ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<expr_print_gstr_helper>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <str_append@plt>
  test   %r12,%r12
  je     L5
  mov    %r12,%rdi
  call   <sym_get_string_value@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1090 <str_printf@plt>
  xchg   %ax,%ax
L5:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5:  [=%s]

assistant: ```c
void expr_print_gstr_helper(void *data, struct symbol *sym, const char *str) {
  str_append((struct gstr *)data, str);
  if (sym)
    str_printf((struct gstr *)data, " [=%s]", sym_get_string_value(sym));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<month_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L16
  cmpl   $0xc,-0x4(%rbp)
  jle    L27
L16:
  mov    D19(%rip),%rax
  jmp    L0
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D19(%rip),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
char *month_name(int n) {
  static char *name[] = {"Illigal month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? *name : *(name + n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0xb,%eax
  jbe    L7
  mov    D6(%rip),%rax
  ret
L7:
  movslq %edi,%rdi
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
char *month_name(int n) {
  static char *name[] = {"Illigal month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? *name : *(name + n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0xb,%eax
  jbe    L6
  mov    D9(%rip),%rax
  ret
  nopl   0x0(%rax)
L6:
  movslq %edi,%rdi
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
char *month_name(int n) {
  static char *name[] = {"Illigal month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? *name : *(name + n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<month_name>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0xb,%eax
  jbe    L3
  mov    D9(%rip),%rax
  ret
  nopl   0x0(%rax)
L3:
  movslq %edi,%rdi
  lea    D9(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
char *month_name(int n) {
  static char *name[] = {"Illigal month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
  return (n < 1 || n > 12) ? *name : *(name + n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Svcmd_CenterPrint_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <trap_Argc@plt>
  cmp    $0x1,%eax
  jg     L18
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <G_Printf@plt>
  jmp    L16
L18:
  mov    $0x1,%edi
  call   <ConcatArgs@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <va@plt>
  mov    %eax,%esi
  mov    $0xffffffff,%edi
  call   <trap_SendServerCommand@plt>
L16:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D1
data_type: string

tool: D10: usage: cp <message>


tool: D1: cp "%s"

assistant: ```c
void Svcmd_CenterPrint_f(void) {
  if (trap_Argc() < 2) {
    G_Printf("usage: cp <message>\n");
    return;
  }
  trap_SendServerCommand(-1, va("cp \"%s\"", ConcatArgs(1)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Svcmd_CenterPrint_f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <trap_Argc@plt>
  cmp    $0x1,%eax
  jle    L5
  mov    $0x1,%edi
  call   <ConcatArgs@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <va@plt>
  mov    %eax,%esi
  mov    $0xffffffff,%edi
  call   <trap_SendServerCommand@plt>
L9:
  add    $0x8,%rsp
  ret
L5:
  lea    D14(%rip),%rdi
  call   <G_Printf@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: label: D11
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string

tool: D11: cp "%s"

tool: D14: usage: cp <message>


assistant: ```c
void Svcmd_CenterPrint_f(void) {
  if (trap_Argc() < 2) {
    G_Printf("usage: cp <message>\n");
    return;
  }
  trap_SendServerCommand(-1, va("cp \"%s\"", ConcatArgs(1)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Svcmd_CenterPrint_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <trap_Argc@plt>
  cmp    $0x1,%eax
  jle    L1
  mov    $0x1,%edi
  call   <ConcatArgs@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <va@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    10b0 <trap_SendServerCommand@plt>
  nopl   0x0(%rax)
L1:
  lea    D16(%rip),%rdi
  add    $0x8,%rsp
  jmp    10d0 <G_Printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D15: cp "%s"

tool: D16: usage: cp <message>


assistant: ```c
void Svcmd_CenterPrint_f(void) {
  if (trap_Argc() < 2) {
    G_Printf("usage: cp <message>\n");
    return;
  }
  trap_SendServerCommand(-1, va("cp \"%s\"", ConcatArgs(1)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Svcmd_CenterPrint_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <trap_Argc@plt>
  cmp    $0x1,%eax
  jle    L4
  mov    $0x1,%edi
  call   <ConcatArgs@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <va@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    10b0 <trap_SendServerCommand@plt>
  nopl   0x0(%rax)
L4:
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    10d0 <G_Printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D12
type_guessed: string

tool: D2: cp "%s"

tool: D12: usage: cp <message>


assistant: ```c
void Svcmd_CenterPrint_f(void) {
  if (trap_Argc() < 2) {
    G_Printf("usage: cp <message>\n");
    return;
  }
  trap_SendServerCommand(-1, va("cp \"%s\"", ConcatArgs(1)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pmom_waketime_parse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x4,-0x20(%rbp)
  je     L17
  mov    $0xffffffff,%eax
  jmp    L14
L17:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x30(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,%ecx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    %eax,%ecx
  lea    D6(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1000,%esi
  call   <snprintf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: wake_acore_interval=%dsec


assistant: ```c
int pmom_waketime_parse(char *in_buf, size_t len, char *out_buf, unsigned int *out_ptr) {
  int data_len = 0;
  unsigned int *interval = (unsigned int *)in_buf;
  if (len != sizeof(*interval)) {
    return (int)(-1);
  }
  data_len = snprintf(&out_buf[*out_ptr], ((4096)), "wake_acore_interval=%dsec\n", *interval);
  *out_ptr = *out_ptr + data_len;
  return (int)(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pmom_waketime_parse>:
  endbr64
  cmp    $0x4,%rsi
  jne    L3
  push   %rbx
  mov    %rdi,%rax
  mov    %rcx,%rbx
  mov    (%rcx),%ecx
  lea    (%rdx,%rcx,1),%rdi
  mov    (%rax),%ecx
  lea    D7(%rip),%rdx
  mov    $0x1000,%esi
  call   <snprintf@plt>
  add    %eax,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: wake_acore_interval=%dsec


assistant: ```c
int pmom_waketime_parse(char *in_buf, size_t len, char *out_buf, unsigned int *out_ptr) {
  int data_len = 0;
  unsigned int *interval = (unsigned int *)in_buf;
  if (len != sizeof(*interval)) {
    return (int)(-1);
  }
  data_len = snprintf(&out_buf[*out_ptr], ((4096)), "wake_acore_interval=%dsec\n", *interval);
  *out_ptr = *out_ptr + data_len;
  return (int)(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pmom_waketime_parse>:
  endbr64
  cmp    $0x4,%rsi
  jne    L1
  push   %rbx
  mov    %rcx,%rbx
  mov    (%rcx),%ecx
  mov    %rdi,%rax
  mov    $0x1000,%esi
  lea    (%rdx,%rcx,1),%rdi
  mov    (%rax),%ecx
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  add    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: wake_acore_interval=%dsec


assistant: ```c
int pmom_waketime_parse(char *in_buf, size_t len, char *out_buf, unsigned int *out_ptr) {
  int data_len = 0;
  unsigned int *interval = (unsigned int *)in_buf;
  if (len != sizeof(*interval)) {
    return (int)(-1);
  }
  data_len = snprintf(&out_buf[*out_ptr], ((4096)), "wake_acore_interval=%dsec\n", *interval);
  *out_ptr = *out_ptr + data_len;
  return (int)(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<pmom_waketime_parse>:
  endbr64
  cmp    $0x4,%rsi
  jne    L6
  push   %rbx
  mov    %rcx,%rbx
  mov    (%rcx),%ecx
  mov    %rdi,%rax
  mov    $0x1000,%esi
  lea    (%rdx,%rcx,1),%rdi
  mov    (%rax),%ecx
  lea    D2(%rip),%rdx
  call   <snprintf@plt>
  add    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: wake_acore_interval=%dsec


assistant: ```c
int pmom_waketime_parse(char *in_buf, size_t len, char *out_buf, unsigned int *out_ptr) {
  int data_len = 0;
  unsigned int *interval = (unsigned int *)in_buf;
  if (len != sizeof(*interval)) {
    return (int)(-1);
  }
  data_len = snprintf(&out_buf[*out_ptr], ((4096)), "wake_acore_interval=%dsec\n", *interval);
  *out_ptr = *out_ptr + data_len;
  return (int)(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<manhattan_dist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double manhattan_dist(double *x1, double *x2, int size) {
  double d = 0;
  for (int i = 0; i < size; i++)
    d += fabs(x1[i] - x2[i]);
  return (d);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<manhattan_dist>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  jle    L25
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
L13:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
L18:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L18
```

assistant: ```c
double manhattan_dist(double *x1, double *x2, int size) {
  double d = 0;
  for (int i = 0; i < size; i++)
    d += fabs(x1[i] - x2[i]);
  return (d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<manhattan_dist>:
  endbr64
  test   %edx,%edx
  jle    L15
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L12:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L12
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double manhattan_dist(double *x1, double *x2, int size) {
  double d = 0;
  for (int i = 0; i < size; i++)
    d += fabs(x1[i] - x2[i]);
  return (d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<manhattan_dist>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L3:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm1,0x8(%rsp)
  add    $0x1,%rbx
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L3
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double manhattan_dist(double *x1, double *x2, int size) {
  double d = 0;
  for (int i = 0; i < size; i++)
    d += fabs(x1[i] - x2[i]);
  return (d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1f4,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0xfb0(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x79,%edi
  call   <min_terms@plt>
  mov    %eax,-0xfb4(%rbp)
  mov    -0xfb4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: Min perfet square terms reqiured are %d

assistant: ```c
void main() {
  int table[1000] = {0};
  int res = min_terms(121, 0, table);
  printf("Min perfet square terms reqiured are %d", res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdx
  mov    $0x0,%esi
  mov    $0x79,%edi
  call   <min_terms@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xfb8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: Min perfet square terms reqiured are %d

assistant: ```c
void main() {
  int table[1000] = {0};
  int res = min_terms(121, 0, table);
  printf("Min perfet square terms reqiured are %d", res);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x1f4,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rdx
  rep stos %rax,%es:(%rdi)
  mov    $0x79,%edi
  call   <min_terms@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xfb8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: Min perfet square terms reqiured are %d

assistant: ```c
void main() {
  int table[1000] = {0};
  int res = min_terms(121, 0, table);
  printf("Min perfet square terms reqiured are %d", res);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0xfb8,%rsp
  mov    $0x1f4,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rdx
  rep stos %rax,%es:(%rdi)
  mov    $0x79,%edi
  call   <min_terms@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xfb8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: Min perfet square terms reqiured are %d

assistant: ```c
void main() {
  int table[1000] = {0};
  int res = min_terms(121, 0, table);
  printf("Min perfet square terms reqiured are %d", res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_hex_palindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L20
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  sub    -0x24(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x24(%rbp)
L20:
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L5
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: %llX

assistant: ```c
int is_hex_palindrome(unsigned long long number) {
  char *string;
  char *reversed_string;
  asprintf(&string, "%llX", number);
  int size = (int)strlen(string);
  reversed_string = (char *)malloc(size + 1 * sizeof(char));
  for (int i = 0; i < size; ++i) {
    reversed_string[i] = string[size - i - 1];
  }
  reversed_string[size] = '\0';
  int result = (strcmp(string, reversed_string) == 0) ? 1 : 0;
  free(string);
  free(reversed_string);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_hex_palindrome>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D5(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L11
  movslq %ebx,%rdx
  lea    -0x1(%rdx),%rax
  lea    -0x2(%rdx),%rsi
  lea    -0x1(%rbx),%ecx
  sub    %rcx,%rsi
  lea    -0x1(%rbp,%rdx,1),%rdi
L23:
  mov    (%rsp),%rdx
  movzbl (%rdx,%rax,1),%ecx
  mov    %rdi,%rdx
  sub    %rax,%rdx
  mov    %cl,(%rdx)
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jne    L23
L11:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <strcmp@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  test   %rbx,%rbx
  sete   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: %llX

assistant: ```c
int is_hex_palindrome(unsigned long long number) {
  char *string;
  char *reversed_string;
  asprintf(&string, "%llX", number);
  int size = (int)strlen(string);
  reversed_string = (char *)malloc(size + 1 * sizeof(char));
  for (int i = 0; i < size; ++i) {
    reversed_string[i] = string[size - i - 1];
  }
  reversed_string[size] = '\0';
  int result = (strcmp(string, reversed_string) == 0) ? 1 : 0;
  free(string);
  free(reversed_string);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_hex_palindrome>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D3(%rip),%rsi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  movslq %ebx,%r8
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L9
  lea    -0x2(%r8),%rsi
  lea    -0x1(%rbx),%edx
  lea    -0x1(%r8),%rax
  sub    %rdx,%rsi
  lea    -0x1(%rbp,%r8,1),%rdi
  nopl   (%rax)
L7:
  mov    (%rsp),%rdx
  movzbl (%rdx,%rax,1),%ecx
  mov    %rdi,%rdx
  sub    %rax,%rdx
  sub    $0x1,%rax
  mov    %cl,(%rdx)
  cmp    %rsi,%rax
  jne    L7
L9:
  movb   $0x0,0x0(%rbp,%r8,1)
  mov    (%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbx
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: %llX

assistant: ```c
int is_hex_palindrome(unsigned long long number) {
  char *string;
  char *reversed_string;
  asprintf(&string, "%llX", number);
  int size = (int)strlen(string);
  reversed_string = (char *)malloc(size + 1 * sizeof(char));
  for (int i = 0; i < size; ++i) {
    reversed_string[i] = string[size - i - 1];
  }
  reversed_string[size] = '\0';
  int result = (strcmp(string, reversed_string) == 0) ? 1 : 0;
  free(string);
  free(reversed_string);
  return result;
}
```