ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<longword>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  xor    %eax,%eax
  test   %dl,%dl
  je     L4
  nopw   0x0(%rax,%rax,1)
L24:
  and    $0xdf,%edx
  je     L50
  movslq %eax,%rdx
  lea    0x1(%rdi,%rdx,1),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L56:
  movzbl (%rcx),%esi
  mov    %edx,%r8d
  mov    %eax,%r9d
  add    $0x1,%edx
  add    $0x1,%eax
  add    $0x1,%rcx
  and    $0xdf,%esi
  jne    L56
  cmp    %r10d,%edx
  jle    L50
  mov    %r9d,%r11d
  mov    %edx,%r10d
  sub    %r8d,%r11d
L50:
  add    $0x1,%eax
  movslq %eax,%rdx
  movzbl (%rdi,%rdx,1),%edx
  test   %dl,%dl
  jne    L24
  movslq %r11d,%r11
  movsbl (%rdi,%r11,1),%esi
  test   $0xdf,%sil
  je     L30
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi,%r11,1),%rbx
  sub    $0x8,%rsp
  nop
L5:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl -0x1(%rbx),%esi
  test   $0xdf,%sil
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
L30:
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: %c

assistant: ```c
void longword(char str[]) {
  int i = 0;
  int length = 0, count, location = 0;
  while (str[i] != '\0') {
    count = 0;
    while (str[i] != ' ' && str[i] != '\0') {
      count++;
      i++;
    }
    if (length < count) {
      length = count;
      location = i - count;
    }
    i++;
  }
  for (i = location; str[i] != '\0' && str[i] != ' '; i++) {
    printf("%c", str[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: n

assistant: ```c
int main(void) {
  for (;;) {
    puts("n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
L0:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: n

assistant: ```c
int main(void) {
  for (;;) {
    puts("n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rbx
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: n

assistant: ```c
int main(void) {
  for (;;) {
    puts("n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: n

assistant: ```c
int main(void) {
  for (;;) {
    puts("n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HTS_gnorm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L42
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  je     L2
L42:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L0
L21:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x24(%rbp)
L0:
  cmpl   $0x0,-0x24(%rbp)
  jg     L21
  movsd  D8(%rip),%xmm0
  divsd  -0x30(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L43
L2:
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rsi
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <HTS_movem@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L43:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: f64

tool: D8: 1

assistant: ```c
void HTS_gnorm(double *c1, double *c2, int m, const double g) {
  double k;
  if (g != 0.0) {
    k = 1.0 + g * c1[0];
    for (; m >= 1; m--)
      c2[m] = c1[m] / k;
    c2[0] = pow(k, 1.0 / g);
  } else {
    HTS_movem(&c1[1], &c2[1], m);
    c2[0] = exp(c1[0]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HTS_gnorm>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  ucomisd D14(%rip),%xmm0
  jp     L5
  je     L26
L5:
  movapd %xmm0,%xmm2
  mulsd  0x0(%rbp),%xmm2
  addsd  D6(%rip),%xmm2
  test   %edx,%edx
  jle    L31
  movslq %edx,%rdx
L3:
  movsd  0x0(%rbp,%rdx,8),%xmm1
  divsd  %xmm2,%xmm1
  movsd  %xmm1,(%rbx,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jg     L3
L31:
  movsd  D6(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <pow@plt>
L27:
  movsd  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  lea    0x8(%rsi),%rsi
  lea    0x8(%rdi),%rdi
  call   <HTS_movem@plt>
  movsd  0x0(%rbp),%xmm0
  call   <exp@plt>
  jmp    L27
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: f64
name: unpack_data
arguments: tag: D6
datatype: f64

tool: D14: 0

tool: D6: 1

assistant: ```c
void HTS_gnorm(double *c1, double *c2, int m, const double g) {
  double k;
  if (g != 0.0) {
    k = 1.0 + g * c1[0];
    for (; m >= 1; m--)
      c2[m] = c1[m] / k;
    c2[0] = pow(k, 1.0 / g);
  } else {
    HTS_movem(&c1[1], &c2[1], m);
    c2[0] = exp(c1[0]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<HTS_gnorm>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm3
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  ucomisd D16(%rip),%xmm0
  jp     L18
  je     L12
L18:
  movsd  0x0(%rbp),%xmm0
  movsd  D18(%rip),%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  test   %edx,%edx
  jle    L35
  movslq %edx,%rdx
  nopl   0x0(%rax)
L37:
  movsd  0x0(%rbp,%rdx,8),%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rbx,%rdx,8)
  sub    $0x1,%rdx
  test   %edx,%edx
  jg     L37
L35:
  divsd  %xmm3,%xmm1
  call   <pow@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  lea    0x8(%rsi),%rsi
  lea    0x8(%rdi),%rdi
  call   <HTS_movem@plt>
  movsd  0x0(%rbp),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type: f64
name: parse_data
arguments: data_tag: D18
type: f64

tool: D16: 0

tool: D18: 1

assistant: ```c
void HTS_gnorm(double *c1, double *c2, int m, const double g) {
  double k;
  if (g != 0.0) {
    k = 1.0 + g * c1[0];
    for (; m >= 1; m--)
      c2[m] = c1[m] / k;
    c2[0] = pow(k, 1.0 / g);
  } else {
    HTS_movem(&c1[1], &c2[1], m);
    c2[0] = exp(c1[0]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HTS_gnorm>:
  endbr64
  push   %rbp
  movapd %xmm0,%xmm3
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  ucomisd D2(%rip),%xmm0
  jp     L83
  je     L21
L83:
  movsd  0x0(%rbp),%xmm0
  movsd  D14(%rip),%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  test   %edx,%edx
  jle    L0
  movslq %edx,%rax
  lea    0x0(,%rax,8),%rcx
  lea    -0x8(%rcx),%rsi
  add    %rbx,%rcx
  lea    0x0(%rbp,%rsi,1),%rdi
  cmp    %rcx,%rdi
  je     L4
  cmp    $0x1,%edx
  je     L4
  mov    %edx,%ecx
  movapd %xmm0,%xmm4
  add    %rbx,%rsi
  xor    %eax,%eax
  shr    %ecx
  unpcklpd %xmm4,%xmm4
  neg    %rcx
  shl    $0x4,%rcx
  cs nopw 0x0(%rax,%rax,1)
L26:
  movupd (%rdi,%rax,1),%xmm2
  shufpd $0x1,%xmm2,%xmm2
  divpd  %xmm4,%xmm2
  shufpd $0x1,%xmm2,%xmm2
  movups %xmm2,(%rsi,%rax,1)
  sub    $0x10,%rax
  cmp    %rax,%rcx
  jne    L26
  mov    %edx,%eax
  and    $0x1,%eax
  and    $0x1,%edx
  je     L0
  cltq
  movsd  0x0(%rbp,%rax,8),%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rbx,%rax,8)
L0:
  divsd  %xmm3,%xmm1
  call   <pow@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L4:
  movsd  0x0(%rbp,%rax,8),%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rbx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jg     L4
  jmp    L0
  nopl   0x0(%rax)
L21:
  lea    0x8(%rsi),%rsi
  lea    0x8(%rdi),%rdi
  call   <HTS_movem@plt>
  movsd  0x0(%rbp),%xmm0
  call   <exp@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: f64
name: read_data
arguments: data_tag: D14
type_guessed: f64

tool: D2: 0

tool: D14: 1

assistant: ```c
void HTS_gnorm(double *c1, double *c2, int m, const double g) {
  double k;
  if (g != 0.0) {
    k = 1.0 + g * c1[0];
    for (; m >= 1; m--)
      c2[m] = c1[m] / k;
    c2[0] = pow(k, 1.0 / g);
  } else {
    HTS_movem(&c1[1], &c2[1], m);
    c2[0] = exp(c1[0]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_orientation_SS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x28(%rbp),%r9
  mov    -0x58(%rbp),%r8
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x20(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <test_orientation@plt>
  add    $0x10,%rsp
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jle    L36
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jle    L36
  mov    -0x60(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L32
L36:
  lea    -0x18(%rbp),%r9
  mov    -0x58(%rbp),%r8
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x40(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x10(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <test_orientation@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jle    L32
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jle    L32
  mov    -0x60(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L32:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D6
type: string

tool: D5: s/S

tool: D6: S/s

assistant: ```c
void get_orientation_SS(long i, long j, long **seidx, char **AtomName, double **xyz, char *type) {
  long n1 = 0, n2 = 0, n3 = 0, n4 = 0;
  test_orientation(i, j, seidx, AtomName, xyz, &n1, &n2);
  if (n1 > 0 && n2 > 0) {
    strcpy(type, "s/S");
  } else {
    test_orientation(j, i, seidx, AtomName, xyz, &n3, &n4);
    if (n3 > 0 && n4 > 0)
      strcpy(type, "S/s");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<get_orientation_SS>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %r9,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x30(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  call   <test_orientation@plt>
  add    $0x10,%rsp
  cmpq   $0x0,0x8(%rsp)
  jle    L52
  cmpq   $0x0,0x10(%rsp)
  jg     L29
L52:
  sub    $0x8,%rsp
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x28(%rsp),%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <test_orientation@plt>
  add    $0x10,%rsp
  cmpq   $0x0,0x18(%rsp)
  jle    L13
  cmpq   $0x0,0x20(%rsp)
  jle    L13
  lea    D16(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L13
L29:
  lea    D8(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
data_type: string
name: parse_data
arguments: data_label: D8
data_type: string

tool: D16: S/s

tool: D8: s/S

assistant: ```c
void get_orientation_SS(long i, long j, long **seidx, char **AtomName, double **xyz, char *type) {
  long n1 = 0, n2 = 0, n3 = 0, n4 = 0;
  test_orientation(i, j, seidx, AtomName, xyz, &n1, &n2);
  if (n1 > 0 && n2 > 0) {
    strcpy(type, "s/S");
  } else {
    test_orientation(j, i, seidx, AtomName, xyz, &n3, &n4);
    if (n3 > 0 && n4 > 0)
      strcpy(type, "S/s");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_orientation_SS>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  push   %rax
  lea    0x18(%rsp),%r9
  call   <test_orientation@plt>
  pop    %rcx
  pop    %rsi
  cmpq   $0x0,0x8(%rsp)
  jle    L0
  cmpq   $0x0,0x10(%rsp)
  jg     L7
L0:
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    0x28(%rsp),%rax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  push   %rax
  lea    0x28(%rsp),%r9
  call   <test_orientation@plt>
  pop    %rax
  pop    %rdx
  cmpq   $0x0,0x18(%rsp)
  jle    L33
  cmpq   $0x0,0x20(%rsp)
  jg     L56
L33:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L7:
  lea    D10(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L33
  nopl   0x0(%rax)
L56:
  lea    D3(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L33
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D10: s/S

tool: D3: S/s

assistant: ```c
void get_orientation_SS(long i, long j, long **seidx, char **AtomName, double **xyz, char *type) {
  long n1 = 0, n2 = 0, n3 = 0, n4 = 0;
  test_orientation(i, j, seidx, AtomName, xyz, &n1, &n2);
  if (n1 > 0 && n2 > 0) {
    strcpy(type, "s/S");
  } else {
    test_orientation(j, i, seidx, AtomName, xyz, &n3, &n4);
    if (n3 > 0 && n4 > 0)
      strcpy(type, "S/s");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_orientation_SS>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x30(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  push   %rax
  lea    0x18(%rsp),%r9
  call   <test_orientation@plt>
  pop    %rcx
  pop    %rsi
  cmpq   $0x0,0x8(%rsp)
  jle    L49
  cmpq   $0x0,0x10(%rsp)
  jg     L15
L49:
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    0x28(%rsp),%rax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  push   %rax
  lea    0x28(%rsp),%r9
  call   <test_orientation@plt>
  pop    %rax
  pop    %rdx
  cmpq   $0x0,0x18(%rsp)
  jle    L45
  cmpq   $0x0,0x20(%rsp)
  jg     L66
L45:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L15:
  lea    D3(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L45
  nopl   0x0(%rax)
L66:
  lea    D10(%rip),%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L45
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D10
data_type: string

tool: D3: s/S

tool: D10: S/s

assistant: ```c
void get_orientation_SS(long i, long j, long **seidx, char **AtomName, double **xyz, char *type) {
  long n1 = 0, n2 = 0, n3 = 0, n4 = 0;
  test_orientation(i, j, seidx, AtomName, xyz, &n1, &n2);
  if (n1 > 0 && n2 > 0) {
    strcpy(type, "s/S");
  } else {
    test_orientation(j, i, seidx, AtomName, xyz, &n3, &n4);
    if (n3 > 0 && n4 > 0)
      strcpy(type, "S/s");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<upscale_1_5x_generic_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void upscale_1_5x_generic_output(void *data, unsigned *out_width, unsigned *out_height, unsigned width, unsigned height) {
  *out_width = width + (width >> 1);
  *out_height = height + (height >> 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<upscale_1_5x_generic_output>:
  endbr64
  mov    %ecx,%eax
  shr    %eax
  lea    (%rax,%rcx,1),%eax
  mov    %eax,(%rsi)
  mov    %r8d,%eax
  shr    %eax
  lea    (%rax,%r8,1),%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void upscale_1_5x_generic_output(void *data, unsigned *out_width, unsigned *out_height, unsigned width, unsigned height) {
  *out_width = width + (width >> 1);
  *out_height = height + (height >> 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<upscale_1_5x_generic_output>:
  endbr64
  mov    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  mov    %eax,(%rsi)
  mov    %r8d,%eax
  shr    %eax
  add    %r8d,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void upscale_1_5x_generic_output(void *data, unsigned *out_width, unsigned *out_height, unsigned width, unsigned height) {
  *out_width = width + (width >> 1);
  *out_height = height + (height >> 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<upscale_1_5x_generic_output>:
  endbr64
  mov    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  mov    %eax,(%rsi)
  mov    %r8d,%eax
  shr    %eax
  add    %r8d,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void upscale_1_5x_generic_output(void *data, unsigned *out_width, unsigned *out_height, unsigned width, unsigned height) {
  *out_width = width + (width >> 1);
  *out_height = height + (height >> 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CountNumWordsInString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L56:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L22
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L22:
  cmpl   $0x0,-0xc(%rbp)
  je     L54
  movl   $0x1,-0xc(%rbp)
  jmp    L30
L54:
  addl   $0x1,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
L30:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int CountNumWordsInString(const char *InString) {
  bool prev_was_letter = false;
  int wordcount = 0;
  for (int i = 0; InString[i] != '\0'; i++) {
    if (InString[i] == ' ') {
      prev_was_letter = false;
    } else if (prev_was_letter) {
      prev_was_letter = true;
    } else {
      wordcount++;
      prev_was_letter = true;
    }
  }
  return wordcount;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CountNumWordsInString>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  add    $0x1,%rdi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x1,%r8d
  jmp    L31
L59:
  mov    %esi,%edx
L51:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L8
L31:
  cmp    $0x20,%al
  je     L59
  test   %edx,%edx
  jne    L51
  add    $0x1,%ecx
  mov    %r8d,%edx
  jmp    L51
L48:
  mov    $0x0,%ecx
L8:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int CountNumWordsInString(const char *InString) {
  bool prev_was_letter = false;
  int wordcount = 0;
  for (int i = 0; InString[i] != '\0'; i++) {
    if (InString[i] == ' ') {
      prev_was_letter = false;
    } else if (prev_was_letter) {
      prev_was_letter = true;
    } else {
      wordcount++;
      prev_was_letter = true;
    }
  }
  return wordcount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CountNumWordsInString>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L46
  add    $0x1,%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L30:
  test   %edx,%edx
  jne    L27
  add    $0x1,%r8d
  mov    $0x1,%edx
L27:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L21
L1:
  cmp    $0x20,%al
  jne    L30
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  xor    %edx,%edx
  test   %al,%al
  jne    L1
L21:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L46:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CountNumWordsInString(const char *InString) {
  bool prev_was_letter = false;
  int wordcount = 0;
  for (int i = 0; InString[i] != '\0'; i++) {
    if (InString[i] == ' ') {
      prev_was_letter = false;
    } else if (prev_was_letter) {
      prev_was_letter = true;
    } else {
      wordcount++;
      prev_was_letter = true;
    }
  }
  return wordcount;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CountNumWordsInString>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L36
  add    $0x1,%rdi
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L53:
  test   %edx,%edx
  jne    L8
  add    $0x1,%r8d
  mov    $0x1,%edx
L8:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L47
L59:
  cmp    $0x20,%al
  jne    L53
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  xor    %edx,%edx
  test   %al,%al
  jne    L59
L47:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L36:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CountNumWordsInString(const char *InString) {
  bool prev_was_letter = false;
  int wordcount = 0;
  for (int i = 0; InString[i] != '\0'; i++) {
    if (InString[i] == ' ') {
      prev_was_letter = false;
    } else if (prev_was_letter) {
      prev_was_letter = true;
    } else {
      wordcount++;
      prev_was_letter = true;
    }
  }
  return wordcount;
}
```