ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L67
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  test   %eax,%eax
  jne    L3
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L17
L3:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  test   %eax,%eax
  js     L69
  call   <atoi@plt>
  mov    %eax,%ebp
L27:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  test   %eax,%eax
  js     L63
  call   <atoi@plt>
  mov    %eax,%esi
L14:
  mov    %ebp,%edi
  call   <pgcd@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L17
L69:
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%ebp
  jmp    L27
L63:
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%esi
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D20
type: string

tool: D7: Nombre de parametres insuffisants

tool: D16: infini

tool: D20: %d

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  } else if (atoi(argv[2]) == 0) {
    printf("infini\n");
    return 1;
  } else {
    int a = (atoi(argv[1]) < 0 ? atoi(argv[1]) * -1 : atoi(argv[1]));
    int b = (atoi(argv[2]) < 0 ? atoi(argv[2]) * -1 : atoi(argv[2]));
    printf("%d", pgcd(a, b));
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<t1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <threadWait@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L18
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <threadSignal@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string

tool: D7: %d t1 started


tool: D15: finished with math! (%d)


tool: D26: %d t1: done result=%d


assistant: ```c
void *t1(void *arg) {
  threadWait(1, 2);
  int param = *((int *)arg);
  int sto = param;
  printf("%d t1 started\n", param);
  int *result = malloc(sizeof(int));
  *result = param;
  int i;
  for (i = 0; i < (param * 1000); i++) {
    *result += 1;
  }
  printf("finished with math! (%d)\n", *result);
  printf("%d t1: done result=%d\n", sto, *result);
  threadSignal(1, 1);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <threadWait@plt>
  mov    (%rbx),%ebp
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,(%rax)
  imul   $0x3e8,%ebp,%edx
  test   %edx,%edx
  jle    L4
  lea    0x1(%rbp),%eax
  lea    0x1(%rbp,%rdx,1),%ecx
L9:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L9
  mov    %edx,(%rbx)
L4:
  mov    (%rbx),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%edx
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <threadSignal@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string

tool: D22: %d t1 started


tool: D1: finished with math! (%d)


tool: D5: %d t1: done result=%d


assistant: ```c
void *t1(void *arg) {
  threadWait(1, 2);
  int param = *((int *)arg);
  int sto = param;
  printf("%d t1 started\n", param);
  int *result = malloc(sizeof(int));
  *result = param;
  int i;
  for (i = 0; i < (param * 1000); i++) {
    *result += 1;
  }
  printf("finished with math! (%d)\n", *result);
  printf("%d t1: done result=%d\n", sto, *result);
  threadSignal(1, 1);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<t1>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <threadWait@plt>
  mov    0x0(%rbp),%ebp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  imul   $0x3e8,%ebp,%esi
  mov    %ebp,(%rax)
  mov    %rax,%r12
  test   %esi,%esi
  jle    L18
  add    %ebp,%esi
  mov    %esi,(%rax)
L8:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r12),%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <threadSignal@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L18:
  mov    %ebp,%esi
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: string

tool: D13: %d t1 started


tool: D21: finished with math! (%d)


tool: D27: %d t1: done result=%d


assistant: ```c
void *t1(void *arg) {
  threadWait(1, 2);
  int param = *((int *)arg);
  int sto = param;
  printf("%d t1 started\n", param);
  int *result = malloc(sizeof(int));
  *result = param;
  int i;
  for (i = 0; i < (param * 1000); i++) {
    *result += 1;
  }
  printf("finished with math! (%d)\n", *result);
  printf("%d t1: done result=%d\n", sto, *result);
  threadSignal(1, 1);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<t1>:
  endbr64
  push   %r12
  mov    $0x2,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <threadWait@plt>
  mov    0x0(%rbp),%ebp
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  imul   $0x3e8,%ebp,%esi
  mov    %ebp,(%rax)
  mov    %rax,%r12
  test   %esi,%esi
  jle    L3
  add    %ebp,%esi
  mov    %esi,(%rax)
L11:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r12),%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <threadSignal@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L3:
  mov    %ebp,%esi
  jmp    L11
```

tool_calls: name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D8
type: string

tool: D17: %d t1 started


tool: D15: finished with math! (%d)


tool: D8: %d t1: done result=%d


assistant: ```c
void *t1(void *arg) {
  threadWait(1, 2);
  int param = *((int *)arg);
  int sto = param;
  printf("%d t1 started\n", param);
  int *result = malloc(sizeof(int));
  *result = param;
  int i;
  for (i = 0; i < (param * 1000); i++) {
    *result += 1;
  }
  printf("finished with math! (%d)\n", *result);
  printf("%d t1: done result=%d\n", sto, *result);
  threadSignal(1, 1);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D66(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D77(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D76(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D79(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x8(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x14(%rsp),%xmm0
  addss  %xmm1,%xmm0
  divss  D69(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D86(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D66
type_guessed: string
name: unpack_data
arguments: label: D77
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string
name: unpack_data
arguments: label: D76
type_guessed: string
name: unpack_data
arguments: label: D79
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D69
type_guessed: byte[4]
name: unpack_data
arguments: label: D86
type_guessed: string

tool: D17: 
 - Write five numbers and I'll give you the average - 

tool: D66: 
What is the first value? 

tool: D77: %d

tool: D20: What is the second value? 

tool: D76: What is the third value? 

tool: D79: What is the fourth value? 

tool: D18: What is the fifth value? 

tool: {"D69": [0x00,0x00,0xa0,0x40]}

tool: D86:  

		Your average is %.2f

assistant: ```c
int main() {
  int value1;
  int value2;
  int value3;
  int value4;
  int value5;
  float average;
  printf("\n - Write five numbers and I'll give you the average - \n");
  printf("\nWhat is the first value? \n");
  scanf("%d", &value1);
  printf("What is the second value? \n");
  scanf("%d", &value2);
  printf("What is the third value? \n");
  scanf("%d", &value3);
  printf("What is the fourth value? \n");
  scanf("%d", &value4);
  printf("What is the fifth value? \n");
  scanf("%d", &value5);
  average = (value1 + value2 + value3 + value4 + value5) / 5;
  average = value1;
  average += value2;
  average += value3;
  average += value4;
  average += value5;
  average /= 5;
  printf(" \n\n\t\tYour average is %.2f", average);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D56(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D18(%rip),%rdi
  cvtsi2ssl 0x4(%rsp),%xmm0
  mov    $0x1,%eax
  cvtsi2ssl 0x8(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x14(%rsp),%xmm0
  addss  %xmm1,%xmm0
  divss  D14(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D56
type: string
name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D3
type: string
name: retrieve_data
arguments: tag: D40
type: string
name: retrieve_data
arguments: tag: D46
type: string
name: retrieve_data
arguments: tag: D27
type: string
name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D14
type: byte[4]

tool: D0: 
 - Write five numbers and I'll give you the average - 

tool: D56: %d

tool: D35: 
What is the first value? 

tool: D3: What is the second value? 

tool: D40: What is the third value? 

tool: D46: What is the fourth value? 

tool: D27: What is the fifth value? 

tool: D18:  

		Your average is %.2f

tool: {"D14": [0x00,0x00,0xa0,0x40]}

assistant: ```c
int main() {
  int value1;
  int value2;
  int value3;
  int value4;
  int value5;
  float average;
  printf("\n - Write five numbers and I'll give you the average - \n");
  printf("\nWhat is the first value? \n");
  scanf("%d", &value1);
  printf("What is the second value? \n");
  scanf("%d", &value2);
  printf("What is the third value? \n");
  scanf("%d", &value3);
  printf("What is the fourth value? \n");
  scanf("%d", &value4);
  printf("What is the fifth value? \n");
  scanf("%d", &value5);
  average = (value1 + value2 + value3 + value4 + value5) / 5;
  average = value1;
  average += value2;
  average += value3;
  average += value4;
  average += value5;
  average /= 5;
  printf(" \n\n\t\tYour average is %.2f", average);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D46(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D65(%rip),%rdi
  cvtsi2ssl 0x4(%rsp),%xmm0
  mov    $0x1,%eax
  cvtsi2ssl 0x8(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0xc(%rsp),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl 0x10(%rsp),%xmm1
  addss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x14(%rsp),%xmm0
  addss  %xmm1,%xmm0
  divss  D22(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D59
type: string
name: unpack_data
arguments: label: D46
type: string
name: unpack_data
arguments: label: D37
type: string
name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D82
type: string
name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D65
type: string
name: unpack_data
arguments: label: D22
type: byte[4]

tool: D59: 
 - Write five numbers and I'll give you the average - 

tool: D46: %d

tool: D37: 
What is the first value? 

tool: D28: What is the second value? 

tool: D39: What is the third value? 

tool: D82: What is the fourth value? 

tool: D12: What is the fifth value? 

tool: D65:  

		Your average is %.2f

tool: {"D22": [0x00,0x00,0xa0,0x40]}

assistant: ```c
int main() {
  int value1;
  int value2;
  int value3;
  int value4;
  int value5;
  float average;
  printf("\n - Write five numbers and I'll give you the average - \n");
  printf("\nWhat is the first value? \n");
  scanf("%d", &value1);
  printf("What is the second value? \n");
  scanf("%d", &value2);
  printf("What is the third value? \n");
  scanf("%d", &value3);
  printf("What is the fourth value? \n");
  scanf("%d", &value4);
  printf("What is the fifth value? \n");
  scanf("%d", &value5);
  average = (value1 + value2 + value3 + value4 + value5) / 5;
  average = value1;
  average += value2;
  average += value3;
  average += value4;
  average += value5;
  average /= 5;
  printf(" \n\n\t\tYour average is %.2f", average);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bits_clrb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L4
  mov    $0xffffffff,%eax
  jmp    L12
L4:
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int bits_clrb(uint8_t *vec, size_t size, uint8_t bit) {
  if (size <= (bit >> 3)) {
    return -1;
  }
  *(vec + (bit >> 3)) &= (uint8_t)(~(1 << (bit & 0x07)));
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<bits_clrb>:
  endbr64
  mov    %edx,%ecx
  mov    %edx,%eax
  sar    $0x3,%eax
  cltq
  mov    $0xffffffff,%edx
  cmp    %rsi,%rax
  jae    L4
  and    $0x7,%ecx
  mov    $0xfffffffe,%edx
  rol    %cl,%edx
  and    %edx,(%rdi,%rax,4)
  mov    $0x1,%edx
L4:
  mov    %edx,%eax
  ret
```

assistant: ```c
int bits_clrb(uint8_t *vec, size_t size, uint8_t bit) {
  if (size <= (bit >> 3)) {
    return -1;
  }
  *(vec + (bit >> 3)) &= (uint8_t)(~(1 << (bit & 0x07)));
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bits_clrb>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    $0xffffffff,%r8d
  sar    $0x3,%eax
  cltq
  cmp    %rsi,%rax
  jae    L8
  and    $0x7,%ecx
  mov    $0xfffffffe,%edx
  mov    $0x1,%r8d
  rol    %cl,%edx
  and    %edx,(%rdi,%rax,4)
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bits_clrb(uint8_t *vec, size_t size, uint8_t bit) {
  if (size <= (bit >> 3)) {
    return -1;
  }
  *(vec + (bit >> 3)) &= (uint8_t)(~(1 << (bit & 0x07)));
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bits_clrb>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    $0xffffffff,%r8d
  sar    $0x3,%eax
  cltq
  cmp    %rsi,%rax
  jae    L8
  and    $0x7,%ecx
  mov    $0xfffffffe,%edx
  mov    $0x1,%r8d
  rol    %cl,%edx
  and    %edx,(%rdi,%rax,4)
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bits_clrb(uint8_t *vec, size_t size, uint8_t bit) {
  if (size <= (bit >> 3)) {
    return -1;
  }
  *(vec + (bit >> 3)) &= (uint8_t)(~(1 << (bit & 0x07)));
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_171_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_171_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_171_1_1>:
  endbr64
  or     %esi,%edx
  mov    %edx,%eax
  not    %eax
  and    (%rdi),%dl
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_171_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_171_1_1>:
  endbr64
  or     %esi,%edx
  mov    %edx,%eax
  and    (%rdi),%dl
  not    %eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_171_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_171_1_1>:
  endbr64
  or     %esi,%edx
  mov    %edx,%eax
  and    (%rdi),%dl
  not    %eax
  or     %edx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_171_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = T | S;
  stk2 = ~stk2;
  stk1 = *D | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assert_ip6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %rdx,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x120(%rbp),%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  lea    -0x110(%rbp),%rdx
  mov    $0xff,%ecx
  mov    %eax,%edi
  call   <inet_ntop@plt>
  mov    -0x128(%rbp),%rdx
  lea    -0x110(%rbp),%rcx
  mov    -0x118(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <assert_string@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void assert_ip6(char *expected, struct sockaddr_storage *reality, char *msg) {
  char dst[255];
  inet_ntop(AF_INET6, &((struct sockaddr_in6 *)reality)->sin6_addr, &dst[0], 255);
  assert_string(expected, dst, msg);
}
```