user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D41(%rip),%rsi
  lea    D30(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D43(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x20(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  mov    0x20(%rsp),%ecx
  test   %ecx,%ecx
  jle    L86
  lea    0x24(%rsp),%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L121:
  mov    0x18(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x24(%rsp),%edx
  mov    %rax,0x10(%rsp)
  test   %edx,%edx
  jle    L50
  mov    %rax,%r15
  mov    %r12,%r14
  xor    %r13d,%r13d
  sub    %r12,%r15
L91:
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <fscanf@plt>
  lea    (%r14,%r15,1),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%r8d
  add    $0x4,%r14
  cmp    %r13d,%r8d
  jg     L91
  test   %r8d,%r8d
  jle    L50
  mov    %r12,%r9
  mov    $0x5f5e0ff,%r14d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L72:
  lea    (%r9,%r15,1),%rsi
  mov    %r12,%rcx
  lea    0x1(%rdi),%r10d
  xor    %edx,%edx
  nopl   (%rax)
L61:
  cmp    %edx,%edi
  je     L23
  mov    (%r9),%eax
  mov    (%rsi),%r11d
  sub    (%rcx),%eax
  sub    (%rcx,%r15,1),%r11d
  imul   %eax,%eax
  imul   %r11d,%r11d
  add    %r11d,%eax
  cmp    %eax,%r14d
  cmovg  %eax,%r14d
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %r8d,%edx
  jne    L61
  mov    %r10d,%edi
  add    $0x4,%r9
  cmp    %r10d,%r8d
  jne    L72
L55:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  addl   $0x1,0xc(%rsp)
  pxor   %xmm0,%xmm0
  mov    0xc(%rsp),%r15d
  lea    D38(%rip),%rdi
  cvtsi2sd %r15d,%xmm0
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  lea    D39(%rip),%rdi
  cvtsi2sd %r14d,%xmm0
  mulsd  D2(%rip),%xmm0
  call   <printf@plt>
  cmp    0x20(%rsp),%r15d
  jl     L121
L86:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r10d,%edx
  add    $0x4,%rcx
  cmp    %r10d,%r8d
  jne    L61
  mov    %r10d,%edi
  add    $0x4,%r9
  cmp    %r10d,%r8d
  jne    L72
  jmp    L55
L50:
  mov    $0x5f5e0ff,%r14d
  jmp    L55
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D41
datatype: string
name: retrieve_data
arguments: data_tag: D30
datatype: string
name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D38
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: byte[8]

tool: D41: rt

tool: D30: squirrels.in

tool: D43:  %d

tool: D38: Campus #%d:


tool: D39: Maximum territory area = %.3f



tool: {"D2": [0x11,0x2d,0x44,0x54,0xfb,0x21,0xe9,0x3f]}

assistant: ```c
int main() {
  int c, t;
  int *x, *y;
  int testCase, i, j;
  int min;
  FILE *in = fopen("squirrels.in", "rt");
  fscanf(in, " %d", &c);
  for (testCase = 0; testCase < c; testCase++) {
    fscanf(in, " %d", &t);
    x = (int *)malloc(t * sizeof(int));
    y = (int *)malloc(t * sizeof(int));
    for (i = 0; i < t; i++) {
      fscanf(in, " %d", &(x[i]));
      fscanf(in, " %d", &(y[i]));
    }
    min = 99999999;
    for (i = 0; i < t; i++) {
      for (j = 0; j < t; j++) {
        if (i != j) {
          int dx = x[i] - x[j];
          int dy = y[i] - y[j];
          int distSq = dx * dx + dy * dy;
          if (min > distSq)
            min = distSq;
        }
      }
    }
    free(x);
    free(y);
    double answer = 3.14159265358979 / 4.0 * min;
    printf("Campus #%d:\n", testCase + 1);
    printf("Maximum territory area = %.3f\n\n", answer);
  }
  fclose(in);
  return 0;
}
```