ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1000,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    $0x1000,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %rax,%r12
  lea    0x4(%rbp),%rax
  sub    %rax,%rdx
  mov    %r12,%rcx
  cmp    $0x8,%rdx
  seta   %dl
  sub    %rax,%rcx
  cmp    $0x8,%rcx
  seta   %al
  test   %al,%dl
  je     L8
  lea    0x4(%r13),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    0x1000(%rbp),%rsi
  mov    %rbp,%rax
  movdqa D10(%rip),%xmm0
  sub    %rbp,%rcx
  sub    %rbp,%rdx
  pxor   %xmm2,%xmm2
  movdqa D11(%rip),%xmm3
  nopl   (%rax)
L57:
  movdqa %xmm0,%xmm1
  paddd  %xmm3,%xmm0
  movups %xmm1,(%rax)
  movups %xmm1,(%rcx,%rax,1)
  movups %xmm2,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L57
L59:
  mov    $0x400,%ecx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <VectorAdd@plt>
  mov    %r12,%r14
  xor    %ebx,%ebx
  lea    D13(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%r14),%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  add    $0x1,%ebx
  add    $0x4,%r14
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L27
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %r13,%rsi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  sub    %rbp,%rsi
  sub    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %eax,(%rdx)
  mov    %eax,(%rsi,%rdx,1)
  add    $0x1,%eax
  movl   $0x0,(%rcx,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x400,%eax
  jne    L45
  jmp    L59
```

tool_calls: name: read_data
arguments: data_label: D10
datatype: byte[16]
name: read_data
arguments: data_label: D11
datatype: byte[16]
name: read_data
arguments: data_label: D13
datatype: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D13: c[%d] = %d


assistant: ```c
int main() {
  int *a, *b, *c;
  a = (int *)malloc(1024 * sizeof(int));
  b = (int *)malloc(1024 * sizeof(int));
  c = (int *)malloc(1024 * sizeof(int));
  for (int i = 0; i < 1024; i++) {
    a[i] = i;
    b[i] = i;
    c[i] = 0;
  }
  VectorAdd(a, b, c, 1024);
  for (int i = 0; i < 10; i++) {
    printf("c[%d] = %d\n", i, c[i]);
  }
  free(a);
  free(b);
  free(c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<allocMatrixInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L19
L24:
  movl   $0x0,-0x20(%rbp)
  jmp    L31
L40:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  mov    $0x0,%eax
  jmp    L19
L49:
  movl   $0x0,-0x1c(%rbp)
  jmp    L66
L42:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L66:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L42
  addl   $0x1,-0x20(%rbp)
L31:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L40
  mov    -0x18(%rbp),%rax
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int **allocMatrixInt(int size) {
  int i = 0;
  int j = 0;
  int **m = NULL;
  m = calloc(size, sizeof(int *));
  if (m == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    m[i] = calloc(size, sizeof(int));
    if (m[i] == NULL)
      return NULL;
    for (j = 0; j < size; j++) {
      m[i][j] = 0;
    }
  }
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<allocMatrixInt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L11
  test   %r12d,%r12d
  jle    L11
  mov    %rax,%rbp
  mov    %r12d,%ebx
  lea    (%rax,%rbx,8),%r13
  shl    $0x2,%rbx
  jmp    L39
L56:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L11
L39:
  mov    $0x4,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rbp,%rcx
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L41
  mov    $0x0,%eax
L2:
  mov    (%rcx),%rdx
  movl   $0x0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rbx
  jne    L2
  jmp    L56
L41:
  mov    %rax,%r14
L11:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **allocMatrixInt(int size) {
  int i = 0;
  int j = 0;
  int **m = NULL;
  m = calloc(size, sizeof(int *));
  if (m == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    m[i] = calloc(size, sizeof(int));
    if (m[i] == NULL)
      return NULL;
    for (j = 0; j < size; j++) {
      m[i][j] = 0;
    }
  }
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocMatrixInt>:
  endbr64
  push   %r14
  mov    $0x8,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <calloc@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L41
  mov    %ebp,%r12d
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r13
  shl    $0x2,%r12
  jmp    L32
  nopl   0x0(%rax)
L30:
  mov    %r12,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r13,%rbx
  je     L41
L32:
  mov    %ebp,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L30
L6:
  xor    %r14d,%r14d
L41:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **allocMatrixInt(int size) {
  int i = 0;
  int j = 0;
  int **m = NULL;
  m = calloc(size, sizeof(int *));
  if (m == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    m[i] = calloc(size, sizeof(int));
    if (m[i] == NULL)
      return NULL;
    for (j = 0; j < size; j++) {
      m[i][j] = 0;
    }
  }
  return m;
}
```
user: What is the c source code of the assembly code below?

```asm
<allocMatrixInt>:
  endbr64
  push   %r14
  mov    $0x8,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <calloc@plt>
  test   %rax,%rax
  je     L26
  mov    %rax,%r14
  test   %ebp,%ebp
  jle    L20
  mov    %ebp,%r12d
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r13
  shl    $0x2,%r12
  jmp    L29
  nopl   0x0(%rax)
L15:
  mov    %r12,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r13,%rbx
  je     L20
L29:
  mov    %ebp,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L15
L26:
  xor    %r14d,%r14d
L20:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **allocMatrixInt(int size) {
  int i = 0;
  int j = 0;
  int **m = NULL;
  m = calloc(size, sizeof(int *));
  if (m == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    m[i] = calloc(size, sizeof(int));
    if (m[i] == NULL)
      return NULL;
    for (j = 0; j < size; j++) {
      m[i][j] = 0;
    }
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_fm_bishop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,0x4(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0xd,-0x4(%rbp)
  jle    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_fm_bishop(int fm[][2]) {
  int i;
  for (i = 0; i < 14; i++) {
    fm[i][0] = -1;
    fm[i][1] = -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_fm_bishop>:
  endbr64
  lea    0x70(%rdi),%rax
L5:
  movl   $0xffffffff,(%rdi)
  movl   $0xffffffff,0x4(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L5
  ret
```

assistant: ```c
void init_fm_bishop(int fm[][2]) {
  int i;
  for (i = 0; i < 14; i++) {
    fm[i][0] = -1;
    fm[i][1] = -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_fm_bishop>:
  endbr64
  lea    0x70(%rdi),%rax
  nopl   0x0(%rax,%rax,1)
L7:
  movl   $0xffffffff,(%rdi)
  add    $0x8,%rdi
  movl   $0xffffffff,-0x4(%rdi)
  cmp    %rax,%rdi
  jne    L7
  ret
```

assistant: ```c
void init_fm_bishop(int fm[][2]) {
  int i;
  for (i = 0; i < 14; i++) {
    fm[i][0] = -1;
    fm[i][1] = -1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_fm_bishop>:
  endbr64
  pcmpeqd %xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm0,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  ret
```

assistant: ```c
void init_fm_bishop(int fm[][2]) {
  int i;
  for (i = 0; i < 14; i++) {
    fm[i][0] = -1;
    fm[i][1] = -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_error_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x66,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit


assistant: ```c
void print_error_2() {
  printf("a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit\n");
  exit(102);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_error_2>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x66,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string

tool: D4: a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit


assistant: ```c
void print_error_2() {
  printf("a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit\n");
  exit(102);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_error_2>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x66,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit


assistant: ```c
void print_error_2() {
  printf("a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit\n");
  exit(102);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_error_2>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x66,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit


assistant: ```c
void print_error_2() {
  printf("a strange error occur, certainly due to the memory allocation in the spectrum initialisation --> exit\n");
  exit(102);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bn_add_words>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %ecx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  test   %r12d,%r12d
  jle    L8
  mov    (%rbx),%rax
  add    0x0(%rbp),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  mov    %rdx,0x0(%r13)
  cmp    $0x1,%r12d
  jle    L8
  add    0x8(%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    0x8(%rbp),%rdx
  adc    $0x0,%rax
  mov    %rdx,0x8(%r13)
  cmp    $0x2,%r12d
  jle    L8
  mov    %r12d,%esi
  and    $0x3,%esi
  lea    -0x4(%r12),%ecx
  lea    -0x1(%r12),%edx
  and    $0xfffffffc,%edx
  sub    %edx,%ecx
L30:
  add    0x10(%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    0x10(%rbp),%rdx
  adc    $0x0,%rax
  mov    %rdx,0x10(%r13)
  cmp    %r12d,%esi
  je     L8
  add    0x18(%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    0x18(%rbp),%rdx
  adc    $0x0,%rax
  mov    %rdx,0x18(%r13)
  sub    $0x4,%r12d
  cmp    %ecx,%r12d
  je     L8
  add    $0x20,%rbx
  add    $0x20,%rbp
  add    $0x20,%r13
  add    (%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    0x0(%rbp),%rdx
  adc    $0x0,%rax
  mov    %rdx,0x0(%r13)
  cmp    $0x1,%r12d
  jle    L8
  add    0x8(%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    0x8(%rbp),%rdx
  adc    $0x0,%rax
  mov    %rdx,0x8(%r13)
  cmp    $0x2,%r12d
  jg     L30
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_add_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long c, l, t;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  c = 0;
  for (;;) {
    t = a[0];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[0]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[0] = l;
    if (--n <= 0)
      break;
    t = a[1];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[1]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[1] = l;
    if (--n <= 0)
      break;
    t = a[2];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[2]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[2] = l;
    if (--n <= 0)
      break;
    t = a[3];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[3]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[3] = l;
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return ((unsigned long long)c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bn_add_words>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %ecx,%edi
  push   %r12
  not    %edi
  mov    %ecx,%r12d
  push   %rbp
  shr    $0x1f,%edi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %eax,%eax
  test   %r12d,%r12d
  jle    L2
  mov    0x0(%rbp),%rax
  add    (%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  mov    %rdx,0x0(%r13)
  movzbl %al,%eax
  cmp    $0x1,%r12d
  jne    L21
  jmp    L2
L25:
  xor    %ecx,%ecx
  add    0x10(%rbx),%rax
  setb   %cl
  add    0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x10(%r13)
  adc    $0x0,%rax
  cmp    $0x3,%r12d
  je     L2
  xor    %ecx,%ecx
  add    0x18(%rbx),%rax
  setb   %cl
  add    0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x18(%r13)
  adc    $0x0,%rax
  sub    $0x4,%r12d
  je     L2
  add    $0x20,%rbx
  add    $0x20,%rbp
  add    $0x20,%r13
  xor    %ecx,%ecx
  add    (%rbx),%rax
  setb   %cl
  add    0x0(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x0(%r13)
  adc    $0x0,%rax
  cmp    $0x1,%r12d
  je     L2
L21:
  xor    %ecx,%ecx
  add    0x8(%rbx),%rax
  setb   %cl
  add    0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x8(%r13)
  adc    $0x0,%rax
  cmp    $0x2,%r12d
  jne    L25
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_add_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long c, l, t;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  c = 0;
  for (;;) {
    t = a[0];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[0]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[0] = l;
    if (--n <= 0)
      break;
    t = a[1];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[1]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[1] = l;
    if (--n <= 0)
      break;
    t = a[2];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[2]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[2] = l;
    if (--n <= 0)
      break;
    t = a[3];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[3]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[3] = l;
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return ((unsigned long long)c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bn_add_words>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %ecx,%edi
  push   %r12
  not    %edi
  mov    %ecx,%r12d
  push   %rbp
  shr    $0x1f,%edi
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %eax,%eax
  test   %r12d,%r12d
  jle    L19
  mov    0x0(%rbp),%rax
  add    (%rbx),%rax
  mov    %rax,%rdx
  setb   %al
  mov    %rdx,0x0(%r13)
  movzbl %al,%eax
  cmp    $0x1,%r12d
  jne    L55
  jmp    L19
L0:
  xor    %ecx,%ecx
  add    0x10(%rbx),%rax
  setb   %cl
  add    0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x10(%r13)
  adc    $0x0,%rax
  cmp    $0x3,%r12d
  je     L19
  xor    %ecx,%ecx
  add    0x18(%rbx),%rax
  setb   %cl
  add    0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x18(%r13)
  adc    $0x0,%rax
  sub    $0x4,%r12d
  je     L19
  add    $0x20,%rbx
  add    $0x20,%rbp
  add    $0x20,%r13
  xor    %ecx,%ecx
  add    (%rbx),%rax
  setb   %cl
  add    0x0(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x0(%r13)
  adc    $0x0,%rax
  cmp    $0x1,%r12d
  je     L19
L55:
  xor    %ecx,%ecx
  add    0x8(%rbx),%rax
  setb   %cl
  add    0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  mov    %rdx,0x8(%r13)
  adc    $0x0,%rax
  cmp    $0x2,%r12d
  jne    L0
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned long long bn_add_words(unsigned long long *r, unsigned long long *a, unsigned long long *b, int n) {
  unsigned long long c, l, t;
  assert(n >= 0);
  if (n <= 0)
    return ((unsigned long long)0);
  c = 0;
  for (;;) {
    t = a[0];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[0]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[0] = l;
    if (--n <= 0)
      break;
    t = a[1];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[1]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[1] = l;
    if (--n <= 0)
      break;
    t = a[2];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[2]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[2] = l;
    if (--n <= 0)
      break;
    t = a[3];
    t = (t + c) & (0xffffffffffffffffLL);
    c = (t < c);
    l = (t + b[3]) & (0xffffffffffffffffLL);
    c += (l < t);
    r[3] = l;
    if (--n <= 0)
      break;
    a += 4;
    b += 4;
    r += 4;
  }
  return ((unsigned long long)c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x2a,-0x18(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x10,-0x19(%rbp)
  mov    $0x2,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%eax
  add    $0xd,%eax
  lea    (%rax,%rax,1),%edx
  movsbl -0x19(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D45
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D37: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c

tool: D3: __LINE__

tool: D4: max=%d


tool: D45: main

tool: D1: %d


assistant: ```c
int main(void) {
  int a = 42, b;
  char *c = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c", *d = "__LINE__", e = 16;
  printf("max=%d\n", ((((2) > (-1) ? (2) : (-1))) > (1) ? (((2) > (-1) ? (2) : (-1))) : (1)));
  puts(c);
  puts(d);
  puts("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c");
  puts(__func__);
  b = 26 + (1 + a * 2 - 1) + e;
  return printf("%d\n", b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D21(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x7e,%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D29
type_guessed: string
name: parse_data
arguments: data_label: D21
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D24
type_guessed: string
name: parse_data
arguments: data_label: D31
type_guessed: string

tool: D29: max=%d


tool: D21: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c

tool: D12: __LINE__

tool: D24: main

tool: D31: %d


assistant: ```c
int main(void) {
  int a = 42, b;
  char *c = "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c", *d = "__LINE__", e = 16;
  printf("max=%d\n", ((((2) > (-1) ? (2) : (-1))) > (1) ? (((2) > (-1) ? (2) : (-1))) : (1)));
  puts(c);
  puts(d);
  puts("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/larmel/c-compiler/refs/heads/master/test/c89/macro.c");
  puts(__func__);
  b = 26 + (1 + a * 2 - 1) + e;
  return printf("%d\n", b);
}
```