ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D34(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  jle    L56
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L27
  lea    D8(%rip),%rbx
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
L64:
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L27
L60:
  add    $0x1,%r12d
  test   $0x1,%al
  je     L26
  lea    0x1(%rax,%rax,2),%esi
  jmp    L64
L27:
  mov    %r12d,%edx
  mov    $0x1,%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
L56:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D57
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D37
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D34: Inital value: 

tool: D24: %d

tool: D57: Initial value is %d


tool: D8: Next value is %d


tool: D37: Final value %d, number of steps %d


tool: D7: Error.

assistant: ```c
int main() {
  int init, steps;
  steps = 0;
  printf("Inital value: ");
  scanf("%d", &init);
  if (init < 2) {
    printf("Error.");
  } else {
    printf("Initial value is %d\n", init);
    while (init != 1) {
      steps++;
      if (init % 2 == 0) {
        init = init / 2;
        printf("Next value is %d\n", init);
      } else {
        init = (init * 3) + 1;
        printf("Next value is %d\n", init);
      }
    }
    printf("Final value %d, number of steps %d\n", init, steps);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<medium_frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <small_frame@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void medium_frame() {
  char S[16384];
  small_frame();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<medium_frame>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <small_frame@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void medium_frame() {
  char S[16384];
  small_frame();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<medium_frame>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <small_frame@plt>
```

assistant: ```c
void medium_frame() {
  char S[16384];
  small_frame();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<medium_frame>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <small_frame@plt>
```

assistant: ```c
void medium_frame() {
  char S[16384];
  small_frame();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fib_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L1
  mov    -0x14(%rbp),%eax
  jmp    L8
L1:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib_serial>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib_serial>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
L8:
  leave
  ret
```

assistant: ```c
int fib_serial(int n) {
  int x = 0, y = 0;
  if (n < 2)
    return n;
  else {
    x = fib_serial(n - 1);
    y = fib_serial(n - 2);
    return (x + y);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fib_serial>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L5
L15:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    -0x1(%rdi),%edi
  call   <fib_serial>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib_serial>
  lea    0x0(%rbp,%rax,1),%ebx
  jmp    L15
```

assistant: ```c
int fib_serial(int n) {
  int x = 0, y = 0;
  if (n < 2)
    return n;
  else {
    x = fib_serial(n - 1);
    y = fib_serial(n - 2);
    return (x + y);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<irealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <imalloc@plt>
  jmp    L12
L6:
  cmpl   $0x0,-0xc(%rbp)
  jne    L16
  movl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
L12:
  leave
  ret
```

assistant: ```c
char *irealloc(char *pointer, int size) {
  if (((pointer) == NULL))
    return imalloc(size);
  if (size == 0)
    size = 1;
  return realloc(pointer, (unsigned)size);
}
```
user: What is the c source code of the assembly code below:

```asm
<irealloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  test   %esi,%esi
  mov    $0x1,%eax
  cmove  %eax,%esi
  call   <realloc@plt>
L15:
  add    $0x8,%rsp
  ret
L16:
  mov    %esi,%edi
  call   <imalloc@plt>
  jmp    L15
```

assistant: ```c
char *irealloc(char *pointer, int size) {
  if (((pointer) == NULL))
    return imalloc(size);
  if (size == 0)
    size = 1;
  return realloc(pointer, (unsigned)size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<irealloc>:
  endbr64
  test   %rdi,%rdi
  je     L0
  test   %esi,%esi
  mov    $0x1,%eax
  cmove  %eax,%esi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %esi,%edi
  jmp    1060 <imalloc@plt>
```

assistant: ```c
char *irealloc(char *pointer, int size) {
  if (((pointer) == NULL))
    return imalloc(size);
  if (size == 0)
    size = 1;
  return realloc(pointer, (unsigned)size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<irealloc>:
  endbr64
  test   %rdi,%rdi
  je     L6
  test   %esi,%esi
  mov    $0x1,%eax
  cmove  %eax,%esi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %esi,%edi
  jmp    1060 <imalloc@plt>
```

assistant: ```c
char *irealloc(char *pointer, int size) {
  if (((pointer) == NULL))
    return imalloc(size);
  if (size == 0)
    size = 1;
  return realloc(pointer, (unsigned)size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L7:
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <fprime@plt>
  movd   %xmm0,%eax
  pxor   %xmm0,%xmm0
  movd   %eax,%xmm2
  ucomiss %xmm0,%xmm2
  jp     L55
  pxor   %xmm0,%xmm0
  movd   %eax,%xmm3
  ucomiss %xmm0,%xmm3
  jne    L55
  mov    $0xffffffff,%eax
  jmp    L19
L55:
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <f@plt>
  movd   %xmm0,%ebx
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <fprime@plt>
  movd   %ebx,%xmm1
  divss  %xmm0,%xmm1
  movss  -0x1c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x24(%rbp)
  movss  -0x24(%rbp),%xmm0
  subss  -0x1c(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm4
  comisd D32(%rip),%xmm4
  jbe    L16
  addl   $0x1,-0x20(%rbp)
  cmpl   $0x270f,-0x20(%rbp)
  jle    L7
L16:
  cmpl   $0x2710,-0x20(%rbp)
  jle    L44
  mov    $0xffffffff,%eax
  jmp    L19
L44:
  movss  -0x24(%rbp),%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm0,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L19:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D42
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: f64
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D18: 
DOWN THE TOILET COMPANY

tool: D42: 
Newton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993

tool: D8: 
Please enter initial value:

tool: D35: %f

tool: D32: 1e-06

tool: D5: 
The zero found is: %.5f

assistant: ```c
int main() {
  int iter = 0;
  float xnew, xold;
  printf("\nDOWN THE TOILET COMPANY");
  printf("\nNewton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993");
  printf("\nPlease enter initial value:");
  scanf("%f", &xnew);
  do {
    xold = xnew;
    if (fprime(xold) == 0)
      return -1;
    xnew = xold - f(xold) / fprime(xold);
  } while ((fabs(xnew - xold) > 0.000001) && (++iter < 10000));
  if (iter > 10000)
    return -1;
  printf("\nThe zero found is: %.5f", xnew);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
L51:
  mov    0x14(%rsp),%ebx
  movd   %ebx,%xmm0
  call   <fprime@plt>
  pxor   %xmm2,%xmm2
  ucomiss %xmm2,%xmm0
  jp     L76
  je     L20
L76:
  movd   %ebx,%xmm0
  call   <f@plt>
  movss  %xmm0,0xc(%rsp)
  movd   %ebx,%xmm0
  call   <fprime@plt>
  movss  0xc(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movd   %ebx,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x14(%rsp)
  movd   %ebx,%xmm3
  subss  %xmm3,%xmm0
  call   <fabs@plt>
  comisd D36(%rip),%xmm0
  jbe    L78
  add    $0x1,%ebp
  cmp    $0x2710,%ebp
  jne    L51
  jmp    L16
L78:
  cmp    $0x2710,%ebp
  jg     L60
L16:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x14(%rsp),%xmm0
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L88:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0xffffffff,%eax
  jmp    L88
L60:
  mov    $0xffffffff,%eax
  jmp    L88
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D48
data_type: string
name: read_data
arguments: label: D40
data_type: string
name: read_data
arguments: label: D36
data_type: f64
name: read_data
arguments: label: D5
data_type: string

tool: D4: 
DOWN THE TOILET COMPANY

tool: D21: 
Newton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993

tool: D48: 
Please enter initial value:

tool: D40: %f

tool: D36: 1e-06

tool: D5: 
The zero found is: %.5f

assistant: ```c
int main() {
  int iter = 0;
  float xnew, xold;
  printf("\nDOWN THE TOILET COMPANY");
  printf("\nNewton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993");
  printf("\nPlease enter initial value:");
  scanf("%f", &xnew);
  do {
    xold = xnew;
    if (fprime(xold) == 0)
      return -1;
    xnew = xold - f(xold) / fprime(xold);
  } while ((fabs(xnew - xold) > 0.000001) && (++iter < 10000));
  if (iter > 10000)
    return -1;
  printf("\nThe zero found is: %.5f", xnew);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D35(%rip),%rdi
  mov    $0x2710,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  jmp    L7
  nopl   0x0(%rax)
L15:
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <f@plt>
  movss  0x8(%rsp),%xmm1
  movss  %xmm0,0xc(%rsp)
  movaps %xmm1,%xmm0
  call   <fprime@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  divss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  movss  %xmm0,0x14(%rsp)
  subss  %xmm1,%xmm0
  call   <fabs@plt>
  comisd D52(%rip),%xmm0
  jbe    L58
  sub    $0x1,%ebx
  je     L58
L7:
  movss  0x14(%rsp),%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <fprime@plt>
  pxor   %xmm3,%xmm3
  movss  0x8(%rsp),%xmm1
  ucomiss %xmm3,%xmm0
  jp     L15
  jne    L15
  or     $0xffffffff,%eax
  jmp    L43
L58:
  pxor   %xmm0,%xmm0
  lea    D54(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0x14(%rsp),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
L43:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x20,%rsp
  pop    %rbx
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D52
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D54
type_guessed: string

tool: D35: 
DOWN THE TOILET COMPANY

tool: D6: 
Newton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993

tool: D23: 
Please enter initial value:

tool: D11: %f

tool: D52: 1e-06

tool: D54: 
The zero found is: %.5f

assistant: ```c
int main() {
  int iter = 0;
  float xnew, xold;
  printf("\nDOWN THE TOILET COMPANY");
  printf("\nNewton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993");
  printf("\nPlease enter initial value:");
  scanf("%f", &xnew);
  do {
    xold = xnew;
    if (fprime(xold) == 0)
      return -1;
    xnew = xold - f(xold) / fprime(xold);
  } while ((fabs(xnew - xold) > 0.000001) && (++iter < 10000));
  if (iter > 10000)
    return -1;
  printf("\nThe zero found is: %.5f", xnew);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  mov    $0x2710,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  jmp    L10
  nopl   0x0(%rax)
L49:
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <f@plt>
  movss  0x8(%rsp),%xmm1
  movss  %xmm0,0xc(%rsp)
  movaps %xmm1,%xmm0
  call   <fprime@plt>
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  divss  %xmm0,%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  movss  %xmm0,0x14(%rsp)
  subss  %xmm1,%xmm0
  call   <fabs@plt>
  comisd D5(%rip),%xmm0
  jbe    L62
  sub    $0x1,%ebx
  je     L62
L10:
  movss  0x14(%rsp),%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <fprime@plt>
  pxor   %xmm3,%xmm3
  movss  0x8(%rsp),%xmm1
  ucomiss %xmm3,%xmm0
  jp     L49
  jne    L49
  or     $0xffffffff,%eax
  jmp    L0
L62:
  pxor   %xmm0,%xmm0
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd 0x14(%rsp),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0x20,%rsp
  pop    %rbx
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D54
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: f64
name: extract_symbolic_data
arguments: tag: D39
type_infered: string

tool: D13: 
DOWN THE TOILET COMPANY

tool: D54: 
Newton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993

tool: D14: 
Please enter initial value:

tool: D2: %f

tool: D5: 1e-06

tool: D39: 
The zero found is: %.5f

assistant: ```c
int main() {
  int iter = 0;
  float xnew, xold;
  printf("\nDOWN THE TOILET COMPANY");
  printf("\nNewton-Raphson to find zero of f(x) = x^3 - 0.165x^2 + 0.0003993");
  printf("\nPlease enter initial value:");
  scanf("%f", &xnew);
  do {
    xold = xnew;
    if (fprime(xold) == 0)
      return -1;
    xnew = xold - f(xold) / fprime(xold);
  } while ((fabs(xnew - xold) > 0.000001) && (++iter < 10000));
  if (iter > 10000)
    return -1;
  printf("\nThe zero found is: %.5f", xnew);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_mem_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L28
L36:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L38
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L48
L34:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L34
  mov    $0x5,%edi
  call   <exit@plt>
L38:
  addl   $0x1,-0x18(%rbp)
L28:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L36
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: Initialize memory fail!


assistant: ```c
void init_mem_int(int *p[], int n, int *cell_pt[]) {
  for (int k = 0; k < n; ++k) {
    p[k] = malloc(cell_pt[k][0] * sizeof(int));
    if (p[k] == NULL) {
      printf("Initialize memory fail!\n");
      for (int j = 0; j < k; j++) {
        free(p[k]);
        p[k] = NULL;
      }
      exit(5);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_mem_int>:
  endbr64
  test   %esi,%esi
  jle    L54
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r14
  mov    %esi,%r13d
  mov    $0x0,%ebx
L44:
  mov    (%r14,%rbx,8),%rax
  mov    (%rax),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  je     L53
L58:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L44
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%r15d
  test   %ebx,%ebx
  jle    L27
  mov    $0x0,%r12d
L37:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%rbp,%rbx,8)
  add    $0x1,%r12d
  cmp    %r15d,%r12d
  jne    L37
L27:
  mov    $0x5,%edi
  call   <exit@plt>
  jmp    L58
L54:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: Initialize memory fail!


assistant: ```c
void init_mem_int(int *p[], int n, int *cell_pt[]) {
  for (int k = 0; k < n; ++k) {
    p[k] = malloc(cell_pt[k][0] * sizeof(int));
    if (p[k] == NULL) {
      printf("Initialize memory fail!\n");
      for (int j = 0; j < k; j++) {
        free(p[k]);
        p[k] = NULL;
      }
      exit(5);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_mem_int>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r15
  push   %r14
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L37:
  mov    (%r12,%rbx,8),%rax
  mov    (%rax),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  je     L1
L12:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    D6(%rip),%rdi
  mov    %ebx,%r15d
  call   <printf@plt>
  test   %rbx,%rbx
  je     L52
  mov    0x0(%rbp,%rbx,8),%rdi
  xor    %r14d,%r14d
  jmp    L45
  xchg   %ax,%ax
L21:
  xor    %edi,%edi
L45:
  call   <free@plt>
  add    $0x1,%r14d
  movq   $0x0,0x0(%rbp,%rbx,8)
  cmp    %r15d,%r14d
  jne    L21
L52:
  mov    $0x5,%edi
  call   <exit@plt>
  jmp    L12
  nopl   (%rax)
L5:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Initialize memory fail!


assistant: ```c
void init_mem_int(int *p[], int n, int *cell_pt[]) {
  for (int k = 0; k < n; ++k) {
    p[k] = malloc(cell_pt[k][0] * sizeof(int));
    if (p[k] == NULL) {
      printf("Initialize memory fail!\n");
      for (int j = 0; j < k; j++) {
        free(p[k]);
        p[k] = NULL;
      }
      exit(5);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_mem_int>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdx),%rax
  mov    (%rax),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  jne    L14
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <exit@plt>
L14:
  movslq %r15d,%r13
  mov    $0x1,%ebx
  lea    D18(%rip),%r14
  cmp    $0x1,%r15d
  je     L27
  nopl   0x0(%rax)
L74:
  mov    (%r12,%rbx,8),%rax
  mov    (%rax),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  je     L42
L29:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L74
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r14,%rdi
  xor    %r15d,%r15d
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L72:
  xor    %edi,%edi
L69:
  call   <free@plt>
  add    $0x1,%r15d
  movq   $0x0,0x0(%rbp,%rbx,8)
  cmp    %ebx,%r15d
  jl     L72
  mov    $0x5,%edi
  call   <exit@plt>
  jmp    L29
  nopl   (%rax)
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string

tool: D18: Initialize memory fail!


assistant: ```c
void init_mem_int(int *p[], int n, int *cell_pt[]) {
  for (int k = 0; k < n; ++k) {
    p[k] = malloc(cell_pt[k][0] * sizeof(int));
    if (p[k] == NULL) {
      printf("Initialize memory fail!\n");
      for (int j = 0; j < k; j++) {
        free(p[k]);
        p[k] = NULL;
      }
      exit(5);
    }
  }
}
```