ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<version_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x30(%rbp)
  jmp    L34
L26:
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x20(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L90
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  jmp    L46
L90:
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x30(%rbp)
L34:
  cmpq   $0x0,-0x28(%rbp)
  je     L12
  cmpq   $0x0,-0x30(%rbp)
  jne    L26
L12:
  cmpq   $0x0,-0x28(%rbp)
  je     L87
  mov    $0xffffffff,%eax
  jmp    L46
L87:
  cmpq   $0x0,-0x30(%rbp)
  je     L66
  mov    $0x1,%eax
  jmp    L46
L66:
  mov    $0x0,%eax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_infered: string

tool: D10: 0123456789

assistant: ```c
int version_compare(const char *a, const char *b) {
  char *at, *bt;
  int aval, bval;
  a = strpbrk(a, "0123456789");
  b = strpbrk(b, "0123456789");
  while (a && b) {
    aval = strtol(a, &at, 10);
    bval = strtol(b, &bt, 10);
    if (aval != bval) {
      return bval - aval;
    }
    a = strpbrk(at, "0123456789");
    b = strpbrk(bt, "0123456789");
  }
  if (a) {
    return -1;
  }
  if (b) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<version_compare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%r12
  mov    %r12,%rsi
  call   <strpbrk@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  je     L63
  test   %rax,%rax
  je     L63
L87:
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %eax,%ebx
  lea    0x10(%rsp),%rsi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <strtol@plt>
  cmp    %eax,%ebx
  jne    L25
  mov    %r12,%rsi
  mov    0x8(%rsp),%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    0x10(%rsp),%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  je     L63
  test   %rax,%rax
  jne    L87
L63:
  test   %rbx,%rbx
  jne    L33
  test   %rbp,%rbp
  setne  %al
  movzbl %al,%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  sub    %ebx,%eax
  jmp    L39
L33:
  mov    $0xffffffff,%eax
  jmp    L39
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: 0123456789

assistant: ```c
int version_compare(const char *a, const char *b) {
  char *at, *bt;
  int aval, bval;
  a = strpbrk(a, "0123456789");
  b = strpbrk(b, "0123456789");
  while (a && b) {
    aval = strtol(a, &at, 10);
    bval = strtol(b, &bt, 10);
    if (aval != bval) {
      return bval - aval;
    }
    a = strpbrk(at, "0123456789");
    b = strpbrk(bt, "0123456789");
  }
  if (a) {
    return -1;
  }
  if (b) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<version_compare>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strpbrk@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  mov    %rax,%r12
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  test   %r12,%r12
  je     L1
  lea    0x8(%rsp),%r14
  lea    0x10(%rsp),%r13
  jmp    L6
  nopl   0x0(%rax)
L28:
  mov    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strpbrk@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %rax,%r12
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %r12,%r12
  je     L1
  test   %rax,%rax
  je     L5
L6:
  mov    %r12,%rdi
  mov    $0xa,%edx
  mov    %r14,%rsi
  call   <strtol@plt>
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strtol@plt>
  cmp    %eax,%r12d
  je     L28
  sub    %r12d,%eax
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  test   %r12,%r12
  jne    L52
L1:
  xor    %eax,%eax
  test   %rbp,%rbp
  setne  %al
L52:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: 0123456789

assistant: ```c
int version_compare(const char *a, const char *b) {
  char *at, *bt;
  int aval, bval;
  a = strpbrk(a, "0123456789");
  b = strpbrk(b, "0123456789");
  while (a && b) {
    aval = strtol(a, &at, 10);
    bval = strtol(b, &bt, 10);
    if (aval != bval) {
      return bval - aval;
    }
    a = strpbrk(at, "0123456789");
    b = strpbrk(bt, "0123456789");
  }
  if (a) {
    return -1;
  }
  if (b) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<version_compare>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strpbrk@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strpbrk@plt>
  test   %rax,%rax
  setne  %dl
  test   %r13,%r13
  je     L18
  test   %dl,%dl
  je     L18
  mov    %rax,%r14
  lea    0x8(%rsp),%r12
  lea    0x10(%rsp),%rbp
  jmp    L19
  xchg   %ax,%ax
L25:
  mov    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strpbrk@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %rax,%r13
  call   <strpbrk@plt>
  test   %rax,%rax
  mov    %rax,%r14
  setne  %dl
  test   %r13,%r13
  je     L18
  test   %dl,%dl
  je     L18
L19:
  mov    %r13,%rdi
  mov    $0xa,%edx
  mov    %r12,%rsi
  call   <strtol@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strtol@plt>
  cmp    %eax,%r13d
  je     L25
  sub    %r13d,%eax
  jmp    L22
  nopl   0x0(%rax)
L18:
  movzbl %dl,%edx
  test   %r13,%r13
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: 0123456789

assistant: ```c
int version_compare(const char *a, const char *b) {
  char *at, *bt;
  int aval, bval;
  a = strpbrk(a, "0123456789");
  b = strpbrk(b, "0123456789");
  while (a && b) {
    aval = strtol(a, &at, 10);
    bval = strtol(b, &bt, 10);
    if (aval != bval) {
      return bval - aval;
    }
    a = strpbrk(at, "0123456789");
    b = strpbrk(bt, "0123456789");
  }
  if (a) {
    return -1;
  }
  if (b) {
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test(5);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(5);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(5);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(5);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sat_extend_resize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L2
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  not    %rax
  mov    %rdx,%rcx
  and    %rax,%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sat_realloc2@plt>
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sat_extend_resize(void *buf, size_t len, size_t size, size_t block) {
  if (len)
    buf = sat_realloc2(buf, (len + block) & ~block, size);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sat_extend_resize>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L0
  ret
L0:
  sub    $0x8,%rsp
  add    %rcx,%rsi
  not    %rcx
  and    %rcx,%rsi
  call   <sat_realloc2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *sat_extend_resize(void *buf, size_t len, size_t size, size_t block) {
  if (len)
    buf = sat_realloc2(buf, (len + block) & ~block, size);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sat_extend_resize>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L0
  ret
  nopl   (%rax)
L0:
  add    %rcx,%rsi
  not    %rcx
  and    %rcx,%rsi
  jmp    1050 <sat_realloc2@plt>
```

assistant: ```c
void *sat_extend_resize(void *buf, size_t len, size_t size, size_t block) {
  if (len)
    buf = sat_realloc2(buf, (len + block) & ~block, size);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sat_extend_resize>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L0
  ret
  nopl   (%rax)
L0:
  add    %rcx,%rsi
  not    %rcx
  and    %rcx,%rsi
  jmp    1050 <sat_realloc2@plt>
```

assistant: ```c
void *sat_extend_resize(void *buf, size_t len, size_t size, size_t block) {
  if (len)
    buf = sat_realloc2(buf, (len + block) & ~block, size);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L16
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jge    L3
  movsbl -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <string_insert_char@plt>
  jmp    L23
L3:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L38
  movsbl -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <string_insert_char@plt>
L23:
  leave
  ret
```

assistant: ```c
void insert(char symbol, char *set, int limit) {
  int i;
  for (i = 1; i < limit; i++) {
    if (symbol < set[i]) {
      string_insert_char(set, symbol, i);
      return;
    }
  }
  string_insert_char(set, symbol, limit);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insert>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r9d
  mov    %rsi,%rdi
  mov    %edx,%r10d
  cmp    $0x1,%edx
  jle    L35
  mov    %r9d,%ecx
  mov    %edx,%r8d
  mov    $0x1,%eax
L36:
  mov    %eax,%edx
  cmp    %cl,(%rdi,%rax,1)
  jg     L22
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L36
L35:
  movsbl %r9b,%esi
  mov    %r10d,%edx
  call   <string_insert_char@plt>
L13:
  add    $0x8,%rsp
  ret
L22:
  movsbl %r9b,%esi
  call   <string_insert_char@plt>
  jmp    L13
```

assistant: ```c
void insert(char symbol, char *set, int limit) {
  int i;
  for (i = 1; i < limit; i++) {
    if (symbol < set[i]) {
      string_insert_char(set, symbol, i);
      return;
    }
  }
  string_insert_char(set, symbol, limit);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<insert>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%r10d
  mov    %rsi,%rdi
  mov    %r9d,%ecx
  cmp    $0x1,%edx
  jle    L12
  movslq %edx,%r8
  mov    $0x1,%eax
  jmp    L22
  nop
L3:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L12
L22:
  mov    %eax,%edx
  cmp    %cl,(%rdi,%rax,1)
  jle    L3
  movsbl %r9b,%esi
  jmp    1050 <string_insert_char@plt>
  nopl   0x0(%rax)
L12:
  movsbl %r9b,%esi
  mov    %r10d,%edx
  jmp    1050 <string_insert_char@plt>
```

assistant: ```c
void insert(char symbol, char *set, int limit) {
  int i;
  for (i = 1; i < limit; i++) {
    if (symbol < set[i]) {
      string_insert_char(set, symbol, i);
      return;
    }
  }
  string_insert_char(set, symbol, limit);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<insert>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%r10d
  mov    %rsi,%rdi
  mov    %r9d,%ecx
  cmp    $0x1,%edx
  jle    L27
  movslq %edx,%r8
  mov    $0x1,%eax
  jmp    L35
  nop
L1:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L27
L35:
  mov    %eax,%edx
  cmp    %cl,(%rdi,%rax,1)
  jle    L1
  movsbl %r9b,%esi
  jmp    1050 <string_insert_char@plt>
  nopl   0x0(%rax)
L27:
  movsbl %r9b,%esi
  mov    %r10d,%edx
  jmp    1050 <string_insert_char@plt>
```

assistant: ```c
void insert(char symbol, char *set, int limit) {
  int i;
  for (i = 1; i < limit; i++) {
    if (symbol < set[i]) {
      string_insert_char(set, symbol, i);
      return;
    }
  }
  string_insert_char(set, symbol, limit);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ho_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L17:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x28(%rbp)
L42:
  cmpq   $0x0,-0x28(%rbp)
  je     L14
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  jmp    L14
L0:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L14:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ho_strncpy(char *s1, const char *s2, size_t n) {
  char *s = s1;
  for (; n && (*s1 = *s2) != '\0'; n--) {
    s1++, s2++;
  }
  while (n--) {
    *s1++ = '\0';
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ho_strncpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  test   %rdx,%rdx
  je     L38
L28:
  movzbl (%rsi),%r8d
  mov    %r8b,(%rcx)
  test   %r8b,%r8b
  je     L43
  add    $0x1,%rcx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  jne    L28
  ret
L38:
  ret
L43:
  test   %rdx,%rdx
  je     L46
  add    %rcx,%rdx
L27:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L27
  ret
L46:
  ret
```

assistant: ```c
char *ho_strncpy(char *s1, const char *s2, size_t n) {
  char *s = s1;
  for (; n && (*s1 = *s2) != '\0'; n--) {
    s1++, s2++;
  }
  while (n--) {
    *s1++ = '\0';
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ho_strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdx,%rdx
  jne    L27
  jmp    L11
L3:
  add    $0x1,%rdi
  add    $0x1,%rsi
  test   %rdx,%rdx
  je     L11
L27:
  movzbl (%rsi),%eax
  mov    %rdx,%r8
  sub    $0x1,%rdx
  mov    %al,(%rdi)
  test   %al,%al
  jne    L3
  mov    %r8,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L11:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ho_strncpy(char *s1, const char *s2, size_t n) {
  char *s = s1;
  for (; n && (*s1 = *s2) != '\0'; n--) {
    s1++, s2++;
  }
  while (n--) {
    *s1++ = '\0';
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ho_strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdx,%rdx
  jne    L6
  jmp    L7
L4:
  add    $0x1,%rdi
  add    $0x1,%rsi
  test   %rdx,%rdx
  je     L7
L6:
  movzbl (%rsi),%eax
  mov    %rdx,%r8
  sub    $0x1,%rdx
  mov    %al,(%rdi)
  test   %al,%al
  jne    L4
  mov    %r8,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L7:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ho_strncpy(char *s1, const char *s2, size_t n) {
  char *s = s1;
  for (; n && (*s1 = *s2) != '\0'; n--) {
    s1++, s2++;
  }
  while (n--) {
    *s1++ = '\0';
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rusagesub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x10(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <timersub@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <timersub@plt>
  nop
  leave
  ret
```

assistant: ```c
void rusagesub(struct rusage *end, struct rusage *start, struct rusage *diff) {
  diff->ru_nvcsw = end->ru_nvcsw - start->ru_nvcsw;
  diff->ru_nivcsw = end->ru_nivcsw - start->ru_nivcsw;
  timersub(&end->ru_utime, &start->ru_utime, &diff->ru_utime);
  timersub(&end->ru_stime, &start->ru_stime, &diff->ru_stime);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rusagesub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    0x10(%rdi),%rax
  sub    0x10(%rsi),%rax
  mov    %rax,0x10(%rdx)
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  mov    %rax,0x8(%rdx)
  lea    0x4(%rdx),%rdx
  lea    0x4(%rsi),%rsi
  lea    0x4(%rdi),%rdi
  call   <timersub@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <timersub@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rusagesub(struct rusage *end, struct rusage *start, struct rusage *diff) {
  diff->ru_nvcsw = end->ru_nvcsw - start->ru_nvcsw;
  diff->ru_nivcsw = end->ru_nivcsw - start->ru_nivcsw;
  timersub(&end->ru_utime, &start->ru_utime, &diff->ru_utime);
  timersub(&end->ru_stime, &start->ru_stime, &diff->ru_stime);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rusagesub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  lea    0x4(%rdx),%rdx
  push   %r12
  mov    %rsi,%r12
  lea    0x4(%rsi),%rsi
  push   %rbp
  mov    0x10(%rdi),%rax
  mov    %rdi,%rbp
  lea    0x4(%rdi),%rdi
  sub    0xc(%rsi),%rax
  mov    %rax,0xc(%rdx)
  mov    0x4(%rdi),%rax
  sub    0x4(%rsi),%rax
  mov    %rax,0x4(%rdx)
  call   <timersub@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <timersub@plt>
```

assistant: ```c
void rusagesub(struct rusage *end, struct rusage *start, struct rusage *diff) {
  diff->ru_nvcsw = end->ru_nvcsw - start->ru_nvcsw;
  diff->ru_nivcsw = end->ru_nivcsw - start->ru_nivcsw;
  timersub(&end->ru_utime, &start->ru_utime, &diff->ru_utime);
  timersub(&end->ru_stime, &start->ru_stime, &diff->ru_stime);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rusagesub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  lea    0x4(%rdx),%rdx
  push   %r12
  mov    %rsi,%r12
  lea    0x4(%rsi),%rsi
  push   %rbp
  movdqu 0x8(%rdi),%xmm0
  mov    %rdi,%rbp
  lea    0x4(%rdi),%rdi
  movdqu 0x4(%rsi),%xmm1
  psubq  %xmm1,%xmm0
  movups %xmm0,0x4(%rdx)
  call   <timersub@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <timersub@plt>
```

assistant: ```c
void rusagesub(struct rusage *end, struct rusage *start, struct rusage *diff) {
  diff->ru_nvcsw = end->ru_nvcsw - start->ru_nvcsw;
  diff->ru_nivcsw = end->ru_nivcsw - start->ru_nivcsw;
  timersub(&end->ru_utime, &start->ru_utime, &diff->ru_utime);
  timersub(&end->ru_stime, &start->ru_stime, &diff->ru_stime);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0xd0(%rbp)
  movl   $0x30,-0xcc(%rbp)
  lea    0x10(%rbp),%rax
  mov    %rax,-0xc8(%rbp)
  lea    -0xb0(%rbp),%rax
  mov    %rax,-0xc0(%rbp)
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void foo(int i, ...) {
  __builtin_va_list ap;
  __builtin_va_start(ap, i);
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int i, ...) {
  __builtin_va_list ap;
  __builtin_va_start(ap, i);
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int i, ...) {
  __builtin_va_list ap;
  __builtin_va_start(ap, i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int i, ...) {
  __builtin_va_list ap;
  __builtin_va_start(ap, i);
}
```