ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scan_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L6:
  cmp    %rdx,%rsp
  je     L58
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L58:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L103
  orq    $0x0,-0x8(%rsp,%rax,1)
L103:
  mov    %rsp,%r12
  mov    %r13,%rdi
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L52
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  lea    0x1(%rax),%r13
  movb   $0x2f,(%rax)
  jmp    L16
L102:
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <open_device@plt>
L16:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L8
  mov    (%rax),%rsi
  cmpb   $0x2e,(%rsi)
  jne    L102
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  je     L16
  cmp    $0x2e,%al
  jne    L102
  cmpb   $0x0,0x2(%rsi)
  jne    L102
  jmp    L16
L8:
  mov    %rbx,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
L62:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L67
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L52:
  mov    $0xffffffff,%eax
  jmp    L62
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scan_dir(const char *dirname) {
  char devname[PATH_MAX];
  char *filename;
  DIR *dir;
  struct dirent *de;
  dir = opendir(dirname);
  if (dir == NULL)
    return -1;
  strcpy(devname, dirname);
  filename = devname + strlen(devname);
  *filename++ = '/';
  while ((de = readdir(dir))) {
    if (de->d_name[0] == '.' && (de->d_name[1] == '\0' || (de->d_name[1] == '.' && de->d_name[2] == '\0')))
      continue;
    strcpy(filename, de->d_name);
    open_device(devname);
  }
  closedir(dir);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scan_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D7(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L53
L14:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L14
L53:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L119
L96:
  mov    %r14,%rdi
  mov    %rsp,%r13
  call   <opendir@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x2f,(%rsp,%rax,1)
  lea    0x1(%rsp,%rax,1),%rbx
L61:
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L71
L88:
  mov    (%rax),%rsi
  cmpb   $0x2e,(%rsi)
  jne    L8
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  je     L61
  cmp    $0x2e,%al
  je     L38
L8:
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <open_device@plt>
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L88
L71:
  mov    %r12,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
L80:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L38:
  cmpb   $0x0,0x2(%rsi)
  jne    L8
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L119:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L96
L9:
  mov    $0xffffffff,%eax
  jmp    L80
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scan_dir(const char *dirname) {
  char devname[PATH_MAX];
  char *filename;
  DIR *dir;
  struct dirent *de;
  dir = opendir(dirname);
  if (dir == NULL)
    return -1;
  strcpy(devname, dirname);
  filename = devname + strlen(devname);
  *filename++ = '/';
  while ((de = readdir(dir))) {
    if (de->d_name[0] == '.' && (de->d_name[1] == '\0' || (de->d_name[1] == '.' && de->d_name[2] == '\0')))
      continue;
    strcpy(filename, de->d_name);
    open_device(devname);
  }
  closedir(dir);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scan_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  mov    D9(%rip),%rax
  mov    %rsp,%rcx
  movslq (%rax),%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L18
L70:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L70
L18:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L77
L2:
  mov    %r14,%rdi
  mov    %rsp,%r13
  call   <opendir@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L43
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x2f,(%rsp,%rax,1)
  lea    0x1(%rsp,%rax,1),%rbx
L15:
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L81
L83:
  mov    (%rax),%rsi
  cmpb   $0x2e,(%rsi)
  jne    L98
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  je     L15
  cmp    $0x2e,%al
  je     L58
L98:
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <open_device@plt>
  mov    %r12,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L83
L81:
  mov    %r12,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
L53:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L58:
  cmpb   $0x0,0x2(%rsi)
  jne    L98
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L77:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
L43:
  mov    $0xffffffff,%eax
  jmp    L53
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scan_dir(const char *dirname) {
  char devname[PATH_MAX];
  char *filename;
  DIR *dir;
  struct dirent *de;
  dir = opendir(dirname);
  if (dir == NULL)
    return -1;
  strcpy(devname, dirname);
  filename = devname + strlen(devname);
  *filename++ = '/';
  while ((de = readdir(dir))) {
    if (de->d_name[0] == '.' && (de->d_name[1] == '\0' || (de->d_name[1] == '.' && de->d_name[2] == '\0')))
      continue;
    strcpy(filename, de->d_name);
    open_device(devname);
  }
  closedir(dir);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<squareRoot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L17
L16:
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  D13(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L17:
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <absoluteValue@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd -0x20(%rbp),%xmm2
  jae    L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type_infered: f64
name: read_data
arguments: tag: D13
type_infered: f64

tool: D17: 1

tool: D13: 2

assistant: ```c
double squareRoot(double x, double epsilon) {
  double guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<squareRoot>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  movsd  D4(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L13
L18:
  movsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm3
  divsd  %xmm3,%xmm0
  addsd  %xmm3,%xmm0
  mulsd  D16(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
L13:
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  0x10(%rsp),%xmm0
  call   <absoluteValue@plt>
  comisd 0x18(%rsp),%xmm0
  jae    L18
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: f64
name: parse_data
arguments: tag: D16
datatype: byte[8]

tool: D4: 1

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double squareRoot(double x, double epsilon) {
  double guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<squareRoot>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x18(%rsp)
  movsd  D0(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  jmp    L19
  xchg   %ax,%ax
L6:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm1
  mulsd  D8(%rip),%xmm1
L19:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <absoluteValue@plt>
  comisd 0x18(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  jae    L6
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[8]

tool: D0: 1

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double squareRoot(double x, double epsilon) {
  double guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<squareRoot>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x18(%rsp)
  movsd  D6(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  jmp    L16
  xchg   %ax,%ax
L14:
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm1
  mulsd  D8(%rip),%xmm1
L16:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <absoluteValue@plt>
  comisd 0x18(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  jae    L14
  movapd %xmm1,%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: f64
name: extract_symbolic_data
arguments: label: D8
type: byte[8]

tool: D6: 1

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double squareRoot(double x, double epsilon) {
  double guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  imul   %edx,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L55
L26:
  movl   $0x0,-0x18(%rbp)
  jmp    L23
L5:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L54
  addl   $0x1,-0x14(%rbp)
L54:
  addl   $0x1,-0x18(%rbp)
L23:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L5
  addl   $0x1,-0x1c(%rbp)
L55:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L26
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D33
type_infered: string
name: parse_data
arguments: data_tag: D47
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D76
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string

tool: D1: Cuantos renglones tiene su matriz?

tool: D33: %d

tool: D47: Cuantas columnas tiene su matriz?

tool: D16: Ingrese el valor de M[%d][%d]:  

tool: D76: 

	Se ingresaron %d ceros



tool: D24: pause

assistant: ```c
int main() {
  int *M;
  int m = 0, n = 0;
  int i, j;
  int total = 0;
  printf("Cuantos renglones tiene su matriz?\n");
  scanf("%d", &m);
  printf("Cuantas columnas tiene su matriz?\n");
  scanf("%d", &n);
  M = (int *)malloc((m * n) * sizeof(int));
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("Ingrese el valor de M[%d][%d]:  ", i + 1, j + 1);
      scanf("%d", M);
      if (*M == 0)
        total++;
    }
  }
  printf("\n\n\tSe ingresaron %d ceros\n\n", total);
  system("pause");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D13(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x1,%r13d
  mov    $0x0,%r12d
  lea    D5(%rip),%r15
  mov    %rbx,%r14
  cmpl   $0x0,(%rsp)
  jg     L9
L42:
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  add    $0x1,%ebx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x0(%rbp)
  adc    $0x0,%r12d
  cmp    0x4(%rsp),%ebx
  jl     L14
L8:
  lea    0x1(%r13),%eax
  cmp    %r13d,(%rsp)
  jle    L42
  mov    %eax,%r13d
L9:
  mov    $0x0,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L14
  jmp    L8
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D59
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D9
type_guessed: string
name: parse_data
arguments: label: D53
type_guessed: string

tool: D59: Cuantos renglones tiene su matriz?

tool: D13: %d

tool: D23: Cuantas columnas tiene su matriz?

tool: D5: Ingrese el valor de M[%d][%d]:  

tool: D9: 

	Se ingresaron %d ceros



tool: D53: pause

assistant: ```c
int main() {
  int *M;
  int m = 0, n = 0;
  int i, j;
  int total = 0;
  printf("Cuantos renglones tiene su matriz?\n");
  scanf("%d", &m);
  printf("Cuantas columnas tiene su matriz?\n");
  scanf("%d", &n);
  M = (int *)malloc((m * n) * sizeof(int));
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("Ingrese el valor de M[%d][%d]:  ", i + 1, j + 1);
      scanf("%d", M);
      if (*M == 0)
        total++;
    }
  }
  printf("\n\n\tSe ingresaron %d ceros\n\n", total);
  system("pause");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  lea    D29(%rip),%r15
  push   %r14
  lea    D57(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L44
  nop
L15:
  mov    0x4(%rsp),%eax
  add    $0x1,%r13d
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L37
  xchg   %ax,%ax
L48:
  add    $0x1,%ebx
  mov    %r13d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x0(%rbp)
  adc    $0x0,%r12d
  cmp    0x4(%rsp),%ebx
  jl     L48
L37:
  cmp    %r13d,(%rsp)
  jg     L15
L44:
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D57
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D55
type_infered: string
name: retrieve_data
arguments: data_tag: D59
type_infered: string

tool: D44: Cuantos renglones tiene su matriz?

tool: D29: Ingrese el valor de M[%d][%d]:  

tool: D57: %d

tool: D28: Cuantas columnas tiene su matriz?

tool: D55: 

	Se ingresaron %d ceros



tool: D59: pause

assistant: ```c
int main() {
  int *M;
  int m = 0, n = 0;
  int i, j;
  int total = 0;
  printf("Cuantos renglones tiene su matriz?\n");
  scanf("%d", &m);
  printf("Cuantas columnas tiene su matriz?\n");
  scanf("%d", &n);
  M = (int *)malloc((m * n) * sizeof(int));
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("Ingrese el valor de M[%d][%d]:  ", i + 1, j + 1);
      scanf("%d", M);
      if (*M == 0)
        total++;
    }
  }
  printf("\n\n\tSe ingresaron %d ceros\n\n", total);
  system("pause");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  imul   0x4(%rsp),%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L54
  mov    %rax,%rbp
  mov    0x4(%rsp),%eax
  xor    %r12d,%r12d
  xor    %r13d,%r13d
  lea    D40(%rip),%r15
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r13d
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%ebx
  mov    %r13d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmpl   $0x1,0x0(%rbp)
  adc    $0x0,%r12d
  cmp    %eax,%ebx
  jl     L51
  cmp    (%rsp),%r13d
  jl     L13
L14:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  xor    %r12d,%r12d
  jmp    L14
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D39
datatype: string
name: read_data
arguments: data_label: D31
datatype: string
name: read_data
arguments: data_label: D40
datatype: string
name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D17
datatype: string

tool: D22: Cuantos renglones tiene su matriz?

tool: D39: %d

tool: D31: Cuantas columnas tiene su matriz?

tool: D40: Ingrese el valor de M[%d][%d]:  

tool: D21: 

	Se ingresaron %d ceros



tool: D17: pause

assistant: ```c
int main() {
  int *M;
  int m = 0, n = 0;
  int i, j;
  int total = 0;
  printf("Cuantos renglones tiene su matriz?\n");
  scanf("%d", &m);
  printf("Cuantas columnas tiene su matriz?\n");
  scanf("%d", &n);
  M = (int *)malloc((m * n) * sizeof(int));
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      printf("Ingrese el valor de M[%d][%d]:  ", i + 1, j + 1);
      scanf("%d", M);
      if (*M == 0)
        total++;
    }
  }
  printf("\n\n\tSe ingresaron %d ceros\n\n", total);
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<countCellToSolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L10:
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L42:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L7
  addl   $0x1,-0x4(%rbp)
L7:
  addl   $0x1,-0x8(%rbp)
L31:
  cmpl   $0x8,-0x8(%rbp)
  jle    L42
  addl   $0x1,-0xc(%rbp)
L39:
  cmpl   $0x8,-0xc(%rbp)
  jle    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int countCellToSolve(int sudoku[9][9]) {
  int i, j, c = 0;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (sudoku[i][j] == 0) {
        c++;
      }
    }
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<countCellToSolve>:
  endbr64
  lea    0x24(%rdi),%rcx
  lea    0x168(%rdi),%rsi
  mov    $0x0,%edx
L6:
  lea    -0x24(%rcx),%rax
L14:
  cmpl   $0x1,(%rax)
  adc    $0x0,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L14
  add    $0x24,%rcx
  cmp    %rsi,%rcx
  jne    L6
  mov    %edx,%eax
  ret
```

assistant: ```c
int countCellToSolve(int sudoku[9][9]) {
  int i, j, c = 0;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (sudoku[i][j] == 0) {
        c++;
      }
    }
  }
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<countCellToSolve>:
  endbr64
  lea    0x24(%rdi),%rdx
  lea    0x168(%rdi),%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L19:
  lea    -0x24(%rdx),%rax
  nopl   0x0(%rax)
L18:
  cmpl   $0x1,(%rax)
  adc    $0x0,%r8d
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
  lea    0x24(%rax),%rdx
  cmp    %rcx,%rdx
  jne    L19
  mov    %r8d,%eax
  ret
```

assistant: ```c
int countCellToSolve(int sudoku[9][9]) {
  int i, j, c = 0;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (sudoku[i][j] == 0) {
        c++;
      }
    }
  }
  return c;
}
```