user: 请从给定的汇编指令推导出C源代码:

```asm
<newton_nle_ad>:
  endbr64
  push   %r15
  mov    $0x10,%edi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    $0x10,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    $0x10,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  movapd D86(%rip),%xmm0
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  movups %xmm0,(%rbx)
  movapd D42(%rip),%xmm0
  movups %xmm0,0x0(%rbp)
  call   <array_max_abs@plt>
  test   %eax,%eax
  lea    D53(%rip),%rax
  mov    %rax,0x18(%rsp)
  jg     L27
  jmp    L22
  nopl   0x0(%rax)
L31:
  cmp    $0x64,%r15d
  je     L22
L27:
  movsd  0x8(%rbx),%xmm2
  movsd  (%rbx),%xmm1
  add    $0x1,%r15d
  mov    D45(%rip),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  mulsd  %xmm2,%xmm3
  mulsd  %xmm1,%xmm0
  subsd  D34(%rip),%xmm1
  movsd  %xmm3,0x8(%rsp)
  addsd  %xmm3,%xmm0
  subsd  D86(%rip),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm3
  mov    %rbp,%rdi
  xor    %eax,%eax
  movsd  0x10(%rsp),%xmm2
  mov    $0x2,%esi
  mulsd  %xmm3,%xmm2
  addsd  %xmm0,%xmm2
  subsd  D86(%rip),%xmm2
  movsd  %xmm2,0x8(%rbp)
  call   <array_max_abs@plt>
  movupd (%rbx),%xmm1
  mov    %eax,0x10(%rsp)
  mov    D45(%rip),%rax
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm4
  addpd  %xmm1,%xmm0
  subsd  D34(%rip),%xmm1
  unpckhpd %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  movups %xmm0,(%r12)
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm2
  mov    %r13,%rdx
  xor    %eax,%eax
  movsd  D40(%rip),%xmm1
  mov    $0x2,%esi
  mov    %r12,%rdi
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  unpcklpd %xmm1,%xmm0
  movups %xmm0,0x10(%r12)
  call   <ludecomp@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rdx
  mov    $0x2,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <linsolve@plt>
  mov    $0x2,%r8d
  mov    %rbx,%rdx
  xor    %eax,%eax
  mov    $0x2,%ecx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <msub@plt>
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r15d,%esi
  mov    0x18(%rsp),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%r10d
  test   %r10d,%r10d
  jg     L31
L22:
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r15d,%esi
  mov    $0x2,%eax
  mov    0x18(%rsp),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x28,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <free@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D86
type_infered: f64[2]
name: unpack_data
arguments: data_label: D42
type_infered: byte[16]
name: unpack_data
arguments: data_label: D53
type_infered: string
name: unpack_data
arguments: data_label: D45
type_infered: f64
name: unpack_data
arguments: data_label: D34
type_infered: f64
name: unpack_data
arguments: data_label: D40
type_infered: byte[8]

tool: {"D86": [2.0,3.0]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40,0xed,0x8a,0x62,0x51,0xe1,0xb7,0x3b,0x40]}

tool: D53: Method 1 : Values obtained %lf , %lf after %d Iterations 


tool: D45: 2.718281828459045

tool: D34: 1

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
void newton_nle_ad() {
  int N, it;
  double *x, *xi, *f, *J;
  double stop;
  int *p;
  N = 2;
  it = 0;
  x = (double *)malloc(sizeof(double) * N);
  xi = (double *)malloc(sizeof(double) * N);
  f = (double *)malloc(sizeof(double) * N);
  J = (double *)malloc(sizeof(double) * N * N);
  p = (int *)malloc(sizeof(int) * N);
  x[0] = 2;
  x[1] = 3;
  f[0] = x[0] * x[0] + x[1] * x[1] - 2.0;
  f[1] = pow((double)2.7182818284590452353602874713526624977572, x[0] - 1.0) + x[1] * x[1] * x[1] - 2.0;
  stop = array_max_abs(f, N);
  while (stop >= 1e-06 && it < 100) {
    f[0] = x[0] * x[0] + x[1] * x[1] - 2.0;
    f[1] = pow((double)2.7182818284590452353602874713526624977572, x[0] - 1.0) + x[1] * x[1] * x[1] - 2.0;
    stop = array_max_abs(f, N);
    J[0] = 2 * x[0];
    J[1] = 2 * x[1];
    J[2] = pow((double)2.7182818284590452353602874713526624977572, x[0] - 1.0);
    J[3] = 3 * x[1] * x[1];
    ludecomp(J, N, p);
    linsolve(J, N, f, p, xi);
    msub(x, xi, x, N, N);
    it++;
    printf("Method 1 : Values obtained %lf , %lf after %d Iterations \n", x[0], x[1], it);
  }
  printf("Method 1 : Values obtained %lf , %lf after %d Iterations \n", x[0], x[1], it);
  free(x);
  free(xi);
  free(f);
  free(J);
  free(p);
}
```