ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<nth_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L96:
  cmp    %rdx,%rsp
  je     L52
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L96
L52:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L60
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L60:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x2,-0x38(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jg     L112
  mov    $0xffffffff,%eax
  jmp    L157
L112:
  cmpl   $0x1,-0x44(%rbp)
  jne    L3
  mov    $0x2,%eax
  jmp    L157
L3:
  cmpl   $0x2,-0x44(%rbp)
  jne    L142
  mov    $0x3,%eax
  jmp    L157
L142:
  mov    -0x20(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x20(%rbp),%rax
  movl   $0x3,0x4(%rax)
  movl   $0x3,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L147
L135:
  addl   $0x2,-0x34(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L87
L34:
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%ecx
  mov    -0x34(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L50
  movl   $0x0,-0x2c(%rbp)
  jmp    L15
L50:
  addl   $0x1,-0x30(%rbp)
L87:
  mov    -0x30(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L34
L15:
  cmpl   $0x0,-0x2c(%rbp)
  je     L147
  mov    -0x20(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x34(%rbp),%ecx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L147:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jne    L135
  mov    -0x38(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
L157:
  mov    %rsi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int nth_prime(int n) {
  int primes[n];
  int size = 2;
  if (n <= 0) {
    return -1;
  } else if (n == 1) {
    return 2;
  } else if (n == 2) {
    return 3;
  }
  primes[0] = 2;
  primes[1] = 3;
  int p = 3;
  int list_iter = 0;
  int isPrime = 0;
  while (size != n) {
    p += 2;
    isPrime = 1;
    for (list_iter = 0; list_iter < size; list_iter++) {
      if (p % primes[list_iter] == 0) {
        isPrime = 0;
        break;
      }
    }
    if (isPrime) {
      primes[size] = p;
      size++;
    }
  }
  return primes[size - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nth_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L44:
  cmp    %rdx,%rsp
  je     L130
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L44
L130:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L40
  orq    $0x0,-0x8(%rsp,%rax,1)
L40:
  lea    0x3(%rsp),%r10
  mov    %r10,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%r10
  test   %r9d,%r9d
  jle    L33
  cmp    $0x1,%r9d
  je     L154
  cmp    $0x2,%r9d
  je     L86
  movl   $0x2,0x0(,%rax,4)
  movl   $0x3,0x4(,%rax,4)
  mov    $0x3,%esi
  mov    $0x2,%r8d
  lea    0x4(%r10),%r11
  jmp    L27
L134:
  lea    -0x1(%r9),%eax
  cltq
  mov    (%r10,%rax,4),%eax
L81:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L77
  leave
  ret
L33:
  mov    $0xffffffff,%eax
  jmp    L81
L154:
  mov    $0x2,%eax
  jmp    L81
L86:
  mov    $0x3,%eax
  jmp    L81
L138:
  movslq %r8d,%rax
  mov    %esi,(%r10,%rax,4)
  add    $0x1,%r8d
L75:
  cmp    %r9d,%r8d
  je     L134
L27:
  add    $0x2,%esi
  test   %r8d,%r8d
  jle    L138
  mov    %r10,%rcx
  lea    -0x1(%r8),%eax
  lea    (%r11,%rax,4),%rdi
L73:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  je     L75
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L73
  jmp    L138
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nth_prime(int n) {
  int primes[n];
  int size = 2;
  if (n <= 0) {
    return -1;
  } else if (n == 1) {
    return 2;
  } else if (n == 2) {
    return 3;
  }
  primes[0] = 2;
  primes[1] = 3;
  int p = 3;
  int list_iter = 0;
  int isPrime = 0;
  while (size != n) {
    p += 2;
    isPrime = 1;
    for (list_iter = 0; list_iter < size; list_iter++) {
      if (p % primes[list_iter] == 0) {
        isPrime = 0;
        break;
      }
    }
    if (isPrime) {
      primes[size] = p;
      size++;
    }
  }
  return primes[size - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nth_prime>:
  endbr64
  push   %rbp
  mov    %edi,%r9d
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L73
L151:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L151
L73:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L107
L153:
  lea    0x3(%rsp),%r10
  mov    %r10,%rax
  and    $0xfffffffffffffffc,%r10
  shr    $0x2,%rax
  test   %r9d,%r9d
  jle    L82
  cmp    $0x1,%r9d
  je     L134
  cmp    $0x2,%r9d
  je     L133
  mov    $0x3,%esi
  mov    $0x2,%r8d
  lea    0x4(%r10),%r11
  movabs $0x300000002,%rdi
  mov    %rdi,0x0(,%rax,4)
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x2,%esi
  test   %r8d,%r8d
  jle    L20
  lea    -0x1(%r8),%eax
  mov    %r10,%rcx
  lea    (%r11,%rax,4),%rdi
  jmp    L33
  nopl   (%rax)
L160:
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  je     L20
L33:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  jne    L160
  cmp    %r9d,%r8d
  jne    L6
L125:
  lea    -0x1(%r8),%eax
  cltq
  mov    (%r10,%rax,4),%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L137
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%r10,%rax,4)
  cmp    %r9d,%r8d
  jne    L6
  jmp    L125
L107:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L153
L134:
  mov    $0x2,%eax
  jmp    L0
L133:
  mov    $0x3,%eax
  jmp    L0
L82:
  mov    $0xffffffff,%eax
  jmp    L0
L137:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nth_prime(int n) {
  int primes[n];
  int size = 2;
  if (n <= 0) {
    return -1;
  } else if (n == 1) {
    return 2;
  } else if (n == 2) {
    return 3;
  }
  primes[0] = 2;
  primes[1] = 3;
  int p = 3;
  int list_iter = 0;
  int isPrime = 0;
  while (size != n) {
    p += 2;
    isPrime = 1;
    for (list_iter = 0; list_iter < size; list_iter++) {
      if (p % primes[list_iter] == 0) {
        isPrime = 0;
        break;
      }
    }
    if (isPrime) {
      primes[size] = p;
      size++;
    }
  }
  return primes[size - 1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nth_prime>:
  endbr64
  push   %rbp
  mov    %edi,%r9d
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L111
L170:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L170
L111:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L151
L126:
  lea    0x3(%rsp),%r10
  mov    %r10,%rdx
  and    $0xfffffffffffffffc,%r10
  shr    $0x2,%rdx
  test   %r9d,%r9d
  jle    L72
  cmp    $0x1,%r9d
  je     L99
  cmp    $0x2,%r9d
  je     L10
  mov    D8(%rip),%rax
  mov    $0x3,%esi
  mov    $0x2,%r8d
  lea    0x4(%r10),%r11
  mov    %rax,0x0(,%rdx,4)
  nopl   0x0(%rax,%rax,1)
L106:
  add    $0x2,%esi
  test   %r8d,%r8d
  jle    L63
  lea    -0x1(%r8),%eax
  mov    %r10,%rcx
  lea    (%r11,%rax,4),%rdi
  jmp    L173
  nopl   (%rax)
L86:
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  je     L63
L173:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  jne    L86
  cmp    %r9d,%r8d
  jne    L106
L0:
  lea    -0x1(%r8),%eax
  cltq
  mov    (%r10,%rax,4),%eax
L68:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  movslq %r8d,%rax
  add    $0x1,%r8d
  mov    %esi,(%r10,%rax,4)
  cmp    %r9d,%r8d
  jne    L106
  jmp    L0
L151:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L126
L99:
  mov    $0x2,%eax
  jmp    L68
L10:
  mov    $0x3,%eax
  jmp    L68
L72:
  mov    $0xffffffff,%eax
  jmp    L68
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type: byte[8]

tool: {"D8": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int nth_prime(int n) {
  int primes[n];
  int size = 2;
  if (n <= 0) {
    return -1;
  } else if (n == 1) {
    return 2;
  } else if (n == 2) {
    return 3;
  }
  primes[0] = 2;
  primes[1] = 3;
  int p = 3;
  int list_iter = 0;
  int isPrime = 0;
  while (size != n) {
    p += 2;
    isPrime = 1;
    for (list_iter = 0; list_iter < size; list_iter++) {
      if (p % primes[list_iter] == 0) {
        isPrime = 0;
        break;
      }
    }
    if (isPrime) {
      primes[size] = p;
      size++;
    }
  }
  return primes[size - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8cspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L30
L111:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L83
L122:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L127
  cmpq   $0x0,-0x8(%rbp)
  je     L127
  mov    -0x18(%rbp),%rax
  jmp    L109
L127:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L112
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L83
L112:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L112
  movq   $0x0,-0x8(%rbp)
L83:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L122
  cmpq   $0x0,-0x8(%rbp)
  je     L114
  mov    -0x18(%rbp),%rax
  jmp    L109
L114:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L114
  addq   $0x1,-0x18(%rbp)
L30:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L111
  mov    -0x18(%rbp),%rax
L109:
  pop    %rbp
  ret
```

assistant: ```c
size_t utf8cspn(const void *src, const void *reject) {
  const char *s = (const char *)src;
  size_t chars = 0;
  while ('\0' != *s) {
    const char *r = (const char *)reject;
    size_t offset = 0;
    while ('\0' != *r) {
      if ((0x80 != (0xc0 & *r)) && (0 < offset)) {
        return chars;
      } else {
        if (*r == s[offset]) {
          offset++;
          r++;
        } else {
          do {
            r++;
          } while (0x80 == (0xc0 & *r));
          offset = 0;
        }
      }
    }
    if (0 < offset) {
      return chars;
    }
    do {
      s++;
    } while ((0x80 == (0xc0 & *s)));
    chars++;
  }
  return chars;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<utf8cspn>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L131
  movzbl (%rsi),%r9d
  mov    $0x0,%r10d
  jmp    L64
L133:
  add    $0x1,%rdx
  movsbl (%rdx),%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L133
  movzbl (%rdx),%eax
  test   %al,%al
  je     L20
  mov    %rdx,%r8
  mov    $0x0,%ecx
L138:
  mov    %r8,%rdx
L106:
  cmp    %al,(%rdi,%rcx,1)
  jne    L133
  add    $0x1,%rcx
  lea    0x1(%rdx),%r8
  movzbl 0x1(%rdx),%eax
  test   %al,%al
  je     L26
  mov    %eax,%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L138
  test   %rcx,%rcx
  je     L138
L78:
  mov    %r10,%rax
  ret
L26:
  test   %rcx,%rcx
  jne    L78
L20:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L20
  add    $0x1,%r10
  test   %al,%al
  je     L78
L64:
  mov    %rsi,%rdx
  mov    %r9d,%eax
  mov    $0x0,%ecx
  test   %r9b,%r9b
  jne    L106
  jmp    L20
L131:
  mov    $0x0,%r10d
  jmp    L78
```

assistant: ```c
size_t utf8cspn(const void *src, const void *reject) {
  const char *s = (const char *)src;
  size_t chars = 0;
  while ('\0' != *s) {
    const char *r = (const char *)reject;
    size_t offset = 0;
    while ('\0' != *r) {
      if ((0x80 != (0xc0 & *r)) && (0 < offset)) {
        return chars;
      } else {
        if (*r == s[offset]) {
          offset++;
          r++;
        } else {
          do {
            r++;
          } while (0x80 == (0xc0 & *r));
          offset = 0;
        }
      }
    }
    if (0 < offset) {
      return chars;
    }
    do {
      s++;
    } while ((0x80 == (0xc0 & *s)));
    chars++;
  }
  return chars;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<utf8cspn>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L82
  movzbl (%rsi),%r9d
  xor    %r10d,%r10d
L90:
  mov    %rsi,%rax
  mov    %r9d,%edx
  xor    %ecx,%ecx
  test   %r9b,%r9b
  je     L84
  nopl   0x0(%rax)
L74:
  cmp    %dl,(%rdi,%rcx,1)
  jne    L25
L80:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L40
  mov    %edx,%r8d
  and    $0xc0,%r8d
  cmp    $0x80,%r8d
  je     L44
  test   %rcx,%rcx
  jne    L113
L44:
  add    $0x1,%rax
  cmp    %dl,(%rdi,%rcx,1)
  je     L80
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  mov    %edx,%ecx
  and    $0xc0,%ecx
  cmp    $0x80,%ecx
  je     L25
  test   %dl,%dl
  je     L84
  xor    %ecx,%ecx
  jmp    L74
L40:
  test   %rcx,%rcx
  jne    L113
  nopl   (%rax)
L84:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  mov    %eax,%edx
  and    $0xc0,%edx
  cmp    $0x80,%edx
  je     L84
  add    $0x1,%r10
  test   %al,%al
  jne    L90
L113:
  mov    %r10,%rax
  ret
L82:
  xor    %r10d,%r10d
  jmp    L113
```

assistant: ```c
size_t utf8cspn(const void *src, const void *reject) {
  const char *s = (const char *)src;
  size_t chars = 0;
  while ('\0' != *s) {
    const char *r = (const char *)reject;
    size_t offset = 0;
    while ('\0' != *r) {
      if ((0x80 != (0xc0 & *r)) && (0 < offset)) {
        return chars;
      } else {
        if (*r == s[offset]) {
          offset++;
          r++;
        } else {
          do {
            r++;
          } while (0x80 == (0xc0 & *r));
          offset = 0;
        }
      }
    }
    if (0 < offset) {
      return chars;
    }
    do {
      s++;
    } while ((0x80 == (0xc0 & *s)));
    chars++;
  }
  return chars;
}
```
user: What is the c source code of the assembly code below:

```asm
<utf8cspn>:
  endbr64
  movzbl (%rdi),%r9d
  test   %r9b,%r9b
  je     L105
  movzbl (%rsi),%r10d
  xor    %r11d,%r11d
L54:
  test   %r10b,%r10b
  je     L91
  mov    %r9d,%r8d
  mov    %rsi,%rax
  mov    %r10d,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L95:
  cmp    %r8b,%dl
  jne    L31
L94:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L69
  mov    %edx,%r8d
  and    $0xc0,%r8d
  cmp    $0x80,%r8d
  je     L57
  test   %rcx,%rcx
  jne    L59
L57:
  movzbl (%rdi,%rcx,1),%r8d
  add    $0x1,%rax
  cmp    %r8b,%dl
  je     L94
  nopw   0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  mov    %edx,%ecx
  and    $0xc0,%ecx
  cmp    $0x80,%ecx
  je     L31
  test   %dl,%dl
  je     L91
  mov    %r9d,%r8d
  xor    %ecx,%ecx
  jmp    L95
L69:
  test   %rcx,%rcx
  jne    L59
  nopl   0x0(%rax,%rax,1)
L91:
  movzbl 0x1(%rdi),%r9d
  add    $0x1,%rdi
  mov    %r9d,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L91
  add    $0x1,%r11
  test   %r9b,%r9b
  jne    L54
L59:
  mov    %r11,%rax
  ret
L105:
  xor    %r11d,%r11d
  jmp    L59
```

assistant: ```c
size_t utf8cspn(const void *src, const void *reject) {
  const char *s = (const char *)src;
  size_t chars = 0;
  while ('\0' != *s) {
    const char *r = (const char *)reject;
    size_t offset = 0;
    while ('\0' != *r) {
      if ((0x80 != (0xc0 & *r)) && (0 < offset)) {
        return chars;
      } else {
        if (*r == s[offset]) {
          offset++;
          r++;
        } else {
          do {
            r++;
          } while (0x80 == (0xc0 & *r));
          offset = 0;
        }
      }
    }
    if (0 < offset) {
      return chars;
    }
    do {
      s++;
    } while ((0x80 == (0xc0 & *s)));
    chars++;
  }
  return chars;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<roadmap_option_height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <roadmap_option_get_geometry@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0xc8,%eax
  jmp    L6
L9:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L6:
  leave
  ret
```

assistant: ```c
int roadmap_option_height(const char *name) {
  const char *option = roadmap_option_get_geometry(name);
  char *separator;
  separator = strchr(option, 'x');
  if (separator == NULL) {
    return 200;
  }
  return atoi(separator + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<roadmap_option_height>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_option_get_geometry@plt>
  mov    %rax,%rdi
  mov    $0x78,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
L0:
  add    $0x8,%rsp
  ret
L12:
  mov    $0xc8,%eax
  jmp    L0
```

assistant: ```c
int roadmap_option_height(const char *name) {
  const char *option = roadmap_option_get_geometry(name);
  char *separator;
  separator = strchr(option, 'x');
  if (separator == NULL) {
    return 200;
  }
  return atoi(separator + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<roadmap_option_height>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_option_get_geometry@plt>
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  lea    0x1(%rax),%rdi
  add    $0x8,%rsp
  jmp    1090 <atoi@plt>
  nopl   0x0(%rax)
L9:
  mov    $0xc8,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int roadmap_option_height(const char *name) {
  const char *option = roadmap_option_get_geometry(name);
  char *separator;
  separator = strchr(option, 'x');
  if (separator == NULL) {
    return 200;
  }
  return atoi(separator + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<roadmap_option_height>:
  endbr64
  sub    $0x8,%rsp
  call   <roadmap_option_get_geometry@plt>
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L4
  lea    0x1(%rax),%rdi
  add    $0x8,%rsp
  jmp    1090 <atoi@plt>
  nopl   0x0(%rax)
L4:
  mov    $0xc8,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int roadmap_option_height(const char *name) {
  const char *option = roadmap_option_get_geometry(name);
  char *separator;
  separator = strchr(option, 'x');
  if (separator == NULL) {
    return 200;
  }
  return atoi(separator + 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cwk_path_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cwk_path_join_and_normalize_multiple@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
size_t cwk_path_join(const char *path_a, const char *path_b, char *buffer, size_t buffer_size) {
  const char *paths[3];
  paths[0] = path_a;
  paths[1] = path_b;
  paths[2] = NULL;
  return cwk_path_join_and_normalize_multiple(paths, buffer, buffer_size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cwk_path_join>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  mov    %rdi,(%rsp)
  mov    %rax,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  call   <cwk_path_join_and_normalize_multiple@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t cwk_path_join(const char *path_a, const char *path_b, char *buffer, size_t buffer_size) {
  const char *paths[3];
  paths[0] = path_a;
  paths[1] = path_b;
  paths[2] = NULL;
  return cwk_path_join_and_normalize_multiple(paths, buffer, buffer_size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cwk_path_join>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%r8
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    %rsp,%rdi
  mov    %r8,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <cwk_path_join_and_normalize_multiple@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t cwk_path_join(const char *path_a, const char *path_b, char *buffer, size_t buffer_size) {
  const char *paths[3];
  paths[0] = path_a;
  paths[1] = path_b;
  paths[2] = NULL;
  return cwk_path_join_and_normalize_multiple(paths, buffer, buffer_size);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cwk_path_join>:
  endbr64
  mov    %rsi,%r8
  sub    $0x28,%rsp
  movq   %rdi,%xmm0
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %r8,%xmm1
  mov    %rcx,%rdx
  mov    %rsp,%rdi
  movq   $0x0,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <cwk_path_join_and_normalize_multiple@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t cwk_path_join(const char *path_a, const char *path_b, char *buffer, size_t buffer_size) {
  const char *paths[3];
  paths[0] = path_a;
  paths[1] = path_b;
  paths[2] = NULL;
  return cwk_path_join_and_normalize_multiple(paths, buffer, buffer_size);
}
```