ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<getexponent>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jae    L75
  xorpd  D9(%rip),%xmm0
L75:
  movsd  D25(%rip),%xmm3
  xor    %eax,%eax
  movsd  D16(%rip),%xmm1
  comisd %xmm0,%xmm3
  ja     L31
  jmp    L17
L33:
  sub    $0x1,%eax
  cmp    $0xffffff9d,%eax
  je     L17
  mulsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jbe    L17
L31:
  comisd %xmm2,%xmm0
  ja     L33
L17:
  comisd %xmm1,%xmm0
  jb     L6
  add    $0x1,%eax
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%eax
  cmp    $0x63,%eax
  je     L6
L44:
  divsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  jae    L50
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: f32[4]
name: disassemble_data
arguments: tag: D25
type_infered: f64
name: disassemble_data
arguments: tag: D16
type_infered: f64

tool: {"D9": [0.0,-0.0,0.0,0.0]}

tool: D25: 1

tool: D16: 10

assistant: ```c
int getexponent(double value) {
  double tmp = (value >= 0.0) ? value : -value;
  int exponent = 0;
  while (tmp < 1.0 && tmp > 0.0 && --exponent > -99)
    tmp *= 10;
  while (tmp >= 10.0 && ++exponent < 99)
    tmp /= 10;
  return exponent;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getexponent>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jae    L47
  xorpd  D0(%rip),%xmm0
L47:
  movsd  D2(%rip),%xmm3
  xor    %eax,%eax
  movsd  D7(%rip),%xmm1
  comisd %xmm0,%xmm3
  ja     L14
  jmp    L33
L96:
  sub    $0x1,%eax
  cmp    $0xffffff9d,%eax
  je     L33
  mulsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jbe    L33
L14:
  comisd %xmm2,%xmm0
  ja     L96
L33:
  comisd %xmm1,%xmm0
  jb     L97
  add    $0x1,%eax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L32:
  add    $0x1,%eax
  cmp    $0x63,%eax
  je     L97
L6:
  divsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  jae    L32
L97:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: f32[4]
name: retrieve_data
arguments: data_label: D2
data_type: f64
name: retrieve_data
arguments: data_label: D7
data_type: f64

tool: {"D0": [0.0,-0.0,0.0,0.0]}

tool: D2: 1

tool: D7: 10

assistant: ```c
int getexponent(double value) {
  double tmp = (value >= 0.0) ? value : -value;
  int exponent = 0;
  while (tmp < 1.0 && tmp > 0.0 && --exponent > -99)
    tmp *= 10;
  while (tmp >= 10.0 && ++exponent < 99)
    tmp /= 10;
  return exponent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__arch_copy_from_user>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long __arch_copy_from_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__arch_copy_from_user>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_from_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__arch_copy_from_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_from_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__arch_copy_from_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_from_user(void *x, void *y, unsigned long z) {
  unsigned long a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  ja     L24
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D101(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D101(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D47(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D78(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D97(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D57(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D116(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D86(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D39(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
  lea    D118(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L24:
  lea    D95(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L36:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D47
datatype: string
name: retrieve_data
arguments: data_tag: D78
datatype: string
name: retrieve_data
arguments: data_tag: D97
datatype: string
name: retrieve_data
arguments: data_tag: D57
datatype: string
name: retrieve_data
arguments: data_tag: D116
datatype: string
name: retrieve_data
arguments: data_tag: D86
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D118
datatype: string
name: retrieve_data
arguments: data_tag: D95
datatype: string
name: retrieve_data
arguments: data_tag: D68
datatype: string

tool: D3: STRAIGHT_FLUSH

tool: D47: FOUR_OF_A_KIND

tool: D78: FULL_HOUSE

tool: D97: FLUSH

tool: D57: STRAIGHT

tool: D116: THREE_OF_A_KIND

tool: D86: TWO_PAIR

tool: D39: ONE_PAIR

tool: D118: HIGH_CARD

tool: D95: NOT_FOUND

tool: D68: Rank: %s (%d)


assistant: ```c
void print_rank(int rank) {
  char *str;
  switch (rank) {
  case 1:
    str = "STRAIGHT_FLUSH";
    break;
  case 2:
    str = "FOUR_OF_A_KIND";
    break;
  case 3:
    str = "FULL_HOUSE";
    break;
  case 4:
    str = "FLUSH";
    break;
  case 5:
    str = "STRAIGHT";
    break;
  case 6:
    str = "THREE_OF_A_KIND";
    break;
  case 7:
    str = "TWO_PAIR";
    break;
  case 8:
    str = "ONE_PAIR";
    break;
  case 9:
    str = "HIGH_CARD";
    break;
  default:
    str = "NOT_FOUND";
    break;
  }
  printf("Rank: %s (%d)\n", str, rank);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_rank>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%edx
  cmp    $0x9,%edi
  ja     L49
  mov    %edi,%eax
  lea    D107(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  lea    D89(%rip),%rsi
L63:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
  lea    D56(%rip),%rsi
  jmp    L63
  lea    D68(%rip),%rsi
  jmp    L63
  lea    D36(%rip),%rsi
  jmp    L63
  lea    D109(%rip),%rsi
  jmp    L63
  lea    D75(%rip),%rsi
  jmp    L63
  lea    D44(%rip),%rsi
  jmp    L63
  lea    D99(%rip),%rsi
  jmp    L63
L49:
  lea    D1(%rip),%rsi
  jmp    L63
  lea    D51(%rip),%rsi
  jmp    L63
```

tool_calls: name: unpack_data
arguments: tag: D89
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D56
datatype: string
name: unpack_data
arguments: tag: D68
datatype: string
name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D109
datatype: string
name: unpack_data
arguments: tag: D75
datatype: string
name: unpack_data
arguments: tag: D44
datatype: string
name: unpack_data
arguments: tag: D99
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D51
datatype: string

tool: D89: FOUR_OF_A_KIND

tool: D26: Rank: %s (%d)


tool: D56: FULL_HOUSE

tool: D68: FLUSH

tool: D36: STRAIGHT

tool: D109: THREE_OF_A_KIND

tool: D75: TWO_PAIR

tool: D44: ONE_PAIR

tool: D99: HIGH_CARD

tool: D1: NOT_FOUND

tool: D51: STRAIGHT_FLUSH

assistant: ```c
void print_rank(int rank) {
  char *str;
  switch (rank) {
  case 1:
    str = "STRAIGHT_FLUSH";
    break;
  case 2:
    str = "FOUR_OF_A_KIND";
    break;
  case 3:
    str = "FULL_HOUSE";
    break;
  case 4:
    str = "FLUSH";
    break;
  case 5:
    str = "STRAIGHT";
    break;
  case 6:
    str = "THREE_OF_A_KIND";
    break;
  case 7:
    str = "TWO_PAIR";
    break;
  case 8:
    str = "ONE_PAIR";
    break;
  case 9:
    str = "HIGH_CARD";
    break;
  default:
    str = "NOT_FOUND";
    break;
  }
  printf("Rank: %s (%d)\n", str, rank);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xe8(%rbp)
  movl   $0x0,-0xe4(%rbp)
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xec(%rbp)
  jmp    L24
L53:
  mov    -0xec(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    -0xe8(%rbp,%rax,4),%edx
  mov    -0xec(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ecx
  mov    -0xec(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0xe8(%rbp,%rax,4)
  mov    -0xe8(%rbp),%eax
  cmp    $0xa,%eax
  jne    L55
  mov    -0xe4(%rbp),%eax
  cmp    $0xa,%eax
  jne    L55
  mov    -0xec(%rbp),%eax
  lea    0x2(%rax),%edx
  lea    -0xe0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <tenten@plt>
  jmp    L40
L55:
  mov    -0xe8(%rbp),%eax
  cmp    $0xa,%eax
  jle    L86
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L40
L86:
  mov    -0xe4(%rbp),%eax
  cmp    $0xa,%eax
  jle    L95
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L40
L95:
  addl   $0x2,-0xec(%rbp)
L24:
  mov    -0xec(%rbp),%eax
  cltq
  movzbl -0xe0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L53
L40:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D26
type: string

tool: D19: %s

tool: D28: A


tool: D26: B


assistant: ```c
int main() {
  int p[2] = {0, 0};
  char game[201];
  scanf("%s", game);
  for (int i = 0; game[i]; i += 2) {
    p[game[i] - 'A'] += (int)(game[i + 1] - '0');
    if (p[0] == 10 && p[1] == 10) {
      tenten(game, i + 2);
      break;
    }
    if (p[0] > 10) {
      printf("A\n");
      break;
    }
    if (p[1] > 10) {
      printf("B\n");
      break;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L31
  lea    0x12(%rsp),%rdx
  mov    $0x0,%edi
  jmp    L44
L65:
  cmpl   $0xa,0xc(%rsp)
  je     L58
L0:
  cmpl   $0xa,0xc(%rsp)
  jg     L79
  add    $0x2,%edi
  add    $0x2,%rdx
  movzbl -0x2(%rdx),%eax
  test   %al,%al
  je     L31
L44:
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  movsbl -0x1(%rdx),%esi
  mov    0x8(%rsp,%rax,4),%ecx
  lea    -0x30(%rsi,%rcx,1),%ecx
  mov    %ecx,0x8(%rsp,%rax,4)
  mov    0x8(%rsp),%eax
  cmp    $0xa,%eax
  je     L65
  jle    L0
  lea    D27(%rip),%rdi
  call   <printf@plt>
L31:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0xf8,%rsp
  ret
L58:
  lea    0x2(%rdi),%esi
  lea    0x10(%rsp),%rdi
  call   <tenten@plt>
  jmp    L31
L79:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D21: %s

tool: D27: A


tool: D3: B


assistant: ```c
int main() {
  int p[2] = {0, 0};
  char game[201];
  scanf("%s", game);
  for (int i = 0; game[i]; i += 2) {
    p[game[i] - 'A'] += (int)(game[i + 1] - '0');
    if (p[0] == 10 && p[1] == 10) {
      tenten(game, i + 2);
      break;
    }
    if (p[0] > 10) {
      printf("A\n");
      break;
    }
    if (p[1] > 10) {
      printf("B\n");
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%eax
  test   %al,%al
  je     L62
  lea    0x12(%rsp),%rdx
  xor    %edi,%edi
  jmp    L19
  xchg   %ax,%ax
L93:
  jg     L28
  mov    0xc(%rsp),%eax
L50:
  cmp    $0xa,%eax
  jg     L99
  movsbl (%rdx),%eax
  add    $0x2,%rdx
  add    $0x2,%edi
  test   %al,%al
  je     L62
L19:
  sub    $0x41,%eax
  movsbl -0x1(%rdx),%esi
  cltq
  mov    0x8(%rsp,%rax,4),%ecx
  lea    -0x30(%rsi,%rcx,1),%ecx
  mov    %ecx,0x8(%rsp,%rax,4)
  cmpl   $0xa,0x8(%rsp)
  jne    L93
  mov    0xc(%rsp),%eax
  cmp    $0xa,%eax
  jne    L50
  lea    0x2(%rdi),%esi
  mov    %rbp,%rdi
  call   <tenten@plt>
  nopl   0x0(%rax)
L62:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L28:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L99:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string

tool: D6: %s

tool: D15: A


tool: D21: B


assistant: ```c
int main() {
  int p[2] = {0, 0};
  char game[201];
  scanf("%s", game);
  for (int i = 0; game[i]; i += 2) {
    p[game[i] - 'A'] += (int)(game[i + 1] - '0');
    if (p[0] == 10 && p[1] == 10) {
      tenten(game, i + 2);
      break;
    }
    if (p[0] > 10) {
      printf("A\n");
      break;
    }
    if (p[1] > 10) {
      printf("B\n");
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%eax
  test   %al,%al
  je     L23
  lea    0x12(%rsp),%rdx
  xor    %edi,%edi
  jmp    L81
  xchg   %ax,%ax
L77:
  jg     L25
  mov    0xc(%rsp),%eax
L68:
  cmp    $0xa,%eax
  jg     L91
  movsbl (%rdx),%eax
  add    $0x2,%rdx
  add    $0x2,%edi
  test   %al,%al
  je     L23
L81:
  sub    $0x41,%eax
  movsbl -0x1(%rdx),%esi
  cltq
  mov    0x8(%rsp,%rax,4),%ecx
  lea    -0x30(%rsi,%rcx,1),%ecx
  mov    %ecx,0x8(%rsp,%rax,4)
  cmpl   $0xa,0x8(%rsp)
  jne    L77
  mov    0xc(%rsp),%eax
  cmp    $0xa,%eax
  jne    L68
  lea    0x2(%rdi),%esi
  mov    %rbp,%rdi
  call   <tenten@plt>
  nopl   0x0(%rax)
L23:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L25:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L91:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D2: %s

tool: D26: A


tool: D7: B


assistant: ```c
int main() {
  int p[2] = {0, 0};
  char game[201];
  scanf("%s", game);
  for (int i = 0; game[i]; i += 2) {
    p[game[i] - 'A'] += (int)(game[i + 1] - '0');
    if (p[0] == 10 && p[1] == 10) {
      tenten(game, i + 2);
      break;
    }
    if (p[0] > 10) {
      printf("A\n");
      break;
    }
    if (p[1] > 10) {
      printf("B\n");
      break;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<show_map_hint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <show_map_hint_chr@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <show_map_hint_obj@plt>
  nop
  leave
  ret
```

assistant: ```c
void show_map_hint(long x, long y) {
  show_map_hint_chr(x, y);
  show_map_hint_obj(x, y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<show_map_hint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <show_map_hint_chr@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <show_map_hint_obj@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void show_map_hint(long x, long y) {
  show_map_hint_chr(x, y);
  show_map_hint_obj(x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show_map_hint>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <show_map_hint_chr@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <show_map_hint_obj@plt>
```

assistant: ```c
void show_map_hint(long x, long y) {
  show_map_hint_chr(x, y);
  show_map_hint_obj(x, y);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<show_map_hint>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <show_map_hint_chr@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <show_map_hint_obj@plt>
```

assistant: ```c
void show_map_hint(long x, long y) {
  show_map_hint_chr(x, y);
  show_map_hint_obj(x, y);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BGBMID_Wave_GenerateHistogram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L34:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0xf,-0x8(%rbp)
  jle    L34
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <BGBMID_Wave_UpdateHistogram@plt>
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int BGBMID_Wave_GenerateHistogram(float *hist, short *sb, int sl) {
  float h, lh;
  int i, j, k;
  for (i = 0; i < 16; i++)
    hist[i] = 0;
  lh = 0;
  for (i = 0; i < sl; i++) {
    h = sb[i];
    BGBMID_Wave_UpdateHistogram(hist, h, lh);
    lh = h;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BGBMID_Wave_GenerateHistogram>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rax
  lea    0x40(%rdi),%rcx
L20:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L20
  test   %edx,%edx
  jle    L8
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x2(%rsi,%rax,2),%r12
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
L14:
  movss  0xc(%rsp),%xmm1
  movswl (%rbx),%eax
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mov    %rbp,%rdi
  call   <BGBMID_Wave_UpdateHistogram@plt>
  add    $0x2,%rbx
  cmp    %r12,%rbx
  jne    L14
L8:
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int BGBMID_Wave_GenerateHistogram(float *hist, short *sb, int sl) {
  float h, lh;
  int i, j, k;
  for (i = 0; i < 16; i++)
    hist[i] = 0;
  lh = 0;
  for (i = 0; i < sl; i++) {
    h = sb[i];
    BGBMID_Wave_UpdateHistogram(hist, h, lh);
    lh = h;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BGBMID_Wave_GenerateHistogram>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  test   %edx,%edx
  jle    L3
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    0x2(%rsi,%rax,2),%r12
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  nopl   (%rax)
L12:
  movswl (%rbx),%eax
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  add    $0x2,%rbx
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <BGBMID_Wave_UpdateHistogram@plt>
  cmp    %rbx,%r12
  movss  0xc(%rsp),%xmm0
  jne    L12
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int BGBMID_Wave_GenerateHistogram(float *hist, short *sb, int sl) {
  float h, lh;
  int i, j, k;
  for (i = 0; i < 16; i++)
    hist[i] = 0;
  lh = 0;
  for (i = 0; i < sl; i++) {
    h = sb[i];
    BGBMID_Wave_UpdateHistogram(hist, h, lh);
    lh = h;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BGBMID_Wave_GenerateHistogram>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  test   %edx,%edx
  jle    L19
  push   %r12
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    0x2(%rsi,%rax,2),%r12
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  nopl   (%rax)
L8:
  movswl (%rbx),%eax
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  add    $0x2,%rbx
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <BGBMID_Wave_UpdateHistogram@plt>
  cmp    %r12,%rbx
  movss  0xc(%rsp),%xmm0
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int BGBMID_Wave_GenerateHistogram(float *hist, short *sb, int sl) {
  float h, lh;
  int i, j, k;
  for (i = 0; i < 16; i++)
    hist[i] = 0;
  lh = 0;
  for (i = 0; i < sl; i++) {
    h = sb[i];
    BGBMID_Wave_UpdateHistogram(hist, h, lh);
    lh = h;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compare_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %ax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  setg   %al
  movzbl %al,%edx
  movzwl -0x4(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  setl   %al
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_short(const void *s1, const void *s2) {
  short a, b;
  a = (long)s1;
  b = (long)s2;
  return (a > b) - (a < b);
}
```
user: What is the c source code of the assembly code below:

```asm
<compare_short>:
  endbr64
  cmp    %si,%di
  setg   %al
  movzbl %al,%eax
  setl   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_short(const void *s1, const void *s2) {
  short a, b;
  a = (long)s1;
  b = (long)s2;
  return (a > b) - (a < b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_short>:
  endbr64
  xor    %eax,%eax
  cmp    %si,%di
  setl   %dl
  setg   %al
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int compare_short(const void *s1, const void *s2) {
  short a, b;
  a = (long)s1;
  b = (long)s2;
  return (a > b) - (a < b);
}
```