ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D35(%rip),%r15
  lea    D51(%rip),%r14
L13:
  lea    0x1(%rbx),%ebp
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebp,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbp
  lea    0x0(%rbp,%rbx,4),%rsi
  lea    D75(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  add    $0x14,%r13
  cmp    $0x5,%rbx
  jne    L13
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x64(%r12),%r13
  lea    D13(%rip),%rbx
L12:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  movsd  D66(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  add    $0x14,%r12
  cmp    %r13,%r12
  jne    L12
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: tag: D51
type_guessed: string
name: extract_symbolic_data
arguments: tag: D44
type_guessed: string
name: extract_symbolic_data
arguments: tag: D75
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D56
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D66
type_guessed: f64

tool: D35: 
Entre com nome do %d. funcionario:

tool: D51: %s

tool: D44: 
Entre com salario do %d. funcionario:

tool: D75: %f

tool: D24: 
Nome		Salario Bruto	Salario Liquido

tool: D56: 
--------------------------------------------------

tool: D13: 
%s		%.2f		%.2f

tool: D66: 0.8

assistant: ```c
int main() {
  char nomes[5][20];
  float salarios[5];
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nEntre com nome do %d. funcionario:", i + 1);
    scanf("%s", nomes[i]);
    printf("\nEntre com salario do %d. funcionario:", i + 1);
    scanf("%f", &salarios[i]);
  }
  printf("\nNome\t\tSalario Bruto\tSalario Liquido");
  printf("\n--------------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s\t\t%.2f\t\t%.2f", nomes[i], salarios[i], salarios[i] * 0.8);
  }
  printf("\n--------------------------------------------------");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D64(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D69(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x30(%rsp),%r13
  mov    %rax,0x8(%rsp)
  mov    %r13,%rbx
L6:
  lea    0x1(%rbp),%r14d
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %r14d,%esi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D72(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r14
  xor    %eax,%eax
  add    $0x14,%rbx
  lea    D19(%rip),%rdi
  lea    (%r14,%rbp,4),%rsi
  add    $0x1,%rbp
  call   <scanf@plt>
  cmp    $0x5,%rbp
  jne    L6
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  lea    0x64(%r13),%rbp
  lea    D15(%rip),%r12
  lea    D9(%rip),%rbx
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  pxor   %xmm0,%xmm0
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  D0(%rip),%xmm1
  cvtss2sd (%r14),%xmm0
  add    $0x14,%r13
  add    $0x4,%r14
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L18
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D64
datatype: string
name: disassemble_data
arguments: label: D69
datatype: string
name: disassemble_data
arguments: label: D72
datatype: string
name: disassemble_data
arguments: label: D19
datatype: string
name: disassemble_data
arguments: label: D13
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D0
datatype: f64

tool: D64: 
Entre com nome do %d. funcionario:

tool: D69: 
Entre com salario do %d. funcionario:

tool: D72: %s

tool: D19: %f

tool: D13: 
Nome		Salario Bruto	Salario Liquido

tool: D15: 
--------------------------------------------------

tool: D9: 
%s		%.2f		%.2f

tool: D0: 0.8

assistant: ```c
int main() {
  char nomes[5][20];
  float salarios[5];
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nEntre com nome do %d. funcionario:", i + 1);
    scanf("%s", nomes[i]);
    printf("\nEntre com salario do %d. funcionario:", i + 1);
    scanf("%f", &salarios[i]);
  }
  printf("\nNome\t\tSalario Bruto\tSalario Liquido");
  printf("\n--------------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s\t\t%.2f\t\t%.2f", nomes[i], salarios[i], salarios[i] * 0.8);
  }
  printf("\n--------------------------------------------------");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D6(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D33(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x30(%rsp),%r13
  mov    %rax,0x8(%rsp)
  mov    %r13,%rbx
L20:
  lea    0x1(%rbp),%r14d
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %r14d,%esi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r14
  xor    %eax,%eax
  add    $0x14,%rbx
  lea    D19(%rip),%rdi
  lea    (%r14,%rbp,4),%rsi
  add    $0x1,%rbp
  call   <scanf@plt>
  cmp    $0x5,%rbp
  jne    L20
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  lea    0x64(%r13),%rbp
  lea    D3(%rip),%r12
  lea    D55(%rip),%rbx
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L6:
  pxor   %xmm0,%xmm0
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  D44(%rip),%xmm1
  cvtss2sd (%r14),%xmm0
  add    $0x14,%r13
  add    $0x4,%r14
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    %r13,%rbp
  jne    L6
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string
name: read_data
arguments: data_label: D33
data_type: string
name: read_data
arguments: data_label: D43
data_type: string
name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D49
data_type: string
name: read_data
arguments: data_label: D3
data_type: string
name: read_data
arguments: data_label: D55
data_type: string
name: read_data
arguments: data_label: D44
data_type: f64

tool: D6: 
Entre com nome do %d. funcionario:

tool: D33: 
Entre com salario do %d. funcionario:

tool: D43: %s

tool: D19: %f

tool: D49: 
Nome		Salario Bruto	Salario Liquido

tool: D3: 
--------------------------------------------------

tool: D55: 
%s		%.2f		%.2f

tool: D44: 0.8

assistant: ```c
int main() {
  char nomes[5][20];
  float salarios[5];
  int i;
  for (i = 0; i < 5; i++) {
    printf("\nEntre com nome do %d. funcionario:", i + 1);
    scanf("%s", nomes[i]);
    printf("\nEntre com salario do %d. funcionario:", i + 1);
    scanf("%f", &salarios[i]);
  }
  printf("\nNome\t\tSalario Bruto\tSalario Liquido");
  printf("\n--------------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s\t\t%.2f\t\t%.2f", nomes[i], salarios[i], salarios[i] * 0.8);
  }
  printf("\n--------------------------------------------------");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fts_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L4
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L4
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L4
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L4
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L4
  mov    D45(%rip),%rax
  mov    (%rax),%edx
  mov    D29(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L48
L4:
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
int fts_set(FTS *sp, FTSENT *p, int instr) {
  ;
  ;
  if (instr && instr != FTS_AGAIN && instr != FTS_FOLLOW && instr != FTS_NOINSTR && instr != FTS_SKIP) {
    errno = EINVAL;
    return (1);
  }
  p->fts_instr = instr;
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<fts_set>:
  endbr64
  test   %edx,%edx
  je     L1
  mov    D42(%rip),%rax
  cmp    %edx,(%rax)
  je     L1
  mov    D15(%rip),%rax
  cmp    %edx,(%rax)
  je     L1
  mov    D10(%rip),%rax
  cmp    %edx,(%rax)
  je     L1
  mov    D19(%rip),%rax
  cmp    %edx,(%rax)
  je     L1
  mov    D57(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  ret
L1:
  mov    %edx,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int fts_set(FTS *sp, FTSENT *p, int instr) {
  ;
  ;
  if (instr && instr != FTS_AGAIN && instr != FTS_FOLLOW && instr != FTS_NOINSTR && instr != FTS_SKIP) {
    errno = EINVAL;
    return (1);
  }
  p->fts_instr = instr;
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<fts_set>:
  endbr64
  test   %edx,%edx
  je     L23
  mov    D37(%rip),%rax
  cmp    %edx,(%rax)
  je     L23
  mov    D1(%rip),%rax
  cmp    %edx,(%rax)
  je     L23
  mov    D20(%rip),%rax
  cmp    %edx,(%rax)
  je     L23
  mov    D4(%rip),%rax
  cmp    %edx,(%rax)
  je     L23
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D46(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L23:
  mov    %edx,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int fts_set(FTS *sp, FTSENT *p, int instr) {
  ;
  ;
  if (instr && instr != FTS_AGAIN && instr != FTS_FOLLOW && instr != FTS_NOINSTR && instr != FTS_SKIP) {
    errno = EINVAL;
    return (1);
  }
  p->fts_instr = instr;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fts_set>:
  endbr64
  test   %edx,%edx
  je     L43
  mov    D59(%rip),%rax
  cmp    %edx,(%rax)
  je     L43
  mov    D12(%rip),%rax
  cmp    %edx,(%rax)
  je     L43
  mov    D32(%rip),%rax
  cmp    %edx,(%rax)
  je     L43
  mov    D30(%rip),%rax
  cmp    %edx,(%rax)
  je     L43
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    D47(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L43:
  mov    %edx,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int fts_set(FTS *sp, FTSENT *p, int instr) {
  ;
  ;
  if (instr && instr != FTS_AGAIN && instr != FTS_FOLLOW && instr != FTS_NOINSTR && instr != FTS_SKIP) {
    errno = EINVAL;
    return (1);
  }
  p->fts_instr = instr;
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_myAdd_normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,(%rax)
  mov    $0x6,%esi
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <myAdd@plt>
  cmp    $0xa,%eax
  je     L4
  lea    D23(%rip),%rax
  jmp    L7
L4:
  mov    -0x8(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,(%rax)
  mov    $0x6,%esi
  mov    $0x5,%edi
  mov    $0x0,%eax
  call   <myAdd@plt>
  cmp    $0xb,%eax
  je     L13
  lea    D16(%rip),%rax
  jmp    L7
L13:
  mov    $0x0,%eax
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D16
type: string

tool: D33: test_myAdd_normal

tool: D23: 4 + 6 == 10

tool: D16: 5 + 6 == 11

assistant: ```c
char *test_myAdd_normal(const char **_ja_name) {
  do {
    *_ja_name = __func__;
    if (!(myAdd(4, 6) == 10))
      return "4 + 6 == 10";
  } while (0);
  do {
    *_ja_name = __func__;
    if (!(myAdd(5, 6) == 11))
      return "5 + 6 == 11";
  } while (0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_myAdd_normal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rax
  mov    %rax,(%rdi)
  mov    $0x6,%esi
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <myAdd@plt>
  mov    %eax,%edx
  lea    D15(%rip),%rax
  cmp    $0xa,%edx
  je     L7
L16:
  pop    %rbx
  ret
L7:
  lea    D7(%rip),%rax
  mov    %rax,(%rbx)
  mov    $0x6,%esi
  mov    $0x5,%edi
  mov    $0x0,%eax
  call   <myAdd@plt>
  cmp    $0xb,%eax
  lea    D35(%rip),%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D35
datatype: string

tool: D7: test_myAdd_normal

tool: D15: 4 + 6 == 10

tool: D35: 5 + 6 == 11

assistant: ```c
char *test_myAdd_normal(const char **_ja_name) {
  do {
    *_ja_name = __func__;
    if (!(myAdd(4, 6) == 10))
      return "4 + 6 == 10";
  } while (0);
  do {
    *_ja_name = __func__;
    if (!(myAdd(5, 6) == 11))
      return "5 + 6 == 11";
  } while (0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_myAdd_normal>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    $0x6,%esi
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    %rbp,(%rdi)
  mov    $0x4,%edi
  call   <myAdd@plt>
  mov    %eax,%r8d
  lea    D21(%rip),%rax
  cmp    $0xa,%r8d
  je     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L0:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <myAdd@plt>
  mov    $0x0,%edx
  cmp    $0xb,%eax
  lea    D16(%rip),%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type_guessed: string
name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D15: test_myAdd_normal

tool: D21: 4 + 6 == 10

tool: D16: 5 + 6 == 11

assistant: ```c
char *test_myAdd_normal(const char **_ja_name) {
  do {
    *_ja_name = __func__;
    if (!(myAdd(4, 6) == 10))
      return "4 + 6 == 10";
  } while (0);
  do {
    *_ja_name = __func__;
    if (!(myAdd(5, 6) == 11))
      return "5 + 6 == 11";
  } while (0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_myAdd_normal>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  mov    $0x6,%esi
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    %rbp,(%rdi)
  mov    $0x4,%edi
  call   <myAdd@plt>
  mov    %eax,%r8d
  lea    D0(%rip),%rax
  cmp    $0xa,%r8d
  je     L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L3:
  mov    %rbp,(%rbx)
  xor    %eax,%eax
  mov    $0x6,%esi
  mov    $0x5,%edi
  call   <myAdd@plt>
  mov    $0x0,%edx
  cmp    $0xb,%eax
  lea    D9(%rip),%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D24: test_myAdd_normal

tool: D0: 4 + 6 == 10

tool: D9: 5 + 6 == 11

assistant: ```c
char *test_myAdd_normal(const char **_ja_name) {
  do {
    *_ja_name = __func__;
    if (!(myAdd(4, 6) == 10))
      return "4 + 6 == 10";
  } while (0);
  do {
    *_ja_name = __func__;
    if (!(myAdd(5, 6) == 11))
      return "5 + 6 == 11";
  } while (0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L37
L8:
  mov    -0x9c54(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <montarMatriz@plt>
  mov    -0x9c54(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <imprimirMatriz@plt>
L37:
  lea    -0x9c54(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x9c54(%rbp),%eax
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main(void) {
  int n, matriz[100][100];
  while (scanf("%d", &n), n != 0) {
    montarMatriz(matriz, n);
    imprimirMatriz(matriz, n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L26:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L26
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rbp
  jmp    L11
L6:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <montarMatriz@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <imprimirMatriz@plt>
L11:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jne    L6
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x9c68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
int main(void) {
  int n, matriz[100][100];
  while (scanf("%d", &n), n != 0) {
    montarMatriz(matriz, n);
    imprimirMatriz(matriz, n);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L38:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L38
  sub    $0xc60,%rsp
  lea    D1(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbx
  jmp    L31
  xchg   %ax,%ax
L24:
  mov    %rbx,%rdi
  call   <montarMatriz@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <imprimirMatriz@plt>
L31:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jne    L24
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x9c60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main(void) {
  int n, matriz[100][100];
  while (scanf("%d", &n), n != 0) {
    montarMatriz(matriz, n);
    imprimirMatriz(matriz, n);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xc60,%rsp
  lea    D0(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbx
  jmp    L4
  xchg   %ax,%ax
L14:
  mov    %rbx,%rdi
  call   <montarMatriz@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <imprimirMatriz@plt>
L4:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jne    L14
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x9c60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: %d

assistant: ```c
int main(void) {
  int n, matriz[100][100];
  while (scanf("%d", &n), n != 0) {
    montarMatriz(matriz, n);
    imprimirMatriz(matriz, n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_invalid_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0xa,%edx
  mov    $0xffffffec,%esi
  mov    %rax,%rdi
  call   <sequential_search@plt>
  cmp    $0xfffffffd,%eax
  je     L8
  mov    $0x1d,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  jmp    L42
L8:
  lea    -0x14(%rbp),%rax
  mov    $0x1e,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sequential_search@plt>
  cmp    $0xfffffffd,%eax
  je     L47
  mov    $0x1e,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  jmp    L42
L47:
  mov    $0x0,%eax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D3: Line number is: %d


tool: D2: error, searched array with negative size

tool: D0: error, searched array with zero size

assistant: ```c
char *test_invalid_size() {
  int array[] = {1, 6, 4};
  do {
    if (!(sequential_search(array, -20, 10) == -3)) {
      printf("Line number is: %d\n", 29);
      return "error, searched array with negative size";
    }
  } while (0);
  do {
    if (!(sequential_search(array, 0, 30) == -3)) {
      printf("Line number is: %d\n", 30);
      return "error, searched array with zero size";
    }
  } while (0);
  return 0;
}
```