ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ccuConfigureCaptureERUChannel0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <ccuEvent0@plt>
  mov    %eax,%ebx
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x9,%edi
  call   <ccuEvent1@plt>
  or     %ebx,%eax
  push   $0x0
  push   $0x0
  push   $0x301
  push   $0x0
  mov    $0x1313,%r9d
  mov    $0xd,%r8d
  mov    $0x40a,%ecx
  mov    $0x21,%edx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <ccuConfigureSlice@plt>
  add    $0x20,%rsp
  mov    $0x1,%edi
  call   <ccuEnableSlices@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int ccuConfigureCaptureERUChannel0(void) {
  ccuConfigureSlice(0, ccuEvent0(0x0009, 0x01, 0x00, (0x00)) | ccuEvent1(0x0009, 0x02, 0x00, (0x01)), (0x01 << 0) | (0x02 << 4), (1 << 1) | (0x01 << 3) | (1 << 10) | 0x00, 0x0d, 4883, 0, (1 << 8) | (1 << 9) | (1 << 0), (0x00 << 8) | (0x00 << 10) | (0x00 << 0), 0);
  ccuEnableSlices((1 << 0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccuConfigureCaptureERUChannel0>:
  endbr64
  push   %rbx
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <ccuEvent0@plt>
  mov    %eax,%ebx
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x9,%edi
  call   <ccuEvent1@plt>
  or     %eax,%ebx
  mov    %ebx,%esi
  push   $0x0
  push   $0x0
  push   $0x301
  push   $0x0
  mov    $0x1313,%r9d
  mov    $0xd,%r8d
  mov    $0x40a,%ecx
  mov    $0x21,%edx
  mov    $0x0,%edi
  call   <ccuConfigureSlice@plt>
  add    $0x20,%rsp
  mov    $0x1,%edi
  call   <ccuEnableSlices@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ccuConfigureCaptureERUChannel0(void) {
  ccuConfigureSlice(0, ccuEvent0(0x0009, 0x01, 0x00, (0x00)) | ccuEvent1(0x0009, 0x02, 0x00, (0x01)), (0x01 << 0) | (0x02 << 4), (1 << 1) | (0x01 << 3) | (1 << 10) | 0x00, 0x0d, 4883, 0, (1 << 8) | (1 << 9) | (1 << 0), (0x00 << 8) | (0x00 << 10) | (0x00 << 0), 0);
  ccuEnableSlices((1 << 0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccuConfigureCaptureERUChannel0>:
  endbr64
  push   %rbx
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <ccuEvent0@plt>
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x9,%edi
  mov    %eax,%ebx
  call   <ccuEvent1@plt>
  push   $0x0
  mov    $0x1313,%r9d
  xor    %edi,%edi
  push   $0x0
  or     %eax,%ebx
  mov    $0xd,%r8d
  mov    $0x40a,%ecx
  push   $0x301
  mov    %ebx,%esi
  mov    $0x21,%edx
  push   $0x0
  call   <ccuConfigureSlice@plt>
  add    $0x20,%rsp
  mov    $0x1,%edi
  call   <ccuEnableSlices@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ccuConfigureCaptureERUChannel0(void) {
  ccuConfigureSlice(0, ccuEvent0(0x0009, 0x01, 0x00, (0x00)) | ccuEvent1(0x0009, 0x02, 0x00, (0x01)), (0x01 << 0) | (0x02 << 4), (1 << 1) | (0x01 << 3) | (1 << 10) | 0x00, 0x0d, 4883, 0, (1 << 8) | (1 << 9) | (1 << 0), (0x00 << 8) | (0x00 << 10) | (0x00 << 0), 0);
  ccuEnableSlices((1 << 0));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ccuConfigureCaptureERUChannel0>:
  endbr64
  push   %rbx
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <ccuEvent0@plt>
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x9,%edi
  mov    %eax,%ebx
  call   <ccuEvent1@plt>
  push   $0x0
  mov    $0x1313,%r9d
  xor    %edi,%edi
  push   $0x0
  or     %eax,%ebx
  mov    $0xd,%r8d
  mov    $0x40a,%ecx
  push   $0x301
  mov    %ebx,%esi
  mov    $0x21,%edx
  push   $0x0
  call   <ccuConfigureSlice@plt>
  add    $0x20,%rsp
  mov    $0x1,%edi
  call   <ccuEnableSlices@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int ccuConfigureCaptureERUChannel0(void) {
  ccuConfigureSlice(0, ccuEvent0(0x0009, 0x01, 0x00, (0x00)) | ccuEvent1(0x0009, 0x02, 0x00, (0x01)), (0x01 << 0) | (0x02 << 4), (1 << 1) | (0x01 << 3) | (1 << 10) | 0x00, 0x0d, 4883, 0, (1 << 8) | (1 << 9) | (1 << 0), (0x00 << 8) | (0x00 << 10) | (0x00 << 0), 0);
  ccuEnableSlices((1 << 0));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L53
L25:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L0:
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L11
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L11
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L0
L11:
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L53:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L25
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gcd3(int n1, int n2) {
  int prev = -1;
  while (n1 > 0) {
    prev = n1;
    while (n1 && n2 && n1 >= n2) {
      n1 = n1 - n2;
    }
    swap(&n1, &n2);
  }
  return prev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd3>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  test   %edi,%edi
  jg     L4
  mov    $0xffffffff,%ebx
L68:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L66:
  mov    %edx,0xc(%rsp)
L34:
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rsi
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L68
  mov    %eax,%ebx
L4:
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%ecx
  test   %eax,%eax
  setne  %sil
  test   %ecx,%ecx
  setne  %dl
  test   %dl,%sil
  je     L34
  cmp    %ecx,%eax
  setge  %dl
  sub    %ecx,%eax
  test   %dl,%dl
  je     L34
L53:
  mov    %eax,%edx
  sub    %ecx,%eax
  test   %edx,%edx
  je     L66
  cmp    %ecx,%edx
  jge    L53
  jmp    L66
```

assistant: ```c
int gcd3(int n1, int n2) {
  int prev = -1;
  while (n1 > 0) {
    prev = n1;
    while (n1 && n2 && n1 >= n2) {
      n1 = n1 - n2;
    }
    swap(&n1, &n2);
  }
  return prev;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gcd3>:
  endbr64
  push   %r12
  mov    $0xffffffff,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  test   %edi,%edi
  jle    L64
  mov    %edi,%r12d
  lea    0x8(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L51:
  mov    0x8(%rsp),%ecx
  test   %ecx,%ecx
  je     L2
  cmp    %r12d,%ecx
  mov    %r12d,%eax
  setle  %dl
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L13
  jmp    L2
  nopl   0x0(%rax)
L9:
  cmp    %ecx,%edx
  jl     L71
L13:
  mov    %eax,%edx
  sub    %ecx,%eax
  test   %edx,%edx
  jne    L9
L71:
  mov    %edx,0xc(%rsp)
L2:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L64
  mov    %eax,%r12d
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L64:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int gcd3(int n1, int n2) {
  int prev = -1;
  while (n1 > 0) {
    prev = n1;
    while (n1 && n2 && n1 >= n2) {
      n1 = n1 - n2;
    }
    swap(&n1, &n2);
  }
  return prev;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd3>:
  endbr64
  push   %r12
  mov    $0xffffffff,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  test   %edi,%edi
  jle    L35
  mov    %edi,%r12d
  lea    0x8(%rsp),%rbp
  lea    0xc(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L38:
  mov    0x8(%rsp),%ecx
  test   %ecx,%ecx
  je     L60
  cmp    %r12d,%ecx
  mov    %r12d,%eax
  setle  %dl
  sub    %ecx,%eax
  test   %dl,%dl
  jne    L24
  jmp    L60
  nopl   0x0(%rax)
L17:
  cmp    %ecx,%edx
  jl     L52
L24:
  mov    %eax,%edx
  sub    %ecx,%eax
  test   %edx,%edx
  jne    L17
L52:
  mov    %edx,0xc(%rsp)
L60:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L35
  mov    %eax,%r12d
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int gcd3(int n1, int n2) {
  int prev = -1;
  while (n1 > 0) {
    prev = n1;
    while (n1 && n2 && n1 >= n2) {
      n1 = n1 - n2;
    }
    swap(&n1, &n2);
  }
  return prev;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_unsigned_long_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <before_append_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L14
L5:
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <add_unsigned_long_parse_katcl@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <after_append_katcl@plt>
L14:
  leave
  ret
```

assistant: ```c
int append_unsigned_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_unsigned_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_unsigned_long_katcl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <add_unsigned_long_parse_katcl@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <after_append_katcl@plt>
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L8
```

assistant: ```c
int append_unsigned_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_unsigned_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_unsigned_long_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L0
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_unsigned_long_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L0:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_unsigned_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_unsigned_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<append_unsigned_long_katcl>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  call   <before_append_katcl@plt>
  test   %rax,%rax
  je     L3
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <add_unsigned_long_parse_katcl@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  pop    %r13
  jmp    1070 <after_append_katcl@plt>
L3:
  pop    %rbp
  mov    $0xffffffff,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int append_unsigned_long_katcl(struct katcl_line *l, int flags, unsigned long v) {
  struct katcl_parse *p;
  int result;
  p = before_append_katcl(l, flags);
  if (p == NULL) {
    return -1;
  }
  result = add_unsigned_long_parse_katcl(p, flags, v);
  return after_append_katcl(l, flags, result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eliminate_mod>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  movsd  %xmm0,0x20(%rsp)
  mov    %r8,0x28(%rsp)
  cmp    $0x1,%edx
  jle    L54
  mov    %edx,%r13d
  mov    %rcx,%rbx
  lea    0x8(%rdi),%rbp
  lea    -0x2(%rdx),%eax
  mov    %eax,0x4(%rsp)
  mov    %eax,%eax
  add    $0x2,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x1,%r14d
  mov    $0x0,%r12d
L56:
  mov    %r12d,%r8d
  mov    %r13d,%ecx
  mov    0x10(%rsp),%rdx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <pivot@plt>
  cmp    %r14d,%r13d
  jle    L37
  lea    0x0(,%r12,8),%r11
  lea    0x0(,%r14,8),%r15
  mov    0x4(%rsp),%eax
  lea    0x2(%r12,%rax,1),%r8
  shl    $0x3,%r8
  mov    %rbp,%r10
  mov    %r14,%r9
L52:
  mov    %r10,%rsi
  mov    %rbp,%rcx
  mov    (%r10),%rdx
  mov    -0x8(%rbp),%rax
  movsd  (%rdx,%r11,1),%xmm2
  divsd  (%rax,%r11,1),%xmm2
  mov    %r15,%rax
L33:
  mov    %rax,%rdx
  add    (%rsi),%rdx
  mov    -0x8(%rcx),%rdi
  movapd %xmm2,%xmm1
  mulsd  (%rdi,%rax,1),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L33
  mulsd  (%rbx,%r12,8),%xmm2
  movsd  (%rbx,%r9,8),%xmm0
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx,%r9,8)
  add    $0x1,%r9
  add    $0x8,%r10
  cmp    %r9d,%r13d
  jg     L52
L37:
  add    $0x1,%r12
  add    $0x1,%r14
  add    $0x8,%rbp
  subl   $0x1,0x4(%rsp)
  cmp    0x18(%rsp),%r14
  jne    L56
  lea    -0x1(%r13),%eax
L13:
  cltq
  mov    0x8(%rsp),%rbx
  mov    (%rbx,%rax,8),%rdx
  movsd  (%rdx,%rax,8),%xmm0
  mov    0x10(%rsp),%rbx
  divsd  (%rbx,%rax,8),%xmm0
  andpd  D0(%rip),%xmm0
  movsd  0x20(%rsp),%xmm3
  comisd %xmm0,%xmm3
  jbe    L32
  mov    0x28(%rsp),%rax
  movl   $0xffffffff,(%rax)
L32:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  mov    $0x0,%eax
  jmp    L13
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: qword[2]

tool: {"D0": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
void eliminate_mod(double **a, double *s, int n, double *b, double tol, int *er) {
  int k, i, j;
  double factor;
  for (k = 0; k < n - 1; k++) {
    pivot(a, b, s, n, k);
    for (i = k + 1; i < n; i++) {
      factor = a[i][k] / a[k][k];
      for (j = k + 1; j < n; j++) {
        a[i][j] = a[i][j] - factor * a[k][j];
      }
      b[i] = b[i] - factor * b[k];
    }
  }
  if (fabs(a[k][k] / s[k]) < tol)
    *er = -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eliminate_mod>:
  endbr64
  push   %r15
  lea    -0x1(%rdx),%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %r8,0x18(%rsp)
  mov    %eax,0xc(%rsp)
  movsd  %xmm0,0x10(%rsp)
  test   %eax,%eax
  jle    L36
  lea    -0x2(%rdx),%ebp
  mov    %edx,%r14d
  mov    %rcx,%r15
  mov    $0x1,%r12d
  add    $0x2,%rbp
  nopl   (%rax)
L4:
  lea    -0x1(%r12),%r8d
  mov    %r14d,%ecx
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <pivot@plt>
  cmp    %r12d,%r14d
  jle    L5
  mov    -0x8(%r13,%r12,8),%rcx
  lea    -0x8(,%r12,8),%rdi
  mov    %r12,%rsi
  lea    (%rcx,%rdi,1),%r8
  nopw   0x0(%rax,%rax,1)
L11:
  mov    0x0(%r13,%rsi,8),%rdx
  mov    %r12,%rax
  movsd  (%rdx,%rdi,1),%xmm2
  divsd  (%r8),%xmm2
  nopw   0x0(%rax,%rax,1)
L31:
  movsd  (%rcx,%rax,8),%xmm1
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%r14d
  jg     L31
  mulsd  -0x8(%r15,%r12,8),%xmm2
  movsd  (%r15,%rsi,8),%xmm0
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%r15,%rsi,8)
  add    $0x1,%rsi
  cmp    %esi,%r14d
  jg     L11
L5:
  add    $0x1,%r12
  cmp    %r12,%rbp
  jne    L4
  movslq 0xc(%rsp),%rax
  shl    $0x3,%rax
  add    %rax,%r13
  add    %rax,%rbx
L55:
  mov    0x0(%r13),%rdx
  movsd  0x10(%rsp),%xmm3
  movsd  (%rdx,%rax,1),%xmm0
  divsd  (%rbx),%xmm0
  andpd  D3(%rip),%xmm0
  comisd %xmm0,%xmm3
  jbe    L29
  mov    0x18(%rsp),%rax
  movl   $0xffffffff,(%rax)
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  xor    %eax,%eax
  jmp    L55
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: qword[2]

tool: {"D3": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
void eliminate_mod(double **a, double *s, int n, double *b, double tol, int *er) {
  int k, i, j;
  double factor;
  for (k = 0; k < n - 1; k++) {
    pivot(a, b, s, n, k);
    for (i = k + 1; i < n; i++) {
      factor = a[i][k] / a[k][k];
      for (j = k + 1; j < n; j++) {
        a[i][j] = a[i][j] - factor * a[k][j];
      }
      b[i] = b[i] - factor * b[k];
    }
  }
  if (fabs(a[k][k] / s[k]) < tol)
    *er = -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L11
L18:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <fact>
  imul   -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
unsigned long long fact(unsigned long long a) {
  if (a == 0)
    return 1;
  return a * fact(a - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  jne    L8
  ret
L8:
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rdi),%rdi
  call   <fact>
  imul   %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long long fact(unsigned long long a) {
  if (a == 0)
    return 1;
  return a * fact(a - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L4
  xchg   %ax,%ax
L0:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L0
L4:
  ret
```

assistant: ```c
unsigned long long fact(unsigned long long a) {
  if (a == 0)
    return 1;
  return a * fact(a - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<fact>:
  endbr64
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L12
  xchg   %ax,%ax
L13:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  jne    L13
L12:
  ret
```

assistant: ```c
unsigned long long fact(unsigned long long a) {
  if (a == 0)
    return 1;
  return a * fact(a - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<platform_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xe000e018,%eax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
uint32_t platform_random(uint32_t max) {
  uint32_t seed = *((volatile uint32_t *)0xe000e018);
  srand(seed);
  return rand() % max;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<platform_random>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xe000e018,%eax
  mov    (%rax),%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t platform_random(uint32_t max) {
  uint32_t seed = *((volatile uint32_t *)0xe000e018);
  srand(seed);
  return rand() % max;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<platform_random>:
  endbr64
  push   %rbx
  mov    $0xe000e018,%eax
  mov    %edi,%ebx
  mov    (%rax),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t platform_random(uint32_t max) {
  uint32_t seed = *((volatile uint32_t *)0xe000e018);
  srand(seed);
  return rand() % max;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<platform_random>:
  endbr64
  push   %rbx
  mov    $0xe000e018,%eax
  mov    %edi,%ebx
  mov    (%rax),%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  pop    %rbx
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t platform_random(uint32_t max) {
  uint32_t seed = *((volatile uint32_t *)0xe000e018);
  srand(seed);
  return rand() % max;
}
```
user: What is the c source code of the assembly code below?

```asm
<issignaling_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%ebx
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  and    %eax,%ebx
  mov    $0x0,%edi
  call   <UINT64_C@plt>
  cmp    %eax,%ebx
  jle    L14
  mov    -0x18(%rbp),%ebx
  mov    $0x0,%edi
  call   <UINT64_C@plt>
  and    %ebx,%eax
  test   %eax,%eax
  jne    L14
  mov    $0x1,%eax
  jmp    L7
L14:
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int issignaling_d(double x) {
  union {
    double d;
    uint64_t u;
  } u = {.d = x};
  return (((u.u & UINT64_C(0x7fffffffffffffff)) > UINT64_C(0x7ff0000000000000)) && (u.u & UINT64_C(0x8000000000000)) == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<issignaling_d>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  and    %ebx,%eax
  mov    %eax,%ebp
  mov    $0x0,%edi
  call   <UINT64_C@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%ebp
  jg     L17
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x0,%edi
  call   <UINT64_C@plt>
  test   %ebx,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

assistant: ```c
int issignaling_d(double x) {
  union {
    double d;
    uint64_t u;
  } u = {.d = x};
  return (((u.u & UINT64_C(0x7fffffffffffffff)) > UINT64_C(0x7ff0000000000000)) && (u.u & UINT64_C(0x8000000000000)) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<issignaling_d>:
  endbr64
  push   %rbp
  mov    $0xffffffff,%edi
  push   %rbx
  movq   %xmm0,%rbx
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  xor    %edi,%edi
  and    %ebx,%eax
  mov    %eax,%ebp
  call   <UINT64_C@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebp
  jg     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  xor    %edi,%edi
  call   <UINT64_C@plt>
  test   %ebx,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int issignaling_d(double x) {
  union {
    double d;
    uint64_t u;
  } u = {.d = x};
  return (((u.u & UINT64_C(0x7fffffffffffffff)) > UINT64_C(0x7ff0000000000000)) && (u.u & UINT64_C(0x8000000000000)) == 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<issignaling_d>:
  endbr64
  push   %rbp
  mov    $0xffffffff,%edi
  push   %rbx
  movq   %xmm0,%rbx
  sub    $0x8,%rsp
  call   <UINT64_C@plt>
  xor    %edi,%edi
  and    %ebx,%eax
  mov    %eax,%ebp
  call   <UINT64_C@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebp
  jg     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  xor    %edi,%edi
  call   <UINT64_C@plt>
  test   %ebx,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int issignaling_d(double x) {
  union {
    double d;
    uint64_t u;
  } u = {.d = x};
  return (((u.u & UINT64_C(0x7fffffffffffffff)) > UINT64_C(0x7ff0000000000000)) && (u.u & UINT64_C(0x8000000000000)) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <main@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void _start(void) {
  int retval = main();
  exit(retval);
}
```