ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<processString>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  cmp    $0x80,%eax
  jg     L30
  test   %eax,%eax
  jle    L65
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rdx
  jmp    L36
  nopl   0x0(%rax)
L57:
  add    $0x1,%rdi
  movl   $0x1,(%rsp,%rax,4)
  cmp    %rdx,%rdi
  je     L65
L36:
  movsbq (%rdi),%rax
  mov    (%rsp,%rax,4),%r12d
  cmp    $0x1,%r12d
  jne    L57
  lea    D19(%rip),%rdi
  call   <printf@plt>
L51:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x218,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L65:
  xor    %r12d,%r12d
  jmp    L51
  nopl   (%rax)
L30:
  lea    D8(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
  jmp    L51
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D19: 
Duplicate!!


tool: D8: 
ERROR : duplicate characters present


assistant: ```c
int processString(char *string) {
  int length = strlen(string);
  int i = 0, position = 0;
  int flags[128];
  if (128 < length) {
    printf("\nERROR : duplicate characters present\n");
    return 1;
  }
  for (i = 0; i < length; i++) {
    position = string[i];
    if (flags[position] == 1) {
      printf("\nDuplicate!!\n");
      return 1;
    }
    flags[position] = 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<store>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <putmem@plt>
  jmp    L9
L2:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <putstk@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
store(lval) int *lval;
{
  if (lval[1] == 0)
    putmem(lval[0]);
  else
    putstk(lval[1]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<store>:
  endbr64
  sub    $0x8,%rsp
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  jne    L2
  mov    (%rdi),%edi
  call   <putmem@plt>
L17:
  add    $0x8,%rsp
  ret
L2:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <putstk@plt>
  jmp    L17
```

assistant: ```c
store(lval) int *lval;
{
  if (lval[1] == 0)
    putmem(lval[0]);
  else
    putstk(lval[1]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<store>:
  endbr64
  mov    0x4(%rdi),%r8d
  test   %r8d,%r8d
  jne    L4
  mov    (%rdi),%edi
  xor    %eax,%eax
  jmp    1070 <putmem@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r8d,%edi
  xor    %eax,%eax
  jmp    1060 <putstk@plt>
```

assistant: ```c
store(lval) int *lval;
{
  if (lval[1] == 0)
    putmem(lval[0]);
  else
    putstk(lval[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store>:
  endbr64
  mov    0x4(%rdi),%r8d
  test   %r8d,%r8d
  jne    L9
  mov    (%rdi),%edi
  xor    %eax,%eax
  jmp    1070 <putmem@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %r8d,%edi
  xor    %eax,%eax
  jmp    1060 <putstk@plt>
```

assistant: ```c
store(lval) int *lval;
{
  if (lval[1] == 0)
    putmem(lval[0]);
  else
    putstk(lval[1]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utf16_to_utf8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x1(%rsi,%rsi,2),%rsi
  shr    %rsi
  add    $0x1,%rsi
  mov    $0x1,%edi
  call   <malloc_multiply@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rdi
  lea    (%rbx,%rbp,4),%rsi
  cmp    %rsi,%rbx
  jae    L103
  mov    %rax,%rdx
  jmp    L80
L77:
  movl   $0x0,(%rdx)
  jmp    L43
L16:
  cmp    $0x7ff,%eax
  jg     L21
  mov    %eax,%ecx
  sar    $0x6,%ecx
  or     $0xc0,%cl
  mov    %ecx,(%rdx)
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,0x4(%rdx)
  lea    0x8(%rdx),%rdx
L60:
  add    $0x8,%rbx
  cmp    %rsi,%rbx
  jae    L68
L80:
  mov    0x4(%rbx),%eax
  shl    $0x8,%eax
  or     (%rbx),%eax
  je     L77
  cmp    $0x7f,%eax
  jg     L16
  mov    %eax,(%rdx)
  lea    0x4(%rdx),%rdx
  jmp    L60
L21:
  mov    %eax,%ecx
  sar    $0xc,%ecx
  or     $0xe0,%cl
  mov    %ecx,(%rdx)
  mov    %eax,%ecx
  sar    $0x6,%ecx
  and    $0x3f,%ecx
  or     $0x80,%cl
  mov    %ecx,0x4(%rdx)
  and    $0x3f,%eax
  or     $0x80,%al
  mov    %eax,0x8(%rdx)
  lea    0xc(%rdx),%rdx
  jmp    L60
L103:
  mov    %rax,%rdx
L68:
  movl   $0x0,(%rdx)
L43:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    $0x0,%edi
  jmp    L43
```

assistant: ```c
char *utf16_to_utf8(const void *s, size_t length) {
  char *r;
  const uint8_t *f;
  uint8_t *t;
  r = ((char *)malloc_multiply(sizeof(char), ((length * 3 + 1) / 2 + 1)));
  if (!r)
    return NULL;
  t = (uint8_t *)r;
  for (f = s; f < (const uint8_t *)s + length; f += 2) {
    uint16_t c;
    c = (f[1] << 8) | f[0];
    if (c == 0) {
      *t = 0;
      return r;
    } else if (c < 0x80) {
      *(t++) = (uint8_t)c;
    } else if (c < 0x800) {
      *(t++) = (uint8_t)(0xc0 | (c >> 6));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    } else {
      *(t++) = (uint8_t)(0xe0 | (c >> 12));
      *(t++) = (uint8_t)(0x80 | ((c >> 6) & 0x3f));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    }
  }
  *t = 0;
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf16_to_utf8>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rsi,%rsi,2),%rsi
  push   %rbx
  shr    %rsi
  mov    %rdi,%rbx
  mov    $0x1,%edi
  add    $0x1,%rsi
  sub    $0x8,%rsp
  call   <malloc_multiply@plt>
  test   %rax,%rax
  je     L82
  lea    (%rbx,%rbp,4),%r8
  mov    %rax,%rcx
  cmp    %r8,%rbx
  jb     L50
  jmp    L14
  nopl   0x0(%rax)
L39:
  mov    %edx,(%rcx)
  add    $0x4,%rcx
L67:
  add    $0x8,%rbx
  cmp    %r8,%rbx
  jae    L14
L50:
  mov    0x4(%rbx),%edx
  shl    $0x8,%edx
  or     (%rbx),%edx
  je     L14
  cmp    $0x7f,%edx
  jle    L39
  mov    %edx,%edi
  mov    %edx,%esi
  and    $0x3f,%edi
  sar    $0x6,%esi
  or     $0x80,%dil
  cmp    $0x7ff,%edx
  jg     L34
  or     $0xc0,%sil
  add    $0x8,%rbx
  mov    %edi,0x4(%rcx)
  add    $0x8,%rcx
  mov    %esi,-0x8(%rcx)
  cmp    %r8,%rbx
  jb     L50
  nopl   0x0(%rax,%rax,1)
L14:
  movl   $0x0,(%rcx)
L82:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L34:
  sar    $0xc,%edx
  and    $0x3f,%esi
  mov    %edi,0x8(%rcx)
  add    $0xc,%rcx
  or     $0xe0,%dl
  or     $0x80,%sil
  mov    %edx,-0xc(%rcx)
  mov    %esi,-0x8(%rcx)
  jmp    L67
```

assistant: ```c
char *utf16_to_utf8(const void *s, size_t length) {
  char *r;
  const uint8_t *f;
  uint8_t *t;
  r = ((char *)malloc_multiply(sizeof(char), ((length * 3 + 1) / 2 + 1)));
  if (!r)
    return NULL;
  t = (uint8_t *)r;
  for (f = s; f < (const uint8_t *)s + length; f += 2) {
    uint16_t c;
    c = (f[1] << 8) | f[0];
    if (c == 0) {
      *t = 0;
      return r;
    } else if (c < 0x80) {
      *(t++) = (uint8_t)c;
    } else if (c < 0x800) {
      *(t++) = (uint8_t)(0xc0 | (c >> 6));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    } else {
      *(t++) = (uint8_t)(0xe0 | (c >> 12));
      *(t++) = (uint8_t)(0x80 | ((c >> 6) & 0x3f));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    }
  }
  *t = 0;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utf16_to_utf8>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    0x1(%rsi,%rsi,2),%rsi
  push   %rbx
  shr    %rsi
  mov    %rdi,%rbx
  mov    $0x1,%edi
  add    $0x1,%rsi
  sub    $0x8,%rsp
  call   <malloc_multiply@plt>
  test   %rax,%rax
  je     L8
  lea    (%rbx,%rbp,4),%r8
  mov    %rax,%rcx
  cmp    %r8,%rbx
  jb     L33
  jmp    L77
  nopl   0x0(%rax)
L29:
  mov    %edx,(%rcx)
  add    $0x4,%rcx
L36:
  add    $0x8,%rbx
  cmp    %r8,%rbx
  jae    L77
L33:
  mov    0x4(%rbx),%edx
  shl    $0x8,%edx
  or     (%rbx),%edx
  je     L77
  cmp    $0x7f,%edx
  jle    L29
  mov    %edx,%edi
  mov    %edx,%esi
  and    $0x3f,%edi
  sar    $0x6,%esi
  or     $0x80,%dil
  cmp    $0x7ff,%edx
  jg     L1
  or     $0xc0,%sil
  add    $0x8,%rbx
  mov    %edi,0x4(%rcx)
  add    $0x8,%rcx
  mov    %esi,-0x8(%rcx)
  cmp    %r8,%rbx
  jb     L33
  nopl   0x0(%rax,%rax,1)
L77:
  movl   $0x0,(%rcx)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L1:
  sar    $0xc,%edx
  and    $0x3f,%esi
  mov    %edi,0x8(%rcx)
  add    $0xc,%rcx
  or     $0xe0,%dl
  or     $0x80,%sil
  mov    %edx,-0xc(%rcx)
  mov    %esi,-0x8(%rcx)
  jmp    L36
```

assistant: ```c
char *utf16_to_utf8(const void *s, size_t length) {
  char *r;
  const uint8_t *f;
  uint8_t *t;
  r = ((char *)malloc_multiply(sizeof(char), ((length * 3 + 1) / 2 + 1)));
  if (!r)
    return NULL;
  t = (uint8_t *)r;
  for (f = s; f < (const uint8_t *)s + length; f += 2) {
    uint16_t c;
    c = (f[1] << 8) | f[0];
    if (c == 0) {
      *t = 0;
      return r;
    } else if (c < 0x80) {
      *(t++) = (uint8_t)c;
    } else if (c < 0x800) {
      *(t++) = (uint8_t)(0xc0 | (c >> 6));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    } else {
      *(t++) = (uint8_t)(0xe0 | (c >> 12));
      *(t++) = (uint8_t)(0x80 | ((c >> 6) & 0x3f));
      *(t++) = (uint8_t)(0x80 | (c & 0x3f));
    }
  }
  *t = 0;
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_results>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <convert_time_to_sec@plt>
  movq   %xmm0,%rbx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <convert_time_to_sec@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_global_header@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L39
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_header@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L43
L15:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <is_supported_domain@plt>
  test   %rax,%rax
  je     L31
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,8),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_value@plt>
L31:
  addl   $0x1,-0x1c(%rbp)
L43:
  cmpl   $0x4,-0x1c(%rbp)
  jle    L15
  addl   $0x1,-0x20(%rbp)
L39:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void print_results(int num_node, double cum_energy_J[num_node][5], struct timeval measurement_start_time, struct timeval measurement_end_time) {
  const double duration = convert_time_to_sec(measurement_end_time) - convert_time_to_sec(measurement_start_time);
  print_global_header(num_node, duration);
  for (int i = 0; i < num_node; i++) {
    print_header(i, duration);
    for (int domain = 0; domain < 5; ++domain) {
      if (is_supported_domain(domain)) {
        print_value(i, domain, cum_energy_J[i][domain]);
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_results>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %ecx,%edi
  call   <convert_time_to_sec@plt>
  movq   %xmm0,%rbx
  mov    %ebp,%edi
  call   <convert_time_to_sec@plt>
  movq   %rbx,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm0
  mov    %r15d,%edi
  call   <print_global_header@plt>
  test   %r15d,%r15d
  jle    L53
  mov    $0x0,%r12d
  jmp    L62
L69:
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  je     L4
L66:
  mov    %ebx,%edi
  call   <is_supported_domain@plt>
  test   %rax,%rax
  je     L69
  movsd  (%r14,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <print_value@plt>
  jmp    L69
L4:
  add    $0x1,%r12d
  add    $0x28,%r13
  cmp    %r12d,%r15d
  je     L53
L62:
  movsd  0x8(%rsp),%xmm0
  mov    %r12d,%edi
  call   <print_header@plt>
  mov    %r13,%r14
  mov    $0x0,%ebx
  jmp    L66
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void print_results(int num_node, double cum_energy_J[num_node][5], struct timeval measurement_start_time, struct timeval measurement_end_time) {
  const double duration = convert_time_to_sec(measurement_end_time) - convert_time_to_sec(measurement_start_time);
  print_global_header(num_node, duration);
  for (int i = 0; i < num_node; i++) {
    print_header(i, duration);
    for (int domain = 0; domain < 5; ++domain) {
      if (is_supported_domain(domain)) {
        print_value(i, domain, cum_energy_J[i][domain]);
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_results>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <convert_time_to_sec@plt>
  mov    %ebp,%edi
  movq   %xmm0,%rbx
  call   <convert_time_to_sec@plt>
  movq   %rbx,%xmm1
  mov    %r14d,%edi
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  movq   %xmm1,%r15
  call   <print_global_header@plt>
  test   %r14d,%r14d
  jle    L44
  xor    %r12d,%r12d
  nop
L49:
  movq   %r15,%xmm0
  mov    %r12d,%edi
  xor    %ebx,%ebx
  call   <print_header@plt>
L27:
  mov    %ebx,%edi
  call   <is_supported_domain@plt>
  test   %rax,%rax
  jne    L12
L11:
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L27
  add    $0x1,%r12d
  add    $0x28,%r13
  cmp    %r12d,%r14d
  jne    L49
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L12:
  movsd  0x0(%r13,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <print_value@plt>
  jmp    L11
```

assistant: ```c
void print_results(int num_node, double cum_energy_J[num_node][5], struct timeval measurement_start_time, struct timeval measurement_end_time) {
  const double duration = convert_time_to_sec(measurement_end_time) - convert_time_to_sec(measurement_start_time);
  print_global_header(num_node, duration);
  for (int i = 0; i < num_node; i++) {
    print_header(i, duration);
    for (int domain = 0; domain < 5; ++domain) {
      if (is_supported_domain(domain)) {
        print_value(i, domain, cum_energy_J[i][domain]);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_results>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <convert_time_to_sec@plt>
  mov    %ebp,%edi
  movq   %xmm0,%rbx
  call   <convert_time_to_sec@plt>
  movq   %rbx,%xmm1
  mov    %r14d,%edi
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  movq   %xmm1,%r15
  call   <print_global_header@plt>
  test   %r14d,%r14d
  jle    L45
  xor    %r12d,%r12d
  nop
L18:
  movq   %r15,%xmm0
  mov    %r12d,%edi
  xor    %ebx,%ebx
  call   <print_header@plt>
L1:
  mov    %ebx,%edi
  call   <is_supported_domain@plt>
  test   %rax,%rax
  jne    L20
L4:
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L1
  add    $0x1,%r12d
  add    $0x28,%r13
  cmp    %r12d,%r14d
  jne    L18
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  movsd  0x0(%r13,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <print_value@plt>
  jmp    L4
```

assistant: ```c
void print_results(int num_node, double cum_energy_J[num_node][5], struct timeval measurement_start_time, struct timeval measurement_end_time) {
  const double duration = convert_time_to_sec(measurement_end_time) - convert_time_to_sec(measurement_start_time);
  print_global_header(num_node, duration);
  for (int i = 0; i < num_node; i++) {
    print_header(i, duration);
    for (int domain = 0; domain < 5; ++domain) {
      if (is_supported_domain(domain)) {
        print_value(i, domain, cum_energy_J[i][domain]);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  cmpq   $0x0,-0x10(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L16
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L16
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x1,%eax
  jmp    L59
L16:
  mov    $0x0,%eax
L59:
  leave
  ret
```

assistant: ```c
int check_command(const char *command, const char *rec_msg) {
  if (command != NULL && rec_msg != NULL && strlen(command) > 0 && strlen(rec_msg) > 0)
    if (strcmp(command, rec_msg) == 0)
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_command>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L14
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L14
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jg     L7
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L14
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int check_command(const char *command, const char *rec_msg) {
  if (command != NULL && rec_msg != NULL && strlen(command) > 0 && strlen(rec_msg) > 0)
    if (strcmp(command, rec_msg) == 0)
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_command>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L46
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L46
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  call   <strlen@plt>
  test   %rax,%rax
  je     L37
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L37
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %r13b
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %r13d,%r13d
L37:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int check_command(const char *command, const char *rec_msg) {
  if (command != NULL && rec_msg != NULL && strlen(command) > 0 && strlen(rec_msg) > 0)
    if (strcmp(command, rec_msg) == 0)
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_command>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L22
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L22
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %r13b
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %r13d,%r13d
L6:
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int check_command(const char *command, const char *rec_msg) {
  if (command != NULL && rec_msg != NULL && strlen(command) > 0 && strlen(rec_msg) > 0)
    if (strcmp(command, rec_msg) == 0)
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_isdigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L10
  cmpl   $0x39,-0x4(%rbp)
  jg     L10
  mov    -0x4(%rbp),%eax
  jmp    L25
L10:
  mov    $0xffffffff,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c > 47 && c < 58)
    return ((int)c);
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_isdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  mov    $0xffffffff,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c > 47 && c < 58)
    return ((int)c);
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  mov    $0xffffffff,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c > 47 && c < 58)
    return ((int)c);
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_isdigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  mov    $0xffffffff,%eax
  cmovbe %edi,%eax
  ret
```

assistant: ```c
int ft_isdigit(int c) {
  if (c > 47 && c < 58)
    return ((int)c);
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<goesIntoNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L17:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L17
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
int goesIntoNum(int large, int small, int offset) {
  int i;
  for (i = 0; i + small + offset <= large; i += small)
    ;
  return i / small;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<goesIntoNum>:
  endbr64
  mov    $0x0,%ecx
L4:
  mov    %ecx,%eax
  add    %esi,%ecx
  lea    (%rcx,%rdx,1),%r8d
  cmp    %r8d,%edi
  jge    L4
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int goesIntoNum(int large, int small, int offset) {
  int i;
  for (i = 0; i + small + offset <= large; i += small)
    ;
  return i / small;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<goesIntoNum>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ecx,%eax
  add    %esi,%ecx
  lea    (%rcx,%rdx,1),%r8d
  cmp    %r8d,%edi
  jge    L5
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int goesIntoNum(int large, int small, int offset) {
  int i;
  for (i = 0; i + small + offset <= large; i += small)
    ;
  return i / small;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<goesIntoNum>:
  endbr64
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ecx,%eax
  add    %esi,%ecx
  lea    (%rcx,%rdx,1),%r8d
  cmp    %r8d,%edi
  jge    L1
  cltd
  idiv   %esi
  ret
```

assistant: ```c
int goesIntoNum(int large, int small, int offset) {
  int i;
  for (i = 0; i + small + offset <= large; i += small)
    ;
  return i / small;
}
```