ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<submask_prefixtomask>:
  endbr64
  cmp    $0x20,%edi
  jg     L125
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L50
  mov    %edi,%ebx
  cmp    $0x8,%edi
  je     L67
  cmp    $0x10,%edi
  je     L129
  cmp    $0x18,%edi
  je     L46
  cmp    $0x20,%edi
  je     L21
  test   %edi,%edi
  jle    L13
L82:
  mov    $0x1f,%ecx
  xor    %edx,%edx
  lea    -0x1f(%rbx),%edi
  mov    $0x1,%esi
L132:
  mov    %esi,%eax
  shl    %cl,%eax
  sub    $0x1,%ecx
  add    %eax,%edx
  lea    (%rdi,%rcx,1),%eax
  test   %eax,%eax
  jg     L132
  mov    %edx,%ecx
  movzbl %dh,%eax
  movzbl %dl,%r9d
  shr    $0x18,%edx
  shr    $0x10,%ecx
  mov    %eax,%r8d
  movzbl %cl,%ecx
L115:
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
L69:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L21:
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L82
  nopl   0x0(%rax)
L46:
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L82
  nopl   0x0(%rax)
L13:
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L115
  nopl   0x0(%rax)
L67:
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L82
  nopl   0x0(%rax)
L129:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L82
L50:
  mov    $0xffffffff,%eax
  jmp    L69
L125:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D44
data_type: string
name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D18: %hhu.%hhu.%hhu.%hhu

tool: D19: 255.255.255.255

tool: D8: 255.255.255.0

tool: D44: 255.0.0.0

tool: D7: 255.255.0.0

assistant: ```c
int submask_prefixtomask(int prefixlen, char *ip_str) {
  unsigned int ip_num = 0;
  int i = 0;
  int j = 0;
  if (ip_str == NULL)
    return -1;
  if (prefixlen > 32)
    return -1;
  if (prefixlen == 8)
    strcpy(ip_str, "255.0.0.0");
  if (prefixlen == 16)
    strcpy(ip_str, "255.255.0.0");
  if (prefixlen == 24)
    strcpy(ip_str, "255.255.255.0");
  if (prefixlen == 32)
    strcpy(ip_str, "255.255.255.255");
  for (i = prefixlen, j = 31; i > 0; i--, j--) {
    ip_num += (1 << j);
  }
  sprintf(ip_str, "%hhu.%hhu.%hhu.%hhu", (ip_num >> 24) & 0xff, (ip_num >> 16) & 0xff, (ip_num >> 8) & 0xff, ip_num & 0xff);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<submask_prefixtomask>:
  endbr64
  cmp    $0x20,%edi
  jg     L2
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L117
  mov    %edi,%ebx
  cmp    $0x8,%edi
  je     L34
  cmp    $0x10,%edi
  je     L41
  cmp    $0x18,%edi
  je     L40
  cmp    $0x20,%edi
  je     L35
  test   %edi,%edi
  jle    L19
L64:
  mov    $0x1f,%ecx
  xor    %edx,%edx
  lea    -0x1f(%rbx),%edi
  mov    $0x1,%esi
L5:
  mov    %esi,%eax
  shl    %cl,%eax
  sub    $0x1,%ecx
  add    %eax,%edx
  lea    (%rdi,%rcx,1),%eax
  test   %eax,%eax
  jg     L5
  mov    %edx,%ecx
  movzbl %dh,%eax
  movzbl %dl,%r9d
  shr    $0x18,%edx
  shr    $0x10,%ecx
  mov    %eax,%r8d
  movzbl %cl,%ecx
L0:
  lea    D35(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L35:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L64
  nopl   0x0(%rax)
L40:
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L64
  nopl   0x0(%rax)
L19:
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  jmp    L0
  nopl   0x0(%rax)
L34:
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L64
  nopl   0x0(%rax)
L41:
  lea    D36(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L64
L117:
  mov    $0xffffffff,%eax
  jmp    L28
L2:
  or     $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D35
type: string
name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D36
type: string

tool: D35: %hhu.%hhu.%hhu.%hhu

tool: D17: 255.255.255.255

tool: D12: 255.255.255.0

tool: D26: 255.0.0.0

tool: D36: 255.255.0.0

assistant: ```c
int submask_prefixtomask(int prefixlen, char *ip_str) {
  unsigned int ip_num = 0;
  int i = 0;
  int j = 0;
  if (ip_str == NULL)
    return -1;
  if (prefixlen > 32)
    return -1;
  if (prefixlen == 8)
    strcpy(ip_str, "255.0.0.0");
  if (prefixlen == 16)
    strcpy(ip_str, "255.255.0.0");
  if (prefixlen == 24)
    strcpy(ip_str, "255.255.255.0");
  if (prefixlen == 32)
    strcpy(ip_str, "255.255.255.255");
  for (i = prefixlen, j = 31; i > 0; i--, j--) {
    ip_num += (1 << j);
  }
  sprintf(ip_str, "%hhu.%hhu.%hhu.%hhu", (ip_num >> 24) & 0xff, (ip_num >> 16) & 0xff, (ip_num >> 8) & 0xff, ip_num & 0xff);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L28:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L2
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L33
L2:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char *cmp1 = (unsigned char *)s1;
  unsigned char *cmp2 = (unsigned char *)s2;
  while (*cmp1 && *cmp2) {
    if (*cmp1 != *cmp2) {
      return (*cmp1 - *cmp2);
    }
    cmp1++;
    cmp2++;
  }
  return (*cmp1 - *cmp2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
L13:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L9
  cmp    %al,%dl
  jne    L17
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L13
L9:
  movzbl %al,%eax
  movzbl (%rsi),%edx
  sub    %edx,%eax
  ret
L17:
  movzbl %al,%eax
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char *cmp1 = (unsigned char *)s1;
  unsigned char *cmp2 = (unsigned char *)s2;
  while (*cmp1 && *cmp2) {
    if (*cmp1 != *cmp2) {
      return (*cmp1 - *cmp2);
    }
    cmp1++;
    cmp2++;
  }
  return (*cmp1 - *cmp2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L53
  jmp    L51
  nopl   (%rax)
L8:
  cmp    %al,%dl
  jne    L47
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L6
  mov    %rdx,%rsi
L53:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L8
L47:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L6:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L51:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L47
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char *cmp1 = (unsigned char *)s1;
  unsigned char *cmp2 = (unsigned char *)s2;
  while (*cmp1 && *cmp2) {
    if (*cmp1 != *cmp2) {
      return (*cmp1 - *cmp2);
    }
    cmp1++;
    cmp2++;
  }
  return (*cmp1 - *cmp2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L52
  jmp    L49
  nopl   (%rax)
L39:
  cmp    %al,%dl
  jne    L1
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L3
  mov    %rdx,%rsi
L52:
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L39
L1:
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L3:
  movzbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L49:
  movzbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  unsigned char *cmp1 = (unsigned char *)s1;
  unsigned char *cmp2 = (unsigned char *)s2;
  while (*cmp1 && *cmp2) {
    if (*cmp1 != *cmp2) {
      return (*cmp1 - *cmp2);
    }
    cmp1++;
    cmp2++;
  }
  return (*cmp1 - *cmp2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    $0x0,%eax
  call   <stack_new@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L37:
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stack_push@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jle    L37
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L24:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_pick@plt>
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_pop@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jle    L24
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <stack_delete@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  struct stack *s;
  s = stack_new();
  for (i = 0; i < 10; i++)
    stack_push(s, &i);
  for (i = 0; i < 10; i++) {
    printf("%d\n", *(int *)stack_pick(s));
    s = stack_pop(s);
  }
  stack_delete(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <stack_new@plt>
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
L13:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <stack_push@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L13
  movl   $0x0,0x4(%rsp)
  lea    D9(%rip),%rbp
L3:
  mov    %rbx,%rdi
  call   <stack_pick@plt>
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stack_pop@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L3
  mov    %rbx,%rdi
  call   <stack_delete@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  struct stack *s;
  s = stack_new();
  for (i = 0; i < 10; i++)
    stack_push(s, &i);
  for (i = 0; i < 10; i++) {
    printf("%d\n", *(int *)stack_pick(s));
    s = stack_pop(s);
  }
  stack_delete(s);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  call   <stack_new@plt>
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L29
  movl   $0x0,0x4(%rsp)
  lea    D0(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  call   <stack_pick@plt>
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L11
  mov    %rbp,%rdi
  call   <stack_delete@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  struct stack *s;
  s = stack_new();
  for (i = 0; i < 10; i++)
    stack_push(s, &i);
  for (i = 0; i < 10; i++) {
    printf("%d\n", *(int *)stack_pick(s));
    s = stack_pop(s);
  }
  stack_delete(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  call   <stack_new@plt>
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <stack_push@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L15
  movl   $0x0,0x4(%rsp)
  lea    D6(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <stack_pick@plt>
  mov    %rbx,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stack_pop@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x9,%eax
  jle    L2
  mov    %rbp,%rdi
  call   <stack_delete@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  struct stack *s;
  s = stack_new();
  for (i = 0; i < 10; i++)
    stack_push(s, &i);
  for (i = 0; i < 10; i++) {
    printf("%d\n", *(int *)stack_pick(s));
    s = stack_pop(s);
  }
  stack_delete(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a[40];
  int n = 30;
  int m = 20;
  int b[n];
  b[29] = 5;
  assert(b[29] = 5);
  int c[n + 4];
  c[31] = 2;
  assert(c[31] = 2);
  int d[n][30];
  d[2][2] = 42;
  assert(d[2][2] == 42);
  int e[20][n];
  e[2][2] = 42;
  assert(e[2][2] == 42);
  int f[m][n];
  f[2][2] = 42;
  assert(f[2][2] == 42);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a[40];
  int n = 30;
  int m = 20;
  int b[n];
  b[29] = 5;
  assert(b[29] = 5);
  int c[n + 4];
  c[31] = 2;
  assert(c[31] = 2);
  int d[n][30];
  d[2][2] = 42;
  assert(d[2][2] == 42);
  int e[20][n];
  e[2][2] = 42;
  assert(e[2][2] == 42);
  int f[m][n];
  f[2][2] = 42;
  assert(f[2][2] == 42);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a[40];
  int n = 30;
  int m = 20;
  int b[n];
  b[29] = 5;
  assert(b[29] = 5);
  int c[n + 4];
  c[31] = 2;
  assert(c[31] = 2);
  int d[n][30];
  d[2][2] = 42;
  assert(d[2][2] == 42);
  int e[20][n];
  e[2][2] = 42;
  assert(e[2][2] == 42);
  int f[m][n];
  f[2][2] = 42;
  assert(f[2][2] == 42);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<month_to_season>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0xc,-0x14(%rbp)
  ja     L12
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x0,-0x4(%rbp)
  jmp    L12
  movl   $0x1,-0x4(%rbp)
  jmp    L12
  movl   $0x2,-0x4(%rbp)
  jmp    L12
  movl   $0x3,-0x4(%rbp)
  nop
L12:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int month_to_season(int mon) {
  int seas = -1;
  switch (mon) {
  case 12:
  case 1:
  case 2:
    seas = 0;
    break;
  case 3:
  case 4:
  case 5:
    seas = 1;
    break;
  case 6:
  case 7:
  case 8:
    seas = 2;
    break;
  case 9:
  case 10:
  case 11:
    seas = 3;
    break;
  }
  return seas;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<month_to_season>:
  endbr64
  cmp    $0xc,%edi
  ja     L0
  mov    %edi,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  ret
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int month_to_season(int mon) {
  int seas = -1;
  switch (mon) {
  case 12:
  case 1:
  case 2:
    seas = 0;
    break;
  case 3:
  case 4:
  case 5:
    seas = 1;
    break;
  case 6:
  case 7:
  case 8:
    seas = 2;
    break;
  case 9:
  case 10:
  case 11:
    seas = 3;
    break;
  }
  return seas;
}
```
user: Translate the below assembly code into C programming language:

```asm
<month_to_season>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0xb,%edi
  ja     L0
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L0:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: 

assistant: ```c
int month_to_season(int mon) {
  int seas = -1;
  switch (mon) {
  case 12:
  case 1:
  case 2:
    seas = 0;
    break;
  case 3:
  case 4:
  case 5:
    seas = 1;
    break;
  case 6:
  case 7:
  case 8:
    seas = 2;
    break;
  case 9:
  case 10:
  case 11:
    seas = 3;
    break;
  }
  return seas;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<month_to_season>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0xb,%edi
  ja     L8
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L8:
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: 

assistant: ```c
int month_to_season(int mon) {
  int seas = -1;
  switch (mon) {
  case 12:
  case 1:
  case 2:
    seas = 0;
    break;
  case 3:
  case 4:
  case 5:
    seas = 1;
    break;
  case 6:
  case 7:
  case 8:
    seas = 2;
    break;
  case 9:
  case 10:
  case 11:
    seas = 3;
    break;
  }
  return seas;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sched_yield>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <schedule@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t sched_yield(void) {
  schedule();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sched_yield>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <schedule@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t sched_yield(void) {
  schedule();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sched_yield>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t sched_yield(void) {
  schedule();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sched_yield>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t sched_yield(void) {
  schedule();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumaPositivos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L12
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  -0x8(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
L12:
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L0
  nop
  pop    %rbp
  ret
```

assistant: ```c
sumaPositivos(int nEle, double *vector, double *suma) {
  int i = 0;
  double aux = 0;
  for (i = 0; i < nEle; i++) {
    aux = *(vector + i);
    if (aux >= 0) {
      *suma = *suma + aux;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sumaPositivos>:
  endbr64
  test   %edi,%edi
  jle    L20
  mov    %rsi,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x8(%rsi,%rcx,8),%rcx
  pxor   %xmm1,%xmm1
  jmp    L11
L32:
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L15:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L20
L11:
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jae    L32
  jmp    L15
L20:
  ret
```

assistant: ```c
sumaPositivos(int nEle, double *vector, double *suma) {
  int i = 0;
  double aux = 0;
  for (i = 0; i < nEle; i++) {
    aux = *(vector + i);
    if (aux >= 0) {
      *suma = *suma + aux;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sumaPositivos>:
  endbr64
  test   %edi,%edi
  jle    L26
  lea    -0x1(%rdi),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax)
L29:
  movsd  (%rsi),%xmm0
  comisd %xmm1,%xmm0
  jb     L2
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L2:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  jne    L29
L26:
  ret
```

assistant: ```c
sumaPositivos(int nEle, double *vector, double *suma) {
  int i = 0;
  double aux = 0;
  for (i = 0; i < nEle; i++) {
    aux = *(vector + i);
    if (aux >= 0) {
      *suma = *suma + aux;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumaPositivos>:
  endbr64
  test   %edi,%edi
  jle    L22
  lea    -0x1(%rdi),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax)
L21:
  movsd  (%rsi),%xmm0
  comisd %xmm1,%xmm0
  jb     L15
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L15:
  add    $0x8,%rsi
  cmp    %rax,%rsi
  jne    L21
L22:
  ret
```

assistant: ```c
sumaPositivos(int nEle, double *vector, double *suma) {
  int i = 0;
  double aux = 0;
  for (i = 0; i < nEle; i++) {
    aux = *(vector + i);
    if (aux >= 0) {
      *suma = *suma + aux;
    }
  }
}
```