ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<project_v>:
  endbr64
  lea    (%rsi,%rdi,2),%eax
  mov    %edx,%r10d
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rdi,1),%edx
  cltq
  lea    (%rsi,%rdx,2),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm7
  movsd  0x8(%r8,%rdx,8),%xmm6
  lea    (%rcx,%r10,2),%edx
  lea    (%rdx,%rdx,2),%r10d
  add    %r10d,%edi
  lea    (%rsi,%rdi,2),%edx
  lea    (%r10,%r10,1),%esi
  add    %edx,%edx
  lea    0x6(%rsi),%edi
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm5
  movsd  0x8(%r8,%rdx,8),%xmm4
  movslq %esi,%rdx
  shl    $0x4,%rdx
  lea    0x20(%rdx,%r9,1),%rcx
  movslq %r10d,%rdx
  sub    %rdx,%rax
  shl    $0x5,%rax
  lea    -0x20(%rax),%r8
L8:
  lea    (%r8,%rcx,1),%rdx
  lea    -0x20(%rcx),%rax
L15:
  movsd  (%rax),%xmm8
  movsd  0x8(%rax),%xmm0
  movapd %xmm7,%xmm1
  movapd %xmm6,%xmm9
  movsd  (%rdx),%xmm2
  movsd  0x8(%rdx),%xmm3
  add    $0x10,%rax
  add    $0x10,%rdx
  mulsd  %xmm0,%xmm9
  mulsd  %xmm8,%xmm1
  mulsd  %xmm7,%xmm0
  mulsd  %xmm6,%xmm8
  subsd  %xmm9,%xmm1
  movapd %xmm5,%xmm9
  mulsd  %xmm2,%xmm9
  addsd  %xmm8,%xmm0
  mulsd  %xmm4,%xmm2
  subsd  %xmm9,%xmm1
  movapd %xmm4,%xmm9
  mulsd  %xmm3,%xmm9
  mulsd  %xmm5,%xmm3
  addsd  %xmm9,%xmm1
  subsd  %xmm3,%xmm0
  movsd  %xmm1,-0x10(%rax)
  subsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rcx
  jne    L15
  add    $0x2,%esi
  add    $0x20,%rcx
  cmp    %esi,%edi
  jne    L8
  ret
```

assistant: ```c
void project_v(int a, int i, int b, int j, double r[], double v[]) {
  int c, k;
  double xi, yi, xj, yj;
  xi = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((i) + 2 * (a))))]))[0];
  yi = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((i) + 2 * (a))))]))[1];
  xj = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((j) + 2 * (b))))]))[0];
  yj = (&((r)[2 * ((i) + 2 * ((a) + 3 * ((j) + 2 * (b))))]))[1];
  for (c = 0; c < 3; c++)
    for (k = 0; k < 2; k++) {
      double zi = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[0];
      double ti = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((i) + 2 * (a))))]))[1];
      double zj = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[0];
      double tj = (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[1];
      (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[0] = xi * zj - yi * tj - xj * zi + yj * ti;
      (&((v)[2 * ((k) + 2 * ((c) + 3 * ((j) + 2 * (b))))]))[1] = xi * tj + yi * zj - xj * ti - yj * zi;
    }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_element>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  js     L19
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L25
L19:
  mov    $0xffffffff,%eax
  jmp    L10
L25:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int read_element(int *array, int size, int index) {
  if (index < 0 || size <= index) {
    return -1;
  }
  int x = array[index];
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_element>:
  endbr64
  test   %edx,%edx
  js     L14
  cmp    %esi,%edx
  jge    L14
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
L14:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read_element(int *array, int size, int index) {
  if (index < 0 || size <= index) {
    return -1;
  }
  int x = array[index];
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_element>:
  endbr64
  test   %edx,%edx
  js     L11
  cmp    %esi,%edx
  jge    L11
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read_element(int *array, int size, int index) {
  if (index < 0 || size <= index) {
    return -1;
  }
  int x = array[index];
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_element>:
  endbr64
  test   %edx,%edx
  js     L1
  cmp    %esi,%edx
  jge    L1
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int read_element(int *array, int size, int index) {
  if (index < 0 || size <= index) {
    return -1;
  }
  int x = array[index];
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0xe,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x32,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  or     -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x1c000,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
signed long long f16(signed long long v_foo) {
  signed long long v_parta = v_foo << 14;
  signed long long v_partb = ((unsigned long long)v_foo) >> 50;
  signed long long v_rotl = v_parta | v_partb;
  signed long long v_and = v_rotl & 114688;
  return v_and;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f16>:
  endbr64
  mov    %rdi,%rax
  rol    $0xe,%rax
  and    $0x1c000,%eax
  ret
```

assistant: ```c
signed long long f16(signed long long v_foo) {
  signed long long v_parta = v_foo << 14;
  signed long long v_partb = ((unsigned long long)v_foo) >> 50;
  signed long long v_rotl = v_parta | v_partb;
  signed long long v_and = v_rotl & 114688;
  return v_and;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f16>:
  endbr64
  mov    %rdi,%rax
  rol    $0xe,%rax
  and    $0x1c000,%eax
  ret
```

assistant: ```c
signed long long f16(signed long long v_foo) {
  signed long long v_parta = v_foo << 14;
  signed long long v_partb = ((unsigned long long)v_foo) >> 50;
  signed long long v_rotl = v_parta | v_partb;
  signed long long v_and = v_rotl & 114688;
  return v_and;
}
```
user: What is the c source code of the assembly code below:

```asm
<f16>:
  endbr64
  mov    %rdi,%rax
  rol    $0xe,%rax
  and    $0x1c000,%eax
  ret
```

assistant: ```c
signed long long f16(signed long long v_foo) {
  signed long long v_parta = v_foo << 14;
  signed long long v_partb = ((unsigned long long)v_foo) >> 50;
  signed long long v_rotl = v_parta | v_partb;
  signed long long v_and = v_rotl & 114688;
  return v_and;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<conf_get_configname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  jmp    L13
L16:
  lea    D12(%rip),%rax
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string

tool: D17: BOZ_KCONFIG_CONFIG

tool: D12: .config

assistant: ```c
const char *conf_get_configname(void) {
  char *name = getenv("BOZ_KCONFIG_CONFIG");
  return name ? name : ".config";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<conf_get_configname>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  lea    D8(%rip),%rdx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string

tool: D14: BOZ_KCONFIG_CONFIG

tool: D8: .config

assistant: ```c
const char *conf_get_configname(void) {
  char *name = getenv("BOZ_KCONFIG_CONFIG");
  return name ? name : ".config";
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<conf_get_configname>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <getenv@plt>
  lea    D1(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D14: BOZ_KCONFIG_CONFIG

tool: D1: .config

assistant: ```c
const char *conf_get_configname(void) {
  char *name = getenv("BOZ_KCONFIG_CONFIG");
  return name ? name : ".config";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<conf_get_configname>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <getenv@plt>
  lea    D15(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D16: BOZ_KCONFIG_CONFIG

tool: D15: .config

assistant: ```c
const char *conf_get_configname(void) {
  char *name = getenv("BOZ_KCONFIG_CONFIG");
  return name ? name : ".config";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xstrtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L31
L3:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
L31:
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L79
L21:
  mov    $0x0,%eax
  jmp    L74
L51:
  addq   $0x1,-0x18(%rbp)
L79:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L51
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L20
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L35
L20:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L46
L2:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L46:
  mov    -0x18(%rbp),%rax
L74:
  leave
  ret
```

assistant: ```c
char *xstrtok(char *buf, char *delim, char **tokp) {
  char *end;
  int len;
  if (buf)
    *tokp = buf;
  else
    buf = *tokp;
  if (!buf || !*buf)
    return NULL;
  while (isspace(*buf))
    ++buf;
  if (*buf == '"') {
    ++buf;
    end = strchr(buf, '"');
    if (!end)
      end = buf + strlen(buf);
  } else {
    len = strcspn(buf, delim);
    end = buf + len;
  }
  if (!*end)
    *tokp = NULL;
  else {
    *end = '\0';
    *tokp = end + 1;
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xstrtok>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L66
  mov    %rdi,%rbx
  mov    %rdi,0x0(%rbp)
L104:
  cmpb   $0x0,(%rbx)
  jne    L98
  mov    $0x0,%r12d
  jmp    L59
L66:
  mov    (%rdx),%rbx
  mov    %rbx,%r12
  test   %rbx,%rbx
  jne    L104
  jmp    L59
L42:
  add    $0x1,%rbx
L98:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
  cmpb   $0x22,(%rbx)
  je     L9
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
  mov    %rbx,%r12
L78:
  cmpb   $0x0,(%rax)
  jne    L71
  movq   $0x0,0x0(%rbp)
L59:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    0x1(%rbx),%r12
  mov    $0x22,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L78
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jmp    L78
L71:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rax,0x0(%rbp)
  jmp    L59
```

assistant: ```c
char *xstrtok(char *buf, char *delim, char **tokp) {
  char *end;
  int len;
  if (buf)
    *tokp = buf;
  else
    buf = *tokp;
  if (!buf || !*buf)
    return NULL;
  while (isspace(*buf))
    ++buf;
  if (*buf == '"') {
    ++buf;
    end = strchr(buf, '"');
    if (!end)
      end = buf + strlen(buf);
  } else {
    len = strcspn(buf, delim);
    end = buf + len;
  }
  if (!*end)
    *tokp = NULL;
  else {
    *end = '\0';
    *tokp = end + 1;
  }
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xstrtok>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L16
  mov    %rdi,0x0(%rbp)
  mov    %rdi,%rbx
L85:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L41
  jmp    L84
  nopl   0x0(%rax)
L56:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L41:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  cmpb   $0x22,(%rbx)
  je     L4
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r12
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
L24:
  cmpb   $0x0,(%rax)
  je     L15
  movb   $0x0,(%rax)
  add    $0x1,%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rax
  pop    %rbx
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L85
L84:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    0x1(%rbx),%r12
  mov    $0x22,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L24
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jmp    L24
```

assistant: ```c
char *xstrtok(char *buf, char *delim, char **tokp) {
  char *end;
  int len;
  if (buf)
    *tokp = buf;
  else
    buf = *tokp;
  if (!buf || !*buf)
    return NULL;
  while (isspace(*buf))
    ++buf;
  if (*buf == '"') {
    ++buf;
    end = strchr(buf, '"');
    if (!end)
      end = buf + strlen(buf);
  } else {
    len = strcspn(buf, delim);
    end = buf + len;
  }
  if (!*end)
    *tokp = NULL;
  else {
    *end = '\0';
    *tokp = end + 1;
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xstrtok>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L10
  mov    %rdi,0x0(%rbp)
  mov    %rdi,%rbx
L87:
  cmpb   $0x0,(%rbx)
  jne    L33
  jmp    L88
  nopl   0x0(%rax)
L40:
  add    $0x1,%rbx
L33:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L40
  cmpb   $0x22,(%rbx)
  je     L17
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r12
  call   <strcspn@plt>
  cltq
  add    %rbx,%rax
L15:
  cmpb   $0x0,(%rax)
  je     L63
  movb   $0x0,(%rax)
  add    $0x1,%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  mov    %r12,%rax
  pop    %rbx
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    (%rdx),%rbx
  test   %rbx,%rbx
  jne    L87
L88:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  lea    0x1(%rbx),%r12
  mov    $0x22,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  jmp    L15
```

assistant: ```c
char *xstrtok(char *buf, char *delim, char **tokp) {
  char *end;
  int len;
  if (buf)
    *tokp = buf;
  else
    buf = *tokp;
  if (!buf || !*buf)
    return NULL;
  while (isspace(*buf))
    ++buf;
  if (*buf == '"') {
    ++buf;
    end = strchr(buf, '"');
    if (!end)
      end = buf + strlen(buf);
  } else {
    len = strcspn(buf, delim);
    end = buf + len;
  }
  if (!*end)
    *tokp = NULL;
  else {
    *end = '\0';
    *tokp = end + 1;
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getheaders>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %rdx,-0x138(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x130(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x130(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x110(%rbp)
  jmp    L58
L3:
  mov    -0x124(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <recvline@plt>
  test   %rax,%rax
  jne    L92
  mov    $0xffffffff,%eax
  jmp    L85
L92:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x138(%rbp),%rax
  sub    %rdx,%rax
  lea    -0x5(%rax),%rdx
  lea    -0x110(%rbp),%rcx
  mov    -0x130(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x138(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x130(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L58:
  movzbl -0x110(%rbp),%eax
  cmp    $0xa,%al
  je     L9
  movzbl -0x110(%rbp),%eax
  cmp    $0xd,%al
  jne    L3
  movzbl -0x10f(%rbp),%eax
  cmp    $0xa,%al
  jne    L3
L9:
  mov    -0x130(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x130(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x118(%rbp)
  jmp    L108
L98:
  subq   $0x1,-0x118(%rbp)
L108:
  mov    -0x118(%rbp),%rax
  cmp    -0x130(%rbp),%rax
  jbe    L106
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L98
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L98
L106:
  mov    -0x118(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L85:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L99
  call   <__stack_chk_fail@plt>
L99:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: 



assistant: ```c
int getheaders(int fd, char *buf, size_t len) {
  char line[256], *cp;
  *line = *buf = '\0';
  while (!(*line == '\n' || (line[0] == '\r' && line[1] == '\n'))) {
    if (recvline(line, 256, fd) == NULL)
      return -1;
    ;
    strncat(buf, line, len - strlen(line) - 5);
    buf[len - 1] = '\0';
  }
  cp = buf + strlen(buf);
  while (cp > buf && (*(cp - 1) == '\r' || *(cp - 1) == '\n'))
    cp--;
  strcpy(cp, "\r\n\r\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getheaders>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  movb   $0x0,(%rsp)
  mov    %rsp,%rbx
L3:
  mov    %r13d,%edx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <recvline@plt>
  test   %rax,%rax
  je     L16
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x5(%r12),%rdx
  sub    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  movb   $0x0,-0x1(%rbp,%r12,1)
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L64
  cmp    $0xd,%al
  jne    L3
  cmpb   $0xa,0x1(%rsp)
  jne    L3
L64:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  cmp    %rdi,%rbp
  jb     L13
  jmp    L63
L86:
  sub    $0x1,%rdi
  cmp    %rdi,%rbp
  je     L88
L13:
  movzbl -0x1(%rdi),%eax
  cmp    $0xd,%al
  je     L86
  cmp    $0xa,%al
  je     L86
L63:
  lea    D5(%rip),%rsi
  call   <strcpy@plt>
  mov    $0x0,%eax
L90:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L88:
  mov    %rbp,%rdi
  jmp    L63
L16:
  mov    $0xffffffff,%eax
  jmp    L90
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: 



assistant: ```c
int getheaders(int fd, char *buf, size_t len) {
  char line[256], *cp;
  *line = *buf = '\0';
  while (!(*line == '\n' || (line[0] == '\r' && line[1] == '\n'))) {
    if (recvline(line, 256, fd) == NULL)
      return -1;
    ;
    strncat(buf, line, len - strlen(line) - 5);
    buf[len - 1] = '\0';
  }
  cp = buf + strlen(buf);
  while (cp > buf && (*(cp - 1) == '\r' || *(cp - 1) == '\n'))
    cp--;
  strcpy(cp, "\r\n\r\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<getheaders>:
  endbr64
  push   %r14
  lea    -0x5(%rdx),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  mov    %rsp,%rbx
  movb   $0x0,(%rsp)
  nopl   (%rax)
L2:
  mov    %r13d,%edx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <recvline@plt>
  test   %rax,%rax
  je     L27
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    %rax,%rdx
  call   <strncat@plt>
  movzbl (%rsp),%eax
  movb   $0x0,-0x1(%rbp,%r12,1)
  cmp    $0xa,%al
  je     L45
  cmp    $0xd,%al
  jne    L2
  cmpb   $0xa,0x1(%rsp)
  jne    L2
L45:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  cmp    %rdi,%rbp
  jb     L66
  jmp    L108
  nop
L109:
  sub    $0x1,%rdi
  cmp    %rdi,%rbp
  je     L108
L66:
  movzbl -0x1(%rdi),%eax
  cmp    $0xd,%al
  je     L109
  cmp    $0xa,%al
  je     L109
L108:
  lea    D8(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
L99:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  jmp    L99
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: 



assistant: ```c
int getheaders(int fd, char *buf, size_t len) {
  char line[256], *cp;
  *line = *buf = '\0';
  while (!(*line == '\n' || (line[0] == '\r' && line[1] == '\n'))) {
    if (recvline(line, 256, fd) == NULL)
      return -1;
    ;
    strncat(buf, line, len - strlen(line) - 5);
    buf[len - 1] = '\0';
  }
  cp = buf + strlen(buf);
  while (cp > buf && (*(cp - 1) == '\r' || *(cp - 1) == '\n'))
    cp--;
  strcpy(cp, "\r\n\r\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getheaders>:
  endbr64
  push   %r14
  lea    -0x5(%rdx),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  mov    %rsp,%rbx
  movb   $0x0,(%rsp)
  nopl   (%rax)
L1:
  mov    %r13d,%edx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <recvline@plt>
  test   %rax,%rax
  je     L89
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    %rax,%rdx
  call   <strncat@plt>
  movzbl (%rsp),%eax
  movb   $0x0,-0x1(%rbp,%r12,1)
  cmp    $0xa,%al
  je     L84
  cmp    $0xd,%al
  jne    L1
  cmpb   $0xa,0x1(%rsp)
  jne    L1
L84:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rax,1),%rdi
  cmp    %rdi,%rbp
  jb     L58
  jmp    L104
  nop
L6:
  sub    $0x1,%rdi
  cmp    %rdi,%rbp
  je     L104
L58:
  movzbl -0x1(%rdi),%eax
  cmp    $0xd,%al
  je     L6
  cmp    $0xa,%al
  je     L6
L104:
  lea    D5(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
L44:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L90
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L89:
  mov    $0xffffffff,%eax
  jmp    L44
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: 



assistant: ```c
int getheaders(int fd, char *buf, size_t len) {
  char line[256], *cp;
  *line = *buf = '\0';
  while (!(*line == '\n' || (line[0] == '\r' && line[1] == '\n'))) {
    if (recvline(line, 256, fd) == NULL)
      return -1;
    ;
    strncat(buf, line, len - strlen(line) - 5);
    buf[len - 1] = '\0';
  }
  cp = buf + strlen(buf);
  while (cp > buf && (*(cp - 1) == '\r' || *(cp - 1) == '\n'))
    cp--;
  strcpy(cp, "\r\n\r\n");
  return 0;
}
```