ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<extractIdentifier>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%edx
  cmp    $0x5b,%dl
  je     L26
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
L53:
  mov    %dl,(%rsi,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x5b,%dl
  jne    L53
L33:
  movslq %ecx,%rcx
  movb   $0x0,(%rsp,%rcx,1)
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L14
  mov    $0x1,%eax
  lea    D8(%rip),%rdi
  lea    -0x1(%rsp),%rsi
L48:
  mov    %dl,(%rax,%rdi,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L48
L30:
  lea    D18(%rip),%rax
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x48,%rsp
  ret
L26:
  mov    $0x0,%ecx
  jmp    L33
L14:
  mov    $0x0,%ecx
  jmp    L30
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractIdentifier(char *arrayIdentifier) {
  char extractedIdentifier[50];
  static char copied[50];
  int i = 0;
  while (arrayIdentifier[i] != '[') {
    extractedIdentifier[i] = arrayIdentifier[i];
    i++;
  }
  extractedIdentifier[i] = '\0';
  i = 0;
  while (extractedIdentifier[i] != '\0') {
    copied[i] = extractedIdentifier[i];
    i++;
  }
  copied[i] = '\0';
  return copied;
}
```
user: What is the c source code of the assembly code below?

```asm
<extractIdentifier>:
  endbr64
  sub    $0x48,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x5b,%dl
  je     L13
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  xchg   %ax,%ax
L44:
  mov    %dl,(%rcx,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x5b,%dl
  jne    L44
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L41
L42:
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  lea    D19(%rip),%rdi
  nopl   0x0(%rax)
L46:
  mov    %dl,(%rdi,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  test   %dl,%dl
  jne    L46
L38:
  lea    D10(%rip),%rax
  movb   $0x0,(%rax,%rsi,1)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x48,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %esi,%esi
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%edx
  test   %dl,%dl
  jne    L42
  xchg   %ax,%ax
L41:
  xor    %esi,%esi
  jmp    L38
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractIdentifier(char *arrayIdentifier) {
  char extractedIdentifier[50];
  static char copied[50];
  int i = 0;
  while (arrayIdentifier[i] != '[') {
    extractedIdentifier[i] = arrayIdentifier[i];
    i++;
  }
  extractedIdentifier[i] = '\0';
  i = 0;
  while (extractedIdentifier[i] != '\0') {
    copied[i] = extractedIdentifier[i];
    i++;
  }
  copied[i] = '\0';
  return copied;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extractIdentifier>:
  endbr64
  sub    $0x48,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmp    $0x5b,%dl
  je     L67
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  xchg   %ax,%ax
L12:
  mov    %dl,(%rcx,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl -0x1(%rdi,%rax,1),%edx
  cmp    $0x5b,%dl
  jne    L12
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%edx
  test   %dl,%dl
  je     L11
L32:
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
  lea    D0(%rip),%rdi
  nopl   0x0(%rax)
L30:
  mov    %dl,(%rdi,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl (%rcx,%rax,1),%edx
  test   %dl,%dl
  jne    L30
L27:
  lea    D1(%rip),%rax
  movb   $0x0,(%rax,%rsi,1)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x48,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  xor    %esi,%esi
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%edx
  test   %dl,%dl
  jne    L32
  xchg   %ax,%ax
L11:
  xor    %esi,%esi
  jmp    L27
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractIdentifier(char *arrayIdentifier) {
  char extractedIdentifier[50];
  static char copied[50];
  int i = 0;
  while (arrayIdentifier[i] != '[') {
    extractedIdentifier[i] = arrayIdentifier[i];
    i++;
  }
  extractedIdentifier[i] = '\0';
  i = 0;
  while (extractedIdentifier[i] != '\0') {
    copied[i] = extractedIdentifier[i];
    i++;
  }
  copied[i] = '\0';
  return copied;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_padded>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L12
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  addq   $0x1,-0x8(%rbp)
L29:
  subl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x0,-0xc(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_padded(char *s, int c, FILE *out) {
  while (0 < c) {
    fputc(s[0], out);
    if (0 != s[0])
      s = s + 1;
    c = c - 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_padded>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  test   %esi,%esi
  jle    L1
L11:
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  cmpb   $0x1,(%rbx)
  sbb    $0xffffffffffffffff,%rbx
  sub    $0x1,%ebp
  jne    L11
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void write_padded(char *s, int c, FILE *out) {
  while (0 < c) {
    fputc(s[0], out);
    if (0 != s[0])
      s = s + 1;
    c = c - 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_padded>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L10:
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  cmpb   $0x1,(%rbx)
  sbb    $0xffffffffffffffff,%rbx
  sub    $0x1,%ebp
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void write_padded(char *s, int c, FILE *out) {
  while (0 < c) {
    fputc(s[0], out);
    if (0 != s[0])
      s = s + 1;
    c = c - 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_padded>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L5:
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  cmpb   $0x1,(%rbx)
  sbb    $0xffffffffffffffff,%rbx
  sub    $0x1,%ebp
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void write_padded(char *s, int c, FILE *out) {
  while (0 < c) {
    fputc(s[0], out);
    if (0 != s[0])
      s = s + 1;
    c = c - 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  jmp    L15
L5:
  mov    -0x8(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int m_max(int a, int b) {
  if (a > b)
    return a;
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<m_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int m_max(int a, int b) {
  if (a > b)
    return a;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int m_max(int a, int b) {
  if (a > b)
    return a;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<m_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int m_max(int a, int b) {
  if (a > b)
    return a;
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<date_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  lea    D9(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: %F

assistant: ```c
void date_now(char *date_str) {
  time_t t = time(NULL);
  struct tm *timeinfo;
  timeinfo = localtime(&t);
  strftime(date_str, 20, "%F", timeinfo);
}
```
user: Translate the below assembly code into C programming language:

```asm
<date_now>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    D6(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: %F

assistant: ```c
void date_now(char *date_str) {
  time_t t = time(NULL);
  struct tm *timeinfo;
  timeinfo = localtime(&t);
  strftime(date_str, 20, "%F", timeinfo);
}
```
user: Translate the below assembly code into C programming language:

```asm
<date_now>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D1(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: %F

assistant: ```c
void date_now(char *date_str) {
  time_t t = time(NULL);
  struct tm *timeinfo;
  timeinfo = localtime(&t);
  strftime(date_str, 20, "%F", timeinfo);
}
```
user: What is the c source code of the assembly code below:

```asm
<date_now>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  lea    D1(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: %F

assistant: ```c
void date_now(char *date_str) {
  time_t t = time(NULL);
  struct tm *timeinfo;
  timeinfo = localtime(&t);
  strftime(date_str, 20, "%F", timeinfo);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L223
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%edx
  mov    $0x2,%ebx
  jmp    L148
L93:
  mov    %rdi,0x0(%rbp)
  mov    %ebx,%edx
  jmp    L233
L109:
  cmp    $0x5d,%al
  je     L19
  cmp    $0x2c,%al
  je     L194
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L233
  cmp    $0x20,%al
  je     L233
  mov    $0x69,%eax
  jmp    L20
L19:
  mov    %rdi,(%r12)
  mov    $0x0,%eax
  jmp    L20
L179:
  cmp    $0x5d,%al
  je     L16
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L233
  cmp    $0x20,%al
  jne    L112
L233:
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,0x8(%rsp)
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L128
L148:
  cmp    $0x1,%dl
  je     L109
  cmp    $0x2,%dl
  je     L179
  test   %dl,%dl
  jne    L233
  cmp    $0x5b,%al
  je     L93
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L233
  cmp    $0x20,%al
  je     L233
  mov    $0x69,%eax
  jmp    L20
L16:
  mov    %rdi,(%r12)
  mov    $0x0,%eax
  jmp    L20
L112:
  lea    0x1f(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  call   <getValue@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x1,%edx
  jmp    L233
L194:
  mov    %ebx,%edx
  jmp    L233
L128:
  mov    $0x69,%eax
L20:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L221
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L223:
  mov    $0x69,%eax
  jmp    L20
L221:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int getArray(char *start, char **first, char **last) {
  unsigned char state = 0;
  char *dummy;
  unsigned char dummyType;
  unsigned int result;
  while (start[0] != '\0') {
    switch (state) {
    case 0:
      if (start[0] == '[') {
        state = 2;
        *first = start;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 105;
      }
      break;
    case 1:
      if (start[0] == ']') {
        *last = start;
        return 0;
      } else if (start[0] == ',') {
        state = 2;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 105;
      }
      break;
    case 2:
      if (start[0] == ']') {
        *last = start;
        return 0;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        result = getValue(start, &dummy, &start, &dummyType);
        if (result != 0) {
          return result;
        } else {
          state = 1;
        }
      }
      break;
    }
    ++start;
  }
  return 105;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getArray>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L24
  mov    %rdi,%rcx
  cmp    $0x5b,%dl
  je     L2
  lea    0x1(%rdi),%rax
  nopl   0x0(%rax)
L147:
  cmp    $0x20,%dl
  je     L155
  cmp    $0x9,%dl
  je     L155
  cmp    $0xa,%dl
  jne    L24
L155:
  mov    %rax,0x8(%rsp)
  movzbl (%rax),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  je     L24
  add    $0x1,%rax
  cmp    $0x5b,%dl
  jne    L147
L2:
  lea    0x1(%rcx),%rdi
  mov    %rcx,(%rsi)
  mov    %rdi,0x8(%rsp)
  movzbl 0x1(%rcx),%eax
  test   %al,%al
  je     L24
  lea    0x1f(%rsp),%rbp
L133:
  cmp    $0x5d,%al
  je     L247
L254:
  cmp    $0x20,%al
  je     L54
  cmp    $0x9,%al
  je     L54
  cmp    $0xa,%al
  je     L54
  lea    0x8(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rcx
  call   <getValue@plt>
  test   %eax,%eax
  jne    L203
  mov    0x8(%rsp),%rdi
  lea    0x1(%rdi),%rcx
  mov    %rcx,0x8(%rsp)
  movzbl 0x1(%rdi),%edx
  test   %dl,%dl
  je     L24
L172:
  cmp    $0x5d,%dl
  je     L213
  cmp    $0x2c,%dl
  je     L1
  cmp    $0x20,%dl
  je     L28
  cmp    $0x9,%dl
  je     L28
  cmp    $0xa,%dl
  jne    L24
L28:
  mov    %rcx,%rdx
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  movzbl 0x1(%rdx),%edx
  test   %dl,%dl
  jne    L172
  nopl   0x0(%rax)
L24:
  mov    $0x69,%eax
L203:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L236
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L54:
  mov    0x8(%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,0x8(%rsp)
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L24
  cmp    $0x5d,%al
  jne    L254
L247:
  mov    %rdi,(%rbx)
  xor    %eax,%eax
  jmp    L203
  nopl   (%rax)
L1:
  lea    0x1(%rcx),%rdi
  mov    %rdi,0x8(%rsp)
  movzbl 0x1(%rcx),%eax
  test   %al,%al
  jne    L133
  jmp    L24
L213:
  mov    %rcx,(%rbx)
  jmp    L203
L236:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int getArray(char *start, char **first, char **last) {
  unsigned char state = 0;
  char *dummy;
  unsigned char dummyType;
  unsigned int result;
  while (start[0] != '\0') {
    switch (state) {
    case 0:
      if (start[0] == '[') {
        state = 2;
        *first = start;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 105;
      }
      break;
    case 1:
      if (start[0] == ']') {
        *last = start;
        return 0;
      } else if (start[0] == ',') {
        state = 2;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        return 105;
      }
      break;
    case 2:
      if (start[0] == ']') {
        *last = start;
        return 0;
      } else if (!(start[0] == ' ' || start[0] == '\t' || start[0] == '\n' || start[0] == '\t')) {
        result = getValue(start, &dummy, &start, &dummyType);
        if (result != 0) {
          return result;
        } else {
          state = 1;
        }
      }
      break;
    }
    ++start;
  }
  return 105;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<date_time_daysInMonth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <NullCheck@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_daysInMonth@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int date_time_daysInMonth(int year, int month, int *daysInMonth) {
  NullCheck(daysInMonth);
  *daysInMonth = _daysInMonth(month, year);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<date_time_daysInMonth>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <NullCheck@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <_daysInMonth@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int date_time_daysInMonth(int year, int month, int *daysInMonth) {
  NullCheck(daysInMonth);
  *daysInMonth = _daysInMonth(month, year);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<date_time_daysInMonth>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <NullCheck@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <_daysInMonth@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int date_time_daysInMonth(int year, int month, int *daysInMonth) {
  NullCheck(daysInMonth);
  *daysInMonth = _daysInMonth(month, year);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<date_time_daysInMonth>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <NullCheck@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <_daysInMonth@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int date_time_daysInMonth(int year, int month, int *daysInMonth) {
  NullCheck(daysInMonth);
  *daysInMonth = _daysInMonth(month, year);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itemdb_split_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L57:
  cmpq   $0x0,-0x28(%rbp)
  je     L45
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x10(%rbp,%rdx,4)
  mov    -0x28(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L40
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x0,(%rax)
  jmp    L40
L45:
  mov    -0x14(%rbp),%eax
  cltq
  movl   $0x0,-0x10(%rbp,%rax,4)
L40:
  addl   $0x1,-0x14(%rbp)
L6:
  cmpl   $0x1,-0x14(%rbp)
  jle    L57
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void itemdb_split_atoi(char *str, int *melee, int *magic) {
  int i, val[2];
  for (i = 0; i < 2; i++) {
    if (str) {
      val[i] = atoi(str);
      str = strchr(str, ':');
      if (str)
        *str++ = 0;
    } else {
      val[i] = 0;
    }
  }
  *melee = val[0];
  *magic = val[1];
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itemdb_split_atoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x8(%rsp),%r14
  jmp    L18
L31:
  movl   $0x0,(%rbx)
L49:
  add    $0x4,%rbx
  cmp    %r14,%rbx
  je     L38
L18:
  test   %rbp,%rbp
  je     L31
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L49
  lea    0x1(%rax),%rbp
  movb   $0x0,(%rax)
  jmp    L49
L38:
  mov    (%rsp),%eax
  mov    %eax,0x0(%r13)
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itemdb_split_atoi(char *str, int *melee, int *magic) {
  int i, val[2];
  for (i = 0; i < 2; i++) {
    if (str) {
      val[i] = atoi(str);
      str = strchr(str, ':');
      if (str)
        *str++ = 0;
    } else {
      val[i] = 0;
    }
  }
  *melee = val[0];
  *magic = val[1];
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itemdb_split_atoi>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L36
  mov    %rdi,%rbp
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    $0x3a,%esi
  xor    %ebp,%ebp
  mov    %eax,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
  lea    0x1(%rax),%r14
  mov    %r14,%rdi
  call   <atoi@plt>
  mov    $0x3a,%esi
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
L25:
  mov    %ebx,0x0(%r13)
  pop    %rbx
  mov    %ebp,(%r12)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L25
```

assistant: ```c
void itemdb_split_atoi(char *str, int *melee, int *magic) {
  int i, val[2];
  for (i = 0; i < 2; i++) {
    if (str) {
      val[i] = atoi(str);
      str = strchr(str, ':');
      if (str)
        *str++ = 0;
    } else {
      val[i] = 0;
    }
  }
  *melee = val[0];
  *magic = val[1];
  return;
}
```