ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fcitx_utf8_strncmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L76
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    $0x0,%r12d
  mov    %rsp,%r14
  jmp    L53
L24:
  add    $0x1,%rbx
  add    $0x1,%rbp
L103:
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  je     L4
L53:
  movzbl (%rbx),%eax
  test   %al,%al
  js     L27
  cmp    0x0(%rbp),%al
  jne    L1
  test   %al,%al
  jne    L24
  mov    $0x0,%eax
  jmp    L58
L27:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  je     L103
  mov    $0x1,%eax
  jmp    L58
L4:
  mov    $0x0,%eax
L58:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L96
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L76:
  mov    $0x0,%eax
  jmp    L58
L1:
  mov    $0x1,%eax
  jmp    L58
L96:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) int fcitx_utf8_strncmp(const char *s1, const char *s2, int n) {
  int c1, c2;
  int i;
  for (i = 0; i < n; i++) {
    if (!(*s1 & 0x80)) {
      if (*s1 != *s2)
        return 1;
      if (*s1 == 0)
        return 0;
      s1++;
      s2++;
    } else {
      s1 = fcitx_utf8_get_char(s1, &c1);
      s2 = fcitx_utf8_get_char(s2, &c2);
      if (c1 != c2)
        return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcitx_utf8_strncmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L67
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  xor    %r13d,%r13d
  mov    %rsp,%rbx
  jmp    L41
  nopl   (%rax)
L54:
  cmp    (%r12),%cl
  jne    L0
  test   %cl,%cl
  je     L67
  add    $0x1,%rbp
  add    $0x1,%r12
L66:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  je     L67
L41:
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jns    L54
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <fcitx_utf8_get_char@plt>
  mov    %r12,%rdi
  lea    0x4(%rsp),%rsi
  mov    %rax,%rbp
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  je     L66
L0:
  mov    $0x1,%eax
  jmp    L50
  nopl   0x0(%rax)
L67:
  xor    %eax,%eax
L50:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) int fcitx_utf8_strncmp(const char *s1, const char *s2, int n) {
  int c1, c2;
  int i;
  for (i = 0; i < n; i++) {
    if (!(*s1 & 0x80)) {
      if (*s1 != *s2)
        return 1;
      if (*s1 == 0)
        return 0;
      s1++;
      s2++;
    } else {
      s1 = fcitx_utf8_get_char(s1, &c1);
      s2 = fcitx_utf8_get_char(s2, &c2);
      if (c1 != c2)
        return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcitx_utf8_strncmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L81
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  xor    %r13d,%r13d
  mov    %rsp,%rbx
  jmp    L26
  nopl   (%rax)
L33:
  cmp    (%r12),%cl
  jne    L59
  test   %cl,%cl
  je     L81
  add    $0x1,%rbp
  add    $0x1,%r12
L83:
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  je     L81
L26:
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jns    L33
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  call   <fcitx_utf8_get_char@plt>
  mov    %r12,%rdi
  lea    0x4(%rsp),%rsi
  mov    %rax,%rbp
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%eax
  cmp    %eax,(%rsp)
  je     L83
L59:
  mov    $0x1,%eax
  jmp    L1
  nopl   0x0(%rax)
L81:
  xor    %eax,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) int fcitx_utf8_strncmp(const char *s1, const char *s2, int n) {
  int c1, c2;
  int i;
  for (i = 0; i < n; i++) {
    if (!(*s1 & 0x80)) {
      if (*s1 != *s2)
        return 1;
      if (*s1 == 0)
        return 0;
      s1++;
      s2++;
    } else {
      s1 = fcitx_utf8_get_char(s1, &c1);
      s2 = fcitx_utf8_get_char(s2, &c2);
      if (c1 != c2)
        return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <factorial@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hal@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x63,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  factorial(10);
  for (int i = 0; i < 100; i++)
    hal(i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <factorial@plt>
  mov    $0x0,%ebx
L4:
  mov    %ebx,%edi
  call   <hal@plt>
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  factorial(10);
  for (int i = 0; i < 100; i++)
    hal(i);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <factorial@plt>
  nopl   0x0(%rax)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hal@plt>
  cmp    $0x64,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  factorial(10);
  for (int i = 0; i < 100; i++)
    hal(i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <factorial@plt>
  nopl   0x0(%rax)
L3:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hal@plt>
  cmp    $0x64,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  factorial(10);
  for (int i = 0; i < 100; i++)
    hal(i);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x64,(%rax)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int test() {
  int a, *b;
  a = 10;
  b = &a;
  *b = 100;
  a++;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test() {
  int a, *b;
  a = 10;
  b = &a;
  *b = 100;
  a++;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  int a, *b;
  a = 10;
  b = &a;
  *b = 100;
  a++;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  int a, *b;
  a = 10;
  b = &a;
  *b = 100;
  a++;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xbb8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minimum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x64,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L49:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L24
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
L24:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L49
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string

tool: D5: A menor nota: %i


assistant: ```c
void minimum(const int grades[][4], int pupils, int tests) {
  int i;
  int j;
  int lowGrade = 100;
  for (i = 0; i < pupils; i++) {
    for (j = 0; j < tests; j++) {
      if (grades[i][j] < lowGrade) {
        lowGrade = grades[i][j];
      }
    }
  }
  printf("A menor nota: %i\n", lowGrade);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minimum>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%r8
  lea    -0x1(%rsi),%ecx
  lea    (%rax,%rcx,4),%rcx
  lea    0x14(%rdi,%rcx,4),%r9
  mov    $0x64,%esi
  not    %rax
  lea    0x0(,%rax,4),%rdi
  jmp    L58
L45:
  mov    (%rax),%ecx
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L45
L40:
  add    $0x10,%r8
  cmp    %r9,%r8
  je     L0
L58:
  lea    (%rdi,%r8,1),%rax
  test   %edx,%edx
  jg     L45
  jmp    L40
L24:
  mov    $0x64,%esi
L0:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: A menor nota: %i


assistant: ```c
void minimum(const int grades[][4], int pupils, int tests) {
  int i;
  int j;
  int lowGrade = 100;
  for (i = 0; i < pupils; i++) {
    for (j = 0; j < tests; j++) {
      if (grades[i][j] < lowGrade) {
        lowGrade = grades[i][j];
      }
    }
  }
  printf("A menor nota: %i\n", lowGrade);
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimum>:
  endbr64
  test   %esi,%esi
  jle    L33
  lea    -0x1(%rdx),%ecx
  sub    $0x1,%esi
  lea    0x0(,%rcx,4),%rax
  lea    (%rcx,%rsi,4),%rcx
  mov    $0x64,%esi
  lea    0x4(%rdi,%rax,1),%r8
  lea    0x14(%rdi,%rcx,4),%r9
  mov    $0xfffffffffffffffc,%rdi
  sub    %rax,%rdi
  nopl   0x0(%rax,%rax,1)
L1:
  lea    (%rdi,%r8,1),%rax
  test   %edx,%edx
  jle    L3
L13:
  mov    (%rax),%ecx
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L13
L3:
  add    $0x10,%r8
  cmp    %r9,%r8
  jne    L1
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
L33:
  mov    $0x64,%esi
  lea    D17(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string

tool: D17: A menor nota: %i


assistant: ```c
void minimum(const int grades[][4], int pupils, int tests) {
  int i;
  int j;
  int lowGrade = 100;
  for (i = 0; i < pupils; i++) {
    for (j = 0; j < tests; j++) {
      if (grades[i][j] < lowGrade) {
        lowGrade = grades[i][j];
      }
    }
  }
  printf("A menor nota: %i\n", lowGrade);
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimum>:
  endbr64
  test   %esi,%esi
  jle    L79
  lea    -0x1(%rsi),%eax
  mov    $0x64,%esi
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rcx
  nopl   (%rax)
L37:
  test   %edx,%edx
  jle    L20
  mov    (%rdi),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    $0x1,%edx
  je     L20
  mov    0x4(%rdi),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    $0x2,%edx
  je     L20
  mov    0x8(%rdi),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    $0x3,%edx
  je     L20
  mov    0xc(%rdi),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    $0x4,%edx
  je     L20
  mov    0x10(%rdi),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    $0x5,%edx
  je     L20
  mov    $0x5,%eax
L48:
  mov    (%rdi,%rax,4),%r8d
  cmp    %r8d,%esi
  cmovg  %r8d,%esi
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L48
  nopl   0x0(%rax)
L20:
  add    $0x10,%rdi
  cmp    %rcx,%rdi
  jne    L37
  lea    D18(%rip),%rdi
  jmp    1050 <printf@plt>
L79:
  mov    $0x64,%esi
  lea    D18(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D18
datatype: string

tool: D18: A menor nota: %i


assistant: ```c
void minimum(const int grades[][4], int pupils, int tests) {
  int i;
  int j;
  int lowGrade = 100;
  for (i = 0; i < pupils; i++) {
    for (j = 0; j < tests; j++) {
      if (grades[i][j] < lowGrade) {
        lowGrade = grades[i][j];
      }
    }
  }
  printf("A menor nota: %i\n", lowGrade);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x74(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L7
L0:
  mov    -0x74(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x74(%rbp)
L7:
  mov    -0x74(%rbp),%eax
  mov    %eax,%edi
  call   <palindrome@plt>
  cmp    $0x1,%eax
  jne    L0
  mov    -0x74(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string

tool: D6: %d

tool: D13: %X

tool: D25: %s

assistant: ```c
int main() {
  int n;
  char c[100];
  scanf("%d", &n);
  while (palindrome(n) != 1) {
    n++;
  }
  sprintf(c, "%X", n);
  printf("%s", c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  jmp    L4
L17:
  addl   $0x1,0xc(%rsp)
L4:
  mov    0xc(%rsp),%edi
  call   <palindrome@plt>
  cmp    $0x1,%eax
  jne    L17
  lea    0x10(%rsp),%rbx
  mov    0xc(%rsp),%edx
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D22
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string

tool: D19: %d

tool: D22: %X

tool: D18: %s

assistant: ```c
int main() {
  int n;
  char c[100];
  scanf("%d", &n);
  while (palindrome(n) != 1) {
    n++;
  }
  sprintf(c, "%X", n);
  printf("%s", c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  jmp    L17
L12:
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
L17:
  call   <palindrome@plt>
  cmp    $0x1,%eax
  jne    L12
  lea    0x10(%rsp),%rbp
  mov    0xc(%rsp),%edx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D28: %d

tool: D14: %X

tool: D13: %s

assistant: ```c
int main() {
  int n;
  char c[100];
  scanf("%d", &n);
  while (palindrome(n) != 1) {
    n++;
  }
  sprintf(c, "%X", n);
  printf("%s", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  jmp    L15
L25:
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  mov    %edi,0xc(%rsp)
L15:
  call   <palindrome@plt>
  cmp    $0x1,%eax
  jne    L25
  lea    0x10(%rsp),%rbp
  mov    0xc(%rsp),%edx
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D15: %d

tool: D22: %X

tool: D6: %s

assistant: ```c
int main() {
  int n;
  char c[100];
  scanf("%d", &n);
  while (palindrome(n) != 1) {
    n++;
  }
  sprintf(c, "%X", n);
  printf("%s", c);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L38
L27:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D0(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L47
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L47:
  addl   $0x1,-0x24(%rbp)
L38:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L27
L13:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L41
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L41:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: f64
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D0: 1000

tool: D13: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 0.0;
    y = log10(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What is the c source code of the assembly code below:

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L18:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D6(%rip),%xmm0
  call   <log10@plt>
  ucomisd %xmm0,%xmm0
  jp     L5
  sub    $0x1,%ebx
  jne    L18
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L2
L5:
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L2:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: f64
name: parse_data
arguments: data_tag: D0
data_type: string

tool: D6: 1000

tool: D0: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 0.0;
    y = log10(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L4
  xchg   %ax,%ax
L5:
  sub    $0x1,%ebx
  je     L10
L4:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D17(%rip),%xmm0
  call   <log10@plt>
  ucomisd %xmm0,%xmm0
  jnp    L5
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: f64
name: retrieve_data
arguments: label: D13
type_guessed: string

tool: D17: 1000

tool: D13: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 0.0;
    y = log10(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L10
  xchg   %ax,%ax
L29:
  sub    $0x1,%ebx
  je     L3
L10:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D15(%rip),%xmm0
  call   <log10@plt>
  ucomisd %xmm0,%xmm0
  jnp    L29
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: f64
name: unpack_data
arguments: tag: D10
datatype: string

tool: D15: 1000

tool: D10: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 0.0;
    y = log10(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```