ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quat_conjugate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  movss  D3(%rip),%xmm1
  xorps  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  D3(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  D3(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movss  0xc(%rax),%xmm0
  movss  %xmm0,(%rdx)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quat_conjugate(float *dst) {
  dst[0] = -dst[0];
  dst[1] = -dst[1];
  dst[2] = -dst[2];
  dst[3] = dst[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quat_conjugate>:
  endbr64
  movss  (%rdi),%xmm0
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quat_conjugate(float *dst) {
  dst[0] = -dst[0];
  dst[1] = -dst[1];
  dst[2] = -dst[2];
  dst[3] = dst[3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quat_conjugate>:
  endbr64
  movss  (%rdi),%xmm0
  movss  D6(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
datatype: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quat_conjugate(float *dst) {
  dst[0] = -dst[0];
  dst[1] = -dst[1];
  dst[2] = -dst[2];
  dst[3] = dst[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quat_conjugate>:
  endbr64
  movq   D14(%rip),%xmm1
  movq   (%rdi),%xmm0
  xorps  %xmm1,%xmm0
  movlps %xmm0,(%rdi)
  movss  0x8(%rdi),%xmm0
  xorps  D11(%rip),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: byte[16]

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80]}

tool: {"D11": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void quat_conjugate(float *dst) {
  dst[0] = -dst[0];
  dst[1] = -dst[1];
  dst[2] = -dst[2];
  dst[3] = dst[3];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x350,%rsp
  mov    %edi,-0x344(%rbp)
  mov    %rsi,-0x350(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x330(%rbp)
  movq   $0x0,-0x328(%rbp)
  lea    -0x320(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x62,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x330(%rbp),%rdx
  mov    -0x350(%rbp),%rcx
  mov    -0x344(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <main2@plt>
  mov    %eax,-0x334(%rbp)
  lea    -0x330(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x334(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int numArgs, const char *args[]) {
  char rs[800] = {0};
  int res = main2(numArgs, args, rs);
  printf(rs);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x338,%rsp
  mov    %edi,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x62,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  mov    %r8d,%edi
  call   <main2@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %ebx,%eax
  add    $0x338,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int numArgs, const char *args[]) {
  char rs[800] = {0};
  int res = main2(numArgs, args, rs);
  printf(rs);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  mov    $0x62,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rbp,%rdx
  rep stos %rax,%es:(%rdi)
  mov    %r8d,%edi
  call   <main2@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x338,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int numArgs, const char *args[]) {
  char rs[800] = {0};
  int res = main2(numArgs, args, rs);
  printf(rs);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %edi,%r8d
  mov    $0x62,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rbp,%rdx
  rep stos %rax,%es:(%rdi)
  mov    %r8d,%edi
  call   <main2@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x338,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int numArgs, const char *args[]) {
  char rs[800] = {0};
  int res = main2(numArgs, args, rs);
  printf(rs);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t1200_nvr_load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <t1000_emsboard_load@plt>
  mov    $0x0,%eax
  call   <t1200_state_load@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void t1200_nvr_load(void) {
  t1000_emsboard_load();
  t1200_state_load();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t1200_nvr_load>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <t1000_emsboard_load@plt>
  mov    $0x0,%eax
  call   <t1200_state_load@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void t1200_nvr_load(void) {
  t1000_emsboard_load();
  t1200_state_load();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<t1200_nvr_load>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t1000_emsboard_load@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <t1200_state_load@plt>
```

assistant: ```c
void t1200_nvr_load(void) {
  t1000_emsboard_load();
  t1200_state_load();
}
```
user: Translate the below assembly code into C programming language:

```asm
<t1200_nvr_load>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t1000_emsboard_load@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <t1200_state_load@plt>
```

assistant: ```c
void t1200_nvr_load(void) {
  t1000_emsboard_load();
  t1200_state_load();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SHA256_VST>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA256@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int SHA256_VST(unsigned char *in, unsigned char *out, unsigned long long inlen) {
  SHA256(in, inlen, out);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SHA256_VST>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdx
  call   <SHA256@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int SHA256_VST(unsigned char *in, unsigned char *out, unsigned long long inlen) {
  SHA256(in, inlen, out);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<SHA256_VST>:
  endbr64
  mov    %rsi,%r8
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %r8,%rdx
  call   <SHA256@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int SHA256_VST(unsigned char *in, unsigned char *out, unsigned long long inlen) {
  SHA256(in, inlen, out);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHA256_VST>:
  endbr64
  mov    %rsi,%r8
  sub    $0x8,%rsp
  mov    %rdx,%rsi
  mov    %r8,%rdx
  call   <SHA256@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int SHA256_VST(unsigned char *in, unsigned char *out, unsigned long long inlen) {
  SHA256(in, inlen, out);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x24(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D23(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jle    L0
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    -0x20(%rbp),%rax
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x18(%rbp)
  movb   $0x31,-0x10(%rbp)
  movb   $0x0,-0xf(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D2: 3

tool: D23: %d

tool: D17: got %d


assistant: ```c
int main() {
  int num;
  char *dup, *c;
  char buf[8];
  dup = strdup("3");
  if (sscanf(dup, "%d", &num) > 0)
    printf("got %d\n", num);
  c = strrchr(dup, 'x');
  c = strchr(dup, 'x');
  c = (char *)memchr(dup, 'x', 2);
  buf[0] = '1';
  buf[1] = '\0';
  strcat(buf, dup);
  num = strlen(dup);
  free(dup);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  lea    0xc(%rsp),%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jg     L11
L23:
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    $0x2,%edx
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <memchr@plt>
  movb   $0x31,0x10(%rsp)
  movb   $0x0,0x11(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  mov    0xc(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string

tool: D12: 3

tool: D25: %d

tool: D20: got %d


assistant: ```c
int main() {
  int num;
  char *dup, *c;
  char buf[8];
  dup = strdup("3");
  if (sscanf(dup, "%d", &num) > 0)
    printf("got %d\n", num);
  c = strrchr(dup, 'x');
  c = strchr(dup, 'x');
  c = (char *)memchr(dup, 'x', 2);
  buf[0] = '1';
  buf[1] = '\0';
  strcat(buf, dup);
  num = strlen(dup);
  free(dup);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  lea    0xc(%rsp),%rdx
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sscanf@plt>
  test   %rax,%rax
  jle    L4
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
L4:
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    $0x2,%edx
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  mov    $0x31,%eax
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ax,0x10(%rsp)
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string
name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D5: 3

tool: D11: %d

tool: D8: got %d


assistant: ```c
int main() {
  int num;
  char *dup, *c;
  char buf[8];
  dup = strdup("3");
  if (sscanf(dup, "%d", &num) > 0)
    printf("got %d\n", num);
  c = strrchr(dup, 'x');
  c = strchr(dup, 'x');
  c = (char *)memchr(dup, 'x', 2);
  buf[0] = '1';
  buf[1] = '\0';
  strcat(buf, dup);
  num = strlen(dup);
  free(dup);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  lea    0xc(%rsp),%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <sscanf@plt>
  test   %rax,%rax
  jle    L14
  mov    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L14:
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    $0x2,%edx
  mov    $0x78,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  mov    $0x31,%eax
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ax,0x10(%rsp)
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D5
type: string

tool: D3: 3

tool: D25: %d

tool: D5: got %d


assistant: ```c
int main() {
  int num;
  char *dup, *c;
  char buf[8];
  dup = strdup("3");
  if (sscanf(dup, "%d", &num) > 0)
    printf("got %d\n", num);
  c = strrchr(dup, 'x');
  c = strchr(dup, 'x');
  c = (char *)memchr(dup, 'x', 2);
  buf[0] = '1';
  buf[1] = '\0';
  strcat(buf, dup);
  num = strlen(dup);
  free(dup);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x80,%edi
  call   <emalloc@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x80,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L18:
  mov    -0x10(%rbp),%rax
  sub    $0x2,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L4
  shlq   -0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L18
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *load(FILE *fin) {
  enum { DEFAULT_TEXTSIZE = BUFSIZ };
  char *text = emalloc(DEFAULT_TEXTSIZE);
  size_t bufsize = DEFAULT_TEXTSIZE;
  size_t i;
  int c;
  for (i = 0; (c = fgetc(fin)) != EOF; ++i) {
    if (bufsize - 2 <= i) {
      bufsize *= 2;
      text = realloc(text, bufsize);
    }
    text[i] = c;
  }
  text[i] = '\0';
  return text;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    $0x80,%edi
  call   <emalloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  mov    $0x80,%r13d
  jmp    L2
L0:
  mov    %bl,(%r12,%rbp,1)
  add    $0x1,%rbp
L2:
  mov    %r14,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  je     L1
  lea    -0x2(%r13),%rax
  cmp    %rbp,%rax
  ja     L0
  add    %r13,%r13
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  jmp    L0
L1:
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *load(FILE *fin) {
  enum { DEFAULT_TEXTSIZE = BUFSIZ };
  char *text = emalloc(DEFAULT_TEXTSIZE);
  size_t bufsize = DEFAULT_TEXTSIZE;
  size_t i;
  int c;
  for (i = 0; (c = fgetc(fin)) != EOF; ++i) {
    if (bufsize - 2 <= i) {
      bufsize *= 2;
      text = realloc(text, bufsize);
    }
    text[i] = c;
  }
  text[i] = '\0';
  return text;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<load>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x80,%edi
  push   %r12
  mov    $0x80,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <emalloc@plt>
  mov    D3(%rip),%r14
  mov    %rax,%r15
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %bl,(%r15,%rbp,1)
  add    $0x1,%rbp
L37:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  je     L39
  lea    -0x2(%r12),%rax
  cmp    %rbp,%rax
  ja     L13
  add    %r12,%r12
  mov    %r15,%rdi
  mov    %r12,%rsi
  call   <realloc@plt>
  mov    %rax,%r15
  jmp    L13
  nopl   0x0(%rax)
L39:
  movb   $0x0,(%r15,%rbp,1)
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *load(FILE *fin) {
  enum { DEFAULT_TEXTSIZE = BUFSIZ };
  char *text = emalloc(DEFAULT_TEXTSIZE);
  size_t bufsize = DEFAULT_TEXTSIZE;
  size_t i;
  int c;
  for (i = 0; (c = fgetc(fin)) != EOF; ++i) {
    if (bufsize - 2 <= i) {
      bufsize *= 2;
      text = realloc(text, bufsize);
    }
    text[i] = c;
  }
  text[i] = '\0';
  return text;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x80,%edi
  push   %r12
  mov    $0x80,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <emalloc@plt>
  mov    D3(%rip),%r14
  mov    %rax,%r15
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %bl,(%r15,%rbp,1)
  add    $0x1,%rbp
L28:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  je     L8
  lea    -0x2(%r12),%rax
  cmp    %rbp,%rax
  ja     L12
  add    %r12,%r12
  mov    %r15,%rdi
  mov    %r12,%rsi
  call   <realloc@plt>
  mov    %rax,%r15
  jmp    L12
  nopl   0x0(%rax)
L8:
  movb   $0x0,(%r15,%rbp,1)
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *load(FILE *fin) {
  enum { DEFAULT_TEXTSIZE = BUFSIZ };
  char *text = emalloc(DEFAULT_TEXTSIZE);
  size_t bufsize = DEFAULT_TEXTSIZE;
  size_t i;
  int c;
  for (i = 0; (c = fgetc(fin)) != EOF; ++i) {
    if (bufsize - 2 <= i) {
      bufsize *= 2;
      text = realloc(text, bufsize);
    }
    text[i] = c;
  }
  text[i] = '\0';
  return text;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L18:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0x5(%rbp),%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x2f,-0x5(%rbp)
  jle    L2
  cmpb   $0x39,-0x5(%rbp)
  jle    L18
L2:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gn(char *cp) {
  int val = 0;
  char d;
  while ('0' <= (d = *cp++) && d <= '9') {
    val = val * 10 + (d - '0');
  }
  return (val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gn>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L20
  mov    $0x0,%edx
L26:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L26
L15:
  mov    %edx,%eax
  ret
L20:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int gn(char *cp) {
  int val = 0;
  char d;
  while ('0' <= (d = *cp++) && d <= '9') {
    val = val * 10 + (d - '0');
  }
  return (val);
}
```
user: What is the c source code of the assembly code below?

```asm
<gn>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L4
  cs nopw 0x0(%rax,%rax,1)
L9:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  movsbl %al,%eax
  lea    (%rax,%rcx,2),%r8d
  movzbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L9
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gn(char *cp) {
  int val = 0;
  char d;
  while ('0' <= (d = *cp++) && d <= '9') {
    val = val * 10 + (d - '0');
  }
  return (val);
}
```
user: What is the c source code of the assembly code below:

```asm
<gn>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L0
  cs nopw 0x0(%rax,%rax,1)
L12:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  movsbl %al,%eax
  lea    (%rax,%rcx,2),%r8d
  movzbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L12
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gn(char *cp) {
  int val = 0;
  char d;
  while ('0' <= (d = *cp++) && d <= '9') {
    val = val * 10 + (d - '0');
  }
  return (val);
}
```