ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<goback>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <feof@plt>
  test   %eax,%eax
  je     L3
L1:
  pop    %rbx
  ret
L3:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  jmp    L1
```

assistant: ```c
void goback(FILE *__stream) {
  if (!feof(__stream)) {
    fseek(__stream, -1, SEEK_CUR);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<goback>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L6
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D7(%rip),%rax
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1070 <fseek@plt>
```

assistant: ```c
void goback(FILE *__stream) {
  if (!feof(__stream)) {
    fseek(__stream, -1, SEEK_CUR);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<goback>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L4
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    D6(%rip),%rax
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  pop    %rbp
  mov    (%rax),%edx
  jmp    1070 <fseek@plt>
```

assistant: ```c
void goback(FILE *__stream) {
  if (!feof(__stream)) {
    fseek(__stream, -1, SEEK_CUR);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <baz@plt>
  movq   %xmm0,%rax
  movsd  D5(%rip),%xmm0
  movq   %rax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L9
  movsd  D5(%rip),%xmm0
  movq   %rax,%xmm2
  ucomisd %xmm0,%xmm2
  je     L12
L9:
  mov    $0x0,%eax
  call   <abort@plt>
L12:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: f64

tool: 

tool: D5: 1

assistant: ```c
int main() {
  if (baz("") != 1.0)
    abort();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <baz@plt>
  ucomisd D3(%rip),%xmm0
  jp     L5
  jne    L5
L6:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L5:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: f64

tool: 

tool: D3: 1

assistant: ```c
int main() {
  if (baz("") != 1.0)
    abort();
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <baz@plt>
  ucomisd D14(%rip),%xmm0
  jp     L22
  jne    L22
L12:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L22:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D14
type: f64

tool: 

tool: D14: 1

assistant: ```c
int main() {
  if (baz("") != 1.0)
    abort();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <baz@plt>
  ucomisd D12(%rip),%xmm0
  jp     L27
  jne    L27
L19:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L27:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: f64

tool: 

tool: D12: 1

assistant: ```c
int main() {
  if (baz("") != 1.0)
    abort();
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L14
L1:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
char *xstrncat(char *pfx, const char *sfx, const size_t n) {
  char *s;
  s = xmalloc(strlen(pfx) + n + 1);
  if (!s)
    return NULL;
  strcpy(s, pfx);
  strncat(s, sfx, n);
  xfree(pfx);
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xstrncat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <xfree@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *xstrncat(char *pfx, const char *sfx, const size_t n) {
  char *s;
  s = xmalloc(strlen(pfx) + n + 1);
  if (!s)
    return NULL;
  strcpy(s, pfx);
  strncat(s, sfx, n);
  xfree(pfx);
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xstrncat>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%rdi
  call   <xmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <xfree@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *xstrncat(char *pfx, const char *sfx, const size_t n) {
  char *s;
  s = xmalloc(strlen(pfx) + n + 1);
  if (!s)
    return NULL;
  strcpy(s, pfx);
  strncat(s, sfx, n);
  xfree(pfx);
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xstrncat>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%rdi
  call   <xmalloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <xfree@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *xstrncat(char *pfx, const char *sfx, const size_t n) {
  char *s;
  s = xmalloc(strlen(pfx) + n + 1);
  if (!s)
    return NULL;
  strcpy(s, pfx);
  strncat(s, sfx, n);
  xfree(pfx);
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<microseconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
long long microseconds(void) {
  struct timeval t;
  gettimeofday(&t, (struct timezone *)0);
  return t.tv_sec * (long long)1000000 + t.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<microseconds>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long microseconds(void) {
  struct timeval t;
  gettimeofday(&t, (struct timezone *)0);
  return t.tv_sec * (long long)1000000 + t.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<microseconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long microseconds(void) {
  struct timeval t;
  gettimeofday(&t, (struct timezone *)0);
  return t.tv_sec * (long long)1000000 + t.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<microseconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long microseconds(void) {
  struct timeval t;
  gettimeofday(&t, (struct timezone *)0);
  return t.tv_sec * (long long)1000000 + t.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pick_element>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L25:
  addq   $0x1,-0x8(%rbp)
L62:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  ja     L25
  subl   $0x1,-0x24(%rbp)
  jmp    L32
L66:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L66
L0:
  cmpl   $0x0,-0x24(%rbp)
  jne    L62
  jmp    L47
L5:
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  ja     L5
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pick_element(const char *in_buf, char *out_buf, int element) {
  const char *count = in_buf;
  int element_len = 0;
  while (element) {
    while ((unsigned)*count > (unsigned)' ')
      count++;
    element--;
    while (*count == ' ')
      count++;
  }
  while ((unsigned)*(count + element_len) > (unsigned)' ')
    element_len++;
  memcpy(out_buf, count, element_len * sizeof(char));
  *(out_buf + element_len) = '\0';
  return (element_len);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pick_element>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %edx,%edx
  jne    L27
L1:
  cmpb   $0x20,(%rdi)
  jbe    L54
  mov    $0x1,%eax
L76:
  mov    %eax,%ebp
  movzbl (%rdi,%rax,1),%edx
  mov    %rax,%r12
  add    $0x1,%rax
  cmp    $0x20,%dl
  ja     L76
L7:
  mov    %ebp,%edx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  ja     L0
L49:
  sub    $0x1,%edx
  cmpb   $0x20,(%rdi)
  jne    L86
L97:
  add    $0x1,%rdi
  cmpb   $0x20,(%rdi)
  je     L97
L86:
  test   %edx,%edx
  je     L1
L27:
  cmpb   $0x20,(%rdi)
  ja     L0
  jmp    L49
L54:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L7
```

assistant: ```c
int pick_element(const char *in_buf, char *out_buf, int element) {
  const char *count = in_buf;
  int element_len = 0;
  while (element) {
    while ((unsigned)*count > (unsigned)' ')
      count++;
    element--;
    while (*count == ' ')
      count++;
  }
  while ((unsigned)*(count + element_len) > (unsigned)' ')
    element_len++;
  memcpy(out_buf, count, element_len * sizeof(char));
  *(out_buf + element_len) = '\0';
  return (element_len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_element>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%r8),%eax
  test   %edx,%edx
  jne    L55
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
L55:
  cmp    $0x20,%al
  ja     L19
  sub    $0x1,%edx
  cmp    $0x20,%al
  jne    L12
  nopl   0x0(%rax)
L78:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x20,%al
  je     L78
L12:
  test   %edx,%edx
  jne    L55
L57:
  cmp    $0x20,%al
  jbe    L76
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L53:
  movzbl (%r8,%rax,1),%edx
  mov    %eax,%r12d
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    $0x20,%dl
  ja     L53
  lea    (%rdi,%rcx,1),%rbx
L10:
  mov    %r12d,%edx
  mov    %r8,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L76:
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L10
```

assistant: ```c
int pick_element(const char *in_buf, char *out_buf, int element) {
  const char *count = in_buf;
  int element_len = 0;
  while (element) {
    while ((unsigned)*count > (unsigned)' ')
      count++;
    element--;
    while (*count == ' ')
      count++;
  }
  while ((unsigned)*(count + element_len) > (unsigned)' ')
    element_len++;
  memcpy(out_buf, count, element_len * sizeof(char));
  *(out_buf + element_len) = '\0';
  return (element_len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pick_element>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%r8),%eax
  test   %edx,%edx
  jne    L79
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L58:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
L79:
  cmp    $0x20,%al
  ja     L58
  sub    $0x1,%edx
  cmp    $0x20,%al
  jne    L40
  nopl   0x0(%rax)
L71:
  movzbl 0x1(%r8),%eax
  add    $0x1,%r8
  cmp    $0x20,%al
  je     L71
L40:
  test   %edx,%edx
  jne    L79
L66:
  cmp    $0x20,%al
  jbe    L36
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L56:
  movzbl (%r8,%rax,1),%edx
  mov    %eax,%r12d
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    $0x20,%dl
  ja     L56
  lea    (%rdi,%rcx,1),%rbx
L15:
  mov    %r12d,%edx
  mov    %r8,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L36:
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L15
```

assistant: ```c
int pick_element(const char *in_buf, char *out_buf, int element) {
  const char *count = in_buf;
  int element_len = 0;
  while (element) {
    while ((unsigned)*count > (unsigned)' ')
      count++;
    element--;
    while (*count == ' ')
      count++;
  }
  while ((unsigned)*(count + element_len) > (unsigned)' ')
    element_len++;
  memcpy(out_buf, count, element_len * sizeof(char));
  *(out_buf + element_len) = '\0';
  return (element_len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(float *x, float *y) {
  float temp;
  temp = *x;
  *x = *y;
  *y = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movss  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap(float *x, float *y) {
  float temp;
  temp = *x;
  *x = *y;
  *y = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movss  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap(float *x, float *y) {
  float temp;
  temp = *x;
  *x = *y;
  *y = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movss  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap(float *x, float *y) {
  float temp;
  temp = *x;
  *x = *y;
  *y = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t f2u(float d) {
  union {
    float f;
    uint32_t i;
  } tmp;
  tmp.f = d;
  return tmp.i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t f2u(float d) {
  union {
    float f;
    uint32_t i;
  } tmp;
  tmp.f = d;
  return tmp.i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t f2u(float d) {
  union {
    float f;
    uint32_t i;
  } tmp;
  tmp.f = d;
  return tmp.i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2u>:
  endbr64
  movd   %xmm0,%eax
  ret
```

assistant: ```c
uint32_t f2u(float d) {
  union {
    float f;
    uint32_t i;
  } tmp;
  tmp.f = d;
  return tmp.i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<build_max_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_down@plt>
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jg     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void build_max_heap(int arr[], int n) {
  int i;
  for (i = n / 2; i >= 1; i--)
    max_down(arr, i, n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L2
L10:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <max_down@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L10
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int arr[], int n) {
  int i;
  for (i = n / 2; i >= 1; i--)
    max_down(arr, i, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L19
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <max_down@plt>
  sub    $0x1,%ebx
  jne    L3
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int arr[], int n) {
  int i;
  for (i = n / 2; i >= 1; i--)
    max_down(arr, i, n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L10
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <max_down@plt>
  sub    $0x1,%ebx
  jne    L15
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int arr[], int n) {
  int i;
  for (i = n / 2; i >= 1; i--)
    max_down(arr, i, n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rcx
  mov    0x8(%rax),%rbx
  mov    %rcx,-0x50(%rbp)
  mov    %rbx,-0x48(%rbp)
  mov    0x10(%rax),%rcx
  mov    0x18(%rax),%rbx
  mov    %rcx,-0x40(%rbp)
  mov    %rbx,-0x38(%rbp)
  mov    0x20(%rax),%rcx
  mov    0x28(%rax),%rbx
  mov    %rcx,-0x30(%rbp)
  mov    %rbx,-0x28(%rbp)
  mov    0x30(%rax),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x64(%rbp)
  jmp    L27
L9:
  mov    -0x78(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x60(%rbp)
  addq   $0x8,-0x78(%rbp)
  mov    -0x64(%rbp),%edx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  xor    %rax,-0x58(%rbp)
  addl   $0x1,-0x64(%rbp)
L27:
  cmpl   $0x6,-0x64(%rbp)
  jbe    L9
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x58(%rbp),%rax
  xor    %edx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int hashKey(char *t_ptr) {
  unsigned long hash_frag = 0;
  unsigned long hash_key = 0;
  unsigned int i;
  char tmp[(56)];
  memcpy(tmp, t_ptr, (56));
  for (i = 0; i < ((56) / (sizeof(unsigned long))); i++) {
    memcpy(&hash_frag, t_ptr, (sizeof(unsigned long)));
    t_ptr += (sizeof(unsigned long));
    hash_key = hash_key ^ (hash_frag + i);
  }
  return hash_key ^ strlen(tmp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashKey>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movdqu (%rdi),%xmm0
  movaps %xmm0,(%rsp)
  movdqu 0x10(%rdi),%xmm1
  movaps %xmm1,0x10(%rsp)
  movdqu 0x20(%rdi),%xmm2
  movaps %xmm2,0x20(%rsp)
  mov    0x30(%rdi),%rax
  mov    %rax,0x30(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%ebx
L17:
  mov    %rdx,%rax
  add    (%rdi,%rdx,8),%rax
  xor    %rax,%rbx
  add    $0x1,%rdx
  cmp    $0x7,%rdx
  jne    L17
  mov    %rsp,%rdi
  call   <strlen@plt>
  xor    %ebx,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x40,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int hashKey(char *t_ptr) {
  unsigned long hash_frag = 0;
  unsigned long hash_key = 0;
  unsigned int i;
  char tmp[(56)];
  memcpy(tmp, t_ptr, (56));
  for (i = 0; i < ((56) / (sizeof(unsigned long))); i++) {
    memcpy(&hash_frag, t_ptr, (sizeof(unsigned long)));
    t_ptr += (sizeof(unsigned long));
    hash_key = hash_key ^ (hash_frag + i);
  }
  return hash_key ^ strlen(tmp);
}
```