ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0xa,%r10d
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xaa(%rsp),%r11
  mov    %rsp,%rbx
  lea    0x80(%rsp),%r9
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rdx
  mov    %r11,%rcx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L4:
  movswl -0x2(%rcx),%esi
  movswl 0x2(%rdx),%eax
  add    $0x4,%rdx
  sub    $0x4,%rcx
  movswl -0x4(%rdx),%r8d
  imul   %esi,%eax
  movswl 0x4(%rcx),%esi
  imul   %r8d,%esi
  add    %esi,%eax
  add    %eax,%edi
  cmp    %rdx,%r9
  jne    L4
  add    $0x1,%r10d
  add    $0x4,%r11
  cmp    $0x6e,%r10d
  jne    L19
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x220,%rsp
  pop    %rbx
  jmp    1060 <bar@plt>
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo() {
  short coefs[2 * 32];
  short input[2 * 100];
  short output[2 * 100];
  int sum_real, sum_imag;
  int i, j, k;
  k = 10;
  for (i = 0; i < 100; i++) {
    sum_real = 0;
    sum_imag = 0;
    for (j = 0; j < 32; j++) {
      sum_real += input[2 * k - 2 * j + 1] * coefs[2 * j + 1] - input[2 * k - 2 * j] * coefs[2 * j];
      sum_imag += input[2 * k - 2 * j] * coefs[2 * j + 1] + input[2 * k - 2 * j + 1] * coefs[2 * j];
    }
    output[2 * i + 1] = sum_imag;
    output[2 * i] = sum_real;
    k++;
  }
  bar(sum_imag);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0xa,%r10d
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xaa(%rsp),%r11
  mov    %rsp,%rbx
  lea    0x80(%rsp),%r9
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rdx
  mov    %r11,%rcx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L12:
  movswl -0x2(%rcx),%esi
  movswl 0x2(%rdx),%eax
  add    $0x4,%rdx
  sub    $0x4,%rcx
  movswl -0x4(%rdx),%r8d
  imul   %esi,%eax
  movswl 0x4(%rcx),%esi
  imul   %r8d,%esi
  add    %esi,%eax
  add    %eax,%edi
  cmp    %r9,%rdx
  jne    L12
  add    $0x1,%r10d
  add    $0x4,%r11
  cmp    $0x6e,%r10d
  jne    L19
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x220,%rsp
  pop    %rbx
  jmp    1060 <bar@plt>
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo() {
  short coefs[2 * 32];
  short input[2 * 100];
  short output[2 * 100];
  int sum_real, sum_imag;
  int i, j, k;
  k = 10;
  for (i = 0; i < 100; i++) {
    sum_real = 0;
    sum_imag = 0;
    for (j = 0; j < 32; j++) {
      sum_real += input[2 * k - 2 * j + 1] * coefs[2 * j + 1] - input[2 * k - 2 * j] * coefs[2 * j];
      sum_imag += input[2 * k - 2 * j] * coefs[2 * j + 1] + input[2 * k - 2 * j + 1] * coefs[2 * j];
    }
    output[2 * i + 1] = sum_imag;
    output[2 * i] = sum_real;
    k++;
  }
  bar(sum_imag);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<updatePre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D37(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x30(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x30(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D2(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D37
datatype: byte[8]
name: retrieve_data
arguments: label: D20
datatype: byte[8]
name: retrieve_data
arguments: label: D2
datatype: byte[8]
name: retrieve_data
arguments: label: D12
datatype: byte[8]

tool: {"D37": [0xfe,0x9c,0x2b,0xfd,0x7c,0xae,0xef,0x3f]}

tool: {"D20": [0xcf,0x7b,0xa4,0xca,0xe3,0x0d,0xef,0x3f]}

tool: {"D2": [0x33,0x33,0x33,0x33,0x33,0x33,0xc3,0x3f]}

tool: {"D12": [0x9f,0x48,0x6c,0x49,0x7b,0xa5,0xef,0x3f]}

assistant: ```c
void updatePre(double *sue, double *sui, double *psp, double *pspS, double *pspTilde, double pre) {
  *sue = exp(-.1 * .1) * *sue + pre;
  *sui = exp(-.3 * .1) * *sui + pre;
  *psp = .1 * .3 / (.3 - .1) * (*sue - *sui);
  *pspS = *psp;
  *pspTilde = exp(-.1 / 9) * *pspTilde + *pspS;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<updatePre>:
  endbr64
  movsd  D12(%rip),%xmm1
  mulsd  (%rdi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D21(%rip),%xmm1
  mulsd  (%rsi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  (%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D24(%rip),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  movsd  D3(%rip),%xmm1
  mulsd  (%r8),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8)
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: byte[8]
name: parse_data
arguments: tag: D21
type_infered: byte[8]
name: parse_data
arguments: tag: D24
type_infered: byte[8]
name: parse_data
arguments: tag: D3
type_infered: byte[8]

tool: {"D12": [0xfe,0x9c,0x2b,0xfd,0x7c,0xae,0xef,0x3f]}

tool: {"D21": [0xcf,0x7b,0xa4,0xca,0xe3,0x0d,0xef,0x3f]}

tool: {"D24": [0x33,0x33,0x33,0x33,0x33,0x33,0xc3,0x3f]}

tool: {"D3": [0x9f,0x48,0x6c,0x49,0x7b,0xa5,0xef,0x3f]}

assistant: ```c
void updatePre(double *sue, double *sui, double *psp, double *pspS, double *pspTilde, double pre) {
  *sue = exp(-.1 * .1) * *sue + pre;
  *sui = exp(-.3 * .1) * *sui + pre;
  *psp = .1 * .3 / (.3 - .1) * (*sue - *sui);
  *pspS = *psp;
  *pspTilde = exp(-.1 / 9) * *pspTilde + *pspS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<updatePre>:
  endbr64
  movsd  D4(%rip),%xmm1
  mulsd  (%rdi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D15(%rip),%xmm1
  mulsd  (%rsi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  (%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D10(%rip),%xmm0
  movsd  D22(%rip),%xmm1
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  mulsd  (%r8),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: byte[8]
name: disassemble_data
arguments: label: D15
type_guessed: byte[8]
name: disassemble_data
arguments: label: D10
type_guessed: byte[8]
name: disassemble_data
arguments: label: D22
type_guessed: byte[8]

tool: {"D4": [0xfe,0x9c,0x2b,0xfd,0x7c,0xae,0xef,0x3f]}

tool: {"D15": [0xcf,0x7b,0xa4,0xca,0xe3,0x0d,0xef,0x3f]}

tool: {"D10": [0x33,0x33,0x33,0x33,0x33,0x33,0xc3,0x3f]}

tool: {"D22": [0x9f,0x48,0x6c,0x49,0x7b,0xa5,0xef,0x3f]}

assistant: ```c
void updatePre(double *sue, double *sui, double *psp, double *pspS, double *pspTilde, double pre) {
  *sue = exp(-.1 * .1) * *sue + pre;
  *sui = exp(-.3 * .1) * *sui + pre;
  *psp = .1 * .3 / (.3 - .1) * (*sue - *sui);
  *pspS = *psp;
  *pspTilde = exp(-.1 / 9) * *pspTilde + *pspS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<updatePre>:
  endbr64
  movsd  D22(%rip),%xmm1
  mulsd  (%rdi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  movsd  D18(%rip),%xmm1
  mulsd  (%rsi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  movsd  (%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D31(%rip),%xmm0
  movsd  D21(%rip),%xmm1
  movsd  %xmm0,(%rdx)
  movsd  %xmm0,(%rcx)
  mulsd  (%r8),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D22
datatype: byte[8]
name: disassemble_data
arguments: data_label: D18
datatype: byte[8]
name: disassemble_data
arguments: data_label: D31
datatype: byte[8]
name: disassemble_data
arguments: data_label: D21
datatype: byte[8]

tool: {"D22": [0xfe,0x9c,0x2b,0xfd,0x7c,0xae,0xef,0x3f]}

tool: {"D18": [0xcf,0x7b,0xa4,0xca,0xe3,0x0d,0xef,0x3f]}

tool: {"D31": [0x33,0x33,0x33,0x33,0x33,0x33,0xc3,0x3f]}

tool: {"D21": [0x9f,0x48,0x6c,0x49,0x7b,0xa5,0xef,0x3f]}

assistant: ```c
void updatePre(double *sue, double *sui, double *psp, double *pspS, double *pspTilde, double pre) {
  *sue = exp(-.1 * .1) * *sue + pre;
  *sui = exp(-.3 * .1) * *sui + pre;
  *psp = .1 * .3 / (.3 - .1) * (*sue - *sui);
  *pspS = *psp;
  *pspTilde = exp(-.1 / 9) * *pspTilde + *pspS;
}
```
user: What is the c source code of the assembly code below?

```asm
<CLOCK_SYS_GetEwmFreq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <CLOCK_SYS_GetLpoClockFreq@plt>
  leave
  ret
```

assistant: ```c
uint32_t CLOCK_SYS_GetEwmFreq(uint32_t instance) {
  (void)instance;
  return CLOCK_SYS_GetLpoClockFreq();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CLOCK_SYS_GetEwmFreq>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CLOCK_SYS_GetLpoClockFreq@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t CLOCK_SYS_GetEwmFreq(uint32_t instance) {
  (void)instance;
  return CLOCK_SYS_GetLpoClockFreq();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CLOCK_SYS_GetEwmFreq>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <CLOCK_SYS_GetLpoClockFreq@plt>
```

assistant: ```c
uint32_t CLOCK_SYS_GetEwmFreq(uint32_t instance) {
  (void)instance;
  return CLOCK_SYS_GetLpoClockFreq();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CLOCK_SYS_GetEwmFreq>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <CLOCK_SYS_GetLpoClockFreq@plt>
```

assistant: ```c
uint32_t CLOCK_SYS_GetEwmFreq(uint32_t instance) {
  (void)instance;
  return CLOCK_SYS_GetLpoClockFreq();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L5:
  movl   $0x4,-0x1c(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: f32

tool: D9: 3.14

assistant: ```c
int main() {
  volatile struct {
    struct s {
      int ii;
      float fp[4];
    } XYZ;
    int i;
    int j;
  } ABC;
  while (1) {
    ABC.i = 4;
    ABC.XYZ.fp[2] = 3.14;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    %fs:0x28,%rax
  mov    %rax,-0x10(%rsp)
  xor    %eax,%eax
  movss  D6(%rip),%xmm0
L6:
  movl   $0x4,-0x24(%rsp)
  movss  %xmm0,-0x2c(%rsp)
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: f32

tool: D6: 3.14

assistant: ```c
int main() {
  volatile struct {
    struct s {
      int ii;
      float fp[4];
    } XYZ;
    int i;
    int j;
  } ABC;
  while (1) {
    ABC.i = 4;
    ABC.XYZ.fp[2] = 3.14;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    %fs:0x28,%rax
  mov    %rax,-0x10(%rsp)
  xor    %eax,%eax
  movss  D4(%rip),%xmm0
  nopl   0x0(%rax)
L5:
  movl   $0x4,-0x24(%rsp)
  movss  %xmm0,-0x2c(%rsp)
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: f32

tool: D4: 3.14

assistant: ```c
int main() {
  volatile struct {
    struct s {
      int ii;
      float fp[4];
    } XYZ;
    int i;
    int j;
  } ABC;
  while (1) {
    ABC.i = 4;
    ABC.XYZ.fp[2] = 3.14;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    %fs:0x28,%rax
  mov    %rax,-0x10(%rsp)
  xor    %eax,%eax
  movss  D4(%rip),%xmm0
  nopl   0x0(%rax)
L7:
  movl   $0x4,-0x24(%rsp)
  movss  %xmm0,-0x2c(%rsp)
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: f32

tool: D4: 3.14

assistant: ```c
int main() {
  volatile struct {
    struct s {
      int ii;
      float fp[4];
    } XYZ;
    int i;
    int j;
  } ABC;
  while (1) {
    ABC.i = 4;
    ABC.XYZ.fp[2] = 3.14;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int file_exists(const char *path) {
  struct stat st;
  return stat(path, &st) == 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(const char *path) {
  struct stat st;
  return stat(path, &st) == 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(const char *path) {
  struct stat st;
  return stat(path, &st) == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int file_exists(const char *path) {
  struct stat st;
  return stat(path, &st) == 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dynarr_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L5
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L3
L5:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
void *dynarr_get(void **arr, size_t index) {
  size_t size = *((size_t *)arr[0]);
  return (index >= size) ? NULL : arr[index + 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dynarr_get>:
  endbr64
  mov    (%rdi),%rdx
  mov    $0x0,%eax
  cmp    %rsi,(%rdx)
  jbe    L0
  mov    0x8(%rdi,%rsi,8),%rax
L0:
  ret
```

assistant: ```c
void *dynarr_get(void **arr, size_t index) {
  size_t size = *((size_t *)arr[0]);
  return (index >= size) ? NULL : arr[index + 1];
}
```
user: What is the c source code of the assembly code below?

```asm
<dynarr_get>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  cmp    %rsi,(%rdx)
  jbe    L5
  mov    0x8(%rdi,%rsi,8),%rax
L5:
  ret
```

assistant: ```c
void *dynarr_get(void **arr, size_t index) {
  size_t size = *((size_t *)arr[0]);
  return (index >= size) ? NULL : arr[index + 1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dynarr_get>:
  endbr64
  mov    (%rdi),%rdx
  xor    %eax,%eax
  cmp    %rsi,(%rdx)
  jbe    L1
  mov    0x8(%rdi,%rsi,8),%rax
L1:
  ret
```

assistant: ```c
void *dynarr_get(void **arr, size_t index) {
  size_t size = *((size_t *)arr[0]);
  return (index >= size) ? NULL : arr[index + 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<exp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L8
L18:
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  test   %rax,%rax
  js     L36
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L30
L36:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L30:
  movss  -0x8(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L8:
  movss  -0x4(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd D1(%rip),%xmm2
  ja     L18
  movss  -0x14(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: f32
name: read_data
arguments: data_tag: D1
type_infered: f64

tool: D11: 1

tool: D1: 1e-06

assistant: ```c
float exp(float x) {
  float result = 1.0;
  unsigned n = 1;
  float power = 1.0;
  float factorial = 1.0;
  float old = 0.0;
  while (fabs(old - result) > 0.000001) {
    old = result;
    power *= x;
    factorial *= n;
    result += (power / factorial);
    n++;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<exp>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  movss  D11(%rip),%xmm7
  movss  %xmm7,0x8(%rsp)
  movss  %xmm7,0x4(%rsp)
  mov    $0x1,%ebx
  movss  %xmm7,(%rsp)
  jmp    L6
L1:
  movss  0x4(%rsp),%xmm2
  mulss  0xc(%rsp),%xmm2
  movss  %xmm2,0x4(%rsp)
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm1
  divss  %xmm0,%xmm1
  add    $0x1,%ebx
  movss  (%rsp),%xmm3
  movaps %xmm3,%xmm0
  addss  %xmm3,%xmm1
  movss  %xmm1,(%rsp)
L6:
  subss  (%rsp),%xmm0
  call   <fabs@plt>
  comisd D17(%rip),%xmm0
  ja     L1
  movss  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
data_type: f32
name: disassemble_data
arguments: data_label: D17
data_type: f64

tool: D11: 1

tool: D17: 1e-06

assistant: ```c
float exp(float x) {
  float result = 1.0;
  unsigned n = 1;
  float power = 1.0;
  float factorial = 1.0;
  float old = 0.0;
  while (fabs(old - result) > 0.000001) {
    old = result;
    power *= x;
    factorial *= n;
    result += (power / factorial);
    n++;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exp>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  movss  D19(%rip),%xmm2
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm2,%xmm3
  movaps %xmm2,%xmm1
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L5:
  mulss  0xc(%rsp),%xmm3
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  cvtsi2ss %rax,%xmm0
  mulss  %xmm0,%xmm2
  movaps %xmm3,%xmm4
  movaps %xmm1,%xmm0
  divss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
L0:
  subss  %xmm1,%xmm0
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0x4(%rsp)
  movss  %xmm1,(%rsp)
  call   <fabs@plt>
  movss  (%rsp),%xmm1
  comisd D6(%rip),%xmm0
  movss  0x4(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  ja     L5
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: f32
name: unpack_data
arguments: label: D6
type_guessed: f64

tool: D19: 1

tool: D6: 1e-06

assistant: ```c
float exp(float x) {
  float result = 1.0;
  unsigned n = 1;
  float power = 1.0;
  float factorial = 1.0;
  float old = 0.0;
  while (fabs(old - result) > 0.000001) {
    old = result;
    power *= x;
    factorial *= n;
    result += (power / factorial);
    n++;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exp>:
  endbr64
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  movss  D15(%rip),%xmm2
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm2,%xmm3
  movaps %xmm2,%xmm1
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L18:
  mulss  0xc(%rsp),%xmm3
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  add    $0x1,%ebx
  cvtsi2ss %rax,%xmm0
  mulss  %xmm0,%xmm2
  movaps %xmm3,%xmm4
  movaps %xmm1,%xmm0
  divss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
L5:
  subss  %xmm1,%xmm0
  movss  %xmm2,0x8(%rsp)
  movss  %xmm3,0x4(%rsp)
  movss  %xmm1,(%rsp)
  call   <fabs@plt>
  movss  (%rsp),%xmm1
  comisd D5(%rip),%xmm0
  movss  0x4(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  ja     L18
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
datatype: f32
name: disassemble_data
arguments: data_tag: D5
datatype: f64

tool: D15: 1

tool: D5: 1e-06

assistant: ```c
float exp(float x) {
  float result = 1.0;
  unsigned n = 1;
  float power = 1.0;
  float factorial = 1.0;
  float old = 0.0;
  while (fabs(old - result) > 0.000001) {
    old = result;
    power *= x;
    factorial *= n;
    result += (power / factorial);
    n++;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main_options>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L21
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <ft_strcmp@plt>
  test   %eax,%eax
  jne    L24
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L3
L24:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_putendl@plt>
L3:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L19
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string

tool: D17: -nocolor

tool: D12: Unknown option: 

assistant: ```c
void main_options(char **av, int *choice) {
  int i;
  i = 1;
  while (av[i]) {
    if (!ft_strcmp("-nocolor", av[i]))
      *choice = 1;
    else {
      ft_putstr("Unknown option: ");
      ft_putendl(av[i]);
    }
    ++i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main_options>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    0x8(%rdi),%rsi
  test   %rsi,%rsi
  je     L20
  lea    0x8(%rdi),%rbx
  lea    D0(%rip),%rbp
  lea    D12(%rip),%r13
  jmp    L39
L22:
  movl   $0x1,(%r12)
L44:
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  je     L20
L39:
  mov    %rbp,%rdi
  call   <ft_strcmp@plt>
  test   %eax,%eax
  je     L22
  mov    %r13,%rdi
  call   <ft_putstr@plt>
  mov    (%rbx),%rdi
  call   <ft_putendl@plt>
  jmp    L44
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string

tool: D0: -nocolor

tool: D12: Unknown option: 

assistant: ```c
void main_options(char **av, int *choice) {
  int i;
  i = 1;
  while (av[i]) {
    if (!ft_strcmp("-nocolor", av[i]))
      *choice = 1;
    else {
      ft_putstr("Unknown option: ");
      ft_putendl(av[i]);
    }
    ++i;
  }
}
```