ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_MM_EXTRACT_EPI64_32>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  movslq %esi,%rbx
  mov    %r8d,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <_mm_store_si128@plt>
  mov    (%rsp,%rbx,4),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int64_t _MM_EXTRACT_EPI64_32(__m128i val, const int LANE) {
  __attribute__((aligned(16))) int64_t tmp[2];
  _mm_store_si128((__m128i *)tmp, val);
  return tmp[LANE];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <match@plt>
  test   %rax,%rax
  je     L39
  mov    -0x4(%rbp),%eax
  jmp    L1
L39:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

assistant: ```c
int findmatch(char *s, char *keyword[]) {
  int i = 0;
  while (keyword[i] != NULL) {
    if (match(s, keyword[i]))
      return (i);
    i++;
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findmatch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L36
  mov    %rdi,%r12
  mov    $0x0,%ebx
L31:
  mov    %ebx,%r13d
  mov    %r12,%rdi
  call   <match@plt>
  test   %rax,%rax
  jne    L16
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  jne    L31
  mov    $0xffffffff,%r13d
L16:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  mov    $0xffffffff,%r13d
  jmp    L16
```

assistant: ```c
int findmatch(char *s, char *keyword[]) {
  int i = 0;
  while (keyword[i] != NULL) {
    if (match(s, keyword[i]))
      return (i);
    i++;
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findmatch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%r12
  xor    %ebx,%ebx
  jmp    L15
L24:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L18
L15:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <match@plt>
  test   %rax,%rax
  je     L24
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findmatch(char *s, char *keyword[]) {
  int i = 0;
  while (keyword[i] != NULL) {
    if (match(s, keyword[i]))
      return (i);
    i++;
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findmatch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  je     L29
  mov    %rdi,%r12
  xor    %ebx,%ebx
  jmp    L21
L11:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L29
L21:
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <match@plt>
  test   %rax,%rax
  je     L11
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int findmatch(char *s, char *keyword[]) {
  int i = 0;
  while (keyword[i] != NULL) {
    if (match(s, keyword[i]))
      return (i);
    i++;
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<run_perf_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L106:
  cmp    %rdx,%rsp
  je     L90
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L106
L90:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L60
  orq    $0x0,-0x8(%rsp,%rax,1)
L60:
  mov    %rsp,%r13
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  jle    L4
  mov    %eax,%r14d
  mov    $0x0,%ebx
  jmp    L50
L39:
  mov    %r15d,%esi
  mov    %ebx,%edi
  call   <loop@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L44:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L58
L50:
  call   <fork@plt>
  mov    %eax,0x0(%r13,%rbx,4)
  test   %eax,%eax
  je     L39
  cmp    $0xffffffff,%eax
  jne    L44
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L44
L58:
  mov    %r13,%rbx
  mov    -0x44(%rbp),%eax
  lea    0x0(%r13,%rax,4),%r14
  lea    -0x3c(%rbp),%r13
L21:
  mov    (%rbx),%r12d
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  cmp    %eax,%r12d
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x3c(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L21
L4:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: couldn't spawn #%d process


assistant: ```c
void run_perf_test(int tasks, int flags) {
  pid_t pid[tasks];
  int i;
  for (i = 0; i < tasks; i++) {
    pid[i] = fork();
    if (pid[i] == 0) {
      loop(i, flags);
      exit(0);
    } else if (pid[i] == -1) {
      printf("couldn't spawn #%d process\n", i);
      exit(1);
    }
  }
  for (i = 0; i < tasks; i++) {
    int status;
    assert(waitpid(pid[i], &status, 0) == pid[i]);
    assert(status == 0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<run_perf_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L120
L112:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L112
L120:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L37
L30:
  mov    %rsp,%rbx
  test   %edi,%edi
  jle    L8
  mov    %edi,%r12d
  xor    %r15d,%r15d
  jmp    L64
  nopl   0x0(%rax)
L77:
  cmp    $0xffffffff,%eax
  je     L36
L58:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L104
L64:
  call   <fork@plt>
  mov    %eax,(%rbx,%r15,4)
  test   %eax,%eax
  jne    L77
  mov    %r15d,%edi
  mov    %r14d,%esi
  add    $0x1,%r15
  call   <loop@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    %r12,%r15
  jne    L64
L104:
  lea    (%rbx,%r15,4),%r14
  lea    -0x3c(%rbp),%r13
  nopw   0x0(%rax,%rax,1)
L94:
  mov    (%rbx),%r12d
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  xor    %edi,%edi
  cmp    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    -0x3c(%rbp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %r14,%rbx
  jne    L94
L8:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L36:
  mov    %r15d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L37:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L30
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: couldn't spawn #%d process


assistant: ```c
void run_perf_test(int tasks, int flags) {
  pid_t pid[tasks];
  int i;
  for (i = 0; i < tasks; i++) {
    pid[i] = fork();
    if (pid[i] == 0) {
      loop(i, flags);
      exit(0);
    } else if (pid[i] == -1) {
      printf("couldn't spawn #%d process\n", i);
      exit(1);
    }
  }
  for (i = 0; i < tasks; i++) {
    int status;
    assert(waitpid(pid[i], &status, 0) == pid[i]);
    assert(status == 0);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<run_perf_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L120
L70:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L70
L120:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L90
L71:
  mov    %rsp,%rbx
  test   %edi,%edi
  jle    L103
  mov    %edi,%r12d
  xor    %r15d,%r15d
  jmp    L11
  nopl   0x0(%rax)
L87:
  cmp    $0xffffffff,%eax
  je     L32
L13:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L125
L11:
  call   <fork@plt>
  mov    %eax,(%rbx,%r15,4)
  test   %eax,%eax
  jne    L87
  mov    %r15d,%edi
  mov    %r14d,%esi
  add    $0x1,%r15
  call   <loop@plt>
  xor    %edi,%edi
  call   <exit@plt>
  cmp    %r12,%r15
  jne    L11
L125:
  lea    (%rbx,%r15,4),%r14
  lea    -0x3c(%rbp),%r13
  nopw   0x0(%rax,%rax,1)
L80:
  mov    (%rbx),%r12d
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  xor    %edi,%edi
  cmp    %eax,%r12d
  sete   %dil
  call   <assert@plt>
  mov    -0x3c(%rbp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %r14,%rbx
  jne    L80
L103:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L32:
  mov    %r15d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L90:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L71
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: couldn't spawn #%d process


assistant: ```c
void run_perf_test(int tasks, int flags) {
  pid_t pid[tasks];
  int i;
  for (i = 0; i < tasks; i++) {
    pid[i] = fork();
    if (pid[i] == 0) {
      loop(i, flags);
      exit(0);
    } else if (pid[i] == -1) {
      printf("couldn't spawn #%d process\n", i);
      exit(1);
    }
  }
  for (i = 0; i < tasks; i++) {
    int status;
    assert(waitpid(pid[i], &status, 0) == pid[i]);
    assert(status == 0);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_228_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_228_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrop3_228_1_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  mov    %eax,%edx
  xor    %esi,%edx
  movzbl %dl,%edx
  xor    %eax,%edx
  or     %esi,%eax
  mov    %edx,%ecx
  xor    $0xff,%cl
  and    %ecx,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xrop3_228_1_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  xor    %esi,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  or     %esi,%edi
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_228_1_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  xor    %esi,%edx
  movzbl %dl,%edx
  xor    %edi,%edx
  or     %esi,%edi
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_228_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T ^ S;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_obs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L22
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,D17(%rip)
  mov    $0x0,%eax
  jmp    L56
L22:
  movl   $0x0,-0x14(%rbp)
  jmp    L54
L55:
  addl   $0x1,-0x14(%rbp)
L54:
  mov    D17(%rip),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L52
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L52
  ucomisd %xmm1,%xmm0
  je     L55
L52:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm1
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm0
  comisd %xmm1,%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
int compare_obs(const void *v1, const void *v2) {
  static int sort_columns = 1;
  const double *a = (const double *)v1;
  const double *b = (const double *)v2;
  int i;
  if (v1 == NULL) {
    sort_columns = *(int *)v2;
    return 0;
  }
  for (i = 0; i < sort_columns && a[i] == b[i]; i++)
    ;
  return (a[i] > b[i]) - (a[i] < b[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_obs>:
  endbr64
  test   %rdi,%rdi
  je     L37
  mov    D0(%rip),%r8d
  test   %r8d,%r8d
  jle    L13
  mov    %r8d,%r8d
  mov    $0x0,%eax
L8:
  mov    %eax,%ecx
  mov    %eax,%edx
  movsd  (%rdi,%rax,8),%xmm0
  ucomisd (%rsi,%rax,8),%xmm0
  jp     L30
  jne    L30
  lea    0x1(%rcx),%edx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L8
L30:
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  movsd  (%rsi,%rdx,8),%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comisd %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
L37:
  mov    (%rsi),%eax
  mov    %eax,D15(%rip)
  mov    $0x0,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L30
```

assistant: ```c
int compare_obs(const void *v1, const void *v2) {
  static int sort_columns = 1;
  const double *a = (const double *)v1;
  const double *b = (const double *)v2;
  int i;
  if (v1 == NULL) {
    sort_columns = *(int *)v2;
    return 0;
  }
  for (i = 0; i < sort_columns && a[i] == b[i]; i++)
    ;
  return (a[i] > b[i]) - (a[i] < b[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compare_obs>:
  endbr64
  test   %rdi,%rdi
  je     L10
  mov    D2(%rip),%edx
  mov    $0x1,%eax
  lea    0x1(%rdx),%ecx
  test   %edx,%edx
  jg     L14
  jmp    L12
  nopl   (%rax)
L20:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L76
L14:
  movsd  -0x8(%rdi,%rax,8),%xmm0
  movsd  -0x8(%rsi,%rax,8),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L35
  je     L20
L35:
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
  nopl   (%rax)
L76:
  movsd  (%rdi,%rdx,8),%xmm0
  movsd  (%rsi,%rdx,8),%xmm1
  jmp    L35
  nopl   0x0(%rax)
L10:
  mov    (%rsi),%eax
  mov    %eax,D15(%rip)
  xor    %eax,%eax
  ret
L12:
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  jmp    L35
```

assistant: ```c
int compare_obs(const void *v1, const void *v2) {
  static int sort_columns = 1;
  const double *a = (const double *)v1;
  const double *b = (const double *)v2;
  int i;
  if (v1 == NULL) {
    sort_columns = *(int *)v2;
    return 0;
  }
  for (i = 0; i < sort_columns && a[i] == b[i]; i++)
    ;
  return (a[i] > b[i]) - (a[i] < b[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_obs>:
  endbr64
  test   %rdi,%rdi
  je     L67
  mov    D8(%rip),%edx
  mov    $0x1,%eax
  lea    0x1(%rdx),%ecx
  test   %edx,%edx
  jg     L2
  jmp    L34
  nopl   (%rax)
L47:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L26
L2:
  movsd  -0x8(%rdi,%rax,8),%xmm0
  movsd  -0x8(%rsi,%rax,8),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L15
  je     L47
L15:
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comisd %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
  nopl   (%rax)
L26:
  movsd  (%rdi,%rdx,8),%xmm0
  movsd  (%rsi,%rdx,8),%xmm1
  jmp    L15
  nopl   0x0(%rax)
L67:
  mov    (%rsi),%eax
  mov    %eax,D15(%rip)
  xor    %eax,%eax
  ret
L34:
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  jmp    L15
```

assistant: ```c
int compare_obs(const void *v1, const void *v2) {
  static int sort_columns = 1;
  const double *a = (const double *)v1;
  const double *b = (const double *)v2;
  int i;
  if (v1 == NULL) {
    sort_columns = *(int *)v2;
    return 0;
  }
  for (i = 0; i < sort_columns && a[i] == b[i]; i++)
    ;
  return (a[i] > b[i]) - (a[i] < b[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<ftoascii>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%r14d
  movaps %xmm0,%xmm2
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  mov    %esi,%ebp
  comiss %xmm2,%xmm0
  ja     L10
L6:
  movss  0xc(%rsp),%xmm0
  cvttss2si %xmm0,%edi
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  subss  %xmm1,%xmm0
  mulss  D40(%rip),%xmm0
  cvttss2si %xmm0,%r15d
  call   <ireverse@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  je     L46
  test   %ebp,%ebp
  jle    L46
  lea    D3(%rip),%r13
L12:
  movslq %ecx,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  add    $0x1e,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    $0x4,%r12
  sub    $0x4,%ebp
  mov    %ebx,%ecx
  test   %ebx,%ebx
  je     L46
  test   %ebp,%ebp
  jg     L12
L46:
  lea    D16(%rip),%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  sub    $0x4,%ebp
  lea    0x1e(%r15),%ecx
  lea    0x4(%r12),%rdi
  lea    D3(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %r14d,%eax
  sub    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  lea    D10(%rip),%rdx
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    $0x4,%r12
  lea    -0x4(%r14),%ebp
  movss  0xc(%rsp),%xmm3
  xorps  D34(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D40
type: byte[4]
name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D34
type: byte[16]

tool: {"D40": [0x00,0x00,0x20,0x41]}

tool: D3: 00%d

tool: D16: 002E

tool: D10: 002D

tool: {"D34": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int ftoascii(char *str, int len, float value) {
  int integer;
  int frac;
  int tmp;
  int count = len;
  if (value < 0) {
    snprintf(str, len, "002D");
    str += 4;
    len -= 4;
    value = -value;
  }
  integer = (int)value;
  frac = (int)(10 * (value - integer));
  integer = ireverse(integer);
  while (integer && len > 0) {
    tmp = integer % 10;
    snprintf(str, len, "00%d", 30 + tmp);
    str += 4;
    len -= 4;
    integer /= 10;
  }
  snprintf(str, len, "002E");
  str += 4;
  len -= 4;
  snprintf(str, len, "00%d", 30 + frac);
  return count - len;
}
```