ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  call   <printw@plt>
  lea    D30(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <scanw@plt>
  mov    D30(%rip),%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D34
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D34: MENU:

	1) Registrar Cliente
	2) Consulta General
	3) Cliente Distinguido
	4) Salir

Introduce tu eleccion
>>

tool: D0: %d

assistant: ```c
int menu() {
  static int m;
  printw("MENU:\n\n\t1) Registrar Cliente\n\t2) Consulta General\n\t3) Cliente Distinguido\n\t4) Salir\n\nIntroduce tu eleccion\n>>");
  scanw("%d", &m);
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rdi
  call   <printw@plt>
  lea    D17(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <scanw@plt>
  mov    D17(%rip),%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string

tool: D21: MENU:

	1) Registrar Cliente
	2) Consulta General
	3) Cliente Distinguido
	4) Salir

Introduce tu eleccion
>>

tool: D9: %d

assistant: ```c
int menu() {
  static int m;
  printw("MENU:\n\n\t1) Registrar Cliente\n\t2) Consulta General\n\t3) Cliente Distinguido\n\t4) Salir\n\nIntroduce tu eleccion\n>>");
  scanw("%d", &m);
  return m;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L38
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L38
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L38:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strlower(char *str) {
  int i;
  i = 0;
  while (str[i]) {
    if (str[i] >= 'A' && str[i] <= 'Z') {
      str[i] = str[i] + ('a' - 'A');
    }
    i++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlower>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L42
  mov    %rdi,%rcx
  jmp    L38
L33:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L42
L38:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L33
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L33
L42:
  ret
```

assistant: ```c
char *strlower(char *str) {
  int i;
  i = 0;
  while (str[i]) {
    if (str[i] >= 'A' && str[i] <= 'Z') {
      str[i] = str[i] + ('a' - 'A');
    }
    i++;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlower>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L6
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L12:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L17
  add    $0x20,%edx
  mov    %dl,(%rcx)
L17:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L12
L6:
  ret
```

assistant: ```c
char *strlower(char *str) {
  int i;
  i = 0;
  while (str[i]) {
    if (str[i] >= 'A' && str[i] <= 'Z') {
      str[i] = str[i] + ('a' - 'A');
    }
    i++;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlower>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L25
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L33:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L5
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L33
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L33
L25:
  ret
```

assistant: ```c
char *strlower(char *str) {
  int i;
  i = 0;
  while (str[i]) {
    if (str[i] >= 'A' && str[i] <= 'Z') {
      str[i] = str[i] + ('a' - 'A');
    }
    i++;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D5(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D22
type_infered: string

tool: D5: printf shoult print text from this | to the end.

tool: D2: |

tool: D22: %s


assistant: ```c
int main() {
  const char *str1 = "printf shoult print text from this | to the end.";
  const char *str2 = "|";
  char *str3 = strstr(str1, str2);
  printf("%s\n", str3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D14
datatype: string

tool: D5: | to the end.

tool: D14: %s


assistant: ```c
int main() {
  const char *str1 = "printf shoult print text from this | to the end.";
  const char *str2 = "|";
  char *str3 = strstr(str1, str2);
  printf("%s\n", str3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D8
type: string

tool: D0: | to the end.

tool: D8: %s


assistant: ```c
int main() {
  const char *str1 = "printf shoult print text from this | to the end.";
  const char *str2 = "|";
  char *str3 = strstr(str1, str2);
  printf("%s\n", str3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D15: | to the end.

tool: D17: %s


assistant: ```c
int main() {
  const char *str1 = "printf shoult print text from this | to the end.";
  const char *str2 = "|";
  char *str3 = strstr(str1, str2);
  printf("%s\n", str3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<affiche_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movw   $0x10,-0xa(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x8000,-0x4(%rbp)
  jmp    L18
L3:
  movswl -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  sarl   -0x4(%rbp)
L18:
  movzwl -0xa(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: %i

assistant: ```c
void affiche_bin(short x) {
  int i, m;
  unsigned short sz = sizeof(x) * 8;
  for (i = 0, m = 0x8000; i < sz; ++i, m >>= 1) {
    printf("%i", (x & m) >> ((sz - 1) - i));
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<affiche_bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    $0xf,%ebx
  mov    $0x8000,%ebp
  lea    D1(%rip),%r13
L2:
  movswl %r12w,%esi
  and    %ebp,%esi
  mov    %ebx,%ecx
  sar    %cl,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sar    %ebp
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: %i

assistant: ```c
void affiche_bin(short x) {
  int i, m;
  unsigned short sz = sizeof(x) * 8;
  for (i = 0, m = 0x8000; i < sz; ++i, m >>= 1) {
    printf("%i", (x & m) >> ((sz - 1) - i));
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<affiche_bin>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  movswl %di,%r12d
  push   %rbp
  mov    $0x8000,%ebp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12d,%esi
  mov    %ebx,%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  and    %ebp,%esi
  sar    %ebp
  sar    %cl,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L2
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: %i

assistant: ```c
void affiche_bin(short x) {
  int i, m;
  unsigned short sz = sizeof(x) * 8;
  for (i = 0, m = 0x8000; i < sz; ++i, m >>= 1) {
    printf("%i", (x & m) >> ((sz - 1) - i));
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<affiche_bin>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  movswl %di,%r12d
  push   %rbp
  mov    $0x8000,%ebp
  push   %rbx
  mov    $0xf,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12d,%esi
  mov    %ebx,%ecx
  mov    %r13,%rdi
  xor    %eax,%eax
  and    %ebp,%esi
  sar    %ebp
  sar    %cl,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jae    L2
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %i

assistant: ```c
void affiche_bin(short x) {
  int i, m;
  unsigned short sz = sizeof(x) * 8;
  for (i = 0, m = 0x8000; i < sz; ++i, m >>= 1) {
    printf("%i", (x & m) >> ((sz - 1) - i));
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wraplow_16bit_shift5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_add_epi32@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_add_epi32@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x5,%esi
  mov    %eax,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_packs_epi32@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
__m128i wraplow_16bit_shift5(const __m128i in0, const __m128i in1, const __m128i rounding) {
  __m128i temp[2];
  temp[0] = _mm_add_epi32(in0, rounding);
  temp[1] = _mm_add_epi32(in1, rounding);
  temp[0] = _mm_srai_epi32(temp[0], 5);
  temp[1] = _mm_srai_epi32(temp[1], 5);
  return _mm_packs_epi32(temp[0], temp[1]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wraplow_16bit_shift5>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %edx,%esi
  call   <_mm_add_epi32@plt>
  mov    %eax,%r12d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <_mm_add_epi32@plt>
  mov    %eax,%ebp
  mov    $0x5,%esi
  mov    %r12d,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,%ebx
  mov    $0x5,%esi
  mov    %ebp,%edi
  call   <_mm_srai_epi32@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <_mm_packs_epi32@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__m128i wraplow_16bit_shift5(const __m128i in0, const __m128i in1, const __m128i rounding) {
  __m128i temp[2];
  temp[0] = _mm_add_epi32(in0, rounding);
  temp[1] = _mm_add_epi32(in1, rounding);
  temp[0] = _mm_srai_epi32(temp[0], 5);
  temp[1] = _mm_srai_epi32(temp[1], 5);
  return _mm_packs_epi32(temp[0], temp[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wraplow_16bit_shift5>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  push   %rbp
  mov    %edx,%ebp
  call   <_mm_add_epi32@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <_mm_add_epi32@plt>
  mov    %r13d,%edi
  mov    $0x5,%esi
  mov    %eax,%r12d
  call   <_mm_srai_epi32@plt>
  mov    %r12d,%edi
  mov    $0x5,%esi
  mov    %eax,%ebp
  call   <_mm_srai_epi32@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    1090 <_mm_packs_epi32@plt>
```

assistant: ```c
__m128i wraplow_16bit_shift5(const __m128i in0, const __m128i in1, const __m128i rounding) {
  __m128i temp[2];
  temp[0] = _mm_add_epi32(in0, rounding);
  temp[1] = _mm_add_epi32(in1, rounding);
  temp[0] = _mm_srai_epi32(temp[0], 5);
  temp[1] = _mm_srai_epi32(temp[1], 5);
  return _mm_packs_epi32(temp[0], temp[1]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wraplow_16bit_shift5>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  push   %rbp
  mov    %edx,%ebp
  call   <_mm_add_epi32@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <_mm_add_epi32@plt>
  mov    %r13d,%edi
  mov    $0x5,%esi
  mov    %eax,%r12d
  call   <_mm_srai_epi32@plt>
  mov    %r12d,%edi
  mov    $0x5,%esi
  mov    %eax,%ebp
  call   <_mm_srai_epi32@plt>
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  mov    %eax,%esi
  pop    %r13
  jmp    1090 <_mm_packs_epi32@plt>
```

assistant: ```c
__m128i wraplow_16bit_shift5(const __m128i in0, const __m128i in1, const __m128i rounding) {
  __m128i temp[2];
  temp[0] = _mm_add_epi32(in0, rounding);
  temp[1] = _mm_add_epi32(in1, rounding);
  temp[0] = _mm_srai_epi32(temp[0], 5);
  temp[1] = _mm_srai_epi32(temp[1], 5);
  return _mm_packs_epi32(temp[0], temp[1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<question_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L0:
  cmp    %rax,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L12:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  mov    %rsp,%rbx
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <insere_lista_auto@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <mostra_lista@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <cont_elemt_par@plt>
  mov    %eax,%r12d
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <cont_elemt_impar@plt>
  mov    %eax,%edx
  mov    %r12d,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <media_maior_50@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <bubblesort_inverso@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <mostra_lista@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D35
data_type: string
name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D34: 
------------- Questao 1 -------------

tool: D1: Lista incial:

tool: D35: par: %d
impar: %d


tool: D20: media: %.2f



tool: D27: lista ordenada: 

assistant: ```c
void question_one() {
  int tam_vetor = 100;
  int vetor[tam_vetor];
  printf("\n------------- Questao 1 -------------\n");
  insere_lista_auto(vetor, tam_vetor);
  printf("Lista incial:\n");
  mostra_lista(vetor, tam_vetor);
  int numPar = cont_elemt_par(vetor, tam_vetor);
  int numImpar = cont_elemt_impar(vetor, tam_vetor);
  printf("par: %d\nimpar: %d\n", numPar, numImpar);
  float media = media_maior_50(vetor, tam_vetor);
  printf("media: %.2f\n\n", media);
  bubblesort_inverso(vetor, tam_vetor);
  printf("lista ordenada: \n");
  mostra_lista(vetor, tam_vetor);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<question_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L27
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L4
L27:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r12
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <insere_lista_auto@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <mostra_lista@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <cont_elemt_par@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <cont_elemt_impar@plt>
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <media_maior_50@plt>
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <bubblesort_inverso@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <mostra_lista@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D44
type_infered: string

tool: D29: 
------------- Questao 1 -------------

tool: D6: Lista incial:

tool: D18: par: %d
impar: %d


tool: D11: media: %.2f



tool: D44: lista ordenada: 

assistant: ```c
void question_one() {
  int tam_vetor = 100;
  int vetor[tam_vetor];
  printf("\n------------- Questao 1 -------------\n");
  insere_lista_auto(vetor, tam_vetor);
  printf("Lista incial:\n");
  mostra_lista(vetor, tam_vetor);
  int numPar = cont_elemt_par(vetor, tam_vetor);
  int numImpar = cont_elemt_impar(vetor, tam_vetor);
  printf("par: %d\nimpar: %d\n", numPar, numImpar);
  float media = media_maior_50(vetor, tam_vetor);
  printf("media: %.2f\n\n", media);
  bubblesort_inverso(vetor, tam_vetor);
  printf("lista ordenada: \n");
  mostra_lista(vetor, tam_vetor);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<question_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L24
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L23
L24:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r12
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <insere_lista_auto@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <mostra_lista@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <cont_elemt_par@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <cont_elemt_impar@plt>
  mov    %r13d,%esi
  lea    D44(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <media_maior_50@plt>
  lea    D9(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <bubblesort_inverso@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <mostra_lista@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D26
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D44
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D47
type_infered: string

tool: D26: 
------------- Questao 1 -------------

tool: D10: Lista incial:

tool: D44: par: %d
impar: %d


tool: D9: media: %.2f



tool: D47: lista ordenada: 

assistant: ```c
void question_one() {
  int tam_vetor = 100;
  int vetor[tam_vetor];
  printf("\n------------- Questao 1 -------------\n");
  insere_lista_auto(vetor, tam_vetor);
  printf("Lista incial:\n");
  mostra_lista(vetor, tam_vetor);
  int numPar = cont_elemt_par(vetor, tam_vetor);
  int numImpar = cont_elemt_impar(vetor, tam_vetor);
  printf("par: %d\nimpar: %d\n", numPar, numImpar);
  float media = media_maior_50(vetor, tam_vetor);
  printf("media: %.2f\n\n", media);
  bubblesort_inverso(vetor, tam_vetor);
  printf("lista ordenada: \n");
  mostra_lista(vetor, tam_vetor);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substring(char *pattern, int start, int end) {
  int length = end - start + 1;
  char *new = malloc(sizeof(char) * length + 1);
  strncpy(new, pattern + start, length);
  new[length] = '\0';
  return new;
}
```