ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<maxSubsequenceMul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jg     L25
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L42
L25:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L75:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L18
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L53
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L53:
  addl   $0x1,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L75
  mov    -0x8(%rbp),%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int maxSubsequenceMul(const int *src, int len) {
  int i, j;
  int maxMul, lineMul;
  if (len < 2) {
    return *src;
  }
  maxMul = *src;
  for (i = 0; i < len; ++i) {
    lineMul = *(src + i);
    if (lineMul > maxMul) {
      maxMul = lineMul;
    }
    for (j = 1 + i; j < len; ++j) {
      lineMul *= *(src + j);
      if (lineMul > maxMul) {
        maxMul = lineMul;
      }
    }
  }
  return maxMul;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maxSubsequenceMul>:
  endbr64
  cmp    $0x1,%esi
  jle    L30
  mov    (%rdi),%ecx
  mov    %esi,%r9d
  mov    %ecx,%eax
  mov    $0x1,%r8d
L31:
  mov    %r8,%rdx
L2:
  imul   (%rdi,%rdx,4),%eax
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L2
  mov    (%rdi,%r8,4),%eax
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L31
L8:
  mov    %ecx,%eax
  ret
L30:
  mov    (%rdi),%ecx
  jmp    L8
```

assistant: ```c
int maxSubsequenceMul(const int *src, int len) {
  int i, j;
  int maxMul, lineMul;
  if (len < 2) {
    return *src;
  }
  maxMul = *src;
  for (i = 0; i < len; ++i) {
    lineMul = *(src + i);
    if (lineMul > maxMul) {
      maxMul = lineMul;
    }
    for (j = 1 + i; j < len; ++j) {
      lineMul *= *(src + j);
      if (lineMul > maxMul) {
        maxMul = lineMul;
      }
    }
  }
  return maxMul;
}
```
user: What is the c source code of the assembly code below?

```asm
<maxSubsequenceMul>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L0
  movslq %esi,%r9
  mov    %r8d,%eax
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  imul   (%rdi,%rdx,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L6
  mov    (%rdi,%rcx,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L14
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxSubsequenceMul(const int *src, int len) {
  int i, j;
  int maxMul, lineMul;
  if (len < 2) {
    return *src;
  }
  maxMul = *src;
  for (i = 0; i < len; ++i) {
    lineMul = *(src + i);
    if (lineMul > maxMul) {
      maxMul = lineMul;
    }
    for (j = 1 + i; j < len; ++j) {
      lineMul *= *(src + j);
      if (lineMul > maxMul) {
        maxMul = lineMul;
      }
    }
  }
  return maxMul;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<maxSubsequenceMul>:
  endbr64
  mov    (%rdi),%r8d
  cmp    $0x1,%esi
  jle    L26
  movslq %esi,%r9
  mov    %r8d,%eax
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L3:
  imul   (%rdi,%rdx,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L3
  mov    (%rdi,%rcx,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L2
L26:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxSubsequenceMul(const int *src, int len) {
  int i, j;
  int maxMul, lineMul;
  if (len < 2) {
    return *src;
  }
  maxMul = *src;
  for (i = 0; i < len; ++i) {
    lineMul = *(src + i);
    if (lineMul > maxMul) {
      maxMul = lineMul;
    }
    for (j = 1 + i; j < len; ++j) {
      lineMul *= *(src + j);
      if (lineMul > maxMul) {
        maxMul = lineMul;
      }
    }
  }
  return maxMul;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ec_encode_data_update_avx2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r15d
  mov    %r8,%rbp
  mov    %r9,(%rsp)
  mov    0x50(%rsp),%r12
  cmp    $0x1f,%edi
  jle    L47
  cmp    $0x6,%edx
  jle    L14
  lea    (%rsi,%rsi,2),%eax
  shl    $0x6,%eax
  cltq
  mov    %rax,0x8(%rsp)
L76:
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_6vect_mad_avx2@plt>
  add    0x8(%rsp),%rbp
  add    $0x30,%r12
  sub    $0x6,%ebx
  cmp    $0x6,%ebx
  jg     L76
L14:
  cmp    $0x6,%ebx
  ja     L4
  mov    %ebx,%ebx
  lea    D1(%rip),%rdx
  movslq (%rdx,%rbx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L47:
  sub    $0x8,%rsp
  push   %r12
  mov    0x10(%rsp),%r9
  call   <ec_encode_data_update_base@plt>
  add    $0x10,%rsp
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_6vect_mad_avx2@plt>
  jmp    L4
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_5vect_mad_avx2@plt>
  jmp    L4
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_4vect_mad_avx2@plt>
  jmp    L4
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_3vect_mad_avx2@plt>
  jmp    L4
  mov    %r12,%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_2vect_mad_avx2@plt>
  jmp    L4
  mov    (%r12),%r9
  mov    (%rsp),%r8
  mov    %rbp,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <gf_vect_mad_avx2@plt>
  jmp    L4
```

assistant: ```c
void ec_encode_data_update_avx2(int len, int k, int rows, int vec_i, unsigned char *g_tbls, unsigned char *data, unsigned char **coding) {
  if (len < 32) {
    ec_encode_data_update_base(len, k, rows, vec_i, g_tbls, data, coding);
    return;
  }
  while (rows > 6) {
    gf_6vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    g_tbls += 6 * k * 32;
    coding += 6;
    rows -= 6;
  }
  switch (rows) {
  case 6:
    gf_6vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    break;
  case 5:
    gf_5vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    break;
  case 4:
    gf_4vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    break;
  case 3:
    gf_3vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    break;
  case 2:
    gf_2vect_mad_avx2(len, k, vec_i, g_tbls, data, coding);
    break;
  case 1:
    gf_vect_mad_avx2(len, k, vec_i, g_tbls, data, *coding);
    break;
  case 0:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<basefilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  test   %eax,%eax
  je     L38
  cmp    $0x2f,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L16
L38:
  mov    -0x10(%rbp),%rax
  jmp    L36
L16:
  jmp    L2
L36:
  pop    %rbp
  ret
```

assistant: ```c
char const *basefilename(char const *p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basefilename>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rdx
  jmp    L10
L5:
  cmp    $0x2f,%cl
  cmove  %rdx,%rax
L10:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  jne    L5
  ret
```

assistant: ```c
char const *basefilename(char const *p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<basefilename>:
  endbr64
  mov    %rdi,%r8
  jmp    L19
  nopl   0x0(%rax)
L10:
  cmp    $0x2f,%al
  cmove  %rdi,%r8
L19:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L10
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *basefilename(char const *p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<basefilename>:
  endbr64
  mov    %rdi,%r8
  jmp    L18
  nopl   0x0(%rax)
L0:
  cmp    $0x2f,%al
  cmove  %rdi,%r8
L18:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L0
  mov    %r8,%rax
  ret
```

assistant: ```c
char const *basefilename(char const *p) {
  char const *b = p, *q = p;
  for (;;)
    switch (*q++) {
    case '/':
      b = q;
      break;
    case 0:
      return b;
    }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: %d


assistant: ```c
int main() {
  int i = 10;
  const int *const p = &i;
  printf("%d\n", *p);
  i++;
  printf("%d\n", *p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%esi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  int i = 10;
  const int *const p = &i;
  printf("%d\n", *p);
  i++;
  printf("%d\n", *p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %d


assistant: ```c
int main() {
  int i = 10;
  const int *const p = &i;
  printf("%d\n", *p);
  i++;
  printf("%d\n", *p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main() {
  int i = 10;
  const int *const p = &i;
  printf("%d\n", *p);
  i++;
  printf("%d\n", *p);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sockprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xe0,%rsp
  mov    %edi,-0x10d4(%rbp)
  mov    %rsi,-0x10e0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x10e0(%rbp),%rdx
  mov    -0x10c8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x10c8(%rbp),%ecx
  mov    -0x10e0(%rbp),%rdx
  lea    -0x10c0(%rbp),%rax
  mov    $0x1000,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x10c4(%rbp)
  mov    -0x10c8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x10c4(%rbp),%edx
  lea    -0x10c0(%rbp),%rcx
  mov    -0x10d4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <WRITE@plt>
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int sockprint(int fd, char *format, ...) {
  char buffer[4096];
  int len;
  va_list ap;
  va_start(ap, format);
  len = vsnprintf(buffer, sizeof(buffer), format, ap);
  va_end(ap);
  return WRITE(fd, buffer, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sockprint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %rsp,%r13
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    $0x1000,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <WRITE@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockprint(int fd, char *format, ...) {
  char buffer[4096];
  int len;
  va_list ap;
  va_start(ap, format);
  len = vsnprintf(buffer, sizeof(buffer), format, ap);
  va_end(ap);
  return WRITE(fd, buffer, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sockprint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    %rsp,%r14
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x1000,%esi
  mov    %r13d,%ecx
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <WRITE@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockprint(int fd, char *format, ...) {
  char buffer[4096];
  int len;
  va_list ap;
  va_start(ap, format);
  len = vsnprintf(buffer, sizeof(buffer), format, ap);
  va_end(ap);
  return WRITE(fd, buffer, len);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sockprint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  xor    %r13d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    %rsp,%r14
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x1000,%esi
  mov    %r13d,%ecx
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <WRITE@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x1018,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockprint(int fd, char *format, ...) {
  char buffer[4096];
  int len;
  va_list ap;
  va_start(ap, format);
  len = vsnprintf(buffer, sizeof(buffer), format, ap);
  va_end(ap);
  return WRITE(fd, buffer, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<path_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    D8(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
bool path_exists(const char *path) {
  struct stat buf;
  bool found;
  found = (stat(path, &buf) == 0);
  errno = 0;
  return found;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<path_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D8(%rip),%rdx
  movq   $0x0,(%rdx)
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool path_exists(const char *path) {
  struct stat buf;
  bool found;
  found = (stat(path, &buf) == 0);
  errno = 0;
  return found;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<path_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D9(%rip),%rdx
  test   %rax,%rax
  movq   $0x0,(%rdx)
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool path_exists(const char *path) {
  struct stat buf;
  bool found;
  found = (stat(path, &buf) == 0);
  errno = 0;
  return found;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<path_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    D2(%rip),%rdx
  test   %rax,%rax
  movq   $0x0,(%rdx)
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool path_exists(const char *path) {
  struct stat buf;
  bool found;
  found = (stat(path, &buf) == 0);
  errno = 0;
  return found;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_rmt_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L33
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L24
  mov    -0x8(%rbp),%rax
  jmp    L22
L24:
  subq   $0x8,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L18
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *_rmt_strrchr(uint8_t *p, uint8_t *start, uint8_t c) {
  while (p >= start) {
    if (*p == c) {
      return p;
    }
    p--;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_rmt_strrchr>:
  endbr64
  cmp    %rsi,%rdi
  jb     L5
L23:
  cmp    %rdx,(%rdi)
  je     L0
  sub    $0x8,%rdi
  cmp    %rdi,%rsi
  jbe    L23
  mov    $0x0,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint8_t *_rmt_strrchr(uint8_t *p, uint8_t *start, uint8_t c) {
  while (p >= start) {
    if (*p == c) {
      return p;
    }
    p--;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_rmt_strrchr>:
  endbr64
  cmp    %rsi,%rdi
  jae    L30
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L32:
  sub    $0x8,%rdi
  cmp    %rdi,%rsi
  ja     L15
L30:
  cmp    %rdx,(%rdi)
  jne    L32
  mov    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t *_rmt_strrchr(uint8_t *p, uint8_t *start, uint8_t c) {
  while (p >= start) {
    if (*p == c) {
      return p;
    }
    p--;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<_rmt_strrchr>:
  endbr64
  cmp    %rsi,%rdi
  jae    L13
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L31:
  sub    $0x8,%rdi
  cmp    %rdi,%rsi
  ja     L32
L13:
  cmp    %rdx,(%rdi)
  jne    L31
  mov    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t *_rmt_strrchr(uint8_t *p, uint8_t *start, uint8_t c) {
  while (p >= start) {
    if (*p == c) {
      return p;
    }
    p--;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<symeig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L8
L18:
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L3:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  addl   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <tred2@plt>
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <tql2@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L52
L7:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L52:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void symeig(double **A, int n, double **V, double *D) {
  int i, j;
  double *d, *e;
  d = (double *)malloc(sizeof(double) * n);
  e = (double *)malloc(sizeof(double) * n);
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      V[i][j] = A[i][j];
  tred2(V, n, d, e);
  tql2(V, n, d, e);
  for (i = 0; i < n; i++)
    D[i] = d[i];
  free(e);
  free(d);
}
```