ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Maxtrix_Sub>:
  endbr64
  movzwl %si,%esi
  movzwl %dx,%edx
  mov    %rdi,%rax
  mov    %rcx,%rdi
  imul   %edx,%esi
  mov    %esi,%r10d
  shr    $0x2,%r10d
  je     L27
  mov    %r10d,%r10d
  mov    %r8,%rcx
  mov    %rdi,%rdx
  shl    $0x4,%r10
  lea    (%rax,%r10,1),%r9
  nopl   0x0(%rax)
L1:
  movss  (%rax),%xmm2
  subss  (%rdx),%xmm2
  add    $0x10,%rax
  add    $0x10,%rdx
  movss  -0xc(%rax),%xmm0
  subss  -0xc(%rdx),%xmm0
  add    $0x10,%rcx
  movss  -0x8(%rax),%xmm1
  movss  -0x8(%rdx),%xmm3
  movss  %xmm2,-0x10(%rcx)
  movss  %xmm0,-0xc(%rcx)
  subss  %xmm3,%xmm1
  movss  -0x4(%rax),%xmm0
  subss  -0x4(%rdx),%xmm0
  movss  %xmm1,-0x8(%rcx)
  movss  %xmm0,-0x4(%rcx)
  cmp    %r9,%rax
  jne    L1
  add    %r10,%rdi
  add    %r10,%r8
L32:
  and    $0x3,%esi
  je     L20
  mov    %esi,%esi
  xor    %eax,%eax
L21:
  movss  (%r9,%rax,4),%xmm0
  subss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L21
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rax,%r9
  jmp    L32
```

assistant: ```c
int Maxtrix_Sub(float *pSrcA, unsigned short numRows, unsigned short numCols, float *pSrcB, float *pDst) {
  float *pIn1 = pSrcA;
  float *pIn2 = pSrcB;
  float *pOut = pDst;
  float inA1, inA2, inB1, inB2, out1, out2;
  unsigned int numSamples;
  unsigned int blkCnt;
  int status;
  numSamples = (unsigned int)numRows * numCols;
  blkCnt = numSamples >> 2u;
  while (blkCnt > 0u) {
    inA1 = pIn1[0];
    inB1 = pIn2[0];
    inA2 = pIn1[1];
    out1 = inA1 - inB1;
    inB2 = pIn2[1];
    inA1 = pIn1[2];
    out2 = inA2 - inB2;
    inB1 = pIn2[2];
    pOut[0] = out1;
    pOut[1] = out2;
    inA2 = pIn1[3];
    inB2 = pIn2[3];
    out1 = inA1 - inB1;
    out2 = inA2 - inB2;
    pOut[2] = out1;
    pOut[3] = out2;
    pIn1 += 4u;
    pIn2 += 4u;
    pOut += 4u;
    blkCnt--;
  }
  blkCnt = numSamples & 0x3u;
  while (blkCnt > 0u) {
    *pOut++ = (*pIn1++) - (*pIn2++);
    blkCnt--;
  }
  status = 0;
  return (status);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Maxtrix_Sub>:
  endbr64
  movzwl %si,%esi
  movzwl %dx,%eax
  mov    %esi,%edx
  imul   %eax,%edx
  mov    %edx,%eax
  shr    $0x2,%eax
  je     L44
  lea    0xf(%rdi),%rsi
  mov    %eax,%r10d
  sub    %r8,%rsi
  cmp    $0x1e,%rsi
  jbe    L113
  lea    0xf(%rcx),%rsi
  sub    %r8,%rsi
  cmp    $0x1e,%rsi
  jbe    L113
  mov    %r10,%rsi
  xor    %eax,%eax
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L19:
  movups (%rdi,%rax,1),%xmm0
  movups (%rcx,%rax,1),%xmm4
  subps  %xmm4,%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L19
L81:
  mov    %r10,%rax
  shl    $0x4,%rax
  add    %rax,%rdi
  add    %rax,%rcx
  add    %rax,%r8
L44:
  and    $0x3,%edx
  je     L79
  lea    0x4(%rcx),%rax
  sub    $0x1,%edx
  cmp    %rax,%r8
  lea    0x4(%rdi),%rax
  setne  %sil
  cmp    %rax,%r8
  setne  %al
  test   %al,%sil
  je     L20
  cmp    $0x1,%edx
  jbe    L20
  movq   (%rdi),%xmm0
  movq   (%rcx),%xmm1
  subps  %xmm1,%xmm0
  movlps %xmm0,(%r8)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rcx),%xmm0
  movss  %xmm0,0x8(%r8)
L79:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L113:
  mov    %r10,%r11
  mov    %r8,%r9
  mov    %rcx,%rsi
  mov    %rdi,%rax
  shl    $0x4,%r11
  add    %rdi,%r11
  nopl   0x0(%rax,%rax,1)
L59:
  movss  (%rax),%xmm2
  subss  (%rsi),%xmm2
  add    $0x10,%rax
  add    $0x10,%rsi
  movss  -0xc(%rax),%xmm0
  subss  -0xc(%rsi),%xmm0
  add    $0x10,%r9
  movss  -0x8(%rax),%xmm1
  movss  -0x8(%rsi),%xmm3
  movss  %xmm2,-0x10(%r9)
  movss  %xmm0,-0xc(%r9)
  subss  %xmm3,%xmm1
  movss  -0x4(%rax),%xmm0
  subss  -0x4(%rsi),%xmm0
  movss  %xmm1,-0x8(%r9)
  movss  %xmm0,-0x4(%r9)
  cmp    %rax,%r11
  jne    L59
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L20:
  movss  (%rdi),%xmm0
  subss  (%rcx),%xmm0
  movss  %xmm0,(%r8)
  test   %edx,%edx
  je     L79
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rcx),%xmm0
  movss  %xmm0,0x4(%r8)
  cmp    $0x1,%edx
  je     L79
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rcx),%xmm0
  movss  %xmm0,0x8(%r8)
  jmp    L79
```

assistant: ```c
int Maxtrix_Sub(float *pSrcA, unsigned short numRows, unsigned short numCols, float *pSrcB, float *pDst) {
  float *pIn1 = pSrcA;
  float *pIn2 = pSrcB;
  float *pOut = pDst;
  float inA1, inA2, inB1, inB2, out1, out2;
  unsigned int numSamples;
  unsigned int blkCnt;
  int status;
  numSamples = (unsigned int)numRows * numCols;
  blkCnt = numSamples >> 2u;
  while (blkCnt > 0u) {
    inA1 = pIn1[0];
    inB1 = pIn2[0];
    inA2 = pIn1[1];
    out1 = inA1 - inB1;
    inB2 = pIn2[1];
    inA1 = pIn1[2];
    out2 = inA2 - inB2;
    inB1 = pIn2[2];
    pOut[0] = out1;
    pOut[1] = out2;
    inA2 = pIn1[3];
    inB2 = pIn2[3];
    out1 = inA1 - inB1;
    out2 = inA2 - inB2;
    pOut[2] = out1;
    pOut[3] = out2;
    pIn1 += 4u;
    pIn2 += 4u;
    pOut += 4u;
    blkCnt--;
  }
  blkCnt = numSamples & 0x3u;
  while (blkCnt > 0u) {
    *pOut++ = (*pIn1++) - (*pIn2++);
    blkCnt--;
  }
  status = 0;
  return (status);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_minio_src_index_in_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L32:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L25
L18:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L32
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int32_t _minio_src_index_in_error(int r, int32_t *error_index) {
  int i;
  for (i = 0; error_index[i] != -1; i++) {
    if (error_index[i] == r) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_minio_src_index_in_error>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0xffffffff,%eax
  je     L1
  add    $0x4,%rsi
L29:
  cmp    %eax,%edi
  je     L14
  add    $0x4,%rsi
  mov    -0x4(%rsi),%eax
  cmp    $0xffffffff,%eax
  jne    L29
  mov    $0x0,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int32_t _minio_src_index_in_error(int r, int32_t *error_index) {
  int i;
  for (i = 0; error_index[i] != -1; i++) {
    if (error_index[i] == r) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_minio_src_index_in_error>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0xffffffff,%eax
  je     L10
  add    $0x4,%rsi
  jmp    L34
  nopl   0x0(%rax)
L26:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  cmp    $0xffffffff,%eax
  je     L10
L34:
  cmp    %eax,%edi
  jne    L26
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int32_t _minio_src_index_in_error(int r, int32_t *error_index) {
  int i;
  for (i = 0; error_index[i] != -1; i++) {
    if (error_index[i] == r) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_minio_src_index_in_error>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0xffffffff,%eax
  je     L17
  add    $0x4,%rsi
  jmp    L25
  nopl   0x0(%rax)
L35:
  mov    (%rsi),%eax
  add    $0x4,%rsi
  cmp    $0xffffffff,%eax
  je     L17
L25:
  cmp    %eax,%edi
  jne    L35
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int32_t _minio_src_index_in_error(int r, int32_t *error_index) {
  int i;
  for (i = 0; error_index[i] != -1; i++) {
    if (error_index[i] == r) {
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usb_suspend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xbf885050,%eax
  mov    (%rax),%edx
  mov    $0xbf885050,%eax
  or     $0x10,%edx
  mov    %edx,(%rax)
  mov    $0xbf885200,%eax
  movl   $0x10,(%rax)
  mov    $0x0,%eax
  call   <usbcb_suspend@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usb_suspend(void) {
  *(volatile unsigned *)(0xBF800000 + (0x85050)) |= 0x0010;
  *(volatile unsigned *)(0xBF800000 + (0x85200)) = 0x0010;
  usbcb_suspend();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usb_suspend>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xbf885050,%edx
  mov    (%rdx),%eax
  or     $0x10,%eax
  mov    %eax,(%rdx)
  mov    $0xbf885200,%eax
  movl   $0x10,(%rax)
  mov    $0x0,%eax
  call   <usbcb_suspend@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usb_suspend(void) {
  *(volatile unsigned *)(0xBF800000 + (0x85050)) |= 0x0010;
  *(volatile unsigned *)(0xBF800000 + (0x85200)) = 0x0010;
  usbcb_suspend();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usb_suspend>:
  endbr64
  mov    $0xbf885050,%edx
  mov    (%rdx),%eax
  or     $0x10,%eax
  mov    %eax,(%rdx)
  mov    $0xbf885200,%eax
  movl   $0x10,(%rax)
  xor    %eax,%eax
  jmp    1050 <usbcb_suspend@plt>
```

assistant: ```c
void usb_suspend(void) {
  *(volatile unsigned *)(0xBF800000 + (0x85050)) |= 0x0010;
  *(volatile unsigned *)(0xBF800000 + (0x85200)) = 0x0010;
  usbcb_suspend();
}
```
user: What is the c source code of the assembly code below?

```asm
<usb_suspend>:
  endbr64
  mov    $0xbf885050,%edx
  mov    (%rdx),%eax
  or     $0x10,%eax
  mov    %eax,(%rdx)
  mov    $0xbf885200,%eax
  movl   $0x10,(%rax)
  xor    %eax,%eax
  jmp    1050 <usbcb_suspend@plt>
```

assistant: ```c
void usb_suspend(void) {
  *(volatile unsigned *)(0xBF800000 + (0x85050)) |= 0x0010;
  *(volatile unsigned *)(0xBF800000 + (0x85200)) = 0x0010;
  usbcb_suspend();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zero_3x4_col1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzwl 0x2(%rax),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <gf4096_inv@plt>
  movzwl %ax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movzwl 0x2(%rax),%eax
  movzwl %ax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gf4096_mul@plt>
  mov    %ax,-0x12(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movzwl (%rax),%ebx
  movzwl -0x12(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gf4096_mul@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  xor    %ebx,%edx
  mov    %dx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movzwl 0x6(%rax),%ebx
  movzwl -0x12(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movzwl 0x6(%rax),%eax
  movzwl %ax,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gf4096_mul@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  xor    %ebx,%edx
  mov    %dx,0x6(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void zero_3x4_col1(unsigned short m[3][4]) {
  unsigned short minv;
  minv = gf4096_mul(m[2][1], gf4096_inv(m[1][1]));
  m[2][0] = m[2][0] ^ gf4096_mul(m[1][0], minv);
  m[2][3] = m[2][3] ^ gf4096_mul(m[1][3], minv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<zero_3x4_col1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzwl 0xa(%rdi),%edi
  call   <gf4096_inv@plt>
  movzwl %ax,%esi
  movzwl 0x12(%rbx),%edi
  call   <gf4096_mul@plt>
  movzwl 0x10(%rbx),%r12d
  movzwl %ax,%ebp
  movzwl 0x8(%rbx),%edi
  mov    %ebp,%esi
  call   <gf4096_mul@plt>
  xor    %eax,%r12d
  mov    %r12w,0x10(%rbx)
  movzwl 0x16(%rbx),%r12d
  movzwl 0xe(%rbx),%edi
  mov    %ebp,%esi
  call   <gf4096_mul@plt>
  xor    %eax,%r12d
  mov    %r12w,0x16(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void zero_3x4_col1(unsigned short m[3][4]) {
  unsigned short minv;
  minv = gf4096_mul(m[2][1], gf4096_inv(m[1][1]));
  m[2][0] = m[2][0] ^ gf4096_mul(m[1][0], minv);
  m[2][3] = m[2][3] ^ gf4096_mul(m[1][3], minv);
}
```
user: What is the c source code of the assembly code below?

```asm
<zero_3x4_col1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzwl 0xa(%rdi),%edi
  call   <gf4096_inv@plt>
  movzwl 0x12(%rbx),%edi
  movzwl %ax,%esi
  call   <gf4096_mul@plt>
  movzwl 0x8(%rbx),%edi
  movzwl 0x10(%rbx),%r12d
  movzwl %ax,%ebp
  mov    %ebp,%esi
  call   <gf4096_mul@plt>
  movzwl 0xe(%rbx),%edi
  mov    %ebp,%esi
  xor    %eax,%r12d
  mov    %r12w,0x10(%rbx)
  movzwl 0x16(%rbx),%r12d
  call   <gf4096_mul@plt>
  xor    %eax,%r12d
  mov    %r12w,0x16(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void zero_3x4_col1(unsigned short m[3][4]) {
  unsigned short minv;
  minv = gf4096_mul(m[2][1], gf4096_inv(m[1][1]));
  m[2][0] = m[2][0] ^ gf4096_mul(m[1][0], minv);
  m[2][3] = m[2][3] ^ gf4096_mul(m[1][3], minv);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zero_3x4_col1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzwl 0xa(%rdi),%edi
  call   <gf4096_inv@plt>
  movzwl 0x12(%rbx),%edi
  movzwl %ax,%esi
  call   <gf4096_mul@plt>
  movzwl 0x8(%rbx),%edi
  movzwl 0x10(%rbx),%r12d
  movzwl %ax,%ebp
  mov    %ebp,%esi
  call   <gf4096_mul@plt>
  movzwl 0xe(%rbx),%edi
  mov    %ebp,%esi
  xor    %eax,%r12d
  mov    %r12w,0x10(%rbx)
  movzwl 0x16(%rbx),%r12d
  call   <gf4096_mul@plt>
  xor    %eax,%r12d
  mov    %r12w,0x16(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void zero_3x4_col1(unsigned short m[3][4]) {
  unsigned short minv;
  minv = gf4096_mul(m[2][1], gf4096_inv(m[1][1]));
  m[2][0] = m[2][0] ^ gf4096_mul(m[1][0], minv);
  m[2][3] = m[2][3] ^ gf4096_mul(m[1][3], minv);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<endln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <kbd_close@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int endln() {
  kbd_close();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<endln>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <kbd_close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int endln() {
  kbd_close();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<endln>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <kbd_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int endln() {
  kbd_close();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<endln>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <kbd_close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int endln() {
  kbd_close();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<immediate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L63:
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L75:
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L1:
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L62:
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <dump_imm@plt>
  addl   $0x1,-0x4(%rbp)
L48:
  cmpl   $0x7,-0x4(%rbp)
  jle    L62
  addl   $0x1,-0x8(%rbp)
L30:
  cmpl   $0x7,-0x8(%rbp)
  jle    L1
  addl   $0x1,-0xc(%rbp)
L36:
  cmpl   $0x2,-0xc(%rbp)
  jle    L75
  addl   $0x1,-0x10(%rbp)
L5:
  cmpl   $0x6,-0x10(%rbp)
  jle    L63
  nop
  nop
  leave
  ret
```

assistant: ```c
void immediate(void) {
  int type, size, mode, sreg;
  for (type = 0; type < 0x7; type++)
    for (size = 0; size < 3; size++)
      for (mode = 0; mode < 8; mode++)
        for (sreg = 0; sreg < 8; sreg++)
          dump_imm(type, size, mode, sreg);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<immediate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r13d
  jmp    L4
L55:
  add    $0x1,%r13d
  cmp    $0x7,%r13d
  je     L36
L4:
  mov    $0x0,%r12d
L52:
  mov    $0x0,%ebp
L48:
  mov    $0x0,%ebx
L2:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <dump_imm@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L2
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L48
  add    $0x1,%r12d
  cmp    $0x3,%r12d
  jne    L52
  jmp    L55
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void immediate(void) {
  int type, size, mode, sreg;
  for (type = 0; type < 0x7; type++)
    for (size = 0; size < 3; size++)
      for (mode = 0; mode < 8; mode++)
        for (sreg = 0; sreg < 8; sreg++)
          dump_imm(type, size, mode, sreg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<immediate>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L36:
  xor    %r12d,%r12d
L28:
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L31:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <dump_imm@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L37
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L31
  add    $0x1,%r12d
  cmp    $0x3,%r12d
  jne    L28
  add    $0x1,%r13d
  cmp    $0x7,%r13d
  jne    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void immediate(void) {
  int type, size, mode, sreg;
  for (type = 0; type < 0x7; type++)
    for (size = 0; size < 3; size++)
      for (mode = 0; mode < 8; mode++)
        for (sreg = 0; sreg < 8; sreg++)
          dump_imm(type, size, mode, sreg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<immediate>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L27:
  xor    %r12d,%r12d
L39:
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <dump_imm@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L29
  add    $0x1,%ebp
  cmp    $0x8,%ebp
  jne    L11
  add    $0x1,%r12d
  cmp    $0x3,%r12d
  jne    L39
  add    $0x1,%r13d
  cmp    $0x7,%r13d
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void immediate(void) {
  int type, size, mode, sreg;
  for (type = 0; type < 0x7; type++)
    for (size = 0; size < 3; size++)
      for (mode = 0; mode < 8; mode++)
        for (sreg = 0; sreg < 8; sreg++)
          dump_imm(type, size, mode, sreg);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x18,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%r12
  mov    %rax,0x0(%rbp)
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%rbx
  mov    %rax,0x8(%rbp)
  call   <malloc@plt>
  movsd  D29(%rip),%xmm0
  mov    $0x18,%edi
  movsd  D19(%rip),%xmm1
  movq   $0x0,(%r12)
  movq   $0x0,0x8(%r12)
  movq   $0x0,0x10(%r12)
  movsd  %xmm0,(%rbx)
  movsd  %xmm0,0x8(%rbx)
  movsd  %xmm0,0x10(%rbx)
  movsd  %xmm1,(%rax)
  movsd  %xmm1,0x8(%rax)
  movsd  %xmm1,0x10(%rax)
  mov    %rax,0x10(%rbp)
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,(%r12)
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x18,%edi
  mov    %rax,0x8(%r12)
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    D29(%rip),%rcx
  mov    %rbp,%rdi
  mov    D19(%rip),%rdx
  movq   $0x0,0x0(%r13)
  mov    $0x3,%esi
  movq   $0x0,0x8(%r13)
  movq   $0x0,0x10(%r13)
  mov    %rax,0x10(%r12)
  mov    %rcx,(%rbx)
  mov    %rcx,0x8(%rbx)
  mov    %rcx,0x10(%rbx)
  xor    %ebx,%ebx
  mov    %rdx,(%rax)
  mov    %rdx,0x8(%rax)
  mov    %rdx,0x10(%rax)
  mov    $0x3,%edx
  xor    %eax,%eax
  call   <printMat@plt>
  mov    $0x3,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    $0x3,%esi
  call   <printMat@plt>
  mov    $0x3,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    D29(%rip),%rax
  mov    $0x3,%r8d
  mov    $0x3,%esi
  movsd  D32(%rip),%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <kernel_perceptron@plt>
L8:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  cmp    $0x3,%rbx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D29
data_type: f64
name: unpack_data
arguments: data_label: D19
data_type: byte[8]
name: unpack_data
arguments: data_label: D32
data_type: f64

tool: D29: 1

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D32: 0.1

assistant: ```c
int main(int argc, char **argv) {
  unsigned long N = 3;
  double **weightVectors = (double **)malloc(N * sizeof(double *));
  unsigned long i = 0;
  unsigned long j = 0;
  for (i = 0; i < 3; i++)
    weightVectors[i] = (double *)malloc(3 * sizeof(double));
  for (i = 0; i < N; i++)
    for (j = 0; j < 3; weightVectors[i][j++] = i)
      ;
  double **learnSamples = (double **)malloc(N * sizeof(double *));
  for (i = 0; i < 3; i++)
    learnSamples[i] = (double *)malloc(3 * sizeof(double));
  for (i = 0; i < N; i++)
    for (j = 0; j < 3; learnSamples[i][j++] = i)
      ;
  printMat(weightVectors, N, 3);
  printMat(learnSamples, N, 3);
  double learnFactor = 1;
  double margin = 0.1;
  kernel_perceptron(weightVectors, N, learnSamples, N, learnFactor, margin, 3);
  for (i = 0; i < N; i++) {
    free(learnSamples[i]);
    free(weightVectors);
  }
  return 0;
}
```