ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<bbb_getPwmPercent>:
  endbr64
  test   %edi,%edi
  jle    L25
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %esi,%esi
  jg     L18
L13:
  mov    D12(%rip),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <bbb_getPwmPeriod@plt>
  mov    %eax,%r12d
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <bbb_getPwmDuty@plt>
  imul   $0x64,%eax,%eax
  cltd
  idiv   %r12d
  mov    %eax,D10(%rip)
  jmp    L13
L25:
  mov    D10(%rip),%eax
  ret
```

assistant: ```c
int bbb_getPwmPercent(int header, int pin) {
  static int ret = -1;
  if (header > 0 && pin > 0) {
    int period = bbb_getPwmPeriod(header, pin);
    int duty = bbb_getPwmDuty(header, pin);
    ret = ((duty * 100) / period);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bbb_getPwmPercent>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r12
  mov    D18(%rip),%eax
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jg     L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  mov    %edi,%ebp
  call   <bbb_getPwmPeriod@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <bbb_getPwmDuty@plt>
  imul   $0x64,%eax,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    %eax,D7(%rip)
  ret
  nopl   0x0(%rax)
L14:
  mov    D7(%rip),%eax
  ret
```

assistant: ```c
int bbb_getPwmPercent(int header, int pin) {
  static int ret = -1;
  if (header > 0 && pin > 0) {
    int period = bbb_getPwmPeriod(header, pin);
    int duty = bbb_getPwmDuty(header, pin);
    ret = ((duty * 100) / period);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bbb_getPwmPercent>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r12
  mov    D9(%rip),%eax
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jg     L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L1:
  mov    %edi,%ebp
  call   <bbb_getPwmPeriod@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <bbb_getPwmDuty@plt>
  imul   $0x64,%eax,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    %eax,D27(%rip)
  ret
  nopl   0x0(%rax)
L2:
  mov    D27(%rip),%eax
  ret
```

assistant: ```c
int bbb_getPwmPercent(int header, int pin) {
  static int ret = -1;
  if (header > 0 && pin > 0) {
    int period = bbb_getPwmPeriod(header, pin);
    int duty = bbb_getPwmDuty(header, pin);
    ret = ((duty * 100) / period);
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func8() {
#pragma critTer : 30 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 31 :../../ test / resources / functionNumber.c:
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func8>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func8() {
#pragma critTer : 30 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 31 :../../ test / resources / functionNumber.c:
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func8>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func8() {
#pragma critTer : 30 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 31 :../../ test / resources / functionNumber.c:
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func8>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func8() {
#pragma critTer : 30 :../../ test / resources / functionNumber.c:
  return 0;
#pragma critTer : 31 :../../ test / resources / functionNumber.c:
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_timestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  mov    $0x80,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    D8(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_infered: string

tool: D24: %Y-%m-%d %H:%M:%S

assistant: ```c
char *get_timestamp() {
  static char buffer[128];
  time_t ttime;
  struct tm *timeinfo;
  time(&ttime);
  timeinfo = localtime(&ttime);
  strftime(buffer, sizeof buffer, "%Y-%m-%d %H:%M:%S", timeinfo);
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_timestamp>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    D16(%rip),%rdx
  mov    $0x80,%esi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string

tool: D16: %Y-%m-%d %H:%M:%S

assistant: ```c
char *get_timestamp() {
  static char buffer[128];
  time_t ttime;
  struct tm *timeinfo;
  time(&ttime);
  timeinfo = localtime(&ttime);
  strftime(buffer, sizeof buffer, "%Y-%m-%d %H:%M:%S", timeinfo);
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_timestamp>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D4(%rip),%rdx
  mov    $0x80,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: %Y-%m-%d %H:%M:%S

assistant: ```c
char *get_timestamp() {
  static char buffer[128];
  time_t ttime;
  struct tm *timeinfo;
  time(&ttime);
  timeinfo = localtime(&ttime);
  strftime(buffer, sizeof buffer, "%Y-%m-%d %H:%M:%S", timeinfo);
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_timestamp>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D0(%rip),%rdx
  mov    $0x80,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %Y-%m-%d %H:%M:%S

assistant: ```c
char *get_timestamp() {
  static char buffer[128];
  time_t ttime;
  struct tm *timeinfo;
  time(&ttime);
  timeinfo = localtime(&ttime);
  strftime(buffer, sizeof buffer, "%Y-%m-%d %H:%M:%S", timeinfo);
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: calloc

assistant: ```c
void *xcalloc(size_t count, size_t sz) {
  void *p;
  if (p = calloc(count, sz), p == NULL) {
    perror("calloc");
    abort();
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xcalloc>:
  endbr64
  push   %rbx
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L6:
  mov    %rbx,%rax
  pop    %rbx
  ret
L10:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: calloc

assistant: ```c
void *xcalloc(size_t count, size_t sz) {
  void *p;
  if (p = calloc(count, sz), p == NULL) {
    perror("calloc");
    abort();
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xcalloc>:
  endbr64
  push   %r12
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L2:
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: calloc

assistant: ```c
void *xcalloc(size_t count, size_t sz) {
  void *p;
  if (p = calloc(count, sz), p == NULL) {
    perror("calloc");
    abort();
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xcalloc>:
  endbr64
  push   %r12
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L15:
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: calloc

assistant: ```c
void *xcalloc(size_t count, size_t sz) {
  void *p;
  if (p = calloc(count, sz), p == NULL) {
    perror("calloc");
    abort();
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L4:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sum_d(const double *restrict input, double *restrict output, int len) {
  output[0] = input[1];
  for (int i = 1; i < len; i++)
    output[i] = input[2 * i - 1] + input[2 * i + 1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum_d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x1,%edx
  jle    L12
  lea    -0x1(%rdx),%edx
  shl    $0x3,%rdx
  mov    $0x0,%eax
L16:
  movsd  0x8(%rdi,%rax,2),%xmm0
  addsd  0x18(%rdi,%rax,2),%xmm0
  movsd  %xmm0,0x8(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
L12:
  ret
```

assistant: ```c
void sum_d(const double *restrict input, double *restrict output, int len) {
  output[0] = input[1];
  for (int i = 1; i < len; i++)
    output[i] = input[2 * i - 1] + input[2 * i + 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum_d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x1,%edx
  jle    L4
  sub    $0x1,%edx
  xor    %eax,%eax
  shl    $0x3,%rdx
  nopl   0x0(%rax,%rax,1)
L12:
  movsd  0x8(%rdi,%rax,2),%xmm0
  addsd  0x18(%rdi,%rax,2),%xmm0
  movsd  %xmm0,0x8(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L12
L4:
  ret
```

assistant: ```c
void sum_d(const double *restrict input, double *restrict output, int len) {
  output[0] = input[1];
  for (int i = 1; i < len; i++)
    output[i] = input[2 * i - 1] + input[2 * i + 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_d>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mov    %rdi,%rcx
  mov    %edx,%r8d
  movsd  %xmm0,(%rsi)
  cmp    $0x1,%edx
  jle    L28
  lea    -0x2(%rdx),%edi
  cmp    $0x1,%edi
  jbe    L16
  mov    %edi,%edx
  movupd 0x8(%rcx),%xmm0
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  jmp    L13
  nopl   0x0(%rax)
L2:
  movapd %xmm2,%xmm0
L13:
  movupd 0x28(%rcx,%rax,2),%xmm2
  movupd 0x18(%rcx,%rax,2),%xmm1
  movhpd 0x18(%rcx,%rax,2),%xmm0
  unpcklpd %xmm2,%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,0x8(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L2
  mov    %edi,%eax
  or     $0x1,%eax
L31:
  movslq %eax,%rdi
  lea    (%rax,%rax,1),%edx
  add    $0x1,%eax
  mov    %rdi,%r9
  movslq %edx,%rdx
  lea    0x0(,%rdi,8),%r10
  shl    $0x4,%r9
  movsd  0x8(%rcx,%rdx,8),%xmm0
  movsd  -0x8(%rcx,%r9,1),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rdi,8)
  cmp    %eax,%r8d
  jle    L28
  addsd  0x18(%rcx,%rdx,8),%xmm0
  movsd  %xmm0,0x8(%rsi,%r10,1)
L28:
  ret
L16:
  mov    $0x1,%eax
  jmp    L31
```

assistant: ```c
void sum_d(const double *restrict input, double *restrict output, int len) {
  output[0] = input[1];
  for (int i = 1; i < len; i++)
    output[i] = input[2 * i - 1] + input[2 * i + 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<logger_start_signal_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <logger_start_buffer@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int logger_start_signal_cb(void *data, const char *signal, const char *type_data, void *signal_data) {
  (void)data;
  (void)signal;
  (void)type_data;
  logger_start_buffer(signal_data);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logger_start_signal_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rdi
  call   <logger_start_buffer@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int logger_start_signal_cb(void *data, const char *signal, const char *type_data, void *signal_data) {
  (void)data;
  (void)signal;
  (void)type_data;
  logger_start_buffer(signal_data);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<logger_start_signal_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rdi
  call   <logger_start_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int logger_start_signal_cb(void *data, const char *signal, const char *type_data, void *signal_data) {
  (void)data;
  (void)signal;
  (void)type_data;
  logger_start_buffer(signal_data);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<logger_start_signal_cb>:
  endbr64
  sub    $0x8,%rsp
  mov    %rcx,%rdi
  call   <logger_start_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int logger_start_signal_cb(void *data, const char *signal, const char *type_data, void *signal_data) {
  (void)data;
  (void)signal;
  (void)type_data;
  logger_start_buffer(signal_data);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  call   <fork@plt>
  mov    %eax,-0x24(%rbp)
  call   <fork@plt>
  mov    %eax,-0x20(%rbp)
  call   <fork@plt>
  mov    %eax,-0x1c(%rbp)
  call   <fork@plt>
  mov    %eax,-0x18(%rbp)
  call   <fork@plt>
  mov    %eax,-0x14(%rbp)
  call   <fork@plt>
  mov    %eax,-0x10(%rbp)
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  call   <fork@plt>
  mov    %eax,-0x8(%rbp)
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int p1, p2, p3, p4, p5, p6, p7, p8, p9, status;
  p1 = fork();
  p2 = fork();
  p3 = fork();
  p4 = fork();
  p5 = fork();
  p6 = fork();
  p7 = fork();
  p8 = fork();
  p9 = fork();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int p1, p2, p3, p4, p5, p6, p7, p8, p9, status;
  p1 = fork();
  p2 = fork();
  p3 = fork();
  p4 = fork();
  p5 = fork();
  p6 = fork();
  p7 = fork();
  p8 = fork();
  p9 = fork();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int p1, p2, p3, p4, p5, p6, p7, p8, p9, status;
  p1 = fork();
  p2 = fork();
  p3 = fork();
  p4 = fork();
  p5 = fork();
  p6 = fork();
  p7 = fork();
  p8 = fork();
  p9 = fork();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  call   <fork@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int p1, p2, p3, p4, p5, p6, p7, p8, p9, status;
  p1 = fork();
  p2 = fork();
  p3 = fork();
  p4 = fork();
  p5 = fork();
  p6 = fork();
  p7 = fork();
  p8 = fork();
  p9 = fork();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<smf_note_on>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %r8d,%ecx
  mov    %dl,-0x18(%rbp)
  mov    %al,-0x24(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <write_var_len@plt>
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  sub    $0x70,%eax
  mov    %al,-0xb(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movzbl -0x24(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0xb(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int smf_note_on(int fd, long dtime, char note, char vel, char channel) {
  unsigned char data[3];
  int num;
  num = write_var_len(fd, dtime);
  data[0] = 0x90 + channel;
  data[1] = note;
  data[2] = vel;
  num += write(fd, data, 3);
  return num;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smf_note_on>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8d,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <write_var_len@plt>
  mov    %eax,%ebp
  sub    $0x70,%ebx
  mov    %bl,0x5(%rsp)
  mov    %r14b,0x6(%rsp)
  mov    %r13b,0x7(%rsp)
  lea    0x5(%rsp),%rsi
  mov    $0x3,%edx
  mov    %r12d,%edi
  call   <write@plt>
  add    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int smf_note_on(int fd, long dtime, char note, char vel, char channel) {
  unsigned char data[3];
  int num;
  num = write_var_len(fd, dtime);
  data[0] = 0x90 + channel;
  data[1] = note;
  data[2] = vel;
  num += write(fd, data, 3);
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<smf_note_on>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x70,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <write_var_len@plt>
  lea    0x5(%rsp),%rsi
  mov    %ebp,%edi
  mov    %bl,0x5(%rsp)
  mov    $0x3,%edx
  mov    %eax,%r14d
  mov    %r13b,0x6(%rsp)
  mov    %r12b,0x7(%rsp)
  call   <write@plt>
  add    %r14d,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int smf_note_on(int fd, long dtime, char note, char vel, char channel) {
  unsigned char data[3];
  int num;
  num = write_var_len(fd, dtime);
  data[0] = 0x90 + channel;
  data[1] = note;
  data[2] = vel;
  num += write(fd, data, 3);
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<smf_note_on>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x70,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <write_var_len@plt>
  mov    %r14d,%ecx
  lea    0x4(%rsp),%rsi
  mov    %r12d,%edi
  mov    %eax,%ebp
  xor    %eax,%eax
  mov    $0x3,%edx
  mov    %r13b,0x6(%rsp)
  mov    %bl,%al
  mov    %cl,%ah
  mov    %ax,0x4(%rsp)
  call   <write@plt>
  add    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int smf_note_on(int fd, long dtime, char note, char vel, char channel) {
  unsigned char data[3];
  int num;
  num = write_var_len(fd, dtime);
  data[0] = 0x90 + channel;
  data[1] = note;
  data[2] = vel;
  num += write(fd, data, 3);
  return num;
}
```