ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_servsock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    D31(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L24
  lea    0xc(%rsp),%rbp
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0x10(%rsp)
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebx
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xffffffff,%ebx
  jmp    L24
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_servsock(int port) {
  int sd = socket(AF_INET, SOCK_STREAM, 0);
  if (sd == -1)
    return -1;
  struct sockaddr_in bindaddr;
  memset(&bindaddr, 0, sizeof(bindaddr));
  bindaddr.sin_family = AF_INET;
  bindaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  bindaddr.sin_port = htons(port);
  if (bind(sd, (struct sockaddr *)&bindaddr, sizeof(bindaddr)) != 0)
    return -1;
  if (listen(sd, 0) != 0)
    return -1;
  return sd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<create_servsock>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D24(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L10
  lea    0xc(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0x14(%rsp)
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %r13d,%edi
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %rax,%rax
  jne    L10
  xor    %esi,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %rax,%rax
  jne    L10
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    $0xffffffff,%r12d
  jmp    L35
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_servsock(int port) {
  int sd = socket(AF_INET, SOCK_STREAM, 0);
  if (sd == -1)
    return -1;
  struct sockaddr_in bindaddr;
  memset(&bindaddr, 0, sizeof(bindaddr));
  bindaddr.sin_family = AF_INET;
  bindaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  bindaddr.sin_port = htons(port);
  if (bind(sd, (struct sockaddr *)&bindaddr, sizeof(bindaddr)) != 0)
    return -1;
  if (listen(sd, 0) != 0)
    return -1;
  return sd;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<create_servsock>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D1(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L14
  lea    0xc(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %eax,0x14(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %r13d,%edi
  mov    %eax,0x10(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %rax,%rax
  jne    L14
  xor    %esi,%esi
  mov    %r12d,%edi
  call   <listen@plt>
  test   %rax,%rax
  jne    L14
L26:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0xffffffff,%r12d
  jmp    L26
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int create_servsock(int port) {
  int sd = socket(AF_INET, SOCK_STREAM, 0);
  if (sd == -1)
    return -1;
  struct sockaddr_in bindaddr;
  memset(&bindaddr, 0, sizeof(bindaddr));
  bindaddr.sin_family = AF_INET;
  bindaddr.sin_addr.s_addr = htonl(INADDR_ANY);
  bindaddr.sin_port = htons(port);
  if (bind(sd, (struct sockaddr *)&bindaddr, sizeof(bindaddr)) != 0)
    return -1;
  if (listen(sd, 0) != 0)
    return -1;
  return sd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int Int;
  int Calloc;
  int floaitng;
  int ReInitialize;
  int Xx;
  int _1312;
  int _;
  int alpha_beta_routine;
  int z;
  int A$;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int Int;
  int Calloc;
  int floaitng;
  int ReInitialize;
  int Xx;
  int _1312;
  int _;
  int alpha_beta_routine;
  int z;
  int A$;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int Int;
  int Calloc;
  int floaitng;
  int ReInitialize;
  int Xx;
  int _1312;
  int _;
  int alpha_beta_routine;
  int z;
  int A$;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int Int;
  int Calloc;
  int floaitng;
  int ReInitialize;
  int Xx;
  int _1312;
  int _;
  int alpha_beta_routine;
  int z;
  int A$;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_profile_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <powerpc405_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _profile_init(void) {
  int i;
  powerpc405_init();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_profile_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <powerpc405_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _profile_init(void) {
  int i;
  powerpc405_init();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_profile_init>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <powerpc405_init@plt>
```

assistant: ```c
void _profile_init(void) {
  int i;
  powerpc405_init();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_profile_init>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <powerpc405_init@plt>
```

assistant: ```c
void _profile_init(void) {
  int i;
  powerpc405_init();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L16:
  cmpl   $0x1,-0x4(%rbp)
  jne    L18
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c = (getchar() != EOF);
  while (c != 1) {
    putchar(c);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    (%rdx),%rax
  setne  %bl
  movzbl %bl,%ebx
  jne    L2
L1:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L1
L2:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int c = (getchar() != EOF);
  while (c != 1) {
    putchar(c);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L3
  setne  %bl
  movzbl %bl,%ebx
  xchg   %ax,%ax
L9:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L9
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int c = (getchar() != EOF);
  while (c != 1) {
    putchar(c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D8(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L6
  setne  %bl
  movzbl %bl,%ebx
  xchg   %ax,%ax
L3:
  mov    %ebx,%edi
  call   <putchar@plt>
  jmp    L3
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int c = (getchar() != EOF);
  while (c != 1) {
    putchar(c);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  je     L39
  cmp    $0x3,%eax
  jg     L22
  cmp    $0x1,%eax
  je     L23
  cmp    $0x2,%eax
  je     L61
  jmp    L22
L23:
  mov    $0x0,%eax
  call   <source@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L44
L61:
  mov    $0x0,%eax
  call   <e_n@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L44
L39:
  mov    $0x0,%eax
  call   <i_areas@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L44
L22:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L44:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D47
data_type: string
name: retrieve_data
arguments: data_label: D62
data_type: string
name: retrieve_data
arguments: data_label: D55
data_type: string
name: retrieve_data
arguments: data_label: D9
data_type: string
name: retrieve_data
arguments: data_label: D27
data_type: string
name: retrieve_data
arguments: data_label: D36
data_type: string

tool: D21: Choose method to calculate cyclomatic Complexity: 

tool: D47: 	1.Using source code.
	

tool: D62: 2.Using number of edges and nodes.
	

tool: D55: 3.Using number of independent areas.


tool: D9: %d

tool: D27: Error

tool: D36: The cyclomatic Complexity is %d


assistant: ```c
int main() {
  int c, cc = 0;
  printf("Choose method to calculate cyclomatic Complexity: \n");
  printf("\t1.Using source code.\n\t");
  printf("2.Using number of edges and nodes.\n\t");
  printf("3.Using number of independent areas.\n\n");
  scanf("%d", &c);
  switch (c) {
  case 1:
    cc = source();
    break;
  case 2:
    cc = e_n();
    break;
  case 3:
    cc = i_areas();
    break;
  default:
    printf("Error");
    break;
  }
  printf("The cyclomatic Complexity is %d\n", cc);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D66(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L15
  cmp    $0x3,%eax
  je     L46
  cmp    $0x1,%eax
  je     L18
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  jmp    L53
L18:
  mov    $0x0,%eax
  call   <source@plt>
  mov    %eax,%esi
L53:
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L15:
  mov    $0x0,%eax
  call   <e_n@plt>
  mov    %eax,%esi
  jmp    L53
L46:
  mov    $0x0,%eax
  call   <i_areas@plt>
  mov    %eax,%esi
  jmp    L53
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D66
datatype: string
name: unpack_data
arguments: data_label: D57
datatype: string
name: unpack_data
arguments: data_label: D42
datatype: string
name: unpack_data
arguments: data_label: D52
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D45
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string

tool: D66: Choose method to calculate cyclomatic Complexity: 

tool: D57: 	1.Using source code.
	

tool: D42: 2.Using number of edges and nodes.
	

tool: D52: 3.Using number of independent areas.


tool: D2: %d

tool: D45: Error

tool: D21: The cyclomatic Complexity is %d


assistant: ```c
int main() {
  int c, cc = 0;
  printf("Choose method to calculate cyclomatic Complexity: \n");
  printf("\t1.Using source code.\n\t");
  printf("2.Using number of edges and nodes.\n\t");
  printf("3.Using number of independent areas.\n\n");
  scanf("%d", &c);
  switch (c) {
  case 1:
    cc = source();
    break;
  case 2:
    cc = e_n();
    break;
  case 3:
    cc = i_areas();
    break;
  default:
    printf("Error");
    break;
  }
  printf("The cyclomatic Complexity is %d\n", cc);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D61(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L5
  cmp    $0x3,%eax
  je     L0
  cmp    $0x1,%eax
  je     L7
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
L21:
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  xor    %eax,%eax
  call   <e_n@plt>
  mov    %eax,%esi
  jmp    L21
L7:
  xor    %eax,%eax
  call   <source@plt>
  mov    %eax,%esi
  jmp    L21
L0:
  xor    %eax,%eax
  call   <i_areas@plt>
  mov    %eax,%esi
  jmp    L21
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D61
type_guessed: string
name: extract_symbolic_data
arguments: label: D55
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D38
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D34
type_guessed: string

tool: D61: Choose method to calculate cyclomatic Complexity: 

tool: D55: 	1.Using source code.
	

tool: D10: 2.Using number of edges and nodes.
	

tool: D13: 3.Using number of independent areas.


tool: D38: %d

tool: D19: Error

tool: D34: The cyclomatic Complexity is %d


assistant: ```c
int main() {
  int c, cc = 0;
  printf("Choose method to calculate cyclomatic Complexity: \n");
  printf("\t1.Using source code.\n\t");
  printf("2.Using number of edges and nodes.\n\t");
  printf("3.Using number of independent areas.\n\n");
  scanf("%d", &c);
  switch (c) {
  case 1:
    cc = source();
    break;
  case 2:
    cc = e_n();
    break;
  case 3:
    cc = i_areas();
    break;
  default:
    printf("Error");
    break;
  }
  printf("The cyclomatic Complexity is %d\n", cc);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L23
  cmp    $0x3,%eax
  je     L26
  cmp    $0x1,%eax
  je     L30
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
L8:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  xor    %eax,%eax
  call   <e_n@plt>
  mov    %eax,%esi
  jmp    L8
L30:
  xor    %eax,%eax
  call   <source@plt>
  mov    %eax,%esi
  jmp    L8
L26:
  xor    %eax,%eax
  call   <i_areas@plt>
  mov    %eax,%esi
  jmp    L8
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
datatype: string
name: disassemble_data
arguments: data_label: D55
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: string
name: disassemble_data
arguments: data_label: D56
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D14: Choose method to calculate cyclomatic Complexity: 

tool: D55: 	1.Using source code.
	

tool: D9: 2.Using number of edges and nodes.
	

tool: D56: 3.Using number of independent areas.


tool: D18: %d

tool: D5: Error

tool: D17: The cyclomatic Complexity is %d


assistant: ```c
int main() {
  int c, cc = 0;
  printf("Choose method to calculate cyclomatic Complexity: \n");
  printf("\t1.Using source code.\n\t");
  printf("2.Using number of edges and nodes.\n\t");
  printf("3.Using number of independent areas.\n\n");
  scanf("%d", &c);
  switch (c) {
  case 1:
    cc = source();
    break;
  case 2:
    cc = e_n();
    break;
  case 3:
    cc = i_areas();
    break;
  default:
    printf("Error");
    break;
  }
  printf("The cyclomatic Complexity is %d\n", cc);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ironlake_debug_rawclk_freq>:
  endbr64
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  mov    %ecx,%eax
  and    $0x3000,%eax
  lea    D89(%rip),%rcx
  cmp    $0x2000,%eax
  je     L73
  jg     L70
  lea    D20(%rip),%rcx
  test   %eax,%eax
  je     L73
  cmp    $0x1000,%eax
  lea    D13(%rip),%rax
  mov    $0x0,%edx
  cmove  %rax,%rdx
  mov    %rdx,%rcx
L73:
  mov    %r9d,%eax
  and    $0xc00,%eax
  lea    D41(%rip),%r8
  cmp    $0x800,%eax
  je     L64
  jg     L66
  lea    D36(%rip),%r8
  test   %eax,%eax
  je     L64
  cmp    $0x400,%eax
  lea    D33(%rip),%r8
  mov    $0x0,%eax
  cmovne %rax,%r8
L64:
  and    $0x3ff,%r9d
  lea    D22(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  ret
L70:
  cmp    $0x3000,%eax
  lea    D75(%rip),%rax
  mov    $0x0,%edx
  mov    %rdx,%rcx
  cmove  %rax,%rcx
  jmp    L73
L66:
  cmp    $0xc00,%eax
  lea    D74(%rip),%r8
  mov    $0x0,%eax
  cmovne %rax,%r8
  jmp    L64
```

tool_calls: name: retrieve_data
arguments: tag: D89
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D41
type_guessed: string
name: retrieve_data
arguments: tag: D36
type_guessed: string
name: retrieve_data
arguments: tag: D33
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D75
type_guessed: string
name: retrieve_data
arguments: tag: D74
type_guessed: string

tool: D89: 2.0us

tool: D20: 0.5us

tool: D13: 1.0us

tool: D41: 6.0us

tool: D36: 1.5us

tool: D33: 3.0us

tool: D22: FDL_TP1 timer %s, FDL_TP2 timer %s, freq %d

tool: D75: 4.0us

tool: D74: 12.0us

assistant: ```c
void ironlake_debug_rawclk_freq(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  const char *tp1 = NULL, *tp2 = NULL;
  switch (val & (3 << 12)) {
  case 0:
    tp1 = "0.5us";
    break;
  case (1 << 12):
    tp1 = "1.0us";
    break;
  case (2 << 12):
    tp1 = "2.0us";
    break;
  case (3 << 12):
    tp1 = "4.0us";
    break;
  }
  switch (val & (3 << 10)) {
  case 0:
    tp2 = "1.5us";
    break;
  case (1 << 10):
    tp2 = "3.0us";
    break;
  case (2 << 10):
    tp2 = "6.0us";
    break;
  case (3 << 10):
    tp2 = "12.0us";
    break;
  }
  snprintf(result, len, "FDL_TP1 timer %s, FDL_TP2 timer %s, freq %d", tp1, tp2, val & 0x3ff);
}
```
user: What is the c source code of the assembly code below:

```asm
<ironlake_debug_rawclk_freq>:
  endbr64
  mov    %ecx,%eax
  mov    %ecx,%r9d
  lea    D32(%rip),%rcx
  and    $0x3000,%eax
  cmp    $0x2000,%eax
  je     L62
  jg     L38
  lea    D62(%rip),%rcx
  test   %eax,%eax
  je     L62
  cmp    $0x1000,%eax
  mov    $0x0,%edx
  lea    D88(%rip),%rax
  cmove  %rax,%rdx
  mov    %rdx,%rcx
L62:
  mov    %r9d,%eax
  lea    D81(%rip),%r8
  and    $0xc00,%eax
  cmp    $0x800,%eax
  je     L49
  jg     L36
  lea    D41(%rip),%r8
  test   %eax,%eax
  je     L49
  cmp    $0x400,%eax
  lea    D25(%rip),%r8
  mov    $0x0,%eax
  cmovne %rax,%r8
L49:
  and    $0x3ff,%r9d
  lea    D63(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax)
L38:
  cmp    $0x3000,%eax
  mov    $0x0,%ecx
  lea    D30(%rip),%rax
  cmove  %rax,%rcx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    $0xc00,%eax
  lea    D87(%rip),%r8
  mov    $0x0,%eax
  cmovne %rax,%r8
  jmp    L49
```

tool_calls: name: read_data
arguments: label: D32
type_guessed: string
name: read_data
arguments: label: D62
type_guessed: string
name: read_data
arguments: label: D88
type_guessed: string
name: read_data
arguments: label: D81
type_guessed: string
name: read_data
arguments: label: D41
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D63
type_guessed: string
name: read_data
arguments: label: D30
type_guessed: string
name: read_data
arguments: label: D87
type_guessed: string

tool: D32: 2.0us

tool: D62: 0.5us

tool: D88: 1.0us

tool: D81: 6.0us

tool: D41: 1.5us

tool: D25: 3.0us

tool: D63: FDL_TP1 timer %s, FDL_TP2 timer %s, freq %d

tool: D30: 4.0us

tool: D87: 12.0us

assistant: ```c
void ironlake_debug_rawclk_freq(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  const char *tp1 = NULL, *tp2 = NULL;
  switch (val & (3 << 12)) {
  case 0:
    tp1 = "0.5us";
    break;
  case (1 << 12):
    tp1 = "1.0us";
    break;
  case (2 << 12):
    tp1 = "2.0us";
    break;
  case (3 << 12):
    tp1 = "4.0us";
    break;
  }
  switch (val & (3 << 10)) {
  case 0:
    tp2 = "1.5us";
    break;
  case (1 << 10):
    tp2 = "3.0us";
    break;
  case (2 << 10):
    tp2 = "6.0us";
    break;
  case (3 << 10):
    tp2 = "12.0us";
    break;
  }
  snprintf(result, len, "FDL_TP1 timer %s, FDL_TP2 timer %s, freq %d", tp1, tp2, val & 0x3ff);
}
```