ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x1c(%rbp)
  jmp    L43
L19:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L31
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L31:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <random_string@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L20
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L27
L20:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L27
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L27:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x7d0,-0x1c(%rbp)
L43:
  cmpl   $0xc34f,-0x1c(%rbp)
  jle    L19
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D36
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D21
type_infered: string

tool: D36: strcpy/1-1.cFailed to allocate memory

tool: D5: strcpy/1-1.c Test Failed, string copy failed. Expected string: %s, But got: %s


tool: D13: strcpy/1-1.c Test Failed, return is not as expected. Expected return: %p, But obtained: %p


tool: D21: strcpy/1-1.c Test Passed, string copied successfully

assistant: ```c
int main(void) {
  char *ret_str;
  int i;
  for (i = 0; i < 50000; i += 2000) {
    char *sample_str_1;
    char *sample_str_2 = malloc(i + 1);
    if (sample_str_2 == NULL) {
      printf("strcpy/1-1.c"
             "Failed to allocate memory\n");
      exit(2);
    }
    sample_str_1 = random_string(i);
    ret_str = strcpy(sample_str_2, sample_str_1);
    if (strcmp(sample_str_1, sample_str_2) != 0) {
      printf("strcpy/1-1.c"
             " Test Failed, string copy failed. "
             "Expected string: %s, But got: %s\n",
             sample_str_1, sample_str_2);
      exit(1);
    } else if (ret_str != sample_str_2) {
      printf("strcpy/1-1.c"
             " Test Failed, return is not as expected. "
             "Expected return: %p, But obtained: %p\n",
             sample_str_2, ret_str);
      exit(1);
    }
    free(sample_str_1);
    free(sample_str_2);
  }
  printf("strcpy/1-1.c"
         " Test Passed, string copied successfully\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  lea    D32(%rip),%r15
  jmp    L45
L12:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  mov    %r12d,%edi
  call   <random_string@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strcpy@plt>
  mov    %rax,%r14
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
L56:
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L40:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x7d0,%r12d
  cmp    $0xc350,%r12d
  je     L4
L45:
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
  mov    %r12d,%edi
  call   <random_string@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%r14
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
  cmp    %rbx,%rbx
  je     L40
  jmp    L56
L61:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
L4:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D26
type_infered: string
name: extract_symbolic_data
arguments: label: D7
type_infered: string
name: extract_symbolic_data
arguments: label: D30
type_infered: string

tool: D32: strcpy/1-1.c Test Failed, return is not as expected. Expected return: %p, But obtained: %p


tool: D26: strcpy/1-1.cFailed to allocate memory

tool: D7: strcpy/1-1.c Test Failed, string copy failed. Expected string: %s, But got: %s


tool: D30: strcpy/1-1.c Test Passed, string copied successfully

assistant: ```c
int main(void) {
  char *ret_str;
  int i;
  for (i = 0; i < 50000; i += 2000) {
    char *sample_str_1;
    char *sample_str_2 = malloc(i + 1);
    if (sample_str_2 == NULL) {
      printf("strcpy/1-1.c"
             "Failed to allocate memory\n");
      exit(2);
    }
    sample_str_1 = random_string(i);
    ret_str = strcpy(sample_str_2, sample_str_1);
    if (strcmp(sample_str_1, sample_str_2) != 0) {
      printf("strcpy/1-1.c"
             " Test Failed, string copy failed. "
             "Expected string: %s, But got: %s\n",
             sample_str_1, sample_str_2);
      exit(1);
    } else if (ret_str != sample_str_2) {
      printf("strcpy/1-1.c"
             " Test Failed, return is not as expected. "
             "Expected return: %p, But obtained: %p\n",
             sample_str_2, ret_str);
      exit(1);
    }
    free(sample_str_1);
    free(sample_str_2);
  }
  printf("strcpy/1-1.c"
         " Test Passed, string copied successfully\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L23:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L2
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L2:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D34
datatype: string
name: unpack_data
arguments: label: D31
datatype: string
name: unpack_data
arguments: label: D26
datatype: string

tool: D14: Please enter your number (0 to exit): 

tool: D34: %d

tool: D31: How many bits you want to shift left? 

tool: D26: Result is %d



assistant: ```c
int main() {
  int n, x, m;
  while (1) {
    printf("Please enter your number (0 to exit): ");
    scanf("%d", &n);
    if (n == 0) {
      break;
    }
    printf("How many bits you want to shift left? ");
    scanf("%d", &x);
    m = n << x;
    printf("Result is %d\n\n", m);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rbp
  lea    D35(%rip),%rbx
  lea    D19(%rip),%r13
  lea    D3(%rip),%r12
  jmp    L17
L22:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  shl    %cl,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jne    L22
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D35
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D3
data_type: string

tool: D31: Please enter your number (0 to exit): 

tool: D35: %d

tool: D19: How many bits you want to shift left? 

tool: D3: Result is %d



assistant: ```c
int main() {
  int n, x, m;
  while (1) {
    printf("Please enter your number (0 to exit): ");
    scanf("%d", &n);
    if (n == 0) {
      break;
    }
    printf("How many bits you want to shift left? ");
    scanf("%d", &x);
    m = n << x;
    printf("Result is %d\n\n", m);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r14
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  shl    %cl,%esi
  call   <printf@plt>
L14:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D13
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D0: How many bits you want to shift left? 

tool: D19: Result is %d



tool: D13: Please enter your number (0 to exit): 

tool: D1: %d

assistant: ```c
int main() {
  int n, x, m;
  while (1) {
    printf("Please enter your number (0 to exit): ");
    scanf("%d", &n);
    if (n == 0) {
      break;
    }
    printf("How many bits you want to shift left? ");
    scanf("%d", &x);
    m = n << x;
    printf("Result is %d\n\n", m);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r14
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  shl    %cl,%esi
  call   <printf@plt>
L3:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L29
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D37
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string

tool: D17: How many bits you want to shift left? 

tool: D37: Result is %d



tool: D36: Please enter your number (0 to exit): 

tool: D22: %d

assistant: ```c
int main() {
  int n, x, m;
  while (1) {
    printf("Please enter your number (0 to exit): ");
    scanf("%d", &n);
    if (n == 0) {
      break;
    }
    printf("How many bits you want to shift left? ");
    scanf("%d", &x);
    m = n << x;
    printf("Result is %d\n\n", m);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<carg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  mov    %rax,%rdx
  movq   %xmm0,%rax
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm2
  movsd  %xmm2,-0x28(%rbp)
  fldl   -0x28(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  fldl   -0x28(%rbp)
  fpatan
  fstpl  -0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
extern __attribute__((__gnu___)) double __attribute__((__const__)) carg(double _Complex _Z) {
  double res;
  __asm__("fpatan;" : "=t"(res) : "0"(__real__ _Z), "u"(__imag__ _Z) : "st(1)");
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<carg>:
  endbr64
  movsd  %xmm1,-0x10(%rsp)
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x10(%rsp)
  fldl   -0x8(%rsp)
  fpatan
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
extern __attribute__((__gnu___)) double __attribute__((__const__)) carg(double _Complex _Z) {
  double res;
  __asm__("fpatan;" : "=t"(res) : "0"(__real__ _Z), "u"(__imag__ _Z) : "st(1)");
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<carg>:
  endbr64
  movsd  %xmm1,-0x10(%rsp)
  movsd  %xmm0,-0x8(%rsp)
  fldl   -0x10(%rsp)
  fldl   -0x8(%rsp)
  fpatan
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
```

assistant: ```c
extern __attribute__((__gnu___)) double __attribute__((__const__)) carg(double _Complex _Z) {
  double res;
  __asm__("fpatan;" : "=t"(res) : "0"(__real__ _Z), "u"(__imag__ _Z) : "st(1)");
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_operator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x2d,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  cmpb   $0x2b,-0x14(%rbp)
  jne    L2
L15:
  mov    $0x1,%eax
  jmp    L24
L2:
  mov    $0x0,%eax
L24:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_operator(char c) {
  int out;
  out = (c == '-');
  out = (out || (c == '+'));
  return (out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_operator>:
  endbr64
  sub    $0x2b,%edi
  test   $0xfd,%dil
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_operator(char c) {
  int out;
  out = (c == '-');
  out = (out || (c == '+'));
  return (out);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_operator>:
  endbr64
  sub    $0x2b,%edi
  xor    %eax,%eax
  and    $0xfd,%edi
  sete   %al
  ret
```

assistant: ```c
int is_operator(char c) {
  int out;
  out = (c == '-');
  out = (out || (c == '+'));
  return (out);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_operator>:
  endbr64
  sub    $0x2b,%edi
  xor    %eax,%eax
  and    $0xfd,%edi
  sete   %al
  ret
```

assistant: ```c
int is_operator(char c) {
  int out;
  out = (c == '-');
  out = (out || (c == '+'));
  return (out);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<buttonLeft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x4,%eax
  cmp    $0x4,%eax
  jne    L34
  mov    D17(%rip),%eax
  test   %eax,%eax
  jne    L2
  movl   $0x1,D17(%rip)
  mov    $0x1,%eax
  jmp    L33
L2:
  mov    $0x0,%eax
  jmp    L33
L34:
  movl   $0x0,D17(%rip)
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
volatile bool buttonLeft(volatile unsigned int *p) {
  static bool b = false;
  if (((*p) & 0x00000004) == 0x00000004) {
    if (b == false) {
      b = true;
      return true;
    } else
      return false;
  }
  b = false;
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<buttonLeft>:
  endbr64
  mov    (%rdi),%eax
  test   $0x4,%al
  je     L17
  mov    $0x0,%eax
  cmpl   $0x0,D15(%rip)
  jne    L12
  movl   $0x1,D15(%rip)
  mov    $0x1,%eax
  ret
L17:
  movl   $0x0,D15(%rip)
  mov    $0x0,%eax
L12:
  ret
```

assistant: ```c
volatile bool buttonLeft(volatile unsigned int *p) {
  static bool b = false;
  if (((*p) & 0x00000004) == 0x00000004) {
    if (b == false) {
      b = true;
      return true;
    } else
      return false;
  }
  b = false;
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<buttonLeft>:
  endbr64
  mov    (%rdi),%eax
  test   $0x4,%al
  je     L2
  mov    D28(%rip),%edx
  xor    %eax,%eax
  test   %edx,%edx
  jne    L16
  movl   $0x1,D28(%rip)
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  movl   $0x0,D28(%rip)
  xor    %eax,%eax
L16:
  ret
```

assistant: ```c
volatile bool buttonLeft(volatile unsigned int *p) {
  static bool b = false;
  if (((*p) & 0x00000004) == 0x00000004) {
    if (b == false) {
      b = true;
      return true;
    } else
      return false;
  }
  b = false;
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<buttonLeft>:
  endbr64
  mov    (%rdi),%eax
  test   $0x4,%al
  je     L1
  mov    D13(%rip),%edx
  xor    %eax,%eax
  test   %edx,%edx
  jne    L12
  movl   $0x1,D13(%rip)
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  movl   $0x0,D13(%rip)
  xor    %eax,%eax
L12:
  ret
```

assistant: ```c
volatile bool buttonLeft(volatile unsigned int *p) {
  static bool b = false;
  if (((*p) & 0x00000004) == 0x00000004) {
    if (b == false) {
      b = true;
      return true;
    } else
      return false;
  }
  b = false;
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strip_html_tags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L121
L37:
  cmpl   $0x0,-0xc(%rbp)
  je     L127
  cmpl   $0x1,-0xc(%rbp)
  je     L119
  jmp    L121
L127:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L96
  movl   $0x1,-0xc(%rbp)
  jmp    L85
L96:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jae    L85
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L85:
  addl   $0x1,-0x8(%rbp)
  jmp    L121
L55:
  addl   $0x1,-0x8(%rbp)
L119:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jae    L64
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L55
L64:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jae    L20
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  nop
L121:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L37
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jae    L67
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L67:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned strip_html_tags(const unsigned char *px, unsigned length, unsigned char *dst, unsigned dst_length) {
  unsigned state = 0;
  unsigned offset = 0;
  unsigned d = 0;
  enum { S_NORMAL, S_LT };
  while (offset < length)
    switch (state) {
    case S_NORMAL:
      if (px[offset] == '<')
        state = S_LT;
      else {
        if (d < dst_length)
          dst[d++] = px[offset];
      }
      offset++;
      break;
    case S_LT:
      while (offset < length && px[offset] != '>')
        offset++;
      if (offset < length) {
        state = S_NORMAL;
        offset++;
      }
      break;
    }
  if (d < dst_length)
    dst[d] = '\0';
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strip_html_tags>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %rdx,%r10
  mov    $0x0,%r9d
  mov    $0x0,%eax
  mov    $0x0,%edi
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L15
L56:
  mov    %eax,%edx
  movzbl (%r8,%rdx,1),%edx
  cmp    $0x3c,%dl
  je     L37
  cmp    %ecx,%r9d
  jae    L16
  mov    %r9d,%r11d
  mov    %dl,(%r10,%r11,1)
  lea    0x1(%r9),%r9d
  jmp    L16
L37:
  mov    %ebp,%edi
L16:
  add    $0x1,%eax
L15:
  cmp    %esi,%eax
  jae    L69
  mov    %eax,%edx
  add    %r8,%rdx
  test   %edi,%edi
  je     L56
L94:
  cmpb   $0x3e,(%rdx)
  je     L6
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%esi
  jne    L94
  mov    %esi,%eax
  jmp    L15
L6:
  cmp    %esi,%eax
  jae    L15
  add    $0x1,%eax
  mov    %ebx,%edi
  jmp    L15
L69:
  cmp    %ecx,%r9d
  jae    L89
  mov    %r9d,%eax
  movb   $0x0,(%r10,%rax,1)
L89:
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned strip_html_tags(const unsigned char *px, unsigned length, unsigned char *dst, unsigned dst_length) {
  unsigned state = 0;
  unsigned offset = 0;
  unsigned d = 0;
  enum { S_NORMAL, S_LT };
  while (offset < length)
    switch (state) {
    case S_NORMAL:
      if (px[offset] == '<')
        state = S_LT;
      else {
        if (d < dst_length)
          dst[d++] = px[offset];
      }
      offset++;
      break;
    case S_LT:
      while (offset < length && px[offset] != '>')
        offset++;
      if (offset < length) {
        state = S_NORMAL;
        offset++;
      }
      break;
    }
  if (d < dst_length)
    dst[d] = '\0';
  return d;
}
```