ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<long_asc>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rcx
  movslq %esi,%rax
  movb   $0x0,(%rdi,%rax,1)
  cmp    $0x9,%rdx
  jle    L17
  lea    -0x1(%rsi),%esi
  movslq %esi,%rsi
  movabs $0x6666666666666667,%r10
L35:
  mov    %esi,%r8d
  mov    %rcx,%rax
  imul   %r10
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%r9
  add    %r9,%r9
  mov    %rcx,%rax
  sub    %r9,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  sub    $0x1,%rsi
  cmp    $0x63,%rax
  jg     L35
L17:
  lea    -0x1(%r8),%edx
  movslq %edx,%rax
  add    %rdi,%rax
  add    $0x30,%ecx
  mov    %cl,(%rax)
  test   %edx,%edx
  je     L5
  movslq %r8d,%rdx
  lea    -0x2(%rdi,%rdx,1),%rdx
  lea    -0x2(%r8),%ecx
  sub    %rcx,%rdx
L10:
  movb   $0x20,-0x1(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L5:
  ret
```

assistant: ```c
long_asc(buf, width, num) char buf[];
int width;
long num;
{
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<long_asc>:
  endbr64
  movslq %esi,%rax
  mov    %rdx,%rcx
  movb   $0x0,(%rdi,%rax,1)
  mov    %rax,%r9
  cmp    $0x9,%rdx
  jle    L10
  movabs $0xcccccccccccccccd,%r10
  lea    -0x1(%rax),%esi
  movslq %esi,%rsi
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rcx,%rax
  mov    %esi,%r9d
  mul    %r10
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r8
  add    %r8,%r8
  sub    %r8,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  sub    $0x1,%rsi
  mov    %rdx,%rcx
  cmp    $0x63,%rax
  jg     L14
L10:
  lea    -0x1(%r9),%edx
  add    $0x30,%ecx
  movslq %edx,%rax
  mov    %cl,(%rdi,%rax,1)
  test   %edx,%edx
  je     L6
  lea    -0x2(%r9),%edx
  sub    $0x1,%rax
  sub    $0x8,%rsp
  mov    $0x20,%esi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %rax,%rdi
  mov    %r8,%rdx
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
long_asc(buf, width, num) char buf[];
int width;
long num;
{
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<long_asc>:
  endbr64
  movslq %esi,%rax
  mov    %rdx,%rcx
  movb   $0x0,(%rdi,%rax,1)
  mov    %rax,%r9
  cmp    $0x9,%rdx
  jle    L8
  movabs $0xcccccccccccccccd,%r10
  lea    -0x1(%rax),%esi
  movslq %esi,%rsi
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rcx,%rax
  mov    %esi,%r9d
  mul    %r10
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r8
  add    %r8,%r8
  sub    %r8,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  sub    $0x1,%rsi
  mov    %rdx,%rcx
  cmp    $0x63,%rax
  jg     L27
L8:
  lea    -0x1(%r9),%edx
  add    $0x30,%ecx
  movslq %edx,%rax
  mov    %cl,(%rdi,%rax,1)
  test   %edx,%edx
  je     L26
  lea    -0x2(%r9),%edx
  sub    $0x1,%rax
  sub    $0x8,%rsp
  mov    $0x20,%esi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %rax,%rdi
  mov    %r8,%rdx
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L26:
  ret
```

assistant: ```c
long_asc(buf, width, num) char buf[];
int width;
long num;
{
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getlogin_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0xffffffff,%eax
  jmp    L13
L17:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: LOGNAME

assistant: ```c
int getlogin_r(char *name, size_t len) {
  char *foo = getenv("LOGNAME");
  if (!foo)
    return -1;
  strncpy(name, foo, len);
  name[len] = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getlogin_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: LOGNAME

assistant: ```c
int getlogin_r(char *name, size_t len) {
  char *foo = getenv("LOGNAME");
  if (!foo)
    return -1;
  strncpy(name, foo, len);
  name[len] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getlogin_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: LOGNAME

assistant: ```c
int getlogin_r(char *name, size_t len) {
  char *foo = getenv("LOGNAME");
  if (!foo)
    return -1;
  strncpy(name, foo, len);
  name[len] = '\0';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getlogin_r>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  xor    %eax,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: LOGNAME

assistant: ```c
int getlogin_r(char *name, size_t len) {
  char *foo = getenv("LOGNAME");
  if (!foo)
    return -1;
  strncpy(name, foo, len);
  name[len] = '\0';
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t_fun4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L0
  mov    $0x0,%edi
  call   <t_fun4>
L0:
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
void *t_fun4(void *arg) {
  int n = arg;
  if (n)
    t_fun4((void *)0);
  return (void *)n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<t_fun4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %edi,%edi
  jne    L16
L10:
  movslq %ebx,%rax
  pop    %rbx
  ret
L16:
  mov    $0x0,%edi
  call   <t_fun4>
  jmp    L10
```

assistant: ```c
void *t_fun4(void *arg) {
  int n = arg;
  if (n)
    t_fun4((void *)0);
  return (void *)n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t_fun4>:
  endbr64
  movslq %edi,%rax
  ret
```

assistant: ```c
void *t_fun4(void *arg) {
  int n = arg;
  if (n)
    t_fun4((void *)0);
  return (void *)n;
}
```
user: What is the c source code of the assembly code below:

```asm
<t_fun4>:
  endbr64
  movslq %edi,%rax
  ret
```

assistant: ```c
void *t_fun4(void *arg) {
  int n = arg;
  if (n)
    t_fun4((void *)0);
  return (void *)n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x2c(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <inputData@plt>
  mov    $0x0,%eax
  call   <selectChoice@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L19
  cmpl   $0x3,-0x14(%rbp)
  jg     L40
  cmpl   $0x1,-0x14(%rbp)
  je     L41
  cmpl   $0x2,-0x14(%rbp)
  je     L26
  jmp    L40
L41:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaLeft@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L40
L26:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaMid@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L40
L19:
  mov    -0x18(%rbp),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <findAreaRight@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  nop
L40:
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <printData@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  int coeff_a;
  int coeff_b;
  int coeff_c;
  int initial;
  int final;
  int rectNum;
  int choice;
  double area;
  inputData(&coeff_a, &coeff_b, &coeff_c, &initial, &final, &rectNum);
  choice = selectChoice();
  switch (choice) {
  case 1:
    area = findAreaLeft(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 2:
    area = findAreaMid(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 3:
    area = findAreaRight(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <inputData@plt>
  mov    $0x0,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L33
  cmp    $0x3,%eax
  je     L27
  cmp    $0x1,%eax
  je     L62
L7:
  movq   %rbx,%xmm0
  call   <printData@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L62:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaLeft@plt>
  movq   %xmm0,%rbx
  jmp    L7
L33:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaMid@plt>
  movq   %xmm0,%rbx
  jmp    L7
L27:
  mov    0x14(%rsp),%r9d
  mov    0x10(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <findAreaRight@plt>
  movq   %xmm0,%rbx
  jmp    L7
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int coeff_a;
  int coeff_b;
  int coeff_c;
  int initial;
  int final;
  int rectNum;
  int choice;
  double area;
  inputData(&coeff_a, &coeff_b, &coeff_c, &initial, &final, &rectNum);
  choice = selectChoice();
  switch (choice) {
  case 1:
    area = findAreaLeft(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 2:
    area = findAreaMid(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 3:
    area = findAreaRight(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <inputData@plt>
  xor    %eax,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L47
  cmp    $0x3,%eax
  je     L56
  cmp    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  je     L17
L51:
  call   <printData@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L47:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaMid@plt>
  jmp    L51
L17:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaLeft@plt>
  jmp    L51
L56:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaRight@plt>
  jmp    L51
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int coeff_a;
  int coeff_b;
  int coeff_c;
  int initial;
  int final;
  int rectNum;
  int choice;
  double area;
  inputData(&coeff_a, &coeff_b, &coeff_c, &initial, &final, &rectNum);
  choice = selectChoice();
  switch (choice) {
  case 1:
    area = findAreaLeft(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 2:
    area = findAreaMid(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 3:
    area = findAreaRight(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x1c(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%r9
  lea    0x20(%rsp),%r8
  call   <inputData@plt>
  xor    %eax,%eax
  call   <selectChoice@plt>
  cmp    $0x2,%eax
  je     L50
  cmp    $0x3,%eax
  je     L56
  cmp    $0x1,%eax
  movsd  0x8(%rsp),%xmm0
  je     L19
L69:
  call   <printData@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L50:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaMid@plt>
  jmp    L69
L19:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaLeft@plt>
  jmp    L69
L56:
  mov    0x24(%rsp),%r9d
  mov    0x20(%rsp),%r8d
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <findAreaRight@plt>
  jmp    L69
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int coeff_a;
  int coeff_b;
  int coeff_c;
  int initial;
  int final;
  int rectNum;
  int choice;
  double area;
  inputData(&coeff_a, &coeff_b, &coeff_c, &initial, &final, &rectNum);
  choice = selectChoice();
  switch (choice) {
  case 1:
    area = findAreaLeft(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 2:
    area = findAreaMid(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  case 3:
    area = findAreaRight(coeff_a, coeff_b, coeff_c, initial, final, rectNum);
    break;
  }
  printData(area);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<can_send_load_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x6,-0x2c(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x2c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%eax
  or     $0x80000000,%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x8,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x4,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <can_send_frame@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int can_send_load_buffer(int fd, canid_t addr, uint8_t len, uint8_t *data) {
  struct can_frame msg;
  assert(len <= 6);
  assert(len % 2 == 0);
  msg.can_id = addr | 1 << 31;
  msg.can_dlc = 8;
  msg.data[0] = 0x04;
  msg.data[1] = len / 2;
  memcpy(&msg.data[2], data, len);
  return can_send_frame(fd, &msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<can_send_load_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x6,%edx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  xor    $0x1,%edi
  and    $0x1,%edi
  call   <assert@plt>
  or     $0x80000000,%r13d
  mov    %r13d,(%rsp)
  movl   $0x8,0x4(%rsp)
  mov    0x8(%rsp),%rax
  movl   $0x4,(%rax)
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    0x8(%rsp),%rdx
  mov    %eax,0x4(%rdx)
  mov    0x8(%rsp),%rax
  lea    0x8(%rax),%rdi
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %ebp,%edi
  call   <can_send_frame@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int can_send_load_buffer(int fd, canid_t addr, uint8_t len, uint8_t *data) {
  struct can_frame msg;
  assert(len <= 6);
  assert(len % 2 == 0);
  msg.can_id = addr | 1 << 31;
  msg.can_dlc = 8;
  msg.data[0] = 0x04;
  msg.data[1] = len / 2;
  memcpy(&msg.data[2], data, len);
  return can_send_frame(fd, &msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<can_send_load_buffer>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x6,%edx
  setle  %dil
  or     $0x80000000,%ebx
  call   <assert@plt>
  mov    %r12d,%edi
  not    %edi
  and    $0x1,%edi
  call   <assert@plt>
  mov    %r12d,%eax
  mov    0x8(%rsp),%rdi
  mov    %ebx,(%rsp)
  shr    $0x1f,%eax
  movl   $0x8,0x4(%rsp)
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    %r12d,%eax
  movl   $0x4,(%rdi)
  add    $0x8,%rdi
  sar    %eax
  mov    %eax,-0x4(%rdi)
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %r13d,%edi
  call   <can_send_frame@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int can_send_load_buffer(int fd, canid_t addr, uint8_t len, uint8_t *data) {
  struct can_frame msg;
  assert(len <= 6);
  assert(len % 2 == 0);
  msg.can_id = addr | 1 << 31;
  msg.can_dlc = 8;
  msg.data[0] = 0x04;
  msg.data[1] = len / 2;
  memcpy(&msg.data[2], data, len);
  return can_send_frame(fd, &msg);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<can_send_load_buffer>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x6,%edx
  setle  %dil
  or     $0x80000000,%ebx
  call   <assert@plt>
  mov    %r12d,%edi
  not    %edi
  and    $0x1,%edi
  call   <assert@plt>
  mov    %r12d,%eax
  mov    0x8(%rsp),%rdi
  mov    %ebx,(%rsp)
  shr    $0x1f,%eax
  movl   $0x8,0x4(%rsp)
  mov    %r12d,%edx
  mov    %rbp,%rsi
  add    %r12d,%eax
  movl   $0x4,(%rdi)
  add    $0x8,%rdi
  sar    %eax
  mov    %eax,-0x4(%rdi)
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %r13d,%edi
  call   <can_send_frame@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int can_send_load_buffer(int fd, canid_t addr, uint8_t len, uint8_t *data) {
  struct can_frame msg;
  assert(len <= 6);
  assert(len % 2 == 0);
  msg.can_id = addr | 1 << 31;
  msg.can_dlc = 8;
  msg.data[0] = 0x04;
  msg.data[1] = len / 2;
  memcpy(&msg.data[2], data, len);
  return can_send_frame(fd, &msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<user2uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x38(%rbp)
  je     L14
  lea    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L20
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
L20:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <getpwnam@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L23
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  cmpq   $0x0,-0x30(%rbp)
  je     L43
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L43:
  mov    $0x0,%eax
  jmp    L21
L14:
  nop
  jmp    L37
L23:
  nop
L37:
  mov    $0xffffffff,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int user2uid(int *uid, int *gid, char *user) {
  char *tmp;
  struct passwd *pw_entry;
  if (user) {
    *uid = strtol(user, &tmp, 10);
    if ((tmp == 0) || (*tmp)) {
      pw_entry = getpwnam(user);
      if (pw_entry == 0) {
        goto error;
      }
      *uid = pw_entry->pw_uid;
      if (gid)
        *gid = pw_entry->pw_gid;
    }
    return 0;
  }
error:
  return -1;
}
```