ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jg     L26
  lea    D49(%rip),%rdi
  call   <puts@plt>
L34:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edi,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L3
  lea    -0x1(%rbx),%edx
  mov    $0x2,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rbx
  mov    -0x8(%rbp,%rbx,8),%rdx
  mov    0x10(%rbp),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L3:
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rbp),%rdx
  mov    0x10(%rbp),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: parse_data
arguments: data_label: D49
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string

tool: D49: 
Not enough arguments


tool: D21: 
So you had %d arguments



tool: D30: I shall now work on %d and %d arguments..


tool: D37: That being %s and %s

tool: D2: I shall now work on %d and %d arguments..

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc <= 2)
    puts("\nNot enough arguments\n");
  else {
    printf("\nSo you had %d arguments\n\n", argc);
    if (argc == 3 || argc == 4) {
      printf("I shall now work on %d and %d arguments..", 2, 3);
      printf("That being %s and %s", argv[2], argv[3]);
    } else {
      printf("I shall now work on %d and %d arguments..\n", 2, argc - 1);
      printf("That being %s and %s", argv[2], argv[argc - 1]);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%ebx
  jg     L9
  lea    D8(%rip),%rdi
  call   <puts@plt>
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rsi,%rbp
  lea    D47(%rip),%rdi
  mov    %ebx,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x3(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L12
  lea    -0x1(%rbx),%edx
  mov    $0x2,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x8(%rbp,%rbx,8),%rdx
  mov    0x10(%rbp),%rsi
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L12:
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rbp),%rdx
  mov    0x10(%rbp),%rsi
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D47
type_guessed: string
name: disassemble_data
arguments: tag: D49
type_guessed: string
name: disassemble_data
arguments: tag: D58
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string

tool: D8: 
Not enough arguments


tool: D47: 
So you had %d arguments



tool: D49: I shall now work on %d and %d arguments..


tool: D58: That being %s and %s

tool: D21: I shall now work on %d and %d arguments..

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc <= 2)
    puts("\nNot enough arguments\n");
  else {
    printf("\nSo you had %d arguments\n\n", argc);
    if (argc == 3 || argc == 4) {
      printf("I shall now work on %d and %d arguments..", 2, 3);
      printf("That being %s and %s", argv[2], argv[3]);
    } else {
      printf("I shall now work on %d and %d arguments..\n", 2, argc - 1);
      printf("That being %s and %s", argv[2], argv[argc - 1]);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%ebx
  jg     L16
  lea    D34(%rip),%rdi
  call   <puts@plt>
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rsi,%rbp
  lea    D10(%rip),%rdi
  mov    %ebx,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x3(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L0
  lea    -0x1(%rbx),%edx
  mov    $0x2,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x8(%rbp,%rbx,8),%rdx
  mov    0x10(%rbp),%rsi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L0:
  mov    $0x3,%edx
  mov    $0x2,%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rbp),%rdx
  mov    0x10(%rbp),%rsi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L26
```

tool_calls: name: unpack_data
arguments: label: D34
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D11
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D38
data_type: string

tool: D34: 
Not enough arguments


tool: D10: 
So you had %d arguments



tool: D11: I shall now work on %d and %d arguments..


tool: D12: That being %s and %s

tool: D38: I shall now work on %d and %d arguments..

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc <= 2)
    puts("\nNot enough arguments\n");
  else {
    printf("\nSo you had %d arguments\n\n", argc);
    if (argc == 3 || argc == 4) {
      printf("I shall now work on %d and %d arguments..", 2, 3);
      printf("That being %s and %s", argv[2], argv[3]);
    } else {
      printf("I shall now work on %d and %d arguments..\n", 2, argc - 1);
      printf("That being %s and %s", argv[2], argv[argc - 1]);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mocksuspend_acquire_wake_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D0: mocksuspend acquire wake lock %s


assistant: ```c
int mocksuspend_acquire_wake_lock(const char *name) {
  printf("mocksuspend acquire wake lock %s\n", name);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mocksuspend_acquire_wake_lock>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: mocksuspend acquire wake lock %s


assistant: ```c
int mocksuspend_acquire_wake_lock(const char *name) {
  printf("mocksuspend acquire wake lock %s\n", name);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mocksuspend_acquire_wake_lock>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D3: mocksuspend acquire wake lock %s


assistant: ```c
int mocksuspend_acquire_wake_lock(const char *name) {
  printf("mocksuspend acquire wake lock %s\n", name);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mocksuspend_acquire_wake_lock>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: mocksuspend acquire wake lock %s


assistant: ```c
int mocksuspend_acquire_wake_lock(const char *name) {
  printf("mocksuspend acquire wake lock %s\n", name);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f15>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc4(%rbp),%edx
  mov    -0xb4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <f15_1@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void f15(int i, ...) {
  va_list ap;
  va_start(ap, i);
  f15_1(ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<f15>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edi
  call   <f15_1@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  pop    %rbx
  ret
```

assistant: ```c
void f15(int i, ...) {
  va_list ap;
  va_start(ap, i);
  f15_1(ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f15>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <f15_1@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void f15(int i, ...) {
  va_list ap;
  va_start(ap, i);
  f15_1(ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f15>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <f15_1@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void f15(int i, ...) {
  va_list ap;
  va_start(ap, i);
  f15_1(ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  jmp    L3
L13:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *cs, int c) {
  const char *s;
  s = cs;
  while (*s) {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
L19:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L2
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
  mov    $0x0,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
L2:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *cs, int c) {
  const char *s;
  s = cs;
  while (*s) {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    %esi,%edx
  je     L27
  add    $0x1,%rdi
L7:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *cs, int c) {
  const char *s;
  s = cs;
  while (*s) {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<strchr>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    %esi,%edx
  je     L28
  add    $0x1,%rdi
L10:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *cs, int c) {
  const char *s;
  s = cs;
  while (*s) {
    if (*s == c)
      return (char *)s;
    s++;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  sub    $0x17447d68,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L39
  mov    %rsp,%rdx
  mov    $0x0,%esi
L5:
  mov    (%rsp),%rax
  cmp    %rsi,%rax
  jbe    L30
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %rax,%r9
  ror    %cl,%r9
  mov    %r9,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
  mov    %rax,(%rsp)
  movzwl 0x2(%rdx),%eax
  movzwl (%rdx),%ecx
  mov    %cx,0x2(%rdx)
  movzwl 0x4(%rdx),%ecx
  mov    %cx,(%rdx)
  mov    %ax,0x4(%rdx)
L18:
  add    $0x1,%rsi
  add    $0x8,%rdx
  cmp    %rdi,%rsi
  jne    L5
L39:
  mov    (%rsp),%rax
  ror    $0xd,%rax
  movabs $0x7d1b73ebade7c1b,%rdx
  add    %rdx,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  ret
L30:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  lea    0x0(,%rax,8),%rcx
  and    $0x3c,%ecx
  or     %rcx,%rax
  mov    %rax,(%rsp)
  jmp    L18
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 13UL) | (state[0UL] << 51UL)) + 563432908449020955UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  sub    $0x17447d68,%rax
  test   %rdi,%rdi
  je     L9
  xor    %edx,%edx
L37:
  cmp    %rax,%rdx
  jae    L10
  mov    %eax,%ecx
  mov    %rax,%r8
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%r8
  mov    %r8,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
L32:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L37
L9:
  movabs $0x7d1b73ebade7c1b,%rdx
  ror    $0xd,%rax
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
  nopl   0x0(%rax)
L10:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  lea    0x0(,%rax,8),%rcx
  and    $0x3c,%ecx
  or     %rcx,%rax
  jmp    L32
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 13UL) | (state[0UL] << 51UL)) + 563432908449020955UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rdx
  mov    0x8(%rdi),%rsi
  sub    $0x17447d68,%rax
  test   %rsi,%rsi
  je     L17
  test   %rax,%rax
  je     L89
  mov    %eax,%ecx
  mov    %rax,%rdi
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rdi
  mov    %rdi,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
  cmp    $0x1,%rsi
  je     L17
  cmp    $0x1,%rax
  je     L65
  mov    %eax,%ecx
  mov    %rax,%rdi
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rdi
  mov    %rdi,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
L90:
  cmp    $0x2,%rsi
  jbe    L17
  mov    $0x2,%edi
L48:
  cmp    %rdi,%rax
  jbe    L92
  mov    %eax,%ecx
  mov    %rax,%r8
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%r8
  mov    %r8,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
L98:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L48
L17:
  movabs $0x7d1b73ebade7c1b,%rcx
  ror    $0xd,%rax
  add    %rcx,%rax
  mov    %rax,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  cmp    $0x1,%rsi
  je     L17
L65:
  rol    %rax
  lea    0x0(,%rax,8),%rcx
  and    $0x3c,%ecx
  or     %rcx,%rax
  jmp    L90
  nopl   0x0(%rax)
L92:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  rol    %cl,%rax
  lea    0x0(,%rax,8),%rcx
  and    $0x3c,%ecx
  or     %rcx,%rax
  jmp    L98
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & 15UL) | 1UL)) | (state[local1] << (64 - ((state[local1] & 15UL) | 1UL)))) & 63UL) << 4UL;
        copy11 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy11;
        copy11 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 2);
        *((unsigned short *)(&state[local1]) + 2) = copy11;
      } else {
        state[0UL] = (state[0UL] << (((state[0UL] >> 2UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 2UL) & 15UL) | 1UL)));
        state[0UL] |= ((state[0UL] + state[local1]) & 15UL) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> 13UL) | (state[0UL] << 51UL)) + 563432908449020955UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<compar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%r12
  jmp    L32
L25:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    $0x0,%eax
  jmp    L18
L32:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%edx
  movzbl (%r12),%eax
  cmp    %al,%dl
  je     L25
  sub    $0x1,%rbx
  movzbl (%rbx),%eax
  movsbl %al,%eax
  movzbl (%r12),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
L18:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
compar(as1, as2) char *as1, *as2;
{
  register char *s1, *s2;
  s1 = as1;
  s2 = as2;
  while (*s1++ == *s2)
    if (*s2++ == 0)
      return (0);
  return (*--s1 - *s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compar>:
  endbr64
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  cmp    %dl,%cl
  jne    L1
  add    $0x1,%rax
  test   %dl,%dl
  jne    L2
  mov    $0x0,%eax
  ret
L1:
  movsbl %cl,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
compar(as1, as2) char *as1, *as2;
{
  register char *s1, *s2;
  s1 = as1;
  s2 = as2;
  while (*s1++ == *s2)
    if (*s2++ == 0)
      return (0);
  return (*--s1 - *s2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compar>:
  endbr64
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  test   %dl,%dl
  je     L7
L14:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L6
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
compar(as1, as2) char *as1, *as2;
{
  register char *s1, *s2;
  s1 = as1;
  s2 = as2;
  while (*s1++ == *s2)
    if (*s2++ == 0)
      return (0);
  return (*--s1 - *s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compar>:
  endbr64
  xor    %eax,%eax
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x1,%rax
  test   %dl,%dl
  je     L8
L20:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L24
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
compar(as1, as2) char *as1, *as2;
{
  register char *s1, *s2;
  s1 = as1;
  s2 = as2;
  while (*s1++ == *s2)
    if (*s2++ == 0)
      return (0);
  return (*--s1 - *s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition_test_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdi),%edi
  movslq %edi,%rdi
  lea    0x0(,%rdi,4),%r15
  imul   %rdi,%rdi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x1,%edx
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <partition_dbl_restr_numbers@plt>
  lea    0xb(%r15),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L45:
  cmp    %rdx,%rsp
  je     L49
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L49:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L83
  orq    $0x0,-0x8(%rsp,%rax,1)
L83:
  mov    %rsp,%r14
  shr    $0x2,%r15
  lea    0x1(%r15),%rax
  movslq %r13d,%rdx
  imul   %rdx,%rax
  cmpl   $0x0,(%r12,%rax,4)
  jle    L13
  mov    $0x0,%ebx
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  add    $0x1,%r15
  imul   %rdx,%r15
  jmp    L65
L30:
  add    $0x1,%ebx
  cmp    %ebx,(%r12,%r15,4)
  jle    L13
L65:
  mov    -0x48(%rbp),%r9
  mov    %r14,%r8
  mov    %ebx,%ecx
  mov    $0x1,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <partition_restr_from_id@plt>
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <partition_to_id@plt>
  cmp    %ebx,%eax
  je     L30
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L30
L13:
  mov    %r12,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: There was an error on id %d.


assistant: ```c
void partition_test_id(int n) {
  int(*p)[n + 1][n + 1] = malloc(((n + 1) * (n + 1) * sizeof(int)));
  partition_dbl_restr_numbers(p, n, 1);
  int part[n], num_part;
  int i;
  for (i = 0; i < (*p)[n][n]; i++) {
    partition_restr_from_id(p, n, 1, i, part, &num_part);
    int res = partition_to_id(p, n, part);
    if (res != i) {
      printf("There was an error on id %d.\n", i);
    }
  }
  free(p);
}
```