ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setRootBrackets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%edi
  movq   %xmm0,%rbp
  movq   %xmm1,%rbx
  movq   %xmm2,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  movsd  D5(%rip),%xmm0
  call   <pow@plt>
  movq   %r14,%xmm3
  movq   %r14,%xmm1
  subsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm0
  movq   %rbp,%xmm4
  maxsd  %xmm1,%xmm4
  movsd  %xmm4,0x0(%r13)
  movq   %rbx,%xmm5
  minsd  %xmm0,%xmm5
  movsd  %xmm5,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 2

assistant: ```c
int setRootBrackets(const int k, const int i, const double Tmin, const double Tmax, const double T, double *Ta, double *Tb) {
  double dT = 1.0;
  dT *= pow(2.0, i);
  *Ta = T - dT;
  *Tb = T + dT;
  *Ta = ((Tmin) > (T - dT) ? (Tmin) : (T - dT));
  *Tb = ((Tmax) < (T + dT) ? (Tmax) : (T + dT));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setRootBrackets>:
  endbr64
  push   %rbp
  mov    %esi,%edi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  movapd %xmm2,%xmm4
  subsd  %xmm0,%xmm4
  addsd  %xmm2,%xmm0
  maxsd  %xmm4,%xmm3
  minsd  %xmm0,%xmm1
  movsd  %xmm3,0x0(%rbp)
  movsd  %xmm1,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: f64

tool: D7: 2

assistant: ```c
int setRootBrackets(const int k, const int i, const double Tmin, const double Tmax, const double T, double *Ta, double *Tb) {
  double dT = 1.0;
  dT *= pow(2.0, i);
  *Ta = T - dT;
  *Tb = T + dT;
  *Ta = ((Tmin) > (T - dT) ? (Tmin) : (T - dT));
  *Tb = ((Tmax) < (T + dT) ? (Tmax) : (T + dT));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setRootBrackets>:
  endbr64
  push   %rbp
  mov    %esi,%edi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  movapd %xmm2,%xmm4
  subsd  %xmm0,%xmm4
  addsd  %xmm2,%xmm0
  maxsd  %xmm4,%xmm3
  minsd  %xmm0,%xmm1
  movsd  %xmm3,0x0(%rbp)
  movsd  %xmm1,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: f64

tool: D0: 2

assistant: ```c
int setRootBrackets(const int k, const int i, const double Tmin, const double Tmax, const double T, double *Ta, double *Tb) {
  double dT = 1.0;
  dT *= pow(2.0, i);
  *Ta = T - dT;
  *Tb = T + dT;
  *Ta = ((Tmin) > (T - dT) ? (Tmin) : (T - dT));
  *Tb = ((Tmax) < (T + dT) ? (Tmax) : (T + dT));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L33
L25:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x7d2,%eax
  jne    L30
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L30:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L33:
  cmpl   $0x1,-0xc(%rbp)
  je     L25
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D18
type_infered: string

tool: D12: %d

tool: D17: Acesso Permitido


tool: D18: Senha Invalida


assistant: ```c
int main() {
  int n, i;
  for (i = 1; i == 1;) {
    scanf("%d", &n);
    if (n == 2002) {
      printf("Acesso Permitido\n");
      break;
    } else {
      printf("Senha Invalida\n");
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    D27(%rip),%rbx
  lea    D19(%rip),%r12
  jmp    L24
L27:
  mov    %r12,%rdi
  call   <printf@plt>
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7d2,0x4(%rsp)
  jne    L27
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D8
data_type: string

tool: D27: %d

tool: D19: Senha Invalida


tool: D8: Acesso Permitido


assistant: ```c
int main() {
  int n, i;
  for (i = 1; i == 1;) {
    scanf("%d", &n);
    if (n == 2002) {
      printf("Acesso Permitido\n");
      break;
    } else {
      printf("Senha Invalida\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D20(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L25
  nopl   0x0(%rax)
L16:
  mov    %r12,%rdi
  call   <printf@plt>
L25:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7d2,0x4(%rsp)
  jne    L16
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D20
datatype: string
name: unpack_data
arguments: label: D25
datatype: string

tool: D27: Senha Invalida


tool: D20: %d

tool: D25: Acesso Permitido


assistant: ```c
int main() {
  int n, i;
  for (i = 1; i == 1;) {
    scanf("%d", &n);
    if (n == 2002) {
      printf("Acesso Permitido\n");
      break;
    } else {
      printf("Senha Invalida\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L10
  nopl   0x0(%rax)
L5:
  mov    %r12,%rdi
  call   <printf@plt>
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7d2,0x4(%rsp)
  jne    L5
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D5: Senha Invalida


tool: D27: %d

tool: D15: Acesso Permitido


assistant: ```c
int main() {
  int n, i;
  for (i = 1; i == 1;) {
    scanf("%d", &n);
    if (n == 2002) {
      printf("Acesso Permitido\n");
      break;
    } else {
      printf("Senha Invalida\n");
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<local_parse_secname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x1,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L74
L63:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L20
  addq   $0x1,-0x10(%rbp)
L20:
  addq   $0x1,-0x18(%rbp)
L74:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L63
L59:
  cmpq   $0x0,-0x10(%rbp)
  jne    L94
  mov    $0x0,%eax
  jmp    L60
L94:
  mov    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x1,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L80
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L90
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L90:
  addq   $0x1,-0x18(%rbp)
L80:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L8
L31:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L60:
  leave
  ret
```

assistant: ```c
char *local_parse_secname(const char *line) {
  size_t n = 1;
  size_t secname_len = 0;
  char *rtn;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n]))
      secname_len++;
    n++;
  }
  if (secname_len == 0)
    return NULL;
  rtn = xmalloc(sizeof(char) * (secname_len + 1));
  n = 1;
  secname_len = 0;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n])) {
      rtn[secname_len] = line[n];
      secname_len++;
    }
    n++;
  }
  rtn[secname_len] = '\0';
  return rtn;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<local_parse_secname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L9
  cmp    $0x5d,%dil
  je     L9
  lea    0x2(%rbp),%rbx
  mov    $0x0,%r12d
L99:
  movsbl %dil,%edi
  call   <isalnum@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L95
  cmp    $0x5d,%dil
  jne    L99
L95:
  mov    $0x0,%r13d
  test   %r12,%r12
  je     L82
  lea    0x1(%r12),%edi
  call   <xmalloc@plt>
  mov    %rax,%r13
  movzbl 0x1(%rbp),%edi
  test   %dil,%dil
  je     L84
  cmp    $0x5d,%dil
  je     L84
  lea    0x1(%rbp),%rbx
  mov    $0x0,%ebp
  jmp    L91
L10:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L64
  cmp    $0x5d,%dil
  je     L64
L91:
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L10
  movzbl (%rbx),%eax
  mov    %al,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
  jmp    L10
L84:
  mov    $0x0,%ebp
L64:
  movb   $0x0,0x0(%r13,%rbp,1)
L82:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%r13d
  jmp    L82
```

assistant: ```c
char *local_parse_secname(const char *line) {
  size_t n = 1;
  size_t secname_len = 0;
  char *rtn;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n]))
      secname_len++;
    n++;
  }
  if (secname_len == 0)
    return NULL;
  rtn = xmalloc(sizeof(char) * (secname_len + 1));
  n = 1;
  secname_len = 0;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n])) {
      rtn[secname_len] = line[n];
      secname_len++;
    }
    n++;
  }
  rtn[secname_len] = '\0';
  return rtn;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<local_parse_secname>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L38
  cmp    $0x5d,%dil
  lea    0x2(%rbp),%rbx
  setne  %al
  xor    %r12d,%r12d
  test   %al,%al
  je     L38
  xchg   %ax,%ax
L48:
  call   <isalnum@plt>
  movsbl (%rbx),%edi
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L20
  cmp    $0x5d,%dil
  jne    L48
L20:
  test   %r12,%r12
  je     L38
  lea    0x1(%r12),%edi
  call   <xmalloc@plt>
  movsbl 0x1(%rbp),%edi
  mov    %rax,%r12
  cmp    $0x5d,%dil
  je     L23
  test   %dil,%dil
  je     L23
  lea    0x1(%rbp),%rbx
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L78:
  call   <isalnum@plt>
  test   %rax,%rax
  je     L52
  movzbl (%rbx),%eax
  mov    %al,(%r12,%rbp,1)
  add    $0x1,%rbp
L52:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L98
  cmp    $0x5d,%dil
  jne    L78
L98:
  add    %r12,%rbp
L92:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
L23:
  mov    %r12,%rbp
  jmp    L92
```

assistant: ```c
char *local_parse_secname(const char *line) {
  size_t n = 1;
  size_t secname_len = 0;
  char *rtn;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n]))
      secname_len++;
    n++;
  }
  if (secname_len == 0)
    return NULL;
  rtn = xmalloc(sizeof(char) * (secname_len + 1));
  n = 1;
  secname_len = 0;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n])) {
      rtn[secname_len] = line[n];
      secname_len++;
    }
    n++;
  }
  rtn[secname_len] = '\0';
  return rtn;
}
```
user: Translate the below assembly code into C programming language:

```asm
<local_parse_secname>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L53
  cmp    $0x5d,%dil
  lea    0x2(%rbp),%rbx
  setne  %al
  xor    %r12d,%r12d
  test   %al,%al
  je     L53
  xchg   %ax,%ax
L31:
  call   <isalnum@plt>
  movsbl (%rbx),%edi
  cmp    $0x1,%rax
  sbb    $0xffffffffffffffff,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L64
  cmp    $0x5d,%dil
  jne    L31
L64:
  test   %r12,%r12
  je     L53
  lea    0x1(%r12),%edi
  call   <xmalloc@plt>
  movsbl 0x1(%rbp),%edi
  mov    %rax,%r12
  cmp    $0x5d,%dil
  je     L42
  test   %dil,%dil
  je     L42
  lea    0x1(%rbp),%rbx
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L110:
  call   <isalnum@plt>
  test   %rax,%rax
  je     L137
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  mov    %al,(%r12,%rbp,1)
  movsbl (%rbx),%edi
  add    $0x1,%rbp
  cmp    $0x5d,%dil
  je     L131
  test   %dil,%dil
  jne    L110
L131:
  add    %r12,%rbp
L94:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L137:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L131
  cmp    $0x5d,%dil
  jne    L110
  jmp    L131
  nopl   (%rax)
L53:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
L42:
  mov    %r12,%rbp
  jmp    L94
```

assistant: ```c
char *local_parse_secname(const char *line) {
  size_t n = 1;
  size_t secname_len = 0;
  char *rtn;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n]))
      secname_len++;
    n++;
  }
  if (secname_len == 0)
    return NULL;
  rtn = xmalloc(sizeof(char) * (secname_len + 1));
  n = 1;
  secname_len = 0;
  while ((line[n] != '\0') && (line[n] != ']')) {
    if (isalnum(line[n])) {
      rtn[secname_len] = line[n];
      secname_len++;
    }
    n++;
  }
  rtn[secname_len] = '\0';
  return rtn;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L10
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L14
L10:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D20: %d%d

tool: D6: %d


assistant: ```c
int main() {
  int a;
  int b;
  scanf("%d%d", &a, &b);
  if (a < b) {
    printf("%d\n", b);
  } else {
    printf("%d\n", a);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%eax
  cmp    %eax,%esi
  jge    L2
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D6: %d%d

tool: D2: %d


assistant: ```c
int main() {
  int a;
  int b;
  scanf("%d%d", &a, &b);
  if (a < b) {
    printf("%d\n", b);
  } else {
    printf("%d\n", a);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%esi
  jge    L11
  mov    %r8d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L11:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D16: %d%d

tool: D4: %d


assistant: ```c
int main() {
  int a;
  int b;
  scanf("%d%d", &a, &b);
  if (a < b) {
    printf("%d\n", b);
  } else {
    printf("%d\n", a);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%esi
  jge    L3
  mov    %r8d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D10
data_type: string

tool: D24: %d%d

tool: D10: %d


assistant: ```c
int main() {
  int a;
  int b;
  scanf("%d%d", &a, &b);
  if (a < b) {
    printf("%d\n", b);
  } else {
    printf("%d\n", a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trimstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L15:
  addq   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_whitespace@plt>
  test   %rax,%rax
  jne    L15
L31:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  jmp    L40
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  jmp    L65
L61:
  subq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L65:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_whitespace@plt>
  test   %rax,%rax
  jne    L61
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
char *trimstr(char *str) {
  char *src = str;
  char *dist = str;
  for (; *src != '\0' && is_whitespace(*src); ++src)
    ;
  if (*src == '\0') {
    dist[0] = '\0';
    return str;
  }
  for (; *src != '\0'; ++src, ++dist)
    *dist = *src;
  while (is_whitespace(*src))
    --src, --dist;
  dist[1] = '\0';
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trimstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movzbl (%rdi),%edi
  mov    %r12,%rbx
  test   %dil,%dil
  je     L70
L8:
  movsbl %dil,%edi
  call   <is_whitespace@plt>
  test   %rax,%rax
  je     L39
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
L70:
  movb   $0x0,(%r12)
  jmp    L61
L39:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L70
  mov    %r12,%rbp
L60:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbx
  add    $0x1,%rbp
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L60
L4:
  movsbl (%rbx),%edi
  call   <is_whitespace@plt>
  test   %rax,%rax
  je     L75
  sub    $0x1,%rbx
  sub    $0x1,%rbp
  jmp    L4
L75:
  movb   $0x0,0x1(%rbp)
L61:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *trimstr(char *str) {
  char *src = str;
  char *dist = str;
  for (; *src != '\0' && is_whitespace(*src); ++src)
    ;
  if (*src == '\0') {
    dist[0] = '\0';
    return str;
  }
  for (; *src != '\0'; ++src, ++dist)
    *dist = *src;
  while (is_whitespace(*src))
    --src, --dist;
  dist[1] = '\0';
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trimstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %r12,%rbx
  test   %dil,%dil
  jne    L23
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L32:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L8
L23:
  call   <is_whitespace@plt>
  test   %rax,%rax
  jne    L32
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L8
  mov    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rbx
  mov    %dil,0x0(%rbp)
  add    $0x1,%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L49
  call   <is_whitespace@plt>
  test   %rax,%rax
  je     L5
  cs nopw 0x0(%rax,%rax,1)
L11:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  sub    $0x1,%rbp
  call   <is_whitespace@plt>
  test   %rax,%rax
  jne    L11
L5:
  movb   $0x0,0x1(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
char *trimstr(char *str) {
  char *src = str;
  char *dist = str;
  for (; *src != '\0' && is_whitespace(*src); ++src)
    ;
  if (*src == '\0') {
    dist[0] = '\0';
    return str;
  }
  for (; *src != '\0'; ++src, ++dist)
    *dist = *src;
  while (is_whitespace(*src))
    --src, --dist;
  dist[1] = '\0';
  return str;
}
```