ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DecStart>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EFifoStart@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x400f,%edi
  call   <McDevIf_ReadDirect@plt>
  movzbl 0x7(%rsp),%esi
  test   %rbp,%rbp
  jne    L4
  or     $0x1,%esi
L26:
  mov    $0x2000400f,%edi
  mov    %sil,0x7(%rsp)
  movzbl %sil,%esi
  call   <McDevIf_AddPacket@plt>
  xor    %eax,%eax
  call   <McDevIf_ExecutePacket@plt>
  mov    %rbp,%rdi
  call   <OFifoStart@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  or     $0x8,%esi
  jmp    L26
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed long DecStart(unsigned long dCoderId) {
  signed long sdRet = ((signed long)0);
  unsigned char bData;
  EFifoStart(dCoderId);
  McDevIf_ReadDirect(((0x00004000UL) | (unsigned long)(15)), &bData);
  if ((0UL) == dCoderId) {
    bData |= (0x01);
  } else {
    bData |= (0x08);
  }
  McDevIf_AddPacket(((0x20000000UL) | (0x00004000UL) | (unsigned long)(15)), bData);
  McDevIf_ExecutePacket();
  sdRet = OFifoStart(dCoderId);
  return sdRet;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L12:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cmp    %rax,%rdx
  jb     L12
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  sub    $0x1,%rdx
  imul   %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    %rax,%rcx
  jae    L5
  mov    -0x8(%rbp),%rax
  sub    $0x1,%eax
  jmp    L38
L5:
  mov    -0x8(%rbp),%rax
L38:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ft_sqrt(unsigned int n) {
  unsigned long int res;
  res = 0;
  while (res * res < n)
    res++;
  if (n - (res - 1) * (res - 1) < n - res * res)
    return (res - 1);
  return ((unsigned int)res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_sqrt>:
  endbr64
  mov    %edi,%edi
  test   %rdi,%rdi
  je     L2
  mov    $0x0,%eax
L25:
  mov    %rax,%rcx
  add    $0x1,%rax
  mov    %rax,%rdx
  imul   %rax,%rdx
  cmp    %rdi,%rdx
  jb     L25
  imul   %rcx,%rcx
  mov    %rdi,%rsi
  sub    %rcx,%rsi
  sub    %rdx,%rdi
  cmp    %rdi,%rsi
  jb     L1
L4:
  ret
L1:
  sub    $0x1,%eax
  ret
L2:
  mov    %rdi,%rax
  jmp    L4
```

assistant: ```c
unsigned int ft_sqrt(unsigned int n) {
  unsigned long int res;
  res = 0;
  while (res * res < n)
    res++;
  if (n - (res - 1) * (res - 1) < n - res * res)
    return (res - 1);
  return ((unsigned int)res);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_sqrt>:
  endbr64
  mov    %edi,%edi
  test   %rdi,%rdi
  je     L4
  xor    %eax,%eax
  nopl   (%rax)
L13:
  mov    %rax,%rcx
  add    $0x1,%rax
  mov    %rax,%rdx
  imul   %rax,%rdx
  cmp    %rdi,%rdx
  jb     L13
  imul   %rcx,%rcx
  mov    %rdi,%rsi
  sub    %rdx,%rdi
  sub    %rcx,%rsi
  cmp    %rdi,%rsi
  sbb    $0x0,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int ft_sqrt(unsigned int n) {
  unsigned long int res;
  res = 0;
  while (res * res < n)
    res++;
  if (n - (res - 1) * (res - 1) < n - res * res)
    return (res - 1);
  return ((unsigned int)res);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_sqrt>:
  endbr64
  mov    %edi,%edi
  test   %rdi,%rdi
  je     L6
  xor    %eax,%eax
  nopl   (%rax)
L9:
  mov    %rax,%rcx
  add    $0x1,%rax
  mov    %rax,%rdx
  imul   %rax,%rdx
  cmp    %rdi,%rdx
  jb     L9
  imul   %rcx,%rcx
  mov    %rdi,%rsi
  sub    %rdx,%rdi
  sub    %rcx,%rsi
  cmp    %rdi,%rsi
  sbb    $0x0,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int ft_sqrt(unsigned int n) {
  unsigned long int res;
  res = 0;
  while (res * res < n)
    res++;
  if (n - (res - 1) * (res - 1) < n - res * res)
    return (res - 1);
  return ((unsigned int)res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L18:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int length(char s[]) {
  int i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x1,%eax
L5:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L5
L12:
  mov    %edx,%eax
  ret
L11:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int length(char s[]) {
  int i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L8
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length(char s[]) {
  int i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length(char s[]) {
  int i = 0;
  while (s[i] != '\0') {
    i++;
  }
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<nibble_to_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  ja     L29
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x30,%eax
  jmp    L66
  mov    $0x31,%eax
  jmp    L66
  mov    $0x32,%eax
  jmp    L66
  mov    $0x33,%eax
  jmp    L66
  mov    $0x34,%eax
  jmp    L66
  mov    $0x35,%eax
  jmp    L66
  mov    $0x36,%eax
  jmp    L66
  mov    $0x37,%eax
  jmp    L66
  mov    $0x38,%eax
  jmp    L66
  mov    $0x39,%eax
  jmp    L66
  mov    $0x41,%eax
  jmp    L66
  mov    $0x42,%eax
  jmp    L66
  mov    $0x43,%eax
  jmp    L66
  mov    $0x44,%eax
  jmp    L66
  mov    $0x45,%eax
  jmp    L66
  mov    $0x46,%eax
  jmp    L66
L29:
  mov    $0x30,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t nibble_to_ascii(uint8_t val) {
  switch (val) {
  case 0x0:
    return '0';
  case 0x1:
    return '1';
  case 0x2:
    return '2';
  case 0x3:
    return '3';
  case 0x4:
    return '4';
  case 0x5:
    return '5';
  case 0x6:
    return '6';
  case 0x7:
    return '7';
  case 0x8:
    return '8';
  case 0x9:
    return '9';
  case 0xA:
    return 'A';
  case 0xB:
    return 'B';
  case 0xC:
    return 'C';
  case 0xD:
    return 'D';
  case 0xE:
    return 'E';
  case 0xF:
    return 'F';
  }
  return '0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nibble_to_ascii>:
  endbr64
  cmp    $0xf,%edi
  ja     L0
  mov    %edi,%edi
  lea    D0(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
  ret
  mov    $0x32,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x41,%eax
  ret
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
L0:
  mov    $0x30,%eax
  ret
```

assistant: ```c
uint8_t nibble_to_ascii(uint8_t val) {
  switch (val) {
  case 0x0:
    return '0';
  case 0x1:
    return '1';
  case 0x2:
    return '2';
  case 0x3:
    return '3';
  case 0x4:
    return '4';
  case 0x5:
    return '5';
  case 0x6:
    return '6';
  case 0x7:
    return '7';
  case 0x8:
    return '8';
  case 0x9:
    return '9';
  case 0xA:
    return 'A';
  case 0xB:
    return 'B';
  case 0xC:
    return 'C';
  case 0xD:
    return 'D';
  case 0xE:
    return 'E';
  case 0xF:
    return 'F';
  }
  return '0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nibble_to_ascii>:
  endbr64
  sub    $0x1,%edi
  mov    $0x30,%eax
  cmp    $0xe,%edi
  ja     L0
  lea    D8(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: 1

assistant: ```c
uint8_t nibble_to_ascii(uint8_t val) {
  switch (val) {
  case 0x0:
    return '0';
  case 0x1:
    return '1';
  case 0x2:
    return '2';
  case 0x3:
    return '3';
  case 0x4:
    return '4';
  case 0x5:
    return '5';
  case 0x6:
    return '6';
  case 0x7:
    return '7';
  case 0x8:
    return '8';
  case 0x9:
    return '9';
  case 0xA:
    return 'A';
  case 0xB:
    return 'B';
  case 0xC:
    return 'C';
  case 0xD:
    return 'D';
  case 0xE:
    return 'E';
  case 0xF:
    return 'F';
  }
  return '0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nibble_to_ascii>:
  endbr64
  sub    $0x1,%edi
  mov    $0x30,%eax
  cmp    $0xe,%edi
  ja     L2
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L2:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: 1

assistant: ```c
uint8_t nibble_to_ascii(uint8_t val) {
  switch (val) {
  case 0x0:
    return '0';
  case 0x1:
    return '1';
  case 0x2:
    return '2';
  case 0x3:
    return '3';
  case 0x4:
    return '4';
  case 0x5:
    return '5';
  case 0x6:
    return '6';
  case 0x7:
    return '7';
  case 0x8:
    return '8';
  case 0x9:
    return '9';
  case 0xA:
    return 'A';
  case 0xB:
    return 'B';
  case 0xC:
    return 'C';
  case 0xD:
    return 'D';
  case 0xE:
    return 'E';
  case 0xF:
    return 'F';
  }
  return '0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cmp    $0x1,%eax
  jne    L64
  mov    $0x0,%eax
  call   <encryption@plt>
  jmp    L52
L64:
  mov    -0x20(%rbp),%eax
  cmp    $0x2,%eax
  jne    L61
  mov    $0x0,%eax
  call   <decryption@plt>
  jmp    L52
L61:
  mov    -0x20(%rbp),%eax
  cmp    $0x3,%eax
  jne    L28
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <bruteforce@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L52
L28:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L52:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D41
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: byte[8]
name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D52
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D14: Choose:
1.Encryption
2.Decryption
3.Bruteforce

tool: D41: %d

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D19: Mesos xronos:%f


tool: D52: Prospa9eies: %d 


tool: D22: Den edwses egkuro xaraktira.

tool: D18: PAUSE

assistant: ```c
int main() {
  time_t start, end;
  int t, option;
  void encryption();
  void decryption();
  void bruteforce();
  printf("Choose:\n1.Encryption\n2.Decryption\n3.Bruteforce\n");
  scanf("%d", &option);
  if (option == 1)
    encryption();
  else if (option == 2)
    decryption();
  else if (option == 3) {
    start = time(NULL);
    bruteforce();
    end = time(NULL);
    double mean;
    mean = (end - start) / t;
    printf("Mesos xronos:%f\n", mean / 10);
    printf("Prospa9eies: %d \n", t);
  } else
    printf("Den edwses egkuro xaraktira.\n");
  system("PAUSE");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L16
  cmp    $0x2,%eax
  je     L30
  cmp    $0x3,%eax
  je     L59
  lea    D34(%rip),%rdi
  call   <puts@plt>
L31:
  lea    D37(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  mov    $0x0,%eax
  call   <encryption@plt>
  jmp    L31
L30:
  mov    $0x0,%eax
  call   <decryption@plt>
  jmp    L31
L59:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <bruteforce@plt>
  mov    $0x0,%edi
  call   <time@plt>
  sub    %ebx,%eax
  mov    $0x0,%ebx
  cltd
  idiv   %ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D65(%rip),%xmm0
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string
name: parse_data
arguments: data_label: D37
type_guessed: string
name: parse_data
arguments: data_label: D65
type_guessed: byte[8]
name: parse_data
arguments: data_label: D18
type_guessed: string
name: parse_data
arguments: data_label: D45
type_guessed: string

tool: D10: Choose:
1.Encryption
2.Decryption
3.Bruteforce

tool: D3: %d

tool: D34: Den edwses egkuro xaraktira.

tool: D37: PAUSE

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D18: Mesos xronos:%f


tool: D45: Prospa9eies: %d 


assistant: ```c
int main() {
  time_t start, end;
  int t, option;
  void encryption();
  void decryption();
  void bruteforce();
  printf("Choose:\n1.Encryption\n2.Decryption\n3.Bruteforce\n");
  scanf("%d", &option);
  if (option == 1)
    encryption();
  else if (option == 2)
    decryption();
  else if (option == 3) {
    start = time(NULL);
    bruteforce();
    end = time(NULL);
    double mean;
    mean = (end - start) / t;
    printf("Mesos xronos:%f\n", mean / 10);
    printf("Prospa9eies: %d \n", t);
  } else
    printf("Den edwses egkuro xaraktira.\n");
  system("PAUSE");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D65(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D47(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L60
  cmp    $0x2,%eax
  je     L58
  cmp    $0x3,%eax
  je     L17
  lea    D16(%rip),%rdi
  call   <puts@plt>
L59:
  lea    D29(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L17:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <bruteforce@plt>
  xor    %edi,%edi
  call   <time@plt>
  pxor   %xmm0,%xmm0
  lea    D9(%rip),%rdi
  sub    %ebp,%eax
  xor    %ebp,%ebp
  cltd
  idiv   %ebp
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  divsd  D27(%rip),%xmm0
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L59
L60:
  xor    %eax,%eax
  call   <encryption@plt>
  jmp    L59
L58:
  xor    %eax,%eax
  call   <decryption@plt>
  jmp    L59
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D65
type: string
name: parse_data
arguments: label: D47
type: string
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D27
type: byte[8]
name: parse_data
arguments: label: D19
type: string

tool: D65: Choose:
1.Encryption
2.Decryption
3.Bruteforce

tool: D47: %d

tool: D16: Den edwses egkuro xaraktira.

tool: D29: PAUSE

tool: D9: Mesos xronos:%f


tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D19: Prospa9eies: %d 


assistant: ```c
int main() {
  time_t start, end;
  int t, option;
  void encryption();
  void decryption();
  void bruteforce();
  printf("Choose:\n1.Encryption\n2.Decryption\n3.Bruteforce\n");
  scanf("%d", &option);
  if (option == 1)
    encryption();
  else if (option == 2)
    decryption();
  else if (option == 3) {
    start = time(NULL);
    bruteforce();
    end = time(NULL);
    double mean;
    mean = (end - start) / t;
    printf("Mesos xronos:%f\n", mean / 10);
    printf("Prospa9eies: %d \n", t);
  } else
    printf("Den edwses egkuro xaraktira.\n");
  system("PAUSE");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L40
  cmp    $0x2,%eax
  je     L4
  cmp    $0x3,%eax
  je     L59
  lea    D29(%rip),%rdi
  call   <puts@plt>
L13:
  lea    D37(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L59:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <bruteforce@plt>
  xor    %edi,%edi
  call   <time@plt>
  pxor   %xmm0,%xmm0
  lea    D47(%rip),%rdi
  sub    %ebp,%eax
  xor    %ebp,%ebp
  cltd
  idiv   %ebp
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  divsd  D41(%rip),%xmm0
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L40:
  xor    %eax,%eax
  call   <encryption@plt>
  jmp    L13
L4:
  xor    %eax,%eax
  call   <decryption@plt>
  jmp    L13
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D54
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D47
type_infered: string
name: parse_data
arguments: label: D41
type_infered: byte[8]
name: parse_data
arguments: label: D40
type_infered: string

tool: D20: Choose:
1.Encryption
2.Decryption
3.Bruteforce

tool: D54: %d

tool: D29: Den edwses egkuro xaraktira.

tool: D37: PAUSE

tool: D47: Mesos xronos:%f


tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D40: Prospa9eies: %d 


assistant: ```c
int main() {
  time_t start, end;
  int t, option;
  void encryption();
  void decryption();
  void bruteforce();
  printf("Choose:\n1.Encryption\n2.Decryption\n3.Bruteforce\n");
  scanf("%d", &option);
  if (option == 1)
    encryption();
  else if (option == 2)
    decryption();
  else if (option == 3) {
    start = time(NULL);
    bruteforce();
    end = time(NULL);
    double mean;
    mean = (end - start) / t;
    printf("Mesos xronos:%f\n", mean / 10);
    printf("Prospa9eies: %d \n", t);
  } else
    printf("Den edwses egkuro xaraktira.\n");
  system("PAUSE");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L8
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: %d:  %d


assistant: ```c
void test1() {
  const int COUNT = 3;
  int *users = malloc(COUNT);
  for (int i = 0; i < COUNT; i++) {
    users[i] = i * i;
    printf("%d:  %d\n", i, users[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0x0,(%rax)
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x1,0x4(%rbx)
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x4,0x8(%rbx)
  mov    $0x4,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d:  %d


assistant: ```c
void test1() {
  const int COUNT = 3;
  int *users = malloc(COUNT);
  for (int i = 0; i < COUNT; i++) {
    users[i] = i * i;
    printf("%d:  %d\n", i, users[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test1>:
  endbr64
  push   %rbp
  mov    $0x3,%edi
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  movl   $0x0,(%rax)
  mov    %rax,%rbx
  call   <printf@plt>
  movl   $0x1,0x4(%rbx)
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  movl   $0x4,0x8(%rbx)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  mov    $0x4,%edx
  mov    $0x2,%esi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: %d:  %d


assistant: ```c
void test1() {
  const int COUNT = 3;
  int *users = malloc(COUNT);
  for (int i = 0; i < COUNT; i++) {
    users[i] = i * i;
    printf("%d:  %d\n", i, users[i]);
  }
}
```