user: What would the C source look like for the assembly code provided here?

```asm
<secant>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x28(%rsp)
  mov    %rdi,%r13
  lea    D16(%rip),%rdi
  call   <puts@plt>
  movsd  D27(%rip),%xmm3
  movsd  %xmm3,0x20(%rsp)
  mov    $0x1,%r12d
  lea    D18(%rip),%r15
  jmp    L39
L34:
  movsd  0x18(%rsp),%xmm6
  movsd  %xmm6,0x8(%rsp)
  mov    %r14d,%r12d
L39:
  movsd  0x8(%rsp),%xmm0
  call   *%r13
  movq   %xmm0,%rbx
  movsd  0x10(%rsp),%xmm0
  call   *%r13
  pxor   %xmm3,%xmm3
  ucomisd %xmm3,%xmm0
  jp     L2
  je     L6
L2:
  movq   %rbx,%xmm1
  movsd  0x10(%rsp),%xmm5
  mulsd  %xmm5,%xmm1
  movsd  0x8(%rsp),%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movq   %rbx,%xmm2
  subsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movsd  %xmm1,0x18(%rsp)
  movapd %xmm3,%xmm4
  subsd  %xmm5,%xmm4
  movsd  %xmm4,0x10(%rsp)
  movapd %xmm4,%xmm0
  mov    $0x1,%eax
  call   <abslt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rbp
  movsd  0x20(%rsp),%xmm0
  call   <log@plt>
  movq   %rbp,%xmm6
  divsd  %xmm0,%xmm6
  movapd %xmm6,%xmm0
  mov    $0x1,%eax
  call   <abslt@plt>
  mov    %eax,%ebp
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  call   <abslt@plt>
  mov    %eax,%edx
  lea    0x1(%r12),%r14d
  mov    %ebp,%ecx
  movq   %rbx,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  call   <abslt@plt>
  pxor   %xmm6,%xmm6
  cvtsi2sd %eax,%xmm6
  movsd  %xmm6,0x20(%rsp)
  movsd  0x18(%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  call   <abslt@plt>
  movsd  0x8(%rsp),%xmm7
  movsd  %xmm7,0x10(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  comisd 0x28(%rsp),%xmm0
  ja     L34
  movsd  0x18(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
L6:
  movsd  0x8(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: byte[8]
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D16: SECANT METHOD:

i	xi		f(xi)		|ei|		|log(ei)/log(e(i-1))|

tool: {"D27": [0x69,0x57,0x14,0x8b,0x0a,0xbf,0x05,0x40]}

tool: D18: %02d	%+09g	%+09g	%+09g	%+09g


assistant: ```c
double secant(double initialminus1, double initial0, double accuracy, double (*f)(double)) {
  int i = 1;
  double xiplus1, xi = initial0, ximinus1 = initialminus1, fxi, fximinus1, ei = exp(1);
  printf("SECANT METHOD:\n\ni\txi\t\tf(xi)\t\t|ei|\t\t|log(ei)/log(e(i-1))|\n");
  do {
    fxi = f(xi);
    if (!(fximinus1 = f(ximinus1)))
      break;
    xiplus1 = (ximinus1 * fxi - xi * fximinus1) / (fxi - fximinus1);
    printf("%02d\t%+09g\t%+09g\t%+09g\t%+09g\n", i++, xi, fxi, abslt(xi - ximinus1), abslt(log(abslt(xi - ximinus1)) / log(ei)));
    ei = abslt(xi - ximinus1);
    ximinus1 = xi;
    xi = xiplus1;
  } while (abslt(xi - ximinus1) > accuracy);
  return xi;
}
```