ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bnodes_>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  sub    $0x4,%rsi
  mov    (%rdi),%edi
  movl   $0x1,D38(%rip)
  test   %edi,%edi
  jle    L55
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %rcx,%rdx
  mov    $0x0,%r10d
  mov    $0x1,%eax
  mov    $0x1,%r12d
  jmp    L63
L44:
  mov    %eax,%ebx
L63:
  mov    %rdx,%r11
  movslq (%rdx),%rcx
  cmpl   $0x0,(%rsi,%rcx,4)
  js     L9
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    %r12d,%r10d
  cmp    %eax,%edi
  jge    L44
  mov    %eax,D45(%rip)
L55:
  movl   $0x0,(%r9)
  sub    $0x2,%edi
  lea    (%rdi,%rdi,1),%eax
  add    %eax,%edi
  mov    0x30(%rsp),%rbx
  mov    %edi,(%rbx)
  mov    0x38(%rsp),%rbx
  mov    %eax,(%rbx)
L33:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  test   %r10b,%r10b
  je     L47
  mov    %ebx,D45(%rip)
L47:
  mov    %eax,(%r8)
  movl   $0x1,D45(%rip)
  movslq (%r11),%rdx
  movslq -0x4(%r13,%rdx,4),%rdx
  mov    (%rsi,%rdx,4),%edx
  mov    %edx,D16(%rip)
  add    $0x4,%r8
  mov    %edx,%ecx
  mov    $0x2,%edi
  cmp    %eax,%edx
  je     L30
L11:
  mov    %edi,%ebx
  mov    %r8,%r10
  mov    %edx,(%r8)
  mov    %edx,%r11d
  movslq %ecx,%rcx
  movslq -0x4(%r14,%rcx,4),%rdx
  movslq -0x4(%r13,%rdx,4),%rdx
  mov    (%rsi,%rdx,4),%edx
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    %eax,%edx
  je     L71
  mov    %edx,%ecx
  jmp    L11
L71:
  mov    %ebx,D8(%rip)
  mov    %r11d,(%r10)
  mov    %eax,D8(%rip)
L30:
  mov    D8(%rip),%edx
  mov    %edx,(%r9)
  mov    0x0(%rbp),%eax
  add    %eax,%eax
  sub    %edx,%eax
  sub    $0x2,%eax
  mov    0x38(%rsp),%rbx
  mov    %eax,(%rbx)
  add    0x0(%rbp),%eax
  sub    $0x1,%eax
  mov    0x30(%rsp),%rbx
  mov    %eax,(%rbx)
  jmp    L33
```

assistant: ```c
int bnodes_(int *n, int *list, int *lptr, int *lend, int *nodes, int *nb, int *na, int *nt) {
  int i__1;
  static int k, n0, lp, nn, nst;
  --lend;
  --list;
  --lptr;
  --nodes;
  nn = *n;
  i__1 = nn;
  for (nst = 1; nst <= i__1; ++nst) {
    lp = lend[nst];
    if (list[lp] < 0) {
      goto L2;
    }
  }
  *nb = 0;
  *na = (nn - 2) * 3;
  *nt = (nn - 2) << 1;
  return 0;
L2:
  nodes[1] = nst;
  k = 1;
  n0 = nst;
L3:
  lp = lend[n0];
  lp = lptr[lp];
  n0 = list[lp];
  if (n0 == nst) {
    goto L4;
  }
  ++k;
  nodes[k] = n0;
  goto L3;
L4:
  *nb = k;
  *nt = (*n << 1) - *nb - 2;
  *na = *nt + *n - 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bnodes_>:
  endbr64
  push   %r12
  mov    %rdi,%r11
  sub    $0x4,%rsi
  push   %rbp
  push   %rbx
  mov    (%rdi),%ebp
  movl   $0x1,D22(%rip)
  test   %ebp,%ebp
  jle    L44
  mov    %rdx,%rbx
  mov    %rcx,%rdi
  mov    %rcx,%rdx
  xor    %r12d,%r12d
  mov    $0x1,%eax
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    $0x1,%r12d
  cmp    %eax,%ebp
  jl     L55
  mov    %eax,%r10d
L43:
  movslq (%rdx),%rcx
  mov    (%rsi,%rcx,4),%ecx
  test   %ecx,%ecx
  jns    L29
  test   %r12b,%r12b
  je     L72
  mov    %r10d,D24(%rip)
L72:
  mov    %eax,(%r8)
  movslq (%rdx),%rdx
  movl   $0x1,D24(%rip)
  movslq -0x4(%rbx,%rdx,4),%rdx
  movslq (%rsi,%rdx,4),%rdx
  mov    %edx,D17(%rip)
  cmp    %eax,%edx
  je     L11
  mov    $0x2,%ecx
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %edx,-0x4(%r8,%rcx,4)
  movslq -0x4(%rdi,%rdx,4),%rdx
  mov    %ecx,%r10d
  add    $0x1,%rcx
  movslq -0x4(%rbx,%rdx,4),%rdx
  movslq (%rsi,%rdx,4),%rdx
  cmp    %eax,%edx
  jne    L74
  mov    %r10d,D64(%rip)
  mov    %edx,D64(%rip)
L10:
  mov    %r10d,(%r9)
  mov    (%r11),%eax
  mov    0x28(%rsp),%rbx
  add    %eax,%eax
  sub    %r10d,%eax
  sub    $0x2,%eax
  mov    %eax,(%rbx)
  mov    0x20(%rsp),%rbx
  add    (%r11),%eax
  sub    $0x1,%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  mov    %eax,D64(%rip)
L44:
  sub    $0x2,%ebp
  mov    0x20(%rsp),%rbx
  movl   $0x0,(%r9)
  lea    0x0(%rbp,%rbp,1),%eax
  add    %eax,%ebp
  mov    %ebp,(%rbx)
  mov    0x28(%rsp),%rbx
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x1,%r10d
  jmp    L10
```

assistant: ```c
int bnodes_(int *n, int *list, int *lptr, int *lend, int *nodes, int *nb, int *na, int *nt) {
  int i__1;
  static int k, n0, lp, nn, nst;
  --lend;
  --list;
  --lptr;
  --nodes;
  nn = *n;
  i__1 = nn;
  for (nst = 1; nst <= i__1; ++nst) {
    lp = lend[nst];
    if (list[lp] < 0) {
      goto L2;
    }
  }
  *nb = 0;
  *na = (nn - 2) * 3;
  *nt = (nn - 2) << 1;
  return 0;
L2:
  nodes[1] = nst;
  k = 1;
  n0 = nst;
L3:
  lp = lend[n0];
  lp = lptr[lp];
  n0 = list[lp];
  if (n0 == nst) {
    goto L4;
  }
  ++k;
  nodes[k] = n0;
  goto L3;
L4:
  *nb = k;
  *nt = (*n << 1) - *nb - 2;
  *na = *nt + *n - 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bnodes_>:
  endbr64
  push   %r12
  mov    %rdi,%r11
  sub    $0x4,%rsi
  push   %rbp
  push   %rbx
  mov    (%rdi),%ebp
  movl   $0x1,D26(%rip)
  test   %ebp,%ebp
  jle    L9
  mov    %rdx,%rbx
  mov    %rcx,%rdi
  mov    %rcx,%rdx
  xor    %r12d,%r12d
  mov    $0x1,%eax
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L34:
  add    $0x1,%eax
  add    $0x4,%rdx
  mov    $0x1,%r12d
  cmp    %eax,%ebp
  jl     L10
  mov    %eax,%r10d
L52:
  movslq (%rdx),%rcx
  mov    (%rsi,%rcx,4),%ecx
  test   %ecx,%ecx
  jns    L34
  test   %r12b,%r12b
  je     L19
  mov    %r10d,D1(%rip)
L19:
  mov    %eax,(%r8)
  movslq (%rdx),%rdx
  movl   $0x1,D1(%rip)
  movslq -0x4(%rbx,%rdx,4),%rdx
  movslq (%rsi,%rdx,4),%rdx
  mov    %edx,D68(%rip)
  cmp    %eax,%edx
  je     L73
  mov    $0x2,%ecx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %edx,-0x4(%r8,%rcx,4)
  movslq -0x4(%rdi,%rdx,4),%rdx
  mov    %ecx,%r10d
  add    $0x1,%rcx
  movslq -0x4(%rbx,%rdx,4),%rdx
  movslq (%rsi,%rdx,4),%rdx
  cmp    %eax,%edx
  jne    L15
  mov    %r10d,D31(%rip)
  mov    %edx,D31(%rip)
L79:
  mov    %r10d,(%r9)
  mov    (%r11),%eax
  mov    0x28(%rsp),%rbx
  add    %eax,%eax
  sub    %r10d,%eax
  sub    $0x2,%eax
  mov    %eax,(%rbx)
  mov    0x20(%rsp),%rbx
  add    (%r11),%eax
  sub    $0x1,%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    %eax,D31(%rip)
L9:
  sub    $0x2,%ebp
  mov    0x20(%rsp),%rbx
  movl   $0x0,(%r9)
  lea    0x0(%rbp,%rbp,1),%eax
  add    %eax,%ebp
  mov    %ebp,(%rbx)
  mov    0x28(%rsp),%rbx
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  mov    $0x1,%r10d
  jmp    L79
```

assistant: ```c
int bnodes_(int *n, int *list, int *lptr, int *lend, int *nodes, int *nb, int *na, int *nt) {
  int i__1;
  static int k, n0, lp, nn, nst;
  --lend;
  --list;
  --lptr;
  --nodes;
  nn = *n;
  i__1 = nn;
  for (nst = 1; nst <= i__1; ++nst) {
    lp = lend[nst];
    if (list[lp] < 0) {
      goto L2;
    }
  }
  *nb = 0;
  *na = (nn - 2) * 3;
  *nt = (nn - 2) << 1;
  return 0;
L2:
  nodes[1] = nst;
  k = 1;
  n0 = nst;
L3:
  lp = lend[n0];
  lp = lptr[lp];
  n0 = list[lp];
  if (n0 == nst) {
    goto L4;
  }
  ++k;
  nodes[k] = n0;
  goto L3;
L4:
  *nb = k;
  *nt = (*n << 1) - *nb - 2;
  *na = *nt + *n - 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<public_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <createRSA@plt>
  mov    %rax,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  mov    -0x8(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <RSA_public_decrypt@plt>
  leave
  ret
```

assistant: ```c
int public_decrypt(const char *data, int data_len, const char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 1);
  return RSA_public_decrypt(data_len, (unsigned char *)data, decrypted, rsa, RSA_PKCS1_PADDING);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<public_decrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%rdi
  mov    %rcx,%r12
  mov    $0x1,%esi
  call   <createRSA@plt>
  mov    %rax,%rcx
  mov    D2(%rip),%rax
  mov    (%rax),%r8d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RSA_public_decrypt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int public_decrypt(const char *data, int data_len, const char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 1);
  return RSA_public_decrypt(data_len, (unsigned char *)data, decrypted, rsa, RSA_PKCS1_PADDING);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<public_decrypt>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  call   <createRSA@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    D3(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%r8d
  jmp    1060 <RSA_public_decrypt@plt>
```

assistant: ```c
int public_decrypt(const char *data, int data_len, const char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 1);
  return RSA_public_decrypt(data_len, (unsigned char *)data, decrypted, rsa, RSA_PKCS1_PADDING);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<public_decrypt>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  call   <createRSA@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    D4(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%r8d
  jmp    1060 <RSA_public_decrypt@plt>
```

assistant: ```c
int public_decrypt(const char *data, int data_len, const char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 1);
  return RSA_public_decrypt(data_len, (unsigned char *)data, decrypted, rsa, RSA_PKCS1_PADDING);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tail_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <tail_stream@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: r

assistant: ```c
void tail_file(char *path, int bytes, int lines) {
  FILE *stream = fopen(path, "r");
  if (stream == NULL) {
    perror(path);
    exit(1);
  }
  tail_stream(stream, bytes, lines);
  fclose(stream);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tail_file>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
L5:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <tail_stream@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: r

assistant: ```c
void tail_file(char *path, int bytes, int lines) {
  FILE *stream = fopen(path, "r");
  if (stream == NULL) {
    perror(path);
    exit(1);
  }
  tail_stream(stream, bytes, lines);
  fclose(stream);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tail_file>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  lea    D7(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
L5:
  mov    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <tail_stream@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <fclose@plt>
  nopl   (%rax)
L7:
  mov    %r12,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: r

assistant: ```c
void tail_file(char *path, int bytes, int lines) {
  FILE *stream = fopen(path, "r");
  if (stream == NULL) {
    perror(path);
    exit(1);
  }
  tail_stream(stream, bytes, lines);
  fclose(stream);
}
```
user: What is the c source code of the assembly code below:

```asm
<tail_file>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  lea    D6(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
L9:
  mov    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <tail_stream@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <fclose@plt>
  nopl   (%rax)
L15:
  mov    %r12,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: r

assistant: ```c
void tail_file(char *path, int bytes, int lines) {
  FILE *stream = fopen(path, "r");
  if (stream == NULL) {
    perror(path);
    exit(1);
  }
  tail_stream(stream, bytes, lines);
  fclose(stream);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotxr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D8
data_type: string

tool: D25: tmp = srcb & 1;


tool: D23: dst = srcb >> 1;


tool: D37: if (c) dst|=0x80;


tool: D8: c = tmp;


assistant: ```c
void rotxr() {
  printf("tmp = srcb & 1;\n");
  printf("dst = srcb >> 1;\n");
  printf("if (c) dst|=0x80;\n");
  printf("c = tmp;\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotxr>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D14
type_infered: string

tool: D6: tmp = srcb & 1;


tool: D19: dst = srcb >> 1;


tool: D25: if (c) dst|=0x80;


tool: D14: c = tmp;


assistant: ```c
void rotxr() {
  printf("tmp = srcb & 1;\n");
  printf("dst = srcb >> 1;\n");
  printf("if (c) dst|=0x80;\n");
  printf("c = tmp;\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotxr>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string

tool: D17: tmp = srcb & 1;


tool: D4: dst = srcb >> 1;


tool: D16: if (c) dst|=0x80;


tool: D28: c = tmp;


assistant: ```c
void rotxr() {
  printf("tmp = srcb & 1;\n");
  printf("dst = srcb >> 1;\n");
  printf("if (c) dst|=0x80;\n");
  printf("c = tmp;\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotxr>:
  endbr64
  sub    $0x8,%rsp
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D37
type_guessed: string

tool: D38: tmp = srcb & 1;


tool: D0: dst = srcb >> 1;


tool: D25: if (c) dst|=0x80;


tool: D37: c = tmp;


assistant: ```c
void rotxr() {
  printf("tmp = srcb & 1;\n");
  printf("dst = srcb >> 1;\n");
  printf("if (c) dst|=0x80;\n");
  printf("c = tmp;\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L26
  movzwl -0xa(%rbp),%eax
  shr    $0x4,%ax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
  jmp    L1
L26:
  movzwl -0xa(%rbp),%eax
  add    %eax,%eax
  mov    %ax,-0xa(%rbp)
L1:
  movzwl -0xa(%rbp),%eax
  lea    0x5421(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + (unsigned short)21537;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x6aab(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + (unsigned short)21537;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x6aab(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + (unsigned short)21537;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x6aab(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        state[0UL] += state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + (unsigned short)21537;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uart_rename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int uart_rename(const char *oldname __attribute__((unused)), const char *newname __attribute__((unused))) {
  errno = EINVAL;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_rename>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int uart_rename(const char *oldname __attribute__((unused)), const char *newname __attribute__((unused))) {
  errno = EINVAL;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_rename>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int uart_rename(const char *oldname __attribute__((unused)), const char *newname __attribute__((unused))) {
  errno = EINVAL;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uart_rename>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int uart_rename(const char *oldname __attribute__((unused)), const char *newname __attribute__((unused))) {
  errno = EINVAL;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<util_utf8toutf16_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <util_utf8toutf16_len@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L17
L27:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  lea    0x2(%rax),%esi
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <util_utf8toutf16@plt>
  test   %eax,%eax
  jne    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L17
L5:
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
unsigned char *util_utf8toutf16_alloc(unsigned char *utf8) {
  unsigned char *out;
  int new_len;
  new_len = util_utf8toutf16_len(utf8);
  if (new_len == -1)
    return NULL;
  out = calloc(1, new_len + 2);
  if (!util_utf8toutf16(out, new_len + 2, utf8, (int)strlen((char *)utf8))) {
    free(out);
    return NULL;
  }
  return out;
}
```