ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<step2b_dbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L37
L12:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L2
  addq   $0x1,-0x8(%rbp)
L2:
  addq   $0x1,-0x10(%rbp)
L37:
  mov    -0x10(%rbp),%rax
  cmp    0x20(%rbp),%rax
  jl     L12
  mov    -0x8(%rbp),%rax
  cmp    0x28(%rbp),%rax
  jne    L39
  mov    0x20(%rbp),%rcx
  mov    0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <buildassignmentvector_dbl@plt>
  jmp    L23
L39:
  mov    -0x40(%rbp),%r8
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <step3_dbl@plt>
  add    $0x20,%rsp
L23:
  nop
  leave
  ret
```

assistant: ```c
void step2b_dbl(long *assignment, double *distMatrix, bool *starMatrix, bool *newStarMatrix, bool *primeMatrix, bool *coveredColumns, bool *coveredRows, long nOfRows, long nOfColumns, long minDim) {
  long col, nOfCoveredColumns;
  nOfCoveredColumns = 0;
  for (col = 0; col < nOfColumns; col++)
    if (coveredColumns[col])
      nOfCoveredColumns++;
  if (nOfCoveredColumns == minDim) {
    buildassignmentvector_dbl(assignment, starMatrix, nOfRows, nOfColumns);
  } else {
    step3_dbl(assignment, distMatrix, starMatrix, newStarMatrix, primeMatrix, coveredColumns, coveredRows, nOfRows, nOfColumns, minDim);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<step2b_dbl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r10
  mov    %rcx,%rbp
  mov    0x28(%rsp),%rdx
  mov    0x30(%rsp),%r11
  mov    0x38(%rsp),%r12
  test   %r11,%r11
  jle    L21
  mov    %r9,%rax
  lea    (%r9,%r11,4),%rsi
  mov    $0x0,%ecx
L31:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rcx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L31
L40:
  cmp    %rcx,%r12
  je     L37
  push   %r12
  push   %r11
  push   %rdx
  push   0x38(%rsp)
  mov    %rbp,%rcx
  mov    %r10,%rdx
  mov    %rbx,%rsi
  call   <step3_dbl@plt>
  add    $0x20,%rsp
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0x0,%ecx
  jmp    L40
L37:
  mov    %r11,%rcx
  mov    %r10,%rsi
  call   <buildassignmentvector_dbl@plt>
  jmp    L36
```

assistant: ```c
void step2b_dbl(long *assignment, double *distMatrix, bool *starMatrix, bool *newStarMatrix, bool *primeMatrix, bool *coveredColumns, bool *coveredRows, long nOfRows, long nOfColumns, long minDim) {
  long col, nOfCoveredColumns;
  nOfCoveredColumns = 0;
  for (col = 0; col < nOfColumns; col++)
    if (coveredColumns[col])
      nOfCoveredColumns++;
  if (nOfCoveredColumns == minDim) {
    buildassignmentvector_dbl(assignment, starMatrix, nOfRows, nOfColumns);
  } else {
    step3_dbl(assignment, distMatrix, starMatrix, newStarMatrix, primeMatrix, coveredColumns, coveredRows, nOfRows, nOfColumns, minDim);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<step2b_dbl>:
  endbr64
  push   %r13
  mov    %rdx,%r10
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11
  mov    0x28(%rsp),%rbp
  mov    0x30(%rsp),%r13
  mov    0x40(%rsp),%rbx
  test   %r11,%r11
  jle    L13
  mov    %r9,%rax
  lea    (%r9,%r11,4),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L19:
  cmpl   $0x1,(%rax)
  sbb    $0xffffffffffffffff,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L19
L18:
  cmp    %rdx,%rbx
  je     L37
  mov    %rbx,0x40(%rsp)
  mov    %r12,%rcx
  mov    %r10,%rdx
  mov    %r11,0x38(%rsp)
  mov    %r13,0x30(%rsp)
  mov    %rbp,0x28(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <step3_dbl@plt>
  nopw   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  mov    %r13,%rdx
  pop    %rbp
  mov    %r11,%rcx
  pop    %r12
  mov    %r10,%rsi
  pop    %r13
  jmp    1060 <buildassignmentvector_dbl@plt>
  nopl   0x0(%rax)
L13:
  xor    %edx,%edx
  jmp    L18
```

assistant: ```c
void step2b_dbl(long *assignment, double *distMatrix, bool *starMatrix, bool *newStarMatrix, bool *primeMatrix, bool *coveredColumns, bool *coveredRows, long nOfRows, long nOfColumns, long minDim) {
  long col, nOfCoveredColumns;
  nOfCoveredColumns = 0;
  for (col = 0; col < nOfColumns; col++)
    if (coveredColumns[col])
      nOfCoveredColumns++;
  if (nOfCoveredColumns == minDim) {
    buildassignmentvector_dbl(assignment, starMatrix, nOfRows, nOfColumns);
  } else {
    step3_dbl(assignment, distMatrix, starMatrix, newStarMatrix, primeMatrix, coveredColumns, coveredRows, nOfRows, nOfColumns, minDim);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<step2b_dbl>:
  endbr64
  push   %r14
  mov    %rcx,%r11
  mov    %rdx,%r10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x40(%rsp),%rcx
  mov    0x30(%rsp),%rbp
  mov    0x38(%rsp),%r12
  mov    0x48(%rsp),%rbx
  test   %rcx,%rcx
  jle    L49
  lea    -0x1(%rcx),%rax
  cmp    $0x2,%rax
  jbe    L80
  mov    %rcx,%rdx
  pxor   %xmm1,%xmm1
  pxor   %xmm3,%xmm3
  mov    %r9,%rax
  shr    $0x2,%rdx
  movdqa D2(%rip),%xmm5
  shl    $0x4,%rdx
  add    %r9,%rdx
  xchg   %ax,%ax
L56:
  movdqu (%rax),%xmm0
  movdqa %xmm3,%xmm2
  add    $0x10,%rax
  pcmpeqd %xmm3,%xmm0
  pandn  %xmm5,%xmm0
  pcmpgtd %xmm0,%xmm2
  movdqa %xmm0,%xmm4
  punpckldq %xmm2,%xmm4
  punpckhdq %xmm2,%xmm0
  paddq  %xmm4,%xmm1
  paddq  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L56
  movdqa %xmm1,%xmm0
  mov    %rcx,%rdx
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffffc,%rdx
  paddq  %xmm0,%xmm1
  movq   %xmm1,%rax
  test   $0x3,%cl
  je     L83
L11:
  cmpl   $0x1,(%r9,%rdx,4)
  lea    0x1(%rdx),%r14
  lea    0x0(,%rdx,4),%r13
  sbb    $0xffffffffffffffff,%rax
  cmp    %rcx,%r14
  jge    L83
  cmpl   $0x1,0x4(%r9,%r13,1)
  sbb    $0xffffffffffffffff,%rax
  add    $0x2,%rdx
  cmp    %rdx,%rcx
  jle    L83
  cmpl   $0x1,0x8(%r9,%r13,1)
  sbb    $0xffffffffffffffff,%rax
L83:
  cmp    %rax,%rbx
  je     L53
  mov    %rcx,0x40(%rsp)
  mov    %r10,%rdx
  mov    %r11,%rcx
  mov    %rbx,0x48(%rsp)
  mov    %r12,0x38(%rsp)
  mov    %rbp,0x30(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <step3_dbl@plt>
  nopw   0x0(%rax,%rax,1)
L53:
  pop    %rbx
  mov    %r12,%rdx
  pop    %rbp
  mov    %r10,%rsi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <buildassignmentvector_dbl@plt>
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  jmp    L83
L80:
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: byte[16]

tool: {"D2": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void step2b_dbl(long *assignment, double *distMatrix, bool *starMatrix, bool *newStarMatrix, bool *primeMatrix, bool *coveredColumns, bool *coveredRows, long nOfRows, long nOfColumns, long minDim) {
  long col, nOfCoveredColumns;
  nOfCoveredColumns = 0;
  for (col = 0; col < nOfColumns; col++)
    if (coveredColumns[col])
      nOfCoveredColumns++;
  if (nOfCoveredColumns == minDim) {
    buildassignmentvector_dbl(assignment, starMatrix, nOfRows, nOfColumns);
  } else {
    step3_dbl(assignment, distMatrix, starMatrix, newStarMatrix, primeMatrix, coveredColumns, coveredRows, nOfRows, nOfColumns, minDim);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: Usage: recover file ...


assistant: ```c
usage() {
  std_err("Usage: recover file ...\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: Usage: recover file ...


assistant: ```c
usage() {
  std_err("Usage: recover file ...\n");
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <std_err@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: Usage: recover file ...


assistant: ```c
usage() {
  std_err("Usage: recover file ...\n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <std_err@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: Usage: recover file ...


assistant: ```c
usage() {
  std_err("Usage: recover file ...\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<axi_stream_counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D25(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D16(%rip)
  mov    D16(%rip),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int axi_stream_counter(int *counter) {
  static int counterValue = 0;
  counterValue++;
  *counter = counterValue;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<axi_stream_counter>:
  endbr64
  mov    D6(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D5(%rip)
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int axi_stream_counter(int *counter) {
  static int counterValue = 0;
  counterValue++;
  *counter = counterValue;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<axi_stream_counter>:
  endbr64
  mov    D3(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D6(%rip)
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int axi_stream_counter(int *counter) {
  static int counterValue = 0;
  counterValue++;
  *counter = counterValue;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<axi_stream_counter>:
  endbr64
  mov    D15(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D10(%rip)
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int axi_stream_counter(int *counter) {
  static int counterValue = 0;
  counterValue++;
  *counter = counterValue;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L26
L27:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jb     L27
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D43
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D35
type_infered: string

tool: D43: Calculate fibonacci sequence up to:
N = 

tool: D9: %d

tool: D37: 
Sequence is:
%d

tool: D19: , %d

tool: D35: 


[Press ENTER to close]

assistant: ```c
int main() {
  unsigned int prev = 0, fib = 1, max;
  printf("Calculate fibonacci sequence up to:\nN = ");
  scanf("%d", &max);
  getchar();
  printf("\nSequence is:\n%d", prev);
  while (fib < max) {
    printf(", %d", fib);
    fib += prev;
    prev = fib - prev;
  }
  printf("\n\n\n[Press ENTER to close]");
  getchar();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D45(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jbe    L15
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  lea    D28(%rip),%r12
L4:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    %ebp,%ebx
  mov    %eax,%ebp
  cmp    %ebx,0x4(%rsp)
  ja     L4
L15:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D49
data_type: string
name: retrieve_data
arguments: data_label: D45
data_type: string
name: retrieve_data
arguments: data_label: D44
data_type: string
name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D24
data_type: string

tool: D49: Calculate fibonacci sequence up to:
N = 

tool: D45: %d

tool: D44: 
Sequence is:
%d

tool: D28: , %d

tool: D24: 


[Press ENTER to close]

assistant: ```c
int main() {
  unsigned int prev = 0, fib = 1, max;
  printf("Calculate fibonacci sequence up to:\nN = ");
  scanf("%d", &max);
  getchar();
  printf("\nSequence is:\n%d", prev);
  while (fib < max) {
    printf(", %d", fib);
    fib += prev;
    prev = fib - prev;
  }
  printf("\n\n\n[Press ENTER to close]");
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jbe    L26
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  lea    D15(%rip),%r12
  nopl   (%rax)
L9:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    %ebp,%ebx
  mov    %eax,%ebp
  cmp    %ebx,0x4(%rsp)
  ja     L9
L26:
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D14: Calculate fibonacci sequence up to:
N = 

tool: D4: %d

tool: D28: 
Sequence is:
%d

tool: D15: , %d

tool: D0: 


[Press ENTER to close]

assistant: ```c
int main() {
  unsigned int prev = 0, fib = 1, max;
  printf("Calculate fibonacci sequence up to:\nN = ");
  scanf("%d", &max);
  getchar();
  printf("\nSequence is:\n%d", prev);
  while (fib < max) {
    printf(", %d", fib);
    fib += prev;
    prev = fib - prev;
  }
  printf("\n\n\n[Press ENTER to close]");
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D30(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jbe    L27
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  lea    D4(%rip),%r12
  nopl   (%rax)
L28:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    %ebp,%ebx
  mov    %eax,%ebp
  cmp    %ebx,0x4(%rsp)
  ja     L28
L27:
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: string

tool: D30: Calculate fibonacci sequence up to:
N = 

tool: D11: %d

tool: D1: 
Sequence is:
%d

tool: D4: , %d

tool: D27: 


[Press ENTER to close]

assistant: ```c
int main() {
  unsigned int prev = 0, fib = 1, max;
  printf("Calculate fibonacci sequence up to:\nN = ");
  scanf("%d", &max);
  getchar();
  printf("\nSequence is:\n%d", prev);
  while (fib < max) {
    printf(", %d", fib);
    fib += prev;
    prev = fib - prev;
  }
  printf("\n\n\n[Press ENTER to close]");
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L10:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x1fc,-0x4(%rbp)
  jle    L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: 90 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 509; i++) {
    printf("90 ");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1fd,%ebx
  lea    D9(%rip),%rbp
L1:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D9: 90 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 509; i++) {
    printf("90 ");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1fd,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: 90 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 509; i++) {
    printf("90 ");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1fd,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: 90 

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 509; i++) {
    printf("90 ");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_243_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_243_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_243_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  and    %esi,%eax
  movzbl %al,%eax
  xor    %esi,%edi
  not    %edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_243_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_243_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  xor    %esi,%edi
  and    %esi,%eax
  not    %edi
  movzbl %al,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_243_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_243_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  not    %eax
  xor    %esi,%edi
  and    %esi,%eax
  not    %edi
  movzbl %al,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_243_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```