ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rcps_check>:
  endbr64
  push   %rbx
  call   <check_dependencies@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <rcps_error@plt>
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: rcps_check: result='%s'


assistant: ```c
int rcps_check(struct rcps_problem *p) {
  int result = 0;
  result = check_dependencies(p);
  printf("rcps_check: result='%s'\n", rcps_error(result));
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rcps_check>:
  endbr64
  push   %r12
  call   <check_dependencies@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <rcps_error@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: rcps_check: result='%s'


assistant: ```c
int rcps_check(struct rcps_problem *p) {
  int result = 0;
  result = check_dependencies(p);
  printf("rcps_check: result='%s'\n", rcps_error(result));
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rcps_check>:
  endbr64
  push   %r12
  call   <check_dependencies@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <rcps_error@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: rcps_check: result='%s'


assistant: ```c
int rcps_check(struct rcps_problem *p) {
  int result = 0;
  result = check_dependencies(p);
  printf("rcps_check: result='%s'\n", rcps_error(result));
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xc,-0x8(%rbp)
  movl   $0xb,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swap@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int girls = 12;
  int boys = 11;
  swap(girls, boys);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  mov    $0xc,%edi
  call   <swap@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int girls = 12;
  int boys = 11;
  swap(girls, boys);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  mov    $0xc,%edi
  call   <swap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int girls = 12;
  int boys = 11;
  swap(girls, boys);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%esi
  mov    $0xc,%edi
  call   <swap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int girls = 12;
  int boys = 11;
  swap(girls, boys);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <chomp@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rtrim@plt>
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  char *string;
  string = chomp(str);
  string = ltrim(string);
  return rtrim(string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trim>:
  endbr64
  sub    $0x8,%rsp
  call   <chomp@plt>
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %rax,%rdi
  call   <rtrim@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *trim(char *str) {
  char *string;
  string = chomp(str);
  string = ltrim(string);
  return rtrim(string);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim>:
  endbr64
  sub    $0x8,%rsp
  call   <chomp@plt>
  mov    %rax,%rdi
  call   <ltrim@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <rtrim@plt>
```

assistant: ```c
char *trim(char *str) {
  char *string;
  string = chomp(str);
  string = ltrim(string);
  return rtrim(string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trim>:
  endbr64
  sub    $0x8,%rsp
  call   <chomp@plt>
  mov    %rax,%rdi
  call   <ltrim@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1080 <rtrim@plt>
```

assistant: ```c
char *trim(char *str) {
  char *string;
  string = chomp(str);
  string = ltrim(string);
  return rtrim(string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Simon_Decrypt_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  movl   $0x10,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  jmp    L16
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %eax,%edi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %edi,%eax
  and    %eax,%esi
  mov    %esi,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  xor    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,4),%edi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %edi,%eax
  xor    %esi,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  subq   $0x1,-0x20(%rbp)
L16:
  cmpq   $0x0,-0x20(%rbp)
  jns    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Simon_Decrypt_32(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 16;
  uint16_t *x_word = (uint16_t *)plaintext;
  uint16_t *y_word = ((uint16_t *)plaintext) + 1;
  uint16_t *round_key_ptr = (uint16_t *)key_schedule;
  *x_word = *(uint16_t *)ciphertext;
  *y_word = *(((uint16_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint16_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Simon_Decrypt_32>:
  endbr64
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    (%rdx),%eax
  mov    %eax,(%rcx)
  mov    0x4(%rdx),%eax
  mov    %eax,0x4(%rcx)
  lea    -0x1(%rdi),%esi
  movslq %esi,%rsi
  test   %rsi,%rsi
  js     L5
L7:
  mov    (%r8),%edx
  lea    (%rdx,%rdx,1),%eax
  mov    %edx,%ecx
  sar    $0xf,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  shl    $0x8,%ecx
  mov    %edx,%edi
  sar    $0x8,%edi
  or     %edi,%ecx
  and    %ecx,%eax
  lea    0x0(,%rdx,4),%ecx
  mov    %edx,%edi
  sar    $0xe,%edi
  or     %edi,%ecx
  xor    0x4(%r8),%ecx
  xor    %ecx,%eax
  mov    %edx,0x4(%r8)
  xor    (%r9,%rsi,4),%eax
  mov    %eax,(%r8)
  sub    $0x1,%rsi
  cmp    $0xffffffffffffffff,%rsi
  jne    L7
L5:
  ret
```

assistant: ```c
void Simon_Decrypt_32(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 16;
  uint16_t *x_word = (uint16_t *)plaintext;
  uint16_t *y_word = ((uint16_t *)plaintext) + 1;
  uint16_t *round_key_ptr = (uint16_t *)key_schedule;
  *x_word = *(uint16_t *)ciphertext;
  *y_word = *(((uint16_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint16_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Simon_Decrypt_32>:
  endbr64
  mov    %rcx,%r9
  mov    (%rdx),%ecx
  sub    $0x1,%edi
  mov    %rsi,%r8
  movslq %edi,%rsi
  mov    %ecx,(%r9)
  mov    0x4(%rdx),%r10d
  mov    %r10d,0x4(%r9)
  jns    L12
  jmp    L10
  nopl   0x0(%rax)
L14:
  mov    %eax,%ecx
L12:
  mov    %ecx,%edx
  lea    (%rcx,%rcx,1),%eax
  mov    %ecx,%edi
  mov    %ecx,0x4(%r9)
  sar    $0xf,%edx
  sar    $0x8,%edi
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  mov    %ecx,%edi
  and    %edx,%eax
  sar    $0xe,%edi
  lea    0x0(,%rcx,4),%edx
  or     %edi,%edx
  xor    (%r8,%rsi,4),%edx
  sub    $0x1,%rsi
  xor    %edx,%eax
  xor    %r10d,%eax
  mov    %ecx,%r10d
  mov    %eax,(%r9)
  cmp    $0xffffffffffffffff,%rsi
  jne    L14
  ret
  xchg   %ax,%ax
L10:
  ret
```

assistant: ```c
void Simon_Decrypt_32(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 16;
  uint16_t *x_word = (uint16_t *)plaintext;
  uint16_t *y_word = ((uint16_t *)plaintext) + 1;
  uint16_t *round_key_ptr = (uint16_t *)key_schedule;
  *x_word = *(uint16_t *)ciphertext;
  *y_word = *(((uint16_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint16_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Simon_Decrypt_32>:
  endbr64
  mov    %rcx,%r9
  mov    (%rdx),%ecx
  sub    $0x1,%edi
  mov    %rsi,%r8
  movslq %edi,%rsi
  mov    %ecx,(%r9)
  mov    0x4(%rdx),%r10d
  mov    %r10d,0x4(%r9)
  jns    L17
  jmp    L27
  nopl   0x0(%rax)
L18:
  mov    %eax,%ecx
L17:
  mov    %ecx,%edx
  lea    (%rcx,%rcx,1),%eax
  mov    %ecx,%edi
  mov    %ecx,0x4(%r9)
  sar    $0xf,%edx
  sar    $0x8,%edi
  or     %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  mov    %ecx,%edi
  and    %edx,%eax
  sar    $0xe,%edi
  lea    0x0(,%rcx,4),%edx
  or     %edi,%edx
  xor    (%r8,%rsi,4),%edx
  sub    $0x1,%rsi
  xor    %edx,%eax
  xor    %r10d,%eax
  mov    %ecx,%r10d
  mov    %eax,(%r9)
  cmp    $0xffffffffffffffff,%rsi
  jne    L18
  ret
  xchg   %ax,%ax
L27:
  ret
```

assistant: ```c
void Simon_Decrypt_32(const uint8_t round_limit, const uint8_t *key_schedule, const uint8_t *ciphertext, uint8_t *plaintext) {
  const uint8_t word_size = 16;
  uint16_t *x_word = (uint16_t *)plaintext;
  uint16_t *y_word = ((uint16_t *)plaintext) + 1;
  uint16_t *round_key_ptr = (uint16_t *)key_schedule;
  *x_word = *(uint16_t *)ciphertext;
  *y_word = *(((uint16_t *)ciphertext) + 1);
  for (int8_t i = round_limit - 1; i >= 0; i--) {
    uint16_t temp = ((((*x_word) << 1) | ((*x_word) >> (word_size - 1))) & (((*x_word) << 8) | ((*x_word) >> (word_size - 8)))) ^ *y_word ^ (((*x_word) << 2) | ((*x_word) >> (word_size - 2)));
    *y_word = *x_word;
    *x_word = temp ^ *(round_key_ptr + i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L19
L11:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  jmp    L23
L34:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L23:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcat_(char *s, char *t) {
  while (*s != '\0') {
    s++;
  }
  while (*t != '\0') {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat_>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L15
L11:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L11
L15:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L20
L39:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L39
L20:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void strcat_(char *s, char *t) {
  while (*s != '\0') {
    s++;
  }
  while (*t != '\0') {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcat_>:
  endbr64
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%rdi
L27:
  cmpb   $0x0,(%rdi)
  jne    L29
  movzbl (%rsi),%eax
  test   %al,%al
  je     L35
L15:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L15
L35:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void strcat_(char *s, char *t) {
  while (*s != '\0') {
    s++;
  }
  while (*t != '\0') {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcat_>:
  endbr64
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L23:
  add    $0x1,%rdi
L5:
  cmpb   $0x0,(%rdi)
  jne    L23
  movzbl (%rsi),%eax
  test   %al,%al
  je     L4
L22:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L22
L4:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void strcat_(char *s, char *t) {
  while (*s != '\0') {
    s++;
  }
  while (*t != '\0') {
    *s++ = *t++;
  }
  *s = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L40
L4:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L29
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L29
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L8
L29:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x8(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
char *unify(const char *src) {
  const char *sptr;
  char *dst, *dptr;
  int c;
  if (!(dst = malloc(strlen(src) + 1)))
    return NULL;
  sptr = src;
  dptr = dst;
  do {
    c = (unsigned char)*sptr;
    if (isascii(c) && isupper(c))
      *dptr++ = tolower(c);
    else
      *dptr++ = *sptr;
  } while (*sptr++);
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<unify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
  lea    0x1(%rax),%rbp
  jmp    L46
L49:
  movzbl (%rbx),%eax
L16:
  mov    %al,-0x1(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbx)
  je     L4
L46:
  movzbl (%rbx),%r12d
  mov    %r12d,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L49
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L49
  mov    %r12d,%edi
  call   <tolower@plt>
  jmp    L16
L4:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *unify(const char *src) {
  const char *sptr;
  char *dst, *dptr;
  int c;
  if (!(dst = malloc(strlen(src) + 1)))
    return NULL;
  sptr = src;
  dptr = dst;
  do {
    c = (unsigned char)*sptr;
    if (isascii(c) && isupper(c))
      *dptr++ = tolower(c);
    else
      *dptr++ = *sptr;
  } while (*sptr++);
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L54
  mov    %rax,%rbp
  jmp    L20
  nopl   0x0(%rax)
L39:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %eax,%edx
  mov    %al,-0x1(%rbp)
  test   %dl,%dl
  je     L54
L20:
  movzbl (%rbx),%r12d
  add    $0x1,%rbp
  mov    %r12d,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L39
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L39
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  movzbl -0x1(%rbx),%edx
  mov    %al,-0x1(%rbp)
  test   %dl,%dl
  jne    L20
L54:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *unify(const char *src) {
  const char *sptr;
  char *dst, *dptr;
  int c;
  if (!(dst = malloc(strlen(src) + 1)))
    return NULL;
  sptr = src;
  dptr = dst;
  do {
    c = (unsigned char)*sptr;
    if (isascii(c) && isupper(c))
      *dptr++ = tolower(c);
    else
      *dptr++ = *sptr;
  } while (*sptr++);
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L25
  mov    %rax,%rbp
  jmp    L13
  nopl   0x0(%rax)
L17:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %eax,%edx
  mov    %al,-0x1(%rbp)
  test   %dl,%dl
  je     L25
L13:
  movzbl (%rbx),%r12d
  add    $0x1,%rbp
  mov    %r12d,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L17
  mov    %r12d,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L17
  mov    %r12d,%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  movzbl -0x1(%rbx),%edx
  mov    %al,-0x1(%rbp)
  test   %dl,%dl
  jne    L13
L25:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *unify(const char *src) {
  const char *sptr;
  char *dst, *dptr;
  int c;
  if (!(dst = malloc(strlen(src) + 1)))
    return NULL;
  sptr = src;
  dptr = dst;
  do {
    c = (unsigned char)*sptr;
    if (isascii(c) && isupper(c))
      *dptr++ = tolower(c);
    else
      *dptr++ = *sptr;
  } while (*sptr++);
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x100000,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L9
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x6,%edx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <EvaluateRS@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  size_t block_size = 1 << 20;
  if (argc > 1) {
    block_size = (size_t)atol(argv[1]);
  }
  EvaluateRS(block_size, 10, 4);
  EvaluateRS(block_size, 6, 3);
  EvaluateRS(block_size, 8, 4);
  EvaluateRS(block_size, 10, 5);
  EvaluateRS(block_size, 9, 3);
  EvaluateRS(block_size, 4, 2);
  EvaluateRS(block_size, 8, 3);
  EvaluateRS(block_size, 6, 4);
  EvaluateRS(block_size, 9, 6);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x100000,%ebx
  cmp    $0x1,%edi
  jg     L12
L7:
  mov    $0x4,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x4,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x5,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x3,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x2,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x3,%edx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x4,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x6,%edx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <EvaluateRS@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rbx
  jmp    L7
```

assistant: ```c
int main(int argc, char *argv[]) {
  size_t block_size = 1 << 20;
  if (argc > 1) {
    block_size = (size_t)atol(argv[1]);
  }
  EvaluateRS(block_size, 10, 4);
  EvaluateRS(block_size, 6, 3);
  EvaluateRS(block_size, 8, 4);
  EvaluateRS(block_size, 10, 5);
  EvaluateRS(block_size, 9, 3);
  EvaluateRS(block_size, 4, 2);
  EvaluateRS(block_size, 8, 3);
  EvaluateRS(block_size, 6, 4);
  EvaluateRS(block_size, 9, 6);
  return 0;
}
```