ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<d2i_ASN1_OBJECT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rdi
  lea    -0x2c(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <ASN1_get_object@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L41
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L18
L41:
  mov    -0x30(%rbp),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L51
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  jmp    L18
L51:
  mov    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <c2i_ASN1_OBJECT@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L67
  mov    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
L67:
  mov    -0x10(%rbp),%rax
  jmp    L59
L18:
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <ASN1error@plt>
  mov    $0x0,%eax
L59:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

assistant: ```c
ASN1_OBJECT *d2i_ASN1_OBJECT(ASN1_OBJECT **a, const unsigned char **pp, long length) {
  const unsigned char *p;
  long len;
  int tag, xclass;
  int inf, i;
  ASN1_OBJECT *ret = NULL;
  p = *pp;
  inf = ASN1_get_object(&p, &len, &tag, &xclass, length);
  if (inf & 0x80) {
    i = ASN1_R_BAD_OBJECT_HEADER;
    goto err;
  }
  if (tag != V_ASN1_OBJECT) {
    i = ASN1_R_EXPECTING_AN_OBJECT;
    goto err;
  }
  ret = c2i_ASN1_OBJECT(a, &p, len);
  if (ret)
    *pp = p;
  return ret;
err:
  ASN1error(i);
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<d2i_ASN1_OBJECT>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rax
  mov    %rax,0x8(%rsp)
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <ASN1_get_object@plt>
  test   $0x80,%al
  jne    L26
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rsp)
  jne    L19
  lea    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rdx
  mov    %rbp,%rdi
  call   <c2i_ASN1_OBJECT@plt>
  test   %rax,%rax
  je     L48
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
  jmp    L48
L26:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  jmp    L5
L19:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
L5:
  call   <ASN1error@plt>
  mov    $0x0,%eax
L48:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *d2i_ASN1_OBJECT(ASN1_OBJECT **a, const unsigned char **pp, long length) {
  const unsigned char *p;
  long len;
  int tag, xclass;
  int inf, i;
  ASN1_OBJECT *ret = NULL;
  p = *pp;
  inf = ASN1_get_object(&p, &len, &tag, &xclass, length);
  if (inf & 0x80) {
    i = ASN1_R_BAD_OBJECT_HEADER;
    goto err;
  }
  if (tag != V_ASN1_OBJECT) {
    i = ASN1_R_EXPECTING_AN_OBJECT;
    goto err;
  }
  ret = c2i_ASN1_OBJECT(a, &p, len);
  if (ret)
    *pp = p;
  return ret;
err:
  ASN1error(i);
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<d2i_ASN1_OBJECT>:
  endbr64
  push   %r12
  mov    %rdx,%r8
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    (%rsi),%rax
  lea    0x8(%rsp),%r12
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    %rax,0x8(%rsp)
  call   <ASN1_get_object@plt>
  test   $0x80,%al
  jne    L12
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rsp)
  jne    L41
  mov    0x10(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <c2i_ASN1_OBJECT@plt>
  test   %rax,%rax
  je     L35
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L41:
  mov    D17(%rip),%rax
  mov    (%rax),%edi
L48:
  call   <ASN1error@plt>
  xor    %eax,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L12:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  jmp    L48
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *d2i_ASN1_OBJECT(ASN1_OBJECT **a, const unsigned char **pp, long length) {
  const unsigned char *p;
  long len;
  int tag, xclass;
  int inf, i;
  ASN1_OBJECT *ret = NULL;
  p = *pp;
  inf = ASN1_get_object(&p, &len, &tag, &xclass, length);
  if (inf & 0x80) {
    i = ASN1_R_BAD_OBJECT_HEADER;
    goto err;
  }
  if (tag != V_ASN1_OBJECT) {
    i = ASN1_R_EXPECTING_AN_OBJECT;
    goto err;
  }
  ret = c2i_ASN1_OBJECT(a, &p, len);
  if (ret)
    *pp = p;
  return ret;
err:
  ASN1error(i);
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<d2i_ASN1_OBJECT>:
  endbr64
  push   %r12
  mov    %rdx,%r8
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    (%rsi),%rax
  lea    0x8(%rsp),%r12
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    %rax,0x8(%rsp)
  call   <ASN1_get_object@plt>
  test   $0x80,%al
  jne    L2
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rsp)
  jne    L54
  mov    0x10(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <c2i_ASN1_OBJECT@plt>
  test   %rax,%rax
  je     L15
  mov    0x8(%rsp),%rdx
  mov    %rdx,(%rbx)
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L54:
  mov    D10(%rip),%rax
  mov    (%rax),%edi
L1:
  call   <ASN1error@plt>
  xor    %eax,%eax
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L2:
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  jmp    L1
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *d2i_ASN1_OBJECT(ASN1_OBJECT **a, const unsigned char **pp, long length) {
  const unsigned char *p;
  long len;
  int tag, xclass;
  int inf, i;
  ASN1_OBJECT *ret = NULL;
  p = *pp;
  inf = ASN1_get_object(&p, &len, &tag, &xclass, length);
  if (inf & 0x80) {
    i = ASN1_R_BAD_OBJECT_HEADER;
    goto err;
  }
  if (tag != V_ASN1_OBJECT) {
    i = ASN1_R_EXPECTING_AN_OBJECT;
    goto err;
  }
  ret = c2i_ASN1_OBJECT(a, &p, len);
  if (ret)
    *pp = p;
  return ret;
err:
  ASN1error(i);
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp_str_cs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L30
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
  jmp    L22
L33:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_str_cs(char *a, char *b) {
  for (; *a == *b; a++, b++)
    if (*a == '\0')
      return 0;
  return *a - *b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmp_str_cs>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L4
  mov    $0x1,%eax
L19:
  test   %dl,%dl
  je     L6
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L19
L4:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cmp_str_cs(char *a, char *b) {
  for (; *a == *b; a++, b++)
    if (*a == '\0')
      return 0;
  return *a - *b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmp_str_cs>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L31
  mov    $0x1,%eax
  jmp    L3
  nopl   (%rax)
L14:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L31
L3:
  test   %dl,%dl
  jne    L14
  xor    %eax,%eax
  ret
L31:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int cmp_str_cs(char *a, char *b) {
  for (; *a == *b; a++, b++)
    if (*a == '\0')
      return 0;
  return *a - *b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp_str_cs>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %dl,%cl
  jne    L0
  mov    $0x1,%eax
  jmp    L37
  nopl   (%rax)
L27:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L0
L37:
  test   %dl,%dl
  jne    L27
  xor    %eax,%eax
  ret
L0:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int cmp_str_cs(char *a, char *b) {
  for (; *a == *b; a++, b++)
    if (*a == '\0')
      return 0;
  return *a - *b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fxp_ln>:
  endbr64
  mov    %edi,%edx
  mov    $0xa65af,%eax
  cmp    $0x7fff,%edi
  jg     L75
  shl    $0x10,%edx
  mov    $0xffff4e8e,%eax
L75:
  cmp    $0x7fffff,%edx
  jg     L102
  shl    $0x8,%edx
  sub    $0x58b91,%eax
L102:
  cmp    $0x7ffffff,%edx
  jg     L54
  shl    $0x4,%edx
  sub    $0x2c5c8,%eax
L54:
  cmp    $0x1fffffff,%edx
  jg     L111
  shl    $0x2,%edx
  sub    $0x162e4,%eax
L111:
  cmp    $0x3fffffff,%edx
  jg     L30
  add    %edx,%edx
  sub    $0xb172,%eax
L30:
  mov    %edx,%ecx
  sar    %ecx
  add    %edx,%ecx
  js     L23
  sub    $0x67cd,%eax
  mov    %ecx,%edx
  sar    $0x2,%edx
  add    %edx,%ecx
L11:
  sub    $0x3920,%eax
  mov    %ecx,%esi
  sar    $0x3,%esi
  add    %ecx,%esi
L22:
  sub    $0x1e27,%eax
  mov    %esi,%ecx
  sar    $0x4,%ecx
  add    %esi,%ecx
L32:
  sub    $0xf85,%eax
  mov    %ecx,%esi
  sar    $0x5,%esi
  add    %ecx,%esi
L19:
  sub    $0x7e1,%eax
  mov    %esi,%ecx
  sar    $0x6,%ecx
  add    %esi,%ecx
L48:
  sub    $0x3f8,%eax
  mov    %ecx,%edx
  sar    $0x7,%edx
  add    %ecx,%edx
L36:
  sub    $0x1fe,%eax
L103:
  mov    $0x80000000,%ecx
  sub    %edx,%ecx
  mov    %ecx,%edx
  sar    $0xf,%edx
  sub    %edx,%eax
  ret
L23:
  mov    %edx,%ecx
  sar    $0x2,%ecx
  add    %edx,%ecx
  jns    L11
  mov    %edx,%esi
  sar    $0x3,%esi
  add    %edx,%esi
  jns    L22
  mov    %edx,%ecx
  sar    $0x4,%ecx
  add    %edx,%ecx
  jns    L32
  mov    %edx,%esi
  sar    $0x5,%esi
  add    %edx,%esi
  jns    L19
  mov    %edx,%ecx
  sar    $0x6,%ecx
  add    %edx,%ecx
  jns    L48
  mov    %edx,%ecx
  sar    $0x7,%ecx
  add    %edx,%ecx
  js     L103
  mov    %ecx,%edx
  jmp    L36
```

assistant: ```c
int fxp_ln(int x) {
  int t, y;
  y = 0xa65af;
  if (x < 0x00008000)
    x <<= 16, y -= 0xb1721;
  if (x < 0x00800000)
    x <<= 8, y -= 0x58b91;
  if (x < 0x08000000)
    x <<= 4, y -= 0x2c5c8;
  if (x < 0x20000000)
    x <<= 2, y -= 0x162e4;
  if (x < 0x40000000)
    x <<= 1, y -= 0x0b172;
  t = x + (x >> 1);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x067cd;
  t = x + (x >> 2);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x03920;
  t = x + (x >> 3);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x01e27;
  t = x + (x >> 4);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x00f85;
  t = x + (x >> 5);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x007e1;
  t = x + (x >> 6);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x003f8;
  t = x + (x >> 7);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x001fe;
  x = 0x80000000 - x;
  y -= x >> 15;
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fxp_ln>:
  endbr64
  mov    %edi,%edx
  mov    $0xa65af,%eax
  cmp    $0x7fff,%edi
  jg     L14
  shl    $0x10,%edx
  mov    $0xffff4e8e,%eax
L14:
  cmp    $0x7fffff,%edx
  jg     L31
  shl    $0x8,%edx
  sub    $0x58b91,%eax
L31:
  cmp    $0x7ffffff,%edx
  jg     L20
  shl    $0x4,%edx
  sub    $0x2c5c8,%eax
L20:
  cmp    $0x1fffffff,%edx
  jg     L59
  shl    $0x2,%edx
  sub    $0x162e4,%eax
L59:
  cmp    $0x3fffffff,%edx
  jg     L67
  add    %edx,%edx
  sub    $0xb172,%eax
L67:
  mov    %edx,%ecx
  sar    %ecx
  add    %edx,%ecx
  js     L94
  mov    %ecx,%edx
  sub    $0x67cd,%eax
  sar    $0x2,%edx
  add    %edx,%ecx
L98:
  mov    %ecx,%esi
  sub    $0x3920,%eax
  sar    $0x3,%esi
  add    %ecx,%esi
L121:
  mov    %esi,%ecx
  sub    $0x1e27,%eax
  sar    $0x4,%ecx
  add    %esi,%ecx
L103:
  mov    %ecx,%esi
  sub    $0xf85,%eax
  sar    $0x5,%esi
  add    %ecx,%esi
L113:
  mov    %esi,%ecx
  sub    $0x7e1,%eax
  sar    $0x6,%ecx
  add    %esi,%ecx
L28:
  mov    %ecx,%edx
  sub    $0x3f8,%eax
  sar    $0x7,%edx
  add    %ecx,%edx
L114:
  sub    $0x1fe,%eax
L12:
  mov    $0x80000000,%ecx
  sub    %edx,%ecx
  mov    %ecx,%edx
  sar    $0xf,%edx
  sub    %edx,%eax
  ret
  xchg   %ax,%ax
L94:
  mov    %edx,%ecx
  sar    $0x2,%ecx
  add    %edx,%ecx
  jns    L98
  mov    %edx,%esi
  sar    $0x3,%esi
  add    %edx,%esi
  jns    L121
  mov    %edx,%ecx
  sar    $0x4,%ecx
  add    %edx,%ecx
  jns    L103
  mov    %edx,%esi
  sar    $0x5,%esi
  add    %edx,%esi
  jns    L113
  mov    %edx,%ecx
  sar    $0x6,%ecx
  add    %edx,%ecx
  jns    L28
  mov    %edx,%ecx
  sar    $0x7,%ecx
  add    %edx,%ecx
  js     L12
  mov    %ecx,%edx
  jmp    L114
```

assistant: ```c
int fxp_ln(int x) {
  int t, y;
  y = 0xa65af;
  if (x < 0x00008000)
    x <<= 16, y -= 0xb1721;
  if (x < 0x00800000)
    x <<= 8, y -= 0x58b91;
  if (x < 0x08000000)
    x <<= 4, y -= 0x2c5c8;
  if (x < 0x20000000)
    x <<= 2, y -= 0x162e4;
  if (x < 0x40000000)
    x <<= 1, y -= 0x0b172;
  t = x + (x >> 1);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x067cd;
  t = x + (x >> 2);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x03920;
  t = x + (x >> 3);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x01e27;
  t = x + (x >> 4);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x00f85;
  t = x + (x >> 5);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x007e1;
  t = x + (x >> 6);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x003f8;
  t = x + (x >> 7);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x001fe;
  x = 0x80000000 - x;
  y -= x >> 15;
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fxp_ln>:
  endbr64
  mov    %edi,%edx
  cmp    $0x7fff,%edi
  jg     L5
  shl    $0x10,%edx
  mov    $0xfff9c2fd,%ecx
  mov    $0xffff4e8e,%eax
L6:
  cmp    $0x7fffff,%edx
  jg     L64
  shl    $0x8,%edx
  mov    %ecx,%eax
L64:
  cmp    $0x7ffffff,%edx
  jg     L51
  shl    $0x4,%edx
  sub    $0x2c5c8,%eax
L51:
  cmp    $0x1fffffff,%edx
  jg     L39
  shl    $0x2,%edx
  sub    $0x162e4,%eax
L39:
  cmp    $0x3fffffff,%edx
  jg     L108
  add    %edx,%edx
  sub    $0xb172,%eax
L108:
  mov    %edx,%ecx
  sar    %ecx
  add    %edx,%ecx
  js     L111
  mov    %ecx,%edx
  sub    $0x67cd,%eax
  sar    $0x2,%edx
  add    %edx,%ecx
L132:
  mov    %ecx,%esi
  sub    $0x3920,%eax
  sar    $0x3,%esi
  add    %ecx,%esi
L84:
  mov    %esi,%ecx
  sub    $0x1e27,%eax
  sar    $0x4,%ecx
  add    %esi,%ecx
L33:
  mov    %ecx,%esi
  sub    $0xf85,%eax
  sar    $0x5,%esi
  add    %ecx,%esi
L60:
  mov    %esi,%ecx
  sub    $0x7e1,%eax
  sar    $0x6,%ecx
  add    %esi,%ecx
L103:
  mov    %ecx,%edx
  sub    $0x3f8,%eax
  sar    $0x7,%edx
  add    %ecx,%edx
L123:
  sub    $0x1fe,%eax
L109:
  mov    $0x80000000,%ecx
  sub    %edx,%ecx
  mov    %ecx,%edx
  sar    $0xf,%edx
  sub    %edx,%eax
  ret
  nop
L5:
  mov    $0x4da1e,%ecx
  mov    $0xa65af,%eax
  jmp    L6
  nop
L111:
  mov    %edx,%ecx
  sar    $0x2,%ecx
  add    %edx,%ecx
  jns    L132
  mov    %edx,%esi
  sar    $0x3,%esi
  add    %edx,%esi
  jns    L84
  mov    %edx,%ecx
  sar    $0x4,%ecx
  add    %edx,%ecx
  jns    L33
  mov    %edx,%esi
  sar    $0x5,%esi
  add    %edx,%esi
  jns    L60
  mov    %edx,%ecx
  sar    $0x6,%ecx
  add    %edx,%ecx
  jns    L103
  mov    %edx,%ecx
  sar    $0x7,%ecx
  add    %edx,%ecx
  js     L109
  mov    %ecx,%edx
  jmp    L123
```

assistant: ```c
int fxp_ln(int x) {
  int t, y;
  y = 0xa65af;
  if (x < 0x00008000)
    x <<= 16, y -= 0xb1721;
  if (x < 0x00800000)
    x <<= 8, y -= 0x58b91;
  if (x < 0x08000000)
    x <<= 4, y -= 0x2c5c8;
  if (x < 0x20000000)
    x <<= 2, y -= 0x162e4;
  if (x < 0x40000000)
    x <<= 1, y -= 0x0b172;
  t = x + (x >> 1);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x067cd;
  t = x + (x >> 2);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x03920;
  t = x + (x >> 3);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x01e27;
  t = x + (x >> 4);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x00f85;
  t = x + (x >> 5);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x007e1;
  t = x + (x >> 6);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x003f8;
  t = x + (x >> 7);
  if ((t & 0x80000000) == 0)
    x = t, y -= 0x001fe;
  x = 0x80000000 - x;
  y -= x >> 15;
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gameresource_test@plt>
  mov    $0x0,%eax
  call   <hankaku_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  gameresource_test();
  hankaku_test();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gameresource_test@plt>
  mov    $0x0,%eax
  call   <hankaku_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gameresource_test();
  hankaku_test();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gameresource_test@plt>
  xor    %eax,%eax
  call   <hankaku_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gameresource_test();
  hankaku_test();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gameresource_test@plt>
  xor    %eax,%eax
  call   <hankaku_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  gameresource_test();
  hankaku_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cag_int_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
size_t cag_int_hash(const int key, const size_t len) {
  (void)len;
  return key;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cag_int_hash>:
  endbr64
  movslq %edi,%rax
  ret
```

assistant: ```c
size_t cag_int_hash(const int key, const size_t len) {
  (void)len;
  return key;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cag_int_hash>:
  endbr64
  movslq %edi,%rax
  ret
```

assistant: ```c
size_t cag_int_hash(const int key, const size_t len) {
  (void)len;
  return key;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cag_int_hash>:
  endbr64
  movslq %edi,%rax
  ret
```

assistant: ```c
size_t cag_int_hash(const int key, const size_t len) {
  (void)len;
  return key;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getltim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L43
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L43
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L43
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x35,%al
  jg     L43
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L43
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L43
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L53
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  jg     L43
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  jne    L43
L53:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  jmp    L45
L43:
  mov    $0xffffffff,%eax
L45:
  leave
  ret
```

assistant: ```c
int getltim(t)
char *t;
{
  if (t[4] == '\0' && t[3] >= '0' && t[3] <= '9' && t[2] >= '0' && t[2] <= '5' && t[1] >= '0' && t[1] <= '9' && (t[0] == '0' || t[0] == '1' || (t[1] <= '3' && t[0] == '2')))
    return (atoi(t));
  else
    return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getltim>:
  endbr64
  cmpb   $0x0,0x4(%rdi)
  jne    L13
  movzbl 0x3(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L2
  movzbl 0x2(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x5,%al
  ja     L42
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L57
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L31
  cmp    $0x32,%dl
  jne    L1
  cmp    $0x33,%al
  jg     L1
L31:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
L13:
  mov    $0xffffffff,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
L42:
  mov    $0xffffffff,%eax
  ret
L57:
  mov    $0xffffffff,%eax
  ret
L1:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getltim(t)
char *t;
{
  if (t[4] == '\0' && t[3] >= '0' && t[3] <= '9' && t[2] >= '0' && t[2] <= '5' && t[1] >= '0' && t[1] <= '9' && (t[0] == '0' || t[0] == '1' || (t[1] <= '3' && t[0] == '2')))
    return (atoi(t));
  else
    return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getltim>:
  endbr64
  cmpb   $0x0,0x4(%rdi)
  jne    L12
  movzbl 0x3(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L12
  movzbl 0x2(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x5,%al
  ja     L12
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L12
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L4
  cmp    $0x32,%dl
  jne    L12
  cmp    $0x33,%al
  jg     L12
L4:
  xor    %eax,%eax
  jmp    1050 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getltim(t)
char *t;
{
  if (t[4] == '\0' && t[3] >= '0' && t[3] <= '9' && t[2] >= '0' && t[2] <= '5' && t[1] >= '0' && t[1] <= '9' && (t[0] == '0' || t[0] == '1' || (t[1] <= '3' && t[0] == '2')))
    return (atoi(t));
  else
    return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<getltim>:
  endbr64
  cmpb   $0x0,0x4(%rdi)
  jne    L61
  movzbl 0x3(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L61
  movzbl 0x2(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x5,%al
  ja     L61
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L61
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L41
  cmp    $0x32,%dl
  jne    L61
  cmp    $0x33,%al
  jg     L61
L41:
  xor    %eax,%eax
  jmp    1050 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L61:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getltim(t)
char *t;
{
  if (t[4] == '\0' && t[3] >= '0' && t[3] <= '9' && t[2] >= '0' && t[2] <= '5' && t[1] >= '0' && t[1] <= '9' && (t[0] == '0' || t[0] == '1' || (t[1] <= '3' && t[0] == '2')))
    return (atoi(t));
  else
    return (-1);
}
```