ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<EMACFrameFilterSet>:
  endbr64
  add    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0x7ffef800,%eax
  or     %esi,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACFrameFilterSet(uint32_t ui32Base, uint32_t ui32FilterOpts) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000004))) = (((*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0x80000000 | 0x00010000 | 0x00000400 | 0x00000200 | 0x00000100 | (0x01 << 6) | (0x02 << 6) | (0x03 << 6) | 0x00000020 | 0x00000010 | 0x00000008 | 0x00000004 | 0x00000002 | 0x00000001)) | ui32FilterOpts);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMACFrameFilterSet>:
  endbr64
  add    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0x7ffef800,%eax
  or     %esi,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACFrameFilterSet(uint32_t ui32Base, uint32_t ui32FilterOpts) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000004))) = (((*((volatile uint32_t *)(ui32Base + 0x00000004))) & ~(0x80000000 | 0x00010000 | 0x00000400 | 0x00000200 | 0x00000100 | (0x01 << 6) | (0x02 << 6) | (0x03 << 6) | 0x00000020 | 0x00000010 | 0x00000008 | 0x00000004 | 0x00000002 | 0x00000001)) | ui32FilterOpts);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_memfuncs_chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  call   <__builtin___memcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin___memcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  call   <__builtin___memmove_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin___memmove_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  call   <__builtin___mempcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin___mempcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  call   <__builtin___memset_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_memfuncs_chk(void *s, unsigned n) {
  sink(0, __builtin___memcpy_chk(null(), s, n, n));
  sink(0, __builtin___memcpy_chk(s, null(), n, n));
  sink(0, __builtin___memmove_chk(null(), s, n, n));
  sink(0, __builtin___memmove_chk(s, null(), n, n));
  sink(0, __builtin___mempcpy_chk(null(), s, n, n));
  sink(0, __builtin___mempcpy_chk(s, null(), n, n));
  sink(0, __builtin___memset_chk(null(), 0, n, n));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_memfuncs_chk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin___memcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin___memcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin___memmove_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin___memmove_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <__builtin___mempcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rsi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <__builtin___mempcpy_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    %rax,%rdi
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  call   <__builtin___memset_chk@plt>
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sink@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test_memfuncs_chk(void *s, unsigned n) {
  sink(0, __builtin___memcpy_chk(null(), s, n, n));
  sink(0, __builtin___memcpy_chk(s, null(), n, n));
  sink(0, __builtin___memmove_chk(null(), s, n, n));
  sink(0, __builtin___memmove_chk(s, null(), n, n));
  sink(0, __builtin___mempcpy_chk(null(), s, n, n));
  sink(0, __builtin___mempcpy_chk(s, null(), n, n));
  sink(0, __builtin___memset_chk(null(), 0, n, n));
}
```
user: What is the c source code of the assembly code below:

```asm
<test_memfuncs_chk>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___memcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___memcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___memmove_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___memmove_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___mempcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___mempcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <__builtin___memset_chk@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10e0 <sink@plt>
```

assistant: ```c
void test_memfuncs_chk(void *s, unsigned n) {
  sink(0, __builtin___memcpy_chk(null(), s, n, n));
  sink(0, __builtin___memcpy_chk(s, null(), n, n));
  sink(0, __builtin___memmove_chk(null(), s, n, n));
  sink(0, __builtin___memmove_chk(s, null(), n, n));
  sink(0, __builtin___mempcpy_chk(null(), s, n, n));
  sink(0, __builtin___mempcpy_chk(s, null(), n, n));
  sink(0, __builtin___memset_chk(null(), 0, n, n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_memfuncs_chk>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___memcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___memcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___memmove_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___memmove_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <__builtin___mempcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <__builtin___mempcpy_chk@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  call   <sink@plt>
  xor    %eax,%eax
  call   <null@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <__builtin___memset_chk@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    10e0 <sink@plt>
```

assistant: ```c
void test_memfuncs_chk(void *s, unsigned n) {
  sink(0, __builtin___memcpy_chk(null(), s, n, n));
  sink(0, __builtin___memcpy_chk(s, null(), n, n));
  sink(0, __builtin___memmove_chk(null(), s, n, n));
  sink(0, __builtin___memmove_chk(s, null(), n, n));
  sink(0, __builtin___mempcpy_chk(null(), s, n, n));
  sink(0, __builtin___mempcpy_chk(s, null(), n, n));
  sink(0, __builtin___memset_chk(null(), 0, n, n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D49(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <standard_swap@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <xor_swap@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string
name: disassemble_data
arguments: data_tag: D49
type_guessed: string
name: disassemble_data
arguments: data_tag: D37
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D42
type_guessed: string

tool: D6: one

tool: D49: two

tool: D37: initial state: %s, %s


tool: D26: standard swap: %s, %s


tool: D42: xor swap back: %s, %s


assistant: ```c
int main(int argc, char **argv) {
  char *a, *b;
  char *o, *t;
  o = "one";
  t = "two";
  a = o;
  b = t;
  printf("initial state: %s, %s\n", a, b);
  standard_swap(&a, &b);
  printf("standard swap: %s, %s\n", a, b);
  xor_swap(&a, &b);
  printf("xor swap back: %s, %s\n", a, b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rsi
  mov    %rsi,0x8(%rsp)
  lea    D4(%rip),%rdx
  mov    %rdx,0x10(%rsp)
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  lea    0x8(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <standard_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <xor_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D49
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string
name: extract_symbolic_data
arguments: tag: D30
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D49: one

tool: D4: two

tool: D30: initial state: %s, %s


tool: D25: standard swap: %s, %s


tool: D19: xor swap back: %s, %s


assistant: ```c
int main(int argc, char **argv) {
  char *a, *b;
  char *o, *t;
  o = "one";
  t = "two";
  a = o;
  b = t;
  printf("initial state: %s, %s\n", a, b);
  standard_swap(&a, &b);
  printf("standard swap: %s, %s\n", a, b);
  xor_swap(&a, &b);
  printf("xor swap back: %s, %s\n", a, b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D48(%rip),%rdx
  lea    D4(%rip),%rsi
  push   %rbp
  lea    D21(%rip),%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %rdx,0x10(%rsp)
  mov    %rsi,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <standard_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <xor_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D48
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D46
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D48: two

tool: D4: one

tool: D21: initial state: %s, %s


tool: D46: standard swap: %s, %s


tool: D7: xor swap back: %s, %s


assistant: ```c
int main(int argc, char **argv) {
  char *a, *b;
  char *o, *t;
  o = "one";
  t = "two";
  a = o;
  b = t;
  printf("initial state: %s, %s\n", a, b);
  standard_swap(&a, &b);
  printf("standard swap: %s, %s\n", a, b);
  xor_swap(&a, &b);
  printf("xor swap back: %s, %s\n", a, b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdx
  lea    D21(%rip),%rsi
  push   %rbp
  lea    D19(%rip),%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %rdx,0x10(%rsp)
  mov    %rsi,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <standard_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <xor_swap@plt>
  mov    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D49
datatype: string

tool: D22: two

tool: D21: one

tool: D19: initial state: %s, %s


tool: D17: standard swap: %s, %s


tool: D49: xor swap back: %s, %s


assistant: ```c
int main(int argc, char **argv) {
  char *a, *b;
  char *o, *t;
  o = "one";
  t = "two";
  a = o;
  b = t;
  printf("initial state: %s, %s\n", a, b);
  standard_swap(&a, &b);
  printf("standard swap: %s, %s\n", a, b);
  xor_swap(&a, &b);
  printf("xor swap back: %s, %s\n", a, b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CMPRegionHeapToHeap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x5,%eax
  cltd
  idivl  -0x14(%rbp)
  jmp    L3
L1:
  mov    -0x14(%rbp),%eax
L3:
  leave
  ret
```

assistant: ```c
int CMPRegionHeapToHeap() {
  int x = 0;
  int *x1 = malloc(8);
  int *x4 = x1;
  if (x1 == x4) {
    free(x1);
    return 5 / x;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CMPRegionHeapToHeap>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x5,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CMPRegionHeapToHeap() {
  int x = 0;
  int *x1 = malloc(8);
  int *x4 = x1;
  if (x1 == x4) {
    free(x1);
    return 5 / x;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CMPRegionHeapToHeap>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  ud2
```

assistant: ```c
int CMPRegionHeapToHeap() {
  int x = 0;
  int *x1 = malloc(8);
  int *x4 = x1;
  if (x1 == x4) {
    free(x1);
    return 5 / x;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kthSmallest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x1c(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <traverse@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int kthSmallest(struct TreeNode *root, int k) {
  int value = 0;
  traverse(root, &k, &value);
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<kthSmallest>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <traverse@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kthSmallest(struct TreeNode *root, int k) {
  int value = 0;
  traverse(root, &k, &value);
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kthSmallest>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <traverse@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kthSmallest(struct TreeNode *root, int k) {
  int value = 0;
  traverse(root, &k, &value);
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kthSmallest>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  call   <traverse@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kthSmallest(struct TreeNode *root, int k) {
  int value = 0;
  traverse(root, &k, &value);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ems_seti_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x34(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0xf,%edx
  mov    %rax,%rdi
  call   <cnfImpn@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <emsSeti@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void ems_seti_(char *const token, int *const ivalue, int token_length) {
  char ctok[15 + 1];

  cnfImpn(token, token_length, 15, ctok);
  emsSeti(ctok, *ivalue);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ems_seti_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  mov    $0xf,%edx
  call   <cnfImpn@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <emsSeti@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ems_seti_(char *const token, int *const ivalue, int token_length) {
  char ctok[15 + 1];

  cnfImpn(token, token_length, 15, ctok);
  emsSeti(ctok, *ivalue);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ems_seti_>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    $0xf,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <cnfImpn@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <emsSeti@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ems_seti_(char *const token, int *const ivalue, int token_length) {
  char ctok[15 + 1];

  cnfImpn(token, token_length, 15, ctok);
  emsSeti(ctok, *ivalue);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ems_seti_>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    $0xf,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rcx
  call   <cnfImpn@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <emsSeti@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ems_seti_(char *const token, int *const ivalue, int token_length) {
  char ctok[15 + 1];

  cnfImpn(token, token_length, 15, ctok);
  emsSeti(ctok, *ivalue);
  return;
}
```