ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd2,%ecx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: Suma liczb naturalnych od %d do %d wynosi %d 


assistant: ```c
int main() {
  int suma, licznik, start, stop;
  suma = 0;
  start = 1;
  stop = 20;
  for (licznik = start; licznik <= stop; licznik++) {
    suma = suma + licznik;
  }
  printf("Suma liczb naturalnych od %d do %d wynosi %d \n", start, stop, suma);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd2,%ecx
  mov    $0x14,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: Suma liczb naturalnych od %d do %d wynosi %d 


assistant: ```c
int main() {
  int suma, licznik, start, stop;
  suma = 0;
  start = 1;
  stop = 20;
  for (licznik = start; licznik <= stop; licznik++) {
    suma = suma + licznik;
  }
  printf("Suma liczb naturalnych od %d do %d wynosi %d \n", start, stop, suma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unscalex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void unscalex(int n, double x[], const double xscale[], const double xoffset[]) {
  int i;
  for (i = 0; i < n; i++) {
    x[i] = x[i] * xscale[i] + xoffset[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unscalex>:
  endbr64
  test   %edi,%edi
  jle    L4
  mov    %edi,%edi
  mov    $0x0,%eax
L15:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L15
L4:
  ret
```

assistant: ```c
void unscalex(int n, double x[], const double xscale[], const double xoffset[]) {
  int i;
  for (i = 0; i < n; i++) {
    x[i] = x[i] * xscale[i] + xoffset[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unscalex>:
  endbr64
  test   %edi,%edi
  jle    L18
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L17:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L17
L18:
  ret
```

assistant: ```c
void unscalex(int n, double x[], const double xscale[], const double xoffset[]) {
  int i;
  for (i = 0; i < n; i++) {
    x[i] = x[i] * xscale[i] + xoffset[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<unscalex>:
  endbr64
  test   %edi,%edi
  jle    L17
  lea    0x8(%rcx),%rax
  cmp    %rax,%rsi
  lea    0x8(%rdx),%rax
  setne  %r8b
  cmp    %rax,%rsi
  setne  %al
  test   %al,%r8b
  je     L44
  cmp    $0x1,%edi
  je     L44
  mov    %edi,%r8d
  xor    %eax,%eax
  shr    %r8d
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L52:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm2
  mulpd  %xmm1,%xmm0
  addpd  %xmm2,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L52
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L17
  lea    (%rsi,%rax,8),%rsi
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  (%rsi),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi)
  ret
  nopl   (%rax)
L44:
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L14:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L14
L17:
  ret
```

assistant: ```c
void unscalex(int n, double x[], const double xscale[], const double xoffset[]) {
  int i;
  for (i = 0; i < n; i++) {
    x[i] = x[i] * xscale[i] + xoffset[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0xa,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%r12
  lea    D5(%rip),%r13
L9:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L9
  mov    %rbx,%rcx
  mov    $0x0,%r12d
  jmp    L77
L34:
  add    $0x4,%rcx
  cmp    %rbp,%rcx
  je     L3
L77:
  mov    (%rcx),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%edx
  je     L34
  movslq %r12d,%rax
  mov    %edx,(%rsp,%rax,4)
  add    $0x1,%r12d
  jmp    L34
L3:
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L57
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%r12
  lea    D23(%rip),%rbp
L24:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L24
L57:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D23
datatype: string

tool: D2: Enter array elements (%d elements): 

tool: D5: %d

tool: D29: New array: 

tool: D23: %d 

assistant: ```c
int main() {
  int size = 10, i, arr[size];
  printf("Enter array elements (%d elements): ", size);
  for (i = 0; i < size; ++i)
    scanf("%d", &arr[i]);
  int j = 0;
  i = 0;
  while (j < size) {
    if (arr[j] % 5 != 0) {
      arr[i] = arr[j];
      ++i;
    }
    ++j;
  }
  size = i;
  printf("New array: ");
  for (i = 0; i < size; ++i)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x28(%rsp),%r12
  mov    %rbp,%rbx
  call   <printf@plt>
  nopl   0x0(%rax)
L36:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L36
  mov    %rbp,%rax
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L54:
  mov    (%rax),%ecx
  imul   $0xcccccccd,%ecx,%edx
  add    $0x19999999,%edx
  cmp    $0x33333332,%edx
  jbe    L26
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %ecx,(%rsp,%rdx,4)
L26:
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L54
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L58
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp),%rbx
  lea    (%rbx,%rax,4),%r13
  lea    D1(%rip),%r12
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L69:
  add    $0x4,%rbx
L33:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbx,%rbp
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L69
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D1
type_infered: string

tool: D5: Enter array elements (%d elements): 

tool: D6: %d

tool: D17: New array: 

tool: D1: %d 

assistant: ```c
int main() {
  int size = 10, i, arr[size];
  printf("Enter array elements (%d elements): ", size);
  for (i = 0; i < size; ++i)
    scanf("%d", &arr[i]);
  int j = 0;
  i = 0;
  while (j < size) {
    if (arr[j] % 5 != 0) {
      arr[i] = arr[j];
      ++i;
    }
    ++j;
  }
  size = i;
  printf("New array: ");
  for (i = 0; i < size; ++i)
    printf("%d ", arr[i]);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<spaces_underscore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x3f(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L0:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void spaces_underscore(char *str, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (str[i] == ' ') {
      str[i] += 63;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<spaces_underscore>:
  endbr64
  test   %esi,%esi
  jle    L35
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
  jmp    L1
L5:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L35
L1:
  cmpb   $0x20,(%rax)
  jne    L5
  movb   $0x5f,(%rax)
  jmp    L5
L35:
  ret
```

assistant: ```c
void spaces_underscore(char *str, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (str[i] == ' ') {
      str[i] += 63;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<spaces_underscore>:
  endbr64
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
L0:
  cmpb   $0x20,(%rdi)
  jne    L4
  movb   $0x5f,(%rdi)
L4:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L0
L24:
  ret
```

assistant: ```c
void spaces_underscore(char *str, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (str[i] == ' ') {
      str[i] += 63;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spaces_underscore>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rax
L21:
  cmpb   $0x20,(%rdi)
  jne    L29
  movb   $0x5f,(%rdi)
L29:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L21
L15:
  ret
```

assistant: ```c
void spaces_underscore(char *str, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (str[i] == ' ') {
      str[i] += 63;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<render_point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  andl   $0x7fff,-0x2c(%rbp)
  andl   $0x7fff,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    -0xc(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  mov    -0x2c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  jmp    L6
L8:
  mov    -0x2c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int render_point(int x0, int x1, int y0, int y1, int x) {
  y0 &= 0x7fff;
  y1 &= 0x7fff;
  {
    int dy = y1 - y0;
    int adx = x1 - x0;
    int ady = abs(dy);
    int err = ady * (x - x0);
    int off = err / adx;
    if (dy < 0)
      return (y0 - off);
    return (y0 + off);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<render_point>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%edi
  and    $0x7fff,%edi
  and    $0x7fff,%ecx
  sub    %edi,%ecx
  mov    %r8d,%eax
  sub    %r9d,%eax
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  imul   %edx,%eax
  sub    %r9d,%esi
  cltd
  idiv   %esi
  mov    %edi,%edx
  sub    %eax,%edx
  add    %edi,%eax
  test   %ecx,%ecx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int render_point(int x0, int x1, int y0, int y1, int x) {
  y0 &= 0x7fff;
  y1 &= 0x7fff;
  {
    int dy = y1 - y0;
    int adx = x1 - x0;
    int ady = abs(dy);
    int err = ady * (x - x0);
    int off = err / adx;
    if (dy < 0)
      return (y0 - off);
    return (y0 + off);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<render_point>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%edi
  and    $0x7fff,%ecx
  mov    %r8d,%eax
  and    $0x7fff,%edi
  sub    %r9d,%eax
  sub    %edi,%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  sub    %r9d,%esi
  imul   %edx,%eax
  cltd
  idiv   %esi
  mov    %edi,%edx
  sub    %eax,%edx
  add    %edi,%eax
  test   %ecx,%ecx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int render_point(int x0, int x1, int y0, int y1, int x) {
  y0 &= 0x7fff;
  y1 &= 0x7fff;
  {
    int dy = y1 - y0;
    int adx = x1 - x0;
    int ady = abs(dy);
    int err = ady * (x - x0);
    int off = err / adx;
    if (dy < 0)
      return (y0 - off);
    return (y0 + off);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<render_point>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%edi
  and    $0x7fff,%ecx
  mov    %r8d,%eax
  and    $0x7fff,%edi
  sub    %r9d,%eax
  sub    %edi,%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  sub    %r9d,%esi
  imul   %edx,%eax
  cltd
  idiv   %esi
  mov    %edi,%edx
  sub    %eax,%edx
  add    %edi,%eax
  test   %ecx,%ecx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int render_point(int x0, int x1, int y0, int y1, int x) {
  y0 &= 0x7fff;
  y1 &= 0x7fff;
  {
    int dy = y1 - y0;
    int adx = x1 - x0;
    int ady = abs(dy);
    int err = ady * (x - x0);
    int off = err / adx;
    if (dy < 0)
      return (y0 - off);
    return (y0 + off);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rx_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void rx_free(const void *rx) {
  if (rx) {
    regfree((regex_t *)rx);
    free((void *)rx);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rx_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbx
  mov    %rdi,%rbx
  call   <regfree@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void rx_free(const void *rx) {
  if (rx) {
    regfree((regex_t *)rx);
    free((void *)rx);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rx_free>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <regfree@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void rx_free(const void *rx) {
  if (rx) {
    regfree((regex_t *)rx);
    free((void *)rx);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rx_free>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbp
  mov    %rdi,%rbp
  call   <regfree@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void rx_free(const void *rx) {
  if (rx) {
    regfree((regex_t *)rx);
    free((void *)rx);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(const char *msg) {
  print_error(msg);
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <print_error@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void error(const char *msg) {
  print_error(msg);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <print_error@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void error(const char *msg) {
  print_error(msg);
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <print_error@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void error(const char *msg) {
  print_error(msg);
  exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L6
  movslq %edi,%rax
  mov    %rsi,%rbx
  lea    D71(%rip),%rbp
  lea    (%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L11:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%edi
  call   <pr_argv@plt>
  cmp    %rbx,%r12
  jne    L11
  lea    D26(%rip),%rdi
  mov    %r14,%rbx
  lea    D64(%rip),%r15
  call   <puts@plt>
  mov    (%r12),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L36:
  xor    %ebp,%ebp
  mov    (%rbx),%esi
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <strcpy_my@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L36
L35:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    %r14,%rdx
  mov    %r13d,%esi
  xor    %edi,%edi
  call   <arr_ops@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L35
```

tool_calls: name: retrieve_data
arguments: label: D71
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string
name: retrieve_data
arguments: label: D64
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D46
data_type: string

tool: D71: * argv = '%s';


tool: D26: end of first cycle.

tool: D64: result string = '%s';


tool: D20: 
after ending of first cycle argc = %d, and * argv = '%s';


tool: D3: before begining of second cycle argc = %d, and * argv = '%s';


tool: D46: end of second cycle.


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int j = argc;
  char *f;
  char **arr;
  while (j-- > 0) {
    printf("* argv = '%s';\n", *argv);
    pr_argv(*argv++);
  }
  printf("end of first cycle.\n");
  printf("\nafter ending of first cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++, *argv--) {
  }
  printf("before begining of second cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++) {
    strcpy_my(f, *argv++);
    printf("result string = '%s';\n", f);
  }
  printf("end of second cycle.\n\n");
  for (i = 0; i < argc; i++, *argv--) {
  }
  arr_ops(arr, argc, argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L0
  movslq %edi,%rax
  mov    %rsi,%rbx
  lea    D29(%rip),%rbp
  lea    (%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L38:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%edi
  call   <pr_argv@plt>
  cmp    %rbx,%r12
  jne    L38
  lea    D27(%rip),%rdi
  mov    %r14,%rbx
  lea    D88(%rip),%r15
  call   <puts@plt>
  mov    (%r12),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L5:
  xor    %ebp,%ebp
  mov    (%rbx),%esi
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <strcpy_my@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L5
L24:
  lea    D79(%rip),%rdi
  call   <puts@plt>
  mov    %r14,%rdx
  mov    %r13d,%esi
  xor    %edi,%edi
  call   <arr_ops@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    (%r14),%rdx
  mov    %r13d,%esi
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: parse_data
arguments: tag: D29
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D88
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D50
type_guessed: string
name: parse_data
arguments: tag: D79
type_guessed: string

tool: D29: * argv = '%s';


tool: D27: end of first cycle.

tool: D88: result string = '%s';


tool: D13: 
after ending of first cycle argc = %d, and * argv = '%s';


tool: D50: before begining of second cycle argc = %d, and * argv = '%s';


tool: D79: end of second cycle.


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int j = argc;
  char *f;
  char **arr;
  while (j-- > 0) {
    printf("* argv = '%s';\n", *argv);
    pr_argv(*argv++);
  }
  printf("end of first cycle.\n");
  printf("\nafter ending of first cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++, *argv--) {
  }
  printf("before begining of second cycle argc = %d, and * argv = '%s';\n", argc, *argv);
  for (i = 0; i < argc; i++) {
    strcpy_my(f, *argv++);
    printf("result string = '%s';\n", f);
  }
  printf("end of second cycle.\n\n");
  for (i = 0; i < argc; i++, *argv--) {
  }
  arr_ops(arr, argc, argv);
  return 0;
}
```