ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fatx_mknod>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  lea    D4(%rip),%rdx
  mov    $0x5,%esi
  call   <fatx_print@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: fatx_mknod(path="%s")


assistant: ```c
int fatx_mknod(struct fatx_fs *fs, char const *path) {
  fatx_print(fs, 5, "fatx_mknod(path=\"%s\")\n", path);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fatx_mknod>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rcx
  lea    D9(%rip),%rdx
  mov    $0x5,%esi
  call   <fatx_print@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: fatx_mknod(path="%s")


assistant: ```c
int fatx_mknod(struct fatx_fs *fs, char const *path) {
  fatx_print(fs, 5, "fatx_mknod(path=\"%s\")\n", path);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<half_chop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L46
L85:
  addq   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L85
  jmp    L10
L14:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
L60:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L61
L62:
  addq   $0x1,-0x8(%rbp)
L61:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L62
  jmp    L26
L4:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void half_chop(char *string, char *arg1, char *arg2) {
  for (; isspace(*string); string++)
    ;
  for (; !isspace(*arg1 = *string) && *string; string++, arg1++)
    ;
  *arg1 = '\0';
  for (; isspace(*string); string++)
    ;
  for (; *arg2 = *string; string++, arg2++)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<half_chop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  jmp    L72
L81:
  add    $0x1,%rbx
L72:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L81
  jmp    L62
L64:
  add    $0x1,%rbx
  add    $0x1,%rbp
L62:
  movzbl (%rbx),%edi
  mov    %dil,0x0(%rbp)
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L79
  cmpb   $0x0,(%rbx)
  jne    L64
L79:
  movb   $0x0,0x0(%rbp)
L15:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L25
  add    $0x1,%rbx
  jmp    L15
L25:
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  test   %al,%al
  je     L53
  mov    $0x1,%eax
L19:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L19
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void half_chop(char *string, char *arg1, char *arg2) {
  for (; isspace(*string); string++)
    ;
  for (; !isspace(*arg1 = *string) && *string; string++, arg1++)
    ;
  *arg1 = '\0';
  for (; isspace(*string); string++)
    ;
  for (; *arg2 = *string; string++, arg2++)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<half_chop>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L74:
  add    $0x1,%rbx
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L74
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L79:
  cmpb   $0x0,(%rbx)
  je     L16
  add    $0x1,%rbx
  add    $0x1,%rbp
L43:
  movsbl (%rbx),%edi
  mov    %dil,0x0(%rbp)
  call   <isspace@plt>
  test   %rax,%rax
  je     L79
L16:
  movb   $0x0,0x0(%rbp)
  jmp    L29
  nopl   0x0(%rax)
L67:
  add    $0x1,%rbx
L29:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L67
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  test   %al,%al
  je     L62
  mov    $0x1,%eax
  nopl   0x0(%rax)
L18:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L18
L62:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void half_chop(char *string, char *arg1, char *arg2) {
  for (; isspace(*string); string++)
    ;
  for (; !isspace(*arg1 = *string) && *string; string++, arg1++)
    ;
  *arg1 = '\0';
  for (; isspace(*string); string++)
    ;
  for (; *arg2 = *string; string++, arg2++)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<half_chop>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rbx
L20:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L86:
  cmpb   $0x0,(%rbx)
  je     L45
  add    $0x1,%rbx
  add    $0x1,%rbp
L19:
  movsbl (%rbx),%edi
  mov    %dil,0x0(%rbp)
  call   <isspace@plt>
  test   %rax,%rax
  je     L86
L45:
  movb   $0x0,0x0(%rbp)
  jmp    L34
  nopl   0x0(%rax)
L9:
  add    $0x1,%rbx
L34:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  test   %al,%al
  je     L33
  mov    $0x1,%eax
  nopl   0x0(%rax)
L39:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L39
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void half_chop(char *string, char *arg1, char *arg2) {
  for (; isspace(*string); string++)
    ;
  for (; !isspace(*arg1 = *string) && *string; string++, arg1++)
    ;
  *arg1 = '\0';
  for (; isspace(*string); string++)
    ;
  for (; *arg2 = *string; string++, arg2++)
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<separator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L17:
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
void separator(int repeat, char c) {
  int x;
  long int r;
  for (x = 0; x < repeat; x++)
    putchar(c);
  putchar('\n');
  r = rand();
  printf("%d\n", r);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<separator>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L15
  mov    %edi,%r12d
  mov    $0x0,%ebx
  movsbl %sil,%ebp
L7:
  mov    %ebp,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L7
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: %d


assistant: ```c
void separator(int repeat, char c) {
  int x;
  long int r;
  for (x = 0; x < repeat; x++)
    putchar(c);
  putchar('\n');
  r = rand();
  printf("%d\n", r);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<separator>:
  endbr64
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L19
  nopl   0x0(%rax)
L16:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L16
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <rand@plt>
  pop    %rbx
  lea    D4(%rip),%rdi
  pop    %rbp
  mov    %rax,%rsi
  pop    %r12
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
void separator(int repeat, char c) {
  int x;
  long int r;
  for (x = 0; x < repeat; x++)
    putchar(c);
  putchar('\n');
  r = rand();
  printf("%d\n", r);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<separator>:
  endbr64
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  test   %edi,%edi
  jle    L9
  nopl   0x0(%rax)
L6:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L6
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <rand@plt>
  pop    %rbx
  lea    D1(%rip),%rdi
  pop    %rbp
  mov    %rax,%rsi
  pop    %r12
  jmp    1080 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: %d


assistant: ```c
void separator(int repeat, char c) {
  int x;
  long int r;
  for (x = 0; x < repeat; x++)
    putchar(c);
  putchar('\n');
  r = rand();
  printf("%d\n", r);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_right_fork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x2,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_busy@plt>
  nop
  leave
  ret
```

assistant: ```c
void get_right_fork(int mine) {
  int item = (((mine) + 1) % 5);
  set_busy(item);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_right_fork>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  call   <set_busy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void get_right_fork(int mine) {
  int item = (((mine) + 1) % 5);
  set_busy(item);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_right_fork>:
  endbr64
  add    $0x1,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  jmp    1050 <set_busy@plt>
```

assistant: ```c
void get_right_fork(int mine) {
  int item = (((mine) + 1) % 5);
  set_busy(item);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_right_fork>:
  endbr64
  add    $0x1,%edi
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edi
  jmp    1050 <set_busy@plt>
```

assistant: ```c
void get_right_fork(int mine) {
  int item = (((mine) + 1) % 5);
  set_busy(item);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<t8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x101c(%rbp)
  jmp    L19
L70:
  movl   $0x0,-0x1018(%rbp)
  jmp    L45
L72:
  mov    -0x1018(%rbp),%eax
  cltq
  movl   $0x0,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x1018(%rbp)
L45:
  cmpl   $0x3ff,-0x1018(%rbp)
  jle    L72
  movl   $0x0,-0x1014(%rbp)
  jmp    L35
L13:
  mov    -0x1014(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x1014(%rbp),%eax
  cltq
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x1014(%rbp)
L35:
  cmpl   $0x3ff,-0x1014(%rbp)
  jle    L13
  movl   $0x0,-0x1018(%rbp)
  jmp    L84
L37:
  mov    -0x1018(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x1018(%rbp)
L84:
  cmpl   $0x3ff,-0x1018(%rbp)
  jle    L37
  shll   -0x101c(%rbp)
L19:
  cmpl   $0x400,-0x101c(%rbp)
  jle    L70
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void t8() {
  int arr[1024];
  int gangs;
  for (gangs = 1; gangs <= 1024; gangs <<= 1) {
    int i;
    for (i = 0; i < 1024; i++)
      arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(gangs) num_workers(1) vector_length(32)
    {
      int j;
#pragma acc loop gang
      for (j = 0; j < 1024; j++)
        arr[j]++;
    }
    for (i = 0; i < 1024; i++)
      assert(arr[i] == 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<t8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    $0xb,%r12d
  lea    0x1000(%rsp),%rbp
L2:
  mov    %rsp,%rbx
  mov    %rbx,%rax
L28:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L28
  mov    %rbx,%rax
L38:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L38
L16:
  cmpl   $0x1,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L16
  sub    $0x1,%r12d
  jne    L2
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t8() {
  int arr[1024];
  int gangs;
  for (gangs = 1; gangs <= 1024; gangs <<= 1) {
    int i;
    for (i = 0; i < 1024; i++)
      arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(gangs) num_workers(1) vector_length(32)
    {
      int j;
#pragma acc loop gang
      for (j = 0; j < 1024; j++)
        arr[j]++;
    }
    for (i = 0; i < 1024; i++)
      assert(arr[i] == 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<t8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    $0xb,%r13d
  xor    %r14d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1000(%rsp),%rbp
L13:
  mov    %r14,%rax
  mov    $0x200,%ecx
  mov    %r12,%rdi
  mov    %r12,%rbx
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rax
  nopw   0x0(%rax,%rax,1)
L11:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L11
  nopl   0x0(%rax)
L6:
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %rbx,%rbp
  jne    L6
  sub    $0x1,%r13d
  jne    L13
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t8() {
  int arr[1024];
  int gangs;
  for (gangs = 1; gangs <= 1024; gangs <<= 1) {
    int i;
    for (i = 0; i < 1024; i++)
      arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(gangs) num_workers(1) vector_length(32)
    {
      int j;
#pragma acc loop gang
      for (j = 0; j < 1024; j++)
        arr[j]++;
    }
    for (i = 0; i < 1024; i++)
      assert(arr[i] == 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<t8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    $0xb,%r13d
  xor    %r14d,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1000(%rsp),%rbp
L38:
  mov    %r14,%rax
  mov    $0x200,%ecx
  mov    %r12,%rdi
  mov    %r12,%rbx
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rax
  nopw   0x0(%rax,%rax,1)
L24:
  movdqa D4(%rip),%xmm0
  paddd  (%rax),%xmm0
  add    $0x10,%rax
  movaps %xmm0,-0x10(%rax)
  cmp    %rbp,%rax
  jne    L24
  nopl   0x0(%rax)
L15:
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %rbx,%rbp
  jne    L15
  sub    $0x1,%r13d
  jne    L38
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: byte[16]

tool: {"D4": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void t8() {
  int arr[1024];
  int gangs;
  for (gangs = 1; gangs <= 1024; gangs <<= 1) {
    int i;
    for (i = 0; i < 1024; i++)
      arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(gangs) num_workers(1) vector_length(32)
    {
      int j;
#pragma acc loop gang
      for (j = 0; j < 1024; j++)
        arr[j]++;
    }
    for (i = 0; i < 1024; i++)
      assert(arr[i] == 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kprint_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L48
  cmpl   $0x0,-0x20(%rbp)
  js     L48
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <get_offset@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L7
L48:
  mov    $0x0,%eax
  call   <get_cursor_offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <get_offset_col@plt>
  mov    %eax,-0x1c(%rbp)
L7:
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L47:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    $0xf,%ecx
  mov    %eax,%edi
  call   <print_char@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <get_offset_col@plt>
  mov    %eax,-0x1c(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  nop
  nop
  leave
  ret
```

assistant: ```c
void kprint_at(char *message, int col, int row) {
  int offset;
  if (col >= 0 && row >= 0)
    offset = get_offset(col, row);
  else {
    offset = get_cursor_offset();
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
  int i = 0;
  while (message[i] != 0) {
    offset = print_char(message[i++], col, row, 0x0f);
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kprint_at>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%eax
  or     %edx,%eax
  js     L28
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    %ebx,%edi
  call   <get_offset@plt>
L18:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L1
L6:
  movsbl %dil,%edi
  mov    $0xf,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  call   <print_char@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <get_offset_col@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  test   %dil,%dil
  jne    L6
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    $0x0,%eax
  call   <get_cursor_offset@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <get_offset_col@plt>
  mov    %eax,%ebx
  jmp    L18
```

assistant: ```c
void kprint_at(char *message, int col, int row) {
  int offset;
  if (col >= 0 && row >= 0)
    offset = get_offset(col, row);
  else {
    offset = get_cursor_offset();
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
  int i = 0;
  while (message[i] != 0) {
    offset = print_char(message[i++], col, row, 0x0f);
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kprint_at>:
  endbr64
  mov    %esi,%eax
  push   %r12
  or     %edx,%eax
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  js     L3
  mov    %esi,%ebp
  mov    %edx,%esi
  mov    %edx,%r12d
  mov    %ebp,%edi
  call   <get_offset@plt>
L38:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L9
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    $0xf,%ecx
  add    $0x1,%rbx
  call   <print_char@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <get_offset_col@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%ebp
  test   %dil,%dil
  jne    L25
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <get_cursor_offset@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <get_offset_col@plt>
  mov    %eax,%ebp
  jmp    L38
```

assistant: ```c
void kprint_at(char *message, int col, int row) {
  int offset;
  if (col >= 0 && row >= 0)
    offset = get_offset(col, row);
  else {
    offset = get_cursor_offset();
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
  int i = 0;
  while (message[i] != 0) {
    offset = print_char(message[i++], col, row, 0x0f);
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<kprint_at>:
  endbr64
  mov    %esi,%eax
  push   %r12
  or     %edx,%eax
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  js     L21
  mov    %esi,%ebp
  mov    %edx,%esi
  mov    %edx,%r12d
  mov    %ebp,%edi
  call   <get_offset@plt>
L7:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L39
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    $0xf,%ecx
  add    $0x1,%rbx
  call   <print_char@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <get_offset_col@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%ebp
  test   %dil,%dil
  jne    L23
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  call   <get_cursor_offset@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <get_offset_row@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <get_offset_col@plt>
  mov    %eax,%ebp
  jmp    L7
```

assistant: ```c
void kprint_at(char *message, int col, int row) {
  int offset;
  if (col >= 0 && row >= 0)
    offset = get_offset(col, row);
  else {
    offset = get_cursor_offset();
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
  int i = 0;
  while (message[i] != 0) {
    offset = print_char(message[i++], col, row, 0x0f);
    row = get_offset_row(offset);
    col = get_offset_col(offset);
  }
}
```