ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L49
L42:
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L50:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,%edx
  je     L2
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L68
L2:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L68:
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jb     L50
  addl   $0x2,-0x10(%rbp)
L49:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L42
  mov    -0xc(%rbp),%eax
  imul   $0xbf382a0,%eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x136ff696(%rax),%edx
  mov    0x4(%rdi),%r8d
  mov    %r8d,%ecx
  mov    $0x0,%edi
  test   %r8d,%r8d
  jne    L2
L10:
  imul   $0xbf382a0,%edx,%edx
  mov    %edx,(%rsi)
  ret
L47:
  add    %edx,%edx
L59:
  add    $0x1,%eax
  cmp    %eax,%ecx
  je     L50
L17:
  cmp    %eax,%edx
  jne    L47
  imul   %edx,%edx
  jmp    L59
L50:
  add    $0x2,%edi
  sub    $0x2,%ecx
  cmp    %r8d,%edi
  jae    L10
L2:
  mov    %edi,%eax
  neg    %eax
  jmp    L17
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  xor    %edi,%edi
  lea    0x136ff696(%rax),%edx
  mov    %r8d,%ecx
  test   %r8d,%r8d
  je     L15
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %edi,%eax
  neg    %eax
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L17:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    %eax,%ecx
  je     L59
L25:
  cmp    %eax,%edx
  jne    L17
  add    $0x1,%eax
  imul   %edx,%edx
  cmp    %eax,%ecx
  jne    L25
L59:
  add    $0x2,%edi
  sub    $0x2,%ecx
  cmp    %r8d,%edi
  jb     L50
L15:
  imul   $0xbf382a0,%edx,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r8d
  lea    0x136ff696(%rax),%edx
  test   %r8d,%r8d
  je     L10
  mov    %r8d,%ecx
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %edi,%eax
  neg    %eax
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L42:
  add    $0x1,%eax
  add    %edx,%edx
  cmp    %ecx,%eax
  je     L18
L29:
  cmp    %edx,%eax
  jne    L42
  mov    %eax,%edx
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L29
L18:
  add    $0x2,%edi
  sub    $0x2,%ecx
  cmp    %r8d,%edi
  jb     L27
L10:
  imul   $0xbf382a0,%edx,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<caesar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L40
L86:
  movzbl (%r12,%rbx,1),%eax
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
L40:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L86
  movzbl (%r12),%eax
  test   %al,%al
  je     L21
  lea    0x1(%r12),%rdx
  mov    %rsp,%rsi
  jmp    L11
L36:
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L51
  movsbl %al,%eax
  lea    -0x41(%rbp,%rax,1),%ecx
  movslq %ecx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  add    $0x41,%ecx
  mov    %cl,(%rsi)
L51:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%rsi
  test   %al,%al
  je     L21
L11:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L36
  movsbl %al,%eax
  lea    -0x61(%rbp,%rax,1),%ecx
  movslq %ecx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x23,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%ecx
  add    $0x61,%ecx
  mov    %cl,(%rsi)
  jmp    L51
L21:
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %s 
 

assistant: ```c
void caesar(char message[], int key) {
  char messageOut[264];
  for (int j = 0; j < (int)strlen(message); j++) {
    messageOut[j] = message[j];
  }
  int i = 0;
  while (message[i] != '\0') {
    if (message[i] >= 'a' && message[i] <= 'z') {
      messageOut[i] = (message[i] - 'a' + key) % 26 + 'a';
    } else if (message[i] >= 'A' && message[i] <= 'Z') {
      messageOut[i] = (message[i] - 'A' + key) % 26 + 'A';
    }
    i++;
  }
  printf("%s \n ", messageOut);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<caesar>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L54
  nopl   0x0(%rax)
L12:
  movzbl 0x0(%r13,%r12,1),%eax
  mov    %al,0x0(%rbp,%r12,1)
  add    $0x1,%r12
L54:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L12
  movzbl 0x0(%r13),%edx
  test   %dl,%dl
  je     L27
  lea    0x1(%r13),%rcx
  mov    %rbp,%rsi
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L63:
  movsbl %al,%eax
  add    %ebx,%eax
  movslq %eax,%rdx
  mov    %eax,%edi
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%edi
  sar    $0x23,%rdx
  sub    %edi,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,(%rsi)
L79:
  movzbl (%rcx),%edx
  add    $0x1,%rsi
  add    $0x1,%rcx
  test   %dl,%dl
  je     L27
L15:
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  jbe    L63
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L79
  movsbl %dl,%edx
  add    $0x1,%rcx
  add    $0x1,%rsi
  add    %ebx,%edx
  movslq %edx,%rax
  mov    %edx,%edi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x23,%rax
  sub    %edi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edx
  add    $0x41,%edx
  mov    %dl,-0x1(%rsi)
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L15
L27:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: %s 
 

assistant: ```c
void caesar(char message[], int key) {
  char messageOut[264];
  for (int j = 0; j < (int)strlen(message); j++) {
    messageOut[j] = message[j];
  }
  int i = 0;
  while (message[i] != '\0') {
    if (message[i] >= 'a' && message[i] <= 'z') {
      messageOut[i] = (message[i] - 'a' + key) % 26 + 'a';
    } else if (message[i] >= 'A' && message[i] <= 'Z') {
      messageOut[i] = (message[i] - 'A' + key) % 26 + 'A';
    }
    i++;
  }
  printf("%s \n ", messageOut);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<caesar>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L33
  nopl   0x0(%rax)
L20:
  movzbl 0x0(%r13,%r12,1),%eax
  mov    %al,0x0(%rbp,%r12,1)
  add    $0x1,%r12
L33:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L20
  movzbl 0x0(%r13),%edx
  test   %dl,%dl
  je     L27
  lea    0x1(%r13),%rcx
  mov    %rbp,%rsi
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl %al,%eax
  add    %ebx,%eax
  movslq %eax,%rdx
  mov    %eax,%edi
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%edi
  sar    $0x23,%rdx
  sub    %edi,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,(%rsi)
L21:
  movzbl (%rcx),%edx
  add    $0x1,%rsi
  add    $0x1,%rcx
  test   %dl,%dl
  je     L27
L65:
  lea    -0x61(%rdx),%eax
  cmp    $0x19,%al
  jbe    L5
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L21
  movsbl %dl,%edx
  add    $0x1,%rcx
  add    $0x1,%rsi
  add    %ebx,%edx
  movslq %edx,%rax
  mov    %edx,%edi
  imul   $0x4ec4ec4f,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x23,%rax
  sub    %edi,%eax
  imul   $0x1a,%eax,%eax
  sub    %eax,%edx
  add    $0x41,%edx
  mov    %dl,-0x1(%rsi)
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L65
L27:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: %s 
 

assistant: ```c
void caesar(char message[], int key) {
  char messageOut[264];
  for (int j = 0; j < (int)strlen(message); j++) {
    messageOut[j] = message[j];
  }
  int i = 0;
  while (message[i] != '\0') {
    if (message[i] >= 'a' && message[i] <= 'z') {
      messageOut[i] = (message[i] - 'a' + key) % 26 + 'a';
    } else if (message[i] >= 'A' && message[i] <= 'Z') {
      messageOut[i] = (message[i] - 'A' + key) % 26 + 'A';
    }
    i++;
  }
  printf("%s \n ", messageOut);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ustrzcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ustrsize@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rbx
  mov    $0x0,%edi
  call   <ucwidth@plt>
  lea    (%rbx,%rax,1),%rdx
  mov    -0x2c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L12
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ucwidth@plt>
  mov    -0x2c(%rbp),%edx
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  js     L36
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <usetc@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
L12:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <ugetxc@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  jmp    L17
L36:
  nop
L17:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <usetc@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ustrzcat(char *dest, int size, const char *src) {
  int pos = ustrsize(dest);
  int c;
  size -= pos + ucwidth(0);
  while ((c = ugetxc(&src)) != 0) {
    size -= ucwidth(c);
    if (size < 0)
      break;
    pos += usetc(dest + pos, c);
  }
  usetc(dest + pos, 0);
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ustrzcat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,0x8(%rsp)
  call   <ustrsize@plt>
  mov    %eax,%ebp
  mov    $0x0,%edi
  call   <ucwidth@plt>
  sub    %ebp,%r12d
  sub    %eax,%r12d
  lea    0x8(%rsp),%r14
  jmp    L13
L7:
  movslq %ebp,%rdi
  add    %r13,%rdi
  mov    %ebx,%esi
  call   <usetc@plt>
  add    %eax,%ebp
L13:
  mov    %r14,%rdi
  call   <ugetxc@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L22
  mov    %ebx,%edi
  call   <ucwidth@plt>
  mov    %rax,%rdx
  mov    %r12d,%eax
  sub    %edx,%eax
  mov    %eax,%r12d
  jns    L7
L22:
  movslq %ebp,%rdi
  add    %r13,%rdi
  mov    $0x0,%esi
  call   <usetc@plt>
  mov    %r13,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ustrzcat(char *dest, int size, const char *src) {
  int pos = ustrsize(dest);
  int c;
  size -= pos + ucwidth(0);
  while ((c = ugetxc(&src)) != 0) {
    size -= ucwidth(c);
    if (size < 0)
      break;
    pos += usetc(dest + pos, c);
  }
  usetc(dest + pos, 0);
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ustrzcat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x8(%rsp),%r15
  call   <ustrsize@plt>
  xor    %edi,%edi
  movslq %eax,%rbx
  call   <ucwidth@plt>
  mov    %rbx,%r13
  add    %rbx,%rax
  sub    %eax,%r12d
  jmp    L29
  nopl   0x0(%rax)
L23:
  mov    %ebp,%edi
  call   <ucwidth@plt>
  sub    %eax,%r12d
  js     L6
  mov    %rbx,%rdi
  mov    %ebp,%esi
  call   <usetc@plt>
  add    %eax,%r13d
  movslq %r13d,%rbx
L29:
  mov    %r15,%rdi
  add    %r14,%rbx
  call   <ugetxc@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L23
L6:
  mov    %rbx,%rdi
  xor    %esi,%esi
  call   <usetc@plt>
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *ustrzcat(char *dest, int size, const char *src) {
  int pos = ustrsize(dest);
  int c;
  size -= pos + ucwidth(0);
  while ((c = ugetxc(&src)) != 0) {
    size -= ucwidth(c);
    if (size < 0)
      break;
    pos += usetc(dest + pos, c);
  }
  usetc(dest + pos, 0);
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ustrzcat>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  lea    0x8(%rsp),%r15
  call   <ustrsize@plt>
  xor    %edi,%edi
  movslq %eax,%rbx
  call   <ucwidth@plt>
  mov    %rbx,%r13
  add    %rbx,%rax
  sub    %eax,%r12d
  jmp    L26
  nopl   0x0(%rax)
L10:
  mov    %ebp,%edi
  call   <ucwidth@plt>
  sub    %eax,%r12d
  js     L25
  mov    %rbx,%rdi
  mov    %ebp,%esi
  call   <usetc@plt>
  add    %eax,%r13d
  movslq %r13d,%rbx
L26:
  mov    %r15,%rdi
  add    %r14,%rbx
  call   <ugetxc@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L10
L25:
  mov    %rbx,%rdi
  xor    %esi,%esi
  call   <usetc@plt>
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *ustrzcat(char *dest, int size, const char *src) {
  int pos = ustrsize(dest);
  int c;
  size -= pos + ucwidth(0);
  while ((c = ugetxc(&src)) != 0) {
    size -= ucwidth(c);
    if (size < 0)
      break;
    pos += usetc(dest + pos, c);
  }
  usetc(dest + pos, 0);
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_shrink_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  jmp    L12
L48:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L30
  jmp    L29
L25:
  addq   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L25
  subq   $0x1,-0x10(%rbp)
L30:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_shrink_string(char *str_pointer, const char *original, char target_char) {
  while (*original) {
    *str_pointer = *original;
    if (*str_pointer == target_char) {
      while (*original == target_char) {
        ++original;
      }
      --original;
    }
    ++str_pointer;
    ++original;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_shrink_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L21
L38:
  ret
L39:
  lea    -0x1(%rsi),%rcx
L58:
  add    $0x1,%rdi
  lea    0x1(%rcx),%rsi
  movzbl 0x1(%rcx),%eax
  test   %al,%al
  je     L38
L21:
  mov    %al,(%rdi)
  mov    %rsi,%rcx
  cmp    %al,%dl
  jne    L58
  cmp    (%rsi),%dl
  jne    L39
L3:
  add    $0x1,%rsi
  cmp    %dl,(%rsi)
  je     L3
  jmp    L39
```

assistant: ```c
void copy_shrink_string(char *str_pointer, const char *original, char target_char) {
  while (*original) {
    *str_pointer = *original;
    if (*str_pointer == target_char) {
      while (*original == target_char) {
        ++original;
      }
      --original;
    }
    ++str_pointer;
    ++original;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy_shrink_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L35
  jmp    L3
  nopl   (%rax)
L48:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
L5:
  add    $0x1,%rdi
  test   %al,%al
  je     L3
L35:
  mov    %al,(%rdi)
  cmp    %al,%dl
  jne    L48
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L68
  nopl   (%rax)
L72:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  cmp    %cl,%al
  je     L72
  add    $0x1,%rdi
  test   %al,%al
  jne    L35
L3:
  ret
  nopl   (%rax)
L68:
  mov    %ecx,%eax
  jmp    L5
```

assistant: ```c
void copy_shrink_string(char *str_pointer, const char *original, char target_char) {
  while (*original) {
    *str_pointer = *original;
    if (*str_pointer == target_char) {
      while (*original == target_char) {
        ++original;
      }
      --original;
    }
    ++str_pointer;
    ++original;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_shrink_string>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L23
  jmp    L64
  nopl   (%rax)
L21:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
L25:
  add    $0x1,%rdi
  test   %al,%al
  je     L64
L23:
  mov    %al,(%rdi)
  cmp    %al,%dl
  jne    L21
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L17
  nopl   (%rax)
L46:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  cmp    %cl,%al
  je     L46
  add    $0x1,%rdi
  test   %al,%al
  jne    L23
L64:
  ret
  nopl   (%rax)
L17:
  mov    %ecx,%eax
  jmp    L25
```

assistant: ```c
void copy_shrink_string(char *str_pointer, const char *original, char target_char) {
  while (*original) {
    *str_pointer = *original;
    if (*str_pointer == target_char) {
      while (*original == target_char) {
        ++original;
      }
      --original;
    }
    ++str_pointer;
    ++original;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bcd_to_proper_single>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  shr    $0x4,%al
  mov    %al,-0x2(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char bcd_to_proper_single(unsigned char value) {
  unsigned char high, low;
  high = (value & 0xf0) >> 4;
  low = (value & 0xf);
  return ((high * 10U) + low) & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bcd_to_proper_single>:
  endbr64
  mov    %edi,%eax
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  and    $0xf,%edi
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bcd_to_proper_single(unsigned char value) {
  unsigned char high, low;
  high = (value & 0xf0) >> 4;
  low = (value & 0xf);
  return ((high * 10U) + low) & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bcd_to_proper_single>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%edi
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bcd_to_proper_single(unsigned char value) {
  unsigned char high, low;
  high = (value & 0xf0) >> 4;
  low = (value & 0xf);
  return ((high * 10U) + low) & 0xff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bcd_to_proper_single>:
  endbr64
  mov    %edi,%eax
  and    $0xf,%edi
  shr    $0x4,%al
  lea    (%rax,%rax,4),%eax
  lea    (%rdi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned char bcd_to_proper_single(unsigned char value) {
  unsigned char high, low;
  high = (value & 0xf0) >> 4;
  low = (value & 0xf);
  return ((high * 10U) + low) & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rsi,-0x8(%rbp)
  mov    $0x989680,%eax
  jmp    L16
L17:
  sub    $0x1,%eax
L16:
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jge    L17
  nop
  pop    %rbp
  ret
```

assistant: ```c
foo(a, p) register int a;
int *p;
{
  for (a = 10000000; a >= *p; a--)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  mov    (%rsi),%edx
  cmp    $0x989680,%edx
  jg     L12
  sub    $0x1,%edx
  mov    $0x989680,%eax
L13:
  sub    $0x1,%eax
  cmp    %edx,%eax
  jne    L13
L12:
  ret
```

assistant: ```c
foo(a, p) register int a;
int *p;
{
  for (a = 10000000; a >= *p; a--)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
foo(a, p) register int a;
int *p;
{
  for (a = 10000000; a >= *p; a--)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
foo(a, p) register int a;
int *p;
{
  for (a = 10000000; a >= *p; a--)
    ;
}
```