ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RPYToRot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x40,%rsp
  lea    0x38(%rsp),%rbp
  lea    0x30(%rsp),%r12
  movsd  %xmm2,0x28(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x30(%rsp),%xmm5
  movsd  0x38(%rsp),%xmm3
  movapd %xmm1,%xmm0
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x30(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm6
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm6,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm6
  movsd  0x38(%rsp),%xmm0
  movapd %xmm2,%xmm4
  movsd  0x18(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm5
  mulsd  %xmm1,%xmm4
  movapd %xmm0,%xmm8
  mulsd  %xmm5,%xmm8
  movsd  %xmm4,(%rbx)
  movapd %xmm2,%xmm4
  mulsd  %xmm6,%xmm4
  movapd %xmm4,%xmm7
  mulsd  %xmm3,%xmm7
  mulsd  %xmm5,%xmm4
  subsd  %xmm8,%xmm7
  movsd  %xmm7,0x8(%rbx)
  movapd %xmm3,%xmm7
  mulsd  %xmm0,%xmm7
  addsd  %xmm7,%xmm4
  movapd %xmm2,%xmm7
  mulsd  %xmm5,%xmm7
  mulsd  %xmm3,%xmm2
  movsd  %xmm4,0x10(%rbx)
  movapd %xmm1,%xmm4
  mulsd  %xmm0,%xmm4
  mulsd  %xmm6,%xmm0
  xorpd  D8(%rip),%xmm6
  movsd  %xmm6,0x30(%rbx)
  movsd  %xmm4,0x18(%rbx)
  movapd %xmm3,%xmm4
  mulsd  %xmm0,%xmm4
  mulsd  %xmm5,%xmm0
  mulsd  %xmm1,%xmm3
  mulsd  %xmm5,%xmm1
  addsd  %xmm7,%xmm4
  subsd  %xmm2,%xmm0
  movsd  %xmm3,0x38(%rbx)
  movsd  %xmm4,0x20(%rbx)
  movsd  %xmm0,0x28(%rbx)
  movsd  %xmm1,0x40(%rbx)
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void RPYToRot(double roll, double pitch, double yaw, double R[3][3]) {
  double alpha = yaw;
  double beta = pitch;
  double gamma = roll;
  R[0][0] = cos(alpha) * cos(beta);
  R[0][1] = cos(alpha) * sin(beta) * sin(gamma) - sin(alpha) * cos(gamma);
  R[0][2] = cos(alpha) * sin(beta) * cos(gamma) + sin(alpha) * sin(gamma);
  R[1][0] = sin(alpha) * cos(beta);
  R[1][1] = sin(alpha) * sin(beta) * sin(gamma) + cos(alpha) * cos(gamma);
  R[1][2] = sin(alpha) * sin(beta) * cos(gamma) - cos(alpha) * sin(gamma);
  R[2][0] = -sin(beta);
  R[2][1] = cos(beta) * sin(gamma);
  R[2][2] = cos(beta) * cos(gamma);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<RPYToRot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x40,%rsp
  lea    0x38(%rsp),%rbp
  lea    0x30(%rsp),%r12
  movsd  %xmm2,0x28(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x30(%rsp),%xmm6
  movsd  0x38(%rsp),%xmm3
  movapd %xmm1,%xmm0
  movsd  %xmm6,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  0x30(%rsp),%xmm4
  movsd  0x38(%rsp),%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm5
  movsd  0x8(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm7
  movsd  0x18(%rsp),%xmm3
  movapd %xmm5,%xmm0
  movsd  0x20(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm4
  movapd %xmm5,%xmm8
  mulsd  %xmm1,%xmm0
  movapd %xmm7,%xmm10
  movapd %xmm1,%xmm2
  mulsd  %xmm6,%xmm10
  xorpd  D5(%rip),%xmm1
  mulsd  %xmm4,%xmm8
  mulsd  %xmm7,%xmm2
  movapd %xmm0,%xmm9
  mulsd  %xmm3,%xmm9
  mulsd  %xmm6,%xmm0
  subsd  %xmm10,%xmm9
  unpcklpd %xmm9,%xmm8
  movups %xmm8,(%rbx)
  movapd %xmm3,%xmm8
  mulsd  %xmm7,%xmm8
  mulsd  %xmm4,%xmm7
  addsd  %xmm8,%xmm0
  unpcklpd %xmm7,%xmm0
  movapd %xmm5,%xmm7
  movups %xmm0,0x10(%rbx)
  mulsd  %xmm3,%xmm5
  movapd %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm7
  mulsd  %xmm6,%xmm2
  mulsd  %xmm4,%xmm3
  mulsd  %xmm6,%xmm4
  addsd  %xmm7,%xmm0
  subsd  %xmm5,%xmm2
  unpcklpd %xmm3,%xmm1
  movups %xmm1,0x30(%rbx)
  unpcklpd %xmm2,%xmm0
  movsd  %xmm4,0x40(%rbx)
  movups %xmm0,0x20(%rbx)
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void RPYToRot(double roll, double pitch, double yaw, double R[3][3]) {
  double alpha = yaw;
  double beta = pitch;
  double gamma = roll;
  R[0][0] = cos(alpha) * cos(beta);
  R[0][1] = cos(alpha) * sin(beta) * sin(gamma) - sin(alpha) * cos(gamma);
  R[0][2] = cos(alpha) * sin(beta) * cos(gamma) + sin(alpha) * sin(gamma);
  R[1][0] = sin(alpha) * cos(beta);
  R[1][1] = sin(alpha) * sin(beta) * sin(gamma) + cos(alpha) * cos(gamma);
  R[1][2] = sin(alpha) * sin(beta) * cos(gamma) - cos(alpha) * sin(gamma);
  R[2][0] = -sin(beta);
  R[2][1] = cos(beta) * sin(gamma);
  R[2][2] = cos(beta) * cos(gamma);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trapz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L7:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L0:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm3
  movapd %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm3
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm3,%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D9(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: f64

tool: D9: 0.5

assistant: ```c
void trapz(int *m, int *n, double *x, double *y, double *out) {
  int k, j;
  double *yptr;
  yptr = y;
  for (k = 0; k < *n; k++) {
    out[k] = 0.0;
    for (j = 0; j < *m - 1; j++)
      out[k] += (x[j + 1] - x[j]) * (yptr[j + 1] + yptr[j]) * 0.5;
    yptr += *m;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trapz>:
  endbr64
  cmpl   $0x0,(%rsi)
  jle    L34
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rdi
  mov    $0x0,%ebx
  movsd  D9(%rip),%xmm2
L1:
  mov    %r8,%rsi
  movq   $0x0,(%r8)
  mov    (%r10),%edx
  cmp    $0x1,%edx
  jle    L22
  mov    $0x0,%eax
L16:
  movsd  0x8(%rdi,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  0x8(%rcx,%rax,8),%xmm1
  addsd  (%rcx,%rax,8),%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rsi)
  mov    (%r10),%edx
  add    $0x1,%rax
  lea    -0x1(%rdx),%r9d
  cmp    %eax,%r9d
  jg     L16
L22:
  movslq %edx,%rdx
  lea    (%rcx,%rdx,8),%rcx
  add    $0x1,%ebx
  add    $0x8,%r8
  cmp    %ebx,(%r11)
  jg     L1
  pop    %rbx
  ret
L34:
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: f64

tool: D9: 0.5

assistant: ```c
void trapz(int *m, int *n, double *x, double *y, double *out) {
  int k, j;
  double *yptr;
  yptr = y;
  for (k = 0; k < *n; k++) {
    out[k] = 0.0;
    for (j = 0; j < *m - 1; j++)
      out[k] += (x[j + 1] - x[j]) * (yptr[j + 1] + yptr[j]) * 0.5;
    yptr += *m;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trapz>:
  endbr64
  mov    %rsi,%r9
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    (%r9),%eax
  test   %eax,%eax
  jle    L37
  movslq (%rdi),%r10
  sub    $0x1,%eax
  movsd  D6(%rip),%xmm3
  pxor   %xmm4,%xmm4
  lea    0x8(%r8,%rax,8),%r11
  mov    %r10,%r9
  shl    $0x3,%r10
  lea    -0x2(%r9),%edi
  nopw   0x0(%rax,%rax,1)
L35:
  movq   $0x0,(%r8)
  xor    %eax,%eax
  movapd %xmm4,%xmm2
  cmp    $0x1,%r9d
  jle    L39
  nopl   0x0(%rax,%rax,1)
L17:
  movsd  0x8(%rsi,%rax,8),%xmm0
  movsd  0x8(%rdx,%rax,8),%xmm1
  mov    %rax,%rcx
  subsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdx,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%r8)
  cmp    %rdi,%rcx
  jne    L17
L39:
  add    $0x8,%r8
  add    %r10,%rdx
  cmp    %r8,%r11
  jne    L35
  ret
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: f64

tool: D6: 0.5

assistant: ```c
void trapz(int *m, int *n, double *x, double *y, double *out) {
  int k, j;
  double *yptr;
  yptr = y;
  for (k = 0; k < *n; k++) {
    out[k] = 0.0;
    for (j = 0; j < *m - 1; j++)
      out[k] += (x[j + 1] - x[j]) * (yptr[j + 1] + yptr[j]) * 0.5;
    yptr += *m;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trapz>:
  endbr64
  mov    %rsi,%r9
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    (%r9),%eax
  test   %eax,%eax
  jle    L13
  movslq (%rdi),%r10
  sub    $0x1,%eax
  movsd  D0(%rip),%xmm3
  pxor   %xmm4,%xmm4
  lea    0x8(%r8,%rax,8),%r11
  mov    %r10,%r9
  shl    $0x3,%r10
  lea    -0x2(%r9),%edi
  nopw   0x0(%rax,%rax,1)
L23:
  movq   $0x0,(%r8)
  xor    %eax,%eax
  movapd %xmm4,%xmm2
  cmp    $0x1,%r9d
  jle    L2
  nopl   0x0(%rax,%rax,1)
L22:
  movsd  0x8(%rsi,%rax,8),%xmm0
  movsd  0x8(%rdx,%rax,8),%xmm1
  mov    %rax,%rcx
  subsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdx,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%r8)
  cmp    %rcx,%rdi
  jne    L22
L2:
  add    $0x8,%r8
  add    %r10,%rdx
  cmp    %r8,%r11
  jne    L23
  ret
L13:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: f64

tool: D0: 0.5

assistant: ```c
void trapz(int *m, int *n, double *x, double *y, double *out) {
  int k, j;
  double *yptr;
  yptr = y;
  for (k = 0; k < *n; k++) {
    out[k] = 0.0;
    for (j = 0; j < *m - 1; j++)
      out[k] += (x[j + 1] - x[j]) * (yptr[j + 1] + yptr[j]) * 0.5;
    yptr += *m;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<msg_app_flt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  movd   %ecx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *msg_app_flt(const char *msg1, float n) {
  char *p = malloc(200);
  int b = sprintf(p, msg1, n);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<msg_app_flt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  movss  %xmm0,0xc(%rsp)
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movss  0xc(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *msg_app_flt(const char *msg1, float n) {
  char *p = malloc(200);
  int b = sprintf(p, msg1, n);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<msg_app_flt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xc8,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *msg_app_flt(const char *msg1, float n) {
  char *p = malloc(200);
  int b = sprintf(p, msg1, n);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msg_app_flt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xc8,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <malloc@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *msg_app_flt(const char *msg1, float n) {
  char *p = malloc(200);
  int b = sprintf(p, msg1, n);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L14:
  mov    -0xc(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L14
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D37
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string

tool: D16: 
Enter an integer > 

tool: D37: %d

tool: D23: 
%d

tool: D14: 
That's all, have a nice day!

assistant: ```c
int main(void) {
  int num;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  do {
    printf("\n%d", num % 10);
    num /= 10;
  } while (num > 0);
  printf("\nThat's all, have a nice day!\n");
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rbx
L10:
  mov    0x4(%rsp),%esi
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%edx
  jg     L10
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string
name: disassemble_data
arguments: data_label: D36
data_type: string
name: disassemble_data
arguments: data_label: D33
data_type: string

tool: D8: 
Enter an integer > 

tool: D12: %d

tool: D36: 
%d

tool: D33: 
That's all, have a nice day!

assistant: ```c
int main(void) {
  int num;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  do {
    printf("\n%d", num % 10);
    num /= 10;
  } while (num > 0);
  printf("\nThat's all, have a nice day!\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  lea    D27(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  nopl   0x0(%rax)
L10:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  cltd
  sar    $0x22,%rsi
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L10
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: string

tool: D18: 
Enter an integer > 

tool: D27: 
%d

tool: D13: %d

tool: D33: 
That's all, have a nice day!

assistant: ```c
int main(void) {
  int num;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  do {
    printf("\n%d", num % 10);
    num /= 10;
  } while (num > 0);
  printf("\nThat's all, have a nice day!\n");
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D11(%rip),%rdi
  lea    D15(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  nopl   0x0(%rax)
L14:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  cltd
  sar    $0x22,%rsi
  sub    %edx,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%eax
  jg     L14
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D11: 
Enter an integer > 

tool: D15: 
%d

tool: D20: %d

tool: D1: 
That's all, have a nice day!

assistant: ```c
int main(void) {
  int num;
  printf("\nEnter an integer > ");
  scanf("%d", &num);
  do {
    printf("\n%d", num % 10);
    num /= 10;
  } while (num > 0);
  printf("\nThat's all, have a nice day!\n");
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L51
  mov    $0x0,%eax
  jmp    L17
L51:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L9
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L9
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L9:
  movl   $0x2,-0x8(%rbp)
  jmp    L32
L52:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L71
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  jmp    L37
L71:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L37:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L52
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int rob(int *nums, int numsSize) {
  int tmp;
  if (numsSize == 0) {
    return 0;
  }
  if (numsSize >= 1 && nums[1] < nums[0]) {
    nums[1] = nums[0];
  }
  for (int i = 2; i < numsSize; i++) {
    tmp = nums[i - 2] + nums[i];
    if (tmp > nums[i - 1]) {
      nums[i] = nums[i - 2] + nums[i];
    } else {
      nums[i] = nums[i - 1];
    }
  }
  return nums[numsSize - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rob>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L11
  jle    L10
  mov    (%rdi),%eax
  cmp    %eax,0x4(%rdi)
  jge    L10
  mov    %eax,0x4(%rdi)
L10:
  cmp    $0x2,%esi
  jle    L27
  mov    %rdi,%rax
  lea    -0x3(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r8
L49:
  mov    0x8(%rax),%edx
  add    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,0x8(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L49
L27:
  movslq %esi,%rsi
  mov    -0x4(%rdi,%rsi,4),%eax
L11:
  ret
```

assistant: ```c
int rob(int *nums, int numsSize) {
  int tmp;
  if (numsSize == 0) {
    return 0;
  }
  if (numsSize >= 1 && nums[1] < nums[0]) {
    nums[1] = nums[0];
  }
  for (int i = 2; i < numsSize; i++) {
    tmp = nums[i - 2] + nums[i];
    if (tmp > nums[i - 1]) {
      nums[i] = nums[i - 2] + nums[i];
    } else {
      nums[i] = nums[i - 1];
    }
  }
  return nums[numsSize - 1];
}
```