ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
void h() {
  int malloc(int);
  int strcpy(int);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
void h() {
  int malloc(int);
  int strcpy(int);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<h>:
  endbr64
  ret
```

assistant: ```c
void h() {
  int malloc(int);
  int strcpy(int);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L20
  mov    $0x1,%eax
  jmp    L16
L20:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int permcmp(int *perm1, int *perm2, int n) {
  int i;
  for (i = 0; i < n; i++)
    if (perm1[i] != perm2[i])
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<permcmp>:
  endbr64
  test   %edx,%edx
  jle    L26
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
  mov    $0x0,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int permcmp(int *perm1, int *perm2, int n) {
  int i;
  for (i = 0; i < n; i++)
    if (perm1[i] != perm2[i])
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<permcmp>:
  endbr64
  test   %edx,%edx
  jle    L24
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L33
  nop
L31:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L24
L33:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L31
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int permcmp(int *perm1, int *perm2, int n) {
  int i;
  for (i = 0; i < n; i++)
    if (perm1[i] != perm2[i])
      return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<permcmp>:
  endbr64
  test   %edx,%edx
  jle    L37
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L11
  nop
L30:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L37
L11:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L30
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
int permcmp(int *perm1, int *perm2, int n) {
  int i;
  for (i = 0; i < n; i++)
    if (perm1[i] != perm2[i])
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L10
L16:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
char *strdup(const char *s) {
  char *new_string = malloc(strlen(s) + 1);
  if (!new_string)
    return errno = ENOMEM, NULL;
  strcpy(new_string, s);
  return new_string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L0
```

assistant: ```c
char *strdup(const char *s) {
  char *new_string = malloc(strlen(s) + 1);
  if (!new_string)
    return errno = ENOMEM, NULL;
  strcpy(new_string, s);
  return new_string;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    D16(%rip),%rax
  mov    (%rax),%rdx
  mov    D8(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L18
```

assistant: ```c
char *strdup(const char *s) {
  char *new_string = malloc(strlen(s) + 1);
  if (!new_string)
    return errno = ENOMEM, NULL;
  strcpy(new_string, s);
  return new_string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    D15(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    %rdx,(%rax)
  jmp    L5
```

assistant: ```c
char *strdup(const char *s) {
  char *new_string = malloc(strlen(s) + 1);
  if (!new_string)
    return errno = ENOMEM, NULL;
  strcpy(new_string, s);
  return new_string;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd,%esi
  mov    $0xc,%edi
  call   <min@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xc,-0x4(%rbp)
  je     L13
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    $0xc,%esi
  mov    $0xd,%edi
  call   <min@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xc,-0x4(%rbp)
  je     L16
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: string
name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D25: Test failed


tool: D5: All tests performed - if no error all passed


assistant: ```c
int main() {
  int ret = min(12, 13);
  if (ret != 12) {
    printf("Test failed\n");
  }
  ret = min(13, 12);
  if (ret != 12) {
    printf("Test failed\n");
  }
  printf("All tests performed - if no error all passed\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0xc,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  jne    L39
L23:
  mov    $0xc,%esi
  mov    $0xd,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  jne    L32
L25:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L39:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L32:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D1: All tests performed - if no error all passed


tool: D12: Test failed


assistant: ```c
int main() {
  int ret = min(12, 13);
  if (ret != 12) {
    printf("Test failed\n");
  }
  ret = min(13, 12);
  if (ret != 12) {
    printf("Test failed\n");
  }
  printf("All tests performed - if no error all passed\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0xc,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  je     L16
  lea    D7(%rip),%rdi
  call   <printf@plt>
L16:
  mov    $0xc,%esi
  mov    $0xd,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  je     L1
  lea    D7(%rip),%rdi
  call   <printf@plt>
L1:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D7: Test failed


tool: D13: All tests performed - if no error all passed


assistant: ```c
int main() {
  int ret = min(12, 13);
  if (ret != 12) {
    printf("Test failed\n");
  }
  ret = min(13, 12);
  if (ret != 12) {
    printf("Test failed\n");
  }
  printf("All tests performed - if no error all passed\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%esi
  mov    $0xc,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  je     L13
  lea    D21(%rip),%rdi
  call   <printf@plt>
L13:
  mov    $0xc,%esi
  mov    $0xd,%edi
  call   <min@plt>
  cmp    $0xc,%eax
  je     L9
  lea    D21(%rip),%rdi
  call   <printf@plt>
L9:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D21: Test failed


tool: D2: All tests performed - if no error all passed


assistant: ```c
int main() {
  int ret = min(12, 13);
  if (ret != 12) {
    printf("Test failed\n");
  }
  ret = min(13, 12);
  if (ret != 12) {
    printf("Test failed\n");
  }
  printf("All tests performed - if no error all passed\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<contains_illegals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L39
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5,%al
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L38
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
L38:
  mov    $0x1,%eax
  jmp    L75
L1:
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L70
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L31
L70:
  mov    $0x0,%eax
L75:
  leave
  ret
```

assistant: ```c
int contains_illegals(const char *string, const char *illegals, int len) {
  for (; *string && len--; string++)
    if ((*string < ' ' && *string != '\005' && !(*string & 0x80)) || strchr(illegals, *string))
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<contains_illegals>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L79
  mov    %rdi,%rbx
  test   %edx,%edx
  je     L43
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rbp
  jmp    L36
L49:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L57
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L3
  cmp    %rbp,%rbx
  je     L73
L36:
  cmp    $0x5,%sil
  je     L49
  cmp    $0x1f,%sil
  ja     L49
  mov    $0x1,%eax
  jmp    L73
L79:
  mov    $0x0,%eax
  jmp    L73
L43:
  mov    %edx,%eax
  jmp    L73
L57:
  mov    $0x1,%eax
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x0,%eax
  jmp    L73
```

assistant: ```c
int contains_illegals(const char *string, const char *illegals, int len) {
  for (; *string && len--; string++)
    if ((*string < ' ' && *string != '\005' && !(*string & 0x80)) || strchr(illegals, *string))
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<contains_illegals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L24
  test   %edx,%edx
  je     L24
  mov    %edx,%edx
  mov    %rdi,%rbx
  lea    (%rdi,%rdx,1),%rbp
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L24
  cmp    %rbx,%rbp
  je     L24
L27:
  cmp    $0x5,%sil
  je     L78
  cmp    $0x1f,%sil
  jbe    L28
L78:
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L18
L28:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int contains_illegals(const char *string, const char *illegals, int len) {
  for (; *string && len--; string++)
    if ((*string < ' ' && *string != '\005' && !(*string & 0x80)) || strchr(illegals, *string))
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<contains_illegals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L77
  test   %edx,%edx
  je     L77
  mov    %edx,%edx
  mov    %rdi,%rbx
  lea    (%rdi,%rdx,1),%rbp
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L23:
  movsbl 0x1(%rbx),%esi
  add    $0x1,%rbx
  test   %sil,%sil
  je     L77
  cmp    %rbx,%rbp
  je     L77
L63:
  cmp    $0x5,%sil
  je     L73
  cmp    $0x1f,%sil
  jbe    L72
L73:
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L23
L72:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L77:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int contains_illegals(const char *string, const char *illegals, int len) {
  for (; *string && len--; string++)
    if ((*string < ' ' && *string != '\005' && !(*string & 0x80)) || strchr(illegals, *string))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CDRgetTD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    $0x3,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
long CDRgetTD(unsigned char track, unsigned char *buffer) {
  memset(buffer + 1, 0, 3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CDRgetTD>:
  endbr64
  sub    $0x8,%rsp
  lea    0x1(%rsi),%rdi
  mov    $0x3,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long CDRgetTD(unsigned char track, unsigned char *buffer) {
  memset(buffer + 1, 0, 3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CDRgetTD>:
  endbr64
  sub    $0x8,%rsp
  lea    0x1(%rsi),%rdi
  mov    $0x3,%edx
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long CDRgetTD(unsigned char track, unsigned char *buffer) {
  memset(buffer + 1, 0, 3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CDRgetTD>:
  endbr64
  sub    $0x8,%rsp
  lea    0x1(%rsi),%rdi
  mov    $0x3,%edx
  xor    %esi,%esi
  call   <memset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long CDRgetTD(unsigned char track, unsigned char *buffer) {
  memset(buffer + 1, 0, 3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ru>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L23
L56:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <ru>
  test   %eax,%eax
  je     L22
  mov    $0x1,%eax
  jmp    L51
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L47
  mov    $0x0,%eax
  jmp    L51
L47:
  addq   $0x1,-0x8(%rbp)
L22:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  sete   %al
  movzbl %al,%eax
L51:
  leave
  ret
```

assistant: ```c
int ru(char *s, char *p) {
  while (*s != '\0') {
    if (*p == '*') {
      if (ru(s + 1, p)) {
        return 1;
      }
    } else {
      if (*s != *p) {
        return 0;
      }
      s++;
    }
    p++;
  }
  return (*s) == (*p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ru>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L29
L19:
  cmpb   $0x0,(%rbx)
  sete   %al
  movzbl %al,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  lea    0x1(%rbp),%rdi
  mov    %rbx,%rsi
  call   <ru>
  test   %eax,%eax
  je     L9
  mov    $0x1,%eax
  jmp    L25
L14:
  add    $0x1,%rbp
L9:
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L19
L29:
  movzbl (%rbx),%edx
  cmp    $0x2a,%dl
  je     L41
  cmp    %al,%dl
  je     L14
  mov    $0x0,%eax
  jmp    L25
```

assistant: ```c
int ru(char *s, char *p) {
  while (*s != '\0') {
    if (*p == '*') {
      if (ru(s + 1, p)) {
        return 1;
      }
    } else {
      if (*s != *p) {
        return 0;
      }
      s++;
    }
    p++;
  }
  return (*s) == (*p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ru>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L59
  mov    %rdi,%rbp
  jmp    L41
  nopl   0x0(%rax)
L39:
  cmp    %al,%dl
  jne    L63
  add    $0x1,%rbp
L42:
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L59
L41:
  movzbl (%rbx),%edx
  cmp    $0x2a,%dl
  jne    L39
  lea    0x1(%rbp),%rdi
  mov    %rbx,%rsi
  call   <ru>
  test   %eax,%eax
  je     L42
  mov    $0x1,%eax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  sete   %al
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ru(char *s, char *p) {
  while (*s != '\0') {
    if (*p == '*') {
      if (ru(s + 1, p)) {
        return 1;
      }
    } else {
      if (*s != *p) {
        return 0;
      }
      s++;
    }
    p++;
  }
  return (*s) == (*p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strconcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L7
  addl   $0x1,-0x1c(%rbp)
  jmp    L8
L7:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L44
  subl   $0x1,-0x14(%rbp)
  jmp    L8
L44:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L13
  subl   $0x1,-0x10(%rbp)
  jmp    L8
L13:
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L8
  addl   $0x1,-0x18(%rbp)
L8:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L78
L30:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L78:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L30
  jmp    L32
L36:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L36
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *my_strconcat(const char *v1, const char *v2) {
  int j = 0, k = 0;
  int sizev1 = length(v1);
  int sizev2 = length(v2);
  int size = 0;
  if (v1[0] == '"')
    j++;
  else if (v1[sizev1] == '"')
    sizev1--;
  else if (v2[sizev2] == '"')
    sizev2--;
  else if (v2[2] == '"')
    k++;
  size = sizev1 + sizev2;
  char *tab;
  tab = calloc(size, sizeof(char));
  for (j; sizev1 >= j; j++) {
    tab[j] = v1[j];
  }
  for (k; sizev2 >= k; k++) {
    tab[sizev1 + k] = v2[k];
  }
  return tab;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strconcat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  call   <length@plt>
  mov    %eax,%ebp
  mov    %r13,%rdi
  call   <length@plt>
  mov    %eax,%r12d
  cmpb   $0x22,(%r14)
  je     L69
  movslq %ebp,%rax
  cmpb   $0x22,(%r14,%rax,1)
  je     L12
  movslq %r12d,%rax
  cmpb   $0x22,0x0(%r13,%rax,1)
  je     L17
  cmpb   $0x22,0x2(%r13)
  sete   %bl
  movzbl %bl,%ebx
  mov    $0x0,%r15d
  jmp    L6
L12:
  sub    $0x1,%ebp
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  jmp    L6
L17:
  sub    $0x1,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  jmp    L6
L69:
  mov    $0x0,%ebx
  mov    $0x1,%r15d
L6:
  lea    0x0(%rbp,%r12,1),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  cmp    %ebp,%r15d
  jg     L73
  movslq %r15d,%rdx
L4:
  movzbl (%r14,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebp
  jge    L4
L73:
  cmp    %r12d,%ebx
  jg     L2
  movslq %ebx,%rdx
  movslq %ebp,%rbp
  add    %rax,%rbp
L87:
  movzbl 0x0(%r13,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jge    L87
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *my_strconcat(const char *v1, const char *v2) {
  int j = 0, k = 0;
  int sizev1 = length(v1);
  int sizev2 = length(v2);
  int size = 0;
  if (v1[0] == '"')
    j++;
  else if (v1[sizev1] == '"')
    sizev1--;
  else if (v2[sizev2] == '"')
    sizev2--;
  else if (v2[2] == '"')
    k++;
  size = sizev1 + sizev2;
  char *tab;
  tab = calloc(size, sizeof(char));
  for (j; sizev1 >= j; j++) {
    tab[j] = v1[j];
  }
  for (k; sizev2 >= k; k++) {
    tab[sizev1 + k] = v2[k];
  }
  return tab;
}
```