ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<_min_max>:
  endbr64
  cmp    %rsi,(%rdi)
  jle    L19
  mov    %rsi,(%rdi)
L19:
  add    %rdx,%rsi
  cmp    0x8(%rdi),%rsi
  jle    L5
  mov    %rsi,0x8(%rdi)
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _min_max(void *ctx, uint32_t addr, uint8_t len, const char *s) {
  (void)s;
  uint32_t *min_max = ctx;
  if (addr < min_max[0]) {
    min_max[0] = addr;
  }
  if (addr + len > min_max[1]) {
    min_max[1] = addr + len;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_min_max>:
  endbr64
  cmp    %rsi,(%rdi)
  jle    L5
  mov    %rsi,(%rdi)
L5:
  add    %rdx,%rsi
  cmp    0x8(%rdi),%rsi
  jle    L17
  mov    %rsi,0x8(%rdi)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _min_max(void *ctx, uint32_t addr, uint8_t len, const char *s) {
  (void)s;
  uint32_t *min_max = ctx;
  if (addr < min_max[0]) {
    min_max[0] = addr;
  }
  if (addr + len > min_max[1]) {
    min_max[1] = addr + len;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_min_max>:
  endbr64
  cmp    %rsi,(%rdi)
  jle    L10
  mov    %rsi,(%rdi)
L10:
  add    %rdx,%rsi
  cmp    0x8(%rdi),%rsi
  jle    L19
  mov    %rsi,0x8(%rdi)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _min_max(void *ctx, uint32_t addr, uint8_t len, const char *s) {
  (void)s;
  uint32_t *min_max = ctx;
  if (addr < min_max[0]) {
    min_max[0] = addr;
  }
  if (addr + len > min_max[1]) {
    min_max[1] = addr + len;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<or_replacenum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L20
L49:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xb65,%ax
  jbe    L39
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xb6f,%ax
  ja     L39
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0xb66,%ax
  je     L51
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  sub    $0x66,%eax
  mov    %eax,%edx
  jmp    L37
L51:
  mov    $0x30,%edx
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x2f,%ax
  jbe    L4
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x39,%ax
  ja     L4
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cmp    $0x30,%ax
  je     L66
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  sub    $0x30,%eax
  mov    %eax,%edx
  jmp    L19
L66:
  mov    $0x30,%edx
L19:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L4:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L49
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *or_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0B66 && s[i] <= 0x0B6F)
      numchar[i] = ((s[i] - 0x0B66) == '\0') ? '0' : (s[i] - 0x0B66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<or_replacenum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r9
  test   %ebx,%ebx
  jle    L56
  mov    %ebx,%edi
  add    %rax,%rdi
  mov    %rax,%rdx
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rcx
  mov    $0x30,%r8d
  jmp    L37
L24:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L55
L37:
  movzwl (%rcx,%rax,2),%edx
  lea    -0xb66(%rdx),%esi
  cmp    $0x9,%si
  ja     L36
  lea    -0x66(%rdx),%esi
  cmp    $0xb66,%dx
  cmove  %r8d,%esi
  mov    %sil,(%rax)
L36:
  movzwl (%rcx,%rax,2),%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%si
  ja     L24
  lea    -0x30(%rdx),%esi
  cmp    $0x30,%dx
  cmove  %r8d,%esi
  mov    %sil,(%rax)
  jmp    L24
L56:
  mov    $0x0,%ebx
L55:
  movslq %ebx,%rbx
  movb   $0x0,(%r9,%rbx,1)
  mov    %r9,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *or_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0B66 && s[i] <= 0x0B6F)
      numchar[i] = ((s[i] - 0x0B66) == '\0') ? '0' : (s[i] - 0x0B66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<or_replacenum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L20
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%r9
  mov    $0x30,%esi
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rdi
  nopw   0x0(%rax,%rax,1)
L34:
  movzwl (%rdi,%rax,2),%edx
  lea    -0xb66(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L8
  lea    -0x66(%rdx),%ecx
  cmp    $0xb66,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
  movzwl (%rdi,%rax,2),%edx
L8:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L13
  lea    -0x30(%rdx),%ecx
  cmp    $0x30,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
L13:
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L34
  add    %r8,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rax,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *or_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0B66 && s[i] <= 0x0B6F)
      numchar[i] = ((s[i] - 0x0B66) == '\0') ? '0' : (s[i] - 0x0B66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<or_replacenum>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L10
  mov    %rax,%rdx
  lea    (%rax,%rbx,1),%r9
  mov    $0x30,%esi
  neg    %rdx
  lea    0x0(%rbp,%rdx,2),%rdi
  nopw   0x0(%rax,%rax,1)
L38:
  movzwl (%rdi,%rax,2),%edx
  lea    -0xb66(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L33
  lea    -0x66(%rdx),%ecx
  cmp    $0xb66,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
  movzwl (%rdi,%rax,2),%edx
L33:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cx
  ja     L29
  lea    -0x30(%rdx),%ecx
  cmp    $0x30,%dx
  cmove  %esi,%ecx
  mov    %cl,(%rax)
L29:
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L38
  add    %r8,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rax,%rbx
  mov    %r8,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *or_replacenum(unsigned short *s, int size) {
  int i, j;
  char *numchar;
  i = 0;
  numchar = (char *)malloc(size * sizeof(char));
  while (i < size) {
    if (s[i] >= 0x0B66 && s[i] <= 0x0B6F)
      numchar[i] = ((s[i] - 0x0B66) == '\0') ? '0' : (s[i] - 0x0B66);
    if (s[i] >= 0x30 && s[i] <= 0x39)
      numchar[i] = ((s[i] - 0x30) == '\0') ? '0' : (s[i] - 0x30);
    i++;
  }
  numchar[i] = '\0';
  return (numchar);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fix_geo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x5,%edx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x5,%edx
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L10:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D4: 

tool: D9: 

assistant: ```c
void fix_geo(unsigned char *buf, int len) {
  static const unsigned char geo_dl_old[] = {0x15, 0x06, 0x00, 0x00, 0x0E};
  static const unsigned char geo_dl_new[] = {0x15, 0x04, 0x00, 0x00, 0x0E};
  for (int i = 0; i < len; i++) {
    if (!memcmp(&buf[i], geo_dl_old, sizeof(geo_dl_old))) {
      memcpy(&buf[i], geo_dl_new, sizeof(geo_dl_new));
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fix_geo>:
  endbr64
  test   %esi,%esi
  jle    L41
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D10(%rip),%rbp
  lea    D1(%rip),%r13
  jmp    L46
L1:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L7
L46:
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L1
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D1
type: string

tool: D10: 

tool: D1: 

assistant: ```c
void fix_geo(unsigned char *buf, int len) {
  static const unsigned char geo_dl_old[] = {0x15, 0x06, 0x00, 0x00, 0x0E};
  static const unsigned char geo_dl_new[] = {0x15, 0x04, 0x00, 0x00, 0x0E};
  for (int i = 0; i < len; i++) {
    if (!memcmp(&buf[i], geo_dl_old, sizeof(geo_dl_old))) {
      memcpy(&buf[i], geo_dl_new, sizeof(geo_dl_new));
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fix_geo>:
  endbr64
  test   %esi,%esi
  jle    L38
  push   %r13
  lea    -0x1(%rsi),%eax
  lea    D12(%rip),%r13
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L44
  nopl   (%rax)
L28:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L47
L44:
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L28
  mov    %rbx,%rdi
  mov    $0x5,%edx
  mov    %r13,%rsi
  add    $0x1,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L44
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L38:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D12: 

tool: D13: 

assistant: ```c
void fix_geo(unsigned char *buf, int len) {
  static const unsigned char geo_dl_old[] = {0x15, 0x06, 0x00, 0x00, 0x0E};
  static const unsigned char geo_dl_new[] = {0x15, 0x04, 0x00, 0x00, 0x0E};
  for (int i = 0; i < len; i++) {
    if (!memcmp(&buf[i], geo_dl_old, sizeof(geo_dl_old))) {
      memcpy(&buf[i], geo_dl_new, sizeof(geo_dl_new));
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fix_geo>:
  endbr64
  test   %esi,%esi
  jle    L48
  push   %r13
  lea    -0x1(%rsi),%eax
  lea    D0(%rip),%r13
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L18
  nopl   (%rax)
L1:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L37
L18:
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L1
  mov    %rbx,%rdi
  mov    $0x5,%edx
  mov    %r13,%rsi
  add    $0x1,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L18
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L48:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string

tool: D0: 

tool: D17: 

assistant: ```c
void fix_geo(unsigned char *buf, int len) {
  static const unsigned char geo_dl_old[] = {0x15, 0x06, 0x00, 0x00, 0x0E};
  static const unsigned char geo_dl_new[] = {0x15, 0x04, 0x00, 0x00, 0x0E};
  for (int i = 0; i < len; i++) {
    if (!memcmp(&buf[i], geo_dl_old, sizeof(geo_dl_old))) {
      memcpy(&buf[i], geo_dl_new, sizeof(geo_dl_new));
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_pbcV_zigzag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%esi
  mov    $0x3f,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  xor    %esi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <_pbcV_encode@plt>
  leave
  ret
```

assistant: ```c
int _pbcV_zigzag(int64_t n, uint8_t buffer[10]) {
  n = (n << 1) ^ (n >> 63);
  return _pbcV_encode(n, buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_pbcV_zigzag>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,1),%eax
  mov    $0x3f,%ecx
  sar    %cl,%edi
  xor    %eax,%edi
  call   <_pbcV_encode@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _pbcV_zigzag(int64_t n, uint8_t buffer[10]) {
  n = (n << 1) ^ (n >> 63);
  return _pbcV_encode(n, buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_pbcV_zigzag>:
  endbr64
  mov    $0x3f,%ecx
  lea    (%rdi,%rdi,1),%eax
  sar    %cl,%edi
  xor    %eax,%edi
  jmp    1050 <_pbcV_encode@plt>
```

assistant: ```c
int _pbcV_zigzag(int64_t n, uint8_t buffer[10]) {
  n = (n << 1) ^ (n >> 63);
  return _pbcV_encode(n, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_pbcV_zigzag>:
  endbr64
  mov    $0x3f,%ecx
  lea    (%rdi,%rdi,1),%eax
  sar    %cl,%edi
  xor    %eax,%edi
  jmp    1050 <_pbcV_encode@plt>
```

assistant: ```c
int _pbcV_zigzag(int64_t n, uint8_t buffer[10]) {
  n = (n << 1) ^ (n >> 63);
  return _pbcV_encode(n, buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L33
L7:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L28
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L28:
  addl   $0x1,-0x14(%rbp)
L33:
  cmpl   $0x63,-0x14(%rbp)
  jle    L7
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D31
type_infered: string

tool: D21: %d

tool: D31: %d


assistant: ```c
int main() {
  int i, n, hg, po;
  scanf("%d", &n);
  hg = n;
  po = 1;
  for (i = 1; i <= 99; i++) {
    scanf("%d", &n);
    if (n > hg) {
      hg = n;
      po = i;
    }
  }
  po = po + 1;
  printf("%d\n", hg);
  printf("%d\n", po);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  mov    $0x1,%r13d
  mov    $0x1,%ebx
  lea    D1(%rip),%r12
  jmp    L39
L42:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L4
L39:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L42
  mov    %ebx,%r13d
  mov    %eax,%ebp
  jmp    L42
L4:
  mov    %ebp,%esi
  lea    D28(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x1(%r13),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string

tool: D1: %d

tool: D28: %d


assistant: ```c
int main() {
  int i, n, hg, po;
  scanf("%d", &n);
  hg = n;
  po = 1;
  for (i = 1; i <= 99; i++) {
    scanf("%d", &n);
    if (n > hg) {
      hg = n;
      po = i;
    }
  }
  po = po + 1;
  printf("%d\n", hg);
  printf("%d\n", po);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L20
  mov    %ebx,%r14d
  mov    %eax,%ebp
L20:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L0
  mov    %ebp,%esi
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x1(%r14),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D9: %d

tool: D0: %d


assistant: ```c
int main() {
  int i, n, hg, po;
  scanf("%d", &n);
  hg = n;
  po = 1;
  for (i = 1; i <= 99; i++) {
    scanf("%d", &n);
    if (n > hg) {
      hg = n;
      po = i;
    }
  }
  po = po + 1;
  printf("%d\n", hg);
  printf("%d\n", po);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jle    L3
  mov    %ebx,%r14d
  mov    %eax,%ebp
L3:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  jne    L27
  mov    %ebp,%esi
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x1(%r14),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D17
datatype: string

tool: D1: %d

tool: D17: %d


assistant: ```c
int main() {
  int i, n, hg, po;
  scanf("%d", &n);
  hg = n;
  po = 1;
  for (i = 1; i <= 99; i++) {
    scanf("%d", &n);
    if (n > hg) {
      hg = n;
      po = i;
    }
  }
  po = po + 1;
  printf("%d\n", hg);
  printf("%d\n", po);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  fldt   (%rax)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L0:
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x4,-0x4(%rbp)
  jle    L0
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string

tool: D26: %s 

tool: D11: %.5Le = 

tool: D14: %04x 

assistant: ```c
void prnum(str, x) char *str;
unsigned short *x;
{
  int i;
  printf("%s ", str);
  printf("%.5Le = ", *(long double *)x);
  for (i = 0; i < 5; i++)
    printf("%04x ", *x++);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prnum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  push   0x8(%rbx)
  push   (%rbx)
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xa(%rbx),%r12
  add    $0x10,%rsp
  lea    D7(%rip),%rbp
L6:
  add    $0x2,%rbx
  movzwl -0x2(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D26: %s 

tool: D9: %.5Le = 

tool: D7: %04x 

assistant: ```c
void prnum(str, x) char *str;
unsigned short *x;
{
  int i;
  printf("%s ", str);
  printf("%.5Le = ", *(long double *)x);
  for (i = 0; i < 5; i++)
    printf("%04x ", *x++);
}
```