ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x3b(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  lea    0x3b(%rsp),%rcx
L23:
  movsbl (%rax,%rcx,1),%edx
  sub    $0x30,%edx
  mov    %edx,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L23
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <month@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <digit_10@plt>
  cmp    %eax,0x24(%rsp)
  jne    L9
  test   %ebx,%ebx
  je     L9
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L9:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D28: %s

tool: D10: 1

tool: D4: 0

assistant: ```c
int main() {
  int n[13], i = 0;
  char s[13];
  int flag = 1, fg = 1;
  scanf("%s", s);
  for (i = 0; i < 10; i++) {
    n[i] = s[i] - '0';
  }
  flag = month(n);
  if (digit_10(n) != n[9]) {
    fg = 0;
  }
  if (flag == 0 || fg == 0) {
    printf("0");
  } else {
    printf("1");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x3b(%rsp),%rbx
  mov    %rsp,%rbp
  mov    %rbx,%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L24:
  movsbl (%rbx,%rax,1),%edx
  sub    $0x30,%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L24
  mov    %rbp,%rdi
  call   <month@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <digit_10@plt>
  cmp    0x24(%rsp),%eax
  je     L19
L7:
  lea    D28(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  test   %ebx,%ebx
  je     L7
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D28
type: string
name: parse_data
arguments: label: D11
type: string

tool: D3: %s

tool: D28: 0

tool: D11: 1

assistant: ```c
int main() {
  int n[13], i = 0;
  char s[13];
  int flag = 1, fg = 1;
  scanf("%s", s);
  for (i = 0; i < 10; i++) {
    n[i] = s[i] - '0';
  }
  flag = month(n);
  if (digit_10(n) != n[9]) {
    fg = 0;
  }
  if (flag == 0 || fg == 0) {
    printf("0");
  } else {
    printf("1");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rdi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x3b(%rsp),%rsi
  mov    %rsp,%rbp
  call   <scanf@plt>
  movsbl 0x3b(%rsp),%eax
  mov    %rbp,%rdi
  sub    $0x30,%eax
  mov    %eax,(%rsp)
  movsbl 0x3c(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x4(%rsp)
  movsbl 0x3d(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x8(%rsp)
  movsbl 0x3e(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0xc(%rsp)
  movsbl 0x3f(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x10(%rsp)
  movsbl 0x40(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x14(%rsp)
  movsbl 0x41(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x18(%rsp)
  movsbl 0x42(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x1c(%rsp)
  movsbl 0x43(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x20(%rsp)
  movsbl 0x44(%rsp),%eax
  sub    $0x30,%eax
  mov    %eax,0x24(%rsp)
  call   <month@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <digit_10@plt>
  cmp    0x24(%rsp),%eax
  je     L25
L2:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  test   %ebx,%ebx
  je     L2
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string
name: parse_data
arguments: data_label: D15
type_guessed: string

tool: D22: %s

tool: D16: 0

tool: D15: 1

assistant: ```c
int main() {
  int n[13], i = 0;
  char s[13];
  int flag = 1, fg = 1;
  scanf("%s", s);
  for (i = 0; i < 10; i++) {
    n[i] = s[i] - '0';
  }
  flag = month(n);
  if (digit_10(n) != n[9]) {
    fg = 0;
  }
  if (flag == 0 || fg == 0) {
    printf("0");
  } else {
    printf("1");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_squh_use_in1fft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mp_mul_csqu@plt>
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rsi
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    0x10(%rbp),%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    $0xffffffff,%esi
  mov    %eax,%edi
  call   <rdft@plt>
  mov    -0x18(%rbp),%rdi
  mov    -0x10(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <mp_mul_d2i@plt>
  nop
  leave
  ret
```

assistant: ```c
void mp_squh_use_in1fft(int n, int radix, double inoutfft[], int out[], int nfft, int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_csqu(nfft, inoutfft);
  rdft(nfft, -1, &inoutfft[1], ip, w);
  mp_mul_d2i(n, radix, nfft, inoutfft, out);
}
```
user: What is the c source code of the assembly code below:

```asm
<mp_squh_use_in1fft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %r8d,%ebx
  mov    %r9,%r15
  mov    %rdx,%rsi
  mov    %r8d,%edi
  call   <mp_mul_csqu@plt>
  lea    0x8(%rbp),%rdx
  mov    0x40(%rsp),%r8
  mov    %r15,%rcx
  mov    $0xffffffff,%esi
  mov    %ebx,%edi
  call   <rdft@plt>
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <mp_mul_d2i@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mp_squh_use_in1fft(int n, int radix, double inoutfft[], int out[], int nfft, int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_csqu(nfft, inoutfft);
  rdft(nfft, -1, &inoutfft[1], ip, w);
  mp_mul_d2i(n, radix, nfft, inoutfft, out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mp_squh_use_in1fft>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r8
  mov    %r8,0x8(%rsp)
  call   <mp_mul_csqu@plt>
  mov    0x8(%rsp),%r8
  mov    %r15,%rcx
  mov    %r12d,%edi
  lea    0x8(%r13),%rdx
  mov    $0xffffffff,%esi
  call   <rdft@plt>
  add    $0x18,%rsp
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <mp_mul_d2i@plt>
```

assistant: ```c
void mp_squh_use_in1fft(int n, int radix, double inoutfft[], int out[], int nfft, int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_csqu(nfft, inoutfft);
  rdft(nfft, -1, &inoutfft[1], ip, w);
  mp_mul_d2i(n, radix, nfft, inoutfft, out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mp_squh_use_in1fft>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r8
  mov    %r8,0x8(%rsp)
  call   <mp_mul_csqu@plt>
  mov    0x8(%rsp),%r8
  mov    %r15,%rcx
  mov    %r12d,%edi
  lea    0x8(%r13),%rdx
  mov    $0xffffffff,%esi
  call   <rdft@plt>
  add    $0x18,%rsp
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <mp_mul_d2i@plt>
```

assistant: ```c
void mp_squh_use_in1fft(int n, int radix, double inoutfft[], int out[], int nfft, int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  mp_mul_csqu(nfft, inoutfft);
  rdft(nfft, -1, &inoutfft[1], ip, w);
  mp_mul_d2i(n, radix, nfft, inoutfft, out);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<howdy_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L0:
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string

tool: D11: Not enough memory

tool: D19: Howdy! Howdy! Hi!

tool: D26: %s


assistant: ```c
void howdy_1(void) {
  char *string;
  string = (char *)malloc(80);
  if (string == (char *)NULL) {
    puts("Not enough memory");
  }
  strcpy(string, "Howdy! Howdy! Hi!");
  printf("%s\n", string);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<howdy_1>:
  endbr64
  push   %rbx
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L19:
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
L9:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D25
type: string
name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D19
type: string

tool: D25: Howdy! Howdy! Hi!

tool: D1: %s


tool: D19: Not enough memory

assistant: ```c
void howdy_1(void) {
  char *string;
  string = (char *)malloc(80);
  if (string == (char *)NULL) {
    puts("Not enough memory");
  }
  strcpy(string, "Howdy! Howdy! Hi!");
  printf("%s\n", string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<howdy_1>:
  endbr64
  push   %rbp
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
L13:
  mov    %rbp,%rdi
  lea    D13(%rip),%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  pop    %rbp
  jmp    10a0 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L13
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D4
datatype: string
name: extract_symbolic_data
arguments: data_label: D15
datatype: string

tool: D13: Howdy! Howdy! Hi!

tool: D4: %s


tool: D15: Not enough memory

assistant: ```c
void howdy_1(void) {
  char *string;
  string = (char *)malloc(80);
  if (string == (char *)NULL) {
    puts("Not enough memory");
  }
  strcpy(string, "Howdy! Howdy! Hi!");
  printf("%s\n", string);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<howdy_1>:
  endbr64
  push   %rbp
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
L3:
  mov    %rbp,%rdi
  lea    D28(%rip),%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  pop    %rbp
  jmp    10a0 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D28: Howdy! Howdy! Hi!

tool: D18: %s


tool: D15: Not enough memory

assistant: ```c
void howdy_1(void) {
  char *string;
  string = (char *)malloc(80);
  if (string == (char *)NULL) {
    puts("Not enough memory");
  }
  strcpy(string, "Howdy! Howdy! Hi!");
  printf("%s\n", string);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<event_fatal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <event_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void event_fatal_error(s) char *s;
{
  event_error(s);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<event_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <event_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void event_fatal_error(s) char *s;
{
  event_error(s);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<event_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <event_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void event_fatal_error(s) char *s;
{
  event_error(s);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<event_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <event_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void event_fatal_error(s) char *s;
{
  event_error(s);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<revstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L0
L3:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L3
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *revstr(char *str) {
  char t;
  size_t i, j;
  assert(str != NULL);
  for (i = 0, j = strlen(str) - 1; i < j; ++i, --j)
    t = str[i], str[i] = str[j], str[j] = t;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<revstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L5
  mov    $0x0,%edx
L2:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L2
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *revstr(char *str) {
  char t;
  size_t i, j;
  assert(str != NULL);
  for (i = 0, j = strlen(str) - 1; i < j; ++i, --j)
    t = str[i], str[i] = str[j], str[j] = t;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<revstr>:
  endbr64
  test   %rdi,%rdi
  push   %r12
  mov    %rdi,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L13
  xor    %edx,%edx
  nopl   (%rax)
L16:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L16
L13:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *revstr(char *str) {
  char t;
  size_t i, j;
  assert(str != NULL);
  for (i = 0, j = strlen(str) - 1; i < j; ++i, --j)
    t = str[i], str[i] = str[j], str[j] = t;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<revstr>:
  endbr64
  test   %rdi,%rdi
  push   %r12
  mov    %rdi,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  test   %rax,%rax
  je     L15
  xor    %edx,%edx
  nopl   (%rax)
L18:
  movzbl (%r12,%rdx,1),%ecx
  movzbl (%r12,%rax,1),%esi
  mov    %sil,(%r12,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L18
L15:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *revstr(char *str) {
  char t;
  size_t i, j;
  assert(str != NULL);
  for (i = 0, j = strlen(str) - 1; i < j; ++i, --j)
    t = str[i], str[i] = str[j], str[j] = t;
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uninivar_vsscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsscanf@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninivar_vsscanf(void) {
  char *s;
  char *format;
  va_list arg;
  (void)vsscanf(s, format, arg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uninivar_vsscanf>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsscanf@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninivar_vsscanf(void) {
  char *s;
  char *format;
  va_list arg;
  (void)vsscanf(s, format, arg);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uninivar_vsscanf>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <vsscanf@plt>
```

assistant: ```c
void uninivar_vsscanf(void) {
  char *s;
  char *format;
  va_list arg;
  (void)vsscanf(s, format, arg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uninivar_vsscanf>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <vsscanf@plt>
```

assistant: ```c
void uninivar_vsscanf(void) {
  char *s;
  char *format;
  va_list arg;
  (void)vsscanf(s, format, arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L22
L25:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L25
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D46
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D32: insert numbers to rotate a,b,c

tool: D7: %d %d %d

tool: D46: insert how many times to rotate

tool: D19: %d

assistant: ```c
int main() {
  int a, b, c, n;
  printf("insert numbers to rotate a,b,c\n");
  scanf("%d %d %d", &a, &b, &c);
  printf("insert how many times to rotate\n");
  scanf("%d", &n);
  while (n > 0) {
    rotr(&a, &b, &c);
    n--;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L24
  lea    0x10(%rsp),%rbx
L13:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rbx,%rdx
  call   <rotr@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  test   %eax,%eax
  jg     L13
L24:
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D37
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D9: insert numbers to rotate a,b,c

tool: D37: %d %d %d

tool: D6: insert how many times to rotate

tool: D3: %d

assistant: ```c
int main() {
  int a, b, c, n;
  printf("insert numbers to rotate a,b,c\n");
  scanf("%d %d %d", &a, &b, &c);
  printf("insert how many times to rotate\n");
  scanf("%d", &n);
  while (n > 0) {
    rotr(&a, &b, &c);
    n--;
  }
  printf("%d %d %d", a, b, c);
  return 0;
}
```