ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<showElapsedTime>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <makeHumanReadableTime@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xd0,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: Elapsed %s


assistant: ```c
void showElapsedTime(uint64_t elapsedTime) {
  char _elapsedTimeHR[200];
  makeHumanReadableTime(_elapsedTimeHR, elapsedTime);
  printf("Elapsed %s\n", _elapsedTimeHR);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parseSpecificAttrFromRequest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <parseChars@plt>
  jmp    L16
L0:
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
char *parseSpecificAttrFromRequest(const char *request, char *attr, int maxlength) {
  char *startPos = strstr(request, attr);
  if (startPos != NULL) {
    startPos += strlen(attr);
    int pos = startPos - request;
    return parseChars(request, pos, maxlength);
  } else {
    return NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parseSpecificAttrFromRequest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%rax,%rbx,1),%esi
  mov    %r13d,%edx
  sub    %ebp,%esi
  mov    %rbp,%rdi
  call   <parseChars@plt>
  mov    %rax,%rbx
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *parseSpecificAttrFromRequest(const char *request, char *attr, int maxlength) {
  char *startPos = strstr(request, attr);
  if (startPos != NULL) {
    startPos += strlen(attr);
    int pos = startPos - request;
    return parseChars(request, pos, maxlength);
  } else {
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parseSpecificAttrFromRequest>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L4
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r13d,%edx
  mov    %rbp,%rdi
  lea    (%rax,%rbx,1),%esi
  pop    %rbx
  sub    %ebp,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <parseChars@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *parseSpecificAttrFromRequest(const char *request, char *attr, int maxlength) {
  char *startPos = strstr(request, attr);
  if (startPos != NULL) {
    startPos += strlen(attr);
    int pos = startPos - request;
    return parseChars(request, pos, maxlength);
  } else {
    return NULL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseSpecificAttrFromRequest>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L7
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r13d,%edx
  mov    %rbp,%rdi
  lea    (%rax,%rbx,1),%esi
  pop    %rbx
  sub    %ebp,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <parseChars@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *parseSpecificAttrFromRequest(const char *request, char *attr, int maxlength) {
  char *startPos = strstr(request, attr);
  if (startPos != NULL) {
    startPos += strlen(attr);
    int pos = startPos - request;
    return parseChars(request, pos, maxlength);
  } else {
    return NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hammingDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L20:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  addl   $0x1,-0x4(%rbp)
L1:
  sarl   -0x8(%rbp)
L19:
  cmpl   $0x0,-0x8(%rbp)
  jne    L20
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int xor = x ^ y;
  int result = 0;
  while (xor) {
    if (xor&1) {
      result++;
    }
    xor >>= 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hammingDistance>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  cmp    %esi,%edi
  je     L22
  mov    $0x0,%edx
L18:
  mov    %eax,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  sbb    $0xffffffff,%edx
  sar    %eax
  jne    L18
L2:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
int hammingDistance(int x, int y) {
  int xor = x ^ y;
  int result = 0;
  while (xor) {
    if (xor&1) {
      result++;
    }
    xor >>= 1;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hammingDistance>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  xor    %esi,%eax
  cmp    %esi,%edi
  je     L18
  nop
L2:
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %eax
  jne    L2
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int xor = x ^ y;
  int result = 0;
  while (xor) {
    if (xor&1) {
      result++;
    }
    xor >>= 1;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hammingDistance>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  xor    %esi,%eax
  cmp    %esi,%edi
  je     L19
  nop
L4:
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r8d
  sar    %eax
  jne    L4
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hammingDistance(int x, int y) {
  int xor = x ^ y;
  int result = 0;
  while (xor) {
    if (xor&1) {
      result++;
    }
    xor >>= 1;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_array_of_zeros_ones_and_twos_ver2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L77
  cmpl   $0x0,-0x1c(%rbp)
  jle    L77
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L54
L48:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  jne    L79
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
  jmp    L54
L79:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L53
  addl   $0x1,-0x8(%rbp)
  jmp    L54
L53:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L48
  jmp    L72
L77:
  nop
L72:
  pop    %rbp
  ret
```

assistant: ```c
void sort_array_of_zeros_ones_and_twos_ver2(int *array, int len) {
  int low, high, mid, temp;
  if (!array || (len <= 0)) {
    return;
  }
  low = mid = 0;
  high = len - 1;
  while (mid <= high) {
    if (array[mid] == 2) {
      temp = array[mid];
      array[mid] = array[high];
      array[high] = temp;
      --high;
    } else if (array[mid] == 1) {
      ++mid;
    } else {
      temp = array[low];
      array[low] = array[mid];
      array[mid] = temp;
      ++low;
      ++mid;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort_array_of_zeros_ones_and_twos_ver2>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %esi,%esi
  jle    L10
  sub    $0x1,%esi
  mov    $0x0,%eax
  mov    $0x0,%r8d
  jmp    L44
L59:
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %r9d,(%rcx)
  movl   $0x2,(%rdx)
  sub    $0x1,%esi
L20:
  cmp    %eax,%esi
  jl     L10
L44:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    $0x2,%edx
  je     L59
  cmp    $0x1,%edx
  je     L72
  movslq %r8d,%r9
  lea    (%rdi,%r9,4),%r9
  mov    (%r9),%r10d
  mov    %edx,(%r9)
  mov    %r10d,(%rcx)
  add    $0x1,%r8d
  add    $0x1,%eax
  jmp    L20
L72:
  add    $0x1,%eax
  jmp    L20
L10:
  ret
```

assistant: ```c
void sort_array_of_zeros_ones_and_twos_ver2(int *array, int len) {
  int low, high, mid, temp;
  if (!array || (len <= 0)) {
    return;
  }
  low = mid = 0;
  high = len - 1;
  while (mid <= high) {
    if (array[mid] == 2) {
      temp = array[mid];
      array[mid] = array[high];
      array[high] = temp;
      --high;
    } else if (array[mid] == 1) {
      ++mid;
    } else {
      temp = array[low];
      array[low] = array[mid];
      array[mid] = temp;
      ++low;
      ++mid;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sort_array_of_zeros_ones_and_twos_ver2>:
  endbr64
  test   %rdi,%rdi
  je     L30
  test   %esi,%esi
  jle    L30
  sub    $0x1,%esi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%eax
  cmp    $0x1,%edx
  je     L18
  movslq %r8d,%r9
  add    $0x1,%r8d
  lea    (%rdi,%r9,4),%r9
  mov    (%r9),%r10d
  mov    %edx,(%r9)
  mov    %r10d,(%rcx)
L18:
  cmp    %eax,%esi
  jl     L30
L14:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    $0x2,%edx
  jne    L44
  movslq %esi,%rdx
  sub    $0x1,%esi
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %r9d,(%rcx)
  movl   $0x2,(%rdx)
  cmp    %eax,%esi
  jge    L14
L30:
  ret
```

assistant: ```c
void sort_array_of_zeros_ones_and_twos_ver2(int *array, int len) {
  int low, high, mid, temp;
  if (!array || (len <= 0)) {
    return;
  }
  low = mid = 0;
  high = len - 1;
  while (mid <= high) {
    if (array[mid] == 2) {
      temp = array[mid];
      array[mid] = array[high];
      array[high] = temp;
      --high;
    } else if (array[mid] == 1) {
      ++mid;
    } else {
      temp = array[low];
      array[low] = array[mid];
      array[mid] = temp;
      ++low;
      ++mid;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_array_of_zeros_ones_and_twos_ver2>:
  endbr64
  test   %rdi,%rdi
  je     L46
  test   %esi,%esi
  jle    L46
  sub    $0x1,%esi
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x1,%eax
  cmp    $0x1,%edx
  je     L41
  movslq %r8d,%r9
  add    $0x1,%r8d
  lea    (%rdi,%r9,4),%r9
  mov    (%r9),%r10d
  mov    %edx,(%r9)
  mov    %r10d,(%rcx)
L41:
  cmp    %eax,%esi
  jl     L46
L58:
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    $0x2,%edx
  jne    L42
  movslq %esi,%rdx
  sub    $0x1,%esi
  lea    (%rdi,%rdx,4),%rdx
  mov    (%rdx),%r9d
  mov    %r9d,(%rcx)
  movl   $0x2,(%rdx)
  cmp    %eax,%esi
  jge    L58
L46:
  ret
```

assistant: ```c
void sort_array_of_zeros_ones_and_twos_ver2(int *array, int len) {
  int low, high, mid, temp;
  if (!array || (len <= 0)) {
    return;
  }
  low = mid = 0;
  high = len - 1;
  while (mid <= high) {
    if (array[mid] == 2) {
      temp = array[mid];
      array[mid] = array[high];
      array[high] = temp;
      --high;
    } else if (array[mid] == 1) {
      ++mid;
    } else {
      temp = array[low];
      array[low] = array[mid];
      array[mid] = temp;
      ++low;
      ++mid;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_receive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L15
L31:
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L15
  mov    -0xc(%rbp),%eax
  jmp    L26
L15:
  lea    -0x10(%rbp),%r8
  mov    -0x30(%rbp),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L31
  mov    -0xc(%rbp),%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *addrlen) {
  socklen_t al;
  al = sizeof(struct sockaddr_storage);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  int n;
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, &al)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sock_receive>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %r8,%rdi
  call   <memset@plt>
  lea    0x4(%rsp),%r15
L11:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  jns    L1
  mov    D7(%rip),%rcx
  mov    D3(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L11
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *addrlen) {
  socklen_t al;
  al = sizeof(struct sockaddr_storage);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  int n;
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, &al)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sock_receive>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %r8,%rdi
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  movl   $0x4,0x4(%rsp)
  call   <memset@plt>
  jmp    L29
  xchg   %ax,%ax
L38:
  mov    D4(%rip),%rdx
  mov    D5(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L17
L29:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  js     L38
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *addrlen) {
  socklen_t al;
  al = sizeof(struct sockaddr_storage);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  int n;
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, &al)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sock_receive>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %r8,%rdi
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  movl   $0x4,0x4(%rsp)
  call   <memset@plt>
  jmp    L18
  xchg   %ax,%ax
L35:
  mov    D15(%rip),%rdx
  mov    D13(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L4
L18:
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <recvfrom@plt>
  test   %eax,%eax
  js     L35
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_receive(int sock, void *buf, size_t len, int flags, struct sockaddr *srcaddr, socklen_t *addrlen) {
  socklen_t al;
  al = sizeof(struct sockaddr_storage);
  memset(srcaddr, 0, sizeof(struct sockaddr));
  int n;
  while ((n = recvfrom(sock, (char *)buf, len, flags, srcaddr, &al)) < 0) {
    if (errno != EINTR)
      return n;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  and    $0x7f,%eax
  imul   -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L13
  shll   $0x7,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L16
L13:
  nop
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t decode(uint8_t *patch, unsigned *offset) {
  uint64_t value;
  uint64_t shift;
  value = 0;
  shift = 1;
  while (1) {
    uint8_t tmp;
    tmp = patch[*offset];
    *offset = *offset + 1;
    value += (tmp & 0x7f) * shift;
    if (tmp & 0x80)
      break;
    shift <<= 7;
    value += shift;
  }
  return value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decode>:
  endbr64
  mov    %rdi,%r8
  mov    (%rsi),%eax
  mov    %eax,%edx
  mov    (%rdi,%rdx,4),%edx
  add    $0x1,%eax
  mov    %eax,(%rsi)
  mov    %edx,%eax
  and    $0x7f,%eax
  test   $0x80,%dl
  jne    L12
  mov    $0x1,%ecx
L18:
  shl    $0x7,%ecx
  add    %ecx,%eax
  mov    (%rsi),%edx
  mov    %edx,%edi
  mov    (%r8,%rdi,4),%edi
  add    $0x1,%edx
  mov    %edx,(%rsi)
  mov    %edi,%edx
  and    $0x7f,%edx
  imul   %ecx,%edx
  add    %edx,%eax
  test   $0x80,%dil
  je     L18
L12:
  ret
```

assistant: ```c
uint64_t decode(uint8_t *patch, unsigned *offset) {
  uint64_t value;
  uint64_t shift;
  value = 0;
  shift = 1;
  while (1) {
    uint8_t tmp;
    tmp = patch[*offset];
    *offset = *offset + 1;
    value += (tmp & 0x7f) * shift;
    if (tmp & 0x80)
      break;
    shift <<= 7;
    value += shift;
  }
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi,%rax,4),%ecx
  mov    %rax,%rdx
  add    $0x1,%edx
  mov    %ecx,%eax
  mov    %edx,(%rsi)
  and    $0x7f,%eax
  and    $0x80,%ecx
  jne    L15
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edx,%r8d
  shl    $0x7,%ecx
  add    $0x1,%edx
  mov    (%rdi,%r8,4),%r9d
  add    %ecx,%eax
  mov    %edx,(%rsi)
  mov    %r9d,%r8d
  and    $0x7f,%r8d
  imul   %ecx,%r8d
  add    %r8d,%eax
  and    $0x80,%r9d
  je     L2
L15:
  ret
```

assistant: ```c
uint64_t decode(uint8_t *patch, unsigned *offset) {
  uint64_t value;
  uint64_t shift;
  value = 0;
  shift = 1;
  while (1) {
    uint8_t tmp;
    tmp = patch[*offset];
    *offset = *offset + 1;
    value += (tmp & 0x7f) * shift;
    if (tmp & 0x80)
      break;
    shift <<= 7;
    value += shift;
  }
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decode>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi,%rax,4),%ecx
  mov    %rax,%rdx
  add    $0x1,%edx
  mov    %ecx,%eax
  mov    %edx,(%rsi)
  and    $0x7f,%eax
  and    $0x80,%ecx
  jne    L9
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %edx,%r8d
  shl    $0x7,%ecx
  add    $0x1,%edx
  mov    (%rdi,%r8,4),%r9d
  add    %ecx,%eax
  mov    %edx,(%rsi)
  mov    %r9d,%r8d
  and    $0x7f,%r8d
  imul   %ecx,%r8d
  add    %r8d,%eax
  and    $0x80,%r9d
  je     L7
L9:
  ret
```

assistant: ```c
uint64_t decode(uint8_t *patch, unsigned *offset) {
  uint64_t value;
  uint64_t shift;
  value = 0;
  shift = 1;
  while (1) {
    uint8_t tmp;
    tmp = patch[*offset];
    *offset = *offset + 1;
    value += (tmp & 0x7f) * shift;
    if (tmp & 0x80)
      break;
    shift <<= 7;
    value += shift;
  }
  return value;
}
```