ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<SetCOMHWConfig>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2da,%eax
  mov    %ax,0x6(%rsp)
  test   %dil,%dil
  je     L6
  movb   $0x12,0x7(%rsp)
L6:
  lea    0x6(%rsp),%rdi
  mov    $0x2,%esi
  call   <oled_SendCommand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SetCOMHWConfig(char x) {
  unsigned char d[] = {0xDA, 0x02};
  if (x)
    d[1] |= 0x10;
  oled_SendCommand(d, sizeof(d));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x2,-0x20(%rbp)
  jmp    L65
L55:
  mov    -0x20(%rbp),%rax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6e,(%rax)
  addq   $0x1,-0x20(%rbp)
L65:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L55
  movq   $0x2,-0x20(%rbp)
  jmp    L69
L56:
  mov    -0x20(%rbp),%rax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6e,%al
  jne    L6
  mov    -0x20(%rbp),%rax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L39
L36:
  mov    -0x18(%rbp),%rax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6a,(%rax)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L36
L6:
  addq   $0x1,-0x20(%rbp)
L69:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L56
  mov    -0x28(%rbp),%rax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D1
type: string

tool: D0: %d ,

tool: D1: 
Es wurden %d Primzahlen berechnet

assistant: ```c
int main(int argc, char *argv[]) {
  char *gestrichen = malloc(atoi(argv[1]) * 8);
  long cou = (long)atoi(argv[1]);
  long cnt = 0;
  long i;
  for (i = 2; i < cou; i++) {
    gestrichen[(int)i] = 'n';
  }
  for (i = 2; i < cou; i++) {
    if (gestrichen[(int)i] == 'n') {
      printf("%d ,", (int)i);
      cnt++;
      long j;
      for (j = i * i; j < cou; j += i) {
        gestrichen[(int)j] = 'j';
      }
    }
  }
  printf("\nEs wurden %d Primzahlen berechnet", (int)cnt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L46
  movslq %eax,%rdx
  mov    $0x2,%ebx
L83:
  movslq %ebx,%rax
  movb   $0x6e,(%r12,%rax,1)
  mov    %rbx,%r13
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  jne    L83
  mov    $0x2,%ebp
  mov    $0x0,%r14d
  lea    D13(%rip),%r15
  jmp    L19
L2:
  mov    %rax,%rbp
L19:
  mov    %ebp,%esi
  movslq %ebp,%rax
  cmpb   $0x6e,(%r12,%rax,1)
  je     L35
L1:
  lea    0x1(%rbp),%rax
  cmp    %rbp,%r13
  jne    L2
L50:
  mov    %r14d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%r14
  mov    %rbp,%rax
  imul   %rbp,%rax
  cmp    %rbx,%rax
  jge    L1
L51:
  movslq %eax,%rdx
  movb   $0x6a,(%r12,%rdx,1)
  add    %rbp,%rax
  cmp    %rbx,%rax
  jl     L51
  jmp    L1
L46:
  mov    $0x0,%r14d
  jmp    L50
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D13: %d ,

tool: D9: 
Es wurden %d Primzahlen berechnet

assistant: ```c
int main(int argc, char *argv[]) {
  char *gestrichen = malloc(atoi(argv[1]) * 8);
  long cou = (long)atoi(argv[1]);
  long cnt = 0;
  long i;
  for (i = 2; i < cou; i++) {
    gestrichen[(int)i] = 'n';
  }
  for (i = 2; i < cou; i++) {
    if (gestrichen[(int)i] == 'n') {
      printf("%d ,", (int)i);
      cnt++;
      long j;
      for (j = i * i; j < cou; j += i) {
        gestrichen[(int)j] = 'j';
      }
    }
  }
  printf("\nEs wurden %d Primzahlen berechnet", (int)cnt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x8(%rbx),%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L66
  movslq %eax,%r12
  lea    0x2(%rbp),%rdi
  mov    $0x6e,%esi
  xor    %r13d,%r13d
  lea    -0x2(%r12),%rdx
  mov    $0x2,%ebx
  lea    D17(%rip),%r14
  call   <memset@plt>
  xchg   %ax,%ax
L54:
  cmpb   $0x6e,0x0(%rbp,%rbx,1)
  je     L28
L39:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L54
L65:
  mov    %r13d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%esi
  mov    %r14,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  mov    %rbx,%rax
  imul   %rbx,%rax
  cmp    %rax,%r12
  jle    L39
  nopw   0x0(%rax,%rax,1)
L57:
  movb   $0x6a,0x0(%rbp,%rax,1)
  add    %rbx,%rax
  cmp    %rax,%r12
  jg     L57
  jmp    L39
L66:
  xor    %r13d,%r13d
  jmp    L65
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string

tool: D17: %d ,

tool: D12: 
Es wurden %d Primzahlen berechnet

assistant: ```c
int main(int argc, char *argv[]) {
  char *gestrichen = malloc(atoi(argv[1]) * 8);
  long cou = (long)atoi(argv[1]);
  long cnt = 0;
  long i;
  for (i = 2; i < cou; i++) {
    gestrichen[(int)i] = 'n';
  }
  for (i = 2; i < cou; i++) {
    if (gestrichen[(int)i] == 'n') {
      printf("%d ,", (int)i);
      cnt++;
      long j;
      for (j = i * i; j < cou; j += i) {
        gestrichen[(int)j] = 'j';
      }
    }
  }
  printf("\nEs wurden %d Primzahlen berechnet", (int)cnt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x8(%rbx),%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L65
  movslq %eax,%r12
  lea    0x2(%rbp),%rdi
  mov    $0x6e,%esi
  xor    %r13d,%r13d
  lea    -0x2(%r12),%rdx
  mov    $0x2,%ebx
  lea    D3(%rip),%r14
  call   <memset@plt>
  xchg   %ax,%ax
L16:
  cmpb   $0x6e,0x0(%rbp,%rbx,1)
  je     L53
L67:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L16
L57:
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %ebx,%esi
  mov    %r14,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  mov    %rbx,%rax
  imul   %rbx,%rax
  cmp    %rax,%r12
  jle    L67
  nopw   0x0(%rax,%rax,1)
L37:
  movb   $0x6a,0x0(%rbp,%rax,1)
  add    %rbx,%rax
  cmp    %rax,%r12
  jg     L37
  jmp    L67
L65:
  xor    %r13d,%r13d
  jmp    L57
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D3: %d ,

tool: D18: 
Es wurden %d Primzahlen berechnet

assistant: ```c
int main(int argc, char *argv[]) {
  char *gestrichen = malloc(atoi(argv[1]) * 8);
  long cou = (long)atoi(argv[1]);
  long cnt = 0;
  long i;
  for (i = 2; i < cou; i++) {
    gestrichen[(int)i] = 'n';
  }
  for (i = 2; i < cou; i++) {
    if (gestrichen[(int)i] == 'n') {
      printf("%d ,", (int)i);
      cnt++;
      long j;
      for (j = i * i; j < cou; j += i) {
        gestrichen[(int)j] = 'j';
      }
    }
  }
  printf("\nEs wurden %d Primzahlen berechnet", (int)cnt);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hmap_is_member_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <hmap_find_member_int@plt>
  test   %rax,%rax
  je     L13
  mov    $0x1,%eax
  jmp    L6
L13:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int hmap_is_member_int(const struct hash_map *ht, unsigned int key) {
  if (hmap_find_member_int(ht, key))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hmap_is_member_int>:
  endbr64
  sub    $0x8,%rsp
  call   <hmap_find_member_int@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int hmap_is_member_int(const struct hash_map *ht, unsigned int key) {
  if (hmap_find_member_int(ht, key))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hmap_is_member_int>:
  endbr64
  sub    $0x8,%rsp
  call   <hmap_find_member_int@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int hmap_is_member_int(const struct hash_map *ht, unsigned int key) {
  if (hmap_find_member_int(ht, key))
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hmap_is_member_int>:
  endbr64
  sub    $0x8,%rsp
  call   <hmap_find_member_int@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int hmap_is_member_int(const struct hash_map *ht, unsigned int key) {
  if (hmap_find_member_int(ht, key))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
L65:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jg     L7
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jle    L65
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L51:
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L84:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L84
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L47
L33:
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L33
  subl   $0x1,-0x18(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L51
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D32
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D45
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D3: n=

tool: D32: %d

tool: D8: n must be >1!


tool: D24:  

tool: D45: ^

tool: D21: 


assistant: ```c
int main() {
  int n, space, counter1, counter2, arrows = 1;
  do {
    printf("n=");
    scanf("%d", &n);
    if (n < 2)
      printf("n must be >1!\n");
  } while (n < 2);
  space = n;
  for (counter1 = 0; counter1 <= n; counter1++) {
    for (counter2 = 0; counter2 != space; counter2++)
      printf(" ");
    arrows = counter1 * 2 - 1;
    for (counter2 = 0; counter2 < arrows; counter2++)
      printf("^");
    space--;
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%r12
  lea    0x14(%rsp),%rbp
  lea    D9(%rip),%rbx
  lea    D43(%rip),%r13
  jmp    L95
L62:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%r15d
  cmp    $0x1,%r15d
  jg     L6
L95:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%r15d
  cmp    $0x1,%r15d
  jle    L62
L6:
  mov    %r15d,%ebp
  movl   $0xffffffff,0xc(%rsp)
  lea    D22(%rip),%r14
  lea    D32(%rip),%r13
  jmp    L104
L37:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L37
L58:
  mov    0xc(%rsp),%eax
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L9
  mov    $0x0,%ebx
L70:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L70
L9:
  sub    $0x1,%ebp
  lea    D21(%rip),%rdi
  call   <printf@plt>
  addl   $0x2,0xc(%rsp)
  mov    %r15d,%eax
  sub    %ebp,%eax
  cmp    %eax,0x14(%rsp)
  jl     L109
L104:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jne    L37
  jmp    L58
L109:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D43
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string

tool: D20: n=

tool: D9: %d

tool: D43: n must be >1!


tool: D22:  

tool: D32: ^

tool: D21: 


assistant: ```c
int main() {
  int n, space, counter1, counter2, arrows = 1;
  do {
    printf("n=");
    scanf("%d", &n);
    if (n < 2)
      printf("n must be >1!\n");
  } while (n < 2);
  space = n;
  for (counter1 = 0; counter1 <= n; counter1++) {
    for (counter2 = 0; counter2 != space; counter2++)
      printf(" ");
    arrows = counter1 * 2 - 1;
    for (counter2 = 0; counter2 < arrows; counter2++)
      printf("^");
    space--;
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D31(%rip),%r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D44(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L79:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r14d
  cmp    $0x1,%r14d
  jle    L46
L4:
  mov    %r14d,%ebx
  mov    $0xffffffff,%ebp
  lea    D56(%rip),%r13
  lea    D50(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %r15d,%r15d
  test   %ebx,%ebx
  je     L52
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebx,%r15d
  jne    L49
L52:
  xor    %r15d,%r15d
  test   %ebp,%ebp
  jle    L83
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jne    L74
L83:
  lea    D37(%rip),%rdi
  sub    $0x1,%ebx
  add    $0x2,%ebp
  call   <printf@plt>
  mov    %r14d,%eax
  sub    %ebx,%eax
  cmp    %eax,0x4(%rsp)
  jge    L44
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L46:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  cmp    $0x1,%r14d
  jle    L79
  jmp    L4
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D56
type_guessed: string
name: extract_symbolic_data
arguments: label: D50
type_guessed: string
name: extract_symbolic_data
arguments: label: D37
type_guessed: string

tool: D31: n must be >1!


tool: D27: n=

tool: D44: %d

tool: D56:  

tool: D50: ^

tool: D37: 


assistant: ```c
int main() {
  int n, space, counter1, counter2, arrows = 1;
  do {
    printf("n=");
    scanf("%d", &n);
    if (n < 2)
      printf("n must be >1!\n");
  } while (n < 2);
  space = n;
  for (counter1 = 0; counter1 <= n; counter1++) {
    for (counter2 = 0; counter2 != space; counter2++)
      printf(" ");
    arrows = counter1 * 2 - 1;
    for (counter2 = 0; counter2 < arrows; counter2++)
      printf("^");
    space--;
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D38(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L22:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r14d
  cmp    $0x1,%r14d
  jle    L71
L5:
  mov    %r14d,%ebx
  mov    $0xffffffff,%ebp
  lea    D36(%rip),%r13
  lea    D37(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %r15d,%r15d
  test   %ebx,%ebx
  je     L44
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %r13,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebx,%r15d
  jne    L67
L44:
  xor    %r15d,%r15d
  test   %ebp,%ebp
  jle    L25
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %ebp,%r15d
  jne    L55
L25:
  lea    D46(%rip),%rdi
  sub    $0x1,%ebx
  add    $0x2,%ebp
  call   <printf@plt>
  mov    %r14d,%eax
  sub    %ebx,%eax
  cmp    %eax,0x4(%rsp)
  jge    L38
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L71:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%r14d
  cmp    $0x1,%r14d
  jle    L22
  jmp    L5
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D36
type: string
name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D46
type: string

tool: D2: n must be >1!


tool: D8: n=

tool: D38: %d

tool: D36:  

tool: D37: ^

tool: D46: 


assistant: ```c
int main() {
  int n, space, counter1, counter2, arrows = 1;
  do {
    printf("n=");
    scanf("%d", &n);
    if (n < 2)
      printf("n must be >1!\n");
  } while (n < 2);
  space = n;
  for (counter1 = 0; counter1 <= n; counter1++) {
    for (counter2 = 0; counter2 != space; counter2++)
      printf(" ");
    arrows = counter1 * 2 - 1;
    for (counter2 = 0; counter2 < arrows; counter2++)
      printf("^");
    space--;
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_empty_pos_since>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L48
L99:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L26
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L62:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x30,%al
  je     L57
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x8,-0x8(%rbp)
  jle    L62
  addl   $0x1,-0x4(%rbp)
L48:
  cmpl   $0x8,-0x4(%rbp)
  jle    L99
  jmp    L82
L57:
  nop
L82:
  cmpl   $0x8,-0x8(%rbp)
  jg     L11
  cmpl   $0x8,-0x4(%rbp)
  jg     L11
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L76
L11:
  mov    $0x0,%eax
L76:
  pop    %rbp
  ret
```

assistant: ```c
int find_empty_pos_since(char board[][11], int *row, int *col) {
  int x = *col, y = *row;
  for (; y < 9; ++y) {
    if (y > *row)
      x = 0;
    for (; x < 9; ++x)
      if (board[y][x] == '0')
        goto found;
  }
found:;
  if (x < 9 && y < 9) {
    *row = y;
    *col = x;
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_empty_pos_since>:
  endbr64
  mov    (%rdx),%ecx
  mov    (%rsi),%r9d
  cmp    $0x8,%r9d
  jg     L21
  movslq %r9d,%rax
  lea    (%rax,%rax,4),%r8
  lea    (%rax,%r8,2),%rax
  add    %rax,%rdi
  mov    %r9d,%r8d
L23:
  cmp    %r8d,%r9d
  jge    L37
  mov    $0x0,%ecx
L66:
  movslq %ecx,%rax
  add    %rdi,%rax
L65:
  cmpb   $0x30,(%rax)
  je     L61
  add    $0x1,%ecx
  add    $0x1,%rax
  cmp    $0x8,%ecx
  jle    L65
L5:
  add    $0x1,%r8d
  add    $0xb,%rdi
  cmp    $0x9,%r8d
  jne    L23
  mov    $0x0,%eax
  ret
L37:
  cmp    $0x8,%ecx
  jle    L66
  jmp    L5
L61:
  cmp    $0x8,%ecx
  jg     L29
  cmp    $0x8,%r8d
  jg     L29
  mov    %r8d,(%rsi)
  mov    %ecx,(%rdx)
  mov    $0x1,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
L29:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int find_empty_pos_since(char board[][11], int *row, int *col) {
  int x = *col, y = *row;
  for (; y < 9; ++y) {
    if (y > *row)
      x = 0;
    for (; x < 9; ++x)
      if (board[y][x] == '0')
        goto found;
  }
found:;
  if (x < 9 && y < 9) {
    *row = y;
    *col = x;
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_empty_pos_since>:
  endbr64
  mov    (%rsi),%r9d
  mov    (%rdx),%ecx
  cmp    $0x8,%r9d
  jg     L2
  movslq %r9d,%rax
  lea    (%rax,%rax,4),%r8
  lea    (%rax,%r8,2),%rax
  mov    %r9d,%r8d
  add    %rax,%rdi
L14:
  cmp    %r8d,%r9d
  jge    L61
  xor    %ecx,%ecx
L22:
  movslq %ecx,%rax
  add    %rdi,%rax
  jmp    L11
  nop
L10:
  add    $0x1,%ecx
  add    $0x1,%rax
  cmp    $0x9,%ecx
  je     L38
L11:
  cmpb   $0x30,(%rax)
  jne    L10
  mov    %r8d,(%rsi)
  mov    $0x1,%eax
  mov    %ecx,(%rdx)
  ret
  nopl   0x0(%rax)
L61:
  cmp    $0x8,%ecx
  jle    L22
  nopl   (%rax)
L38:
  add    $0x1,%r8d
  add    $0xb,%rdi
  cmp    $0x9,%r8d
  jne    L14
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int find_empty_pos_since(char board[][11], int *row, int *col) {
  int x = *col, y = *row;
  for (; y < 9; ++y) {
    if (y > *row)
      x = 0;
    for (; x < 9; ++x)
      if (board[y][x] == '0')
        goto found;
  }
found:;
  if (x < 9 && y < 9) {
    *row = y;
    *col = x;
    return 1;
  }
  return 0;
}
```