ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<plugin_api_info_color_rgb2term_cb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbp
  test   %rcx,%rcx
  je     L3
  mov    $0x0,%ebx
  cmpb   $0x0,(%rcx)
  je     L28
  mov    $0x2c,%esi
  mov    %rcx,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L21
  mov    %eax,%esi
  sub    %ebp,%esi
  mov    %rbp,%rdi
  call   <string_strndup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  lea    0x1(%r12),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <free@plt>
L44:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <gui_color_convert_rgb_to_term@plt>
  mov    %eax,%ecx
  lea    D2(%rip),%rdx
  mov    $0x20,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
L28:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    $0x100,%r12d
  jmp    L44
L3:
  mov    %rcx,%rbx
  jmp    L28
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string

tool: D2: %d

assistant: ```c
const char *plugin_api_info_color_rgb2term_cb(const void *pointer, void *data, const char *info_name, const char *arguments) {
  static char value[32];
  int rgb, limit;
  char *pos, *color;
  (void)pointer;
  (void)data;
  (void)info_name;
  if (!arguments || !arguments[0])
    return NULL;
  limit = 256;
  pos = strchr(arguments, ',');
  if (pos) {
    color = string_strndup(arguments, pos - arguments);
    if (!color)
      return NULL;
    rgb = atoi(color);
    limit = atoi(pos + 1);
    free(color);
  } else {
    rgb = atoi(arguments);
  }
  snprintf(value, sizeof(value), "%d", gui_color_convert_rgb_to_term(rgb, limit));
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<plugin_api_info_color_rgb2term_cb>:
  endbr64
  test   %rcx,%rcx
  je     L39
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rcx)
  je     L29
  mov    $0x2c,%esi
  mov    %rcx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
  mov    %eax,%esi
  mov    %rbp,%rdi
  sub    %ebp,%esi
  call   <string_strndup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L29
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    0x1(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <free@plt>
L8:
  mov    %r13d,%esi
  mov    %r12d,%edi
  lea    D4(%rip),%rbx
  call   <gui_color_convert_rgb_to_term@plt>
  mov    %rbx,%rdi
  mov    $0x20,%esi
  lea    D6(%rip),%rdx
  mov    %eax,%ecx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L36:
  mov    %rbp,%rdi
  mov    $0x100,%r13d
  call   <atoi@plt>
  mov    %eax,%r12d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: %d

assistant: ```c
const char *plugin_api_info_color_rgb2term_cb(const void *pointer, void *data, const char *info_name, const char *arguments) {
  static char value[32];
  int rgb, limit;
  char *pos, *color;
  (void)pointer;
  (void)data;
  (void)info_name;
  if (!arguments || !arguments[0])
    return NULL;
  limit = 256;
  pos = strchr(arguments, ',');
  if (pos) {
    color = string_strndup(arguments, pos - arguments);
    if (!color)
      return NULL;
    rgb = atoi(color);
    limit = atoi(pos + 1);
    free(color);
  } else {
    rgb = atoi(arguments);
  }
  snprintf(value, sizeof(value), "%d", gui_color_convert_rgb_to_term(rgb, limit));
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<plugin_api_info_color_rgb2term_cb>:
  endbr64
  test   %rcx,%rcx
  je     L33
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rcx)
  je     L31
  mov    $0x2c,%esi
  mov    %rcx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  mov    %eax,%esi
  mov    %rbp,%rdi
  sub    %ebp,%esi
  call   <string_strndup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L31
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    0x1(%rbx),%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <free@plt>
L49:
  mov    %r13d,%esi
  mov    %r12d,%edi
  lea    D9(%rip),%rbx
  call   <gui_color_convert_rgb_to_term@plt>
  mov    %rbx,%rdi
  mov    $0x20,%esi
  lea    D4(%rip),%rdx
  mov    %eax,%ecx
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L31:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L27:
  mov    %rbp,%rdi
  mov    $0x100,%r13d
  call   <atoi@plt>
  mov    %eax,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: %d

assistant: ```c
const char *plugin_api_info_color_rgb2term_cb(const void *pointer, void *data, const char *info_name, const char *arguments) {
  static char value[32];
  int rgb, limit;
  char *pos, *color;
  (void)pointer;
  (void)data;
  (void)info_name;
  if (!arguments || !arguments[0])
    return NULL;
  limit = 256;
  pos = strchr(arguments, ',');
  if (pos) {
    color = string_strndup(arguments, pos - arguments);
    if (!color)
      return NULL;
    rgb = atoi(color);
    limit = atoi(pos + 1);
    free(color);
  } else {
    rgb = atoi(arguments);
  }
  snprintf(value, sizeof(value), "%d", gui_color_convert_rgb_to_term(rgb, limit));
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  __VERIFIER_assert(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __VERIFIER_assert(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __VERIFIER_assert(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  __VERIFIER_assert(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<textureResample>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %r8,%r8
  sete   %al
  test   %rdi,%rdi
  sete   %sil
  or     %sil,%al
  jne    L38
  mov    %rdi,%r12
  mov    %r8,%rbx
  mov    %r9d,%r14d
  cmp    $0x20,%rcx
  jne    L38
  lea    -0x18(%r8),%rax
  mov    $0x0,%r13d
  test   $0xfffffffffffffff7,%rax
  jne    L56
  imul   %rdx,%rbp
  lea    0x7(%r8),%r15
  test   %r8,%r8
  cmovns %r8,%r15
  sar    $0x3,%r15
  imul   %rbp,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x18,%rbx
  sete   %al
  test   %r14d,%r14d
  jne    L54
  test   %al,%al
  jne    L85
L54:
  test   %r14d,%r14d
  setne  %dl
  test   %al,%al
  je     L43
  test   %dl,%dl
  jne    L60
L43:
  cmp    $0x20,%rbx
  jne    L113
  test   %dl,%dl
  je     L113
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <textureInvertRBInPlace@plt>
  jmp    L56
L85:
  lea    0x0(,%rbp,4),%rcx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <textureRemoveAlphaChannel@plt>
  jmp    L56
L60:
  lea    0x0(,%rbp,4),%rcx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <textureInvertRBAndRemoveAlphaChannel@plt>
  jmp    L56
L113:
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%r13d
  jmp    L56
L38:
  mov    $0x0,%r13d
L56:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *textureResample(char *srcBuf, long width, long height, long inBitsPerPixel, long outBitsPerPixel, int bgrOutput) {
  char *resampledData = NULL;
  long inBytesPerPixel, outBytesPerPixel;
  if (outBitsPerPixel == 0 || srcBuf == NULL)
    return NULL;
  if (inBitsPerPixel != 32)
    return NULL;
  if (outBitsPerPixel != 32 && outBitsPerPixel != 24)
    return NULL;
  inBytesPerPixel = inBitsPerPixel / 8;
  outBytesPerPixel = outBitsPerPixel / 8;
  resampledData = (char *)malloc(width * height * outBytesPerPixel);
  if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && !bgrOutput) {
    textureRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && bgrOutput) {
    textureInvertRBAndRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 32 && bgrOutput) {
    memcpy(resampledData, srcBuf, width * height * outBytesPerPixel);
    textureInvertRBInPlace(resampledData, width * height * outBytesPerPixel);
  } else {
    free(resampledData);
    resampledData = NULL;
  }
  return resampledData;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<textureResample>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r8,%r8
  sete   %dl
  test   %rdi,%rdi
  sete   %dil
  or     %dil,%dl
  jne    L21
  cmp    $0x20,%rcx
  jne    L21
  lea    -0x18(%r8),%rdx
  mov    %r8,%rbx
  xor    %r12d,%r12d
  test   $0xfffffffffffffff7,%rdx
  jne    L73
  imul   %rax,%rsi
  mov    %r8,%r15
  mov    %r9d,%r14d
  sar    $0x3,%r15
  imul   %rsi,%r15
  mov    %rsi,%r13
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    $0x18,%rbx
  je     L53
  cmp    $0x20,%rbx
  jne    L19
  test   %r14d,%r14d
  je     L19
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %r15,%rdx
  call   <memcpy@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <textureInvertRBInPlace@plt>
L73:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L21:
  xor    %r12d,%r12d
  jmp    L73
  nopl   (%rax)
L53:
  lea    0x0(,%r13,4),%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  test   %r14d,%r14d
  je     L88
  call   <textureInvertRBAndRemoveAlphaChannel@plt>
  jmp    L73
  nopl   (%rax)
L88:
  call   <textureRemoveAlphaChannel@plt>
  jmp    L73
  nop
L19:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L73
```

assistant: ```c
char *textureResample(char *srcBuf, long width, long height, long inBitsPerPixel, long outBitsPerPixel, int bgrOutput) {
  char *resampledData = NULL;
  long inBytesPerPixel, outBytesPerPixel;
  if (outBitsPerPixel == 0 || srcBuf == NULL)
    return NULL;
  if (inBitsPerPixel != 32)
    return NULL;
  if (outBitsPerPixel != 32 && outBitsPerPixel != 24)
    return NULL;
  inBytesPerPixel = inBitsPerPixel / 8;
  outBytesPerPixel = outBitsPerPixel / 8;
  resampledData = (char *)malloc(width * height * outBytesPerPixel);
  if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && !bgrOutput) {
    textureRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && bgrOutput) {
    textureInvertRBAndRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 32 && bgrOutput) {
    memcpy(resampledData, srcBuf, width * height * outBytesPerPixel);
    textureInvertRBInPlace(resampledData, width * height * outBytesPerPixel);
  } else {
    free(resampledData);
    resampledData = NULL;
  }
  return resampledData;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<textureResample>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r8,%r8
  sete   %dl
  test   %rdi,%rdi
  sete   %dil
  or     %dil,%dl
  jne    L2
  cmp    $0x20,%rcx
  jne    L2
  lea    -0x18(%r8),%rdx
  mov    %r8,%rbx
  xor    %r12d,%r12d
  test   $0xfffffffffffffff7,%rdx
  jne    L35
  imul   %rax,%rsi
  mov    %r8,%r15
  mov    %r9d,%r14d
  sar    $0x3,%r15
  imul   %rsi,%r15
  mov    %rsi,%r13
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    $0x18,%rbx
  je     L6
  cmp    $0x20,%rbx
  jne    L54
  test   %r14d,%r14d
  je     L54
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %r15,%rdx
  call   <memcpy@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <textureInvertRBInPlace@plt>
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L2:
  xor    %r12d,%r12d
  jmp    L35
  nopl   (%rax)
L6:
  lea    0x0(,%r13,4),%rcx
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %rax,%rdi
  test   %r14d,%r14d
  je     L17
  call   <textureInvertRBAndRemoveAlphaChannel@plt>
  jmp    L35
  nopl   (%rax)
L17:
  call   <textureRemoveAlphaChannel@plt>
  jmp    L35
  nop
L54:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L35
```

assistant: ```c
char *textureResample(char *srcBuf, long width, long height, long inBitsPerPixel, long outBitsPerPixel, int bgrOutput) {
  char *resampledData = NULL;
  long inBytesPerPixel, outBytesPerPixel;
  if (outBitsPerPixel == 0 || srcBuf == NULL)
    return NULL;
  if (inBitsPerPixel != 32)
    return NULL;
  if (outBitsPerPixel != 32 && outBitsPerPixel != 24)
    return NULL;
  inBytesPerPixel = inBitsPerPixel / 8;
  outBytesPerPixel = outBitsPerPixel / 8;
  resampledData = (char *)malloc(width * height * outBytesPerPixel);
  if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && !bgrOutput) {
    textureRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 24 && bgrOutput) {
    textureInvertRBAndRemoveAlphaChannel(resampledData, width * height * outBytesPerPixel, srcBuf, width * height * inBytesPerPixel);
  } else if (inBitsPerPixel == 32 && outBitsPerPixel == 32 && bgrOutput) {
    memcpy(resampledData, srcBuf, width * height * outBytesPerPixel);
    textureInvertRBInPlace(resampledData, width * height * outBytesPerPixel);
  } else {
    free(resampledData);
    resampledData = NULL;
  }
  return resampledData;
}
```
user: What is the c source code of the assembly code below?

```asm
<maze_cost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x4c(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <maze_width@plt>
  mov    %eax,%ecx
  mov    -0x48(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x44(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <maze_width@plt>
  mov    %eax,%esi
  mov    -0x48(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <maze_width@plt>
  mov    %eax,%ecx
  mov    -0x4c(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x3c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <maze_width@plt>
  mov    %eax,%ebx
  mov    -0x4c(%rbp),%eax
  cltd
  idiv   %ebx
  mov    %eax,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x44(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x3c(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x40(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x38(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%eax
  movd   %eax,%xmm0
  call   <abs@plt>
  add    %rbx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  -0x2c(%rbp),%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float maze_cost(void *context, void *first, void *second) {
  char *maze = context;
  char *f = first;
  char *s = second;
  int sx, sy, fx, fy;
  float d, dx, dy;
  int fp = f - maze;
  int sp = s - maze;
  sx = sp % maze_width(maze);
  sy = sp / maze_width(maze);
  fx = fp % maze_width(maze);
  fy = fp / maze_width(maze);
  dx = (float)sx - fx;
  dy = (float)sy - fy;
  d = (float)(abs(dx) + abs(dy));
  return d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maze_cost>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  sub    %edi,%ebx
  mov    %edx,%ebp
  sub    %edi,%ebp
  call   <maze_width@plt>
  mov    %eax,%esi
  mov    %ebp,%eax
  cltd
  idiv   %esi
  mov    %edx,%r13d
  mov    %r12,%rdi
  call   <maze_width@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <maze_width@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%r14d
  mov    %r12,%rdi
  call   <maze_width@plt>
  mov    %eax,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  subss  %xmm0,%xmm1
  movd   %xmm1,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r14d,%xmm1
  subss  %xmm1,%xmm0
  call   <abs@plt>
  mov    %rax,%rbx
  movd   %ebp,%xmm0
  call   <abs@plt>
  add    %rax,%rbx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
float maze_cost(void *context, void *first, void *second) {
  char *maze = context;
  char *f = first;
  char *s = second;
  int sx, sy, fx, fy;
  float d, dx, dy;
  int fp = f - maze;
  int sp = s - maze;
  sx = sp % maze_width(maze);
  sy = sp / maze_width(maze);
  fx = fp % maze_width(maze);
  fy = fp / maze_width(maze);
  dx = (float)sx - fx;
  dy = (float)sy - fy;
  d = (float)(abs(dx) + abs(dy));
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<maze_cost>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    %edi,%r12d
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    %edi,%ebx
  sub    $0x10,%rsp
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r13d
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r14d
  call   <maze_width@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %eax,%r8d
  cvtsi2ss %r12d,%xmm1
  mov    %ebx,%eax
  cltd
  cvtsi2ss %r14d,%xmm2
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  subss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  movss  %xmm1,0xc(%rsp)
  subss  %xmm2,%xmm0
  call   <abs@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rax,%rbx
  movaps %xmm1,%xmm0
  call   <abs@plt>
  add    $0x10,%rsp
  pxor   %xmm0,%xmm0
  add    %rax,%rbx
  cvtsi2ss %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
float maze_cost(void *context, void *first, void *second) {
  char *maze = context;
  char *f = first;
  char *s = second;
  int sx, sy, fx, fy;
  float d, dx, dy;
  int fp = f - maze;
  int sp = s - maze;
  sx = sp % maze_width(maze);
  sy = sp / maze_width(maze);
  fx = fp % maze_width(maze);
  fy = fp / maze_width(maze);
  dx = (float)sx - fx;
  dy = (float)sy - fy;
  d = (float)(abs(dx) + abs(dy));
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maze_cost>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  sub    %edi,%r12d
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    %edi,%ebx
  sub    $0x10,%rsp
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r13d
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  call   <maze_width@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r14d
  call   <maze_width@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %eax,%r8d
  cvtsi2ss %r12d,%xmm1
  mov    %ebx,%eax
  cltd
  cvtsi2ss %r14d,%xmm2
  idiv   %r8d
  cvtsi2ss %eax,%xmm0
  subss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r13d,%xmm0
  movss  %xmm1,0xc(%rsp)
  subss  %xmm2,%xmm0
  call   <abs@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rax,%rbx
  movaps %xmm1,%xmm0
  call   <abs@plt>
  add    $0x10,%rsp
  pxor   %xmm0,%xmm0
  add    %rax,%rbx
  cvtsi2ss %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
float maze_cost(void *context, void *first, void *second) {
  char *maze = context;
  char *f = first;
  char *s = second;
  int sx, sy, fx, fy;
  float d, dx, dy;
  int fp = f - maze;
  int sp = s - maze;
  sx = sp % maze_width(maze);
  sy = sp / maze_width(maze);
  fx = fp % maze_width(maze);
  fy = fp / maze_width(maze);
  dx = (float)sx - fx;
  dy = (float)sy - fy;
  d = (float)(abs(dx) + abs(dy));
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <ok@plt>
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: sizeof operator

assistant: ```c
int main() {
  init("sizeof operator");
  test();
  return ok();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <init@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <ok@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: sizeof operator

assistant: ```c
int main() {
  init("sizeof operator");
  test();
  return ok();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ok@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: sizeof operator

assistant: ```c
int main() {
  init("sizeof operator");
  test();
  return ok();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <init@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <ok@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string

tool: D3: sizeof operator

assistant: ```c
int main() {
  init("sizeof operator");
  test();
  return ok();
}
```