ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x9b,(%rsp)
  movl   $0xffffffc5,0x4(%rsp)
  movl   $0x12,0x8(%rsp)
  movl   $0x1d,0xc(%rsp)
  movl   $0x220,0x10(%rsp)
  movl   $0x1a,0x14(%rsp)
  movl   $0x1f,0x18(%rsp)
  movl   $0x2f,0x1c(%rsp)
  movl   $0x3b,0x20(%rsp)
  movl   $0x34e,0x24(%rsp)
  movl   $0x19,0x28(%rsp)
  movl   $0x3b,0x2c(%rsp)
  lea    D32(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x30(%rsp),%r12
  mov    %rbx,%rbp
  lea    D17(%rip),%r13
L0:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L0
  mov    %rsp,%rdi
  mov    $0xc,%esi
  call   <randomized_quicksort@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rbp
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L19
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D32
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D10
type: string

tool: D32: Before sorting

tool: D17: %d 

tool: D10: 
After sorting

assistant: ```c
int main(void) {
  int array[] = {155, -59, 18, 29, 544, 26, 31, 47, 59, 846, 25, 59};
  unsigned int i = 0;
  puts("Before sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  randomized_quicksort(array, sizeof(array) / sizeof(int));
  puts("\nAfter sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D21(%rip),%rdi
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xffffffc50000009b,%rax
  mov    %rsp,%r14
  lea    0x30(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0x1d00000012,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1a00000220,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x2f0000001f,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x34e0000003b,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x3b00000019,%rax
  mov    %rax,0x28(%rsp)
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L20
  mov    %r14,%rdi
  mov    $0xc,%esi
  call   <randomized_quicksort@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L9:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D13
datatype: string

tool: D21: Before sorting

tool: D19: %d 

tool: D13: 
After sorting

assistant: ```c
int main(void) {
  int array[] = {155, -59, 18, 29, 544, 26, 31, 47, 59, 846, 25, 59};
  unsigned int i = 0;
  puts("Before sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  randomized_quicksort(array, sizeof(array) / sizeof(int));
  puts("\nAfter sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x30(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D35(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  movaps %xmm0,0x10(%rsp)
  movdqa D43(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L9
  mov    %r14,%rdi
  mov    $0xc,%esi
  call   <randomized_quicksort@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L25:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L25
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: byte[16]
name: retrieve_data
arguments: label: D35
type_infered: byte[16]
name: retrieve_data
arguments: label: D43
type_infered: byte[16]
name: retrieve_data
arguments: label: D13
type_infered: string

tool: D15: Before sorting

tool: D10: %d 

tool: {"D3": [0x9b,0x00,0x00,0x00,0xc5,0xff,0xff,0xff,0x12,0x00,0x00,0x00,0x1d,0x00,0x00,0x00]}

tool: {"D35": [0x20,0x02,0x00,0x00,0x1a,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x2f,0x00,0x00,0x00]}

tool: {"D43": [0x3b,0x00,0x00,0x00,0x4e,0x03,0x00,0x00,0x19,0x00,0x00,0x00,0x3b,0x00,0x00,0x00]}

tool: D13: 
After sorting

assistant: ```c
int main(void) {
  int array[] = {155, -59, 18, 29, 544, 26, 31, 47, 59, 846, 25, 59};
  unsigned int i = 0;
  puts("Before sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  randomized_quicksort(array, sizeof(array) / sizeof(int));
  puts("\nAfter sorting");
  for (i = 0; i < sizeof(array) / sizeof(int); i++) {
    printf("%d ", array[i]);
  }
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L68
L29:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L42
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L64
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x28(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dfs>
  cmp    $0x1,%eax
  jne    L42
  mov    $0x1,%eax
  jmp    L30
L64:
  mov    $0x1,%eax
  jmp    L30
L42:
  addl   $0x1,-0x4(%rbp)
L68:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L29
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
int dfs(int **g, int *visited, int s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (g[s][i] == 1) {
      if (visited[i] == 0) {
        visited[i] = 1;
        if (dfs(g, visited, i, n) == 1) {
          return 1;
        }
      } else {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dfs>:
  endbr64
  test   %ecx,%ecx
  jle    L35
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %ecx,%r14d
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rbp
  mov    %ecx,%r12d
  mov    $0x0,%ebx
  jmp    L12
L59:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L48
L12:
  mov    %ebx,%edx
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,4),%eax
  cmp    $0x1,%eax
  jne    L59
  cmpl   $0x0,0x0(%r13,%rbx,4)
  jne    L62
  movl   $0x1,0x0(%r13,%rbx,4)
  mov    %r14d,%ecx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <dfs>
  cmp    $0x1,%eax
  jne    L59
  jmp    L62
L48:
  mov    $0x0,%eax
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int dfs(int **g, int *visited, int s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (g[s][i] == 1) {
      if (visited[i] == 0) {
        visited[i] = 1;
        if (dfs(g, visited, i, n) == 1) {
          return 1;
        }
      } else {
        return 1;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dfs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  jle    L59
  movslq %edx,%rdx
  mov    %rsi,%r14
  mov    %ecx,%r15d
  movslq %ecx,%r13
  mov    (%rdi,%rdx,8),%rbp
  xor    %ebx,%ebx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L59
L4:
  mov    0x0(%rbp,%rbx,4),%r12d
  mov    %ebx,%edx
  cmp    $0x1,%r12d
  jne    L19
  mov    (%r14,%rbx,4),%eax
  test   %eax,%eax
  jne    L65
  movl   $0x1,(%r14,%rbx,4)
  mov    %r15d,%ecx
  mov    %r14,%rsi
  mov    %rdi,0x8(%rsp)
  call   <dfs>
  mov    0x8(%rsp),%rdi
  cmp    $0x1,%eax
  jne    L19
L65:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  xor    %r12d,%r12d
  jmp    L65
```

assistant: ```c
int dfs(int **g, int *visited, int s, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (g[s][i] == 1) {
      if (visited[i] == 0) {
        visited[i] = 1;
        if (dfs(g, visited, i, n) == 1) {
          return 1;
        }
      } else {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<task_add_nanos_to_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x9,%rax
  movabs $0x44b82fa09b5a53,%rdx
  mul    %rdx
  shr    $0xb,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rax
  shr    $0x9,%rax
  movabs $0x44b82fa09b5a53,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0xb,%rax
  imul   $0x3b9aca00,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void task_add_nanos_to_timespec(struct timespec *time, unsigned long long add) {
  unsigned long long nanoseconds = time->tv_nsec;
  time_t seconds = time->tv_sec;
  nanoseconds += add;
  time->tv_sec = seconds + nanoseconds / 1000000000;
  time->tv_nsec = nanoseconds % 1000000000;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<task_add_nanos_to_timespec>:
  endbr64
  add    (%rdi),%rsi
  mov    %rsi,%rdx
  shr    $0x9,%rdx
  movabs $0x44b82fa09b5a53,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0xb,%rdx
  add    %rdx,0x8(%rdi)
  imul   $0x3b9aca00,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void task_add_nanos_to_timespec(struct timespec *time, unsigned long long add) {
  unsigned long long nanoseconds = time->tv_nsec;
  time_t seconds = time->tv_sec;
  nanoseconds += add;
  time->tv_sec = seconds + nanoseconds / 1000000000;
  time->tv_nsec = nanoseconds % 1000000000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<task_add_nanos_to_timespec>:
  endbr64
  movabs $0x44b82fa09b5a53,%rcx
  add    (%rdi),%rsi
  mov    %rsi,%rdx
  shr    $0x9,%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0xb,%rdx
  add    %rdx,0x8(%rdi)
  imul   $0x3b9aca00,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void task_add_nanos_to_timespec(struct timespec *time, unsigned long long add) {
  unsigned long long nanoseconds = time->tv_nsec;
  time_t seconds = time->tv_sec;
  nanoseconds += add;
  time->tv_sec = seconds + nanoseconds / 1000000000;
  time->tv_nsec = nanoseconds % 1000000000;
}
```
user: What is the c source code of the assembly code below:

```asm
<task_add_nanos_to_timespec>:
  endbr64
  movabs $0x44b82fa09b5a53,%rcx
  add    (%rdi),%rsi
  mov    %rsi,%rdx
  shr    $0x9,%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0xb,%rdx
  add    %rdx,0x8(%rdi)
  imul   $0x3b9aca00,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void task_add_nanos_to_timespec(struct timespec *time, unsigned long long add) {
  unsigned long long nanoseconds = time->tv_nsec;
  time_t seconds = time->tv_sec;
  nanoseconds += add;
  time->tv_sec = seconds + nanoseconds / 1000000000;
  time->tv_nsec = nanoseconds % 1000000000;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    %eax,%ecx
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: %d %d %d

assistant: ```c
void print() {
  int i = 1;
  printf("%d %d %d", ++i, i, i++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %d %d %d

assistant: ```c
void print() {
  int i = 1;
  printf("%d %d %d", ++i, i, i++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print>:
  endbr64
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %d %d %d

assistant: ```c
void print() {
  int i = 1;
  printf("%d %d %d", ++i, i, i++);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print>:
  endbr64
  mov    $0x1,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: %d %d %d

assistant: ```c
void print() {
  int i = 1;
  printf("%d %d %d", ++i, i, i++);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_rem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  je     L95
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L61
L95:
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <urem_i8@plt>
  test   %rax,%rax
  je     L63
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L61
L63:
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  je     L6
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L61
L6:
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <srem_i16@plt>
  cmp    $0xfffffffd,%eax
  je     L99
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L61
L99:
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <urem_i16@plt>
  cmp    $0x6,%eax
  je     L3
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L61
L3:
  mov    $0x400,%eax
L61:
  pop    %rbp
  ret
```

assistant: ```c
int test_rem(void) {
  if (srem_i8(-1, 1) != 0)
    return fail(0);
  if (urem_i8(-1, 1) != 0)
    return fail(0);
  if (srem_i8(1, -1) != 0)
    return fail(0);
  if (srem_i16(-535, 7) != -3)
    return fail(0);
  if (urem_i16(-535, 7) != 6)
    return fail(0);
  return 0x400;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_rem>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L83
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <urem_i8@plt>
  test   %rax,%rax
  jne    L5
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <srem_i16@plt>
  cmp    $0xfffffffd,%eax
  je     L43
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L62
L83:
  mov    $0x0,%edi
  call   <fail@plt>
L62:
  add    $0x8,%rsp
  ret
L5:
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L62
L7:
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L62
L43:
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <urem_i16@plt>
  mov    %eax,%edx
  mov    $0x400,%eax
  cmp    $0x6,%edx
  je     L62
  mov    $0x0,%edi
  call   <fail@plt>
  jmp    L62
```

assistant: ```c
int test_rem(void) {
  if (srem_i8(-1, 1) != 0)
    return fail(0);
  if (urem_i8(-1, 1) != 0)
    return fail(0);
  if (srem_i8(1, -1) != 0)
    return fail(0);
  if (srem_i16(-535, 7) != -3)
    return fail(0);
  if (urem_i16(-535, 7) != 6)
    return fail(0);
  return 0x400;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_rem>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <urem_i8@plt>
  test   %rax,%rax
  jne    L37
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <srem_i16@plt>
  cmp    $0xfffffffd,%eax
  jne    L37
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <urem_i16@plt>
  cmp    $0x6,%eax
  jne    L37
  mov    $0x400,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <fail@plt>
```

assistant: ```c
int test_rem(void) {
  if (srem_i8(-1, 1) != 0)
    return fail(0);
  if (urem_i8(-1, 1) != 0)
    return fail(0);
  if (srem_i8(1, -1) != 0)
    return fail(0);
  if (srem_i16(-535, 7) != -3)
    return fail(0);
  if (urem_i16(-535, 7) != 6)
    return fail(0);
  return 0x400;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_rem>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <urem_i8@plt>
  test   %rax,%rax
  jne    L16
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <srem_i8@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <srem_i16@plt>
  cmp    $0xfffffffd,%eax
  jne    L16
  mov    $0x7,%esi
  mov    $0xfffffde9,%edi
  call   <urem_i16@plt>
  cmp    $0x6,%eax
  jne    L16
  mov    $0x400,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <fail@plt>
```

assistant: ```c
int test_rem(void) {
  if (srem_i8(-1, 1) != 0)
    return fail(0);
  if (urem_i8(-1, 1) != 0)
    return fail(0);
  if (srem_i8(1, -1) != 0)
    return fail(0);
  if (srem_i16(-535, 7) != -3)
    return fail(0);
  if (urem_i16(-535, 7) != 6)
    return fail(0);
  return 0x400;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L4:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash(const char *s, int num_buckets) {
  unsigned hash_val;
  char *p;
  p = (char *)s;
  hash_val = 0;
  while (*p) {
    hash_val = hash_val * 31 + *p++;
  }
  return hash_val % num_buckets;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L20
  mov    $0x0,%eax
L19:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  add    $0x1,%rdi
  movsbl %dl,%edx
  lea    (%rdx,%rcx,1),%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
L21:
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%eax
  ret
L20:
  mov    $0x0,%eax
  jmp    L21
```

assistant: ```c
unsigned hash(const char *s, int num_buckets) {
  unsigned hash_val;
  char *p;
  p = (char *)s;
  hash_val = 0;
  while (*p) {
    hash_val = hash_val * 31 + *p++;
  }
  return hash_val % num_buckets;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  xor    %eax,%eax
  nopl   (%rax)
L3:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  sub    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(const char *s, int num_buckets) {
  unsigned hash_val;
  char *p;
  p = (char *)s;
  hash_val = 0;
  while (*p) {
    hash_val = hash_val * 31 + *p++;
  }
  return hash_val % num_buckets;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L1
  xor    %eax,%eax
  nopl   (%rax)
L3:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  sub    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(const char *s, int num_buckets) {
  unsigned hash_val;
  char *p;
  p = (char *)s;
  hash_val = 0;
  while (*p) {
    hash_val = hash_val * 31 + *p++;
  }
  return hash_val % num_buckets;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D6: %d

tool: D3: %c

assistant: ```c
int main(void) {
  int a;
  scanf("%d", &a);
  printf("%c", a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D15
data_type: string

tool: D10: %d

tool: D15: %c

assistant: ```c
int main(void) {
  int a;
  scanf("%d", &a);
  printf("%c", a);
  return 0;
}
```