ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <sum@plt>
  mov    $0xa,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <print2@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D0: size of integer is %lu 


tool: D18: print x in main :%d 


assistant: ```c
void main() {
  printf("size of integer is %lu \n", sizeof(int));
  int x = 10;
  int y = 20;
  int result;
  result = sum(x, y);
  printf("print x in main :%d \n", x);
  result = print();
  print2();
}
```
user: Translate the below assembly code into C programming language:

```asm
<xhypot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movq   D13(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movq   D13(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L40
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L20
L40:
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L20:
  pxor   %xmm0,%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jp     L48
  pxor   %xmm0,%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jne    L48
  movsd  -0x20(%rbp),%xmm0
  jmp    L18
L48:
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D11(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x20(%rbp),%xmm0
L18:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
data_type: qword
name: read_data
arguments: data_tag: D11
data_type: byte[8]

tool: D13: 9223372036854775807

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double xhypot(const double x, const double y) {
  double xabs = fabs(x);
  double yabs = fabs(y);
  double min, max;
  if (xabs < yabs) {
    min = xabs;
    max = yabs;
  } else {
    min = yabs;
    max = xabs;
  }
  if (min == 0) {
    return max;
  }
  {
    double u = min / max;
    return max * sqrt(1 + u * u);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xhypot>:
  endbr64
  push   %rbx
  movq   D12(%rip),%xmm2
  andpd  %xmm2,%xmm0
  andpd  %xmm2,%xmm1
  movq   %xmm1,%rbx
  comisd %xmm0,%xmm1
  ja     L17
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  mov    %rax,%rbx
L17:
  ucomisd D1(%rip),%xmm0
  jp     L35
  jne    L35
L34:
  movq   %rbx,%xmm0
  pop    %rbx
  ret
L35:
  movq   %rbx,%xmm5
  divsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movq   %rbx,%xmm4
  mulsd  %xmm0,%xmm4
  movq   %xmm4,%rbx
  jmp    L34
```

tool_calls: name: retrieve_data
arguments: tag: D12
data_type: qword
name: retrieve_data
arguments: tag: D1
data_type: byte[8]
name: retrieve_data
arguments: tag: D6
data_type: byte[8]

tool: D12: 9223372036854775807

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double xhypot(const double x, const double y) {
  double xabs = fabs(x);
  double yabs = fabs(y);
  double min, max;
  if (xabs < yabs) {
    min = xabs;
    max = yabs;
  } else {
    min = yabs;
    max = xabs;
  }
  if (min == 0) {
    return max;
  }
  {
    double u = min / max;
    return max * sqrt(1 + u * u);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xhypot>:
  endbr64
  movq   D23(%rip),%xmm2
  andpd  %xmm2,%xmm0
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  ja     L2
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L2:
  ucomisd D11(%rip),%xmm0
  jp     L8
  jne    L8
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L8:
  divsd  %xmm1,%xmm0
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm0,%xmm0
  addsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
type_infered: qword
name: disassemble_data
arguments: label: D11
type_infered: byte[8]
name: disassemble_data
arguments: label: D2
type_infered: byte[8]

tool: D23: 9223372036854775807

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double xhypot(const double x, const double y) {
  double xabs = fabs(x);
  double yabs = fabs(y);
  double min, max;
  if (xabs < yabs) {
    min = xabs;
    max = yabs;
  } else {
    min = yabs;
    max = xabs;
  }
  if (min == 0) {
    return max;
  }
  {
    double u = min / max;
    return max * sqrt(1 + u * u);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xhypot>:
  endbr64
  movq   D19(%rip),%xmm2
  andpd  %xmm2,%xmm0
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  ja     L24
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L24:
  ucomisd D28(%rip),%xmm0
  jp     L25
  jne    L25
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L25:
  divsd  %xmm1,%xmm0
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm0,%xmm0
  addsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type: qword
name: parse_data
arguments: data_label: D28
type: byte[8]
name: parse_data
arguments: data_label: D17
type: byte[8]

tool: D19: 9223372036854775807

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double xhypot(const double x, const double y) {
  double xabs = fabs(x);
  double yabs = fabs(y);
  double min, max;
  if (xabs < yabs) {
    min = xabs;
    max = yabs;
  } else {
    min = yabs;
    max = xabs;
  }
  if (min == 0) {
    return max;
  }
  {
    double u = min / max;
    return max * sqrt(1 + u * u);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D46
type_infered: string
name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D45
type_infered: string
name: disassemble_data
arguments: label: D62
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D28
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string

tool: D46: Enter 3 Int: 

tool: D0: %d %d %d

tool: D45: 1: %d 

tool: D62: %d 

tool: D19: %d


tool: D28: 2: %d %d %d 


tool: D16: 3: Is it even Possible????

assistant: ```c
int main() {
  int a, b, c;
  printf("Enter 3 Int: ");
  scanf("%d %d %d", &a, &b, &c);
  printf("1: %d ", a);
  printf("%d ", b);
  printf("%d\n", c);
  printf("2: %d %d %d \n", a, b, c);
  printf("3: Is it even Possible????\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D35
type_infered: string
name: read_data
arguments: tag: D65
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D19
type_infered: string

tool: D35: Enter 3 Int: 

tool: D65: %d %d %d

tool: D25: 1: %d 

tool: D14: %d 

tool: D8: %d


tool: D17: 2: %d %d %d 


tool: D19: 3: Is it even Possible????

assistant: ```c
int main() {
  int a, b, c;
  printf("Enter 3 Int: ");
  scanf("%d %d %d", &a, &b, &c);
  printf("1: %d ", a);
  printf("%d ", b);
  printf("%d\n", c);
  printf("2: %d %d %d \n", a, b, c);
  printf("3: Is it even Possible????\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D59
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D58
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D11
type_guessed: string

tool: D23: Enter 3 Int: 

tool: D59: %d %d %d

tool: D13: 1: %d 

tool: D0: %d 

tool: D58: %d


tool: D33: 2: %d %d %d 


tool: D11: 3: Is it even Possible????

assistant: ```c
int main() {
  int a, b, c;
  printf("Enter 3 Int: ");
  scanf("%d %d %d", &a, &b, &c);
  printf("1: %d ", a);
  printf("%d ", b);
  printf("%d\n", c);
  printf("2: %d %d %d \n", a, b, c);
  printf("3: Is it even Possible????\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D40(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0xc(%rsp),%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
type_guessed: string
name: retrieve_data
arguments: data_label: D50
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D40: Enter 3 Int: 

tool: D50: %d %d %d

tool: D15: 1: %d 

tool: D4: %d 

tool: D36: %d


tool: D39: 2: %d %d %d 


tool: D8: 3: Is it even Possible????

assistant: ```c
int main() {
  int a, b, c;
  printf("Enter 3 Int: ");
  scanf("%d %d %d", &a, &b, &c);
  printf("1: %d ", a);
  printf("%d ", b);
  printf("%d\n", c);
  printf("2: %d %d %d \n", a, b, c);
  printf("3: Is it even Possible????\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <matexp_scale_factor@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L20
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <matexp_pade@plt>
  jmp    L13
L20:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x10(%rbp),%rsi
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <dscal_@plt>
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <matexp_pade@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <matcopy@plt>
  mov    -0x38(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <matpow_by_squaring@plt>
L13:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: f64

tool: D9: 1

assistant: ```c
void matexp(int n, const int p, double *x, double *ret) {
  int m;
  int nn = n * n;
  int one = 1;
  double tmp;
  m = matexp_scale_factor(x, n);
  if (m == 0)
    matexp_pade(n, p, x, ret);
  else {
    tmp = 1. / ((double)m);
    dscal_(&nn, &tmp, x, &one);
    matexp_pade(n, p, x, ret);
    matcopy(n, ret, x);
    matpow_by_squaring(x, n, m, ret);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matexp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   %edi,%eax
  mov    %eax,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  mov    %edi,%esi
  mov    %rdx,%rdi
  call   <matexp_scale_factor@plt>
  test   %eax,%eax
  jne    L2
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <matexp_pade@plt>
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    %eax,%r12d
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  call   <dscal_@plt>
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <matexp_pade@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <matcopy@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <matpow_by_squaring@plt>
  jmp    L11
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: f64

tool: D1: 1

assistant: ```c
void matexp(int n, const int p, double *x, double *ret) {
  int m;
  int nn = n * n;
  int one = 1;
  double tmp;
  m = matexp_scale_factor(x, n);
  if (m == 0)
    matexp_pade(n, p, x, ret);
  else {
    tmp = 1. / ((double)m);
    dscal_(&nn, &tmp, x, &one);
    matexp_pade(n, p, x, ret);
    matcopy(n, ret, x);
    matpow_by_squaring(x, n, m, ret);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matexp>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  mov    %edi,%esi
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %edi,%eax
  movl   $0x1,0xc(%rsp)
  imul   %edi,%eax
  mov    %rdx,%rdi
  mov    %eax,0x8(%rsp)
  call   <matexp_scale_factor@plt>
  test   %eax,%eax
  jne    L4
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <matexp_pade@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  pxor   %xmm1,%xmm1
  lea    0xc(%rsp),%rcx
  mov    %r12,%rdx
  mov    %eax,%r13d
  cvtsi2sd %eax,%xmm1
  movsd  D4(%rip),%xmm0
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <dscal_@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <matexp_pade@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <matcopy@plt>
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <matpow_by_squaring@plt>
  jmp    L8
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
void matexp(int n, const int p, double *x, double *ret) {
  int m;
  int nn = n * n;
  int one = 1;
  double tmp;
  m = matexp_scale_factor(x, n);
  if (m == 0)
    matexp_pade(n, p, x, ret);
  else {
    tmp = 1. / ((double)m);
    dscal_(&nn, &tmp, x, &one);
    matexp_pade(n, p, x, ret);
    matcopy(n, ret, x);
    matpow_by_squaring(x, n, m, ret);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matexp>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  mov    %edi,%esi
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %edi,%eax
  movl   $0x1,0xc(%rsp)
  imul   %edi,%eax
  mov    %rdx,%rdi
  mov    %eax,0x8(%rsp)
  call   <matexp_scale_factor@plt>
  test   %eax,%eax
  jne    L13
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <matexp_pade@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  pxor   %xmm1,%xmm1
  lea    0xc(%rsp),%rcx
  mov    %r12,%rdx
  mov    %eax,%r13d
  cvtsi2sd %eax,%xmm1
  movsd  D4(%rip),%xmm0
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  call   <dscal_@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <matexp_pade@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <matcopy@plt>
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <matpow_by_squaring@plt>
  jmp    L17
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: f64

tool: D4: 1

assistant: ```c
void matexp(int n, const int p, double *x, double *ret) {
  int m;
  int nn = n * n;
  int one = 1;
  double tmp;
  m = matexp_scale_factor(x, n);
  if (m == 0)
    matexp_pade(n, p, x, ret);
  else {
    tmp = 1. / ((double)m);
    dscal_(&nn, &tmp, x, &one);
    matexp_pade(n, p, x, ret);
    matcopy(n, ret, x);
    matpow_by_squaring(x, n, m, ret);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x8000,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L10
L31:
  mov    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L23
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L10:
  cmpl   $0x0,-0x14(%rbp)
  jg     L31
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D32
data_type: string

tool: D10: Please enter two integers: 

tool: D2: %d %d

tool: D19: The following bits are the same
: 

tool: D32: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  printf("Please enter two integers: ");
  int i1, i2;
  scanf("%d %d", &i1, &i2);
  int orEd = (i1 ^ i2);
  printf("The following bits are the same\n: ");
  for (int i = 32768, j = 1; i > 0; i /= 2, j++) {
    if (!(orEd & i)) {
      printf("%d ", j);
    }
  }
  putchar('\n');
}
```