user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x346,(%rsp)
  movl   $0x1ca,0x4(%rsp)
  movl   $0x3d1,0x8(%rsp)
  movl   $0x11e,0xc(%rsp)
  movl   $0x34a,0x10(%rsp)
  movl   $0x372,0x14(%rsp)
  movl   $0x331,0x18(%rsp)
  movl   $0x1b2,0x1c(%rsp)
  movl   $0x22d,0x20(%rsp)
  movl   $0x263,0x24(%rsp)
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L54:
  mov    (%rsp,%rbx,4),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L54
  mov    $0x0,%ebp
  lea    D66(%rip),%r14
  lea    0x60(%rsp),%r12
  lea    D3(%rip),%r13
L4:
  mov    $0x0,%ebx
L45:
  mov    (%rsp,%rbx,4),%edi
  mov    %rbp,%rsi
  call   <getVal@plt>
  mov    %eax,0x30(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L45
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x30(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0xa,%ecx
  mov    %r12,%rdx
  call   <counting_sort@plt>
  mov    $0x0,%ebx
L32:
  mov    (%r12,%rbx,4),%edx
  mov    %edx,(%rsp,%rbx,4)
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L32
  add    $0x1,%rbp
  cmp    $0x3,%rbp
  jne    L4
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
L49:
  mov    (%rsp,%rbx,4),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L49
  mov    $0x3,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D46
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D66
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string

tool: D46: The test data is:

tool: D3: %zu	,%d,


tool: D66: For the %zuth digit sorting:


tool: D1: For the final sorted data:

tool: D21: ....%d


assistant: ```c
int main(void) {
  int srcdata[10] = {838, 458, 977, 286, 842, 882, 817, 434, 557, 611};
  int testdata[10];
  int rtndata[10];
  int digit = 3;
  size_t idx, jdx;
  printf("The test data is:\n");
  for (idx = 0; idx < 10; idx++) {
    printf("%zu\t,%d,\n", idx, srcdata[idx]);
  }
  for (jdx = 0; jdx < digit; jdx++) {
    for (idx = 0; idx < 10; idx++) {
      testdata[idx] = getVal(srcdata[idx], jdx);
    }
    printf("For the %zuth digit sorting:\n", jdx);
    counting_sort(srcdata, testdata, rtndata, 10);
    for (idx = 0; idx < 10; idx++) {
      srcdata[idx] = rtndata[idx];
      printf("%zu\t,%d,\n", idx, rtndata[idx]);
    }
  }
  printf("For the final sorted data:\n");
  for (idx = 0; idx < 10; idx++) {
    printf("%zu\t,%d,\n", idx, srcdata[idx]);
  }
  printf("....%d\n", (int)pow(10, 3));
  return 0;
}
```