ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<solve>:
  endbr64
  push   %r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x1,0x10(%rsp)
  call   <calloc@plt>
  movq   $0x1,(%rax)
  mov    %rax,%rdi
  cmp    $0x1,%rbx
  jle    L3
  mov    $0x2,%r14d
  mov    $0x1,%r15d
  lea    0x10(%rsp),%rbp
  movabs $0x6666666666666667,%r12
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  jmp    L109
  nopw   0x0(%rax,%rax,1)
L116:
  lea    (%rdi,%r13,8),%rsi
  mov    (%rsi),%rcx
  imul   %r14,%rcx
  add    %rbx,%rcx
  mov    %rcx,%rax
  imul   %r12
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rdx,%rbx
  add    %rax,%rax
  sub    %rax,%rcx
  lea    0x1(%r13),%rax
  mov    %rcx,(%rsi)
  cmp    %r15,%rax
  jl     L25
  test   %rdx,%rdx
  je     L7
L25:
  mov    %rax,%r13
L109:
  cmp    %r13,0x10(%rsp)
  ja     L116
  mov    %rbp,%rsi
  call   <grow@plt>
  mov    %rax,%rdi
  jmp    L116
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%r14
  cmp    %r14,0x8(%rsp)
  jl     L21
  mov    %rax,%r15
  jmp    L43
L21:
  test   %r13,%r13
  je     L95
  mov    %rax,%rcx
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  shr    %rcx
  shl    $0x4,%rcx
  add    %rdi,%rcx
  nopl   0x0(%rax)
L35:
  movdqu (%rdx),%xmm2
  add    $0x10,%rdx
  paddq  %xmm2,%xmm0
  cmp    %rdx,%rcx
  jne    L35
  movdqa %xmm0,%xmm1
  mov    %rax,%rdx
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffffe,%rdx
  paddq  %xmm1,%xmm0
  movq   %xmm0,%r13
  test   $0x1,%al
  je     L3
L48:
  add    (%rdi,%rdx,8),%r13
L3:
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L129
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  xor    %edx,%edx
  jmp    L48
L129:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t solve(uint64_t n) {
  size_t nalloc = 1;
  uint8_t *digits = calloc(nalloc, sizeof(uint8_t));
  uint32_t nused = 1;
  digits[0] = 1;
  for (uint32_t x = 2; x <= n; ++x) {
    uint32_t carry = 0;
    uint32_t i = 0;
    for (i = 0; i < nused || carry; ++i) {
      if (i >= nalloc)
        digits = grow(digits, &nalloc);
      uint32_t value = carry + x * digits[i];
      digits[i] = value % 10;
      carry = value / 10;
    }
    nused = i;
  }
  uint64_t sum = 0;
  for (uint64_t i = 0; i < nused; ++i) {
    sum += digits[i];
  }
  free(digits);
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L7
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L7:
  mov    $0x0,%esi
  mov    $0xaf,%edi
  call   <_IO@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L15:
  mov    $0x0,%eax
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D23: /dev/logger

tool: D19: Open /dev/logger failed


tool: D17: Flush failed


assistant: ```c
int flush(void) {
  int fd_logger;
  int ret;
  fd_logger = open("/dev/logger", 0);
  if (fd_logger < 0) {
    printf("Open /dev/logger failed\n");
    return -1;
  }
  ret = ioctl(fd_logger, _IO(0XAF, 0));
  if (ret < 0) {
    printf("Flush failed\n");
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<flush>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <open@plt>
  test   %eax,%eax
  js     L10
  mov    %eax,%ebx
  mov    $0x0,%esi
  mov    $0xaf,%edi
  call   <_IO@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L29
  mov    $0x0,%eax
L11:
  pop    %rbx
  ret
L10:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L11
L29:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D25
type: string

tool: D0: /dev/logger

tool: D16: Open /dev/logger failed


tool: D25: Flush failed


assistant: ```c
int flush(void) {
  int fd_logger;
  int ret;
  fd_logger = open("/dev/logger", 0);
  if (fd_logger < 0) {
    printf("Open /dev/logger failed\n");
    return -1;
  }
  ret = ioctl(fd_logger, _IO(0XAF, 0));
  if (ret < 0) {
    printf("Flush failed\n");
    return -1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flush>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  lea    D17(%rip),%rdi
  call   <open@plt>
  test   %eax,%eax
  js     L18
  xor    %esi,%esi
  mov    $0xaf,%edi
  mov    %eax,%ebp
  call   <_IO@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L0
  xor    %eax,%eax
  pop    %rbp
  ret
L18:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L0:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type: string
name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D5
type: string

tool: D17: /dev/logger

tool: D20: Open /dev/logger failed


tool: D5: Flush failed


assistant: ```c
int flush(void) {
  int fd_logger;
  int ret;
  fd_logger = open("/dev/logger", 0);
  if (fd_logger < 0) {
    printf("Open /dev/logger failed\n");
    return -1;
  }
  ret = ioctl(fd_logger, _IO(0XAF, 0));
  if (ret < 0) {
    printf("Flush failed\n");
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<flush>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  call   <open@plt>
  test   %eax,%eax
  js     L0
  xor    %esi,%esi
  mov    $0xaf,%edi
  mov    %eax,%ebp
  call   <_IO@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L12
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L12:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D24
type: string

tool: D21: /dev/logger

tool: D17: Open /dev/logger failed


tool: D24: Flush failed


assistant: ```c
int flush(void) {
  int fd_logger;
  int ret;
  fd_logger = open("/dev/logger", 0);
  if (fd_logger < 0) {
    printf("Open /dev/logger failed\n");
    return -1;
  }
  ret = ioctl(fd_logger, _IO(0XAF, 0));
  if (ret < 0) {
    printf("Flush failed\n");
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__prefix_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %rax,-0x30(%rbp)
  cmpq   $0x1,-0x30(%rbp)
  jne    L45
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L45
  movq   $0x0,-0x30(%rbp)
L45:
  mov    $0x0,%ebx
  jmp    L25
L33:
  lea    0x0(,%rbx,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L0
  jmp    L61
L29:
  sub    $0x1,%rbx
  lea    0x0(,%rbx,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L61:
  test   %rbx,%rbx
  jne    L29
  mov    $0x1,%eax
  jmp    L1
L0:
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x2f,(%rax)
  lea    0x0(,%rbx,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  lea    0x0(,%rbx,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    0x0(,%rbx,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  add    $0x1,%rbx
L25:
  cmp    -0x48(%rbp),%rbx
  jb     L33
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __prefix_array(const char *dirname, char **array, size_t n) {
  register size_t i;
  size_t dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    size_t eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == NULL) {
      while (i > 0)
        free(array[--i]);
      return 1;
    }
    {
      char *endp = mempcpy(new, dirname, dirlen);
      *endp++ = '/';
      mempcpy(endp, array[i], eltlen);
    }
    free(array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r13
  mov    %rdx,%r14
  call   <strlen@plt>
  movslq %eax,%r15
  cmp    $0x1,%eax
  je     L42
L95:
  test   %r14,%r14
  je     L72
  mov    $0x0,%ebx
  lea    0x1(%r15),%rax
  mov    %rax,(%rsp)
L4:
  mov    0x0(%r13,%rbx,8),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  movslq %ebp,%rbp
  mov    (%rsp),%rax
  lea    (%rax,%rbp,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L85
  mov    %r15,%rdx
  mov    0x8(%rsp),%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  movb   $0x2f,(%rax)
  mov    0x0(%r13,%rbx,8),%rsi
  lea    0x1(%rax),%rdi
  mov    %rbp,%rdx
  call   <mempcpy@plt>
  mov    0x0(%r13,%rbx,8),%rdi
  call   <free@plt>
  mov    %r12,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L4
  mov    $0x0,%eax
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  mov    0x8(%rsp),%rax
  cmpb   $0x2f,(%rax)
  setne  %r15b
  movzbl %r15b,%r15d
  jmp    L95
L85:
  test   %rbx,%rbx
  je     L52
L79:
  sub    $0x1,%rbx
  mov    0x0(%r13,%rbx,8),%rdi
  call   <free@plt>
  test   %rbx,%rbx
  jne    L79
  mov    $0x1,%eax
  jmp    L46
L72:
  mov    $0x0,%eax
  jmp    L46
L52:
  mov    $0x1,%eax
  jmp    L46
```

assistant: ```c
int __prefix_array(const char *dirname, char **array, size_t n) {
  register size_t i;
  size_t dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    size_t eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == NULL) {
      while (i > 0)
        free(array[--i]);
      return 1;
    }
    {
      char *endp = mempcpy(new, dirname, dirlen);
      *endp++ = '/';
      mempcpy(endp, array[i], eltlen);
    }
    free(array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  call   <strlen@plt>
  movslq %eax,%r14
  cmp    $0x1,%eax
  jne    L35
  xor    %r14d,%r14d
  cmpb   $0x2f,0x0(%rbp)
  setne  %r14b
L35:
  lea    0x1(%r14),%rax
  xor    %r13d,%r13d
  cmpq   $0x0,(%rsp)
  mov    %rax,0x8(%rsp)
  jne    L54
  jmp    L41
  nopl   0x0(%rax)
L39:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %r12,%rdx
  movb   $0x2f,(%rax)
  mov    (%rbx,%r13,8),%rsi
  lea    0x1(%rax),%rdi
  call   <mempcpy@plt>
  mov    (%rbx,%r13,8),%rdi
  call   <free@plt>
  mov    %r15,(%rbx,%r13,8)
  add    $0x1,%r13
  cmp    %r13,(%rsp)
  je     L41
L54:
  mov    (%rbx,%r13,8),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    0x8(%rsp),%rax
  movslq %r12d,%r12
  lea    (%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L39
  jmp    L28
L13:
  sub    $0x1,%r13
  mov    (%rbx,%r13,8),%rdi
  call   <free@plt>
L28:
  test   %r13,%r13
  jne    L13
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __prefix_array(const char *dirname, char **array, size_t n) {
  register size_t i;
  size_t dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    size_t eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == NULL) {
      while (i > 0)
        free(array[--i]);
      return 1;
    }
    {
      char *endp = mempcpy(new, dirname, dirlen);
      *endp++ = '/';
      mempcpy(endp, array[i], eltlen);
    }
    free(array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  call   <strlen@plt>
  movslq %eax,%r14
  cmp    $0x1,%eax
  jne    L21
  xor    %r14d,%r14d
  cmpb   $0x2f,0x0(%rbp)
  setne  %r14b
L21:
  lea    0x1(%r14),%rax
  xor    %r13d,%r13d
  cmpq   $0x0,(%rsp)
  mov    %rax,0x8(%rsp)
  jne    L28
  jmp    L11
  nopl   0x0(%rax)
L37:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %r12,%rdx
  movb   $0x2f,(%rax)
  mov    (%rbx,%r13,8),%rsi
  lea    0x1(%rax),%rdi
  call   <mempcpy@plt>
  mov    (%rbx,%r13,8),%rdi
  call   <free@plt>
  mov    %r15,(%rbx,%r13,8)
  add    $0x1,%r13
  cmp    %r13,(%rsp)
  je     L11
L28:
  mov    (%rbx,%r13,8),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    0x8(%rsp),%rax
  movslq %r12d,%r12
  lea    (%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L37
  jmp    L44
L61:
  sub    $0x1,%r13
  mov    (%rbx,%r13,8),%rdi
  call   <free@plt>
L44:
  test   %r13,%r13
  jne    L61
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int __prefix_array(const char *dirname, char **array, size_t n) {
  register size_t i;
  size_t dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    size_t eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == NULL) {
      while (i > 0)
        free(array[--i]);
      return 1;
    }
    {
      char *endp = mempcpy(new, dirname, dirlen);
      *endp++ = '/';
      mempcpy(endp, array[i], eltlen);
    }
    free(array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <worker@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %lx


assistant: ```c
int main() {
  uint64_t out;
  out = worker();
  printf("%lx\n", out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <worker@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: %lx


assistant: ```c
int main() {
  uint64_t out;
  out = worker();
  printf("%lx\n", out);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <worker@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %lx


assistant: ```c
int main() {
  uint64_t out;
  out = worker();
  printf("%lx\n", out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <worker@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: %lx


assistant: ```c
int main() {
  uint64_t out;
  out = worker();
  printf("%lx\n", out);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x7c(%rbp),%edx
  mov    -0x78(%rbp),%rcx
  lea    -0x70(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <error@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void nerror(char *fmt, int n) {
  char buf[100];
  sprintf(buf, fmt, n);
  error(buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nerror>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <error@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nerror(char *fmt, int n) {
  char buf[100];
  sprintf(buf, fmt, n);
  error(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nerror>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <error@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x70,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nerror(char *fmt, int n) {
  char buf[100];
  sprintf(buf, fmt, n);
  error(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nerror>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rdi,%rsi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <error@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x70,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void nerror(char *fmt, int n) {
  char buf[100];
  sprintf(buf, fmt, n);
  error(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  mov    %rax,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rcx
  lea    -0xe0(%rbp),%rdx
  mov    -0xe8(%rbp),%rax
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  lea    -0x70(%rbp),%rcx
  lea    -0xe0(%rbp),%rdx
  mov    -0xe8(%rbp),%rax
  lea    D42(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D48
type: string
name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D40
type: string

tool: D48: 2006:03:18 -2006:04:18

tool: D19: %[0-9,:] - %[0-9,:]

tool: D42: %[0-9,:]-%[0-9,:]

tool: D40: %s


assistant: ```c
int main() {
  char *p_time = "2006:03:18 -2006:04:18";
  char sz_time1[100] = {0};
  char sz_time2[100] = {0};
  sscanf(p_time, "%[0-9,:] - %[0-9,:]", sz_time1, sz_time2);
  sscanf(p_time, "%[0-9,:]-%[0-9,:]", sz_time1, sz_time2);
  printf("%s\n", sz_time1);
  printf("%s\n", sz_time2);
  return 0;
}
```