ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<bla2gt>:
  endbr64
  mov    D7(%rip),%rax
  cmp    %edi,(%rax)
  jl     L5
  ret
L5:
  xor    %eax,%eax
  jmp    1050 <this_comparison_is_not_decidable@plt>
```

assistant: ```c
void bla2gt(int var) {
  if (var + 10 > INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: What is the c source code of the assembly code below:

```asm
<bla2gt>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  jl     L7
  ret
L7:
  xor    %eax,%eax
  jmp    1050 <this_comparison_is_not_decidable@plt>
```

assistant: ```c
void bla2gt(int var) {
  if (var + 10 > INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_activities>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L29
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L17
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L17:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string

tool: D1: Following activities are selected

tool: D6: 
%d  

tool: D10: %d  

assistant: ```c
void print_activities(int start[], int finish[], int n) {
  printf("Following activities are selected");
  int i = 0;
  printf("\n%d  ", i);
  int j;
  for (j = 1; j < n; j++) {
    if (start[j] >= finish[i]) {
      printf("%d  ", j);
      i = j;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_activities>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L45
  mov    %ebp,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%edx
  lea    D21(%rip),%r14
  jmp    L14
L35:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L45
L14:
  mov    %ebx,%esi
  movslq %edx,%rax
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  jl     L35
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  jmp    L35
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type: string
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D21
type: string

tool: D22: Following activities are selected

tool: D15: 
%d  

tool: D21: %d  

assistant: ```c
void print_activities(int start[], int finish[], int n) {
  printf("Following activities are selected");
  int i = 0;
  printf("\n%d  ", i);
  int j;
  for (j = 1; j < n; j++) {
    if (start[j] >= finish[i]) {
      printf("%d  ", j);
      i = j;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_activities>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  call   <printf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L1
  mov    $0x1,%ebx
  xor    %edx,%edx
  lea    D1(%rip),%r13
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L1
L14:
  movslq %edx,%rax
  mov    %ebx,%esi
  mov    (%r14,%rax,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  jl     L31
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L14
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D1
type: string

tool: D18: Following activities are selected

tool: D27: 
%d  

tool: D1: %d  

assistant: ```c
void print_activities(int start[], int finish[], int n) {
  printf("Following activities are selected");
  int i = 0;
  printf("\n%d  ", i);
  int j;
  for (j = 1; j < n; j++) {
    if (start[j] >= finish[i]) {
      printf("%d  ", j);
      i = j;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_activities>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D12(%rip),%rdi
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  call   <printf@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L36
  mov    $0x1,%ebx
  xor    %edx,%edx
  lea    D13(%rip),%r13
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L36
L38:
  movslq %edx,%rax
  mov    %ebx,%esi
  mov    (%r14,%rax,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  jl     L15
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L38
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D12: Following activities are selected

tool: D17: 
%d  

tool: D13: %d  

assistant: ```c
void print_activities(int start[], int finish[], int n) {
  printf("Following activities are selected");
  int i = 0;
  printf("\n%d  ", i);
  int j;
  for (j = 1; j < n; j++) {
    if (start[j] >= finish[i]) {
      printf("%d  ", j);
      i = j;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_167_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_167_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_167_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  or     %esi,%eax
  movzbl %al,%eax
  xor    %esi,%eax
  or     %edi,%eax
  not    %eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: What is the c source code of the assembly code below:

```asm
<xrop3_167_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  or     %esi,%eax
  movzbl %al,%eax
  xor    %esi,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_167_1_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  or     %esi,%eax
  movzbl %al,%eax
  xor    %esi,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_167_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk2 = D & stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L21
L32:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L8:
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subq   $0x1,-0x8(%rbp)
L19:
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L8
L6:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x2c(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jb     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int *a, int n) {
  for (size_t i = 1; i < n; ++i) {
    int tmp = a[i];
    size_t j = i;
    while (j > 0 && tmp < a[j - 1]) {
      a[j] = a[j - 1];
      --j;
    }
    a[j] = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insertion_sort>:
  endbr64
  movslq %esi,%r9
  cmp    $0x1,%r9
  jbe    L60
  mov    $0x2,%r8d
  mov    $0x1,%esi
  jmp    L4
L72:
  mov    %ecx,(%rdi,%rax,4)
  cmp    %r9,%r8
  jae    L60
L1:
  add    $0x1,%rsi
  add    $0x1,%r8
L4:
  mov    (%rdi,%rsi,4),%ecx
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L18
L3:
  mov    -0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L72
  mov    %edx,(%rdi,%rax,4)
  sub    $0x1,%rax
  jne    L3
  jmp    L72
L18:
  mov    %ecx,(%rdi)
  jmp    L1
L60:
  ret
```

assistant: ```c
void insertion_sort(int *a, int n) {
  for (size_t i = 1; i < n; ++i) {
    int tmp = a[i];
    size_t j = i;
    while (j > 0 && tmp < a[j - 1]) {
      a[j] = a[j - 1];
      --j;
    }
    a[j] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insertion_sort>:
  endbr64
  movslq %esi,%r11
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  cmp    $0x1,%r11
  jbe    L27
  nopw   0x0(%rax,%rax,1)
L34:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9,%rdx
  nopl   0x0(%rax)
L18:
  mov    -0x4(%rax),%ecx
  mov    %rax,%rsi
  cmp    %r8d,%ecx
  jle    L6
  mov    %ecx,(%rax)
  lea    -0x4(%rsi),%rax
  sub    $0x1,%rdx
  jne    L18
  mov    %rdi,%rsi
L6:
  add    $0x1,%r9
  mov    %r8d,(%rsi)
  add    $0x4,%r10
  cmp    %r11,%r9
  jne    L34
L27:
  ret
```

assistant: ```c
void insertion_sort(int *a, int n) {
  for (size_t i = 1; i < n; ++i) {
    int tmp = a[i];
    size_t j = i;
    while (j > 0 && tmp < a[j - 1]) {
      a[j] = a[j - 1];
      --j;
    }
    a[j] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion_sort>:
  endbr64
  movslq %esi,%r11
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  cmp    $0x1,%r11
  jbe    L0
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9,%rdx
  nopl   0x0(%rax)
L23:
  mov    -0x4(%rax),%ecx
  mov    %rax,%rsi
  cmp    %r8d,%ecx
  jle    L8
  mov    %ecx,(%rax)
  lea    -0x4(%rsi),%rax
  sub    $0x1,%rdx
  jne    L23
  mov    %rdi,%rsi
L8:
  add    $0x1,%r9
  mov    %r8d,(%rsi)
  add    $0x4,%r10
  cmp    %r11,%r9
  jne    L17
L0:
  ret
```

assistant: ```c
void insertion_sort(int *a, int n) {
  for (size_t i = 1; i < n; ++i) {
    int tmp = a[i];
    size_t j = i;
    while (j > 0 && tmp < a[j - 1]) {
      a[j] = a[j - 1];
      --j;
    }
    a[j] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<writen_ni>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L32
L46:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L44
  mov    D7(%rip),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L46
L44:
  cmpq   $0x0,-0x8(%rbp)
  jle    L35
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L32:
  cmpq   $0x0,-0x18(%rbp)
  jne    L46
  jmp    L29
L35:
  nop
L29:
  mov    -0x38(%rbp),%rax
  sub    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t writen_ni(int fd, const void *buff, size_t n) {
  size_t nl;
  ssize_t nw;
  const char *p;
  p = buff;
  nl = n;
  while (nl > 0) {
    ;
    do {
      nw = write(fd, p, nl);
    } while (nw < 0 && errno == EINTR);
    if (nw <= 0)
      break;
    nl -= nw;
    p += nw;
  }
  return n - nl;
}
```
user: What is the c source code of the assembly code below?

```asm
<writen_ni>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L44
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L57
L9:
  je     L34
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L34
L57:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L9
  mov    D15(%rip),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L57
L34:
  mov    %r13,%rax
  sub    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    %rdx,%rbx
  jmp    L34
```

assistant: ```c
ssize_t writen_ni(int fd, const void *buff, size_t n) {
  size_t nl;
  ssize_t nw;
  const char *p;
  p = buff;
  nl = n;
  while (nl > 0) {
    ;
    do {
      nw = write(fd, p, nl);
    } while (nw < 0 && errno == EINTR);
    if (nw <= 0)
      break;
    nl -= nw;
    p += nw;
  }
  return n - nl;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<writen_ni>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L31
  jmp    L44
  nopl   0x0(%rax)
L50:
  mov    D7(%rip),%rax
  mov    D6(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L58
L31:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L50
  je     L58
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L31
L44:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L58:
  add    $0x8,%rsp
  sub    %rbx,%r13
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen_ni(int fd, const void *buff, size_t n) {
  size_t nl;
  ssize_t nw;
  const char *p;
  p = buff;
  nl = n;
  while (nl > 0) {
    ;
    do {
      nw = write(fd, p, nl);
    } while (nw < 0 && errno == EINTR);
    if (nw <= 0)
      break;
    nl -= nw;
    p += nw;
  }
  return n - nl;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writen_ni>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L0
  jmp    L37
  nopl   0x0(%rax)
L45:
  mov    D4(%rip),%rax
  mov    D9(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L55
L0:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L45
  je     L55
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L0
L37:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L55:
  add    $0x8,%rsp
  sub    %rbx,%r13
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen_ni(int fd, const void *buff, size_t n) {
  size_t nl;
  ssize_t nw;
  const char *p;
  p = buff;
  nl = n;
  while (nl > 0) {
    ;
    do {
      nw = write(fd, p, nl);
    } while (nw < 0 && errno == EINTR);
    if (nw <= 0)
      break;
    nl -= nw;
    p += nw;
  }
  return n - nl;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    D26(%rip),%rax
  movq   $0x0,(%rax)
  jmp    L89
L58:
  mov    -0x8(%rbp),%rsi
  mov    -0x20(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L24
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
L24:
  cmpl   $0x0,-0xc(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L61
  mov    $0x0,%eax
  jmp    L105
L26:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L80
  mov    $0x0,%eax
  jmp    L105
L80:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L3
L89:
  cmpl   $0x1,-0x10(%rbp)
  jg     L58
  jmp    L9
L61:
  nop
  jmp    L9
L3:
  nop
L9:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L105:
  leave
  ret
```

assistant: ```c
char *sgets(char *sbuf, int size, int sock) {
  int togo = size;
  char *s = sbuf;
  errno = 0;
  while (togo > 1) {
    int e;
    do {
      e = recv(sock, s, 1, 0);
      if (e == -1 && errno == EINTR)
        continue;
    } while (0);
    if (e == 0) {
      if (s == sbuf)
        return 0;
      break;
    }
    if (e == -1)
      return 0;
    s++;
    togo--;
    if (s[-1] == '\n')
      break;
  }
  *s++ = 0;
  return sbuf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sgets>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    D3(%rip),%rax
  movq   $0x0,(%rax)
  mov    %rdi,%rbx
  lea    (%rsi,%rdi,1),%ebp
L2:
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jle    L62
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L8
  cmp    $0xffffffff,%eax
  je     L67
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  jne    L2
L62:
  movb   $0x0,(%rbx)
  mov    %r13,%rax
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  cmp    %r13,%rbx
  jne    L62
  mov    $0x0,%eax
  jmp    L50
L67:
  mov    $0x0,%eax
  jmp    L50
```

assistant: ```c
char *sgets(char *sbuf, int size, int sock) {
  int togo = size;
  char *s = sbuf;
  errno = 0;
  while (togo > 1) {
    int e;
    do {
      e = recv(sock, s, 1, 0);
      if (e == -1 && errno == EINTR)
        continue;
    } while (0);
    if (e == 0) {
      if (s == sbuf)
        return 0;
      break;
    }
    if (e == -1)
      return 0;
    s++;
    togo--;
    if (s[-1] == '\n')
      break;
  }
  *s++ = 0;
  return sbuf;
}
```
user: What is the c source code of the assembly code below:

```asm
<sgets>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    (%rsi,%rdi,1),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  movq   $0x0,(%rax)
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L19
  cmp    $0xffffffff,%eax
  je     L9
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L29
L3:
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jg     L38
L29:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L19:
  cmp    %r13,%rbx
  jne    L29
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *sgets(char *sbuf, int size, int sock) {
  int togo = size;
  char *s = sbuf;
  errno = 0;
  while (togo > 1) {
    int e;
    do {
      e = recv(sock, s, 1, 0);
      if (e == -1 && errno == EINTR)
        continue;
    } while (0);
    if (e == 0) {
      if (s == sbuf)
        return 0;
      break;
    }
    if (e == -1)
      return 0;
    s++;
    togo--;
    if (s[-1] == '\n')
      break;
  }
  *s++ = 0;
  return sbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sgets>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    (%rsi,%rdi,1),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  movq   $0x0,(%rax)
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  test   %eax,%eax
  je     L18
  cmp    $0xffffffff,%eax
  je     L2
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L6
L13:
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jg     L0
L6:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L18:
  cmp    %r13,%rbx
  jne    L6
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *sgets(char *sbuf, int size, int sock) {
  int togo = size;
  char *s = sbuf;
  errno = 0;
  while (togo > 1) {
    int e;
    do {
      e = recv(sock, s, 1, 0);
      if (e == -1 && errno == EINTR)
        continue;
    } while (0);
    if (e == 0) {
      if (s == sbuf)
        return 0;
      break;
    }
    if (e == -1)
      return 0;
    s++;
    togo--;
    if (s[-1] == '\n')
      break;
  }
  *s++ = 0;
  return sbuf;
}
```