user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x14,%eax
  jbe    L199
  mov    $0x0,%eax
L208:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L209
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L208
L122:
  cmp    $0x31,%al
  je     L121
L77:
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,0xc(%rsp)
  jle    L71
L33:
  lea    0xb(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x20,0xb(%rsp)
  jne    L13
  lea    0xb(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0xb(%rsp),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x1,%dl
  ja     L165
  test   %ebx,%ebx
  je     L122
  mov    0xc(%rsp),%ecx
  lea    -0x1(%rcx),%edx
  cmp    %ebx,%edx
  jne    L77
  jmp    L122
L121:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L208
L165:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L208
L199:
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D23(%rip),%r12
  test   %eax,%eax
  jg     L33
L71:
  movslq %ebx,%rbx
  movb   $0x0,0x10(%rsp,%rbx,1)
  mov    $0x3e8,%r13d
  lea    0x10(%rsp),%rbp
  lea    D38(%rip),%r12
  lea    D15(%rip),%r14
  jmp    L169
L173:
  mov    %r14,%rdi
  call   <printf@plt>
L57:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L55
L35:
  cmpb   $0x30,(%rbx,%rbp,1)
  je     L173
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L57
L55:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x31,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L161
  lea    0x30(%rsp),%rsi
  mov    0xc(%rsp),%edx
  mov    %rbp,%rdi
  call   <next_generation@plt>
  sub    $0x1,%r13d
  je     L98
L169:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L35
  jmp    L55
L161:
  mov    $0x0,%eax
  jmp    L208
L98:
  mov    $0x0,%eax
  jmp    L208
L209:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D56
data_type: string
name: retrieve_data
arguments: label: D53
data_type: string
name: retrieve_data
arguments: label: D62
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D38
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string

tool: D56: %d

tool: D53: error: Input error! Space expected.

tool: D62: error: Input error! cell chain must start and end with 0.

tool: D14: error: Input error! 0/1 expected.

tool: D23: %c

tool: D38: *

tool: D15: .

tool: D7: 


assistant: ```c
int main() {
  int len, i = 0, j;
  char str[20], nextStr[20], temp;
  scanf("%d", &len);
  if (len >= 0 && len <= 20) {
    while (i < len) {
      scanf("%c", &temp);
      if (temp != ' ') {
        printf("error: Input error! Space expected.");
        return 1;
      }
      scanf("%c", &temp);
      if (temp == '0' || temp == '1') {
        if ((i == 0 || i == (len - 1)) && temp == '1') {
          printf("error: Input error! cell chain must start and end with 0.");
          return 1;
        }
        str[i] = temp;
      } else {
        printf("error: Input error! 0/1 expected.");
        return 1;
      }
      i++;
    }
    str[i] = '\0';
    for (i = 0; i < 1000; i++) {
      for (j = 0; j < len; j++) {
        if (str[j] == '0')
          printf(".");
        else
          printf("*");
      }
      printf("\n");
      if (strchr(str, '1') == NULL)
        break;
      next_generation(str, nextStr, len);
    }
  }
  return 0;
}
```