ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x40(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D18(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   D25(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L9
  movsd  -0x10(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L9
  mov    -0x40(%rbp),%rax
  movq   %rax,%xmm0
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L20
L9:
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L22
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L22
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L20
L22:
  movsd  -0x20(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L20
  movsd  -0x18(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L20
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D48
datatype: string
name: retrieve_data
arguments: data_tag: D78
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: byte[8]
name: retrieve_data
arguments: data_tag: D25
datatype: qword
name: retrieve_data
arguments: data_tag: D54
datatype: string

tool: D48: Please enter 3 numbers separated by spaces > 

tool: D78: %lf%lf%lf

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D25: 9223372036854775807

tool: D54: %.0f is the median


assistant: ```c
int main() {
  double first, second, third;
  double median;
  double comp_fir, comp_sec, comp_thi;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%lf"
        "%lf"
        "%lf",
        &first, &second, &third);
  median = (first + second + third) / 3;
  comp_fir = fabs(first - median);
  comp_sec = fabs(second - median);
  comp_thi = fabs(third - median);
  if (comp_fir < comp_sec && comp_fir < comp_thi)
    printf("%.0f is the median\n", first);
  else if (comp_sec < comp_fir && comp_sec < comp_thi)
    printf("%.0f is the median\n", second);
  else if (comp_thi < comp_fir && comp_thi < comp_sec)
    printf("%.0f is the median\n", third);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm7
  movapd %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  addsd  %xmm7,%xmm0
  divsd  D12(%rip),%xmm0
  movapd %xmm5,%xmm1
  subsd  %xmm0,%xmm1
  movq   D14(%rip),%xmm4
  andpd  %xmm4,%xmm1
  movapd %xmm6,%xmm2
  subsd  %xmm0,%xmm2
  andpd  %xmm4,%xmm2
  movapd %xmm7,%xmm3
  subsd  %xmm0,%xmm3
  andpd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  comisd %xmm1,%xmm2
  jbe    L88
  comisd %xmm1,%xmm3
  ja     L57
L88:
  comisd %xmm2,%xmm1
  jbe    L56
  comisd %xmm2,%xmm0
  ja     L18
L56:
  comisd %xmm0,%xmm1
  jbe    L1
  comisd %xmm0,%xmm2
  ja     L38
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L57:
  movapd %xmm5,%xmm0
  lea    D45(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L1
L18:
  movapd %xmm6,%xmm0
  lea    D45(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L1
L38:
  movapd %xmm7,%xmm0
  lea    D45(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L1
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D49
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D14
data_type: qword
name: extract_symbolic_data
arguments: label: D45
data_type: string

tool: D49: Please enter 3 numbers separated by spaces > 

tool: D13: %lf%lf%lf

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D14: 9223372036854775807

tool: D45: %.0f is the median


assistant: ```c
int main() {
  double first, second, third;
  double median;
  double comp_fir, comp_sec, comp_thi;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%lf"
        "%lf"
        "%lf",
        &first, &second, &third);
  median = (first + second + third) / 3;
  comp_fir = fabs(first - median);
  comp_sec = fabs(second - median);
  comp_thi = fabs(third - median);
  if (comp_fir < comp_sec && comp_fir < comp_thi)
    printf("%.0f is the median\n", first);
  else if (comp_sec < comp_fir && comp_sec < comp_thi)
    printf("%.0f is the median\n", second);
  else if (comp_thi < comp_fir && comp_thi < comp_sec)
    printf("%.0f is the median\n", third);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D57(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdx
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm7
  movq   D13(%rip),%xmm4
  movapd %xmm5,%xmm0
  movapd %xmm5,%xmm1
  movapd %xmm6,%xmm2
  addsd  %xmm6,%xmm0
  movapd %xmm7,%xmm3
  addsd  %xmm7,%xmm0
  divsd  D17(%rip),%xmm0
  subsd  %xmm0,%xmm1
  subsd  %xmm0,%xmm2
  subsd  %xmm0,%xmm3
  andpd  %xmm4,%xmm1
  andpd  %xmm4,%xmm2
  andpd  %xmm4,%xmm3
  comisd %xmm1,%xmm2
  movapd %xmm3,%xmm0
  jbe    L3
  comisd %xmm1,%xmm3
  ja     L27
L3:
  comisd %xmm2,%xmm1
  jbe    L53
  comisd %xmm2,%xmm0
  ja     L38
L53:
  comisd %xmm0,%xmm1
  ja     L81
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L81:
  comisd %xmm0,%xmm2
  jbe    L4
  movapd %xmm7,%xmm0
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L4
L27:
  movapd %xmm5,%xmm0
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L4
L38:
  movapd %xmm6,%xmm0
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L4
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D57
type_infered: string
name: parse_data
arguments: data_tag: D46
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: qword
name: parse_data
arguments: data_tag: D17
type_infered: byte[8]
name: parse_data
arguments: data_tag: D31
type_infered: string

tool: D57: Please enter 3 numbers separated by spaces > 

tool: D46: %lf%lf%lf

tool: D13: 9223372036854775807

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D31: %.0f is the median


assistant: ```c
int main() {
  double first, second, third;
  double median;
  double comp_fir, comp_sec, comp_thi;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%lf"
        "%lf"
        "%lf",
        &first, &second, &third);
  median = (first + second + third) / 3;
  comp_fir = fabs(first - median);
  comp_sec = fabs(second - median);
  comp_thi = fabs(third - median);
  if (comp_fir < comp_sec && comp_fir < comp_thi)
    printf("%.0f is the median\n", first);
  else if (comp_sec < comp_fir && comp_sec < comp_thi)
    printf("%.0f is the median\n", second);
  else if (comp_thi < comp_fir && comp_thi < comp_sec)
    printf("%.0f is the median\n", third);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D49(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdx
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm6
  movsd  0x10(%rsp),%xmm7
  movq   D27(%rip),%xmm4
  movapd %xmm5,%xmm0
  movapd %xmm5,%xmm1
  movapd %xmm6,%xmm2
  addsd  %xmm6,%xmm0
  movapd %xmm7,%xmm3
  addsd  %xmm7,%xmm0
  divsd  D40(%rip),%xmm0
  subsd  %xmm0,%xmm1
  subsd  %xmm0,%xmm2
  subsd  %xmm0,%xmm3
  andpd  %xmm4,%xmm1
  andpd  %xmm4,%xmm2
  andpd  %xmm4,%xmm3
  comisd %xmm1,%xmm2
  movapd %xmm3,%xmm0
  jbe    L30
  comisd %xmm1,%xmm3
  ja     L10
L30:
  comisd %xmm2,%xmm1
  jbe    L8
  comisd %xmm2,%xmm0
  ja     L1
L8:
  comisd %xmm0,%xmm1
  ja     L54
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L54:
  comisd %xmm0,%xmm2
  jbe    L48
  movapd %xmm7,%xmm0
  lea    D61(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L48
L10:
  movapd %xmm5,%xmm0
  lea    D61(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L48
L1:
  movapd %xmm6,%xmm0
  lea    D61(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L48
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D49
datatype: string
name: unpack_data
arguments: data_label: D58
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: qword
name: unpack_data
arguments: data_label: D40
datatype: byte[8]
name: unpack_data
arguments: data_label: D61
datatype: string

tool: D49: Please enter 3 numbers separated by spaces > 

tool: D58: %lf%lf%lf

tool: D27: 9223372036854775807

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D61: %.0f is the median


assistant: ```c
int main() {
  double first, second, third;
  double median;
  double comp_fir, comp_sec, comp_thi;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%lf"
        "%lf"
        "%lf",
        &first, &second, &third);
  median = (first + second + third) / 3;
  comp_fir = fabs(first - median);
  comp_sec = fabs(second - median);
  comp_thi = fabs(third - median);
  if (comp_fir < comp_sec && comp_fir < comp_thi)
    printf("%.0f is the median\n", first);
  else if (comp_sec < comp_fir && comp_sec < comp_thi)
    printf("%.0f is the median\n", second);
  else if (comp_thi < comp_fir && comp_thi < comp_sec)
    printf("%.0f is the median\n", third);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L48
L0:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L41:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L5
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L5:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L41
  subl   $0x1,-0x8(%rbp)
L48:
  cmpl   $0x0,-0x8(%rbp)
  jg     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubble_sort(int array[], size_t array_length) {
  for (int ordered_index = array_length - 1; ordered_index > 0; --ordered_index) {
    for (int element = 0; element < ordered_index; ++element) {
      if (array[element] < array[element + 1]) {
        swap(array + element, array + element + 1);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bubble_sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  lea    -0x1(%rsi),%r12d
  lea    0x4(%rdi),%r14
  test   %r12d,%r12d
  jg     L63
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L55:
  cmp    %rbx,%rbp
  je     L40
L37:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L55
  mov    %rbx,%rsi
  call   <swap@plt>
  jmp    L55
L40:
  sub    $0x1,%r12d
  je     L49
L63:
  test   %r12d,%r12d
  jle    L40
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    (%r14,%rax,4),%rbp
  jmp    L37
```

assistant: ```c
void bubble_sort(int array[], size_t array_length) {
  for (int ordered_index = array_length - 1; ordered_index > 0; --ordered_index) {
    for (int element = 0; element < ordered_index; ++element) {
      if (array[element] < array[element + 1]) {
        swap(array + element, array + element + 1);
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort>:
  endbr64
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r12d,%r12d
  jle    L29
  mov    %rdi,%r13
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rbx
  xor    %ebp,%ebp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jle    L54
L9:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L23
  mov    %rbx,%rsi
  add    $0x1,%ebp
  call   <swap@plt>
  cmp    %ebp,%r12d
  jg     L9
L54:
  sub    $0x1,%r12d
  jne    L19
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bubble_sort(int array[], size_t array_length) {
  for (int ordered_index = array_length - 1; ordered_index > 0; --ordered_index) {
    for (int element = 0; element < ordered_index; ++element) {
      if (array[element] < array[element + 1]) {
        swap(array + element, array + element + 1);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bubble_sort>:
  endbr64
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %r12d,%r12d
  jle    L16
  mov    %rdi,%r13
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rbx
  xor    %ebp,%ebp
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jle    L57
L30:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  mov    0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L8
  mov    %rbx,%rsi
  add    $0x1,%ebp
  call   <swap@plt>
  cmp    %ebp,%r12d
  jg     L30
L57:
  sub    $0x1,%r12d
  jne    L28
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bubble_sort(int array[], size_t array_length) {
  for (int ordered_index = array_length - 1; ordered_index > 0; --ordered_index) {
    for (int element = 0; element < ordered_index; ++element) {
      if (array[element] < array[element + 1]) {
        swap(array + element, array + element + 1);
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_strings_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
L30:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L113
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L113
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L71
L113:
  mov    $0x0,%eax
  jmp    L136
L71:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L58
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L106
L58:
  addl   $0x1,-0x24(%rbp)
  jmp    L30
L106:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  je     L7
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L7
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L7
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L129
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x24(%rbp),%eax
  jmp    L136
L129:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x24(%rbp)
  jmp    L106
L136:
  pop    %rbp
  ret
```

assistant: ```c
int get_next_strings_ptr(char buf[], char str[], int ptr) {
  int p = 0;
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n')
      return 0;
    else if (buf[ptr] == ' ' || buf[ptr] == '\t')
      ptr++;
    else
      break;
  }
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n' || buf[ptr] == ' ' || buf[ptr] == '\t') {
      str[p] = '\0';
      return (ptr);
    } else {
      str[p] = buf[ptr];
      p++, ptr++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_next_strings_ptr>:
  endbr64
  mov    %rsi,%r8
  movslq %edx,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    $0x3b,%al
  ja     L107
  movabs $0x800000000000401,%rcx
  bt     %rax,%rcx
  jb     L133
L107:
  movabs $0x800000000000401,%rsi
  jmp    L115
L4:
  movslq %edx,%rax
  add    %rax,%rdi
  movzbl (%rdi),%esi
  cmp    $0x3b,%sil
  ja     L111
  mov    $0x1,%eax
  movabs $0x800000100000601,%r9
  bt     %rsi,%r9
  jae    L61
  mov    $0x0,%r9d
  jmp    L148
L111:
  mov    $0x1,%eax
L61:
  movabs $0x800000100000601,%r10
  jmp    L15
L133:
  mov    $0x0,%ecx
  jmp    L55
L45:
  add    $0x1,%rdx
L115:
  mov    %edx,%ecx
  cmp    $0x20,%al
  je     L72
  cmp    $0x9,%al
  jne    L4
L72:
  movzbl 0x1(%rdi,%rdx,1),%eax
  cmp    $0x3b,%al
  ja     L45
  add    $0x1,%rdx
  bt     %rax,%rsi
  jae    L115
  mov    $0x0,%ecx
L55:
  mov    %ecx,%eax
  ret
L145:
  add    $0x1,%rax
L15:
  mov    %sil,-0x1(%r8,%rax,1)
  mov    %eax,%r9d
  lea    (%rdx,%rax,1),%ecx
  movzbl (%rdi,%rax,1),%esi
  cmp    $0x3b,%sil
  ja     L145
  add    $0x1,%rax
  bt     %rsi,%r10
  jae    L15
L148:
  movslq %r9d,%r9
  movb   $0x0,(%r8,%r9,1)
  jmp    L55
```

assistant: ```c
int get_next_strings_ptr(char buf[], char str[], int ptr) {
  int p = 0;
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n')
      return 0;
    else if (buf[ptr] == ' ' || buf[ptr] == '\t')
      ptr++;
    else
      break;
  }
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n' || buf[ptr] == ' ' || buf[ptr] == '\t') {
      str[p] = '\0';
      return (ptr);
    } else {
      str[p] = buf[ptr];
      p++, ptr++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_next_strings_ptr>:
  endbr64
  movslq %edx,%rcx
  mov    %rsi,%r9
  movzbl (%rdi,%rcx,1),%esi
  mov    %rcx,%rax
  cmp    $0x3b,%sil
  jbe    L151
L18:
  add    %rax,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L144
  cmp    $0x3b,%cl
  je     L144
  mov    %edx,%eax
  mov    %r9,%rsi
  mov    $0x1,%edx
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L143:
  cmp    $0x8,%cl
  jg     L78
L140:
  mov    %cl,(%rsi)
  movzbl (%rdi,%rdx,1),%ecx
  movslq %edx,%r8
  add    $0x1,%eax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    $0x3b,%cl
  je     L28
  test   %cl,%cl
  je     L28
L88:
  mov    %rsi,%r8
  cmp    $0xa,%cl
  jle    L143
  cmp    $0x20,%cl
  jne    L140
L78:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L151:
  movabs $0xf7fffffffffffbfe,%r8
  xor    %eax,%eax
  bt     %rsi,%r8
  jae    L14
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %ecx,%edx
  cmp    $0x20,%sil
  je     L53
  cmp    $0x9,%sil
  jne    L108
L53:
  movzbl 0x1(%rdi,%rcx,1),%esi
  add    $0x1,%rcx
  cmp    $0x3b,%sil
  ja     L64
  bt     %rsi,%r8
  jb     L64
  xor    %eax,%eax
L14:
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  add    %r9,%r8
  movb   $0x0,(%r8)
  ret
L144:
  mov    %r9,%r8
  mov    %edx,%eax
  jmp    L78
L108:
  movslq %ecx,%rax
  jmp    L18
```

assistant: ```c
int get_next_strings_ptr(char buf[], char str[], int ptr) {
  int p = 0;
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n')
      return 0;
    else if (buf[ptr] == ' ' || buf[ptr] == '\t')
      ptr++;
    else
      break;
  }
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n' || buf[ptr] == ' ' || buf[ptr] == '\t') {
      str[p] = '\0';
      return (ptr);
    } else {
      str[p] = buf[ptr];
      p++, ptr++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_next_strings_ptr>:
  endbr64
  mov    %rsi,%r9
  movslq %edx,%rsi
  movzbl (%rdi,%rsi,1),%ecx
  cmp    $0x3b,%cl
  jbe    L135
L74:
  test   %cl,%cl
  je     L26
  cmp    $0x3b,%cl
  je     L26
  movslq %edx,%r8
  mov    %r9,%rsi
  mov    $0x1,%edx
  mov    %r8,%rax
  add    %r8,%rdi
  jmp    L108
  nopw   0x0(%rax,%rax,1)
L137:
  cmp    $0x8,%cl
  jg     L56
L77:
  mov    %cl,(%rsi)
  movzbl (%rdi,%rdx,1),%ecx
  movslq %edx,%r8
  add    $0x1,%eax
  add    $0x1,%rdx
  add    $0x1,%rsi
  cmp    $0x3b,%cl
  je     L46
  test   %cl,%cl
  je     L46
L108:
  mov    %rsi,%r8
  cmp    $0xa,%cl
  jle    L137
  cmp    $0x20,%cl
  jne    L77
L56:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L135:
  movabs $0xf7fffffffffffbfe,%r8
  xor    %eax,%eax
  bt     %rcx,%r8
  jae    L138
  nopw   0x0(%rax,%rax,1)
L143:
  mov    %esi,%edx
  cmp    $0x20,%cl
  je     L17
  cmp    $0x9,%cl
  jne    L74
L17:
  movzbl 0x1(%rdi,%rsi,1),%ecx
  add    $0x1,%rsi
  cmp    $0x3b,%cl
  ja     L143
  bt     %rcx,%r8
  jb     L143
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L138:
  ret
  nopl   0x0(%rax)
L46:
  add    %r9,%r8
  movb   $0x0,(%r8)
  ret
L26:
  mov    %r9,%r8
  mov    %edx,%eax
  jmp    L56
```

assistant: ```c
int get_next_strings_ptr(char buf[], char str[], int ptr) {
  int p = 0;
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n')
      return 0;
    else if (buf[ptr] == ' ' || buf[ptr] == '\t')
      ptr++;
    else
      break;
  }
  while (1) {
    if (buf[ptr] == ';' || buf[ptr] == '\0' || buf[ptr] == '\n' || buf[ptr] == ' ' || buf[ptr] == '\t') {
      str[p] = '\0';
      return (ptr);
    } else {
      str[p] = buf[ptr];
      p++, ptr++;
    }
  }
}
```