ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x25,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L45
  movzbl -0x9(%rbp),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L22
  movzbl -0x9(%rbp),%eax
  mov    %eax,%ecx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  imul   %edx,%eax
  shl    $0x4,%eax
  and    $0xfffffff0,%eax
  or     %ecx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L49
L22:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    %eax,%eax
  shl    $0x3,%eax
  and    $0x70,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  jmp    L49
L45:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  sar    %cl,%esi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    %al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  mov    $0x8,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edi,%eax
  mov    %al,-0x9(%rbp)
L49:
  movzbl -0x9(%rbp),%eax
  lea    -0x1a(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)31) << 4UL;
      } else {
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    }
    output[0UL] = state[0UL] + (unsigned char)230;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L28
  test   $0x4,%al
  je     L35
  imul   %edx,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  jmp    L11
L35:
  shl    $0x4,%edx
  and    $0x70,%edx
  or     %edx,%eax
  jmp    L11
L28:
  mov    %eax,%r8d
  shr    %r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x8,%ecx
  sub    %r8d,%ecx
  mov    %edx,%edi
  shl    %cl,%edi
  mov    %r8d,%ecx
  sar    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
L11:
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)31) << 4UL;
      } else {
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    }
    output[0UL] = state[0UL] + (unsigned char)230;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L19
  test   $0x4,%al
  je     L4
  imul   %edx,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %eax,%r8d
  mov    $0x8,%ecx
  shr    %r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edi
  sub    %edi,%ecx
  mov    %edx,%edi
  shl    %cl,%edi
  mov    %r8d,%ecx
  sar    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  shl    $0x4,%edx
  and    $0x70,%edx
  or     %edx,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)31) << 4UL;
      } else {
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    }
    output[0UL] = state[0UL] + (unsigned char)230;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L4
  test   $0x4,%al
  je     L9
  imul   %edx,%edx
  shl    $0x4,%edx
  or     %edx,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %eax,%r8d
  mov    $0x8,%ecx
  shr    %r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edi
  sub    %edi,%ecx
  mov    %edx,%edi
  shl    %cl,%edi
  mov    %r8d,%ecx
  sar    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  shl    $0x4,%edx
  and    $0x70,%edx
  or     %edx,%eax
  sub    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      if ((state[0UL] >> (unsigned char)2) & (unsigned char)1) {
        state[0UL] |= (state[0UL] * state[0UL] & (unsigned char)31) << 4UL;
      } else {
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 3UL;
      }
    } else {
      state[0UL] |= (((state[0UL] >> (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)) | (state[0UL] << (8 - (((state[0UL] >> (unsigned char)1) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    }
    output[0UL] = state[0UL] + (unsigned char)230;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ftgeti4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    $0x1e,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ftgetc@plt>
  test   %eax,%eax
  je     L1
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atof@plt>
  jmp    L24
L1:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int ftgeti4(entry, kw)
char *entry;
struct Keyword *kw;
{
  char temp[30];
  if (ftgetc(entry, kw, temp, 30))
    return ((int)atof(temp));
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ftgeti4>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x1e,%ecx
  call   <ftgetc@plt>
  test   %eax,%eax
  jne    L25
L19:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x38,%rsp
  ret
L25:
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <atof@plt>
  jmp    L19
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftgeti4(entry, kw)
char *entry;
struct Keyword *kw;
{
  char temp[30];
  if (ftgetc(entry, kw, temp, 30))
    return ((int)atof(temp));
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ftgeti4>:
  endbr64
  push   %rbp
  mov    $0x1e,%ecx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <ftgetc@plt>
  test   %eax,%eax
  jne    L28
L1:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x30,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <atof@plt>
  jmp    L1
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftgeti4(entry, kw)
char *entry;
struct Keyword *kw;
{
  char temp[30];
  if (ftgetc(entry, kw, temp, 30))
    return ((int)atof(temp));
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ftgeti4>:
  endbr64
  push   %rbp
  mov    $0x1e,%ecx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  call   <ftgetc@plt>
  test   %eax,%eax
  jne    L3
L12:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <atof@plt>
  jmp    L12
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ftgeti4(entry, kw)
char *entry;
struct Keyword *kw;
{
  char temp[30];
  if (ftgetc(entry, kw, temp, 30))
    return ((int)atof(temp));
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L20
  mov    $0x0,%eax
  call   <warning@plt>
  jmp    L29
L20:
  cmpl   $0x2,-0x4(%rbp)
  jne    L29
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <cbf@plt>
L29:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    warning();
  } else if (argc == 2) {
    cbf(argv[1]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L19
  mov    $0x0,%eax
  call   <warning@plt>
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L19:
  mov    0x8(%rsi),%rdi
  call   <cbf@plt>
  jmp    L8
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    warning();
  } else if (argc == 2) {
    cbf(argv[1]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L19
  xor    %eax,%eax
  call   <warning@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L19:
  mov    0x8(%rsi),%rdi
  call   <cbf@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    warning();
  } else if (argc == 2) {
    cbf(argv[1]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L13
  xor    %eax,%eax
  call   <warning@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L13:
  mov    0x8(%rsi),%rdi
  call   <cbf@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    warning();
  } else if (argc == 2) {
    cbf(argv[1]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x1c(%rbp)
  jmp    L41
L23:
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L34
L17:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jg     L17
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string

tool: D5: %d

tool: D0: %ld

tool: D25: %ld


assistant: ```c
int main() {
  int count, entries;
  long int number;
  long int wahdan = 0;
  scanf("%d", &entries);
  for (count = 1; count <= entries; count++) {
    wahdan = 0;
    scanf("%ld", &number);
    for (; number > 0;) {
      number /= 5;
      wahdan += number;
    }
    printf("%ld\n", wahdan);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L15
  mov    $0x1,%ebp
  lea    0x10(%rsp),%r14
  lea    D1(%rip),%r13
  movabs $0x6666666666666667,%rbx
  lea    D5(%rip),%r12
L58:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rcx
  test   %rcx,%rcx
  jle    L9
  mov    $0x0,%esi
L1:
  mov    %rcx,%rdi
  mov    %rcx,%rax
  imul   %rbx
  sar    %rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  mov    %rdx,%rcx
  add    %rdx,%rsi
  cmp    $0x4,%rdi
  jg     L1
  mov    %rdx,0x10(%rsp)
L51:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jge    L58
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  mov    $0x0,%esi
  jmp    L51
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string

tool: D21: %d

tool: D1: %ld

tool: D5: %ld


assistant: ```c
int main() {
  int count, entries;
  long int number;
  long int wahdan = 0;
  scanf("%d", &entries);
  for (count = 1; count <= entries; count++) {
    wahdan = 0;
    scanf("%ld", &number);
    for (; number > 0;) {
      number /= 5;
      wahdan += number;
    }
    printf("%ld\n", wahdan);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%rdi
  movabs $0xcccccccccccccccd,%r14
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L10
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rdx
  xor    %esi,%esi
  test   %rdx,%rdx
  jle    L47
  nopl   0x0(%rax)
L37:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  mul    %r14
  shr    $0x2,%rdx
  add    %rdx,%rsi
  cmp    $0x4,%rcx
  jg     L37
  mov    %rdx,0x10(%rsp)
L47:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L0
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D3: %d

tool: D0: %ld

tool: D6: %ld


assistant: ```c
int main() {
  int count, entries;
  long int number;
  long int wahdan = 0;
  scanf("%d", &entries);
  for (count = 1; count <= entries; count++) {
    wahdan = 0;
    scanf("%ld", &number);
    for (; number > 0;) {
      number /= 5;
      wahdan += number;
    }
    printf("%ld\n", wahdan);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D14(%rip),%rdi
  movabs $0xcccccccccccccccd,%r14
  push   %r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L5
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rdx
  xor    %esi,%esi
  test   %rdx,%rdx
  jle    L35
  nopl   0x0(%rax)
L38:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  mul    %r14
  shr    $0x2,%rdx
  add    %rdx,%rsi
  cmp    $0x4,%rcx
  jg     L38
  mov    %rdx,0x10(%rsp)
L35:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jge    L17
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: string
name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D14: %d

tool: D26: %ld

tool: D13: %ld


assistant: ```c
int main() {
  int count, entries;
  long int number;
  long int wahdan = 0;
  scanf("%d", &entries);
  for (count = 1; count <= entries; count++) {
    wahdan = 0;
    scanf("%ld", &number);
    for (; number > 0;) {
      number /= 5;
      wahdan += number;
    }
    printf("%ld\n", wahdan);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_cpu_usecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <timespec_to_usecs@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned long long get_cpu_usecs(void) {
  struct timespec ts = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return timespec_to_usecs(&ts);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_cpu_usecs>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    %rbx,%rdi
  call   <timespec_to_usecs@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_cpu_usecs(void) {
  struct timespec ts = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return timespec_to_usecs(&ts);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_cpu_usecs>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    %rbp,%rdi
  call   <timespec_to_usecs@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_cpu_usecs(void) {
  struct timespec ts = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return timespec_to_usecs(&ts);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_cpu_usecs>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    %rbp,%rdi
  call   <timespec_to_usecs@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long get_cpu_usecs(void) {
  struct timespec ts = {0, 0};
  clock_gettime(CLOCK_MONOTONIC, &ts);
  return timespec_to_usecs(&ts);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checkresolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <checkcmp@plt>
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D17: tools/.chk

tool: D3: gcc tools/chkresolv.c -o tools/chkresolv -lresolv 2>tools/.chk 

assistant: ```c
int checkresolve() {
  int rc;
  unlink("tools/.chk");
  system("gcc tools/chkresolv.c -o tools/chkresolv -lresolv"
         " 2>tools/.chk ");
  return checkcmp();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkresolve>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <unlink@plt>
  lea    D13(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <checkcmp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
datatype: string
name: unpack_data
arguments: data_label: D13
datatype: string

tool: D18: tools/.chk

tool: D13: gcc tools/chkresolv.c -o tools/chkresolv -lresolv 2>tools/.chk 

assistant: ```c
int checkresolve() {
  int rc;
  unlink("tools/.chk");
  system("gcc tools/chkresolv.c -o tools/chkresolv -lresolv"
         " 2>tools/.chk ");
  return checkcmp();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<checkresolve>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <unlink@plt>
  lea    D11(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <checkcmp@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string

tool: D19: tools/.chk

tool: D11: gcc tools/chkresolv.c -o tools/chkresolv -lresolv 2>tools/.chk 

assistant: ```c
int checkresolve() {
  int rc;
  unlink("tools/.chk");
  system("gcc tools/chkresolv.c -o tools/chkresolv -lresolv"
         " 2>tools/.chk ");
  return checkcmp();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<checkresolve>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <unlink@plt>
  lea    D18(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <checkcmp@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D0: tools/.chk

tool: D18: gcc tools/chkresolv.c -o tools/chkresolv -lresolv 2>tools/.chk 

assistant: ```c
int checkresolve() {
  int rc;
  unlink("tools/.chk");
  system("gcc tools/chkresolv.c -o tools/chkresolv -lresolv"
         " 2>tools/.chk ");
  return checkcmp();
}
```