ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L23
L76:
  movl   $0xc,-0x24(%rbp)
  jmp    L42
L11:
  movl   $0x0,-0x20(%rbp)
  jmp    L66
L124:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x28(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <rel_part_ecr@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L66:
  cmpl   $0x1,-0x20(%rbp)
  jle    L124
  addl   $0x1,-0x24(%rbp)
L42:
  cmpl   $0x64,-0x24(%rbp)
  jle    L11
  addl   $0x1,-0x28(%rbp)
L23:
  cmpl   $0x1,-0x28(%rbp)
  jle    L76
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x32,-0xc(%rbp)
  movl   $0x64,-0x1c(%rbp)
  jmp    L116
L125:
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L30:
  movl   $0xc,-0x14(%rbp)
  jmp    L94
L31:
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L121:
  mov    -0x10(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0xc(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <rel_single_ecr@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%r8d
  mov    -0x14(%rbp),%edi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0x8(%rbp),%esi
  push   %rsi
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x10(%rbp)
L6:
  cmpl   $0x1,-0x10(%rbp)
  jle    L121
  addl   $0x1,-0x14(%rbp)
L94:
  cmpl   $0x64,-0x14(%rbp)
  jle    L31
  addl   $0x1,-0x18(%rbp)
L32:
  cmpl   $0x1,-0x18(%rbp)
  jle    L30
  addl   $0x1,-0x1c(%rbp)
L116:
  cmpl   $0xc7,-0x1c(%rbp)
  jle    L125
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D8: sex	age	orient	ecr

tool: D15: %d	%d	%d	%d


tool: D13: id	bcr	sex	age	orient	ecr

tool: D17: %d	%d	%d	%d	%d	%d


assistant: ```c
int main(int argc, char *argv) {
  printf("sex\tage\torient\tecr\n");
  for (int s = 0; s <= 1; ++s) {
    for (int a = 12; a <= 100; ++a) {
      for (int o = 0; o <= 1; ++o) {
        int ecr = rel_part_ecr(s, a, o);
        printf("%d\t%d\t%d\t%d\n", s, a, o, ecr);
      }
    }
  }
  printf("id\tbcr\tsex\tage\torient\tecr\n");
  int id = 50;
  for (int b = 100; b < 200; ++b) {
    for (int s = 0; s <= 1; ++s) {
      for (int a = 12; a <= 100; ++a) {
        for (int o = 0; o <= 1; ++o) {
          int ecr = rel_single_ecr(id, b, s, a, o);
          printf("%d\t%d\t%d\t%d\t%d\t%d\n", id, b, s, a, o, ecr);
        }
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D31(%rip),%r12
L14:
  mov    $0xc,%ebx
L97:
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  mov    %eax,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  mov    %eax,%r8d
  mov    $0x1,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L97
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  jne    L14
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%r13d
  lea    D10(%rip),%r14
  jmp    L5
L78:
  add    $0x1,%ebp
  cmp    $0x65,%ebp
  je     L70
L12:
  mov    $0x0,%ebx
L22:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    $0x32,%edi
  call   <rel_single_ecr@plt>
  sub    $0x8,%rsp
  push   %rax
  mov    %ebx,%r9d
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    $0x32,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x10,%rsp
  cmp    $0x2,%ebx
  jne    L22
  jmp    L78
L70:
  add    $0x1,%r12d
  cmp    $0x2,%r12d
  je     L43
L31:
  mov    $0xc,%ebp
  jmp    L12
L43:
  add    $0x1,%r13d
  cmp    $0xc8,%r13d
  je     L41
L5:
  mov    $0x0,%r12d
  jmp    L31
L41:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string

tool: D14: sex	age	orient	ecr

tool: D31: %d	%d	%d	%d


tool: D16: id	bcr	sex	age	orient	ecr

tool: D10: %d	%d	%d	%d	%d	%d


assistant: ```c
int main(int argc, char *argv) {
  printf("sex\tage\torient\tecr\n");
  for (int s = 0; s <= 1; ++s) {
    for (int a = 12; a <= 100; ++a) {
      for (int o = 0; o <= 1; ++o) {
        int ecr = rel_part_ecr(s, a, o);
        printf("%d\t%d\t%d\t%d\n", s, a, o, ecr);
      }
    }
  }
  printf("id\tbcr\tsex\tage\torient\tecr\n");
  int id = 50;
  for (int b = 100; b < 200; ++b) {
    for (int s = 0; s <= 1; ++s) {
      for (int a = 12; a <= 100; ++a) {
        for (int o = 0; o <= 1; ++o) {
          int ecr = rel_single_ecr(id, b, s, a, o);
          printf("%d\t%d\t%d\t%d\t%d\t%d\n", id, b, s, a, o, ecr);
        }
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <puts@plt>
L9:
  mov    $0xc,%ebx
L35:
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %eax,%r8d
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  mov    %ebx,%edx
  mov    $0x1,%ecx
  mov    %ebp,%esi
  mov    %eax,%r8d
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L35
  cmp    $0x1,%ebp
  je     L71
  mov    $0x1,%ebp
  jmp    L9
L71:
  lea    D13(%rip),%rdi
  mov    $0x64,%r13d
  lea    D20(%rip),%r14
  call   <puts@plt>
L25:
  xor    %r12d,%r12d
L67:
  mov    $0xc,%ebp
  nopl   (%rax)
L89:
  xor    %ebx,%ebx
L22:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    $0x32,%edi
  call   <rel_single_ecr@plt>
  sub    $0x8,%rsp
  mov    %r13d,%edx
  mov    %ebx,%r9d
  push   %rax
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    $0x32,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    $0x1,%ebx
  jne    L12
  add    $0x1,%ebp
  cmp    $0x65,%ebp
  jne    L89
  cmp    $0x1,%r12d
  je     L88
  mov    $0x1,%r12d
  jmp    L67
  nopl   0x0(%rax)
L12:
  mov    $0x1,%ebx
  jmp    L22
L88:
  add    $0x1,%r13d
  cmp    $0xc8,%r13d
  jne    L25
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string

tool: D2: sex	age	orient	ecr

tool: D27: %d	%d	%d	%d


tool: D13: id	bcr	sex	age	orient	ecr

tool: D20: %d	%d	%d	%d	%d	%d


assistant: ```c
int main(int argc, char *argv) {
  printf("sex\tage\torient\tecr\n");
  for (int s = 0; s <= 1; ++s) {
    for (int a = 12; a <= 100; ++a) {
      for (int o = 0; o <= 1; ++o) {
        int ecr = rel_part_ecr(s, a, o);
        printf("%d\t%d\t%d\t%d\n", s, a, o, ecr);
      }
    }
  }
  printf("id\tbcr\tsex\tage\torient\tecr\n");
  int id = 50;
  for (int b = 100; b < 200; ++b) {
    for (int s = 0; s <= 1; ++s) {
      for (int a = 12; a <= 100; ++a) {
        for (int o = 0; o <= 1; ++o) {
          int ecr = rel_single_ecr(id, b, s, a, o);
          printf("%d\t%d\t%d\t%d\t%d\t%d\n", id, b, s, a, o, ecr);
        }
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <puts@plt>
L22:
  mov    $0xc,%ebx
L43:
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  xor    %ecx,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %eax,%r8d
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <rel_part_ecr@plt>
  mov    %ebx,%edx
  mov    $0x1,%ecx
  mov    %ebp,%esi
  mov    %eax,%r8d
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x65,%ebx
  jne    L43
  cmp    $0x1,%ebp
  je     L29
  mov    $0x1,%ebp
  jmp    L22
L29:
  lea    D1(%rip),%rdi
  mov    $0x64,%r13d
  lea    D33(%rip),%r14
  call   <puts@plt>
L35:
  xor    %r12d,%r12d
L79:
  mov    $0xc,%ebp
  nopl   (%rax)
L19:
  xor    %ebx,%ebx
L18:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    $0x32,%edi
  call   <rel_single_ecr@plt>
  sub    $0x8,%rsp
  mov    %r13d,%edx
  mov    %ebx,%r9d
  push   %rax
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    $0x32,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  cmp    $0x1,%ebx
  jne    L59
  add    $0x1,%ebp
  cmp    $0x65,%ebp
  jne    L19
  cmp    $0x1,%r12d
  je     L7
  mov    $0x1,%r12d
  jmp    L79
  nopl   0x0(%rax)
L59:
  mov    $0x1,%ebx
  jmp    L18
L7:
  add    $0x1,%r13d
  cmp    $0xc8,%r13d
  jne    L35
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D33
datatype: string

tool: D0: sex	age	orient	ecr

tool: D35: %d	%d	%d	%d


tool: D1: id	bcr	sex	age	orient	ecr

tool: D33: %d	%d	%d	%d	%d	%d


assistant: ```c
int main(int argc, char *argv) {
  printf("sex\tage\torient\tecr\n");
  for (int s = 0; s <= 1; ++s) {
    for (int a = 12; a <= 100; ++a) {
      for (int o = 0; o <= 1; ++o) {
        int ecr = rel_part_ecr(s, a, o);
        printf("%d\t%d\t%d\t%d\n", s, a, o, ecr);
      }
    }
  }
  printf("id\tbcr\tsex\tage\torient\tecr\n");
  int id = 50;
  for (int b = 100; b < 200; ++b) {
    for (int s = 0; s <= 1; ++s) {
      for (int a = 12; a <= 100; ++a) {
        for (int o = 0; o <= 1; ++o) {
          int ecr = rel_single_ecr(id, b, s, a, o);
          printf("%d\t%d\t%d\t%d\t%d\t%d\n", id, b, s, a, o, ecr);
        }
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L21
  mov    -0x10(%rbp),%rax
  jmp    L44
L21:
  movl   $0x0,-0x18(%rbp)
  jmp    L91
L52:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L87
  shll   -0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L84
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L87
L84:
  mov    -0x10(%rbp),%rax
  jmp    L44
L87:
  cmpl   $0xa,-0x14(%rbp)
  jne    L67
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L71
  subl   $0x1,-0x20(%rbp)
  jmp    L91
L71:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L44
L67:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L91:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L52
  mov    $0x0,%eax
L44:
  leave
  ret
```

assistant: ```c
char *get_line(FILE *pfile, int continue_ch) {
  char *str;
  char *tmp_str;
  int str_len;
  int str_size;
  int ch;
  int last_ch;
  str_len = 0;
  str_size = 10;
  str = malloc(sizeof(char) * str_size);
  if (!str) {
    return (str);
  }
  last_ch = '\0';
  while ((ch = fgetc(pfile)) != EOF) {
    if (str_len >= str_size) {
      str_size *= 2;
      tmp_str = realloc(str, sizeof(char) * str_size);
      if (tmp_str) {
        str = tmp_str;
      } else {
        return (str);
      }
    }
    if (ch == '\n') {
      if (last_ch == continue_ch) {
        str_len--;
      } else {
        str[str_len++] = '\0';
        return (str);
      }
    } else {
      str[str_len++] = ch;
      last_ch = ch;
    }
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,0xc(%rsp)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L83
  mov    $0x0,%r15d
  mov    $0xa,%r12d
  mov    $0x0,%ebp
  jmp    L29
L44:
  add    %r12d,%r12d
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L83
  mov    %rax,%r13
  jmp    L50
L84:
  cmp    0xc(%rsp),%r15d
  jne    L11
  sub    $0x1,%ebp
L29:
  mov    %r14,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  cmp    %ebx,(%rax)
  je     L60
  cmp    %r12d,%ebp
  jge    L44
L50:
  cmp    $0xa,%ebx
  je     L84
  movslq %ebp,%rax
  mov    %bl,0x0(%r13,%rax,1)
  mov    %ebx,%r15d
  lea    0x1(%rbp),%ebp
  jmp    L29
L11:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  jmp    L83
L60:
  mov    $0x0,%r13d
L83:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *get_line(FILE *pfile, int continue_ch) {
  char *str;
  char *tmp_str;
  int str_len;
  int str_size;
  int ch;
  int last_ch;
  str_len = 0;
  str_size = 10;
  str = malloc(sizeof(char) * str_size);
  if (!str) {
    return (str);
  }
  last_ch = '\0';
  while ((ch = fgetc(pfile)) != EOF) {
    if (str_len >= str_size) {
      str_size *= 2;
      tmp_str = realloc(str, sizeof(char) * str_size);
      if (tmp_str) {
        str = tmp_str;
      } else {
        return (str);
      }
    }
    if (ch == '\n') {
      if (last_ch == continue_ch) {
        str_len--;
      } else {
        str[str_len++] = '\0';
        return (str);
      }
    } else {
      str[str_len++] = ch;
      last_ch = ch;
    }
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  test   %rax,%rax
  je     L53
  mov    D7(%rip),%r13
  mov    %rax,%r12
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  mov    $0xa,%ebx
  nopl   (%rax)
L24:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L53
L31:
  cmp    %ebx,%r15d
  jge    L8
L77:
  cmp    $0xa,%edx
  je     L36
  movslq %r15d,%rax
  mov    %rbp,%rdi
  mov    %edx,%r14d
  add    $0x1,%r15d
  mov    %dl,(%r12,%rax,1)
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  jne    L31
L53:
  xor    %r12d,%r12d
L66:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L36:
  cmp    0xc(%rsp),%r14d
  jne    L54
  sub    $0x1,%r15d
  jmp    L24
  nopl   (%rax)
L8:
  add    %ebx,%ebx
  mov    %r12,%rdi
  mov    %edx,0x8(%rsp)
  mov    %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L66
  mov    0x8(%rsp),%edx
  mov    %rax,%r12
  jmp    L77
  xchg   %ax,%ax
L54:
  movslq %r15d,%rcx
  movb   $0x0,(%r12,%rcx,1)
  jmp    L66
```

assistant: ```c
char *get_line(FILE *pfile, int continue_ch) {
  char *str;
  char *tmp_str;
  int str_len;
  int str_size;
  int ch;
  int last_ch;
  str_len = 0;
  str_size = 10;
  str = malloc(sizeof(char) * str_size);
  if (!str) {
    return (str);
  }
  last_ch = '\0';
  while ((ch = fgetc(pfile)) != EOF) {
    if (str_len >= str_size) {
      str_size *= 2;
      tmp_str = realloc(str, sizeof(char) * str_size);
      if (tmp_str) {
        str = tmp_str;
      } else {
        return (str);
      }
    }
    if (ch == '\n') {
      if (last_ch == continue_ch) {
        str_len--;
      } else {
        str[str_len++] = '\0';
        return (str);
      }
    } else {
      str[str_len++] = ch;
      last_ch = ch;
    }
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  test   %rax,%rax
  je     L82
  mov    D1(%rip),%r13
  mov    %rax,%r12
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  mov    $0xa,%ebx
  nopl   (%rax)
L78:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L82
L97:
  cmp    %ebx,%r15d
  jge    L93
L56:
  cmp    $0xa,%edx
  je     L60
  movslq %r15d,%rax
  mov    %rbp,%rdi
  mov    %edx,%r14d
  add    $0x1,%r15d
  mov    %dl,(%r12,%rax,1)
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  jne    L97
L82:
  xor    %r12d,%r12d
L70:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L60:
  cmp    0xc(%rsp),%r14d
  jne    L43
  sub    $0x1,%r15d
  jmp    L78
  nopl   (%rax)
L93:
  add    %ebx,%ebx
  mov    %r12,%rdi
  mov    %edx,0x8(%rsp)
  mov    %ebx,%esi
  call   <realloc@plt>
  test   %rax,%rax
  je     L70
  mov    0x8(%rsp),%edx
  mov    %rax,%r12
  jmp    L56
  xchg   %ax,%ax
L43:
  movslq %r15d,%rcx
  movb   $0x0,(%r12,%rcx,1)
  jmp    L70
```

assistant: ```c
char *get_line(FILE *pfile, int continue_ch) {
  char *str;
  char *tmp_str;
  int str_len;
  int str_size;
  int ch;
  int last_ch;
  str_len = 0;
  str_size = 10;
  str = malloc(sizeof(char) * str_size);
  if (!str) {
    return (str);
  }
  last_ch = '\0';
  while ((ch = fgetc(pfile)) != EOF) {
    if (str_len >= str_size) {
      str_size *= 2;
      tmp_str = realloc(str, sizeof(char) * str_size);
      if (tmp_str) {
        str = tmp_str;
      } else {
        return (str);
      }
    }
    if (ch == '\n') {
      if (last_ch == continue_ch) {
        str_len--;
      } else {
        str[str_len++] = '\0';
        return (str);
      }
    } else {
      str[str_len++] = ch;
      last_ch = ch;
    }
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_pdu_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <be64_to_cpu@plt>
  leave
  ret
```

assistant: ```c
unsigned long long get_pdu_int(void *data) {
  const unsigned long long *val = data;
  return be64_to_cpu(*val);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_pdu_int>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <be64_to_cpu@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long long get_pdu_int(void *data) {
  const unsigned long long *val = data;
  return be64_to_cpu(*val);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_pdu_int>:
  endbr64
  mov    (%rdi),%rdi
  jmp    1050 <be64_to_cpu@plt>
```

assistant: ```c
unsigned long long get_pdu_int(void *data) {
  const unsigned long long *val = data;
  return be64_to_cpu(*val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_pdu_int>:
  endbr64
  mov    (%rdi),%rdi
  jmp    1050 <be64_to_cpu@plt>
```

assistant: ```c
unsigned long long get_pdu_int(void *data) {
  const unsigned long long *val = data;
  return be64_to_cpu(*val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D2: Usage:

tool: D17:   %s <dbfile-to-import>


assistant: ```c
void print_help(char *prog_name) {
  printf("Usage:\n");
  printf("  %s <dbfile-to-import>\n", prog_name);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_help>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D3: Usage:

tool: D19:   %s <dbfile-to-import>


assistant: ```c
void print_help(char *prog_name) {
  printf("Usage:\n");
  printf("  %s <dbfile-to-import>\n", prog_name);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D7: Usage:

tool: D3:   %s <dbfile-to-import>


assistant: ```c
void print_help(char *prog_name) {
  printf("Usage:\n");
  printf("  %s <dbfile-to-import>\n", prog_name);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D0: Usage:

tool: D4:   %s <dbfile-to-import>


assistant: ```c
void print_help(char *prog_name) {
  printf("Usage:\n");
  printf("  %s <dbfile-to-import>\n", prog_name);
  printf("\n");
}
```