ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<be_to_le>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L10
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    -0x1(%rdi,%rsi,1),%rdx
L16:
  movzbl (%rdx),%esi
  movzbl (%rdi,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%r8d
  jg     L16
L10:
  ret
```

assistant: ```c
void be_to_le(void *vdata, int bytes) {
  char tmp;
  unsigned char *data = (unsigned char *)vdata;
  for (int i = 0; i < bytes / 2; i++) {
    tmp = *(data + i);
    *(data + i) = *(data + bytes - 1 - i);
    *(data + bytes - 1 - i) = tmp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HariMain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0xa0000,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  and    $0xf,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0xffff,-0xc(%rbp)
  jle    L6
L4:
  mov    $0x0,%eax
  call   <io_hlt@plt>
  jmp    L4
```

assistant: ```c
void HariMain(void) {
  int i;
  char *p;
  p = (char *)0xa0000;
  for (i = 0; i <= 0xffff; i++) {
    *(p + i) = i & 0x0f;
  }
  for (;;) {
    io_hlt();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HariMain>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0000,%eax
L13:
  mov    %eax,%edx
  and    $0xf,%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    $0xb0000,%rax
  jne    L13
L16:
  mov    $0x0,%eax
  call   <io_hlt@plt>
  jmp    L16
```

assistant: ```c
void HariMain(void) {
  int i;
  char *p;
  p = (char *)0xa0000;
  for (i = 0; i <= 0xffff; i++) {
    *(p + i) = i & 0x0f;
  }
  for (;;) {
    io_hlt();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HariMain>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0000,%eax
  nopl   (%rax)
L3:
  mov    %eax,%edx
  add    $0x1,%rax
  and    $0xf,%edx
  mov    %dl,-0x1(%rax)
  cmp    $0xb0000,%rax
  jne    L3
L14:
  xor    %eax,%eax
  call   <io_hlt@plt>
  xor    %eax,%eax
  call   <io_hlt@plt>
  jmp    L14
```

assistant: ```c
void HariMain(void) {
  int i;
  char *p;
  p = (char *)0xa0000;
  for (i = 0; i <= 0xffff; i++) {
    *(p + i) = i & 0x0f;
  }
  for (;;) {
    io_hlt();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HariMain>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa0000,%eax
  nopl   (%rax)
L8:
  mov    %eax,%edx
  add    $0x1,%rax
  and    $0xf,%edx
  mov    %dl,-0x1(%rax)
  cmp    $0xb0000,%rax
  jne    L8
L3:
  xor    %eax,%eax
  call   <io_hlt@plt>
  xor    %eax,%eax
  call   <io_hlt@plt>
  jmp    L3
```

assistant: ```c
void HariMain(void) {
  int i;
  char *p;
  p = (char *)0xa0000;
  for (i = 0; i <= 0xffff; i++) {
    *(p + i) = i & 0x0f;
  }
  for (;;) {
    io_hlt();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L35
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L6:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jns    L1
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L1:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <qsort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <qsort>
  jmp    L3
L35:
  nop
L3:
  leave
  ret
```

assistant: ```c
void qsort(void *v[], int left, int right, int (*comp)(void *, void *)) {
  int i, last;
  void swap(void *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if ((*comp)(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  qsort(v, left, last - 1, comp);
  qsort(v, last + 1, right, comp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<qsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  cmp    %edx,%esi
  jl     L62
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    %rdi,%rbp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %esi,%ebx
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  mov    %esi,%r14d
  call   <swap@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jl     L41
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,8),%r15
  movslq %ebx,%rbx
  jmp    L59
L26:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L60
L59:
  mov    %ebx,0x8(%rsp)
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    (%r15),%rsi
  call   *%r13
  test   %eax,%eax
  jns    L26
  add    $0x1,%r14d
  mov    0x8(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L26
L41:
  mov    0xc(%rsp),%r14d
L60:
  mov    %r14d,%edx
  mov    0xc(%rsp),%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13,%rcx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <qsort>
  lea    0x1(%r14),%esi
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <qsort>
  jmp    L68
```

assistant: ```c
void qsort(void *v[], int left, int right, int (*comp)(void *, void *)) {
  int i, last;
  void swap(void *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if ((*comp)(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  qsort(v, left, last - 1, comp);
  qsort(v, last + 1, right, comp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qsort>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rcx,(%rsp)
L54:
  cmp    %r15d,%ebp
  jle    L40
L20:
  lea    0x0(%rbp,%r15,1),%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r15),%ecx
  cmp    %ecx,%ebp
  jl     L29
  movslq %r15d,%rax
  movslq %ecx,%r14
  mov    %r15d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L33
L5:
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L39
L33:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r14,8),%rdi
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L5
  add    $0x1,%r13d
  mov    %r14d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r14
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r14d,%ebp
  jge    L33
L39:
  mov    %r15d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    (%rsp),%rcx
  mov    %r15d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  lea    0x1(%r13),%r15d
  call   <qsort>
  cmp    %ebp,%r15d
  jl     L20
L40:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r15d,%edx
  mov    %r15d,%esi
  lea    -0x1(%r15),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L54
```

assistant: ```c
void qsort(void *v[], int left, int right, int (*comp)(void *, void *)) {
  int i, last;
  void swap(void *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if ((*comp)(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  qsort(v, left, last - 1, comp);
  qsort(v, last + 1, right, comp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<qsort>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rcx,(%rsp)
L30:
  cmp    %r15d,%ebp
  jle    L71
L33:
  lea    0x0(%rbp,%r15,1),%eax
  mov    %r15d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r15),%ecx
  cmp    %ecx,%ebp
  jl     L21
  movslq %r15d,%rax
  movslq %ecx,%r14
  mov    %r15d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L8
L57:
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jl     L24
L8:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r14,8),%rdi
  mov    (%rax),%rsi
  mov    (%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jns    L57
  add    $0x1,%r13d
  mov    %r14d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r14
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r14d,%ebp
  jge    L8
L24:
  mov    %r15d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    (%rsp),%rcx
  mov    %r15d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  lea    0x1(%r13),%r15d
  call   <qsort>
  cmp    %ebp,%r15d
  jl     L33
L71:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r15d,%edx
  mov    %r15d,%esi
  lea    -0x1(%r15),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L30
```

assistant: ```c
void qsort(void *v[], int left, int right, int (*comp)(void *, void *)) {
  int i, last;
  void swap(void *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if ((*comp)(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  qsort(v, left, last - 1, comp);
  qsort(v, last + 1, right, comp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L19
L12:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int puts(const char *str) {
  size_t len = strlen(str);
  for (size_t i = 0; i < len; i++)
    putchar(str[i]);
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<puts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %rbp,%rbx
  add    %rax,%rbp
L16:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
L9:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int puts(const char *str) {
  size_t len = strlen(str);
  for (size_t i = 0; i < len; i++)
    putchar(str[i]);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  lea    (%rbx,%rax,1),%rbp
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L16
L6:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int puts(const char *str) {
  size_t len = strlen(str);
  for (size_t i = 0; i < len; i++)
    putchar(str[i]);
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<puts>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  lea    (%rbx,%rax,1),%rbp
  nopl   0x0(%rax)
L1:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L1
L8:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int puts(const char *str) {
  size_t len = strlen(str);
  for (size_t i = 0; i < len; i++)
    putchar(str[i]);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L62
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L99
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L62
L99:
  movl   $0x2,-0x18(%rbp)
  jmp    L62
L77:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    $0x39,%eax
  jle    L110
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  add    %ebx,%eax
  sub    $0x57,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L71
L110:
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  add    %ebx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
L71:
  addl   $0x1,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L106
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L77
L106:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L46
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L77
L46:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L61
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L77
L61:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int htoi(const char *s) {
  int i = 0;
  unsigned int n = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    i = 2;
  for (; (s[i] >= '0' && s[i] <= '9') || (s[i] >= 'a' && s[i] <= 'z') || (s[i] >= 'A' && s[i] <= 'Z'); i++) {
    if (tolower(s[i]) > '9')
      n = 16 * n + (10 + tolower(s[i]) - 'a');
    else
      n = 16 * n + (tolower(s[i]) - '0');
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<htoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  cmpb   $0x30,(%rdi)
  je     L46
L28:
  cltq
  lea    (%rdi,%rax,1),%rbx
  mov    $0x0,%ebp
  jmp    L31
L46:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  jmp    L28
L25:
  movsbl (%r12),%edi
  call   <tolower@plt>
  shl    $0x4,%ebp
  lea    -0x30(%rbp,%rax,1),%ebp
L10:
  add    $0x1,%rbx
L31:
  mov    %rbx,%r12
  movzbl (%rbx),%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L32
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L69
L32:
  movsbl %dil,%edi
  call   <tolower@plt>
  cmp    $0x39,%eax
  jle    L25
  movsbl (%r12),%edi
  call   <tolower@plt>
  shl    $0x4,%ebp
  lea    -0x57(%rbp,%rax,1),%ebp
  jmp    L10
L69:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int htoi(const char *s) {
  int i = 0;
  unsigned int n = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    i = 2;
  for (; (s[i] >= '0' && s[i] <= '9') || (s[i] >= 'a' && s[i] <= 'z') || (s[i] >= 'A' && s[i] <= 'Z'); i++) {
    if (tolower(s[i]) > '9')
      n = 16 * n + (10 + tolower(s[i]) - 'a');
    else
      n = 16 * n + (tolower(s[i]) - '0');
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<htoi>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  cmp    $0x30,%dil
  jne    L53
  movzbl 0x1(%rbx),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  cltq
  movsbl (%rbx,%rax,1),%edi
L53:
  add    %rax,%rbx
  xor    %r12d,%r12d
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L11:
  call   <tolower@plt>
  lea    -0x57(%r12,%rax,1),%r12d
L28:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L0:
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L15
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L47
L15:
  call   <tolower@plt>
  shl    $0x4,%r12d
  movsbl (%rbx),%edi
  cmp    $0x39,%eax
  jg     L11
  call   <tolower@plt>
  lea    -0x30(%r12,%rax,1),%r12d
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int htoi(const char *s) {
  int i = 0;
  unsigned int n = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    i = 2;
  for (; (s[i] >= '0' && s[i] <= '9') || (s[i] >= 'a' && s[i] <= 'z') || (s[i] >= 'A' && s[i] <= 'Z'); i++) {
    if (tolower(s[i]) > '9')
      n = 16 * n + (10 + tolower(s[i]) - 'a');
    else
      n = 16 * n + (tolower(s[i]) - '0');
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<htoi>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x30,(%rdi)
  jne    L40
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L40:
  cltq
  xor    %r12d,%r12d
  lea    (%rdi,%rax,1),%rbx
  jmp    L57
  xchg   %ax,%ax
L31:
  call   <tolower@plt>
  lea    -0x57(%r12,%rax,1),%r12d
L49:
  add    $0x1,%rbx
L57:
  movsbl (%rbx),%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L35
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L44
L35:
  call   <tolower@plt>
  shl    $0x4,%r12d
  movsbl (%rbx),%edi
  cmp    $0x39,%eax
  jg     L31
  call   <tolower@plt>
  lea    -0x30(%r12,%rax,1),%r12d
  jmp    L49
  nopl   0x0(%rax)
L44:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int htoi(const char *s) {
  int i = 0;
  unsigned int n = 0;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    i = 2;
  for (; (s[i] >= '0' && s[i] <= '9') || (s[i] >= 'a' && s[i] <= 'z') || (s[i] >= 'A' && s[i] <= 'Z'); i++) {
    if (tolower(s[i]) > '9')
      n = 16 * n + (10 + tolower(s[i]) - 'a');
    else
      n = 16 * n + (tolower(s[i]) - '0');
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SHR_W_IMM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L5
  mov    $0x41,%edi
  call   <addbyte@plt>
L5:
  mov    $0xc1,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  or     $0xe8,%al
  mov    %eax,%edi
  call   <addbyte@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  nop
  leave
  ret
```

assistant: ```c
void SHR_W_IMM(int reg, int count) {
  addbyte(0x66);
  if (reg & 8)
    addbyte(0x41);
  addbyte(0xc1);
  addbyte(0xc0 | (reg & 7) | 0x28);
  addbyte(count);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SHR_W_IMM>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x66,%edi
  call   <addbyte@plt>
  test   $0x8,%bl
  jne    L14
L9:
  mov    $0xc1,%edi
  call   <addbyte@plt>
  and    $0x7,%ebx
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  mov    %ebp,%edi
  call   <addbyte@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L9
```

assistant: ```c
void SHR_W_IMM(int reg, int count) {
  addbyte(0x66);
  if (reg & 8)
    addbyte(0x41);
  addbyte(0xc1);
  addbyte(0xc0 | (reg & 7) | 0x28);
  addbyte(count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SHR_W_IMM>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x66,%edi
  sub    $0x8,%rsp
  call   <addbyte@plt>
  test   $0x8,%bl
  jne    L10
L0:
  mov    $0xc1,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <addbyte@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L0
```

assistant: ```c
void SHR_W_IMM(int reg, int count) {
  addbyte(0x66);
  if (reg & 8)
    addbyte(0x41);
  addbyte(0xc1);
  addbyte(0xc0 | (reg & 7) | 0x28);
  addbyte(count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SHR_W_IMM>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x66,%edi
  sub    $0x8,%rsp
  call   <addbyte@plt>
  test   $0x8,%bl
  jne    L10
L17:
  mov    $0xc1,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <addbyte@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L17
```

assistant: ```c
void SHR_W_IMM(int reg, int count) {
  addbyte(0x66);
  if (reg & 8)
    addbyte(0x41);
  addbyte(0xc1);
  addbyte(0xc0 | (reg & 7) | 0x28);
  addbyte(count);
}
```