ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printPredefinedMacros>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rsi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D44(%rip),%rsi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D78(%rip),%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2f,%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D38(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
data_type: string
name: extract_symbolic_data
arguments: data_tag: D54
data_type: string
name: extract_symbolic_data
arguments: data_tag: D44
data_type: string
name: extract_symbolic_data
arguments: data_tag: D69
data_type: string
name: extract_symbolic_data
arguments: data_tag: D78
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D42
data_type: string
name: extract_symbolic_data
arguments: data_tag: D38
data_type: string

tool: D24: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Ztiany/Repository/refs/heads/master/C&C++/c-program/Pretreatment/Pretreatment.c

tool: D54: File :%s


tool: D44: Mar 15 2022

tool: D69: Date :%s


tool: D78: 18:18:15

tool: D3: Time :%s


tool: D42: Line :%d


tool: D38: ANSI :%d


assistant: ```c
void printPredefinedMacros() {
  printf("File :%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Ztiany/Repository/refs/heads/master/C&C++/c-program/Pretreatment/Pretreatment.c");
  printf("Date :%s\n", "Mar 15 2022");
  printf("Time :%s\n", "18:18:15");
  printf("Line :%d\n", 47);
  printf("ANSI :%d\n", 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printPredefinedMacros>:
  endbr64
  sub    $0x8,%rsp
  lea    D73(%rip),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D49(%rip),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rsi
  lea    D62(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2f,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D57(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D73
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D49
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D62
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D57
type_infered: string

tool: D73: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Ztiany/Repository/refs/heads/master/C&C++/c-program/Pretreatment/Pretreatment.c

tool: D11: File :%s


tool: D49: Mar 15 2022

tool: D16: Date :%s


tool: D20: 18:18:15

tool: D62: Time :%s


tool: D17: Line :%d


tool: D57: ANSI :%d


assistant: ```c
void printPredefinedMacros() {
  printf("File :%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Ztiany/Repository/refs/heads/master/C&C++/c-program/Pretreatment/Pretreatment.c");
  printf("Date :%s\n", "Mar 15 2022");
  printf("Time :%s\n", "18:18:15");
  printf("Line :%d\n", 47);
  printf("ANSI :%d\n", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmMultMatrix3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L41:
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L37:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L58
L47:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L58:
  cmpl   $0x2,-0xc(%rbp)
  jle    L47
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L6:
  cmpl   $0x2,-0x10(%rbp)
  jle    L37
  addl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x2,-0x14(%rbp)
  jle    L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmMultMatrix3d(double result[9], const double m1[9], const double m2[9]) {
  double sum;
  int x, y, i;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++) {
      sum = 0;
      for (i = 0; i < 3; i++)
        sum += m1[y + 3 * i] * m2[3 * x + i];
      result[y + 3 * x] = sum;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<glmMultMatrix3d>:
  endbr64
  mov    $0x0,%r9d
  jmp    L33
L11:
  movsd  %xmm1,(%rdi,%r8,8)
  add    $0x1,%r8
  cmp    $0x3,%r8
  je     L55
L54:
  lea    (%rsi,%r8,8),%rcx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L1:
  movsd  (%rcx),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  add    $0x18,%rcx
  cmp    $0x3,%rax
  jne    L1
  jmp    L11
L55:
  add    $0x3,%r9d
  add    $0x18,%rdi
  add    $0x18,%rdx
  cmp    $0x9,%r9d
  je     L27
L33:
  mov    $0x0,%r8d
  jmp    L54
L27:
  ret
```

assistant: ```c
void glmMultMatrix3d(double result[9], const double m1[9], const double m2[9]) {
  double sum;
  int x, y, i;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++) {
      sum = 0;
      for (i = 0; i < 3; i++)
        sum += m1[y + 3 * i] * m2[3 * x + i];
      result[y + 3 * x] = sum;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<glmMultMatrix3d>:
  endbr64
  xor    %r9d,%r9d
  pxor   %xmm2,%xmm2
L18:
  xor    %r8d,%r8d
L21:
  lea    (%rsi,%r8,8),%rcx
  xor    %eax,%eax
  movapd %xmm2,%xmm1
L4:
  movsd  (%rcx),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  add    $0x18,%rcx
  addsd  %xmm0,%xmm1
  cmp    $0x3,%rax
  jne    L4
  movsd  %xmm1,(%rdi,%r8,8)
  add    $0x1,%r8
  cmp    $0x3,%r8
  jne    L21
  add    $0x3,%r9d
  add    $0x18,%rdi
  add    $0x18,%rdx
  cmp    $0x9,%r9d
  jne    L18
  ret
```

assistant: ```c
void glmMultMatrix3d(double result[9], const double m1[9], const double m2[9]) {
  double sum;
  int x, y, i;
  for (x = 0; x < 3; x++) {
    for (y = 0; y < 3; y++) {
      sum = 0;
      for (i = 0; i < 3; i++)
        sum += m1[y + 3 * i] * m2[3 * x + i];
      result[y + 3 * x] = sum;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printCpuVendorID>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  cpuid
  mov    %ebx,-0x24(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x1c(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void printCpuVendorID() {
  char ebx[4];
  char edx[4];
  char ecx[4];
  asm("movl	$0,	%%eax\n"
      "CPUID\n"
      "movl   %%ebx,  %[ebx]\n"
      "movl	%%edx,	%[edx]\n"
      "movl	%%ecx,	%[ecx]\n"
      : [ebx] "=m"(ebx), [edx] "=m"(edx), [ecx] "=m"(ecx)
      :
      : "%eax", "%ebx", "%edx", "%ecx");
  printf("%s\n", ebx);
}
```
user: What is the c source code of the assembly code below?

```asm
<printCpuVendorID>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%eax
  cpuid
  mov    %ebx,0xc(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %ecx,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printCpuVendorID() {
  char ebx[4];
  char edx[4];
  char ecx[4];
  asm("movl	$0,	%%eax\n"
      "CPUID\n"
      "movl   %%ebx,  %[ebx]\n"
      "movl	%%edx,	%[edx]\n"
      "movl	%%ecx,	%[ecx]\n"
      : [ebx] "=m"(ebx), [edx] "=m"(edx), [ecx] "=m"(ecx)
      :
      : "%eax", "%ebx", "%edx", "%ecx");
  printf("%s\n", ebx);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printCpuVendorID>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    $0x0,%eax
  cpuid
  mov    %ebx,0xc(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %ecx,0x14(%rsp)
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printCpuVendorID() {
  char ebx[4];
  char edx[4];
  char ecx[4];
  asm("movl	$0,	%%eax\n"
      "CPUID\n"
      "movl   %%ebx,  %[ebx]\n"
      "movl	%%edx,	%[edx]\n"
      "movl	%%ecx,	%[ecx]\n"
      : [ebx] "=m"(ebx), [edx] "=m"(edx), [ecx] "=m"(ecx)
      :
      : "%eax", "%ebx", "%edx", "%ecx");
  printf("%s\n", ebx);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printCpuVendorID>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    $0x0,%eax
  cpuid
  mov    %ebx,0xc(%rsp)
  mov    %edx,0x10(%rsp)
  mov    %ecx,0x14(%rsp)
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printCpuVendorID() {
  char ebx[4];
  char edx[4];
  char ecx[4];
  asm("movl	$0,	%%eax\n"
      "CPUID\n"
      "movl   %%ebx,  %[ebx]\n"
      "movl	%%edx,	%[edx]\n"
      "movl	%%ecx,	%[ecx]\n"
      : [ebx] "=m"(ebx), [edx] "=m"(edx), [ecx] "=m"(ecx)
      :
      : "%eax", "%ebx", "%edx", "%ecx");
  printf("%s\n", ebx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L14:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L40
  jmp    L21
L45:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
L40:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_whitespace(char **ptr) {
  char *p = *ptr;
  while (*p && isspace(*p))
    ++p;
  if (*p == ';')
    while (*p)
      ++p;
  *ptr = p;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L21
L15:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L53
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L21:
  mov    %rbx,0x0(%rbp)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L53:
  cmpb   $0x3b,(%rbx)
  jne    L21
L19:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L19
  jmp    L21
```

assistant: ```c
char *skip_whitespace(char **ptr) {
  char *p = *ptr;
  while (*p && isspace(*p))
    ++p;
  if (*p == ';')
    while (*p)
      ++p;
  *ptr = p;
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<skip_whitespace>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L3
  jmp    L51
  nopl   (%rax)
L30:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L51
L3:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
  cmpb   $0x3b,(%r12)
  jne    L51
L52:
  add    $0x1,%r12
  cmpb   $0x0,(%r12)
  jne    L52
L51:
  mov    %r12,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *skip_whitespace(char **ptr) {
  char *p = *ptr;
  while (*p && isspace(*p))
    ++p;
  if (*p == ';')
    while (*p)
      ++p;
  *ptr = p;
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_whitespace>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L26
  jmp    L46
  nopl   (%rax)
L22:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L46
L26:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  cmpb   $0x3b,(%r12)
  jne    L46
L51:
  add    $0x1,%r12
  cmpb   $0x0,(%r12)
  jne    L51
L46:
  mov    %r12,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *skip_whitespace(char **ptr) {
  char *p = *ptr;
  while (*p && isspace(*p))
    ++p;
  if (*p == ';')
    while (*p)
      ++p;
  *ptr = p;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<edit_distn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rbx
  mov    %rcx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
L60:
  mov    %eax,(%rsp,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%r8
  jne    L60
  test   %r11,%r11
  je     L41
  mov    $0x1,%ebp
  lea    0x104(%rsp),%rsi
  mov    %rsp,%rdi
  jmp    L0
L16:
  mov    %rax,%rbp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
L0:
  mov    %ebp,(%rsi)
  test   %r8,%r8
  je     L78
  movzbl -0x1(%r10,%rbp,1),%r9d
  mov    $0x0,%edx
L62:
  add    $0x1,%rdx
  mov    (%rdi,%rdx,4),%eax
  add    $0x1,%eax
  mov    -0x4(%rsi,%rdx,4),%ecx
  add    $0x1,%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %r9b,-0x1(%rbx,%rdx,1)
  setne  %r12b
  movzbl %r12b,%r12d
  mov    -0x4(%rdi,%rdx,4),%ecx
  lea    (%rcx,%r12,2),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%rsi,%rdx,4)
  cmp    %r8,%rdx
  jne    L62
L78:
  lea    0x1(%rbp),%rax
  cmp    %rbp,%r11
  jne    L16
L55:
  mov    (%rsi,%r8,4),%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    %rsp,%rsi
  jmp    L55
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int edit_distn(const char *s1, size_t s1len, const char *s2, size_t s2len) {
  int t[2][64 + 1];
  int *t1 = t[0];
  int *t2 = t[1];
  int *t3;
  size_t i1, i2;
  for (i2 = 0; i2 <= s2len; i2++)
    t[0][i2] = i2;
  for (i1 = 0; i1 < s1len; i1++) {
    t2[0] = i1 + 1;
    for (i2 = 0; i2 < s2len; i2++) {
      int cost_a = t1[i2 + 1] + 1;
      int cost_d = t2[i2] + 1;
      int cost_r = t1[i2] + (s1[i1] == s2[i2] ? 0 : 2);
      t2[i2 + 1] = ((((cost_a) < (cost_d) ? (cost_a) : (cost_d))) < (cost_r) ? (((cost_a) < (cost_d) ? (cost_a) : (cost_d))) : (cost_r));
    }
    t3 = t1;
    t1 = t2;
    t2 = t3;
  }
  return t1[s2len];
}
```
user: What is the c source code of the assembly code below?

```asm
<edit_distn>:
  endbr64
  push   %r12
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rcx,%r9
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L67:
  mov    %rax,%rdx
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%r9
  jne    L67
  test   %r11,%r11
  je     L30
  mov    $0x1,%ebp
  lea    0x104(%rsp),%r8
  nopl   0x0(%rax)
L32:
  mov    %ebp,(%r8)
  mov    %ebp,%ecx
  test   %r9,%r9
  je     L68
  movzbl -0x1(%r10,%rbp,1),%r12d
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdx
  xor    %esi,%esi
  mov    -0x4(%rdi,%rdx,4),%eax
  cmp    %r12b,-0x1(%rbx,%rdx,1)
  setne  %sil
  add    $0x1,%ecx
  lea    (%rax,%rsi,2),%esi
  mov    (%rdi,%rdx,4),%eax
  add    $0x1,%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  cmp    %eax,%esi
  cmovle %esi,%eax
  mov    %eax,(%r8,%rdx,4)
  mov    %eax,%ecx
  cmp    %r9,%rdx
  jne    L0
L68:
  lea    0x1(%rbp),%rax
  cmp    %rbp,%r11
  je     L46
  mov    %rax,%rbp
  mov    %rdi,%rax
  mov    %r8,%rdi
  mov    %rax,%r8
  jmp    L32
L30:
  mov    %rdi,%r8
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    (%r8,%r9,4),%eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int edit_distn(const char *s1, size_t s1len, const char *s2, size_t s2len) {
  int t[2][64 + 1];
  int *t1 = t[0];
  int *t2 = t[1];
  int *t3;
  size_t i1, i2;
  for (i2 = 0; i2 <= s2len; i2++)
    t[0][i2] = i2;
  for (i1 = 0; i1 < s1len; i1++) {
    t2[0] = i1 + 1;
    for (i2 = 0; i2 < s2len; i2++) {
      int cost_a = t1[i2 + 1] + 1;
      int cost_d = t2[i2] + 1;
      int cost_r = t1[i2] + (s1[i1] == s2[i2] ? 0 : 2);
      t2[i2 + 1] = ((((cost_a) < (cost_d) ? (cost_a) : (cost_d))) < (cost_r) ? (((cost_a) < (cost_d) ? (cost_a) : (cost_d))) : (cost_r));
    }
    t3 = t1;
    t1 = t2;
    t2 = t3;
  }
  return t1[s2len];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L20
L1:
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L10
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L1
L10:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *mem0, const void *mem1, size_t n) {
  const char *st0 = mem0;
  const char *st1 = mem1;
  size_t i;
  for (i = 0; st0[i] == st1[i] && i < n - 1; i++)
    ;
  return st0[i] - st1[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L4
  sub    $0x1,%rdx
  je     L4
  mov    $0x0,%ecx
L0:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  jne    L4
  cmp    %rdx,%rcx
  jne    L0
L4:
  movsbl %al,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int memcmp(const void *mem0, const void *mem1, size_t n) {
  const char *st0 = mem0;
  const char *st1 = mem1;
  size_t i;
  for (i = 0; st0[i] == st1[i] && i < n - 1; i++)
    ;
  return st0[i] - st1[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L11
  sub    $0x1,%rdx
  je     L11
  xor    %ecx,%ecx
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    %rdx,%rcx
  je     L11
L27:
  add    $0x1,%rcx
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  je     L8
L11:
  sub    %r8d,%eax
  ret
```

assistant: ```c
int memcmp(const void *mem0, const void *mem1, size_t n) {
  const char *st0 = mem0;
  const char *st1 = mem1;
  size_t i;
  for (i = 0; st0[i] == st1[i] && i < n - 1; i++)
    ;
  return st0[i] - st1[i];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L21
  sub    $0x1,%rdx
  je     L21
  xor    %ecx,%ecx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L23:
  cmp    %rdx,%rcx
  je     L21
L0:
  add    $0x1,%rcx
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  je     L23
L21:
  sub    %r8d,%eax
  ret
```

assistant: ```c
int memcmp(const void *mem0, const void *mem1, size_t n) {
  const char *st0 = mem0;
  const char *st1 = mem1;
  size_t i;
  for (i = 0; st0[i] == st1[i] && i < n - 1; i++)
    ;
  return st0[i] - st1[i];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_if_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    D25(%rip),%rax
  mov    (%rax),%ecx
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0xffffffff,-0x20(%rbp)
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L55
L28:
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D35(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strnzcpy@plt>
  mov    D37(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  cmp    $0xffffffff,%eax
  jne    L32
  mov    $0xffffffff,%eax
  jmp    L55
L32:
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L66
  mov    $0xffffffff,%eax
  jmp    L55
L66:
  lea    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L55:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int get_if_addr(const char *ifname, struct in_addr *addr) {
  int sock_fd;
  struct ifreq ifr;
  int ioctl_ret;
  struct sockaddr_in *sa_in = NULL;
  addr->s_addr = INADDR_NONE;
  sock_fd = socket(AF_INET, SOCK_DGRAM, 0);
  if (sock_fd == -1) {
    return -1;
  }
  memset(&ifr, 0, sizeof(ifr));
  strnzcpy(ifr.ifr_name, ifname, IFNAMSIZ);
  ioctl_ret = ioctl(sock_fd, SIOCGIFADDR, &ifr);
  if (close(sock_fd) == -1) {
    return -1;
  }
  if (ioctl_ret == -1) {
    return -1;
  }
  sa_in = (struct sockaddr_in *)&ifr.ifr_addr;
  memcpy(&addr->s_addr, &sa_in->sin_addr, sizeof(in_addr_t));
  return 0;
}
```