user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D38(%rip),%r15
  push   %r14
  push   %r13
  lea    D70(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  call   <adainit@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
L63:
  mov    %r14,%rdi
  call   <retrieve_continuation_parameters@plt>
  mov    %r14,%rdi
  call   <write_continuation_parameters@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  test   %esi,%esi
  jg     L24
L43:
  xor    %eax,%eax
  call   <adafinal@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  lea    0x18(%rsp),%rbx
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  mov    %r14,%rdi
  movsd  0x18(%rsp),%xmm0
  lea    0x13(%rsp),%rbp
  lea    D54(%rip),%r12
  sub    $0x1,%eax
  cltq
  movsd  %xmm0,0x20(%rsp,%rax,8)
  call   <set_continuation_parameters@plt>
  movb   $0x79,0x13(%rsp)
  jmp    L38
L33:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  mov    %rbx,%rsi
  call   <set_value_of_continuation_parameter@plt>
  cmpb   $0x0,0x13(%rsp)
  je     L25
L38:
  mov    0x14(%rsp),%edi
  mov    %rbx,%rsi
  call   <get_value_of_continuation_parameter@plt>
  movsd  0x18(%rsp),%xmm0
  mov    0x14(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpb   $0x79,0x13(%rsp)
  je     L33
L25:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jg     L63
  jmp    L43
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D70
datatype: string
name: extract_symbolic_data
arguments: tag: D34
datatype: string
name: extract_symbolic_data
arguments: tag: D55
datatype: string
name: extract_symbolic_data
arguments: tag: D36
datatype: string
name: extract_symbolic_data
arguments: tag: D54
datatype: string
name: extract_symbolic_data
arguments: tag: D69
datatype: string
name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D32
datatype: string

tool: D38: %lf

tool: D70: %d

tool: D34: 
Tuning the Continuation parameters in PHCpack...

tool: D55: Give index of parameter to change (0 to quit) : 

tool: D36: Give value for parameter %d : 

tool: D54: %c

tool: D69: -> give value for index %d : 

tool: D19: -> the value for parameter %d : %.3e.


tool: D32: -> change value of index ? (y/n) 

assistant: ```c
int main(int argc, char *argv[]) {
  int fail, i;
  double v[34], x;
  adainit();
  printf("\nTuning the Continuation parameters in PHCpack...\n");
  printf("\n");
  do {
    fail = retrieve_continuation_parameters(v);
    write_continuation_parameters(v);
    printf("Give index of parameter to change (0 to quit) : ");
    scanf("%d", &i);
    if (i > 0) {
      printf("Give value for parameter %d : ", i);
      scanf("%lf", &x);
      v[i - 1] = x;
      set_continuation_parameters(v);
      {
        char ans = 'y';
        do {
          fail = get_value_of_continuation_parameter(i, &x);
          printf("-> the value for parameter %d : %.3e.\n", i, x);
          printf("-> change value of index ? (y/n) ");
          scanf("%d", &ans);
          scanf("%c", &ans);
          if (ans != 'y')
            break;
          scanf("%c", &ans);
          printf("-> give value for index %d : ", i);
          scanf("%lf", &x);
          fail = set_value_of_continuation_parameter(i, &x);
        } while (ans != 0);
      }
    }
  } while (i > 0);
  adafinal();
  return 0;
}
```