ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x5857565554535251,%rax
  mov    %rax,0x40(%rsp)
  movw   $0x5a59,0x48(%rsp)
  movb   $0x0,0x4a(%rsp)
  lea    0x28(%rsp),%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x28(%rsp)
  jle    L5
  movl   $0x1,0x14(%rsp)
  lea    0x2c(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L40
L24:
  mov    %r12d,0xc(%rsp)
  lea    (%r15,%r12,1),%rsi
  mov    $0x1,%edx
  mov    %r14,%rdi
  call   <strncmp@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L24
  mov    0xc(%rsp),%eax
  add    %ebp,%eax
  add    %r13d,%eax
  mov    0x10(%rsp),%ecx
  lea    (%rax,%rcx,1),%ebp
  add    $0x1,%r13d
  add    $0x1,%r14
  cmp    %r13d,%ebx
  je     L84
L108:
  mov    $0x0,%r12d
  jmp    L24
L84:
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jle    L30
L58:
  lea    0x50(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x50(%rsp),%r14
  mov    $0x0,%r13d
  lea    0x30(%rsp),%r15
  test   %eax,%eax
  jg     L108
  jmp    L84
L3:
  mov    $0x0,%ebp
L30:
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x28(%rsp)
  jl     L5
L40:
  mov    0x18(%rsp),%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x2c(%rsp)
  jle    L3
  mov    $0x0,%ebp
  movl   $0x0,0x10(%rsp)
  jmp    L58
L5:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D39
datatype: string
name: retrieve_data
arguments: tag: D36
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string

tool: D39: %d

tool: D36: %s

tool: D35: %d


assistant: ```c
int main() {
  char Alfa[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ", String0[51];
  int Cont, N, NLin, Cont2, Lim, Cont3, Cont4, Som = 0, Cond = 0;
  scanf("%d", &N);
  for (Cont = 1; Cont <= N; Cont++) {
    scanf("%d", &NLin);
    Som = 0;
    for (Cont2 = 0; Cont2 < NLin; Cont2++) {
      scanf("%s", String0);
      Lim = strlen(String0) - 1;
      Cont4 = 0;
      for (Cont3 = 0; Cont3 <= Lim; Cont3++) {
        Cond = 0;
        while (Cond != 1) {
          if (strncmp(&String0[Cont3], &Alfa[Cont4], 1) == 0) {
            Som = Som + Cont4;
            Som = Som + Cont3;
            Som = Som + Cont2;
            Cond = 1;
            Cont4 = 0;
          } else
            Cont4++;
        }
      }
    }
    printf("%d\n", Som);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x10(%rbp)
  jmp    L19
L11:
  addq   $0x1,-0x10(%rbp)
L19:
  mov    $0x3e8,%edi
  call   <srpc_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <srpc_dump@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: allocated %ld kB


assistant: ```c
int main() {
  void *p;
  long i;
  for (i = 0; (p = srpc_malloc(1000)) != NULL; i++)
    ;
  printf("allocated %ld kB\n", i);
  srpc_dump();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  jmp    L8
L11:
  add    $0x1,%rbx
L8:
  mov    $0x3e8,%edi
  call   <srpc_malloc@plt>
  test   %rax,%rax
  jne    L11
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <srpc_dump@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: allocated %ld kB


assistant: ```c
int main() {
  void *p;
  long i;
  for (i = 0; (p = srpc_malloc(1000)) != NULL; i++)
    ;
  printf("allocated %ld kB\n", i);
  srpc_dump();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  jmp    L6
  nopl   0x0(%rax)
L8:
  add    $0x1,%rbp
L6:
  mov    $0x3e8,%edi
  call   <srpc_malloc@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <srpc_dump@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: allocated %ld kB


assistant: ```c
int main() {
  void *p;
  long i;
  for (i = 0; (p = srpc_malloc(1000)) != NULL; i++)
    ;
  printf("allocated %ld kB\n", i);
  srpc_dump();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  jmp    L5
  nopl   0x0(%rax)
L14:
  add    $0x1,%rbp
L5:
  mov    $0x3e8,%edi
  call   <srpc_malloc@plt>
  test   %rax,%rax
  jne    L14
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <srpc_dump@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: allocated %ld kB


assistant: ```c
int main() {
  void *p;
  long i;
  for (i = 0; (p = srpc_malloc(1000)) != NULL; i++)
    ;
  printf("allocated %ld kB\n", i);
  srpc_dump();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kaiser_beta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L6:
  mov    -0x20(%rbp),%eax
  movd   %eax,%xmm0
  call   <bessel@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  D9(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  -0x20(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <bessel@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: f64

tool: D9: 1

assistant: ```c
int kaiser_beta(float *w, const int N, const float beta) {
  int i;
  float Ia, Ib;
  for (i = 0; i < N; i++) {
    float x;
    Ib = bessel(beta);
    x = (float)((2. * i / (N - 1)) - 1);
    Ia = bessel(beta * (float)sqrt(1. - x * x));
    w[i] = (float)(Ia / Ib);
  }
  return N;
}
```
user: What is the c source code of the assembly code below?

```asm
<kaiser_beta>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebp
  movss  %xmm0,0x8(%rsp)
  test   %esi,%esi
  jle    L0
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x0,%ebx
L19:
  movss  0x8(%rsp),%xmm0
  call   <bessel@plt>
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  %xmm0,%xmm0
  lea    -0x1(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  subsd  D2(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D2(%rip),%xmm1
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  0x8(%rsp),%xmm0
  call   <bessel@plt>
  divss  0xc(%rsp),%xmm0
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L19
L0:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: f64

tool: D2: 1

assistant: ```c
int kaiser_beta(float *w, const int N, const float beta) {
  int i;
  float Ia, Ib;
  for (i = 0; i < N; i++) {
    float x;
    Ib = bessel(beta);
    x = (float)((2. * i / (N - 1)) - 1);
    Ia = bessel(beta * (float)sqrt(1. - x * x));
    w[i] = (float)(Ia / Ib);
  }
  return N;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kaiser_beta>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,(%rsp)
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  pxor   %xmm5,%xmm5
  mov    %rdi,%rbx
  movslq %esi,%rbp
  cvtsi2sd %eax,%xmm5
  xor    %r13d,%r13d
  movsd  %xmm5,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L19:
  movss  (%rsp),%xmm0
  call   <bessel@plt>
  movsd  D4(%rip),%xmm1
  movss  %xmm0,0x4(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r13d,%xmm0
  addsd  %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm0
  subsd  D4(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  (%rsp),%xmm0
  call   <bessel@plt>
  divss  0x4(%rsp),%xmm0
  movss  %xmm0,(%rbx,%r13,4)
  add    $0x1,%r13
  cmp    %rbp,%r13
  jne    L19
L4:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
int kaiser_beta(float *w, const int N, const float beta) {
  int i;
  float Ia, Ib;
  for (i = 0; i < N; i++) {
    float x;
    Ib = bessel(beta);
    x = (float)((2. * i / (N - 1)) - 1);
    Ia = bessel(beta * (float)sqrt(1. - x * x));
    w[i] = (float)(Ia / Ib);
  }
  return N;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kaiser_beta>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,(%rsp)
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  pxor   %xmm5,%xmm5
  mov    %rdi,%rbx
  movslq %esi,%rbp
  cvtsi2sd %eax,%xmm5
  xor    %r13d,%r13d
  movsd  %xmm5,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L10:
  movss  (%rsp),%xmm0
  call   <bessel@plt>
  movsd  D16(%rip),%xmm1
  movss  %xmm0,0x4(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r13d,%xmm0
  addsd  %xmm0,%xmm0
  divsd  0x8(%rsp),%xmm0
  subsd  D16(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  (%rsp),%xmm0
  call   <bessel@plt>
  divss  0x4(%rsp),%xmm0
  movss  %xmm0,(%rbx,%r13,4)
  add    $0x1,%r13
  cmp    %r13,%rbp
  jne    L10
L16:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: f64

tool: D16: 1

assistant: ```c
int kaiser_beta(float *w, const int N, const float beta) {
  int i;
  float Ia, Ib;
  for (i = 0; i < N; i++) {
    float x;
    Ib = bessel(beta);
    x = (float)((2. * i / (N - 1)) - 1);
    Ia = bessel(beta * (float)sqrt(1. - x * x));
    w[i] = (float)(Ia / Ib);
  }
  return N;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  add    %esi,%r12d
  sar    %r12d
  cmp    $0x1,%esi
  jle    L10
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%ebp
  movslq %esi,%rsi
  lea    -0x1(%rsi),%r13
  lea    0x0(,%r13,4),%r8
  mov    %rdi,%r11
  lea    (%rdi,%rsi,8),%r9
  mov    $0x0,%edi
  mov    $0x0,%ebx
  jmp    L13
L33:
  mov    %r13,%r10
  sub    %rbx,%r10
  lea    -0x1(%rbp),%eax
  sub    %rax,%r10
  shl    $0x2,%r10
  mov    %r8,%rax
  mov    %rdi,%rdx
L23:
  mov    %rdx,%rsi
  add    (%r11),%rsi
  mov    (%rsi),%r14d
  mov    (%rcx,%rdx,2),%r15
  mov    (%r15,%r8,1),%r15d
  mov    %r15d,(%rsi)
  mov    -0x8(%r9),%rsi
  mov    (%rsi,%rax,1),%r15d
  mov    (%rcx,%rdx,2),%rsi
  mov    %r15d,(%rsi,%r8,1)
  mov    (%rcx,%rax,2),%rsi
  mov    (%rsi,%rdi,1),%r15d
  mov    -0x8(%r9),%rsi
  mov    %r15d,(%rsi,%rax,1)
  mov    (%rcx,%rax,2),%rsi
  mov    %r14d,(%rsi,%rdi,1)
  add    $0x4,%rdx
  mov    %rax,%rsi
  sub    $0x4,%rax
  cmp    %r10,%rsi
  jne    L23
L57:
  add    $0x1,%rbx
  sub    $0x1,%ebp
  add    $0x4,%rdi
  sub    $0x4,%r8
  add    $0x8,%r11
  sub    $0x8,%r9
  cmp    %ebx,%r12d
  jle    L10
L13:
  test   %ebp,%ebp
  jg     L33
  jmp    L57
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void rotate(int **matrix, int n) {
  int layer;
  int first, last, shift;
  int tmp;
  for (layer = 0; layer < n / 2; ++layer) {
    for (shift = 0; shift < n - 1 - layer; ++shift) {
      first = layer;
      last = n - 1 - layer;
      tmp = matrix[first][first + shift];
      matrix[first][first + shift] = matrix[first + shift][last];
      matrix[first + shift][last] = matrix[last][last - shift];
      matrix[last][last - shift] = matrix[last - shift][first];
      matrix[last - shift][first] = tmp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rotate>:
  endbr64
  mov    %esi,%eax
  push   %r15
  shr    $0x1f,%eax
  push   %r14
  push   %r13
  add    %esi,%eax
  push   %r12
  sar    %eax
  push   %rbp
  push   %rbx
  mov    %eax,-0x4(%rsp)
  cmp    $0x1,%esi
  jle    L30
  mov    %esi,%ebp
  mov    %rdi,%r12
  xor    %r11d,%r11d
  xor    %r15d,%r15d
  sub    $0x1,%ebp
  xor    %r14d,%r14d
  movslq %ebp,%r10
  lea    (%rdi,%r10,8),%r13
  shl    $0x2,%r10
L4:
  test   %ebp,%ebp
  jle    L26
  mov    (%r12),%rax
  lea    -0x1(%rbp),%edi
  mov    0x0(%r13),%rcx
  mov    %r13,%r8
  mov    %rdi,%rbp
  add    %r15,%rdi
  lea    0x4(%rax,%rdi,4),%rbx
  mov    %ebp,-0x8(%rsp)
  lea    (%rax,%r11,1),%rdx
  mov    %r12,%rdi
  lea    (%rcx,%r10,1),%rsi
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rdi),%rax
  mov    (%r8),%rcx
L20:
  add    %r10,%rax
  mov    (%rdx),%r9d
  add    %r11,%rcx
  add    $0x4,%rdx
  mov    (%rax),%ebp
  sub    $0x4,%rsi
  add    $0x8,%rdi
  sub    $0x8,%r8
  mov    %ebp,-0x4(%rdx)
  mov    0x4(%rsi),%ebp
  mov    %ebp,(%rax)
  mov    (%rcx),%eax
  mov    %eax,0x4(%rsi)
  mov    %r9d,(%rcx)
  cmp    %rbx,%rdx
  jne    L7
  mov    -0x8(%rsp),%ebp
L34:
  add    $0x1,%r14d
  add    $0x1,%r15
  add    $0x8,%r12
  sub    $0x8,%r13
  sub    $0x4,%r10
  add    $0x4,%r11
  cmp    -0x4(%rsp),%r14d
  jl     L4
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  sub    $0x1,%ebp
  jmp    L34
```

assistant: ```c
void rotate(int **matrix, int n) {
  int layer;
  int first, last, shift;
  int tmp;
  for (layer = 0; layer < n / 2; ++layer) {
    for (shift = 0; shift < n - 1 - layer; ++shift) {
      first = layer;
      last = n - 1 - layer;
      tmp = matrix[first][first + shift];
      matrix[first][first + shift] = matrix[first + shift][last];
      matrix[first + shift][last] = matrix[last][last - shift];
      matrix[last][last - shift] = matrix[last - shift][first];
      matrix[last - shift][first] = tmp;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  shr    $0x1f,%r15d
  push   %r14
  add    %esi,%r15d
  push   %r13
  sar    %r15d
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L38
  mov    %esi,%ebx
  mov    %rdi,%rbp
  xor    %r10d,%r10d
  xor    %r14d,%r14d
  sub    $0x1,%ebx
  xor    %r13d,%r13d
  movslq %ebx,%r9
  lea    (%rdi,%r9,8),%r12
  shl    $0x2,%r9
L27:
  test   %ebx,%ebx
  jle    L17
  lea    -0x1(%rbx),%ecx
  mov    0x0(%rbp),%rsi
  mov    (%r12),%rdx
  mov    %rcx,%rbx
  add    %r14,%rcx
  mov    %ebx,-0x4(%rsp)
  lea    0x4(%rsi,%rcx,4),%r11
  lea    (%rsi,%r10,1),%rax
  add    %r9,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rcx
  nop
L24:
  mov    (%rcx),%rdi
  mov    (%rax),%r8d
  add    $0x4,%rax
  add    $0x8,%rcx
  sub    $0x4,%rdx
  sub    $0x8,%rsi
  add    %r9,%rdi
  mov    (%rdi),%ebx
  mov    %ebx,-0x4(%rax)
  mov    0x4(%rdx),%ebx
  mov    %ebx,(%rdi)
  mov    0x8(%rsi),%rdi
  add    %r10,%rdi
  mov    (%rdi),%ebx
  mov    %ebx,0x4(%rdx)
  mov    %r8d,(%rdi)
  cmp    %rax,%r11
  jne    L24
  mov    -0x4(%rsp),%ebx
L12:
  add    $0x1,%r13d
  add    $0x1,%r14
  add    $0x8,%rbp
  sub    $0x8,%r12
  sub    $0x4,%r9
  add    $0x4,%r10
  cmp    %r15d,%r13d
  jl     L27
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  sub    $0x1,%ebx
  jmp    L12
```

assistant: ```c
void rotate(int **matrix, int n) {
  int layer;
  int first, last, shift;
  int tmp;
  for (layer = 0; layer < n / 2; ++layer) {
    for (shift = 0; shift < n - 1 - layer; ++shift) {
      first = layer;
      last = n - 1 - layer;
      tmp = matrix[first][first + shift];
      matrix[first][first + shift] = matrix[first + shift][last];
      matrix[first + shift][last] = matrix[last][last - shift];
      matrix[last][last - shift] = matrix[last - shift][first];
      matrix[last - shift][first] = tmp;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <init_cond@plt>
  mov    $0x0,%eax
  call   <lax_wendroff@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    %eax,-0x4(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D12
type: string

tool: D4: ../bin/plot_LW

tool: D12: ../bin/plot_LW_last

assistant: ```c
int main() {
  int ret_codes = 0;
  init_cond();
  lax_wendroff();
  ret_codes = system("../bin/plot_LW");
  ret_codes = system("../bin/plot_LW_last");
  return ret_codes;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_cond@plt>
  mov    $0x0,%eax
  call   <lax_wendroff@plt>
  lea    D15(%rip),%rdi
  call   <system@plt>
  lea    D4(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D15: ../bin/plot_LW

tool: D4: ../bin/plot_LW_last

assistant: ```c
int main() {
  int ret_codes = 0;
  init_cond();
  lax_wendroff();
  ret_codes = system("../bin/plot_LW");
  ret_codes = system("../bin/plot_LW_last");
  return ret_codes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_cond@plt>
  xor    %eax,%eax
  call   <lax_wendroff@plt>
  lea    D19(%rip),%rdi
  call   <system@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <system@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string

tool: D19: ../bin/plot_LW

tool: D10: ../bin/plot_LW_last

assistant: ```c
int main() {
  int ret_codes = 0;
  init_cond();
  lax_wendroff();
  ret_codes = system("../bin/plot_LW");
  ret_codes = system("../bin/plot_LW_last");
  return ret_codes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_cond@plt>
  xor    %eax,%eax
  call   <lax_wendroff@plt>
  lea    D15(%rip),%rdi
  call   <system@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <system@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: string
name: read_data
arguments: data_label: D5
data_type: string

tool: D15: ../bin/plot_LW

tool: D5: ../bin/plot_LW_last

assistant: ```c
int main() {
  int ret_codes = 0;
  init_cond();
  lax_wendroff();
  ret_codes = system("../bin/plot_LW");
  ret_codes = system("../bin/plot_LW_last");
  return ret_codes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_from_pascal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L3
L12:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jae    L7
  mov    -0x24(%rbp),%eax
  mov    %al,-0x1(%rbp)
L7:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movzbl -0x1(%rbp),%eax
L3:
  leave
  ret
```

assistant: ```c
unsigned char copy_from_pascal(char *dest, char *pascal, unsigned int max_len) {
  unsigned char len;
  if (!pascal)
    return 0;
  len = *pascal;
  if (max_len < len)
    len = max_len;
  memset(dest, 0, max_len);
  memcpy(dest, pascal + 1, len);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_from_pascal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L12
  mov    %rdi,%r12
  mov    %rsi,%rbx
  movzbl (%rsi),%ebp
  movzbl %bpl,%eax
  cmp    %edx,%eax
  cmova  %edx,%ebp
  mov    $0x0,%esi
  call   <memset@plt>
  movzbl %bpl,%edx
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
L10:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%ebp
  jmp    L10
```

assistant: ```c
unsigned char copy_from_pascal(char *dest, char *pascal, unsigned int max_len) {
  unsigned char len;
  if (!pascal)
    return 0;
  len = *pascal;
  if (max_len < len)
    len = max_len;
  memset(dest, 0, max_len);
  memcpy(dest, pascal + 1, len);
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy_from_pascal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L3
  movzbl (%rsi),%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %r13d,%r12d
  cmp    %edx,%r13d
  ja     L12
L13:
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  lea    0x1(%rbx),%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  movzbl %dl,%r13d
  mov    %r13d,%r12d
  jmp    L13
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char copy_from_pascal(char *dest, char *pascal, unsigned int max_len) {
  unsigned char len;
  if (!pascal)
    return 0;
  len = *pascal;
  if (max_len < len)
    len = max_len;
  memset(dest, 0, max_len);
  memcpy(dest, pascal + 1, len);
  return len;
}
```