ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1f,(%rsp)
  movl   $0x1c,0x4(%rsp)
  movl   $0x1f,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  movl   $0x1f,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  movl   $0x1f,0x18(%rsp)
  movl   $0x1f,0x1c(%rsp)
  movl   $0x1e,0x20(%rsp)
  movl   $0x1f,0x24(%rsp)
  mov    $0x1,%ebx
  lea    D1(%rip),%rbp
L1:
  mov    -0x4(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  jne    L1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++) {
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1f,%edx
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1c,0x4(%rsp)
  movabs $0x1e0000001f,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x1f0000001f,%rax
  mov    %rax,0x18(%rsp)
  sub    $0x1,%rax
  mov    %rax,0x20(%rsp)
  jmp    L21
  nopl   0x0(%rax)
L6:
  mov    (%rsp,%rbx,4),%edx
  add    $0x1,%rbx
L21:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++) {
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D35(%rip),%rax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D6(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
L7:
  mov    -0x4(%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xb,%rbx
  jne    L7
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D5
type_infered: byte[16]
name: read_data
arguments: tag: D35
type_infered: byte[8]
name: read_data
arguments: tag: D6
type_infered: byte[16]

tool: D14: Month %2d has %d days.


tool: {"D5": [0x1f,0x00,0x00,0x00,0x1c,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D35": [0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

tool: {"D6": [0x1f,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++) {
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<szb_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <szb_clear@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void szb_free(struct szb_s *szb) {
  assert(szb != NULL);
  szb_clear(szb);
  free(szb);
}
```
user: What is the c source code of the assembly code below:

```asm
<szb_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <szb_clear@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void szb_free(struct szb_s *szb) {
  assert(szb != NULL);
  szb_clear(szb);
  free(szb);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<szb_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <szb_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void szb_free(struct szb_s *szb) {
  assert(szb != NULL);
  szb_clear(szb);
  free(szb);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<szb_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <szb_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

assistant: ```c
void szb_free(struct szb_s *szb) {
  assert(szb != NULL);
  szb_clear(szb);
  free(szb);
}
```
user: Translate the below assembly code into C programming language:

```asm
<waitForTimerMs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  shr    $0x6,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    -0x4(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void waitForTimerMs(unsigned int nbMs) {
  unsigned int nbSecs;
  unsigned int nbMsecs;
  nbSecs = nbMs / 1000;
  nbMsecs = nbMs % 1000;
  sleep(nbSecs);
  usleep(1000 * nbMsecs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<waitForTimerMs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%ebp
  imul   $0x10624dd3,%rbp,%rbp
  shr    $0x26,%rbp
  mov    %ebp,%edi
  call   <sleep@plt>
  imul   $0x3e8,%ebp,%ebp
  sub    %ebp,%ebx
  imul   $0x3e8,%ebx,%edi
  call   <usleep@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void waitForTimerMs(unsigned int nbMs) {
  unsigned int nbSecs;
  unsigned int nbMsecs;
  nbSecs = nbMs / 1000;
  nbMsecs = nbMs % 1000;
  sleep(nbSecs);
  usleep(1000 * nbMsecs);
}
```
user: What is the c source code of the assembly code below?

```asm
<waitForTimerMs>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rbp,%rbx
  imul   $0x10624dd3,%rbp,%rbp
  shr    $0x26,%rbp
  sub    $0x8,%rsp
  mov    %ebp,%edi
  imul   $0x3e8,%ebp,%ebp
  call   <sleep@plt>
  add    $0x8,%rsp
  sub    %ebp,%ebx
  imul   $0x3e8,%ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <usleep@plt>
```

assistant: ```c
void waitForTimerMs(unsigned int nbMs) {
  unsigned int nbSecs;
  unsigned int nbMsecs;
  nbSecs = nbMs / 1000;
  nbMsecs = nbMs % 1000;
  sleep(nbSecs);
  usleep(1000 * nbMsecs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<waitForTimerMs>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rbp,%rbx
  imul   $0x10624dd3,%rbp,%rbp
  shr    $0x26,%rbp
  sub    $0x8,%rsp
  mov    %ebp,%edi
  imul   $0x3e8,%ebp,%ebp
  call   <sleep@plt>
  add    $0x8,%rsp
  sub    %ebp,%ebx
  imul   $0x3e8,%ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <usleep@plt>
```

assistant: ```c
void waitForTimerMs(unsigned int nbMs) {
  unsigned int nbSecs;
  unsigned int nbMsecs;
  nbSecs = nbMs / 1000;
  nbMsecs = nbMs % 1000;
  sleep(nbSecs);
  usleep(1000 * nbMsecs);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PCAP16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L36
  cmpl   $0x2,-0x4(%rbp)
  je     L20
  jmp    L28
L36:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  jmp    L39
L20:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  jmp    L39
L28:
  mov    $0xa3a3,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
unsigned PCAP16(unsigned byte_order, const unsigned char *buf) {
  switch (byte_order) {
  case 1:
    return buf[0] * 256 + buf[1];
  case 2:
    return buf[1] * 256 + buf[0];
  default:
    return 0xa3a3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PCAP16>:
  endbr64
  cmp    $0x1,%edi
  je     L17
  cmp    $0x2,%edi
  je     L0
  mov    $0xa3a3,%eax
  ret
L17:
  movzbl (%rsi),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rsi),%edx
  add    %edx,%eax
  ret
L0:
  movzbl 0x1(%rsi),%eax
  shl    $0x8,%eax
  movzbl (%rsi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned PCAP16(unsigned byte_order, const unsigned char *buf) {
  switch (byte_order) {
  case 1:
    return buf[0] * 256 + buf[1];
  case 2:
    return buf[1] * 256 + buf[0];
  default:
    return 0xa3a3;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PCAP16>:
  endbr64
  cmp    $0x1,%edi
  je     L14
  cmp    $0x2,%edi
  jne    L19
  movzbl 0x1(%rsi),%eax
  movzbl (%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xa3a3,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned PCAP16(unsigned byte_order, const unsigned char *buf) {
  switch (byte_order) {
  case 1:
    return buf[0] * 256 + buf[1];
  case 2:
    return buf[1] * 256 + buf[0];
  default:
    return 0xa3a3;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PCAP16>:
  endbr64
  cmp    $0x1,%edi
  je     L6
  cmp    $0x2,%edi
  jne    L4
  movzbl 0x1(%rsi),%eax
  movzbl (%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xa3a3,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  movzbl (%rsi),%eax
  movzbl 0x1(%rsi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned PCAP16(unsigned byte_order, const unsigned char *buf) {
  switch (byte_order) {
  case 1:
    return buf[0] * 256 + buf[1];
  case 2:
    return buf[1] * 256 + buf[0];
  default:
    return 0xa3a3;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dmp_set_tap_time_multi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzwl -0x14(%rbp),%eax
  movzwl %ax,%eax
  imul   $0xcccd,%eax,%eax
  shr    $0x10,%eax
  shr    $0x2,%ax
  mov    %ax,-0xc(%rbp)
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  mov    %al,-0xa(%rbp)
  movzwl -0xc(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x1da,%edi
  call   <mpu_write_mem@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int dmp_set_tap_time_multi(unsigned short time) {
  unsigned short dmp_time;
  unsigned char tmp[2];
  dmp_time = time / (1000 / (200));
  tmp[0] = (unsigned char)(dmp_time >> 8);
  tmp[1] = (unsigned char)(dmp_time & 0xFF);
  return mpu_write_mem((256 + 218), 2, tmp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dmp_set_tap_time_multi>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl %di,%edi
  imul   $0xcccd,%edi,%edi
  mov    %edi,%eax
  shr    $0x12,%eax
  shr    $0x1a,%edi
  mov    %dil,0x6(%rsp)
  mov    %al,0x7(%rsp)
  lea    0x6(%rsp),%rdx
  mov    $0x2,%esi
  mov    $0x1da,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_time_multi(unsigned short time) {
  unsigned short dmp_time;
  unsigned char tmp[2];
  dmp_time = time / (1000 / (200));
  tmp[0] = (unsigned char)(dmp_time >> 8);
  tmp[1] = (unsigned char)(dmp_time & 0xFF);
  return mpu_write_mem((256 + 218), 2, tmp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dmp_set_tap_time_multi>:
  endbr64
  movzwl %di,%edi
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0xcccd,%edi,%edi
  lea    0x6(%rsp),%rdx
  shr    $0x12,%edi
  rol    $0x8,%di
  mov    %di,0x6(%rsp)
  mov    $0x1da,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_time_multi(unsigned short time) {
  unsigned short dmp_time;
  unsigned char tmp[2];
  dmp_time = time / (1000 / (200));
  tmp[0] = (unsigned char)(dmp_time >> 8);
  tmp[1] = (unsigned char)(dmp_time & 0xFF);
  return mpu_write_mem((256 + 218), 2, tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<dmp_set_tap_time_multi>:
  endbr64
  movzwl %di,%edi
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  imul   $0xcccd,%edi,%edi
  lea    0x6(%rsp),%rdx
  shr    $0x12,%edi
  rol    $0x8,%di
  mov    %di,0x6(%rsp)
  mov    $0x1da,%edi
  call   <mpu_write_mem@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dmp_set_tap_time_multi(unsigned short time) {
  unsigned short dmp_time;
  unsigned char tmp[2];
  dmp_time = time / (1000 / (200));
  tmp[0] = (unsigned char)(dmp_time >> 8);
  tmp[1] = (unsigned char)(dmp_time & 0xFF);
  return mpu_write_mem((256 + 218), 2, tmp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcasecmp_diff_length_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D19(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  cmp    $0xffffffff,%eax
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D19: aBc

tool: D3: abcde

assistant: ```c
void strcasecmp_diff_length_3() {
  char *x = "aBc";
  char *y = "abcde";
  if (strcasecmp(x, y) != -1)
    (void)*(char *)0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcasecmp_diff_length_3>:
  endbr64
  ret
```

assistant: ```c
void strcasecmp_diff_length_3() {
  char *x = "aBc";
  char *y = "abcde";
  if (strcasecmp(x, y) != -1)
    (void)*(char *)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcasecmp_diff_length_3>:
  endbr64
  ret
```

assistant: ```c
void strcasecmp_diff_length_3() {
  char *x = "aBc";
  char *y = "abcde";
  if (strcasecmp(x, y) != -1)
    (void)*(char *)0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp_diff_length_3>:
  endbr64
  ret
```

assistant: ```c
void strcasecmp_diff_length_3() {
  char *x = "aBc";
  char *y = "abcde";
  if (strcasecmp(x, y) != -1)
    (void)*(char *)0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_get_suite_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L1:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *_get_suite_name(const char *filename) {
  char *suite_name = malloc(strlen(filename) + 1);
  strcpy(suite_name, filename);
  char *last_dot_pos = strrchr(suite_name, '.');
  if (last_dot_pos != NULL)
    *last_dot_pos = '\0';
  return suite_name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_get_suite_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *_get_suite_name(const char *filename) {
  char *suite_name = malloc(strlen(filename) + 1);
  strcpy(suite_name, filename);
  char *last_dot_pos = strrchr(suite_name, '.');
  if (last_dot_pos != NULL)
    *last_dot_pos = '\0';
  return suite_name;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_get_suite_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *_get_suite_name(const char *filename) {
  char *suite_name = malloc(strlen(filename) + 1);
  strcpy(suite_name, filename);
  char *last_dot_pos = strrchr(suite_name, '.');
  if (last_dot_pos != NULL)
    *last_dot_pos = '\0';
  return suite_name;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_get_suite_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2e,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *_get_suite_name(const char *filename) {
  char *suite_name = malloc(strlen(filename) + 1);
  strcpy(suite_name, filename);
  char *last_dot_pos = strrchr(suite_name, '.');
  if (last_dot_pos != NULL)
    *last_dot_pos = '\0';
  return suite_name;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memdup(void *src, size_t size) {
  void *dst = malloc(size);
  memcpy(dst, src, size);
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(void *src, size_t size) {
  void *dst = malloc(size);
  memcpy(dst, src, size);
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(void *src, size_t size) {
  void *dst = malloc(size);
  memcpy(dst, src, size);
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(void *src, size_t size) {
  void *dst = malloc(size);
  memcpy(dst, src, size);
  return dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<tounix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L67
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
L67:
  mov    $0x0,%eax
  jmp    L8
L12:
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L0
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movzbl (%rcx),%edx
  cltq
  lea    D13(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
L0:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  cmpl   $0xf7,-0x4(%rbp)
  jle    L26
L42:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D13(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    -0x18(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x4(%rbp),%eax
L8:
  leave
  ret
```

assistant: ```c
int tounix(char *label) {
  static char buf[250 + 1];
  int i, j = 0;
  j = 0;
  if (label == NULL || label[0] == '\0')
    return 0;
  for (i = 0; label[i] && j < 250 - 2; i++) {
    if (label[i] != '\r')
      buf[j++] = label[i];
  }
  buf[j] = '\0';
  strcpy(label, buf);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tounix>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L56
  movzbl (%rdi),%eax
  mov    $0x0,%ebx
  test   %al,%al
  je     L23
  lea    0x1(%rdi),%rdx
  lea    D17(%rip),%rsi
  jmp    L30
L79:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  cmp    $0xf7,%ebx
  jg     L29
  test   %al,%al
  je     L29
L30:
  cmp    $0xd,%al
  je     L79
  movslq %ebx,%rcx
  mov    %al,(%rsi,%rcx,1)
  lea    0x1(%rbx),%ebx
  jmp    L79
L29:
  lea    D17(%rip),%rsi
  movslq %ebx,%rax
  movb   $0x0,(%rsi,%rax,1)
  call   <strcpy@plt>
L23:
  mov    %ebx,%eax
  pop    %rbx
  ret
L56:
  mov    $0x0,%ebx
  jmp    L23
```

assistant: ```c
int tounix(char *label) {
  static char buf[250 + 1];
  int i, j = 0;
  j = 0;
  if (label == NULL || label[0] == '\0')
    return 0;
  for (i = 0; label[i] && j < 250 - 2; i++) {
    if (label[i] != '\r')
      buf[j++] = label[i];
  }
  buf[j] = '\0';
  strcpy(label, buf);
  return j;
}
```