user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L5
L20:
  movq   $0x0,-0x28(%rbp)
  jmp    L16
L67:
  addq   $0x1,-0x28(%rbp)
L16:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L60
  mov    -0x38(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jl     L67
L60:
  mov    -0x38(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jne    L114
  addl   $0x1,-0x3c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L95
L22:
  mov    -0x10(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    -0x50(%rbp),%rdx
  add    %rsi,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L95:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L22
  mov    -0x30(%rbp),%rax
  sub    -0x20(%rbp),%rax
  add    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L89
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x50(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L89:
  mov    -0x34(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jl     L15
  mov    -0x34(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  cltq
  add    %rax,-0x30(%rbp)
L114:
  addq   $0x1,-0x30(%rbp)
L5:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,-0x30(%rbp)
  jle    L20
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L90
L41:
  mov    -0x10(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    -0x50(%rbp),%rdx
  add    %rsi,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L90:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L41
  mov    -0x3c(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long replace(char *str, char *str2, char *s, char *t) {
  int ls, lt, c;
  long a, b, fl, f, e, m;
  ls = length(s);
  lt = length(t);
  fl = length(str);
  c = 0;
  f = 0;
  e = 0;
  for (a = 0; a <= fl - ls; a++) {
    b = 0;
    while (*(str + a + b) == *(s + b) && b < ls)
      b++;
    if (b == ls) {
      c++;
      for (m = f; m < a; m++)
        *(str2 + e + m - f) = *(str + m);
      e += a - f;
      for (m = 0; m < lt; m++)
        *(str2 + e + m) = *(t + m);
      e += lt;
      f = a + ls;
      a += ls - 1;
    }
  }
  for (m = f; m <= fl; m++)
    *(str2 + e + m - f) = *(str + m);
  return c;
}
```