ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x5254532054534554,%rax
  mov    $0x474e49,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <string_reverse@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: %s


assistant: ```c
int main() {
  char str[100] = "TEST STRING";
  printf("%s\n", str);
  string_reverse(str);
  printf("%s\n", str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x0,0x60(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <string_reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D3
type: byte[16]

tool: D2: %s


tool: {"D3": [0x54,0x45,0x53,0x54,0x20,0x53,0x54,0x52,0x49,0x4e,0x47,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  char str[100] = "TEST STRING";
  printf("%s\n", str);
  string_reverse(str);
  printf("%s\n", str);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x0,0x60(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <string_reverse@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D8
type: byte[16]

tool: D19: %s


tool: {"D8": [0x54,0x45,0x53,0x54,0x20,0x53,0x54,0x52,0x49,0x4e,0x47,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  char str[100] = "TEST STRING";
  printf("%s\n", str);
  string_reverse(str);
  printf("%s\n", str);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SetMotors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <SetMotor@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <SetMotor@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <SetMotor@plt>
  nop
  leave
  ret
```

assistant: ```c
void SetMotors(int v) {
  SetMotor(0, v);
  SetMotor(1, v);
  SetMotor(2, v);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SetMotors>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  mov    $0x0,%edi
  call   <SetMotor@plt>
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <SetMotor@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <SetMotor@plt>
  pop    %rbx
  ret
```

assistant: ```c
void SetMotors(int v) {
  SetMotor(0, v);
  SetMotor(1, v);
  SetMotor(2, v);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SetMotors>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <SetMotor@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  call   <SetMotor@plt>
  mov    %ebp,%esi
  mov    $0x2,%edi
  pop    %rbp
  jmp    1050 <SetMotor@plt>
```

assistant: ```c
void SetMotors(int v) {
  SetMotor(0, v);
  SetMotor(1, v);
  SetMotor(2, v);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SetMotors>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <SetMotor@plt>
  mov    %ebp,%esi
  mov    $0x1,%edi
  call   <SetMotor@plt>
  mov    %ebp,%esi
  mov    $0x2,%edi
  pop    %rbp
  jmp    1050 <SetMotor@plt>
```

assistant: ```c
void SetMotors(int v) {
  SetMotor(0, v);
  SetMotor(1, v);
  SetMotor(2, v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L0
  movl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L14
L0:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L4
L14:
  cmpl   $0x0,-0x10(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L19
L13:
  mov    -0x8(%rbp),%rax
L19:
  leave
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  char *result;
  int found = 0;
  int i = 0;
  while (i < strlen(haystack)) {
    if (haystack[i] == needle) {
      found = 1;
      result = malloc(i * sizeof(char));
      strncpy(result, haystack, i + 1);
      result[i + 1] = '\0';
      break;
    }
    i++;
  }
  if (!found) {
    return NULL;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L28:
  mov    %ebx,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L24
  lea    0x1(%rbx),%rax
  cmp    %r12b,0x0(%rbp,%rbx,1)
  je     L8
  mov    %rax,%rbx
  jmp    L28
L8:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x1(%r13),%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  jmp    L5
L24:
  mov    $0x0,%r12d
L5:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  char *result;
  int found = 0;
  int i = 0;
  while (i < strlen(haystack)) {
    if (haystack[i] == needle) {
      found = 1;
      result = malloc(i * sizeof(char));
      strncpy(result, haystack, i + 1);
      result[i + 1] = '\0';
      break;
    }
    i++;
  }
  if (!found) {
    return NULL;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L9:
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%r14d
  add    $0x1,%rbx
  cmp    %r12b,%al
  je     L12
L20:
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  char *result;
  int found = 0;
  int i = 0;
  while (i < strlen(haystack)) {
    if (haystack[i] == needle) {
      found = 1;
      result = malloc(i * sizeof(char));
      strncpy(result, haystack, i + 1);
      result[i + 1] = '\0';
      break;
    }
    i++;
  }
  if (!found) {
    return NULL;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L16:
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%r14d
  add    $0x1,%rbx
  cmp    %r12b,%al
  je     L21
L20:
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *find(char *haystack, char needle) {
  char *result;
  int found = 0;
  int i = 0;
  while (i < strlen(haystack)) {
    if (haystack[i] == needle) {
      found = 1;
      result = malloc(i * sizeof(char));
      strncpy(result, haystack, i + 1);
      result[i + 1] = '\0';
      break;
    }
    i++;
  }
  if (!found) {
    return NULL;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strnpc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L15
L26:
  addq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
L15:
  cmpq   $0x0,-0x10(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L26
L12:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strnpc(const char *str, size_t len) {
  while (len && isspace((int)*str)) {
    str++;
    len--;
  }
  return (char *)str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnpc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L14
  lea    (%rdi,%rsi,1),%rbp
L21:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L14
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L21
  mov    %rbp,%rbx
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strnpc(const char *str, size_t len) {
  while (len && isspace((int)*str)) {
    str++;
    len--;
  }
  return (char *)str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strnpc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L4
  lea    (%rdi,%rsi,1),%rbx
  jmp    L29
  nopl   0x0(%rax)
L32:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L4
L29:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L32
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strnpc(const char *str, size_t len) {
  while (len && isspace((int)*str)) {
    str++;
    len--;
  }
  return (char *)str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strnpc>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L17
  lea    (%rdi,%rsi,1),%rbx
  jmp    L5
  nopl   0x0(%rax)
L35:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L17
L5:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strnpc(const char *str, size_t len) {
  while (len && isspace((int)*str)) {
    str++;
    len--;
  }
  return (char *)str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <f@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int a = f(1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = f(1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = f(1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = f(1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<glob_match_after_star>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%r13
  mov    -0x30(%rbp),%r12
  jmp    L28
L123:
  cmp    $0x3f,%bl
  jne    L28
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
  jmp    L48
L28:
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rax),%ebx
  cmp    $0x3f,%bl
  je     L123
  cmp    $0x2a,%bl
  je     L123
  test   %bl,%bl
  jne    L45
  mov    $0x1,%eax
  jmp    L48
L45:
  cmp    $0x5c,%bl
  jne    L139
  movzbl 0x0(%r13),%r14d
  jmp    L87
L139:
  mov    %ebx,%r14d
L87:
  cmp    $0x5b,%bl
  je     L32
  movzbl (%r12),%eax
  cmp    %al,%r14b
  jne    L125
L32:
  lea    -0x1(%r13),%rax
  mov    $0x0,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <glob_match@plt>
  test   %eax,%eax
  je     L125
  mov    $0x1,%eax
  jmp    L48
L125:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  test   %al,%al
  jne    L87
  mov    $0x0,%eax
L48:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
int glob_match_after_star(pattern, text)
char *pattern, *text;
{
  register char *p = pattern, *t = text;
  register char c, c1;
  while ((c = *p++) == '?' || c == '*') {
    if (c == '?' && *t++ == 0)
      return 0;
  }
  if (c == 0)
    return 1;
  if (c == '\\')
    c1 = *p;
  else
    c1 = c;
  for (;;) {
    if ((c == '[' || *t == c1) && glob_match(p - 1, t, 0))
      return 1;
    if (*t++ == 0)
      return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glob_match_after_star>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    0x1(%rdi),%r12
  movzbl (%rdi),%ebx
  cmp    $0x2a,%bl
  je     L161
  cmp    $0x3f,%bl
  je     L161
  mov    %r12,%rax
  mov    %rdi,%r12
  jmp    L84
L148:
  mov    %rax,%r12
L161:
  cmp    $0x3f,%bl
  je     L93
L165:
  lea    0x1(%r12),%rax
  movzbl -0x1(%rax),%ebx
  cmp    $0x2a,%bl
  je     L148
  cmp    $0x3f,%bl
  je     L148
L84:
  mov    $0x1,%edx
  test   %bl,%bl
  je     L50
  mov    %ebx,%r13d
  cmp    $0x5c,%bl
  jne    L76
  movzbl (%rax),%r13d
  jmp    L76
L93:
  lea    0x1(%rbp),%rax
  cmpb   $0x0,0x0(%rbp)
  je     L78
  mov    %rax,%rbp
  jmp    L165
L62:
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <glob_match@plt>
  test   %eax,%eax
  jne    L163
L95:
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  je     L164
L76:
  cmp    $0x5b,%bl
  je     L62
  cmp    %r13b,0x0(%rbp)
  jne    L95
  jmp    L62
L164:
  mov    $0x0,%edx
  jmp    L50
L78:
  mov    $0x0,%edx
L50:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L163:
  mov    $0x1,%edx
  jmp    L50
```

assistant: ```c
int glob_match_after_star(pattern, text)
char *pattern, *text;
{
  register char *p = pattern, *t = text;
  register char c, c1;
  while ((c = *p++) == '?' || c == '*') {
    if (c == '?' && *t++ == 0)
      return 0;
  }
  if (c == 0)
    return 1;
  if (c == '\\')
    c1 = *p;
  else
    c1 = c;
  for (;;) {
    if ((c == '[' || *t == c1) && glob_match(p - 1, t, 0))
      return 1;
    if (*t++ == 0)
      return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<glob_match_after_star>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L22:
  cmp    $0x2a,%bl
  jne    L29
L78:
  mov    %rax,%rbp
L44:
  movzbl 0x0(%rbp),%ebx
  lea    0x1(%rbp),%rax
  cmp    $0x3f,%bl
  jne    L22
  cmpb   $0x0,(%r12)
  lea    0x1(%r12),%rdx
  je     L39
  mov    %rdx,%r12
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L29:
  test   %bl,%bl
  je     L33
  mov    %ebx,%r13d
  cmp    $0x5c,%bl
  jne    L16
  movzbl (%rax),%r13d
  cmp    $0x5b,%bl
  jne    L68
  nopl   (%rax)
L117:
  xor    %edx,%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <glob_match@plt>
  test   %eax,%eax
  jne    L33
  movzbl (%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L39
L16:
  cmp    $0x5b,%bl
  je     L117
L68:
  movzbl (%r12),%eax
  cmp    %r13b,%al
  je     L117
  add    $0x1,%r12
  test   %al,%al
  jne    L16
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int glob_match_after_star(pattern, text)
char *pattern, *text;
{
  register char *p = pattern, *t = text;
  register char c, c1;
  while ((c = *p++) == '?' || c == '*') {
    if (c == '?' && *t++ == 0)
      return 0;
  }
  if (c == 0)
    return 1;
  if (c == '\\')
    c1 = *p;
  else
    c1 = c;
  for (;;) {
    if ((c == '[' || *t == c1) && glob_match(p - 1, t, 0))
      return 1;
    if (*t++ == 0)
      return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glob_match_after_star>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L29
L76:
  cmp    $0x2a,%bl
  jne    L91
L71:
  mov    %rax,%r12
L29:
  movzbl (%r12),%ebx
  lea    0x1(%r12),%rax
  cmp    $0x3f,%bl
  jne    L76
  cmpb   $0x0,0x0(%rbp)
  lea    0x1(%rbp),%rdx
  je     L114
  mov    %rdx,%rbp
  jmp    L71
  cs nopw 0x0(%rax,%rax,1)
L91:
  test   %bl,%bl
  je     L112
  cmp    $0x5c,%bl
  je     L115
  cmp    $0x5b,%bl
  jne    L25
  jmp    L122
L52:
  add    $0x1,%rbp
  test   %al,%al
  je     L114
L25:
  movzbl 0x0(%rbp),%eax
  cmp    %al,%bl
  jne    L52
  xor    %edx,%edx
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <glob_match@plt>
  test   %eax,%eax
  jne    L112
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  jne    L25
L114:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L55:
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  je     L114
L122:
  xor    %edx,%edx
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <glob_match@plt>
  test   %eax,%eax
  je     L55
L112:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L115:
  movzbl (%rax),%ebx
  jmp    L25
```

assistant: ```c
int glob_match_after_star(pattern, text)
char *pattern, *text;
{
  register char *p = pattern, *t = text;
  register char c, c1;
  while ((c = *p++) == '?' || c == '*') {
    if (c == '?' && *t++ == 0)
      return 0;
  }
  if (c == 0)
    return 1;
  if (c == '\\')
    c1 = *p;
  else
    c1 = c;
  for (;;) {
    if ((c == '[' || *t == c1) && glob_match(p - 1, t, 0))
      return 1;
    if (*t++ == 0)
      return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x7d2b7500,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L40
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L40:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L25
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L6
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L6:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L4
L18:
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int ans = 2100000000;
  if (ans > a) {
    ans = a;
  }
  if (ans > b) {
    ans = b;
  }
  if (ans > c) {
    ans = c;
  }
  if (ans == -1) {
    return 0;
  }
  return ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<min>:
  endbr64
  mov    $0x7d2b7500,%eax
  cmp    %eax,%edi
  cmovg  %eax,%edi
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovle %esi,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  cmp    $0xffffffff,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int ans = 2100000000;
  if (ans > a) {
    ans = a;
  }
  if (ans > b) {
    ans = b;
  }
  if (ans > c) {
    ans = c;
  }
  if (ans == -1) {
    return 0;
  }
  return ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  mov    $0x7d2b7500,%eax
  cmp    %eax,%edi
  cmovg  %eax,%edi
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovle %esi,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  xor    %edx,%edx
  cmp    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int ans = 2100000000;
  if (ans > a) {
    ans = a;
  }
  if (ans > b) {
    ans = b;
  }
  if (ans > c) {
    ans = c;
  }
  if (ans == -1) {
    return 0;
  }
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min>:
  endbr64
  mov    $0x7d2b7500,%eax
  cmp    %eax,%edi
  cmovg  %eax,%edi
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovle %esi,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  xor    %edx,%edx
  cmp    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int ans = 2100000000;
  if (ans > a) {
    ans = a;
  }
  if (ans > b) {
    ans = b;
  }
  if (ans > c) {
    ans = c;
  }
  if (ans == -1) {
    return 0;
  }
  return ans;
}
```