ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<copyDynamicGrid>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  xor    %edi,%edi
  jmp    L47
  xchg   %ax,%ax
L31:
  movdqu (%rax),%xmm0
  add    $0x8,%rdi
  movups %xmm0,(%rdx)
  movdqu 0x10(%rax),%xmm1
  movups %xmm1,0x10(%rdx)
  movdqu 0x20(%rax),%xmm2
  movups %xmm2,0x20(%rdx)
  mov    0x30(%rax),%rcx
  mov    %rcx,0x30(%rdx)
  movzwl 0x38(%rax),%eax
  mov    %ax,0x38(%rdx)
  cmp    $0x278,%rdi
  je     L32
L47:
  mov    (%r8,%rdi,1),%rax
  mov    (%r9,%rdi,1),%rdx
  lea    0x2(%rax),%rsi
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  cmp    $0xc,%rcx
  ja     L31
  xor    %ecx,%ecx
L42:
  movzwl (%rax,%rcx,1),%esi
  mov    %si,(%rdx,%rcx,1)
  add    $0x2,%rcx
  cmp    $0x3a,%rcx
  jne    L42
  add    $0x8,%rdi
  cmp    $0x278,%rdi
  jne    L47
L32:
  ret
```

assistant: ```c
void copyDynamicGrid(short **to, short **from) {
  short i, j;
  for (i = 0; i < (100 - 20 - 1); i++) {
    for (j = 0; j < ((31 + 3) - 3 - 2); j++) {
      to[i][j] = from[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L72:
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L72
  jmp    L55
L17:
  subl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L17
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L58
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L58:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L11
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L2
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Quicksort>
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L59
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Quicksort>
L59:
  nop
  leave
  ret
```

assistant: ```c
void Quicksort(int a[], int l, int r) {
  int i, j, x, w;
  i = l;
  j = r;
  x = a[(l + r) / 2];
  do {
    while (a[i] < x)
      i = i + 1;
    while (x < a[j])
      j = j - 1;
    if (i <= j) {
      w = a[i];
      a[i] = a[j];
      a[j] = w;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (l < j)
    Quicksort(a, l, j);
  if (i < r)
    Quicksort(a, i, r);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Quicksort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%esi
  movslq %r14d,%rax
  lea    (%rdi,%rax,4),%r8
  mov    %r14d,%r9d
  lea    0x1(%r14),%r10d
  mov    %r12d,%edx
  jmp    L9
L59:
  mov    %ecx,0x0(%r13)
  mov    %r11d,(%rdi)
  mov    %r10d,%ebx
  sub    $0x1,%edx
  cmp    %edx,%r10d
  jg     L82
L75:
  add    $0x4,%r8
  add    $0x1,%r10d
  add    $0x1,%r9d
L9:
  mov    %r9d,%ebx
  mov    %r8,%r13
  mov    (%r8),%r11d
  cmp    %esi,%r11d
  jl     L75
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  mov    (%rdi),%ecx
  cmp    %ecx,%esi
  jge    L62
  lea    -0x4(%rbp,%rax,4),%rax
L13:
  sub    $0x1,%edx
  mov    %rax,%rdi
  sub    $0x4,%rax
  mov    0x4(%rax),%ecx
  cmp    %esi,%ecx
  jg     L13
L62:
  cmp    %edx,%ebx
  jle    L59
L82:
  cmp    %edx,%r14d
  jl     L35
L28:
  cmp    %ebx,%r12d
  jg     L81
L63:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <Quicksort>
  jmp    L28
L81:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Quicksort>
  jmp    L63
```

assistant: ```c
void Quicksort(int a[], int l, int r) {
  int i, j, x, w;
  i = l;
  j = r;
  x = a[(l + r) / 2];
  do {
    while (a[i] < x)
      i = i + 1;
    while (x < a[j])
      j = j - 1;
    if (i <= j) {
      w = a[i];
      a[i] = a[j];
      a[j] = w;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (l < j)
    Quicksort(a, l, j);
  if (i < r)
    Quicksort(a, i, r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Quicksort>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
L93:
  lea    (%r14,%rbp,1),%edx
  mov    %r14d,%r8d
  lea    0x1(%r14),%r10d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  mov    %ebp,%edx
  sar    %eax
  cltq
  mov    0x0(%r13,%rax,4),%edi
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,4),%r9
  mov    %r12,%rax
L84:
  mov    (%r9),%r11d
  lea    0x0(%r13,%rax,4),%rsi
  mov    %r8d,%ebx
  mov    (%rsi),%ecx
  cmp    %edi,%r11d
  jl     L81
  cmp    %ecx,%edi
  jge    L7
  lea    -0x4(%r13,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L87:
  mov    %rax,%rsi
  mov    (%rax),%ecx
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%ecx
  jg     L87
L7:
  cmp    %r8d,%edx
  jge    L86
L14:
  cmp    %edx,%r14d
  jl     L89
L75:
  cmp    %ebx,%ebp
  jle    L19
  mov    %ebx,%r14d
  jmp    L93
  nopl   0x0(%rax,%rax,1)
L86:
  sub    $0x1,%edx
  mov    %ecx,(%r9)
  mov    %r10d,%ebx
  mov    %r11d,(%rsi)
  cmp    %edx,%r10d
  jg     L14
  movslq %edx,%rax
L81:
  add    $0x4,%r9
  add    $0x1,%r10d
  add    $0x1,%r8d
  jmp    L84
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <Quicksort>
  jmp    L75
```

assistant: ```c
void Quicksort(int a[], int l, int r) {
  int i, j, x, w;
  i = l;
  j = r;
  x = a[(l + r) / 2];
  do {
    while (a[i] < x)
      i = i + 1;
    while (x < a[j])
      j = j - 1;
    if (i <= j) {
      w = a[i];
      a[i] = a[j];
      a[j] = w;
      i = i + 1;
      j = j - 1;
    }
  } while (i <= j);
  if (l < j)
    Quicksort(a, l, j);
  if (i < r)
    Quicksort(a, i, r);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remover_elemento>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L12:
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L12
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L0
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void remover_elemento(int *n, int x, int *v) {
  int i = 0, j = 0, temp;
  while (j < *n) {
    while (v[j] == x)
      j++;
    temp = v[i];
    v[i] = v[j];
    v[j] = temp;
    i++;
    j++;
  }
  *n = i - 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<remover_elemento>:
  endbr64
  mov    %rdi,%r11
  mov    $0x1,%r10d
  mov    $0x0,%ecx
  mov    $0x0,%eax
  cmpl   $0x0,(%rdi)
  jg     L39
L2:
  sub    $0x1,%eax
  mov    %eax,(%r11)
  ret
L8:
  add    $0x1,%ecx
  mov    %rax,%r8
  add    $0x4,%rax
  mov    -0x4(%rax),%edi
  cmp    %r9d,%edi
  je     L8
L30:
  mov    -0x4(%rdx,%r10,4),%eax
  mov    %edi,-0x4(%rdx,%r10,4)
  mov    %eax,(%r8)
  mov    %r10d,%eax
  add    $0x1,%ecx
  add    $0x1,%r10
  cmp    %ecx,(%r11)
  jle    L2
L39:
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%r8
  mov    (%r8),%r9d
  lea    0x4(%rdx,%rax,1),%rax
  mov    %r9d,%edi
  cmp    %r9d,%esi
  je     L8
  jmp    L30
```

assistant: ```c
void remover_elemento(int *n, int x, int *v) {
  int i = 0, j = 0, temp;
  while (j < *n) {
    while (v[j] == x)
      j++;
    temp = v[i];
    v[i] = v[j];
    v[j] = temp;
    i++;
    j++;
  }
  *n = i - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remover_elemento>:
  endbr64
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%r11
  mov    $0xffffffff,%ebx
  test   %eax,%eax
  jle    L17
  xor    %r10d,%r10d
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L25:
  movslq %ecx,%rax
  mov    %r10d,%ebx
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%r8
  lea    0x4(%rdx,%rax,1),%rax
  mov    (%r8),%r9d
  mov    %r9d,%edi
  cmp    %r9d,%esi
  jne    L31
  xchg   %ax,%ax
L13:
  mov    %rax,%r8
  mov    (%rax),%edi
  add    $0x4,%rax
  add    $0x1,%ecx
  cmp    %r9d,%edi
  je     L13
L31:
  mov    (%rdx,%r10,4),%eax
  add    $0x1,%ecx
  mov    %edi,(%rdx,%r10,4)
  add    $0x1,%r10
  mov    %eax,(%r8)
  cmp    %ecx,(%r11)
  jg     L25
L17:
  mov    %ebx,(%r11)
  pop    %rbx
  ret
```

assistant: ```c
void remover_elemento(int *n, int x, int *v) {
  int i = 0, j = 0, temp;
  while (j < *n) {
    while (v[j] == x)
      j++;
    temp = v[i];
    v[i] = v[j];
    v[j] = temp;
    i++;
    j++;
  }
  *n = i - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<remover_elemento>:
  endbr64
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%r11
  mov    $0xffffffff,%ebx
  test   %eax,%eax
  jle    L32
  xor    %r10d,%r10d
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L6:
  movslq %ecx,%rax
  mov    %r10d,%ebx
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%r8
  lea    0x4(%rdx,%rax,1),%rax
  mov    (%r8),%r9d
  mov    %r9d,%edi
  cmp    %r9d,%esi
  jne    L4
  xchg   %ax,%ax
L27:
  mov    %rax,%r8
  mov    (%rax),%edi
  add    $0x4,%rax
  add    $0x1,%ecx
  cmp    %r9d,%edi
  je     L27
L4:
  mov    (%rdx,%r10,4),%eax
  add    $0x1,%ecx
  mov    %edi,(%rdx,%r10,4)
  add    $0x1,%r10
  mov    %eax,(%r8)
  cmp    %ecx,(%r11)
  jg     L6
L32:
  mov    %ebx,(%r11)
  pop    %rbx
  ret
```

assistant: ```c
void remover_elemento(int *n, int x, int *v) {
  int i = 0, j = 0, temp;
  while (j < *n) {
    while (v[j] == x)
      j++;
    temp = v[i];
    v[i] = v[j];
    v[j] = temp;
    i++;
    j++;
  }
  *n = i - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<G_NewString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <BG_Alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L66
L48:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L23
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L23
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6e,%al
  jne    L31
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0xa,(%rax)
  jmp    L17
L31:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x5c,(%rax)
  jmp    L17
L23:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
L17:
  addl   $0x1,-0x18(%rbp)
L66:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L48
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = BG_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<G_NewString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <BG_Alloc@plt>
  test   %r12d,%r12d
  jle    L41
  lea    0x1(%rax),%rsi
  mov    $0x0,%edx
  mov    $0x5c,%r9d
  mov    $0xa,%r8d
  jmp    L22
L34:
  mov    %edx,%ecx
L10:
  mov    %dil,-0x1(%rsi)
  lea    0x1(%rcx),%edx
  add    $0x1,%rsi
  cmp    %ecx,%ebx
  jle    L41
L22:
  movslq %edx,%rcx
  movzbl 0x0(%rbp,%rcx,1),%edi
  cmp    %edx,%ebx
  jle    L34
  cmp    $0x5c,%dil
  jne    L34
  lea    0x1(%rdx),%ecx
  movslq %ecx,%rdx
  cmpb   $0x6e,0x0(%rbp,%rdx,1)
  mov    %r8d,%edi
  cmovne %r9d,%edi
  jmp    L10
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = BG_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<G_NewString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <BG_Alloc@plt>
  test   %r12d,%r12d
  jle    L44
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0x5c,%r9d
  mov    $0xa,%r8d
  nopl   0x0(%rax)
L40:
  movslq %edx,%rcx
  add    $0x1,%rsi
  movzbl 0x0(%rbp,%rcx,1),%edi
  cmp    %edx,%ebx
  jle    L10
  cmp    $0x5c,%dil
  je     L39
L10:
  mov    %edx,%ecx
L31:
  mov    %dil,-0x1(%rsi)
  lea    0x1(%rcx),%edx
  cmp    %ecx,%ebx
  jg     L40
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  lea    0x1(%rdx),%ecx
  mov    %r8d,%edi
  movslq %ecx,%rdx
  cmpb   $0x6e,0x0(%rbp,%rdx,1)
  cmovne %r9d,%edi
  jmp    L31
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = BG_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: What is the c source code of the assembly code below:

```asm
<G_NewString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <BG_Alloc@plt>
  test   %r12d,%r12d
  jle    L46
  mov    %rax,%rsi
  xor    %edx,%edx
  mov    $0xa,%r9d
  mov    $0x5c,%r8d
  nopl   0x0(%rax)
L36:
  movslq %edx,%rcx
  add    $0x1,%rsi
  movzbl 0x0(%rbp,%rcx,1),%edi
  cmp    %edx,%ebx
  jle    L43
  cmp    $0x5c,%dil
  je     L13
L43:
  mov    %edx,%ecx
L23:
  mov    %dil,-0x1(%rsi)
  lea    0x1(%rcx),%edx
  cmp    %ecx,%ebx
  jg     L36
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    0x1(%rdx),%ecx
  mov    %r8d,%edi
  movslq %ecx,%rdx
  cmpb   $0x6e,0x0(%rbp,%rdx,1)
  cmove  %r9d,%edi
  jmp    L23
```

assistant: ```c
char *G_NewString(const char *string) {
  char *newb, *new_p;
  int i, l;
  l = strlen(string) + 1;
  newb = BG_Alloc(l);
  new_p = newb;
  for (i = 0; i < l; i++) {
    if (string[i] == '\\' && i < l - 1) {
      i++;
      if (string[i] == 'n') {
        *new_p++ = '\n';
      } else {
        *new_p++ = '\\';
      }
    } else {
      *new_p++ = string[i];
    }
  }
  return newb;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<string_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D65(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D63(%rip),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <create_dlink@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  mov    $0x0,%eax
  call   <dlink_is_empty@plt>
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dlink_size@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dlink_size@plt>
  mov    %eax,-0x3c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L21
L0:
  mov    -0x40(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dlink_get@plt>
  cltq
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x40(%rbp)
L21:
  mov    -0x40(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  call   <destroy_dlink@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D42
type_guessed: string
name: read_data
arguments: data_tag: D28
type_guessed: string
name: read_data
arguments: data_tag: D65
type_guessed: string
name: read_data
arguments: data_tag: D63
type_guessed: string
name: read_data
arguments: data_tag: D61
type_guessed: string
name: read_data
arguments: data_tag: D40
type_guessed: string
name: read_data
arguments: data_tag: D44
type_guessed: string
name: read_data
arguments: data_tag: D58
type_guessed: string

tool: D15: ten

tool: D42: twenty

tool: D28: thirty

tool: D65: forty

tool: D63: string_test

tool: D61: 
----%s----


tool: D40: dlink_is_empty() = %d


tool: D44: dlink_size() = %d


tool: D58: dlink_get(%d) = %s


assistant: ```c
void string_test() {
  char *sarr[4] = {"ten", "twenty", "thirty", "forty"};
  printf("\n----%s----\n", __FUNCTION__);
  create_dlink();
  dlink_insert(0, sarr[0]);
  dlink_insert(0, sarr[1]);
  dlink_insert(0, sarr[2]);
  printf("dlink_is_empty() = %d\n", dlink_is_empty());
  printf("dlink_size() = %d\n", dlink_size());
  int i;
  char *p;
  int sz = dlink_size();
  for (i = 0; i < sz; i++) {
    p = (char *)dlink_get(i);
    printf("dlink_get(%d) = %s\n", i, p);
  }
  destroy_dlink();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D65(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <create_dlink@plt>
  lea    D59(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  lea    D73(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  lea    D49(%rip),%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <dlink_insert@plt>
  mov    $0x0,%eax
  call   <dlink_is_empty@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dlink_size@plt>
  mov    %eax,%esi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <dlink_size@plt>
  test   %eax,%eax
  jle    L6
  mov    %eax,%ebp
  mov    $0x0,%ebx
  lea    D12(%rip),%r12
L17:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <dlink_get@plt>
  movslq %eax,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L17
L6:
  mov    $0x0,%eax
  call   <destroy_dlink@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D65
type_guessed: string
name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D59
type_guessed: string
name: retrieve_data
arguments: label: D73
type_guessed: string
name: retrieve_data
arguments: label: D49
type_guessed: string
name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D69
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string

tool: D65: string_test

tool: D35: 
----%s----


tool: D59: ten

tool: D73: twenty

tool: D49: thirty

tool: D11: dlink_is_empty() = %d


tool: D69: dlink_size() = %d


tool: D12: dlink_get(%d) = %s


assistant: ```c
void string_test() {
  char *sarr[4] = {"ten", "twenty", "thirty", "forty"};
  printf("\n----%s----\n", __FUNCTION__);
  create_dlink();
  dlink_insert(0, sarr[0]);
  dlink_insert(0, sarr[1]);
  dlink_insert(0, sarr[2]);
  printf("dlink_is_empty() = %d\n", dlink_is_empty());
  printf("dlink_size() = %d\n", dlink_size());
  int i;
  char *p;
  int sz = dlink_size();
  for (i = 0; i < sz; i++) {
    p = (char *)dlink_get(i);
    printf("dlink_get(%d) = %s\n", i, p);
  }
  destroy_dlink();
}
```