ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<eps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L10
L117:
  mov    D8(%rip),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L98
L33:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L20
L102:
  mov    -0x18(%rbp),%rax
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L9
  movsd  -0x10(%rbp),%xmm0
  jmp    L93
L9:
  mov    -0x18(%rbp),%rax
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  imul   -0x58(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
L93:
  movsd  %xmm0,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jb     L102
  movsd  -0x10(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L81
  movsd  -0x20(%rbp),%xmm0
  jmp    L53
L81:
  movsd  -0x10(%rbp),%xmm0
L53:
  movsd  %xmm0,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L98:
  mov    -0x18(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L33
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L83
  movsd  -0x30(%rbp),%xmm0
  jmp    L85
L83:
  movsd  -0x20(%rbp),%xmm0
L85:
  movsd  %xmm0,-0x30(%rbp)
  addq   $0x1,-0x28(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jb     L117
  movsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double eps(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  double eps_i = 0.0;
  for (size_t i = 0; i < numelB; i++) {
    double eps_j = INFINITY;
    for (size_t j = 0; j < numelA; j++) {
      double eps_k = 0.0;
      for (size_t k = 0; k < nObjs; k++)
        eps_k = (((eps_k) > (A[j * nObjs + k] - B[i * nObjs + k])) ? (eps_k) : (A[j * nObjs + k] - B[i * nObjs + k]));
      eps_j = (((eps_j) < (eps_k)) ? (eps_j) : (eps_k));
    }
    eps_i = (((eps_i) > (eps_j)) ? (eps_i) : (eps_j));
  }
  return eps_i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eps>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  test   %rcx,%rcx
  je     L61
  mov    %rdi,%r10
  mov    %rdx,%r9
  mov    %r8,%rcx
  mov    D7(%rip),%rax
  movsd  (%rax),%xmm4
  lea    0x0(,%r8,8),%r8
  mov    $0x0,%r11d
  pxor   %xmm3,%xmm3
  jmp    L49
L15:
  movsd  (%rdx,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  maxsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L15
L48:
  minsd  %xmm1,%xmm2
  add    $0x1,%rdi
  add    %r8,%rdx
  cmp    %rdi,%r9
  je     L82
L27:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  test   %rcx,%rcx
  jne    L15
  jmp    L48
L9:
  movapd %xmm4,%xmm2
L82:
  maxsd  %xmm2,%xmm3
  add    $0x1,%r11
  add    %r8,%rsi
  cmp    %r11,%rbx
  je     L6
L49:
  test   %r9,%r9
  je     L9
  mov    %r10,%rdx
  movapd %xmm4,%xmm2
  mov    $0x0,%edi
  jmp    L27
L61:
  pxor   %xmm3,%xmm3
L6:
  movapd %xmm3,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double eps(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  double eps_i = 0.0;
  for (size_t i = 0; i < numelB; i++) {
    double eps_j = INFINITY;
    for (size_t j = 0; j < numelA; j++) {
      double eps_k = 0.0;
      for (size_t k = 0; k < nObjs; k++)
        eps_k = (((eps_k) > (A[j * nObjs + k] - B[i * nObjs + k])) ? (eps_k) : (A[j * nObjs + k] - B[i * nObjs + k]));
      eps_j = (((eps_j) < (eps_k)) ? (eps_j) : (eps_k));
    }
    eps_i = (((eps_i) > (eps_j)) ? (eps_i) : (eps_j));
  }
  return eps_i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eps>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  test   %rcx,%rcx
  je     L45
  mov    D2(%rip),%rax
  mov    %r8,%rcx
  mov    %rdi,%r10
  mov    %rdx,%r9
  pxor   %xmm3,%xmm3
  lea    0x0(,%r8,8),%r8
  xor    %r11d,%r11d
  movsd  (%rax),%xmm5
  movapd %xmm3,%xmm4
  nopl   0x0(%rax,%rax,1)
L28:
  test   %r9,%r9
  je     L37
  mov    %r10,%rdx
  movapd %xmm5,%xmm2
  xor    %edi,%edi
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  test   %rcx,%rcx
  je     L11
  nopl   0x0(%rax,%rax,1)
L38:
  movsd  (%rdx,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  maxsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L38
L11:
  add    $0x1,%rdi
  minsd  %xmm1,%xmm2
  add    %r8,%rdx
  cmp    %rdi,%r9
  jne    L6
  add    $0x1,%r11
  maxsd  %xmm2,%xmm4
  add    %r8,%rsi
  cmp    %r11,%rbx
  jne    L28
L69:
  movapd %xmm4,%xmm0
  pop    %rbx
  ret
L37:
  movapd %xmm5,%xmm2
  add    $0x1,%r11
  add    %r8,%rsi
  maxsd  %xmm2,%xmm4
  cmp    %r11,%rbx
  jne    L28
  jmp    L69
L45:
  pxor   %xmm4,%xmm4
  pop    %rbx
  movapd %xmm4,%xmm0
  ret
```

assistant: ```c
double eps(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  double eps_i = 0.0;
  for (size_t i = 0; i < numelB; i++) {
    double eps_j = INFINITY;
    for (size_t j = 0; j < numelA; j++) {
      double eps_k = 0.0;
      for (size_t k = 0; k < nObjs; k++)
        eps_k = (((eps_k) > (A[j * nObjs + k] - B[i * nObjs + k])) ? (eps_k) : (A[j * nObjs + k] - B[i * nObjs + k]));
      eps_j = (((eps_j) < (eps_k)) ? (eps_j) : (eps_k));
    }
    eps_i = (((eps_i) > (eps_j)) ? (eps_i) : (eps_j));
  }
  return eps_i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eps>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  test   %rcx,%rcx
  je     L56
  mov    D5(%rip),%rax
  mov    %r8,%rcx
  mov    %rdi,%r10
  mov    %rdx,%r9
  pxor   %xmm3,%xmm3
  lea    0x0(,%r8,8),%r8
  xor    %r11d,%r11d
  movsd  (%rax),%xmm5
  movapd %xmm3,%xmm4
  nopl   0x0(%rax,%rax,1)
L53:
  test   %r9,%r9
  je     L43
  mov    %r10,%rdx
  movapd %xmm5,%xmm2
  xor    %edi,%edi
  xchg   %ax,%ax
L39:
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  test   %rcx,%rcx
  je     L11
  nopl   0x0(%rax,%rax,1)
L44:
  movsd  (%rdx,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  maxsd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L44
L11:
  add    $0x1,%rdi
  minsd  %xmm1,%xmm2
  add    %r8,%rdx
  cmp    %rdi,%r9
  jne    L39
  add    $0x1,%r11
  maxsd  %xmm2,%xmm4
  add    %r8,%rsi
  cmp    %r11,%rbx
  jne    L53
L22:
  movapd %xmm4,%xmm0
  pop    %rbx
  ret
L43:
  movapd %xmm5,%xmm2
  add    $0x1,%r11
  add    %r8,%rsi
  maxsd  %xmm2,%xmm4
  cmp    %r11,%rbx
  jne    L53
  jmp    L22
L56:
  pxor   %xmm4,%xmm4
  pop    %rbx
  movapd %xmm4,%xmm0
  ret
```

assistant: ```c
double eps(double *A, double *B, size_t numelA, size_t numelB, size_t nObjs) {
  double eps_i = 0.0;
  for (size_t i = 0; i < numelB; i++) {
    double eps_j = INFINITY;
    for (size_t j = 0; j < numelA; j++) {
      double eps_k = 0.0;
      for (size_t k = 0; k < nObjs; k++)
        eps_k = (((eps_k) > (A[j * nObjs + k] - B[i * nObjs + k])) ? (eps_k) : (A[j * nObjs + k] - B[i * nObjs + k]));
      eps_j = (((eps_j) < (eps_k)) ? (eps_j) : (eps_k));
    }
    eps_i = (((eps_i) > (eps_j)) ? (eps_i) : (eps_j));
  }
  return eps_i;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_return>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xd8(%rbp),%rcx
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rename_pop_registers@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1:  %s;

assistant: ```c
void print_return(char *ret_string) {
  char buffer[200];
  rename_pop_registers(buffer, ret_string, 200);
  printf(" %s;", buffer);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_return>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0xc8,%edx
  mov    %rbx,%rdi
  call   <rename_pop_registers@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xd0,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4:  %s;

assistant: ```c
void print_return(char *ret_string) {
  char buffer[200];
  rename_pop_registers(buffer, ret_string, 200);
  printf(" %s;", buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_return>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0xc8,%edx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <rename_pop_registers@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xd0,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string

tool: D6:  %s;

assistant: ```c
void print_return(char *ret_string) {
  char buffer[200];
  rename_pop_registers(buffer, ret_string, 200);
  printf(" %s;", buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_return>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0xc8,%edx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <rename_pop_registers@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xd0,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7:  %s;

assistant: ```c
void print_return(char *ret_string) {
  char buffer[200];
  rename_pop_registers(buffer, ret_string, 200);
  printf(" %s;", buffer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  imul   $0x7b,%rax,%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0xff,-0x4(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) void foo(long long *arr) {
  for (int i = 0; i < 256; i++)
    arr[i] *= 123;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  lea    0x800(%rdi),%rdx
L7:
  imul   $0x7b,(%rdi),%rax
  mov    %rax,(%rdi)
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L7
  ret
```

assistant: ```c
__attribute__((no)) void foo(long long *arr) {
  for (int i = 0; i < 256; i++)
    arr[i] *= 123;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  lea    0x800(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  imul   $0x7b,(%rdi),%rax
  add    $0x8,%rdi
  mov    %rax,-0x8(%rdi)
  cmp    %rdx,%rdi
  jne    L4
  ret
```

assistant: ```c
__attribute__((no)) void foo(long long *arr) {
  for (int i = 0; i < 256; i++)
    arr[i] *= 123;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  lea    0x800(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L1:
  imul   $0x7b,(%rdi),%rax
  add    $0x8,%rdi
  mov    %rax,-0x8(%rdi)
  cmp    %rdx,%rdi
  jne    L1
  ret
```

assistant: ```c
__attribute__((no)) void foo(long long *arr) {
  for (int i = 0; i < 256; i++)
    arr[i] *= 123;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<YYYYMMDDHHMMSS2SECS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x60(%rbp)
  movl   $0xffffffff,-0x5c(%rbp)
  movl   $0xffffffff,-0x58(%rbp)
  movl   $0xffffffff,-0x54(%rbp)
  movl   $0xffffffff,-0x50(%rbp)
  movl   $0xffffffff,-0x4c(%rbp)
  movl   $0xffffffff,-0x48(%rbp)
  movl   $0xffffffff,-0x44(%rbp)
  movq   $0x0,-0x40(%rbp)
  movl   $0x64,-0x4c(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x1,-0x54(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    -0x58(%rbp),%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  lea    0x8(%rax),%r8
  lea    -0x30(%rbp),%rax
  lea    0xc(%rax),%rdi
  lea    -0x30(%rbp),%rax
  lea    0x10(%rax),%rcx
  lea    -0x30(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0x78(%rbp),%rax
  lea    -0x30(%rbp),%rsi
  push   %rsi
  lea    -0x30(%rbp),%rsi
  add    $0x4,%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  add    $0x10,%rsp
  mov    -0x1c(%rbp),%eax
  sub    $0x76c,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0x68(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0x64(%rbp)
  mov    -0x68(%rbp),%edx
  mov    -0x64(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  movq   %xmm0,%rax
  mov    -0x80(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %4d%2d%2d%2d%2d%2d

assistant: ```c
void YYYYMMDDHHMMSS2SECS(char *date, double *time) {
  struct tm t1, t2;
  time_t tt1, tt2;
  t1.tm_sec = -1;
  t1.tm_min = -1;
  t1.tm_hour = -1;
  t1.tm_mday = -1;
  t1.tm_mon = -1;
  t1.tm_year = -1;
  t1.tm_wday = -1;
  t1.tm_yday = -1;
  t1.tm_isdst = 0;
  t1.tm_year = 100;
  t1.tm_mon = 0;
  t1.tm_mday = 1;
  t1.tm_hour = 0;
  t1.tm_min = 0;
  t1.tm_sec = 0;
  ;
  t2 = t1;
  sscanf(date, "%4d%2d%2d%2d%2d%2d", &t2.tm_year, &t2.tm_mon, &t2.tm_mday, &t2.tm_hour, &t2.tm_min, &t2.tm_sec);
  t2.tm_year -= 1900;
  t2.tm_mon -= 1;
  tt1 = mktime(&t1);
  tt2 = mktime(&t2);
  *time = difftime(tt2, tt1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<YYYYMMDDHHMMSS2SECS>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x18(%rsp)
  movl   $0xffffffff,0x1c(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x64,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  movdqa (%rsp),%xmm1
  movaps %xmm1,0x30(%rsp)
  movdqa 0x10(%rsp),%xmm2
  movaps %xmm2,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  lea    0x30(%rsp),%r12
  lea    0x40(%rsp),%rcx
  lea    0x44(%rsp),%rdx
  push   %r12
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x48(%rsp),%r9
  lea    0x4c(%rsp),%r8
  lea    D8(%rip),%rsi
  call   <sscanf@plt>
  subl   $0x76c,0x54(%rsp)
  subl   $0x1,0x50(%rsp)
  lea    0x10(%rsp),%rdi
  call   <mktime@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <difftime@plt>
  movsd  %xmm0,(%rbx)
  add    $0x10,%rsp
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: %4d%2d%2d%2d%2d%2d

assistant: ```c
void YYYYMMDDHHMMSS2SECS(char *date, double *time) {
  struct tm t1, t2;
  time_t tt1, tt2;
  t1.tm_sec = -1;
  t1.tm_min = -1;
  t1.tm_hour = -1;
  t1.tm_mday = -1;
  t1.tm_mon = -1;
  t1.tm_year = -1;
  t1.tm_wday = -1;
  t1.tm_yday = -1;
  t1.tm_isdst = 0;
  t1.tm_year = 100;
  t1.tm_mon = 0;
  t1.tm_mday = 1;
  t1.tm_hour = 0;
  t1.tm_min = 0;
  t1.tm_sec = 0;
  ;
  t2 = t1;
  sscanf(date, "%4d%2d%2d%2d%2d%2d", &t2.tm_year, &t2.tm_mon, &t2.tm_mday, &t2.tm_hour, &t2.tm_min, &t2.tm_sec);
  t2.tm_year -= 1900;
  t2.tm_mon -= 1;
  tt1 = mktime(&t1);
  tt2 = mktime(&t2);
  *time = difftime(tt2, tt1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<YYYYMMDDHHMMSS2SECS>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D4(%rip),%rsi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  lea    0x40(%rsp),%rcx
  movabs $0x100000000,%rax
  mov    %rax,0x8(%rsp)
  lea    0x44(%rsp),%rdx
  movabs $0x6400000000,%rax
  mov    %rax,0x10(%rsp)
  movq   $0x0,(%rsp)
  movdqa (%rsp),%xmm1
  movq   $0xffffffffffffffff,0x18(%rsp)
  movdqa 0x10(%rsp),%xmm2
  movaps %xmm1,0x30(%rsp)
  movaps %xmm2,0x40(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x50(%rsp)
  push   %r12
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x48(%rsp),%r9
  lea    0x4c(%rsp),%r8
  call   <sscanf@plt>
  lea    0x10(%rsp),%rdi
  subl   $0x1,0x50(%rsp)
  subl   $0x76c,0x54(%rsp)
  call   <mktime@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <mktime@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  pop    %rax
  pop    %rdx
  movsd  %xmm0,(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: %4d%2d%2d%2d%2d%2d

assistant: ```c
void YYYYMMDDHHMMSS2SECS(char *date, double *time) {
  struct tm t1, t2;
  time_t tt1, tt2;
  t1.tm_sec = -1;
  t1.tm_min = -1;
  t1.tm_hour = -1;
  t1.tm_mday = -1;
  t1.tm_mon = -1;
  t1.tm_year = -1;
  t1.tm_wday = -1;
  t1.tm_yday = -1;
  t1.tm_isdst = 0;
  t1.tm_year = 100;
  t1.tm_mon = 0;
  t1.tm_mday = 1;
  t1.tm_hour = 0;
  t1.tm_min = 0;
  t1.tm_sec = 0;
  ;
  t2 = t1;
  sscanf(date, "%4d%2d%2d%2d%2d%2d", &t2.tm_year, &t2.tm_mon, &t2.tm_mday, &t2.tm_hour, &t2.tm_min, &t2.tm_sec);
  t2.tm_year -= 1900;
  t2.tm_mon -= 1;
  tt1 = mktime(&t1);
  tt2 = mktime(&t2);
  *time = difftime(tt2, tt1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<YYYYMMDDHHMMSS2SECS>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D33(%rip),%rsi
  sub    $0x60,%rsp
  movdqa D19(%rip),%xmm1
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  lea    0x40(%rsp),%rcx
  movq   $0x0,0x20(%rsp)
  lea    0x44(%rsp),%rdx
  movaps %xmm1,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm1,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  push   %r12
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x48(%rsp),%r9
  lea    0x4c(%rsp),%r8
  call   <sscanf@plt>
  movq   0x50(%rsp),%xmm0
  lea    0x10(%rsp),%rdi
  movq   D0(%rip),%xmm1
  paddd  %xmm1,%xmm0
  movq   %xmm0,0x50(%rsp)
  call   <mktime@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <mktime@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  pop    %rax
  pop    %rdx
  movsd  %xmm0,(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D33
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: byte[16]
name: unpack_data
arguments: data_label: D13
type_infered: byte[16]
name: unpack_data
arguments: data_label: D0
type_infered: byte[8]

tool: D33: %4d%2d%2d%2d%2d%2d

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x64,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: {"D0": [0xff,0xff,0xff,0xff,0x94,0xf8,0xff,0xff]}

assistant: ```c
void YYYYMMDDHHMMSS2SECS(char *date, double *time) {
  struct tm t1, t2;
  time_t tt1, tt2;
  t1.tm_sec = -1;
  t1.tm_min = -1;
  t1.tm_hour = -1;
  t1.tm_mday = -1;
  t1.tm_mon = -1;
  t1.tm_year = -1;
  t1.tm_wday = -1;
  t1.tm_yday = -1;
  t1.tm_isdst = 0;
  t1.tm_year = 100;
  t1.tm_mon = 0;
  t1.tm_mday = 1;
  t1.tm_hour = 0;
  t1.tm_min = 0;
  t1.tm_sec = 0;
  ;
  t2 = t1;
  sscanf(date, "%4d%2d%2d%2d%2d%2d", &t2.tm_year, &t2.tm_mon, &t2.tm_mday, &t2.tm_hour, &t2.tm_min, &t2.tm_sec);
  t2.tm_year -= 1900;
  t2.tm_mon -= 1;
  tt1 = mktime(&t1);
  tt2 = mktime(&t2);
  *time = difftime(tt2, tt1);
}
```
user: What is the c source code of the assembly code below?

```asm
<find_overlay_mount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    -0xc(%rbp),%eax
  jmp    L31
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L24
  movl   $0x0,-0xc(%rbp)
L24:
  cmpl   $0x0,-0xc(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x100,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L2
L20:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
L31:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D34
type_guessed: string

tool: D9: r

tool: D34: /proc/mounts

assistant: ```c
int find_overlay_mount(char *overlay) {
  FILE *fp = fopen("/proc/mounts", "r");
  static char line[256];
  int ret = -1;
  if (!fp)
    return ret;
  while (ret && fgets(line, sizeof(line), fp))
    if (!strncmp(line, overlay, strlen(overlay)))
      ret = 0;
  fclose(fp);
  return ret;
}
```