ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dmat_init_1x2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  test   %edx,%edx
  jle    L27
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %rsi,%r14
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r15
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%r14,%rbx,1),%r12
  mov    0x0(%r13,%rbx,1),%rbp
  lea    (%r12,%r15,1),%rax
  cmp    %rax,%rbp
  jae    L5
  lea    0x0(%rbp,%r15,1),%rax
  cmp    %rax,%r12
  jb     L42
L5:
  mov    %r15,%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r15,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L30:
  movsd  (%rsp),%xmm1
  movsd  %xmm1,0x0(%rbp,%rbx,1)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L20
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L49:
  movq   $0x0,0x0(%rbp,%rax,8)
  movq   $0x0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    0x8(%rsp),%rax
  jne    L49
  jmp    L30
```

assistant: ```c
void dmat_init_1x2(double **a11, double **a12, double alpha, int n) {
  int i;
  int j;
  for (i = 0; i < n; ++i) {
    for (j = 0; j < n; ++j) {
      a11[i][j] = 0.;
      a12[i][j] = 0.;
    }
    a11[i][i] = alpha;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<host_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  (bad)
  add    %dl,(%rax)
  add    (%rax),%al
  add    %al,(%rax)
  add    %al,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void host_close(int fd) {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x02"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       :
                       : "a"(fd));
}
```
user: Translate the below assembly code into C programming language:

```asm
<host_close>:
  endbr64
  mov    %edi,%eax
  (bad)
  add    %dl,(%rax)
  add    (%rax),%al
  add    %al,(%rax)
  add    %al,(%rax)
  ret
```

assistant: ```c
void host_close(int fd) {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x02"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       :
                       : "a"(fd));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<host_close>:
  endbr64
  mov    %edi,%eax
  (bad)
  add    %dl,(%rax)
  add    (%rax),%al
  add    %al,(%rax)
  add    %al,(%rax)
  ret
```

assistant: ```c
void host_close(int fd) {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x02"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       :
                       : "a"(fd));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<host_close>:
  endbr64
  mov    %edi,%eax
  (bad)
  add    %dl,(%rax)
  add    (%rax),%al
  add    %al,(%rax)
  add    %al,(%rax)
  ret
```

assistant: ```c
void host_close(int fd) {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, "
                       "0x10"
                       "\n"
                       ".byte "
                       "0x02"
                       ", 0x00\n"
                       ".byte 0x00, 0x00, 0x00\n"
                       ".byte 0x00\n"
                       :
                       : "a"(fd));
}
```
user: What is the c source code of the assembly code below:

```asm
<get_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L6
L57:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L35:
  subl   $0x1,-0x10(%rbp)
L6:
  cmpl   $0x0,-0x10(%rbp)
  jg     L57
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_arg(int argc, char *argv[], const char *name) {
  int len = strlen(name);
  char *ret = NULL;
  int i;
  for (i = argc - 1; i > 0; i--) {
    if (argv[i] && strncmp(argv[i], name, len) == 0 && (argv[i][len] != '\0')) {
      ret = argv[i] + len;
      break;
    }
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_arg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L61
  mov    %eax,%r13d
  movslq %ebx,%rbx
  movslq %eax,%r14
  jmp    L13
L20:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jle    L23
L13:
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L20
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L20
  mov    %r14,%rax
  add    0x0(%rbp,%rbx,8),%rax
  cmpb   $0x0,(%rax)
  je     L20
  jmp    L77
L23:
  mov    $0x0,%eax
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  mov    $0x0,%eax
  jmp    L77
```

assistant: ```c
char *get_arg(int argc, char *argv[], const char *name) {
  int len = strlen(name);
  char *ret = NULL;
  int i;
  for (i = argc - 1; i > 0; i--) {
    if (argv[i] && strncmp(argv[i], name, len) == 0 && (argv[i][len] != '\0')) {
      ret = argv[i] + len;
      break;
    }
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_arg>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rdx,%rdi
  sub    $0x1,%ebx
  call   <strlen@plt>
  test   %ebx,%ebx
  jle    L11
  mov    %eax,%r12d
  movslq %ebx,%rbx
  movslq %eax,%r14
  nopl   0x0(%rax)
L45:
  mov    0x0(%r13,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L17
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L17
  mov    0x0(%r13,%rbx,8),%rax
  add    %r14,%rax
  cmpb   $0x0,(%rax)
  jne    L37
L17:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L45
L11:
  xor    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *get_arg(int argc, char *argv[], const char *name) {
  int len = strlen(name);
  char *ret = NULL;
  int i;
  for (i = argc - 1; i > 0; i--) {
    if (argv[i] && strncmp(argv[i], name, len) == 0 && (argv[i][len] != '\0')) {
      ret = argv[i] + len;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_arg>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rdx,%rdi
  sub    $0x1,%ebx
  call   <strlen@plt>
  test   %ebx,%ebx
  jle    L31
  mov    %eax,%r12d
  movslq %ebx,%rbx
  movslq %eax,%r14
  nopl   0x0(%rax)
L22:
  mov    0x0(%r13,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L37
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L37
  mov    0x0(%r13,%rbx,8),%rax
  add    %r14,%rax
  cmpb   $0x0,(%rax)
  jne    L30
L37:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L22
L31:
  xor    %eax,%eax
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *get_arg(int argc, char *argv[], const char *name) {
  int len = strlen(name);
  char *ret = NULL;
  int i;
  for (i = argc - 1; i > 0; i--) {
    if (argv[i] && strncmp(argv[i], name, len) == 0 && (argv[i][len] != '\0')) {
      ret = argv[i] + len;
      break;
    }
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<btktermio_get_cols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  mov    (%rax),%ecx
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int btktermio_get_cols(void) {
  struct winsize w;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
  return w.ws_col;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<btktermio_get_cols>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int btktermio_get_cols(void) {
  struct winsize w;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
  return w.ws_col;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<btktermio_get_cols>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D13(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int btktermio_get_cols(void) {
  struct winsize w;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
  return w.ws_col;
}
```
user: Translate the below assembly code into C programming language:

```asm
<btktermio_get_cols>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int btktermio_get_cols(void) {
  struct winsize w;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
  return w.ws_col;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L57:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L57
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x9c5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x9c5c(%rbp),%edx
  mov    -0x9c5c(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x9c58(%rbp)
  jmp    L55
L19:
  movl   $0x0,-0x9c54(%rbp)
  jmp    L16
L13:
  lea    -0x9c50(%rbp),%rcx
  mov    -0x9c54(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c58(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x9c54(%rbp)
L16:
  mov    -0x9c5c(%rbp),%eax
  cmp    %eax,-0x9c54(%rbp)
  jl     L13
  addl   $0x1,-0x9c58(%rbp)
L55:
  mov    -0x9c5c(%rbp),%eax
  cmp    %eax,-0x9c58(%rbp)
  jl     L19
  mov    -0x9c5c(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <prim@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D31
type_guessed: string

tool: D11: Prim Algorithm

tool: D16: Enter number of vertices

tool: D34: %d

tool: D31: Enter %d X %d adj matrix


assistant: ```c
int main() {
  printf("Prim Algorithm\n");
  int arr[100][100], N;
  int i, j;
  printf("Enter number of vertices\n");
  scanf("%d", &N);
  printf("Enter %d X %d adj matrix\n", N, N);
  for (i = 0; i < N; i++)
    for (j = 0; j < N; j++)
      scanf("%d", &arr[i][j]);
  prim(arr, N);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L62:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L62
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %esi,%edx
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D26(%rip),%r12
  test   %esi,%esi
  jg     L53
L17:
  lea    0x10(%rsp),%rdi
  call   <prim@plt>
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  mov    $0x0,%eax
  add    $0x9c60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    0x10(%rsp,%r14,4),%rbp
  mov    $0x0,%ebx
L68:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L68
L22:
  add    $0x1,%r13d
  mov    0xc(%rsp),%esi
  add    $0x64,%r14
  cmp    %r13d,%esi
  jle    L17
L53:
  cmpl   $0x0,0xc(%rsp)
  jg     L21
  jmp    L22
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string

tool: D9: Prim Algorithm

tool: D23: Enter number of vertices

tool: D26: %d

tool: D15: Enter %d X %d adj matrix


assistant: ```c
int main() {
  printf("Prim Algorithm\n");
  int arr[100][100], N;
  int i, j;
  printf("Enter number of vertices\n");
  scanf("%d", &N);
  printf("Enter %d X %d adj matrix\n", N, N);
  for (i = 0; i < N; i++)
    for (j = 0; j < N; j++)
      scanf("%d", &arr[i][j]);
  prim(arr, N);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L28:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L28
  sub    $0xc68,%rsp
  lea    D31(%rip),%rdi
  lea    D15(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L29
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    0x10(%rsp),%r15
  nopl   0x0(%rax)
L34:
  lea    (%r15,%r14,4),%rbp
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L54
  add    $0x1,%r13d
  add    $0x64,%r14
  cmp    %r13d,%esi
  jle    L29
  test   %esi,%esi
  jg     L34
L29:
  mov    %r15,%rdi
  call   <prim@plt>
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x9c68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D31
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D38
type: string

tool: D31: Prim Algorithm

tool: D15: %d

tool: D12: Enter number of vertices

tool: D38: Enter %d X %d adj matrix


assistant: ```c
int main() {
  printf("Prim Algorithm\n");
  int arr[100][100], N;
  int i, j;
  printf("Enter number of vertices\n");
  scanf("%d", &N);
  printf("Enter %d X %d adj matrix\n", N, N);
  for (i = 0; i < N; i++)
    for (j = 0; j < N; j++)
      scanf("%d", &arr[i][j]);
  prim(arr, N);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0xc68,%rsp
  lea    D11(%rip),%rdi
  xor    %r13d,%r13d
  xor    %r14d,%r14d
  lea    D6(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L13
  nopl   0x0(%rax)
L46:
  lea    (%r15,%r13,4),%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L17
  add    $0x1,%r14d
  cmp    %r14d,%esi
  jle    L13
  add    $0x64,%r13
  jmp    L46
  nopl   0x0(%rax)
L13:
  mov    %r15,%rdi
  call   <prim@plt>
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x9c68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string
name: retrieve_data
arguments: label: D33
datatype: string

tool: D11: Prim Algorithm

tool: D6: %d

tool: D29: Enter number of vertices

tool: D33: Enter %d X %d adj matrix


assistant: ```c
int main() {
  printf("Prim Algorithm\n");
  int arr[100][100], N;
  int i, j;
  printf("Enter number of vertices\n");
  scanf("%d", &N);
  printf("Enter %d X %d adj matrix\n", N, N);
  for (i = 0; i < N; i++)
    for (j = 0; j < N; j++)
      scanf("%d", &arr[i][j]);
  prim(arr, N);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <comput@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string

tool: D7: 431-5*+

tool: D19: 4+(3-1)*5=%d


assistant: ```c
int main3(void) {
  int ret = comput("431-5*+");
  printf("4+(3-1)*5=%d\n", ret);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main3>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <comput@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D19: 431-5*+

tool: D3: 4+(3-1)*5=%d


assistant: ```c
int main3(void) {
  int ret = comput("431-5*+");
  printf("4+(3-1)*5=%d\n", ret);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main3>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <comput@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string

tool: D7: 431-5*+

tool: D13: 4+(3-1)*5=%d


assistant: ```c
int main3(void) {
  int ret = comput("431-5*+");
  printf("4+(3-1)*5=%d\n", ret);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main3>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <comput@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D1: 431-5*+

tool: D19: 4+(3-1)*5=%d


assistant: ```c
int main3(void) {
  int ret = comput("431-5*+");
  printf("4+(3-1)*5=%d\n", ret);
  return 0;
}
```