ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<DumpMemory>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %edx,%r15d
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    $0x20,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D14(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    %r12d,%r15d
  cmovbe %r15d,%r12d
  xor    %ebx,%ebx
  test   %r15d,%r15d
  je     L21
  nopl   0x0(%rax,%rax,1)
L33:
  test   $0x7,%bl
  je     L26
  movzbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %ebx,%r12d
  jne    L33
L21:
  add    $0x8,%rsp
  lea    D33(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <puts@plt>
  nopl   0x0(%rax)
L26:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  movzbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L33
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D33
data_type: string

tool: D39: 
%p	

tool: D4: %02x 

tool: D14: DUMP %s: ...................................


tool: D33: 
...................................................

assistant: ```c
void DumpMemory(const char *BufferName, const unsigned char *BufferStart, const unsigned int BufferLen) {
  int i;
  printf("DUMP %s: ...................................\n", BufferName);
  const int maxLen = (BufferLen > 32) ? 32 : BufferLen;
  for (i = 0; i < maxLen; i++) {
    if (!(i & 0x7)) {
      printf("\n%p\t", &BufferStart[i]);
    }
    printf("%02x ", BufferStart[i]);
  }
  printf("\n...................................................\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<format_matrix_repr_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void format_matrix_repr_short(char *repr, char *digits, unsigned length) {
  for (unsigned i = 0; i < length; i++) {
    repr[i] = digits[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<format_matrix_repr_short>:
  endbr64
  test   %edx,%edx
  je     L7
  mov    %edx,%edx
  mov    $0x0,%eax
L1:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L1
L7:
  ret
```

assistant: ```c
void format_matrix_repr_short(char *repr, char *digits, unsigned length) {
  for (unsigned i = 0; i < length; i++) {
    repr[i] = digits[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<format_matrix_repr_short>:
  endbr64
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
L15:
  ret
```

assistant: ```c
void format_matrix_repr_short(char *repr, char *digits, unsigned length) {
  for (unsigned i = 0; i < length; i++) {
    repr[i] = digits[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_matrix_repr_short>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  je     L120
  lea    0x1(%rsi),%r8
  lea    -0x1(%rdx),%eax
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L115
  cmp    $0x6,%eax
  jbe    L115
  mov    %edx,%edi
  cmp    $0xe,%eax
  jbe    L60
  shr    $0x4,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
L99:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L99
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  test   $0xf,%dl
  je     L120
  mov    %edx,%edi
  sub    %eax,%edi
  lea    -0x1(%rdi),%r8d
  cmp    $0x6,%r8d
  jbe    L83
L98:
  mov    %eax,%r8d
  mov    (%rsi,%r8,1),%r9
  mov    %r9,(%rcx,%r8,1)
  mov    %edi,%r8d
  and    $0xfffffff8,%r8d
  add    %r8d,%eax
  cmp    %r8d,%edi
  je     L120
L83:
  mov    %eax,%edi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jbe    L120
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jbe    L120
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jbe    L120
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jbe    L120
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jbe    L120
  movzbl (%rsi,%rdi,1),%r8d
  add    $0x6,%eax
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jbe    L120
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  cs nopw 0x0(%rax,%rax,1)
L115:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L120:
  ret
L60:
  xor    %eax,%eax
  jmp    L98
```

assistant: ```c
void format_matrix_repr_short(char *repr, char *digits, unsigned length) {
  for (unsigned i = 0; i < length; i++) {
    repr[i] = digits[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x828(%rbp),%rax
  mov    %rax,-0x810(%rbp)
  lea    -0x800(%rbp),%rax
  mov    $0x7f8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x818(%rbp)
  movl   $0x0,-0x814(%rbp)
  jmp    L66
L78:
  mov    -0x828(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x800(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L63
  addl   $0x1,-0x818(%rbp)
  jmp    L72
L63:
  mov    -0x818(%rbp),%eax
  cmp    -0x814(%rbp),%eax
  jle    L54
  mov    -0x818(%rbp),%eax
  mov    %eax,-0x814(%rbp)
L54:
  mov    -0x828(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x800(%rbp,%rax,8),%rax
  mov    %rax,-0x808(%rbp)
  jmp    L6
L69:
  mov    -0x810(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x810(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movq   $0x0,-0x800(%rbp,%rax,8)
L6:
  mov    -0x810(%rbp),%rax
  cmp    -0x808(%rbp),%rax
  jne    L69
  mov    -0x810(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x810(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movq   $0x0,-0x800(%rbp,%rax,8)
  mov    -0x828(%rbp),%rax
  sub    -0x810(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x818(%rbp)
L72:
  mov    -0x828(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x828(%rbp),%rdx
  mov    %rdx,-0x800(%rbp,%rax,8)
  addq   $0x1,-0x828(%rbp)
L66:
  mov    -0x828(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    -0x818(%rbp),%edx
  mov    -0x814(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *p[255];
  char *q = s;
  char *t;
  memset(p, 0, sizeof(p));
  int len = 0, max = 0;
  while (*s != 0) {
    if (!p[*s]) {
      ++len;
    } else {
      if (len > max) {
        max = len;
      }
      t = p[*s];
      while (q != t) {
        p[*(q++)] = 0;
      };
      p[*(q++)] = 0;
      len = s - q + 1;
    }
    p[*s] = s;
    ++s;
  }
  return max > len ? max : len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  sub    $0x800,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x7f8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L66
  mov    %rbx,%rdx
  mov    $0x0,%edi
  mov    $0x0,%eax
  jmp    L52
L60:
  cmp    %eax,%edi
  cmovl  %eax,%edi
  cmp    %rdx,%rcx
  je     L29
L58:
  add    $0x1,%rdx
  movsbq -0x1(%rdx),%rax
  movq   $0x0,(%rsp,%rax,8)
  cmp    %rdx,%rcx
  jne    L58
L57:
  movsbq (%rcx),%rax
  movq   $0x0,(%rsp,%rax,8)
  lea    0x1(%rcx),%rdx
  mov    %ebx,%eax
  sub    %ecx,%eax
L53:
  movslq %esi,%rcx
  mov    %rbx,(%rsp,%rcx,8)
  add    $0x1,%rbx
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L84
L52:
  movsbl %cl,%esi
  movsbq %cl,%rcx
  mov    (%rsp,%rcx,8),%rcx
  test   %rcx,%rcx
  jne    L60
  add    $0x1,%eax
  jmp    L53
L29:
  mov    %rdx,%rcx
  jmp    L57
L66:
  mov    $0x0,%edi
  mov    $0x0,%eax
L84:
  cmp    %edi,%eax
  cmovl  %edi,%eax
  mov    0x7f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L80
  add    $0x800,%rsp
  pop    %rbx
  ret
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *p[255];
  char *q = s;
  char *t;
  memset(p, 0, sizeof(p));
  int len = 0, max = 0;
  while (*s != 0) {
    if (!p[*s]) {
      ++len;
    } else {
      if (len > max) {
        max = len;
      }
      t = p[*s];
      while (q != t) {
        p[*(q++)] = 0;
      };
      p[*(q++)] = 0;
      len = s - q + 1;
    }
    p[*s] = s;
    ++s;
  }
  return max > len ? max : len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  mov    $0x7f8,%edx
  mov    %rdi,%rbx
  xor    %esi,%esi
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L57
  mov    %rbx,%rsi
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L24
  nopl   (%rax)
L80:
  mov    %rsi,(%rsp,%rcx,8)
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%eax
  test   %dl,%dl
  je     L87
L24:
  movsbq %dl,%rcx
  mov    (%rsp,%rcx,8),%rdx
  test   %rdx,%rdx
  je     L80
  cmp    %eax,%edi
  cmovl  %eax,%edi
  cmp    %rbx,%rdx
  je     L58
  nopw   0x0(%rax,%rax,1)
L0:
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  movq   $0x0,(%rsp,%rax,8)
  cmp    %rbx,%rdx
  jne    L0
L58:
  movsbq (%rdx),%rax
  lea    0x1(%rdx),%rbx
  movq   $0x0,(%rsp,%rax,8)
  mov    %esi,%eax
  mov    %rsi,(%rsp,%rcx,8)
  add    $0x1,%rsi
  sub    %edx,%eax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L24
L87:
  cmp    %edi,%eax
  cmovl  %edi,%eax
L41:
  mov    0x7f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x800,%rsp
  pop    %rbx
  ret
L57:
  xor    %eax,%eax
  jmp    L41
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *p[255];
  char *q = s;
  char *t;
  memset(p, 0, sizeof(p));
  int len = 0, max = 0;
  while (*s != 0) {
    if (!p[*s]) {
      ++len;
    } else {
      if (len > max) {
        max = len;
      }
      t = p[*s];
      while (q != t) {
        p[*(q++)] = 0;
      };
      p[*(q++)] = 0;
      len = s - q + 1;
    }
    p[*s] = s;
    ++s;
  }
  return max > len ? max : len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %rbx
  mov    $0x7f8,%edx
  mov    %rdi,%rbx
  xor    %esi,%esi
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L8
  mov    %rbx,%rsi
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L61
  nopl   (%rax)
L52:
  mov    %rsi,(%rsp,%rcx,8)
  movzbl 0x1(%rsi),%edx
  add    $0x1,%rsi
  add    $0x1,%eax
  test   %dl,%dl
  je     L32
L61:
  movsbq %dl,%rcx
  mov    (%rsp,%rcx,8),%rdx
  test   %rdx,%rdx
  je     L52
  cmp    %eax,%edi
  cmovl  %eax,%edi
  cmp    %rbx,%rdx
  je     L13
  nopw   0x0(%rax,%rax,1)
L70:
  movsbq (%rbx),%rax
  add    $0x1,%rbx
  movq   $0x0,(%rsp,%rax,8)
  cmp    %rbx,%rdx
  jne    L70
L13:
  movsbq (%rdx),%rax
  lea    0x1(%rdx),%rbx
  movq   $0x0,(%rsp,%rax,8)
  mov    %esi,%eax
  mov    %rsi,(%rsp,%rcx,8)
  add    $0x1,%rsi
  sub    %edx,%eax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L61
L32:
  cmp    %edi,%eax
  cmovl  %edi,%eax
L1:
  mov    0x7f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x800,%rsp
  pop    %rbx
  ret
L8:
  xor    %eax,%eax
  jmp    L1
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lengthOfLongestSubstring(char *s) {
  char *p[255];
  char *q = s;
  char *t;
  memset(p, 0, sizeof(p));
  int len = 0, max = 0;
  while (*s != 0) {
    if (!p[*s]) {
      ++len;
    } else {
      if (len > max) {
        max = len;
      }
      t = p[*s];
      while (q != t) {
        p[*(q++)] = 0;
      };
      p[*(q++)] = 0;
      len = s - q + 1;
    }
    p[*s] = s;
    ++s;
  }
  return max > len ? max : len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L97
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x0,%eax
  jmp    L18
L97:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <read_int@plt>
  mov    %eax,-0xc(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <read_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L3
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L142
L3:
  mov    $0x1,%eax
  jmp    L18
L159:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L114
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L142
L114:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L30
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L142
L30:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L18
L142:
  addq   $0x8,-0x20(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L159
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L96
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L101
L96:
  cmpl   $0x0,-0x10(%rbp)
  jns    L101
  movl   $0x0,-0x10(%rbp)
L101:
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x30d40,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <transition@plt>
  cmp    $0xffffffff,%eax
  jne    L69
  mov    $0x1,%eax
  jmp    L18
L69:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D9
type: string

tool: D3: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness

tool: D9: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    usage();
    return 0;
  }
  int cur;
  int max;
  int desired;
  int delta;
  cur = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness");
  max = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness");
  delta = max / 15;
  if (cur == -1 || max == -1)
    return 1;
  while (++argv, --argc) {
    if (**argv == '+')
      desired = cur + delta;
    else if (**argv == '-')
      desired = cur - delta;
    else {
      usage();
      return 1;
    }
  }
  if (desired > max)
    desired = max;
  else if (desired < 0)
    desired = 0;
  if (transition(cur, desired, (200 * 1000)) == -1)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L71
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <read_int@plt>
  mov    %eax,%ebx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <read_int@plt>
  mov    %eax,%edi
  cmp    $0xffffffff,%ebx
  je     L97
  cmp    $0xffffffff,%eax
  je     L97
  mov    $0xf,%ecx
  cltd
  idiv   %ecx
  lea    0x8(%r12),%rdx
  mov    %ebp,%ebp
  lea    (%r12,%rbp,8),%rsi
  mov    %ebx,%r8d
  sub    %eax,%r8d
  add    %ebx,%eax
  jmp    L57
L71:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x0,%eax
  jmp    L80
L17:
  mov    %eax,%ecx
L87:
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  je     L91
L57:
  mov    (%rdx),%rcx
  movzbl (%rcx),%ecx
  cmp    $0x2b,%cl
  je     L17
  cmp    $0x2d,%cl
  jne    L84
  mov    %r8d,%ecx
  jmp    L87
L84:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L80
L91:
  cmp    %ecx,%edi
  jl     L79
  test   %ecx,%ecx
  mov    $0x0,%edi
  cmovns %ecx,%edi
L79:
  mov    $0x30d40,%edx
  mov    %edi,%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <transition@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
L80:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L97:
  mov    $0x1,%eax
  jmp    L80
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D14: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness

tool: D13: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    usage();
    return 0;
  }
  int cur;
  int max;
  int desired;
  int delta;
  cur = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness");
  max = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness");
  delta = max / 15;
  if (cur == -1 || max == -1)
    return 1;
  while (++argv, --argc) {
    if (**argv == '+')
      desired = cur + delta;
    else if (**argv == '-')
      desired = cur - delta;
    else {
      usage();
      return 1;
    }
  }
  if (desired > max)
    desired = max;
  else if (desired < 0)
    desired = 0;
  if (transition(cur, desired, (200 * 1000)) == -1)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  cmp    $0x1,%ebx
  jle    L8
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%r12
  call   <read_int@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <read_int@plt>
  mov    %eax,%r8d
  cmp    $0xffffffff,%ebp
  je     L60
  cmp    $0xffffffff,%eax
  je     L60
  mov    $0xf,%ecx
  cltd
  lea    (%r12,%rbx,8),%rsi
  mov    %ebp,%edi
  idiv   %ecx
  lea    0x8(%r12),%rdx
  sub    %eax,%edi
  add    %ebp,%eax
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L78:
  cmp    $0x2d,%cl
  jne    L47
  add    $0x8,%rdx
  mov    %edi,%ecx
  cmp    %rsi,%rdx
  je     L63
L46:
  mov    (%rdx),%rcx
  movzbl (%rcx),%ecx
  cmp    $0x2b,%cl
  jne    L78
  add    $0x8,%rdx
  mov    %eax,%ecx
  cmp    %rsi,%rdx
  jne    L46
L63:
  cmp    %ecx,%r8d
  jge    L1
L86:
  xor    %eax,%eax
  mov    $0x30d40,%edx
  mov    %r8d,%esi
  mov    %ebp,%edi
  call   <transition@plt>
  add    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L113
L60:
  mov    $0x1,%eax
L113:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %eax,%eax
  jmp    L113
L1:
  xor    %r8d,%r8d
  test   %ecx,%ecx
  cmovns %ecx,%r8d
  jmp    L86
L47:
  xor    %eax,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L113
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D7: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness

tool: D11: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    usage();
    return 0;
  }
  int cur;
  int max;
  int desired;
  int delta;
  cur = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness");
  max = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness");
  delta = max / 15;
  if (cur == -1 || max == -1)
    return 1;
  while (++argv, --argc) {
    if (**argv == '+')
      desired = cur + delta;
    else if (**argv == '-')
      desired = cur - delta;
    else {
      usage();
      return 1;
    }
  }
  if (desired > max)
    desired = max;
  else if (desired < 0)
    desired = 0;
  if (transition(cur, desired, (200 * 1000)) == -1)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  cmp    $0x1,%ebx
  jle    L21
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%r12
  call   <read_int@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <read_int@plt>
  mov    %eax,%r8d
  cmp    $0xffffffff,%ebp
  je     L9
  cmp    $0xffffffff,%eax
  je     L9
  mov    $0xf,%ecx
  cltd
  lea    (%r12,%rbx,8),%rsi
  mov    %ebp,%edi
  idiv   %ecx
  lea    0x8(%r12),%rdx
  sub    %eax,%edi
  add    %ebp,%eax
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L28:
  cmp    $0x2d,%cl
  jne    L115
  add    $0x8,%rdx
  mov    %edi,%ecx
  cmp    %rsi,%rdx
  je     L12
L58:
  mov    (%rdx),%rcx
  movzbl (%rcx),%ecx
  cmp    $0x2b,%cl
  jne    L28
  add    $0x8,%rdx
  mov    %eax,%ecx
  cmp    %rsi,%rdx
  jne    L58
L12:
  cmp    %ecx,%r8d
  jge    L60
L110:
  xor    %eax,%eax
  mov    $0x30d40,%edx
  mov    %r8d,%esi
  mov    %ebp,%edi
  call   <transition@plt>
  add    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L51
L9:
  mov    $0x1,%eax
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  xor    %eax,%eax
  call   <usage@plt>
  xor    %eax,%eax
  jmp    L51
L60:
  xor    %r8d,%r8d
  test   %ecx,%ecx
  cmovns %ecx,%r8d
  jmp    L110
L115:
  xor    %eax,%eax
  call   <usage@plt>
  mov    $0x1,%eax
  jmp    L51
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string

tool: D7: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness

tool: D15: /sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    usage();
    return 0;
  }
  int cur;
  int max;
  int desired;
  int delta;
  cur = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/brightness");
  max = read_int("/sys/devices/pci0000:00/0000:00:02.0/backlight/acpi_video0/max_brightness");
  delta = max / 15;
  if (cur == -1 || max == -1)
    return 1;
  while (++argv, --argc) {
    if (**argv == '+')
      desired = cur + delta;
    else if (**argv == '-')
      desired = cur - delta;
    else {
      usage();
      return 1;
    }
  }
  if (desired > max)
    desired = max;
  else if (desired < 0)
    desired = 0;
  if (transition(cur, desired, (200 * 1000)) == -1)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L7:
  mov    $0x1,%edi
  call   <_exit@plt>
  jmp    L7
```

assistant: ```c
void abort(void) {
  while (1)
    _exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
L5:
  mov    $0x1,%edi
  call   <_exit@plt>
  jmp    L5
```

assistant: ```c
void abort(void) {
  while (1)
    _exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  push   %rax
L7:
  mov    $0x1,%edi
  call   <_exit@plt>
  jmp    L7
```

assistant: ```c
void abort(void) {
  while (1)
    _exit(1);
}
```