ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L10
  add    $0x1,%r12
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int len2;
  len2 = strlen(s2);
  while (1) {
    s1 = strchr(s1, s2[0]);
    if (s1 == NULL) {
      break;
    }
    if (!strncmp(s1, s2, len2)) {
      return (char *)s1;
    }
    ++s1;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strstr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L20
  add    $0x1,%r12
L25:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L14
L20:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int len2;
  len2 = strlen(s2);
  while (1) {
    s1 = strchr(s1, s2[0]);
    if (s1 == NULL) {
      break;
    }
    if (!strncmp(s1, s2, len2)) {
      return (char *)s1;
    }
    ++s1;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mpz_bitsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mpz_sizeinbase@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
extern ulong mpz_bitsize(mpz_t z) {
  size_t s = mpz_sizeinbase(z, 2);
  return (ulong)s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mpz_bitsize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <mpz_sizeinbase@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern ulong mpz_bitsize(mpz_t z) {
  size_t s = mpz_sizeinbase(z, 2);
  return (ulong)s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mpz_bitsize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <mpz_sizeinbase@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern ulong mpz_bitsize(mpz_t z) {
  size_t s = mpz_sizeinbase(z, 2);
  return (ulong)s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mpz_bitsize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  call   <mpz_sizeinbase@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern ulong mpz_bitsize(mpz_t z) {
  size_t s = mpz_sizeinbase(z, 2);
  return (ulong)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outputMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printError@plt>
L4:
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    %esi,%edx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string

tool: D18: wb

tool: D23: error while opening output file

tool: D13: Element #%d located on memory address %d


tool: D16: BigExtract: successfully written %d entries to %s


assistant: ```c
void outputMatrix(char *outfile, int *matrix, int *filecounter) {
  FILE *out;
  int i;
  if ((out = fopen(outfile, "wb")) == NULL) {
    printError("error while opening output file");
  }
  for (i = 0; i < *filecounter; i++) {
    fprintf(out, "Element #%d located on memory address %d\n", i + 1, matrix[i]);
  }
  fclose(out);
  printf("BigExtract: successfully written %d entries to %s\n", *filecounter, outfile);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<outputMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    D17(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L3
L14:
  cmpl   $0x0,(%r12)
  jle    L5
  mov    $0x0,%ebx
  lea    D27(%rip),%r15
L15:
  add    $0x1,%ebx
  mov    0x0(%rbp),%ecx
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
  add    $0x4,%rbp
  cmp    (%r12),%ebx
  jl     L15
L5:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r14,%rdx
  mov    (%r12),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    D33(%rip),%rdi
  call   <printError@plt>
  jmp    L14
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string
name: read_data
arguments: data_tag: D33
data_type: string

tool: D17: wb

tool: D27: Element #%d located on memory address %d


tool: D14: BigExtract: successfully written %d entries to %s


tool: D33: error while opening output file

assistant: ```c
void outputMatrix(char *outfile, int *matrix, int *filecounter) {
  FILE *out;
  int i;
  if ((out = fopen(outfile, "wb")) == NULL) {
    printError("error while opening output file");
  }
  for (i = 0; i < *filecounter; i++) {
    fprintf(out, "Element #%d located on memory address %d\n", i + 1, matrix[i]);
  }
  fclose(out);
  printf("BigExtract: successfully written %d entries to %s\n", *filecounter, outfile);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<outputMatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D14(%rip),%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L19
L20:
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  lea    D34(%rip),%r15
L29:
  mov    0x0(%rbp),%ecx
  add    $0x1,%ebx
  mov    %r15,%rsi
  mov    %r13,%rdi
  mov    %ebx,%edx
  add    $0x4,%rbp
  call   <fprintf@plt>
  cmp    (%r12),%ebx
  jl     L29
L14:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    (%r12),%esi
  add    $0x8,%rsp
  mov    %r14,%rdx
  pop    %rbx
  lea    D38(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L19:
  lea    D7(%rip),%rdi
  call   <printError@plt>
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D38
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D14: wb

tool: D34: Element #%d located on memory address %d


tool: D38: BigExtract: successfully written %d entries to %s


tool: D7: error while opening output file

assistant: ```c
void outputMatrix(char *outfile, int *matrix, int *filecounter) {
  FILE *out;
  int i;
  if ((out = fopen(outfile, "wb")) == NULL) {
    printError("error while opening output file");
  }
  for (i = 0; i < *filecounter; i++) {
    fprintf(out, "Element #%d located on memory address %d\n", i + 1, matrix[i]);
  }
  fclose(out);
  printf("BigExtract: successfully written %d entries to %s\n", *filecounter, outfile);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<outputMatrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D32(%rip),%rsi
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L29
L9:
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L37
  xor    %ebx,%ebx
  lea    D36(%rip),%r15
L20:
  mov    0x0(%rbp),%ecx
  add    $0x1,%ebx
  mov    %r15,%rsi
  mov    %r13,%rdi
  mov    %ebx,%edx
  add    $0x4,%rbp
  call   <fprintf@plt>
  cmp    (%r12),%ebx
  jl     L20
L37:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    (%r12),%esi
  add    $0x8,%rsp
  mov    %r14,%rdx
  pop    %rbx
  lea    D27(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <printf@plt>
  cs nopw 0x0(%rax,%rax,1)
L29:
  lea    D29(%rip),%rdi
  call   <printError@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: tag: D32
type_infered: string
name: parse_data
arguments: tag: D36
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string

tool: D32: wb

tool: D36: Element #%d located on memory address %d


tool: D27: BigExtract: successfully written %d entries to %s


tool: D29: error while opening output file

assistant: ```c
void outputMatrix(char *outfile, int *matrix, int *filecounter) {
  FILE *out;
  int i;
  if ((out = fopen(outfile, "wb")) == NULL) {
    printError("error while opening output file");
  }
  for (i = 0; i < *filecounter; i++) {
    fprintf(out, "Element #%d located on memory address %d\n", i + 1, matrix[i]);
  }
  fclose(out);
  printf("BigExtract: successfully written %d entries to %s\n", *filecounter, outfile);
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_getc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  mov    $0x90000005,%eax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    $0x90000000,%eax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char uart_getc() {
  unsigned char lsr;
  char c;
  do {
    lsr = *((volatile unsigned char *)(0x90000000 + 5));
  } while ((lsr & 0x01) != 0x01);
  c = *((volatile unsigned char *)(0x90000000 + 0));
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_getc>:
  endbr64
  mov    $0x90000005,%edx
L1:
  movzbl (%rdx),%eax
  test   $0x1,%al
  je     L1
  movabs 0x90000000,%al
  ret
```

assistant: ```c
char uart_getc() {
  unsigned char lsr;
  char c;
  do {
    lsr = *((volatile unsigned char *)(0x90000000 + 5));
  } while ((lsr & 0x01) != 0x01);
  c = *((volatile unsigned char *)(0x90000000 + 0));
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_getc>:
  endbr64
  mov    $0x90000005,%edx
  nopl   0x0(%rax)
L2:
  movzbl (%rdx),%eax
  test   $0x1,%al
  je     L2
  movabs 0x90000000,%al
  ret
```

assistant: ```c
char uart_getc() {
  unsigned char lsr;
  char c;
  do {
    lsr = *((volatile unsigned char *)(0x90000000 + 5));
  } while ((lsr & 0x01) != 0x01);
  c = *((volatile unsigned char *)(0x90000000 + 0));
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uart_getc>:
  endbr64
  mov    $0x90000005,%edx
  nopl   0x0(%rax)
L2:
  movzbl (%rdx),%eax
  test   $0x1,%al
  je     L2
  movabs 0x90000000,%al
  ret
```

assistant: ```c
char uart_getc() {
  unsigned char lsr;
  char c;
  do {
    lsr = *((volatile unsigned char *)(0x90000000 + 5));
  } while ((lsr & 0x01) != 0x01);
  c = *((volatile unsigned char *)(0x90000000 + 0));
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lastStrStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L1
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *lastStrStr(const char *s1, const char *s2) {
  char *pos;
  while (strstr(s1, s2) != NULL) {
    pos = (char *)s1;
    s1++;
  }
  return pos;
}
```
user: What is the c source code of the assembly code below?

```asm
<lastStrStr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  jmp    L19
L9:
  mov    %rbx,%r12
  lea    0x1(%rbx),%rbx
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *lastStrStr(const char *s1, const char *s2) {
  char *pos;
  while (strstr(s1, s2) != NULL) {
    pos = (char *)s1;
    s1++;
  }
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lastStrStr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L16
L14:
  mov    %rbx,%r12
  add    $0x1,%rbx
L16:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *lastStrStr(const char *s1, const char *s2) {
  char *pos;
  while (strstr(s1, s2) != NULL) {
    pos = (char *)s1;
    s1++;
  }
  return pos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lastStrStr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L18
L11:
  mov    %rbx,%r12
  add    $0x1,%rbx
L18:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *lastStrStr(const char *s1, const char *s2) {
  char *pos;
  while (strstr(s1, s2) != NULL) {
    pos = (char *)s1;
    s1++;
  }
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<byte_to_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L19:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  mov    $0x31,%ecx
  jmp    L14
L1:
  mov    $0x30,%ecx
L14:
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    D25(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x7,-0x4(%rbp)
  jle    L19
  movb   $0x0,D6(%rip)
  lea    D25(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *byte_to_binary(int x) {
  static char b[9];
  int pos;
  for (pos = 0; pos < 8; pos++)
    b[7 - pos] = (x & (1 << pos)) ? '1' : '0';
  b[8] = '\0';
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_to_binary>:
  endbr64
  lea    D20(%rip),%rdx
  mov    $0x0,%ecx
L0:
  mov    %edi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,(%rdx)
  add    $0x1,%ecx
  sub    $0x1,%rdx
  cmp    $0x8,%ecx
  jne    L0
  movb   $0x0,D25(%rip)
  lea    D14(%rip),%rax
  ret
```

assistant: ```c
const char *byte_to_binary(int x) {
  static char b[9];
  int pos;
  for (pos = 0; pos < 8; pos++)
    b[7 - pos] = (x & (1 << pos)) ? '1' : '0';
  b[8] = '\0';
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<byte_to_binary>:
  endbr64
  lea    D24(%rip),%rdx
  xor    %ecx,%ecx
  nopl   (%rax)
L3:
  mov    %edi,%eax
  sub    $0x1,%rdx
  sar    %cl,%eax
  add    $0x1,%ecx
  and    $0x1,%eax
  add    $0x30,%eax
  mov    %al,0x1(%rdx)
  cmp    $0x8,%ecx
  jne    L3
  movb   $0x0,D1(%rip)
  lea    D23(%rip),%rax
  ret
```

assistant: ```c
const char *byte_to_binary(int x) {
  static char b[9];
  int pos;
  for (pos = 0; pos < 8; pos++)
    b[7 - pos] = (x & (1 << pos)) ? '1' : '0';
  b[8] = '\0';
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<byte_to_binary>:
  endbr64
  mov    %edi,%r11d
  mov    %edi,%edx
  mov    %edi,%ecx
  mov    %edi,%esi
  mov    %edi,%r8d
  mov    %edi,%r9d
  mov    %edi,%r10d
  sar    %r11d
  sar    $0x2,%r10d
  and    $0x1,%edi
  and    $0x1,%r11d
  sar    $0x3,%r9d
  lea    0x30(%rdi),%rax
  lea    0x30(%r11),%rdi
  and    $0x1,%r10d
  and    $0x1,%r9d
  shl    $0x8,%rax
  sar    $0x4,%r8d
  movb   $0x0,D10(%rip)
  sar    $0x5,%esi
  or     %rdi,%rax
  lea    0x30(%r10),%rdi
  and    $0x1,%r8d
  shl    $0x8,%rax
  and    $0x1,%esi
  sar    $0x6,%ecx
  or     %rdi,%rax
  lea    0x30(%r9),%rdi
  add    $0x30,%rsi
  and    $0x1,%ecx
  shl    $0x8,%rax
  sar    $0x7,%edx
  add    $0x30,%rcx
  or     %rdi,%rax
  lea    0x30(%r8),%rdi
  and    $0x1,%edx
  shl    $0x8,%rax
  add    $0x30,%rdx
  or     %rdi,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,D14(%rip)
  lea    D14(%rip),%rax
  ret
```

assistant: ```c
const char *byte_to_binary(int x) {
  static char b[9];
  int pos;
  for (pos = 0; pos < 8; pos++)
    b[7 - pos] = (x & (1 << pos)) ? '1' : '0';
  b[8] = '\0';
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_section_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L136
L44:
  addq   $0x1,-0x20(%rbp)
L136:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L44
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L112
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L88
L112:
  addq   $0x1,-0x20(%rbp)
  jmp    L11
L94:
  cmpl   $0x13,-0x4(%rbp)
  jg     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L8:
  addq   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L82
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L82
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L82
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L94
L82:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L34
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L88
L37:
  subl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x0,-0x4(%rbp)
  jle    L134
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L37
L134:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L88:
  pop    %rbp
  ret
```

assistant: ```c
void get_section_name(char *out, char *in) {
  int i = 0;
  while (in[0] == ' ')
    in++;
  if (in[0] != '[') {
    out[0] = 0;
    return;
  }
  in++;
  while (in[0] != ']' && in[0] != 13 && in[0] != 10 && in[0] != 0) {
    if (i < 20) {
      out[i] = in[0];
      i++;
    }
    in++;
  }
  if (in[0] != ']') {
    out[0] = 0;
    return;
  }
  while (i > 0 && out[i - 1] == ' ')
    i--;
  out[i] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_section_name>:
  endbr64
  mov    %rdi,%r8
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  jne    L54
L133:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  je     L133
L54:
  cmp    $0x5b,%al
  je     L96
  movb   $0x0,(%r8)
  ret
L96:
  lea    0x1(%rsi),%rdi
  movzbl 0x1(%rsi),%ecx
  cmp    $0x5d,%cl
  setne  %r9b
  mov    $0x1,%eax
  cmp    $0xd,%cl
  ja     L31
  mov    $0x2401,%eax
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L31:
  and    %al,%r9b
  je     L39
  mov    $0x0,%edx
  mov    $0x2401,%r10d
  jmp    L51
L156:
  test   %sil,%sil
  je     L97
  test   %al,%al
  je     L97
L51:
  cmp    $0x13,%edx
  jg     L136
  movslq %edx,%rax
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%edx
L136:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  cmp    $0x5d,%cl
  setne  %sil
  mov    %r9d,%eax
  cmp    $0xd,%cl
  ja     L156
  mov    %r10,%rax
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
  jmp    L156
L97:
  cmp    $0x5d,%cl
  jne    L141
  test   %edx,%edx
  jle    L94
  movslq %edx,%rax
  lea    -0x1(%r8,%rax,1),%rax
L100:
  cmpb   $0x20,(%rax)
  jne    L94
  sub    $0x1,%rax
  sub    $0x1,%edx
  jne    L100
L94:
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  ret
L39:
  mov    $0x0,%edx
  cmp    $0x5d,%cl
  je     L94
L141:
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
void get_section_name(char *out, char *in) {
  int i = 0;
  while (in[0] == ' ')
    in++;
  if (in[0] != '[') {
    out[0] = 0;
    return;
  }
  in++;
  while (in[0] != ']' && in[0] != 13 && in[0] != 10 && in[0] != 0) {
    if (i < 20) {
      out[i] = in[0];
      i++;
    }
    in++;
  }
  if (in[0] != ']') {
    out[0] = 0;
    return;
  }
  while (i > 0 && out[i - 1] == ' ')
    i--;
  out[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_section_name>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L67:
  add    $0x1,%rsi
L7:
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  je     L67
  cmp    $0x5b,%al
  jne    L47
  movzbl 0x1(%rsi),%eax
  lea    0x1(%rsi),%rcx
  cmp    $0xd,%al
  je     L47
  cmp    $0x5d,%al
  je     L47
  xor    %edx,%edx
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L58:
  cmp    $0xa,%al
  je     L47
  cmp    $0x13,%edx
  jg     L62
  movslq %edx,%rsi
  add    $0x1,%edx
  mov    %al,(%rdi,%rsi,1)
L62:
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  cmp    $0x5d,%al
  je     L3
  cmp    $0xd,%al
  je     L105
L113:
  test   %al,%al
  jne    L58
L47:
  movb   $0x0,(%rdi)
  ret
L105:
  cmp    $0x5d,%al
  jne    L47
L3:
  movslq %edx,%rdx
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L22:
  sub    $0x1,%rdx
  je     L47
L27:
  cmpb   $0x20,-0x1(%rdi,%rdx,1)
  je     L22
  add    %rdx,%rdi
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void get_section_name(char *out, char *in) {
  int i = 0;
  while (in[0] == ' ')
    in++;
  if (in[0] != '[') {
    out[0] = 0;
    return;
  }
  in++;
  while (in[0] != ']' && in[0] != 13 && in[0] != 10 && in[0] != 0) {
    if (i < 20) {
      out[i] = in[0];
      i++;
    }
    in++;
  }
  if (in[0] != ']') {
    out[0] = 0;
    return;
  }
  while (i > 0 && out[i - 1] == ' ')
    i--;
  out[i] = 0;
}
```