ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ThrowOnBadRange>:
  endbr64
  cmp    %rsi,%rdi
  jb     L2
  cmp    %rdx,%rdi
  jbe    L11
L2:
  movl   $0x1,0x0
L11:
  ret
```

assistant: ```c
void ThrowOnBadRange(unsigned long ulValue, unsigned long ulMin, unsigned long ulMax) {
  if (ulValue < ulMin || ulValue > ulMax) {
    int *p = 0;
    (*p) = 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ThrowOnBadRange>:
  endbr64
  cmp    %rsi,%rdi
  jb     L14
  cmp    %rdx,%rdi
  ja     L14
  ret
  nop
L14:
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void ThrowOnBadRange(unsigned long ulValue, unsigned long ulMin, unsigned long ulMax) {
  if (ulValue < ulMin || ulValue > ulMax) {
    int *p = 0;
    (*p) = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ThrowOnBadRange>:
  endbr64
  cmp    %rsi,%rdi
  jb     L2
  cmp    %rdx,%rdi
  ja     L2
  ret
  nop
L2:
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void ThrowOnBadRange(unsigned long ulValue, unsigned long ulMin, unsigned long ulMax) {
  if (ulValue < ulMin || ulValue > ulMax) {
    int *p = 0;
    (*p) = 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ProcessInterProverRuleSelectionError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <AbortedMsg@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <Kill_bplatform_and_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6:        InterProver format error %d


assistant: ```c
void ProcessInterProverRuleSelectionError(nn) int nn;
{
  printf("       InterProver format error %d\n", nn);
  AbortedMsg();
  Kill_bplatform_and_exit(1, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ProcessInterProverRuleSelectionError>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <AbortedMsg@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <Kill_bplatform_and_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9:        InterProver format error %d


assistant: ```c
void ProcessInterProverRuleSelectionError(nn) int nn;
{
  printf("       InterProver format error %d\n", nn);
  AbortedMsg();
  Kill_bplatform_and_exit(1, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ProcessInterProverRuleSelectionError>:
  endbr64
  mov    %edi,%esi
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <AbortedMsg@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <Kill_bplatform_and_exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3:        InterProver format error %d


assistant: ```c
void ProcessInterProverRuleSelectionError(nn) int nn;
{
  printf("       InterProver format error %d\n", nn);
  AbortedMsg();
  Kill_bplatform_and_exit(1, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ProcessInterProverRuleSelectionError>:
  endbr64
  mov    %edi,%esi
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <AbortedMsg@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <Kill_bplatform_and_exit@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7:        InterProver format error %d


assistant: ```c
void ProcessInterProverRuleSelectionError(nn) int nn;
{
  printf("       InterProver format error %d\n", nn);
  AbortedMsg();
  Kill_bplatform_and_exit(1, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_searchenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_searchenv1@plt>
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %eax,%edi
  call   <memcheck@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <downcase@plt>
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_searchenv1@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L10
L6:
  nop
L10:
  leave
  ret
```

assistant: ```c
void my_searchenv(char *name, char *envname, char *hitfile, int hitlen) {
  my_searchenv1(name, envname, hitfile, hitlen);
  if (*hitfile) {
    return;
  }
  char *copy = memcheck(strdup(name));
  downcase(copy);
  my_searchenv1(copy, envname, hitfile, hitlen);
  free(copy);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_searchenv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  call   <my_searchenv1@plt>
  cmpb   $0x0,(%rbx)
  je     L12
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %eax,%edi
  call   <memcheck@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <downcase@plt>
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <my_searchenv1@plt>
  mov    %r13,%rdi
  call   <free@plt>
  jmp    L14
```

assistant: ```c
void my_searchenv(char *name, char *envname, char *hitfile, int hitlen) {
  my_searchenv1(name, envname, hitfile, hitlen);
  if (*hitfile) {
    return;
  }
  char *copy = memcheck(strdup(name));
  downcase(copy);
  my_searchenv1(copy, envname, hitfile, hitlen);
  free(copy);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_searchenv>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <my_searchenv1@plt>
  cmpb   $0x0,(%r12)
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    %eax,%edi
  call   <memcheck@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <downcase@plt>
  mov    %r14,%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <my_searchenv1@plt>
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
```

assistant: ```c
void my_searchenv(char *name, char *envname, char *hitfile, int hitlen) {
  my_searchenv1(name, envname, hitfile, hitlen);
  if (*hitfile) {
    return;
  }
  char *copy = memcheck(strdup(name));
  downcase(copy);
  my_searchenv1(copy, envname, hitfile, hitlen);
  free(copy);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_searchenv>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <my_searchenv1@plt>
  cmpb   $0x0,(%r12)
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    %eax,%edi
  call   <memcheck@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <downcase@plt>
  mov    %r14,%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <my_searchenv1@plt>
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
```

assistant: ```c
void my_searchenv(char *name, char *envname, char *hitfile, int hitlen) {
  my_searchenv1(name, envname, hitfile, hitlen);
  if (*hitfile) {
    return;
  }
  char *copy = memcheck(strdup(name));
  downcase(copy);
  my_searchenv1(copy, envname, hitfile, hitlen);
  free(copy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prod_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L19
L16:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <value@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <right@plt>
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  call   <prod_right>
  imul   -0x4(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
int prod_right(int l, struct pos *p, int n, int nums[]) {
  if (l == 0) {
    return 1;
  }
  int v = value(p, n, nums);
  right(p);
  return v * prod_right(l - 1, p, n, nums);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prod_right>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L1
  ret
L1:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %rcx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <value@plt>
  mov    %eax,%r14d
  mov    %rbp,%rdi
  call   <right@plt>
  lea    -0x1(%rbx),%edi
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <prod_right>
  imul   %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int prod_right(int l, struct pos *p, int n, int nums[]) {
  if (l == 0) {
    return 1;
  }
  int v = value(p, n, nums);
  right(p);
  return v * prod_right(l - 1, p, n, nums);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prod_right>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L12
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %rcx,%r13
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <value@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <right@plt>
  imul   %ebx,%r15d
  sub    $0x1,%ebp
  jne    L18
L12:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int prod_right(int l, struct pos *p, int n, int nums[]) {
  if (l == 0) {
    return 1;
  }
  int v = value(p, n, nums);
  right(p);
  return v * prod_right(l - 1, p, n, nums);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prod_right>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L8
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %rcx,%r13
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r13,%rdx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <value@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <right@plt>
  imul   %ebx,%r15d
  sub    $0x1,%ebp
  jne    L7
L8:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int prod_right(int l, struct pos *p, int n, int nums[]) {
  if (l == 0) {
    return 1;
  }
  int v = value(p, n, nums);
  right(p);
  return v * prod_right(l - 1, p, n, nums);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sinl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldt   0x10(%rbp)
  fsin
  fstpt  0x10(%rbp)
  fldt   0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double sinl(long double x) {
  __asm__ __volatile__("fldt %0;"
                       "fsin;"
                       "fstpt %0"
                       : "+m"(x));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sinl>:
  endbr64
  fldt   0x8(%rsp)
  fsin
  fstpt  0x8(%rsp)
  fldt   0x8(%rsp)
  ret
```

assistant: ```c
long double sinl(long double x) {
  __asm__ __volatile__("fldt %0;"
                       "fsin;"
                       "fstpt %0"
                       : "+m"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sinl>:
  endbr64
  fldt   0x8(%rsp)
  fsin
  fstpt  0x8(%rsp)
  fldt   0x8(%rsp)
  ret
```

assistant: ```c
long double sinl(long double x) {
  __asm__ __volatile__("fldt %0;"
                       "fsin;"
                       "fstpt %0"
                       : "+m"(x));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sinl>:
  endbr64
  fldt   0x8(%rsp)
  fsin
  fstpt  0x8(%rsp)
  fldt   0x8(%rsp)
  ret
```

assistant: ```c
long double sinl(long double x) {
  __asm__ __volatile__("fldt %0;"
                       "fsin;"
                       "fstpt %0"
                       : "+m"(x));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <C@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <C@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: multi=%d nelec=%d dim=%d


assistant: ```c
int main(int argc, char **argv) {
  int multi = atoi(argv[1]);
  int n = atoi(argv[2]);
  int dim = (int)(C(n, (n - multi + 1) / 2) - C(n, (n - multi - 1) / 2));
  printf("multi=%d nelec=%d dim=%d\n", multi, n, dim);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %eax,%r13d
  sub    %r12d,%r13d
  lea    0x1(%r13),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %ebx,%edi
  call   <C@plt>
  mov    %rax,%rbp
  sub    $0x1,%r13d
  mov    %r13d,%esi
  shr    $0x1f,%esi
  add    %r13d,%esi
  sar    %esi
  mov    %ebx,%edi
  call   <C@plt>
  mov    %ebp,%ecx
  sub    %eax,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: multi=%d nelec=%d dim=%d


assistant: ```c
int main(int argc, char **argv) {
  int multi = atoi(argv[1]);
  int n = atoi(argv[2]);
  int dim = (int)(C(n, (n - multi + 1) / 2) - C(n, (n - multi - 1) / 2));
  printf("multi=%d nelec=%d dim=%d\n", multi, n, dim);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    %eax,%r12d
  sub    %ebp,%r13d
  mov    %r12d,%edi
  lea    0x1(%r13),%eax
  sub    $0x1,%r13d
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <C@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  shr    $0x1f,%esi
  mov    %rax,%rbx
  add    %r13d,%esi
  sar    %esi
  call   <C@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  sub    %eax,%ecx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: multi=%d nelec=%d dim=%d


assistant: ```c
int main(int argc, char **argv) {
  int multi = atoi(argv[1]);
  int n = atoi(argv[2]);
  int dim = (int)(C(n, (n - multi + 1) / 2) - C(n, (n - multi - 1) / 2));
  printf("multi=%d nelec=%d dim=%d\n", multi, n, dim);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    %eax,%r12d
  sub    %ebp,%r13d
  mov    %r12d,%edi
  lea    0x1(%r13),%eax
  sub    $0x1,%r13d
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  call   <C@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  shr    $0x1f,%esi
  mov    %rax,%rbx
  add    %r13d,%esi
  sar    %esi
  call   <C@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  sub    %eax,%ecx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: multi=%d nelec=%d dim=%d


assistant: ```c
int main(int argc, char **argv) {
  int multi = atoi(argv[1]);
  int n = atoi(argv[2]);
  int dim = (int)(C(n, (n - multi + 1) / 2) - C(n, (n - multi - 1) / 2));
  printf("multi=%d nelec=%d dim=%d\n", multi, n, dim);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%edi
  call   <assert@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void read_line(FILE *file, char line[256]) {
  if (fgets(line, 256, file) == NULL) {
    assert(0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<read_line>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  mov    $0x100,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L14
L8:
  add    $0x8,%rsp
  ret
L14:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L8
```

assistant: ```c
void read_line(FILE *file, char line[256]) {
  if (fgets(line, 256, file) == NULL) {
    assert(0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_line>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  mov    $0x100,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

assistant: ```c
void read_line(FILE *file, char line[256]) {
  if (fgets(line, 256, file) == NULL) {
    assert(0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_line>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  mov    $0x100,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

assistant: ```c
void read_line(FILE *file, char line[256]) {
  if (fgets(line, 256, file) == NULL) {
    assert(0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<procmgr_collector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
L0:
  lea    -0x14(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jle    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: process %d exit


assistant: ```c
void *procmgr_collector(void *arg) {
  int status = 0;
  pid_t pid = 0;
  while (1) {
    pid = waitpid(-1, &status, 0);
    if (pid > 0) {
      printf("process %d exit\r\n", pid);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<procmgr_collector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D2(%rip),%rbp
L18:
  lea    0x4(%rsp),%rbx
L8:
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jle    L8
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: process %d exit


assistant: ```c
void *procmgr_collector(void *arg) {
  int status = 0;
  pid_t pid = 0;
  while (1) {
    pid = waitpid(-1, &status, 0);
    if (pid > 0) {
      printf("process %d exit\r\n", pid);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<procmgr_collector>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  xchg   %ax,%ax
L4:
  mov    %rbx,%rsi
  xor    %edx,%edx
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jle    L4
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: process %d exit


assistant: ```c
void *procmgr_collector(void *arg) {
  int status = 0;
  pid_t pid = 0;
  while (1) {
    pid = waitpid(-1, &status, 0);
    if (pid > 0) {
      printf("process %d exit\r\n", pid);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<procmgr_collector>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  xchg   %ax,%ax
L17:
  mov    %rbx,%rsi
  xor    %edx,%edx
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jle    L17
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: process %d exit


assistant: ```c
void *procmgr_collector(void *arg) {
  int status = 0;
  pid_t pid = 0;
  while (1) {
    pid = waitpid(-1, &status, 0);
    if (pid > 0) {
      printf("process %d exit\r\n", pid);
    }
  }
  return 0;
}
```