ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_toyfile_list>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L10
  mov    %rdi,%rbp
  mov    %rsi,%rdx
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  lea    D0(%rip),%rsi
  call   <get_value_by_key@plt>
  test   %rax,%rax
  js     L10
  mov    (%rsp),%rsi
  mov    $0x1,%ecx
  lea    D14(%rip),%rdx
  mov    %rbp,%rdi
  call   <str_split@plt>
  mov    (%rsp),%rdi
  call   <free_mem@plt>
  xor    %eax,%eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  mov    $0xffffffff,%eax
  jmp    L39
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D0: toyfile

tool: D14: , 	

assistant: ```c
int get_toyfile_list(char ***file_list, char *const *line_list) {
  if (NULL == line_list) {
    return -1;
  }
  char *value = NULL;
  if (get_value_by_key(&value, "toyfile", line_list) < 0) {
    ;
    return -1;
  };
  ;
  if (str_split(file_list, value, ", \t", 1) < 0) {
    ;
  }
  free_mem(value);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_creturn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: 

assistant: ```c
const char *remove_creturn(char *str) {
  str = strtok(str, "\r");
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_creturn>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  call   <strtok@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: 

assistant: ```c
const char *remove_creturn(char *str) {
  str = strtok(str, "\r");
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_creturn>:
  endbr64
  lea    D4(%rip),%rsi
  jmp    1050 <strtok@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: 

assistant: ```c
const char *remove_creturn(char *str) {
  str = strtok(str, "\r");
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_creturn>:
  endbr64
  lea    D8(%rip),%rsi
  jmp    1050 <strtok@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: 

assistant: ```c
const char *remove_creturn(char *str) {
  str = strtok(str, "\r");
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arg_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  je     L1
  mov    $0x0,%eax
  call   <print_help@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void arg_check(int argc, int expected) {
  if (argc - 2 != expected) {
    print_help();
    exit(EXIT_FAILURE);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arg_check>:
  endbr64
  sub    $0x2,%edi
  cmp    %esi,%edi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_help@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void arg_check(int argc, int expected) {
  if (argc - 2 != expected) {
    print_help();
    exit(EXIT_FAILURE);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<arg_check>:
  endbr64
  sub    $0x2,%edi
  cmp    %esi,%edi
  jne    L3
  ret
  nopl   0x0(%rax)
L3:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_help@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void arg_check(int argc, int expected) {
  if (argc - 2 != expected) {
    print_help();
    exit(EXIT_FAILURE);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<arg_check>:
  endbr64
  sub    $0x2,%edi
  cmp    %esi,%edi
  jne    L4
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_help@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void arg_check(int argc, int expected) {
  if (argc - 2 != expected) {
    print_help();
    exit(EXIT_FAILURE);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L38
  mov    $0x1,%eax
  jmp    L36
L38:
  movl   $0x0,-0x14(%rbp)
  jmp    L54
L22:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L46
  mov    $0x1,%eax
  jmp    L36
L46:
  addl   $0x1,-0x14(%rbp)
L54:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L22
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i;
  if (strlen(s1) != strlen(s1))
    return 1;
  for (i = 0; i < strlen(s1); i++)
    if (toupper(s1[i]) != toupper(s2[i]))
      return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    %edx,%ebx
  jne    L36
  mov    $0x0,%ebx
L35:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L38
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  mov    %rax,%rbp
  movsbl 0x0(%r13,%rbx,1),%edi
  call   <toupper@plt>
  add    $0x1,%rbx
  cmp    %rax,%rbp
  je     L35
  mov    $0x1,%eax
  jmp    L36
L38:
  mov    $0x0,%eax
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i;
  if (strlen(s1) != strlen(s1))
    return 1;
  for (i = 0; i < strlen(s1); i++)
    if (toupper(s1[i]) != toupper(s2[i]))
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasecmp>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L36
  xor    %ebx,%ebx
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  movsbl 0x0(%r13,%rbx,1),%edi
  add    $0x1,%rbx
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L36
L29:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i;
  if (strlen(s1) != strlen(s1))
    return 1;
  for (i = 0; i < strlen(s1); i++)
    if (toupper(s1[i]) != toupper(s2[i]))
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasecmp>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jne    L19
  xor    %ebx,%ebx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L27:
  movsbl (%r12,%rbx,1),%edi
  call   <toupper@plt>
  movsbl 0x0(%r13,%rbx,1),%edi
  add    $0x1,%rbx
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L19
L30:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L27
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i;
  if (strlen(s1) != strlen(s1))
    return 1;
  for (i = 0; i < strlen(s1); i++)
    if (toupper(s1[i]) != toupper(s2[i]))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uchar_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <unsigned_value@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L15
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jae    L14
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char uchar_range(unsigned min, unsigned max) {
  unsigned x = unsigned_value();
  if (x < min || max < x)
    x = min;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uchar_range>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <unsigned_value@plt>
  cmp    %ebx,%eax
  jb     L9
  cmp    %ebp,%eax
  jbe    L18
L9:
  mov    %ebx,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char uchar_range(unsigned min, unsigned max) {
  unsigned x = unsigned_value();
  if (x < min || max < x)
    x = min;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uchar_range>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <unsigned_value@plt>
  cmp    %ebx,%eax
  jb     L0
  cmp    %ebp,%eax
  ja     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char uchar_range(unsigned min, unsigned max) {
  unsigned x = unsigned_value();
  if (x < min || max < x)
    x = min;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uchar_range>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <unsigned_value@plt>
  cmp    %ebx,%eax
  jb     L19
  cmp    %ebp,%eax
  ja     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L19:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char uchar_range(unsigned min, unsigned max) {
  unsigned x = unsigned_value();
  if (x < min || max < x)
    x = min;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x7,%eax
  and    $0x4334b500,%eax
  je     L18
  rol    $0xf,%eax
L4:
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
L18:
  mov    %eax,%edx
  sar    $0x18,%edx
  and    $0xffffff,%eax
  mov    %dl,%al
  mov    %eax,%ecx
  shr    $0x3,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%eax
  jmp    L4
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > local2 << (((local1 >> 1U) & 7U) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> 4U) & 7U) | 1UL);
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local2]) + 3);
          *((char *)(&state[local2]) + 3) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy12;
          state[local2] = state[local1] >> (((state[local1] >> 3U) & 7U) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  shl    $0x7,%edx
  mov    %edx,%ecx
  and    $0x4334b500,%ecx
  je     L1
  mov    %ecx,%eax
  rol    $0xf,%eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
  xchg   %ax,%ax
L1:
  mov    %edx,%eax
  and    $0x34b500,%eax
  xor    %al,%al
  mov    %eax,%ecx
  shr    $0x3,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > local2 << (((local1 >> 1U) & 7U) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> 4U) & 7U) | 1UL);
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local2]) + 3);
          *((char *)(&state[local2]) + 3) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy12;
          state[local2] = state[local1] >> (((state[local1] >> 3U) & 7U) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x7,%eax
  mov    %eax,%edx
  and    $0x4334b500,%edx
  je     L1
  mov    %edx,%eax
  rol    $0xf,%eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
  xchg   %ax,%ax
L1:
  and    $0x34b500,%eax
  shr    %eax
  shl    $0x3,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > local2 << (((local1 >> 1U) & 7U) | 1UL)) {
          state[local2] = state[local1] >> (((state[local1] >> 4U) & 7U) | 1UL);
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          copy12 = *((char *)(&state[local2]) + 3);
          *((char *)(&state[local2]) + 3) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy12;
          state[local2] = state[local1] >> (((state[local1] >> 3U) & 7U) | 1UL);
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] << 3U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<md5_process_part2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r11
  mov    (%rdi),%r14d
  mov    0x4(%rdi),%edi
  mov    %edi,-0xc(%rsp)
  mov    0x8(%r13),%r10d
  mov    %r10d,-0x8(%rsp)
  mov    0xc(%r13),%eax
  mov    %eax,-0x4(%rsp)
  mov    %eax,%r8d
  mov    %r14d,%ecx
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%r9d
  mov    $0x20,%r12d
  jmp    L14
L34:
  mov    %r10d,%r9d
  xor    %r8d,%r9d
  and    %edi,%r9d
  xor    %r8d,%r9d
  mov    %esi,%edx
L70:
  lea    (%r9,%rcx,1),%eax
  add    (%rbx,%rsi,4),%eax
  movslq %edx,%rcx
  add    0x0(%rbp,%rcx,4),%eax
  mov    %r12d,%ecx
  sub    (%r11,%rsi,4),%ecx
  mov    %eax,%r15d
  sar    %cl,%r15d
  movzbl (%r11,%rsi,4),%ecx
  shl    %cl,%eax
  or     %eax,%r15d
  add    %edi,%r15d
  add    $0x1,%rsi
  mov    %r8d,%ecx
  cmp    $0x40,%rsi
  je     L24
  mov    %r10d,%r8d
  mov    %edi,%r10d
  mov    %r15d,%edi
L14:
  cmp    $0xf,%esi
  jbe    L34
  lea    -0x10(%rsi),%r15d
  cmp    $0xf,%r15d
  jbe    L40
  lea    -0x20(%rsi),%r15d
  cmp    $0xf,%r15d
  jbe    L69
  lea    -0x30(%rsi),%r15d
  cmp    $0xf,%r15d
  ja     L70
  mov    %r8d,%r9d
  not    %r9d
  or     %edi,%r9d
  xor    %r10d,%r9d
  imul   $0x7,%esi,%eax
  mov    $0x10,%r15d
  cltd
  idiv   %r15d
  jmp    L70
L40:
  mov    %edi,%r9d
  xor    %r10d,%r9d
  and    %r8d,%r9d
  xor    %r10d,%r9d
  imul   $0x5,%esi,%eax
  add    $0x1,%eax
  mov    $0x10,%r15d
  cltd
  idiv   %r15d
  jmp    L70
L69:
  mov    %edi,%r9d
  xor    %r10d,%r9d
  xor    %r8d,%r9d
  imul   $0x3,%esi,%eax
  add    $0x5,%eax
  mov    $0x10,%r15d
  cltd
  idiv   %r15d
  jmp    L70
L24:
  add    %r8d,%r14d
  mov    %r14d,0x0(%r13)
  mov    -0xc(%rsp),%eax
  add    %r15d,%eax
  mov    %eax,0x4(%r13)
  mov    -0x8(%rsp),%eax
  add    %edi,%eax
  mov    %eax,0x8(%r13)
  mov    -0x4(%rsp),%eax
  add    %r10d,%eax
  mov    %eax,0xc(%r13)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void md5_process_part2(uint32_t abcd[4], uint32_t *w, const uint32_t k[64], const uint32_t s[64]) {
  uint32_t i;
  uint32_t a = abcd[0];
  uint32_t b = abcd[1];
  uint32_t c = abcd[2];
  uint32_t d = abcd[3];
  uint32_t f = 0;
  uint32_t g = 0;
  for (i = 0; i < 64; i++) {
    if (i >= 0 && i <= 15) {
      f = (b & c) | ((~b) & d);
      g = i;
    } else if (i >= 16 && i <= 31) {
      f = (d & b) | ((~d) & c);
      g = (5 * i + 1) % 16;
    } else if (i >= 32 && i <= 47) {
      f = b ^ c ^ d;
      g = (3 * i + 5) % 16;
    } else if (i >= 48 && i <= 63) {
      f = c ^ (b | (~d));
      g = (7 * i) % 16;
    }
    uint32_t temp = d;
    d = c;
    c = b;
    b = ((((a + f + k[i] + w[g])) << (s[i])) | (((a + f + k[i] + w[g])) >> (32 - (s[i])))) + b;
    a = temp;
  }
  abcd[0] += a;
  abcd[1] += b;
  abcd[2] += c;
  abcd[3] += d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<md5_process_part2>:
  endbr64
  push   %r15
  mov    %rcx,%r10
  mov    %rdx,%r11
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x20,%ebp
  push   %rbx
  mov    0xc(%rdi),%eax
  mov    %rsi,%rbx
  xor    %esi,%esi
  mov    (%rdi),%r14d
  mov    0x8(%rdi),%r9d
  mov    0x4(%rdi),%r13d
  mov    %eax,%r8d
  mov    %r9d,-0x8(%rsp)
  mov    %r14d,%ecx
  mov    %eax,-0x4(%rsp)
  mov    %r13d,%edi
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L39:
  lea    -0x10(%rsi),%eax
  cmp    $0xf,%eax
  jbe    L14
  lea    -0x20(%rsi),%eax
  cmp    $0xf,%eax
  jbe    L18
  mov    %r8d,%eax
  lea    0x0(,%rsi,8),%r15d
  not    %eax
  sub    %esi,%r15d
  or     %edi,%eax
  mov    %r15d,%edx
  xor    %r9d,%eax
  and    $0xf,%edx
L49:
  mov    (%r10,%rsi,4),%r15d
  movslq %edx,%rdx
  add    %ecx,%eax
  mov    %ebp,%ecx
  add    (%r11,%rsi,4),%eax
  add    (%rbx,%rdx,4),%eax
  add    $0x1,%rsi
  sub    %r15d,%ecx
  mov    %eax,%edx
  sar    %cl,%edx
  mov    %r15d,%ecx
  shl    %cl,%eax
  mov    %r8d,%ecx
  or     %edx,%eax
  add    %edi,%eax
  cmp    $0x40,%rsi
  je     L38
  mov    %r9d,%r8d
  mov    %edi,%r9d
  mov    %eax,%edi
L55:
  mov    %esi,%edx
  cmp    $0xf,%rsi
  ja     L39
  mov    %r9d,%eax
  xor    %r8d,%eax
  and    %edi,%eax
  xor    %r8d,%eax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L38:
  add    %eax,%r13d
  mov    -0x8(%rsp),%eax
  add    %r8d,%r14d
  mov    %r14d,(%r12)
  add    %edi,%eax
  mov    %r13d,0x4(%r12)
  mov    %eax,0x8(%r12)
  mov    -0x4(%rsp),%eax
  pop    %rbx
  pop    %rbp
  add    %r9d,%eax
  mov    %eax,0xc(%r12)
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    %edi,%eax
  lea    (%rsi,%rsi,4),%edx
  xor    %r9d,%eax
  add    $0x1,%edx
  and    %r8d,%eax
  and    $0xf,%edx
  xor    %r9d,%eax
  jmp    L49
L18:
  mov    %edi,%eax
  lea    (%rsi,%rsi,2),%edx
  xor    %r9d,%eax
  add    $0x5,%edx
  xor    %r8d,%eax
  and    $0xf,%edx
  jmp    L49
```

assistant: ```c
void md5_process_part2(uint32_t abcd[4], uint32_t *w, const uint32_t k[64], const uint32_t s[64]) {
  uint32_t i;
  uint32_t a = abcd[0];
  uint32_t b = abcd[1];
  uint32_t c = abcd[2];
  uint32_t d = abcd[3];
  uint32_t f = 0;
  uint32_t g = 0;
  for (i = 0; i < 64; i++) {
    if (i >= 0 && i <= 15) {
      f = (b & c) | ((~b) & d);
      g = i;
    } else if (i >= 16 && i <= 31) {
      f = (d & b) | ((~d) & c);
      g = (5 * i + 1) % 16;
    } else if (i >= 32 && i <= 47) {
      f = b ^ c ^ d;
      g = (3 * i + 5) % 16;
    } else if (i >= 48 && i <= 63) {
      f = c ^ (b | (~d));
      g = (7 * i) % 16;
    }
    uint32_t temp = d;
    d = c;
    c = b;
    b = ((((a + f + k[i] + w[g])) << (s[i])) | (((a + f + k[i] + w[g])) >> (32 - (s[i])))) + b;
    a = temp;
  }
  abcd[0] += a;
  abcd[1] += b;
  abcd[2] += c;
  abcd[3] += d;
}
```