user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insert_student>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r15,%rsi
  lea    D40(%rip),%rdi
  call   <scanf@plt>
  lea    0x4(%r15),%rax
  mov    %rax,(%rsp)
  movl   $0x1,0x8(%rsp)
  mov    $0x0,%ebp
  lea    D40(%rip),%r12
  jmp    L32
L3:
  add    $0x1,%ebp
L28:
  cmp    %r13d,%ebp
  jge    L114
L135:
  movslq %ebp,%rax
  shl    $0x4,%rax
  mov    (%r15,%rax,1),%eax
  cmp    %eax,0xc(%rbx)
  jne    L3
  mov    0xc(%rsp),%esi
  lea    D107(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  jmp    L28
L83:
  mov    $0x0,%ebp
L114:
  addq   $0x10,(%rsp)
L32:
  mov    0x8(%rsp),%esi
  mov    %esi,%r13d
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%r14
  mov    %r14,%rbx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%r14),%eax
  mov    %eax,0xc(%rsp)
  sub    $0x12,%eax
  cmp    $0x11,%eax
  jbe    L86
  lea    D7(%rip),%r14
L108:
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x12,%eax
  cmp    $0x11,%eax
  ja     L108
L86:
  mov    %r13d,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    0x4(%rax),%r14
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L5
L53:
  lea    D102(%rip),%rdi
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x1,%eax
  ja     L53
L5:
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    0x8(%rax),%r14
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq %ebp,%rbp
  shl    $0x4,%rbp
  add    %r15,%rbp
  jmp    L67
L45:
  lea    D98(%rip),%rdi
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
L67:
  cmpl   $0x0,0x8(%rbx)
  jle    L45
  cmpl   $0xa,0xc(%rbp)
  jg     L45
  cmpl   $0x3,0x8(%rsp)
  je     L92
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%esi
  mov    %esi,0xc(%rsp)
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    0xc(%rax),%r14
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %r13d,%r13d
  jle    L83
  mov    $0x0,%ebp
  jmp    L135
L92:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D40
type: string
name: parse_data
arguments: data_tag: D107
type: string
name: parse_data
arguments: data_tag: D14
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D102
type: string
name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D98
type: string

tool: D15: 
Give the ID, between 0 to 500 ,of the %d student:


tool: D40: %d

tool: D107: 
Already given.Give another ID, between 0 to 500 ,of the %d student:


tool: D14: 
Give the age ,between 18 and 35, of the %d student:


tool: D7: 
Age out of range, between 18 and 35, of the %d student:


tool: D6: 
Give the sex  ,1 for male and 2 for female,of the %d student:


tool: D102: 
Wrong,1 for male and 2 for female:

tool: D1: 
Give the degree , between 1 to 10,of the %d student:


tool: D98: 
Wrong degree,1 to N:

assistant: ```c
void insert_student(int a[3][4]) {
  int i, k, j;
  i = j = k = 0;
  while (i < 3 && j < 4) {
    printf("\nGive the ID, between 0 to 500 ,of the %d student:\n", i + 1);
    scanf("%d", &a[i][j]);
    k = 0;
    while (k < i) {
      if (a[i][j] == a[k][j]) {
        printf("\nAlready given.Give another ID, between 0 to 500 ,of the %d student:\n", i + 1);
        scanf("%d", &a[i][j]);
      } else
        k++;
    }
    j++;
    printf("\nGive the age ,between 18 and 35, of the %d student:\n", i + 1);
    scanf("%d", &a[i][j]);
    while (a[i][j] < 18 || a[i][j] > 35) {
      printf("\nAge out of range, between 18 and 35, of the %d student:\n", i + 1);
      scanf("%d", &a[i][j]);
    }
    j++;
    printf("\nGive the sex  ,1 for male and 2 for female,of the %d student:\n", i + 1);
    scanf("%d", &a[i][j]);
    while (a[i][j] < 1 || a[i][j] > 2) {
      printf("\nWrong,1 for male and 2 for female:\n");
      scanf("%d", &a[i][j]);
    }
    j++;
    printf("\nGive the degree , between 1 to 10,of the %d student:\n", i + 1);
    scanf("%d", &a[i][j]);
    while (a[i][j] < 1 || a[k][j] > 10) {
      printf("\nWrong degree,1 to N:\n");
      scanf("%d", &a[i][j]);
    }
    j = 0;
    i++;
  }
}
```