ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trim_and_validate>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L9
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L86
  jmp    L9
  nopl   (%rax)
L58:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
L86:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L9
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L2:
  movb   $0x0,(%rbx)
  lea    -0x1(%rbx),%rax
  cmp    %r12,%rbx
  je     L62
  mov    %rax,%rbx
L28:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
L62:
  cmpb   $0x0,(%r12)
  je     L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L9:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim_and_validate(char *string) {
  size_t last;
  if (!string || string[0] == '\0')
    return NULL;
  while (isspace(*string))
    string++;
  last = strlen(string);
  if (!last)
    return NULL;
  last--;
  while (isspace(string[last])) {
    string[last] = '\0';
    if (last)
      last--;
    else
      break;
  }
  if (!*string)
    return NULL;
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trim_and_validate>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  jne    L80
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x1,%r12
L80:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L63
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L17
  lea    -0x1(%r12,%rax,1),%rbx
  jmp    L51
  nopw   0x0(%rax,%rax,1)
L44:
  movb   $0x0,(%rbx)
  lea    -0x1(%rbx),%rax
  cmp    %rbx,%r12
  je     L9
  mov    %rax,%rbx
L51:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L44
L9:
  cmpb   $0x0,(%r12)
  je     L17
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  xchg   %ax,%ax
L17:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trim_and_validate(char *string) {
  size_t last;
  if (!string || string[0] == '\0')
    return NULL;
  while (isspace(*string))
    string++;
  last = strlen(string);
  if (!last)
    return NULL;
  last--;
  while (isspace(string[last])) {
    string[last] = '\0';
    if (last)
      last--;
    else
      break;
  }
  if (!*string)
    return NULL;
  return string;
}
```
user: What is the c source code of the assembly code below?

```asm
<qcs_diffclock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double qcs_diffclock(clock_t clock1, clock_t clock2) {
  double diffticks = clock1 - clock2;
  double diffms = (diffticks) / (CLOCKS_PER_SEC / 1000);
  return diffms;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qcs_diffclock>:
  endbr64
  subsd  %xmm1,%xmm0
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double qcs_diffclock(clock_t clock1, clock_t clock2) {
  double diffticks = clock1 - clock2;
  double diffms = (diffticks) / (CLOCKS_PER_SEC / 1000);
  return diffms;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qcs_diffclock>:
  endbr64
  mov    D7(%rip),%rax
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movslq (%rax),%rax
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double qcs_diffclock(clock_t clock1, clock_t clock2) {
  double diffticks = clock1 - clock2;
  double diffms = (diffticks) / (CLOCKS_PER_SEC / 1000);
  return diffms;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<qcs_diffclock>:
  endbr64
  mov    D2(%rip),%rax
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movslq (%rax),%rax
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double qcs_diffclock(clock_t clock1, clock_t clock2) {
  double diffticks = clock1 - clock2;
  double diffms = (diffticks) / (CLOCKS_PER_SEC / 1000);
  return diffms;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<set_lmm_break>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    $0x5,%esi
  mov    $0x80,%edi
  call   <debug_cmd@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  je     L18
  mov    -0x3c(%rbp),%eax
  jmp    L29
L18:
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    -0x44(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    -0x48(%rbp),%edx
  movzbl %dl,%edx
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl %cl,%edx
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl %cl,%edx
  mov    %edx,(%rax)
  mov    -0x48(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  lea    -0x30(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <tx@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x2710,%edx
  mov    %rax,%rsi
  mov    $0xfa,%edi
  call   <rx_ack_chksum@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int set_lmm_break(int brknum, uint32_t addr) {
  int err = 0;
  uint8_t rchksum;
  uint8_t pkt[8];
  uint8_t *p = pkt;
  err = debug_cmd(0x80, 5);
  if (err != 0)
    return err;
  *p++ = brknum;
  *p++ = addr & 0xff;
  *p++ = (addr >> 8) & 0xff;
  *p++ = (addr >> 16) & 0xff;
  *p++ = (addr >> 24) & 0xff;
  tx(pkt, 5);
  err = rx_ack_chksum(0xfa, &rchksum, 10000);
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_lmm_break>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x5,%esi
  mov    $0x80,%edi
  call   <debug_cmd@plt>
  test   %eax,%eax
  je     L1
L26:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    %ebp,0x10(%rsp)
  movzbl %bl,%eax
  mov    %eax,0x14(%rsp)
  movzbl %bh,%eax
  mov    %eax,0x18(%rsp)
  mov    %ebx,%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,0x1c(%rsp)
  shr    $0x18,%ebx
  mov    %ebx,0x20(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x5,%esi
  call   <tx@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x2710,%edx
  mov    $0xfa,%edi
  call   <rx_ack_chksum@plt>
  jmp    L26
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_lmm_break(int brknum, uint32_t addr) {
  int err = 0;
  uint8_t rchksum;
  uint8_t pkt[8];
  uint8_t *p = pkt;
  err = debug_cmd(0x80, 5);
  if (err != 0)
    return err;
  *p++ = brknum;
  *p++ = addr & 0xff;
  *p++ = (addr >> 8) & 0xff;
  *p++ = (addr >> 16) & 0xff;
  *p++ = (addr >> 24) & 0xff;
  tx(pkt, 5);
  err = rx_ack_chksum(0xfa, &rchksum, 10000);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_lmm_break>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x80,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x5,%esi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <debug_cmd@plt>
  test   %eax,%eax
  jne    L0
  movzbl %bl,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x5,%esi
  mov    %ebp,0x10(%rsp)
  mov    %eax,0x14(%rsp)
  movzbl %bh,%eax
  mov    %eax,0x18(%rsp)
  mov    %ebx,%eax
  shr    $0x18,%ebx
  sar    $0x10,%eax
  mov    %ebx,0x20(%rsp)
  and    $0xff,%eax
  mov    %eax,0x1c(%rsp)
  call   <tx@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x2710,%edx
  mov    $0xfa,%edi
  call   <rx_ack_chksum@plt>
L0:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_lmm_break(int brknum, uint32_t addr) {
  int err = 0;
  uint8_t rchksum;
  uint8_t pkt[8];
  uint8_t *p = pkt;
  err = debug_cmd(0x80, 5);
  if (err != 0)
    return err;
  *p++ = brknum;
  *p++ = addr & 0xff;
  *p++ = (addr >> 8) & 0xff;
  *p++ = (addr >> 16) & 0xff;
  *p++ = (addr >> 24) & 0xff;
  tx(pkt, 5);
  err = rx_ack_chksum(0xfa, &rchksum, 10000);
  return err;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_lmm_break>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x80,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x5,%esi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <debug_cmd@plt>
  test   %eax,%eax
  jne    L9
  movzbl %bh,%eax
  movzbl %bl,%edx
  movd   %ebp,%xmm0
  mov    $0x5,%esi
  movd   %eax,%xmm1
  movd   %edx,%xmm3
  lea    0x10(%rsp),%rdi
  mov    %ebx,%eax
  sar    $0x10,%eax
  punpckldq %xmm3,%xmm0
  shr    $0x18,%ebx
  movzbl %al,%eax
  mov    %ebx,0x20(%rsp)
  movd   %eax,%xmm2
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <tx@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x2710,%edx
  mov    $0xfa,%edi
  call   <rx_ack_chksum@plt>
L9:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int set_lmm_break(int brknum, uint32_t addr) {
  int err = 0;
  uint8_t rchksum;
  uint8_t pkt[8];
  uint8_t *p = pkt;
  err = debug_cmd(0x80, 5);
  if (err != 0)
    return err;
  *p++ = brknum;
  *p++ = addr & 0xff;
  *p++ = (addr >> 8) & 0xff;
  *p++ = (addr >> 16) & 0xff;
  *p++ = (addr >> 24) & 0xff;
  tx(pkt, 5);
  err = rx_ack_chksum(0xfa, &rchksum, 10000);
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copyMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L24:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L34:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L34
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copyMatrix(int m, int n, double **from, double **to) {
  int i = 0;
  int j = 0;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      to[i][j] = from[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copyMatrix>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  jle    L20
  mov    %rdx,%rsi
  lea    -0x1(%rdi),%eax
  lea    0x8(%rdx,%rax,8),%r9
  lea    -0x1(%r8),%eax
  lea    0x8(,%rax,8),%rdi
  jmp    L31
L2:
  mov    (%rsi),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L2
L27:
  add    $0x8,%rsi
  add    $0x8,%rcx
  cmp    %r9,%rsi
  je     L20
L31:
  mov    $0x0,%eax
  test   %r8d,%r8d
  jg     L2
  jmp    L27
L20:
  ret
```

assistant: ```c
void copyMatrix(int m, int n, double **from, double **to) {
  int i = 0;
  int j = 0;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      to[i][j] = from[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copyMatrix>:
  endbr64
  test   %edi,%edi
  jle    L38
  movslq %edi,%r11
  xor    %r10d,%r10d
  movslq %esi,%r9
  nopl   0x0(%rax)
L3:
  test   %esi,%esi
  jle    L6
  mov    (%rdx,%r10,8),%r8
  mov    (%rcx,%r10,8),%rdi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L36:
  movsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L36
L6:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L3
L38:
  ret
```

assistant: ```c
void copyMatrix(int m, int n, double **from, double **to) {
  int i = 0;
  int j = 0;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      to[i][j] = from[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<copyMatrix>:
  endbr64
  test   %edi,%edi
  jle    L74
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L74
  mov    %esi,%eax
  push   %r13
  movslq %edi,%r11
  xor    %r8d,%r8d
  push   %r12
  shr    %eax
  mov    %esi,%r12d
  lea    -0x1(%r10),%r13d
  lea    -0x1(%rax),%edi
  and    $0xfffffffe,%r12d
  push   %rbp
  mov    %r10d,%r9d
  add    $0x1,%rdi
  mov    %r12d,%esi
  push   %rbx
  mov    %rcx,%rbp
  shl    $0x4,%rdi
  mov    %rdx,%rbx
  shl    $0x3,%rsi
  nopl   (%rax)
L52:
  mov    (%rbx,%r8,8),%rdx
  mov    0x0(%rbp,%r8,8),%rcx
  lea    0x8(%rdx),%rax
  cmp    %rax,%rcx
  je     L86
  xor    %eax,%eax
  cmp    $0x2,%r13d
  jbe    L86
  nopw   0x0(%rax,%rax,1)
L70:
  movupd (%rdx,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L70
  cmp    %r12d,%r10d
  je     L23
  movsd  (%rdx,%rsi,1),%xmm0
  movsd  %xmm0,(%rcx,%rsi,1)
L23:
  add    $0x1,%r8
  cmp    %r11,%r8
  jne    L52
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L86:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L41:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L41
  jmp    L23
L74:
  ret
```

assistant: ```c
void copyMatrix(int m, int n, double **from, double **to) {
  int i = 0;
  int j = 0;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      to[i][j] = from[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Finish_branch_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Distance@plt>
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Distance@plt>
  movapd %xmm0,%xmm2
  addsd  -0x30(%rbp),%xmm2
  movsd  %xmm2,-0x30(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Distance@plt>
  movsd  -0x30(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: f64

tool: D7: 0.5

assistant: ```c
double Finish_branch_length(int i, int j, int k, double **delta) {
  double length;
  length = 0.5 * (Distance(i, j, delta) + Distance(i, k, delta) - Distance(j, k, delta));
  return (length);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Finish_branch_length>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %rcx,%rbx
  mov    %rcx,%rdx
  call   <Distance@plt>
  movq   %xmm0,%r14
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <Distance@plt>
  movq   %r14,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <Distance@plt>
  movapd %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D2(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: f64

tool: D2: 0.5

assistant: ```c
double Finish_branch_length(int i, int j, int k, double **delta) {
  double length;
  length = 0.5 * (Distance(i, j, delta) + Distance(i, k, delta) - Distance(j, k, delta));
  return (length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Finish_branch_length>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edx,%r13d
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x18,%rsp
  call   <Distance@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <Distance@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %r13d,%esi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Distance@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  mulsd  D2(%rip),%xmm1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: f64

tool: D2: 0.5

assistant: ```c
double Finish_branch_length(int i, int j, int k, double **delta) {
  double length;
  length = 0.5 * (Distance(i, j, delta) + Distance(i, k, delta) - Distance(j, k, delta));
  return (length);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Finish_branch_length>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edx,%r13d
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x18,%rsp
  call   <Distance@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <Distance@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %r13d,%esi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <Distance@plt>
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  mulsd  D7(%rip),%xmm1
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: f64

tool: D7: 0.5

assistant: ```c
double Finish_branch_length(int i, int j, int k, double **delta) {
  double length;
  length = 0.5 * (Distance(i, j, delta) + Distance(i, k, delta) - Distance(j, k, delta));
  return (length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D27(%rip),%eax
  add    $0x5,%eax
  mov    %eax,D28(%rip)
  mov    D28(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int increment() {
  static int i = 45;
  i += 5;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<increment>:
  endbr64
  mov    D10(%rip),%eax
  add    $0x5,%eax
  mov    %eax,D5(%rip)
  ret
```

assistant: ```c
int increment() {
  static int i = 45;
  i += 5;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<increment>:
  endbr64
  mov    D2(%rip),%eax
  add    $0x5,%eax
  mov    %eax,D5(%rip)
  ret
```

assistant: ```c
int increment() {
  static int i = 45;
  i += 5;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<increment>:
  endbr64
  mov    D5(%rip),%eax
  add    $0x5,%eax
  mov    %eax,D2(%rip)
  ret
```

assistant: ```c
int increment() {
  static int i = 45;
  i += 5;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %edx,-0x234(%rbp)
  mov    %ecx,-0x238(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %eax,-0x214(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x234(%rbp),%ecx
  mov    -0x228(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  jmp    L14
L2:
  mov    -0x228(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x230(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  subl   $0x200,-0x238(%rbp)
L14:
  cmpl   $0x1ff,-0x238(%rbp)
  jg     L2
  cmpl   $0x0,-0x238(%rbp)
  je     L10
  mov    -0x228(%rbp),%rcx
  mov    -0x238(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x230(%rbp),%rcx
  mov    -0x238(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
L10:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x214(%rbp),%ecx
  mov    -0x228(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int dump(FILE *infile, FILE *outfile, int offset, int size) {
  char dumpbuf[512];
  int oldoff;
  oldoff = ftell(infile);
  fseek(infile, offset, SEEK_SET);
  for (; size >= 512; size -= 512) {
    fread(dumpbuf, 1, 512, infile);
    fwrite(dumpbuf, 1, 512, outfile);
  }
  if (size) {
    fread(dumpbuf, 1, size, infile);
    fwrite(dumpbuf, 1, size, outfile);
  }
  fseek(infile, oldoff, SEEK_SET);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %ecx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <ftell@plt>
  mov    %eax,%r15d
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <fseek@plt>
  cmp    $0x1ff,%r14d
  jle    L41
  mov    %r14d,%ebx
  mov    %rsp,%rbp
L9:
  mov    %r12,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  mov    %r13,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  sub    $0x200,%ebx
  cmp    $0x1ff,%ebx
  jg     L9
  and    $0x1ff,%r14d
L41:
  test   %r14d,%r14d
  jne    L13
L7:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <fseek@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    %rsp,%rbx
  mov    %r12,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %r13,%rcx
  mov    %r14d,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  jmp    L7
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump(FILE *infile, FILE *outfile, int offset, int size) {
  char dumpbuf[512];
  int oldoff;
  oldoff = ftell(infile);
  fseek(infile, offset, SEEK_SET);
  for (; size >= 512; size -= 512) {
    fread(dumpbuf, 1, 512, infile);
    fwrite(dumpbuf, 1, 512, outfile);
  }
  if (size) {
    fread(dumpbuf, 1, size, infile);
    fwrite(dumpbuf, 1, size, outfile);
  }
  fseek(infile, oldoff, SEEK_SET);
}
```