ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L12
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L12
L28:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L28
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D16
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D13: Enter a year: 

tool: D16: %d

tool: D18: 
%d IS a leap year.


tool: D0: 
%d IS NOT a leap year.


assistant: ```c
int main() {
  int year = 0;
  printf("Enter a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("\n%d IS a leap year.\n", year);
  else
    printf("\n%d IS NOT a leap year.\n", year);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L29
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L29
L10:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L10
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L33
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D9
type: string

tool: D4: Enter a year: 

tool: D28: %d

tool: D0: 
%d IS a leap year.


tool: D9: 
%d IS NOT a leap year.


assistant: ```c
int main() {
  int year = 0;
  printf("Enter a year: ");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("\n%d IS a leap year.\n", year);
  else
    printf("\n%d IS NOT a leap year.\n", year);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<serializeInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void serializeInt(void **buffer, int value) {
  *(int *)*buffer = value;
  *buffer += sizeof(int);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serializeInt>:
  endbr64
  mov    (%rdi),%rax
  mov    %esi,(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void serializeInt(void **buffer, int value) {
  *(int *)*buffer = value;
  *buffer += sizeof(int);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serializeInt>:
  endbr64
  mov    (%rdi),%rax
  mov    %esi,(%rax)
  add    $0x4,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void serializeInt(void **buffer, int value) {
  *(int *)*buffer = value;
  *buffer += sizeof(int);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<serializeInt>:
  endbr64
  mov    (%rdi),%rax
  mov    %esi,(%rax)
  add    $0x4,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void serializeInt(void **buffer, int value) {
  *(int *)*buffer = value;
  *buffer += sizeof(int);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<board_ck_rb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <serialport_set_rts@plt>
  mov    $0x1,%edi
  call   <serialport_set_dtr@plt>
  mov    $0x0,%eax
  call   <serialport_send_break@plt>
  mov    $0x5,%edi
  call   <espcomm_delay_ms@plt>
  mov    $0x0,%edi
  call   <serialport_set_rts@plt>
  mov    $0xfa,%edi
  call   <espcomm_delay_ms@plt>
  mov    $0x0,%edi
  call   <serialport_set_dtr@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void board_ck_rb() {
  serialport_set_rts(1);
  serialport_set_dtr(1);
  serialport_send_break();
  espcomm_delay_ms(5);
  serialport_set_rts(0);
  espcomm_delay_ms(250);
  serialport_set_dtr(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<board_ck_rb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <serialport_set_rts@plt>
  mov    $0x1,%edi
  call   <serialport_set_dtr@plt>
  mov    $0x0,%eax
  call   <serialport_send_break@plt>
  mov    $0x5,%edi
  call   <espcomm_delay_ms@plt>
  mov    $0x0,%edi
  call   <serialport_set_rts@plt>
  mov    $0xfa,%edi
  call   <espcomm_delay_ms@plt>
  mov    $0x0,%edi
  call   <serialport_set_dtr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void board_ck_rb() {
  serialport_set_rts(1);
  serialport_set_dtr(1);
  serialport_send_break();
  espcomm_delay_ms(5);
  serialport_set_rts(0);
  espcomm_delay_ms(250);
  serialport_set_dtr(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<board_ck_rb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <serialport_set_rts@plt>
  mov    $0x1,%edi
  call   <serialport_set_dtr@plt>
  xor    %eax,%eax
  call   <serialport_send_break@plt>
  mov    $0x5,%edi
  call   <espcomm_delay_ms@plt>
  xor    %edi,%edi
  call   <serialport_set_rts@plt>
  mov    $0xfa,%edi
  call   <espcomm_delay_ms@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <serialport_set_dtr@plt>
```

assistant: ```c
void board_ck_rb() {
  serialport_set_rts(1);
  serialport_set_dtr(1);
  serialport_send_break();
  espcomm_delay_ms(5);
  serialport_set_rts(0);
  espcomm_delay_ms(250);
  serialport_set_dtr(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<board_ck_rb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <serialport_set_rts@plt>
  mov    $0x1,%edi
  call   <serialport_set_dtr@plt>
  xor    %eax,%eax
  call   <serialport_send_break@plt>
  mov    $0x5,%edi
  call   <espcomm_delay_ms@plt>
  xor    %edi,%edi
  call   <serialport_set_rts@plt>
  mov    $0xfa,%edi
  call   <espcomm_delay_ms@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <serialport_set_dtr@plt>
```

assistant: ```c
void board_ck_rb() {
  serialport_set_rts(1);
  serialport_set_dtr(1);
  serialport_send_break();
  espcomm_delay_ms(5);
  serialport_set_rts(0);
  espcomm_delay_ms(250);
  serialport_set_dtr(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__byte_decode_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L1
  mov    $0xffffffff,%eax
  jmp    L2
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x2c(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int __byte_decode_array(const void *_buf, int offset, int maxlen, uint8_t *p, int elements) {
  if (maxlen < elements)
    return -1;
  uint8_t *buf = (uint8_t *)_buf;
  memcpy(p, &buf[offset], elements);
  return elements;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__byte_decode_array>:
  endbr64
  cmp    %r8d,%edx
  jl     L3
  push   %rbx
  mov    %rdi,%r9
  mov    %rcx,%rdi
  mov    %r8d,%ebx
  movslq %esi,%rsi
  lea    (%r9,%rsi,4),%rsi
  mov    %r8d,%edx
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int __byte_decode_array(const void *_buf, int offset, int maxlen, uint8_t *p, int elements) {
  if (maxlen < elements)
    return -1;
  uint8_t *buf = (uint8_t *)_buf;
  memcpy(p, &buf[offset], elements);
  return elements;
}
```
user: What is the c source code of the assembly code below:

```asm
<__byte_decode_array>:
  endbr64
  cmp    %r8d,%edx
  jl     L5
  push   %rbx
  mov    %rdi,%rax
  movslq %esi,%rsi
  mov    %r8d,%ebx
  mov    %rcx,%rdi
  lea    (%rax,%rsi,4),%rsi
  mov    %r8d,%edx
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int __byte_decode_array(const void *_buf, int offset, int maxlen, uint8_t *p, int elements) {
  if (maxlen < elements)
    return -1;
  uint8_t *buf = (uint8_t *)_buf;
  memcpy(p, &buf[offset], elements);
  return elements;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__byte_decode_array>:
  endbr64
  cmp    %r8d,%edx
  jl     L5
  push   %rbx
  mov    %rdi,%rax
  movslq %esi,%rsi
  mov    %r8d,%ebx
  mov    %rcx,%rdi
  lea    (%rax,%rsi,4),%rsi
  mov    %r8d,%edx
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int __byte_decode_array(const void *_buf, int offset, int maxlen, uint8_t *p, int elements) {
  if (maxlen < elements)
    return -1;
  uint8_t *buf = (uint8_t *)_buf;
  memcpy(p, &buf[offset], elements);
  return elements;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Info_RemoveKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L66
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  je     L66
  mov    $0x1,%eax
  jmp    L88
L66:
  mov    $0x0,%eax
L88:
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  je     L81
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  je     L81
  mov    $0x1,%eax
  jmp    L124
L81:
  mov    $0x0,%eax
L124:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  je     L112
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  je     L112
L139:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Info_FindKey@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L80
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L46
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
L46:
  cmpq   $0x0,-0x10(%rbp)
  jne    L39
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L139
L39:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  jmp    L139
L112:
  nop
  jmp    L96
L80:
  nop
L96:
  leave
  ret
```

assistant: ```c
void Info_RemoveKey(char *info, const char *key) {
  assert(info && Info_Validate(info));
  assert(key && Info_ValidateKey(key));
  if (!Info_Validate(info) || !Info_ValidateKey(key))
    return;
  while (1) {
    char *start, *p;
    p = Info_FindKey(info, key);
    if (!p)
      return;
    start = p;
    p++;
    p = strchr(p, '\\');
    if (p) {
      p++;
      p = strchr(p, '\\');
    }
    if (!p) {
      *start = 0;
    } else {
      memmove(start, p, strlen(p) + 1);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%edi
  test   %rbp,%rbp
  je     L5
  mov    %rbp,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
L5:
  call   <assert@plt>
  mov    $0x0,%edi
  test   %r12,%r12
  je     L50
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
L50:
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  jne    L18
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  je     L2
  jmp    L54
L40:
  movb   $0x0,(%rbx)
L54:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <Info_FindKey@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L40
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L40
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  jmp    L54
```

assistant: ```c
void Info_RemoveKey(char *info, const char *key) {
  assert(info && Info_Validate(info));
  assert(key && Info_ValidateKey(key));
  if (!Info_Validate(info) || !Info_ValidateKey(key))
    return;
  while (1) {
    char *start, *p;
    p = Info_FindKey(info, key);
    if (!p)
      return;
    start = p;
    p++;
    p = strchr(p, '\\');
    if (p) {
      p++;
      p = strchr(p, '\\');
    }
    if (!p) {
      *start = 0;
    } else {
      memmove(start, p, strlen(p) + 1);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  je     L36
  mov    %rbx,%rdi
  call   <Info_Validate@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
L36:
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  je     L51
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
L51:
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  jne    L14
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  je     L5
  nopl   (%rax)
L60:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <Info_FindKey@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L57
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L57
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  jmp    L60
  nopl   (%rax)
L57:
  movb   $0x0,0x0(%rbp)
  jmp    L60
```

assistant: ```c
void Info_RemoveKey(char *info, const char *key) {
  assert(info && Info_Validate(info));
  assert(key && Info_ValidateKey(key));
  if (!Info_Validate(info) || !Info_ValidateKey(key))
    return;
  while (1) {
    char *start, *p;
    p = Info_FindKey(info, key);
    if (!p)
      return;
    start = p;
    p++;
    p = strchr(p, '\\');
    if (p) {
      p++;
      p = strchr(p, '\\');
    }
    if (!p) {
      *start = 0;
    } else {
      memmove(start, p, strlen(p) + 1);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Info_RemoveKey>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rbx,%rbx
  je     L50
  mov    %rbx,%rdi
  call   <Info_Validate@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
L50:
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  je     L32
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
L32:
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <Info_Validate@plt>
  test   %rax,%rax
  jne    L82
L88:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L82:
  mov    %r12,%rdi
  call   <Info_ValidateKey@plt>
  test   %rax,%rax
  je     L88
  nopl   (%rax)
L89:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <Info_FindKey@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L88
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  lea    0x1(%rax),%rdi
  mov    $0x5c,%esi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  jmp    L89
  nopl   (%rax)
L9:
  movb   $0x0,0x0(%rbp)
  jmp    L89
```

assistant: ```c
void Info_RemoveKey(char *info, const char *key) {
  assert(info && Info_Validate(info));
  assert(key && Info_ValidateKey(key));
  if (!Info_Validate(info) || !Info_ValidateKey(key))
    return;
  while (1) {
    char *start, *p;
    p = Info_FindKey(info, key);
    if (!p)
      return;
    start = p;
    p++;
    p = strchr(p, '\\');
    if (p) {
      p++;
      p = strchr(p, '\\');
    }
    if (!p) {
      *start = 0;
    } else {
      memmove(start, p, strlen(p) + 1);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_isquote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x27,-0x4(%rbp)
  je     L6
  cmpl   $0x22,-0x4(%rbp)
  je     L6
  cmpl   $0x60,-0x4(%rbp)
  jne    L10
L6:
  mov    $0x1,%eax
  jmp    L11
L10:
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isquote(int c) {
  if (c == '\'' || c == '"' || c == '`')
    return (1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_isquote>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3e,%ecx
  ja     L8
  movabs $0x4000000000000021,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_isquote(int c) {
  if (c == '\'' || c == '"' || c == '`')
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_isquote>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3e,%ecx
  ja     L4
  movabs $0x4000000000000021,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isquote(int c) {
  if (c == '\'' || c == '"' || c == '`')
    return (1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_isquote>:
  endbr64
  lea    -0x22(%rdi),%ecx
  cmp    $0x3e,%ecx
  ja     L4
  movabs $0x4000000000000021,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isquote(int c) {
  if (c == '\'' || c == '"' || c == '`')
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<solve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
L35:
  movl   $0x2,-0x4(%rbp)
  jmp    L79
L20:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L12
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L12:
  movl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L79:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L20
L57:
  cmpl   $0x0,-0x8(%rbp)
  je     L22
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x2711,-0x10(%rbp)
  jne    L22
  mov    -0xc(%rbp),%eax
  jmp    L48
L22:
  addl   $0x1,-0xc(%rbp)
  jmp    L35
L48:
  leave
  ret
```

assistant: ```c
int solve() {
  int prime_count = 2, number = 2, is_prime = 0;
  while (1) {
    for (int j = 2; j <= sqrt(number); j++) {
      if (number % j == 0) {
        is_prime = 0;
        break;
      } else {
        is_prime = 1;
      }
    }
    if (is_prime) {
      prime_count++;
      if (prime_count == 10001) {
        return number;
      }
    }
    number += 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solve>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  mov    $0x2,%ebp
  mov    $0x2,%r14d
  mov    $0x1,%r13d
  jmp    L47
L13:
  test   %r12d,%r12d
  je     L51
  add    $0x1,%r14d
  cmp    $0x2711,%r14d
  je     L12
L51:
  add    $0x1,%ebp
L47:
  mov    $0x2,%ebx
L38:
  mov    %ebp,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L13
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r12d
  test   %edx,%edx
  je     L51
  add    $0x1,%ebx
  mov    %r13d,%r12d
  jmp    L38
L12:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int solve() {
  int prime_count = 2, number = 2, is_prime = 0;
  while (1) {
    for (int j = 2; j <= sqrt(number); j++) {
      if (number % j == 0) {
        is_prime = 0;
        break;
      } else {
        is_prime = 1;
      }
    }
    if (is_prime) {
      prime_count++;
      if (prime_count == 10001) {
        return number;
      }
    }
    number += 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solve>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L39:
  mov    $0x2,%ebx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L11
  add    $0x1,%ebx
  mov    $0x1,%ebp
L23:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L19
  test   %ebp,%ebp
  je     L11
  cmp    $0x2711,%r13d
  je     L36
  add    $0x1,%r13d
L11:
  add    $0x1,%r12d
  jmp    L39
L36:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve() {
  int prime_count = 2, number = 2, is_prime = 0;
  while (1) {
    for (int j = 2; j <= sqrt(number); j++) {
      if (number % j == 0) {
        is_prime = 0;
        break;
      } else {
        is_prime = 1;
      }
    }
    if (is_prime) {
      prime_count++;
      if (prime_count == 10001) {
        return number;
      }
    }
    number += 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solve>:
  endbr64
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L57:
  mov    $0x2,%ebx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L46
  add    $0x1,%ebx
  mov    $0x1,%ebp
L7:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L48
  test   %ebp,%ebp
  je     L46
  cmp    $0x2711,%r13d
  je     L37
  add    $0x1,%r13d
L46:
  add    $0x1,%r12d
  jmp    L57
L37:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve() {
  int prime_count = 2, number = 2, is_prime = 0;
  while (1) {
    for (int j = 2; j <= sqrt(number); j++) {
      if (number % j == 0) {
        is_prime = 0;
        break;
      } else {
        is_prime = 1;
      }
    }
    if (is_prime) {
      prime_count++;
      if (prime_count == 10001) {
        return number;
      }
    }
    number += 1;
  }
}
```