ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%esi
  call   <leibniz@plt>
  mov    $0xd,%ebp
  mov    %rsp,%rbx
L3:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printseq@plt>
  lea    0x70(%rsp),%rsi
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <aitken@plt>
  lea    -0x2(%rbp),%eax
  test   %eax,%eax
  jle    L29
  lea    -0x3(%rbp),%ecx
  mov    $0x0,%eax
L35:
  movsd  0x70(%rsp,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L35
L29:
  sub    $0x2,%ebp
  cmp    $0x1,%ebp
  jne    L3
  mov    %rsp,%rdi
  mov    $0x1,%esi
  call   <printseq@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  const int len = 13;
  double seq1[len];
  double seq2[len];
  int n, i, j;
  leibniz(seq1, len);
  n = len / 2;
  if (len % 2 == 0)
    n--;
  for (i = 0; i < n; i++) {
    printseq(seq1, len - 2 * i);
    aitken(seq1, seq2, len - 2 * i);
    for (j = 0; j < len - 2 * (i + 1); j++)
      seq1[j] = seq2[j];
  }
  if (len % 2 == 0)
    printseq(seq1, 2);
  else
    printseq(seq1, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xd,%esi
  push   %rbp
  push   %rbx
  mov    $0xd,%ebx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rdi
  call   <leibniz@plt>
  nopl   0x0(%rax)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printseq@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aitken@plt>
  lea    -0x3(%rbx),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x8(,%rax,8),%rdx
  sub    $0x2,%ebx
  call   <memcpy@plt>
  cmp    $0x1,%ebx
  jne    L9
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printseq@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  const int len = 13;
  double seq1[len];
  double seq2[len];
  int n, i, j;
  leibniz(seq1, len);
  n = len / 2;
  if (len % 2 == 0)
    n--;
  for (i = 0; i < n; i++) {
    printseq(seq1, len - 2 * i);
    aitken(seq1, seq2, len - 2 * i);
    for (j = 0; j < len - 2 * (i + 1); j++)
      seq1[j] = seq2[j];
  }
  if (len % 2 == 0)
    printseq(seq1, 2);
  else
    printseq(seq1, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xd,%esi
  push   %rbp
  push   %rbx
  mov    $0xd,%ebx
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  mov    %rbp,%rdi
  call   <leibniz@plt>
  nopl   0x0(%rax)
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printseq@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aitken@plt>
  lea    -0x3(%rbx),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    0x8(,%rax,8),%rdx
  sub    $0x2,%ebx
  call   <memcpy@plt>
  cmp    $0x1,%ebx
  jne    L7
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printseq@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xe0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  const int len = 13;
  double seq1[len];
  double seq2[len];
  int n, i, j;
  leibniz(seq1, len);
  n = len / 2;
  if (len % 2 == 0)
    n--;
  for (i = 0; i < n; i++) {
    printseq(seq1, len - 2 * i);
    aitken(seq1, seq2, len - 2 * i);
    for (j = 0; j < len - 2 * (i + 1); j++)
      seq1[j] = seq2[j];
  }
  if (len % 2 == 0)
    printseq(seq1, 2);
  else
    printseq(seq1, 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testPtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <module_getsym@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: ERROR: Can't find %s


assistant: ```c
int testPtr(struct module *mod, const char *name, double *val) {
  double **ptr = module_getsym(mod, name);
  if (!ptr) {
    printf("ERROR: Can't find %s\n", name);
  }
  return *ptr == val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testPtr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <module_getsym@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L14:
  cmp    %r12,(%rbx)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: ERROR: Can't find %s


assistant: ```c
int testPtr(struct module *mod, const char *name, double *val) {
  double **ptr = module_getsym(mod, name);
  if (!ptr) {
    printf("ERROR: Can't find %s\n", name);
  }
  return *ptr == val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testPtr>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <module_getsym@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  xor    %eax,%eax
  cmp    %r12,(%rbx)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  cmp    %r12,(%rbx)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: ERROR: Can't find %s


assistant: ```c
int testPtr(struct module *mod, const char *name, double *val) {
  double **ptr = module_getsym(mod, name);
  if (!ptr) {
    printf("ERROR: Can't find %s\n", name);
  }
  return *ptr == val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<testPtr>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <module_getsym@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  xor    %eax,%eax
  cmp    %r12,(%rbx)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  cmp    %r12,(%rbx)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: ERROR: Can't find %s


assistant: ```c
int testPtr(struct module *mod, const char *name, double *val) {
  double **ptr = module_getsym(mod, name);
  if (!ptr) {
    printf("ERROR: Can't find %s\n", name);
  }
  return *ptr == val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_null>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L35:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L13
  mov    $0x0,%eax
  jmp    L6
L13:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int is_null(unsigned char *key, int size) {
  for (int i = 0; i < size; i++) {
    if (*key != 0) {
      return 0;
    }
    key++;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_null>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
L27:
  cmpb   $0x0,(%rdi)
  jne    L6
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L27
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_null(unsigned char *key, int size) {
  for (int i = 0; i < size; i++) {
    if (*key != 0) {
      return 0;
    }
    key++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_null>:
  endbr64
  test   %esi,%esi
  jle    L19
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rax
  jmp    L28
  nopl   0x0(%rax)
L14:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L19
L28:
  cmpb   $0x0,(%rdi)
  je     L14
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_null(unsigned char *key, int size) {
  for (int i = 0; i < size; i++) {
    if (*key != 0) {
      return 0;
    }
    key++;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_null>:
  endbr64
  test   %esi,%esi
  jle    L10
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rax
  jmp    L25
  nopl   0x0(%rax)
L26:
  add    $0x1,%rdi
  cmp    %rax,%rdi
  je     L10
L25:
  cmpb   $0x0,(%rdi)
  je     L26
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_null(unsigned char *key, int size) {
  for (int i = 0; i < size; i++) {
    if (*key != 0) {
      return 0;
    }
    key++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L19
  cmpl   $0x2,-0x4(%rbp)
  jg     L23
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  cmpl   $0x1,-0x4(%rbp)
  je     L43
  jmp    L23
L19:
  nop
  jmp    L65
L23:
  nop
  jmp    L65
L4:
  nop
  jmp    L65
L43:
  nop
L65:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<control_event_my_descriptor_changed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0xe,%edi
  call   <send_control_event@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: 650 DESCCHANGED


assistant: ```c
int control_event_my_descriptor_changed(void) {
  send_control_event(0x000E, 1, "650 DESCCHANGED\r\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<control_event_my_descriptor_changed>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdx
  mov    $0x1,%esi
  mov    $0xe,%edi
  call   <send_control_event@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: 650 DESCCHANGED


assistant: ```c
int control_event_my_descriptor_changed(void) {
  send_control_event(0x000E, 1, "650 DESCCHANGED\r\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<control_event_my_descriptor_changed>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xe,%edi
  lea    D9(%rip),%rdx
  call   <send_control_event@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: 650 DESCCHANGED


assistant: ```c
int control_event_my_descriptor_changed(void) {
  send_control_event(0x000E, 1, "650 DESCCHANGED\r\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<control_event_my_descriptor_changed>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0xe,%edi
  lea    D3(%rip),%rdx
  call   <send_control_event@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: 650 DESCCHANGED


assistant: ```c
int control_event_my_descriptor_changed(void) {
  send_control_event(0x000E, 1, "650 DESCCHANGED\r\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxSubArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L93
L7:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L37
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L37:
  cmpl   $0x0,-0xc(%rbp)
  jns    L40
  movl   $0x0,-0xc(%rbp)
L40:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  cmpl   $0x0,-0x10(%rbp)
  jne    L72
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L50:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
L72:
  mov    -0x10(%rbp),%eax
L93:
  pop    %rbp
  ret
```

assistant: ```c
int maxSubArray(int *nums, int numsSize) {
  if (numsSize == 0)
    return 0;
  int maxVal = 0;
  int val = 0;
  for (int i = 0; i < numsSize; i++) {
    val += nums[i];
    if (val > maxVal)
      maxVal = val;
    if (val < 0)
      val = 0;
  }
  if (maxVal == 0) {
    maxVal = nums[0];
    for (int i = 1; i < numsSize; i++) {
      if (nums[i] > maxVal) {
        maxVal = nums[i];
      }
    }
  }
  return maxVal;
}
```
user: What is the c source code of the assembly code below:

```asm
<maxSubArray>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  je     L20
  jle    L19
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r9
  mov    $0x0,%eax
  mov    $0x0,%edx
L7:
  add    (%rcx),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
  test   %eax,%eax
  mov    $0x0,%r8d
  cmovs  %r8d,%eax
  add    $0x4,%rcx
  cmp    %r9,%rcx
  jne    L7
  test   %edx,%edx
  je     L19
L20:
  mov    %edx,%eax
  ret
L19:
  mov    (%rdi),%edx
  cmp    $0x1,%esi
  jle    L20
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rsi
L24:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L24
  jmp    L20
```

assistant: ```c
int maxSubArray(int *nums, int numsSize) {
  if (numsSize == 0)
    return 0;
  int maxVal = 0;
  int val = 0;
  for (int i = 0; i < numsSize; i++) {
    val += nums[i];
    if (val > maxVal)
      maxVal = val;
    if (val < 0)
      val = 0;
  }
  if (maxVal == 0) {
    maxVal = nums[0];
    for (int i = 1; i < numsSize; i++) {
      if (nums[i] > maxVal) {
        maxVal = nums[i];
      }
    }
  }
  return maxVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<maxSubArray>:
  endbr64
  mov    %rdi,%r10
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L59
  mov    (%rdi),%r11d
  jle    L53
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi),%rcx
  mov    %rdi,%rdx
  lea    (%rcx,%rax,4),%r9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L14:
  add    (%rdx),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  xor    %edi,%edi
  test   %eax,%eax
  cmovs  %edi,%eax
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L14
  test   %r8d,%r8d
  je     L1
L59:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  cmp    $0x1,%esi
  je     L53
  lea    -0x2(%rsi),%edx
  mov    %rcx,%rax
  mov    %r11d,%r8d
  lea    0x8(%r10,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L38
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L53:
  mov    %r11d,%r8d
  jmp    L59
```

assistant: ```c
int maxSubArray(int *nums, int numsSize) {
  if (numsSize == 0)
    return 0;
  int maxVal = 0;
  int val = 0;
  for (int i = 0; i < numsSize; i++) {
    val += nums[i];
    if (val > maxVal)
      maxVal = val;
    if (val < 0)
      val = 0;
  }
  if (maxVal == 0) {
    maxVal = nums[0];
    for (int i = 1; i < numsSize; i++) {
      if (nums[i] > maxVal) {
        maxVal = nums[i];
      }
    }
  }
  return maxVal;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maxSubArray>:
  endbr64
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L41
  mov    %rdi,%r10
  mov    (%rdi),%edi
  jle    L102
  lea    -0x1(%rsi),%eax
  mov    %esi,%r11d
  lea    0x4(%r10),%rsi
  push   %rbx
  lea    (%rsi,%rax,4),%r9
  mov    %rax,%rbx
  mov    %r10,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L27:
  add    (%rdx),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  xor    %ecx,%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L27
  test   %r8d,%r8d
  je     L1
L79:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x1,%r11d
  je     L29
  lea    -0x2(%r11),%eax
  cmp    $0x2,%eax
  jbe    L84
  mov    %ebx,%edx
  movd   %edi,%xmm3
  mov    %rsi,%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm3,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x14(%r10,%rdx,1),%rdx
  nopl   0x0(%rax)
L72:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L72
  movdqa %xmm2,%xmm1
  mov    %ebx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  movdqa %xmm1,%xmm0
  lea    0x1(%rdx),%eax
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%r8d
  cmp    %ebx,%edx
  je     L79
L48:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    (%r10,%rdx,4),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  lea    0x1(%rax),%edx
  cmp    %edx,%r11d
  jle    L79
  mov    0x4(%r10,%rcx,1),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x2,%eax
  cmp    %eax,%r11d
  jle    L79
  mov    0x8(%r10,%rcx,1),%eax
  pop    %rbx
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L102:
  mov    %edi,%r8d
L41:
  mov    %r8d,%eax
  ret
L84:
  mov    %edi,%r8d
  mov    $0x1,%eax
  jmp    L48
L29:
  mov    %edi,%r8d
  jmp    L79
```

assistant: ```c
int maxSubArray(int *nums, int numsSize) {
  if (numsSize == 0)
    return 0;
  int maxVal = 0;
  int val = 0;
  for (int i = 0; i < numsSize; i++) {
    val += nums[i];
    if (val > maxVal)
      maxVal = val;
    if (val < 0)
      val = 0;
  }
  if (maxVal == 0) {
    maxVal = nums[0];
    for (int i = 1; i < numsSize; i++) {
      if (nums[i] > maxVal) {
        maxVal = nums[i];
      }
    }
  }
  return maxVal;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_current_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
struct tm *get_current_time() {
  time_t rawtime;
  struct tm *current_time;
  time(&rawtime);
  current_time = localtime(&rawtime);
  return current_time;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_current_time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct tm *get_current_time() {
  time_t rawtime;
  struct tm *current_time;
  time(&rawtime);
  current_time = localtime(&rawtime);
  return current_time;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_current_time>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct tm *get_current_time() {
  time_t rawtime;
  struct tm *current_time;
  time(&rawtime);
  current_time = localtime(&rawtime);
  return current_time;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_current_time>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct tm *get_current_time() {
  time_t rawtime;
  struct tm *current_time;
  time(&rawtime);
  current_time = localtime(&rawtime);
  return current_time;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<proc4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400000,%edx
  mov    $0x403000,%esi
  mov    $0x403000,%edi
  call   <proc6@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void proc4() {
  proc6(0x403000, 0x403000, 0x400000);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<proc4>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400000,%edx
  mov    $0x403000,%esi
  mov    $0x403000,%edi
  call   <proc6@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void proc4() {
  proc6(0x403000, 0x403000, 0x400000);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<proc4>:
  endbr64
  mov    $0x400000,%edx
  mov    $0x403000,%esi
  mov    $0x403000,%edi
  jmp    1050 <proc6@plt>
```

assistant: ```c
void proc4() {
  proc6(0x403000, 0x403000, 0x400000);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<proc4>:
  endbr64
  mov    $0x400000,%edx
  mov    $0x403000,%esi
  mov    $0x403000,%edi
  jmp    1050 <proc6@plt>
```

assistant: ```c
void proc4() {
  proc6(0x403000, 0x403000, 0x400000);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L11
L50:
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L50
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  cmpl   $0x0,-0xc(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  jmp    L20
L1:
  mov    $0x0,%eax
  jmp    L20
L46:
  mov    -0x8(%rbp),%rax
L20:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)(*s ? s : (c ? ((void *)0) : s));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L54
L50:
  movsbl %al,%edx
  cmp    %esi,%edx
  je     L54
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L50
L54:
  test   %esi,%esi
  je     L55
  mov    $0x0,%edx
  test   %al,%al
  jne    L55
L46:
  mov    %rdx,%rax
  ret
L55:
  mov    %rdi,%rdx
  jmp    L46
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)(*s ? s : (c ? ((void *)0) : s));
}
```