ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_allocate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <read_size@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void do_allocate() {
  uint32_t size = read_size();
  char *buf = malloc(size);
  write(STDOUT_FILENO, &buf, sizeof(buf));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_allocate>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <read_size@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_allocate() {
  uint32_t size = read_size();
  char *buf = malloc(size);
  write(STDOUT_FILENO, &buf, sizeof(buf));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_allocate>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <read_size@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_allocate() {
  uint32_t size = read_size();
  char *buf = malloc(size);
  write(STDOUT_FILENO, &buf, sizeof(buf));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_allocate>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <read_size@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,(%rsp)
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_allocate() {
  uint32_t size = read_size();
  char *buf = malloc(size);
  write(STDOUT_FILENO, &buf, sizeof(buf));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<imprimeVetor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D6: %d


assistant: ```c
void imprimeVetor(int vetor[], int tamanho) {
  int i;
  for (i = 0; i < tamanho; i++) {
    printf("%d\n", vetor[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<imprimeVetor>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D7(%rip),%rbp
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: %d


assistant: ```c
void imprimeVetor(int vetor[], int tamanho) {
  int i;
  for (i = 0; i < tamanho; i++) {
    printf("%d\n", vetor[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imprimeVetor>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: %d


assistant: ```c
void imprimeVetor(int vetor[], int tamanho) {
  int i;
  for (i = 0; i < tamanho; i++) {
    printf("%d\n", vetor[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<imprimeVetor>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: %d


assistant: ```c
void imprimeVetor(int vetor[], int tamanho) {
  int i;
  for (i = 0; i < tamanho; i++) {
    printf("%d\n", vetor[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CPU_read_MSR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  rdmsr
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t CPU_read_MSR(uint32_t msr) {
  uint32_t eax, edx;
  asm("rdmsr" : "=a"(eax), "=d"(edx) : "c"(msr));
  return eax;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CPU_read_MSR>:
  endbr64
  mov    %rdi,%rcx
  rdmsr
  ret
```

assistant: ```c
uint32_t CPU_read_MSR(uint32_t msr) {
  uint32_t eax, edx;
  asm("rdmsr" : "=a"(eax), "=d"(edx) : "c"(msr));
  return eax;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CPU_read_MSR>:
  endbr64
  mov    %rdi,%rcx
  rdmsr
  ret
```

assistant: ```c
uint32_t CPU_read_MSR(uint32_t msr) {
  uint32_t eax, edx;
  asm("rdmsr" : "=a"(eax), "=d"(edx) : "c"(msr));
  return eax;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CPU_read_MSR>:
  endbr64
  mov    %rdi,%rcx
  rdmsr
  ret
```

assistant: ```c
uint32_t CPU_read_MSR(uint32_t msr) {
  uint32_t eax, edx;
  asm("rdmsr" : "=a"(eax), "=d"(edx) : "c"(msr));
  return eax;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PadToX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %edx,-0x434(%rbp)
  mov    %rcx,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x414(%rbp)
  movl   $0x0,-0x41c(%rbp)
  movl   $0x0,-0x418(%rbp)
  movl   $0x0,-0x41c(%rbp)
  jmp    L13
L5:
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x41c(%rbp)
  jne    L2
  mov    -0x434(%rbp),%eax
  sub    -0x41c(%rbp),%eax
  mov    %eax,-0x414(%rbp)
  movl   $0x0,-0x418(%rbp)
  jmp    L8
L0:
  mov    -0x440(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x418(%rbp)
L8:
  mov    -0x418(%rbp),%eax
  cmp    -0x414(%rbp),%eax
  jl     L0
L2:
  addl   $0x1,-0x41c(%rbp)
L13:
  mov    -0x41c(%rbp),%eax
  cmp    -0x434(%rbp),%eax
  jl     L5
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x430(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lr_save_string@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int PadToX(char *cCharToPad, char *cParamName, int iValLength, char *cValueToAdd) {
  char cTemp[1024] = "";
  int iLoop = 0;
  int iMainLoop = 0;
  int iSubLoop = 0;
  for (iMainLoop = 0; iMainLoop < iValLength; iMainLoop++) {
    if (iMainLoop == strlen(cCharToPad)) {
      iLoop = iValLength - iMainLoop;
      for (iSubLoop = 0; iSubLoop < iLoop; iSubLoop++) {
        strcat(cTemp, cValueToAdd);
      }
    }
  }
  strcat(cTemp, cCharToPad);
  lr_save_string(cTemp, cParamName);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PadToX>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rcx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L54
  mov    %edx,%r12d
  mov    %edx,%ebx
  lea    0x10(%rsp),%r15
  jmp    L59
L11:
  sub    $0x1,%ebx
  je     L54
L59:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    %eax,%edx
  jne    L11
  mov    %ebx,%r14d
  test   %ebx,%ebx
  jle    L11
  mov    $0x0,%ebp
L45:
  mov    (%rsp),%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  jne    L45
  jmp    L11
L54:
  lea    0x10(%rsp),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <lr_save_string@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PadToX(char *cCharToPad, char *cParamName, int iValLength, char *cValueToAdd) {
  char cTemp[1024] = "";
  int iLoop = 0;
  int iMainLoop = 0;
  int iSubLoop = 0;
  for (iMainLoop = 0; iMainLoop < iValLength; iMainLoop++) {
    if (iMainLoop == strlen(cCharToPad)) {
      iLoop = iValLength - iMainLoop;
      for (iSubLoop = 0; iSubLoop < iLoop; iSubLoop++) {
        strcat(cTemp, cValueToAdd);
      }
    }
  }
  strcat(cTemp, cCharToPad);
  lr_save_string(cTemp, cParamName);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PadToX>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  mov    $0x7e,%ecx
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L39
  mov    %edx,%r13d
  mov    %edx,%ebx
  lea    0x10(%rsp),%r12
  jmp    L47
  xchg   %ax,%ax
L35:
  sub    $0x1,%ebx
  je     L39
L47:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    %eax,%r8d
  jne    L35
  xor    %r15d,%r15d
  nopl   (%rax)
L8:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <strcat@plt>
  cmp    %ebx,%r15d
  jne    L8
  sub    $0x1,%ebx
  jne    L47
  nopl   0x0(%rax)
L39:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <lr_save_string@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PadToX(char *cCharToPad, char *cParamName, int iValLength, char *cValueToAdd) {
  char cTemp[1024] = "";
  int iLoop = 0;
  int iMainLoop = 0;
  int iSubLoop = 0;
  for (iMainLoop = 0; iMainLoop < iValLength; iMainLoop++) {
    if (iMainLoop == strlen(cCharToPad)) {
      iLoop = iValLength - iMainLoop;
      for (iSubLoop = 0; iSubLoop < iLoop; iSubLoop++) {
        strcat(cTemp, cValueToAdd);
      }
    }
  }
  strcat(cTemp, cCharToPad);
  lr_save_string(cTemp, cParamName);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PadToX>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  mov    $0x7e,%ecx
  push   %rbx
  sub    $0x428,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  test   %edx,%edx
  jle    L64
  mov    %edx,%r13d
  mov    %edx,%ebx
  lea    0x10(%rsp),%r12
  jmp    L50
  xchg   %ax,%ax
L41:
  sub    $0x1,%ebx
  je     L64
L50:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    %eax,%r8d
  jne    L41
  xor    %r15d,%r15d
  nopl   (%rax)
L31:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <strcat@plt>
  cmp    %ebx,%r15d
  jne    L31
  sub    $0x1,%ebx
  jne    L50
  nopl   0x0(%rax)
L64:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <lr_save_string@plt>
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x428,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int PadToX(char *cCharToPad, char *cParamName, int iValLength, char *cValueToAdd) {
  char cTemp[1024] = "";
  int iLoop = 0;
  int iMainLoop = 0;
  int iSubLoop = 0;
  for (iMainLoop = 0; iMainLoop < iValLength; iMainLoop++) {
    if (iMainLoop == strlen(cCharToPad)) {
      iLoop = iValLength - iMainLoop;
      for (iSubLoop = 0; iSubLoop < iLoop; iSubLoop++) {
        strcat(cTemp, cValueToAdd);
      }
    }
  }
  strcat(cTemp, cCharToPad);
  lr_save_string(cTemp, cParamName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<boot_id_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L57:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L82
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L82
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    $0x3,%eax
  sub    -0x8(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  jmp    L27
L82:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x37(%rax),%edx
  mov    $0x3,%eax
  sub    -0x8(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  jmp    L27
L1:
  mov    $0xffffffff,%eax
  jmp    L21
L27:
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x3,-0x8(%rbp)
  jle    L57
  mov    -0x4(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int boot_id_hex(const char s[4]) {
  int i;
  int id = 0;
  for (i = 0; i < 4; i++)
    if (s[i] >= '0' && s[i] <= '9')
      id |= (s[i] - '0') << (3 - i) * 4;
    else if (s[i] >= 'A' && s[i] <= 'F')
      id |= (s[i] - 'A' + 10) << (3 - i) * 4;
    else
      return -1;
  return id;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<boot_id_hex>:
  endbr64
  mov    $0xc,%ecx
  mov    $0x0,%edx
  jmp    L10
L11:
  lea    -0x41(%rax),%esi
  cmp    $0x5,%sil
  ja     L24
  movsbl %al,%eax
  sub    $0x37,%eax
  shl    %cl,%eax
  or     %eax,%edx
L8:
  add    $0x1,%rdi
  sub    $0x4,%ecx
  cmp    $0xfffffffc,%ecx
  je     L27
L10:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L11
  movsbl %al,%eax
  sub    $0x30,%eax
  shl    %cl,%eax
  or     %eax,%edx
  jmp    L8
L24:
  mov    $0xffffffff,%edx
L27:
  mov    %edx,%eax
  ret
```

assistant: ```c
int boot_id_hex(const char s[4]) {
  int i;
  int id = 0;
  for (i = 0; i < 4; i++)
    if (s[i] >= '0' && s[i] <= '9')
      id |= (s[i] - '0') << (3 - i) * 4;
    else if (s[i] >= 'A' && s[i] <= 'F')
      id |= (s[i] - 'A' + 10) << (3 - i) * 4;
    else
      return -1;
  return id;
}
```
user: Translate the below assembly code into C programming language:

```asm
<boot_id_hex>:
  endbr64
  mov    $0xc,%ecx
  xor    %r8d,%r8d
L9:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L17
  movsbl %dl,%edx
  shl    %cl,%edx
  or     %edx,%r8d
L10:
  sub    $0x4,%ecx
  add    $0x1,%rdi
  cmp    $0xfffffffc,%ecx
  jne    L9
L6:
  mov    %r8d,%eax
  ret
  nop
L17:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%dl
  ja     L47
  sub    $0x37,%eax
  movsbl %al,%eax
  shl    %cl,%eax
  or     %eax,%r8d
  jmp    L10
  nopl   (%rax)
L47:
  mov    $0xffffffff,%r8d
  jmp    L6
```

assistant: ```c
int boot_id_hex(const char s[4]) {
  int i;
  int id = 0;
  for (i = 0; i < 4; i++)
    if (s[i] >= '0' && s[i] <= '9')
      id |= (s[i] - '0') << (3 - i) * 4;
    else if (s[i] >= 'A' && s[i] <= 'F')
      id |= (s[i] - 'A' + 10) << (3 - i) * 4;
    else
      return -1;
  return id;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<boot_id_hex>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rdx
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x41(%rcx),%eax
  cmp    $0x5,%al
  ja     L17
  sub    $0x37,%ecx
  movsbl %cl,%eax
  movzbl 0x1(%rdx),%ecx
  shl    $0xc,%eax
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L18
L108:
  lea    -0x41(%rcx),%esi
  cmp    $0x5,%sil
  ja     L17
  sub    $0x37,%ecx
  movsbl %cl,%ecx
  shl    $0x8,%ecx
  or     %ecx,%eax
  movzbl 0x2(%rdx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L33
L21:
  lea    -0x41(%rcx),%esi
  cmp    $0x5,%sil
  ja     L17
  sub    $0x37,%ecx
  movzbl 0x3(%rdx),%edx
  movsbl %cl,%ecx
  shl    $0x4,%ecx
  or     %ecx,%eax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L69
L41:
  movsbl %cl,%ecx
  or     %ecx,%eax
  ret
  nopl   (%rax)
L4:
  movzbl 0x1(%rdx),%ecx
  movsbl %al,%eax
  shl    $0xc,%eax
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L108
L18:
  movzbl 0x2(%rdx),%ecx
  movsbl %sil,%esi
  shl    $0x8,%esi
  or     %esi,%eax
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L21
L33:
  movzbl 0x3(%rdx),%edx
  movsbl %sil,%esi
  shl    $0x4,%esi
  lea    -0x30(%rdx),%ecx
  or     %esi,%eax
  cmp    $0x9,%cl
  jbe    L41
L69:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L17
  sub    $0x37,%edx
  movsbl %dl,%edx
  or     %edx,%eax
  ret
  nop
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int boot_id_hex(const char s[4]) {
  int i;
  int id = 0;
  for (i = 0; i < 4; i++)
    if (s[i] >= '0' && s[i] <= '9')
      id |= (s[i] - '0') << (3 - i) * 4;
    else if (s[i] >= 'A' && s[i] <= 'F')
      id |= (s[i] - 'A' + 10) << (3 - i) * 4;
    else
      return -1;
  return id;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0xff,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8:  %d - %c


assistant: ```c
int main() {
  int c;
  for (c = 0; c <= 255; c++) {
    printf(" %d - %c\n", c, c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D2(%rip),%rbp
L2:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2:  %d - %c


assistant: ```c
int main() {
  int c;
  for (c = 0; c <= 255; c++) {
    printf(" %d - %c\n", c, c);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2:  %d - %c


assistant: ```c
int main() {
  int c;
  for (c = 0; c <= 255; c++) {
    printf(" %d - %c\n", c, c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4:  %d - %c


assistant: ```c
int main() {
  int c;
  for (c = 0; c <= 255; c++) {
    printf(" %d - %c\n", c, c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toUpperCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L24
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L24
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L24:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void toUpperCase(char *value) {
  while (*value != '\0') {
    if (*value >= 'a' && *value <= 'z')
      *value -= 32;
    value++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<toUpperCase>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L37:
  ret
L2:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L37
L6:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L2
  sub    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L2
```

assistant: ```c
void toUpperCase(char *value) {
  while (*value != '\0') {
    if (*value >= 'a' && *value <= 'z')
      *value -= 32;
    value++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<toUpperCase>:
  endbr64
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L14:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L9
  sub    $0x20,%eax
  mov    %al,(%rdi)
L9:
  add    $0x1,%rdi
L16:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L14
  ret
```

assistant: ```c
void toUpperCase(char *value) {
  while (*value != '\0') {
    if (*value >= 'a' && *value <= 'z')
      *value -= 32;
    value++;
  }
}
```