user: 请从给定的汇编指令推导出C源代码：

```asm
<print_output>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %esi,%r13d
  mov    %edi,%esi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edi,%ebx
  lea    D65(%rip),%rdi
  call   <printf@plt>
  cmp    $0xe0f,%ebx
  setg   %al
  cmp    $0x1,%r13d
  jle    L167
  test   %al,%al
  jne    L89
L167:
  cmp    $0x1,%r13d
  jne    L2
  test   %al,%al
  je     L2
  mov    $0x1,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  test   %r13d,%r13d
  setg   %al
  test   %ebp,%ebp
  setg   %r14b
  test   %r12d,%r12d
  jle    L129
  test   %al,%al
  je     L4
  test   %ebp,%ebp
  je     L25
  lea    D100(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  cmp    $0x3b,%ebx
  setg   %r13b
  cmp    $0x1,%r12d
  jle    L222
  test   %r13b,%r13b
  jne    L190
L222:
  cmp    $0x1,%r12d
  jne    L74
  test   %r13b,%r13b
  je     L151
  mov    $0x1,%esi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L74:
  test   %r13b,%r13b
  je     L151
  test   %r14b,%r14b
  jne    L32
L151:
  test   %ebx,%ebx
  setg   %al
  cmp    $0x1,%ebp
  jle    L188
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  test   %al,%al
  jne    L150
L188:
  cmp    $0x1,%ebp
  jne    L49
  test   %al,%al
  je     L49
  mov    $0x1,%esi
  lea    D91(%rip),%rdi
L150:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L32:
  lea    D92(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L151
  nopl   0x0(%rax,%rax,1)
L89:
  mov    %r13d,%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L190:
  mov    %r12d,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L74
  cs nopw 0x0(%rax,%rax,1)
L49:
  pop    %rbx
  lea    D107(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L129:
  test   %al,%al
  je     L4
  test   %r14b,%r14b
  je     L4
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L25:
  lea    D81(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_tag: D65
type_guessed: string
name: retrieve_data
arguments: data_tag: D56
type_guessed: string
name: retrieve_data
arguments: data_tag: D100
type_guessed: string
name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D91
type_guessed: string
name: retrieve_data
arguments: data_tag: D92
type_guessed: string
name: retrieve_data
arguments: data_tag: D45
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D107
type_guessed: string
name: retrieve_data
arguments: data_tag: D81
type_guessed: string

tool: D65: 
%d seconds is 

tool: D56: %d hour

tool: D100: , 

tool: D41: %d minute 

tool: D35: %d seconds 



tool: D91: %d second 



tool: D92: and 

tool: D45: %d hours

tool: D28: %d minutes 

tool: D107: 


tool: D81:  and 

assistant: ```c
void print_output(int time, int hour, int minute, int second) {
  printf("\n%d seconds is ", time);
  if (time >= 3600 && hour > 1)
    printf("%d hours", hour);
  else if (time >= 3600 && hour == 1)
    printf("%d hour", hour);
  if (minute >= 1 && hour >= 1 && second == 0)
    printf(" and ");
  else if (minute >= 1 && hour >= 1)
    printf(", ");
  else if (second >= 1 && hour >= 1)
    printf(" ");
  if (time >= 60 && minute > 1)
    printf("%d minutes ", minute);
  else if (time >= 60 && minute == 1)
    printf("%d minute ", minute);
  if (second >= 1 && time >= 60)
    printf("and ");
  if (time >= 1 && second > 1)
    printf("%d seconds \n\n", second);
  else if (time >= 1 && second == 1)
    printf("%d second \n\n", second);
  else
    printf("\n\n");
}
```