ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_private>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L142:
  addl   $0x1,-0x10(%rbp)
L32:
  cmpl   $0xf,-0x10(%rbp)
  jle    L142
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L57:
  addl   $0x1,-0x10(%rbp)
L31:
  cmpl   $0xf,-0x10(%rbp)
  jle    L57
  movl   $0x0,-0x10(%rbp)
  jmp    L123
L22:
  addl   $0x1,-0x10(%rbp)
L123:
  cmpl   $0xf,-0x10(%rbp)
  jle    L22
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L40:
  addl   $0x1,-0x10(%rbp)
L29:
  cmpl   $0xf,-0x10(%rbp)
  jle    L40
  movl   $0x0,-0x10(%rbp)
  jmp    L79
L60:
  addl   $0x1,-0x10(%rbp)
L79:
  cmpl   $0xf,-0x10(%rbp)
  jle    L60
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L39:
  addl   $0x1,-0x10(%rbp)
L1:
  cmpl   $0xf,-0x10(%rbp)
  jle    L39
  movl   $0x0,-0x10(%rbp)
  jmp    L114
L145:
  addl   $0x1,-0x10(%rbp)
L114:
  cmpl   $0xf,-0x10(%rbp)
  jle    L145
  movl   $0x0,-0x10(%rbp)
  jmp    L43
L68:
  addl   $0x1,-0x10(%rbp)
L43:
  cmpl   $0xf,-0x10(%rbp)
  jle    L68
  movl   $0x0,-0x10(%rbp)
  jmp    L91
L99:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
L91:
  cmpl   $0xf,-0x10(%rbp)
  jle    L99
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_private() {
  int i;
#pragma omp parallel
#pragma omp for simd private(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(0)
  for (i = 0; i < 16; ++i)
    ;
  int x, y, z;
#pragma omp parallel
#pragma omp for simd private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y, z)
  for (i = 0; i < 16; ++i) {
    x = y * i + z;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_private>:
  endbr64
  ret
```

assistant: ```c
void test_private() {
  int i;
#pragma omp parallel
#pragma omp for simd private(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(0)
  for (i = 0; i < 16; ++i)
    ;
  int x, y, z;
#pragma omp parallel
#pragma omp for simd private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y, z)
  for (i = 0; i < 16; ++i) {
    x = y * i + z;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_private>:
  endbr64
  ret
```

assistant: ```c
void test_private() {
  int i;
#pragma omp parallel
#pragma omp for simd private(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(0)
  for (i = 0; i < 16; ++i)
    ;
  int x, y, z;
#pragma omp parallel
#pragma omp for simd private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y, z)
  for (i = 0; i < 16; ++i) {
    x = y * i + z;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<test_private>:
  endbr64
  ret
```

assistant: ```c
void test_private() {
  int i;
#pragma omp parallel
#pragma omp for simd private(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(0)
  for (i = 0; i < 16; ++i)
    ;
  int x, y, z;
#pragma omp parallel
#pragma omp for simd private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp parallel
#pragma omp for simd private(x, y, z)
  for (i = 0; i < 16; ++i) {
    x = y * i + z;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xf4240,%edi
  call   <test1@plt>
  mov    $0xf4240,%edi
  call   <test2@plt>
  mov    $0xf4240,%edi
  call   <test3@plt>
  mov    $0x3e8,%esi
  mov    $0xf4240,%edi
  call   <test4@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test1(1000 * 1000);
  test2(1000 * 1000);
  test3(1000 * 1000);
  test4(1000 * 1000, 1000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <test1@plt>
  mov    $0xf4240,%edi
  call   <test2@plt>
  mov    $0xf4240,%edi
  call   <test3@plt>
  mov    $0x3e8,%esi
  mov    $0xf4240,%edi
  call   <test4@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test1(1000 * 1000);
  test2(1000 * 1000);
  test3(1000 * 1000);
  test4(1000 * 1000, 1000);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <test1@plt>
  mov    $0xf4240,%edi
  call   <test2@plt>
  mov    $0xf4240,%edi
  call   <test3@plt>
  mov    $0x3e8,%esi
  mov    $0xf4240,%edi
  call   <test4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test1(1000 * 1000);
  test2(1000 * 1000);
  test3(1000 * 1000);
  test4(1000 * 1000, 1000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf4240,%edi
  call   <test1@plt>
  mov    $0xf4240,%edi
  call   <test2@plt>
  mov    $0xf4240,%edi
  call   <test3@plt>
  mov    $0x3e8,%esi
  mov    $0xf4240,%edi
  call   <test4@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test1(1000 * 1000);
  test2(1000 * 1000);
  test3(1000 * 1000);
  test4(1000 * 1000, 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PAPIF_QUERY_NAMED_EVENT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %edx,-0xa4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xa4(%rbp),%edx
  mov    -0x98(%rbp),%rsi
  lea    -0x90(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x80,%edx
  mov    %rax,%rdi
  call   <Fortran2cstring@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <PAPI_query_named_event@plt>
  mov    -0xa0(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void PAPIF_QUERY_NAMED_EVENT(char *EventName, int *check, int Event_len) {
  char tmp[128];
  Fortran2cstring(tmp, EventName, 128, Event_len);
  *check = PAPI_query_named_event(tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PAPIF_QUERY_NAMED_EVENT>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x80,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <Fortran2cstring@plt>
  mov    %rbp,%rdi
  call   <PAPI_query_named_event@plt>
  mov    %eax,(%rbx)
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void PAPIF_QUERY_NAMED_EVENT(char *EventName, int *check, int Event_len) {
  char tmp[128];
  Fortran2cstring(tmp, EventName, 128, Event_len);
  *check = PAPI_query_named_event(tmp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PAPIF_QUERY_NAMED_EVENT>:
  endbr64
  push   %rbp
  mov    %edx,%ecx
  mov    $0x80,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <Fortran2cstring@plt>
  mov    %rbp,%rdi
  call   <PAPI_query_named_event@plt>
  mov    %eax,(%rbx)
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void PAPIF_QUERY_NAMED_EVENT(char *EventName, int *check, int Event_len) {
  char tmp[128];
  Fortran2cstring(tmp, EventName, 128, Event_len);
  *check = PAPI_query_named_event(tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PAPIF_QUERY_NAMED_EVENT>:
  endbr64
  push   %rbp
  mov    %edx,%ecx
  mov    $0x80,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <Fortran2cstring@plt>
  mov    %rbp,%rdi
  call   <PAPI_query_named_event@plt>
  mov    %eax,(%rbx)
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void PAPIF_QUERY_NAMED_EVENT(char *EventName, int *check, int Event_len) {
  char tmp[128];
  Fortran2cstring(tmp, EventName, 128, Event_len);
  *check = PAPI_query_named_event(tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xef34ca9f65fb16,%rdx
  imul   %rdx,%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L28
L18:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L59
  lea    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  lea    -0x10(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzwl -0x1a(%rbp),%edx
  mov    %dx,(%rax)
  jmp    L31
L59:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
L31:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L35
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1b(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x7,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x7,%rax
  movzbl -0x1b(%rbp),%edx
  mov    %dl,(%rax)
L35:
  addq   $0x1,-0x18(%rbp)
L28:
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L18
  mov    -0x10(%rbp),%rax
  lea    -0x14c18299(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      if (state[0UL] == local1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy12;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 348226201UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ee5b9fd1c,%rcx
  add    %rcx,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rsi
  test   %rsi,%rsi
  je     L27
  mov    $0x0,%eax
L1:
  mov    (%rsp),%rcx
  cmp    %rax,%rcx
  jae    L47
  movzwl (%rsp),%ecx
  movzwl 0x6(%rsp),%edi
  mov    %di,(%rsp)
  mov    %cx,0x6(%rsp)
L17:
  cmp    %rax,(%rsp)
  je     L31
L54:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L1
L27:
  mov    (%rsp),%rax
  sub    $0x14c18299,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  ret
L47:
  add    %rcx,%rcx
  mov    %rcx,(%rsp,%rax,8)
  jmp    L17
L31:
  movzbl 0x1(%rsp),%ecx
  movzbl 0x7(%rsp),%edi
  mov    %dil,0x1(%rsp)
  mov    %cl,0x7(%rsp)
  jmp    L54
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      if (state[0UL] == local1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy12;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 348226201UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movabs $0xdf61e99ee5b9fd1c,%rdx
  sub    $0x18,%rsp
  mov    0x8(%rdi),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  add    %rdx,%rax
  mov    %rax,(%rsp)
  test   %rcx,%rcx
  je     L52
  xor    %edx,%edx
L49:
  cmp    %rax,%rdx
  jbe    L44
  movzwl (%rsp),%eax
  movzwl 0x6(%rsp),%edi
  mov    %ax,0x6(%rsp)
  mov    %di,(%rsp)
  mov    (%rsp),%rax
L4:
  cmp    %rax,%rdx
  jne    L22
  movzbl 0x1(%rsp),%eax
  movzbl 0x7(%rsp),%edi
  mov    %al,0x7(%rsp)
  mov    %dil,0x1(%rsp)
  mov    (%rsp),%rax
L22:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L49
L52:
  sub    $0x14c18299,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L44:
  add    %rax,%rax
  mov    %rax,(%rsp,%rdx,8)
  jmp    L4
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      if (state[0UL] == local1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy12;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 348226201UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  movabs $0xdf61e99ee5b9fd1c,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  add    %rcx,%rax
  mov    0x8(%rdi),%rcx
  test   %rcx,%rcx
  je     L145
  add    %rax,%rax
  mov    %rax,(%rsp)
  je     L26
  cmp    $0x1,%rcx
  jne    L99
L145:
  sub    $0x14c18299,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L156
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  movb   $0x0,0x1(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    (%rsp),%rax
  cmp    $0x1,%rcx
  je     L145
  test   %rax,%rax
  jne    L99
  movzwl (%rsp),%eax
  movzwl 0x6(%rsp),%esi
  mov    %ax,0x6(%rsp)
  mov    %si,(%rsp)
  mov    (%rsp),%rax
  cmp    $0x1,%rax
  jne    L38
  movzbl 0x1(%rsp),%eax
  movzbl 0x7(%rsp),%esi
  mov    %al,0x7(%rsp)
  mov    %sil,0x1(%rsp)
  mov    (%rsp),%rax
L38:
  cmp    $0x2,%rcx
  jbe    L145
  mov    $0x2,%esi
L41:
  cmp    %rax,%rsi
  jbe    L133
  movzwl (%rsp),%eax
  movzwl 0x6(%rsp),%edi
  mov    %ax,0x6(%rsp)
  mov    %di,(%rsp)
  mov    (%rsp),%rax
L154:
  cmp    %rax,%rsi
  je     L158
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L41
  jmp    L145
  nopl   (%rax)
L99:
  add    %rax,%rax
  mov    %rax,0x8(%rsp)
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L133:
  add    %rax,%rax
  mov    %rax,(%rsp,%rsi,8)
  jmp    L154
  nopl   0x0(%rax)
L158:
  movzbl 0x1(%rsp),%eax
  movzbl 0x7(%rsp),%edi
  add    $0x1,%rsi
  mov    %dil,0x1(%rsp)
  mov    %al,0x7(%rsp)
  mov    (%rsp),%rax
  cmp    %rcx,%rsi
  jne    L41
  jmp    L145
L156:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      if (state[0UL] == local1) {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy12;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 348226201UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_of_powers_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L6
  mov    -0x8(%rbp),%eax
  jmp    L3
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <power@plt>
  add    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <sum_of_powers_helper>
L3:
  leave
  ret
```

assistant: ```c
int sum_of_powers_helper(n, sum, count) {
  if (count == 0)
    return sum;
  else {
    sum = sum + power(count);
    return sum_of_powers_helper(n, sum, count - 1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sum_of_powers_helper>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %edx,%edx
  jne    L0
L3:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %edi,%r12d
  mov    %edx,%ebp
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <power@plt>
  lea    -0x1(%rbp),%edx
  lea    (%rax,%rbx,1),%esi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <sum_of_powers_helper>
  mov    %eax,%ebx
  jmp    L3
```

assistant: ```c
int sum_of_powers_helper(n, sum, count) {
  if (count == 0)
    return sum;
  else {
    sum = sum + power(count);
    return sum_of_powers_helper(n, sum, count - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sum_of_powers_helper>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L14
  mov    %edx,%ebx
  nopl   0x0(%rax)
L16:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <power@plt>
  add    %eax,%r12d
  sub    $0x1,%ebx
  jne    L16
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int sum_of_powers_helper(n, sum, count) {
  if (count == 0)
    return sum;
  else {
    sum = sum + power(count);
    return sum_of_powers_helper(n, sum, count - 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum_of_powers_helper>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L10
  mov    %edx,%ebx
  nopl   0x0(%rax)
L4:
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <power@plt>
  add    %eax,%r12d
  sub    $0x1,%ebx
  jne    L4
L10:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int sum_of_powers_helper(n, sum, count) {
  if (count == 0)
    return sum;
  else {
    sum = sum + power(count);
    return sum_of_powers_helper(n, sum, count - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x7,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x9,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L5
L24:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L5:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string

tool: D3: %d

assistant: ```c
int main() {
  int a[] = {3, 6, 1, 3, 7, 8, 9, 2, 5};
  int len = sizeof(a) / sizeof(a[0]);
  quick(a, 0, len);
  for (int i = 0; i < len; i++)
    printf("%d", a[i]);
  return 0;
}
```