ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Strncmp>:
  endbr64
  cmp    $0x1,%edx
  jle    L41
  lea    -0x2(%rdx),%eax
  lea    0x2(%rdi,%rax,2),%rcx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x2(%rdi),%rax
  lea    0x2(%rsi),%rdx
  cmp    %rcx,%rax
  je     L14
  mov    %rdx,%rsi
  mov    %rax,%rdi
L32:
  movzwl (%rdi),%eax
  movzwl (%rsi),%edx
  cmp    %dx,%ax
  je     L29
L18:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L14:
  movzwl 0x2(%rdi),%eax
  movzwl 0x2(%rsi),%edx
  sub    %edx,%eax
  ret
L41:
  movzwl (%rdi),%eax
  movzwl (%rsi),%edx
  jmp    L18
```

assistant: ```c
Strncmp(s, t, n) unsigned short *s, *t;
{
  for (; --n > 0 && *s == *t; s++, t++)
    ;
  return *s - *t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testDouble@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  testDouble();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testDouble@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testDouble();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testDouble@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testDouble();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testDouble@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testDouble();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLineWidth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%ecx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  je     L11
  mov    $0x50,%eax
  jmp    L20
L11:
  mov    -0xc(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
__attribute__((pure)) int getLineWidth(void) {
  struct winsize w;
  if (ioctl(STDOUT_FILENO, TIOCGWINSZ, &w)) {
    return 80;
  }
  return w.ws_col;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getLineWidth>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  test   %rax,%rax
  mov    $0x50,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((pure)) int getLineWidth(void) {
  struct winsize w;
  if (ioctl(STDOUT_FILENO, TIOCGWINSZ, &w)) {
    return 80;
  }
  return w.ws_col;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getLineWidth>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  test   %rax,%rax
  mov    $0x50,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((pure)) int getLineWidth(void) {
  struct winsize w;
  if (ioctl(STDOUT_FILENO, TIOCGWINSZ, &w)) {
    return 80;
  }
  return w.ws_col;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getLineWidth>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  test   %rax,%rax
  mov    $0x50,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((pure)) int getLineWidth(void) {
  struct winsize w;
  if (ioctl(STDOUT_FILENO, TIOCGWINSZ, &w)) {
    return 80;
  }
  return w.ws_col;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<truth_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L9:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L34
  mov    $0x1,%eax
  jmp    L12
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int truth_table(char cache, char *strhld) {
  int count = 0;
  while (strhld[count] != '\0')
    if (cache == strhld[count++])
      return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<truth_table>:
  endbr64
L8:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L11
  add    $0x1,%rsi
  cmp    %dil,%al
  jne    L8
  mov    $0x1,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int truth_table(char cache, char *strhld) {
  int count = 0;
  while (strhld[count] != '\0')
    if (cache == strhld[count++])
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<truth_table>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L5:
  add    $0x1,%rsi
  cmp    %dil,%al
  je     L21
L17:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int truth_table(char cache, char *strhld) {
  int count = 0;
  while (strhld[count] != '\0')
    if (cache == strhld[count++])
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<truth_table>:
  endbr64
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%rsi
  cmp    %dil,%al
  je     L3
L20:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L29
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int truth_table(char cache, char *strhld) {
  int count = 0;
  while (strhld[count] != '\0')
    if (cache == strhld[count++])
      return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
  jmp    L66
L28:
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L7:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L23:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L66
L53:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L7
  mov    $0x1,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int prime(int n) {
  int i, j;
  if (n % 2 == 0)
    return 0;
  else
    for (i = 0; i * i < n; ++i) {
      for (j = i + 1; j < n; ++j) {
        if (i * j == n)
          return 0;
      }
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prime>:
  endbr64
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L78
  test   %edi,%edi
  jle    L4
  mov    $0x0,%esi
L32:
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edi
  jle    L12
  mov    %r8d,%edx
  imul   %eax,%edx
  cmp    %edx,%edi
  je     L2
  lea    0x2(%rax),%edx
  imul   %eax,%edx
  mov    %r8d,%eax
L29:
  add    $0x1,%eax
  cmp    %eax,%edi
  je     L12
  lea    (%rdx,%rsi,1),%ecx
  cmp    %edx,%edi
  je     L57
  mov    %ecx,%edx
  jmp    L29
L12:
  add    $0x1,%esi
  mov    %r8d,%eax
  imul   %r8d,%eax
  cmp    %edi,%eax
  jge    L39
  mov    %r8d,%eax
  jmp    L32
L39:
  mov    $0x1,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
L57:
  mov    $0x0,%eax
L78:
  ret
```

assistant: ```c
int prime(int n) {
  int i, j;
  if (n % 2 == 0)
    return 0;
  else
    for (i = 0; i * i < n; ++i) {
      for (j = i + 1; j < n; ++j) {
        if (i * j == n)
          return 0;
      }
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prime>:
  endbr64
  xor    %eax,%eax
  test   $0x1,%dil
  je     L25
  test   %edi,%edi
  jle    L69
  xor    %esi,%esi
L0:
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edi
  jle    L49
  mov    %r8d,%edx
  imul   %eax,%edx
  cmp    %edx,%edi
  je     L38
  lea    0x2(%rax),%edx
  imul   %eax,%edx
  mov    %r8d,%eax
  jmp    L78
L16:
  lea    (%rdx,%rsi,1),%ecx
  cmp    %edx,%edi
  je     L38
  mov    %ecx,%edx
L78:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L16
L49:
  mov    %r8d,%eax
  add    $0x1,%esi
  imul   %r8d,%eax
  cmp    %edi,%eax
  jge    L69
  mov    %r8d,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
L25:
  ret
L69:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int prime(int n) {
  int i, j;
  if (n % 2 == 0)
    return 0;
  else
    for (i = 0; i * i < n; ++i) {
      for (j = i + 1; j < n; ++j) {
        if (i * j == n)
          return 0;
      }
    }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prime>:
  endbr64
  xor    %eax,%eax
  test   $0x1,%dil
  je     L76
  test   %edi,%edi
  jle    L41
  xor    %esi,%esi
L3:
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edi
  jle    L35
  mov    %r8d,%edx
  imul   %eax,%edx
  cmp    %edx,%edi
  je     L5
  lea    0x2(%rax),%edx
  imul   %eax,%edx
  mov    %r8d,%eax
  jmp    L13
L23:
  lea    (%rdx,%rsi,1),%ecx
  cmp    %edx,%edi
  je     L5
  mov    %ecx,%edx
L13:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L23
L35:
  mov    %r8d,%eax
  add    $0x1,%esi
  imul   %r8d,%eax
  cmp    %edi,%eax
  jge    L41
  mov    %r8d,%eax
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
L76:
  ret
L41:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int prime(int n) {
  int i, j;
  if (n % 2 == 0)
    return 0;
  else
    for (i = 0; i * i < n; ++i) {
      for (j = i + 1; j < n; ++j) {
        if (i * j == n)
          return 0;
      }
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<keyup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0xf0,%edi
  call   <ps2sim_send@plt>
  mov    $0xc8,%edi
  call   <delay_us@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ps2sim_send@plt>
  mov    $0x12c,%edi
  call   <delay_us@plt>
  mov    $0x1,%edi
  call   <led@plt>
  nop
  leave
  ret
```

assistant: ```c
void keyup(unsigned char keycode) {
  ps2sim_send(0xF0);
  delay_us(200);
  ps2sim_send(keycode);
  delay_us(300);
  led(0x01);
}
```
user: Translate the below assembly code into C programming language:

```asm
<keyup>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf0,%edi
  call   <ps2sim_send@plt>
  mov    $0xc8,%edi
  call   <delay_us@plt>
  movzbl %bl,%edi
  call   <ps2sim_send@plt>
  mov    $0x12c,%edi
  call   <delay_us@plt>
  mov    $0x1,%edi
  call   <led@plt>
  pop    %rbx
  ret
```

assistant: ```c
void keyup(unsigned char keycode) {
  ps2sim_send(0xF0);
  delay_us(200);
  ps2sim_send(keycode);
  delay_us(300);
  led(0x01);
}
```
user: What is the c source code of the assembly code below?

```asm
<keyup>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf0,%edi
  call   <ps2sim_send@plt>
  mov    $0xc8,%edi
  call   <delay_us@plt>
  movzbl %bl,%edi
  call   <ps2sim_send@plt>
  mov    $0x12c,%edi
  call   <delay_us@plt>
  mov    $0x1,%edi
  pop    %rbx
  jmp    1080 <led@plt>
```

assistant: ```c
void keyup(unsigned char keycode) {
  ps2sim_send(0xF0);
  delay_us(200);
  ps2sim_send(keycode);
  delay_us(300);
  led(0x01);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<keyup>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf0,%edi
  call   <ps2sim_send@plt>
  mov    $0xc8,%edi
  call   <delay_us@plt>
  movzbl %bl,%edi
  call   <ps2sim_send@plt>
  mov    $0x12c,%edi
  call   <delay_us@plt>
  mov    $0x1,%edi
  pop    %rbx
  jmp    1080 <led@plt>
```

assistant: ```c
void keyup(unsigned char keycode) {
  ps2sim_send(0xF0);
  delay_us(200);
  ps2sim_send(keycode);
  delay_us(300);
  led(0x01);
}
```
user: Translate the below assembly code into C programming language:

```asm
<zget_readable_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L22
  mov    -0xc(%rbp),%eax
  jmp    L15
L22:
  mov    $0xffffffff,%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int zget_readable_count(int fd) {
  int count;
  return (ioctl(fd, FIONREAD, (char *)&count) < 0 ? -1 : count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zget_readable_count>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L19
  mov    0x4(%rsp),%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L3
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zget_readable_count(int fd) {
  int count;
  return (ioctl(fd, FIONREAD, (char *)&count) < 0 ? -1 : count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zget_readable_count>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L14
  mov    0x4(%rsp),%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L14:
  mov    $0xffffffff,%eax
  jmp    L24
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zget_readable_count(int fd) {
  int count;
  return (ioctl(fd, FIONREAD, (char *)&count) < 0 ? -1 : count);
}
```
user: What is the c source code of the assembly code below?

```asm
<zget_readable_count>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L21
  mov    0x4(%rsp),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L21:
  mov    $0xffffffff,%eax
  jmp    L9
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int zget_readable_count(int fd) {
  int count;
  return (ioctl(fd, FIONREAD, (char *)&count) < 0 ? -1 : count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initialize_hash_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initialize_hash_function(const unsigned char *pub_seed, const unsigned char *sk_seed) {
  (void)pub_seed;
  (void)sk_seed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<initialize_hash_function>:
  endbr64
  ret
```

assistant: ```c
void initialize_hash_function(const unsigned char *pub_seed, const unsigned char *sk_seed) {
  (void)pub_seed;
  (void)sk_seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<initialize_hash_function>:
  endbr64
  ret
```

assistant: ```c
void initialize_hash_function(const unsigned char *pub_seed, const unsigned char *sk_seed) {
  (void)pub_seed;
  (void)sk_seed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<initialize_hash_function>:
  endbr64
  ret
```

assistant: ```c
void initialize_hash_function(const unsigned char *pub_seed, const unsigned char *sk_seed) {
  (void)pub_seed;
  (void)sk_seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cut_rod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L40
  mov    $0x0,%eax
  jmp    L35
L40:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L21
L25:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x2c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cut_rod>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L36
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L36:
  addl   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L25
  mov    -0x1c(%rbp),%eax
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int cut_rod(int price_table[], int n) {
  if (n == 0) {
    return 0;
  }
  int max = INT_MIN;
  for (int i = 0; i < n; i++) {
    int p = price_table[i] + cut_rod(price_table, n - i);
    if (p > max) {
      max = p;
    }
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cut_rod>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %esi,%esi
  je     L6
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    D0(%rip),%rax
  mov    (%rax),%ebp
  jle    L6
  mov    %esi,%r14d
  mov    $0x0,%ebx
L1:
  mov    0x0(%r13,%rbx,4),%r15d
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    %r13,%rdi
  call   <cut_rod>
  add    %r15d,%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L1
L6:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cut_rod(int price_table[], int n) {
  if (n == 0) {
    return 0;
  }
  int max = INT_MIN;
  for (int i = 0; i < n; i++) {
    int p = price_table[i] + cut_rod(price_table, n - i);
    if (p > max) {
      max = p;
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xa00,%edi
  call   <adc_open@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gdb_stdio_printf@plt>
L17:
  nop
L23:
  lea    -0xa10(%rbp),%rax
  mov    $0x500,%esi
  mov    %rax,%rdi
  call   <adc1_read@plt>
  cmp    $0xffffffff,%eax
  je     L23
  lea    -0xa10(%rbp),%rax
  mov    $0x500,%esi
  mov    %rax,%rdi
  call   <calc_sd@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xa18(%rbp)
  nop
L12:
  lea    -0xa10(%rbp),%rax
  mov    $0x500,%esi
  mov    %rax,%rdi
  call   <adc2_read@plt>
  cmp    $0xffffffff,%eax
  je     L12
  lea    -0xa10(%rbp),%rax
  mov    $0x500,%esi
  mov    %rax,%rdi
  call   <calc_sd@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xa14(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xa14(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0xa18(%rbp),%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <gdb_stdio_printf@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D2: Starting!


tool: D11: adc1: %5.1f adc2: %5.1f


assistant: ```c
int main(void) {
  short buf[(320 * 4)];
  float sd1, sd2;
  adc_open(2 * (320 * 4));
  gdb_stdio_printf("Starting!\n");
  while (1) {
    while (adc1_read(buf, (320 * 4)) == -1)
      ;
    sd1 = calc_sd(buf, (320 * 4));
    while (adc2_read(buf, (320 * 4)) == -1)
      ;
    sd2 = calc_sd(buf, (320 * 4));
    gdb_stdio_printf("adc1: %5.1f adc2: %5.1f\n", (double)sd1, (double)sd2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xa28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa18(%rsp)
  xor    %eax,%eax
  mov    $0xa00,%edi
  call   <adc_open@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <gdb_stdio_printf@plt>
  lea    0x10(%rsp),%rbx
  lea    D4(%rip),%rbp
L0:
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <adc1_read@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <calc_sd@plt>
  movss  %xmm0,0xc(%rsp)
L18:
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <adc2_read@plt>
  cmp    $0xffffffff,%eax
  je     L18
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <calc_sd@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <gdb_stdio_printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string

tool: D7: Starting!


tool: D4: adc1: %5.1f adc2: %5.1f


assistant: ```c
int main(void) {
  short buf[(320 * 4)];
  float sd1, sd2;
  adc_open(2 * (320 * 4));
  gdb_stdio_printf("Starting!\n");
  while (1) {
    while (adc1_read(buf, (320 * 4)) == -1)
      ;
    sd1 = calc_sd(buf, (320 * 4));
    while (adc2_read(buf, (320 * 4)) == -1)
      ;
    sd2 = calc_sd(buf, (320 * 4));
    gdb_stdio_printf("adc1: %5.1f adc2: %5.1f\n", (double)sd1, (double)sd2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xa00,%edi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0xa10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <adc_open@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <gdb_stdio_printf@plt>
  nopl   0x0(%rax)
L12:
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <adc1_read@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <calc_sd@plt>
  movd   %xmm0,%r14d
L23:
  mov    $0x500,%esi
  mov    %rbx,%rdi
  call   <adc2_read@plt>
  cmp    $0xffffffff,%eax
  je     L23
  mov    %rbx,%rdi
  mov    $0x500,%esi
  call   <calc_sd@plt>
  movd   %r14d,%xmm2
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <gdb_stdio_printf@plt>
  jmp    L12
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string

tool: D3: adc1: %5.1f adc2: %5.1f


tool: D17: Starting!


assistant: ```c
int main(void) {
  short buf[(320 * 4)];
  float sd1, sd2;
  adc_open(2 * (320 * 4));
  gdb_stdio_printf("Starting!\n");
  while (1) {
    while (adc1_read(buf, (320 * 4)) == -1)
      ;
    sd1 = calc_sd(buf, (320 * 4));
    while (adc2_read(buf, (320 * 4)) == -1)
      ;
    sd2 = calc_sd(buf, (320 * 4));
    gdb_stdio_printf("adc1: %5.1f adc2: %5.1f\n", (double)sd1, (double)sd2);
  }
}
```