ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  lea    D30(%rip),%r14
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  mov    %r12,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L38
  nopl   0x0(%rax)
L48:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %edx,%ebx
  jl     L48
L38:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <quicksort@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L1
  xor    %ebx,%ebx
  lea    D15(%rip),%rbp
  xchg   %ax,%ax
L34:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L34
L1:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D37
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D6: Enter number of elements of array (less than 10)

tool: D30: Enter element number %d: 

tool: D37: %d

tool: D15: %d 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[10], i, j, n;
  printf("Enter number of elements of array (less than 10)\n");
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    printf("Enter element number %d: ", i + 1);
    scanf("%d", &a[i]);
  }
  quicksort(a, 0, n - 1);
  printf("\n");
  for (i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strength_test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L12
  movl   $0x2,-0x4(%rbp)
  jmp    L25
L12:
  movl   $0x0,-0x4(%rbp)
L8:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strength_test4(int *data) {
  int i;
  if (data[1]) {
    i = 2;
    goto here;
  }
  i = 0;
  do {
    i = i + 1;
  here:
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strength_test4>:
  endbr64
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  jne    L23
L16:
  add    $0x1,%eax
L8:
  movslq 0x8(%rdi),%rdx
  movl   $0x2,(%rdi,%rdx,4)
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,4),%edx
  cmp    0xc(%rdi),%edx
  jl     L16
  ret
L23:
  mov    $0x2,%eax
  jmp    L8
```

assistant: ```c
void strength_test4(int *data) {
  int i;
  if (data[1]) {
    i = 2;
    goto here;
  }
  i = 0;
  do {
    i = i + 1;
  here:
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strength_test4>:
  endbr64
  cmpl   $0x1,0x4(%rdi)
  movslq 0x8(%rdi),%rcx
  sbb    %eax,%eax
  and    $0xffffffeb,%eax
  add    $0x2a,%eax
  cmpl   $0x1,0x4(%rdi)
  movl   $0x2,(%rdi,%rcx,4)
  sbb    %edx,%edx
  add    $0x2,%edx
  cmp    %eax,0xc(%rdi)
  jle    L17
L3:
  add    $0x1,%edx
  movslq 0x8(%rdi),%rcx
  lea    (%rdx,%rdx,4),%eax
  movl   $0x2,(%rdi,%rcx,4)
  lea    (%rdx,%rax,4),%eax
  cmp    %eax,0xc(%rdi)
  jg     L3
L17:
  ret
```

assistant: ```c
void strength_test4(int *data) {
  int i;
  if (data[1]) {
    i = 2;
    goto here;
  }
  i = 0;
  do {
    i = i + 1;
  here:
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strength_test4>:
  endbr64
  cmpl   $0x1,0x4(%rdi)
  movslq 0x8(%rdi),%rcx
  sbb    %eax,%eax
  and    $0xffffffeb,%eax
  add    $0x2a,%eax
  cmpl   $0x1,0x4(%rdi)
  movl   $0x2,(%rdi,%rcx,4)
  sbb    %edx,%edx
  add    $0x2,%edx
  cmp    %eax,0xc(%rdi)
  jle    L5
L9:
  add    $0x1,%edx
  movslq 0x8(%rdi),%rcx
  lea    (%rdx,%rdx,4),%eax
  movl   $0x2,(%rdi,%rcx,4)
  lea    (%rdx,%rax,4),%eax
  cmp    %eax,0xc(%rdi)
  jg     L9
L5:
  ret
```

assistant: ```c
void strength_test4(int *data) {
  int i;
  if (data[1]) {
    i = 2;
    goto here;
  }
  i = 0;
  do {
    i = i + 1;
  here:
    data[data[2]] = 2;
  } while (i * 21 < data[3]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_read_frame_extended>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L52
L30:
  mov    -0x1c(%rbp),%eax
  sub    $0xdfff0,%eax
  mov    %eax,%eax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %dl,-0x15(%rbp,%rax,1)
  addl   $0x1,-0x1c(%rbp)
L52:
  cmpl   $0xc,-0x1c(%rbp)
  jle    L30
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L53:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L36
  mov    $0x0,%eax
  jmp    L7
L36:
  addl   $0x1,-0x1c(%rbp)
L29:
  cmpl   $0xc,-0x1c(%rbp)
  jle    L53
  mov    $0x1,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
int test_read_frame_extended(volatile unsigned char write_field[]) {
  volatile unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((volatile unsigned char *)(0xfff20000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_read_frame_extended>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xfff20010,%esi
L20:
  lea    (%rax,%rsi,1),%rdx
  movzbl (%rdx),%ecx
  movslq %eax,%rdx
  mov    %cl,0xb(%rsp,%rdx,1)
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L20
  mov    $0x0,%eax
L37:
  movslq %eax,%rdx
  movzbl 0xb(%rsp,%rdx,1),%ecx
  lea    (%rdi,%rax,1),%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%cl
  jne    L14
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L37
  mov    $0x1,%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x28,%rsp
  ret
L14:
  mov    $0x0,%eax
  jmp    L15
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_read_frame_extended(volatile unsigned char write_field[]) {
  volatile unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((volatile unsigned char *)(0xfff20000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_read_frame_extended>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xfff20010,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  nopl   (%rax)
L20:
  lea    (%rax,%rsi,1),%rdx
  movzbl (%rdx),%ecx
  movslq %eax,%rdx
  add    $0x1,%rax
  mov    %cl,0xb(%rsp,%rdx,1)
  cmp    $0xd,%rax
  jne    L20
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  movslq %eax,%rdx
  movzbl 0xb(%rsp,%rdx,1),%ecx
  lea    (%rdi,%rax,1),%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%cl
  jne    L33
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L21
  mov    $0x1,%eax
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %eax,%eax
  jmp    L35
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_read_frame_extended(volatile unsigned char write_field[]) {
  volatile unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((volatile unsigned char *)(0xfff20000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_read_frame_extended>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs 0xfff20010,%al
  mov    %al,0xb(%rsp)
  movabs 0xfff20011,%al
  mov    %al,0xc(%rsp)
  movabs 0xfff20012,%al
  mov    %al,0xd(%rsp)
  movabs 0xfff20013,%al
  mov    %al,0xe(%rsp)
  movabs 0xfff20014,%al
  mov    %al,0xf(%rsp)
  movabs 0xfff20015,%al
  mov    %al,0x10(%rsp)
  movabs 0xfff20016,%al
  mov    %al,0x11(%rsp)
  movabs 0xfff20017,%al
  mov    %al,0x12(%rsp)
  movabs 0xfff20018,%al
  mov    %al,0x13(%rsp)
  movabs 0xfff20019,%al
  mov    %al,0x14(%rsp)
  movabs 0xfff2001a,%al
  mov    %al,0x15(%rsp)
  movabs 0xfff2001b,%al
  mov    %al,0x16(%rsp)
  movabs 0xfff2001c,%al
  mov    %al,0x17(%rsp)
  movzbl 0xb(%rsp),%ecx
  movzbl (%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0xc(%rsp),%ecx
  movzbl 0x1(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0xd(%rsp),%ecx
  movzbl 0x2(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0xe(%rsp),%ecx
  movzbl 0x3(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0xf(%rsp),%ecx
  movzbl 0x4(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x10(%rsp),%ecx
  movzbl 0x5(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x11(%rsp),%ecx
  movzbl 0x6(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x12(%rsp),%ecx
  movzbl 0x7(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x13(%rsp),%ecx
  movzbl 0x8(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x14(%rsp),%ecx
  movzbl 0x9(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x15(%rsp),%ecx
  movzbl 0xa(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x16(%rsp),%ecx
  movzbl 0xb(%rdi),%eax
  cmp    %al,%cl
  jne    L82
  movzbl 0x17(%rsp),%ecx
  movzbl 0xc(%rdi),%eax
  cmp    %al,%cl
  sete   %al
  movzbl %al,%eax
L116:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L82:
  xor    %eax,%eax
  jmp    L116
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_read_frame_extended(volatile unsigned char write_field[]) {
  volatile unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((volatile unsigned char *)(0xfff20000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L15
L12:
  movsd  -0x30(%rbp),%xmm1
  movsd  D30(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  D55(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D45(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  lea    -0x30(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D30
data_type: f32[2]
name: read_data
arguments: data_label: D55
data_type: byte[8]
name: read_data
arguments: data_label: D45
data_type: f32[2]
name: read_data
arguments: data_label: D10
data_type: f32[2]
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D2
data_type: string

tool: {"D30": [0.0,3.8515625]}

tool: {"D55": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D45": [0.0,3.6015625]}

tool: {"D10": [0.0,1.75]}

tool: D34: %.3lf


tool: D2: %lf %lf

assistant: ```c
int main() {
  double n, r, area, degree, red;
  while (scanf("%lf %lf", &r, &n) == 2) {
    degree = 360 / n;
    red = sin(degree * 2 * acos(0.0) / 180);
    area = .5 * n * r * r * red;
    printf("%.3lf\n", area);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rbp
  jmp    L21
L7:
  mov    0x8(%rsp),%rbx
  movsd  D49(%rip),%xmm0
  movq   %rbx,%xmm3
  divsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm0
  mulsd  D13(%rip),%xmm0
  divsd  D58(%rip),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm1
  movq   %rbx,%xmm0
  mulsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  lea    D16(%rip),%rdi
  call   <printf@plt>
L21:
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D49
type_guessed: f32[2]
name: retrieve_data
arguments: label: D13
type_guessed: byte[8]
name: retrieve_data
arguments: label: D58
type_guessed: f32[2]
name: retrieve_data
arguments: label: D33
type_guessed: f32[2]
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D26: %lf %lf

tool: {"D49": [0.0,3.8515625]}

tool: {"D13": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D58": [0.0,3.6015625]}

tool: {"D33": [0.0,1.75]}

tool: D16: %.3lf


assistant: ```c
int main() {
  double n, r, area, degree, red;
  while (scanf("%lf %lf", &r, &n) == 2) {
    degree = 360 / n;
    red = sin(degree * 2 * acos(0.0) / 180);
    area = .5 * n * r * r * red;
    printf("%.3lf\n", area);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%r12
  lea    0x20(%rsp),%rbp
  jmp    L8
  nop
L19:
  movsd  0x18(%rsp),%xmm1
  movsd  D29(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  addsd  %xmm0,%xmm0
  mulsd  D38(%rip),%xmm0
  divsd  D9(%rip),%xmm0
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D54(%rip),%xmm1
  movsd  0x20(%rsp),%xmm2
  lea    D13(%rip),%rdi
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
L8:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D29
datatype: f32[2]
name: unpack_data
arguments: label: D38
datatype: byte[8]
name: unpack_data
arguments: label: D9
datatype: f32[2]
name: unpack_data
arguments: label: D54
datatype: f32[2]
name: unpack_data
arguments: label: D13
datatype: string

tool: D4: %lf %lf

tool: {"D29": [0.0,3.8515625]}

tool: {"D38": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D9": [0.0,3.6015625]}

tool: {"D54": [0.0,1.75]}

tool: D13: %.3lf


assistant: ```c
int main() {
  double n, r, area, degree, red;
  while (scanf("%lf %lf", &r, &n) == 2) {
    degree = 360 / n;
    red = sin(degree * 2 * acos(0.0) / 180);
    area = .5 * n * r * r * red;
    printf("%.3lf\n", area);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D47(%rip),%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%r12
  lea    0x20(%rsp),%rbp
  jmp    L22
  nop
L15:
  movsd  0x18(%rsp),%xmm1
  movsd  D45(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  addsd  %xmm0,%xmm0
  mulsd  D23(%rip),%xmm0
  divsd  D35(%rip),%xmm0
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D9(%rip),%xmm1
  movsd  0x20(%rsp),%xmm2
  lea    D26(%rip),%rdi
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
L22:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D47
type_guessed: string
name: read_data
arguments: data_tag: D45
type_guessed: f32[2]
name: read_data
arguments: data_tag: D23
type_guessed: byte[8]
name: read_data
arguments: data_tag: D35
type_guessed: f32[2]
name: read_data
arguments: data_tag: D9
type_guessed: f32[2]
name: read_data
arguments: data_tag: D26
type_guessed: string

tool: D47: %lf %lf

tool: {"D45": [0.0,3.8515625]}

tool: {"D23": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D35": [0.0,3.6015625]}

tool: {"D9": [0.0,1.75]}

tool: D26: %.3lf


assistant: ```c
int main() {
  double n, r, area, degree, red;
  while (scanf("%lf %lf", &r, &n) == 2) {
    degree = 360 / n;
    red = sin(degree * 2 * acos(0.0) / 180);
    area = .5 * n * r * r * red;
    printf("%.3lf\n", area);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ocfs2_find_next_bit_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movb   $0xff,-0x1d(%rbp)
  movzbl -0x1d(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L115
L42:
  mov    -0x30(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  shll   $0x3,-0x1c(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  neg    %eax
  and    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    %edx,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ffs@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L25
  mov    -0x30(%rbp),%eax
  and    $0xfffffff8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  jmp    L115
L25:
  addq   $0x1,-0x8(%rbp)
  addl   $0x8,-0x1c(%rbp)
  jmp    L53
L59:
  addq   $0x1,-0x8(%rbp)
  addl   $0x8,-0x1c(%rbp)
L53:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jae    L58
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1d(%rbp)
  je     L59
L58:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jb     L1
  mov    -0x2c(%rbp),%eax
  jmp    L115
L1:
  mov    -0x1c(%rbp),%eax
  lea    0x8(%rax),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  jbe    L16
  mov    -0x2c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  add    $0x8,%eax
  mov    %eax,%ecx
  shrl   %cl,-0x18(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x18(%rbp),%edx
  and    %edx,%eax
  not    %eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ffs@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  mov    -0x2c(%rbp),%eax
  jmp    L115
L0:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
L115:
  leave
  ret
```

assistant: ```c
int ocfs2_find_next_bit_clear(void *addr, int size, int offset) {
  unsigned char *p;
  int set = 0, d0;
  unsigned int bit = offset & 7, res = 0;
  unsigned char tilde = ~0;
  unsigned int mask = 0U | tilde;
  if (size == 0)
    return 0;
  res = offset >> 3;
  p = ((unsigned char *)addr) + res;
  res <<= 3;
  if (bit) {
    set = ffs(~*p & ~((1 << bit) - 1) & mask);
    if (set)
      return (offset & ~7) + set - 1;
    p++;
    res += 8;
  }
  while ((size > res) && (*p == tilde)) {
    p++;
    res += 8;
  }
  if (res >= size)
    return size;
  if ((res + 8) > size)
    mask >>= 8 - (size - res);
  d0 = ffs(~(*p & mask));
  if (d0 == 0)
    return size;
  return (res + d0 - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ocfs2_find_next_bit_clear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  test   %esi,%esi
  je     L95
  mov    %edx,%ebp
  mov    %edx,%eax
  sar    $0x3,%eax
  lea    (%rdi,%rax,1),%rbx
  mov    %edx,%r12d
  and    $0xfffffff8,%r12d
  mov    %edx,%ecx
  and    $0x7,%ecx
  jne    L70
L56:
  mov    %r13d,%eax
  cmp    %r13d,%r12d
  jae    L95
L35:
  cmpb   $0xff,(%rbx)
  jne    L34
  add    $0x1,%rbx
  add    $0x8,%r12d
  cmp    %eax,%r12d
  jb     L35
  jmp    L95
L70:
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%edi
  neg    %edi
  movzbl (%rbx),%eax
  not    %eax
  and    %eax,%edi
  movzbl %dil,%edi
  call   <ffs@plt>
  add    $0x1,%rbx
  add    $0x8,%r12d
  test   %eax,%eax
  je     L56
  and    $0xfffffff8,%ebp
  lea    -0x1(%rax,%rbp,1),%r13d
  jmp    L95
L34:
  cmp    %r12d,%eax
  jbe    L95
  lea    0x8(%r12),%edx
  mov    $0xff,%edi
  cmp    %eax,%edx
  jbe    L68
  mov    %r12d,%edx
  sub    %eax,%edx
  lea    0x8(%rdx),%ecx
  shr    %cl,%edi
L68:
  and    (%rbx),%dil
  not    %edi
  movzbl %dil,%edi
  call   <ffs@plt>
  lea    -0x1(%r12,%rax,1),%edx
  test   %eax,%eax
  cmovne %edx,%r13d
L95:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ocfs2_find_next_bit_clear(void *addr, int size, int offset) {
  unsigned char *p;
  int set = 0, d0;
  unsigned int bit = offset & 7, res = 0;
  unsigned char tilde = ~0;
  unsigned int mask = 0U | tilde;
  if (size == 0)
    return 0;
  res = offset >> 3;
  p = ((unsigned char *)addr) + res;
  res <<= 3;
  if (bit) {
    set = ffs(~*p & ~((1 << bit) - 1) & mask);
    if (set)
      return (offset & ~7) + set - 1;
    p++;
    res += 8;
  }
  while ((size > res) && (*p == tilde)) {
    p++;
    res += 8;
  }
  if (res >= size)
    return size;
  if ((res + 8) > size)
    mask >>= 8 - (size - res);
  d0 = ffs(~(*p & mask));
  if (d0 == 0)
    return size;
  return (res + d0 - 1);
}
```