user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x64,-0x28(%rbp)
  movsd  D58(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movabs $0x1000000000000000,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x28(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  js     L9
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L19
L9:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L19:
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x0,-0x29(%rbp)
  movsbl -0x29(%rbp),%eax
  mov    -0x28(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x61,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D58
type: f64
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D11
type: string
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D0
type: string
name: retrieve_data
arguments: data_label: D44
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D58: 1.2

tool: D12: You have %d bugs at the imaginary rate of %f.


tool: D11: The entire universe has %ld bugs.


tool: D4: You are expected to have %f bugs.


tool: D0: That is only a %e portion of the universe.


tool: D44: Which means you should care %d%%.


tool: D10: Value is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %f.\n", bugs, bug_rate);
  unsigned long universe_of_defects = 1L * 1024L * 1024L * 1024L * 1024L * 1024L * 1024L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You are expected to have %f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  printf("Value is %d\n", 'a');
  return 0;
}
```