ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<render_oid>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <oid_parts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <oid_split@plt>
  mov    (%rsp),%eax
  mov    %r13,%rsi
  lea    (%rax,%rax,4),%edx
  mov    0x4(%rsp),%eax
  lea    (%rax,%rdx,8),%edi
  call   <render_byte@plt>
  mov    %rax,%rsi
  cmp    $0x2,%r12d
  jle    L15
  lea    -0x3(%r12),%eax
  lea    0x8(%rsp),%rbx
  lea    0xc(%rsp,%rax,4),%rbp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <render_oid_part@plt>
  mov    %rax,%rsi
  cmp    %rbp,%rbx
  jne    L8
L15:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x418,%rsp
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *render_oid(char *oid, void *dest) {
  int num_parts = oid_parts(oid);
  int parts[256];
  int i;
  int first_two;
  oid_split(oid, parts);
  first_two = parts[0] * 40 + parts[1];
  dest = render_byte(first_two, dest);
  for (i = 2; i < num_parts; i++)
    dest = render_oid_part(parts[i], dest);
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D8(%rip),%rax
  movq   %rax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D2: %f


assistant: ```c
int main() {
  printf("%f\n", pow(10.0, 3.0));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D6(%rip),%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: byte[8]
name: parse_data
arguments: label: D2
type_infered: string

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D2: %f


assistant: ```c
int main() {
  printf("%f\n", pow(10.0, 3.0));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D15
datatype: string

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D15: %f


assistant: ```c
int main() {
  printf("%f\n", pow(10.0, 3.0));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: byte[8]
name: read_data
arguments: data_label: D18
type_guessed: string

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D18: %f


assistant: ```c
int main() {
  printf("%f\n", pow(10.0, 3.0));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShareMallocM1d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: double * malloc error!


assistant: ```c
double *ShareMallocM1d(int size) {
  double *s = NULL;
  if ((s = (double *)calloc(size, sizeof(double))) == NULL) {
    printf("double * malloc error!\n");
    exit(1);
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ShareMallocM1d>:
  endbr64
  push   %rbx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L15:
  mov    %rbx,%rax
  pop    %rbx
  ret
L10:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: double * malloc error!


assistant: ```c
double *ShareMallocM1d(int size) {
  double *s = NULL;
  if ((s = (double *)calloc(size, sizeof(double))) == NULL) {
    printf("double * malloc error!\n");
    exit(1);
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ShareMallocM1d>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: double * malloc error!


assistant: ```c
double *ShareMallocM1d(int size) {
  double *s = NULL;
  if ((s = (double *)calloc(size, sizeof(double))) == NULL) {
    printf("double * malloc error!\n");
    exit(1);
  }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ShareMallocM1d>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r12,%rax
  pop    %r12
  ret
  xchg   %ax,%ax
L0:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D6: double * malloc error!


assistant: ```c
double *ShareMallocM1d(int size) {
  double *s = NULL;
  if ((s = (double *)calloc(size, sizeof(double))) == NULL) {
    printf("double * malloc error!\n");
    exit(1);
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utarray_str_dtor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    $0xe3,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <m_free_@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L3:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    (m_free_((*eltc), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h", 227), (*eltc) = NULL);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utarray_str_dtor>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  mov    $0xe3,%edx
  lea    D7(%rip),%rsi
  call   <m_free_@plt>
  movq   $0x0,(%rbx)
L9:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    (m_free_((*eltc), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h", 227), (*eltc) = NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utarray_str_dtor>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  mov    $0xe3,%edx
  lea    D6(%rip),%rsi
  call   <m_free_@plt>
  movq   $0x0,(%rbx)
L8:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    (m_free_((*eltc), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h", 227), (*eltc) = NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utarray_str_dtor>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  mov    $0xe3,%edx
  lea    D6(%rip),%rsi
  call   <m_free_@plt>
  movq   $0x0,(%rbx)
L6:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h

assistant: ```c
void utarray_str_dtor(void *elt) {
  char **eltc = (char **)elt;
  if (*eltc)
    (m_free_((*eltc), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bitfixer/bitfixer/refs/heads/master/dg/z88dk/src/z80asm/lib/utarray.h", 227), (*eltc) = NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PhyStatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <MiiStationRead@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  orl    $0x1,-0x8(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  and    $0x4000,%eax
  test   %eax,%eax
  je     L6
  orl    $0x2,-0x8(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L21
  orl    $0x4,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned PhyStatus(void) {
  unsigned status = MiiStationRead(0x11, 1);
  unsigned r = 0;
  if (status & (1 << (0)))
    r |= 0x0001;
  if (status & (1 << (14)))
    r |= 0x0002;
  if (status & (1 << (15)))
    r |= 0x0004;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PhyStatus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <MiiStationRead@plt>
  mov    %eax,%ecx
  and    $0x1,%eax
  mov    %eax,%edx
  or     $0x2,%edx
  test   $0x40,%ch
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x4,%edx
  test   $0x80,%ch
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned PhyStatus(void) {
  unsigned status = MiiStationRead(0x11, 1);
  unsigned r = 0;
  if (status & (1 << (0)))
    r |= 0x0001;
  if (status & (1 << (14)))
    r |= 0x0002;
  if (status & (1 << (15)))
    r |= 0x0004;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<PhyStatus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <MiiStationRead@plt>
  mov    %eax,%edx
  and    $0x1,%eax
  mov    %eax,%ecx
  or     $0x2,%ecx
  test   $0x40,%dh
  cmovne %ecx,%eax
  mov    %eax,%ecx
  or     $0x4,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned PhyStatus(void) {
  unsigned status = MiiStationRead(0x11, 1);
  unsigned r = 0;
  if (status & (1 << (0)))
    r |= 0x0001;
  if (status & (1 << (14)))
    r |= 0x0002;
  if (status & (1 << (15)))
    r |= 0x0004;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PhyStatus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x11,%edi
  call   <MiiStationRead@plt>
  mov    %eax,%edx
  and    $0x1,%eax
  mov    %eax,%ecx
  or     $0x2,%ecx
  test   $0x40,%dh
  cmovne %ecx,%eax
  mov    %eax,%ecx
  or     $0x4,%ecx
  and    $0x80,%dh
  cmovne %ecx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned PhyStatus(void) {
  unsigned status = MiiStationRead(0x11, 1);
  unsigned r = 0;
  if (status & (1 << (0)))
    r |= 0x0001;
  if (status & (1 << (14)))
    r |= 0x0002;
  if (status & (1 << (15)))
    r |= 0x0004;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %edi,-0xf4(%rbp)
  mov    %rsi,-0x100(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xf0(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L17
L21:
  lea    -0xe8(%rbp),%rdx
  lea    -0xec(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xec(%rbp),%edx
  lea    -0xe0(%rbp),%rax
  lea    D40(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0xe8(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D40(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0xe0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xec(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xe8(%rbp)
  mov    -0xec(%rbp),%edx
  mov    -0xe8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xe4(%rbp)
  mov    -0xe4(%rbp),%edx
  lea    -0xe0(%rbp),%rax
  lea    D40(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0xe0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0xf0(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xf0(%rbp)
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D40
datatype: string
name: disassemble_data
arguments: data_tag: D30
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: string

tool: D40: %d

tool: D30: %d %d

tool: D17: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int t, a, b, r;
  char A[100], B[100];
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &a, &b);
    sprintf(A, "%d", a);
    sprintf(B, "%d", b);
    reverse(A, strlen(A));
    reverse(B, strlen(B));
    a = atoi(A);
    b = atoi(B);
    r = a + b;
    sprintf(A, "%d", r);
    reverse(A, strlen(A));
    printf("%s\n", A);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L1
  lea    0xc(%rsp),%r14
  lea    D38(%rip),%r13
  lea    D5(%rip),%rbp
  lea    D11(%rip),%r12
L20:
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  mov    0x8(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    0x80(%rsp),%r15
  mov    0xc(%rsp),%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %r15,%rdi
  call   <reverse@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,0x8(%rsp)
  mov    %r15,%rdi
  call   <atoi@plt>
  mov    %eax,0xc(%rsp)
  add    0x8(%rsp),%eax
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <reverse@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L20
L1:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D38
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string

tool: D5: %d

tool: D38: %d %d

tool: D11: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int t, a, b, r;
  char A[100], B[100];
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &a, &b);
    sprintf(A, "%d", a);
    sprintf(B, "%d", b);
    reverse(A, strlen(A));
    reverse(B, strlen(B));
    a = atoi(A);
    b = atoi(B);
    r = a + b;
    sprintf(A, "%d", r);
    reverse(A, strlen(A));
    printf("%s\n", A);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L13
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D12(%rip),%r13
  lea    0x10(%rsp),%rbx
  lea    0x80(%rsp),%rbp
  nopl   (%rax)
L7:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <atoi@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %eax,0xc(%rsp)
  add    0x8(%rsp),%eax
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L7
L13:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xf8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string

tool: D21: %d

tool: D12: %d %d

tool: D28: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int t, a, b, r;
  char A[100], B[100];
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &a, &b);
    sprintf(A, "%d", a);
    sprintf(B, "%d", b);
    reverse(A, strlen(A));
    reverse(B, strlen(B));
    a = atoi(A);
    b = atoi(B);
    r = a + b;
    sprintf(A, "%d", r);
    reverse(A, strlen(A));
    printf("%s\n", A);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L17
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D25(%rip),%r13
  lea    0x10(%rsp),%rbx
  lea    0x80(%rsp),%rbp
  nopl   (%rax)
L11:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <atoi@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %eax,0xc(%rsp)
  add    0x8(%rsp),%eax
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <reverse@plt>
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L11
L17:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xf8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D28
data_type: string
name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D24
data_type: string

tool: D28: %d

tool: D25: %d %d

tool: D24: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int t, a, b, r;
  char A[100], B[100];
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &a, &b);
    sprintf(A, "%d", a);
    sprintf(B, "%d", b);
    reverse(A, strlen(A));
    reverse(B, strlen(B));
    a = atoi(A);
    b = atoi(B);
    r = a + b;
    sprintf(A, "%d", r);
    reverse(A, strlen(A));
    printf("%s\n", A);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<harbol_unilist_new_from_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L14
L16:
  mov    $0x0,%eax
  call   <harbol_unilist_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <harbol_unilist_from_vector@plt>
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
struct HarbolUniList *harbol_unilist_new_from_vector(const struct HarbolVector *const v) {
  if (!v)
    return NULL;
  struct HarbolUniList *const unilist = harbol_unilist_new();
  harbol_unilist_from_vector(unilist, v);
  return unilist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<harbol_unilist_new_from_vector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L0
  mov    $0x0,%eax
  call   <harbol_unilist_new@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <harbol_unilist_from_vector@plt>
L9:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rdi,%rbp
  jmp    L9
```

assistant: ```c
struct HarbolUniList *harbol_unilist_new_from_vector(const struct HarbolVector *const v) {
  if (!v)
    return NULL;
  struct HarbolUniList *const unilist = harbol_unilist_new();
  harbol_unilist_from_vector(unilist, v);
  return unilist;
}
```