ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D51(%rip),%xmm1
  movsd  D11(%rip),%xmm0
  call   <dotest@plt>
  movsd  D46(%rip),%xmm1
  movsd  D2(%rip),%xmm0
  call   <dotest@plt>
  movsd  D44(%rip),%xmm1
  movsd  D66(%rip),%xmm0
  call   <dotest@plt>
  movsd  D52(%rip),%xmm1
  movsd  D57(%rip),%xmm0
  call   <dotest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D51
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D11
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D46
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D2
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D44
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D66
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D52
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D57
type_guessed: byte[8]

tool: {"D51": [0xb6,0xbc,0x33,0x56,0xd3,0xea,0x4b,0x3e]}

tool: {"D11": [0xb2,0x1c,0x3f,0x59,0xd3,0xea,0x5b,0x3e]}

tool: {"D46": [0x2c,0x9e,0x78,0xde,0x43,0x0d,0x08,0x3e]}

tool: {"D2": [0x03,0xc6,0x9c,0xde,0x43,0x0d,0x18,0x3e]}

tool: {"D44": [0x61,0xb3,0x15,0xd1,0xb3,0xf8,0xc4,0x3e]}

tool: {"D66": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: {"D52": [0xd6,0xe4,0x6d,0x19,0x2b,0x1b,0x80,0x3e]}

tool: {"D57": [0x2b,0x69,0xa4,0x29,0x2b,0x1b,0x90,0x3e]}

assistant: ```c
int main() {
  dotest(2.6e-08, 1.29999999155e-08);
  dotest(1.4e-09, 6.999999997549999e-10);
  dotest(5.0e-06, 2.499996875007812e-06);
  dotest(2.4e-07, 1.1999999280000085e-07);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D73(%rip),%xmm1
  movsd  D40(%rip),%xmm0
  call   <dotest@plt>
  movsd  D56(%rip),%xmm1
  movsd  D58(%rip),%xmm0
  call   <dotest@plt>
  movsd  D45(%rip),%xmm1
  movsd  D3(%rip),%xmm0
  call   <dotest@plt>
  movsd  D10(%rip),%xmm1
  movsd  D7(%rip),%xmm0
  call   <dotest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D73
data_type: byte[8]
name: retrieve_data
arguments: data_label: D40
data_type: byte[8]
name: retrieve_data
arguments: data_label: D56
data_type: byte[8]
name: retrieve_data
arguments: data_label: D58
data_type: byte[8]
name: retrieve_data
arguments: data_label: D45
data_type: byte[8]
name: retrieve_data
arguments: data_label: D3
data_type: byte[8]
name: retrieve_data
arguments: data_label: D10
data_type: byte[8]
name: retrieve_data
arguments: data_label: D7
data_type: byte[8]

tool: {"D73": [0xb6,0xbc,0x33,0x56,0xd3,0xea,0x4b,0x3e]}

tool: {"D40": [0xb2,0x1c,0x3f,0x59,0xd3,0xea,0x5b,0x3e]}

tool: {"D56": [0x2c,0x9e,0x78,0xde,0x43,0x0d,0x08,0x3e]}

tool: {"D58": [0x03,0xc6,0x9c,0xde,0x43,0x0d,0x18,0x3e]}

tool: {"D45": [0x61,0xb3,0x15,0xd1,0xb3,0xf8,0xc4,0x3e]}

tool: {"D3": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: {"D10": [0xd6,0xe4,0x6d,0x19,0x2b,0x1b,0x80,0x3e]}

tool: {"D7": [0x2b,0x69,0xa4,0x29,0x2b,0x1b,0x90,0x3e]}

assistant: ```c
int main() {
  dotest(2.6e-08, 1.29999999155e-08);
  dotest(1.4e-09, 6.999999997549999e-10);
  dotest(5.0e-06, 2.499996875007812e-06);
  dotest(2.4e-07, 1.1999999280000085e-07);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_input(void) {
  int input = 0;
  return input;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_input>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int get_input(void) {
  int input = 0;
  return input;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_input>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_input(void) {
  int input = 0;
  return input;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_input>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_input(void) {
  int input = 0;
  return input;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xa,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <arrayAlloc2D@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L35
L8:
  movl   $0x0,-0x14(%rbp)
  jmp    L46
L34:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L34
  addl   $0x1,-0x18(%rbp)
L35:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L8
  movl   $0x0,-0x18(%rbp)
  jmp    L65
L23:
  movl   $0x0,-0x14(%rbp)
  jmp    L73
L72:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L73:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L72
  addl   $0x1,-0x18(%rbp)
L65:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <arrayFree2D@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: %f 


assistant: ```c
int main() {
  int dim1 = 10;
  int dim2 = 20;
  int i, j;
  double **array = arrayAlloc2D(dim1, dim2);
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      array[i][j] = i + j;
    }
  }
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      printf("%f \n", array[i][j]);
    }
  }
  arrayFree2D(array);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <arrayAlloc2D@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    $0x0,%edi
L4:
  mov    %edi,%edx
  mov    $0x0,%eax
L26:
  mov    (%rsi),%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  add    $0x8,%rax
  add    $0x1,%edx
  cmp    $0xa0,%rax
  jne    L26
  add    $0x1,%edi
  add    $0x8,%rsi
  cmp    $0xa,%edi
  jne    L4
  lea    0x50(%r12),%r14
  lea    D0(%rip),%r13
L29:
  mov    $0x0,%ebx
L27:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    $0xa0,%rbx
  jne    L27
  add    $0x8,%rbp
  cmp    %rbp,%r14
  jne    L29
  mov    %r12,%rdi
  call   <arrayFree2D@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: %f 


assistant: ```c
int main() {
  int dim1 = 10;
  int dim2 = 20;
  int i, j;
  double **array = arrayAlloc2D(dim1, dim2);
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      array[i][j] = i + j;
    }
  }
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      printf("%f \n", array[i][j]);
    }
  }
  arrayFree2D(array);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x14,%esi
  mov    $0xa,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <arrayAlloc2D@plt>
  xor    %ecx,%ecx
  mov    %rax,%rbp
L20:
  mov    0x0(%rbp,%rcx,8),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L25:
  lea    (%rax,%rcx,1),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x14,%rax
  jne    L25
  add    $0x1,%rcx
  cmp    $0xa,%rcx
  jne    L20
  mov    %rbp,%r14
  lea    0x50(%rbp),%r13
  lea    D5(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%r14),%rax
  mov    %r12,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    $0xa0,%rbx
  jne    L35
  add    $0x8,%r14
  cmp    %r14,%r13
  jne    L31
  mov    %rbp,%rdi
  call   <arrayFree2D@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: %f 


assistant: ```c
int main() {
  int dim1 = 10;
  int dim2 = 20;
  int i, j;
  double **array = arrayAlloc2D(dim1, dim2);
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      array[i][j] = i + j;
    }
  }
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      printf("%f \n", array[i][j]);
    }
  }
  arrayFree2D(array);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x14,%esi
  mov    $0xa,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <arrayAlloc2D@plt>
  movdqa D47(%rip),%xmm6
  xor    %edx,%edx
  movdqa D17(%rip),%xmm5
  movdqa D22(%rip),%xmm4
  movdqa D1(%rip),%xmm3
  mov    %rax,%r12
  movdqa D52(%rip),%xmm2
  nopl   0x0(%rax,%rax,1)
L0:
  movd   %edx,%xmm7
  mov    (%r12,%rdx,8),%rax
  add    $0x1,%rdx
  pshufd $0x0,%xmm7,%xmm0
  movdqa %xmm0,%xmm1
  paddd  %xmm6,%xmm1
  cvtdq2pd %xmm1,%xmm7
  pshufd $0xee,%xmm1,%xmm1
  movups %xmm7,(%rax)
  cvtdq2pd %xmm1,%xmm1
  movups %xmm1,0x10(%rax)
  movdqa %xmm0,%xmm1
  paddd  %xmm5,%xmm1
  cvtdq2pd %xmm1,%xmm7
  pshufd $0xee,%xmm1,%xmm1
  movups %xmm7,0x20(%rax)
  cvtdq2pd %xmm1,%xmm1
  movups %xmm1,0x30(%rax)
  movdqa %xmm0,%xmm1
  paddd  %xmm4,%xmm1
  cvtdq2pd %xmm1,%xmm7
  pshufd $0xee,%xmm1,%xmm1
  movups %xmm7,0x40(%rax)
  cvtdq2pd %xmm1,%xmm1
  movups %xmm1,0x50(%rax)
  movdqa %xmm0,%xmm1
  paddd  %xmm2,%xmm0
  paddd  %xmm3,%xmm1
  cvtdq2pd %xmm1,%xmm7
  pshufd $0xee,%xmm1,%xmm1
  movups %xmm7,0x60(%rax)
  cvtdq2pd %xmm1,%xmm1
  movups %xmm1,0x70(%rax)
  cvtdq2pd %xmm0,%xmm1
  pshufd $0xee,%xmm0,%xmm0
  cvtdq2pd %xmm0,%xmm0
  movups %xmm1,0x80(%rax)
  movups %xmm0,0x90(%rax)
  cmp    $0xa,%rdx
  jne    L0
  mov    %r12,%r14
  lea    0x50(%r12),%r13
  lea    D58(%rip),%rbp
  nopl   0x0(%rax)
L12:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%r14),%rax
  mov    %rbp,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    $0xa0,%rbx
  jne    L17
  add    $0x8,%r14
  cmp    %r14,%r13
  jne    L12
  mov    %r12,%rdi
  call   <arrayFree2D@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D47
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D17
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D22
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D1
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D52
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D58
data_type: string

tool: {"D47": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D22": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D1": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: {"D52": [0x10,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x13,0x00,0x00,0x00]}

tool: D58: %f 


assistant: ```c
int main() {
  int dim1 = 10;
  int dim2 = 20;
  int i, j;
  double **array = arrayAlloc2D(dim1, dim2);
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      array[i][j] = i + j;
    }
  }
  for (i = 0; i < dim1; i++) {
    for (j = 0; j < dim2; j++) {
      printf("%f \n", array[i][j]);
    }
  }
  arrayFree2D(array);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <crc64_little@plt>
  jmp    L13
L1:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <crc64_big@plt>
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
uint64_t crc64(uint64_t crc, void *buf, size_t len) {
  uint64_t n = 1;
  return *(char *)&n ? crc64_little(crc, buf, len) : crc64_big(crc, buf, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc64>:
  endbr64
  sub    $0x8,%rsp
  call   <crc64_little@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint64_t crc64(uint64_t crc, void *buf, size_t len) {
  uint64_t n = 1;
  return *(char *)&n ? crc64_little(crc, buf, len) : crc64_big(crc, buf, len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crc64>:
  endbr64
  jmp    1050 <crc64_little@plt>
```

assistant: ```c
uint64_t crc64(uint64_t crc, void *buf, size_t len) {
  uint64_t n = 1;
  return *(char *)&n ? crc64_little(crc, buf, len) : crc64_big(crc, buf, len);
}
```
user: What is the c source code of the assembly code below?

```asm
<crc64>:
  endbr64
  jmp    1050 <crc64_little@plt>
```

assistant: ```c
uint64_t crc64(uint64_t crc, void *buf, size_t len) {
  uint64_t n = 1;
  return *(char *)&n ? crc64_little(crc, buf, len) : crc64_big(crc, buf, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L40
L7:
  movl   $0x1,-0x10(%rbp)
  jmp    L23
L2:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L2
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D37
datatype: string
name: disassemble_data
arguments: data_tag: D32
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D2: Digite um numero: 

tool: D37: %d

tool: D32: *

tool: D7: 


assistant: ```c
main() {
  int n, j = 0, i = 0;
  printf("Digite um numero: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%r12d
  lea    D19(%rip),%rbp
  lea    D1(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L18
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L50
L10:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jl     L32
L18:
  mov    $0x1,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L50
  jmp    L10
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D28: Digite um numero: 

tool: D21: %d

tool: D19: *

tool: D1: 


assistant: ```c
main() {
  int n, j = 0, i = 0;
  printf("Digite um numero: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  lea    D5(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D31(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%ebx
  nopl   (%rax)
L35:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L35
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L13
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D33
type: string

tool: D22: Digite um numero: 

tool: D5: 


tool: D31: *

tool: D33: %d

assistant: ```c
main() {
  int n, j = 0, i = 0;
  printf("Digite um numero: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D36(%rip),%rdi
  lea    D31(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L6
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%ebx
  nopl   (%rax)
L25:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L25
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jge    L22
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D36
type_guessed: string
name: unpack_data
arguments: tag: D31
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string
name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D36: Digite um numero: 

tool: D31: 


tool: D32: *

tool: D1: %d

assistant: ```c
main() {
  int n, j = 0, i = 0;
  printf("Digite um numero: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= n; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L26
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L26
L42:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L38:
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

assistant: ```c
char *strdup(const char *src) {
  char *dup;
  unsigned int len;
  if (!src)
    return NULL;
  len = strlen(src);
  if (len == 0)
    return NULL;
  dup = malloc(len + 1);
  if (dup)
    strcpy(dup, src);
  return dup;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L15
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strdup(const char *src) {
  char *dup;
  unsigned int len;
  if (!src)
    return NULL;
  len = strlen(src);
  if (len == 0)
    return NULL;
  dup = malloc(len + 1);
  if (dup)
    strcpy(dup, src);
  return dup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strdup>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L7
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *src) {
  char *dup;
  unsigned int len;
  if (!src)
    return NULL;
  len = strlen(src);
  if (len == 0)
    return NULL;
  dup = malloc(len + 1);
  if (dup)
    strcpy(dup, src);
  return dup;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strdup>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L17
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdup(const char *src) {
  char *dup;
  unsigned int len;
  if (!src)
    return NULL;
  len = strlen(src);
  if (len == 0)
    return NULL;
  dup = malloc(len + 1);
  if (dup)
    strcpy(dup, src);
  return dup;
}
```