ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%r8d
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mapRange@plt>
  movq   %xmm0,%rax
  mov    -0x4(%rbp),%edx
  movq   %rax,%xmm0
  mov    %edx,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0xa,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string

tool: D1: Mapping [0,10] to [-1,0] at intervals of 1:

tool: D11: f(%d) = %g


assistant: ```c
int main() {
  int i;
  puts("Mapping [0,10] to [-1,0] at intervals of 1:");
  for (i = 0; i <= 10; i++) {
    printf("f(%d) = %g\n", i, mapRange(0, 10, -1, 0, i));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L2:
  mov    %ebx,%r8d
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <mapRange@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D6: Mapping [0,10] to [-1,0] at intervals of 1:

tool: D1: f(%d) = %g


assistant: ```c
int main() {
  int i;
  puts("Mapping [0,10] to [-1,0] at intervals of 1:");
  for (i = 0; i <= 10; i++) {
    printf("f(%d) = %g\n", i, mapRange(0, 10, -1, 0, i));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nop
L0:
  mov    %ebx,%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <mapRange@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D11: Mapping [0,10] to [-1,0] at intervals of 1:

tool: D8: f(%d) = %g


assistant: ```c
int main() {
  int i;
  puts("Mapping [0,10] to [-1,0] at intervals of 1:");
  for (i = 0; i <= 10; i++) {
    printf("f(%d) = %g\n", i, mapRange(0, 10, -1, 0, i));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D19(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nop
L4:
  mov    %ebx,%r8d
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <mapRange@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D13: Mapping [0,10] to [-1,0] at intervals of 1:

tool: D19: f(%d) = %g


assistant: ```c
int main() {
  int i;
  puts("Mapping [0,10] to [-1,0] at intervals of 1:");
  for (i = 0; i <= 10; i++) {
    printf("f(%d) = %g\n", i, mapRange(0, 10, -1, 0, i));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L18
  mov    -0x4(%rbp),%eax
  jmp    L2
L18:
  mov    -0x8(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<min>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int min(int a, int b) {
  if (a <= b) {
    return a;
  } else {
    return b;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atoo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L16
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x38,%al
  jg     L16
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L16:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L34
L28:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoo(char *buff) {
  int i = 0;
  int num = 0;
  while (buff[i] != '\0' && buff[i] != '\n') {
    if (buff[i] >= '0' && buff[i] < '9')
      num = num * 8 + ((buff[i]) - '0');
    i++;
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<atoo>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  cmp    $0xa,%al
  je     L23
  add    $0x1,%rdi
  mov    $0x0,%ecx
  jmp    L43
L40:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L38
  cmp    $0xa,%al
  je     L38
L43:
  lea    -0x30(%rax),%edx
  cmp    $0x8,%dl
  ja     L40
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,8),%ecx
  jmp    L40
L23:
  mov    $0x0,%ecx
L38:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int atoo(char *buff) {
  int i = 0;
  int num = 0;
  while (buff[i] != '\0' && buff[i] != '\n') {
    if (buff[i] >= '0' && buff[i] < '9')
      num = num * 8 + ((buff[i]) - '0');
    i++;
  }
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<atoo>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  cmp    $0xa,%al
  je     L48
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L40:
  sub    $0x30,%eax
  cmp    $0x8,%al
  ja     L13
  movsbl %al,%eax
  lea    (%rax,%r8,8),%r8d
L13:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L35
  cmp    $0xa,%al
  jne    L40
L35:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L48:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoo(char *buff) {
  int i = 0;
  int num = 0;
  while (buff[i] != '\0' && buff[i] != '\n') {
    if (buff[i] >= '0' && buff[i] < '9')
      num = num * 8 + ((buff[i]) - '0');
    i++;
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atoo>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  cmp    $0xa,%al
  je     L2
  add    $0x1,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L29:
  sub    $0x30,%eax
  cmp    $0x8,%al
  ja     L42
  movsbl %al,%eax
  lea    (%rax,%r8,8),%r8d
L42:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L22
  cmp    $0xa,%al
  jne    L29
L22:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoo(char *buff) {
  int i = 0;
  int num = 0;
  while (buff[i] != '\0' && buff[i] != '\n') {
    if (buff[i] >= '0' && buff[i] < '9')
      num = num * 8 + ((buff[i]) - '0');
    i++;
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<history_search_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%eax
  call   <where_history@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <history_search@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
  mov    $0xffffffff,%eax
  jmp    L1
L18:
  mov    $0x0,%eax
  call   <where_history@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
  mov    -0x4(%rbp),%eax
L1:
  leave
  ret
```

assistant: ```c
int history_search_pos(string, dir, pos)
char *string;
int dir, pos;
{
  int ret, old;
  old = where_history();
  history_set_pos(pos);
  if (history_search(string, dir) == -1) {
    history_set_pos(old);
    return (-1);
  }
  ret = where_history();
  history_set_pos(old);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<history_search_pos>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r13d
  mov    $0x0,%eax
  call   <where_history@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <history_search@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    $0x0,%eax
  call   <where_history@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
L0:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    %eax,%ebx
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <history_set_pos@plt>
  jmp    L0
```

assistant: ```c
int history_search_pos(string, dir, pos)
char *string;
int dir, pos;
{
  int ret, old;
  old = where_history();
  history_set_pos(pos);
  if (history_search(string, dir) == -1) {
    history_set_pos(old);
    return (-1);
  }
  ret = where_history();
  history_set_pos(old);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<history_search_pos>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <where_history@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <history_set_pos@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <history_search@plt>
  cmp    $0xffffffff,%eax
  je     L2
  xor    %eax,%eax
  call   <where_history@plt>
L2:
  mov    %eax,%r12d
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <history_set_pos@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int history_search_pos(string, dir, pos)
char *string;
int dir, pos;
{
  int ret, old;
  old = where_history();
  history_set_pos(pos);
  if (history_search(string, dir) == -1) {
    history_set_pos(old);
    return (-1);
  }
  ret = where_history();
  history_set_pos(old);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<history_search_pos>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <where_history@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <history_set_pos@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <history_search@plt>
  cmp    $0xffffffff,%eax
  je     L9
  xor    %eax,%eax
  call   <where_history@plt>
L9:
  mov    %eax,%r12d
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <history_set_pos@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int history_search_pos(string, dir, pos)
char *string;
int dir, pos;
{
  int ret, old;
  old = where_history();
  history_set_pos(pos);
  if (history_search(string, dir) == -1) {
    history_set_pos(old);
    return (-1);
  }
  ret = where_history();
  history_set_pos(old);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cpu_temperature>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <i8k_get_cpu_temp@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: %d


assistant: ```c
int cpu_temperature() {
  printf("%d\n", i8k_get_cpu_temp());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cpu_temperature>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <i8k_get_cpu_temp@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int cpu_temperature() {
  printf("%d\n", i8k_get_cpu_temp());
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cpu_temperature>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <i8k_get_cpu_temp@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int cpu_temperature() {
  printf("%d\n", i8k_get_cpu_temp());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpu_temperature>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <i8k_get_cpu_temp@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int cpu_temperature() {
  printf("%d\n", i8k_get_cpu_temp());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<grabYear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L10:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L10
  sub    $0x30,%rsp
  mov    %rdi,-0x4028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4028(%rbp),%rdx
  lea    -0x4010(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x4010(%rbp),%rcx
  lea    -0x2010(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x200c(%rbp)
  lea    -0x4018(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x4018(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %lu

assistant: ```c
unsigned long grabYear(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long year;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf, 4);
  buf2[4] = '\0';
  sscanf(buf2, "%lu", &year);
  return year;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grabYear>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x20,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    D9(%rip),%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    0x2010(%rsp),%rbx
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x2014(%rsp)
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x4020,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
datatype: string

tool: D9: %lu

assistant: ```c
unsigned long grabYear(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long year;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf, 4);
  buf2[4] = '\0';
  sscanf(buf2, "%lu", &year);
  return year;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<grabYear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x20,%rsp
  lea    D5(%rip),%r12
  mov    %r12,%rsi
  lea    0x10(%rsp),%r13
  mov    %rdi,%rdx
  lea    0x2010(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2014(%rsp)
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x4020,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: %lu

assistant: ```c
unsigned long grabYear(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long year;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf, 4);
  buf2[4] = '\0';
  sscanf(buf2, "%lu", &year);
  return year;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<grabYear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L1:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L1
  sub    $0x20,%rsp
  lea    D1(%rip),%r12
  mov    %r12,%rsi
  lea    0x10(%rsp),%r13
  mov    %rdi,%rdx
  lea    0x2010(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2014(%rsp)
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x4020,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: %lu

assistant: ```c
unsigned long grabYear(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long year;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf, 4);
  buf2[4] = '\0';
  sscanf(buf2, "%lu", &year);
  return year;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exist_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movss  %xmm1,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L3:
  movss  -0x1c(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rcx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  D7(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rcx
  jne    L27
  movss  -0x20(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rcx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  0x4(%rax),%xmm1
  movss  D7(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rcx
  jne    L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  0x8(%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
L27:
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x7a,0x44]}

assistant: ```c
float exist_file(float FR8[5000][3], float lat, float lon, int cells) {
  int i;
  float return_fraction = 0.0;
  for (i = 0; i < cells; i++) {
    if (((long)(1000 * lat) == (long)(1000 * FR8[i][0])) && ((long)(1000 * lon) == (long)(1000 * FR8[i][1]))) {
      return_fraction = FR8[i][2];
    }
  }
  return return_fraction;
}
```
user: What is the c source code of the assembly code below?

```asm
<exist_file>:
  endbr64
  test   %esi,%esi
  jle    L50
  mulss  D5(%rip),%xmm0
  cvttss2si %xmm0,%r8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    (%rdx,%rdx,2),%rdx
  lea    0xc(%rdi,%rdx,4),%rsi
  pxor   %xmm4,%xmm4
  movss  D5(%rip),%xmm2
  movaps %xmm2,%xmm3
  jmp    L47
L10:
  add    $0xc,%rax
  cmp    %rsi,%rax
  je     L14
L47:
  movaps %xmm2,%xmm0
  mulss  (%rax),%xmm0
  cvttss2si %xmm0,%rdx
  cmp    %rdx,%r8
  jne    L10
  movaps %xmm1,%xmm0
  mulss  %xmm3,%xmm0
  cvttss2si %xmm0,%rdi
  movaps %xmm3,%xmm0
  mulss  0x4(%rax),%xmm0
  cvttss2si %xmm0,%rdx
  cmp    %rdx,%rdi
  jne    L10
  movss  0x8(%rax),%xmm4
  jmp    L10
L50:
  pxor   %xmm4,%xmm4
L14:
  movaps %xmm4,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: byte[4]

tool: {"D5": [0x00,0x00,0x7a,0x44]}

assistant: ```c
float exist_file(float FR8[5000][3], float lat, float lon, int cells) {
  int i;
  float return_fraction = 0.0;
  for (i = 0; i < cells; i++) {
    if (((long)(1000 * lat) == (long)(1000 * FR8[i][0])) && ((long)(1000 * lon) == (long)(1000 * FR8[i][1]))) {
      return_fraction = FR8[i][2];
    }
  }
  return return_fraction;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exist_file>:
  endbr64
  test   %esi,%esi
  jle    L29
  movss  D1(%rip),%xmm2
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    (%rax,%rax,2),%rax
  mulss  %xmm2,%xmm0
  lea    0xc(%rdi,%rax,4),%rdx
  cvttss2si %xmm0,%rcx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0xc,%rdi
  cmp    %rdx,%rdi
  je     L50
L18:
  movss  (%rdi),%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rcx
  jne    L26
  movaps %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rsi
  movss  0x4(%rdi),%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rsi
  jne    L26
  movss  0x8(%rdi),%xmm3
  add    $0xc,%rdi
  cmp    %rdx,%rdi
  jne    L18
L50:
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L29:
  pxor   %xmm3,%xmm3
  movaps %xmm3,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: byte[4]

tool: {"D1": [0x00,0x00,0x7a,0x44]}

assistant: ```c
float exist_file(float FR8[5000][3], float lat, float lon, int cells) {
  int i;
  float return_fraction = 0.0;
  for (i = 0; i < cells; i++) {
    if (((long)(1000 * lat) == (long)(1000 * FR8[i][0])) && ((long)(1000 * lon) == (long)(1000 * FR8[i][1]))) {
      return_fraction = FR8[i][2];
    }
  }
  return return_fraction;
}
```