ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<output_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x1,%esi
  mov    $0x3e,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L33
L14:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x3c,%eax
  sub    %edx,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %ebx,%eax
  xor    $0x1,%eax
  and    $0x1,%eax
  mov    %r12d,%r14d
  sub    %eax,%r14d
  je     L22
  mov    $0x0,%ebx
  lea    D26(%rip),%r15
L52:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jne    L52
L22:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  sub    $0x1,%r12d
  je     L2
  mov    $0x0,%ebx
  lea    D26(%rip),%r14
L40:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jne    L40
L2:
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  lea    D31(%rip),%rdi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string

tool: D30: *

tool: D26:  

tool: D25: *


tool: D31: print_info(): Out of memory !

assistant: ```c
char *output_line(char *string) {
  char *tmp;
  if (NULL == (tmp = (calloc(62, sizeof(char))))) {
    error("print_info(): Out of memory !");
  }
  int x, i, y;
  y = 0;
  if (strlen(string) % 2 == 0)
    y = 1;
  x = (60 - strlen(string)) / 2;
  strcat(tmp, "*");
  for (i = 0; i != x - y; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, string);
  for (i = 0; i != x - 1; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, "*\n");
  free(string);
  string = &(tmp[0]);
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_line>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  mov    %rdi,%r14
  mov    $0x3e,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
L11:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    D45(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    $0x3c,%eax
  sub    %r8d,%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  call   <strcat@plt>
  mov    %ebx,%eax
  sar    %ebp
  not    %eax
  mov    %ebp,%r15d
  and    $0x1,%eax
  sub    %eax,%r15d
  je     L21
  xor    %ebx,%ebx
  lea    D40(%rip),%r13
  nopl   (%rax)
L47:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %r15d,%ebx
  jne    L47
L21:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  je     L1
  xor    %ebx,%ebx
  lea    D40(%rip),%r13
  nopl   0x0(%rax)
L38:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %ebp,%ebx
  jne    L38
L1:
  mov    %r12,%rdi
  lea    D30(%rip),%rsi
  call   <strcat@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    D15(%rip),%rdi
  call   <error@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_label: D45
type_guessed: string
name: disassemble_data
arguments: data_label: D40
type_guessed: string
name: disassemble_data
arguments: data_label: D30
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D45: *

tool: D40:  

tool: D30: *


tool: D15: print_info(): Out of memory !

assistant: ```c
char *output_line(char *string) {
  char *tmp;
  if (NULL == (tmp = (calloc(62, sizeof(char))))) {
    error("print_info(): Out of memory !");
  }
  int x, i, y;
  y = 0;
  if (strlen(string) % 2 == 0)
    y = 1;
  x = (60 - strlen(string)) / 2;
  strcat(tmp, "*");
  for (i = 0; i != x - y; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, string);
  for (i = 0; i != x - 1; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, "*\n");
  free(string);
  string = &(tmp[0]);
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_line>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  mov    %rdi,%r14
  mov    $0x3e,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L48:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    D25(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    $0x3c,%eax
  sub    %r8d,%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  call   <strcat@plt>
  mov    %ebx,%eax
  sar    %ebp
  not    %eax
  mov    %ebp,%r15d
  and    $0x1,%eax
  sub    %eax,%r15d
  je     L38
  xor    %ebx,%ebx
  lea    D28(%rip),%r13
  nopl   (%rax)
L24:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %r15d,%ebx
  jne    L24
L38:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  je     L52
  xor    %ebx,%ebx
  lea    D28(%rip),%r13
  nopl   0x0(%rax)
L37:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <strcat@plt>
  cmp    %ebp,%ebx
  jne    L37
L52:
  mov    %r12,%rdi
  lea    D1(%rip),%rsi
  call   <strcat@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    D31(%rip),%rdi
  call   <error@plt>
  jmp    L48
```

tool_calls: name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D28
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D31
type_guessed: string

tool: D25: *

tool: D28:  

tool: D1: *


tool: D31: print_info(): Out of memory !

assistant: ```c
char *output_line(char *string) {
  char *tmp;
  if (NULL == (tmp = (calloc(62, sizeof(char))))) {
    error("print_info(): Out of memory !");
  }
  int x, i, y;
  y = 0;
  if (strlen(string) % 2 == 0)
    y = 1;
  x = (60 - strlen(string)) / 2;
  strcat(tmp, "*");
  for (i = 0; i != x - y; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, string);
  for (i = 0; i != x - 1; ++i) {
    strcat(tmp, " ");
  }
  strcat(tmp, "*\n");
  free(string);
  string = &(tmp[0]);
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xe2329b00,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L27
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L27:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_score(int *scores, int nsq) {
  int max, i;
  max = -500000000;
  for (i = 1; i < nsq; i++) {
    if (scores[i] > max)
      max = scores[i];
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<max_score>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rsi
  mov    $0xe2329b00,%edx
L23:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L23
L10:
  mov    %edx,%eax
  ret
L0:
  mov    $0xe2329b00,%edx
  jmp    L10
```

assistant: ```c
int max_score(int *scores, int nsq) {
  int max, i;
  max = -500000000;
  for (i = 1; i < nsq; i++) {
    if (scores[i] > max)
      max = scores[i];
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<max_score>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    $0xe2329b00,%r8d
  lea    0x8(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0xe2329b00,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int max_score(int *scores, int nsq) {
  int max, i;
  max = -500000000;
  for (i = 1; i < nsq; i++) {
    if (scores[i] > max)
      max = scores[i];
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<max_score>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%edx
  cmp    $0x1,%esi
  jle    L67
  lea    -0x2(%rdx),%eax
  lea    -0x1(%rsi),%esi
  cmp    $0x2,%eax
  jbe    L65
  mov    %esi,%ecx
  movdqa D7(%rip),%xmm2
  lea    0x4(%rdi),%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x14(%rdi,%rcx,1),%rcx
  xchg   %ax,%ax
L32:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L32
  movdqa %xmm2,%xmm0
  mov    %esi,%edi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edi
  movdqa %xmm0,%xmm1
  lea    0x1(%rdi),%ecx
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %edi,%esi
  je     L45
L48:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    (%r8,%rsi,4),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L22
  mov    0x4(%r8,%rdi,1),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L22
  mov    0x8(%r8,%rdi,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    $0xe2329b00,%eax
L22:
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  ret
L65:
  mov    $0x1,%ecx
  mov    $0xe2329b00,%eax
  jmp    L48
```

tool_calls: name: unpack_data
arguments: label: D7
type: byte[16]

tool: {"D7": [0x00,0x9b,0x32,0xe2,0x00,0x9b,0x32,0xe2,0x00,0x9b,0x32,0xe2,0x00,0x9b,0x32,0xe2]}

assistant: ```c
int max_score(int *scores, int nsq) {
  int max, i;
  max = -500000000;
  for (i = 1; i < nsq; i++) {
    if (scores[i] > max)
      max = scores[i];
  }
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<br_configuration_update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <br_root_selection@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <br_designated_port_selection@plt>
  nop
  leave
  ret
```

assistant: ```c
void br_configuration_update(struct net_bridge *br) {
  br_root_selection(br);
  br_designated_port_selection(br);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<br_configuration_update>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <br_root_selection@plt>
  mov    %rbx,%rdi
  call   <br_designated_port_selection@plt>
  pop    %rbx
  ret
```

assistant: ```c
void br_configuration_update(struct net_bridge *br) {
  br_root_selection(br);
  br_designated_port_selection(br);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<br_configuration_update>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <br_root_selection@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <br_designated_port_selection@plt>
```

assistant: ```c
void br_configuration_update(struct net_bridge *br) {
  br_root_selection(br);
  br_designated_port_selection(br);
}
```
user: What is the c source code of the assembly code below?

```asm
<br_configuration_update>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <br_root_selection@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <br_designated_port_selection@plt>
```

assistant: ```c
void br_configuration_update(struct net_bridge *br) {
  br_root_selection(br);
  br_designated_port_selection(br);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rmalloc_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rmalloc_strndup(const char *s, size_t n) {
  char *ret = calloc(n + 1, sizeof(char));
  if (ret)
    memcpy(ret, s, n);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rmalloc_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *rmalloc_strndup(const char *s, size_t n) {
  char *ret = calloc(n + 1, sizeof(char));
  if (ret)
    memcpy(ret, s, n);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rmalloc_strndup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *rmalloc_strndup(const char *s, size_t n) {
  char *ret = calloc(n + 1, sizeof(char));
  if (ret)
    memcpy(ret, s, n);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rmalloc_strndup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *rmalloc_strndup(const char *s, size_t n) {
  char *ret = calloc(n + 1, sizeof(char));
  if (ret)
    memcpy(ret, s, n);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x20,-0x4(%rbp)
  sete   %dl
  cmpb   $0x9,-0x4(%rbp)
  sete   %al
  or     %edx,%eax
  movzbl %al,%edx
  cmpb   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  or     %edx,%eax
  test   %eax,%eax
  je     L8
  mov    $0x1,%eax
  jmp    L16
L8:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
isspace(c) char c;
{
  if (c == ' ' | c == '\t' | c == '\n')
    return (1);
  else
    return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isspace(c) char c;
{
  if (c == ' ' | c == '\t' | c == '\n')
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isspace(c) char c;
{
  if (c == ' ' | c == '\t' | c == '\n')
    return (1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isspace>:
  endbr64
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x20,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
isspace(c) char c;
{
  if (c == ' ' | c == '\t' | c == '\n')
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<std_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L7
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: write

assistant: ```c
ssize_t std_write(int fd, const void *buf, size_t count) {
  ssize_t c;
  if ((c = write(fd, buf, count)) == -1) {
    perror("write");
    exit(1);
  }
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<std_write>:
  endbr64
  push   %rbx
  call   <write@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L0
L9:
  mov    %ebx,%eax
  pop    %rbx
  ret
L0:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: write

assistant: ```c
ssize_t std_write(int fd, const void *buf, size_t count) {
  ssize_t c;
  if ((c = write(fd, buf, count)) == -1) {
    perror("write");
    exit(1);
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<std_write>:
  endbr64
  push   %r12
  call   <write@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L8
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: write

assistant: ```c
ssize_t std_write(int fd, const void *buf, size_t count) {
  ssize_t c;
  if ((c = write(fd, buf, count)) == -1) {
    perror("write");
    exit(1);
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<std_write>:
  endbr64
  push   %r12
  call   <write@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L2
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: write

assistant: ```c
ssize_t std_write(int fd, const void *buf, size_t count) {
  ssize_t c;
  if ((c = write(fd, buf, count)) == -1) {
    perror("write");
    exit(1);
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pythag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   D36(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movq   D36(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L3
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  jmp    L16
L3:
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L30
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L30
  pxor   %xmm0,%xmm0
  jmp    L16
L30:
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
L16:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D36
type_infered: qword
name: parse_data
arguments: label: D5
type_infered: f64

tool: D36: 9223372036854775807

tool: D5: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb * absb) / (absa * absa));
  else if (absb == 0.0)
    return 0.0;
  else
    return absb * sqrt(1.0 + (absa * absa) / (absb * absb));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pythag>:
  endbr64
  sub    $0x18,%rsp
  movq   D31(%rip),%xmm2
  movapd %xmm0,%xmm3
  andpd  %xmm2,%xmm3
  movsd  %xmm3,0x8(%rsp)
  andpd  %xmm1,%xmm2
  movsd  %xmm2,(%rsp)
  comisd %xmm2,%xmm3
  ja     L79
  ucomisd D5(%rip),%xmm1
  jp     L12
  pxor   %xmm2,%xmm2
  jne    L12
L78:
  movapd %xmm2,%xmm0
  add    $0x18,%rsp
  ret
L79:
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  addsd  D25(%rip),%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L74
  sqrtsd %xmm1,%xmm1
L56:
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm1,%xmm2
  jmp    L78
L74:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L56
L12:
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  divsd  %xmm1,%xmm0
  addsd  D25(%rip),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L48
  movapd %xmm0,%xmm2
  sqrtsd %xmm2,%xmm2
L50:
  mulsd  (%rsp),%xmm2
  jmp    L78
L48:
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L50
```

tool_calls: name: disassemble_data
arguments: data_tag: D31
type_infered: qword
name: disassemble_data
arguments: data_tag: D5
type_infered: f64
name: disassemble_data
arguments: data_tag: D25
type_infered: f64

tool: D31: 9223372036854775807

tool: D5: 0

tool: D25: 1

assistant: ```c
double pythag(double a, double b) {
  double absa, absb;
  absa = fabs(a);
  absb = fabs(b);
  if (absa > absb)
    return absa * sqrt(1.0 + (absb * absb) / (absa * absa));
  else if (absb == 0.0)
    return 0.0;
  else
    return absb * sqrt(1.0 + (absa * absa) / (absb * absb));
}
```