ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_gateway>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x1074(%rbp)
  mov    %rsi,-0x1080(%rbp)
  mov    %edx,-0x1078(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x1010(%rbp),%rax
  mov    %rax,-0x1060(%rbp)
  mov    $0x4,%edi
  call   <NLMSG_LENGTH@plt>
  mov    -0x1060(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1060(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x1060(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1060(%rbp),%rax
  mov    %rax,%rdi
  call   <NLMSG_DATA@plt>
  mov    %rax,-0x1058(%rbp)
  mov    -0x1058(%rbp),%rax
  mov    -0x1078(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x1060(%rbp),%rax
  mov    %eax,-0x1050(%rbp)
  mov    -0x1060(%rbp),%rax
  mov    0x4(%rax),%eax
  cltq
  mov    %rax,-0x1048(%rbp)
  mov    -0x1080(%rbp),%rax
  mov    %eax,-0x1040(%rbp)
  movl   $0x4,-0x103c(%rbp)
  lea    -0x1050(%rbp),%rax
  mov    %eax,-0x1038(%rbp)
  movl   $0x1,-0x1034(%rbp)
  movq   $0x0,-0x1030(%rbp)
  movq   $0x0,-0x1028(%rbp)
  movq   $0x0,-0x1020(%rbp)
  lea    -0x1040(%rbp),%rcx
  mov    -0x1074(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sendmsg@plt>
  mov    %eax,-0x1064(%rbp)
  cmpl   $0x0,-0x1064(%rbp)
  jns    L26
  mov    $0xffffffff,%eax
  jmp    L5
L26:
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int get_gateway(int fd, struct sockaddr_nl *sa, int domain) {
  char buf[4096];
  memset(buf, 0, 4096);
  struct nlmsghdr *nl;
  nl = (struct nlmsghdr *)buf;
  nl->nlmsg_len = NLMSG_LENGTH(sizeof(struct rtmsg));
  nl->nlmsg_type = RTM_GETROUTE;
  nl->nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
  struct rtmsg *rt;
  rt = (struct rtmsg *)NLMSG_DATA(nl);
  rt->rtm_family = domain;
  struct iovec iov = {nl, nl->nlmsg_len};
  struct msghdr msg = {sa, sizeof(*sa), &iov, 1, NULL, 0, 0};
  int r = sendmsg(fd, &msg, 0);
  return (r < 0) ? -1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_gateway>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1048(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%r12
  mov    $0x1000,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x4,%edi
  call   <NLMSG_LENGTH@plt>
  mov    %eax,0x44(%rsp)
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x48(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    D1(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,0x40(%rsp)
  mov    %r12,%rdi
  call   <NLMSG_DATA@plt>
  mov    %r13d,(%rax)
  mov    %r12d,(%rsp)
  movslq 0x44(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %ebp,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  mov    %rsp,%rax
  mov    %eax,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    0x10(%rsp),%rsi
  mov    $0x0,%edx
  mov    %ebx,%edi
  call   <sendmsg@plt>
  sar    $0x1f,%eax
  mov    0x1048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x1058,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_gateway(int fd, struct sockaddr_nl *sa, int domain) {
  char buf[4096];
  memset(buf, 0, 4096);
  struct nlmsghdr *nl;
  nl = (struct nlmsghdr *)buf;
  nl->nlmsg_len = NLMSG_LENGTH(sizeof(struct rtmsg));
  nl->nlmsg_type = RTM_GETROUTE;
  nl->nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
  struct rtmsg *rt;
  rt = (struct rtmsg *)NLMSG_DATA(nl);
  rt->rtm_family = domain;
  struct iovec iov = {nl, nl->nlmsg_len};
  struct msghdr msg = {sa, sizeof(*sa), &iov, 1, NULL, 0, 0};
  int r = sendmsg(fd, &msg, 0);
  return (r < 0) ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_gateway>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x58,%rsp
  lea    0x40(%rsp),%r12
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1048(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  mov    $0x1000,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x4,%edi
  call   <NLMSG_LENGTH@plt>
  mov    D6(%rip),%rdx
  mov    %r12,%rdi
  mov    %eax,0x44(%rsp)
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x48(%rsp)
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    %eax,0x40(%rsp)
  call   <NLMSG_DATA@plt>
  lea    0x10(%rsp),%rsi
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %r13d,(%rax)
  movslq 0x44(%rsp),%rax
  mov    %r12d,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rsp,%rax
  mov    %ebx,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  mov    %eax,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  call   <sendmsg@plt>
  sar    $0x1f,%eax
  mov    0x1048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x1058,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_gateway(int fd, struct sockaddr_nl *sa, int domain) {
  char buf[4096];
  memset(buf, 0, 4096);
  struct nlmsghdr *nl;
  nl = (struct nlmsghdr *)buf;
  nl->nlmsg_len = NLMSG_LENGTH(sizeof(struct rtmsg));
  nl->nlmsg_type = RTM_GETROUTE;
  nl->nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
  struct rtmsg *rt;
  rt = (struct rtmsg *)NLMSG_DATA(nl);
  rt->rtm_family = domain;
  struct iovec iov = {nl, nl->nlmsg_len};
  struct msghdr msg = {sa, sizeof(*sa), &iov, 1, NULL, 0, 0};
  int r = sendmsg(fd, &msg, 0);
  return (r < 0) ? -1 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_gateway>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x58,%rsp
  lea    0x40(%rsp),%r12
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1048(%rsp)
  xor    %eax,%eax
  xor    %esi,%esi
  mov    $0x1000,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x4,%edi
  call   <NLMSG_LENGTH@plt>
  mov    D18(%rip),%rdx
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    D26(%rip),%rax
  movd   %r8d,%xmm1
  mov    (%rax),%eax
  mov    %eax,0x48(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  or     (%rdx),%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x40(%rsp)
  call   <NLMSG_DATA@plt>
  pxor   %xmm0,%xmm0
  lea    0x10(%rsp),%rsi
  xor    %edx,%edx
  mov    %r13d,(%rax)
  movslq 0x44(%rsp),%rax
  mov    %ebp,%edi
  mov    %r12d,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rsp,%rax
  mov    %ebx,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  mov    %eax,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <sendmsg@plt>
  sar    $0x1f,%eax
  mov    0x1048(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x1058,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_gateway(int fd, struct sockaddr_nl *sa, int domain) {
  char buf[4096];
  memset(buf, 0, 4096);
  struct nlmsghdr *nl;
  nl = (struct nlmsghdr *)buf;
  nl->nlmsg_len = NLMSG_LENGTH(sizeof(struct rtmsg));
  nl->nlmsg_type = RTM_GETROUTE;
  nl->nlmsg_flags = NLM_F_REQUEST | NLM_F_ROOT;
  struct rtmsg *rt;
  rt = (struct rtmsg *)NLMSG_DATA(nl);
  rt->rtm_family = domain;
  struct iovec iov = {nl, nl->nlmsg_len};
  struct msghdr msg = {sa, sizeof(*sa), &iov, 1, NULL, 0, 0};
  int r = sendmsg(fd, &msg, 0);
  return (r < 0) ? -1 : 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<hpctimer_calibrate_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x3,-0x8(%rbp)
  mov    $0x0,%eax
  call   <hpctimer_gettsc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <hpctimer_gettsc@plt>
  sub    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  leave
  ret
```

assistant: ```c
uint64_t hpctimer_calibrate_sleep(uint64_t overhead) {
  uint64_t count;
  int delay = 3;
  count = hpctimer_gettsc();
  sleep(delay);
  count = hpctimer_gettsc() - count - overhead;
  return count / delay;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hpctimer_calibrate_sleep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <hpctimer_gettsc@plt>
  mov    %eax,%ebp
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <hpctimer_gettsc@plt>
  sub    %ebp,%eax
  mov    %eax,%edx
  sub    %ebx,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t hpctimer_calibrate_sleep(uint64_t overhead) {
  uint64_t count;
  int delay = 3;
  count = hpctimer_gettsc();
  sleep(delay);
  count = hpctimer_gettsc() - count - overhead;
  return count / delay;
}
```
user: What is the c source code of the assembly code below:

```asm
<hpctimer_calibrate_sleep>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <hpctimer_gettsc@plt>
  mov    $0x3,%edi
  mov    %eax,%ebp
  call   <sleep@plt>
  xor    %eax,%eax
  call   <hpctimer_gettsc@plt>
  add    $0x8,%rsp
  sub    %ebp,%eax
  mov    %eax,%edx
  sub    %ebx,%edx
  pop    %rbx
  pop    %rbp
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  ret
```

assistant: ```c
uint64_t hpctimer_calibrate_sleep(uint64_t overhead) {
  uint64_t count;
  int delay = 3;
  count = hpctimer_gettsc();
  sleep(delay);
  count = hpctimer_gettsc() - count - overhead;
  return count / delay;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hpctimer_calibrate_sleep>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <hpctimer_gettsc@plt>
  mov    $0x3,%edi
  mov    %eax,%ebp
  call   <sleep@plt>
  xor    %eax,%eax
  call   <hpctimer_gettsc@plt>
  add    $0x8,%rsp
  sub    %ebp,%eax
  mov    %eax,%edx
  sub    %ebx,%edx
  pop    %rbx
  pop    %rbp
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  ret
```

assistant: ```c
uint64_t hpctimer_calibrate_sleep(uint64_t overhead) {
  uint64_t count;
  int delay = 3;
  count = hpctimer_gettsc();
  sleep(delay);
  count = hpctimer_gettsc() - count - overhead;
  return count / delay;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L7
L9:
  mov    -0x30(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L9
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double **dmatrix(size_t m, size_t n) {
  double **mat = malloc(sizeof(double *) * m);
  for (int i = 0; i < m; i++) {
    mat[i] = malloc(sizeof(double) * n);
  }
  return mat;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dmatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L10
  shl    $0x3,%r12d
  mov    $0x0,%ebx
L6:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
L10:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **dmatrix(size_t m, size_t n) {
  double **mat = malloc(sizeof(double *) * m);
  for (int i = 0; i < m; i++) {
    mat[i] = malloc(sizeof(double) * n);
  }
  return mat;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dmatrix>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x3,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L16
  shl    $0x3,%r12d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L16:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **dmatrix(size_t m, size_t n) {
  double **mat = malloc(sizeof(double *) * m);
  for (int i = 0; i < m; i++) {
    mat[i] = malloc(sizeof(double) * n);
  }
  return mat;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dmatrix>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  shl    $0x3,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L15
  shl    $0x3,%r12d
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
L15:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double **dmatrix(size_t m, size_t n) {
  double **mat = malloc(sizeof(double *) * m);
  for (int i = 0; i < m; i++) {
    mat[i] = malloc(sizeof(double) * n);
  }
  return mat;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_input@plt>
  cmp    $0x1,%eax
  jne    L3
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solve@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: pause

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *adjMtx;
  if (read_input(&n, &adjMtx) == 1) {
    solve(n, adjMtx);
    free(adjMtx);
  }
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <read_input@plt>
  cmp    $0x1,%eax
  je     L11
L27:
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L11:
  mov    0x10(%rsp),%rsi
  mov    0xc(%rsp),%edi
  call   <solve@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  jmp    L27
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: pause

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *adjMtx;
  if (read_input(&n, &adjMtx) == 1) {
    solve(n, adjMtx);
    free(adjMtx);
  }
  system("pause");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <read_input@plt>
  cmp    $0x1,%eax
  je     L13
L20:
  lea    D6(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L13:
  mov    0xc(%rsp),%edi
  mov    0x10(%rsp),%rsi
  call   <solve@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  jmp    L20
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: pause

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *adjMtx;
  if (read_input(&n, &adjMtx) == 1) {
    solve(n, adjMtx);
    free(adjMtx);
  }
  system("pause");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <read_input@plt>
  cmp    $0x1,%eax
  je     L3
L4:
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  mov    0xc(%rsp),%edi
  mov    0x10(%rsp),%rsi
  call   <solve@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  jmp    L4
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: pause

assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  int *adjMtx;
  if (read_input(&n, &adjMtx) == 1) {
    solve(n, adjMtx);
    free(adjMtx);
  }
  system("pause");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L11
  mov    $0x0,%eax
  jmp    L17
L11:
  mov    $0x0,%eax
  call   <random@plt>
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
L17:
  leave
  ret
```

assistant: ```c
int get_random(int rng) {
  if (rng < 1) {
    return 0;
  }
  return (int)(random() % rng);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_random>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jle    L0
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <random@plt>
  cltd
  idiv   %ebx
  mov    %edx,%eax
  pop    %rbx
  ret
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
int get_random(int rng) {
  if (rng < 1) {
    return 0;
  }
  return (int)(random() % rng);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_random>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random@plt>
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %edx,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_random(int rng) {
  if (rng < 1) {
    return 0;
  }
  return (int)(random() % rng);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_random>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <random@plt>
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %edx,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_random(int rng) {
  if (rng < 1) {
    return 0;
  }
  return (int)(random() % rng);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<make_2d_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L3
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L13
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int **make_2d_array(int cols, int rows) {
  int y;
  int **arr;
  arr = malloc(sizeof(int *) * rows);
  for (y = 0; y < rows; ++y) {
    arr[y] = calloc(sizeof(int), cols);
  }
  return arr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<make_2d_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L14
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L12:
  mov    %ebp,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L12
L14:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **make_2d_array(int cols, int rows) {
  int y;
  int **arr;
  arr = malloc(sizeof(int *) * rows);
  for (y = 0; y < rows; ++y) {
    arr[y] = calloc(sizeof(int), cols);
  }
  return arr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<make_2d_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    0x0(,%r12,8),%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L8
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L0:
  mov    %ebp,%esi
  mov    $0x4,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L0
L8:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **make_2d_array(int cols, int rows) {
  int y;
  int **arr;
  arr = malloc(sizeof(int *) * rows);
  for (y = 0; y < rows; ++y) {
    arr[y] = calloc(sizeof(int), cols);
  }
  return arr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_2d_array>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    0x0(,%r12,8),%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L3
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L4:
  mov    %ebp,%esi
  mov    $0x4,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L4
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **make_2d_array(int cols, int rows) {
  int y;
  int **arr;
  arr = malloc(sizeof(int *) * rows);
  for (y = 0; y < rows; ++y) {
    arr[y] = calloc(sizeof(int), cols);
  }
  return arr;
}
```