ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<debug>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: %ld 

assistant: ```c
void debug(long *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%ld ", a[i]);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<debug>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: %ld 

assistant: ```c
void debug(long *a, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%ld ", a[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<httpsqs_maxqueue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x188,%rsp
  mov    %rdi,-0x188(%rbp)
  mov    %rsi,-0x190(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x174(%rbp)
  movl   $0x0,-0x170(%rbp)
  mov    -0x188(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x190(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x23,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x168(%rbp)
  mov    -0x190(%rbp),%rcx
  mov    -0x188(%rbp),%rdx
  mov    -0x168(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x168(%rbp),%rax
  mov    %rax,%rdi
  call   <http_get@plt>
  mov    %eax,-0x16c(%rbp)
  mov    -0x168(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L50
L17:
  cmpl   $0x6,-0x170(%rbp)
  jle    L20
  movzbl -0x153(%rbp),%edx
  mov    -0x174(%rbp),%eax
  cltq
  mov    %dl,-0x150(%rbp,%rax,1)
  addl   $0x1,-0x174(%rbp)
L20:
  movzbl -0x153(%rbp),%eax
  cmp    $0xa,%al
  jne    L50
  addl   $0x1,-0x170(%rbp)
L50:
  lea    -0x153(%rbp),%rcx
  mov    -0x16c(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L17
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  mov    -0x174(%rbp),%eax
  cltq
  movb   $0x0,-0x150(%rbp,%rax,1)
L18:
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x160(%rbp)
  lea    -0x150(%rbp),%rdx
  mov    -0x160(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x160(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D19
type_infered: string

tool: D6: utf-8

tool: D19: /?charset=%s&name=%s&opt=maxqueue&num=%s

assistant: ```c
char *httpsqs_maxqueue(char *name, char *num) {
  char data[3];
  int sock;
  char *query;
  char max[300];
  int i = 0, j = 0;
  char *fs;
  query = (char *)malloc((strlen(name) + strlen(num) + strlen("utf-8") + 35) * sizeof(char));
  sprintf(query, "/?charset=%s&name=%s&opt=maxqueue&num=%s", "utf-8", name, num);
  sock = http_get(query);
  free(query);
  while (read(sock, data, 1) > 0) {
    if (j >= 7) {
      max[i] = data[0];
      i++;
    }
    if (data[0] == '\n') {
      j++;
    }
  }
  if (strlen(max) > 0) {
    max[i] = '\0';
  }
  fs = (char *)malloc(strlen(max) * sizeof(char));
  strcpy(fs, max);
  return fs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<httpsqs_maxqueue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  lea    D6(%rip),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x23(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %r13,%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <http_get@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    0xd(%rsp),%r13
  jmp    L24
L12:
  cmpb   $0xa,0xd(%rsp)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
L24:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jle    L8
  cmp    $0x6,%ebx
  jle    L12
  movslq %ebp,%rax
  movzbl 0xd(%rsp),%edx
  mov    %dl,0x10(%rsp,%rax,1)
  add    $0x1,%ebp
  jmp    L12
L8:
  lea    0x10(%rsp),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L36
  movslq %ebp,%rbp
  movb   $0x0,0x10(%rsp,%rbp,1)
L36:
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %rbx,%rax
  add    $0x158,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string

tool: D6: utf-8

tool: D19: /?charset=%s&name=%s&opt=maxqueue&num=%s

assistant: ```c
char *httpsqs_maxqueue(char *name, char *num) {
  char data[3];
  int sock;
  char *query;
  char max[300];
  int i = 0, j = 0;
  char *fs;
  query = (char *)malloc((strlen(name) + strlen(num) + strlen("utf-8") + 35) * sizeof(char));
  sprintf(query, "/?charset=%s&name=%s&opt=maxqueue&num=%s", "utf-8", name, num);
  sock = http_get(query);
  free(query);
  while (read(sock, data, 1) > 0) {
    if (j >= 7) {
      max[i] = data[0];
      i++;
    }
    if (data[0] == '\n') {
      j++;
    }
  }
  if (strlen(max) > 0) {
    max[i] = '\0';
  }
  fs = (char *)malloc(strlen(max) * sizeof(char));
  strcpy(fs, max);
  return fs;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<httpsqs_maxqueue>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    0x23(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %rax,%rbp
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0xd(%rsp),%r13
  call   <http_get@plt>
  mov    %rbp,%rdi
  xor    %ebp,%ebp
  mov    %eax,%r12d
  call   <free@plt>
  jmp    L15
  xchg   %ax,%ax
L43:
  cmp    $0x6,%ebx
  jle    L12
  movzbl 0xd(%rsp),%edx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %dl,0x10(%rsp,%rax,1)
L12:
  xor    %eax,%eax
  cmpb   $0xa,0xd(%rsp)
  sete   %al
  add    %eax,%ebx
L15:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L43
  lea    0x10(%rsp),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  movslq %ebp,%rbp
  movb   $0x0,0x10(%rsp,%rbp,1)
L13:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x150,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D0: utf-8

tool: D19: /?charset=%s&name=%s&opt=maxqueue&num=%s

assistant: ```c
char *httpsqs_maxqueue(char *name, char *num) {
  char data[3];
  int sock;
  char *query;
  char max[300];
  int i = 0, j = 0;
  char *fs;
  query = (char *)malloc((strlen(name) + strlen(num) + strlen("utf-8") + 35) * sizeof(char));
  sprintf(query, "/?charset=%s&name=%s&opt=maxqueue&num=%s", "utf-8", name, num);
  sock = http_get(query);
  free(query);
  while (read(sock, data, 1) > 0) {
    if (j >= 7) {
      max[i] = data[0];
      i++;
    }
    if (data[0] == '\n') {
      j++;
    }
  }
  if (strlen(max) > 0) {
    max[i] = '\0';
  }
  fs = (char *)malloc(strlen(max) * sizeof(char));
  strcpy(fs, max);
  return fs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<httpsqs_maxqueue>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    0x23(%rbx,%rax,1),%edi
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    %rax,%rbp
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    0xd(%rsp),%r13
  call   <http_get@plt>
  mov    %rbp,%rdi
  xor    %ebp,%ebp
  mov    %eax,%r12d
  call   <free@plt>
  jmp    L24
  xchg   %ax,%ax
L49:
  cmp    $0x6,%ebx
  jle    L48
  movzbl 0xd(%rsp),%edx
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %dl,0x10(%rsp,%rax,1)
L48:
  xor    %eax,%eax
  cmpb   $0xa,0xd(%rsp)
  sete   %al
  add    %eax,%ebx
L24:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L49
  lea    0x10(%rsp),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L46
  movslq %ebp,%rbp
  movb   $0x0,0x10(%rsp,%rbp,1)
L46:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x150,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D13
type: string

tool: D7: utf-8

tool: D13: /?charset=%s&name=%s&opt=maxqueue&num=%s

assistant: ```c
char *httpsqs_maxqueue(char *name, char *num) {
  char data[3];
  int sock;
  char *query;
  char max[300];
  int i = 0, j = 0;
  char *fs;
  query = (char *)malloc((strlen(name) + strlen(num) + strlen("utf-8") + 35) * sizeof(char));
  sprintf(query, "/?charset=%s&name=%s&opt=maxqueue&num=%s", "utf-8", name, num);
  sock = http_get(query);
  free(query);
  while (read(sock, data, 1) > 0) {
    if (j >= 7) {
      max[i] = data[0];
      i++;
    }
    if (data[0] == '\n') {
      j++;
    }
  }
  if (strlen(max) > 0) {
    max[i] = '\0';
  }
  fs = (char *)malloc(strlen(max) * sizeof(char));
  strcpy(fs, max);
  return fs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L6:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L24
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L24:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t max) {
  size_t len = 0;
  while (len < max && *s) {
    len++;
    s++;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  mov    $0x0,%edx
  test   %rsi,%rsi
  je     L25
L0:
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L30
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L0
  jmp    L17
L25:
  ret
L30:
  mov    %rdx,%rax
L17:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t max) {
  size_t len = 0;
  while (len < max && *s) {
    len++;
    s++;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L22
  jmp    L36
L31:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L10
L22:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L31
  mov    %rdx,%rax
L10:
  ret
L36:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t max) {
  size_t len = 0;
  while (len < max && *s) {
    len++;
    s++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strnlen>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  test   %rsi,%rsi
  jne    L18
  jmp    L21
L32:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L13
L18:
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L32
  mov    %rdx,%rax
L13:
  ret
L21:
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t max) {
  size_t len = 0;
  while (len < max && *s) {
    len++;
    s++;
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L3
  mov    $0x40,%eax
  jmp    L16
L3:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L16:
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  if (argc < 2)
    return (64);
  return (unlink(argv[1]) == 0 ? 0 : 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x40,%eax
  cmp    $0x1,%edi
  jle    L8
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  if (argc < 2)
    return (64);
  return (unlink(argv[1]) == 0 ? 0 : 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L3
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
L3:
  mov    $0x40,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  if (argc < 2)
    return (64);
  return (unlink(argv[1]) == 0 ? 0 : 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L2
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <unlink@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
L2:
  mov    $0x40,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  if (argc < 2)
    return (64);
  return (unlink(argv[1]) == 0 ? 0 : 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rechc>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%r9d
  test   %ecx,%ecx
  jle    L12
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%r8
  mov    $0x0,%edi
L3:
  mov    0x4(%rax),%r10d
  mov    %r10d,%edx
  add    (%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rsi)
  mov    0x8(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x4(%rsi)
  mov    0xc(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x8(%rsi)
  mov    0x10(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0xc(%rsi)
  mov    0x14(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x10(%rsi)
  mov    0x18(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x14(%rsi)
  mov    0x1c(%rax),%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  sar    %ecx
  mov    %ecx,0x18(%rsi)
  add    0x20(%rax),%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rsi)
  add    %r8,%rax
  add    %r8,%rsi
  add    $0x1,%edi
  cmp    %edi,%r9d
  jne    L3
L12:
  ret
```

assistant: ```c
void rechc(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1;
    dp[1] = (uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1;
    dp[2] = (uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1;
    dp[3] = (uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1;
    dp[4] = (uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1;
    dp[5] = (uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1;
    dp[6] = (uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1;
    dp[7] = (uint32_t)(s2 + sp[8] + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rechc>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%r9d
  test   %ecx,%ecx
  jle    L1
  movslq %edx,%rdx
  xor    %edi,%edi
  lea    0x0(,%rdx,4),%r8
  nop
L4:
  mov    0x4(%rax),%r10d
  mov    (%rax),%edx
  add    $0x1,%edi
  add    %r10d,%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rsi)
  mov    0x8(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x4(%rsi)
  mov    0xc(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x8(%rsi)
  mov    0x10(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0xc(%rsi)
  mov    0x14(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x10(%rsi)
  mov    0x18(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x14(%rsi)
  mov    0x1c(%rax),%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  sar    %ecx
  mov    %ecx,0x18(%rsi)
  add    0x20(%rax),%edx
  add    %r8,%rax
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rsi)
  add    %r8,%rsi
  cmp    %edi,%r9d
  jne    L4
L1:
  ret
```

assistant: ```c
void rechc(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1;
    dp[1] = (uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1;
    dp[2] = (uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1;
    dp[3] = (uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1;
    dp[4] = (uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1;
    dp[5] = (uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1;
    dp[6] = (uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1;
    dp[7] = (uint32_t)(s2 + sp[8] + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rechc>:
  endbr64
  mov    %rdi,%rax
  mov    %ecx,%r9d
  test   %ecx,%ecx
  jle    L19
  movslq %edx,%rdx
  xor    %edi,%edi
  lea    0x0(,%rdx,4),%r8
  nop
L5:
  mov    0x4(%rax),%r10d
  mov    (%rax),%edx
  add    $0x1,%edi
  add    %r10d,%edx
  add    $0x1,%edx
  sar    %edx
  mov    %edx,(%rsi)
  mov    0x8(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x4(%rsi)
  mov    0xc(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x8(%rsi)
  mov    0x10(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0xc(%rsi)
  mov    0x14(%rax),%r10d
  lea    0x1(%rcx,%r10,1),%edx
  sar    %edx
  mov    %edx,0x10(%rsi)
  mov    0x18(%rax),%ecx
  lea    0x1(%r10,%rcx,1),%edx
  sar    %edx
  mov    %edx,0x14(%rsi)
  mov    0x1c(%rax),%edx
  lea    0x1(%rcx,%rdx,1),%ecx
  sar    %ecx
  mov    %ecx,0x18(%rsi)
  add    0x20(%rax),%edx
  add    %r8,%rax
  add    $0x1,%edx
  sar    %edx
  mov    %edx,0x1c(%rsi)
  add    %r8,%rsi
  cmp    %edi,%r9d
  jne    L5
L19:
  ret
```

assistant: ```c
void rechc(uint8_t *s, uint8_t *d, int lx2, int h) {
  uint8_t *dp = d, *sp = s;
  uint32_t s1, s2;
  int j;
  for (j = 0; j < h; ++j) {
    s1 = sp[0];
    dp[0] = (uint32_t)(s1 + (s2 = sp[1]) + 1) >> 1;
    dp[1] = (uint32_t)(s2 + (s1 = sp[2]) + 1) >> 1;
    dp[2] = (uint32_t)(s1 + (s2 = sp[3]) + 1) >> 1;
    dp[3] = (uint32_t)(s2 + (s1 = sp[4]) + 1) >> 1;
    dp[4] = (uint32_t)(s1 + (s2 = sp[5]) + 1) >> 1;
    dp[5] = (uint32_t)(s2 + (s1 = sp[6]) + 1) >> 1;
    dp[6] = (uint32_t)(s1 + (s2 = sp[7]) + 1) >> 1;
    dp[7] = (uint32_t)(s2 + sp[8] + 1) >> 1;
    sp += lx2;
    dp += lx2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<toLowerCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <makeCopy@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L0:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <len@plt>
  cmp    %eax,-0x1c(%rbp)
  jl     L0
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *toLowerCase(char *s) {
  char *q = makeCopy(s);
  int i;
  for (i = 0; i < len(q); i++) {
    *(q + i) = tolower(*(q + i));
  }
  return q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toLowerCase>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <makeCopy@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L12
L17:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L12:
  mov    %rbp,%rdi
  call   <len@plt>
  cmp    %ebx,%eax
  jg     L17
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *toLowerCase(char *s) {
  char *q = makeCopy(s);
  int i;
  for (i = 0; i < len(q); i++) {
    *(q + i) = tolower(*(q + i));
  }
  return q;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<toLowerCase>:
  endbr64
  push   %r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <makeCopy@plt>
  mov    %rax,%r12
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L8:
  mov    %r12,%rdi
  call   <len@plt>
  cmp    %ebx,%eax
  jg     L10
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *toLowerCase(char *s) {
  char *q = makeCopy(s);
  int i;
  for (i = 0; i < len(q); i++) {
    *(q + i) = tolower(*(q + i));
  }
  return q;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<toLowerCase>:
  endbr64
  push   %r12
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <makeCopy@plt>
  mov    %rax,%r12
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L6:
  mov    %r12,%rdi
  call   <len@plt>
  cmp    %ebx,%eax
  jg     L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *toLowerCase(char *s) {
  char *q = makeCopy(s);
  int i;
  for (i = 0; i < len(q); i++) {
    *(q + i) = tolower(*(q + i));
  }
  return q;
}
```