ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x6a,%eax
  mov    %eax,%edx
  shr    $0x7,%al
  xor    $0xb,%edx
  movzbl %al,%eax
  movzbl %dl,%edx
  add    %edx,%edx
  or     %edx,%eax
  lea    0x0(,%rax,4),%edx
  sub    %edx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
        } else {
          state[0UL] |= (state[0UL] & (unsigned char)15) << 2UL;
        }
      } else {
        state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] >> (unsigned char)7) | (state[0UL] << (unsigned char)1)) * (unsigned char)253;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scnt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L20
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L0
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int scnt(const char *s1) {
  int count = 0;
  if (s1 == NULL)
    return 0;
  while (*s1) {
    if (*(s1++) == '/')
      count++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scnt>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  mov    $0x0,%edx
L18:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
L44:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L44
L7:
  mov    $0x0,%edx
  jmp    L44
```

assistant: ```c
int scnt(const char *s1) {
  int count = 0;
  if (s1 == NULL)
    return 0;
  while (*s1) {
    if (*(s1++) == '/')
      count++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<scnt>:
  endbr64
  test   %rdi,%rdi
  je     L20
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L13
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L13:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int scnt(const char *s1) {
  int count = 0;
  if (s1 == NULL)
    return 0;
  while (*s1) {
    if (*(s1++) == '/')
      count++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scnt>:
  endbr64
  test   %rdi,%rdi
  je     L20
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L24
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L29
L24:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int scnt(const char *s1) {
  int count = 0;
  if (s1 == NULL)
    return 0;
  while (*s1) {
    if (*(s1++) == '/')
      count++;
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lms_parser_info_find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %ecx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ecx,%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L68:
  cmp    %rdx,%rsp
  je     L62
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L68
L62:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L63
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L63:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L13
L10:
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lms_parser_find@plt>
  test   %eax,%eax
  jne    L31
  mov    $0x0,%eax
  jmp    L13
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <lms_parser_info@plt>
L13:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct lms_parser_info *lms_parser_info_find(const char *name) {
  char so_path[PATH_MAX];
  if (!name)
    return NULL;
  if (!lms_parser_find(so_path, sizeof(so_path), name))
    return NULL;
  return lms_parser_info(so_path);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lms_parser_info_find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L35:
  cmp    %rcx,%rsp
  je     L47
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L47:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L16
  orq    $0x0,-0x8(%rsp,%rax,1)
L16:
  mov    %rsp,%rbx
  test   %rdx,%rdx
  je     L9
  mov    %rbx,%rdi
  call   <lms_parser_find@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L68
  mov    %rbx,%rdi
  call   <lms_parser_info@plt>
L68:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  mov    -0x8(%rbp),%rbx
  leave
  ret
L9:
  mov    %rdx,%rax
  jmp    L68
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct lms_parser_info *lms_parser_info_find(const char *name) {
  char so_path[PATH_MAX];
  if (!name)
    return NULL;
  if (!lms_parser_find(so_path, sizeof(so_path), name))
    return NULL;
  return lms_parser_info(so_path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lms_parser_info_find>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    %rsp,%rdi
  movslq (%rax),%rax
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L43
L76:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L76
L43:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L53
L71:
  test   %rdx,%rdx
  je     L69
  mov    %rsp,%rdi
  call   <lms_parser_find@plt>
  test   %eax,%eax
  je     L69
  mov    %rsp,%rdi
  call   <lms_parser_info@plt>
L70:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  jmp    L70
  nopl   0x0(%rax)
L53:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L71
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct lms_parser_info *lms_parser_info_find(const char *name) {
  char so_path[PATH_MAX];
  if (!name)
    return NULL;
  if (!lms_parser_find(so_path, sizeof(so_path), name))
    return NULL;
  return lms_parser_info(so_path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lms_parser_info_find>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    %rsp,%rdi
  movslq (%rax),%rax
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L50
L73:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L73
L50:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L38
L15:
  test   %rdx,%rdx
  je     L47
  mov    %rsp,%rdi
  call   <lms_parser_find@plt>
  test   %eax,%eax
  je     L47
  mov    %rsp,%rdi
  call   <lms_parser_info@plt>
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  jmp    L60
  nopl   0x0(%rax)
L38:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L15
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct lms_parser_info *lms_parser_info_find(const char *name) {
  char so_path[PATH_MAX];
  if (!name)
    return NULL;
  if (!lms_parser_find(so_path, sizeof(so_path), name))
    return NULL;
  return lms_parser_info(so_path);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_getnext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x81c(%rbp)
  movl   $0x400,-0x818(%rbp)
  mov    $0x0,%eax
  call   <db_read@plt>
  lea    -0x410(%rbp),%rdx
  lea    -0x810(%rbp),%rcx
  mov    -0x828(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <parse_pair@plt>
  movl   $0x0,-0x814(%rbp)
  nop
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x814(%rbp)
  jge    L13
  mov    -0x814(%rbp),%eax
  cltq
  movb   $0x25,-0x810(%rbp,%rax,1)
  mov    -0x814(%rbp),%eax
  cltq
  movb   $0x0,-0x810(%rbp,%rax,1)
  nop
L13:
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int list_getnext(const char *str) {
  int result = 1;
  int i, index;
  const int max_index = 2048 / 2;
  char name[1024], value[1024], s[1024];
  db_read();
  parse_pair(str, name, value);
  for (i = 0; i < strlen(name); i++)
    if (name[i] = '%') {
      name[i] = '\0';
      break;
    }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_getnext>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <db_read@plt>
  lea    0x400(%rsp),%rdx
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <parse_pair@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x1,%eax
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int list_getnext(const char *str) {
  int result = 1;
  int i, index;
  const int max_index = 2048 / 2;
  char name[1024], value[1024], s[1024];
  db_read();
  parse_pair(str, name, value);
  for (i = 0; i < strlen(name); i++)
    if (name[i] = '%') {
      name[i] = '\0';
      break;
    }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_getnext>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <db_read@plt>
  mov    %rbp,%rdi
  lea    0x400(%rsp),%rdx
  mov    %r12,%rsi
  call   <parse_pair@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x818,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int list_getnext(const char *str) {
  int result = 1;
  int i, index;
  const int max_index = 2048 / 2;
  char name[1024], value[1024], s[1024];
  db_read();
  parse_pair(str, name, value);
  for (i = 0; i < strlen(name); i++)
    if (name[i] = '%') {
      name[i] = '\0';
      break;
    }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_getnext>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <db_read@plt>
  mov    %rbp,%rdi
  lea    0x400(%rsp),%rdx
  mov    %r12,%rsi
  call   <parse_pair@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x818,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int list_getnext(const char *str) {
  int result = 1;
  int i, index;
  const int max_index = 2048 / 2;
  char name[1024], value[1024], s[1024];
  db_read();
  parse_pair(str, name, value);
  for (i = 0; i < strlen(name); i++)
    if (name[i] = '%') {
      name[i] = '\0';
      break;
    }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x40653f4e,-0x4(%rbp)
  cmpl   $0x40653f4e,-0x4(%rbp)
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int b;
  b = 1080377166;
  if (b != 1080377166)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int b;
  b = 1080377166;
  if (b != 1080377166)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int b;
  b = 1080377166;
  if (b != 1080377166)
    abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int b;
  b = 1080377166;
  if (b != 1080377166)
    abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %edi,-0x404(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x400(%rbp),%rdx
  mov    -0x410(%rbp),%rcx
  mov    -0x404(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <settab@plt>
  lea    -0x400(%rbp),%rax
  mov    %rax,%rdi
  call   <entab@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char tab[1000 + 1];
  settab(argc, argv, tab);
  entab(tab);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  call   <settab@plt>
  mov    %rbx,%rdi
  call   <entab@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char tab[1000 + 1];
  settab(argc, argv, tab);
  entab(tab);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <settab@plt>
  mov    %rbp,%rdi
  call   <entab@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char tab[1000 + 1];
  settab(argc, argv, tab);
  entab(tab);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <settab@plt>
  mov    %rbp,%rdi
  call   <entab@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char tab[1000 + 1];
  settab(argc, argv, tab);
  entab(tab);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L37
  mov    $0x0,%eax
  jmp    L45
L37:
  addq   $0x1,-0x10(%rbp)
  jmp    L8
L69:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5c,%eax
  jne    L34
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <escape@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  jmp    L50
L34:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
L50:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L69
L38:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L45:
  leave
  ret
```

assistant: ```c
char *string_parse(char *input) {
  char *c = input;
  char *o = input;
  if (*c != '"') {
    return NULL;
  }
  c++;
  while (*c != 0 && *c != '"') {
    switch (*c) {
    case '\\':
      c++;
      *o = escape(c);
      break;
    default:
      *o = *c;
      break;
    }
    c++;
    o++;
  }
  *o = 0;
  return input;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_parse>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x22,(%rdi)
  jne    L52
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L16
  cmp    $0x22,%al
  je     L16
  mov    %rdi,%rbp
  jmp    L13
L59:
  mov    %al,0x0(%rbp)
  lea    0x1(%rbx),%rdx
  add    $0x1,%rbp
  movzbl 0x1(%rbx),%eax
  test   %al,%al
  je     L28
  cmp    $0x22,%al
  je     L28
L13:
  mov    %rdx,%rbx
  cmp    $0x5c,%al
  jne    L59
  lea    0x1(%rdx),%rbx
  mov    %rbx,%rdi
  call   <escape@plt>
  jmp    L59
L16:
  mov    %r12,%rbp
L28:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  ret
```

assistant: ```c
char *string_parse(char *input) {
  char *c = input;
  char *o = input;
  if (*c != '"') {
    return NULL;
  }
  c++;
  while (*c != 0 && *c != '"') {
    switch (*c) {
    case '\\':
      c++;
      *o = escape(c);
      break;
    default:
      *o = *c;
      break;
    }
    c++;
    o++;
  }
  *o = 0;
  return input;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_parse>:
  endbr64
  cmpb   $0x22,(%rdi)
  jne    L25
  push   %r12
  lea    0x1(%rdi),%rdx
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  jne    L53
  jmp    L9
  nopl   0x0(%rax)
L14:
  mov    %al,0x0(%rbp)
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rdx
  add    $0x1,%rbp
  test   %al,%al
  je     L9
L53:
  cmp    $0x22,%al
  je     L9
  mov    %rdx,%rbx
  cmp    $0x5c,%al
  jne    L14
  add    $0x1,%rbx
  mov    %rbx,%rdi
  call   <escape@plt>
  jmp    L14
  nopl   0x0(%rax)
L9:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *string_parse(char *input) {
  char *c = input;
  char *o = input;
  if (*c != '"') {
    return NULL;
  }
  c++;
  while (*c != 0 && *c != '"') {
    switch (*c) {
    case '\\':
      c++;
      *o = escape(c);
      break;
    default:
      *o = *c;
      break;
    }
    c++;
    o++;
  }
  *o = 0;
  return input;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_parse>:
  endbr64
  cmpb   $0x22,(%rdi)
  jne    L33
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  movzbl 0x1(%rdi),%eax
  mov    %rdi,%rbx
  test   %al,%al
  je     L47
  cmp    $0x22,%al
  jne    L61
  jmp    L47
  nopl   (%rax)
L52:
  mov    %al,(%rbx)
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rdx
  add    $0x1,%rbx
  test   %al,%al
  je     L47
L43:
  cmp    $0x22,%al
  je     L47
  mov    %rdx,%rbp
L61:
  cmp    $0x5c,%al
  jne    L52
  lea    0x1(%rbp),%rdi
  add    $0x1,%rbx
  call   <escape@plt>
  lea    0x2(%rbp),%rdx
  mov    %al,-0x1(%rbx)
  movzbl 0x2(%rbp),%eax
  test   %al,%al
  jne    L43
L47:
  movb   $0x0,(%rbx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *string_parse(char *input) {
  char *c = input;
  char *o = input;
  if (*c != '"') {
    return NULL;
  }
  c++;
  while (*c != 0 && *c != '"') {
    switch (*c) {
    case '\\':
      c++;
      *o = escape(c);
      break;
    default:
      *o = *c;
      break;
    }
    c++;
    o++;
  }
  *o = 0;
  return input;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<start_simulation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%eax
  call   <update_channels@plt>
  mov    $0x0,%eax
  call   <init_threads@plt>
  mov    $0x0,%eax
  call   <fire_delta_events@plt>
  mov    $0x0,%eax
  call   <activate_threads@plt>
  mov    $0x0,%eax
  call   <reset_delta_events@plt>
L21:
  movl   $0x1,-0xc(%rbp)
  mov    $0x0,%eax
  call   <eval@plt>
  movl   $0x2,-0xc(%rbp)
  mov    $0x0,%eax
  call   <update_channels@plt>
  movl   $0x3,-0xc(%rbp)
  mov    $0x0,%eax
  call   <fire_delta_events@plt>
  mov    $0x0,%eax
  call   <activate_threads@plt>
  mov    $0x0,%eax
  call   <reset_delta_events@plt>
  mov    $0x0,%eax
  call   <exists_runnable_thread@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L28
  movl   $0x4,-0xc(%rbp)
  mov    $0x0,%eax
  call   <fire_time_events@plt>
  mov    $0x0,%eax
  call   <activate_threads@plt>
  mov    $0x0,%eax
  call   <reset_time_events@plt>
L28:
  mov    $0x0,%eax
  call   <stop_simulation@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  jmp    L21
L12:
  nop
  nop
  leave
  ret
```

assistant: ```c
void start_simulation(void) {
  int kernel_st;
  int tmp;
  int tmp___0;
  {
    {
      kernel_st = 0;
      update_channels();
      init_threads();
      fire_delta_events();
      activate_threads();
      reset_delta_events();
    }
    {
      while (1) {
      while_16_continue:;
        {
          kernel_st = 1;
          eval();
        }
        {
          kernel_st = 2;
          update_channels();
        }
        {
          kernel_st = 3;
          fire_delta_events();
          activate_threads();
          reset_delta_events();
        }
        { tmp = exists_runnable_thread(); }
        if (tmp == 0) {
          {
            kernel_st = 4;
            fire_time_events();
            activate_threads();
            reset_time_events();
          }
        } else {
        }
        { tmp___0 = stop_simulation(); }
        if (tmp___0) {
          goto while_16_break;
        } else {
        }
      }
    while_16_break:;
    }
    return;
  }
}
```