ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1f,(%rsp)
  movl   $0x3,0x4(%rsp)
  mov    $0x1f,%edx
  mov    $0x3,%esi
  mov    $0x7e0,%edi
  call   <day_of_year@plt>
  mov    %eax,%ebx
  mov    %eax,%r8d
  mov    $0x7e0,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %rsp,%rcx
  lea    0x4(%rsp),%rdx
  mov    %ebx,%esi
  mov    $0x7e0,%edi
  call   <month_day@plt>
  mov    %ebx,%r8d
  mov    $0x7e0,%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %02d/%02d/%d, day of year: %d


assistant: ```c
int main(void) {
  int day = 31;
  int mon = 3;
  int year = 2016;
  int dayOfYear = 0;
  dayOfYear = day_of_year(year, mon, day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  ++dayOfYear;
  month_day(year, dayOfYear, &mon, &day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1f,%edx
  mov    $0x3,%esi
  mov    $0x7e0,%edi
  push   %rbx
  lea    D5(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1f,(%rsp)
  movl   $0x3,0x4(%rsp)
  call   <day_of_year@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    %eax,%r8d
  mov    $0x7e0,%ecx
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %rsp,%rcx
  lea    0x4(%rsp),%rdx
  mov    %ebx,%esi
  mov    $0x7e0,%edi
  call   <month_day@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %ebx,%r8d
  mov    $0x7e0,%ecx
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: %02d/%02d/%d, day of year: %d


assistant: ```c
int main(void) {
  int day = 31;
  int mon = 3;
  int year = 2016;
  int dayOfYear = 0;
  dayOfYear = day_of_year(year, mon, day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  ++dayOfYear;
  month_day(year, dayOfYear, &mon, &day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1f,%edx
  mov    $0x3,%esi
  mov    $0x7e0,%edi
  push   %rbx
  lea    D0(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1f,(%rsp)
  movl   $0x3,0x4(%rsp)
  call   <day_of_year@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    %eax,%r8d
  mov    $0x7e0,%ecx
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %rsp,%rcx
  lea    0x4(%rsp),%rdx
  mov    %ebx,%esi
  mov    $0x7e0,%edi
  call   <month_day@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %ebx,%r8d
  mov    $0x7e0,%ecx
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: %02d/%02d/%d, day of year: %d


assistant: ```c
int main(void) {
  int day = 31;
  int mon = 3;
  int year = 2016;
  int dayOfYear = 0;
  dayOfYear = day_of_year(year, mon, day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  ++dayOfYear;
  month_day(year, dayOfYear, &mon, &day);
  printf("%02d/%02d/%d, day of year: %d\n", day, mon, year, dayOfYear);
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__imlib_rgb_to_hls>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  mov    %rcx,%rax
  cvtsi2ss %edi,%xmm0
  movss  D68(%rip),%xmm3
  cvtsi2ss %esi,%xmm2
  cvtsi2ss %edx,%xmm1
  divss  %xmm3,%xmm0
  divss  %xmm3,%xmm2
  divss  %xmm3,%xmm1
  comiss %xmm0,%xmm2
  ja     L73
  movaps %xmm2,%xmm4
  movaps %xmm0,%xmm3
  xor    %edx,%edx
L47:
  comiss %xmm3,%xmm1
  ja     L92
  movaps %xmm1,%xmm6
  minss  %xmm4,%xmm6
  movaps %xmm6,%xmm4
L68:
  movaps %xmm3,%xmm7
  movaps %xmm3,%xmm9
  pxor   %xmm8,%xmm8
  movss  D49(%rip),%xmm6
  addss  %xmm4,%xmm7
  subss  %xmm4,%xmm9
  movaps %xmm7,%xmm5
  ucomiss %xmm8,%xmm9
  mulss  %xmm6,%xmm5
  movss  %xmm5,(%r8)
  jp     L114
  jne    L114
  movl   $0x0,(%r9)
  movl   $0x0,(%rax)
  ret
  xchg   %ax,%ax
L92:
  movaps %xmm1,%xmm3
  mov    $0x2,%edx
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L73:
  movaps %xmm0,%xmm4
  movaps %xmm2,%xmm3
  mov    $0x1,%edx
  jmp    L47
  nopl   (%rax)
L114:
  comiss %xmm5,%xmm6
  jbe    L110
  movaps %xmm9,%xmm4
  divss  %xmm7,%xmm4
  cmp    $0x1,%edx
  je     L112
L38:
  cmp    $0x2,%edx
  je     L15
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  divss  %xmm9,%xmm0
L93:
  mulss  D28(%rip),%xmm0
  movss  %xmm4,(%r9)
  comiss %xmm0,%xmm8
  jbe    L101
  addss  D60(%rip),%xmm0
L101:
  movss  %xmm0,(%rax)
  ret
  nopl   0x0(%rax,%rax,1)
L110:
  movss  D4(%rip),%xmm5
  subss  %xmm3,%xmm5
  subss  %xmm4,%xmm5
  movaps %xmm9,%xmm4
  divss  %xmm5,%xmm4
  cmp    $0x1,%edx
  jne    L38
L112:
  subss  %xmm0,%xmm1
  divss  %xmm9,%xmm1
  addss  D4(%rip),%xmm1
  movaps %xmm1,%xmm0
  jmp    L93
  nopl   0x0(%rax,%rax,1)
L15:
  subss  %xmm2,%xmm0
  divss  %xmm9,%xmm0
  addss  D65(%rip),%xmm0
  jmp    L93
```

tool_calls: name: unpack_data
arguments: data_tag: D68
type: f32
name: unpack_data
arguments: data_tag: D49
type: f32
name: unpack_data
arguments: data_tag: D28
type: f32
name: unpack_data
arguments: data_tag: D60
type: f32
name: unpack_data
arguments: data_tag: D4
type: f32
name: unpack_data
arguments: data_tag: D65
type: byte[4]

tool: D68: 255

tool: D49: 0.5

tool: D28: 60

tool: D60: 360

tool: D4: 2

tool: {"D65": [0x00,0x00,0x80,0x40]}

assistant: ```c
void __imlib_rgb_to_hls(int r, int g, int b, float *hue, float *lightness, float *saturation) {
  int f;
  float i, j, k, max, min, d;
  i = ((float)r) / 255.0;
  j = ((float)g) / 255.0;
  k = ((float)b) / 255.0;
  f = 0;
  max = min = i;
  if (j > max) {
    max = j;
    f = 1;
  } else
    min = j;
  if (k > max) {
    max = k;
    f = 2;
  } else if (k < min)
    min = k;
  d = max - min;
  *lightness = (max + min) / 2.0;
  if (d == 0) {
    *saturation = 0;
    *hue = 0;
  } else {
    if (*lightness < 0.5)
      *saturation = d / (max + min);
    else
      *saturation = d / (2 - max - min);
    switch (f) {
    case 0:
      *hue = (j - k) / d;
      break;
    case 1:
      *hue = 2 + (k - i) / d;
      break;
    case 2:
      *hue = 4 + (i - j) / d;
      break;
    }
    *hue *= 60.0;
    if (*hue < 0)
      *hue += 360.0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__imlib_rgb_to_hls>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  mov    %rcx,%rax
  cvtsi2ss %edi,%xmm0
  movss  D42(%rip),%xmm3
  cvtsi2ss %esi,%xmm2
  cvtsi2ss %edx,%xmm1
  divss  %xmm3,%xmm0
  divss  %xmm3,%xmm2
  divss  %xmm3,%xmm1
  comiss %xmm0,%xmm2
  ja     L75
  movaps %xmm2,%xmm4
  movaps %xmm0,%xmm3
  xor    %edx,%edx
L78:
  comiss %xmm3,%xmm1
  ja     L96
  movaps %xmm1,%xmm6
  minss  %xmm4,%xmm6
  movaps %xmm6,%xmm4
L1:
  movaps %xmm3,%xmm7
  movaps %xmm3,%xmm9
  pxor   %xmm8,%xmm8
  movss  D47(%rip),%xmm6
  addss  %xmm4,%xmm7
  subss  %xmm4,%xmm9
  movaps %xmm7,%xmm5
  ucomiss %xmm8,%xmm9
  mulss  %xmm6,%xmm5
  movss  %xmm5,(%r8)
  jp     L31
  jne    L31
  movl   $0x0,(%r9)
  movl   $0x0,(%rax)
  ret
  xchg   %ax,%ax
L96:
  movaps %xmm1,%xmm3
  mov    $0x2,%edx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L75:
  movaps %xmm0,%xmm4
  movaps %xmm2,%xmm3
  mov    $0x1,%edx
  jmp    L78
  nopl   (%rax)
L31:
  comiss %xmm5,%xmm6
  jbe    L0
  movaps %xmm9,%xmm4
  divss  %xmm7,%xmm4
  cmp    $0x1,%edx
  je     L73
L128:
  cmp    $0x2,%edx
  je     L4
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  divss  %xmm9,%xmm0
L28:
  mulss  D38(%rip),%xmm0
  movss  %xmm4,(%r9)
  comiss %xmm0,%xmm8
  jbe    L116
  addss  D5(%rip),%xmm0
L116:
  movss  %xmm0,(%rax)
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  movss  D31(%rip),%xmm5
  subss  %xmm3,%xmm5
  subss  %xmm4,%xmm5
  movaps %xmm9,%xmm4
  divss  %xmm5,%xmm4
  cmp    $0x1,%edx
  jne    L128
L73:
  subss  %xmm0,%xmm1
  divss  %xmm9,%xmm1
  addss  D31(%rip),%xmm1
  movaps %xmm1,%xmm0
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L4:
  subss  %xmm2,%xmm0
  divss  %xmm9,%xmm0
  addss  D39(%rip),%xmm0
  jmp    L28
```

tool_calls: name: unpack_data
arguments: tag: D42
type: f32
name: unpack_data
arguments: tag: D47
type: f32
name: unpack_data
arguments: tag: D38
type: f32
name: unpack_data
arguments: tag: D5
type: f32
name: unpack_data
arguments: tag: D31
type: f32
name: unpack_data
arguments: tag: D39
type: byte[4]

tool: D42: 255

tool: D47: 0.5

tool: D38: 60

tool: D5: 360

tool: D31: 2

tool: {"D39": [0x00,0x00,0x80,0x40]}

assistant: ```c
void __imlib_rgb_to_hls(int r, int g, int b, float *hue, float *lightness, float *saturation) {
  int f;
  float i, j, k, max, min, d;
  i = ((float)r) / 255.0;
  j = ((float)g) / 255.0;
  k = ((float)b) / 255.0;
  f = 0;
  max = min = i;
  if (j > max) {
    max = j;
    f = 1;
  } else
    min = j;
  if (k > max) {
    max = k;
    f = 2;
  } else if (k < min)
    min = k;
  d = max - min;
  *lightness = (max + min) / 2.0;
  if (d == 0) {
    *saturation = 0;
    *hue = 0;
  } else {
    if (*lightness < 0.5)
      *saturation = d / (max + min);
    else
      *saturation = d / (2 - max - min);
    switch (f) {
    case 0:
      *hue = (j - k) / d;
      break;
    case 1:
      *hue = 2 + (k - i) / d;
      break;
    case 2:
      *hue = 4 + (i - j) / d;
      break;
    }
    *hue *= 60.0;
    if (*hue < 0)
      *hue += 360.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rndloglogistic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    $0x0,%eax
  call   <rndlogistic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D4(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L0
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
L0:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: f64
name: unpack_data
arguments: data_tag: D4
type_infered: byte[8]

tool: D7: 1e+300

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x89,0x40]}

assistant: ```c
double rndloglogistic(double loc, double s) {
  double t = rndlogistic(), logt = 1E300;
  if (t < 800)
    logt = exp(loc + s * t);
  return (logt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rndloglogistic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  mov    $0x0,%eax
  call   <rndlogistic@plt>
  movsd  D8(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L12
  movsd  D6(%rip),%xmm0
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  movq   %rbp,%xmm2
  mulsd  %xmm2,%xmm0
  movq   %rbx,%xmm3
  addsd  %xmm3,%xmm0
  call   <exp@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: byte[8]
name: retrieve_data
arguments: data_label: D6
datatype: f64

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x89,0x40]}

tool: D6: 1e+300

assistant: ```c
double rndloglogistic(double loc, double s) {
  double t = rndlogistic(), logt = 1E300;
  if (t < 800)
    logt = exp(loc + s * t);
  return (logt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rndloglogistic>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <rndlogistic@plt>
  movsd  D19(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L9
  movsd  D1(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L9:
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1060 <exp@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type_infered: byte[8]
name: parse_data
arguments: tag: D1
type_infered: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x89,0x40]}

tool: D1: 1e+300

assistant: ```c
double rndloglogistic(double loc, double s) {
  double t = rndlogistic(), logt = 1E300;
  if (t < 800)
    logt = exp(loc + s * t);
  return (logt);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rndloglogistic>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <rndlogistic@plt>
  movsd  D2(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L8
  movsd  D10(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L8:
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1060 <exp@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: byte[8]
name: parse_data
arguments: data_label: D10
type_guessed: f64

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x89,0x40]}

tool: D10: 1e+300

assistant: ```c
double rndloglogistic(double loc, double s) {
  double t = rndlogistic(), logt = 1E300;
  if (t < 800)
    logt = exp(loc + s * t);
  return (logt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *ptr;
  if (ptr = malloc(nmemb * size))
    memset(ptr, 0, nmemb * size);
  return (ptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *ptr;
  if (ptr = malloc(nmemb * size))
    memset(ptr, 0, nmemb * size);
  return (ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *ptr;
  if (ptr = malloc(nmemb * size))
    memset(ptr, 0, nmemb * size);
  return (ptr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *ptr;
  if (ptr = malloc(nmemb * size))
    memset(ptr, 0, nmemb * size);
  return (ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<store_jump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x18(%rbp),%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store_jump(char *from, char opcode, char *to) {
  from[0] = opcode;
  from[1] = (char)((to - (from + 3)) & 0377);
  from[2] = (char)((to - (from + 3)) >> 8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<store_jump>:
  endbr64
  mov    %sil,(%rdi)
  lea    0x3(%rdi),%rax
  sub    %rax,%rdx
  mov    %dl,0x1(%rdi)
  movzbl %dh,%eax
  mov    %al,0x2(%rdi)
  ret
```

assistant: ```c
void store_jump(char *from, char opcode, char *to) {
  from[0] = opcode;
  from[1] = (char)((to - (from + 3)) & 0377);
  from[2] = (char)((to - (from + 3)) >> 8);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<store_jump>:
  endbr64
  lea    0x3(%rdi),%rax
  mov    %sil,(%rdi)
  sub    %rax,%rdx
  mov    %dx,0x1(%rdi)
  ret
```

assistant: ```c
void store_jump(char *from, char opcode, char *to) {
  from[0] = opcode;
  from[1] = (char)((to - (from + 3)) & 0377);
  from[2] = (char)((to - (from + 3)) >> 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<store_jump>:
  endbr64
  lea    0x3(%rdi),%rax
  mov    %sil,(%rdi)
  sub    %rax,%rdx
  mov    %dx,0x1(%rdi)
  ret
```

assistant: ```c
void store_jump(char *from, char opcode, char *to) {
  from[0] = opcode;
  from[1] = (char)((to - (from + 3)) & 0377);
  from[2] = (char)((to - (from + 3)) >> 8);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<eat_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x20,-0x1(%rbp)
  je     L0
  cmpb   $0xa,-0x1(%rbp)
  je     L0
  movsbl -0x1(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  nop
  leave
  ret
```

assistant: ```c
void eat_space(FILE *fp) {
  char c;
  while ((c = getc(fp)) == ' ' || c == '\n')
    ;
  ungetc(c, fp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eat_space>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L12:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    $0xa,%al
  je     L12
  cmp    $0x20,%al
  je     L12
  movsbl %al,%edi
  mov    %rbx,%rsi
  call   <ungetc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void eat_space(FILE *fp) {
  char c;
  while ((c = getc(fp)) == ' ' || c == '\n')
    ;
  ungetc(c, fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eat_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%al
  je     L11
  cmp    $0x20,%al
  je     L11
  mov    %rbp,%rsi
  movsbl %al,%edi
  pop    %rbp
  jmp    1060 <ungetc@plt>
```

assistant: ```c
void eat_space(FILE *fp) {
  char c;
  while ((c = getc(fp)) == ' ' || c == '\n')
    ;
  ungetc(c, fp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<eat_space>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <getc@plt>
  cmp    $0xa,%al
  je     L2
  cmp    $0x20,%al
  je     L2
  mov    %rbp,%rsi
  movsbl %al,%edi
  pop    %rbp
  jmp    1060 <ungetc@plt>
```

assistant: ```c
void eat_space(FILE *fp) {
  char c;
  while ((c = getc(fp)) == ' ' || c == '\n')
    ;
  ungetc(c, fp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <memory_init@plt>
  mov    $0x0,%eax
  call   <register_init@plt>
  mov    $0x0,%eax
  call   <pipeline_init@plt>
L2:
  jmp    L2
```

assistant: ```c
int main() {
  memory_init();
  register_init();
  pipeline_init();
  while (1) {
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <memory_init@plt>
  mov    $0x0,%eax
  call   <register_init@plt>
  mov    $0x0,%eax
  call   <pipeline_init@plt>
L4:
  jmp    L4
```

assistant: ```c
int main() {
  memory_init();
  register_init();
  pipeline_init();
  while (1) {
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <memory_init@plt>
  xor    %eax,%eax
  call   <register_init@plt>
  xor    %eax,%eax
  call   <pipeline_init@plt>
L5:
  jmp    L5
```

assistant: ```c
int main() {
  memory_init();
  register_init();
  pipeline_init();
  while (1) {
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <memory_init@plt>
  xor    %eax,%eax
  call   <register_init@plt>
  xor    %eax,%eax
  call   <pipeline_init@plt>
L9:
  jmp    L9
```

assistant: ```c
int main() {
  memory_init();
  register_init();
  pipeline_init();
  while (1) {
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L29
L25:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L2:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L23:
  cmpl   $0x2,-0x14(%rbp)
  jle    L2
  addl   $0x1,-0x18(%rbp)
L29:
  cmpl   $0x6,-0x18(%rbp)
  jle    L25
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D27
type: string
name: parse_data
arguments: label: D11
type: string

tool: D7: dnanmax

tool: D27: # c::%s:len=%d


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanmax", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```