ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    -0x18(%rbp),%rax
  jmp    L7
L26:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L16
L24:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x18(%rbp),%rax
  jmp    L7
L4:
  addq   $0x1,-0x18(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t needlelen;
  if (*needle == '\0')
    return (char *)haystack;
  needlelen = strlen(needle);
  for (; (haystack = strchr(haystack, *needle)) != 0; haystack++)
    if (strncmp(haystack, needle, needlelen) == 0)
      return (char *)haystack;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmpb   $0x0,(%rsi)
  je     L16
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
L6:
  movsbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L16
  lea    0x1(%rbx),%r12
  jmp    L6
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t needlelen;
  if (*needle == '\0')
    return (char *)haystack;
  needlelen = strlen(needle);
  for (; (haystack = strchr(haystack, *needle)) != 0; haystack++)
    if (strncmp(haystack, needle, needlelen) == 0)
      return (char *)haystack;
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebx
  test   %bl,%bl
  je     L33
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r13
  jmp    L37
  nopl   0x0(%rax)
L35:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L33
  movzbl 0x0(%rbp),%ebx
  lea    0x1(%r12),%r14
L37:
  movsbl %bl,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L35
L33:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t needlelen;
  if (*needle == '\0')
    return (char *)haystack;
  needlelen = strlen(needle);
  for (; (haystack = strchr(haystack, *needle)) != 0; haystack++)
    if (strncmp(haystack, needle, needlelen) == 0)
      return (char *)haystack;
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebx
  test   %bl,%bl
  je     L8
  mov    %rdi,%r14
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r13
  jmp    L39
  nopl   0x0(%rax)
L34:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L8
  movzbl 0x0(%rbp),%ebx
  lea    0x1(%r12),%r14
L39:
  movsbl %bl,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L34
L8:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t needlelen;
  if (*needle == '\0')
    return (char *)haystack;
  needlelen = strlen(needle);
  for (; (haystack = strchr(haystack, *needle)) != 0; haystack++)
    if (strncmp(haystack, needle, needlelen) == 0)
      return (char *)haystack;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HashString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
L6:
  movzbl (%rax),%edx
  movsbl %dl,%r12d
  add    $0x1,%rax
  test   %r12d,%r12d
  je     L16
  lea    0x0(,%rbx,8),%edx
  mov    %r12d,%ecx
  add    %ecx,%edx
  add    %edx,%ebx
  jmp    L6
L16:
  nop
  mov    %ebx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned int HashString(string)
register char *string;
{
  register unsigned int result;
  register int c;
  result = 0;
  while (1) {
    c = *string;
    string++;
    if (c == 0) {
      break;
    }
    result += (result << 3) + c;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HashString>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L13
  mov    $0x0,%edx
L14:
  movsbl %al,%eax
  lea    (%rax,%rdx,8),%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L14
L27:
  mov    %edx,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
unsigned int HashString(string)
register char *string;
{
  register unsigned int result;
  register int c;
  result = 0;
  while (1) {
    c = *string;
    string++;
    if (c == 0) {
      break;
    }
    result += (result << 3) + c;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HashString>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  add    $0x1,%rdi
  test   %al,%al
  je     L6
  nopw   0x0(%rax,%rax,1)
L0:
  lea    (%rax,%r8,8),%eax
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L0
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int HashString(string)
register char *string;
{
  register unsigned int result;
  register int c;
  result = 0;
  while (1) {
    c = *string;
    string++;
    if (c == 0) {
      break;
    }
    result += (result << 3) + c;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HashString>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  add    $0x1,%rdi
  test   %al,%al
  je     L11
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%rax,%r8,8),%eax
  add    $0x1,%rdi
  add    %eax,%r8d
  movsbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L13
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int HashString(string)
register char *string;
{
  register unsigned int result;
  register int c;
  result = 0;
  while (1) {
    c = *string;
    string++;
    if (c == 0) {
      break;
    }
    result += (result << 3) + c;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  jmp    L16
L14:
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  mov    $0x0,%eax
  call   <link_error@plt>
L16:
  nop
  leave
  ret
```

assistant: ```c
void test5(int x) {
  extern int foo(int);
  if (x == 0)
    foo(x);
  else if (x == 0)
    link_error();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test5>:
  endbr64
  test   %edi,%edi
  je     L9
  ret
L9:
  sub    $0x8,%rsp
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test5(int x) {
  extern int foo(int);
  if (x == 0)
    foo(x);
  else if (x == 0)
    link_error();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test5>:
  endbr64
  test   %edi,%edi
  je     L8
  ret
  nopl   0x0(%rax)
L8:
  jmp    1050 <foo@plt>
```

assistant: ```c
void test5(int x) {
  extern int foo(int);
  if (x == 0)
    foo(x);
  else if (x == 0)
    link_error();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test5>:
  endbr64
  test   %edi,%edi
  je     L0
  ret
  nopl   0x0(%rax)
L0:
  jmp    1050 <foo@plt>
```

assistant: ```c
void test5(int x) {
  extern int foo(int);
  if (x == 0)
    foo(x);
  else if (x == 0)
    link_error();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__read_png_int_raw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t __read_png_int_raw(const uint8_t *buf) {
  int32_t b0, b1, b2, b3;
  b0 = buf[0];
  b1 = buf[1];
  b2 = buf[2];
  b3 = buf[3];
  return b0 << 24 | b1 << 16 | b2 << 8 | b3;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__read_png_int_raw>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x18,%eax
  mov    0x4(%rdi),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  or     0xc(%rdi),%eax
  mov    0x8(%rdi),%edx
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int32_t __read_png_int_raw(const uint8_t *buf) {
  int32_t b0, b1, b2, b3;
  b0 = buf[0];
  b1 = buf[1];
  b2 = buf[2];
  b3 = buf[3];
  return b0 << 24 | b1 << 16 | b2 << 8 | b3;
}
```
user: What is the c source code of the assembly code below?

```asm
<__read_png_int_raw>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  shl    $0x18,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    0x8(%rdi),%edx
  or     0xc(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int32_t __read_png_int_raw(const uint8_t *buf) {
  int32_t b0, b1, b2, b3;
  b0 = buf[0];
  b1 = buf[1];
  b2 = buf[2];
  b3 = buf[3];
  return b0 << 24 | b1 << 16 | b2 << 8 | b3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__read_png_int_raw>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  shl    $0x18,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    0x8(%rdi),%edx
  or     0xc(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int32_t __read_png_int_raw(const uint8_t *buf) {
  int32_t b0, b1, b2, b3;
  b0 = buf[0];
  b1 = buf[1];
  b2 = buf[2];
  b3 = buf[3];
  return b0 << 24 | b1 << 16 | b2 << 8 | b3;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<failoverlist_tests>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <test_failover_list_empty@plt>
  mov    %rax,%rbx
  lea    D101(%rip),%rdx
  lea    D13(%rip),%rsi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbx,%rbx
  je     L24
  mov    %rbx,%rsi
  lea    D128(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
L46:
  mov    $0x0,%edi
  call   <test_failover_list_single@plt>
  mov    %rax,%rbp
  lea    D30(%rip),%rdx
  lea    D13(%rip),%rsi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L13
  mov    %rbp,%rsi
  lea    D128(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
L8:
  mov    $0x0,%edi
  call   <test_failover_list_multiple@plt>
  mov    %rax,%rbp
  lea    D148(%rip),%rdx
  lea    D13(%rip),%rsi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L41
  mov    %rbp,%rsi
  lea    D128(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
L32:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  lea    D135(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  jmp    L46
L13:
  lea    D135(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L41:
  lea    D135(%rip),%rdi
  call   <puts@plt>
  jmp    L32
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D101
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D76
type_infered: string
name: extract_symbolic_data
arguments: data_label: D128
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D148
type_infered: string
name: extract_symbolic_data
arguments: data_label: D135
type_infered: string

tool: D101: test_failover_list_empty

tool: D13: failover_tests

tool: D76: Test Case %s.%s: 

tool: D128: FAIL: %s


tool: D30: test_failover_list_single

tool: D148: test_failover_list_multiple

tool: D135: PASS

assistant: ```c
int failoverlist_tests() {
  int result = 0;
  char *test_group = "failover_tests";
  do {
    char *r = test_failover_list_empty(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_empty");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_single(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_single");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_multiple(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_multiple");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<failoverlist_tests>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D39(%rip),%r14
  push   %r13
  lea    D108(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <test_failover_list_empty@plt>
  lea    D24(%rip),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L23
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%r12d
  call   <printf@plt>
L24:
  xor    %edi,%edi
  call   <test_failover_list_single@plt>
  lea    D73(%rip),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L30
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
L5:
  xor    %edi,%edi
  call   <test_failover_list_multiple@plt>
  lea    D32(%rip),%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L22
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L23:
  lea    D91(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L24
  nopl   0x0(%rax)
L22:
  lea    D91(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  lea    D91(%rip),%rdi
  call   <puts@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D108
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D14
type_infered: string
name: parse_data
arguments: tag: D73
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string
name: parse_data
arguments: tag: D91
type_infered: string

tool: D39: failover_tests

tool: D108: Test Case %s.%s: 

tool: D24: test_failover_list_empty

tool: D14: FAIL: %s


tool: D73: test_failover_list_single

tool: D32: test_failover_list_multiple

tool: D91: PASS

assistant: ```c
int failoverlist_tests() {
  int result = 0;
  char *test_group = "failover_tests";
  do {
    char *r = test_failover_list_empty(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_empty");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_single(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_single");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_multiple(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_multiple");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<failoverlist_tests>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  lea    D94(%rip),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  call   <test_failover_list_empty@plt>
  lea    D71(%rip),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L26
  mov    %rbp,%rsi
  xor    %eax,%eax
  mov    $0x2,%r14d
  mov    $0x1,%ebx
  lea    D88(%rip),%rdi
  call   <printf@plt>
L35:
  xor    %edi,%edi
  call   <test_failover_list_single@plt>
  lea    D52(%rip),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L48
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L30:
  xor    %edi,%edi
  call   <test_failover_list_multiple@plt>
  lea    D30(%rip),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  test   %rbp,%rbp
  je     L14
  mov    %rbp,%rsi
  add    $0x1,%r14d
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L26:
  lea    D2(%rip),%rdi
  mov    $0x1,%r14d
  xor    %ebx,%ebx
  call   <puts@plt>
  jmp    L35
  nopl   0x0(%rax)
L14:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  lea    D2(%rip),%rdi
  mov    %ebx,%r14d
  call   <puts@plt>
  jmp    L30
```

tool_calls: name: read_data
arguments: data_tag: D94
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D71
datatype: string
name: read_data
arguments: data_tag: D88
datatype: string
name: read_data
arguments: data_tag: D52
datatype: string
name: read_data
arguments: data_tag: D30
datatype: string
name: read_data
arguments: data_tag: D2
datatype: string

tool: D94: failover_tests

tool: D5: Test Case %s.%s: 

tool: D71: test_failover_list_empty

tool: D88: FAIL: %s


tool: D52: test_failover_list_single

tool: D30: test_failover_list_multiple

tool: D2: PASS

assistant: ```c
int failoverlist_tests() {
  int result = 0;
  char *test_group = "failover_tests";
  do {
    char *r = test_failover_list_empty(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_empty");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_single(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_single");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  do {
    char *r = test_failover_list_multiple(0);
    printf("Test Case %s.%s: ", test_group, "test_failover_list_multiple");
    if (r) {
      printf("FAIL: %s\n", r);
      result++;
    } else
      printf("PASS\n");
  } while (0);
  ;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L19:
  call   <fork@plt>
  test   %eax,%eax
  jne    L25
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x2,-0x4(%rbp)
  jle    L19
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string

tool: D15: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i <= 2; i++) {
    if (!fork())
      printf("%d\n", i);
  }
  printf("%d\n", i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  je     L36
L14:
  call   <fork@plt>
  test   %eax,%eax
  je     L4
L31:
  mov    $0x3,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L36:
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L4:
  mov    $0x2,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L31
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: string

tool: D14: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i <= 2; i++) {
    if (!fork())
      printf("%d\n", i);
  }
  printf("%d\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  call   <fork@plt>
  test   %eax,%eax
  je     L25
L2:
  call   <fork@plt>
  test   %eax,%eax
  je     L39
L18:
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L25:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L2
L39:
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i <= 2; i++) {
    if (!fork())
      printf("%d\n", i);
  }
  printf("%d\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  call   <fork@plt>
  test   %eax,%eax
  je     L17
L25:
  call   <fork@plt>
  test   %eax,%eax
  je     L8
L21:
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L17:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L25
L8:
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 1; i <= 2; i++) {
    if (!fork())
      printf("%d\n", i);
  }
  printf("%d\n", i);
  return 0;
}
```