ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_newwin>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L13
  lea    D5(%rip),%rbp
  mov    (%rbx),%rdi
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L52
  mov    0x8(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L52
  mov    0x10(%rbx),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L52
  mov    0x18(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L52
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x8(%rsp),%edi
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  call   <newwin@plt>
  mov    %eax,%edi
  call   <report_ptr@plt>
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D4(%rip),%rdi
  call   <report_error@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D5: %d

tool: D4: BAD ARGUMENT

assistant: ```c
void cmd_newwin(int nargs, char **args) {
  int lines, cols, begin_y, begin_x;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%d", &lines) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &cols) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &begin_y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &begin_x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_ptr(newwin(lines, cols, begin_y, begin_x));
}
```
user: What is the c source code of the assembly code below:

```asm
<cmd_newwin>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L62
  lea    D16(%rip),%rbp
  mov    (%rbx),%rdi
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L9
  mov    0x8(%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L9
  mov    0x10(%rbx),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L9
  mov    0x18(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x8(%rsp),%edi
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  call   <newwin@plt>
  mov    %eax,%edi
  call   <report_ptr@plt>
  jmp    L62
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  call   <report_error@plt>
L62:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D16: %d

tool: D9: BAD ARGUMENT

assistant: ```c
void cmd_newwin(int nargs, char **args) {
  int lines, cols, begin_y, begin_x;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%d", &lines) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &cols) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &begin_y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &begin_x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_ptr(newwin(lines, cols, begin_y, begin_x));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lfb_exit_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void lfb_exit_error(char *str) {
  write(1, str, strlen(str));
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lfb_exit_error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

assistant: ```c
void lfb_exit_error(char *str) {
  write(1, str, strlen(str));
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lfb_exit_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void lfb_exit_error(char *str) {
  write(1, str, strlen(str));
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lfb_exit_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void lfb_exit_error(char *str) {
  write(1, str, strlen(str));
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x3c(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  int x = array[0].a + array[1].a;
  double y = array[0].b + array[1].b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  int x = array[0].a + array[1].a;
  double y = array[0].b + array[1].b;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  int x = array[0].a + array[1].a;
  double y = array[0].b + array[1].b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  int x = array[0].a + array[1].a;
  double y = array[0].b + array[1].b;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_fpathconf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L19
  mov    $0x0,%eax
  call   <libau_dl_fpathconf@plt>
  test   %eax,%eax
  jne    L5
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <real_fpathconf@plt>
  mov    %rax,-0x8(%rbp)
L5:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    D7(%rip),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L19:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long do_fpathconf(int fd, int name) {
  long err;
  int wbr_fd, e;
  err = -1;
  wbr_fd = ioctl(fd, AUFS_CTL_WBR_FD);
  if (wbr_fd >= 0) {
    if (!libau_dl_fpathconf())
      err = real_fpathconf(wbr_fd, name);
    e = errno;
    close(wbr_fd);
    errno = e;
  }
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_fpathconf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L6
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <libau_dl_fpathconf@plt>
  mov    $0xffffffffffffffff,%rbp
  test   %eax,%eax
  je     L19
L4:
  mov    D3(%rip),%r12
  mov    (%r12),%r13d
  mov    %ebx,%edi
  call   <close@plt>
  mov    %r13d,(%r12)
L7:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <real_fpathconf@plt>
  mov    %rax,%rbp
  jmp    L4
L6:
  mov    $0xffffffffffffffff,%rbp
  jmp    L7
```

assistant: ```c
long do_fpathconf(int fd, int name) {
  long err;
  int wbr_fd, e;
  err = -1;
  wbr_fd = ioctl(fd, AUFS_CTL_WBR_FD);
  if (wbr_fd >= 0) {
    if (!libau_dl_fpathconf())
      err = real_fpathconf(wbr_fd, name);
    e = errno;
    close(wbr_fd);
    errno = e;
  }
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_fpathconf>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L38
  mov    %eax,%ebp
  xor    %eax,%eax
  mov    $0xffffffffffffffff,%r12
  call   <libau_dl_fpathconf@plt>
  test   %eax,%eax
  je     L21
L22:
  mov    D1(%rip),%rbx
  mov    %ebp,%edi
  mov    (%rbx),%r13d
  call   <close@plt>
  mov    %r13d,(%rbx)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <real_fpathconf@plt>
  mov    %rax,%r12
  jmp    L22
  nop
L38:
  mov    $0xffffffffffffffff,%r12
  jmp    L9
```

assistant: ```c
long do_fpathconf(int fd, int name) {
  long err;
  int wbr_fd, e;
  err = -1;
  wbr_fd = ioctl(fd, AUFS_CTL_WBR_FD);
  if (wbr_fd >= 0) {
    if (!libau_dl_fpathconf())
      err = real_fpathconf(wbr_fd, name);
    e = errno;
    close(wbr_fd);
    errno = e;
  }
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_fpathconf>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  js     L20
  mov    %eax,%ebp
  xor    %eax,%eax
  mov    $0xffffffffffffffff,%r12
  call   <libau_dl_fpathconf@plt>
  test   %eax,%eax
  je     L36
L34:
  mov    D0(%rip),%rbx
  mov    %ebp,%edi
  mov    (%rbx),%r13d
  call   <close@plt>
  mov    %r13d,(%rbx)
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L36:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <real_fpathconf@plt>
  mov    %rax,%r12
  jmp    L34
  nop
L20:
  mov    $0xffffffffffffffff,%r12
  jmp    L1
```

assistant: ```c
long do_fpathconf(int fd, int name) {
  long err;
  int wbr_fd, e;
  err = -1;
  wbr_fd = ioctl(fd, AUFS_CTL_WBR_FD);
  if (wbr_fd >= 0) {
    if (!libau_dl_fpathconf())
      err = real_fpathconf(wbr_fd, name);
    e = errno;
    close(wbr_fd);
    errno = e;
  }
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lucas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L35
  mov    $0x2,%eax
  jmp    L32
L35:
  cmpl   $0x1,-0x14(%rbp)
  jne    L10
  mov    $0x1,%eax
  jmp    L32
L10:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <lucas>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <lucas>
  add    %ebx,%eax
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lucas(int n) {
  if (n == 0) {
    return 2;
  }
  if (n == 1) {
    return 1;
  }
  return lucas(n - 1) + lucas(n - 2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lucas>:
  endbr64
  mov    $0x2,%eax
  test   %edi,%edi
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L6
  lea    -0x1(%rdi),%edi
  call   <lucas>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <lucas>
  add    %ebp,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  ret
```

assistant: ```c
int lucas(int n) {
  if (n == 0) {
    return 2;
  }
  if (n == 1) {
    return 1;
  }
  return lucas(n - 1) + lucas(n - 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_center>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: byte[8]

tool: {"D14": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

assistant: ```c
void get_center(const double *a, const double *b, const double *c, double *cc) {
  static const double third = (1. / 3.);
  cc[0] = (a[0] + b[0] + c[0]) * third;
  cc[1] = (a[1] + b[1] + c[1]) * third;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_center>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  movsd  D4(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  movsd  0x8(%rdi),%xmm0
  addsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: byte[8]

tool: {"D4": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

assistant: ```c
void get_center(const double *a, const double *b, const double *c, double *cc) {
  static const double third = (1. / 3.);
  cc[0] = (a[0] + b[0] + c[0]) * third;
  cc[1] = (a[1] + b[1] + c[1]) * third;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_center>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  movsd  0x8(%rdi),%xmm0
  addsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: byte[8]

tool: {"D7": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

assistant: ```c
void get_center(const double *a, const double *b, const double *c, double *cc) {
  static const double third = (1. / 3.);
  cc[0] = (a[0] + b[0] + c[0]) * third;
  cc[1] = (a[1] + b[1] + c[1]) * third;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_center>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  movsd  D3(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  movsd  0x8(%rdi),%xmm0
  addsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: byte[8]

tool: {"D3": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

assistant: ```c
void get_center(const double *a, const double *b, const double *c, double *cc) {
  static const double third = (1. / 3.);
  cc[0] = (a[0] + b[0] + c[0]) * third;
  cc[1] = (a[1] + b[1] + c[1]) * third;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<alive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L24
  mov    $0x1,%eax
  jmp    L8
L24:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int alive(int *arr, int lenght) {
  int i;
  for (i = 0; i < lenght; i++) {
    if (arr[i] == 1) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<alive>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
L27:
  mov    (%rax),%edx
  cmp    $0x1,%edx
  je     L20
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L27
  mov    $0x0,%edx
L20:
  mov    %edx,%eax
  ret
L8:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int alive(int *arr, int lenght) {
  int i;
  for (i = 0; i < lenght; i++) {
    if (arr[i] == 1) {
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alive>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L21
L36:
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  jne    L19
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int alive(int *arr, int lenght) {
  int i;
  for (i = 0; i < lenght; i++) {
    if (arr[i] == 1) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<alive>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L0
L19:
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  jne    L18
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int alive(int *arr, int lenght) {
  int i;
  for (i = 0; i < lenght; i++) {
    if (arr[i] == 1) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<poly_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L49
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  jmp    L11
L49:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L11:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void poly_sum(double a[], int Na, double b[], int Nb, double ans[], int Nans) {
  int i;
  Nans = Na > Nb ? Na : Nb;
  for (i = 0; i < Nans; i++) {
    if (Na > Nb) {
      ans[i] = a[i];
      if (i > Na - Nb - 1) {
        ans[i] = ans[i] + b[i - Na + Nb];
      }
    } else {
      ans[i] = b[i];
      if (i > Nb - Na - 1) {
        ans[i] = ans[i] + a[i - Nb + Na];
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<poly_sum>:
  endbr64
  mov    %rdx,%r9
  mov    %ecx,%edx
  cmp    %esi,%ecx
  mov    %esi,%ecx
  cmovge %edx,%ecx
  test   %ecx,%ecx
  jle    L38
  push   %rbx
  mov    %ecx,%ecx
  mov    $0x0,%eax
  mov    %edx,%ebx
  sub    %esi,%ebx
  mov    %esi,%r11d
  sub    %edx,%r11d
  jmp    L17
L32:
  movsd  (%r9,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  cmp    %eax,%ebx
  jg     L46
  lea    (%r11,%rax,1),%r10d
  movslq %r10d,%r10
  addsd  (%rdi,%r10,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L46:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L6
L17:
  cmp    %esi,%edx
  jge    L32
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  cmp    %eax,%r11d
  jg     L46
  lea    (%rbx,%rax,1),%r10d
  movslq %r10d,%r10
  addsd  (%r9,%r10,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  jmp    L46
L6:
  pop    %rbx
  ret
L38:
  ret
```

assistant: ```c
void poly_sum(double a[], int Na, double b[], int Nb, double ans[], int Nans) {
  int i;
  Nans = Na > Nb ? Na : Nb;
  for (i = 0; i < Nans; i++) {
    if (Na > Nb) {
      ans[i] = a[i];
      if (i > Na - Nb - 1) {
        ans[i] = ans[i] + b[i - Na + Nb];
      }
    } else {
      ans[i] = b[i];
      if (i > Nb - Na - 1) {
        ans[i] = ans[i] + a[i - Nb + Na];
      }
    }
  }
}
```