ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<build_max_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <max_heapify@plt>
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jg     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void build_max_heap(int array[], int array_size) {
  int i;
  for (i = array_size / 2; i >= 1; i--) {
    max_heapify(array, array_size, i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L12
L19:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L19
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int array[], int array_size) {
  int i;
  for (i = array_size / 2; i >= 1; i--) {
    max_heapify(array, array_size, i);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L13
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%ebx
  jne    L15
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int array[], int array_size) {
  int i;
  for (i = array_size / 2; i >= 1; i--) {
    max_heapify(array, array_size, i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<build_max_heap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L11
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%ebx
  jne    L16
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_max_heap(int array[], int array_size) {
  int i;
  for (i = array_size / 2; i >= 1; i--) {
    max_heapify(array, array_size, i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L14:
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x2,-0xc(%rbp)
  jle    L14
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string

tool: D14: log10

tool: D27: # c::%s


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "log10");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D15(%rip),%r13
  lea    D10(%rip),%r12
  lea    D20(%rip),%rbp
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L3
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D20
data_type: string

tool: D15: log10

tool: D10: # c::%s


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "log10");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D27(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D6
datatype: string

tool: D27: log10

tool: D24: # c::%s


tool: D6: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "log10");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D1(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D1: log10

tool: D28: # c::%s


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "log10");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pow_modn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L1
L21:
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L5
  mov    -0x14(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  mov    %rdx,-0x8(%rbp)
L5:
  sarl   -0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x14(%rbp)
L1:
  cmpl   $0x0,-0x18(%rbp)
  jg     L21
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int pow_modn(int base, int exponent, int n) {
  long long result = 1;
  while (exponent > 0) {
    if (exponent % 2 == 1)
      result = (result * base) % n;
    exponent = exponent >> 1;
    base = (base * base) % n;
  }
  return (int)result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pow_modn>:
  endbr64
  mov    %edx,%r9d
  test   %esi,%esi
  jle    L42
  mov    $0x1,%r11d
  movslq %edx,%r10
  jmp    L46
L9:
  sar    %esi
  mov    %edi,%eax
  imul   %edi,%eax
  cltd
  idiv   %r9d
  mov    %edx,%edi
  test   %esi,%esi
  jle    L25
L46:
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  lea    (%rsi,%r8,1),%ecx
  and    $0x1,%ecx
  sub    %r8d,%ecx
  cmp    $0x1,%ecx
  jne    L9
  movslq %edi,%rax
  imul   %r11,%rax
  cqto
  idiv   %r10
  mov    %rdx,%r11
  jmp    L9
L42:
  mov    $0x1,%r11d
L25:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int pow_modn(int base, int exponent, int n) {
  long long result = 1;
  while (exponent > 0) {
    if (exponent % 2 == 1)
      result = (result * base) % n;
    exponent = exponent >> 1;
    base = (base * base) % n;
  }
  return (int)result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pow_modn>:
  endbr64
  mov    %edx,%ecx
  test   %esi,%esi
  jle    L0
  mov    $0x1,%r8d
  movslq %edx,%r9
  nopl   0x0(%rax,%rax,1)
L18:
  test   $0x1,%sil
  je     L5
  movslq %edi,%rax
  imul   %r8,%rax
  cqto
  idiv   %r9
  mov    %rdx,%r8
L5:
  imul   %edi,%edi
  mov    %edi,%eax
  cltd
  idiv   %ecx
  sar    %esi
  mov    %edx,%edi
  jne    L18
  mov    %r8d,%eax
  ret
  nop
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int pow_modn(int base, int exponent, int n) {
  long long result = 1;
  while (exponent > 0) {
    if (exponent % 2 == 1)
      result = (result * base) % n;
    exponent = exponent >> 1;
    base = (base * base) % n;
  }
  return (int)result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pow_modn>:
  endbr64
  mov    %edx,%ecx
  test   %esi,%esi
  jle    L10
  mov    $0x1,%r8d
  movslq %edx,%r9
  nopl   0x0(%rax,%rax,1)
L25:
  test   $0x1,%sil
  je     L3
  movslq %edi,%rax
  imul   %r8,%rax
  cqto
  idiv   %r9
  mov    %rdx,%r8
L3:
  imul   %edi,%edi
  mov    %edi,%eax
  cltd
  idiv   %ecx
  sar    %esi
  mov    %edx,%edi
  jne    L25
  mov    %r8d,%eax
  ret
  nop
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int pow_modn(int base, int exponent, int n) {
  long long result = 1;
  while (exponent > 0) {
    if (exponent % 2 == 1)
      result = (result * base) % n;
    exponent = exponent >> 1;
    base = (base * base) % n;
  }
  return (int)result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setSocketNoDelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int setSocketNoDelay(int socket) {
  int optval = 1;
  return setsockopt(socket, IPPROTO_TCP, TCP_NODELAY, &optval, sizeof(optval));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setSocketNoDelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    $0x4,%r8d
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setSocketNoDelay(int socket) {
  int optval = 1;
  return setsockopt(socket, IPPROTO_TCP, TCP_NODELAY, &optval, sizeof(optval));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setSocketNoDelay>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setSocketNoDelay(int socket) {
  int optval = 1;
  return setsockopt(socket, IPPROTO_TCP, TCP_NODELAY, &optval, sizeof(optval));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<setSocketNoDelay>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setSocketNoDelay(int socket) {
  int optval = 1;
  return setsockopt(socket, IPPROTO_TCP, TCP_NODELAY, &optval, sizeof(optval));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  5 >= 6.0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(void) {
  5 >= 6.0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(void) {
  5 >= 6.0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main(void) {
  5 >= 6.0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6,-0xc(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <myprintf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <passByCopy@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <passByPointer@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D19: hello world

tool: D28: hello world again


tool: D23: n=%d


assistant: ```c
int main() {
  int n = 6;
  printf("hello world\n");
  myprintf("hello world again\n");
  passByCopy(n);
  passByPointer(&n);
  printf("n=%d\n", n);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6,0x4(%rsp)
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <myprintf@plt>
  mov    0x4(%rsp),%edi
  call   <passByCopy@plt>
  lea    0x4(%rsp),%rdi
  call   <passByPointer@plt>
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D19
data_type: string

tool: D25: hello world

tool: D11: hello world again


tool: D19: n=%d


assistant: ```c
int main() {
  int n = 6;
  printf("hello world\n");
  myprintf("hello world again\n");
  passByCopy(n);
  passByPointer(&n);
  printf("n=%d\n", n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6,0x4(%rsp)
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <myprintf@plt>
  mov    0x4(%rsp),%edi
  call   <passByCopy@plt>
  lea    0x4(%rsp),%rdi
  call   <passByPointer@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D29: hello world

tool: D11: hello world again


tool: D17: n=%d


assistant: ```c
int main() {
  int n = 6;
  printf("hello world\n");
  myprintf("hello world again\n");
  passByCopy(n);
  passByPointer(&n);
  printf("n=%d\n", n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6,0x4(%rsp)
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <myprintf@plt>
  mov    0x4(%rsp),%edi
  call   <passByCopy@plt>
  lea    0x4(%rsp),%rdi
  call   <passByPointer@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D3
type: string

tool: D7: hello world

tool: D15: hello world again


tool: D3: n=%d


assistant: ```c
int main() {
  int n = 6;
  printf("hello world\n");
  myprintf("hello world again\n");
  passByCopy(n);
  passByPointer(&n);
  printf("n=%d\n", n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BrzCase_ackup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%edi
  call   <SEND_ACKUP@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzCase_ackup(struct comp *comp, int port) {
  struct BrzCase_ *c = (struct BrzCase_ *)comp;
  SEND_ACKUP(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BrzCase_ackup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <SEND_ACKUP@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzCase_ackup(struct comp *comp, int port) {
  struct BrzCase_ *c = (struct BrzCase_ *)comp;
  SEND_ACKUP(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BrzCase_ackup>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <SEND_ACKUP@plt>
```

assistant: ```c
void BrzCase_ackup(struct comp *comp, int port) {
  struct BrzCase_ *c = (struct BrzCase_ *)comp;
  SEND_ACKUP(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BrzCase_ackup>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <SEND_ACKUP@plt>
```

assistant: ```c
void BrzCase_ackup(struct comp *comp, int port) {
  struct BrzCase_ *c = (struct BrzCase_ *)comp;
  SEND_ACKUP(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtok_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <_DIAGASSERT@plt>
  cmpq   $0x0,-0x38(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <_DIAGASSERT@plt>
  cmpq   $0x0,-0x28(%rbp)
  jne    L4
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L142
L4:
  nop
L78:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L37
L18:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L37
  jmp    L78
L37:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  cmpl   $0x0,-0x18(%rbp)
  jne    L145
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L142
L145:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L98:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L144
  cmpl   $0x0,-0x18(%rbp)
  jne    L132
  movq   $0x0,-0x28(%rbp)
  jmp    L60
L132:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,(%rax)
L60:
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L142
L144:
  cmpl   $0x0,-0x14(%rbp)
  jne    L13
  jmp    L98
L142:
  leave
  ret
```

assistant: ```c
char *strtok_r(char *s, const char *delim, char **lasts) {
  const char *spanp;
  int c, sc;
  char *tok;
  _DIAGASSERT(delim != NULL);
  _DIAGASSERT(lasts != NULL);
  if (s == NULL && (s = *lasts) == NULL)
    return (NULL);
cont:
  c = *s++;
  for (spanp = delim; (sc = *spanp++) != 0;) {
    if (c == sc)
      goto cont;
  }
  if (c == 0) {
    *lasts = NULL;
    return (NULL);
  }
  tok = s - 1;
  for (;;) {
    c = *s++;
    spanp = delim;
    do {
      if ((sc = *spanp++) == c) {
        if (c == 0)
          s = NULL;
        else
          s[-1] = 0;
        *lasts = s;
        return (tok);
      }
    } while (sc != 0);
  }
}
```