ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<splitmix64_next>:
  endbr64
  mov    (%rdi),%eax
  lea    0x7f4a7c15(%rax),%edx
  mov    %edx,%eax
  mov    %edx,(%rdi)
  sar    $0x1e,%eax
  xor    %edx,%eax
  imul   $0x1ce4e5b9,%eax,%eax
  mov    %eax,%edx
  sar    $0x1b,%edx
  xor    %eax,%edx
  imul   $0x133111eb,%edx,%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint64_t splitmix64_next(uint64_t *state) {
  uint64_t z = (*state += 0x9e3779b97f4a7c15);
  z = (z ^ (z >> 30)) * 0xbf58476d1ce4e5b9;
  z = (z ^ (z >> 27)) * 0x94d049bb133111eb;
  return z ^ (z >> 31);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movw   $0x1,-0x12(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L20:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzwl -0x12(%rbp),%ecx
  movswl %cx,%eax
  imul   $0x6667,%eax,%eax
  shr    $0x10,%eax
  sar    $0x2,%ax
  mov    %ecx,%esi
  sar    $0xf,%si
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %dx,%dx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
L25:
  movzwl -0x12(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x12(%rbp)
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L20
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string

tool: D4: %x 

assistant: ```c
void print_buffer(void *buf, unsigned size) {
  short step = 1;
  unsigned char *i = (unsigned char *)buf;
  unsigned char *end = (unsigned char *)buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  add    %rdi,%r12
  cmp    %r12,%rdi
  jae    L13
  mov    %rdi,%rbp
  movzbl (%rdi),%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  mov    $0x2,%r13d
  sub    %ebp,%r13d
  lea    D16(%rip),%r14
L35:
  lea    0x0(%r13,%rbx,1),%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L13
  movzbl (%rbx),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movswl %bp,%eax
  imul   $0x6667,%eax,%eax
  sar    $0x12,%eax
  mov    %ebp,%edx
  sar    $0xf,%dx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %ax,%bp
  jne    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L35
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type_guessed: string

tool: D16: %x 

assistant: ```c
void print_buffer(void *buf, unsigned size) {
  short step = 1;
  unsigned char *i = (unsigned char *)buf;
  unsigned char *end = (unsigned char *)buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  add    %rdi,%rbp
  push   %rbx
  cmp    %rbp,%rdi
  jae    L21
  movzbl (%rdi),%esi
  lea    D6(%rip),%r13
  mov    %rdi,%r14
  xor    %eax,%eax
  mov    %r13,%rdi
  mov    $0x2,%r12d
  call   <printf@plt>
  sub    %r14d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    (%r12,%r14,1),%ebx
  add    $0x1,%r14
  cmp    %r14,%rbp
  je     L21
L33:
  imul   $0xcccd,%bx,%bx
  movzbl (%r14),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1998,%bx
  ror    %bx
  cmp    $0x1998,%bx
  ja     L0
  mov    $0xa,%edi
  lea    (%r12,%r14,1),%ebx
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L33
L21:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %x 

assistant: ```c
void print_buffer(void *buf, unsigned size) {
  short step = 1;
  unsigned char *i = (unsigned char *)buf;
  unsigned char *end = (unsigned char *)buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  add    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  jae    L2
  movzbl (%rdi),%esi
  mov    %rdi,%r13
  lea    D8(%rip),%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  add    $0x1,%r13
  mov    $0x2,%ebp
  call   <printf@plt>
  sub    %r13d,%ebp
  cmp    %rbx,%r13
  jae    L2
L10:
  movzbl 0x0(%r13),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x0(%rbp,%r13,1),%eax
  imul   $0xcccd,%ax,%ax
  add    $0x1998,%ax
  ror    %ax
  cmp    $0x1998,%ax
  ja     L12
  mov    $0xa,%edi
  call   <putchar@plt>
L12:
  add    $0x1,%r13
  cmp    %r13,%rbx
  jne    L10
L2:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: %x 

assistant: ```c
void print_buffer(void *buf, unsigned size) {
  short step = 1;
  unsigned char *i = (unsigned char *)buf;
  unsigned char *end = (unsigned char *)buf + size;
  while (i < end) {
    printf("%x ", *i);
    if (step % 10 == 0)
      printf("\n");
    ++step;
    ++i;
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitxor_funktion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitxor_funktion(int var1, int var2) {
  int erg;
  erg = var1 ^ var2;
  return (var1 ^ var2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitxor_funktion>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int bitxor_funktion(int var1, int var2) {
  int erg;
  erg = var1 ^ var2;
  return (var1 ^ var2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitxor_funktion>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int bitxor_funktion(int var1, int var2) {
  int erg;
  erg = var1 ^ var2;
  return (var1 ^ var2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitxor_funktion>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int bitxor_funktion(int var1, int var2) {
  int erg;
  erg = var1 ^ var2;
  return (var1 ^ var2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x4343,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: CC

assistant: ```c
int main() {
  char msg[] = "CC";
  test(msg);
  test("CC");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x4343,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x5(%rsp),%rdi
  call   <test@plt>
  lea    D5(%rip),%rdi
  call   <test@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: CC

assistant: ```c
int main() {
  char msg[] = "CC";
  test(msg);
  test("CC");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdi
  mov    $0x4343,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <test@plt>
  lea    D2(%rip),%rdi
  call   <test@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: CC

assistant: ```c
int main() {
  char msg[] = "CC";
  test(msg);
  test("CC");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdi
  mov    $0x4343,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <test@plt>
  lea    D5(%rip),%rdi
  call   <test@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: CC

assistant: ```c
int main() {
  char msg[] = "CC";
  test(msg);
  test("CC");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fs_read_nth_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  nop
L5:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cmp    %eax,-0x1c(%rbp)
  jle    L10
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <find_next_in_filestream@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L10
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  cmp    $0xffffffff,%eax
  jne    L5
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fs_first_line@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *restrict fs_read_nth_line(FILE *file_stream, const int nth) {
  char *string;
  int current_line = 0;
  int char_offset = 0;
  while (current_line++ < nth && (char_offset = find_next_in_filestream(file_stream, '\n') + 1) && (fseek(file_stream, char_offset, 1) != -1))
    ;
  string = fs_first_line(file_stream);
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fs_read_nth_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L14:
  cmp    %ebx,%r12d
  jle    L5
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <find_next_in_filestream@plt>
  add    $0x1,%eax
  mov    %eax,%esi
  je     L5
  mov    $0x1,%edx
  mov    %rbp,%rdi
  call   <fseek@plt>
  add    $0x1,%ebx
  cmp    $0xffffffff,%eax
  jne    L14
L5:
  mov    %rbp,%rdi
  call   <fs_first_line@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *restrict fs_read_nth_line(FILE *file_stream, const int nth) {
  char *string;
  int current_line = 0;
  int char_offset = 0;
  while (current_line++ < nth && (char_offset = find_next_in_filestream(file_stream, '\n') + 1) && (fseek(file_stream, char_offset, 1) != -1))
    ;
  string = fs_first_line(file_stream);
  return string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fs_read_nth_line>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <find_next_in_filestream@plt>
  add    $0x1,%eax
  mov    %eax,%esi
  je     L17
  mov    $0x1,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <fseek@plt>
  cmp    $0xffffffff,%eax
  je     L17
L16:
  cmp    %ebx,%r12d
  jg     L10
L17:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fs_first_line@plt>
```

assistant: ```c
char *restrict fs_read_nth_line(FILE *file_stream, const int nth) {
  char *string;
  int current_line = 0;
  int char_offset = 0;
  while (current_line++ < nth && (char_offset = find_next_in_filestream(file_stream, '\n') + 1) && (fseek(file_stream, char_offset, 1) != -1))
    ;
  string = fs_first_line(file_stream);
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fs_read_nth_line>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <find_next_in_filestream@plt>
  add    $0x1,%eax
  mov    %eax,%esi
  je     L0
  mov    $0x1,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <fseek@plt>
  cmp    $0xffffffff,%eax
  je     L0
L37:
  cmp    %ebx,%r12d
  jg     L30
L0:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <fs_first_line@plt>
```

assistant: ```c
char *restrict fs_read_nth_line(FILE *file_stream, const int nth) {
  char *string;
  int current_line = 0;
  int char_offset = 0;
  while (current_line++ < nth && (char_offset = find_next_in_filestream(file_stream, '\n') + 1) && (fseek(file_stream, char_offset, 1) != -1))
    ;
  string = fs_first_line(file_stream);
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MEM_readLEST>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <MEM_32bits@plt>
  test   %rax,%rax
  je     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <MEM_readLE32@plt>
  cltq
  jmp    L18
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <MEM_readLE64@plt>
  cltq
L18:
  leave
  ret
```

assistant: ```c
__attribute__((unused)) size_t MEM_readLEST(const void *memPtr) {
  if (MEM_32bits())
    return (size_t)MEM_readLE32(memPtr);
  else
    return (size_t)MEM_readLE64(memPtr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<MEM_readLEST>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <MEM_32bits@plt>
  test   %rax,%rax
  je     L18
  mov    %rbx,%rdi
  call   <MEM_readLE32@plt>
  cltq
L10:
  pop    %rbx
  ret
L18:
  mov    %rbx,%rdi
  call   <MEM_readLE64@plt>
  cltq
  jmp    L10
```

assistant: ```c
__attribute__((unused)) size_t MEM_readLEST(const void *memPtr) {
  if (MEM_32bits())
    return (size_t)MEM_readLE32(memPtr);
  else
    return (size_t)MEM_readLE64(memPtr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MEM_readLEST>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <MEM_32bits@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L1
  call   <MEM_readLE32@plt>
  pop    %rbp
  cltq
  ret
L1:
  call   <MEM_readLE64@plt>
  pop    %rbp
  cltq
  ret
```

assistant: ```c
__attribute__((unused)) size_t MEM_readLEST(const void *memPtr) {
  if (MEM_32bits())
    return (size_t)MEM_readLE32(memPtr);
  else
    return (size_t)MEM_readLE64(memPtr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<MEM_readLEST>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <MEM_32bits@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L5
  call   <MEM_readLE32@plt>
  pop    %rbp
  cltq
  ret
L5:
  call   <MEM_readLE64@plt>
  pop    %rbp
  cltq
  ret
```

assistant: ```c
__attribute__((unused)) size_t MEM_readLEST(const void *memPtr) {
  if (MEM_32bits())
    return (size_t)MEM_readLE32(memPtr);
  else
    return (size_t)MEM_readLE64(memPtr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculate_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L8:
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L8
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *calculate_primes(int n) {
  int *primes = (int *)malloc(n * sizeof(int));
  assert(primes != NULL);
  int p = 1;
  for (int i = 0; i < n; i++) {
    while (!is_prime(p))
      p++;
    primes[i] = p;
    p++;
  }
  return primes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculate_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebx,%ebx
  jle    L30
  mov    %r13,%rbp
  mov    %ebx,%ebx
  lea    0x0(%r13,%rbx,4),%r12
  mov    $0x1,%ebx
  jmp    L32
L27:
  add    $0x1,%ebx
L32:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L27
  mov    %ebx,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L32
L30:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *calculate_primes(int n) {
  int *primes = (int *)malloc(n * sizeof(int));
  assert(primes != NULL);
  int p = 1;
  for (int i = 0; i < n; i++) {
    while (!is_prime(p))
      p++;
    primes[i] = p;
    p++;
  }
  return primes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calculate_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r13
  setne  %dil
  call   <assert@plt>
  test   %ebx,%ebx
  jle    L28
  lea    0x0(%r13,%rbx,4),%r12
  mov    %r13,%rbp
  mov    $0x1,%ebx
  xchg   %ax,%ax
L5:
  mov    %ebx,%edi
  call   <is_prime@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  test   %eax,%eax
  je     L5
  mov    %edx,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L5
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *calculate_primes(int n) {
  int *primes = (int *)malloc(n * sizeof(int));
  assert(primes != NULL);
  int p = 1;
  for (int i = 0; i < n; i++) {
    while (!is_prime(p))
      p++;
    primes[i] = p;
    p++;
  }
  return primes;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculate_primes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r13
  setne  %dil
  call   <assert@plt>
  test   %ebx,%ebx
  jle    L3
  lea    0x0(%r13,%rbx,4),%r12
  mov    %r13,%rbp
  mov    $0x1,%ebx
  xchg   %ax,%ax
L5:
  mov    %ebx,%edi
  call   <is_prime@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  test   %eax,%eax
  je     L5
  mov    %edx,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L5
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *calculate_primes(int n) {
  int *primes = (int *)malloc(n * sizeof(int));
  assert(primes != NULL);
  int p = 1;
  for (int i = 0; i < n; i++) {
    while (!is_prime(p))
      p++;
    primes[i] = p;
    p++;
  }
  return primes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <make_9x9@plt>
  movl   $0x0,-0x158(%rbp)
  jmp    L43
L25:
  movl   $0x0,-0x154(%rbp)
  jmp    L15
L2:
  mov    -0x154(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x158(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x150(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x154(%rbp)
L15:
  cmpl   $0x8,-0x154(%rbp)
  jle    L2
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x158(%rbp)
L43:
  cmpl   $0x8,-0x158(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D9: %d 

tool: 

assistant: ```c
int main() {
  int a[9][9], i, k;
  make_9x9(a);
  i = 0;
  while (i < 9) {
    k = 0;
    while (k < 9) {
      printf("%d ", a[i][k]);
      k += 1;
    }
    puts("");
    i += 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <make_9x9@plt>
  lea    0x24(%rsp),%rbp
  lea    0x168(%rsp),%r14
  lea    D2(%rip),%r12
  lea    D9(%rip),%r13
L1:
  lea    -0x24(%rbp),%rbx
L21:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L21
  mov    %r13,%rdi
  call   <puts@plt>
  add    $0x24,%rbp
  cmp    %r14,%rbp
  jne    L1
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D2: %d 

tool: 

assistant: ```c
int main() {
  int a[9][9], i, k;
  make_9x9(a);
  i = 0;
  while (i < 9) {
    k = 0;
    while (k < 9) {
      printf("%d ", a[i][k]);
      k += 1;
    }
    puts("");
    i += 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %rsp,%rdi
  lea    0x24(%rsp),%rbp
  lea    0x168(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <make_9x9@plt>
  nopl   0x0(%rax)
L14:
  lea    -0x24(%rbp),%rbx
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L5
  mov    %r13,%rdi
  lea    0x24(%rbx),%rbp
  call   <puts@plt>
  cmp    %r14,%rbp
  jne    L14
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x150,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: 

tool: D9: %d 

assistant: ```c
int main() {
  int a[9][9], i, k;
  make_9x9(a);
  i = 0;
  while (i < 9) {
    k = 0;
    while (k < 9) {
      printf("%d ", a[i][k]);
      k += 1;
    }
    puts("");
    i += 1;
  }
  return 0;
}
```