ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  cmp    $0x1,%edi
  jg     L35
  jmp    L6
  xchg   %ax,%ax
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fibo@plt>
  mov    $0xa,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L35:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jge    L8
L19:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string

tool: D4: %d%c

tool: D10: usage: ./fibo [NUMBER]

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("usage: ./fibo [NUMBER]");
    return 0;
  }
  for (int i = 1; i <= atoi(argv[1]); i++)
    printf("%d%c", fibo(i), 10);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  cmp    $0x1,%edi
  jg     L4
  jmp    L22
  xchg   %ax,%ax
L18:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fibo@plt>
  mov    $0xa,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <printf@plt>
L4:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  cmp    %ebx,%eax
  jge    L18
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L22:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D5: %d%c

tool: D8: usage: ./fibo [NUMBER]

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("usage: ./fibo [NUMBER]");
    return 0;
  }
  for (int i = 1; i <= atoi(argv[1]); i++)
    printf("%d%c", fibo(i), 10);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_118_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_118_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_118_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  or     (%rdi),%sil
  xor    %eax,%esi
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_118_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_118_1_0>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  mov    %edx,%esi
  not    %ecx
  and    %ecx,%esi
  or     (%rdi),%sil
  xor    %eax,%esi
  and    (%rdi),%al
  and    %ecx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_118_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rop3_118_1_0>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  mov    %edx,%esi
  not    %ecx
  and    %ecx,%esi
  or     (%rdi),%sil
  xor    %eax,%esi
  and    (%rdi),%al
  and    %ecx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_118_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L29
L9:
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L16
L34:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L34
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D20
type: string

tool: D13: %d%d

tool: D24: 1*%d=%d

tool: D20:   %d*%d=%d

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  for (int i = a; i <= b; i++) {
    printf("1*%d=%d", i, i);
    for (int k = 2; k <= i; k++)
      printf("  %d*%d=%d", k, i, k * i);
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r12d
  cmp    0x4(%rsp),%r12d
  jg     L36
  lea    D18(%rip),%r15
  lea    D5(%rip),%r14
L0:
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%r12d
  jle    L25
  mov    %r12d,%r13d
  lea    (%r12,%r12,1),%ebp
  mov    $0x2,%ebx
L27:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13d,%ebp
  cmp    %r12d,%ebx
  jle    L27
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jge    L0
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D15: %d%d

tool: D18: 1*%d=%d

tool: D5:   %d*%d=%d

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  for (int i = a; i <= b; i++) {
    printf("1*%d=%d", i, i);
    for (int k = 2; k <= i; k++)
      printf("  %d*%d=%d", k, i, k * i);
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    0x4(%rsp),%ebp
  jg     L33
  lea    D1(%rip),%r14
  lea    D17(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L14
  lea    0x0(%rbp,%rbp,1),%r12d
  mov    $0x2,%ebx
  nopl   (%rax)
L48:
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L48
L14:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L32
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D1
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D5: %d%d

tool: D1: 1*%d=%d

tool: D17:   %d*%d=%d

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  for (int i = a; i <= b; i++) {
    printf("1*%d=%d", i, i);
    for (int k = 2; k <= i; k++)
      printf("  %d*%d=%d", k, i, k * i);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    0x4(%rsp),%ebp
  jg     L40
  lea    D19(%rip),%r14
  lea    D10(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L15
  lea    0x0(%rbp,%rbp,1),%r12d
  mov    $0x2,%ebx
  nopl   (%rax)
L14:
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L14
L15:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jge    L39
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D28
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D28: %d%d

tool: D19: 1*%d=%d

tool: D10:   %d*%d=%d

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  for (int i = a; i <= b; i++) {
    printf("1*%d=%d", i, i);
    for (int k = 2; k <= i; k++)
      printf("  %d*%d=%d", k, i, k * i);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<local_pid_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  je     L19
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
L19:
  mov    $0x0,%eax
  jmp    L39
L45:
  movabs $0x69702f78796e2e2f,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x64,-0xa(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    $0xb,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <xcalloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rsi
  lea    -0x12(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  test   %rax,%rax
  jns    L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L39
L22:
  mov    -0x20(%rbp),%rax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: %s%s

assistant: ```c
const char *local_pid_dir(const char *local_dir) {
  if (local_dir == NULL || *local_dir == '\0')
    return NULL;
  const char pid_dir[] = "/.nyx/pid";
  size_t len = strlen(local_dir) + (sizeof(pid_dir) / sizeof(pid_dir[0])) + 1;
  char *buffer = xcalloc(len, sizeof(char));
  if (snprintf(buffer, len - 1, "%s%s", local_dir, pid_dir) < 0) {
    free(buffer);
    return NULL;
  }
  return buffer;
}
```
user: What is the c source code of the assembly code below:

```asm
<local_pid_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L30
  mov    $0x0,%ebp
  cmpb   $0x0,(%rdi)
  je     L22
  movabs $0x69702f78796e2e2f,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x64,0x16(%rsp)
  call   <strlen@plt>
  movslq %eax,%r12
  lea    0xb(%r12),%rdi
  mov    $0x1,%esi
  call   <xcalloc@plt>
  mov    %rax,%rbp
  lea    0xa(%r12),%rsi
  lea    0xe(%rsp),%r8
  mov    %rbx,%rcx
  lea    D5(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  test   %rax,%rax
  js     L38
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbp,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L22
L30:
  mov    %rdi,%rbp
  jmp    L22
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: %s%s

assistant: ```c
const char *local_pid_dir(const char *local_dir) {
  if (local_dir == NULL || *local_dir == '\0')
    return NULL;
  const char pid_dir[] = "/.nyx/pid";
  size_t len = strlen(local_dir) + (sizeof(pid_dir) / sizeof(pid_dir[0])) + 1;
  char *buffer = xcalloc(len, sizeof(char));
  if (snprintf(buffer, len - 1, "%s%s", local_dir, pid_dir) < 0) {
    free(buffer);
    return NULL;
  }
  return buffer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<local_pid_dir>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L52
  xor    %r13d,%r13d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  je     L9
  movabs $0x69702f78796e2e2f,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x64,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    $0x1,%esi
  movslq %eax,%rbx
  lea    0xb(%rbx),%rdi
  call   <xcalloc@plt>
  lea    0xa(%rbx),%rsi
  mov    %r12,%rcx
  lea    0xe(%rsp),%r8
  lea    D1(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  test   %rax,%rax
  js     L3
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L52:
  xor    %r13d,%r13d
  jmp    L9
  nopl   (%rax)
L3:
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <free@plt>
  jmp    L9
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s%s

assistant: ```c
const char *local_pid_dir(const char *local_dir) {
  if (local_dir == NULL || *local_dir == '\0')
    return NULL;
  const char pid_dir[] = "/.nyx/pid";
  size_t len = strlen(local_dir) + (sizeof(pid_dir) / sizeof(pid_dir[0])) + 1;
  char *buffer = xcalloc(len, sizeof(char));
  if (snprintf(buffer, len - 1, "%s%s", local_dir, pid_dir) < 0) {
    free(buffer);
    return NULL;
  }
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<local_pid_dir>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  xor    %r13d,%r13d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  je     L7
  movabs $0x69702f78796e2e2f,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x64,%eax
  mov    %ax,0x16(%rsp)
  call   <strlen@plt>
  mov    $0x1,%esi
  movslq %eax,%rbx
  lea    0xb(%rbx),%rdi
  call   <xcalloc@plt>
  lea    0xa(%rbx),%rsi
  mov    %r12,%rcx
  lea    0xe(%rsp),%r8
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <snprintf@plt>
  test   %rax,%rax
  js     L0
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L40:
  xor    %r13d,%r13d
  jmp    L7
  nopl   (%rax)
L0:
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <free@plt>
  jmp    L7
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %s%s

assistant: ```c
const char *local_pid_dir(const char *local_dir) {
  if (local_dir == NULL || *local_dir == '\0')
    return NULL;
  const char pid_dir[] = "/.nyx/pid";
  size_t len = strlen(local_dir) + (sizeof(pid_dir) / sizeof(pid_dir[0])) + 1;
  char *buffer = xcalloc(len, sizeof(char));
  if (snprintf(buffer, len - 1, "%s%s", local_dir, pid_dir) < 0) {
    free(buffer);
    return NULL;
  }
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L18
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <f>
  add    $0x2,%eax
  jmp    L4
L18:
  mov    $0x70,%eax
L4:
  leave
  ret
```

assistant: ```c
int f(int x) {
  if (x > 0)
    return 2 + f(x - 1);
  return 112;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x70,%eax
  test   %edi,%edi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <f>
  add    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f(int x) {
  if (x > 0)
    return 2 + f(x - 1);
  return 112;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  lea    0x70(%rdi,%rdi,1),%eax
  test   %edi,%edi
  mov    $0x70,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int f(int x) {
  if (x > 0)
    return 2 + f(x - 1);
  return 112;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  lea    0x70(%rdi,%rdi,1),%eax
  test   %edi,%edi
  mov    $0x70,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int f(int x) {
  if (x > 0)
    return 2 + f(x - 1);
  return 112;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x9,-0xc(%rbp)
  jg     L37
  mov    -0xc(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  jmp    L32
L37:
  mov    -0xc(%rbp),%eax
  add    $0x37,%eax
  mov    %eax,%ecx
L32:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %cl,(%rax)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L31
  cmpl   $0x0,-0x10(%rbp)
  jns    L4
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itob(int n, char *s, int b) {
  char *sindex = s;
  int sign = n;
  do {
    int d = abs(n % b);
    *sindex++ = (d <= 9) ? (char)d + '0' : (char)d + 'A' - 10;
  } while ((n /= b) != 0);
  if (sign < 0)
    *sindex++ = '-';
  *sindex = '\0';
  reverse(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itob>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r9d
  mov    %rsi,%r10
  mov    %edx,%esi
  mov    %r10,%r8
  mov    %edi,%ecx
  jmp    L2
L30:
  mov    %rdi,%r8
L2:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  neg    %eax
  cmovns %eax,%edx
  lea    0x30(%rdx),%edi
  lea    0x37(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %edi,%eax
  lea    0x1(%r8),%rdi
  mov    %al,-0x1(%rdi)
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L30
  test   %r9d,%r9d
  js     L36
L14:
  movb   $0x0,(%rdi)
  mov    %r10,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  ret
L36:
  movb   $0x2d,(%rdi)
  lea    0x2(%r8),%rdi
  jmp    L14
```

assistant: ```c
void itob(int n, char *s, int b) {
  char *sindex = s;
  int sign = n;
  do {
    int d = abs(n % b);
    *sindex++ = (d <= 9) ? (char)d + '0' : (char)d + 'A' - 10;
  } while ((n /= b) != 0);
  if (sign < 0)
    *sindex++ = '-';
  *sindex = '\0';
  reverse(s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itob>:
  endbr64
  mov    %edi,%r8d
  mov    %rsi,%r9
  mov    %edx,%esi
  mov    %r9,%rdi
  mov    %r8d,%eax
  jmp    L29
  nopl   0x0(%rax)
L9:
  mov    %rcx,%rdi
L29:
  cltd
  idiv   %esi
  mov    %edx,%ecx
  neg    %ecx
  cmovns %ecx,%edx
  lea    0x30(%rdx),%r10d
  lea    0x37(%rdx),%ecx
  cmp    $0x9,%edx
  mov    %r10d,%edx
  cmovg  %ecx,%edx
  lea    0x1(%rdi),%rcx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  jne    L9
  test   %r8d,%r8d
  jns    L3
  movb   $0x2d,(%rcx)
  lea    0x2(%rdi),%rcx
L3:
  movb   $0x0,(%rcx)
  mov    %r9,%rdi
  jmp    1050 <reverse@plt>
```

assistant: ```c
void itob(int n, char *s, int b) {
  char *sindex = s;
  int sign = n;
  do {
    int d = abs(n % b);
    *sindex++ = (d <= 9) ? (char)d + '0' : (char)d + 'A' - 10;
  } while ((n /= b) != 0);
  if (sign < 0)
    *sindex++ = '-';
  *sindex = '\0';
  reverse(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itob>:
  endbr64
  mov    %edi,%r10d
  mov    %edx,%r8d
  mov    %rsi,%rdi
  mov    %rsi,%r9
  mov    %r10d,%eax
  jmp    L22
  nopl   (%rax)
L8:
  add    $0x30,%edx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  je     L25
L9:
  mov    %rcx,%r9
L22:
  cltd
  idiv   %r8d
  mov    %edx,%ecx
  neg    %ecx
  cmovns %ecx,%edx
  lea    0x1(%r9),%rcx
  cmp    $0x9,%edx
  jle    L8
  add    $0x37,%edx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  jne    L9
L25:
  test   %r10d,%r10d
  jns    L46
  movb   $0x2d,(%rcx)
  lea    0x2(%r9),%rcx
L46:
  movb   $0x0,(%rcx)
  jmp    1050 <reverse@plt>
```

assistant: ```c
void itob(int n, char *s, int b) {
  char *sindex = s;
  int sign = n;
  do {
    int d = abs(n % b);
    *sindex++ = (d <= 9) ? (char)d + '0' : (char)d + 'A' - 10;
  } while ((n /= b) != 0);
  if (sign < 0)
    *sindex++ = '-';
  *sindex = '\0';
  reverse(s);
}
```