ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<splitStringIntoArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L9
L13:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L9:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
L27:
  nop
  leave
  ret
```

assistant: ```c
void splitStringIntoArray(char *src, char *dest[], const char *delimiters) {
  int ct = 0;
  char *token = strtok(src, delimiters);
  if (token != NULL) {
    dest[ct++] = token;
    while ((token = strtok(NULL, delimiters)) != NULL) {
      dest[ct++] = token;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<splitStringIntoArray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <strtok@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  jmp    L8
L5:
  mov    %rax,(%rbx)
  add    $0x8,%rbx
L8:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  test   %rax,%rax
  jne    L5
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void splitStringIntoArray(char *src, char *dest[], const char *delimiters) {
  int ct = 0;
  char *token = strtok(src, delimiters);
  if (token != NULL) {
    dest[ct++] = token;
    while ((token = strtok(NULL, delimiters)) != NULL) {
      dest[ct++] = token;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<splitStringIntoArray>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L5
  nopl   (%rax)
L10:
  mov    %rax,(%rbx)
  xor    %edi,%edi
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <strtok@plt>
  test   %rax,%rax
  jne    L10
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void splitStringIntoArray(char *src, char *dest[], const char *delimiters) {
  int ct = 0;
  char *token = strtok(src, delimiters);
  if (token != NULL) {
    dest[ct++] = token;
    while ((token = strtok(NULL, delimiters)) != NULL) {
      dest[ct++] = token;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<splitStringIntoArray>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L3
  nopl   (%rax)
L1:
  mov    %rax,(%rbx)
  xor    %edi,%edi
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <strtok@plt>
  test   %rax,%rax
  jne    L1
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void splitStringIntoArray(char *src, char *dest[], const char *delimiters) {
  int ct = 0;
  char *token = strtok(src, delimiters);
  if (token != NULL) {
    dest[ct++] = token;
    while ((token = strtok(NULL, delimiters)) != NULL) {
      dest[ct++] = token;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xstrndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <die@plt>
L1:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: bug in xstrndup call

assistant: ```c
char *xstrndup(const char *s, int n) {
  char *t;
  if (s == NULL)
    die(4, ("bug in xstrndup call"));
  t = xmalloc(n + 1);
  strncpy(t, s, n);
  t[n] = 0;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  test   %rdi,%rdi
  je     L4
L7:
  lea    0x1(%rbx),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  lea    D0(%rip),%rsi
  mov    $0x4,%edi
  call   <die@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: bug in xstrndup call

assistant: ```c
char *xstrndup(const char *s, int n) {
  char *t;
  if (s == NULL)
    die(4, ("bug in xstrndup call"));
  t = xmalloc(n + 1);
  strncpy(t, s, n);
  t[n] = 0;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  test   %rdi,%rdi
  je     L13
L6:
  lea    0x1(%rbx),%edi
  call   <xmalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  lea    D5(%rip),%rsi
  mov    $0x4,%edi
  call   <die@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: bug in xstrndup call

assistant: ```c
char *xstrndup(const char *s, int n) {
  char *t;
  if (s == NULL)
    die(4, ("bug in xstrndup call"));
  t = xmalloc(n + 1);
  strncpy(t, s, n);
  t[n] = 0;
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xstrndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  test   %rdi,%rdi
  je     L1
L12:
  lea    0x1(%rbx),%edi
  call   <xmalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D3(%rip),%rsi
  mov    $0x4,%edi
  call   <die@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: bug in xstrndup call

assistant: ```c
char *xstrndup(const char *s, int n) {
  char *t;
  if (s == NULL)
    die(4, ("bug in xstrndup call"));
  t = xmalloc(n + 1);
  strncpy(t, s, n);
  t[n] = 0;
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<onion_shortcut_etag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    %edx,%r8d
  lea    D6(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: %04X-%04X

assistant: ```c
void onion_shortcut_etag(struct stat *st, char etag[32]) {
  size_t size = st->st_size;
  unsigned int time = st->st_mtime;
  snprintf(etag, 32, "%04X-%04X", (int32_t)size, (int32_t)time);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<onion_shortcut_etag>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    0x8(%rax),%r8d
  mov    (%rax),%ecx
  lea    D1(%rip),%rdx
  mov    $0x20,%esi
  call   <snprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: %04X-%04X

assistant: ```c
void onion_shortcut_etag(struct stat *st, char etag[32]) {
  size_t size = st->st_size;
  unsigned int time = st->st_mtime;
  snprintf(etag, 32, "%04X-%04X", (int32_t)size, (int32_t)time);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<onion_shortcut_etag>:
  endbr64
  mov    %rdi,%rax
  lea    D5(%rip),%rdx
  mov    %rsi,%rdi
  mov    $0x20,%esi
  mov    0x8(%rax),%r8d
  mov    (%rax),%ecx
  jmp    1050 <snprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: D5: %04X-%04X

assistant: ```c
void onion_shortcut_etag(struct stat *st, char etag[32]) {
  size_t size = st->st_size;
  unsigned int time = st->st_mtime;
  snprintf(etag, 32, "%04X-%04X", (int32_t)size, (int32_t)time);
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<onion_shortcut_etag>:
  endbr64
  mov    %rdi,%rax
  lea    D0(%rip),%rdx
  mov    %rsi,%rdi
  mov    $0x20,%esi
  mov    0x8(%rax),%r8d
  mov    (%rax),%ecx
  jmp    1050 <snprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: %04X-%04X

assistant: ```c
void onion_shortcut_etag(struct stat *st, char etag[32]) {
  size_t size = st->st_size;
  unsigned int time = st->st_mtime;
  snprintf(etag, 32, "%04X-%04X", (int32_t)size, (int32_t)time);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x1,%edi
  call   <assert@plt>
  cmpl   $0x7,-0x24(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L1
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L22:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L22
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L1:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L25
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L40
L25:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
L40:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= (int)sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list_alloc_aux>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x1,%edi
  call   <assert@plt>
  cmp    $0x7,%ebp
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L12
L13:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
L69:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %ebp,%edi
  shl    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L66
  mov    %ebp,%edx
  shl    $0x5,%edx
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L61
  movslq %ebp,%rbp
L25:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rax,%rdx
  ja     L25
L61:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L31
L66:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  jmp    L69
L31:
  mov    %rax,%r12
  jmp    L13
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= (int)sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<list_alloc_aux>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L56
L33:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L56:
  mov    %ebp,%r13d
  shl    $0x5,%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L17
  sub    %ebp,%r13d
  movslq %r13d,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L18
  nopl   (%rax)
L19:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rdx,%rax
  jb     L19
L18:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L55
L17:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  mov    %rax,%r12
  jmp    L33
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= (int)sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_alloc_aux>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L13
L8:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  mov    %ebp,%r13d
  shl    $0x5,%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L54
  sub    %ebp,%r13d
  movslq %r13d,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L37
  nopl   (%rax)
L17:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rdx,%rax
  jb     L17
L37:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L7
L54:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %rax,%r12
  jmp    L8
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= (int)sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_show_wordtab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L39
L17:
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L32
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
L32:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int my_show_wordtab(char **tab) {
  int lp;
  if (tab == NULL)
    return (0);
  lp = -1;
  while (tab[++lp] != 0) {
    my_putstr(tab[lp]);
    my_putchar('\n');
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_show_wordtab>:
  endbr64
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L12
  push   %rbx
  lea    0x8(%rax),%rbx
L27:
  call   <my_putstr@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L27
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int my_show_wordtab(char **tab) {
  int lp;
  if (tab == NULL)
    return (0);
  lp = -1;
  while (tab[++lp] != 0) {
    my_putstr(tab[lp]);
    my_putchar('\n');
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_show_wordtab>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    (%rdi),%r8
  test   %r8,%r8
  je     L5
  push   %rbx
  lea    0x8(%rdi),%rbx
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %r8,%rdi
  add    $0x8,%rbx
  call   <my_putstr@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    -0x8(%rbx),%r8
  test   %r8,%r8
  jne    L25
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_show_wordtab(char **tab) {
  int lp;
  if (tab == NULL)
    return (0);
  lp = -1;
  while (tab[++lp] != 0) {
    my_putstr(tab[lp]);
    my_putchar('\n');
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_show_wordtab>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    (%rdi),%r8
  test   %r8,%r8
  je     L4
  push   %rbx
  lea    0x8(%rdi),%rbx
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r8,%rdi
  add    $0x8,%rbx
  call   <my_putstr@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  mov    -0x8(%rbx),%r8
  test   %r8,%r8
  jne    L21
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int my_show_wordtab(char **tab) {
  int lp;
  if (tab == NULL)
    return (0);
  lp = -1;
  while (tab[++lp] != 0) {
    my_putstr(tab[lp]);
    my_putchar('\n');
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L6:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *x, int c, size_t n) {
  unsigned char *b = x;
  unsigned char *e = b + n;
  while (b != e)
    *b++ = c;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  je     L1
  mov    %rdi,%rcx
L16:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L16
L1:
  ret
```

assistant: ```c
void *memset(void *x, int c, size_t n) {
  unsigned char *b = x;
  unsigned char *e = b + n;
  while (b != e)
    *b++ = c;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L2
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *x, int c, size_t n) {
  unsigned char *b = x;
  unsigned char *e = b + n;
  while (b != e)
    *b++ = c;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L0
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *x, int c, size_t n) {
  unsigned char *b = x;
  unsigned char *e = b + n;
  while (b != e)
    *b++ = c;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_estop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %esi,-0xe8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xe8(%rbp),%ecx
  mov    -0xe8(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x0,%eax
  call   <get_current_time@plt>
  mov    %rax,%rsi
  mov    -0xe8(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movb   $0xa,-0xcb(%rbp)
  movb   $0x0,-0xca(%rbp)
  movb   $0x0,-0xc9(%rbp)
  lea    -0xd0(%rbp),%rax
  mov    %rax,-0xd8(%rbp)
  jmp    L9
L18:
  mov    -0xd8(%rbp),%rcx
  mov    -0xe4(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    $0x64,%edi
  call   <usleep@plt>
  addq   $0x1,-0xd8(%rbp)
L9:
  mov    -0xd8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D1
type: string

tool: D5: E%02X%02X

tool: D1: %s : estop command = %5s (%d)

assistant: ```c
int set_estop(int fd, int c) {
  char obuf[10];
  char bbuf[200];
  char *p;
  sprintf(obuf, "E%02X%02X", c, c);
  printf("%s : estop command = %5s (%d)", get_current_time(), obuf, c);
  obuf[5] = 10;
  obuf[6] = 0;
  obuf[7] = 0;
  p = &obuf[0];
  while (*p != 0) {
    write(fd, p, 1);
    usleep(100);
    p++;
  }
  return (0);
}
```