ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D63(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L31
  movss  D23(%rip),%xmm3
  mov    $0x2,%ebp
  lea    D35(%rip),%r12
  movaps %xmm3,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L43:
  mov    $0x1,%ebx
  movaps %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L46:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  add    $0x1,%ebx
  mulss  %xmm0,%xmm1
  cmp    %ebp,%ebx
  jne    L46
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebp
  cvtss2sd %xmm1,%xmm0
  movss  %xmm2,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  D23(%rip),%xmm3
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  movaps %xmm3,%xmm0
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  cmp    %ebx,0x14(%rsp)
  jge    L43
L39:
  pxor   %xmm0,%xmm0
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  movss  D23(%rip),%xmm2
  jmp    L39
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D63
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D23
data_type: byte[4]
name: unpack_data
arguments: data_tag: D35
data_type: string
name: unpack_data
arguments: data_tag: D11
data_type: string

tool: D63: enter the number: 

tool: D3: %d

tool: {"D23": [0x00,0x00,0x80,0x3f]}

tool: D35:  + 1/%.f

tool: D11: 

exp is %.10f


assistant: ```c
int main(void) {
  float factorial, e = 1.0f, number;
  int n, i, j;
  printf("enter the number: ");
  scanf("%d", &n);
  printf("1");
  for (i = 1; i <= n; i++) {
    for (j = 1, factorial = 1.0f; j <= i; j++) {
      factorial *= j;
    }
    number = 1.0f / factorial;
    printf(" + 1/%.f", factorial);
    e += number;
  }
  printf("\n\nexp is %.10f\n", e);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D53(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L13
  movss  D34(%rip),%xmm3
  mov    $0x2,%ebp
  lea    D18(%rip),%r12
  movaps %xmm3,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    $0x1,%ebx
  movaps %xmm3,%xmm1
  nopl   0x0(%rax,%rax,1)
L42:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  add    $0x1,%ebx
  mulss  %xmm0,%xmm1
  cmp    %ebp,%ebx
  jne    L42
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebp
  cvtss2sd %xmm1,%xmm0
  movss  %xmm2,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  D34(%rip),%xmm3
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  movaps %xmm3,%xmm0
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  cmp    %ebx,0x14(%rsp)
  jge    L38
L8:
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  movss  D34(%rip),%xmm2
  jmp    L8
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D53
type: string
name: parse_data
arguments: data_label: D61
type: string
name: parse_data
arguments: data_label: D34
type: byte[4]
name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D16
type: string

tool: D53: enter the number: 

tool: D61: %d

tool: {"D34": [0x00,0x00,0x80,0x3f]}

tool: D18:  + 1/%.f

tool: D16: 

exp is %.10f


assistant: ```c
int main(void) {
  float factorial, e = 1.0f, number;
  int n, i, j;
  printf("enter the number: ");
  scanf("%d", &n);
  printf("1");
  for (i = 1; i <= n; i++) {
    for (j = 1, factorial = 1.0f; j <= i; j++) {
      factorial *= j;
    }
    number = 1.0f / factorial;
    printf(" + 1/%.f", factorial);
    e += number;
  }
  printf("\n\nexp is %.10f\n", e);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_subarchitecture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  jne    L88
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L88:
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  jne    L89
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L89:
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x4,%eax
  jne    L43
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L43:
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x5,%eax
  jne    L45
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L45:
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x6,%eax
  jne    L73
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L73:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D40
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string

tool: D11: LOONGSON3R3

tool: D56: LOONGSON3R4

tool: D40: I6400

tool: D21: P6600

tool: D9: I6500

tool: D15: SICORTEX

assistant: ```c
void get_subarchitecture(void) {
  if (detect() == 2) {
    printf("LOONGSON3R3");
  } else if (detect() == 3) {
    printf("LOONGSON3R4");
  } else if (detect() == 4) {
    printf("I6400");
  } else if (detect() == 5) {
    printf("P6600");
  } else if (detect() == 6) {
    printf("I6500");
  } else {
    printf("SICORTEX");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_subarchitecture>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L29
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L93
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x4,%eax
  je     L13
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x5,%eax
  je     L99
  mov    $0x0,%eax
  call   <detect@plt>
  cmp    $0x6,%eax
  je     L11
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L29:
  lea    D43(%rip),%rdi
  call   <printf@plt>
L54:
  add    $0x8,%rsp
  ret
L93:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L13:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L99:
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L11:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L54
```

tool_calls: name: retrieve_data
arguments: label: D56
datatype: string
name: retrieve_data
arguments: label: D43
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D23
datatype: string
name: retrieve_data
arguments: label: D41
datatype: string
name: retrieve_data
arguments: label: D47
datatype: string

tool: D56: SICORTEX

tool: D43: LOONGSON3R3

tool: D28: LOONGSON3R4

tool: D23: I6400

tool: D41: P6600

tool: D47: I6500

assistant: ```c
void get_subarchitecture(void) {
  if (detect() == 2) {
    printf("LOONGSON3R3");
  } else if (detect() == 3) {
    printf("LOONGSON3R4");
  } else if (detect() == 4) {
    printf("I6400");
  } else if (detect() == 5) {
    printf("P6600");
  } else if (detect() == 6) {
    printf("I6500");
  } else {
    printf("SICORTEX");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_subarchitecture>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L45
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L0
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x4,%eax
  je     L30
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x5,%eax
  je     L46
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x6,%eax
  je     L15
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L0:
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L45:
  lea    D55(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L46:
  lea    D59(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L30:
  lea    D48(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L15:
  lea    D47(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D59
data_type: string
name: retrieve_data
arguments: data_label: D48
data_type: string
name: retrieve_data
arguments: data_label: D47
data_type: string

tool: D3: SICORTEX

tool: D0: LOONGSON3R4

tool: D55: LOONGSON3R3

tool: D59: P6600

tool: D48: I6400

tool: D47: I6500

assistant: ```c
void get_subarchitecture(void) {
  if (detect() == 2) {
    printf("LOONGSON3R3");
  } else if (detect() == 3) {
    printf("LOONGSON3R4");
  } else if (detect() == 4) {
    printf("I6400");
  } else if (detect() == 5) {
    printf("P6600");
  } else if (detect() == 6) {
    printf("I6500");
  } else {
    printf("SICORTEX");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_subarchitecture>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x2,%eax
  je     L22
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x3,%eax
  je     L3
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x4,%eax
  je     L14
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x5,%eax
  je     L20
  xor    %eax,%eax
  call   <detect@plt>
  cmp    $0x6,%eax
  je     L35
  lea    D23(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L3:
  lea    D40(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L22:
  lea    D34(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L20:
  lea    D33(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L14:
  lea    D39(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
L35:
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D40
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D33
type_infered: string
name: extract_symbolic_data
arguments: tag: D39
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string

tool: D23: SICORTEX

tool: D40: LOONGSON3R4

tool: D34: LOONGSON3R3

tool: D33: P6600

tool: D39: I6400

tool: D28: I6500

assistant: ```c
void get_subarchitecture(void) {
  if (detect() == 2) {
    printf("LOONGSON3R3");
  } else if (detect() == 3) {
    printf("LOONGSON3R4");
  } else if (detect() == 4) {
    printf("I6400");
  } else if (detect() == 5) {
    printf("P6600");
  } else if (detect() == 6) {
    printf("I6500");
  } else {
    printf("SICORTEX");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  jmp    L11
L6:
  addl   $0x1,-0x4(%rbp)
  jmp    L18
L11:
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *str) {
  int i;
  for (i = 0;; i++)
    if (str[i] == '\0')
      return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlen>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%edx
  cmpb   $0x0,(%rdi)
  je     L18
L9:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L9
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  int i;
  for (i = 0;; i++)
    if (str[i] == '\0')
      return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strlen>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L5
  nopl   0x0(%rax)
L16:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L16
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  int i;
  for (i = 0;; i++)
    if (str[i] == '\0')
      return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    $0x1,%eax
  je     L0
  nopl   0x0(%rax)
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const char *str) {
  int i;
  for (i = 0;; i++)
    if (str[i] == '\0')
      return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<index_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L26
L1:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L26:
  pop    %rbp
  ret
```

assistant: ```c
size_t index_of(const char *s, char c) {
  const char *p = s;
  for (; *p; p++)
    if (*p == c)
      return p - s;
  return p - s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<index_of>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L22
  mov    %rdi,%rax
L38:
  cmp    %dl,%sil
  je     L2
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L38
L25:
  sub    %rdi,%rax
  ret
L2:
  sub    %rdi,%rax
  ret
L22:
  mov    %rdi,%rax
  jmp    L25
```

assistant: ```c
size_t index_of(const char *s, char c) {
  const char *p = s;
  for (; *p; p++)
    if (*p == c)
      return p - s;
  return p - s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<index_of>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L35
  mov    %rdi,%rax
  jmp    L20
L13:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L2
L20:
  cmp    %dl,%sil
  jne    L13
L2:
  sub    %rdi,%rax
  ret
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t index_of(const char *s, char c) {
  const char *p = s;
  for (; *p; p++)
    if (*p == c)
      return p - s;
  return p - s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<index_of>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L35
  mov    %rdi,%rax
  jmp    L32
L22:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L17
L32:
  cmp    %dl,%sil
  jne    L22
L17:
  sub    %rdi,%rax
  ret
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t index_of(const char *s, char c) {
  const char *p = s;
  for (; *p; p++)
    if (*p == c)
      return p - s;
  return p - s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ProcessArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L66:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L16
  movl   $0x1,-0x4(%rbp)
  jmp    L67
L57:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6f,%al
  jne    L37
  mov    -0x28(%rbp),%rax
  movl   $0x8,(%rax)
  jmp    L34
L37:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L34
  mov    -0x28(%rbp),%rax
  movl   $0x10,(%rax)
L34:
  addl   $0x1,-0x4(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
L16:
  cmpl   $0x1,-0x14(%rbp)
  jg     L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ProcessArgs(int argc, char *argv[], int *output) {
  int i = 0;
  while (argc > 1) {
    --argc;
    if (argv[argc][0] == '-') {
      i = 1;
      while (argv[argc][i] != '\0') {
        if (argv[argc][i] == 'o') {
          *output = 8;
        } else if (argv[argc][i] == 'x') {
          *output = 16;
        } else {
        }
        ++i;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ProcessArgs>:
  endbr64
  cmp    $0x1,%edi
  jle    L75
  movslq %edi,%rcx
  shl    $0x3,%rcx
  lea    (%rsi,%rcx,1),%rax
  lea    -0x8(%rsi,%rcx,1),%r8
  lea    -0x2(%rdi),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%r8
  jmp    L83
L10:
  movl   $0x8,(%rdx)
L4:
  mov    -0x8(%rdi),%rcx
  movzbl (%rcx,%rsi,1),%ecx
  add    $0x1,%rsi
  test   %cl,%cl
  je     L90
L42:
  cmp    $0x6f,%cl
  je     L10
  cmp    $0x78,%cl
  jne    L4
  movl   $0x10,(%rdx)
  jmp    L4
L90:
  sub    $0x8,%rax
  cmp    %r8,%rax
  je     L75
L83:
  mov    %rax,%rdi
  mov    -0x8(%rax),%rcx
  cmpb   $0x2d,(%rcx)
  jne    L90
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L90
  mov    $0x2,%esi
  jmp    L42
L75:
  ret
```

assistant: ```c
void ProcessArgs(int argc, char *argv[], int *output) {
  int i = 0;
  while (argc > 1) {
    --argc;
    if (argv[argc][0] == '-') {
      i = 1;
      while (argv[argc][i] != '\0') {
        if (argv[argc][i] == 'o') {
          *output = 8;
        } else if (argv[argc][i] == 'x') {
          *output = 16;
        } else {
        }
        ++i;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ProcessArgs>:
  endbr64
  cmp    $0x1,%edi
  jle    L72
  movslq %edi,%rdi
  jmp    L97
  xchg   %ax,%ax
L50:
  sub    $0x1,%rdi
  cmp    $0x1,%edi
  jle    L72
L97:
  mov    -0x8(%rsi,%rdi,8),%rax
  cmpb   $0x2d,(%rax)
  jne    L50
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L50
  add    $0x2,%rax
  jmp    L8
  nopl   0x0(%rax)
L35:
  cmp    $0x78,%cl
  jne    L49
  movl   $0x10,(%rdx)
L49:
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L50
L8:
  cmp    $0x6f,%cl
  jne    L35
  movl   $0x8,(%rdx)
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L72:
  ret
```

assistant: ```c
void ProcessArgs(int argc, char *argv[], int *output) {
  int i = 0;
  while (argc > 1) {
    --argc;
    if (argv[argc][0] == '-') {
      i = 1;
      while (argv[argc][i] != '\0') {
        if (argv[argc][i] == 'o') {
          *output = 8;
        } else if (argv[argc][i] == 'x') {
          *output = 16;
        } else {
        }
        ++i;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ProcessArgs>:
  endbr64
  cmp    $0x1,%edi
  jle    L78
  movslq %edi,%rdi
  jmp    L94
  xchg   %ax,%ax
L86:
  sub    $0x1,%rdi
  cmp    $0x1,%edi
  jle    L78
L94:
  mov    -0x8(%rsi,%rdi,8),%rax
  cmpb   $0x2d,(%rax)
  jne    L86
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L86
  add    $0x2,%rax
  jmp    L57
  nopl   0x0(%rax)
L8:
  cmp    $0x78,%cl
  jne    L36
  movl   $0x10,(%rdx)
L36:
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L86
L57:
  cmp    $0x6f,%cl
  jne    L8
  movl   $0x8,(%rdx)
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L78:
  ret
```

assistant: ```c
void ProcessArgs(int argc, char *argv[], int *output) {
  int i = 0;
  while (argc > 1) {
    --argc;
    if (argv[argc][0] == '-') {
      i = 1;
      while (argv[argc][i] != '\0') {
        if (argv[argc][i] == 'o') {
          *output = 8;
        } else if (argv[argc][i] == 'x') {
          *output = 16;
        } else {
        }
        ++i;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Matrix_Multiplication_One>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %r8d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    %r14d,%edi
  call   <omp_set_num_threads@plt>
  test   %ebp,%ebp
  jle    L14
  mov    %r12,%r10
  mov    %r13,%r9
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r11
  mov    %ebp,%r8d
  shl    $0x3,%r8
L30:
  mov    $0x0,%ecx
L18:
  mov    %r10,%rbp
  mov    (%r10),%rax
  movq   $0x0,(%rax,%rcx,1)
  mov    $0x0,%eax
L40:
  mov    %rcx,%rdx
  add    0x0(%rbp),%rdx
  mov    (%r9),%rdi
  mov    (%rbx,%rax,1),%rsi
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rcx,1),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L40
  add    $0x8,%rcx
  cmp    %r8,%rcx
  jne    L18
  add    $0x8,%r10
  add    $0x8,%r9
  cmp    %r11,%r10
  jne    L30
L14:
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x10(%rsp),%eax
  add    0x14(%rsp),%eax
  cltq
  imul   $0xf4240,0x8(%rsp),%edx
  add    0xc(%rsp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D2(%rip),%xmm0
  movq   %xmm0,%rbx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  movq   %rbx,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: f64
name: parse_data
arguments: label: D12
type_guessed: string

tool: D2: 1000000

tool: D12: 
		 Matrix into Matrix Multiplication using one Parallel for pragma......Done 


assistant: ```c
double Matrix_Multiplication_One(double **Matrix_A, double **Matrix_B, double **Result, int N_size, int Total_threads) {
  int i, j, k;
  struct timeval TimeValue_Start;
  struct timezone TimeZone_Start;
  struct timeval TimeValue_Final;
  struct timezone TimeZone_Final;
  long time_start, time_end;
  double time_overhead;
  gettimeofday(&TimeValue_Start, &TimeZone_Start);
  omp_set_num_threads(Total_threads);
#pragma omp parallel for private(j, k)
  for (i = 0; i < N_size; i = i + 1)
    for (j = 0; j < N_size; j = j + 1) {
      Result[i][j] = 0.0;
      for (k = 0; k < N_size; k = k + 1)
        Result[i][j] = Result[i][j] + Matrix_A[i][k] * Matrix_B[k][j];
    }
  gettimeofday(&TimeValue_Final, &TimeZone_Final);
  time_start = TimeValue_Start.tv_sec * 1000000 + TimeValue_Start.tv_usec;
  time_end = TimeValue_Final.tv_sec * 1000000 + TimeValue_Final.tv_usec;
  time_overhead = (time_end - time_start) / 1000000.0;
  printf("\n\t\t Matrix into Matrix Multiplication using one Parallel for pragma......Done \n");
  return time_overhead;
}
```