user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D117(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jne    L6
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L6
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L6
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L12
L6:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L46
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jne    L46
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L12
L46:
  lea    D125(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L12:
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D113
type: string
name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D50
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D117
type: string
name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D76
type: string
name: retrieve_data
arguments: data_label: D125
type: string
name: retrieve_data
arguments: data_label: D20
type: string

tool: D12: Digite o valor do lado 1: 

tool: D113: %d

tool: D10: Digite o valor do lado 2: 

tool: D50: Digite o valor do lado 3: 

tool: D15: Digite o valor do lado 4: 

tool: D117: Lado 1: %d
Lado 2: %d
Lado 3: %d
Lado 4: %d


tool: D6: Quadrado

tool: D76: Retangulo

tool: D125: Figura nao conhecida

tool: D20: pause

assistant: ```c
int main() {
  int l1, l2, l3, l4 = 0;
  printf("Digite o valor do lado 1: ");
  scanf("%d", &l1);
  printf("Digite o valor do lado 2: ");
  scanf("%d", &l2);
  printf("Digite o valor do lado 3: ");
  scanf("%d", &l3);
  printf("Digite o valor do lado 4: ");
  scanf("%d", &l4);
  printf("Lado 1: %d\nLado 2: %d\nLado 3: %d\nLado 4: %d\n", l1, l2, l3, l4);
  if (l1 == l2 && l2 == l3 && l3 == l4) {
    printf("Quadrado\n");
  } else if (l1 == l3 && l2 == l4) {
    printf("Retangulo\n");
  } else {
    printf("Figura nao conhecida\n");
  }
  system("pause");
  return 0;
}
```