user: 这段汇编代码用C语言表示是什么样的?

```asm
<_print_idle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%r8
  lea    D56(%rip),%rdx
  mov    %rdx,%rcx
  lea    D83(%rip),%rdx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmp    $0x10,%eax
  jle    L87
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L87:
  lea    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  je     L73
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L73:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x1517f,-0x28(%rbp)
  jbe    L47
  mov    -0x28(%rbp),%rax
  movabs $0xc22e450672894ab7,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L47:
  cmpq   $0xe0f,-0x28(%rbp)
  jbe    L21
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rax
  shr    $0x4,%rax
  movabs $0x91a2b3c4d5e6f81,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  imul   $0xe10,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  movabs $0x8888888888888889,%rdx
  mul    %rdx
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  mov    -0x28(%rbp),%rax
  shr    $0x4,%rax
  movabs $0x91a2b3c4d5e6f81,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rcx,%rdx
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L21:
  mov    -0x28(%rbp),%rsi
  movabs $0x8888888888888889,%rdx
  mov    %rsi,%rax
  mul    %rdx
  mov    %rdx,%rcx
  shr    $0x5,%rcx
  mov    %rcx,%rax
  shl    $0x4,%rax
  sub    %rcx,%rax
  shl    $0x2,%rax
  sub    %rax,%rsi
  mov    %rsi,%rcx
  mov    -0x28(%rbp),%rax
  movabs $0x8888888888888889,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x5,%rax
  mov    %rcx,%rdx
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D56
data_type: string
name: read_data
arguments: tag: D83
data_type: string
name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D69
data_type: string
name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D7
data_type: string

tool: D56: /dev/

tool: D83: %s%s

tool: D18: ?

tool: D69: %5s 

tool: D28: %4lud 

tool: D23: %02lu:%02lu 

tool: D7: %02lum%02lu 

assistant: ```c
int _print_idle(struct timeval *tv, char *device) {
  char dev[16];
  struct stat st;
  unsigned long idle;
  if (snprintf(dev, sizeof(dev), "%s%s", "/dev/", device) > (int)sizeof(dev))
    return printf("%5s ", "?");
  if (lstat(dev, &st) != 0)
    return printf("%5s ", "?");
  idle = tv->tv_sec - st.st_atime;
  if (idle / 3600 >= 24)
    return printf("%4lud ", idle / 3600 / 24);
  else if (idle / 60 >= 60)
    return printf("%02lu:%02lu ", idle / 3600, idle % 3600 / 60);
  return printf("%02lum%02lu ", idle / 60, idle % 60);
}
```