ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    $0x19,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L69
L45:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x54,%eax
  je     L98
  cmp    $0x54,%eax
  jg     L27
  cmp    $0x47,%eax
  je     L83
  cmp    $0x47,%eax
  jg     L27
  cmp    $0x41,%eax
  je     L126
  cmp    $0x43,%eax
  je     L109
  jmp    L27
L126:
  addl   $0x1,-0x20(%rbp)
  jmp    L4
L109:
  addl   $0x1,-0x1c(%rbp)
  jmp    L4
L83:
  addl   $0x1,-0x18(%rbp)
  jmp    L4
L98:
  addl   $0x1,-0x14(%rbp)
  jmp    L4
L27:
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  jmp    L113
L4:
  addq   $0x1,-0x10(%rbp)
L69:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x10(%rbp)
  jb     L45
  mov    -0x14(%rbp),%edi
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edi,%r9d
  mov    %esi,%r8d
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
L113:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string

tool: 

tool: D14: A:%d C:%d G:%d T:%d

assistant: ```c
char *count(const char *strand) {
  int a = 0;
  int c = 0;
  int g = 0;
  int t = 0;
  char *result = malloc(25);
  for (size_t i = 0; i < strlen(strand); ++i) {
    switch (strand[i]) {
    case 'A':
      a++;
      break;
    case 'C':
      c++;
      break;
    case 'G':
      g++;
      break;
    case 'T':
      t++;
      break;
    default:
      strcpy(result, "");
      return result;
    }
  }
  sprintf(result, "A:%d C:%d G:%d T:%d", a, c, g, t);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x19,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  jmp    L93
L91:
  cmp    $0x54,%al
  jne    L49
  add    $0x1,%r9d
  jmp    L60
L106:
  add    $0x1,%esi
L60:
  add    $0x1,%rdx
L93:
  cmp    %rdi,%rdx
  je     L63
  movzbl (%rdx),%eax
  cmp    $0x47,%al
  je     L79
  jg     L91
  cmp    $0x41,%al
  je     L106
  cmp    $0x43,%al
  jne    L49
  add    $0x1,%ecx
  jmp    L60
L79:
  add    $0x1,%r8d
  jmp    L60
L49:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L22:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L63:
  mov    %esi,%edx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D6
type: string

tool: 

tool: D6: A:%d C:%d G:%d T:%d

assistant: ```c
char *count(const char *strand) {
  int a = 0;
  int c = 0;
  int g = 0;
  int t = 0;
  char *result = malloc(25);
  for (size_t i = 0; i < strlen(strand); ++i) {
    switch (strand[i]) {
    case 'A':
      a++;
      break;
    case 'C':
      c++;
      break;
    case 'G':
      g++;
      break;
    case 'T':
      t++;
      break;
    default:
      strcpy(result, "");
      return result;
    }
  }
  sprintf(result, "A:%d C:%d G:%d T:%d", a, c, g, t);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x19,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rdi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  add    %rbx,%rax
  xor    %ecx,%ecx
  xor    %r10d,%r10d
  cmp    %rax,%rdi
  je     L67
L83:
  movzbl (%rdi),%edx
  cmp    $0x47,%dl
  je     L54
  jg     L23
  cmp    $0x41,%dl
  je     L60
  cmp    $0x43,%dl
  jne    L21
  add    $0x1,%ecx
L49:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L83
L67:
  mov    %r12,%rdi
  mov    %r10d,%edx
  lea    D12(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  cmp    $0x54,%dl
  jne    L21
  add    $0x1,%r9d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%r8d
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %r12,%rdi
  lea    D9(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  add    $0x1,%r10d
  jmp    L49
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D9
type: string

tool: D12: A:%d C:%d G:%d T:%d

tool: 

assistant: ```c
char *count(const char *strand) {
  int a = 0;
  int c = 0;
  int g = 0;
  int t = 0;
  char *result = malloc(25);
  for (size_t i = 0; i < strlen(strand); ++i) {
    switch (strand[i]) {
    case 'A':
      a++;
      break;
    case 'C':
      c++;
      break;
    case 'G':
      g++;
      break;
    case 'T':
      t++;
      break;
    default:
      strcpy(result, "");
      return result;
    }
  }
  sprintf(result, "A:%d C:%d G:%d T:%d", a, c, g, t);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x19,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbx,%rdi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  add    %rbx,%rax
  xor    %ecx,%ecx
  xor    %r10d,%r10d
  cmp    %rax,%rdi
  je     L89
L21:
  movzbl (%rdi),%edx
  cmp    $0x47,%dl
  je     L50
  jg     L99
  cmp    $0x41,%dl
  je     L43
  cmp    $0x43,%dl
  jne    L35
  add    $0x1,%ecx
L72:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L21
L89:
  mov    %r12,%rdi
  mov    %r10d,%edx
  lea    D18(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L99:
  cmp    $0x54,%dl
  jne    L35
  add    $0x1,%r9d
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%r8d
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    %r12,%rdi
  lea    D9(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%r10d
  jmp    L72
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D18: A:%d C:%d G:%d T:%d

tool: 

assistant: ```c
char *count(const char *strand) {
  int a = 0;
  int c = 0;
  int g = 0;
  int t = 0;
  char *result = malloc(25);
  for (size_t i = 0; i < strlen(strand); ++i) {
    switch (strand[i]) {
    case 'A':
      a++;
      break;
    case 'C':
      c++;
      break;
    case 'G':
      g++;
      break;
    case 'T':
      t++;
      break;
    default:
      strcpy(result, "");
      return result;
    }
  }
  sprintf(result, "A:%d C:%d G:%d T:%d", a, c, g, t);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void put32(uint8_t *ptr, uint32_t value) {
  ptr[0] = value & 0xFF;
  ptr[1] = (value >> 8) & 0xFF;
  ptr[2] = (value >> 16) & 0xFF;
  ptr[3] = (value >> 24) & 0xFF;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<put32>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  shr    $0x18,%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void put32(uint8_t *ptr, uint32_t value) {
  ptr[0] = value & 0xFF;
  ptr[1] = (value >> 8) & 0xFF;
  ptr[2] = (value >> 16) & 0xFF;
  ptr[3] = (value >> 24) & 0xFF;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<put32>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  shr    $0x18,%eax
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %eax,0xc(%rdi)
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  ret
```

assistant: ```c
void put32(uint8_t *ptr, uint32_t value) {
  ptr[0] = value & 0xFF;
  ptr[1] = (value >> 8) & 0xFF;
  ptr[2] = (value >> 16) & 0xFF;
  ptr[3] = (value >> 24) & 0xFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<put32>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  movzbl %sil,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %ah,%ecx
  shr    $0x18,%eax
  movzbl %dl,%esi
  movd   %ecx,%xmm2
  movd   %eax,%xmm3
  movd   %esi,%xmm1
  punpckldq %xmm2,%xmm0
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void put32(uint8_t *ptr, uint32_t value) {
  ptr[0] = value & 0xFF;
  ptr[1] = (value >> 8) & 0xFF;
  ptr[2] = (value >> 16) & 0xFF;
  ptr[3] = (value >> 24) & 0xFF;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<iscntrl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x1f,-0x1(%rbp)
  jbe    L19
  cmpb   $0x7e,-0x1(%rbp)
  jbe    L7
  cmpb   $0xa0,-0x1(%rbp)
  ja     L7
L19:
  mov    $0x1,%eax
  jmp    L34
L7:
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int iscntrl(int x) {
  unsigned char c = x & 0xff;
  return (c < 32) || (c >= 127 && c <= 160);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iscntrl>:
  endbr64
  lea    -0x7f(%rdi),%eax
  cmp    $0x21,%al
  setbe  %al
  cmp    $0x1f,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iscntrl(int x) {
  unsigned char c = x & 0xff;
  return (c < 32) || (c >= 127 && c <= 160);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iscntrl>:
  endbr64
  lea    -0x7f(%rdi),%eax
  cmp    $0x21,%al
  setbe  %al
  cmp    $0x1f,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iscntrl(int x) {
  unsigned char c = x & 0xff;
  return (c < 32) || (c >= 127 && c <= 160);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iscntrl>:
  endbr64
  lea    -0x7f(%rdi),%eax
  cmp    $0x21,%al
  setbe  %al
  cmp    $0x1f,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int iscntrl(int x) {
  unsigned char c = x & 0xff;
  return (c < 32) || (c >= 127 && c <= 160);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_binary_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L33:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L7:
  movsbl -0x11(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  and    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L37:
  cmpl   $0x7,-0xc(%rbp)
  jle    L7
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L33
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *get_binary_data(char *encode_str) {
  int *ret = malloc(sizeof(int) * 8 * strlen(encode_str));
  for (int i = 0; i < strlen(encode_str); i++) {
    char cur_char = encode_str[i];
    for (int j = 0; j < 8; j++) {
      ret[i * 8 + j] = (cur_char >> j) & 1;
    }
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_binary_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbx
  mov    $0x0,%ebp
  jmp    L23
L29:
  add    $0x1,%rbp
  add    $0x20,%rbx
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L26
  mov    $0x0,%ecx
  movsbl (%r12,%rbp,1),%edx
L28:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %eax,(%rbx,%rcx,4)
  add    $0x1,%rcx
  cmp    $0x8,%rcx
  jne    L28
  jmp    L29
L26:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *get_binary_data(char *encode_str) {
  int *ret = malloc(sizeof(int) * 8 * strlen(encode_str));
  for (int i = 0; i < strlen(encode_str); i++) {
    char cur_char = encode_str[i];
    for (int j = 0; j < 8; j++) {
      ret[i * 8 + j] = (cur_char >> j) & 1;
    }
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_binary_data>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L25
  nopl   0x0(%rax)
L27:
  movsbl 0x0(%r13,%rbp,1),%edx
  xor    %ecx,%ecx
L14:
  mov    %edx,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %eax,(%rbx,%rcx,4)
  add    $0x1,%rcx
  cmp    $0x8,%rcx
  jne    L14
  mov    %r13,%rdi
  add    $0x1,%rbp
  add    $0x20,%rbx
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L27
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *get_binary_data(char *encode_str) {
  int *ret = malloc(sizeof(int) * 8 * strlen(encode_str));
  for (int i = 0; i < strlen(encode_str); i++) {
    char cur_char = encode_str[i];
    for (int j = 0; j < 8; j++) {
      ret[i * 8 + j] = (cur_char >> j) & 1;
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_binary_data>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rbp
  jmp    L4
  nopl   (%rax)
L7:
  movsbl 0x0(%r13,%rbx,1),%eax
  add    $0x20,%rbp
  add    $0x1,%rbx
  mov    %eax,%ecx
  mov    %eax,%edi
  mov    %eax,%edx
  sar    %ecx
  sar    $0x3,%edi
  and    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%ecx
  movd   %edx,%xmm0
  and    $0x1,%edi
  sar    $0x2,%ecx
  and    $0x1,%esi
  movd   %edi,%xmm2
  mov    %eax,%edx
  and    $0x1,%ecx
  movd   %esi,%xmm3
  sar    $0x4,%edx
  movd   %ecx,%xmm1
  punpckldq %xmm3,%xmm0
  and    $0x1,%edx
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x20(%rbp)
  movd   %edx,%xmm0
  mov    %eax,%edx
  sar    $0x5,%edx
  mov    %edx,%ecx
  mov    %eax,%edx
  shr    $0x1f,%eax
  sar    $0x6,%edx
  and    $0x1,%ecx
  movd   %eax,%xmm4
  and    $0x1,%edx
  movd   %ecx,%xmm5
  movd   %edx,%xmm1
  punpckldq %xmm5,%xmm0
  punpckldq %xmm4,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x10(%rbp)
L4:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *get_binary_data(char *encode_str) {
  int *ret = malloc(sizeof(int) * 8 * strlen(encode_str));
  for (int i = 0; i < strlen(encode_str); i++) {
    char cur_char = encode_str[i];
    for (int j = 0; j < 8; j++) {
      ret[i * 8 + j] = (cur_char >> j) & 1;
    }
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_60_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_60_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = T ^ S;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_60_0_1>:
  endbr64
  mov    %edx,%ecx
  xor    %esi,%ecx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    %ecx,%eax
  not    %esi
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_60_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = T ^ S;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_60_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  not    %eax
  xor    %esi,%ecx
  or     %esi,%eax
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_60_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = T ^ S;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rop3_60_0_1>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  not    %eax
  xor    %esi,%ecx
  or     %esi,%eax
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_60_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  stk1 = T ^ S;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trunc_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L2:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trunc_str(char *s, char c) {
  char *ch = strchr(s, c);
  if (ch != NULL) {
    *ch = '\0';
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trunc_str>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *trunc_str(char *s, char c) {
  char *ch = strchr(s, c);
  if (ch != NULL) {
    *ch = '\0';
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trunc_str>:
  endbr64
  push   %r12
  movsbl %sil,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
L2:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trunc_str(char *s, char c) {
  char *ch = strchr(s, c);
  if (ch != NULL) {
    *ch = '\0';
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trunc_str>:
  endbr64
  push   %r12
  movsbl %sil,%esi
  mov    %rdi,%r12
  call   <strchr@plt>
  test   %rax,%rax
  je     L4
  movb   $0x0,(%rax)
L4:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *trunc_str(char *s, char c) {
  char *ch = strchr(s, c);
  if (ch != NULL) {
    *ch = '\0';
  }
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<index_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movsbl -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L14
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L14
L12:
  movl   $0xffffffff,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int index_of(char *str, char ch, int start, int len) {
  const char *region = str + start;
  const char *p = strchr(region, ch);
  int pos;
  if (p) {
    pos = (p - region) + start;
    if (pos >= (start + len)) {
      pos = -1;
    }
  } else {
    pos = -1;
  }
  if (0)
    fprintf(stderr, "%s: index_of(\"%s\", %c, %d, %d) = %d\n", "advent7_abba", str, ch, start, len, pos);
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index_of>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ecx,%ebp
  movslq %edx,%rax
  lea    (%rdi,%rax,1),%r12
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  sub    %r12,%rax
  add    %ebx,%eax
  add    %ebp,%ebx
  cmp    %eax,%ebx
  jle    L11
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L2
L21:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int index_of(char *str, char ch, int start, int len) {
  const char *region = str + start;
  const char *p = strchr(region, ch);
  int pos;
  if (p) {
    pos = (p - region) + start;
    if (pos >= (start + len)) {
      pos = -1;
    }
  } else {
    pos = -1;
  }
  if (0)
    fprintf(stderr, "%s: index_of(\"%s\", %c, %d, %d) = %d\n", "advent7_abba", str, ch, start, len, pos);
  return pos;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<index_of>:
  endbr64
  push   %r12
  movslq %edx,%rax
  movsbl %sil,%esi
  push   %rbp
  lea    (%rdi,%rax,1),%r12
  mov    %ecx,%ebp
  push   %rbx
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L24
  sub    %r12,%rax
  add    %ebx,%eax
  add    %ebp,%ebx
  cmp    %eax,%ebx
  jle    L24
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L24:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int index_of(char *str, char ch, int start, int len) {
  const char *region = str + start;
  const char *p = strchr(region, ch);
  int pos;
  if (p) {
    pos = (p - region) + start;
    if (pos >= (start + len)) {
      pos = -1;
    }
  } else {
    pos = -1;
  }
  if (0)
    fprintf(stderr, "%s: index_of(\"%s\", %c, %d, %d) = %d\n", "advent7_abba", str, ch, start, len, pos);
  return pos;
}
```