ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be_uint32_write>:
  endbr64
  mov    %esi,%eax
  mov    %sil,0x3(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x1(%rdi)
  shr    $0x18,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void be_uint32_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[3] = (unsigned char)(v & 0xFF);
  ptr8[2] = (unsigned char)((v >> 8) & 0xFF);
  ptr8[1] = (unsigned char)((v >> 16) & 0xFF);
  ptr8[0] = (unsigned char)((v >> 24) & 0xFF);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<be_uint32_write>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void be_uint32_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[3] = (unsigned char)(v & 0xFF);
  ptr8[2] = (unsigned char)((v >> 8) & 0xFF);
  ptr8[1] = (unsigned char)((v >> 16) & 0xFF);
  ptr8[0] = (unsigned char)((v >> 24) & 0xFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<be_uint32_write>:
  endbr64
  bswap  %esi
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void be_uint32_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[3] = (unsigned char)(v & 0xFF);
  ptr8[2] = (unsigned char)((v >> 8) & 0xFF);
  ptr8[1] = (unsigned char)((v >> 16) & 0xFF);
  ptr8[0] = (unsigned char)((v >> 24) & 0xFF);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_double_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L54:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L21:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L33:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L43:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L54
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D16
type: string

tool: D10: x = %d


tool: D17: #%d	

tool: D16: %.2e 

assistant: ```c
void print_double_array(double ***array, int dim1, int dim2, int dim3) {
  int i, j, k;
  for (i = 0; i < dim1; i++) {
    printf("x = %d\n", i);
    for (j = 0; j < dim2; j++) {
      printf("#%d\t", j);
      for (k = 0; k < dim3; k++) {
        printf("%.2e ", array[i][j][k]);
      }
      printf("\n");
    }
    printf("\n");
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_double_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %ecx,0x10(%rsp)
  test   %esi,%esi
  jle    L25
  mov    %rdi,%r12
  lea    -0x1(%rcx),%eax
  lea    0x8(,%rax,8),%r14
  movl   $0x0,0x14(%rsp)
  lea    D5(%rip),%r13
L16:
  mov    0x14(%rsp),%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L13
  mov    %eax,%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r15d
L44:
  mov    %r15d,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x10(%rsp)
  jle    L34
  lea    0x0(,%r15,8),%rbp
  mov    $0x0,%ebx
L0:
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L0
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  jne    L44
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  add    $0x8,%r12
  cmp    %eax,0x18(%rsp)
  jne    L16
L25:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D5: %.2e 

tool: D26: x = %d


tool: D2: #%d	

assistant: ```c
void print_double_array(double ***array, int dim1, int dim2, int dim3) {
  int i, j, k;
  for (i = 0; i < dim1; i++) {
    printf("x = %d\n", i);
    for (j = 0; j < dim2; j++) {
      printf("#%d\t", j);
      for (k = 0; k < dim3; k++) {
        printf("%.2e ", array[i][j][k]);
      }
      printf("\n");
    }
    printf("\n");
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_double_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %ecx,0x10(%rsp)
  test   %esi,%esi
  jle    L40
  lea    -0x1(%rcx),%eax
  movl   $0x0,0x14(%rsp)
  mov    %rdi,%rbp
  lea    D28(%rip),%r12
  lea    0x8(,%rax,8),%r13
  movslq %edx,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L38:
  mov    0x14(%rsp),%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L48
  xor    %r14d,%r14d
  nopl   (%rax)
L35:
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L11
  lea    0x0(,%r14,8),%rbx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L1:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%rax
  movsd  (%rax,%r15,1),%xmm0
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %r15,%r13
  jne    L1
L11:
  mov    $0xa,%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    0x8(%rsp),%r14
  jne    L35
L48:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x18(%rsp)
  jne    L38
L40:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D28
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D28: %.2e 

tool: D17: x = %d


tool: D1: #%d	

assistant: ```c
void print_double_array(double ***array, int dim1, int dim2, int dim3) {
  int i, j, k;
  for (i = 0; i < dim1; i++) {
    printf("x = %d\n", i);
    for (j = 0; j < dim2; j++) {
      printf("#%d\t", j);
      for (k = 0; k < dim3; k++) {
        printf("%.2e ", array[i][j][k]);
      }
      printf("\n");
    }
    printf("\n");
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_double_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %ecx,0x10(%rsp)
  test   %esi,%esi
  jle    L40
  lea    -0x1(%rcx),%eax
  movl   $0x0,0x14(%rsp)
  mov    %rdi,%rbp
  lea    D1(%rip),%r12
  lea    0x8(,%rax,8),%r13
  movslq %edx,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L39:
  mov    0x14(%rsp),%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L23
  xor    %r14d,%r14d
  nopl   (%rax)
L28:
  mov    %r14d,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L12
  lea    0x0(,%r14,8),%rbx
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L14:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,1),%rax
  movsd  (%rax,%r15,1),%xmm0
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %r15,%r13
  jne    L14
L12:
  mov    $0xa,%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %r14,0x8(%rsp)
  jne    L28
L23:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x18(%rsp)
  jne    L39
L40:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D7
data_type: string

tool: D1: %.2e 

tool: D12: x = %d


tool: D7: #%d	

assistant: ```c
void print_double_array(double ***array, int dim1, int dim2, int dim3) {
  int i, j, k;
  for (i = 0; i < dim1; i++) {
    printf("x = %d\n", i);
    for (j = 0; j < dim2; j++) {
      printf("#%d\t", j);
      for (k = 0; k < dim3; k++) {
        printf("%.2e ", array[i][j][k]);
      }
      printf("\n");
    }
    printf("\n");
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <reset_score@plt>
  mov    $0x0,%eax
  call   <init_board@plt>
  mov    $0x0,%eax
  call   <draw_board@plt>
  mov    $0x0,%eax
  call   <draw_player@plt>
  mov    $0x0,%eax
  call   <draw_ghosts@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init() {
  reset_score();
  init_board();
  draw_board();
  draw_player();
  draw_ghosts();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <reset_score@plt>
  mov    $0x0,%eax
  call   <init_board@plt>
  mov    $0x0,%eax
  call   <draw_board@plt>
  mov    $0x0,%eax
  call   <draw_player@plt>
  mov    $0x0,%eax
  call   <draw_ghosts@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init() {
  reset_score();
  init_board();
  draw_board();
  draw_player();
  draw_ghosts();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reset_score@plt>
  xor    %eax,%eax
  call   <init_board@plt>
  xor    %eax,%eax
  call   <draw_board@plt>
  xor    %eax,%eax
  call   <draw_player@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <draw_ghosts@plt>
```

assistant: ```c
void init() {
  reset_score();
  init_board();
  draw_board();
  draw_player();
  draw_ghosts();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <reset_score@plt>
  xor    %eax,%eax
  call   <init_board@plt>
  xor    %eax,%eax
  call   <draw_board@plt>
  xor    %eax,%eax
  call   <draw_player@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <draw_ghosts@plt>
```

assistant: ```c
void init() {
  reset_score();
  init_board();
  draw_board();
  draw_player();
  draw_ghosts();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L19:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L8
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <unget_char@plt>
  jmp    L24
L8:
  movsbl -0x14(%rbp),%eax
  sub    $0x30,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <get_char@plt>
  mov    %al,-0x14(%rbp)
  jmp    L19
L24:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: f64

tool: D0: 10

assistant: ```c
double read_decimal(char c) {
  double d = 0;
  double n = 10;
  for (;;) {
    if (!isdigit(c)) {
      unget_char(c);
      break;
    }
    d += (c - '0') / n;
    n *= 10;
    c = get_char();
  }
  return d;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_decimal>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%eax
  movsd  D2(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  pxor   %xmm4,%xmm4
  movsd  %xmm4,(%rsp)
  jmp    L1
L19:
  sub    $0x30,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  mulsd  D2(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    $0x0,%eax
  call   <get_char@plt>
L1:
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L19
  mov    %ebx,%edi
  call   <unget_char@plt>
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: f64

tool: D2: 10

assistant: ```c
double read_decimal(char c) {
  double d = 0;
  double n = 10;
  for (;;) {
    if (!isdigit(c)) {
      unget_char(c);
      break;
    }
    d += (c - '0') / n;
    n *= 10;
    c = get_char();
  }
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_decimal>:
  endbr64
  push   %rbp
  pxor   %xmm4,%xmm4
  mov    %edi,%eax
  sub    $0x10,%rsp
  mov    D2(%rip),%rdx
  movsd  %xmm4,(%rsp)
  mov    %rdx,0x8(%rsp)
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L3:
  sub    $0x30,%ebp
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  cvtsi2sd %ebp,%xmm0
  movsd  D2(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  divsd  %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  call   <get_char@plt>
L16:
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L3
  mov    %ebp,%edi
  call   <unget_char@plt>
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: f64

tool: D2: 10

assistant: ```c
double read_decimal(char c) {
  double d = 0;
  double n = 10;
  for (;;) {
    if (!isdigit(c)) {
      unget_char(c);
      break;
    }
    d += (c - '0') / n;
    n *= 10;
    c = get_char();
  }
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_decimal>:
  endbr64
  push   %rbp
  pxor   %xmm4,%xmm4
  mov    %edi,%eax
  sub    $0x10,%rsp
  mov    D10(%rip),%rdx
  movsd  %xmm4,(%rsp)
  mov    %rdx,0x8(%rsp)
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L3:
  sub    $0x30,%ebp
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  xor    %eax,%eax
  cvtsi2sd %ebp,%xmm0
  movsd  D10(%rip),%xmm2
  mulsd  %xmm1,%xmm2
  divsd  %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  call   <get_char@plt>
L7:
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L3
  mov    %ebp,%edi
  call   <unget_char@plt>
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_infered: f64

tool: D10: 10

assistant: ```c
double read_decimal(char c) {
  double d = 0;
  double n = 10;
  for (;;) {
    if (!isdigit(c)) {
      unget_char(c);
      break;
    }
    d += (c - '0') / n;
    n *= 10;
    c = get_char();
  }
  return d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<energenie_on>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <output_1@plt>
  mov    $0x0,%eax
  call   <output_0@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void energenie_on() {
  output_1();
  output_0();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<energenie_on>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <output_1@plt>
  mov    $0x0,%eax
  call   <output_0@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void energenie_on() {
  output_1();
  output_0();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<energenie_on>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <output_1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <output_0@plt>
```

assistant: ```c
void energenie_on() {
  output_1();
  output_0();
}
```
user: Translate the below assembly code into C programming language:

```asm
<energenie_on>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <output_1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <output_0@plt>
```

assistant: ```c
void energenie_on() {
  output_1();
  output_0();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lowercase_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L35
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jbe    L20
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  ja     L20
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L20:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lowercase_string(unsigned char *string) {
  for (; *string; string++)
    if (*string >= 'A' && *string <= 'Z')
      *string = *string - 'A' + 'a';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lowercase_string>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L31
L21:
  ret
L38:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
L31:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L38
  add    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L38
```

assistant: ```c
void lowercase_string(unsigned char *string) {
  for (; *string; string++)
    if (*string >= 'A' && *string <= 'Z')
      *string = *string - 'A' + 'a';
}
```
user: Translate the below assembly code into C programming language:

```asm
<lowercase_string>:
  endbr64
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L7
  add    $0x20,%eax
  mov    %al,(%rdi)
L7:
  add    $0x1,%rdi
L26:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  ret
```

assistant: ```c
void lowercase_string(unsigned char *string) {
  for (; *string; string++)
    if (*string >= 'A' && *string <= 'Z')
      *string = *string - 'A' + 'a';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lowercase_string>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L34
  add    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L19
L20:
  ret
```

assistant: ```c
void lowercase_string(unsigned char *string) {
  for (; *string; string++)
    if (*string >= 'A' && *string <= 'Z')
      *string = *string - 'A' + 'a';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0xc(%rbp)
  mov    %esi,-0x10(%rbp)
  mov    $0x1,%ebx
  jmp    L0
L17:
  imul   -0xc(%rbp),%ebx
  subl   $0x1,-0x10(%rbp)
L0:
  cmpl   $0x0,-0x10(%rbp)
  jne    L17
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int pwr(int a, int b) {
  register int t = 1;
  for (; b; b--)
    t = t * a;
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pwr>:
  endbr64
  test   %esi,%esi
  je     L1
  mov    $0x1,%eax
L6:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L6
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int pwr(int a, int b) {
  register int t = 1;
  for (; b; b--)
    t = t * a;
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pwr>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L9
  nopl   (%rax)
L0:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L0
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
int pwr(int a, int b) {
  register int t = 1;
  for (; b; b--)
    t = t * a;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pwr>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L18
  nopl   (%rax)
L6:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L6
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
int pwr(int a, int b) {
  register int t = 1;
  for (; b; b--)
    t = t * a;
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BSP_Time_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400fe65c,%eax
  mov    (%rax),%eax
  mov    $0x400fe65c,%edx
  or     $0x20,%eax
  mov    %eax,(%rdx)
  nop
L8:
  mov    $0x400fea5c,%eax
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L8
  mov    $0x4004f00c,%eax
  mov    (%rax),%eax
  mov    $0x4004f00c,%edx
  and    $0xfe,%ah
  mov    %eax,(%rdx)
  mov    $0x4004f000,%eax
  movl   $0x4,(%rax)
  mov    $0x4004f008,%eax
  movl   $0x2,(%rax)
  mov    $0x4004f02c,%eax
  movl   $0xffffffff,(%rax)
  mov    $0x4004f03c,%eax
  movl   $0x4f,(%rax)
  mov    $0x4004f024,%eax
  movl   $0x100,(%rax)
  mov    $0x4004f018,%eax
  mov    (%rax),%eax
  mov    $0x4004f018,%edx
  and    $0xfe,%ah
  mov    %eax,(%rdx)
  mov    $0x4004f00c,%eax
  mov    (%rax),%eax
  mov    $0x4004f00c,%edx
  or     $0x1,%ah
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EndCritical@plt>
  nop
  leave
  ret
```

assistant: ```c
void BSP_Time_Init(void) {
  long sr;
  (*((volatile uint32_t *)0x400FE65C)) |= 0x20;
  while (((*((volatile uint32_t *)0x400FEA5C)) & 0x20) == 0) {
  };
  (*((volatile uint32_t *)0x4004F00C)) &= ~0x00000100;
  (*((volatile uint32_t *)0x4004F000)) = 0x00000004;
  (*((volatile uint32_t *)0x4004F008)) = 0x00000002;
  (*((volatile uint32_t *)0x4004F02C)) = 0xFFFFFFFF;
  (*((volatile uint32_t *)0x4004F03C)) = 79;
  (*((volatile uint32_t *)0x4004F024)) = 0x00000100;
  (*((volatile uint32_t *)0x4004F018)) &= ~0x00000100;
  (*((volatile uint32_t *)0x4004F00C)) |= 0x00000100;
  EndCritical(sr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<BSP_Time_Init>:
  endbr64
  sub    $0x8,%rsp
  mov    0x400fe65c,%eax
  or     $0x20,%eax
  mov    %eax,0x400fe65c
L4:
  mov    0x400fea5c,%eax
  test   $0x20,%al
  je     L4
  mov    0x4004f00c,%eax
  and    $0xfe,%ah
  mov    %eax,0x4004f00c
  movl   $0x4,0x4004f000
  movl   $0x2,0x4004f008
  movl   $0xffffffff,0x4004f02c
  movl   $0x4f,0x4004f03c
  movl   $0x100,0x4004f024
  mov    0x4004f018,%eax
  and    $0xfe,%ah
  mov    %eax,0x4004f018
  mov    0x4004f00c,%eax
  or     $0x1,%ah
  mov    %eax,0x4004f00c
  mov    $0x0,%edi
  call   <EndCritical@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BSP_Time_Init(void) {
  long sr;
  (*((volatile uint32_t *)0x400FE65C)) |= 0x20;
  while (((*((volatile uint32_t *)0x400FEA5C)) & 0x20) == 0) {
  };
  (*((volatile uint32_t *)0x4004F00C)) &= ~0x00000100;
  (*((volatile uint32_t *)0x4004F000)) = 0x00000004;
  (*((volatile uint32_t *)0x4004F008)) = 0x00000002;
  (*((volatile uint32_t *)0x4004F02C)) = 0xFFFFFFFF;
  (*((volatile uint32_t *)0x4004F03C)) = 79;
  (*((volatile uint32_t *)0x4004F024)) = 0x00000100;
  (*((volatile uint32_t *)0x4004F018)) &= ~0x00000100;
  (*((volatile uint32_t *)0x4004F00C)) |= 0x00000100;
  EndCritical(sr);
}
```