user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  lea    D58(%rip),%r15
  push   %r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  movdqa D49(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r9
  lea    0x20(%rsp),%r14
  movl   $0x0,0x1c(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D3(%rip),%xmm0
  mov    %r9,%rsi
  mov    %r14,%rdi
  mov    %r9,0x8(%rsp)
  movaps %xmm0,0x30(%rsp)
  movdqa D35(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D14(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <get_2_tupples@plt>
  movdqa 0x20(%rsp),%xmm0
  paddd  0x30(%rsp),%xmm0
  lea    D41(%rip),%rdi
  paddd  0x40(%rsp),%xmm0
  paddd  0x50(%rsp),%xmm0
  mov    %rax,%rbp
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   %eax,%eax
  lea    0x3(%rax),%r12d
  cmovns %eax,%r12d
  sar    $0x2,%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <display_tupples@plt>
  mov    0x8(%rsp),%r9
L18:
  mov    0x1c(%rsp),%edx
  mov    %r13d,%ecx
  mov    %r12d,%r8d
  mov    %rbp,%rsi
  mov    %rbp,%rbx
  mov    %r14,%rdi
  mov    %r9,0x8(%rsp)
  call   <get_next_size_tupples@plt>
  mov    %rbx,%rdi
  lea    0x1(%r13),%ebx
  mov    $0x3,%r13d
  mov    %rax,%rbp
  call   <free@plt>
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <display_tupples@plt>
  cmp    $0x4,%ebx
  mov    0x8(%rsp),%r9
  jne    L18
  mov    0x1c(%rsp),%esi
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <get_all_solutions@plt>
  test   %rbp,%rbp
  je     L29
  mov    %rbp,%rdi
  call   <free@plt>
L29:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D58
data_type: string
name: read_data
arguments: tag: D49
data_type: byte[16]
name: read_data
arguments: tag: D3
data_type: byte[16]
name: read_data
arguments: tag: D35
data_type: byte[16]
name: read_data
arguments: tag: D14
data_type: byte[16]
name: read_data
arguments: tag: D41
data_type: string

tool: D58: Cardinality = %d


tool: {"D49": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D3": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D35": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D14": [0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: D41: Sum = %d


assistant: ```c
int main() {
  int seq[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  int tupple_array_size = 0;
  int cardinality = 2;
  int *tupples_n = get_2_tupples(seq, &tupple_array_size);
  int *tupples_nplus1 = NULL;
  int *final_tupples = NULL;
  int sum = 0;
  int final_cardinality = 4;
  int num_tupples_in_sol = 4;
  int seq_sz = sizeof(seq) / sizeof(seq[0]);
  for (int i = 0; i < seq_sz; i++) {
    sum += seq[i];
  }
  sum /= final_cardinality;
  printf("Sum = %d\n", sum);
  printf("Cardinality = %d\n", cardinality);
  display_tupples(tupples_n, tupple_array_size, cardinality);
  while (cardinality != final_cardinality) {
    tupples_nplus1 = get_next_size_tupples(seq, tupples_n, tupple_array_size, cardinality, sum, &tupple_array_size);
    free(tupples_n);
    tupples_n = tupples_nplus1;
    cardinality++;
    printf("Cardinality = %d\n", cardinality);
    display_tupples(tupples_n, tupple_array_size, cardinality);
  }
  get_all_solutions(tupples_nplus1, tupple_array_size, final_cardinality, num_tupples_in_sol);
  if (tupples_nplus1) {
    free(tupples_nplus1);
  }
}
```