ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<chk_key_version>:
  endbr64
  sub    $0x2,%edi
  cmp    $0x1,%dil
  jbe    L3
  ret
  xchg   %ax,%ax
L3:
  push   %rbp
  lea    D79(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D76(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D79
type_guessed: string
name: extract_symbolic_data
arguments: label: D45
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D76
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string

tool: D79: <hr size="1" width="100%%">


tool: D45: <font color="red">Warning</font>


tool: D4: <br></br>


tool: D28: <p>You have uploaded a PGP key which is of a version less than 4.


tool: D3: PGP keys before version 4 have a number of serious weaknesses in them


tool: D76: which could allow your key, your digitial signatures, or your encrypted


tool: D44: communications, to be more easily compromised.  CryptNET recommends that


tool: D31: you revoke all keys which are of a version less than 4.</p>


assistant: ```c
void chk_key_version(unsigned char vrsn) {
  if (vrsn == (unsigned char)0x04) {
    return;
  } else if ((vrsn == (unsigned char)0x03) || (vrsn == (unsigned char)0x02)) {
    printf("<hr size=\"1\" width=\"100%%\">\n");
    printf(gettext("<font color=\"red\">Warning</font>\n"));
    printf("<br></br>\n");
    printf(gettext("<p>You have uploaded a PGP key which is of a version less than 4.\n"));
    printf(gettext("PGP keys before version 4 have a number of serious weaknesses in them\n"));
    printf(gettext("which could allow your key, your digitial signatures, or your encrypted\n"));
    printf(gettext("communications, to be more easily compromised.  CryptNET recommends that\n"));
    printf(gettext("you revoke all keys which are of a version less than 4.</p>\n"));
    printf("<hr size=\"1\" width=\"100%%\">\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chk_key_version>:
  endbr64
  sub    $0x2,%edi
  cmp    $0x1,%dil
  jbe    L1
  ret
  xchg   %ax,%ax
L1:
  push   %rbp
  lea    D79(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D79
type_guessed: string
name: extract_symbolic_data
arguments: label: D52
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D43
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D67
type_guessed: string
name: extract_symbolic_data
arguments: label: D62
type_guessed: string
name: extract_symbolic_data
arguments: label: D45
type_guessed: string

tool: D79: <hr size="1" width="100%%">


tool: D52: <font color="red">Warning</font>


tool: D0: <br></br>


tool: D43: <p>You have uploaded a PGP key which is of a version less than 4.


tool: D19: PGP keys before version 4 have a number of serious weaknesses in them


tool: D67: which could allow your key, your digitial signatures, or your encrypted


tool: D62: communications, to be more easily compromised.  CryptNET recommends that


tool: D45: you revoke all keys which are of a version less than 4.</p>


assistant: ```c
void chk_key_version(unsigned char vrsn) {
  if (vrsn == (unsigned char)0x04) {
    return;
  } else if ((vrsn == (unsigned char)0x03) || (vrsn == (unsigned char)0x02)) {
    printf("<hr size=\"1\" width=\"100%%\">\n");
    printf(gettext("<font color=\"red\">Warning</font>\n"));
    printf("<br></br>\n");
    printf(gettext("<p>You have uploaded a PGP key which is of a version less than 4.\n"));
    printf(gettext("PGP keys before version 4 have a number of serious weaknesses in them\n"));
    printf(gettext("which could allow your key, your digitial signatures, or your encrypted\n"));
    printf(gettext("communications, to be more easily compromised.  CryptNET recommends that\n"));
    printf(gettext("you revoke all keys which are of a version less than 4.</p>\n"));
    printf("<hr size=\"1\" width=\"100%%\">\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1a4(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a4(%rbp),%edx
  lea    -0x1a0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <matrica@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D15: Unesite n: 

tool: D3: %d

assistant: ```c
int main() {
  int n;
  int niz[10][10];
  printf("Unesite n: ");
  scanf("%d", &n);
  matrica(niz, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%esi
  call   <matrica@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D6: Unesite n: 

tool: D14: %d

assistant: ```c
int main() {
  int n;
  int niz[10][10];
  printf("Unesite n: ");
  scanf("%d", &n);
  matrica(niz, n);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdi
  call   <matrica@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D5: Unesite n: 

tool: D6: %d

assistant: ```c
int main() {
  int n;
  int niz[10][10];
  printf("Unesite n: ");
  scanf("%d", &n);
  matrica(niz, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x1b8,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdi
  call   <matrica@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x1b8,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D9: Unesite n: 

tool: D2: %d

assistant: ```c
int main() {
  int n;
  int niz[10][10];
  printf("Unesite n: ");
  scanf("%d", &n);
  matrica(niz, n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SomeFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D13: x = %d


tool: D1: c = %s


assistant: ```c
int SomeFunction(x, c)
int x;
char c;
{
  printf("x = %d\n", x);
  printf("c = %s\n", &c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SomeFunction>:
  endbr64
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string
name: retrieve_data
arguments: tag: D5
data_type: string

tool: D2: x = %d


tool: D5: c = %s


assistant: ```c
int SomeFunction(x, c)
int x;
char c;
{
  printf("x = %d\n", x);
  printf("c = %s\n", &c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SomeFunction>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %sil,0xc(%rsp)
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D1: x = %d


tool: D18: c = %s


assistant: ```c
int SomeFunction(x, c)
int x;
char c;
{
  printf("x = %d\n", x);
  printf("c = %s\n", &c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SomeFunction>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %sil,0xc(%rsp)
  mov    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D12: x = %d


tool: D4: c = %s


assistant: ```c
int SomeFunction(x, c)
int x;
char c;
{
  printf("x = %d\n", x);
  printf("c = %s\n", &c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rand_uniform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  jbe    L1
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
L1:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    D6(%rip),%rax
  movss  (%rax),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  -0x18(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  addss  -0x14(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float rand_uniform(float min, float max) {
  if (max < min) {
    float swap = min;
    min = max;
    max = swap;
  }
  return ((float)rand() / RAND_MAX * (max - min)) + min;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rand_uniform>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  comiss %xmm1,%xmm0
  jbe    L3
  movss  %xmm1,0x8(%rsp)
  movss  %xmm0,0xc(%rsp)
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    D5(%rip),%rax
  divss  (%rax),%xmm0
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm4
  subss  %xmm4,%xmm1
  mulss  %xmm1,%xmm0
  addss  %xmm4,%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
float rand_uniform(float min, float max) {
  if (max < min) {
    float swap = min;
    min = max;
    max = swap;
  }
  return ((float)rand() / RAND_MAX * (max - min)) + min;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rand_uniform>:
  endbr64
  sub    $0x18,%rsp
  comiss %xmm1,%xmm0
  jbe    L1
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
L1:
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <rand@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %rax,%xmm2
  mov    D7(%rip),%rax
  subss  %xmm0,%xmm1
  divss  (%rax),%xmm2
  add    $0x18,%rsp
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float rand_uniform(float min, float max) {
  if (max < min) {
    float swap = min;
    min = max;
    max = swap;
  }
  return ((float)rand() / RAND_MAX * (max - min)) + min;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rand_uniform>:
  endbr64
  sub    $0x18,%rsp
  comiss %xmm1,%xmm0
  jbe    L9
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm0
  movaps %xmm2,%xmm1
L9:
  xor    %eax,%eax
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <rand@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %rax,%xmm2
  mov    D4(%rip),%rax
  subss  %xmm0,%xmm1
  divss  (%rax),%xmm2
  add    $0x18,%rsp
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float rand_uniform(float min, float max) {
  if (max < min) {
    float swap = min;
    min = max;
    max = swap;
  }
  return ((float)rand() / RAND_MAX * (max - min)) + min;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rd_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x20,-0x8(%rbp)
  je     L59
  cmpl   $0xa,-0x8(%rbp)
  jne    L39
  jmp    L59
L39:
  nop
  movl   $0x0,-0x4(%rbp)
  jmp    L91
L32:
  cmpl   $0x20,-0x8(%rbp)
  je     L35
  cmpl   $0xa,-0x8(%rbp)
  jne    L103
L35:
  mov    $0x1,%eax
  jmp    L24
L103:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L91:
  cmpl   $0x2,-0x4(%rbp)
  jle    L32
  cmpl   $0x20,-0x8(%rbp)
  je     L33
  cmpl   $0xa,-0x8(%rbp)
  je     L33
  mov    $0x1,%eax
  jmp    L24
L33:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
rd_name(char **f, char *p) {
  int c, i;
  for (;;) {
    c = *(*f)++;
    if (c != ' ' && c != '\n')
      break;
  }
  for (i = 0; i < 3; i++) {
    if (c == ' ' || c == '\n')
      return 1;
    *p++ = c;
    c = *(*f)++;
  }
  if (c != ' ' && c != '\n')
    return 1;
  *p = 0;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rd_name>:
  endbr64
  mov    %rdi,%rdx
L58:
  mov    (%rdx),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  cmp    $0x20,%al
  je     L58
  cmp    $0xa,%ecx
  je     L58
  mov    %al,(%rsi)
  mov    (%rdx),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  cmp    $0x20,%al
  je     L17
  cmp    $0xa,%ecx
  je     L17
  mov    %al,0x1(%rsi)
  mov    (%rdx),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  cmp    $0x20,%al
  je     L17
  cmp    $0xa,%ecx
  je     L17
  mov    %al,0x2(%rsi)
  mov    (%rdx),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdx)
  movsbl (%rax),%eax
  cmp    $0x20,%eax
  je     L60
  mov    $0x1,%edx
  cmp    $0xa,%eax
  jne    L13
L60:
  movb   $0x0,0x3(%rsi)
  mov    $0x0,%edx
L13:
  mov    %edx,%eax
  ret
L17:
  mov    $0x1,%edx
  jmp    L13
```

assistant: ```c
rd_name(char **f, char *p) {
  int c, i;
  for (;;) {
    c = *(*f)++;
    if (c != ' ' && c != '\n')
      break;
  }
  for (i = 0; i < 3; i++) {
    if (c == ' ' || c == '\n')
      return 1;
    *p++ = c;
    c = *(*f)++;
  }
  if (c != ' ' && c != '\n')
    return 1;
  *p = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rd_name>:
  endbr64
  mov    (%rdi),%rax
  add    $0x1,%rax
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rax,(%rdi)
  movsbl -0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%edx
  je     L43
  cmp    $0xa,%edx
  je     L43
  lea    0x3(%rsi),%rcx
L60:
  mov    %dl,(%rsi)
  mov    (%rdi),%rax
  add    $0x1,%rsi
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movsbl (%rax),%edx
  cmp    %rsi,%rcx
  je     L42
  cmp    $0x20,%edx
  je     L3
  cmp    $0xa,%edx
  jne    L60
L3:
  mov    $0x1,%eax
L28:
  ret
  nopl   0x0(%rax)
L42:
  cmp    $0x20,%edx
  je     L11
  mov    $0x1,%eax
  cmp    $0xa,%edx
  jne    L28
L11:
  movb   $0x0,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
rd_name(char **f, char *p) {
  int c, i;
  for (;;) {
    c = *(*f)++;
    if (c != ' ' && c != '\n')
      break;
  }
  for (i = 0; i < 3; i++) {
    if (c == ' ' || c == '\n')
      return 1;
    *p++ = c;
    c = *(*f)++;
  }
  if (c != ' ' && c != '\n')
    return 1;
  *p = 0;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rd_name>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    (%rcx),%rax
  add    $0x1,%rax
  nopl   0x0(%rax)
L44:
  mov    %rax,(%rcx)
  movsbl -0x1(%rax),%esi
  add    $0x1,%rax
  cmp    $0x20,%sil
  je     L44
  cmp    $0xa,%esi
  je     L44
  mov    %sil,(%rdi)
  mov    (%rcx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rcx)
  movsbl (%rax),%edx
  cmp    $0x20,%dl
  je     L70
  cmp    $0xa,%edx
  je     L70
  mov    %dl,0x1(%rdi)
  mov    (%rcx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rcx)
  movsbl (%rax),%edx
  cmp    $0x20,%dl
  je     L70
  cmp    $0xa,%edx
  je     L70
  mov    %dl,0x2(%rdi)
  mov    (%rcx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rcx)
  movsbl (%rax),%eax
  cmp    $0x20,%eax
  je     L68
  mov    $0x1,%r8d
  cmp    $0xa,%eax
  je     L68
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  xor    %r8d,%r8d
  movb   $0x0,0x3(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
rd_name(char **f, char *p) {
  int c, i;
  for (;;) {
    c = *(*f)++;
    if (c != ' ' && c != '\n')
      break;
  }
  for (i = 0; i < 3; i++) {
    if (c == ' ' || c == '\n')
      return 1;
    *p++ = c;
    c = *(*f)++;
  }
  if (c != ' ' && c != '\n')
    return 1;
  *p = 0;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ReverseNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L20
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L26
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  sub    $0x30,%edx
  mov    %edx,(%rax)
  jmp    L29
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x2e,(%rax)
L29:
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x0,-0x8(%rbp)
  jns    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void ReverseNumber(char *inNumber, int *operateNumber, int smallLength, int maxSmallLength) {
  int length = (int)strlen(inNumber);
  for (int i = maxSmallLength - smallLength, j = length - 1; j >= 0; --j, ++i) {
    if (inNumber[j] != '.') {
      operateNumber[i] = inNumber[j] - '0';
    } else {
      operateNumber[i] = '.';
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ReverseNumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%ebp
  call   <strlen@plt>
  sub    %r13d,%ebp
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L18
  movslq %edx,%rdx
  lea    (%rbx,%rdx,1),%rsi
  movslq %ebp,%rcx
  lea    (%r12,%rcx,4),%rdx
  lea    -0x1(%rax),%eax
  add    %rcx,%rax
  lea    0x4(%r12,%rax,4),%rcx
  jmp    L33
L13:
  movl   $0x2e,(%rdx)
L34:
  sub    $0x1,%rsi
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  je     L18
L33:
  movzbl (%rsi),%eax
  cmp    $0x2e,%al
  je     L13
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,(%rdx)
  jmp    L34
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ReverseNumber(char *inNumber, int *operateNumber, int smallLength, int maxSmallLength) {
  int length = (int)strlen(inNumber);
  for (int i = maxSmallLength - smallLength, j = length - 1; j >= 0; --j, ++i) {
    if (inNumber[j] != '.') {
      operateNumber[i] = inNumber[j] - '0';
    } else {
      operateNumber[i] = '.';
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ReverseNumber>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    %r13d,%ebp
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L0
  movslq %eax,%rdx
  movslq %ebp,%rcx
  mov    %eax,%eax
  mov    $0x2e,%esi
  add    %rcx,%rax
  lea    (%rbx,%rdx,1),%rdi
  lea    (%r12,%rcx,4),%rdx
  lea    0x4(%r12,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%rdi),%eax
  mov    %eax,%ecx
  sub    $0x30,%eax
  cmp    $0x2e,%cl
  cmove  %esi,%eax
  add    $0x4,%rdx
  sub    $0x1,%rdi
  mov    %eax,-0x4(%rdx)
  cmp    %r8,%rdx
  jne    L4
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ReverseNumber(char *inNumber, int *operateNumber, int smallLength, int maxSmallLength) {
  int length = (int)strlen(inNumber);
  for (int i = maxSmallLength - smallLength, j = length - 1; j >= 0; --j, ++i) {
    if (inNumber[j] != '.') {
      operateNumber[i] = inNumber[j] - '0';
    } else {
      operateNumber[i] = '.';
    }
  }
}
```