ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<ptrace_read_regs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <start_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  mov    %r13,(%rsp)
  shl    $0x3,%ebx
  mov    %ebx,0x8(%rsp)
  mov    %rsp,%rcx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <ptrace@plt>
  test   %rax,%rax
  je     L11
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %ebp,%edi
  call   <stop_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  mov    $0x0,%eax
  jmp    L26
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ptrace_read_regs(pid_t child, unsigned long type, unsigned long regs[], int n) {
  struct iovec iov;
  long ret;
  FAIL_IF(start_trace(child));
  iov.iov_base = regs;
  iov.iov_len = n * sizeof(unsigned long);
  ret = ptrace(PTRACE_GETREGSET, child, type, &iov);
  if (ret)
    return ret;
  FAIL_IF(stop_trace(child));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ptrace_read_regs>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  shl    $0x3,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <start_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  mov    %rsp,%rcx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    D8(%rip),%rax
  mov    %r13,(%rsp)
  mov    %ebx,0x8(%rsp)
  mov    (%rax),%edi
  call   <ptrace@plt>
  test   %rax,%rax
  jne    L0
  mov    %ebp,%edi
  call   <stop_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  xor    %eax,%eax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ptrace_read_regs(pid_t child, unsigned long type, unsigned long regs[], int n) {
  struct iovec iov;
  long ret;
  FAIL_IF(start_trace(child));
  iov.iov_base = regs;
  iov.iov_len = n * sizeof(unsigned long);
  ret = ptrace(PTRACE_GETREGSET, child, type, &iov);
  if (ret)
    return ret;
  FAIL_IF(stop_trace(child));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptrace_read_regs>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  shl    $0x3,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <start_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  mov    %rsp,%rcx
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    D9(%rip),%rax
  mov    %r13,(%rsp)
  mov    %ebx,0x8(%rsp)
  mov    (%rax),%edi
  call   <ptrace@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebp,%edi
  call   <stop_trace@plt>
  mov    %eax,%edi
  call   <FAIL_IF@plt>
  xor    %eax,%eax
L5:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ptrace_read_regs(pid_t child, unsigned long type, unsigned long regs[], int n) {
  struct iovec iov;
  long ret;
  FAIL_IF(start_trace(child));
  iov.iov_base = regs;
  iov.iov_len = n * sizeof(unsigned long);
  ret = ptrace(PTRACE_GETREGSET, child, type, &iov);
  if (ret)
    return ret;
  FAIL_IF(stop_trace(child));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D17: Usage: tst_usleep interval[s|ms|us]



tool: D13:        If no unit is specified the interval is in seconds


assistant: ```c
void print_help(void) {
  printf("Usage: tst_usleep interval[s|ms|us]\n\n");
  printf("       If no unit is specified the interval is in seconds\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D2: Usage: tst_usleep interval[s|ms|us]



tool: D11:        If no unit is specified the interval is in seconds


assistant: ```c
void print_help(void) {
  printf("Usage: tst_usleep interval[s|ms|us]\n\n");
  printf("       If no unit is specified the interval is in seconds\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D5: Usage: tst_usleep interval[s|ms|us]



tool: D2:        If no unit is specified the interval is in seconds


assistant: ```c
void print_help(void) {
  printf("Usage: tst_usleep interval[s|ms|us]\n\n");
  printf("       If no unit is specified the interval is in seconds\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string

tool: D1: Usage: tst_usleep interval[s|ms|us]



tool: D17:        If no unit is specified the interval is in seconds


assistant: ```c
void print_help(void) {
  printf("Usage: tst_usleep interval[s|ms|us]\n\n");
  printf("       If no unit is specified the interval is in seconds\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<white2null>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r9d
  movb   $0x0,(%rdi)
  cmp    $0x1,%esi
  jle    L149
  lea    0x1(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x2(%rdi,%rdx,1),%rsi
  mov    %rax,%rdx
  mov    $0x0,%edi
  mov    $0x0,%ebx
  jmp    L87
L79:
  cmp    $0x1,%edi
  setne  %cl
  movzbl %cl,%ecx
  je     L5
  mov    %ecx,%edi
  jmp    L172
L40:
  movb   $0x0,(%r8)
L172:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L120
L87:
  mov    %rdx,%r8
  movzbl (%rdx),%ecx
  cmp    $0x22,%cl
  je     L79
  test   %edi,%edi
  jne    L172
  lea    -0x9(%rcx),%r11d
  cmp    $0x1,%r11b
  jbe    L40
  cmp    $0x20,%cl
  je     L40
  mov    %edi,%ecx
L5:
  mov    %ecx,%edi
  cmpb   $0x0,-0x1(%r8)
  jne    L172
  add    $0x1,%ebx
  jmp    L172
L120:
  mov    $0x0,%ecx
  mov    $0x0,%edi
  mov    $0x1,%r8d
  jmp    L152
L90:
  cmp    $0x1,%ecx
  jne    L63
  mov    %edi,%ecx
L111:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L160
L152:
  mov    %rax,%rdx
  cmpb   $0x22,(%rax)
  je     L90
  test   %ecx,%ecx
  je     L111
L63:
  movzbl 0x1(%rdx),%ecx
  cmp    $0x22,%cl
  je     L107
  mov    %cl,(%rdx)
  mov    %r8d,%ecx
  jmp    L111
L107:
  movb   $0x0,(%rdx)
  movb   $0x0,0x1(%rdx)
  mov    %edi,%ecx
  jmp    L111
L149:
  mov    $0x0,%ebx
L160:
  movslq %r9d,%r9
  movb   $0x0,(%r10,%r9,1)
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int white2null(char *str, int len) {
  int i;
  int count;
  int inquote = (0);
  str[0] = '\0';
  for (i = 1, count = 0; i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (!inquote) {
      if (((str[i]) == ' ' || (str[i]) == '\t' || (str[i]) == '\n')) {
        str[i] = '\0';
      } else if (!str[i - 1]) {
        count++;
      }
    }
  }
  for (i = 1, inquote = (0); i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (inquote) {
      if (str[i + 1] != '"') {
        str[i] = str[i + 1];
      } else {
        str[i] = '\0';
        str[i + 1] = '\0';
        inquote = (0);
      }
    }
  }
  str[len] = '\0';
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<white2null>:
  endbr64
  movb   $0x0,(%rdi)
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L152
  lea    0x1(%rdi),%rdx
  lea    -0x2(%rsi),%eax
  xor    %r8d,%r8d
  xor    %r11d,%r11d
  lea    0x2(%rdi,%rax,1),%rdi
  mov    %rdx,%rax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L186:
  test   %r8d,%r8d
  jne    L95
  lea    -0x9(%rcx),%r10d
  cmp    $0x1,%r10b
  jbe    L112
  cmp    $0x20,%cl
  jne    L159
L112:
  movb   $0x0,(%rax)
L95:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L81
L8:
  movzbl (%rax),%ecx
  cmp    $0x22,%cl
  jne    L186
  mov    %r8d,%ecx
  xor    $0x1,%ecx
  cmp    $0x1,%r8d
  je     L195
  mov    %ecx,%r8d
  jmp    L95
  nopl   0x0(%rax)
L199:
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  je     L182
L81:
  cmpb   $0x22,(%rdx)
  mov    %rdx,%rcx
  je     L36
L20:
  lea    0x1(%rdx),%rax
  cmp    %rdi,%rax
  je     L182
L131:
  cmpb   $0x22,0x1(%rdx)
  mov    %rax,%rcx
  jne    L199
L181:
  movzbl 0x1(%rcx),%edx
  cmp    $0x22,%dl
  je     L170
  add    $0x1,%rax
  mov    %dl,(%rcx)
  cmp    %rdi,%rax
  je     L182
  cmpb   $0x22,(%rax)
  mov    %rax,%rcx
  jne    L181
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  cmp    %rdi,%rax
  jne    L131
L182:
  movslq %esi,%rsi
  mov    %r11d,%eax
  movb   $0x0,(%r9,%rsi,1)
  ret
  nop
L170:
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rcx)
  movb   $0x0,0x1(%rcx)
  cmp    %rdi,%rdx
  je     L182
  cmpb   $0x22,0x1(%rax)
  mov    %rdx,%rcx
  jne    L20
L36:
  mov    %rcx,%rax
  jmp    L181
L159:
  xor    %ecx,%ecx
L195:
  cmpb   $0x1,-0x1(%rax)
  mov    %ecx,%r8d
  adc    $0x0,%r11d
  jmp    L95
L152:
  xor    %r11d,%r11d
  movslq %esi,%rsi
  movb   $0x0,(%r9,%rsi,1)
  mov    %r11d,%eax
  ret
```

assistant: ```c
int white2null(char *str, int len) {
  int i;
  int count;
  int inquote = (0);
  str[0] = '\0';
  for (i = 1, count = 0; i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (!inquote) {
      if (((str[i]) == ' ' || (str[i]) == '\t' || (str[i]) == '\n')) {
        str[i] = '\0';
      } else if (!str[i - 1]) {
        count++;
      }
    }
  }
  for (i = 1, inquote = (0); i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (inquote) {
      if (str[i + 1] != '"') {
        str[i] = str[i + 1];
      } else {
        str[i] = '\0';
        str[i + 1] = '\0';
        inquote = (0);
      }
    }
  }
  str[len] = '\0';
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<white2null>:
  endbr64
  movb   $0x0,(%rdi)
  mov    %rdi,%r9
  cmp    $0x1,%esi
  jle    L209
  lea    0x1(%rdi),%rdx
  lea    -0x2(%rsi),%eax
  xor    %r8d,%r8d
  xor    %r11d,%r11d
  lea    0x2(%rdi,%rax,1),%rdi
  mov    %rdx,%rax
  jmp    L107
  nopw   0x0(%rax,%rax,1)
L105:
  test   %r8d,%r8d
  jne    L203
  lea    -0x9(%rcx),%r10d
  cmp    $0x1,%r10b
  jbe    L108
  cmp    $0x20,%cl
  jne    L82
L108:
  movb   $0x0,(%rax)
L203:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L115
L107:
  movzbl (%rax),%ecx
  cmp    $0x22,%cl
  jne    L105
  mov    %r8d,%ecx
  xor    $0x1,%ecx
  cmp    $0x1,%r8d
  je     L139
  mov    %ecx,%r8d
  jmp    L203
  nopl   0x0(%rax)
L200:
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  je     L50
L115:
  cmpb   $0x22,(%rdx)
  mov    %rdx,%rcx
  je     L58
L161:
  lea    0x1(%rdx),%rax
  cmp    %rdi,%rax
  je     L50
L27:
  cmpb   $0x22,0x1(%rdx)
  mov    %rax,%rcx
  jne    L200
L123:
  movzbl 0x1(%rcx),%edx
  cmp    $0x22,%dl
  je     L194
  add    $0x1,%rax
  mov    %dl,(%rcx)
  cmp    %rdi,%rax
  je     L50
  cmpb   $0x22,(%rax)
  mov    %rax,%rcx
  jne    L123
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  cmp    %rdi,%rax
  jne    L27
L50:
  movslq %esi,%rsi
  mov    %r11d,%eax
  movb   $0x0,(%r9,%rsi,1)
  ret
  nop
L194:
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rcx)
  movb   $0x0,0x1(%rcx)
  cmp    %rdi,%rdx
  je     L50
  cmpb   $0x22,0x1(%rax)
  mov    %rdx,%rcx
  jne    L161
L58:
  mov    %rcx,%rax
  jmp    L123
L82:
  xor    %ecx,%ecx
L139:
  cmpb   $0x1,-0x1(%rax)
  mov    %ecx,%r8d
  adc    $0x0,%r11d
  jmp    L203
L209:
  xor    %r11d,%r11d
  movslq %esi,%rsi
  movb   $0x0,(%r9,%rsi,1)
  mov    %r11d,%eax
  ret
```

assistant: ```c
int white2null(char *str, int len) {
  int i;
  int count;
  int inquote = (0);
  str[0] = '\0';
  for (i = 1, count = 0; i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (!inquote) {
      if (((str[i]) == ' ' || (str[i]) == '\t' || (str[i]) == '\n')) {
        str[i] = '\0';
      } else if (!str[i - 1]) {
        count++;
      }
    }
  }
  for (i = 1, inquote = (0); i < len; i++) {
    if (str[i] == '"')
      inquote = (inquote == (1)) ? (0) : (1);
    if (inquote) {
      if (str[i + 1] != '"') {
        str[i] = str[i + 1];
      } else {
        str[i] = '\0';
        str[i + 1] = '\0';
        inquote = (0);
      }
    }
  }
  str[len] = '\0';
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<QSlog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <QSlogv@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void QSlog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  QSlogv(format, args);
  va_end(args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<QSlog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <QSlogv@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void QSlog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  QSlogv(format, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<QSlog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <QSlogv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void QSlog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  QSlogv(format, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QSlog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <QSlogv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void QSlog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  QSlogv(format, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_initial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L60:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L12
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L12
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  sub    $0x30,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  jmp    L23
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
L23:
  addl   $0x1,-0x4(%rbp)
L43:
  cmpl   $0x8,-0x4(%rbp)
  jle    L60
  addl   $0x1,-0x8(%rbp)
L44:
  cmpl   $0x8,-0x8(%rbp)
  jle    L8
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_initial(char **argv, int sudoku[9][9]) {
  int i;
  int j;
  i = 0;
  while (i < 9) {
    j = 0;
    while (j < 9) {
      if (argv[i + 1][j] >= 48 && argv[i + 1][j] <= 57)
        sudoku[i][j] = argv[i + 1][j] - 48;
      else
        sudoku[i][j] = 0;
      j++;
    }
    i++;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_initial>:
  endbr64
  add    $0x8,%rdi
  lea    0x144(%rsi),%r10
  mov    $0x0,%r9d
L9:
  mov    %rsi,%r8
  mov    $0x0,%edx
L18:
  mov    (%rdi),%rax
  movzbl (%rax,%rdx,1),%eax
  lea    -0x30(%rax),%ecx
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0xa,%cl
  cmovae %r9d,%eax
  mov    %eax,(%r8,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x9,%rdx
  jne    L18
  add    $0x24,%rsi
  add    $0x8,%rdi
  cmp    %r10,%rsi
  jne    L9
  ret
```

assistant: ```c
void ft_initial(char **argv, int sudoku[9][9]) {
  int i;
  int j;
  i = 0;
  while (i < 9) {
    j = 0;
    while (j < 9) {
      if (argv[i + 1][j] >= 48 && argv[i + 1][j] <= 57)
        sudoku[i][j] = argv[i + 1][j] - 48;
      else
        sudoku[i][j] = 0;
      j++;
    }
    i++;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_initial>:
  endbr64
  lea    0x8(%rdi),%r9
  lea    0x144(%rsi),%r10
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%r9),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L14:
  movzbl (%rdi,%rax,1),%edx
  sub    $0x30,%edx
  cmp    $0xa,%dl
  movsbl %dl,%ecx
  cmovae %r8d,%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    $0x9,%rax
  jne    L14
  add    $0x24,%rsi
  add    $0x8,%r9
  cmp    %rsi,%r10
  jne    L2
  ret
```

assistant: ```c
void ft_initial(char **argv, int sudoku[9][9]) {
  int i;
  int j;
  i = 0;
  while (i < 9) {
    j = 0;
    while (j < 9) {
      if (argv[i + 1][j] >= 48 && argv[i + 1][j] <= 57)
        sudoku[i][j] = argv[i + 1][j] - 48;
      else
        sudoku[i][j] = 0;
      j++;
    }
    i++;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_initial>:
  endbr64
  add    $0x8,%rdi
  mov    %rsi,%rax
  lea    0x144(%rsi),%r8
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L10:
  mov    (%rdi),%rdx
  movzbl (%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,(%rax)
  movzbl 0x1(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x4(%rax)
  movzbl 0x2(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x8(%rax)
  movzbl 0x3(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0xc(%rax)
  movzbl 0x4(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x10(%rax)
  movzbl 0x5(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x14(%rax)
  movzbl 0x6(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x18(%rax)
  movzbl 0x7(%rdx),%esi
  sub    $0x30,%esi
  movsbl %sil,%r9d
  cmp    $0xa,%sil
  mov    %r9d,%esi
  cmovae %ecx,%esi
  mov    %esi,0x1c(%rax)
  movzbl 0x8(%rdx),%edx
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L26
  movsbl %dl,%edx
  add    $0x24,%rax
  add    $0x8,%rdi
  mov    %edx,-0x4(%rax)
  cmp    %rax,%r8
  jne    L10
  ret
  nopl   (%rax)
L26:
  movl   $0x0,0x20(%rax)
  add    $0x24,%rax
  add    $0x8,%rdi
  cmp    %r8,%rax
  jne    L10
  ret
```

assistant: ```c
void ft_initial(char **argv, int sudoku[9][9]) {
  int i;
  int j;
  i = 0;
  while (i < 9) {
    j = 0;
    while (j < 9) {
      if (argv[i + 1][j] >= 48 && argv[i + 1][j] <= 57)
        sudoku[i][j] = argv[i + 1][j] - 48;
      else
        sudoku[i][j] = 0;
      j++;
    }
    i++;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate_key_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fs_write@plt>
  cmp    %eax,-0x2c(%rbp)
  je     L17
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L17:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string

tool: D14: ./key

tool: D2: %li

tool: D27: 
error writing key file


assistant: ```c
void generate_key_file(long success_key) {
  char *path = "./key";
  char key[20];
  int length;
  length = sprintf(key, "%li", success_key);
  if (fs_write(path, (unsigned char *)key, length) != length) {
    printf("\nerror writing key file\n");
    exit(-1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generate_key_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <fs_write@plt>
  cmp    %ebx,%eax
  jne    L0
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L27
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D6: %li

tool: D18: ./key

tool: D14: 
error writing key file


assistant: ```c
void generate_key_file(long success_key) {
  char *path = "./key";
  char key[20];
  int length;
  length = sprintf(key, "%li", success_key);
  if (fs_write(path, (unsigned char *)key, length) != length) {
    printf("\nerror writing key file\n");
    exit(-1);
  }
}
```