ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_convert_time>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <atoi@plt>
  cmpb   $0x3a,(%r14)
  mov    %eax,%r12d
  je     L61
  mov    $0x1,%eax
  nopl   0x0(%rax)
L49:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L49
  lea    0x1(%rdx),%r13d
  lea    0x2(%rdx),%ebx
  add    $0x3,%edx
  movslq %r13d,%rax
  movslq %ebx,%rcx
  movslq %edx,%r15
L33:
  lea    (%r14,%rax,1),%rdx
  mov    %rcx,0x8(%rsp)
  mov    %rdx,%rdi
  mov    %rdx,(%rsp)
  call   <atoi@plt>
  mov    (%rsp),%rdx
  mov    0x8(%rsp),%rcx
  mov    %eax,%ebp
  cmpb   $0x3a,(%rdx)
  je     L43
  lea    0x1(%r13),%eax
  cltq
  nopl   0x0(%rax)
L11:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L11
  lea    0x1(%rdx),%ebx
  add    $0x2,%edx
  movslq %ebx,%rcx
  movslq %edx,%r15
L43:
  lea    (%r14,%rcx,1),%r13
  mov    %r13,%rdi
  call   <atoi@plt>
  cmpb   $0x3a,0x0(%r13)
  mov    %eax,(%rsp)
  je     L14
  lea    0x1(%rbx),%eax
  cltq
  nopl   (%rax)
L7:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x3a,-0x1(%r14,%rax,1)
  jne    L7
  add    $0x1,%edx
  movslq %edx,%r15
L14:
  lea    (%r14,%r15,1),%rdi
  call   <atoi@plt>
  fildl  (%rsp)
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm1
  mov    %eax,(%rsp)
  mulsd  D19(%rip),%xmm1
  cvtsi2sd %ebp,%xmm0
  mulsd  D4(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  faddl  0x8(%rsp)
  fildl  (%rsp)
  fdivs  0xddd(%rip)        # 2010 <_fini+0xda8>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  faddp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L61:
  mov    $0x3,%r15d
  mov    $0x2,%ecx
  mov    $0x2,%ebx
  mov    $0x1,%eax
  mov    $0x1,%r13d
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type: f64
name: extract_symbolic_data
arguments: tag: D4
type: f64

tool: D19: 3600

tool: D4: 60

assistant: ```c
long double _convert_time(char *c) {
  long double time;
  int H, m, s, i, f;
  H = atoi(c);
  for (i = 0; c[i] != ':'; i++)
    ;
  m = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  s = atoi(&c[++i]);
  for (; c[i] != ':'; i++)
    ;
  f = atoi(&c[++i]);
  time = (H * 3600.) + (m * 60.) + (long double)s + (long double)f / 1000000.;
  return time;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getForce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dl,-0x24(%rbp)
  mov    %ecx,%edx
  mov    %dl,-0x28(%rbp)
  mov    %al,-0x2c(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,%edx
  movzbl -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <getValueInternal@plt>
  mov    %ax,-0x12(%rbp)
  movzwl -0x12(%rbp),%esi
  mov    $0x9c4000,%eax
  mov    $0x0,%edx
  div    %rsi
  sub    $0x2710,%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x1e8480,%eax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned int getForce(unsigned char boardNumber, unsigned char rowNumber, unsigned char pinNumber) {
  unsigned short value = getValueInternal((unsigned int)(boardNumber)*32 + rowNumber * 8 + pinNumber);
  unsigned long intermediate = ((unsigned long)10000) * 1024 / value - 10000;
  unsigned long forceInGrams = (unsigned long)2000000 / intermediate;
  return (unsigned int)forceInGrams;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getForce>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  shl    $0x5,%edi
  movzbl %sil,%esi
  lea    (%rdi,%rsi,8),%edi
  movzbl %dl,%edx
  add    %edx,%edi
  mov    $0x0,%eax
  call   <getValueInternal@plt>
  movzwl %ax,%ecx
  mov    $0x9c4000,%eax
  mov    $0x0,%edx
  div    %rcx
  lea    -0x2710(%rax),%rcx
  mov    $0x1e8480,%eax
  mov    $0x0,%edx
  div    %rcx
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int getForce(unsigned char boardNumber, unsigned char rowNumber, unsigned char pinNumber) {
  unsigned short value = getValueInternal((unsigned int)(boardNumber)*32 + rowNumber * 8 + pinNumber);
  unsigned long intermediate = ((unsigned long)10000) * 1024 / value - 10000;
  unsigned long forceInGrams = (unsigned long)2000000 / intermediate;
  return (unsigned int)forceInGrams;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getForce>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  movzbl %dl,%edx
  sub    $0x8,%rsp
  shl    $0x5,%edi
  xor    %eax,%eax
  lea    (%rdi,%rsi,8),%edi
  add    %edx,%edi
  call   <getValueInternal@plt>
  xor    %edx,%edx
  add    $0x8,%rsp
  movzwl %ax,%ecx
  mov    $0x9c4000,%eax
  div    %rcx
  xor    %edx,%edx
  lea    -0x2710(%rax),%rcx
  mov    $0x1e8480,%eax
  div    %rcx
  ret
```

assistant: ```c
unsigned int getForce(unsigned char boardNumber, unsigned char rowNumber, unsigned char pinNumber) {
  unsigned short value = getValueInternal((unsigned int)(boardNumber)*32 + rowNumber * 8 + pinNumber);
  unsigned long intermediate = ((unsigned long)10000) * 1024 / value - 10000;
  unsigned long forceInGrams = (unsigned long)2000000 / intermediate;
  return (unsigned int)forceInGrams;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getForce>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  movzbl %dl,%edx
  sub    $0x8,%rsp
  shl    $0x5,%edi
  xor    %eax,%eax
  lea    (%rdi,%rsi,8),%edi
  add    %edx,%edi
  call   <getValueInternal@plt>
  xor    %edx,%edx
  add    $0x8,%rsp
  movzwl %ax,%ecx
  mov    $0x9c4000,%eax
  div    %rcx
  xor    %edx,%edx
  lea    -0x2710(%rax),%rcx
  mov    $0x1e8480,%eax
  div    %rcx
  ret
```

assistant: ```c
unsigned int getForce(unsigned char boardNumber, unsigned char rowNumber, unsigned char pinNumber) {
  unsigned short value = getValueInternal((unsigned int)(boardNumber)*32 + rowNumber * 8 + pinNumber);
  unsigned long intermediate = ((unsigned long)10000) * 1024 / value - 10000;
  unsigned long forceInGrams = (unsigned long)2000000 / intermediate;
  return (unsigned int)forceInGrams;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <start_netlink_monitor@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start_netlink_monitor();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <start_netlink_monitor@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start_netlink_monitor();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <start_netlink_monitor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start_netlink_monitor();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <start_netlink_monitor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  start_netlink_monitor();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isPalindromeIterative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L29:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L7
  mov    $0x0,%eax
  jmp    L12
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
bool isPalindromeIterative(char *input, int length) {
  int start = 0, end = length - 1;
  while (start < end) {
    if (input[start++] != input[end--]) {
      return false;
    }
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPalindromeIterative>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  mov    $0x0,%eax
L17:
  cmp    %esi,%eax
  jge    L16
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdi,%rsi,1),%edx
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %dl,%cl
  je     L17
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool isPalindromeIterative(char *input, int length) {
  int start = 0, end = length - 1;
  while (start < end) {
    if (input[start++] != input[end--]) {
      return false;
    }
  }
  return true;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPalindromeIterative>:
  endbr64
  sub    $0x1,%esi
  xor    %eax,%eax
  movslq %esi,%rsi
  jmp    L12
  xchg   %ax,%ax
L2:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdi,%rsi,1),%edx
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %dl,%cl
  jne    L17
L12:
  cmp    %esi,%eax
  jl     L2
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPalindromeIterative(char *input, int length) {
  int start = 0, end = length - 1;
  while (start < end) {
    if (input[start++] != input[end--]) {
      return false;
    }
  }
  return true;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPalindromeIterative>:
  endbr64
  sub    $0x1,%esi
  xor    %eax,%eax
  movslq %esi,%rsi
  jmp    L23
  xchg   %ax,%ax
L25:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdi,%rsi,1),%edx
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %dl,%cl
  jne    L21
L23:
  cmp    %esi,%eax
  jl     L25
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPalindromeIterative(char *input, int length) {
  int start = 0, end = length - 1;
  while (start < end) {
    if (input[start++] != input[end--]) {
      return false;
    }
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lcd_putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  movsbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x2,%edi
  call   <lcd_send_cmd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L30
  mov    -0x4(%rbp),%eax
  jmp    L16
L30:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <lcd_send_cmd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  jmp    L16
L3:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <lcd_send_cmd@plt>
L16:
  leave
  ret
```

assistant: ```c
int lcd_putc(char c) {
  int ret;
  uint8_t c1 = (c & 0xf0) >> 4;
  uint8_t c2 = c & 0x0f;
  ret = lcd_send_cmd(0x02);
  if (ret)
    return ret;
  ret = lcd_send_cmd(c1);
  if (ret)
    return ret;
  return lcd_send_cmd(c2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lcd_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  je     L13
L21:
  pop    %rbx
  ret
L13:
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  jne    L21
  and    $0xf,%ebx
  mov    %ebx,%edi
  call   <lcd_send_cmd@plt>
  jmp    L21
```

assistant: ```c
int lcd_putc(char c) {
  int ret;
  uint8_t c1 = (c & 0xf0) >> 4;
  uint8_t c2 = c & 0x0f;
  ret = lcd_send_cmd(0x02);
  if (ret)
    return ret;
  ret = lcd_send_cmd(c1);
  if (ret)
    return ret;
  return lcd_send_cmd(c2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcd_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  je     L9
L6:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  jne    L6
  and    $0xf,%ebx
  mov    %ebx,%edi
  pop    %rbx
  jmp    1050 <lcd_send_cmd@plt>
```

assistant: ```c
int lcd_putc(char c) {
  int ret;
  uint8_t c1 = (c & 0xf0) >> 4;
  uint8_t c2 = c & 0x0f;
  ret = lcd_send_cmd(0x02);
  if (ret)
    return ret;
  ret = lcd_send_cmd(c1);
  if (ret)
    return ret;
  return lcd_send_cmd(c2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lcd_putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  je     L18
L12:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  shr    $0x4,%edi
  and    $0xf,%edi
  call   <lcd_send_cmd@plt>
  test   %eax,%eax
  jne    L12
  and    $0xf,%ebx
  mov    %ebx,%edi
  pop    %rbx
  jmp    1050 <lcd_send_cmd@plt>
```

assistant: ```c
int lcd_putc(char c) {
  int ret;
  uint8_t c1 = (c & 0xf0) >> 4;
  uint8_t c2 = c & 0x0f;
  ret = lcd_send_cmd(0x02);
  if (ret)
    return ret;
  ret = lcd_send_cmd(c1);
  if (ret)
    return ret;
  return lcd_send_cmd(c2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_dec_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    D18(%rip),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
datatype: string

tool: D19: %lu

assistant: ```c
char *print_dec_2(val)
unsigned long val;
{
  static char vbuf[32];
  sprintf(vbuf, "%lu", val);
  return vbuf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_dec_2>:
  endbr64
  push   %rbx
  mov    %rdi,%rdx
  lea    D14(%rip),%rsi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D14: %lu

assistant: ```c
char *print_dec_2(val)
unsigned long val;
{
  static char vbuf[32];
  sprintf(vbuf, "%lu", val);
  return vbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_dec_2>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  mov    %rdi,%rdx
  xor    %eax,%eax
  mov    %r12,%rdi
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: %lu

assistant: ```c
char *print_dec_2(val)
unsigned long val;
{
  static char vbuf[32];
  sprintf(vbuf, "%lu", val);
  return vbuf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_dec_2>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  mov    %rdi,%rdx
  xor    %eax,%eax
  mov    %r12,%rdi
  lea    D11(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: string

tool: D11: %lu

assistant: ```c
char *print_dec_2(val)
unsigned long val;
{
  static char vbuf[32];
  sprintf(vbuf, "%lu", val);
  return vbuf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<double_add_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L34:
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L24:
  mov    -0x8(%rbp),%edx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movsd  (%rdx,%rax,8),%xmm1
  mov    -0x8(%rbp),%edx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movsd  (%rdx,%rax,8),%xmm0
  mov    -0x8(%rbp),%edx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  addsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L24
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void double_add_matrix(unsigned int lines, unsigned int columns, double m1[20][20], double m2[20][20], double result[20][20]) {
  unsigned int i, j;
  for (i = 0; i < lines; i++) {
    for (j = 0; j < columns; j++) {
      result[i][j] = m1[i][j] + m2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<double_add_matrix>:
  endbr64
  test   %edi,%edi
  je     L39
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %edi,%edi
  lea    (%rdi,%rdi,4),%r11
  shl    $0x5,%r11
  mov    $0x0,%r9d
  mov    %esi,%edi
  jmp    L22
L24:
  lea    (%rbx,%r9,1),%rsi
  lea    0x0(%rbp,%r9,1),%rcx
  lea    (%r8,%r9,1),%rdx
  mov    $0x0,%eax
L35:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L35
L23:
  add    $0xa0,%r9
  cmp    %r11,%r9
  je     L30
L22:
  test   %r10d,%r10d
  jne    L24
  jmp    L23
L30:
  pop    %rbx
  pop    %rbp
  ret
L39:
  ret
```

assistant: ```c
void double_add_matrix(unsigned int lines, unsigned int columns, double m1[20][20], double m2[20][20], double result[20][20]) {
  unsigned int i, j;
  for (i = 0; i < lines; i++) {
    for (j = 0; j < columns; j++) {
      result[i][j] = m1[i][j] + m2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<double_add_matrix>:
  endbr64
  test   %edi,%edi
  je     L6
  mov    %edi,%edi
  push   %rbp
  mov    %esi,%r10d
  mov    %rcx,%rbp
  lea    (%rdi,%rdi,4),%r11
  push   %rbx
  xor    %r9d,%r9d
  mov    %rdx,%rbx
  shl    $0x5,%r11
  mov    %esi,%edi
  nopw   0x0(%rax,%rax,1)
L14:
  test   %r10d,%r10d
  je     L27
  lea    (%rbx,%r9,1),%rsi
  lea    0x0(%rbp,%r9,1),%rcx
  xor    %eax,%eax
  lea    (%r8,%r9,1),%rdx
  nopl   0x0(%rax)
L33:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L33
L27:
  add    $0xa0,%r9
  cmp    %r11,%r9
  jne    L14
  pop    %rbx
  pop    %rbp
  ret
L6:
  ret
```

assistant: ```c
void double_add_matrix(unsigned int lines, unsigned int columns, double m1[20][20], double m2[20][20], double result[20][20]) {
  unsigned int i, j;
  for (i = 0; i < lines; i++) {
    for (j = 0; j < columns; j++) {
      result[i][j] = m1[i][j] + m2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<double_add_matrix>:
  endbr64
  test   %edi,%edi
  je     L106
  mov    %esi,%r11d
  test   %esi,%esi
  je     L106
  mov    %rdx,%rsi
  lea    -0x1(%rdi),%edx
  push   %r12
  mov    %r8,%rax
  lea    (%rdx,%rdx,4),%rdx
  push   %rbp
  mov    %r11d,%ebp
  lea    -0x1(%r11),%r12d
  shl    $0x5,%rdx
  push   %rbx
  and    $0xfffffffe,%ebp
  mov    %r11d,%r10d
  lea    0xa0(%r8,%rdx,1),%rbx
  mov    %r11d,%r8d
  mov    %ebp,%edx
  shr    %r8d
  nopl   0x0(%rax)
L25:
  lea    0x8(%rsi),%rdi
  cmp    %rdi,%rax
  lea    0x8(%rcx),%rdi
  setne  %r9b
  cmp    %rdi,%rax
  setne  %dil
  test   %dil,%r9b
  je     L156
  cmp    $0x1,%r12d
  jbe    L156
  movupd (%rcx),%xmm0
  movupd (%rsi),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rax)
  cmp    $0x1,%r8d
  jbe    L77
  movupd 0x10(%rsi),%xmm0
  movupd 0x10(%rcx),%xmm2
  addpd  %xmm2,%xmm0
  movups %xmm0,0x10(%rax)
  cmp    $0x2,%r8d
  je     L77
  movupd 0x20(%rsi),%xmm0
  movupd 0x20(%rcx),%xmm3
  addpd  %xmm3,%xmm0
  movups %xmm0,0x20(%rax)
  cmp    $0x3,%r8d
  je     L77
  movupd 0x30(%rsi),%xmm0
  movupd 0x30(%rcx),%xmm4
  addpd  %xmm4,%xmm0
  movups %xmm0,0x30(%rax)
  cmp    $0x4,%r8d
  je     L77
  movupd 0x40(%rsi),%xmm0
  movupd 0x40(%rcx),%xmm5
  addpd  %xmm5,%xmm0
  movups %xmm0,0x40(%rax)
  cmp    $0x5,%r8d
  je     L77
  movupd 0x50(%rsi),%xmm0
  movupd 0x50(%rcx),%xmm6
  addpd  %xmm6,%xmm0
  movups %xmm0,0x50(%rax)
  cmp    $0x6,%r8d
  je     L77
  movupd 0x60(%rsi),%xmm0
  movupd 0x60(%rcx),%xmm7
  addpd  %xmm7,%xmm0
  movups %xmm0,0x60(%rax)
  cmp    $0x7,%r8d
  je     L77
  movupd 0x70(%rsi),%xmm0
  movupd 0x70(%rcx),%xmm7
  addpd  %xmm7,%xmm0
  movups %xmm0,0x70(%rax)
  cmp    $0x8,%r8d
  je     L77
  movupd 0x80(%rsi),%xmm0
  movupd 0x80(%rcx),%xmm6
  addpd  %xmm6,%xmm0
  movups %xmm0,0x80(%rax)
  cmp    $0x9,%r8d
  je     L77
  movupd 0x90(%rsi),%xmm0
  movupd 0x90(%rcx),%xmm5
  addpd  %xmm5,%xmm0
  movups %xmm0,0x90(%rax)
  cmp    $0xa,%r8d
  je     L77
  mov    $0xa0,%edi
  mov    $0xa,%r9d
L74:
  movupd (%rsi,%rdi,1),%xmm0
  movupd (%rcx,%rdi,1),%xmm4
  add    $0x1,%r9d
  addpd  %xmm4,%xmm0
  movups %xmm0,(%rax,%rdi,1)
  add    $0x10,%rdi
  cmp    %r8d,%r9d
  jne    L74
  xchg   %ax,%ax
L77:
  cmp    %ebp,%r11d
  je     L109
  movsd  (%rsi,%rdx,8),%xmm0
  addsd  (%rcx,%rdx,8),%xmm0
  movsd  %xmm0,(%rax,%rdx,8)
L109:
  add    $0xa0,%rax
  add    $0xa0,%rsi
  add    $0xa0,%rcx
  cmp    %rbx,%rax
  jne    L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L156:
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L139:
  movsd  (%rsi,%rdi,8),%xmm0
  addsd  (%rcx,%rdi,8),%xmm0
  movsd  %xmm0,(%rax,%rdi,8)
  add    $0x1,%rdi
  cmp    %rdi,%r10
  jne    L139
  jmp    L109
L106:
  ret
```

assistant: ```c
void double_add_matrix(unsigned int lines, unsigned int columns, double m1[20][20], double m2[20][20], double result[20][20]) {
  unsigned int i, j;
  for (i = 0; i < lines; i++) {
    for (j = 0; j < columns; j++) {
      result[i][j] = m1[i][j] + m2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmd_ends_with_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L32
  addq   $0x1,-0x8(%rbp)
L32:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmd_ends_with_space(const char *cmd) {
  while (cmd[0] != '\0' && cmd[1] != '\0') {
    if (cmd[0] == '\\')
      cmd++;
    cmd++;
  }
  return cmd[0] == ' ';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_ends_with_space>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
L37:
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  ret
L28:
  lea    0x2(%rdi),%rdx
  movzbl 0x2(%rdi),%eax
  test   %al,%al
  je     L37
  mov    %rdx,%rdi
L23:
  cmpb   $0x0,0x1(%rdi)
  je     L37
  cmp    $0x5c,%al
  je     L28
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdi
  jmp    L23
```

assistant: ```c
int cmd_ends_with_space(const char *cmd) {
  while (cmd[0] != '\0' && cmd[1] != '\0') {
    if (cmd[0] == '\\')
      cmd++;
    cmd++;
  }
  return cmd[0] == ' ';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmd_ends_with_space>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L38
L34:
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L46
L45:
  cmp    $0x5c,%dl
  je     L3
  add    $0x1,%rdi
  mov    %eax,%edx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  jne    L45
L46:
  xor    %eax,%eax
  cmp    $0x20,%dl
  sete   %al
  ret
  nop
L3:
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  test   %dl,%dl
  jne    L34
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmd_ends_with_space(const char *cmd) {
  while (cmd[0] != '\0' && cmd[1] != '\0') {
    if (cmd[0] == '\\')
      cmd++;
    cmd++;
  }
  return cmd[0] == ' ';
}
```