ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<stuff2byteuint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzwl -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stuff2byteuint(unsigned short data, unsigned char *buffer, unsigned short *index) {
  buffer[*index] = (data >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (data >> 8) & 0xff;
  *index += 1;
  return (*index);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stuff2byteuint>:
  endbr64
  mov    %edi,%ecx
  movzwl (%rdx),%eax
  mov    %dil,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  movzbl %ch,%ecx
  mov    %cl,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  ret
```

assistant: ```c
int stuff2byteuint(unsigned short data, unsigned char *buffer, unsigned short *index) {
  buffer[*index] = (data >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (data >> 8) & 0xff;
  *index += 1;
  return (*index);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stuff2byteuint>:
  endbr64
  movzwl (%rdx),%eax
  mov    %edi,%ecx
  mov    %dil,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  mov    %ch,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  ret
```

assistant: ```c
int stuff2byteuint(unsigned short data, unsigned char *buffer, unsigned short *index) {
  buffer[*index] = (data >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (data >> 8) & 0xff;
  *index += 1;
  return (*index);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stuff2byteuint>:
  endbr64
  movzwl (%rdx),%eax
  mov    %edi,%ecx
  mov    %dil,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  mov    %ch,(%rsi,%rax,1)
  movzwl (%rdx),%eax
  add    $0x1,%eax
  mov    %ax,(%rdx)
  movzwl %ax,%eax
  ret
```

assistant: ```c
int stuff2byteuint(unsigned short data, unsigned char *buffer, unsigned short *index) {
  buffer[*index] = (data >> 0) & 0xff;
  *index += 1;
  buffer[*index] = (data >> 8) & 0xff;
  *index += 1;
  return (*index);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mystrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L9
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *buf;
  if (!(buf = (char *)malloc(strlen(s) + 1)))
    return NULL;
  strcpy(buf, s);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mystrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  mov    %rax,%rbp
  mov    %rbx,%rsi
  call   <strcpy@plt>
L9:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *buf;
  if (!(buf = (char *)malloc(strlen(s) + 1)))
    return NULL;
  strcpy(buf, s);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mystrdup>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *buf;
  if (!(buf = (char *)malloc(strlen(s) + 1)))
    return NULL;
  strcpy(buf, s);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mystrdup>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L2
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mystrdup(char *s) {
  char *buf;
  if (!(buf = (char *)malloc(strlen(s) + 1)))
    return NULL;
  strcpy(buf, s);
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_log_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8,-0x20(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L15:
  nop
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string

tool: D7: %s


assistant: ```c
void test_log_fn(int level, int dm_errno, const char *file, int line, const char *format) {
  if (level != 4)
    return;
  printf("%s\n", format);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_log_fn>:
  endbr64
  cmp    $0x4,%edi
  je     L3
  ret
L3:
  sub    $0x8,%rsp
  mov    %r8,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: %s


assistant: ```c
void test_log_fn(int level, int dm_errno, const char *file, int line, const char *format) {
  if (level != 4)
    return;
  printf("%s\n", format);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_log_fn>:
  endbr64
  cmp    $0x4,%edi
  je     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r8,%rsi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: %s


assistant: ```c
void test_log_fn(int level, int dm_errno, const char *file, int line, const char *format) {
  if (level != 4)
    return;
  printf("%s\n", format);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_log_fn>:
  endbr64
  cmp    $0x4,%edi
  je     L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r8,%rsi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: %s


assistant: ```c
void test_log_fn(int level, int dm_errno, const char *file, int line, const char *format) {
  if (level != 4)
    return;
  printf("%s\n", format);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<spi_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L35:
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L32:
  addl   $0x1,-0x10(%rbp)
L37:
  cmpl   $0x31f,-0x10(%rbp)
  jle    L32
L2:
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  sub    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  jg     L35
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  sub    %rdx,%rax
  leave
  ret
```

assistant: ```c
uint32_t spi_read(int fd, uint8_t *buffer, uint32_t size) {
  int status, i;
  uint8_t *ptr;
  ptr = buffer;
  while ((uint32_t)ptr - (uint32_t)buffer < size) {
    status = read(fd, ptr, 1);
    ptr++;
    for (i = 0; i < 800; i++)
      ;
  }
  return (uint32_t)ptr - (uint32_t)buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<spi_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rsi,%r13
  test   %rdx,%rdx
  jle    L28
L16:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  add    $0x4,%rbx
  mov    $0x320,%eax
L38:
  sub    $0x1,%eax
  jne    L38
  mov    %rbx,%rax
  sub    %r13,%rax
  cmp    %rbp,%rax
  jl     L16
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
uint32_t spi_read(int fd, uint8_t *buffer, uint32_t size) {
  int status, i;
  uint8_t *ptr;
  ptr = buffer;
  while ((uint32_t)ptr - (uint32_t)buffer < size) {
    status = read(fd, ptr, 1);
    ptr++;
    for (i = 0; i < 800; i++)
      ;
  }
  return (uint32_t)ptr - (uint32_t)buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<spi_read>:
  endbr64
  test   %rdx,%rdx
  jle    L17
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L18:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  add    $0x4,%rbx
  call   <read@plt>
  mov    %rbx,%rax
  sub    %r13,%rax
  cmp    %rbp,%rax
  jl     L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t spi_read(int fd, uint8_t *buffer, uint32_t size) {
  int status, i;
  uint8_t *ptr;
  ptr = buffer;
  while ((uint32_t)ptr - (uint32_t)buffer < size) {
    status = read(fd, ptr, 1);
    ptr++;
    for (i = 0; i < 800; i++)
      ;
  }
  return (uint32_t)ptr - (uint32_t)buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<spi_read>:
  endbr64
  test   %rdx,%rdx
  jle    L0
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nop
L19:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  add    $0x4,%rbx
  call   <read@plt>
  mov    %rbx,%rax
  sub    %r13,%rax
  cmp    %rbp,%rax
  jl     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint32_t spi_read(int fd, uint8_t *buffer, uint32_t size) {
  int status, i;
  uint8_t *ptr;
  ptr = buffer;
  while ((uint32_t)ptr - (uint32_t)buffer < size) {
    status = read(fd, ptr, 1);
    ptr++;
    for (i = 0; i < 800; i++)
      ;
  }
  return (uint32_t)ptr - (uint32_t)buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x4,-0x4(%rbp)
  jmp    L23
L0:
  mov    -0x4(%rbp),%eax
  sub    $0x4,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  add    $0x3,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: %.2f 

assistant: ```c
void printArray(double *a, int n) {
  for (int i = 4; i < (n * n) + 4; i++) {
    if ((i - 4) % n == 0)
      printf("\n");
    printf("%.2f ", a[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  imul   %esi,%r12d
  add    $0x3,%r12d
  cmp    $0x3,%r12d
  jle    L26
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x4,%ebx
  lea    D1(%rip),%r14
  jmp    L37
L41:
  movsd  0x0(%r13,%rbx,8),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L26
L37:
  lea    -0x4(%rbx),%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L41
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L41
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: %.2f 

assistant: ```c
void printArray(double *a, int n) {
  for (int i = 4; i < (n * n) + 4; i++) {
    if ((i - 4) % n == 0)
      printf("\n");
    printf("%.2f ", a[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printArray>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  test   %eax,%eax
  je     L39
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    0x3(%rax),%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x4,%ebx
  jmp    L0
  nopl   0x0(%rax)
L37:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jl     L33
L0:
  lea    -0x4(%rbx),%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L37
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L39:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4: %.2f 

assistant: ```c
void printArray(double *a, int n) {
  for (int i = 4; i < (n * n) + 4; i++) {
    if ((i - 4) % n == 0)
      printf("\n");
    printf("%.2f ", a[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printArray>:
  endbr64
  mov    %esi,%eax
  imul   %esi,%eax
  test   %eax,%eax
  je     L49
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    0x3(%rax),%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x4,%ebx
  jmp    L34
  nopl   0x0(%rax)
L25:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r13d
  jl     L21
L34:
  lea    -0x4(%rbx),%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L49:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: %.2f 

assistant: ```c
void printArray(double *a, int n) {
  for (int i = 4; i < (n * n) + 4; i++) {
    if ((i - 4) % n == 0)
      printf("\n");
    printf("%.2f ", a[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<maxNumberOfBalloons>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x88(%rbp)
  cmpl   $0x6,-0x88(%rbp)
  jg     L0
  mov    $0x0,%eax
  jmp    L83
L0:
  lea    -0x80(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x6f6c6162,-0xd(%rbp)
  movb   $0x6e,-0x9(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L32
L71:
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x80(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x80(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L32:
  mov    -0x94(%rbp),%eax
  cmp    -0x88(%rbp),%eax
  jl     L71
  mov    -0x54(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x54(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x48(%rbp)
  movl   $0x0,-0x90(%rbp)
  movl   $0x0,-0x8c(%rbp)
  jmp    L37
L66:
  mov    -0x8c(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  mov    %eax,-0x84(%rbp)
  cmpl   $0x0,-0x8c(%rbp)
  je     L80
  mov    -0x84(%rbp),%eax
  cmp    -0x90(%rbp),%eax
  jge    L48
L80:
  mov    -0x84(%rbp),%eax
  mov    %eax,-0x90(%rbp)
L48:
  addl   $0x1,-0x8c(%rbp)
L37:
  cmpl   $0x4,-0x8c(%rbp)
  jle    L66
  mov    -0x90(%rbp),%eax
L83:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L72
  call   <__stack_chk_fail@plt>
L72:
  leave
  ret
```

assistant: ```c
int maxNumberOfBalloons(char *text) {
  int len = strlen(text);
  if (len < 7) {
    return 0;
  }
  int counts[26] = {0};
  char alphabet[5] = {'b', 'a', 'l', 'o', 'n'};
  for (int i = 0; i < len; i++) {
    counts[text[i] - 'a']++;
  }
  counts['l' - 'a'] /= 2;
  counts['o' - 'a'] /= 2;
  int max = 0;
  for (int i = 0; i < 5; i++) {
    int c = counts[alphabet[i] - 'a'];
    if (i == 0 || c < max) {
      max = c;
    }
  }
  return max;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maxNumberOfBalloons>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    $0x0,%ecx
  cmp    $0x6,%eax
  jle    L59
  mov    %eax,%esi
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  movl   $0x6f6c6162,0x73(%rsp)
  movb   $0x6e,0x77(%rsp)
  mov    %rbx,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rbx,%rax,1),%rcx
L40:
  movsbl (%rdx),%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L40
  mov    0x2c(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,0x2c(%rsp)
  mov    0x38(%rsp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,0x38(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%ecx
  lea    0x73(%rsp),%rsi
  jmp    L49
L5:
  mov    %eax,%ecx
L7:
  add    $0x1,%rdx
  cmp    $0x5,%rdx
  je     L59
L49:
  movsbl (%rdx,%rsi,1),%eax
  sub    $0x61,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  test   %edx,%edx
  je     L5
  cmp    %ecx,%eax
  jge    L7
  jmp    L5
L59:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    %ecx,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxNumberOfBalloons(char *text) {
  int len = strlen(text);
  if (len < 7) {
    return 0;
  }
  int counts[26] = {0};
  char alphabet[5] = {'b', 'a', 'l', 'o', 'n'};
  for (int i = 0; i < len; i++) {
    counts[text[i] - 'a']++;
  }
  counts['l' - 'a'] /= 2;
  counts['o' - 'a'] /= 2;
  int max = 0;
  for (int i = 0; i < 5; i++) {
    int c = counts[alphabet[i] - 'a'];
    if (i == 0 || c < max) {
      max = c;
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxNumberOfBalloons>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x6,%eax
  jle    L45
  mov    %eax,%edx
  mov    %rsp,%rdi
  xor    %eax,%eax
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  movb   $0x6e,0x77(%rsp)
  lea    -0x1(%rdx),%eax
  mov    %rbx,%rdi
  movl   $0x6f6c6162,0x73(%rsp)
  lea    0x1(%rbx,%rax,1),%rdx
  nopl   0x0(%rax)
L40:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rdi
  jne    L40
  mov    0x2c(%rsp),%edx
  lea    0x78(%rsp),%rcx
  mov    0x4(%rsp),%r8d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    0x38(%rsp),%edx
  sar    %eax
  mov    %eax,0x2c(%rsp)
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  lea    0x73(%rsp),%rdx
  sar    %eax
  add    $0x1,%rdx
  mov    %eax,0x38(%rsp)
  cmp    %rdx,%rcx
  je     L45
L6:
  movsbl (%rdx),%eax
  sub    $0x61,%eax
  cltq
  mov    (%rsp,%rax,4),%eax
  cmp    %eax,%r8d
  cmovg  %eax,%r8d
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L6
L45:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  sub    $0xffffffffffffff80,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxNumberOfBalloons(char *text) {
  int len = strlen(text);
  if (len < 7) {
    return 0;
  }
  int counts[26] = {0};
  char alphabet[5] = {'b', 'a', 'l', 'o', 'n'};
  for (int i = 0; i < len; i++) {
    counts[text[i] - 'a']++;
  }
  counts['l' - 'a'] /= 2;
  counts['o' - 'a'] /= 2;
  int max = 0;
  for (int i = 0; i < 5; i++) {
    int c = counts[alphabet[i] - 'a'];
    if (i == 0 || c < max) {
      max = c;
    }
  }
  return max;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maxNumberOfBalloons>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x6,%edx
  jle    L6
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  lea    -0x1(%rdx),%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rdi
  jne    L11
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    0x2c(%rsp),%ecx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    0x34(%rsp),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  mov    0x38(%rsp),%ecx
  sar    %edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L6:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x70,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int maxNumberOfBalloons(char *text) {
  int len = strlen(text);
  if (len < 7) {
    return 0;
  }
  int counts[26] = {0};
  char alphabet[5] = {'b', 'a', 'l', 'o', 'n'};
  for (int i = 0; i < len; i++) {
    counts[text[i] - 'a']++;
  }
  counts['l' - 'a'] /= 2;
  counts['o' - 'a'] /= 2;
  int max = 0;
  for (int i = 0; i < 5; i++) {
    int c = counts[alphabet[i] - 'a'];
    if (i == 0 || c < max) {
      max = c;
    }
  }
  return max;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<weapon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <__BNF_trans_string@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <__BNF_trans_string@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L32
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <__BNF_trans_string@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L33
L7:
  nop
  jmp    L33
L32:
  nop
L33:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D3: axe

tool: D26: wand

tool: D28: rod

assistant: ```c
int weapon(void) {
  int state;
  do {
    state = __BNF_trans_string("axe");
    if (!state)
      break;
    state = __BNF_trans_string("wand");
    if (!state)
      break;
    state = __BNF_trans_string("rod");
  } while (0);
  return state;
}
```