user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x110(%rbp)
  movl   $0x1,-0x10c(%rbp)
  movl   $0x2,-0x108(%rbp)
  movl   $0x21,-0x104(%rbp)
  movl   $0x2d,-0x100(%rbp)
  movl   $0x28e,-0xfc(%rbp)
  movl   $0x89b165,-0xf8(%rbp)
  movl   $0xffffffff,-0xf4(%rbp)
  movl   $0xfff1cbf8,-0xf0(%rbp)
  movl   $0xfffffff8,-0xec(%rbp)
  movl   $0xffffffb3,-0xe8(%rbp)
  movl   $0xffffffa9,-0xe4(%rbp)
  lea    D61(%rip),%rax
  mov    %rax,-0xe0(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0xd8(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,-0xd0(%rbp)
  lea    D55(%rip),%rax
  mov    %rax,-0xc8(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0xc0(%rbp)
  lea    D119(%rip),%rax
  mov    %rax,-0xb8(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,-0xb0(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,-0xa8(%rbp)
  lea    D99(%rip),%rax
  mov    %rax,-0xa0(%rbp)
  lea    D89(%rip),%rax
  mov    %rax,-0x98(%rbp)
  lea    D82(%rip),%rax
  mov    %rax,-0x90(%rbp)
  lea    D58(%rip),%rax
  mov    %rax,-0x88(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x114(%rbp)
  jmp    L4
L15:
  mov    -0x114(%rbp),%eax
  cltq
  movb   $0x2e,-0x7d(%rbp,%rax,1)
  mov    -0x114(%rbp),%eax
  cltq
  mov    -0x110(%rbp,%rax,4),%eax
  lea    -0x70(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <my_atoi@plt>
  mov    -0x114(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,8),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L25
  mov    -0x114(%rbp),%eax
  cltq
  movb   $0x21,-0x7d(%rbp,%rax,1)
  mov    -0x114(%rbp),%eax
  cltq
  mov    -0xe0(%rbp,%rax,8),%rax
  lea    -0x70(%rbp),%rdx
  mov    %rax,%rsi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L25:
  addl   $0x1,-0x114(%rbp)
L4:
  cmpl   $0xb,-0x114(%rbp)
  jle    L15
  lea    -0x7d(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D61
type_infered: string
name: extract_symbolic_data
arguments: tag: D27
type_infered: string
name: extract_symbolic_data
arguments: tag: D67
type_infered: string
name: extract_symbolic_data
arguments: tag: D55
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D119
type_infered: string
name: extract_symbolic_data
arguments: tag: D41
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D99
type_infered: string
name: extract_symbolic_data
arguments: tag: D89
type_infered: string
name: extract_symbolic_data
arguments: tag: D82
type_infered: string
name: extract_symbolic_data
arguments: tag: D58
type_infered: string
name: extract_symbolic_data
arguments: tag: D80
type_infered: string

tool: D61: 0

tool: D27: 1

tool: D67: 2

tool: D55: 33

tool: D15: 45

tool: D119: 654

tool: D41: 9023845

tool: D34: -1

tool: D99: -930824

tool: D89: -8

tool: D82: -77

tool: D58: -87

tool: D80: expected: %s , actual %s


assistant: ```c
int main(void) {
  int test_ints[12] = {0, 1, 2, 33, 45, 654, 9023845, -1, -930824, -8, -77, -87};
  char *expected[12] = {"0", "1", "2", "33", "45", "654", "9023845", "-1", "-930824", "-8", "-77", "-87"};
  char test_status[12 + 1];
  printf("\n");
  for (int i = 0; i < 12; i++) {
    test_status[i] = '.';
    char buf[100];
    my_atoi(test_ints[i], buf);
    if (strcmp(buf, expected[i])) {
      test_status[i] = '!';
      printf("expected: %s , actual %s\n", expected[i], buf);
      printf("\n");
    }
  }
  printf("%s\n", test_status);
  return 0;
}
```