ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<hint_msg>:
  endbr64
  sub    $0x8,%rsp
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D35
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D35: Welcome;


tool: D22: This is a basic program for adding, subtracting, and multiplying polynomials.


tool: D37: A polynomial is a function, that takes the general form of:
	->	a(n)*x^(n) + a(n-1)*x^(n-1) + a(n-2)*x^(n-2) + ... + a(0)
Where:	a(i) is an arbitrary constant, positive or negative, with or without a fraction, representing the coefficient of the unknown X.
	n is a positive integer, representing the power of the unknown X.



tool: D21: 	*Notes on input*
-> Order of the terms does not need to be decending or ascending based on it's power.
-> Presence of the brackets { ( and ) } is not neccessary.
-> Presence of '*' (multiplied by) sign between the coefficient and the unknow X is not neccessary.
-> Presence of '^' (raised to the power of) sign is required. Otherwise the input would be concidered incorrect.



tool: D5: 		****


assistant: ```c
void hint_msg() {
  printf("Welcome;\n");
  printf("This is a basic program for adding, subtracting, and multiplying polynomials.\n");
  printf("A polynomial is a function, that takes the general form of:\n\t->\ta(n)*x^(n) + a(n-1)*x^(n-1) + a(n-2)*x^(n-2) + ... + a(0)\nWhere:\ta(i) is an arbitrary constant, positive or negative, with or without a fraction, representing the coefficient of the unknown X.\n\tn is a positive integer, representing the power of the unknown X.\n\n");
  printf("\t*Notes on input*\n-> Order of the terms does not need to be decending or ascending based on it's power.\n-> Presence of the brackets { ( and ) } is not neccessary.\n-> Presence of '*' (multiplied by) sign between the coefficient and the unknow X is not neccessary.\n-> Presence of '^' (raised to the power of) sign is required. Otherwise the input would be concidered incorrect.\n\n");
  printf("\t\t****\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hint_msg>:
  endbr64
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
type: string
name: parse_data
arguments: data_tag: D45
type: string
name: parse_data
arguments: data_tag: D42
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D4
type: string

tool: D37: Welcome;


tool: D45: This is a basic program for adding, subtracting, and multiplying polynomials.


tool: D42: A polynomial is a function, that takes the general form of:
	->	a(n)*x^(n) + a(n-1)*x^(n-1) + a(n-2)*x^(n-2) + ... + a(0)
Where:	a(i) is an arbitrary constant, positive or negative, with or without a fraction, representing the coefficient of the unknown X.
	n is a positive integer, representing the power of the unknown X.



tool: D38: 	*Notes on input*
-> Order of the terms does not need to be decending or ascending based on it's power.
-> Presence of the brackets { ( and ) } is not neccessary.
-> Presence of '*' (multiplied by) sign between the coefficient and the unknow X is not neccessary.
-> Presence of '^' (raised to the power of) sign is required. Otherwise the input would be concidered incorrect.



tool: D4: 		****


assistant: ```c
void hint_msg() {
  printf("Welcome;\n");
  printf("This is a basic program for adding, subtracting, and multiplying polynomials.\n");
  printf("A polynomial is a function, that takes the general form of:\n\t->\ta(n)*x^(n) + a(n-1)*x^(n-1) + a(n-2)*x^(n-2) + ... + a(0)\nWhere:\ta(i) is an arbitrary constant, positive or negative, with or without a fraction, representing the coefficient of the unknown X.\n\tn is a positive integer, representing the power of the unknown X.\n\n");
  printf("\t*Notes on input*\n-> Order of the terms does not need to be decending or ascending based on it's power.\n-> Presence of the brackets { ( and ) } is not neccessary.\n-> Presence of '*' (multiplied by) sign between the coefficient and the unknow X is not neccessary.\n-> Presence of '^' (raised to the power of) sign is required. Otherwise the input would be concidered incorrect.\n\n");
  printf("\t\t****\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x46,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <initList@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 70;
  initList(size);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%edi
  call   <initList@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 70;
  initList(size);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%edi
  call   <initList@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 70;
  initList(size);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x46,%edi
  call   <initList@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int size = 70;
  initList(size);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<item_type_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L57
  mov    $0x1,%eax
  jmp    L7
L57:
  mov    -0x8(%rbp),%rax
  lea    D44(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
  mov    $0x2,%eax
  jmp    L7
L61:
  mov    -0x8(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L66
  mov    $0x3,%eax
  jmp    L7
L66:
  mov    -0x8(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L90
  mov    $0x4,%eax
  jmp    L7
L90:
  mov    -0x8(%rbp),%rax
  lea    D34(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x5,%eax
  jmp    L7
L53:
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D44
data_type: string
name: disassemble_data
arguments: tag: D21
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string

tool: D29: hptn

tool: D44: key

tool: D21: dcat

tool: D36: shtg

tool: D34: shtg_ammo

assistant: ```c
unsigned int item_type_id(const char *name) {
  if (strcmp(name, "hptn") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "key") == 0) {
    return 0x00000002;
  } else if (strcmp(name, "dcat") == 0) {
    return 0x00000003;
  } else if (strcmp(name, "shtg") == 0) {
    return 0x00000004;
  } else if (strcmp(name, "shtg_ammo") == 0) {
    return 0x00000005;
  }
  return 0xFFFFFFFF;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<item_type_id>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D28(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L15
L2:
  pop    %rbx
  ret
L15:
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L2
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x3,%eax
  test   %rdx,%rdx
  je     L2
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x4,%eax
  test   %rdx,%rdx
  je     L2
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string
name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D28: hptn

tool: D17: key

tool: D1: dcat

tool: D13: shtg

tool: D2: shtg_ammo

assistant: ```c
unsigned int item_type_id(const char *name) {
  if (strcmp(name, "hptn") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "key") == 0) {
    return 0x00000002;
  } else if (strcmp(name, "dcat") == 0) {
    return 0x00000003;
  } else if (strcmp(name, "shtg") == 0) {
    return 0x00000004;
  } else if (strcmp(name, "shtg_ammo") == 0) {
    return 0x00000005;
  }
  return 0xFFFFFFFF;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<item_type_id>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L18
L36:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L36
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L36
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L36
  mov    %rbp,%rdi
  lea    D28(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D32
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D33
datatype: string
name: retrieve_data
arguments: tag: D34
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string

tool: D32: hptn

tool: D30: key

tool: D33: dcat

tool: D34: shtg

tool: D28: shtg_ammo

assistant: ```c
unsigned int item_type_id(const char *name) {
  if (strcmp(name, "hptn") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "key") == 0) {
    return 0x00000002;
  } else if (strcmp(name, "dcat") == 0) {
    return 0x00000003;
  } else if (strcmp(name, "shtg") == 0) {
    return 0x00000004;
  } else if (strcmp(name, "shtg_ammo") == 0) {
    return 0x00000005;
  }
  return 0xFFFFFFFF;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<item_type_id>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L39
L3:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L3
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L3
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L3
  mov    %rbp,%rdi
  lea    D38(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D8
type: string
name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D38
type: string

tool: D7: hptn

tool: D14: key

tool: D8: dcat

tool: D9: shtg

tool: D38: shtg_ammo

assistant: ```c
unsigned int item_type_id(const char *name) {
  if (strcmp(name, "hptn") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "key") == 0) {
    return 0x00000002;
  } else if (strcmp(name, "dcat") == 0) {
    return 0x00000003;
  } else if (strcmp(name, "shtg") == 0) {
    return 0x00000004;
  } else if (strcmp(name, "shtg_ammo") == 0) {
    return 0x00000005;
  }
  return 0xFFFFFFFF;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xd,-0x8(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mul@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: a=%d, b=%d, x=%d


assistant: ```c
main() {
  int a, b;
  a = 13;
  b = 8;
  printf("a=%d, b=%d, x=%d\n", a, b, mul(a, b));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0xd,%edi
  call   <mul@plt>
  mov    %eax,%ecx
  mov    $0x8,%edx
  mov    $0xd,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: a=%d, b=%d, x=%d


assistant: ```c
main() {
  int a, b;
  a = 13;
  b = 8;
  printf("a=%d, b=%d, x=%d\n", a, b, mul(a, b));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0xd,%edi
  call   <mul@plt>
  mov    $0x8,%edx
  mov    $0xd,%esi
  lea    D2(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: a=%d, b=%d, x=%d


assistant: ```c
main() {
  int a, b;
  a = 13;
  b = 8;
  printf("a=%d, b=%d, x=%d\n", a, b, mul(a, b));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0xd,%edi
  call   <mul@plt>
  mov    $0x8,%edx
  mov    $0xd,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: a=%d, b=%d, x=%d


assistant: ```c
main() {
  int a, b;
  a = 13;
  b = 8;
  printf("a=%d, b=%d, x=%d\n", a, b, mul(a, b));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int init() {
  if (0)
    _dbg("init()\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<init>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int init() {
  if (0)
    _dbg("init()\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int init() {
  if (0)
    _dbg("init()\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int init() {
  if (0)
    _dbg("init()\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<random7_pair>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L24
L239:
  mov    $0x0,%eax
  call   <drand48@plt>
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <drand48@plt>
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L229
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  cmpl   $0x1,-0x4(%rbp)
  je     L9
  cmpl   $0x2,-0x4(%rbp)
  jne    L229
L9:
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L229:
  cmpl   $0x0,-0x8(%rbp)
  je     L110
  cmpl   $0x1,-0x8(%rbp)
  jne    L297
  cmpl   $0x0,-0x4(%rbp)
  jne    L297
L110:
  movl   $0x1,-0xc(%rbp)
  jmp    L24
L297:
  cmpl   $0x1,-0x8(%rbp)
  jne    L134
  cmpl   $0x1,-0x4(%rbp)
  je     L11
  cmpl   $0x2,-0x4(%rbp)
  je     L11
  cmpl   $0x3,-0x4(%rbp)
  jne    L134
L11:
  movl   $0x2,-0xc(%rbp)
  jmp    L24
L134:
  cmpl   $0x1,-0x8(%rbp)
  je     L268
  cmpl   $0x2,-0x8(%rbp)
  jne    L197
  cmpl   $0x0,-0x4(%rbp)
  je     L268
  cmpl   $0x1,-0x4(%rbp)
  jne    L197
L268:
  movl   $0x3,-0xc(%rbp)
  jmp    L24
L197:
  cmpl   $0x2,-0x8(%rbp)
  jne    L60
  movl   $0x4,-0xc(%rbp)
  jmp    L24
L60:
  cmpl   $0x3,-0x8(%rbp)
  jne    L175
  cmpl   $0x0,-0x4(%rbp)
  je     L86
  cmpl   $0x1,-0x4(%rbp)
  je     L86
  cmpl   $0x2,-0x4(%rbp)
  jne    L175
L86:
  movl   $0x5,-0xc(%rbp)
  jmp    L24
L175:
  cmpl   $0x3,-0x8(%rbp)
  je     L10
  cmpl   $0x4,-0x8(%rbp)
  jne    L24
  cmpl   $0x0,-0x4(%rbp)
  jne    L24
L10:
  movl   $0x6,-0xc(%rbp)
L24:
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L239
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: f64

tool: D7: 5

assistant: ```c
int random7_pair() {
  int a, b, result = -1;
  while (result == -1) {
    a = ((int)floor(5.0 * drand48()));
    b = ((int)floor(5.0 * drand48()));
    if (a == 0 && (b == 0 || b == 1 || b == 2))
      result = 0;
    else if (a == 0 || (a == 1 && b == 0))
      result = 1;
    else if (a == 1 && (b == 1 || b == 2 || b == 3))
      result = 2;
    else if (a == 1 || (a == 2 && (b == 0 || b == 1)))
      result = 3;
    else if (a == 2)
      result = 4;
    else if (a == 3 && (b == 0 || b == 1 || b == 2))
      result = 5;
    else if (a == 3 || (a == 4 && b == 0))
      result = 6;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random7_pair>:
  endbr64
  push   %rbx
L71:
  mov    $0x0,%eax
  call   <drand48@plt>
  mulsd  D13(%rip),%xmm0
  call   <floor@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <drand48@plt>
  mulsd  D13(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,%edx
  cmp    $0x2,%eax
  setbe  %cl
  test   %ebx,%ebx
  jne    L32
  test   %cl,%cl
  jne    L36
L32:
  test   %ebx,%ebx
  je     L123
  test   %eax,%eax
  sete   %sil
  cmp    $0x1,%ebx
  jne    L214
  test   %sil,%sil
  jne    L87
L214:
  cmp    $0x1,%ebx
  je     L13
  cmp    $0x2,%ebx
  jne    L113
  cmp    $0x1,%eax
  jbe    L116
L113:
  cmp    $0x2,%ebx
  je     L84
  cmp    $0x3,%ebx
  jne    L11
  test   %cl,%cl
  jne    L52
L11:
  cmp    $0x3,%ebx
  je     L16
  cmp    $0x4,%ebx
  jne    L71
  test   %sil,%sil
  je     L71
  mov    $0x6,%eax
  jmp    L147
L13:
  sub    $0x1,%edx
  cmp    $0x3,%edx
  sbb    %eax,%eax
  add    $0x3,%eax
L147:
  pop    %rbx
  ret
L36:
  mov    $0x0,%eax
  jmp    L147
L123:
  mov    $0x1,%eax
  jmp    L147
L87:
  mov    $0x1,%eax
  jmp    L147
L116:
  mov    $0x3,%eax
  jmp    L147
L84:
  mov    $0x4,%eax
  jmp    L147
L52:
  mov    $0x5,%eax
  jmp    L147
L16:
  mov    $0x6,%eax
  jmp    L147
```

tool_calls: name: retrieve_data
arguments: label: D13
type_infered: f64

tool: D13: 5

assistant: ```c
int random7_pair() {
  int a, b, result = -1;
  while (result == -1) {
    a = ((int)floor(5.0 * drand48()));
    b = ((int)floor(5.0 * drand48()));
    if (a == 0 && (b == 0 || b == 1 || b == 2))
      result = 0;
    else if (a == 0 || (a == 1 && b == 0))
      result = 1;
    else if (a == 1 && (b == 1 || b == 2 || b == 3))
      result = 2;
    else if (a == 1 || (a == 2 && (b == 0 || b == 1)))
      result = 3;
    else if (a == 2)
      result = 4;
    else if (a == 3 && (b == 0 || b == 1 || b == 2))
      result = 5;
    else if (a == 3 || (a == 4 && b == 0))
      result = 6;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<random7_pair>:
  endbr64
  push   %rbx
  nopl   (%rax)
L41:
  xor    %eax,%eax
  call   <drand48@plt>
  mulsd  D3(%rip),%xmm0
  call   <floor@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <drand48@plt>
  mulsd  D3(%rip),%xmm0
  call   <floor@plt>
  cmp    $0x2,%eax
  mov    %eax,%edx
  setbe  %cl
  test   %ebx,%ebx
  jne    L25
  test   %cl,%cl
  jne    L3
  test   %ebx,%ebx
  je     L24
L25:
  test   %eax,%eax
  sete   %sil
  cmp    $0x1,%ebx
  jne    L44
  test   %sil,%sil
  jne    L24
  cmp    $0x1,%ebx
  jne    L44
  sub    $0x1,%edx
  pop    %rbx
  cmp    $0x3,%edx
  sbb    %eax,%eax
  add    $0x3,%eax
  ret
  nopl   0x0(%rax)
L44:
  cmp    $0x2,%ebx
  jne    L124
  cmp    $0x1,%eax
  jbe    L115
  cmp    $0x2,%ebx
  je     L31
L124:
  cmp    $0x3,%ebx
  jne    L5
  test   %cl,%cl
  jne    L89
  cmp    $0x3,%ebx
  je     L72
L5:
  cmp    $0x4,%ebx
  jne    L41
  test   %sil,%sil
  je     L41
L72:
  mov    $0x6,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L115:
  mov    $0x3,%eax
  pop    %rbx
  ret
  nop
L31:
  mov    $0x4,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  mov    $0x5,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: f64

tool: D3: 5

assistant: ```c
int random7_pair() {
  int a, b, result = -1;
  while (result == -1) {
    a = ((int)floor(5.0 * drand48()));
    b = ((int)floor(5.0 * drand48()));
    if (a == 0 && (b == 0 || b == 1 || b == 2))
      result = 0;
    else if (a == 0 || (a == 1 && b == 0))
      result = 1;
    else if (a == 1 && (b == 1 || b == 2 || b == 3))
      result = 2;
    else if (a == 1 || (a == 2 && (b == 0 || b == 1)))
      result = 3;
    else if (a == 2)
      result = 4;
    else if (a == 3 && (b == 0 || b == 1 || b == 2))
      result = 5;
    else if (a == 3 || (a == 4 && b == 0))
      result = 6;
  }
  return result;
}
```