ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<normalize>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L54
  mov    %eax,%esi
  movzbl (%rbx),%edi
  lea    -0x1(%rax),%r8d
  mov    $0x0,%edx
  jmp    L13
L58:
  mov    %ecx,%edi
L13:
  mov    %edx,%r9d
  cmp    %r8,%rdx
  je     L62
  movzbl 0x1(%rbx,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    $0x2f,%dil
  jne    L58
  cmp    $0x2f,%cl
  jne    L58
  mov    %r9d,%edx
  mov    %rbx,%rdi
  call   <normalizePath@plt>
L66:
  pop    %rbx
  ret
L62:
  mov    %rbx,%rax
  cmp    $0x2f,%dil
  jne    L66
  lea    -0x1(%rsi),%edx
  mov    %rbx,%rdi
  call   <normalizePath@plt>
  jmp    L66
L54:
  mov    %rbx,%rax
  jmp    L66
```

assistant: ```c
char *normalize(const char *pathname) {
  int i;
  int n = strlen(pathname);
  char prevChar = 0;
  for (i = 0; i < n; i++) {
    char c = pathname[i];
    if ((prevChar == '/') && (c == '/'))
      return normalizePath(pathname, n, i - 1);
    prevChar = c;
  }
  if (prevChar == '/')
    return normalizePath(pathname, n, n - 1);
  return (char *)pathname;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<normalize>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L5
  lea    -0x1(%rax),%edi
  movzbl 0x0(%rbp),%r8d
  mov    %eax,%esi
  xor    %edx,%edx
  mov    %rdi,%r10
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L59:
  movzbl 0x1(%rbp,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    $0x2f,%r8b
  jne    L31
  cmp    $0x2f,%cl
  je     L4
L31:
  mov    %ecx,%r8d
L22:
  mov    %edx,%r9d
  cmp    %rdi,%rdx
  jne    L59
  cmp    $0x2f,%r8b
  je     L14
L5:
  mov    %rbp,%rax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  mov    %r9d,%edx
  pop    %rbp
  jmp    1070 <normalizePath@plt>
L14:
  mov    %rbp,%rdi
  mov    %r10d,%edx
  pop    %rbp
  jmp    1070 <normalizePath@plt>
```

assistant: ```c
char *normalize(const char *pathname) {
  int i;
  int n = strlen(pathname);
  char prevChar = 0;
  for (i = 0; i < n; i++) {
    char c = pathname[i];
    if ((prevChar == '/') && (c == '/'))
      return normalizePath(pathname, n, i - 1);
    prevChar = c;
  }
  if (prevChar == '/')
    return normalizePath(pathname, n, n - 1);
  return (char *)pathname;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<normalize>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L30
  lea    -0x1(%rax),%edi
  movzbl 0x0(%rbp),%r8d
  mov    %eax,%esi
  xor    %edx,%edx
  mov    %rdi,%r10
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl 0x1(%rbp,%rdx,1),%ecx
  add    $0x1,%rdx
  cmp    $0x2f,%r8b
  jne    L6
  cmp    $0x2f,%cl
  je     L27
L6:
  mov    %ecx,%r8d
L25:
  mov    %edx,%r9d
  cmp    %rdx,%rdi
  jne    L35
  cmp    $0x2f,%r8b
  je     L13
L30:
  mov    %rbp,%rax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdi
  mov    %r9d,%edx
  pop    %rbp
  jmp    1070 <normalizePath@plt>
L13:
  mov    %rbp,%rdi
  mov    %r10d,%edx
  pop    %rbp
  jmp    1070 <normalizePath@plt>
```

assistant: ```c
char *normalize(const char *pathname) {
  int i;
  int n = strlen(pathname);
  char prevChar = 0;
  for (i = 0; i < n; i++) {
    char c = pathname[i];
    if ((prevChar == '/') && (c == '/'))
      return normalizePath(pathname, n, i - 1);
    prevChar = c;
  }
  if (prevChar == '/')
    return normalizePath(pathname, n, n - 1);
  return (char *)pathname;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L27:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L24:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
L37:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L42
  movl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L42
L144:
  cmpl   $0x0,-0x8(%rbp)
  je     L146
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L33
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L143
L146:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L102
L33:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L101
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L101:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L144
  jmp    L143
L102:
  nop
L143:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  cmpl   $0x0,-0x8(%rbp)
  je     L72
L5:
  mov    $0x1,%eax
  jmp    L13
L72:
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int get_token(char **src, char *dest) {
  int quoted = 0, nchars = 0;
  while (**src && isspace(**src))
    (*src)++;
  if (**src == '"') {
    quoted = 1;
    (*src)++;
  }
  while (**src) {
    if (quoted) {
      if (**src == '"') {
        (*src)++;
        break;
      }
    } else {
      if (isspace(**src))
        break;
    }
    if (**src == '\\')
      (*src)++;
    *dest++ = *(*src)++;
    nchars++;
  }
  *dest = '\0';
  return nchars || quoted;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L100
L134:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L118
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L134
L100:
  mov    $0x0,%r13d
L84:
  mov    (%rbx),%rax
  movzbl (%rax),%edi
  mov    $0x0,%r12d
  test   %dil,%dil
  jne    L29
  jmp    L1
L118:
  mov    (%rbx),%rax
  mov    $0x0,%r13d
  cmpb   $0x22,(%rax)
  jne    L84
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    $0x1,%r13d
  jmp    L84
L80:
  add    $0x1,%rax
  mov    %rax,(%rbx)
L1:
  movb   $0x0,0x0(%rbp)
  or     %r12d,%r13d
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L82:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L5
  jmp    L1
L83:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  add    $0x1,%rbp
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  add    $0x1,%r12d
  mov    (%rbx),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L1
L29:
  test   %r13d,%r13d
  je     L82
  cmp    $0x22,%dil
  je     L80
L5:
  mov    (%rbx),%rax
  cmpb   $0x5c,(%rax)
  jne    L83
  add    $0x1,%rax
  mov    %rax,(%rbx)
  jmp    L83
```

assistant: ```c
int get_token(char **src, char *dest) {
  int quoted = 0, nchars = 0;
  while (**src && isspace(**src))
    (*src)++;
  if (**src == '"') {
    quoted = 1;
    (*src)++;
  }
  while (**src) {
    if (quoted) {
      if (**src == '"') {
        (*src)++;
        break;
      }
    } else {
      if (isspace(**src))
        break;
    }
    if (**src == '\\')
      (*src)++;
    *dest++ = *(*src)++;
    nchars++;
  }
  *dest = '\0';
  return nchars || quoted;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  test   %dil,%dil
  jne    L36
  jmp    L41
  nopl   0x0(%rax)
L58:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L41
L36:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
  mov    (%rbx),%rdx
  movsbl (%rdx),%edi
  cmp    $0x22,%dil
  jne    L85
  lea    0x1(%rdx),%rax
  mov    $0x1,%r13d
  mov    %rax,(%rbx)
  movsbl 0x1(%rdx),%edi
L158:
  test   %dil,%dil
  je     L131
  xor    %r12d,%r12d
  jmp    L129
  nopl   0x0(%rax,%rax,1)
L88:
  cmp    $0x22,%dil
  je     L60
L27:
  mov    (%rbx),%rax
  xor    %edx,%edx
  cmpb   $0x5c,(%rax)
  sete   %dl
  add    $0x1,%rbp
  add    $0x1,%r12d
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L115
L129:
  test   %r13d,%r13d
  jne    L88
  call   <isspace@plt>
  test   %rax,%rax
  je     L27
  jmp    L26
  nopl   (%rax)
L41:
  xor    %r12d,%r12d
L26:
  xor    %eax,%eax
  test   %r12d,%r12d
  movb   $0x0,0x0(%rbp)
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L115:
  or     %r13d,%r12d
  jmp    L26
  nopl   (%rax)
L60:
  add    $0x1,%rax
  or     $0x1,%r12d
  mov    %rax,(%rbx)
  jmp    L26
  nopl   (%rax)
L85:
  mov    %rdx,%rax
  xor    %r13d,%r13d
  jmp    L158
L131:
  mov    %r13d,%r12d
  jmp    L26
```

assistant: ```c
int get_token(char **src, char *dest) {
  int quoted = 0, nchars = 0;
  while (**src && isspace(**src))
    (*src)++;
  if (**src == '"') {
    quoted = 1;
    (*src)++;
  }
  while (**src) {
    if (quoted) {
      if (**src == '"') {
        (*src)++;
        break;
      }
    } else {
      if (isspace(**src))
        break;
    }
    if (**src == '\\')
      (*src)++;
    *dest++ = *(*src)++;
    nchars++;
  }
  *dest = '\0';
  return nchars || quoted;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_token>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movsbl (%rax),%edi
  test   %dil,%dil
  jne    L130
  jmp    L16
  xchg   %ax,%ax
L163:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L16
L130:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L163
  mov    (%rbx),%rdx
  movsbl (%rdx),%edi
  cmp    $0x22,%dil
  jne    L55
  lea    0x1(%rdx),%rax
  mov    %rax,(%rbx)
  movzbl 0x1(%rdx),%edx
  test   %dl,%dl
  jne    L52
  jmp    L86
  xchg   %ax,%ax
L110:
  lea    0x1(%rax),%rdx
  add    $0x1,%rbp
  mov    %rdx,(%rbx)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L86
L52:
  cmp    $0x22,%dl
  je     L56
  cmp    $0x5c,%dl
  jne    L110
  lea    0x2(%rax),%rdx
  add    $0x1,%rbp
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    (%rbx),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L52
L86:
  mov    $0x1,%eax
L109:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nop
L16:
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L109
  xchg   %ax,%ax
L55:
  xor    %r12d,%r12d
  test   %dil,%dil
  jne    L14
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L117:
  lea    0x1(%rax),%rdx
  add    $0x1,%rbp
  mov    %rdx,(%rbx)
  movzbl (%rax),%eax
L107:
  mov    %al,-0x1(%rbp)
  mov    (%rbx),%rax
  add    $0x1,%r12d
  movsbl (%rax),%edi
  test   %dil,%dil
  je     L86
L14:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
  mov    (%rbx),%rax
  cmpb   $0x5c,(%rax)
  jne    L117
  lea    0x2(%rax),%rdx
  add    $0x1,%rbp
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%eax
  jmp    L107
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  test   %r12d,%r12d
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  setne  %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get_token(char **src, char *dest) {
  int quoted = 0, nchars = 0;
  while (**src && isspace(**src))
    (*src)++;
  if (**src == '"') {
    quoted = 1;
    (*src)++;
  }
  while (**src) {
    if (quoted) {
      if (**src == '"') {
        (*src)++;
        break;
      }
    } else {
      if (isspace(**src))
        break;
    }
    if (**src == '\\')
      (*src)++;
    *dest++ = *(*src)++;
    nchars++;
  }
  *dest = '\0';
  return nchars || quoted;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3d,%edi
  call   <test@plt>
  mov    $0x6d,%edi
  call   <test@plt>
  mov    $0xb5,%edi
  call   <test@plt>
  mov    $0x115,%edi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test(61);
  test(109);
  test(181);
  test(277);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d,%edi
  call   <test@plt>
  mov    $0x6d,%edi
  call   <test@plt>
  mov    $0xb5,%edi
  call   <test@plt>
  mov    $0x115,%edi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(61);
  test(109);
  test(181);
  test(277);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d,%edi
  call   <test@plt>
  mov    $0x6d,%edi
  call   <test@plt>
  mov    $0xb5,%edi
  call   <test@plt>
  mov    $0x115,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(61);
  test(109);
  test(181);
  test(277);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d,%edi
  call   <test@plt>
  mov    $0x6d,%edi
  call   <test@plt>
  mov    $0xb5,%edi
  call   <test@plt>
  mov    $0x115,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(61);
  test(109);
  test(181);
  test(277);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solcon_append_quaddobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x18c,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int solcon_append_quaddobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(396, a, b, sol);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solcon_append_quaddobl_solution>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdx
  mov    $0x0,%esi
  mov    $0x18c,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_quaddobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(396, a, b, sol);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solcon_append_quaddobl_solution>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    %edi,(%rsp)
  mov    $0x18c,%edi
  mov    %esi,0x4(%rsp)
  xor    %esi,%esi
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_quaddobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(396, a, b, sol);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solcon_append_quaddobl_solution>:
  endbr64
  sub    $0x18,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  mov    %rdx,%rcx
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rdx
  xor    %esi,%esi
  mov    $0x18c,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   %xmm0,(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_quaddobl_solution(int n, int m, double *sol) {
  int *a, fail;
  int b[2];
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(396, a, b, sol);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<alloc_2d_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  cltq
  imul   %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L19:
  mov    -0x14(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
bool **alloc_2d_array(int xc, int yc) {
  int i, j;
  bool *values = malloc(sizeof(bool) * xc * yc);
  bool **res = malloc(sizeof(bool *) * xc);
  for (i = 0; i < xc; i++) {
    res[i] = values + i * xc;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_2d_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  movslq %edi,%rbp
  imul   %edi,%esi
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x0(,%r12,8),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L5
  lea    0x0(,%rbp,4),%rsi
  mov    %rbx,%rcx
  mov    %rax,%rdx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%rdi
L1:
  mov    %rcx,(%rdx)
  add    %rsi,%rcx
  add    $0x8,%rdx
  cmp    %rdi,%rdx
  jne    L1
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool **alloc_2d_array(int xc, int yc) {
  int i, j;
  bool *values = malloc(sizeof(bool) * xc * yc);
  bool **res = malloc(sizeof(bool *) * xc);
  for (i = 0; i < xc; i++) {
    res[i] = values + i * xc;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_2d_array>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  imul   %ebp,%esi
  push   %rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  lea    0x0(,%rbp,8),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %ebp,%r12d
  lea    0x0(,%rbp,4),%rsi
  mov    %rbx,%rcx
  mov    %rax,%rdx
  lea    (%rax,%r12,8),%rdi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rcx,(%rdx)
  add    $0x8,%rdx
  add    %rsi,%rcx
  cmp    %rdi,%rdx
  jne    L8
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool **alloc_2d_array(int xc, int yc) {
  int i, j;
  bool *values = malloc(sizeof(bool) * xc * yc);
  bool **res = malloc(sizeof(bool *) * xc);
  for (i = 0; i < xc; i++) {
    res[i] = values + i * xc;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%r8d
  mov    $0x16,%ecx
  mov    $0x20,%edx
  mov    $0x3,%esi
  mov    $0x4,%edi
  call   <sum@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: hello world %f


assistant: ```c
int main(int argc, char **argv) {
  double x = sum(4, 3, 32, 22, 0);
  printf("hello world %f\n", x);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x16,%ecx
  mov    $0x20,%edx
  mov    $0x3,%esi
  mov    $0x4,%edi
  call   <sum@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: hello world %f


assistant: ```c
int main(int argc, char **argv) {
  double x = sum(4, 3, 32, 22, 0);
  printf("hello world %f\n", x);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  mov    $0x16,%ecx
  mov    $0x20,%edx
  mov    $0x3,%esi
  mov    $0x4,%edi
  call   <sum@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: hello world %f


assistant: ```c
int main(int argc, char **argv) {
  double x = sum(4, 3, 32, 22, 0);
  printf("hello world %f\n", x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  mov    $0x16,%ecx
  mov    $0x20,%edx
  mov    $0x3,%esi
  mov    $0x4,%edi
  call   <sum@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: hello world %f


assistant: ```c
int main(int argc, char **argv) {
  double x = sum(4, 3, 32, 22, 0);
  printf("hello world %f\n", x);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fac@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x1869f,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %lld 


assistant: ```c
int main(void) {
  for (int i = 0; i < 100000; i++) {
    printf("%lld \n", fac(i));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L8:
  mov    %ebx,%edi
  call   <fac@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x186a0,%ebx
  jne    L8
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %lld 


assistant: ```c
int main(void) {
  for (int i = 0; i < 100000; i++) {
    printf("%lld \n", fac(i));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fac@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    $0x186a0,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: %lld 


assistant: ```c
int main(void) {
  for (int i = 0; i < 100000; i++) {
    printf("%lld \n", fac(i));
  }
  return 0;
}
```