ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<CE_TCCP>:
  endbr64
  push   %rbx
  movq   %xmm1,%rbx
  sub    $0x60,%rsp
  movsd  %xmm0,0x58(%rsp)
  movapd %xmm7,%xmm0
  movsd  %xmm7,0x48(%rsp)
  movsd  %xmm6,0x50(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm3,0x28(%rsp)
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <CE_Activity@plt>
  movsd  0x8(%rsp),%xmm4
  mov    $0x7,%edi
  movsd  0x30(%rsp),%xmm10
  movsd  0x28(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x20(%rsp)
  movapd %xmm0,%xmm5
  movapd %xmm10,%xmm1
  movq   %rbx,%xmm0
  movsd  %xmm10,0x40(%rsp)
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <CE_MP_pH@plt>
  movsd  0x20(%rsp),%xmm5
  movq   %rbx,%xmm1
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <CE_pHM_HCO3@plt>
  movsd  0x28(%rsp),%xmm5
  movq   %rbx,%xmm1
  movsd  0x8(%rsp),%xmm9
  movsd  0x20(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  movsd  %xmm0,0x38(%rsp)
  movsd  0x10(%rsp),%xmm2
  movapd %xmm9,%xmm0
  movsd  %xmm5,0x30(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <CE_pHM_CO3@plt>
  movsd  0x8(%rsp),%xmm9
  mov    $0xa,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  D13(%rip),%xmm0
  subsd  %xmm9,%xmm0
  cvttsd2si %xmm0,%esi
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm5
  sub    $0x10,%rsp
  xor    %edi,%edi
  movsd  0x48(%rsp),%xmm12
  movsd  D14(%rip),%xmm1
  divsd  %xmm5,%xmm0
  movsd  0x20(%rsp),%xmm8
  movsd  0x38(%rsp),%xmm4
  mulsd  %xmm1,%xmm12
  movsd  0x58(%rsp),%xmm7
  movsd  %xmm5,(%rsp)
  movsd  0x60(%rsp),%xmm6
  addsd  %xmm8,%xmm8
  movsd  0x30(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm2
  movsd  0x50(%rsp),%xmm10
  movsd  0x68(%rsp),%xmm11
  movsd  0x18(%rsp),%xmm9
  addsd  %xmm12,%xmm8
  movapd %xmm0,%xmm12
  mulsd  %xmm1,%xmm12
  addsd  %xmm12,%xmm8
  movapd %xmm5,%xmm12
  mulsd  %xmm5,%xmm12
  movapd %xmm3,%xmm5
  movapd %xmm10,%xmm3
  mulsd  %xmm0,%xmm12
  movapd %xmm4,%xmm0
  divsd  %xmm12,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm11,%xmm1
  addsd  %xmm0,%xmm8
  movapd %xmm9,%xmm0
  subsd  %xmm8,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movapd %xmm6,%xmm7
  movapd %xmm4,%xmm6
  movapd %xmm2,%xmm4
  movq   %rbx,%xmm2
  call   <finddCa@plt>
  add    $0x70,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type: byte[8]
name: read_data
arguments: data_label: D14
type: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double CE_TCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double IS) {
  double pH0;
  double f0, HCO3, CO3, H3O, OH, IB;
  f0 = CE_Activity(IS);
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  HCO3 = CE_pHM_HCO3(pH0, M, K1, K2, Kw, f0);
  CO3 = CE_pHM_CO3(pH0, M, K1, K2, Kw, f0);
  H3O = pow(10, (3 - pH0)) / f0;
  OH = Kw / (f0 * f0 * H3O);
  IB = IS - (2 * CO3 + HCO3 / 2 + H3O / 2 + OH / 2);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CE_TCCP>:
  endbr64
  push   %rbx
  movq   %xmm1,%rbx
  sub    $0x60,%rsp
  movsd  %xmm0,0x58(%rsp)
  movapd %xmm7,%xmm0
  movsd  %xmm7,0x48(%rsp)
  movsd  %xmm6,0x50(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm3,0x28(%rsp)
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <CE_Activity@plt>
  movsd  0x8(%rsp),%xmm4
  mov    $0x7,%edi
  movsd  0x30(%rsp),%xmm10
  movsd  0x28(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x20(%rsp)
  movapd %xmm0,%xmm5
  movapd %xmm10,%xmm1
  movq   %rbx,%xmm0
  movsd  %xmm10,0x40(%rsp)
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <CE_MP_pH@plt>
  movsd  0x20(%rsp),%xmm5
  movq   %rbx,%xmm1
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <CE_pHM_HCO3@plt>
  movsd  0x28(%rsp),%xmm5
  movq   %rbx,%xmm1
  movsd  0x8(%rsp),%xmm9
  movsd  0x20(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  movsd  %xmm0,0x38(%rsp)
  movsd  0x10(%rsp),%xmm2
  movapd %xmm9,%xmm0
  movsd  %xmm5,0x30(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <CE_pHM_CO3@plt>
  movsd  0x8(%rsp),%xmm9
  mov    $0xa,%edi
  movsd  %xmm0,0x10(%rsp)
  movsd  D16(%rip),%xmm0
  subsd  %xmm9,%xmm0
  cvttsd2si %xmm0,%esi
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm5
  sub    $0x10,%rsp
  xor    %edi,%edi
  movsd  0x48(%rsp),%xmm12
  movsd  D19(%rip),%xmm1
  divsd  %xmm5,%xmm0
  movsd  0x20(%rsp),%xmm8
  movsd  0x38(%rsp),%xmm4
  mulsd  %xmm1,%xmm12
  movsd  0x58(%rsp),%xmm7
  movsd  %xmm5,(%rsp)
  movsd  0x60(%rsp),%xmm6
  addsd  %xmm8,%xmm8
  movsd  0x30(%rsp),%xmm3
  movsd  0x28(%rsp),%xmm2
  movsd  0x50(%rsp),%xmm10
  movsd  0x68(%rsp),%xmm11
  movsd  0x18(%rsp),%xmm9
  addsd  %xmm12,%xmm8
  movapd %xmm0,%xmm12
  mulsd  %xmm1,%xmm12
  addsd  %xmm12,%xmm8
  movapd %xmm5,%xmm12
  mulsd  %xmm5,%xmm12
  movapd %xmm3,%xmm5
  movapd %xmm10,%xmm3
  mulsd  %xmm0,%xmm12
  movapd %xmm4,%xmm0
  divsd  %xmm12,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm11,%xmm1
  addsd  %xmm0,%xmm8
  movapd %xmm9,%xmm0
  subsd  %xmm8,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movapd %xmm6,%xmm7
  movapd %xmm4,%xmm6
  movapd %xmm2,%xmm4
  movq   %rbx,%xmm2
  call   <finddCa@plt>
  add    $0x70,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
datatype: byte[8]
name: disassemble_data
arguments: label: D19
datatype: byte[8]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double CE_TCCP(double Ca, double M, double P, double K1, double K2, double Kw, double Ks, double IS) {
  double pH0;
  double f0, HCO3, CO3, H3O, OH, IB;
  f0 = CE_Activity(IS);
  pH0 = CE_MP_pH(M, P, K1, K2, Kw, f0, 7);
  HCO3 = CE_pHM_HCO3(pH0, M, K1, K2, Kw, f0);
  CO3 = CE_pHM_CO3(pH0, M, K1, K2, Kw, f0);
  H3O = pow(10, (3 - pH0)) / f0;
  OH = Kw / (f0 * f0 * H3O);
  IB = IS - (2 * CO3 + HCO3 / 2 + H3O / 2 + OH / 2);
  return finddCa(0, pH0, Ca, M, P, K1, K2, Kw, Ks, f0, IB);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L18
  movl   $0x1,-0xc(%rbp)
  jmp    L36
L22:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L58
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x0,-0x8(%rbp)
  js     L42
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
L42:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  jmp    L57
L18:
  nop
L57:
  pop    %rbp
  ret
```

assistant: ```c
void insertSort(int a[], int len) {
  if (len < 2) {
    return;
  }
  for (int i = 1; i < len; i++) {
    int temp = a[i];
    int j = i - 1;
    while (j >= 0 && a[j] > temp) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = temp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L7
L0:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L5
L7:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L0
L23:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L0
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L23
  jmp    L0
L5:
  ret
```

assistant: ```c
void insertSort(int a[], int len) {
  if (len < 2) {
    return;
  }
  for (int i = 1; i < len; i++) {
    int temp = a[i];
    int j = i - 1;
    while (j >= 0 && a[j] > temp) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L37
L11:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L20
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L13
  mov    %rdi,%rax
L12:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L11
L37:
  ret
  nopl   (%rax)
L20:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L12
```

assistant: ```c
void insertSort(int a[], int len) {
  if (len < 2) {
    return;
  }
  for (int i = 1; i < len; i++) {
    int temp = a[i];
    int j = i - 1;
    while (j >= 0 && a[j] > temp) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insertSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  jle    L36
L32:
  mov    0x4(%rdi,%r8,4),%esi
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jle    L16
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L37
  mov    %rdi,%rax
L17:
  add    $0x1,%r8
  mov    %esi,(%rax)
  cmp    %r8,%r9
  jne    L32
L36:
  ret
  nopl   (%rax)
L16:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  jmp    L17
```

assistant: ```c
void insertSort(int a[], int len) {
  if (len < 2) {
    return;
  }
  for (int i = 1; i < len; i++) {
    int temp = a[i];
    int j = i - 1;
    while (j >= 0 && a[j] > temp) {
      a[j + 1] = a[j];
      j--;
    }
    a[j + 1] = temp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x2d,%edi
  call   <gpio_set@plt>
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <gpio_set@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stop() {
  gpio_set((45), 0);
  gpio_set((23), 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x2d,%edi
  call   <gpio_set@plt>
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <gpio_set@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stop() {
  gpio_set((45), 0);
  gpio_set((23), 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stop>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x2d,%edi
  call   <gpio_set@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  add    $0x8,%rsp
  jmp    1050 <gpio_set@plt>
```

assistant: ```c
void stop() {
  gpio_set((45), 0);
  gpio_set((23), 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stop>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x2d,%edi
  call   <gpio_set@plt>
  xor    %esi,%esi
  mov    $0x17,%edi
  add    $0x8,%rsp
  jmp    1050 <gpio_set@plt>
```

assistant: ```c
void stop() {
  gpio_set((45), 0);
  gpio_set((23), 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<path_parser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x840(%rbp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L56
  mov    $0x1,%ebx
  lea    D8(%rip),%r12
L0:
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x1,%ebx
  test   %rax,%rax
  jne    L0
L18:
  movslq %ebx,%rbx
  lea    0xf(,%rbx,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L60:
  cmp    %rdx,%rsp
  je     L37
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L56:
  mov    $0x1,%ebx
  jmp    L18
L37:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L59
  orq    $0x0,-0x8(%rsp,%rax,1)
L59:
  mov    %rsp,%r12
  lea    -0x840(%rbp),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <strcpy@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%ebx
  lea    D8(%rip),%r14
L3:
  mov    %rax,-0x8(%r12,%rbx,8)
  mov    %ebx,%r13d
  mov    %r14,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L3
L87:
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    %r13d,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L7:
  mov    $0x0,%r13d
  jmp    L87
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: /

assistant: ```c
int path_parser(char *path, char *pathfound) {
  char *token;
  char aux[2048];
  strcpy(aux, path);
  int char_size = 1;
  token = strtok(aux, "/");
  while (token != NULL) {
    token = strtok(NULL, "/");
    ++char_size;
  }
  const char *paths[char_size];
  strcpy(aux, path);
  char_size = 0;
  token = strtok(aux, "/");
  while (token != NULL) {
    paths[char_size] = token;
    ++char_size;
    token = strtok(NULL, "/");
  }
  strcpy(pathfound, paths);
  return char_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_parser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x840(%rbp),%r15
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  mov    %r15,%rdi
  push   %r12
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L23
  mov    $0x1,%r12d
L14:
  mov    %rbx,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  jne    L14
  movslq %r12d,%r12
  shl    $0x3,%r12
L84:
  add    $0xf,%r12
  mov    %rsp,%rdx
  mov    %r12,%rax
  and    $0xfffffffffffff000,%r12
  sub    %r12,%rdx
  and    $0xfffffffffffffff0,%rax
  cmp    %rdx,%rsp
  je     L97
L89:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L89
L97:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L16
L25:
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L76
  mov    $0x1,%r15d
  nop
L30:
  mov    %rax,-0x8(%r12,%r15,8)
  mov    %rbx,%rsi
  xor    %edi,%edi
  mov    %r15d,%r13d
  add    $0x1,%r15
  call   <strtok@plt>
  test   %rax,%rax
  jne    L30
L64:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x8,%r12d
  jmp    L84
L76:
  xor    %r13d,%r13d
  jmp    L64
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: /

assistant: ```c
int path_parser(char *path, char *pathfound) {
  char *token;
  char aux[2048];
  strcpy(aux, path);
  int char_size = 1;
  token = strtok(aux, "/");
  while (token != NULL) {
    token = strtok(NULL, "/");
    ++char_size;
  }
  const char *paths[char_size];
  strcpy(aux, path);
  char_size = 0;
  token = strtok(aux, "/");
  while (token != NULL) {
    paths[char_size] = token;
    ++char_size;
    token = strtok(NULL, "/");
  }
  strcpy(pathfound, paths);
  return char_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<path_parser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x840(%rbp),%r15
  mov    %rsi,%r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  mov    %r15,%rdi
  push   %r12
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L103
  mov    $0x1,%r12d
L23:
  mov    %rbx,%rsi
  xor    %edi,%edi
  add    $0x1,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  jne    L23
  movslq %r12d,%r12
  shl    $0x3,%r12
L19:
  add    $0xf,%r12
  mov    %rsp,%rdx
  mov    %r12,%rax
  and    $0xfffffffffffff000,%r12
  sub    %r12,%rdx
  and    $0xfffffffffffffff0,%rax
  cmp    %rdx,%rsp
  je     L30
L34:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L34
L30:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L44
L67:
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L38
  mov    $0x1,%r15d
  nop
L79:
  mov    %rax,-0x8(%r12,%r15,8)
  mov    %rbx,%rsi
  xor    %edi,%edi
  mov    %r15d,%r13d
  add    $0x1,%r15
  call   <strtok@plt>
  test   %rax,%rax
  jne    L79
L48:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  lea    -0x28(%rbp),%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L44:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L103:
  mov    $0x8,%r12d
  jmp    L19
L38:
  xor    %r13d,%r13d
  jmp    L48
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: /

assistant: ```c
int path_parser(char *path, char *pathfound) {
  char *token;
  char aux[2048];
  strcpy(aux, path);
  int char_size = 1;
  token = strtok(aux, "/");
  while (token != NULL) {
    token = strtok(NULL, "/");
    ++char_size;
  }
  const char *paths[char_size];
  strcpy(aux, path);
  char_size = 0;
  token = strtok(aux, "/");
  while (token != NULL) {
    paths[char_size] = token;
    ++char_size;
    token = strtok(NULL, "/");
  }
  strcpy(pathfound, paths);
  return char_size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<io_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf1c20890,%eax
  movl   $0x111111,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void io_init(void) {
  *(volatile unsigned int *)((0xf1c20890)) = 0x111111;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<io_init>:
  endbr64
  mov    $0xf1c20890,%eax
  movl   $0x111111,(%rax)
  ret
```

assistant: ```c
void io_init(void) {
  *(volatile unsigned int *)((0xf1c20890)) = 0x111111;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<io_init>:
  endbr64
  mov    $0xf1c20890,%eax
  movl   $0x111111,(%rax)
  ret
```

assistant: ```c
void io_init(void) {
  *(volatile unsigned int *)((0xf1c20890)) = 0x111111;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<io_init>:
  endbr64
  mov    $0xf1c20890,%eax
  movl   $0x111111,(%rax)
  ret
```

assistant: ```c
void io_init(void) {
  *(volatile unsigned int *)((0xf1c20890)) = 0x111111;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L17
L29:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L17
L26:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L85
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L17
L85:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L17
L30:
  addq   $0x1,-0x8(%rbp)
  jmp    L28
L17:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int str_len(const char *s) {
  const char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_len>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L27
L42:
  cmpb   $0x0,0x1(%rax)
  je     L1
  cmpb   $0x0,0x2(%rax)
  je     L2
  cmpb   $0x0,0x3(%rax)
  je     L22
  add    $0x4,%rax
  cmpb   $0x0,(%rax)
  jne    L42
L27:
  sub    %edi,%eax
  ret
L1:
  add    $0x1,%rax
  sub    %edi,%eax
  ret
L2:
  add    $0x2,%rax
  sub    %edi,%eax
  ret
L22:
  add    $0x3,%rax
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int str_len(const char *s) {
  const char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_len>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  jne    L36
  jmp    L6
  xchg   %ax,%ax
L57:
  cmpb   $0x0,0x2(%rax)
  je     L12
  cmpb   $0x0,0x3(%rax)
  je     L31
  add    $0x4,%rax
  cmpb   $0x0,(%rax)
  je     L11
L36:
  cmpb   $0x0,0x1(%rax)
  jne    L57
  add    $0x1,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x2,%rax
  sub    %edi,%eax
  ret
  nop
L31:
  add    $0x3,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  sub    %edi,%eax
  ret
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int str_len(const char *s) {
  const char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_len>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  jne    L47
  jmp    L15
  xchg   %ax,%ax
L38:
  cmpb   $0x0,0x2(%rax)
  je     L37
  cmpb   $0x0,0x3(%rax)
  je     L10
  add    $0x4,%rax
  cmpb   $0x0,(%rax)
  je     L24
L47:
  cmpb   $0x0,0x1(%rax)
  jne    L38
  add    $0x1,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x2,%rax
  sub    %edi,%eax
  ret
  nop
L10:
  add    $0x3,%rax
  sub    %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  sub    %edi,%eax
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int str_len(const char *s) {
  const char *t;
  t = s;
  for (;;) {
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
    if (!*t)
      return t - s;
    ++t;
  }
}
```