ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%edi
  call   <input@plt>
  jmp    L4
```

assistant: ```c
main() {
  int i = -1;
  int prime[1000] = {2, 2, 2};
  int c1, c2, c3;
  for (i = -1; i < 1 || i > 999; 1)
    input(i);
  for (c1 = 2; c1 <= i; c1++) {
    prime[c1] = 0;
  }
  prime[0] = 1;
  prime[1] = 1;
  for (c2 = 2; c2 <= i / 2 + 1; c2++) {
    if (prime[c2] == 0) {
      c1 = c2;
      for (c3 = 2 * c1; c3 <= i + 1; c3 = c3 + c1) {
        prime[c3] = 1;
      }
    }
  }
  for (c1 = 0; c1 < i + 1; c1++) {
    if (prime[c1] == 0)
      output(c1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%edi
  call   <input@plt>
  jmp    L2
```

assistant: ```c
main() {
  int i = -1;
  int prime[1000] = {2, 2, 2};
  int c1, c2, c3;
  for (i = -1; i < 1 || i > 999; 1)
    input(i);
  for (c1 = 2; c1 <= i; c1++) {
    prime[c1] = 0;
  }
  prime[0] = 1;
  prime[1] = 1;
  for (c2 = 2; c2 <= i / 2 + 1; c2++) {
    if (prime[c2] == 0) {
      c1 = c2;
      for (c3 = 2 * c1; c3 <= i + 1; c3 = c3 + c1) {
        prime[c3] = 1;
      }
    }
  }
  for (c1 = 0; c1 < i + 1; c1++) {
    if (prime[c1] == 0)
      output(c1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Permedia2WriteData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    $0x4008,%esi
  mov    %eax,%edi
  call   <v_writel@plt>
  nop
  leave
  ret
```

assistant: ```c
void Permedia2WriteData(unsigned char data) {
  do {
    ;
    ;
    ;
    v_writel(data, 0x4008);
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Permedia2WriteData>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  mov    $0x4008,%esi
  call   <v_writel@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Permedia2WriteData(unsigned char data) {
  do {
    ;
    ;
    ;
    v_writel(data, 0x4008);
  } while (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Permedia2WriteData>:
  endbr64
  movzbl %dil,%edi
  mov    $0x4008,%esi
  jmp    1050 <v_writel@plt>
```

assistant: ```c
void Permedia2WriteData(unsigned char data) {
  do {
    ;
    ;
    ;
    v_writel(data, 0x4008);
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x90(%rbp)
  movl   $0x2,-0x8c(%rbp)
  movl   $0x3,-0x88(%rbp)
  movl   $0x4,-0x84(%rbp)
  movl   $0x5,-0x80(%rbp)
  movl   $0x6,-0x7c(%rbp)
  movl   $0x7,-0x78(%rbp)
  movl   $0x4,-0x70(%rbp)
  movl   $0x5,-0x6c(%rbp)
  movl   $0x6,-0x68(%rbp)
  movl   $0x7,-0x64(%rbp)
  movl   $0x8,-0x60(%rbp)
  movl   $0x9,-0x5c(%rbp)
  movl   $0xa,-0x58(%rbp)
  movl   $0xb,-0x54(%rbp)
  movl   $0xc,-0x50(%rbp)
  movl   $0xd,-0x4c(%rbp)
  movl   $0xe,-0x48(%rbp)
  movl   $0x6,-0x40(%rbp)
  movl   $0x7,-0x3c(%rbp)
  movl   $0x8,-0x38(%rbp)
  movl   $0x9,-0x34(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0xd,-0x24(%rbp)
  movl   $0xe,-0x20(%rbp)
  movl   $0xf,-0x1c(%rbp)
  movl   $0x10,-0x18(%rbp)
  movl   $0x11,-0x14(%rbp)
  lea    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x7,%ecx
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    $0xb,%ecx
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    $0x7,%ecx
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
datatype: string

tool: D28: Number is %d


assistant: ```c
int main(int argc, char **argv) {
  int A[7] = {1, 2, 3, 4, 5, 6, 7};
  int B[11] = {4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14};
  int C[12] = {6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17};
  printf("Number is %d\n", search(B, 11, A, 7));
  printf("Number is %d\n", search(C, 12, B, 11));
  printf("Number is %d\n", search(C, 12, A, 7));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x6,0x28(%rsp)
  movl   $0x7,0x2c(%rsp)
  movl   $0x8,0x30(%rsp)
  movl   $0x9,0x34(%rsp)
  movl   $0xa,0x38(%rsp)
  movl   $0xb,0x3c(%rsp)
  movl   $0xc,0x40(%rsp)
  movl   $0xd,0x44(%rsp)
  movl   $0xe,0x48(%rsp)
  movl   $0x6,0x50(%rsp)
  movl   $0x7,0x54(%rsp)
  movl   $0x8,0x58(%rsp)
  movl   $0x9,0x5c(%rsp)
  movl   $0xa,0x60(%rsp)
  movl   $0xb,0x64(%rsp)
  movl   $0xc,0x68(%rsp)
  movl   $0xd,0x6c(%rsp)
  movl   $0xe,0x70(%rsp)
  movl   $0xf,0x74(%rsp)
  movl   $0x10,0x78(%rsp)
  movl   $0x11,0x7c(%rsp)
  mov    %rsp,%rbp
  lea    0x20(%rsp),%r13
  mov    $0x7,%ecx
  mov    %rbp,%rdx
  mov    $0xb,%esi
  mov    %r13,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x50(%rsp),%r12
  mov    $0xb,%ecx
  mov    %r13,%rdx
  mov    $0xc,%esi
  mov    %r12,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x7,%ecx
  mov    %rbp,%rdx
  mov    $0xc,%esi
  mov    %r12,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string

tool: D4: Number is %d


assistant: ```c
int main(int argc, char **argv) {
  int A[7] = {1, 2, 3, 4, 5, 6, 7};
  int B[11] = {4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14};
  int C[12] = {6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17};
  printf("Number is %d\n", search(B, 11, A, 7));
  printf("Number is %d\n", search(C, 12, B, 11));
  printf("Number is %d\n", search(C, 12, A, 7));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  movabs $0x700000006,%rsi
  push   %r14
  movabs $0x900000008,%rcx
  movabs $0xb0000000a,%rdx
  push   %r13
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%r13
  lea    0x20(%rsp),%r14
  mov    %rsi,0x28(%rsp)
  mov    %rcx,0x30(%rsp)
  mov    %r14,%rdi
  lea    0x50(%rsp),%r12
  mov    %rdx,0x38(%rsp)
  mov    %rsi,0x50(%rsp)
  mov    $0xb,%esi
  mov    %rcx,0x58(%rsp)
  mov    $0x7,%ecx
  mov    %rdx,0x60(%rsp)
  mov    %r13,%rdx
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xd0000000c,%rax
  mov    %rax,0x40(%rsp)
  mov    %rax,0x68(%rsp)
  movabs $0xf0000000e,%rax
  mov    %rax,0x70(%rsp)
  movabs $0x1100000010,%rax
  movl   $0x7,0x18(%rsp)
  movl   $0xe,0x48(%rsp)
  mov    %rax,0x78(%rsp)
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xb,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  mov    $0xc,%esi
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    $0x7,%ecx
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D3: Number is %d


assistant: ```c
int main(int argc, char **argv) {
  int A[7] = {1, 2, 3, 4, 5, 6, 7};
  int B[11] = {4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14};
  int C[12] = {6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17};
  printf("Number is %d\n", search(B, 11, A, 7));
  printf("Number is %d\n", search(C, 12, B, 11));
  printf("Number is %d\n", search(C, 12, A, 7));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x7,%ecx
  mov    $0xb,%esi
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  sub    $0x98,%rsp
  movdqa D76(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x20(%rsp),%r14
  lea    0x50(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    D59(%rip),%rax
  mov    %r13,%rdx
  mov    %r14,%rdi
  movdqa D86(%rip),%xmm0
  movl   $0x7,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  mov    D42(%rip),%rax
  movaps %xmm0,0x20(%rsp)
  movdqa D2(%rip),%xmm0
  mov    %rax,0x40(%rsp)
  movaps %xmm0,0x30(%rsp)
  movdqa D30(%rip),%xmm0
  movl   $0xe,0x48(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xb,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  mov    $0xc,%esi
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %r12,%rdi
  mov    %r13,%rdx
  mov    $0x7,%ecx
  call   <search@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D76
data_type: byte[16]
name: read_data
arguments: tag: D59
data_type: byte[8]
name: read_data
arguments: tag: D86
data_type: byte[16]
name: read_data
arguments: tag: D42
data_type: byte[8]
name: read_data
arguments: tag: D2
data_type: byte[16]
name: read_data
arguments: tag: D30
data_type: byte[16]
name: read_data
arguments: tag: D19
data_type: byte[16]
name: read_data
arguments: tag: D20
data_type: byte[16]

tool: D11: Number is %d


tool: {"D76": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D59": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D86": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D42": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D2": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D30": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D19": [0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D20": [0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  int A[7] = {1, 2, 3, 4, 5, 6, 7};
  int B[11] = {4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14};
  int C[12] = {6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17};
  printf("Number is %d\n", search(B, 11, A, 7));
  printf("Number is %d\n", search(C, 12, B, 11));
  printf("Number is %d\n", search(C, 12, A, 7));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_avx_supported>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <cpuid@plt>
  mov    -0x10(%rbp),%eax
  shr    $0x1c,%eax
  and    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int is_avx_supported() {
  unsigned int eax, ebx, ecx, edx;
  cpuid(1, &eax, &ebx, &ecx, &edx);
  return (ecx & (1 << 28)) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_avx_supported>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0x1,%edi
  call   <cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x1c,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_avx_supported() {
  unsigned int eax, ebx, ecx, edx;
  cpuid(1, &eax, &ebx, &ecx, &edx);
  return (ecx & (1 << 28)) ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_avx_supported>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x1c,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_avx_supported() {
  unsigned int eax, ebx, ecx, edx;
  cpuid(1, &eax, &ebx, &ecx, &edx);
  return (ecx & (1 << 28)) ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_avx_supported>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  mov    0x10(%rsp),%eax
  shr    $0x1c,%eax
  and    $0x1,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_avx_supported() {
  unsigned int eax, ebx, ecx, edx;
  cpuid(1, &eax, &ebx, &ecx, &edx);
  return (ecx & (1 << 28)) ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myAtoi>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L92
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rdx
  mov    D11(%rip),%rcx
  mov    (%rcx),%ebx
  movslq %ebx,%r10
  imul   $0x66666667,%r10,%r10
  sar    $0x22,%r10
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%r10d
  mov    D16(%rip),%rcx
  mov    (%rcx),%r11d
  movslq %r11d,%r9
  imul   $0x66666667,%r9,%r9
  sar    $0x22,%r9
  mov    %r11d,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%r9d
  mov    $0x0,%esi
  mov    $0x0,%ecx
  mov    $0x1,%r8d
  mov    $0x30,%ebp
  mov    $0xffffffff,%r12d
  jmp    L170
L24:
  cmp    $0x30,%al
  je     L88
L69:
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  ja     L78
  movsbl %al,%eax
  lea    -0x30(%rax),%edi
  cmp    $0x1,%r8d
  je     L144
  cmp    $0xffffffff,%r8d
  jne    L157
  mov    %ecx,%r13d
  neg    %r13d
  cmp    %r10d,%r13d
  jl     L39
  lea    (%rcx,%rcx,4),%r13d
  lea    (%rbx,%r13,2),%r14d
  mov    %ebp,%r13d
  sub    %eax,%r13d
  cmp    %r13d,%r14d
  jl     L157
  mov    %ebx,%r11d
  jmp    L150
L144:
  cmp    %ecx,%r9d
  jl     L150
  imul   $0xfffffff6,%ecx,%eax
  add    %r11d,%eax
  cmp    %edi,%eax
  jle    L150
L157:
  lea    (%rcx,%rcx,4),%eax
  lea    (%rdi,%rax,2),%ecx
L11:
  add    $0x1,%esi
L88:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L78
L170:
  test   %esi,%esi
  jne    L69
  cmp    $0x2d,%al
  je     L59
  jg     L24
  cmp    $0x20,%al
  je     L88
  cmp    $0x2b,%al
  je     L11
L78:
  mov    %r8d,%r11d
  imul   %ecx,%r11d
L150:
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  mov    %r12d,%r8d
  jmp    L11
L39:
  mov    %ebx,%r11d
  jmp    L150
L92:
  mov    $0x0,%ecx
  mov    $0x1,%r8d
  mov    %r8d,%r11d
  imul   %ecx,%r11d
  mov    %r11d,%eax
  ret
```

assistant: ```c
int myAtoi(char *str) {
  int sign = 1, integer = 0;
  int i = 0;
  char *c = str;
  int tmp = 0;
  while (*c != '\0') {
    if (i == 0) {
      switch (*c) {
      case ' ':
      case '0':
        goto NEXT_CHAR;
      case '-':
        sign = -1;
        goto CONTINUE;
      case '+':
        goto CONTINUE;
      }
    }
    if (*c >= '0' && *c <= '9') {
      tmp = *c - '0';
      if (sign == 1) {
        if (integer > INT_MAX / 10 || INT_MAX - integer * 10 <= tmp) {
          return INT_MAX;
        }
      }
      if (sign == -1) {
        if (-integer < INT_MIN / 10 || INT_MIN + integer * 10 >= -tmp) {
          return INT_MIN;
        }
      }
      integer = integer * 10 + (*c - '0');
    } else {
      break;
    }
  CONTINUE:
    i++;
  NEXT_CHAR:
    c++;
  }
  return integer * sign;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myAtoi>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L122
  mov    D11(%rip),%rdx
  push   %r13
  mov    %rdi,%rcx
  xor    %esi,%esi
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  push   %rbx
  movslq (%rdx),%r9
  mov    $0x30,%ebx
  mov    %r9,%r11
  imul   $0x66666667,%r9,%r9
  mov    %r11d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%r9
  sub    %edx,%r9d
  mov    D19(%rip),%rdx
  movslq (%rdx),%r8
  mov    %r8,%r10
  imul   $0x66666667,%r8,%r8
  mov    %r10d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%r8
  sub    %edx,%r8d
  xor    %edx,%edx
  jmp    L121
  nopw   0x0(%rax,%rax,1)
L65:
  cmp    $0x2d,%al
  je     L98
  jg     L110
  cmp    $0x20,%al
  je     L94
  cmp    $0x2b,%al
  jne    L11
L86:
  add    $0x1,%esi
L94:
  movsbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L40
L121:
  test   %esi,%esi
  je     L65
  lea    -0x30(%rax),%ebp
  cmp    $0x9,%bpl
  ja     L11
L57:
  lea    -0x30(%rax),%ebp
  cmp    $0x1,%edi
  je     L117
  cmp    $0xffffffff,%edi
  jne    L178
  mov    %edx,%r12d
  neg    %r12d
  cmp    %r9d,%r12d
  jl     L189
  lea    (%rdx,%rdx,4),%edx
  mov    %ebx,%r12d
  add    %edx,%edx
  sub    %eax,%r12d
  lea    (%r11,%rdx,1),%r13d
  cmp    %r12d,%r13d
  jge    L189
  add    %ebp,%edx
  jmp    L86
  nopw   0x0(%rax,%rax,1)
L110:
  cmp    $0x30,%al
  je     L94
  lea    -0x30(%rax),%ebp
  cmp    $0x9,%bpl
  jbe    L57
L11:
  imul   %edi,%edx
  mov    %edx,%r10d
L160:
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L117:
  cmp    %edx,%r8d
  jl     L160
  imul   $0xfffffff6,%edx,%eax
  add    %r10d,%eax
  cmp    %ebp,%eax
  jle    L160
L178:
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  add    %ebp,%edx
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L98:
  mov    $0xffffffff,%edi
  jmp    L86
  nopw   0x0(%rax,%rax,1)
L40:
  imul   %edx,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    %edi,%r10d
  mov    %r10d,%eax
  ret
L189:
  mov    %r11d,%r10d
  pop    %rbx
  pop    %rbp
  mov    %r10d,%eax
  pop    %r12
  pop    %r13
  ret
L122:
  xor    %eax,%eax
  ret
```

assistant: ```c
int myAtoi(char *str) {
  int sign = 1, integer = 0;
  int i = 0;
  char *c = str;
  int tmp = 0;
  while (*c != '\0') {
    if (i == 0) {
      switch (*c) {
      case ' ':
      case '0':
        goto NEXT_CHAR;
      case '-':
        sign = -1;
        goto CONTINUE;
      case '+':
        goto CONTINUE;
      }
    }
    if (*c >= '0' && *c <= '9') {
      tmp = *c - '0';
      if (sign == 1) {
        if (integer > INT_MAX / 10 || INT_MAX - integer * 10 <= tmp) {
          return INT_MAX;
        }
      }
      if (sign == -1) {
        if (-integer < INT_MIN / 10 || INT_MIN + integer * 10 >= -tmp) {
          return INT_MIN;
        }
      }
      integer = integer * 10 + (*c - '0');
    } else {
      break;
    }
  CONTINUE:
    i++;
  NEXT_CHAR:
    c++;
  }
  return integer * sign;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myAtoi>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L73
  mov    D4(%rip),%rdx
  push   %r13
  mov    %rdi,%rcx
  xor    %esi,%esi
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  push   %rbx
  movslq (%rdx),%r9
  mov    $0x30,%ebx
  mov    %r9,%r11
  imul   $0x66666667,%r9,%r9
  mov    %r11d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%r9
  sub    %edx,%r9d
  mov    D12(%rip),%rdx
  movslq (%rdx),%r8
  mov    %r8,%r10
  imul   $0x66666667,%r8,%r8
  mov    %r10d,%edx
  sar    $0x1f,%edx
  sar    $0x22,%r8
  sub    %edx,%r8d
  xor    %edx,%edx
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x2d,%al
  je     L8
  jg     L183
  cmp    $0x20,%al
  je     L20
  cmp    $0x2b,%al
  jne    L189
L191:
  add    $0x1,%esi
L20:
  movsbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L70
L88:
  test   %esi,%esi
  je     L16
  lea    -0x30(%rax),%ebp
  cmp    $0x9,%bpl
  ja     L189
L195:
  lea    -0x30(%rax),%ebp
  cmp    $0x1,%edi
  je     L117
  cmp    $0xffffffff,%edi
  jne    L153
  mov    %edx,%r12d
  neg    %r12d
  cmp    %r9d,%r12d
  jl     L180
  lea    (%rdx,%rdx,4),%edx
  mov    %ebx,%r12d
  add    %edx,%edx
  sub    %eax,%r12d
  lea    (%r11,%rdx,1),%r13d
  cmp    %r12d,%r13d
  jge    L180
  add    %ebp,%edx
  jmp    L191
  nopw   0x0(%rax,%rax,1)
L183:
  cmp    $0x30,%al
  je     L20
  lea    -0x30(%rax),%ebp
  cmp    $0x9,%bpl
  jbe    L195
L189:
  imul   %edi,%edx
  mov    %edx,%r10d
L77:
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L117:
  cmp    %edx,%r8d
  jl     L77
  imul   $0xfffffff6,%edx,%eax
  add    %r10d,%eax
  cmp    %ebp,%eax
  jle    L77
L153:
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  add    %ebp,%edx
  jmp    L191
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%edi
  jmp    L191
  nopw   0x0(%rax,%rax,1)
L70:
  imul   %edx,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    %edi,%r10d
  mov    %r10d,%eax
  ret
L180:
  mov    %r11d,%r10d
  pop    %rbx
  pop    %rbp
  mov    %r10d,%eax
  pop    %r12
  pop    %r13
  ret
L73:
  xor    %eax,%eax
  ret
```

assistant: ```c
int myAtoi(char *str) {
  int sign = 1, integer = 0;
  int i = 0;
  char *c = str;
  int tmp = 0;
  while (*c != '\0') {
    if (i == 0) {
      switch (*c) {
      case ' ':
      case '0':
        goto NEXT_CHAR;
      case '-':
        sign = -1;
        goto CONTINUE;
      case '+':
        goto CONTINUE;
      }
    }
    if (*c >= '0' && *c <= '9') {
      tmp = *c - '0';
      if (sign == 1) {
        if (integer > INT_MAX / 10 || INT_MAX - integer * 10 <= tmp) {
          return INT_MAX;
        }
      }
      if (sign == -1) {
        if (-integer < INT_MIN / 10 || INT_MIN + integer * 10 >= -tmp) {
          return INT_MIN;
        }
      }
      integer = integer * 10 + (*c - '0');
    } else {
      break;
    }
  CONTINUE:
    i++;
  NEXT_CHAR:
    c++;
  }
  return integer * sign;
}
```