ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<servo_initialize>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %edi,%esi
  xor    %edi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  call   <set_servo_position@plt>
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <set_servo_position@plt>
  mov    %r12d,%esi
  mov    $0x2,%edi
  call   <set_servo_position@plt>
  mov    %ebp,%esi
  mov    $0x3,%edi
  call   <set_servo_position@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1060 <enable_servos@plt>
```

assistant: ```c
void servo_initialize(int port0_position, int port1_position, int port2_position, int port3_position) {
  set_servo_position(0, port0_position);
  set_servo_position(1, port1_position);
  set_servo_position(2, port2_position);
  set_servo_position(3, port3_position);
  enable_servos();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<servo_initialize>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %edi,%esi
  xor    %edi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  call   <set_servo_position@plt>
  mov    %r13d,%esi
  mov    $0x1,%edi
  call   <set_servo_position@plt>
  mov    %r12d,%esi
  mov    $0x2,%edi
  call   <set_servo_position@plt>
  mov    %ebp,%esi
  mov    $0x3,%edi
  call   <set_servo_position@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1060 <enable_servos@plt>
```

assistant: ```c
void servo_initialize(int port0_position, int port1_position, int port2_position, int port3_position) {
  set_servo_position(0, port0_position);
  set_servo_position(1, port1_position);
  set_servo_position(2, port2_position);
  set_servo_position(3, port3_position);
  enable_servos();
}
```
user: Translate the below assembly code into C programming language:

```asm
<k_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L36
  mov    $0x0,%eax
  jmp    L11
L36:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    $0x1,%eax
  jmp    L11
L14:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int k_equal(char *node_key, char *key, int node_k_len, int key_length) {
  if (node_k_len != key_length)
    return (0);
  if (memcmp(node_key, key, key_length) == 0)
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<k_equal>:
  endbr64
  mov    $0x0,%eax
  cmp    %ecx,%edx
  je     L1
  ret
L1:
  sub    $0x8,%rsp
  mov    %ecx,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int k_equal(char *node_key, char *key, int node_k_len, int key_length) {
  if (node_k_len != key_length)
    return (0);
  if (memcmp(node_key, key, key_length) == 0)
    return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<k_equal>:
  endbr64
  cmp    %ecx,%edx
  je     L0
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x8,%rsp
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int k_equal(char *node_key, char *key, int node_k_len, int key_length) {
  if (node_k_len != key_length)
    return (0);
  if (memcmp(node_key, key, key_length) == 0)
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<k_equal>:
  endbr64
  cmp    %ecx,%edx
  je     L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x8,%rsp
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int k_equal(char *node_key, char *key, int node_k_len, int key_length) {
  if (node_k_len != key_length)
    return (0);
  if (memcmp(node_key, key, key_length) == 0)
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vink_arena_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vink_arena_alloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L2
L14:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
void *vink_arena_calloc(struct vink_arena *arena, size_t size) {
  void *result;
  result = vink_arena_alloc(arena, size);
  if (!result)
    return 0;
  memset(result, 0, size);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vink_arena_calloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <vink_arena_alloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *vink_arena_calloc(struct vink_arena *arena, size_t size) {
  void *result;
  result = vink_arena_alloc(arena, size);
  if (!result)
    return 0;
  memset(result, 0, size);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vink_arena_calloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <vink_arena_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *vink_arena_calloc(struct vink_arena *arena, size_t size) {
  void *result;
  result = vink_arena_alloc(arena, size);
  if (!result)
    return 0;
  memset(result, 0, size);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vink_arena_calloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <vink_arena_alloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *vink_arena_calloc(struct vink_arena *arena, size_t size) {
  void *result;
  result = vink_arena_alloc(arena, size);
  if (!result)
    return 0;
  memset(result, 0, size);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getfilesize_env>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L6
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  jmp    L13
L6:
  mov    $0xffffffffffffffff,%rax
L13:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string

tool: D11: CONTENT_LENGTH

assistant: ```c
long long int getfilesize_env() {
  unsigned long tContentLength = 0;
  char *cContentLength = NULL;
  if (getenv("CONTENT_LENGTH") != NULL) {
    cContentLength = getenv("CONTENT_LENGTH");
    tContentLength = atoi(cContentLength);
  } else
    return -1;
  return tContentLength;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getfilesize_env>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L11
  lea    D9(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
L10:
  add    $0x8,%rsp
  ret
L11:
  mov    $0xffffffffffffffff,%rax
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: CONTENT_LENGTH

assistant: ```c
long long int getfilesize_env() {
  unsigned long tContentLength = 0;
  char *cContentLength = NULL;
  if (getenv("CONTENT_LENGTH") != NULL) {
    cContentLength = getenv("CONTENT_LENGTH");
    tContentLength = atoi(cContentLength);
  } else
    return -1;
  return tContentLength;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getfilesize_env>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdi
  call   <getenv@plt>
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <atoi@plt>
L5:
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5: CONTENT_LENGTH

assistant: ```c
long long int getfilesize_env() {
  unsigned long tContentLength = 0;
  char *cContentLength = NULL;
  if (getenv("CONTENT_LENGTH") != NULL) {
    cContentLength = getenv("CONTENT_LENGTH");
    tContentLength = atoi(cContentLength);
  } else
    return -1;
  return tContentLength;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getfilesize_env>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rdi
  call   <getenv@plt>
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <atoi@plt>
L5:
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: CONTENT_LENGTH

assistant: ```c
long long int getfilesize_env() {
  unsigned long tContentLength = 0;
  char *cContentLength = NULL;
  if (getenv("CONTENT_LENGTH") != NULL) {
    cContentLength = getenv("CONTENT_LENGTH");
    tContentLength = atoi(cContentLength);
  } else
    return -1;
  return tContentLength;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<brnflip_flip_32_in_place>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movzbl -0x9(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0xa(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  movzbl -0xb(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void brnflip_flip_32_in_place(char *x) {
  char temp[4];
  memcpy(&temp, x, 4);
  x[0] = temp[3];
  x[1] = temp[2];
  x[2] = temp[1];
  x[3] = temp[0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<brnflip_flip_32_in_place>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  movzbl 0x7(%rsp),%eax
  mov    %al,(%rbx)
  movzbl 0x6(%rsp),%eax
  mov    %al,0x1(%rbx)
  movzbl 0x5(%rsp),%eax
  mov    %al,0x2(%rbx)
  movzbl 0x4(%rsp),%eax
  mov    %al,0x3(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void brnflip_flip_32_in_place(char *x) {
  char temp[4];
  memcpy(&temp, x, 4);
  x[0] = temp[3];
  x[1] = temp[2];
  x[2] = temp[1];
  x[3] = temp[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<brnflip_flip_32_in_place>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  mov    %rbx,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  bswap  %eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void brnflip_flip_32_in_place(char *x) {
  char temp[4];
  memcpy(&temp, x, 4);
  x[0] = temp[3];
  x[1] = temp[2];
  x[2] = temp[1];
  x[3] = temp[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<brnflip_flip_32_in_place>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  mov    %rbx,%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  bswap  %eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void brnflip_flip_32_in_place(char *x) {
  char temp[4];
  memcpy(&temp, x, 4);
  x[0] = temp[3];
  x[1] = temp[2];
  x[2] = temp[1];
  x[3] = temp[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CToPascal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_length@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void CToPascal(char *s) {
  int i, j;
  j = string_length(s);
  for (i = j; i != 0; i--)
    s[i] = s[i - 1];
  s[0] = j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CToPascal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <string_length@plt>
  test   %eax,%eax
  je     L10
  movslq %eax,%rcx
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x1(%rbx,%rcx,1),%rsi
  lea    -0x1(%rax),%ecx
  sub    %rcx,%rsi
L12:
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
L10:
  mov    %al,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void CToPascal(char *s) {
  int i, j;
  j = string_length(s);
  for (i = j; i != 0; i--)
    s[i] = s[i - 1];
  s[0] = j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CToPascal>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <string_length@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L8
  movslq %ebp,%rdi
  lea    -0x1(%rax),%eax
  lea    -0x1(%rdi),%rsi
  sub    %rax,%rdi
  lea    0x1(%rax),%rdx
  sub    %rax,%rsi
  add    %rbx,%rdi
  add    %rbx,%rsi
  call   <memmove@plt>
L8:
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void CToPascal(char *s) {
  int i, j;
  j = string_length(s);
  for (i = j; i != 0; i--)
    s[i] = s[i - 1];
  s[0] = j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CToPascal>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <string_length@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L2
  movslq %ebp,%rdi
  lea    -0x1(%rax),%eax
  lea    -0x1(%rdi),%rsi
  sub    %rax,%rdi
  lea    0x1(%rax),%rdx
  sub    %rax,%rsi
  add    %rbx,%rdi
  add    %rbx,%rsi
  call   <memmove@plt>
L2:
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void CToPascal(char *s) {
  int i, j;
  j = string_length(s);
  for (i = j; i != 0; i--)
    s[i] = s[i - 1];
  s[0] = j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FOO1>:
  endbr64
  sub    $0x10,%rsp
  movupd 0xb0(%rsi),%xmm0
  movupd 0xa0(%rsi),%xmm6
  mov    $0x10,%eax
  movupd 0xc0(%rsi),%xmm1
  movupd 0xd0(%rsi),%xmm2
  movupd 0xe0(%rsi),%xmm3
  movaps %xmm0,-0x68(%rsp)
  movupd 0xf0(%rsi),%xmm4
  movupd 0x100(%rsi),%xmm5
  movupd 0x110(%rsi),%xmm0
  movaps %xmm1,-0x58(%rsp)
  movupd 0x80(%rsi),%xmm8
  movaps %xmm2,-0x48(%rsp)
  movupd 0x10(%rsi),%xmm15
  movupd 0x90(%rsi),%xmm7
  movaps %xmm3,-0x38(%rsp)
  movupd 0x20(%rsi),%xmm14
  movaps %xmm4,-0x28(%rsp)
  movupd 0x30(%rsi),%xmm13
  movupd 0x40(%rsi),%xmm12
  movaps %xmm5,-0x18(%rsp)
  movupd 0x50(%rsi),%xmm11
  movupd 0x60(%rsi),%xmm10
  movaps %xmm0,-0x8(%rsp)
  movupd 0x70(%rsi),%xmm9
  movupd 0x120(%rsi),%xmm5
  movupd 0x130(%rsi),%xmm4
  movupd 0x140(%rsi),%xmm3
  movaps %xmm8,-0x78(%rsp)
  movupd 0x150(%rsi),%xmm2
  movupd 0x160(%rsi),%xmm1
  movupd 0x170(%rsi),%xmm0
  movupd (%rsi),%xmm8
  movups %xmm6,0xa0(%rdi)
  movapd -0x68(%rsp),%xmm6
  movups %xmm7,0x90(%rdi)
  movapd -0x58(%rsp),%xmm7
  movups %xmm8,(%rdi)
  movapd -0x78(%rsp),%xmm8
  movups %xmm6,0xb0(%rdi)
  movapd -0x48(%rsp),%xmm6
  movups %xmm7,0xc0(%rdi)
  movapd -0x38(%rsp),%xmm7
  movups %xmm6,0xd0(%rdi)
  movapd -0x28(%rsp),%xmm6
  movups %xmm7,0xe0(%rdi)
  movapd -0x18(%rsp),%xmm7
  movups %xmm6,0xf0(%rdi)
  movapd -0x8(%rsp),%xmm6
  movups %xmm15,0x10(%rdi)
  movups %xmm14,0x20(%rdi)
  movups %xmm13,0x30(%rdi)
  movups %xmm12,0x40(%rdi)
  movups %xmm11,0x50(%rdi)
  movups %xmm10,0x60(%rdi)
  movups %xmm9,0x70(%rdi)
  movups %xmm8,0x80(%rdi)
  movups %xmm7,0x100(%rdi)
  movups %xmm6,0x110(%rdi)
  movups %xmm5,0x120(%rdi)
  movups %xmm4,0x130(%rdi)
  movups %xmm3,0x140(%rdi)
  movups %xmm2,0x150(%rdi)
  movups %xmm1,0x160(%rdi)
  movups %xmm0,0x170(%rdi)
  add    $0x10,%rsp
  ret
```

assistant: ```c
int FOO1(double *restrict a, double *restrict b, double *restrict c) {
  int i, bytes = 16, len = 24;
  a[0] = b[0];
  a[1] = b[1];
  a[2] = b[2];
  a[3] = b[3];
  a[4] = b[4];
  a[5] = b[5];
  a[6] = b[6];
  a[7] = b[7];
  a[8] = b[8];
  a[9] = b[9];
  a[10] = b[10];
  a[11] = b[11];
  a[12] = b[12];
  a[13] = b[13];
  a[14] = b[14];
  a[15] = b[15];
  a[16] = b[16];
  a[17] = b[17];
  a[18] = b[18];
  a[19] = b[19];
  a[20] = b[20];
  a[21] = b[21];
  a[22] = b[22];
  a[23] = b[23];
  a[24] = b[24];
  a[25] = b[25];
  a[26] = b[26];
  a[27] = b[27];
  a[28] = b[28];
  a[29] = b[29];
  a[30] = b[30];
  a[31] = b[31];
  a[32] = b[32];
  a[33] = b[33];
  a[34] = b[34];
  a[35] = b[35];
  a[36] = b[36];
  a[37] = b[37];
  a[38] = b[38];
  a[39] = b[39];
  a[40] = b[40];
  a[41] = b[41];
  a[42] = b[42];
  a[43] = b[43];
  a[44] = b[44];
  a[45] = b[45];
  a[46] = b[46];
  a[47] = b[47];
  return bytes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <display@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = atoi(argv[1]);
  display(n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <display@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = atoi(argv[1]);
  display(n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <display@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = atoi(argv[1]);
  display(n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <display@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char const *argv[]) {
  int n = atoi(argv[1]);
  display(n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sockatmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jns    L3
  mov    $0xffffffff,%eax
  jmp    L18
L3:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int sockatmark(int sockfd) {
  int flag;
  if (ioctl(sockfd, SIOCATMARK, &flag) < 0)
    return -1;
  return (flag != 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sockatmark>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  js     L18
  cmpl   $0x0,0x4(%rsp)
  setne  %al
  movzbl %al,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockatmark(int sockfd) {
  int flag;
  if (ioctl(sockfd, SIOCATMARK, &flag) < 0)
    return -1;
  return (flag != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sockatmark>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  js     L6
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setne  %al
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockatmark(int sockfd) {
  int flag;
  if (ioctl(sockfd, SIOCATMARK, &flag) < 0)
    return -1;
  return (flag != 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sockatmark>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  js     L10
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  setne  %al
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockatmark(int sockfd) {
  int flag;
  if (ioctl(sockfd, SIOCATMARK, &flag) < 0)
    return -1;
  return (flag != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_symlink_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  je     L35
  mov    $0x0,%eax
  jmp    L17
L35:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISLNK@plt>
  test   %eax,%eax
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L17
L2:
  mov    $0x1,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int _symlink_exists(char *path) {
  struct stat buf;
  if (lstat(path, &buf)) {
    return 0;
  }
  if (!S_ISLNK(buf.st_mode)) {
    return -1;
  }
  return 1;
}
```