ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<estostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x1(%rax),%r8d
  movslq %r8d,%rdx
  add    $0xf,%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L121
L61:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L61
L121:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L193
L159:
  mov    %r8d,%edx
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    %rsp,%r13
  call   <memset@plt>
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  xor    %r12d,%r12d
  jmp    L164
L9:
  mov    %al,0x0(%r13,%r12,1)
  movslq %edx,%r12
L137:
  add    $0x1,%rbx
L164:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L192
  movzbl (%r15,%rbx,1),%eax
  cmp    $0x5c,%al
  je     L124
  lea    0x1(%r12),%edx
  test   %r14d,%r14d
  je     L9
  cmp    $0x72,%al
  je     L48
  jg     L103
  cmp    $0x30,%al
  je     L180
  cmp    $0x6e,%al
  jne    L31
  movb   $0xa,0x0(%r13,%r12,1)
L197:
  movslq %edx,%r12
  xor    %r14d,%r14d
  jmp    L137
  nopl   0x0(%rax,%rax,1)
L103:
  cmp    $0x74,%al
  jne    L31
  movb   $0x9,0x0(%r13,%r12,1)
  jmp    L197
  nopl   0x0(%rax)
L124:
  mov    $0x1,%r14d
  jmp    L137
  nopl   0x0(%rax,%rax,1)
L192:
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  movb   $0xd,0x0(%r13,%r12,1)
  jmp    L197
  nopl   0x0(%rax,%rax,1)
L31:
  movslq %edx,%rcx
  movb   $0x5c,0x0(%r13,%r12,1)
  add    $0x1,%edx
  mov    %al,0x0(%r13,%rcx,1)
  jmp    L197
  nopl   0x0(%rax,%rax,1)
L180:
  movb   $0x0,0x0(%r13,%r12,1)
  jmp    L197
  nopl   0x0(%rax,%rax,1)
L193:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L159
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *estostr(char *s) {
  int i, j = 0;
  int f = 0;
  char ss[strlen(s) + 1];
  memset(ss, 0, sizeof ss);
  for (i = 0; i < strlen(s) + 1; i++) {
    if (s[i] == '\\') {
      f = 1;
      continue;
    }
    if (f) {
      switch (s[i]) {
      case 'n':
        ss[j] = '\n';
        break;
      case 'r':
        ss[j] = '\r';
        break;
      case 't':
        ss[j] = '\t';
        break;
      case '0':
        ss[j] = '\0';
        break;
      case '\\':
        ss[j] = '\\';
        break;
      default:
        ss[j] = '\\';
        j++;
        ss[j] = s[i];
        break;
      }
      j++;
      f = 0;
      continue;
    }
    ss[j] = s[i];
    j++;
  }
  return strcpy(s, ss);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string

tool: D15: Please input 4 numbers:

tool: D14: %d %d %d %d

tool: D19: You entered:
%d
%d
%d
%d

assistant: ```c
main() {
  int n1, n2, n3, n4;
  printf("Please input 4 numbers:\n");
  scanf("%d %d %d %d", &n1, &n2, &n3, &n4);
  printf("You entered:\n%d\n%d\n%d\n%d", n4, n3, n2, n1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D3
datatype: string

tool: D8: Please input 4 numbers:

tool: D11: %d %d %d %d

tool: D3: You entered:
%d
%d
%d
%d

assistant: ```c
main() {
  int n1, n2, n3, n4;
  printf("Please input 4 numbers:\n");
  scanf("%d %d %d %d", &n1, &n2, &n3, &n4);
  printf("You entered:\n%d\n%d\n%d\n%d", n4, n3, n2, n1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  xor    %eax,%eax
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D15: Please input 4 numbers:

tool: D19: %d %d %d %d

tool: D6: You entered:
%d
%d
%d
%d

assistant: ```c
main() {
  int n1, n2, n3, n4;
  printf("Please input 4 numbers:\n");
  scanf("%d %d %d %d", &n1, &n2, &n3, &n4);
  printf("You entered:\n%d\n%d\n%d\n%d", n4, n3, n2, n1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  xor    %eax,%eax
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D29
type: string
name: unpack_data
arguments: data_tag: D17
type: string

tool: D8: Please input 4 numbers:

tool: D29: %d %d %d %d

tool: D17: You entered:
%d
%d
%d
%d

assistant: ```c
main() {
  int n1, n2, n3, n4;
  printf("Please input 4 numbers:\n");
  scanf("%d %d %d %d", &n1, &n2, &n3, &n4);
  printf("You entered:\n%d\n%d\n%d\n%d", n4, n3, n2, n1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L10:
  mov    $0x0,%eax
  call   <kkybrd_get_last_key@plt>
  mov    %eax,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  je     L10
  mov    $0x0,%eax
  call   <kkybrd_discard_last_key@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getch() {
  int key = 0;
  while (key == 0) {
    key = kkybrd_get_last_key();
  }
  kkybrd_discard_last_key();
  return key;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getch>:
  endbr64
  push   %rbx
L8:
  mov    $0x0,%eax
  call   <kkybrd_get_last_key@plt>
  test   %eax,%eax
  je     L8
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <kkybrd_discard_last_key@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getch() {
  int key = 0;
  while (key == 0) {
    key = kkybrd_get_last_key();
  }
  kkybrd_discard_last_key();
  return key;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getch>:
  endbr64
  push   %r12
  cs nopw 0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <kkybrd_get_last_key@plt>
  test   %eax,%eax
  je     L5
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <kkybrd_discard_last_key@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int getch() {
  int key = 0;
  while (key == 0) {
    key = kkybrd_get_last_key();
  }
  kkybrd_discard_last_key();
  return key;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getch>:
  endbr64
  push   %r12
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <kkybrd_get_last_key@plt>
  test   %eax,%eax
  je     L4
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <kkybrd_discard_last_key@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int getch() {
  int key = 0;
  while (key == 0) {
    key = kkybrd_get_last_key();
  }
  kkybrd_discard_last_key();
  return key;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<relay_dogechat_msg_add_pointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %al,-0x91(%rbp)
  lea    -0x91(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  movzbl -0x91(%rbp),%eax
  movzbl %al,%edx
  lea    -0x90(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: %lx

assistant: ```c
void relay_dogechat_msg_add_pointer(struct t_relay_dogechat_msg *msg, void *pointer) {
  char str_pointer[128];
  unsigned char length;
  snprintf(str_pointer, sizeof(str_pointer), "%lx", (long unsigned int)pointer);
  length = strlen(str_pointer);
  relay_dogechat_msg_add_bytes(msg, &length, 1);
  relay_dogechat_msg_add_bytes(msg, str_pointer, length);
}
```
user: What is the c source code of the assembly code below?

```asm
<relay_dogechat_msg_add_pointer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    D3(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %al,0xf(%rsp)
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %lx

assistant: ```c
void relay_dogechat_msg_add_pointer(struct t_relay_dogechat_msg *msg, void *pointer) {
  char str_pointer[128];
  unsigned char length;
  snprintf(str_pointer, sizeof(str_pointer), "%lx", (long unsigned int)pointer);
  length = strlen(str_pointer);
  relay_dogechat_msg_add_bytes(msg, &length, 1);
  relay_dogechat_msg_add_bytes(msg, str_pointer, length);
}
```
user: What is the c source code of the assembly code below:

```asm
<relay_dogechat_msg_add_pointer>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D8(%rip),%rdx
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <relay_dogechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: %lx

assistant: ```c
void relay_dogechat_msg_add_pointer(struct t_relay_dogechat_msg *msg, void *pointer) {
  char str_pointer[128];
  unsigned char length;
  snprintf(str_pointer, sizeof(str_pointer), "%lx", (long unsigned int)pointer);
  length = strlen(str_pointer);
  relay_dogechat_msg_add_bytes(msg, &length, 1);
  relay_dogechat_msg_add_bytes(msg, str_pointer, length);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<relay_dogechat_msg_add_pointer>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D8(%rip),%rdx
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <relay_dogechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <relay_dogechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: %lx

assistant: ```c
void relay_dogechat_msg_add_pointer(struct t_relay_dogechat_msg *msg, void *pointer) {
  char str_pointer[128];
  unsigned char length;
  snprintf(str_pointer, sizeof(str_pointer), "%lx", (long unsigned int)pointer);
  length = strlen(str_pointer);
  relay_dogechat_msg_add_bytes(msg, &length, 1);
  relay_dogechat_msg_add_bytes(msg, str_pointer, length);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x24(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
f() {
  int i = g();
  int j = {g()};
  int k[] = {g()};
  int l[] = {{g()}};
  struct {
    int x;
  } s = {g()};
  struct {
    int x;
  } s2[] = {g()};
  struct {
    int x;
  } s3[] = {{g()}};
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  mov    $0x0,%eax
  call   <g@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
f() {
  int i = g();
  int j = {g()};
  int k[] = {g()};
  int l[] = {{g()}};
  struct {
    int x;
  } s = {g()};
  struct {
    int x;
  } s2[] = {g()};
  struct {
    int x;
  } s3[] = {{g()}};
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <g@plt>
```

assistant: ```c
f() {
  int i = g();
  int j = {g()};
  int k[] = {g()};
  int l[] = {{g()}};
  struct {
    int x;
  } s = {g()};
  struct {
    int x;
  } s2[] = {g()};
  struct {
    int x;
  } s3[] = {{g()}};
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <g@plt>
```

assistant: ```c
f() {
  int i = g();
  int j = {g()};
  int k[] = {g()};
  int l[] = {{g()}};
  struct {
    int x;
  } s = {g()};
  struct {
    int x;
  } s2[] = {g()};
  struct {
    int x;
  } s3[] = {{g()}};
}
```
user: Translate the below assembly code into C programming language:

```asm
<jachs28>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%ebx
  mov    %ebx,%r12d
  jmp    L14
L1:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x1,%r12d
L14:
  cmp    -0x38(%rbp),%r12d
  jl     L1
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void jachs28(double *p, double *jac, int m, int n, void *data) {
  register int i, j;
  double t1, t2;
  t1 = p[0] + p[1];
  t2 = p[1] + p[2];
  for (i = j = 0; i < n; ++i) {
    jac[j++] = 2.0 * t1;
    jac[j++] = 2.0 * (t1 + t2);
    jac[j++] = 2.0 * t2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jachs28>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movapd %xmm0,%xmm1
  addsd  (%rdi),%xmm1
  addsd  0x10(%rdi),%xmm0
  test   %ecx,%ecx
  jle    L9
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm1
  addsd  %xmm0,%xmm0
  mov    %rsi,%rax
  lea    -0x1(%rcx),%edx
  lea    (%rdx,%rdx,2),%rdx
  lea    0x18(%rsi,%rdx,8),%rdx
L13:
  movsd  %xmm2,(%rax)
  movsd  %xmm1,0x8(%rax)
  movsd  %xmm0,0x10(%rax)
  add    $0x18,%rax
  cmp    %rdx,%rax
  jne    L13
L9:
  ret
```

assistant: ```c
void jachs28(double *p, double *jac, int m, int n, void *data) {
  register int i, j;
  double t1, t2;
  t1 = p[0] + p[1];
  t2 = p[1] + p[2];
  for (i = j = 0; i < n; ++i) {
    jac[j++] = 2.0 * t1;
    jac[j++] = 2.0 * (t1 + t2);
    jac[j++] = 2.0 * t2;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jachs28>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  addsd  %xmm0,%xmm1
  addsd  0x10(%rdi),%xmm0
  test   %ecx,%ecx
  jle    L13
  movapd %xmm1,%xmm2
  lea    -0x1(%rcx),%eax
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm0
  lea    (%rax,%rax,2),%rax
  lea    0x18(%rsi,%rax,8),%rax
  addsd  %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  %xmm2,(%rsi)
  add    $0x18,%rsi
  movsd  %xmm1,-0x10(%rsi)
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L7
L13:
  ret
```

assistant: ```c
void jachs28(double *p, double *jac, int m, int n, void *data) {
  register int i, j;
  double t1, t2;
  t1 = p[0] + p[1];
  t2 = p[1] + p[2];
  for (i = j = 0; i < n; ++i) {
    jac[j++] = 2.0 * t1;
    jac[j++] = 2.0 * (t1 + t2);
    jac[j++] = 2.0 * t2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jachs28>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mov    %rsi,%rdx
  addsd  %xmm0,%xmm1
  addsd  0x10(%rdi),%xmm0
  test   %ecx,%ecx
  jle    L3
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm1
  cmp    $0x1,%ecx
  je     L13
  movapd %xmm1,%xmm5
  movapd %xmm0,%xmm4
  movapd %xmm2,%xmm3
  mov    %rsi,%rax
  unpcklpd %xmm0,%xmm5
  unpcklpd %xmm2,%xmm4
  unpcklpd %xmm1,%xmm3
  mov    %ecx,%esi
  shr    %esi
  sub    $0x1,%esi
  lea    (%rsi,%rsi,2),%rsi
  shl    $0x4,%rsi
  lea    0x30(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax)
L8:
  movups %xmm3,(%rax)
  add    $0x30,%rax
  movups %xmm4,-0x20(%rax)
  movups %xmm5,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L8
  mov    %ecx,%esi
  and    $0xfffffffe,%esi
  lea    (%rsi,%rsi,2),%eax
  cmp    %esi,%ecx
  je     L35
L33:
  cltq
  lea    0x0(,%rax,8),%rcx
  movsd  %xmm2,(%rdx,%rax,8)
  movsd  %xmm1,0x8(%rdx,%rcx,1)
  movsd  %xmm0,0x10(%rdx,%rcx,1)
L3:
  ret
  nopl   0x0(%rax)
L35:
  ret
L13:
  xor    %eax,%eax
  jmp    L33
```

assistant: ```c
void jachs28(double *p, double *jac, int m, int n, void *data) {
  register int i, j;
  double t1, t2;
  t1 = p[0] + p[1];
  t2 = p[1] + p[2];
  for (i = j = 0; i < n; ++i) {
    jac[j++] = 2.0 * t1;
    jac[j++] = 2.0 * (t1 + t2);
    jac[j++] = 2.0 * t2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mpui_list_remove_last>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <mpui_list_length@plt>
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L7
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L7:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mpui_list_remove_last(void *list) {
  int n = mpui_list_length(list) - 1;
  void **l = list, *e = NULL;
  if (n >= 0) {
    e = l[n];
    l[n] = NULL;
  }
  return e;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpui_list_remove_last>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mpui_list_length@plt>
  mov    $0x0,%edx
  sub    $0x1,%eax
  js     L0
  cltq
  lea    (%rbx,%rax,8),%rax
  mov    (%rax),%rdx
  movq   $0x0,(%rax)
L0:
  mov    %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *mpui_list_remove_last(void *list) {
  int n = mpui_list_length(list) - 1;
  void **l = list, *e = NULL;
  if (n >= 0) {
    e = l[n];
    l[n] = NULL;
  }
  return e;
}
```