ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<quotestring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax,%rax,1),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L19
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rdx,1),%r9
  xor    %edx,%edx
  jmp    L15
L11:
  add    $0x1,%rdi
  mov    %r8b,(%rcx)
  mov    %esi,%edx
  cmp    %rdi,%r9
  je     L32
L15:
  movzbl (%rdi),%r8d
  movslq %edx,%rcx
  lea    0x1(%rdx),%esi
  add    %rax,%rcx
  cmp    $0x27,%r8b
  jne    L11
  movslq %esi,%rsi
  add    $0x1,%rdi
  movb   $0x27,(%rcx)
  add    $0x2,%edx
  movb   $0x27,(%rax,%rsi,1)
  cmp    %rdi,%r9
  jne    L15
L32:
  movslq %edx,%rdx
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rax,%rdx
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *quotestring(char *stringIn) {
  int slen = strlen(stringIn);
  char *stringOut = malloc(slen * 2 + 1);
  int x, y = 0;
  for (x = 0; x < slen; x++) {
    if (stringIn[x] == '\'') {
      stringOut[y] = '\'';
      y++;
      stringOut[y] = '\'';
      y++;
    } else {
      stringOut[y] = stringIn[x];
      y++;
    }
  }
  stringOut[y] = '\0';
  return stringOut;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x18(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm3
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  -0x14(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm4,%xmm4
  cvtss2sd -0xc(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x1c(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L45
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L45:
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L12
  ucomiss -0xc(%rbp),%xmm0
  jne    L12
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L12:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D35
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D47: %f %f %f %f %f

tool: D15: %f demo


tool: D36: Point is inside the Circle.

tool: D35: Point is on the Circle.

tool: D2: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r;
  float x1;
  float y1;
  float h;
  float g;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  h = (x1 - x) * (x1 - x) + (y1 - y) * (y1 - y);
  g = sqrt(h);
  printf("%f demo\n", g);
  if (g < r) {
    printf("Point is inside the Circle.");
  } else if (g == r) {
    printf("Point is on the Circle.");
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm0
  subss  0x14(%rsp),%xmm0
  movss  0x24(%rsp),%xmm1
  subss  0x18(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D31(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm0
  comiss 0xc(%rsp),%xmm0
  ja     L1
  movss  0xc(%rsp),%xmm3
  ucomiss %xmm3,%xmm0
  jp     L33
  jne    L33
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L51:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L1:
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L51
L33:
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L51
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D31
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string

tool: D19: %f %f %f %f %f

tool: D31: %f demo


tool: D16: Point is on the Circle.

tool: D7: Point is inside the Circle.

tool: D1: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r;
  float x1;
  float y1;
  float h;
  float g;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  h = (x1 - x) * (x1 - x) + (y1 - y) * (y1 - y);
  g = sqrt(h);
  printf("%f demo\n", g);
  if (g < r) {
    printf("Point is inside the Circle.");
  } else if (g == r) {
    printf("Point is on the Circle.");
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D9(%rip),%rdi
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm0
  movss  0x24(%rsp),%xmm1
  subss  0x14(%rsp),%xmm0
  subss  0x18(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  movaps %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  ja     L47
  ucomiss %xmm1,%xmm0
  jp     L10
  jne    L10
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L10:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L47:
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D42
data_type: string

tool: D9: %f %f %f %f %f

tool: D3: %f demo


tool: D4: Point is on the Circle.

tool: D12: Point is outside the Circle.

tool: D42: Point is inside the Circle.

assistant: ```c
int main() {
  float x, y, r;
  float x1;
  float y1;
  float h;
  float g;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  h = (x1 - x) * (x1 - x) + (y1 - y) * (y1 - y);
  g = sqrt(h);
  printf("%f demo\n", g);
  if (g < r) {
    printf("Point is inside the Circle.");
  } else if (g == r) {
    printf("Point is on the Circle.");
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D20(%rip),%rdi
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm0
  movss  0x24(%rsp),%xmm1
  subss  0x14(%rsp),%xmm0
  subss  0x18(%rsp),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  movaps %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0x1c(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  comiss %xmm1,%xmm0
  ja     L18
  ucomiss %xmm1,%xmm0
  jp     L34
  jne    L34
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L34:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L18:
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D17
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D20: %f %f %f %f %f

tool: D21: %f demo


tool: D2: Point is on the Circle.

tool: D17: Point is outside the Circle.

tool: D29: Point is inside the Circle.

assistant: ```c
int main() {
  float x, y, r;
  float x1;
  float y1;
  float h;
  float g;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  h = (x1 - x) * (x1 - x) + (y1 - y) * (y1 - y);
  g = sqrt(h);
  printf("%f demo\n", g);
  if (g < r) {
    printf("Point is inside the Circle.");
  } else if (g == r) {
    printf("Point is on the Circle.");
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<solcon_length_solution_intro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xca,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_length_solution_intro(int k, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(202, &k, n, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solcon_length_solution_intro>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0xca,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_length_solution_intro(int k, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(202, &k, n, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solcon_length_solution_intro>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0xca,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_length_solution_intro(int k, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(202, &k, n, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<solcon_length_solution_intro>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0xca,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int solcon_length_solution_intro(int k, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(202, &k, n, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L6
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x163,%edi
  call   <errhandler@plt>
L6:
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  mov    $0x164,%edi
  call   <errhandler@plt>
L31:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x1,-0x1c(%rbp)
  jmp    L38
L22:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L38:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L22
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D3: Storage cannot be allocated

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(355, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(356, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %edx,%r12d
  sub    %edi,%esi
  mov    %esi,%r14d
  lea    0x1(%rsi),%r15d
  sub    %edx,%ecx
  lea    0x1(%rcx),%ebx
  movslq %r15d,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r15d,%edi
  imul   %ebx,%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L21
L18:
  test   %r13,%r13
  je     L58
L32:
  movslq %r12d,%r12
  shl    $0x3,%r12
  sub    %r12,%r13
  mov    %r13,0x0(%rbp)
  cmp    $0x1,%r15d
  jle    L25
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  mov    %rbp,%rax
  lea    -0x1(%r14),%edx
  lea    0x8(%rbp,%rdx,8),%rcx
L49:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rbx,%rdx
  mov    %rdx,(%rax)
  cmp    %rcx,%rax
  jne    L49
L25:
  movslq 0xc(%rsp),%rdx
  shl    $0x3,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  lea    D14(%rip),%rdx
  lea    D39(%rip),%rsi
  mov    $0x163,%edi
  call   <errhandler@plt>
  jmp    L18
L58:
  lea    D14(%rip),%rdx
  lea    D39(%rip),%rsi
  mov    $0x164,%edi
  call   <errhandler@plt>
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D39
datatype: string

tool: D14: Storage cannot be allocated

tool: D39: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(355, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(356, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  sub    %r15d,%ecx
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    %ebp,%esi
  lea    0x1(%rcx),%ebx
  lea    0x1(%rsi),%r14d
  mov    %esi,%r12d
  movslq %r14d,%rdi
  sub    $0x18,%rsp
  shl    $0x3,%rdi
  mov    %ebx,0xc(%rsp)
  imul   %r14d,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %ebx,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r13,%r13
  je     L10
  test   %rbx,%rbx
  je     L39
L23:
  shl    $0x3,%r15
  sub    %r15,%rbx
  mov    %rbx,0x0(%r13)
  mov    %rbx,%rdx
  cmp    $0x1,%r14d
  jle    L4
  movslq 0xc(%rsp),%rcx
  lea    -0x1(%r12),%esi
  lea    0x8(%r13),%rax
  lea    0x8(%r13,%rsi,8),%rsi
  shl    $0x3,%rcx
  jmp    L26
  nopl   0x0(%rax)
L49:
  add    $0x8,%rax
L26:
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L49
L4:
  add    $0x18,%rsp
  shl    $0x3,%rbp
  mov    %r13,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  lea    D24(%rip),%rdx
  lea    D39(%rip),%rsi
  mov    $0x163,%edi
  call   <errhandler@plt>
  test   %rbx,%rbx
  jne    L23
L39:
  lea    D24(%rip),%rdx
  lea    D39(%rip),%rsi
  mov    $0x164,%edi
  call   <errhandler@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D39
data_type: string

tool: D24: Storage cannot be allocated

tool: D39: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(355, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(356, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matrix>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  sub    %r15d,%ecx
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  sub    %ebp,%esi
  lea    0x1(%rcx),%ebx
  lea    0x1(%rsi),%r14d
  mov    %esi,%r12d
  movslq %r14d,%rdi
  sub    $0x18,%rsp
  shl    $0x3,%rdi
  mov    %ebx,0xc(%rsp)
  imul   %r14d,%ebx
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %ebx,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r13,%r13
  je     L30
  test   %rbx,%rbx
  je     L59
L48:
  shl    $0x3,%r15
  sub    %r15,%rbx
  mov    %rbx,0x0(%r13)
  mov    %rbx,%rdx
  cmp    $0x1,%r14d
  jle    L19
  movslq 0xc(%rsp),%rcx
  lea    -0x1(%r12),%esi
  lea    0x8(%r13),%rax
  lea    0x10(%r13,%rsi,8),%rsi
  shl    $0x3,%rcx
  nopw   0x0(%rax,%rax,1)
L40:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L40
L19:
  add    $0x18,%rsp
  shl    $0x3,%rbp
  mov    %r13,%rax
  pop    %rbx
  sub    %rbp,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L30:
  lea    D39(%rip),%rdx
  lea    D9(%rip),%rsi
  mov    $0x163,%edi
  call   <errhandler@plt>
  test   %rbx,%rbx
  jne    L48
L59:
  lea    D39(%rip),%rdx
  lea    D9(%rip),%rsi
  mov    $0x164,%edi
  call   <errhandler@plt>
  jmp    L48
```

tool_calls: name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D39: Storage cannot be allocated

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c

assistant: ```c
double **matrix(int nrl, int nrh, int ncl, int nch) {
  int i;
  int nrow = nrh - nrl + 1;
  int ncol = nch - ncl + 1;
  double **pArray = (double **)malloc((size_t)(nrow * sizeof(double *)));
  double *pMatrix = (double *)malloc((size_t)(nrow * ncol * sizeof(double)));
  if (pArray == 0)
    errhandler(355, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  if (pMatrix == 0)
    errhandler(356, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/EvaBr/CFD-Lab/refs/heads/master/Worksheet3/helper.c", "Storage cannot be allocated");
  pArray[0] = pMatrix - ncl;
  for (i = 1; i < nrow; i++) {
    pArray[i] = pArray[i - 1] + ncol;
  }
  return pArray - nrl;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<typset_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <typ_is_tentative@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <typ_hash_ready@plt>
  test   %eax,%eax
  jne    L21
L9:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <typ_permanent_loc@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <add_tentative@plt>
  jmp    L11
L21:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <add_final@plt>
  nop
L11:
  nop
  leave
  ret
```

assistant: ```c
void typset_add(struct typset *set, struct typ *t) {
  if (typ_is_tentative(t) || !typ_hash_ready(t)) {
    add_tentative(set, typ_permanent_loc(t));
  } else {
    add_final(set, t);
  }
}
```