ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<load_chunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x5,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L24:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  lea    D58(%rip),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rcx,%rdx,1)
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jl     L24
  mov    -0x28(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L21
L5:
  mov    $0x0,%eax
  call   <my_rand@plt>
  imul   -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D58(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D58(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    D58(%rip),%rdx
  mov    %eax,(%rcx,%rdx,1)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  lea    D58(%rip),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rcx,%rdx,1)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D58(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  shl    $0x5,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <load@plt>
  subl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x0,-0xc(%rbp)
  jns    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void load_chunk(FILE *fh, unsigned char *ptr, unsigned long sz) {
  static int idx[(2048 * 1024) / 32];
  int i;
  sz /= 32;
  for (i = 0; i < (signed long)sz; i++)
    idx[i] = i;
  for (i = sz - 1; i >= 0; --i) {
    int x = (my_rand() * i) >> 16;
    int tmp = idx[i];
    idx[i] = idx[x];
    idx[x] = tmp;
    load(fh, ptr + 32 * idx[i], 32);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<load_chunk>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  shr    $0x5,%rbx
  je     L34
  mov    $0x0,%eax
  lea    D11(%rip),%rdx
L24:
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L24
L34:
  sub    $0x1,%ebx
  js     L29
  movslq %ebx,%rax
  lea    D11(%rip),%rdx
  lea    (%rdx,%rax,4),%rbp
  mov    %rdx,%r12
L35:
  mov    $0x0,%eax
  call   <my_rand@plt>
  imul   %ebx,%eax
  sar    $0x10,%eax
  mov    0x0(%rbp),%edx
  cltq
  mov    (%r12,%rax,4),%ecx
  mov    %ecx,0x0(%rbp)
  mov    %edx,(%r12,%rax,4)
  mov    0x0(%rbp),%esi
  shl    $0x5,%esi
  movslq %esi,%rsi
  add    %r14,%rsi
  mov    $0x20,%edx
  mov    %r13,%rdi
  call   <load@plt>
  sub    $0x4,%rbp
  sub    $0x1,%ebx
  jns    L35
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void load_chunk(FILE *fh, unsigned char *ptr, unsigned long sz) {
  static int idx[(2048 * 1024) / 32];
  int i;
  sz /= 32;
  for (i = 0; i < (signed long)sz; i++)
    idx[i] = i;
  for (i = sz - 1; i >= 0; --i) {
    int x = (my_rand() * i) >> 16;
    int tmp = idx[i];
    idx[i] = idx[x];
    idx[x] = tmp;
    load(fh, ptr + 32 * idx[i], 32);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<load_chunk>:
  endbr64
  shr    $0x5,%rdx
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  je     L17
  xor    %eax,%eax
  lea    D7(%rip),%r14
  nopl   0x0(%rax)
L21:
  mov    %eax,(%r14,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L21
L17:
  lea    -0x1(%rdx),%ebx
  test   %edx,%edx
  je     L22
  movslq %ebx,%rax
  lea    D7(%rip),%r14
  lea    (%r14,%rax,4),%r13
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  sub    $0x4,%r13
  call   <my_rand@plt>
  mov    0x4(%r13),%edx
  mov    %rbp,%rdi
  imul   %ebx,%eax
  sub    $0x1,%ebx
  sar    $0x10,%eax
  cltq
  mov    (%r14,%rax,4),%ecx
  mov    %ecx,0x4(%r13)
  mov    %edx,(%r14,%rax,4)
  mov    0x4(%r13),%esi
  mov    $0x20,%edx
  shl    $0x5,%esi
  movslq %esi,%rsi
  add    %r12,%rsi
  call   <load@plt>
  cmp    $0xffffffff,%ebx
  jne    L27
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void load_chunk(FILE *fh, unsigned char *ptr, unsigned long sz) {
  static int idx[(2048 * 1024) / 32];
  int i;
  sz /= 32;
  for (i = 0; i < (signed long)sz; i++)
    idx[i] = i;
  for (i = sz - 1; i >= 0; --i) {
    int x = (my_rand() * i) >> 16;
    int tmp = idx[i];
    idx[i] = idx[x];
    idx[x] = tmp;
    load(fh, ptr + 32 * idx[i], 32);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load_chunk>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  shr    $0x5,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  je     L82
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L86
  shr    $0x7,%rdx
  lea    D16(%rip),%rbp
  movdqa D20(%rip),%xmm0
  movdqa D40(%rip),%xmm2
  mov    %rdx,%rcx
  mov    %rbp,%rax
  shl    $0x4,%rcx
  add    %rbp,%rcx
  nopl   (%rax)
L11:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movaps %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L11
  shl    $0x2,%rdx
  mov    %edx,%eax
  cmp    %rdx,%rsi
  je     L82
L21:
  movslq %eax,%rdx
  lea    0x1(%rax),%ecx
  mov    %eax,0x0(%rbp,%rdx,4)
  movslq %ecx,%rdx
  cmp    %rdx,%rsi
  jle    L82
  add    $0x2,%eax
  mov    %ecx,0x0(%rbp,%rdx,4)
  movslq %eax,%rdx
  cmp    %rdx,%rsi
  jle    L82
  mov    %eax,0x0(%rbp,%rdx,4)
L82:
  lea    -0x1(%rsi),%ebx
  test   %esi,%esi
  je     L30
  movslq %ebx,%rax
  lea    D16(%rip),%rbp
  lea    0x0(%rbp,%rax,4),%r14
  nopl   0x0(%rax,%rax,1)
L65:
  xor    %eax,%eax
  sub    $0x4,%r14
  call   <my_rand@plt>
  mov    0x4(%r14),%edx
  mov    %r12,%rdi
  imul   %ebx,%eax
  sub    $0x1,%ebx
  sar    $0x10,%eax
  cltq
  mov    0x0(%rbp,%rax,4),%ecx
  mov    %ecx,0x4(%r14)
  mov    %edx,0x0(%rbp,%rax,4)
  mov    0x4(%r14),%esi
  mov    $0x20,%edx
  shl    $0x5,%esi
  movslq %esi,%rsi
  add    %r13,%rsi
  call   <load@plt>
  cmp    $0xffffffff,%ebx
  jne    L65
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L86:
  xor    %eax,%eax
  lea    D16(%rip),%rbp
  jmp    L21
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D40
type: byte[16]

tool: {"D20": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D40": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void load_chunk(FILE *fh, unsigned char *ptr, unsigned long sz) {
  static int idx[(2048 * 1024) / 32];
  int i;
  sz /= 32;
  for (i = 0; i < (signed long)sz; i++)
    idx[i] = i;
  for (i = sz - 1; i >= 0; --i) {
    int x = (my_rand() * i) >> 16;
    int tmp = idx[i];
    idx[i] = idx[x];
    idx[x] = tmp;
    load(fh, ptr + 32 * idx[i], 32);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__rawmemchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %al,-0x31(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L37
L50:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L74
  mov    -0x30(%rbp),%rax
  jmp    L22
L74:
  addq   $0x1,-0x30(%rbp)
L37:
  mov    -0x30(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L50
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x7efefeff,-0x20(%rbp)
  movzbl -0x31(%rbp),%edx
  movzbl -0x31(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  or     %rax,-0x18(%rbp)
L30:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  xor    -0x10(%rbp),%rax
  or     -0x20(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L30
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L70
  mov    -0x8(%rbp),%rax
  jmp    L22
L70:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L22
L6:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L77
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  jmp    L22
L77:
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L30
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
L22:
  pop    %rbp
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  je     L93
L42:
  cmp    %cl,(%rax)
  je     L87
  add    $0x1,%rax
  test   $0x7,%al
  jne    L42
L93:
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%r8
  shl    $0x10,%r8
  or     %rdx,%r8
L48:
  mov    %rax,%rdi
  add    $0x8,%rax
  mov    %r8,%rsi
  xor    -0x8(%rax),%rsi
  lea    0x7efefeff(%rsi),%rdx
  xor    %rsi,%rdx
  or     $0x7efefeff,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L48
  cmp    %cl,-0x8(%rax)
  je     L104
  cmp    %cl,-0x7(%rax)
  je     L36
  cmp    %cl,-0x6(%rax)
  je     L105
  cmp    %cl,-0x5(%rax)
  jne    L48
  add    $0x3,%rdi
  jmp    L104
L36:
  add    $0x1,%rdi
  jmp    L104
L105:
  add    $0x2,%rdi
  jmp    L104
L87:
  mov    %rax,%rdi
L104:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  jne    L23
  jmp    L45
  nop
L43:
  add    $0x1,%rax
  test   $0x7,%al
  je     L45
L23:
  cmp    %cl,(%rax)
  jne    L43
  mov    %rax,%r8
L20:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%rdi
  shl    $0x10,%rdi
  or     %rdx,%rdi
L81:
  mov    %rax,%r8
  lea    0x8(%rax),%rax
  mov    (%r8),%rsi
  xor    %rdi,%rsi
  lea    0x7efefeff(%rsi),%rdx
  xor    %rsi,%rdx
  or     $0x7efefeff,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L81
  cmp    %cl,-0x8(%rax)
  je     L20
  cmp    %cl,-0x7(%rax)
  je     L40
  cmp    %cl,-0x6(%rax)
  je     L4
  cmp    %cl,-0x5(%rax)
  jne    L81
  add    $0x3,%r8
  mov    %r8,%rax
  ret
L40:
  add    $0x1,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x2,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  jne    L47
  jmp    L13
  nop
L30:
  add    $0x1,%rax
  test   $0x7,%al
  je     L13
L47:
  cmp    %cl,(%rax)
  jne    L30
  mov    %rax,%r8
L70:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%rdi
  shl    $0x10,%rdi
  or     %rdx,%rdi
L0:
  mov    %rax,%r8
  lea    0x8(%rax),%rax
  mov    (%r8),%rsi
  xor    %rdi,%rsi
  lea    0x7efefeff(%rsi),%rdx
  xor    %rsi,%rdx
  or     $0x7efefeff,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L0
  cmp    %cl,-0x8(%rax)
  je     L70
  cmp    %cl,-0x7(%rax)
  je     L56
  cmp    %cl,-0x6(%rax)
  je     L35
  cmp    %cl,-0x5(%rax)
  jne    L0
  add    $0x3,%r8
  mov    %r8,%rax
  ret
L56:
  add    $0x1,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x2,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
void *__rawmemchr(s, c_in) const void *s;
int c_in;
{
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  if (sizeof(longword) != 4 && sizeof(longword) != 8)
    abort();
  magic_bits = 0x7efefeff;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jle    L17
  mov    $0x0,%eax
  jmp    L14
L17:
  mov    $0x1,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int getFloat(char *s, float *y) {
  char *endptr;
  *y = (float)strtod(s, &endptr);
  if (*endptr > 0)
    return (0);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getFloat>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getFloat(char *s, float *y) {
  char *endptr;
  *y = (float)strtod(s, &endptr);
  if (*endptr > 0)
    return (0);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getFloat>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    (%rsp),%rax
  movss  %xmm0,(%rbx)
  cmpb   $0x0,(%rax)
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getFloat(char *s, float *y) {
  char *endptr;
  *y = (float)strtod(s, &endptr);
  if (*endptr > 0)
    return (0);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getFloat>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    (%rsp),%rax
  movss  %xmm0,(%rbx)
  cmpb   $0x0,(%rax)
  setle  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getFloat(char *s, float *y) {
  char *endptr;
  *y = (float)strtod(s, &endptr);
  if (*endptr > 0)
    return (0);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<QCBOR_Int64ToUInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jg     L2
  cmpq   $0x0,-0x8(%rbp)
  jns    L7
L2:
  mov    $0xffffffff,%eax
  jmp    L23
L7:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int QCBOR_Int64ToUInt32(int64_t src, uint32_t *dest) {
  if (src > UINT32_MAX || src < 0) {
    return -1;
  } else {
    *dest = (uint32_t)src;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<QCBOR_Int64ToUInt32>:
  endbr64
  mov    D7(%rip),%rax
  cmp    %rdi,(%rax)
  jl     L11
  test   %rdi,%rdi
  js     L11
  mov    %rdi,(%rsi)
  mov    $0x0,%eax
  ret
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int QCBOR_Int64ToUInt32(int64_t src, uint32_t *dest) {
  if (src > UINT32_MAX || src < 0) {
    return -1;
  } else {
    *dest = (uint32_t)src;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<QCBOR_Int64ToUInt32>:
  endbr64
  mov    D7(%rip),%rax
  cmp    %rdi,(%rax)
  jl     L2
  test   %rdi,%rdi
  js     L2
  mov    %rdi,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int QCBOR_Int64ToUInt32(int64_t src, uint32_t *dest) {
  if (src > UINT32_MAX || src < 0) {
    return -1;
  } else {
    *dest = (uint32_t)src;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<QCBOR_Int64ToUInt32>:
  endbr64
  mov    D5(%rip),%rax
  cmp    %rdi,(%rax)
  jl     L5
  test   %rdi,%rdi
  js     L5
  mov    %rdi,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int QCBOR_Int64ToUInt32(int64_t src, uint32_t *dest) {
  if (src > UINT32_MAX || src < 0) {
    return -1;
  } else {
    *dest = (uint32_t)src;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bin_setbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x24(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L55
L42:
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L18:
  mov    -0x24(%rbp),%eax
  sub    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x20(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  mov    -0x1c(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  not    %edx
  and    $0x7,%edx
  mov    $0x1,%edi
  mov    %edx,%ecx
  shl    %cl,%edi
  mov    %edi,%edx
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  or     %esi,%edx
  mov    %edx,(%rax)
L9:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  nop
L55:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bin_setbits(uint8_t *buf, int offset, uint8_t val, int len) {
  if (offset % 8 == 0 && len % 8 == 0) {
    buf[offset / 8] |= val;
  } else {
    int i;
    for (i = 0; i < len; i++) {
      if (val & (1 << (len - i - 1)))
        ((buf)[(offset + i) / 8] |= 1 << (7 - ((offset + i) & 7)));
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bin_setbits>:
  endbr64
  mov    %edx,%r8d
  mov    %esi,%eax
  or     %ecx,%eax
  test   $0x7,%al
  je     L15
  lea    -0x1(%rcx),%eax
  lea    -0x1(%rsi,%rcx,1),%r9d
  mov    $0x1,%esi
  test   %ecx,%ecx
  jg     L37
  ret
L15:
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  or     %edx,(%rdi,%rax,4)
  ret
L23:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  je     L43
L37:
  bt     %eax,%r8d
  jae    L23
  mov    %r9d,%ecx
  sub    %eax,%ecx
  lea    0x7(%rcx),%edx
  cmovns %ecx,%edx
  sar    $0x3,%edx
  movslq %edx,%rdx
  not    %ecx
  and    $0x7,%ecx
  mov    %esi,%r10d
  shl    %cl,%r10d
  or     %r10d,(%rdi,%rdx,4)
  jmp    L23
L43:
  ret
```

assistant: ```c
void bin_setbits(uint8_t *buf, int offset, uint8_t val, int len) {
  if (offset % 8 == 0 && len % 8 == 0) {
    buf[offset / 8] |= val;
  } else {
    int i;
    for (i = 0; i < len; i++) {
      if (val & (1 << (len - i - 1)))
        ((buf)[(offset + i) / 8] |= 1 << (7 - ((offset + i) & 7)));
    }
  }
}
```