ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getNumberOfEvenlyDividingDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L38:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  jne    L38
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getNumberOfEvenlyDividingDigits(int n) {
  int copy = n;
  int count = 0;
  while (copy) {
    int digit = copy % 10;
    if (digit && 0 == (n % digit)) {
      count++;
    }
    copy /= 10;
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getNumberOfEvenlyDividingDigits>:
  endbr64
  test   %edi,%edi
  je     L27
  mov    %edi,%esi
  mov    $0x0,%r8d
  jmp    L15
L34:
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  mov    %edx,%esi
  je     L20
L15:
  movslq %esi,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%edx
  add    %edx,%edx
  mov    %esi,%ecx
  sub    %edx,%ecx
  je     L34
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r8d
  jmp    L34
L27:
  mov    %edi,%r8d
L20:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getNumberOfEvenlyDividingDigits(int n) {
  int copy = n;
  int count = 0;
  while (copy) {
    int digit = copy % 10;
    if (digit && 0 == (n % digit)) {
      count++;
    }
    copy /= 10;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getNumberOfEvenlyDividingDigits>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  je     L2
  xor    %r9d,%r9d
  xchg   %ax,%ax
L10:
  movslq %edi,%rsi
  mov    %edi,%edx
  imul   $0x66666667,%rsi,%rcx
  sar    $0x1f,%edx
  sar    $0x22,%rcx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  mov    %edi,%ecx
  add    %edx,%edx
  sub    %edx,%ecx
  je     L17
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r9d
L17:
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%edi
  sar    $0x22,%rsi
  sub    %edi,%esi
  mov    %esi,%edi
  jne    L10
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L2:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int getNumberOfEvenlyDividingDigits(int n) {
  int copy = n;
  int count = 0;
  while (copy) {
    int digit = copy % 10;
    if (digit && 0 == (n % digit)) {
      count++;
    }
    copy /= 10;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getNumberOfEvenlyDividingDigits>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  je     L2
  xor    %r9d,%r9d
  xchg   %ax,%ax
L17:
  movslq %edi,%rsi
  mov    %edi,%edx
  imul   $0x66666667,%rsi,%rcx
  sar    $0x1f,%edx
  sar    $0x22,%rcx
  sub    %edx,%ecx
  lea    (%rcx,%rcx,4),%edx
  mov    %edi,%ecx
  add    %edx,%edx
  sub    %edx,%ecx
  je     L10
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r9d
L10:
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%edi
  sar    $0x22,%rsi
  sub    %edi,%esi
  mov    %esi,%edi
  jne    L17
  mov    %r9d,%eax
  ret
  nopl   (%rax)
L2:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int getNumberOfEvenlyDividingDigits(int n) {
  int copy = n;
  int count = 0;
  while (copy) {
    int digit = copy % 10;
    if (digit && 0 == (n % digit)) {
      count++;
    }
    copy /= 10;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetRange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  %xmm5,-0x50(%rbp)
  movsd  %xmm6,-0x58(%rbp)
  movsd  %xmm7,-0x60(%rbp)
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  movsd  -0x50(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x58(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x60(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0x68(%rbp),%rdx
  mov    %rax,(%rdx)
  movsd  0x10(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  0x18(%rbp),%xmm0
  subsd  -0x48(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x68(%rbp),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x70(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void GetRange(double SiteX, double SiteY, double SiteZ, double SiteVX, double SiteVY, double SatX, double SatY, double SatZ, double SatVX, double SatVY, double SatVZ, double *Range, double *RangeRate) {
  double DX, DY, DZ;
  DX = SatX - SiteX;
  DY = SatY - SiteY;
  DZ = SatZ - SiteZ;
  *Range = sqrt(((DX) * (DX)) + ((DY) * (DY)) + ((DZ) * (DZ)));
  *RangeRate = ((SatVX - SiteVX) * DX + (SatVY - SiteVY) * DY + SatVZ * DZ) / *Range;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetRange>:
  endbr64
  push   %r15
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movq   %xmm3,%r14
  movq   %xmm4,%r15
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  subsd  %xmm0,%xmm5
  movsd  %xmm5,0x8(%rsp)
  subsd  %xmm1,%xmm6
  movsd  %xmm6,0x10(%rsp)
  subsd  %xmm2,%xmm7
  movsd  %xmm7,0x18(%rsp)
  movapd %xmm5,%xmm0
  mulsd  %xmm5,%xmm0
  movapd %xmm6,%xmm1
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm7,%xmm1
  mulsd  %xmm7,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L4
  sqrtsd %xmm0,%xmm0
L1:
  movsd  %xmm0,0x0(%rbp)
  movsd  0x50(%rsp),%xmm1
  movq   %r14,%xmm5
  subsd  %xmm5,%xmm1
  mulsd  0x8(%rsp),%xmm1
  movsd  0x58(%rsp),%xmm2
  movq   %r15,%xmm5
  subsd  %xmm5,%xmm2
  mulsd  0x10(%rsp),%xmm2
  addsd  %xmm2,%xmm1
  movsd  0x18(%rsp),%xmm2
  mulsd  0x60(%rsp),%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
L4:
  call   <sqrt@plt>
  jmp    L1
```

assistant: ```c
void GetRange(double SiteX, double SiteY, double SiteZ, double SiteVX, double SiteVY, double SatX, double SatY, double SatZ, double SatVX, double SatVY, double SatVZ, double *Range, double *RangeRate) {
  double DX, DY, DZ;
  DX = SatX - SiteX;
  DY = SatY - SiteY;
  DZ = SatZ - SiteZ;
  *Range = sqrt(((DX) * (DX)) + ((DY) * (DY)) + ((DZ) * (DZ)));
  *RangeRate = ((SatVX - SiteVX) * DX + (SatVY - SiteVY) * DY + SatVZ * DZ) / *Range;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GetRange>:
  endbr64
  subsd  %xmm0,%xmm5
  subsd  %xmm1,%xmm6
  sub    $0x48,%rsp
  subsd  %xmm2,%xmm7
  movapd %xmm5,%xmm0
  movapd %xmm6,%xmm1
  movapd %xmm5,%xmm8
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm7,%xmm1
  mulsd  %xmm7,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L12
  sqrtsd %xmm0,%xmm0
L17:
  movsd  0x50(%rsp),%xmm5
  movsd  0x58(%rsp),%xmm1
  movsd  %xmm0,(%rdi)
  mulsd  0x60(%rsp),%xmm7
  subsd  %xmm3,%xmm5
  subsd  %xmm4,%xmm1
  mulsd  %xmm8,%xmm5
  mulsd  %xmm1,%xmm6
  addsd  %xmm6,%xmm5
  addsd  %xmm7,%xmm5
  divsd  %xmm0,%xmm5
  movsd  %xmm5,(%rsi)
  add    $0x48,%rsp
  ret
L12:
  mov    %rsi,0x38(%rsp)
  mov    %rdi,0x30(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm7,0x18(%rsp)
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x38(%rsp),%rsi
  mov    0x30(%rsp),%rdi
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm7
  movsd  0x10(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm8
  jmp    L17
```

assistant: ```c
void GetRange(double SiteX, double SiteY, double SiteZ, double SiteVX, double SiteVY, double SatX, double SatY, double SatZ, double SatVX, double SatVY, double SatVZ, double *Range, double *RangeRate) {
  double DX, DY, DZ;
  DX = SatX - SiteX;
  DY = SatY - SiteY;
  DZ = SatZ - SiteZ;
  *Range = sqrt(((DX) * (DX)) + ((DY) * (DY)) + ((DZ) * (DZ)));
  *RangeRate = ((SatVX - SiteVX) * DX + (SatVY - SiteVY) * DY + SatVZ * DZ) / *Range;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetRange>:
  endbr64
  subsd  %xmm0,%xmm5
  subsd  %xmm1,%xmm6
  sub    $0x48,%rsp
  subsd  %xmm2,%xmm7
  movapd %xmm5,%xmm0
  movapd %xmm6,%xmm1
  movapd %xmm5,%xmm8
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm7,%xmm1
  mulsd  %xmm7,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L15
  sqrtsd %xmm0,%xmm0
L16:
  movsd  0x50(%rsp),%xmm5
  movsd  0x58(%rsp),%xmm1
  movsd  %xmm0,(%rdi)
  mulsd  0x60(%rsp),%xmm7
  subsd  %xmm3,%xmm5
  subsd  %xmm4,%xmm1
  mulsd  %xmm8,%xmm5
  mulsd  %xmm1,%xmm6
  addsd  %xmm6,%xmm5
  addsd  %xmm7,%xmm5
  divsd  %xmm0,%xmm5
  movsd  %xmm5,(%rsi)
  add    $0x48,%rsp
  ret
L15:
  mov    %rsi,0x38(%rsp)
  mov    %rdi,0x30(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm7,0x18(%rsp)
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x38(%rsp),%rsi
  mov    0x30(%rsp),%rdi
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm7
  movsd  0x10(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm8
  jmp    L16
```

assistant: ```c
void GetRange(double SiteX, double SiteY, double SiteZ, double SiteVX, double SiteVY, double SatX, double SatY, double SatZ, double SatVX, double SatVY, double SatVZ, double *Range, double *RangeRate) {
  double DX, DY, DZ;
  DX = SatX - SiteX;
  DY = SatY - SiteY;
  DZ = SatZ - SiteZ;
  *Range = sqrt(((DX) * (DX)) + ((DY) * (DY)) + ((DZ) * (DZ)));
  *RangeRate = ((SatVX - SiteVX) * DX + (SatVY - SiteVY) * DY + SatVZ * DZ) / *Range;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<float2Int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  cvttss2si %xmm0,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  subss  %xmm1,%xmm0
  comiss D6(%rip),%xmm0
  jb     L5
  add    $0x1,%ebx
L5:
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: f32

tool: D6: 0.5

assistant: ```c
int float2Int(register float convert) {
  register int ans;
  ans = (int)convert;
  convert -= ans;
  if (convert >= 0.5)
    ans++;
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<float2Int>:
  endbr64
  cvttss2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  comiss D1(%rip),%xmm0
  sbb    $0xffffffff,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: f32

tool: D1: 0.5

assistant: ```c
int float2Int(register float convert) {
  register int ans;
  ans = (int)convert;
  convert -= ans;
  if (convert >= 0.5)
    ans++;
  return ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<float2Int>:
  endbr64
  cvttss2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  comiss D6(%rip),%xmm0
  sbb    $0xffffffff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: f32

tool: D6: 0.5

assistant: ```c
int float2Int(register float convert) {
  register int ans;
  ans = (int)convert;
  convert -= ans;
  if (convert >= 0.5)
    ans++;
  return ans;
}
```
user: What is the c source code of the assembly code below:

```asm
<float2Int>:
  endbr64
  cvttss2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  subss  %xmm1,%xmm0
  comiss D1(%rip),%xmm0
  sbb    $0xffffffff,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: f32

tool: D1: 0.5

assistant: ```c
int float2Int(register float convert) {
  register int ans;
  ans = (int)convert;
  convert -= ans;
  if (convert >= 0.5)
    ans++;
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<releaseResources>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <releaseControlResources@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  mov    $0x0,%eax
  call   <controllerTimeReleaseResources@plt>
  jmp    L6
L4:
  mov    $0x0,%eax
  call   <controllerTimeReleaseResources@plt>
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int releaseResources() {
  int status = 0;
  status = releaseControlResources();
  if (status) {
    (void)controllerTimeReleaseResources();
  } else {
    status = controllerTimeReleaseResources();
  }
  return status;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<releaseResources>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <releaseControlResources@plt>
  test   %eax,%eax
  je     L18
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <controllerTimeReleaseResources@plt>
L0:
  mov    %ebx,%eax
  pop    %rbx
  ret
L18:
  mov    $0x0,%eax
  call   <controllerTimeReleaseResources@plt>
  mov    %eax,%ebx
  jmp    L0
```

assistant: ```c
int releaseResources() {
  int status = 0;
  status = releaseControlResources();
  if (status) {
    (void)controllerTimeReleaseResources();
  } else {
    status = controllerTimeReleaseResources();
  }
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<releaseResources>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <releaseControlResources@plt>
  test   %eax,%eax
  jne    L8
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <controllerTimeReleaseResources@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <controllerTimeReleaseResources@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int releaseResources() {
  int status = 0;
  status = releaseControlResources();
  if (status) {
    (void)controllerTimeReleaseResources();
  } else {
    status = controllerTimeReleaseResources();
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<releaseResources>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <releaseControlResources@plt>
  test   %eax,%eax
  jne    L0
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <controllerTimeReleaseResources@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <controllerTimeReleaseResources@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int releaseResources() {
  int status = 0;
  status = releaseControlResources();
  if (status) {
    (void)controllerTimeReleaseResources();
  } else {
    status = controllerTimeReleaseResources();
  }
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  char dummy[10];
  f(dummy);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <f@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char dummy[10];
  f(dummy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <f@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char dummy[10];
  f(dummy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <f@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char dummy[10];
  f(dummy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__assert_long_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    $0x0,%eax
  call   <test_case_assert_pass@plt>
  jmp    L17
L9:
  mov    $0x0,%eax
  call   <test_case_assert_fail@plt>
L17:
  nop
  leave
  ret
```

assistant: ```c
void __assert_long_equal(const char *spec, long expected, long actual, int line, const char *file) {
  int pass = expected == actual;
  if (pass) {
    test_case_assert_pass();
  } else {
    test_case_assert_fail();
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__assert_long_equal>:
  endbr64
  sub    $0x8,%rsp
  cmp    %rdx,%rsi
  je     L3
  mov    $0x0,%eax
  call   <test_case_assert_fail@plt>
L2:
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <test_case_assert_pass@plt>
  jmp    L2
```

assistant: ```c
void __assert_long_equal(const char *spec, long expected, long actual, int line, const char *file) {
  int pass = expected == actual;
  if (pass) {
    test_case_assert_pass();
  } else {
    test_case_assert_fail();
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__assert_long_equal>:
  endbr64
  xor    %eax,%eax
  cmp    %rdx,%rsi
  je     L6
  jmp    1060 <test_case_assert_fail@plt>
L6:
  jmp    1070 <test_case_assert_pass@plt>
```

assistant: ```c
void __assert_long_equal(const char *spec, long expected, long actual, int line, const char *file) {
  int pass = expected == actual;
  if (pass) {
    test_case_assert_pass();
  } else {
    test_case_assert_fail();
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__assert_long_equal>:
  endbr64
  xor    %eax,%eax
  cmp    %rdx,%rsi
  je     L5
  jmp    1060 <test_case_assert_fail@plt>
L5:
  jmp    1070 <test_case_assert_pass@plt>
```

assistant: ```c
void __assert_long_equal(const char *spec, long expected, long actual, int line, const char *file) {
  int pass = expected == actual;
  if (pass) {
    test_case_assert_pass();
  } else {
    test_case_assert_fail();
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<argparse_help_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <argparse_usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *this, const struct argparse_option *option) {
  argparse_usage(this);
  exit(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *this, const struct argparse_option *option) {
  argparse_usage(this);
  exit(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *this, const struct argparse_option *option) {
  argparse_usage(this);
  exit(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *this, const struct argparse_option *option) {
  argparse_usage(this);
  exit(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<NewtonPolynomialInterpolation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L116
  cmpq   $0x0,-0x20(%rbp)
  je     L116
  cmpl   $0x1,-0x24(%rbp)
  jle    L116
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L116
  mov    $0x1,%eax
  jmp    L72
L116:
  mov    $0x0,%eax
L72:
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L85
  cmpq   $0x0,-0x38(%rbp)
  je     L85
  cmpl   $0x0,-0x28(%rbp)
  jle    L85
  mov    $0x1,%eax
  jmp    L15
L85:
  mov    $0x0,%eax
L15:
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L117
L80:
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  movl   $0x1,-0xc(%rbp)
  jmp    L90
L27:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L90:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L27
  addl   $0x1,-0x10(%rbp)
L117:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L80
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: f64

tool: D2: 1

assistant: ```c
void NewtonPolynomialInterpolation(const double *x, const double *slopes, int n, const double *z, double *pz, int m) {
  int i, j;
  assert(x != NULL && slopes != NULL && n > 1 && x[0] < x[n - 1]);
  assert(z != NULL && pz != NULL && m > 0);
  for (i = 0; i < m; ++i) {
    double temp = 1.0;
    pz[i] = slopes[0];
    for (j = 1; j < n; ++j) {
      temp *= z[i] - x[j - 1];
      pz[i] += slopes[j] * temp;
    }
  }
}
```