ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_sq_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L5
L16:
  add    $0x8,%rsp
  lea    D24(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L5:
  mov    (%r12),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    $0x1,%ebp
  jle    L16
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%r13
  lea    D28(%rip),%r12
  nopl   0x0(%rax)
L25:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    %r13,%rbx
  jne    L25
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string

tool: D6: [

tool: D24: ]

tool: D28: ,


assistant: ```c
void print_sq_mat(int n, double **A) {
  printf("[");
  if (n > 0)
    print_vec(n, A[0]);
  for (int row = 1; row < n; row++) {
    printf(",\n");
    print_vec(n, A[row]);
  }
  printf("]");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_sq_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D4(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L7
L10:
  add    $0x8,%rsp
  lea    D10(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L7:
  mov    (%r12),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    $0x1,%ebp
  jle    L10
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%r13
  lea    D20(%rip),%r12
  nopl   0x0(%rax)
L24:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    %r13,%rbx
  jne    L24
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D4: [

tool: D10: ]

tool: D20: ,


assistant: ```c
void print_sq_mat(int n, double **A) {
  printf("[");
  if (n > 0)
    print_vec(n, A[0]);
  for (int row = 1; row < n; row++) {
    printf(",\n");
    print_vec(n, A[row]);
  }
  printf("]");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<L1_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <L0_z@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double L1_z(double sign, double xi, double et, double qq) {
  double l0_z = L0_z(sign, xi, et, qq);
  return xi * l0_z;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<L1_z>:
  endbr64
  push   %rbx
  movq   %xmm1,%rbx
  call   <L0_z@plt>
  movq   %rbx,%xmm4
  mulsd  %xmm4,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double L1_z(double sign, double xi, double et, double qq) {
  double l0_z = L0_z(sign, xi, et, qq);
  return xi * l0_z;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<L1_z>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <L0_z@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double L1_z(double sign, double xi, double et, double qq) {
  double l0_z = L0_z(sign, xi, et, qq);
  return xi * l0_z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<L1_z>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <L0_z@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  mulsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double L1_z(double sign, double xi, double et, double qq) {
  double l0_z = L0_z(sign, xi, et, qq);
  return xi * l0_z;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread_task>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <barrier_point@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void *thread_task(void *param) {
  sleep(1);
  barrier_point();
  pthread_exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<thread_task>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <barrier_point@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_task(void *param) {
  sleep(1);
  barrier_point();
  pthread_exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<thread_task>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <barrier_point@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_task(void *param) {
  sleep(1);
  barrier_point();
  pthread_exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<thread_task>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <barrier_point@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_task(void *param) {
  sleep(1);
  barrier_point();
  pthread_exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xorshift1024star_32>:
  endbr64
  mov    0x80(%rdi),%eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%r9d
  mov    0x4(%rdi,%rdx,4),%esi
  add    $0x2,%eax
  and    $0x1f,%eax
  mov    %eax,0x80(%rdi)
  cltq
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  mov    (%r8),%r10d
  lea    0x4(%rdi,%rax,1),%rdi
  mov    (%rdi),%eax
  mov    %eax,%ecx
  shl    $0x1f,%ecx
  mov    %r10d,%edx
  sar    %edx
  or     %edx,%ecx
  xor    %eax,%ecx
  mov    %r10d,%edx
  shl    $0x1f,%edx
  xor    %r10d,%edx
  mov    %r9d,%eax
  sar    $0x1e,%eax
  lea    0x0(,%rsi,4),%r10d
  or     %r10d,%eax
  xor    %r9d,%eax
  xor    %edx,%eax
  sar    $0xb,%edx
  mov    %ecx,%r9d
  shl    $0x15,%r9d
  or     %r9d,%edx
  xor    %edx,%eax
  mov    %eax,(%r8)
  mov    %esi,%edx
  sar    $0x1e,%edx
  xor    %esi,%edx
  xor    %ecx,%edx
  sar    $0xb,%ecx
  xor    %ecx,%edx
  mov    %edx,(%rdi)
  movzwl %ax,%ecx
  sar    $0x10,%eax
  imul   $0x5497fdb5,%eax,%eax
  imul   $0x89d45497,%ecx,%esi
  add    %esi,%eax
  imul   $0xfdb5,%ecx,%ecx
  sar    $0x10,%ecx
  add    %ecx,%eax
  imul   $0xfdb50000,%edx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t xorshift1024star_32(uint32_t *state) {
  int p;
  uint32_t x, y, z, w;
  p = state[32];
  x = state[p];
  y = state[p + 1];
  p = state[32] = (p + 2) & 31;
  z = state[p];
  w = state[p + 1];
  w ^= (w << 31) | (z >> 1);
  z ^= z << 31;
  state[p] = z ^ x ^ ((z >> 11) | (w << 21)) ^ ((x >> 30) | (y << 2));
  state[p + 1] = w ^ y ^ (w >> 11) ^ (y >> 30);
  x = state[p] & 0xFFFF;
  return (x * 64949 >> 16) + x * 2312393879 + (state[p] >> 16) * 1419247029 + state[p + 1] * 4256497664;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xorshift1024star_32>:
  endbr64
  movslq 0x80(%rdi),%rdx
  mov    %rdx,%rax
  mov    0x4(%rdi,%rdx,4),%esi
  mov    (%rdi,%rdx,4),%r9d
  add    $0x2,%eax
  and    $0x1f,%eax
  mov    %eax,0x80(%rdi)
  cltq
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  lea    0x4(%rdi,%rax,1),%rdi
  mov    (%r8),%r10d
  mov    (%rdi),%eax
  mov    %r10d,%edx
  mov    %eax,%ecx
  sar    %edx
  shl    $0x1f,%ecx
  or     %edx,%ecx
  mov    %r10d,%edx
  xor    %eax,%ecx
  shl    $0x1f,%edx
  mov    %r9d,%eax
  xor    %r10d,%edx
  sar    $0x1e,%eax
  lea    0x0(,%rsi,4),%r10d
  or     %r10d,%eax
  xor    %r9d,%eax
  mov    %ecx,%r9d
  xor    %edx,%eax
  shl    $0x15,%r9d
  sar    $0xb,%edx
  or     %r9d,%edx
  xor    %edx,%eax
  mov    %esi,%edx
  sar    $0x1e,%edx
  mov    %eax,(%r8)
  xor    %esi,%edx
  xor    %ecx,%edx
  sar    $0xb,%ecx
  xor    %ecx,%edx
  movzwl %ax,%ecx
  sar    $0x10,%eax
  imul   $0x89d45497,%ecx,%esi
  mov    %edx,(%rdi)
  imul   $0x5497fdb5,%eax,%eax
  imul   $0xfdb5,%ecx,%ecx
  imul   $0xfdb50000,%edx,%edx
  add    %esi,%eax
  sar    $0x10,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t xorshift1024star_32(uint32_t *state) {
  int p;
  uint32_t x, y, z, w;
  p = state[32];
  x = state[p];
  y = state[p + 1];
  p = state[32] = (p + 2) & 31;
  z = state[p];
  w = state[p + 1];
  w ^= (w << 31) | (z >> 1);
  z ^= z << 31;
  state[p] = z ^ x ^ ((z >> 11) | (w << 21)) ^ ((x >> 30) | (y << 2));
  state[p + 1] = w ^ y ^ (w >> 11) ^ (y >> 30);
  x = state[p] & 0xFFFF;
  return (x * 64949 >> 16) + x * 2312393879 + (state[p] >> 16) * 1419247029 + state[p + 1] * 4256497664;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xorshift1024star_32>:
  endbr64
  movslq 0x80(%rdi),%rdx
  mov    %rdx,%rax
  mov    0x4(%rdi,%rdx,4),%esi
  mov    (%rdi,%rdx,4),%r10d
  add    $0x2,%eax
  and    $0x1f,%eax
  mov    %eax,0x80(%rdi)
  cltq
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  mov    0x4(%rdi,%rax,1),%eax
  lea    0x0(,%rsi,4),%edi
  mov    (%r8),%r9d
  mov    %eax,%ecx
  mov    %r9d,%edx
  shl    $0x1f,%ecx
  sar    %edx
  or     %edx,%ecx
  mov    %r9d,%edx
  xor    %eax,%ecx
  mov    %r10d,%eax
  shl    $0x1f,%edx
  sar    $0x1e,%eax
  xor    %r9d,%edx
  or     %edi,%eax
  mov    %ecx,%edi
  xor    %r10d,%eax
  shl    $0x15,%edi
  xor    %edx,%eax
  sar    $0xb,%edx
  or     %edi,%edx
  xor    %edx,%eax
  mov    %esi,%edx
  sar    $0x1e,%edx
  movd   %eax,%xmm0
  xor    %esi,%edx
  xor    %ecx,%edx
  sar    $0xb,%ecx
  xor    %ecx,%edx
  movzwl %ax,%ecx
  sar    $0x10,%eax
  imul   $0x89d45497,%ecx,%esi
  movd   %edx,%xmm1
  imul   $0x5497fdb5,%eax,%eax
  punpckldq %xmm1,%xmm0
  imul   $0xfdb5,%ecx,%ecx
  movq   %xmm0,(%r8)
  imul   $0xfdb50000,%edx,%edx
  add    %esi,%eax
  sar    $0x10,%ecx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
uint32_t xorshift1024star_32(uint32_t *state) {
  int p;
  uint32_t x, y, z, w;
  p = state[32];
  x = state[p];
  y = state[p + 1];
  p = state[32] = (p + 2) & 31;
  z = state[p];
  w = state[p + 1];
  w ^= (w << 31) | (z >> 1);
  z ^= z << 31;
  state[p] = z ^ x ^ ((z >> 11) | (w << 21)) ^ ((x >> 30) | (y << 2));
  state[p + 1] = w ^ y ^ (w >> 11) ^ (y >> 30);
  x = state[p] & 0xFFFF;
  return (x * 64949 >> 16) + x * 2312393879 + (state[p] >> 16) * 1419247029 + state[p + 1] * 4256497664;
}
```
user: What is the c source code of the assembly code below:

```asm
<newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L40
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L46
L40:
  mov    $0x1,%eax
  jmp    L28
L46:
  cmpl   $0x3b,-0x4(%rbp)
  jne    L38
  nop
L19:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <newline>
  test   %eax,%eax
  je     L19
  mov    $0x1,%eax
  jmp    L28
L38:
  mov    $0x0,%eax
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: 


assistant: ```c
bool newline(int c, FILE *f) {
  if (c < 0 || strchr("\r\n", c)) {
    return true;
  } else if (c == ';') {
    while (!newline(fgetc(f), f))
      ;
    return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<newline>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  js     L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L10
  mov    $0x0,%eax
  cmp    $0x3b,%ebx
  je     L22
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %rbp,%rsi
  call   <newline>
  test   %eax,%eax
  je     L22
  mov    $0x1,%eax
  jmp    L10
L33:
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: 


assistant: ```c
bool newline(int c, FILE *f) {
  if (c < 0 || strchr("\r\n", c)) {
    return true;
  } else if (c == ';') {
    while (!newline(fgetc(f), f))
      ;
    return true;
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<newline>:
  endbr64
  test   %edi,%edi
  js     L16
  push   %rbp
  mov    %rsi,%rbp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  jne    L15
  cmp    $0x3b,%ebx
  je     L38
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <newline>
  test   %eax,%eax
  je     L38
L15:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: 


assistant: ```c
bool newline(int c, FILE *f) {
  if (c < 0 || strchr("\r\n", c)) {
    return true;
  } else if (c == ';') {
    while (!newline(fgetc(f), f))
      ;
    return true;
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<newline>:
  endbr64
  test   %edi,%edi
  js     L27
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L75
  cmp    $0x3b,%ebx
  jne    L57
L50:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L75
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L75
  cmp    $0x3b,%ebx
  jne    L50
L84:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L75
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L75
  cmp    $0x3b,%ebx
  jne    L84
L51:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <newline>
  test   %eax,%eax
  je     L51
  nopw   0x0(%rax,%rax,1)
L75:
  mov    $0x1,%eax
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: 


assistant: ```c
bool newline(int c, FILE *f) {
  if (c < 0 || strchr("\r\n", c)) {
    return true;
  } else if (c == ';') {
    while (!newline(fgetc(f), f))
      ;
    return true;
  }
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<average_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L3:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double average_values(int *array, int array_size) {
  double sum = 0.0;
  int i = 0;
  while (i < array_size) {
    sum += *(array + i++);
  }
  return (sum / (double)array_size);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<average_values>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sdl (%rax),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L15
L0:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L13:
  pxor   %xmm0,%xmm0
  jmp    L0
```

assistant: ```c
double average_values(int *array, int array_size) {
  double sum = 0.0;
  int i = 0;
  while (i < array_size) {
    sum += *(array + i++);
  }
  return (sum / (double)array_size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<average_values>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L12:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtsi2sdl -0x4(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L12
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double average_values(int *array, int array_size) {
  double sum = 0.0;
  int i = 0;
  while (i < array_size) {
    sum += *(array + i++);
  }
  return (sum / (double)array_size);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<average_values>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L8:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtsi2sdl -0x4(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L8
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double average_values(int *array, int array_size) {
  double sum = 0.0;
  int i = 0;
  while (i < array_size) {
    sum += *(array + i++);
  }
  return (sum / (double)array_size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<core_directory_verify_existence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L2
  mov    $0x1,%eax
  jmp    L17
L2:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int core_directory_verify_existence(const char *directory) {
  int mode;
  int result;
  mode = F_OK;
  result = access(directory, mode);
  if (result != -1) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<core_directory_verify_existence>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int core_directory_verify_existence(const char *directory) {
  int mode;
  int result;
  mode = F_OK;
  result = access(directory, mode);
  if (result != -1) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<core_directory_verify_existence>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int core_directory_verify_existence(const char *directory) {
  int mode;
  int result;
  mode = F_OK;
  result = access(directory, mode);
  if (result != -1) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<core_directory_verify_existence>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int core_directory_verify_existence(const char *directory) {
  int mode;
  int result;
  mode = F_OK;
  result = access(directory, mode);
  if (result != -1) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__fchmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L12:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L13:
  leave
  ret
```

assistant: ```c
int __fchmod(int fd, mode_t mode) {
  if (fd < 0) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__fchmod>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L14
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
L0:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L14:
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  jmp    L0
```

assistant: ```c
int __fchmod(int fd, mode_t mode) {
  if (fd < 0) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__fchmod>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L3
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __fchmod(int fd, mode_t mode) {
  if (fd < 0) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__fchmod>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L7
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L7:
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __fchmod(int fd, mode_t mode) {
  if (fd < 0) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<b_setenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L4
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <error@plt>
  jmp    L23
L4:
  cmpl   $0x3,-0x4(%rbp)
  jle    L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L23
L0:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
L23:
  leave
  ret
```

assistant: ```c
int b_setenv(int argc, char *argv[]) {
  if (argc < 3)
    return error(0, argv[0]);
  if (argc > 3)
    return error(1, argv[0]);
  setenv(argv[1], argv[2]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<b_setenv>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L28
  cmp    $0x3,%edi
  jg     L16
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <setenv@plt>
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  ret
L28:
  mov    (%rsi),%rsi
  mov    $0x0,%edi
  call   <error@plt>
  jmp    L17
L16:
  mov    (%rsi),%rsi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L17
```

assistant: ```c
int b_setenv(int argc, char *argv[]) {
  if (argc < 3)
    return error(0, argv[0]);
  if (argc > 3)
    return error(1, argv[0]);
  setenv(argv[1], argv[2]);
  return 0;
}
```