ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    $0xf4240,%ebx
  mov    D2(%rip),%rbp
  jmp    L41
L46:
  call   <binet@plt>
  movapd %xmm0,%xmm3
  movsd  %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm3,%xmm0
  ja     L28
  sub    $0x1,%ebx
  je     L48
L41:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D55(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  movq   %rbp,%xmm2
  andpd  %xmm1,%xmm2
  movsd  D0(%rip),%xmm4
  ucomisd %xmm2,%xmm4
  jbe    L46
  cvttsd2si %xmm1,%rax
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movapd %xmm2,%xmm0
  cmpnlesd %xmm1,%xmm0
  movsd  D51(%rip),%xmm5
  andpd  %xmm5,%xmm0
  subsd  %xmm0,%xmm2
  movq   %rbp,%xmm0
  andnpd %xmm1,%xmm0
  orpd   %xmm2,%xmm0
  jmp    L46
L28:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  movq   %xmm0,%rbx
L18:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L48:
  mov    $0x0,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  movq   %xmm0,%rbx
  pxor   %xmm0,%xmm0
  comisd (%rsp),%xmm0
  ja     L18
L22:
  movq   %rbx,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: byte[8]
name: read_data
arguments: data_tag: D55
type: f64
name: read_data
arguments: data_tag: D0
type: byte[8]
name: read_data
arguments: data_tag: D51
type: byte[8]
name: read_data
arguments: data_tag: D26
type: string

tool: {"D2": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: D55: 79

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D26: should return a nonnegative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  double x;
  double y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = floor(79.0 * rand_double());
    y = binet(x);
    if (y < 0) {
      printf("should return a nonnegative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should return a nonnegative number\n");
  }
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L37
  xchg   %ax,%ax
L33:
  sub    $0x1,%ebx
  je     L16
L37:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D11(%rip),%xmm0
  movsd  D13(%rip),%xmm2
  movsd  D1(%rip),%xmm4
  movapd %xmm0,%xmm1
  andpd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm4
  jbe    L32
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  movsd  D34(%rip),%xmm6
  andnpd %xmm0,%xmm2
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm3
  cmpnlesd %xmm0,%xmm3
  andpd  %xmm6,%xmm3
  subsd  %xmm3,%xmm1
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
L32:
  call   <binet@plt>
  pxor   %xmm5,%xmm5
  comisd %xmm0,%xmm5
  jbe    L33
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L16:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: f64
name: read_data
arguments: tag: D13
type_infered: byte[8]
name: read_data
arguments: tag: D1
type_infered: byte[8]
name: read_data
arguments: tag: D34
type_infered: byte[8]
name: read_data
arguments: tag: D29
type_infered: string

tool: D11: 79

tool: {"D13": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D29: should return a nonnegative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  double x;
  double y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = floor(79.0 * rand_double());
    y = binet(x);
    if (y < 0) {
      printf("should return a nonnegative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should return a nonnegative number\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L2
  xchg   %ax,%ax
L30:
  sub    $0x1,%ebx
  je     L10
L2:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D28(%rip),%xmm0
  movsd  D23(%rip),%xmm2
  movsd  D21(%rip),%xmm4
  movapd %xmm0,%xmm1
  andpd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm4
  jbe    L16
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  movsd  D38(%rip),%xmm6
  andnpd %xmm0,%xmm2
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm3
  cmpnlesd %xmm0,%xmm3
  andpd  %xmm6,%xmm3
  subsd  %xmm3,%xmm1
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
L16:
  call   <binet@plt>
  pxor   %xmm5,%xmm5
  comisd %xmm0,%xmm5
  jbe    L30
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L10:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type: f64
name: retrieve_data
arguments: label: D23
type: byte[8]
name: retrieve_data
arguments: label: D21
type: byte[8]
name: retrieve_data
arguments: label: D38
type: byte[8]
name: retrieve_data
arguments: label: D19
type: string

tool: D28: 79

tool: {"D23": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D19: should return a nonnegative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  double x;
  double y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = floor(79.0 * rand_double());
    y = binet(x);
    if (y < 0) {
      printf("should return a nonnegative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should return a nonnegative number\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mpfr_to_doubledouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_get_prec@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpfr_init2@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_get_prec@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpfr_init2@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpfr_set@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sollya_mpfr_get_d@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    D45(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <mpfr_set_d@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpfr_set@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_sub@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <sollya_mpfr_get_d@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    D45(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <mpfr_set_d@plt>
  mov    D45(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_add@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_clear@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpfr_clear@plt>
  nop
  leave
  ret
```

assistant: ```c
void mpfr_to_doubledouble(double *dh, double *dm, mpfr_t op) {
  mpfr_t rest, temp;
  mpfr_init2(rest, mpfr_get_prec(op));
  mpfr_init2(temp, mpfr_get_prec(op));
  mpfr_set(rest, op, GMP_RNDN);
  *dh = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dh, GMP_RNDN);
  mpfr_set(op, temp, GMP_RNDN);
  mpfr_sub(rest, rest, temp, GMP_RNDN);
  *dm = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dm, GMP_RNDN);
  mpfr_add(op, op, temp, GMP_RNDN);
  mpfr_clear(rest);
  mpfr_clear(temp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mpfr_to_doubledouble>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <mpfr_get_prec@plt>
  mov    %eax,%esi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <mpfr_init2@plt>
  mov    %ebx,%edi
  call   <mpfr_get_prec@plt>
  mov    %eax,%esi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <mpfr_init2@plt>
  mov    D2(%rip),%rbp
  mov    0x0(%rbp),%edx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <mpfr_set@plt>
  mov    0x0(%rbp),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  movsd  %xmm0,(%r15)
  mov    0x0(%rbp),%esi
  mov    %r12d,%edi
  call   <mpfr_set_d@plt>
  mov    0x0(%rbp),%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mpfr_set@plt>
  mov    0x0(%rbp),%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpfr_sub@plt>
  mov    0x0(%rbp),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  movsd  %xmm0,(%r14)
  mov    0x0(%rbp),%esi
  mov    %r12d,%edi
  call   <mpfr_set_d@plt>
  mov    0x0(%rbp),%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpfr_add@plt>
  mov    %r13d,%edi
  call   <mpfr_clear@plt>
  mov    %r12d,%edi
  call   <mpfr_clear@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mpfr_to_doubledouble(double *dh, double *dm, mpfr_t op) {
  mpfr_t rest, temp;
  mpfr_init2(rest, mpfr_get_prec(op));
  mpfr_init2(temp, mpfr_get_prec(op));
  mpfr_set(rest, op, GMP_RNDN);
  *dh = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dh, GMP_RNDN);
  mpfr_set(op, temp, GMP_RNDN);
  mpfr_sub(rest, rest, temp, GMP_RNDN);
  *dm = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dm, GMP_RNDN);
  mpfr_add(op, op, temp, GMP_RNDN);
  mpfr_clear(rest);
  mpfr_clear(temp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mpfr_to_doubledouble>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %edx,%edi
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpfr_get_prec@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <mpfr_init2@plt>
  mov    %ebp,%edi
  call   <mpfr_get_prec@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <mpfr_init2@plt>
  mov    D1(%rip),%rbx
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    (%rbx),%edx
  call   <mpfr_set@plt>
  mov    (%rbx),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  mov    (%rbx),%esi
  mov    %r12d,%edi
  movsd  %xmm0,(%r15)
  call   <mpfr_set_d@plt>
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpfr_set@plt>
  mov    (%rbx),%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpfr_sub@plt>
  mov    (%rbx),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  mov    (%rbx),%esi
  mov    %r12d,%edi
  movsd  %xmm0,(%r14)
  call   <mpfr_set_d@plt>
  mov    (%rbx),%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_add@plt>
  mov    %r13d,%edi
  call   <mpfr_clear@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <mpfr_clear@plt>
```

assistant: ```c
void mpfr_to_doubledouble(double *dh, double *dm, mpfr_t op) {
  mpfr_t rest, temp;
  mpfr_init2(rest, mpfr_get_prec(op));
  mpfr_init2(temp, mpfr_get_prec(op));
  mpfr_set(rest, op, GMP_RNDN);
  *dh = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dh, GMP_RNDN);
  mpfr_set(op, temp, GMP_RNDN);
  mpfr_sub(rest, rest, temp, GMP_RNDN);
  *dm = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dm, GMP_RNDN);
  mpfr_add(op, op, temp, GMP_RNDN);
  mpfr_clear(rest);
  mpfr_clear(temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpfr_to_doubledouble>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %edx,%edi
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <mpfr_get_prec@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <mpfr_init2@plt>
  mov    %ebp,%edi
  call   <mpfr_get_prec@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <mpfr_init2@plt>
  mov    D6(%rip),%rbx
  mov    %ebp,%esi
  mov    %r13d,%edi
  mov    (%rbx),%edx
  call   <mpfr_set@plt>
  mov    (%rbx),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  mov    (%rbx),%esi
  mov    %r12d,%edi
  movsd  %xmm0,(%r15)
  call   <mpfr_set_d@plt>
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpfr_set@plt>
  mov    (%rbx),%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpfr_sub@plt>
  mov    (%rbx),%esi
  mov    %r13d,%edi
  call   <sollya_mpfr_get_d@plt>
  mov    (%rbx),%esi
  mov    %r12d,%edi
  movsd  %xmm0,(%r14)
  call   <mpfr_set_d@plt>
  mov    (%rbx),%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpfr_add@plt>
  mov    %r13d,%edi
  call   <mpfr_clear@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <mpfr_clear@plt>
```

assistant: ```c
void mpfr_to_doubledouble(double *dh, double *dm, mpfr_t op) {
  mpfr_t rest, temp;
  mpfr_init2(rest, mpfr_get_prec(op));
  mpfr_init2(temp, mpfr_get_prec(op));
  mpfr_set(rest, op, GMP_RNDN);
  *dh = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dh, GMP_RNDN);
  mpfr_set(op, temp, GMP_RNDN);
  mpfr_sub(rest, rest, temp, GMP_RNDN);
  *dm = sollya_mpfr_get_d(rest, GMP_RNDN);
  mpfr_set_d(temp, *dm, GMP_RNDN);
  mpfr_add(op, op, temp, GMP_RNDN);
  mpfr_clear(rest);
  mpfr_clear(temp);
}
```
user: What is the c source code of the assembly code below?

```asm
<histlog2_account>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <histlog2_index@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void histlog2_account(__u32 *bucket, __u32 val, struct histlog2 *h) {
  int index = histlog2_index(val, h);
  bucket[index]++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<histlog2_account>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  call   <histlog2_index@plt>
  cltq
  addl   $0x1,(%rbx,%rax,4)
  pop    %rbx
  ret
```

assistant: ```c
void histlog2_account(__u32 *bucket, __u32 val, struct histlog2 *h) {
  int index = histlog2_index(val, h);
  bucket[index]++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<histlog2_account>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  call   <histlog2_index@plt>
  cltq
  addl   $0x1,(%rbx,%rax,4)
  pop    %rbx
  ret
```

assistant: ```c
void histlog2_account(__u32 *bucket, __u32 val, struct histlog2 *h) {
  int index = histlog2_index(val, h);
  bucket[index]++;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<histlog2_account>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %rdx,%rsi
  call   <histlog2_index@plt>
  cltq
  addl   $0x1,(%rbx,%rax,4)
  pop    %rbx
  ret
```

assistant: ```c
void histlog2_account(__u32 *bucket, __u32 val, struct histlog2 *h) {
  int index = histlog2_index(val, h);
  bucket[index]++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swapRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L6:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapRows(int n, double **mat, int r1, int r2) {
  int j = 0;
  double temp;
  for (j = 0; j < n; j++) {
    temp = mat[r1][j];
    mat[r1][j] = mat[r2][j];
    mat[r2][j] = temp;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swapRows>:
  endbr64
  test   %edi,%edi
  jle    L19
  movslq %edx,%rdx
  lea    (%rsi,%rdx,8),%r8
  movslq %ecx,%rcx
  lea    (%rsi,%rcx,8),%rcx
  mov    %edi,%edi
  shl    $0x3,%rdi
  mov    $0x0,%eax
L15:
  mov    %rax,%rdx
  add    (%r8),%rdx
  movsd  (%rdx),%xmm0
  mov    (%rcx),%rsi
  movsd  (%rsi,%rax,1),%xmm1
  movsd  %xmm1,(%rdx)
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L15
L19:
  ret
```

assistant: ```c
void swapRows(int n, double **mat, int r1, int r2) {
  int j = 0;
  double temp;
  for (j = 0; j < n; j++) {
    temp = mat[r1][j];
    mat[r1][j] = mat[r2][j];
    mat[r2][j] = temp;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swapRows>:
  endbr64
  test   %edi,%edi
  jle    L4
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movslq %edi,%rdi
  xor    %eax,%eax
  mov    (%rsi,%rdx,8),%r8
  mov    (%rsi,%rcx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L12:
  movsd  (%r8,%rax,8),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  movsd  %xmm1,(%r8,%rax,8)
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L12
L4:
  ret
```

assistant: ```c
void swapRows(int n, double **mat, int r1, int r2) {
  int j = 0;
  double temp;
  for (j = 0; j < n; j++) {
    temp = mat[r1][j];
    mat[r1][j] = mat[r2][j];
    mat[r2][j] = temp;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swapRows>:
  endbr64
  test   %edi,%edi
  jle    L41
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rsi,%rdx,8),%rdx
  mov    (%rsi,%rcx,8),%rcx
  lea    0xf(%rdx),%rax
  sub    %rcx,%rax
  cmp    $0x1e,%rax
  jbe    L6
  lea    -0x1(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L6
  mov    %edi,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L22:
  movupd (%rdx,%rax,1),%xmm0
  movupd (%rcx,%rax,1),%xmm2
  movups %xmm2,(%rdx,%rax,1)
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L22
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L41
  shl    $0x3,%rax
  add    %rax,%rdx
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
L6:
  mov    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L28:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  (%rcx,%rax,8),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L28
L41:
  ret
```

assistant: ```c
void swapRows(int n, double **mat, int r1, int r2) {
  int j = 0;
  double temp;
  for (j = 0; j < n; j++) {
    temp = mat[r1][j];
    mat[r1][j] = mat[r2][j];
    mat[r2][j] = temp;
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
L18:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_binary_rep@plt>
L1:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D17: Enter a real number in the range ]0, 1[


tool: D9: %lf

assistant: ```c
int main(void) {
  printf("Enter a real number in the range ]0, 1[\n");
  double n;
  while (scanf("%lf", &n) == 1) {
    print_binary_rep(n);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rbx
  jmp    L11
L23:
  movsd  (%rsp),%xmm0
  call   <print_binary_rep@plt>
L11:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L23
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D10: Enter a real number in the range ]0, 1[


tool: D1: %lf

assistant: ```c
int main(void) {
  printf("Enter a real number in the range ]0, 1[\n");
  double n;
  while (scanf("%lf", &n) == 1) {
    print_binary_rep(n);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  (%rsp),%xmm0
  call   <print_binary_rep@plt>
L27:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D2: Enter a real number in the range ]0, 1[


tool: D3: %lf

assistant: ```c
int main(void) {
  printf("Enter a real number in the range ]0, 1[\n");
  double n;
  while (scanf("%lf", &n) == 1) {
    print_binary_rep(n);
  }
  return 0;
}
```