ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fklt>:
  endbr64
  test   %ecx,%ecx
  jle    L29
  lea    -0x1(%rcx),%eax
  mov    %rdi,%r10
  push   %r12
  mov    %ecx,%r11d
  lea    0x8(%r10,%rax,8),%r12
  mov    %ecx,%eax
  push   %rbp
  movslq %ecx,%rbp
  shr    %eax
  push   %rbx
  mov    %ecx,%ebx
  mov    %rdx,%r8
  lea    -0x1(%rax),%r9d
  shl    $0x3,%rbp
  mov    %rdx,%rdi
  and    $0xfffffffe,%ebx
  add    $0x1,%r9
  xor    %ecx,%ecx
  pxor   %xmm3,%xmm3
  shl    $0x4,%r9
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmp    $0x1,%r11d
  je     L30
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  nopl   0x0(%rax)
L4:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  mulpd  %xmm4,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%r9
  jne    L4
  movslq %ebx,%rax
  cmp    %ebx,%r11d
  je     L53
L18:
  lea    (%rcx,%rax,1),%edx
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
L53:
  movsd  %xmm1,(%r10)
  add    $0x8,%r10
  add    %r11d,%ecx
  add    %rbp,%rdi
  cmp    %r12,%r10
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L30:
  movapd %xmm3,%xmm1
  xor    %eax,%eax
  jmp    L18
L29:
  ret
```

assistant: ```c
void fklt(double *out, double *in, double *klt, int support) {
  int i, j;
  for (i = 0; i < support; i++) {
    double acc = 0.;
    for (j = 0; j < support; j++)
      acc += klt[i * support + j] * in[j];
    out[i] = acc;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_result_phase_II>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r12
  movslq %edx,%rax
  lea    0x0(,%rax,8),%r15
  movslq %esi,%rdx
  mov    (%rdi,%rdx,8),%rdx
  cvttsd2si (%rdx,%rax,8),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L82
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  jmp    L51
L87:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L82
L51:
  mov    (%r12,%rbx,4),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L87
  mov    0x0(%r13,%rbx,8),%rax
  movsd  (%rax,%r15,1),%xmm0
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  add    $0x1,%esi
  lea    D5(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L87
L82:
  test   %r14d,%r14d
  jle    L76
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rbx
  lea    -0x1(%r14),%eax
  lea    0x4(%rcx,%rax,4),%rbp
  lea    D5(%rip),%r12
  jmp    L65
L77:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L76
L65:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L77
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  add    $0x1,%esi
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L77
L76:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D4: The maximum solution occurs at Z=%lf with


tool: D5: X%d=%lf	

assistant: ```c
void print_result_phase_II(double **T, int no_of_eqns, int no_of_variables, int *column, int *row) {
  int i;
  printf("The maximum solution occurs at Z=%lf with\n", T[no_of_eqns][no_of_variables]);
  for (i = 0; i < no_of_eqns; i++) {
    if (row[i] / 10 == 1) {
      printf("X%d=%lf\t", (row[i] % 10) + 1, T[i][no_of_variables]);
    }
  }
  for (i = 0; i < no_of_variables; i++) {
    if (column[i] / 10 == 1) {
      printf("X%d=%lf\t", (column[i] % 10) + 1, 0.00);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_result_phase_II>:
  endbr64
  push   %r15
  movslq %edx,%rax
  mov    %rdi,%r15
  push   %r14
  lea    0x0(,%rax,8),%rdx
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    (%rdi,%r13,8),%rcx
  lea    D6(%rip),%rdi
  mov    %rdx,(%rsp)
  cvttsd2si (%rcx,%rax,8),%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L54
  xor    %ebp,%ebp
  lea    D8(%rip),%r14
  jmp    L66
  nopl   0x0(%rax)
L84:
  add    $0x1,%rbp
  cmp    %r13,%rbp
  je     L54
L66:
  mov    (%rbx,%rbp,4),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L84
  mov    (%r15,%rbp,8),%rax
  mov    (%rsp),%rdi
  mov    %esi,%ecx
  add    $0x1,%rbp
  sar    $0x1f,%ecx
  movsd  (%rax,%rdi,1),%xmm0
  movslq %esi,%rax
  mov    %r14,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %r13,%rbp
  jne    L66
L54:
  test   %r12d,%r12d
  jle    L22
  mov    0x8(%rsp),%rbx
  lea    -0x1(%r12),%eax
  lea    D8(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x4,%rbx
  cmp    %rbx,%r12
  je     L22
L13:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L59
  movslq %esi,%rax
  mov    %esi,%edx
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  add    $0x4,%rbx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L13
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D6: The maximum solution occurs at Z=%lf with


tool: D8: X%d=%lf	

assistant: ```c
void print_result_phase_II(double **T, int no_of_eqns, int no_of_variables, int *column, int *row) {
  int i;
  printf("The maximum solution occurs at Z=%lf with\n", T[no_of_eqns][no_of_variables]);
  for (i = 0; i < no_of_eqns; i++) {
    if (row[i] / 10 == 1) {
      printf("X%d=%lf\t", (row[i] % 10) + 1, T[i][no_of_variables]);
    }
  }
  for (i = 0; i < no_of_variables; i++) {
    if (column[i] / 10 == 1) {
      printf("X%d=%lf\t", (column[i] % 10) + 1, 0.00);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_result_phase_II>:
  endbr64
  push   %r15
  movslq %edx,%rax
  mov    %rdi,%r15
  push   %r14
  lea    0x0(,%rax,8),%rdx
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %rax,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    (%rdi,%r13,8),%rcx
  lea    D28(%rip),%rdi
  mov    %rdx,(%rsp)
  cvttsd2si (%rcx,%rax,8),%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %r13d,%r13d
  jle    L2
  xor    %ebp,%ebp
  lea    D3(%rip),%r14
  jmp    L0
  nopl   0x0(%rax)
L48:
  add    $0x1,%rbp
  cmp    %rbp,%r13
  je     L2
L0:
  mov    (%rbx,%rbp,4),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L48
  mov    (%r15,%rbp,8),%rax
  mov    (%rsp),%rdi
  mov    %esi,%ecx
  add    $0x1,%rbp
  sar    $0x1f,%ecx
  movsd  (%rax,%rdi,1),%xmm0
  movslq %esi,%rax
  mov    %r14,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L0
L2:
  test   %r12d,%r12d
  jle    L76
  mov    0x8(%rsp),%rbx
  lea    -0x1(%r12),%eax
  lea    D3(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L76
L61:
  mov    (%rbx),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0x9,%eax
  ja     L40
  movslq %esi,%rax
  mov    %esi,%edx
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  add    $0x4,%rbx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    $0x1,%eax
  add    $0x1,%esi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L61
L76:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D28: The maximum solution occurs at Z=%lf with


tool: D3: X%d=%lf	

assistant: ```c
void print_result_phase_II(double **T, int no_of_eqns, int no_of_variables, int *column, int *row) {
  int i;
  printf("The maximum solution occurs at Z=%lf with\n", T[no_of_eqns][no_of_variables]);
  for (i = 0; i < no_of_eqns; i++) {
    if (row[i] / 10 == 1) {
      printf("X%d=%lf\t", (row[i] % 10) + 1, T[i][no_of_variables]);
    }
  }
  for (i = 0; i < no_of_variables; i++) {
    if (column[i] / 10 == 1) {
      printf("X%d=%lf\t", (column[i] % 10) + 1, 0.00);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mvn_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x34(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L7
L58:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <rand_normal_r@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x20(%rbp)
L7:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L58
  movl   $0x0,-0x20(%rbp)
  jmp    L38
L8:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x1c(%rbp)
  jmp    L47
L46:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L47:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L46
  addl   $0x1,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mvn_rand(double *mu, double *L, int D, double *y) {
  int i, j;
  double *x = (double *)calloc(D, sizeof(double));
  for (i = 0; i < D; i++)
    x[i] = rand_normal_r();
  for (i = 0; i < D; i++) {
    y[i] = mu[i];
    for (j = 0; j < D; j++) {
      y[i] += L[j * D + i] * x[j];
    }
  }
  free(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mvn_rand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,0x8(%rsp)
  mov    %edx,%ebx
  mov    %rcx,%r12
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L33
  mov    %ebx,%eax
  lea    (%r14,%rax,8),%rbp
  mov    %r14,%r13
L27:
  mov    $0x0,%eax
  call   <rand_normal_r@plt>
  movsd  %xmm0,0x0(%r13)
  add    $0x8,%r13
  cmp    %rbp,%r13
  jne    L27
  mov    0x8(%rsp),%r8
  mov    %ebx,%r9d
  movslq %ebx,%rsi
  shl    $0x3,%rsi
  mov    $0x0,%edi
L20:
  movsd  (%r15,%rdi,8),%xmm0
  mov    %r12,%rcx
  movsd  %xmm0,(%r12)
  mov    %r14,%rax
  mov    %r8,%rdx
L31:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L31
  add    $0x1,%rdi
  add    $0x8,%r12
  add    $0x8,%r8
  cmp    %r9,%rdi
  jne    L20
L33:
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mvn_rand(double *mu, double *L, int D, double *y) {
  int i, j;
  double *x = (double *)calloc(D, sizeof(double));
  for (i = 0; i < D; i++)
    x[i] = rand_normal_r();
  for (i = 0; i < D; i++) {
    y[i] = mu[i];
    for (j = 0; j < D; j++) {
      y[i] += L[j * D + i] * x[j];
    }
  }
  free(x);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mvn_rand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    $0x8,%esi
  mov    %rcx,0x8(%rsp)
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L34
  mov    %r13d,%r12d
  mov    %rax,%r14
  lea    (%rax,%r12,8),%r15
  nop
L18:
  xor    %eax,%eax
  add    $0x8,%r14
  call   <rand_normal_r@plt>
  movsd  %xmm0,-0x8(%r14)
  cmp    %r15,%r14
  jne    L18
  movslq %r13d,%rdi
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%r14
  xor    %r8d,%r8d
  shl    $0x3,%rdi
  nopl   0x0(%rax)
L36:
  movsd  (%rbx,%r8,8),%xmm1
  mov    %rbp,%rax
  mov    %r14,%rdx
  movsd  %xmm1,(%rcx)
L12:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %r15,%rax
  jne    L12
  add    $0x1,%r8
  add    $0x8,%rcx
  add    $0x8,%r14
  cmp    %r12,%r8
  jne    L36
L34:
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void mvn_rand(double *mu, double *L, int D, double *y) {
  int i, j;
  double *x = (double *)calloc(D, sizeof(double));
  for (i = 0; i < D; i++)
    x[i] = rand_normal_r();
  for (i = 0; i < D; i++) {
    y[i] = mu[i];
    for (j = 0; j < D; j++) {
      y[i] += L[j * D + i] * x[j];
    }
  }
  free(x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mvn_rand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    $0x8,%esi
  mov    %rcx,0x8(%rsp)
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L27
  mov    %r13d,%r12d
  mov    %rax,%r14
  lea    (%rax,%r12,8),%r15
  nop
L23:
  xor    %eax,%eax
  add    $0x8,%r14
  call   <rand_normal_r@plt>
  movsd  %xmm0,-0x8(%r14)
  cmp    %r15,%r14
  jne    L23
  movslq %r13d,%rdi
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%r14
  xor    %r8d,%r8d
  shl    $0x3,%rdi
  nopl   0x0(%rax)
L30:
  movsd  (%rbx,%r8,8),%xmm1
  mov    %rbp,%rax
  mov    %r14,%rdx
  movsd  %xmm1,(%rcx)
L18:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %r15,%rax
  jne    L18
  add    $0x1,%r8
  add    $0x8,%rcx
  add    $0x8,%r14
  cmp    %r12,%r8
  jne    L30
L27:
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void mvn_rand(double *mu, double *L, int D, double *y) {
  int i, j;
  double *x = (double *)calloc(D, sizeof(double));
  for (i = 0; i < D; i++)
    x[i] = rand_normal_r();
  for (i = 0; i < D; i++) {
    y[i] = mu[i];
    for (j = 0; j < D; j++) {
      y[i] += L[j * D + i] * x[j];
    }
  }
  free(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L73
L44:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L71:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0xa,-0x8(%rbp)
  jne    L109
  nop
  jmp    L17
L3:
  nop
L17:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L109:
  cmpl   $0xf,-0x8(%rbp)
  je     L37
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x13,-0x8(%rbp)
  jle    L71
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L63:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x14,-0x4(%rbp)
  jne    L91
  jmp    L8
L37:
  nop
L8:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L91:
  cmpl   $0x19,-0x4(%rbp)
  je     L3
  addl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0x1d,-0x4(%rbp)
  jle    L63
  addl   $0x1,-0xc(%rbp)
L73:
  cmpl   $0x63,-0xc(%rbp)
  jle    L44
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D36
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D0: 1


tool: D36: 2


tool: D11: 3


tool: D17: 4


tool: D8: 5


tool: D7: 6


assistant: ```c
int main() {
  int i, j, k;
  for (i = 0; i < 100; i++) {
    printf("1\n");
    while (j < 20) {
      printf("2\n");
      if (j == 10) {
      loop1:
        printf("3\n");
      }
      if (j == 15)
        goto loop2;
      j++;
    }
    printf("4\n");
    while (k < 30) {
      printf("5\n");
      if (k == 20) {
      loop2:
        printf("6\n");
      }
      if (k == 25)
        goto loop1;
      k++;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x64,0xc(%rsp)
  lea    D41(%rip),%r12
  lea    D21(%rip),%r14
L3:
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D52(%rip),%r13
  lea    D24(%rip),%r15
  jmp    L4
L22:
  cmp    $0xf,%ebx
  je     L70
  add    $0x1,%ebx
L4:
  cmp    $0x13,%ebx
  jg     L64
  lea    D51(%rip),%rdi
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L22
L23:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L22
L64:
  mov    %r13,%rdi
  call   <printf@plt>
L13:
  cmp    $0x1d,%ebp
  jg     L74
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0x14,%ebp
  je     L70
L51:
  cmp    $0x19,%ebp
  je     L23
  add    $0x1,%ebp
  jmp    L13
L70:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L51
L74:
  subl   $0x1,0xc(%rsp)
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D41
data_type: string
name: extract_symbolic_data
arguments: tag: D21
data_type: string
name: extract_symbolic_data
arguments: tag: D52
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D51
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string

tool: D41: 1


tool: D21: 5


tool: D52: 4


tool: D24: 3


tool: D51: 2


tool: D13: 6


assistant: ```c
int main() {
  int i, j, k;
  for (i = 0; i < 100; i++) {
    printf("1\n");
    while (j < 20) {
      printf("2\n");
      if (j == 10) {
      loop1:
        printf("3\n");
      }
      if (j == 15)
        goto loop2;
      j++;
    }
    printf("4\n");
    while (k < 30) {
      printf("5\n");
      if (k == 20) {
      loop2:
        printf("6\n");
      }
      if (k == 25)
        goto loop1;
      k++;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D43(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    D45(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x64,0xc(%rsp)
L31:
  mov    %r12,%rdi
  lea    D50(%rip),%r15
  call   <printf@plt>
  cmp    $0x13,%ebx
  jg     L25
L99:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  cmp    $0xa,%ebx
  je     L54
L19:
  cmp    $0xf,%ebx
  je     L39
  add    $0x1,%ebx
  cmp    $0x13,%ebx
  jle    L99
L25:
  mov    %r14,%rdi
  call   <printf@plt>
L22:
  cmp    $0x1d,%ebp
  jg     L13
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x14,%ebp
  je     L39
L62:
  cmp    $0x19,%ebp
  je     L54
  add    $0x1,%ebp
  jmp    L22
L39:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L54:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L19
L13:
  subl   $0x1,0xc(%rsp)
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D43
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D45
data_type: string
name: disassemble_data
arguments: data_label: D50
data_type: string
name: disassemble_data
arguments: data_label: D47
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D43: 4


tool: D8: 5


tool: D45: 1


tool: D50: 3


tool: D47: 2


tool: D7: 6


assistant: ```c
int main() {
  int i, j, k;
  for (i = 0; i < 100; i++) {
    printf("1\n");
    while (j < 20) {
      printf("2\n");
      if (j == 10) {
      loop1:
        printf("3\n");
      }
      if (j == 15)
        goto loop2;
      j++;
    }
    printf("4\n");
    while (k < 30) {
      printf("5\n");
      if (k == 20) {
      loop2:
        printf("6\n");
      }
      if (k == 25)
        goto loop1;
      k++;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D56(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x64,0xc(%rsp)
L106:
  mov    %r12,%rdi
  lea    D36(%rip),%r15
  call   <printf@plt>
  cmp    $0x13,%ebx
  jg     L79
L92:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  cmp    $0xa,%ebx
  je     L40
L0:
  cmp    $0xf,%ebx
  je     L32
  add    $0x1,%ebx
  cmp    $0x13,%ebx
  jle    L92
L79:
  mov    %r14,%rdi
  call   <printf@plt>
L37:
  cmp    $0x1d,%ebp
  jg     L82
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x14,%ebp
  je     L32
L11:
  cmp    $0x19,%ebp
  je     L40
  add    $0x1,%ebp
  jmp    L37
L32:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L40:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L0
L82:
  subl   $0x1,0xc(%rsp)
  jne    L106
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string
name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string
name: disassemble_data
arguments: tag: D31
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string

tool: D19: 4


tool: D17: 5


tool: D56: 1


tool: D36: 3


tool: D31: 2


tool: D14: 6


assistant: ```c
int main() {
  int i, j, k;
  for (i = 0; i < 100; i++) {
    printf("1\n");
    while (j < 20) {
      printf("2\n");
      if (j == 10) {
      loop1:
        printf("3\n");
      }
      if (j == 15)
        goto loop2;
      j++;
    }
    printf("4\n");
    while (k < 30) {
      printf("5\n");
      if (k == 20) {
      loop2:
        printf("6\n");
      }
      if (k == 25)
        goto loop1;
      k++;
    }
  }
  return 0;
}
```