ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<ft_valid_key>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L58
  mov    $0x1,%eax
L29:
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%esi
  lea    -0x30(%rsi),%edx
  add    $0x1,%rax
  cmp    $0x9,%dl
  jbe    L29
L54:
  movslq %ecx,%rax
  cmpb   $0xa,(%rdi,%rax,1)
  je     L40
  mov    $0x1,%edx
  sub    %ecx,%edx
L27:
  mov    %eax,%ecx
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0xa,(%rdi,%rax,1)
  jne    L27
  mov    $0x0,%eax
  cmp    $0x3,%esi
  jne    L6
  movslq %ecx,%rcx
  movzbl (%rdi,%rcx,1),%edx
  movzbl -0x1(%rdi,%rcx,1),%esi
  cmp    %sil,%dl
  je     L6
  movzbl -0x2(%rdi,%rcx,1),%ecx
  cmp    %cl,%sil
  sete   %al
  cmp    %cl,%dl
  sete   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
L58:
  mov    $0x0,%ecx
  jmp    L54
L40:
  mov    $0x0,%eax
L6:
  ret
```

assistant: ```c
int ft_valid_key(char *str) {
  int i;
  int ch_count;
  i = 0;
  ch_count = 0;
  while (str[i] <= '9' && str[i] >= '0' && str[i] != '\n')
    i++;
  while (str[i] != '\n') {
    ch_count++;
    i++;
  }
  i--;
  if (ch_count != 3 || str[i] == str[i - 1] || str[i] == str[i - 2] || str[i - 1] == str[i - 2])
    return (0);
  else
    return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_valid_key>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L60
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L65:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L65
L55:
  cmp    $0xa,%dl
  je     L9
  mov    $0x1,%edx
  movslq %esi,%rax
  sub    %esi,%edx
  nopl   0x0(%rax)
L15:
  movslq %eax,%rcx
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0xa,(%rdi,%rax,1)
  jne    L15
  xor    %eax,%eax
  cmp    $0x3,%esi
  jne    L37
  movzbl (%rdi,%rcx,1),%edx
  movzbl -0x1(%rdi,%rcx,1),%esi
  cmp    %sil,%dl
  je     L37
  movzbl -0x2(%rdi,%rcx,1),%ecx
  cmp    %cl,%sil
  sete   %al
  cmp    %cl,%dl
  sete   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
L37:
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  xor    %esi,%esi
  jmp    L55
```

assistant: ```c
int ft_valid_key(char *str) {
  int i;
  int ch_count;
  i = 0;
  ch_count = 0;
  while (str[i] <= '9' && str[i] >= '0' && str[i] != '\n')
    i++;
  while (str[i] != '\n') {
    ch_count++;
    i++;
  }
  i--;
  if (ch_count != 3 || str[i] == str[i - 1] || str[i] == str[i - 2] || str[i - 1] == str[i - 2])
    return (0);
  else
    return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_valid_key>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  ja     L16
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%esi
  add    $0x1,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L37
L64:
  cmp    $0xa,%dl
  je     L60
  mov    $0x1,%edx
  movslq %esi,%rax
  sub    %esi,%edx
  nopl   0x0(%rax)
L35:
  movslq %eax,%rcx
  lea    (%rdx,%rax,1),%esi
  add    $0x1,%rax
  cmpb   $0xa,(%rdi,%rax,1)
  jne    L35
  xor    %eax,%eax
  cmp    $0x3,%esi
  jne    L18
  movzbl (%rdi,%rcx,1),%edx
  movzbl -0x1(%rdi,%rcx,1),%esi
  cmp    %sil,%dl
  je     L18
  movzbl -0x2(%rdi,%rcx,1),%ecx
  cmp    %cl,%sil
  sete   %al
  cmp    %cl,%dl
  sete   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L60:
  xor    %eax,%eax
L18:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %esi,%esi
  jmp    L64
```

assistant: ```c
int ft_valid_key(char *str) {
  int i;
  int ch_count;
  i = 0;
  ch_count = 0;
  while (str[i] <= '9' && str[i] >= '0' && str[i] != '\n')
    i++;
  while (str[i] != '\n') {
    ch_count++;
    i++;
  }
  i--;
  if (ch_count != 3 || str[i] == str[i - 1] || str[i] == str[i - 2] || str[i - 1] == str[i - 2])
    return (0);
  else
    return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tk_puts_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L5:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tk_putc@plt>
L6:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void tk_puts_n(char *msg, int n) {
  char *s;
  s = msg;
  while (n--) {
    tk_putc(*s++);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tk_puts_n>:
  endbr64
  test   %esi,%esi
  je     L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L1:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <tk_putc@plt>
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  ret
```

assistant: ```c
void tk_puts_n(char *msg, int n) {
  char *s;
  s = msg;
  while (n--) {
    tk_putc(*s++);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tk_puts_n>:
  endbr64
  test   %esi,%esi
  je     L5
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tk_putc@plt>
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void tk_puts_n(char *msg, int n) {
  char *s;
  s = msg;
  while (n--) {
    tk_putc(*s++);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<tk_puts_n>:
  endbr64
  test   %esi,%esi
  je     L11
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tk_putc@plt>
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
void tk_puts_n(char *msg, int n) {
  char *s;
  s = msg;
  while (n--) {
    tk_putc(*s++);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__test1@plt>
  mov    $0x0,%eax
  call   <__test2@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  __test1();
  __test2();
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__test1@plt>
  mov    $0x0,%eax
  call   <__test2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  __test1();
  __test2();
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__test1@plt>
  xor    %eax,%eax
  call   <__test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  __test1();
  __test2();
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__test1@plt>
  xor    %eax,%eax
  call   <__test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  __test1();
  __test2();
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<obterNoComMenorDistancia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L25
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L25
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L25:
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L39
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int obterNoComMenorDistancia(int *distancia, int *visitado, int N) {
  int i, menorIndice = 0, menorValor = INT_MAX;
  for (i = 0; i < N; i++) {
    if (distancia[i] < menorValor && !visitado[i]) {
      menorIndice = i;
      menorValor = distancia[i];
    }
  }
  return menorIndice;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<obterNoComMenorDistancia>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%r8d
  test   %edx,%edx
  jle    L31
  mov    %edx,%edx
  mov    $0x0,%eax
  mov    $0x0,%r10d
  jmp    L23
L26:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L7
L23:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jge    L26
  cmpl   $0x0,(%rsi,%rax,4)
  cmove  %ecx,%r8d
  cmove  %eax,%r10d
  jmp    L26
L31:
  mov    $0x0,%r10d
L7:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int obterNoComMenorDistancia(int *distancia, int *visitado, int N) {
  int i, menorIndice = 0, menorValor = INT_MAX;
  for (i = 0; i < N; i++) {
    if (distancia[i] < menorValor && !visitado[i]) {
      menorIndice = i;
      menorValor = distancia[i];
    }
  }
  return menorIndice;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<obterNoComMenorDistancia>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%r8d
  test   %edx,%edx
  jle    L22
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jge    L27
  mov    (%rsi,%rax,4),%r10d
  test   %r10d,%r10d
  cmove  %ecx,%r8d
  cmove  %eax,%r9d
L27:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L22:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int obterNoComMenorDistancia(int *distancia, int *visitado, int N) {
  int i, menorIndice = 0, menorValor = INT_MAX;
  for (i = 0; i < N; i++) {
    if (distancia[i] < menorValor && !visitado[i]) {
      menorIndice = i;
      menorValor = distancia[i];
    }
  }
  return menorIndice;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<obterNoComMenorDistancia>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%r8d
  test   %edx,%edx
  jle    L17
  movslq %edx,%rdx
  xor    %eax,%eax
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rdi,%rax,4),%ecx
  cmp    %r8d,%ecx
  jge    L14
  mov    (%rsi,%rax,4),%r10d
  test   %r10d,%r10d
  cmove  %ecx,%r8d
  cmove  %eax,%r9d
L14:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L0
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int obterNoComMenorDistancia(int *distancia, int *visitado, int N) {
  int i, menorIndice = 0, menorValor = INT_MAX;
  for (i = 0; i < N; i++) {
    if (distancia[i] < menorValor && !visitado[i]) {
      menorIndice = i;
      menorValor = distancia[i];
    }
  }
  return menorIndice;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L96:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L102
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L9
L102:
  mov    $0x1,%eax
  jmp    L70
L9:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L96
  mov    $0x0,%eax
L70:
  leave
  ret
```

assistant: ```c
bool isCode(char *chars) {
  int i = 0;
  for (i; i < strlen(chars); i++) {
    if (chars[i] == '+' || chars[i] == '-' || chars[i] == '>' || chars[i] == '<' || chars[i] == '[' || chars[i] == ']' || chars[i] == ',' || chars[i] == '.') {
      return true;
    }
  }
  return false;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isCode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  movabs $0x2800000050005,%r12
  jmp    L0
L29:
  add    $0x1,%rbx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L64
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x2b(%rax),%edx
  test   $0xfd,%dl
  je     L26
  sub    $0x2c,%eax
  cmp    $0x31,%al
  ja     L29
  bt     %rax,%r12
  jae    L29
  mov    $0x1,%eax
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  mov    $0x0,%eax
  jmp    L61
L26:
  mov    $0x1,%eax
  jmp    L61
```

assistant: ```c
bool isCode(char *chars) {
  int i = 0;
  for (i; i < strlen(chars); i++) {
    if (chars[i] == '+' || chars[i] == '-' || chars[i] == '>' || chars[i] == '<' || chars[i] == '[' || chars[i] == ']' || chars[i] == ',' || chars[i] == '.') {
      return true;
    }
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isCode>:
  endbr64
  push   %r12
  movabs $0x2800000050005,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L48
  nopl   0x0(%rax)
L19:
  add    $0x1,%rbx
L48:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L6
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  je     L10
  sub    $0x2c,%eax
  cmp    $0x31,%al
  ja     L19
  bt     %rax,%r12
  jae    L19
L10:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool isCode(char *chars) {
  int i = 0;
  for (i; i < strlen(chars); i++) {
    if (chars[i] == '+' || chars[i] == '-' || chars[i] == '>' || chars[i] == '<' || chars[i] == '[' || chars[i] == ']' || chars[i] == ',' || chars[i] == '.') {
      return true;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isCode>:
  endbr64
  push   %r12
  movabs $0x2800000050005,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L24
  nopl   0x0(%rax)
L44:
  add    $0x1,%rbx
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L2
  movzbl 0x0(%rbp,%rbx,1),%eax
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  je     L38
  sub    $0x2c,%eax
  cmp    $0x31,%al
  ja     L44
  bt     %rax,%r12
  jae    L44
L38:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool isCode(char *chars) {
  int i = 0;
  for (i; i < strlen(chars); i++) {
    if (chars[i] == '+' || chars[i] == '-' || chars[i] == '>' || chars[i] == '<' || chars[i] == '[' || chars[i] == ']' || chars[i] == ',' || chars[i] == '.') {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fe_hamming_window>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L3
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L28
  nop
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fe_hamming_window(double *in, double *window, int in_len) {
  int i;
  if (in_len > 1) {
    for (i = 0; i < in_len; i++)
      in[i] *= window[i];
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fe_hamming_window>:
  endbr64
  cmp    $0x1,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
L4:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L14:
  ret
```

assistant: ```c
void fe_hamming_window(double *in, double *window, int in_len) {
  int i;
  if (in_len > 1) {
    for (i = 0; i < in_len; i++)
      in[i] *= window[i];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fe_hamming_window>:
  endbr64
  cmp    $0x1,%edx
  jle    L4
  movslq %edx,%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L10:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L10
L4:
  ret
```

assistant: ```c
void fe_hamming_window(double *in, double *window, int in_len) {
  int i;
  if (in_len > 1) {
    for (i = 0; i < in_len; i++)
      in[i] *= window[i];
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fe_hamming_window>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%edx
  jle    L32
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L55
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L55
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L23:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L23
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L32
  lea    (%rcx,%rax,8),%rdx
  movsd  (%rdx),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L22
L32:
  ret
```

assistant: ```c
void fe_hamming_window(double *in, double *window, int in_len) {
  int i;
  if (in_len > 1) {
    for (i = 0; i < in_len; i++)
      in[i] *= window[i];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x64,%edi
  call   <malloc_recursive@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  malloc_recursive(100);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc_recursive@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  malloc_recursive(100);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc_recursive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  malloc_recursive(100);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc_recursive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  malloc_recursive(100);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vturnaround_extra_parse_katcl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <copy_string_parse_katcl@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L84
  mov    $0x0,%eax
  jmp    L79
L84:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <reuse_parse_katcl@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy_parse_katcl@plt>
  mov    $0x0,%eax
  jmp    L79
L14:
  mov    -0x10(%rbp),%rax
  movb   $0x21,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x11,%esi
  mov    %rax,%rdi
  call   <add_string_parse_katcl@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <code_to_name_katcm@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L51
  cmpq   $0x0,-0x10(%rbp)
  je     L62
  mov    -0x10(%rbp),%rax
  jmp    L65
L62:
  lea    D2(%rip),%rax
L65:
  mov    -0x8(%rbp),%rcx
  mov    %rax,%rdx
  mov    $0x10,%esi
  mov    %rcx,%rdi
  call   <add_plain_parse_katcl@plt>
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <add_vargs_parse_katcl@plt>
  jmp    L88
L51:
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  jmp    L63
L6:
  lea    D2(%rip),%rax
L63:
  mov    -0x8(%rbp),%rcx
  mov    %rax,%rdx
  mov    $0x12,%esi
  mov    %rcx,%rdi
  call   <add_plain_parse_katcl@plt>
L88:
  mov    -0x8(%rbp),%rax
L79:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: fail

assistant: ```c
struct katcl_parse *vturnaround_extra_parse_katcl(struct katcl_parse *p, int code, char *fmt, va_list args) {
  char *string;
  struct katcl_parse *px;
  string = copy_string_parse_katcl(p, 0);
  if (string == NULL) {
    return NULL;
  }
  px = reuse_parse_katcl(p);
  if (px == NULL) {
    destroy_parse_katcl(p);
    return NULL;
  }
  string[0] = '!';
  add_string_parse_katcl(px, 0x01 | 0x10, string);
  free(string);
  string = code_to_name_katcm(code);
  if (fmt) {
    add_plain_parse_katcl(px, 0x10, string ? string : "fail");
    add_vargs_parse_katcl(px, 0x02 | 0x10, fmt, args);
  } else {
    add_plain_parse_katcl(px, 0x02 | 0x10, string ? string : "fail");
  }
  return px;
}
```