ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  mov    $0x1,%edi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x15,%r12d
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  movaps %xmm0,(%rsp)
  call   <_mm_malloc@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L64:
  test   %rbp,%rbp
  je     L28
L68:
  mov    $0x10,%r15d
  mov    %r14,%rsi
  mov    %rbp,%rdi
  cmp    %r15d,%ebx
  cmovbe %ebx,%r15d
  mov    %r15d,%edx
  call   <memcpy@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  mov    %rbp,%rdi
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r13d
  add    %ebx,%ebx
  call   <_mm_free@plt>
  sub    $0x1,%r12d
  je     L79
L49:
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <_mm_malloc@plt>
  mov    %rax,%rbp
  lea    -0x1(%rbx),%eax
  test   %ebp,%eax
  je     L64
  xor    %eax,%eax
  call   <abort@plt>
  test   %rbp,%rbp
  jne    L68
L28:
  add    $0x1,%r13d
  add    %ebx,%ebx
  sub    $0x1,%r12d
  jne    L49
L79:
  test   %r13d,%r13d
  jne    L45
L9:
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L9
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: byte[16]

tool: {"D9": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x74,0x65,0x73,0x74,0x2e,0x00]}

assistant: ```c
int main() {
  int alignment, n;
  void *ptr;
  int errors = 0;
  const char test[] = "This is a test.";
  for (alignment = 1; alignment <= (1 << 20); alignment += alignment) {
    ptr = _mm_malloc(alignment, alignment);
    if (((ptrdiff_t)ptr) & (alignment - 1))
      abort();
    if (ptr) {
      n = alignment > sizeof test ? sizeof test : alignment;
      memcpy(ptr, test, n);
      if (memcmp(ptr, test, n) != 0)
        errors++;
      _mm_free(ptr);
    } else
      errors++;
  }
  if (errors != 0)
    abort();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_test_case_executor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edi
  mov    -0x18(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %edi,%r9d
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0:   if (1 == cutest_test_name_argument_given("%s")) {
    memset(&cutest_mock, 0, sizeof(cutest_mock));
    cutest_execute_test(&junit_report[%llu], cutest_%s, "%s", %d, argv[0]);
  }


assistant: ```c
void print_test_case_executor(const char *name, size_t idx, int reset_mocks) {
  const unsigned long long int idx_llu = idx;
  printf("  if (1 == cutest_test_name_argument_given(\"%s\")) {\n"
         "    memset(&cutest_mock, 0, sizeof(cutest_mock));\n"
         "    cutest_execute_test(&junit_report[%llu], cutest_%s, \"%s\", %d, argv[0]);\n"
         "  }\n",
         name, idx_llu, name, name, reset_mocks);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_test_case_executor>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %edx,%r9d
  mov    %rdi,%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1:   if (1 == cutest_test_name_argument_given("%s")) {
    memset(&cutest_mock, 0, sizeof(cutest_mock));
    cutest_execute_test(&junit_report[%llu], cutest_%s, "%s", %d, argv[0]);
  }


assistant: ```c
void print_test_case_executor(const char *name, size_t idx, int reset_mocks) {
  const unsigned long long int idx_llu = idx;
  printf("  if (1 == cutest_test_name_argument_given(\"%s\")) {\n"
         "    memset(&cutest_mock, 0, sizeof(cutest_mock));\n"
         "    cutest_execute_test(&junit_report[%llu], cutest_%s, \"%s\", %d, argv[0]);\n"
         "  }\n",
         name, idx_llu, name, name, reset_mocks);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_test_case_executor>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%r9d
  mov    %rdi,%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6:   if (1 == cutest_test_name_argument_given("%s")) {
    memset(&cutest_mock, 0, sizeof(cutest_mock));
    cutest_execute_test(&junit_report[%llu], cutest_%s, "%s", %d, argv[0]);
  }


assistant: ```c
void print_test_case_executor(const char *name, size_t idx, int reset_mocks) {
  const unsigned long long int idx_llu = idx;
  printf("  if (1 == cutest_test_name_argument_given(\"%s\")) {\n"
         "    memset(&cutest_mock, 0, sizeof(cutest_mock));\n"
         "    cutest_execute_test(&junit_report[%llu], cutest_%s, \"%s\", %d, argv[0]);\n"
         "  }\n",
         name, idx_llu, name, name, reset_mocks);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_test_case_executor>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%r9d
  mov    %rdi,%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3:   if (1 == cutest_test_name_argument_given("%s")) {
    memset(&cutest_mock, 0, sizeof(cutest_mock));
    cutest_execute_test(&junit_report[%llu], cutest_%s, "%s", %d, argv[0]);
  }


assistant: ```c
void print_test_case_executor(const char *name, size_t idx, int reset_mocks) {
  const unsigned long long int idx_llu = idx;
  printf("  if (1 == cutest_test_name_argument_given(\"%s\")) {\n"
         "    memset(&cutest_mock, 0, sizeof(cutest_mock));\n"
         "    cutest_execute_test(&junit_report[%llu], cutest_%s, \"%s\", %d, argv[0]);\n"
         "  }\n",
         name, idx_llu, name, name, reset_mocks);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vgetbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L19
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jge    L7
L19:
  mov    $0x0,%eax
  jmp    L4
L7:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  sarl   %cl,-0x1c(%rbp)
  jmp    L11
L27:
  mov    -0x1c(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  subq   $0x4,-0x18(%rbp)
  sarl   -0x1c(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L27
  mov    -0x8(%rbp),%rax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int *vgetbits(int *y, int x, int p, int n) {
  int lsb = 0x1;
  int *retval = y;
  if (n < 0 || p < n - 1)
    return (NULL);
  for (y += n - 1, x >>= p - n + 1; y >= retval; y--, x >>= 1)
    *y = x & lsb;
  return (retval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vgetbits>:
  endbr64
  test   %ecx,%ecx
  js     L55
  lea    -0x1(%rcx),%eax
  cmp    %edx,%eax
  jg     L26
  movslq %ecx,%rax
  lea    -0x4(%rdi,%rax,4),%rax
  sub    %ecx,%edx
  lea    0x1(%rdx),%ecx
  sar    %cl,%esi
  cmp    %rax,%rdi
  ja     L9
L32:
  mov    %esi,%edx
  and    $0x1,%edx
  mov    %edx,(%rax)
  sub    $0x4,%rax
  sar    %esi
  cmp    %rax,%rdi
  jbe    L32
L9:
  mov    %rdi,%rax
  ret
L55:
  mov    $0x0,%edi
  jmp    L9
L26:
  mov    $0x0,%edi
  jmp    L9
```

assistant: ```c
int *vgetbits(int *y, int x, int p, int n) {
  int lsb = 0x1;
  int *retval = y;
  if (n < 0 || p < n - 1)
    return (NULL);
  for (y += n - 1, x >>= p - n + 1; y >= retval; y--, x >>= 1)
    *y = x & lsb;
  return (retval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vgetbits>:
  endbr64
  mov    %rdi,%rax
  test   %ecx,%ecx
  js     L26
  lea    -0x1(%rcx),%edi
  cmp    %edx,%edi
  jg     L26
  movslq %ecx,%rdi
  sub    %ecx,%edx
  lea    0x1(%rdx),%ecx
  lea    -0x4(%rax,%rdi,4),%rdi
  sar    %cl,%esi
  cmp    %rdi,%rax
  ja     L28
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %esi,%edx
  sub    $0x4,%rdi
  sar    %esi
  and    $0x1,%edx
  mov    %edx,0x4(%rdi)
  cmp    %rdi,%rax
  jbe    L14
  ret
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
L28:
  ret
```

assistant: ```c
int *vgetbits(int *y, int x, int p, int n) {
  int lsb = 0x1;
  int *retval = y;
  if (n < 0 || p < n - 1)
    return (NULL);
  for (y += n - 1, x >>= p - n + 1; y >= retval; y--, x >>= 1)
    *y = x & lsb;
  return (retval);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vgetbits>:
  endbr64
  mov    %rdi,%rax
  test   %ecx,%ecx
  js     L39
  lea    -0x1(%rcx),%edi
  cmp    %edx,%edi
  jg     L39
  movslq %ecx,%rdi
  sub    %ecx,%edx
  lea    0x1(%rdx),%ecx
  lea    -0x4(%rax,%rdi,4),%rdi
  sar    %cl,%esi
  cmp    %rdi,%rax
  ja     L18
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %esi,%edx
  sub    $0x4,%rdi
  sar    %esi
  and    $0x1,%edx
  mov    %edx,0x4(%rdi)
  cmp    %rdi,%rax
  jbe    L5
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
L18:
  ret
```

assistant: ```c
int *vgetbits(int *y, int x, int p, int n) {
  int lsb = 0x1;
  int *retval = y;
  if (n < 0 || p < n - 1)
    return (NULL);
  for (y += n - 1, x >>= p - n + 1; y >= retval; y--, x >>= 1)
    *y = x & lsb;
  return (retval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<database_restore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x818(%rbp),%rax
  mov    %rax,%rdi
  call   <file_exists@plt>
  test   %rax,%rax
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L24
L18:
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <database_directory@plt>
  mov    -0x818(%rbp),%rcx
  lea    -0x810(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x1,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: tar -C %s -zxpf %s

assistant: ```c
int database_restore(char backup_filename[]) {
  char directory[1024];
  char command[1024];
  if (file_exists(backup_filename) == 0)
    return -1;
  database_directory(directory);
  sprintf(command, "tar -C %s -zxpf %s", directory, backup_filename);
  system(command);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<database_restore>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <file_exists@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L25
L27:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <database_directory@plt>
  lea    0x400(%rsp),%rbp
  mov    %rbx,%rcx
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    $0x1,%eax
  jmp    L27
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: tar -C %s -zxpf %s

assistant: ```c
int database_restore(char backup_filename[]) {
  char directory[1024];
  char command[1024];
  if (file_exists(backup_filename) == 0)
    return -1;
  database_directory(directory);
  sprintf(command, "tar -C %s -zxpf %s", directory, backup_filename);
  system(command);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<database_restore>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <file_exists@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  je     L17
  mov    %rsp,%r13
  lea    0x400(%rsp),%rbp
  mov    %r13,%rdi
  call   <database_directory@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    $0x1,%eax
L17:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: tar -C %s -zxpf %s

assistant: ```c
int database_restore(char backup_filename[]) {
  char directory[1024];
  char command[1024];
  if (file_exists(backup_filename) == 0)
    return -1;
  database_directory(directory);
  sprintf(command, "tar -C %s -zxpf %s", directory, backup_filename);
  system(command);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<database_restore>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <file_exists@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  je     L8
  mov    %rsp,%r13
  lea    0x400(%rsp),%rbp
  mov    %r13,%rdi
  call   <database_directory@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    $0x1,%eax
L8:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: tar -C %s -zxpf %s

assistant: ```c
int database_restore(char backup_filename[]) {
  char directory[1024];
  char command[1024];
  if (file_exists(backup_filename) == 0)
    return -1;
  database_directory(directory);
  sprintf(command, "tar -C %s -zxpf %s", directory, backup_filename);
  system(command);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sqliteStrCompare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L8
  mov    $0x1,%eax
  jmp    L15
L8:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
L15:
  leave
  ret
```

assistant: ```c
int sqliteStrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return strncmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqliteStrCompare>:
  endbr64
  mov    %esi,%r8d
  mov    $0x1,%eax
  cmp    %ecx,%esi
  je     L8
  ret
L8:
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %r8d,%edx
  call   <strncmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sqliteStrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return strncmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sqliteStrCompare>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  cmp    %ecx,%r8d
  je     L1
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L1:
  mov    %r8d,%edx
  jmp    1050 <strncmp@plt>
```

assistant: ```c
int sqliteStrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return strncmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sqliteStrCompare>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  cmp    %ecx,%r8d
  je     L1
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L1:
  mov    %r8d,%edx
  jmp    1050 <strncmp@plt>
```

assistant: ```c
int sqliteStrCompare(const void *pKey1, int n1, const void *pKey2, int n2) {
  if (n1 != n2)
    return 1;
  return strncmp((const char *)pKey1, (const char *)pKey2, n1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convert_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    $0x0,%eax
  jmp    L6
L2:
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int convert_num(char *str, long long int *num) {
  *num = strtoll(str, &str, 10);
  if (*str) {
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_num>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  lea    0x8(%rsp),%rsi
  mov    $0xa,%edx
  call   <strtoll@plt>
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  cmpb   $0x0,(%rax)
  sete   %al
  movzbl %al,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int convert_num(char *str, long long int *num) {
  *num = strtoll(str, &str, 10);
  if (*str) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert_num>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  lea    0x8(%rsp),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strtoll@plt>
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  cmpb   $0x0,(%rax)
  sete   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int convert_num(char *str, long long int *num) {
  *num = strtoll(str, &str, 10);
  if (*str) {
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_num>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  lea    0x8(%rsp),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strtoll@plt>
  mov    %rax,(%rbx)
  mov    0x8(%rsp),%rax
  cmpb   $0x0,(%rax)
  sete   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int convert_num(char *str, long long int *num) {
  *num = strtoll(str, &str, 10);
  if (*str) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x100,-0x4(%rbp)
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cmp    $0x1ff,%eax
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: a = %d


assistant: ```c
int main() {
  int a;
  a = 256;
  while (a++ < 512)
    printf("a = %d\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x101,%ebx
  lea    D7(%rip),%rbp
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x201,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: a = %d


assistant: ```c
int main() {
  int a;
  a = 256;
  while (a++ < 512)
    printf("a = %d\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x101,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x201,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: a = %d


assistant: ```c
int main() {
  int a;
  a = 256;
  while (a++ < 512)
    printf("a = %d\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x101,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x201,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: a = %d


assistant: ```c
int main() {
  int a;
  a = 256;
  while (a++ < 512)
    printf("a = %d\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<OPENSSL_gmtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L12
L4:
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
struct tm *OPENSSL_gmtime(const time_t *timer, struct tm *result) {
  struct tm *ts = NULL;
  ts = gmtime(timer);
  if (ts == NULL)
    return NULL;
  memcpy(result, ts, sizeof(struct tm));
  ts = result;
  return ts;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OPENSSL_gmtime>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <gmtime@plt>
  test   %rax,%rax
  je     L0
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
L0:
  pop    %rbx
  ret
```

assistant: ```c
struct tm *OPENSSL_gmtime(const time_t *timer, struct tm *result) {
  struct tm *ts = NULL;
  ts = gmtime(timer);
  if (ts == NULL)
    return NULL;
  memcpy(result, ts, sizeof(struct tm));
  ts = result;
  return ts;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<OPENSSL_gmtime>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <gmtime@plt>
  test   %rax,%rax
  je     L4
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
L4:
  pop    %rbx
  ret
```

assistant: ```c
struct tm *OPENSSL_gmtime(const time_t *timer, struct tm *result) {
  struct tm *ts = NULL;
  ts = gmtime(timer);
  if (ts == NULL)
    return NULL;
  memcpy(result, ts, sizeof(struct tm));
  ts = result;
  return ts;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<OPENSSL_gmtime>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <gmtime@plt>
  test   %rax,%rax
  je     L2
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
L2:
  pop    %rbx
  ret
```

assistant: ```c
struct tm *OPENSSL_gmtime(const time_t *timer, struct tm *result) {
  struct tm *ts = NULL;
  ts = gmtime(timer);
  if (ts == NULL)
    return NULL;
  memcpy(result, ts, sizeof(struct tm));
  ts = result;
  return ts;
}
```