user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<charset_readWordsBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <numberOfStrings@plt>
  mov    D13(%rip),%edx
  cmp    %edx,%eax
  jg     L63
  mov    $0x0,%eax
  jmp    L42
L63:
  movl   $0x0,-0x1c(%rbp)
  jmp    L56
L32:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L69
  mov    -0x48(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L45
L69:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x48(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L45:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    D13(%rip),%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %rax,%rsi
  call   <indexedWordFromAlphabet@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  movslq %eax,%rcx
  mov    -0x40(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L19
  mov    D13(%rip),%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <numberOfStrings@plt>
  cmp    %eax,%ebx
  jl     L32
L19:
  mov    D13(%rip),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D9(%rip)
  mov    -0x1c(%rbp),%eax
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int charset_readWordsBlock(int block_size, char *alphabet, int minlength, int maxlength, char *words, int *words_init, int *words_length) {
  char *buffer;
  static int count = 0;
  int i;
  if (count >= numberOfStrings(strlen(alphabet), minlength, maxlength))
    return 0;
  for (i = 0; i < block_size && count + i < numberOfStrings(strlen(alphabet), minlength, maxlength); i++) {
    if (i == 0)
      words_init[0] = 0;
    else
      words_init[i] = words_init[i - 1] + words_length[i - 1];
    buffer = indexedWordFromAlphabet(i + count, alphabet, strlen(alphabet), minlength, maxlength);
    words_length[i] = strlen(buffer);
    memcpy(words + words_init[i], buffer, strlen(buffer));
    words[words_init[i] + strlen(buffer)] = '\0';
  }
  count += i;
  return i;
}
```