ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<l_getParamDig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <l_getParam@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L51
  mov    $0x0,%eax
  jmp    L36
L51:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <s_len@plt>
  cmp    $0x3e,%eax
  jle    L69
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L36
L69:
  lea    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L36
L44:
  mov    -0x10(%rbp),%rax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
char *l_getParamDig(char **ptr, double *dig) {
  char *mem = (*ptr) + 2;
  char *tmp = l_getParam(ptr);
  char *buf;
  if (tmp == NULL)
    return NULL;
  if (s_len(tmp) > 64 - 2) {
    free(tmp);
    return NULL;
  }
  *dig = strtod(tmp, &buf);
  if ((*buf) != '\0') {
    *ptr = mem;
    free(tmp);
    return NULL;
  }
  return tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<l_getParamDig>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%r13
  call   <l_getParam@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L45
  mov    %rax,%rdi
  call   <s_len@plt>
  cmp    $0x3e,%eax
  jg     L23
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <strtod@plt>
  movsd  %xmm0,(%r12)
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  jne    L10
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L45
L10:
  add    $0x2,%r13
  mov    %r13,0x0(%rbp)
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L45
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_getParamDig(char **ptr, double *dig) {
  char *mem = (*ptr) + 2;
  char *tmp = l_getParam(ptr);
  char *buf;
  if (tmp == NULL)
    return NULL;
  if (s_len(tmp) > 64 - 2) {
    free(tmp);
    return NULL;
  }
  *dig = strtod(tmp, &buf);
  if ((*buf) != '\0') {
    *ptr = mem;
    free(tmp);
    return NULL;
  }
  return tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<l_getParamDig>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <l_getParam@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %rax,%rdi
  call   <s_len@plt>
  cmp    $0x3e,%eax
  jg     L40
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strtod@plt>
  mov    (%rsp),%rax
  movsd  %xmm0,0x0(%rbp)
  cmpb   $0x0,(%rax)
  jne    L21
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x2,%r13
  mov    %r13,(%rbx)
L40:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L17
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_getParamDig(char **ptr, double *dig) {
  char *mem = (*ptr) + 2;
  char *tmp = l_getParam(ptr);
  char *buf;
  if (tmp == NULL)
    return NULL;
  if (s_len(tmp) > 64 - 2) {
    free(tmp);
    return NULL;
  }
  *dig = strtod(tmp, &buf);
  if ((*buf) != '\0') {
    *ptr = mem;
    free(tmp);
    return NULL;
  }
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<l_getParamDig>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <l_getParam@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <s_len@plt>
  cmp    $0x3e,%eax
  jg     L40
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strtod@plt>
  mov    (%rsp),%rax
  movsd  %xmm0,0x0(%rbp)
  cmpb   $0x0,(%rax)
  jne    L22
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x2,%r13
  mov    %r13,(%rbx)
L40:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L3
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_getParamDig(char **ptr, double *dig) {
  char *mem = (*ptr) + 2;
  char *tmp = l_getParam(ptr);
  char *buf;
  if (tmp == NULL)
    return NULL;
  if (s_len(tmp) > 64 - 2) {
    free(tmp);
    return NULL;
  }
  *dig = strtod(tmp, &buf);
  if ((*buf) != '\0') {
    *ptr = mem;
    free(tmp);
    return NULL;
  }
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_OS_JumpToTask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_OS_STORE_SP@plt>
  mov    $0x0,%eax
  call   <_OS_SET_FSR_CUR_TASK@plt>
  mov    $0x0,%eax
  call   <_OS_Restore_TaskSP@plt>
  mov    $0x0,%eax
  call   <_OS_Restore_Btemp@plt>
  mov    $0x0,%eax
  call   <_OS_SET_PC@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _OS_JumpToTask(void) {
  _OS_STORE_SP();
  _OS_SET_FSR_CUR_TASK();
  _OS_Restore_TaskSP();
  _OS_Restore_Btemp();
  _OS_SET_PC();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_OS_JumpToTask>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_OS_STORE_SP@plt>
  mov    $0x0,%eax
  call   <_OS_SET_FSR_CUR_TASK@plt>
  mov    $0x0,%eax
  call   <_OS_Restore_TaskSP@plt>
  mov    $0x0,%eax
  call   <_OS_Restore_Btemp@plt>
  mov    $0x0,%eax
  call   <_OS_SET_PC@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _OS_JumpToTask(void) {
  _OS_STORE_SP();
  _OS_SET_FSR_CUR_TASK();
  _OS_Restore_TaskSP();
  _OS_Restore_Btemp();
  _OS_SET_PC();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_OS_JumpToTask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_OS_STORE_SP@plt>
  xor    %eax,%eax
  call   <_OS_SET_FSR_CUR_TASK@plt>
  xor    %eax,%eax
  call   <_OS_Restore_TaskSP@plt>
  xor    %eax,%eax
  call   <_OS_Restore_Btemp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <_OS_SET_PC@plt>
```

assistant: ```c
void _OS_JumpToTask(void) {
  _OS_STORE_SP();
  _OS_SET_FSR_CUR_TASK();
  _OS_Restore_TaskSP();
  _OS_Restore_Btemp();
  _OS_SET_PC();
}
```
user: What is the c source code of the assembly code below?

```asm
<_OS_JumpToTask>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_OS_STORE_SP@plt>
  xor    %eax,%eax
  call   <_OS_SET_FSR_CUR_TASK@plt>
  xor    %eax,%eax
  call   <_OS_Restore_TaskSP@plt>
  xor    %eax,%eax
  call   <_OS_Restore_Btemp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <_OS_SET_PC@plt>
```

assistant: ```c
void _OS_JumpToTask(void) {
  _OS_STORE_SP();
  _OS_SET_FSR_CUR_TASK();
  _OS_Restore_TaskSP();
  _OS_Restore_Btemp();
  _OS_SET_PC();
}
```
user: What is the c source code of the assembly code below?

```asm
<gpzrec_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0xffffffff,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gpzrec_(scan_no, feed_no, rec_no, num_rec, record, return_code) int *scan_no, *feed_no, *rec_no, *num_rec;
char *record;
int *return_code;
{ *return_code = -1; }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gpzrec_>:
  endbr64
  movl   $0xffffffff,(%r9)
  ret
```

assistant: ```c
void gpzrec_(scan_no, feed_no, rec_no, num_rec, record, return_code) int *scan_no, *feed_no, *rec_no, *num_rec;
char *record;
int *return_code;
{ *return_code = -1; }
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gpzrec_>:
  endbr64
  movl   $0xffffffff,(%r9)
  ret
```

assistant: ```c
void gpzrec_(scan_no, feed_no, rec_no, num_rec, record, return_code) int *scan_no, *feed_no, *rec_no, *num_rec;
char *record;
int *return_code;
{ *return_code = -1; }
```
user: Translate the below assembly code into C programming language:

```asm
<gpzrec_>:
  endbr64
  movl   $0xffffffff,(%r9)
  ret
```

assistant: ```c
void gpzrec_(scan_no, feed_no, rec_no, num_rec, record, return_code) int *scan_no, *feed_no, *rec_no, *num_rec;
char *record;
int *return_code;
{ *return_code = -1; }
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  jmp    L14
L34:
  movl   $0x2,-0x4(%rbp)
  jmp    L51
L22:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L41
  addl   $0x1,-0x4(%rbp)
L51:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  cmp    %eax,-0x4(%rbp)
  jle    L22
  jmp    L52
L41:
  nop
L52:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  cmp    %eax,-0x4(%rbp)
  jle    L59
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L59:
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x63,-0x8(%rbp)
  jle    L34
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %d is prime


assistant: ```c
int main() {
  int i, j;
  for (i = 2; i < 100; i++) {
    for (j = 2; j <= (i / j); j++) {
      if (!(i % j))
        break;
    }
    if (j > (i / j))
      printf("%d is prime\n", i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%ebx
  lea    D7(%rip),%rbp
  jmp    L22
L48:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L58:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L33
L22:
  cmp    $0x3,%ebx
  jle    L48
  test   $0x1,%bl
  je     L58
  mov    $0x2,%ecx
L37:
  add    $0x1,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cmp    %ecx,%eax
  jl     L48
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L37
  jmp    L58
L33:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d is prime


assistant: ```c
int main() {
  int i, j;
  for (i = 2; i < 100; i++) {
    for (j = 2; j <= (i / j); j++) {
      if (!(i % j))
        break;
    }
    if (j > (i / j))
      printf("%d is prime\n", i);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%r12d
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0x3,%r12d
  jle    L51
  test   $0x1,%r12b
  je     L3
  mov    $0x2,%ecx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L36:
  test   %edx,%edx
  je     L3
L41:
  mov    %r12d,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  cmp    %ecx,%eax
  jge    L36
L51:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L3:
  add    $0x1,%r12d
  cmp    $0x64,%r12d
  jne    L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: %d is prime


assistant: ```c
int main() {
  int i, j;
  for (i = 2; i < 100; i++) {
    for (j = 2; j <= (i / j); j++) {
      if (!(i % j))
        break;
    }
    if (j > (i / j))
      printf("%d is prime\n", i);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%r12d
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    $0x3,%r12d
  jle    L4
  test   $0x1,%r12b
  je     L45
  mov    $0x2,%ecx
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L36:
  test   %edx,%edx
  je     L45
L33:
  mov    %r12d,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  cmp    %ecx,%eax
  jge    L36
L4:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
L45:
  add    $0x1,%r12d
  cmp    $0x64,%r12d
  jne    L44
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: %d is prime


assistant: ```c
int main() {
  int i, j;
  for (i = 2; i < 100; i++) {
    for (j = 2; j <= (i / j); j++) {
      if (!(i % j))
        break;
    }
    if (j > (i / j))
      printf("%d is prime\n", i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L17
L33:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L6
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D6
type: string

tool: D11: %d %d

tool: D6: %d 

assistant: ```c
int main() {
  int a, n1, n2, num;
  scanf("%d %d", &n1, &n2);
  for (num = n1; num <= n2; num++) {
    a = check_prime(num);
    if (a != 0)
      printf("%d ", num);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L30
  lea    D7(%rip),%rbp
  jmp    L23
L42:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L30
L23:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  je     L42
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L42
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D7
type: string

tool: D15: %d %d

tool: D7: %d 

assistant: ```c
int main() {
  int a, n1, n2, num;
  scanf("%d %d", &n1, &n2);
  for (num = n1; num <= n2; num++) {
    a = check_prime(num);
    if (a != 0)
      printf("%d ", num);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L32
  lea    D1(%rip),%rbp
  jmp    L33
L58:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L32
L33:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  je     L58
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L33
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D0: %d %d

tool: D1: %d 

assistant: ```c
int main() {
  int a, n1, n2, num;
  scanf("%d %d", &n1, &n2);
  for (num = n1; num <= n2; num++) {
    a = check_prime(num);
    if (a != 0)
      printf("%d ", num);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L6
  lea    D8(%rip),%rbp
  xchg   %ax,%ax
L57:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L3
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L57
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jle    L57
  jmp    L6
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D7: %d %d

tool: D8: %d 

assistant: ```c
int main() {
  int a, n1, n2, num;
  scanf("%d %d", &n1, &n2);
  for (num = n1; num <= n2; num++) {
    a = check_prime(num);
    if (a != 0)
      printf("%d ", num);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<on_dict_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <append@plt>
  mov    $0x0,%eax
  call   <indent@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", name);
  indent();
}
```
user: What is the c source code of the assembly code below:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  lea    D5(%rip),%rdi
  call   <append@plt>
  mov    $0x0,%eax
  call   <indent@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", name);
  indent();
}
```
user: Translate the below assembly code into C programming language:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  lea    D0(%rip),%rdi
  call   <append@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <indent@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string

tool: D0: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", name);
  indent();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<on_dict_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  lea    D6(%rip),%rdi
  call   <append@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <indent@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: %s:

assistant: ```c
void on_dict_start(void *ctx, const char *code, const char *name) {
  append("%s:", name);
  indent();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar() {
  foo();
  foo();
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bar() {
  foo();
  foo();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <foo@plt>
```

assistant: ```c
void bar() {
  foo();
  foo();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <foo@plt>
```

assistant: ```c
void bar() {
  foo();
  foo();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<teacher_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <int_input@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: Is Teacher (1 = Teacher, 0 = Not Teacher)?

assistant: ```c
int teacher_input(void) {
  int teacher = 0;
  printf("Is Teacher (1 = Teacher, 0 = Not Teacher)?");
  teacher = int_input();
  return teacher;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<teacher_input>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <int_input@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: Is Teacher (1 = Teacher, 0 = Not Teacher)?

assistant: ```c
int teacher_input(void) {
  int teacher = 0;
  printf("Is Teacher (1 = Teacher, 0 = Not Teacher)?");
  teacher = int_input();
  return teacher;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<teacher_input>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <int_input@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: Is Teacher (1 = Teacher, 0 = Not Teacher)?

assistant: ```c
int teacher_input(void) {
  int teacher = 0;
  printf("Is Teacher (1 = Teacher, 0 = Not Teacher)?");
  teacher = int_input();
  return teacher;
}
```
user: What is the c source code of the assembly code below:

```asm
<teacher_input>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <int_input@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: Is Teacher (1 = Teacher, 0 = Not Teacher)?

assistant: ```c
int teacher_input(void) {
  int teacher = 0;
  printf("Is Teacher (1 = Teacher, 0 = Not Teacher)?");
  teacher = int_input();
  return teacher;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<def_is_inc_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L18
  mov    $0x1,%eax
  jmp    L15
L18:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
bool def_is_inc_comp(int *x, int *y) {
  if (*x < *y)
    return true;
  else
    return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<def_is_inc_comp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool def_is_inc_comp(int *x, int *y) {
  if (*x < *y)
    return true;
  else
    return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<def_is_inc_comp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool def_is_inc_comp(int *x, int *y) {
  if (*x < *y)
    return true;
  else
    return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<def_is_inc_comp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool def_is_inc_comp(int *x, int *y) {
  if (*x < *y)
    return true;
  else
    return false;
}
```