ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<smileDsp_winBaH>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L3
L18:
  movsd  -0x8(%rbp),%xmm0
  movsd  D37(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  D35(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   D7(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x38(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  movsd  D37(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x40(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D37(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L3:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  ja     L18
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type_infered: f64
name: extract_symbolic_data
arguments: tag: D35
type_infered: f64
name: extract_symbolic_data
arguments: tag: D7
type_infered: qword
name: extract_symbolic_data
arguments: tag: D8
type_infered: byte[8]

tool: D37: 1

tool: D35: 0.5

tool: D7: 9223372036854775807

tool: {"D8": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
double *smileDsp_winBaH(long _N, double alpha0, double alpha1, double alpha2) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = alpha0 - alpha1 * fabs(i / (NN - 1.0) - 0.5) - alpha2 * cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0));
    x++;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smileDsp_winBaH>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  movq   %xmm0,%rbp
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x18(%rsp)
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  pxor   %xmm7,%xmm7
  cvtsi2sd %rbx,%xmm7
  pxor   %xmm5,%xmm5
  movsd  %xmm5,(%rsp)
  comisd %xmm5,%xmm7
  jbe    L18
  movq   %xmm7,%r14
  mov    %rax,%rbx
  subsd  D31(%rip),%xmm7
  movsd  %xmm7,0x8(%rsp)
L6:
  movsd  D39(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm1
  divsd  0x8(%rsp),%xmm1
  subsd  D23(%rip),%xmm1
  andpd  D43(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  movq   %rbp,%xmm2
  subsd  %xmm1,%xmm2
  mulsd  0x18(%rsp),%xmm0
  subsd  %xmm0,%xmm2
  movsd  %xmm2,(%rbx)
  add    $0x8,%rbx
  movsd  D31(%rip),%xmm4
  addsd  %xmm3,%xmm4
  movsd  %xmm4,(%rsp)
  movq   %r14,%xmm6
  comisd %xmm4,%xmm6
  ja     L6
L18:
  mov    %r12,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D31
datatype: f64
name: parse_data
arguments: label: D39
datatype: byte[8]
name: parse_data
arguments: label: D23
datatype: f64
name: parse_data
arguments: label: D43
datatype: qword[2]

tool: D31: 1

tool: {"D39": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D23: 0.5

tool: {"D43": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double *smileDsp_winBaH(long _N, double alpha0, double alpha1, double alpha2) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = alpha0 - alpha1 * fabs(i / (NN - 1.0) - 0.5) - alpha2 * cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0));
    x++;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<smileDsp_winBaH>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%edi
  sub    $0x28,%rsp
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <malloc@plt>
  pxor   %xmm5,%xmm5
  pxor   %xmm6,%xmm6
  cvtsi2sd %rbx,%xmm5
  mov    %rax,%r12
  comisd %xmm6,%xmm5
  jbe    L2
  movq   %xmm5,%r14
  subsd  D33(%rip),%xmm5
  pxor   %xmm2,%xmm2
  mov    %rax,%rbx
  movsd  %xmm5,(%rsp)
  xchg   %ax,%ax
L6:
  movsd  D8(%rip),%xmm0
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm2,%xmm0
  divsd  (%rsp),%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  0x18(%rsp),%xmm0
  movq   %r15,%xmm3
  movq   %r14,%xmm7
  movapd %xmm2,%xmm1
  divsd  (%rsp),%xmm1
  subsd  D21(%rip),%xmm1
  andpd  D6(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  D33(%rip),%xmm2
  subsd  %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movsd  %xmm3,-0x8(%rbx)
  comisd %xmm2,%xmm7
  ja     L6
L2:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D33
type_guessed: f64
name: retrieve_data
arguments: data_label: D8
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D21
type_guessed: f64
name: retrieve_data
arguments: data_label: D6
type_guessed: qword[2]

tool: D33: 1

tool: {"D8": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D21: 0.5

tool: {"D6": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double *smileDsp_winBaH(long _N, double alpha0, double alpha1, double alpha2) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = alpha0 - alpha1 * fabs(i / (NN - 1.0) - 0.5) - alpha2 * cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0));
    x++;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smileDsp_winBaH>:
  endbr64
  push   %r15
  movq   %xmm0,%r15
  push   %r14
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%edi
  sub    $0x28,%rsp
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <malloc@plt>
  pxor   %xmm5,%xmm5
  pxor   %xmm6,%xmm6
  cvtsi2sd %rbx,%xmm5
  mov    %rax,%r12
  comisd %xmm6,%xmm5
  jbe    L7
  movq   %xmm5,%r14
  subsd  D23(%rip),%xmm5
  pxor   %xmm2,%xmm2
  mov    %rax,%rbx
  movsd  %xmm5,(%rsp)
  xchg   %ax,%ax
L2:
  movsd  D40(%rip),%xmm0
  movsd  %xmm2,0x8(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm2,%xmm0
  divsd  (%rsp),%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  0x18(%rsp),%xmm0
  movq   %r15,%xmm3
  movq   %r14,%xmm7
  movapd %xmm2,%xmm1
  divsd  (%rsp),%xmm1
  subsd  D46(%rip),%xmm1
  andpd  D12(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  D23(%rip),%xmm2
  subsd  %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movsd  %xmm3,-0x8(%rbx)
  comisd %xmm2,%xmm7
  ja     L2
L7:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_infered: f64
name: parse_data
arguments: data_tag: D40
type_infered: byte[8]
name: parse_data
arguments: data_tag: D46
type_infered: f64
name: parse_data
arguments: data_tag: D12
type_infered: qword[2]

tool: D23: 1

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D46: 0.5

tool: {"D12": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double *smileDsp_winBaH(long _N, double alpha0, double alpha1, double alpha2) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = alpha0 - alpha1 * fabs(i / (NN - 1.0) - 0.5) - alpha2 * cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0));
    x++;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jne    L68
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L16
L68:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jle    L6
  mov    $0x1,%eax
  jmp    L49
L6:
  mov    $0xffffffff,%eax
L49:
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L75
L69:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L50
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
L75:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L69
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D20: %d %d

tool: D1: 0

tool: D8: %d


assistant: ```c
int main(void) {
  int inicio, fim, inc, i, soma = 0;
  scanf("%d %d", &inicio, &fim);
  if (inicio == fim) {
    printf("0\n");
  } else {
    inc = fim > inicio ? 1 : -1;
    for (i = inicio + inc; i != fim; i += inc) {
      if (i % 2 != 0) {
        soma += i;
      }
    }
    printf("%d\n", soma);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%ecx
  cmp    %ecx,%eax
  je     L45
  setl   %dil
  movzbl %dil,%edi
  lea    -0x1(%rdi,%rdi,1),%edi
  add    %edi,%eax
  cmp    %eax,%ecx
  je     L29
  mov    $0x0,%esi
L30:
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmovne %edx,%esi
  add    %edi,%eax
  cmp    %eax,%ecx
  jne    L30
L57:
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L45:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L53
L29:
  mov    $0x0,%esi
  jmp    L57
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D2
type_infered: string

tool: D16: %d %d

tool: D7: %d


tool: D2: 0

assistant: ```c
int main(void) {
  int inicio, fim, inc, i, soma = 0;
  scanf("%d %d", &inicio, &fim);
  if (inicio == fim) {
    printf("0\n");
  } else {
    inc = fim > inicio ? 1 : -1;
    for (i = inicio + inc; i != fim; i += inc) {
      if (i % 2 != 0) {
        soma += i;
      }
    }
    printf("%d\n", soma);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edi
  cmp    %edi,%eax
  je     L43
  setl   %cl
  xor    %esi,%esi
  movzbl %cl,%ecx
  lea    -0x1(%rcx,%rcx,1),%ecx
  add    %ecx,%eax
  cmp    %eax,%edi
  je     L24
  nopl   0x0(%rax)
L41:
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmovne %edx,%esi
  add    %ecx,%eax
  cmp    %eax,%edi
  jne    L41
L24:
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L43:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L30
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: string

tool: D22: %d %d

tool: D29: %d


tool: D21: 0

assistant: ```c
int main(void) {
  int inicio, fim, inc, i, soma = 0;
  scanf("%d %d", &inicio, &fim);
  if (inicio == fim) {
    printf("0\n");
  } else {
    inc = fim > inicio ? 1 : -1;
    for (i = inicio + inc; i != fim; i += inc) {
      if (i % 2 != 0) {
        soma += i;
      }
    }
    printf("%d\n", soma);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edi
  cmp    %edi,%eax
  je     L34
  setl   %cl
  xor    %esi,%esi
  movzbl %cl,%ecx
  lea    -0x1(%rcx,%rcx,1),%ecx
  add    %ecx,%eax
  cmp    %eax,%edi
  je     L46
  nopl   0x0(%rax)
L24:
  lea    (%rsi,%rax,1),%edx
  test   $0x1,%al
  cmovne %edx,%esi
  add    %ecx,%eax
  cmp    %eax,%edi
  jne    L24
L46:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L34:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D20
type_guessed: string

tool: D27: %d %d

tool: D14: %d


tool: D20: 0

assistant: ```c
int main(void) {
  int inicio, fim, inc, i, soma = 0;
  scanf("%d %d", &inicio, &fim);
  if (inicio == fim) {
    printf("0\n");
  } else {
    inc = fim > inicio ? 1 : -1;
    for (i = inicio + inc; i != fim; i += inc) {
      if (i % 2 != 0) {
        soma += i;
      }
    }
    printf("%d\n", soma);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_random_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x20,-0x5(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x4bda12f7,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  add    $0x60,%eax
  jmp    L12
L1:
  movzbl -0x5(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
unsigned char get_random_char() {
  unsigned char base = ' ';
  unsigned int res = rand() % 27;
  if (res) {
    return 96 + res;
  }
  return base;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_random_char>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x4bda12f7,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rdx,%rdx,8),%ecx
  sub    %ecx,%eax
  lea    0x60(%rax),%eax
  mov    $0x20,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char get_random_char() {
  unsigned char base = ' ';
  unsigned int res = rand() % 27;
  if (res) {
    return 96 + res;
  }
  return base;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_random_char>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4bda12f7,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rdx,%rdx,8),%ecx
  mov    $0x20,%edx
  sub    %ecx,%eax
  lea    0x60(%rax),%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char get_random_char() {
  unsigned char base = ' ';
  unsigned int res = rand() % 27;
  if (res) {
    return 96 + res;
  }
  return base;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_random_char>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4bda12f7,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  lea    (%rdx,%rdx,8),%ecx
  mov    $0x20,%edx
  sub    %ecx,%eax
  lea    0x60(%rax),%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char get_random_char() {
  unsigned char base = ' ';
  unsigned int res = rand() % 27;
  if (res) {
    return 96 + res;
  }
  return base;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0xb,%edx
  mov    $0x1,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D38(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x17,%edx
  mov    $0x1,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x11,%edx
  mov    $0x1,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x26,%edx
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D49
datatype: string
name: extract_symbolic_data
arguments: tag: D43
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D54
datatype: string
name: extract_symbolic_data
arguments: tag: D66
datatype: string

tool: D7: SIPRO V2.0


tool: D38: Usage: %s [-t] [-d] [-h] file


tool: D49: 	 Runs <file> on SIPRO


tool: D43: 	 -t: trace mode


tool: D19: 	 -d: dump memory at end of execution


tool: D54: 	 -s: print stack in trace mode


tool: D66: 	 -h: print this message and exit


assistant: ```c
void usage(FILE *fdo, const char *name, const char *prog) {
  fprintf(fdo, "SIPRO V2.0"
               "\n");
  fprintf(fdo, "Usage: %s [-t] [-d] [-h] file\n", name);
  fprintf(fdo, "\t Runs <file> on SIPRO\n");
  fprintf(fdo, "\t -t: trace mode\n");
  fprintf(fdo, "\t -d: dump memory at end of execution\n");
  fprintf(fdo, "\t -s: print stack in trace mode\n");
  fprintf(fdo, "\t -h: print this message and exit\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rcx
  mov    $0xb,%edx
  mov    $0x1,%esi
  lea    D47(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rdx
  lea    D38(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rcx
  mov    $0x17,%edx
  mov    $0x1,%esi
  lea    D66(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x11,%edx
  mov    $0x1,%esi
  lea    D43(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x26,%edx
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D47
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D66
datatype: string
name: extract_symbolic_data
arguments: tag: D43
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D47: SIPRO V2.0


tool: D38: Usage: %s [-t] [-d] [-h] file


tool: D66: 	 Runs <file> on SIPRO


tool: D43: 	 -t: trace mode


tool: D20: 	 -d: dump memory at end of execution


tool: D11: 	 -s: print stack in trace mode


tool: D4: 	 -h: print this message and exit


assistant: ```c
void usage(FILE *fdo, const char *name, const char *prog) {
  fprintf(fdo, "SIPRO V2.0"
               "\n");
  fprintf(fdo, "Usage: %s [-t] [-d] [-h] file\n", name);
  fprintf(fdo, "\t Runs <file> on SIPRO\n");
  fprintf(fdo, "\t -t: trace mode\n");
  fprintf(fdo, "\t -d: dump memory at end of execution\n");
  fprintf(fdo, "\t -s: print stack in trace mode\n");
  fprintf(fdo, "\t -h: print this message and exit\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  mov    %rsi,%r13
  mov    $0xb,%edx
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  lea    D27(%rip),%rdi
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x17,%edx
  mov    $0x1,%esi
  lea    D53(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x11,%edx
  mov    $0x1,%esi
  lea    D48(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x26,%edx
  mov    $0x1,%esi
  lea    D68(%rip),%rdi
  call   <fwrite@plt>
  mov    %r12,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x22,%edx
  pop    %r12
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  pop    %r13
  jmp    1070 <fwrite@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D53
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D68
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D27: SIPRO V2.0


tool: D15: Usage: %s [-t] [-d] [-h] file


tool: D53: 	 Runs <file> on SIPRO


tool: D48: 	 -t: trace mode


tool: D68: 	 -d: dump memory at end of execution


tool: D1: 	 -s: print stack in trace mode


tool: D0: 	 -h: print this message and exit


assistant: ```c
void usage(FILE *fdo, const char *name, const char *prog) {
  fprintf(fdo, "SIPRO V2.0"
               "\n");
  fprintf(fdo, "Usage: %s [-t] [-d] [-h] file\n", name);
  fprintf(fdo, "\t Runs <file> on SIPRO\n");
  fprintf(fdo, "\t -t: trace mode\n");
  fprintf(fdo, "\t -d: dump memory at end of execution\n");
  fprintf(fdo, "\t -s: print stack in trace mode\n");
  fprintf(fdo, "\t -h: print this message and exit\n");
}
```