ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  add    $0x2,%eax
  sub    $0x9,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
long main() {
  long g;
  g = (-1 * (6 + 3) / (3 - 2)) + (2 + (2 / 0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  long g;
  g = (-1 * (6 + 3) / (3 - 2)) + (2 + (2 / 0));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  long g;
  g = (-1 * (6 + 3) / (3 - 2)) + (2 + (2 / 0));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  long g;
  g = (-1 * (6 + 3) / (3 - 2)) + (2 + (2 / 0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L1:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff80180481,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  imul   $0xffd,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash(char *word) {
  int hashcode = 0;
  while (*word) {
    hashcode = (31 * hashcode + *word++) % 4093;
  }
  return abs(hashcode);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L0
  mov    $0x0,%edx
L21:
  add    $0x1,%rdi
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff80180481,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xffd,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L21
L29:
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L29
```

assistant: ```c
int hash(char *word) {
  int hashcode = 0;
  while (*word) {
    hashcode = (31 * hashcode + *word++) % 4093;
  }
  return abs(hashcode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%ecx
  test   %cl,%cl
  je     L3
  xor    %edx,%edx
  nopl   (%rax)
L10:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80180481,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sub    %ecx,%edx
  imul   $0xffd,%edx,%ecx
  sub    %ecx,%eax
  movsbl (%rdi),%ecx
  mov    %eax,%edx
  test   %cl,%cl
  jne    L10
  neg    %eax
  cmovs  %edx,%eax
  ret
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(char *word) {
  int hashcode = 0;
  while (*word) {
    hashcode = (31 * hashcode + *word++) % 4093;
  }
  return abs(hashcode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%ecx
  test   %cl,%cl
  je     L5
  xor    %edx,%edx
  nopl   (%rax)
L1:
  mov    %edx,%eax
  add    $0x1,%rdi
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff80180481,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sub    %ecx,%edx
  imul   $0xffd,%edx,%ecx
  sub    %ecx,%eax
  movsbl (%rdi),%ecx
  mov    %eax,%edx
  test   %cl,%cl
  jne    L1
  neg    %eax
  cmovs  %edx,%eax
  ret
  xchg   %ax,%ax
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(char *word) {
  int hashcode = 0;
  while (*word) {
    hashcode = (31 * hashcode + *word++) % 4093;
  }
  return abs(hashcode);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nibble_sort_grayson>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <davidegrayson_nibble_sort_counter_word@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L8:
  cmpl   $0x3ff,-0x14(%rbp)
  jle    L16
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void nibble_sort_grayson(unsigned long *buf) {
  for (int i = 0; i < 1024; i++) {
    buf[i] = davidegrayson_nibble_sort_counter_word(buf[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nibble_sort_grayson>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x2000(%rdi),%rbp
L7:
  mov    (%rbx),%rdi
  call   <davidegrayson_nibble_sort_counter_word@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void nibble_sort_grayson(unsigned long *buf) {
  for (int i = 0; i < 1024; i++) {
    buf[i] = davidegrayson_nibble_sort_counter_word(buf[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nibble_sort_grayson>:
  endbr64
  push   %rbp
  lea    0x2000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <davidegrayson_nibble_sort_counter_word@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void nibble_sort_grayson(unsigned long *buf) {
  for (int i = 0; i < 1024; i++) {
    buf[i] = davidegrayson_nibble_sort_counter_word(buf[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nibble_sort_grayson>:
  endbr64
  push   %rbp
  lea    0x2000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <davidegrayson_nibble_sort_counter_word@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void nibble_sort_grayson(unsigned long *buf) {
  for (int i = 0; i < 1024; i++) {
    buf[i] = davidegrayson_nibble_sort_counter_word(buf[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_test_various_MAX_biggerullong_smallerint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <_test_MAX_biggerullong_smallerint@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _test_various_MAX_biggerullong_smallerint() {
  _test_MAX_biggerullong_smallerint(0, -1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_test_various_MAX_biggerullong_smallerint>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <_test_MAX_biggerullong_smallerint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _test_various_MAX_biggerullong_smallerint() {
  _test_MAX_biggerullong_smallerint(0, -1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_test_various_MAX_biggerullong_smallerint>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  xor    %edi,%edi
  call   <_test_MAX_biggerullong_smallerint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _test_various_MAX_biggerullong_smallerint() {
  _test_MAX_biggerullong_smallerint(0, -1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_test_various_MAX_biggerullong_smallerint>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  xor    %edi,%edi
  call   <_test_MAX_biggerullong_smallerint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _test_various_MAX_biggerullong_smallerint() {
  _test_MAX_biggerullong_smallerint(0, -1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<si475xAMRX_regional_cfg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x9,%esi
  mov    $0x1102,%edi
  call   <si475x_set_property@plt>
  mov    $0x213,%esi
  mov    $0x1100,%edi
  call   <si475x_set_property@plt>
  mov    $0x65d,%esi
  mov    $0x1101,%edi
  call   <si475x_set_property@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void si475xAMRX_regional_cfg(void) {
  si475x_set_property(0x1102, 9);
  si475x_set_property(0x1100, 531);
  si475x_set_property(0x1101, 1629);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<si475xAMRX_regional_cfg>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  mov    $0x1102,%edi
  call   <si475x_set_property@plt>
  mov    $0x213,%esi
  mov    $0x1100,%edi
  call   <si475x_set_property@plt>
  mov    $0x65d,%esi
  mov    $0x1101,%edi
  call   <si475x_set_property@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void si475xAMRX_regional_cfg(void) {
  si475x_set_property(0x1102, 9);
  si475x_set_property(0x1100, 531);
  si475x_set_property(0x1101, 1629);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<si475xAMRX_regional_cfg>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  mov    $0x1102,%edi
  call   <si475x_set_property@plt>
  mov    $0x213,%esi
  mov    $0x1100,%edi
  call   <si475x_set_property@plt>
  mov    $0x65d,%esi
  mov    $0x1101,%edi
  add    $0x8,%rsp
  jmp    1050 <si475x_set_property@plt>
```

assistant: ```c
void si475xAMRX_regional_cfg(void) {
  si475x_set_property(0x1102, 9);
  si475x_set_property(0x1100, 531);
  si475x_set_property(0x1101, 1629);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<si475xAMRX_regional_cfg>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  mov    $0x1102,%edi
  call   <si475x_set_property@plt>
  mov    $0x213,%esi
  mov    $0x1100,%edi
  call   <si475x_set_property@plt>
  mov    $0x65d,%esi
  mov    $0x1101,%edi
  add    $0x8,%rsp
  jmp    1050 <si475x_set_property@plt>
```

assistant: ```c
void si475xAMRX_regional_cfg(void) {
  si475x_set_property(0x1102, 9);
  si475x_set_property(0x1100, 531);
  si475x_set_property(0x1101, 1629);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uci_print_nps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L27
  mov    $0x0,%eax
  call   <GetTickCount@plt>
  sub    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  D14(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L26
  pxor   %xmm0,%xmm0
  ucomiss -0x8(%rbp),%xmm0
  je     L3
L26:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x18(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L42
L27:
  nop
  jmp    L42
L3:
  nop
L42:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: byte[4]
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: {"D14": [0x00,0x00,0x7a,0x44]}

tool: D17: info nps %.0f


assistant: ```c
void uci_print_nps(int time_start, int nodes) {
  if (!nodes)
    return;
  float time_used_in_sec, nps;
  time_used_in_sec = (float)(((int)(GetTickCount())) - time_start) / 1000;
  if (!time_used_in_sec)
    return;
  nps = (float)nodes / time_used_in_sec;
  printf("info nps %.0f\n", nps);
}
```
user: What is the c source code of the assembly code below:

```asm
<uci_print_nps>:
  endbr64
  test   %esi,%esi
  jne    L19
  ret
L19:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <GetTickCount@plt>
  sub    %ebp,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  D5(%rip),%xmm1
  ucomiss D25(%rip),%xmm1
  jp     L39
  jne    L39
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  divss  %xmm1,%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: byte[4]
name: disassemble_data
arguments: tag: D25
type_infered: byte[4]
name: disassemble_data
arguments: tag: D22
type_infered: string

tool: {"D5": [0x00,0x00,0x7a,0x44]}

tool: {"D25": [0x00,0x00,0x00,0x00]}

tool: D22: info nps %.0f


assistant: ```c
void uci_print_nps(int time_start, int nodes) {
  if (!nodes)
    return;
  float time_used_in_sec, nps;
  time_used_in_sec = (float)(((int)(GetTickCount())) - time_start) / 1000;
  if (!time_used_in_sec)
    return;
  nps = (float)nodes / time_used_in_sec;
  printf("info nps %.0f\n", nps);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uci_print_nps>:
  endbr64
  test   %esi,%esi
  jne    L26
  ret
  nopl   0x0(%rax)
L26:
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <GetTickCount@plt>
  pxor   %xmm1,%xmm1
  sub    %ebp,%eax
  cvtsi2ss %eax,%xmm1
  divss  D17(%rip),%xmm1
  ucomiss D29(%rip),%xmm1
  jp     L19
  je     L3
L19:
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  cvtsi2ss %ebx,%xmm0
  pop    %rbx
  pop    %rbp
  divss  %xmm1,%xmm0
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
type: byte[4]
name: unpack_data
arguments: data_tag: D29
type: byte[4]
name: unpack_data
arguments: data_tag: D7
type: string

tool: {"D17": [0x00,0x00,0x7a,0x44]}

tool: {"D29": [0x00,0x00,0x00,0x00]}

tool: D7: info nps %.0f


assistant: ```c
void uci_print_nps(int time_start, int nodes) {
  if (!nodes)
    return;
  float time_used_in_sec, nps;
  time_used_in_sec = (float)(((int)(GetTickCount())) - time_start) / 1000;
  if (!time_used_in_sec)
    return;
  nps = (float)nodes / time_used_in_sec;
  printf("info nps %.0f\n", nps);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uci_print_nps>:
  endbr64
  test   %esi,%esi
  jne    L26
  ret
  nopl   0x0(%rax)
L26:
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <GetTickCount@plt>
  pxor   %xmm1,%xmm1
  sub    %ebp,%eax
  cvtsi2ss %eax,%xmm1
  divss  D25(%rip),%xmm1
  ucomiss D28(%rip),%xmm1
  jp     L17
  je     L19
L17:
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  lea    D11(%rip),%rdi
  cvtsi2ss %ebx,%xmm0
  pop    %rbx
  pop    %rbp
  divss  %xmm1,%xmm0
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: byte[4]
name: retrieve_data
arguments: label: D28
datatype: byte[4]
name: retrieve_data
arguments: label: D11
datatype: string

tool: {"D25": [0x00,0x00,0x7a,0x44]}

tool: {"D28": [0x00,0x00,0x00,0x00]}

tool: D11: info nps %.0f


assistant: ```c
void uci_print_nps(int time_start, int nodes) {
  if (!nodes)
    return;
  float time_used_in_sec, nps;
  time_used_in_sec = (float)(((int)(GetTickCount())) - time_start) / 1000;
  if (!time_used_in_sec)
    return;
  nps = (float)nodes / time_used_in_sec;
  printf("info nps %.0f\n", nps);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getSTcoordinates>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %r9,0x8(%rsp)
  mov    0xc0(%rsp),%r15
  mov    0xc8(%rsp),%r14
  mov    0xd0(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movsd  (%rsi),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x30(%rsp)
  movsd  (%rcx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x38(%rsp)
  movsd  0x8(%rsi),%xmm1
  movsd  0x8(%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x40(%rsp)
  movsd  0x8(%rcx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  lea    0x50(%rsp),%r12
  lea    0x30(%rsp),%rdi
  mov    %r12,%rsi
  call   <mat22Invert@plt>
  movsd  %xmm0,(%rsp)
  movsd  0x0(%rbp),%xmm0
  subsd  (%rbx),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rbp),%xmm0
  subsd  0x8(%rbx),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  lea    0x20(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <mat221Multiply@plt>
  movsd  (%rsp),%xmm5
  ucomisd D2(%rip),%xmm5
  jp     L23
  je     L2
L23:
  mov    0x8(%rsp),%rax
  movsd  (%rax),%xmm2
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm3
  movsd  (%r15),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  movsd  (%r14),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%r13)
  movsd  0x8(%rax),%xmm2
  movsd  0x8(%r15),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  movsd  0x8(%r14),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%r13)
L27:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: f64
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D2: 0

tool: D8: The matrix doesn't have an Inverse, something is wrong here


assistant: ```c
void getSTcoordinates(double x[2], double a[2], double b[2], double c[2], double rgb[3], double alpha[2], double beta[2], double gamma[2], double coordinates[2]) {
  double m[2][2] = {{b[0] - a[0], c[0] - a[0]}, {b[1] - a[1], c[1] - a[1]}};
  double Inv[2][2] = {{0.0, 0.0}, {0.0, 0.0}};
  double det = mat22Invert(m, Inv);
  double vec[2] = {x[0] - a[0], x[1] - a[1]};
  double pq[2] = {0.0, 0.0};
  mat221Multiply(Inv, vec, pq);
  if (det != 0) {
    coordinates[0] = alpha[0] + pq[0] * (beta[0] - alpha[0]) + pq[1] * (gamma[0] - alpha[0]);
    coordinates[1] = alpha[1] + pq[0] * (beta[1] - alpha[1]) + pq[1] * (gamma[1] - alpha[1]);
  } else {
    printf("The matrix doesn't have an Inverse, something is wrong here\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getSTcoordinates>:
  endbr64
  push   %r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x88,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rdx),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%r8
  lea    0x30(%rsp),%rdi
  movq   $0x0,0x50(%rsp)
  subsd  %xmm1,%xmm0
  mov    %r8,0x8(%rsp)
  mov    0xc0(%rsp),%r15
  mov    0xc8(%rsp),%r13
  mov    0xd0(%rsp),%r12
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movsd  %xmm0,0x30(%rsp)
  movsd  (%rcx),%xmm0
  movq   $0x0,0x68(%rsp)
  subsd  %xmm1,%xmm0
  movsd  0x8(%rsi),%xmm1
  mov    %r8,%rsi
  movsd  %xmm0,0x38(%rsp)
  movsd  0x8(%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x40(%rsp)
  movsd  0x8(%rcx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x48(%rsp)
  call   <mat22Invert@plt>
  movsd  0x0(%rbp),%xmm1
  subsd  (%rbx),%xmm1
  lea    0x20(%rsp),%rdx
  mov    0x8(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  movsd  %xmm0,(%rsp)
  movq   $0x0,0x20(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  0x8(%rbp),%xmm1
  subsd  0x8(%rbx),%xmm1
  movq   $0x0,0x28(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <mat221Multiply@plt>
  movsd  (%rsp),%xmm0
  ucomisd D4(%rip),%xmm0
  jp     L28
  je     L19
L28:
  movsd  (%r14),%xmm2
  movsd  (%r15),%xmm0
  movsd  0x0(%r13),%xmm1
  movsd  0x20(%rsp),%xmm4
  subsd  %xmm2,%xmm0
  movsd  0x28(%rsp),%xmm3
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  movsd  0x8(%r14),%xmm2
  movsd  0x8(%r15),%xmm0
  movsd  0x8(%r13),%xmm1
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%r12)
L35:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: f64
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: D4: 0

tool: D11: The matrix doesn't have an Inverse, something is wrong here


assistant: ```c
void getSTcoordinates(double x[2], double a[2], double b[2], double c[2], double rgb[3], double alpha[2], double beta[2], double gamma[2], double coordinates[2]) {
  double m[2][2] = {{b[0] - a[0], c[0] - a[0]}, {b[1] - a[1], c[1] - a[1]}};
  double Inv[2][2] = {{0.0, 0.0}, {0.0, 0.0}};
  double det = mat22Invert(m, Inv);
  double vec[2] = {x[0] - a[0], x[1] - a[1]};
  double pq[2] = {0.0, 0.0};
  mat221Multiply(Inv, vec, pq);
  if (det != 0) {
    coordinates[0] = alpha[0] + pq[0] * (beta[0] - alpha[0]) + pq[1] * (gamma[0] - alpha[0]);
    coordinates[1] = alpha[1] + pq[0] * (beta[1] - alpha[1]) + pq[1] * (gamma[1] - alpha[1]);
  } else {
    printf("The matrix doesn't have an Inverse, something is wrong here\n");
  }
}
```