ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<dispel_magic>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <get_random@plt>
  mov    %rax,%rbp
  mov    $0xc8,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <mod6@plt>
  cmp    %rax,%rbp
  jl     L17
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x17,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x15,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x16,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x7,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x1a,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x1b,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0xf,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  mov    $0x19,%esi
  mov    %rbx,%rdi
  call   <remove_status@plt>
  jmp    L19
```

assistant: ```c
void dispel_magic(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 200)) {
    remove_status(target, 23);
    remove_status(target, 20);
    remove_status(target, 21);
    remove_status(target, 22);
    remove_status(target, 7);
    remove_status(target, 26);
    remove_status(target, 27);
    remove_status(target, 15);
    remove_status(target, 25);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dispel_magic>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x64,%esi
  push   %rbx
  call   <get_random@plt>
  mov    $0xc8,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <mod6@plt>
  cmp    %rax,%rbx
  jl     L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  mov    $0x17,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x15,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x16,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x1a,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x1b,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0xf,%esi
  call   <remove_status@plt>
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x19,%esi
  pop    %rbp
  pop    %r12
  jmp    1080 <remove_status@plt>
```

assistant: ```c
void dispel_magic(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 200)) {
    remove_status(target, 23);
    remove_status(target, 20);
    remove_status(target, 21);
    remove_status(target, 22);
    remove_status(target, 7);
    remove_status(target, 26);
    remove_status(target, 27);
    remove_status(target, 15);
    remove_status(target, 25);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dispel_magic>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x64,%esi
  push   %rbx
  call   <get_random@plt>
  mov    $0xc8,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <mod6@plt>
  cmp    %rax,%rbx
  jl     L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  mov    $0x17,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x15,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x16,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x7,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x1a,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0x1b,%esi
  call   <remove_status@plt>
  mov    %rbp,%rdi
  mov    $0xf,%esi
  call   <remove_status@plt>
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0x19,%esi
  pop    %rbp
  pop    %r12
  jmp    1080 <remove_status@plt>
```

assistant: ```c
void dispel_magic(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 200)) {
    remove_status(target, 23);
    remove_status(target, 20);
    remove_status(target, 21);
    remove_status(target, 22);
    remove_status(target, 7);
    remove_status(target, 26);
    remove_status(target, 27);
    remove_status(target, 15);
    remove_status(target, 25);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L68
L47:
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L20
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jne    L41
  addl   $0x1,-0x10(%rbp)
  jmp    L68
L41:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x72,%al
  jne    L20
  addl   $0x1,-0xc(%rbp)
  jmp    L68
L20:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <rm@plt>
L68:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L47
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main(argc, argv) char *argv[];
{
  char *arg;
  int fflg, rflg;
  fflg = 0;
  rflg = 0;
  while (--argc > 0) {
    arg = *++argv;
    if (arg[0] == '-') {
      if (arg[1] == 'f') {
        fflg++;
        continue;
      }
      if (arg[1] == 'r') {
        rflg++;
        continue;
      }
    }
    rm(arg, fflg, rflg);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L59
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L6
L63:
  add    $0x1,%ebp
  jmp    L20
L25:
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    $0x0,%eax
  call   <rm@plt>
L20:
  cmp    %rbx,%r12
  je     L32
L6:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  cmpb   $0x2d,(%rdi)
  jne    L25
  movzbl 0x1(%rdi),%eax
  cmp    $0x66,%al
  je     L63
  cmp    $0x72,%al
  jne    L25
  add    $0x1,%r13d
  jmp    L20
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  mov    $0x0,%eax
  ret
```

assistant: ```c
main(argc, argv) char *argv[];
{
  char *arg;
  int fflg, rflg;
  fflg = 0;
  rflg = 0;
  while (--argc > 0) {
    arg = *++argv;
    if (arg[0] == '-') {
      if (arg[1] == 'f') {
        fflg++;
        continue;
      }
      if (arg[1] == 'r') {
        rflg++;
        continue;
      }
    }
    rm(arg, fflg, rflg);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L61
  push   %r13
  lea    -0x2(%rdi),%eax
  xor    %r13d,%r13d
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L69:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  cmpb   $0x2d,(%rdi)
  jne    L39
  movzbl 0x1(%rdi),%eax
  cmp    $0x66,%al
  je     L62
  cmp    $0x72,%al
  je     L19
L39:
  mov    %r13d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  call   <rm@plt>
L45:
  cmp    %rbx,%r12
  jne    L69
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L62:
  add    $0x1,%ebp
  jmp    L45
  nopl   (%rax)
L19:
  add    $0x1,%r13d
  jmp    L45
L61:
  xor    %eax,%eax
  ret
```

assistant: ```c
main(argc, argv) char *argv[];
{
  char *arg;
  int fflg, rflg;
  fflg = 0;
  rflg = 0;
  while (--argc > 0) {
    arg = *++argv;
    if (arg[0] == '-') {
      if (arg[1] == 'f') {
        fflg++;
        continue;
      }
      if (arg[1] == 'r') {
        rflg++;
        continue;
      }
    }
    rm(arg, fflg, rflg);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  push   %r13
  lea    -0x2(%rdi),%eax
  xor    %r13d,%r13d
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L50:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  cmpb   $0x2d,(%rdi)
  jne    L11
  movzbl 0x1(%rdi),%eax
  cmp    $0x66,%al
  je     L37
  cmp    $0x72,%al
  je     L23
L11:
  mov    %r13d,%edx
  mov    %ebp,%esi
  xor    %eax,%eax
  call   <rm@plt>
L39:
  cmp    %rbx,%r12
  jne    L50
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L37:
  add    $0x1,%ebp
  jmp    L39
  nopl   (%rax)
L23:
  add    $0x1,%r13d
  jmp    L39
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
main(argc, argv) char *argv[];
{
  char *arg;
  int fflg, rflg;
  fflg = 0;
  rflg = 0;
  while (--argc > 0) {
    arg = *++argv;
    if (arg[0] == '-') {
      if (arg[1] == 'f') {
        fflg++;
        continue;
      }
      if (arg[1] == 'r') {
        rflg++;
        continue;
      }
    }
    rm(arg, fflg, rflg);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<to_floating>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  jmp    L11
L2:
  movss  -0x4(%rbp),%xmm0
  movss  D19(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L11:
  movss  -0x4(%rbp),%xmm0
  movss  D18(%rip),%xmm1
  comiss %xmm1,%xmm0
  jae    L2
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
datatype: byte[4]
name: retrieve_data
arguments: label: D18
datatype: byte[4]

tool: {"D19": [0x00,0x00,0x20,0x41]}

tool: {"D18": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float to_floating(float num) {
  while (num >= 1)
    num /= 10;
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<to_floating>:
  endbr64
  movss  D1(%rip),%xmm2
  movss  D8(%rip),%xmm1
  comiss %xmm1,%xmm0
  jb     L3
L13:
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  jae    L13
L3:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D8
datatype: byte[4]

tool: {"D1": [0x00,0x00,0x20,0x41]}

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float to_floating(float num) {
  while (num >= 1)
    num /= 10;
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<to_floating>:
  endbr64
  movss  D18(%rip),%xmm1
  movss  D0(%rip),%xmm2
  comiss %xmm1,%xmm0
  jb     L10
  nopl   0x0(%rax)
L5:
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  jae    L5
L10:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: byte[4]
name: unpack_data
arguments: data_tag: D0
type_guessed: byte[4]

tool: {"D18": [0x00,0x00,0x80,0x3f]}

tool: {"D0": [0x00,0x00,0x20,0x41]}

assistant: ```c
float to_floating(float num) {
  while (num >= 1)
    num /= 10;
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<to_floating>:
  endbr64
  movss  D16(%rip),%xmm1
  movss  D18(%rip),%xmm2
  comiss %xmm1,%xmm0
  jb     L5
  nopl   0x0(%rax)
L11:
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  jae    L11
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D18
type_infered: byte[4]

tool: {"D16": [0x00,0x00,0x80,0x3f]}

tool: {"D18": [0x00,0x00,0x20,0x41]}

assistant: ```c
float to_floating(float num) {
  while (num >= 1)
    num /= 10;
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<modld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  fldz
  fstpt  -0x10(%rbp)
  fldz
  fldt   0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jb     L2
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <floorld@plt>
  add    $0x10,%rsp
  mov    %rax,-0x30(%rbp)
  fildll -0x30(%rbp)
  fldt   0x10(%rbp)
  fsubp  %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x10(%rbp)
  fsubrp %st,%st(1)
  mov    -0x18(%rbp),%rax
  fstpt  (%rax)
  jmp    L3
L2:
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <ceilld@plt>
  add    $0x10,%rsp
  mov    %rax,-0x30(%rbp)
  fildll -0x30(%rbp)
  fldt   0x10(%rbp)
  fsubp  %st,%st(1)
  fchs
  fstpt  -0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%edx
  mov    %rax,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  mov    -0x18(%rbp),%rax
  fstpt  (%rax)
L3:
  fldt   -0x10(%rbp)
  leave
  ret
```

assistant: ```c
long double modld(long double value, long double *intpart) {
  long double decimal_part = 0.0;
  if (value >= 0) {
    decimal_part = value - (long double)floorld(value);
    *intpart = value - decimal_part;
  } else {
    decimal_part = -(value - (long double)ceilld(value));
    *intpart = value + decimal_part;
  }
  return decimal_part;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modld>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  fldz
  fldt   0x20(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jb     L9
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <floorld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  fsub   %st,%st(1)
  fsub   %st(1),%st
  add    $0x10,%rsp
L1:
  fstpt  (%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  fstp   %st(0)
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <ceilld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  fsub   %st,%st(1)
  fld    %st(1)
  fchs
  fxch   %st(2)
  fsubrp %st,%st(1)
  add    $0x10,%rsp
  jmp    L1
```

assistant: ```c
long double modld(long double value, long double *intpart) {
  long double decimal_part = 0.0;
  if (value >= 0) {
    decimal_part = value - (long double)floorld(value);
    *intpart = value - decimal_part;
  } else {
    decimal_part = -(value - (long double)ceilld(value));
    *intpart = value + decimal_part;
  }
  return decimal_part;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<modld>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  fldz
  fldt   0x20(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jb     L4
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <floorld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  pop    %rcx
  pop    %rsi
  fsub   %st,%st(1)
  fsub   %st(1),%st
  fstpt  (%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L4:
  sub    $0x10,%rsp
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x30(%rsp)
  call   <ceilld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  pop    %rax
  pop    %rdx
  fsub   %st,%st(1)
  fld    %st(1)
  fchs
  fxch   %st(1)
  fsubp  %st,%st(2)
  fxch   %st(1)
  fstpt  (%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
long double modld(long double value, long double *intpart) {
  long double decimal_part = 0.0;
  if (value >= 0) {
    decimal_part = value - (long double)floorld(value);
    *intpart = value - decimal_part;
  } else {
    decimal_part = -(value - (long double)ceilld(value));
    *intpart = value + decimal_part;
  }
  return decimal_part;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modld>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  fldz
  fldt   0x20(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jb     L1
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <floorld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  pop    %rcx
  pop    %rsi
  fsub   %st,%st(1)
  fsub   %st(1),%st
  fstpt  (%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
  nop
L1:
  sub    $0x10,%rsp
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x30(%rsp)
  call   <ceilld@plt>
  mov    %rax,0x18(%rsp)
  fildll 0x18(%rsp)
  fldt   0x30(%rsp)
  pop    %rax
  pop    %rdx
  fsub   %st,%st(1)
  fld    %st(1)
  fchs
  fxch   %st(1)
  fsubp  %st,%st(2)
  fxch   %st(1)
  fstpt  (%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
long double modld(long double value, long double *intpart) {
  long double decimal_part = 0.0;
  if (value >= 0) {
    decimal_part = value - (long double)floorld(value);
    *intpart = value - decimal_part;
  } else {
    decimal_part = -(value - (long double)ceilld(value));
    *intpart = value + decimal_part;
  }
  return decimal_part;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L55
L8:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
L55:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L8
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L20
L53:
  mov    -0x34(%rbp),%ebx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%edi
  mov    %ebx,%eax
  cltd
  idiv   %edi
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x20(%rbp)
  cmpl   $0x7,-0x20(%rbp)
  jne    L47
  addl   $0x1,-0x24(%rbp)
L47:
  subl   $0x1,-0x30(%rbp)
L20:
  cmpl   $0x0,-0x30(%rbp)
  jns    L53
  mov    -0x34(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D27
datatype: string

tool: D21: Icinde kac tane 7 oldugunu bulmak icin bir tam sayi giriniz:

tool: D19: %d

tool: D27: Girdiginiz %d basamakli %d sayisinin %d basamagi 7 dir

assistant: ```c
int main() {
  int ara_basamak_sayici, basamak_bolum, sayi, ara_atama, bolum;
  printf("Icinde kac tane 7 oldugunu bulmak icin bir tam sayi giriniz:");
  scanf("%d", &sayi);
  ara_atama = sayi;
  int basamak_sayici = 0;
  while (ara_atama > 0) {
    basamak_bolum = ara_atama / 10;
    ara_atama = basamak_bolum;
    basamak_sayici++;
  }
  ara_basamak_sayici = basamak_sayici;
  int sayici_7 = 0;
  while (ara_basamak_sayici >= 0) {
    bolum = sayi / pow(10, ara_basamak_sayici);
    bolum = bolum % 10;
    if (bolum == 7) {
      sayici_7++;
    }
    ara_basamak_sayici--;
  }
  printf("Girdiginiz %d basamakli %d sayisinin %d basamagi 7 dir", basamak_sayici, sayi, sayici_7);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L26
  mov    $0x0,%r12d
L60:
  mov    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  add    $0x1,%r12d
  cmp    $0x9,%ecx
  jg     L60
  test   %r12d,%r12d
  js     L38
L46:
  mov    %r12d,%ebp
  mov    $0x0,%r13d
L4:
  mov    0x4(%rsp),%ebx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    $0x7,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%r13d
  sub    $0x1,%ebp
  jns    L4
L30:
  mov    %r13d,%ecx
  mov    0x4(%rsp),%edx
  mov    %r12d,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  mov    $0x0,%r12d
  jmp    L46
L38:
  mov    $0x0,%r13d
  jmp    L30
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string

tool: D13: Icinde kac tane 7 oldugunu bulmak icin bir tam sayi giriniz:

tool: D3: %d

tool: D27: Girdiginiz %d basamakli %d sayisinin %d basamagi 7 dir

assistant: ```c
int main() {
  int ara_basamak_sayici, basamak_bolum, sayi, ara_atama, bolum;
  printf("Icinde kac tane 7 oldugunu bulmak icin bir tam sayi giriniz:");
  scanf("%d", &sayi);
  ara_atama = sayi;
  int basamak_sayici = 0;
  while (ara_atama > 0) {
    basamak_bolum = ara_atama / 10;
    ara_atama = basamak_bolum;
    basamak_sayici++;
  }
  ara_basamak_sayici = basamak_sayici;
  int sayici_7 = 0;
  while (ara_basamak_sayici >= 0) {
    bolum = sayi / pow(10, ara_basamak_sayici);
    bolum = bolum % 10;
    if (bolum == 7) {
      sayici_7++;
    }
    ara_basamak_sayici--;
  }
  printf("Girdiginiz %d basamakli %d sayisinin %d basamagi 7 dir", basamak_sayici, sayi, sayici_7);
  return 0;
}
```