ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<get_precision>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L0
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%r14
  xor    %r13d,%r13d
  lea    0x10(%rsi,%rax,8),%rbp
L26:
  mov    (%r14),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  mov    %eax,%r12d
  call   <strchr@plt>
  test   %rax,%rax
  je     L39
  mov    %r12d,%edx
  sub    $0x1,%r12d
  sub    %rbx,%rax
  movslq %r12d,%r12
  sub    %eax,%edx
  lea    (%rbx,%r12,1),%rax
  cmpb   $0x30,(%rax)
  jne    L13
  nopl   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%rax
  sub    $0x1,%edx
  cmpb   $0x30,(%rax)
  je     L4
L13:
  sub    $0x1,%edx
  cmp    %edx,%r13d
  cmovl  %edx,%r13d
L39:
  add    $0x8,%r14
  cmp    %rbp,%r14
  jne    L26
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_precision(int argc, char **argv) {
  int i, precision = 0;
  for (i = 1; i < argc; i++) {
    char *tmp = argv[i], *end = NULL;
    int len = strlen(tmp);
    end = strchr(tmp, '.');
    if (!end)
      continue;
    int j, curprec = len - (end - tmp);
    for (j = len - 1; tmp[j] == '0'; j--)
      curprec--;
    curprec--;
    if (curprec > precision)
      precision = curprec;
  }
  return precision;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<est_base64_contains_nl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x3f,-0x1c(%rbp)
  jg     L44
  mov    $0x0,%eax
  jmp    L25
L44:
  movl   $0x3f,-0x4(%rbp)
  jmp    L26
L56:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L51
  mov    $0x1,%eax
  jmp    L25
L51:
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L56
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int est_base64_contains_nl(const char *src, int len) {
  int i;
  if (len < 64) {
    return 0;
  }
  for (i = 63; i < len - 1; i++) {
    if (src[i] == 0xA) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<est_base64_contains_nl>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x40,%esi
  jle    L20
  lea    0x3f(%rdi),%rax
  lea    -0x41(%rsi),%edx
  lea    0x40(%rdi,%rdx,1),%rdx
L28:
  cmpb   $0xa,(%rax)
  je     L12
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L28
  mov    $0x0,%eax
  ret
L12:
  mov    $0x1,%eax
L20:
  ret
```

assistant: ```c
int est_base64_contains_nl(const char *src, int len) {
  int i;
  if (len < 64) {
    return 0;
  }
  for (i = 63; i < len - 1; i++) {
    if (src[i] == 0xA) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<est_base64_contains_nl>:
  endbr64
  xor    %eax,%eax
  cmp    $0x40,%esi
  jle    L32
  lea    -0x41(%rsi),%edx
  lea    0x3f(%rdi),%rax
  lea    0x40(%rdi,%rdx,1),%rdx
  jmp    L10
  nopl   0x0(%rax)
L38:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L31
L10:
  cmpb   $0xa,(%rax)
  jne    L38
  mov    $0x1,%eax
L32:
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int est_base64_contains_nl(const char *src, int len) {
  int i;
  if (len < 64) {
    return 0;
  }
  for (i = 63; i < len - 1; i++) {
    if (src[i] == 0xA) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<est_base64_contains_nl>:
  endbr64
  xor    %eax,%eax
  cmp    $0x40,%esi
  jle    L16
  lea    -0x41(%rsi),%edx
  lea    0x3f(%rdi),%rax
  lea    0x40(%rdi,%rdx,1),%rdx
  jmp    L7
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L20
L7:
  cmpb   $0xa,(%rax)
  jne    L8
  mov    $0x1,%eax
L16:
  ret
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int est_base64_contains_nl(const char *src, int len) {
  int i;
  if (len < 64) {
    return 0;
  }
  for (i = 63; i < len - 1; i++) {
    if (src[i] == 0xA) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int *const *b;
  int **c;
  c = b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *const *b;
  int **c;
  c = b;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *const *b;
  int **c;
  c = b;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *const *b;
  int **c;
  c = b;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigdelset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int test(void) {
  sigset_t signal_set;
  int signal_number;
  int result;
  signal_number = SIGALRM;
  result = sigdelset(&signal_set, signal_number);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <sigdelset@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(void) {
  sigset_t signal_set;
  int signal_number;
  int result;
  signal_number = SIGALRM;
  result = sigdelset(&signal_set, signal_number);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%esi
  call   <sigdelset@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(void) {
  sigset_t signal_set;
  int signal_number;
  int result;
  signal_number = SIGALRM;
  result = sigdelset(&signal_set, signal_number);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%esi
  call   <sigdelset@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(void) {
  sigset_t signal_set;
  int signal_number;
  int result;
  signal_number = SIGALRM;
  result = sigdelset(&signal_set, signal_number);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readConfig_FetchValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L13
  jmp    L29
L38:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strStrip@plt>
  nop
  leave
  ret
```

assistant: ```c
void readConfig_FetchValue(char *line, char *out) {
  char *scan = out;
  while ((*line != '\0') && (*(line++) != '='))
    ;
  while (*line != '\0')
    *(scan++) = *(line++);
  *scan = '\0';
  strStrip(out, out);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readConfig_FetchValue>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
L37:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L48
  add    $0x1,%rax
  cmp    $0x3d,%dl
  jne    L37
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L47
  mov    %rdi,%rdx
L30:
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L30
L45:
  movb   $0x0,(%rdx)
  mov    %rdi,%rsi
  call   <strStrip@plt>
  add    $0x8,%rsp
  ret
L48:
  mov    %rdi,%rdx
  jmp    L45
L47:
  mov    %rdi,%rdx
  jmp    L45
```

assistant: ```c
void readConfig_FetchValue(char *line, char *out) {
  char *scan = out;
  while ((*line != '\0') && (*(line++) != '='))
    ;
  while (*line != '\0')
    *(scan++) = *(line++);
  *scan = '\0';
  strStrip(out, out);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readConfig_FetchValue>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  jmp    L46
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  cmp    $0x3d,%dl
  je     L1
L46:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L12
  mov    %rdi,%rdx
L49:
  movb   $0x0,(%rdx)
  mov    %rdi,%rsi
  jmp    1050 <strStrip@plt>
  xchg   %ax,%ax
L1:
  movzbl (%rax),%ecx
  mov    %rdi,%rdx
  test   %cl,%cl
  je     L49
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L6
  movb   $0x0,(%rdx)
  mov    %rdi,%rsi
  jmp    1050 <strStrip@plt>
```

assistant: ```c
void readConfig_FetchValue(char *line, char *out) {
  char *scan = out;
  while ((*line != '\0') && (*(line++) != '='))
    ;
  while (*line != '\0')
    *(scan++) = *(line++);
  *scan = '\0';
  strStrip(out, out);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readConfig_FetchValue>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  jmp    L28
  nopl   0x0(%rax)
L26:
  add    $0x1,%rax
  cmp    $0x3d,%dl
  je     L16
L28:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L26
  mov    %rdi,%rdx
L43:
  movb   $0x0,(%rdx)
  mov    %rdi,%rsi
  jmp    1050 <strStrip@plt>
  xchg   %ax,%ax
L16:
  movzbl (%rax),%ecx
  mov    %rdi,%rdx
  test   %cl,%cl
  je     L43
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rax
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl (%rax),%ecx
  test   %cl,%cl
  jne    L35
  movb   $0x0,(%rdx)
  mov    %rdi,%rsi
  jmp    1050 <strStrip@plt>
```

assistant: ```c
void readConfig_FetchValue(char *line, char *out) {
  char *scan = out;
  while ((*line != '\0') && (*(line++) != '='))
    ;
  while (*line != '\0')
    *(scan++) = *(line++);
  *scan = '\0';
  strStrip(out, out);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strbcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L19
  cmpq   $0x0,-0x30(%rbp)
  je     L19
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  cmp    %ebx,-0x1c(%rbp)
  jg     L19
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x1c(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L25
L19:
  mov    $0x1,%eax
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strbcmp(const char *haystack, const char *needle) {
  int length;
  char *sub;
  if (haystack && needle && strlen(haystack) >= (length = strlen(needle)) && (sub = strstr(haystack, needle)) && strlen(sub) == length)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strbcmp>:
  endbr64
  test   %rdi,%rdi
  je     L37
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x1,%eax
  test   %rsi,%rsi
  jne    L49
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x1,%eax
  cmp    %r12d,%r13d
  jl     L47
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L47
  call   <strlen@plt>
  cmp    %r12d,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L47
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strbcmp(const char *haystack, const char *needle) {
  int length;
  char *sub;
  if (haystack && needle && strlen(haystack) >= (length = strlen(needle)) && (sub = strstr(haystack, needle)) && strlen(sub) == length)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strbcmp>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L40
L7:
  mov    $0x1,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r13d
  jl     L7
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  call   <strlen@plt>
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L16
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strbcmp(const char *haystack, const char *needle) {
  int length;
  char *sub;
  if (haystack && needle && strlen(haystack) >= (length = strlen(needle)) && (sub = strstr(haystack, needle)) && strlen(sub) == length)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strbcmp>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jne    L39
L31:
  mov    $0x1,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %eax,%r13d
  jl     L31
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L31
  call   <strlen@plt>
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L19
  nopl   0x0(%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strbcmp(const char *haystack, const char *needle) {
  int length;
  char *sub;
  if (haystack && needle && strlen(haystack) >= (length = strlen(needle)) && (sub = strstr(haystack, needle)) && strlen(sub) == length)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test2func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: This is a function in the second object


assistant: ```c
int test2func1(void) {
  printf("This is a function in the second object\n");
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test2func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: This is a function in the second object


assistant: ```c
int test2func1(void) {
  printf("This is a function in the second object\n");
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test2func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: This is a function in the second object


assistant: ```c
int test2func1(void) {
  printf("This is a function in the second object\n");
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<test2func1>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: This is a function in the second object


assistant: ```c
int test2func1(void) {
  printf("This is a function in the second object\n");
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jvc_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x802c8,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L19:
  mov    -0x4(%rbp),%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L33
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  jmp    L23
L33:
  mov    -0x4(%rbp),%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
L23:
  shrl   -0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0xf,-0x8(%rbp)
  jle    L19
  mov    -0x4(%rbp),%eax
  add    $0x1f4,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x23,%eax
  pop    %rbp
  ret
```

assistant: ```c
int jvc_encode(enum rc_proto proto, unsigned scancode, unsigned *buf) {
  const int jvc_unit = 525000;
  int i;
  scancode = ((scancode << 8) & 0xff00) | ((scancode >> 8) & 0x00ff);
  *buf++ = (((jvc_unit * 16) + 500) / 1000);
  *buf++ = (((jvc_unit * 8) + 500) / 1000);
  for (i = 0; i < 16; i++) {
    *buf++ = (((jvc_unit) + 500) / 1000);
    if (scancode & 1)
      *buf++ = (((jvc_unit * 3) + 500) / 1000);
    else
      *buf++ = (((jvc_unit) + 500) / 1000);
    scancode >>= 1;
  }
  *buf = (((jvc_unit) + 500) / 1000);
  return 35;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jvc_encode>:
  endbr64
  mov    %esi,%eax
  shl    $0x8,%esi
  movzwl %si,%esi
  movzbl %ah,%eax
  or     %eax,%esi
  movl   $0x20d0,(%rdx)
  movl   $0x1068,0x4(%rdx)
  lea    0x10(%rdx),%rcx
  lea    0x90(%rdx),%rdi
L6:
  movl   $0x20d,-0x8(%rcx)
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0xfffffbe6,%eax
  add    $0x627,%eax
  mov    %eax,-0x4(%rcx)
  shr    %esi
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  jne    L6
  movl   $0x20d,0x88(%rdx)
  mov    $0x23,%eax
  ret
```

assistant: ```c
int jvc_encode(enum rc_proto proto, unsigned scancode, unsigned *buf) {
  const int jvc_unit = 525000;
  int i;
  scancode = ((scancode << 8) & 0xff00) | ((scancode >> 8) & 0x00ff);
  *buf++ = (((jvc_unit * 16) + 500) / 1000);
  *buf++ = (((jvc_unit * 8) + 500) / 1000);
  for (i = 0; i < 16; i++) {
    *buf++ = (((jvc_unit) + 500) / 1000);
    if (scancode & 1)
      *buf++ = (((jvc_unit * 3) + 500) / 1000);
    else
      *buf++ = (((jvc_unit) + 500) / 1000);
    scancode >>= 1;
  }
  *buf = (((jvc_unit) + 500) / 1000);
  return 35;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jvc_encode>:
  endbr64
  mov    %esi,%eax
  shl    $0x8,%esi
  lea    0x8(%rdx),%rcx
  lea    0x88(%rdx),%rdi
  movzbl %ah,%eax
  movzwl %si,%esi
  or     %eax,%esi
  movabs $0x1068000020d0,%rax
  mov    %rax,(%rdx)
  nopl   0x0(%rax)
L8:
  mov    %esi,%eax
  movl   $0x20d,(%rcx)
  add    $0x8,%rcx
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %eax,%eax
  shr    %esi
  and    $0xfffffbe6,%eax
  add    $0x627,%eax
  mov    %eax,-0x4(%rcx)
  cmp    %rcx,%rdi
  jne    L8
  movl   $0x20d,0x88(%rdx)
  mov    $0x23,%eax
  ret
```

assistant: ```c
int jvc_encode(enum rc_proto proto, unsigned scancode, unsigned *buf) {
  const int jvc_unit = 525000;
  int i;
  scancode = ((scancode << 8) & 0xff00) | ((scancode >> 8) & 0x00ff);
  *buf++ = (((jvc_unit * 16) + 500) / 1000);
  *buf++ = (((jvc_unit * 8) + 500) / 1000);
  for (i = 0; i < 16; i++) {
    *buf++ = (((jvc_unit) + 500) / 1000);
    if (scancode & 1)
      *buf++ = (((jvc_unit * 3) + 500) / 1000);
    else
      *buf++ = (((jvc_unit) + 500) / 1000);
    scancode >>= 1;
  }
  *buf = (((jvc_unit) + 500) / 1000);
  return 35;
}
```
user: Translate the below assembly code into C programming language:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0xd,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void puts(unsigned char *cp) {
  while (*cp) {
    serial_console_putc(0, *cp);
    *cp++;
  }
  serial_console_putc(0, '\r');
  serial_console_putc(0, '\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L16
L0:
  movsbl %sil,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L16:
  mov    $0xd,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <serial_console_putc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void puts(unsigned char *cp) {
  while (*cp) {
    serial_console_putc(0, *cp);
    *cp++;
  }
  serial_console_putc(0, '\r');
  serial_console_putc(0, '\n');
}
```