ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fname_is_avail>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jns    L9
  mov    D1(%rip),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  sete   %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fname_is_avail(char *fname) {
  struct stat stat_buf;
  if ((stat(fname, &stat_buf) < 0) && errno == ENOENT)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NewPage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <PageThrow@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: %c

assistant: ```c
void NewPage(void) {
  printf("%c", 0x0C);
  PageThrow();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<NewPage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <PageThrow@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string

tool: D1: %c

assistant: ```c
void NewPage(void) {
  printf("%c", 0x0C);
  PageThrow();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<NewPage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <PageThrow@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: %c

assistant: ```c
void NewPage(void) {
  printf("%c", 0x0C);
  PageThrow();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<NewPage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <PageThrow@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: %c

assistant: ```c
void NewPage(void) {
  printf("%c", 0x0C);
  PageThrow();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ulong_to_binary_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x40,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L34:
  mov    -0x10(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L16
  cmpl   $0x0,-0x10(%rbp)
  jle    L16
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5f,(%rax)
L16:
  subl   $0x1,-0x10(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  jns    L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ulong_to_binary_string(unsigned long input, char output[]) {
  int num_bits = sizeof(unsigned long) * 8;
  int i;
  char *p;
  p = output;
  for (i = num_bits - 1; i >= 0; i--) {
    *p++ = ((input >> i) & 1) + '0';
    if (((i % 8) == 0) && (i > 0))
      *p++ = '_';
  }
  *p++ = 0;
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ulong_to_binary_string>:
  endbr64
  mov    %rsi,%rdx
  mov    $0x3e,%r8d
  mov    $0x3f,%ecx
  jmp    L15
L49:
  test   %r8d,%r8d
  js     L37
  add    $0x1,%rdx
L48:
  sub    $0x1,%ecx
  sub    $0x1,%r8d
L15:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,(%rdx)
  test   $0x7,%cl
  jne    L49
  test   %ecx,%ecx
  jle    L49
  movb   $0x5f,0x1(%rdx)
  lea    0x2(%rdx),%rdx
  jmp    L48
L37:
  movb   $0x0,0x1(%rdx)
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *ulong_to_binary_string(unsigned long input, char output[]) {
  int num_bits = sizeof(unsigned long) * 8;
  int i;
  char *p;
  p = output;
  for (i = num_bits - 1; i >= 0; i--) {
    *p++ = ((input >> i) & 1) + '0';
    if (((i % 8) == 0) && (i > 0))
      *p++ = '_';
  }
  *p++ = 0;
  return output;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ulong_to_binary_string>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  lea    0x1(%rsi),%rdx
  mov    $0x3f,%ecx
  shr    $0x3f,%rax
  add    $0x30,%eax
  mov    %al,(%rsi)
  nopl   0x0(%rax)
L8:
  sub    $0x1,%ecx
  jb     L26
L14:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,(%rdx)
  test   $0x7,%cl
  jne    L44
  test   %ecx,%ecx
  je     L44
  movb   $0x5f,0x1(%rdx)
  add    $0x2,%rdx
  sub    $0x1,%ecx
  jae    L14
L26:
  movb   $0x0,(%rdx)
  mov    %r8,%rax
  ret
L44:
  add    $0x1,%rdx
  jmp    L8
```

assistant: ```c
char *ulong_to_binary_string(unsigned long input, char output[]) {
  int num_bits = sizeof(unsigned long) * 8;
  int i;
  char *p;
  p = output;
  for (i = num_bits - 1; i >= 0; i--) {
    *p++ = ((input >> i) & 1) + '0';
    if (((i % 8) == 0) && (i > 0))
      *p++ = '_';
  }
  *p++ = 0;
  return output;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ulong_to_binary_string>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  lea    0x1(%rsi),%rdx
  mov    $0x3e,%ecx
  shr    $0x3f,%rax
  add    $0x30,%eax
  mov    %al,(%rsi)
  jmp    L17
  xchg   %ax,%ax
L43:
  test   %ecx,%ecx
  je     L19
  movb   $0x5f,0x1(%rdx)
  add    $0x2,%rdx
  sub    $0x1,%ecx
  jb     L13
L17:
  mov    %rdi,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,(%rdx)
  test   $0x7,%cl
  je     L43
L19:
  add    $0x1,%rdx
  sub    $0x1,%ecx
  jae    L17
L13:
  movb   $0x0,(%rdx)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ulong_to_binary_string(unsigned long input, char output[]) {
  int num_bits = sizeof(unsigned long) * 8;
  int i;
  char *p;
  p = output;
  for (i = num_bits - 1; i >= 0; i--) {
    *p++ = ((input >> i) & 1) + '0';
    if (((i % 8) == 0) && (i > 0))
      *p++ = '_';
  }
  *p++ = 0;
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <count@plt>
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int setBits(int n) {
  int bit = 0;
  for (int i = 0; i < n; i++) {
    bit = bit + count(i);
  }
  return bit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setBits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L0
  mov    %edi,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L24:
  mov    %ebx,%edi
  call   <count@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L24
L23:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    $0x0,%ebp
  jmp    L23
```

assistant: ```c
int setBits(int n) {
  int bit = 0;
  for (int i = 0; i < n; i++) {
    bit = bit + count(i);
  }
  return bit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setBits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L9
  mov    %edi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <count@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jne    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int setBits(int n) {
  int bit = 0;
  for (int i = 0; i < n; i++) {
    bit = bit + count(i);
  }
  return bit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<setBits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L3
  mov    %edi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <count@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jne    L19
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int setBits(int n) {
  int bit = 0;
  for (int i = 0; i < n; i++) {
    bit = bit + count(i);
  }
  return bit;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<int_tobin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x1,-0x8(%rbp)
  movb   $0x0,-0xa(%rbp)
  movb   $0x3f,-0x9(%rbp)
  jmp    L6
L22:
  movsbl -0x9(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  and    -0x18(%rbp),%rax
  cmp    $0x1,%rax
  jne    L17
  movb   $0x1,-0xa(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x31,(%rax)
  jmp    L24
L17:
  cmpb   $0x0,-0xa(%rbp)
  je     L24
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x30,(%rax)
L24:
  movzbl -0x9(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x9(%rbp)
L6:
  cmpb   $0x0,-0x9(%rbp)
  jns    L22
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *int_tobin(const unsigned long long value, char *buffer) {
  const unsigned long long mask = 1;
  unsigned char nonzero = 0;
  for (char bit = 63; bit >= 0; --bit) {
    if ((value & (mask << bit)) == 1) {
      nonzero = 1;
      *buffer++ = '1';
    } else if (nonzero != 0) {
      *buffer++ = '0';
    }
  }
  *buffer = '\0';
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<int_tobin>:
  endbr64
  mov    $0x3f,%ecx
  mov    $0x0,%r8d
  mov    $0x1,%edx
  mov    $0x1,%r9d
  jmp    L27
L4:
  movb   $0x31,(%rsi)
  lea    0x1(%rsi),%rsi
  mov    %r9d,%r8d
L6:
  sub    $0x1,%ecx
  cmp    $0xffffffff,%ecx
  je     L15
L27:
  mov    %rdx,%rax
  shl    %cl,%rax
  and    %rdi,%rax
  cmp    $0x1,%rax
  je     L4
  test   %r8b,%r8b
  je     L6
  movb   $0x30,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L6
L15:
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *int_tobin(const unsigned long long value, char *buffer) {
  const unsigned long long mask = 1;
  unsigned char nonzero = 0;
  for (char bit = 63; bit >= 0; --bit) {
    if ((value & (mask << bit)) == 1) {
      nonzero = 1;
      *buffer++ = '1';
    } else if (nonzero != 0) {
      *buffer++ = '0';
    }
  }
  *buffer = '\0';
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_tobin>:
  endbr64
  mov    %rsi,%r8
  mov    $0x3f,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  jmp    L18
  nopl   (%rax)
L39:
  test   %sil,%sil
  je     L12
  movb   $0x30,(%r8)
  add    $0x1,%r8
L12:
  sub    $0x1,%ecx
  jb     L23
L18:
  mov    %rdx,%rax
  shl    %cl,%rax
  and    %rdi,%rax
  cmp    $0x1,%rax
  jne    L39
  movb   $0x31,(%r8)
  mov    $0x1,%esi
  add    $0x1,%r8
  sub    $0x1,%ecx
  jae    L18
L23:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *int_tobin(const unsigned long long value, char *buffer) {
  const unsigned long long mask = 1;
  unsigned char nonzero = 0;
  for (char bit = 63; bit >= 0; --bit) {
    if ((value & (mask << bit)) == 1) {
      nonzero = 1;
      *buffer++ = '1';
    } else if (nonzero != 0) {
      *buffer++ = '0';
    }
  }
  *buffer = '\0';
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<int_tobin>:
  endbr64
  mov    %rsi,%r8
  mov    $0x3f,%ecx
  xor    %esi,%esi
  mov    $0x1,%edx
  jmp    L32
  nopl   (%rax)
L28:
  test   %sil,%sil
  je     L9
  movb   $0x30,(%r8)
  add    $0x1,%r8
L9:
  sub    $0x1,%ecx
  jb     L19
L32:
  mov    %rdx,%rax
  shl    %cl,%rax
  and    %rdi,%rax
  cmp    $0x1,%rax
  jne    L28
  movb   $0x31,(%r8)
  mov    $0x1,%esi
  add    $0x1,%r8
  sub    $0x1,%ecx
  jae    L32
L19:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *int_tobin(const unsigned long long value, char *buffer) {
  const unsigned long long mask = 1;
  unsigned char nonzero = 0;
  for (char bit = 63; bit >= 0; --bit) {
    if ((value & (mask << bit)) == 1) {
      nonzero = 1;
      *buffer++ = '1';
    } else if (nonzero != 0) {
      *buffer++ = '0';
    }
  }
  *buffer = '\0';
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ta_sscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ta_vsscanf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void ta_sscanf(const char *buf, const char *format, ...) {
  va_list list;
  va_start(list, format);
  ta_vsscanf(buf, format, list);
  va_end(list);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ta_sscanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <ta_vsscanf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ta_sscanf(const char *buf, const char *format, ...) {
  va_list list;
  va_start(list, format);
  ta_vsscanf(buf, format, list);
  va_end(list);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ta_sscanf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ta_vsscanf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ta_sscanf(const char *buf, const char *format, ...) {
  va_list list;
  va_start(list, format);
  ta_vsscanf(buf, format, list);
  va_end(list);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ta_sscanf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <ta_vsscanf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ta_sscanf(const char *buf, const char *format, ...) {
  va_list list;
  va_start(list, format);
  ta_vsscanf(buf, format, list);
  va_end(list);
}
```
user: What is the c source code of the assembly code below?

```asm
<LPCChannelConfigEPSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shr    %rax
  shl    $0x5,%rax
  and    $0x7fe0,%eax
  or     %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x18,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LPCChannelConfigEPSet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulConfig, unsigned long ulAddress, unsigned long ulOffset) {
  ;
  ;

  ;
  ;

  ;
  ulConfig |= (((ulOffset >> 1) << 5) & 0x00007FE0);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulChannel * 0x10)))) = ulConfig;
  (*((volatile unsigned long *)(ulBase + 0x00000018 + (ulChannel * 0x10)))) = ulAddress;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LPCChannelConfigEPSet>:
  endbr64
  shl    $0x4,%r8
  and    $0x7fe0,%r8d
  or     %rdx,%r8
  shl    $0x4,%rsi
  add    %rdi,%rsi
  mov    %r8,0x10(%rsi)
  mov    %rcx,0x18(%rsi)
  ret
```

assistant: ```c
void LPCChannelConfigEPSet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulConfig, unsigned long ulAddress, unsigned long ulOffset) {
  ;
  ;

  ;
  ;

  ;
  ulConfig |= (((ulOffset >> 1) << 5) & 0x00007FE0);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulChannel * 0x10)))) = ulConfig;
  (*((volatile unsigned long *)(ulBase + 0x00000018 + (ulChannel * 0x10)))) = ulAddress;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<LPCChannelConfigEPSet>:
  endbr64
  shl    $0x4,%r8
  shl    $0x4,%rsi
  and    $0x7fe0,%r8d
  add    %rdi,%rsi
  or     %rdx,%r8
  mov    %r8,0x10(%rsi)
  mov    %rcx,0x18(%rsi)
  ret
```

assistant: ```c
void LPCChannelConfigEPSet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulConfig, unsigned long ulAddress, unsigned long ulOffset) {
  ;
  ;

  ;
  ;

  ;
  ulConfig |= (((ulOffset >> 1) << 5) & 0x00007FE0);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulChannel * 0x10)))) = ulConfig;
  (*((volatile unsigned long *)(ulBase + 0x00000018 + (ulChannel * 0x10)))) = ulAddress;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LPCChannelConfigEPSet>:
  endbr64
  shl    $0x4,%r8
  shl    $0x4,%rsi
  and    $0x7fe0,%r8d
  add    %rdi,%rsi
  or     %rdx,%r8
  mov    %r8,0x10(%rsi)
  mov    %rcx,0x18(%rsi)
  ret
```

assistant: ```c
void LPCChannelConfigEPSet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulConfig, unsigned long ulAddress, unsigned long ulOffset) {
  ;
  ;

  ;
  ;

  ;
  ulConfig |= (((ulOffset >> 1) << 5) & 0x00007FE0);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulChannel * 0x10)))) = ulConfig;
  (*((volatile unsigned long *)(ulBase + 0x00000018 + (ulChannel * 0x10)))) = ulAddress;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <usage_banner@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usage() {
  usage_banner();
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <usage_banner@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usage() {
  usage_banner();
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <usage_banner@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void usage() {
  usage_banner();
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L21
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x48(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x40(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    0x10(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L8
L21:
  movl   $0x0,-0x14(%rbp)
  jmp    L22
L12:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L35
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x40(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%r8d
  mov    -0x48(%rbp),%rdi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %rdi,%r9
  mov    %rax,%rdi
  call   <dfs>
  add    $0x10,%rsp
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L35:
  addl   $0x1,-0x14(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
L8:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void dfs(int *nums, int size, bool *used, int *stack, int len, int **results, int *count, int *col_size) {
  int i;
  if (len == size) {
    results[*count] = malloc(size * sizeof(int));
    memcpy(results[*count], stack, size * sizeof(int));
    col_size[*count] = size;
    (*count)++;
  } else {
    for (i = 0; i < size; i++) {
      if (!used[i]) {
        used[i] = true;
        stack[len] = nums[i];
        dfs(nums, size, used, stack, len + 1, results, count, col_size);
        used[i] = false;
      }
    }
  }
}
```