ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<longCmpFn>:
  endbr64
  mov    (%rsi),%rdx
  xor    %eax,%eax
  cmp    %rdx,(%rdi)
  je     L8
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L8:
  ret
```

assistant: ```c
int longCmpFn(const void *p1, const void *p2) {
  long v1, v2;
  v1 = *((long *)p1);
  v2 = *((long *)p2);
  if (v1 == v2)
    return 0;
  return (v1 < v2) ? -1 : +1;
}
```
user: What is the c source code of the assembly code below:

```asm
<multiple_ir_debug_section_item_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int multiple_ir_debug_section_item_destroy(struct multiple_ir_debug_section_item *item) {
  free(item);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiple_ir_debug_section_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int multiple_ir_debug_section_item_destroy(struct multiple_ir_debug_section_item *item) {
  free(item);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiple_ir_debug_section_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int multiple_ir_debug_section_item_destroy(struct multiple_ir_debug_section_item *item) {
  free(item);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<multiple_ir_debug_section_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int multiple_ir_debug_section_item_destroy(struct multiple_ir_debug_section_item *item) {
  free(item);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_mate_readid_matching>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L46
  mov    $0x0,%eax
  jmp    L54
L46:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L2
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L2
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L41
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  je     L35
L41:
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  jne    L2
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L2
  mov    -0x14(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L2
L35:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  jmp    L54
L2:
  movl   $0x0,-0x18(%rbp)
  jmp    L37
L22:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L77
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L77
  mov    -0x18(%rbp),%eax
  jmp    L54
L77:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L1
  mov    $0x0,%eax
  jmp    L54
L1:
  addl   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L22
  mov    -0x14(%rbp),%eax
L54:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char check_mate_readid_matching(char *read_id1, char *read_id2) {
  int i, slen;
  if (strlen(read_id1) != strlen(read_id2))
    return 0;
  slen = strlen(read_id1);
  if (read_id1[slen - 2] == '/' && read_id2[slen - 2] == '/' && ((read_id1[slen - 1] == '1' && read_id2[slen - 1] == '2') || (read_id1[slen - 1] == '2' && read_id2[slen - 1] == '1') && strncmp(read_id1, read_id2, slen - 2) == 0))
    return (slen - 2);
  else {
    for (i = 0; i < slen; i++) {
      if (read_id1[i] == ' ' && read_id2[i] == ' ')
        return i;
      if (read_id1[i] != read_id2[i])
        return 0;
    }
    return (slen);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_mate_readid_matching>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%r12d
  jne    L148
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cltq
  cmpb   $0x2f,-0x2(%rbp,%rax,1)
  je     L67
L164:
  test   %r12d,%r12d
  jle    L65
  mov    %r12d,%ecx
  mov    $0x0,%eax
  jmp    L100
L67:
  cmpb   $0x2f,-0x2(%rbx,%rax,1)
  jne    L164
  movzbl -0x1(%rbp,%rax,1),%edx
  cmp    $0x31,%dl
  je     L59
  cmp    $0x32,%dl
  jne    L164
  cmpb   $0x31,-0x1(%rbx,%rax,1)
  jne    L164
  lea    -0x2(%r12),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L164
  jmp    L114
L59:
  cmpb   $0x32,-0x1(%rbx,%rax,1)
  jne    L164
L114:
  lea    -0x2(%r12),%eax
  jmp    L148
L61:
  cmp    (%rbx,%rax,1),%dl
  jne    L62
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L65
L100:
  movzbl 0x0(%rbp,%rax,1),%edx
  cmp    $0x20,%dl
  jne    L61
  cmpb   $0x20,(%rbx,%rax,1)
  mov    $0x0,%edx
  cmovne %edx,%eax
L148:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  mov    %r12d,%eax
  jmp    L148
L62:
  mov    $0x0,%eax
  jmp    L148
```

assistant: ```c
char check_mate_readid_matching(char *read_id1, char *read_id2) {
  int i, slen;
  if (strlen(read_id1) != strlen(read_id2))
    return 0;
  slen = strlen(read_id1);
  if (read_id1[slen - 2] == '/' && read_id2[slen - 2] == '/' && ((read_id1[slen - 1] == '1' && read_id2[slen - 1] == '2') || (read_id1[slen - 1] == '2' && read_id2[slen - 1] == '1') && strncmp(read_id1, read_id2, slen - 2) == 0))
    return (slen - 2);
  else {
    for (i = 0; i < slen; i++) {
      if (read_id1[i] == ' ' && read_id2[i] == ' ')
        return i;
      if (read_id1[i] != read_id2[i])
        return 0;
    }
    return (slen);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_mate_readid_matching>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  je     L124
L52:
  xor    %eax,%eax
L103:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L124:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%r13
  cmpb   $0x2f,-0x2(%rbx,%r13,1)
  mov    %r13,%r12
  je     L83
L168:
  test   %r12d,%r12d
  jle    L99
  xor    %edx,%edx
  jmp    L149
  nop
L146:
  cmp    %sil,%cl
  jne    L52
  add    $0x1,%rdx
  cmp    %rdx,%r13
  je     L99
L149:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    $0x20,%cl
  jne    L146
  mov    %edx,%eax
  cmp    $0x20,%sil
  jne    L52
  jmp    L103
  cs nopw 0x0(%rax,%rax,1)
L99:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L83:
  cmpb   $0x2f,-0x2(%rbp,%r13,1)
  jne    L168
  movzbl -0x1(%rbx,%r13,1),%eax
  cmp    $0x31,%al
  je     L32
  cmp    $0x32,%al
  jne    L168
  cmpb   $0x31,-0x1(%rbp,%r13,1)
  jne    L168
  lea    -0x2(%r13),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L168
L122:
  lea    -0x2(%r12),%eax
  jmp    L103
L32:
  cmpb   $0x32,-0x1(%rbp,%r13,1)
  jne    L168
  jmp    L122
```

assistant: ```c
char check_mate_readid_matching(char *read_id1, char *read_id2) {
  int i, slen;
  if (strlen(read_id1) != strlen(read_id2))
    return 0;
  slen = strlen(read_id1);
  if (read_id1[slen - 2] == '/' && read_id2[slen - 2] == '/' && ((read_id1[slen - 1] == '1' && read_id2[slen - 1] == '2') || (read_id1[slen - 1] == '2' && read_id2[slen - 1] == '1') && strncmp(read_id1, read_id2, slen - 2) == 0))
    return (slen - 2);
  else {
    for (i = 0; i < slen; i++) {
      if (read_id1[i] == ' ' && read_id2[i] == ' ')
        return i;
      if (read_id1[i] != read_id2[i])
        return 0;
    }
    return (slen);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_mate_readid_matching>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  cmp    %eax,%r12d
  je     L54
L15:
  xor    %eax,%eax
L137:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%r13
  cmpb   $0x2f,-0x2(%rbx,%r13,1)
  mov    %r13,%r12
  je     L32
L147:
  test   %r12d,%r12d
  jle    L98
  xor    %edx,%edx
  jmp    L134
  nop
L25:
  cmp    %sil,%cl
  jne    L15
  add    $0x1,%rdx
  cmp    %rdx,%r13
  je     L98
L134:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl 0x0(%rbp,%rdx,1),%esi
  cmp    $0x20,%cl
  jne    L25
  mov    %edx,%eax
  cmp    $0x20,%sil
  jne    L15
  jmp    L137
  cs nopw 0x0(%rax,%rax,1)
L98:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L32:
  cmpb   $0x2f,-0x2(%rbp,%r13,1)
  jne    L147
  movzbl -0x1(%rbx,%r13,1),%eax
  cmp    $0x31,%al
  je     L160
  cmp    $0x32,%al
  jne    L147
  cmpb   $0x31,-0x1(%rbp,%r13,1)
  jne    L147
  lea    -0x2(%r13),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L147
L91:
  lea    -0x2(%r12),%eax
  jmp    L137
L160:
  cmpb   $0x32,-0x1(%rbp,%r13,1)
  jne    L147
  jmp    L91
```

assistant: ```c
char check_mate_readid_matching(char *read_id1, char *read_id2) {
  int i, slen;
  if (strlen(read_id1) != strlen(read_id2))
    return 0;
  slen = strlen(read_id1);
  if (read_id1[slen - 2] == '/' && read_id2[slen - 2] == '/' && ((read_id1[slen - 1] == '1' && read_id2[slen - 1] == '2') || (read_id1[slen - 1] == '2' && read_id2[slen - 1] == '1') && strncmp(read_id1, read_id2, slen - 2) == 0))
    return (slen - 2);
  else {
    for (i = 0; i < slen; i++) {
      if (read_id1[i] == ' ' && read_id2[i] == ' ')
        return i;
      if (read_id1[i] != read_id2[i])
        return 0;
    }
    return (slen);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrix_display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
void matrix_display(int (*matrix)[2], int dimen) {
  for (int i = 0; i < dimen; i++) {
    for (int j = 0; j < dimen; j++)
      printf("%d ", matrix[i][j]);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<matrix_display>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
  lea    (%rax,%rax,2),%rax
  lea    0xc(%rdi,%rax,4),%r13
  mov    %esi,%esi
  neg    %rsi
  lea    0x0(,%rsi,4),%r12
  lea    D6(%rip),%r14
  jmp    L39
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L4
L39:
  lea    (%r12,%rbp,1),%rbx
L23:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L23
  jmp    L20
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: %d 

assistant: ```c
void matrix_display(int (*matrix)[2], int dimen) {
  for (int i = 0; i < dimen; i++) {
    for (int j = 0; j < dimen; j++)
      printf("%d ", matrix[i][j]);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix_display>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r14
  lea    -0x1(%rsi),%eax
  push   %r13
  lea    0x0(,%rax,4),%rdx
  mov    $0xfffffffffffffffc,%r13
  lea    (%rax,%rax,2),%rax
  push   %r12
  lea    0xc(%rdi,%rax,4),%r14
  lea    D1(%rip),%r12
  sub    %rdx,%r13
  push   %rbp
  lea    0x4(%rdi,%rdx,1),%rbp
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L28:
  lea    0x0(%r13,%rbp,1),%rbx
L25:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L25
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: %d 

assistant: ```c
void matrix_display(int (*matrix)[2], int dimen) {
  for (int i = 0; i < dimen; i++) {
    for (int j = 0; j < dimen; j++)
      printf("%d ", matrix[i][j]);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_display>:
  endbr64
  test   %esi,%esi
  jle    L49
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    -0x4(%rsi),%r14d
  push   %r13
  lea    0x14(%rdi,%rax,8),%r13
  lea    0x1(%r14),%rax
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0xc(%rdi),%rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L38:
  mov    -0xc(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  je     L26
  mov    -0x8(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  je     L26
  mov    -0x4(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebp
  je     L26
  mov    0x8(%rsp),%rax
  mov    %rbx,%r14
  lea    (%rbx,%rax,4),%r15
L3:
  mov    (%r14),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %r15,%r14
  jne    L3
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: %d 

assistant: ```c
void matrix_display(int (*matrix)[2], int dimen) {
  for (int i = 0; i < dimen; i++) {
    for (int j = 0; j < dimen; j++)
      printf("%d ", matrix[i][j]);
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main_dos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_arg@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <chk_arg@plt>
  mov    $0x0,%eax
  call   <init_game@plt>
  mov    $0x0,%eax
  call   <game_main@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int main_dos(int argc, char **argv) {
  init_arg();
  chk_arg(argc, argv);
  init_game();
  game_main();
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main_dos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <init_arg@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <chk_arg@plt>
  mov    $0x0,%eax
  call   <init_game@plt>
  mov    $0x0,%eax
  call   <game_main@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main_dos(int argc, char **argv) {
  init_arg();
  chk_arg(argc, argv);
  init_game();
  game_main();
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main_dos>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <init_arg@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <chk_arg@plt>
  xor    %eax,%eax
  call   <init_game@plt>
  xor    %eax,%eax
  call   <game_main@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main_dos(int argc, char **argv) {
  init_arg();
  chk_arg(argc, argv);
  init_game();
  game_main();
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main_dos>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <init_arg@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <chk_arg@plt>
  xor    %eax,%eax
  call   <init_game@plt>
  xor    %eax,%eax
  call   <game_main@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main_dos(int argc, char **argv) {
  init_arg();
  chk_arg(argc, argv);
  init_game();
  game_main();
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<task2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3d0900,%edi
  call   <fib_s@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int task2() {
  long t2 = fib_s(4000000);
  return t2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<task2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d0900,%edi
  call   <fib_s@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int task2() {
  long t2 = fib_s(4000000);
  return t2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<task2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d0900,%edi
  call   <fib_s@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int task2() {
  long t2 = fib_s(4000000);
  return t2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<task2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d0900,%edi
  call   <fib_s@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int task2() {
  long t2 = fib_s(4000000);
  return t2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L1
L24:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while ((*s1 == *s2) && *s1) {
    s1++;
    s2++;
  }
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  test   %al,%al
  je     L1
  cmp    %cl,%al
  jne    L1
  mov    $0x1,%edx
L27:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L1
  cmp    %cl,%al
  je     L27
L1:
  movzbl %al,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while ((*s1 == *s2) && *s1) {
    s1++;
    s2++;
  }
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %dl,%cl
  je     L38
  jmp    L37
  nopl   (%rax)
L16:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L37
L38:
  test   %dl,%dl
  jne    L16
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while ((*s1 == *s2) && *s1) {
    s1++;
    s2++;
  }
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  cmp    %dl,%cl
  je     L18
  jmp    L26
  nopl   (%rax)
L19:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L26
L18:
  test   %dl,%dl
  jne    L19
  xor    %eax,%eax
  sub    %ecx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while ((*s1 == *s2) && *s1) {
    s1++;
    s2++;
  }
  return *(const unsigned char *)s1 - *(const unsigned char *)s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L10
L19:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L4
L27:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x14(%rbp)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jg     L27
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *permutation(int size) {
  int *elements = malloc(sizeof(int) * size);
  for (int i = 0; i < size; ++i)
    elements[i] = i;
  for (int i = size - 1; i > 0; --i) {
    int w = rand() % i;
    int t = elements[i];
    elements[i] = elements[w];
    elements[w] = t;
  }
  return elements;
}
```