ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void my_unlock(int fd) {
  struct flock lock;
  lock.l_type = F_UNLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  fcntl(fd, F_SETLK, &lock);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<my_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    %rsp,%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_unlock(int fd) {
  struct flock lock;
  lock.l_type = F_UNLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  fcntl(fd, F_SETLK, &lock);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D5(%rip),%rax
  mov    %rsp,%rdx
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    D20(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_unlock(int fd) {
  struct flock lock;
  lock.l_type = F_UNLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  fcntl(fd, F_SETLK, &lock);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_unlock>:
  endbr64
  sub    $0x28,%rsp
  mov    D11(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D0(%rip),%rax
  movd   (%rdx),%xmm0
  mov    %rsp,%rdx
  mov    (%rax),%eax
  movd   %eax,%xmm1
  mov    D7(%rip),%rax
  punpckldq %xmm1,%xmm0
  mov    (%rax),%esi
  movq   %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  call   <fcntl@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_unlock(int fd) {
  struct flock lock;
  lock.l_type = F_UNLCK;
  lock.l_whence = SEEK_SET;
  lock.l_start = 0;
  lock.l_len = 0;
  fcntl(fd, F_SETLK, &lock);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<threadMainFunction2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L10:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x4,-0xc(%rbp)
  jle    L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: %s


assistant: ```c
void *threadMainFunction2(void *arg) {
  int i;
  char *pStr = (char *)arg;
  for (i = 0; i < 5; i++) {
    sleep(2);
    printf("%s\n", pStr);
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<threadMainFunction2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x5,%ebx
  lea    D9(%rip),%r12
L7:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: %s


assistant: ```c
void *threadMainFunction2(void *arg) {
  int i;
  char *pStr = (char *)arg;
  for (i = 0; i < 5; i++) {
    sleep(2);
    printf("%s\n", pStr);
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<threadMainFunction2>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x5,%ebx
L1:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %s


assistant: ```c
void *threadMainFunction2(void *arg) {
  int i;
  char *pStr = (char *)arg;
  for (i = 0; i < 5; i++) {
    sleep(2);
    printf("%s\n", pStr);
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<threadMainFunction2>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x5,%ebx
L7:
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: %s


assistant: ```c
void *threadMainFunction2(void *arg) {
  int i;
  char *pStr = (char *)arg;
  for (i = 0; i < 5; i++) {
    sleep(2);
    printf("%s\n", pStr);
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<apesq__strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L39
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L39
  mov    $0x1,%eax
  jmp    L0
L39:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  setne  %al
  movzbl %al,%eax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int apesq__strcasecmp(char *a, char *b) {
  while (*(a++) && *(b++)) {
    if (tolower(*a) != tolower(*b)) {
      return 1;
    }
  }
  return !(*a == *b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<apesq__strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
L26:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L24
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  je     L24
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%r12
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %rax,%r12
  je     L26
  mov    $0x1,%eax
  jmp    L1
L24:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  setne  %al
  movzbl %al,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int apesq__strcasecmp(char *a, char *b) {
  while (*(a++) && *(b++)) {
    if (tolower(*a) != tolower(*b)) {
      return 1;
    }
  }
  return !(*a == *b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<apesq__strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L7
L26:
  add    $0x1,%rbp
  test   %al,%al
  je     L8
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jne    L16
L7:
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%eax
  cmpb   $0x0,-0x1(%rbx)
  jne    L26
L8:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  setne  %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
L16:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int apesq__strcasecmp(char *a, char *b) {
  while (*(a++) && *(b++)) {
    if (tolower(*a) != tolower(*b)) {
      return 1;
    }
  }
  return !(*a == *b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<apesq__strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L36
L39:
  add    $0x1,%rbp
  test   %al,%al
  je     L34
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jne    L4
L36:
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%eax
  cmpb   $0x0,-0x1(%rbx)
  jne    L39
L34:
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  setne  %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
L4:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int apesq__strcasecmp(char *a, char *b) {
  while (*(a++) && *(b++)) {
    if (tolower(*a) != tolower(*b)) {
      return 1;
    }
  }
  return !(*a == *b);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_settings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cfgetospeed@plt>
  mov    %eax,%edi
  call   <print_baud@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <print_characters@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_flags@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_settings(struct termios *ttyp) {
  print_baud(cfgetospeed(ttyp));
  putchar('\n');
  print_characters(ttyp->c_cc);
  putchar('\n');
  print_flags(ttyp);
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_settings>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <cfgetospeed@plt>
  mov    %eax,%edi
  call   <print_baud@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rbx),%edi
  call   <print_characters@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <print_flags@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void print_settings(struct termios *ttyp) {
  print_baud(cfgetospeed(ttyp));
  putchar('\n');
  print_characters(ttyp->c_cc);
  putchar('\n');
  print_flags(ttyp);
  exit(EXIT_SUCCESS);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_settings>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <cfgetospeed@plt>
  mov    %eax,%edi
  call   <print_baud@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x0(%rbp),%edi
  call   <print_characters@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <print_flags@plt>
  mov    D7(%rip),%rax
  pop    %rbp
  mov    (%rax),%edi
  jmp    10f0 <exit@plt>
```

assistant: ```c
void print_settings(struct termios *ttyp) {
  print_baud(cfgetospeed(ttyp));
  putchar('\n');
  print_characters(ttyp->c_cc);
  putchar('\n');
  print_flags(ttyp);
  exit(EXIT_SUCCESS);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_settings>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <cfgetospeed@plt>
  mov    %eax,%edi
  call   <print_baud@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x0(%rbp),%edi
  call   <print_characters@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <print_flags@plt>
  mov    D0(%rip),%rax
  pop    %rbp
  mov    (%rax),%edi
  jmp    10f0 <exit@plt>
```

assistant: ```c
void print_settings(struct termios *ttyp) {
  print_baud(cfgetospeed(ttyp));
  putchar('\n');
  print_characters(ttyp->c_cc);
  putchar('\n');
  print_flags(ttyp);
  exit(EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L1
L43:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L1:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L43
  lea    D10(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L44
L18:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L44:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D46
type: string
name: disassemble_data
arguments: label: D10
type: string
name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D46: arg %d: %s


tool: D10: California

tool: D11: Oregon

tool: D25: Washington

tool: D3: Texas

tool: D1: state %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d is %s\n", i, states[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L5
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x1,%ebx
  lea    D19(%rip),%r13
L35:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L35
L5:
  lea    D26(%rip),%rax
  mov    %rax,(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D39(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L33:
  mov    (%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L33
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D39
type_guessed: string
name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D19: arg %d: %s


tool: D26: California

tool: D13: Oregon

tool: D12: Washington

tool: D39: Texas

tool: D7: state %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d is %s\n", i, states[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L18
  mov    %rsi,%rbp
  movslq %edi,%r13
  mov    $0x1,%ebx
  lea    D57(%rip),%r12
  nopl   (%rax)
L36:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L36
L18:
  lea    D51(%rip),%rax
  xor    %ebx,%ebx
  lea    D41(%rip),%rdx
  mov    %rax,0x8(%rsp)
  lea    D46(%rip),%rax
  lea    D58(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x18(%rsp)
L41:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L35
  mov    (%rsp,%rbx,8),%rdx
  jmp    L41
  xchg   %ax,%ax
L35:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D57
datatype: string
name: disassemble_data
arguments: data_label: D51
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D46
datatype: string
name: disassemble_data
arguments: data_label: D58
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string

tool: D57: arg %d: %s


tool: D51: Oregon

tool: D41: California

tool: D46: Washington

tool: D58: state %d is %s


tool: D29: Texas

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d is %s\n", i, states[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L2
  mov    %rsi,%r12
  movslq %edi,%rbp
  mov    $0x1,%ebx
  lea    D18(%rip),%r13
  nopl   (%rax)
L29:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L29
L2:
  lea    D55(%rip),%rax
  lea    D59(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D49(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D22(%rip),%rax
  lea    D56(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L38:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L38
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D55
type: string
name: extract_symbolic_data
arguments: tag: D59
type: string
name: extract_symbolic_data
arguments: tag: D49
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D56
type: string

tool: D18: arg %d: %s


tool: D55: Oregon

tool: D59: California

tool: D49: Washington

tool: D22: Texas

tool: D56: state %d is %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  for (i = 1; i < argc; i++) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; i++) {
    printf("state %d is %s\n", i, states[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<h2o_mem_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <h2o__fatal@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h:330:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h"
               ":"
               "330"
               ":"
               "no memory");
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<h2o_mem_alloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L13:
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  lea    D9(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h:330:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h"
               ":"
               "330"
               ":"
               "no memory");
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<h2o_mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L9:
  mov    %r12,%rax
  pop    %r12
  ret
L13:
  lea    D7(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h:330:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h"
               ":"
               "330"
               ":"
               "no memory");
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h2o_mem_alloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L6:
  mov    %r12,%rax
  pop    %r12
  ret
L16:
  lea    D4(%rip),%rdi
  call   <h2o__fatal@plt>
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h:330:no memory

assistant: ```c
void *h2o_mem_alloc(size_t sz) {
  void *p = malloc(sz);
  if (p == NULL)
    h2o__fatal("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/cubicdaiya/h2o/refs/heads/master/include/h2o/memory.h"
               ":"
               "330"
               ":"
               "no memory");
  return p;
}
```