ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x9,%esi
  jle    L21
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L21:
  movl   $0x9,0x4(%rsp)
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D29
data_type: string

tool: D30: Enter a number 

tool: D23: %d

tool: D12: %d is larger than 9 


tool: D29: Your input was 9 

assistant: ```c
void main() {
  int var;
  printf("Enter a number \n");
  scanf("%d", &var);
  if (var > 9)
    printf("%d is larger than 9 \n", var);
  else if (var = 9)
    printf("Your input was 9 \n");
  else
    printf("%d is smaller than 9 \n", var);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x9,%esi
  jle    L26
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L26:
  lea    D32(%rip),%rdi
  movl   $0x9,0x4(%rsp)
  call   <puts@plt>
  jmp    L22
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D30
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D32
type_guessed: string

tool: D30: Enter a number 

tool: D13: %d

tool: D2: %d is larger than 9 


tool: D32: Your input was 9 

assistant: ```c
void main() {
  int var;
  printf("Enter a number \n");
  scanf("%d", &var);
  if (var > 9)
    printf("%d is larger than 9 \n", var);
  else if (var = 9)
    printf("Your input was 9 \n");
  else
    printf("%d is smaller than 9 \n", var);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x9,%esi
  jle    L11
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L11:
  lea    D24(%rip),%rdi
  movl   $0x9,0x4(%rsp)
  call   <puts@plt>
  jmp    L7
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D30
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string

tool: D23: Enter a number 

tool: D30: %d

tool: D21: %d is larger than 9 


tool: D24: Your input was 9 

assistant: ```c
void main() {
  int var;
  printf("Enter a number \n");
  scanf("%d", &var);
  if (var > 9)
    printf("%d is larger than 9 \n", var);
  else if (var = 9)
    printf("Your input was 9 \n");
  else
    printf("%d is smaller than 9 \n", var);
}
```
user: Translate the below assembly code into C programming language:

```asm
<http_header_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L27
  cmpl   $0x10,-0x24(%rbp)
  jg     L27
  cmpq   $0x0,-0x30(%rbp)
  jne    L59
L27:
  mov    $0xffffffff,%eax
  jmp    L50
L59:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <get_http_header_str@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L40
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L40:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
L50:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int http_header_size(int code, char *value) {
  char *name;
  int len = 0;
  if (code < 0 || code > 16 || value == NULL) {
    return -1;
  }
  if ((name = get_http_header_str(code)) == NULL) {
    free(name);
    return -1;
  }
  len = strlen(name) + 2 + strlen(value) + 2;
  free(name);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<http_header_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x10,%edi
  ja     L26
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L26
  call   <get_http_header_str@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x4(%r12,%rax,1),%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L11:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x0,%edi
  call   <free@plt>
  mov    $0xffffffff,%ebp
  jmp    L11
L26:
  mov    $0xffffffff,%ebp
  jmp    L11
```

assistant: ```c
int http_header_size(int code, char *value) {
  char *name;
  int len = 0;
  if (code < 0 || code > 16 || value == NULL) {
    return -1;
  }
  if ((name = get_http_header_str(code)) == NULL) {
    free(name);
    return -1;
  }
  len = strlen(name) + 2 + strlen(value) + 2;
  free(name);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<http_header_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x10,%edi
  ja     L32
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L32
  call   <get_http_header_str@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x4(%rbx,%rax,1),%r12d
  call   <free@plt>
L7:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  mov    $0xffffffff,%r12d
  jmp    L7
L18:
  xor    %edi,%edi
  mov    $0xffffffff,%r12d
  call   <free@plt>
  jmp    L7
```

assistant: ```c
int http_header_size(int code, char *value) {
  char *name;
  int len = 0;
  if (code < 0 || code > 16 || value == NULL) {
    return -1;
  }
  if ((name = get_http_header_str(code)) == NULL) {
    free(name);
    return -1;
  }
  len = strlen(name) + 2 + strlen(value) + 2;
  free(name);
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<http_header_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x10,%edi
  ja     L3
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L3
  call   <get_http_header_str@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L25
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    0x4(%rbx,%rax,1),%r12d
  call   <free@plt>
L33:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xffffffff,%r12d
  jmp    L33
L25:
  xor    %edi,%edi
  mov    $0xffffffff,%r12d
  call   <free@plt>
  jmp    L33
```

assistant: ```c
int http_header_size(int code, char *value) {
  char *name;
  int len = 0;
  if (code < 0 || code > 16 || value == NULL) {
    return -1;
  }
  if ((name = get_http_header_str(code)) == NULL) {
    free(name);
    return -1;
  }
  len = strlen(name) + 2 + strlen(value) + 2;
  free(name);
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isUDP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x11,-0x4(%rbp)
  jne    L5
  mov    $0x1,%eax
  jmp    L14
L5:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int isUDP(unsigned char b) {
  if (b == 0x11) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isUDP>:
  endbr64
  cmp    $0x11,%dil
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isUDP(unsigned char b) {
  if (b == 0x11) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isUDP>:
  endbr64
  xor    %eax,%eax
  cmp    $0x11,%dil
  sete   %al
  ret
```

assistant: ```c
int isUDP(unsigned char b) {
  if (b == 0x11) {
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isUDP>:
  endbr64
  xor    %eax,%eax
  cmp    $0x11,%dil
  sete   %al
  ret
```

assistant: ```c
int isUDP(unsigned char b) {
  if (b == 0x11) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pack754>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jp     L88
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jne    L88
  mov    $0x0,%eax
  jmp    L81
L88:
  fldt   0x10(%rbp)
  fldz
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L54
  movq   $0x1,-0x28(%rbp)
  fldt   0x10(%rbp)
  fchs
  fstpt  -0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%edx
  mov    %rax,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  jmp    L75
L54:
  movq   $0x0,-0x28(%rbp)
  fldt   0x10(%rbp)
  fstpt  -0x10(%rbp)
L75:
  movl   $0x0,-0x30(%rbp)
  jmp    L14
L32:
  fldt   -0x10(%rbp)
  fldt   0xe82(%rip)        # 2000 <_fini+0xdac>
  fdivrp %st,%st(1)
  fstpt  -0x10(%rbp)
  addl   $0x1,-0x30(%rbp)
L14:
  fldt   0xe73(%rip)        # 2000 <_fini+0xdac>
  fldt   -0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jae    L32
  jmp    L27
L42:
  fldt   -0x10(%rbp)
  fadd   %st(0),%st
  fstpt  -0x10(%rbp)
  subl   $0x1,-0x30(%rbp)
L27:
  fldt   -0x10(%rbp)
  fld1
  fcomip %st(1),%st
  fstp   %st(0)
  ja     L42
  fldt   -0x10(%rbp)
  fld1
  fsubrp %st,%st(1)
  fstpt  -0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  D4(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x50(%rbp)
  flds   -0x50(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fnstcw -0x3a(%rbp)
  movzwl -0x3a(%rbp),%eax
  or     $0xc,%ah
  mov    %ax,-0x3c(%rbp)
  fldcw  -0x3c(%rbp)
  fistpll -0x20(%rbp)
  fldcw  -0x3a(%rbp)
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    -0x34(%rbp),%eax
  sub    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  or     %rsi,%rax
  or     -0x20(%rbp),%rax
L81:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x3f]}

assistant: ```c
unsigned long long int pack754(long double f, unsigned bits, unsigned expbits) {
  long double fnorm;
  int shift;
  long long sign, exp, significand;
  unsigned significandbits = bits - expbits - 1;
  if (f == 0.0)
    return 0;
  if (f < 0) {
    sign = 1;
    fnorm = -f;
  } else {
    sign = 0;
    fnorm = f;
  }
  shift = 0;
  while (fnorm >= 2.0) {
    fnorm /= 2.0;
    shift++;
  }
  while (fnorm < 1.0) {
    fnorm *= 2.0;
    shift--;
  }
  fnorm = fnorm - 1.0;
  significand = fnorm * ((1LL << significandbits) + 0.5f);
  exp = shift + ((1 << (expbits - 1)) - 1);
  return (sign << (bits - 1)) | (exp << (bits - expbits - 1)) | significand;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pack754>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  mov    %edi,%edx
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L80
  mov    $0x0,%eax
  je     L50
L80:
  fldz
  mov    $0x0,%r8d
  fcomip %st(1),%st
  ja     L88
L107:
  mov    $0x0,%eax
  flds   0xed3(%rip)        # 2004 <_fini+0xdfc>
  flds   0xec9(%rip)        # 2000 <_fini+0xdf8>
  fld    %st(0)
  fxch   %st(3)
  fcomi  %st(3),%st
  fstp   %st(3)
  jb     L105
  fxch   %st(2)
L25:
  fmul   %st(1),%st
  add    $0x1,%eax
  fld    %st(2)
  fxch   %st(1)
  fcomi  %st(1),%st
  fstp   %st(1)
  jae    L25
  fstp   %st(1)
  fstp   %st(1)
L47:
  fld1
  fcomi  %st(1),%st
  jbe    L81
  fxch   %st(1)
  jmp    L102
L112:
  fxch   %st(1)
L102:
  fadd   %st(0),%st
  fxch   %st(1)
  sub    $0x1,%eax
  fcomi  %st(1),%st
  ja     L112
  fstp   %st(0)
  jmp    L6
L81:
  fstp   %st(0)
L6:
  mov    %edx,%edi
  sub    %esi,%edi
  sub    $0x1,%edi
  mov    $0x1,%r9d
  mov    %edi,%ecx
  shl    %cl,%r9
  pxor   %xmm0,%xmm0
  cvtsi2ss %r9,%xmm0
  addss  D4(%rip),%xmm0
  movss  %xmm0,-0x18(%rsp)
  fld1
  fsubrp %st,%st(1)
  fmuls  -0x18(%rsp)
  fnstcw -0xa(%rsp)
  movzwl -0xa(%rsp),%ecx
  or     $0xc,%ch
  mov    %cx,-0xc(%rsp)
  fldcw  -0xc(%rsp)
  fistpll -0x18(%rsp)
  fldcw  -0xa(%rsp)
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%esi
  shl    %cl,%esi
  lea    -0x1(%rax,%rsi,1),%eax
  cltq
  mov    %edi,%ecx
  shl    %cl,%rax
  or     -0x18(%rsp),%rax
  lea    -0x1(%rdx),%ecx
  shl    %cl,%r8
  or     %r8,%rax
  jmp    L16
L50:
  fstp   %st(0)
L16:
  ret
L88:
  fchs
  mov    $0x1,%r8d
  jmp    L107
L105:
  fstp   %st(0)
  fstp   %st(0)
  mov    $0x0,%eax
  jmp    L47
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x3f]}

assistant: ```c
unsigned long long int pack754(long double f, unsigned bits, unsigned expbits) {
  long double fnorm;
  int shift;
  long long sign, exp, significand;
  unsigned significandbits = bits - expbits - 1;
  if (f == 0.0)
    return 0;
  if (f < 0) {
    sign = 1;
    fnorm = -f;
  } else {
    sign = 0;
    fnorm = f;
  }
  shift = 0;
  while (fnorm >= 2.0) {
    fnorm /= 2.0;
    shift++;
  }
  while (fnorm < 1.0) {
    fnorm *= 2.0;
    shift--;
  }
  fnorm = fnorm - 1.0;
  significand = fnorm * ((1LL << significandbits) + 0.5f);
  exp = shift + ((1 << (expbits - 1)) - 1);
  return (sign << (bits - 1)) | (exp << (bits - expbits - 1)) | significand;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pack754>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L76
  mov    $0x0,%eax
  je     L90
L76:
  fldz
  xor    %r8d,%r8d
  fcomip %st(1),%st
  ja     L88
L119:
  flds   0xed2(%rip)        # 2000 <_fini+0xde4>
  xor    %eax,%eax
  fld    %st(0)
  flds   0xecc(%rip)        # 2004 <_fini+0xde8>
  fxch   %st(3)
  fcomi  %st(1),%st
  fstp   %st(1)
  jb     L39
L68:
  fmul   %st(2),%st
  add    $0x1,%eax
  fld    %st(1)
  fxch   %st(1)
  fcomi  %st(1),%st
  fstp   %st(1)
  jae    L68
  fstp   %st(1)
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L39:
  fstp   %st(1)
  nopw   0x0(%rax,%rax,1)
L51:
  fld1
  fcomi  %st(1),%st
  jbe    L100
  fxch   %st(1)
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L98:
  fxch   %st(1)
L115:
  fadd   %st(0),%st
  fxch   %st(1)
  sub    $0x1,%eax
  fcomi  %st(1),%st
  ja     L98
  fstp   %st(0)
  fxch   %st(1)
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L100:
  fstp   %st(0)
  fxch   %st(1)
  nopl   0x0(%rax)
L73:
  sub    %esi,%edi
  mov    $0x1,%edx
  pxor   %xmm0,%xmm0
  fstps  -0x18(%rsp)
  fnstcw -0xa(%rsp)
  sub    $0x1,%edi
  movss  -0x18(%rsp),%xmm1
  fld1
  mov    %edi,%ecx
  fsubrp %st,%st(1)
  shl    %cl,%rdx
  lea    -0x1(%rsi),%ecx
  cvtsi2ss %rdx,%xmm0
  movzwl -0xa(%rsp),%edx
  or     $0xc,%dh
  mov    %dx,-0xc(%rsp)
  mov    $0x1,%edx
  addss  %xmm0,%xmm1
  shl    %cl,%edx
  mov    %edi,%ecx
  lea    -0x1(%rax,%rdx,1),%eax
  cltq
  movss  %xmm1,-0x18(%rsp)
  fmuls  -0x18(%rsp)
  shl    %cl,%rax
  fldcw  -0xc(%rsp)
  fistpll -0x18(%rsp)
  fldcw  -0xa(%rsp)
  or     -0x18(%rsp),%rax
  or     %r8,%rax
  jmp    L53
L90:
  fstp   %st(0)
L53:
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  lea    -0x1(%rdi),%ecx
  fchs
  mov    $0x1,%r8d
  shl    %cl,%r8
  jmp    L119
```

assistant: ```c
unsigned long long int pack754(long double f, unsigned bits, unsigned expbits) {
  long double fnorm;
  int shift;
  long long sign, exp, significand;
  unsigned significandbits = bits - expbits - 1;
  if (f == 0.0)
    return 0;
  if (f < 0) {
    sign = 1;
    fnorm = -f;
  } else {
    sign = 0;
    fnorm = f;
  }
  shift = 0;
  while (fnorm >= 2.0) {
    fnorm /= 2.0;
    shift++;
  }
  while (fnorm < 1.0) {
    fnorm *= 2.0;
    shift--;
  }
  fnorm = fnorm - 1.0;
  significand = fnorm * ((1LL << significandbits) + 0.5f);
  exp = shift + ((1 << (expbits - 1)) - 1);
  return (sign << (bits - 1)) | (exp << (bits - expbits - 1)) | significand;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pack754>:
  endbr64
  fldz
  fldt   0x8(%rsp)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L9
  mov    $0x0,%eax
  je     L110
L9:
  fldz
  xor    %r8d,%r8d
  fcomip %st(1),%st
  ja     L20
L103:
  flds   0xed2(%rip)        # 2000 <_fini+0xde4>
  xor    %eax,%eax
  fld    %st(0)
  flds   0xecc(%rip)        # 2004 <_fini+0xde8>
  fxch   %st(3)
  fcomi  %st(1),%st
  fstp   %st(1)
  jb     L105
L34:
  fmul   %st(2),%st
  add    $0x1,%eax
  fld    %st(1)
  fxch   %st(1)
  fcomi  %st(1),%st
  fstp   %st(1)
  jae    L34
  fstp   %st(1)
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L105:
  fstp   %st(1)
  nopw   0x0(%rax,%rax,1)
L88:
  fld1
  fcomi  %st(1),%st
  jbe    L29
  fxch   %st(1)
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L14:
  fxch   %st(1)
L83:
  fadd   %st(0),%st
  fxch   %st(1)
  sub    $0x1,%eax
  fcomi  %st(1),%st
  ja     L14
  fstp   %st(0)
  fxch   %st(1)
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L29:
  fstp   %st(0)
  fxch   %st(1)
  nopl   0x0(%rax)
L52:
  sub    %esi,%edi
  mov    $0x1,%edx
  pxor   %xmm0,%xmm0
  fstps  -0x18(%rsp)
  fnstcw -0xa(%rsp)
  sub    $0x1,%edi
  movss  -0x18(%rsp),%xmm1
  fld1
  mov    %edi,%ecx
  fsubrp %st,%st(1)
  shl    %cl,%rdx
  lea    -0x1(%rsi),%ecx
  cvtsi2ss %rdx,%xmm0
  movzwl -0xa(%rsp),%edx
  or     $0xc,%dh
  mov    %dx,-0xc(%rsp)
  mov    $0x1,%edx
  addss  %xmm0,%xmm1
  shl    %cl,%edx
  mov    %edi,%ecx
  lea    -0x1(%rax,%rdx,1),%eax
  cltq
  movss  %xmm1,-0x18(%rsp)
  fmuls  -0x18(%rsp)
  shl    %cl,%rax
  fldcw  -0xc(%rsp)
  fistpll -0x18(%rsp)
  fldcw  -0xa(%rsp)
  or     -0x18(%rsp),%rax
  or     %r8,%rax
  jmp    L115
L110:
  fstp   %st(0)
L115:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  lea    -0x1(%rdi),%ecx
  fchs
  mov    $0x1,%r8d
  shl    %cl,%r8
  jmp    L103
```

assistant: ```c
unsigned long long int pack754(long double f, unsigned bits, unsigned expbits) {
  long double fnorm;
  int shift;
  long long sign, exp, significand;
  unsigned significandbits = bits - expbits - 1;
  if (f == 0.0)
    return 0;
  if (f < 0) {
    sign = 1;
    fnorm = -f;
  } else {
    sign = 0;
    fnorm = f;
  }
  shift = 0;
  while (fnorm >= 2.0) {
    fnorm /= 2.0;
    shift++;
  }
  while (fnorm < 1.0) {
    fnorm *= 2.0;
    shift--;
  }
  fnorm = fnorm - 1.0;
  significand = fnorm * ((1LL << significandbits) + 0.5f);
  exp = shift + ((1 << (expbits - 1)) - 1);
  return (sign << (bits - 1)) | (exp << (bits - expbits - 1)) | significand;
}
```
user: What is the c source code of the assembly code below:

```asm
<in_chksum_ip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xe,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x12,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  subl   $0x14,-0x1c(%rbp)
  addq   $0x14,-0x18(%rbp)
  jmp    L3
L17:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x4,-0x18(%rbp)
  subl   $0x4,-0x1c(%rbp)
L3:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short in_chksum_ip(unsigned short *w, int blen) {
  unsigned int cksum;
  cksum = w[0];
  cksum += w[1];
  cksum += w[2];
  cksum += w[3];
  cksum += w[4];
  cksum += w[5];
  cksum += w[6];
  cksum += w[7];
  cksum += w[8];
  cksum += w[9];
  blen -= 20;
  w += 10;
  while (blen) {
    cksum += w[0];
    cksum += w[1];
    w += 2;
    blen -= 4;
  }
  cksum = (cksum >> 16) + (cksum & 0x0000ffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<in_chksum_ip>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x4(%rdi),%eax
  add    %ecx,%eax
  movzwl 0x6(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x8(%rdi),%eax
  add    %ecx,%eax
  movzwl 0xa(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0xc(%rdi),%eax
  add    %ecx,%eax
  movzwl 0xe(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x10(%rdi),%eax
  add    %ecx,%eax
  movzwl 0x12(%rdi),%ecx
  add    %eax,%ecx
  lea    0x14(%rdi),%rax
  cmp    $0x14,%esi
  je     L18
  lea    -0x18(%rsi),%esi
  lea    0x18(%rdi,%rsi,1),%rdi
L10:
  movzwl (%rax),%edx
  movzwl 0x2(%rax),%esi
  add    %esi,%edx
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L10
L18:
  mov    %ecx,%edx
  shr    $0x10,%edx
  movzwl %cx,%ecx
  add    %ecx,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned short in_chksum_ip(unsigned short *w, int blen) {
  unsigned int cksum;
  cksum = w[0];
  cksum += w[1];
  cksum += w[2];
  cksum += w[3];
  cksum += w[4];
  cksum += w[5];
  cksum += w[6];
  cksum += w[7];
  cksum += w[8];
  cksum += w[9];
  blen -= 20;
  w += 10;
  while (blen) {
    cksum += w[0];
    cksum += w[1];
    w += 2;
    blen -= 4;
  }
  cksum = (cksum >> 16) + (cksum & 0x0000ffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```