_subtract(const double *vec_i, const double *vec_j, size_t size, double *result) {
  assert(vec_i && vec_j && result);
  for (size_t i = 0; i != size; ++i) {
    result[i] = vec_i[i] - vec_j[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L7:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <test@plt>
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int bits = sizeof(int) * CHAR_BIT;
  int i;
  for (i = 0; i < bits; i++)
    test(i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%ebp
  shl    $0x2,%ebp
  test   %ebp,%ebp
  jle    L9
  mov    $0x0,%ebx
L10:
  mov    %ebx,%edi
  call   <test@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L10
L9:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int bits = sizeof(int) * CHAR_BIT;
  int i;
  for (i = 0; i < bits; i++)
    test(i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%ebp
  shl    $0x2,%ebp
  test   %ebp,%ebp
  jle    L2
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L16:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <test@plt>
  cmp    %ebx,%ebp
  jne    L16
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int bits = sizeof(int) * CHAR_BIT;
  int i;
  for (i = 0; i < bits; i++)
    test(i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%ebp
  shl    $0x2,%ebp
  test   %ebp,%ebp
  jle    L17
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <test@plt>
  cmp    %ebx,%ebp
  jne    L8
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int bits = sizeof(int) * CHAR_BIT;
  int i;
  for (i = 0; i < bits; i++)
    test(i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x9f65fb16,%eax,%eax
  sub    $0x1a4602e4,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L4:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  add    $0x2,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L2:
  cmpl   $0x0,-0x10(%rbp)
  je     L4
  mov    -0xc(%rbp),%eax
  imul   $0x3e7313eb,%eax,%eax
  lea    -0x2345799a(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] * 1047729131UL + 3703211622U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  imul   $0x9f65fb16,(%rdi),%eax
  sub    $0x1a4602e4,%eax
  rol    $0x10,%eax
  imul   $0x3e7313eb,%eax,%eax
  sub    $0x2345799a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] * 1047729131UL + 3703211622U;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  imul   $0x3221f32,(%rdi),%eax
  add    $0x7d2f31a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] * 1047729131UL + 3703211622U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  imul   $0x3221f32,(%rdi),%eax
  add    $0x7d2f31a,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 2674260758U;
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
      *((unsigned short *)(&state[local1]) + 0) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] * 1047729131UL + 3703211622U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <randomLong@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: %ld


assistant: ```c
int main() {
  printf("%ld\n", randomLong());
  return 9;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <randomLong@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: %ld


assistant: ```c
int main() {
  printf("%ld\n", randomLong());
  return 9;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <randomLong@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %ld


assistant: ```c
int main() {
  printf("%ld\n", randomLong());
  return 9;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <randomLong@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x9,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %ld


assistant: ```c
int main() {
  printf("%ld\n", randomLong());
  return 9;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_array_i32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L18:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jae    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2c,%edi
  call   <fputc@plt>
L8:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: %d

assistant: ```c
void write_array_i32(FILE *f, const int *x, const unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    fprintf(f, "%d", x[i]);
    if (i < len - 1) {
      fprintf(f, ",");
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_array_i32>:
  endbr64
  test   %edx,%edx
  je     L9
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  lea    -0x1(%rdx),%r14d
  mov    %edx,%ebp
  mov    $0x0,%ebx
  lea    D4(%rip),%r15
  jmp    L32
L27:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L16
L32:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  cmp    %ebx,%r14d
  jbe    L27
  mov    %r12,%rsi
  mov    $0x2c,%edi
  call   <fputc@plt>
  jmp    L27
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %d

assistant: ```c
void write_array_i32(FILE *f, const int *x, const unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    fprintf(f, "%d", x[i]);
    if (i < len - 1) {
      fprintf(f, ",");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_array_i32>:
  endbr64
  test   %edx,%edx
  je     L49
  push   %r15
  lea    -0x1(%rdx),%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L17
  xchg   %ax,%ax
L22:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L15
L17:
  mov    (%r12,%rbx,4),%edx
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  cmp    %ebx,%r15d
  jbe    L22
  mov    %rbp,%rsi
  mov    $0x2c,%edi
  add    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r14,%rbx
  jne    L17
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L49:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: %d

assistant: ```c
void write_array_i32(FILE *f, const int *x, const unsigned int len) {
  unsigned int i;
  for (i = 0; i < len; i++) {
    fprintf(f, "%d", x[i]);
    if (i < len - 1) {
      fprintf(f, ",");
    }
  }
}
```