ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<prependToPath>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  call   <getenv@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r15d
  movslq %r15d,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    %r15,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
L17:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlcpy@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: :

assistant: ```c
int prependToPath(const char *name, const char *prepend) {
  const char *old_value = getenv(name);
  char *new_value = NULL;
  if (old_value == NULL) {
    size_t max_length = strlen(prepend) + 1;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
  } else {
    size_t max_length = strlen(old_value) + strlen(prepend) + 2;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
    strlcat(new_value, ":", max_length);
    strlcat(new_value, old_value, max_length);
  }
  setenv(name, new_value, 1);
  free(new_value);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prependToPath>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r15d
  movslq %r15d,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    %r15,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
L19:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlcpy@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: :

assistant: ```c
int prependToPath(const char *name, const char *prepend) {
  const char *old_value = getenv(name);
  char *new_value = NULL;
  if (old_value == NULL) {
    size_t max_length = strlen(prepend) + 1;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
  } else {
    size_t max_length = strlen(old_value) + strlen(prepend) + 2;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
    strlcat(new_value, ":", max_length);
    strlcat(new_value, old_value, max_length);
  }
  setenv(name, new_value, 1);
  free(new_value);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D52
type_guessed: string

tool: D2:  ___

tool: D1: %s


tool: D52: |___|

assistant: ```c
void test_display() {
  printf("%s\n", " ___");
  printf("%s\n", "|___|");
  printf("%s\n", "|___|");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_display>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D10(%rip),%rsi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D10:  ___

tool: D11: %s


tool: D18: |___|

assistant: ```c
void test_display() {
  printf("%s\n", " ___");
  printf("%s\n", "|___|");
  printf("%s\n", "|___|");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_display>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  lea    D10(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D23
datatype: string

tool: D4:  ___

tool: D10: |___|

tool: D23: %s


assistant: ```c
void test_display() {
  printf("%s\n", " ___");
  printf("%s\n", "|___|");
  printf("%s\n", "|___|");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_display>:
  endbr64
  push   %r12
  lea    D25(%rip),%rsi
  lea    D20(%rip),%r12
  push   %rbp
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D25:  ___

tool: D20: |___|

tool: D17: %s


assistant: ```c
void test_display() {
  printf("%s\n", " ___");
  printf("%s\n", "|___|");
  printf("%s\n", "|___|");
}
```
user: Translate the below assembly code into C programming language:

```asm
<ResetCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  movzbl -0x8(%rbp),%eax
  cmp    $0x68,%eax
  je     L6
  cmp    $0x68,%eax
  jg     L89
  cmp    $0x40,%eax
  je     L19
  cmp    $0x40,%eax
  jg     L89
  cmp    $0x28,%eax
  je     L107
  cmp    $0x28,%eax
  jg     L89
  cmp    $0x8,%eax
  je     L38
  cmp    $0x20,%eax
  je     L3
  jmp    L89
L38:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ResetTachoCount@plt>
  jmp    L89
L3:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ResetBlockTachoCount@plt>
  jmp    L89
L19:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ResetRotationCount@plt>
  jmp    L89
L107:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ResetBlockAndTachoCount@plt>
  jmp    L89
L6:
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ResetAllTachoCounts@plt>
  nop
L89:
  leave
  ret
```

assistant: ```c
void ResetCount(unsigned char Outputs, unsigned char reset) {
  switch (reset) {
  case 0x08:
    ResetTachoCount(Outputs);
    return;
  case 0x20:
    ResetBlockTachoCount(Outputs);
    return;
  case 0x40:
    ResetRotationCount(Outputs);
    return;
  case 0x28:
    ResetBlockAndTachoCount(Outputs);
    return;
  case 0x68:
    ResetAllTachoCounts(Outputs);
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ResetCount>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x28,%sil
  je     L28
  jbe    L5
  cmp    $0x40,%sil
  je     L57
  cmp    $0x68,%sil
  jne    L54
  movzbl %dil,%edi
  call   <ResetAllTachoCounts@plt>
  jmp    L54
L5:
  cmp    $0x8,%sil
  je     L39
  cmp    $0x20,%sil
  jne    L54
  movzbl %dil,%edi
  call   <ResetBlockTachoCount@plt>
  jmp    L54
L39:
  movzbl %dil,%edi
  call   <ResetTachoCount@plt>
L54:
  add    $0x8,%rsp
  ret
L57:
  movzbl %dil,%edi
  call   <ResetRotationCount@plt>
  jmp    L54
L28:
  movzbl %dil,%edi
  call   <ResetBlockAndTachoCount@plt>
  jmp    L54
```

assistant: ```c
void ResetCount(unsigned char Outputs, unsigned char reset) {
  switch (reset) {
  case 0x08:
    ResetTachoCount(Outputs);
    return;
  case 0x20:
    ResetBlockTachoCount(Outputs);
    return;
  case 0x40:
    ResetRotationCount(Outputs);
    return;
  case 0x28:
    ResetBlockAndTachoCount(Outputs);
    return;
  case 0x68:
    ResetAllTachoCounts(Outputs);
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ResetCount>:
  endbr64
  cmp    $0x28,%sil
  je     L55
  jbe    L34
  cmp    $0x40,%sil
  je     L45
  cmp    $0x68,%sil
  jne    L56
  movzbl %dil,%edi
  jmp    10d0 <ResetAllTachoCounts@plt>
  nopl   0x0(%rax)
L34:
  cmp    $0x8,%sil
  je     L36
  cmp    $0x20,%sil
  jne    L57
  movzbl %dil,%edi
  jmp    10b0 <ResetBlockTachoCount@plt>
  nopl   (%rax)
L55:
  movzbl %dil,%edi
  jmp    10c0 <ResetBlockAndTachoCount@plt>
  nopl   0x0(%rax)
L45:
  movzbl %dil,%edi
  jmp    10a0 <ResetRotationCount@plt>
  nopl   0x0(%rax)
L36:
  movzbl %dil,%edi
  jmp    1090 <ResetTachoCount@plt>
L56:
  ret
L57:
  ret
```

assistant: ```c
void ResetCount(unsigned char Outputs, unsigned char reset) {
  switch (reset) {
  case 0x08:
    ResetTachoCount(Outputs);
    return;
  case 0x20:
    ResetBlockTachoCount(Outputs);
    return;
  case 0x40:
    ResetRotationCount(Outputs);
    return;
  case 0x28:
    ResetBlockAndTachoCount(Outputs);
    return;
  case 0x68:
    ResetAllTachoCounts(Outputs);
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ResetCount>:
  endbr64
  cmp    $0x28,%sil
  je     L57
  jbe    L27
  cmp    $0x40,%sil
  je     L41
  cmp    $0x68,%sil
  jne    L45
  movzbl %dil,%edi
  jmp    10d0 <ResetAllTachoCounts@plt>
  nopl   0x0(%rax)
L27:
  cmp    $0x8,%sil
  je     L20
  cmp    $0x20,%sil
  jne    L25
  movzbl %dil,%edi
  jmp    10b0 <ResetBlockTachoCount@plt>
  nopl   (%rax)
L57:
  movzbl %dil,%edi
  jmp    10c0 <ResetBlockAndTachoCount@plt>
  nopl   0x0(%rax)
L41:
  movzbl %dil,%edi
  jmp    10a0 <ResetRotationCount@plt>
  nopl   0x0(%rax)
L20:
  movzbl %dil,%edi
  jmp    1090 <ResetTachoCount@plt>
L45:
  ret
L25:
  ret
```

assistant: ```c
void ResetCount(unsigned char Outputs, unsigned char reset) {
  switch (reset) {
  case 0x08:
    ResetTachoCount(Outputs);
    return;
  case 0x20:
    ResetBlockTachoCount(Outputs);
    return;
  case 0x40:
    ResetRotationCount(Outputs);
    return;
  case 0x28:
    ResetBlockAndTachoCount(Outputs);
    return;
  case 0x68:
    ResetAllTachoCounts(Outputs);
    return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<multiply42>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L4
L29:
  movl   $0x0,-0x3c(%rbp)
  jmp    L19
L37:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L19:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L37
  addl   $0x1,-0x40(%rbp)
L4:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L29
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply42(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply42>:
  endbr64
  test   %edi,%edi
  jle    L20
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L26:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L2:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L2
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  ret
```

assistant: ```c
void multiply42(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply42>:
  endbr64
  test   %edi,%edi
  jle    L27
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L9
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L2
  pop    %rbx
  ret
L27:
  ret
```

assistant: ```c
void multiply42(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply42>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L95
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L8:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L81
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L81
  nopl   0x0(%rax)
L72:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L72
  cmp    -0x24(%rsp),%r11d
  je     L63
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L63
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L63
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L63:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L8
L95:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L71:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L71
  mov    -0x18(%rsp),%r8
  jmp    L63
```

assistant: ```c
void multiply42(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<unespcape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L57
L56:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L43
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L43
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  addq   $0x4,-0x18(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L16
L43:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L16:
  addl   $0x1,-0x1c(%rbp)
L57:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: %2x

assistant: ```c
int unespcape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<unespcape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  je     L51
  mov    %rsi,%rbp
  add    $0x1,%rdi
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r14
  lea    D8(%rip),%r13
  mov    $0x1,%r12d
  sub    %edi,%r12d
  jmp    L43
L48:
  add    $0x1,%rbp
L25:
  mov    %al,-0x1(%rbx)
  lea    (%r12,%rbx,1),%edx
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L45
L43:
  cmp    $0x5c,%al
  jne    L48
  cmpb   $0x78,0x1(%rbp)
  jne    L48
  lea    0x2(%rbp),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  call   <sscanf@plt>
  add    $0x4,%rbp
  movzbl 0x4(%rsp),%eax
  jmp    L25
L51:
  mov    $0x0,%edx
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D8: %2x

assistant: ```c
int unespcape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unespcape>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%eax
  test   %al,%al
  je     L7
  mov    $0x1,%r12d
  mov    %rsi,%rbp
  lea    0x4(%rsp),%r14
  mov    %rdi,%rbx
  lea    D3(%rip),%r13
  sub    %edi,%r12d
  jmp    L66
  nopl   0x0(%rax)
L29:
  add    $0x1,%rbp
L62:
  mov    %al,(%rbx)
  movzbl 0x0(%rbp),%eax
  lea    (%r12,%rbx,1),%r8d
  add    $0x1,%rbx
  test   %al,%al
  je     L61
L66:
  cmp    $0x5c,%al
  jne    L29
  cmpb   $0x78,0x1(%rbp)
  jne    L29
  lea    0x2(%rbp),%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  add    $0x4,%rbp
  call   <sscanf@plt>
  movzbl 0x4(%rsp),%eax
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: %2x

assistant: ```c
int unespcape(char *_dst, char *_src, size_t len) {
  int ret = 0;
  char *src = _src;
  char *dst = _dst;
  unsigned int ch;
  while (*src) {
    if (*src == '\\' && *(src + 1) == 'x') {
      sscanf(src + 2, "%2x", &ch);
      src += 4;
      *dst++ = (unsigned char)ch;
    } else {
      *dst++ = *src++;
    }
    ret++;
  }
  return ret;
}
```