ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<toUpperCase>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L29
  nopl   0x0(%rax,%rax,1)
L30:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L17
  sub    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L30
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L30
L29:
  ret
```

assistant: ```c
void toUpperCase(char *value) {
  while (*value != '\0') {
    if (*value >= 'a' && *value <= 'z')
      *value -= 32;
    value++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<icvTrace_64d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L4
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x10(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L12
  mov    -0x28(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void icvTrace_64d(const double *src, int w, int h, double *trace) {
  int i, len = ((w) > (h) ? (h) : (w));
  double sum = 0;
  for (i = 0; len--; i += w + 1)
    sum += src[i];
  *trace = sum;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<icvTrace_64d>:
  endbr64
  cmp    %edx,%esi
  cmovle %esi,%edx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L9
  movslq %esi,%rsi
  lea    0x8(,%rsi,8),%rdx
  pxor   %xmm0,%xmm0
L2:
  addsd  (%rdi),%xmm0
  sub    $0x1,%eax
  add    %rdx,%rdi
  cmp    $0xffffffff,%eax
  jne    L2
L27:
  movsd  %xmm0,(%rcx)
  ret
L9:
  pxor   %xmm0,%xmm0
  jmp    L27
```

assistant: ```c
void icvTrace_64d(const double *src, int w, int h, double *trace) {
  int i, len = ((w) > (h) ? (h) : (w));
  double sum = 0;
  for (i = 0; len--; i += w + 1)
    sum += src[i];
  *trace = sum;
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<icvTrace_64d>:
  endbr64
  cmp    %edx,%esi
  cmovle %esi,%edx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L5
  lea    0x1(%rsi),%edx
  pxor   %xmm0,%xmm0
  movslq %edx,%rdx
  shl    $0x3,%rdx
  xchg   %ax,%ax
L17:
  sub    $0x1,%eax
  addsd  (%rdi),%xmm0
  add    %rdx,%rdi
  cmp    $0xffffffff,%eax
  jne    L17
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rcx)
  ret
```

assistant: ```c
void icvTrace_64d(const double *src, int w, int h, double *trace) {
  int i, len = ((w) > (h) ? (h) : (w));
  double sum = 0;
  for (i = 0; len--; i += w + 1)
    sum += src[i];
  *trace = sum;
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<icvTrace_64d>:
  endbr64
  cmp    %edx,%esi
  cmovle %esi,%edx
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  je     L15
  lea    0x1(%rsi),%edx
  pxor   %xmm0,%xmm0
  movslq %edx,%rdx
  shl    $0x3,%rdx
  xchg   %ax,%ax
L0:
  sub    $0x1,%eax
  addsd  (%rdi),%xmm0
  add    %rdx,%rdi
  cmp    $0xffffffff,%eax
  jne    L0
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax)
L15:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rcx)
  ret
```

assistant: ```c
void icvTrace_64d(const double *src, int w, int h, double *trace) {
  int i, len = ((w) > (h) ? (h) : (w));
  double sum = 0;
  for (i = 0; len--; i += w + 1)
    sum += src[i];
  *trace = sum;
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  sub    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  sub    %rcx,%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x20(%rbp),%rdx
  shr    %rdx
  cmp    %rdx,%rax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *data, size_t size) {
  int i;
  for (i = 0; i < size / 2; i++) {
    do {
      char temp = data[size - 1 - i];
      data[size - 1 - i] = data[i];
      data[i] = temp;
    } while (0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse>:
  endbr64
  mov    %rsi,%r8
  shr    %r8
  cmp    $0x1,%rsi
  jbe    L12
  lea    -0x1(%rdi,%rsi,1),%rdx
  mov    $0x0,%eax
L4:
  movzbl (%rdx),%ecx
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdx)
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %rax,%r8
  ja     L4
L12:
  ret
```

assistant: ```c
void reverse(char *data, size_t size) {
  int i;
  for (i = 0; i < size / 2; i++) {
    do {
      char temp = data[size - 1 - i];
      data[size - 1 - i] = data[i];
      data[i] = temp;
    } while (0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  mov    %rsi,%rdx
  shr    %rdx
  je     L13
  lea    -0x1(%rdi,%rsi,1),%rax
  lea    (%rdi,%rdx,1),%rsi
  nopl   (%rax)
L12:
  movzbl (%rax),%edx
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,0x1(%rax)
  mov    %dl,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L12
L13:
  ret
```

assistant: ```c
void reverse(char *data, size_t size) {
  int i;
  for (i = 0; i < size / 2; i++) {
    do {
      char temp = data[size - 1 - i];
      data[size - 1 - i] = data[i];
      data[i] = temp;
    } while (0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  mov    %rsi,%rdx
  shr    %rdx
  je     L5
  lea    -0x1(%rdi,%rsi,1),%rax
  lea    (%rdi,%rdx,1),%rsi
  nopl   (%rax)
L19:
  movzbl (%rax),%edx
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,0x1(%rax)
  mov    %dl,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L19
L5:
  ret
```

assistant: ```c
void reverse(char *data, size_t size) {
  int i;
  for (i = 0; i < size / 2; i++) {
    do {
      char temp = data[size - 1 - i];
      data[size - 1 - i] = data[i];
      data[i] = temp;
    } while (0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<matrixSubtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixSubtract(int rows, int cols, float *matrixC, float *matrixA, float *matrixB) {
  int i;
  for (i = 0; i < rows * cols; i++) {
    matrixC[i] = matrixA[i] - matrixB[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrixSubtract>:
  endbr64
  imul   %esi,%edi
  test   %edi,%edi
  jle    L0
  mov    %edi,%edi
  mov    $0x0,%eax
L9:
  movss  (%rcx,%rax,4),%xmm0
  subss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L9
L0:
  ret
```

assistant: ```c
void matrixSubtract(int rows, int cols, float *matrixC, float *matrixA, float *matrixB) {
  int i;
  for (i = 0; i < rows * cols; i++) {
    matrixC[i] = matrixA[i] - matrixB[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrixSubtract>:
  endbr64
  imul   %esi,%edi
  test   %edi,%edi
  jle    L12
  movslq %edi,%rdi
  xor    %eax,%eax
L5:
  movss  (%rcx,%rax,4),%xmm0
  subss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L5
L12:
  ret
```

assistant: ```c
void matrixSubtract(int rows, int cols, float *matrixC, float *matrixA, float *matrixB) {
  int i;
  for (i = 0; i < rows * cols; i++) {
    matrixC[i] = matrixA[i] - matrixB[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixSubtract>:
  endbr64
  imul   %edi,%esi
  test   %esi,%esi
  jle    L61
  lea    0x4(%rcx),%rdi
  mov    %rdx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  seta   %dil
  cmp    $0x1,%esi
  setne  %al
  test   %al,%dil
  je     L65
  lea    0x4(%r8),%rdi
  mov    %rdx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L65
  lea    -0x1(%rsi),%eax
  mov    %esi,%r9d
  cmp    $0x2,%eax
  jbe    L88
  mov    %esi,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  xchg   %ax,%ax
L8:
  movups (%rcx,%rax,1),%xmm0
  movups (%r8,%rax,1),%xmm2
  subps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L8
  mov    %esi,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%eax
  cmp    %edi,%esi
  je     L61
  sub    %edi,%esi
  mov    %esi,%r9d
  cmp    $0x1,%esi
  je     L67
L51:
  mov    %edi,%esi
  movq   (%rcx,%rsi,4),%xmm0
  movq   (%r8,%rsi,4),%xmm1
  subps  %xmm1,%xmm0
  movlps %xmm0,(%rdx,%rsi,4)
  mov    %r9d,%esi
  and    $0xfffffffe,%esi
  add    %esi,%eax
  cmp    %esi,%r9d
  je     L61
L67:
  cltq
  movss  (%rcx,%rax,4),%xmm0
  subss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   (%rax)
L92:
  movss  (%rcx,%rax,4),%xmm0
  subss  (%r8,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L92
L61:
  ret
L88:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L51
```

assistant: ```c
void matrixSubtract(int rows, int cols, float *matrixC, float *matrixA, float *matrixB) {
  int i;
  for (i = 0; i < rows * cols; i++) {
    matrixC[i] = matrixA[i] - matrixB[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L23:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  add    %rcx,%rax
  shl    $0x8,%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void transpose(int n, double A[][800]) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = i + 1; j < n; j++)
      swap(&A[i][j], &A[j][i]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r15
  lea    0x1900(%rsi),%r14
  lea    -0x1(%rdi),%eax
  mov    %rax,(%rsp)
  mov    $0x0,%r13d
  lea    -0x2(%rdi),%eax
  mov    %eax,0xc(%rsp)
L21:
  cmp    (%rsp),%r13
  je     L7
  lea    -0x18f8(%r14),%rbx
  mov    0xc(%rsp),%eax
  sub    %r13d,%eax
  add    %r13,%rax
  lea    0x10(%r15,%rax,8),%r12
  mov    %r14,%rbp
L14:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <swap@plt>
  add    $0x8,%rbx
  add    $0x1900,%rbp
  cmp    %r12,%rbx
  jne    L14
  add    $0x1,%r13
  add    $0x1908,%r14
  add    $0x1900,%r15
  jmp    L21
L7:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  ret
```

assistant: ```c
void transpose(int n, double A[][800]) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = i + 1; j < n; j++)
      swap(&A[i][j], &A[j][i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L23
  push   %r15
  lea    -0x1(%rdi),%eax
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    0x1900(%rsi),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  lea    -0x2(%rdi),%eax
  mov    %eax,0xc(%rsp)
  cmp    (%rsp),%rbp
  je     L27
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0xc(%rsp),%eax
  lea    -0x18f8(%r12),%r14
  mov    %r12,%r15
  sub    %ebp,%eax
  add    %rbp,%rax
  lea    0x10(%r13,%rax,8),%rbx
  nopl   0x0(%rax)
L31:
  mov    %r15,%rsi
  mov    %r14,%rdi
  add    $0x8,%r14
  add    $0x1900,%r15
  call   <swap@plt>
  cmp    %rbx,%r14
  jne    L31
  add    $0x1,%rbp
  add    $0x1908,%r12
  add    $0x1900,%r13
  cmp    (%rsp),%rbp
  jne    L26
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

assistant: ```c
void transpose(int n, double A[][800]) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = i + 1; j < n; j++)
      swap(&A[i][j], &A[j][i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<transpose>:
  endbr64
  test   %edi,%edi
  jle    L28
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    0x8(%rsi),%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L29
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x18f8(%r14),%r12
  mov    %r14,%rbp
  mov    %r15d,%ebx
  nopl   (%rax)
L37:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x8,%rbp
  call   <swap@plt>
  add    $0x1900,%r12
  cmp    %ebx,%r13d
  jg     L37
  add    $0x1,%r15d
  add    $0x1908,%r14
  cmp    %r15d,%r13d
  jne    L1
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  ret
```

assistant: ```c
void transpose(int n, double A[][800]) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = i + 1; j < n; j++)
      swap(&A[i][j], &A[j][i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D17
type: string

tool: D8: main

tool: D17: %s: Hello world


assistant: ```c
int main(int argc, char **argv) {
  printf("%s: Hello world\n", __func__);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D17: main

tool: D9: %s: Hello world


assistant: ```c
int main(int argc, char **argv) {
  printf("%s: Hello world\n", __func__);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D14: main

tool: D12: %s: Hello world


assistant: ```c
int main(int argc, char **argv) {
  printf("%s: Hello world\n", __func__);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string

tool: D18: main

tool: D13: %s: Hello world


assistant: ```c
int main(int argc, char **argv) {
  printf("%s: Hello world\n", __func__);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rcx
  lea    D35(%rip),%rdx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L14
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L3
L14:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L3:
  mov    -0x68(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rcx
  lea    D35(%rip),%rdx
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L24
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L41
L24:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L41:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
datatype: string
name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string

tool: D35: time and date: %r, %a %b %d, %Y

tool: D37: buffer length 16 is too small

tool: D22: buffer length 64 is too small

assistant: ```c
int main(void) {
  time_t t;
  struct tm *tmp;
  char buf1[16];
  char buf2[64];
  time(&t);
  tmp = localtime(&t);
  if (strftime(buf1, 16, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 16 is too small\n");
  else
    printf("%s\n", buf1);
  if (strftime(buf2, 64, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 64 is too small\n");
  else
    printf("%s\n", buf2);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rbx
  lea    0x10(%rsp),%rdi
  mov    %rax,%rcx
  lea    D17(%rip),%rdx
  mov    $0x10,%esi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L48
  lea    D25(%rip),%rdi
  call   <puts@plt>
L33:
  lea    0x20(%rsp),%rdi
  mov    %rbx,%rcx
  lea    D17(%rip),%rdx
  mov    $0x40,%esi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L1
  lea    D5(%rip),%rdi
  call   <puts@plt>
L2:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L48:
  lea    0x10(%rsp),%rdi
  call   <puts@plt>
  jmp    L33
L1:
  lea    0x20(%rsp),%rdi
  call   <puts@plt>
  jmp    L2
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D17: time and date: %r, %a %b %d, %Y

tool: D25: buffer length 16 is too small

tool: D5: buffer length 64 is too small

assistant: ```c
int main(void) {
  time_t t;
  struct tm *tmp;
  char buf1[16];
  char buf2[64];
  time(&t);
  tmp = localtime(&t);
  if (strftime(buf1, 16, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 16 is too small\n");
  else
    printf("%s\n", buf1);
  if (strftime(buf2, 64, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 64 is too small\n");
  else
    printf("%s\n", buf2);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  mov    %r13,%rdx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  mov    %rax,%rcx
  mov    %rax,%r12
  call   <strftime@plt>
  test   %rax,%rax
  jne    L46
  lea    D18(%rip),%rdi
  call   <puts@plt>
L15:
  lea    0x20(%rsp),%rbp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L44
  lea    D28(%rip),%rdi
  call   <puts@plt>
L38:
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L15
L44:
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L38
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string

tool: D8: time and date: %r, %a %b %d, %Y

tool: D18: buffer length 16 is too small

tool: D28: buffer length 64 is too small

assistant: ```c
int main(void) {
  time_t t;
  struct tm *tmp;
  char buf1[16];
  char buf2[64];
  time(&t);
  tmp = localtime(&t);
  if (strftime(buf1, 16, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 16 is too small\n");
  else
    printf("%s\n", buf1);
  if (strftime(buf2, 64, "time and date: %r, %a %b %d, %Y", tmp) == 0)
    printf("buffer length 64 is too small\n");
  else
    printf("%s\n", buf2);
  exit(0);
}
```