ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itoa_own>:
  endbr64
  mov    %edi,%esi
  test   %di,%di
  je     L23
  mov    $0x6,%ecx
  lea    D14(%rip),%rax
  lea    D3(%rip),%r10
  xchg   %ax,%ax
L22:
  movzwl %si,%edx
  mov    %esi,%edi
  movzbl %cl,%r9d
  imul   $0xcccd,%edx,%edx
  shr    $0x13,%edx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  sub    %r8d,%edi
  movzbl %cl,%r8d
  sub    $0x1,%ecx
  movzwl %di,%edi
  movzbl (%r10,%rdi,1),%edi
  mov    %dil,(%rax,%r9,1)
  mov    %esi,%edi
  mov    %edx,%esi
  cmp    $0x9,%di
  jbe    L14
  test   %cl,%cl
  jne    L22
L14:
  add    %r8,%rax
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x7,%r8d
  lea    D14(%rip),%rax
  add    %r8,%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: 0123456789abcdef

assistant: ```c
char *itoa_own(unsigned short val) {
  static char buf[6] = {0, 0, 0, 0, 0, 0};
  unsigned char i = sizeof(buf);
  for (; val && i; --i, val /= 10)
    buf[i] = "0123456789abcdef"[val % 10];
  return &buf[i + 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isalnum_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L31
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L31
  cmpl   $0x7f,-0x4(%rbp)
  jbe    L6
L31:
  mov    $0x1,%eax
  jmp    L29
L6:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int isalnum_utf8(int _ch) {
  unsigned int ch = (unsigned int)_ch;
  return isdigit(_ch) || isalpha(_ch) || (ch > 0x7F);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isalnum_utf8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isdigit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L3
L17:
  pop    %rbx
  ret
L3:
  mov    %ebx,%edi
  call   <isalpha@plt>
  mov    %rax,%rdx
  cmp    $0x7f,%ebx
  seta   %al
  test   %rdx,%rdx
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  jmp    L17
```

assistant: ```c
int isalnum_utf8(int _ch) {
  unsigned int ch = (unsigned int)_ch;
  return isdigit(_ch) || isalpha(_ch) || (ch > 0x7F);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isalnum_utf8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L8
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  call   <isalpha@plt>
  cmp    $0x7f,%ebx
  pop    %rbx
  mov    %rax,%r8
  seta   %al
  test   %r8,%r8
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int isalnum_utf8(int _ch) {
  unsigned int ch = (unsigned int)_ch;
  return isdigit(_ch) || isalpha(_ch) || (ch > 0x7F);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isalnum_utf8>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isdigit@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L6
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <isalpha@plt>
  cmp    $0x7f,%ebx
  pop    %rbx
  mov    %rax,%r8
  seta   %al
  test   %r8,%r8
  setne  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int isalnum_utf8(int _ch) {
  unsigned int ch = (unsigned int)_ch;
  return isdigit(_ch) || isalpha(_ch) || (ch > 0x7F);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L36
  cmpb   $0x39,-0x4(%rbp)
  jg     L36
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L85
L36:
  cmpb   $0x40,-0x4(%rbp)
  jle    L18
  cmpb   $0x46,-0x4(%rbp)
  jg     L18
  movsbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L85
L18:
  cmpb   $0x60,-0x4(%rbp)
  jle    L9
  cmpb   $0x66,-0x4(%rbp)
  jg     L9
  movsbl -0x4(%rbp),%eax
  sub    $0x61,%eax
  jmp    L85
L9:
  mov    $0x291,%edx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <c_assertion_message@plt>
  mov    $0x0,%eax
L85:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c

tool: D0: * Assertion: should not be reached at %s:%d


assistant: ```c
int decode(char p) {
  if (p >= '0' && p <= '9')
    return p - '0';
  if (p >= 'A' && p <= 'F')
    return p - 'A';
  if (p >= 'a' && p <= 'f')
    return p - 'a';
  do {
    c_assertion_message("* Assertion: should not be reached at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c", 657);
  } while (0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L24
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L28
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  ja     L4
  movsbl %dil,%edi
  lea    -0x61(%rdi),%eax
  ret
L24:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L28:
  movsbl %dil,%edi
  lea    -0x41(%rdi),%eax
  ret
L4:
  sub    $0x8,%rsp
  mov    $0x291,%edx
  lea    D18(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <c_assertion_message@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c

tool: D1: * Assertion: should not be reached at %s:%d


assistant: ```c
int decode(char p) {
  if (p >= '0' && p <= '9')
    return p - '0';
  if (p >= 'A' && p <= 'F')
    return p - 'A';
  if (p >= 'a' && p <= 'f')
    return p - 'a';
  do {
    c_assertion_message("* Assertion: should not be reached at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c", 657);
  } while (0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L11
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L11
  sub    $0x61,%edi
  cmp    $0x5,%dil
  ja     L22
  movsbl %dil,%eax
  ret
L11:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L22:
  sub    $0x8,%rsp
  mov    $0x291,%edx
  lea    D9(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <c_assertion_message@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c

tool: D3: * Assertion: should not be reached at %s:%d


assistant: ```c
int decode(char p) {
  if (p >= '0' && p <= '9')
    return p - '0';
  if (p >= 'A' && p <= 'F')
    return p - 'A';
  if (p >= 'a' && p <= 'f')
    return p - 'a';
  do {
    c_assertion_message("* Assertion: should not be reached at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c", 657);
  } while (0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L8
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L8
  sub    $0x61,%edi
  cmp    $0x5,%dil
  ja     L22
  movsbl %dil,%eax
  ret
L8:
  movsbl %al,%eax
  ret
  nopl   0x0(%rax)
L22:
  sub    $0x8,%rsp
  mov    $0x291,%edx
  lea    D5(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <c_assertion_message@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c

tool: D15: * Assertion: should not be reached at %s:%d


assistant: ```c
int decode(char p) {
  if (p >= '0' && p <= '9')
    return p - '0';
  if (p >= 'A' && p <= 'F')
    return p - 'A';
  if (p >= 'a' && p <= 'f')
    return p - 'a';
  do {
    c_assertion_message("* Assertion: should not be reached at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/rig-project/clib/refs/heads/master/clib/cstr.c", 657);
  } while (0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HASH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  shll   -0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int HASH(char *str) {
  int idx = 0;
  while (*str) {
    idx = idx << 1;
    idx += *str;
    str++;
  }
  return (idx & (256 - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HASH>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L23
  mov    $0x0,%eax
L18:
  movsbl %dl,%edx
  lea    (%rdx,%rax,2),%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L18
L6:
  movzbl %al,%eax
  ret
L23:
  mov    $0x0,%eax
  jmp    L6
```

assistant: ```c
int HASH(char *str) {
  int idx = 0;
  while (*str) {
    idx = idx << 1;
    idx += *str;
    str++;
  }
  return (idx & (256 - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HASH>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L12
  nopl   (%rax)
L3:
  add    $0x1,%rdi
  lea    (%rdx,%rax,2),%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
int HASH(char *str) {
  int idx = 0;
  while (*str) {
    idx = idx << 1;
    idx += *str;
    str++;
  }
  return (idx & (256 - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HASH>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L10
  nopl   (%rax)
L14:
  add    $0x1,%rdi
  lea    (%rdx,%rax,2),%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
int HASH(char *str) {
  int idx = 0;
  while (*str) {
    idx = idx << 1;
    idx += *str;
    str++;
  }
  return (idx & (256 - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gl_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  cmpl   $0x0,-0x1c(%rbp)
  je     L10
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <gl_err@plt>
L10:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: No more memory

assistant: ```c
void *gl_realloc(void *ptr, int size) {
  void *ptr2;
  ptr2 = realloc(ptr, size);
  if (ptr2 == 0 && size)
    gl_err("No more memory");
  return ptr2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gl_realloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L11
  test   %ebp,%ebp
  jne    L15
L11:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D5(%rip),%rdi
  call   <gl_err@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: No more memory

assistant: ```c
void *gl_realloc(void *ptr, int size) {
  void *ptr2;
  ptr2 = realloc(ptr, size);
  if (ptr2 == 0 && size)
    gl_err("No more memory");
  return ptr2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gl_realloc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L12
  test   %ebx,%ebx
  jne    L3
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  lea    D6(%rip),%rdi
  call   <gl_err@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: No more memory

assistant: ```c
void *gl_realloc(void *ptr, int size) {
  void *ptr2;
  ptr2 = realloc(ptr, size);
  if (ptr2 == 0 && size)
    gl_err("No more memory");
  return ptr2;
}
```
user: What is the c source code of the assembly code below?

```asm
<gl_realloc>:
  endbr64
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L5
  test   %ebx,%ebx
  jne    L8
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D1(%rip),%rdi
  call   <gl_err@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: No more memory

assistant: ```c
void *gl_realloc(void *ptr, int size) {
  void *ptr2;
  ptr2 = realloc(ptr, size);
  if (ptr2 == 0 && size)
    gl_err("No more memory");
  return ptr2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timerinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x34,%esi
  mov    $0x43,%edi
  call   <outb@plt>
  mov    $0x9c,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x2e,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x0,%edi
  call   <picenable@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timerinit(void) {
  outb((0x040 + 3), 0x00 | 0x04 | 0x30);
  outb(0x040, ((1193182 + (100) / 2) / (100)) % 256);
  outb(0x040, ((1193182 + (100) / 2) / (100)) / 256);
  picenable(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timerinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%esi
  mov    $0x43,%edi
  call   <outb@plt>
  mov    $0x9c,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x2e,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x0,%edi
  call   <picenable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void timerinit(void) {
  outb((0x040 + 3), 0x00 | 0x04 | 0x30);
  outb(0x040, ((1193182 + (100) / 2) / (100)) % 256);
  outb(0x040, ((1193182 + (100) / 2) / (100)) / 256);
  picenable(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<timerinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%esi
  mov    $0x43,%edi
  call   <outb@plt>
  mov    $0x9c,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x40,%edi
  mov    $0x2e,%esi
  call   <outb@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <picenable@plt>
```

assistant: ```c
void timerinit(void) {
  outb((0x040 + 3), 0x00 | 0x04 | 0x30);
  outb(0x040, ((1193182 + (100) / 2) / (100)) % 256);
  outb(0x040, ((1193182 + (100) / 2) / (100)) / 256);
  picenable(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<timerinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%esi
  mov    $0x43,%edi
  call   <outb@plt>
  mov    $0x9c,%esi
  mov    $0x40,%edi
  call   <outb@plt>
  mov    $0x40,%edi
  mov    $0x2e,%esi
  call   <outb@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <picenable@plt>
```

assistant: ```c
void timerinit(void) {
  outb((0x040 + 3), 0x00 | 0x04 | 0x30);
  outb(0x040, ((1193182 + (100) / 2) / (100)) % 256);
  outb(0x040, ((1193182 + (100) / 2) / (100)) / 256);
  picenable(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x0,-0x18(%rbp)
  movq   $0x3,-0x10(%rbp)
  movq   $0x10bdb,-0x8(%rbp)
  jmp    L6
L56:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L50
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <isNumberPrime@plt>
  test   %rax,%rax
  je     L50
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rax,-0x8(%rbp)
  movq   $0x3,-0x10(%rbp)
  cmpq   $0x1,-0x8(%rbp)
  je     L0
L50:
  addq   $0x2,-0x10(%rbp)
L6:
  cmpq   $0x10bdb,-0x10(%rbp)
  jle    L56
  jmp    L10
L0:
  nop
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x10bdb,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D15: Prime denominator = %lu currentLargestPrimeDivisor = %lu


tool: D6: Largest Prime Divisor of %lu = %lu


assistant: ```c
int main(void) {
  long currentLargestPrimeDivisor = 0;
  long primeDenominator = 3;
  long numerator = 68571;
  if (0 == 68571 % 2) {
    currentLargestPrimeDivisor = 2;
  } else {
    while (primeDenominator <= 68571) {
      if (0 == (numerator % primeDenominator)) {
        if (isNumberPrime(primeDenominator)) {
          currentLargestPrimeDivisor = primeDenominator;
          printf("Prime denominator = %lu currentLargestPrimeDivisor = %lu\n", primeDenominator, currentLargestPrimeDivisor);
          numerator /= primeDenominator;
          primeDenominator = 3;
          if (1 == numerator) {
            break;
          }
        }
      }
      primeDenominator += 2;
    }
  }
  printf("Largest Prime Divisor of %lu = %lu\n", 68571, currentLargestPrimeDivisor);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10bdb,%ebp
  mov    $0x3,%ebx
  mov    $0x0,%r12d
  lea    D4(%rip),%r13
  jmp    L34
L26:
  add    $0x2,%rbx
  cmp    $0x10bdb,%rbx
  jg     L22
L34:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  jne    L26
  mov    %rbx,%rdi
  call   <isNumberPrime@plt>
  test   %rax,%rax
  je     L26
  mov    %rbx,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  mov    %rax,%rbp
  cmp    $0x1,%rax
  je     L13
  mov    %rbx,%r12
  mov    $0x5,%ebx
  jmp    L34
L13:
  mov    %rbx,%r12
L22:
  mov    %r12,%rdx
  mov    $0x10bdb,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D4: Prime denominator = %lu currentLargestPrimeDivisor = %lu


tool: D9: Largest Prime Divisor of %lu = %lu


assistant: ```c
int main(void) {
  long currentLargestPrimeDivisor = 0;
  long primeDenominator = 3;
  long numerator = 68571;
  if (0 == 68571 % 2) {
    currentLargestPrimeDivisor = 2;
  } else {
    while (primeDenominator <= 68571) {
      if (0 == (numerator % primeDenominator)) {
        if (isNumberPrime(primeDenominator)) {
          currentLargestPrimeDivisor = primeDenominator;
          printf("Prime denominator = %lu currentLargestPrimeDivisor = %lu\n", primeDenominator, currentLargestPrimeDivisor);
          numerator /= primeDenominator;
          primeDenominator = 3;
          if (1 == numerator) {
            break;
          }
        }
      }
      primeDenominator += 2;
    }
  }
  printf("Largest Prime Divisor of %lu = %lu\n", 68571, currentLargestPrimeDivisor);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    $0x10bdb,%ebp
  push   %rbx
  mov    $0x3,%ebx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x2,%rbx
  cmp    $0x10bdb,%rbx
  jg     L30
L18:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  mov    %rax,%r12
  test   %rdx,%rdx
  jne    L11
  mov    %rbx,%rdi
  call   <isNumberPrime@plt>
  test   %rax,%rax
  je     L11
  mov    %rbx,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %r12,%rbp
  call   <printf@plt>
  mov    %rbx,%r13
  cmp    $0x1,%r12
  je     L30
  mov    $0x5,%ebx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r13,%rdx
  mov    $0x10bdb,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D15
type: string

tool: D4: Prime denominator = %lu currentLargestPrimeDivisor = %lu


tool: D15: Largest Prime Divisor of %lu = %lu


assistant: ```c
int main(void) {
  long currentLargestPrimeDivisor = 0;
  long primeDenominator = 3;
  long numerator = 68571;
  if (0 == 68571 % 2) {
    currentLargestPrimeDivisor = 2;
  } else {
    while (primeDenominator <= 68571) {
      if (0 == (numerator % primeDenominator)) {
        if (isNumberPrime(primeDenominator)) {
          currentLargestPrimeDivisor = primeDenominator;
          printf("Prime denominator = %lu currentLargestPrimeDivisor = %lu\n", primeDenominator, currentLargestPrimeDivisor);
          numerator /= primeDenominator;
          primeDenominator = 3;
          if (1 == numerator) {
            break;
          }
        }
      }
      primeDenominator += 2;
    }
  }
  printf("Largest Prime Divisor of %lu = %lu\n", 68571, currentLargestPrimeDivisor);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    $0x10bdb,%ebp
  push   %rbx
  mov    $0x3,%ebx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x2,%rbx
  cmp    $0x10bdb,%rbx
  jg     L56
L44:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  mov    %rax,%r12
  test   %rdx,%rdx
  jne    L0
  mov    %rbx,%rdi
  call   <isNumberPrime@plt>
  test   %rax,%rax
  je     L0
  mov    %rbx,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %r12,%rbp
  call   <printf@plt>
  mov    %rbx,%r13
  cmp    $0x1,%r12
  je     L56
  mov    $0x5,%ebx
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %r13,%rdx
  mov    $0x10bdb,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D3: Prime denominator = %lu currentLargestPrimeDivisor = %lu


tool: D11: Largest Prime Divisor of %lu = %lu


assistant: ```c
int main(void) {
  long currentLargestPrimeDivisor = 0;
  long primeDenominator = 3;
  long numerator = 68571;
  if (0 == 68571 % 2) {
    currentLargestPrimeDivisor = 2;
  } else {
    while (primeDenominator <= 68571) {
      if (0 == (numerator % primeDenominator)) {
        if (isNumberPrime(primeDenominator)) {
          currentLargestPrimeDivisor = primeDenominator;
          printf("Prime denominator = %lu currentLargestPrimeDivisor = %lu\n", primeDenominator, currentLargestPrimeDivisor);
          numerator /= primeDenominator;
          primeDenominator = 3;
          if (1 == numerator) {
            break;
          }
        }
      }
      primeDenominator += 2;
    }
  }
  printf("Largest Prime Divisor of %lu = %lu\n", 68571, currentLargestPrimeDivisor);
  return 0;
}
```