ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetLengthSymbol>:
  endbr64
  movslq %edi,%rdi
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: 

assistant: ```c
int GetLengthSymbol(int l) {
  static const int table[259] = {0, 0, 0, 257, 258, 259, 260, 261, 262, 263, 264, 265, 265, 266, 266, 267, 267, 268, 268, 269, 269, 269, 269, 270, 270, 270, 270, 271, 271, 271, 271, 272, 272, 272, 272, 273, 273, 273, 273, 273, 273, 273, 273, 274, 274, 274, 274, 274, 274, 274, 274, 275, 275, 275, 275, 275, 275, 275, 275, 276, 276, 276, 276, 276, 276, 276, 276, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 277, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 278, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 279, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 280, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 281, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 283, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 284, 285};
  return table[l];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<echo_test_setup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D23
data_type: string

tool: D21: Command line:

tool: D26:   argv[%d]: %s


tool: D23: optstring: %s


assistant: ```c
void echo_test_setup(int argc, char *const argv[], const char *optstring) {
  printf("Command line:\n");
  for (int i = 0; i < argc; ++i)
    printf("  argv[%d]: %s\n", i, argv[i]);
  printf("optstring: %s\n", optstring);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<echo_test_setup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%r13
  lea    D10(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L19
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D26(%rip),%r14
L16:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
L19:
  mov    %r13,%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D29
data_type: string

tool: D10: Command line:

tool: D26:   argv[%d]: %s


tool: D29: optstring: %s


assistant: ```c
void echo_test_setup(int argc, char *const argv[], const char *optstring) {
  printf("Command line:\n");
  for (int i = 0; i < argc; ++i)
    printf("  argv[%d]: %s\n", i, argv[i]);
  printf("optstring: %s\n", optstring);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<echo_test_setup>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D8(%rip),%rdi
  push   %rbx
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L10
  xor    %ebx,%ebx
  lea    D4(%rip),%r13
  xchg   %ax,%ax
L2:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L2
L10:
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  lea    D26(%rip),%rdi
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string

tool: D8: Command line:

tool: D4:   argv[%d]: %s


tool: D26: optstring: %s


assistant: ```c
void echo_test_setup(int argc, char *const argv[], const char *optstring) {
  printf("Command line:\n");
  for (int i = 0; i < argc; ++i)
    printf("  argv[%d]: %s\n", i, argv[i]);
  printf("optstring: %s\n", optstring);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<echo_test_setup>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D18(%rip),%rdi
  push   %rbx
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L6
  xor    %ebx,%ebx
  lea    D0(%rip),%r13
  xchg   %ax,%ax
L12:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L12
L6:
  pop    %rbx
  mov    %r14,%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  lea    D8(%rip),%rdi
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D18: Command line:

tool: D0:   argv[%d]: %s


tool: D8: optstring: %s


assistant: ```c
void echo_test_setup(int argc, char *const argv[], const char *optstring) {
  printf("Command line:\n");
  for (int i = 0; i < argc; ++i)
    printf("  argv[%d]: %s\n", i, argv[i]);
  printf("optstring: %s\n", optstring);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_opt@plt>
  mov    $0x0,%eax
  call   <use_flags@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  get_opt(argc, argv);
  use_flags();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <get_opt@plt>
  mov    $0x0,%eax
  call   <use_flags@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  get_opt(argc, argv);
  use_flags();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <get_opt@plt>
  xor    %eax,%eax
  call   <use_flags@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  get_opt(argc, argv);
  use_flags();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <get_opt@plt>
  xor    %eax,%eax
  call   <use_flags@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  get_opt(argc, argv);
  use_flags();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__xstat64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x5f5e100,%edi
  mov    $0x0,%eax
  call   <delay@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D26: # 

tool: D13: __xstat64

tool: D19: ()


assistant: ```c
int __xstat64(const char *path, struct stat *buf) {
  puts("# ");
  puts(__FUNCTION__);
  puts("()\n");
  delay(100000000);
  (void)(path);
  (void)(buf);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__xstat64>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x5f5e100,%edi
  mov    $0x0,%eax
  call   <delay@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: string
name: extract_symbolic_data
arguments: data_label: D13
datatype: string

tool: D4: # 

tool: D8: __xstat64

tool: D13: ()


assistant: ```c
int __xstat64(const char *path, struct stat *buf) {
  puts("# ");
  puts(__FUNCTION__);
  puts("()\n");
  delay(100000000);
  (void)(path);
  (void)(buf);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__xstat64>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x5f5e100,%edi
  xor    %eax,%eax
  call   <delay@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D28
datatype: string

tool: D14: # 

tool: D8: __xstat64

tool: D28: ()


assistant: ```c
int __xstat64(const char *path, struct stat *buf) {
  puts("# ");
  puts(__FUNCTION__);
  puts("()\n");
  delay(100000000);
  (void)(path);
  (void)(buf);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__xstat64>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x5f5e100,%edi
  xor    %eax,%eax
  call   <delay@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D1
type: string

tool: D26: # 

tool: D23: __xstat64

tool: D1: ()


assistant: ```c
int __xstat64(const char *path, struct stat *buf) {
  puts("# ");
  puts(__FUNCTION__);
  puts("()\n");
  delay(100000000);
  (void)(path);
  (void)(buf);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nbl_decrypt_headers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L19:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x5,%eax
  cltq
  add    %rcx,%rax
  lea    0x10(%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x30,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <nbl_decrypt_buffer@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void nbl_decrypt_headers(struct bf_ctx *pCtx, char *pstrBuffer, int iHeaderChunksPos) {
  int i, iNbChunks;
  iNbChunks = (*((int *)(pstrBuffer + 0x0C)));
  for (i = 0; i < iNbChunks; i++)
    nbl_decrypt_buffer(pCtx, pstrBuffer + iHeaderChunksPos + 0x10 + i * 96, 0x30);
}
```
user: What is the c source code of the assembly code below:

```asm
<nbl_decrypt_headers>:
  endbr64
  mov    0xc(%rsi),%eax
  test   %eax,%eax
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movslq %edx,%rdx
  lea    0x10(%rsi,%rdx,1),%rbx
  lea    0x70(%rsi,%rdx,1),%r12
  lea    -0x1(%rax),%eax
  lea    (%rax,%rax,2),%rax
  shl    $0x5,%rax
  add    %rax,%r12
L8:
  mov    $0x30,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <nbl_decrypt_buffer@plt>
  add    $0x60,%rbx
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

assistant: ```c
void nbl_decrypt_headers(struct bf_ctx *pCtx, char *pstrBuffer, int iHeaderChunksPos) {
  int i, iNbChunks;
  iNbChunks = (*((int *)(pstrBuffer + 0x0C)));
  for (i = 0; i < iNbChunks; i++)
    nbl_decrypt_buffer(pCtx, pstrBuffer + iHeaderChunksPos + 0x10 + i * 96, 0x30);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nbl_decrypt_headers>:
  endbr64
  mov    0xc(%rsi),%eax
  test   %eax,%eax
  jle    L2
  sub    $0x1,%eax
  movslq %edx,%rdx
  push   %r12
  lea    (%rax,%rax,2),%rax
  lea    0x70(%rsi,%rdx,1),%r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x5,%rax
  push   %rbx
  lea    0x10(%rsi,%rdx,1),%rbx
  add    %rax,%r12
  nopl   (%rax)
L14:
  mov    %rbx,%rsi
  mov    $0x30,%edx
  mov    %rbp,%rdi
  add    $0x60,%rbx
  call   <nbl_decrypt_buffer@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
void nbl_decrypt_headers(struct bf_ctx *pCtx, char *pstrBuffer, int iHeaderChunksPos) {
  int i, iNbChunks;
  iNbChunks = (*((int *)(pstrBuffer + 0x0C)));
  for (i = 0; i < iNbChunks; i++)
    nbl_decrypt_buffer(pCtx, pstrBuffer + iHeaderChunksPos + 0x10 + i * 96, 0x30);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nbl_decrypt_headers>:
  endbr64
  mov    0xc(%rsi),%eax
  test   %eax,%eax
  jle    L2
  sub    $0x1,%eax
  movslq %edx,%rdx
  push   %r12
  lea    (%rax,%rax,2),%rax
  lea    0x70(%rsi,%rdx,1),%r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x5,%rax
  push   %rbx
  lea    0x10(%rsi,%rdx,1),%rbx
  add    %rax,%r12
  nopl   (%rax)
L3:
  mov    %rbx,%rsi
  mov    $0x30,%edx
  mov    %rbp,%rdi
  add    $0x60,%rbx
  call   <nbl_decrypt_buffer@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  ret
```

assistant: ```c
void nbl_decrypt_headers(struct bf_ctx *pCtx, char *pstrBuffer, int iHeaderChunksPos) {
  int i, iNbChunks;
  iNbChunks = (*((int *)(pstrBuffer + 0x0C)));
  for (i = 0; i < iNbChunks; i++)
    nbl_decrypt_buffer(pCtx, pstrBuffer + iHeaderChunksPos + 0x10 + i * 96, 0x30);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<aeron_idle_strategy_yielding_idle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L1
  mov    $0x0,%eax
  call   <sched_yield@plt>
  jmp    L7
L1:
  nop
L7:
  leave
  ret
```

assistant: ```c
void aeron_idle_strategy_yielding_idle(void *state, int work_count) {
  if (work_count > 0) {
    return;
  }
  sched_yield();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aeron_idle_strategy_yielding_idle>:
  endbr64
  test   %esi,%esi
  jle    L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sched_yield@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void aeron_idle_strategy_yielding_idle(void *state, int work_count) {
  if (work_count > 0) {
    return;
  }
  sched_yield();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aeron_idle_strategy_yielding_idle>:
  endbr64
  test   %esi,%esi
  jle    L5
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  jmp    1050 <sched_yield@plt>
```

assistant: ```c
void aeron_idle_strategy_yielding_idle(void *state, int work_count) {
  if (work_count > 0) {
    return;
  }
  sched_yield();
}
```
user: Translate the below assembly code into C programming language:

```asm
<aeron_idle_strategy_yielding_idle>:
  endbr64
  test   %esi,%esi
  jle    L1
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  jmp    1050 <sched_yield@plt>
```

assistant: ```c
void aeron_idle_strategy_yielding_idle(void *state, int work_count) {
  if (work_count > 0) {
    return;
  }
  sched_yield();
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_fh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dump_fh(const char *data, int len) {
  (void)data;
  (void)len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dump_fh>:
  endbr64
  ret
```

assistant: ```c
void dump_fh(const char *data, int len) {
  (void)data;
  (void)len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dump_fh>:
  endbr64
  ret
```

assistant: ```c
void dump_fh(const char *data, int len) {
  (void)data;
  (void)len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dump_fh>:
  endbr64
  ret
```

assistant: ```c
void dump_fh(const char *data, int len) {
  (void)data;
  (void)len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a = 1 + 2 * 3;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1 + 2 * 3;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1 + 2 * 3;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 1 + 2 * 3;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<WOCalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  je     L13
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L7
L13:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
L7:
  leave
  ret
```

assistant: ```c
void *WOCalloc(size_t count, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return calloc(count, size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<WOCalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <calloc@plt>
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
void *WOCalloc(size_t count, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return calloc(count, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<WOCalloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <calloc@plt>
  nop
L1:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *WOCalloc(size_t count, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return calloc(count, size);
}
```
user: What is the c source code of the assembly code below?

```asm
<WOCalloc>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <WOMallocShouldFail@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <calloc@plt>
  nop
L7:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *WOCalloc(size_t count, size_t size) {
  if (WOMallocShouldFail()) {
    errno = ENOMEM;
    return NULL;
  }
  return calloc(count, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<brkstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rbx
  movl   $0x0,-0x14(%rbp)
  jmp    L36
L66:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
L53:
  movzbl (%rbx),%r12d
  movsbl %r12b,%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  jne    L66
  test   %r12b,%r12b
  je     L85
  movsbl %r12b,%eax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  je     L72
L85:
  movb   $0x0,(%rbx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D8(%rip),%rax
  movq   $0x0,(%rdx,%rax,1)
  lea    D8(%rip),%rax
  jmp    L23
L72:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D8(%rip),%rax
  mov    %rbx,(%rdx,%rax,1)
  nop
L6:
  add    $0x1,%rbx
  movzbl (%rbx),%r12d
  test   %r12b,%r12b
  je     L39
  movsbl %r12b,%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  jne    L39
  movsbl %r12b,%eax
  mov    -0x38(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <brkany@plt>
  test   %eax,%eax
  je     L6
L39:
  addl   $0x1,-0x14(%rbp)
L36:
  cmpl   $0x18,-0x14(%rbp)
  jle    L53
  movq   $0x0,D7(%rip)
  lea    D8(%rip),%rax
L23:
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char **brkstring(strg, brksep, brkterm)
char *strg;
char *brksep, *brkterm;
{
  register char c, *sp;
  static char *broken[25 + 1];
  int bi;
  sp = strg;
  for (bi = 0; bi < 25; bi++) {
    while (brkany(c = *sp, brksep))
      *sp++ = 0;
    if (!c || brkany(c, brkterm)) {
      *sp = 0;
      broken[bi] = 0;
      return (broken);
    }
    broken[bi] = sp;
    while ((c = *++sp) && !brkany(c, brksep) && !brkany(c, brkterm))
      ;
  }
  broken[25] = 0;
  return (broken);
}
```