ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_index>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  add    $0x1,%rdi
  mov    $0x0,%eax
L16:
  lea    (%rax,%rax,8),%eax
  movsbl %dl,%edx
  lea    (%rdx,%rax,4),%edx
  movslq %edx,%rax
  imul   $0x33af3e2f,%rax,%rax
  sar    $0x26,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x13d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L16
  ret
L14:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hash_index(char *text) {
  int i, h = 0;
  for (i = 0; text[i] != '\0'; i++)
    h = (h * 36 + text[i]) % 317;
  return h;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_index>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L18:
  lea    (%rax,%rax,8),%eax
  add    $0x1,%rdi
  lea    (%rdx,%rax,4),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x33af3e2f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0x13d,%eax,%ecx
  mov    %edx,%eax
  movsbl -0x1(%rdi),%edx
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L18
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash_index(char *text) {
  int i, h = 0;
  for (i = 0; text[i] != '\0'; i++)
    h = (h * 36 + text[i]) % 317;
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_index>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L6:
  lea    (%rax,%rax,8),%eax
  add    $0x1,%rdi
  lea    (%rdx,%rax,4),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x33af3e2f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  imul   $0x13d,%eax,%ecx
  mov    %edx,%eax
  movsbl -0x1(%rdi),%edx
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L6
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash_index(char *text) {
  int i, h = 0;
  for (i = 0; text[i] != '\0'; i++)
    h = (h * 36 + text[i]) % 317;
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cmdline@plt>
  mov    $0x0,%eax
  call   <cpus_init@plt>
  mov    $0x0,%eax
  call   <verify_param@plt>
  test   %eax,%eax
  jne    L9
  mov    $0x0,%eax
  call   <help@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L9:
  mov    $0x0,%eax
  call   <start_worker_threads@plt>
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  cmdline(argc, argv);
  cpus_init();
  if (!verify_param()) {
    help();
    return -1;
  }
  start_worker_threads();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <cmdline@plt>
  mov    $0x0,%eax
  call   <cpus_init@plt>
  mov    $0x0,%eax
  call   <verify_param@plt>
  test   %eax,%eax
  je     L17
  mov    $0x0,%eax
  call   <start_worker_threads@plt>
  mov    $0x0,%eax
L5:
  add    $0x8,%rsp
  ret
L17:
  call   <help@plt>
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int main(int argc, char *argv[]) {
  cmdline(argc, argv);
  cpus_init();
  if (!verify_param()) {
    help();
    return -1;
  }
  start_worker_threads();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <cmdline@plt>
  xor    %eax,%eax
  call   <cpus_init@plt>
  xor    %eax,%eax
  call   <verify_param@plt>
  test   %eax,%eax
  je     L13
  xor    %eax,%eax
  call   <start_worker_threads@plt>
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  ret
L13:
  call   <help@plt>
  or     $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  cmdline(argc, argv);
  cpus_init();
  if (!verify_param()) {
    help();
    return -1;
  }
  start_worker_threads();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <cmdline@plt>
  xor    %eax,%eax
  call   <cpus_init@plt>
  xor    %eax,%eax
  call   <verify_param@plt>
  test   %eax,%eax
  je     L4
  xor    %eax,%eax
  call   <start_worker_threads@plt>
  xor    %eax,%eax
L15:
  add    $0x8,%rsp
  ret
L4:
  call   <help@plt>
  or     $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int main(int argc, char *argv[]) {
  cmdline(argc, argv);
  cpus_init();
  if (!verify_param()) {
    help();
    return -1;
  }
  start_worker_threads();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raw_kbhit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movl   $0x64,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <FD_SET@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rcx
  lea    -0x2c(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int raw_kbhit() {
  struct timeval wait;
  fd_set readfd, writefd, exceptfd;
  int ret;
  wait.tv_sec = 0;
  wait.tv_usec = 100;
  FD_ZERO(&readfd);
  FD_SET(0, &readfd);
  FD_ZERO(&writefd);
  FD_ZERO(&exceptfd);
  ret = select(0 + 1, &readfd, &writefd, &exceptfd, &wait);
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<raw_kbhit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x18(%rsp)
  movl   $0x64,0x10(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <FD_SET@plt>
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  lea    0x10(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int raw_kbhit() {
  struct timeval wait;
  fd_set readfd, writefd, exceptfd;
  int ret;
  wait.tv_sec = 0;
  wait.tv_usec = 100;
  FD_ZERO(&readfd);
  FD_SET(0, &readfd);
  FD_ZERO(&writefd);
  FD_ZERO(&exceptfd);
  ret = select(0 + 1, &readfd, &writefd, &exceptfd, &wait);
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<raw_kbhit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  mov    %rbp,%rdi
  movl   $0x64,0x10(%rsp)
  lea    0xc(%rsp),%r13
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <FD_SET@plt>
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rdx
  lea    0x10(%rsp),%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int raw_kbhit() {
  struct timeval wait;
  fd_set readfd, writefd, exceptfd;
  int ret;
  wait.tv_sec = 0;
  wait.tv_usec = 100;
  FD_ZERO(&readfd);
  FD_SET(0, &readfd);
  FD_ZERO(&writefd);
  FD_ZERO(&exceptfd);
  ret = select(0 + 1, &readfd, &writefd, &exceptfd, &wait);
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<raw_kbhit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  mov    %rbp,%rdi
  movl   $0x64,0x10(%rsp)
  lea    0xc(%rsp),%r13
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <FD_SET@plt>
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rdx
  lea    0x10(%rsp),%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <select@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int raw_kbhit() {
  struct timeval wait;
  fd_set readfd, writefd, exceptfd;
  int ret;
  wait.tv_sec = 0;
  wait.tv_usec = 100;
  FD_ZERO(&readfd);
  FD_SET(0, &readfd);
  FD_ZERO(&writefd);
  FD_ZERO(&exceptfd);
  ret = select(0 + 1, &readfd, &writefd, &exceptfd, &wait);
  return (ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<mat_copier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L24
L20:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L19:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L20
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **mat_copier(char grid[][11], int n) {
  int i, j;
  char **p;
  char *tem;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * n);
    for (j = 0; j < n; ++j) {
      tem[j] = grid[i][j];
    }
    p[i] = tem;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mat_copier>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %r12d,%r12d
  jle    L6
  mov    %rax,%rbx
  mov    %r12d,%eax
  lea    (%r15,%rax,8),%r14
  mov    %r12d,%r13d
L23:
  mov    %r12d,%edi
  call   <malloc@plt>
  lea    0x0(%r13,%rax,1),%rdi
  mov    %rax,%rdx
  mov    %rbp,%rsi
  sub    %rax,%rsi
L7:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L7
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  add    $0xb,%rbp
  cmp    %r14,%rbx
  jne    L23
L6:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **mat_copier(char grid[][11], int n) {
  int i, j;
  char **p;
  char *tem;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * n);
    for (j = 0; j < n; ++j) {
      tem[j] = grid[i][j];
    }
    p[i] = tem;
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat_copier>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  lea    0x0(,%rsi,8),%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L21
  mov    %ebx,%ebp
  mov    %rax,%r14
  lea    (%rax,%rbp,8),%r12
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %r15,%rsi
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%rdx
  sub    %rax,%rsi
  nopl   0x0(%rax)
L2:
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L2
  mov    %rax,(%r14)
  add    $0x8,%r14
  add    $0xb,%r15
  cmp    %r12,%r14
  jne    L5
L21:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **mat_copier(char grid[][11], int n) {
  int i, j;
  char **p;
  char *tem;
  p = (char **)malloc(sizeof(char *) * n);
  for (i = 0; i < n; ++i) {
    tem = (char *)malloc(sizeof(char) * n);
    for (j = 0; j < n; ++j) {
      tem[j] = grid[i][j];
    }
    p[i] = tem;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L8:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L8
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string

tool: D13: %d

tool: D15: %d %d %d

assistant: ```c
int main() {
  int a, b, c, t;
  int i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &t);
  do {
    rotr(&a, &b, &c);
    i++;
  } while (i < t);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
L10:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jg     L10
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D14
type: string

tool: D19: %d

tool: D14: %d %d %d

assistant: ```c
int main() {
  int a, b, c, t;
  int i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &t);
  do {
    rotr(&a, &b, &c);
    i++;
  } while (i < t);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0xc(%rsp),%r12
  mov    %r13,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L1
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D7(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D7
type: string

tool: D19: %d

tool: D7: %d %d %d

assistant: ```c
int main() {
  int a, b, c, t;
  int i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &t);
  do {
    rotr(&a, &b, &c);
    i++;
  } while (i < t);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0xc(%rsp),%r12
  mov    %r13,%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x14(%rsp)
  jg     L0
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D11(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D0: %d

tool: D11: %d %d %d

assistant: ```c
int main() {
  int a, b, c, t;
  int i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &t);
  do {
    rotr(&a, &b, &c);
    i++;
  } while (i < t);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L29:
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L31:
  mov    -0x14(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L31
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D8: 
Matrix %s


tool: D13: %8g	

assistant: ```c
void print_matrix(int N, char *name, double *matrix) {
  printf("\nMatrix %s\n", name);
  for (int i = 0; i < N; i++) {
    for (int j = 0; j < N; j++) {
      printf("%8g\t", matrix[N * i + j]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %rdx,%rbx
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r14d,%r14d
  jle    L21
  movslq %r14d,%rax
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r14),%eax
  lea    0x8(%rbx,%rax,8),%rbp
  mov    $0x0,%r13d
  mov    %r14d,%r15d
  neg    %r15
  shl    $0x3,%r15
  lea    D16(%rip),%r12
L7:
  lea    (%r15,%rbp,1),%rbx
L1:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x8(%rsp),%rbp
  cmp    %r13d,%r14d
  jne    L7
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string

tool: D3: 
Matrix %s


tool: D16: %8g	

assistant: ```c
void print_matrix(int N, char *name, double *matrix) {
  printf("\nMatrix %s\n", name);
  for (int i = 0; i < N; i++) {
    for (int j = 0; j < N; j++) {
      printf("%8g\t", matrix[N * i + j]);
    }
    printf("\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_matrix>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edi,%r13d
  lea    D6(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L11
  movslq %r13d,%r15
  mov    $0xfffffffffffffff8,%r14
  xor    %r12d,%r12d
  lea    0x0(,%r15,8),%rax
  lea    D1(%rip),%rbp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%r13),%eax
  shl    $0x3,%rax
  lea    0x8(%rbx,%rax,1),%rbx
  sub    %rax,%r14
  nopl   0x0(%rax)
L29:
  lea    (%r14,%rbx,1),%r15
  nopl   0x0(%rax)
L15:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L15
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  add    0x8(%rsp),%rbx
  cmp    %r12d,%r13d
  jne    L29
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D6: 
Matrix %s


tool: D1: %8g	

assistant: ```c
void print_matrix(int N, char *name, double *matrix) {
  printf("\nMatrix %s\n", name);
  for (int i = 0; i < N; i++) {
    for (int j = 0; j < N; j++) {
      printf("%8g\t", matrix[N * i + j]);
    }
    printf("\n");
  }
}
```