ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Setsockopt>:
  endbr64
  sub    $0x8,%rsp
  call   <setsockopt@plt>
  test   %rax,%rax
  js     L1
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <err_sys@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: setsockopt error

assistant: ```c
void Setsockopt(int fd, int level, int optname, const void *optval, socklen_t optlen) {
  if (setsockopt(fd, level, optname, optval, optlen) < 0)
    err_sys("setsockopt error");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Setsockopt>:
  endbr64
  sub    $0x8,%rsp
  call   <setsockopt@plt>
  test   %rax,%rax
  js     L5
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <err_sys@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: setsockopt error

assistant: ```c
void Setsockopt(int fd, int level, int optname, const void *optval, socklen_t optlen) {
  if (setsockopt(fd, level, optname, optval, optlen) < 0)
    err_sys("setsockopt error");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mdoc_ud_pre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print_text@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: currently under development.

assistant: ```c
int mdoc_ud_pre(const struct mdoc_meta *m, const struct mdoc_node *n, struct html *h) {
  print_text(h, "currently under development.");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mdoc_ud_pre>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D5(%rip),%rsi
  call   <print_text@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: currently under development.

assistant: ```c
int mdoc_ud_pre(const struct mdoc_meta *m, const struct mdoc_node *n, struct html *h) {
  print_text(h, "currently under development.");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<mdoc_ud_pre>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D7(%rip),%rsi
  call   <print_text@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: currently under development.

assistant: ```c
int mdoc_ud_pre(const struct mdoc_meta *m, const struct mdoc_node *n, struct html *h) {
  print_text(h, "currently under development.");
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mdoc_ud_pre>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rdi
  lea    D4(%rip),%rsi
  call   <print_text@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: currently under development.

assistant: ```c
int mdoc_ud_pre(const struct mdoc_meta *m, const struct mdoc_node *n, struct html *h) {
  print_text(h, "currently under development.");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_proc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %edi,-0x1c4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%edi
  call   <saw_this_pid@plt>
  test   %rax,%rax
  jne    L2
  lea    -0x1bc(%rbp),%rdx
  mov    -0x1c4(%rbp),%eax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_int@plt>
  cmp    $0xffffffff,%eax
  je     L48
  mov    -0x1c4(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D30(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x1b0(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  jne    L25
  movb   $0x0,-0x1b0(%rbp)
L25:
  mov    -0x1bc(%rbp),%eax
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,-0x1b8(%rbp)
  mov    -0x1c4(%rbp),%eax
  mov    %eax,%edi
  call   <mark_seen@plt>
  cmpq   $0x0,-0x1b8(%rbp)
  je     L72
  mov    -0x1b8(%rbp),%rax
  mov    (%rax),%rax
  jmp    L20
L72:
  lea    D39(%rip),%rax
L20:
  lea    -0x1b0(%rbp),%rdx
  mov    -0x1c4(%rbp),%esi
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
L2:
  nop
  jmp    L3
L48:
  nop
L3:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D30
data_type: string
name: read_data
arguments: data_label: D39
data_type: string
name: read_data
arguments: data_label: D25
data_type: string

tool: D10: uid

tool: D30: /proc/%d/exe

tool: D39: ???

tool: D25: %4d %s %s


assistant: ```c
void print_proc(int pid) {
  if (saw_this_pid(pid))
    return;
  int uid;
  if (read_int(pid, "uid", &uid) == -1)
    return;
  char path[256];
  char link[156];
  sprintf(path, "/proc/%d/exe", pid);
  if (readlink(path, link, 256) == -1)
    link[0] = 0;
  struct passwd *pw;
  pw = getpwuid(uid);
  mark_seen(pid);
  printf("%4d %s %s\n", pid, pw ? pw->pw_name : "???", link);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_proc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <saw_this_pid@plt>
  test   %rax,%rax
  je     L10
L28:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    0xc(%rsp),%rdx
  lea    D0(%rip),%rsi
  mov    %ebx,%edi
  call   <read_int@plt>
  cmp    $0xffffffff,%eax
  je     L28
  lea    0xb0(%rsp),%rbp
  mov    %ebx,%edx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x10(%rsp),%rsi
  mov    $0x100,%edx
  mov    %rbp,%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  je     L5
L25:
  mov    0xc(%rsp),%edi
  call   <getpwuid@plt>
  mov    %rax,%rbp
  mov    %ebx,%edi
  call   <mark_seen@plt>
  lea    D18(%rip),%rdx
  test   %rbp,%rbp
  je     L33
  mov    0x0(%rbp),%rdx
L33:
  lea    0x10(%rsp),%rcx
  mov    %ebx,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L5:
  movb   $0x0,0x10(%rsp)
  jmp    L25
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string

tool: D0: uid

tool: D1: /proc/%d/exe

tool: D18: ???

tool: D13: %4d %s %s


assistant: ```c
void print_proc(int pid) {
  if (saw_this_pid(pid))
    return;
  int uid;
  if (read_int(pid, "uid", &uid) == -1)
    return;
  char path[256];
  char link[156];
  sprintf(path, "/proc/%d/exe", pid);
  if (readlink(path, link, 256) == -1)
    link[0] = 0;
  struct passwd *pw;
  pw = getpwuid(uid);
  mark_seen(pid);
  printf("%4d %s %s\n", pid, pw ? pw->pw_name : "???", link);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_proc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <saw_this_pid@plt>
  test   %rax,%rax
  je     L49
L42:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L49:
  lea    0xc(%rsp),%rdx
  lea    D29(%rip),%rsi
  mov    %ebp,%edi
  call   <read_int@plt>
  cmp    $0xffffffff,%eax
  je     L42
  lea    0xb0(%rsp),%r13
  mov    %ebp,%edx
  lea    0x10(%rsp),%r12
  lea    D8(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x100,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  movb   $0x0,0x10(%rsp)
L9:
  mov    0xc(%rsp),%edi
  call   <getpwuid@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <mark_seen@plt>
  lea    D13(%rip),%rdx
  test   %rbx,%rbx
  je     L19
  mov    (%rbx),%rdx
L19:
  mov    %r12,%rcx
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D8
type: string
name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D22
type: string

tool: D29: uid

tool: D8: /proc/%d/exe

tool: D13: ???

tool: D22: %4d %s %s


assistant: ```c
void print_proc(int pid) {
  if (saw_this_pid(pid))
    return;
  int uid;
  if (read_int(pid, "uid", &uid) == -1)
    return;
  char path[256];
  char link[156];
  sprintf(path, "/proc/%d/exe", pid);
  if (readlink(path, link, 256) == -1)
    link[0] = 0;
  struct passwd *pw;
  pw = getpwuid(uid);
  mark_seen(pid);
  printf("%4d %s %s\n", pid, pw ? pw->pw_name : "???", link);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_proc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <saw_this_pid@plt>
  test   %rax,%rax
  je     L3
L37:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1c8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L3:
  lea    0xc(%rsp),%rdx
  lea    D37(%rip),%rsi
  mov    %ebp,%edi
  call   <read_int@plt>
  cmp    $0xffffffff,%eax
  je     L37
  lea    0xb0(%rsp),%r13
  mov    %ebp,%edx
  lea    0x10(%rsp),%r12
  lea    D16(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x100,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <readlink@plt>
  cmp    $0xffffffff,%eax
  jne    L27
  movb   $0x0,0x10(%rsp)
L27:
  mov    0xc(%rsp),%edi
  call   <getpwuid@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <mark_seen@plt>
  lea    D2(%rip),%rdx
  test   %rbx,%rbx
  je     L46
  mov    (%rbx),%rdx
L46:
  mov    %r12,%rcx
  mov    %ebp,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D37
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D39
type_infered: string

tool: D37: uid

tool: D16: /proc/%d/exe

tool: D2: ???

tool: D39: %4d %s %s


assistant: ```c
void print_proc(int pid) {
  if (saw_this_pid(pid))
    return;
  int uid;
  if (read_int(pid, "uid", &uid) == -1)
    return;
  char path[256];
  char link[156];
  sprintf(path, "/proc/%d/exe", pid);
  if (readlink(path, link, 256) == -1)
    link[0] = 0;
  struct passwd *pw;
  pw = getpwuid(uid);
  mark_seen(pid);
  printf("%4d %s %s\n", pid, pw ? pw->pw_name : "???", link);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printid@plt>
  addl   $0x5,-0x4(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printid@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string

tool: D2: a  2

tool: D14: a  7

assistant: ```c
int main() {
  int a = 2;
  print("a  2");
  printid(a);
  a = a + 5;
  print("a  7");
  printid(a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%edi
  call   <printid@plt>
  lea    D0(%rip),%rdi
  call   <print@plt>
  mov    $0x7,%edi
  call   <printid@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D1: a  2

tool: D0: a  7

assistant: ```c
int main() {
  int a = 2;
  print("a  2");
  printid(a);
  a = a + 5;
  print("a  7");
  printid(a);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%edi
  call   <printid@plt>
  lea    D8(%rip),%rdi
  call   <print@plt>
  mov    $0x7,%edi
  call   <printid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D8
type: string

tool: D19: a  2

tool: D8: a  7

assistant: ```c
int main() {
  int a = 2;
  print("a  2");
  printid(a);
  a = a + 5;
  print("a  7");
  printid(a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <print@plt>
  mov    $0x2,%edi
  call   <printid@plt>
  lea    D9(%rip),%rdi
  call   <print@plt>
  mov    $0x7,%edi
  call   <printid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D9
type: string

tool: D14: a  2

tool: D9: a  7

assistant: ```c
int main() {
  int a = 2;
  print("a  2");
  printid(a);
  a = a + 5;
  print("a  7");
  printid(a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_username>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: USER

assistant: ```c
char *get_username() {
  char *username = (char *)calloc(strlen(getenv("USER")) + 1, sizeof(char));
  if (!username)
    exit(1);
  strcpy(username, getenv("USER"));
  return username;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_username>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L5:
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
L18:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: USER

assistant: ```c
char *get_username() {
  char *username = (char *)calloc(strlen(getenv("USER")) + 1, sizeof(char));
  if (!username)
    exit(1);
  strcpy(username, getenv("USER"));
  return username;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_username>:
  endbr64
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <getenv@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L9:
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: USER

assistant: ```c
char *get_username() {
  char *username = (char *)calloc(strlen(getenv("USER")) + 1, sizeof(char));
  if (!username)
    exit(1);
  strcpy(username, getenv("USER"));
  return username;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_username>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <getenv@plt>
  mov    %eax,%edi
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L19:
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: USER

assistant: ```c
char *get_username() {
  char *username = (char *)calloc(strlen(getenv("USER")) + 1, sizeof(char));
  if (!username)
    exit(1);
  strcpy(username, getenv("USER"));
  return username;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<controller_tab_prev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <tab_show_prev@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int controller_tab_prev(int k) {
  tab_show_prev();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<controller_tab_prev>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tab_show_prev@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int controller_tab_prev(int k) {
  tab_show_prev();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<controller_tab_prev>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tab_show_prev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int controller_tab_prev(int k) {
  tab_show_prev();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<controller_tab_prev>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tab_show_prev@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int controller_tab_prev(int k) {
  tab_show_prev();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<predictor_banner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L55
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D91(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D91(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D36(%rip),%rax
  jmp    L13
  lea    D15(%rip),%rax
  jmp    L13
  lea    D49(%rip),%rax
  jmp    L13
  lea    D3(%rip),%rax
  jmp    L13
  lea    D14(%rip),%rax
  jmp    L13
  lea    D85(%rip),%rax
  jmp    L13
  lea    D73(%rip),%rax
  jmp    L13
L55:
  lea    D74(%rip),%rax
L13:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D49
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D85
data_type: string
name: retrieve_data
arguments: tag: D73
data_type: string
name: retrieve_data
arguments: tag: D74
data_type: string

tool: D36: ( x:Sec,t:Rea )

tool: D15: ( x:Sec,t:Com )

tool: D49: ( x:Sec,t:Geo )

tool: D3: ( x:Tan,t:Rea )

tool: D14: ( x:Tan,t:Com )

tool: D85: ( x:Tan,t:Geo )

tool: D73: ( x:Her,t:Rea )

tool: D74:  no predictor  

assistant: ```c
const char *predictor_banner(int pred_type) {
  switch (pred_type) {
  case 0:
    return "( x:Sec,t:Rea )";
  case 1:
    return "( x:Sec,t:Com )";
  case 2:
    return "( x:Sec,t:Geo )";
  case 3:
    return "( x:Tan,t:Rea )";
  case 4:
    return "( x:Tan,t:Com )";
  case 5:
    return "( x:Tan,t:Geo )";
  case 6:
    return "( x:Her,t:Rea )";
  default:
    return " no predictor  ";
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<predictor_banner>:
  endbr64
  cmp    $0x6,%edi
  ja     L0
  mov    %edi,%edi
  lea    D64(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D7(%rip),%rax
  ret
  lea    D77(%rip),%rax
  ret
  lea    D69(%rip),%rax
  ret
  lea    D54(%rip),%rax
  ret
  lea    D61(%rip),%rax
  ret
  lea    D3(%rip),%rax
  ret
L0:
  lea    D79(%rip),%rax
  ret
  lea    D43(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D77
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D69
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D54
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D61
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D79
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D43
type_guessed: string

tool: D7: ( x:Sec,t:Com )

tool: D77: ( x:Sec,t:Geo )

tool: D69: ( x:Tan,t:Rea )

tool: D54: ( x:Tan,t:Com )

tool: D61: ( x:Tan,t:Geo )

tool: D3: ( x:Her,t:Rea )

tool: D79:  no predictor  

tool: D43: ( x:Sec,t:Rea )

assistant: ```c
const char *predictor_banner(int pred_type) {
  switch (pred_type) {
  case 0:
    return "( x:Sec,t:Rea )";
  case 1:
    return "( x:Sec,t:Com )";
  case 2:
    return "( x:Sec,t:Geo )";
  case 3:
    return "( x:Tan,t:Rea )";
  case 4:
    return "( x:Tan,t:Com )";
  case 5:
    return "( x:Tan,t:Geo )";
  case 6:
    return "( x:Her,t:Rea )";
  default:
    return " no predictor  ";
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: (%d): %s


assistant: ```c
int print(line, message)
int line;
const char *message;
{ return printf("(%d): %s\n", line, message); }
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: (%d): %s


assistant: ```c
int print(line, message)
int line;
const char *message;
{ return printf("(%d): %s\n", line, message); }
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print>:
  endbr64
  mov    %rsi,%rdx
  xor    %eax,%eax
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: (%d): %s


assistant: ```c
int print(line, message)
int line;
const char *message;
{ return printf("(%d): %s\n", line, message); }
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print>:
  endbr64
  mov    %rsi,%rdx
  xor    %eax,%eax
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string

tool: D3: (%d): %s


assistant: ```c
int print(line, message)
int line;
const char *message;
{ return printf("(%d): %s\n", line, message); }
```