ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xf00d,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: goto ftw!


assistant: ```c
int main() {
  goto mylabel;
  printf("skipped\n");
mylabel:
  printf("goto ftw!\n");
  return 0xf00d;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xf00d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: goto ftw!


assistant: ```c
int main() {
  goto mylabel;
  printf("skipped\n");
mylabel:
  printf("goto ftw!\n");
  return 0xf00d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xf00d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: goto ftw!


assistant: ```c
int main() {
  goto mylabel;
  printf("skipped\n");
mylabel:
  printf("goto ftw!\n");
  return 0xf00d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xf00d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: goto ftw!


assistant: ```c
int main() {
  goto mylabel;
  printf("skipped\n");
mylabel:
  printf("goto ftw!\n");
  return 0xf00d;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L83
L39:
  addl   $0x1,-0x18(%rbp)
L83:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L39
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L62
L40:
  addl   $0x1,-0x14(%rbp)
L62:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L40
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L54
L41:
  addl   $0x1,-0x10(%rbp)
L54:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L41
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L13
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L13
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L13
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D0: %d

tool: D17: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++)
    ;
  {
    for (j = i; j <= N; j = j + 1)
      ;
    {
      for (k = j; k <= N; k = k + 1)
        ;
      {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L47
  add    $0x1,%edx
  mov    $0x1,%eax
L48:
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L48
  mov    %eax,%edx
L36:
  add    %eax,%eax
  mov    $0x0,%esi
  cmp    %edx,%eax
  jle    L7
  test   %edx,%edx
  setg   %sil
  movzbl %sil,%esi
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L47:
  mov    $0x1,%edx
  mov    $0x1,%eax
  jmp    L36
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D11: %d

tool: D6: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++)
    ;
  {
    for (j = i; j <= N; j = j + 1)
      ;
    {
      for (k = j; k <= N; k = k + 1)
        ;
      {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    D6(%rip),%rdi
  test   %edx,%edx
  lea    0x1(%rdx),%eax
  mov    $0x1,%edx
  cmovle %edx,%eax
  xor    %esi,%esi
  lea    (%rax,%rax,1),%edx
  cmp    %eax,%edx
  setg   %sil
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D6
type: string

tool: D8: %d

tool: D6: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++)
    ;
  {
    for (j = i; j <= N; j = j + 1)
      ;
    {
      for (k = j; k <= N; k = k + 1)
        ;
      {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    D14(%rip),%rdi
  test   %edx,%edx
  lea    0x1(%rdx),%eax
  mov    $0x1,%edx
  cmovle %edx,%eax
  xor    %esi,%esi
  lea    (%rax,%rax,1),%edx
  cmp    %eax,%edx
  setg   %sil
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string

tool: D12: %d

tool: D14: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++)
    ;
  {
    for (j = i; j <= N; j = j + 1)
      ;
    {
      for (k = j; k <= N; k = k + 1)
        ;
      {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L23
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L23:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x20(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L7
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  leave
  ret
```

assistant: ```c
int partition(int arr[], int low, int high) {
  int pivot = arr[high];
  int i = (low - 1);
  for (int j = low; j <= high - 1; j++) {
    if (arr[j] <= pivot) {
      i++;
      swap(&arr[i], &arr[j]);
    }
  }
  swap(&arr[i + 1], &arr[high]);
  return (i + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r15
  mov    (%r15),%r13d
  lea    -0x1(%rsi),%ebp
  cmp    %esi,%edx
  jle    L18
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%rbx
  sub    %esi,%edx
  lea    -0x1(%rdx),%eax
  add    %rcx,%rax
  lea    0x4(%rdi,%rax,4),%r14
  jmp    L47
L11:
  add    $0x4,%rbx
  cmp    %r14,%rbx
  je     L18
L47:
  cmp    %r13d,(%rbx)
  jg     L11
  add    $0x1,%ebp
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  jmp    L11
L18:
  movslq %ebp,%rax
  lea    0x4(%r12,%rax,4),%rdi
  mov    %r15,%rsi
  call   <swap@plt>
  lea    0x1(%rbp),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int partition(int arr[], int low, int high) {
  int pivot = arr[high];
  int i = (low - 1);
  for (int j = low; j <= high - 1; j++) {
    if (arr[j] <= pivot) {
      i++;
      swap(&arr[i], &arr[j]);
    }
  }
  swap(&arr[i + 1], &arr[high]);
  return (i + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    (%rdi,%rax,4),%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r14),%r13d
  cmp    %esi,%edx
  jle    L11
  sub    %esi,%edx
  movslq %esi,%rcx
  lea    -0x1(%rdx),%eax
  lea    (%rdi,%rcx,4),%rbx
  add    %rcx,%rax
  lea    0x4(%rdi,%rax,4),%r15
  jmp    L44
  nopl   0x0(%rax)
L58:
  add    $0x4,%rbx
  cmp    %rbx,%r15
  je     L37
L44:
  cmp    %r13d,(%rbx)
  jg     L58
  add    $0x1,%ebp
  mov    %rbx,%rsi
  add    $0x4,%rbx
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%r15
  jne    L44
L37:
  lea    0x1(%rbp),%r13d
L26:
  movslq %ebp,%rbp
  mov    %r14,%rsi
  lea    0x4(%r12,%rbp,4),%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L11:
  mov    %esi,%r13d
  jmp    L26
```

assistant: ```c
int partition(int arr[], int low, int high) {
  int pivot = arr[high];
  int i = (low - 1);
  for (int j = low; j <= high - 1; j++) {
    if (arr[j] <= pivot) {
      i++;
      swap(&arr[i], &arr[j]);
    }
  }
  swap(&arr[i + 1], &arr[high]);
  return (i + 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partition>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    (%rdi,%rax,4),%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r14),%r13d
  cmp    %esi,%edx
  jle    L11
  sub    %esi,%edx
  movslq %esi,%rcx
  lea    -0x1(%rdx),%eax
  lea    (%rdi,%rcx,4),%rbx
  add    %rcx,%rax
  lea    0x4(%rdi,%rax,4),%r15
  jmp    L32
  nopl   0x0(%rax)
L18:
  add    $0x4,%rbx
  cmp    %rbx,%r15
  je     L28
L32:
  cmp    %r13d,(%rbx)
  jg     L18
  add    $0x1,%ebp
  mov    %rbx,%rsi
  add    $0x4,%rbx
  movslq %ebp,%rax
  lea    (%r12,%rax,4),%rdi
  call   <swap@plt>
  cmp    %rbx,%r15
  jne    L32
L28:
  lea    0x1(%rbp),%r13d
L33:
  movslq %ebp,%rbp
  mov    %r14,%rsi
  lea    0x4(%r12,%rbp,4),%rdi
  call   <swap@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L11:
  mov    %esi,%r13d
  jmp    L33
```

assistant: ```c
int partition(int arr[], int low, int high) {
  int pivot = arr[high];
  int i = (low - 1);
  for (int j = low; j <= high - 1; j++) {
    if (arr[j] <= pivot) {
      i++;
      swap(&arr[i], &arr[j]);
    }
  }
  swap(&arr[i + 1], &arr[high]);
  return (i + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L29
L20:
  cmpl   $0x9,-0x4(%rbp)
  jne    L26
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L13:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x3,-0x8(%rbp)
  jle    L13
  jmp    L29
L26:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L29:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L20
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\t')
      for (int i = 0; i < 4; i++)
        putchar(' ');
    else
      putchar(c);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L28
L3:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
L28:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L32
  cmp    $0x9,%eax
  je     L3
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L28
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\t')
      for (int i = 0; i < 4; i++)
        putchar(' ');
    else
      putchar(c);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
L39:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L3
L18:
  cmp    $0x9,%edi
  je     L9
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L18
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L39
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\t')
      for (int i = 0; i < 4; i++)
        putchar(' ');
    else
      putchar(c);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
L6:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L25
L37:
  cmp    $0x9,%edi
  je     L33
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L37
L25:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L33:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L6
```

assistant: ```c
int main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == '\t')
      for (int i = 0; i < 4; i++)
        putchar(' ');
    else
      putchar(c);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gleIntLoad_Version_3_3_Comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gleIntClear@plt>
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_1_Base@plt>
  test   %eax,%eax
  jne    L108
  movl   $0x0,-0x4(%rbp)
L108:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_2_Base@plt>
  test   %eax,%eax
  jne    L95
  movl   $0x0,-0x4(%rbp)
L95:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_3_Base@plt>
  test   %eax,%eax
  jne    L55
  movl   $0x0,-0x4(%rbp)
L55:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_4_Base@plt>
  test   %eax,%eax
  jne    L24
  movl   $0x0,-0x4(%rbp)
L24:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_5_Base@plt>
  test   %eax,%eax
  jne    L109
  movl   $0x0,-0x4(%rbp)
L109:
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_0_Base@plt>
  test   %eax,%eax
  jne    L59
  movl   $0x0,-0x4(%rbp)
L59:
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_1_Base@plt>
  test   %eax,%eax
  jne    L11
  movl   $0x0,-0x4(%rbp)
L11:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_0_Base@plt>
  test   %eax,%eax
  jne    L107
  movl   $0x0,-0x4(%rbp)
L107:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  jne    L4
  movl   $0x0,-0x4(%rbp)
L4:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  jne    L79
  movl   $0x0,-0x4(%rbp)
L79:
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_3_Base@plt>
  test   %eax,%eax
  jne    L47
  movl   $0x0,-0x4(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gleIntLoad_Version_3_3_Comp() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_3_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gleIntLoad_Version_3_3_Comp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gleIntClear@plt>
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_1_Base@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_2_Base@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L0
  test   %ebp,%ebp
  setne  %bl
  movzbl %bl,%ebx
L0:
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_3_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_4_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_1_5_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_0_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_2_1_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_0_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    $0x0,%eax
  call   <gleIntLoadCore_3_3_Base@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int gleIntLoad_Version_3_3_Comp() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_3_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gleIntLoad_Version_3_3_Comp>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <gleIntClear@plt>
  xor    %eax,%eax
  call   <gleIntLoadCore_1_1_Base@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gleIntLoadCore_1_2_Base@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L6
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L6:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <gleIntLoadCore_1_3_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_4_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_5_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_0_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_0_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_3_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int gleIntLoad_Version_3_3_Comp() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_3_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```