user: 下面的汇编指令对应的C源代码是什么:

```asm
<booth>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  mov    %esi,%r13d
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    D99(%rip),%rdi
  call   <puts@plt>
  lea    D68(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  add    %ebx,%ebx
  and    $0x1fe,%ebx
  mov    %ebx,%ecx
  mov    %r13d,%edx
  lea    D61(%rip),%rsi
  mov    $0x0,%edi
  call   <println@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r13d,%eax
  shl    $0x9,%eax
  and    $0x1fe00,%eax
  mov    %eax,0x8(%rsp)
  mov    %r13d,%eax
  neg    %eax
  shl    $0x9,%eax
  and    $0x1fe00,%eax
  mov    %eax,0x4(%rsp)
  mov    $0x1,%r12d
  lea    D53(%rip),%r15
  lea    D45(%rip),%r14
  jmp    L37
L57:
  add    0x8(%rsp),%ebx
  mov    %ebx,%ecx
  mov    %r13d,%edx
  lea    D15(%rip),%rsi
  mov    %r12d,%edi
  call   <println@plt>
  jmp    L19
L11:
  add    0x4(%rsp),%ebx
  mov    %ebx,%ecx
  mov    %r13d,%edx
  lea    D22(%rip),%rsi
  mov    %r12d,%edi
  call   <println@plt>
L19:
  mov    %ebx,%ebp
  and    $0x1ffff,%ebp
  lea    0x20000(%rbp),%eax
  test   $0x10000,%ebx
  cmovne %eax,%ebp
  mov    %ebp,%ebx
  shr    %ebx
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <println@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r12d
  cmp    $0x9,%r12d
  je     L16
L37:
  mov    %ebx,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L57
  cmp    $0x2,%eax
  je     L11
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r12d,%edi
  call   <println@plt>
  jmp    L19
L16:
  mov    0xc(%rsp),%esi
  imul   %r13d,%esi
  lea    D84(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  shr    $0x2,%edi
  mov    $0x20,%edx
  mov    $0x0,%esi
  call   <printbin@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D62
type_guessed: string
name: extract_symbolic_data
arguments: tag: D99
type_guessed: string
name: extract_symbolic_data
arguments: tag: D68
type_guessed: string
name: extract_symbolic_data
arguments: tag: D61
type_guessed: string
name: extract_symbolic_data
arguments: tag: D53
type_guessed: string
name: extract_symbolic_data
arguments: tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: tag: D84
type_guessed: string

tool: D62: 
____________________________________________________________________________________________________________________

tool: D99: | Iteration  |     Operation    | 		Multiplicand		 |    		 Product 		   |

tool: D68: |____________|__________________|________________________________________|_________________________________________|

tool: D61: Initialization

tool: D53: No Operation

tool: D45: Shift Right

tool: D15: prod=prod+mcand

tool: D22: prod=prod-mcand

tool: D84: 

The answer is: %d

Binary: 

assistant: ```c
void booth(unsigned int multiplier, int multiplicand) {
  unsigned int product = multiplier;
  product &= 0xFF;
  printf("\n____________________________________________________________________________________________________________________\n");
  printf("| Iteration  |     Operation    | \t\tMultiplicand\t\t |    \t\t Product \t\t   |\n");
  printf("|____________|__________________|________________________________________|_________________________________________|\n");
  product <<= 1;
  println(0, "Initialization", multiplicand, product);
  printf("|____________|__________________|________________________________________|_________________________________________|\n");
  unsigned int add = (multiplicand << (8 + 1)) & 130560;
  unsigned int sub = (-multiplicand << (8 + 1)) & 130560;
  for (int i = 1; i <= 8; i++) {
    if ((product & 3) == 1) {
      product += add;
      println(i, "prod=prod+mcand", multiplicand, product);
    } else if ((product & 3) == 2) {
      product += sub;
      println(i, "prod=prod-mcand", multiplicand, product);
    } else
      println(i, "No Operation", multiplicand, product);
    product &= 0x1FFFF;
    if ((product & 65536) == 65536)
      product += 131072;
    product >>= 1;
    println(i, "Shift Right", multiplicand, product);
    printf("|____________|__________________|________________________________________|_________________________________________|\n");
  }
  product = product >> 1;
  int val = product;
  printf("\n\nThe answer is: %d\n\nBinary: ", multiplicand * multiplier);
  printbin(product, 0, 32);
}
```