user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  sub    $0x98,%rsp
  movsd  D78(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D78(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D149(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D149(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D243(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D243(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D156(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D156(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D62(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D62(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D22(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D22(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D88(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D88(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D213(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D213(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D116(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D116(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D9(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D70(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D70(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  movsd  D93(%rip),%xmm0
  mov    %r12,%rdi
  call   <dollar_text@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  mov    D93(%rip),%rax
  movq   %rax,%xmm0
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D78
type: f64
name: parse_data
arguments: data_label: D149
type: f64
name: parse_data
arguments: data_label: D243
type: f64
name: parse_data
arguments: data_label: D156
type: f64
name: parse_data
arguments: data_label: D62
type: f64
name: parse_data
arguments: data_label: D22
type: f64
name: parse_data
arguments: data_label: D88
type: f64
name: parse_data
arguments: data_label: D213
type: f64
name: parse_data
arguments: data_label: D116
type: f64
name: parse_data
arguments: data_label: D9
type: f64
name: parse_data
arguments: data_label: D70
type: f64
name: parse_data
arguments: data_label: D93
type: f64

tool: D3: %.2lf is %s


tool: D78: 0.12

tool: D149: 1.23

tool: D243: 2.34

tool: D156: 12.34

tool: D62: 112.34

tool: D22: 123.45

tool: D88: 1234.56

tool: D213: 9999.99

tool: D116: 10000

tool: D9: 100000

tool: D70: 123456.78

tool: D93: 999999.99

assistant: ```c
int main(void) {
  double dollar;
  char destination[128];
  dollar = 0.12;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 1.23;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 2.34;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 12.34;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 112.34;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 123.45;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 1234.56;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 9999.99;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 10000.00;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 100000.00;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 123456.78;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  dollar = 999999.99;
  printf("%.2lf is %s\n", dollar, dollar_text(destination, dollar));
  return 0;
}
```