ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<svd_idamax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jg     L98
  mov    $0xffffffffffffffff,%rax
  jmp    L2
L98:
  cmpq   $0x1,-0x38(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L2
L21:
  cmpq   $0x0,-0x48(%rbp)
  jne    L88
  mov    $0xffffffffffffffff,%rax
  jmp    L2
L88:
  cmpq   $0x0,-0x48(%rbp)
  jns    L51
  mov    $0x1,%eax
  sub    -0x38(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L19
L51:
  movq   $0x0,-0x28(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x1,-0x20(%rbp)
  jmp    L14
L100:
  mov    -0x48(%rbp),%rax
  add    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L38
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L38:
  addq   $0x1,-0x20(%rbp)
L14:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L100
  mov    -0x18(%rbp),%rax
L2:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: qword

tool: D9: 9223372036854775807

assistant: ```c
long svd_idamax(long n, double *dx, long incx) {
  long ix, i, imax;
  double dtemp, dmax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx == 0)
    return (-1);
  if (incx < 0)
    ix = (-n + 1) * incx;
  else
    ix = 0;
  imax = ix;
  dx += ix;
  dmax = fabs(*dx);
  for (i = 1; i < n; i++) {
    ix += incx;
    dx += incx;
    dtemp = fabs(*dx);
    if (dtemp > dmax) {
      dmax = dtemp;
      imax = ix;
    }
  }
  return (imax);
}
```
user: Translate the below assembly code into C programming language:

```asm
<svd_idamax>:
  endbr64
  test   %rdi,%rdi
  jle    L38
  mov    $0x0,%r8d
  cmp    $0x1,%rdi
  je     L51
  test   %rdx,%rdx
  je     L57
  mov    $0x0,%eax
  js     L17
L36:
  lea    (%rsi,%rax,8),%rcx
  movsd  (%rcx),%xmm1
  andpd  D15(%rip),%xmm1
  lea    0x0(,%rdx,8),%r9
  mov    %rax,%r8
  mov    $0x1,%esi
  movq   D15(%rip),%xmm2
L27:
  add    %rdx,%rax
  add    %r9,%rcx
  movsd  (%rcx),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmova  %rax,%r8
  add    $0x1,%rsi
  cmp    %rsi,%rdi
  jg     L27
L51:
  mov    %r8,%rax
  ret
L17:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  jmp    L36
L38:
  mov    $0xffffffffffffffff,%r8
  jmp    L51
L57:
  mov    $0xffffffffffffffff,%r8
  jmp    L51
```

tool_calls: name: read_data
arguments: label: D15
datatype: qword[2]

tool: {"D15": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
long svd_idamax(long n, double *dx, long incx) {
  long ix, i, imax;
  double dtemp, dmax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx == 0)
    return (-1);
  if (incx < 0)
    ix = (-n + 1) * incx;
  else
    ix = 0;
  imax = ix;
  dx += ix;
  dmax = fabs(*dx);
  for (i = 1; i < n; i++) {
    ix += incx;
    dx += incx;
    dtemp = fabs(*dx);
    if (dtemp > dmax) {
      dmax = dtemp;
      imax = ix;
    }
  }
  return (imax);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<svd_idamax>:
  endbr64
  test   %rdi,%rdi
  jle    L25
  xor    %r8d,%r8d
  cmp    $0x1,%rdi
  je     L34
  test   %rdx,%rdx
  je     L25
  mov    $0x0,%eax
  js     L15
L49:
  movsd  (%rsi),%xmm1
  movq   D9(%rip),%xmm2
  mov    %rax,%r8
  mov    $0x1,%ecx
  lea    0x0(,%rdx,8),%r9
  andpd  %xmm2,%xmm1
  xchg   %ax,%ax
L64:
  add    %r9,%rsi
  add    %rdx,%rax
  movsd  (%rsi),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  cmova  %rax,%r8
  add    $0x1,%rcx
  movapd %xmm0,%xmm1
  cmp    %rcx,%rdi
  jg     L64
L34:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  lea    (%rsi,%rax,8),%rsi
  jmp    L49
L25:
  mov    $0xffffffffffffffff,%r8
  jmp    L34
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: qword

tool: D9: 9223372036854775807

assistant: ```c
long svd_idamax(long n, double *dx, long incx) {
  long ix, i, imax;
  double dtemp, dmax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx == 0)
    return (-1);
  if (incx < 0)
    ix = (-n + 1) * incx;
  else
    ix = 0;
  imax = ix;
  dx += ix;
  dmax = fabs(*dx);
  for (i = 1; i < n; i++) {
    ix += incx;
    dx += incx;
    dtemp = fabs(*dx);
    if (dtemp > dmax) {
      dmax = dtemp;
      imax = ix;
    }
  }
  return (imax);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<svd_idamax>:
  endbr64
  test   %rdi,%rdi
  jle    L28
  xor    %eax,%eax
  cmp    $0x1,%rdi
  je     L5
  test   %rdx,%rdx
  je     L28
  js     L70
  movsd  (%rsi),%xmm1
  movq   D16(%rip),%xmm2
  lea    0x0(,%rdx,8),%rcx
  andpd  %xmm2,%xmm1
  cmp    $0x1,%rdx
  jne    L77
  nopw   0x0(%rax,%rax,1)
L69:
  add    %rcx,%rsi
  movsd  (%rsi),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  cmova  %rdx,%rax
  add    $0x1,%rdx
  movapd %xmm0,%xmm1
  cmp    %rdx,%rdi
  jg     L69
  ret
L28:
  mov    $0xffffffffffffffff,%rax
L5:
  ret
  nopl   (%rax)
L70:
  mov    $0x1,%r8d
  movq   D16(%rip),%xmm2
  lea    0x0(,%rdx,8),%rcx
  sub    %rdi,%r8
  imul   %rdx,%r8
  lea    (%rsi,%r8,8),%rsi
  mov    %r8,%rax
  movsd  (%rsi),%xmm1
  andpd  %xmm2,%xmm1
L24:
  mov    $0x1,%r9d
  nopw   0x0(%rax,%rax,1)
L33:
  add    %rcx,%rsi
  add    %rdx,%r8
  movsd  (%rsi),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  maxsd  %xmm1,%xmm0
  cmova  %r8,%rax
  add    $0x1,%r9
  movapd %xmm0,%xmm1
  cmp    %r9,%rdi
  jg     L33
  ret
L77:
  xor    %r8d,%r8d
  jmp    L24
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: qword

tool: D16: 9223372036854775807

assistant: ```c
long svd_idamax(long n, double *dx, long incx) {
  long ix, i, imax;
  double dtemp, dmax;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx == 0)
    return (-1);
  if (incx < 0)
    ix = (-n + 1) * incx;
  else
    ix = 0;
  imax = ix;
  dx += ix;
  dmax = fabs(*dx);
  for (i = 1; i < n; i++) {
    ix += incx;
    dx += incx;
    dtemp = fabs(*dx);
    if (dtemp > dmax) {
      dmax = dtemp;
      imax = ix;
    }
  }
  return (imax);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  jmp    L21
L9:
  cmpb   $0xa,-0x1(%rbp)
  je     L27
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <dec_bin@plt>
L27:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
L21:
  mov    D5(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L9
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  char z;
  z = getchar();
  while (z != EOF) {
    if (z != '\n')
      dec_bin(z);
    z = getchar();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    (%rdx),%al
  jne    L17
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L38:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %al,(%rdx)
  je     L32
L17:
  cmp    $0xa,%al
  je     L38
  movsbl %al,%edi
  call   <dec_bin@plt>
  jmp    L38
```

assistant: ```c
int main() {
  char z;
  z = getchar();
  while (z != EOF) {
    if (z != '\n')
      dec_bin(z);
    z = getchar();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rbx
  cmp    (%rbx),%al
  je     L8
  nopw   0x0(%rax,%rax,1)
L3:
  cmp    $0xa,%al
  je     L18
  movsbl %al,%edi
  call   <dec_bin@plt>
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L3
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  char z;
  z = getchar();
  while (z != EOF) {
    if (z != '\n')
      dec_bin(z);
    z = getchar();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D2(%rip),%rbx
  cmp    (%rbx),%al
  je     L8
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    $0xa,%al
  je     L10
  movsbl %al,%edi
  call   <dec_bin@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  jne    L5
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L5
  jmp    L8
```

assistant: ```c
int main() {
  char z;
  z = getchar();
  while (z != EOF) {
    if (z != '\n')
      dec_bin(z);
    z = getchar();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dcf_binop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dc_pop@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dc_pop@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x7c,%eax
  je     L1
  cmp    $0x7c,%eax
  jg     L33
  cmp    $0x2f,%eax
  jg     L99
  cmp    $0x25,%eax
  jl     L33
  sub    $0x25,%eax
  cmp    $0xa,%eax
  ja     L33
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D16(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D16(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L99:
  cmp    $0x5e,%eax
  je     L77
  jmp    L33
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0xc(%rbp)
  jmp    L13
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0xc(%rbp)
  jmp    L13
L77:
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L1:
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L33:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  nop
L13:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <dc_push@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type: string

tool: D29: dcf_binop(%s)

assistant: ```c
void dcf_binop(struct dc *dc, char *cmd) {
  int v0 = dc_pop(dc);
  int v1 = dc_pop(dc);
  int v2 = 0;
  switch (*cmd) {
  case '+':
    v2 = v0 + v1;
    break;
  case '-':
    v2 = v0 - v1;
    break;
  case '*':
    v2 = v0 * v1;
    break;
  case '/':
    v2 = v0 / v1;
    break;
  case '%':
    v2 = v0 % v1;
    break;
  case '^':
    v2 = v0 ^ v1;
    break;
  case '&':
    v2 = v0 & v1;
    break;
  case '|':
    v2 = v0 | v1;
    break;
  default:
    errx(2, "dcf_binop(%s)", cmd);
    break;
  }
  dc_push(dc, v2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dcf_binop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <dc_pop@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <dc_pop@plt>
  mov    %eax,%ecx
  movzbl (%r12),%edx
  cmp    $0x2f,%dl
  jg     L111
  cmp    $0x24,%dl
  jle    L6
  sub    $0x25,%edx
  cmp    $0xa,%dl
  ja     L6
  movzbl %dl,%edx
  lea    D15(%rip),%rsi
  movslq (%rsi,%rdx,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
L111:
  mov    %ebp,%esi
  xor    %eax,%esi
  cmp    $0x5e,%dl
  je     L50
  cmp    $0x7c,%dl
  jne    L6
  mov    %ebp,%esi
  or     %eax,%esi
  jmp    L50
  lea    0x0(%rbp,%rcx,1),%esi
L50:
  mov    %rbx,%rdi
  call   <dc_push@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  mov    %ebp,%esi
  sub    %ecx,%esi
  jmp    L50
  mov    %ebp,%esi
  imul   %ecx,%esi
  jmp    L50
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  jmp    L50
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  jmp    L50
  mov    %ebp,%esi
  and    %ecx,%esi
  jmp    L50
L6:
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  mov    $0x0,%esi
  jmp    L50
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0: dcf_binop(%s)

assistant: ```c
void dcf_binop(struct dc *dc, char *cmd) {
  int v0 = dc_pop(dc);
  int v1 = dc_pop(dc);
  int v2 = 0;
  switch (*cmd) {
  case '+':
    v2 = v0 + v1;
    break;
  case '-':
    v2 = v0 - v1;
    break;
  case '*':
    v2 = v0 * v1;
    break;
  case '/':
    v2 = v0 / v1;
    break;
  case '%':
    v2 = v0 % v1;
    break;
  case '^':
    v2 = v0 ^ v1;
    break;
  case '&':
    v2 = v0 & v1;
    break;
  case '|':
    v2 = v0 | v1;
    break;
  default:
    errx(2, "dcf_binop(%s)", cmd);
    break;
  }
  dc_push(dc, v2);
}
```
user: What is the c source code of the assembly code below:

```asm
<d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x1,-0x4(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <e@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: d(%d)


assistant: ```c
void d(int x) {
  printf("d(%d)\n", x);
  if (x > 1)
    e(x - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<d>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jg     L8
L11:
  pop    %rbx
  ret
L8:
  lea    -0x1(%rbx),%edi
  call   <e@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: d(%d)


assistant: ```c
void d(int x) {
  printf("d(%d)\n", x);
  if (x > 1)
    e(x - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<d>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jg     L8
  pop    %rbx
  ret
  nopl   0x0(%rax)
L8:
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1070 <e@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: d(%d)


assistant: ```c
void d(int x) {
  printf("d(%d)\n", x);
  if (x > 1)
    e(x - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<d>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jg     L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  lea    -0x1(%rbx),%edi
  pop    %rbx
  jmp    1070 <e@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: d(%d)


assistant: ```c
void d(int x) {
  printf("d(%d)\n", x);
  if (x > 1)
    e(x - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ztimeout_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%esi
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  add    %esi,%eax
  movslq %eax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
long ztimeout_left(long timeout) {
  long r;
  struct timeval tv;
  gettimeofday(&tv, 0);
  r = timeout + 1 - (tv.tv_sec * 1000 + tv.tv_usec / 1000);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ztimeout_left>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0x1(%rbx),%rax
  imul   $0x3e8,(%rsp),%ecx
  mov    0x4(%rsp),%esi
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long ztimeout_left(long timeout) {
  long r;
  struct timeval tv;
  gettimeofday(&tv, 0);
  r = timeout + 1 - (tv.tv_sec * 1000 + tv.tv_usec / 1000);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ztimeout_left>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%ecx
  lea    0x1(%rbx),%rax
  mov    %rdx,%rsi
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x26,%rdx
  sub    %esi,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long ztimeout_left(long timeout) {
  long r;
  struct timeval tv;
  gettimeofday(&tv, 0);
  r = timeout + 1 - (tv.tv_sec * 1000 + tv.tv_usec / 1000);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<ztimeout_left>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%ecx
  lea    0x1(%rbx),%rax
  mov    %rdx,%rsi
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x26,%rdx
  sub    %esi,%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long ztimeout_left(long timeout) {
  long r;
  struct timeval tv;
  gettimeofday(&tv, 0);
  r = timeout + 1 - (tv.tv_sec * 1000 + tv.tv_usec / 1000);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D43(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <plus@plt>
  movq   %xmm0,%rbx
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <plus@plt>
  movq   %rbx,%xmm1
  lea    D9(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <minus@plt>
  movq   %xmm0,%rbx
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <minus@plt>
  movq   %rbx,%xmm1
  lea    D87(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <mul@plt>
  movq   %xmm0,%rbx
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <mul@plt>
  movq   %rbx,%xmm1
  lea    D48(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0x4(%rsp),%xmm1
  ucomiss D22(%rip),%xmm1
  jp     L14
  jne    L14
  lea    D73(%rip),%rdi
  call   <puts@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  movss  (%rsp),%xmm0
  call   <div@plt>
  movq   %xmm0,%rbx
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <div@plt>
  movq   %rbx,%xmm1
  lea    D40(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L24
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D43
datatype: string
name: extract_symbolic_data
arguments: tag: D35
datatype: string
name: extract_symbolic_data
arguments: tag: D9
datatype: string
name: extract_symbolic_data
arguments: tag: D87
datatype: string
name: extract_symbolic_data
arguments: tag: D48
datatype: string
name: extract_symbolic_data
arguments: tag: D22
datatype: byte[4]
name: extract_symbolic_data
arguments: tag: D73
datatype: string
name: extract_symbolic_data
arguments: tag: D40
datatype: string

tool: D11:  Input a  number, please? 

tool: D43: %f

tool: D35:  Input a  number2, please?  

tool: D9:  c + d = %.4f     %e


tool: D87:  c - d = %.4f     %e


tool: D48:  c * d = %.4f     %e


tool: {"D22": [0x00,0x00,0x00,0x00]}

tool: D73:  Unknown.

tool: D40:  c / d = %.4f     %e


assistant: ```c
int main() {
  float c, d;
  printf(" Input a  number, please? ");
  scanf("%f", &c);
  printf(" Input a  number2, please?  ");
  scanf("%f", &d);
  printf(" c + d = %.4f     %e\n", plus(c, d), plus(c, d));
  printf(" c - d = %.4f     %e\n", minus(c, d), minus(c, d));
  printf(" c * d = %.4f     %e\n", mul(c, d), mul(c, d));
  if (d == 0)
    printf(" Unknown.\n");
  else
    printf(" c / d = %.4f     %e\n", div(c, d), div(c, d));
  return 0;
}
```