ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mpd_sanitizeArg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L13:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L19
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L41
L19:
  addl   $0x1,-0x14(%rbp)
L41:
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rax,-0x10(%rbp)
  jb     L13
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x14(%rbp),%edx
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L3
L78:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L49
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L62
L49:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5c,(%rax)
  addl   $0x1,-0x14(%rbp)
L62:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jb     L78
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mpd_sanitizeArg(const char *arg) {
  size_t i;
  int count = 0;
  char *ret;
  for (i = 0; i < strlen(arg); i++) {
    if (arg[i] == '"' || arg[i] == '\\')
      count++;
  }
  ret = malloc(strlen(arg) + count + 1);
  count = 0;
  for (i = 0; i < strlen(arg) + 1; i++) {
    if (arg[i] == '"' || arg[i] == '\\') {
      ret[i + count] = '\\';
      count++;
    }
    ret[i + count] = arg[i];
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mpd_sanitizeArg>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L72
L24:
  add    $0x1,%r12d
L92:
  add    $0x1,%rbx
L72:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rbx,%rax
  jbe    L76
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x22,%al
  je     L24
  cmp    $0x5c,%al
  jne    L92
  jmp    L24
L76:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L65
L98:
  movslq %r12d,%rax
  lea    0x0(%r13,%rbx,1),%rdx
  movb   $0x5c,(%rdx,%rax,1)
  add    $0x1,%r12d
L17:
  movzbl 0x0(%rbp,%rbx,1),%ecx
  movslq %r12d,%rax
  lea    0x0(%r13,%rbx,1),%rdx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rbx
L65:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  jbe    L10
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x22,%al
  je     L98
  cmp    $0x5c,%al
  jne    L17
  jmp    L98
L10:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mpd_sanitizeArg(const char *arg) {
  size_t i;
  int count = 0;
  char *ret;
  for (i = 0; i < strlen(arg); i++) {
    if (arg[i] == '"' || arg[i] == '\\')
      count++;
  }
  ret = malloc(strlen(arg) + count + 1);
  count = 0;
  for (i = 0; i < strlen(arg) + 1; i++) {
    if (arg[i] == '"' || arg[i] == '\\') {
      ret[i + count] = '\\';
      count++;
    }
    ret[i + count] = arg[i];
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mpd_sanitizeArg>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L70:
  add    $0x1,%rbx
L30:
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rbx,%rax
  jbe    L6
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x22,%al
  je     L25
  cmp    $0x5c,%al
  jne    L70
L25:
  add    $0x1,%ebp
  jmp    L70
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %r13,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%edi
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L78:
  movslq %ebp,%rcx
  add    $0x1,%rbx
  mov    %al,(%rdx,%rcx,1)
L83:
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  jbe    L44
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x22,%al
  je     L90
  lea    (%r12,%rbx,1),%rdx
  cmp    $0x5c,%al
  jne    L78
L90:
  movslq %ebp,%rax
  lea    (%r12,%rbx,1),%rdx
  add    $0x1,%ebp
  movb   $0x5c,(%rdx,%rax,1)
  movzbl 0x0(%r13,%rbx,1),%eax
  jmp    L78
  nopl   0x0(%rax)
L44:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mpd_sanitizeArg(const char *arg) {
  size_t i;
  int count = 0;
  char *ret;
  for (i = 0; i < strlen(arg); i++) {
    if (arg[i] == '"' || arg[i] == '\\')
      count++;
  }
  ret = malloc(strlen(arg) + count + 1);
  count = 0;
  for (i = 0; i < strlen(arg) + 1; i++) {
    if (arg[i] == '"' || arg[i] == '\\') {
      ret[i + count] = '\\';
      count++;
    }
    ret[i + count] = arg[i];
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mpd_sanitizeArg>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L65:
  add    $0x1,%rbx
L85:
  mov    %r13,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rbx,%rax
  jbe    L69
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x22,%al
  je     L84
  cmp    $0x5c,%al
  jne    L65
L84:
  add    $0x1,%ebp
  jmp    L65
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r13,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%edi
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L28:
  movslq %ebp,%rcx
  add    $0x1,%rbx
  mov    %al,(%rdx,%rcx,1)
L35:
  mov    %r13,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  cmp    %rbx,%rax
  jbe    L61
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x22,%al
  je     L4
  lea    (%r12,%rbx,1),%rdx
  cmp    $0x5c,%al
  jne    L28
L4:
  movslq %ebp,%rax
  lea    (%r12,%rbx,1),%rdx
  add    $0x1,%ebp
  movb   $0x5c,(%rdx,%rax,1)
  movzbl 0x0(%r13,%rbx,1),%eax
  jmp    L28
  nopl   0x0(%rax)
L61:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mpd_sanitizeArg(const char *arg) {
  size_t i;
  int count = 0;
  char *ret;
  for (i = 0; i < strlen(arg); i++) {
    if (arg[i] == '"' || arg[i] == '\\')
      count++;
  }
  ret = malloc(strlen(arg) + count + 1);
  count = 0;
  for (i = 0; i < strlen(arg) + 1; i++) {
    if (arg[i] == '"' || arg[i] == '\\') {
      ret[i + count] = '\\';
      count++;
    }
    ret[i + count] = arg[i];
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitmap_fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L26
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bitmap_zero@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_first_bit@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L5
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <set_bit@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_next_bit@plt>
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L3
  jmp    L20
L26:
  nop
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: oldbit = %d


assistant: ```c
void bitmap_fold(unsigned long *dst, const unsigned long *orig, int sz, int bits) {
  int oldbit;
  if (dst == orig)
    return;
  bitmap_zero(dst, bits);
  for ((oldbit) = find_first_bit((orig), (bits)); (oldbit) < (bits); (oldbit) = find_next_bit((orig), (bits), (oldbit) + 1)) {
    printf("oldbit = %d\n", oldbit);
    set_bit(oldbit % sz, dst);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_fold>:
  endbr64
  cmp    %rsi,%rdi
  je     L19
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    %ecx,%esi
  call   <bitmap_zero@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <find_first_bit@plt>
  mov    %eax,%ebx
  cmp    %eax,%ebp
  jle    L3
  lea    D6(%rip),%r15
L15:
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %r12d
  mov    %edx,%edi
  mov    %r13,%rsi
  call   <set_bit@plt>
  lea    0x1(%rbx),%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <find_next_bit@plt>
  mov    %eax,%ebx
  cmp    %eax,%ebp
  jg     L15
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: oldbit = %d


assistant: ```c
void bitmap_fold(unsigned long *dst, const unsigned long *orig, int sz, int bits) {
  int oldbit;
  if (dst == orig)
    return;
  bitmap_zero(dst, bits);
  for ((oldbit) = find_first_bit((orig), (bits)); (oldbit) < (bits); (oldbit) = find_next_bit((orig), (bits), (oldbit) + 1)) {
    printf("oldbit = %d\n", oldbit);
    set_bit(oldbit % sz, dst);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_fold>:
  endbr64
  cmp    %rsi,%rdi
  je     L5
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    %ecx,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <bitmap_zero@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <find_first_bit@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jle    L12
  lea    D3(%rip),%r15
L13:
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  mov    %r13,%rsi
  cltd
  idiv   %ebp
  mov    %edx,%edi
  call   <set_bit@plt>
  lea    0x1(%r12),%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <find_next_bit@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jg     L13
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: oldbit = %d


assistant: ```c
void bitmap_fold(unsigned long *dst, const unsigned long *orig, int sz, int bits) {
  int oldbit;
  if (dst == orig)
    return;
  bitmap_zero(dst, bits);
  for ((oldbit) = find_first_bit((orig), (bits)); (oldbit) < (bits); (oldbit) = find_next_bit((orig), (bits), (oldbit) + 1)) {
    printf("oldbit = %d\n", oldbit);
    set_bit(oldbit % sz, dst);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bitmap_fold>:
  endbr64
  cmp    %rsi,%rdi
  je     L23
  push   %r15
  push   %r14
  mov    %rsi,%r14
  mov    %ecx,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  call   <bitmap_zero@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <find_first_bit@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jle    L12
  lea    D5(%rip),%r15
L19:
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  mov    %r13,%rsi
  cltd
  idiv   %ebp
  mov    %edx,%edi
  call   <set_bit@plt>
  lea    0x1(%r12),%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <find_next_bit@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  jg     L19
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: oldbit = %d


assistant: ```c
void bitmap_fold(unsigned long *dst, const unsigned long *orig, int sz, int bits) {
  int oldbit;
  if (dst == orig)
    return;
  bitmap_zero(dst, bits);
  for ((oldbit) = find_first_bit((orig), (bits)); (oldbit) < (bits); (oldbit) = find_next_bit((orig), (bits), (oldbit) + 1)) {
    printf("oldbit = %d\n", oldbit);
    set_bit(oldbit % sz, dst);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pow_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L9:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L27
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mul_mod@plt>
  mov    %eax,-0x4(%rbp)
L27:
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mul_mod@plt>
  mov    %eax,-0x14(%rbp)
  sarl   -0x18(%rbp)
L8:
  cmpl   $0x0,-0x18(%rbp)
  jg     L9
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t pow_mod(uint64_t b, uint64_t power, uint64_t modulus) {
  uint64_t x = 1;
  while (power > 0) {
    if ((power & 1) == 1) {
      x = mul_mod(x, b, modulus);
    }
    b = mul_mod(b, b, modulus);
    power = power >> 1;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pow_mod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L3
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    $0x1,%r13d
  jmp    L47
L35:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mul_mod@plt>
  mov    %eax,%ebx
  sar    %ebp
  test   %ebp,%ebp
  jle    L12
L47:
  test   $0x1,%bpl
  je     L35
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <mul_mod@plt>
  mov    %eax,%r13d
  jmp    L35
L3:
  mov    $0x1,%r13d
L12:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t pow_mod(uint64_t b, uint64_t power, uint64_t modulus) {
  uint64_t x = 1;
  while (power > 0) {
    if ((power & 1) == 1) {
      x = mul_mod(x, b, modulus);
    }
    b = mul_mod(b, b, modulus);
    power = power >> 1;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pow_mod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L22
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x1,%r13d
  jmp    L11
  nopl   0x0(%rax)
L20:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <mul_mod@plt>
  sar    %ebx
  mov    %eax,%ebp
  je     L36
L11:
  test   $0x1,%bl
  je     L20
  mov    %r13d,%edi
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <mul_mod@plt>
  mov    %eax,%r13d
  jmp    L20
  nopl   0x0(%rax)
L22:
  mov    $0x1,%r13d
L36:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t pow_mod(uint64_t b, uint64_t power, uint64_t modulus) {
  uint64_t x = 1;
  while (power > 0) {
    if ((power & 1) == 1) {
      x = mul_mod(x, b, modulus);
    }
    b = mul_mod(b, b, modulus);
    power = power >> 1;
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pow_mod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L3
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x1,%r13d
  jmp    L44
  nopl   0x0(%rax)
L7:
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %r12d,%edx
  call   <mul_mod@plt>
  sar    %ebx
  mov    %eax,%ebp
  je     L2
L44:
  test   $0x1,%bl
  je     L7
  mov    %r13d,%edi
  mov    %r12d,%edx
  mov    %ebp,%esi
  call   <mul_mod@plt>
  mov    %eax,%r13d
  jmp    L7
  nopl   0x0(%rax)
L3:
  mov    $0x1,%r13d
L2:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t pow_mod(uint64_t b, uint64_t power, uint64_t modulus) {
  uint64_t x = 1;
  while (power > 0) {
    if ((power & 1) == 1) {
      x = mul_mod(x, b, modulus);
    }
    b = mul_mod(b, b, modulus);
    power = power >> 1;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L72
L49:
  cmpl   $0x20,-0x4(%rbp)
  je     L46
  cmpl   $0x9,-0x4(%rbp)
  je     L46
  cmpl   $0xa,-0x4(%rbp)
  jne    L43
L46:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L68
L43:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    $0x2a,%edi
  call   <putchar@plt>
L68:
  cmpl   $0x1,-0xc(%rbp)
  jne    L72
  cmpl   $0x0,-0x8(%rbp)
  jne    L72
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
L72:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L49
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int c, prevstate, state;
  prevstate = state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\t' || c == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      putchar('*');
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      putchar('\n');
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebp
L32:
  mov    $0x0,%ebx
  jmp    L35
L33:
  cmp    $0x20,%eax
  jne    L68
L17:
  cmp    $0x1,%ebx
  je     L31
L35:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D2(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L26
  cmp    $0xa,%eax
  jg     L33
  cmp    $0x8,%eax
  jg     L17
L68:
  mov    $0x2a,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
  jmp    L35
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L32
L26:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int c, prevstate, state;
  prevstate = state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\t' || c == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      putchar('*');
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      putchar('\n');
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbx
L57:
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L56
L45:
  cmp    $0xa,%eax
  jg     L6
  cmp    $0x8,%eax
  jg     L4
L68:
  mov    $0x2a,%edi
  mov    $0x1,%ebp
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L45
L56:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  cmp    $0x20,%eax
  jne    L68
L4:
  test   %ebp,%ebp
  je     L42
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L57
```

assistant: ```c
int main(void) {
  int c, prevstate, state;
  prevstate = state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\t' || c == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      putchar('*');
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      putchar('\n');
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%rbx
L62:
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  je     L38
L27:
  cmp    $0xa,%eax
  jg     L53
  cmp    $0x8,%eax
  jg     L36
L68:
  mov    $0x2a,%edi
  mov    $0x1,%ebp
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L27
L38:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L53:
  cmp    $0x20,%eax
  jne    L68
L36:
  test   %ebp,%ebp
  je     L64
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L62
```

assistant: ```c
int main(void) {
  int c, prevstate, state;
  prevstate = state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\t' || c == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      putchar('*');
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      putchar('\n');
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Sscount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L9:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Sscount(char **ss) {
  int i = 0;
  while (ss[i])
    ++i;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Sscount>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L21
  mov    $0x1,%eax
L12:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L12
L10:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
int Sscount(char **ss) {
  int i = 0;
  while (ss[i])
    ++i;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Sscount>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  nop
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L7
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Sscount(char **ss) {
  int i = 0;
  while (ss[i])
    ++i;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sscount>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L2
  mov    $0x1,%eax
  nop
L12:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpq   $0x0,-0x8(%rdi,%rax,8)
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Sscount(char **ss) {
  int i = 0;
  while (ss[i])
    ++i;
  return i;
}
```