ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  lea    D8(%rip),%rbx
  jmp    L56
L22:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%edx
  mov    %rbx,%rax
  lea    -0x1(%rax),%rbx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x18(%rbp)
L56:
  cmpl   $0x0,-0x14(%rbp)
  jle    L21
  lea    D27(%rip),%rax
  cmp    %rax,%rbx
  ja     L22
  jmp    L21
L29:
  mov    %rbx,%rax
  lea    -0x1(%rax),%rbx
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L21:
  lea    D27(%rip),%rax
  cmp    %rax,%rbx
  jbe    L45
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L29
L45:
  add    $0x1,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <_add@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void _conv(n, digits, fill) int n, digits, fill;
{
  static char buf[10];
  register char *p;
  for (p = buf + sizeof(buf) - 2; n > 0 && p > buf; n /= 10, --digits)
    *p-- = n % 10 + '0';
  while (p > buf && digits-- > 0)
    *p-- = fill;
  _add(++p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_conv>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%r9d
  mov    %edx,%r8d
  test   %edi,%edi
  jle    L76
  mov    %edi,%ecx
  lea    D38(%rip),%rdi
  mov    %rdi,%r11
  lea    -0x8(%rdi),%r10
L41:
  sub    $0x1,%rdi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rdi)
  mov    %ecx,%edx
  mov    %eax,%ecx
  mov    %edi,%eax
  sub    %r11d,%eax
  add    %r9d,%eax
  cmp    %r10,%rdi
  jbe    L1
  cmp    $0x9,%edx
  jg     L41
L1:
  lea    D19(%rip),%rdx
  cmp    %rdx,%rdi
  jbe    L29
L31:
  test   %eax,%eax
  jle    L29
  lea    -0x1(%rax),%eax
  not    %rax
  add    %rdi,%rax
  lea    D19(%rip),%rdx
L47:
  sub    $0x1,%rdi
  mov    %r8b,0x1(%rdi)
  cmp    %rdx,%rdi
  jbe    L29
  cmp    %rdi,%rax
  jne    L47
  mov    %rax,%rdi
L29:
  add    $0x1,%rdi
  mov    $0x0,%eax
  call   <_add@plt>
  add    $0x8,%rsp
  ret
L76:
  mov    %esi,%eax
  lea    D38(%rip),%rdi
  jmp    L31
```

assistant: ```c
void _conv(n, digits, fill) int n, digits, fill;
{
  static char buf[10];
  register char *p;
  for (p = buf + sizeof(buf) - 2; n > 0 && p > buf; n /= 10, --digits)
    *p-- = n % 10 + '0';
  while (p > buf && digits-- > 0)
    *p-- = fill;
  _add(++p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_conv>:
  endbr64
  mov    %edx,%r11d
  test   %edi,%edi
  jle    L96
  lea    D2(%rip),%rax
  push   %rbx
  mov    %edi,%ecx
  mov    $0xcccccccd,%ebx
  lea    -0x8(%rax),%r9
  sub    %eax,%esi
  nopl   0x0(%rax)
L23:
  mov    %ecx,%edx
  mov    %ecx,%edi
  mov    %rax,%r10
  sub    $0x1,%rax
  imul   %rbx,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  add    $0x30,%edi
  mov    %dil,0x1(%rax)
  mov    %ecx,%edi
  mov    %edx,%ecx
  lea    (%rsi,%rax,1),%edx
  cmp    $0x9,%edi
  jle    L33
  cmp    %r9,%rax
  jne    L23
L76:
  mov    %r10,%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <_add@plt>
  nopl   0x0(%rax,%rax,1)
L33:
  cmp    %r9,%rax
  jbe    L76
  lea    0x1(%rax),%r10
  test   %edx,%edx
  jle    L76
  sub    $0x1,%edx
  lea    D13(%rip),%r9
  not    %rdx
  add    %rax,%rdx
  nopl   (%rax)
L93:
  mov    %rax,%r10
  sub    $0x1,%rax
  mov    %r11b,0x1(%rax)
  cmp    %r9,%rax
  jbe    L76
  cmp    %rax,%rdx
  jne    L93
  mov    %r10,%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <_add@plt>
L96:
  lea    D2(%rip),%rax
  mov    %esi,%edx
  lea    0x1(%rax),%r10
  test   %esi,%esi
  jle    L14
  sub    $0x1,%edx
  lea    D13(%rip),%r9
  not    %rdx
  add    %rax,%rdx
  nopl   0x0(%rax)
L10:
  mov    %rax,%r10
  sub    $0x1,%rax
  mov    %r11b,0x1(%rax)
  cmp    %r9,%rax
  jbe    L14
  cmp    %rax,%rdx
  jne    L10
L14:
  mov    %r10,%rdi
  xor    %eax,%eax
  jmp    1050 <_add@plt>
```

assistant: ```c
void _conv(n, digits, fill) int n, digits, fill;
{
  static char buf[10];
  register char *p;
  for (p = buf + sizeof(buf) - 2; n > 0 && p > buf; n /= 10, --digits)
    *p-- = n % 10 + '0';
  while (p > buf && digits-- > 0)
    *p-- = fill;
  _add(++p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_conv>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  test   %edi,%edi
  jle    L128
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %edi,%edx
  lea    (%rax,%rax,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edx
  add    $0x30,%edx
  mov    %dl,D85(%rip)
  lea    -0x1(%rcx),%edx
  cmp    $0x9,%edi
  jle    L92
  mov    %eax,%edx
  mov    $0xcccccccd,%r8d
  imul   %r8,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,D120(%rip)
  lea    -0x2(%rcx),%eax
  cmp    $0x63,%edi
  jle    L151
  mov    %edx,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edx
  add    $0x30,%edx
  mov    %dl,D74(%rip)
  lea    -0x3(%rcx),%edx
  cmp    $0x3e7,%edi
  jle    L85
  mov    %eax,%edx
  imul   %r8,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,D3(%rip)
  lea    -0x4(%rcx),%eax
  cmp    $0x270f,%edi
  jle    L69
  mov    %edx,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edx
  add    $0x30,%edx
  mov    %dl,D119(%rip)
  lea    -0x5(%rcx),%edx
  cmp    $0x1869f,%edi
  jle    L86
  mov    %eax,%edx
  imul   %r8,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%eax
  add    $0x30,%eax
  mov    %al,D41(%rip)
  lea    -0x6(%rcx),%eax
  cmp    $0xf423f,%edi
  jle    L21
  mov    %edx,%eax
  sub    $0x7,%ecx
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%edx
  add    $0x30,%edx
  mov    %dl,D16(%rip)
  cmp    $0x98967f,%edi
  jle    L44
  mov    %eax,%edx
  lea    D131(%rip),%rdi
  imul   %r8,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,D14(%rip)
L52:
  xor    %eax,%eax
  jmp    1050 <_add@plt>
L128:
  lea    D85(%rip),%rax
L14:
  lea    0x1(%rax),%rdi
  test   %ecx,%ecx
  jle    L52
  lea    -0x1(%rcx),%edx
  lea    D14(%rip),%rcx
  not    %rdx
  add    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %rax,%rdi
  sub    $0x1,%rax
  mov    %sil,0x1(%rax)
  cmp    %rcx,%rax
  jbe    L52
  cmp    %rax,%rdx
  jne    L48
  xor    %eax,%eax
  jmp    1050 <_add@plt>
L92:
  mov    %edx,%ecx
  lea    D120(%rip),%rax
  jmp    L14
L151:
  mov    %eax,%ecx
  lea    D74(%rip),%rax
  jmp    L14
L85:
  mov    %edx,%ecx
  lea    D3(%rip),%rax
  jmp    L14
L69:
  mov    %eax,%ecx
  lea    D119(%rip),%rax
  jmp    L14
L86:
  mov    %edx,%ecx
  lea    D41(%rip),%rax
  jmp    L14
L21:
  mov    %eax,%ecx
  lea    D16(%rip),%rax
  jmp    L14
L44:
  lea    D14(%rip),%rax
  jmp    L14
```

assistant: ```c
void _conv(n, digits, fill) int n, digits, fill;
{
  static char buf[10];
  register char *p;
  for (p = buf + sizeof(buf) - 2; n > 0 && p > buf; n /= 10, --digits)
    *p-- = n % 10 + '0';
  while (p > buf && digits-- > 0)
    *p-- = fill;
  _add(++p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getNode@plt>
  mov    %rax,-0x58(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L24
L18:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <addString@plt>
  mov    %eax,-0x5c(%rbp)
  cmpl   $0x0,-0x5c(%rbp)
  je     L24
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L13
L24:
  mov    -0x60(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x60(%rbp)
  test   %eax,%eax
  jne    L18
L13:
  cmpl   $0x0,-0x5c(%rbp)
  jne    L5
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D21
data_type: string

tool: D35: %d

tool: D37: %s

tool: D22: BAD SET

tool: D21: GOOD SET

assistant: ```c
int main() {
  struct trienode *root = getNode();
  int n, flag;
  scanf("%d", &n);
  while (n--) {
    char str[61];
    scanf("%s", str);
    flag = addString(root, str);
    if (flag) {
      printf("BAD SET\n");
      printf("%s\n", str);
      break;
    }
  }
  if (!flag) {
    printf("GOOD SET\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <getNode@plt>
  mov    %rax,%rbp
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L21
  lea    D22(%rip),%r12
L23:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <addString@plt>
  test   %eax,%eax
  jne    L29
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L23
L21:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  jmp    L42
L29:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
L42:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D32
type: string

tool: D20: %d

tool: D22: %s

tool: D12: GOOD SET

tool: D32: BAD SET

assistant: ```c
int main() {
  struct trienode *root = getNode();
  int n, flag;
  scanf("%d", &n);
  while (n--) {
    char str[61];
    scanf("%s", str);
    flag = addString(root, str);
    if (flag) {
      printf("BAD SET\n");
      printf("%s\n", str);
      break;
    }
  }
  if (!flag) {
    printf("GOOD SET\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <getNode@plt>
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L49
  lea    0x10(%rsp),%rbp
  lea    D31(%rip),%r12
  jmp    L57
  nopl   0x0(%rax)
L40:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L49
L57:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <addString@plt>
  test   %eax,%eax
  je     L40
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L8
L49:
  lea    D12(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string

tool: D17: %d

tool: D31: %s

tool: D8: BAD SET

tool: D12: GOOD SET

assistant: ```c
int main() {
  struct trienode *root = getNode();
  int n, flag;
  scanf("%d", &n);
  while (n--) {
    char str[61];
    scanf("%s", str);
    flag = addString(root, str);
    if (flag) {
      printf("BAD SET\n");
      printf("%s\n", str);
      break;
    }
  }
  if (!flag) {
    printf("GOOD SET\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <getNode@plt>
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L5
  lea    0x10(%rsp),%rbp
  lea    D24(%rip),%r12
  jmp    L24
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L5
L24:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <addString@plt>
  test   %eax,%eax
  je     L7
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L20
L5:
  lea    D27(%rip),%rdi
  call   <puts@plt>
L20:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D37
datatype: string
name: unpack_data
arguments: label: D27
datatype: string

tool: D1: %d

tool: D24: %s

tool: D37: BAD SET

tool: D27: GOOD SET

assistant: ```c
int main() {
  struct trienode *root = getNode();
  int n, flag;
  scanf("%d", &n);
  while (n--) {
    char str[61];
    scanf("%s", str);
    flag = addString(root, str);
    if (flag) {
      printf("BAD SET\n");
      printf("%s\n", str);
      break;
    }
  }
  if (!flag) {
    printf("GOOD SET\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DoUpdate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <CheckRunningInMainThread@plt>
  test   %eax,%eax
  jne    L11
  mov    $0x3d2,%eax
  jmp    L10
L11:
  mov    $0x47,%edi
  call   <CallBack0@plt>
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: DoUpdate

assistant: ```c
int DoUpdate(void) {
  if (!CheckRunningInMainThread("DoUpdate"))
    return 978;
  CallBack0(71);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DoUpdate>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  mov    %eax,%edx
  mov    $0x3d2,%eax
  test   %edx,%edx
  je     L8
  mov    $0x47,%edi
  call   <CallBack0@plt>
  mov    $0x0,%eax
L8:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: DoUpdate

assistant: ```c
int DoUpdate(void) {
  if (!CheckRunningInMainThread("DoUpdate"))
    return 978;
  CallBack0(71);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DoUpdate>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  mov    %eax,%r8d
  mov    $0x3d2,%eax
  test   %r8d,%r8d
  je     L2
  mov    $0x47,%edi
  call   <CallBack0@plt>
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: DoUpdate

assistant: ```c
int DoUpdate(void) {
  if (!CheckRunningInMainThread("DoUpdate"))
    return 978;
  CallBack0(71);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DoUpdate>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  mov    %eax,%r8d
  mov    $0x3d2,%eax
  test   %r8d,%r8d
  je     L4
  mov    $0x47,%edi
  call   <CallBack0@plt>
  xor    %eax,%eax
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: DoUpdate

assistant: ```c
int DoUpdate(void) {
  if (!CheckRunningInMainThread("DoUpdate"))
    return 978;
  CallBack0(71);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arraystr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x4(%rbp),%eax
  jmp    L15
L29:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  mov    $0xffffffff,%eax
L15:
  leave
  ret
```

assistant: ```c
int arraystr(char **arr, int nmemb, char *str) {
  for (int i = 0; i < nmemb; i++) {
    if (strcmp(arr[i], str) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arraystr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L6:
  mov    %ebx,%r14d
  mov    (%r12,%rbx,8),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  mov    $0xffffffff,%r14d
L13:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0xffffffff,%r14d
  jmp    L13
```

assistant: ```c
int arraystr(char **arr, int nmemb, char *str) {
  for (int i = 0; i < nmemb; i++) {
    if (strcmp(arr[i], str) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<arraystr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  mov    %rdi,%r14
  mov    %rdx,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L38
  nopl   (%rax)
L35:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L7
L38:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int arraystr(char **arr, int nmemb, char *str) {
  for (int i = 0; i < nmemb; i++) {
    if (strcmp(arr[i], str) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arraystr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L34
  mov    %rdi,%r14
  mov    %rdx,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  jmp    L20
  nopl   (%rax)
L17:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L34
L20:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int arraystr(char **arr, int nmemb, char *str) {
  for (int i = 0; i < nmemb; i++) {
    if (strcmp(arr[i], str) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stack_depth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  cmpl   $0x80,-0x424(%rbp)
  jle    L10
  movl   $0x80,-0x424(%rbp)
L10:
  mov    -0x424(%rbp),%edx
  lea    -0x410(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <backtrace@plt>
  mov    %eax,-0x414(%rbp)
  mov    -0x414(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int stack_depth(int max) {
  void *stack[128];
  int size = 0;
  if (max > 128)
    max = 128;
  size = backtrace(stack, max);
  return size - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<stack_depth>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x80,%eax
  cmp    %eax,%edi
  cmovle %edi,%eax
  mov    %eax,%esi
  mov    %rsp,%rdi
  call   <backtrace@plt>
  sub    $0x1,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x418,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stack_depth(int max) {
  void *stack[128];
  int size = 0;
  if (max > 128)
    max = 128;
  size = backtrace(stack, max);
  return size - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stack_depth>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  mov    $0x80,%eax
  cmp    %eax,%edi
  cmovle %edi,%eax
  mov    %rsp,%rdi
  mov    %eax,%esi
  call   <backtrace@plt>
  sub    $0x1,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x418,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stack_depth(int max) {
  void *stack[128];
  int size = 0;
  if (max > 128)
    max = 128;
  size = backtrace(stack, max);
  return size - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stack_depth>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  mov    $0x80,%eax
  cmp    %eax,%edi
  cmovle %edi,%eax
  mov    %rsp,%rdi
  mov    %eax,%esi
  call   <backtrace@plt>
  sub    $0x1,%eax
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x418,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stack_depth(int max) {
  void *stack[128];
  int size = 0;
  if (max > 128)
    max = 128;
  size = backtrace(stack, max);
  return size - 1;
}
```