ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<increment>:
  endbr64
  test   %rsi,%rsi
  je     L11
  lea    -0x1(%rdi,%rsi,1),%rax
  movzbl (%rax),%ecx
  cmp    $0x7a,%cl
  jne    L25
  lea    -0x2(%rdi,%rsi,1),%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  nopl   0x0(%rax)
L22:
  sub    $0x1,%rdx
  movb   $0x61,(%rax)
  add    %rsi,%rax
  movzbl 0x1(%rdx),%ecx
  cmp    $0x7a,%cl
  je     L22
L25:
  add    $0x1,%ecx
  mov    %cl,(%rax)
L11:
  ret
```

assistant: ```c
void increment(char *s, size_t len) {
  if (len < 1) {
    return;
  }
  for (size_t idx = len - 1;; idx--) {
    if (s[idx] == 'z') {
      s[idx] = 'a';
    } else {
      s[idx] += 1;
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0x96a,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L35
L30:
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jbe    L51
  movzwl -0xa(%rbp),%eax
  cmp    %ax,-0xc(%rbp)
  jne    L68
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  lea    -0xa(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L66
L68:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%edx
  movzwl -0xc(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  jmp    L66
L51:
  movzwl -0xa(%rbp),%edx
  movzwl -0xc(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
L66:
  addw   $0x2,-0xc(%rbp)
L35:
  cmpw   $0x0,-0xc(%rbp)
  je     L30
  movzwl -0xa(%rbp),%eax
  lea    0x3cf8(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 468445703UL) + (unsigned short)21233;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x2a24(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 468445703UL) + (unsigned short)21233;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x2a24(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 468445703UL) + (unsigned short)21233;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x2a24(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned short)8426;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          state[local1] += state[local1];
        }
      } else {
        state[local1] = state[0UL] + state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 468445703UL) + (unsigned short)21233;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pad_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void pad_blanks(char s[], int numc) {
  int len;
  int k;
  len = strlen(s);
  for (k = len; k < numc; k++)
    s[k] = ' ';
  s[numc] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pad_blanks>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L1
  movslq %eax,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  lea    -0x1(%rbx),%esi
  sub    %eax,%esi
  lea    (%rcx,%rsi,1),%rax
L3:
  movb   $0x20,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L3
L1:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_blanks(char s[], int numc) {
  int len;
  int k;
  len = strlen(s);
  for (k = len; k < numc; k++)
    s[k] = ' ';
  s[numc] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<pad_blanks>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L9
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
L9:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_blanks(char s[], int numc) {
  int len;
  int k;
  len = strlen(s);
  for (k = len; k < numc; k++)
    s[k] = ' ';
  s[numc] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pad_blanks>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L9
  lea    -0x1(%rbx),%edx
  mov    $0x20,%esi
  sub    %eax,%edx
  cltq
  add    $0x1,%rdx
  lea    0x0(%rbp,%rax,1),%rdi
  call   <memset@plt>
L9:
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_blanks(char s[], int numc) {
  int len;
  int k;
  len = strlen(s);
  for (k = len; k < numc; k++)
    s[k] = ' ';
  s[numc] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<_malloc_flex_struct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <_try_load_flex_struct_size@plt>
  test   %rax,%rax
  je     L12
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L19
L12:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
void *_malloc_flex_struct(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length) {
  size_t size;
  return (_try_load_flex_struct_size(struct_size, fam_type_size, fam_offset, fam_length, &size)) ? malloc(size) : NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<_malloc_flex_struct>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  call   <_try_load_flex_struct_size@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L14
  mov    (%rsp),%rdi
  call   <malloc@plt>
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_malloc_flex_struct(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length) {
  size_t size;
  return (_try_load_flex_struct_size(struct_size, fam_type_size, fam_offset, fam_length, &size)) ? malloc(size) : NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_malloc_flex_struct>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  call   <_try_load_flex_struct_size@plt>
  test   %rax,%rax
  je     L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  jmp    1090 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_malloc_flex_struct(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length) {
  size_t size;
  return (_try_load_flex_struct_size(struct_size, fam_type_size, fam_offset, fam_length, &size)) ? malloc(size) : NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_malloc_flex_struct>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  call   <_try_load_flex_struct_size@plt>
  test   %rax,%rax
  je     L26
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  jmp    1090 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *_malloc_flex_struct(size_t struct_size, size_t fam_type_size, size_t fam_offset, size_t fam_length) {
  size_t size;
  return (_try_load_flex_struct_size(struct_size, fam_type_size, fam_offset, fam_length, &size)) ? malloc(size) : NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  jne    L47
  mov    -0x18(%rbp),%rax
  jmp    L31
L47:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(char *d, const char *s) {
  const char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return ((void *)0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L27
L10:
  mov    %rsi,%rdx
L8:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L49
  add    $0x1,%rdx
  cmp    %r8b,%cl
  jne    L8
L39:
  ret
L27:
  mov    $0x0,%eax
  ret
L49:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L10
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
char *strpbrk(char *d, const char *s) {
  const char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return ((void *)0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L2
L31:
  mov    %rsi,%rdx
  jmp    L0
  nopl   (%rax)
L26:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L30
L0:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L26
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L31
L2:
  xor    %eax,%eax
L30:
  ret
```

assistant: ```c
char *strpbrk(char *d, const char *s) {
  const char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return ((void *)0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L26
L35:
  mov    %rsi,%rdx
  jmp    L9
  nopl   (%rax)
L25:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L22
L9:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L25
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L35
L26:
  xor    %eax,%eax
L22:
  ret
```

assistant: ```c
char *strpbrk(char *d, const char *s) {
  const char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return ((void *)0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_pico_strrtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L80
L56:
  cmpl   $0x0,-0xc(%rbp)
  je     L106
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L106
  movl   $0x0,-0xc(%rbp)
L106:
  addq   $0x1,-0x8(%rbp)
L80:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  cmpl   $0x0,-0xc(%rbp)
  je     L25
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L7
L25:
  subq   $0x1,-0x8(%rbp)
  jmp    L40
L94:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L7
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L94
L7:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *_pico_strrtrim(char *str) {
  if (str && *str) {
    char *str1 = str;
    int allspace = 1;
    while (*str1) {
      if (allspace && !isspace(*str1))
        allspace = 0;
      str1++;
    }
    if (allspace)
      *str = '\0';
    else {
      str1--;
      while ((isspace(*str1)) && (str1 >= str))
        *str1-- = '\0';
    }
  }
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_pico_strrtrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L18
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L18
  mov    %rbp,%rbx
  mov    $0x1,%edx
  jmp    L55
L89:
  lea    0x1(%rbx),%rax
  movzbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L48
  mov    %rax,%rbx
L55:
  test   %edx,%edx
  je     L89
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  setne  %dl
  movzbl %dl,%edx
  jmp    L89
L48:
  test   %edx,%edx
  je     L96
  movb   $0x0,0x0(%rbp)
L18:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L96:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    %rbp,%rbx
  jb     L18
  test   %rax,%rax
  je     L18
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  jmp    L96
```

assistant: ```c
char *_pico_strrtrim(char *str) {
  if (str && *str) {
    char *str1 = str;
    int allspace = 1;
    while (*str1) {
      if (allspace && !isspace(*str1))
        allspace = 0;
      str1++;
    }
    if (allspace)
      *str = '\0';
    else {
      str1--;
      while ((isspace(*str1)) && (str1 >= str))
        *str1-- = '\0';
    }
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_pico_strrtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L46
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L46
  mov    $0x1,%ebx
  mov    %r12,%rbp
  test   %ebx,%ebx
  je     L123
L3:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L30
  cmpb   $0x0,0x1(%rbp)
  lea    0x1(%rbp),%rbx
  je     L136
L40:
  cmpb   $0x0,0x1(%rbx)
  lea    0x1(%rbx),%rbp
  je     L81
  xor    %ebx,%ebx
L30:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rax
  test   %dil,%dil
  je     L0
  mov    %rax,%rbp
  test   %ebx,%ebx
  jne    L3
L123:
  mov    %rbp,%rbx
  jmp    L40
  nopl   (%rax)
L0:
  test   %ebx,%ebx
  je     L136
  movb   $0x0,(%r12)
L46:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L134:
  test   %rax,%rax
  je     L46
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L81:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    %r12,%rbx
  jae    L134
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L136:
  mov    %rbp,%rbx
  jmp    L81
```

assistant: ```c
char *_pico_strrtrim(char *str) {
  if (str && *str) {
    char *str1 = str;
    int allspace = 1;
    while (*str1) {
      if (allspace && !isspace(*str1))
        allspace = 0;
      str1++;
    }
    if (allspace)
      *str = '\0';
    else {
      str1--;
      while ((isspace(*str1)) && (str1 >= str))
        *str1-- = '\0';
    }
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_pico_strrtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L14
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
  mov    $0x1,%ebx
  mov    %r12,%rbp
  test   %ebx,%ebx
  je     L82
L20:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L79
  cmpb   $0x0,0x1(%rbp)
  lea    0x1(%rbp),%rbx
  je     L43
L81:
  cmpb   $0x0,0x1(%rbx)
  lea    0x1(%rbx),%rbp
  je     L41
  xor    %ebx,%ebx
L79:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rax
  test   %dil,%dil
  je     L124
  mov    %rax,%rbp
  test   %ebx,%ebx
  jne    L20
L82:
  mov    %rbp,%rbx
  jmp    L81
  nopl   (%rax)
L124:
  test   %ebx,%ebx
  je     L43
  movb   $0x0,(%r12)
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L112:
  test   %rax,%rax
  je     L14
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L41:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  cmp    %r12,%rbx
  jae    L112
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rbp,%rbx
  jmp    L41
```

assistant: ```c
char *_pico_strrtrim(char *str) {
  if (str && *str) {
    char *str1 = str;
    int allspace = 1;
    while (*str1) {
      if (allspace && !isspace(*str1))
        allspace = 0;
      str1++;
    }
    if (allspace)
      *str = '\0';
    else {
      str1--;
      while ((isspace(*str1)) && (str1 >= str))
        *str1-- = '\0';
    }
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<database_prepare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <sqlite3_prepare_v2@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x80,-0x14(%rbp)
  jne    L28
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <logprintf@plt>
  mov    -0x10(%rbp),%rax
  jmp    L19
L28:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlite3_errmsg@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <logprintf@plt>
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D6
type_infered: string

tool: D12: Statement (%s) compiled ok


tool: D6: Failed to prepare statement (%s): %s


assistant: ```c
sqlite3_stmt *database_prepare(sqlite3 *conn, char *query) {
  int status;
  sqlite3_stmt *target = NULL;
  status = sqlite3_prepare_v2(conn, query, strlen(query), &target, NULL);
  switch (status) {
  case SQLITE_OK:
    logprintf(3, "Statement (%s) compiled ok\n", query);
    return target;
  default:
    logprintf(0, "Failed to prepare statement (%s): %s\n", query, sqlite3_errmsg(conn));
  }
  return NULL;
}
```