ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    (%rsi),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L37
  orq    $0x0,-0x8(%rsp,%rax,1)
L37:
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  lea    -0x20(%rbp),%rcx
  lea    -0x1c(%rbp),%r8
  mov    %rsp,%rdx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    %eax,%edi
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %rsp,%rsi
  call   <executeDll@plt>
  lea    -0x21(%rbp),%rcx
  mov    %rsp,%rdx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  mov    %eax,%edi
  movsbl -0x21(%rbp),%edx
  mov    %rsp,%rsi
  call   <executeGpl@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    -0x8(%rbp),%rbx
  leave
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string

tool: D16: %s %d %d

tool: D4: %s %c

assistant: ```c
void parseLine(char *line, size_t *nbytes) {
  int nargs;
  char command[*nbytes], c;
  int a1 = 0, a2 = 0;
  nargs = sscanf(line, "%s %d %d", command, &a1, &a2);
  executeDll(nargs, command, a1, a2);
  nargs = sscanf(line, "%s %c", command, &c);
  executeGpl(nargs, command, c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parseLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    (%rsi),%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L38
L47:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L47
L38:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L10
L17:
  lea    -0x1c(%rbp),%r8
  lea    -0x20(%rbp),%rcx
  mov    %rsp,%rdx
  mov    %r12,%rdi
  lea    D15(%rip),%rsi
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  call   <sscanf@plt>
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <executeDll@plt>
  mov    %rsp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D10(%rip),%rsi
  lea    -0x21(%rbp),%rcx
  call   <sscanf@plt>
  movsbl -0x21(%rbp),%edx
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <executeGpl@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   (%rax)
L10:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L17
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string

tool: D15: %s %d %d

tool: D10: %s %c

assistant: ```c
void parseLine(char *line, size_t *nbytes) {
  int nargs;
  char command[*nbytes], c;
  int a1 = 0, a2 = 0;
  nargs = sscanf(line, "%s %d %d", command, &a1, &a2);
  executeDll(nargs, command, a1, a2);
  nargs = sscanf(line, "%s %c", command, &c);
  executeGpl(nargs, command, c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parseLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    (%rsi),%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L36
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L36:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L47
L8:
  lea    -0x1c(%rbp),%r8
  lea    -0x20(%rbp),%rcx
  mov    %rsp,%rdx
  mov    %r12,%rdi
  lea    D0(%rip),%rsi
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  call   <sscanf@plt>
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <executeDll@plt>
  mov    %rsp,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D4(%rip),%rsi
  lea    -0x21(%rbp),%rcx
  call   <sscanf@plt>
  movsbl -0x21(%rbp),%edx
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <executeGpl@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   (%rax)
L47:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L8
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D4
type: string

tool: D0: %s %d %d

tool: D4: %s %c

assistant: ```c
void parseLine(char *line, size_t *nbytes) {
  int nargs;
  char command[*nbytes], c;
  int a1 = 0, a2 = 0;
  nargs = sscanf(line, "%s %d %d", command, &a1, &a2);
  executeDll(nargs, command, a1, a2);
  nargs = sscanf(line, "%s %c", command, &c);
  executeGpl(nargs, command, c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <testVaCopyArg@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string

tool: D18: abc

tool: D14: s

assistant: ```c
int main() {
  testVaCopyArg("s", "abc");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <testVaCopyArg@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D17: abc

tool: D2: s

assistant: ```c
int main() {
  testVaCopyArg("s", "abc");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <testVaCopyArg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D14
type_infered: string

tool: D0: abc

tool: D14: s

assistant: ```c
int main() {
  testVaCopyArg("s", "abc");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <testVaCopyArg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string

tool: D17: abc

tool: D8: s

assistant: ```c
int main() {
  testVaCopyArg("s", "abc");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<info_led_blink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L0:
  mov    $0x0,%eax
  call   <info_led_on@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <msleep@plt>
  mov    $0x0,%eax
  call   <info_led_off@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <msleep@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void info_led_blink(int times, int delay_on, int delay_off) {
  for (int i = 0; i < times; i++) {
    info_led_on();
    msleep(delay_on);
    info_led_off();
    msleep(delay_off);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<info_led_blink>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    $0x0,%ebx
L3:
  mov    $0x0,%eax
  call   <info_led_on@plt>
  mov    %r12d,%edi
  call   <msleep@plt>
  mov    $0x0,%eax
  call   <info_led_off@plt>
  mov    %r13d,%edi
  call   <msleep@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  ret
```

assistant: ```c
void info_led_blink(int times, int delay_on, int delay_off) {
  for (int i = 0; i < times; i++) {
    info_led_on();
    msleep(delay_on);
    info_led_off();
    msleep(delay_off);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<info_led_blink>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <info_led_on@plt>
  mov    %r12d,%edi
  call   <msleep@plt>
  xor    %eax,%eax
  call   <info_led_off@plt>
  mov    %r13d,%edi
  call   <msleep@plt>
  cmp    %ebx,%ebp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void info_led_blink(int times, int delay_on, int delay_off) {
  for (int i = 0; i < times; i++) {
    info_led_on();
    msleep(delay_on);
    info_led_off();
    msleep(delay_off);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<info_led_blink>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <info_led_on@plt>
  mov    %r12d,%edi
  call   <msleep@plt>
  xor    %eax,%eax
  call   <info_led_off@plt>
  mov    %r13d,%edi
  call   <msleep@plt>
  cmp    %ebx,%ebp
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  ret
```

assistant: ```c
void info_led_blink(int times, int delay_on, int delay_off) {
  for (int i = 0; i < times; i++) {
    info_led_on();
    msleep(delay_on);
    info_led_off();
    msleep(delay_off);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<commlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L27:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L27
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int commlen(const char *a, const char *b) {
  int l = 0;
  while (*a && *a++ == *b++)
    l++;
  return (l);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<commlen>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  mov    $0x0,%ecx
  test   %dl,%dl
  je     L16
L4:
  mov    %eax,%ecx
  cmp    %dl,(%rsi,%rax,1)
  jne    L16
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L4
L16:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int commlen(const char *a, const char *b) {
  int l = 0;
  while (*a && *a++ == *b++)
    l++;
  return (l);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<commlen>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  xor    %r8d,%r8d
  test   %dl,%dl
  jne    L27
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L16:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L19
L27:
  mov    %eax,%r8d
  cmp    %dl,(%rsi,%rax,1)
  je     L16
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int commlen(const char *a, const char *b) {
  int l = 0;
  while (*a && *a++ == *b++)
    l++;
  return (l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<commlen>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  xor    %r8d,%r8d
  test   %dl,%dl
  jne    L33
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L23:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L8
L33:
  mov    %eax,%r8d
  cmp    %dl,(%rsi,%rax,1)
  je     L23
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int commlen(const char *a, const char *b) {
  int l = 0;
  while (*a && *a++ == *b++)
    l++;
  return (l);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x48,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %esi,-0xbc(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int open(const char *path, int flags, ...) {
  errno = EMFILE;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<open>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int open(const char *path, int flags, ...) {
  errno = EMFILE;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<open>:
  endbr64
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int open(const char *path, int flags, ...) {
  errno = EMFILE;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<open>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int open(const char *path, int flags, ...) {
  errno = EMFILE;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L10:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: D7: Je suis le maitre !

tool: D19: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
#pragma omp for
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L8
  mov    $0x0,%esi
  mov    $0x0,%eax
L14:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L14
L5:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L8:
  mov    $0x0,%esi
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D5
type: string

tool: D1: Je suis le maitre !

tool: D5: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
#pragma omp for
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  xor    %esi,%esi
  test   %ebx,%ebx
  jle    L10
  xor    %eax,%eax
  nopl   0x0(%rax)
L5:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L5
L10:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string

tool: D19: Je suis le maitre !

tool: D10: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
#pragma omp for
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L118
  lea    -0x1(%rbx),%eax
  cmp    $0x9,%eax
  jbe    L95
  mov    %ebx,%edx
  movdqa D32(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D28(%rip),%xmm3
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L78:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L78
  movdqa %xmm0,%xmm1
  mov    %ebx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%bl
  je     L145
L40:
  lea    0x1(%rax),%edx
  add    %eax,%esi
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x6(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x7(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    %edx,%esi
  lea    0x8(%rax),%edx
  cmp    %edx,%ebx
  jle    L145
  add    $0x9,%eax
  add    %edx,%esi
  cmp    %eax,%ebx
  jle    L145
  add    %eax,%esi
L145:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L118:
  xor    %esi,%esi
  jmp    L145
L95:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L40
```

tool_calls: name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D32
data_type: byte[16]
name: read_data
arguments: data_tag: D28
data_type: byte[16]
name: read_data
arguments: data_tag: D4
data_type: string

tool: D25: Je suis le maitre !

tool: {"D32": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D28": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D4: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
#pragma omp for
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L28
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  cmp    $0x1,%eax
  jne    L28
  mov    $0x1,%eax
  jmp    L34
L28:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L18
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab++) {
    if (f(*tab) == 1)
      return (1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_any>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
L15:
  add    $0x8,%rbx
  cmpq   $0x0,-0x8(%rbx)
  je     L22
  mov    (%rbx),%rdi
  call   *%rbp
  cmp    $0x1,%eax
  jne    L15
  jmp    L23
L22:
  mov    $0x0,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab++) {
    if (f(*tab) == 1)
      return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%rdi
  call   *%rbp
  cmp    $0x1,%eax
  je     L25
L21:
  add    $0x8,%rbx
  cmpq   $0x0,-0x8(%rbx)
  jne    L10
  xor    %eax,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab++) {
    if (f(*tab) == 1)
      return (1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rdi
  call   *%rbp
  cmp    $0x1,%eax
  je     L27
L2:
  add    $0x8,%rbx
  cmpq   $0x0,-0x8(%rbx)
  jne    L4
  xor    %eax,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab++) {
    if (f(*tab) == 1)
      return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<getCloserInterval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getCloserInterval(int now, int interval) {
  int tmp;
  tmp = (now % interval);
  return (now - tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getCloserInterval>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int getCloserInterval(int now, int interval) {
  int tmp;
  tmp = (now % interval);
  return (now - tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getCloserInterval>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int getCloserInterval(int now, int interval) {
  int tmp;
  tmp = (now % interval);
  return (now - tmp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCloserInterval>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int getCloserInterval(int now, int interval) {
  int tmp;
  tmp = (now % interval);
  return (now - tmp);
}
```