ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unpack>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rbx),%eax
  movsbl (%rdi),%edi
  shr    $0x3,%al
  shl    $0x5,%edi
  and    $0x1fe0,%edi
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x1(%rbx),%edi
  movsbl 0x2(%rbx),%eax
  lea    0x2(%rbp),%rsi
  shl    $0xa,%edi
  shl    $0x2,%eax
  and    $0x3fc,%eax
  and    $0x1c00,%edi
  or     %eax,%edi
  movzbl 0x3(%rbx),%eax
  shr    $0x6,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x3(%rbx),%edi
  movzbl 0x4(%rbx),%eax
  lea    0x4(%rbp),%rsi
  shl    $0x7,%edi
  shr    %al
  and    $0x1f80,%edi
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x4(%rbx),%edi
  movsbl 0x5(%rbx),%eax
  lea    0x6(%rbp),%rsi
  shl    $0xc,%edi
  shl    $0x4,%eax
  and    $0xff0,%eax
  and    $0x1000,%edi
  or     %eax,%edi
  movzbl 0x6(%rbx),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x6(%rbx),%edi
  movsbl 0x7(%rbx),%eax
  lea    0x8(%rbp),%rsi
  shl    $0x9,%edi
  and    $0x1e00,%edi
  add    %eax,%eax
  and    $0x1fe,%eax
  or     %eax,%edi
  movzbl 0x8(%rbx),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x8(%rbx),%edi
  movzbl 0x9(%rbx),%eax
  lea    0xa(%rbp),%rsi
  shl    $0x6,%edi
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x1fc0,%edi
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x9(%rbx),%edi
  movsbl 0xa(%rbx),%eax
  lea    0xc(%rbp),%rsi
  shl    $0xb,%edi
  shl    $0x3,%eax
  and    $0x7f8,%eax
  and    $0x1800,%edi
  or     %eax,%edi
  movzbl 0xb(%rbx),%eax
  shr    $0x5,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0xb(%rbx),%edi
  movzbl 0xc(%rbx),%eax
  add    $0x8,%rsp
  lea    0xe(%rbp),%rsi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  and    $0x1f00,%edi
  or     %eax,%edi
  xor    %eax,%eax
  jmp    1050 <conv@plt>
```

assistant: ```c
void unpack(p, s) register char *p, *s;
{
  conv(p[0] << 5 & 017740 | p[1] >> 3 & 037, s);
  s += 2;
  p += 1;
  conv(p[0] << 10 & 016000 | p[1] << 2 & 01774 | p[2] >> 6 & 3, s);
  s += 2;
  p += 2;
  conv(p[0] << 7 & 017600 | p[1] >> 1 & 0177, s);
  s += 2;
  p += 1;
  conv(p[0] << 12 & 010000 | p[1] << 4 & 07760 | p[2] >> 4 & 017, s);
  s += 2;
  p += 2;
  conv(p[0] << 9 & 017000 | p[1] << 1 & 0776 | p[2] >> 7 & 01, s);
  s += 2;
  p += 2;
  conv(p[0] << 6 & 017700 | p[1] >> 2 & 077, s);
  s += 2;
  p += 1;
  conv(p[0] << 11 & 014000 | p[1] << 3 & 03770 | p[2] >> 5 & 07, s);
  s += 2;
  p += 2;
  conv(p[0] << 8 & 017400 | p[1] & 0377, s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unpack>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rbx),%eax
  movsbl (%rdi),%edi
  shr    $0x3,%al
  shl    $0x5,%edi
  and    $0x1fe0,%edi
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x1(%rbx),%edi
  movsbl 0x2(%rbx),%eax
  lea    0x2(%rbp),%rsi
  shl    $0xa,%edi
  shl    $0x2,%eax
  and    $0x3fc,%eax
  and    $0x1c00,%edi
  or     %eax,%edi
  movzbl 0x3(%rbx),%eax
  shr    $0x6,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x3(%rbx),%edi
  movzbl 0x4(%rbx),%eax
  lea    0x4(%rbp),%rsi
  shl    $0x7,%edi
  shr    %al
  and    $0x1f80,%edi
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x4(%rbx),%edi
  movsbl 0x5(%rbx),%eax
  lea    0x6(%rbp),%rsi
  shl    $0xc,%edi
  shl    $0x4,%eax
  and    $0xff0,%eax
  and    $0x1000,%edi
  or     %eax,%edi
  movzbl 0x6(%rbx),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x6(%rbx),%edi
  movsbl 0x7(%rbx),%eax
  lea    0x8(%rbp),%rsi
  shl    $0x9,%edi
  and    $0x1e00,%edi
  add    %eax,%eax
  and    $0x1fe,%eax
  or     %eax,%edi
  movzbl 0x8(%rbx),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x8(%rbx),%edi
  movzbl 0x9(%rbx),%eax
  lea    0xa(%rbp),%rsi
  shl    $0x6,%edi
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x1fc0,%edi
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0x9(%rbx),%edi
  movsbl 0xa(%rbx),%eax
  lea    0xc(%rbp),%rsi
  shl    $0xb,%edi
  shl    $0x3,%eax
  and    $0x7f8,%eax
  and    $0x1800,%edi
  or     %eax,%edi
  movzbl 0xb(%rbx),%eax
  shr    $0x5,%al
  movzbl %al,%eax
  or     %eax,%edi
  xor    %eax,%eax
  call   <conv@plt>
  movsbl 0xb(%rbx),%edi
  movzbl 0xc(%rbx),%eax
  add    $0x8,%rsp
  lea    0xe(%rbp),%rsi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  and    $0x1f00,%edi
  or     %eax,%edi
  xor    %eax,%eax
  jmp    1050 <conv@plt>
```

assistant: ```c
void unpack(p, s) register char *p, *s;
{
  conv(p[0] << 5 & 017740 | p[1] >> 3 & 037, s);
  s += 2;
  p += 1;
  conv(p[0] << 10 & 016000 | p[1] << 2 & 01774 | p[2] >> 6 & 3, s);
  s += 2;
  p += 2;
  conv(p[0] << 7 & 017600 | p[1] >> 1 & 0177, s);
  s += 2;
  p += 1;
  conv(p[0] << 12 & 010000 | p[1] << 4 & 07760 | p[2] >> 4 & 017, s);
  s += 2;
  p += 2;
  conv(p[0] << 9 & 017000 | p[1] << 1 & 0776 | p[2] >> 7 & 01, s);
  s += 2;
  p += 2;
  conv(p[0] << 6 & 017700 | p[1] >> 2 & 077, s);
  s += 2;
  p += 1;
  conv(p[0] << 11 & 014000 | p[1] << 3 & 03770 | p[2] >> 5 & 07, s);
  s += 2;
  p += 2;
  conv(p[0] << 8 & 017400 | p[1] & 0377, s);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L110:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L110
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L45
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L45
  cmpl   $0x2b,-0x8(%rbp)
  je     L45
  cmpl   $0x2d,-0x8(%rbp)
  je     L45
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x0,%eax
  jmp    L103
L45:
  cmpl   $0x2d,-0x8(%rbp)
  jne    L32
  mov    $0xffffffff,%eax
  jmp    L85
L32:
  mov    $0x1,%eax
L85:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2b,-0x8(%rbp)
  je     L18
  cmpl   $0x2d,-0x8(%rbp)
  jne    L82
L18:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x8(%rbp)
L82:
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L79
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    $0x30,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x8(%rbp)
L79:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L128
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L128:
  mov    -0x8(%rbp),%eax
L103:
  leave
  ret
```

assistant: ```c
int getint(int *pn) {
  int c, sign;
  while (isspace(c = getch())) {
    ;
  }
  if (!isdigit(c) && c != EOF && c != '+' && c != '-') {
    ungetch(c);
    return 0;
  }
  sign = (c == '-') ? -1 : 1;
  if (c == '+' || c == '-') {
    c = getch();
  }
  for (*pn = 0; isdigit(c); c = getch()) {
    *pn = 10 * *pn + (c - '0');
  }
  *pn *= sign;
  if (c != EOF) {
    ungetch(c);
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
L55:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L55
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L107
  mov    D10(%rip),%rax
  cmp    %ebx,(%rax)
  je     L107
  lea    -0x2b(%rbx),%eax
  test   $0xfffffffd,%eax
  jne    L109
L107:
  cmp    $0x2d,%ebx
  je     L42
  lea    -0x2b(%rbx),%eax
  test   $0xfffffffd,%eax
  je     L86
  mov    $0x1,%r12d
L9:
  movl   $0x0,0x0(%rbp)
  jmp    L44
L109:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x0,%ebx
  jmp    L30
L86:
  mov    $0x1,%r12d
  jmp    L105
L42:
  mov    $0xffffffff,%r12d
L105:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  jmp    L9
L129:
  mov    0x0(%rbp),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
L44:
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L129
  imul   0x0(%rbp),%r12d
  mov    %r12d,0x0(%rbp)
  mov    D10(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L128
L30:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L128:
  mov    %ebx,%edi
  call   <ungetch@plt>
  jmp    L30
```

assistant: ```c
int getint(int *pn) {
  int c, sign;
  while (isspace(c = getch())) {
    ;
  }
  if (!isdigit(c) && c != EOF && c != '+' && c != '-') {
    ungetch(c);
    return 0;
  }
  sign = (c == '-') ? -1 : 1;
  if (c == '+' || c == '-') {
    c = getch();
  }
  for (*pn = 0; isdigit(c); c = getch()) {
    *pn = 10 * *pn + (c - '0');
  }
  *pn *= sign;
  if (c != EOF) {
    ungetch(c);
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L93:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L93
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    D3(%rip),%r13
  test   %rax,%rax
  jne    L48
  cmp    %r12d,0x0(%r13)
  je     L48
  lea    -0x2b(%r12),%eax
  and    $0xfffffffd,%eax
  jne    L87
L48:
  cmp    $0x2d,%r12d
  je     L34
  mov    $0x1,%ebp
  cmp    $0x2b,%r12d
  je     L76
L84:
  movl   $0x0,(%rbx)
  jmp    L63
  nop
L96:
  mov    (%rbx),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%r12,%rax,2),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L63:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L96
  imul   (%rbx),%ebp
  mov    %ebp,(%rbx)
  cmp    %r12d,0x0(%r13)
  jne    L22
L61:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  mov    %r12d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    $0xffffffff,%ebp
L76:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  jmp    L84
L87:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  jmp    L61
```

assistant: ```c
int getint(int *pn) {
  int c, sign;
  while (isspace(c = getch())) {
    ;
  }
  if (!isdigit(c) && c != EOF && c != '+' && c != '-') {
    ungetch(c);
    return 0;
  }
  sign = (c == '-') ? -1 : 1;
  if (c == '+' || c == '-') {
    c = getch();
  }
  for (*pn = 0; isdigit(c); c = getch()) {
    *pn = 10 * *pn + (c - '0');
  }
  *pn *= sign;
  if (c != EOF) {
    ungetch(c);
  }
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
  mov    %r12d,%edi
  call   <isdigit@plt>
  mov    D1(%rip),%r13
  test   %rax,%rax
  jne    L109
  cmp    %r12d,0x0(%r13)
  je     L109
  lea    -0x2b(%r12),%eax
  and    $0xfffffffd,%eax
  jne    L98
L109:
  cmp    $0x2d,%r12d
  je     L14
  mov    $0x1,%ebp
  cmp    $0x2b,%r12d
  je     L60
L80:
  movl   $0x0,(%rbx)
  jmp    L37
  nop
L34:
  mov    (%rbx),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%r12,%rax,2),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
L37:
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L34
  imul   (%rbx),%ebp
  mov    %ebp,(%rbx)
  cmp    %r12d,0x0(%r13)
  jne    L66
L25:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L66:
  mov    %r12d,%edi
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%ebp
L60:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  jmp    L80
L98:
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <ungetch@plt>
  jmp    L25
```

assistant: ```c
int getint(int *pn) {
  int c, sign;
  while (isspace(c = getch())) {
    ;
  }
  if (!isdigit(c) && c != EOF && c != '+' && c != '-') {
    ungetch(c);
    return 0;
  }
  sign = (c == '-') ? -1 : 1;
  if (c == '+' || c == '-') {
    c = getch();
  }
  for (*pn = 0; isdigit(c); c = getch()) {
    *pn = 10 * *pn + (c - '0');
  }
  *pn *= sign;
  if (c != EOF) {
    ungetch(c);
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rawname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L2
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%r9
  mov    %rax,%r8
  lea    D22(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    D2(%rip),%rax
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D22
type: string

tool: D22: %.*s/r%s

assistant: ```c
const char *rawname(name) const char *name;
{
  static char rawbuf[32];
  const char *dp;
  if ((dp = strrchr(name, '/')) == 0)
    return (0);
  (void)snprintf(rawbuf, 32, "%.*s/r%s", (int)(dp - name), name, dp + 1);
  return (rawbuf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rawname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%r9
  mov    %rbx,%r8
  mov    %eax,%ecx
  sub    %ebx,%ecx
  lea    D9(%rip),%rdx
  mov    $0x20,%esi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %rbx,%rax
L0:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: %.*s/r%s

assistant: ```c
const char *rawname(name) const char *name;
{
  static char rawbuf[32];
  const char *dp;
  if ((dp = strrchr(name, '/')) == 0)
    return (0);
  (void)snprintf(rawbuf, 32, "%.*s/r%s", (int)(dp - name), name, dp + 1);
  return (rawbuf);
}
```
user: What is the c source code of the assembly code below:

```asm
<rawname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  mov    %eax,%ecx
  mov    %rbx,%r8
  lea    0x1(%rax),%r9
  mov    $0x20,%esi
  sub    %ebx,%ecx
  lea    D11(%rip),%rbx
  lea    D8(%rip),%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
L4:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: %.*s/r%s

assistant: ```c
const char *rawname(name) const char *name;
{
  static char rawbuf[32];
  const char *dp;
  if ((dp = strrchr(name, '/')) == 0)
    return (0);
  (void)snprintf(rawbuf, 32, "%.*s/r%s", (int)(dp - name), name, dp + 1);
  return (rawbuf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rawname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  mov    %eax,%ecx
  mov    %rbx,%r8
  lea    0x1(%rax),%r9
  mov    $0x20,%esi
  sub    %ebx,%ecx
  lea    D13(%rip),%rbx
  lea    D17(%rip),%rdx
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
L5:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string

tool: D17: %.*s/r%s

assistant: ```c
const char *rawname(name) const char *name;
{
  static char rawbuf[32];
  const char *dp;
  if ((dp = strrchr(name, '/')) == 0)
    return (0);
  (void)snprintf(rawbuf, 32, "%.*s/r%s", (int)(dp - name), name, dp + 1);
  return (rawbuf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L5
L2:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L37
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L18
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_matrix(double **m, int nrl, int nrh, int ncl, int nch, double a) {
  int i, j;
  for (i = nrl; i <= nrh; i++)
    for (j = ncl; j <= nch; j++)
      m[i][j] = a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_matrix>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  mov    %ecx,%edi
  cmp    %edx,%esi
  jg     L12
  movslq %esi,%rsi
  lea    (%r9,%rsi,8),%rcx
  sub    %eax,%edx
  lea    (%rdx,%rsi,1),%rax
  lea    0x8(%r9,%rax,8),%r10
  movslq %edi,%rax
  lea    0x0(,%rax,8),%r9
  mov    %r8d,%edx
  sub    %edi,%edx
  lea    0x1(%rax,%rdx,1),%rsi
  shl    $0x3,%rsi
  jmp    L7
L8:
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L8
L28:
  add    $0x8,%rcx
  cmp    %r10,%rcx
  je     L12
L7:
  mov    %r9,%rax
  cmp    %r8d,%edi
  jle    L8
  jmp    L28
L12:
  ret
```

assistant: ```c
void init_matrix(double **m, int nrl, int nrh, int ncl, int nch, double a) {
  int i, j;
  for (i = nrl; i <= nrh; i++)
    for (j = ncl; j <= nch; j++)
      m[i][j] = a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_matrix>:
  endbr64
  mov    %esi,%eax
  mov    %ecx,%esi
  cmp    %edx,%eax
  jg     L3
  movslq %eax,%r9
  sub    %eax,%edx
  lea    (%rdx,%r9,1),%rax
  mov    %r8d,%edx
  lea    (%rdi,%r9,8),%rcx
  sub    %esi,%edx
  lea    0x8(%rdi,%rax,8),%r9
  movslq %esi,%rax
  lea    0x1(%rax,%rdx,1),%rdi
  lea    0x0(,%rax,8),%r10
  shl    $0x3,%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    %r8d,%esi
  jg     L4
  mov    (%rcx),%rdx
  lea    (%rdx,%r10,1),%rax
  add    %rdi,%rdx
  nop
L22:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L22
L4:
  add    $0x8,%rcx
  cmp    %r9,%rcx
  jne    L5
L3:
  ret
```

assistant: ```c
void init_matrix(double **m, int nrl, int nrh, int ncl, int nch, double a) {
  int i, j;
  for (i = nrl; i <= nrh; i++)
    for (j = ncl; j <= nch; j++)
      m[i][j] = a;
}
```
user: What is the c source code of the assembly code below?

```asm
<init_matrix>:
  endbr64
  cmp    %edx,%esi
  jg     L15
  mov    %ecx,%r9d
  cmp    %r8d,%ecx
  jg     L15
  movslq %esi,%rcx
  sub    %esi,%edx
  mov    %rdi,%r10
  push   %r12
  lea    (%rdx,%rcx,1),%rax
  push   %rbp
  movslq %r9d,%r11
  lea    (%rdi,%rcx,8),%rdi
  lea    0x8(%r10,%rax,8),%rbp
  lea    0x1(%r8),%r10d
  push   %rbx
  shl    $0x3,%r11
  sub    %r9d,%r10d
  movapd %xmm0,%xmm1
  mov    %r10d,%ebx
  mov    %r10d,%eax
  unpcklpd %xmm1,%xmm1
  and    $0xfffffffe,%ebx
  shr    %eax
  cmp    %r8d,%r9d
  lea    (%r9,%rbx,1),%ecx
  lea    -0x1(%rax),%r12d
  cmove  %r9d,%ecx
  add    $0x1,%r12
  shl    $0x4,%r12
  movslq %ecx,%rcx
  shl    $0x3,%rcx
L17:
  mov    (%rdi),%rdx
  lea    (%rdx,%r11,1),%rax
  lea    (%r12,%rax,1),%rsi
  cmp    %r8d,%r9d
  je     L45
L20:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L20
  cmp    %ebx,%r10d
  je     L4
L45:
  movsd  %xmm0,(%rdx,%rcx,1)
L4:
  add    $0x8,%rdi
  cmp    %rbp,%rdi
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  ret
```

assistant: ```c
void init_matrix(double **m, int nrl, int nrh, int ncl, int nch, double a) {
  int i, j;
  for (i = nrl; i <= nrh; i++)
    for (j = ncl; j <= nch; j++)
      m[i][j] = a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <PlaceQueenMethodNum@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x9,-0x4(%rbp)
  jle    L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %d -> %d


assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d -> %d\n", i, PlaceQueenMethodNum(i));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L1:
  mov    %ebx,%edi
  call   <PlaceQueenMethodNum@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %d -> %d


assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d -> %d\n", i, PlaceQueenMethodNum(i));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <PlaceQueenMethodNum@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %d -> %d


assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d -> %d\n", i, PlaceQueenMethodNum(i));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <PlaceQueenMethodNum@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: %d -> %d


assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 10; ++i)
    printf("%d -> %d\n", i, PlaceQueenMethodNum(i));
  return 0;
}
```