ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<DotProduct>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float DotProduct(float v0[3], float v1[3]) {
  float dot;
  dot = v0[0] * v1[0] + v0[1] * v1[1] + v0[2] * v1[2];
  return dot;
}
```
user: Translate the below assembly code into C programming language:

```asm
<DotProduct>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float DotProduct(float v0[3], float v1[3]) {
  float dot;
  dot = v0[0] * v1[0] + v0[1] * v1[1] + v0[2] * v1[2];
  return dot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findParen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L66:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
  addl   $0x1,-0x8(%rbp)
  jmp    L25
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  subl   $0x1,-0x8(%rbp)
L25:
  cmpl   $0x0,-0x8(%rbp)
  jne    L60
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L19
L60:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L66
  jmp    L4
L19:
  nop
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string

tool: D17: (

tool: D14: )

assistant: ```c
int findParen(char **tokens, int start, int finish, int firstParenLocation) {
  int parenCount = 0, j = 0;
  for (j = firstParenLocation; j < finish; j++) {
    if (strcmp(tokens[j], "(") == 0)
      parenCount++;
    else if (strcmp(tokens[j], ")") == 0)
      parenCount--;
    if (parenCount == 0 && j != start)
      break;
  }
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<findParen>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%ebx
  cmp    %edx,%ecx
  jge    L79
  mov    %esi,%r15d
  mov    %edx,%r13d
  movslq %ecx,%rax
  lea    (%rdi,%rax,8),%rbp
  mov    $0x0,%r12d
  lea    D13(%rip),%r14
  jmp    L32
L72:
  lea    D3(%rip),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r12d
  jmp    L10
L68:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r13d
  je     L15
L32:
  mov    %r14,%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L72
  add    $0x1,%r12d
L10:
  test   %r12d,%r12d
  jne    L68
  cmp    %ebx,%r15d
  je     L68
L79:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    %r13d,%ebx
  jmp    L79
```

tool_calls: name: read_data
arguments: label: D13
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: string

tool: D13: (

tool: D3: )

assistant: ```c
int findParen(char **tokens, int start, int finish, int firstParenLocation) {
  int parenCount = 0, j = 0;
  for (j = firstParenLocation; j < finish; j++) {
    if (strcmp(tokens[j], "(") == 0)
      parenCount++;
    else if (strcmp(tokens[j], ")") == 0)
      parenCount--;
    if (parenCount == 0 && j != start)
      break;
  }
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findParen>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    %edx,%ecx
  jge    L18
  movslq %ecx,%rax
  mov    %edx,%ebp
  lea    D4(%rip),%r14
  xor    %r13d,%r13d
  lea    (%rdi,%rax,8),%rbx
  lea    D0(%rip),%r15
  jmp    L10
  nopl   0x0(%rax)
L66:
  add    $0x1,%r13d
L4:
  test   %r13d,%r13d
  jne    L28
  cmp    %r12d,0xc(%rsp)
  jne    L18
L28:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%ebp
  je     L18
L10:
  mov    (%rbx),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L66
  mov    (%rbx),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r13d
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D4: (

tool: D0: )

assistant: ```c
int findParen(char **tokens, int start, int finish, int firstParenLocation) {
  int parenCount = 0, j = 0;
  for (j = firstParenLocation; j < finish; j++) {
    if (strcmp(tokens[j], "(") == 0)
      parenCount++;
    else if (strcmp(tokens[j], ")") == 0)
      parenCount--;
    if (parenCount == 0 && j != start)
      break;
  }
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findParen>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    %edx,%ecx
  jge    L52
  movslq %ecx,%rax
  mov    %edx,%ebp
  lea    D12(%rip),%r14
  xor    %r13d,%r13d
  lea    (%rdi,%rax,8),%rbx
  lea    D14(%rip),%r15
  jmp    L36
  nopl   0x0(%rax)
L47:
  add    $0x1,%r13d
L33:
  test   %r13d,%r13d
  jne    L57
  cmp    %r12d,0xc(%rsp)
  jne    L52
L57:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%ebp
  je     L52
L36:
  mov    (%rbx),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L47
  mov    (%rbx),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    $0x0,%r13d
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: string

tool: D12: (

tool: D14: )

assistant: ```c
int findParen(char **tokens, int start, int finish, int firstParenLocation) {
  int parenCount = 0, j = 0;
  for (j = firstParenLocation; j < finish; j++) {
    if (strcmp(tokens[j], "(") == 0)
      parenCount++;
    else if (strcmp(tokens[j], ")") == 0)
      parenCount--;
    if (parenCount == 0 && j != start)
      break;
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mostraInvertido>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D4: 
%s



tool: D15: %d 

assistant: ```c
void mostraInvertido(int *v, int n, char *msg) {
  int i = 0;
  printf("\n%s\n\n", msg);
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", v[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mostraInvertido>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  js     L3
  movslq %ebx,%rbx
  lea    D11(%rip),%r12
L7:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L7
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D18: 
%s



tool: D11: %d 

assistant: ```c
void mostraInvertido(int *v, int n, char *msg) {
  int i = 0;
  printf("\n%s\n\n", msg);
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", v[i]);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mostraInvertido>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  call   <printf@plt>
  sub    $0x1,%ebx
  js     L14
  movslq %ebx,%rbx
  lea    D4(%rip),%r12
  nopl   (%rax)
L17:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L17
L14:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string

tool: D3: 
%s



tool: D4: %d 

assistant: ```c
void mostraInvertido(int *v, int n, char *msg) {
  int i = 0;
  printf("\n%s\n\n", msg);
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", v[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mostraInvertido>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  call   <printf@plt>
  sub    $0x1,%ebx
  js     L1
  movslq %ebx,%rbx
  lea    D14(%rip),%r12
  nopl   (%rax)
L8:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L8
L1:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D4: 
%s



tool: D14: %d 

assistant: ```c
void mostraInvertido(int *v, int n, char *msg) {
  int i = 0;
  printf("\n%s\n\n", msg);
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", v[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rtcp_interval>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%eax
  movsd  D18(%rip),%xmm3
  test   %ecx,%ecx
  je     L46
  movsd  D65(%rip),%xmm3
L46:
  test   %esi,%esi
  jle    L47
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  mulsd  D29(%rip),%xmm4
  comisd %xmm2,%xmm4
  jbe    L47
  test   %edx,%edx
  je     L43
  mulsd  D29(%rip),%xmm0
  mov    %esi,%eax
L47:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm5
  divsd  %xmm0,%xmm5
  maxsd  %xmm5,%xmm3
  movsd  %xmm3,0x8(%rsp)
  mov    $0x0,%eax
  call   <drand30@plt>
  addsd  D12(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D6(%rip),%xmm0
  add    $0x18,%rsp
  ret
L43:
  mulsd  D30(%rip),%xmm0
  sub    %esi,%eax
  jmp    L47
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: f64
name: parse_data
arguments: data_tag: D65
datatype: byte[8]
name: parse_data
arguments: data_tag: D29
datatype: f64
name: parse_data
arguments: data_tag: D12
datatype: f64
name: parse_data
arguments: data_tag: D6
datatype: byte[8]
name: parse_data
arguments: data_tag: D30
datatype: byte[8]

tool: D18: 5

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: D29: 0.25

tool: D12: 0.5

tool: {"D6": [0x20,0xef,0x55,0x2b,0x13,0x7e,0xf3,0x3f]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

assistant: ```c
double rtcp_interval(int members, int senders, double rtcp_bw, int we_sent, double avg_rtcp_size, int initial) {
  double const RTCP_MIN_TIME = 5.;
  double const RTCP_SENDER_BW_FRACTION = 0.25;
  double const RTCP_RCVR_BW_FRACTION = (1 - RTCP_SENDER_BW_FRACTION);
  double const COMPENSATION = 2.71828 - 1.5;
  double t;
  double rtcp_min_time = RTCP_MIN_TIME;
  int n;
  if (initial) {
    rtcp_min_time /= 2;
  }
  n = members;
  if (senders > 0 && senders < members * RTCP_SENDER_BW_FRACTION) {
    if (we_sent) {
      rtcp_bw *= RTCP_SENDER_BW_FRACTION;
      n = senders;
    } else {
      rtcp_bw *= RTCP_RCVR_BW_FRACTION;
      n -= senders;
    }
  }
  t = avg_rtcp_size * n / rtcp_bw;
  if (t < rtcp_min_time)
    t = rtcp_min_time;
  t = t * (drand30() + 0.5);
  t = t / COMPENSATION;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rtcp_interval>:
  endbr64
  sub    $0x18,%rsp
  movsd  D56(%rip),%xmm3
  test   %ecx,%ecx
  je     L9
  movsd  D41(%rip),%xmm3
L9:
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  test   %esi,%esi
  jle    L16
  movsd  D54(%rip),%xmm5
  movapd %xmm2,%xmm6
  pxor   %xmm4,%xmm4
  cvtsi2sd %esi,%xmm4
  mulsd  %xmm5,%xmm6
  comisd %xmm4,%xmm6
  jbe    L16
  test   %edx,%edx
  je     L27
  mulsd  %xmm5,%xmm0
  movapd %xmm4,%xmm2
L16:
  mulsd  %xmm2,%xmm1
  xor    %eax,%eax
  divsd  %xmm0,%xmm1
  maxsd  %xmm1,%xmm3
  movsd  %xmm3,0x8(%rsp)
  call   <drand30@plt>
  addsd  D35(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  divsd  D50(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mulsd  D11(%rip),%xmm0
  sub    %esi,%edi
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D56
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D41
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D54
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D35
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: byte[8]

tool: D56: 5

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: D54: 0.25

tool: D35: 0.5

tool: {"D50": [0x20,0xef,0x55,0x2b,0x13,0x7e,0xf3,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

assistant: ```c
double rtcp_interval(int members, int senders, double rtcp_bw, int we_sent, double avg_rtcp_size, int initial) {
  double const RTCP_MIN_TIME = 5.;
  double const RTCP_SENDER_BW_FRACTION = 0.25;
  double const RTCP_RCVR_BW_FRACTION = (1 - RTCP_SENDER_BW_FRACTION);
  double const COMPENSATION = 2.71828 - 1.5;
  double t;
  double rtcp_min_time = RTCP_MIN_TIME;
  int n;
  if (initial) {
    rtcp_min_time /= 2;
  }
  n = members;
  if (senders > 0 && senders < members * RTCP_SENDER_BW_FRACTION) {
    if (we_sent) {
      rtcp_bw *= RTCP_SENDER_BW_FRACTION;
      n = senders;
    } else {
      rtcp_bw *= RTCP_RCVR_BW_FRACTION;
      n -= senders;
    }
  }
  t = avg_rtcp_size * n / rtcp_bw;
  if (t < rtcp_min_time)
    t = rtcp_min_time;
  t = t * (drand30() + 0.5);
  t = t / COMPENSATION;
  return t;
}
```
user: What is the c source code of the assembly code below:

```asm
<rtcp_interval>:
  endbr64
  sub    $0x18,%rsp
  movsd  D42(%rip),%xmm3
  test   %ecx,%ecx
  je     L8
  movsd  D25(%rip),%xmm3
L8:
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  test   %esi,%esi
  jle    L30
  movsd  D41(%rip),%xmm5
  movapd %xmm2,%xmm6
  pxor   %xmm4,%xmm4
  cvtsi2sd %esi,%xmm4
  mulsd  %xmm5,%xmm6
  comisd %xmm4,%xmm6
  jbe    L30
  test   %edx,%edx
  je     L15
  mulsd  %xmm5,%xmm0
  movapd %xmm4,%xmm2
L30:
  mulsd  %xmm2,%xmm1
  xor    %eax,%eax
  divsd  %xmm0,%xmm1
  maxsd  %xmm1,%xmm3
  movsd  %xmm3,0x8(%rsp)
  call   <drand30@plt>
  addsd  D50(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  divsd  D20(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mulsd  D47(%rip),%xmm0
  sub    %esi,%edi
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: label: D42
datatype: f64
name: disassemble_data
arguments: label: D25
datatype: byte[8]
name: disassemble_data
arguments: label: D41
datatype: f64
name: disassemble_data
arguments: label: D50
datatype: f64
name: disassemble_data
arguments: label: D20
datatype: byte[8]
name: disassemble_data
arguments: label: D47
datatype: byte[8]

tool: D42: 5

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x04,0x40]}

tool: D41: 0.25

tool: D50: 0.5

tool: {"D20": [0x20,0xef,0x55,0x2b,0x13,0x7e,0xf3,0x3f]}

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0xe8,0x3f]}

assistant: ```c
double rtcp_interval(int members, int senders, double rtcp_bw, int we_sent, double avg_rtcp_size, int initial) {
  double const RTCP_MIN_TIME = 5.;
  double const RTCP_SENDER_BW_FRACTION = 0.25;
  double const RTCP_RCVR_BW_FRACTION = (1 - RTCP_SENDER_BW_FRACTION);
  double const COMPENSATION = 2.71828 - 1.5;
  double t;
  double rtcp_min_time = RTCP_MIN_TIME;
  int n;
  if (initial) {
    rtcp_min_time /= 2;
  }
  n = members;
  if (senders > 0 && senders < members * RTCP_SENDER_BW_FRACTION) {
    if (we_sent) {
      rtcp_bw *= RTCP_SENDER_BW_FRACTION;
      n = senders;
    } else {
      rtcp_bw *= RTCP_RCVR_BW_FRACTION;
      n -= senders;
    }
  }
  t = avg_rtcp_size * n / rtcp_bw;
  if (t < rtcp_min_time)
    t = rtcp_min_time;
  t = t * (drand30() + 0.5);
  t = t / COMPENSATION;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mult_vec_r_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L3
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
double *mult_vec_r_1(double *res, double *vec1, double *vec2, int lo1, int hi1) {
  int i;
  double sum = 0;
  for (i = 0; i <= hi1 - lo1; i++) {
    res[i] = vec1[i] * vec2[i];
    sum += res[i];
  }
  res[hi1 - lo1 + 1] = sum;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mult_vec_r_1>:
  endbr64
  sub    %ecx,%r8d
  js     L16
  lea    0x1(%r8),%ecx
  shl    $0x3,%rcx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L26:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L26
L3:
  movslq %r8d,%r8
  movsd  %xmm1,0x8(%rdi,%r8,8)
  mov    %rdi,%rax
  ret
L16:
  pxor   %xmm1,%xmm1
  jmp    L3
```

assistant: ```c
double *mult_vec_r_1(double *res, double *vec1, double *vec2, int lo1, int hi1) {
  int i;
  double sum = 0;
  for (i = 0; i <= hi1 - lo1; i++) {
    res[i] = vec1[i] * vec2[i];
    sum += res[i];
  }
  res[hi1 - lo1 + 1] = sum;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mult_vec_r_1>:
  endbr64
  mov    %rdi,%r9
  sub    %ecx,%r8d
  js     L3
  movslq %r8d,%rax
  pxor   %xmm1,%xmm1
  lea    0x8(,%rax,8),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L28:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%r9,%rax,1)
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L28
L11:
  add    $0x1,%r8d
  mov    %r9,%rax
  movslq %r8d,%r8
  movsd  %xmm1,(%r9,%r8,8)
  ret
  xchg   %ax,%ax
L3:
  pxor   %xmm1,%xmm1
  jmp    L11
```

assistant: ```c
double *mult_vec_r_1(double *res, double *vec1, double *vec2, int lo1, int hi1) {
  int i;
  double sum = 0;
  for (i = 0; i <= hi1 - lo1; i++) {
    res[i] = vec1[i] * vec2[i];
    sum += res[i];
  }
  res[hi1 - lo1 + 1] = sum;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mult_vec_r_1>:
  endbr64
  mov    %rdi,%r9
  sub    %ecx,%r8d
  js     L38
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdi
  setne  %al
  test   %al,%cl
  je     L8
  cmp    $0x1,%r8d
  jbe    L8
  add    $0x1,%r8d
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  mov    %r8d,%ecx
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L5:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm3
  mulpd  %xmm3,%xmm0
  addsd  %xmm0,%xmm1
  movups %xmm0,(%r9,%rax,1)
  unpckhpd %xmm0,%xmm0
  add    $0x10,%rax
  addsd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L5
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%r8b
  je     L22
  cltq
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm0,(%r9,%rax,8)
L22:
  movslq %r8d,%r8
  mov    %r9,%rax
  movsd  %xmm1,(%r9,%r8,8)
  ret
  nop
L8:
  movslq %r8d,%rax
  pxor   %xmm1,%xmm1
  lea    0x8(,%rax,8),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L45:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%r9,%rax,1)
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L45
  add    $0x1,%r8d
L3:
  movslq %r8d,%r8
  mov    %r9,%rax
  movsd  %xmm1,(%r9,%r8,8)
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  pxor   %xmm1,%xmm1
  add    $0x1,%r8d
  jmp    L3
```

assistant: ```c
double *mult_vec_r_1(double *res, double *vec1, double *vec2, int lo1, int hi1) {
  int i;
  double sum = 0;
  for (i = 0; i <= hi1 - lo1; i++) {
    res[i] = vec1[i] * vec2[i];
    sum += res[i];
  }
  res[hi1 - lo1 + 1] = sum;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<applet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L17:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *applet(const char *arg0) {
  const char *applet = strrchr(arg0, '/');
  if (!applet)
    applet = arg0;
  else
    applet++;
  return applet;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<applet>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *applet(const char *arg0) {
  const char *applet = strrchr(arg0, '/');
  if (!applet)
    applet = arg0;
  else
    applet++;
  return applet;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<applet>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *applet(const char *arg0) {
  const char *applet = strrchr(arg0, '/');
  if (!applet)
    applet = arg0;
  else
    applet++;
  return applet;
}
```