ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L26
  mov    %rsi,%r14
  movslq %edi,%rbx
  mov    $0x1,%r12d
L6:
  lea    0xf(%r12),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r13
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L34:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L34
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L36
  orq    $0x0,-0x8(%rsp,%rdx,1)
L36:
  mov    %r12d,%edx
  mov    %rsp,%rdi
  mov    %r14,%rsi
  add    $0x1,%r12
  call   <memcpy@plt>
  mov    %r13,%rsp
  cmp    %rbx,%r12
  jne    L6
L26:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bar(int a, char buffer[a]) {
  for (int i = 1; i < a; ++i) {
    char copy[i];
    memcpy(copy, buffer, i);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<shubert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L10:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <cos@plt>
  imul   -0x4(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <cos@plt>
  imul   -0x4(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x5,-0x4(%rbp)
  jle    L10
  movss  -0xc(%rbp),%xmm0
  mulss  -0x8(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_infered: f64

tool: D19: 1

assistant: ```c
float shubert(float x1, float x2) {
  float sum1 = 0.0;
  float sum2 = 0.0;
  int i;
  for (i = 1; i <= 5; i++) {
    sum1 += (i * cos((i + 1.0) * x1 + i));
    sum2 += (i * cos((i + 1.0) * x2 + i));
  }
  return sum1 * sum2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<shubert>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  movss  %xmm1,0x24(%rsp)
  mov    $0x1,%ebx
  pxor   %xmm6,%xmm6
  movss  %xmm6,0x20(%rsp)
  movss  %xmm6,0xc(%rsp)
  pxor   %xmm7,%xmm7
  cvtss2sd %xmm0,%xmm7
  movsd  %xmm7,0x28(%rsp)
L2:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  movsd  D9(%rip),%xmm3
  addsd  %xmm2,%xmm3
  movsd  0x28(%rsp),%xmm0
  movsd  %xmm3,0x18(%rsp)
  mulsd  %xmm3,%xmm0
  movsd  %xmm2,0x10(%rsp)
  addsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  imul   %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x24(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  imul   %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  0x20(%rsp),%xmm0
  movss  %xmm0,0x20(%rsp)
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L2
  movss  0xc(%rsp),%xmm0
  mulss  0x20(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: f64

tool: D9: 1

assistant: ```c
float shubert(float x1, float x2) {
  float sum1 = 0.0;
  float sum2 = 0.0;
  int i;
  for (i = 1; i <= 5; i++) {
    sum1 += (i * cos((i + 1.0) * x1 + i));
    sum2 += (i * cos((i + 1.0) * x2 + i));
  }
  return sum1 * sum2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shubert>:
  endbr64
  push   %rbx
  pxor   %xmm6,%xmm6
  pxor   %xmm3,%xmm3
  pxor   %xmm7,%xmm7
  cvtss2sd %xmm0,%xmm6
  cvtss2sd %xmm1,%xmm7
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  movsd  %xmm6,0x20(%rsp)
  movss  %xmm3,0x18(%rsp)
  movsd  %xmm7,0x28(%rsp)
L9:
  pxor   %xmm1,%xmm1
  movsd  D4(%rip),%xmm0
  movsd  0x20(%rsp),%xmm2
  movss  %xmm3,0x1c(%rsp)
  cvtsi2sd %ebx,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm0,%xmm2
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%edi
  call   <cos@plt>
  movsd  0x10(%rsp),%xmm0
  mulsd  0x28(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  imul   %ebx,%eax
  cvtsi2ss %eax,%xmm2
  addss  0x18(%rsp),%xmm2
  addsd  %xmm1,%xmm0
  movss  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm3
  imul   %ebx,%eax
  add    $0x1,%ebx
  cvtsi2ss %eax,%xmm0
  addss  %xmm0,%xmm3
  cmp    $0x6,%ebx
  jne    L9
  movss  0x18(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  mulss  %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: f64

tool: D4: 1

assistant: ```c
float shubert(float x1, float x2) {
  float sum1 = 0.0;
  float sum2 = 0.0;
  int i;
  for (i = 1; i <= 5; i++) {
    sum1 += (i * cos((i + 1.0) * x1 + i));
    sum2 += (i * cos((i + 1.0) * x2 + i));
  }
  return sum1 * sum2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shubert>:
  endbr64
  push   %rbx
  pxor   %xmm6,%xmm6
  pxor   %xmm3,%xmm3
  pxor   %xmm7,%xmm7
  cvtss2sd %xmm0,%xmm6
  cvtss2sd %xmm1,%xmm7
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  movsd  %xmm6,0x20(%rsp)
  movss  %xmm3,0x18(%rsp)
  movsd  %xmm7,0x28(%rsp)
L4:
  pxor   %xmm1,%xmm1
  movsd  D3(%rip),%xmm0
  movsd  0x20(%rsp),%xmm2
  movss  %xmm3,0x1c(%rsp)
  cvtsi2sd %ebx,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm0,%xmm2
  movsd  %xmm0,0x10(%rsp)
  addsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%edi
  call   <cos@plt>
  movsd  0x10(%rsp),%xmm0
  mulsd  0x28(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  imul   %ebx,%eax
  cvtsi2ss %eax,%xmm2
  addss  0x18(%rsp),%xmm2
  addsd  %xmm1,%xmm0
  movss  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm3
  imul   %ebx,%eax
  add    $0x1,%ebx
  cvtsi2ss %eax,%xmm0
  addss  %xmm0,%xmm3
  cmp    $0x6,%ebx
  jne    L4
  movss  0x18(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  mulss  %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: f64

tool: D3: 1

assistant: ```c
float shubert(float x1, float x2) {
  float sum1 = 0.0;
  float sum2 = 0.0;
  int i;
  for (i = 1; i <= 5; i++) {
    sum1 += (i * cos((i + 1.0) * x1 + i));
    sum2 += (i * cos((i + 1.0) * x2 + i));
  }
  return sum1 * sum2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_quick_rec_median>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r10d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%ecx
  sub    %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
  cltq
  mov    (%rdi,%rax,4),%eax
  movslq %r12d,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %eax,%ecx
  jge    L113
  cmp    %edx,%ecx
  cmovle %eax,%ecx
L144:
  mov    %r12d,%edx
  mov    %r10d,%ebx
  jmp    L154
L113:
  cmp    %edx,%eax
  cmovg  %edx,%ecx
  jmp    L144
L95:
  mov    %edi,(%r8)
  mov    %esi,(%r9)
  add    $0x1,%ebx
  sub    $0x1,%edx
  jmp    L154
L69:
  cmp    %r10d,%edx
  jg     L23
L47:
  cmp    %r12d,%ebx
  jl     L143
L139:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    %r10d,%esi
  mov    %rbp,%rdi
  call   <_quick_rec_median>
  jmp    L47
L143:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <_quick_rec_median>
  jmp    L139
L85:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %edi,%ecx
  jge    L95
L98:
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
L3:
  sub    $0x1,%edx
  mov    %rax,%r9
  sub    $0x4,%rax
  mov    0x4(%rax),%edi
  cmp    %ecx,%edi
  jg     L3
L61:
  cmp    %ebx,%edx
  jge    L95
L154:
  cmp    %edx,%ebx
  jg     L69
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%r8
  mov    (%r8),%esi
  lea    0x4(%rbp,%rax,1),%rax
  cmp    %esi,%ecx
  jle    L85
L107:
  add    $0x1,%ebx
  mov    %rax,%r8
  add    $0x4,%rax
  mov    -0x4(%rax),%esi
  cmp    %ecx,%esi
  jl     L107
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%r9
  mov    (%r9),%edi
  cmp    %edi,%ecx
  jl     L98
  jmp    L61
```

assistant: ```c
void _quick_rec_median(int *vet, int begin, int end) {
  int i = begin, j = end;
  int tmp;
  int a = vet[begin], b = vet[begin + (end - begin) / 2], c = vet[end];
  int pivot = a < b ? (a > c ? a : b) : (b > c ? c : a);
  while (i <= j) {
    while (vet[i] < pivot)
      i++;
    while (vet[j] > pivot)
      j--;
    if (i <= j) {
      tmp = vet[i];
      vet[i] = vet[j];
      vet[j] = tmp;
      i++;
      j--;
    }
  }
  if (begin < j) {
    _quick_rec_median(vet, begin, j);
  }
  if (i < end) {
    _quick_rec_median(vet, i, end);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_quick_rec_median>:
  endbr64
  push   %r13
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %esi,%r10d
  push   %r12
  lea    (%rdi,%rax,4),%r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  sub    $0x8,%rsp
L49:
  mov    %ebp,%edx
  movslq %r10d,%rax
  sub    %r10d,%edx
  mov    0x0(%r13,%rax,4),%ecx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    (%r12),%edx
  sar    %eax
  add    %r10d,%eax
  cltq
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,%ecx
  jge    L99
  cmp    %edx,%ecx
  cmovle %eax,%ecx
L147:
  mov    %ebp,%edx
  mov    %r10d,%ebx
  nopl   0x0(%rax)
L113:
  cmp    %edx,%ebx
  jg     L93
L142:
  movslq %ebx,%rax
  movslq %edx,%r11
  shl    $0x2,%rax
  lea    0x0(%r13,%r11,4),%r9
  lea    0x0(%r13,%rax,1),%rsi
  mov    (%r9),%r8d
  lea    0x4(%r13,%rax,1),%rax
  mov    (%rsi),%edi
  cmp    %edi,%ecx
  jle    L12
  xchg   %ax,%ax
L116:
  mov    %rax,%rsi
  mov    (%rax),%edi
  lea    0x4(%rax),%rax
  add    $0x1,%ebx
  cmp    %ecx,%edi
  jl     L116
  cmp    %r8d,%ecx
  jge    L16
L110:
  lea    -0x4(%r13,%r11,4),%rax
  nopw   0x0(%rax,%rax,1)
L109:
  mov    %rax,%r9
  mov    (%rax),%r8d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %ecx,%r8d
  jg     L109
L16:
  cmp    %ebx,%edx
  jl     L113
  mov    %r8d,(%rsi)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %edi,(%r9)
L78:
  cmp    %edx,%ebx
  jle    L142
L93:
  cmp    %r10d,%edx
  jg     L1
L9:
  cmp    %ebp,%ebx
  jge    L84
  mov    %ebx,%r10d
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    %r8d,%ecx
  jl     L110
  mov    %r8d,(%rsi)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %edi,(%r9)
  jmp    L78
L99:
  cmp    %edx,%eax
  cmovg  %edx,%ecx
  jmp    L147
L84:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %r10d,%esi
  mov    %r13,%rdi
  call   <_quick_rec_median>
  jmp    L9
```

assistant: ```c
void _quick_rec_median(int *vet, int begin, int end) {
  int i = begin, j = end;
  int tmp;
  int a = vet[begin], b = vet[begin + (end - begin) / 2], c = vet[end];
  int pivot = a < b ? (a > c ? a : b) : (b > c ? c : a);
  while (i <= j) {
    while (vet[i] < pivot)
      i++;
    while (vet[j] > pivot)
      j--;
    if (i <= j) {
      tmp = vet[i];
      vet[i] = vet[j];
      vet[j] = tmp;
      i++;
      j--;
    }
  }
  if (begin < j) {
    _quick_rec_median(vet, begin, j);
  }
  if (i < end) {
    _quick_rec_median(vet, i, end);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_quick_rec_median>:
  endbr64
  push   %r13
  movslq %edx,%rax
  mov    %rdi,%r13
  mov    %esi,%r10d
  push   %r12
  lea    (%rdi,%rax,4),%r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  sub    $0x8,%rsp
L94:
  mov    %ebp,%edx
  movslq %r10d,%rax
  sub    %r10d,%edx
  mov    0x0(%r13,%rax,4),%ecx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    (%r12),%edx
  sar    %eax
  add    %r10d,%eax
  cltq
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,%ecx
  jge    L109
  cmp    %edx,%ecx
  cmovle %eax,%ecx
L101:
  mov    %ebp,%edx
  mov    %r10d,%ebx
  nopl   0x0(%rax)
L27:
  cmp    %edx,%ebx
  jg     L135
L8:
  movslq %ebx,%rax
  movslq %edx,%r11
  shl    $0x2,%rax
  lea    0x0(%r13,%r11,4),%r9
  lea    0x0(%r13,%rax,1),%rsi
  mov    (%r9),%r8d
  lea    0x4(%r13,%rax,1),%rax
  mov    (%rsi),%edi
  cmp    %edi,%ecx
  jle    L118
  xchg   %ax,%ax
L105:
  mov    %rax,%rsi
  mov    (%rax),%edi
  lea    0x4(%rax),%rax
  add    $0x1,%ebx
  cmp    %ecx,%edi
  jl     L105
  cmp    %r8d,%ecx
  jge    L72
L4:
  lea    -0x4(%r13,%r11,4),%rax
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rax,%r9
  mov    (%rax),%r8d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %ecx,%r8d
  jg     L15
L72:
  cmp    %ebx,%edx
  jl     L27
  mov    %r8d,(%rsi)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %edi,(%r9)
L82:
  cmp    %edx,%ebx
  jle    L8
L135:
  cmp    %r10d,%edx
  jg     L136
L148:
  cmp    %ebp,%ebx
  jge    L44
  mov    %ebx,%r10d
  jmp    L94
  nopw   0x0(%rax,%rax,1)
L118:
  cmp    %r8d,%ecx
  jl     L4
  mov    %r8d,(%rsi)
  add    $0x1,%ebx
  sub    $0x1,%edx
  mov    %edi,(%r9)
  jmp    L82
L109:
  cmp    %edx,%eax
  cmovg  %edx,%ecx
  jmp    L101
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L136:
  mov    %r10d,%esi
  mov    %r13,%rdi
  call   <_quick_rec_median>
  jmp    L148
```

assistant: ```c
void _quick_rec_median(int *vet, int begin, int end) {
  int i = begin, j = end;
  int tmp;
  int a = vet[begin], b = vet[begin + (end - begin) / 2], c = vet[end];
  int pivot = a < b ? (a > c ? a : b) : (b > c ? c : a);
  while (i <= j) {
    while (vet[i] < pivot)
      i++;
    while (vet[j] > pivot)
      j--;
    if (i <= j) {
      tmp = vet[i];
      vet[i] = vet[j];
      vet[j] = tmp;
      i++;
      j--;
    }
  }
  if (begin < j) {
    _quick_rec_median(vet, begin, j);
  }
  if (i < end) {
    _quick_rec_median(vet, i, end);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strv_push_prepend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L77
L50:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strv_length@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jae    L73
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L77
L73:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x8,%edi
  call   <malloc_multiply@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L77
L35:
  movl   $0x0,-0x14(%rbp)
  jmp    L33
L3:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,%edx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jb     L3
  mov    -0x8(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L77:
  leave
  ret
```

assistant: ```c
int strv_push_prepend(char ***l, char *value) {
  char **c;
  unsigned n, m, i;
  if (!value)
    return 0;
  n = strv_length(*l);
  m = n + 2;
  if (m < n)
    return -ENOMEM;
  c = ((char **)malloc_multiply(sizeof(char *), (m)));
  if (!c)
    return -ENOMEM;
  for (i = 0; i < n; i++)
    c[i + 1] = (*l)[i];
  c[0] = value;
  c[n + 1] = NULL;
  free(*l);
  *l = c;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strv_push_prepend>:
  endbr64
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L38
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%rdi
  call   <strv_length@plt>
  mov    %eax,%r12d
  lea    0x2(%rax),%esi
  cmp    $0xfffffffe,%eax
  jb     L67
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  mov    $0x8,%edi
  call   <malloc_multiply@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L13
  mov    %r12d,%ecx
  shl    $0x3,%rcx
  mov    $0x0,%eax
  test   %r12d,%r12d
  je     L33
L27:
  mov    (%rbx),%rdx
  mov    (%rdx,%rax,1),%rdx
  mov    %rdx,0x8(%r13,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L27
L33:
  mov    %rbp,0x0(%r13)
  lea    0x1(%r12),%eax
  movq   $0x0,0x0(%r13,%rax,8)
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %r13,(%rbx)
  mov    $0x0,%eax
  jmp    L41
L13:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L41
L38:
  ret
```

assistant: ```c
int strv_push_prepend(char ***l, char *value) {
  char **c;
  unsigned n, m, i;
  if (!value)
    return 0;
  n = strv_length(*l);
  m = n + 2;
  if (m < n)
    return -ENOMEM;
  c = ((char **)malloc_multiply(sizeof(char *), (m)));
  if (!c)
    return -ENOMEM;
  for (i = 0; i < n; i++)
    c[i + 1] = (*l)[i];
  c[0] = value;
  c[n + 1] = NULL;
  free(*l);
  *l = c;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strv_push_prepend>:
  endbr64
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L19
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <strv_length@plt>
  mov    %eax,%esi
  mov    %eax,%ebx
  add    $0x2,%esi
  jb     L44
  mov    $0x8,%edi
  call   <malloc_multiply@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L44
  mov    (%r12),%rdi
  test   %ebx,%ebx
  je     L22
  lea    0x8(%rax),%rdx
  mov    %rdi,%rcx
  lea    -0x1(%rbx),%eax
  lea    0x10(%r13,%rax,8),%rsi
  sub    %r13,%rcx
  nopl   0x0(%rax)
L1:
  mov    -0x8(%rcx,%rdx,1),%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rsi,%rdx
  jne    L1
L22:
  lea    0x1(%rbx),%eax
  mov    %rbp,0x0(%r13)
  movq   $0x0,0x0(%r13,%rax,8)
  call   <free@plt>
  mov    %r13,(%r12)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
  nopl   0x0(%rax)
L44:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strv_push_prepend(char ***l, char *value) {
  char **c;
  unsigned n, m, i;
  if (!value)
    return 0;
  n = strv_length(*l);
  m = n + 2;
  if (m < n)
    return -ENOMEM;
  c = ((char **)malloc_multiply(sizeof(char *), (m)));
  if (!c)
    return -ENOMEM;
  for (i = 0; i < n; i++)
    c[i + 1] = (*l)[i];
  c[0] = value;
  c[n + 1] = NULL;
  free(*l);
  *l = c;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strv_push_prepend>:
  endbr64
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L6
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <strv_length@plt>
  mov    %eax,%esi
  mov    %eax,%ebx
  add    $0x2,%esi
  jb     L37
  mov    $0x8,%edi
  call   <malloc_multiply@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
  mov    0x0(%r13),%rdi
  test   %ebx,%ebx
  je     L5
  lea    0x8(%rax),%rdx
  lea    0x8(%rdi),%rsi
  lea    -0x1(%rbx),%ecx
  mov    %rdx,%rax
  cmp    %rsi,%rdx
  je     L13
  cmp    $0x2,%ecx
  jbe    L13
  mov    %ebx,%edx
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%rbp,%rdx,1),%rcx
  mov    %rdi,%rdx
  sub    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L19:
  movdqu -0x8(%rax,%rdx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L19
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bl
  je     L5
  mov    %eax,%edx
  add    $0x1,%eax
  mov    (%rdi,%rdx,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
L5:
  lea    0x1(%rbx),%eax
  mov    %r12,0x0(%rbp)
  movq   $0x0,0x0(%rbp,%rax,8)
  call   <free@plt>
  mov    %rbp,0x0(%r13)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  ret
  nopl   0x0(%rax)
L37:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  lea    0x10(%rbp,%rcx,8),%rsi
  mov    %rdi,%rcx
  sub    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    -0x8(%rcx,%rdx,1),%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rdx,%rsi
  jne    L14
  jmp    L5
```

assistant: ```c
int strv_push_prepend(char ***l, char *value) {
  char **c;
  unsigned n, m, i;
  if (!value)
    return 0;
  n = strv_length(*l);
  m = n + 2;
  if (m < n)
    return -ENOMEM;
  c = ((char **)malloc_multiply(sizeof(char *), (m)));
  if (!c)
    return -ENOMEM;
  for (i = 0; i < n; i++)
    c[i + 1] = (*l)[i];
  c[0] = value;
  c[n + 1] = NULL;
  free(*l);
  *l = c;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L9
L4:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x14(%rbp),%edi
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  imul   %eax,%esi
  mov    %esi,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L4
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D13
data_type: string

tool: D21: %d

tool: D13: %d


assistant: ```c
int main() {
  int n, m, k, sell = 0, i = 0;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  for (; i < n; i++) {
    sell = sell + m - (i / k * (2 * m / 100));
  }
  printf("%d\n", sell);
  return 0;
}
```