ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%edx
  mov    $0x7,%ecx
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000007,%rax
  mov    %rsp,%rbp
  lea    0x18(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  movabs $0x500000008,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %rbp,%rax
  jmp    L57
  nopl   (%rax)
L0:
  mov    (%rsi),%ecx
  mov    (%rax),%edx
L57:
  cmp    %ecx,%edx
  jle    L46
  mov    %ecx,(%rax)
  mov    %edx,(%rsi)
L46:
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L0
  add    $0x4,%rsi
  mov    (%rsp),%edx
  cmp    %rbx,%rsi
  je     L4
  mov    (%rsi),%ecx
  jmp    L58
  nopl   (%rax)
L4:
  lea    D8(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L48:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L48
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: %d	

assistant: ```c
int main(int argc, char const *argv[]) {
  int arrNum[] = {7, 2, 8, 5, 4, 1};
  int count = sizeof arrNum / sizeof arrNum[0];
  int i, j, temp;
  for (i = 0; i < count; i++) {
    for (j = 0; j < count; j++) {
      if (arrNum[i] < arrNum[j]) {
        temp = arrNum[j];
        arrNum[j] = arrNum[i];
        arrNum[i] = temp;
      }
    }
  }
  for (i = 0; i < count; i++) {
    printf("%d\t", arrNum[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: byte[16]
name: retrieve_data
arguments: data_label: D19
type_infered: byte[8]

tool: D15: %d	

tool: {"D27": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D19": [0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char const *argv[]) {
  int arrNum[] = {7, 2, 8, 5, 4, 1};
  int count = sizeof arrNum / sizeof arrNum[0];
  int i, j, temp;
  for (i = 0; i < count; i++) {
    for (j = 0; j < count; j++) {
      if (arrNum[i] < arrNum[j]) {
        temp = arrNum[j];
        arrNum[j] = arrNum[i];
        arrNum[i] = temp;
      }
    }
  }
  for (i = 0; i < count; i++) {
    printf("%d\t", arrNum[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x12c,-0x4(%rbp)
  mov    $0x0,%eax
  call   <krad_system_init@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x3e8,%edx
  mov    $0x7530,%esi
  mov    %eax,%edi
  call   <krad_ticker_test@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x200,%edx
  mov    $0xac44,%esi
  mov    %eax,%edi
  call   <krad_ticker_test@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x400,%edx
  mov    $0xac44,%esi
  mov    %eax,%edi
  call   <krad_ticker_test@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x400,%edx
  mov    $0xbb80,%esi
  mov    %eax,%edi
  call   <krad_ticker_test@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x3e8,%edx
  mov    $0xea60,%esi
  mov    %eax,%edi
  call   <krad_ticker_test@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: Clean Exit

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  count = 300;
  krad_system_init();
  krad_ticker_test(count, 30000, 1000);
  krad_ticker_test(count, 44100, 512);
  krad_ticker_test(count, 44100, 1024);
  krad_ticker_test(count, 48000, 1024);
  krad_ticker_test(count, 60000, 1000);
  printk("Clean Exit");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <krad_system_init@plt>
  mov    $0x3e8,%edx
  mov    $0x7530,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x200,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xbb80,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x3e8,%edx
  mov    $0xea60,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  lea    D7(%rip),%rdi
  call   <printk@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: Clean Exit

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  count = 300;
  krad_system_init();
  krad_ticker_test(count, 30000, 1000);
  krad_ticker_test(count, 44100, 512);
  krad_ticker_test(count, 44100, 1024);
  krad_ticker_test(count, 48000, 1024);
  krad_ticker_test(count, 60000, 1000);
  printk("Clean Exit");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <krad_system_init@plt>
  mov    $0x3e8,%edx
  mov    $0x7530,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x200,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xbb80,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x3e8,%edx
  mov    $0xea60,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  lea    D0(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: Clean Exit

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  count = 300;
  krad_system_init();
  krad_ticker_test(count, 30000, 1000);
  krad_ticker_test(count, 44100, 512);
  krad_ticker_test(count, 44100, 1024);
  krad_ticker_test(count, 48000, 1024);
  krad_ticker_test(count, 60000, 1000);
  printk("Clean Exit");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <krad_system_init@plt>
  mov    $0x3e8,%edx
  mov    $0x7530,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x200,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xac44,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x400,%edx
  mov    $0xbb80,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  mov    $0x3e8,%edx
  mov    $0xea60,%esi
  mov    $0x12c,%edi
  call   <krad_ticker_test@plt>
  lea    D9(%rip),%rdi
  call   <printk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D9: Clean Exit

assistant: ```c
int main(int argc, char *argv[]) {
  int count;
  count = 300;
  krad_system_init();
  krad_ticker_test(count, 30000, 1000);
  krad_ticker_test(count, 44100, 512);
  krad_ticker_test(count, 44100, 1024);
  krad_ticker_test(count, 48000, 1024);
  krad_ticker_test(count, 60000, 1000);
  printk("Clean Exit");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  imul   -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L8
L20:
  movl   $0x1,-0x1c(%rbp)
  jmp    L72
L50:
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  imul   -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L55
L27:
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L39
L64:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  imul   -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L23
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  nop
L23:
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L64
  addl   $0x1,-0x14(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  addl   $0x1,-0x1c(%rbp)
L72:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L50
  addl   $0x1,-0x18(%rbp)
L8:
  cmpl   $0x31,-0x18(%rbp)
  jle    L20
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: Ramanujan Number %d : %d


assistant: ```c
int main(void) {
  int a = 1, b = 1, c = 1, d = 1;
  int left = a * a * a + b * b * b;
  int right = 0;
  int count = 1;
  for (b = 1; b < 50; b++) {
    for (a = 1; a <= b; a++) {
      left = a * a * a + b * b * b;
      for (c = 1; c < a; c++) {
        right = 0;
        for (d = c; right <= left; d++) {
          right = c * c * c + d * d * d;
          for (; right == left;) {
            printf("Ramanujan Number %d : %d\n", count, left);
            count++;
            break;
          }
        }
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x1,%r14d
  movl   $0x1,0x8(%rsp)
  lea    D8(%rip),%r15
  jmp    L1
L63:
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%r14d
L6:
  add    $0x1,%ebx
L80:
  lea    -0x1(%rbx),%edx
  mov    %edx,%eax
  imul   %edx,%eax
  imul   %edx,%eax
  add    %r12d,%eax
  cmp    %eax,%ebp
  je     L63
  jge    L6
L108:
  lea    0x1(%r13),%eax
  cmp    %r13d,(%rsp)
  je     L21
  mov    %eax,%r13d
L15:
  test   %ebp,%ebp
  js     L108
  mov    %r13d,%r12d
  imul   %r13d,%r12d
  imul   %r13d,%r12d
  lea    0x1(%r13),%ebx
  jmp    L80
L21:
  mov    0x4(%rsp),%eax
  mov    %eax,(%rsp)
L99:
  mov    (%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    0x8(%rsp),%eax
  jg     L107
  mov    0x4(%rsp),%eax
  mov    %eax,%ebp
  imul   %eax,%ebp
  imul   %eax,%ebp
  add    0xc(%rsp),%ebp
  cmp    $0x1,%eax
  jle    L21
  mov    $0x1,%r13d
  jmp    L15
L107:
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    $0x32,%eax
  je     L87
L1:
  mov    0x8(%rsp),%edi
  mov    %edi,%eax
  test   %edi,%edi
  jle    L107
  imul   %edi,%eax
  imul   %edi,%eax
  mov    %eax,0xc(%rsp)
  movl   $0x1,(%rsp)
  jmp    L99
L87:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: Ramanujan Number %d : %d


assistant: ```c
int main(void) {
  int a = 1, b = 1, c = 1, d = 1;
  int left = a * a * a + b * b * b;
  int right = 0;
  int count = 1;
  for (b = 1; b < 50; b++) {
    for (a = 1; a <= b; a++) {
      left = a * a * a + b * b * b;
      for (c = 1; c < a; c++) {
        right = 0;
        for (d = c; right <= left; d++) {
          right = c * c * c + d * d * d;
          for (; right == left;) {
            printf("Ramanujan Number %d : %d\n", count, left);
            count++;
            break;
          }
        }
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x18,%rsp
L11:
  mov    %r13d,%eax
  movl   $0x1,0x4(%rsp)
  imul   %r13d,%eax
  imul   %r13d,%eax
  mov    %eax,0xc(%rsp)
  lea    0x1(%r13),%eax
  mov    %eax,0x8(%rsp)
  nopl   0x0(%rax)
L62:
  mov    0x4(%rsp),%eax
  mov    %eax,(%rsp)
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    %eax,0x8(%rsp)
  je     L44
  mov    0x4(%rsp),%eax
  mov    $0x1,%r13d
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %eax,%edx
  mov    0xc(%rsp),%eax
  lea    (%rdx,%rax,1),%r12d
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    %r13d,%ecx
  mov    %r13d,%r15d
  imul   %r13d,%ecx
  imul   %r13d,%ecx
  mov    %ecx,%ebp
L58:
  mov    %r15d,%eax
  imul   %r15d,%eax
  imul   %r15d,%eax
  add    $0x1,%r15d
  add    %ebp,%eax
  cmp    %eax,%r12d
  je     L19
  jge    L58
  lea    0x1(%r13),%eax
  cmp    %r13d,(%rsp)
  je     L62
  mov    %eax,%r13d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r14d,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  jmp    L58
L44:
  mov    0x8(%rsp),%r13d
  cmp    $0x32,%r13d
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: Ramanujan Number %d : %d


assistant: ```c
int main(void) {
  int a = 1, b = 1, c = 1, d = 1;
  int left = a * a * a + b * b * b;
  int right = 0;
  int count = 1;
  for (b = 1; b < 50; b++) {
    for (a = 1; a <= b; a++) {
      left = a * a * a + b * b * b;
      for (c = 1; c < a; c++) {
        right = 0;
        for (d = c; right <= left; d++) {
          right = c * c * c + d * d * d;
          for (; right == left;) {
            printf("Ramanujan Number %d : %d\n", count, left);
            count++;
            break;
          }
        }
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%eax
  push   %r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
L24:
  mov    %eax,%r13d
  lea    0x1(%rax),%ecx
  movl   $0x2,0x4(%rsp)
  imul   %eax,%r13d
  mov    %ecx,0x8(%rsp)
  imul   %eax,%r13d
  mov    %r13d,0xc(%rsp)
  cmp    $0x1,%eax
  je     L37
  nopl   0x0(%rax)
L47:
  mov    0x4(%rsp),%eax
  mov    $0x1,%r13d
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %eax,%edx
  mov    0xc(%rsp),%eax
  lea    (%rdx,%rax,1),%ebx
  nopl   0x0(%rax)
L35:
  mov    %r13d,%r15d
  mov    %r13d,%r14d
  imul   %r13d,%r15d
  imul   %r13d,%r15d
  xchg   %ax,%ax
L40:
  mov    %r14d,%eax
  imul   %r14d,%eax
  imul   %r14d,%eax
  add    $0x1,%r14d
  add    %r15d,%eax
  cmp    %eax,%ebx
  je     L49
  jge    L40
  add    $0x1,%r13d
  cmp    %r13d,0x4(%rsp)
  jne    L35
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    0x8(%rsp),%eax
  jne    L47
  mov    0x8(%rsp),%eax
  cmp    $0x32,%eax
  jne    L24
L16:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    %r12d,%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  jmp    L40
L37:
  movl   $0x2,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    $0x32,%eax
  jne    L24
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: Ramanujan Number %d : %d


assistant: ```c
int main(void) {
  int a = 1, b = 1, c = 1, d = 1;
  int left = a * a * a + b * b * b;
  int right = 0;
  int count = 1;
  for (b = 1; b < 50; b++) {
    for (a = 1; a <= b; a++) {
      left = a * a * a + b * b * b;
      for (c = 1; c < a; c++) {
        right = 0;
        for (d = c; right <= left; d++) {
          right = c * c * c + d * d * d;
          for (; right == left;) {
            printf("Ramanujan Number %d : %d\n", count, left);
            count++;
            break;
          }
        }
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <create_tree@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    $0x0,%eax
  call   <abort@plt>
L24:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  call   <abort@plt>
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main0() {
  struct node *node = create_tree();
  node = tree_add(node);
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main0>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <create_tree@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L56
L52:
  mov    %rbx,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
L20:
  mov    %rbx,%rdi
  call   <tree_get_parent@plt>
  test   %rax,%rax
  je     L54
L2:
  mov    $0x0,%eax
  pop    %rbx
  ret
L56:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L52
L31:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L20
L54:
  call   <abort@plt>
  jmp    L2
```

assistant: ```c
int main0() {
  struct node *node = create_tree();
  node = tree_add(node);
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main0>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <create_tree@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L22
L49:
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
  call   <tree_get_parent@plt>
  test   %rax,%rax
  je     L5
L46:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L22:
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <abort@plt>
  mov    0x8(%rsp),%rdi
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <abort@plt>
  mov    0x8(%rsp),%rdi
  call   <tree_get_parent@plt>
  test   %rax,%rax
  jne    L46
L5:
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main0() {
  struct node *node = create_tree();
  node = tree_add(node);
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main0>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <create_tree@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L47
L6:
  call   <tree_add@plt>
  mov    %rax,%rdi
  call   <tree_get_parent@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L44
  call   <tree_get_parent@plt>
  test   %rax,%rax
  je     L21
L32:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L47:
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <abort@plt>
  mov    0x8(%rsp),%rdi
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <abort@plt>
  mov    0x8(%rsp),%rdi
  call   <tree_get_parent@plt>
  test   %rax,%rax
  jne    L32
L21:
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main0() {
  struct node *node = create_tree();
  node = tree_add(node);
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_add(node);
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  node = tree_get_parent(node);
  if (node == 0)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xasprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  mov    %eax,-0xb4(%rbp)
  cmpl   $0xffffffff,-0xb4(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <vmefail@plt>
L1:
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int xasprintf(char **strp, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vasprintf(strp, fmt, args);
  if (ret == -1)
    vmefail();
  va_end(args);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xasprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vasprintf@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L15
L12:
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0x0,%eax
  call   <vmefail@plt>
  jmp    L12
```

assistant: ```c
int xasprintf(char **strp, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = vasprintf(strp, fmt, args);
  if (ret == -1)
    vmefail();
  va_end(args);
  return ret;
}
```