ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L24:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L24
  cmp    $0x5,%edi
  je     L39
L37:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  jne    L15
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L39:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L37
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: %4d

assistant: ```c
int main() {
  int t, a, n, min = 100, max = 1000, sum;
  for (n = min; n < max; n++) {
    t = n;
    sum = 0;
    while (t != 0) {
      a = t % 10;
      t = t / 10;
      sum = sum + a;
    }
    t = n;
    if (sum == 5)
      printf("%4d", t);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L34:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L34
  cmp    $0x5,%edi
  je     L32
L24:
  add    $0x1,%ebp
  cmp    $0x3e8,%ebp
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L32:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: %4d

assistant: ```c
int main() {
  int t, a, n, min = 100, max = 1000, sum;
  for (n = min; n < max; n++) {
    t = n;
    sum = 0;
    while (t != 0) {
      a = t % 10;
      t = t / 10;
      sum = sum + a;
    }
    t = n;
    if (sum == 5)
      printf("%4d", t);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L39:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  jmp    L12
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strcat(char *str, char *src) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\0')
    i++;
  while (src[j] != '\0') {
    str[i + j] = src[j];
    j++;
  }
  str[i + j] = '\0';
  return (str);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L45
  mov    $0x1,%edx
L27:
  mov    %edx,%edi
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L27
L54:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L52
  mov    $0x1,%edx
  movslq %edi,%r8
  add    %rax,%r8
L2:
  mov    %cl,-0x1(%r8,%rdx,1)
  mov    %edx,%r9d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L2
L40:
  add    %r9d,%edi
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  ret
L45:
  mov    $0x0,%edi
  jmp    L54
L52:
  mov    $0x0,%r9d
  jmp    L40
```

assistant: ```c
char *ft_strcat(char *str, char *src) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\0')
    i++;
  while (src[j] != '\0') {
    str[i + j] = src[j];
    j++;
  }
  str[i + j] = '\0';
  return (str);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L7
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L23:
  lea    (%rcx,%rdx,1),%r10d
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L23
L8:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L13
  movslq %r10d,%r9
  mov    $0x1,%edx
  add    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %cl,-0x1(%r9,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L41
  add    %r10d,%r8d
  movslq %r8d,%r8
  add    %rax,%r8
L13:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rdi,%r8
  xor    %r10d,%r10d
  jmp    L8
```

assistant: ```c
char *ft_strcat(char *str, char *src) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\0')
    i++;
  while (src[j] != '\0') {
    str[i + j] = src[j];
    j++;
  }
  str[i + j] = '\0';
  return (str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L40
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L17:
  lea    (%rcx,%rdx,1),%r10d
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L17
L7:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L22
  movslq %r10d,%r9
  mov    $0x1,%edx
  add    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %cl,-0x1(%r9,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L45
  add    %r10d,%r8d
  movslq %r8d,%r8
  add    %rax,%r8
L22:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rdi,%r8
  xor    %r10d,%r10d
  jmp    L7
```

assistant: ```c
char *ft_strcat(char *str, char *src) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\0')
    i++;
  while (src[j] != '\0') {
    str[i + j] = src[j];
    j++;
  }
  str[i + j] = '\0';
  return (str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_last_char_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x50(%rbp)
  movl   $0x9,-0x4c(%rbp)
  movl   $0xa,-0x48(%rbp)
  movl   $0x5,-0x44(%rbp)
  movl   $0x8,-0x40(%rbp)
  movl   $0x4,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  movl   $0x6,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x0,-0x90(%rbp)
  movl   $0x0,-0x8c(%rbp)
  jmp    L16
L8:
  mov    -0x8c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x84(%rbp)
  mov    -0x8c(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  imul   -0x84(%rbp),%eax
  add    %eax,-0x90(%rbp)
  addl   $0x1,-0x8c(%rbp)
L16:
  mov    -0xac(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8c(%rbp)
  jl     L8
  mov    -0x90(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x88(%rbp)
  movl   $0x31,-0x80(%rbp)
  movl   $0x30,-0x7c(%rbp)
  movl   $0x58,-0x78(%rbp)
  movl   $0x39,-0x74(%rbp)
  movl   $0x38,-0x70(%rbp)
  movl   $0x37,-0x6c(%rbp)
  movl   $0x36,-0x68(%rbp)
  movl   $0x35,-0x64(%rbp)
  movl   $0x34,-0x60(%rbp)
  movl   $0x33,-0x5c(%rbp)
  movl   $0x32,-0x58(%rbp)
  mov    -0x88(%rbp),%eax
  cltq
  mov    -0x80(%rbp,%rax,4),%eax
  mov    %al,-0x91(%rbp)
  mov    -0xac(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x91(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L13
L7:
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int is_last_char_valid(char id[], int len) {
  int weights[17] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
  int sum = 0;
  for (int i = 0; i < len - 1; i++) {
    int num = id[i] - '0';
    sum += num * weights[i];
  }
  int z = sum % 11;
  int z_check[11] = {'1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
  char last = z_check[z];
  if (last == id[len - 1]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_last_char_valid>:
  endbr64
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x7,0x30(%rsp)
  movl   $0x9,0x34(%rsp)
  movl   $0xa,0x38(%rsp)
  movl   $0x5,0x3c(%rsp)
  movl   $0x8,0x40(%rsp)
  movl   $0x4,0x44(%rsp)
  movl   $0x2,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  movl   $0x6,0x50(%rsp)
  movl   $0x3,0x54(%rsp)
  movl   $0x7,0x58(%rsp)
  movl   $0x9,0x5c(%rsp)
  movl   $0xa,0x60(%rsp)
  movl   $0x5,0x64(%rsp)
  movl   $0x8,0x68(%rsp)
  movl   $0x4,0x6c(%rsp)
  movl   $0x2,0x70(%rsp)
  cmp    $0x1,%esi
  jle    L39
  lea    -0x2(%rsi),%r9d
  mov    $0x0,%edx
  mov    $0x0,%ecx
  lea    0x30(%rsp),%r8
L34:
  movsbl (%rdi,%rdx,1),%eax
  sub    $0x30,%eax
  imul   (%r8,%rdx,4),%eax
  add    %eax,%ecx
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %r9,%rax
  jne    L34
L31:
  movl   $0x31,(%rsp)
  movl   $0x30,0x4(%rsp)
  movl   $0x58,0x8(%rsp)
  movl   $0x39,0xc(%rsp)
  movl   $0x38,0x10(%rsp)
  movl   $0x37,0x14(%rsp)
  movl   $0x36,0x18(%rsp)
  movl   $0x35,0x1c(%rsp)
  movl   $0x34,0x20(%rsp)
  movl   $0x33,0x24(%rsp)
  movl   $0x32,0x28(%rsp)
  movslq %esi,%rsi
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%eax
  sub    %eax,%ecx
  movslq %ecx,%rcx
  movzbl (%rsp,%rcx,4),%eax
  cmp    %al,-0x1(%rdi,%rsi,1)
  sete   %al
  movzbl %al,%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x88,%rsp
  ret
L39:
  mov    $0x0,%ecx
  jmp    L31
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_last_char_valid(char id[], int len) {
  int weights[17] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
  int sum = 0;
  for (int i = 0; i < len - 1; i++) {
    int num = id[i] - '0';
    sum += num * weights[i];
  }
  int z = sum % 11;
  int z_check[11] = {'1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
  char last = z_check[z];
  if (last == id[len - 1]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_last_char_valid>:
  endbr64
  sub    $0x88,%rsp
  movslq %esi,%r9
  movabs $0x600000001,%rsi
  movabs $0xa00000009,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x4c(%rsp)
  movabs $0x800000005,%rdx
  movabs $0x200000004,%rax
  movabs $0x700000003,%rsi
  mov    %rcx,0x34(%rsp)
  mov    %rdx,0x3c(%rsp)
  mov    %rax,0x44(%rsp)
  mov    %rsi,0x54(%rsp)
  mov    %rcx,0x5c(%rsp)
  mov    %rdx,0x64(%rsp)
  mov    %rax,0x6c(%rsp)
  cmp    $0x1,%r9d
  jle    L39
  lea    -0x2(%r9),%r8d
  xor    %edx,%edx
  mov    $0x7,%esi
  xor    %ecx,%ecx
  jmp    L10
  nopl   0x0(%rax)
L16:
  mov    0x30(%rsp,%rax,4),%esi
  mov    %rax,%rdx
L10:
  movsbl (%rdi,%rdx,1),%eax
  sub    $0x30,%eax
  imul   %esi,%eax
  add    %eax,%ecx
  lea    0x1(%rdx),%rax
  cmp    %r8,%rdx
  jne    L16
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
L3:
  movabs $0x3000000031,%rcx
  movl   $0x32,0x28(%rsp)
  cltq
  mov    %rcx,(%rsp)
  movabs $0x3900000058,%rcx
  mov    %rcx,0x8(%rsp)
  movabs $0x3700000038,%rcx
  mov    %rcx,0x10(%rsp)
  movabs $0x3500000036,%rcx
  mov    %rcx,0x18(%rsp)
  movabs $0x3300000034,%rcx
  mov    %rcx,0x20(%rsp)
  movzbl (%rsp,%rax,4),%eax
  cmp    %al,-0x1(%rdi,%r9,1)
  sete   %al
  movzbl %al,%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x88,%rsp
  ret
  xchg   %ax,%ax
L39:
  xor    %eax,%eax
  jmp    L3
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_last_char_valid(char id[], int len) {
  int weights[17] = {7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
  int sum = 0;
  for (int i = 0; i < len - 1; i++) {
    int num = id[i] - '0';
    sum += num * weights[i];
  }
  int z = sum % 11;
  int z_check[11] = {'1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
  char last = z_check[z];
  if (last == id[len - 1]) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  jne    L33
  nop
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L6
  jmp    L37
L33:
  nop
L37:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D14: %d

assistant: ```c
int main() {
  int n, x;
  scanf("%d", &n);
  for (x = n; x >= n; x++) {
    if (check_prime(x)) {
      break;
    } else {
      continue;
    }
  }
  printf("%d", x);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
L6:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L8
L0:
  mov    %ebx,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jle    L6
  jmp    L0
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D15: %d

assistant: ```c
int main() {
  int n, x;
  scanf("%d", &n);
  for (x = n; x >= n; x++) {
    if (check_prime(x)) {
      break;
    } else {
      continue;
    }
  }
  printf("%d", x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
L37:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L21
L29:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L21:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L37
  jmp    L29
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int n, x;
  scanf("%d", &n);
  for (x = n; x >= n; x++) {
    if (check_prime(x)) {
      break;
    } else {
      continue;
    }
  }
  printf("%d", x);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
L4:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L10
L2:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L4
  jmp    L2
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int n, x;
  scanf("%d", &n);
  for (x = n; x >= n; x++) {
    if (check_prime(x)) {
      break;
    } else {
      continue;
    }
  }
  printf("%d", x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<float_i2f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L42
L44:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L51
  mov    -0x24(%rbp),%eax
  neg    %eax
  mov    %eax,-0x14(%rbp)
  movl   $0x80000000,-0x18(%rbp)
  jmp    L51
L40:
  shll   -0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L40
  mov    $0x9e,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  shll   $0x17,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  cmp    $0x80,%eax
  ja     L68
  mov    -0x14(%rbp),%eax
  and    $0x1ff,%eax
  cmp    $0x180,%eax
  jne    L33
L68:
  movl   $0x1,-0xc(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  and    $0x7fffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
unsigned float_i2f(int x) {
  unsigned res = 0;
  unsigned tmp;
  unsigned shift = 0;
  unsigned expo = 0;
  unsigned carry = 0;
  unsigned mantissa;
  if (x == 0)
    return 0;
  tmp = x;
  if (x < 0) {
    tmp = -x;
    res = 0x80000000;
  }
  while (!(tmp & 0x80000000)) {
    tmp <<= 1;
    ++shift;
  }
  expo = 158 - shift;
  expo = expo << 23;
  if (((tmp & 0xff) > 0x80) || ((tmp & 0x1ff) == 0x180))
    carry = 1;
  mantissa = (tmp >> 8) & 0x007fffff;
  return res + expo + mantissa + carry;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<float_i2f>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  je     L5
  mov    %edi,%eax
  mov    $0x0,%esi
  js     L0
L32:
  mov    $0x0,%edx
L26:
  add    $0x1,%edx
  add    %eax,%eax
  jns    L26
  mov    $0x9e,%ecx
  sub    %edx,%ecx
  shl    $0x17,%ecx
  mov    %ecx,%edx
  mov    $0x1,%ecx
  cmp    $0x80,%al
  ja     L30
  mov    %eax,%ecx
  and    $0x1ff,%ecx
  cmp    $0x180,%ecx
  sete   %cl
  movzbl %cl,%ecx
L30:
  shr    $0x8,%eax
  and    $0x7fffff,%eax
  add    %edx,%eax
  add    %esi,%eax
  add    %ecx,%eax
L5:
  ret
L0:
  neg    %eax
  mov    $0x80000000,%esi
  jmp    L32
```

assistant: ```c
unsigned float_i2f(int x) {
  unsigned res = 0;
  unsigned tmp;
  unsigned shift = 0;
  unsigned expo = 0;
  unsigned carry = 0;
  unsigned mantissa;
  if (x == 0)
    return 0;
  tmp = x;
  if (x < 0) {
    tmp = -x;
    res = 0x80000000;
  }
  while (!(tmp & 0x80000000)) {
    tmp <<= 1;
    ++shift;
  }
  expo = 158 - shift;
  expo = expo << 23;
  if (((tmp & 0xff) > 0x80) || ((tmp & 0x1ff) == 0x180))
    carry = 1;
  mantissa = (tmp >> 8) & 0x007fffff;
  return res + expo + mantissa + carry;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<float_i2f>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L39
  js     L31
  xor    %esi,%esi
L15:
  xor    %eax,%eax
L45:
  add    $0x1,%eax
  add    %edi,%edi
  jns    L45
  mov    $0x9e,%edx
  movzbl %dil,%ecx
  sub    %eax,%edx
  mov    $0x1,%eax
  shl    $0x17,%edx
  cmp    $0x80,%ecx
  ja     L13
  mov    %edi,%eax
  and    $0x1ff,%eax
  cmp    $0x180,%eax
  sete   %al
  movzbl %al,%eax
L13:
  shr    $0x8,%edi
  and    $0x7fffff,%edi
  add    %edi,%edx
  add    %esi,%edx
  add    %edx,%eax
L39:
  ret
  nopl   0x0(%rax)
L31:
  neg    %edi
  mov    $0x80000000,%esi
  jmp    L15
```

assistant: ```c
unsigned float_i2f(int x) {
  unsigned res = 0;
  unsigned tmp;
  unsigned shift = 0;
  unsigned expo = 0;
  unsigned carry = 0;
  unsigned mantissa;
  if (x == 0)
    return 0;
  tmp = x;
  if (x < 0) {
    tmp = -x;
    res = 0x80000000;
  }
  while (!(tmp & 0x80000000)) {
    tmp <<= 1;
    ++shift;
  }
  expo = 158 - shift;
  expo = expo << 23;
  if (((tmp & 0xff) > 0x80) || ((tmp & 0x1ff) == 0x180))
    carry = 1;
  mantissa = (tmp >> 8) & 0x007fffff;
  return res + expo + mantissa + carry;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<float_i2f>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L3
  js     L25
  xor    %esi,%esi
L37:
  xor    %eax,%eax
L46:
  add    $0x1,%eax
  add    %edi,%edi
  jns    L46
  mov    $0x9e,%edx
  movzbl %dil,%ecx
  sub    %eax,%edx
  mov    $0x1,%eax
  shl    $0x17,%edx
  cmp    $0x80,%ecx
  ja     L32
  mov    %edi,%eax
  and    $0x1ff,%eax
  cmp    $0x180,%eax
  sete   %al
  movzbl %al,%eax
L32:
  shr    $0x8,%edi
  and    $0x7fffff,%edi
  add    %edi,%edx
  add    %esi,%edx
  add    %edx,%eax
L3:
  ret
  nopl   0x0(%rax)
L25:
  neg    %edi
  mov    $0x80000000,%esi
  jmp    L37
```

assistant: ```c
unsigned float_i2f(int x) {
  unsigned res = 0;
  unsigned tmp;
  unsigned shift = 0;
  unsigned expo = 0;
  unsigned carry = 0;
  unsigned mantissa;
  if (x == 0)
    return 0;
  tmp = x;
  if (x < 0) {
    tmp = -x;
    res = 0x80000000;
  }
  while (!(tmp & 0x80000000)) {
    tmp <<= 1;
    ++shift;
  }
  expo = 158 - shift;
  expo = expo << 23;
  if (((tmp & 0xff) > 0x80) || ((tmp & 0x1ff) == 0x180))
    carry = 1;
  mantissa = (tmp >> 8) & 0x007fffff;
  return res + expo + mantissa + carry;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<macnumcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <get_num@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <get_num@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  jns    L37
  mov    -0x28(%rbp),%rax
  movb   $0x3e,(%rax)
  jmp    L31
L37:
  cmpq   $0x0,-0x18(%rbp)
  jle    L7
  mov    -0x28(%rbp),%rax
  movb   $0x3c,(%rax)
  jmp    L31
L7:
  mov    -0x28(%rbp),%rax
  movb   $0x3d,(%rax)
L31:
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: numcmp

assistant: ```c
char *macnumcmp(char *arg) {
  long int num;
  num = get_num("numcmp", arg) - get_num("numcmp", arg);
  arg[1] = '\0';
  if (num < 0)
    *arg = '>';
  else if (num > 0)
    *arg = '<';
  else
    *arg = '=';
  return (arg);
}
```