ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setUp2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D3(%rip),%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <buildFromFile@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <readData@plt>
  mov    %rbp,%rdi
  movsd  0x20(%rax),%xmm4
  movsd  0x18(%rax),%xmm3
  movsd  0x10(%rax),%xmm2
  movsd  0x8(%rax),%xmm1
  movsd  (%rax),%xmm0
  call   <kbs_insert_times@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <makeFile@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: file.txt

assistant: ```c
void setUp2(char *data) {
  struct keyBundleStore *kbs = buildFromFile("file.txt");
  double *info = readData(data);
  kbs_insert_times(kbs, info[0], info[1], info[2], info[3], info[4]);
  makeFile(kbs);
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L5:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char ch[]) {
  int i;
  for (i = 0; ch[i] != '\0'; i++)
    ;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L22
  mov    $0x1,%eax
L7:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L7
L1:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
int strlen(char ch[]) {
  int i;
  for (i = 0; ch[i] != '\0'; i++)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x1,%eax
  xchg   %ax,%ax
L3:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char ch[]) {
  int i;
  for (i = 0; ch[i] != '\0'; i++)
    ;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L6
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L11
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char ch[]) {
  int i;
  for (i = 0; ch[i] != '\0'; i++)
    ;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HEAP_INCREASE_KEY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L14
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L1
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <exchange@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  mov    %eax,-0xc(%rbp)
L1:
  cmpl   $0x0,-0xc(%rbp)
  jle    L14
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L16
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string

tool: D5: new key is small than current key

assistant: ```c
void HEAP_INCREASE_KEY(int A[], int i, int key) {
  if (key < A[i]) {
    printf("new key is small than current key\n");
    return -1;
  }
  A[i] = key;
  while (i > 0 && A[PARENT(i)] < A[i]) {
    exchange(A, i, PARENT(i));
    i = PARENT(i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HEAP_INCREASE_KEY>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  cmp    %edx,(%rax)
  jg     L12
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,(%rax)
  test   %esi,%esi
  jle    L30
L48:
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  cltq
  movslq %ebx,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jge    L30
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <exchange@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <PARENT@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L48
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L30
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: new key is small than current key

assistant: ```c
void HEAP_INCREASE_KEY(int A[], int i, int key) {
  if (key < A[i]) {
    printf("new key is small than current key\n");
    return -1;
  }
  A[i] = key;
  while (i > 0 && A[PARENT(i)] < A[i]) {
    exchange(A, i, PARENT(i));
    i = PARENT(i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HEAP_INCREASE_KEY>:
  endbr64
  push   %r12
  movslq %esi,%r12
  lea    (%rdi,%r12,4),%rax
  push   %rbp
  push   %rbx
  cmp    %edx,(%rax)
  jg     L21
  mov    %edx,(%rax)
  mov    %rdi,%rbx
  mov    %r12,%rbp
  test   %r12d,%r12d
  jg     L47
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <exchange@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L13
  movslq %eax,%r12
L47:
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    (%rbx,%r12,4),%ecx
  cltq
  cmp    %ecx,(%rbx,%rax,4)
  jl     L18
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  lea    D6(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D6: new key is small than current key

assistant: ```c
void HEAP_INCREASE_KEY(int A[], int i, int key) {
  if (key < A[i]) {
    printf("new key is small than current key\n");
    return -1;
  }
  A[i] = key;
  while (i > 0 && A[PARENT(i)] < A[i]) {
    exchange(A, i, PARENT(i));
    i = PARENT(i);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<HEAP_INCREASE_KEY>:
  endbr64
  push   %r12
  movslq %esi,%r12
  lea    (%rdi,%r12,4),%rax
  push   %rbp
  push   %rbx
  cmp    %edx,(%rax)
  jg     L7
  mov    %edx,(%rax)
  mov    %rdi,%rbx
  mov    %r12,%rbp
  test   %r12d,%r12d
  jg     L8
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <exchange@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L0
  movslq %eax,%r12
L8:
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <PARENT@plt>
  mov    (%rbx,%r12,4),%ecx
  cltq
  cmp    %ecx,(%rbx,%rax,4)
  jl     L36
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: new key is small than current key

assistant: ```c
void HEAP_INCREASE_KEY(int A[], int i, int key) {
  if (key < A[i]) {
    printf("new key is small than current key\n");
    return -1;
  }
  A[i] = key;
  while (i > 0 && A[PARENT(i)] < A[i]) {
    exchange(A, i, PARENT(i));
    i = PARENT(i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<putnchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L28:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L28
  jmp    L3
L23:
  nop
L3:
  nop
  leave
  ret
```

assistant: ```c
void putnchar(char *str, int nchar) {
  unsigned int i;
  for (i = 0; i < nchar; i++) {
    if (!str[i])
      break;
    putchar(str[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<putnchar>:
  endbr64
  test   %esi,%esi
  je     L2
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L17:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L25
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  ret
```

assistant: ```c
void putnchar(char *str, int nchar) {
  unsigned int i;
  for (i = 0; i < nchar; i++) {
    if (!str[i])
      break;
    putchar(str[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<putnchar>:
  endbr64
  test   %esi,%esi
  je     L23
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L10:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L31
L11:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L10
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  ret
```

assistant: ```c
void putnchar(char *str, int nchar) {
  unsigned int i;
  for (i = 0; i < nchar; i++) {
    if (!str[i])
      break;
    putchar(str[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<putnchar>:
  endbr64
  test   %esi,%esi
  je     L36
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L5:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L38
L26:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  ret
```

assistant: ```c
void putnchar(char *str, int nchar) {
  unsigned int i;
  for (i = 0; i < nchar; i++) {
    if (!str[i])
      break;
    putchar(str[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L57
L29:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L34
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  je     L16
L34:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  je     L16
  mov    -0x8(%rbp),%rax
  jmp    L0
L16:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x8(%rbp)
L57:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
L22:
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
char *find_line(const char *str, const char *line) {
  if (str) {
    const char *p;
    int len = strlen(line);
    for (p = str; (p = strstr(p, line)) != NULL; p += len + 1) {
      if ((p == str || is_line_sep(p[-1])) && is_line_sep(p[len]))
        return (char *)p;
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  movslq %eax,%rbp
  jmp    L69
L44:
  movsbl (%rbx,%rbp,1),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  jne    L2
L55:
  lea    0x1(%rbx,%rbp,1),%rdi
L69:
  mov    %r13,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  cmp    %rbx,%r12
  je     L44
  movsbl -0x1(%rbx),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  je     L55
  jmp    L44
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *find_line(const char *str, const char *line) {
  if (str) {
    const char *p;
    int len = strlen(line);
    for (p = str; (p = strstr(p, line)) != NULL; p += len + 1) {
      if ((p == str || is_line_sep(p[-1])) && is_line_sep(p[len]))
        return (char *)p;
    }
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  jmp    L16
  nopl   0x0(%rax)
L14:
  cmp    %r12,%rbp
  je     L25
  movsbl -0x1(%r12),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  je     L58
L25:
  movsbl (%r12,%rbx,1),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  jne    L32
L58:
  lea    0x1(%r12,%rbx,1),%rdi
L16:
  mov    %r13,%rsi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L14
L12:
  xor    %r12d,%r12d
L32:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *find_line(const char *str, const char *line) {
  if (str) {
    const char *p;
    int len = strlen(line);
    for (p = str; (p = strstr(p, line)) != NULL; p += len + 1) {
      if ((p == str || is_line_sep(p[-1])) && is_line_sep(p[len]))
        return (char *)p;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  jmp    L38
  nopl   0x0(%rax)
L50:
  cmp    %r12,%rbp
  je     L31
  movsbl -0x1(%r12),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  je     L21
L31:
  movsbl (%r12,%rbx,1),%edi
  call   <is_line_sep@plt>
  test   %rax,%rax
  jne    L47
L21:
  lea    0x1(%r12,%rbx,1),%rdi
L38:
  mov    %r13,%rsi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L50
L1:
  xor    %r12d,%r12d
L47:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *find_line(const char *str, const char *line) {
  if (str) {
    const char *p;
    int len = strlen(line);
    for (p = str; (p = strstr(p, line)) != NULL; p += len + 1) {
      if ((p == str || is_line_sep(p[-1])) && is_line_sep(p[len]))
        return (char *)p;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop3_prepare_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pop3_strip_newlines@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L44
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L32
L44:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  jmp    L25
L21:
  subl   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L30
  cmpl   $0x0,-0x10(%rbp)
  jg     L21
L30:
  mov    -0x8(%rbp),%rax
L32:
  leave
  ret
```

assistant: ```c
char *pop3_prepare_arg(char *msg, ssize_t msglen, char *command) {
  int l, c;
  char *pos;
  l = pop3_strip_newlines(msg, msglen);
  c = strlen(command);
  if (c >= l) {
    return &(msg[l]);
  }
  pos = msg + c;
  l -= c;
  while (' ' == *pos && l > 0) {
    l--;
    pos++;
  }
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pop3_prepare_arg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%r12
  call   <pop3_strip_newlines@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jle    L20
  movslq %eax,%rdx
  lea    (%rbx,%rdx,1),%rcx
  mov    %ebp,%esi
  sub    %eax,%esi
  cmpb   $0x20,(%rcx)
  jne    L9
  mov    %rcx,%rax
L0:
  add    $0x1,%rax
  mov    %esi,%edx
  sub    %eax,%edx
  add    %ecx,%edx
  cmpb   $0x20,(%rax)
  jne    L51
  test   %edx,%edx
  jg     L0
  jmp    L51
L20:
  movslq %ebp,%rax
  add    %rbx,%rax
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    %rcx,%rax
  jmp    L51
```

assistant: ```c
char *pop3_prepare_arg(char *msg, ssize_t msglen, char *command) {
  int l, c;
  char *pos;
  l = pop3_strip_newlines(msg, msglen);
  c = strlen(command);
  if (c >= l) {
    return &(msg[l]);
  }
  pos = msg + c;
  l -= c;
  while (' ' == *pos && l > 0) {
    l--;
    pos++;
  }
  return pos;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pop3_prepare_arg>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <pop3_strip_newlines@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jle    L18
  movslq %eax,%rdx
  mov    %ebp,%ecx
  lea    (%rbx,%rdx,1),%rdi
  sub    %eax,%ecx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rax
  je     L35
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L46:
  cmpb   $0x20,(%rax)
  jne    L27
L35:
  add    $0x1,%rax
  mov    %ecx,%edx
  sub    %eax,%edx
  add    %edi,%edx
  jne    L46
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  movslq %ebp,%rcx
  lea    (%rbx,%rcx,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pop3_prepare_arg(char *msg, ssize_t msglen, char *command) {
  int l, c;
  char *pos;
  l = pop3_strip_newlines(msg, msglen);
  c = strlen(command);
  if (c >= l) {
    return &(msg[l]);
  }
  pos = msg + c;
  l -= c;
  while (' ' == *pos && l > 0) {
    l--;
    pos++;
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop3_prepare_arg>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <pop3_strip_newlines@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  cmp    %eax,%ebp
  jle    L21
  movslq %eax,%rdx
  mov    %ebp,%ecx
  lea    (%rbx,%rdx,1),%rdi
  sub    %eax,%ecx
  cmpb   $0x20,(%rdi)
  mov    %rdi,%rax
  je     L44
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L8:
  cmpb   $0x20,(%rax)
  jne    L49
L44:
  add    $0x1,%rax
  mov    %ecx,%edx
  sub    %eax,%edx
  add    %edi,%edx
  jne    L8
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  movslq %ebp,%rcx
  lea    (%rbx,%rcx,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pop3_prepare_arg(char *msg, ssize_t msglen, char *command) {
  int l, c;
  char *pos;
  l = pop3_strip_newlines(msg, msglen);
  c = strlen(command);
  if (c >= l) {
    return &(msg[l]);
  }
  pos = msg + c;
  l -= c;
  while (' ' == *pos && l > 0) {
    l--;
    pos++;
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inMandelbrot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L43
L28:
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  subl   $0x1,-0x34(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  comisd D6(%rip),%xmm0
  ja     L27
  jmp    L43
L27:
  mov    $0x0,%eax
  jmp    L31
L43:
  cmpl   $0x0,-0x34(%rbp)
  jg     L28
  mov    $0x1,%eax
L31:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: f32

tool: D6: 0

assistant: ```c
int inMandelbrot(double x0, double y0, int n) {
  double x = 0.0;
  double y = 0.0;
  double xtemp;
  while (n > 0) {
    xtemp = x * x - y * y + x0;
    y = 2 * x * y + y0;
    x = xtemp;
    n -= 1;
    if (x * x + y * y > 4) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inMandelbrot>:
  endbr64
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm4
  movsd  D0(%rip),%xmm6
L4:
  test   %edi,%edi
  jle    L18
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  movapd %xmm2,%xmm5
  mulsd  %xmm2,%xmm5
  subsd  %xmm5,%xmm3
  addsd  %xmm0,%xmm3
  addsd  %xmm4,%xmm4
  mulsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm2
  sub    $0x1,%edi
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  movapd %xmm2,%xmm5
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm4
  comisd %xmm6,%xmm4
  ja     L14
  movapd %xmm3,%xmm4
  jmp    L4
L18:
  mov    $0x1,%eax
  ret
L14:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: f32[2]

tool: {"D0": [0.0,2.25]}

assistant: ```c
int inMandelbrot(double x0, double y0, int n) {
  double x = 0.0;
  double y = 0.0;
  double xtemp;
  while (n > 0) {
    xtemp = x * x - y * y + x0;
    y = 2 * x * y + y0;
    x = xtemp;
    n -= 1;
    if (x * x + y * y > 4) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inMandelbrot>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D3(%rip),%xmm6
  movapd %xmm2,%xmm4
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L29:
  movapd %xmm4,%xmm3
  movapd %xmm2,%xmm5
  sub    $0x1,%edi
  mulsd  %xmm2,%xmm5
  mulsd  %xmm4,%xmm3
  addsd  %xmm4,%xmm4
  mulsd  %xmm4,%xmm2
  subsd  %xmm5,%xmm3
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm3
  movapd %xmm2,%xmm5
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm4
  comisd %xmm6,%xmm4
  ja     L15
  movapd %xmm3,%xmm4
L23:
  test   %edi,%edi
  jg     L29
  mov    $0x1,%eax
  ret
  nop
L15:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: f32[2]

tool: {"D3": [0.0,2.25]}

assistant: ```c
int inMandelbrot(double x0, double y0, int n) {
  double x = 0.0;
  double y = 0.0;
  double xtemp;
  while (n > 0) {
    xtemp = x * x - y * y + x0;
    y = 2 * x * y + y0;
    x = xtemp;
    n -= 1;
    if (x * x + y * y > 4) {
      return 0;
    }
  }
  return 1;
}
```