ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<esp_log_timestamp>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  cmpq   $0x0,D20(%rip)
  jne    L4
  call   <time@plt>
  sub    D20(%rip),%rax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L4:
  call   <time@plt>
  mov    %rax,D9(%rip)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t esp_log_timestamp(void) {
  static time_t t_first = 0;
  if (t_first) {
    t_first = time(NULL);
    return 0;
  }
  return time(NULL) - t_first;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<esp_log_timestamp>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  cmpq   $0x0,D28(%rip)
  jne    L2
  call   <time@plt>
  sub    D28(%rip),%rax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L2:
  call   <time@plt>
  mov    %rax,D16(%rip)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t esp_log_timestamp(void) {
  static time_t t_first = 0;
  if (t_first) {
    t_first = time(NULL);
    return 0;
  }
  return time(NULL) - t_first;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<interaction_getchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void interaction_getchar(char *arg1) {
  0;
  char input = getchar();
  putchar(input);
  0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<interaction_getchar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void interaction_getchar(char *arg1) {
  0;
  char input = getchar();
  putchar(input);
  0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<interaction_getchar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  movsbl %al,%edi
  jmp    1060 <putchar@plt>
```

assistant: ```c
void interaction_getchar(char *arg1) {
  0;
  char input = getchar();
  putchar(input);
  0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<interaction_getchar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  movsbl %al,%edi
  jmp    1060 <putchar@plt>
```

assistant: ```c
void interaction_getchar(char *arg1) {
  0;
  char input = getchar();
  putchar(input);
  0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum_rows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L20:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L2:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x3,-0x8(%rbp)
  jle    L2
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: row %d: sum = %d


assistant: ```c
void sum_rows(int ar[][4], int rows) {
  int r, c, tot;
  for (r = 0; r < rows; r++) {
    tot = 0;
    for (c = 0; c < 4; c++) {
      tot += ar[r][c];
    }
    printf("row %d: sum = %d\n", r, tot);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sum_rows>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  lea    D4(%rip),%r13
L17:
  mov    0x4(%rbx),%edx
  add    (%rbx),%edx
  add    0x8(%rbx),%edx
  add    0xc(%rbx),%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x10,%rbx
  cmp    %ebp,%r12d
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: row %d: sum = %d


assistant: ```c
void sum_rows(int ar[][4], int rows) {
  int r, c, tot;
  for (r = 0; r < rows; r++) {
    tot = 0;
    for (c = 0; c < 4; c++) {
      tot += ar[r][c];
    }
    printf("row %d: sum = %d\n", r, tot);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum_rows>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  mov    0x4(%r12),%edx
  mov    %r13d,%esi
  add    (%r12),%edx
  mov    %rbp,%rdi
  add    0x8(%r12),%edx
  add    $0x1,%r13d
  add    0xc(%r12),%edx
  add    $0x10,%r12
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: row %d: sum = %d


assistant: ```c
void sum_rows(int ar[][4], int rows) {
  int r, c, tot;
  for (r = 0; r < rows; r++) {
    tot = 0;
    for (c = 0; c < 4; c++) {
      tot += ar[r][c];
    }
    printf("row %d: sum = %d\n", r, tot);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sum_rows>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L10:
  mov    0x4(%r12),%edx
  mov    %r13d,%esi
  add    (%r12),%edx
  mov    %rbp,%rdi
  add    0x8(%r12),%edx
  add    $0x1,%r13d
  add    0xc(%r12),%edx
  add    $0x10,%r12
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: row %d: sum = %d


assistant: ```c
void sum_rows(int ar[][4], int rows) {
  int r, c, tot;
  for (r = 0; r < rows; r++) {
    tot = 0;
    for (c = 0; c < 4; c++) {
      tot += ar[r][c];
    }
    printf("row %d: sum = %d\n", r, tot);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x207365696b6f6f43,%rax
  movabs $0x756f7920656b616d,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x74616620,-0x10(%rbp)
  movw   $0x2e,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fortune_cookie@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main() {
  char quote[] = "Cookies make you fat.";
  fortune_cookie(quote);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x207365696b6f6f43,%rax
  movabs $0x756f7920656b616d,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x74616620,0x10(%rsp)
  movw   $0x2e,0x14(%rsp)
  mov    %rsp,%rdi
  call   <fortune_cookie@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char quote[] = "Cookies make you fat.";
  fortune_cookie(quote);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x2e,%eax
  movl   $0x74616620,0x10(%rsp)
  mov    %ax,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <fortune_cookie@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: byte[16]

tool: {"D7": [0x43,0x6f,0x6f,0x6b,0x69,0x65,0x73,0x20,0x6d,0x61,0x6b,0x65,0x20,0x79,0x6f,0x75]}

assistant: ```c
int main() {
  char quote[] = "Cookies make you fat.";
  fortune_cookie(quote);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x2e,%eax
  movl   $0x74616620,0x10(%rsp)
  mov    %ax,0x14(%rsp)
  movaps %xmm0,(%rsp)
  call   <fortune_cookie@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: byte[16]

tool: {"D9": [0x43,0x6f,0x6f,0x6b,0x69,0x65,0x73,0x20,0x6d,0x61,0x6b,0x65,0x20,0x79,0x6f,0x75]}

assistant: ```c
int main() {
  char quote[] = "Cookies make you fat.";
  fortune_cookie(quote);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atohex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L53
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L53
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L20
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L10
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L10
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  addq   $0x1,-0x18(%rbp)
L31:
  cmpq   $0x0,-0x18(%rbp)
  jne    L5
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atohex(const char *a_char) {
  int result;
  for (result = 0; a_char; a_char++) {
    if (*a_char >= '0' && *a_char <= '9') {
      result = (result << 4) + (*a_char - '0');
    } else if (*a_char >= 'A' && *a_char <= 'F') {
      result = (result << 4) + (*a_char - 'A' + 10);
    } else if (*a_char >= 'a' && *a_char <= 'f') {
      result = (result << 4) + (*a_char - 'a' + 10);
    } else {
      break;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<atohex>:
  endbr64
  test   %rdi,%rdi
  je     L26
  mov    $0x0,%eax
  jmp    L21
L32:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L46
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x37(%rax,%rdx,1),%eax
L40:
  add    $0x1,%rdi
L21:
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L32
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x30(%rax,%rdx,1),%eax
  jmp    L40
L46:
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L57
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x57(%rax,%rdx,1),%eax
  jmp    L40
L26:
  mov    $0x0,%eax
L57:
  ret
```

assistant: ```c
int atohex(const char *a_char) {
  int result;
  for (result = 0; a_char; a_char++) {
    if (*a_char >= '0' && *a_char <= '9') {
      result = (result << 4) + (*a_char - '0');
    } else if (*a_char >= 'A' && *a_char <= 'F') {
      result = (result << 4) + (*a_char - 'A' + 10);
    } else if (*a_char >= 'a' && *a_char <= 'f') {
      result = (result << 4) + (*a_char - 'a' + 10);
    } else {
      break;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atohex>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L64
  jmp    L19
  nopl   (%rax)
L67:
  shl    $0x4,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
L61:
  add    $0x1,%rdi
L64:
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L67
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L66
  sub    $0x37,%edx
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  jmp    L61
  nopl   0x0(%rax)
L66:
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L19
  sub    $0x57,%edx
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  jmp    L61
  nopl   (%rax)
L19:
  ret
```

assistant: ```c
int atohex(const char *a_char) {
  int result;
  for (result = 0; a_char; a_char++) {
    if (*a_char >= '0' && *a_char <= '9') {
      result = (result << 4) + (*a_char - '0');
    } else if (*a_char >= 'A' && *a_char <= 'F') {
      result = (result << 4) + (*a_char - 'A' + 10);
    } else if (*a_char >= 'a' && *a_char <= 'f') {
      result = (result << 4) + (*a_char - 'a' + 10);
    } else {
      break;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<atohex>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L8
  jmp    L20
  nopl   (%rax)
L1:
  shl    $0x4,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
L6:
  add    $0x1,%rdi
L8:
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L1
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L53
  sub    $0x37,%edx
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  jmp    L6
  nopl   0x0(%rax)
L53:
  lea    -0x61(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L20
  sub    $0x57,%edx
  shl    $0x4,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  jmp    L6
  nopl   (%rax)
L20:
  ret
```

assistant: ```c
int atohex(const char *a_char) {
  int result;
  for (result = 0; a_char; a_char++) {
    if (*a_char >= '0' && *a_char <= '9') {
      result = (result << 4) + (*a_char - '0');
    } else if (*a_char >= 'A' && *a_char <= 'F') {
      result = (result << 4) + (*a_char - 'A' + 10);
    } else if (*a_char >= 'a' && *a_char <= 'f') {
      result = (result << 4) + (*a_char - 'a' + 10);
    } else {
      break;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<util_string_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L30
L54:
  addq   $0x1,-0x18(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L54
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L2:
  subq   $0x1,-0x10(%rbp)
L33:
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L21
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
L21:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void util_string_trim(char *string) {
  const char *firstNonSpace = string;
  while (*firstNonSpace != '\0' && isspace(*firstNonSpace)) {
    ++firstNonSpace;
  }
  size_t len = strlen(firstNonSpace) + 1;
  memmove(string, firstNonSpace, len);
  char *endOfString = string + len;
  while (string < endOfString && isspace(*endOfString)) {
    --endOfString;
  }
  *endOfString = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<util_string_trim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  mov    %rbp,%r12
  test   %dil,%dil
  je     L27
L58:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L27
  add    $0x1,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L58
L27:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  jae    L50
L33:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L50
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L33
  mov    %rbp,%rbx
L50:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void util_string_trim(char *string) {
  const char *firstNonSpace = string;
  while (*firstNonSpace != '\0' && isspace(*firstNonSpace)) {
    ++firstNonSpace;
  }
  size_t len = strlen(firstNonSpace) + 1;
  memmove(string, firstNonSpace, len);
  char *endOfString = string + len;
  while (string < endOfString && isspace(*endOfString)) {
    --endOfString;
  }
  *endOfString = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_string_trim>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rbp,%r12
  test   %dil,%dil
  jne    L59
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L32:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L17
L59:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
L17:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdx
  add    %rbp,%rbx
  call   <memmove@plt>
  cmp    %rbx,%rbp
  jb     L51
  jmp    L69
  nop
L10:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L69
L51:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
L69:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void util_string_trim(char *string) {
  const char *firstNonSpace = string;
  while (*firstNonSpace != '\0' && isspace(*firstNonSpace)) {
    ++firstNonSpace;
  }
  size_t len = strlen(firstNonSpace) + 1;
  memmove(string, firstNonSpace, len);
  char *endOfString = string + len;
  while (string < endOfString && isspace(*endOfString)) {
    --endOfString;
  }
  *endOfString = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<util_string_trim>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rbp,%r12
  test   %dil,%dil
  jne    L37
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L20:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L72
L37:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
L72:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdx
  add    %rbp,%rbx
  call   <memmove@plt>
  cmp    %rbx,%rbp
  jb     L56
  jmp    L63
  nop
L61:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L63
L56:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L61
L63:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void util_string_trim(char *string) {
  const char *firstNonSpace = string;
  while (*firstNonSpace != '\0' && isspace(*firstNonSpace)) {
    ++firstNonSpace;
  }
  size_t len = strlen(firstNonSpace) + 1;
  memmove(string, firstNonSpace, len);
  char *endOfString = string + len;
  while (string < endOfString && isspace(*endOfString)) {
    --endOfString;
  }
  *endOfString = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signex32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x4(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t signex32(uint32_t v, int bit) {
  int32_t m = 1U << (bit - 1);
  return (v ^ m) - m;
}
```
user: What is the c source code of the assembly code below?

```asm
<signex32>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int32_t signex32(uint32_t v, int bit) {
  int32_t m = 1U << (bit - 1);
  return (v ^ m) - m;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<signex32>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int32_t signex32(uint32_t v, int bit) {
  int32_t m = 1U << (bit - 1);
  return (v ^ m) - m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<signex32>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  xor    %edx,%edi
  mov    %edi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
int32_t signex32(uint32_t v, int bit) {
  int32_t m = 1U << (bit - 1);
  return (v ^ m) - m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x80,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D16(%rip),%rax
  leave
  ret
```

assistant: ```c
char *fmt(char *fmt, ...) {
  static char buf[128];
  va_list args;
  va_start(args, fmt);
  vsnprintf(buf, sizeof(buf), fmt, args);
  va_end(args);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x80,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *fmt(char *fmt, ...) {
  static char buf[128];
  va_list args;
  va_start(args, fmt);
  vsnprintf(buf, sizeof(buf), fmt, args);
  va_end(args);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fmt>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    $0x80,%esi
  lea    D2(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *fmt(char *fmt, ...) {
  static char buf[128];
  va_list args;
  va_start(args, fmt);
  vsnprintf(buf, sizeof(buf), fmt, args);
  va_end(args);
  return buf;
}
```