ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ReverseBits>:
  endbr64
  lea    -0x1(%rsi),%ecx
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L3
  xchg   %ax,%ax
L2:
  mov    %edi,%eax
  sar    %edi
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%r8d
  sub    $0x1,%ecx
  jae    L2
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ReverseBits(int i, int max_bits) {
  const int tab_size = 1 << max_bits;
  int v = 0, n = max_bits;
  while (n-- > 0) {
    v |= (i & 1) << n;
    i >>= 1;
  }
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D32
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string

tool: D32: 9==8%d


tool: D18: 9==9=%d


tool: D20: 9!=8%d


tool: D25: 9!=9=%d


assistant: ```c
void main() {
  printf("9==8%d\n", 9 == 8);
  printf("9==9=%d\n", 9 == 9);
  printf("9!=8%d\n", 9 != 8);
  printf("9!=9=%d\n", 9 != 9);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D32
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D20
type: string

tool: D32: 9==8%d


tool: D14: 9==9=%d


tool: D9: 9!=8%d


tool: D20: 9!=9=%d


assistant: ```c
void main() {
  printf("9==8%d\n", 9 == 8);
  printf("9==9=%d\n", 9 == 9);
  printf("9!=8%d\n", 9 != 8);
  printf("9!=9=%d\n", 9 != 9);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D21
type: string

tool: D1: 9==8%d


tool: D3: 9==9=%d


tool: D26: 9!=8%d


tool: D21: 9!=9=%d


assistant: ```c
void main() {
  printf("9==8%d\n", 9 == 8);
  printf("9==9=%d\n", 9 == 9);
  printf("9!=8%d\n", 9 != 8);
  printf("9!=9=%d\n", 9 != 9);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string

tool: D29: 9==8%d


tool: D17: 9==9=%d


tool: D9: 9!=8%d


tool: D10: 9!=9=%d


assistant: ```c
void main() {
  printf("9==8%d\n", 9 == 8);
  printf("9==9=%d\n", 9 == 9);
  printf("9!=8%d\n", 9 != 8);
  printf("9!=9=%d\n", 9 != 9);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L41
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L69
L38:
  subq   $0x1,-0x20(%rbp)
L69:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  ja     L62
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L38
L62:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L52
L15:
  addq   $0x1,-0x18(%rbp)
L52:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  ja     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L6:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L3
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L3:
  mov    -0x28(%rbp),%rax
L41:
  leave
  ret
```

assistant: ```c
char *trim(char *str) {
  if (str == NULL)
    return NULL;
  size_t len = strlen(str);
  unsigned char *ustr = (unsigned char *)str;
  unsigned char *right = ustr + len;
  while (*right <= 0x20 && right >= ustr) {
    --right;
  }
  *++right = '\0';
  unsigned char *left = ustr;
  while (*left <= 0x20 && *left != '\0')
    ++left;
  if (left != ustr)
    memmove(ustr, left, right - left + 1);
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L40
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdx
  cmpb   $0x20,(%rdx)
  ja     L54
  cmp    %rdx,%rbx
  ja     L54
L78:
  sub    $0x1,%rdx
  cmpb   $0x20,(%rdx)
  ja     L54
  cmp    %rdx,%rbx
  jbe    L78
L54:
  movb   $0x0,0x1(%rdx)
  movzbl (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L40
  mov    %rbx,%rsi
L69:
  mov    %rsi,%rcx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L69
  cmp    %rsi,%rbx
  je     L40
  sub    %rcx,%rdx
  add    $0x1,%edx
  mov    %rbx,%rdi
  call   <memmove@plt>
L40:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trim(char *str) {
  if (str == NULL)
    return NULL;
  size_t len = strlen(str);
  unsigned char *ustr = (unsigned char *)str;
  unsigned char *right = ustr + len;
  while (*right <= 0x20 && right >= ustr) {
    --right;
  }
  *++right = '\0';
  unsigned char *left = ustr;
  while (*left <= 0x20 && *left != '\0')
    ++left;
  if (left != ustr)
    memmove(ustr, left, right - left + 1);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L21
  call   <strlen@plt>
  add    %r12,%rax
  jae    L6
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %rax,%r12
  ja     L28
L6:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  jbe    L36
L28:
  movb   $0x0,0x1(%rax)
  movzbl (%r12),%ecx
  lea    -0x1(%rcx),%edx
  cmp    $0x1f,%dl
  ja     L21
  mov    %r12,%rsi
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rsi,%rcx
  movzbl 0x1(%rsi),%edi
  add    $0x1,%rsi
  lea    -0x1(%rdi),%edx
  cmp    $0x1f,%dl
  jbe    L33
  cmp    %rsi,%r12
  je     L21
  sub    %rcx,%rax
  mov    %r12,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
L21:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *str) {
  if (str == NULL)
    return NULL;
  size_t len = strlen(str);
  unsigned char *ustr = (unsigned char *)str;
  unsigned char *right = ustr + len;
  while (*right <= 0x20 && right >= ustr) {
    --right;
  }
  *++right = '\0';
  unsigned char *left = ustr;
  while (*left <= 0x20 && *left != '\0')
    ++left;
  if (left != ustr)
    memmove(ustr, left, right - left + 1);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L17
  call   <strlen@plt>
  add    %r12,%rax
  jae    L45
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L51:
  cmp    %rax,%r12
  ja     L1
L45:
  sub    $0x1,%rax
  cmpb   $0x20,(%rax)
  jbe    L51
L1:
  movb   $0x0,0x1(%rax)
  movzbl (%r12),%ecx
  lea    -0x1(%rcx),%edx
  cmp    $0x1f,%dl
  ja     L17
  mov    %r12,%rsi
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %rsi,%rcx
  movzbl 0x1(%rsi),%edi
  add    $0x1,%rsi
  lea    -0x1(%rdi),%edx
  cmp    $0x1f,%dl
  jbe    L52
  cmp    %rsi,%r12
  je     L17
  sub    %rcx,%rax
  mov    %r12,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
L17:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trim(char *str) {
  if (str == NULL)
    return NULL;
  size_t len = strlen(str);
  unsigned char *ustr = (unsigned char *)str;
  unsigned char *right = ustr + len;
  while (*right <= 0x20 && right >= ustr) {
    --right;
  }
  *++right = '\0';
  unsigned char *left = ustr;
  while (*left <= 0x20 && *left != '\0')
    ++left;
  if (left != ustr)
    memmove(ustr, left, right - left + 1);
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<udp_socket_listen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L38
  mov    $0xffffffff,%eax
  jmp    L1
L38:
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x10(%rbp)
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L48
  mov    $0xfffffffe,%eax
  jmp    L1
L48:
  mov    -0x1c(%rbp),%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
int udp_socket_listen(int port) {
  int sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (sock < 0)
    return -1;
  struct sockaddr_in listen_addr;
  memset(&listen_addr, 0, sizeof(struct sockaddr_in));
  listen_addr.sin_family = AF_INET;
  listen_addr.sin_port = htons(port);
  listen_addr.sin_addr.s_addr = INADDR_ANY;
  int res = bind(sock, (struct sockaddr *)&listen_addr, sizeof(struct sockaddr_in));
  if (res < 0)
    return -2;
  return sock;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<udp_socket_listen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D27(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L26
  mov    %eax,%ebx
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  test   %eax,%eax
  mov    $0xfffffffe,%eax
  cmovs  %eax,%ebx
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    $0xffffffff,%ebx
  jmp    L14
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_socket_listen(int port) {
  int sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (sock < 0)
    return -1;
  struct sockaddr_in listen_addr;
  memset(&listen_addr, 0, sizeof(struct sockaddr_in));
  listen_addr.sin_family = AF_INET;
  listen_addr.sin_port = htons(port);
  listen_addr.sin_addr.s_addr = INADDR_ANY;
  int res = bind(sock, (struct sockaddr *)&listen_addr, sizeof(struct sockaddr_in));
  if (res < 0)
    return -2;
  return sock;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udp_socket_listen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L19
  lea    0xc(%rsp),%r13
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D19(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %r12d,%edi
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %eax,0x10(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  mov    $0xfffffffe,%eax
  cmovs  %eax,%r12d
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L19:
  mov    $0xffffffff,%r12d
  jmp    L2
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_socket_listen(int port) {
  int sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (sock < 0)
    return -1;
  struct sockaddr_in listen_addr;
  memset(&listen_addr, 0, sizeof(struct sockaddr_in));
  listen_addr.sin_family = AF_INET;
  listen_addr.sin_port = htons(port);
  listen_addr.sin_addr.s_addr = INADDR_ANY;
  int res = bind(sock, (struct sockaddr *)&listen_addr, sizeof(struct sockaddr_in));
  if (res < 0)
    return -2;
  return sock;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<udp_socket_listen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D48(%rip),%rax
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L4
  lea    0x8(%rsp),%r13
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D19(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    D9(%rip),%rdx
  mov    %r12d,%edi
  mov    %r13,%rsi
  movd   %eax,%xmm1
  movd   (%rdx),%xmm0
  mov    $0xc,%edx
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  mov    $0xfffffffe,%eax
  cmovs  %eax,%r12d
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  mov    $0xffffffff,%r12d
  jmp    L3
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_socket_listen(int port) {
  int sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (sock < 0)
    return -1;
  struct sockaddr_in listen_addr;
  memset(&listen_addr, 0, sizeof(struct sockaddr_in));
  listen_addr.sin_family = AF_INET;
  listen_addr.sin_port = htons(port);
  listen_addr.sin_addr.s_addr = INADDR_ANY;
  int res = bind(sock, (struct sockaddr *)&listen_addr, sizeof(struct sockaddr_in));
  if (res < 0)
    return -2;
  return sock;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L9:
  cmpl   $0x31,-0x8(%rbp)
  jg     L15
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x63,-0x8(%rbp)
  jle    L9
  jmp    L2
L15:
  nop
L2:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 50)
      break;
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  mov    $0x32,%eax
L6:
  sub    $0x1,%eax
  jne    L6
  mov    $0x4c9,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 50)
      break;
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  mov    $0x4c9,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 50)
      break;
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  mov    $0x4c9,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 50)
      break;
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *permute(int p[], int plength, char *text) {
  char *permutated = malloc(sizeof(char) * (plength + 1));
  int i;
  for (i = 0; i < plength; i++) {
    permutated[i] = text[p[i] - 1];
  }
  permutated[i] = '\0';
  return permutated;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<permute>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  jle    L5
  mov    %r12d,%esi
  mov    $0x0,%edx
L10:
  movslq (%rbx,%rdx,4),%rcx
  movzbl -0x1(%rbp,%rcx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L10
L13:
  movslq %r12d,%r12
  movb   $0x0,(%rax,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0x0,%r12d
  jmp    L13
```

assistant: ```c
char *permute(int p[], int plength, char *text) {
  char *permutated = malloc(sizeof(char) * (plength + 1));
  int i;
  for (i = 0; i < plength; i++) {
    permutated[i] = text[p[i] - 1];
  }
  permutated[i] = '\0';
  return permutated;
}
```
user: What is the c source code of the assembly code below?

```asm
<permute>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L4
  movslq %ebx,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L6:
  movslq 0x0(%rbp,%rcx,4),%rdi
  movzbl -0x1(%r12,%rdi,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L6
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *permute(int p[], int plength, char *text) {
  char *permutated = malloc(sizeof(char) * (plength + 1));
  int i;
  for (i = 0; i < plength; i++) {
    permutated[i] = text[p[i] - 1];
  }
  permutated[i] = '\0';
  return permutated;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<permute>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L13
  movslq %ebx,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L3:
  movslq 0x0(%rbp,%rcx,4),%rdi
  movzbl -0x1(%r12,%rdi,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L3
  add    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rax,%rsi
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *permute(int p[], int plength, char *text) {
  char *permutated = malloc(sizeof(char) * (plength + 1));
  int i;
  for (i = 0; i < plength; i++) {
    permutated[i] = text[p[i] - 1];
  }
  permutated[i] = '\0';
  return permutated;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<d_getnumbyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L36
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L16
L36:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    $0xffffffff,%eax
L16:
  leave
  ret
```

assistant: ```c
int d_getnumbyname(const char **arr, int arr_size, const char *str) {
  int i;
  for (i = 0; i < arr_size; i++) {
    if (strncmp(arr[i], str, 3) == 0) {
      return i + 1;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d_getnumbyname>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L34:
  mov    (%r12,%rbx,8),%rdi
  mov    $0x3,%edx
  mov    %r13,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L19
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L34
  mov    $0xffffffff,%eax
  jmp    L36
L19:
  lea    0x1(%rbx),%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int d_getnumbyname(const char **arr, int arr_size, const char *str) {
  int i;
  for (i = 0; i < arr_size; i++) {
    if (strncmp(arr[i], str, 3) == 0) {
      return i + 1;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<d_getnumbyname>:
  endbr64
  test   %esi,%esi
  jle    L34
  push   %r13
  lea    0x1(%rsi),%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L20
L15:
  mov    -0x8(%r12,%rbx,8),%rdi
  mov    $0x3,%edx
  mov    %rbp,%rsi
  call   <strncmp@plt>
  mov    %ebx,%r8d
  test   %rax,%rax
  jne    L16
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int d_getnumbyname(const char **arr, int arr_size, const char *str) {
  int i;
  for (i = 0; i < arr_size; i++) {
    if (strncmp(arr[i], str, 3) == 0) {
      return i + 1;
    }
  }
  return -1;
}
```