ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  jmp    L16
L2:
  movl   $0x0,-0x34(%rbp)
  jmp    L45
L30:
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L45:
  cmpl   $0x1,-0x34(%rbp)
  jle    L30
  addl   $0x1,-0x38(%rbp)
L16:
  cmpl   $0x3,-0x38(%rbp)
  jle    L2
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <inverte_linhas@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <imprime_matriz@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D6: 
Informe o valor para A[%d][%d] na matriz: 

tool: D4: %d

assistant: ```c
int main() {
  int i, j;
  int mat[4][2];
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 2; j++) {
      printf("\nInforme o valor para A[%d][%d] na matriz: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  inverte_linhas(mat);
  imprime_matriz(mat);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D10(%rip),%r13
  lea    D2(%rip),%r12
L3:
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    $0x4,%ebx
  jne    L3
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <inverte_linhas@plt>
  mov    %rbx,%rdi
  call   <imprime_matriz@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D10: 
Informe o valor para A[%d][%d] na matriz: 

tool: D2: %d

assistant: ```c
int main() {
  int i, j;
  int mat[4][2];
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 2; j++) {
      printf("\nInforme o valor para A[%d][%d] na matriz: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  inverte_linhas(mat);
  imprime_matriz(mat);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rbp
L17:
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x8,%rbp
  cmp    $0x4,%ebx
  jne    L17
  mov    %r14,%rdi
  call   <inverte_linhas@plt>
  mov    %r14,%rdi
  call   <imprime_matriz@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string

tool: D16: 
Informe o valor para A[%d][%d] na matriz: 

tool: D7: %d

assistant: ```c
int main() {
  int i, j;
  int mat[4][2];
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 2; j++) {
      printf("\nInforme o valor para A[%d][%d] na matriz: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  inverte_linhas(mat);
  imprime_matriz(mat);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rbp
L11:
  xor    %edx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  lea    0x4(%rbp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x8,%rbp
  cmp    $0x4,%ebx
  jne    L11
  mov    %r14,%rdi
  call   <inverte_linhas@plt>
  mov    %r14,%rdi
  call   <imprime_matriz@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D13: 
Informe o valor para A[%d][%d] na matriz: 

tool: D0: %d

assistant: ```c
int main() {
  int i, j;
  int mat[4][2];
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 2; j++) {
      printf("\nInforme o valor para A[%d][%d] na matriz: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  inverte_linhas(mat);
  imprime_matriz(mat);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0x8(%rsp)
  movabs $0x53202e412064655a,%rax
  mov    %rax,0xc(%rsp)
  movl   $0x776168,0x14(%rsp)
  mov    $0x4,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xa,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D89(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D53
data_type: string
name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D23
data_type: string
name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D34
data_type: string
name: parse_data
arguments: tag: D89
data_type: string
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D5: The size of an int: %ld


tool: D53: The size of areas (int[]): %ld


tool: D0: The number of ints in areas: %ld


tool: D23: The first area is %d, the 2nd %d.


tool: D7: The size of a char: %ld


tool: D34: The size of name (char[]): %ld


tool: D89: The number of chars: %ld


tool: D26: The size of full name (char[]): %ld


tool: D10: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Zed";
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w', '\0'};
  printf("The size of an int: %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D74(%rip),%rdi
  lea    D52(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0x8(%rsp)
  movabs $0x53202e412064655a,%rax
  mov    %rax,0xc(%rsp)
  xor    %eax,%eax
  movl   $0x776168,0x14(%rsp)
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xa,%esi
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D83(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D74
data_type: string
name: parse_data
arguments: data_label: D52
data_type: string
name: parse_data
arguments: data_label: D46
data_type: string
name: parse_data
arguments: data_label: D65
data_type: string
name: parse_data
arguments: data_label: D50
data_type: string
name: parse_data
arguments: data_label: D17
data_type: string
name: parse_data
arguments: data_label: D83
data_type: string
name: parse_data
arguments: data_label: D68
data_type: string
name: parse_data
arguments: data_label: D22
data_type: string

tool: D74: The size of an int: %ld


tool: D52: The number of chars: %ld


tool: D46: The size of areas (int[]): %ld


tool: D65: The number of ints in areas: %ld


tool: D50: The first area is %d, the 2nd %d.


tool: D17: The size of a char: %ld


tool: D83: The size of name (char[]): %ld


tool: D68: The size of full name (char[]): %ld


tool: D22: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Zed";
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w', '\0'};
  printf("The size of an int: %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__builtin_inff@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__builtin_infl@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: byte[8]
name: unpack_data
arguments: data_label: D11
datatype: string
name: unpack_data
arguments: data_label: D29
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D11: The __builtin_inf():[%lf]


tool: D29: The __builtin_inff():[%f]


tool: D17: The __builtin_infl:[%Lf]


assistant: ```c
int main() {
  printf("The __builtin_inf():[%lf]\n", __builtin_inf());
  printf("The __builtin_inff():[%f]\n", __builtin_inff());
  printf("The __builtin_infl:[%Lf]\n", __builtin_infl());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D26(%rip),%xmm0
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__builtin_inff@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <__builtin_infl@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
type_guessed: byte[8]
name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D17: The __builtin_inf():[%lf]


tool: D36: The __builtin_inff():[%f]


tool: D8: The __builtin_infl:[%Lf]


assistant: ```c
int main() {
  printf("The __builtin_inf():[%lf]\n", __builtin_inf());
  printf("The __builtin_inff():[%f]\n", __builtin_inff());
  printf("The __builtin_infl:[%Lf]\n", __builtin_infl());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D25(%rip),%xmm0
  lea    D38(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__builtin_inff@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__builtin_infl@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_infered: byte[8]
name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D38: The __builtin_inf():[%lf]


tool: D14: The __builtin_inff():[%f]


tool: D17: The __builtin_infl:[%Lf]


assistant: ```c
int main() {
  printf("The __builtin_inf():[%lf]\n", __builtin_inf());
  printf("The __builtin_inff():[%f]\n", __builtin_inff());
  printf("The __builtin_infl:[%Lf]\n", __builtin_infl());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D23(%rip),%xmm0
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__builtin_inff@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <__builtin_infl@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type_guessed: byte[8]
name: read_data
arguments: data_tag: D37
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D37: The __builtin_inf():[%lf]


tool: D25: The __builtin_inff():[%f]


tool: D3: The __builtin_infl:[%Lf]


assistant: ```c
int main() {
  printf("The __builtin_inf():[%lf]\n", __builtin_inf());
  printf("The __builtin_inff():[%f]\n", __builtin_inff());
  printf("The __builtin_infl:[%Lf]\n", __builtin_infl());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Matrix_matrix_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <allocateSpace@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L71
  mov    $0x0,%eax
  jmp    L74
L71:
  movl   $0x0,-0x1c(%rbp)
  jmp    L56
L53:
  movl   $0x0,-0x18(%rbp)
  jmp    L41
L16:
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L31:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L31
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L41:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L16
  addl   $0x1,-0x1c(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L53
  mov    -0x8(%rbp),%rax
L74:
  leave
  ret
```

assistant: ```c
double **Matrix_matrix_multiply(double **matrixa, double **matrixb, int size) {
  double sum = 0;
  double **output = allocateSpace(size);
  if (output == NULL) {
    return NULL;
  }
  int i, j, k;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matrixa[i][k] * matrixb[k][j];
      }
      output[i][j] = sum;
      sum = 0;
    }
  }
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Matrix_matrix_multiply>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %edx,%edi
  call   <allocateSpace@plt>
  mov    %rax,%r9
  test   %rax,%rax
  je     L49
  test   %r12d,%r12d
  jle    L49
  mov    %r12d,%edi
  lea    0x0(,%rdi,8),%r10
  mov    $0x0,%r8d
L15:
  mov    $0x0,%ecx
L48:
  mov    0x0(%rbp,%r8,8),%rsi
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L24:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L24
  mov    (%r9,%r8,8),%rax
  movsd  %xmm1,(%rax,%rcx,1)
  add    $0x8,%rcx
  cmp    %r10,%rcx
  jne    L48
  add    $0x1,%r8
  cmp    %rdi,%r8
  jne    L15
L49:
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **Matrix_matrix_multiply(double **matrixa, double **matrixb, int size) {
  double sum = 0;
  double **output = allocateSpace(size);
  if (output == NULL) {
    return NULL;
  }
  int i, j, k;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matrixa[i][k] * matrixb[k][j];
      }
      output[i][j] = sum;
      sum = 0;
    }
  }
  return output;
}
```
user: What is the c source code of the assembly code below?

```asm
<Matrix_matrix_multiply>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <allocateSpace@plt>
  mov    %rax,%r11
  test   %rax,%rax
  je     L4
  test   %r12d,%r12d
  jle    L4
  movslq %r12d,%rsi
  xor    %r10d,%r10d
  pxor   %xmm2,%xmm2
  lea    0x0(,%rsi,8),%r9
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0x0(%rbp,%r10,8),%rdi
  mov    (%r11,%r10,8),%r8
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L0
  movsd  %xmm1,(%r8,%rcx,1)
  add    $0x8,%rcx
  cmp    %rcx,%r9
  jne    L2
  add    $0x1,%r10
  cmp    %r10,%rsi
  jne    L18
L4:
  pop    %rbx
  mov    %r11,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **Matrix_matrix_multiply(double **matrixa, double **matrixb, int size) {
  double sum = 0;
  double **output = allocateSpace(size);
  if (output == NULL) {
    return NULL;
  }
  int i, j, k;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matrixa[i][k] * matrixb[k][j];
      }
      output[i][j] = sum;
      sum = 0;
    }
  }
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Matrix_matrix_multiply>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <allocateSpace@plt>
  mov    %rax,%r11
  test   %rax,%rax
  je     L14
  test   %r12d,%r12d
  jle    L14
  movslq %r12d,%rsi
  xor    %r10d,%r10d
  pxor   %xmm2,%xmm2
  lea    0x0(,%rsi,8),%r9
  nopw   0x0(%rax,%rax,1)
L33:
  mov    0x0(%rbp,%r10,8),%rdi
  mov    (%r11,%r10,8),%r8
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L20
  movsd  %xmm1,(%r8,%rcx,1)
  add    $0x8,%rcx
  cmp    %rcx,%r9
  jne    L25
  add    $0x1,%r10
  cmp    %r10,%rsi
  jne    L33
L14:
  pop    %rbx
  mov    %r11,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double **Matrix_matrix_multiply(double **matrixa, double **matrixb, int size) {
  double sum = 0;
  double **output = allocateSpace(size);
  if (output == NULL) {
    return NULL;
  }
  int i, j, k;
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; j++) {
      for (k = 0; k < size; k++) {
        sum += matrixa[i][k] * matrixb[k][j];
      }
      output[i][j] = sum;
      sum = 0;
    }
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bla>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2a,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L18
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L3
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <get_args@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: wrong3


assistant: ```c
void bla(void) {
  int __ret = 42;
  ({
    if (__builtin_expect(!!(0), 0)) {
      if (__builtin_expect(!!__ret, 0))
        printf("wrong3\n");
      int x = !!(__ret);
    }
    __ret;
  });
  get_args(!!__ret, sizeof(__ret));
}
```