ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<repeat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L1:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: %c

assistant: ```c
void repeat(char symbol, int times) {
  for (int i = 0; i < times; i++) {
    printf("%c", symbol);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<repeat>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edi,%r12d
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L6:
  movsbl %r12b,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: %c

assistant: ```c
void repeat(char symbol, int times) {
  for (int i = 0; i < times; i++) {
    printf("%c", symbol);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<repeat>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: %c

assistant: ```c
void repeat(char symbol, int times) {
  for (int i = 0; i < times; i++) {
    printf("%c", symbol);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<repeat>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L0:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: %c

assistant: ```c
void repeat(char symbol, int times) {
  for (int i = 0; i < times; i++) {
    printf("%c", symbol);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quicly_encode_max_streams_frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  mov    $0x13,%ecx
  jmp    L9
L1:
  mov    $0x12,%ecx
L9:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,(%rax)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ptls_encode_quicint@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint8_t *quicly_encode_max_streams_frame(uint8_t *dst, int uni, uint64_t count) {
  *dst++ = uni ? 19 : 18;
  dst = ptls_encode_quicint(dst, count);
  return dst;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quicly_encode_max_streams_frame>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  mov    %edx,%esi
  cmp    $0x1,%eax
  mov    $0x12,%eax
  sbb    $0xffffffff,%eax
  lea    0x4(%rdi),%rdx
  mov    %eax,(%rdi)
  mov    %rdx,%rdi
  call   <ptls_encode_quicint@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t *quicly_encode_max_streams_frame(uint8_t *dst, int uni, uint64_t count) {
  *dst++ = uni ? 19 : 18;
  dst = ptls_encode_quicint(dst, count);
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quicly_encode_max_streams_frame>:
  endbr64
  mov    %esi,%r8d
  mov    $0x12,%eax
  mov    %edx,%esi
  cmp    $0x1,%r8d
  lea    0x4(%rdi),%r8
  sbb    $0xffffffff,%eax
  mov    %eax,(%rdi)
  mov    %r8,%rdi
  jmp    1050 <ptls_encode_quicint@plt>
```

assistant: ```c
uint8_t *quicly_encode_max_streams_frame(uint8_t *dst, int uni, uint64_t count) {
  *dst++ = uni ? 19 : 18;
  dst = ptls_encode_quicint(dst, count);
  return dst;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quicly_encode_max_streams_frame>:
  endbr64
  mov    %esi,%r8d
  mov    $0x12,%eax
  mov    %edx,%esi
  cmp    $0x1,%r8d
  lea    0x4(%rdi),%r8
  sbb    $0xffffffff,%eax
  mov    %eax,(%rdi)
  mov    %r8,%rdi
  jmp    1050 <ptls_encode_quicint@plt>
```

assistant: ```c
uint8_t *quicly_encode_max_streams_frame(uint8_t *dst, int uni, uint64_t count) {
  *dst++ = uni ? 19 : 18;
  dst = ptls_encode_quicint(dst, count);
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<log_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L12
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L12:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xd8(%rbp)
  lea    -0xd0(%rbp),%rdx
  lea    -0xd8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  mov    -0xbc(%rbp),%ecx
  mov    -0xc0(%rbp),%r8d
  mov    -0xc4(%rbp),%edi
  mov    -0xc8(%rbp),%eax
  mov    -0xcc(%rbp),%edx
  add    $0x1,%edx
  mov    -0xd0(%rbp),%esi
  add    $0x76c,%esi
  sub    $0x8,%rsp
  push   %rcx
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%ecx
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    -0xe8(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xd4(%rbp),%edx
  mov    -0xe8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xd4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: [%04d/%02d/%02d-%02d:%02d:%02d] 

assistant: ```c
void log_msg(const char *fmt, ...) {
  time_t t;
  struct tm tm;
  va_list ap;
  t = time(NULL);
  localtime_r(&t, &tm);
  printf("[%04d/%02d/%02d-%02d:%02d:%02d] ", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log_msg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  call   <localtime_r@plt>
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%edx
  mov    0x10(%rsp),%eax
  lea    0x76c(%rax),%esi
  sub    $0x8,%rsp
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%r9d
  mov    0x2c(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: [%04d/%02d/%02d-%02d:%02d:%02d] 

assistant: ```c
void log_msg(const char *fmt, ...) {
  time_t t;
  struct tm tm;
  va_list ap;
  t = time(NULL);
  localtime_r(&t, &tm);
  printf("[%04d/%02d/%02d-%02d:%02d:%02d] ", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<log_msg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime_r@plt>
  mov    0x14(%rsp),%eax
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  lea    0x1(%rax),%edx
  mov    0x18(%rsp),%eax
  lea    0x76c(%rax),%esi
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%r9d
  mov    0x2c(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: [%04d/%02d/%02d-%02d:%02d:%02d] 

assistant: ```c
void log_msg(const char *fmt, ...) {
  time_t t;
  struct tm tm;
  va_list ap;
  t = time(NULL);
  localtime_r(&t, &tm);
  printf("[%04d/%02d/%02d-%02d:%02d:%02d] ", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below:

```asm
<log_msg>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <localtime_r@plt>
  mov    0x14(%rsp),%eax
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  lea    0x1(%rax),%edx
  mov    0x18(%rsp),%eax
  lea    0x76c(%rax),%esi
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%r9d
  mov    0x2c(%rsp),%r8d
  mov    0x28(%rsp),%ecx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: [%04d/%02d/%02d-%02d:%02d:%02d] 

assistant: ```c
void log_msg(const char *fmt, ...) {
  time_t t;
  struct tm tm;
  va_list ap;
  t = time(NULL);
  localtime_r(&t, &tm);
  printf("[%04d/%02d/%02d-%02d:%02d:%02d] ", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec);
  va_start(ap, fmt);
  vprintf(fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  sub    $0x44,%eax
  cmp    $0x33,%eax
  ja     L12
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D90(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D90(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
L12:
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L69:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D81
type: string
name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D68
type: string
name: disassemble_data
arguments: data_tag: D71
type: string
name: disassemble_data
arguments: data_tag: D32
type: string
name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D78
type: string

tool: D81: Please input marriage status
(S=single, M=married, W=widowed, E=separated, D=divorced):

tool: D6: %c

tool: D28: You are Single.

tool: D68: You are Married.

tool: D71: You are Widdowed.

tool: D32: You are Separated.

tool: D27: You are Divorced

tool: D78: Invalid input.

assistant: ```c
main() {
  char stat;
  printf("Please input marriage status\n(S=single, M=married, W=widowed, E=separated, D=divorced):");
  scanf("%c", &stat);
  switch (stat) {
  case 'S':
  case 's':
    printf("You are Single.");
    break;
  case 'M':
  case 'm':
    printf("You are Married.");
    break;
  case 'W':
  case 'w':
    printf("You are Widdowed.");
    break;
  case 'E':
  case 'e':
    printf("You are Separated.");
    break;
  case 'D':
  case 'd':
    printf("You are Divorced");
    break;
  default:
    printf("Invalid input.");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L31
  movzbl %al,%eax
  lea    D15(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D42(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L11
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L11
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L11
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L31:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D42
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D79
type_infered: string
name: parse_data
arguments: label: D64
type_infered: string

tool: D3: Please input marriage status
(S=single, M=married, W=widowed, E=separated, D=divorced):

tool: D20: %c

tool: D42: You are Single.

tool: D23: You are Married.

tool: D16: You are Widdowed.

tool: D7: You are Separated.

tool: D79: You are Divorced

tool: D64: Invalid input.

assistant: ```c
main() {
  char stat;
  printf("Please input marriage status\n(S=single, M=married, W=widowed, E=separated, D=divorced):");
  scanf("%c", &stat);
  switch (stat) {
  case 'S':
  case 's':
    printf("You are Single.");
    break;
  case 'M':
  case 'm':
    printf("You are Married.");
    break;
  case 'W':
  case 'w':
    printf("You are Widdowed.");
    break;
  case 'E':
  case 'e':
    printf("You are Separated.");
    break;
  case 'D':
  case 'd':
    printf("You are Divorced");
    break;
  default:
    printf("Invalid input.");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L67
  lea    D61(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L67:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L66
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L66
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L66
  lea    D55(%rip),%rdi
  call   <printf@plt>
  jmp    L66
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type: string
name: read_data
arguments: tag: D54
type: string
name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D24
type: string
name: read_data
arguments: tag: D84
type: string
name: read_data
arguments: tag: D28
type: string
name: read_data
arguments: tag: D55
type: string
name: read_data
arguments: tag: D35
type: string

tool: D16: Please input marriage status
(S=single, M=married, W=widowed, E=separated, D=divorced):

tool: D54: %c

tool: D45: Invalid input.

tool: D24: You are Divorced

tool: D84: You are Separated.

tool: D28: You are Married.

tool: D55: You are Single.

tool: D35: You are Widdowed.

assistant: ```c
main() {
  char stat;
  printf("Please input marriage status\n(S=single, M=married, W=widowed, E=separated, D=divorced):");
  scanf("%c", &stat);
  switch (stat) {
  case 'S':
  case 's':
    printf("You are Single.");
    break;
  case 'M':
  case 'm':
    printf("You are Married.");
    break;
  case 'W':
  case 'w':
    printf("You are Widdowed.");
    break;
  case 'E':
  case 'e':
    printf("You are Separated.");
    break;
  case 'D':
  case 'd':
    printf("You are Divorced");
    break;
  default:
    printf("Invalid input.");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D40(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L66
  lea    D64(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L66:
  lea    D84(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L67
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L67
  lea    D89(%rip),%rdi
  call   <printf@plt>
  jmp    L67
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L67
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D40
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string
name: disassemble_data
arguments: tag: D84
type_infered: string
name: disassemble_data
arguments: tag: D87
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D89
type_infered: string
name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D23
type_infered: string

tool: D40: Please input marriage status
(S=single, M=married, W=widowed, E=separated, D=divorced):

tool: D14: %c

tool: D84: Invalid input.

tool: D87: You are Divorced

tool: D21: You are Separated.

tool: D89: You are Married.

tool: D56: You are Single.

tool: D23: You are Widdowed.

assistant: ```c
main() {
  char stat;
  printf("Please input marriage status\n(S=single, M=married, W=widowed, E=separated, D=divorced):");
  scanf("%c", &stat);
  switch (stat) {
  case 'S':
  case 's':
    printf("You are Single.");
    break;
  case 'M':
  case 'm':
    printf("You are Married.");
    break;
  case 'W':
  case 'w':
    printf("You are Widdowed.");
    break;
  case 'E':
  case 'e':
    printf("You are Separated.");
    break;
  case 'D':
  case 'd':
    printf("You are Divorced");
    break;
  default:
    printf("Invalid input.");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZBarcode_Encode_File_and_Buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ZBarcode_Encode_File@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  jmp    L0
L13:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ZBarcode_Buffer@plt>
L0:
  leave
  ret
```

assistant: ```c
int ZBarcode_Encode_File_and_Buffer(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  error_number = 0;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number != 0) {
    return error_number;
  }
  return ZBarcode_Buffer(symbol, rotate_angle);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ZBarcode_Encode_File_and_Buffer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  call   <ZBarcode_Encode_File@plt>
  test   %eax,%eax
  je     L6
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <ZBarcode_Buffer@plt>
  jmp    L10
```

assistant: ```c
int ZBarcode_Encode_File_and_Buffer(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  error_number = 0;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number != 0) {
    return error_number;
  }
  return ZBarcode_Buffer(symbol, rotate_angle);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ZBarcode_Encode_File_and_Buffer>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ZBarcode_Encode_File@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <ZBarcode_Buffer@plt>
```

assistant: ```c
int ZBarcode_Encode_File_and_Buffer(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  error_number = 0;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number != 0) {
    return error_number;
  }
  return ZBarcode_Buffer(symbol, rotate_angle);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ZBarcode_Encode_File_and_Buffer>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <ZBarcode_Encode_File@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <ZBarcode_Buffer@plt>
```

assistant: ```c
int ZBarcode_Encode_File_and_Buffer(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  error_number = 0;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number != 0) {
    return error_number;
  }
  return ZBarcode_Buffer(symbol, rotate_angle);
}
```