ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_multi_set_permutation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r15d
  mov    %rdx,(%rsp)
  cmp    %edi,%ecx
  je     L131
  mov    %rsi,%rbp
  mov    %ecx,%r14d
  test   %edi,%edi
  jle    L78
  movslq %ecx,%rax
  mov    (%rsp),%rdi
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r15),%ecx
  mov    %rcx,0x8(%rsp)
  lea    -0x1(%r14),%eax
  lea    0x4(%rdi,%rax,4),%r13
  lea    0x4(%rsi,%rcx,4),%r12
  mov    $0x0,%ebx
  lea    0x1(%r14),%eax
  mov    %eax,0x1c(%rsp)
  jmp    L74
L131:
  test   %edi,%edi
  jle    L61
  mov    (%rsp),%rdi
  mov    %rdi,%rbx
  lea    -0x1(%r15),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D8(%rip),%rbp
L60:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L60
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
L78:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    $0x0,%ecx
  test   %r14d,%r14d
  jle    L103
  mov    0x0(%rbp,%rbx,4),%esi
  mov    (%rsp),%rax
  mov    $0x0,%ecx
L130:
  cmp    %esi,(%rax)
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L130
L103:
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %rbp,%rax
  mov    $0x0,%edx
L81:
  cmp    %edi,(%rax)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%edx
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L81
  cmp    %ecx,%edx
  jg     L96
L69:
  lea    0x1(%rbx),%rax
  cmp    0x8(%rsp),%rbx
  je     L78
  mov    %rax,%rbx
L74:
  test   %ebx,%ebx
  je     L79
  mov    -0x4(%rbp,%rbx,4),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  je     L69
  jmp    L79
L96:
  mov    0x10(%rsp),%rax
  mov    %edi,(%rax)
  mov    0x1c(%rsp),%ecx
  mov    (%rsp),%rdx
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <print_multi_set_permutation>
  jmp    L69
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: %3d

assistant: ```c
void print_multi_set_permutation(int n, int b[], int a[], int cur) {
  int i, j;
  if (cur == n) {
    for (i = 0; i < n; ++i)
      printf("%3d", a[i]);
    putchar('\n');
  } else
    for (i = 0; i < n; ++i) {
      if (!i || b[i] != b[i - 1]) {
        int c1, c2;
        c1 = c2 = 0;
        for (j = 0; j < cur; ++j)
          if (a[j] == b[i])
            c1++;
        for (j = 0; j < n; ++j)
          if (b[j] == b[i])
            c2++;
        if (c1 < c2) {
          a[cur] = b[i];
          print_multi_set_permutation(n, b, a, cur + 1);
        }
      }
    }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_multi_set_permutation>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  cmp    %edi,%ecx
  je     L26
  test   %edi,%edi
  jle    L117
  movslq %ecx,%rax
  mov    %rsi,%r14
  mov    %edi,%r8d
  xor    %ebp,%ebp
  lea    (%rdx,%rax,4),%r9
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r13
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
  lea    0x1(%rcx),%ecx
L6:
  mov    (%r14,%rbp,4),%edx
  test   %rbp,%rbp
  je     L72
  cmp    %edx,-0x4(%r14,%rbp,4)
  jne    L72
L2:
  add    $0x1,%rbp
  cmp    %r8,%rbp
  jne    L6
L117:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L72:
  test   %r15d,%r15d
  jle    L60
  mov    %rbx,%rax
  xor    %r10d,%r10d
  nop
L29:
  xor    %esi,%esi
  cmp    %edx,(%rax)
  sete   %sil
  add    $0x4,%rax
  add    %esi,%r10d
  cmp    %r13,%rax
  jne    L29
L78:
  mov    %r14,%rax
  xor    %esi,%esi
  nopl   0x0(%rax)
L111:
  xor    %r11d,%r11d
  cmp    %edx,(%rax)
  sete   %r11b
  add    $0x4,%rax
  add    %r11d,%esi
  cmp    %r12,%rax
  jne    L111
  cmp    %esi,%r10d
  jge    L2
  mov    %edx,(%r9)
  mov    %r14,%rsi
  mov    %rbx,%rdx
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %edi,0x8(%rsp)
  call   <print_multi_set_permutation>
  mov    0x18(%rsp),%r8
  mov    0x10(%rsp),%r9
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edi
  jmp    L2
  nopl   0x0(%rax)
L26:
  test   %ecx,%ecx
  jle    L97
  lea    -0x1(%rcx),%eax
  lea    D1(%rip),%rbp
  lea    0x4(%rdx,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L7
L97:
  add    $0x28,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L60:
  xor    %r10d,%r10d
  jmp    L78
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: %3d

assistant: ```c
void print_multi_set_permutation(int n, int b[], int a[], int cur) {
  int i, j;
  if (cur == n) {
    for (i = 0; i < n; ++i)
      printf("%3d", a[i]);
    putchar('\n');
  } else
    for (i = 0; i < n; ++i) {
      if (!i || b[i] != b[i - 1]) {
        int c1, c2;
        c1 = c2 = 0;
        for (j = 0; j < cur; ++j)
          if (a[j] == b[i])
            c1++;
        for (j = 0; j < n; ++j)
          if (b[j] == b[i])
            c2++;
        if (c1 < c2) {
          a[cur] = b[i];
          print_multi_set_permutation(n, b, a, cur + 1);
        }
      }
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Syscall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  ja     L22
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x8(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <PrintChar@plt>
  jmp    L67
  mov    -0x8(%rbp),%eax
  mov    %rax,%rdi
  call   <PrintString@plt>
  jmp    L67
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <PrintInt@plt>
  jmp    L67
  mov    -0x8(%rbp),%eax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <ReadChar@plt>
  jmp    L67
  mov    -0xc(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%eax
  movzwl %ax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Read@plt>
  jmp    L67
  mov    -0xc(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%eax
  movzwl %ax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Write@plt>
  jmp    L67
L22:
  nop
L67:
  nop
  leave
  ret
```

assistant: ```c
void Syscall(unsigned int syscall_code, unsigned int a0, unsigned int a1, unsigned int a2) {
  switch (syscall_code) {
  case 11:
    PrintChar((char)a0);
    break;
  case 4:
    PrintString((char *)a0);
    break;
  case 1:
    PrintInt(a0);
    break;
  case 12:
    ReadChar((char *)a0, a1, a2);
    break;
  case 14:
    Read((unsigned short)a0, (unsigned short)a1);
    break;
  case 15:
    Write((unsigned short)a0, (unsigned short)a1);
    break;
  default:
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Syscall>:
  endbr64
  cmp    $0xf,%edi
  ja     L47
  sub    $0x8,%rsp
  mov    %edx,%r8d
  mov    %edi,%eax
  lea    D6(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movsbl %sil,%edi
  call   <PrintChar@plt>
L1:
  add    $0x8,%rsp
  ret
  mov    %esi,%edi
  call   <PrintString@plt>
  jmp    L1
  mov    %esi,%edi
  call   <PrintInt@plt>
  jmp    L1
  mov    %esi,%edi
  mov    %ecx,%edx
  mov    %r8d,%esi
  call   <ReadChar@plt>
  jmp    L1
  movzwl %r8w,%r8d
  movzwl %si,%edi
  mov    %r8d,%esi
  call   <Read@plt>
  jmp    L1
  movzwl %r8w,%r8d
  movzwl %si,%edi
  mov    %r8d,%esi
  call   <Write@plt>
  jmp    L1
L47:
  ret
```

assistant: ```c
void Syscall(unsigned int syscall_code, unsigned int a0, unsigned int a1, unsigned int a2) {
  switch (syscall_code) {
  case 11:
    PrintChar((char)a0);
    break;
  case 4:
    PrintString((char *)a0);
    break;
  case 1:
    PrintInt(a0);
    break;
  case 12:
    ReadChar((char *)a0, a1, a2);
    break;
  case 14:
    Read((unsigned short)a0, (unsigned short)a1);
    break;
  case 15:
    Write((unsigned short)a0, (unsigned short)a1);
    break;
  default:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x2800000,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x2800000,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0xa00000,%esi
  mov    %rax,%rdi
  call   <init_data@plt>
  mov    -0x18(%rbp),%rax
  mov    $0xa00000,%esi
  mov    %rax,%rdi
  call   <init_data@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%r9
  mov    $0x1,%r8d
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    $0xa00000,%edi
  call   <pencil_saxpy_nn@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  double start_time, end_time;
  float(*A)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  float(*B)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  init_data(*A, 1024 * 1024 * 10);
  init_data(*B, 1024 * 1024 * 10);
  start_time = get_time();
  pencil_saxpy_nn(1024 * 1024 * 10, 10, 1, *A, 1, *B);
  end_time = get_time();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2800000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x2800000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0xa00000,%esi
  mov    %rbx,%rdi
  call   <init_data@plt>
  mov    $0xa00000,%esi
  mov    %rbp,%rdi
  call   <init_data@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  mov    %rbp,%r9
  mov    $0x1,%r8d
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    $0xa00000,%edi
  call   <pencil_saxpy_nn@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  double start_time, end_time;
  float(*A)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  float(*B)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  init_data(*A, 1024 * 1024 * 10);
  init_data(*B, 1024 * 1024 * 10);
  start_time = get_time();
  pencil_saxpy_nn(1024 * 1024 * 10, 10, 1, *A, 1, *B);
  end_time = get_time();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2800000,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2800000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    $0xa00000,%esi
  mov    %rax,%rbx
  call   <init_data@plt>
  mov    %rbx,%rdi
  mov    $0xa00000,%esi
  call   <init_data@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  mov    %rbx,%r9
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%r8d
  mov    $0xa,%esi
  mov    $0xa00000,%edi
  call   <pencil_saxpy_nn@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int main() {
  double start_time, end_time;
  float(*A)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  float(*B)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  init_data(*A, 1024 * 1024 * 10);
  init_data(*B, 1024 * 1024 * 10);
  start_time = get_time();
  pencil_saxpy_nn(1024 * 1024 * 10, 10, 1, *A, 1, *B);
  end_time = get_time();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2800000,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x2800000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    $0xa00000,%esi
  mov    %rax,%rbx
  call   <init_data@plt>
  mov    %rbx,%rdi
  mov    $0xa00000,%esi
  call   <init_data@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  mov    %rbx,%r9
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%r8d
  mov    $0xa,%esi
  mov    $0xa00000,%edi
  call   <pencil_saxpy_nn@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int main() {
  double start_time, end_time;
  float(*A)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  float(*B)[1024 * 1024 * 10][1] = (float(*)[1024 * 1024 * 10][1]) malloc(1024 * 1024 * 10 * sizeof(float));
  init_data(*A, 1024 * 1024 * 10);
  init_data(*B, 1024 * 1024 * 10);
  start_time = get_time();
  pencil_saxpy_nn(1024 * 1024 * 10, 10, 1, *A, 1, *B);
  end_time = get_time();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L9
  mov    -0x8(%rbp),%rax
  jmp    L6
L9:
  mov    -0x10(%rbp),%rax
L6:
  pop    %rbp
  ret
```

assistant: ```c
long long min(long long a, long long b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long long min(long long a, long long b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long long min(long long a, long long b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min>:
  endbr64
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
long long min(long long a, long long b) {
  if (a < b)
    return a;
  else
    return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PopulateKeyholeArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  and    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cmp    $0x8,%eax
  jle    L29
  movl   $0x0,-0x4(%rbp)
L29:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void PopulateKeyholeArray(int *keyholes, char *duckingkey) {
  int i, j = 0;
  for (i = 0; i < strlen(duckingkey); i++) {
    keyholes[i] = (int)(duckingkey[j] & 0x01);
    if (j++ > 8) {
      j = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<PopulateKeyholeArray>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  jmp    L18
L13:
  movslq %ebp,%rax
  movzbl (%r12,%rax,1),%eax
  and    $0x1,%eax
  mov    %eax,0x0(%r13,%rbx,4)
  lea    0x1(%rbp),%eax
  cmp    $0x9,%ebp
  cmovge %r14d,%eax
  mov    %eax,%ebp
  add    $0x1,%rbx
L18:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void PopulateKeyholeArray(int *keyholes, char *duckingkey) {
  int i, j = 0;
  for (i = 0; i < strlen(duckingkey); i++) {
    keyholes[i] = (int)(duckingkey[j] & 0x01);
    if (j++ > 8) {
      j = 0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PopulateKeyholeArray>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L10:
  movslq %ebp,%rax
  movzbl (%r14,%rax,1),%eax
  and    $0x1,%eax
  cmp    $0x9,%ebp
  mov    %eax,(%r12,%rbx,4)
  lea    0x1(%rbp),%eax
  cmovge %r13d,%eax
  add    $0x1,%rbx
  mov    %eax,%ebp
L4:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void PopulateKeyholeArray(int *keyholes, char *duckingkey) {
  int i, j = 0;
  for (i = 0; i < strlen(duckingkey); i++) {
    keyholes[i] = (int)(duckingkey[j] & 0x01);
    if (j++ > 8) {
      j = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<PopulateKeyholeArray>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L1:
  movslq %ebp,%rax
  movzbl (%r14,%rax,1),%eax
  and    $0x1,%eax
  cmp    $0x9,%ebp
  mov    %eax,(%r12,%rbx,4)
  lea    0x1(%rbp),%eax
  cmovge %r13d,%eax
  add    $0x1,%rbx
  mov    %eax,%ebp
L10:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void PopulateKeyholeArray(int *keyholes, char *duckingkey) {
  int i, j = 0;
  for (i = 0; i < strlen(duckingkey); i++) {
    keyholes[i] = (int)(duckingkey[j] & 0x01);
    if (j++ > 8) {
      j = 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delay_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
L7:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay_us(unsigned int i) {
  while (i--) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delay_us>:
  endbr64
L1:
  sub    $0x1,%edi
  cmp    $0xffffffff,%edi
  jne    L1
  ret
```

assistant: ```c
void delay_us(unsigned int i) {
  while (i--) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay_us>:
  endbr64
  ret
```

assistant: ```c
void delay_us(unsigned int i) {
  while (i--) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delay_us>:
  endbr64
  ret
```

assistant: ```c
void delay_us(unsigned int i) {
  while (i--) {
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trap_water>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  mov    $0x0,%esi
  test   %r12d,%r12d
  jle    L9
  mov    %rdi,%rbx
  movslq %r12d,%r13
  lea    0x0(,%r12,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    (%rbx),%eax
  mov    %eax,0x0(%rbp)
  cmp    $0x1,%r12d
  jle    L46
  lea    0x4(%rbp),%rax
  lea    -0x2(%r12),%edx
  lea    0x8(%rbp,%rdx,4),%r8
  mov    %rbx,%rsi
  sub    %rbp,%rsi
L1:
  mov    (%rsi,%rax,1),%edx
  mov    -0x4(%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L1
  shl    $0x2,%r13
  mov    -0x4(%rbx,%r13,1),%eax
  mov    %eax,-0x4(%rdi,%r13,1)
  lea    -0x2(%r12),%ecx
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rbx,%r8
  sub    %rdi,%r8
L13:
  mov    (%r8,%rax,1),%edx
  mov    0x4(%rax),%esi
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%ecx
  jns    L13
L59:
  mov    %r12d,%r12d
  lea    0x0(%rbp,%r12,4),%r8
  mov    %rbp,%rdx
  mov    $0x0,%esi
  sub    %rbp,%rdi
  sub    %rbp,%rbx
L19:
  mov    (%rdi,%rdx,1),%eax
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  sub    (%rbx,%rdx,1),%eax
  add    %eax,%esi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L19
L9:
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  shl    $0x2,%r13
  mov    -0x4(%rbx,%r13,1),%eax
  mov    %eax,-0x4(%rdi,%r13,1)
  jmp    L59
```

assistant: ```c
int trap_water(int *height, int height_size) {
  int *max_left, *max_right;
  int water = 0, i, n = height_size;
  if (n < 1) {
    return water;
  }
  max_left = (int *)malloc(sizeof(int) * n);
  max_right = (int *)malloc(sizeof(int) * n);
  max_left[0] = height[0];
  for (i = 1; i < n; ++i) {
    max_left[i] = (((max_left[i - 1]) < (height[i])) ? (height[i]) : (max_left[i - 1]));
  }
  max_right[n - 1] = height[n - 1];
  for (i = n - 2; i >= 0; --i) {
    max_right[i] = (((max_right[i + 1]) < (height[i])) ? (height[i]) : (max_right[i + 1]));
  }
  for (i = 0; i < n; ++i) {
    water += (((max_left[i]) > (max_right[i])) ? (max_right[i]) : (max_left[i])) - height[i];
  }
  return water;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trap_water>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L11
  push   %r13
  lea    0x0(,%rsi,4),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    0x0(%rbp),%edx
  movslq %r12d,%r10
  lea    -0x2(%r12),%r9d
  shl    $0x2,%r10
  mov    %rax,%rdi
  mov    %edx,(%rbx)
  lea    -0x4(%rbp,%r10,1),%r11
  cmp    $0x1,%r12d
  je     L67
  mov    %r9d,%ecx
  mov    %rbp,%rsi
  lea    0x4(%rbx),%rax
  lea    0x4(%rbx,%rcx,4),%r8
  sub    %rbx,%rsi
  jmp    L22
  nopl   0x0(%rax)
L63:
  add    $0x4,%rax
L22:
  mov    (%rsi,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,(%rax)
  cmp    %r8,%rax
  jne    L63
  mov    (%r11),%eax
  mov    %eax,-0x4(%rdi,%r10,1)
L41:
  movslq %r9d,%rsi
  shl    $0x2,%r9
  mov    %rbp,%r8
  shl    $0x2,%rsi
  sub    %rdi,%r8
  lea    (%rdi,%rsi,1),%rax
  sub    $0x4,%rsi
  sub    %r9,%rsi
  add    %rdi,%rsi
  nopw   0x0(%rax,%rax,1)
L71:
  mov    (%r8,%rax,1),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  sub    $0x4,%rax
  mov    %edx,0x4(%rax)
  cmp    %rax,%rsi
  jne    L71
  mov    %r12d,%r12d
  mov    %rbx,%rdx
  xor    %r8d,%r8d
  sub    %rbx,%rdi
  lea    (%rbx,%r12,4),%rsi
  sub    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rdi,%rdx,1),%eax
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  sub    0x0(%rbp,%rdx,1),%eax
  add    $0x4,%rdx
  add    %eax,%r8d
  cmp    %rdx,%rsi
  jne    L6
L51:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L67:
  mov    (%r11),%eax
  mov    %eax,-0x4(%rdi,%r10,1)
  cmp    $0xffffffff,%r9d
  jne    L41
  mov    (%rbx),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovle %eax,%edx
  mov    %edx,%r8d
  sub    0x0(%rbp),%r8d
  jmp    L51
```

assistant: ```c
int trap_water(int *height, int height_size) {
  int *max_left, *max_right;
  int water = 0, i, n = height_size;
  if (n < 1) {
    return water;
  }
  max_left = (int *)malloc(sizeof(int) * n);
  max_right = (int *)malloc(sizeof(int) * n);
  max_left[0] = height[0];
  for (i = 1; i < n; ++i) {
    max_left[i] = (((max_left[i - 1]) < (height[i])) ? (height[i]) : (max_left[i - 1]));
  }
  max_right[n - 1] = height[n - 1];
  for (i = n - 2; i >= 0; --i) {
    max_right[i] = (((max_right[i + 1]) < (height[i])) ? (height[i]) : (max_right[i + 1]));
  }
  for (i = 0; i < n; ++i) {
    water += (((max_left[i]) > (max_right[i])) ? (max_right[i]) : (max_left[i])) - height[i];
  }
  return water;
}
```