ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xe(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L6:
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xe(%rbp),%eax
  cmp    $0xa,%al
  je     L4
  movzbl -0xe(%rbp),%eax
  movsbl %al,%eax
  add    %eax,-0xc(%rbp)
L4:
  movzbl -0xe(%rbp),%eax
  cmp    $0xa,%al
  jne    L6
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %al,-0xd(%rbp)
  movzbl -0xd(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D34: Enter an abitrarily long string, ending with carriage return > 

tool: D38: %c

tool: D13: Check sum is %c


assistant: ```c
int main() {
  int num;
  char i;
  char final;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  scanf("%c", &i);
  num = i;
  while (i != '\n') {
    scanf("%c", &i);
    if (i != '\n') {
      num += i;
    }
  }
  final = num % 64;
  final += ' ';
  printf("Check sum is %c\n", final);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  movsbl %al,%ebx
  cmp    $0xa,%al
  je     L17
  lea    D2(%rip),%rbp
L23:
  lea    0x7(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L17
  movsbl %al,%eax
  add    %eax,%ebx
  jmp    L23
L17:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  add    $0x20,%esi
  movsbl %sil,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string

tool: D9: Enter an abitrarily long string, ending with carriage return > 

tool: D2: %c

tool: D23: Check sum is %c


assistant: ```c
int main() {
  int num;
  char i;
  char final;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  scanf("%c", &i);
  num = i;
  while (i != '\n') {
    scanf("%c", &i);
    if (i != '\n') {
      num += i;
    }
  }
  final = num % 64;
  final += ' ';
  printf("Check sum is %c\n", final);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%ebx
  cmp    $0xa,%bl
  je     L22
  nopl   0x0(%rax)
L20:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L2
  add    %eax,%ebx
  jmp    L20
L22:
  mov    $0xa,%ebx
  nopl   (%rax)
L2:
  mov    %ebx,%eax
  lea    D27(%rip),%rdi
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x20,%esi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D27
datatype: string

tool: D18: Enter an abitrarily long string, ending with carriage return > 

tool: D29: %c

tool: D27: Check sum is %c


assistant: ```c
int main() {
  int num;
  char i;
  char final;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  scanf("%c", &i);
  num = i;
  while (i != '\n') {
    scanf("%c", &i);
    if (i != '\n') {
      num += i;
    }
  }
  final = num % 64;
  final += ' ';
  printf("Check sum is %c\n", final);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%ebx
  cmp    $0xa,%bl
  je     L35
  nopl   0x0(%rax)
L1:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%eax
  cmp    $0xa,%al
  je     L37
  add    %eax,%ebx
  jmp    L1
L35:
  mov    $0xa,%ebx
  nopl   (%rax)
L37:
  mov    %ebx,%eax
  lea    D26(%rip),%rdi
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x3f,%esi
  sub    %eax,%esi
  xor    %eax,%eax
  add    $0x20,%esi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string

tool: D5: Enter an abitrarily long string, ending with carriage return > 

tool: D28: %c

tool: D26: Check sum is %c


assistant: ```c
int main() {
  int num;
  char i;
  char final;
  printf("Enter an abitrarily long string, ending with carriage return > ");
  scanf("%c", &i);
  num = i;
  while (i != '\n') {
    scanf("%c", &i);
    if (i != '\n') {
      num += i;
    }
  }
  final = num % 64;
  final += ' ';
  printf("Check sum is %c\n", final);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mask@plt>
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mask@plt>
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L11
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L11:
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  or     %edx,%eax
  xor    %eax,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string

tool: D7: Swapping is not required


assistant: ```c
int swap_bits(int f_num, int f_src_pos, int f_dst_pos) {
  int mask1;
  int mask2;
  mask1 = (f_num & (mask(f_src_pos, 1)));
  mask2 = (f_num & (mask(f_dst_pos, 1)));
  if (mask1 == mask2) {
    printf("Swapping is not required\n");
  } else {
    f_num = f_num ^ ((1 << f_src_pos) | (1 << f_dst_pos));
  }
  return f_num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap_bits>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <mask@plt>
  mov    %eax,%ebx
  mov    $0x1,%esi
  mov    %r13d,%edi
  call   <mask@plt>
  xor    %eax,%ebx
  test   %ebp,%ebx
  je     L8
  mov    $0x1,%eax
  mov    %r13d,%ecx
  shl    %cl,%eax
  bts    %r12d,%eax
  xor    %ebp,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%eax
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: Swapping is not required


assistant: ```c
int swap_bits(int f_num, int f_src_pos, int f_dst_pos) {
  int mask1;
  int mask2;
  mask1 = (f_num & (mask(f_src_pos, 1)));
  mask2 = (f_num & (mask(f_dst_pos, 1)));
  if (mask1 == mask2) {
    printf("Swapping is not required\n");
  } else {
    f_num = f_num ^ ((1 << f_src_pos) | (1 << f_dst_pos));
  }
  return f_num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_bits>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x1,%esi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <mask@plt>
  mov    $0x1,%esi
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <mask@plt>
  xor    %eax,%ebx
  test   %ebp,%ebx
  je     L2
  mov    %r12d,%ecx
  mov    $0x1,%eax
  add    $0x8,%rsp
  shl    %cl,%eax
  pop    %rbx
  bts    %r13d,%eax
  xor    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Swapping is not required


assistant: ```c
int swap_bits(int f_num, int f_src_pos, int f_dst_pos) {
  int mask1;
  int mask2;
  mask1 = (f_num & (mask(f_src_pos, 1)));
  mask2 = (f_num & (mask(f_dst_pos, 1)));
  if (mask1 == mask2) {
    printf("Swapping is not required\n");
  } else {
    f_num = f_num ^ ((1 << f_src_pos) | (1 << f_dst_pos));
  }
  return f_num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap_bits>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    $0x1,%esi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <mask@plt>
  mov    $0x1,%esi
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <mask@plt>
  xor    %eax,%ebx
  test   %ebp,%ebx
  je     L6
  mov    %r12d,%ecx
  mov    $0x1,%eax
  add    $0x8,%rsp
  shl    %cl,%eax
  pop    %rbx
  bts    %r13d,%eax
  xor    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: Swapping is not required


assistant: ```c
int swap_bits(int f_num, int f_src_pos, int f_dst_pos) {
  int mask1;
  int mask2;
  mask1 = (f_num & (mask(f_src_pos, 1)));
  mask2 = (f_num & (mask(f_dst_pos, 1)));
  if (mask1 == mask2) {
    printf("Swapping is not required\n");
  } else {
    f_num = f_num ^ ((1 << f_src_pos) | (1 << f_dst_pos));
  }
  return f_num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<branchfree_search2_prefetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  test   %rsi,%rsi
  je     L13
  mov    %rsi,%rbp
  cmp    $0x1,%rsi
  jbe    L20
  mov    %rdi,%r12
  mov    %rdi,%r13
L14:
  mov    %rbp,%r15
  shr    %r15
  mov    %rbp,%rbx
  shr    $0x2,%rbx
  mov    %rbp,%r14
  and    $0xfffffffffffffffc,%r14
  lea    0x0(%r13,%r14,1),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <__builtin_prefetch@plt>
  add    %r15,%rbx
  shl    $0x2,%rbx
  lea    0x0(%r13,%rbx,1),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <__builtin_prefetch@plt>
  lea    (%r12,%r14,1),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <__builtin_prefetch@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <__builtin_prefetch@plt>
  lea    0x0(,%r15,4),%rax
  lea    0x0(%r13,%rax,1),%rdx
  mov    (%rsp),%ecx
  cmp    %ecx,(%rdx)
  cmovl  %rdx,%r13
  add    %r12,%rax
  mov    0x4(%rsp),%ecx
  cmp    %ecx,(%rax)
  cmovl  %rax,%r12
  sub    %r15,%rbp
  cmp    $0x1,%rbp
  ja     L14
L12:
  mov    (%rsp),%eax
  cmp    %eax,0x0(%r13)
  setl   %al
  movzbl %al,%eax
  lea    0x0(%r13,%rax,4),%rax
  mov    0x8(%rsp),%rcx
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    0x10(%rsp),%rsi
  mov    %rax,(%rsi)
  mov    0x4(%rsp),%eax
  cmp    %eax,(%r12)
  setl   %al
  movzbl %al,%eax
  lea    (%r12,%rax,4),%rax
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    0x18(%rsp),%rsi
  mov    %rax,(%rsi)
L13:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  mov    0x8(%rsp),%r13
  mov    %r13,%r12
  jmp    L12
```

assistant: ```c
void branchfree_search2_prefetch(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    __builtin_prefetch(base1 + (half >> 1), 0, 0);
    __builtin_prefetch(base1 + half + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + half + (half >> 1), 0, 0);
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<branchfree_search2_prefetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  test   %rsi,%rsi
  je     L25
  mov    %rsi,%r13
  cmp    $0x1,%rsi
  je     L30
  mov    %rdi,%rbp
  mov    %rdi,%r15
  nopl   0x0(%rax)
L17:
  mov    %r13,%r12
  mov    %r13,%rbx
  mov    %r13,%r14
  xor    %edx,%edx
  shr    %r12
  shr    $0x2,%rbx
  and    $0xfffffffffffffffc,%r14
  xor    %esi,%esi
  add    %r12,%rbx
  lea    (%r15,%r14,1),%rdi
  call   <__builtin_prefetch@plt>
  shl    $0x2,%rbx
  xor    %edx,%edx
  xor    %esi,%esi
  lea    (%r15,%rbx,1),%rdi
  call   <__builtin_prefetch@plt>
  lea    0x0(%rbp,%r14,1),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <__builtin_prefetch@plt>
  xor    %edx,%edx
  lea    0x0(%rbp,%rbx,1),%rdi
  xor    %esi,%esi
  call   <__builtin_prefetch@plt>
  lea    0x0(,%r12,4),%rax
  mov    (%rsp),%ecx
  lea    (%r15,%rax,1),%rdx
  cmp    %ecx,(%rdx)
  mov    0x4(%rsp),%ecx
  cmovl  %rdx,%r15
  add    %rbp,%rax
  cmp    %ecx,(%rax)
  cmovl  %rax,%rbp
  sub    %r12,%r13
  cmp    $0x1,%r13
  ja     L17
L19:
  mov    (%rsp),%eax
  cmp    %eax,(%r15)
  setl   %al
  mov    0x8(%rsp),%rcx
  mov    0x10(%rsp),%rsi
  movzbl %al,%eax
  lea    (%r15,%rax,4),%rax
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    %rax,(%rsi)
  mov    0x4(%rsp),%eax
  cmp    %eax,0x0(%rbp)
  mov    0x18(%rsp),%rsi
  setl   %al
  movzbl %al,%eax
  lea    0x0(%rbp,%rax,4),%rax
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    %rax,(%rsi)
L25:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x8(%rsp),%r15
  mov    %r15,%rbp
  jmp    L19
```

assistant: ```c
void branchfree_search2_prefetch(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    __builtin_prefetch(base1 + (half >> 1), 0, 0);
    __builtin_prefetch(base1 + half + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + half + (half >> 1), 0, 0);
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<branchfree_search2_prefetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  test   %rsi,%rsi
  je     L13
  mov    %rsi,%r13
  cmp    $0x1,%rsi
  je     L1
  mov    %rdi,%rbp
  mov    %rdi,%r15
  nopl   0x0(%rax)
L32:
  mov    %r13,%r12
  mov    %r13,%rbx
  mov    %r13,%r14
  xor    %edx,%edx
  shr    %r12
  shr    $0x2,%rbx
  and    $0xfffffffffffffffc,%r14
  xor    %esi,%esi
  add    %r12,%rbx
  lea    (%r15,%r14,1),%rdi
  call   <__builtin_prefetch@plt>
  shl    $0x2,%rbx
  xor    %edx,%edx
  xor    %esi,%esi
  lea    (%r15,%rbx,1),%rdi
  call   <__builtin_prefetch@plt>
  lea    0x0(%rbp,%r14,1),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <__builtin_prefetch@plt>
  xor    %edx,%edx
  lea    0x0(%rbp,%rbx,1),%rdi
  xor    %esi,%esi
  call   <__builtin_prefetch@plt>
  lea    0x0(,%r12,4),%rax
  mov    (%rsp),%ecx
  lea    (%r15,%rax,1),%rdx
  cmp    %ecx,(%rdx)
  mov    0x4(%rsp),%ecx
  cmovl  %rdx,%r15
  add    %rbp,%rax
  cmp    %ecx,(%rax)
  cmovl  %rax,%rbp
  sub    %r12,%r13
  cmp    $0x1,%r13
  ja     L32
L11:
  mov    (%rsp),%eax
  cmp    %eax,(%r15)
  setl   %al
  mov    0x8(%rsp),%rcx
  mov    0x10(%rsp),%rsi
  movzbl %al,%eax
  lea    (%r15,%rax,4),%rax
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    %rax,(%rsi)
  mov    0x4(%rsp),%eax
  cmp    %eax,0x0(%rbp)
  mov    0x18(%rsp),%rsi
  setl   %al
  movzbl %al,%eax
  lea    0x0(%rbp,%rax,4),%rax
  sub    %rcx,%rax
  sar    $0x2,%rax
  mov    %rax,(%rsi)
L13:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%r15
  mov    %rdi,%rbp
  jmp    L11
```

assistant: ```c
void branchfree_search2_prefetch(int *source, size_t n, int target1, int target2, size_t *index1, size_t *index2) {
  int *base1 = source;
  int *base2 = source;
  if (n == 0)
    return;
  while (n > 1) {
    size_t half = n >> 1;
    __builtin_prefetch(base1 + (half >> 1), 0, 0);
    __builtin_prefetch(base1 + half + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + (half >> 1), 0, 0);
    __builtin_prefetch(base2 + half + (half >> 1), 0, 0);
    base1 = (base1[half] < target1) ? &base1[half] : base1;
    base2 = (base2[half] < target2) ? &base2[half] : base2;
    n -= half;
  }
  *index1 = (*base1 < target1) + base1 - source;
  *index2 = (*base2 < target2) + base2 - source;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_set_outputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %esi,-0xfc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xf8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0xe8(%rbp)
  cmpq   $0x0,-0xe8(%rbp)
  jne    L38
  mov    $0xffffffff,%eax
  jmp    L8
L38:
  mov    -0xe8(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L36
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <is_hex@plt>
  mov    %eax,-0xf0(%rbp)
  cmpl   $0x0,-0xf0(%rbp)
  js     L36
  mov    -0xf0(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0xec(%rbp)
  mov    -0xec(%rbp),%ecx
  mov    -0xec(%rbp),%edx
  lea    -0x70(%rbp),%rax
  lea    D28(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L36:
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D27
data_type: string

tool: D6: r

tool: D28: L%01x%01x


tool: D27: %s

assistant: ```c
int my_set_outputs(char *filename, int fd) {
  FILE *fp;
  char first;
  char buf[100];
  char send[100];
  int i, n;
  if ((fp = fopen(filename, "r")) == NULL) {
    return (-1);
  }
  if (fgets(buf, 99, fp) != NULL) {
    if ((i = is_hex(&buf[0])) >= 0) {
      n = i & 0xf;
      sprintf(send, "L%01x%01x\n", n, n);
      printf("%s", send);
    }
  }
  fclose(fp);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_set_outputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    %rax,%rdx
  mov    $0x63,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L9
  mov    %rsp,%rdi
  call   <is_hex@plt>
  test   %eax,%eax
  jns    L35
L9:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L49:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  and    $0xf,%eax
  mov    %eax,%edx
  lea    0x70(%rsp),%rbp
  mov    %eax,%ecx
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L1:
  mov    $0xffffffff,%eax
  jmp    L49
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D29: r

tool: D23: L%01x%01x


tool: D7: %s

assistant: ```c
int my_set_outputs(char *filename, int fd) {
  FILE *fp;
  char first;
  char buf[100];
  char send[100];
  int i, n;
  if ((fp = fopen(filename, "r")) == NULL) {
    return (-1);
  }
  if (fgets(buf, 99, fp) != NULL) {
    if ((i = is_hex(&buf[0])) >= 0) {
      n = i & 0xf;
      sprintf(send, "L%01x%01x\n", n, n);
      printf("%s", send);
    }
  }
  fclose(fp);
  return (0);
}
```