ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<NormalizeSignature>:
  endbr64
  push   %rbx
  mov    $0x4,%edx
  lea    D5(%rip),%rsi
  mov    %rdi,%rbx
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L4
  movb   $0x50,0x3(%rbx)
L4:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: RSD 

assistant: ```c
void NormalizeSignature(char *Signature) {
  if (!strncmp(Signature, "RSD ", 4)) {
    Signature[3] = 'P';
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LUSolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <LUSubstitute@plt>
  nop
  leave
  ret
```

assistant: ```c
extern void LUSolve(int n, double *LU, double *x, double *b) {
  LUSubstitute(n, LU, x, b);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LUSolve>:
  endbr64
  sub    $0x8,%rsp
  call   <LUSubstitute@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern void LUSolve(int n, double *LU, double *x, double *b) {
  LUSubstitute(n, LU, x, b);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<LUSolve>:
  endbr64
  jmp    1050 <LUSubstitute@plt>
```

assistant: ```c
extern void LUSolve(int n, double *LU, double *x, double *b) {
  LUSubstitute(n, LU, x, b);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<LUSolve>:
  endbr64
  jmp    1050 <LUSubstitute@plt>
```

assistant: ```c
extern void LUSolve(int n, double *LU, double *x, double *b) {
  LUSubstitute(n, LU, x, b);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<proc6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    %ax,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movswq -0x10(%rbp),%rax
  add    %rdx,%rax
  movsbq -0x14(%rbp),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long proc6(long p1, int p2, short p3, char p4, long *p5, long p6) {
  *p5 = p1 + p2 + p3 - p4;
  return *p5 + p6;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<proc6>:
  endbr64
  movslq %esi,%rsi
  add    %rdi,%rsi
  movswq %dx,%rdx
  lea    (%rsi,%rdx,1),%rax
  movsbq %cl,%rcx
  sub    %rcx,%rax
  mov    %rax,(%r8)
  add    %r9,%rax
  ret
```

assistant: ```c
long proc6(long p1, int p2, short p3, char p4, long *p5, long p6) {
  *p5 = p1 + p2 + p3 - p4;
  return *p5 + p6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proc6>:
  endbr64
  movslq %esi,%rsi
  movswq %dx,%rdx
  movsbq %cl,%rcx
  add    %rdi,%rsi
  lea    (%rsi,%rdx,1),%rax
  sub    %rcx,%rax
  mov    %rax,(%r8)
  add    %r9,%rax
  ret
```

assistant: ```c
long proc6(long p1, int p2, short p3, char p4, long *p5, long p6) {
  *p5 = p1 + p2 + p3 - p4;
  return *p5 + p6;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<proc6>:
  endbr64
  movslq %esi,%rsi
  movswq %dx,%rdx
  movsbq %cl,%rcx
  add    %rdi,%rsi
  lea    (%rsi,%rdx,1),%rax
  sub    %rcx,%rax
  mov    %rax,(%r8)
  add    %r9,%rax
  ret
```

assistant: ```c
long proc6(long p1, int p2, short p3, char p4, long *p5, long p6) {
  *p5 = p1 + p2 + p3 - p4;
  return *p5 + p6;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rop3_229_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_229_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & T;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_229_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  or     (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  not    %esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_229_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & T;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rop3_229_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  or     (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_229_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & T;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_229_1_0>:
  endbr64
  mov    %esi,%eax
  mov    %edx,%esi
  and    %eax,%esi
  or     (%rdi),%sil
  xor    %edx,%esi
  or     %eax,%esi
  and    (%rdi),%al
  not    %esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_229_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = S & T;
  stk2 = *D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L3
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <get_mime@plt>
  mov    %eax,%edi
  call   <putmime@plt>
L3:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: %s : 

assistant: ```c
int main(int argc, char **argv) {
  while (--argc) {
    printf("%s : ", argv[argc]);
    putmime(get_mime(argv[argc]));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x1,%edi
  je     L12
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  movslq %edi,%rbx
  lea    D5(%rip),%r12
L18:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <get_mime@plt>
  mov    %eax,%edi
  call   <putmime@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jne    L18
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: %s : 

assistant: ```c
int main(int argc, char **argv) {
  while (--argc) {
    printf("%s : ", argv[argc]);
    putmime(get_mime(argv[argc]));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x1,%edi
  je     L19
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  nopw   0x0(%rax,%rax,1)
L15:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <get_mime@plt>
  mov    %eax,%edi
  call   <putmime@plt>
  test   %ebx,%ebx
  jne    L15
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L19:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: %s : 

assistant: ```c
int main(int argc, char **argv) {
  while (--argc) {
    printf("%s : ", argv[argc]);
    putmime(get_mime(argv[argc]));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x1,%edi
  je     L12
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <get_mime@plt>
  mov    %eax,%edi
  call   <putmime@plt>
  test   %ebx,%ebx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L12:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %s : 

assistant: ```c
int main(int argc, char **argv) {
  while (--argc) {
    printf("%s : ", argv[argc]);
    putmime(get_mime(argv[argc]));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DLLUnRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ASF_Done@plt>
  mov    $0x0,%eax
  call   <AVI_Done@plt>
  mov    $0x0,%eax
  call   <WAV_Done@plt>
  mov    $0x0,%eax
  call   <MP4_Done@plt>
  mov    $0x0,%eax
  call   <MPG_Done@plt>
  mov    $0x0,%eax
  call   <NSV_Done@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DLLUnRegister() {
  ASF_Done();
  AVI_Done();
  WAV_Done();
  MP4_Done();
  MPG_Done();
  NSV_Done();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<DLLUnRegister>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ASF_Done@plt>
  mov    $0x0,%eax
  call   <AVI_Done@plt>
  mov    $0x0,%eax
  call   <WAV_Done@plt>
  mov    $0x0,%eax
  call   <MP4_Done@plt>
  mov    $0x0,%eax
  call   <MPG_Done@plt>
  mov    $0x0,%eax
  call   <NSV_Done@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void DLLUnRegister() {
  ASF_Done();
  AVI_Done();
  WAV_Done();
  MP4_Done();
  MPG_Done();
  NSV_Done();
}
```
user: What is the c source code of the assembly code below?

```asm
<DLLUnRegister>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ASF_Done@plt>
  xor    %eax,%eax
  call   <AVI_Done@plt>
  xor    %eax,%eax
  call   <WAV_Done@plt>
  xor    %eax,%eax
  call   <MP4_Done@plt>
  xor    %eax,%eax
  call   <MPG_Done@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <NSV_Done@plt>
```

assistant: ```c
void DLLUnRegister() {
  ASF_Done();
  AVI_Done();
  WAV_Done();
  MP4_Done();
  MPG_Done();
  NSV_Done();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DLLUnRegister>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ASF_Done@plt>
  xor    %eax,%eax
  call   <AVI_Done@plt>
  xor    %eax,%eax
  call   <WAV_Done@plt>
  xor    %eax,%eax
  call   <MP4_Done@plt>
  xor    %eax,%eax
  call   <MPG_Done@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <NSV_Done@plt>
```

assistant: ```c
void DLLUnRegister() {
  ASF_Done();
  AVI_Done();
  WAV_Done();
  MP4_Done();
  MPG_Done();
  NSV_Done();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L11
L47:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L30
L11:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
L30:
  pop    %rbp
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *p = string;
  while (*p) {
    if (*p == '\n' || *p == '\r') {
      *p = '\0';
      return;
    }
    p++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_newline>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
L28:
  cmp    $0xa,%al
  je     L13
  cmp    $0xd,%al
  je     L13
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
L16:
  ret
L13:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *p = string;
  while (*p) {
    if (*p == '\n' || *p == '\r') {
      *p = '\0';
      return;
    }
    p++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<remove_newline>:
  endbr64
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L23:
  cmp    $0xa,%al
  je     L38
  cmp    $0xd,%al
  je     L38
  add    $0x1,%rdi
L11:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
  ret
  nopl   0x0(%rax)
L38:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *p = string;
  while (*p) {
    if (*p == '\n' || *p == '\r') {
      *p = '\0';
      return;
    }
    p++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remove_newline>:
  endbr64
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L1:
  cmp    $0xa,%al
  je     L14
  cmp    $0xd,%al
  je     L14
  add    $0x1,%rdi
L29:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
  ret
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *string) {
  char *p = string;
  while (*p) {
    if (*p == '\n' || *p == '\r') {
      *p = '\0';
      return;
    }
    p++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ilog10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L33
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L13
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L33:
  cmpq   $0x13,-0x10(%rbp)
  jbe    L4
  jmp    L48
L13:
  nop
L48:
  cmpq   $0x0,-0x10(%rbp)
  je     L39
  mov    -0x10(%rbp),%rax
  jmp    L42
L39:
  mov    $0x1,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
size_t ilog10(unsigned long num) {
  size_t i;
  unsigned long p = 1;
  for (i = 0; i < ((sizeof(unsigned long) << 1) + (sizeof(unsigned long) >> 1)); i++) {
    if (num < p)
      break;
    p *= 10;
  }
  return !i ? 1 : i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ilog10>:
  endbr64
  test   %rdi,%rdi
  je     L33
  mov    $0x1,%ecx
  mov    $0x0,%eax
L23:
  lea    (%rcx,%rcx,4),%rdx
  add    %rdx,%rdx
  mov    %rdx,%rcx
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jb     L39
  cmp    $0x13,%rax
  jbe    L23
L39:
  test   %rax,%rax
  mov    $0x1,%edx
  cmove  %rdx,%rax
  ret
L33:
  mov    %rdi,%rax
  jmp    L39
```

assistant: ```c
size_t ilog10(unsigned long num) {
  size_t i;
  unsigned long p = 1;
  for (i = 0; i < ((sizeof(unsigned long) << 1) + (sizeof(unsigned long) >> 1)); i++) {
    if (num < p)
      break;
    p *= 10;
  }
  return !i ? 1 : i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ilog10>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L14
  xchg   %ax,%ax
L24:
  lea    (%rax,%rax,4),%rax
  add    $0x1,%r8
  add    %rax,%rax
  cmp    $0x14,%r8
  je     L28
L14:
  cmp    %rax,%rdi
  jae    L24
  test   %r8,%r8
  mov    $0x1,%eax
  cmove  %rax,%r8
L28:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t ilog10(unsigned long num) {
  size_t i;
  unsigned long p = 1;
  for (i = 0; i < ((sizeof(unsigned long) << 1) + (sizeof(unsigned long) >> 1)); i++) {
    if (num < p)
      break;
    p *= 10;
  }
  return !i ? 1 : i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ilog10>:
  endbr64
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L19
  xchg   %ax,%ax
L4:
  lea    (%rax,%rax,4),%rax
  add    $0x1,%r8
  add    %rax,%rax
  cmp    $0x14,%r8
  je     L13
L19:
  cmp    %rax,%rdi
  jae    L4
  test   %r8,%r8
  mov    $0x1,%eax
  cmove  %rax,%r8
L13:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t ilog10(unsigned long num) {
  size_t i;
  unsigned long p = 1;
  for (i = 0; i < ((sizeof(unsigned long) << 1) + (sizeof(unsigned long) >> 1)); i++) {
    if (num < p)
      break;
    p *= 10;
  }
  return !i ? 1 : i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minimoVETOR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x1c(%rbp)
  jmp    L7
L24:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L28
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L28:
  subl   $0x1,-0x1c(%rbp)
L7:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L24
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int minimoVETOR(int vector[], int n) {
  int res;
  --n;
  res = vector[n];
  for (--n; n >= 0; --n)
    if (vector[n] < res)
      res = vector[n];
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minimoVETOR>:
  endbr64
  mov    %esi,%eax
  lea    -0x1(%rsi),%edx
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%edx
  sub    $0x2,%eax
  js     L14
  cltq
L8:
  mov    (%rdi,%rax,4),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L8
L14:
  mov    %edx,%eax
  ret
```

assistant: ```c
int minimoVETOR(int vector[], int n) {
  int res;
  --n;
  res = vector[n];
  for (--n; n >= 0; --n)
    if (vector[n] < res)
      res = vector[n];
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<minimoVETOR>:
  endbr64
  lea    -0x1(%rsi),%edx
  mov    %esi,%eax
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%r8d
  sub    $0x2,%eax
  js     L4
  cltq
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rdi,%rax,4),%edx
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L1
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int minimoVETOR(int vector[], int n) {
  int res;
  --n;
  res = vector[n];
  for (--n; n >= 0; --n)
    if (vector[n] < res)
      res = vector[n];
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<minimoVETOR>:
  endbr64
  lea    -0x1(%rsi),%r8d
  mov    %rdi,%rcx
  movslq %r8d,%rax
  lea    0x0(,%rax,4),%rdx
  mov    (%rdi,%rax,4),%eax
  sub    $0x2,%esi
  js     L20
  cmp    $0x2,%esi
  jbe    L26
  lea    -0x10(%rdi,%rdx,1),%rdx
  mov    %r8d,%edi
  movd   %eax,%xmm3
  shr    $0x2,%edi
  lea    -0x10(%rdx),%rax
  pshufd $0x0,%xmm3,%xmm0
  lea    -0x1(%rdi),%r9d
  mov    %rax,%rdi
  shl    $0x4,%r9
  sub    %r9,%rdi
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L57:
  sub    $0x10,%rax
L14:
  movdqu (%rdx),%xmm2
  mov    %rax,%rdx
  pshufd $0x1b,%xmm2,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L57
  movdqa %xmm0,%xmm2
  mov    %r8d,%edx
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%edx
  movdqa %xmm2,%xmm1
  sub    %edx,%esi
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %edx,%r8d
  je     L20
L26:
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rdi
  mov    (%rcx,%rdx,4),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  test   %esi,%esi
  je     L20
  mov    -0x4(%rcx,%rdi,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cmp    $0x1,%esi
  je     L20
  mov    -0x8(%rcx,%rdi,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
L20:
  ret
```

assistant: ```c
int minimoVETOR(int vector[], int n) {
  int res;
  --n;
  res = vector[n];
  for (--n; n >= 0; --n)
    if (vector[n] < res)
      res = vector[n];
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aes_ctr_cbuf_inc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0xf,-0x4(%rbp)
  jmp    L20
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  add    $0x1,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  subl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  jmp    L22
L10:
  nop
L22:
  pop    %rbp
  ret
```

assistant: ```c
void aes_ctr_cbuf_inc(unsigned char *cbuf) {
  int i = 15;
  while (i >= 0) {
    cbuf[i]++;
    if (cbuf[i])
      return;
    i--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_ctr_cbuf_inc>:
  endbr64
  lea    0xf(%rdi),%rdx
  jmp    L0
L17:
  mov    %rax,%rdx
L0:
  movzbl (%rdx),%eax
  add    $0x1,%eax
  mov    %al,(%rdx)
  test   %al,%al
  jne    L23
  lea    -0x1(%rdx),%rax
  cmp    %rdi,%rdx
  jne    L17
L23:
  ret
```

assistant: ```c
void aes_ctr_cbuf_inc(unsigned char *cbuf) {
  int i = 15;
  while (i >= 0) {
    cbuf[i]++;
    if (cbuf[i])
      return;
    i--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<aes_ctr_cbuf_inc>:
  endbr64
  lea    0xf(%rdi),%rdx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rax,%rdx
L11:
  addb   $0x1,(%rdx)
  jne    L29
  lea    -0x1(%rdx),%rax
  cmp    %rdi,%rdx
  jne    L27
L29:
  ret
```

assistant: ```c
void aes_ctr_cbuf_inc(unsigned char *cbuf) {
  int i = 15;
  while (i >= 0) {
    cbuf[i]++;
    if (cbuf[i])
      return;
    i--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aes_ctr_cbuf_inc>:
  endbr64
  addb   $0x1,0xf(%rdi)
  jne    L122
  addb   $0x1,0xe(%rdi)
  jne    L122
  addb   $0x1,0xd(%rdi)
  jne    L122
  addb   $0x1,0xc(%rdi)
  jne    L122
  addb   $0x1,0xb(%rdi)
  jne    L122
  addb   $0x1,0xa(%rdi)
  jne    L122
  addb   $0x1,0x9(%rdi)
  jne    L122
  addb   $0x1,0x8(%rdi)
  jne    L122
  addb   $0x1,0x7(%rdi)
  jne    L122
  addb   $0x1,0x6(%rdi)
  jne    L122
  addb   $0x1,0x5(%rdi)
  jne    L122
  addb   $0x1,0x4(%rdi)
  jne    L122
  addb   $0x1,0x3(%rdi)
  jne    L122
  addb   $0x1,0x2(%rdi)
  jne    L122
  addb   $0x1,0x1(%rdi)
  jne    L122
  addb   $0x1,(%rdi)
L122:
  ret
```

assistant: ```c
void aes_ctr_cbuf_inc(unsigned char *cbuf) {
  int i = 15;
  while (i >= 0) {
    cbuf[i]++;
    if (cbuf[i])
      return;
    i--;
  }
}
```