ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pmu_adc_disable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edi
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x6, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pmu_adc_disable>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edi
  mov    $0xfc7ff,%edx
  mov    $0x3b,%esi
  call   <mbus_remote_register_write@plt>
  mov    $0x64,%edi
  add    $0x8,%rsp
  jmp    1070 <delay@plt>
```

assistant: ```c
void pmu_adc_disable() {
  mbus_remote_register_write(0x6, 0x3B, ((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3) | (1 << 4) | (1 << 5) | (1 << 6) | (1 << 7) | (1 << 8) | (1 << 9) | (1 << 10) | (0 << 11) | (0 << 12) | (0 << 13) | (1 << 14) | (1 << 15) | (1 << 16) | (1 << 17) | (1 << 18) | (1 << 19)));
  delay(100);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrdup_asciify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strdup_asciify@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: Out of memory

assistant: ```c
char *xstrdup_asciify(const unsigned char *p, unsigned int len) {
  char *s = strdup_asciify(p, len);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xstrdup_asciify>:
  endbr64
  push   %rbx
  call   <strdup_asciify@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L6:
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  lea    D7(%rip),%rdi
  call   <fatal@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: Out of memory

assistant: ```c
char *xstrdup_asciify(const unsigned char *p, unsigned int len) {
  char *s = strdup_asciify(p, len);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<xstrdup_asciify>:
  endbr64
  push   %r12
  call   <strdup_asciify@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  lea    D4(%rip),%rdi
  call   <fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: Out of memory

assistant: ```c
char *xstrdup_asciify(const unsigned char *p, unsigned int len) {
  char *s = strdup_asciify(p, len);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xstrdup_asciify>:
  endbr64
  push   %r12
  call   <strdup_asciify@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    D7(%rip),%rdi
  call   <fatal@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: Out of memory

assistant: ```c
char *xstrdup_asciify(const unsigned char *p, unsigned int len) {
  char *s = strdup_asciify(p, len);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L5:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <myputchar@plt>
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void myputs(const char *str) {
  while (*str)
    myputchar(*str++);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<myputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L7:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <myputchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L7
L18:
  pop    %rbx
  ret
```

assistant: ```c
void myputs(const char *str) {
  while (*str)
    myputchar(*str++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<myputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L7:
  call   <myputchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L10:
  pop    %rbx
  ret
```

assistant: ```c
void myputs(const char *str) {
  while (*str)
    myputchar(*str++);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<myputs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L15
L8:
  call   <myputchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L8
L15:
  pop    %rbx
  ret
```

assistant: ```c
void myputs(const char *str) {
  while (*str)
    myputchar(*str++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<icsFGetStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L64
L69:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L24
  cmpl   $0xd,-0x4(%rbp)
  jne    L44
  cmpb   $0xa,-0x20(%rbp)
  jne    L44
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  movsbl -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  je     L44
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L44
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movl   $0xd,-0x4(%rbp)
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %al,-0x20(%rbp)
  je     L94
L64:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L69
  jmp    L63
L24:
  nop
  jmp    L63
L94:
  nop
L63:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x8(%rbp)
  je     L22
  mov    -0x18(%rbp),%rax
  jmp    L108
L22:
  mov    $0x0,%eax
L108:
  leave
  ret
```

assistant: ```c
char *icsFGetStr(char *line, int n, FILE *fi, char sep) {
  int i = 0;
  int ch;
  while (i < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[i] = (char)ch;
    i++;
    if ((char)ch == sep)
      break;
  }
  line[i] = '\0';
  if (i != 0) {
    return line;
  } else {
    return NULL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<icsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%r15d
  jmp    L78
L76:
  mov    %al,(%r14,%rbx,1)
  mov    0xc(%rsp),%ebp
  add    $0x1,%ebp
  cmp    %r12b,%al
  je     L49
L28:
  add    $0x1,%rbx
L78:
  mov    %ebx,0xc(%rsp)
  mov    %ebx,%ebp
  cmp    %ebx,%r15d
  jle    L49
  mov    %r13,%rdi
  call   <getc@plt>
  mov    D19(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L49
  cmp    $0xd,%eax
  jne    L76
  cmp    $0xa,%r12b
  jne    L76
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L6
  mov    D19(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L76
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,(%r14,%rbx,1)
  jmp    L28
L6:
  movslq %ebp,%rax
  movb   $0xa,(%r14,%rax,1)
  add    $0x1,%ebp
L49:
  movslq %ebp,%rax
  movb   $0x0,(%r14,%rax,1)
  test   %ebp,%ebp
  mov    $0x0,%eax
  cmove  %rax,%r14
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *icsFGetStr(char *line, int n, FILE *fi, char sep) {
  int i = 0;
  int ch;
  while (i < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[i] = (char)ch;
    i++;
    if ((char)ch == sep)
      break;
  }
  line[i] = '\0';
  if (i != 0) {
    return line;
  } else {
    return NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<icsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r14d,%r14d
  jle    L92
  mov    D5(%rip),%r15
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L117:
  cmp    $0xa,%r12b
  jne    L40
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L39
  cmp    %eax,(%r15)
  je     L40
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,0x0(%rbp)
  nopw   0x0(%rax,%rax,1)
L119:
  add    $0x1,%rbp
  cmp    %ebx,%r14d
  je     L43
L47:
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    %eax,(%r15)
  je     L95
  add    $0x1,%ebx
  cmp    $0xd,%eax
  je     L117
L40:
  mov    %al,0x0(%rbp)
  cmp    %r12b,%al
  jne    L119
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L95:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  test   %ebx,%ebx
  jne    L2
L14:
  xor    %eax,%eax
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0xa,0x0(%rbp)
  movb   $0x0,(%rax,%rbx,1)
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L43:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r14
  movb   $0x0,(%rax,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  jmp    L14
```

assistant: ```c
char *icsFGetStr(char *line, int n, FILE *fi, char sep) {
  int i = 0;
  int ch;
  while (i < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[i] = (char)ch;
    i++;
    if ((char)ch == sep)
      break;
  }
  line[i] = '\0';
  if (i != 0) {
    return line;
  } else {
    return NULL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<icsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r14d,%r14d
  jle    L23
  mov    D9(%rip),%r15
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L64:
  cmp    $0xa,%r12b
  jne    L86
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L117
  cmp    %eax,(%r15)
  je     L86
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,0x0(%rbp)
  nopw   0x0(%rax,%rax,1)
L82:
  add    $0x1,%rbp
  cmp    %ebx,%r14d
  je     L95
L84:
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    %eax,(%r15)
  je     L40
  add    $0x1,%ebx
  cmp    $0xd,%eax
  je     L64
L86:
  mov    %al,0x0(%rbp)
  cmp    %r12b,%al
  jne    L82
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L115:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  test   %ebx,%ebx
  jne    L112
L113:
  xor    %eax,%eax
L112:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L117:
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0xa,0x0(%rbp)
  movb   $0x0,(%rax,%rbx,1)
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L95:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r14
  movb   $0x0,(%rax,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  movb   $0x0,(%rdi)
  jmp    L113
```

assistant: ```c
char *icsFGetStr(char *line, int n, FILE *fi, char sep) {
  int i = 0;
  int ch;
  while (i < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[i] = (char)ch;
    i++;
    if ((char)ch == sep)
      break;
  }
  line[i] = '\0';
  if (i != 0) {
    return line;
  } else {
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L26
L5:
  movq   $0x1,-0x8(%rbp)
  jmp    L6
L44:
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L74
  addq   $0x1,-0x8(%rbp)
L6:
  cmpq   $0x14,-0x8(%rbp)
  jle    L44
  jmp    L65
L74:
  nop
L65:
  cmpq   $0x15,-0x8(%rbp)
  je     L72
  addq   $0x1,-0x10(%rbp)
L26:
  cmpq   $0x14,-0x8(%rbp)
  jle    L5
  jmp    L33
L72:
  nop
L33:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: The solution is: %li


assistant: ```c
main() {
  long int num, div;
  div = 0;
  for (num = 1; div < 21; num++) {
    for (div = 1; div <= 20; div++) {
      if (num % div != 0) {
        break;
      }
    }
    if (div == 21)
      break;
  }
  printf("The solution is: %li\n", num);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  jmp    L38
L39:
  add    $0x1,%rsi
  cmp    $0x14,%rcx
  jg     L7
L38:
  mov    $0x2,%ecx
L10:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L39
  add    $0x1,%rcx
  cmp    $0x15,%rcx
  jne    L10
L7:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: The solution is: %li


assistant: ```c
main() {
  long int num, div;
  div = 0;
  for (num = 1; div < 21; num++) {
    for (div = 1; div <= 20; div++) {
      if (num % div != 0) {
        break;
      }
    }
    if (div == 21)
      break;
  }
  printf("The solution is: %li\n", num);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  nopl   (%rax)
L10:
  mov    $0x1,%ecx
  nopl   (%rax)
L28:
  add    $0x1,%rcx
  cmp    $0x15,%rcx
  je     L0
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L28
  add    $0x1,%rsi
  jmp    L10
  nopl   (%rax)
L0:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: The solution is: %li


assistant: ```c
main() {
  long int num, div;
  div = 0;
  for (num = 1; div < 21; num++) {
    for (div = 1; div <= 20; div++) {
      if (num % div != 0) {
        break;
      }
    }
    if (div == 21)
      break;
  }
  printf("The solution is: %li\n", num);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  nopl   (%rax)
L1:
  mov    $0x1,%ecx
  nopl   (%rax)
L13:
  add    $0x1,%rcx
  cmp    $0x15,%rcx
  je     L0
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L13
  add    $0x1,%rsi
  jmp    L1
  nopl   (%rax)
L0:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: The solution is: %li


assistant: ```c
main() {
  long int num, div;
  div = 0;
  for (num = 1; div < 21; num++) {
    for (div = 1; div <= 20; div++) {
      if (num % div != 0) {
        break;
      }
    }
    if (div == 21)
      break;
  }
  printf("The solution is: %li\n", num);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<s_wb32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <s_wb16@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <s_wb16@plt>
  nop
  leave
  ret
```

assistant: ```c
void s_wb32(struct serializer *s, uint32_t u32) {
  s_wb16(s, (uint16_t)(u32 >> 16));
  s_wb16(s, (uint16_t)u32);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<s_wb32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  sar    $0x10,%esi
  call   <s_wb16@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <s_wb16@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void s_wb32(struct serializer *s, uint32_t u32) {
  s_wb16(s, (uint16_t)(u32 >> 16));
  s_wb16(s, (uint16_t)u32);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s_wb32>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  sar    $0x10,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <s_wb16@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <s_wb16@plt>
```

assistant: ```c
void s_wb32(struct serializer *s, uint32_t u32) {
  s_wb16(s, (uint16_t)(u32 >> 16));
  s_wb16(s, (uint16_t)u32);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<s_wb32>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  sar    $0x10,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <s_wb16@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <s_wb16@plt>
```

assistant: ```c
void s_wb32(struct serializer *s, uint32_t u32) {
  s_wb16(s, (uint16_t)(u32 >> 16));
  s_wb16(s, (uint16_t)u32);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L24
L17:
  addq   $0x2,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L45
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L17
L45:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L43
L12:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L43:
  leave
  ret
```

assistant: ```c
char *trim(const char *fn) {
  char *name;
  while (fn[0] == '.' && fn[1] == '/')
    fn += 2;
  name = xmalloc(strlen(fn) + 1);
  if (name == 0)
    return 0;
  strcpy(name, fn);
  return name;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x2e,(%rdi)
  jne    L15
L23:
  cmpb   $0x2f,0x1(%rbx)
  jne    L15
  add    $0x2,%rbx
  cmpb   $0x2e,(%rbx)
  je     L23
L15:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L14:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *trim(const char *fn) {
  char *name;
  while (fn[0] == '.' && fn[1] == '/')
    fn += 2;
  name = xmalloc(strlen(fn) + 1);
  if (name == 0)
    return 0;
  strcpy(name, fn);
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2e,(%rdi)
  je     L32
  jmp    L43
  nopl   (%rax)
L33:
  add    $0x2,%rbp
  cmpb   $0x2e,0x0(%rbp)
  jne    L43
L32:
  cmpb   $0x2f,0x1(%rbp)
  je     L33
L43:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L40
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L40:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim(const char *fn) {
  char *name;
  while (fn[0] == '.' && fn[1] == '/')
    fn += 2;
  name = xmalloc(strlen(fn) + 1);
  if (name == 0)
    return 0;
  strcpy(name, fn);
  return name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  cmpb   $0x2e,(%rdi)
  je     L40
  jmp    L39
  nopl   (%rax)
L12:
  add    $0x2,%rbp
  cmpb   $0x2e,0x0(%rbp)
  jne    L39
L40:
  cmpb   $0x2f,0x1(%rbp)
  je     L12
L39:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L26
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L26:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trim(const char *fn) {
  char *name;
  while (fn[0] == '.' && fn[1] == '/')
    fn += 2;
  name = xmalloc(strlen(fn) + 1);
  if (name == 0)
    return 0;
  strcpy(name, fn);
  return name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<KMP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <GetPrefixValue@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <KMPStringMatch@plt>
  leave
  ret
```

assistant: ```c
int KMP(const char *strPattern, int len, const char *strTarget) {
  GetPrefixValue(strPattern, len);
  return KMPStringMatch(strPattern, len, strTarget, strlen(strTarget));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<KMP>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  call   <GetPrefixValue@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <KMPStringMatch@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int KMP(const char *strPattern, int len, const char *strTarget) {
  GetPrefixValue(strPattern, len);
  return KMPStringMatch(strPattern, len, strTarget, strlen(strTarget));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<KMP>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  call   <GetPrefixValue@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <KMPStringMatch@plt>
```

assistant: ```c
int KMP(const char *strPattern, int len, const char *strTarget) {
  GetPrefixValue(strPattern, len);
  return KMPStringMatch(strPattern, len, strTarget, strlen(strTarget));
}
```