ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findRank>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L55
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L34
  shr    $0x2,%esi
  movd   %edx,%xmm3
  pxor   %xmm0,%xmm0
  mov    %rdi,%rax
  sub    $0x1,%esi
  pshufd $0x0,%xmm3,%xmm2
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax)
L44:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  pcmpgtd %xmm2,%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L44
  movdqa %xmm0,%xmm1
  mov    %ecx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    $0x1,%eax
  test   $0x3,%cl
  je     L14
L16:
  movslq %esi,%r8
  lea    0x0(,%r8,4),%r9
  cmp    %edx,(%rdi,%r8,4)
  jg     L97
L105:
  lea    0x1(%rsi),%r8d
  cmp    %ecx,%r8d
  jge    L65
  cmp    0x4(%rdi,%r9,1),%edx
  jl     L85
L23:
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L65
  cmp    0x8(%rdi,%r9,1),%edx
  jge    L65
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  mov    $0x1,%eax
L65:
  ret
  xchg   %ax,%ax
L97:
  add    $0x1,%eax
  jmp    L105
  nopl   (%rax)
L85:
  add    $0x1,%eax
  jmp    L23
  nopl   (%rax)
L14:
  ret
L34:
  xor    %esi,%esi
  mov    $0x1,%eax
  jmp    L16
```

assistant: ```c
int findRank(int *arr, int size, int num) {
  int r, i = 0;
  r = 1;
  while (i < size) {
    if (arr[i] > num)
      r++;
    i++;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<log_perr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <logm@plt>
  jmp    L15
L3:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  lea    D7(%rip),%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <logm@plt>
L15:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D7
type: string

tool: D5: %s

tool: D7: %s: %s

assistant: ```c
void log_perr(int priority, const char msg[], int fault_errno) {
  if (!fault_errno)
    logm(priority, "%s", msg);
  else
    logm(priority, "%s: %s", msg, strerror(fault_errno));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_perr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edx,%edx
  jne    L19
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  mov    $0x0,%eax
  call   <logm@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    %edx,%edi
  call   <strerror@plt>
  mov    %eax,%ecx
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <logm@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D10
datatype: string

tool: D4: %s

tool: D10: %s: %s

assistant: ```c
void log_perr(int priority, const char msg[], int fault_errno) {
  if (!fault_errno)
    logm(priority, "%s", msg);
  else
    logm(priority, "%s: %s", msg, strerror(fault_errno));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<log_perr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L9
  add    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <logm@plt>
  nopl   0x0(%rax)
L9:
  mov    %edx,%edi
  call   <strerror@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <logm@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D5
data_type: string

tool: D1: %s

tool: D5: %s: %s

assistant: ```c
void log_perr(int priority, const char msg[], int fault_errno) {
  if (!fault_errno)
    logm(priority, "%s", msg);
  else
    logm(priority, "%s: %s", msg, strerror(fault_errno));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_perr>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L5
  add    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D16(%rip),%rsi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <logm@plt>
  nopl   0x0(%rax)
L5:
  mov    %edx,%edi
  call   <strerror@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  pop    %r12
  jmp    1060 <logm@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D16: %s

tool: D2: %s: %s

assistant: ```c
void log_perr(int priority, const char msg[], int fault_errno) {
  if (!fault_errno)
    logm(priority, "%s", msg);
  else
    logm(priority, "%s: %s", msg, strerror(fault_errno));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L18:
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x9,-0x4(%rbp)
  jle    L18
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 10; i++) {
  }
ERROR:
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 10; i++) {
  }
ERROR:
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 10; i++) {
  }
ERROR:
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  for (int i = 0; i < 10; i++) {
  }
ERROR:
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x757a666564636261,%rax
  mov    %rax,-0x1c(%rbp)
  movw   $0x686f,-0x14(%rbp)
  movabs $0x3736353433323130,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x3938,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L6
L15:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x2c(%rbp)
L6:
  cmpl   $0x13,-0x2c(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string

tool: D3: %c


assistant: ```c
int main() {
  char a[10] = "abcdefzuohui";
  char b[10] = "0123456789";
  char *p = b;
  int i;
  for (i = 0; i < 20; i++) {
    printf("%c\n", *(p + i));
    printf("%s\n", p + i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x3938,0x16(%rsp)
  lea    0xe(%rsp),%rbx
  lea    0x22(%rsp),%r12
  lea    D8(%rip),%rbp
L18:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %c


assistant: ```c
int main() {
  char a[10] = "abcdefzuohui";
  char b[10] = "0123456789";
  char *p = b;
  int i;
  for (i = 0; i < 20; i++) {
    printf("%c\n", *(p + i));
    printf("%s\n", p + i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x30,%esi
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3736353433323130,%rax
  lea    0xe(%rsp),%rbx
  lea    0x22(%rsp),%r12
  mov    %rax,0xe(%rsp)
  mov    $0x3938,%eax
  mov    %ax,0x16(%rsp)
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%esi
L8:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: %c


assistant: ```c
int main() {
  char a[10] = "abcdefzuohui";
  char b[10] = "0123456789";
  char *p = b;
  int i;
  for (i = 0; i < 20; i++) {
    printf("%c\n", *(p + i));
    printf("%s\n", p + i);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3736353433323130,%rax
  lea    0xe(%rsp),%rbx
  lea    0x22(%rsp),%r12
  mov    %rax,0xe(%rsp)
  mov    $0x3938,%eax
  mov    %ax,0x16(%rsp)
  nopl   0x0(%rax)
L10:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %r12,%rbx
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: %c


assistant: ```c
int main() {
  char a[10] = "abcdefzuohui";
  char b[10] = "0123456789";
  char *p = b;
  int i;
  for (i = 0; i < 20; i++) {
    printf("%c\n", *(p + i));
    printf("%s\n", p + i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L6:
  cmpl   $0x4,-0x4(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i = 0;
  do {
  } while (i < 5);
  printf(i);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
L3:
  jmp    L3
```

assistant: ```c
main() {
  int i = 0;
  do {
  } while (i < 5);
  printf(i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
main() {
  int i = 0;
  do {
  } while (i < 5);
  printf(i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
main() {
  int i = 0;
  do {
  } while (i < 5);
  printf(i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tcsetattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x82,-0x18(%rbp)
  je     L34
  cmpl   $0x82,-0x18(%rbp)
  jg     L10
  cmpl   $0x80,-0x18(%rbp)
  je     L73
  cmpl   $0x81,-0x18(%rbp)
  je     L47
  jmp    L10
L73:
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L82
L34:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L82
L47:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L82
L10:
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L60
L82:
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
L60:
  leave
  ret
```

assistant: ```c
int tcsetattr(int fd, int optional_actions, const struct termios *termios_p) {
  int cmd;
  switch (optional_actions) {
  case TCSANOW:
    cmd = TCSETS;
    break;
  case TCSADRAIN:
    cmd = TCSETSW;
    break;
  case TCSAFLUSH:
    cmd = TCSETSF;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  return ioctl(fd, cmd, termios_p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tcsetattr>:
  endbr64
  cmp    $0x81,%esi
  je     L21
  cmp    $0x82,%esi
  je     L32
  cmp    $0x80,%esi
  je     L15
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
L15:
  mov    D28(%rip),%rax
  mov    (%rax),%esi
L45:
  sub    $0x8,%rsp
  call   <ioctl@plt>
  add    $0x8,%rsp
  ret
L32:
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  jmp    L45
L21:
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  jmp    L45
```

assistant: ```c
int tcsetattr(int fd, int optional_actions, const struct termios *termios_p) {
  int cmd;
  switch (optional_actions) {
  case TCSANOW:
    cmd = TCSETS;
    break;
  case TCSADRAIN:
    cmd = TCSETSW;
    break;
  case TCSAFLUSH:
    cmd = TCSETSF;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  return ioctl(fd, cmd, termios_p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tcsetattr>:
  endbr64
  cmp    $0x81,%esi
  je     L6
  cmp    $0x82,%esi
  je     L2
  cmp    $0x80,%esi
  je     L28
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D35(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
  xchg   %ax,%ax
L2:
  mov    D32(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
```

assistant: ```c
int tcsetattr(int fd, int optional_actions, const struct termios *termios_p) {
  int cmd;
  switch (optional_actions) {
  case TCSANOW:
    cmd = TCSETS;
    break;
  case TCSADRAIN:
    cmd = TCSETSW;
    break;
  case TCSAFLUSH:
    cmd = TCSETSF;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  return ioctl(fd, cmd, termios_p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tcsetattr>:
  endbr64
  cmp    $0x81,%esi
  je     L23
  cmp    $0x82,%esi
  je     L7
  cmp    $0x80,%esi
  je     L2
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D41(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax)
L23:
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
  xchg   %ax,%ax
L7:
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <ioctl@plt>
```

assistant: ```c
int tcsetattr(int fd, int optional_actions, const struct termios *termios_p) {
  int cmd;
  switch (optional_actions) {
  case TCSANOW:
    cmd = TCSETS;
    break;
  case TCSADRAIN:
    cmd = TCSETSW;
    break;
  case TCSAFLUSH:
    cmd = TCSETSF;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  return ioctl(fd, cmd, termios_p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D35
type: string
name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D4
type: string

tool: D35: [{[{[(())]}]}]

tool: D36: %d

tool: D4: [{[{[(())]]}]

assistant: ```c
int main() {
  printf("%d", isValid("[{[{[(())]}]}]"));
  printf("%d", isValid("[{[{[(())]]}]"));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <isValid@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string

tool: D12: [{[{[(())]}]}]

tool: D18: %d

tool: D6: [{[{[(())]]}]

assistant: ```c
int main() {
  printf("%d", isValid("[{[{[(())]}]}]"));
  printf("%d", isValid("[{[{[(())]]}]"));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  lea    D16(%rip),%rbp
  call   <isValid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <isValid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D2: [{[{[(())]}]}]

tool: D16: %d

tool: D14: [{[{[(())]]}]

assistant: ```c
int main() {
  printf("%d", isValid("[{[{[(())]}]}]"));
  printf("%d", isValid("[{[{[(())]]}]"));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  lea    D3(%rip),%rbp
  call   <isValid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <isValid@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string

tool: D1: [{[{[(())]}]}]

tool: D3: %d

tool: D19: [{[{[(())]]}]

assistant: ```c
int main() {
  printf("%d", isValid("[{[{[(())]}]}]"));
  printf("%d", isValid("[{[{[(())]]}]"));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x900,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x8f0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x11b,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x1,-0x900(%rbp)
  jmp    L88
L61:
  mov    -0x900(%rbp),%eax
  mov    %eax,-0x8fc(%rbp)
  jmp    L96
L45:
  mov    -0x8fc(%rbp),%eax
  mov    %eax,%edi
  call   <square_digits@plt>
  mov    %eax,-0x8fc(%rbp)
L96:
  cmpl   $0x59,-0x8fc(%rbp)
  je     L94
  cmpl   $0x1,-0x8fc(%rbp)
  jne    L45
L94:
  cmpl   $0x59,-0x8fc(%rbp)
  jne    L99
  mov    -0x900(%rbp),%eax
  cltq
  movl   $0x1,-0x8f0(%rbp,%rax,4)
L99:
  addl   $0x1,-0x900(%rbp)
L88:
  cmpl   $0x236,-0x900(%rbp)
  jle    L61
  movl   $0x0,-0x8f8(%rbp)
  movl   $0x1,-0x900(%rbp)
  jmp    L2
L97:
  mov    -0x900(%rbp),%eax
  mov    %eax,%edi
  call   <square_digits@plt>
  mov    %eax,-0x8f4(%rbp)
  mov    -0x8f4(%rbp),%eax
  cltq
  mov    -0x8f0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L77
  addl   $0x1,-0x8f8(%rbp)
L77:
  addl   $0x1,-0x900(%rbp)
L2:
  cmpl   $0x98967f,-0x900(%rbp)
  jle    L97
  mov    -0x8f8(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int cache[567] = {0};
  int i;
  for (i = 1; i < 567; ++i) {
    int t = i;
    while (t != 89 && t != 1)
      t = square_digits(t);
    if (t == 89)
      cache[i] = 1;
  }
  int sum = 0;
  for (i = 1; i < 10000000; ++i) {
    int t = square_digits(i);
    if (cache[t])
      ++sum;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x11b,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  mov    $0x2,%ebx
  jmp    L56
L17:
  add    $0x1,%rbx
  cmp    $0x59,%edi
  je     L108
L56:
  mov    %ebx,%edi
  cmp    $0x237,%rbx
  je     L1
  cmp    $0x59,%ebx
  je     L17
  cmp    $0x1,%ebx
  je     L17
L43:
  call   <square_digits@plt>
  mov    %eax,%edi
  cmp    $0x59,%eax
  je     L17
  cmp    $0x1,%eax
  jne    L43
  jmp    L17
L108:
  movl   $0x1,-0x4(%rsp,%rbx,4)
  jmp    L56
L1:
  mov    $0x0,%ebp
  mov    $0x1,%ebx
L35:
  mov    %ebx,%edi
  call   <square_digits@plt>
  cltq
  cmpl   $0x1,(%rsp,%rax,4)
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x989680,%ebx
  jne    L35
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x8f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main(void) {
  int cache[567] = {0};
  int i;
  for (i = 1; i < 567; ++i) {
    int t = i;
    while (t != 89 && t != 1)
      t = square_digits(t);
    if (t == 89)
      cache[i] = 1;
  }
  int sum = 0;
  for (i = 1; i < 10000000; ++i) {
    int t = square_digits(i);
    if (cache[t])
      ++sum;
  }
  printf("%d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x11b,%ecx
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  nopl   0x0(%rax)
L47:
  mov    %ebx,%edi
  cmp    $0x237,%rbx
  je     L0
L77:
  cmp    $0x59,%rbx
  je     L17
  nopl   0x0(%rax)
L45:
  call   <square_digits@plt>
  mov    %eax,%edi
  cmp    $0x59,%eax
  je     L17
  cmp    $0x1,%eax
  jne    L45
L17:
  add    $0x1,%rbx
  cmp    $0x59,%edi
  jne    L47
  movl   $0x1,-0x4(%rbp,%rbx,4)
  mov    %ebx,%edi
  cmp    $0x237,%rbx
  jne    L77
L0:
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L15:
  mov    %ebx,%edi
  call   <square_digits@plt>
  cltq
  cmpl   $0x1,(%rsp,%rax,4)
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x989680,%ebx
  jne    L15
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x8f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(void) {
  int cache[567] = {0};
  int i;
  for (i = 1; i < 567; ++i) {
    int t = i;
    while (t != 89 && t != 1)
      t = square_digits(t);
    if (t == 89)
      cache[i] = 1;
  }
  int sum = 0;
  for (i = 1; i < 10000000; ++i) {
    int t = square_digits(i);
    if (cache[t])
      ++sum;
  }
  printf("%d\n", sum);
  return 0;
}
```