ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<funcAngDist_alpha1_3minus_2plus_15097_L1_L3_L5>:
  endbr64
  push   %rbx
  mov    (%rsi),%rbx
  movsd  (%rdi),%xmm0
  call   <EvalAngDist_alpha1_3minus_2plus_15097_L1_L3_L5@plt>
  movq   %rbx,%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double funcAngDist_alpha1_3minus_2plus_15097_L1_L3_L5(double *x, double *par) {
  double result;
  result = par[0] * EvalAngDist_alpha1_3minus_2plus_15097_L1_L3_L5(x[0]);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<funcAngDist_alpha1_3minus_2plus_15097_L1_L3_L5>:
  endbr64
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rdi),%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <EvalAngDist_alpha1_3minus_2plus_15097_L1_L3_L5@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double funcAngDist_alpha1_3minus_2plus_15097_L1_L3_L5(double *x, double *par) {
  double result;
  result = par[0] * EvalAngDist_alpha1_3minus_2plus_15097_L1_L3_L5(x[0]);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L6:
  mov    $0x0,%eax
  call   <prompt@plt>
  movl   $0x0,-0x21c(%rbp)
  jmp    L39
L19:
  mov    -0x21c(%rbp),%eax
  cltq
  movb   $0x0,-0x210(%rbp,%rax,1)
  addl   $0x1,-0x21c(%rbp)
L39:
  cmpl   $0x1ff,-0x21c(%rbp)
  jle    L19
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  lea    -0x210(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    %rax,-0x218(%rbp)
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <process_command@plt>
  test   %rax,%rax
  jne    L2
  jmp    L6
L2:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void interact() {
  int i;
  char buf[512];
  char *cmd;
  while (1) {
    prompt();
    for (i = 0; i < 512; i++)
      buf[i] = '\0';
    fgets(buf, 512, stdin);
    cmd = trim(buf);
    if (process_command(cmd))
      return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<interact>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    0x200(%rsp),%rbx
L9:
  mov    $0x0,%eax
  call   <prompt@plt>
  mov    %rsp,%rax
L6:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L6
  mov    %rsp,%rbp
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <trim@plt>
  mov    %rax,%rdi
  call   <process_command@plt>
  test   %rax,%rax
  je     L9
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interact() {
  int i;
  char buf[512];
  char *cmd;
  while (1) {
    prompt();
    for (i = 0; i < 512; i++)
      buf[i] = '\0';
    fgets(buf, 512, stdin);
    cmd = trim(buf);
    if (process_command(cmd))
      return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<interact>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x210,%rsp
  mov    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L2:
  xor    %eax,%eax
  call   <prompt@plt>
  mov    %rbx,%rax
  mov    $0x40,%ecx
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    (%r12),%edx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <trim@plt>
  mov    %rax,%rdi
  call   <process_command@plt>
  test   %rax,%rax
  je     L2
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interact() {
  int i;
  char buf[512];
  char *cmd;
  while (1) {
    prompt();
    for (i = 0; i < 512; i++)
      buf[i] = '\0';
    fgets(buf, 512, stdin);
    cmd = trim(buf);
    if (process_command(cmd))
      return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<interact>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x210,%rsp
  mov    D5(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L3:
  xor    %eax,%eax
  call   <prompt@plt>
  mov    %rbx,%rax
  mov    $0x40,%ecx
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  mov    (%r12),%edx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <trim@plt>
  mov    %rax,%rdi
  call   <process_command@plt>
  test   %rax,%rax
  je     L3
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void interact() {
  int i;
  char buf[512];
  char *cmd;
  while (1) {
    prompt();
    for (i = 0; i < 512; i++)
      buf[i] = '\0';
    fgets(buf, 512, stdin);
    cmd = trim(buf);
    if (process_command(cmd))
      return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_MPI_safeFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void _MPI_safeFree(void *buffer, char *message) {
  ;
  if (buffer)
    free(buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_MPI_safeFree>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
void _MPI_safeFree(void *buffer, char *message) {
  ;
  if (buffer)
    free(buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_MPI_safeFree>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L5:
  ret
```

assistant: ```c
void _MPI_safeFree(void *buffer, char *message) {
  ;
  if (buffer)
    free(buffer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_MPI_safeFree>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void _MPI_safeFree(void *buffer, char *message) {
  ;
  if (buffer)
    free(buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<count_tokens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0x5c(%rbp)
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x58(%rbp)
  jmp    L17
L2:
  mov    -0x70(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x58(%rbp)
  addl   $0x1,-0x5c(%rbp)
L17:
  cmpq   $0x0,-0x58(%rbp)
  jne    L2
  mov    -0x5c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int count_tokens(const char *text, const char *tokens) {
  char _text[64];
  strcpy(_text, text);
  int count = 0;
  char *pch = strtok(_text, tokens);
  while (pch != NULL) {
    pch = strtok(NULL, tokens);
    count++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count_tokens>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%ebx
L17:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x1,%ebx
  test   %rax,%rax
  jne    L17
L15:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %ebx,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%ebx
  jmp    L15
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_tokens(const char *text, const char *tokens) {
  char _text[64];
  strcpy(_text, text);
  int count = 0;
  char *pch = strtok(_text, tokens);
  while (pch != NULL) {
    pch = strtok(NULL, tokens);
    count++;
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<count_tokens>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %rbx,%rsi
  xor    %r12d,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  je     L23
  nop
L21:
  mov    %rbx,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  jne    L21
L23:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_tokens(const char *text, const char *tokens) {
  char _text[64];
  strcpy(_text, text);
  int count = 0;
  char *pch = strtok(_text, tokens);
  while (pch != NULL) {
    pch = strtok(NULL, tokens);
    count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_tokens>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %rbx,%rsi
  xor    %r12d,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  je     L0
  nop
L26:
  mov    %rbx,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  jne    L26
L0:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_tokens(const char *text, const char *tokens) {
  char _text[64];
  strcpy(_text, text);
  int count = 0;
  char *pch = strtok(_text, tokens);
  while (pch != NULL) {
    pch = strtok(NULL, tokens);
    count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jbe    L0
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    -0x30(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L13:
  mov    -0x2c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L13
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Error: Substring (%s, %d, %d) will read beyond string boundary %d.


assistant: ```c
char *substr(S, pos, len)
char *S;
int pos, len;
{
  int i;
  char *SubS;
  SubS = malloc(len + 1);
  if ((pos + len) > strlen(S)) {
    printf("Error: Substring (%s, %d, %d) will read beyond string boundary %d.\n", S, pos, len, strlen(S));
    exit(1);
  }
  for (i = 0; i < len; i++)
    SubS[i] = S[pos + i];
  SubS[len] = '\0';
  return SubS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<substr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    0x1(%rdx),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%edx
  movslq %edx,%rdx
  cmp    %rax,%rdx
  ja     L12
  mov    %r12d,%esi
  mov    $0x0,%eax
  movslq %ebx,%rcx
  add    %r13,%rcx
  test   %r12d,%r12d
  jle    L24
L9:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L9
L24:
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %rax,%r8
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: Error: Substring (%s, %d, %d) will read beyond string boundary %d.


assistant: ```c
char *substr(S, pos, len)
char *S;
int pos, len;
{
  int i;
  char *SubS;
  SubS = malloc(len + 1);
  if ((pos + len) > strlen(S)) {
    printf("Error: Substring (%s, %d, %d) will read beyond string boundary %d.\n", S, pos, len, strlen(S));
    exit(1);
  }
  for (i = 0; i < len; i++)
    SubS[i] = S[pos + i];
  SubS[len] = '\0';
  return SubS;
}
```
user: What is the c source code of the assembly code below?

```asm
<substr>:
  endbr64
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%r12),%edi
  movslq %edi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  lea    (%r12,%r13,1),%edx
  movslq %edx,%rdx
  cmp    %rax,%rdx
  ja     L17
  test   %r12d,%r12d
  jle    L19
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <memcpy@plt>
L19:
  movb   $0x0,(%r14,%r12,1)
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %rax,%r8
  lea    D1(%rip),%rdi
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: Error: Substring (%s, %d, %d) will read beyond string boundary %d.


assistant: ```c
char *substr(S, pos, len)
char *S;
int pos, len;
{
  int i;
  char *SubS;
  SubS = malloc(len + 1);
  if ((pos + len) > strlen(S)) {
    printf("Error: Substring (%s, %d, %d) will read beyond string boundary %d.\n", S, pos, len, strlen(S));
    exit(1);
  }
  for (i = 0; i < len; i++)
    SubS[i] = S[pos + i];
  SubS[len] = '\0';
  return SubS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substr>:
  endbr64
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%r12),%edi
  movslq %edi,%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  lea    (%r12,%r13,1),%edx
  movslq %edx,%rdx
  cmp    %rax,%rdx
  ja     L16
  test   %r12d,%r12d
  jle    L15
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <memcpy@plt>
L15:
  movb   $0x0,(%r14,%r12,1)
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    %rax,%r8
  lea    D1(%rip),%rdi
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Error: Substring (%s, %d, %d) will read beyond string boundary %d.


assistant: ```c
char *substr(S, pos, len)
char *S;
int pos, len;
{
  int i;
  char *SubS;
  SubS = malloc(len + 1);
  if ((pos + len) > strlen(S)) {
    printf("Error: Substring (%s, %d, %d) will read beyond string boundary %d.\n", S, pos, len, strlen(S));
    exit(1);
  }
  for (i = 0; i < len; i++)
    SubS[i] = S[pos + i];
  SubS[len] = '\0';
  return SubS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  cmpq   $0x0,-0x20(%rbp)
  jne    L77
L18:
  mov    $0x0,%eax
  jmp    L32
L77:
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  je     L25
  mov    $0x0,%eax
  jmp    L32
L25:
  mov    -0x18(%rbp),%rsi
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <regexec@plt>
  mov    D12(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  je     L44
  movl   $0x1,-0xc(%rbp)
  jmp    L59
L44:
  movl   $0x0,-0xc(%rbp)
L59:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  mov    -0xc(%rbp),%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
bool match_string(const char *haystack, const char *needle) {
  regex_t regex;
  bool ret;
  if (haystack == NULL || needle == NULL) {
    return false;
  }
  if (regcomp(&regex, needle, REG_ICASE | REG_EXTENDED | REG_NOSUB | REG_NEWLINE) != 0) {
    return false;
  }
  if (regexec(&regex, haystack, 0, 0, 0) != REG_NOMATCH) {
    ret = true;
  } else {
    ret = false;
  }
  regfree(&regex);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<match_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L21
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L21
  mov    D49(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  or     (%rax),%edx
  mov    D11(%rip),%rax
  or     (%rax),%edx
  mov    D38(%rip),%rax
  or     (%rax),%edx
  lea    0x4(%rsp),%rdi
  call   <regcomp@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  jne    L49
  lea    0x4(%rsp),%r12
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <regexec@plt>
  mov    D16(%rip),%rdx
  cmp    %rax,(%rdx)
  setne  %bpl
  movzbl %bpl,%ebp
  mov    %r12,%rdi
  call   <regfree@plt>
  jmp    L49
L21:
  mov    $0x0,%ebp
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool match_string(const char *haystack, const char *needle) {
  regex_t regex;
  bool ret;
  if (haystack == NULL || needle == NULL) {
    return false;
  }
  if (regcomp(&regex, needle, REG_ICASE | REG_EXTENDED | REG_NOSUB | REG_NEWLINE) != 0) {
    return false;
  }
  if (regexec(&regex, haystack, 0, 0, 0) != REG_NOMATCH) {
    ret = true;
  } else {
    ret = false;
  }
  regfree(&regex);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<match_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L14
  test   %rsi,%rsi
  je     L14
  mov    D13(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    %rdi,%rbp
  mov    %r13,%rdi
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  or     (%rax),%edx
  mov    D35(%rip),%rax
  or     (%rax),%edx
  mov    D16(%rip),%rax
  or     (%rax),%edx
  call   <regcomp@plt>
  test   %rax,%rax
  jne    L14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  xor    %r12d,%r12d
  call   <regexec@plt>
  mov    D33(%rip),%rdx
  mov    %r13,%rdi
  cmp    %rax,(%rdx)
  setne  %r12b
  call   <regfree@plt>
  jmp    L33
  nopl   (%rax)
L14:
  xor    %r12d,%r12d
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool match_string(const char *haystack, const char *needle) {
  regex_t regex;
  bool ret;
  if (haystack == NULL || needle == NULL) {
    return false;
  }
  if (regcomp(&regex, needle, REG_ICASE | REG_EXTENDED | REG_NOSUB | REG_NEWLINE) != 0) {
    return false;
  }
  if (regexec(&regex, haystack, 0, 0, 0) != REG_NOMATCH) {
    ret = true;
  } else {
    ret = false;
  }
  regfree(&regex);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<match_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L25
  test   %rsi,%rsi
  je     L25
  mov    D39(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    %rdi,%rbp
  mov    %r13,%rdi
  mov    (%rax),%edx
  mov    D38(%rip),%rax
  or     (%rax),%edx
  mov    D48(%rip),%rax
  or     (%rax),%edx
  mov    D41(%rip),%rax
  or     (%rax),%edx
  call   <regcomp@plt>
  test   %rax,%rax
  jne    L25
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  xor    %r12d,%r12d
  call   <regexec@plt>
  mov    D3(%rip),%rdx
  mov    %r13,%rdi
  cmp    %rax,(%rdx)
  setne  %r12b
  call   <regfree@plt>
  jmp    L47
  nopl   (%rax)
L25:
  xor    %r12d,%r12d
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool match_string(const char *haystack, const char *needle) {
  regex_t regex;
  bool ret;
  if (haystack == NULL || needle == NULL) {
    return false;
  }
  if (regcomp(&regex, needle, REG_ICASE | REG_EXTENDED | REG_NOSUB | REG_NEWLINE) != 0) {
    return false;
  }
  if (regexec(&regex, haystack, 0, 0, 0) != REG_NOMATCH) {
    ret = true;
  } else {
    ret = false;
  }
  regfree(&regex);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x34(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x4c,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x21,-0x10(%rbp)
  movl   $0x57,-0xc(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <display@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int n = 10;
  int a1[] = {2, 3, 6, 4, 76, 11, 9, 4, 33, 87};
  bubble_sort(a1, n);
  display(a1, n);
  return 0;
}
```