user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x3d4000(%rsp),%r11
L144:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L144
  sub    $0x7d0,%rsp
  mov    %edi,-0x3d47c4(%rbp)
  mov    %rsi,-0x3d47d0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3d47a0(%rbp),%rax
  mov    $0x3d4790,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0x3d47a8(%rbp)
  movl   $0xffffffff,-0x3d47ac(%rbp)
  movl   $0x0,-0x3d47a4(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3d47b8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3d47b8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    %eax,-0x3d47b0(%rbp)
  mov    -0x3d47b0(%rbp),%eax
  mov    %eax,-0x3d47b4(%rbp)
L6:
  mov    -0x3d47b0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x3d47b4(%rbp),%eax
  cltq
  imul   $0x3ea,%rax,%rax
  add    %rax,%rdx
  mov    -0x3d47a8(%rbp),%eax
  mov    %eax,-0x3d47a0(%rbp,%rdx,4)
  addl   $0x1,-0x3d47a8(%rbp)
  mov    -0x3d47b4(%rbp),%eax
  cmp    -0x3d47b0(%rbp),%eax
  je     L22
  mov    -0x3d47b4(%rbp),%edx
  mov    -0x3d47b0(%rbp),%eax
  add    %eax,%edx
  mov    -0x3d47b8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L80
L22:
  mov    -0x3d47b0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x3d47b4(%rbp),%eax
  cltq
  imul   $0x3ea,%rax,%rax
  add    %rdx,%rax
  mov    -0x3d47a0(%rbp,%rax,4),%eax
  add    %eax,-0x3d47a4(%rbp)
L80:
  mov    -0x3d47b4(%rbp),%eax
  cmp    -0x3d47b0(%rbp),%eax
  je     L40
  mov    -0x3d47b4(%rbp),%eax
  cmp    -0x3d47b0(%rbp),%eax
  jge    L104
  mov    -0x3d47b4(%rbp),%edx
  mov    -0x3d47b0(%rbp),%eax
  add    %eax,%edx
  mov    -0x3d47b8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,%edx
  je     L40
L104:
  mov    -0x3d47b4(%rbp),%eax
  cmp    -0x3d47b0(%rbp),%eax
  jle    L37
  mov    -0x3d47b4(%rbp),%edx
  mov    -0x3d47b0(%rbp),%eax
  add    %eax,%edx
  mov    -0x3d47b8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L37
L40:
  mov    -0x3d47ac(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x3d47ac(%rbp)
L37:
  mov    -0x3d47ac(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L126
  mov    $0x2,%eax
  sub    -0x3d47ac(%rbp),%eax
  add    %eax,-0x3d47b4(%rbp)
  jmp    L149
L126:
  mov    $0x1,%eax
  sub    -0x3d47ac(%rbp),%eax
  add    %eax,-0x3d47b0(%rbp)
L149:
  mov    -0x3d47b8(%rbp),%edx
  mov    -0x3d47b8(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0x3d47a8(%rbp)
  jle    L6
  mov    -0x3d47b8(%rbp),%eax
  cmp    $0x64,%eax
  jg     L131
  movl   $0x1,-0x3d47b4(%rbp)
  jmp    L98
L59:
  movl   $0x1,-0x3d47b0(%rbp)
  jmp    L27
L9:
  mov    -0x3d47b0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x3d47b4(%rbp),%eax
  cltq
  imul   $0x3ea,%rax,%rax
  add    %rdx,%rax
  mov    -0x3d47a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x3d47b0(%rbp)
L27:
  mov    -0x3d47b8(%rbp),%eax
  cmp    %eax,-0x3d47b0(%rbp)
  jle    L9
  addl   $0x1,-0x3d47b4(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L98:
  mov    -0x3d47b8(%rbp),%eax
  cmp    %eax,-0x3d47b4(%rbp)
  jle    L59
L131:
  mov    -0x3d47a4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L160
  call   <__stack_chk_fail@plt>
L160:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D34
type: string
name: extract_symbolic_data
arguments: data_tag: D20
type: string

tool: D35: Enter value of n:

tool: D5: %d

tool: D34: %4d 

tool: D20: Sum of all diagonal elements is : %d


assistant: ```c
int main(int argc, char *argv[]) {
  int square[1002][1002] = {{0}};
  int i, j, direction, count, sum, n;
  count = 1;
  direction = -1;
  sum = 0;
  printf("Enter value of n:");
  scanf("%d", &n);
  i = j = (n / 2) + 1;
  do {
    square[i][j] = count;
    count++;
    if (i == j || (i + j) == (n + 1))
      sum += square[i][j];
    if (i == j || (i < j && i + j == (n + 2)) || (i > j && i + j == (n + 1)))
      direction = (direction + 1) % 4;
    if (direction & 1)
      i += (2 - direction);
    else
      j += (1 - direction);
  } while (count <= (n * n));
  if (n <= 100) {
    for (i = 1; i <= n; i++, printf("\n"))
      for (j = 1; j <= n; j++)
        printf("%4d ", square[i][j]);
  }
  printf("Sum of all diagonal elements is : %d\n", sum);
  return 0;
}
```