ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<whoami>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  jmp    L9
L0:
  lea    D8(%rip),%rax
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: nobody

assistant: ```c
char *whoami() {
  struct passwd *pw;
  if (NULL != (pw = getpwuid(getuid())))
    return pw->pw_name;
  else
    return "nobody";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<whoami>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  lea    D2(%rip),%rdx
  test   %rax,%rax
  je     L8
  mov    (%rax),%rdx
L8:
  mov    %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: nobody

assistant: ```c
char *whoami() {
  struct passwd *pw;
  if (NULL != (pw = getpwuid(getuid())))
    return pw->pw_name;
  else
    return "nobody";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<whoami>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  lea    D0(%rip),%r8
  test   %rax,%rax
  je     L8
  mov    (%rax),%r8
L8:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: nobody

assistant: ```c
char *whoami() {
  struct passwd *pw;
  if (NULL != (pw = getpwuid(getuid())))
    return pw->pw_name;
  else
    return "nobody";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<whoami>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <getpwuid@plt>
  lea    D5(%rip),%r8
  test   %rax,%rax
  je     L8
  mov    (%rax),%r8
L8:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: nobody

assistant: ```c
char *whoami() {
  struct passwd *pw;
  if (NULL != (pw = getpwuid(getuid())))
    return pw->pw_name;
  else
    return "nobody";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xvm_axpy>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  movq   %xmm0,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%r15
  mov    $0x0,%edi
  test   %rbx,%rbx
  je     L5
  test   $0xf,%bl
  sete   %dil
  movzbl %dil,%edi
L5:
  call   <assert@plt>
  mov    $0x0,%edi
  test   %r12,%r12
  je     L41
  test   $0xf,%r12b
  sete   %dil
  movzbl %dil,%edi
L41:
  call   <assert@plt>
  mov    $0x0,%edi
  test   %rbp,%rbp
  je     L49
  test   $0xf,%bpl
  sete   %dil
  movzbl %dil,%edi
L49:
  call   <assert@plt>
  movq   %r13,%xmm0
  call   <_mm_set1_pd@plt>
  mov    %eax,%r14d
  test   %r15,%r15
  je     L9
  sub    $0x1,%r15
  shr    $0x2,%r15
  mov    $0x0,%r13d
L12:
  mov    %r12,%rdi
  call   <_mm_load_pd@plt>
  mov    %eax,(%rsp)
  lea    0x10(%r12),%rdi
  call   <_mm_load_pd@plt>
  mov    %eax,0x4(%rsp)
  mov    %rbp,%rdi
  call   <_mm_load_pd@plt>
  mov    %eax,0x8(%rsp)
  lea    0x10(%rbp),%rdi
  call   <_mm_load_pd@plt>
  mov    %eax,0xc(%rsp)
  mov    %r14d,%esi
  mov    (%rsp),%edi
  call   <_mm_mul_pd@plt>
  mov    %eax,(%rsp)
  mov    %r14d,%esi
  mov    0x4(%rsp),%edi
  call   <_mm_mul_pd@plt>
  mov    %eax,0x4(%rsp)
  mov    0x8(%rsp),%esi
  mov    (%rsp),%edi
  call   <_mm_add_pd@plt>
  mov    %eax,(%rsp)
  mov    0xc(%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <_mm_add_pd@plt>
  mov    %eax,0x4(%rsp)
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <_mm_store_pd@plt>
  lea    0x10(%rbx),%rdi
  mov    0x4(%rsp),%esi
  call   <_mm_store_pd@plt>
  mov    %r13,%rax
  add    $0x1,%r13
  add    $0x20,%r12
  add    $0x20,%rbp
  add    $0x20,%rbx
  cmp    %r15,%rax
  jne    L12
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xvm_axpy(double r[], double a, const double x[], const double y[], size_t N) {
  assert(r != NULL && ((size_t)r % 16) == 0);
  assert(x != NULL && ((size_t)x % 16) == 0);
  assert(y != NULL && ((size_t)y % 16) == 0);
  const __m128d va = _mm_set1_pd(a);
  for (size_t n = 0; n < N; n += 4) {
    const __m128d x0 = _mm_load_pd(x + n);
    const __m128d x1 = _mm_load_pd(x + n + 2);
    const __m128d y0 = _mm_load_pd(y + n);
    const __m128d y1 = _mm_load_pd(y + n + 2);
    const __m128d t0 = _mm_mul_pd(x0, va);
    const __m128d t1 = _mm_mul_pd(x1, va);
    const __m128d r0 = _mm_add_pd(t0, y0);
    const __m128d r1 = _mm_add_pd(t1, y1);
    _mm_store_pd(r + n, r0);
    _mm_store_pd(r + n + 2, r1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xvm_axpy>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  movq   %xmm0,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x28,%rsp
  test   %rbx,%rbx
  je     L16
  xor    %edi,%edi
  test   $0xf,%bl
  sete   %dil
L16:
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  je     L25
  xor    %edi,%edi
  test   $0xf,%r12b
  sete   %dil
L25:
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  je     L19
  xor    %edi,%edi
  test   $0xf,%bpl
  sete   %dil
L19:
  call   <assert@plt>
  movq   %r13,%xmm0
  call   <_mm_set1_pd@plt>
  mov    %eax,%r14d
  test   %r15,%r15
  je     L46
  sub    $0x1,%r15
  shr    $0x2,%r15
  mov    %r15,0x18(%rsp)
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r12,%rdi
  call   <_mm_load_pd@plt>
  lea    0x10(%r12),%rdi
  add    $0x20,%r12
  mov    %eax,0xc(%rsp)
  call   <_mm_load_pd@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <_mm_load_pd@plt>
  lea    0x10(%rbp),%rdi
  add    $0x20,%rbp
  mov    %eax,0x14(%rsp)
  call   <_mm_load_pd@plt>
  mov    0xc(%rsp),%edi
  mov    %r14d,%esi
  mov    %eax,0x10(%rsp)
  call   <_mm_mul_pd@plt>
  mov    %r13d,%edi
  mov    %r14d,%esi
  mov    %eax,0xc(%rsp)
  call   <_mm_mul_pd@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %eax,%r13d
  call   <_mm_add_pd@plt>
  mov    0x10(%rsp),%esi
  mov    %r13d,%edi
  mov    %eax,0xc(%rsp)
  call   <_mm_add_pd@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <_mm_store_pd@plt>
  lea    0x10(%rbx),%rdi
  mov    %r13d,%esi
  add    $0x20,%rbx
  call   <_mm_store_pd@plt>
  mov    %r15,%rax
  add    $0x1,%r15
  cmp    0x18(%rsp),%rax
  jne    L37
L46:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xvm_axpy(double r[], double a, const double x[], const double y[], size_t N) {
  assert(r != NULL && ((size_t)r % 16) == 0);
  assert(x != NULL && ((size_t)x % 16) == 0);
  assert(y != NULL && ((size_t)y % 16) == 0);
  const __m128d va = _mm_set1_pd(a);
  for (size_t n = 0; n < N; n += 4) {
    const __m128d x0 = _mm_load_pd(x + n);
    const __m128d x1 = _mm_load_pd(x + n + 2);
    const __m128d y0 = _mm_load_pd(y + n);
    const __m128d y1 = _mm_load_pd(y + n + 2);
    const __m128d t0 = _mm_mul_pd(x0, va);
    const __m128d t1 = _mm_mul_pd(x1, va);
    const __m128d r0 = _mm_add_pd(t0, y0);
    const __m128d r1 = _mm_add_pd(t1, y1);
    _mm_store_pd(r + n, r0);
    _mm_store_pd(r + n + 2, r1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xvm_axpy>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  movq   %xmm0,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x28,%rsp
  test   %rbx,%rbx
  je     L32
  xor    %edi,%edi
  test   $0xf,%bl
  sete   %dil
L32:
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  je     L41
  xor    %edi,%edi
  test   $0xf,%r12b
  sete   %dil
L41:
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  je     L30
  xor    %edi,%edi
  test   $0xf,%bpl
  sete   %dil
L30:
  call   <assert@plt>
  movq   %r13,%xmm0
  call   <_mm_set1_pd@plt>
  mov    %eax,%r14d
  test   %r15,%r15
  je     L22
  sub    $0x1,%r15
  shr    $0x2,%r15
  mov    %r15,0x18(%rsp)
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rdi
  call   <_mm_load_pd@plt>
  lea    0x10(%r12),%rdi
  add    $0x20,%r12
  mov    %eax,0xc(%rsp)
  call   <_mm_load_pd@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <_mm_load_pd@plt>
  lea    0x10(%rbp),%rdi
  add    $0x20,%rbp
  mov    %eax,0x14(%rsp)
  call   <_mm_load_pd@plt>
  mov    0xc(%rsp),%edi
  mov    %r14d,%esi
  mov    %eax,0x10(%rsp)
  call   <_mm_mul_pd@plt>
  mov    %r13d,%edi
  mov    %r14d,%esi
  mov    %eax,0xc(%rsp)
  call   <_mm_mul_pd@plt>
  mov    0x14(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %eax,%r13d
  call   <_mm_add_pd@plt>
  mov    0x10(%rsp),%esi
  mov    %r13d,%edi
  mov    %eax,0xc(%rsp)
  call   <_mm_add_pd@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <_mm_store_pd@plt>
  lea    0x10(%rbx),%rdi
  mov    %r13d,%esi
  add    $0x20,%rbx
  call   <_mm_store_pd@plt>
  mov    %r15,%rax
  add    $0x1,%r15
  cmp    0x18(%rsp),%rax
  jne    L38
L22:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xvm_axpy(double r[], double a, const double x[], const double y[], size_t N) {
  assert(r != NULL && ((size_t)r % 16) == 0);
  assert(x != NULL && ((size_t)x % 16) == 0);
  assert(y != NULL && ((size_t)y % 16) == 0);
  const __m128d va = _mm_set1_pd(a);
  for (size_t n = 0; n < N; n += 4) {
    const __m128d x0 = _mm_load_pd(x + n);
    const __m128d x1 = _mm_load_pd(x + n + 2);
    const __m128d y0 = _mm_load_pd(y + n);
    const __m128d y1 = _mm_load_pd(y + n + 2);
    const __m128d t0 = _mm_mul_pd(x0, va);
    const __m128d t1 = _mm_mul_pd(x1, va);
    const __m128d r0 = _mm_add_pd(t0, y0);
    const __m128d r1 = _mm_add_pd(t1, y1);
    _mm_store_pd(r + n, r0);
    _mm_store_pd(r + n + 2, r1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<D_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L9:
  addl   $0x1,-0x4(%rbp)
L10:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int D_log2(int num) {
  int c;
  c = 0;
  while (num >>= 1)
    c++;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<D_log2>:
  endbr64
  sar    %edi
  je     L8
  mov    $0x0,%eax
L9:
  add    $0x1,%eax
  sar    %edi
  jne    L9
  ret
L8:
  mov    %edi,%eax
  ret
```

assistant: ```c
int D_log2(int num) {
  int c;
  c = 0;
  while (num >>= 1)
    c++;
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<D_log2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L2
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%eax
  sar    %edi
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
int D_log2(int num) {
  int c;
  c = 0;
  while (num >>= 1)
    c++;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<D_log2>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L10
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%eax
  sar    %edi
  jne    L7
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
int D_log2(int num) {
  int c;
  c = 0;
  while (num >>= 1)
    c++;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L5
L3:
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <handleLine@plt>
L5:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L3
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
void getInput(char *indexName, char *typeName) {
  char *line = NULL;
  size_t linecap = 0;
  while (getline(&line, &linecap, stdin) > 0) {
    handleLine(indexName, typeName, line);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getInput>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    D5(%rip),%r12
  jmp    L8
L25:
  mov    0x8(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <handleLine@plt>
L8:
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    (%r12),%edx
  call   <getline@plt>
  test   %rax,%rax
  jg     L25
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInput(char *indexName, char *typeName) {
  char *line = NULL;
  size_t linecap = 0;
  while (getline(&line, &linecap, stdin) > 0) {
    handleLine(indexName, typeName, line);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getInput>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    D5(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x8(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <handleLine@plt>
L19:
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L17
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInput(char *indexName, char *typeName) {
  char *line = NULL;
  size_t linecap = 0;
  while (getline(&line, &linecap, stdin) > 0) {
    handleLine(indexName, typeName, line);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getInput>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    D5(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <handleLine@plt>
L23:
  mov    (%r14),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jg     L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInput(char *indexName, char *typeName) {
  char *line = NULL;
  size_t linecap = 0;
  while (getline(&line, &linecap, stdin) > 0) {
    handleLine(indexName, typeName, line);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__int32_t_decode_little_endian_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L17
  mov    $0xffffffff,%eax
  jmp    L4
L17:
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L34:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  add    %esi,%edx
  mov    %edx,(%rax)
  addl   $0x4,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L34
  mov    -0xc(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int __int32_t_decode_little_endian_array(const void *_buf, uint32_t offset, uint32_t maxlen, int32_t *p, uint32_t elements) {
  uint32_t total_size = (4) * elements;
  uint8_t *buf = (uint8_t *)_buf;
  uint32_t pos = offset;
  uint32_t element;
  if (maxlen < total_size)
    return -1;
  for (element = 0; element < elements; ++element) {
    p[element] = (((uint32_t)buf[pos + 3]) << 24) + (((uint32_t)buf[pos + 2]) << 16) + (((uint32_t)buf[pos + 1]) << 8) + ((uint32_t)buf[pos + 0]);
    pos += 4;
  }
  return total_size;
}
```
user: What is the c source code of the assembly code below:

```asm
<__int32_t_decode_little_endian_array>:
  endbr64
  lea    0x0(,%r8,4),%r9d
  cmp    %edx,%r9d
  jg     L11
  test   %r8d,%r8d
  jle    L31
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rdx
  mov    %rcx,%rsi
  lea    -0x1(%r8),%eax
  lea    0x4(%rcx,%rax,4),%rdi
L3:
  mov    0x18(%rdx),%eax
  shl    $0x18,%eax
  mov    0x10(%rdx),%ecx
  shl    $0x10,%ecx
  add    %ecx,%eax
  mov    0x8(%rdx),%ecx
  shl    $0x8,%ecx
  add    %ecx,%eax
  add    (%rdx),%eax
  mov    %eax,(%rsi)
  add    $0x20,%rdx
  add    $0x4,%rsi
  cmp    %rdi,%rsi
  jne    L3
L31:
  mov    %r9d,%eax
  ret
L11:
  mov    $0xffffffff,%r9d
  jmp    L31
```

assistant: ```c
int __int32_t_decode_little_endian_array(const void *_buf, uint32_t offset, uint32_t maxlen, int32_t *p, uint32_t elements) {
  uint32_t total_size = (4) * elements;
  uint8_t *buf = (uint8_t *)_buf;
  uint32_t pos = offset;
  uint32_t element;
  if (maxlen < total_size)
    return -1;
  for (element = 0; element < elements; ++element) {
    p[element] = (((uint32_t)buf[pos + 3]) << 24) + (((uint32_t)buf[pos + 2]) << 16) + (((uint32_t)buf[pos + 1]) << 8) + ((uint32_t)buf[pos + 0]);
    pos += 4;
  }
  return total_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__int32_t_decode_little_endian_array>:
  endbr64
  lea    0x0(,%r8,4),%r9d
  cmp    %edx,%r9d
  jg     L12
  test   %r8d,%r8d
  jle    L1
  movslq %esi,%rsi
  lea    -0x1(%r8),%eax
  lea    (%rdi,%rsi,8),%rdx
  lea    0x4(%rcx,%rax,4),%rdi
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    0x18(%rdx),%eax
  mov    0x10(%rdx),%esi
  add    $0x4,%rcx
  add    $0x20,%rdx
  shl    $0x10,%esi
  shl    $0x18,%eax
  add    %esi,%eax
  mov    -0x18(%rdx),%esi
  shl    $0x8,%esi
  add    %esi,%eax
  add    -0x20(%rdx),%eax
  mov    %eax,-0x4(%rcx)
  cmp    %rcx,%rdi
  jne    L7
L1:
  mov    %r9d,%eax
  ret
L12:
  mov    $0xffffffff,%r9d
  jmp    L1
```

assistant: ```c
int __int32_t_decode_little_endian_array(const void *_buf, uint32_t offset, uint32_t maxlen, int32_t *p, uint32_t elements) {
  uint32_t total_size = (4) * elements;
  uint8_t *buf = (uint8_t *)_buf;
  uint32_t pos = offset;
  uint32_t element;
  if (maxlen < total_size)
    return -1;
  for (element = 0; element < elements; ++element) {
    p[element] = (((uint32_t)buf[pos + 3]) << 24) + (((uint32_t)buf[pos + 2]) << 16) + (((uint32_t)buf[pos + 1]) << 8) + ((uint32_t)buf[pos + 0]);
    pos += 4;
  }
  return total_size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L48
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xa,%eax
  jg     L28
  jmp    L48
L28:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L48:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x13,%eax
  jle    L14
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *i = 0;
  *c = 0;
  while (*i < 20) {
    (*i)++;
    if (*i <= 10)
      continue;
    (*c)++;
  }
  return *c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  movl   $0x0,(%rbx)
  mov    $0x0,%edx
  jmp    L35
L40:
  mov    (%rax),%ecx
  lea    0x1(%rcx),%edx
L35:
  mov    %edx,(%rax)
L9:
  mov    (%rbx),%edx
  cmp    $0x13,%edx
  jg     L38
  add    $0x1,%edx
  mov    %edx,(%rbx)
  cmp    $0xa,%edx
  jg     L40
  jmp    L9
L38:
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  mov    -0x8(%rbp),%rbx
  leave
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *i = 0;
  *c = 0;
  while (*i < 20) {
    (*i)++;
    if (*i <= 10)
      continue;
    (*c)++;
  }
  return *c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  movl   $0x0,(%rbx)
  xor    %edx,%edx
  jmp    L26
  nopl   (%rax)
L1:
  add    $0x1,%edx
  mov    %edx,(%rbx)
  cmp    $0xa,%edx
  jle    L2
  mov    (%rax),%ecx
  lea    0x1(%rcx),%edx
L26:
  mov    %edx,(%rax)
  mov    (%rbx),%edx
L2:
  cmp    $0x13,%edx
  jle    L1
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  mov    -0x8(%rbp),%rbx
  leave
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *i = 0;
  *c = 0;
  while (*i < 20) {
    (*i)++;
    if (*i <= 10)
      continue;
    (*c)++;
  }
  return *c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <alloca@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <alloca@plt>
  movl   $0x0,(%rbx)
  xor    %edx,%edx
  jmp    L35
  nopl   (%rax)
L36:
  add    $0x1,%edx
  mov    %edx,(%rbx)
  cmp    $0xa,%edx
  jle    L10
  mov    (%rax),%ecx
  lea    0x1(%rcx),%edx
L35:
  mov    %edx,(%rax)
  mov    (%rbx),%edx
L10:
  cmp    $0x13,%edx
  jle    L36
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  mov    -0x8(%rbp),%rbx
  leave
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *i = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *i = 0;
  *c = 0;
  while (*i < 20) {
    (*i)++;
    if (*i <= 10)
      continue;
    (*c)++;
  }
  return *c;
}
```