ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<hello2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x10,%ebx
  lea    D1(%rip),%r12
L2:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: %d


assistant: ```c
void hello2(int **p) {
  for (int i = 0; i < 4; i++)
    printf("%d\n", *(*p + 4 + i));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hello2>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x10,%ebx
L3:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x20,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: %d


assistant: ```c
void hello2(int **p) {
  for (int i = 0; i < 4; i++)
    printf("%d\n", *(*p + 4 + i));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hello2>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x10,%ebx
L0:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x20,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
void hello2(int **p) {
  for (int i = 0; i < 4; i++)
    printf("%d\n", *(*p + 4 + i));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xa(%rbp),%eax
  mov    %eax,%edx
  mov    $0xffffffdb,%eax
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string

tool: D7: %c

tool: D15: %c


assistant: ```c
int main() {
  char n, m;
  scanf("%c", &n);
  m = 'z' - (n - 'a');
  printf("%c\n", m);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  movsbl %sil,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D2
data_type: string

tool: D10: %c

tool: D2: %c


assistant: ```c
int main() {
  char n, m;
  scanf("%c", &n);
  m = 'z' - (n - 'a');
  printf("%c\n", m);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  lea    D12(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string

tool: D14: %c

tool: D12: %c


assistant: ```c
int main() {
  char n, m;
  scanf("%c", &n);
  m = 'z' - (n - 'a');
  printf("%c\n", m);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  lea    D5(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D19: %c

tool: D5: %c


assistant: ```c
int main() {
  char n, m;
  scanf("%c", &n);
  m = 'z' - (n - 'a');
  printf("%c\n", m);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D10(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
datatype: f32
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D10: 2

tool: D19: RADIO = %f

assistant: ```c
int main() {
  float r;
  r = 2.0;
  ;
  printf("RADIO = %f", r);
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D11(%rip),%xmm0
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: f64
name: disassemble_data
arguments: data_tag: D8
type: string

tool: D11: 2

tool: D8: RADIO = %f

assistant: ```c
int main() {
  float r;
  r = 2.0;
  ;
  printf("RADIO = %f", r);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  movsd  D1(%rip),%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: f64

tool: D7: RADIO = %f

tool: D1: 2

assistant: ```c
int main() {
  float r;
  r = 2.0;
  ;
  printf("RADIO = %f", r);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  movsd  D8(%rip),%xmm0
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: f64

tool: D5: RADIO = %f

tool: D8: 2

assistant: ```c
int main() {
  float r;
  r = 2.0;
  ;
  printf("RADIO = %f", r);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_write_beint08>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  lea    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__wbeu08@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%r8d
  mov    $0x5,%ecx
  mov    %eax,%edi
  call   <i2c_transact@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int i2c_write_beint08(int fd, int chip_addr, int reg, int8_t value) {
  uint8_t data[1 + sizeof(uint8_t)];
  data[0] = reg;
  __wbeu08(&data[1], (uint8_t)value);
  return i2c_transact(fd, chip_addr, data, 1 + sizeof(uint8_t), 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<i2c_write_beint08>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edx,(%rsp)
  mov    %rsp,%r12
  lea    0x4(%rsp),%rdi
  mov    %ecx,%esi
  call   <__wbeu08@plt>
  mov    $0x0,%r8d
  mov    $0x5,%ecx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <i2c_transact@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beint08(int fd, int chip_addr, int reg, int8_t value) {
  uint8_t data[1 + sizeof(uint8_t)];
  data[0] = reg;
  __wbeu08(&data[1], (uint8_t)value);
  return i2c_transact(fd, chip_addr, data, 1 + sizeof(uint8_t), 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2c_write_beint08>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %ecx,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    %rsp,%r13
  mov    %edx,(%rsp)
  call   <__wbeu08@plt>
  xor    %r8d,%r8d
  mov    %r13,%rdx
  mov    $0x5,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <i2c_transact@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beint08(int fd, int chip_addr, int reg, int8_t value) {
  uint8_t data[1 + sizeof(uint8_t)];
  data[0] = reg;
  __wbeu08(&data[1], (uint8_t)value);
  return i2c_transact(fd, chip_addr, data, 1 + sizeof(uint8_t), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<i2c_write_beint08>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    %ecx,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    %rsp,%r13
  mov    %edx,(%rsp)
  call   <__wbeu08@plt>
  xor    %r8d,%r8d
  mov    %r13,%rdx
  mov    $0x5,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <i2c_transact@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_write_beint08(int fd, int chip_addr, int reg, int8_t value) {
  uint8_t data[1 + sizeof(uint8_t)];
  data[0] = reg;
  __wbeu08(&data[1], (uint8_t)value);
  return i2c_transact(fd, chip_addr, data, 1 + sizeof(uint8_t), 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L12:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *destination, const char *s) {
  char *d = (destination + strlen(destination));
  for (; *s != '\0'; *d++ = *s++)
    ;
  *d = '\0';
  return destination;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L3
L2:
  add    $0x1,%rbx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L2
L3:
  movb   $0x0,(%rax)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *destination, const char *s) {
  char *d = (destination + strlen(destination));
  for (; *s != '\0'; *d++ = *s++)
    ;
  *d = '\0';
  return destination;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl (%rbx),%edx
  cltq
  add    %r12,%rax
  test   %dl,%dl
  je     L4
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rbx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L16
L4:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *destination, const char *s) {
  char *d = (destination + strlen(destination));
  for (; *s != '\0'; *d++ = *s++)
    ;
  *d = '\0';
  return destination;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movzbl (%rbx),%edx
  cltq
  add    %r12,%rax
  test   %dl,%dl
  je     L4
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rbx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L5
L4:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *destination, const char *s) {
  char *d = (destination + strlen(destination));
  for (; *s != '\0'; *d++ = *s++)
    ;
  *d = '\0';
  return destination;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L4:
  mov    $0x0,%eax
  call   <main@plt>
  add    %eax,-0x4(%rbp)
L12:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L4
  nop
  leave
  ret
```

assistant: ```c
int fib(int a) {
  int sum;
  sum = 0;
  while ((a = a - 1) > 0) {
    sum = sum + main();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L16
L18:
  mov    $0x0,%eax
  call   <main@plt>
  sub    $0x1,%ebx
  jne    L18
L16:
  pop    %rbx
  ret
```

assistant: ```c
int fib(int a) {
  int sum;
  sum = 0;
  while ((a = a - 1) > 0) {
    sum = sum + main();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L17
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  call   <main@plt>
  sub    $0x1,%ebx
  jne    L18
L17:
  pop    %rbx
  ret
```

assistant: ```c
int fib(int a) {
  int sum;
  sum = 0;
  while ((a = a - 1) > 0) {
    sum = sum + main();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fib>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L16
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <main@plt>
  sub    $0x1,%ebx
  jne    L6
L16:
  pop    %rbx
  ret
```

assistant: ```c
int fib(int a) {
  int sum;
  sum = 0;
  while ((a = a - 1) > 0) {
    sum = sum + main();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<do_process_html>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <gzip_free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <process_html@plt>
  leave
  ret
```

assistant: ```c
int do_process_html(struct connection *conn) {
  gzip_free(conn);
  return process_html(conn);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_process_html>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <gzip_free@plt>
  mov    %rbx,%rdi
  call   <process_html@plt>
  pop    %rbx
  ret
```

assistant: ```c
int do_process_html(struct connection *conn) {
  gzip_free(conn);
  return process_html(conn);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_process_html>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <gzip_free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <process_html@plt>
```

assistant: ```c
int do_process_html(struct connection *conn) {
  gzip_free(conn);
  return process_html(conn);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_process_html>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <gzip_free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <process_html@plt>
```

assistant: ```c
int do_process_html(struct connection *conn) {
  gzip_free(conn);
  return process_html(conn);
}
```
user: What is the c source code of the assembly code below?

```asm
<os_alloc_reset_light>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <log_printf@plt>
  mov    $0x0,%eax
  call   <os_alloc_reset_cores@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L13:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <os_alloc_reset_schematas@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L8:
  mov    $0x0,%eax
  call   <os_alloc_reset_tasks@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: INFO: OS alloc reset - LIGHT


assistant: ```c
int os_alloc_reset_light(const struct pqos_cap_l3ca *l3_cap, const struct pqos_cap_l2ca *l2_cap, const struct pqos_cap_mba *mba_cap) {
  int ret = 0;
  int step_result;
  log_printf((1 << 0), "INFO: "
                       "OS alloc reset - LIGHT\n");
  step_result = os_alloc_reset_cores();
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_schematas(l3_cap, l2_cap, mba_cap);
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_tasks();
  if (step_result != 0)
    ret = step_result;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<os_alloc_reset_light>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  call   <log_printf@plt>
  mov    $0x0,%eax
  call   <os_alloc_reset_cores@plt>
  mov    %eax,%ebx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <os_alloc_reset_schematas@plt>
  test   %eax,%eax
  cmovne %eax,%ebx
  mov    $0x0,%eax
  call   <os_alloc_reset_tasks@plt>
  test   %eax,%eax
  cmovne %eax,%ebx
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: INFO: OS alloc reset - LIGHT


assistant: ```c
int os_alloc_reset_light(const struct pqos_cap_l3ca *l3_cap, const struct pqos_cap_l2ca *l2_cap, const struct pqos_cap_mba *mba_cap) {
  int ret = 0;
  int step_result;
  log_printf((1 << 0), "INFO: "
                       "OS alloc reset - LIGHT\n");
  step_result = os_alloc_reset_cores();
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_schematas(l3_cap, l2_cap, mba_cap);
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_tasks();
  if (step_result != 0)
    ret = step_result;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<os_alloc_reset_light>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D3(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <log_printf@plt>
  xor    %eax,%eax
  call   <os_alloc_reset_cores@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <os_alloc_reset_schematas@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
  xor    %eax,%eax
  call   <os_alloc_reset_tasks@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: INFO: OS alloc reset - LIGHT


assistant: ```c
int os_alloc_reset_light(const struct pqos_cap_l3ca *l3_cap, const struct pqos_cap_l2ca *l2_cap, const struct pqos_cap_mba *mba_cap) {
  int ret = 0;
  int step_result;
  log_printf((1 << 0), "INFO: "
                       "OS alloc reset - LIGHT\n");
  step_result = os_alloc_reset_cores();
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_schematas(l3_cap, l2_cap, mba_cap);
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_tasks();
  if (step_result != 0)
    ret = step_result;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<os_alloc_reset_light>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  lea    D5(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <log_printf@plt>
  xor    %eax,%eax
  call   <os_alloc_reset_cores@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <os_alloc_reset_schematas@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
  xor    %eax,%eax
  call   <os_alloc_reset_tasks@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: INFO: OS alloc reset - LIGHT


assistant: ```c
int os_alloc_reset_light(const struct pqos_cap_l3ca *l3_cap, const struct pqos_cap_l2ca *l2_cap, const struct pqos_cap_mba *mba_cap) {
  int ret = 0;
  int step_result;
  log_printf((1 << 0), "INFO: "
                       "OS alloc reset - LIGHT\n");
  step_result = os_alloc_reset_cores();
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_schematas(l3_cap, l2_cap, mba_cap);
  if (step_result != 0)
    ret = step_result;
  step_result = os_alloc_reset_tasks();
  if (step_result != 0)
    ret = step_result;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0xc8,-0x14(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L15
L0:
  movsd  -0x10(%rbp),%xmm0
  movq   D4(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  imul   -0x18(%rbp),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L0
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double f(double x) {
  double t = x;
  double s = t;
  int i, n = 200;
  for (i = 1; i <= n; i++) {
    t = -t * (x * x) / ((2 * i + 1) * (2 * i));
    s = s + t;
  }
  return s;
}
```