user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  lea    D10(%rip),%r15
  lea    D12(%rip),%r13
  jmp    L198
L66:
  add    $0x1,%ebp
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L50:
  cmp    %r12d,%ebp
  je     L188
L95:
  mov    %ebx,%edx
  add    $0x1,%ebx
  mov    %ebx,%eax
  lea    0x3(%rdx),%ecx
  sub    $0x2,%edx
  test   $0xfffffffd,%edx
  je     L66
  test   $0x1,%bl
  je     L50
  movslq %ebx,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ebx,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %edx,%ebx
  je     L50
  test   $0x3,%al
  je     L50
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ebx,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edx
  cmp    %edx,%ebx
  je     L50
  movslq %ebx,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %ebx,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  cmp    %edx,%ebx
  je     L50
  movslq %ebx,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ebx,%edx
  sar    $0x2,%edx
  mov    %ebx,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    0x0(,%rdx,8),%edi
  sub    %edx,%edi
  cmp    %edi,%ebx
  je     L50
  test   $0x7,%al
  je     L50
  mov    $0x9,%r8d
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L50
  test   $0x1,%cl
  je     L50
  mov    %ecx,%eax
  cltd
  idiv   %r14d
  test   %edx,%edx
  je     L50
  test   $0x3,%cl
  je     L50
  mov    $0x5,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L50
  mov    $0x6,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L50
  mov    $0x7,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L50
  test   $0x7,%cl
  je     L50
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L50
  add    $0x1,%ebp
  mov    %ecx,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L50
L188:
  mov    %r12d,%ebp
L102:
  cmp    $0x9,%ebp
  jg     L174
L198:
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  je     L102
  mov    $0x3,%r14d
  jmp    L95
L174:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D10: (%d, %d)


tool: D12: (%d , %d)


assistant: ```c
int main() {
  int fp, sp, i, n;
  i = 0;
  n = 0;
  fp = 1;
  sp = 1;
  while (i < 10) {
    n++;
    while (i != n) {
      fp++;
      sp = fp + 2;
      if (fp == 3 || fp == 5) {
        i++;
        printf("(%d , %d)\n", fp, sp);
      } else {
        if (fp % 2 != 0 && fp % 3 != 0 && fp % 4 != 0 && fp % 5 != 0 && fp % 6 != 0 && fp % 7 != 0 && fp % 8 != 0 && fp % 9 != 0 && sp % 2 != 0 && sp % 3 != 0 && sp % 4 != 0 && sp % 5 != 0 && sp % 6 != 0 && sp % 7 != 0 && sp % 8 != 0 && sp % 9 != 0) {
          i++;
          printf("(%d, %d)\n", fp, sp);
        }
      }
    }
  }
  return 0;
}
```