ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %r8,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EVP_CIPHER_CTX_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L32
L6:
  mov    $0x0,%eax
  call   <EVP_aes_256_cbc@plt>
  mov    %eax,%esi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <EVP_EncryptInit_ex@plt>
  cmp    $0x1,%eax
  jne    L31
L36:
  lea    0x4(%rsp),%rdx
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EVP_EncryptUpdate@plt>
  cmp    $0x1,%eax
  jne    L34
L72:
  mov    0x4(%rsp),%r12d
  lea    0x4(%rsp),%rdx
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <EVP_EncryptFinal_ex@plt>
  cmp    $0x1,%eax
  jne    L86
L58:
  add    0x4(%rsp),%r12d
  mov    %rbx,%rdi
  call   <EVP_CIPHER_CTX_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%eax
  call   <secreteLibSSLError@plt>
  jmp    L6
L31:
  mov    $0x0,%eax
  call   <secreteLibSSLError@plt>
  jmp    L36
L34:
  mov    $0x0,%eax
  call   <secreteLibSSLError@plt>
  jmp    L72
L86:
  mov    $0x0,%eax
  call   <secreteLibSSLError@plt>
  jmp    L58
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int encrypt(void *plaintext, size_t plaintext_len, void *key, void *iv, void *ciphertext) {
  EVP_CIPHER_CTX *ctx;
  int len;
  int ciphertext_len;
  if (!(ctx = EVP_CIPHER_CTX_new())) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptInit_ex(ctx, EVP_aes_256_cbc(), NULL, key, iv)) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptUpdate(ctx, ciphertext, &len, plaintext, plaintext_len)) {
    secreteLibSSLError();
  }
  ciphertext_len = len;
  if (1 != EVP_EncryptFinal_ex(ctx, ciphertext + len, &len)) {
    secreteLibSSLError();
  }
  ciphertext_len += len;
  EVP_CIPHER_CTX_free(ctx);
  return ciphertext_len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encrypt>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EVP_CIPHER_CTX_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L52
L1:
  xor    %eax,%eax
  call   <EVP_aes_256_cbc@plt>
  xor    %edx,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <EVP_EncryptInit_ex@plt>
  cmp    $0x1,%eax
  je     L30
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L30:
  lea    0x4(%rsp),%r14
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbx,%rsi
  mov    %r14,%rdx
  mov    %rbp,%rdi
  call   <EVP_EncryptUpdate@plt>
  cmp    $0x1,%eax
  je     L38
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L38:
  movslq 0x4(%rsp),%rax
  mov    %r14,%rdx
  mov    %rbp,%rdi
  lea    (%rbx,%rax,1),%rsi
  mov    %rax,%r12
  call   <EVP_EncryptFinal_ex@plt>
  cmp    $0x1,%eax
  je     L8
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L8:
  mov    %rbp,%rdi
  add    0x4(%rsp),%r12d
  call   <EVP_CIPHER_CTX_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L52:
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
  jmp    L1
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int encrypt(void *plaintext, size_t plaintext_len, void *key, void *iv, void *ciphertext) {
  EVP_CIPHER_CTX *ctx;
  int len;
  int ciphertext_len;
  if (!(ctx = EVP_CIPHER_CTX_new())) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptInit_ex(ctx, EVP_aes_256_cbc(), NULL, key, iv)) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptUpdate(ctx, ciphertext, &len, plaintext, plaintext_len)) {
    secreteLibSSLError();
  }
  ciphertext_len = len;
  if (1 != EVP_EncryptFinal_ex(ctx, ciphertext + len, &len)) {
    secreteLibSSLError();
  }
  ciphertext_len += len;
  EVP_CIPHER_CTX_free(ctx);
  return ciphertext_len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<encrypt>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <EVP_CIPHER_CTX_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
L9:
  xor    %eax,%eax
  call   <EVP_aes_256_cbc@plt>
  xor    %edx,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <EVP_EncryptInit_ex@plt>
  cmp    $0x1,%eax
  je     L12
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L12:
  lea    0x4(%rsp),%r14
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbx,%rsi
  mov    %r14,%rdx
  mov    %rbp,%rdi
  call   <EVP_EncryptUpdate@plt>
  cmp    $0x1,%eax
  je     L35
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L35:
  movslq 0x4(%rsp),%rax
  mov    %r14,%rdx
  mov    %rbp,%rdi
  lea    (%rbx,%rax,1),%rsi
  mov    %rax,%r12
  call   <EVP_EncryptFinal_ex@plt>
  cmp    $0x1,%eax
  je     L48
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
L48:
  mov    %rbp,%rdi
  add    0x4(%rsp),%r12d
  call   <EVP_CIPHER_CTX_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L21:
  xor    %eax,%eax
  call   <secreteLibSSLError@plt>
  jmp    L9
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int encrypt(void *plaintext, size_t plaintext_len, void *key, void *iv, void *ciphertext) {
  EVP_CIPHER_CTX *ctx;
  int len;
  int ciphertext_len;
  if (!(ctx = EVP_CIPHER_CTX_new())) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptInit_ex(ctx, EVP_aes_256_cbc(), NULL, key, iv)) {
    secreteLibSSLError();
  }
  if (1 != EVP_EncryptUpdate(ctx, ciphertext, &len, plaintext, plaintext_len)) {
    secreteLibSSLError();
  }
  ciphertext_len = len;
  if (1 != EVP_EncryptFinal_ex(ctx, ciphertext + len, &len)) {
    secreteLibSSLError();
  }
  ciphertext_len += len;
  EVP_CIPHER_CTX_free(ctx);
  return ciphertext_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x800,%eax
L16:
  sub    $0x1,%eax
  jne    L16
  mov    $0x20000,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  mov    $0x800,%edx
  jmp    L64
L59:
  sub    $0x1,%edx
  je     L23
L64:
  mov    $0x40,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x40,%eax
L36:
  sub    $0x1,%eax
  jne    L36
  jmp    L59
L23:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t = 0;
  float result = 0;
  float A[2048];
  float B[(2048 * 64)];
  float out1[(2048 * 64)];
  float out2[(2048 * 64)];
  for (i = 0; i < 2048; i++) {
    A[i] = 0.6;
  }
  for (i = 0; i < (2048 * 64); i++) {
    B[i] = i % 6 + i;
  }
#pragma scop
#pragma species kernel A[0 : BASE - 1] | element ^ B[0 : SIZE - 1] | chunk(0 : TILE - 1)->out1[0 : SIZE - 1] | chunk(0 : TILE - 1) ^ out2[0 : SIZE - 1] | chunk(0 : TILE - 1)
  for (i = 0; i < 2048; i++) {
    result = A[i];
    for (t = 0; t < 64; t++) {
      result = result + t * B[i * 64 + t];
    }
    for (t = 0; t < 64; t++) {
      out1[i * 64 + t] = result;
      out2[i * 64 + t] = -result;
    }
  }
#pragma species endkernel example3
#pragma endscop
  fflush(stdout);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t = 0;
  float result = 0;
  float A[2048];
  float B[(2048 * 64)];
  float out1[(2048 * 64)];
  float out2[(2048 * 64)];
  for (i = 0; i < 2048; i++) {
    A[i] = 0.6;
  }
  for (i = 0; i < (2048 * 64); i++) {
    B[i] = i % 6 + i;
  }
#pragma scop
#pragma species kernel A[0 : BASE - 1] | element ^ B[0 : SIZE - 1] | chunk(0 : TILE - 1)->out1[0 : SIZE - 1] | chunk(0 : TILE - 1) ^ out2[0 : SIZE - 1] | chunk(0 : TILE - 1)
  for (i = 0; i < 2048; i++) {
    result = A[i];
    for (t = 0; t < 64; t++) {
      result = result + t * B[i * 64 + t];
    }
    for (t = 0; t < 64; t++) {
      out1[i * 64 + t] = result;
      out2[i * 64 + t] = -result;
    }
  }
#pragma species endkernel example3
#pragma endscop
  fflush(stdout);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t = 0;
  float result = 0;
  float A[2048];
  float B[(2048 * 64)];
  float out1[(2048 * 64)];
  float out2[(2048 * 64)];
  for (i = 0; i < 2048; i++) {
    A[i] = 0.6;
  }
  for (i = 0; i < (2048 * 64); i++) {
    B[i] = i % 6 + i;
  }
#pragma scop
#pragma species kernel A[0 : BASE - 1] | element ^ B[0 : SIZE - 1] | chunk(0 : TILE - 1)->out1[0 : SIZE - 1] | chunk(0 : TILE - 1) ^ out2[0 : SIZE - 1] | chunk(0 : TILE - 1)
  for (i = 0; i < 2048; i++) {
    result = A[i];
    for (t = 0; t < 64; t++) {
      result = result + t * B[i * 64 + t];
    }
    for (t = 0; t < 64; t++) {
      out1[i * 64 + t] = result;
      out2[i * 64 + t] = -result;
    }
  }
#pragma species endkernel example3
#pragma endscop
  fflush(stdout);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x0,%eax
  jmp    L8
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L38:
  subl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L38
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *str_rtrim(char *src) {
  int i;
  if (src[0] == 0)
    return NULL;
  for (i = strlen(src) - 1; src[i] == ' '; i--)
    ;
  src[i + 1] = 0;
  return src;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rtrim>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x20,(%rbx,%rdx,1)
  jne    L4
  sub    $0x2,%eax
  cltq
L13:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbx,%rax,1)
  je     L13
L4:
  movb   $0x0,0x1(%rbx,%rdx,1)
  mov    %rbx,%rax
  pop    %rbx
  ret
L18:
  ret
```

assistant: ```c
char *str_rtrim(char *src) {
  int i;
  if (src[0] == 0)
    return NULL;
  for (i = strlen(src) - 1; src[i] == ' '; i--)
    ;
  src[i + 1] = 0;
  return src;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_rtrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x20,(%rbx,%rdx,1)
  jne    L16
  sub    $0x2,%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbx,%rax,1)
  je     L23
L16:
  mov    %rbx,%rax
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *str_rtrim(char *src) {
  int i;
  if (src[0] == 0)
    return NULL;
  for (i = strlen(src) - 1; src[i] == ' '; i--)
    ;
  src[i + 1] = 0;
  return src;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_rtrim>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L28
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x20,(%rbx,%rdx,1)
  jne    L0
  sub    $0x2,%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rbx,%rax,1)
  je     L26
L0:
  mov    %rbx,%rax
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  ret
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *str_rtrim(char *src) {
  int i;
  if (src[0] == 0)
    return NULL;
  for (i = strlen(src) - 1; src[i] == ' '; i--)
    ;
  src[i + 1] = 0;
  return src;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<int_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string

tool: D0: %d

assistant: ```c
char *int_to_string(int a) {
  char *str = malloc(sizeof(char) * 15);
  sprintf(str, "%d", a);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_to_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %d

assistant: ```c
char *int_to_string(int a) {
  char *str = malloc(sizeof(char) * 15);
  sprintf(str, "%d", a);
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_to_string>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0xf,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: %d

assistant: ```c
char *int_to_string(int a) {
  char *str = malloc(sizeof(char) * 15);
  sprintf(str, "%d", a);
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<int_to_string>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0xf,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13d,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
char *int_to_string(int a) {
  char *str = malloc(sizeof(char) * 15);
  sprintf(str, "%d", a);
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L3:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L23
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L3
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L17
  mov    -0x18(%rbp),%rax
  jmp    L9
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L9:
  leave
  ret
```

assistant: ```c
char *split(char *text, char seperator) {
  int i;
  int pos = -1;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == seperator) {
      pos = i;
      i = strlen(text) + 1;
    }
  }
  if (pos == -1)
    return text;
  text[pos] = 0;
  return &(text[pos + 1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0xffffffff,%r13d
  mov    $0x0,%ebx
  jmp    L0
L11:
  add    $0x1,%ebx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L32
  movslq %ebx,%rax
  cmp    %r12b,0x0(%rbp,%rax,1)
  jne    L11
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%r13d
  lea    0x1(%rax),%ebx
  jmp    L11
L32:
  mov    %rbp,%rax
  cmp    $0xffffffff,%r13d
  je     L42
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  lea    0x1(%rbp,%r13,1),%rax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *split(char *text, char seperator) {
  int i;
  int pos = -1;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == seperator) {
      pos = i;
      i = strlen(text) + 1;
    }
  }
  if (pos == -1)
    return text;
  text[pos] = 0;
  return &(text[pos + 1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<split>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L41
  nop
L8:
  add    $0x1,%ebx
L41:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L42
  movslq %ebx,%rax
  cmp    %r13b,0x0(%rbp,%rax,1)
  jne    L8
  mov    %rbp,%rdi
  movslq %ebx,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  jmp    L8
  nopl   0x0(%rax)
L42:
  mov    %rbp,%rax
  cmp    $0xffffffff,%r12d
  je     L19
  movb   $0x0,0x0(%rbp,%r12,1)
  lea    0x1(%rbp,%r12,1),%rax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *split(char *text, char seperator) {
  int i;
  int pos = -1;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == seperator) {
      pos = i;
      i = strlen(text) + 1;
    }
  }
  if (pos == -1)
    return text;
  text[pos] = 0;
  return &(text[pos + 1]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    $0xffffffffffffffff,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L10
  nop
L32:
  add    $0x1,%ebx
L10:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L15
  movslq %ebx,%rax
  cmp    %r13b,0x0(%rbp,%rax,1)
  jne    L32
  mov    %rbp,%rdi
  movslq %ebx,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  jmp    L32
  nopl   0x0(%rax)
L15:
  mov    %rbp,%rax
  cmp    $0xffffffff,%r12d
  je     L24
  movb   $0x0,0x0(%rbp,%r12,1)
  lea    0x1(%rbp,%r12,1),%rax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *split(char *text, char seperator) {
  int i;
  int pos = -1;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == seperator) {
      pos = i;
      i = strlen(text) + 1;
    }
  }
  if (pos == -1)
    return text;
  text[pos] = 0;
  return &(text[pos + 1]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_user_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  lea    D43(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L20:
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L38
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D43
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D32
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D67
type_guessed: string

tool: D20: r

tool: D43: data/user.db

tool: D1: error	:	files %s can not open !


tool: D32: data/select.db

tool: D15: read user num from %s ...


tool: D67: user num are %d 


assistant: ```c
int read_user_sum() {
  int sum;
  FILE *fpin;
  fpin = fopen("data/user.db", "r");
  if (fpin == NULL) {
    printf("error	:	files %s can not open !\n", "data/user.db");
    exit(1);
  }
  printf("read user num from %s ...\n", "data/select.db");
  for (sum = 0; !feof(fpin);) {
    if ('\n' == fgetc(fpin))
      sum++;
  }
  fclose(fpin);
  printf("user num are %d \n", sum);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_user_sum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
L6:
  lea    D12(%rip),%rsi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebp
  jmp    L17
L23:
  lea    D26(%rip),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L6
L35:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebp
L17:
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L35
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    %ebp,%esi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D58
type: string
name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D57
type: string

tool: D5: r

tool: D26: data/user.db

tool: D12: data/select.db

tool: D58: read user num from %s ...


tool: D19: error	:	files %s can not open !


tool: D57: user num are %d 


assistant: ```c
int read_user_sum() {
  int sum;
  FILE *fpin;
  fpin = fopen("data/user.db", "r");
  if (fpin == NULL) {
    printf("error	:	files %s can not open !\n", "data/user.db");
    exit(1);
  }
  printf("read user num from %s ...\n", "data/select.db");
  for (sum = 0; !feof(fpin);) {
    if ('\n' == fgetc(fpin))
      sum++;
  }
  fclose(fpin);
  printf("user num are %d \n", sum);
  return sum;
}
```