ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clz>:
  endbr64
  cmp    $0xffff,%edi
  jle    L37
  sar    $0x10,%edi
  mov    $0x8,%edx
  mov    $0x10,%eax
L18:
  test   $0xff00,%edi
  je     L32
  sar    $0x8,%edi
  mov    %edx,%eax
L32:
  test   $0xf0,%dil
  je     L26
  sub    $0x4,%eax
  sar    $0x4,%edi
L26:
  movslq %edi,%rdi
  lea    D1(%rip),%rdx
  sub    (%rdx,%rdi,4),%eax
  ret
L37:
  mov    $0x18,%edx
  mov    $0x20,%eax
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: 

assistant: ```c
uint8_t clz(uint32_t x) {
  static const uint8_t bval[] = {0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4};
  unsigned int r = 32;
  if (x >= 0x10000) {
    r -= 16;
    x >>= 16;
  }
  if (x & 0xFF00) {
    r -= 8;
    x >>= 8;
  }
  if (x & 0xF0) {
    r -= 4;
    x >>= 4;
  }
  return r - bval[x];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L12
  cmpb   $0x39,-0x4(%rbp)
  jg     L12
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L0
L12:
  cmpb   $0x40,-0x4(%rbp)
  jle    L27
  cmpb   $0x46,-0x4(%rbp)
  jg     L27
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L0
L27:
  cmpb   $0x60,-0x4(%rbp)
  jle    L43
  cmpb   $0x66,-0x4(%rbp)
  jg     L43
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L0
L43:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int ToHex(char ch) {
  if ((ch >= '0') && (ch <= '9'))
    return ch - 0x30;
  else if ((ch >= 'A') && (ch <= 'F'))
    return ch - 0x37;
  else if ((ch >= 'a') && (ch <= 'f'))
    return ch - 0x57;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ToHex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L0
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L2
  lea    -0x61(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x57,%eax
  cmp    $0x6,%dl
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
L0:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L2:
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int ToHex(char ch) {
  if ((ch >= '0') && (ch <= '9'))
    return ch - 0x30;
  else if ((ch >= 'A') && (ch <= 'F'))
    return ch - 0x37;
  else if ((ch >= 'a') && (ch <= 'f'))
    return ch - 0x57;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ToHex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L7
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L18
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl %al,%eax
  ret
```

assistant: ```c
int ToHex(char ch) {
  if ((ch >= '0') && (ch <= '9'))
    return ch - 0x30;
  else if ((ch >= 'A') && (ch <= 'F'))
    return ch - 0x37;
  else if ((ch >= 'a') && (ch <= 'f'))
    return ch - 0x57;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ToHex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L1
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L12
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  movsbl %al,%eax
  ret
```

assistant: ```c
int ToHex(char ch) {
  if ((ch >= '0') && (ch <= '9'))
    return ch - 0x30;
  else if ((ch >= 'A') && (ch <= 'F'))
    return ch - 0x37;
  else if ((ch >= 'a') && (ch <= 'f'))
    return ch - 0x57;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a | b;
  return tem1 ^ tem2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a | b;
  return tem1 ^ tem2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a | b;
  return tem1 ^ tem2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn6>:
  endbr64
  mov    %esi,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int fn6(int a, int b) {
  int tem1 = b ^ a;
  int tem2 = a | b;
  return tem1 ^ tem2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<s2e_disable_all_apic_interrupts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  (bad)
  add    %dl,0x1(%rcx)
  add    %al,(%rax)
  add    %al,(%rax)
  .byte 0x0
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s2e_disable_all_apic_interrupts() {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, 0x51, 0x01, 0x00\n"
                       ".byte 0x00, 0x00, 0x00, 0x00\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<s2e_disable_all_apic_interrupts>:
  endbr64
  (bad)
  add    %dl,0x1(%rcx)
  add    %al,(%rax)
  add    %al,(%rax)
  add    %al,%bl
```

assistant: ```c
void s2e_disable_all_apic_interrupts() {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, 0x51, 0x01, 0x00\n"
                       ".byte 0x00, 0x00, 0x00, 0x00\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s2e_disable_all_apic_interrupts>:
  endbr64
  (bad)
  add    %dl,0x1(%rcx)
  add    %al,(%rax)
  add    %al,(%rax)
  add    %al,%bl
```

assistant: ```c
void s2e_disable_all_apic_interrupts() {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, 0x51, 0x01, 0x00\n"
                       ".byte 0x00, 0x00, 0x00, 0x00\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<s2e_disable_all_apic_interrupts>:
  endbr64
  (bad)
  add    %dl,0x1(%rcx)
  add    %al,(%rax)
  add    %al,(%rax)
  add    %al,%bl
```

assistant: ```c
void s2e_disable_all_apic_interrupts() {
  __asm__ __volatile__(".byte 0x0f, 0x3f\n"
                       ".byte 0x00, 0x51, 0x01, 0x00\n"
                       ".byte 0x00, 0x00, 0x00, 0x00\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int a, int b) {
  int c = a + b;
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int sum(int a, int b) {
  int c = a + b;
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int sum(int a, int b) {
  int c = a + b;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int sum(int a, int b) {
  int c = a + b;
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wpa_sm_call_step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wpa_sm_step@plt>
  nop
  leave
  ret
```

assistant: ```c
void wpa_sm_call_step(void *eloop_ctx, void *timeout_ctx) {
  struct wpa_state_machine *sm = timeout_ctx;
  wpa_sm_step(sm);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wpa_sm_call_step>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <wpa_sm_step@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wpa_sm_call_step(void *eloop_ctx, void *timeout_ctx) {
  struct wpa_state_machine *sm = timeout_ctx;
  wpa_sm_step(sm);
}
```
user: What is the c source code of the assembly code below?

```asm
<wpa_sm_call_step>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <wpa_sm_step@plt>
```

assistant: ```c
void wpa_sm_call_step(void *eloop_ctx, void *timeout_ctx) {
  struct wpa_state_machine *sm = timeout_ctx;
  wpa_sm_step(sm);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wpa_sm_call_step>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <wpa_sm_step@plt>
```

assistant: ```c
void wpa_sm_call_step(void *eloop_ctx, void *timeout_ctx) {
  struct wpa_state_machine *sm = timeout_ctx;
  wpa_sm_step(sm);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modulo360>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x168,%edi
  movd   %eax,%xmm0
  call   <modulo@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  comisd D10(%rip),%xmm0
  jbe    L17
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L17
  cmpl   $0x0,-0x18(%rbp)
  jne    L3
  pxor   %xmm0,%xmm0
  jmp    L22
L3:
  movss  D18(%rip),%xmm0
  jmp    L22
L17:
  movss  -0x4(%rbp),%xmm0
L22:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: byte[16]
name: unpack_data
arguments: label: D12
type_guessed: f64
name: unpack_data
arguments: label: D18
type_guessed: f32

tool: {"D10": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0xbf,0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D12: 0.001

tool: D18: 360

assistant: ```c
float modulo360(float num, int type) {
  float res;
  res = modulo(num, 360);
  if (res > -0.001 && res < 0.001) {
    switch (type) {
    case 0:
      return (0.);
    default:
      return (360.);
    }
  }
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<modulo360>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x168,%edi
  call   <modulo@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D10(%rip),%xmm1
  jbe    L17
  movsd  D16(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L17
  pxor   %xmm0,%xmm0
  test   %ebx,%ebx
  je     L17
  movss  D17(%rip),%xmm0
L17:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D16
type_infered: f64
name: disassemble_data
arguments: data_tag: D17
type_infered: f32

tool: {"D10": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0xbf,0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D16: 0.001

tool: D17: 360

assistant: ```c
float modulo360(float num, int type) {
  float res;
  res = modulo(num, 360);
  if (res > -0.001 && res < 0.001) {
    switch (type) {
    case 0:
      return (0.);
    default:
      return (360.);
    }
  }
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<modulo360>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x168,%edi
  call   <modulo@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D14(%rip),%xmm1
  jbe    L1
  movsd  D27(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L1
  pxor   %xmm0,%xmm0
  test   %ebx,%ebx
  je     L1
  movss  D26(%rip),%xmm0
L1:
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type: byte[16]
name: unpack_data
arguments: tag: D27
type: f64
name: unpack_data
arguments: tag: D26
type: f32

tool: {"D14": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0xbf,0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D27: 0.001

tool: D26: 360

assistant: ```c
float modulo360(float num, int type) {
  float res;
  res = modulo(num, 360);
  if (res > -0.001 && res < 0.001) {
    switch (type) {
    case 0:
      return (0.);
    default:
      return (360.);
    }
  }
  return (res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modulo360>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x168,%edi
  call   <modulo@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  comisd D15(%rip),%xmm1
  jbe    L6
  movsd  D19(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L6
  pxor   %xmm0,%xmm0
  test   %ebx,%ebx
  je     L6
  movss  D0(%rip),%xmm0
L6:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D15
data_type: byte[16]
name: retrieve_data
arguments: label: D19
data_type: f64
name: retrieve_data
arguments: label: D0
data_type: f32

tool: {"D15": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0xbf,0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D19: 0.001

tool: D0: 360

assistant: ```c
float modulo360(float num, int type) {
  float res;
  res = modulo(num, 360);
  if (res > -0.001 && res < 0.001) {
    switch (type) {
    case 0:
      return (0.);
    default:
      return (360.);
    }
  }
  return (res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<new_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  ja     L48
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x15,%eax
  jmp    L50
  mov    $0x16,%eax
  jmp    L50
  mov    $0x14,%eax
  jmp    L50
  mov    $0x17,%eax
  jmp    L50
  mov    $0x18,%eax
  jmp    L50
L48:
  nop
  mov    $0x21,%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
int new_type(int x) {
  switch (x) {
  case 1:
    return 21;
  case 2:
    return 22;
  case 3:
    return 20;
  case 4:
    return 23;
  case 5:
    return 24;
  default:
    break;
  }
  return 33;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<new_type>:
  endbr64
  cmp    $0x5,%edi
  ja     L0
  mov    %edi,%edi
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x16,%eax
  ret
  mov    $0x14,%eax
  ret
  mov    $0x17,%eax
  ret
  mov    $0x18,%eax
  ret
L0:
  mov    $0x21,%eax
  ret
  mov    $0x15,%eax
  ret
```

assistant: ```c
int new_type(int x) {
  switch (x) {
  case 1:
    return 21;
  case 2:
    return 22;
  case 3:
    return 20;
  case 4:
    return 23;
  case 5:
    return 24;
  default:
    break;
  }
  return 33;
}
```
user: What is the c source code of the assembly code below:

```asm
<new_type>:
  endbr64
  sub    $0x1,%edi
  mov    $0x21,%eax
  cmp    $0x4,%edi
  ja     L9
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L9:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: 

assistant: ```c
int new_type(int x) {
  switch (x) {
  case 1:
    return 21;
  case 2:
    return 22;
  case 3:
    return 20;
  case 4:
    return 23;
  case 5:
    return 24;
  default:
    break;
  }
  return 33;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<new_type>:
  endbr64
  sub    $0x1,%edi
  mov    $0x21,%eax
  cmp    $0x4,%edi
  ja     L3
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L3:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: 

assistant: ```c
int new_type(int x) {
  switch (x) {
  case 1:
    return 21;
  case 2:
    return 22;
  case 3:
    return 20;
  case 4:
    return 23;
  case 5:
    return 24;
  default:
    break;
  }
  return 33;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xtoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  je     L34
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
  mov    -0x28(%rbp),%rax
  neg    %rax
  mov    %rax,-0x28(%rbp)
L34:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L8:
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x28(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jbe    L1
  mov    -0x14(%rbp),%eax
  lea    0x57(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L10
L1:
  mov    -0x14(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L10:
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L27:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xtoa(unsigned long val, char *buf, unsigned radix, int negative) {
  char *p;
  char *firstdig;
  char temp;
  unsigned digval;
  p = buf;
  if (negative) {
    *p++ = '-';
    val = (unsigned long)(-(long)val);
  }
  firstdig = p;
  do {
    digval = (unsigned)(val % radix);
    val /= radix;
    if (digval > 9)
      *p++ = (char)(digval - 10 + 'a');
    else
      *p++ = (char)(digval + '0');
  } while (val > 0);
  *p-- = '\0';
  do {
    temp = *p;
    *p = *firstdig;
    *firstdig = temp;
    p--;
    firstdig++;
  } while (firstdig < p);
}
```
user: What is the c source code of the assembly code below?

```asm
<xtoa>:
  endbr64
  mov    %rdi,%rax
  test   %ecx,%ecx
  je     L53
  movb   $0x2d,(%rsi)
  neg    %rax
  lea    0x1(%rsi),%rsi
L53:
  lea    0x1(%rsi),%rcx
  mov    %edx,%edi
  jmp    L48
L13:
  mov    %rcx,%r9
  add    $0x57,%edx
L51:
  mov    %dl,-0x1(%rcx)
  add    $0x1,%rcx
  cmp    %r8,%rdi
  ja     L47
L48:
  mov    %rax,%r8
  mov    $0x0,%edx
  div    %rdi
  cmp    $0x9,%edx
  ja     L13
  mov    %rcx,%r9
  add    $0x30,%edx
  jmp    L51
L47:
  lea    -0x1(%r9),%rax
  movb   $0x0,(%r9)
L23:
  movzbl (%rax),%edx
  movzbl (%rsi),%ecx
  mov    %cl,(%rax)
  mov    %dl,(%rsi)
  sub    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rsi,%rax
  ja     L23
  ret
```

assistant: ```c
void xtoa(unsigned long val, char *buf, unsigned radix, int negative) {
  char *p;
  char *firstdig;
  char temp;
  unsigned digval;
  p = buf;
  if (negative) {
    *p++ = '-';
    val = (unsigned long)(-(long)val);
  }
  firstdig = p;
  do {
    digval = (unsigned)(val % radix);
    val /= radix;
    if (digval > 9)
      *p++ = (char)(digval - 10 + 'a');
    else
      *p++ = (char)(digval + '0');
  } while (val > 0);
  *p-- = '\0';
  do {
    temp = *p;
    *p = *firstdig;
    *firstdig = temp;
    p--;
    firstdig++;
  } while (firstdig < p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xtoa>:
  endbr64
  mov    %rdi,%rax
  test   %ecx,%ecx
  je     L5
  movb   $0x2d,(%rsi)
  neg    %rax
  add    $0x1,%rsi
L5:
  mov    %edx,%r8d
  mov    %rsi,%r9
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %edx,%edx
  mov    %rax,%r10
  mov    %r9,%rcx
  div    %r8
  lea    0x1(%r9),%r9
  lea    0x57(%rdx),%r11d
  lea    0x30(%rdx),%edi
  cmp    $0xa,%rdx
  cmovae %r11d,%edi
  mov    %dil,-0x1(%r9)
  cmp    %r8,%r10
  jae    L21
  movb   $0x0,(%r9)
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl (%rcx),%eax
  movzbl (%rsi),%edx
  sub    $0x1,%rcx
  add    $0x1,%rsi
  mov    %dl,0x1(%rcx)
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rcx
  ja     L1
  ret
```

assistant: ```c
void xtoa(unsigned long val, char *buf, unsigned radix, int negative) {
  char *p;
  char *firstdig;
  char temp;
  unsigned digval;
  p = buf;
  if (negative) {
    *p++ = '-';
    val = (unsigned long)(-(long)val);
  }
  firstdig = p;
  do {
    digval = (unsigned)(val % radix);
    val /= radix;
    if (digval > 9)
      *p++ = (char)(digval - 10 + 'a');
    else
      *p++ = (char)(digval + '0');
  } while (val > 0);
  *p-- = '\0';
  do {
    temp = *p;
    *p = *firstdig;
    *firstdig = temp;
    p--;
    firstdig++;
  } while (firstdig < p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xtoa>:
  endbr64
  test   %ecx,%ecx
  je     L30
  movb   $0x2d,(%rsi)
  neg    %rdi
  add    $0x1,%rsi
L30:
  mov    %edx,%r8d
  mov    %rsi,%rcx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x57,%edx
  mov    %dl,-0x1(%r9)
  cmp    %r8,%rdi
  jb     L3
L26:
  mov    %r9,%rcx
  mov    %rax,%rdi
L35:
  mov    %rdi,%rax
  xor    %edx,%edx
  lea    0x1(%rcx),%r9
  div    %r8
  cmp    $0x9,%rdx
  ja     L28
  add    $0x30,%edx
  mov    %dl,-0x1(%r9)
  cmp    %r8,%rdi
  jae    L26
L3:
  movb   $0x0,(%r9)
  nopl   0x0(%rax)
L29:
  movzbl (%rcx),%eax
  movzbl (%rsi),%edx
  sub    $0x1,%rcx
  add    $0x1,%rsi
  mov    %dl,0x1(%rcx)
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rcx
  ja     L29
  ret
```

assistant: ```c
void xtoa(unsigned long val, char *buf, unsigned radix, int negative) {
  char *p;
  char *firstdig;
  char temp;
  unsigned digval;
  p = buf;
  if (negative) {
    *p++ = '-';
    val = (unsigned long)(-(long)val);
  }
  firstdig = p;
  do {
    digval = (unsigned)(val % radix);
    val /= radix;
    if (digval > 9)
      *p++ = (char)(digval - 10 + 'a');
    else
      *p++ = (char)(digval + '0');
  } while (val > 0);
  *p-- = '\0';
  do {
    temp = *p;
    *p = *firstdig;
    *firstdig = temp;
    p--;
    firstdig++;
  } while (firstdig < p);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy_dobldobl_start_solutions_to_container>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x101,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_dobldobl_start_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(257, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_dobldobl_start_solutions_to_container>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x101,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_dobldobl_start_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(257, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy_dobldobl_start_solutions_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x101,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_start_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(257, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copy_dobldobl_start_solutions_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x101,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_start_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(257, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scaleMarkX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x66,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L32:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edi
  call   <absInt@plt>
  test   %eax,%eax
  jg     L13
  mov    $0x1,%eax
  jmp    L31
L13:
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0xa,-0x8(%rbp)
  jle    L32
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int scaleMarkX(int x) {
  int scale = 1024 / 10;
  for (int i = 0; i < 10 + 1; i++) {
    if (absInt(x - scale * i) < 1) {
      return 1;
    }
  }
  return 0;
}
```