ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L44
L43:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L44:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L43
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L52
L50:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L72
L78:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    -0x24(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L74
  addl   $0x1,-0x18(%rbp)
L74:
  addl   $0x1,-0x1c(%rbp)
L72:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L78
  addl   $0x1,-0x20(%rbp)
L52:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L50
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D18
type: string

tool: D0: %d %d

tool: D18: %d

assistant: ```c
int main() {
  int n;
  int k;
  int i, j, count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  count = 0;
  for (i = 0; i < n - 1; i++) {
    for (j = i + 1; j < n; j++) {
      if ((a[i] + a[j]) % k == 0) {
        count++;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    (%rsp),%r8d
  test   %r8d,%r8d
  jle    L51
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D0(%rip),%r13
L67:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    (%rsp),%r8d
  add    $0x4,%r12
  cmp    %ebp,%r8d
  jg     L67
L51:
  cmp    $0x1,%r8d
  jle    L11
  mov    0x4(%rsp),%edi
  lea    -0x2(%r8),%r11d
  add    $0x2,%r11
  mov    $0x1,%r10d
  mov    $0x0,%esi
L3:
  cmp    %r10d,%r8d
  jle    L75
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %r10,%rcx
L4:
  mov    %r9d,%eax
  add    (%rbx,%rcx,4),%eax
  cltd
  idiv   %edi
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%rcx
  cmp    %ecx,%r8d
  jg     L4
L75:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L3
L62:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0x0,%esi
  jmp    L62
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string

tool: D3: %d %d

tool: D0: %d

assistant: ```c
int main() {
  int n;
  int k;
  int i, j, count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  count = 0;
  for (i = 0; i < n - 1; i++) {
    for (j = i + 1; j < n; j++) {
      if ((a[i] + a[j]) % k == 0) {
        count++;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L26
  mov    %rax,%rbx
  mov    %rax,%r13
  lea    D12(%rip),%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    (%rsp),%r8d
  add    $0x4,%r13
  cmp    %ebp,%r8d
  jg     L67
  cmp    $0x1,%r8d
  jle    L32
  lea    -0x2(%r8),%r11d
  mov    0x4(%rsp),%edi
  mov    $0x1,%r10d
  xor    %esi,%esi
  add    $0x2,%r11
  nopw   0x0(%rax,%rax,1)
L80:
  cmp    %r10d,%r8d
  jle    L29
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %r10,%rcx
  nopl   (%rax)
L15:
  mov    (%rbx,%rcx,4),%eax
  add    %r9d,%eax
  cltd
  idiv   %edi
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%rcx
  cmp    %ecx,%r8d
  jg     L15
L29:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L80
L4:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  xor    %esi,%esi
  lea    D12(%rip),%r12
  jmp    L4
L32:
  xor    %esi,%esi
  jmp    L4
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D22: %d %d

tool: D12: %d

assistant: ```c
int main() {
  int n;
  int k;
  int i, j, count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  count = 0;
  for (i = 0; i < n - 1; i++) {
    for (j = i + 1; j < n; j++) {
      if ((a[i] + a[j]) % k == 0) {
        count++;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L8
  mov    %rax,%rbx
  mov    %rax,%r13
  lea    D16(%rip),%r12
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <scanf@plt>
  mov    (%rsp),%r8d
  add    $0x4,%r13
  cmp    %ebp,%r8d
  jg     L42
  cmp    $0x1,%r8d
  jle    L76
  lea    -0x2(%r8),%r11d
  mov    0x4(%rsp),%edi
  mov    $0x1,%r10d
  xor    %esi,%esi
  add    $0x2,%r11
  nopw   0x0(%rax,%rax,1)
L23:
  cmp    %r10d,%r8d
  jle    L15
  mov    -0x4(%rbx,%r10,4),%r9d
  mov    %r10,%rcx
  nopl   (%rax)
L66:
  mov    (%rbx,%rcx,4),%eax
  add    %r9d,%eax
  cltd
  idiv   %edi
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%rcx
  cmp    %ecx,%r8d
  jg     L66
L15:
  add    $0x1,%r10
  cmp    %r11,%r10
  jne    L23
L80:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  xor    %esi,%esi
  lea    D16(%rip),%r12
  jmp    L80
L76:
  xor    %esi,%esi
  jmp    L80
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D24: %d %d

tool: D16: %d

assistant: ```c
int main() {
  int n;
  int k;
  int i, j, count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  count = 0;
  for (i = 0; i < n - 1; i++) {
    for (j = i + 1; j < n; j++) {
      if ((a[i] + a[j]) % k == 0) {
        count++;
      }
    }
  }
  printf("%d", count);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<solcon_write_solution_dimensions_to_defined_output_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x8c,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_write_solution_dimensions_to_defined_output_file(int len, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(140, &len, &dim, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solcon_write_solution_dimensions_to_defined_output_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x8c,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_write_solution_dimensions_to_defined_output_file(int len, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(140, &len, &dim, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<solcon_write_solution_dimensions_to_defined_output_file>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x8c,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_write_solution_dimensions_to_defined_output_file(int len, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(140, &len, &dim, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<solcon_write_solution_dimensions_to_defined_output_file>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x8c,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_write_solution_dimensions_to_defined_output_file(int len, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(140, &len, &dim, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: func1

assistant: ```c
int func1(int i) {
  printf("%s\n", __func__);
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func1>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: func1

assistant: ```c
int func1(int i) {
  printf("%s\n", __func__);
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<func1>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: func1

assistant: ```c
int func1(int i) {
  printf("%s\n", __func__);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func1>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: func1

assistant: ```c
int func1(int i) {
  printf("%s\n", __func__);
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strccmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %ecx,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  jmp    L87
L26:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L87:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L76
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L76
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L76
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x18(%rbp)
  jne    L26
L76:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  jmp    L42
L8:
  mov    $0x0,%eax
L42:
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    %dl,-0x18(%rbp)
  je     L12
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  jmp    L78
L12:
  mov    $0x0,%edx
L78:
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_strccmp(const char *s1, const char *s2, char c1, char c2) {
  while (*s1 == *s2 && *s1 != '\0' && *s1 != c1 && *s2 != c2) {
    s1++;
    s2++;
  }
  return ((unsigned char)(*s1 == c1 ? 0 : *s1) - (unsigned char)(*s2 == c2 ? 0 : *s2));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strccmp>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%r9
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    %edx,%r10d
  mov    %ecx,%r11d
  movzbl (%rdi),%edx
  movzbl (%rsi),%esi
  test   %dl,%dl
  setne  %al
  cmp    %sil,%dl
  sete   %cl
  and    %ecx,%eax
  cmp    %sil,%bl
  setne  %cl
  test   %cl,%al
  je     L15
  mov    %rdi,%r8
  cmp    %bpl,%dl
  je     L15
  mov    $0x1,%eax
L34:
  movzbl (%r8,%rax,1),%edx
  movzbl (%r9,%rax,1),%esi
  add    $0x1,%rax
  test   %dl,%dl
  setne  %cl
  cmp    %sil,%dl
  sete   %dil
  and    %edi,%ecx
  cmp    %r10b,%dl
  setne  %dil
  test   %dil,%cl
  je     L15
  cmp    %r11b,%sil
  jne    L34
L15:
  movzbl %dl,%eax
  cmp    %bpl,%dl
  mov    $0x0,%edx
  cmove  %edx,%eax
  movzbl %sil,%edx
  cmp    %bl,%sil
  mov    $0x0,%ecx
  cmove  %ecx,%edx
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_strccmp(const char *s1, const char *s2, char c1, char c2) {
  while (*s1 == *s2 && *s1 != '\0' && *s1 != c1 && *s2 != c2) {
    s1++;
    s2++;
  }
  return ((unsigned char)(*s1 == c1 ? 0 : *s1) - (unsigned char)(*s2 == c2 ? 0 : *s2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strccmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%r9d
  mov    %edx,%r10d
  mov    %ecx,%r11d
  mov    $0x1,%r8d
  cmp    %al,%r9b
  je     L57
  jmp    L9
  xchg   %ax,%ax
L7:
  cmp    %al,%r10b
  je     L42
  cmp    %r9b,%r11b
  je     L22
  movzbl (%rdi,%r8,1),%eax
  add    $0x1,%r8
  movzbl -0x1(%rsi,%r8,1),%r9d
  cmp    %r9b,%al
  jne    L9
L57:
  test   %al,%al
  jne    L7
L9:
  cmp    %dl,%al
  je     L42
L22:
  movzbl %r9b,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  cmp    %cl,%r9b
  cmovne %edx,%eax
  ret
  nopl   (%rax)
L42:
  xor    %eax,%eax
  movzbl %r9b,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  cmp    %cl,%r9b
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ft_strccmp(const char *s1, const char *s2, char c1, char c2) {
  while (*s1 == *s2 && *s1 != '\0' && *s1 != c1 && *s2 != c2) {
    s1++;
    s2++;
  }
  return ((unsigned char)(*s1 == c1 ? 0 : *s1) - (unsigned char)(*s2 == c2 ? 0 : *s2));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_strccmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%r9d
  mov    %edx,%r10d
  mov    %ecx,%r11d
  mov    $0x1,%r8d
  cmp    %al,%r9b
  je     L63
  jmp    L36
  xchg   %ax,%ax
L50:
  cmp    %al,%r10b
  je     L16
  cmp    %r9b,%r11b
  je     L5
  movzbl (%rdi,%r8,1),%eax
  add    $0x1,%r8
  movzbl -0x1(%rsi,%r8,1),%r9d
  cmp    %r9b,%al
  jne    L36
L63:
  test   %al,%al
  jne    L50
L36:
  cmp    %dl,%al
  je     L16
L5:
  movzbl %r9b,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  cmp    %cl,%r9b
  cmovne %edx,%eax
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  movzbl %r9b,%esi
  mov    %eax,%edx
  sub    %esi,%edx
  cmp    %cl,%r9b
  cmovne %edx,%eax
  ret
```

assistant: ```c
int ft_strccmp(const char *s1, const char *s2, char c1, char c2) {
  while (*s1 == *s2 && *s1 != '\0' && *s1 != c1 && *s2 != c2) {
    s1++;
    s2++;
  }
  return ((unsigned char)(*s1 == c1 ? 0 : *s1) - (unsigned char)(*s2 == c2 ? 0 : *s2));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<divide_media_token>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L64
  mov    %rax,%rbx
  lea    D28(%rip),%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
L30:
  movb   $0x0,0x63(%rsp)
  movb   $0x0,0x62(%rsp)
  movb   $0x0,0x61(%rsp)
  mov    %rsp,%rdi
  mov    $0x20,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L78
  movb   $0x0,(%rax)
L78:
  mov    %rsp,%rdi
  mov    $0x9,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L104
  movb   $0x0,(%rax)
L104:
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L45
  movb   $0x0,(%rax)
L45:
  mov    %r14,%r13
  mov    $0x0,%r12d
  mov    %rsp,%rbp
  jmp    L54
L64:
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  mov    $0x0,%r12d
  test   %rax,%rax
  je     L18
  lea    D39(%rip),%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  jmp    L30
L76:
  movb   $0x0,(%rax)
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  add    $0x1,%r12d
  lea    0x1(%rbx),%rbp
  add    $0x1e,%r13
  cmp    $0x5,%r12d
  je     L18
L54:
  cmpb   $0x0,0x0(%rbp)
  je     L18
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L76
  movslq %r12d,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    (%r14,%rax,2),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  add    $0x1,%r12d
L18:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  mov    %r12d,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D28
data_type: string
name: read_data
arguments: data_label: D39
data_type: string

tool: D28: media=

tool: D39: PageSize=

assistant: ```c
int divide_media_token(char *input, char output[5][30]) {
  char media_command[100];
  char *media, *p, *pp;
  int i;
  if ((p = strstr(input, "media=")) != NULL) {
    strcpy(media_command, p + strlen("media="));
  } else if ((p = strstr(input, "PageSize=")) != NULL) {
    strcpy(media_command, p + strlen("PageSize="));
  } else {
    return 0;
  }
  media_command[sizeof(media_command) - 1] = 0;
  media_command[sizeof(media_command) - 2] = 0;
  media_command[sizeof(media_command) - 3] = 0;
  p = strchr(media_command, ' ');
  if (p)
    *p = 0;
  p = strchr(media_command, '\t');
  if (p)
    *p = 0;
  p = strchr(media_command, '\n');
  if (p)
    *p = 0;
  p = media_command;
  for (i = 0; i < 5;) {
    if (*p == 0)
      break;
    pp = strchr(p, ',');
    if (pp)
      *pp = 0;
    strcpy(output[i], p);
    i++;
    if (pp == NULL)
      break;
    p = pp + 1;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<divide_media_token>:
  endbr64
  push   %r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  test   %rax,%rax
  je     L83
  mov    %rax,%rbx
  mov    %r13,%rdi
L42:
  call   <strlen@plt>
  mov    %rsp,%rbp
  cltq
  mov    %rbp,%rdi
  lea    (%rbx,%rax,1),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
  mov    $0x20,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x61(%rsp)
  mov    %ax,0x62(%rsp)
  call   <strchr@plt>
  test   %rax,%rax
  je     L50
  movb   $0x0,(%rax)
L50:
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  movb   $0x0,(%rax)
L34:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
  movb   $0x0,(%rax)
L41:
  xor    %r13d,%r13d
L89:
  cmpb   $0x0,0x0(%rbp)
  je     L27
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L69
  movb   $0x0,(%rax)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rbx),%rbp
  add    $0x1e,%r12
  call   <strcpy@plt>
  cmp    $0x5,%r13d
  jne    L89
L27:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x70,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  lea    D19(%rip),%r14
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  mov    %r14,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  mov    %r14,%rdi
  jmp    L42
  nopl   (%rax)
L69:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L27
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D19
data_type: string

tool: D16: media=

tool: D19: PageSize=

assistant: ```c
int divide_media_token(char *input, char output[5][30]) {
  char media_command[100];
  char *media, *p, *pp;
  int i;
  if ((p = strstr(input, "media=")) != NULL) {
    strcpy(media_command, p + strlen("media="));
  } else if ((p = strstr(input, "PageSize=")) != NULL) {
    strcpy(media_command, p + strlen("PageSize="));
  } else {
    return 0;
  }
  media_command[sizeof(media_command) - 1] = 0;
  media_command[sizeof(media_command) - 2] = 0;
  media_command[sizeof(media_command) - 3] = 0;
  p = strchr(media_command, ' ');
  if (p)
    *p = 0;
  p = strchr(media_command, '\t');
  if (p)
    *p = 0;
  p = strchr(media_command, '\n');
  if (p)
    *p = 0;
  p = media_command;
  for (i = 0; i < 5;) {
    if (*p == 0)
      break;
    pp = strchr(p, ',');
    if (pp)
      *pp = 0;
    strcpy(output[i], p);
    i++;
    if (pp == NULL)
      break;
    p = pp + 1;
  }
  return i;
}
```