ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<d1cp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  movsd  (%rbx),%xmm0
  movsd  %xmm0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void *d1cp(void *key) {
  double *newkey = malloc(sizeof(double));
  *newkey = *(double *)key;
  return newkey;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L9:
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <interface@plt>
  mov    $0x0,%eax
  call   <FH_DU@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x86,-0x4(%rbp)
  jbe    L9
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0; i < 135; i++) {
    init();
    interface();
    FH_DU();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x87,%ebx
L8:
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <interface@plt>
  mov    $0x0,%eax
  call   <FH_DU@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0; i < 135; i++) {
    init();
    interface();
    FH_DU();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x87,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <interface@plt>
  xor    %eax,%eax
  call   <FH_DU@plt>
  sub    $0x1,%ebx
  jne    L2
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0; i < 135; i++) {
    init();
    interface();
    FH_DU();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x87,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <interface@plt>
  xor    %eax,%eax
  call   <FH_DU@plt>
  sub    $0x1,%ebx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  unsigned int i;
  for (i = 0; i < 135; i++) {
    init();
    interface();
    FH_DU();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<mat2cum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L27:
  movl   $0x1,-0xc(%rbp)
  jmp    L1
L17:
  mov    -0x1c(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  D1(%rip),%xmm2
  xorps  %xmm2,%xmm0
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  divss  %xmm2,%xmm0
  mov    -0x1c(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
float *mat2cum(float *arr, int n, int *excind) {
  int i, j;
  float *cumarr;
  cumarr = calloc(n * n, sizeof(float));
  for (i = 0; i < n; ++i)
    for (j = 1; j < n; ++j)
      cumarr[n * i + j] = cumarr[n * i + j - 1] + (arr[i * n + excind[i * (n - 1) + j - 1]] / -arr[i * n + i]);
  return cumarr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mat2cum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %esi,%edi
  imul   %esi,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L51
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  lea    0x1(%rbp),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x0,%r13d
  mov    $0x0,%r11d
  mov    $0x0,%r9d
  mov    $0x0,%r10d
  lea    -0x2(%rbp),%eax
  mov    %rax,0x8(%rsp)
  lea    0x4(%r14),%r15
  movss  D5(%rip),%xmm1
  jmp    L20
L57:
  mov    %r9d,%r8d
  movslq %r13d,%rax
  lea    (%rbx,%rax,4),%rdi
  movslq %r9d,%rdx
  lea    (%r14,%rdx,4),%rax
  movslq %r11d,%rcx
  lea    (%r12,%rcx,4),%rcx
  add    0x8(%rsp),%rdx
  lea    (%r15,%rdx,4),%rsi
L38:
  mov    %r8d,%edx
  add    (%rcx),%edx
  movslq %edx,%rdx
  movss  (%rbx,%rdx,4),%xmm0
  xorps  %xmm1,%xmm0
  divss  (%rdi),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,0x4(%rax)
  add    $0x4,%rax
  add    $0x4,%rcx
  cmp    %rsi,%rax
  jne    L38
L39:
  add    $0x1,%r10d
  add    %ebp,%r9d
  add    (%rsp),%r11d
  add    0x4(%rsp),%r13d
  cmp    %r10d,%ebp
  je     L51
L20:
  cmp    $0x1,%ebp
  jg     L57
  jmp    L39
L51:
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x80]}

assistant: ```c
float *mat2cum(float *arr, int n, int *excind) {
  int i, j;
  float *cumarr;
  cumarr = calloc(n * n, sizeof(float));
  for (i = 0; i < n; ++i)
    for (j = 1; j < n; ++j)
      cumarr[n * i + j] = cumarr[n * i + j - 1] + (arr[i * n + excind[i * (n - 1) + j - 1]] / -arr[i * n + i]);
  return cumarr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mat2cum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  imul   %esi,%edi
  mov    $0x4,%esi
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L35
  lea    -0x2(%rbp),%eax
  lea    -0x1(%rbp),%r15d
  xor    %r11d,%r11d
  xor    %r10d,%r10d
  mov    %rax,(%rsp)
  lea    0x4(%r13),%rax
  lea    0x1(%rbp),%r14d
  xor    %esi,%esi
  mov    %rax,0x8(%rsp)
  xor    %r9d,%r9d
  movss  D7(%rip),%xmm1
  nop
L22:
  cmp    $0x1,%ebp
  je     L29
  movslq %r11d,%rax
  movslq %esi,%rdx
  mov    0x8(%rsp),%rdi
  movslq %r10d,%rcx
  lea    (%rbx,%rax,4),%r8
  lea    0x0(%r13,%rdx,4),%rax
  add    (%rsp),%rdx
  lea    (%r12,%rcx,4),%rcx
  lea    (%rdi,%rdx,4),%rdi
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%rcx),%edx
  add    $0x4,%rax
  add    $0x4,%rcx
  add    %esi,%edx
  movslq %edx,%rdx
  movss  (%rbx,%rdx,4),%xmm0
  xorps  %xmm1,%xmm0
  divss  (%r8),%xmm0
  addss  -0x4(%rax),%xmm0
  movss  %xmm0,(%rax)
  cmp    %rdi,%rax
  jne    L11
L29:
  add    $0x1,%r9d
  add    %ebp,%esi
  add    %r15d,%r10d
  add    %r14d,%r11d
  cmp    %r9d,%ebp
  jne    L22
L35:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x80]}

assistant: ```c
float *mat2cum(float *arr, int n, int *excind) {
  int i, j;
  float *cumarr;
  cumarr = calloc(n * n, sizeof(float));
  for (i = 0; i < n; ++i)
    for (j = 1; j < n; ++j)
      cumarr[n * i + j] = cumarr[n * i + j - 1] + (arr[i * n + excind[i * (n - 1) + j - 1]] / -arr[i * n + i]);
  return cumarr;
}
```
user: What is the c source code of the assembly code below?

```asm
<mat2cum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  imul   %esi,%edi
  mov    $0x4,%esi
  mov    %rdx,%rbx
  call   <calloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%r12d
  jle    L0
  movslq %r12d,%rax
  mov    %rbx,%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    0x0(,%rax,4),%r11
  lea    -0x4(,%rax,4),%r10
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  lea    0x4(,%rax,4),%rbx
  movss  D6(%rip),%xmm2
  lea    -0x1(%r12),%r8d
  nopw   0x0(%rax,%rax,1)
L12:
  movss  (%rdx),%xmm1
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    (%rdi,%rax,4),%r14d
  add    %ecx,%r14d
  movslq %r14d,%r14
  movss  0x0(%rbp,%r14,4),%xmm0
  xorps  %xmm2,%xmm0
  divss  (%rsi),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L16
  add    $0x1,%r9d
  add    %r11,%rdx
  add    %r12d,%ecx
  add    %r10,%rdi
  add    %rbx,%rsi
  cmp    %r9d,%r12d
  jne    L12
L0:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80]}

assistant: ```c
float *mat2cum(float *arr, int n, int *excind) {
  int i, j;
  float *cumarr;
  cumarr = calloc(n * n, sizeof(float));
  for (i = 0; i < n; ++i)
    for (j = 1; j < n; ++j)
      cumarr[n * i + j] = cumarr[n * i + j - 1] + (arr[i * n + excind[i * (n - 1) + j - 1]] / -arr[i * n + i]);
  return cumarr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L19:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    D3(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  je     L18
  cmpb   $0xa,-0x1(%rbp)
  jne    L19
L18:
  nop
  leave
  ret
```

assistant: ```c
void clear_buffer() {
  char c;
  while ((c = getchar()) != EOF && c != '\n')
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_buffer>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %al,(%rdx)
  je     L2
  cmp    $0xa,%al
  jne    L8
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void clear_buffer() {
  char c;
  while ((c = getchar()) != EOF && c != '\n')
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clear_buffer>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  jmp    L8
  xchg   %ax,%ax
L17:
  cmp    $0xa,%al
  je     L5
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L17
L5:
  pop    %rbx
  ret
```

assistant: ```c
void clear_buffer() {
  char c;
  while ((c = getchar()) != EOF && c != '\n')
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_buffer>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  jmp    L10
  xchg   %ax,%ax
L11:
  cmp    $0xa,%al
  je     L22
L10:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L11
L22:
  pop    %rbx
  ret
```

assistant: ```c
void clear_buffer() {
  char c;
  while ((c = getchar()) != EOF && c != '\n')
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L13
L17:
  cmpl   $0x1,-0x14(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L13
L39:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L13:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned fib(unsigned n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return 1;
  return fib(n - 1) + fib(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  je     L0
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
L0:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned fib(unsigned n) {
  if (n == 0)
    return 0;
  if (n == 1)
    return 1;
  return fib(n - 1) + fib(n - 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D48(%rip),%eax
  test   %eax,%eax
  jne    L14
  lea    D62(%rip),%rax
  mov    %rax,D9(%rip)
  lea    D53(%rip),%rax
  mov    %rax,D54(%rip)
  movl   $0x1,D48(%rip)
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  nop
  jmp    *%rax
  endbr64
  mov    $0x1,%eax
  jmp    L4
  endbr64
  mov    $0x2,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int doit(int x) {
  __label__ lbl1;
  __label__ lbl2;
  static int jtab_init = 0;
  static void *jtab[2];
  if (!jtab_init) {
    jtab[0] = &&lbl1;
    jtab[1] = &&lbl2;
    jtab_init = 1;
  }
  goto *jtab[x];
lbl1:
  return 1;
lbl2:
  return 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doit>:
  endbr64
  cmpl   $0x0,D58(%rip)
  jne    L5
  lea    D62(%rip),%rax
  mov    %rax,D23(%rip)
  lea    D24(%rip),%rax
  mov    %rax,D22(%rip)
  movl   $0x1,D58(%rip)
L5:
  lea    D23(%rip),%rax
  movslq %edi,%rdi
  jmp    *(%rax,%rdi,8)
  endbr64
  mov    $0x1,%eax
  ret
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int doit(int x) {
  __label__ lbl1;
  __label__ lbl2;
  static int jtab_init = 0;
  static void *jtab[2];
  if (!jtab_init) {
    jtab[0] = &&lbl1;
    jtab[1] = &&lbl2;
    jtab_init = 1;
  }
  goto *jtab[x];
lbl1:
  return 1;
lbl2:
  return 2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<doit>:
  endbr64
  mov    D26(%rip),%eax
  test   %eax,%eax
  jne    L8
  lea    D37(%rip),%rax
  movslq %edi,%rdi
  movl   $0x1,D26(%rip)
  mov    %rax,D4(%rip)
  lea    D11(%rip),%rax
  mov    %rax,D68(%rip)
  lea    D4(%rip),%rax
  jmp    *(%rax,%rdi,8)
  nopl   0x0(%rax)
  endbr64
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    $0x2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D4(%rip),%rax
  movslq %edi,%rdi
  jmp    *(%rax,%rdi,8)
```

assistant: ```c
int doit(int x) {
  __label__ lbl1;
  __label__ lbl2;
  static int jtab_init = 0;
  static void *jtab[2];
  if (!jtab_init) {
    jtab[0] = &&lbl1;
    jtab[1] = &&lbl2;
    jtab_init = 1;
  }
  goto *jtab[x];
lbl1:
  return 1;
lbl2:
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<doit>:
  endbr64
  mov    D49(%rip),%eax
  test   %eax,%eax
  jne    L6
  lea    D21(%rip),%rax
  movslq %edi,%rdi
  lea    D56(%rip),%rdx
  movl   $0x1,D49(%rip)
  movq   %rax,%xmm1
  movq   %rdx,%xmm0
  lea    D35(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,D42(%rip)
  jmp    *(%rax,%rdi,8)
  nopl   0x0(%rax,%rax,1)
  endbr64
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    $0x2,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D42(%rip),%rax
  movslq %edi,%rdi
  jmp    *(%rax,%rdi,8)
```

assistant: ```c
int doit(int x) {
  __label__ lbl1;
  __label__ lbl2;
  static int jtab_init = 0;
  static void *jtab[2];
  if (!jtab_init) {
    jtab[0] = &&lbl1;
    jtab[1] = &&lbl2;
    jtab_init = 1;
  }
  goto *jtab[x];
lbl1:
  return 1;
lbl2:
  return 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<core_cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <graphics_sprites_cleanup@plt>
  mov    $0x0,%eax
  call   <gameplay_cleanup@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void core_cleanup(void) {
  graphics_sprites_cleanup();
  gameplay_cleanup();
  endwin();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<core_cleanup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <graphics_sprites_cleanup@plt>
  mov    $0x0,%eax
  call   <gameplay_cleanup@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void core_cleanup(void) {
  graphics_sprites_cleanup();
  gameplay_cleanup();
  endwin();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<core_cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <graphics_sprites_cleanup@plt>
  xor    %eax,%eax
  call   <gameplay_cleanup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <endwin@plt>
```

assistant: ```c
void core_cleanup(void) {
  graphics_sprites_cleanup();
  gameplay_cleanup();
  endwin();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<core_cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <graphics_sprites_cleanup@plt>
  xor    %eax,%eax
  call   <gameplay_cleanup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <endwin@plt>
```

assistant: ```c
void core_cleanup(void) {
  graphics_sprites_cleanup();
  gameplay_cleanup();
  endwin();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numCar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    $0x1,%eax
  and    %edx,%eax
  mov    %eax,%edi
  call   <kernighan@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int numCar(int *m, int n) {
  int i, r = 0;
  for (i = 0; i < n; i++)
    r += kernighan(m[i] & ((1 << n) - 1));
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<numCar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L1
  mov    $0x1,%r12d
  mov    %esi,%ecx
  shl    %cl,%r12d
  sub    $0x1,%r12d
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r13
  mov    $0x0,%ebp
L10:
  mov    %r12d,%edi
  and    (%rbx),%edi
  call   <kernighan@plt>
  add    %eax,%ebp
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L10
L13:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    $0x0,%ebp
  jmp    L13
```

assistant: ```c
int numCar(int *m, int n) {
  int i, r = 0;
  for (i = 0; i < n; i++)
    r += kernighan(m[i] & ((1 << n) - 1));
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numCar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L7
  mov    $0x1,%ebp
  mov    %esi,%ecx
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  shl    %cl,%ebp
  lea    0x4(%rdi,%rax,4),%r13
  xor    %r12d,%r12d
  sub    $0x1,%ebp
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  and    %ebp,%edi
  call   <kernighan@plt>
  add    %eax,%r12d
  cmp    %r13,%rbx
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int numCar(int *m, int n) {
  int i, r = 0;
  for (i = 0; i < n; i++)
    r += kernighan(m[i] & ((1 << n) - 1));
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numCar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L4
  mov    $0x1,%ebp
  mov    %esi,%ecx
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  shl    %cl,%ebp
  lea    0x4(%rdi,%rax,4),%r13
  xor    %r12d,%r12d
  sub    $0x1,%ebp
  nopl   0x0(%rax)
L16:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  and    %ebp,%edi
  call   <kernighan@plt>
  add    %eax,%r12d
  cmp    %r13,%rbx
  jne    L16
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int numCar(int *m, int n) {
  int i, r = 0;
  for (i = 0; i < n; i++)
    r += kernighan(m[i] & ((1 << n) - 1));
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x80,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  rol    %al
  mov    %al,-0x1(%rbp)
  cmpb   $0x1,-0x1(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned char arg = 0x80;
  unsigned char out = 0;
  __asm__("rolb $1, %%al;" : "=a"(out) : "a"(arg));
  return (out == 0x01);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0xffffff80,%eax
  rol    %al
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  unsigned char arg = 0x80;
  unsigned char out = 0;
  __asm__("rolb $1, %%al;" : "=a"(out) : "a"(arg));
  return (out == 0x01);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0xffffff80,%eax
  rol    %al
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  unsigned char arg = 0x80;
  unsigned char out = 0;
  __asm__("rolb $1, %%al;" : "=a"(out) : "a"(arg));
  return (out == 0x01);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0xffffff80,%eax
  rol    %al
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  unsigned char arg = 0x80;
  unsigned char out = 0;
  __asm__("rolb $1, %%al;" : "=a"(out) : "a"(arg));
  return (out == 0x01);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pathSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  jmp    L13
L3:
  mov    -0x40(%rbp),%r8
  mov    -0x38(%rbp),%rdi
  lea    -0x18(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  push   $0x0
  lea    -0x10(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <f@plt>
  add    $0x10,%rsp
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int **pathSum(struct TreeNode *root, int sum, int **columnSizes, int *returnSize) {
  int **ret = (int **)malloc(0), *ns = (int *)malloc(0);
  *returnSize = 0;
  *columnSizes = (int *)malloc(0);
  if (!root)
    return ret;
  f(root, 0, sum, &ret, columnSizes, returnSize, &ns, 0);
  free(ns);
  return ret;
}
```