ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x25,0x4(%rsp)
  movl   $0x4f,0x8(%rsp)
  movl   $0x80,0xc(%rsp)
  movl   $0x391,0x10(%rsp)
  movl   $0x2cb,0x14(%rsp)
  movl   $0xbd,0x18(%rsp)
  movl   $0x356,0x1c(%rsp)
  movl   $0x2ad,0x20(%rsp)
  movl   $0xc,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    %rsp,%rbx
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <radixSort@plt>
  lea    0x2c(%rsp),%r12
  lea    D2(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: %d 

assistant: ```c
int main() {
  int v[] = {5, 37, 79, 128, 913, 715, 189, 854, 685, 12, 0};
  int n = sizeof(v) / sizeof(v[0]);
  int i;
  radixSort(v, n);
  for (i = 0; i < n; ++i)
    printf("%d ", v[i]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x2500000005,%rax
  mov    %rsp,%rbx
  lea    0x2c(%rsp),%r12
  movl   $0x0,0x28(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x800000004f,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2cb00000391,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x356000000bd,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xc000002ad,%rax
  mov    %rax,0x20(%rsp)
  call   <radixSort@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
int main() {
  int v[] = {5, 37, 79, 128, 913, 715, 189, 854, 685, 12, 0};
  int n = sizeof(v) / sizeof(v[0]);
  int i;
  radixSort(v, n);
  for (i = 0; i < n; ++i)
    printf("%d ", v[i]);
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%esi
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x2c(%rsp),%r12
  mov    D18(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D35(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <radixSort@plt>
  nopl   (%rax)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D37
data_type: byte[16]
name: disassemble_data
arguments: tag: D18
data_type: byte[8]
name: disassemble_data
arguments: tag: D35
data_type: byte[16]

tool: D29: %d 

tool: {"D37": [0x05,0x00,0x00,0x00,0x25,0x00,0x00,0x00,0x4f,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

tool: {"D18": [0xad,0x02,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D35": [0x91,0x03,0x00,0x00,0xcb,0x02,0x00,0x00,0xbd,0x00,0x00,0x00,0x56,0x03,0x00,0x00]}

assistant: ```c
int main() {
  int v[] = {5, 37, 79, 128, 913, 715, 189, 854, 685, 12, 0};
  int n = sizeof(v) / sizeof(v[0]);
  int i;
  radixSort(v, n);
  for (i = 0; i < n; ++i)
    printf("%d ", v[i]);
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  nop
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r0 = a;
  int r1 = b;
  int gcd_ab;
  while (1) {
    int q2 = r0 / r1;
    int r2 = r0 - r1 * q2;
    r0 = r1, r1 = r2;
    if (r2 == 0) {
      gcd_ab = r0;
      break;
    }
  }
  return gcd_ab;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
L0:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L0
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r0 = a;
  int r1 = b;
  int gcd_ab;
  while (1) {
    int q2 = r0 / r1;
    int r2 = r0 - r1 * q2;
    r0 = r1, r1 = r2;
    if (r2 == 0) {
      gcd_ab = r0;
      break;
    }
  }
  return gcd_ab;
}
```
user: What is the c source code of the assembly code below?

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L9
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r0 = a;
  int r1 = b;
  int gcd_ab;
  while (1) {
    int q2 = r0 / r1;
    int r2 = r0 - r1 * q2;
    r0 = r1, r1 = r2;
    if (r2 == 0) {
      gcd_ab = r0;
      break;
    }
  }
  return gcd_ab;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edx,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L4
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int r0 = a;
  int r1 = b;
  int gcd_ab;
  while (1) {
    int q2 = r0 / r1;
    int r2 = r0 - r1 * q2;
    r0 = r1, r1 = r2;
    if (r2 == 0) {
      gcd_ab = r0;
      break;
    }
  }
  return gcd_ab;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HibernateIntUnregister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3b,%edi
  call   <IntDisable@plt>
  mov    $0x3b,%edi
  call   <IntUnregister@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void HibernateIntUnregister(void) {
  IntDisable(59);
  IntUnregister(59);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HibernateIntUnregister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b,%edi
  call   <IntDisable@plt>
  mov    $0x3b,%edi
  call   <IntUnregister@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void HibernateIntUnregister(void) {
  IntDisable(59);
  IntUnregister(59);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<HibernateIntUnregister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b,%edi
  call   <IntDisable@plt>
  mov    $0x3b,%edi
  add    $0x8,%rsp
  jmp    1060 <IntUnregister@plt>
```

assistant: ```c
void HibernateIntUnregister(void) {
  IntDisable(59);
  IntUnregister(59);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: Hola Mundo!!

assistant: ```c
int main() {
  printf("Hola Mundo!!");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: Hola Mundo!!

assistant: ```c
int main() {
  printf("Hola Mundo!!");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: Hola Mundo!!

assistant: ```c
int main() {
  printf("Hola Mundo!!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: Hola Mundo!!

assistant: ```c
int main() {
  printf("Hola Mundo!!");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<callx5_again>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <x5@plt>
  call   <x6@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void callx5_again(void) {
  x5();
  asm("call "
      "x6");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<callx5_again>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <x5@plt>
  call   <x6@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void callx5_again(void) {
  x5();
  asm("call "
      "x6");
}
```
user: Translate the below assembly code into C programming language:

```asm
<callx5_again>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <x5@plt>
  call   <x6@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void callx5_again(void) {
  x5();
  asm("call "
      "x6");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<callx5_again>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <x5@plt>
  call   <x6@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void callx5_again(void) {
  x5();
  asm("call "
      "x6");
}
```
user: What is the c source code of the assembly code below:

```asm
<_atof>:
  endbr64
  mov    %rdi,%rsi
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L111
L39:
  test   %dl,%dl
  je     L99
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jle    L39
L111:
  cmp    $0x2b,%dl
  je     L79
  movss  D24(%rip),%xmm0
  cmp    $0x2d,%dl
  jne    L73
  add    $0x1,%rax
  movss  D8(%rip),%xmm0
  jmp    L73
L79:
  add    $0x1,%rax
  movss  D24(%rip),%xmm0
L73:
  movzbl (%rax),%edx
  pxor   %xmm1,%xmm1
  cmp    $0x2e,%dl
  je     L89
  add    $0x1,%rax
  movsbl %dl,%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  ja     L46
  movss  D3(%rip),%xmm3
L134:
  mulss  %xmm3,%xmm1
  sub    $0x30,%ecx
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm2
  addss  %xmm2,%xmm1
  add    $0x1,%rax
  movsbl -0x1(%rax),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  jbe    L134
L89:
  cmp    $0x2e,%ecx
  je     L141
L133:
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
L112:
  mov    %rax,(%rsi)
  ret
L46:
  pxor   %xmm1,%xmm1
  jmp    L89
L141:
  lea    0x1(%rax),%rdx
  movsbl (%rax),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  ja     L36
  movsd  D35(%rip),%xmm3
  movapd %xmm3,%xmm4
L5:
  sub    $0x30,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm3,%xmm2
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulsd  %xmm4,%xmm3
  add    $0x1,%rdx
  movsbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  jbe    L5
  mov    %rdx,%rax
  jmp    L133
L36:
  mov    %rdx,%rax
  jmp    L133
L99:
  pxor   %xmm0,%xmm0
  jmp    L112
```

tool_calls: name: parse_data
arguments: data_label: D24
type: byte[4]
name: parse_data
arguments: data_label: D8
type: byte[4]
name: parse_data
arguments: data_label: D3
type: byte[4]
name: parse_data
arguments: data_label: D35
type: f64

tool: {"D24": [0x00,0x00,0x80,0x3f]}

tool: {"D8": [0x00,0x00,0x80,0xbf]}

tool: {"D3": [0x00,0x00,0x20,0x41]}

tool: D35: 0.1

assistant: ```c
double _atof(const char **stringPtr) {
  const char *string;
  float sign;
  float value;
  int c;
  string = *stringPtr;
  while (*string <= ' ') {
    if (!*string) {
      *stringPtr = string;
      return 0;
    }
    string++;
  }
  switch (*string) {
  case '+':
    string++;
    sign = 1;
    break;
  case '-':
    string++;
    sign = -1;
    break;
  default:
    sign = 1;
    break;
  }
  value = 0;
  if (string[0] != '.') {
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value = value * 10 + c;
    } while (1);
  }
  if (c == '.') {
    double fraction;
    fraction = 0.1;
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value += c * fraction;
      fraction *= 0.1;
    } while (1);
  }
  *stringPtr = string;
  return value * sign;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_atof>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jle    L19
  jmp    L137
  nopl   0x0(%rax)
L49:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L137
L19:
  test   %dl,%dl
  jne    L49
  mov    %rax,(%rdi)
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L137:
  cmp    $0x2b,%dl
  je     L30
  cmp    $0x2d,%dl
  je     L136
L11:
  movss  D27(%rip),%xmm0
L78:
  movzbl (%rax),%edx
  pxor   %xmm1,%xmm1
  cmp    $0x2e,%dl
  je     L58
  movsbl %dl,%ecx
  add    $0x1,%rax
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  ja     L58
  movss  D4(%rip),%xmm3
  nopl   (%rax)
L146:
  mulss  %xmm3,%xmm1
  pxor   %xmm2,%xmm2
  movsbl (%rax),%ecx
  add    $0x1,%rax
  cvtsi2ss %edx,%xmm2
  lea    -0x30(%rcx),%edx
  addss  %xmm2,%xmm1
  cmp    $0x9,%edx
  jbe    L146
L58:
  cmp    $0x2e,%ecx
  je     L15
L31:
  mulss  %xmm1,%xmm0
  mov    %rax,(%rdi)
  cvtss2sd %xmm0,%xmm0
  ret
L136:
  movss  D2(%rip),%xmm0
  add    $0x1,%rax
  jmp    L78
  xchg   %ax,%ax
L30:
  add    $0x1,%rax
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L15:
  movsbl (%rax),%edx
  lea    0x1(%rax),%rcx
  mov    %rcx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L31
  movsd  D21(%rip),%xmm4
  movapd %xmm4,%xmm3
  xchg   %ax,%ax
L34:
  pxor   %xmm2,%xmm2
  add    $0x1,%rax
  cvtss2sd %xmm1,%xmm1
  cvtsi2sd %edx,%xmm2
  movsbl -0x1(%rax),%edx
  sub    $0x30,%edx
  mulsd  %xmm3,%xmm2
  mulsd  %xmm4,%xmm3
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cmp    $0x9,%edx
  jbe    L34
  jmp    L31
```

tool_calls: name: unpack_data
arguments: tag: D27
data_type: byte[4]
name: unpack_data
arguments: tag: D4
data_type: byte[4]
name: unpack_data
arguments: tag: D2
data_type: byte[4]
name: unpack_data
arguments: tag: D21
data_type: f64

tool: {"D27": [0x00,0x00,0x80,0x3f]}

tool: {"D4": [0x00,0x00,0x20,0x41]}

tool: {"D2": [0x00,0x00,0x80,0xbf]}

tool: D21: 0.1

assistant: ```c
double _atof(const char **stringPtr) {
  const char *string;
  float sign;
  float value;
  int c;
  string = *stringPtr;
  while (*string <= ' ') {
    if (!*string) {
      *stringPtr = string;
      return 0;
    }
    string++;
  }
  switch (*string) {
  case '+':
    string++;
    sign = 1;
    break;
  case '-':
    string++;
    sign = -1;
    break;
  default:
    sign = 1;
    break;
  }
  value = 0;
  if (string[0] != '.') {
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value = value * 10 + c;
    } while (1);
  }
  if (c == '.') {
    double fraction;
    fraction = 0.1;
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value += c * fraction;
      fraction *= 0.1;
    } while (1);
  }
  *stringPtr = string;
  return value * sign;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_atof>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jle    L30
  jmp    L128
  nopl   0x0(%rax)
L78:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L128
L30:
  test   %dl,%dl
  jne    L78
  mov    %rax,(%rdi)
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L128:
  cmp    $0x2b,%dl
  je     L75
  cmp    $0x2d,%dl
  je     L38
L92:
  movss  D31(%rip),%xmm0
L110:
  pxor   %xmm1,%xmm1
  cmp    $0x2e,%dl
  je     L89
  movsbl %dl,%ecx
  add    $0x1,%rax
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  ja     L89
  movss  D26(%rip),%xmm3
  nopw   0x0(%rax,%rax,1)
L109:
  mulss  %xmm3,%xmm1
  pxor   %xmm2,%xmm2
  movsbl (%rax),%ecx
  add    $0x1,%rax
  cvtsi2ss %edx,%xmm2
  lea    -0x30(%rcx),%edx
  addss  %xmm2,%xmm1
  cmp    $0x9,%edx
  jbe    L109
L89:
  cmp    $0x2e,%ecx
  je     L142
L37:
  mulss  %xmm1,%xmm0
  mov    %rax,(%rdi)
  cvtss2sd %xmm0,%xmm0
  ret
L38:
  movzbl 0x1(%rax),%edx
  movss  D12(%rip),%xmm0
  add    $0x1,%rax
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L75:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L142:
  movsbl (%rax),%edx
  lea    0x1(%rax),%rcx
  mov    %rcx,%rax
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L37
  movsd  D25(%rip),%xmm4
  movapd %xmm4,%xmm3
  cs nopw 0x0(%rax,%rax,1)
L19:
  pxor   %xmm2,%xmm2
  add    $0x1,%rax
  cvtss2sd %xmm1,%xmm1
  cvtsi2sd %edx,%xmm2
  movsbl -0x1(%rax),%edx
  sub    $0x30,%edx
  mulsd  %xmm3,%xmm2
  mulsd  %xmm4,%xmm3
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  cmp    $0x9,%edx
  jbe    L19
  jmp    L37
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D26
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D12
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D25
type_infered: f64

tool: {"D31": [0x00,0x00,0x80,0x3f]}

tool: {"D26": [0x00,0x00,0x20,0x41]}

tool: {"D12": [0x00,0x00,0x80,0xbf]}

tool: D25: 0.1

assistant: ```c
double _atof(const char **stringPtr) {
  const char *string;
  float sign;
  float value;
  int c;
  string = *stringPtr;
  while (*string <= ' ') {
    if (!*string) {
      *stringPtr = string;
      return 0;
    }
    string++;
  }
  switch (*string) {
  case '+':
    string++;
    sign = 1;
    break;
  case '-':
    string++;
    sign = -1;
    break;
  default:
    sign = 1;
    break;
  }
  value = 0;
  if (string[0] != '.') {
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value = value * 10 + c;
    } while (1);
  }
  if (c == '.') {
    double fraction;
    fraction = 0.1;
    do {
      c = *string++;
      if (c < '0' || c > '9') {
        break;
      }
      c -= '0';
      value += c * fraction;
      fraction *= 0.1;
    } while (1);
  }
  *stringPtr = string;
  return value * sign;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L11
  mov    $0x0,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L15
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  divsd  %xmm3,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  cmpl   $0x2,-0x4(%rbp)
  jne    L51
  mov    $0xa,%eax
  jmp    L43
L51:
  mov    $0x20,%eax
L43:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x2,-0x4(%rbp)
  jle    L49
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: %.4f

assistant: ```c
int print(int *j, int *r, int index) {
  for (int i = 0; i < 3; i++) {
    if (i == index) {
      printf("%.4f", 0.0f);
    } else {
      printf("%.4f", j[i] - j[index] * (r[i] / (double)r[index]));
    }
    putchar(i == 2 ? '\n' : ' ');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r12d
  movslq %edx,%rbp
  shl    $0x2,%rbp
  lea    (%rdi,%rbp,1),%r15
  add    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D8(%rip),%r14
L9:
  cmp    %ebx,%r12d
  je     L27
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x0(%r13,%rbx,4),%xmm1
  mov    0x8(%rsp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rax,%rbx,4),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl 0x0(%rbp),%xmm2
  divsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%r15),%xmm2
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L13:
  cmp    $0x2,%rbx
  je     L39
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  jmp    L9
L27:
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L13
L39:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: %.4f

assistant: ```c
int print(int *j, int *r, int index) {
  for (int i = 0; i < 3; i++) {
    if (i == index) {
      printf("%.4f", 0.0f);
    } else {
      printf("%.4f", j[i] - j[index] * (r[i] / (double)r[index]));
    }
    putchar(i == 2 ? '\n' : ' ');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  movslq %edx,%rbx
  mov    %rbx,%rbp
  shl    $0x2,%rbx
  lea    (%rsi,%rbx,1),%rax
  lea    (%rdi,%rbx,1),%r15
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  cmp    %ebx,%ebp
  je     L1
L14:
  mov    0x8(%rsp),%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %r14,%rdi
  cvtsi2sdl (%r12,%rbx,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rax),%xmm2
  cvtsi2sdl 0x0(%r13,%rbx,4),%xmm1
  divsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%r15),%xmm2
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  call   <printf@plt>
  cmp    $0x2,%rbx
  je     L9
L27:
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L14
L1:
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0x2,%rbx
  jne    L27
L9:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: %.4f

assistant: ```c
int print(int *j, int *r, int index) {
  for (int i = 0; i < 3; i++) {
    if (i == index) {
      printf("%.4f", 0.0f);
    } else {
      printf("%.4f", j[i] - j[index] * (r[i] / (double)r[index]));
    }
    putchar(i == 2 ? '\n' : ' ');
  }
}
```