ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xlog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm0,%xmm4
  mulsd  D16(%rip),%xmm4
  movapd %xmm4,%xmm0
  call   <ilogbp1@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  neg    %edi
  movsd  (%rsp),%xmm0
  call   <ldexpk@plt>
  movsd  D7(%rip),%xmm1
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm3
  movsd  %xmm2,0x8(%rsp)
  mulsd  %xmm2,%xmm3
  movapd %xmm3,%xmm1
  movq   %xmm3,%rbp
  mov    $0x0,%edi
  movsd  D40(%rip),%xmm0
  call   <mla@plt>
  mov    $0x0,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  mov    $0x0,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  mov    $0x0,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  mov    $0x0,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  mov    $0x0,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  mov    $0x2,%edi
  movq   %rbp,%xmm1
  call   <mla@plt>
  movq   %xmm0,%rbp
  movsd  (%rsp),%xmm0
  call   <xisinf@plt>
  movsd  D66(%rip),%xmm0
  test   %rax,%rax
  jne    L35
  movq   %rbp,%xmm1
  mulsd  0x8(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
L35:
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm5
  comisd %xmm5,%xmm1
  ja     L26
  ucomisd %xmm1,%xmm5
  jp     L5
  movq   %xmm0,%rax
  cmove  D49(%rip),%rax
  movq   %rax,%xmm0
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  movsd  D65(%rip),%xmm0
  jmp    L5
```

tool_calls: name: parse_data
arguments: label: D16
type_guessed: f64
name: parse_data
arguments: label: D7
type_guessed: byte[8]
name: parse_data
arguments: label: D40
type_guessed: f64
name: parse_data
arguments: label: D66
type_guessed: byte[8]
name: parse_data
arguments: label: D0
type_guessed: f64
name: parse_data
arguments: label: D49
type_guessed: byte[8]
name: parse_data
arguments: label: D65
type_guessed: byte[8]

tool: D16: 0.7071

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D40: 0.1481970551779351

tool: {"D66": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D0: 0.6931471805599453

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xff]}

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0xf8,0x7f]}

assistant: ```c
double xlog(double d) {
  double x, x2, t, m;
  int e;
  e = ilogbp1(d * 0.7071);
  m = ldexpk(d, -e);
  x = (m - 1) / (m + 1);
  x2 = x * x;
  t = 0.148197055177935105296783;
  t = mla(t, x2, 0.153108178020442575739679);
  t = mla(t, x2, 0.181837339521549679055568);
  t = mla(t, x2, 0.22222194152736701733275);
  t = mla(t, x2, 0.285714288030134544449368);
  t = mla(t, x2, 0.399999999989941956712869);
  t = mla(t, x2, 0.666666666666685503450651);
  t = mla(t, x2, 2);
  x = x * t + 0.693147180559945286226764 * e;
  if (xisinf(d))
    x = __builtin_inf();
  if (d < 0)
    x = __builtin_nan("");
  if (d == 0)
    x = -__builtin_inf();
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xlog>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,(%rsp)
  mulsd  D48(%rip),%xmm0
  call   <ilogbp1@plt>
  movsd  (%rsp),%xmm2
  mov    %eax,%edi
  mov    %eax,%ebx
  movapd %xmm2,%xmm0
  neg    %edi
  movsd  %xmm2,0x8(%rsp)
  call   <ldexpk@plt>
  movsd  D16(%rip),%xmm1
  xor    %edi,%edi
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm3
  movsd  D14(%rip),%xmm0
  movapd %xmm3,%xmm1
  movsd  %xmm3,0x18(%rsp)
  mulsd  %xmm3,%xmm1
  movsd  %xmm1,(%rsp)
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  mov    $0x2,%edi
  call   <mla@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <xisinf@plt>
  movsd  D69(%rip),%xmm0
  movsd  (%rsp),%xmm2
  test   %rax,%rax
  jne    L11
  pxor   %xmm0,%xmm0
  movsd  0x18(%rsp),%xmm3
  cvtsi2sd %ebx,%xmm0
  mulsd  0x10(%rsp),%xmm3
  mulsd  D54(%rip),%xmm0
  addsd  %xmm3,%xmm0
L11:
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  ja     L10
  ucomisd %xmm1,%xmm2
  jp     L26
  movq   %xmm0,%rax
  cmove  D43(%rip),%rax
  movq   %rax,%xmm0
L26:
  add    $0x20,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L10:
  movsd  D34(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D48
type_guessed: f64
name: unpack_data
arguments: label: D16
type_guessed: byte[8]
name: unpack_data
arguments: label: D14
type_guessed: f64
name: unpack_data
arguments: label: D69
type_guessed: byte[8]
name: unpack_data
arguments: label: D54
type_guessed: f64
name: unpack_data
arguments: label: D43
type_guessed: byte[8]
name: unpack_data
arguments: label: D34
type_guessed: byte[8]

tool: D48: 0.7071

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D14: 0.1481970551779351

tool: {"D69": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D54: 0.6931471805599453

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xff]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf8,0x7f]}

assistant: ```c
double xlog(double d) {
  double x, x2, t, m;
  int e;
  e = ilogbp1(d * 0.7071);
  m = ldexpk(d, -e);
  x = (m - 1) / (m + 1);
  x2 = x * x;
  t = 0.148197055177935105296783;
  t = mla(t, x2, 0.153108178020442575739679);
  t = mla(t, x2, 0.181837339521549679055568);
  t = mla(t, x2, 0.22222194152736701733275);
  t = mla(t, x2, 0.285714288030134544449368);
  t = mla(t, x2, 0.399999999989941956712869);
  t = mla(t, x2, 0.666666666666685503450651);
  t = mla(t, x2, 2);
  x = x * t + 0.693147180559945286226764 * e;
  if (xisinf(d))
    x = __builtin_inf();
  if (d < 0)
    x = __builtin_nan("");
  if (d == 0)
    x = -__builtin_inf();
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xlog>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,(%rsp)
  mulsd  D29(%rip),%xmm0
  call   <ilogbp1@plt>
  movsd  (%rsp),%xmm2
  mov    %eax,%edi
  mov    %eax,%ebx
  movapd %xmm2,%xmm0
  neg    %edi
  movsd  %xmm2,0x8(%rsp)
  call   <ldexpk@plt>
  movsd  D3(%rip),%xmm1
  xor    %edi,%edi
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm3
  movsd  D63(%rip),%xmm0
  movapd %xmm3,%xmm1
  movsd  %xmm3,0x18(%rsp)
  mulsd  %xmm3,%xmm1
  movsd  %xmm1,(%rsp)
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  call   <mla@plt>
  movsd  (%rsp),%xmm1
  mov    $0x2,%edi
  call   <mla@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <xisinf@plt>
  movsd  D64(%rip),%xmm0
  movsd  (%rsp),%xmm2
  test   %rax,%rax
  jne    L11
  pxor   %xmm0,%xmm0
  movsd  0x18(%rsp),%xmm3
  cvtsi2sd %ebx,%xmm0
  mulsd  0x10(%rsp),%xmm3
  mulsd  D39(%rip),%xmm0
  addsd  %xmm3,%xmm0
L11:
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  ja     L5
  ucomisd %xmm1,%xmm2
  jp     L26
  movq   %xmm0,%rax
  cmove  D17(%rip),%rax
  movq   %rax,%xmm0
L26:
  add    $0x20,%rsp
  pop    %rbx
  ret
  xchg   %ax,%ax
L5:
  movsd  D0(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D29
type_guessed: f64
name: parse_data
arguments: tag: D3
type_guessed: byte[8]
name: parse_data
arguments: tag: D63
type_guessed: f64
name: parse_data
arguments: tag: D64
type_guessed: byte[8]
name: parse_data
arguments: tag: D39
type_guessed: f64
name: parse_data
arguments: tag: D17
type_guessed: byte[8]
name: parse_data
arguments: tag: D0
type_guessed: byte[8]

tool: D29: 0.7071

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D63: 0.1481970551779351

tool: {"D64": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x7f]}

tool: D39: 0.6931471805599453

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xff]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf8,0x7f]}

assistant: ```c
double xlog(double d) {
  double x, x2, t, m;
  int e;
  e = ilogbp1(d * 0.7071);
  m = ldexpk(d, -e);
  x = (m - 1) / (m + 1);
  x2 = x * x;
  t = 0.148197055177935105296783;
  t = mla(t, x2, 0.153108178020442575739679);
  t = mla(t, x2, 0.181837339521549679055568);
  t = mla(t, x2, 0.22222194152736701733275);
  t = mla(t, x2, 0.285714288030134544449368);
  t = mla(t, x2, 0.399999999989941956712869);
  t = mla(t, x2, 0.666666666666685503450651);
  t = mla(t, x2, 2);
  x = x * t + 0.693147180559945286226764 * e;
  if (xisinf(d))
    x = __builtin_inf();
  if (d < 0)
    x = __builtin_nan("");
  if (d == 0)
    x = -__builtin_inf();
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<bucket_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L79
  cmpq   $0x0,-0x28(%rbp)
  je     L79
  cmpl   $0x0,-0x1c(%rbp)
  jle    L79
  mov    $0x1,%eax
  jmp    L13
L79:
  mov    $0x0,%eax
L13:
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L16:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  nop
  nop
  leave
  ret
```

assistant: ```c
void bucket_sort(int *input, int len, int *output) {
  int index;
  int *out = output;
  assert(input != NULL && output != NULL && len > 0);
  for (index = 0; index < len; index++) {
    out[index] == 0;
  }
  for (index = 0; index < len; index++) {
    out[input[index]]++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bucket_sort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %esi,%esi
  setg   %dl
  and    %edx,%eax
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L4
  mov    $0x0,%eax
L27:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%ebp
  jne    L27
  mov    %r12,%rax
  mov    %edx,%edx
  lea    0x4(%r12,%rdx,4),%rcx
L5:
  movslq (%rax),%rdx
  addl   $0x1,(%rbx,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L5
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bucket_sort(int *input, int len, int *output) {
  int index;
  int *out = output;
  assert(input != NULL && output != NULL && len > 0);
  for (index = 0; index < len; index++) {
    out[index] == 0;
  }
  for (index = 0; index < len; index++) {
    out[input[index]]++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bucket_sort>:
  endbr64
  test   %rdi,%rdi
  push   %r12
  mov    %esi,%r12d
  setne  %al
  test   %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  setg   %dl
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  and    %edx,%eax
  test   %rbp,%rbp
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  jle    L17
  lea    -0x1(%r12),%eax
  mov    %rbx,%rdi
  lea    0x4(%rbx,%rax,4),%rdx
L13:
  movslq (%rdi),%rax
  add    $0x4,%rdi
  addl   $0x1,0x0(%rbp,%rax,4)
  cmp    %rdi,%rdx
  jne    L13
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bucket_sort(int *input, int len, int *output) {
  int index;
  int *out = output;
  assert(input != NULL && output != NULL && len > 0);
  for (index = 0; index < len; index++) {
    out[index] == 0;
  }
  for (index = 0; index < len; index++) {
    out[input[index]]++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bucket_sort>:
  endbr64
  test   %rdi,%rdi
  push   %r12
  mov    %esi,%r12d
  setne  %al
  test   %esi,%esi
  push   %rbp
  mov    %rdx,%rbp
  setg   %dl
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  and    %edx,%eax
  test   %rbp,%rbp
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %r12d,%r12d
  jle    L1
  lea    -0x1(%r12),%eax
  mov    %rbx,%rdi
  lea    0x4(%rbx,%rax,4),%rdx
L17:
  movslq (%rdi),%rax
  add    $0x4,%rdi
  addl   $0x1,0x0(%rbp,%rax,4)
  cmp    %rdi,%rdx
  jne    L17
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bucket_sort(int *input, int len, int *output) {
  int index;
  int *out = output;
  assert(input != NULL && output != NULL && len > 0);
  for (index = 0; index < len; index++) {
    out[index] == 0;
  }
  for (index = 0; index < len; index++) {
    out[input[index]]++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SlopeDiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x1ff,-0x18(%rbp)
  ja     L6
  mov    $0x800,%eax
  jmp    L13
L6:
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x18(%rbp),%edx
  mov    %edx,%ecx
  shr    $0x8,%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x800,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int SlopeDiv(unsigned num, unsigned den) {
  unsigned ans;
  if (den < 512)
    return 2048;
  ans = (num << 3) / (den >> 8);
  return ans <= 2048 ? ans : 2048;
}
```
user: What is the c source code of the assembly code below?

```asm
<SlopeDiv>:
  endbr64
  mov    $0x800,%eax
  cmp    $0x1ff,%esi
  jbe    L0
  lea    0x0(,%rdi,8),%eax
  shr    $0x8,%esi
  mov    $0x0,%edx
  div    %esi
  mov    $0x800,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
L0:
  ret
```

assistant: ```c
int SlopeDiv(unsigned num, unsigned den) {
  unsigned ans;
  if (den < 512)
    return 2048;
  ans = (num << 3) / (den >> 8);
  return ans <= 2048 ? ans : 2048;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SlopeDiv>:
  endbr64
  mov    $0x800,%eax
  cmp    $0x1ff,%esi
  jbe    L5
  shr    $0x8,%esi
  xor    %edx,%edx
  lea    0x0(,%rdi,8),%eax
  div    %esi
  mov    $0x800,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
L5:
  ret
```

assistant: ```c
int SlopeDiv(unsigned num, unsigned den) {
  unsigned ans;
  if (den < 512)
    return 2048;
  ans = (num << 3) / (den >> 8);
  return ans <= 2048 ? ans : 2048;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parity_counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L6:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  xor    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parity_counter>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    $0x0,%edx
  mov    $0x0,%eax
L20:
  mov    %edi,%ecx
  and    $0x1,%ecx
  xor    %ecx,%edx
  sar    %edi
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L20
L19:
  mov    %edx,%eax
  ret
L17:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parity_counter>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L15
  xor    %eax,%eax
  nopl   (%rax)
L12:
  mov    %edi,%edx
  add    $0x1,%eax
  sar    %edi
  and    $0x1,%edx
  xor    %edx,%r8d
  cmp    %eax,%esi
  jne    L12
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parity_counter>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  jle    L19
  xor    %eax,%eax
  nopl   (%rax)
L1:
  mov    %edi,%edx
  add    $0x1,%eax
  sar    %edi
  and    $0x1,%edx
  xor    %edx,%r8d
  cmp    %eax,%esi
  jne    L1
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parity_counter(int symbol, int length) {
  int counter;
  int temp_parity = 0;
  for (counter = 0; counter < length; counter++) {
    temp_parity = temp_parity ^ (symbol & 1);
    symbol = symbol >> 1;
  }
  return (temp_parity);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_date>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L44:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L6:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L43
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L43:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    $0x3,%edx
  sub    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x0,-0xc(%rbp)
  jne    L44
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void parse_date(char *date, int *parsed_date) {
  int count = 3;
  int i = 0;
  while (count) {
    int number = 0;
    while (date[i] != '-' && date[i] != '\0') {
      number = number * 10 + (date[i] - '0');
      i++;
    }
    parsed_date[3 - (count--)] = number;
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_date>:
  endbr64
  lea    0xc(%rsi),%r11
  mov    $0x0,%r8d
  mov    $0x0,%r10d
  jmp    L52
L46:
  mov    %r10d,%ecx
L2:
  mov    %ecx,(%rsi)
  add    $0x1,%r8d
  add    $0x4,%rsi
  cmp    %r11,%rsi
  je     L37
L52:
  movslq %r8d,%rax
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x2d,%al
  je     L46
  test   %al,%al
  setne  %r9b
  lea    0x1(%r8),%edx
  movslq %edx,%rdx
  mov    %r10d,%ecx
  test   %r9b,%r9b
  je     L46
L43:
  lea    (%rcx,%rcx,4),%ecx
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%ecx
  mov    %edx,%r8d
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    $0x2d,%al
  je     L2
  test   %al,%al
  jne    L43
  jmp    L2
L37:
  ret
```

assistant: ```c
void parse_date(char *date, int *parsed_date) {
  int count = 3;
  int i = 0;
  while (count) {
    int number = 0;
    while (date[i] != '-' && date[i] != '\0') {
      number = number * 10 + (date[i] - '0');
      i++;
    }
    parsed_date[3 - (count--)] = number;
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_date>:
  endbr64
  lea    0xc(%rsi),%r10
  xor    %r8d,%r8d
L6:
  movslq %r8d,%rax
  movsbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L21
  cmp    $0x2d,%al
  lea    0x1(%r8),%edx
  setne  %r9b
  movslq %edx,%rdx
  xor    %ecx,%ecx
  test   %r9b,%r9b
  je     L21
  nopw   0x0(%rax,%rax,1)
L26:
  lea    (%rcx,%rcx,4),%ecx
  mov    %edx,%r8d
  lea    -0x30(%rax,%rcx,2),%ecx
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    $0x2d,%al
  je     L20
  test   %al,%al
  jne    L26
L20:
  mov    %ecx,(%rsi)
  add    $0x4,%rsi
  add    $0x1,%r8d
  cmp    %rsi,%r10
  jne    L6
L33:
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %ecx,%ecx
  add    $0x4,%rsi
  add    $0x1,%r8d
  mov    %ecx,-0x4(%rsi)
  cmp    %rsi,%r10
  jne    L6
  jmp    L33
```

assistant: ```c
void parse_date(char *date, int *parsed_date) {
  int count = 3;
  int i = 0;
  while (count) {
    int number = 0;
    while (date[i] != '-' && date[i] != '\0') {
      number = number * 10 + (date[i] - '0');
      i++;
    }
    parsed_date[3 - (count--)] = number;
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_date>:
  endbr64
  lea    0xc(%rsi),%r10
  xor    %r8d,%r8d
L2:
  movslq %r8d,%rax
  movsbl (%rdi,%rax,1),%eax
  test   %al,%al
  je     L32
  cmp    $0x2d,%al
  lea    0x1(%r8),%edx
  setne  %r9b
  movslq %edx,%rdx
  xor    %ecx,%ecx
  test   %r9b,%r9b
  je     L32
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%rcx,%rcx,4),%ecx
  mov    %edx,%r8d
  lea    -0x30(%rax,%rcx,2),%ecx
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  cmp    $0x2d,%al
  je     L64
  test   %al,%al
  jne    L13
L64:
  mov    %ecx,(%rsi)
  add    $0x4,%rsi
  add    $0x1,%r8d
  cmp    %rsi,%r10
  jne    L2
L61:
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %ecx,%ecx
  add    $0x4,%rsi
  add    $0x1,%r8d
  mov    %ecx,-0x4(%rsi)
  cmp    %rsi,%r10
  jne    L2
  jmp    L61
```

assistant: ```c
void parse_date(char *date, int *parsed_date) {
  int count = 3;
  int i = 0;
  while (count) {
    int number = 0;
    while (date[i] != '-' && date[i] != '\0') {
      number = number * 10 + (date[i] - '0');
      i++;
    }
    parsed_date[3 - (count--)] = number;
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <vnormal@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <vcopy@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd -0x1c(%rbp),%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x10(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rdx
  mov    -0x28(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <vscale@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd -0x1c(%rbp),%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  pxor   %xmm0,%xmm0
  cvtsd2ss -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type: f64

tool: D17: 2

assistant: ```c
void axis_to_quat(float *a, float phi, float *q) {
  vnormal(a);
  vcopy(a, q);
  double return_value_sin$1;
  return_value_sin$1 = sin((double)phi / 2.000000);
  vscale(q, (float)return_value_sin$1);
  double return_value_cos$2;
  return_value_cos$2 = cos((double)phi / 2.000000);
  q[(signed long int)3] = (float)return_value_cos$2;
}
```