ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x61,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    $0x3,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcat@plt>
  cmp    $0x2,%eax
  jne    L36
  movzbl -0xb(%rbp),%eax
  cmp    $0x61,%al
  jne    L36
  movzbl -0xa(%rbp),%eax
  cmp    $0x62,%al
  jne    L36
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  je     L12
L36:
  mov    $0x1,%eax
  jmp    L16
L12:
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: b

assistant: ```c
int main(void) {
  char buf[3] = "a";
  return !(strlcat(buf, "b", sizeof(buf)) == 2 && buf[0] == 'a' && buf[1] == 'b' && buf[2] == '\0');
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x61,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x5(%rsp),%rdi
  mov    $0x3,%edx
  lea    D7(%rip),%rsi
  call   <strlcat@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x2,%edx
  je     L4
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L4:
  cmpb   $0x61,0x5(%rsp)
  jne    L13
  cmpb   $0x62,0x6(%rsp)
  jne    L13
  cmpb   $0x0,0x7(%rsp)
  setne  %al
  movzbl %al,%eax
  jmp    L13
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string

tool: D7: b

assistant: ```c
int main(void) {
  char buf[3] = "a";
  return !(strlcat(buf, "b", sizeof(buf)) == 2 && buf[0] == 'a' && buf[1] == 'b' && buf[2] == '\0');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edx
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdi
  mov    $0x61,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <strlcat@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x2,%r8d
  je     L3
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L3:
  cmpb   $0x61,0x5(%rsp)
  jne    L13
  cmpb   $0x62,0x6(%rsp)
  jne    L13
  xor    %eax,%eax
  cmpb   $0x0,0x7(%rsp)
  setne  %al
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: b

assistant: ```c
int main(void) {
  char buf[3] = "a";
  return !(strlcat(buf, "b", sizeof(buf)) == 2 && buf[0] == 'a' && buf[1] == 'b' && buf[2] == '\0');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%edx
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdi
  mov    $0x61,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  call   <strlcat@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x2,%r8d
  je     L45
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L45:
  cmpb   $0x61,0x5(%rsp)
  jne    L44
  cmpb   $0x62,0x6(%rsp)
  jne    L44
  xor    %eax,%eax
  cmpb   $0x0,0x7(%rsp)
  setne  %al
  jmp    L44
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: b

assistant: ```c
int main(void) {
  char buf[3] = "a";
  return !(strlcat(buf, "b", sizeof(buf)) == 2 && buf[0] == 'a' && buf[1] == 'b' && buf[2] == '\0');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vector_fmul_window_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x40(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  neg    %eax
  mov    %eax,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L14
L17:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  mulss  -0x8(%rbp),%xmm1
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x8(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  subl   $0x1,-0x14(%rbp)
L14:
  cmpl   $0x0,-0x18(%rbp)
  js     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vector_fmul_window_c(float *dst, const float *src0, const float *src1, const float *win, int len) {
  int i, j;
  dst += len;
  win += len;
  src0 += len;
  for (i = -len, j = len - 1; i < 0; i++, j--) {
    float s0 = src0[i];
    float s1 = src1[j];
    float wi = win[i];
    float wj = win[j];
    dst[i] = s0 * wj - s1 * wi;
    dst[j] = s0 * wi + s1 * wj;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<vector_fmul_window_c>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    %rcx,%rsi
  movslq %r8d,%r10
  shl    $0x2,%r10
  lea    (%rax,%r10,1),%rcx
  add    %r10,%rsi
  mov    %r8d,%eax
  neg    %eax
  test   %r8d,%r8d
  jle    L13
  cltq
  lea    -0x4(%r10),%rdx
  lea    (%r9,%r10,1),%r8
L2:
  movss  (%r8,%rax,4),%xmm0
  movss  (%rdi,%rdx,1),%xmm1
  movss  (%rsi,%rax,4),%xmm4
  movss  (%rsi,%rdx,1),%xmm3
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  subss  %xmm5,%xmm2
  movss  %xmm2,(%rcx,%rax,4)
  mulss  %xmm4,%xmm0
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rcx,%rdx,1)
  add    $0x1,%rax
  sub    $0x4,%rdx
  test   %eax,%eax
  js     L2
L13:
  ret
```

assistant: ```c
void vector_fmul_window_c(float *dst, const float *src0, const float *src1, const float *win, int len) {
  int i, j;
  dst += len;
  win += len;
  src0 += len;
  for (i = -len, j = len - 1; i < 0; i++, j--) {
    float s0 = src0[i];
    float s1 = src1[j];
    float wi = win[i];
    float wj = win[j];
    dst[i] = s0 * wj - s1 * wi;
    dst[j] = s0 * wi + s1 * wj;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vector_fmul_window_c>:
  endbr64
  movslq %r8d,%r10
  mov    %r8d,%eax
  mov    %rdx,%r9
  shl    $0x2,%r10
  neg    %eax
  add    %r10,%rdi
  add    %r10,%rcx
  test   %r8d,%r8d
  jle    L18
  cltq
  lea    -0x4(%r10),%rdx
  add    %r10,%rsi
  nopw   0x0(%rax,%rax,1)
L8:
  movss  (%rsi,%rax,4),%xmm0
  movss  (%r9,%rdx,1),%xmm1
  movss  (%rcx,%rax,4),%xmm4
  movss  (%rcx,%rdx,1),%xmm3
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm3,%xmm2
  mulss  %xmm4,%xmm5
  mulss  %xmm4,%xmm0
  mulss  %xmm3,%xmm1
  subss  %xmm5,%xmm2
  addss  %xmm1,%xmm0
  movss  %xmm2,(%rdi,%rax,4)
  add    $0x1,%rax
  movss  %xmm0,(%rdi,%rdx,1)
  sub    $0x4,%rdx
  test   %eax,%eax
  js     L8
L18:
  ret
```

assistant: ```c
void vector_fmul_window_c(float *dst, const float *src0, const float *src1, const float *win, int len) {
  int i, j;
  dst += len;
  win += len;
  src0 += len;
  for (i = -len, j = len - 1; i < 0; i++, j--) {
    float s0 = src0[i];
    float s1 = src1[j];
    float wi = win[i];
    float wj = win[j];
    dst[i] = s0 * wj - s1 * wi;
    dst[j] = s0 * wi + s1 * wj;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  jmp    L36
L4:
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x41c(%rbp)
  movl   $0x0,-0x420(%rbp)
  jmp    L30
L25:
  mov    -0x420(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x420(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x420(%rbp)
L30:
  mov    -0x420(%rbp),%eax
  cmp    -0x41c(%rbp),%eax
  jl     L25
L36:
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L4
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string

tool: D19: rb

tool: D27: D:\temp\bin-file.exe

tool: D17: buf[%d] = %x


assistant: ```c
int main01(void) {
  FILE *p = fopen("D:\\temp\\bin-file.exe", "rb");
  while (!feof(p)) {
    char buf[1024] = {0};
    int res = fread(buf, sizeof(char), sizeof(buf), p);
    int i;
    for (i = 0; i < res; i++) {
      printf("buf[%d] = %x\n", i, buf[i]);
    }
  }
  fclose(p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main01>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rsi
  lea    D20(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  lea    D9(%rip),%r12
L30:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L24
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  mov    %r13,%rcx
  mov    $0x400,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  test   %eax,%eax
  jle    L30
  mov    %eax,%ebp
  mov    $0x0,%ebx
L17:
  movsbl (%rsp,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
  jmp    L30
L24:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
datatype: string
name: extract_symbolic_data
arguments: label: D20
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D25: rb

tool: D20: D:\temp\bin-file.exe

tool: D9: buf[%d] = %x


assistant: ```c
int main01(void) {
  FILE *p = fopen("D:\\temp\\bin-file.exe", "rb");
  while (!feof(p)) {
    char buf[1024] = {0};
    int res = fread(buf, sizeof(char), sizeof(buf), p);
    int i;
    for (i = 0; i < res; i++) {
      printf("buf[%d] = %x\n", i, buf[i]);
    }
  }
  fclose(p);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main01>:
  endbr64
  push   %r14
  lea    D10(%rip),%rsi
  lea    D29(%rip),%rdi
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r14
L17:
  mov    %r14,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L1
L7:
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  pxor   %xmm0,%xmm0
  mov    %r14,%rcx
  mov    %r12,%rdi
  mov    $0x400,%edx
  mov    $0x1,%esi
  movaps %xmm0,(%rsp)
  call   <fread@plt>
  test   %eax,%eax
  jle    L17
  movslq %eax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L25:
  movsbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L25
  mov    %r14,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L7
L1:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D0
datatype: string

tool: D10: rb

tool: D29: D:\temp\bin-file.exe

tool: D0: buf[%d] = %x


assistant: ```c
int main01(void) {
  FILE *p = fopen("D:\\temp\\bin-file.exe", "rb");
  while (!feof(p)) {
    char buf[1024] = {0};
    int res = fread(buf, sizeof(char), sizeof(buf), p);
    int i;
    for (i = 0; i < res; i++) {
      printf("buf[%d] = %x\n", i, buf[i]);
    }
  }
  fclose(p);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main01>:
  endbr64
  push   %r14
  lea    D8(%rip),%rsi
  lea    D1(%rip),%rdi
  push   %r13
  lea    D24(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r14
L31:
  mov    %r14,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L42
L30:
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  pxor   %xmm0,%xmm0
  mov    %r14,%rcx
  mov    %r12,%rdi
  mov    $0x400,%edx
  mov    $0x1,%esi
  movaps %xmm0,(%rsp)
  call   <fread@plt>
  test   %eax,%eax
  jle    L31
  movslq %eax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L48:
  movsbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L48
  mov    %r14,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L30
L42:
  mov    %r14,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D24
type_infered: string

tool: D8: rb

tool: D1: D:\temp\bin-file.exe

tool: D24: buf[%d] = %x


assistant: ```c
int main01(void) {
  FILE *p = fopen("D:\\temp\\bin-file.exe", "rb");
  while (!feof(p)) {
    char buf[1024] = {0};
    int res = fread(buf, sizeof(char), sizeof(buf), p);
    int i;
    for (i = 0; i < res; i++) {
      printf("buf[%d] = %x\n", i, buf[i]);
    }
  }
  fclose(p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L38
L8:
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  mov    -0x28(%rbp),%rcx
  cqto
  idiv   %rcx
  mov    %rdx,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L11
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L38:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D9
type: string

tool: D12: %d

tool: D2: %ld %ld %ld

tool: D9: %ld


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int i = 0; i < t; i++) {
    long int n, m, s;
    scanf("%ld %ld %ld", &n, &m, &s);
    long int x = (s + m - 1) % n;
    if (!x) {
      x = n;
    }
    printf("%ld\n", x);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L18
  mov    $0x0,%ebx
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    D22(%rip),%r12
  lea    D13(%rip),%rbp
L19:
  lea    0x10(%rsp),%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rcx
  mov    0x18(%rsp),%rax
  add    0x20(%rsp),%rax
  sub    $0x1,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  cmovne %rdx,%rcx
  mov    %rcx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L19
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D28: %d

tool: D22: %ld %ld %ld

tool: D13: %ld


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int i = 0; i < t; i++) {
    long int n, m, s;
    scanf("%ld %ld %ld", &n, &m, &s);
    long int x = (s + m - 1) % n;
    if (!x) {
      x = n;
    }
    printf("%ld\n", x);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D25(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L11
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
  lea    D9(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  add    0x20(%rsp),%rax
  mov    %rbx,%rdi
  mov    0x10(%rsp),%rcx
  sub    $0x1,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  cmovne %rdx,%rcx
  add    $0x1,%r15d
  mov    %rcx,%rsi
  call   <printf@plt>
  cmp    %r15d,0xc(%rsp)
  jg     L29
L11:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type_guessed: string
name: disassemble_data
arguments: data_label: D6
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D25: %d

tool: D6: %ld %ld %ld

tool: D9: %ld


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int i = 0; i < t; i++) {
    long int n, m, s;
    scanf("%ld %ld %ld", &n, &m, &s);
    long int x = (s + m - 1) % n;
    if (!x) {
      x = n;
    }
    printf("%ld\n", x);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D23(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L43
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r15
  lea    0x18(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D0(%rip),%r12
  lea    D28(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r15,%rcx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rax
  add    0x20(%rsp),%rax
  sub    $0x1,%rax
  mov    0x10(%rsp),%rsi
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L45
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    0xc(%rsp),%ebx
  jl     L44
L43:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L44
  jmp    L43
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string

tool: D23: %d

tool: D0: %ld %ld %ld

tool: D28: %ld


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int i = 0; i < t; i++) {
    long int n, m, s;
    scanf("%ld %ld %ld", &n, &m, &s);
    long int x = (s + m - 1) % n;
    if (!x) {
      x = n;
    }
    printf("%ld\n", x);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sigaltstack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L5
  mov    D32(%rip),%rax
  mov    (%rax),%edx
  mov    D58(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L48
L5:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  test   %eax,%eax
  je     L27
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D58(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L48
L27:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xba,%edi
  call   <syscall@plt>
L48:
  leave
  ret
```

assistant: ```c
int sigaltstack(const stack_t *ss, stack_t *old) {
  if (ss) {
    if (ss->ss_size < MINSIGSTKSZ) {
      errno = ENOMEM;
      return -1;
    }
    if (ss->ss_flags & ~SS_DISABLE) {
      errno = EINVAL;
      return -1;
    }
  }
  return syscall(186, ss, old);
}
```