ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<proc>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  movb   $0x75,0x27(%rsp)
  movl   $0x6f696561,0x23(%rsp)
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %al,%al
  je     L123
  lea    0x1(%rdi),%rdx
  xor    %r11d,%r11d
  xor    %esi,%esi
  xor    %ebx,%ebx
  xor    %edi,%edi
  xor    %ebp,%ebp
  xor    %r9d,%r9d
  xor    %r12d,%r12d
  xor    %r10d,%r10d
  xor    %r13d,%r13d
  lea    D18(%rip),%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L61:
  sub    $0x61,%eax
  cmp    $0x14,%al
  ja     L192
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  add    $0x1,%r8d
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L192:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L61
L3:
  test   %r11b,%r11b
  je     L92
  mov    %esi,0x10(%rsp)
L92:
  test   %bl,%bl
  je     L90
  mov    %edi,0xc(%rsp)
L90:
  test   %bpl,%bpl
  je     L179
  mov    %r9d,0x8(%rsp)
L179:
  test   %r12b,%r12b
  je     L34
  mov    %r10d,0x4(%rsp)
L34:
  test   %r13b,%r13b
  je     L123
L70:
  xor    %ebx,%ebx
  mov    $0x61,%esi
  lea    D7(%rip),%rbp
L110:
  mov    %r8d,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  je     L114
  mov    (%rsp,%rbx,4),%r8d
  movsbl 0x23(%rsp,%rbx,1),%esi
  jmp    L110
  nopl   0x0(%rax,%rax,1)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    $0x1,%r11d
  test   %al,%al
  jne    L61
  jmp    L3
  nopw   0x0(%rax,%rax,1)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%edi
  mov    $0x1,%ebx
  test   %al,%al
  jne    L61
  jmp    L3
  nopl   0x0(%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r9d
  mov    $0x1,%ebp
  test   %al,%al
  jne    L61
  jmp    L3
  nopl   (%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r10d
  mov    $0x1,%r12d
  test   %al,%al
  jne    L61
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L114:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L123:
  xor    %r8d,%r8d
  jmp    L70
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %c:%d


assistant: ```c
void proc(char sz[]) {
  int i = 0;
  char sa[5] = {'a', 'e', 'i', 'o', 'u'};
  int a[5] = {0};
  while (sz[i] != '\0') {
    switch (sz[i++]) {
    case 'a':
      ++(a[0]);
      break;
    case 'e':
      ++(a[1]);
      break;
    case 'i':
      ++(a[2]);
      break;
    case 'o':
      ++(a[3]);
      break;
    case 'u':
      ++(a[4]);
      break;
    default:
      break;
    }
  }
  for (i = 0; i < 5; ++i) {
    printf("%c:%d\n", sa[i], a[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<proc>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  movb   $0x75,0x27(%rsp)
  movl   $0x6f696561,0x23(%rsp)
  movl   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %al,%al
  je     L135
  lea    0x1(%rdi),%rdx
  xor    %r11d,%r11d
  xor    %esi,%esi
  xor    %ebx,%ebx
  xor    %edi,%edi
  xor    %ebp,%ebp
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  xor    %r9d,%r9d
  xor    %r13d,%r13d
  lea    D19(%rip),%rcx
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L84:
  sub    $0x61,%eax
  cmp    $0x14,%al
  ja     L81
  movzbl %al,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  add    $0x1,%r10d
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L81:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L84
L167:
  test   %r11b,%r11b
  je     L45
  mov    %esi,0x10(%rsp)
L45:
  test   %bl,%bl
  je     L102
  mov    %edi,0xc(%rsp)
L102:
  test   %bpl,%bpl
  je     L106
  mov    %r8d,0x8(%rsp)
L106:
  test   %r12b,%r12b
  je     L133
  mov    %r9d,0x4(%rsp)
L133:
  test   %r13b,%r13b
  je     L135
  mov    %r10d,(%rsp)
L135:
  xor    %ebx,%ebx
  mov    %rsp,%r13
  lea    0x23(%rsp),%r12
  lea    D1(%rip),%rbp
L157:
  mov    0x0(%r13,%rbx,4),%edx
  movsbl (%r12,%rbx,1),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L157
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    $0x1,%r11d
  test   %al,%al
  jne    L84
  jmp    L167
  nopl   (%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%edi
  mov    $0x1,%ebx
  test   %al,%al
  jne    L84
  jmp    L167
  nopl   0x0(%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r8d
  mov    $0x1,%ebp
  test   %al,%al
  jne    L84
  jmp    L167
  nopl   (%rax)
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r9d
  mov    $0x1,%r12d
  test   %al,%al
  jne    L84
  jmp    L167
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: %c:%d


assistant: ```c
void proc(char sz[]) {
  int i = 0;
  char sa[5] = {'a', 'e', 'i', 'o', 'u'};
  int a[5] = {0};
  while (sz[i] != '\0') {
    switch (sz[i++]) {
    case 'a':
      ++(a[0]);
      break;
    case 'e':
      ++(a[1]);
      break;
    case 'i':
      ++(a[2]);
      break;
    case 'o':
      ++(a[3]);
      break;
    case 'u':
      ++(a[4]);
      break;
    default:
      break;
    }
  }
  for (i = 0; i < 5; ++i) {
    printf("%c:%d\n", sa[i], a[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<KIONIX_ACCEL_motion_mask_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0xd(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1f,%edi
  call   <KIONIX_ACCEL_read_bytes@plt>
  test   %rax,%rax
  jne    L20
  movzbl -0xd(%rbp),%eax
  or     $0x20,%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x1f,%edi
  call   <KIONIX_ACCEL_write_byte@plt>
  jmp    L12
L20:
  movl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int KIONIX_ACCEL_motion_mask_z(void) {
  char int_ctrl_reg2 = 0;
  int status = 0;
  if (KIONIX_ACCEL_read_bytes(0x1F, &int_ctrl_reg2, 1) == 0) {
    int_ctrl_reg2 |= 0x20;
    KIONIX_ACCEL_write_byte(0x1F, int_ctrl_reg2);
  } else
    status = 1;
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<KIONIX_ACCEL_motion_mask_z>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1f,%edi
  call   <KIONIX_ACCEL_read_bytes@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L26
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  ret
L26:
  movzbl 0x7(%rsp),%esi
  or     $0x20,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  mov    $0x1f,%edi
  call   <KIONIX_ACCEL_write_byte@plt>
  mov    $0x0,%eax
  jmp    L0
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int KIONIX_ACCEL_motion_mask_z(void) {
  char int_ctrl_reg2 = 0;
  int status = 0;
  if (KIONIX_ACCEL_read_bytes(0x1F, &int_ctrl_reg2, 1) == 0) {
    int_ctrl_reg2 |= 0x20;
    KIONIX_ACCEL_write_byte(0x1F, int_ctrl_reg2);
  } else
    status = 1;
  return status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<KIONIX_ACCEL_motion_mask_z>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x1f,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <KIONIX_ACCEL_read_bytes@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L28
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movzbl 0x7(%rsp),%esi
  mov    $0x1f,%edi
  or     $0x20,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  call   <KIONIX_ACCEL_write_byte@plt>
  xor    %eax,%eax
  jmp    L9
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int KIONIX_ACCEL_motion_mask_z(void) {
  char int_ctrl_reg2 = 0;
  int status = 0;
  if (KIONIX_ACCEL_read_bytes(0x1F, &int_ctrl_reg2, 1) == 0) {
    int_ctrl_reg2 |= 0x20;
    KIONIX_ACCEL_write_byte(0x1F, int_ctrl_reg2);
  } else
    status = 1;
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<KIONIX_ACCEL_motion_mask_z>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x1f,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <KIONIX_ACCEL_read_bytes@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L7
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl 0x7(%rsp),%esi
  mov    $0x1f,%edi
  or     $0x20,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  call   <KIONIX_ACCEL_write_byte@plt>
  xor    %eax,%eax
  jmp    L15
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int KIONIX_ACCEL_motion_mask_z(void) {
  char int_ctrl_reg2 = 0;
  int status = 0;
  if (KIONIX_ACCEL_read_bytes(0x1F, &int_ctrl_reg2, 1) == 0) {
    int_ctrl_reg2 |= 0x20;
    KIONIX_ACCEL_write_byte(0x1F, int_ctrl_reg2);
  } else
    status = 1;
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3030303030307830,%rax
  mov    %rax,-0x2b(%rbp)
  movw   $0x3030,-0x23(%rbp)
  movb   $0x0,-0x21(%rbp)
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x9,-0x34(%rbp)
  jmp    L27
L47:
  mov    -0x48(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x34(%rbp),%eax
  mov    %dl,-0x2b(%rbp,%rax,1)
  mov    -0x48(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  je     L8
  subl   $0x1,-0x34(%rbp)
L27:
  cmpl   $0x1,-0x34(%rbp)
  ja     L47
  jmp    L9
L8:
  nop
L9:
  lea    -0x2b(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
void print_hex(unsigned long number) {
  char buf[] = "0x00000000";
  char hex[] = "0123456789ABCDEF";
  unsigned int i, digit;
  for (i = 9; i > 1; i--) {
    digit = number % 0x10;
    buf[i] = hex[digit];
    number /= 0x10;
    if (number == 0)
      break;
  }
  print(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_hex>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x3030303030307830,%rax
  mov    %rax,0x5(%rsp)
  movw   $0x3030,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  mov    %rdi,%rax
  and    $0xf,%eax
  movzbl 0x10(%rsp,%rax,1),%eax
  mov    %al,0xe(%rsp)
  mov    %rdi,%rax
  shr    $0x4,%rax
  lea    0xd(%rsp),%rdx
  lea    0x6(%rsp),%rsi
  cmp    $0xf,%rdi
  jbe    L10
L2:
  mov    %rax,%rcx
  and    $0xf,%ecx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  mov    %cl,(%rdx)
  mov    %rax,%rcx
  shr    $0x4,%rax
  cmp    $0xf,%rcx
  jbe    L10
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L2
L10:
  lea    0x5(%rsp),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_hex(unsigned long number) {
  char buf[] = "0x00000000";
  char hex[] = "0123456789ABCDEF";
  unsigned int i, digit;
  for (i = 9; i > 1; i--) {
    digit = number % 0x10;
    buf[i] = hex[digit];
    number /= 0x10;
    if (number == 0)
      break;
  }
  print(buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_hex>:
  endbr64
  sub    $0x38,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x3030303030307830,%rax
  movb   $0x0,0xf(%rsp)
  lea    0x6(%rsp),%rcx
  movb   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x5(%rsp)
  mov    $0x3030,%eax
  mov    %ax,0xd(%rsp)
  lea    0xe(%rsp),%rax
L6:
  mov    %rdi,%rdx
  and    $0xf,%edx
  movzbl 0x10(%rsp,%rdx,1),%edx
  mov    %dl,(%rax)
  mov    %rdi,%rdx
  shr    $0x4,%rdi
  cmp    $0xf,%rdx
  jbe    L9
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L6
L9:
  lea    0x5(%rsp),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D0": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void print_hex(unsigned long number) {
  char buf[] = "0x00000000";
  char hex[] = "0123456789ABCDEF";
  unsigned int i, digit;
  for (i = 9; i > 1; i--) {
    digit = number % 0x10;
    buf[i] = hex[digit];
    number /= 0x10;
    if (number == 0)
      break;
  }
  print(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_hex>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x3030,%eax
  movdqa D1(%rip),%xmm0
  movabs $0x3030303030307830,%rsi
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  mov    %rdi,%rdx
  mov    %ax,0xd(%rsp)
  and    $0xf,%edx
  movaps %xmm0,0x10(%rsp)
  movzbl 0x10(%rsp,%rdx,1),%edx
  mov    %rsi,0x5(%rsp)
  movb   $0x0,0xf(%rsp)
  mov    %dl,0xe(%rsp)
  mov    %rdi,%rdx
  movb   $0x0,0x20(%rsp)
  shr    $0x4,%rdx
  cmp    $0xf,%rdi
  jbe    L50
  mov    %rdx,%rcx
  mov    %rdi,%rax
  and    $0xf,%ecx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  mov    %cl,0xd(%rsp)
  mov    %rdi,%rcx
  shr    $0x8,%rcx
  cmp    $0xf,%rdx
  jbe    L50
  mov    %rcx,%rdx
  and    $0xf,%edx
  movzbl 0x10(%rsp,%rdx,1),%edx
  mov    %dl,0xc(%rsp)
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  cmp    $0xf,%rcx
  jbe    L50
  mov    %rdx,%rcx
  and    $0xf,%ecx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  mov    %cl,0xb(%rsp)
  mov    %rdi,%rcx
  shr    $0x10,%rcx
  cmp    $0xf,%rdx
  jbe    L50
  mov    %rcx,%rdx
  and    $0xf,%edx
  movzbl 0x10(%rsp,%rdx,1),%edx
  mov    %dl,0xa(%rsp)
  mov    %rdi,%rdx
  shr    $0x14,%rdx
  cmp    $0xf,%rcx
  jbe    L50
  mov    %rdx,%rcx
  and    $0xf,%ecx
  movzbl 0x10(%rsp,%rcx,1),%ecx
  mov    %cl,0x9(%rsp)
  mov    %rdi,%rcx
  shr    $0x18,%rcx
  cmp    $0xf,%rdx
  jbe    L50
  mov    %rcx,%rdx
  shr    $0x1c,%rax
  and    $0xf,%edx
  movzbl 0x10(%rsp,%rdx,1),%edx
  mov    %dl,0x8(%rsp)
  cmp    $0xf,%rcx
  jbe    L50
  and    $0xf,%eax
  movzbl 0x10(%rsp,%rax,1),%eax
  mov    %al,0x7(%rsp)
L50:
  lea    0x5(%rsp),%rdi
  call   <print@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x38,%rsp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: byte[16]

tool: {"D1": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void print_hex(unsigned long number) {
  char buf[] = "0x00000000";
  char hex[] = "0123456789ABCDEF";
  unsigned int i, digit;
  for (i = 9; i > 1; i--) {
    digit = number % 0x10;
    buf[i] = hex[digit];
    number /= 0x10;
    if (number == 0)
      break;
  }
  print(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<basename_match_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  mov    $0x1,%eax
  jmp    L12
L18:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int basename_match_filter(char *filename, char *textcontent) {
  if (strcmp(basename(filename), textcontent) == 0)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<basename_match_filter>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <basename@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int basename_match_filter(char *filename, char *textcontent) {
  if (strcmp(basename(filename), textcontent) == 0)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basename_match_filter>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <basename@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int basename_match_filter(char *filename, char *textcontent) {
  if (strcmp(basename(filename), textcontent) == 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basename_match_filter>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <basename@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int basename_match_filter(char *filename, char *textcontent) {
  if (strcmp(basename(filename), textcontent) == 0)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<solv_zextend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <solv_extend@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rcx
  imul   -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *solv_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = solv_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solv_zextend>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  call   <solv_extend@plt>
  mov    %rax,%r12
  mov    %rbp,%rdx
  imul   %r13,%rdx
  imul   %r13,%rbx
  lea    (%rax,%rbx,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *solv_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = solv_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solv_zextend>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  imul   %r12,%rbx
  sub    $0x8,%rsp
  call   <solv_extend@plt>
  mov    %rbp,%rdx
  xor    %esi,%esi
  imul   %r12,%rdx
  lea    (%rax,%rbx,1),%rdi
  mov    %rax,%r13
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *solv_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = solv_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<solv_zextend>:
  endbr64
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  imul   %r12,%rbx
  sub    $0x8,%rsp
  call   <solv_extend@plt>
  mov    %rbp,%rdx
  xor    %esi,%esi
  imul   %r12,%rdx
  lea    (%rax,%rbx,1),%rdi
  mov    %rax,%r13
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *solv_zextend(void *buf, size_t len, size_t nmemb, size_t size, size_t block) {
  buf = solv_extend(buf, len, nmemb, size, block);
  memset((char *)buf + len * size, 0, nmemb * size);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
L26:
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  je     L27
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <even@plt>
  cmp    $0x1,%eax
  jne    L0
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L27
L0:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
data_type: string
name: disassemble_data
arguments: tag: D42
data_type: string
name: disassemble_data
arguments: tag: D35
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string

tool: D15: Inserire il primo numero ( -1 per uscire ): 

tool: D42: %s

tool: D35: %d

tool: D1: Il numero: %d e' pari.


tool: D20: Il numero: %d non e' pari.


assistant: ```c
int main(void) {
  unsigned int even(int numeroInserito);
  int valoreSentinella = -1;
  int numeroInserito;
  do {
    printf("%s", "Inserire il primo numero ( -1 per uscire ): ");
    scanf("%d", &numeroInserito);
    if (numeroInserito != valoreSentinella) {
      if (even(numeroInserito) == 1) {
        printf("Il numero: %d e' pari.\n", numeroInserito);
      } else {
        printf("Il numero: %d non e' pari.\n", numeroInserito);
      }
    }
  } while (numeroInserito != valoreSentinella);
  return 0;
}
```