ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  lea    D26(%rip),%rbp
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <flushall@plt>
  lea    0x4(%rbx),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <flushall@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L13
  mov    (%rsp),%esi
  mov    0x4(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  test   %esi,%esi
  mov    $0x0,%eax
  cmovs  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D25: 		Please enter 6 numbers and this program 
		will tell you the biggest of these numbers:

tool: D26: %d

tool: D1: The largest number in the array is %d

assistant: ```c
main() {
  int matrix[3][2];
  int i, j;
  int largest;
  printf("\t\tPlease enter 6 numbers and this program \n\t\twill tell you the biggest of these numbers:\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      scanf("%d", &matrix[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (largest < matrix[i][j]) {
        largest = matrix[i][j];
      }
    }
  }
  printf("The largest number in the array is %d", largest);
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  call   <puts@plt>
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  lea    0x4(%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  cmp    %r12,%rbx
  jne    L13
  mov    0x4(%rsp),%eax
  mov    (%rsp),%esi
  lea    D23(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string

tool: D7: 		Please enter 6 numbers and this program 
		will tell you the biggest of these numbers:

tool: D28: %d

tool: D23: The largest number in the array is %d

assistant: ```c
main() {
  int matrix[3][2];
  int i, j;
  int largest;
  printf("\t\tPlease enter 6 numbers and this program \n\t\twill tell you the biggest of these numbers:\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      scanf("%d", &matrix[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (largest < matrix[i][j]) {
        largest = matrix[i][j];
      }
    }
  }
  printf("The largest number in the array is %d", largest);
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D20(%rip),%rdi
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  call   <puts@plt>
L11:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  lea    0x4(%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <scanf@plt>
  xor    %eax,%eax
  call   <flushall@plt>
  cmp    %rbx,%r12
  jne    L11
  mov    (%rsp),%eax
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x8(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  test   %esi,%esi
  cmovs  %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D20: 		Please enter 6 numbers and this program 
		will tell you the biggest of these numbers:

tool: D24: %d

tool: D3: The largest number in the array is %d

assistant: ```c
main() {
  int matrix[3][2];
  int i, j;
  int largest;
  printf("\t\tPlease enter 6 numbers and this program \n\t\twill tell you the biggest of these numbers:\n");
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      scanf("%d", &matrix[i][j]);
      flushall();
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      if (largest < matrix[i][j]) {
        largest = matrix[i][j];
      }
    }
  }
  printf("The largest number in the array is %d", largest);
  getchar();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<put_dos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0xd,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x2(%rax),%esi
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  leave
  ret
```

assistant: ```c
void put_dos(FILE *f, char *buf, int len) {
  buf[len] = 0x0d;
  buf[len + 1] = 0x0a;
  fwrite(buf, len + 2, 1, f);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<put_dos>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movslq %edx,%rax
  movb   $0xd,(%rsi,%rax,1)
  movb   $0xa,0x1(%rsi,%rax,1)
  lea    0x2(%rdx),%esi
  mov    $0x1,%edx
  call   <fwrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void put_dos(FILE *f, char *buf, int len) {
  buf[len] = 0x0d;
  buf[len + 1] = 0x0a;
  fwrite(buf, len + 2, 1, f);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<put_dos>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movb   $0xd,(%rsi,%rax,1)
  movb   $0xa,0x1(%rsi,%rax,1)
  lea    0x2(%rdx),%esi
  mov    $0x1,%edx
  jmp    1050 <fwrite@plt>
```

assistant: ```c
void put_dos(FILE *f, char *buf, int len) {
  buf[len] = 0x0d;
  buf[len + 1] = 0x0a;
  fwrite(buf, len + 2, 1, f);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<put_dos>:
  endbr64
  movslq %edx,%rax
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  movb   $0xd,(%rsi,%rax,1)
  movb   $0xa,0x1(%rsi,%rax,1)
  lea    0x2(%rdx),%esi
  mov    $0x1,%edx
  jmp    1050 <fwrite@plt>
```

assistant: ```c
void put_dos(FILE *f, char *buf, int len) {
  buf[len] = 0x0d;
  buf[len + 1] = 0x0a;
  fwrite(buf, len + 2, 1, f);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<match_skill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L11
  mov    $0x1,%eax
  jmp    L18
L11:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int match_skill(const void *skill1, const void *skill2) {
  if (*(const char *)skill1 == *(const char *)skill2)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match_skill>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int match_skill(const void *skill1, const void *skill2) {
  if (*(const char *)skill1 == *(const char *)skill2)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match_skill>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int match_skill(const void *skill1, const void *skill2) {
  if (*(const char *)skill1 == *(const char *)skill2)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<match_skill>:
  endbr64
  movzbl (%rsi),%eax
  cmp    %al,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int match_skill(const void *skill1, const void *skill2) {
  if (*(const char *)skill1 == *(const char *)skill2)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wdc_UtilsCreateDir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0xfffffffd,%eax
  jmp    L35
L10:
  mov    -0x18(%rbp),%rax
  mov    $0x999,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L42
  mov    D9(%rip),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L3
  movl   $0xffffffdc,-0x8(%rbp)
  jmp    L42
L3:
  mov    D9(%rip),%rax
  mov    (%rax),%rdx
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L22
  movl   $0xffffffdb,-0x8(%rbp)
  jmp    L42
L22:
  movl   $0xffffffda,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
L35:
  leave
  ret
```

assistant: ```c
int wdc_UtilsCreateDir(char *path) {
  int retStatus;
  int status = 0;
  if (!path) {
    return -3;
  }
  retStatus = mkdir(path, 0x999);
  if (retStatus < 0) {
    if (errno == EEXIST) {
      status = -36;
    } else if (errno == ENOENT) {
      status = -37;
    } else {
      status = -38;
    }
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wdc_UtilsCreateDir>:
  endbr64
  test   %rdi,%rdi
  je     L17
  sub    $0x8,%rsp
  mov    $0x999,%esi
  call   <mkdir@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  js     L15
L29:
  add    $0x8,%rsp
  ret
L15:
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  mov    D22(%rip),%rdx
  cmp    (%rdx),%rax
  je     L11
  mov    D26(%rip),%rdx
  cmp    (%rdx),%rax
  sete   %al
  movzbl %al,%eax
  sub    $0x26,%eax
  jmp    L29
L17:
  mov    $0xfffffffd,%eax
  ret
L11:
  mov    $0xffffffdc,%eax
  jmp    L29
```

assistant: ```c
int wdc_UtilsCreateDir(char *path) {
  int retStatus;
  int status = 0;
  if (!path) {
    return -3;
  }
  retStatus = mkdir(path, 0x999);
  if (retStatus < 0) {
    if (errno == EEXIST) {
      status = -36;
    } else if (errno == ENOENT) {
      status = -37;
    } else {
      status = -38;
    }
  }
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wdc_UtilsCreateDir>:
  endbr64
  test   %rdi,%rdi
  je     L34
  sub    $0x8,%rsp
  mov    $0x999,%esi
  call   <mkdir@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  js     L19
L28:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    D17(%rip),%rax
  mov    D23(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L22
  mov    D4(%rip),%rdx
  cmp    (%rdx),%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  sub    $0x26,%eax
  ret
L34:
  mov    $0xfffffffd,%eax
  ret
L22:
  mov    $0xffffffdc,%eax
  jmp    L28
```

assistant: ```c
int wdc_UtilsCreateDir(char *path) {
  int retStatus;
  int status = 0;
  if (!path) {
    return -3;
  }
  retStatus = mkdir(path, 0x999);
  if (retStatus < 0) {
    if (errno == EEXIST) {
      status = -36;
    } else if (errno == ENOENT) {
      status = -37;
    } else {
      status = -38;
    }
  }
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wdc_UtilsCreateDir>:
  endbr64
  test   %rdi,%rdi
  je     L14
  sub    $0x8,%rsp
  mov    $0x999,%esi
  call   <mkdir@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  js     L18
L0:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    D20(%rip),%rax
  mov    D29(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L22
  mov    D5(%rip),%rdx
  cmp    (%rdx),%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  sub    $0x26,%eax
  ret
L14:
  mov    $0xfffffffd,%eax
  ret
L22:
  mov    $0xffffffdc,%eax
  jmp    L0
```

assistant: ```c
int wdc_UtilsCreateDir(char *path) {
  int retStatus;
  int status = 0;
  if (!path) {
    return -3;
  }
  retStatus = mkdir(path, 0x999);
  if (retStatus < 0) {
    if (errno == EEXIST) {
      status = -36;
    } else if (errno == ENOENT) {
      status = -37;
    } else {
      status = -38;
    }
  }
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
L1:
  cmpl   $0x3e8,-0x8(%rbp)
  je     L56
  addl   $0x1,-0x8(%rbp)
  jmp    L1
L56:
  nop
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x3e9,-0x8(%rbp)
  je     L74
  jmp    L1
L74:
  nop
  movl   $0x0,-0x4(%rbp)
  jmp    L61
L46:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x3,-0x4(%rbp)
  je     L19
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L54
L19:
  nop
L54:
  addl   $0x1,-0x4(%rbp)
L61:
  cmpl   $0x9,-0x4(%rbp)
  jle    L46
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D6: 
Starti%d

tool: D9: 
End

assistant: ```c
int main() {
  int i = 0;
  while (1) {
    while (1) {
      if (i == 1000) {
        break;
      }
      i++;
    }
    i++;
    if (i == 1001) {
      break;
    }
  }
  for (int j = 0; j < 10; j++) {
    printf("\nStarti%d", j);
    if (j == 3)
      continue;
    printf("\nEnd");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3e9,%ebx
L16:
  sub    $0x1,%ebx
  jne    L16
  mov    $0x1,%ebp
  lea    D6(%rip),%r12
  lea    D9(%rip),%r13
  jmp    L37
L15:
  add    $0x1,%ebx
  add    $0x1,%ebp
L37:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  je     L15
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x9,%ebp
  jle    L15
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D6: 
Starti%d

tool: D9: 
End

assistant: ```c
int main() {
  int i = 0;
  while (1) {
    while (1) {
      if (i == 1000) {
        break;
      }
      i++;
    }
    i++;
    if (i == 1001) {
      break;
    }
  }
  for (int j = 0; j < 10; j++) {
    printf("\nStarti%d", j);
    if (j == 3)
      continue;
    printf("\nEnd");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x4,%ebx
  je     L4
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D18
type_guessed: string

tool: D13: 
End

tool: D18: 
Starti%d

assistant: ```c
int main() {
  int i = 0;
  while (1) {
    while (1) {
      if (i == 1000) {
        break;
      }
      i++;
    }
    i++;
    if (i == 1001) {
      break;
    }
  }
  for (int j = 0; j < 10; j++) {
    printf("\nStarti%d", j);
    if (j == 3)
      continue;
    printf("\nEnd");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x4,%ebx
  je     L14
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L14
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D6
type_guessed: string

tool: D7: 
End

tool: D6: 
Starti%d

assistant: ```c
int main() {
  int i = 0;
  while (1) {
    while (1) {
      if (i == 1000) {
        break;
      }
      i++;
    }
    i++;
    if (i == 1001) {
      break;
    }
  }
  for (int j = 0; j < 10; j++) {
    printf("\nStarti%d", j);
    if (j == 3)
      continue;
    printf("\nEnd");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<random_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void random_sleep(unsigned int max_usecs) {
  int r = rand();
  unsigned int usec;
  usec = r % max_usecs;
  usleep(usec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<random_sleep>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    $0x0,%edx
  div    %ebx
  mov    %edx,%edi
  call   <usleep@plt>
  pop    %rbx
  ret
```

assistant: ```c
void random_sleep(unsigned int max_usecs) {
  int r = rand();
  unsigned int usec;
  usec = r % max_usecs;
  usleep(usec);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<random_sleep>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <rand@plt>
  xor    %edx,%edx
  div    %ebx
  pop    %rbx
  mov    %edx,%edi
  jmp    1070 <usleep@plt>
```

assistant: ```c
void random_sleep(unsigned int max_usecs) {
  int r = rand();
  unsigned int usec;
  usec = r % max_usecs;
  usleep(usec);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_sleep>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <rand@plt>
  xor    %edx,%edx
  div    %ebx
  pop    %rbx
  mov    %edx,%edi
  jmp    1070 <usleep@plt>
```

assistant: ```c
void random_sleep(unsigned int max_usecs) {
  int r = rand();
  unsigned int usec;
  usec = r % max_usecs;
  usleep(usec);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L4:
  jmp    L4
```

assistant: ```c
int main(void) {
  while (1) {
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
int main(void) {
  while (1) {
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
int main(void) {
  while (1) {
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
int main(void) {
  while (1) {
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<s9_Decompression>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L8
L10:
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <s9_decode@plt>
  mov    %eax,-0x1c(%rbp)
  addq   $0x4,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    %eax,-0x20(%rbp)
L8:
  cmpl   $0x0,-0x20(%rbp)
  jg     L10
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int s9_Decompression(unsigned int *input, unsigned int *output, int size) {
  unsigned int *_p = output;
  int num;
  unsigned *tmp = input;
  int left = size;
  while (left > 0) {
    num = s9_decode(tmp, &_p);
    tmp++;
    left -= num;
  }
  return tmp - input;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<s9_Decompression>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,(%rsp)
  test   %edx,%edx
  jle    L12
  mov    %edx,%ebp
  mov    %rdi,%rbx
  mov    %rsp,%r12
L24:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <s9_decode@plt>
  add    $0x4,%rbx
  sub    %eax,%ebp
  test   %ebp,%ebp
  jg     L24
L36:
  mov    %rbx,%rax
  sub    %r13,%rax
  sar    $0x2,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %rdi,%rbx
  jmp    L36
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int s9_Decompression(unsigned int *input, unsigned int *output, int size) {
  unsigned int *_p = output;
  int num;
  unsigned *tmp = input;
  int left = size;
  while (left > 0) {
    num = s9_decode(tmp, &_p);
    tmp++;
    left -= num;
  }
  return tmp - input;
}
```
user: What is the c source code of the assembly code below?

```asm
<s9_Decompression>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,(%rsp)
  test   %edx,%edx
  jle    L13
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %rdi,%rbx
  mov    %rsp,%r13
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  mov    %r13,%rsi
  add    $0x4,%rbx
  call   <s9_decode@plt>
  sub    %eax,%ebp
  test   %ebp,%ebp
  jg     L6
  mov    %rbx,%rax
  sub    %r12,%rax
  sar    $0x2,%rax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    L21
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int s9_Decompression(unsigned int *input, unsigned int *output, int size) {
  unsigned int *_p = output;
  int num;
  unsigned *tmp = input;
  int left = size;
  while (left > 0) {
    num = s9_decode(tmp, &_p);
    tmp++;
    left -= num;
  }
  return tmp - input;
}
```