user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%r13
  jmp    L26
L105:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L66
  orq    $0x0,-0x8(%rsp,%rax,1)
L66:
  mov    %rsp,%r14
  lea    0xf(,%rdx,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L111:
  cmp    %rdx,%rsp
  je     L90
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L111
L90:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L118
  orq    $0x0,-0x8(%rsp,%rax,1)
L118:
  mov    %rsp,%r15
  test   %rcx,%rcx
  je     L97
  mov    %r14,%r12
  mov    $0x0,%ebx
L28:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  add    $0x4,%r12
  cmp    %rbx,-0x48(%rbp)
  ja     L28
L97:
  mov    -0x40(%rbp),%rcx
  test   %rcx,%rcx
  je     L29
  mov    %r15,%r12
  mov    $0x0,%ebx
L104:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  mov    -0x40(%rbp),%rcx
  add    $0x4,%r12
  cmp    %rbx,%rcx
  ja     L104
L29:
  mov    %r15,%rdx
  mov    -0x48(%rbp),%rsi
  mov    %r14,%rdi
  call   <merge@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%rsi
  add    -0x48(%rbp),%rsi
  mov    %r14,%rdi
  call   <print_arr@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    -0x58(%rbp),%rsp
L26:
  lea    -0x40(%rbp),%rdx
  lea    -0x48(%rbp),%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L79
  mov    %rsp,-0x58(%rbp)
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rsi
  sub    %rax,%rsi
L110:
  cmp    %rsi,%rsp
  je     L105
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L110
L79:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D39
type_infered: string

tool: D12: Enter A's size, followed by B's size, followed by the elements of A and then the elements of B.


tool: D34: %d

tool: D1: Merged:


tool: D11: 


tool: D39: %zu%zu

assistant: ```c
int main(void) {
  printf("Enter A's size, followed by B's size, followed by the elements of A and then "
         "the elements of B.\n");
  size_t a_sz, b_sz;
  while (scanf("%zu%zu", &a_sz, &b_sz) == 2) {
    int A[a_sz + b_sz];
    int B[b_sz];
    size_t i;
    for (i = 0; i < a_sz; i++) {
      scanf("%d", &A[i]);
    }
    for (i = 0; i < b_sz; i++) {
      scanf("%d", &B[i]);
    }
    merge(A, a_sz, B, b_sz);
    printf("Merged:\n");
    print_arr(A, a_sz + b_sz);
    printf("\n");
  }
  return 0;
}
```