ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<e_add_arg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %ecx,%r12d
  lea    0x1(%rcx),%r14d
  lea    0x10(,%rcx,8),%esi
  mov    (%rdi),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  cmp    %ebp,%r14d
  jle    L18
  movslq %r14d,%rax
  shl    $0x3,%rax
  movslq %r12d,%rsi
  sub    %ebp,%r12d
  sub    %r12,%rsi
  shl    $0x3,%rsi
L17:
  mov    (%rbx),%rdx
  mov    -0x8(%rdx,%rax,1),%rcx
  mov    %rcx,(%rdx,%rax,1)
  sub    $0x8,%rax
  cmp    %rsi,%rax
  jne    L17
L18:
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %ebp,%rbp
  mov    (%rbx),%rdx
  lea    (%rdx,%rbp,8),%r12
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    (%rbx),%rax
  mov    (%rax,%rbp,8),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int e_add_arg(char ***arg, char *str, int n, int argc) {
  int i;
  argc++;
  *arg = (char **)realloc((*arg), ((argc + 1) * sizeof(char *)));
  for (i = argc; i > n; i--)
    (*arg)[i] = (*arg)[i - 1];
  (*arg)[n] = malloc(strlen(str) + 1);
  strcpy((*arg)[n], str);
  return (argc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<e_add_arg>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    0x1(%rcx),%r13d
  push   %r12
  mov    %rsi,%r12
  lea    0x10(,%rcx,8),%esi
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <realloc@plt>
  mov    %rax,(%r15)
  mov    %rax,%r14
  cmp    %ebp,%r13d
  jle    L2
  sub    %ebp,%ebx
  movslq %r13d,%rax
  mov    %rbx,%rdi
  shl    $0x3,%rax
  lea    0x8(,%rbx,8),%rdx
  neg    %rdi
  shl    $0x3,%rdi
  lea    -0x8(%rax,%rdi,1),%rsi
  add    %rax,%rdi
  add    %r14,%rsi
  add    %r14,%rdi
  call   <memmove@plt>
L2:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%r14,%rbp,8)
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int e_add_arg(char ***arg, char *str, int n, int argc) {
  int i;
  argc++;
  *arg = (char **)realloc((*arg), ((argc + 1) * sizeof(char *)));
  for (i = argc; i > n; i--)
    (*arg)[i] = (*arg)[i - 1];
  (*arg)[n] = malloc(strlen(str) + 1);
  strcpy((*arg)[n], str);
  return (argc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<e_add_arg>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  lea    0x1(%rcx),%r13d
  push   %r12
  mov    %rsi,%r12
  lea    0x10(,%rcx,8),%esi
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <realloc@plt>
  mov    %rax,(%r15)
  mov    %rax,%r14
  cmp    %ebp,%r13d
  jle    L4
  sub    %ebp,%ebx
  movslq %r13d,%rax
  mov    %rbx,%rdi
  shl    $0x3,%rax
  lea    0x8(,%rbx,8),%rdx
  neg    %rdi
  shl    $0x3,%rdi
  lea    -0x8(%rax,%rdi,1),%rsi
  add    %rax,%rdi
  add    %r14,%rsi
  add    %r14,%rdi
  call   <memmove@plt>
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,(%r14,%rbp,8)
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int e_add_arg(char ***arg, char *str, int n, int argc) {
  int i;
  argc++;
  *arg = (char **)realloc((*arg), ((argc + 1) * sizeof(char *)));
  for (i = argc; i > n; i--)
    (*arg)[i] = (*arg)[i - 1];
  (*arg)[n] = malloc(strlen(str) + 1);
  strcpy((*arg)[n], str);
  return (argc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__shrink_str_1_filt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x8,%eax
  jg     L9
  lea    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hash_add@plt>
  mov    $0x1,%eax
  jmp    L6
L9:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
bool __shrink_str_1_filt(void *cc_, void *k, void *v) {
  if (*(uint32_t *)v < 9) {
    hash_add(cc_, &k, &v);
    return true;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__shrink_str_1_filt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    $0x0,%eax
  cmpl   $0x8,(%rdx)
  jle    L7
L18:
  add    $0x18,%rsp
  ret
L7:
  mov    %rsp,%rdx
  lea    0x8(%rsp),%rsi
  call   <hash_add@plt>
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
bool __shrink_str_1_filt(void *cc_, void *k, void *v) {
  if (*(uint32_t *)v < 9) {
    hash_add(cc_, &k, &v);
    return true;
  }
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<__shrink_str_1_filt>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  cmpl   $0x8,(%rdx)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  jle    L0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L0:
  mov    %rsp,%rdx
  lea    0x8(%rsp),%rsi
  call   <hash_add@plt>
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
bool __shrink_str_1_filt(void *cc_, void *k, void *v) {
  if (*(uint32_t *)v < 9) {
    hash_add(cc_, &k, &v);
    return true;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__shrink_str_1_filt>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  cmpl   $0x8,(%rdx)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  jle    L4
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L4:
  mov    %rsp,%rdx
  lea    0x8(%rsp),%rsi
  call   <hash_add@plt>
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
bool __shrink_str_1_filt(void *cc_, void *k, void *v) {
  if (*(uint32_t *)v < 9) {
    hash_add(cc_, &k, &v);
    return true;
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__vsprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x4000,%edi
  call   <__pformat@plt>
  mov    %eax,%ebx
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vsprintf(char *buf, const char *fmt, va_list argv) {
  register int retval;
  buf[retval = __pformat(0x4000, buf, 0, fmt, argv)] = '\0';
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__vsprintf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rcx
  mov    %edx,%r8d
  mov    $0x0,%edx
  mov    %rdi,%rsi
  mov    $0x4000,%edi
  call   <__pformat@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vsprintf(char *buf, const char *fmt, va_list argv) {
  register int retval;
  buf[retval = __pformat(0x4000, buf, 0, fmt, argv)] = '\0';
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__vsprintf>:
  endbr64
  push   %rbx
  mov    %rsi,%rcx
  mov    %rdi,%rbx
  mov    %edx,%r8d
  mov    %rdi,%rsi
  xor    %edx,%edx
  mov    $0x4000,%edi
  call   <__pformat@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vsprintf(char *buf, const char *fmt, va_list argv) {
  register int retval;
  buf[retval = __pformat(0x4000, buf, 0, fmt, argv)] = '\0';
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__vsprintf>:
  endbr64
  push   %rbx
  mov    %rsi,%rcx
  mov    %rdi,%rbx
  mov    %edx,%r8d
  mov    %rdi,%rsi
  xor    %edx,%edx
  mov    $0x4000,%edi
  call   <__pformat@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vsprintf(char *buf, const char *fmt, va_list argv) {
  register int retval;
  buf[retval = __pformat(0x4000, buf, 0, fmt, argv)] = '\0';
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Subsample_Horizontal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %ecx,-0x58(%rbp)
  mov    %r8d,-0x5c(%rbp)
  mov    %r9d,-0x60(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L69
L20:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x54(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   0x18(%rbp),%eax
  cltd
  idivl  0x20(%rbp)
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x5c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x28(%rbp)
  jge    L11
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L57
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L57:
  mov    -0x2c(%rbp),%eax
  imul   0x18(%rbp),%eax
  cltd
  idivl  0x20(%rbp)
  mov    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    0x20(%rbp),%eax
  sar    %eax
  add    %edx,%eax
  cltd
  idivl  0x20(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    $0x10,%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L66
L54:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  cwtl
  imul   -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L32
  movl   $0x80,-0x30(%rbp)
  jmp    L36
L32:
  movl   $0x7f,-0x30(%rbp)
L36:
  mov    -0x1c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x60(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x34(%rbp)
L66:
  mov    -0x34(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L54
  addl   $0x1,-0x38(%rbp)
L69:
  mov    -0x38(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jl     L20
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Subsample_Horizontal(short *s, unsigned char *d, int x0, int lx, int lxs, int lxd, int ly, int m, int n) {
  int i;
  int i1;
  int j;
  int id;
  int c1;
  int c2;
  int v;
  short *s1;
  short *s2;
  unsigned char *d1;
  int tmp;
  {
    i1 = 0;
    while (i1 < lx) {
      d1 = d + i1;
      i = x0 + i1;
      id = (i * m) / n;
      s1 = s + id;
      if (id < lxs - 1) {
        s2 = s1 + 1;
      } else {
        s2 = s1;
      }
      c2 = (16 * ((i * m) % n) + (n >> 1)) / n;
      c1 = 16 - c2;
      j = 0;
      while (j < ly) {
        v = c1 * (int)*s1 + c2 * (int)*s2;
        if (v >= 0) {
          tmp = 128;
        } else {
          tmp = 127;
        }
        *d1 = (unsigned char)((v + tmp) >> 8);
        d1 += lxd;
        s1 += lxs;
        s2 += lxs;
        j++;
      }
      i1++;
    }
    return;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Subsample_Horizontal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x18(%rsp)
  mov    0x38(%rsp),%ebx
  mov    0x48(%rsp),%r14d
  test   %ecx,%ecx
  jle    L54
  mov    %edx,%r13d
  mov    %r14d,%edi
  sar    %edi
  mov    %edi,-0x8(%rsp)
  movslq %r8d,%r12
  add    %r12,%r12
  imul   0x40(%rsp),%r13d
  mov    %rsi,%r15
  lea    -0x1(%rcx),%eax
  lea    0x1(%rsi,%rax,1),%rax
  mov    %rax,-0x10(%rsp)
  lea    -0x1(%r8),%eax
  mov    %eax,-0x4(%rsp)
  movslq %r9d,%rbp
  jmp    L33
L0:
  movswl (%r10,%rcx,1),%edx
  imul   %r11d,%edx
  movswl (%r9,%rcx,1),%esi
  imul   %eax,%esi
  add    %esi,%edx
  mov    %edx,%esi
  not    %esi
  shr    $0x1f,%esi
  lea    0x7f(%rsi,%rdx,1),%edx
  movzbl %dh,%edx
  mov    %dl,(%rdi)
  add    %rbp,%rdi
  add    $0x1,%r8d
  add    %r12,%rcx
  cmp    %r8d,%ebx
  jne    L0
L35:
  add    0x40(%rsp),%r13d
  add    $0x1,%r15
  cmp    -0x10(%rsp),%r15
  je     L54
L33:
  mov    %r15,%rdi
  mov    %r13d,%eax
  cltd
  idiv   %r14d
  movslq %eax,%rdx
  mov    -0x18(%rsp),%rcx
  lea    (%rcx,%rdx,2),%r10
  lea    0x2(%r10),%r9
  cmp    %eax,-0x4(%rsp)
  cmovle %r10,%r9
  mov    %r13d,%eax
  cltd
  idiv   %r14d
  shl    $0x4,%edx
  mov    -0x8(%rsp),%eax
  add    %edx,%eax
  cltd
  idiv   %r14d
  mov    $0x10,%r11d
  sub    %eax,%r11d
  test   %ebx,%ebx
  jle    L35
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  jmp    L0
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Subsample_Horizontal(short *s, unsigned char *d, int x0, int lx, int lxs, int lxd, int ly, int m, int n) {
  int i;
  int i1;
  int j;
  int id;
  int c1;
  int c2;
  int v;
  short *s1;
  short *s2;
  unsigned char *d1;
  int tmp;
  {
    i1 = 0;
    while (i1 < lx) {
      d1 = d + i1;
      i = x0 + i1;
      id = (i * m) / n;
      s1 = s + id;
      if (id < lxs - 1) {
        s2 = s1 + 1;
      } else {
        s2 = s1;
      }
      c2 = (16 * ((i * m) % n) + (n >> 1)) / n;
      c1 = 16 - c2;
      j = 0;
      while (j < ly) {
        v = c1 * (int)*s1 + c2 * (int)*s2;
        if (v >= 0) {
          tmp = 128;
        } else {
          tmp = 127;
        }
        *d1 = (unsigned char)((v + tmp) >> 8);
        d1 += lxd;
        s1 += lxs;
        s2 += lxs;
        j++;
      }
      i1++;
    }
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Subsample_Horizontal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%ebx
  mov    0x48(%rsp),%r15d
  mov    %rdi,-0x18(%rsp)
  test   %ecx,%ecx
  jle    L9
  mov    %ecx,%eax
  mov    %r15d,%edi
  mov    %edx,%r14d
  movslq %r8d,%r12
  sar    %edi
  sub    $0x1,%eax
  mov    %rsi,%r13
  add    %r12,%r12
  mov    %edi,-0x8(%rsp)
  lea    0x1(%rsi,%rax,1),%rax
  lea    -0x1(%r8),%edi
  movslq %r9d,%rbp
  mov    %edi,-0x4(%rsp)
  imul   0x40(%rsp),%r14d
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax)
L30:
  mov    %r14d,%eax
  mov    -0x18(%rsp),%rdi
  mov    $0x10,%r11d
  mov    %r13,%r8
  cltd
  idiv   %r15d
  cmp    -0x4(%rsp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rsp),%eax
  lea    (%rdi,%rcx,2),%r10
  lea    0x2(%r10),%r9
  cmovge %r10,%r9
  shl    $0x4,%edx
  xor    %ecx,%ecx
  xor    %edi,%edi
  add    %edx,%eax
  cltd
  idiv   %r15d
  sub    %eax,%r11d
  test   %ebx,%ebx
  jle    L25
L11:
  movswl (%r10,%rcx,1),%edx
  movswl (%r9,%rcx,1),%esi
  add    $0x1,%edi
  add    %r12,%rcx
  imul   %eax,%esi
  imul   %r11d,%edx
  add    %esi,%edx
  mov    %edx,%esi
  not    %esi
  shr    $0x1f,%esi
  lea    0x7f(%rsi,%rdx,1),%edx
  movzbl %dh,%edx
  mov    %dl,(%r8)
  add    %rbp,%r8
  cmp    %edi,%ebx
  jne    L11
L25:
  add    0x40(%rsp),%r14d
  add    $0x1,%r13
  cmp    %r13,-0x10(%rsp)
  jne    L30
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Subsample_Horizontal(short *s, unsigned char *d, int x0, int lx, int lxs, int lxd, int ly, int m, int n) {
  int i;
  int i1;
  int j;
  int id;
  int c1;
  int c2;
  int v;
  short *s1;
  short *s2;
  unsigned char *d1;
  int tmp;
  {
    i1 = 0;
    while (i1 < lx) {
      d1 = d + i1;
      i = x0 + i1;
      id = (i * m) / n;
      s1 = s + id;
      if (id < lxs - 1) {
        s2 = s1 + 1;
      } else {
        s2 = s1;
      }
      c2 = (16 * ((i * m) % n) + (n >> 1)) / n;
      c1 = 16 - c2;
      j = 0;
      while (j < ly) {
        v = c1 * (int)*s1 + c2 * (int)*s2;
        if (v >= 0) {
          tmp = 128;
        } else {
          tmp = 127;
        }
        *d1 = (unsigned char)((v + tmp) >> 8);
        d1 += lxd;
        s1 += lxs;
        s2 += lxs;
        j++;
      }
      i1++;
    }
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  lea    D22(%rip),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <check@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D25
type: string
name: read_data
arguments: data_label: D11
type: string

tool: D22: b

tool: D25: a

tool: D11: foo

assistant: ```c
int main(void) {
  check("foo", "a", 1, "b", 0, NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  lea    D14(%rip),%rcx
  mov    $0x1,%edx
  lea    D10(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <check@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string

tool: D14: b

tool: D10: a

tool: D12: foo

assistant: ```c
int main(void) {
  check("foo", "a", 1, "b", 0, NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%edx
  lea    D3(%rip),%rcx
  lea    D9(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <check@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D10
type: string

tool: D3: b

tool: D9: a

tool: D10: foo

assistant: ```c
int main(void) {
  check("foo", "a", 1, "b", 0, NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%edx
  lea    D26(%rip),%rcx
  lea    D0(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <check@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D26: b

tool: D0: a

tool: D2: foo

assistant: ```c
int main(void) {
  check("foo", "a", 1, "b", 0, NULL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nhr_free_clean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <nhr_free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L4:
  nop
  leave
  ret
```

assistant: ```c
void nhr_free_clean(void **mem) {
  if (mem) {
    nhr_free(*mem);
    *mem = NULL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<nhr_free_clean>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <nhr_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void nhr_free_clean(void **mem) {
  if (mem) {
    nhr_free(*mem);
    *mem = NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nhr_free_clean>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <nhr_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void nhr_free_clean(void **mem) {
  if (mem) {
    nhr_free(*mem);
    *mem = NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nhr_free_clean>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <nhr_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void nhr_free_clean(void **mem) {
  if (mem) {
    nhr_free(*mem);
    *mem = NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_unique_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2c,%edi
  call   <mm_alloc_char@plt>
  mov    %rax,-0x38(%rbp)
L9:
  lea    -0x30(%rbp),%rax
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <gen_random@plt>
  mov    -0x38(%rbp),%rax
  lea    -0x30(%rbp),%rcx
  mov    $0x28,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x38(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x38(%rbp),%rax
  lea    -0x3c(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L16
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  jmp    L36
L16:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <mm_free_char@plt>
  mov    $0x2c,%edi
  call   <mm_alloc_char@plt>
  mov    %rax,-0x38(%rbp)
  jmp    L9
L36:
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: .out

assistant: ```c
char *get_unique_filename(void) {
  char *filename = mm_alloc_char(44);
  struct stat sts;
  while (1) {
    char headname[40];
    gen_random(headname, 40);
    strncpy(filename, headname, 40);
    strcat(filename, ".out");
    if (stat(filename, &sts) == -1)
      break;
    else {
      mm_free_char(&filename);
      filename = mm_alloc_char(44);
    }
  }
  return filename;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_unique_filename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x2c,%edi
  call   <mm_alloc_char@plt>
  mov    %rax,0x8(%rsp)
  lea    D0(%rip),%rbp
  jmp    L23
L14:
  lea    0x8(%rsp),%rdi
  call   <mm_free_char@plt>
  mov    $0x2c,%edi
  call   <mm_alloc_char@plt>
  mov    %rax,0x8(%rsp)
L23:
  lea    0x10(%rsp),%rbx
  mov    $0x28,%esi
  mov    %rbx,%rdi
  call   <gen_random@plt>
  mov    $0x28,%edx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <strcat@plt>
  lea    0x4(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L14
  mov    0x8(%rsp),%rax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: .out

assistant: ```c
char *get_unique_filename(void) {
  char *filename = mm_alloc_char(44);
  struct stat sts;
  while (1) {
    char headname[40];
    gen_random(headname, 40);
    strncpy(filename, headname, 40);
    strcat(filename, ".out");
    if (stat(filename, &sts) == -1)
      break;
    else {
      mm_free_char(&filename);
      filename = mm_alloc_char(44);
    }
  }
  return filename;
}
```