ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rmescapes>:
  endbr64
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L7:
  test   %al,%al
  je     L61
L26:
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  lea    0x1(%rdi),%rdi
  cmp    $0x81,%al
  jne    L7
  mov    $0xffffff81,%edi
  mov    %rdx,%rcx
  jmp    L63
  nopl   0x0(%rax)
L31:
  mov    %dil,(%rdx)
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rdx
  lea    0x1(%rcx),%rsi
  test   %al,%al
  je     L33
L36:
  mov    %eax,%edi
  mov    %rsi,%rcx
L63:
  cmp    $0x81,%al
  jne    L31
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rdx
  lea    0x2(%rcx),%rsi
  mov    %al,-0x1(%rdx)
  movzbl 0x2(%rcx),%eax
  test   %al,%al
  jne    L36
L33:
  movb   $0x0,(%rdx)
L61:
  ret
```

assistant: ```c
void rmescapes(str) char *str;
{
  register char *p, *q;
  p = str;
  while (*p != '\201') {
    if (*p++ == '\0')
      return;
  }
  q = p;
  while (*p) {
    if (*p == '\201')
      p++;
    *q++ = *p++;
  }
  *q = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<amount_touched>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L7
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jp     L16
  ucomisd -0x28(%rbp),%xmm0
  jne    L16
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L16:
  subl   $0x1,-0x8(%rbp)
L7:
  cmpl   $0x0,-0x8(%rbp)
  jns    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int amount_touched(double *a, int size, double val) {
  int i, last;
  last = size - 1;
  for (i = last; i >= 0; i--) {
    if (a[i] == val)
      last = i;
  }
  return (last);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<amount_touched>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L25
  movslq %eax,%rdx
L0:
  ucomisd (%rdi,%rdx,8),%xmm0
  jp     L12
  cmove  %edx,%eax
L12:
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L0
L25:
  ret
```

assistant: ```c
int amount_touched(double *a, int size, double val) {
  int i, last;
  last = size - 1;
  for (i = last; i >= 0; i--) {
    if (a[i] == val)
      last = i;
  }
  return (last);
}
```
user: What is the c source code of the assembly code below?

```asm
<amount_touched>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L7
  movslq %eax,%rdx
  xchg   %ax,%ax
L11:
  ucomisd (%rdi,%rdx,8),%xmm0
  jp     L26
  cmove  %edx,%eax
L26:
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L11
L7:
  ret
```

assistant: ```c
int amount_touched(double *a, int size, double val) {
  int i, last;
  last = size - 1;
  for (i = last; i >= 0; i--) {
    if (a[i] == val)
      last = i;
  }
  return (last);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<amount_touched>:
  endbr64
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L22
  movslq %eax,%rdx
  xchg   %ax,%ax
L20:
  ucomisd (%rdi,%rdx,8),%xmm0
  jp     L3
  cmove  %edx,%eax
L3:
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L20
L22:
  ret
```

assistant: ```c
int amount_touched(double *a, int size, double val) {
  int i, last;
  last = size - 1;
  for (i = last; i >= 0; i--) {
    if (a[i] == val)
      last = i;
  }
  return (last);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x49,%eax
  movb   $0x1,(%rax)
L8:
  jmp    L8
```

assistant: ```c
void __attribute__((noreturn)) abort(void) {
  (*((volatile unsigned char *)(0x29 + 0x20))) = 1;
  for (;;)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<abort>:
  endbr64
  movb   $0x1,0x49
L0:
  jmp    L0
```

assistant: ```c
void __attribute__((noreturn)) abort(void) {
  (*((volatile unsigned char *)(0x29 + 0x20))) = 1;
  for (;;)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<abort>:
  endbr64
  movb   $0x1,0x49
L2:
  jmp    L2
```

assistant: ```c
void __attribute__((noreturn)) abort(void) {
  (*((volatile unsigned char *)(0x29 + 0x20))) = 1;
  for (;;)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abort>:
  endbr64
  movb   $0x1,0x49
L9:
  jmp    L9
```

assistant: ```c
void __attribute__((noreturn)) abort(void) {
  (*((volatile unsigned char *)(0x29 + 0x20))) = 1;
  for (;;)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ux00ddr_phy_fixup>:
  endbr64
  lea    0x2000(%rdi),%rsi
  mov    $0x98,%ecx
  jmp    L16
L5:
  add    $0x200,%ecx
  cmp    $0x1098,%ecx
  je     L18
L16:
  lea    -0x10(%rcx),%eax
L30:
  movslq %eax,%rdx
  add    %rsi,%rdx
  mov    (%rdx),%edx
  add    $0x4,%eax
  cmp    %ecx,%eax
  jne    L30
  jmp    L5
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint64_t ux00ddr_phy_fixup(size_t ahbregaddr) {
  size_t ddrphyreg = ahbregaddr + 0x2000;
  uint64_t fails = 0;
  uint32_t slicebase = 0;
  uint32_t dq = 0;
  for (uint32_t slice = 0; slice < 8; slice++) {
    uint32_t regbase = slicebase + 34;
    for (uint32_t reg = 0; reg < 4; reg++) {
      uint32_t updownreg = (*(volatile uint32_t *)(((regbase + reg) << 2) + (ddrphyreg)));
      for (uint32_t bit = 0; bit < 2; bit++) {
        uint32_t phy_rx_cal_dqn_0_offset;
        if (bit == 0) {
          phy_rx_cal_dqn_0_offset = 0;
        } else {
          phy_rx_cal_dqn_0_offset = 16;
        }
        uint32_t down = (updownreg >> phy_rx_cal_dqn_0_offset) & 0x3F;
        uint32_t up = (updownreg >> (phy_rx_cal_dqn_0_offset + 6)) & 0x3F;
        uint8_t failc0 = ((down == 0) && (up == 0x3F));
        uint8_t failc1 = ((up == 0) && (down == 0x3F));
        if (failc0 || failc1) {
          fails |= (1 << dq);
          char slicelsc = '0';
          char slicemsc = '0';
          slicelsc += (dq % 10);
          slicemsc += (dq / 10);
        }
        dq++;
      }
    }
    slicebase += 128;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ux00ddr_phy_fixup>:
  endbr64
  add    $0x2000,%rdi
  mov    $0x98,%ecx
L16:
  lea    -0x10(%rcx),%eax
L9:
  movslq %eax,%rdx
  add    $0x4,%eax
  add    %rdi,%rdx
  mov    (%rdx),%edx
  cmp    %ecx,%eax
  jne    L9
  lea    0x200(%rax),%ecx
  cmp    $0xe98,%eax
  jne    L16
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t ux00ddr_phy_fixup(size_t ahbregaddr) {
  size_t ddrphyreg = ahbregaddr + 0x2000;
  uint64_t fails = 0;
  uint32_t slicebase = 0;
  uint32_t dq = 0;
  for (uint32_t slice = 0; slice < 8; slice++) {
    uint32_t regbase = slicebase + 34;
    for (uint32_t reg = 0; reg < 4; reg++) {
      uint32_t updownreg = (*(volatile uint32_t *)(((regbase + reg) << 2) + (ddrphyreg)));
      for (uint32_t bit = 0; bit < 2; bit++) {
        uint32_t phy_rx_cal_dqn_0_offset;
        if (bit == 0) {
          phy_rx_cal_dqn_0_offset = 0;
        } else {
          phy_rx_cal_dqn_0_offset = 16;
        }
        uint32_t down = (updownreg >> phy_rx_cal_dqn_0_offset) & 0x3F;
        uint32_t up = (updownreg >> (phy_rx_cal_dqn_0_offset + 6)) & 0x3F;
        uint8_t failc0 = ((down == 0) && (up == 0x3F));
        uint8_t failc1 = ((up == 0) && (down == 0x3F));
        if (failc0 || failc1) {
          fails |= (1 << dq);
          char slicelsc = '0';
          char slicemsc = '0';
          slicelsc += (dq % 10);
          slicemsc += (dq / 10);
        }
        dq++;
      }
    }
    slicebase += 128;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ux00ddr_phy_fixup>:
  endbr64
  mov    %rdi,%rax
  mov    0x2088(%rdi),%edx
  mov    0x208c(%rdi),%edx
  mov    0x2090(%rdi),%edx
  mov    0x2094(%rdi),%edx
  mov    0x2288(%rdi),%edx
  mov    0x228c(%rdi),%edx
  mov    0x2290(%rdi),%edx
  mov    0x2294(%rdi),%edx
  mov    0x2488(%rdi),%edx
  mov    0x248c(%rdi),%edx
  mov    0x2490(%rdi),%edx
  mov    0x2494(%rdi),%edx
  mov    0x2688(%rdi),%edx
  mov    0x268c(%rdi),%edx
  mov    0x2690(%rdi),%edx
  mov    0x2694(%rdi),%edx
  mov    0x2888(%rdi),%edx
  mov    0x288c(%rdi),%edx
  mov    0x2890(%rdi),%edx
  mov    0x2894(%rdi),%edx
  mov    0x2a88(%rdi),%edx
  mov    0x2a8c(%rdi),%edx
  mov    0x2a90(%rdi),%edx
  mov    0x2a94(%rdi),%edx
  mov    0x2c88(%rdi),%edx
  mov    0x2c8c(%rdi),%edx
  mov    0x2c90(%rdi),%edx
  mov    0x2c94(%rdi),%edx
  mov    0x2e88(%rdi),%edx
  mov    0x2e8c(%rdi),%edx
  mov    0x2e90(%rdi),%edx
  mov    0x2e94(%rax),%eax
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t ux00ddr_phy_fixup(size_t ahbregaddr) {
  size_t ddrphyreg = ahbregaddr + 0x2000;
  uint64_t fails = 0;
  uint32_t slicebase = 0;
  uint32_t dq = 0;
  for (uint32_t slice = 0; slice < 8; slice++) {
    uint32_t regbase = slicebase + 34;
    for (uint32_t reg = 0; reg < 4; reg++) {
      uint32_t updownreg = (*(volatile uint32_t *)(((regbase + reg) << 2) + (ddrphyreg)));
      for (uint32_t bit = 0; bit < 2; bit++) {
        uint32_t phy_rx_cal_dqn_0_offset;
        if (bit == 0) {
          phy_rx_cal_dqn_0_offset = 0;
        } else {
          phy_rx_cal_dqn_0_offset = 16;
        }
        uint32_t down = (updownreg >> phy_rx_cal_dqn_0_offset) & 0x3F;
        uint32_t up = (updownreg >> (phy_rx_cal_dqn_0_offset + 6)) & 0x3F;
        uint8_t failc0 = ((down == 0) && (up == 0x3F));
        uint8_t failc1 = ((up == 0) && (down == 0x3F));
        if (failc0 || failc1) {
          fails |= (1 << dq);
          char slicelsc = '0';
          char slicemsc = '0';
          slicelsc += (dq % 10);
          slicemsc += (dq / 10);
        }
        dq++;
      }
    }
    slicebase += 128;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,-0x4(%rbp)
  jmp    L11
L20:
  add    $0x1,%rax
L11:
  movzbl (%rax),%edx
  movsbl %dl,%edx
  cmp    %edx,-0x4(%rbp)
  je     L4
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L20
L4:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L32
  jmp    L22
L32:
  mov    $0x0,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(register const char *buf, int ch) {
  register char c = ch;
  while (*buf != ch && *buf)
    buf++;
  if (*buf)
    return (char *)buf;
  return ((void *)0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  movsbl %al,%edx
  cmp    %esi,%edx
  je     L22
L32:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  movsbl %al,%edx
  cmp    %esi,%edx
  jne    L32
L22:
  test   %al,%al
  mov    $0x0,%eax
  cmovne %rdi,%rax
  ret
```

assistant: ```c
char *strchr(register const char *buf, int ch) {
  register char c = ch;
  while (*buf != ch && *buf)
    buf++;
  if (*buf)
    return (char *)buf;
  return ((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strchr>:
  endbr64
  movsbl (%rdi),%edx
  mov    %edx,%eax
  cmp    %edx,%esi
  jne    L35
  jmp    L22
  nop
L1:
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%eax
  cmp    %esi,%edx
  je     L22
L35:
  test   %al,%al
  jne    L1
  xor    %eax,%eax
  ret
  nopl   (%rax)
L22:
  test   %al,%al
  mov    $0x0,%eax
  cmovne %rdi,%rax
  ret
```

assistant: ```c
char *strchr(register const char *buf, int ch) {
  register char c = ch;
  while (*buf != ch && *buf)
    buf++;
  if (*buf)
    return (char *)buf;
  return ((void *)0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strchr>:
  endbr64
  movsbl (%rdi),%edx
  mov    %edx,%eax
  cmp    %edx,%esi
  jne    L16
  jmp    L7
  nop
L30:
  movsbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%eax
  cmp    %esi,%edx
  je     L7
L16:
  test   %al,%al
  jne    L30
  xor    %eax,%eax
  ret
  nopl   (%rax)
L7:
  test   %al,%al
  mov    $0x0,%eax
  cmovne %rdi,%rax
  ret
```

assistant: ```c
char *strchr(register const char *buf, int ch) {
  register char c = ch;
  while (*buf != ch && *buf)
    buf++;
  if (*buf)
    return (char *)buf;
  return ((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cvCvToIplDepth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x3,%eax
  and    $0x3,%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  add    %eax,%eax
  mov    $0xfa50,%esi
  mov    %eax,%ecx
  shr    %cl,%rsi
  mov    %rsi,%rax
  and    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  mov    %eax,%edx
  cmpl   $0x1,-0x4(%rbp)
  je     L9
  cmpl   $0x3,-0x4(%rbp)
  je     L9
  cmpl   $0x4,-0x4(%rbp)
  jne    L3
L9:
  mov    $0x80000000,%eax
  jmp    L36
L3:
  mov    $0x0,%eax
L36:
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cvCvToIplDepth(int type) {
  int depth = ((type) & ((1 << 3) - 1));
  return (((((depth) & ((4 - 1) << 3)) >> 3) + 1) << ((((sizeof(size_t) / 4 + 1) * 16384 | 0x3a50) >> ((depth) & ((1 << 3) - 1)) * 2) & 3)) * 8 | (depth == 1 || depth == 3 || depth == 4 ? 0x80000000 : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cvCvToIplDepth>:
  endbr64
  and    $0x7,%edi
  mov    %edi,%ecx
  mov    $0x1a,%eax
  shr    %cl,%rax
  shl    $0x1f,%eax
  add    %ecx,%ecx
  mov    $0xfa50,%edx
  shr    %cl,%rdx
  mov    %rdx,%rcx
  and    $0x3,%ecx
  mov    $0x8,%edx
  shl    %cl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int cvCvToIplDepth(int type) {
  int depth = ((type) & ((1 << 3) - 1));
  return (((((depth) & ((4 - 1) << 3)) >> 3) + 1) << ((((sizeof(size_t) / 4 + 1) * 16384 | 0x3a50) >> ((depth) & ((1 << 3) - 1)) * 2) & 3)) * 8 | (depth == 1 || depth == 3 || depth == 4 ? 0x80000000 : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cvCvToIplDepth>:
  endbr64
  and    $0x7,%edi
  mov    $0xfa50,%eax
  mov    $0x1a,%edx
  lea    (%rdi,%rdi,1),%ecx
  shr    %cl,%rax
  mov    %rax,%rcx
  mov    $0x8,%eax
  and    $0x3,%ecx
  shl    %cl,%eax
  mov    %edi,%ecx
  shr    %cl,%rdx
  shl    $0x1f,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int cvCvToIplDepth(int type) {
  int depth = ((type) & ((1 << 3) - 1));
  return (((((depth) & ((4 - 1) << 3)) >> 3) + 1) << ((((sizeof(size_t) / 4 + 1) * 16384 | 0x3a50) >> ((depth) & ((1 << 3) - 1)) * 2) & 3)) * 8 | (depth == 1 || depth == 3 || depth == 4 ? 0x80000000 : 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvCvToIplDepth>:
  endbr64
  and    $0x7,%edi
  mov    $0xfa50,%eax
  mov    $0x1a,%edx
  lea    (%rdi,%rdi,1),%ecx
  shr    %cl,%rax
  mov    %rax,%rcx
  mov    $0x8,%eax
  and    $0x3,%ecx
  shl    %cl,%eax
  mov    %edi,%ecx
  shr    %cl,%rdx
  shl    $0x1f,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int cvCvToIplDepth(int type) {
  int depth = ((type) & ((1 << 3) - 1));
  return (((((depth) & ((4 - 1) << 3)) >> 3) + 1) << ((((sizeof(size_t) / 4 + 1) * 16384 | 0x3a50) >> ((depth) & ((1 << 3) - 1)) * 2) & 3)) * 8 | (depth == 1 || depth == 3 || depth == 4 ? 0x80000000 : 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D46
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D41
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string

tool: D26: program liczy pole detoidu

tool: D46: podaj p:

tool: D0: %d

tool: D41: podaj q:

tool: D13: pole deltoidu wynosi:%d


assistant: ```c
main() {
  int p, q, pole;
  printf("program liczy pole detoidu\n");
  printf("podaj p:");
  scanf("%d", &p);
  printf("podaj q:");
  scanf("%d", &q);
  pole = p * q / 2;
  printf("pole deltoidu wynosi:%d\n", pole);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D42(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  imul   0x4(%rsp),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D35
type_infered: string
name: retrieve_data
arguments: label: D27
type_infered: string
name: retrieve_data
arguments: label: D42
type_infered: string
name: retrieve_data
arguments: label: D38
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D35: program liczy pole detoidu

tool: D27: podaj p:

tool: D42: %d

tool: D38: podaj q:

tool: D29: pole deltoidu wynosi:%d


assistant: ```c
main() {
  int p, q, pole;
  printf("program liczy pole detoidu\n");
  printf("podaj p:");
  scanf("%d", &p);
  printf("podaj q:");
  scanf("%d", &q);
  pole = p * q / 2;
  printf("pole deltoidu wynosi:%d\n", pole);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D11(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  imul   0x4(%rsp),%eax
  lea    D37(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D49
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D37
data_type: string

tool: D49: program liczy pole detoidu

tool: D11: %d

tool: D9: podaj p:

tool: D39: podaj q:

tool: D37: pole deltoidu wynosi:%d


assistant: ```c
main() {
  int p, q, pole;
  printf("program liczy pole detoidu\n");
  printf("podaj p:");
  scanf("%d", &p);
  printf("podaj q:");
  scanf("%d", &q);
  pole = p * q / 2;
  printf("pole deltoidu wynosi:%d\n", pole);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rdi
  lea    D35(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  imul   0x4(%rsp),%eax
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D45
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D45: program liczy pole detoidu

tool: D35: %d

tool: D5: podaj p:

tool: D7: podaj q:

tool: D4: pole deltoidu wynosi:%d


assistant: ```c
main() {
  int p, q, pole;
  printf("program liczy pole detoidu\n");
  printf("podaj p:");
  scanf("%d", &p);
  printf("podaj q:");
  scanf("%d", &q);
  pole = p * q / 2;
  printf("pole deltoidu wynosi:%d\n", pole);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<segment_internal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,0x4(%rsp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x0(%rbp),%rdi
  call   <iswlower@plt>
  mov    %eax,(%rsp)
  mov    %rbp,%rdi
  call   <wcslen@plt>
  mov    %rax,%r14
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <count_double_characters@plt>
  lea    0x10(%r14,%rax,1),%r15
  lea    0x0(,%r15,8),%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <copy_and_normalize@plt>
  mov    %rax,%r14
  cmpl   $0x0,(%rsp)
  sete   %dl
  movzbl %dl,%edx
  mov    0x4(%rsp),%ecx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strip_suffixes@plt>
  mov    %rax,%rbp
  sub    %rax,%r14
  lea    (%rbx,%rax,8),%r15
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <wcsncpy@plt>
  movq   $0x0,0x0(%r13,%r14,8)
  movq   $0x0,(%r15)
  mov    0x8(%rsp),%r15
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <copy_and_denormalize@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r15,(%r12)
  mov    %r13,0x8(%r12)
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
wchar_t **segment_internal(wchar_t *word, int case_insensitive) {
  wchar_t **result = malloc(2 * sizeof(wchar_t *));
  int uppercase = !iswlower(word[0]);
  unsigned long length = wcslen(word);
  unsigned long intermediate_length = length + count_double_characters(word, length) + 16;
  wchar_t *intermediate = malloc(intermediate_length * sizeof(wchar_t));
  wchar_t *stem_result = malloc(intermediate_length * sizeof(wchar_t));
  wchar_t *suffix_result = malloc(intermediate_length * sizeof(wchar_t));
  unsigned long normalized_length = copy_and_normalize(word, length, intermediate, 0);
  unsigned long stem_length = strip_suffixes(intermediate, intermediate_length, uppercase, case_insensitive);
  wcsncpy(suffix_result, intermediate + stem_length, normalized_length - stem_length);
  suffix_result[normalized_length - stem_length] = 0;
  intermediate[stem_length] = 0;
  copy_and_denormalize(intermediate, stem_length, stem_result);
  free(intermediate);
  result[0] = stem_result;
  result[1] = suffix_result;
  return result;
}
```