ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ATMtoKPA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ATMtoMB@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double ATMtoKPA(double ATM) {
  double KPA = ATMtoMB(ATM) / 10;
  return KPA;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ATMtoKPA>:
  endbr64
  sub    $0x8,%rsp
  call   <ATMtoMB@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  add    $0x8,%rsp
  ret
```

assistant: ```c
double ATMtoKPA(double ATM) {
  double KPA = ATMtoMB(ATM) / 10;
  return KPA;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ATMtoKPA>:
  endbr64
  sub    $0x8,%rsp
  call   <ATMtoMB@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm0
  ret
```

assistant: ```c
double ATMtoKPA(double ATM) {
  double KPA = ATMtoMB(ATM) / 10;
  return KPA;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ATMtoKPA>:
  endbr64
  sub    $0x8,%rsp
  call   <ATMtoMB@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm0
  ret
```

assistant: ```c
double ATMtoKPA(double ATM) {
  double KPA = ATMtoMB(ATM) / 10;
  return KPA;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gregorian_calendar_to_jd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  addl   $0x1f40,-0x4(%rbp)
  cmpl   $0x2,-0x8(%rbp)
  jg     L1
  subl   $0x1,-0x4(%rbp)
  addl   $0xc,-0x8(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  imul   $0x16d,%eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x7,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  lea    -0x1252b4(%rax),%ecx
  mov    -0x8(%rbp),%eax
  imul   $0x99,%eax,%eax
  add    $0x3,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  lea    -0x5c(%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  movsd  D18(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D9(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movsd  D34(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D17(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D18
data_type: f64
name: read_data
arguments: label: D9
data_type: f64
name: read_data
arguments: label: D34
data_type: f64
name: read_data
arguments: label: D17
data_type: f64

tool: D18: 24

tool: D9: 1440

tool: D34: 86400

tool: D17: 0.5

assistant: ```c
double gregorian_calendar_to_jd(int y, int m, int d, int h, int mi, int s) {
  y += 8000;
  if (m < 3) {
    y--;
    m += 12;
  }
  return (y * 365) + (y / 4) - (y / 100) + (y / 400) - 1200820 + (m * 153 + 3) / 5 - 92 + d - 1 + h / 24.0 + mi / 1440.0 + s / 86400.0 - 0.5;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gregorian_calendar_to_jd>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %edx,%edi
  cmp    $0x2,%esi
  jle    L8
  add    $0x1f40,%eax
  jmp    L19
L8:
  add    $0x1f3f,%eax
  add    $0xc,%esi
L19:
  imul   $0x16d,%eax,%r10d
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x2,%edx
  add    %edx,%r10d
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  mov    %rdx,%rbx
  sar    $0x25,%rbx
  sar    $0x1f,%eax
  mov    %eax,%r11d
  sub    %ebx,%r11d
  add    %r11d,%r10d
  sar    $0x27,%rdx
  sub    %eax,%edx
  lea    -0x1252b4(%r10,%rdx,1),%edx
  imul   $0x99,%esi,%esi
  add    $0x3,%esi
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    -0x5c(%rdx,%rax,1),%eax
  lea    -0x1(%rdi,%rax,1),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  D39(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  divsd  D34(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  divsd  D37(%rip),%xmm1
  addsd  %xmm1,%xmm0
  subsd  D18(%rip),%xmm0
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D39
type_infered: f64
name: retrieve_data
arguments: tag: D34
type_infered: f64
name: retrieve_data
arguments: tag: D37
type_infered: f64
name: retrieve_data
arguments: tag: D18
type_infered: f64

tool: D39: 24

tool: D34: 1440

tool: D37: 86400

tool: D18: 0.5

assistant: ```c
double gregorian_calendar_to_jd(int y, int m, int d, int h, int mi, int s) {
  y += 8000;
  if (m < 3) {
    y--;
    m += 12;
  }
  return (y * 365) + (y / 4) - (y / 100) + (y / 400) - 1200820 + (m * 153 + 3) / 5 - 92 + d - 1 + h / 24.0 + mi / 1440.0 + s / 86400.0 - 0.5;
}
```
user: What is the c source code of the assembly code below:

```asm
<gregorian_calendar_to_jd>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edx,%edi
  cmp    $0x2,%esi
  jle    L2
  add    $0x1f40,%eax
L10:
  imul   $0x16d,%eax,%r10d
  lea    0x3(%rax),%edx
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  cmovns %eax,%edx
  imul   $0x99,%esi,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  D10(%rip),%xmm1
  sar    $0x2,%edx
  add    %edx,%r10d
  movslq %eax,%rdx
  add    $0x3,%esi
  sar    $0x1f,%eax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %eax,%r11d
  mov    %rdx,%rbx
  sar    $0x27,%rdx
  sub    %eax,%edx
  movslq %esi,%rax
  sar    $0x25,%rbx
  imul   $0x66666667,%rax,%rax
  sub    %ebx,%r11d
  sar    $0x1f,%esi
  pop    %rbx
  add    %r11d,%r10d
  lea    -0x1252b4(%r10,%rdx,1),%edx
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    -0x5c(%rdx,%rax,1),%eax
  lea    -0x1(%rdi,%rax,1),%eax
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  divsd  D18(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  divsd  D13(%rip),%xmm1
  addsd  %xmm1,%xmm0
  subsd  D0(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1f3f,%eax
  add    $0xc,%esi
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D10
data_type: f64
name: unpack_data
arguments: tag: D18
data_type: f64
name: unpack_data
arguments: tag: D13
data_type: f64
name: unpack_data
arguments: tag: D0
data_type: f64

tool: D10: 24

tool: D18: 1440

tool: D13: 86400

tool: D0: 0.5

assistant: ```c
double gregorian_calendar_to_jd(int y, int m, int d, int h, int mi, int s) {
  y += 8000;
  if (m < 3) {
    y--;
    m += 12;
  }
  return (y * 365) + (y / 4) - (y / 100) + (y / 400) - 1200820 + (m * 153 + 3) / 5 - 92 + d - 1 + h / 24.0 + mi / 1440.0 + s / 86400.0 - 0.5;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gregorian_calendar_to_jd>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edx,%edi
  cmp    $0x2,%esi
  jle    L10
  add    $0x1f40,%eax
L16:
  imul   $0x16d,%eax,%r10d
  lea    0x3(%rax),%edx
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  cmovns %eax,%edx
  imul   $0x99,%esi,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  D39(%rip),%xmm1
  sar    $0x2,%edx
  add    %edx,%r10d
  movslq %eax,%rdx
  add    $0x3,%esi
  sar    $0x1f,%eax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %eax,%r11d
  mov    %rdx,%rbx
  sar    $0x27,%rdx
  sub    %eax,%edx
  movslq %esi,%rax
  sar    $0x25,%rbx
  imul   $0x66666667,%rax,%rax
  sub    %ebx,%r11d
  sar    $0x1f,%esi
  pop    %rbx
  add    %r11d,%r10d
  lea    -0x1252b4(%r10,%rdx,1),%edx
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    -0x5c(%rdx,%rax,1),%eax
  lea    -0x1(%rdi,%rax,1),%eax
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  divsd  D11(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  divsd  D25(%rip),%xmm1
  addsd  %xmm1,%xmm0
  subsd  D12(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1f3f,%eax
  add    $0xc,%esi
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D39
data_type: f64
name: parse_data
arguments: data_tag: D11
data_type: f64
name: parse_data
arguments: data_tag: D25
data_type: f64
name: parse_data
arguments: data_tag: D12
data_type: f64

tool: D39: 24

tool: D11: 1440

tool: D25: 86400

tool: D12: 0.5

assistant: ```c
double gregorian_calendar_to_jd(int y, int m, int d, int h, int mi, int s) {
  y += 8000;
  if (m < 3) {
    y--;
    m += 12;
  }
  return (y * 365) + (y / 4) - (y / 100) + (y / 400) - 1200820 + (m * 153 + 3) / 5 - 92 + d - 1 + h / 24.0 + mi / 1440.0 + s / 86400.0 - 0.5;
}
```
user: What is the c source code of the assembly code below:

```asm
<math_sin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: f64
name: retrieve_data
arguments: data_tag: D0
type_infered: f64

tool: D6: 3.141592653589793

tool: D0: 180

assistant: ```c
void math_sin(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D3(%rip),%xmm0
  divsd  D2(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  call   <lua_pushnumber@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: f64
name: parse_data
arguments: label: D2
type: f64

tool: D3: 3.141592653589793

tool: D2: 180

assistant: ```c
void math_sin(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: What is the c source code of the assembly code below?

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D8(%rip),%xmm0
  divsd  D4(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: f64
name: retrieve_data
arguments: data_label: D4
type_guessed: f64

tool: D8: 3.141592653589793

tool: D4: 180

assistant: ```c
void math_sin(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<math_sin>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <luaL_check_number@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D5(%rip),%xmm0
  divsd  D15(%rip),%xmm0
  call   <sin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1080 <lua_pushnumber@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: f64
name: parse_data
arguments: tag: D15
data_type: f64

tool: D5: 3.141592653589793

tool: D15: 180

assistant: ```c
void math_sin(void) {
  double d = luaL_check_number(1);
  lua_pushnumber(sin(((d)*3.14159265358979323846 / 180.0)));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2a,%edi
  call   <doit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  doit(42);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <doit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doit(42);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <doit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doit(42);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%edi
  call   <doit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  doit(42);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_dead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L31:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L29
  mov    $0x0,%eax
  jmp    L26
L29:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L31
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int is_dead(int *current, int length) {
  int counter;
  for (counter = 0; counter < length - 1; counter++) {
    if (*(current + counter) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_dead>:
  endbr64
  cmp    $0x1,%esi
  jle    L16
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L19:
  cmpl   $0x0,(%rax)
  jne    L21
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
  mov    $0x1,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_dead(int *current, int length) {
  int counter;
  for (counter = 0; counter < length - 1; counter++) {
    if (*(current + counter) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_dead>:
  endbr64
  cmp    $0x1,%esi
  jle    L37
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L37
L5:
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L36
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_dead(int *current, int length) {
  int counter;
  for (counter = 0; counter < length - 1; counter++) {
    if (*(current + counter) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_dead>:
  endbr64
  cmp    $0x1,%esi
  jle    L10
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L10
L28:
  mov    (%rdi),%edx
  test   %edx,%edx
  je     L35
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_dead(int *current, int length) {
  int counter;
  for (counter = 0; counter < length - 1; counter++) {
    if (*(current + counter) != 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cdTrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L55
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L35:
  addq   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jae    L39
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L35
L39:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L29
L55:
  nop
L29:
  leave
  ret
```

assistant: ```c
void cdTrim(char *s, int n) {
  char *c;
  if (s == NULL)
    return;
  for (c = s; *c && c < s + n - 1 && !isspace(*c); c++)
    ;
  *c = '\0';
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cdTrim>:
  endbr64
  test   %rdi,%rdi
  je     L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L47
  movslq %esi,%rsi
  lea    -0x1(%rbx,%rsi,1),%rbp
  cmp    %rbp,%rbx
  jae    L47
L43:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L47
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L47
  cmp    %rbp,%rbx
  jne    L43
  mov    %rbp,%rbx
L47:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  ret
```

assistant: ```c
void cdTrim(char *s, int n) {
  char *c;
  if (s == NULL)
    return;
  for (c = s; *c && c < s + n - 1 && !isspace(*c); c++)
    ;
  *c = '\0';
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cdTrim>:
  endbr64
  test   %rdi,%rdi
  je     L41
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L67
  movslq %esi,%rsi
  lea    -0x1(%rbx,%rsi,1),%rbp
  cmp    %rbp,%rbx
  jb     L17
  jmp    L67
  nopl   0x0(%rax)
L1:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L67
  cmp    %rbp,%rbx
  je     L67
L17:
  call   <isspace@plt>
  test   %eax,%eax
  je     L1
L67:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L41:
  ret
```

assistant: ```c
void cdTrim(char *s, int n) {
  char *c;
  if (s == NULL)
    return;
  for (c = s; *c && c < s + n - 1 && !isspace(*c); c++)
    ;
  *c = '\0';
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cdTrim>:
  endbr64
  test   %rdi,%rdi
  je     L32
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L50
  movslq %esi,%rsi
  lea    -0x1(%rbx,%rsi,1),%rbp
  cmp    %rbp,%rbx
  jb     L36
  jmp    L50
  nopl   0x0(%rax)
L6:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L50
  cmp    %rbp,%rbx
  je     L50
L36:
  call   <isspace@plt>
  test   %eax,%eax
  je     L6
L50:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L32:
  ret
```

assistant: ```c
void cdTrim(char *s, int n) {
  char *c;
  if (s == NULL)
    return;
  for (c = s; *c && c < s + n - 1 && !isspace(*c); c++)
    ;
  *c = '\0';
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L53
L26:
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x28(%rbp)
L53:
  cmpl   $0x4,-0x28(%rbp)
  jle    L26
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x28(%rbp)
  jmp    L20
L51:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  cmp    %eax,%edx
  jne    L49
  addl   $0x1,-0x24(%rbp)
L49:
  addl   $0x1,-0x28(%rbp)
L20:
  cmpl   $0x4,-0x28(%rbp)
  jle    L51
  mov    -0x2c(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D0: %d

tool: D21: 
Entre com uma chave: 

tool: D12: 
O numero %d apareceu %d vezes!

assistant: ```c
int main() {
  int vetor[5], i, chave, cont = 0;
  for (i = 0; i < 5; i++) {
    scanf("%d", &vetor[i]);
  }
  printf("\nEntre com uma chave: ");
  scanf("%d", &chave);
  for (i = 0; i < 5; i++) {
    if (vetor[i] == chave) {
      cont++;
    }
  }
  printf("\nO numero %d apareceu %d vezes!", chave, cont);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x24(%rsp),%r12
  mov    %rbx,%rbp
  lea    D6(%rip),%r13
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L15
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x0,%edx
L17:
  cmp    %esi,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D39
type: string

tool: D6: %d

tool: D8: 
Entre com uma chave: 

tool: D39: 
O numero %d apareceu %d vezes!

assistant: ```c
int main() {
  int vetor[5], i, chave, cont = 0;
  for (i = 0; i < 5; i++) {
    scanf("%d", &vetor[i]);
  }
  printf("\nEntre com uma chave: ");
  scanf("%d", &chave);
  for (i = 0; i < 5; i++) {
    if (vetor[i] == chave) {
      cont++;
    }
  }
  printf("\nO numero %d apareceu %d vezes!", chave, cont);
  return 0;
}
```