ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<power>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L8
  lea    0x1(%rsi),%edx
  mov    $0x1,%eax
  mov    $0x1,%esi
L7:
  imul   %edi,%esi
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L7
L15:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    $0x1,%esi
  jmp    L15
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: Ans: %d

assistant: ```c
void power(int base, int exp) {
  int x = 1;
  for (int i = 1; i <= exp; i++)
    x = x * base;
  printf("Ans: %d", x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    0x1(%rsi),%edx
  mov    $0x1,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L3:
  add    $0x1,%eax
  imul   %edi,%esi
  cmp    %edx,%eax
  jne    L3
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
L1:
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: Ans: %d

assistant: ```c
void power(int base, int exp) {
  int x = 1;
  for (int i = 1; i <= exp; i++)
    x = x * base;
  printf("Ans: %d", x);
}
```
user: What is the c source code of the assembly code below?

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    0x1(%rsi),%edx
  mov    $0x1,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L10:
  add    $0x1,%eax
  imul   %edi,%esi
  cmp    %edx,%eax
  jne    L10
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
  xchg   %ax,%ax
L17:
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: Ans: %d

assistant: ```c
void power(int base, int exp) {
  int x = 1;
  for (int i = 1; i <= exp; i++)
    x = x * base;
  printf("Ans: %d", x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prbs15_gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %esi,%eax
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    %edi,%edx
  mov    %dx,-0x24(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpw   $0x0,-0x24(%rbp)
  jne    L64
  movw   $0xc001,-0x24(%rbp)
L64:
  movzwl -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <reverse_bit16@plt>
  mov    %ax,-0x16(%rbp)
  shrw   -0x16(%rbp)
  jmp    L2
L72:
  cmpl   $0x6,-0x34(%rbp)
  jle    L0
  movzwl -0x16(%rbp),%eax
  mov    -0x38(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <prbs15_next_7_bytes@plt>
  mov    %ax,-0x16(%rbp)
  addq   $0x7,-0x30(%rbp)
  subl   $0x7,-0x34(%rbp)
  jmp    L2
L0:
  movzwl -0x16(%rbp),%eax
  mov    -0x38(%rbp),%edx
  lea    -0xf(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <prbs15_next_7_bytes@plt>
  mov    %ax,-0x16(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L51
L77:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xf(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L77
  movl   $0x0,-0x34(%rbp)
L2:
  cmpl   $0x0,-0x34(%rbp)
  jg     L72
  movzwl -0x16(%rbp),%eax
  mov    %eax,%edi
  call   <reverse_bit16@plt>
  mov    %ax,-0x28(%rbp)
  shrw   -0x28(%rbp)
  movzwl -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
unsigned short prbs15_gen(unsigned short polynomial, unsigned short seed, unsigned char *buf, int length, int reverse_output) {
  unsigned short seed_rev;
  if ((0) == polynomial) {
    polynomial = 0xC001;
  };
  seed_rev = reverse_bit16(seed);
  seed_rev >>= 1;
  while (length > 0) {
    if (length >= (7)) {
      seed_rev = prbs15_next_7_bytes(seed_rev, buf, reverse_output);
      buf += (7);
      length -= (7);
    } else {
      int i;
      unsigned char cur_prbs_buf[(7)];
      seed_rev = prbs15_next_7_bytes(seed_rev, cur_prbs_buf, reverse_output);
      for (i = 0; i < length; i++) {
        buf[i] = cur_prbs_buf[i];
      }
      length = 0;
    }
  }
  seed = reverse_bit16(seed_rev);
  seed >>= 1;
  return seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prbs15_gen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  mov    %r8d,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl %si,%edi
  call   <reverse_bit16@plt>
  shr    %ax
  test   %ebx,%ebx
  jg     L66
  jmp    L10
L25:
  movzwl %ax,%edi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <prbs15_next_7_bytes@plt>
  add    $0x7,%rbp
  sub    $0x7,%ebx
  test   %ebx,%ebx
  jle    L10
L66:
  cmp    $0x6,%ebx
  jg     L25
  movzwl %ax,%edi
  lea    0x1(%rsp),%rsi
  mov    %r12d,%edx
  call   <prbs15_next_7_bytes@plt>
  test   %ebx,%ebx
  jle    L10
  mov    $0x0,%edx
L32:
  movzbl 0x1(%rsp,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L32
L10:
  movzwl %ax,%edi
  call   <reverse_bit16@plt>
  shr    %ax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short prbs15_gen(unsigned short polynomial, unsigned short seed, unsigned char *buf, int length, int reverse_output) {
  unsigned short seed_rev;
  if ((0) == polynomial) {
    polynomial = 0xC001;
  };
  seed_rev = reverse_bit16(seed);
  seed_rev >>= 1;
  while (length > 0) {
    if (length >= (7)) {
      seed_rev = prbs15_next_7_bytes(seed_rev, buf, reverse_output);
      buf += (7);
      length -= (7);
    } else {
      int i;
      unsigned char cur_prbs_buf[(7)];
      seed_rev = prbs15_next_7_bytes(seed_rev, cur_prbs_buf, reverse_output);
      for (i = 0; i < length; i++) {
        buf[i] = cur_prbs_buf[i];
      }
      length = 0;
    }
  }
  seed = reverse_bit16(seed_rev);
  seed >>= 1;
  return seed;
}
```
user: What is the c source code of the assembly code below:

```asm
<prbs15_gen>:
  endbr64
  push   %r13
  movzwl %si,%edi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <reverse_bit16@plt>
  shr    %ax
  test   %ebx,%ebx
  jle    L34
  nopl   (%rax)
L7:
  movzwl %ax,%edi
  cmp    $0x6,%ebx
  jle    L0
  mov    %rbp,%rsi
  mov    %r12d,%edx
  add    $0x7,%rbp
  call   <prbs15_next_7_bytes@plt>
  sub    $0x7,%ebx
  jne    L7
L34:
  movzwl %ax,%edi
  call   <reverse_bit16@plt>
  shr    %ax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    0x1(%rsp),%r13
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <prbs15_next_7_bytes@plt>
  movslq %ebx,%rdx
  test   %ebx,%ebx
  mov    $0x1,%ecx
  cmovle %rcx,%rdx
  mov    %edx,%edi
  test   %edx,%edx
  je     L34
  xor    %edx,%edx
L3:
  mov    %edx,%ecx
  add    $0x1,%edx
  movzbl 0x0(%r13,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  cmp    %edi,%edx
  jb     L3
  jmp    L34
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short prbs15_gen(unsigned short polynomial, unsigned short seed, unsigned char *buf, int length, int reverse_output) {
  unsigned short seed_rev;
  if ((0) == polynomial) {
    polynomial = 0xC001;
  };
  seed_rev = reverse_bit16(seed);
  seed_rev >>= 1;
  while (length > 0) {
    if (length >= (7)) {
      seed_rev = prbs15_next_7_bytes(seed_rev, buf, reverse_output);
      buf += (7);
      length -= (7);
    } else {
      int i;
      unsigned char cur_prbs_buf[(7)];
      seed_rev = prbs15_next_7_bytes(seed_rev, cur_prbs_buf, reverse_output);
      for (i = 0; i < length; i++) {
        buf[i] = cur_prbs_buf[i];
      }
      length = 0;
    }
  }
  seed = reverse_bit16(seed_rev);
  seed >>= 1;
  return seed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prbs15_gen>:
  endbr64
  push   %r13
  movzwl %si,%edi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <reverse_bit16@plt>
  shr    %ax
  test   %ebx,%ebx
  jle    L53
  nopl   (%rax)
L50:
  movzwl %ax,%edi
  cmp    $0x6,%ebx
  jle    L39
  mov    %rbp,%rsi
  mov    %r12d,%edx
  add    $0x7,%rbp
  call   <prbs15_next_7_bytes@plt>
  sub    $0x7,%ebx
  jne    L50
L53:
  movzwl %ax,%edi
  call   <reverse_bit16@plt>
  shr    %ax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  lea    0x1(%rsp),%r13
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <prbs15_next_7_bytes@plt>
  movslq %ebx,%rdx
  test   %ebx,%ebx
  mov    $0x1,%ecx
  cmovle %rcx,%rdx
  mov    %edx,%edi
  test   %edx,%edx
  je     L53
  xor    %edx,%edx
L46:
  mov    %edx,%ecx
  add    $0x1,%edx
  movzbl 0x0(%r13,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  cmp    %edi,%edx
  jb     L46
  jmp    L53
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short prbs15_gen(unsigned short polynomial, unsigned short seed, unsigned char *buf, int length, int reverse_output) {
  unsigned short seed_rev;
  if ((0) == polynomial) {
    polynomial = 0xC001;
  };
  seed_rev = reverse_bit16(seed);
  seed_rev >>= 1;
  while (length > 0) {
    if (length >= (7)) {
      seed_rev = prbs15_next_7_bytes(seed_rev, buf, reverse_output);
      buf += (7);
      length -= (7);
    } else {
      int i;
      unsigned char cur_prbs_buf[(7)];
      seed_rev = prbs15_next_7_bytes(seed_rev, cur_prbs_buf, reverse_output);
      for (i = 0; i < length; i++) {
        buf[i] = cur_prbs_buf[i];
      }
      length = 0;
    }
  }
  seed = reverse_bit16(seed_rev);
  seed >>= 1;
  return seed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<div_s64_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x20,%rax
  test   %rax,%rax
  jne    L23
  mov    -0x18(%rbp),%rax
  mov    -0x1c(%rbp),%ecx
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,-0x8(%rbp)
  jmp    L3
L23:
  nop
L1:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  ja     L1
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int div_s64_32(unsigned long long dividend, int divisor) {
  int result = 0;
  int i = 0;
  if (dividend >> 32 == 0)
    result = (unsigned int)dividend / divisor;
  else {
    while ((divisor * (i++) + divisor - 1) < dividend)
      ;
    result = i - 1;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<div_s64_32>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  jne    L16
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  ret
L16:
  movslq %esi,%rsi
  mov    %rsi,%r8
  mov    $0x0,%ecx
L7:
  mov    %ecx,%eax
  add    $0x1,%ecx
  mov    %r8,%rdx
  add    %rsi,%r8
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  ja     L7
  ret
```

assistant: ```c
int div_s64_32(unsigned long long dividend, int divisor) {
  int result = 0;
  int i = 0;
  if (dividend >> 32 == 0)
    result = (unsigned int)dividend / divisor;
  else {
    while ((divisor * (i++) + divisor - 1) < dividend)
      ;
    result = i - 1;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<div_s64_32>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  jne    L3
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  ret
  nopl   0x0(%rax)
L3:
  movslq %esi,%rsi
  xor    %ecx,%ecx
  mov    %rsi,%r8
L1:
  mov    %r8,%rdx
  mov    %ecx,%eax
  add    %rsi,%r8
  add    $0x1,%ecx
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  ja     L1
  ret
```

assistant: ```c
int div_s64_32(unsigned long long dividend, int divisor) {
  int result = 0;
  int i = 0;
  if (dividend >> 32 == 0)
    result = (unsigned int)dividend / divisor;
  else {
    while ((divisor * (i++) + divisor - 1) < dividend)
      ;
    result = i - 1;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<div_s64_32>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  jne    L18
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  ret
  nopl   0x0(%rax)
L18:
  movslq %esi,%rsi
  xor    %ecx,%ecx
  mov    %rsi,%r8
L3:
  mov    %r8,%rdx
  mov    %ecx,%eax
  add    %rsi,%r8
  add    $0x1,%ecx
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  ja     L3
  ret
```

assistant: ```c
int div_s64_32(unsigned long long dividend, int divisor) {
  int result = 0;
  int i = 0;
  if (dividend >> 32 == 0)
    result = (unsigned int)dividend / divisor;
  else {
    while ((divisor * (i++) + divisor - 1) < dividend)
      ;
    result = i - 1;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mycopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mycopy(char *target, char *source, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    target[i] = source[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mycopy>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
L1:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L1
L14:
  ret
```

assistant: ```c
void mycopy(char *target, char *source, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    target[i] = source[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mycopy>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L10:
  ret
```

assistant: ```c
void mycopy(char *target, char *source, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    target[i] = source[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mycopy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L11
  lea    0x1(%rsi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%eax
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L44
  cmp    $0x6,%eax
  jbe    L44
  cmp    $0xe,%eax
  jbe    L153
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L86:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L86
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L11
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L60
L8:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L11
L60:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L11
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L11
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L11
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L11
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L11
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L11
  cltq
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L11:
  ret
L153:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
void mycopy(char *target, char *source, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    target[i] = source[i];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<simp2>:
  endbr64
  mov    %edx,%r9d
  mov    %rcx,%r10
  movl   $0x0,(%rcx)
  test   %esi,%esi
  jle    L136
  movslq %r8d,%rax
  lea    0x4(,%rax,4),%r11
  mov    $0x1,%eax
  movsd  D30(%rip),%xmm3
L171:
  mov    %eax,%edx
  mov    0x8(%rdi,%rax,8),%rcx
  pxor   %xmm2,%xmm2
  cvtss2sd (%rcx,%r11,1),%xmm2
  comisd %xmm2,%xmm3
  ja     L179
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L171
  ret
L136:
  mov    $0x1,%edx
L179:
  cmp    %edx,%esi
  jl     L174
  movslq %edx,%rax
  mov    0x8(%rdi,%rax,8),%rax
  movslq %r8d,%r8
  add    $0x1,%r8
  lea    0x0(,%r8,4),%r11
  movss  0x4(%rax),%xmm4
  xorps  D23(%rip),%xmm4
  divss  (%rax,%r8,4),%xmm4
  mov    %edx,(%r10)
  lea    0x1(%rdx),%eax
  cmp    %eax,%esi
  jl     L174
  push   %rbx
  cltq
  movsd  D30(%rip),%xmm6
  movss  D23(%rip),%xmm7
  movaps %xmm7,%xmm5
  jmp    L120
L150:
  ucomiss %xmm4,%xmm2
  jp     L91
  je     L119
L91:
  add    $0x1,%rax
  cmp    %eax,%esi
  jl     L15
L120:
  mov    %eax,%r8d
  mov    0x8(%rdi,%rax,8),%rdx
  movss  (%rdx,%r11,1),%xmm3
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm3,%xmm2
  comisd %xmm2,%xmm6
  jbe    L91
  movss  0x4(%rdx),%xmm2
  xorps  %xmm7,%xmm2
  divss  %xmm3,%xmm2
  comiss %xmm2,%xmm4
  jbe    L150
  mov    %eax,(%r10)
  movaps %xmm2,%xmm4
  jmp    L91
L119:
  test   %r9d,%r9d
  jle    L178
  movslq (%r10),%rcx
  mov    0x8(%rdi,%rcx,8),%rbx
  movss  (%rbx,%r11,1),%xmm2
  mov    $0x1,%ecx
L133:
  movss  0x4(%rbx,%rcx,4),%xmm0
  xorps  %xmm5,%xmm0
  divss  %xmm2,%xmm0
  movss  0x4(%rdx,%rcx,4),%xmm1
  xorps  %xmm5,%xmm1
  divss  %xmm3,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L178
  jne    L178
  add    $0x1,%rcx
  cmp    %ecx,%r9d
  jge    L133
L178:
  comiss %xmm1,%xmm0
  jbe    L91
  mov    %r8d,(%r10)
  jmp    L91
L15:
  pop    %rbx
  ret
L174:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D30
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D23
type_guessed: byte[16]

tool: {"D30": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: {"D23": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void simp2(float **a, int m, int n, int *ip, int kp) {
  int k, i;
  float qp, q0, q, q1;
  *ip = 0;
  for (i = 1; i <= m; i++)
    if (a[i + 1][kp + 1] < -1.0e-6)
      break;
  if (i > m)
    return;
  q1 = -a[i + 1][1] / a[i + 1][kp + 1];
  *ip = i;
  for (i = *ip + 1; i <= m; i++) {
    if (a[i + 1][kp + 1] < -1.0e-6) {
      q = -a[i + 1][1] / a[i + 1][kp + 1];
      if (q < q1) {
        *ip = i;
        q1 = q;
      } else if (q == q1) {
        for (k = 1; k <= n; k++) {
          qp = -a[*ip + 1][k + 1] / a[*ip + 1][kp + 1];
          q0 = -a[i + 1][k + 1] / a[i + 1][kp + 1];
          if (q0 != qp)
            break;
        }
        if (q0 < qp)
          *ip = i;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<simp2>:
  endbr64
  movl   $0x0,(%rcx)
  test   %esi,%esi
  jle    L20
  movslq %r8d,%r8
  mov    %edx,%r9d
  mov    %rcx,%r10
  mov    $0x1,%eax
  movsd  D2(%rip),%xmm4
  lea    0x4(,%r8,4),%r8
  lea    0x10(%rdi),%rdx
  jmp    L126
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x8,%rdx
  cmp    %eax,%esi
  jl     L70
L126:
  mov    (%rdx),%rcx
  pxor   %xmm3,%xmm3
  mov    %eax,%r11d
  add    $0x1,%eax
  movss  (%rcx,%r8,1),%xmm2
  cvtss2sd %xmm2,%xmm3
  comisd %xmm3,%xmm4
  jbe    L53
  movss  0x4(%rcx),%xmm6
  movss  D5(%rip),%xmm5
  mov    %r11d,(%r10)
  movslq %eax,%rdx
  xorps  %xmm5,%xmm6
  divss  %xmm2,%xmm6
  cmp    %eax,%esi
  jl     L118
  push   %rbx
  jmp    L131
  xchg   %ax,%ax
L50:
  mov    %edx,(%r10)
  movaps %xmm2,%xmm6
L173:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jl     L83
L131:
  mov    0x8(%rdi,%rdx,8),%rax
  pxor   %xmm2,%xmm2
  mov    %edx,%r11d
  movss  (%rax,%r8,1),%xmm3
  cvtss2sd %xmm3,%xmm2
  comisd %xmm2,%xmm4
  jbe    L173
  movss  0x4(%rax),%xmm2
  xorps  %xmm5,%xmm2
  divss  %xmm3,%xmm2
  comiss %xmm2,%xmm6
  ja     L50
  ucomiss %xmm6,%xmm2
  jp     L173
  jne    L173
  test   %r9d,%r9d
  jle    L86
  movslq (%r10),%rcx
  mov    0x8(%rdi,%rcx,8),%rbx
  mov    $0x1,%ecx
  movss  (%rbx,%r8,1),%xmm2
  jmp    L132
L22:
  add    $0x1,%rcx
  cmp    %ecx,%r9d
  jl     L86
L132:
  movss  0x4(%rbx,%rcx,4),%xmm0
  movss  0x4(%rax,%rcx,4),%xmm1
  xorps  %xmm5,%xmm0
  xorps  %xmm5,%xmm1
  divss  %xmm2,%xmm0
  divss  %xmm3,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L86
  je     L22
L86:
  comiss %xmm1,%xmm0
  jbe    L173
  add    $0x1,%rdx
  mov    %r11d,(%r10)
  cmp    %edx,%esi
  jge    L131
L83:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L70:
  ret
L20:
  ret
L118:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: byte[8]
name: disassemble_data
arguments: label: D5
datatype: byte[4]

tool: {"D2": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0xbe]}

tool: {"D5": [0x00,0x00,0x00,0x80]}

assistant: ```c
void simp2(float **a, int m, int n, int *ip, int kp) {
  int k, i;
  float qp, q0, q, q1;
  *ip = 0;
  for (i = 1; i <= m; i++)
    if (a[i + 1][kp + 1] < -1.0e-6)
      break;
  if (i > m)
    return;
  q1 = -a[i + 1][1] / a[i + 1][kp + 1];
  *ip = i;
  for (i = *ip + 1; i <= m; i++) {
    if (a[i + 1][kp + 1] < -1.0e-6) {
      q = -a[i + 1][1] / a[i + 1][kp + 1];
      if (q < q1) {
        *ip = i;
        q1 = q;
      } else if (q == q1) {
        for (k = 1; k <= n; k++) {
          qp = -a[*ip + 1][k + 1] / a[*ip + 1][kp + 1];
          q0 = -a[i + 1][k + 1] / a[i + 1][kp + 1];
          if (q0 != qp)
            break;
        }
        if (q0 < qp)
          *ip = i;
      }
    }
  }
}
```