ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<i_u_conv>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbp
  movl   $0x0,(%rdi)
  mov    %rdx,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
  mov    $0x0,%r13d
  jmp    L37
L21:
  mov    %rbp,%rdi
  call   <jelio_buffer_getc@plt>
  add    $0x1,%r13d
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
L37:
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L21
  mov    $0x0,%r14d
  jmp    L34
L19:
  add    $0x1,%r14d
  mov    %rbp,%rdi
  call   <jelio_buffer_getc@plt>
  mov    (%r12),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,(%r12)
L34:
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%ebx
  lea    -0x30(%rax),%eax
  cmp    $0x9,%eax
  jbe    L19
  add    %r14d,%r13d
  test   %r14d,%r14d
  cmovne %r13d,%r14d
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int i_u_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  unsigned int *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i_u_conv>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  movl   $0x0,(%rdi)
  mov    %rdx,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <jelio_buffer_getc@plt>
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
L38:
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L17
  xor    %r14d,%r14d
  jmp    L4
  nopl   (%rax)
L16:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <jelio_buffer_getc@plt>
  mov    0x0(%r13),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,0x0(%r13)
L4:
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%ebx
  lea    -0x30(%rax),%eax
  cmp    $0x9,%eax
  jbe    L16
  add    %r14d,%r12d
  test   %r14d,%r14d
  pop    %rbx
  pop    %rbp
  cmovne %r12d,%r14d
  pop    %r12
  pop    %r13
  mov    %r14d,%eax
  pop    %r14
  ret
```

assistant: ```c
int i_u_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  unsigned int *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<i_u_conv>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  movl   $0x0,(%rdi)
  mov    %rdx,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <jelio_buffer_getc@plt>
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%edi
L6:
  call   <char_isspace@plt>
  test   %rax,%rax
  jne    L35
  xor    %r14d,%r14d
  jmp    L5
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <jelio_buffer_getc@plt>
  mov    0x0(%r13),%eax
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rbx,%rax,2),%eax
  mov    %eax,0x0(%r13)
L5:
  mov    %rbp,%rdi
  call   <jelio_buffer_peekc@plt>
  mov    %eax,%ebx
  lea    -0x30(%rax),%eax
  cmp    $0x9,%eax
  jbe    L4
  add    %r14d,%r12d
  test   %r14d,%r14d
  pop    %rbx
  pop    %rbp
  cmovne %r12d,%r14d
  pop    %r12
  pop    %r13
  mov    %r14d,%eax
  pop    %r14
  ret
```

assistant: ```c
int i_u_conv(void *value, int n, void *inbuf) {
  struct jelio_buf *jb = inbuf;
  unsigned int *ival = value;
  int c, count = 0, wcount = 0;
  *ival = 0;
  for (c = jelio_buffer_peekc(jb); char_isspace(c); c = jelio_buffer_peekc(jb)) {
    jelio_buffer_getc(jb);
    wcount++;
  }
  while (1) {
    c = jelio_buffer_peekc(jb);
    if (c < '0' || c > '9')
      break;
    count++;
    jelio_buffer_getc(jb);
    *ival *= 10;
    *ival += c - '0';
  }
  if (!count)
    return 0;
  return count + wcount;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L11:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double distance(double x[], double y[], int n) {
  int i;
  double t = 0;
  for (i = 0; i < n; i++)
    t += ((x[i] - y[i]) * (x[i] - y[i]));
  return (sqrt(t));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<distance>:
  endbr64
  test   %edx,%edx
  jle    L16
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L21:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
L33:
  sqrtsd %xmm0,%xmm0
  ret
L16:
  pxor   %xmm0,%xmm0
  jmp    L33
L7:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double distance(double x[], double y[], int n) {
  int i;
  double t = 0;
  for (i = 0; i < n; i++)
    t += ((x[i] - y[i]) * (x[i] - y[i]));
  return (sqrt(t));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<distance>:
  endbr64
  test   %edx,%edx
  jle    L25
  pxor   %xmm2,%xmm2
  movslq %edx,%rdx
  xor    %eax,%eax
  movapd %xmm2,%xmm0
  nopl   (%rax)
L15:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L15
  ucomisd %xmm0,%xmm2
  ja     L20
  sqrtsd %xmm0,%xmm0
  ret
  xchg   %ax,%ax
L25:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L20:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double distance(double x[], double y[], int n) {
  int i;
  double t = 0;
  for (i = 0; i < n; i++)
    t += ((x[i] - y[i]) * (x[i] - y[i]));
  return (sqrt(t));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distance>:
  endbr64
  test   %edx,%edx
  jle    L57
  cmp    $0x1,%edx
  je     L26
  mov    %edx,%ecx
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  shr    %ecx
  movapd %xmm3,%xmm0
  shl    $0x4,%rcx
  nop
L46:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  subpd  %xmm4,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L46
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L54
L10:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L54:
  ucomisd %xmm0,%xmm3
  ja     L32
  sqrtsd %xmm0,%xmm0
  ret
L57:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L26:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L10
L32:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double distance(double x[], double y[], int n) {
  int i;
  double t = 0;
  for (i = 0; i < n; i++)
    t += ((x[i] - y[i]) * (x[i] - y[i]));
  return (sqrt(t));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]
            [-v] shp_file


assistant: ```c
void Usage() {
  printf("shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]\n"
         "            [-v] shp_file\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]
            [-v] shp_file


assistant: ```c
void Usage() {
  printf("shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]\n"
         "            [-v] shp_file\n");
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]
            [-v] shp_file


assistant: ```c
void Usage() {
  printf("shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]\n"
         "            [-v] shp_file\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]
            [-v] shp_file


assistant: ```c
void Usage() {
  printf("shptreedump [-maxdepth n] [-search xmin ymin xmax ymax]\n"
         "            [-v] shp_file\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<map_parameter_landsurface>:
  endbr64
  test   %edx,%edx
  jne    L10
  cmp    $0x5,%ecx
  jle    L31
  lea    -0xc0(%rcx),%eax
  cmp    $0xf,%eax
  ja     L39
  sub    $0xc0,%ecx
  cmp    $0xf,%ecx
  ja     L13
  mov    %ecx,%ecx
  lea    D2(%rip),%rdx
  movslq (%rdx,%rcx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L31:
  test   %ecx,%ecx
  jns    L5
  mov    $0xffffffff,%eax
  ret
L5:
  cmp    $0x5,%ecx
  ja     L26
  mov    %ecx,%ecx
  lea    D18(%rip),%rdx
  movslq (%rdx,%rcx,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x53,%eax
  ret
L26:
  mov    $0xffffffff,%eax
  ret
  mov    $0x55,%eax
  ret
  mov    $0x56,%eax
  ret
  mov    $0x57,%eax
  ret
  mov    $0x5a,%eax
  ret
  cmp    $0x7,%edi
  mov    $0x90,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0x9b,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xcf,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xd0,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xdf,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xe2,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xe1,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cmp    $0x7,%edi
  mov    $0xc9,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
L10:
  mov    $0xffffffff,%eax
  ret
L13:
  mov    $0xffffffff,%eax
  ret
  mov    $0x51,%eax
  ret
L39:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int map_parameter_landsurface(int center, int disc, int param_cat, int param_num) {
  (void)(disc);
  switch (param_cat) {
  case 0:
    switch (param_num) {
    case 0:
      return 81;
    case 1:
      return 83;
    case 2:
      return 85;
    case 3:
      return 86;
    case 4:
      return 87;
    case 5:
      return 90;
    case 192:
      switch (center) {
      case 7:
        return 144;
      default:
        break;
      }
    case 193:
      switch (center) {
      case 7:
        return 155;
      default:
        break;
      }
    case 194:
      switch (center) {
      case 7:
        return 207;
      default:
        break;
      }
    case 195:
      switch (center) {
      case 7:
        return 208;
      default:
        break;
      }
    case 196:
      switch (center) {
      case 7:
        return 223;
      default:
        break;
      }
    case 197:
      switch (center) {
      case 7:
        return 226;
      default:
        break;
      }
    case 198:
      switch (center) {
      case 7:
        return 225;
      default:
        break;
      }
    case 207:
      switch (center) {
      case 7:
        return 201;
      default:
        break;
      }
    default:
      break;
    }
    break;
  default:
    break;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<countfields>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L19
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L31
  addl   $0x1,-0x8(%rbp)
L31:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x8(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int countfields(char *s) {
  int n = 1, i;
  if (s == NULL)
    return 0;
  for (i = 0; s[i] != '\0'; i++)
    if (s[i] == ' ')
      n++;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<countfields>:
  endbr64
  test   %rdi,%rdi
  je     L12
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  add    $0x1,%rdi
  mov    $0x1,%eax
L29:
  cmp    $0x20,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L29
  ret
L7:
  mov    $0x1,%eax
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int countfields(char *s) {
  int n = 1, i;
  if (s == NULL)
    return 0;
  for (i = 0; s[i] != '\0'; i++)
    if (s[i] == ' ')
      n++;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<countfields>:
  endbr64
  test   %rdi,%rdi
  je     L23
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  add    $0x1,%rdi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L0:
  cmp    $0x20,%dl
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L0
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int countfields(char *s) {
  int n = 1, i;
  if (s == NULL)
    return 0;
  for (i = 0; s[i] != '\0'; i++)
    if (s[i] == ' ')
      n++;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<countfields>:
  endbr64
  test   %rdi,%rdi
  je     L12
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  add    $0x1,%rdi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L17:
  cmp    $0x20,%dl
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int countfields(char *s) {
  int n = 1, i;
  if (s == NULL)
    return 0;
  for (i = 0; s[i] != '\0'; i++)
    if (s[i] == ' ')
      n++;
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<gw_np_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1018(%rbp)
  movl   $0x0,-0x1014(%rbp)
  movl   $0x0,-0x101c(%rbp)
  jmp    L53
L42:
  mov    -0x101c(%rbp),%eax
  cltq
  mov    -0x101c(%rbp),%edx
  mov    %edx,-0x1010(%rbp,%rax,4)
  addl   $0x1,-0x101c(%rbp)
L53:
  cmpl   $0x3ff,-0x101c(%rbp)
  jle    L42
  movl   $0x0,-0x101c(%rbp)
  jmp    L33
L31:
  mov    -0x101c(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  add    %eax,-0x1018(%rbp)
  addl   $0x1,-0x101c(%rbp)
L33:
  cmpl   $0x3ff,-0x101c(%rbp)
  jle    L31
  movl   $0x0,-0x101c(%rbp)
  jmp    L41
L30:
  mov    -0x101c(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%eax
  add    %eax,-0x1014(%rbp)
  addl   $0x1,-0x101c(%rbp)
L41:
  cmpl   $0x3ff,-0x101c(%rbp)
  jle    L30
  mov    -0x1018(%rbp),%eax
  cmp    -0x1014(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void gw_np_1() {
  int i, arr[1024], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32)
  {
#pragma acc loop gang worker reduction(+ : res)
    for (i = 0; i < 1024; i++)
      res += arr[i];
  }
  for (i = 0; i < 1024; i++)
    hres += arr[i];
  assert(res == hres);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gw_np_1>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
L32:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x400,%rax
  jne    L32
  mov    %rsp,%rax
  lea    0x1000(%rsp),%rsi
  mov    %rax,%rdx
  mov    $0x0,%ecx
L21:
  add    (%rdx),%ecx
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L21
  mov    $0x0,%edx
L4:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L4
  cmp    %ecx,%edx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x1018,%rsp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gw_np_1() {
  int i, arr[1024], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32)
  {
#pragma acc loop gang worker reduction(+ : res)
    for (i = 0; i < 1024; i++)
      res += arr[i];
  }
  for (i = 0; i < 1024; i++)
    hres += arr[i];
  assert(res == hres);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gw_np_1>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  nopl   0x0(%rax)
L14:
  mov    %edx,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x400,%rdx
  jne    L14
  lea    0x1000(%rsp),%rsi
  mov    %rax,%rdx
  xor    %edi,%edi
  nopl   (%rax)
L3:
  mov    (%rdx),%ecx
  add    $0x4,%rdx
  add    %edi,%ecx
  mov    %ecx,%edi
  cmp    %rsi,%rdx
  jne    L3
  xor    %edx,%edx
  nopl   0x0(%rax)
L33:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L33
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  xor    %edi,%edi
  cmp    %ecx,%edx
  sete   %dil
  add    $0x1018,%rsp
  jmp    1070 <assert@plt>
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void gw_np_1() {
  int i, arr[1024], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32)
  {
#pragma acc loop gang worker reduction(+ : res)
    for (i = 0; i < 1024; i++)
      res += arr[i];
  }
  for (i = 0; i < 1024; i++)
    hres += arr[i];
  assert(res == hres);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gw_np_1>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movdqa D6(%rip),%xmm0
  movdqa D3(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  mov    %rsp,%rax
  lea    0x1000(%rsp),%rcx
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L0:
  movdqa %xmm0,%xmm1
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rdx)
  cmp    %rdx,%rcx
  jne    L0
  mov    %rax,%rdx
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L22:
  paddd  (%rdx),%xmm0
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L22
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L21:
  paddd  (%rax),%xmm0
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L21
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  movdqa %xmm0,%xmm1
  xor    %edi,%edi
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%eax
  sete   %dil
  add    $0x1018,%rsp
  jmp    1070 <assert@plt>
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: byte[16]
name: disassemble_data
arguments: data_tag: D3
type_guessed: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D3": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void gw_np_1() {
  int i, arr[1024], res = 0, hres = 0;
  for (i = 0; i < 1024; i++)
    arr[i] = i;
#pragma acc parallel num_gangs(32) num_workers(32) vector_length(32)
  {
#pragma acc loop gang worker reduction(+ : res)
    for (i = 0; i < 1024; i++)
      res += arr[i];
  }
  for (i = 0; i < 1024; i++)
    hres += arr[i];
  assert(res == hres);
}
```