ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read_file@plt>
  xor    %eax,%eax
  call   <write_file@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  int i, j;
  char *s;
  char *progname;
  progname = argv[0];
  read_file();
  write_file();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_char_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L65
  cmpb   $0x39,-0x4(%rbp)
  jg     L65
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L46
L65:
  cmpb   $0x60,-0x4(%rbp)
  jle    L39
  cmpb   $0x66,-0x4(%rbp)
  jg     L39
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L46
L39:
  cmpb   $0x40,-0x4(%rbp)
  jle    L79
  cmpb   $0x46,-0x4(%rbp)
  jg     L79
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L46
L79:
  mov    $0xffffffff,%eax
L46:
  pop    %rbp
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else if (c >= 'a' && c <= 'f') {
    return c - 'a' + 10;
  } else if (c >= 'A' && c <= 'F') {
    return c - 'A' + 10;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L13
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L15
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L13:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L15:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else if (c >= 'a' && c <= 'f') {
    return c - 'a' + 10;
  } else if (c >= 'A' && c <= 'F') {
    return c - 'A' + 10;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L17
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else if (c >= 'a' && c <= 'f') {
    return c - 'a' + 10;
  } else if (c >= 'A' && c <= 'F') {
    return c - 'A' + 10;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_char_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L17
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L9
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_char_to_int(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else if (c >= 'a' && c <= 'f') {
    return c - 'a' + 10;
  } else if (c >= 'A' && c <= 'F') {
    return c - 'A' + 10;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply396>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L16
L19:
  movl   $0x0,-0x3c(%rbp)
  jmp    L25
L8:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L25:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L8
  addl   $0x1,-0x40(%rbp)
L16:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L19
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply396(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply396>:
  endbr64
  test   %edi,%edi
  jle    L20
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L7:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L11:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L11
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  ret
```

assistant: ```c
void multiply396(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multiply396>:
  endbr64
  test   %edi,%edi
  jle    L18
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L12
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L23
  pop    %rbx
  ret
L18:
  ret
```

assistant: ```c
void multiply396(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply396>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L69
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L63:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L53
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L53
  nopl   0x0(%rax)
L80:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L80
  cmp    -0x24(%rsp),%r11d
  je     L92
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L92
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L92
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L92:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L63
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L51:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L51
  mov    -0x18(%rsp),%r8
  jmp    L92
```

assistant: ```c
void multiply396(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hypot9>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double hypot9(double *a) {
  double r;
  r = *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  return sqrt(r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hypot9>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x20(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x28(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x30(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x38(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x40(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L0
  sqrtsd %xmm0,%xmm0
  ret
L0:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double hypot9(double *a) {
  double r;
  r = *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  return sqrt(r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hypot9>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x20(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x28(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x30(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x38(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x40(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
  ret
L3:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double hypot9(double *a) {
  double r;
  r = *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  return sqrt(r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hypot9>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x18(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x20(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x28(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x30(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x38(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x40(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L6
  sqrtsd %xmm0,%xmm0
  ret
L6:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double hypot9(double *a) {
  double r;
  r = *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  a++;
  r += *a * *a;
  return sqrt(r);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pcap_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <pcap_vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pcap_snprintf(char *str, size_t str_size, const char *format, ...) {
  va_list args;
  int ret;
  va_start(args, format);
  ret = pcap_vsnprintf(str, str_size, format, args);
  va_end(args);
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pcap_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <pcap_vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int pcap_snprintf(char *str, size_t str_size, const char *format, ...) {
  va_list args;
  int ret;
  va_start(args, format);
  ret = pcap_vsnprintf(str, str_size, format, args);
  va_end(args);
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<pcap_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <pcap_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pcap_snprintf(char *str, size_t str_size, const char *format, ...) {
  va_list args;
  int ret;
  va_start(args, format);
  ret = pcap_vsnprintf(str, str_size, format, args);
  va_end(args);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pcap_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <pcap_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pcap_snprintf(char *str, size_t str_size, const char *format, ...) {
  va_list args;
  int ret;
  va_start(args, format);
  ret = pcap_vsnprintf(str, str_size, format, args);
  va_end(args);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<enqueue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L1
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
enqueue(int *a, int val, int *rear, int *front) {
  if (*front == -1)
    (*front)++;
  (*rear)++;
  *(a + (*rear)) = val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<enqueue>:
  endbr64
  cmpl   $0xffffffff,(%rcx)
  je     L15
L0:
  mov    (%rdx),%eax
  add    $0x1,%eax
  mov    %eax,(%rdx)
  cltq
  mov    %esi,(%rdi,%rax,4)
  ret
L15:
  movl   $0x0,(%rcx)
  jmp    L0
```

assistant: ```c
enqueue(int *a, int val, int *rear, int *front) {
  if (*front == -1)
    (*front)++;
  (*rear)++;
  *(a + (*rear)) = val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<enqueue>:
  endbr64
  cmpl   $0xffffffff,(%rcx)
  jne    L5
  movl   $0x0,(%rcx)
L5:
  mov    (%rdx),%eax
  add    $0x1,%eax
  mov    %eax,(%rdx)
  cltq
  mov    %esi,(%rdi,%rax,4)
  ret
```

assistant: ```c
enqueue(int *a, int val, int *rear, int *front) {
  if (*front == -1)
    (*front)++;
  (*rear)++;
  *(a + (*rear)) = val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<enqueue>:
  endbr64
  cmpl   $0xffffffff,(%rcx)
  jne    L0
  movl   $0x0,(%rcx)
L0:
  mov    (%rdx),%eax
  add    $0x1,%eax
  mov    %eax,(%rdx)
  cltq
  mov    %esi,(%rdi,%rax,4)
  ret
```

assistant: ```c
enqueue(int *a, int val, int *rear, int *front) {
  if (*front == -1)
    (*front)++;
  (*rear)++;
  *(a + (*rear)) = val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isearch_seq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  mov    $0xffffffff,%ecx
  mov    %eax,%edi
  call   <bsearch_seq@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <region_to_hi_lo@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int isearch_seq(unsigned int key, unsigned int *I, unsigned int I_size, unsigned int D_size, int *D_hi, int *D_lo) {
  unsigned int region = bsearch_seq(key, I, I_size, -1, I_size);
  region_to_hi_lo(region, I_size + 1, D_size, D_hi, D_lo);
  return region;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isearch_seq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %r8,%r13
  mov    %r9,%r14
  mov    %edx,%r8d
  mov    $0xffffffff,%ecx
  call   <bsearch_seq@plt>
  mov    %eax,%ebp
  lea    0x1(%rbx),%esi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %eax,%edi
  call   <region_to_hi_lo@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int isearch_seq(unsigned int key, unsigned int *I, unsigned int I_size, unsigned int D_size, int *D_hi, int *D_lo) {
  unsigned int region = bsearch_seq(key, I, I_size, -1, I_size);
  region_to_hi_lo(region, I_size + 1, D_size, D_hi, D_lo);
  return region;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isearch_seq>:
  endbr64
  push   %r14
  mov    %r8,%r14
  mov    %edx,%r8d
  push   %r13
  mov    %ecx,%r13d
  mov    $0xffffffff,%ecx
  push   %r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <bsearch_seq@plt>
  lea    0x1(%rbx),%esi
  mov    %rbp,%r8
  mov    %r14,%rcx
  mov    %eax,%r12d
  mov    %r13d,%edx
  mov    %eax,%edi
  call   <region_to_hi_lo@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned int isearch_seq(unsigned int key, unsigned int *I, unsigned int I_size, unsigned int D_size, int *D_hi, int *D_lo) {
  unsigned int region = bsearch_seq(key, I, I_size, -1, I_size);
  region_to_hi_lo(region, I_size + 1, D_size, D_hi, D_lo);
  return region;
}
```