ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  movabs $0x6d61796873,%rax
  lea    0x100(%rsp),%r13
  mov    %rsp,%r12
  mov    %rdx,0x8(%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   $0x7968,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  mov    %rax,(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  movaps %xmm0,0x190(%rsp)
  movaps %xmm0,0x1a0(%rsp)
  movaps %xmm0,0x1b0(%rsp)
  movaps %xmm0,0x1c0(%rsp)
  movaps %xmm0,0x1d0(%rsp)
  movaps %xmm0,0x1e0(%rsp)
  movaps %xmm0,0x1f0(%rsp)
  call   <rabinStr@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %r12,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  lea    D24(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D24
type: string

tool: D19: str %p


tool: D3: Substring found %s


tool: D24: strstr %s


assistant: ```c
int main() {
  char str[256] = "shyam";
  char substr[256] = "hy";
  char *ptr = NULL;
  ptr = rabinStr(str, substr);
  if (ptr) {
    printf("str %p\n", str);
    printf("Substring found %s\n", ptr);
  }
  printf("strstr %s\n", strstr(str, substr));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  movabs $0x6d61796873,%rax
  lea    0x100(%rsp),%r13
  mov    %rsp,%r12
  mov    %rdx,0x8(%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  movq   $0x7968,0x100(%rsp)
  movq   $0x0,0x108(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  mov    %rax,(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  movaps %xmm0,0x190(%rsp)
  movaps %xmm0,0x1a0(%rsp)
  movaps %xmm0,0x1b0(%rsp)
  movaps %xmm0,0x1c0(%rsp)
  movaps %xmm0,0x1d0(%rsp)
  movaps %xmm0,0x1e0(%rsp)
  movaps %xmm0,0x1f0(%rsp)
  call   <rabinStr@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  lea    D18(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D18
type: string

tool: D12: str %p


tool: D5: Substring found %s


tool: D18: strstr %s


assistant: ```c
int main() {
  char str[256] = "shyam";
  char substr[256] = "hy";
  char *ptr = NULL;
  ptr = rabinStr(str, substr);
  if (ptr) {
    printf("str %p\n", str);
    printf("Substring found %s\n", ptr);
  }
  printf("strstr %s\n", strstr(str, substr));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gt_uint32_key_mul_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x9e3779b1,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t gt_uint32_key_mul_hash(uint32_t key) {
  uint32_t x = ((uint64_t)2654435761UL * key) & (~(uint32_t)0);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gt_uint32_key_mul_hash>:
  endbr64
  imul   $0x9e3779b1,%edi,%eax
  ret
```

assistant: ```c
uint32_t gt_uint32_key_mul_hash(uint32_t key) {
  uint32_t x = ((uint64_t)2654435761UL * key) & (~(uint32_t)0);
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gt_uint32_key_mul_hash>:
  endbr64
  imul   $0x9e3779b1,%edi,%eax
  ret
```

assistant: ```c
uint32_t gt_uint32_key_mul_hash(uint32_t key) {
  uint32_t x = ((uint64_t)2654435761UL * key) & (~(uint32_t)0);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gt_uint32_key_mul_hash>:
  endbr64
  imul   $0x9e3779b1,%edi,%eax
  ret
```

assistant: ```c
uint32_t gt_uint32_key_mul_hash(uint32_t key) {
  uint32_t x = ((uint64_t)2654435761UL * key) & (~(uint32_t)0);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i___0;
  int a;
  {
    i___0 = 0;
    a = 0;
    return (0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int i___0;
  int a;
  {
    i___0 = 0;
    a = 0;
    return (0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i___0;
  int a;
  {
    i___0 = 0;
    a = 0;
    return (0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i___0;
  int a;
  {
    i___0 = 0;
    a = 0;
    return (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quatMultLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9d,-0x5c(%rbp)
  movq   $0x4,-0x18(%rbp)
  cmpq   $0x1,-0x50(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L77
L6:
  mov    $0x4,%eax
L77:
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x58(%rbp)
  jne    L74
  mov    $0x0,%eax
  jmp    L52
L74:
  mov    $0x4,%eax
L52:
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x50(%rbp)
  jbe    L22
  cmpq   $0x1,-0x58(%rbp)
  jbe    L22
  mov    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L65
L22:
  mov    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  cmp    %rax,%rdx
  cmovae %rdx,%rax
  mov    %rax,-0x20(%rbp)
L65:
  movq   $0x0,-0x28(%rbp)
  jmp    L69
L62:
  mov    -0x28(%rbp),%rax
  imul   -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  imul   -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x40(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x28(%rbp),%rax
  imul   -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  lea    (%rcx,%rax,1),%rdi
  mov    -0x5c(%rbp),%eax
  mov    %eax,%ecx
  call   <quatMultiply@plt>
  mov    %eax,-0x2c(%rbp)
  addq   $0x1,-0x28(%rbp)
L69:
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L62
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int quatMultLoop(double *q1, double *q2, double *q1q2, unsigned long long nq1, unsigned long long nq2, int p) {
  unsigned long long i, q1step, q2step, q1q2step, nq;
  int trash;
  q1q2step = 4;
  q1step = (nq1 == 1) ? 0 : 4;
  q2step = (nq2 == 1) ? 0 : 4;
  if ((nq1 > 1) && (nq2 > 1)) {
    nq = (nq1 <= nq2) ? nq1 : nq2;
  } else {
    nq = (nq1 >= nq2) ? nq1 : nq2;
  }
#pragma omp parallel shared(q1, q2, q1q2) private(i, trash) firstprivate(q1step, q2step, q1q2step, nq, p)
  {
#pragma omp for schedule(static) nowait
    for (i = 0; i < nq; i++) {
      trash = quatMultiply(&(q1[i * q1step]), &(q2[i * q2step]), &(q1q2[i * q1q2step]), p);
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quatMultLoop>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %r9d,%r15d
  cmp    $0x1,%rcx
  setne  %al
  movzbl %al,%eax
  lea    0x0(,%rax,4),%rdx
  cmp    $0x1,%r8
  setne  %al
  movzbl %al,%eax
  shl    $0x2,%rax
  cmp    $0x1,%rcx
  jbe    L44
  cmp    $0x1,%r8
  jbe    L44
  cmp    %r8,%rcx
  cmovbe %rcx,%r8
  mov    %r8,%r14
L40:
  lea    0x0(,%rdx,8),%rsi
  mov    %rsi,(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
L3:
  mov    %r15d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <quatMultiply@plt>
  add    $0x1,%r13
  add    (%rsp),%r12
  add    0x8(%rsp),%rbp
  add    $0x20,%rbx
  cmp    %r13,%r14
  ja     L3
L45:
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  cmp    %r8,%rcx
  cmovae %rcx,%r8
  mov    %r8,%r14
  test   %r8,%r8
  jne    L40
  jmp    L45
```

assistant: ```c
int quatMultLoop(double *q1, double *q2, double *q1q2, unsigned long long nq1, unsigned long long nq2, int p) {
  unsigned long long i, q1step, q2step, q1q2step, nq;
  int trash;
  q1q2step = 4;
  q1step = (nq1 == 1) ? 0 : 4;
  q2step = (nq2 == 1) ? 0 : 4;
  if ((nq1 > 1) && (nq2 > 1)) {
    nq = (nq1 <= nq2) ? nq1 : nq2;
  } else {
    nq = (nq1 >= nq2) ? nq1 : nq2;
  }
#pragma omp parallel shared(q1, q2, q1q2) private(i, trash) firstprivate(q1step, q2step, q1q2step, nq, p)
  {
#pragma omp for schedule(static) nowait
    for (i = 0; i < nq; i++) {
      trash = quatMultiply(&(q1[i * q1step]), &(q2[i * q2step]), &(q1q2[i * q1q2step]), p);
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quatMultLoop>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  cmp    $0x1,%rcx
  setne  %r12b
  shl    $0x2,%r12
  cmp    $0x1,%r8
  je     L50
  cmp    $0x1,%rcx
  jbe    L36
  cmp    $0x1,%r8
  jbe    L36
  cmp    %r8,%rcx
  mov    $0x4,%r14d
  cmovbe %rcx,%r8
  mov    %r8,(%rsp)
L57:
  lea    0x0(,%r12,8),%rax
  shl    $0x3,%r14
  mov    %rdi,%r12
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  nop
L42:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    %r13d,%ecx
  call   <quatMultiply@plt>
  add    $0x1,%rbp
  add    %r14,%r15
  add    $0x20,%rbx
  add    0x8(%rsp),%r12
  cmp    (%rsp),%rbp
  jb     L42
L4:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %r14d,%r14d
L39:
  cmp    %r8,%rcx
  cmovae %rcx,%r8
  mov    %r8,(%rsp)
  test   %r8,%r8
  jne    L57
  jmp    L4
  nopl   (%rax)
L36:
  mov    $0x4,%r14d
  jmp    L39
```

assistant: ```c
int quatMultLoop(double *q1, double *q2, double *q1q2, unsigned long long nq1, unsigned long long nq2, int p) {
  unsigned long long i, q1step, q2step, q1q2step, nq;
  int trash;
  q1q2step = 4;
  q1step = (nq1 == 1) ? 0 : 4;
  q2step = (nq2 == 1) ? 0 : 4;
  if ((nq1 > 1) && (nq2 > 1)) {
    nq = (nq1 <= nq2) ? nq1 : nq2;
  } else {
    nq = (nq1 >= nq2) ? nq1 : nq2;
  }
#pragma omp parallel shared(q1, q2, q1q2) private(i, trash) firstprivate(q1step, q2step, q1q2step, nq, p)
  {
#pragma omp for schedule(static) nowait
    for (i = 0; i < nq; i++) {
      trash = quatMultiply(&(q1[i * q1step]), &(q2[i * q2step]), &(q1q2[i * q1q2step]), p);
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quatMultLoop>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  cmp    $0x1,%rcx
  setne  %r12b
  shl    $0x2,%r12
  cmp    $0x1,%r8
  je     L3
  cmp    $0x1,%rcx
  jbe    L69
  cmp    $0x1,%r8
  jbe    L69
  cmp    %r8,%rcx
  mov    $0x4,%r14d
  cmovbe %rcx,%r8
  mov    %r8,(%rsp)
L2:
  lea    0x0(,%r12,8),%rax
  shl    $0x3,%r14
  mov    %rdi,%r12
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  nop
L24:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    %r13d,%ecx
  call   <quatMultiply@plt>
  add    $0x1,%rbp
  add    %r14,%r15
  add    $0x20,%rbx
  add    0x8(%rsp),%r12
  cmp    (%rsp),%rbp
  jb     L24
L63:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %r14d,%r14d
L17:
  cmp    %r8,%rcx
  cmovae %rcx,%r8
  mov    %r8,(%rsp)
  test   %r8,%r8
  jne    L2
  jmp    L63
  nopl   (%rax)
L69:
  mov    $0x4,%r14d
  jmp    L17
```

assistant: ```c
int quatMultLoop(double *q1, double *q2, double *q1q2, unsigned long long nq1, unsigned long long nq2, int p) {
  unsigned long long i, q1step, q2step, q1q2step, nq;
  int trash;
  q1q2step = 4;
  q1step = (nq1 == 1) ? 0 : 4;
  q2step = (nq2 == 1) ? 0 : 4;
  if ((nq1 > 1) && (nq2 > 1)) {
    nq = (nq1 <= nq2) ? nq1 : nq2;
  } else {
    nq = (nq1 >= nq2) ? nq1 : nq2;
  }
#pragma omp parallel shared(q1, q2, q1q2) private(i, trash) firstprivate(q1step, q2step, q1q2step, nq, p)
  {
#pragma omp for schedule(static) nowait
    for (i = 0; i < nq; i++) {
      trash = quatMultiply(&(q1[i * q1step]), &(q2[i * q2step]), &(q1q2[i * q1q2step]), p);
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x12(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x60,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    $0x7b,%eax
  sub    %edx,%eax
  mov    %al,-0x11(%rbp)
  movsbl -0x11(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string

tool: D13: %c

assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  int k;
  k = c;
  int n;
  n = k - 96;
  char a;
  a = 123 - n;
  printf("%c", a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: %c

assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  int k;
  k = c;
  int n;
  n = k - 96;
  char a;
  a = 123 - n;
  printf("%c", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: %c

assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  int k;
  k = c;
  int n;
  n = k - 96;
  char a;
  a = 123 - n;
  printf("%c", a);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  mov    %rbp,%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %c

assistant: ```c
int main() {
  char c;
  scanf("%c", &c);
  int k;
  k = c;
  int n;
  n = k - 96;
  char a;
  a = 123 - n;
  printf("%c", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mangle_lrest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <class_upper@plt>
  test   %rax,%rax
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  xor    $0x20,%edx
  mov    %dl,(%rax)
L18:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mangle_lrest(char arr[64], int arr_len) {
  int pos;
  for (pos = 0; pos < arr_len; pos++)
    if (class_upper((arr)[(pos)]))
      (arr)[(pos)] ^= 0x20;
  return (arr_len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mangle_lrest>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  test   %esi,%esi
  jle    L30
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
  jmp    L41
L37:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L30
L41:
  movsbl (%rbx),%edi
  call   <class_upper@plt>
  test   %rax,%rax
  je     L37
  xorb   $0x20,(%rbx)
  jmp    L37
L30:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mangle_lrest(char arr[64], int arr_len) {
  int pos;
  for (pos = 0; pos < arr_len; pos++)
    if (class_upper((arr)[(pos)]))
      (arr)[(pos)] ^= 0x20;
  return (arr_len);
}
```
user: What is the c source code of the assembly code below?

```asm
<mangle_lrest>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  call   <class_upper@plt>
  test   %rax,%rax
  je     L5
  xorb   $0x20,(%rbx)
L5:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
L7:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mangle_lrest(char arr[64], int arr_len) {
  int pos;
  for (pos = 0; pos < arr_len; pos++)
    if (class_upper((arr)[(pos)]))
      (arr)[(pos)] ^= 0x20;
  return (arr_len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mangle_lrest>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L28
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%edi
  call   <class_upper@plt>
  test   %rax,%rax
  je     L2
  xorb   $0x20,(%rbx)
L2:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
L28:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mangle_lrest(char arr[64], int arr_len) {
  int pos;
  for (pos = 0; pos < arr_len; pos++)
    if (class_upper((arr)[(pos)]))
      (arr)[(pos)] ^= 0x20;
  return (arr_len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<af2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L0:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float **af2d(int X, int Y) {
  int i;
  float **A = (float **)malloc(X * sizeof(float *));
  for (i = 0; i < X; i++)
    A[i] = (float *)malloc(Y * sizeof(float));
  return A;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<af2d>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L17
  shl    $0x2,%ebp
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L13:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
L17:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **af2d(int X, int Y) {
  int i;
  float **A = (float **)malloc(X * sizeof(float *));
  for (i = 0; i < X; i++)
    A[i] = (float *)malloc(Y * sizeof(float));
  return A;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<af2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L3
  shl    $0x2,%ebp
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L14
L3:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **af2d(int X, int Y) {
  int i;
  float **A = (float **)malloc(X * sizeof(float *));
  for (i = 0; i < X; i++)
    A[i] = (float *)malloc(Y * sizeof(float));
  return A;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<af2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L19
  shl    $0x2,%ebp
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L2
L19:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float **af2d(int X, int Y) {
  int i;
  float **A = (float **)malloc(X * sizeof(float *));
  for (i = 0; i < X; i++)
    A[i] = (float *)malloc(Y * sizeof(float));
  return A;
}
```