ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<search>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  sub    $0x1,%r15d
  js     L16
  mov    %rdi,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  xor    %ebp,%ebp
  jmp    L33
  nopl   (%rax)
L50:
  je     L7
  lea    -0x1(%r14),%r15d
  cmp    %ebp,%r15d
  jl     L16
L33:
  lea    0x0(%rbp,%r15,1),%r14d
  mov    %r12,%rsi
  sar    %r14d
  movslq %r14d,%rdi
  imul   0x8(%rsp),%rdi
  add    %rbx,%rdi
  call   *%r13
  test   %eax,%eax
  jns    L50
  lea    0x1(%r14),%ebp
  cmp    %ebp,%r15d
  jge    L33
L16:
  mov    $0xffffffff,%r14d
L7:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int search(void *array, size_t element_size, size_t array_size, void *element, int (*compare)(const void *v1, const void *v2)) {
  int l = 0;
  int r = array_size - 1;
  int m;
  while (l <= r) {
    m = (r + l) / 2;
    int c = compare(array + m * element_size, element);
    if (c < 0)
      l = m + 1;
    else if (c > 0)
      r = m - 1;
    else
      return m;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  sub    $0x1,%r15d
  js     L53
  mov    %rdi,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  xor    %ebp,%ebp
  jmp    L14
  nopl   (%rax)
L37:
  je     L51
  lea    -0x1(%r14),%r15d
  cmp    %ebp,%r15d
  jl     L53
L14:
  lea    0x0(%rbp,%r15,1),%r14d
  mov    %r12,%rsi
  sar    %r14d
  movslq %r14d,%rdi
  imul   0x8(%rsp),%rdi
  add    %rbx,%rdi
  call   *%r13
  test   %eax,%eax
  jns    L37
  lea    0x1(%r14),%ebp
  cmp    %ebp,%r15d
  jge    L14
L53:
  mov    $0xffffffff,%r14d
L51:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int search(void *array, size_t element_size, size_t array_size, void *element, int (*compare)(const void *v1, const void *v2)) {
  int l = 0;
  int r = array_size - 1;
  int m;
  while (l <= r) {
    m = (r + l) / 2;
    int c = compare(array + m * element_size, element);
    if (c < 0)
      l = m + 1;
    else if (c > 0)
      r = m - 1;
    else
      return m;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L1
  movq   $0x0,-0x20(%rbp)
  jmp    L18
L43:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L18:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L43
  jmp    L11
L1:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L11
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L53
L32:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x18(%rbp)
L53:
  cmpq   $0x0,-0x18(%rbp)
  jne    L32
L11:
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *destination_pointer, const void *source_pointer, size_t n) {
  char *destination = (char *)destination_pointer;
  char *source = (char *)source_pointer;
  if (source > destination) {
    for (size_t i = 0; i < n; i++) {
      destination[i] = source[i];
    }
  } else if (destination > source) {
    for (size_t i = n; i > 0; i--) {
      destination[i - 1] = source[i - 1];
    }
  }
  return destination_pointer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jae    L35
  test   %rdx,%rdx
  je     L45
  mov    $0x0,%ecx
L9:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L9
  ret
L35:
  jbe    L45
  test   %rdx,%rdx
  je     L45
L38:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L38
L45:
  ret
```

assistant: ```c
void *memmove(void *destination_pointer, const void *source_pointer, size_t n) {
  char *destination = (char *)destination_pointer;
  char *source = (char *)source_pointer;
  if (source > destination) {
    for (size_t i = 0; i < n; i++) {
      destination[i] = source[i];
    }
  } else if (destination > source) {
    for (size_t i = n; i > 0; i--) {
      destination[i - 1] = source[i - 1];
    }
  }
  return destination_pointer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jae    L43
  test   %rdx,%rdx
  je     L48
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L33:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L33
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  ja     L27
L48:
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  test   %rdx,%rdx
  je     L48
  nopl   (%rax)
L10:
  sub    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  jne    L10
  ret
```

assistant: ```c
void *memmove(void *destination_pointer, const void *source_pointer, size_t n) {
  char *destination = (char *)destination_pointer;
  char *source = (char *)source_pointer;
  if (source > destination) {
    for (size_t i = 0; i < n; i++) {
      destination[i] = source[i];
    }
  } else if (destination > source) {
    for (size_t i = n; i > 0; i--) {
      destination[i - 1] = source[i - 1];
    }
  }
  return destination_pointer;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memmove>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rax
  cmp    %rsi,%rdi
  jae    L198
  test   %rdx,%rdx
  je     L184
  lea    0x1(%rsi),%rdi
  mov    %r8,%rcx
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L96
  cmp    $0x6,%rdx
  jbe    L96
  mov    %rax,%rcx
  cmp    $0xe,%rdx
  jbe    L72
  and    $0xfffffffffffffff0,%rcx
  xor    %edx,%edx
  nopl   0x0(%rax)
L178:
  movdqu (%rsi,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jne    L178
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  test   $0xf,%al
  je     L184
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    -0x1(%rcx),%rdi
  cmp    $0x6,%rdi
  jbe    L191
L201:
  mov    (%rsi,%rdx,1),%rdi
  mov    %rdi,(%r8,%rdx,1)
  mov    %rcx,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rdx
  cmp    %rdi,%rcx
  je     L184
L191:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x1(%rsi,%rdx,1),%ecx
  mov    %cl,0x1(%r8,%rdx,1)
  lea    0x2(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x2(%rsi,%rdx,1),%ecx
  mov    %cl,0x2(%r8,%rdx,1)
  lea    0x3(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x3(%rsi,%rdx,1),%ecx
  mov    %cl,0x3(%r8,%rdx,1)
  lea    0x4(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x4(%rsi,%rdx,1),%ecx
  mov    %cl,0x4(%r8,%rdx,1)
  lea    0x5(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x5(%rsi,%rdx,1),%ecx
  mov    %cl,0x5(%r8,%rdx,1)
  lea    0x6(%rdx),%rcx
  cmp    %rcx,%rax
  jbe    L184
  movzbl 0x6(%rsi,%rdx,1),%eax
  mov    %al,0x6(%r8,%rdx,1)
L184:
  mov    %r8,%rax
  ret
  nop
L198:
  jbe    L184
  test   %rdx,%rdx
  je     L184
  nopw   0x0(%rax,%rax,1)
L41:
  sub    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  jne    L41
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L7
  jmp    L184
L72:
  xor    %edx,%edx
  jmp    L201
```

assistant: ```c
void *memmove(void *destination_pointer, const void *source_pointer, size_t n) {
  char *destination = (char *)destination_pointer;
  char *source = (char *)source_pointer;
  if (source > destination) {
    for (size_t i = 0; i < n; i++) {
      destination[i] = source[i];
    }
  } else if (destination > source) {
    for (size_t i = n; i > 0; i--) {
      destination[i - 1] = source[i - 1];
    }
  }
  return destination_pointer;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<send_cmd_i2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <send_cmd@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void send_cmd_i2(int cmd_code, int arg1, int arg2) {
  int ibuf[2];
  ibuf[0] = arg1;
  ibuf[1] = arg2;
  send_cmd(cmd_code, (char *)ibuf, 2 * sizeof(int));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<send_cmd_i2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <send_cmd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_cmd_i2(int cmd_code, int arg1, int arg2) {
  int ibuf[2];
  ibuf[0] = arg1;
  ibuf[1] = arg2;
  send_cmd(cmd_code, (char *)ibuf, 2 * sizeof(int));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<send_cmd_i2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %rsp,%rsi
  mov    %edx,0x4(%rsp)
  mov    $0x8,%edx
  call   <send_cmd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_cmd_i2(int cmd_code, int arg1, int arg2) {
  int ibuf[2];
  ibuf[0] = arg1;
  ibuf[1] = arg2;
  send_cmd(cmd_code, (char *)ibuf, 2 * sizeof(int));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_cmd_i2>:
  endbr64
  sub    $0x18,%rsp
  movd   %esi,%xmm0
  movd   %edx,%xmm1
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rsi
  movq   %xmm0,(%rsp)
  call   <send_cmd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void send_cmd_i2(int cmd_code, int arg1, int arg2) {
  int ibuf[2];
  ibuf[0] = arg1;
  ibuf[1] = arg2;
  send_cmd(cmd_code, (char *)ibuf, 2 * sizeof(int));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__arch_copy_to_user>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *to, void *from, unsigned long n) {
  unsigned long a;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__arch_copy_to_user>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *to, void *from, unsigned long n) {
  unsigned long a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__arch_copy_to_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *to, void *from, unsigned long n) {
  unsigned long a;
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<__arch_copy_to_user>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long __arch_copy_to_user(void *to, void *from, unsigned long n) {
  unsigned long a;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L52
  mov    $0x1,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L52:
  movl   $0x0,-0x14(%rbp)
  jmp    L63
L57:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L63:
  cmpl   $0x0,-0x14(%rbp)
  jle    L57
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0xbb,%al
  jne    L47
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L47:
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L11:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x0,-0x10(%rbp)
  jle    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D17
data_type: string

tool: D12: Call this program with %i arguments


tool: D15: You win!

tool: D17: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 187) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L22
L19:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %al,0x6(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpb   $0xbb,0x7(%rsp)
  je     L47
L18:
  movzbl 0x7(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L19
L47:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D9
type: string
name: parse_data
arguments: data_label: D20
type: string

tool: D26: %u


tool: D9: Call this program with %i arguments


tool: D20: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 187) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L29
  lea    D26(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0xbb,%sil
  je     L10
L37:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L37
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string

tool: D26: Call this program with %i arguments


tool: D4: %u


tool: D14: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 187) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L28
  lea    D27(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L28:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0xbb,%sil
  je     L37
L17:
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L17
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D27: Call this program with %i arguments


tool: D29: %u


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 187) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<openbsd_reallocarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0xffffffff,%eax
  cmp    %rax,-0x10(%rbp)
  ja     L31
  mov    $0xffffffff,%eax
  cmp    %rax,-0x18(%rbp)
  jbe    L41
L31:
  cmpq   $0x0,-0x10(%rbp)
  je     L41
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  divq   -0x10(%rbp)
  cmp    %rax,-0x18(%rbp)
  jbe    L41
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D29(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L6
L41:
  cmpq   $0x0,-0x18(%rbp)
  je     L54
  cmpq   $0x0,-0x10(%rbp)
  jne    L51
L54:
  mov    $0x0,%eax
  jmp    L6
L51:
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L6:
  leave
  ret
```

assistant: ```c
void *openbsd_reallocarray(void *optr, size_t nmemb, size_t size) {
  if ((nmemb >= ((size_t)1 << (sizeof(size_t) * 4)) || size >= ((size_t)1 << (sizeof(size_t) * 4))) && nmemb > 0 && UINTPTR_MAX / nmemb < size) {
    errno = ENOMEM;
    return NULL;
  }
  if (size == 0 || nmemb == 0)
    return NULL;
  return realloc(optr, size * nmemb);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<openbsd_reallocarray>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rax
  or     %rdx,%rax
  shr    $0x20,%rax
  je     L16
  test   %rsi,%rsi
  jne    L11
L16:
  test   %rcx,%rcx
  je     L44
  test   %rsi,%rsi
  je     L44
  sub    $0x8,%rsp
  imul   %rcx,%rsi
  call   <realloc@plt>
  add    $0x8,%rsp
  ret
L11:
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  div    %rsi
  cmp    %rcx,%rax
  jae    L16
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
L44:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *openbsd_reallocarray(void *optr, size_t nmemb, size_t size) {
  if ((nmemb >= ((size_t)1 << (sizeof(size_t) * 4)) || size >= ((size_t)1 << (sizeof(size_t) * 4))) && nmemb > 0 && UINTPTR_MAX / nmemb < size) {
    errno = ENOMEM;
    return NULL;
  }
  if (size == 0 || nmemb == 0)
    return NULL;
  return realloc(optr, size * nmemb);
}
```