ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<compute_fst>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x53,%dl
  je     L118
  jg     L22
  cmp    $0x4d,%dl
  je     L23
  cmp    $0x50,%dl
  jne    L4
  mov    $0x2,%eax
L2:
  cmpb   $0x4f,0x1(%rdi)
  jne    L4
  mov    $0x2,%edx
L21:
  cmpb   $0x50,(%rdi,%rdx,1)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  nopl   (%rax)
L22:
  mov    $0x5,%eax
  cmp    $0x54,%dl
  je     L2
L4:
  mov    $0xffffffff,%eax
L50:
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmpb   $0x4f,0x1(%rdi)
  jne    L4
  movzbl 0x2(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x50,%dl
  je     L50
  mov    $0xffffffff,%eax
  cmp    $0x54,%dl
  jne    L50
  xor    %eax,%eax
  cmpb   $0x48,0x3(%rdi)
  sete   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax)
L118:
  cmpb   $0x54,0x1(%rdi)
  jne    L4
  movzbl 0x2(%rdi),%eax
  cmp    $0x41,%al
  je     L18
  cmp    $0x4f,%al
  jne    L4
  mov    $0x3,%edx
  mov    $0x4,%eax
  jmp    L21
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  cmpb   $0x52,0x3(%rdi)
  sete   %al
  lea    -0x1(,%rax,4),%eax
  ret
```

assistant: ```c
int compute_fst(const char *token) {
  int pos = 0;
  int total = 0;
NODE_0:
  switch (token[pos++]) {
  case 'M':
    goto NODE_1;
  case 'P':
    total += 2;
    goto NODE_4;
  case 'T':
    total += 5;
    goto NODE_4;
  case 'S':
    total += 3;
    goto NODE_6;
  default:
    return -1;
  }
NODE_1:
  switch (token[pos++]) {
  case 'O':
    goto NODE_2;
  default:
    return -1;
  }
NODE_2:
  switch (token[pos++]) {
  case 'T':
    total += 1;
    goto NODE_3;
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_3:
  switch (token[pos++]) {
  case 'H':
    goto NODE_9;
  default:
    return -1;
  }
NODE_4:
  switch (token[pos++]) {
  case 'O':
    goto NODE_5;
  default:
    return -1;
  }
NODE_5:
  switch (token[pos++]) {
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_6:
  switch (token[pos++]) {
  case 'T':
    goto NODE_7;
  default:
    return -1;
  }
NODE_7:
  switch (token[pos++]) {
  case 'O':
    total += 1;
    goto NODE_5;
  case 'A':
    goto NODE_8;
  default:
    return -1;
  }
NODE_8:
  switch (token[pos++]) {
  case 'R':
    goto NODE_9;
  default:
    return -1;
  }
NODE_9:
  goto END;
END:
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<compute_fst>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x53,%dl
  je     L122
  jg     L64
  cmp    $0x4d,%dl
  je     L69
  cmp    $0x50,%dl
  jne    L5
  mov    $0x2,%eax
L54:
  cmpb   $0x4f,0x1(%rdi)
  jne    L5
  mov    $0x2,%edx
L28:
  cmpb   $0x50,(%rdi,%rdx,1)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  nopl   (%rax)
L64:
  mov    $0x5,%eax
  cmp    $0x54,%dl
  je     L54
L5:
  mov    $0xffffffff,%eax
L114:
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  cmpb   $0x4f,0x1(%rdi)
  jne    L5
  movzbl 0x2(%rdi),%edx
  xor    %eax,%eax
  cmp    $0x50,%dl
  je     L114
  mov    $0xffffffff,%eax
  cmp    $0x54,%dl
  jne    L114
  xor    %eax,%eax
  cmpb   $0x48,0x3(%rdi)
  sete   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopl   0x0(%rax)
L122:
  cmpb   $0x54,0x1(%rdi)
  jne    L5
  movzbl 0x2(%rdi),%eax
  cmp    $0x41,%al
  je     L105
  cmp    $0x4f,%al
  jne    L5
  mov    $0x3,%edx
  mov    $0x4,%eax
  jmp    L28
  xchg   %ax,%ax
L105:
  xor    %eax,%eax
  cmpb   $0x52,0x3(%rdi)
  sete   %al
  lea    -0x1(,%rax,4),%eax
  ret
```

assistant: ```c
int compute_fst(const char *token) {
  int pos = 0;
  int total = 0;
NODE_0:
  switch (token[pos++]) {
  case 'M':
    goto NODE_1;
  case 'P':
    total += 2;
    goto NODE_4;
  case 'T':
    total += 5;
    goto NODE_4;
  case 'S':
    total += 3;
    goto NODE_6;
  default:
    return -1;
  }
NODE_1:
  switch (token[pos++]) {
  case 'O':
    goto NODE_2;
  default:
    return -1;
  }
NODE_2:
  switch (token[pos++]) {
  case 'T':
    total += 1;
    goto NODE_3;
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_3:
  switch (token[pos++]) {
  case 'H':
    goto NODE_9;
  default:
    return -1;
  }
NODE_4:
  switch (token[pos++]) {
  case 'O':
    goto NODE_5;
  default:
    return -1;
  }
NODE_5:
  switch (token[pos++]) {
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_6:
  switch (token[pos++]) {
  case 'T':
    goto NODE_7;
  default:
    return -1;
  }
NODE_7:
  switch (token[pos++]) {
  case 'O':
    total += 1;
    goto NODE_5;
  case 'A':
    goto NODE_8;
  default:
    return -1;
  }
NODE_8:
  switch (token[pos++]) {
  case 'R':
    goto NODE_9;
  default:
    return -1;
  }
NODE_9:
  goto END;
END:
  return total;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x1,%edx
  jmp    L25
L61:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L61
  mov    $0x0,%eax
L20:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L20
L42:
  add    $0x1,%edx
  cmp    $0x64,%edx
  je     L13
L25:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L61
  jmp    L42
L13:
  mov    $0x64,%eax
L56:
  sub    $0x1,%eax
  jne    L56
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int k, i;
  int y[100][100];
  int sum[100][100];
  int beta[100];
  int alpha[100];
  int r[100];
  int out[100];
  y[0][0] = r[0];
  beta[0] = 1;
  alpha[0] = r[0];
  for (k = 1; k <= 100 - 1; k++) {
    beta[k] = beta[k - 1] - alpha[k - 1] * alpha[k - 1] * beta[k - 1];
    sum[0][k] = r[k];
    for (i = 0; i <= k - 1; i++) {
      sum[i + 1][k] = sum[i][k] + r[k - i - 1] * y[i][k - 1];
    }
    alpha[k] = -sum[k][k] * beta[k];
    for (i = 0; i <= k - 1; i++) {
      y[i][k] = y[i][k - 1] + alpha[k] * y[k - i - 1][k - 1];
    }
    y[k][k] = alpha[k];
  }
  for (i = 0; i <= 100 - 1; i++) {
    out[i] = y[i][100 - 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int k, i;
  int y[100][100];
  int sum[100][100];
  int beta[100];
  int alpha[100];
  int r[100];
  int out[100];
  y[0][0] = r[0];
  beta[0] = 1;
  alpha[0] = r[0];
  for (k = 1; k <= 100 - 1; k++) {
    beta[k] = beta[k - 1] - alpha[k - 1] * alpha[k - 1] * beta[k - 1];
    sum[0][k] = r[k];
    for (i = 0; i <= k - 1; i++) {
      sum[i + 1][k] = sum[i][k] + r[k - i - 1] * y[i][k - 1];
    }
    alpha[k] = -sum[k][k] * beta[k];
    for (i = 0; i <= k - 1; i++) {
      y[i][k] = y[i][k - 1] + alpha[k] * y[k - i - 1][k - 1];
    }
    y[k][k] = alpha[k];
  }
  for (i = 0; i <= 100 - 1; i++) {
    out[i] = y[i][100 - 1];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int k, i;
  int y[100][100];
  int sum[100][100];
  int beta[100];
  int alpha[100];
  int r[100];
  int out[100];
  y[0][0] = r[0];
  beta[0] = 1;
  alpha[0] = r[0];
  for (k = 1; k <= 100 - 1; k++) {
    beta[k] = beta[k - 1] - alpha[k - 1] * alpha[k - 1] * beta[k - 1];
    sum[0][k] = r[k];
    for (i = 0; i <= k - 1; i++) {
      sum[i + 1][k] = sum[i][k] + r[k - i - 1] * y[i][k - 1];
    }
    alpha[k] = -sum[k][k] * beta[k];
    for (i = 0; i <= k - 1; i++) {
      y[i][k] = y[i][k - 1] + alpha[k] * y[k - i - 1][k - 1];
    }
    y[k][k] = alpha[k];
  }
  for (i = 0; i <= 100 - 1; i++) {
    out[i] = y[i][100 - 1];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strDup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: strdup failed

assistant: ```c
char *strDup(char const *str) {
  char *copy = malloc(strlen(str) + 1);
  if (!copy) {
    fatal("strdup failed");
  }
  strcpy(copy, str);
  return copy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strDup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D7(%rip),%rdi
  call   <fatal@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: strdup failed

assistant: ```c
char *strDup(char const *str) {
  char *copy = malloc(strlen(str) + 1);
  if (!copy) {
    fatal("strdup failed");
  }
  strcpy(copy, str);
  return copy;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strDup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L5:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D4(%rip),%rdi
  call   <fatal@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: strdup failed

assistant: ```c
char *strDup(char const *str) {
  char *copy = malloc(strlen(str) + 1);
  if (!copy) {
    fatal("strdup failed");
  }
  strcpy(copy, str);
  return copy;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strDup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    D8(%rip),%rdi
  call   <fatal@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: strdup failed

assistant: ```c
char *strDup(char const *str) {
  char *copy = malloc(strlen(str) + 1);
  if (!copy) {
    fatal("strdup failed");
  }
  strcpy(copy, str);
  return copy;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L46
  mov    -0xc(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L6
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x3,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L42
L6:
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl -0xe(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L42
L46:
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  lea    -0xc(%rbp),%rdx
  add    $0x1,%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
L42:
  mov    -0xc(%rbp),%eax
  lea    0x4191d562(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      if ((state[0UL] >> 3U) & 1U) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
      }
    } else {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 119333056UL) + 980743330U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  test   $0x10,%al
  je     L5
  push   %rbx
  mov    %eax,%edx
  test   $0x8,%al
  je     L8
  mov    %eax,%ebx
  sar    $0x18,%ebx
  mov    %bl,%dh
  mov    %eax,%esi
  shl    $0x18,%esi
  and    $0xffffff,%edx
  or     %esi,%edx
  movsbl %ah,%eax
  mov    %al,%dl
L22:
  add    $0x4191d562,%edx
  mov    %edx,(%rcx)
  pop    %rbx
  ret
L8:
  mov    %eax,%ebx
  shl    $0x8,%ebx
  sar    $0x18,%ebx
  mov    %bl,%dh
  movzbl %ah,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %eax,%edx
  jmp    L22
L5:
  movzbl %ah,%esi
  shl    $0x10,%esi
  mov    %eax,%edx
  and    $0xff00ffff,%edx
  or     %esi,%edx
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %al,%dh
  add    $0x4191d562,%edx
  mov    %edx,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      if ((state[0UL] >> 3U) & 1U) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
      }
    } else {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 119333056UL) + 980743330U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x136ff696,%edx
  mov    %edx,%eax
  movsbl %dh,%ecx
  test   $0x10,%al
  je     L16
  test   $0x8,%al
  je     L7
  push   %rbx
  mov    %edx,%ebx
  shl    $0x18,%edx
  sar    $0x18,%ebx
  mov    %bl,%ah
  pop    %rbx
  and    $0xffffff,%eax
  or     %edx,%eax
  mov    %cl,%al
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  movzbl %cl,%ecx
  and    $0xff00ffff,%eax
  shl    $0x8,%edx
  shl    $0x10,%ecx
  sar    $0x18,%edx
  or     %ecx,%eax
  mov    %dl,%ah
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L7:
  shl    $0x8,%edx
  movzbl %cl,%ecx
  sar    $0x18,%edx
  shl    $0x10,%ecx
  mov    %dl,%ah
  and    $0xff00ffff,%eax
  or     %ecx,%eax
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      if ((state[0UL] >> 3U) & 1U) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
      }
    } else {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 119333056UL) + 980743330U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x136ff696,%edx
  mov    %edx,%eax
  movsbl %dh,%ecx
  test   $0x10,%al
  je     L6
  test   $0x8,%al
  je     L18
  push   %rbx
  mov    %edx,%edi
  xor    %ebx,%ebx
  and    $0xffffff,%eax
  shl    $0x18,%edi
  mov    %cl,%bl
  sar    $0x18,%edx
  mov    %dl,%bh
  or     %edi,%eax
  mov    %bx,%ax
  pop    %rbx
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl %cl,%ecx
  and    $0xff00ffff,%eax
  shl    $0x8,%edx
  shl    $0x10,%ecx
  sar    $0x18,%edx
  or     %ecx,%eax
  mov    %dl,%ah
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L18:
  shl    $0x8,%edx
  movzbl %cl,%ecx
  sar    $0x18,%edx
  shl    $0x10,%ecx
  mov    %dl,%ah
  and    $0xff00ffff,%eax
  or     %ecx,%eax
  add    $0x4191d562,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  char copy11;
  char copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    if ((state[0UL] >> 4U) & 1U) {
      if ((state[0UL] >> 3U) & 1U) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = copy11;
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
      } else {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy12;
      }
    } else {
      copy13 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy13;
    }
    output[0UL] = (state[0UL] + 119333056UL) + 980743330U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sph2rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdi,-0x38(%rbp)
  movsd  D2(%rip),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x40(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mulsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  lea    0x10(%rax),%rbx
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: f64

tool: D2: 1.5707963267948966

assistant: ```c
void sph2rec(double lon, double lat, double *v) {
  double theta;
  theta = 1.5707963267948966 - lat;
  v[0] = sin(theta) * cos(lon);
  v[1] = sin(theta) * sin(lon);
  v[2] = cos(theta);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sph2rec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm1,%r15
  mov    %rdi,%rbx
  lea    0x8(%rsp),%r13
  mov    %rsp,%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  mov    (%rsp),%r12
  mov    0x8(%rsp),%rbp
  movsd  D6(%rip),%xmm0
  movq   %r15,%xmm3
  subsd  %xmm3,%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm0
  movq   %r12,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movq   %rbp,%xmm2
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rbx)
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: f64

tool: D6: 1.5707963267948966

assistant: ```c
void sph2rec(double lon, double lat, double *v) {
  double theta;
  theta = 1.5707963267948966 - lat;
  v[0] = sin(theta) * cos(lon);
  v[1] = sin(theta) * sin(lon);
  v[2] = cos(theta);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sph2rec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm1,0x10(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  movsd  D4(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  subsd  0x10(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm1,(%rbx)
  movsd  %xmm0,0x8(%rbx)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: f64

tool: D4: 1.5707963267948966

assistant: ```c
void sph2rec(double lon, double lat, double *v) {
  double theta;
  theta = 1.5707963267948966 - lat;
  v[0] = sin(theta) * cos(lon);
  v[1] = sin(theta) * sin(lon);
  v[2] = cos(theta);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sph2rec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  lea    0x28(%rsp),%rbp
  lea    0x20(%rsp),%r12
  movsd  %xmm1,0x8(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sincos@plt>
  movsd  D5(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  subsd  0x8(%rsp),%xmm0
  movsd  0x20(%rsp),%xmm1
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  unpcklpd %xmm0,%xmm0
  unpcklpd %xmm2,%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rbx)
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,0x10(%rbx)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: f64

tool: D5: 1.5707963267948966

assistant: ```c
void sph2rec(double lon, double lat, double *v) {
  double theta;
  theta = 1.5707963267948966 - lat;
  v[0] = sin(theta) * cos(lon);
  v[1] = sin(theta) * sin(lon);
  v[2] = cos(theta);
}
```