ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<fn2>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int fn2(int x) {
  int i = x;
  inline __attribute__((always_inline)) int should_not_appear2(void) { return i; }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L0
L89:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  cmpl   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x9,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
L7:
  cmpl   $0x0,-0xc(%rbp)
  je     L21
  cmpl   $0x9,-0x4(%rbp)
  jne    L26
  mov    $0x9,%edi
  call   <putchar@plt>
  jmp    L87
L26:
  cmpl   $0x20,-0x4(%rbp)
  je     L87
  mov    $0x4,%eax
  sub    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  jmp    L8
L27:
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x0,-0xc(%rbp)
  jne    L27
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L87
L21:
  cmpl   $0x20,-0x4(%rbp)
  jne    L140
  mov    $0x4,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L87
L140:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L87:
  cmpl   $0x9,-0x4(%rbp)
  je     L44
  cmpl   $0xa,-0x4(%rbp)
  jne    L0
L44:
  movl   $0x0,-0xc(%rbp)
  movl   $0x3,-0x8(%rbp)
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L89
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c, spaceHeld = 0, count = 3;
  while ((c = getchar()) != EOF) {
    count = (count + 1) % 4;
    if (spaceHeld != 0 && count == 0) {
      putchar('\t');
      spaceHeld = 0;
    }
    if (spaceHeld != 0) {
      if (c == '\t')
        putchar('\t');
      else if (c != ' ') {
        spaceHeld -= 4 - count;
        for (; spaceHeld != 0; --spaceHeld)
          putchar(' ');
        putchar(c);
      }
    } else if (c == ' ') {
      spaceHeld = 4 - count;
    } else
      putchar(c);
    if (c == '\t' || c == '\n') {
      spaceHeld = 0;
      count = 3;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x3,%r14d
  mov    $0x0,%r12d
  mov    $0x3,%r13d
  jmp    L34
L79:
  mov    $0x9,%edi
  call   <putchar@plt>
L86:
  cmp    $0x20,%ebx
  jne    L26
  mov    $0x4,%r12d
  sub    %ebp,%r12d
  jmp    L34
L67:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x3,%r14d
  mov    $0x0,%r12d
  jmp    L34
L26:
  mov    %ebx,%edi
  call   <putchar@plt>
L40:
  sub    $0x9,%ebx
  cmp    $0x1,%ebx
  cmovbe %r13d,%r14d
  mov    $0x0,%r12d
L34:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  je     L121
  lea    0x1(%r14),%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rdx,%rax,1),%ebp
  and    $0x3,%ebp
  sub    %eax,%ebp
  mov    %ebp,%r14d
  test   $0x3,%dl
  jne    L58
  test   %r12d,%r12d
  jne    L79
L58:
  test   %r12d,%r12d
  je     L86
  cmp    $0x9,%ebx
  je     L67
  cmp    $0x20,%ebx
  je     L34
  lea    -0x4(%r12,%rbp,1),%ebp
  test   %ebp,%ebp
  je     L89
L112:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L112
L89:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L40
L121:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main() {
  int c, spaceHeld = 0, count = 3;
  while ((c = getchar()) != EOF) {
    count = (count + 1) % 4;
    if (spaceHeld != 0 && count == 0) {
      putchar('\t');
      spaceHeld = 0;
    }
    if (spaceHeld != 0) {
      if (c == '\t')
        putchar('\t');
      else if (c != ' ') {
        spaceHeld -= 4 - count;
        for (; spaceHeld != 0; --spaceHeld)
          putchar(' ');
        putchar(c);
      }
    } else if (c == ' ') {
      spaceHeld = 4 - count;
    } else
      putchar(c);
    if (c == '\t' || c == '\n') {
      spaceHeld = 0;
      count = 3;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    D6(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  nopl   0x0(%rax)
L49:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L2
L29:
  add    $0x1,%ebp
  and    $0x3,%ebp
  jne    L54
  test   %r14d,%r14d
  je     L65
  mov    $0x9,%edi
  call   <putchar@plt>
L65:
  cmp    $0x20,%ebx
  jne    L114
  xor    %eax,%eax
  mov    $0x4,%r14d
  call   <getchar@plt>
  sub    %ebp,%r14d
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L29
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  test   %r14d,%r14d
  je     L65
  cmp    $0x9,%ebx
  je     L69
  cmp    $0x20,%ebx
  je     L49
  lea    -0x4(%r14,%rbp,1),%r14d
  test   %r14d,%r14d
  je     L114
  nopl   0x0(%rax)
L33:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r14d
  jne    L33
L114:
  mov    %ebx,%edi
  sub    $0x9,%ebx
  call   <putchar@plt>
  cmp    $0x1,%ebx
  cmovbe %r13d,%ebp
  xor    %r14d,%r14d
  jmp    L49
L69:
  mov    $0x9,%edi
  mov    $0x3,%ebp
  xor    %r14d,%r14d
  call   <putchar@plt>
  jmp    L49
```

assistant: ```c
int main() {
  int c, spaceHeld = 0, count = 3;
  while ((c = getchar()) != EOF) {
    count = (count + 1) % 4;
    if (spaceHeld != 0 && count == 0) {
      putchar('\t');
      spaceHeld = 0;
    }
    if (spaceHeld != 0) {
      if (c == '\t')
        putchar('\t');
      else if (c != ' ') {
        spaceHeld -= 4 - count;
        for (; spaceHeld != 0; --spaceHeld)
          putchar(' ');
        putchar(c);
      }
    } else if (c == ' ') {
      spaceHeld = 4 - count;
    } else
      putchar(c);
    if (c == '\t' || c == '\n') {
      spaceHeld = 0;
      count = 3;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    $0x3,%r13d
  push   %r12
  mov    D0(%rip),%r12
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  nopl   0x0(%rax)
L92:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  je     L37
L61:
  add    $0x1,%ebp
  and    $0x3,%ebp
  jne    L96
  test   %r14d,%r14d
  je     L102
  mov    $0x9,%edi
  call   <putchar@plt>
L102:
  cmp    $0x20,%ebx
  jne    L45
  xor    %eax,%eax
  mov    $0x4,%r14d
  call   <getchar@plt>
  sub    %ebp,%r14d
  mov    %eax,%ebx
  cmp    %eax,(%r12)
  jne    L61
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L96:
  test   %r14d,%r14d
  je     L102
  cmp    $0x9,%ebx
  je     L56
  cmp    $0x20,%ebx
  je     L92
  lea    -0x4(%r14,%rbp,1),%r14d
  test   %r14d,%r14d
  je     L45
  nopl   0x0(%rax)
L109:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r14d
  jne    L109
L45:
  mov    %ebx,%edi
  sub    $0x9,%ebx
  call   <putchar@plt>
  cmp    $0x1,%ebx
  cmovbe %r13d,%ebp
  xor    %r14d,%r14d
  jmp    L92
L56:
  mov    $0x9,%edi
  mov    $0x3,%ebp
  xor    %r14d,%r14d
  call   <putchar@plt>
  jmp    L92
```

assistant: ```c
int main() {
  int c, spaceHeld = 0, count = 3;
  while ((c = getchar()) != EOF) {
    count = (count + 1) % 4;
    if (spaceHeld != 0 && count == 0) {
      putchar('\t');
      spaceHeld = 0;
    }
    if (spaceHeld != 0) {
      if (c == '\t')
        putchar('\t');
      else if (c != ' ') {
        spaceHeld -= 4 - count;
        for (; spaceHeld != 0; --spaceHeld)
          putchar(' ');
        putchar(c);
      }
    } else if (c == ' ') {
      spaceHeld = 4 - count;
    } else
      putchar(c);
    if (c == '\t' || c == '\n') {
      spaceHeld = 0;
      count = 3;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_ncpus_proc_cpuinfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
  mov    $0xffffffffffffffff,%rax
  jmp    L19
L15:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_get_ncpus_proc_cpuinfo@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: r

assistant: ```c
long get_ncpus_proc_cpuinfo(const char *path) {
  FILE *cpuinfo_fp = fopen(path, "r");
  if (cpuinfo_fp == NULL) {
    return -1;
  }
  long ncpus = _get_ncpus_proc_cpuinfo(cpuinfo_fp);
  fclose(cpuinfo_fp);
  return ncpus;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_ncpus_proc_cpuinfo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <_get_ncpus_proc_cpuinfo@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fclose@plt>
L1:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0xffffffffffffffff,%rbp
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: r

assistant: ```c
long get_ncpus_proc_cpuinfo(const char *path) {
  FILE *cpuinfo_fp = fopen(path, "r");
  if (cpuinfo_fp == NULL) {
    return -1;
  }
  long ncpus = _get_ncpus_proc_cpuinfo(cpuinfo_fp);
  fclose(cpuinfo_fp);
  return ncpus;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_ncpus_proc_cpuinfo>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <_get_ncpus_proc_cpuinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffffffffffff,%r12
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: r

assistant: ```c
long get_ncpus_proc_cpuinfo(const char *path) {
  FILE *cpuinfo_fp = fopen(path, "r");
  if (cpuinfo_fp == NULL) {
    return -1;
  }
  long ncpus = _get_ncpus_proc_cpuinfo(cpuinfo_fp);
  fclose(cpuinfo_fp);
  return ncpus;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_ncpus_proc_cpuinfo>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <_get_ncpus_proc_cpuinfo@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    $0xffffffffffffffff,%r12
  jmp    L1
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: r

assistant: ```c
long get_ncpus_proc_cpuinfo(const char *path) {
  FILE *cpuinfo_fp = fopen(path, "r");
  if (cpuinfo_fp == NULL) {
    return -1;
  }
  long ncpus = _get_ncpus_proc_cpuinfo(cpuinfo_fp);
  fclose(cpuinfo_fp);
  return ncpus;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<absentSurColonne>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L28
L1:
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x8,-0x4(%rbp)
  jle    L4
  mov    $0x1,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
bool absentSurColonne(int k, int grille[9][9], int j) {
  for (int i = 0; i < 9; i++)
    if (grille[i][j] == k)
      return false;
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<absentSurColonne>:
  endbr64
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rsi,%rdx,1),%rax
  lea    0x144(%rsi,%rdx,1),%rdx
L4:
  cmp    %edi,(%rax)
  je     L18
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    $0x1,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool absentSurColonne(int k, int grille[9][9], int j) {
  for (int i = 0; i < 9; i++)
    if (grille[i][j] == k)
      return false;
  return true;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<absentSurColonne>:
  endbr64
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rsi,%rdx,1),%rax
  lea    0x144(%rsi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    %edi,(%rax)
  je     L17
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool absentSurColonne(int k, int grille[9][9], int j) {
  for (int i = 0; i < 9; i++)
    if (grille[i][j] == k)
      return false;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<absentSurColonne>:
  endbr64
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  cmp    (%rsi,%rdx,4),%edi
  je     L75
  cmp    0x24(%rsi,%rax,1),%edi
  je     L75
  cmp    0x48(%rsi,%rax,1),%edi
  je     L75
  cmp    0x6c(%rsi,%rax,1),%edi
  je     L75
  cmp    0x90(%rsi,%rax,1),%edi
  je     L75
  cmp    0xb4(%rsi,%rax,1),%edi
  je     L75
  cmp    0xd8(%rsi,%rax,1),%edi
  je     L75
  cmp    0xfc(%rsi,%rax,1),%edi
  je     L75
  cmp    %edi,0x120(%rsi,%rax,1)
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool absentSurColonne(int k, int grille[9][9], int j) {
  for (int i = 0; i < 9; i++)
    if (grille[i][j] == k)
      return false;
  return true;
}
```
user: What is the c source code of the assembly code below:

```asm
<systemd_sock_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int systemd_sock_get(struct Server *s) {
  int n = 0;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<systemd_sock_get>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int systemd_sock_get(struct Server *s) {
  int n = 0;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<systemd_sock_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int systemd_sock_get(struct Server *s) {
  int n = 0;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<systemd_sock_get>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int systemd_sock_get(struct Server *s) {
  int n = 0;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fftCosInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  movss  D1(%rip),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x1,-0x18(%rbp)
  jmp    L3
L58:
  mov    -0x18(%rbp),%eax
  test   %rax,%rax
  js     L8
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L47
L8:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L47:
  movsd  D8(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  test   %rax,%rax
  js     L54
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L43
L54:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L43:
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    -0x18(%rbp),%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addl   $0x1,-0x18(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  shr    $0x2,%eax
  cmp    %eax,-0x18(%rbp)
  jb     L58
  mov    -0x14(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: f32
name: disassemble_data
arguments: label: D8
type_guessed: byte[8]

tool: D1: 1

tool: {"D8": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void fftCosInit(int M, float *Utbl) {
  unsigned int fftN = ((unsigned long)1 << (M));
  unsigned int i1;
  Utbl[0] = 1.0;
  for (i1 = 1; i1 < fftN / 4; i1++)
    Utbl[i1] = cos((2.0 * 3.141592653589793238462643383279502884197 * i1) / fftN);
  Utbl[fftN / 4] = 0.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fftCosInit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%rax
  movl   $0x3f800000,(%rsi)
  mov    %eax,%r12d
  shr    $0x2,%r12d
  cmp    $0x7,%eax
  jbe    L18
  mov    $0x1,%ebx
  mov    %eax,%edx
  pxor   %xmm2,%xmm2
  cvtsi2sd %rdx,%xmm2
  movsd  %xmm2,0x8(%rsp)
L11:
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  ja     L11
L18:
  mov    %r12d,%r12d
  movl   $0x0,0x0(%rbp,%r12,4)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: byte[8]

tool: {"D1": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void fftCosInit(int M, float *Utbl) {
  unsigned int fftN = ((unsigned long)1 << (M));
  unsigned int i1;
  Utbl[0] = 1.0;
  for (i1 = 1; i1 < fftN / 4; i1++)
    Utbl[i1] = cos((2.0 * 3.141592653589793238462643383279502884197 * i1) / fftN);
  Utbl[fftN / 4] = 0.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fftCosInit>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  mov    %edi,%ecx
  push   %rbp
  shl    %cl,%rax
  mov    %rsi,%rbp
  push   %rbx
  mov    %eax,%r12d
  shr    $0x2,%r12d
  sub    $0x10,%rsp
  movl   $0x3f800000,(%rsi)
  cmp    $0x7,%eax
  jbe    L15
  mov    %eax,%eax
  pxor   %xmm2,%xmm2
  mov    $0x1,%ebx
  cvtsi2sd %rax,%xmm2
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax)
L8:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D8(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L8
L15:
  movl   $0x0,0x0(%rbp,%r12,4)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: byte[8]

tool: {"D8": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void fftCosInit(int M, float *Utbl) {
  unsigned int fftN = ((unsigned long)1 << (M));
  unsigned int i1;
  Utbl[0] = 1.0;
  for (i1 = 1; i1 < fftN / 4; i1++)
    Utbl[i1] = cos((2.0 * 3.141592653589793238462643383279502884197 * i1) / fftN);
  Utbl[fftN / 4] = 0.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fftCosInit>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  mov    %edi,%ecx
  push   %rbp
  shl    %cl,%rax
  mov    %rsi,%rbp
  push   %rbx
  mov    %eax,%r12d
  shr    $0x2,%r12d
  sub    $0x10,%rsp
  movl   $0x3f800000,(%rsi)
  cmp    $0x7,%eax
  jbe    L6
  mov    %eax,%eax
  pxor   %xmm2,%xmm2
  mov    $0x1,%ebx
  cvtsi2sd %rax,%xmm2
  movsd  %xmm2,0x8(%rsp)
  nopl   0x0(%rax)
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D5(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L18
L6:
  movl   $0x0,0x0(%rbp,%r12,4)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: byte[8]

tool: {"D5": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
void fftCosInit(int M, float *Utbl) {
  unsigned int fftN = ((unsigned long)1 << (M));
  unsigned int i1;
  Utbl[0] = 1.0;
  for (i1 = 1; i1 < fftN / 4; i1++)
    Utbl[i1] = cos((2.0 * 3.141592653589793238462643383279502884197 * i1) / fftN);
  Utbl[fftN / 4] = 0.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L24
L18:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <re_comp@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x14(%rbp)
L35:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <re_exec@plt>
  test   %eax,%eax
  jne    L19
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x14(%rbp)
L19:
  addq   $0x1,-0x10(%rbp)
L24:
  cmpq   $0x63,-0x10(%rbp)
  jbe    L18
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D34
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D5
type_infered: string
name: disassemble_data
arguments: tag: D30
type_infered: string

tool: D34: a t.st

tool: D39: re_comp failed: %s


tool: D5: This is a test.

tool: D30: re_exec failed

assistant: ```c
int main(void) {
  const char *err;
  size_t i;
  int ret = 0;
  for (i = 0; i < 100; ++i) {
    err = re_comp("a t.st");
    if (err) {
      printf("re_comp failed: %s\n", err);
      ret = 1;
    }
    if (!re_exec("This is a test.")) {
      printf("re_exec failed\n");
      ret = 1;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebx
  mov    $0x0,%r13d
  lea    D25(%rip),%r12
  lea    D2(%rip),%r14
  lea    D24(%rip),%rbp
  lea    D0(%rip),%r15
  jmp    L44
L52:
  mov    %rbp,%rdi
  call   <re_exec@plt>
  test   %eax,%eax
  je     L51
L9:
  sub    $0x1,%rbx
  je     L31
L44:
  mov    %r12,%rdi
  call   <re_comp@plt>
  test   %rax,%rax
  je     L52
  mov    %rax,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%r13d
  jmp    L52
L51:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    $0x1,%r13d
  jmp    L9
L31:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D24
data_type: string
name: parse_data
arguments: label: D0
data_type: string

tool: D25: a t.st

tool: D2: re_comp failed: %s


tool: D24: This is a test.

tool: D0: re_exec failed

assistant: ```c
int main(void) {
  const char *err;
  size_t i;
  int ret = 0;
  for (i = 0; i < 100; ++i) {
    err = re_comp("a t.st");
    if (err) {
      printf("re_comp failed: %s\n", err);
      ret = 1;
    }
    if (!re_exec("This is a test.")) {
      printf("re_exec failed\n");
      ret = 1;
    }
  }
  return ret;
}
```