ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<length_slow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  addq   $0x1,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int length_slow(char *string) {
  int i;
  for (i = 0; '\0' != *string; ++i) {
    ++string;
    usleep(i * i);
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<length_slow>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L10
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L5:
  add    $0x1,%rbp
  mov    %ebx,%edi
  imul   %ebx,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmpb   $0x0,0x0(%rbp)
  jne    L5
L17:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%ebx
  jmp    L17
```

assistant: ```c
int length_slow(char *string) {
  int i;
  for (i = 0; '\0' != *string; ++i) {
    ++string;
    usleep(i * i);
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<length_slow>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L12
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r12d,%edi
  add    $0x1,%rbx
  imul   %r12d,%edi
  add    $0x1,%r12d
  call   <usleep@plt>
  cmpb   $0x0,(%rbx)
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int length_slow(char *string) {
  int i;
  for (i = 0; '\0' != *string; ++i) {
    ++string;
    usleep(i * i);
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<length_slow>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L13
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r12d,%edi
  add    $0x1,%rbx
  imul   %r12d,%edi
  add    $0x1,%r12d
  call   <usleep@plt>
  cmpb   $0x0,(%rbx)
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L13:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int length_slow(char *string) {
  int i;
  for (i = 0; '\0' != *string; ++i) {
    ++string;
    usleep(i * i);
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x41,%edx
  mov    $0x61,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9eb10,%edx
  mov    $0x7b9,%esi
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D17(%rip),%xmm1
  movsd  D17(%rip),%xmm0
  mov    D17(%rip),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D28
datatype: string
name: read_data
arguments: tag: D92
datatype: string
name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D6
datatype: string
name: read_data
arguments: tag: D73
datatype: string
name: read_data
arguments: tag: D17
datatype: f64
name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D67
datatype: string
name: read_data
arguments: tag: D42
datatype: string

tool: D28: Characters: %c %c 


tool: D92: Decimals: %d %1d


tool: D0: Preceding with blanks: %10d 


tool: D6: Preceding with zeros: %010d 


tool: D73: Some difference radices: %d %x %o %#x %#o 


tool: D17: 3.1416

tool: D13: floats: %4.2f %+.0e %E 


tool: D67: A string

tool: D42: %s 


assistant: ```c
int main() {
  printf("Characters: %c %c \n", 'a', 65);
  printf("Decimals: %d %1d\n", 1977, 650000);
  printf("Preceding with blanks: %10d \n", 1977);
  printf("Preceding with zeros: %010d \n", 1977);
  printf("Some difference radices: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100);
  printf("floats: %4.2f %+.0e %E \n", 3.1416, 3.1416, 3.1416);
  printf("%s \n", "A string");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x61,%esi
  lea    D74(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9eb10,%edx
  mov    $0x7b9,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D1(%rip),%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  lea    D61(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D5(%rip),%rsi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D74
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D1
datatype: f64
name: retrieve_data
arguments: label: D61
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D59
datatype: string

tool: D74: Characters: %c %c 


tool: D19: Decimals: %d %1d


tool: D10: Preceding with blanks: %10d 


tool: D49: Preceding with zeros: %010d 


tool: D12: Some difference radices: %d %x %o %#x %#o 


tool: D1: 3.1416

tool: D61: floats: %4.2f %+.0e %E 


tool: D5: A string

tool: D59: %s 


assistant: ```c
int main() {
  printf("Characters: %c %c \n", 'a', 65);
  printf("Decimals: %d %1d\n", 1977, 650000);
  printf("Preceding with blanks: %10d \n", 1977);
  printf("Preceding with zeros: %010d \n", 1977);
  printf("Some difference radices: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100);
  printf("floats: %4.2f %+.0e %E \n", 3.1416, 3.1416, 3.1416);
  printf("%s \n", "A string");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x61,%esi
  xor    %eax,%eax
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    $0x9eb10,%edx
  mov    $0x7b9,%esi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D32(%rip),%xmm0
  mov    $0x3,%eax
  lea    D50(%rip),%rdi
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <printf@plt>
  lea    D36(%rip),%rsi
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D40
type_guessed: string
name: retrieve_data
arguments: data_tag: D32
type_guessed: f64
name: retrieve_data
arguments: data_tag: D50
type_guessed: string
name: retrieve_data
arguments: data_tag: D36
type_guessed: string
name: retrieve_data
arguments: data_tag: D73
type_guessed: string

tool: D41: Characters: %c %c 


tool: D30: Decimals: %d %1d


tool: D27: Preceding with blanks: %10d 


tool: D9: Preceding with zeros: %010d 


tool: D40: Some difference radices: %d %x %o %#x %#o 


tool: D32: 3.1416

tool: D50: floats: %4.2f %+.0e %E 


tool: D36: A string

tool: D73: %s 


assistant: ```c
int main() {
  printf("Characters: %c %c \n", 'a', 65);
  printf("Decimals: %d %1d\n", 1977, 650000);
  printf("Preceding with blanks: %10d \n", 1977);
  printf("Preceding with zeros: %010d \n", 1977);
  printf("Some difference radices: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100);
  printf("floats: %4.2f %+.0e %E \n", 3.1416, 3.1416, 3.1416);
  printf("%s \n", "A string");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edx
  mov    $0x61,%esi
  xor    %eax,%eax
  lea    D67(%rip),%rdi
  call   <printf@plt>
  mov    $0x9eb10,%edx
  mov    $0x7b9,%esi
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7b9,%esi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x64,%r9d
  mov    $0x64,%r8d
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D2(%rip),%xmm0
  mov    $0x3,%eax
  lea    D65(%rip),%rdi
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <printf@plt>
  lea    D54(%rip),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D67
datatype: string
name: retrieve_data
arguments: tag: D52
datatype: string
name: retrieve_data
arguments: tag: D40
datatype: string
name: retrieve_data
arguments: tag: D44
datatype: string
name: retrieve_data
arguments: tag: D45
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D65
datatype: string
name: retrieve_data
arguments: tag: D54
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D67: Characters: %c %c 


tool: D52: Decimals: %d %1d


tool: D40: Preceding with blanks: %10d 


tool: D44: Preceding with zeros: %010d 


tool: D45: Some difference radices: %d %x %o %#x %#o 


tool: D2: 3.1416

tool: D65: floats: %4.2f %+.0e %E 


tool: D54: A string

tool: D19: %s 


assistant: ```c
int main() {
  printf("Characters: %c %c \n", 'a', 65);
  printf("Decimals: %d %1d\n", 1977, 650000);
  printf("Preceding with blanks: %10d \n", 1977);
  printf("Preceding with zeros: %010d \n", 1977);
  printf("Some difference radices: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100);
  printf("floats: %4.2f %+.0e %E \n", 3.1416, 3.1416, 3.1416);
  printf("%s \n", "A string");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L19
L2:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sum>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L19:
  leave
  ret
```

assistant: ```c
int sum(int k) {
  if (k == 0)
    return 0;
  else
    return k + sum(k - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L19
L6:
  mov    %ebx,%eax
  pop    %rbx
  ret
L19:
  lea    -0x1(%rdi),%edi
  call   <sum>
  add    %eax,%ebx
  jmp    L6
```

assistant: ```c
int sum(int k) {
  if (k == 0)
    return 0;
  else
    return k + sum(k - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L9
  nopw   0x0(%rax,%rax,1)
L12:
  add    %edi,%eax
  sub    $0x1,%edi
  jne    L12
L9:
  ret
```

assistant: ```c
int sum(int k) {
  if (k == 0)
    return 0;
  else
    return k + sum(k - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  test   %edi,%edi
  je     L121
  lea    -0x1(%rdi),%edx
  mov    %edi,%ecx
  cmp    $0x9,%edx
  jbe    L42
  movd   %edi,%xmm4
  mov    %edi,%edx
  movdqa D12(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  paddd  D5(%rip),%xmm1
  shr    $0x2,%edx
  pxor   %xmm0,%xmm0
  xchg   %ax,%ax
L16:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L16
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  sub    %edx,%edi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%ecx
  je     L60
  lea    -0x1(%rdi),%edx
L46:
  add    %edi,%eax
  test   %edx,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x2,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x3,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x4,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x5,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x6,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x7,%edx
  je     L60
  add    %edx,%eax
  mov    %edi,%edx
  sub    $0x8,%edx
  je     L60
  add    %eax,%edx
  lea    -0x9(%rdi,%rdx,1),%eax
L60:
  ret
  nopl   0x0(%rax,%rax,1)
L121:
  xor    %eax,%eax
  ret
L42:
  xor    %eax,%eax
  jmp    L46
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
datatype: byte[16]
name: extract_symbolic_data
arguments: label: D5
datatype: byte[16]

tool: {"D12": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D5": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

assistant: ```c
int sum(int k) {
  if (k == 0)
    return 0;
  else
    return k + sum(k - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xround>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double xround(double d, int precision) {
  int factor = pow(10, precision);
  long i = d * factor;
  return i / (double)factor;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xround>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movq   %rbx,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double xround(double d, int precision) {
  int factor = pow(10, precision);
  long i = d * factor;
  return i / (double)factor;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xround>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double xround(double d, int precision) {
  int factor = pow(10, precision);
  long i = d * factor;
  return i / (double)factor;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xround>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double xround(double d, int precision) {
  int factor = pow(10, precision);
  long i = d * factor;
  return i / (double)factor;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printMessages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movl   $0x1,-0x3c(%rbp)
  jmp    L21
L7:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <display_thread_sched_attr@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x499602d2,-0x28(%rbp)
  movq   $0x499602d2,-0x20(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L5
L60:
  movl   $0x0,-0x34(%rbp)
  jmp    L30
L57:
  addl   $0x1,-0x34(%rbp)
L30:
  cmpl   $0x12d687,-0x34(%rbp)
  jle    L57
  addl   $0x1,-0x38(%rbp)
L5:
  cmpl   $0x7b,-0x38(%rbp)
  jle    L60
  addl   $0x1,-0x3c(%rbp)
L21:
  cmpl   $0x19,-0x3c(%rbp)
  jle    L7
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D8: jagi_%ld

tool: D7:  thread number %3ld - multiplication iter num %2d

assistant: ```c
void *printMessages(void *arg) {
  long tid;
  tid = (long)arg;
  char name[12];
  sprintf(name, "jagi_%ld", tid);
  int sleepValue;
  for (int m = 1; m <= 25; m++) {
    display_thread_sched_attr(name);
    printf(" thread number %3ld - multiplication iter num %2d", tid, m);
    long i = 1234567890;
    long j = 1234567890;
    for (int mult = 0; mult <= 123; mult++) {
      for (int inmult = 0; inmult <= 1234567; inmult++) {
        i *j;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printMessages>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x1,%ebx
  lea    D11(%rip),%rbp
L7:
  lea    0xc(%rsp),%rdi
  call   <display_thread_sched_attr@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x7c,%edx
L23:
  mov    $0x12d688,%eax
L28:
  sub    $0x1,%eax
  jne    L28
  sub    $0x1,%edx
  jne    L23
  add    $0x1,%ebx
  cmp    $0x1a,%ebx
  jne    L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D3: jagi_%ld

tool: D11:  thread number %3ld - multiplication iter num %2d

assistant: ```c
void *printMessages(void *arg) {
  long tid;
  tid = (long)arg;
  char name[12];
  sprintf(name, "jagi_%ld", tid);
  int sleepValue;
  for (int m = 1; m <= 25; m++) {
    display_thread_sched_attr(name);
    printf(" thread number %3ld - multiplication iter num %2d", tid, m);
    long i = 1234567890;
    long j = 1234567890;
    for (int mult = 0; mult <= 123; mult++) {
      for (int inmult = 0; inmult <= 1234567; inmult++) {
        i *j;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printMessages>:
  endbr64
  push   %r13
  mov    %rdi,%rdx
  lea    D15(%rip),%rsi
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  nopl   0x0(%rax)
L11:
  mov    %r12,%rdi
  call   <display_thread_sched_attr@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x1a,%ebx
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string

tool: D15: jagi_%ld

tool: D11:  thread number %3ld - multiplication iter num %2d

assistant: ```c
void *printMessages(void *arg) {
  long tid;
  tid = (long)arg;
  char name[12];
  sprintf(name, "jagi_%ld", tid);
  int sleepValue;
  for (int m = 1; m <= 25; m++) {
    display_thread_sched_attr(name);
    printf(" thread number %3ld - multiplication iter num %2d", tid, m);
    long i = 1234567890;
    long j = 1234567890;
    for (int mult = 0; mult <= 123; mult++) {
      for (int inmult = 0; inmult <= 1234567; inmult++) {
        i *j;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printMessages>:
  endbr64
  push   %r13
  mov    %rdi,%rdx
  lea    D17(%rip),%rsi
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  nopl   0x0(%rax)
L2:
  mov    %r12,%rdi
  call   <display_thread_sched_attr@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x1a,%ebx
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D17: jagi_%ld

tool: D3:  thread number %3ld - multiplication iter num %2d

assistant: ```c
void *printMessages(void *arg) {
  long tid;
  tid = (long)arg;
  char name[12];
  sprintf(name, "jagi_%ld", tid);
  int sleepValue;
  for (int m = 1; m <= 25; m++) {
    display_thread_sched_attr(name);
    printf(" thread number %3ld - multiplication iter num %2d", tid, m);
    long i = 1234567890;
    long j = 1234567890;
    for (int mult = 0; mult <= 123; mult++) {
      for (int inmult = 0; inmult <= 1234567; inmult++) {
        i *j;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ffs_ref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L15
L17:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L58
L11:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L18
  mov    -0x4(%rbp),%eax
  jmp    L15
L18:
  addl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x1f,-0x8(%rbp)
  jle    L11
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ffs_ref(uint32_t word) {
  if (!word)
    return 0;
  for (int c = 0, i = 0; c < 32; c++)
    if (((1 << i++) & word) != 0)
      return i;
  return 0;
}
```