ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    $0x1,%edi
  test   %eax,%eax
  jle    L55
  lea    0x1(%rdi),%r12d
  cmp    %r12d,0x4(%rsp)
  jl     L55
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %esi,%esi
  mov    $0x1,%ecx
  jmp    L64
  nopl   0x0(%rax)
L77:
  mov    %eax,%ecx
L64:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  lea    0x1(%rcx),%eax
  cmp    %ecx,%edi
  jne    L77
  cmp    %r12d,%esi
  je     L46
L3:
  mov    %r12d,%edi
  lea    0x1(%rdi),%r12d
  cmp    %r12d,0x4(%rsp)
  jge    L16
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L3
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D17: %d

tool: D14: %d 

assistant: ```c
int main() {
  int n, m;
  scanf("%d", &m);
  for (n = 1; n <= m; n++) {
    int fac, sum;
    for (sum = 0, fac = 1; fac < n; fac++)
      if (n % fac == 0)
        sum += fac;
    if (sum == n) {
      printf("%d ", n);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  mov    $0x1,%edi
  test   %r8d,%r8d
  jle    L37
  lea    0x1(%rdi),%r12d
  cmp    %r12d,%r8d
  jl     L37
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %esi,%esi
  mov    $0x1,%ecx
  jmp    L51
  nopl   0x0(%rax)
L64:
  mov    %eax,%ecx
L51:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  lea    0x1(%rcx),%eax
  cmp    %edi,%ecx
  jne    L64
  cmp    %r12d,%esi
  je     L35
L5:
  mov    %r12d,%edi
  lea    0x1(%rdi),%r12d
  cmp    %r12d,%r8d
  jge    L21
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%r8d
  jmp    L5
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D7
data_type: string

tool: D0: %d

tool: D7: %d 

assistant: ```c
int main() {
  int n, m;
  scanf("%d", &m);
  for (n = 1; n <= m; n++) {
    int fac, sum;
    for (sum = 0, fac = 1; fac < n; fac++)
      if (n % fac == 0)
        sum += fac;
    if (sum == n) {
      printf("%d ", n);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dd_mlt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_two_prod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <dd_quick_two_sum@plt>
  movq   %xmm0,%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void dd_mlt(double *a, const double *b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b[0], &p2);
  p2 += b[1] * a[0];
  p2 += b[0] * a[1];
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dd_mlt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movsd  (%rsi),%xmm1
  movsd  (%rbx),%xmm0
  call   <dd_two_prod@plt>
  movsd  0x8(%rbp),%xmm1
  mulsd  (%rbx),%xmm1
  addsd  (%rsp),%xmm1
  movsd  0x0(%rbp),%xmm2
  mulsd  0x8(%rbx),%xmm2
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsp)
  lea    0x8(%rbx),%rdi
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt(double *a, const double *b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b[0], &p2);
  p2 += b[1] * a[0];
  p2 += b[0] * a[1];
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dd_mlt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rbx),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <dd_two_prod@plt>
  movsd  0x0(%rbp),%xmm2
  mulsd  0x8(%rbx),%xmm2
  lea    0x8(%rbx),%rdi
  movsd  0x8(%rbp),%xmm1
  mulsd  (%rbx),%xmm1
  addsd  (%rsp),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsp)
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt(double *a, const double *b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b[0], &p2);
  p2 += b[1] * a[0];
  p2 += b[0] * a[1];
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dd_mlt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  (%rsi),%xmm1
  movsd  (%rbx),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <dd_two_prod@plt>
  movsd  0x0(%rbp),%xmm2
  mulsd  0x8(%rbx),%xmm2
  lea    0x8(%rbx),%rdi
  movsd  0x8(%rbp),%xmm1
  mulsd  (%rbx),%xmm1
  addsd  (%rsp),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rsp)
  call   <dd_quick_two_sum@plt>
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dd_mlt(double *a, const double *b) {
  double p1, p2;
  p1 = dd_two_prod(a[0], b[0], &p2);
  p2 += b[1] * a[0];
  p2 += b[0] * a[1];
  a[0] = dd_quick_two_sum(p1, p2, &a[1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xorshift128plus_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  cmpl   $0x0,-0xc(%rbp)
  je     L12
  mov    -0xc(%rbp),%eax
  neg    %eax
  cmp    %eax,-0x14(%rbp)
  jl     L12
  mov    $0x1,%eax
  jmp    L22
L12:
  mov    $0x0,%eax
L22:
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x17,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x9,%eax
  or     %edx,%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0xe,%eax
  xor    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  shl    $0x17,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sar    $0x9,%eax
  or     %edx,%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0xe,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  sar    $0x12,%eax
  or     %eax,%ecx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  sar    $0x1c,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  sar    $0x1c,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t xorshift128plus_32(uint32_t *state) {
  uint32_t x, y, z, w, t;
  x = state[0];
  y = state[1];
  z = state[2];
  w = state[3];
  t = y + w + (z != 0 && x >= -z ? 1 : 0);
  z ^= x;
  w ^= y;
  state[0] = ((y << 23) | (x >> 9)) ^ z ^ (z << 14);
  state[1] = ((x << 23) | (y >> 9)) ^ w ^ ((w << 14) | (z >> 18));
  state[2] = (w << 4) | (z >> 28);
  state[3] = (z << 4) | (w >> 28);
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<xorshift128plus_32>:
  endbr64
  mov    %rdi,%rsi
  mov    (%rdi),%ecx
  mov    0x4(%rdi),%r10d
  mov    0x8(%rdi),%edx
  mov    0xc(%rdi),%edi
  lea    (%r10,%rdi,1),%eax
  mov    %edx,%r9d
  test   %edx,%edx
  je     L8
  mov    %edx,%r8d
  neg    %r8d
  cmp    %ecx,%r8d
  setle  %r9b
  movzbl %r9b,%r9d
L8:
  xor    %ecx,%edx
  xor    %r10d,%edi
  mov    %r10d,%r8d
  shl    $0x17,%r8d
  mov    %ecx,%r11d
  sar    $0x9,%r11d
  or     %r11d,%r8d
  mov    %edx,%r11d
  shl    $0xe,%r11d
  xor    %r11d,%r8d
  xor    %edx,%r8d
  mov    %r8d,(%rsi)
  shl    $0x17,%ecx
  sar    $0x9,%r10d
  or     %r10d,%ecx
  xor    %edi,%ecx
  mov    %edi,%r8d
  shl    $0xe,%r8d
  mov    %edx,%r10d
  sar    $0x12,%r10d
  or     %r10d,%r8d
  xor    %r8d,%ecx
  mov    %ecx,0x4(%rsi)
  mov    %edi,%ecx
  shl    $0x4,%ecx
  mov    %edx,%r8d
  sar    $0x1c,%r8d
  or     %r8d,%ecx
  mov    %ecx,0x8(%rsi)
  shl    $0x4,%edx
  sar    $0x1c,%edi
  or     %edi,%edx
  mov    %edx,0xc(%rsi)
  add    %r9d,%eax
  ret
```

assistant: ```c
uint32_t xorshift128plus_32(uint32_t *state) {
  uint32_t x, y, z, w, t;
  x = state[0];
  y = state[1];
  z = state[2];
  w = state[3];
  t = y + w + (z != 0 && x >= -z ? 1 : 0);
  z ^= x;
  w ^= y;
  state[0] = ((y << 23) | (x >> 9)) ^ z ^ (z << 14);
  state[1] = ((x << 23) | (y >> 9)) ^ w ^ ((w << 14) | (z >> 18));
  state[2] = (w << 4) | (z >> 28);
  state[3] = (z << 4) | (w >> 28);
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xorshift128plus_32>:
  endbr64
  mov    0x4(%rdi),%r9d
  mov    0xc(%rdi),%esi
  mov    %rdi,%rcx
  mov    0x8(%rdi),%eax
  mov    (%rdi),%edx
  lea    (%r9,%rsi,1),%r8d
  test   %eax,%eax
  je     L2
  mov    %eax,%edi
  neg    %edi
  cmp    %edx,%edi
  setle  %dil
  movzbl %dil,%edi
  add    %edi,%r8d
L2:
  mov    %r9d,%edi
  mov    %edx,%r10d
  xor    %edx,%eax
  xor    %r9d,%esi
  sar    $0x9,%r10d
  shl    $0x17,%edi
  sar    $0x9,%r9d
  or     %r10d,%edi
  mov    %eax,%r10d
  shl    $0x17,%edx
  shl    $0xe,%r10d
  or     %r9d,%edx
  mov    %eax,%r9d
  xor    %r10d,%edi
  sar    $0x12,%r9d
  xor    %esi,%edx
  xor    %eax,%edi
  mov    %edi,(%rcx)
  mov    %esi,%edi
  shl    $0xe,%edi
  or     %r9d,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x4,%eax
  mov    %edx,0x4(%rcx)
  mov    %esi,%edx
  sar    $0x1c,%edi
  shl    $0x4,%edx
  sar    $0x1c,%esi
  or     %esi,%eax
  or     %edi,%edx
  mov    %eax,0xc(%rcx)
  mov    %r8d,%eax
  mov    %edx,0x8(%rcx)
  ret
```

assistant: ```c
uint32_t xorshift128plus_32(uint32_t *state) {
  uint32_t x, y, z, w, t;
  x = state[0];
  y = state[1];
  z = state[2];
  w = state[3];
  t = y + w + (z != 0 && x >= -z ? 1 : 0);
  z ^= x;
  w ^= y;
  state[0] = ((y << 23) | (x >> 9)) ^ z ^ (z << 14);
  state[1] = ((x << 23) | (y >> 9)) ^ w ^ ((w << 14) | (z >> 18));
  state[2] = (w << 4) | (z >> 28);
  state[3] = (z << 4) | (w >> 28);
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xorshift128plus_32>:
  endbr64
  mov    0x4(%rdi),%r9d
  mov    (%rdi),%edx
  mov    %rdi,%rsi
  mov    0x8(%rdi),%eax
  mov    0xc(%rdi),%edi
  lea    (%r9,%rdi,1),%r8d
  test   %eax,%eax
  je     L8
  mov    %eax,%ecx
  neg    %ecx
  cmp    %edx,%ecx
  setle  %cl
  movzbl %cl,%ecx
  add    %ecx,%r8d
L8:
  mov    %r9d,%ecx
  mov    %edx,%r10d
  xor    %edx,%eax
  xor    %r9d,%edi
  sar    $0x9,%r10d
  shl    $0x17,%ecx
  sar    $0x9,%r9d
  or     %r10d,%ecx
  mov    %eax,%r10d
  shl    $0x17,%edx
  shl    $0xe,%r10d
  or     %r9d,%edx
  mov    %eax,%r9d
  xor    %r10d,%ecx
  sar    $0x12,%r9d
  xor    %edi,%edx
  xor    %eax,%ecx
  movd   %ecx,%xmm0
  mov    %edi,%ecx
  shl    $0xe,%ecx
  or     %r9d,%ecx
  mov    %eax,%r9d
  shl    $0x4,%eax
  xor    %ecx,%edx
  mov    %edi,%ecx
  sar    $0x1c,%r9d
  shl    $0x4,%ecx
  sar    $0x1c,%edi
  movd   %edx,%xmm3
  or     %edi,%eax
  or     %r9d,%ecx
  punpckldq %xmm3,%xmm0
  movd   %eax,%xmm2
  movd   %ecx,%xmm1
  mov    %r8d,%eax
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rsi)
  ret
```

assistant: ```c
uint32_t xorshift128plus_32(uint32_t *state) {
  uint32_t x, y, z, w, t;
  x = state[0];
  y = state[1];
  z = state[2];
  w = state[3];
  t = y + w + (z != 0 && x >= -z ? 1 : 0);
  z ^= x;
  w ^= y;
  state[0] = ((y << 23) | (x >> 9)) ^ z ^ (z << 14);
  state[1] = ((x << 23) | (y >> 9)) ^ w ^ ((w << 14) | (z >> 18));
  state[2] = (w << 4) | (z >> 28);
  state[3] = (z << 4) | (w >> 28);
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: +---------------------------------------+
|        Doom's OTP Service v1.0        |
+---------------------------------------+
|------------ Services Menu ------------|
|---------------------------------------|
| 1. Create secure message              |
| 2. Edit secure message                |
| 3. Destroy secure message             |
| 4. Print message details              |
| 5. Quit                               |
+---------------------------------------+


assistant: ```c
void print_menu() {
  printf("+---------------------------------------+\n"
         "|        Doom's OTP Service v1.0        |\n"
         "+---------------------------------------+\n"
         "|------------ Services Menu ------------|\n"
         "|---------------------------------------|\n"
         "| 1. Create secure message              |\n"
         "| 2. Edit secure message                |\n"
         "| 3. Destroy secure message             |\n"
         "| 4. Print message details              |\n"
         "| 5. Quit                               |\n"
         "+---------------------------------------+\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: +---------------------------------------+
|        Doom's OTP Service v1.0        |
+---------------------------------------+
|------------ Services Menu ------------|
|---------------------------------------|
| 1. Create secure message              |
| 2. Edit secure message                |
| 3. Destroy secure message             |
| 4. Print message details              |
| 5. Quit                               |
+---------------------------------------+


assistant: ```c
void print_menu() {
  printf("+---------------------------------------+\n"
         "|        Doom's OTP Service v1.0        |\n"
         "+---------------------------------------+\n"
         "|------------ Services Menu ------------|\n"
         "|---------------------------------------|\n"
         "| 1. Create secure message              |\n"
         "| 2. Edit secure message                |\n"
         "| 3. Destroy secure message             |\n"
         "| 4. Print message details              |\n"
         "| 5. Quit                               |\n"
         "+---------------------------------------+\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_menu>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: +---------------------------------------+
|        Doom's OTP Service v1.0        |
+---------------------------------------+
|------------ Services Menu ------------|
|---------------------------------------|
| 1. Create secure message              |
| 2. Edit secure message                |
| 3. Destroy secure message             |
| 4. Print message details              |
| 5. Quit                               |
+---------------------------------------+


assistant: ```c
void print_menu() {
  printf("+---------------------------------------+\n"
         "|        Doom's OTP Service v1.0        |\n"
         "+---------------------------------------+\n"
         "|------------ Services Menu ------------|\n"
         "|---------------------------------------|\n"
         "| 1. Create secure message              |\n"
         "| 2. Edit secure message                |\n"
         "| 3. Destroy secure message             |\n"
         "| 4. Print message details              |\n"
         "| 5. Quit                               |\n"
         "+---------------------------------------+\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_menu>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: +---------------------------------------+
|        Doom's OTP Service v1.0        |
+---------------------------------------+
|------------ Services Menu ------------|
|---------------------------------------|
| 1. Create secure message              |
| 2. Edit secure message                |
| 3. Destroy secure message             |
| 4. Print message details              |
| 5. Quit                               |
+---------------------------------------+


assistant: ```c
void print_menu() {
  printf("+---------------------------------------+\n"
         "|        Doom's OTP Service v1.0        |\n"
         "+---------------------------------------+\n"
         "|------------ Services Menu ------------|\n"
         "|---------------------------------------|\n"
         "| 1. Create secure message              |\n"
         "| 2. Edit secure message                |\n"
         "| 3. Destroy secure message             |\n"
         "| 4. Print message details              |\n"
         "| 5. Quit                               |\n"
         "+---------------------------------------+\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Readline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readline@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: readline error


assistant: ```c
ssize_t Readline(int fd, void *ptr, size_t maxlen) {
  ssize_t n;
  if ((n = readline(fd, ptr, maxlen)) < 0) {
    printf("readline error\n");
    exit(1);
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Readline>:
  endbr64
  push   %rbx
  call   <readline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L13
L16:
  mov    %ebx,%eax
  pop    %rbx
  ret
L13:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: readline error


assistant: ```c
ssize_t Readline(int fd, void *ptr, size_t maxlen) {
  ssize_t n;
  if ((n = readline(fd, ptr, maxlen)) < 0) {
    printf("readline error\n");
    exit(1);
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Readline>:
  endbr64
  push   %r12
  call   <readline@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L4
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: readline error


assistant: ```c
ssize_t Readline(int fd, void *ptr, size_t maxlen) {
  ssize_t n;
  if ((n = readline(fd, ptr, maxlen)) < 0) {
    printf("readline error\n");
    exit(1);
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Readline>:
  endbr64
  push   %r12
  call   <readline@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L6
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: readline error


assistant: ```c
ssize_t Readline(int fd, void *ptr, size_t maxlen) {
  ssize_t n;
  if ((n = readline(fd, ptr, maxlen)) < 0) {
    printf("readline error\n");
    exit(1);
  }
  return n;
}
```