ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_json_util_allocStringByInteger>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  movl   $0xffffffff,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x14,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x4,0x24(%rsp)
  movl   $0x64,0x28(%rsp)
  mov    $0x1,%ebx
  lea    0x8(%rsp),%r12
  lea    D40(%rip),%r13
  lea    D44(%rip),%r14
  jmp    L4
L27:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  je     L19
L4:
  mov    0xc(%rsp,%rbx,4),%ebp
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <json_util_allocStringByInteger@plt>
  test   %rax,%rax
  jne    L27
  mov    0x8(%rsp),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  jmp    L8
L19:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D49
datatype: string
name: disassemble_data
arguments: label: D40
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D9: Test json_util_allocStringByInteger

tool: D49: ================================================================================

tool: D40: %d. %s


tool: D44: allocate string by integer (%d) failure


tool: D0: ================================================================================


assistant: ```c
void test_json_util_allocStringByInteger() {
  puts("Test json_util_allocStringByInteger");
  puts("================================================================================");
  const int a[] = {-1, 0, 1, 20, 3, 4, 100};
  int i;
  for (i = 0; i < 7; i++) {
    char *string;
    if (json_util_allocStringByInteger(a[i], &string) != 0) {
      printf("allocate string by integer (%d) failure\n", a[i]);
      continue;
    }
    printf("%d. %s\n", i + 1, string);
    free(string);
  }
  puts("================================================================================\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_json_util_allocStringByInteger>:
  endbr64
  push   %r14
  lea    D44(%rip),%rdi
  lea    D21(%rip),%r14
  push   %r13
  lea    D47(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0xffffffff,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  movl   $0x64,0x28(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x1400000001,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x20(%rsp)
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0x8(%rsp),%rdx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  cmp    $0x7,%rbx
  je     L28
L34:
  mov    0x10(%rsp,%rbx,4),%ebp
  add    $0x1,%rbx
L14:
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <json_util_allocStringByInteger@plt>
  mov    %ebx,%esi
  test   %rax,%rax
  je     L5
  xor    %eax,%eax
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L34
L28:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  lea    D36(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <puts@plt>
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D44
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D47
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D36
data_type: string

tool: D44: Test json_util_allocStringByInteger

tool: D21: allocate string by integer (%d) failure


tool: D47: %d. %s


tool: D27: ================================================================================

tool: D36: ================================================================================


assistant: ```c
void test_json_util_allocStringByInteger() {
  puts("Test json_util_allocStringByInteger");
  puts("================================================================================");
  const int a[] = {-1, 0, 1, 20, 3, 4, 100};
  int i;
  for (i = 0; i < 7; i++) {
    char *string;
    if (json_util_allocStringByInteger(a[i], &string) != 0) {
      printf("allocate string by integer (%d) failure\n", a[i]);
      continue;
    }
    printf("%d. %s\n", i + 1, string);
    free(string);
  }
  puts("================================================================================\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_json_util_allocStringByInteger>:
  endbr64
  push   %r15
  lea    D60(%rip),%rdi
  lea    D34(%rip),%r15
  push   %r14
  lea    D43(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    D17(%rip),%rax
  movdqa D42(%rip),%xmm0
  movl   $0x64,0x28(%rsp)
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L26:
  mov    -0x4(%r13,%rbx,4),%ebp
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <json_util_allocStringByInteger@plt>
  mov    %ebx,%esi
  test   %rax,%rax
  jne    L47
  mov    0x8(%rsp),%rdx
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  cmp    $0x8,%rbx
  jne    L26
L13:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x48,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x8,%rbx
  jne    L26
  jmp    L13
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D60
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string
name: parse_data
arguments: data_label: D43
type_guessed: string
name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: byte[8]
name: parse_data
arguments: data_label: D42
type_guessed: byte[16]
name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D60: Test json_util_allocStringByInteger

tool: D34: allocate string by integer (%d) failure


tool: D43: %d. %s


tool: D8: ================================================================================

tool: {"D17": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D42": [0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: D4: ================================================================================


assistant: ```c
void test_json_util_allocStringByInteger() {
  puts("Test json_util_allocStringByInteger");
  puts("================================================================================");
  const int a[] = {-1, 0, 1, 20, 3, 4, 100};
  int i;
  for (i = 0; i < 7; i++) {
    char *string;
    if (json_util_allocStringByInteger(a[i], &string) != 0) {
      printf("allocate string by integer (%d) failure\n", a[i]);
      continue;
    }
    printf("%d. %s\n", i + 1, string);
    free(string);
  }
  puts("================================================================================\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<USBEndpointDMAChannel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x2,%eax
  mov    $0xf,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x450,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  not    %rax
  and    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  or     %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x450,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBEndpointDMAChannel(unsigned long ulBase, unsigned long ulEndpoint, unsigned long ulChannel) {
  unsigned long ulMask;
  ;

  ;
  ;
  ulMask = 0xf << (ulChannel * 4);
  ulMask = (*((volatile unsigned long *)(ulBase + 0x00000450))) & (~ulMask);
  ulMask |= (((ulEndpoint) >> 4)) << (ulChannel * 4);
  (*((volatile unsigned long *)(ulBase + 0x00000450))) = ulMask;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBEndpointDMAChannel>:
  endbr64
  lea    0x0(,%rdx,4),%ecx
  mov    0x450(%rdi),%rdx
  mov    $0xf,%eax
  shl    %cl,%eax
  cltq
  not    %rax
  and    %rdx,%rax
  shr    $0x4,%rsi
  shl    %cl,%rsi
  or     %rax,%rsi
  mov    %rsi,0x450(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(unsigned long ulBase, unsigned long ulEndpoint, unsigned long ulChannel) {
  unsigned long ulMask;
  ;

  ;
  ;
  ulMask = 0xf << (ulChannel * 4);
  ulMask = (*((volatile unsigned long *)(ulBase + 0x00000450))) & (~ulMask);
  ulMask |= (((ulEndpoint) >> 4)) << (ulChannel * 4);
  (*((volatile unsigned long *)(ulBase + 0x00000450))) = ulMask;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBEndpointDMAChannel>:
  endbr64
  lea    0x0(,%rdx,4),%ecx
  mov    $0xf,%eax
  shr    $0x4,%rsi
  mov    0x450(%rdi),%rdx
  shl    %cl,%eax
  shl    %cl,%rsi
  cltq
  not    %rax
  and    %rdx,%rax
  or     %rax,%rsi
  mov    %rsi,0x450(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(unsigned long ulBase, unsigned long ulEndpoint, unsigned long ulChannel) {
  unsigned long ulMask;
  ;

  ;
  ;
  ulMask = 0xf << (ulChannel * 4);
  ulMask = (*((volatile unsigned long *)(ulBase + 0x00000450))) & (~ulMask);
  ulMask |= (((ulEndpoint) >> 4)) << (ulChannel * 4);
  (*((volatile unsigned long *)(ulBase + 0x00000450))) = ulMask;
}
```
user: What is the c source code of the assembly code below?

```asm
<USBEndpointDMAChannel>:
  endbr64
  lea    0x0(,%rdx,4),%ecx
  mov    $0xf,%eax
  shr    $0x4,%rsi
  mov    0x450(%rdi),%rdx
  shl    %cl,%eax
  shl    %cl,%rsi
  cltq
  not    %rax
  and    %rdx,%rax
  or     %rax,%rsi
  mov    %rsi,0x450(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(unsigned long ulBase, unsigned long ulEndpoint, unsigned long ulChannel) {
  unsigned long ulMask;
  ;

  ;
  ;
  ulMask = 0xf << (ulChannel * 4);
  ulMask = (*((volatile unsigned long *)(ulBase + 0x00000450))) & (~ulMask);
  ulMask |= (((ulEndpoint) >> 4)) << (ulChannel * 4);
  (*((volatile unsigned long *)(ulBase + 0x00000450))) = ulMask;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lexPermute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L42
L21:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L10
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L48:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L89
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L30
L89:
  subl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L48
L30:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L96
L54:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L96:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L54
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lexPermute>
  jmp    L15
L10:
  subl   $0x1,-0x14(%rbp)
L42:
  cmpl   $0x0,-0x14(%rbp)
  jns    L21
  nop
L15:
  leave
  ret
```

assistant: ```c
void lexPermute(int p[], int pSize) {
  int i, k, j, g, h, temp;
  for (i = pSize - 2; i >= 0; i--) {
    if (p[i] < p[i + 1]) {
      for (k = pSize - 1; k > i; k--) {
        if (p[k] > p[i]) {
          j = k;
          break;
        }
      }
      swap(&p[i], &p[j]);
      g = i + 1;
      h = pSize - 1;
      while (g < h) {
        swap(&p[g], &p[h]);
        g++;
        h--;
      }
      printArray(p, pSize);
      lexPermute(p, pSize);
      return;
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lexPermute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  sub    $0x2,%ebx
  js     L0
  mov    %rdi,%r12
  mov    %esi,%ebp
  movslq %ebx,%rax
  lea    (%rdi,%rax,4),%rax
L66:
  mov    %rax,%rdi
  mov    (%rax),%edx
  cmp    0x4(%rax),%edx
  jl     L63
  sub    $0x1,%ebx
  sub    $0x4,%rax
  cmp    $0xffffffff,%ebx
  jne    L66
  jmp    L0
L63:
  lea    -0x1(%rbp),%r13d
  cmp    %ebx,%r13d
  jle    L46
  movslq %r13d,%rax
L82:
  mov    %eax,%ecx
  cmp    (%r12,%rax,4),%edx
  jl     L46
  sub    $0x1,%rax
  cmp    %eax,%ebx
  jl     L82
L46:
  movslq %ecx,%rcx
  lea    (%r12,%rcx,4),%rsi
  call   <swap@plt>
  lea    0x1(%rbx),%r14d
  cmp    %r14d,%r13d
  jle    L40
  movslq %r14d,%rax
  lea    (%r12,%rax,4),%r13
  movslq %ebp,%rax
  movslq %ebx,%rdx
  add    %rdx,%rax
  lea    (%r12,%rax,2),%r15
  add    %r15,%r15
L29:
  mov    %r15,%rsi
  sub    %r13,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  add    $0x1,%r14d
  add    $0x4,%r13
  mov    %ebp,%eax
  sub    %r14d,%eax
  add    %ebx,%eax
  cmp    %eax,%r14d
  jl     L29
L40:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printArray@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <lexPermute>
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void lexPermute(int p[], int pSize) {
  int i, k, j, g, h, temp;
  for (i = pSize - 2; i >= 0; i--) {
    if (p[i] < p[i + 1]) {
      for (k = pSize - 1; k > i; k--) {
        if (p[k] > p[i]) {
          j = k;
          break;
        }
      }
      swap(&p[i], &p[j]);
      g = i + 1;
      h = pSize - 1;
      while (g < h) {
        swap(&p[g], &p[h]);
        g++;
        h--;
      }
      printArray(p, pSize);
      lexPermute(p, pSize);
      return;
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lexPermute>:
  endbr64
  push   %r15
  lea    -0x2(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x38,%rsp
  mov    %eax,(%rsp)
  cltq
  mov    (%rsp),%r15d
  lea    (%rdi,%rax,4),%rax
  mov    %rdi,0x28(%rsp)
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0x4(%rsp)
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  movslq %esi,%rax
  mov    %rax,0x20(%rsp)
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  test   %r15d,%r15d
  js     L64
L45:
  mov    0x8(%rsp),%rdi
  jmp    L61
  nopl   0x0(%rax)
L104:
  sub    $0x1,%r15d
  sub    $0x4,%rdi
  cmp    $0xffffffff,%r15d
  je     L64
L61:
  mov    (%rdi),%eax
  cmp    0x4(%rdi),%eax
  jge    L104
  cmp    %r15d,0x4(%rsp)
  jle    L42
  mov    (%rsp),%esi
  mov    0x18(%rsp),%rdx
  sub    %r15d,%esi
  lea    -0x8(%rdx),%rcx
  shl    $0x2,%rsi
  sub    %rsi,%rcx
  mov    0x10(%rsp),%rsi
  jmp    L62
  nopl   0x0(%rax)
L48:
  sub    $0x4,%rsi
  cmp    %rcx,%rsi
  je     L42
L62:
  cmp    (%rsi),%eax
  jge    L48
L115:
  call   <swap@plt>
  lea    0x1(%r15),%r13d
  cmp    %r13d,0x4(%rsp)
  jle    L99
  movslq %r13d,%rax
  lea    (%r12,%rax,4),%r14
  movslq %r15d,%rax
  add    0x20(%rsp),%rax
  lea    (%r12,%rax,2),%rbp
  add    %rbp,%rbp
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%r13d
  sub    %r14,%rsi
  add    $0x4,%r14
  call   <swap@plt>
  mov    %ebx,%eax
  sub    %r13d,%eax
  add    %r15d,%eax
  cmp    %r13d,%eax
  jg     L41
L99:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printArray@plt>
  mov    (%rsp),%r15d
  test   %r15d,%r15d
  jns    L45
L64:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L42:
  mov    0x28(%rsp),%rsi
  jmp    L115
```

assistant: ```c
void lexPermute(int p[], int pSize) {
  int i, k, j, g, h, temp;
  for (i = pSize - 2; i >= 0; i--) {
    if (p[i] < p[i + 1]) {
      for (k = pSize - 1; k > i; k--) {
        if (p[k] > p[i]) {
          j = k;
          break;
        }
      }
      swap(&p[i], &p[j]);
      g = i + 1;
      h = pSize - 1;
      while (g < h) {
        swap(&p[g], &p[h]);
        g++;
        h--;
      }
      printArray(p, pSize);
      lexPermute(p, pSize);
      return;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lexPermute>:
  endbr64
  push   %r15
  movslq %esi,%rdx
  push   %r14
  lea    -0x2(%rdx),%eax
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %eax,0x8(%rsp)
  cltq
  mov    0x8(%rsp),%r14d
  lea    (%rdi,%rax,4),%rax
  mov    %rdx,0x20(%rsp)
  lea    (%rdi,%rdx,4),%rdx
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbx),%eax
  mov    %eax,0xc(%rsp)
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    %rdx,(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rdi,0x28(%rsp)
  test   %r14d,%r14d
  js     L54
L84:
  mov    (%rsp),%rax
  mov    0x10(%rsp),%rdi
  mov    -0x4(%rax),%eax
  jmp    L94
  nopl   (%rax)
L18:
  sub    $0x1,%r14d
  sub    $0x4,%rdi
  cmp    $0xffffffff,%r14d
  je     L54
L94:
  mov    %eax,%ecx
  mov    (%rdi),%eax
  cmp    %ecx,%eax
  jge    L18
  cmp    %r14d,0xc(%rsp)
  jle    L7
  mov    0x8(%rsp),%esi
  mov    (%rsp),%rdx
  sub    %r14d,%esi
  lea    -0x8(%rdx),%rcx
  shl    $0x2,%rsi
  sub    %rsi,%rcx
  mov    0x18(%rsp),%rsi
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L23:
  sub    $0x4,%rsi
  cmp    %rsi,%rcx
  je     L7
L78:
  cmp    (%rsi),%eax
  jge    L23
L11:
  call   <swap@plt>
  lea    0x1(%r14),%r13d
  cmp    %r13d,0xc(%rsp)
  jle    L82
  movslq %r13d,%rax
  lea    (%r12,%rax,4),%r15
  movslq %r14d,%rax
  add    0x20(%rsp),%rax
  lea    (%r12,%rax,2),%rbp
  add    %rbp,%rbp
  nopl   0x0(%rax,%rax,1)
L105:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  add    $0x1,%r13d
  sub    %r15,%rsi
  add    $0x4,%r15
  call   <swap@plt>
  mov    %ebx,%eax
  sub    %r13d,%eax
  add    %r14d,%eax
  cmp    %eax,%r13d
  jl     L105
L82:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printArray@plt>
  mov    0x8(%rsp),%r14d
  test   %r14d,%r14d
  jns    L84
L54:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x28(%rsp),%rsi
  jmp    L11
```

assistant: ```c
void lexPermute(int p[], int pSize) {
  int i, k, j, g, h, temp;
  for (i = pSize - 2; i >= 0; i--) {
    if (p[i] < p[i + 1]) {
      for (k = pSize - 1; k > i; k--) {
        if (p[k] > p[i]) {
          j = k;
          break;
        }
      }
      swap(&p[i], &p[j]);
      g = i + 1;
      h = pSize - 1;
      while (g < h) {
        swap(&p[g], &p[h]);
        g++;
        h--;
      }
      printArray(p, pSize);
      lexPermute(p, pSize);
      return;
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L53
  cmpq   $0x0,-0x28(%rbp)
  je     L53
  cmpl   $0x0,-0x14(%rbp)
  jns    L26
L53:
  mov    $0x1,%eax
  jmp    L33
L26:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L47:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L47
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
int mean(int size, int *values, double *result) {
  int i;
  int sum;
  if ((values == NULL) || (result == NULL) || (size < 0)) {
    return 1;
  }
  sum = 0;
  for (i = 0; i < size; i++) {
    sum += values[i];
  }
  *result = ((double)sum) / size;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mean>:
  endbr64
  test   %rdx,%rdx
  sete   %al
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  or     %cl,%al
  jne    L20
  test   %rsi,%rsi
  je     L20
  test   %edi,%edi
  jle    L43
  mov    %rsi,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x4(%rsi,%rcx,4),%rsi
  mov    $0x0,%ecx
L28:
  add    (%rax),%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L28
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  mov    $0x0,%eax
  ret
L43:
  mov    $0x0,%ecx
  jmp    L5
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int mean(int size, int *values, double *result) {
  int i;
  int sum;
  if ((values == NULL) || (result == NULL) || (size < 0)) {
    return 1;
  }
  sum = 0;
  for (i = 0; i < size; i++) {
    sum += values[i];
  }
  *result = ((double)sum) / size;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mean>:
  endbr64
  test   %rdx,%rdx
  mov    %edi,%ecx
  sete   %al
  shr    $0x1f,%ecx
  or     %cl,%al
  jne    L46
  test   %rsi,%rsi
  je     L46
  test   %edi,%edi
  je     L6
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    (%rsi),%eax
  add    $0x4,%rsi
  cmp    %rcx,%rsi
  jne    L25
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L41:
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  jmp    L41
```

assistant: ```c
int mean(int size, int *values, double *result) {
  int i;
  int sum;
  if ((values == NULL) || (result == NULL) || (size < 0)) {
    return 1;
  }
  sum = 0;
  for (i = 0; i < size; i++) {
    sum += values[i];
  }
  *result = ((double)sum) / size;
  return 0;
}
```