ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HariMain>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_palette@plt>
  movswl 0xff6,%edx
  movswl 0xff4,%esi
  movslq 0xff8,%rdi
  call   <init_screen@plt>
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  call   <io_hlt@plt>
  jmp    L2
```

assistant: ```c
void HariMain(void) {
  char *vram;
  int width, height;
  short *binfo_screen_w;
  short *binfo_screen_h;
  int *binfo_vram;
  init_palette();
  binfo_screen_w = (short *)0x0ff4;
  binfo_screen_h = (short *)0xff6;
  binfo_vram = (int *)0x0ff8;
  width = *binfo_screen_w;
  height = *binfo_screen_h;
  vram = (unsigned char *)*binfo_vram;
  init_screen(vram, width, height);
  for (;;)
    io_hlt();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<HariMain>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_palette@plt>
  movswl 0xff6,%edx
  movswl 0xff4,%esi
  movslq 0xff8,%rdi
  call   <init_screen@plt>
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <io_hlt@plt>
  jmp    L1
```

assistant: ```c
void HariMain(void) {
  char *vram;
  int width, height;
  short *binfo_screen_w;
  short *binfo_screen_h;
  int *binfo_vram;
  init_palette();
  binfo_screen_w = (short *)0x0ff4;
  binfo_screen_h = (short *)0xff6;
  binfo_vram = (int *)0x0ff8;
  width = *binfo_screen_w;
  height = *binfo_screen_h;
  vram = (unsigned char *)*binfo_vram;
  init_screen(vram, width, height);
  for (;;)
    io_hlt();
}
```
user: Translate the below assembly code into C programming language:

```asm
<freeArrayofPointers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L34
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L34:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L21:
  nop
  leave
  ret
```

assistant: ```c
void freeArrayofPointers(void **pointer, int index) {
  int i = 0;
  if (pointer) {
    for (i = 0; i < index; i++) {
      if (pointer[i])
        free(pointer[i]);
    }
    free(pointer);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<freeArrayofPointers>:
  endbr64
  test   %rdi,%rdi
  je     L50
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L53
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
  jmp    L41
L8:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L53
L41:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L8
  call   <free@plt>
  jmp    L8
L53:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  ret
```

assistant: ```c
void freeArrayofPointers(void **pointer, int index) {
  int i = 0;
  if (pointer) {
    for (i = 0; i < index; i++) {
      if (pointer[i])
        free(pointer[i]);
    }
    free(pointer);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<freeArrayofPointers>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nop
L4:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L12
  call   <free@plt>
L12:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L4
L9:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  ret
```

assistant: ```c
void freeArrayofPointers(void **pointer, int index) {
  int i = 0;
  if (pointer) {
    for (i = 0; i < index; i++) {
      if (pointer[i])
        free(pointer[i]);
    }
    free(pointer);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<freeArrayofPointers>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nop
L13:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L2
  call   <free@plt>
L2:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L13
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L21:
  ret
```

assistant: ```c
void freeArrayofPointers(void **pointer, int index) {
  int i = 0;
  if (pointer) {
    for (i = 0; i < index; i++) {
      if (pointer[i])
        free(pointer[i]);
    }
    free(pointer);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0x96a,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L9
L48:
  addw   $0x2,-0xc(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L48
  movw   $0x0,-0xc(%rbp)
  jmp    L31
L26:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%edx
  movzwl -0xc(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  addw   $0x2,-0xc(%rbp)
L31:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L26
  movzwl -0xa(%rbp),%eax
  lea    0x13a0(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 945167787UL) - (unsigned short)2571;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    -0x96a(%rax),%edx
  movzwl 0x2(%rdi),%ecx
  test   %cx,%cx
  je     L6
  mov    $0x0,%eax
L11:
  add    $0x2,%eax
  cmp    %cx,%ax
  jb     L11
  mov    $0x0,%eax
L25:
  add    %edx,%edx
  add    $0x2,%eax
  cmp    %cx,%ax
  jb     L25
L6:
  add    $0x13a0,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 945167787UL) - (unsigned short)2571;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%ecx
  lea    -0x96a(%rax),%edx
  test   %cx,%cx
  je     L7
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x2,%eax
  cmp    %cx,%ax
  jb     L8
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x2,%eax
  add    %edx,%edx
  cmp    %cx,%ax
  jb     L3
L7:
  add    $0x13a0,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 945167787UL) - (unsigned short)2571;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edx
  mov    %rsi,%r8
  lea    -0x96a(%rax),%ecx
  test   %dx,%dx
  je     L110
  xor    %eax,%eax
  nop
L7:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L7
  lea    -0x1(%rdx),%eax
  mov    %eax,%edi
  shr    %di
  add    $0x1,%edi
  cmp    $0x13,%ax
  jbe    L37
  mov    %edi,%esi
  movdqa D9(%rip),%xmm0
  xor    %eax,%eax
  shr    $0x3,%si
  nopl   (%rax)
L46:
  add    $0x1,%eax
  psllw  $0x1,%xmm0
  cmp    %ax,%si
  ja     L46
  movdqa %xmm0,%xmm1
  mov    %edi,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%esi
  pmullw %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pmullw %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  pmullw %xmm1,%xmm0
  pextrw $0x0,%xmm0,%eax
  imul   %eax,%ecx
  lea    (%rsi,%rsi,1),%eax
  cmp    %si,%di
  je     L110
L84:
  lea    0x2(%rax),%esi
  lea    (%rcx,%rcx,1),%edi
  cmp    %dx,%si
  jae    L81
  lea    0x4(%rax),%esi
  lea    0x0(,%rcx,4),%edi
  cmp    %si,%dx
  jbe    L81
  lea    0x6(%rax),%esi
  lea    0x0(,%rcx,8),%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%edi
  lea    0x8(%rax),%esi
  shl    $0x4,%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%edi
  lea    0xa(%rax),%esi
  shl    $0x5,%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%edi
  lea    0xc(%rax),%esi
  shl    $0x6,%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%edi
  lea    0xe(%rax),%esi
  shl    $0x7,%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%edi
  lea    0x10(%rax),%esi
  shl    $0x8,%edi
  cmp    %si,%dx
  jbe    L81
  mov    %ecx,%esi
  add    $0x12,%eax
  shl    $0xa,%ecx
  shl    $0x9,%esi
  cmp    %ax,%dx
  cmovbe %esi,%ecx
L110:
  add    $0x13a0,%cx
  mov    %cx,(%r8)
  ret
  xchg   %ax,%ax
L81:
  mov    %edi,%ecx
  add    $0x13a0,%cx
  mov    %cx,(%r8)
  ret
L37:
  xor    %eax,%eax
  jmp    L84
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: byte[16]

tool: {"D9": [0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00]}

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 945167787UL) - (unsigned short)2571;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmodem_rx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x1,-0x11(%rbp)
  movl   $0x1,-0x10(%rbp)
L36:
  cmpl   $0x0,-0x10(%rbp)
  je     L28
  mov    $0x43,%edi
  call   <putchar@plt>
L28:
  mov    $0x1,%edi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L46
  cmpl   $0x1,-0xc(%rbp)
  je     L72
  cmpl   $0x4,-0xc(%rbp)
  jne    L46
L72:
  cmpl   $0x4,-0xc(%rbp)
  jne    L25
  mov    $0x6,%edi
  call   <putchar@plt>
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L9
L25:
  movl   $0x0,-0x10(%rbp)
  movsbl -0x11(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <GetRecord@plt>
  test   %eax,%eax
  jne    L41
  mov    $0xffffffff,%eax
  jmp    L9
L41:
  subq   $0xffffffffffffff80,-0x28(%rbp)
  movzbl -0x11(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x11(%rbp)
  jmp    L36
L46:
  nop
  jmp    L36
L9:
  leave
  ret
```

assistant: ```c
int xmodem_rx(char *dest) {
  int starting, ch;
  char packetNumber, *startAddress = dest;
  packetNumber = 1;
  starting = 1;
  while (1) {
    if (starting)
      putchar('C');
    if (((ch = getc(1)) == -1) || (ch != 0x01 && ch != 0x04))
      continue;
    if (ch == 0x04) {
      putchar(0x06);
      return (dest - startAddress);
    }
    starting = 0;
    if (!GetRecord(packetNumber, dest))
      return (-1);
    dest += 128;
    packetNumber++;
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xmodem_rx>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rdi,%rbx
  mov    $0x1,%r12d
  mov    $0x1,%ebp
  mov    $0x0,%r13d
  jmp    L32
L95:
  mov    $0x43,%edi
  call   <putchar@plt>
  jmp    L52
L64:
  cmp    $0x4,%eax
  je     L51
  movsbl %r12b,%edi
  mov    %rbx,%rsi
  call   <GetRecord@plt>
  test   %eax,%eax
  je     L23
  sub    $0xffffffffffffff80,%rbx
  add    $0x1,%r12d
  mov    %r13d,%ebp
L32:
  test   %ebp,%ebp
  jne    L95
L52:
  mov    $0x1,%edi
  call   <getc@plt>
  cmp    $0xffffffff,%eax
  je     L32
  cmp    $0x1,%eax
  je     L64
  cmp    $0x4,%eax
  je     L64
  jmp    L32
L51:
  mov    $0x6,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  sub    %r14d,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L28
```

assistant: ```c
int xmodem_rx(char *dest) {
  int starting, ch;
  char packetNumber, *startAddress = dest;
  packetNumber = 1;
  starting = 1;
  while (1) {
    if (starting)
      putchar('C');
    if (((ch = getc(1)) == -1) || (ch != 0x01 && ch != 0x04))
      continue;
    if (ch == 0x04) {
      putchar(0x06);
      return (dest - startAddress);
    }
    starting = 0;
    if (!GetRecord(packetNumber, dest))
      return (-1);
    dest += 128;
    packetNumber++;
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmodem_rx>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L14:
  test   %r13d,%r13d
  je     L58
  mov    $0x43,%edi
  call   <putchar@plt>
L58:
  mov    $0x1,%edi
  call   <getc@plt>
  cmp    $0xffffffff,%eax
  je     L14
  cmp    $0x1,%eax
  je     L8
  cmp    $0x4,%eax
  jne    L14
L60:
  mov    $0x6,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    $0x4,%eax
  je     L60
  movsbl %bpl,%edi
  mov    %rbx,%rsi
  call   <GetRecord@plt>
  test   %eax,%eax
  je     L0
  sub    $0xffffffffffffff80,%rbx
  add    $0x1,%ebp
  xor    %r13d,%r13d
  jmp    L58
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int xmodem_rx(char *dest) {
  int starting, ch;
  char packetNumber, *startAddress = dest;
  packetNumber = 1;
  starting = 1;
  while (1) {
    if (starting)
      putchar('C');
    if (((ch = getc(1)) == -1) || (ch != 0x01 && ch != 0x04))
      continue;
    if (ch == 0x04) {
      putchar(0x06);
      return (dest - startAddress);
    }
    starting = 0;
    if (!GetRecord(packetNumber, dest))
      return (-1);
    dest += 128;
    packetNumber++;
  }
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmodem_rx>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nop
L32:
  test   %r13d,%r13d
  je     L16
  mov    $0x43,%edi
  call   <putchar@plt>
L16:
  mov    $0x1,%edi
  call   <getc@plt>
  cmp    $0xffffffff,%eax
  je     L32
  cmp    $0x1,%eax
  je     L61
  cmp    $0x4,%eax
  jne    L32
L4:
  mov    $0x6,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  cmp    $0x4,%eax
  je     L4
  movsbl %bpl,%edi
  mov    %rbx,%rsi
  call   <GetRecord@plt>
  test   %eax,%eax
  je     L28
  sub    $0xffffffffffffff80,%rbx
  add    $0x1,%ebp
  xor    %r13d,%r13d
  jmp    L16
  nopl   0x0(%rax)
L28:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int xmodem_rx(char *dest) {
  int starting, ch;
  char packetNumber, *startAddress = dest;
  packetNumber = 1;
  starting = 1;
  while (1) {
    if (starting)
      putchar('C');
    if (((ch = getc(1)) == -1) || (ch != 0x01 && ch != 0x04))
      continue;
    if (ch == 0x04) {
      putchar(0x06);
      return (dest - startAddress);
    }
    starting = 0;
    if (!GetRecord(packetNumber, dest))
      return (-1);
    dest += 128;
    packetNumber++;
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <buildHeap@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L10:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <heapify@plt>
  subl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(void **ar, int left, int right, int (*cmp)(const void *, const void *)) {
  int i;
  buildHeap(&ar[left], cmp, right - left + 1);
  for (i = right; i > left; i--) {
    void *tmp;
    tmp = ar[left];
    ar[left] = ar[i];
    ar[i] = tmp;
    heapify(ar, cmp, left, i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<heapSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r15d
  mov    %rcx,%r14
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%r12
  sub    %esi,%edx
  add    $0x1,%edx
  mov    %rcx,%rsi
  mov    %r12,%rdi
  call   <buildHeap@plt>
  cmp    %r13d,%r15d
  jle    L6
  movslq %r15d,%rbx
  lea    -0x1(%rbx),%rdx
  mov    %r15d,%eax
  sub    %r13d,%eax
  lea    -0x1(%rax),%eax
  sub    %rax,%rdx
  mov    %rdx,%r15
L16:
  mov    (%r12),%rax
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %rdx,(%r12)
  mov    %rax,0x0(%rbp,%rbx,8)
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <heapify@plt>
  sub    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L16
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heapSort(void **ar, int left, int right, int (*cmp)(const void *, const void *)) {
  int i;
  buildHeap(&ar[left], cmp, right - left + 1);
  for (i = right; i > left; i--) {
    void *tmp;
    tmp = ar[left];
    ar[left] = ar[i];
    ar[i] = tmp;
    heapify(ar, cmp, left, i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapSort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  mov    %rcx,%rsi
  push   %r14
  lea    (%rdi,%rax,8),%r15
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  mov    %r15,%rdi
  push   %r12
  sub    %eax,%r13d
  mov    %rcx,%r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  mov    %edx,%ebx
  lea    0x1(%r13),%edx
  sub    $0x8,%rsp
  call   <buildHeap@plt>
  cmp    %ebp,%ebx
  jle    L16
  movslq %ebx,%rcx
  lea    -0x1(%r13),%eax
  lea    -0x1(%rcx),%rbx
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L11
L2:
  sub    $0x1,%rbx
L11:
  mov    (%r14,%rcx,8),%rdx
  mov    (%r15),%rax
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %rdx,(%r15)
  mov    %ebp,%edx
  mov    %rax,(%r14,%rcx,8)
  call   <heapify@plt>
  mov    %rbx,%rcx
  cmp    %r13,%rbx
  jne    L2
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heapSort(void **ar, int left, int right, int (*cmp)(const void *, const void *)) {
  int i;
  buildHeap(&ar[left], cmp, right - left + 1);
  for (i = right; i > left; i--) {
    void *tmp;
    tmp = ar[left];
    ar[left] = ar[i];
    ar[i] = tmp;
    heapify(ar, cmp, left, i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<heapSort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  mov    %rcx,%rsi
  push   %r14
  lea    (%rdi,%rax,8),%r15
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  mov    %r15,%rdi
  push   %r12
  sub    %eax,%r13d
  mov    %rcx,%r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  mov    %edx,%ebx
  lea    0x1(%r13),%edx
  sub    $0x8,%rsp
  call   <buildHeap@plt>
  cmp    %ebp,%ebx
  jle    L8
  movslq %ebx,%rcx
  lea    -0x1(%r13),%eax
  lea    -0x1(%rcx),%rbx
  mov    %rbx,%r13
  sub    %rax,%r13
  jmp    L4
L19:
  sub    $0x1,%rbx
L4:
  mov    (%r14,%rcx,8),%rdx
  mov    (%r15),%rax
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %rdx,(%r15)
  mov    %ebp,%edx
  mov    %rax,(%r14,%rcx,8)
  call   <heapify@plt>
  mov    %rbx,%rcx
  cmp    %r13,%rbx
  jne    L19
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void heapSort(void **ar, int left, int right, int (*cmp)(const void *, const void *)) {
  int i;
  buildHeap(&ar[left], cmp, right - left + 1);
  for (i = right; i > left; i--) {
    void *tmp;
    tmp = ar[left];
    ar[left] = ar[i];
    ar[i] = tmp;
    heapify(ar, cmp, left, i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interpret_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rx@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rx@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  cmp    $0xb,%eax
  ja     L3
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L3:
  mov    $0x0,%eax
  call   <ack@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <npush@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <npop@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <jsr@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <lda@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <ldf@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <intr@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <nafetch@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <nffetch@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <nastore@plt>
  jmp    L6
  mov    $0x0,%eax
  call   <nfstore@plt>
  nop
L6:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <infof@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D28
type_guessed: string

tool: D28: 


assistant: ```c
void interpret_packet(void) {
  int size = rx();
  (void)size;
  int command = rx();
  switch (command & 0x0F) {
  default:
  case 0:
    ack();
    break;
  case 1:
    npush();
    break;
  case 2:
    npop();
    break;
  case 3:
    jsr();
    break;
  case 4:
    lda();
    break;
  case 5:
    ldf();
    break;
  case 7:
    intr();
    break;
  case 8:
    nafetch();
    break;
  case 9:
    nffetch();
    break;
  case 10:
    nastore();
    break;
  case 11:
    nfstore();
    break;
  }
  infof("\n");
}
```