ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<condense_v6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x10,-0x8(%rbp)
  jbe    L19
  mov    -0x28(%rbp),%rax
  add    $0x7,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2e,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%rax
  lea    -0x7(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L25:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L4
L19:
  nop
L4:
  leave
  ret
```

assistant: ```c
void condense_v6(char *s) {
  size_t len = strlen(s);
  char *p, *q;
  if (len <= 16)
    return;
  p = s + 7;
  *p++ = '.';
  *p++ = '.';
  q = s + len - 7;
  while (*q) {
    *p++ = *q++;
  }
  *p = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<condense_v6>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x10,%rax
  jbe    L22
  movb   $0x2e,0x7(%rbx)
  lea    0x9(%rbx),%rdx
  movb   $0x2e,0x8(%rbx)
  lea    -0x7(%rbx,%rax,1),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L2
L25:
  add    $0x1,%rcx
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L25
L2:
  movb   $0x0,(%rdx)
L22:
  pop    %rbx
  ret
```

assistant: ```c
void condense_v6(char *s) {
  size_t len = strlen(s);
  char *p, *q;
  if (len <= 16)
    return;
  p = s + 7;
  *p++ = '.';
  *p++ = '.';
  q = s + len - 7;
  while (*q) {
    *p++ = *q++;
  }
  *p = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<condense_v6>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x10,%rax
  jbe    L28
  mov    $0x2e2e,%ecx
  lea    0x9(%rbx),%rdx
  mov    %cx,0x7(%rbx)
  lea    -0x7(%rbx,%rax,1),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L29
  nopl   0x0(%rax)
L13:
  add    $0x1,%rcx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L13
L29:
  movb   $0x0,(%rdx)
L28:
  pop    %rbx
  ret
```

assistant: ```c
void condense_v6(char *s) {
  size_t len = strlen(s);
  char *p, *q;
  if (len <= 16)
    return;
  p = s + 7;
  *p++ = '.';
  *p++ = '.';
  q = s + len - 7;
  while (*q) {
    *p++ = *q++;
  }
  *p = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<condense_v6>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x10,%rax
  jbe    L8
  mov    $0x2e2e,%ecx
  lea    0x9(%rbx),%rdx
  mov    %cx,0x7(%rbx)
  lea    -0x7(%rbx,%rax,1),%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L0
  nopl   0x0(%rax)
L21:
  add    $0x1,%rcx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L21
L0:
  movb   $0x0,(%rdx)
L8:
  pop    %rbx
  ret
```

assistant: ```c
void condense_v6(char *s) {
  size_t len = strlen(s);
  char *p, *q;
  if (len <= 16)
    return;
  p = s + 7;
  *p++ = '.';
  *p++ = '.';
  q = s + len - 7;
  while (*q) {
    *p++ = *q++;
  }
  *p = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L1:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L19
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
L19:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char *str1;
  unsigned char *str2;
  str1 = (unsigned char *)s1;
  str2 = (unsigned char *)s2;
  while (*str1 == *str2 && *str1 != 0 && *str2 != 0) {
    str1++;
    str2++;
  }
  return (*str1 - *str2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  test   %al,%al
  setne  %r8b
  cmp    %cl,%al
  sete   %dl
  test   %dl,%r8b
  je     L34
  test   %cl,%cl
  je     L34
  mov    $0x1,%edx
L25:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  setne  %r9b
  cmp    %cl,%al
  sete   %r8b
  test   %r8b,%r9b
  je     L34
  test   %cl,%cl
  jne    L25
L34:
  movzbl %al,%eax
  movzbl %cl,%ecx
  sub    %ecx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char *str1;
  unsigned char *str2;
  str1 = (unsigned char *)s1;
  str2 = (unsigned char *)s2;
  while (*str1 == *str2 && *str1 != 0 && *str2 != 0) {
    str1++;
    str2++;
  }
  return (*str1 - *str2);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  mov    $0x1,%edx
  cmp    %cl,%al
  je     L26
  jmp    L28
  nopl   (%rax)
L16:
  test   %cl,%cl
  je     L15
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L8
L26:
  test   %al,%al
  jne    L16
  movzbl %cl,%eax
  neg    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
  nopl   0x0(%rax)
L8:
  movzbl %al,%eax
  movzbl %cl,%ecx
L28:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char *str1;
  unsigned char *str2;
  str1 = (unsigned char *)s1;
  str2 = (unsigned char *)s2;
  while (*str1 == *str2 && *str1 != 0 && *str2 != 0) {
    str1++;
    str2++;
  }
  return (*str1 - *str2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  mov    $0x1,%edx
  cmp    %cl,%al
  je     L48
  jmp    L39
  nopl   (%rax)
L35:
  test   %cl,%cl
  je     L3
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L30
L48:
  test   %al,%al
  jne    L35
  movzbl %cl,%eax
  neg    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
  nopl   0x0(%rax)
L30:
  movzbl %al,%eax
  movzbl %cl,%ecx
L39:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  unsigned char *str1;
  unsigned char *str2;
  str1 = (unsigned char *)s1;
  str2 = (unsigned char *)s2;
  while (*str1 == *str2 && *str1 != 0 && *str2 != 0) {
    str1++;
    str2++;
  }
  return (*str1 - *str2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mostrarVetorInteiros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string

tool: D11: [ 

tool: D18: %d 

tool: D6: ]

assistant: ```c
void mostrarVetorInteiros(int v[], int n) {
  int i;
  printf("[ ");
  for (i = 0; i < n; i++)
    printf("%d ", v[i]);
  printf("]\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mostrarVetorInteiros>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L4
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D11(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
L4:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string

tool: D22: [ 

tool: D11: %d 

tool: D28: ]

assistant: ```c
void mostrarVetorInteiros(int v[], int n) {
  int i;
  printf("[ ");
  for (i = 0; i < n; i++)
    printf("%d ", v[i]);
  printf("]\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mostrarVetorInteiros>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D21(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L19
  lea    -0x1(%rbp),%eax
  lea    D18(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
L19:
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D21: [ 

tool: D18: %d 

tool: D0: ]

assistant: ```c
void mostrarVetorInteiros(int v[], int n) {
  int i;
  printf("[ ");
  for (i = 0; i < n; i++)
    printf("%d ", v[i]);
  printf("]\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mostrarVetorInteiros>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L19
  lea    -0x1(%rbp),%eax
  lea    D17(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  xchg   %ax,%ax
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
L19:
  pop    %rbx
  lea    D13(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string

tool: D5: [ 

tool: D17: %d 

tool: D13: ]

assistant: ```c
void mostrarVetorInteiros(int v[], int n) {
  int i;
  printf("[ ");
  for (i = 0; i < n; i++)
    printf("%d ", v[i]);
  printf("]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L33
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L33
  mov    -0x4(%rbp),%eax
  jmp    L40
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L43
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L43
  mov    -0x8(%rbp),%eax
  jmp    L40
L43:
  mov    -0xc(%rbp),%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  if (a <= b && a <= c)
    return a;
  if (b <= a && b <= c)
    return b;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%ecx
  cmovle %esi,%ecx
  mov    %edi,%eax
  cmp    %ecx,%edi
  jle    L2
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edi,%esi
  mov    %esi,%eax
  cmovg  %edx,%eax
L2:
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  if (a <= b && a <= c)
    return a;
  if (b <= a && b <= c)
    return b;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%ecx
  mov    %edi,%eax
  cmovle %esi,%ecx
  cmp    %ecx,%edi
  jle    L1
  cmp    %edx,%edi
  cmovg  %edx,%eax
  cmp    %eax,%esi
  mov    %esi,%eax
  cmovg  %edx,%eax
L1:
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  if (a <= b && a <= c)
    return a;
  if (b <= a && b <= c)
    return b;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%ecx
  mov    %edi,%eax
  cmovle %esi,%ecx
  cmp    %ecx,%edi
  jle    L2
  cmp    %edx,%edi
  cmovg  %edx,%eax
  cmp    %eax,%esi
  mov    %esi,%eax
  cmovg  %edx,%eax
L2:
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  if (a <= b && a <= c)
    return a;
  if (b <= a && b <= c)
    return b;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Create_Action_Message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%r14,%r15,2),%rdx
  lea    0x108(%rdx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L11
  mov    %rax,%rdi
  mov    %rbx,%r9
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x0,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    $0xfffffe0d,%eax
  jmp    L7
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: <?xml version="1.0" encoding="utf-8"?>
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/" s:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<s:Body>
<u:%s xmlns:u="urn:schemas-upnp-org:service:%s">
%s</u:%s>
</s:Body>
</s:Envelope>


assistant: ```c
int Create_Action_Message(const char *service_type, const char *action_name, const char *action_params, char **action_message) {
  *action_message = (char *)malloc(strlen("<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                                          "<s:Envelope xmlns:s="
                                          "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                                          "s:encodingStyle="
                                          "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                                          "<s:Body>\r\n"
                                          "<u:%s xmlns:u="
                                          "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                                          "</u:%s>\r\n"
                                          "</s:Body>\r\n"
                                          "</s:Envelope>\r\n") +
                                   strlen(service_type) + strlen(action_name) + strlen(action_params) + strlen(action_name) + 1);
  if (NULL == *action_message) {
    return -499;
  }
  (void)sprintf(*action_message,
                "<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                "<s:Envelope xmlns:s="
                "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                "s:encodingStyle="
                "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                "<s:Body>\r\n"
                "<u:%s xmlns:u="
                "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                "</u:%s>\r\n"
                "</s:Body>\r\n"
                "</s:Envelope>\r\n",
                action_name, service_type, action_params, action_name);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Create_Action_Message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  lea    (%r14,%r15,2),%rdx
  lea    0x108(%rdx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  mov    %r12,%r9
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  xor    %eax,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    $0xfffffe0d,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: <?xml version="1.0" encoding="utf-8"?>
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/" s:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<s:Body>
<u:%s xmlns:u="urn:schemas-upnp-org:service:%s">
%s</u:%s>
</s:Body>
</s:Envelope>


assistant: ```c
int Create_Action_Message(const char *service_type, const char *action_name, const char *action_params, char **action_message) {
  *action_message = (char *)malloc(strlen("<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                                          "<s:Envelope xmlns:s="
                                          "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                                          "s:encodingStyle="
                                          "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                                          "<s:Body>\r\n"
                                          "<u:%s xmlns:u="
                                          "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                                          "</u:%s>\r\n"
                                          "</s:Body>\r\n"
                                          "</s:Envelope>\r\n") +
                                   strlen(service_type) + strlen(action_name) + strlen(action_params) + strlen(action_name) + 1);
  if (NULL == *action_message) {
    return -499;
  }
  (void)sprintf(*action_message,
                "<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                "<s:Envelope xmlns:s="
                "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                "s:encodingStyle="
                "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                "<s:Body>\r\n"
                "<u:%s xmlns:u="
                "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                "</u:%s>\r\n"
                "</s:Body>\r\n"
                "</s:Envelope>\r\n",
                action_name, service_type, action_params, action_name);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Create_Action_Message>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <strlen@plt>
  lea    (%r14,%r15,2),%rdx
  lea    0x108(%rdx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L19
  mov    %rax,%rdi
  mov    %r12,%r9
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D1(%rip),%rsi
  call   <sprintf@plt>
  xor    %eax,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    $0xfffffe0d,%eax
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: <?xml version="1.0" encoding="utf-8"?>
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/" s:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<s:Body>
<u:%s xmlns:u="urn:schemas-upnp-org:service:%s">
%s</u:%s>
</s:Body>
</s:Envelope>


assistant: ```c
int Create_Action_Message(const char *service_type, const char *action_name, const char *action_params, char **action_message) {
  *action_message = (char *)malloc(strlen("<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                                          "<s:Envelope xmlns:s="
                                          "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                                          "s:encodingStyle="
                                          "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                                          "<s:Body>\r\n"
                                          "<u:%s xmlns:u="
                                          "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                                          "</u:%s>\r\n"
                                          "</s:Body>\r\n"
                                          "</s:Envelope>\r\n") +
                                   strlen(service_type) + strlen(action_name) + strlen(action_params) + strlen(action_name) + 1);
  if (NULL == *action_message) {
    return -499;
  }
  (void)sprintf(*action_message,
                "<?xml version=\"1.0\" encoding=\"utf-8\"?>\r\n"
                "<s:Envelope xmlns:s="
                "\"http://schemas.xmlsoap.org/soap/envelope/\" "
                "s:encodingStyle="
                "\"http://schemas.xmlsoap.org/soap/encoding/\">\r\n"
                "<s:Body>\r\n"
                "<u:%s xmlns:u="
                "\"urn:schemas-upnp-org:service:%s\">\r\n%s"
                "</u:%s>\r\n"
                "</s:Body>\r\n"
                "</s:Envelope>\r\n",
                action_name, service_type, action_params, action_name);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <def_prog_mode@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <reset_prog_mode@plt>
  nop
  leave
  ret
```

assistant: ```c
void run_command(char *command) {
  def_prog_mode();
  endwin();
  system(command);
  reset_prog_mode();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_command>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <def_prog_mode@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <reset_prog_mode@plt>
  pop    %rbx
  ret
```

assistant: ```c
void run_command(char *command) {
  def_prog_mode();
  endwin();
  system(command);
  reset_prog_mode();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<run_command>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <def_prog_mode@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <reset_prog_mode@plt>
```

assistant: ```c
void run_command(char *command) {
  def_prog_mode();
  endwin();
  system(command);
  reset_prog_mode();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_command>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <def_prog_mode@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1090 <reset_prog_mode@plt>
```

assistant: ```c
void run_command(char *command) {
  def_prog_mode();
  endwin();
  system(command);
  reset_prog_mode();
}
```