user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  cmp    $0x22,%eax
  jle    L42
  mov    -0x20(%rbp),%eax
  cmp    $0x22,%eax
  jle    L42
  mov    -0x1c(%rbp),%eax
  cmp    $0x22,%eax
  jle    L42
  mov    -0x18(%rbp),%eax
  cmp    $0x22,%eax
  jle    L42
  mov    -0x14(%rbp),%eax
  cmp    $0x22,%eax
  jle    L42
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x4f,-0xc(%rbp)
  jle    L17
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L17:
  cmpl   $0x3b,-0xc(%rbp)
  jle    L54
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L54:
  cmpl   $0x2c,-0xc(%rbp)
  jle    L112
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L112:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L85
L42:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L85:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D71
type_guessed: string
name: disassemble_data
arguments: data_tag: D43
type_guessed: string
name: disassemble_data
arguments: data_tag: D63
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D47
type_guessed: string
name: disassemble_data
arguments: data_tag: D60
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D35
type_guessed: string

tool: D71: Enter the marks of subjects: English, Nepali, Foit, Education, C programming respectively

tool: D43: %d %d %d %d %d

tool: D63: 
Congrats, You are passed in 

tool: D14: Distinction with percentage %d

tool: D47: 1st Division with percentage %d

tool: D60: 2nd Division with percentage %d

tool: D2: 3rd Division with percentage %d

tool: D35: 
Sorry, You are failed !

assistant: ```c
int main(void) {
  int e, n, f, ed, c, tot, per;
  printf("Enter the marks of subjects: English, Nepali, Foit, Education, C programming respectively\n");
  scanf("%d %d %d %d %d", &e, &n, &f, &ed, &c);
  if (e >= 35 && n >= 35 && f >= 35 && ed >= 35 && c >= 35) {
    tot = e + n + f + ed + c;
    per = tot / 5;
    printf("\nCongrats, You are passed in ");
    if (per >= 80)
      printf("Distinction with percentage %d", per);
    else if (per >= 60)
      printf("1st Division with percentage %d", per);
    else if (per >= 45)
      printf("2nd Division with percentage %d", per);
    else
      printf("3rd Division with percentage %d", per);
  } else
    printf("\nSorry, You are failed !");
  return 0;
}
```