ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rndrm99_get_description>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: Create a directory named rndrm99_test_dir_pid, where pid is the process id.  Within that directory, randomly create and remove a number of sub-directories and small files, but do more creates than removes. When the total size of all sub-directories and files is greater than the size specified by the size parameter, start to do more removes than creates. The size parameter is given by the -z or --size option, otherwise it defaults to 1000000. A size of zero fills the file system until there is no space left. The task repeats, sleeping in between each iteration. The repeat count is set by the -n or --repeat option, otherwise it defaults to 1. A repeat count of zero repeats forever. The sleep value is given by the -p or --sleep option, otherwise it defaults to 0. Sleep is specified in milliseconds.

assistant: ```c
const char *rndrm99_get_description(void) {
  return "Create a directory named rndrm99_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "randomly create and remove "
         "a number of sub-directories and small files, "
         "but do more creates than removes. "
         "When the total size of all sub-directories and files "
         "is greater than the size specified by the size parameter, "
         "start to do more removes than creates. "
         "The size parameter is given by the -z or --size option, "
         "otherwise it defaults to 1000000. "
         "A size of zero fills the file system until there is no "
         "space left. "
         "The task repeats, sleeping in between each iteration. "
         "The repeat count is set by the -n or --repeat option, "
         "otherwise it defaults to 1. "
         "A repeat count of zero repeats forever. "
         "The sleep value is given by the -p or --sleep option, "
         "otherwise it defaults to 0. "
         "Sleep is specified in milliseconds.";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rndrm99_get_description>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: Create a directory named rndrm99_test_dir_pid, where pid is the process id.  Within that directory, randomly create and remove a number of sub-directories and small files, but do more creates than removes. When the total size of all sub-directories and files is greater than the size specified by the size parameter, start to do more removes than creates. The size parameter is given by the -z or --size option, otherwise it defaults to 1000000. A size of zero fills the file system until there is no space left. The task repeats, sleeping in between each iteration. The repeat count is set by the -n or --repeat option, otherwise it defaults to 1. A repeat count of zero repeats forever. The sleep value is given by the -p or --sleep option, otherwise it defaults to 0. Sleep is specified in milliseconds.

assistant: ```c
const char *rndrm99_get_description(void) {
  return "Create a directory named rndrm99_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "randomly create and remove "
         "a number of sub-directories and small files, "
         "but do more creates than removes. "
         "When the total size of all sub-directories and files "
         "is greater than the size specified by the size parameter, "
         "start to do more removes than creates. "
         "The size parameter is given by the -z or --size option, "
         "otherwise it defaults to 1000000. "
         "A size of zero fills the file system until there is no "
         "space left. "
         "The task repeats, sleeping in between each iteration. "
         "The repeat count is set by the -n or --repeat option, "
         "otherwise it defaults to 1. "
         "A repeat count of zero repeats forever. "
         "The sleep value is given by the -p or --sleep option, "
         "otherwise it defaults to 0. "
         "Sleep is specified in milliseconds.";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <create_window@plt>
  nop
L4:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x5,%edi
  call   <KEY_F@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <destroy_window@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int input;
  create_window();
  while ((input = getch()) != KEY_F(5)) {
  }
  destroy_window();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <create_window@plt>
L7:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    $0x5,%edi
  call   <KEY_F@plt>
  cmp    %ebx,%eax
  jne    L7
  mov    $0x0,%eax
  call   <destroy_window@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int input;
  create_window();
  while ((input = getch()) != KEY_F(5)) {
  }
  destroy_window();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <create_window@plt>
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <getch@plt>
  mov    $0x5,%edi
  mov    %eax,%ebx
  call   <KEY_F@plt>
  cmp    %ebx,%eax
  jne    L8
  xor    %eax,%eax
  call   <destroy_window@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int input;
  create_window();
  while ((input = getch()) != KEY_F(5)) {
  }
  destroy_window();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <create_window@plt>
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <getch@plt>
  mov    $0x5,%edi
  mov    %eax,%ebx
  call   <KEY_F@plt>
  cmp    %ebx,%eax
  jne    L1
  xor    %eax,%eax
  call   <destroy_window@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int input;
  create_window();
  while ((input = getch()) != KEY_F(5)) {
  }
  destroy_window();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fls64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x20,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fls@plt>
  add    $0x20,%eax
  jmp    L3
L10:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fls@plt>
L3:
  leave
  ret
```

assistant: ```c
__attribute__((always_)) int fls64(uint64_t x) {
  uint32_t h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fls64>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  jne    L17
  call   <fls@plt>
L14:
  add    $0x8,%rsp
  ret
L17:
  mov    %eax,%edi
  call   <fls@plt>
  add    $0x20,%eax
  jmp    L14
```

assistant: ```c
__attribute__((always_)) int fls64(uint64_t x) {
  uint32_t h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fls64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x20,%ecx
  sar    %cl,%r8d
  test   %r8d,%r8d
  jne    L7
  jmp    1050 <fls@plt>
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  mov    %r8d,%edi
  call   <fls@plt>
  add    $0x8,%rsp
  add    $0x20,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int fls64(uint64_t x) {
  uint32_t h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fls64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x20,%ecx
  sar    %cl,%r8d
  test   %r8d,%r8d
  jne    L7
  jmp    1050 <fls@plt>
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  mov    %r8d,%edi
  call   <fls@plt>
  add    $0x8,%rsp
  add    $0x20,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int fls64(uint64_t x) {
  uint32_t h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <potega@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type_guessed: string
name: unpack_data
arguments: data_tag: D59
type_guessed: string
name: unpack_data
arguments: data_tag: D55
type_guessed: string
name: unpack_data
arguments: data_tag: D43
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D28: Obliczanie potegi

tool: D59: podaj podstawe: 

tool: D55: %d

tool: D43: podaj wykladnik: 

tool: D16: wynik %lld 


assistant: ```c
int main(void) {
  int x, y;
  long long int wynik;
  printf("Obliczanie potegi\n");
  printf("podaj podstawe: ");
  scanf("%d", &x);
  printf("podaj wykladnik: ");
  scanf("%d", &y);
  wynik = potega(x, y);
  printf("wynik %lld \n", wynik);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D48(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <potega@plt>
  mov    %rax,%rsi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D48
type_infered: string
name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D49
type_infered: string

tool: D15: Obliczanie potegi

tool: D1: podaj podstawe: 

tool: D48: %d

tool: D19: podaj wykladnik: 

tool: D49: wynik %lld 


assistant: ```c
int main(void) {
  int x, y;
  long long int wynik;
  printf("Obliczanie potegi\n");
  printf("podaj podstawe: ");
  scanf("%d", &x);
  printf("podaj wykladnik: ");
  scanf("%d", &y);
  wynik = potega(x, y);
  printf("wynik %lld \n", wynik);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D21(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <potega@plt>
  lea    D16(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D21
type: string
name: read_data
arguments: data_label: D4
type: string
name: read_data
arguments: data_label: D44
type: string
name: read_data
arguments: data_label: D16
type: string

tool: D34: Obliczanie potegi

tool: D21: %d

tool: D4: podaj podstawe: 

tool: D44: podaj wykladnik: 

tool: D16: wynik %lld 


assistant: ```c
int main(void) {
  int x, y;
  long long int wynik;
  printf("Obliczanie potegi\n");
  printf("podaj podstawe: ");
  scanf("%d", &x);
  printf("podaj wykladnik: ");
  scanf("%d", &y);
  wynik = potega(x, y);
  printf("wynik %lld \n", wynik);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D33(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <potega@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D38
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D38: Obliczanie potegi

tool: D33: %d

tool: D25: podaj podstawe: 

tool: D4: podaj wykladnik: 

tool: D10: wynik %lld 


assistant: ```c
int main(void) {
  int x, y;
  long long int wynik;
  printf("Obliczanie potegi\n");
  printf("podaj podstawe: ");
  scanf("%d", &x);
  printf("podaj wykladnik: ");
  scanf("%d", &y);
  wynik = potega(x, y);
  printf("wynik %lld \n", wynik);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dlcom_string_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L141
  cmp    $0xd,%al
  je     L141
  lea    0x1(%rdi),%rdx
  mov    $0x0,%r8d
  mov    $0x0,%esi
  jmp    L28
L100:
  add    $0x1,%r8d
  cmp    $0x2,%r8d
  je     L149
L147:
  add    $0x1,%rdx
  test   %al,%al
  je     L149
  cmp    $0xd,%al
  je     L149
L28:
  mov    %eax,%ecx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L149
  cmp    $0x22,%cl
  je     L100
  movslq %esi,%rdi
  mov    %cl,(%rsp,%rdi,1)
  lea    0x1(%rsi),%esi
  jmp    L147
L141:
  mov    $0x0,%esi
L149:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%eax
  test   %al,%al
  je     L62
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r13
  jmp    L106
L119:
  lea    0x3(%rbp),%r14d
  movslq %r14d,%r14
  movzbl (%rsp,%r14,1),%r15d
  movb   $0x0,(%rsp,%r14,1)
  movslq %ebp,%rax
  lea    0x1(%r13,%rax,1),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %al,-0x1(%r12,%rbx,1)
  mov    %r15b,(%rsp,%r14,1)
  add    $0x2,%ebp
L9:
  add    $0x1,%ebp
  mov    %ebx,%edx
  movslq %ebp,%rax
  movzbl (%rsp,%rax,1),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L46
L106:
  cmp    $0x25,%al
  je     L119
  mov    %al,-0x1(%r12,%rbx,1)
  jmp    L9
L62:
  mov    $0x0,%edx
L46:
  movslq %edx,%rdx
  movb   $0x0,(%r12,%rdx,1)
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    %r12,%rax
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dlcom_string_decode(char *src) {
  char tmp[4096];
  char *s = src;
  int i, j, k, t;
  for (i = j = k = 0; s[i] && s[i] != '\r' && s[i + 1] != '\n'; i++) {
    if (s[i] != '"')
      tmp[j++] = s[i];
    else {
      if (2 == ++k)
        break;
    }
  }
  tmp[j] = 0;
  s = src;
  for (i = j = k = 0; tmp[i]; i++, j++) {
    if (tmp[i] == '%') {
      t = tmp[i + 3];
      tmp[i + 3] = 0;
      k = strtol(tmp + i + 1, NULL, 16);
      s[j] = (char)k;
      tmp[i + 3] = t;
      i += 2;
    } else {
      s[j] = tmp[i];
    }
  }
  s[j] = 0;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dlcom_string_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L146
  cmp    $0xd,%al
  je     L146
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  xor    %esi,%esi
  jmp    L86
  nopw   0x0(%rax,%rax,1)
L132:
  movslq %esi,%rdi
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    %cl,(%rsp,%rdi,1)
  test   %al,%al
  je     L108
L88:
  cmp    $0xd,%al
  je     L108
L86:
  mov    %eax,%ecx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L108
  cmp    $0x22,%cl
  jne    L132
  cmp    $0x1,%r8d
  je     L108
  mov    $0x1,%r8d
  add    $0x1,%rdx
  test   %al,%al
  jne    L88
  nop
L108:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%ebx
  test   %bl,%bl
  je     L39
  mov    $0x1,%ebp
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L96
  nop
L7:
  add    $0x1,%eax
  mov    %bl,-0x1(%r12,%rbp,1)
  movslq %eax,%rdx
  movzbl (%rsp,%rdx,1),%ebx
  movslq %ebp,%rdx
  add    $0x1,%rbp
  test   %bl,%bl
  je     L65
L96:
  cmp    $0x25,%bl
  jne    L7
  lea    0x3(%rax),%r15d
  cltq
  mov    $0x10,%edx
  xor    %esi,%esi
  movslq %r15d,%r14
  lea    0x1(%r13,%rax,1),%rdi
  movzbl (%rsp,%r14,1),%ebx
  movb   $0x0,(%rsp,%r14,1)
  call   <strtol@plt>
  movslq %ebp,%rdx
  mov    %al,-0x1(%r12,%rbp,1)
  mov    %r15d,%eax
  add    $0x1,%rbp
  mov    %bl,(%rsp,%r14,1)
  test   %bl,%bl
  jne    L96
L65:
  add    %r12,%rdx
L148:
  movb   $0x0,(%rdx)
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x1018,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    %r12,%rdx
  jmp    L148
L146:
  xor    %esi,%esi
  jmp    L108
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dlcom_string_decode(char *src) {
  char tmp[4096];
  char *s = src;
  int i, j, k, t;
  for (i = j = k = 0; s[i] && s[i] != '\r' && s[i + 1] != '\n'; i++) {
    if (s[i] != '"')
      tmp[j++] = s[i];
    else {
      if (2 == ++k)
        break;
    }
  }
  tmp[j] = 0;
  s = src;
  for (i = j = k = 0; tmp[i]; i++, j++) {
    if (tmp[i] == '%') {
      t = tmp[i + 3];
      tmp[i + 3] = 0;
      k = strtol(tmp + i + 1, NULL, 16);
      s[j] = (char)k;
      tmp[i + 3] = t;
      i += 2;
    } else {
      s[j] = tmp[i];
    }
  }
  s[j] = 0;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dlcom_string_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L105
  cmp    $0xd,%al
  je     L105
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  xor    %esi,%esi
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L62:
  movslq %esi,%rdi
  add    $0x1,%rdx
  add    $0x1,%esi
  mov    %cl,(%rsp,%rdi,1)
  test   %al,%al
  je     L67
L22:
  cmp    $0xd,%al
  je     L67
L16:
  mov    %eax,%ecx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L67
  cmp    $0x22,%cl
  jne    L62
  cmp    $0x1,%r8d
  je     L67
  mov    $0x1,%r8d
  add    $0x1,%rdx
  test   %al,%al
  jne    L22
  nop
L67:
  movslq %esi,%rsi
  movb   $0x0,(%rsp,%rsi,1)
  movzbl (%rsp),%ebx
  test   %bl,%bl
  je     L104
  mov    $0x1,%ebp
  xor    %eax,%eax
  mov    %rsp,%r13
  nopl   (%rax)
L60:
  cmp    $0x25,%bl
  je     L94
  add    $0x1,%eax
  mov    %bl,-0x1(%r12,%rbp,1)
  movslq %eax,%rdx
  movzbl (%rsp,%rdx,1),%ebx
  movslq %ebp,%rdx
  add    $0x1,%rbp
  test   %bl,%bl
  jne    L60
L18:
  add    %r12,%rdx
L165:
  movb   $0x0,(%rdx)
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  add    $0x1018,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L94:
  lea    0x3(%rax),%r15d
  cltq
  mov    $0x10,%edx
  xor    %esi,%esi
  movslq %r15d,%r14
  lea    0x1(%r13,%rax,1),%rdi
  movzbl (%rsp,%r14,1),%ebx
  movb   $0x0,(%rsp,%r14,1)
  call   <strtol@plt>
  movslq %ebp,%rdx
  mov    %al,-0x1(%r12,%rbp,1)
  add    $0x1,%rbp
  mov    %bl,(%rsp,%r14,1)
  test   %bl,%bl
  je     L18
  mov    %r15d,%eax
  jmp    L60
L104:
  mov    %r12,%rdx
  jmp    L165
L105:
  xor    %esi,%esi
  jmp    L67
L123:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dlcom_string_decode(char *src) {
  char tmp[4096];
  char *s = src;
  int i, j, k, t;
  for (i = j = k = 0; s[i] && s[i] != '\r' && s[i + 1] != '\n'; i++) {
    if (s[i] != '"')
      tmp[j++] = s[i];
    else {
      if (2 == ++k)
        break;
    }
  }
  tmp[j] = 0;
  s = src;
  for (i = j = k = 0; tmp[i]; i++, j++) {
    if (tmp[i] == '%') {
      t = tmp[i + 3];
      tmp[i + 3] = 0;
      k = strtol(tmp + i + 1, NULL, 16);
      s[j] = (char)k;
      tmp[i + 3] = t;
      i += 2;
    } else {
      s[j] = tmp[i];
    }
  }
  s[j] = 0;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jsCalendarHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D23
data_type: string
name: read_data
arguments: label: D39
data_type: string
name: read_data
arguments: label: D20
data_type: string

tool: D14: <link rel='stylesheet' type='text/css' media='all' href='/js/calendar-blue.css'/>


tool: D23: <script type='text/javascript' src='/js/calendar.js'></script>


tool: D39: <script type='text/javascript' src='/js/calendar-en.js'></script>


tool: D20: <script type='text/javascript' src='/js/calendar-setup.js'></script>


assistant: ```c
void jsCalendarHeader(void) {
  printf("<link rel='stylesheet' type='text/css' media='all' href='/js/calendar-blue.css'/>\n");
  printf("<script type='text/javascript' src='/js/calendar.js'></script>\n");
  printf("<script type='text/javascript' src='/js/calendar-en.js'></script>\n");
  printf("<script type='text/javascript' src='/js/calendar-setup.js'></script>\n");
}
```