ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crStrncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L6
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  jmp    L34
L6:
  nop
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L71
  mov    $0x0,%eax
  jmp    L55
L71:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int crStrncmp(const char *str1, const char *str2, int n) {
  int i = 0;
  while (*str1 && *str2 && i < n) {
    if (*str1 != *str2) {
      break;
    }
    str1++;
    str2++;
    i++;
  }
  if (i == n)
    return 0;
  return (*str1 - *str2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<crStrncmp>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rcx
  mov    %edx,%r9d
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L7
  movzbl (%rcx),%eax
  test   %edx,%edx
  setg   %dil
  test   %al,%al
  setne  %dl
  test   %dl,%dil
  je     L9
  cmp    %al,%sil
  jne    L9
  mov    $0x1,%edx
L22:
  add    $0x1,%rcx
  mov    %edx,%r11d
  movzbl (%r10,%rdx,1),%esi
  test   %sil,%sil
  je     L5
  movzbl (%rcx),%edi
  cmp    %edx,%r9d
  setg   %al
  test   %dil,%dil
  setne  %r8b
  and    %r8d,%eax
  xor    $0x1,%eax
  cmp    %dil,%sil
  setne  %dil
  add    $0x1,%rdx
  or     %dil,%al
  je     L22
L5:
  mov    $0x0,%eax
  cmp    %r11d,%r9d
  je     L79
  movsbl %sil,%eax
  movsbl (%rcx),%edx
  sub    %edx,%eax
L79:
  ret
L7:
  mov    $0x0,%r11d
  jmp    L5
L9:
  mov    $0x0,%r11d
  jmp    L5
```

assistant: ```c
int crStrncmp(const char *str1, const char *str2, int n) {
  int i = 0;
  while (*str1 && *str2 && i < n) {
    if (*str1 != *str2) {
      break;
    }
    str1++;
    str2++;
    i++;
  }
  if (i == n)
    return 0;
  return (*str1 - *str2);
}
```
user: What is the c source code of the assembly code below:

```asm
<crStrncmp>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L86
  movzbl (%rsi),%eax
  xor    %r8d,%r8d
  test   %edx,%edx
  jg     L89
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L88:
  cmp    %al,%cl
  jne    L87
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  add    $0x1,%rsi
  add    $0x1,%r8d
  test   %cl,%cl
  je     L21
  movzbl (%rsi),%eax
  cmp    %r8d,%edx
  jle    L21
L89:
  test   %al,%al
  jne    L88
L21:
  xor    %eax,%eax
  cmp    %r8d,%edx
  je     L33
L87:
  movsbl (%rsi),%edx
  movsbl %cl,%eax
  sub    %edx,%eax
L33:
  ret
L86:
  xor    %r8d,%r8d
  jmp    L21
```

assistant: ```c
int crStrncmp(const char *str1, const char *str2, int n) {
  int i = 0;
  while (*str1 && *str2 && i < n) {
    if (*str1 != *str2) {
      break;
    }
    str1++;
    str2++;
    i++;
  }
  if (i == n)
    return 0;
  return (*str1 - *str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crStrncmp>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L22
  movsbl (%rsi),%ecx
  test   %edx,%edx
  jle    L22
  test   %cl,%cl
  je     L22
  mov    $0x1,%eax
  nopl   (%rax)
L38:
  cmp    %cl,%r8b
  jne    L36
  movzbl (%rdi,%rax,1),%r8d
  add    $0x1,%rsi
  mov    %eax,%r11d
  test   %r8b,%r8b
  je     L29
  movsbl (%rsi),%ecx
  cmp    %eax,%edx
  setg   %r10b
  test   %cl,%cl
  setne  %r9b
  add    $0x1,%rax
  test   %r9b,%r10b
  jne    L38
L29:
  xor    %eax,%eax
  cmp    %r11d,%edx
  je     L69
  movsbl (%rsi),%ecx
L36:
  movsbl %r8b,%eax
  sub    %ecx,%eax
L69:
  ret
L22:
  xor    %r11d,%r11d
  jmp    L29
```

assistant: ```c
int crStrncmp(const char *str1, const char *str2, int n) {
  int i = 0;
  while (*str1 && *str2 && i < n) {
    if (*str1 != *str2) {
      break;
    }
    str1++;
    str2++;
    i++;
  }
  if (i == n)
    return 0;
  return (*str1 - *str2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<st_getbytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  jmp    L13
L10:
  movl   $0x4,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  cmp    $0x1,%eax
  je     L16
  mov    $0xffffffff,%eax
  jmp    L63
L16:
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L50
  mov    $0xffffffff,%eax
  jmp    L63
L50:
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x28(%rbp)
L13:
  cmpl   $0x0,-0x28(%rbp)
  jne    L10
  mov    $0x0,%eax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
int st_getbytes(int devfd, char *buf, int len) {
  fd_set s;
  struct timeval tv;
  int ret;
  FD_ZERO(&s);
  FD_SET(devfd, &s);
  while (len) {
    tv.tv_sec = 4000000 / 1000000;
    tv.tv_usec = 4000000 % 1000000;
    if (select(devfd + 1, &s, NULL, NULL, &tv) != 1)
      return -1;
    ret = read(devfd, buf, len);
    if (ret <= 0)
      return -1;
    len -= ret;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st_getbytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  mov    %r13,%rdi
  call   <FD_ZERO@plt>
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  test   %ebx,%ebx
  je     L63
  lea    0x10(%rsp),%r13
L22:
  movl   $0x4,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x1(%rbp),%edi
  mov    %r13,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <select@plt>
  cmp    $0x1,%eax
  jne    L75
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L71
  sub    %eax,%ebx
  jne    L22
  mov    %ebx,%eax
  jmp    L67
L63:
  mov    %ebx,%eax
  jmp    L67
L75:
  mov    $0xffffffff,%eax
L67:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    $0xffffffff,%eax
  jmp    L67
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int st_getbytes(int devfd, char *buf, int len) {
  fd_set s;
  struct timeval tv;
  int ret;
  FD_ZERO(&s);
  FD_SET(devfd, &s);
  while (len) {
    tv.tv_sec = 4000000 / 1000000;
    tv.tv_usec = 4000000 % 1000000;
    if (select(devfd + 1, &s, NULL, NULL, &tv) != 1)
      return -1;
    ret = read(devfd, buf, len);
    if (ret <= 0)
      return -1;
    len -= ret;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st_getbytes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  lea    0x1(%rbp),%r15d
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%r14
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  test   %ebx,%ebx
  jne    L26
  jmp    L28
  nop
L62:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L68
  sub    %eax,%ebx
  je     L28
L26:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r14,%r8
  mov    %r12,%rsi
  movq   $0x4,0x10(%rsp)
  mov    %r15d,%edi
  call   <select@plt>
  cmp    $0x1,%eax
  je     L62
L68:
  mov    $0xffffffff,%eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  jmp    L14
L60:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int st_getbytes(int devfd, char *buf, int len) {
  fd_set s;
  struct timeval tv;
  int ret;
  FD_ZERO(&s);
  FD_SET(devfd, &s);
  while (len) {
    tv.tv_sec = 4000000 / 1000000;
    tv.tv_usec = 4000000 % 1000000;
    if (select(devfd + 1, &s, NULL, NULL, &tv) != 1)
      return -1;
    ret = read(devfd, buf, len);
    if (ret <= 0)
      return -1;
    len -= ret;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<st_getbytes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  lea    0x1(%rbp),%r15d
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%r14
  mov    %r12,%rdi
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  test   %ebx,%ebx
  jne    L65
  jmp    L56
  nop
L48:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L25
  sub    %eax,%ebx
  je     L56
L65:
  mov    D2(%rip),%rax
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r14,%r8
  mov    %r12,%rsi
  mov    %r15d,%edi
  mov    %rax,0x10(%rsp)
  call   <select@plt>
  cmp    $0x1,%eax
  je     L48
L25:
  mov    $0xffffffff,%eax
L11:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  jmp    L11
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: byte[8]

tool: {"D2": [0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int st_getbytes(int devfd, char *buf, int len) {
  fd_set s;
  struct timeval tv;
  int ret;
  FD_ZERO(&s);
  FD_SET(devfd, &s);
  while (len) {
    tv.tv_sec = 4000000 / 1000000;
    tv.tv_usec = 4000000 % 1000000;
    if (select(devfd + 1, &s, NULL, NULL, &tv) != 1)
      return -1;
    ret = read(devfd, buf, len);
    if (ret <= 0)
      return -1;
    len -= ret;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<modules_worker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: in modules_worker!


assistant: ```c
int modules_worker(int argc, char *argv[]) {
  printf("in modules_worker!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<modules_worker>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: in modules_worker!


assistant: ```c
int modules_worker(int argc, char *argv[]) {
  printf("in modules_worker!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modules_worker>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: in modules_worker!


assistant: ```c
int modules_worker(int argc, char *argv[]) {
  printf("in modules_worker!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<modules_worker>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: in modules_worker!


assistant: ```c
int modules_worker(int argc, char *argv[]) {
  printf("in modules_worker!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L18
  movsd  -0x8(%rbp),%xmm0
  jmp    L5
L18:
  movsd  -0x10(%rbp),%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double min(double x, double y) {
  if (x <= y)
    return x;
  else
    return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<min>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double min(double x, double y) {
  if (x <= y)
    return x;
  else
    return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<min>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double min(double x, double y) {
  if (x <= y)
    return x;
  else
    return y;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<min>:
  endbr64
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm2,%xmm0
  ret
```

assistant: ```c
double min(double x, double y) {
  if (x <= y)
    return x;
  else
    return y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0xffffffff,%edi
  call   <send_byte@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <send_byte@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <send_byte@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L10
  mov    $0xffffffff,%edi
  call   <send_byte@plt>
  nop
  leave
  ret
```

assistant: ```c
void send_frame(unsigned char *frame, int size) {
  send_byte(-1);
  for (unsigned int i = 0; i < size; ++i) {
    send_byte(frame[i] & 0xF);
    send_byte(frame[i] >> 4);
  }
  send_byte(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_frame>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0xffffffff,%edi
  call   <send_byte@plt>
  test   %ebp,%ebp
  je     L13
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L16:
  movzbl (%rbx),%edi
  and    $0xf,%edi
  call   <send_byte@plt>
  movzbl (%rbx),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <send_byte@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
L13:
  mov    $0xffffffff,%edi
  call   <send_byte@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void send_frame(unsigned char *frame, int size) {
  send_byte(-1);
  for (unsigned int i = 0; i < size; ++i) {
    send_byte(frame[i] & 0xF);
    send_byte(frame[i] >> 4);
  }
  send_byte(-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_frame>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <send_byte@plt>
  test   %ebp,%ebp
  je     L4
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   (%rax)
L11:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  and    $0xf,%edi
  call   <send_byte@plt>
  movzbl -0x1(%rbx),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <send_byte@plt>
  cmp    %rbp,%rbx
  jne    L11
L4:
  add    $0x8,%rsp
  mov    $0xffffffff,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <send_byte@plt>
```

assistant: ```c
void send_frame(unsigned char *frame, int size) {
  send_byte(-1);
  for (unsigned int i = 0; i < size; ++i) {
    send_byte(frame[i] & 0xF);
    send_byte(frame[i] >> 4);
  }
  send_byte(-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_frame>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xffffffff,%edi
  sub    $0x8,%rsp
  call   <send_byte@plt>
  test   %ebp,%ebp
  je     L18
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   (%rax)
L0:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  and    $0xf,%edi
  call   <send_byte@plt>
  movzbl -0x1(%rbx),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <send_byte@plt>
  cmp    %rbp,%rbx
  jne    L0
L18:
  add    $0x8,%rsp
  mov    $0xffffffff,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <send_byte@plt>
```

assistant: ```c
void send_frame(unsigned char *frame, int size) {
  send_byte(-1);
  for (unsigned int i = 0; i < size; ++i) {
    send_byte(frame[i] & 0xF);
    send_byte(frame[i] >> 4);
  }
  send_byte(-1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SPIC_Read_Bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L17:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0xff,%edi
  call   <SPIC_Read@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  ja     L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void SPIC_Read_Bytes(char *buffer, unsigned NoBytes) {
  int i;
  for (i = 0; i < NoBytes; i++)
    buffer[i] = SPIC_Read(0xFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SPIC_Read_Bytes>:
  endbr64
  test   %esi,%esi
  je     L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L6:
  mov    $0xff,%edi
  call   <SPIC_Read@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void SPIC_Read_Bytes(char *buffer, unsigned NoBytes) {
  int i;
  for (i = 0; i < NoBytes; i++)
    buffer[i] = SPIC_Read(0xFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SPIC_Read_Bytes>:
  endbr64
  test   %esi,%esi
  je     L15
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    $0xff,%edi
  add    $0x1,%rbx
  call   <SPIC_Read@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L15:
  ret
```

assistant: ```c
void SPIC_Read_Bytes(char *buffer, unsigned NoBytes) {
  int i;
  for (i = 0; i < NoBytes; i++)
    buffer[i] = SPIC_Read(0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SPIC_Read_Bytes>:
  endbr64
  test   %esi,%esi
  je     L14
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    $0xff,%edi
  add    $0x1,%rbx
  call   <SPIC_Read@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L14:
  ret
```

assistant: ```c
void SPIC_Read_Bytes(char *buffer, unsigned NoBytes) {
  int i;
  for (i = 0; i < NoBytes; i++)
    buffer[i] = SPIC_Read(0xFF);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<temporizador>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x14(%rbp),%xmm0
  ja     L29
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L17
L14:
  mov    $0x0,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
L17:
  movss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  -0x4(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L14
  jmp    L18
L29:
  nop
L18:
  leave
  ret
```

assistant: ```c
void temporizador(float pausa) {
  if (pausa < 0.0)
    return;
  float tempoin = 0.0, tempofim = 0.0;
  tempoin = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  while ((tempofim - tempoin) < pausa) {
    tempofim = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  };
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<temporizador>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  movss  %xmm4,0x8(%rsp)
  comiss %xmm4,%xmm0
  ja     L17
  mov    $0x0,%eax
  call   <clock@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  mov    D5(%rip),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rax),%xmm0
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rsp)
  pxor   %xmm0,%xmm0
  subss  %xmm1,%xmm0
  movss  0x8(%rsp),%xmm4
  comiss %xmm0,%xmm4
  jbe    L17
L7:
  mov    $0x0,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    D5(%rip),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ssq (%rax),%xmm1
  divss  %xmm1,%xmm0
  subss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm3
  comiss %xmm0,%xmm3
  ja     L7
L17:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void temporizador(float pausa) {
  if (pausa < 0.0)
    return;
  float tempoin = 0.0, tempofim = 0.0;
  tempoin = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  while ((tempofim - tempoin) < pausa) {
    tempofim = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  };
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<temporizador>:
  endbr64
  push   %rbx
  pxor   %xmm5,%xmm5
  sub    $0x10,%rsp
  comiss %xmm0,%xmm5
  movss  %xmm0,0x8(%rsp)
  ja     L25
  xor    %eax,%eax
  call   <clock@plt>
  mov    D8(%rip),%rbx
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm1
  pxor   %xmm6,%xmm6
  movss  0x8(%rsp),%xmm4
  cvtsi2ssq (%rbx),%xmm0
  divss  %xmm0,%xmm1
  subss  %xmm1,%xmm6
  movss  %xmm1,0xc(%rsp)
  comiss %xmm6,%xmm4
  jbe    L25
  nopl   (%rax)
L12:
  xor    %eax,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm3
  cvtsi2ss %rax,%xmm0
  cvtsi2ssq (%rbx),%xmm1
  divss  %xmm1,%xmm0
  subss  0xc(%rsp),%xmm0
  comiss %xmm0,%xmm3
  ja     L12
L25:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void temporizador(float pausa) {
  if (pausa < 0.0)
    return;
  float tempoin = 0.0, tempofim = 0.0;
  tempoin = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  while ((tempofim - tempoin) < pausa) {
    tempofim = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  };
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<temporizador>:
  endbr64
  push   %rbx
  pxor   %xmm5,%xmm5
  sub    $0x10,%rsp
  comiss %xmm0,%xmm5
  movss  %xmm0,0x8(%rsp)
  ja     L16
  xor    %eax,%eax
  call   <clock@plt>
  mov    D7(%rip),%rbx
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm1
  pxor   %xmm6,%xmm6
  movss  0x8(%rsp),%xmm4
  cvtsi2ssq (%rbx),%xmm0
  divss  %xmm0,%xmm1
  subss  %xmm1,%xmm6
  movss  %xmm1,0xc(%rsp)
  comiss %xmm6,%xmm4
  jbe    L16
  nopl   (%rax)
L26:
  xor    %eax,%eax
  call   <clock@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movss  0x8(%rsp),%xmm3
  cvtsi2ss %rax,%xmm0
  cvtsi2ssq (%rbx),%xmm1
  divss  %xmm1,%xmm0
  subss  0xc(%rsp),%xmm0
  comiss %xmm0,%xmm3
  ja     L26
L16:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void temporizador(float pausa) {
  if (pausa < 0.0)
    return;
  float tempoin = 0.0, tempofim = 0.0;
  tempoin = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  while ((tempofim - tempoin) < pausa) {
    tempofim = ((float)clock()) / ((float)CLOCKS_PER_SEC);
  };
  return;
}
```