user: 请从给定的汇编指令推导出C源代码:

```asm
<read_obs_seq_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %rdx,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x404(%rbp)
  movl   $0x0,-0x400(%rbp)
  jmp    L17
L8:
  movzbl -0x3f0(%rbp),%eax
  cmp    $0x3e,%al
  je     L17
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x3fc(%rbp)
  jmp    L20
L46:
  subl   $0x1,-0x3fc(%rbp)
L20:
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L46
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0xd,%al
  je     L46
  mov    -0x3fc(%rbp),%eax
  add    %eax,-0x404(%rbp)
L17:
  mov    -0x418(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x420(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x420(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x428(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x428(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x3f8(%rbp)
  mov    -0x404(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x404(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x3f8(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L129
L108:
  movzbl -0x3f0(%rbp),%eax
  cmp    $0x3e,%al
  je     L129
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x3fc(%rbp)
  jmp    L38
L94:
  subl   $0x1,-0x3fc(%rbp)
L38:
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L94
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x3f0(%rbp,%rax,1),%eax
  cmp    $0xd,%al
  je     L94
  mov    -0x3f8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x400(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x3fc(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x3fc(%rbp),%eax
  add    %eax,-0x400(%rbp)
L129:
  mov    -0x418(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L108
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void read_obs_seq_from_file(FILE *fp, int *num_seqs_ptr, char ***obs_seqs_ptr) {
  int i = 0;
  int j = 0;
  int bp_count;
  char mystring[1000];
  while (fgets(mystring, sizeof mystring, fp)) {
    if (mystring[0] == '>') {
    } else {
      bp_count = strlen(mystring) - 1;
      while (mystring[bp_count - 1] == 10 || mystring[bp_count - 1] == 13) {
        bp_count--;
      }
      i += bp_count;
    }
  }
  rewind(fp);
  *num_seqs_ptr = 1;
  *obs_seqs_ptr = (char **)malloc(*num_seqs_ptr * sizeof(char *));
  char **obs_seqs = *obs_seqs_ptr;
  obs_seqs[0] = (char *)malloc(i * sizeof(char) + 1);
  memset(obs_seqs[0], 0, i * sizeof(char) + 1);
  while (fgets(mystring, sizeof mystring, fp)) {
    if (mystring[0] == '>') {
    } else {
      bp_count = strlen(mystring) - 1;
      while (mystring[bp_count - 1] == 10 || mystring[bp_count - 1] == 13) {
        bp_count--;
      }
      memcpy(obs_seqs[0] + j, mystring, bp_count);
      j += bp_count;
    }
  }
}
```