ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strncpy_crlf>:
  endbr64
  lea    -0x1(%rdi,%rdx,1),%rdx
  add    %rsi,%rcx
  nopl   0x0(%rax)
L50:
  cmp    %rdx,%rdi
  jae    L70
L47:
  cmp    %rcx,%rsi
  jae    L70
  movzbl (%rsi),%eax
  cmp    $0xd,%al
  je     L7
  cmp    $0xa,%al
  jne    L3
  cmpb   $0xd,0x1(%rsi)
  je     L22
L42:
  mov    $0xa0d,%eax
  add    $0x2,%rdi
  add    $0x1,%rsi
  mov    %ax,-0x2(%rdi)
  cmp    %rdx,%rdi
  jb     L47
L70:
  movb   $0x0,(%rdi)
  ret
  nopl   (%rax)
L3:
  mov    %al,(%rdi)
  add    $0x1,%rsi
  add    $0x1,%rdi
  jmp    L50
  nopl   0x0(%rax)
L7:
  cmpb   $0xa,0x1(%rsi)
  jne    L42
L22:
  mov    $0xa0d,%r8d
  add    $0x2,%rsi
  add    $0x2,%rdi
  mov    %r8w,-0x2(%rdi)
  jmp    L50
```

assistant: ```c
void strncpy_crlf(char *dest, const char *src, size_t destmax, size_t srcmax) {
  char *destend = dest + destmax - 1;
  const char *srcend = src + srcmax;
  while (dest < destend && src < srcend) {
    if ((src[0] == '\r' && src[1] == '\n') || (src[0] == '\n' && src[1] == '\r')) {
      *dest++ = '\r';
      *dest++ = '\n';
      src += 2;
      continue;
    };
    if (src[0] == '\r') {
      *dest++ = '\r';
      *dest++ = '\n';
      src += 1;
      continue;
    };
    if (src[0] == '\n') {
      *dest++ = '\r';
      *dest++ = '\n';
      src += 1;
      continue;
    };
    *dest++ = *src++;
  };
  *dest = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__fstatvfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __fstatvfs(int fd, struct statvfs *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__fstatvfs>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __fstatvfs(int fd, struct statvfs *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__fstatvfs>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __fstatvfs(int fd, struct statvfs *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<__fstatvfs>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __fstatvfs(int fd, struct statvfs *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    $0x9,%edi
  call   <tarai@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int benchmark() {
  volatile int cnt = 0;
  cnt = tarai(9, 6, 3);
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<benchmark>:
  endbr64
  sub    $0x18,%rsp
  movl   $0x0,0xc(%rsp)
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    $0x9,%edi
  call   <tarai@plt>
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int benchmark() {
  volatile int cnt = 0;
  cnt = tarai(9, 6, 3);
  return cnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    $0x9,%edi
  movl   $0x0,0xc(%rsp)
  call   <tarai@plt>
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int benchmark() {
  volatile int cnt = 0;
  cnt = tarai(9, 6, 3);
  return cnt;
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edx
  mov    $0x6,%esi
  mov    $0x9,%edi
  movl   $0x0,0xc(%rsp)
  call   <tarai@plt>
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int benchmark() {
  volatile int cnt = 0;
  cnt = tarai(9, 6, 3);
  return cnt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ylet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L28
L7:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L7
L4:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
ylet(str, k) char *str;
{
  k++;
  while (*str && k--)
    str++;
  return (*--str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ylet>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L37
  cmp    $0xffffffff,%esi
  je     L37
  lea    0x1(%rsi),%eax
  add    %rdi,%rax
L25:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L37
  cmp    %rax,%rdi
  jne    L25
  mov    %rax,%rdi
L37:
  movsbl -0x1(%rdi),%eax
  ret
```

assistant: ```c
ylet(str, k) char *str;
{
  k++;
  while (*str && k--)
    str++;
  return (*--str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ylet>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  cmp    $0xffffffff,%esi
  je     L6
  lea    0x1(%rsi),%eax
  add    %rdi,%rax
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L4:
  cmp    %rax,%rdi
  je     L6
L34:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L4
L6:
  movsbl -0x1(%rdi),%eax
  ret
```

assistant: ```c
ylet(str, k) char *str;
{
  k++;
  while (*str && k--)
    str++;
  return (*--str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ylet>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L34
  cmp    $0xffffffff,%esi
  je     L34
  lea    0x1(%rsi),%eax
  add    %rdi,%rax
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    %rax,%rdi
  je     L34
L17:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L7
L34:
  movsbl -0x1(%rdi),%eax
  ret
```

assistant: ```c
ylet(str, k) char *str;
{
  k++;
  while (*str && k--)
    str++;
  return (*--str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_negative_sized_VLA_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  movb   $0xff,-0x29(%rbp)
  movzbl -0x29(%rbp),%eax
  movsbq %al,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movsbq %al,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movsbq %al,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  movsbq %al,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L16
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L16:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L30
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L30:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    %rsi,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void check_negative_sized_VLA_5() {
  signed char x = -1;
  int vla[x];
}
```
user: What is the c source code of the assembly code below?

```asm
<check_negative_sized_VLA_5>:
  endbr64
  ret
```

assistant: ```c
void check_negative_sized_VLA_5() {
  signed char x = -1;
  int vla[x];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_negative_sized_VLA_5>:
  endbr64
  ret
```

assistant: ```c
void check_negative_sized_VLA_5() {
  signed char x = -1;
  int vla[x];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_negative_sized_VLA_5>:
  endbr64
  ret
```

assistant: ```c
void check_negative_sized_VLA_5() {
  signed char x = -1;
  int vla[x];
}
```
user: What is the c source code of the assembly code below?

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <test5a@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void __attribute__((no)) __attribute__((noclone)) * test5(void) {
  char *save = (char *)alloca(4);
  return test5a(save);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rdi
  call   <test5a@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  leave
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) __attribute__((noclone)) * test5(void) {
  char *save = (char *)alloca(4);
  return test5a(save);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test5>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %rax,%rdi
  call   <test5a@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  leave
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) __attribute__((noclone)) * test5(void) {
  char *save = (char *)alloca(4);
  return test5a(save);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    %rax,%rdi
  call   <test5a@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  leave
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __attribute__((no)) __attribute__((noclone)) * test5(void) {
  char *save = (char *)alloca(4);
  return test5a(save);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L4:
  jmp    L4
```

assistant: ```c
void abort() {
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<abort>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
void abort() {
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abort>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void abort() {
  while (1)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abort>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void abort() {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<should_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L69
  mov    $0x0,%eax
  jmp    L75
L69:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L63
L80:
  addq   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L76
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L80
L76:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L0
  mov    $0x0,%eax
  jmp    L75
L0:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x10(%rbp)
  jmp    L49
L9:
  addq   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L46
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
L46:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  sete   %al
  movzbl %al,%eax
L75:
  leave
  ret
```

assistant: ```c
int should_tag(const char *line, const char *propname) {
  const char *prop = strstr(line, propname);
  if (prop == NULL)
    return 0;
  const char *ptr;
  for (ptr = line; ptr < prop && isspace(*ptr); ++ptr)
    ;
  if (ptr != prop)
    return 0;
  for (ptr += strlen(propname); *ptr != '\0' && isspace(*ptr); ++ptr)
    ;
  return (*ptr == '=');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<should_tag>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strstr@plt>
  test   %rax,%rax
  je     L63
  mov    %rax,%rbp
  cmp    %rax,%rbx
  jae    L5
L105:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L5
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L105
L89:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L76
L107:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L76
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L107
L76:
  cmpb   $0x3d,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L44
L5:
  cmp    %rbx,%rbp
  je     L108
  mov    $0x0,%eax
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L108:
  mov    %rbx,%rbp
  jmp    L89
L63:
  mov    $0x0,%eax
  jmp    L44
```

assistant: ```c
int should_tag(const char *line, const char *propname) {
  const char *prop = strstr(line, propname);
  if (prop == NULL)
    return 0;
  const char *ptr;
  for (ptr = line; ptr < prop && isspace(*ptr); ++ptr)
    ;
  if (ptr != prop)
    return 0;
  for (ptr += strlen(propname); *ptr != '\0' && isspace(*ptr); ++ptr)
    ;
  return (*ptr == '=');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<should_tag>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbp
  cmp    %rax,%rbx
  jb     L58
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L41
L58:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
L93:
  cmp    %rbx,%rbp
  je     L41
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L82
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L52:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L40
L82:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L52
  movzbl 0x0(%rbp),%edi
L40:
  xor    %eax,%eax
  cmp    $0x3d,%dil
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
```

assistant: ```c
int should_tag(const char *line, const char *propname) {
  const char *prop = strstr(line, propname);
  if (prop == NULL)
    return 0;
  const char *ptr;
  for (ptr = line; ptr < prop && isspace(*ptr); ++ptr)
    ;
  if (ptr != prop)
    return 0;
  for (ptr += strlen(propname); *ptr != '\0' && isspace(*ptr); ++ptr)
    ;
  return (*ptr == '=');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<should_tag>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbp
  cmp    %rax,%rbx
  jb     L1
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L15
L1:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
L16:
  cmp    %rbx,%rbp
  je     L15
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L50
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L14:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L52
L50:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  movzbl 0x0(%rbp),%edi
L52:
  xor    %eax,%eax
  cmp    $0x3d,%dil
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
```

assistant: ```c
int should_tag(const char *line, const char *propname) {
  const char *prop = strstr(line, propname);
  if (prop == NULL)
    return 0;
  const char *ptr;
  for (ptr = line; ptr < prop && isspace(*ptr); ++ptr)
    ;
  if (ptr != prop)
    return 0;
  for (ptr += strlen(propname); *ptr != '\0' && isspace(*ptr); ++ptr)
    ;
  return (*ptr == '=');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arith_expr_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    $0x0,%eax
  call   <arith_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct expr *arith_expr_new(struct expr *left, struct expr *right, int operator) {
  struct object *expr = object_new(arith_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, operator);
  return ((struct expr *)(expr));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arith_expr_new>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x0,%eax
  call   <arith_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %rax,%rbx
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <binary_expr_init@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct expr *arith_expr_new(struct expr *left, struct expr *right, int operator) {
  struct object *expr = object_new(arith_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, operator);
  return ((struct expr *)(expr));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<arith_expr_new>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <arith_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <binary_expr_init@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
struct expr *arith_expr_new(struct expr *left, struct expr *right, int operator) {
  struct object *expr = object_new(arith_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, operator);
  return ((struct expr *)(expr));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arith_expr_new>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <arith_expr_class_get@plt>
  mov    %eax,%edi
  call   <object_new@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <binary_expr_init@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
struct expr *arith_expr_new(struct expr *left, struct expr *right, int operator) {
  struct object *expr = object_new(arith_expr_class_get());
  binary_expr_init(((struct binary_expr *)(expr)), left, right, operator);
  return ((struct expr *)(expr));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<removeSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L0:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L4
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  jmp    L38
L4:
  movl   $0x1,-0x4(%rbp)
L38:
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int removeSpace(char str[], char result[]) {
  int strInd, resultInd, hasSpace;
  hasSpace = 0;
  for (resultInd = 0, strInd = 0; str[strInd] != '\0'; strInd++)
    if (!isspace(str[strInd])) {
      result[resultInd] = str[strInd];
      resultInd++;
    } else
      hasSpace = 1;
  result[resultInd] = '\0';
  return hasSpace;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<removeSpace>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L44
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  mov    $0x1,%r14d
  jmp    L30
L40:
  mov    %r14d,%r13d
L25:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L15
L30:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L40
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%ebp
  jmp    L25
L44:
  mov    $0x0,%r13d
  mov    $0x0,%ebp
L15:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int removeSpace(char str[], char result[]) {
  int strInd, resultInd, hasSpace;
  hasSpace = 0;
  for (resultInd = 0, strInd = 0; str[strInd] != '\0'; strInd++)
    if (!isspace(str[strInd])) {
      result[resultInd] = str[strInd];
      resultInd++;
    } else
      hasSpace = 1;
  result[resultInd] = '\0';
  return hasSpace;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<removeSpace>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L46
  xor    %ebp,%ebp
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L35:
  movzbl (%rbx),%edx
  movslq %ebp,%rax
  add    $0x1,%rbx
  add    $0x1,%ebp
  mov    %dl,(%r12,%rax,1)
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L34
L26:
  call   <isspace@plt>
  test   %eax,%eax
  je     L35
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  mov    $0x1,%r13d
  test   %dil,%dil
  jne    L26
L34:
  movslq %ebp,%rbp
  add    %rbp,%r12
L46:
  movb   $0x0,(%r12)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int removeSpace(char str[], char result[]) {
  int strInd, resultInd, hasSpace;
  hasSpace = 0;
  for (resultInd = 0, strInd = 0; str[strInd] != '\0'; strInd++)
    if (!isspace(str[strInd])) {
      result[resultInd] = str[strInd];
      resultInd++;
    } else
      hasSpace = 1;
  result[resultInd] = '\0';
  return hasSpace;
}
```