ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printDiff>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  lea    D8(%rip),%rdi
  mov    %rsi,0x28(%rsp)
  mov    %r8d,%esi
  mov    %r8d,0x10(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  cvttss2si 0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L20
  movslq %ebp,%rax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L68:
  mov    %r12d,0x14(%rsp)
  test   %ebx,%ebx
  jle    L19
  mov    0x20(%rsp),%rax
  lea    0x0(,%r12,4),%rcx
  lea    (%rax,%rcx,1),%r13
  mov    0x28(%rsp),%rax
  lea    (%rax,%rcx,1),%r14
  xor    %eax,%eax
  mov    %r14,%r15
  mov    %eax,%r14d
  jmp    L4
  nopl   0x0(%rax)
L30:
  add    $0x1,%ebp
L32:
  add    $0x1,%r14d
  add    $0x1f40,%r13
  add    $0x1f40,%r15
  cmp    %r14d,%ebx
  je     L19
L4:
  movss  0x0(%r13),%xmm0
  subss  (%r15),%xmm0
  call   <fabs@plt>
  comiss 0xc(%rsp),%xmm0
  jbe    L32
  cmp    %ebp,0x10(%rsp)
  jle    L30
  mov    0x14(%rsp),%edx
  pxor   %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x0(%r13),%xmm3
  cvtss2sd %xmm0,%xmm2
  mov    %r14d,%esi
  movapd %xmm3,%xmm0
  lea    D14(%rip),%rdi
  mov    $0x3,%eax
  cvtss2sd (%r15),%xmm1
  call   <printf@plt>
  jmp    L30
L19:
  add    $0x1,%r12
  cmp    0x18(%rsp),%r12
  jne    L68
L46:
  add    $0x38,%rsp
  mov    %ebp,%esi
  mov    $0x3d0900,%edx
  xor    %eax,%eax
  pop    %rbx
  lea    D37(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
L20:
  xor    %ebp,%ebp
  jmp    L46
```

tool_calls: name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D34
data_type: string
name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D37
data_type: string

tool: D8: Listing first %d.

tool: D34:  Differences > %.6f...


tool: D14:     Loc(%d,%d)	CPU=%.5f	GPU=%.5f	Diff=%.6f


tool: D37:  
  Total Errors = %d of %d



assistant: ```c
void printDiff(float data1[2000][2000], float data2[2000][2000], int width, int height, int iListLength, float fListTol) {
  printf("Listing first %d.", iListLength);
  printf(" Differences > %.6f...\n", fListTol);
  int i, j;
  int error_count = 0;
  for (j = 0; j < height; j++) {
    for (i = 0; i < width; i++) {
      float fDiff = fabs(data1[i][j] - data2[i][j]);
      if (fDiff > fListTol) {
        if (error_count < iListLength) {
          printf("    Loc(%d,%d)\tCPU=%.5f\tGPU=%.5f\tDiff=%.6f\n", i, j, data1[i][j], data2[i][j], fDiff);
        }
        error_count++;
      }
    }
  }
  printf(" \n  Total Errors = %d of %d\n\n", error_count, 2000 * 2000);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<name_allowed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  jne    L2
  mov    $0x1,%eax
  jmp    L26
L2:
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hash_table_get@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int name_allowed(const struct hash_table *ht, const char *b, const char *e) {
  char *copy;
  if (!ht)
    return 1;
  do {
    const char *BTA_beg = (b);
    int BTA_len = (e)-BTA_beg;
    char **BTA_dest = &(copy);
    *BTA_dest = alloca(BTA_len + 1);
    memcpy(*BTA_dest, BTA_beg, BTA_len);
    (*BTA_dest)[BTA_len] = '\0';
  } while (0);
  return hash_table_get(ht, copy) != NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<name_allowed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  sub    %rsi,%rbx
  lea    0x1(%rbx),%edi
  call   <alloca@plt>
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <hash_table_get@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L1:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int name_allowed(const struct hash_table *ht, const char *b, const char *e) {
  char *copy;
  if (!ht)
    return 1;
  do {
    const char *BTA_beg = (b);
    int BTA_len = (e)-BTA_beg;
    char **BTA_dest = &(copy);
    *BTA_dest = alloca(BTA_len + 1);
    memcpy(*BTA_dest, BTA_beg, BTA_len);
    (*BTA_dest)[BTA_len] = '\0';
  } while (0);
  return hash_table_get(ht, copy) != NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<name_allowed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L1
  mov    %rdx,%rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  sub    %rsi,%rbx
  lea    0x1(%rbx),%edi
  call   <alloca@plt>
  mov    %ebx,%edx
  mov    %r13,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <hash_table_get@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L1:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int name_allowed(const struct hash_table *ht, const char *b, const char *e) {
  char *copy;
  if (!ht)
    return 1;
  do {
    const char *BTA_beg = (b);
    int BTA_len = (e)-BTA_beg;
    char **BTA_dest = &(copy);
    *BTA_dest = alloca(BTA_len + 1);
    memcpy(*BTA_dest, BTA_beg, BTA_len);
    (*BTA_dest)[BTA_len] = '\0';
  } while (0);
  return hash_table_get(ht, copy) != NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<name_allowed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L7
  mov    %rdx,%rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  sub    %rsi,%rbx
  lea    0x1(%rbx),%edi
  call   <alloca@plt>
  mov    %ebx,%edx
  mov    %r13,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <hash_table_get@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L7:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int name_allowed(const struct hash_table *ht, const char *b, const char *e) {
  char *copy;
  if (!ht)
    return 1;
  do {
    const char *BTA_beg = (b);
    int BTA_len = (e)-BTA_beg;
    char **BTA_dest = &(copy);
    *BTA_dest = alloca(BTA_len + 1);
    memcpy(*BTA_dest, BTA_beg, BTA_len);
    (*BTA_dest)[BTA_len] = '\0';
  } while (0);
  return hash_table_get(ht, copy) != NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<realloc_or_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <report_error_and_die@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string

tool: D4: failed to realloc

assistant: ```c
void *realloc_or_die(void *ptr, size_t size) {
  void *p = realloc(ptr, size);
  if (!p)
    report_error_and_die("failed to realloc");
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<realloc_or_die>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L0:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  lea    D1(%rip),%rdi
  call   <report_error_and_die@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: failed to realloc

assistant: ```c
void *realloc_or_die(void *ptr, size_t size) {
  void *p = realloc(ptr, size);
  if (!p)
    report_error_and_die("failed to realloc");
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<realloc_or_die>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L4:
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  lea    D5(%rip),%rdi
  call   <report_error_and_die@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: failed to realloc

assistant: ```c
void *realloc_or_die(void *ptr, size_t size) {
  void *p = realloc(ptr, size);
  if (!p)
    report_error_and_die("failed to realloc");
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<realloc_or_die>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L8:
  mov    %r12,%rax
  pop    %r12
  ret
L7:
  lea    D6(%rip),%rdi
  call   <report_error_and_die@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: failed to realloc

assistant: ```c
void *realloc_or_die(void *ptr, size_t size) {
  void *p = realloc(ptr, size);
  if (!p)
    report_error_and_die("failed to realloc");
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    $0x0,%eax
  call   <rnd@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rnd@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <log@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: byte[8]
name: parse_data
arguments: label: D7
type_infered: f64

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D7: 6.283185307179586

assistant: ```c
double normal(double av, double st) {
  float r1, r2, z1, z2;
  r1 = rnd();
  r2 = rnd();
  z1 = sqrt(-2. * log(r1));
  z2 = sin(6.283185307179586 * r2);
  return st * z1 * z2 + av;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normal>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  mov    $0x0,%eax
  call   <rnd@plt>
  movss  %xmm0,0x8(%rsp)
  mov    $0x0,%eax
  call   <rnd@plt>
  movss  %xmm0,0xc(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D14(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movss  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  mulsd  D5(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rsp),%xmm1
  movq   %r14,%xmm2
  mulsd  %xmm2,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  addsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D5
type_infered: f64

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D5: 6.283185307179586

assistant: ```c
double normal(double av, double st) {
  float r1, r2, z1, z2;
  r1 = rnd();
  r2 = rnd();
  z1 = sqrt(-2. * log(r1));
  z2 = sin(6.283185307179586 * r2);
  return st * z1 * z2 + av;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<normal>:
  endbr64
  sub    $0x28,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <rnd@plt>
  xor    %eax,%eax
  movss  %xmm0,0x18(%rsp)
  call   <rnd@plt>
  movss  0x18(%rsp),%xmm1
  movss  %xmm0,0x1c(%rsp)
  movaps %xmm1,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm2
  movss  %xmm0,0x18(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D12(%rip),%xmm0
  call   <sin@plt>
  movss  0x18(%rsp),%xmm3
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  mulsd  0x10(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: byte[8]
name: unpack_data
arguments: tag: D12
datatype: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D12: 6.283185307179586

assistant: ```c
double normal(double av, double st) {
  float r1, r2, z1, z2;
  r1 = rnd();
  r2 = rnd();
  z1 = sqrt(-2. * log(r1));
  z2 = sin(6.283185307179586 * r2);
  return st * z1 * z2 + av;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<normal>:
  endbr64
  sub    $0x28,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <rnd@plt>
  xor    %eax,%eax
  movss  %xmm0,0x18(%rsp)
  call   <rnd@plt>
  movss  0x18(%rsp),%xmm1
  movss  %xmm0,0x1c(%rsp)
  movaps %xmm1,%xmm0
  call   <log@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm2
  movss  %xmm0,0x18(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D6(%rip),%xmm0
  call   <sin@plt>
  movss  0x18(%rsp),%xmm3
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  mulsd  0x10(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
datatype: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D6: 6.283185307179586

assistant: ```c
double normal(double av, double st) {
  float r1, r2, z1, z2;
  r1 = rnd();
  r2 = rnd();
  z1 = sqrt(-2. * log(r1));
  z2 = sin(6.283185307179586 * r2);
  return st * z1 * z2 + av;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x30(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jg     L2
  movl   $0x1,-0x30(%rbp)
L2:
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L3
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L73
L56:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x2c(%rbp)
L73:
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L56
  jmp    L38
L19:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x28(%rbp)
L38:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L19
  mov    $0x0,%eax
L3:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  int i, j;
  int length = __VERIFIER_nondet_int();
  if (length < 1)
    length = 1;
  int *arr = alloca(length);
  if (!arr)
    return 0;
  int *a = arr;
  for (int k = 0; k < length; k++) {
    arr[k] = __VERIFIER_nondet_int();
  }
  while (*a != *(arr + length - 1)) {
    *a += *(arr + length - 1);
    a++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %eax,%edx
  mov    %edx,%r13d
  mov    %edx,%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rbx
  mov    %rax,%r12
  lea    -0x1(%r13),%eax
  lea    0x4(%rbx,%rax,4),%r14
L17:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,(%r12)
  add    $0x4,%r12
  cmp    %r14,%r12
  jne    L17
  mov    (%rbx),%eax
  movslq %r13d,%r13
  lea    -0x4(%rbx,%r13,4),%rcx
  mov    (%rcx),%edx
  cmp    %edx,%eax
  je     L29
L24:
  add    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  mov    (%rbx),%eax
  mov    (%rcx),%edx
  cmp    %edx,%eax
  jne    L24
L29:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j;
  int length = __VERIFIER_nondet_int();
  if (length < 1)
    length = 1;
  int *arr = alloca(length);
  if (!arr)
    return 0;
  int *a = arr;
  for (int k = 0; k < length; k++) {
    arr[k] = __VERIFIER_nondet_int();
  }
  while (*a != *(arr + length - 1)) {
    *a += *(arr + length - 1);
    a++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  cmovg  %eax,%edx
  movslq %edx,%r14
  mov    %r14d,%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L52
  mov    %rax,%r13
  mov    %rax,%rbx
  lea    -0x1(%r14),%eax
  lea    0x4(%r13),%r12
  lea    (%r12,%rax,4),%r15
  nopl   (%rax)
L22:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r15,%rbx
  jne    L22
  lea    -0x4(%r13,%r14,4),%rcx
  mov    0x0(%r13),%eax
  mov    (%rcx),%edx
  cmp    %edx,%eax
  jne    L34
  jmp    L52
  nopl   0x0(%rax)
L43:
  add    $0x4,%r12
L34:
  add    %edx,%eax
  mov    %eax,0x0(%r13)
  mov    (%r12),%eax
  mov    %r12,%r13
  mov    (%rcx),%edx
  cmp    %edx,%eax
  jne    L43
L52:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j;
  int length = __VERIFIER_nondet_int();
  if (length < 1)
    length = 1;
  int *arr = alloca(length);
  if (!arr)
    return 0;
  int *a = arr;
  for (int k = 0; k < length; k++) {
    arr[k] = __VERIFIER_nondet_int();
  }
  while (*a != *(arr + length - 1)) {
    *a += *(arr + length - 1);
    a++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  cmovg  %eax,%edx
  movslq %edx,%r14
  mov    %r14d,%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L59
  mov    %rax,%r13
  mov    %rax,%rbx
  lea    -0x1(%r14),%eax
  lea    0x4(%r13),%r12
  lea    (%r12,%rax,4),%r15
  nopl   (%rax)
L10:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r15,%rbx
  jne    L10
  lea    -0x4(%r13,%r14,4),%rcx
  mov    0x0(%r13),%eax
  mov    (%rcx),%edx
  cmp    %edx,%eax
  jne    L17
  jmp    L59
  nopl   0x0(%rax)
L23:
  add    $0x4,%r12
L17:
  add    %edx,%eax
  mov    %eax,0x0(%r13)
  mov    (%r12),%eax
  mov    %r12,%r13
  mov    (%rcx),%edx
  cmp    %edx,%eax
  jne    L23
L59:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int i, j;
  int length = __VERIFIER_nondet_int();
  if (length < 1)
    length = 1;
  int *arr = alloca(length);
  if (!arr)
    return 0;
  int *a = arr;
  for (int k = 0; k < length; k++) {
    arr[k] = __VERIFIER_nondet_int();
  }
  while (*a != *(arr + length - 1)) {
    *a += *(arr + length - 1);
    a++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<road_prospect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <marker_show@plt>
  cmpl   $0x3,-0x8(%rbp)
  je     L83
  cmpl   $0x3,-0x8(%rbp)
  jg     L73
  cmpl   $0x2,-0x8(%rbp)
  je     L7
  cmpl   $0x2,-0x8(%rbp)
  jg     L73
  cmpl   $0x0,-0x8(%rbp)
  je     L21
  cmpl   $0x1,-0x8(%rbp)
  je     L107
  jmp    L73
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <road_up_prospect@plt>
  jmp    L5
L107:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <road_down_prospect@plt>
  jmp    L5
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <road_left_prospect@plt>
  jmp    L5
L83:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <road_right_prospect@plt>
  jmp    L5
L73:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int road_prospect(int player, int dir) {
  marker_show();
  switch (dir) {
  case 0:
    return road_up_prospect(player);
    break;
  case 1:
    return road_down_prospect(player);
    break;
  case 2:
    return road_left_prospect(player);
    break;
  case 3:
    return road_right_prospect(player);
    break;
  default:
    return 0;
    break;
  }
}
```