ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drag_cd_gi>:
  endbr64
  comisd D109(%rip),%xmm0
  ja     L8
  comisd D117(%rip),%xmm0
  ja     L4
  comisd D36(%rip),%xmm0
  jb     L20
  movsd  D29(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D107(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D61(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mulsd  D76(%rip),%xmm0
  addsd  D81(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L8:
  movsd  D110(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D13(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L20:
  movsd  D40(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D109
data_type: f64[2]
name: read_data
arguments: data_tag: D117
data_type: f64[2]
name: read_data
arguments: data_tag: D36
data_type: f64[2]
name: read_data
arguments: data_tag: D29
data_type: f64
name: read_data
arguments: data_tag: D107
data_type: f64
name: read_data
arguments: data_tag: D61
data_type: f64
name: read_data
arguments: data_tag: D76
data_type: f64
name: read_data
arguments: data_tag: D81
data_type: f64
name: read_data
arguments: data_tag: D110
data_type: f64
name: read_data
arguments: data_tag: D23
data_type: f64
name: read_data
arguments: data_tag: D13
data_type: f64
name: read_data
arguments: data_tag: D40
data_type: f64

tool: {"D109": [1.65,0.0113272]}

tool: {"D117": [1.2,0.00701308]}

tool: {"D36": [0.7,1.17628]}

tool: D29: 1.17628

tool: D107: 1.28079

tool: D61: 0.531976

tool: D76: 0.00701308

tool: D81: 0.630556

tool: D110: 0.0113272

tool: D23: 0.143989

tool: D13: 0.845362

tool: D40: 0.2282

assistant: ```c
double drag_cd_gi(double mach) {
  if (mach > 1.65)
    return 0.845362 + mach * (-0.143989 + mach * 0.0113272);
  else if (mach > 1.2)
    return 0.630556 + mach * 0.00701308;
  else if (mach >= 0.7)
    return 0.531976 + mach * (-1.28079 + mach * 1.17628);
  else
    return 0.2282;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drag_cd_gi>:
  endbr64
  comisd D71(%rip),%xmm0
  ja     L28
  comisd D58(%rip),%xmm0
  ja     L17
  comisd D76(%rip),%xmm0
  jb     L16
  movsd  D8(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D87(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D108(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mulsd  D34(%rip),%xmm0
  addsd  D83(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L28:
  movsd  D79(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  subsd  D69(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  D80(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L16:
  movsd  D39(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D71
datatype: f64[2]
name: unpack_data
arguments: label: D58
datatype: f64[2]
name: unpack_data
arguments: label: D76
datatype: f64[2]
name: unpack_data
arguments: label: D8
datatype: f64
name: unpack_data
arguments: label: D87
datatype: f64
name: unpack_data
arguments: label: D108
datatype: f64
name: unpack_data
arguments: label: D34
datatype: f64
name: unpack_data
arguments: label: D83
datatype: f64
name: unpack_data
arguments: label: D79
datatype: f64
name: unpack_data
arguments: label: D69
datatype: f64
name: unpack_data
arguments: label: D80
datatype: f64
name: unpack_data
arguments: label: D39
datatype: f64

tool: {"D71": [1.65,0.0113272]}

tool: {"D58": [1.2,0.00701308]}

tool: {"D76": [0.7,1.17628]}

tool: D8: 1.17628

tool: D87: 1.28079

tool: D108: 0.531976

tool: D34: 0.00701308

tool: D83: 0.630556

tool: D79: 0.0113272

tool: D69: 0.143989

tool: D80: 0.845362

tool: D39: 0.2282

assistant: ```c
double drag_cd_gi(double mach) {
  if (mach > 1.65)
    return 0.845362 + mach * (-0.143989 + mach * 0.0113272);
  else if (mach > 1.2)
    return 0.630556 + mach * 0.00701308;
  else if (mach >= 0.7)
    return 0.531976 + mach * (-1.28079 + mach * 1.17628);
  else
    return 0.2282;
}
```
user: What is the c source code of the assembly code below?

```asm
<assert_parse_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %esi,-0x6c(%rbp)
  mov    %edx,-0x70(%rbp)
  mov    %rcx,-0x78(%rbp)
  mov    %r8,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rcx
  lea    -0x58(%rbp),%rdx
  lea    -0x60(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_line@plt>
  mov    %eax,-0x5c(%rbp)
  mov    -0x5c(%rbp),%eax
  cmp    -0x6c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x6c(%rbp)
  jne    L11
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x70(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x78(%rbp),%rdx
  lea    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x80(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L11:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void assert_parse_line(const char *line, const int expected_result, const unsigned int expected_address, const char *expected_instruction, const char *expected_args) {
  int result;
  unsigned int address;
  char instruction_name[8];
  char instruction_args[64];
  result = parse_line(line, &address, instruction_name, instruction_args);
  assert(result == expected_result);
  if (expected_result == 0) {
    assert(address == expected_address);
    assert(strcmp(instruction_name, expected_instruction) == 0);
    assert(strcmp(instruction_args, expected_args) == 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assert_parse_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %rcx,%r12
  mov    %r8,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   <parse_line@plt>
  cmp    %ebx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebx,%ebx
  je     L20
L17:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  cmp    %r13d,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x8(%rsp),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L17
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void assert_parse_line(const char *line, const int expected_result, const unsigned int expected_address, const char *expected_instruction, const char *expected_args) {
  int result;
  unsigned int address;
  char instruction_name[8];
  char instruction_args[64];
  result = parse_line(line, &address, instruction_name, instruction_args);
  assert(result == expected_result);
  if (expected_result == 0) {
    assert(address == expected_address);
    assert(strcmp(instruction_name, expected_instruction) == 0);
    assert(strcmp(instruction_args, expected_args) == 0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<assert_parse_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r15
  lea    0x4(%rsp),%rsi
  mov    %r14,%rcx
  mov    %r15,%rdx
  call   <parse_line@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  sete   %dil
  call   <assert@plt>
  test   %ebx,%ebx
  je     L23
L21:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %edi,%edi
  cmp    %r13d,0x4(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  jmp    L21
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void assert_parse_line(const char *line, const int expected_result, const unsigned int expected_address, const char *expected_instruction, const char *expected_args) {
  int result;
  unsigned int address;
  char instruction_name[8];
  char instruction_args[64];
  result = parse_line(line, &address, instruction_name, instruction_args);
  assert(result == expected_result);
  if (expected_result == 0) {
    assert(address == expected_address);
    assert(strcmp(instruction_name, expected_instruction) == 0);
    assert(strcmp(instruction_args, expected_args) == 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assert_parse_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r15
  lea    0x4(%rsp),%rsi
  mov    %r14,%rcx
  mov    %r15,%rdx
  call   <parse_line@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  sete   %dil
  call   <assert@plt>
  test   %ebx,%ebx
  je     L22
L20:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %edi,%edi
  cmp    %r13d,0x4(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  jmp    L20
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void assert_parse_line(const char *line, const int expected_result, const unsigned int expected_address, const char *expected_instruction, const char *expected_args) {
  int result;
  unsigned int address;
  char instruction_name[8];
  char instruction_args[64];
  result = parse_line(line, &address, instruction_name, instruction_args);
  assert(result == expected_result);
  if (expected_result == 0) {
    assert(address == expected_address);
    assert(strcmp(instruction_name, expected_instruction) == 0);
    assert(strcmp(instruction_args, expected_args) == 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unsetAddressName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <findAddressIndex@plt>
  test   %rax,%rax
  je     L17
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <removeAddressEntry@plt>
L17:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
void unsetAddressName(void *address) {
  int index;
  if (findAddressIndex(&index, address)) {
    removeAddressEntry(index);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unsetAddressName>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <findAddressIndex@plt>
  test   %rax,%rax
  jne    L21
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L21:
  mov    0x4(%rsp),%edi
  call   <removeAddressEntry@plt>
  jmp    L1
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unsetAddressName(void *address) {
  int index;
  if (findAddressIndex(&index, address)) {
    removeAddressEntry(index);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<unsetAddressName>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <findAddressIndex@plt>
  test   %rax,%rax
  jne    L4
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
  nop
L4:
  mov    0x4(%rsp),%edi
  call   <removeAddressEntry@plt>
  jmp    L14
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unsetAddressName(void *address) {
  int index;
  if (findAddressIndex(&index, address)) {
    removeAddressEntry(index);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unsetAddressName>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <findAddressIndex@plt>
  test   %rax,%rax
  jne    L24
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  ret
  nop
L24:
  mov    0x4(%rsp),%edi
  call   <removeAddressEntry@plt>
  jmp    L17
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unsetAddressName(void *address) {
  int index;
  if (findAddressIndex(&index, address)) {
    removeAddressEntry(index);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L0:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L9
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L9:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void swap_memory(void *data1, void *data2, size_t size) {
  char temp[size];
  memcpy(temp, data1, size);
  memcpy(data1, data2, size);
  memcpy(data2, temp, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L6:
  cmp    %rdx,%rsp
  je     L19
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L19:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L39
  orq    $0x0,-0x8(%rsp,%rax,1)
L39:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_memory(void *data1, void *data2, size_t size) {
  char temp[size];
  memcpy(temp, data1, size);
  memcpy(data1, data2, size);
  memcpy(data2, temp, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L6
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L7
L6:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L45
L15:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L45:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L15
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_memory(void *data1, void *data2, size_t size) {
  char temp[size];
  memcpy(temp, data1, size);
  memcpy(data1, data2, size);
  memcpy(data2, temp, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L3
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L39
L3:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L32:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x18(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L32
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void swap_memory(void *data1, void *data2, size_t size) {
  char temp[size];
  memcpy(temp, data1, size);
  memcpy(data1, data2, size);
  memcpy(data2, temp, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L11
L48:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L48
  jmp    L39
L34:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L34
L2:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int trim_spaces(char *source_str) {
  char *dest_str = source_str;
  int length = strlen(dest_str);
  while (dest_str[length - 1] == 32)
    dest_str[--length] = 0;
  while (*dest_str && *dest_str == 32)
    ++dest_str, --length;
  memmove(source_str, dest_str, length + 1);
  return length;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trim_spaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  movslq %eax,%rcx
  lea    -0x1(%rbp,%rcx,1),%rsi
  cmpb   $0x20,(%rsi)
  jne    L1
  mov    $0x0,%edx
  lea    -0x1(%rax),%edi
  add    %rbp,%rcx
L7:
  lea    (%rdi,%rdx,1),%eax
  movb   $0x0,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  cmpb   $0x20,-0x1(%rcx,%rdx,1)
  je     L7
L1:
  cmpb   $0x20,0x0(%rbp)
  jne    L38
  mov    %rbp,%rsi
L20:
  add    $0x1,%rsi
  mov    %ebp,%edx
  sub    %esi,%edx
  lea    (%rdx,%rax,1),%ebx
  cmpb   $0x20,(%rsi)
  je     L20
L2:
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  call   <memmove@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %eax,%ebx
  mov    %rbp,%rsi
  jmp    L2
```

assistant: ```c
int trim_spaces(char *source_str) {
  char *dest_str = source_str;
  int length = strlen(dest_str);
  while (dest_str[length - 1] == 32)
    dest_str[--length] = 0;
  while (*dest_str && *dest_str == 32)
    ++dest_str, --length;
  memmove(source_str, dest_str, length + 1);
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trim_spaces>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdi
  lea    -0x1(%rbp,%rdi,1),%rcx
  cmpb   $0x20,(%rcx)
  jne    L53
  lea    -0x1(%rax),%esi
  xor    %edx,%edx
  lea    0x0(%rbp,%rdi,1),%rax
  nopw   0x0(%rax,%rax,1)
L50:
  movb   $0x0,(%rcx,%rdx,1)
  lea    (%rsi,%rdx,1),%r12d
  sub    $0x1,%rdx
  cmpb   $0x20,-0x1(%rax,%rdx,1)
  je     L50
  cmpb   $0x20,0x0(%rbp)
  jne    L56
L45:
  mov    %rbp,%rsi
  nopl   0x0(%rax)
L7:
  add    $0x1,%rsi
  mov    %r12d,%edx
  sub    $0x1,%r12d
  cmpb   $0x20,(%rsi)
  je     L7
L19:
  mov    %rbp,%rdi
  call   <memmove@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  cmpb   $0x20,0x0(%rbp)
  mov    %eax,%r12d
  je     L45
  nopl   0x0(%rax)
L56:
  lea    0x1(%r12),%edx
  mov    %rbp,%rsi
  jmp    L19
```

assistant: ```c
int trim_spaces(char *source_str) {
  char *dest_str = source_str;
  int length = strlen(dest_str);
  while (dest_str[length - 1] == 32)
    dest_str[--length] = 0;
  while (*dest_str && *dest_str == 32)
    ++dest_str, --length;
  memmove(source_str, dest_str, length + 1);
  return length;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim_spaces>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdi
  lea    -0x1(%rbp,%rdi,1),%rcx
  cmpb   $0x20,(%rcx)
  jne    L12
  lea    -0x1(%rax),%esi
  xor    %edx,%edx
  lea    0x0(%rbp,%rdi,1),%rax
  nopw   0x0(%rax,%rax,1)
L34:
  movb   $0x0,(%rcx,%rdx,1)
  lea    (%rsi,%rdx,1),%r12d
  sub    $0x1,%rdx
  cmpb   $0x20,-0x1(%rax,%rdx,1)
  je     L34
  cmpb   $0x20,0x0(%rbp)
  jne    L16
L20:
  mov    %rbp,%rsi
  nopl   0x0(%rax)
L13:
  add    $0x1,%rsi
  mov    %r12d,%edx
  sub    $0x1,%r12d
  cmpb   $0x20,(%rsi)
  je     L13
L59:
  mov    %rbp,%rdi
  call   <memmove@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  cmpb   $0x20,0x0(%rbp)
  mov    %eax,%r12d
  je     L20
  nopl   0x0(%rax)
L16:
  lea    0x1(%r12),%edx
  mov    %rbp,%rsi
  jmp    L59
```

assistant: ```c
int trim_spaces(char *source_str) {
  char *dest_str = source_str;
  int length = strlen(dest_str);
  while (dest_str[length - 1] == 32)
    dest_str[--length] = 0;
  while (*dest_str && *dest_str == 32)
    ++dest_str, --length;
  memmove(source_str, dest_str, length + 1);
  return length;
}
```