ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<core_extend>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <core_nil@plt>
  xor    %eax,%eax
  call   <core_cons@plt>
  xor    %eax,%eax
  call   <core_cons@plt>
  xor    %eax,%eax
  call   <core_swap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <core_cons@plt>
```

assistant: ```c
void core_extend(void) {
  core_nil();
  core_cons();
  core_cons();
  core_swap();
  core_cons();
}
```
user: What is the c source code of the assembly code below:

```asm
<core_extend>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <core_nil@plt>
  xor    %eax,%eax
  call   <core_cons@plt>
  xor    %eax,%eax
  call   <core_cons@plt>
  xor    %eax,%eax
  call   <core_swap@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <core_cons@plt>
```

assistant: ```c
void core_extend(void) {
  core_nil();
  core_cons();
  core_cons();
  core_swap();
  core_cons();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L112
L79:
  cmpl   $0x0,-0x14(%rbp)
  je     L36
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L90
L36:
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L66:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L66
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L90:
  movl   $0x0,-0xc(%rbp)
  jmp    L86
L38:
  cmpl   $0x0,-0xc(%rbp)
  jne    L98
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L98:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  addl   $0x1,-0xc(%rbp)
L86:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L38
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  addl   $0x1,-0x14(%rbp)
L112:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L79
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D47
datatype: string
name: read_data
arguments: data_label: D67
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D24
datatype: string
name: read_data
arguments: data_label: D28
datatype: string

tool: D47: Perimiter of square: 

tool: D67: %d

tool: D20: X

tool: D24: X


tool: D28:  

assistant: ```c
int main(void) {
  int side;
  printf("Perimiter of square: ");
  scanf("%d", &side);
  int i, j, k;
  for (i = 0; i < side; i++) {
    if (i == 0 || i == side - 1) {
      for (j = 0; j < side - 1; j++) {
        printf("X");
      }
      printf("X\n");
    } else {
      for (k = 0; k < side - 1; k++) {
        if (k == 0)
          printf("X");
        else
          printf(" ");
      }
      printf("X\n");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L123
  mov    $0x0,%r12d
  lea    D1(%rip),%r13
  lea    D41(%rip),%rbp
  lea    D20(%rip),%r14
  jmp    L104
L127:
  mov    $0x0,%ebx
  cmpl   $0x1,0x4(%rsp)
  jle    L16
L19:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L19
L16:
  mov    %r14,%rdi
  call   <printf@plt>
L26:
  add    $0x1,%r12d
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jle    L123
L104:
  test   %r12d,%r12d
  je     L127
  sub    $0x1,%eax
  cmp    %r12d,%eax
  je     L127
  mov    $0x0,%ebx
  cmpl   $0x1,0x4(%rsp)
  jg     L70
L105:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L26
L59:
  mov    %r13,%rdi
  call   <printf@plt>
L76:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L105
L70:
  test   %ebx,%ebx
  jne    L59
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L76
L123:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D43
data_type: string
name: retrieve_data
arguments: tag: D31
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D41
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string

tool: D43: Perimiter of square: 

tool: D31: %d

tool: D1:  

tool: D41: X

tool: D20: X


assistant: ```c
int main(void) {
  int side;
  printf("Perimiter of square: ");
  scanf("%d", &side);
  int i, j, k;
  for (i = 0; i < side; i++) {
    if (i == 0 || i == side - 1) {
      for (j = 0; j < side - 1; j++) {
        printf("X");
      }
      printf("X\n");
    } else {
      for (k = 0; k < side - 1; k++) {
        if (k == 0)
          printf("X");
        else
          printf(" ");
      }
      printf("X\n");
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D38(%rip),%rdi
  lea    D8(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D30(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L43
  nopl   (%rax)
L92:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  je     L101
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  je     L101
  cmp    $0x1,%eax
  jne    L60
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L85:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L39
L60:
  test   %ebx,%ebx
  je     L85
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L60
L39:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jg     L92
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L101:
  cmp    $0x1,%eax
  je     L39
  nopl   (%rax)
L25:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L25
  jmp    L39
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D38
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D30
type_infered: string
name: retrieve_data
arguments: label: D37
type_infered: string

tool: D38: Perimiter of square: 

tool: D8: X


tool: D9:  

tool: D30: X

tool: D37: %d

assistant: ```c
int main(void) {
  int side;
  printf("Perimiter of square: ");
  scanf("%d", &side);
  int i, j, k;
  for (i = 0; i < side; i++) {
    if (i == 0 || i == side - 1) {
      for (j = 0; j < side - 1; j++) {
        printf("X");
      }
      printf("X\n");
    } else {
      for (k = 0; k < side - 1; k++) {
        if (k == 0)
          printf("X");
        else
          printf(" ");
      }
      printf("X\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%rdi
  lea    D48(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D30(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L117
  nopl   (%rax)
L95:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  je     L25
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  je     L25
  cmp    $0x1,%eax
  jne    L119
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L77:
  mov    $0x1,%ebx
L20:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L105
L119:
  test   %ebx,%ebx
  jne    L20
  mov    %rbp,%rdi
  call   <printf@plt>
  cmpl   $0x2,0x4(%rsp)
  jg     L77
L105:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jg     L95
L117:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  cmp    $0x1,%eax
  je     L105
  nopl   (%rax)
L113:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L113
  jmp    L105
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D48
type_infered: string
name: read_data
arguments: label: D20
type_infered: string
name: read_data
arguments: label: D30
type_infered: string
name: read_data
arguments: label: D41
type_infered: string

tool: D4: Perimiter of square: 

tool: D48: X


tool: D20:  

tool: D30: X

tool: D41: %d

assistant: ```c
int main(void) {
  int side;
  printf("Perimiter of square: ");
  scanf("%d", &side);
  int i, j, k;
  for (i = 0; i < side; i++) {
    if (i == 0 || i == side - 1) {
      for (j = 0; j < side - 1; j++) {
        printf("X");
      }
      printf("X\n");
    } else {
      for (k = 0; k < side - 1; k++) {
        if (k == 0)
          printf("X");
        else
          printf(" ");
      }
      printf("X\n");
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L26
L3:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a4(%rbp)
L26:
  mov    -0x1ac(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L3
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1a8(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a8(%rbp),%edx
  mov    -0x1ac(%rbp),%ecx
  lea    -0x1a0(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <subset_sum@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D60
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D21
datatype: string

tool: D32: 
Subset sum 

tool: D3: Enter the number of elements

tool: D60: %d

tool: D17: Enter %d elements


tool: D21: Enter the required sum

assistant: ```c
int main() {
  printf("\nSubset sum \n");
  int arr[100], N, D;
  int i;
  printf("Enter the number of elements\n");
  scanf("%d", &N);
  printf("Enter %d elements\n", N);
  for (i = 0; i < N; i++)
    scanf("%d", &arr[i]);
  printf("Enter the required sum\n");
  scanf("%d", &D);
  subset_sum(arr, N, D);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L15
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D46(%rip),%r12
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L25
L15:
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <subset_sum@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D32
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string
name: unpack_data
arguments: tag: D46
type_infered: string
name: unpack_data
arguments: tag: D65
type_infered: string
name: unpack_data
arguments: tag: D68
type_infered: string

tool: D32: 
Subset sum 

tool: D3: Enter the number of elements

tool: D46: %d

tool: D65: Enter %d elements


tool: D68: Enter the required sum

assistant: ```c
int main() {
  printf("\nSubset sum \n");
  int arr[100], N, D;
  int i;
  printf("Enter the number of elements\n");
  scanf("%d", &N);
  printf("Enter %d elements\n", N);
  for (i = 0; i < N; i++)
    scanf("%d", &arr[i]);
  printf("Enter the required sum\n");
  scanf("%d", &D);
  subset_sum(arr, N, D);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    D43(%rip),%rdi
  mov    %r13,%rbp
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L8
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L13
L8:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  call   <subset_sum@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D24
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D32
type_infered: string
name: unpack_data
arguments: data_tag: D45
type_infered: string

tool: D24: 
Subset sum 

tool: D6: %d

tool: D43: Enter the number of elements

tool: D32: Enter %d elements


tool: D45: Enter the required sum

assistant: ```c
int main() {
  printf("\nSubset sum \n");
  int arr[100], N, D;
  int i;
  printf("Enter the number of elements\n");
  scanf("%d", &N);
  printf("Enter %d elements\n", N);
  for (i = 0; i < N; i++)
    scanf("%d", &arr[i]);
  printf("Enter the required sum\n");
  scanf("%d", &D);
  subset_sum(arr, N, D);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D28(%rip),%rdi
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  call   <puts@plt>
  lea    D14(%rip),%rdi
  mov    %r13,%rbp
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L15
  nopl   0x0(%rax)
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L19
L15:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  call   <subset_sum@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string
name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D28: 
Subset sum 

tool: D22: %d

tool: D14: Enter the number of elements

tool: D43: Enter %d elements


tool: D8: Enter the required sum

assistant: ```c
int main() {
  printf("\nSubset sum \n");
  int arr[100], N, D;
  int i;
  printf("Enter the number of elements\n");
  scanf("%d", &N);
  printf("Enter %d elements\n", N);
  for (i = 0; i < N; i++)
    scanf("%d", &arr[i]);
  printf("Enter the required sum\n");
  scanf("%d", &D);
  subset_sum(arr, N, D);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<assert_fail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rsi
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <kprintf@plt>
L0:
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: %s:%d: %s: Assertion '%s' failed.


assistant: ```c
void assert_fail(char *exp, char *file, unsigned int line, char *func) {
  kprintf("%s:%d: %s: Assertion \'%s\' failed.\n", file, line, func, exp);
  while (1)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<assert_fail>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  lea    D1(%rip),%rdi
  call   <kprintf@plt>
L6:
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: %s:%d: %s: Assertion '%s' failed.


assistant: ```c
void assert_fail(char *exp, char *file, unsigned int line, char *func) {
  kprintf("%s:%d: %s: Assertion \'%s\' failed.\n", file, line, func, exp);
  while (1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<assert_fail>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <kprintf@plt>
L7:
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: %s:%d: %s: Assertion '%s' failed.


assistant: ```c
void assert_fail(char *exp, char *file, unsigned int line, char *func) {
  kprintf("%s:%d: %s: Assertion \'%s\' failed.\n", file, line, func, exp);
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<assert_fail>:
  endbr64
  mov    %rdi,%r8
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <kprintf@plt>
L0:
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %s:%d: %s: Assertion '%s' failed.


assistant: ```c
void assert_fail(char *exp, char *file, unsigned int line, char *func) {
  kprintf("%s:%d: %s: Assertion \'%s\' failed.\n", file, line, func, exp);
  while (1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L2
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L2:
  call   <fork@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L19
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L19:
  lea    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  lea    -0x24(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D5
type: string

tool: D15: Soy el primer hijo (%d, hijo de %d)


tool: D18: Soy el segundo hijo (%d, hijo de %d)


tool: D5: Soy el padre (%d, hijo de %d)


assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid1, pid2;
  int status1, status2;
  if ((pid1 = fork()) == 0)
    printf("Soy el primer hijo (%d, hijo de %d)\n", getpid(), getppid());
  else {
    if ((pid2 = fork()) == 0) {
      printf("Soy el segundo hijo (%d, hijo de %d)\n", getpid(), getppid());
    } else {
      waitpid(pid1, &status1, 0);
      waitpid(pid2, &status2, 0);
      printf("Soy el padre (%d, hijo de %d)\n", getpid(), getppid());
    }
  }
  return 0;
}
```