ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<s2lab_>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %r8,%rsi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r8
  mov    0x58(%rsp),%rbx
  mov    %r8,0x8(%rsp)
  call   <_s2_f2cstr@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <_s2_f2cstr@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <_s2_f2cstr@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    %rax,%r13
  call   <_s2_f2cstr@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  mov    %rax,%r14
  call   <s2lab@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void s2lab_(char *xlab, char *ylab, char *zlab, char *title, long int xlablen, long int ylablen, long int zlablen, long int titlen) {
  char *cxlab = _s2_f2cstr(xlab, xlablen);
  char *cylab = _s2_f2cstr(ylab, ylablen);
  char *czlab = _s2_f2cstr(zlab, zlablen);
  char *ctitl = _s2_f2cstr(title, titlen);
  s2lab(cxlab, cylab, czlab, ctitl);
  free(ctitl);
  free(czlab);
  free(cylab);
  free(cxlab);
}
```
user: Translate the below assembly code into C programming language:

```asm
<EDirectBlendRowARGB32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  jmp    L9
L17:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rbx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  mov    -0x30(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rax
  lea    0xc(%rax),%rbx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  addq   $0x10,-0x28(%rbp)
  addq   $0x10,-0x30(%rbp)
L9:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  test   %eax,%eax
  jne    L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void EDirectBlendRowARGB32(u_int8_t *src, u_int8_t *dst, int width) {
  while (width--) {
    u_int8_t a = src[0];
    dst[0] = eblend(a, src[0], dst[0]);
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EDirectBlendRowARGB32>:
  endbr64
  test   %edx,%edx
  je     L19
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%edx
  shl    $0x4,%rdx
  lea    (%rdi,%rdx,1),%r13
L13:
  mov    0x0(%rbp),%r12d
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,(%rbx)
  mov    0x4(%rbx),%edx
  mov    0x4(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0x4(%rbx)
  mov    0x8(%rbx),%edx
  mov    0x8(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0x8(%rbx)
  mov    0xc(%rbx),%edx
  mov    0xc(%rbp),%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    %eax,0xc(%rbx)
  add    $0x10,%rbp
  add    $0x10,%rbx
  cmp    %r13,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  ret
```

assistant: ```c
void EDirectBlendRowARGB32(u_int8_t *src, u_int8_t *dst, int width) {
  while (width--) {
    u_int8_t a = src[0];
    dst[0] = eblend(a, src[0], dst[0]);
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<EDirectBlendRowARGB32>:
  endbr64
  test   %edx,%edx
  je     L10
  push   %r13
  mov    %edx,%edx
  push   %r12
  shl    $0x4,%rdx
  push   %rbp
  lea    (%rdi,%rdx,1),%r13
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp),%r12d
  mov    (%rbx),%edx
  add    $0x10,%rbp
  add    $0x10,%rbx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    -0xc(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x10(%rbx)
  mov    -0xc(%rbp),%esi
  call   <eblend@plt>
  mov    -0x8(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0xc(%rbx)
  mov    -0x8(%rbp),%esi
  call   <eblend@plt>
  mov    -0x4(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x8(%rbx)
  mov    -0x4(%rbp),%esi
  call   <eblend@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L10:
  ret
```

assistant: ```c
void EDirectBlendRowARGB32(u_int8_t *src, u_int8_t *dst, int width) {
  while (width--) {
    u_int8_t a = src[0];
    dst[0] = eblend(a, src[0], dst[0]);
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EDirectBlendRowARGB32>:
  endbr64
  test   %edx,%edx
  je     L3
  push   %r13
  mov    %edx,%edx
  push   %r12
  shl    $0x4,%rdx
  push   %rbp
  lea    (%rdi,%rdx,1),%r13
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    0x0(%rbp),%r12d
  mov    (%rbx),%edx
  add    $0x10,%rbp
  add    $0x10,%rbx
  mov    %r12d,%esi
  mov    %r12d,%edi
  call   <eblend@plt>
  mov    -0xc(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x10(%rbx)
  mov    -0xc(%rbp),%esi
  call   <eblend@plt>
  mov    -0x8(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0xc(%rbx)
  mov    -0x8(%rbp),%esi
  call   <eblend@plt>
  mov    -0x4(%rbx),%edx
  mov    %r12d,%edi
  mov    %eax,-0x8(%rbx)
  mov    -0x4(%rbp),%esi
  call   <eblend@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %r13,%rbp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L3:
  ret
```

assistant: ```c
void EDirectBlendRowARGB32(u_int8_t *src, u_int8_t *dst, int width) {
  while (width--) {
    u_int8_t a = src[0];
    dst[0] = eblend(a, src[0], dst[0]);
    dst[1] = eblend(a, src[1], dst[1]);
    dst[2] = eblend(a, src[2], dst[2]);
    dst[3] = eblend(a, src[3], dst[3]);
    src += 4;
    dst += 4;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OffsetOfSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L13
L2:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
int OffsetOfSubstring(char *line, char *token) {
  char *inset = strstr(line, token);
  if (!inset)
    return -1;
  else
    return inset - line;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<OffsetOfSubstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L1
  sub    %ebx,%eax
L0:
  pop    %rbx
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int OffsetOfSubstring(char *line, char *token) {
  char *inset = strstr(line, token);
  if (!inset)
    return -1;
  else
    return inset - line;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OffsetOfSubstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L6
  sub    %ebx,%eax
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int OffsetOfSubstring(char *line, char *token) {
  char *inset = strstr(line, token);
  if (!inset)
    return -1;
  else
    return inset - line;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<OffsetOfSubstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  sub    %ebx,%eax
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int OffsetOfSubstring(char *line, char *token) {
  char *inset = strstr(line, token);
  if (!inset)
    return -1;
  else
    return inset - line;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_dh512>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <DH_new@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L19
L13:
  mov    $0x0,%edx
  mov    $0x40,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <BN_bin2bn@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <BN_bin2bn@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <DH_set0_pqg@plt>
  test   %eax,%eax
  jne    L33
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <DH_free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    $0x0,%eax
  jmp    L19
L33:
  mov    -0x18(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
DH *get_dh512() {
  static unsigned char dhp_512[] = {
      0xED, 0x78, 0x7E, 0x95, 0xB9, 0x05, 0xD5, 0x00, 0x38, 0xC6, 0x6B, 0x49, 0x78, 0x22, 0x78, 0x43, 0x8D, 0xCC, 0xF9, 0x83, 0x18, 0xBB, 0x6E, 0xFE, 0xCD, 0x90, 0xC3, 0x84, 0xA8, 0x5C, 0x04, 0x84, 0xEB, 0x85, 0x1D, 0x5B, 0x81, 0x68, 0xA1, 0xB5, 0xCC, 0x09, 0x10, 0x46, 0x04, 0x8B, 0x0A, 0x06, 0xA5, 0xA7, 0x10, 0x7D, 0x43, 0x1B, 0x6F, 0xAD, 0xA8, 0xA1, 0xB0, 0xD3, 0xD9, 0x23, 0xD1, 0x83,
  };
  static unsigned char dhg_512[] = {
      0x02,
  };
  DH *dh;
  BIGNUM *dhp_bn, *dhg_bn;
  if ((dh = DH_new()) == NULL)
    return (NULL);
  dhp_bn = BN_bin2bn(dhp_512, sizeof(dhp_512), NULL);
  dhg_bn = BN_bin2bn(dhg_512, sizeof(dhg_512), NULL);
  if (!DH_set0_pqg(dh, dhp_bn, NULL, dhg_bn)) {
    DH_free(dh);
    BN_free(dhp_bn);
    BN_free(dhg_bn);
    return (NULL);
  }
  return (dh);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_dh512>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <DH_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
  mov    $0x0,%edx
  mov    $0x40,%esi
  lea    D7(%rip),%rdi
  call   <BN_bin2bn@plt>
  mov    %rax,%r12
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <BN_bin2bn@plt>
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    $0x0,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <DH_set0_pqg@plt>
  test   %eax,%eax
  je     L10
L23:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %rbx,%rdi
  call   <DH_free@plt>
  mov    %r12,%rdi
  call   <BN_free@plt>
  mov    %rbp,%rdi
  call   <BN_free@plt>
  mov    $0x0,%ebx
  jmp    L23
```

assistant: ```c
DH *get_dh512() {
  static unsigned char dhp_512[] = {
      0xED, 0x78, 0x7E, 0x95, 0xB9, 0x05, 0xD5, 0x00, 0x38, 0xC6, 0x6B, 0x49, 0x78, 0x22, 0x78, 0x43, 0x8D, 0xCC, 0xF9, 0x83, 0x18, 0xBB, 0x6E, 0xFE, 0xCD, 0x90, 0xC3, 0x84, 0xA8, 0x5C, 0x04, 0x84, 0xEB, 0x85, 0x1D, 0x5B, 0x81, 0x68, 0xA1, 0xB5, 0xCC, 0x09, 0x10, 0x46, 0x04, 0x8B, 0x0A, 0x06, 0xA5, 0xA7, 0x10, 0x7D, 0x43, 0x1B, 0x6F, 0xAD, 0xA8, 0xA1, 0xB0, 0xD3, 0xD9, 0x23, 0xD1, 0x83,
  };
  static unsigned char dhg_512[] = {
      0x02,
  };
  DH *dh;
  BIGNUM *dhp_bn, *dhg_bn;
  if ((dh = DH_new()) == NULL)
    return (NULL);
  dhp_bn = BN_bin2bn(dhp_512, sizeof(dhp_512), NULL);
  dhg_bn = BN_bin2bn(dhg_512, sizeof(dhg_512), NULL);
  if (!DH_set0_pqg(dh, dhp_bn, NULL, dhg_bn)) {
    DH_free(dh);
    BN_free(dhp_bn);
    BN_free(dhg_bn);
    return (NULL);
  }
  return (dh);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_dh512>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <DH_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  xor    %edx,%edx
  mov    $0x40,%esi
  lea    D11(%rip),%rdi
  call   <BN_bin2bn@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  mov    %rax,%r13
  call   <BN_bin2bn@plt>
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <DH_set0_pqg@plt>
  test   %eax,%eax
  je     L7
L5:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <DH_free@plt>
  mov    %r13,%rdi
  call   <BN_free@plt>
  mov    %rbp,%rdi
  call   <BN_free@plt>
  jmp    L5
```

assistant: ```c
DH *get_dh512() {
  static unsigned char dhp_512[] = {
      0xED, 0x78, 0x7E, 0x95, 0xB9, 0x05, 0xD5, 0x00, 0x38, 0xC6, 0x6B, 0x49, 0x78, 0x22, 0x78, 0x43, 0x8D, 0xCC, 0xF9, 0x83, 0x18, 0xBB, 0x6E, 0xFE, 0xCD, 0x90, 0xC3, 0x84, 0xA8, 0x5C, 0x04, 0x84, 0xEB, 0x85, 0x1D, 0x5B, 0x81, 0x68, 0xA1, 0xB5, 0xCC, 0x09, 0x10, 0x46, 0x04, 0x8B, 0x0A, 0x06, 0xA5, 0xA7, 0x10, 0x7D, 0x43, 0x1B, 0x6F, 0xAD, 0xA8, 0xA1, 0xB0, 0xD3, 0xD9, 0x23, 0xD1, 0x83,
  };
  static unsigned char dhg_512[] = {
      0x02,
  };
  DH *dh;
  BIGNUM *dhp_bn, *dhg_bn;
  if ((dh = DH_new()) == NULL)
    return (NULL);
  dhp_bn = BN_bin2bn(dhp_512, sizeof(dhp_512), NULL);
  dhg_bn = BN_bin2bn(dhg_512, sizeof(dhg_512), NULL);
  if (!DH_set0_pqg(dh, dhp_bn, NULL, dhg_bn)) {
    DH_free(dh);
    BN_free(dhp_bn);
    BN_free(dhg_bn);
    return (NULL);
  }
  return (dh);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_dh512>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <DH_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  xor    %edx,%edx
  mov    $0x40,%esi
  lea    D2(%rip),%rdi
  call   <BN_bin2bn@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  mov    %rax,%r13
  call   <BN_bin2bn@plt>
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <DH_set0_pqg@plt>
  test   %eax,%eax
  je     L13
L27:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <DH_free@plt>
  mov    %r13,%rdi
  call   <BN_free@plt>
  mov    %rbp,%rdi
  call   <BN_free@plt>
  jmp    L27
```

assistant: ```c
DH *get_dh512() {
  static unsigned char dhp_512[] = {
      0xED, 0x78, 0x7E, 0x95, 0xB9, 0x05, 0xD5, 0x00, 0x38, 0xC6, 0x6B, 0x49, 0x78, 0x22, 0x78, 0x43, 0x8D, 0xCC, 0xF9, 0x83, 0x18, 0xBB, 0x6E, 0xFE, 0xCD, 0x90, 0xC3, 0x84, 0xA8, 0x5C, 0x04, 0x84, 0xEB, 0x85, 0x1D, 0x5B, 0x81, 0x68, 0xA1, 0xB5, 0xCC, 0x09, 0x10, 0x46, 0x04, 0x8B, 0x0A, 0x06, 0xA5, 0xA7, 0x10, 0x7D, 0x43, 0x1B, 0x6F, 0xAD, 0xA8, 0xA1, 0xB0, 0xD3, 0xD9, 0x23, 0xD1, 0x83,
  };
  static unsigned char dhg_512[] = {
      0x02,
  };
  DH *dh;
  BIGNUM *dhp_bn, *dhg_bn;
  if ((dh = DH_new()) == NULL)
    return (NULL);
  dhp_bn = BN_bin2bn(dhp_512, sizeof(dhp_512), NULL);
  dhg_bn = BN_bin2bn(dhg_512, sizeof(dhg_512), NULL);
  if (!DH_set0_pqg(dh, dhp_bn, NULL, dhg_bn)) {
    DH_free(dh);
    BN_free(dhp_bn);
    BN_free(dhg_bn);
    return (NULL);
  }
  return (dh);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x14,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L1:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fibonacci@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_vector@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <matrix@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D22
datatype: string

tool: D9: Fibonacci


tool: D22: 


assistant: ```c
int main(void) {
  const int size = 20;
  int series[size];
  fibonacci(series, size);
  printf("Fibonacci\n");
  print_vector(series, size);
  printf("\n");
  matrix();
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <fibonacci@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <print_vector@plt>
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <matrix@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D13: Fibonacci


tool: D0: 


assistant: ```c
int main(void) {
  const int size = 20;
  int series[size];
  fibonacci(series, size);
  printf("Fibonacci\n");
  print_vector(series, size);
  printf("\n");
  matrix();
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%esi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fibonacci@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  lea    D5(%rip),%rbp
  call   <print_vector@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <matrix@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D9: Fibonacci


tool: D5: 


assistant: ```c
int main(void) {
  const int size = 20;
  int series[size];
  fibonacci(series, size);
  printf("Fibonacci\n");
  print_vector(series, size);
  printf("\n");
  matrix();
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x14,%esi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fibonacci@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  lea    D9(%rip),%rbp
  call   <print_vector@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <matrix@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D9
datatype: string

tool: D16: Fibonacci


tool: D9: 


assistant: ```c
int main(void) {
  const int size = 20;
  int series[size];
  fibonacci(series, size);
  printf("Fibonacci\n");
  print_vector(series, size);
  printf("\n");
  matrix();
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L51
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x28(%rbp)
L51:
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftime@plt>
L28:
  movl   $0x0,-0x20(%rbp)
  jmp    L30
L13:
  mov    -0x20(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x24(%rbp)
  addl   $0x1,-0x20(%rbp)
L30:
  cmpl   $0x3e7,-0x20(%rbp)
  jle    L13
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ftime@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L50
  jmp    L28
L50:
  nop
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D17
datatype: string

tool: D6: Going to be busy for %d seconds


tool: D17: Waking up

assistant: ```c
int main(int argc, char *argv[]) {
  int busySeconds = 1;
  int dummyNum = 2;
  int i = 0, duration;
  struct timeb beg, end;
  if (argc > 1) {
    busySeconds = atoi(argv[1]);
  }
  printf("Going to be busy for %d seconds\n", busySeconds);
  ftime(&beg);
  while (1) {
    for (i = 0; i < 1000; i++)
      dummyNum += i * i;
    ftime(&end);
    duration = ((end.millitm + end.time * 1000) - (beg.millitm + beg.time * 1000));
    if (duration > busySeconds * 1000)
      break;
  }
  printf("Waking up\n");
  return 0;
}
```