ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<bm_save_palette>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L27
  mov    %rsi,%r13
  mov    %edx,%r12d
  lea    D47(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  test   %rbp,%rbp
  je     L27
  mov    %rbp,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rcx
  mov    $0x5,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <fwrite@plt>
  movzbl %r12b,%edx
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  test   %r12d,%r12d
  je     L22
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    0x4(%r13,%rax,4),%r13
  lea    D9(%rip),%r12
L30:
  lea    0x7(%rsp),%rcx
  lea    0x6(%rsp),%rdx
  lea    0x5(%rsp),%rsi
  mov    (%rbx),%edi
  call   <bm_get_rgb@plt>
  movzbl 0x6(%rsp),%ecx
  movzbl 0x5(%rsp),%edx
  movzbl 0x7(%rsp),%r8d
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L30
L22:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D47
type: string
name: parse_data
arguments: data_label: D5
type: string
name: parse_data
arguments: data_label: D16
type: string
name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D9
type: string

tool: D47: w

tool: D5: JASC-PAL


tool: D16: 0100


tool: D23: %u


tool: D9: %u %u %u


assistant: ```c
int bm_save_palette(const char *filename, unsigned int *pal, unsigned int npal) {
  unsigned i;
  FILE *f;
  if (!filename)
    return 0;
  f = fopen(filename, "w");
  if (!f)
    return 0;
  fputs("JASC-PAL\n", f);
  fputs("0100\n", f);
  fprintf(f, "%u\n", npal);
  for (i = 0; i < npal; i++) {
    unsigned char R, G, B;
    bm_get_rgb(pal[i], &R, &G, &B);
    fprintf(f, "%u %u %u\n", R, G, B);
  }
  fclose(f);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bm_save_palette>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L53
  mov    %rsi,%r15
  lea    D49(%rip),%rsi
  mov    %edx,%ebx
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L53
  mov    %rax,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D42(%rip),%rdi
  call   <fwrite@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbp,%rcx
  lea    D38(%rip),%rdi
  call   <fwrite@plt>
  xor    %eax,%eax
  movzbl %bl,%edx
  mov    %rbp,%rdi
  lea    D48(%rip),%rsi
  call   <fprintf@plt>
  test   %ebx,%ebx
  je     L17
  lea    -0x1(%rbx),%eax
  lea    0x17(%rsp),%r14
  lea    0x4(%r15,%rax,4),%rax
  lea    0x16(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    0x15(%rsp),%r12
  lea    D26(%rip),%rbx
  nopl   (%rax)
L10:
  mov    (%r15),%edi
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  add    $0x4,%r15
  call   <bm_get_rgb@plt>
  movzbl 0x16(%rsp),%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movzbl 0x15(%rsp),%edx
  movzbl 0x17(%rsp),%r8d
  xor    %eax,%eax
  call   <fprintf@plt>
  cmp    0x8(%rsp),%r15
  jne    L10
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L50
L53:
  xor    %eax,%eax
L50:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D49
type: string
name: read_data
arguments: label: D42
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D48
type: string
name: read_data
arguments: label: D26
type: string

tool: D49: w

tool: D42: JASC-PAL


tool: D38: 0100


tool: D48: %u


tool: D26: %u %u %u


assistant: ```c
int bm_save_palette(const char *filename, unsigned int *pal, unsigned int npal) {
  unsigned i;
  FILE *f;
  if (!filename)
    return 0;
  f = fopen(filename, "w");
  if (!f)
    return 0;
  fputs("JASC-PAL\n", f);
  fputs("0100\n", f);
  fprintf(f, "%u\n", npal);
  for (i = 0; i < npal; i++) {
    unsigned char R, G, B;
    bm_get_rgb(pal[i], &R, &G, &B);
    fprintf(f, "%u %u %u\n", R, G, B);
  }
  fclose(f);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bm_save_palette>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  mov    %rsi,%r15
  lea    D3(%rip),%rsi
  mov    %edx,%ebx
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  mov    %rax,%rcx
  mov    $0x9,%edx
  mov    $0x1,%esi
  lea    D47(%rip),%rdi
  call   <fwrite@plt>
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    %rbp,%rcx
  lea    D9(%rip),%rdi
  call   <fwrite@plt>
  xor    %eax,%eax
  movzbl %bl,%edx
  mov    %rbp,%rdi
  lea    D25(%rip),%rsi
  call   <fprintf@plt>
  test   %ebx,%ebx
  je     L17
  lea    -0x1(%rbx),%eax
  lea    0x17(%rsp),%r14
  lea    0x4(%r15,%rax,4),%rax
  lea    0x16(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    0x15(%rsp),%r12
  lea    D32(%rip),%rbx
  nopl   (%rax)
L56:
  mov    (%r15),%edi
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  add    $0x4,%r15
  call   <bm_get_rgb@plt>
  movzbl 0x16(%rsp),%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  movzbl 0x15(%rsp),%edx
  movzbl 0x17(%rsp),%r8d
  xor    %eax,%eax
  call   <fprintf@plt>
  cmp    0x8(%rsp),%r15
  jne    L56
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x1,%eax
  jmp    L44
L4:
  xor    %eax,%eax
L44:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D47
type: string
name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D32
type: string

tool: D3: w

tool: D47: JASC-PAL


tool: D9: 0100


tool: D25: %u


tool: D32: %u %u %u


assistant: ```c
int bm_save_palette(const char *filename, unsigned int *pal, unsigned int npal) {
  unsigned i;
  FILE *f;
  if (!filename)
    return 0;
  f = fopen(filename, "w");
  if (!f)
    return 0;
  fputs("JASC-PAL\n", f);
  fputs("0100\n", f);
  fprintf(f, "%u\n", npal);
  for (i = 0; i < npal; i++) {
    unsigned char R, G, B;
    bm_get_rgb(pal[i], &R, &G, &B);
    fprintf(f, "%u %u %u\n", R, G, B);
  }
  fclose(f);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<verificarReglas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getCantidadConflictosEnReglaHorizontal@plt>
  test   %rax,%rax
  je     L29
  mov    $0x0,%eax
  jmp    L47
L29:
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getCantidadConflictosEnReglaVertical@plt>
  test   %rax,%rax
  je     L56
  mov    $0x0,%eax
  jmp    L47
L56:
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <getCantidadConflictosEnReglaCuadrado@plt>
  test   %rax,%rax
  je     L38
  mov    $0x0,%eax
  jmp    L47
L38:
  mov    $0x1,%eax
L47:
  leave
  ret
```

assistant: ```c
int verificarReglas(int tabla[9][9], int ii, int jj, int candidato, int enGeneral) {
  if (getCantidadConflictosEnReglaHorizontal(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaVertical(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaCuadrado(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<verificarReglas>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  call   <getCantidadConflictosEnReglaHorizontal@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L23
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <getCantidadConflictosEnReglaVertical@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L24
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <getCantidadConflictosEnReglaCuadrado@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L24
```

assistant: ```c
int verificarReglas(int tabla[9][9], int ii, int jj, int candidato, int enGeneral) {
  if (getCantidadConflictosEnReglaHorizontal(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaVertical(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaCuadrado(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<verificarReglas>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <getCantidadConflictosEnReglaHorizontal@plt>
  test   %rax,%rax
  je     L5
L17:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getCantidadConflictosEnReglaVertical@plt>
  test   %rax,%rax
  jne    L17
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getCantidadConflictosEnReglaCuadrado@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
```

assistant: ```c
int verificarReglas(int tabla[9][9], int ii, int jj, int candidato, int enGeneral) {
  if (getCantidadConflictosEnReglaHorizontal(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaVertical(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaCuadrado(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<verificarReglas>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  call   <getCantidadConflictosEnReglaHorizontal@plt>
  test   %rax,%rax
  je     L17
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getCantidadConflictosEnReglaVertical@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getCantidadConflictosEnReglaCuadrado@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  pop    %r13
  sete   %al
  pop    %r14
  movzbl %al,%eax
  ret
```

assistant: ```c
int verificarReglas(int tabla[9][9], int ii, int jj, int candidato, int enGeneral) {
  if (getCantidadConflictosEnReglaHorizontal(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaVertical(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  if (getCantidadConflictosEnReglaCuadrado(tabla, ii, jj, candidato, enGeneral)) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arch_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x73,-0x4(%rbp)
  jne    L15
  mov    $0x0,%edi
  call   <cpu_reset@plt>
  jmp    L1
L15:
  mov    $0x0,%edi
  call   <cpu_reset@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void arch_reset(char mode) {
  if (1 && mode == 's') {
    cpu_reset(0);
  } else {
    cpu_reset(0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arch_reset>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x73,%dil
  je     L14
  mov    $0x0,%edi
  call   <cpu_reset@plt>
L2:
  add    $0x8,%rsp
  ret
L14:
  mov    $0x0,%edi
  call   <cpu_reset@plt>
  jmp    L2
```

assistant: ```c
void arch_reset(char mode) {
  if (1 && mode == 's') {
    cpu_reset(0);
  } else {
    cpu_reset(0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<arch_reset>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <cpu_reset@plt>
```

assistant: ```c
void arch_reset(char mode) {
  if (1 && mode == 's') {
    cpu_reset(0);
  } else {
    cpu_reset(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<arch_reset>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <cpu_reset@plt>
```

assistant: ```c
void arch_reset(char mode) {
  if (1 && mode == 's') {
    cpu_reset(0);
  } else {
    cpu_reset(0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L4
L25:
  cmpl   $0x1,-0x24(%rbp)
  jne    L10
  movsd  -0x20(%rbp),%xmm0
  movsd  D49(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L23
L10:
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L23:
  addl   $0x1,-0x24(%rbp)
L4:
  cmpl   $0x14,-0x24(%rbp)
  jle    L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D35
type_guessed: string
name: unpack_data
arguments: data_label: D38
type_guessed: string
name: unpack_data
arguments: data_label: D49
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string

tool: D35: Informe o numero: 

tool: D38: %lf

tool: {"D49": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D25: %d aprox.: %.5lf


tool: D26: %d aprox.: %.60lf


assistant: ```c
void main() {
  double y, xn, div;
  printf("Informe o numero: ");
  scanf("%lf", &y);
  for (int i = 1; i <= 20; i++) {
    if (i == 1) {
      xn = y / 2;
      printf("%d aprox.: %.5lf\n", i, xn);
    } else {
      div = ((xn * xn) - y) / (2 * xn);
      xn = xn - div;
      printf("%d aprox.: %.60lf\n", i, xn);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    $0x2,%ebp
  mov    $0x1,%ebx
  lea    D5(%rip),%r12
  lea    D4(%rip),%r13
  jmp    L18
L3:
  movsd  0x10(%rsp),%xmm3
  mulsd  D46(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm0
  mov    $0x1,%esi
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L39:
  add    $0x1,%ebx
  add    $0x1,%ebp
L18:
  cmp    $0x1,%ebx
  je     L3
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  0x10(%rsp),%xmm0
  movapd %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    $0x14,%ebp
  jle    L39
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D24
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D46
type: byte[8]

tool: D3: Informe o numero: 

tool: D24: %lf

tool: D5: %d aprox.: %.60lf


tool: D4: %d aprox.: %.5lf


tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void main() {
  double y, xn, div;
  printf("Informe o numero: ");
  scanf("%lf", &y);
  for (int i = 1; i <= 20; i++) {
    if (i == 1) {
      xn = y / 2;
      printf("%d aprox.: %.5lf\n", i, xn);
    } else {
      div = ((xn * xn) - y) / (2 * xn);
      xn = xn - div;
      printf("%d aprox.: %.60lf\n", i, xn);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  lea    D36(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%esi
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  lea    0x1(%rsi),%ebx
  cmp    $0x1,%esi
  je     L30
  cs nopw 0x0(%rax,%rax,1)
L41:
  movapd %xmm0,%xmm1
  mov    %rbp,%rdi
  mov    $0x1,%eax
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  cmp    $0x15,%ebx
  movsd  0x8(%rsp),%xmm0
  je     L4
  mov    %ebx,%esi
L11:
  movsd  0x10(%rsp),%xmm2
  lea    0x1(%rsi),%ebx
  cmp    $0x1,%esi
  jne    L41
L30:
  movsd  D19(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string
name: unpack_data
arguments: tag: D19
datatype: byte[8]

tool: D14: Informe o numero: 

tool: D36: %d aprox.: %.5lf


tool: D6: %d aprox.: %.60lf


tool: D13: %lf

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void main() {
  double y, xn, div;
  printf("Informe o numero: ");
  scanf("%lf", &y);
  for (int i = 1; i <= 20; i++) {
    if (i == 1) {
      xn = y / 2;
      printf("%d aprox.: %.5lf\n", i, xn);
    } else {
      div = ((xn * xn) - y) / (2 * xn);
      xn = xn - div;
      printf("%d aprox.: %.60lf\n", i, xn);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  lea    D9(%rip),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%esi
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  lea    0x1(%rsi),%ebx
  cmp    $0x1,%esi
  je     L45
  cs nopw 0x0(%rax,%rax,1)
L9:
  movapd %xmm0,%xmm1
  mov    %rbp,%rdi
  mov    $0x1,%eax
  mulsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  cmp    $0x15,%ebx
  movsd  0x8(%rsp),%xmm0
  je     L27
  mov    %ebx,%esi
L25:
  movsd  0x10(%rsp),%xmm2
  lea    0x1(%rsi),%ebx
  cmp    $0x1,%esi
  jne    L9
L45:
  movsd  D2(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D2
type: byte[8]

tool: D8: Informe o numero: 

tool: D9: %d aprox.: %.5lf


tool: D13: %d aprox.: %.60lf


tool: D18: %lf

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void main() {
  double y, xn, div;
  printf("Informe o numero: ");
  scanf("%lf", &y);
  for (int i = 1; i <= 20; i++) {
    if (i == 1) {
      xn = y / 2;
      printf("%d aprox.: %.5lf\n", i, xn);
    } else {
      div = ((xn * xn) - y) / (2 * xn);
      xn = xn - div;
      printf("%d aprox.: %.60lf\n", i, xn);
    }
  }
}
```