ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gpio_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20e02d0,%edi
  call   <gpio_init_mux@plt>
  mov    $0x20e06b8,%edi
  call   <gpio_init_pad@plt>
  mov    0x20b4004,%eax
  mov    $0x20e00bc,%edi
  or     $0x1,%ah
  mov    %eax,0x20b4004
  call   <gpio_init_mux@plt>
  mov    $0x20e03d0,%edi
  call   <gpio_init_pad@plt>
  mov    0x20a4004,%eax
  mov    $0x20e0250,%edi
  or     $0x4000000,%eax
  mov    %eax,0x20a4004
  call   <gpio_init_mux@plt>
  mov    $0x20e0620,%edi
  call   <gpio_init_pad@plt>
  mov    0x20b4004,%eax
  mov    $0x20e0254,%edi
  or     $0x20,%ah
  mov    %eax,0x20b4004
  call   <gpio_init_mux@plt>
  mov    $0x20e0624,%edi
  call   <gpio_init_pad@plt>
  mov    0x20a8004,%eax
  or     $0x20,%eax
  mov    %eax,0x20a8004
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gpio_init(void) {
  gpio_init_mux(&(*((volatile uint32_t *)0x20e02d0u)));
  gpio_init_pad(&(*((volatile uint32_t *)0x20e06b8u)));
  (*((volatile uint32_t *)0x20b4004u)) |= 1 << 8;
  gpio_init_mux(&(*((volatile uint32_t *)0x20e00bcu)));
  gpio_init_pad(&(*((volatile uint32_t *)0x20e03d0u)));
  (*((volatile uint32_t *)0x20a4004u)) |= 1 << 26;
  gpio_init_mux(&(*((volatile uint32_t *)0x20e0250u)));
  gpio_init_pad(&(*((volatile uint32_t *)0x20e0620u)));
  (*((volatile uint32_t *)0x20b4004u)) |= 1 << 13;
  gpio_init_mux(&(*((volatile uint32_t *)0x20e0254u)));
  gpio_init_pad(&(*((volatile uint32_t *)0x20e0624u)));
  (*((volatile uint32_t *)0x20a8004u)) |= 1 << 5;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L17:
  movzbl -0x9(%rbp),%eax
  mov    $0x3f0,%esi
  mov    %eax,%edi
  call   <__builtin_outb@plt>
L1:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L17
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: one


assistant: ```c
void main(void) {
  const char *str;
  unsigned char ch;
  str = "one\r\n";
  while ((ch = *str++) != '\0') {
    __builtin_outb(ch, 0x3f0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6f,%edi
  lea    D8(%rip),%rbx
L4:
  movzbl %dil,%edi
  mov    $0x3f0,%esi
  call   <__builtin_outb@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L4
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: ne


assistant: ```c
void main(void) {
  const char *str;
  unsigned char ch;
  str = "one\r\n";
  while ((ch = *str++) != '\0') {
    __builtin_outb(ch, 0x3f0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6f,%edi
  lea    D4(%rip),%rbx
  nopl   0x0(%rax)
L5:
  mov    $0x3f0,%esi
  add    $0x1,%rbx
  call   <__builtin_outb@plt>
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L5
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: ne


assistant: ```c
void main(void) {
  const char *str;
  unsigned char ch;
  str = "one\r\n";
  while ((ch = *str++) != '\0') {
    __builtin_outb(ch, 0x3f0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6f,%edi
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L8:
  mov    $0x3f0,%esi
  add    $0x1,%rbx
  call   <__builtin_outb@plt>
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L8
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: ne


assistant: ```c
void main(void) {
  const char *str;
  unsigned char ch;
  str = "one\r\n";
  while ((ch = *str++) != '\0') {
    __builtin_outb(ch, 0x3f0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fillPosition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <writePosition@plt>
  cmpl   $0x7,-0x4(%rbp)
  jne    L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <addToSolutionList@plt>
  jmp    L13
L10:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <fillRow@plt>
L13:
  nop
  leave
  ret
```

assistant: ```c
void fillPosition(int row, int col, int **chessboard) {
  writePosition(row, col, chessboard);
  if (row == 7) {
    addToSolutionList(chessboard);
  } else {
    fillRow(row + 1, chessboard);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fillPosition>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rdx,%rbp
  call   <writePosition@plt>
  cmp    $0x7,%ebx
  je     L0
  lea    0x1(%rbx),%edi
  mov    %rbp,%rsi
  call   <fillRow@plt>
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rdi
  call   <addToSolutionList@plt>
  jmp    L3
```

assistant: ```c
void fillPosition(int row, int col, int **chessboard) {
  writePosition(row, col, chessboard);
  if (row == 7) {
    addToSolutionList(chessboard);
  } else {
    fillRow(row + 1, chessboard);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fillPosition>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <writePosition@plt>
  cmp    $0x7,%ebx
  je     L0
  add    $0x8,%rsp
  lea    0x1(%rbx),%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1090 <fillRow@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <addToSolutionList@plt>
```

assistant: ```c
void fillPosition(int row, int col, int **chessboard) {
  writePosition(row, col, chessboard);
  if (row == 7) {
    addToSolutionList(chessboard);
  } else {
    fillRow(row + 1, chessboard);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fillPosition>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <writePosition@plt>
  cmp    $0x7,%ebx
  je     L6
  add    $0x8,%rsp
  lea    0x1(%rbx),%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1090 <fillRow@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <addToSolutionList@plt>
```

assistant: ```c
void fillPosition(int row, int col, int **chessboard) {
  writePosition(row, col, chessboard);
  if (row == 7) {
    addToSolutionList(chessboard);
  } else {
    fillRow(row + 1, chessboard);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%edi
  call   <my_sleep@plt>
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D13
data_type: string

tool: D16: [%lu] caught %d


tool: D13: [%lu] wake from sleep in signal handler


assistant: ```c
void sig_int(int signo) {
  printf("[%lu] caught %d\n", pthread_self(), signo);
  my_sleep(5);
  printf("[%lu] wake from sleep in signal handler\n", pthread_self());
}
```
user: What is the c source code of the assembly code below?

```asm
<sig_int>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%edi
  call   <my_sleep@plt>
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string

tool: D12: [%lu] caught %d


tool: D5: [%lu] wake from sleep in signal handler


assistant: ```c
void sig_int(int signo) {
  printf("[%lu] caught %d\n", pthread_self(), signo);
  my_sleep(5);
  printf("[%lu] wake from sleep in signal handler\n", pthread_self());
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sig_int>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <pthread_self@plt>
  mov    %r12d,%edx
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%edi
  call   <my_sleep@plt>
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D18(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D16: [%lu] caught %d


tool: D18: [%lu] wake from sleep in signal handler


assistant: ```c
void sig_int(int signo) {
  printf("[%lu] caught %d\n", pthread_self(), signo);
  my_sleep(5);
  printf("[%lu] wake from sleep in signal handler\n", pthread_self());
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sig_int>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <pthread_self@plt>
  mov    %r12d,%edx
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%edi
  call   <my_sleep@plt>
  xor    %eax,%eax
  call   <pthread_self@plt>
  lea    D9(%rip),%rdi
  pop    %r12
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D2: [%lu] caught %d


tool: D9: [%lu] wake from sleep in signal handler


assistant: ```c
void sig_int(int signo) {
  printf("[%lu] caught %d\n", pthread_self(), signo);
  my_sleep(5);
  printf("[%lu] wake from sleep in signal handler\n", pthread_self());
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getbool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L27
L8:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x54,%al
  je     L46
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x74,%al
  jne    L48
L46:
  mov    $0x1,%eax
  jmp    L20
L48:
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
int getbool(char *start) {
  while (isspace(*start))
    ++start;
  if (*start == 'T' || *start == 't')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getbool>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L9
L4:
  add    $0x1,%rbx
L9:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  movzbl (%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getbool(char *start) {
  while (isspace(*start))
    ++start;
  if (*start == 'T' || *start == 't')
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getbool>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rbx
L1:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  movzbl (%rbx),%eax
  pop    %rbx
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int getbool(char *start) {
  while (isspace(*start))
    ++start;
  if (*start == 'T' || *start == 't')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getbool>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rbx
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  movzbl (%rbx),%eax
  pop    %rbx
  and    $0xffffffdf,%eax
  cmp    $0x54,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int getbool(char *start) {
  while (isspace(*start))
    ++start;
  if (*start == 'T' || *start == 't')
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <convert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  convert();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <convert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  convert();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <convert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  convert();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <convert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  convert();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f_calculate>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L44
  cmp    $0x8,%eax
  ja     L3
  mov    %eax,%eax
  lea    D32(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L44:
  mov    $0x0,%eax
  call   <first_f@plt>
  mov    $0x0,%ebx
L92:
  mov    $0x0,%eax
  call   <clear_s@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
  mov    $0x0,%eax
  call   <second_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x0,%eax
  call   <third_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x0,%eax
  call   <fourth_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x0,%eax
  call   <fifth_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x0,%eax
  call   <sixth_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <eighth_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <eighth_f@plt>
  mov    $0x0,%ebx
  jmp    L92
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%ebx
  jmp    L92
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  jmp    L92
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D38
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D39
datatype: string
name: disassemble_data
arguments: data_label: D42
datatype: string

tool: D38: ENTER NEW SELECTION : 

tool: D25: %d

tool: D4: cls

tool: D39: Thanks for using this program

tool: D42: EAP / exercise 1 / theme 4

assistant: ```c
int f_calculate(i) {
  i = 0;
  int a_num;
  printf("ENTER NEW SELECTION : ");
  scanf("%d", &a_num);
  system("cls");
  if (a_num == 1) {
    first_f();
  } else if (a_num == 2) {
    second_f();
  } else if (a_num == 3) {
    third_f();
  } else if (a_num == 4) {
    fourth_f();
  } else if (a_num == 5) {
    fifth_f();
  } else if (a_num == 6) {
    sixth_f();
  } else if (a_num == 7) {
    int show = 0;
    eighth_f(show);
  } else if (a_num == 8) {
    int show = 1;
    eighth_f(show);
  } else if (a_num == 0) {
    printf("Thanks for using this program\n");
    printf("EAP / exercise 1 / theme 4\n");
    i = -1;
  } else {
    printf("\n");
  }
  clear_s();
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f_calculate>:
  endbr64
  push   %r12
  lea    D59(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L85
  cmp    $0x8,%eax
  ja     L55
  lea    D16(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L85:
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <first_f@plt>
L100:
  xor    %eax,%eax
  call   <clear_s@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
  mov    $0x1,%edi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <eighth_f@plt>
  jmp    L100
  nopl   0x0(%rax)
  lea    D12(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L100
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <second_f@plt>
  jmp    L100
  nopl   0x0(%rax)
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <third_f@plt>
  jmp    L100
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fourth_f@plt>
  jmp    L100
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fifth_f@plt>
  jmp    L100
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <sixth_f@plt>
  jmp    L100
  nop
  xor    %edi,%edi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <eighth_f@plt>
  jmp    L100
  nopl   0x0(%rax)
L55:
  mov    $0xa,%edi
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L100
L96:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D59
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D33
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D59: ENTER NEW SELECTION : 

tool: D22: %d

tool: D33: cls

tool: D12: Thanks for using this program

tool: D1: EAP / exercise 1 / theme 4

assistant: ```c
int f_calculate(i) {
  i = 0;
  int a_num;
  printf("ENTER NEW SELECTION : ");
  scanf("%d", &a_num);
  system("cls");
  if (a_num == 1) {
    first_f();
  } else if (a_num == 2) {
    second_f();
  } else if (a_num == 3) {
    third_f();
  } else if (a_num == 4) {
    fourth_f();
  } else if (a_num == 5) {
    fifth_f();
  } else if (a_num == 6) {
    sixth_f();
  } else if (a_num == 7) {
    int show = 0;
    eighth_f(show);
  } else if (a_num == 8) {
    int show = 1;
    eighth_f(show);
  } else if (a_num == 0) {
    printf("Thanks for using this program\n");
    printf("EAP / exercise 1 / theme 4\n");
    i = -1;
  } else {
    printf("\n");
  }
  clear_s();
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f_calculate>:
  endbr64
  push   %r12
  lea    D26(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <system@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L117
  cmp    $0x8,%eax
  ja     L56
  lea    D43(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L117:
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <first_f@plt>
L15:
  xor    %eax,%eax
  call   <clear_s@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
  mov    $0x1,%edi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <eighth_f@plt>
  jmp    L15
  nopl   0x0(%rax)
  lea    D28(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <puts@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  jmp    L15
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <second_f@plt>
  jmp    L15
  nopl   0x0(%rax)
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <third_f@plt>
  jmp    L15
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fourth_f@plt>
  jmp    L15
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fifth_f@plt>
  jmp    L15
  nop
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <sixth_f@plt>
  jmp    L15
  nop
  xor    %edi,%edi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <eighth_f@plt>
  jmp    L15
  nopl   0x0(%rax)
L56:
  mov    $0xa,%edi
  xor    %r12d,%r12d
  call   <putchar@plt>
  jmp    L15
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type: string
name: unpack_data
arguments: data_tag: D42
type: string
name: unpack_data
arguments: data_tag: D58
type: string
name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D53
type: string

tool: D26: ENTER NEW SELECTION : 

tool: D42: %d

tool: D58: cls

tool: D28: Thanks for using this program

tool: D53: EAP / exercise 1 / theme 4

assistant: ```c
int f_calculate(i) {
  i = 0;
  int a_num;
  printf("ENTER NEW SELECTION : ");
  scanf("%d", &a_num);
  system("cls");
  if (a_num == 1) {
    first_f();
  } else if (a_num == 2) {
    second_f();
  } else if (a_num == 3) {
    third_f();
  } else if (a_num == 4) {
    fourth_f();
  } else if (a_num == 5) {
    fifth_f();
  } else if (a_num == 6) {
    sixth_f();
  } else if (a_num == 7) {
    int show = 0;
    eighth_f(show);
  } else if (a_num == 8) {
    int show = 1;
    eighth_f(show);
  } else if (a_num == 0) {
    printf("Thanks for using this program\n");
    printf("EAP / exercise 1 / theme 4\n");
    i = -1;
  } else {
    printf("\n");
  }
  clear_s();
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HMM_Power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  mov    $0x21a,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <_hmt_count_cover@plt>
  movss  D26(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L10
  movss  D26(%rip),%xmm0
  divss  -0x14(%rbp),%xmm0
  jmp    L21
L10:
  movss  -0x14(%rbp),%xmm0
L21:
  movss  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L49
L27:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L41
  mov    $0x223,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <_hmt_count_cover@plt>
  movss  -0xc(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L41:
  movss  -0x8(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  sarl   -0x4(%rbp)
L49:
  cmpl   $0x0,-0x4(%rbp)
  jne    L27
  movss  -0xc(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D26
datatype: byte[4]

tool: D28: HMM_Power

tool: {"D26": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float HMM_Power(float Base, int Exponent) {
  { _hmt_count_cover("HMM_Power", 538); };
  float Result = 1.0f;
  float Mul = Exponent < 0 ? 1.f / Base : Base;
  int X = Exponent < 0 ? -Exponent : Exponent;
  while (X) {
    if (X & 1) {
      { _hmt_count_cover("HMM_Power", 547); };
      Result *= Mul;
    }
    Mul *= Mul;
    X >>= 1;
  }
  return (Result);
}
```