user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  jg     L55
  mov    $0x1,%eax
  jmp    L9
L55:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D80(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L9
L16:
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L7
L23:
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edi
  movzbl -0xa(%rbp),%eax
  movzbl %al,%esi
  movzbl -0xb(%rbp),%eax
  movzbl %al,%ecx
  movzbl -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L23
  jmp    L44
L46:
  mov    -0x20(%rbp),%eax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L44:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L46
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D80
type: string
name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D74
type: string
name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D37
type: string
name: read_data
arguments: label: D1
type: string

tool: D80: rb

tool: D17: DEPTH = %d;


tool: D38: WIDTH = 32;

tool: D26: ADDRESS_RADIX = HEX;

tool: D9: DATA_RADIX = HEX;

tool: D74: CONTENT

tool: D2: BEGIN

tool: D37: %x : %02X%02X%02X%02X;


tool: D1: END;

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char x[4];
  int i, n;
  FILE *f;
  if (argc < 3)
    return 1;
  if (!(f = fopen(argv[1], "rb")))
    return 1;
  n = atoi(argv[2]) / 4;
  printf("DEPTH = %d;\n", n);
  printf("WIDTH = 32;\n");
  printf("ADDRESS_RADIX = HEX;\n");
  printf("DATA_RADIX = HEX;\n");
  printf("CONTENT\n");
  printf("BEGIN\n");
  for (i = 0; !feof(f); ++i) {
    fread(x, 1, 4, f);
    printf("%x : %02X%02X%02X%02X;\n", i, x[0], x[1], x[2], x[3]);
  }
  for (; i < n; ++i) {
    printf("%x : %02X%02X%02X%02X;\n", i, 0, 0, 0, 0);
  }
  printf("END;\n");
  fclose(f);
  return 0;
}
```