ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<parse_cmdline_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  mov    %rax,%r14
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L96
  mov    %rax,%r15
  cmp    %rax,%r14
  jb     L96
  mov    %rbx,%rcx
  mov    %rax,%rdi
  lea    0x1(%r14),%rbx
  mov    %rax,%r12
  neg    %rdi
  sub    %rax,%rbx
  mov    %rcx,%r14
  sub    %rcx,%r12
  mov    %rdi,0x18(%rsp)
  add    %rcx,%rbx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x1,%r14
  cmpb   $0x0,(%r14)
  je     L96
  cmp    %r14,%rbx
  je     L96
L41:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    (%r12,%r14,1),%r13
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L58
  mov    0x10(%rsp),%rdx
  lea    0x1(%r13),%rcx
  mov    $0xa,%r8d
  cmpb   $0x30,0x1(%rdx,%r13,1)
  je     L39
L45:
  lea    (%r15,%rcx,1),%rdx
  cmp    %rdx,0x8(%rsp)
  jb     L1
  mov    0x10(%rsp),%rdi
  mov    0x18(%rsp),%rbx
  xor    %eax,%eax
  add    %rbx,%rdi
  jmp    L88
L79:
  imul   %r8,%rax
  cmp    $0x39,%rcx
  lea    -0x30(%rcx,%rax,1),%rsi
  lea    -0x57(%rcx,%rax,1),%rax
  cmovbe %rsi,%rax
  add    $0x1,%rdx
  cmp    0x8(%rsp),%rdx
  ja     L1
L88:
  movsbq (%rdi,%rdx,1),%rcx
  mov    %rcx,%rsi
  and    $0xdf,%esi
  jne    L79
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L96:
  xor    %eax,%eax
L1:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L39:
  cmpb   $0x78,0x2(%rdx,%r13,1)
  jne    L45
  lea    0x3(%r13),%rcx
  mov    $0x10,%r8d
  jmp    L45
```

assistant: ```c
int parse_cmdline_int(char *cmdline, char *key) {
  uint32_t i = 0, digit = 0, base = 10;
  int32_t result = 0;
  uint32_t cmdline_len, key_len;
  cmdline_len = strlen(cmdline);
  key_len = strlen(key);
  while (1) {
    if (cmdline[i] == 0)
      break;
    if (i + key_len > cmdline_len)
      break;
    if (!strncmp(key, cmdline + i, key_len)) {
      i += key_len;
      i++;
      if ((cmdline[i] == '0') && (cmdline[i + 1] == 'x')) {
        base = 16;
        i += 2;
      } else {
        base = 10;
      }
      while (1) {
        if (i + key_len > cmdline_len)
          break;
        digit = cmdline[i];
        if ((digit == ' ') || (digit == 0))
          break;
        result *= base;
        if (digit <= '9')
          result += (digit - '0');
        else
          result += ((digit - 'a') + 10);
        i++;
      }
      break;
    }
    i++;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_cmdline_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,0x8(%rsp)
  mov    %rax,%r14
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L30
  mov    %rax,%r15
  cmp    %rax,%r14
  jb     L30
  mov    %rbx,%rcx
  mov    %rax,%rdi
  lea    0x1(%r14),%rbx
  mov    %rax,%r12
  neg    %rdi
  sub    %rax,%rbx
  mov    %rcx,%r14
  sub    %rcx,%r12
  mov    %rdi,0x18(%rsp)
  add    %rcx,%rbx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L57:
  add    $0x1,%r14
  cmpb   $0x0,(%r14)
  je     L30
  cmp    %r14,%rbx
  je     L30
L59:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    (%r12,%r14,1),%r13
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L57
  mov    0x10(%rsp),%rdx
  lea    0x1(%r13),%rcx
  mov    $0xa,%r8d
  cmpb   $0x30,0x1(%rdx,%r13,1)
  je     L61
L66:
  lea    (%r15,%rcx,1),%rdx
  cmp    %rdx,0x8(%rsp)
  jb     L10
  mov    0x10(%rsp),%rdi
  mov    0x18(%rsp),%rbx
  xor    %eax,%eax
  add    %rbx,%rdi
  jmp    L96
L87:
  imul   %r8,%rax
  cmp    $0x39,%rcx
  lea    -0x30(%rcx,%rax,1),%rsi
  lea    -0x57(%rcx,%rax,1),%rax
  cmovbe %rsi,%rax
  add    $0x1,%rdx
  cmp    %rdx,0x8(%rsp)
  jb     L10
L96:
  movsbq (%rdi,%rdx,1),%rcx
  mov    %rcx,%rsi
  and    $0xdf,%esi
  jne    L87
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  xor    %eax,%eax
L10:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L61:
  cmpb   $0x78,0x2(%rdx,%r13,1)
  jne    L66
  lea    0x3(%r13),%rcx
  mov    $0x10,%r8d
  jmp    L66
```

assistant: ```c
int parse_cmdline_int(char *cmdline, char *key) {
  uint32_t i = 0, digit = 0, base = 10;
  int32_t result = 0;
  uint32_t cmdline_len, key_len;
  cmdline_len = strlen(cmdline);
  key_len = strlen(key);
  while (1) {
    if (cmdline[i] == 0)
      break;
    if (i + key_len > cmdline_len)
      break;
    if (!strncmp(key, cmdline + i, key_len)) {
      i += key_len;
      i++;
      if ((cmdline[i] == '0') && (cmdline[i + 1] == 'x')) {
        base = 16;
        i += 2;
      } else {
        base = 10;
      }
      while (1) {
        if (i + key_len > cmdline_len)
          break;
        digit = cmdline[i];
        if ((digit == ' ') || (digit == 0))
          break;
        result *= base;
        if (digit <= '9')
          result += (digit - '0');
        else
          result += ((digit - 'a') + 10);
        i++;
      }
      break;
    }
    i++;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<first_unordered>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L32:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L13
  mov    -0x4(%rbp),%eax
  jmp    L1
L13:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L32
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int first_unordered(int n[], int size) {
  for (int i = 1; i < size; i++) {
    if (n[i] < n[i - 1])
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<first_unordered>:
  endbr64
  cmp    $0x1,%esi
  jle    L28
  mov    %esi,%esi
  mov    $0x1,%eax
L7:
  mov    %eax,%edx
  mov    -0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jl     L35
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L7
  mov    $0xffffffff,%edx
L35:
  mov    %edx,%eax
  ret
L28:
  mov    $0xffffffff,%edx
  jmp    L35
```

assistant: ```c
int first_unordered(int n[], int size) {
  for (int i = 1; i < size; i++) {
    if (n[i] < n[i - 1])
      return i;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<first_unordered>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  movslq %esi,%rsi
  mov    $0x1,%eax
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L5
L17:
  mov    -0x4(%rdi,%rax,4),%edx
  mov    %eax,%r8d
  cmp    %edx,(%rdi,%rax,4)
  jge    L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int first_unordered(int n[], int size) {
  for (int i = 1; i < size; i++) {
    if (n[i] < n[i - 1])
      return i;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<first_unordered>:
  endbr64
  cmp    $0x1,%esi
  jle    L35
  mov    (%rdi),%edx
  movslq %esi,%rsi
  mov    $0x1,%eax
  jmp    L27
  nopl   (%rax)
L24:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L35
L27:
  mov    %edx,%ecx
  mov    (%rdi,%rax,4),%edx
  mov    %eax,%r8d
  cmp    %ecx,%edx
  jge    L24
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L35:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int first_unordered(int n[], int size) {
  for (int i = 1; i < size; i++) {
    if (n[i] < n[i - 1])
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<osal_is_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x104,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstombs@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  je     L26
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
  jmp    L25
L26:
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int osal_is_directory(const wchar_t *_name) {
  char name[260 + 1];
  wcstombs(name, _name, 260);
  DIR *dir;
  dir = opendir(name);
  if (dir != NULL) {
    closedir(dir);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<osal_is_directory>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x104,%edx
  mov    %rbx,%rdi
  call   <wcstombs@plt>
  mov    %rbx,%rdi
  call   <opendir@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  jne    L3
L20:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x110,%rsp
  pop    %rbx
  ret
L3:
  call   <closedir@plt>
  mov    $0x1,%eax
  jmp    L20
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int osal_is_directory(const wchar_t *_name) {
  char name[260 + 1];
  wcstombs(name, _name, 260);
  DIR *dir;
  dir = opendir(name);
  if (dir != NULL) {
    closedir(dir);
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<osal_is_directory>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x104,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <wcstombs@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  call   <closedir@plt>
  mov    $0x1,%eax
L7:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x110,%rsp
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int osal_is_directory(const wchar_t *_name) {
  char name[260 + 1];
  wcstombs(name, _name, 260);
  DIR *dir;
  dir = opendir(name);
  if (dir != NULL) {
    closedir(dir);
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<osal_is_directory>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x104,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <wcstombs@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  call   <closedir@plt>
  mov    $0x1,%eax
L3:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x110,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int osal_is_directory(const wchar_t *_name) {
  char name[260 + 1];
  wcstombs(name, _name, 260);
  DIR *dir;
  dir = opendir(name);
  if (dir != NULL) {
    closedir(dir);
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x6(%rbp)
  cmpb   $0xa,-0x6(%rbp)
  je     L7
  movsbl -0x6(%rbp),%eax
  add    %eax,-0x4(%rbp)
L23:
  cmpb   $0xa,-0x6(%rbp)
  jne    L11
  jmp    L18
L7:
  nop
L18:
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  add    $0x20,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D0: Enter an abitrarily long string, ending with carriage return > 

tool: D17: Check sum is %c


assistant: ```c
int main() {
  char n;
  int total = 0;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (n != '\n') {
    n = getchar();
    if (n == '\n') {
      break;
    } else {
      total += (int)n;
    }
  }
  total = (total % 64) + 32;
  char output = (char)total;
  printf("Check sum is %c\n", output);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L16
L17:
  movsbl %al,%eax
  add    %eax,%ebx
L16:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L17
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  add    $0x20,%esi
  movsbl %sil,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D4
type: string

tool: D2: Enter an abitrarily long string, ending with carriage return > 

tool: D4: Check sum is %c


assistant: ```c
int main() {
  char n;
  int total = 0;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (n != '\n') {
    n = getchar();
    if (n == '\n') {
      break;
    } else {
      total += (int)n;
    }
  }
  total = (total % 64) + 32;
  char output = (char)total;
  printf("Check sum is %c\n", output);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl %al,%eax
  add    %eax,%ebx
L6:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L5
  mov    %ebx,%eax
  lea    D18(%rip),%rdi
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x20,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D18
type: string

tool: D1: Enter an abitrarily long string, ending with carriage return > 

tool: D18: Check sum is %c


assistant: ```c
int main() {
  char n;
  int total = 0;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (n != '\n') {
    n = getchar();
    if (n == '\n') {
      break;
    } else {
      total += (int)n;
    }
  }
  total = (total % 64) + 32;
  char output = (char)total;
  printf("Check sum is %c\n", output);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl %al,%eax
  add    %eax,%ebx
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  mov    %ebx,%eax
  lea    D18(%rip),%rdi
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x20,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D15: Enter an abitrarily long string, ending with carriage return > 

tool: D18: Check sum is %c


assistant: ```c
int main() {
  char n;
  int total = 0;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  while (n != '\n') {
    n = getchar();
    if (n == '\n') {
      break;
    } else {
      total += (int)n;
    }
  }
  total = (total % 64) + 32;
  char output = (char)total;
  printf("Check sum is %c\n", output);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cstr_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  jmp    L2
L20:
  addq   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
L9:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int cstr_len(char *s) {
  char *r;
  if ((r = s)) {
    while ((*s)) {
      ++s;
    }
  }
  return (s - r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cstr_len>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L22
  cmpb   $0x0,(%rdi)
  je     L22
L13:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L13
L22:
  sub    %edi,%eax
  ret
```

assistant: ```c
int cstr_len(char *s) {
  char *r;
  if ((r = s)) {
    while ((*s)) {
      ++s;
    }
  }
  return (s - r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstr_len>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  cmpb   $0x0,(%rdi)
  je     L8
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L9
  sub    %edi,%eax
L8:
  ret
```

assistant: ```c
int cstr_len(char *s) {
  char *r;
  if ((r = s)) {
    while ((*s)) {
      ++s;
    }
  }
  return (s - r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cstr_len>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  cmpb   $0x0,(%rdi)
  je     L10
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L29
  sub    %edi,%eax
L10:
  ret
```

assistant: ```c
int cstr_len(char *s) {
  char *r;
  if ((r = s)) {
    while ((*s)) {
      ++s;
    }
  }
  return (s - r);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vtime_account_irq_enter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vtime_account@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <irqtime_account_irq@plt>
  nop
  leave
  ret
```

assistant: ```c
void vtime_account_irq_enter(struct task_struct *tsk) {
  vtime_account(tsk);
  irqtime_account_irq(tsk);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vtime_account_irq_enter>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vtime_account@plt>
  mov    %rbx,%rdi
  call   <irqtime_account_irq@plt>
  pop    %rbx
  ret
```

assistant: ```c
void vtime_account_irq_enter(struct task_struct *tsk) {
  vtime_account(tsk);
  irqtime_account_irq(tsk);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vtime_account_irq_enter>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <vtime_account@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <irqtime_account_irq@plt>
```

assistant: ```c
void vtime_account_irq_enter(struct task_struct *tsk) {
  vtime_account(tsk);
  irqtime_account_irq(tsk);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vtime_account_irq_enter>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <vtime_account@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <irqtime_account_irq@plt>
```

assistant: ```c
void vtime_account_irq_enter(struct task_struct *tsk) {
  vtime_account(tsk);
  irqtime_account_irq(tsk);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L42
  mov    $0x0,%eax
  jmp    L33
L42:
  cmpl   $0x2,-0x18(%rbp)
  je     L36
  mov    $0x0,%eax
  jmp    L33
L36:
  cmpl   $0x2,0x38(%rbp)
  je     L30
  mov    $0x0,%eax
  jmp    L33
L30:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    0x10(%rbp),%eax
  add    %eax,%edx
  mov    0x18(%rbp),%eax
  add    %eax,%edx
  mov    0x20(%rbp),%eax
  add    %eax,%edx
  mov    0x28(%rbp),%eax
  add    %eax,%edx
  mov    0x30(%rbp),%eax
  add    %eax,%edx
  mov    0x38(%rbp),%eax
  add    %edx,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int foo(int a, int b, int c, int d, int e, int f, int g, int h, int i, int j, int k, int l) {
  if (a != 1)
    return 0;
  if (f != 2)
    return 0;
  if (l != 2)
    return 0;
  return a + b + c + d + e + f + g + h + i + j + k + l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  cmp    $0x2,%r9d
  setne  %dil
  cmpl   $0x2,0x30(%rsp)
  setne  %r9b
  or     %r9b,%dil
  jne    L6
  cmp    $0x1,%eax
  je     L1
L6:
  mov    $0x0,%eax
  ret
L1:
  lea    0x1(%rsi,%rdx,1),%eax
  add    %ecx,%eax
  lea    0x2(%r8,%rax,1),%eax
  add    0x8(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x18(%rsp),%eax
  add    0x20(%rsp),%eax
  mov    0x28(%rsp),%edx
  lea    0x2(%rdx,%rax,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b, int c, int d, int e, int f, int g, int h, int i, int j, int k, int l) {
  if (a != 1)
    return 0;
  if (f != 2)
    return 0;
  if (l != 2)
    return 0;
  return a + b + c + d + e + f + g + h + i + j + k + l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  cmp    $0x2,%r9d
  mov    %edi,%eax
  setne  %dil
  cmpl   $0x2,0x30(%rsp)
  setne  %r9b
  or     %r9b,%dil
  jne    L5
  cmp    $0x1,%eax
  je     L9
L5:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L9:
  lea    0x1(%rsi,%rdx,1),%eax
  mov    0x28(%rsp),%edx
  add    %ecx,%eax
  lea    0x2(%r8,%rax,1),%eax
  add    0x8(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x18(%rsp),%eax
  add    0x20(%rsp),%eax
  lea    0x2(%rdx,%rax,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b, int c, int d, int e, int f, int g, int h, int i, int j, int k, int l) {
  if (a != 1)
    return 0;
  if (f != 2)
    return 0;
  if (l != 2)
    return 0;
  return a + b + c + d + e + f + g + h + i + j + k + l;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  cmp    $0x2,%r9d
  mov    %edi,%eax
  setne  %dil
  cmpl   $0x2,0x30(%rsp)
  setne  %r9b
  or     %r9b,%dil
  jne    L3
  cmp    $0x1,%eax
  je     L9
L3:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L9:
  lea    0x1(%rsi,%rdx,1),%eax
  mov    0x28(%rsp),%edx
  add    %ecx,%eax
  lea    0x2(%r8,%rax,1),%eax
  add    0x8(%rsp),%eax
  add    0x10(%rsp),%eax
  add    0x18(%rsp),%eax
  add    0x20(%rsp),%eax
  lea    0x2(%rdx,%rax,1),%eax
  ret
```

assistant: ```c
int foo(int a, int b, int c, int d, int e, int f, int g, int h, int i, int j, int k, int l) {
  if (a != 1)
    return 0;
  if (f != 2)
    return 0;
  if (l != 2)
    return 0;
  return a + b + c + d + e + f + g + h + i + j + k + l;
}
```