ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<test_1_opt_1_operand>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D30(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D24(%rip),%rax
  mov    %rsp,%rbp
  mov    %rax,(%rsp)
  lea    D25(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <echo_test_setup@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <test_validation@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D24
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string

tool: D30: Testing with 1 option and 1 operand.


tool: D24: test

tool: D25: -a

tool: D29: bc

assistant: ```c
bool test_1_opt_1_operand(const char *optstring) {
  int argc = 3;
  char *argv[] = {"test", "-a", "bc"};
  printf("Testing with 1 option and 1 operand.\n");
  echo_test_setup(argc, argv, optstring);
  return test_validation(argc, argv, optstring);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_1_opt_1_operand>:
  endbr64
  push   %r12
  lea    D12(%rip),%rcx
  mov    %rdi,%r12
  lea    D25(%rip),%rdi
  push   %rbp
  movq   %rcx,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D22(%rip),%rax
  mov    %rsp,%rbp
  movq   %rax,%xmm1
  lea    D36(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <echo_test_setup@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <test_validation@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D25
datatype: string
name: parse_data
arguments: label: D22
datatype: string
name: parse_data
arguments: label: D36
datatype: string

tool: D12: test

tool: D25: Testing with 1 option and 1 operand.


tool: D22: -a

tool: D36: bc

assistant: ```c
bool test_1_opt_1_operand(const char *optstring) {
  int argc = 3;
  char *argv[] = {"test", "-a", "bc"};
  printf("Testing with 1 option and 1 operand.\n");
  echo_test_setup(argc, argv, optstring);
  return test_validation(argc, argv, optstring);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shannon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x40,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x21c(%rbp)
  movl   $0x0,-0x218(%rbp)
  jmp    L44
L29:
  mov    -0x218(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movslq %eax,%rdx
  movss  -0x210(%rbp,%rdx,4),%xmm1
  movss  D13(%rip),%xmm0
  addss  %xmm1,%xmm0
  cltq
  movss  %xmm0,-0x210(%rbp,%rax,4)
  addl   $0x1,-0x218(%rbp)
L44:
  pxor   %xmm4,%xmm4
  cvtsi2ssl -0x218(%rbp),%xmm4
  movss  %xmm4,-0x22c(%rbp)
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm5
  comiss -0x22c(%rbp),%xmm5
  ja     L29
  movl   $0x0,-0x214(%rbp)
  jmp    L24
L6:
  mov    -0x214(%rbp),%eax
  cltq
  movss  -0x210(%rbp,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L54
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L37
L54:
  mov    -0x214(%rbp),%eax
  cltq
  movss  -0x210(%rbp,%rax,4),%xmm2
  movss  %xmm2,-0x22c(%rbp)
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movss  -0x22c(%rbp),%xmm2
  divss  %xmm0,%xmm2
  movss  %xmm2,-0x22c(%rbp)
  mov    -0x214(%rbp),%eax
  cltq
  movss  -0x210(%rbp,%rax,4),%xmm3
  movss  %xmm3,-0x230(%rbp)
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movss  -0x230(%rbp),%xmm3
  divss  %xmm0,%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  call   <log2f@plt>
  mulss  -0x22c(%rbp),%xmm0
  jmp    L12
L37:
  pxor   %xmm0,%xmm0
L12:
  movss  -0x21c(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x21c(%rbp)
  addl   $0x1,-0x214(%rbp)
L24:
  cmpl   $0x7f,-0x214(%rbp)
  jle    L6
  movss  -0x21c(%rbp),%xmm0
  movss  D16(%rip),%xmm1
  xorps  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: byte[4]
name: unpack_data
arguments: label: D16
type_infered: byte[4]

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x80]}

assistant: ```c
float shannon(char *str) {
  float count[128] = {0};
  float sum = 0;
  for (int i = 0; i < strlen(str); i++)
    count[str[i]]++;
  for (int i = 0; i < 128; i++)
    sum += count[i] ? (count[i] / strlen(str)) * log2f(count[i] / strlen(str)) : 0;
  return -1 * sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shannon>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x40,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%ebx
  jmp    L41
L14:
  movsbq 0x0(%r13,%rbx,1),%rax
  movss  0x10(%rsp,%rax,4),%xmm0
  addss  D14(%rip),%xmm0
  movss  %xmm0,0x10(%rsp,%rax,4)
  add    $0x1,%rbx
L41:
  mov    %r13,%rdi
  call   <strlen@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  comiss %xmm0,%xmm1
  ja     L14
  lea    0x10(%rsp),%rbp
  lea    0x210(%rsp),%r12
  pxor   %xmm7,%xmm7
  movss  %xmm7,0x8(%rsp)
  jmp    L24
L7:
  mov    %r13,%rdi
  call   <strlen@plt>
  movd   %ebx,%xmm6
  divss  %xmm0,%xmm6
  movss  %xmm6,0xc(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  divss  %xmm1,%xmm0
  call   <log2f@plt>
  mulss  0xc(%rsp),%xmm0
L75:
  addss  0x8(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  je     L8
L24:
  mov    0x0(%rbp),%ebx
  movd   %ebx,%xmm2
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L7
  movaps %xmm3,%xmm0
  je     L75
  jmp    L7
L8:
  xorps  D3(%rip),%xmm0
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
type: byte[4]
name: retrieve_data
arguments: label: D3
type: byte[16]

tool: {"D14": [0x00,0x00,0x80,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float shannon(char *str) {
  float count[128] = {0};
  float sum = 0;
  for (int i = 0; i < strlen(str); i++)
    count[str[i]]++;
  for (int i = 0; i < 128; i++)
    sum += count[i] ? (count[i] / strlen(str)) * log2f(count[i] / strlen(str)) : 0;
  return -1 * sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shannon>:
  endbr64
  push   %r12
  mov    $0x40,%ecx
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L45
  nopl   0x0(%rax)
L66:
  movsbq (%r12,%rbp,1),%rax
  movss  D7(%rip),%xmm0
  add    $0x1,%rbp
  addss  0x10(%rsp,%rax,4),%xmm0
  movss  %xmm0,0x10(%rsp,%rax,4)
L45:
  mov    %r12,%rdi
  call   <strlen@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  comiss %xmm0,%xmm1
  ja     L66
  pxor   %xmm3,%xmm3
  lea    0x210(%rsp),%rbp
  movaps %xmm3,%xmm2
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x4,%rbx
  addss  %xmm0,%xmm2
  cmp    %rbp,%rbx
  je     L34
L7:
  movss  (%rbx),%xmm1
  ucomiss %xmm3,%xmm1
  jp     L3
  movaps %xmm3,%xmm0
  je     L37
L3:
  mov    %r12,%rdi
  movss  %xmm2,0xc(%rsp)
  add    $0x4,%rbx
  movss  %xmm1,0x4(%rsp)
  call   <strlen@plt>
  movss  0x4(%rsp),%xmm1
  mov    %r12,%rdi
  movaps %xmm1,%xmm4
  movss  %xmm1,0x8(%rsp)
  divss  %xmm0,%xmm4
  movss  %xmm4,0x4(%rsp)
  call   <strlen@plt>
  movss  0x8(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <log2f@plt>
  mulss  0x4(%rsp),%xmm0
  movss  0xc(%rsp),%xmm2
  pxor   %xmm3,%xmm3
  addss  %xmm0,%xmm2
  cmp    %rbp,%rbx
  jne    L7
L34:
  xorps  D3(%rip),%xmm2
  movaps %xmm2,%xmm0
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x220,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: byte[4]
name: unpack_data
arguments: data_label: D3
type_infered: byte[16]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float shannon(char *str) {
  float count[128] = {0};
  float sum = 0;
  for (int i = 0; i < strlen(str); i++)
    count[str[i]]++;
  for (int i = 0; i < 128; i++)
    sum += count[i] ? (count[i] / strlen(str)) * log2f(count[i] / strlen(str)) : 0;
  return -1 * sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shannon>:
  endbr64
  push   %r12
  mov    $0x40,%ecx
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L59
  nopl   0x0(%rax)
L25:
  movsbq (%r12,%rbp,1),%rax
  movss  D4(%rip),%xmm0
  add    $0x1,%rbp
  addss  0x10(%rsp,%rax,4),%xmm0
  movss  %xmm0,0x10(%rsp,%rax,4)
L59:
  mov    %r12,%rdi
  call   <strlen@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  comiss %xmm0,%xmm1
  ja     L25
  pxor   %xmm3,%xmm3
  lea    0x210(%rsp),%rbp
  movaps %xmm3,%xmm2
  nopl   0x0(%rax)
L14:
  movss  (%rbx),%xmm1
  ucomiss %xmm3,%xmm1
  jp     L65
  jne    L65
  add    $0x4,%rbx
  addss  %xmm3,%xmm2
  cmp    %rbp,%rbx
  jne    L14
L77:
  xorps  D3(%rip),%xmm2
  movaps %xmm2,%xmm0
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x220,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L65:
  mov    %r12,%rdi
  movss  %xmm2,0xc(%rsp)
  add    $0x4,%rbx
  movss  %xmm1,0x4(%rsp)
  call   <strlen@plt>
  movss  0x4(%rsp),%xmm1
  mov    %r12,%rdi
  movaps %xmm1,%xmm4
  movss  %xmm1,0x8(%rsp)
  divss  %xmm0,%xmm4
  movss  %xmm4,0x4(%rsp)
  call   <strlen@plt>
  movss  0x8(%rsp),%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <log2f@plt>
  mulss  0x4(%rsp),%xmm0
  cmp    %rbp,%rbx
  pxor   %xmm3,%xmm3
  movss  0xc(%rsp),%xmm2
  addss  %xmm0,%xmm2
  jne    L14
  jmp    L77
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: byte[4]
name: disassemble_data
arguments: label: D3
type: byte[16]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float shannon(char *str) {
  float count[128] = {0};
  float sum = 0;
  for (int i = 0; i < strlen(str); i++)
    count[str[i]]++;
  for (int i = 0; i < 128; i++)
    sum += count[i] ? (count[i] / strlen(str)) * log2f(count[i] / strlen(str)) : 0;
  return -1 * sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bellTriangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <setBell@plt>
  movl   $0x2,-0x2c(%rbp)
  jmp    L6
L28:
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getBell@plt>
  mov    %eax,%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <setBell@plt>
  movl   $0x1,-0x28(%rbp)
  jmp    L39
L4:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getBell@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getBell@plt>
  add    %ebx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x2c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <setBell@plt>
  addl   $0x1,-0x28(%rbp)
L39:
  mov    -0x28(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  addl   $0x1,-0x2c(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L28
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *bellTriangle(int n) {
  size_t length = n * (n + 1) / 2;
  int *tri = calloc(length, sizeof(int));
  int i, j;
  setBell(tri, 1, 0, 1);
  for (i = 2; i <= n; ++i) {
    setBell(tri, i, 0, getBell(tri, i - 1, i - 2));
    for (j = 1; j < i; ++j) {
      int value = getBell(tri, i, j - 1) + getBell(tri, i - 1, j - 1);
      setBell(tri, i, j, value);
    }
  }
  return tri;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bellTriangle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  lea    0x1(%rdi),%eax
  imul   %edi,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  movslq %edi,%rdi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <setBell@plt>
  cmp    $0x1,%ebx
  jle    L3
  mov    $0x2,%r12d
L5:
  lea    -0x1(%r12),%r15d
  lea    -0x2(%r12),%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <getBell@plt>
  mov    %eax,%ecx
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <setBell@plt>
  cmp    $0x1,%r12d
  jle    L22
  mov    $0x1,%ebp
L33:
  lea    -0x1(%rbp),%r14d
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <getBell@plt>
  mov    %eax,%ebx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <getBell@plt>
  lea    (%rbx,%rax,1),%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <setBell@plt>
  add    $0x1,%ebp
  cmp    %r12d,%ebp
  jne    L33
L22:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L5
L3:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *bellTriangle(int n) {
  size_t length = n * (n + 1) / 2;
  int *tri = calloc(length, sizeof(int));
  int i, j;
  setBell(tri, 1, 0, 1);
  for (i = 2; i <= n; ++i) {
    setBell(tri, i, 0, getBell(tri, i - 1, i - 2));
    for (j = 1; j < i; ++j) {
      int value = getBell(tri, i, j - 1) + getBell(tri, i - 1, j - 1);
      setBell(tri, i, j, value);
    }
  }
  return tri;
}
```
user: What is the c source code of the assembly code below?

```asm
<bellTriangle>:
  endbr64
  push   %r15
  lea    0x1(%rdi),%eax
  mov    $0x4,%esi
  push   %r14
  imul   %edi,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  movslq %edi,%rdi
  call   <calloc@plt>
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <setBell@plt>
  cmp    $0x1,%ebx
  jle    L27
  mov    $0x2,%r12d
  nopw   0x0(%rax,%rax,1)
L2:
  lea    -0x1(%r12),%r13d
  lea    -0x2(%r12),%edx
  mov    %r15,%rdi
  mov    $0x1,%ebp
  mov    %r13d,%esi
  call   <getBell@plt>
  xor    %edx,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %eax,%ecx
  call   <setBell@plt>
  nopl   0x0(%rax)
L12:
  lea    -0x1(%rbp),%r14d
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %r14d,%edx
  call   <getBell@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <getBell@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  lea    (%rbx,%rax,1),%ecx
  add    $0x1,%ebp
  call   <setBell@plt>
  cmp    %r12d,%ebp
  jne    L12
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L2
L27:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *bellTriangle(int n) {
  size_t length = n * (n + 1) / 2;
  int *tri = calloc(length, sizeof(int));
  int i, j;
  setBell(tri, 1, 0, 1);
  for (i = 2; i <= n; ++i) {
    setBell(tri, i, 0, getBell(tri, i - 1, i - 2));
    for (j = 1; j < i; ++j) {
      int value = getBell(tri, i, j - 1) + getBell(tri, i - 1, j - 1);
      setBell(tri, i, j, value);
    }
  }
  return tri;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bellTriangle>:
  endbr64
  push   %r15
  lea    0x1(%rdi),%eax
  mov    $0x4,%esi
  push   %r14
  imul   %edi,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  movslq %edi,%rdi
  call   <calloc@plt>
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <setBell@plt>
  cmp    $0x1,%ebx
  jle    L9
  mov    $0x2,%r12d
  nopw   0x0(%rax,%rax,1)
L26:
  lea    -0x1(%r12),%r13d
  lea    -0x2(%r12),%edx
  mov    %r15,%rdi
  mov    $0x1,%ebp
  mov    %r13d,%esi
  call   <getBell@plt>
  xor    %edx,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %eax,%ecx
  call   <setBell@plt>
  nopl   0x0(%rax)
L11:
  lea    -0x1(%rbp),%r14d
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    %r14d,%edx
  call   <getBell@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <getBell@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  lea    (%rbx,%rax,1),%ecx
  add    $0x1,%ebp
  call   <setBell@plt>
  cmp    %r12d,%ebp
  jne    L11
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L26
L9:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *bellTriangle(int n) {
  size_t length = n * (n + 1) / 2;
  int *tri = calloc(length, sizeof(int));
  int i, j;
  setBell(tri, 1, 0, 1);
  for (i = 2; i <= n; ++i) {
    setBell(tri, i, 0, getBell(tri, i - 1, i - 2));
    for (j = 1; j < i; ++j) {
      int value = getBell(tri, i, j - 1) + getBell(tri, i - 1, j - 1);
      setBell(tri, i, j, value);
    }
  }
  return tri;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_var_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L33:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2,%al
  jne    L45
  addl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L45
  mov    -0x10(%rbp),%eax
  jmp    L9
L45:
  addq   $0x1,-0x28(%rbp)
  shll   -0x14(%rbp)
L44:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L33
  mov    $0x0,%edi
  call   <assert@plt>
L9:
  leave
  ret
```

assistant: ```c
unsigned int get_var_mask(const char *basemask, const int bits, const int bp) {
  const char *const end = basemask + bits;
  unsigned int curbit = 1;
  unsigned int var_mask = 0;
  int count2s = 0;
  for (; basemask < end; basemask++, curbit <<= 1) {
    if (*basemask == 2) {
      count2s++;
      var_mask |= curbit;
      if (count2s == bp)
        return var_mask;
    }
  }
  assert(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_var_mask>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L49
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x1,%eax
  jmp    L30
L25:
  add    $0x1,%rdi
  add    %eax,%eax
  cmp    %rdi,%rsi
  je     L49
L30:
  cmpb   $0x2,(%rdi)
  jne    L25
  add    $0x1,%ecx
  or     %eax,%r8d
  cmp    %edx,%ecx
  jne    L25
  mov    %r8d,%eax
  ret
L49:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int get_var_mask(const char *basemask, const int bits, const int bp) {
  const char *const end = basemask + bits;
  unsigned int curbit = 1;
  unsigned int var_mask = 0;
  int count2s = 0;
  for (; basemask < end; basemask++, curbit <<= 1) {
    if (*basemask == 2) {
      count2s++;
      var_mask |= curbit;
      if (count2s == bp)
        return var_mask;
    }
  }
  assert(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_var_mask>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L5
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%eax
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rdi
  add    %eax,%eax
  cmp    %rdi,%rsi
  je     L5
L30:
  cmpb   $0x2,(%rdi)
  jne    L45
  add    $0x1,%ecx
  or     %eax,%r8d
  cmp    %edx,%ecx
  jne    L45
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L5:
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
unsigned int get_var_mask(const char *basemask, const int bits, const int bp) {
  const char *const end = basemask + bits;
  unsigned int curbit = 1;
  unsigned int var_mask = 0;
  int count2s = 0;
  for (; basemask < end; basemask++, curbit <<= 1) {
    if (*basemask == 2) {
      count2s++;
      var_mask |= curbit;
      if (count2s == bp)
        return var_mask;
    }
  }
  assert(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_var_mask>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L46
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%eax
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rdi
  add    %eax,%eax
  cmp    %rdi,%rsi
  je     L46
L39:
  cmpb   $0x2,(%rdi)
  jne    L30
  add    $0x1,%ecx
  or     %eax,%r8d
  cmp    %edx,%ecx
  jne    L30
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L46:
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
unsigned int get_var_mask(const char *basemask, const int bits, const int bp) {
  const char *const end = basemask + bits;
  unsigned int curbit = 1;
  unsigned int var_mask = 0;
  int count2s = 0;
  for (; basemask < end; basemask++, curbit <<= 1) {
    if (*basemask == 2) {
      count2s++;
      var_mask |= curbit;
      if (count2s == bp)
        return var_mask;
    }
  }
  assert(0);
}
```