ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<equal_2d>:
  endbr64
  test   %edx,%edx
  jle    L39
  mov    %edx,%edx
  mov    $0x0,%r9d
L0:
  mov    (%rdi,%r9,8),%r8
  mov    (%rsi,%r9,8),%rcx
  mov    $0x0,%eax
L26:
  movzbl (%rcx,%rax,1),%r10d
  cmp    %r10b,(%r8,%rax,1)
  jne    L3
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  add    $0x1,%r9
  cmp    %rdx,%r9
  jne    L0
  mov    $0x1,%eax
  ret
L39:
  mov    $0x1,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int equal_2d(char **arr, char **arr2, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      if (arr[i][j] != arr2[i][j])
        return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<equal_2d>:
  endbr64
  test   %edx,%edx
  jle    L26
  movslq %edx,%rdx
  xor    %r9d,%r9d
L7:
  mov    (%rdi,%r9,8),%r8
  mov    (%rsi,%r9,8),%rcx
  xor    %eax,%eax
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L13
L25:
  movzbl (%rcx,%rax,1),%r10d
  cmp    %r10b,(%r8,%rax,1)
  je     L12
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r9
  cmp    %rax,%r9
  jne    L7
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal_2d(char **arr, char **arr2, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      if (arr[i][j] != arr2[i][j])
        return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<equal_2d>:
  endbr64
  test   %edx,%edx
  jle    L8
  movslq %edx,%rdx
  xor    %r9d,%r9d
L46:
  mov    (%rdi,%r9,8),%r8
  mov    (%rsi,%r9,8),%rcx
  xor    %eax,%eax
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L6
L15:
  movzbl (%rcx,%rax,1),%r10d
  cmp    %r10b,(%r8,%rax,1)
  je     L1
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r9
  cmp    %rax,%r9
  jne    L46
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal_2d(char **arr, char **arr2, int n) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      if (arr[i][j] != arr2[i][j])
        return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  cmpq   $0x0,-0xc8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0xd8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x0,-0xb4(%rbp)
  jns    L0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L0:
  mov    -0xb4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L17
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <Warning@plt>
L17:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D0: snprintf

tool: D8: snprintf: the output may be truncated.

assistant: ```c
void Snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int retval;
  assert(str != NULL);
  assert(format != NULL);
  va_start(ap, format);
  retval = vsnprintf(str, size, format, ap);
  va_end(ap);
  if (retval < 0)
    Sys_failure("snprintf");
  if (retval == size - 1)
    Warning("snprintf: the output may be truncated.");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <va_end@plt>
  test   %ebp,%ebp
  js     L28
L36:
  movslq %ebp,%rbp
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L9
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  lea    D9(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L36
L9:
  lea    D3(%rip),%rdi
  call   <Warning@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D9: snprintf

tool: D3: snprintf: the output may be truncated.

assistant: ```c
void Snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int retval;
  assert(str != NULL);
  assert(format != NULL);
  va_start(ap, format);
  retval = vsnprintf(str, size, format, ap);
  va_end(ap);
  if (retval < 0)
    Sys_failure("snprintf");
  if (retval == size - 1)
    Warning("snprintf: the output may be truncated.");
}
```
user: What is the c source code of the assembly code below?

```asm
<Snprintf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  xor    %r13d,%r13d
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  movslq %eax,%rbp
  call   <va_end@plt>
  test   %ebp,%ebp
  js     L18
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L13
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  lea    D12(%rip),%rdi
  sub    $0x1,%rbx
  call   <Sys_failure@plt>
  cmp    %rbx,%rbp
  jne    L28
L13:
  lea    D15(%rip),%rdi
  call   <Warning@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string

tool: D12: snprintf

tool: D15: snprintf: the output may be truncated.

assistant: ```c
void Snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int retval;
  assert(str != NULL);
  assert(format != NULL);
  va_start(ap, format);
  retval = vsnprintf(str, size, format, ap);
  va_end(ap);
  if (retval < 0)
    Sys_failure("snprintf");
  if (retval == size - 1)
    Warning("snprintf: the output may be truncated.");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Snprintf>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  xor    %r13d,%r13d
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  movslq %eax,%rbp
  call   <va_end@plt>
  test   %ebp,%ebp
  js     L6
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L18
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D0(%rip),%rdi
  sub    $0x1,%rbx
  call   <Sys_failure@plt>
  cmp    %rbx,%rbp
  jne    L23
L18:
  lea    D3(%rip),%rdi
  call   <Warning@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D3
type: string

tool: D0: snprintf

tool: D3: snprintf: the output may be truncated.

assistant: ```c
void Snprintf(char *str, size_t size, const char *format, ...) {
  va_list ap;
  int retval;
  assert(str != NULL);
  assert(format != NULL);
  va_start(ap, format);
  retval = vsnprintf(str, size, format, ap);
  va_end(ap);
  if (retval < 0)
    Sys_failure("snprintf");
  if (retval == size - 1)
    Warning("snprintf: the output may be truncated.");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x9999,%edi
  call   <bufferedInputStream@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  fildl  -0x20(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  jmp    L39
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,-0x1c(%rbp)
  fildl  -0x1c(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
L39:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L29
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L16
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadLongDouble@plt>
  fstpt  -0x10(%rbp)
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
L16:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L23
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L41
L50:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferedReadLongDouble@plt>
  fstpt  -0x10(%rbp)
  fildl  -0x1c(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
L41:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L50
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D41
type: string

tool: D4: %d


tool: D41: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n, m, k;
  long double d;
  n = bufferedReadInt(bis);
  m = n;
  printf("%d\n", n);
  while (m--) {
    k = bufferedReadInt(bis);
    printf("%d\n", k);
  }
  m = n;
  while (m--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  m = n;
  while (m--) {
    k = bufferedReadInt(bis);
    d = bufferedReadLongDouble(bis);
    printf("%d\n", k);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    $0x9999,%edi
  call   <bufferedInputStream@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,%ebp
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D13(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  test   %ebp,%ebp
  je     L16
  mov    %ebp,%r12d
  mov    %ebp,%r13d
  lea    D13(%rip),%r14
L12:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,0xc(%rsp)
  fildl  0xc(%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  sub    $0x1,%r13d
  jne    L12
  lea    D28(%rip),%r13
L30:
  mov    %rbx,%rdi
  call   <bufferedReadLongDouble@plt>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  sub    $0x1,%ebp
  jne    L30
  lea    D13(%rip),%r13
  lea    D28(%rip),%rbp
L11:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  mov    %eax,0xc(%rsp)
  mov    %rbx,%rdi
  call   <bufferedReadLongDouble@plt>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%r14
  mov    0x18(%rsp),%r15d
  fildl  0xc(%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %r13,%rdi
  call   <printf@plt>
  push   %r15
  push   %r14
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  sub    $0x1,%r12d
  jne    L11
L16:
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string

tool: D13: %d


tool: D28: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n, m, k;
  long double d;
  n = bufferedReadInt(bis);
  m = n;
  printf("%d\n", n);
  while (m--) {
    k = bufferedReadInt(bis);
    printf("%d\n", k);
  }
  m = n;
  while (m--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  m = n;
  while (m--) {
    k = bufferedReadInt(bis);
    d = bufferedReadLongDouble(bis);
    printf("%d\n", k);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x9999,%edi
  lea    D8(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  call   <bufferedInputStream@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  mov    %eax,%ebp
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rdi
  pop    %r8
  test   %ebp,%ebp
  je     L27
  mov    %ebp,%r12d
  mov    %ebp,%r13d
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rcx
  pop    %rsi
  sub    $0x1,%r13d
  jne    L34
  lea    D12(%rip),%r13
  xchg   %ax,%ax
L3:
  mov    %rbx,%rdi
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r13,%rdi
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  sub    $0x1,%ebp
  jne    L3
  xchg   %ax,%ax
L29:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  mov    %rbx,%rdi
  mov    %eax,0xc(%rsp)
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  fstpt  0x20(%rsp)
  fildl  0x1c(%rsp)
  fstpt  (%rsp)
  call   <printf@plt>
  fldt   0x20(%rsp)
  mov    %r13,%rdi
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <printf@plt>
  add    $0x20,%rsp
  sub    $0x1,%r12d
  jne    L29
L27:
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D12
data_type: string

tool: D8: %d


tool: D12: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n, m, k;
  long double d;
  n = bufferedReadInt(bis);
  m = n;
  printf("%d\n", n);
  while (m--) {
    k = bufferedReadInt(bis);
    printf("%d\n", k);
  }
  m = n;
  while (m--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  m = n;
  while (m--) {
    k = bufferedReadInt(bis);
    d = bufferedReadLongDouble(bis);
    printf("%d\n", k);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x9999,%edi
  lea    D14(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  call   <bufferedInputStream@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  mov    %eax,%ebp
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rdi
  pop    %r8
  test   %ebp,%ebp
  je     L1
  mov    %ebp,%r12d
  mov    %ebp,%r13d
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  mov    %eax,0x1c(%rsp)
  fildl  0x1c(%rsp)
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rcx
  pop    %rsi
  sub    $0x1,%r13d
  jne    L4
  lea    D9(%rip),%r13
  xchg   %ax,%ax
L35:
  mov    %rbx,%rdi
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r13,%rdi
  fstpt  (%rsp)
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  sub    $0x1,%ebp
  jne    L35
  xchg   %ax,%ax
L32:
  mov    %rbx,%rdi
  call   <bufferedReadInt@plt>
  mov    %rbx,%rdi
  mov    %eax,0xc(%rsp)
  call   <bufferedReadLongDouble@plt>
  sub    $0x10,%rsp
  mov    %r14,%rdi
  fstpt  0x20(%rsp)
  fildl  0x1c(%rsp)
  fstpt  (%rsp)
  call   <printf@plt>
  fldt   0x20(%rsp)
  mov    %r13,%rdi
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <printf@plt>
  add    $0x20,%rsp
  sub    $0x1,%r12d
  jne    L32
L1:
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D14: %d


tool: D9: %.6LF


assistant: ```c
int main() {
  struct BufferedInputStream *bis = bufferedInputStream(786432ull / 20);
  int n, m, k;
  long double d;
  n = bufferedReadInt(bis);
  m = n;
  printf("%d\n", n);
  while (m--) {
    k = bufferedReadInt(bis);
    printf("%d\n", k);
  }
  m = n;
  while (m--) {
    d = bufferedReadLongDouble(bis);
    printf("%.6LF\n", d);
  }
  m = n;
  while (m--) {
    k = bufferedReadInt(bis);
    d = bufferedReadLongDouble(bis);
    printf("%d\n", k);
    printf("%.6LF\n", d);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movss  D27(%rip),%xmm0
  movss  %xmm0,-0x58(%rbp)
  movsd  D28(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movl   $0x1,-0x54(%rbp)
  movw   $0x1,-0x5a(%rbp)
  movq   $0x1,-0x48(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x58(%rbp),%xmm2
  movq   %xmm2,%rax
  movsd  D28(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <expectf@plt>
  movsd  D28(%rip),%xmm0
  mov    -0x50(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <expectd@plt>
  mov    -0x54(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  movswl -0x5a(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    -0x48(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    $0x0,%eax
  call   <ignore@plt>
  cltq
  mov    $0x400,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x40(%rbp),%rax
  lea    (%rax,%rdx,1),%rbx
  mov    $0x0,%eax
  call   <ignore@plt>
  mov    %eax,(%rbx)
  mov    -0x54(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    $0x400,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D27
datatype: f32
name: disassemble_data
arguments: tag: D28
datatype: byte[8]

tool: D27: 1

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void test() {
  float a = (float)1;
  double b = (double)1;
  int c = (int)1.0;
  short d = (short)1.0;
  long e = (long)1.0;
  expectf(a, 1.0);
  expectd(b, 1.0);
  expecti(c, 1);
  expecti(d, 1);
  expecti(e, 1);
  expecti((int *)(ignore()), 1024);
  int n[10];
  *(int *)(n + c) = (int *)(ignore());
  expecti(n[c], 1024);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  movq   %rax,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <expectf@plt>
  mov    D8(%rip),%rax
  movq   %rax,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <expectd@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    $0x0,%eax
  call   <ignore@plt>
  movslq %eax,%rdi
  mov    $0x400,%esi
  mov    $0x0,%eax
  call   <expecti@plt>
  mov    $0x0,%eax
  call   <ignore@plt>
  mov    %eax,%edi
  mov    $0x400,%esi
  mov    $0x0,%eax
  call   <expecti@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: f64

tool: D8: 1

assistant: ```c
void test() {
  float a = (float)1;
  double b = (double)1;
  int c = (int)1.0;
  short d = (short)1.0;
  long e = (long)1.0;
  expectf(a, 1.0);
  expectd(b, 1.0);
  expecti(c, 1);
  expecti(d, 1);
  expecti(e, 1);
  expecti((int *)(ignore()), 1024);
  int n[10];
  *(int *)(n + c) = (int *)(ignore());
  expecti(n[c], 1024);
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  movsd  D19(%rip),%xmm1
  mov    $0x2,%eax
  movapd %xmm1,%xmm0
  call   <expectf@plt>
  mov    D19(%rip),%rax
  movq   %rax,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <expectd@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <expecti@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <expecti@plt>
  xor    %eax,%eax
  call   <ignore@plt>
  mov    $0x400,%esi
  movslq %eax,%rdi
  xor    %eax,%eax
  call   <expecti@plt>
  xor    %eax,%eax
  call   <ignore@plt>
  mov    $0x400,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1080 <expecti@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: f64

tool: D19: 1

assistant: ```c
void test() {
  float a = (float)1;
  double b = (double)1;
  int c = (int)1.0;
  short d = (short)1.0;
  long e = (long)1.0;
  expectf(a, 1.0);
  expectd(b, 1.0);
  expecti(c, 1);
  expecti(d, 1);
  expecti(e, 1);
  expecti((int *)(ignore()), 1024);
  int n[10];
  *(int *)(n + c) = (int *)(ignore());
  expecti(n[c], 1024);
}
```