ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<dec_bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L112
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  mov    %edx,%eax
  add    %edi,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L69
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x4(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L120
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x8(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L138
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0xc(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L26
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x10(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L106
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x14(%rsp)
  add    %ecx,%eax
  mov    %eax,%ecx
  sar    %ecx
  je     L152
  shr    $0x1f,%eax
  lea    (%rcx,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  mov    %edx,0x18(%rsp)
  add    %ecx,%eax
  mov    %eax,%edx
  sar    %edx
  je     L87
  shr    $0x1f,%eax
  mov    $0x8,%ebx
  add    %eax,%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %edx,0x1c(%rsp)
L143:
  mov    %rsp,%r12
  lea    D5(%rip),%rbp
  nop
L166:
  mov    -0x4(%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L166
L112:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  add    $0x30,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
L106:
  mov    $0x5,%ebx
  jmp    L143
L69:
  mov    $0x1,%ebx
  jmp    L143
L120:
  mov    $0x2,%ebx
  jmp    L143
L138:
  mov    $0x3,%ebx
  jmp    L143
L26:
  mov    $0x4,%ebx
  jmp    L143
L152:
  mov    $0x6,%ebx
  jmp    L143
L87:
  mov    $0x7,%ebx
  jmp    L143
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: %i

assistant: ```c
void dec_bin(int x) {
  int tab[8];
  int i = 0;
  while (x != 0) {
    tab[i] = x % 2;
    x = x / 2;
    i++;
  }
  while (i > 0) {
    i--;
    printf("%i", tab[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arr_float_sum_stages_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movss  D23(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L8
L43:
  movzwl -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movw   $0x0,-0xa(%rbp)
  jmp    L20
L32:
  movzwl -0xa(%rbp),%eax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  movzwl -0xc(%rbp),%eax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L67
  movss  -0x4(%rbp),%xmm0
  movss  D5(%rip),%xmm1
  andps  %xmm1,%xmm0
  ucomiss D19(%rip),%xmm0
  setbe  %al
  xor    $0x1,%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L67
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L67
  movzwl -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movzwl -0xc(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
L67:
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L20:
  movzwl -0xa(%rbp),%eax
  cmp    %rax,-0x30(%rbp)
  ja     L32
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L8:
  movzwl -0xc(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L43
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D5
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D19
type_infered: byte[4]

tool: {"D23": [0x6f,0x12,0x83,0x3a]}

tool: {"D5": [0xff,0xff,0xff,0x7f]}

tool: {"D19": [0xff,0xff,0x7f,0x7f]}

assistant: ```c
void arr_float_sum_stages_pos(float *pDest, float *pSrc, unsigned long int uStates, unsigned long int uStages) {
  float fTol = 1E-3;
  unsigned short int i, j;
  for (i = 0; i < uStates; i++) {
    pDest[i] = 0;
    for (j = 0; j < uStages; j++) {
      float v = pSrc[j * uStates + i];
      if (!isnanf(v) && !isinff(v)) {
        if (v > fTol) {
          pDest[i] += v;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<arr_float_sum_stages_pos>:
  endbr64
  test   %rdx,%rdx
  je     L20
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rdi
  mov    $0x0,%r11d
  mov    $0x0,%esi
  mov    $0x0,%ebx
  movss  D7(%rip),%xmm2
  jmp    L67
L31:
  add    $0x1,%edx
  movzwl %dx,%eax
  cmp    %rcx,%rax
  jae    L93
L2:
  imul   %rdi,%rax
  add    %rsi,%rax
  movss  (%r9,%rax,4),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L31
  movaps %xmm0,%xmm1
  andps  %xmm2,%xmm1
  ucomiss D6(%rip),%xmm1
  ja     L31
  comiss D9(%rip),%xmm0
  jbe    L31
  addss  (%r10),%xmm0
  movss  %xmm0,(%r10)
  jmp    L31
L93:
  add    $0x1,%r11d
  movzwl %r11w,%esi
  cmp    %rdi,%rsi
  jae    L83
L67:
  lea    (%r8,%rsi,4),%r10
  movl   $0x0,(%r10)
  test   %rcx,%rcx
  je     L93
  mov    $0x0,%edx
  mov    %rbx,%rax
  jmp    L2
L83:
  pop    %rbx
  ret
L20:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D6
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D9
data_type: byte[4]

tool: {"D7": [0xff,0xff,0xff,0x7f]}

tool: {"D6": [0xff,0xff,0x7f,0x7f]}

tool: {"D9": [0x6f,0x12,0x83,0x3a]}

assistant: ```c
void arr_float_sum_stages_pos(float *pDest, float *pSrc, unsigned long int uStates, unsigned long int uStages) {
  float fTol = 1E-3;
  unsigned short int i, j;
  for (i = 0; i < uStates; i++) {
    pDest[i] = 0;
    for (j = 0; j < uStages; j++) {
      float v = pSrc[j * uStates + i];
      if (!isnanf(v) && !isinff(v)) {
        if (v > fTol) {
          pDest[i] += v;
        }
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arr_float_sum_stages_pos>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  test   %rdx,%rdx
  je     L52
  xor    %r11d,%r11d
  xor    %edi,%edi
  movss  D22(%rip),%xmm2
  nopl   0x0(%rax)
L65:
  lea    (%r8,%rdi,4),%r10
  movl   $0x0,(%r10)
  test   %rcx,%rcx
  je     L20
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  imul   %rdx,%rax
  add    %rdi,%rax
  movss  (%r9,%rax,4),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L63
  movaps %xmm0,%xmm1
  andps  %xmm2,%xmm1
  ucomiss D8(%rip),%xmm1
  ja     L63
  comiss D19(%rip),%xmm0
  jbe    L63
  addss  (%r10),%xmm0
  movss  %xmm0,(%r10)
L63:
  add    $0x1,%esi
  movzwl %si,%eax
  cmp    %rcx,%rax
  jb     L16
L20:
  add    $0x1,%r11d
  movzwl %r11w,%edi
  cmp    %rdx,%rdi
  jb     L65
L52:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D22
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D8
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D19
type_guessed: byte[4]

tool: {"D22": [0xff,0xff,0xff,0x7f]}

tool: {"D8": [0xff,0xff,0x7f,0x7f]}

tool: {"D19": [0x6f,0x12,0x83,0x3a]}

assistant: ```c
void arr_float_sum_stages_pos(float *pDest, float *pSrc, unsigned long int uStates, unsigned long int uStages) {
  float fTol = 1E-3;
  unsigned short int i, j;
  for (i = 0; i < uStates; i++) {
    pDest[i] = 0;
    for (j = 0; j < uStages; j++) {
      float v = pSrc[j * uStates + i];
      if (!isnanf(v) && !isinff(v)) {
        if (v > fTol) {
          pDest[i] += v;
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arr_float_sum_stages_pos>:
  endbr64
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L67
  cmp    $0x1,%rdx
  jne    L72
  movl   $0x0,(%rdi)
  test   %rcx,%rcx
  je     L67
  xor    %edx,%edx
  xor    %eax,%eax
  movss  D55(%rip),%xmm2
  nopl   0x0(%rax)
L6:
  movss  (%rsi,%rax,4),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L51
  movaps %xmm0,%xmm1
  andps  %xmm2,%xmm1
  ucomiss D35(%rip),%xmm1
  ja     L51
  comiss D21(%rip),%xmm0
  jbe    L51
  addss  (%r8),%xmm0
  movss  %xmm0,(%r8)
L51:
  add    $0x1,%edx
  movzwl %dx,%eax
  cmp    %rax,%rcx
  ja     L6
L67:
  ret
L72:
  xor    %r11d,%r11d
  xor    %r9d,%r9d
  movss  D55(%rip),%xmm2
  cs nopw 0x0(%rax,%rax,1)
L96:
  lea    (%r8,%r9,4),%r10
  movl   $0x0,(%r10)
  test   %rcx,%rcx
  je     L107
  xor    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L110:
  imul   %rdx,%rax
  add    %r9,%rax
  movss  (%rsi,%rax,4),%xmm0
  ucomiss %xmm0,%xmm0
  jp     L69
  movaps %xmm0,%xmm1
  andps  %xmm2,%xmm1
  ucomiss D35(%rip),%xmm1
  ja     L69
  comiss D21(%rip),%xmm0
  jbe    L69
  addss  (%r10),%xmm0
  movss  %xmm0,(%r10)
L69:
  add    $0x1,%edi
  movzwl %di,%eax
  cmp    %rcx,%rax
  jb     L110
L107:
  add    $0x1,%r11d
  movzwl %r11w,%r9d
  cmp    %rdx,%r9
  jb     L96
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D55
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D35
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D21
datatype: byte[4]

tool: {"D55": [0xff,0xff,0xff,0x7f]}

tool: {"D35": [0xff,0xff,0x7f,0x7f]}

tool: {"D21": [0x6f,0x12,0x83,0x3a]}

assistant: ```c
void arr_float_sum_stages_pos(float *pDest, float *pSrc, unsigned long int uStates, unsigned long int uStages) {
  float fTol = 1E-3;
  unsigned short int i, j;
  for (i = 0; i < uStates; i++) {
    pDest[i] = 0;
    for (j = 0; j < uStages; j++) {
      float v = pSrc[j * uStates + i];
      if (!isnanf(v) && !isinff(v)) {
        if (v > fTol) {
          pDest[i] += v;
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Exist_Blk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L4
L38:
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L19:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  cmp    %eax,-0x34(%rbp)
  jne    L2
  movl   $0x1,-0x14(%rbp)
L2:
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x2,-0xc(%rbp)
  jle    L19
  addl   $0x1,-0x10(%rbp)
L4:
  cmpl   $0x2,-0x10(%rbp)
  jle    L38
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Exist_Blk(int a[9][9], int i, int j, int k) {
  int x = i / 3, y = j / 3;
  int result = 0;
  for (int m = 0; m < 3; m++) {
    for (int n = 0; n < 3; n++) {
      if (a[3 * x + m][3 * y + n] == k) {
        result = 1;
      }
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Exist_Blk>:
  endbr64
  mov    %edx,%r8d
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  lea    (%rax,%rax,8),%rdx
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rdx
  lea    0x6c(%rdi,%rax,1),%rdi
  mov    $0x0,%eax
  mov    $0x1,%esi
L5:
  cmp    (%rdx),%ecx
  cmove  %esi,%eax
  cmp    0x4(%rdx),%ecx
  cmove  %esi,%eax
  cmp    %ecx,0x8(%rdx)
  cmove  %esi,%eax
  add    $0x24,%rdx
  cmp    %rdi,%rdx
  jne    L5
  ret
```

assistant: ```c
int Exist_Blk(int a[9][9], int i, int j, int k) {
  int x = i / 3, y = j / 3;
  int result = 0;
  for (int m = 0; m < 3; m++) {
    for (int n = 0; n < 3; n++) {
      if (a[3 * x + m][3 * y + n] == k) {
        result = 1;
      }
    }
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Exist_Blk>:
  endbr64
  movslq %esi,%rax
  sar    $0x1f,%esi
  mov    %edx,%r8d
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %esi,%eax
  mov    $0x1,%esi
  lea    (%rax,%rax,2),%eax
  cltq
  lea    (%rax,%rax,8),%rdx
  movslq %r8d,%rax
  sar    $0x1f,%r8d
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  cltq
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rdx
  lea    0x6c(%rdi,%rax,1),%rdi
  xor    %eax,%eax
L6:
  cmp    (%rdx),%ecx
  cmove  %esi,%eax
  cmp    0x4(%rdx),%ecx
  cmove  %esi,%eax
  cmp    %ecx,0x8(%rdx)
  cmove  %esi,%eax
  add    $0x24,%rdx
  cmp    %rdi,%rdx
  jne    L6
  ret
```

assistant: ```c
int Exist_Blk(int a[9][9], int i, int j, int k) {
  int x = i / 3, y = j / 3;
  int result = 0;
  for (int m = 0; m < 3; m++) {
    for (int n = 0; n < 3; n++) {
      if (a[3 * x + m][3 * y + n] == k) {
        result = 1;
      }
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Exist_Blk>:
  endbr64
  movslq %esi,%rax
  sar    $0x1f,%esi
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,2),%r8d
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  mov    $0x1,%edx
  lea    (%rax,%rax,2),%esi
  movslq %r8d,%rax
  movslq %esi,%rsi
  lea    (%rax,%rax,8),%rax
  shl    $0x2,%rsi
  lea    (%rsi,%rax,4),%r9
  xor    %eax,%eax
  add    %rdi,%r9
  cmp    %ecx,(%r9)
  sete   %al
  cmp    0x4(%r9),%ecx
  cmove  %edx,%eax
  cmp    0x8(%r9),%ecx
  cmove  %edx,%eax
  add    $0x1,%r8d
  movslq %r8d,%r8
  lea    (%r8,%r8,8),%r9
  shl    $0x2,%r9
  lea    (%r9,%rsi,1),%r8
  lea    0x24(%rsi,%r9,1),%rsi
  add    %rdi,%r8
  cmp    (%r8),%ecx
  cmove  %edx,%eax
  cmp    0x4(%r8),%ecx
  cmove  %edx,%eax
  cmp    0x8(%r8),%ecx
  cmove  %edx,%eax
  add    %rsi,%rdi
  cmp    %ecx,(%rdi)
  cmove  %edx,%eax
  cmp    0x4(%rdi),%ecx
  cmove  %edx,%eax
  cmp    0x8(%rdi),%ecx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int Exist_Blk(int a[9][9], int i, int j, int k) {
  int x = i / 3, y = j / 3;
  int result = 0;
  for (int m = 0; m < 3; m++) {
    for (int n = 0; n < 3; n++) {
      if (a[3 * x + m][3 * y + n] == k) {
        result = 1;
      }
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldl_valid_perm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L96
  cmpq   $0x0,-0x28(%rbp)
  jne    L35
L96:
  mov    $0x0,%eax
  jmp    L61
L35:
  cmpq   $0x0,-0x20(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L61
L39:
  movl   $0x0,-0x8(%rbp)
  jmp    L69
L127:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L127
  movl   $0x0,-0x4(%rbp)
  jmp    L80
L84:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L115
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L115
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L5
L115:
  mov    $0x0,%eax
  jmp    L61
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x4(%rbp)
L80:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L84
  mov    $0x1,%eax
L61:
  pop    %rbp
  ret
```

assistant: ```c
int ldl_valid_perm(int n, int P[], int Flag[]) {
  int j, k;
  if (n < 0 || !Flag) {
    return (0);
  }
  if (!P) {
    return (1);
  }
  for (j = 0; j < n; j++) {
    Flag[j] = 0;
  }
  for (k = 0; k < n; k++) {
    j = P[k];
    if (j < 0 || j >= n || Flag[j] != 0) {
      return (0);
    }
    Flag[j] = 1;
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ldl_valid_perm>:
  endbr64
  test   %edi,%edi
  js     L45
  test   %rdx,%rdx
  je     L45
  test   %rsi,%rsi
  je     L9
  test   %edi,%edi
  jle    L33
  mov    %rdx,%rax
  lea    -0x1(%rdi),%r8d
  shl    $0x2,%r8
  lea    0x4(%rdx,%r8,1),%rcx
L34:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L34
  mov    %rsi,%rcx
  lea    0x4(%rsi,%r8,1),%rsi
L20:
  mov    (%rcx),%eax
  test   %eax,%eax
  js     L77
  cmp    %eax,%edi
  jle    L77
  cltq
  lea    (%rdx,%rax,4),%rax
  cmpl   $0x0,(%rax)
  jne    L61
  movl   $0x1,(%rax)
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L20
  mov    $0x1,%eax
  ret
L45:
  mov    $0x0,%eax
  ret
L9:
  mov    $0x1,%eax
  ret
L33:
  mov    $0x1,%eax
  ret
L77:
  mov    $0x0,%eax
  ret
L61:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ldl_valid_perm(int n, int P[], int Flag[]) {
  int j, k;
  if (n < 0 || !Flag) {
    return (0);
  }
  if (!P) {
    return (1);
  }
  for (j = 0; j < n; j++) {
    Flag[j] = 0;
  }
  for (k = 0; k < n; k++) {
    j = P[k];
    if (j < 0 || j >= n || Flag[j] != 0) {
      return (0);
    }
    Flag[j] = 1;
  }
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<ldl_valid_perm>:
  endbr64
  test   %edi,%edi
  js     L25
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L25
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L82
  mov    %edi,%ebp
  test   %edi,%edi
  je     L82
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rax,%rcx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rdx
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x4,%rsi
  movl   $0x1,(%rax)
  cmp    %rsi,%rdx
  je     L82
L79:
  movslq (%rsi),%rax
  test   %eax,%eax
  js     L46
  cmp    %eax,%ebp
  jle    L46
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%edi
  test   %edi,%edi
  je     L45
L46:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L82:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ldl_valid_perm(int n, int P[], int Flag[]) {
  int j, k;
  if (n < 0 || !Flag) {
    return (0);
  }
  if (!P) {
    return (1);
  }
  for (j = 0; j < n; j++) {
    Flag[j] = 0;
  }
  for (k = 0; k < n; k++) {
    j = P[k];
    if (j < 0 || j >= n || Flag[j] != 0) {
      return (0);
    }
    Flag[j] = 1;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldl_valid_perm>:
  endbr64
  test   %edi,%edi
  js     L50
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L50
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L0
  mov    %edi,%ebp
  test   %edi,%edi
  je     L0
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %rcx,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rax,%rcx
  lea    -0x1(%rbp),%eax
  lea    0x4(%rbx,%rax,4),%rdx
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x4,%rsi
  movl   $0x1,(%rax)
  cmp    %rdx,%rsi
  je     L0
L40:
  movslq (%rsi),%rax
  test   %eax,%eax
  js     L82
  cmp    %eax,%ebp
  jle    L82
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%edi
  test   %edi,%edi
  je     L28
L82:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L0:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L50:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ldl_valid_perm(int n, int P[], int Flag[]) {
  int j, k;
  if (n < 0 || !Flag) {
    return (0);
  }
  if (!P) {
    return (1);
  }
  for (j = 0; j < n; j++) {
    Flag[j] = 0;
  }
  for (k = 0; k < n; k++) {
    j = P[k];
    if (j < 0 || j >= n || Flag[j] != 0) {
      return (0);
    }
    Flag[j] = 1;
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L66
  cmpl   $0x0,-0x24(%rbp)
  jne    L72
L66:
  mov    $0xfffffffe,%eax
  jmp    L2
L72:
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  mov    $0xffffffff,%eax
  jmp    L2
L43:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L58
L69:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L20
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L20
L58:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %eax,%eax
  add    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    %rax,-0x10(%rbp)
  jb     L69
L20:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: rb

assistant: ```c
int read_file(const char *filename, char *buf, unsigned int len) {
  FILE *fp = NULL;
  size_t ret = 0;
  if (!buf || len == 0) {
    return -2;
  }
  if ((fp = fopen(filename, "rb")) == NULL) {
    return -1;
  }
  memset(buf, 0x00, len);
  while ((ret += fread(buf + ret, 1, len, fp)) < len) {
    if (ferror(fp) || feof(fp))
      break;
  }
  fclose(fp);
  return ret;
}
```