ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x7a120,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  mov    %ebp,%edi
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  call   <next_term@plt>
  mov    %eax,%edi
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    $0x1,%edi
  jne    L6
  add    $0x2,%eax
  cmp    %r12d,%eax
  jle    L28
  mov    %ebp,%r13d
  mov    %eax,%r12d
L28:
  add    $0x1,%ebp
  cmp    $0xf4240,%ebp
  jne    L14
  mov    %r13d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  int last = 1000000;
  int max = 0;
  int maxi = 0;
  int i;
  for (i = (last >> 1); i < last; ++i) {
    int counter = 0;
    uint64_t j = i;
    while (j != 1) {
      j = next_term(j);
      counter++;
    }
    counter++;
    if (counter > max) {
      max = counter;
      maxi = i;
    }
  }
  printf("%d\n", maxi);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L3
  mov    $0x1,%eax
  jmp    L0
L3:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  mov    -0x14(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L0:
  leave
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  if (n == 1) {
    return 1;
  }
  r = n * factorial(n - 1);
  return (r);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L6
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
L6:
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  if (n == 1) {
    return 1;
  }
  r = n * factorial(n - 1);
  return (r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L1
  xchg   %ax,%ax
L11:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L11
L1:
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  if (n == 1) {
    return 1;
  }
  r = n * factorial(n - 1);
  return (r);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L11
  xchg   %ax,%ax
L13:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L13
L11:
  ret
```

assistant: ```c
int factorial(int n) {
  int r;
  if (n == 1) {
    return 1;
  }
  r = n * factorial(n - 1);
  return (r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen_stride_mmul_1x2_2x2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  mov    -0x20(%rbp),%r9d
  mov    -0x1c(%rbp),%r8d
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x20(%rbp),%edi
  push   %rdi
  mov    0x18(%rbp),%edi
  push   %rdi
  push   0x10(%rbp)
  mov    %rax,%rdi
  call   <gen_stride_mmul_1x2_2x1@plt>
  add    $0x20,%rsp
  mov    0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%r8
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%r9d
  mov    -0x1c(%rbp),%r10d
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x20(%rbp),%edi
  push   %rdi
  mov    0x18(%rbp),%edi
  push   %rdi
  push   %r8
  mov    %r10d,%r8d
  mov    %rax,%rdi
  call   <gen_stride_mmul_1x2_2x1@plt>
  add    $0x20,%rsp
  nop
  leave
  ret
```

assistant: ```c
void gen_stride_mmul_1x2_2x2(const double *a, int a_row_stride, int a_col_stride, const double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (0) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (0) * c_col_stride], c_row_stride, c_col_stride);
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (1) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (1) * c_col_stride], c_row_stride, c_col_stride);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gen_stride_mmul_1x2_2x2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %rcx,%r15
  mov    %r8d,%r14d
  mov    %r9d,%ebx
  mov    0x68(%rsp),%ebp
  push   %rbp
  mov    0x68(%rsp),%eax
  push   %rax
  push   0x68(%rsp)
  mov    %rdi,0x28(%rsp)
  call   <gen_stride_mmul_1x2_2x1@plt>
  add    $0x18,%rsp
  movslq %ebx,%rax
  lea    (%r15,%rax,8),%rcx
  push   %rbp
  mov    0x68(%rsp),%eax
  push   %rax
  movslq %ebp,%rbp
  mov    0x68(%rsp),%rax
  lea    (%rax,%rbp,8),%rax
  push   %rax
  mov    %ebx,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    0x28(%rsp),%rdi
  call   <gen_stride_mmul_1x2_2x1@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void gen_stride_mmul_1x2_2x2(const double *a, int a_row_stride, int a_col_stride, const double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (0) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (0) * c_col_stride], c_row_stride, c_col_stride);
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (1) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (1) * c_col_stride], c_row_stride, c_col_stride);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gen_stride_mmul_1x2_2x2>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x30,%rsp
  movslq 0x78(%rsp),%rbp
  mov    0x70(%rsp),%r11d
  mov    0x68(%rsp),%r10
  push   %rbp
  push   %r11
  mov    %r11d,0x34(%rsp)
  push   %r10
  mov    %r10,0x30(%rsp)
  mov    %rcx,0x28(%rsp)
  call   <gen_stride_mmul_1x2_2x1@plt>
  mov    0x28(%rsp),%rcx
  movslq %ebx,%rax
  mov    %ebx,%r9d
  mov    0x30(%rsp),%r10
  mov    0x3c(%rsp),%r11d
  mov    %r15d,%r8d
  mov    %r14d,%edx
  lea    (%rcx,%rax,8),%rcx
  mov    %ebp,0x90(%rsp)
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    (%r10,%rbp,8),%rax
  mov    %r11d,0x88(%rsp)
  mov    %rax,0x80(%rsp)
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <gen_stride_mmul_1x2_2x1@plt>
```

assistant: ```c
void gen_stride_mmul_1x2_2x2(const double *a, int a_row_stride, int a_col_stride, const double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (0) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (0) * c_col_stride], c_row_stride, c_col_stride);
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (1) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (1) * c_col_stride], c_row_stride, c_col_stride);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gen_stride_mmul_1x2_2x2>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x30,%rsp
  movslq 0x78(%rsp),%rbp
  mov    0x70(%rsp),%r11d
  mov    0x68(%rsp),%r10
  push   %rbp
  push   %r11
  mov    %r11d,0x34(%rsp)
  push   %r10
  mov    %r10,0x30(%rsp)
  mov    %rcx,0x28(%rsp)
  call   <gen_stride_mmul_1x2_2x1@plt>
  mov    0x28(%rsp),%rcx
  movslq %ebx,%rax
  mov    %ebx,%r9d
  mov    0x30(%rsp),%r10
  mov    0x3c(%rsp),%r11d
  mov    %r15d,%r8d
  mov    %r14d,%edx
  lea    (%rcx,%rax,8),%rcx
  mov    %ebp,0x90(%rsp)
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    (%r10,%rbp,8),%rax
  mov    %r11d,0x88(%rsp)
  mov    %rax,0x80(%rsp)
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <gen_stride_mmul_1x2_2x1@plt>
```

assistant: ```c
void gen_stride_mmul_1x2_2x2(const double *a, int a_row_stride, int a_col_stride, const double *b, int b_row_stride, int b_col_stride, double *c, int c_row_stride, int c_col_stride) {
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (0) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (0) * c_col_stride], c_row_stride, c_col_stride);
  gen_stride_mmul_1x2_2x1(&a[(0) * a_row_stride + (0) * a_col_stride], a_row_stride, a_col_stride, &b[(0) * b_row_stride + (1) * b_col_stride], b_row_stride, b_col_stride, &c[(0) * c_row_stride + (1) * c_col_stride], c_row_stride, c_col_stride);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x17447d68,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L34
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L24
  mov    -0x10(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L5
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x5,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x5,%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L41
L5:
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  and    $0x1f0,%eax
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L41
L24:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L41
L34:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
L41:
  mov    -0x10(%rbp),%rax
  lea    0x2a28b8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        if (state[0UL] & 1UL) {
          copy11 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy11;
          copy11 = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy11;
        } else {
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 2762936UL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rsi
  lea    -0x17447d68(%rsi),%rdx
  lea    (%rdx,%rdx,1),%rax
  test   $0x8,%sil
  jne    L1
  test   $0x1,%dl
  je     L1
  mov    %rdx,%rsi
  shl    $0x10,%rsi
  shr    $0x38,%rsi
  shl    $0x30,%rsi
  movabs $0xff00ffffffffffff,%rax
  and    %rdx,%rax
  or     %rsi,%rax
  mov    %edx,%esi
  shl    $0x8,%esi
  sar    $0x18,%esi
  movzbl %sil,%esi
  shl    $0x28,%rsi
  movabs $0xffff00ffffffffff,%rdi
  and    %rdi,%rax
  or     %rsi,%rax
  shr    $0x20,%rdx
  and    $0xff0000,%edx
  and    $0xffffffffff00ffff,%rax
  or     %rdx,%rax
L1:
  add    $0x2a28b8,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        if (state[0UL] & 1UL) {
          copy11 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy11;
          copy11 = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy11;
        } else {
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 2762936UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rcx
  sub    $0x17447d68,%rax
  lea    (%rax,%rax,1),%rdx
  test   $0x8,%al
  je     L14
  test   $0x1,%al
  je     L14
  movabs $0xff00ffffffffffff,%rdx
  mov    %rax,%rsi
  movabs $0xffff00ffffffffff,%rdi
  shl    $0x10,%rsi
  and    %rax,%rdx
  shr    $0x38,%rsi
  shl    $0x30,%rsi
  or     %rsi,%rdx
  mov    %rax,%rsi
  shr    $0x20,%rax
  shr    $0x10,%rsi
  and    %rdi,%rdx
  and    $0xff0000,%eax
  and    $0xff,%esi
  shl    $0x28,%rsi
  or     %rsi,%rdx
  and    $0xffffffffff00ffff,%rdx
  or     %rax,%rdx
L14:
  add    $0x2a28b8,%rdx
  mov    %rdx,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        if (state[0UL] & 1UL) {
          copy11 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy11;
          copy11 = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy11;
        } else {
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 2762936UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rcx
  sub    $0x17447d68,%rax
  lea    (%rax,%rax,1),%rdx
  test   $0x8,%al
  je     L19
  test   $0x1,%al
  je     L19
  movabs $0xff00ffffffffffff,%rdx
  mov    %rax,%rsi
  movabs $0xffff00ffffffffff,%rdi
  shl    $0x10,%rsi
  and    %rax,%rdx
  shr    $0x38,%rsi
  shl    $0x30,%rsi
  or     %rsi,%rdx
  mov    %rax,%rsi
  shr    $0x20,%rax
  shr    $0x10,%rsi
  and    %rdi,%rdx
  and    $0xff0000,%eax
  and    $0xff,%esi
  shl    $0x28,%rsi
  or     %rsi,%rdx
  and    $0xffffffffff00ffff,%rdx
  or     %rax,%rdx
L19:
  add    $0x2a28b8,%rdx
  mov    %rdx,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if (state[0UL] & 1UL) {
        if (state[0UL] & 1UL) {
          copy11 = *((char *)(&state[0UL]) + 6);
          *((char *)(&state[0UL]) + 6) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy11;
          copy11 = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = copy11;
        } else {
          state[0UL] |= (state[0UL] & 31UL) << 4UL;
        }
      } else {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 2762936UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1c0(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b0(%rbp)
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x1a8(%rbp)
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  lea    -0x1a0(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1b8(%rbp),%rax
  movl   $0x11,(%rax)
  mov    -0x1b8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1b0(%rbp),%rax
  movl   $0x11,(%rax)
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free(array2);
  free(free_twice);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%r14
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r14,%rdi
  call   <read_element@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  movl   $0x11,0x0(%rbp)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free(array2);
  free(free_twice);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free(array2);
  free(free_twice);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free(never_free);
  free(array2);
  free(free_twice);
  return 0;
}
```