ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%r13d
  mov    %rsp,%r14
  lea    D15(%rip),%r12
  mov    $0x0,%r15d
  jmp    L20
L32:
  lea    0x1(%r13),%ebx
  mov    %ebp,%edx
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%r13d
L20:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L36
  cmpl   $0x0,(%rsp)
  jle    L36
  mov    $0x0,%ebx
  mov    %r15d,%ebp
L58:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L58
  jmp    L32
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D15: %d

tool: D18: Teste %d
%d



assistant: ```c
main() {
  int n, x, acc, i, teste = 1;
  while (scanf("%d", &n) == 1 && n > 0) {
    acc = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &x);
      acc += x;
    }
    printf("Teste %d\n%d\n\n", teste++, acc);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L33
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L33
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L3:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%r15d
  cmp    %ebx,(%rsp)
  jg     L3
  mov    %r13d,%esi
  lea    D2(%rip),%rdi
  lea    0x1(%r13),%ebx
  mov    %r15d,%edx
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L26
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string

tool: D8: %d

tool: D2: Teste %d
%d



assistant: ```c
main() {
  int n, x, acc, i, teste = 1;
  while (scanf("%d", &n) == 1 && n > 0) {
    acc = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &x);
      acc += x;
    }
    printf("Teste %d\n%d\n\n", teste++, acc);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L27
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %ebx,%ebx
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L20:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x4(%rsp),%r15d
  cmp    %ebx,(%rsp)
  jg     L20
  mov    %r13d,%esi
  lea    D17(%rip),%rdi
  lea    0x1(%r13),%ebx
  mov    %r15d,%edx
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L7
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D17
type: string

tool: D2: %d

tool: D17: Teste %d
%d



assistant: ```c
main() {
  int n, x, acc, i, teste = 1;
  while (scanf("%d", &n) == 1 && n > 0) {
    acc = 0;
    for (i = 0; i < n; i++) {
      scanf("%d", &x);
      acc += x;
    }
    printf("Teste %d\n%d\n\n", teste++, acc);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiplicacao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int multiplicacao(int one_parameter, int second_paramater) {
  int resultado = 0;
  resultado = one_parameter * second_paramater;
  return resultado;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiplicacao>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int multiplicacao(int one_parameter, int second_paramater) {
  int resultado = 0;
  resultado = one_parameter * second_paramater;
  return resultado;
}
```
user: What is the c source code of the assembly code below?

```asm
<multiplicacao>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int multiplicacao(int one_parameter, int second_paramater) {
  int resultado = 0;
  resultado = one_parameter * second_paramater;
  return resultado;
}
```
user: What is the c source code of the assembly code below:

```asm
<multiplicacao>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int multiplicacao(int one_parameter, int second_paramater) {
  int resultado = 0;
  resultado = one_parameter * second_paramater;
  return resultado;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<endnetent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_endnethtent@plt>
  mov    $0x0,%eax
  call   <_endnetdnsent@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void endnetent(void) {
  _endnethtent();
  _endnetdnsent();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endnetent>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_endnethtent@plt>
  mov    $0x0,%eax
  call   <_endnetdnsent@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void endnetent(void) {
  _endnethtent();
  _endnetdnsent();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<endnetent>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_endnethtent@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <_endnetdnsent@plt>
```

assistant: ```c
void endnetent(void) {
  _endnethtent();
  _endnetdnsent();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<primo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L67
L22:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L16
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x1,-0x4(%rbp)
  jg     L34
  addl   $0x1,-0x8(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jle    L22
  jmp    L50
L34:
  nop
L50:
  cmpl   $0x1,-0x4(%rbp)
  jg     L10
  cmpl   $0x1,-0x14(%rbp)
  jg     L17
L10:
  mov    $0x0,%eax
  jmp    L27
L17:
  mov    $0x1,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int primo(int n) {
  int i, cont = 0;
  for (i = 1; i <= n / 2; i++) {
    if (n % i == 0)
      cont++;
    if (cont > 1)
      break;
  }
  if (cont > 1 || n < 2)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<primo>:
  endbr64
  mov    %edi,%r8d
  shr    $0x1f,%r8d
  add    %edi,%r8d
  sar    %r8d
  cmp    $0x1,%edi
  jle    L19
  mov    $0x0,%esi
  mov    $0x1,%ecx
L29:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  cmp    $0x1,%esi
  jg     L25
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jle    L29
L25:
  cmp    $0x1,%esi
  setg   %al
  cmp    $0x1,%edi
  setle  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
L19:
  mov    $0x0,%esi
  jmp    L25
```

assistant: ```c
int primo(int n) {
  int i, cont = 0;
  for (i = 1; i <= n / 2; i++) {
    if (n % i == 0)
      cont++;
    if (cont > 1)
      break;
  }
  if (cont > 1 || n < 2)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<primo>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x1,%edi
  jle    L33
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  jmp    L41
  nopl   0x0(%rax)
L35:
  mov    $0x1,%r8d
L28:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L33
L41:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L28
  cmp    $0x1,%r8d
  jne    L35
  mov    %edx,%eax
  ret
  nop
L33:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setg   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
int primo(int n) {
  int i, cont = 0;
  for (i = 1; i <= n / 2; i++) {
    if (n % i == 0)
      cont++;
    if (cont > 1)
      break;
  }
  if (cont > 1 || n < 2)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<primo>:
  endbr64
  mov    %edi,%esi
  shr    $0x1f,%esi
  add    %edi,%esi
  sar    %esi
  cmp    $0x1,%edi
  jle    L0
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  jmp    L28
  nopl   0x0(%rax)
L29:
  mov    $0x1,%r8d
L36:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L0
L28:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L36
  cmp    $0x1,%r8d
  jne    L29
  mov    %edx,%eax
  ret
  nop
L0:
  xor    %edx,%edx
  cmp    $0x1,%edi
  setg   %dl
  mov    %edx,%eax
  ret
```

assistant: ```c
int primo(int n) {
  int i, cont = 0;
  for (i = 1; i <= n / 2; i++) {
    if (n % i == 0)
      cont++;
    if (cont > 1)
      break;
  }
  if (cont > 1 || n < 2)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yp_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x5,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: 

assistant: ```c
int yp_match(const char *dom, const char *map, const char *key, int keylen, char **val, int *vallen) {
  *val = "";
  *vallen = 0;
  return 5;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<yp_match>:
  endbr64
  lea    D5(%rip),%rax
  mov    %rax,(%r8)
  movl   $0x0,(%r9)
  mov    $0x5,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: 

assistant: ```c
int yp_match(const char *dom, const char *map, const char *key, int keylen, char **val, int *vallen) {
  *val = "";
  *vallen = 0;
  return 5;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yp_match>:
  endbr64
  lea    D0(%rip),%rax
  mov    %rax,(%r8)
  mov    $0x5,%eax
  movl   $0x0,(%r9)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: 

assistant: ```c
int yp_match(const char *dom, const char *map, const char *key, int keylen, char **val, int *vallen) {
  *val = "";
  *vallen = 0;
  return 5;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yp_match>:
  endbr64
  lea    D3(%rip),%rax
  mov    %rax,(%r8)
  mov    $0x5,%eax
  movl   $0x0,(%r9)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: 

assistant: ```c
int yp_match(const char *dom, const char *map, const char *key, int keylen, char **val, int *vallen) {
  *val = "";
  *vallen = 0;
  return 5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<countsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%r8
  and    $0xfffffffffffffff0,%r8
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L86:
  cmp    %rdx,%rsp
  je     L50
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L86
L50:
  mov    %r8,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L36
  orq    $0x0,-0x8(%rsp,%rax,1)
L36:
  mov    %rsp,%r8
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  test   %esi,%esi
  jle    L39
  mov    %rdi,%r9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
L5:
  mov    (%r9),%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%eax
  movslq %eax,%rdx
  addl   $0x1,-0x30(%rbp,%rdx,4)
  add    $0x4,%r9
  cmp    %r10,%r9
  jne    L5
L39:
  lea    -0x2c(%rbp),%rax
  lea    -0x8(%rbp),%r9
L38:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L38
  mov    %esi,%r9d
  sub    $0x1,%r9d
  js     L72
  movslq %r9d,%r9
L46:
  mov    (%rdi,%r9,4),%r10d
  mov    %r10d,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp,%rdx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%r11
  mov    %r10d,(%r8,%r11,4)
  mov    %eax,-0x30(%rbp,%rdx,4)
  sub    $0x1,%r9
  test   %r9d,%r9d
  jns    L46
L72:
  test   %esi,%esi
  jle    L12
  mov    %esi,%esi
  mov    $0x0,%eax
L54:
  mov    (%r8,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L54
L12:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  leave
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void countsort(int arr[], int n, int exp) {
  int output[n];
  int i, count[10] = {};
  for (i = 0; i < n; i++) {
    count[(arr[i] / exp) % 10]++;
  }
  for (i = 1; i < 10; i++) {
    count[i] = count[i] + count[i - 1];
  }
  for (i = n - 1; i >= 0; i--) {
    output[count[(arr[i] / exp) % 10] - 1] = arr[i];
    count[(arr[i] / exp) % 10]--;
  }
  for (i = 0; i < n; i++) {
    arr[i] = output[i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<countsort>:
  endbr64
  push   %rbp
  movslq %esi,%r9
  mov    %edx,%ecx
  mov    %r9,%r8
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r9,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L75
L105:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L105
L75:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L62
L91:
  pxor   %xmm0,%xmm0
  movq   $0x0,-0x20(%rbp)
  mov    %rsp,%rsi
  movaps %xmm0,-0x40(%rbp)
  movaps %xmm0,-0x30(%rbp)
  test   %r8d,%r8d
  jle    L38
  lea    -0x1(%r8),%eax
  mov    %rdi,%r10
  mov    %rax,%rbx
  lea    0x4(%rdi,%rax,4),%r11
  nopl   0x0(%rax)
L63:
  mov    (%r10),%eax
  add    $0x4,%r10
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  mov    %eax,%r12d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r12d
  sar    $0x22,%rdx
  sub    %r12d,%edx
  lea    (%rdx,%rdx,4),%r12d
  add    %r12d,%r12d
  sub    %r12d,%eax
  movslq %eax,%rdx
  addl   $0x1,-0x40(%rbp,%rdx,4)
  cmp    %r10,%r11
  jne    L63
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%r10d
L86:
  lea    -0x3c(%rbp),%rax
  lea    -0x18(%rbp),%r11
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rax),%edx
  mov    -0x4(%rax),%r10d
L45:
  add    %r10d,%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %r11,%rax
  jne    L3
  movslq %ebx,%r10
  test   %ebx,%ebx
  js     L95
  nopl   0x0(%rax)
L35:
  mov    (%rdi,%r10,4),%r11d
  sub    $0x1,%r10
  mov    %r11d,%eax
  cltd
  idiv   %ecx
  movslq %eax,%rdx
  mov    %eax,%ebx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ebx
  sar    $0x22,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%ebx
  add    %ebx,%ebx
  sub    %ebx,%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp,%rdx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rbx
  mov    %eax,-0x40(%rbp,%rdx,4)
  mov    %r11d,(%rsi,%rbx,4)
  test   %r10d,%r10d
  jns    L35
L95:
  test   %r8d,%r8d
  jle    L124
  lea    0x0(,%r9,4),%rdx
  call   <memcpy@plt>
L124:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
  xchg   %ax,%ax
L62:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L91
L38:
  xor    %r10d,%r10d
  xor    %edx,%edx
  lea    -0x1(%r8),%ebx
  jmp    L86
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void countsort(int arr[], int n, int exp) {
  int output[n];
  int i, count[10] = {};
  for (i = 0; i < n; i++) {
    count[(arr[i] / exp) % 10]++;
  }
  for (i = 1; i < 10; i++) {
    count[i] = count[i] + count[i - 1];
  }
  for (i = n - 1; i >= 0; i--) {
    output[count[(arr[i] / exp) % 10] - 1] = arr[i];
    count[(arr[i] / exp) % 10]--;
  }
  for (i = 0; i < n; i++) {
    arr[i] = output[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__CCAPRICE_FDOLOCK@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__ccaprice_fseek@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__CCAPRICE_FUNLOCK@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fseek(FILE *fp, long off, int whence) {
  int r;
  __CCAPRICE_FDOLOCK(fp);
  r = __ccaprice_fseek(fp, off, whence);
  __CCAPRICE_FUNLOCK(fp);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fseek>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <__CCAPRICE_FDOLOCK@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__ccaprice_fseek@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <__CCAPRICE_FUNLOCK@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fseek(FILE *fp, long off, int whence) {
  int r;
  __CCAPRICE_FDOLOCK(fp);
  r = __ccaprice_fseek(fp, off, whence);
  __CCAPRICE_FUNLOCK(fp);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fseek>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <__CCAPRICE_FDOLOCK@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__ccaprice_fseek@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <__CCAPRICE_FUNLOCK@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fseek(FILE *fp, long off, int whence) {
  int r;
  __CCAPRICE_FDOLOCK(fp);
  r = __ccaprice_fseek(fp, off, whence);
  __CCAPRICE_FUNLOCK(fp);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fseek>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <__CCAPRICE_FDOLOCK@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__ccaprice_fseek@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <__CCAPRICE_FUNLOCK@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fseek(FILE *fp, long off, int whence) {
  int r;
  __CCAPRICE_FDOLOCK(fp);
  r = __ccaprice_fseek(fp, off, whence);
  __CCAPRICE_FUNLOCK(fp);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<proba_cond>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L4:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x14(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D25(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L4
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  -0x8(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type: f64

tool: D25: 1

assistant: ```c
double proba_cond(int *neighb_counts, double *weights, int *nodes, int rev_count) {
  int n, C;
  double p = 1;
  double notp = 1;
  for (int i = 0; i < rev_count; i++) {
    n = nodes[i];
    C = neighb_counts[n];
    p *= weights[n] / C;
    notp *= 1 - weights[n] / C;
  }
  return p / (p + notp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<proba_cond>:
  endbr64
  test   %ecx,%ecx
  jle    L29
  mov    %rdx,%rax
  lea    -0x1(%rcx),%ecx
  lea    0x4(%rdx,%rcx,4),%rcx
  movsd  D4(%rip),%xmm2
  movapd %xmm2,%xmm0
  movapd %xmm2,%xmm4
L13:
  movslq (%rax),%rdx
  pxor   %xmm3,%xmm3
  cvtsi2sdl (%rdi,%rdx,4),%xmm3
  movsd  (%rsi,%rdx,8),%xmm1
  divsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  movapd %xmm4,%xmm3
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
L5:
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm0
  ret
L29:
  movsd  D4(%rip),%xmm2
  movapd %xmm2,%xmm0
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: f64

tool: D4: 1

assistant: ```c
double proba_cond(int *neighb_counts, double *weights, int *nodes, int rev_count) {
  int n, C;
  double p = 1;
  double notp = 1;
  for (int i = 0; i < rev_count; i++) {
    n = nodes[i];
    C = neighb_counts[n];
    p *= weights[n] / C;
    notp *= 1 - weights[n] / C;
  }
  return p / (p + notp);
}
```