ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <STK_newStack@plt>
  mov    %r12,%rsi
  movl   $0x4,0x4(%rsp)
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <STK_push@plt>
  mov    %rbp,%rdi
  call   <STK_size@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_top@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %rbx,%r12
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_pop@plt>
  mov    %rbp,%rdi
  call   <STK_size@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_deleteStack@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct Stack *testStack = STK_newStack();
  int testInt = 4;
  STK_push(testStack, &testInt);
  assert(STK_size(testStack) == 1);
  int *testPtr = (int *)STK_top(testStack);
  assert(testPtr != NULL);
  assert(testPtr == &testInt);
  STK_pop(testStack);
  assert(STK_size(testStack) == 0);
  STK_deleteStack(testStack);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <STK_newStack@plt>
  mov    %r12,%rsi
  movl   $0x4,0x4(%rsp)
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <STK_push@plt>
  mov    %rbp,%rdi
  call   <STK_size@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_top@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %rbx,%r12
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_pop@plt>
  mov    %rbp,%rdi
  call   <STK_size@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <STK_deleteStack@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct Stack *testStack = STK_newStack();
  int testInt = 4;
  STK_push(testStack, &testInt);
  assert(STK_size(testStack) == 1);
  int *testPtr = (int *)STK_top(testStack);
  assert(testPtr != NULL);
  assert(testPtr == &testInt);
  STK_pop(testStack);
  assert(STK_size(testStack) == 0);
  STK_deleteStack(testStack);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L79
L69:
  addl   $0x1,-0x8(%rbp)
L79:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  jmp    L50
L74:
  addl   $0x1,-0x4(%rbp)
L50:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L74
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L63
  mov    $0x0,%eax
  jmp    L47
L2:
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L63
  mov    $0x0,%eax
  jmp    L47
L63:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jns    L2
  mov    $0x1,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  int i, j;
  i = 0;
  j = 0;
  while (*(++s) != '\0')
    ++i;
  while (*(++t) != '\0')
    ++j;
  if (j > i)
    return 0;
  while (j-- >= 0)
    if (*(--s) != *(--t))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strend>:
  endbr64
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,0x1(%rdi)
  je     L60
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L38:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L38
L39:
  lea    0x1(%rsi),%r8
  cmpb   $0x0,0x1(%rsi)
  je     L67
  mov    %r8,%rdx
  mov    $0x1,%ecx
  sub    %r8d,%ecx
L28:
  lea    (%rcx,%rdx,1),%esi
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L28
L27:
  mov    $0x0,%ecx
  cmp    %esi,%edi
  jl     L69
  mov    $0xffffffffffffffff,%rcx
  add    $0x1,%esi
L74:
  mov    %esi,%edi
  add    %ecx,%edi
  js     L99
  movzbl (%rax,%rcx,1),%edi
  sub    $0x1,%rcx
  cmp    0x1(%rdx,%rcx,1),%dil
  je     L74
  mov    $0x0,%ecx
  jmp    L69
L60:
  mov    %rcx,%rax
  mov    $0x0,%edi
  jmp    L39
L67:
  mov    %r8,%rdx
  mov    $0x0,%esi
  jmp    L27
L99:
  mov    $0x1,%ecx
L69:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  int i, j;
  i = 0;
  j = 0;
  while (*(++s) != '\0')
    ++i;
  while (*(++t) != '\0')
    ++j;
  if (j > i)
    return 0;
  while (j-- >= 0)
    if (*(--s) != *(--t))
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strend>:
  endbr64
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L76
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L15:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L15
L46:
  cmpb   $0x0,0x1(%rsi)
  lea    0x1(%rsi),%rdx
  je     L4
  mov    $0x1,%ecx
  sub    %edx,%ecx
  nopl   (%rax)
L62:
  lea    (%rcx,%rdx,1),%esi
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L62
  xor    %r8d,%r8d
  cmp    %esi,%edi
  jl     L64
L1:
  mov    $0xffffffffffffffff,%rcx
  lea    0x1(%rsi),%edi
  jmp    L87
  nop
L83:
  movzbl (%rax,%rcx,1),%esi
  sub    $0x1,%rcx
  cmp    0x1(%rdx,%rcx,1),%sil
  jne    L95
L87:
  mov    %edi,%esi
  add    %ecx,%esi
  jns    L83
  mov    $0x1,%r8d
L64:
  mov    %r8d,%eax
  ret
  nop
L95:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %esi,%esi
  jmp    L1
  nopl   0x0(%rax)
L76:
  xor    %edi,%edi
  jmp    L46
```

assistant: ```c
int strend(char *s, char *t) {
  int i, j;
  i = 0;
  j = 0;
  while (*(++s) != '\0')
    ++i;
  while (*(++t) != '\0')
    ++j;
  if (j > i)
    return 0;
  while (j-- >= 0)
    if (*(--s) != *(--t))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strend>:
  endbr64
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L37
  mov    $0x1,%edx
  sub    %eax,%edx
  nopl   0x0(%rax)
L86:
  lea    (%rdx,%rax,1),%edi
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L86
L75:
  cmpb   $0x0,0x1(%rsi)
  lea    0x1(%rsi),%rdx
  je     L88
  mov    $0x1,%ecx
  sub    %edx,%ecx
  nopl   (%rax)
L20:
  lea    (%rcx,%rdx,1),%esi
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L20
  xor    %r8d,%r8d
  cmp    %esi,%edi
  jl     L98
L3:
  mov    $0xffffffffffffffff,%rcx
  lea    0x1(%rsi),%edi
  jmp    L72
  nop
L24:
  movzbl (%rax,%rcx,1),%esi
  sub    $0x1,%rcx
  cmp    0x1(%rdx,%rcx,1),%sil
  jne    L35
L72:
  mov    %edi,%esi
  add    %ecx,%esi
  jns    L24
  mov    $0x1,%r8d
L98:
  mov    %r8d,%eax
  ret
  nop
L35:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L88:
  xor    %esi,%esi
  jmp    L3
  nopl   0x0(%rax)
L37:
  xor    %edi,%edi
  jmp    L75
```

assistant: ```c
int strend(char *s, char *t) {
  int i, j;
  i = 0;
  j = 0;
  while (*(++s) != '\0')
    ++i;
  while (*(++t) != '\0')
    ++j;
  if (j > i)
    return 0;
  while (j-- >= 0)
    if (*(--s) != *(--t))
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <get_section_by_name@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <hexdump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D23
type: string
name: disassemble_data
arguments: data_tag: D27
type: string

tool: D6: .text

tool: D23: ./a.out

tool: D27: Result from get_section_by_name (%u bytes):


assistant: ```c
int main() {
  size_t size;
  void *result = get_section_by_name("./a.out", ".text", &size);
  printf("Result from get_section_by_name (%u bytes):\n", size);
  hexdump(1, result, size);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    D16(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <get_section_by_name@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rdx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <hexdump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string
name: read_data
arguments: data_tag: D24
data_type: string

tool: D16: .text

tool: D27: ./a.out

tool: D24: Result from get_section_by_name (%u bytes):


assistant: ```c
int main() {
  size_t size;
  void *result = get_section_by_name("./a.out", ".text", &size);
  printf("Result from get_section_by_name (%u bytes):\n", size);
  hexdump(1, result, size);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rsi
  lea    D27(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <get_section_by_name@plt>
  mov    (%rsp),%rsi
  lea    D24(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rdx
  mov    $0x1,%edi
  mov    %rbp,%rsi
  call   <hexdump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D24
type_infered: string

tool: D13: .text

tool: D27: ./a.out

tool: D24: Result from get_section_by_name (%u bytes):


assistant: ```c
int main() {
  size_t size;
  void *result = get_section_by_name("./a.out", ".text", &size);
  printf("Result from get_section_by_name (%u bytes):\n", size);
  hexdump(1, result, size);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rsi
  lea    D15(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <get_section_by_name@plt>
  mov    (%rsp),%rsi
  lea    D8(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rdx
  mov    $0x1,%edi
  mov    %rbp,%rsi
  call   <hexdump@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D3: .text

tool: D15: ./a.out

tool: D8: Result from get_section_by_name (%u bytes):


assistant: ```c
int main() {
  size_t size;
  void *result = get_section_by_name("./a.out", ".text", &size);
  printf("Result from get_section_by_name (%u bytes):\n", size);
  hexdump(1, result, size);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nextchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  jmp    L25
L2:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L2
L9:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *nextchar(const char *string, char tok) {
  while (*string != 0 && *string != tok)
    string++;
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextchar>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  movzbl (%rdi),%edx
  cmp    %sil,%dl
  je     L30
  test   %dl,%dl
  je     L30
L14:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L30
  test   %dl,%dl
  jne    L14
L30:
  ret
```

assistant: ```c
const char *nextchar(const char *string, char tok) {
  while (*string != 0 && *string != tok)
    string++;
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nextchar>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    %sil,%dl
  jne    L7
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L2
L7:
  test   %dl,%dl
  jne    L13
L2:
  ret
```

assistant: ```c
const char *nextchar(const char *string, char tok) {
  while (*string != 0 && *string != tok)
    string++;
  return string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nextchar>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    %sil,%dl
  jne    L0
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L1
L0:
  test   %dl,%dl
  jne    L38
L1:
  ret
```

assistant: ```c
const char *nextchar(const char *string, char tok) {
  while (*string != 0 && *string != tok)
    string++;
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ML_display_vram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0xb4000000,%eax
  mov    %rax,-0x10(%rbp)
  mov    $0xb4010000,%eax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <ML_vram_adress@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L21
L0:
  mov    -0x10(%rbp),%rax
  movb   $0x4,(%rax)
  mov    -0x20(%rbp),%eax
  or     $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movb   $0x4,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movb   $0x7,(%rax)
  movl   $0x0,-0x1c(%rbp)
  jmp    L24
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x1c(%rbp)
L24:
  cmpl   $0xf,-0x1c(%rbp)
  jle    L15
  addl   $0x1,-0x20(%rbp)
L21:
  cmpl   $0x3f,-0x20(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void ML_display_vram() {
  char *LCD_register_selector = (char *)0xB4000000, *LCD_data_register = (char *)0xB4010000, *vram;
  int i, j;
  vram = ML_vram_adress();
  for (i = 0; i < 64; i++) {
    *LCD_register_selector = 4;
    *LCD_data_register = i | 192;
    *LCD_register_selector = 4;
    *LCD_data_register = 0;
    *LCD_register_selector = 7;
    for (j = 0; j < 16; j++)
      *LCD_data_register = *vram++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ML_display_vram>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ML_vram_adress@plt>
  mov    %rax,%rdi
  lea    0x10(%rax),%rcx
  add    $0x410,%rdi
  mov    $0xb4010000,%esi
  mov    $0xb4000000,%r8d
  jmp    L31
L27:
  add    $0x10,%rcx
  cmp    %rdi,%rcx
  je     L39
L31:
  lea    -0x10(%rcx),%rax
  movb   $0x0,(%rsi)
  movb   $0x7,(%r8)
L28:
  add    $0x1,%rax
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rsi)
  cmp    %rcx,%rax
  jne    L28
  jmp    L27
L39:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ML_display_vram() {
  char *LCD_register_selector = (char *)0xB4000000, *LCD_data_register = (char *)0xB4010000, *vram;
  int i, j;
  vram = ML_vram_adress();
  for (i = 0; i < 64; i++) {
    *LCD_register_selector = 4;
    *LCD_data_register = i | 192;
    *LCD_register_selector = 4;
    *LCD_data_register = 0;
    *LCD_register_selector = 7;
    for (j = 0; j < 16; j++)
      *LCD_data_register = *vram++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ML_display_vram>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ML_vram_adress@plt>
  mov    $0xb4010000,%esi
  mov    %rax,%rdi
  lea    0x10(%rax),%rcx
  add    $0x410,%rdi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0xb4010000,%edx
  lea    -0x10(%rcx),%rax
  movb   $0x0,(%rdx)
  movb   $0x7,-0x10000(%rdx)
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rax),%edx
  add    $0x1,%rax
  mov    %dl,(%rsi)
  cmp    %rcx,%rax
  jne    L16
  lea    0x10(%rax),%rcx
  cmp    %rdi,%rcx
  jne    L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ML_display_vram() {
  char *LCD_register_selector = (char *)0xB4000000, *LCD_data_register = (char *)0xB4010000, *vram;
  int i, j;
  vram = ML_vram_adress();
  for (i = 0; i < 64; i++) {
    *LCD_register_selector = 4;
    *LCD_data_register = i | 192;
    *LCD_register_selector = 4;
    *LCD_data_register = 0;
    *LCD_register_selector = 7;
    for (j = 0; j < 16; j++)
      *LCD_data_register = *vram++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ML_display_vram>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ML_vram_adress@plt>
  mov    $0xb4010000,%edx
  lea    0x400(%rax),%rsi
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xb4010000,%edi
  add    $0x10,%rax
  movb   $0x0,(%rdi)
  movb   $0x7,-0x10000(%rdi)
  movzbl -0x10(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xf(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xe(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xd(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xc(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xb(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0xa(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x9(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x8(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x7(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x6(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x5(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x4(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x3(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x2(%rax),%ecx
  mov    %cl,(%rdx)
  movzbl -0x1(%rax),%ecx
  mov    %cl,(%rdx)
  cmp    %rsi,%rax
  jne    L9
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ML_display_vram() {
  char *LCD_register_selector = (char *)0xB4000000, *LCD_data_register = (char *)0xB4010000, *vram;
  int i, j;
  vram = ML_vram_adress();
  for (i = 0; i < 64; i++) {
    *LCD_register_selector = 4;
    *LCD_data_register = i | 192;
    *LCD_register_selector = 4;
    *LCD_data_register = 0;
    *LCD_register_selector = 7;
    for (j = 0; j < 16; j++)
      *LCD_data_register = *vram++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sd_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sd_ensure_data_mode@plt>
  test   %rax,%rax
  je     L25
  mov    $0xffffffff,%eax
  jmp    L27
L25:
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sd_do_data_command@plt>
  test   %rax,%rax
  jns    L35
  mov    $0xffffffff,%eax
  jmp    L27
L35:
  mov    -0x28(%rbp),%rax
L27:
  leave
  ret
```

assistant: ```c
int sd_read(struct block_device *dev, uint8_t *buf, size_t buf_size, uint32_t block_no) {
  struct emmc_block_dev *edev = (struct emmc_block_dev *)dev;
  if (sd_ensure_data_mode(edev) != 0)
    return -1;
  if (sd_do_data_command(edev, 0, buf, buf_size, block_no) < 0)
    return -1;
  return buf_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sd_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  call   <sd_ensure_data_mode@plt>
  test   %rax,%rax
  jne    L2
  mov    %r13d,%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <sd_do_data_command@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovns %ebx,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int sd_read(struct block_device *dev, uint8_t *buf, size_t buf_size, uint32_t block_no) {
  struct emmc_block_dev *edev = (struct emmc_block_dev *)dev;
  if (sd_ensure_data_mode(edev) != 0)
    return -1;
  if (sd_do_data_command(edev, 0, buf, buf_size, block_no) < 0)
    return -1;
  return buf_size;
}
```
user: What is the c source code of the assembly code below?

```asm
<sd_read>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <sd_ensure_data_mode@plt>
  test   %rax,%rax
  jne    L26
  xor    %esi,%esi
  mov    %r13d,%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <sd_do_data_command@plt>
  test   %rax,%rax
  js     L26
  mov    %ebx,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int sd_read(struct block_device *dev, uint8_t *buf, size_t buf_size, uint32_t block_no) {
  struct emmc_block_dev *edev = (struct emmc_block_dev *)dev;
  if (sd_ensure_data_mode(edev) != 0)
    return -1;
  if (sd_do_data_command(edev, 0, buf, buf_size, block_no) < 0)
    return -1;
  return buf_size;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sd_read>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <sd_ensure_data_mode@plt>
  test   %rax,%rax
  jne    L29
  xor    %esi,%esi
  mov    %r13d,%r8d
  mov    %rbx,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <sd_do_data_command@plt>
  test   %rax,%rax
  js     L29
  mov    %ebx,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int sd_read(struct block_device *dev, uint8_t *buf, size_t buf_size, uint32_t block_no) {
  struct emmc_block_dev *edev = (struct emmc_block_dev *)dev;
  if (sd_ensure_data_mode(edev) != 0)
    return -1;
  if (sd_do_data_command(edev, 0, buf, buf_size, block_no) < 0)
    return -1;
  return buf_size;
}
```