ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compute_multiplier_accumulator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <combine_multiplier_accumulator@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x4a,%esi
  mov    %rax,%rdi
  call   <signed_byte_value@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long compute_multiplier_accumulator(struct program_counter *pc) {
  int *combined = combine_multiplier_accumulator(pc);
  long long output = signed_byte_value(combined, 38 + 36);
  free(combined);
  return output;
}
```
user: What is the c source code of the assembly code below:

```asm
<compute_multiplier_accumulator>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <combine_multiplier_accumulator@plt>
  mov    %rax,%rbx
  mov    $0x4a,%esi
  mov    %rax,%rdi
  call   <signed_byte_value@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long compute_multiplier_accumulator(struct program_counter *pc) {
  int *combined = combine_multiplier_accumulator(pc);
  long long output = signed_byte_value(combined, 38 + 36);
  free(combined);
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_multiplier_accumulator>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <combine_multiplier_accumulator@plt>
  mov    $0x4a,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <signed_byte_value@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long compute_multiplier_accumulator(struct program_counter *pc) {
  int *combined = combine_multiplier_accumulator(pc);
  long long output = signed_byte_value(combined, 38 + 36);
  free(combined);
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_multiplier_accumulator>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <combine_multiplier_accumulator@plt>
  mov    $0x4a,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <signed_byte_value@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long compute_multiplier_accumulator(struct program_counter *pc) {
  int *combined = combine_multiplier_accumulator(pc);
  long long output = signed_byte_value(combined, 38 + 36);
  free(combined);
  return output;
}
```
user: What is the c source code of the assembly code below?

```asm
<t2t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void t2t(double *x, double *y) {
  y[0] = x[0];
  y[1] = x[1];
  y[2] = x[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t2t>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void t2t(double *x, double *y) {
  y[0] = x[0];
  y[1] = x[1];
  y[2] = x[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<t2t>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void t2t(double *x, double *y) {
  y[0] = x[0];
  y[1] = x[1];
  y[2] = x[2];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<t2t>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  ret
```

assistant: ```c
void t2t(double *x, double *y) {
  y[0] = x[0];
  y[1] = x[1];
  y[2] = x[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <venprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void eprintf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  venprintf(1, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <venprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void eprintf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  venprintf(1, fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<eprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <venprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void eprintf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  venprintf(1, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <venprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void eprintf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  venprintf(1, fmt, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<edid_is_ascii_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0xfe,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
  mov    $0x1,%eax
  jmp    L44
L50:
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int edid_is_ascii_block(unsigned char *block) {
  if ((block[0] == 0x00) && (block[1] == 0x00) && (block[2] == 0x00) && (block[3] == 0xfe) && (block[4] == 0x00))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<edid_is_ascii_block>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L5
  cmpb   $0x0,0x1(%rdi)
  jne    L5
  cmpb   $0x0,0x2(%rdi)
  jne    L5
  cmpb   $0xfe,0x3(%rdi)
  jne    L5
  cmpb   $0x0,0x4(%rdi)
  sete   %al
  movzbl %al,%eax
L5:
  ret
```

assistant: ```c
int edid_is_ascii_block(unsigned char *block) {
  if ((block[0] == 0x00) && (block[1] == 0x00) && (block[2] == 0x00) && (block[3] == 0xfe) && (block[4] == 0x00))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<edid_is_ascii_block>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L13
  cmpb   $0x0,0x1(%rdi)
  jne    L13
  cmpb   $0x0,0x2(%rdi)
  jne    L13
  cmpb   $0xfe,0x3(%rdi)
  jne    L13
  xor    %eax,%eax
  cmpb   $0x0,0x4(%rdi)
  sete   %al
L13:
  ret
```

assistant: ```c
int edid_is_ascii_block(unsigned char *block) {
  if ((block[0] == 0x00) && (block[1] == 0x00) && (block[2] == 0x00) && (block[3] == 0xfe) && (block[4] == 0x00))
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<edid_is_ascii_block>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L24
  cmpb   $0x0,0x1(%rdi)
  jne    L24
  cmpb   $0x0,0x2(%rdi)
  jne    L24
  cmpb   $0xfe,0x3(%rdi)
  jne    L24
  xor    %eax,%eax
  cmpb   $0x0,0x4(%rdi)
  sete   %al
L24:
  ret
```

assistant: ```c
int edid_is_ascii_block(unsigned char *block) {
  if ((block[0] == 0x00) && (block[1] == 0x00) && (block[2] == 0x00) && (block[3] == 0xfe) && (block[4] == 0x00))
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *zalloc(size_t len) {
  void *ptr = malloc(len);
  if (ptr)
    memset(ptr, 0, len);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *zalloc(size_t len) {
  void *ptr = malloc(len);
  if (ptr)
    memset(ptr, 0, len);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *zalloc(size_t len) {
  void *ptr = malloc(len);
  if (ptr)
    memset(ptr, 0, len);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zalloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *zalloc(size_t len) {
  void *ptr = malloc(len);
  if (ptr)
    memset(ptr, 0, len);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4c0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,-0x4c8(%rbp)
L142:
  lea    -0x4c8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4c8(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4cc(%rbp)
  mov    -0x4c8(%rbp),%eax
  cmp    $0x1,%eax
  jle    L87
  mov    -0x4c8(%rbp),%eax
  cmp    $0xc8,%eax
  jle    L1
L87:
  mov    -0x4cc(%rbp),%eax
  test   %eax,%eax
  jne    L142
L1:
  movl   $0x0,-0x4c4(%rbp)
  jmp    L35
L130:
  lea    -0x4cc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x4cc(%rbp),%eax
  test   %eax,%eax
  jle    L154
  mov    -0x4cc(%rbp),%eax
  cmp    $0x64,%eax
  jg     L154
  mov    -0x4cc(%rbp),%edx
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    %edx,-0x330(%rbp,%rax,4)
L154:
  addl   $0x1,-0x4c4(%rbp)
L35:
  mov    -0x4c8(%rbp),%eax
  cmp    %eax,-0x4c4(%rbp)
  jl     L130
  movl   $0x0,-0x4c4(%rbp)
  jmp    L17
L19:
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  movslq %eax,%rdx
  mov    -0x4c0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x4c0(%rbp,%rax,4)
  addl   $0x1,-0x4c4(%rbp)
L17:
  mov    -0x4c8(%rbp),%eax
  cmp    %eax,-0x4c4(%rbp)
  jl     L19
  movl   $0x0,-0x4cc(%rbp)
  jmp    L127
L116:
  mov    -0x4cc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4cc(%rbp)
L127:
  mov    -0x4cc(%rbp),%eax
  cmp    $0x63,%eax
  jg     L156
  mov    -0x4cc(%rbp),%eax
  cltq
  mov    -0x4c0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L116
L156:
  movl   $0x0,-0x4c4(%rbp)
  jmp    L77
L56:
  addl   $0x1,-0x4c4(%rbp)
L77:
  cmpl   $0xc7,-0x4c4(%rbp)
  jg     L45
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%edx
  mov    -0x4cc(%rbp),%eax
  cmp    %eax,%edx
  jne    L56
L45:
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L93
  call   <__stack_chk_fail@plt>
L93:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string

tool: D14: %d

tool: D28: 
%d

assistant: ```c
int main() {
  int num[200], inum[100] = {0};
  int i, j, br;
  br = 1;
  do {
    scanf("%d", &br);
    j = br % 2;
  } while ((br < 2 || br > 200) && j);
  for (i = 0; i < br; i++) {
    scanf("%d", &j);
    if (j > 0 && j <= 100) {
      num[i] = j;
    }
  }
  for (i = 0; i < br; i++) {
    inum[num[i]]++;
  }
  j = 0;
  while (j < 100 && inum[j] != 1) {
    j++;
  }
  i = 0;
  while (i < 200 && num[i] != j) {
    i++;
  };
  printf("\n%d", num[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0xc(%rsp)
  lea    D7(%rip),%rbp
L54:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,0x8(%rsp)
  lea    -0x2(%rdx),%eax
  cmp    $0xc6,%eax
  jbe    L28
  test   $0x1,%dl
  jne    L54
L28:
  mov    $0x0,%ebp
  lea    D7(%rip),%r12
  test   %edx,%edx
  jg     L82
  jmp    L145
L4:
  mov    0xc(%rsp),%edx
  add    $0x1,%rbp
  cmp    %ebp,%edx
  jle    L166
L82:
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L4
  mov    %eax,0x1a0(%rsp,%rbp,4)
  jmp    L4
L166:
  test   %edx,%edx
  jle    L145
  lea    0x1a0(%rsp),%rax
  lea    -0x1(%rdx),%edx
  lea    0x1a4(%rsp,%rdx,4),%rcx
L156:
  movslq (%rax),%rdx
  addl   $0x1,0x10(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L156
L145:
  movl   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdx
  mov    $0x0,%ecx
  mov    $0x0,%eax
  mov    $0x1,%esi
L91:
  cmpl   $0x1,(%rdx)
  je     L88
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    %esi,%ecx
  cmp    $0x64,%eax
  je     L80
  mov    %eax,%ebx
  jmp    L91
L80:
  movl   $0x64,0x8(%rsp)
L46:
  lea    0x1a0(%rsp),%rcx
  mov    $0x0,%edx
L92:
  cmp    %eax,(%rcx)
  je     L56
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    $0xc8,%edx
  jne    L92
L56:
  movslq %edx,%rdx
  mov    0x1a0(%rsp,%rdx,4),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x4d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L88:
  test   %cl,%cl
  je     L46
  mov    %ebx,0x8(%rsp)
  jmp    L46
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D2
data_type: string

tool: D7: %d

tool: D2: 
%d

assistant: ```c
int main() {
  int num[200], inum[100] = {0};
  int i, j, br;
  br = 1;
  do {
    scanf("%d", &br);
    j = br % 2;
  } while ((br < 2 || br > 200) && j);
  for (i = 0; i < br; i++) {
    scanf("%d", &j);
    if (j > 0 && j <= 100) {
      num[i] = j;
    }
  }
  for (i = 0; i < br; i++) {
    inum[num[i]]++;
  }
  j = 0;
  while (j < 100 && inum[j] != 1) {
    j++;
  }
  i = 0;
  while (i < 200 && num[i] != j) {
    i++;
  };
  printf("\n%d", num[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x32,%ecx
  push   %r14
  push   %r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  movl   $0x1,0xc(%rsp)
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L167
  xchg   %ax,%ax
L101:
  test   $0x1,%dl
  je     L61
L167:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,0x8(%rsp)
  lea    -0x2(%rdx),%eax
  cmp    $0xc6,%eax
  ja     L101
  xor    %r14d,%r14d
L11:
  lea    0x8(%rsp),%r15
  lea    0x1a0(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L142:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L169
  mov    %eax,(%rbx,%r14,4)
L169:
  mov    0xc(%rsp),%edx
  add    $0x1,%r14
  cmp    %r14d,%edx
  jg     L142
  test   %edx,%edx
  jle    L141
  sub    $0x1,%edx
  mov    %rbx,%rax
  lea    0x1a4(%rsp,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L148:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0x10(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L148
L141:
  movl   $0x0,0x8(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L109
  nopw   0x0(%rax,%rax,1)
L130:
  add    $0x1,%esi
  add    $0x4,%rbp
  mov    $0x1,%eax
  cmp    $0x64,%esi
  je     L18
  mov    %esi,%r13d
L109:
  cmpl   $0x1,0x0(%rbp)
  jne    L130
  test   %al,%al
  je     L8
  mov    %r13d,0x8(%rsp)
L8:
  mov    %rbx,%rax
  lea    0x4c0(%rsp),%rdx
  jmp    L58
L187:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L149
L58:
  cmp    %esi,(%rax)
  jne    L187
L41:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x4d8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  xor    %r14d,%r14d
  test   %edx,%edx
  jg     L11
  lea    0x1a0(%rsp),%rbx
  jmp    L141
L18:
  movl   $0x64,0x8(%rsp)
  jmp    L8
L149:
  mov    0x4c0(%rsp),%esi
  jmp    L41
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D13: %d

tool: D11: 
%d

assistant: ```c
int main() {
  int num[200], inum[100] = {0};
  int i, j, br;
  br = 1;
  do {
    scanf("%d", &br);
    j = br % 2;
  } while ((br < 2 || br > 200) && j);
  for (i = 0; i < br; i++) {
    scanf("%d", &j);
    if (j > 0 && j <= 100) {
      num[i] = j;
    }
  }
  for (i = 0; i < br; i++) {
    inum[num[i]]++;
  }
  j = 0;
  while (j < 100 && inum[j] != 1) {
    j++;
  }
  i = 0;
  while (i < 200 && num[i] != j) {
    i++;
  };
  printf("\n%d", num[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x32,%ecx
  push   %r14
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  movl   $0x1,0xc(%rsp)
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L100
  xchg   %ax,%ax
L106:
  test   $0x1,%dl
  je     L19
L100:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,0x8(%rsp)
  lea    -0x2(%rdx),%eax
  cmp    $0xc6,%eax
  ja     L106
  xor    %r14d,%r14d
L145:
  lea    0x8(%rsp),%r15
  lea    0x1a0(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L200:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L207
  mov    0xc(%rsp),%edx
  mov    %eax,(%rbx,%r14,4)
  add    $0x1,%r14
  cmp    %r14d,%edx
  jg     L200
L98:
  test   %edx,%edx
  jle    L122
  sub    $0x1,%edx
  mov    %rbx,%rax
  lea    0x1a4(%rsp,%rdx,4),%rcx
  cs nopw 0x0(%rax,%rax,1)
L161:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0x10(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L161
L122:
  movl   $0x0,0x8(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  jmp    L105
  nop
L73:
  add    $0x1,%esi
  add    $0x4,%rbp
  mov    $0x1,%eax
  cmp    $0x64,%esi
  je     L186
  mov    %esi,%r13d
L105:
  cmpl   $0x1,0x0(%rbp)
  jne    L73
  test   %al,%al
  je     L37
  mov    %r13d,0x8(%rsp)
L37:
  mov    %rbx,%rax
  lea    0x4c0(%rsp),%rdx
  jmp    L15
  nopl   0x0(%rax)
L10:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L68
L15:
  cmp    %esi,(%rax)
  jne    L10
L44:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x4d8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L207:
  mov    0xc(%rsp),%edx
  add    $0x1,%r14
  cmp    %r14d,%edx
  jg     L200
  jmp    L98
L19:
  xor    %r14d,%r14d
  test   %edx,%edx
  jg     L145
  lea    0x1a0(%rsp),%rbx
  jmp    L122
L186:
  movl   $0x64,0x8(%rsp)
  jmp    L37
L68:
  mov    0x4c0(%rsp),%esi
  jmp    L44
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D6: %d

tool: D5: 
%d

assistant: ```c
int main() {
  int num[200], inum[100] = {0};
  int i, j, br;
  br = 1;
  do {
    scanf("%d", &br);
    j = br % 2;
  } while ((br < 2 || br > 200) && j);
  for (i = 0; i < br; i++) {
    scanf("%d", &j);
    if (j > 0 && j <= 100) {
      num[i] = j;
    }
  }
  for (i = 0; i < br; i++) {
    inum[num[i]]++;
  }
  j = 0;
  while (j < 100 && inum[j] != 1) {
    j++;
  }
  i = 0;
  while (i < 200 && num[i] != j) {
    i++;
  };
  printf("\n%d", num[i]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_invite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D10: USER

tool: D6: %s@sh07 > 

assistant: ```c
void show_invite() {
  char *username = getenv("USER");
  printf("%s@sh07 > ", username);
}
```