ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<isFullHouse>:
  endbr64
  push   %r15
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x4(%rbx),%r15
  add    $0x14,%rbx
  sub    $0x18,%rsp
  mov    (%rsi),%esi
  call   <getCardFace@plt>
  movl   $0xffffffff,0xc(%rsp)
L6:
  mov    (%r15),%esi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <getCardFace@plt>
  cmp    %r13d,%eax
  je     L32
  mov    $0x1,%ebp
L36:
  add    $0x4,%r15
  cmp    %r15,%rbx
  jne    L6
  mov    0xc(%rsp),%eax
  or     %r14d,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%r14d
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L32:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L40
  cmp    $0x3,%ebp
  mov    $0xffffffff,%edx
  cmovne 0xc(%rsp),%edx
  cmove  %eax,%r14d
  mov    %edx,0xc(%rsp)
  jmp    L36
  nop
L40:
  movl   $0x1,0xc(%rsp)
  jmp    L36
```

assistant: ```c
int isFullHouse(const int wDeck[][13], const int *hand) {
  int i, card, count = 1;
  int prevCard = getCardFace(wDeck, hand[0]);
  int hasThreeOfKind = -1;
  int hasPair = -1;
  for (i = 1; i < 5; i++) {
    card = getCardFace(wDeck, hand[i]);
    if (card == prevCard) {
      if (++count == 2) {
        hasPair = 1;
      }
      if (count == 3) {
        hasThreeOfKind = card;
        hasPair = -1;
      }
    } else
      count = 1;
    prevCard = card;
  }
  if (hasPair >= 0 && hasThreeOfKind >= 0)
    return hasThreeOfKind;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isFullHouse>:
  endbr64
  push   %r15
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x4(%rbx),%r15
  add    $0x14,%rbx
  sub    $0x18,%rsp
  mov    (%rsi),%esi
  call   <getCardFace@plt>
  movl   $0xffffffff,0xc(%rsp)
L11:
  mov    (%r15),%esi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <getCardFace@plt>
  cmp    %r13d,%eax
  je     L9
  mov    $0x1,%ebp
L1:
  add    $0x4,%r15
  cmp    %r15,%rbx
  jne    L11
  mov    0xc(%rsp),%eax
  or     %r14d,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%r14d
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L9:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L35
  cmp    $0x3,%ebp
  mov    $0xffffffff,%edx
  cmovne 0xc(%rsp),%edx
  cmove  %eax,%r14d
  mov    %edx,0xc(%rsp)
  jmp    L1
  nop
L35:
  movl   $0x1,0xc(%rsp)
  jmp    L1
```

assistant: ```c
int isFullHouse(const int wDeck[][13], const int *hand) {
  int i, card, count = 1;
  int prevCard = getCardFace(wDeck, hand[0]);
  int hasThreeOfKind = -1;
  int hasPair = -1;
  for (i = 1; i < 5; i++) {
    card = getCardFace(wDeck, hand[i]);
    if (card == prevCard) {
      if (++count == 2) {
        hasPair = 1;
      }
      if (count == 3) {
        hasThreeOfKind = card;
        hasPair = -1;
      }
    } else
      count = 1;
    prevCard = card;
  }
  if (hasPair >= 0 && hasThreeOfKind >= 0)
    return hasThreeOfKind;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crypto_verify_16>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%eax
  xor    (%rsi),%al
  movzbl 0x1(%rdi),%esi
  xor    0x1(%rcx),%sil
  or     %esi,%eax
  movzbl 0x2(%rdi),%esi
  xor    0x2(%rcx),%sil
  or     %esi,%eax
  movzbl 0x3(%rdi),%esi
  xor    0x3(%rcx),%sil
  or     %esi,%eax
  movzbl 0x4(%rdi),%esi
  xor    0x4(%rcx),%sil
  or     %esi,%eax
  movzbl 0x5(%rdi),%esi
  xor    0x5(%rcx),%sil
  or     %esi,%eax
  movzbl 0x6(%rdi),%esi
  xor    0x6(%rcx),%sil
  or     %esi,%eax
  movzbl 0x7(%rdi),%esi
  xor    0x7(%rcx),%sil
  or     %esi,%eax
  movzbl 0x8(%rdi),%esi
  xor    0x8(%rcx),%sil
  or     %esi,%eax
  movzbl 0x9(%rdi),%esi
  xor    0x9(%rcx),%sil
  or     %esi,%eax
  movzbl 0xa(%rdi),%esi
  xor    0xa(%rcx),%sil
  or     %esi,%eax
  movzbl 0xb(%rdi),%esi
  xor    0xb(%rcx),%sil
  or     %esi,%eax
  movzbl 0xc(%rdi),%esi
  xor    0xc(%rcx),%sil
  or     %esi,%eax
  movzbl 0xd(%rdi),%esi
  xor    0xd(%rcx),%sil
  or     %esi,%eax
  movzbl 0xe(%rdi),%esi
  xor    0xe(%rcx),%sil
  or     %esi,%eax
  movzbl 0xf(%rdi),%edx
  xor    0xf(%rcx),%dl
  or     %edx,%eax
  movzbl %al,%eax
  sub    $0x1,%eax
  shr    $0x1f,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int crypto_verify_16(const unsigned char *x, const unsigned char *y) {
  unsigned int differentbits = 0;
  differentbits |= x[0] ^ y[0];
  differentbits |= x[1] ^ y[1];
  differentbits |= x[2] ^ y[2];
  differentbits |= x[3] ^ y[3];
  differentbits |= x[4] ^ y[4];
  differentbits |= x[5] ^ y[5];
  differentbits |= x[6] ^ y[6];
  differentbits |= x[7] ^ y[7];
  differentbits |= x[8] ^ y[8];
  differentbits |= x[9] ^ y[9];
  differentbits |= x[10] ^ y[10];
  differentbits |= x[11] ^ y[11];
  differentbits |= x[12] ^ y[12];
  differentbits |= x[13] ^ y[13];
  differentbits |= x[14] ^ y[14];
  differentbits |= x[15] ^ y[15];
  return (1 & ((differentbits - 1) >> 8)) - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crypto_verify_16>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%eax
  xor    (%rsi),%al
  movzbl 0x1(%rdi),%esi
  xor    0x1(%rcx),%sil
  or     %esi,%eax
  movzbl 0x2(%rdi),%esi
  xor    0x2(%rcx),%sil
  or     %esi,%eax
  movzbl 0x3(%rdi),%esi
  xor    0x3(%rcx),%sil
  or     %esi,%eax
  movzbl 0x4(%rdi),%esi
  xor    0x4(%rcx),%sil
  or     %esi,%eax
  movzbl 0x5(%rdi),%esi
  xor    0x5(%rcx),%sil
  or     %esi,%eax
  movzbl 0x6(%rdi),%esi
  xor    0x6(%rcx),%sil
  or     %esi,%eax
  movzbl 0x7(%rdi),%esi
  xor    0x7(%rcx),%sil
  or     %esi,%eax
  movzbl 0x8(%rdi),%esi
  xor    0x8(%rcx),%sil
  or     %esi,%eax
  movzbl 0x9(%rdi),%esi
  xor    0x9(%rcx),%sil
  or     %esi,%eax
  movzbl 0xa(%rdi),%esi
  xor    0xa(%rcx),%sil
  or     %esi,%eax
  movzbl 0xb(%rdi),%esi
  xor    0xb(%rcx),%sil
  or     %esi,%eax
  movzbl 0xc(%rdi),%esi
  xor    0xc(%rcx),%sil
  or     %esi,%eax
  movzbl 0xd(%rdi),%esi
  xor    0xd(%rcx),%sil
  or     %esi,%eax
  movzbl 0xe(%rdi),%esi
  xor    0xe(%rcx),%sil
  or     %esi,%eax
  movzbl 0xf(%rdi),%edx
  xor    0xf(%rcx),%dl
  or     %edx,%eax
  movzbl %al,%eax
  sub    $0x1,%eax
  shr    $0x1f,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int crypto_verify_16(const unsigned char *x, const unsigned char *y) {
  unsigned int differentbits = 0;
  differentbits |= x[0] ^ y[0];
  differentbits |= x[1] ^ y[1];
  differentbits |= x[2] ^ y[2];
  differentbits |= x[3] ^ y[3];
  differentbits |= x[4] ^ y[4];
  differentbits |= x[5] ^ y[5];
  differentbits |= x[6] ^ y[6];
  differentbits |= x[7] ^ y[7];
  differentbits |= x[8] ^ y[8];
  differentbits |= x[9] ^ y[9];
  differentbits |= x[10] ^ y[10];
  differentbits |= x[11] ^ y[11];
  differentbits |= x[12] ^ y[12];
  differentbits |= x[13] ^ y[13];
  differentbits |= x[14] ^ y[14];
  differentbits |= x[15] ^ y[15];
  return (1 & ((differentbits - 1) >> 8)) - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crypto_verify_16>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%eax
  xor    (%rsi),%al
  movzbl 0x1(%rdi),%esi
  xor    0x1(%rcx),%sil
  or     %esi,%eax
  movzbl 0x2(%rdi),%esi
  xor    0x2(%rcx),%sil
  or     %esi,%eax
  movzbl 0x3(%rdi),%esi
  xor    0x3(%rcx),%sil
  or     %esi,%eax
  movzbl 0x4(%rdi),%esi
  xor    0x4(%rcx),%sil
  or     %esi,%eax
  movzbl 0x5(%rdi),%esi
  xor    0x5(%rcx),%sil
  or     %esi,%eax
  movzbl 0x6(%rdi),%esi
  xor    0x6(%rcx),%sil
  or     %esi,%eax
  movzbl 0x7(%rdi),%esi
  xor    0x7(%rcx),%sil
  or     %esi,%eax
  movzbl 0x8(%rdi),%esi
  xor    0x8(%rcx),%sil
  or     %esi,%eax
  movzbl 0x9(%rdi),%esi
  xor    0x9(%rcx),%sil
  or     %esi,%eax
  movzbl 0xa(%rdi),%esi
  xor    0xa(%rcx),%sil
  or     %esi,%eax
  movzbl 0xb(%rdi),%esi
  xor    0xb(%rcx),%sil
  or     %esi,%eax
  movzbl 0xc(%rdi),%esi
  xor    0xc(%rcx),%sil
  or     %esi,%eax
  movzbl 0xd(%rdi),%esi
  xor    0xd(%rcx),%sil
  or     %esi,%eax
  movzbl 0xe(%rdi),%esi
  xor    0xe(%rcx),%sil
  or     %esi,%eax
  movzbl 0xf(%rdi),%edx
  xor    0xf(%rcx),%dl
  or     %edx,%eax
  movzbl %al,%eax
  sub    $0x1,%eax
  shr    $0x1f,%eax
  sub    $0x1,%eax
  ret
```

assistant: ```c
int crypto_verify_16(const unsigned char *x, const unsigned char *y) {
  unsigned int differentbits = 0;
  differentbits |= x[0] ^ y[0];
  differentbits |= x[1] ^ y[1];
  differentbits |= x[2] ^ y[2];
  differentbits |= x[3] ^ y[3];
  differentbits |= x[4] ^ y[4];
  differentbits |= x[5] ^ y[5];
  differentbits |= x[6] ^ y[6];
  differentbits |= x[7] ^ y[7];
  differentbits |= x[8] ^ y[8];
  differentbits |= x[9] ^ y[9];
  differentbits |= x[10] ^ y[10];
  differentbits |= x[11] ^ y[11];
  differentbits |= x[12] ^ y[12];
  differentbits |= x[13] ^ y[13];
  differentbits |= x[14] ^ y[14];
  differentbits |= x[15] ^ y[15];
  return (1 & ((differentbits - 1) >> 8)) - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<insert_linefeed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xd,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *insert_linefeed(char *str) {
  *(str++) = '\n';
  *(str++) = '\r';
  *str = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_linefeed>:
  endbr64
  movb   $0xa,(%rdi)
  movb   $0xd,0x1(%rdi)
  movb   $0x0,0x2(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *insert_linefeed(char *str) {
  *(str++) = '\n';
  *(str++) = '\r';
  *str = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insert_linefeed>:
  endbr64
  mov    $0xd0a,%eax
  movb   $0x0,0x2(%rdi)
  mov    %ax,(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *insert_linefeed(char *str) {
  *(str++) = '\n';
  *(str++) = '\r';
  *str = '\0';
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insert_linefeed>:
  endbr64
  mov    $0xd0a,%eax
  movb   $0x0,0x2(%rdi)
  mov    %ax,(%rdi)
  lea    0x2(%rdi),%rax
  ret
```

assistant: ```c
char *insert_linefeed(char *str) {
  *(str++) = '\n';
  *(str++) = '\r';
  *str = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<to_1750flt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <frexp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    $0xffffff80,%eax
  jge    L26
  mov    $0xffffffff,%eax
  jmp    L7
L26:
  mov    -0x14(%rbp),%eax
  cmp    $0x7f,%eax
  jle    L21
  mov    $0x1,%eax
  jmp    L7
L21:
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L4
  movsd  -0x28(%rbp),%xmm0
  comisd D0(%rip),%xmm0
  jb     L4
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L4:
  movsd  -0x28(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sar    $0x10,%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%al
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  movzbl %al,%edx
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  or     %ecx,%edx
  mov    %dx,(%rax)
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: f32[4]
name: extract_symbolic_data
arguments: tag: D6
datatype: f64

tool: {"D0": [0.0,-1.75,0.0,28.0]}

tool: D6: 2147483648

assistant: ```c
int to_1750flt(double input, short output[2]) {
  int exp;
  long mant;
  input = frexp(input, &exp);
  if (exp < -128)
    return -1;
  else if (exp > 127)
    return 1;
  if (input < 0.0 && input >= -0.5) {
    input *= 2.0;
    exp--;
  }
  mant = (long)(input * 2147483648.0);
  output[0] = (short)(mant >> 16);
  output[1] = (short)(mant & 0xFF00) | (exp & 0xFF);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<to_1750flt>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <frexp@plt>
  mov    0x4(%rsp),%edx
  mov    $0xffffffff,%eax
  cmp    $0xffffff80,%edx
  jl     L44
  mov    $0x1,%eax
  cmp    $0x7f,%edx
  jg     L44
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L38
L49:
  mulsd  D17(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,%rdx
  sar    $0x10,%rdx
  mov    %dx,(%rbx)
  movzbl 0x4(%rsp),%edx
  mov    $0x0,%al
  or     %edx,%eax
  mov    %ax,0x2(%rbx)
  mov    $0x0,%eax
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbx
  ret
L38:
  comisd D4(%rip),%xmm0
  jb     L49
  addsd  %xmm0,%xmm0
  sub    $0x1,%edx
  mov    %edx,0x4(%rsp)
  jmp    L49
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: f64
name: unpack_data
arguments: label: D4
data_type: f32[4]

tool: D17: 2147483648

tool: {"D4": [0.0,-1.75,0.0,28.0]}

assistant: ```c
int to_1750flt(double input, short output[2]) {
  int exp;
  long mant;
  input = frexp(input, &exp);
  if (exp < -128)
    return -1;
  else if (exp > 127)
    return 1;
  if (input < 0.0 && input >= -0.5) {
    input *= 2.0;
    exp--;
  }
  mant = (long)(input * 2147483648.0);
  output[0] = (short)(mant >> 16);
  output[1] = (short)(mant & 0xFF00) | (exp & 0xFF);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to_1750flt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <frexp@plt>
  mov    0x4(%rsp),%eax
  mov    $0xffffffff,%r8d
  cmp    $0xffffff80,%eax
  jl     L13
  mov    $0x1,%r8d
  cmp    $0x7f,%eax
  jg     L13
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
L22:
  mulsd  D7(%rip),%xmm0
  movzbl %al,%eax
  xor    %r8d,%r8d
  cvttsd2si %xmm0,%rdx
  mov    %rdx,%rcx
  xor    %dl,%dl
  sar    $0x10,%rcx
  or     %eax,%edx
  mov    %cx,(%rbx)
  mov    %dx,0x2(%rbx)
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  comisd D12(%rip),%xmm0
  jb     L22
  addsd  %xmm0,%xmm0
  sub    $0x1,%eax
  jmp    L22
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: f64
name: disassemble_data
arguments: label: D12
data_type: f32[4]

tool: D7: 2147483648

tool: {"D12": [0.0,-1.75,0.0,28.0]}

assistant: ```c
int to_1750flt(double input, short output[2]) {
  int exp;
  long mant;
  input = frexp(input, &exp);
  if (exp < -128)
    return -1;
  else if (exp > 127)
    return 1;
  if (input < 0.0 && input >= -0.5) {
    input *= 2.0;
    exp--;
  }
  mant = (long)(input * 2147483648.0);
  output[0] = (short)(mant >> 16);
  output[1] = (short)(mant & 0xFF00) | (exp & 0xFF);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<to_1750flt>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <frexp@plt>
  mov    0x4(%rsp),%eax
  mov    $0xffffffff,%r8d
  cmp    $0xffffff80,%eax
  jl     L55
  mov    $0x1,%r8d
  cmp    $0x7f,%eax
  jg     L55
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L27
L7:
  mulsd  D11(%rip),%xmm0
  movzbl %al,%eax
  xor    %r8d,%r8d
  cvttsd2si %xmm0,%rdx
  mov    %rdx,%rcx
  xor    %dl,%dl
  sar    $0x10,%rcx
  or     %eax,%edx
  mov    %cx,(%rbx)
  mov    %dx,0x2(%rbx)
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  comisd D8(%rip),%xmm0
  jb     L7
  addsd  %xmm0,%xmm0
  sub    $0x1,%eax
  jmp    L7
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: f64
name: extract_symbolic_data
arguments: tag: D8
type_infered: f32[4]

tool: D11: 2147483648

tool: {"D8": [0.0,-1.75,0.0,28.0]}

assistant: ```c
int to_1750flt(double input, short output[2]) {
  int exp;
  long mant;
  input = frexp(input, &exp);
  if (exp < -128)
    return -1;
  else if (exp > 127)
    return 1;
  if (input < 0.0 && input >= -0.5) {
    input *= 2.0;
    exp--;
  }
  mant = (long)(input * 2147483648.0);
  output[0] = (short)(mant >> 16);
  output[1] = (short)(mant & 0xFF00) | (exp & 0xFF);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  int aa = *((int *)a);
  int bb = *((int *)b);
  return (aa) - (bb);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  int aa = *((int *)a);
  int bb = *((int *)b);
  return (aa) - (bb);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  int aa = *((int *)a);
  int bb = *((int *)b);
  return (aa) - (bb);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  int aa = *((int *)a);
  int bb = *((int *)b);
  return (aa) - (bb);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_parse_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L43
  mov    $0xffffffff,%eax
  jmp    L48
L43:
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L45
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
L45:
  mov    $0xffffffff,%eax
  jmp    L48
L0:
  mov    -0x10(%rbp),%rax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int _parse_unsigned(char const *string) {
  char *p;
  long l;
  if (string == NULL)
    return -1;
  l = strtol(string, &p, 0);
  if (string[0] == '\0' || *p != '\0')
    return -1;
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_parse_unsigned>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbx
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <strtol@plt>
  cmpb   $0x0,(%rbx)
  je     L12
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L38
L12:
  mov    $0xffffffff,%eax
  jmp    L38
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _parse_unsigned(char const *string) {
  char *p;
  long l;
  if (string == NULL)
    return -1;
  l = strtol(string, &p, 0);
  if (string[0] == '\0' || *p != '\0')
    return -1;
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<_parse_unsigned>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  mov    %rdi,%rbx
  xor    %edx,%edx
  mov    %rsp,%rsi
  call   <strtol@plt>
  cmpb   $0x0,(%rbx)
  je     L5
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L5
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L5:
  mov    $0xffffffff,%eax
  jmp    L33
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _parse_unsigned(char const *string) {
  char *p;
  long l;
  if (string == NULL)
    return -1;
  l = strtol(string, &p, 0);
  if (string[0] == '\0' || *p != '\0')
    return -1;
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_parse_unsigned>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbx
  xor    %edx,%edx
  mov    %rsp,%rsi
  call   <strtol@plt>
  cmpb   $0x0,(%rbx)
  je     L0
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L0
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L0:
  mov    $0xffffffff,%eax
  jmp    L13
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _parse_unsigned(char const *string) {
  char *p;
  long l;
  if (string == NULL)
    return -1;
  l = strtol(string, &p, 0);
  if (string[0] == '\0' || *p != '\0')
    return -1;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <isatty@plt>
  test   %rax,%rax
  je     L56
  lea    D74(%rip),%rax
  jmp    L46
L56:
  lea    D8(%rip),%rax
L46:
  mov    %rax,%rsi
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <isatty@plt>
  test   %rax,%rax
  je     L27
  lea    D74(%rip),%rax
  jmp    L17
L27:
  lea    D8(%rip),%rax
L17:
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <isatty@plt>
  test   %rax,%rax
  je     L16
  lea    D74(%rip),%rax
  jmp    L23
L16:
  lea    D8(%rip),%rax
L23:
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D74
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D85
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string

tool: D74: tty

tool: D8: not a tty

tool: D85: fd 0: %s


tool: D18: fd 1: %s


tool: D23: fd 2: %s


assistant: ```c
int main(void) {
  printf("fd 0: %s\n", isatty(0) ? "tty" : "not a tty");
  printf("fd 1: %s\n", isatty(1) ? "tty" : "not a tty");
  printf("fd 2: %s\n", isatty(2) ? "tty" : "not a tty");
  exit(0);
}
```