ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<AES_hncpy32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AES_hncpy32(uint32_t *dst, uint32_t *src) {
  dst[0] = ((((uint32_t)(src[0]) & 0xff000000) >> 24) | (((uint32_t)(src[0]) & 0x00ff0000) >> 8) | (((uint32_t)(src[0]) & 0x0000ff00) << 8) | (((uint32_t)(src[0]) & 0x000000ff) << 24));
  dst[1] = ((((uint32_t)(src[1]) & 0xff000000) >> 24) | (((uint32_t)(src[1]) & 0x00ff0000) >> 8) | (((uint32_t)(src[1]) & 0x0000ff00) << 8) | (((uint32_t)(src[1]) & 0x000000ff) << 24));
  dst[2] = ((((uint32_t)(src[2]) & 0xff000000) >> 24) | (((uint32_t)(src[2]) & 0x00ff0000) >> 8) | (((uint32_t)(src[2]) & 0x0000ff00) << 8) | (((uint32_t)(src[2]) & 0x000000ff) << 24));
  dst[3] = ((((uint32_t)(src[3]) & 0xff000000) >> 24) | (((uint32_t)(src[3]) & 0x00ff0000) >> 8) | (((uint32_t)(src[3]) & 0x0000ff00) << 8) | (((uint32_t)(src[3]) & 0x000000ff) << 24));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<AES_hncpy32>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    (%rsi),%esi
  mov    %esi,%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  mov    %esi,%edi
  shl    $0x8,%edi
  and    $0xff0000,%edi
  or     %edi,%eax
  mov    %esi,%edi
  shr    $0x18,%edi
  or     %edi,%eax
  shl    $0x18,%esi
  or     %esi,%eax
  mov    %eax,(%rdx)
  mov    0x4(%rcx),%esi
  mov    %esi,%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  mov    %esi,%edi
  shl    $0x8,%edi
  and    $0xff0000,%edi
  or     %edi,%eax
  mov    %esi,%edi
  shr    $0x18,%edi
  or     %edi,%eax
  shl    $0x18,%esi
  or     %esi,%eax
  mov    %eax,0x4(%rdx)
  mov    0x8(%rcx),%esi
  mov    %esi,%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  mov    %esi,%edi
  shl    $0x8,%edi
  and    $0xff0000,%edi
  or     %edi,%eax
  mov    %esi,%edi
  shr    $0x18,%edi
  or     %edi,%eax
  shl    $0x18,%esi
  or     %esi,%eax
  mov    %eax,0x8(%rdx)
  mov    0xc(%rcx),%ecx
  mov    %ecx,%eax
  sar    $0x8,%eax
  and    $0xff00,%eax
  mov    %ecx,%esi
  shl    $0x8,%esi
  and    $0xff0000,%esi
  or     %esi,%eax
  mov    %ecx,%esi
  shr    $0x18,%esi
  or     %esi,%eax
  shl    $0x18,%ecx
  or     %ecx,%eax
  mov    %eax,0xc(%rdx)
  ret
```

assistant: ```c
void AES_hncpy32(uint32_t *dst, uint32_t *src) {
  dst[0] = ((((uint32_t)(src[0]) & 0xff000000) >> 24) | (((uint32_t)(src[0]) & 0x00ff0000) >> 8) | (((uint32_t)(src[0]) & 0x0000ff00) << 8) | (((uint32_t)(src[0]) & 0x000000ff) << 24));
  dst[1] = ((((uint32_t)(src[1]) & 0xff000000) >> 24) | (((uint32_t)(src[1]) & 0x00ff0000) >> 8) | (((uint32_t)(src[1]) & 0x0000ff00) << 8) | (((uint32_t)(src[1]) & 0x000000ff) << 24));
  dst[2] = ((((uint32_t)(src[2]) & 0xff000000) >> 24) | (((uint32_t)(src[2]) & 0x00ff0000) >> 8) | (((uint32_t)(src[2]) & 0x0000ff00) << 8) | (((uint32_t)(src[2]) & 0x000000ff) << 24));
  dst[3] = ((((uint32_t)(src[3]) & 0xff000000) >> 24) | (((uint32_t)(src[3]) & 0x00ff0000) >> 8) | (((uint32_t)(src[3]) & 0x0000ff00) << 8) | (((uint32_t)(src[3]) & 0x000000ff) << 24));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<AES_hncpy32>:
  endbr64
  mov    (%rsi),%eax
  bswap  %eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  bswap  %eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  bswap  %eax
  mov    %eax,0x8(%rdi)
  mov    0xc(%rsi),%eax
  bswap  %eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void AES_hncpy32(uint32_t *dst, uint32_t *src) {
  dst[0] = ((((uint32_t)(src[0]) & 0xff000000) >> 24) | (((uint32_t)(src[0]) & 0x00ff0000) >> 8) | (((uint32_t)(src[0]) & 0x0000ff00) << 8) | (((uint32_t)(src[0]) & 0x000000ff) << 24));
  dst[1] = ((((uint32_t)(src[1]) & 0xff000000) >> 24) | (((uint32_t)(src[1]) & 0x00ff0000) >> 8) | (((uint32_t)(src[1]) & 0x0000ff00) << 8) | (((uint32_t)(src[1]) & 0x000000ff) << 24));
  dst[2] = ((((uint32_t)(src[2]) & 0xff000000) >> 24) | (((uint32_t)(src[2]) & 0x00ff0000) >> 8) | (((uint32_t)(src[2]) & 0x0000ff00) << 8) | (((uint32_t)(src[2]) & 0x000000ff) << 24));
  dst[3] = ((((uint32_t)(src[3]) & 0xff000000) >> 24) | (((uint32_t)(src[3]) & 0x00ff0000) >> 8) | (((uint32_t)(src[3]) & 0x0000ff00) << 8) | (((uint32_t)(src[3]) & 0x000000ff) << 24));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AES_hncpy32>:
  endbr64
  mov    (%rsi),%eax
  bswap  %eax
  mov    %eax,(%rdi)
  mov    0x4(%rsi),%eax
  bswap  %eax
  mov    %eax,0x4(%rdi)
  mov    0x8(%rsi),%eax
  bswap  %eax
  mov    %eax,0x8(%rdi)
  mov    0xc(%rsi),%eax
  bswap  %eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void AES_hncpy32(uint32_t *dst, uint32_t *src) {
  dst[0] = ((((uint32_t)(src[0]) & 0xff000000) >> 24) | (((uint32_t)(src[0]) & 0x00ff0000) >> 8) | (((uint32_t)(src[0]) & 0x0000ff00) << 8) | (((uint32_t)(src[0]) & 0x000000ff) << 24));
  dst[1] = ((((uint32_t)(src[1]) & 0xff000000) >> 24) | (((uint32_t)(src[1]) & 0x00ff0000) >> 8) | (((uint32_t)(src[1]) & 0x0000ff00) << 8) | (((uint32_t)(src[1]) & 0x000000ff) << 24));
  dst[2] = ((((uint32_t)(src[2]) & 0xff000000) >> 24) | (((uint32_t)(src[2]) & 0x00ff0000) >> 8) | (((uint32_t)(src[2]) & 0x0000ff00) << 8) | (((uint32_t)(src[2]) & 0x000000ff) << 24));
  dst[3] = ((((uint32_t)(src[3]) & 0xff000000) >> 24) | (((uint32_t)(src[3]) & 0x00ff0000) >> 8) | (((uint32_t)(src[3]) & 0x0000ff00) << 8) | (((uint32_t)(src[3]) & 0x000000ff) << 24));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getpass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *getpass(const char *prompt) {
  errno = ENXIO;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getpass>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *getpass(const char *prompt) {
  errno = ENXIO;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getpass>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getpass(const char *prompt) {
  errno = ENXIO;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getpass>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *getpass(const char *prompt) {
  errno = ENXIO;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L16
  mov    $0xffffffff,%eax
  jmp    L8
L16:
  mov    $0x1,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
char d(int a, int b) {
  if (a > b)
    return -1;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<d>:
  endbr64
  cmp    %esi,%edi
  setle  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
char d(int a, int b) {
  if (a > b)
    return -1;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<d>:
  endbr64
  cmp    %esi,%edi
  setle  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
char d(int a, int b) {
  if (a > b)
    return -1;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<d>:
  endbr64
  cmp    %esi,%edi
  setle  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
char d(int a, int b) {
  if (a > b)
    return -1;
  else
    return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<finhb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <finhn@plt>
  shl    $0x4,%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <finhn@plt>
  or     %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char finhb(FILE *f) {
  unsigned char result;
  result = finhn(f) << 4;
  result |= finhn(f);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<finhb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <finhn@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <finhn@plt>
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char finhb(FILE *f) {
  unsigned char result;
  result = finhn(f) << 4;
  result |= finhn(f);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<finhb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <finhn@plt>
  mov    %rbp,%rdi
  shl    $0x4,%eax
  mov    %eax,%ebx
  call   <finhn@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char finhb(FILE *f) {
  unsigned char result;
  result = finhn(f) << 4;
  result |= finhn(f);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<finhb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <finhn@plt>
  mov    %rbp,%rdi
  shl    $0x4,%eax
  mov    %eax,%ebx
  call   <finhn@plt>
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char finhb(FILE *f) {
  unsigned char result;
  result = finhn(f) << 4;
  result |= finhn(f);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<BULBtoE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D28(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D25(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D23(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_infered: f64
name: parse_data
arguments: label: D25
type_infered: f64
name: parse_data
arguments: label: D23
type_infered: f64

tool: D28: 0.00115

tool: D25: 1

tool: D23: 0.00066

assistant: ```c
double BULBtoE(double Ew, double wetc, double dryc, double mb) {
  double E = Ew - (0.00066 * (1 + 0.00115 * wetc) * (dryc - wetc) * mb);
  return E;
}
```
user: Translate the below assembly code into C programming language:

```asm
<BULBtoE>:
  endbr64
  movapd %xmm1,%xmm4
  mulsd  D17(%rip),%xmm4
  addsd  D15(%rip),%xmm4
  mulsd  D7(%rip),%xmm4
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm4
  mulsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_guessed: f64
name: disassemble_data
arguments: label: D15
type_guessed: f64
name: disassemble_data
arguments: label: D7
type_guessed: f64

tool: D17: 0.00115

tool: D15: 1

tool: D7: 0.00066

assistant: ```c
double BULBtoE(double Ew, double wetc, double dryc, double mb) {
  double E = Ew - (0.00066 * (1 + 0.00115 * wetc) * (dryc - wetc) * mb);
  return E;
}
```
user: What is the c source code of the assembly code below:

```asm
<BULBtoE>:
  endbr64
  movsd  D15(%rip),%xmm4
  subsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm4
  addsd  D19(%rip),%xmm4
  mulsd  D1(%rip),%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: f64
name: disassemble_data
arguments: tag: D19
type: f64
name: disassemble_data
arguments: tag: D1
type: f64

tool: D15: 0.00115

tool: D19: 1

tool: D1: 0.00066

assistant: ```c
double BULBtoE(double Ew, double wetc, double dryc, double mb) {
  double E = Ew - (0.00066 * (1 + 0.00115 * wetc) * (dryc - wetc) * mb);
  return E;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BULBtoE>:
  endbr64
  movsd  D15(%rip),%xmm4
  subsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm4
  addsd  D8(%rip),%xmm4
  mulsd  D27(%rip),%xmm4
  mulsd  %xmm2,%xmm4
  mulsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: f64
name: retrieve_data
arguments: tag: D8
type: f64
name: retrieve_data
arguments: tag: D27
type: f64

tool: D15: 0.00115

tool: D8: 1

tool: D27: 0.00066

assistant: ```c
double BULBtoE(double Ew, double wetc, double dryc, double mb) {
  double E = Ew - (0.00066 * (1 + 0.00115 * wetc) * (dryc - wetc) * mb);
  return E;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_usart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    $0xc5,%eax
  mov    %dl,(%rax)
  mov    $0xc4,%eax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0xc1,%eax
  movb   $0x18,(%rax)
  mov    $0xc2,%eax
  movb   $0xe,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_usart(unsigned int ubrr) {
  *((volatile unsigned char *)(0xC5)) = (unsigned char)(ubrr >> 8);
  *((volatile unsigned char *)(0xC4)) = (unsigned char)ubrr;
  *((volatile unsigned char *)(0xC1)) = (1 << 4) | (1 << 3);
  *((volatile unsigned char *)(0xC2)) = (1 << 3) | (3 << 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<init_usart>:
  endbr64
  mov    %edi,%eax
  shr    $0x8,%eax
  mov    %al,0xc5
  mov    %dil,0xc4
  movb   $0x18,0xc1
  movb   $0xe,0xc2
  ret
```

assistant: ```c
void init_usart(unsigned int ubrr) {
  *((volatile unsigned char *)(0xC5)) = (unsigned char)(ubrr >> 8);
  *((volatile unsigned char *)(0xC4)) = (unsigned char)ubrr;
  *((volatile unsigned char *)(0xC1)) = (1 << 4) | (1 << 3);
  *((volatile unsigned char *)(0xC2)) = (1 << 3) | (3 << 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_usart>:
  endbr64
  mov    %edi,%eax
  shr    $0x8,%eax
  mov    %al,0xc5
  mov    %dil,0xc4
  movb   $0x18,0xc1
  movb   $0xe,0xc2
  ret
```

assistant: ```c
void init_usart(unsigned int ubrr) {
  *((volatile unsigned char *)(0xC5)) = (unsigned char)(ubrr >> 8);
  *((volatile unsigned char *)(0xC4)) = (unsigned char)ubrr;
  *((volatile unsigned char *)(0xC1)) = (1 << 4) | (1 << 3);
  *((volatile unsigned char *)(0xC2)) = (1 << 3) | (3 << 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_usart>:
  endbr64
  mov    %edi,%eax
  shr    $0x8,%eax
  mov    %al,0xc5
  mov    %dil,0xc4
  movb   $0x18,0xc1
  movb   $0xe,0xc2
  ret
```

assistant: ```c
void init_usart(unsigned int ubrr) {
  *((volatile unsigned char *)(0xC5)) = (unsigned char)(ubrr >> 8);
  *((volatile unsigned char *)(0xC4)) = (unsigned char)ubrr;
  *((volatile unsigned char *)(0xC1)) = (1 << 4) | (1 << 3);
  *((volatile unsigned char *)(0xC2)) = (1 << 3) | (3 << 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<filecopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %esi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L1
L11:
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  mov    -0x428(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    %eax,-0x414(%rbp)
  je     L1
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  lea    -0x410(%rbp),%rcx
  mov    -0x424(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0x0,-0x414(%rbp)
  jg     L11
  cmpl   $0xffffffff,-0x414(%rbp)
  jne    L3
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
L3:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D2
type_infered: string

tool: D17: Cat cannot write


tool: D2: Cat cannot read

assistant: ```c
void filecopy(int fd1, int fd2) {
  int n;
  char buff[1024];
  while ((n = read(fd1, buff, 1024)) > 0) {
    if (write(fd2, buff, n) != n) {
      printf("Cat cannot write\n");
      exit(0);
    }
  }
  if (n == -1) {
    printf("Cat cannot read");
    exit(0);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<filecopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%r14
L15:
  mov    %rsp,%rbp
L9:
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L29
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  je     L9
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L15
L29:
  cmp    $0xffffffff,%eax
  je     L50
L32:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L32
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D9: Cat cannot write


tool: D2: Cat cannot read

assistant: ```c
void filecopy(int fd1, int fd2) {
  int n;
  char buff[1024];
  while ((n = read(fd1, buff, 1024)) > 0) {
    if (write(fd2, buff, n) != n) {
      printf("Cat cannot write\n");
      exit(0);
    }
  }
  if (n == -1) {
    printf("Cat cannot read");
    exit(0);
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<filecopy>:
  endbr64
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L22
L52:
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L37
  cmp    $0xffffffff,%eax
  je     L32
L17:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L22:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L52
  nopl   0x0(%rax)
L32:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L17
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string

tool: D14: Cat cannot write


tool: D4: Cat cannot read

assistant: ```c
void filecopy(int fd1, int fd2) {
  int n;
  char buff[1024];
  while ((n = read(fd1, buff, 1024)) > 0) {
    if (write(fd2, buff, n) != n) {
      printf("Cat cannot write\n");
      exit(0);
    }
  }
  if (n == -1) {
    printf("Cat cannot read");
    exit(0);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filecopy>:
  endbr64
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  cmp    %ebx,%eax
  jne    L54
L52:
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L18
  cmp    $0xffffffff,%eax
  je     L37
L56:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L54:
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L52
  nopl   0x0(%rax)
L37:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L56
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string

tool: D11: Cat cannot write


tool: D15: Cat cannot read

assistant: ```c
void filecopy(int fd1, int fd2) {
  int n;
  char buff[1024];
  while ((n = read(fd1, buff, 1024)) > 0) {
    if (write(fd2, buff, n) != n) {
      printf("Cat cannot write\n");
      exit(0);
    }
  }
  if (n == -1) {
    printf("Cat cannot read");
    exit(0);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inner_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double inner_product(int n, double *p, double *q) {
  double result = 0.0;
  int i;
  for (i = 0; i < n; i++)
    result = result + p[i] * q[i];
  return result;
}
```