ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <setjmp@plt>
  endbr64
  cmp    $0x2,%eax
  je     L40
  jg     L63
  test   %eax,%eax
  je     L4
  cmp    $0x1,%eax
  jne    L65
  lea    D41(%rip),%rdi
  call   <printf@plt>
L40:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <longjmp@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
L65:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  cmp    $0x3,%eax
  jne    L65
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L4:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  mov    $0x2,%esi
  call   <longjmp@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L65
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D41
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D12
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string

tool: D41: Got Foo!


tool: D4: Got Bar!


tool: D12: I do not appear 2


tool: D19: Got Baz!


tool: D0: In Try Statement


tool: D34: I do not appear


assistant: ```c
int main(int argc, char **argv) {
  jmp_buf ex_buf__;
  switch (setjmp(ex_buf__)) {
  case 0: {
    printf("In Try Statement\n");
    longjmp(ex_buf__, 2);
    printf("I do not appear\n");
  } break;
  case 1: {
    printf("Got Foo!\n");
  }
  case 2: {
    printf("Got Bar!\n");
    longjmp(ex_buf__, 1);
    printf("I do not appear 2\n");
  } break;
  case 3: {
    printf("Got Baz!\n");
  } break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<NumberIO_StrToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  mov    %eax,%edx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  mov    %eax,%edx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L0:
  cmp    %rdx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L0
L31:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L1
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L1:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x2c(%rbp),%rdx
  mov    -0x3c(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <NumberIO_StrToHexInt@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void NumberIO_StrToHex(char *a_, unsigned int _a_high, unsigned int *x) {
  int i;
  char a[_a_high + 1];
  memcpy(a, a_, _a_high + 1);
  NumberIO_StrToHexInt((char *)a, _a_high, &i);
  (*x) = (unsigned int)(i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<NumberIO_StrToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%edx
  mov    %edx,%eax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rdi
  mov    %rsp,%rsi
  sub    %rdi,%rsi
L25:
  cmp    %rsi,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L31:
  mov    %rax,%rsi
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  je     L7
  orq    $0x0,-0x8(%rsp,%rsi,1)
L7:
  mov    %rcx,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x1c(%rbp),%rdx
  mov    %ebx,%esi
  mov    %rsp,%rdi
  call   <NumberIO_StrToHexInt@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%r12)
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_StrToHex(char *a_, unsigned int _a_high, unsigned int *x) {
  int i;
  char a[_a_high + 1];
  memcpy(a, a_, _a_high + 1);
  NumberIO_StrToHexInt((char *)a, _a_high, &i);
  (*x) = (unsigned int)(i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NumberIO_StrToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L32
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L39
L32:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L20
L26:
  mov    %rdi,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x1c(%rbp),%rdx
  mov    %r12d,%esi
  mov    %rsp,%rdi
  call   <NumberIO_StrToHexInt@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L26
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_StrToHex(char *a_, unsigned int _a_high, unsigned int *x) {
  int i;
  char a[_a_high + 1];
  memcpy(a, a_, _a_high + 1);
  NumberIO_StrToHexInt((char *)a, _a_high, &i);
  (*x) = (unsigned int)(i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NumberIO_StrToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L12
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L42
L12:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L20
L6:
  mov    %rdi,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    -0x1c(%rbp),%rdx
  mov    %r12d,%esi
  mov    %rsp,%rdi
  call   <NumberIO_StrToHexInt@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L6
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void NumberIO_StrToHex(char *a_, unsigned int _a_high, unsigned int *x) {
  int i;
  char a[_a_high + 1];
  memcpy(a, a_, _a_high + 1);
  NumberIO_StrToHexInt((char *)a, _a_high, &i);
  (*x) = (unsigned int)(i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x30(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add(int len, int a[], int b[], int c[]) {
#pragma omp parallel
  {
#pragma omp for simd schedule(static) simdlen(4)
    for (int i = 0; i < len; i++) {
      c[i] = a[i] + b[i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add>:
  endbr64
  test   %edi,%edi
  jle    L4
  mov    %edi,%edi
  mov    $0x0,%eax
L12:
  mov    (%rdx,%rax,4),%r8d
  add    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
L4:
  ret
```

assistant: ```c
void add(int len, int a[], int b[], int c[]) {
#pragma omp parallel
  {
#pragma omp for simd schedule(static) simdlen(4)
    for (int i = 0; i < len; i++) {
      c[i] = a[i] + b[i];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<add>:
  endbr64
  test   %edi,%edi
  jle    L17
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L11:
  mov    (%rdx,%rax,4),%r8d
  add    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L11
L17:
  ret
```

assistant: ```c
void add(int len, int a[], int b[], int c[]) {
#pragma omp parallel
  {
#pragma omp for simd schedule(static) simdlen(4)
    for (int i = 0; i < len; i++) {
      c[i] = a[i] + b[i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add>:
  endbr64
  movslq %edi,%r8
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  test   %r8d,%r8d
  jle    L90
  lea    0x4(%rsi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  seta   %cl
  cmp    $0x1,%r8d
  setne  %al
  test   %al,%cl
  je     L57
  lea    0x4(%rdi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L57
  lea    -0x1(%r8),%eax
  mov    %r8d,%r9d
  cmp    $0x2,%eax
  jbe    L58
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L22:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  paddd  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L22
  mov    %r8d,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%r8d
  je     L90
  mov    %r8d,%r9d
  sub    %ecx,%r9d
  cmp    $0x1,%r9d
  je     L33
L95:
  movq   (%rdi,%rcx,4),%xmm0
  movq   (%rsi,%rcx,4),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rdx,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L90
L33:
  cltq
  mov    (%rsi,%rax,4),%ecx
  add    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  ret
L57:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L40:
  mov    (%rsi,%rax,4),%ecx
  add    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L40
L90:
  ret
L58:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L95
```

assistant: ```c
void add(int len, int a[], int b[], int c[]) {
#pragma omp parallel
  {
#pragma omp for simd schedule(static) simdlen(4)
    for (int i = 0; i < len; i++) {
      c[i] = a[i] + b[i];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string

tool: D15: ################################################


assistant: ```c
int main(int argc, char *argv[]) {
  printf("################################################\n");
  printf("################################################\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: ################################################


assistant: ```c
int main(int argc, char *argv[]) {
  printf("################################################\n");
  printf("################################################\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: ################################################


assistant: ```c
int main(int argc, char *argv[]) {
  printf("################################################\n");
  printf("################################################\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: ################################################


assistant: ```c
int main(int argc, char *argv[]) {
  printf("################################################\n");
  printf("################################################\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L8:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L17:
  cmpl   $0x1d,-0x10(%rbp)
  jle    L8
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D6: %d

tool: D9: %d


assistant: ```c
int main() {
  int i, horas, total = 0;
  for (i = 0; i < 30; i++) {
    scanf("%d", &horas);
    total += horas;
  }
  printf("%d\n", total);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1e,%ebx
  mov    $0x0,%ebp
  lea    D18(%rip),%r12
L10:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L10
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D7
datatype: string

tool: D18: %d

tool: D7: %d


assistant: ```c
int main() {
  int i, horas, total = 0;
  for (i = 0; i < 30; i++) {
    scanf("%d", &horas);
    total += horas;
  }
  printf("%d\n", total);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1e,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L19:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L19
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D7
type: string

tool: D5: %d

tool: D7: %d


assistant: ```c
int main() {
  int i, horas, total = 0;
  for (i = 0; i < 30; i++) {
    scanf("%d", &horas);
    total += horas;
  }
  printf("%d\n", total);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1e,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  sub    $0x1,%ebx
  jne    L5
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string

tool: D0: %d

tool: D16: %d


assistant: ```c
int main() {
  int i, horas, total = 0;
  for (i = 0; i < 30; i++) {
    scanf("%d", &horas);
    total += horas;
  }
  printf("%d\n", total);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L44
L8:
  movq   $0x0,-0x20(%rbp)
  jmp    L2
L36:
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x26(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  lea    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  movzwl -0x26(%rbp),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x2,-0x20(%rbp)
L2:
  cmpq   $0x0,-0x20(%rbp)
  je     L36
  addq   $0x1,-0x18(%rbp)
L44:
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x10(%rbp),%rax
  imul   $0xe3600c9,%rax,%rax
  movabs $0x6e800000001d584d,%rdx
  or     %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 238420169UL | 7962364141192960077UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,%rdx
  mov    %rax,%rcx
  shr    $0x10,%rcx
  mov    %cx,%dx
  movzwl %ax,%eax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rcx
  and    %rcx,%rdx
  or     %rdx,%rax
  shr    $0x20,%rdx
  shl    $0x20,%rax
  or     %rdx,%rax
  imul   $0xe3600c9,%rax,%rax
  movabs $0x6e800000001d584d,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 238420169UL | 7962364141192960077UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x3686696a,%rdx
  xor    $0xffffffffce5d000b,%rdx
  mov    %rdx,%rax
  movzwl %dx,%ecx
  shr    $0x20,%rdx
  shr    $0x10,%rax
  shl    $0x10,%rcx
  movzwl %ax,%eax
  or     %rcx,%rax
  shl    $0x20,%rax
  or     %rdx,%rax
  movabs $0x6e800000001d584d,%rdx
  imul   $0xe3600c9,%rax,%rax
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 238420169UL | 7962364141192960077UL;
  }
}
```