user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D50(%rip),%rsi
  lea    D39(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x1e(%rsp),%rcx
  lea    0x1d(%rsp),%rdx
  mov    %rax,%rdi
  mov    %rax,%r15
  xor    %eax,%eax
  lea    0x1f(%rsp),%r8
  lea    D17(%rip),%rsi
  call   <fscanf@plt>
  cmpb   $0x0,0x1d(%rsp)
  jle    L158
  movzbl 0x1e(%rsp),%eax
  xor    %r14d,%r14d
  lea    D1(%rip),%r12
L76:
  test   %al,%al
  jle    L158
  movsbq %r14b,%rax
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r13
  lea    (%rax,%rax,4),%rbp
  add    %rbp,%rbp
  nopw   0x0(%rax,%rax,1)
L89:
  movsbq %bl,%rax
  mov    %r12,%rsi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    %rbp,%rax
  lea    0x0(%r13,%rax,4),%rdx
  xor    %eax,%eax
  call   <fscanf@plt>
  movzbl 0x1e(%rsp),%eax
  cmp    %bl,%al
  jg     L89
  add    $0x1,%r14d
  cmp    0x1d(%rsp),%r14b
  jl     L76
L158:
  mov    %r15,%rdi
  call   <fclose@plt>
  movzbl 0x1d(%rsp),%eax
  test   %al,%al
  jle    L51
  movb   $0x1,0x8(%rsp)
  pxor   %xmm2,%xmm2
  movzbl 0x1e(%rsp),%edx
  movb   $0x0,0xc(%rsp)
  movss  %xmm2,0x4(%rsp)
L119:
  movb   $0x0,0xf(%rsp)
  test   %dl,%dl
  jle    L122
  nopl   0x0(%rax,%rax,1)
L132:
  cmp    %al,0xc(%rsp)
  jge    L122
  movzbl 0xc(%rsp),%r14d
  movsbl 0xf(%rsp),%r13d
  mov    $0x1,%eax
  sub    %r14d,%eax
  lea    -0x1(%r13),%ebx
  mov    %al,0xd(%rsp)
  mov    %bl,0xe(%rsp)
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl 0xd(%rsp),%eax
  movsbl 0x1f(%rsp),%edi
  lea    (%rax,%r14,1),%esi
  movsbl %sil,%esi
  call   <divpp@plt>
  movzbl 0xe(%rsp),%ecx
  movzbl 0x1e(%rsp),%edx
  lea    (%rax,%rcx,1),%r15d
  cmp    %dl,%r15b
  jge    L38
  cmpb   $0x0,0x8(%rsp)
  movsbl 0xc(%rsp),%ebp
  movsbl %r14b,%ebx
  movsbl %r15b,%r8d
  lea    0x20(%rsp),%r12
  je     L55
L138:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <average@plt>
  movss  %xmm0,0x4(%rsp)
L16:
  movzbl 0x1e(%rsp),%edx
  add    $0x1,%r15d
  movsbl %r15b,%r8d
  cmp    %r15b,%dl
  jle    L84
L55:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %r8d,0x8(%rsp)
  call   <average@plt>
  comiss 0x4(%rsp),%xmm0
  mov    0x8(%rsp),%r8d
  jbe    L16
  jmp    L138
  nopl   0x0(%rax)
L84:
  movb   $0x0,0x8(%rsp)
L38:
  movzbl 0x1d(%rsp),%eax
  add    $0x1,%r14d
  cmp    %r14b,%al
  jg     L13
  addb   $0x1,0xf(%rsp)
  movzbl 0xf(%rsp),%ebx
  cmp    %dl,%bl
  jl     L132
L122:
  addb   $0x1,0xc(%rsp)
  movzbl 0xc(%rsp),%ecx
  cmp    %al,%cl
  jl     L119
L27:
  lea    D22(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <fopen@plt>
  movss  0x4(%rsp),%xmm0
  lea    D58(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x4(%rsp)
  jmp    L27
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D50
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D22
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D58
type_guessed: string

tool: D50: r

tool: D39: INP.TXT

tool: D17: %hhd %hhd %d

tool: D1: %d

tool: D22: w

tool: D29: OUT.TXT

tool: D58: %f


assistant: ```c
int main() {
  FILE *f = fopen("INP.TXT", "r");
  char m, n, s, i, i0, j, j0, b = 1;
  int a[10][10];
  float r = 0;
  fscanf(f, "%hhd %hhd %d", &m, &n, &s);
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      fscanf(f, "%d", &a[i][j]);
  fclose(f);
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      for (i0 = i; i0 < m; i0++)
        for (j0 = j + divpp(s, i0 - i + 1) - 1; j0 < n; j0++)
          if (b || average(a, i, j, i0, j0) > r) {
            r = average(a, i, j, i0, j0);
            b = 0;
          }
  f = fopen("OUT.TXT", "w");
  fprintf(f, "%f\n", r);
  fclose(f);
  return 0;
}
```