ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L12
  nopw   0x0(%rax,%rax,1)
L44:
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  je     L12
  xor    %edi,%edi
  add    %eax,%edx
  je     L11
  nopw   0x0(%rax,%rax,1)
L28:
  movslq %edx,%rax
  mov    %edx,%ecx
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,%edx
  add    %ecx,%ecx
  sub    %ecx,%esi
  lea    0x30(%rsi),%ecx
  je     L34
  movslq %edi,%rsi
  add    $0x1,%edi
  mov    %cl,0x10(%rsp,%rsi,1)
L34:
  test   %eax,%eax
  jne    L28
L11:
  movslq %edi,%rdi
  lea    0x10(%rsp),%r14
  movb   $0x0,0x10(%rsp,%rdi,1)
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1c(%rsp),%r8
  movslq %eax,%rdx
  movb   $0x0,0x1c(%rsp,%rdx,1)
  test   %eax,%eax
  jle    L3
  lea    0x1c(%rsp),%r8
  sub    $0x1,%eax
  lea    -0x1(%r14,%rdx,1),%rcx
  lea    0x1d(%rsp,%rax,1),%rsi
  mov    %r8,%rdx
  xchg   %ax,%ax
L89:
  movzbl (%rcx),%eax
  add    $0x1,%rdx
  sub    $0x1,%rcx
  mov    %al,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L89
L3:
  mov    %r8,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L44
L12:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: D11: %s


tool: D17: %d%d

assistant: ```c
int main() {
  int A, B, Result, Div, Cont, Mod, Cont2;
  char ForaZero[12], SemZer[12];
  scanf("%d%d", &A, &B);
  while (B != 0 && A != 0) {
    Cont = 0;
    Result = A + B;
    while (Result != 0) {
      Mod = Result % 10;
      Result = Result / 10;
      Mod = Mod + 48;
      if (Mod != 48) {
        ForaZero[Cont] = Mod;
        Cont++;
      }
    }
    ForaZero[Cont] = '\0';
    Cont = strlen(ForaZero);
    SemZer[Cont] = '\0';
    Mod = Cont;
    Cont = Cont - 1;
    for (Cont2 = 0; Cont2 < Mod; Cont2++) {
      SemZer[Cont2] = ForaZero[Cont];
      Cont--;
    }
    printf("%s\n", SemZer);
    scanf("%d%d", &A, &B);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mysprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  mov    -0xd0(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <reformat@plt>
  mov    %rax,-0xb8(%rbp)
  cmpq   $0x0,-0xb8(%rbp)
  je     L15
  mov    -0xbc(%rbp),%edx
  mov    -0xb8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xc0(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L6
L15:
  mov    -0xbc(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  movl   $0xffffffff,-0xc0(%rbp)
L6:
  mov    -0xc0(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mysprintf(char *s, const char *fmt, ...) {
  va_list ap;
  char *fmt2;
  int nchar;
  va_start(ap, fmt);
  fmt2 = reformat(fmt);
  if (fmt2) {
    nchar = vsprintf(s, fmt2, ap);
    free(fmt2);
  } else {
    vsprintf(s, fmt, ap);
    nchar = -1;
  }
  return nchar;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mysprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  call   <reformat@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L12:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    $0xffffffff,%ebp
  jmp    L12
```

assistant: ```c
int mysprintf(char *s, const char *fmt, ...) {
  va_list ap;
  char *fmt2;
  int nchar;
  va_start(ap, fmt);
  fmt2 = reformat(fmt);
  if (fmt2) {
    nchar = vsprintf(s, fmt2, ap);
    free(fmt2);
  } else {
    vsprintf(s, fmt, ap);
    nchar = -1;
  }
  return nchar;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mysprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <reformat@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbp
  mov    %r13,%rdi
  xor    %edx,%edx
  mov    %rax,%rsi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L5:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r12,%rsi
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    $0xffffffff,%r12d
  call   <vsprintf@plt>
  jmp    L5
```

assistant: ```c
int mysprintf(char *s, const char *fmt, ...) {
  va_list ap;
  char *fmt2;
  int nchar;
  va_start(ap, fmt);
  fmt2 = reformat(fmt);
  if (fmt2) {
    nchar = vsprintf(s, fmt2, ap);
    free(fmt2);
  } else {
    vsprintf(s, fmt, ap);
    nchar = -1;
  }
  return nchar;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mysprintf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <reformat@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    %r13,%rdi
  xor    %edx,%edx
  mov    %rax,%rsi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L18:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    %r12,%rsi
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    $0xffffffff,%r12d
  call   <vsprintf@plt>
  jmp    L18
```

assistant: ```c
int mysprintf(char *s, const char *fmt, ...) {
  va_list ap;
  char *fmt2;
  int nchar;
  va_start(ap, fmt);
  fmt2 = reformat(fmt);
  if (fmt2) {
    nchar = vsprintf(s, fmt2, ap);
    free(fmt2);
  } else {
    vsprintf(s, fmt, ap);
    nchar = -1;
  }
  return nchar;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
  jmp    L3
L5:
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool is_dir(const char *name1, const char *name2) {
  char *name;
  DIR *directory;
  name = (char *)malloc(strlen(name1) + strlen(name2) + 1);
  strcpy(name, name1);
  strcat(name, name2);
  directory = opendir(name);
  free(name);
  if (directory) {
    closedir(directory);
    return true;
  } else
    return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  test   %rbp,%rbp
  je     L8
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool is_dir(const char *name1, const char *name2) {
  char *name;
  DIR *directory;
  name = (char *)malloc(strlen(name1) + strlen(name2) + 1);
  strcpy(name, name1);
  strcat(name, name2);
  directory = opendir(name);
  free(name);
  if (directory) {
    closedir(directory);
    return true;
  } else
    return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_dir>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  xor    %eax,%eax
  test   %r12,%r12
  je     L4
  mov    %r12,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L4:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool is_dir(const char *name1, const char *name2) {
  char *name;
  DIR *directory;
  name = (char *)malloc(strlen(name1) + strlen(name2) + 1);
  strcpy(name, name1);
  strcat(name, name2);
  directory = opendir(name);
  free(name);
  if (directory) {
    closedir(directory);
    return true;
  } else
    return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_dir>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  xor    %eax,%eax
  test   %r12,%r12
  je     L3
  mov    %r12,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L3:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool is_dir(const char *name1, const char *name2) {
  char *name;
  DIR *directory;
  name = (char *)malloc(strlen(name1) + strlen(name2) + 1);
  strcpy(name, name1);
  strcat(name, name2);
  directory = opendir(name);
  free(name);
  if (directory) {
    closedir(directory);
    return true;
  } else
    return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<flip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L0:
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0xc(%rbp)
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flip(int array[], int pos, int size) {
  int length = size - pos;
  for (int i = 0; i < length / 2; i++) {
    int temp = array[pos + i];
    array[pos + i] = array[size - 1 - i];
    array[size - 1 - i] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flip>:
  endbr64
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L1
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rdx
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    $0x0,%eax
L2:
  mov    (%rcx,%rax,4),%esi
  mov    -0x4(%rdx),%edi
  mov    %edi,(%rcx,%rax,4)
  mov    %esi,-0x4(%rdx)
  add    $0x1,%rax
  sub    $0x4,%rdx
  cmp    %eax,%r8d
  jg     L2
L1:
  ret
```

assistant: ```c
void flip(int array[], int pos, int size) {
  int length = size - pos;
  for (int i = 0; i < length / 2; i++) {
    int temp = array[pos + i];
    array[pos + i] = array[size - 1 - i];
    array[size - 1 - i] = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flip>:
  endbr64
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x1,%eax
  jle    L8
  sub    $0x1,%edx
  movslq %esi,%rsi
  xor    %eax,%eax
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rdx
  nopl   (%rax)
L14:
  mov    (%rdx),%edi
  mov    (%rcx,%rax,4),%esi
  sub    $0x4,%rdx
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  mov    %esi,0x4(%rdx)
  cmp    %eax,%r8d
  jg     L14
L8:
  ret
```

assistant: ```c
void flip(int array[], int pos, int size) {
  int length = size - pos;
  for (int i = 0; i < length / 2; i++) {
    int temp = array[pos + i];
    array[pos + i] = array[size - 1 - i];
    array[size - 1 - i] = temp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flip>:
  endbr64
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%r9d
  shr    $0x1f,%r9d
  add    %ecx,%r9d
  sar    %r9d
  cmp    $0x1,%ecx
  jle    L44
  mov    %esi,%eax
  lea    -0x1(%rdx),%esi
  movslq %edx,%rdx
  push   %rbp
  lea    0x0(,%rdx,4),%r10
  push   %rbx
  mov    %r9d,%edx
  movslq %eax,%rbx
  shl    $0x2,%rdx
  lea    0x0(,%rbx,4),%r8
  mov    %r10,%r11
  sub    %rdx,%r11
  lea    (%rdx,%r8,1),%rbp
  cmp    %r11,%rbp
  setle  %dl
  cmp    %r10,%r8
  setge  %r11b
  or     %r11b,%dl
  je     L97
  cmp    $0x3,%ecx
  jle    L97
  cmp    $0x7,%ecx
  jle    L77
  mov    %r9d,%ecx
  add    %rdi,%r8
  lea    -0x10(%rdi,%r10,1),%rdx
  shr    $0x2,%ecx
  lea    -0x1(%rcx),%r11d
  lea    0x10(%r8),%rcx
  shl    $0x4,%r11
  add    %rcx,%r11
  jmp    L103
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x10,%rcx
L103:
  movdqu (%r8),%xmm0
  movdqu (%rdx),%xmm2
  sub    $0x10,%rdx
  pshufd $0x1b,%xmm2,%xmm1
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm1,(%r8)
  mov    %rcx,%r8
  movups %xmm0,0x10(%rdx)
  cmp    %r11,%rcx
  jne    L73
  mov    %r9d,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%r8d
  cmp    %edx,%r9d
  je     L93
L31:
  sub    %edx,%r9d
  cmp    $0x1,%r9d
  je     L48
  add    %rdx,%rbx
  neg    %rdx
  lea    -0x8(%r10,%rdx,4),%rdx
  lea    (%rdi,%rbx,4),%rcx
  add    %rdi,%rdx
  movq   (%rcx),%xmm0
  movq   (%rdx),%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  movq   %xmm1,(%rcx)
  movq   %xmm0,(%rdx)
  mov    %r9d,%edx
  and    $0xfffffffe,%edx
  add    %edx,%r8d
  cmp    %edx,%r9d
  je     L93
L48:
  add    %r8d,%eax
  sub    %r8d,%esi
  cltq
  movslq %esi,%rdx
  lea    (%rdi,%rax,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%r9d
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %r9d,(%rax)
L93:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L97:
  movslq %esi,%rdx
  lea    (%rdi,%r8,1),%rax
  lea    (%rdi,%rdx,4),%rcx
  xor    %edx,%edx
  nopl   (%rax)
L105:
  mov    (%rcx),%edi
  mov    (%rax,%rdx,4),%esi
  sub    $0x4,%rcx
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  mov    %esi,0x4(%rcx)
  cmp    %edx,%r9d
  jg     L105
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  ret
L77:
  xor    %edx,%edx
  xor    %r8d,%r8d
  jmp    L31
```

assistant: ```c
void flip(int array[], int pos, int size) {
  int length = size - pos;
  for (int i = 0; i < length / 2; i++) {
    int temp = array[pos + i];
    array[pos + i] = array[size - 1 - i];
    array[size - 1 - i] = temp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<computeSignal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x10,-0x14(%rbp)
  ja     L75
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x8,-0x4(%rbp)
  jmp    L13
  movl   $0x5,-0x4(%rbp)
  jmp    L13
  movl   $0x5,-0x4(%rbp)
  jmp    L13
  movl   $0x10,-0x4(%rbp)
  jmp    L13
  movl   $0x10,-0x4(%rbp)
  jmp    L13
  movl   $0x4,-0x4(%rbp)
  jmp    L13
  movl   $0x8,-0x4(%rbp)
  jmp    L13
  movl   $0x7,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0xb,-0x4(%rbp)
  jmp    L13
  movl   $0x7,-0x4(%rbp)
  jmp    L13
L75:
  movl   $0x7,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int computeSignal(int exceptionVector) {
  int sigval;
  switch (exceptionVector) {
  case 0:
    sigval = 8;
    break;
  case 1:
    sigval = 5;
    break;
  case 3:
    sigval = 5;
    break;
  case 4:
    sigval = 16;
    break;
  case 5:
    sigval = 16;
    break;
  case 6:
    sigval = 4;
    break;
  case 7:
    sigval = 8;
    break;
  case 8:
    sigval = 7;
    break;
  case 9:
    sigval = 11;
    break;
  case 10:
    sigval = 11;
    break;
  case 11:
    sigval = 11;
    break;
  case 12:
    sigval = 11;
    break;
  case 13:
    sigval = 11;
    break;
  case 14:
    sigval = 11;
    break;
  case 16:
    sigval = 7;
    break;
  default:
    sigval = 7;
  }
  return (sigval);
}
```
user: What is the c source code of the assembly code below:

```asm
<computeSignal>:
  endbr64
  cmp    $0x10,%edi
  ja     L5
  mov    %edi,%eax
  lea    D4(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x5,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    %edi,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0x7,%eax
  ret
L5:
  mov    $0x7,%eax
  ret
  mov    $0x8,%eax
  ret
```

assistant: ```c
int computeSignal(int exceptionVector) {
  int sigval;
  switch (exceptionVector) {
  case 0:
    sigval = 8;
    break;
  case 1:
    sigval = 5;
    break;
  case 3:
    sigval = 5;
    break;
  case 4:
    sigval = 16;
    break;
  case 5:
    sigval = 16;
    break;
  case 6:
    sigval = 4;
    break;
  case 7:
    sigval = 8;
    break;
  case 8:
    sigval = 7;
    break;
  case 9:
    sigval = 11;
    break;
  case 10:
    sigval = 11;
    break;
  case 11:
    sigval = 11;
    break;
  case 12:
    sigval = 11;
    break;
  case 13:
    sigval = 11;
    break;
  case 14:
    sigval = 11;
    break;
  case 16:
    sigval = 7;
    break;
  default:
    sigval = 7;
  }
  return (sigval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<computeSignal>:
  endbr64
  mov    $0x7,%eax
  cmp    $0x10,%edi
  ja     L7
  mov    %edi,%edi
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L7:
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: 

assistant: ```c
int computeSignal(int exceptionVector) {
  int sigval;
  switch (exceptionVector) {
  case 0:
    sigval = 8;
    break;
  case 1:
    sigval = 5;
    break;
  case 3:
    sigval = 5;
    break;
  case 4:
    sigval = 16;
    break;
  case 5:
    sigval = 16;
    break;
  case 6:
    sigval = 4;
    break;
  case 7:
    sigval = 8;
    break;
  case 8:
    sigval = 7;
    break;
  case 9:
    sigval = 11;
    break;
  case 10:
    sigval = 11;
    break;
  case 11:
    sigval = 11;
    break;
  case 12:
    sigval = 11;
    break;
  case 13:
    sigval = 11;
    break;
  case 14:
    sigval = 11;
    break;
  case 16:
    sigval = 7;
    break;
  default:
    sigval = 7;
  }
  return (sigval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computeSignal>:
  endbr64
  mov    $0x7,%eax
  cmp    $0x10,%edi
  ja     L8
  mov    %edi,%edi
  lea    D1(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: 

assistant: ```c
int computeSignal(int exceptionVector) {
  int sigval;
  switch (exceptionVector) {
  case 0:
    sigval = 8;
    break;
  case 1:
    sigval = 5;
    break;
  case 3:
    sigval = 5;
    break;
  case 4:
    sigval = 16;
    break;
  case 5:
    sigval = 16;
    break;
  case 6:
    sigval = 4;
    break;
  case 7:
    sigval = 8;
    break;
  case 8:
    sigval = 7;
    break;
  case 9:
    sigval = 11;
    break;
  case 10:
    sigval = 11;
    break;
  case 11:
    sigval = 11;
    break;
  case 12:
    sigval = 11;
    break;
  case 13:
    sigval = 11;
    break;
  case 14:
    sigval = 11;
    break;
  case 16:
    sigval = 7;
    break;
  default:
    sigval = 7;
  }
  return (sigval);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_internal_login_tty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    $0x0,%eax
  call   <setsid@plt>
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  lea    -0x4(%rbp),%rax
  mov    $0x1,%r8d
  mov    %rax,%rdi
  call   <_internal_get_tty@plt>
  test   %rax,%rax
  je     L7
  mov    $0xffffffff,%eax
  jmp    L11
L7:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  mov    -0x4(%rbp),%eax
  cmp    $0x2,%eax
  jle    L9
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L9:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int _internal_login_tty(int fd, const char *path, struct termios *termp, struct winsize *winp) {
  setsid();
  if (_internal_get_tty(&fd, path, termp, winp, 1) != 0)
    return -1;
  dup2(fd, 0);
  dup2(fd, 1);
  dup2(fd, 2);
  if (fd > 2)
    close(fd);
  return 0;
}
```