user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D56(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D101(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D116(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D132(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x38(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D13(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D66
type_infered: string
name: retrieve_data
arguments: data_tag: D95
type_infered: string
name: retrieve_data
arguments: data_tag: D132
type_infered: string
name: retrieve_data
arguments: data_tag: D101
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D116
type_infered: string
name: retrieve_data
arguments: data_tag: D13
type_infered: f64
name: retrieve_data
arguments: data_tag: D97
type_infered: string

tool: {"D56": [0x52,0xb8,0x1e,0x85,0xeb,0x3f,0x8f,0xc0]}

tool: D66: Hello, you will be inputing 5 different values and this program will give you 
the average of these numbers.

tool: D95: 
Please input any number for the first value:

tool: D132: %lf

tool: D101: 
Please input any number for the second value:

tool: D8: 
Please input any number for the third value:

tool: D9: 
Please input any number for the fourth value:

tool: D116: 
Please input any number for the fifth value:

tool: D13: 5

tool: D97: 
The average of all of the numbers is %.3lf



assistant: ```c
int main() {
  double a1, a2, a3, a4, a5, avg;
  a1 = a2 = a3 = a4 = a5 = -999.99;
  avg = 0;
  printf("Hello, you will be inputing 5 different values and this program will give you \nthe average of these numbers.\n");
  printf("\nPlease input any number for the first value:");
  scanf("%lf", &a1);
  printf("\nPlease input any number for the second value:");
  scanf("%lf", &a2);
  printf("\nPlease input any number for the third value:");
  scanf("%lf", &a3);
  printf("\nPlease input any number for the fourth value:");
  scanf("%lf", &a4);
  printf("\nPlease input any number for the fifth value:");
  scanf("%lf", &a5);
  avg += a1;
  avg += a2;
  avg += a3;
  avg += a4;
  avg += a5;
  avg /= 5.000;
  printf("\nThe average of all of the numbers is %.3lf\n\n", avg);
  return 0;
}
```