ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4c,%edi
  call   <putchar@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4:  Nothing 

assistant: ```c
main() {
  char a = 'A';
  if ((a == 'Z') || ((a = 'L') && (a == 'A')))
    a = a;
  printf("%c", a);
  printf(" Nothing ");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  rdtsc
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t tmp;
  uint64_t val;
  __asm__ __volatile__("rdtsc" : "=A"(val));
  tmp = val;
  if (t)
    *t = tmp;
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<time>:
  endbr64
  rdtsc
  test   %rdi,%rdi
  je     L6
  mov    %rax,(%rdi)
L6:
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t tmp;
  uint64_t val;
  __asm__ __volatile__("rdtsc" : "=A"(val));
  tmp = val;
  if (t)
    *t = tmp;
  return tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time>:
  endbr64
  rdtsc
  test   %rdi,%rdi
  je     L6
  mov    %rax,(%rdi)
L6:
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t tmp;
  uint64_t val;
  __asm__ __volatile__("rdtsc" : "=A"(val));
  tmp = val;
  if (t)
    *t = tmp;
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<time>:
  endbr64
  rdtsc
  test   %rdi,%rdi
  je     L3
  mov    %rax,(%rdi)
L3:
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t tmp;
  uint64_t val;
  __asm__ __volatile__("rdtsc" : "=A"(val));
  tmp = val;
  if (t)
    *t = tmp;
  return tmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<run_simulation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L21
  cmpl   $0x3,-0x4(%rbp)
  jg     L73
  cmpl   $0x1,-0x4(%rbp)
  je     L12
  cmpl   $0x2,-0x4(%rbp)
  je     L65
  jmp    L73
L21:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <stride_scheduling@plt>
  jmp    L2
L12:
  mov    $0x0,%eax
  call   <priority_scheduling@plt>
  jmp    L2
L65:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mlfq_scheduling@plt>
  jmp    L2
L73:
  mov    $0x0,%eax
  call   <first_come_first_serve@plt>
  nop
L2:
  nop
  leave
  ret
```

assistant: ```c
void run_simulation(int algorithm, int quantum) {
  switch (algorithm) {
  case 3:
    stride_scheduling(quantum);
    break;
  case 1:
    priority_scheduling();
    break;
  case 2:
    mlfq_scheduling(quantum);
    break;
  case 0:
  default:
    first_come_first_serve();
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<run_simulation>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L56
  cmp    $0x3,%edi
  je     L13
  cmp    $0x1,%edi
  je     L25
  mov    $0x0,%eax
  call   <first_come_first_serve@plt>
  jmp    L19
L13:
  mov    %esi,%edi
  call   <stride_scheduling@plt>
L19:
  add    $0x8,%rsp
  ret
L25:
  mov    $0x0,%eax
  call   <priority_scheduling@plt>
  jmp    L19
L56:
  mov    %esi,%edi
  call   <mlfq_scheduling@plt>
  jmp    L19
```

assistant: ```c
void run_simulation(int algorithm, int quantum) {
  switch (algorithm) {
  case 3:
    stride_scheduling(quantum);
    break;
  case 1:
    priority_scheduling();
    break;
  case 2:
    mlfq_scheduling(quantum);
    break;
  case 0:
  default:
    first_come_first_serve();
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<run_simulation>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  cmp    $0x2,%eax
  je     L10
  cmp    $0x3,%eax
  je     L16
  cmp    $0x1,%eax
  je     L0
  xor    %eax,%eax
  jmp    1080 <first_come_first_serve@plt>
  xchg   %ax,%ax
L10:
  jmp    10b0 <mlfq_scheduling@plt>
  nopl   (%rax)
L0:
  xor    %eax,%eax
  jmp    10a0 <priority_scheduling@plt>
  nop
L16:
  jmp    1090 <stride_scheduling@plt>
```

assistant: ```c
void run_simulation(int algorithm, int quantum) {
  switch (algorithm) {
  case 3:
    stride_scheduling(quantum);
    break;
  case 1:
    priority_scheduling();
    break;
  case 2:
    mlfq_scheduling(quantum);
    break;
  case 0:
  default:
    first_come_first_serve();
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<run_simulation>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  cmp    $0x2,%eax
  je     L15
  cmp    $0x3,%eax
  je     L19
  cmp    $0x1,%eax
  je     L24
  xor    %eax,%eax
  jmp    1080 <first_come_first_serve@plt>
  xchg   %ax,%ax
L15:
  jmp    10b0 <mlfq_scheduling@plt>
  nopl   (%rax)
L24:
  xor    %eax,%eax
  jmp    10a0 <priority_scheduling@plt>
  nop
L19:
  jmp    1090 <stride_scheduling@plt>
```

assistant: ```c
void run_simulation(int algorithm, int quantum) {
  switch (algorithm) {
  case 3:
    stride_scheduling(quantum);
    break;
  case 1:
    priority_scheduling();
    break;
  case 2:
    mlfq_scheduling(quantum);
    break;
  case 0:
  default:
    first_come_first_serve();
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string

tool: D5: %d 

tool: 

assistant: ```c
void putvec(int b[], int p) {
  int i;
  for (i = 0; i < p; i++)
    printf("%d ", b[i]);
  puts("");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putvec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D11(%rip),%rbp
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
L16:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: string
name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D11: %d 

tool: 

assistant: ```c
void putvec(int b[], int p) {
  int i;
  for (i = 0; i < p; i++)
    printf("%d ", b[i]);
  puts("");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putvec>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  pop    %rbx
  lea    D8(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  lea    D8(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D12: %d 

tool: 

assistant: ```c
void putvec(int b[], int p) {
  int i;
  for (i = 0; i < p; i++)
    printf("%d ", b[i]);
  puts("");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<putvec>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  lea    D27(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  lea    D27(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string

tool: D17: %d 

tool: 

assistant: ```c
void putvec(int b[], int p) {
  int i;
  for (i = 0; i < p; i++)
    printf("%d ", b[i]);
  puts("");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L29
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L29:
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L13:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L32:
  cmpl   $0x0,-0x14(%rbp)
  jle    L13
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0x2800,%ax
  jne    L15
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L15:
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L14:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D5
data_type: string

tool: D19: Call this program with %i arguments


tool: D0: You win!

tool: D5: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 10240) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L38
L28:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0x2800,0x6(%rsp)
  je     L17
L26:
  movzwl 0x6(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L28
L17:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L26
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
data_type: string
name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D11
data_type: string

tool: D22: %u


tool: D1: Call this program with %i arguments


tool: D11: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 10240) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L28
  lea    D8(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L28:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x2800,%si
  je     L33
L13:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L13
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D8: Call this program with %i arguments


tool: D17: %u


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 10240) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L10
  lea    D28(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L10:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x2800,%si
  je     L0
L19:
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L19
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: D28: Call this program with %i arguments


tool: D26: %u


tool: D16: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 10240) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<promptOperation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <displayMenu@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <promptValue@plt>
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: Veuillez choisir une operation ?

assistant: ```c
int promptOperation() {
  displayMenu();
  return promptValue("Veuillez choisir une operation ?");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<promptOperation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <displayMenu@plt>
  lea    D6(%rip),%rdi
  call   <promptValue@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Veuillez choisir une operation ?

assistant: ```c
int promptOperation() {
  displayMenu();
  return promptValue("Veuillez choisir une operation ?");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<promptOperation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <displayMenu@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <promptValue@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: Veuillez choisir une operation ?

assistant: ```c
int promptOperation() {
  displayMenu();
  return promptValue("Veuillez choisir une operation ?");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<promptOperation>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <displayMenu@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <promptValue@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: Veuillez choisir une operation ?

assistant: ```c
int promptOperation() {
  displayMenu();
  return promptValue("Veuillez choisir une operation ?");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func_54>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    $0xe,%edi
  call   <step_hash@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
short func_54(int *p_55) {
  unsigned l_56 = 1UL;
  step_hash(14);
  return l_56;
}
```
user: What is the c source code of the assembly code below:

```asm
<func_54>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <step_hash@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
short func_54(int *p_55) {
  unsigned l_56 = 1UL;
  step_hash(14);
  return l_56;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_54>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <step_hash@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
short func_54(int *p_55) {
  unsigned l_56 = 1UL;
  step_hash(14);
  return l_56;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<func_54>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <step_hash@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
short func_54(int *p_55) {
  unsigned l_56 = 1UL;
  step_hash(14);
  return l_56;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_func_00>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *test_func_00(float *p, float *x) {
  float r = 0;
  r += *p++;
  r += *p++;
  *x = r;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_func_00>:
  endbr64
  pxor   %xmm0,%xmm0
  addss  (%rdi),%xmm0
  addss  0x4(%rdi),%xmm0
  movss  %xmm0,(%rsi)
  lea    0x8(%rdi),%rax
  ret
```

assistant: ```c
float *test_func_00(float *p, float *x) {
  float r = 0;
  r += *p++;
  r += *p++;
  *x = r;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func_00>:
  endbr64
  pxor   %xmm0,%xmm0
  addss  (%rdi),%xmm0
  addss  0x4(%rdi),%xmm0
  lea    0x8(%rdi),%rax
  movss  %xmm0,(%rsi)
  ret
```

assistant: ```c
float *test_func_00(float *p, float *x) {
  float r = 0;
  r += *p++;
  r += *p++;
  *x = r;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_func_00>:
  endbr64
  pxor   %xmm0,%xmm0
  addss  (%rdi),%xmm0
  addss  0x4(%rdi),%xmm0
  lea    0x8(%rdi),%rax
  movss  %xmm0,(%rsi)
  ret
```

assistant: ```c
float *test_func_00(float *p, float *x) {
  float r = 0;
  r += *p++;
  r += *p++;
  *x = r;
  return p;
}
```