ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<c_sasum>:
  endbr64
  test   %edi,%edi
  jle    L56
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L51
  mov    %edi,%r12d
  mov    %rsi,%rbp
  cmp    $0x1,%edx
  je     L36
  imul   %edx,%r12d
  movslq %edx,%r14
  pxor   %xmm1,%xmm1
  xor    %ebx,%ebx
  shl    $0x2,%r14
  nop
L1:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    %r13d,%ebx
  add    %r14,%rbp
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  cmp    %ebx,%r12d
  jg     L1
L41:
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L36:
  movslq %edi,%r13
  mov    %edi,%eax
  pxor   %xmm1,%xmm1
  imul   $0x2aaaaaab,%r13,%r13
  sar    $0x1f,%eax
  shr    $0x20,%r13
  sub    %eax,%r13d
  lea    0x0(%r13,%r13,2),%eax
  mov    %edi,%r13d
  add    %eax,%eax
  sub    %eax,%r13d
  je     L5
  lea    -0x1(%r13),%eax
  mov    %rsi,%rbx
  lea    0x4(%rsi,%rax,4),%r14
L71:
  movss  (%rbx),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x4,%rbx
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rbx,%r14
  jne    L71
L5:
  cmp    $0x5,%r12d
  jle    L41
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L63:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x6,%r13d
  add    $0x18,%rbp
  call   <fabsf@plt>
  movss  -0x14(%rbp),%xmm0
  mov    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x10(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0xc(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x8(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x4(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  add    %rax,%rbx
  cvtsi2ss %rbx,%xmm0
  addss  %xmm0,%xmm1
  cmp    %r13d,%r12d
  jg     L63
  jmp    L41
  nopl   0x0(%rax)
L51:
  add    $0x10,%rsp
  pxor   %xmm1,%xmm1
  pop    %rbx
  movaps %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L56:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float c_sasum(const int N, const float *X, const int stride) {
  float sum;
  int m;
  int i;
  sum = 0.0f;
  if (N <= 0 || stride <= 0) {
    return sum;
  }
  if (stride == 1) {
    m = N % 6;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        sum += fabsf(X[i]);
      }
    }
    if (N < 6) {
      return sum;
    }
    for (i = m; i < N; i += 6) {
      sum += fabsf(X[i]) + fabsf(X[i + 1]) + fabsf(X[i + 2]) + fabsf(X[i + 3]) + fabsf(X[i + 4]) + fabsf(X[i + 5]);
    }
    return sum;
  }
  for (i = 0; i < N * stride; i += stride) {
    sum += fabsf(X[i]);
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<c_sasum>:
  endbr64
  test   %edi,%edi
  jle    L80
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L82
  mov    %edi,%r12d
  mov    %rsi,%rbp
  cmp    $0x1,%edx
  je     L17
  imul   %edx,%r12d
  movslq %edx,%r14
  pxor   %xmm1,%xmm1
  xor    %ebx,%ebx
  shl    $0x2,%r14
  nop
L23:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    %r13d,%ebx
  add    %r14,%rbp
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  cmp    %ebx,%r12d
  jg     L23
L36:
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L17:
  movslq %edi,%r13
  mov    %edi,%eax
  pxor   %xmm1,%xmm1
  imul   $0x2aaaaaab,%r13,%r13
  sar    $0x1f,%eax
  shr    $0x20,%r13
  sub    %eax,%r13d
  lea    0x0(%r13,%r13,2),%eax
  mov    %edi,%r13d
  add    %eax,%eax
  sub    %eax,%r13d
  je     L33
  lea    -0x1(%r13),%eax
  mov    %rsi,%rbx
  lea    0x4(%rsi,%rax,4),%r14
L4:
  movss  (%rbx),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x4,%rbx
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rbx,%r14
  jne    L4
L33:
  cmp    $0x5,%r12d
  jle    L36
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rbp
  xchg   %ax,%ax
L88:
  movss  0x0(%rbp),%xmm0
  movss  %xmm1,0xc(%rsp)
  add    $0x6,%r13d
  add    $0x18,%rbp
  call   <fabsf@plt>
  movss  -0x14(%rbp),%xmm0
  mov    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x10(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0xc(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x8(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  movss  -0x4(%rbp),%xmm0
  add    %rax,%rbx
  call   <fabsf@plt>
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  add    %rax,%rbx
  cvtsi2ss %rbx,%xmm0
  addss  %xmm0,%xmm1
  cmp    %r13d,%r12d
  jg     L88
  jmp    L36
  nopl   0x0(%rax)
L82:
  add    $0x10,%rsp
  pxor   %xmm1,%xmm1
  pop    %rbx
  movaps %xmm1,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L80:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float c_sasum(const int N, const float *X, const int stride) {
  float sum;
  int m;
  int i;
  sum = 0.0f;
  if (N <= 0 || stride <= 0) {
    return sum;
  }
  if (stride == 1) {
    m = N % 6;
    if (m > 0) {
      for (i = 0; i < m; i++) {
        sum += fabsf(X[i]);
      }
    }
    if (N < 6) {
      return sum;
    }
    for (i = m; i < N; i += 6) {
      sum += fabsf(X[i]) + fabsf(X[i + 1]) + fabsf(X[i + 2]) + fabsf(X[i + 3]) + fabsf(X[i + 4]) + fabsf(X[i + 5]);
    }
    return sum;
  }
  for (i = 0; i < N * stride; i += stride) {
    sum += fabsf(X[i]);
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list l;
  va_start(l, errstr);
  vfprintf(stderr, errstr, l);
  va_end(l);
  exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list l;
  va_start(l, errstr);
  vfprintf(stderr, errstr, l);
  va_end(l);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list l;
  va_start(l, errstr);
  vfprintf(stderr, errstr, l);
  va_end(l);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list l;
  va_start(l, errstr);
  vfprintf(stderr, errstr, l);
  va_end(l);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unlockb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <real_unlockb@plt>
  nop
  leave
  ret
```

assistant: ```c
void unlockb(pthread_mutex_t *ua, pthread_mutex_t *ub) {
  real_unlockb(ua, ub);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unlockb>:
  endbr64
  sub    $0x8,%rsp
  call   <real_unlockb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void unlockb(pthread_mutex_t *ua, pthread_mutex_t *ub) {
  real_unlockb(ua, ub);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unlockb>:
  endbr64
  jmp    1050 <real_unlockb@plt>
```

assistant: ```c
void unlockb(pthread_mutex_t *ua, pthread_mutex_t *ub) {
  real_unlockb(ua, ub);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unlockb>:
  endbr64
  jmp    1050 <real_unlockb@plt>
```

assistant: ```c
void unlockb(pthread_mutex_t *ua, pthread_mutex_t *ub) {
  real_unlockb(ua, ub);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<singleNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  jmp    L49
L41:
  mov    -0x3c(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x3c(%rbp)
L49:
  cmpl   $0x1f,-0x3c(%rbp)
  jle    L41
  movl   $0x0,-0x3c(%rbp)
  jmp    L37
L20:
  movl   $0x0,-0x38(%rbp)
  jmp    L56
L24:
  mov    -0x38(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  movsbl %al,%esi
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  add    %esi,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x38(%rbp)
L56:
  cmpl   $0x1f,-0x38(%rbp)
  jle    L24
  addl   $0x1,-0x3c(%rbp)
L37:
  mov    -0x3c(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L20
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L83
L59:
  mov    -0x3c(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  movsbl %al,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x34(%rbp)
  addl   $0x1,-0x3c(%rbp)
L83:
  cmpl   $0x1f,-0x3c(%rbp)
  jle    L59
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  char x[32];
  int i, j, ret;
  for (i = 0; i < 32; ++i) {
    x[i] = 0;
  }
  for (i = 0; i < numsSize; ++i) {
    for (j = 0; j < 32; ++j) {
      x[j] = (x[j] + ((nums[i] >> j) & 1)) % 3;
    }
  }
  ret = 0;
  for (i = 0; i < 32; ++i) {
    ret |= (x[i] & 1) << i;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<singleNumber>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  lea    0x20(%rsp),%rdx
  mov    %r9,%rax
L41:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L41
  test   %esi,%esi
  jle    L12
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
L33:
  mov    (%r8),%edi
  mov    %r9,%rsi
  mov    $0x0,%ecx
L44:
  mov    %edi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  movsbl (%rsi),%edx
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  mov    %al,(%rsi)
  add    $0x1,%ecx
  add    $0x1,%rsi
  cmp    $0x20,%ecx
  jne    L44
  add    $0x4,%r8
  cmp    %r10,%r8
  jne    L33
L12:
  mov    $0x0,%ecx
  mov    $0x0,%edx
L48:
  movzbl (%rsp,%rcx,1),%eax
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%edx
  add    $0x1,%rcx
  cmp    $0x20,%rcx
  jne    L48
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %edx,%eax
  add    $0x38,%rsp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  char x[32];
  int i, j, ret;
  for (i = 0; i < 32; ++i) {
    x[i] = 0;
  }
  for (i = 0; i < numsSize; ++i) {
    for (j = 0; j < 32; ++j) {
      x[j] = (x[j] + ((nums[i] >> j) & 1)) % 3;
    }
  }
  ret = 0;
  for (i = 0; i < 32; ++i) {
    ret |= (x[i] & 1) << i;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<singleNumber>:
  endbr64
  sub    $0x38,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %esi,%esi
  jle    L30
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r9
  mov    %rsp,%r8
  lea    0x4(%rdi,%rax,4),%r10
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r9),%edi
  mov    %r8,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %edi,%eax
  movsbl (%rsi),%edx
  add    $0x1,%rsi
  sar    %cl,%eax
  add    $0x1,%ecx
  and    $0x1,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%r11d
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%r11d
  shr    $0x20,%rdx
  sub    %r11d,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x20,%ecx
  jne    L15
  add    $0x4,%r9
  cmp    %r9,%r10
  jne    L14
L30:
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl (%r8,%rcx,1),%eax
  and    $0x1,%eax
  shl    %cl,%eax
  add    $0x1,%rcx
  or     %eax,%r9d
  cmp    $0x20,%rcx
  jne    L9
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %r9d,%eax
  add    $0x38,%rsp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  char x[32];
  int i, j, ret;
  for (i = 0; i < 32; ++i) {
    x[i] = 0;
  }
  for (i = 0; i < numsSize; ++i) {
    for (j = 0; j < 32; ++j) {
      x[j] = (x[j] + ((nums[i] >> j) & 1)) % 3;
    }
  }
  ret = 0;
  for (i = 0; i < 32; ++i) {
    ret |= (x[i] & 1) << i;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<singleNumber>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %esi,%esi
  jle    L70
  mov    %rdi,%r10
  mov    %esi,%r11d
  lea    -0x1(%rsi),%r12d
  cmp    $0x2,%esi
  jle    L73
  mov    $0x2,%ebx
  mov    $0x1,%ebp
  mov    %rsp,%r8
L49:
  mov    -0x8(%r10,%rbx,4),%r9d
  mov    -0x4(%r10,%rbx,4),%edi
  mov    %r8,%rsi
  xor    %ecx,%ecx
  nopl   (%rax)
L19:
  mov    %r9d,%eax
  movsbl (%rsi),%edx
  add    $0x1,%rsi
  sar    %cl,%eax
  and    $0x1,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%r13d
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%r13d
  shr    $0x20,%rdx
  sub    %r13d,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  mov    %edi,%edx
  sar    %cl,%edx
  add    $0x1,%ecx
  and    $0x1,%edx
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%r13d
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%r13d
  shr    $0x20,%rdx
  sub    %r13d,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x20,%ecx
  jne    L19
  add    $0x2,%ebp
  movslq %ebx,%r9
  add    $0x2,%rbx
  cmp    %r12d,%ebp
  jl     L49
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%r10,%r9,4),%edi
  mov    %r8,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L78:
  mov    %edi,%eax
  movsbl (%rsi),%edx
  add    $0x1,%rsi
  sar    %cl,%eax
  add    $0x1,%ecx
  and    $0x1,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%ebx
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%ebx
  shr    $0x20,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x20,%ecx
  jne    L78
  add    $0x1,%r9
  cmp    %r9d,%r11d
  jg     L18
L70:
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%r8,%rcx,1),%eax
  and    $0x1,%eax
  shl    %cl,%eax
  add    $0x1,%rcx
  or     %eax,%r9d
  cmp    $0x20,%rcx
  jne    L13
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x38,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  xor    %r9d,%r9d
  mov    %rsp,%r8
  jmp    L18
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  char x[32];
  int i, j, ret;
  for (i = 0; i < 32; ++i) {
    x[i] = 0;
  }
  for (i = 0; i < numsSize; ++i) {
    for (j = 0; j < 32; ++j) {
      x[j] = (x[j] + ((nums[i] >> j) & 1)) % 3;
    }
  }
  ret = 0;
  for (i = 0; i < 32; ++i) {
    ret |= (x[i] & 1) << i;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sorter_quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jbe    L9
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sorter_quick_sort_recursive@plt>
  jmp    L10
L9:
  nop
L10:
  leave
  ret
```

assistant: ```c
void sorter_quick_sort(int64_t *dst, const size_t size) {
  if (size <= 1) {
    return;
  }
  sorter_quick_sort_recursive(dst, 0U, size - 1U);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sorter_quick_sort>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L1
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%rdx
  mov    $0x0,%esi
  call   <sorter_quick_sort_recursive@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void sorter_quick_sort(int64_t *dst, const size_t size) {
  if (size <= 1) {
    return;
  }
  sorter_quick_sort_recursive(dst, 0U, size - 1U);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sorter_quick_sort>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L1
  lea    -0x1(%rsi),%rdx
  xor    %esi,%esi
  jmp    1050 <sorter_quick_sort_recursive@plt>
  nopl   (%rax)
L1:
  ret
```

assistant: ```c
void sorter_quick_sort(int64_t *dst, const size_t size) {
  if (size <= 1) {
    return;
  }
  sorter_quick_sort_recursive(dst, 0U, size - 1U);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sorter_quick_sort>:
  endbr64
  cmp    $0x1,%rsi
  jbe    L7
  lea    -0x1(%rsi),%rdx
  xor    %esi,%esi
  jmp    1050 <sorter_quick_sort_recursive@plt>
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void sorter_quick_sort(int64_t *dst, const size_t size) {
  if (size <= 1) {
    return;
  }
  sorter_quick_sort_recursive(dst, 0U, size - 1U);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<has_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L17
L13:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  setb   %al
  movzbl %al,%eax
L17:
  leave
  ret
```

assistant: ```c
int has_port(const char *s) {
  const char *slash = strchr(s, '/');
  const char *colon = strchr(s, ':');
  if (!colon) {
    return 0;
  }
  return colon < slash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<has_port>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    $0x3a,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  cmp    %rax,%rbp
  seta   %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
int has_port(const char *s) {
  const char *slash = strchr(s, '/');
  const char *colon = strchr(s, ':');
  if (!colon) {
    return 0;
  }
  return colon < slash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<has_port>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  cmp    %rax,%rbx
  seta   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int has_port(const char *s) {
  const char *slash = strchr(s, '/');
  const char *colon = strchr(s, ':');
  if (!colon) {
    return 0;
  }
  return colon < slash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<has_port>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  cmp    %rax,%rbx
  seta   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int has_port(const char *s) {
  const char *slash = strchr(s, '/');
  const char *colon = strchr(s, ':');
  if (!colon) {
    return 0;
  }
  return colon < slash;
}
```