ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D49(%rip),%eax
  add    $0x5,%eax
  mov    %eax,D3(%rip)
  mov    D3(%rip),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D3(%rip),%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: increment returns %d


assistant: ```c
int increment() {
  static int i = 42;
  i += 5;
  printf("increment returns %d\n", i);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<increment>:
  endbr64
  sub    $0x8,%rsp
  mov    D20(%rip),%eax
  lea    0x5(%rax),%esi
  mov    %esi,D28(%rip)
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    D28(%rip),%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string

tool: D28: increment returns %d


assistant: ```c
int increment() {
  static int i = 42;
  i += 5;
  printf("increment returns %d\n", i);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TA_GetVersionString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D6: 0.4.0 (Mar 18 2022 06:18:21)

assistant: ```c
const char *TA_GetVersionString(void) {
  return "0"
         "."
         "4"
         "."
         "0"
         " ("
         "Mar 18 2022"
         " "
         "06:18:21"
         ")";
}
```
user: What is the c source code of the assembly code below:

```asm
<TA_GetVersionString>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: 0.4.0 (Mar 18 2022 06:18:21)

assistant: ```c
const char *TA_GetVersionString(void) {
  return "0"
         "."
         "4"
         "."
         "0"
         " ("
         "Mar 18 2022"
         " "
         "06:18:21"
         ")";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TA_GetVersionString>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: 0.4.0 (Mar 18 2022 06:18:21)

assistant: ```c
const char *TA_GetVersionString(void) {
  return "0"
         "."
         "4"
         "."
         "0"
         " ("
         "Mar 18 2022"
         " "
         "06:18:21"
         ")";
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<TA_GetVersionString>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: 0.4.0 (Mar 18 2022 06:18:21)

assistant: ```c
const char *TA_GetVersionString(void) {
  return "0"
         "."
         "4"
         "."
         "0"
         " ("
         "Mar 18 2022"
         " "
         "06:18:21"
         ")";
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<escojer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L36
  ucomiss %xmm1,%xmm0
  jne    L36
  movl   $0x1,-0x4(%rbp)
  jmp    L42
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
  addl   $0x1,-0xc(%rbp)
L36:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L33
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int escojer(int cl, float **dat, float **mat, int fc[]) {
  int f = 0;
  for (int i = 0; i < fc[0]; i++) {
    if (dat[i][0] == cl) {
      for (int j = 1; j < fc[1]; j++)
        mat[f][j - 1] = dat[i][j];
      f++;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<escojer>:
  endbr64
  mov    %rsi,%r8
  mov    %rdx,%r11
  cmpl   $0x0,(%rcx)
  jle    L56
  mov    $0x0,%esi
  mov    $0x0,%r10d
  pxor   %xmm1,%xmm1
  cvtsi2ss %edi,%xmm1
  jmp    L45
L78:
  add    $0x1,%r10d
L10:
  add    $0x1,%rsi
  cmp    %esi,(%rcx)
  jle    L56
L45:
  mov    (%r8,%rsi,8),%rax
  ucomiss (%rax),%xmm1
  jp     L10
  jne    L10
  cmpl   $0x1,0x4(%rcx)
  jle    L78
  movslq %r10d,%rax
  lea    (%r11,%rax,8),%r9
  mov    $0x4,%eax
  mov    $0x1,%edx
L71:
  mov    (%r8,%rsi,8),%rdi
  movss  (%rdi,%rax,1),%xmm0
  mov    (%r9),%rdi
  movss  %xmm0,-0x4(%rdi,%rax,1)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,0x4(%rcx)
  jg     L71
  jmp    L78
L56:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int escojer(int cl, float **dat, float **mat, int fc[]) {
  int f = 0;
  for (int i = 0; i < fc[0]; i++) {
    if (dat[i][0] == cl) {
      for (int j = 1; j < fc[1]; j++)
        mat[f][j - 1] = dat[i][j];
      f++;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<escojer>:
  endbr64
  mov    (%rcx),%eax
  mov    %rdx,%r11
  mov    %rcx,%r10
  test   %eax,%eax
  jle    L15
  pxor   %xmm1,%xmm1
  sub    $0x1,%eax
  xor    %r9d,%r9d
  cvtsi2ss %edi,%xmm1
  lea    0x8(%rsi,%rax,8),%r8
  jmp    L36
  nopl   (%rax)
L35:
  add    $0x8,%rsi
  cmp    %r8,%rsi
  je     L15
L36:
  mov    (%rsi),%rdx
  ucomiss (%rdx),%xmm1
  jp     L35
  jne    L35
  movslq 0x4(%r10),%rcx
  cmp    $0x1,%ecx
  jle    L63
  movslq %r9d,%rax
  mov    (%r11,%rax,8),%rdi
  mov    $0x1,%eax
L28:
  movss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,-0x4(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L28
L63:
  add    $0x8,%rsi
  add    $0x1,%r9d
  cmp    %r8,%rsi
  jne    L36
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int escojer(int cl, float **dat, float **mat, int fc[]) {
  int f = 0;
  for (int i = 0; i < fc[0]; i++) {
    if (dat[i][0] == cl) {
      for (int j = 1; j < fc[1]; j++)
        mat[f][j - 1] = dat[i][j];
      f++;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<escojer>:
  endbr64
  mov    (%rcx),%eax
  test   %eax,%eax
  jle    L137
  pxor   %xmm0,%xmm0
  sub    $0x1,%eax
  push   %r12
  mov    %rdx,%r11
  push   %rbp
  cvtsi2ss %edi,%xmm0
  lea    0x8(%rsi,%rax,8),%r9
  xor    %r10d,%r10d
  push   %rbx
  mov    %rcx,%rbx
  jmp    L81
  nopl   (%rax)
L145:
  add    $0x8,%rsi
  cmp    %r9,%rsi
  je     L67
L81:
  mov    (%rsi),%rdx
  ucomiss (%rdx),%xmm0
  jp     L145
  jne    L145
  mov    0x4(%rbx),%r8d
  cmp    $0x1,%r8d
  jle    L114
  movslq %r10d,%rax
  lea    0x8(%rdx),%rdi
  mov    (%r11,%rax,8),%rcx
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L105
  lea    -0x2(%r8),%eax
  cmp    $0x2,%eax
  jbe    L105
  lea    -0x1(%r8),%ebp
  xor    %eax,%eax
  mov    %ebp,%edi
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L70:
  movups 0x4(%rdx,%rax,1),%xmm2
  movups %xmm2,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L70
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  lea    0x1(%rax),%edi
  cmp    %eax,%ebp
  je     L114
  movslq %edi,%rdi
  lea    0x2(%rax),%r12d
  movss  (%rdx,%rdi,4),%xmm1
  lea    0x0(,%rdi,4),%rbp
  movss  %xmm1,-0x4(%rcx,%rbp,1)
  cmp    %r12d,%r8d
  jle    L114
  movss  0x4(%rdx,%rbp,1),%xmm1
  add    $0x3,%eax
  movss  %xmm1,(%rcx,%rdi,4)
  cmp    %eax,%r8d
  jle    L114
  movss  0x8(%rdx,%rbp,1),%xmm1
  movss  %xmm1,0x4(%rcx,%rbp,1)
L114:
  add    $0x8,%rsi
  add    $0x1,%r10d
  cmp    %r9,%rsi
  jne    L81
L67:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  mov    $0x1,%eax
  nopl   (%rax)
L38:
  movss  (%rdx,%rax,4),%xmm1
  movss  %xmm1,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L38
  jmp    L114
L137:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int escojer(int cl, float **dat, float **mat, int fc[]) {
  int f = 0;
  for (int i = 0; i < fc[0]; i++) {
    if (dat[i][0] == cl) {
      for (int j = 1; j < fc[1]; j++)
        mat[f][j - 1] = dat[i][j];
      f++;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prv_parse_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L82
L0:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L47
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L47
  cmpl   $0x0,-0x8(%rbp)
  jne    L45
  movl   $0xa,-0x8(%rbp)
  jmp    L22
L45:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L22:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L82
L47:
  mov    $0xffffffff,%eax
  jmp    L40
L82:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L69
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L0
L69:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L73
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L73:
  mov    -0xc(%rbp),%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int prv_parse_number(const char *uriString, size_t len, int *headP) {
  int result = 0;
  int mul = 0;
  int uriLength = len;
  while (*headP < uriLength && uriString[*headP] != '/') {
    if ('0' <= uriString[*headP] && uriString[*headP] <= '9') {
      if (0 == mul) {
        mul = 10;
      } else {
        result *= mul;
      }
      result += uriString[*headP] - '0';
    } else {
      return -1;
    }
    *headP += 1;
  }
  if (uriString[*headP] == '/')
    *headP += 1;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prv_parse_number>:
  endbr64
  mov    %rdi,%r10
  mov    (%rdx),%edi
  cmp    %edi,%esi
  jle    L104
  push   %rbx
  mov    %esi,%r11d
  movslq %edi,%rax
  mov    $0x0,%r8d
  mov    $0x0,%esi
  mov    $0xa,%ebx
  jmp    L111
L94:
  mov    %ebx,%r8d
L89:
  movsbl %cl,%ecx
  lea    -0x30(%rsi,%rcx,1),%esi
  lea    0x1(%r9),%edi
  mov    %edi,(%rdx)
  add    $0x1,%rax
  cmp    %eax,%r11d
  jle    L41
L111:
  mov    %eax,%r9d
  mov    %eax,%edi
  movzbl (%r10,%rax,1),%ecx
  cmp    $0x2f,%cl
  je     L64
  lea    -0x30(%rcx),%edi
  cmp    $0x9,%dil
  ja     L46
  test   %r8d,%r8d
  je     L94
  imul   %r8d,%esi
  jmp    L89
L41:
  movslq %edi,%rax
  cmpb   $0x2f,(%r10,%rax,1)
  je     L64
L115:
  mov    %esi,%eax
  pop    %rbx
  ret
L64:
  add    $0x1,%edi
  mov    %edi,(%rdx)
  jmp    L115
L46:
  mov    $0xffffffff,%esi
  jmp    L115
L104:
  mov    $0x0,%esi
  movslq %edi,%rax
  cmpb   $0x2f,(%r10,%rax,1)
  je     L86
L37:
  mov    %esi,%eax
  ret
L86:
  add    $0x1,%edi
  mov    %edi,(%rdx)
  jmp    L37
```

assistant: ```c
int prv_parse_number(const char *uriString, size_t len, int *headP) {
  int result = 0;
  int mul = 0;
  int uriLength = len;
  while (*headP < uriLength && uriString[*headP] != '/') {
    if ('0' <= uriString[*headP] && uriString[*headP] <= '9') {
      if (0 == mul) {
        mul = 10;
      } else {
        result *= mul;
      }
      result += uriString[*headP] - '0';
    } else {
      return -1;
    }
    *headP += 1;
  }
  if (uriString[*headP] == '/')
    *headP += 1;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prv_parse_number>:
  endbr64
  mov    %rdi,%r10
  mov    (%rdx),%edi
  mov    %esi,%r11d
  cmp    %edi,%esi
  jle    L61
  movslq %edi,%rcx
  xor    %esi,%esi
  xor    %r8d,%r8d
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L3:
  imul   %esi,%r8d
L67:
  sub    $0x30,%eax
  lea    0x1(%r9),%edi
  add    $0x1,%rcx
  movsbl %al,%eax
  mov    %edi,(%rdx)
  add    %eax,%r8d
  cmp    %ecx,%r11d
  jle    L43
L69:
  movzbl (%r10,%rcx,1),%eax
  mov    %ecx,%r9d
  mov    %ecx,%edi
  cmp    $0x2f,%al
  je     L52
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  ja     L79
  test   %esi,%esi
  jne    L3
  mov    $0xa,%esi
  jmp    L67
L61:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L43:
  movslq %edi,%rax
  cmpb   $0x2f,(%r10,%rax,1)
  je     L52
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%edi
  mov    %r8d,%eax
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
int prv_parse_number(const char *uriString, size_t len, int *headP) {
  int result = 0;
  int mul = 0;
  int uriLength = len;
  while (*headP < uriLength && uriString[*headP] != '/') {
    if ('0' <= uriString[*headP] && uriString[*headP] <= '9') {
      if (0 == mul) {
        mul = 10;
      } else {
        result *= mul;
      }
      result += uriString[*headP] - '0';
    } else {
      return -1;
    }
    *headP += 1;
  }
  if (uriString[*headP] == '/')
    *headP += 1;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prv_parse_number>:
  endbr64
  mov    %rdi,%r10
  mov    (%rdx),%edi
  mov    %rdx,%r9
  mov    %esi,%r11d
  cmp    %edi,%esi
  jle    L37
  movslq %edi,%rcx
  xor    %esi,%esi
  xor    %eax,%eax
  xchg   %ax,%ax
L65:
  movzbl (%r10,%rcx,1),%edx
  mov    %ecx,%r8d
  mov    %ecx,%edi
  cmp    $0x2f,%dl
  je     L36
L38:
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L88
  test   %esi,%esi
  je     L84
  imul   %esi,%eax
  movsbl %dl,%edx
  add    $0x1,%edi
  add    $0x1,%rcx
  mov    %edi,(%r9)
  add    %edx,%eax
  cmp    %ecx,%r11d
  jg     L65
L76:
  movslq %edi,%rdx
  cmpb   $0x2f,(%r10,%rdx,1)
  je     L36
  ret
  nopl   (%rax)
L84:
  movsbl %dl,%edx
  lea    0x1(%r8),%edi
  add    $0x1,%rcx
  mov    %edi,(%r9)
  add    %edx,%eax
  cmp    %ecx,%r11d
  jle    L76
  movzbl (%r10,%rcx,1),%edx
  mov    $0xa,%esi
  mov    %ecx,%r8d
  mov    %ecx,%edi
  cmp    $0x2f,%dl
  jne    L38
L36:
  add    $0x1,%edi
  mov    %edi,(%r9)
  ret
L88:
  mov    $0xffffffff,%eax
  ret
L37:
  xor    %eax,%eax
  jmp    L76
```

assistant: ```c
int prv_parse_number(const char *uriString, size_t len, int *headP) {
  int result = 0;
  int mul = 0;
  int uriLength = len;
  while (*headP < uriLength && uriString[*headP] != '/') {
    if ('0' <= uriString[*headP] && uriString[*headP] <= '9') {
      if (0 == mul) {
        mul = 10;
      } else {
        result *= mul;
      }
      result += uriString[*headP] - '0';
    } else {
      return -1;
    }
    *headP += 1;
  }
  if (uriString[*headP] == '/')
    *headP += 1;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <_vprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  int i;
  va_list arp;
  va_start(arp, fmt);
  i = _vprintf(INT_MAX, fmt, arp);
  va_end(arp);
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <_vprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  int i;
  va_list arp;
  va_start(arp, fmt);
  i = _vprintf(INT_MAX, fmt, arp);
  va_end(arp);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <_vprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  int i;
  va_list arp;
  va_start(arp, fmt);
  i = _vprintf(INT_MAX, fmt, arp);
  va_end(arp);
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <_vprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  int i;
  va_list arp;
  va_start(arp, fmt);
  i = _vprintf(INT_MAX, fmt, arp);
  va_end(arp);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exponent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl -0x30(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x0,-0x2c(%rbp)
  jns    L74
  negl   -0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x2d,(%rax)
  jmp    L26
L74:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x2b,(%rax)
L26:
  lea    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x9,-0x2c(%rbp)
  jle    L32
L57:
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  subq   $0x1,-0x18(%rbp)
  lea    0x30(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x9,-0x2c(%rbp)
  jg     L57
  mov    -0x2c(%rbp),%eax
  subq   $0x1,-0x18(%rbp)
  lea    0x30(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L35
L8:
  nop
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L35:
  lea    -0x10(%rbp),%rax
  add    $0x8,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L8
  jmp    L0
L32:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x30,(%rax)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  lea    0x30(%rcx),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
unsigned char *exponent(unsigned char *p, int exp, unsigned char fmtch) {
  unsigned char expbuf[8], *t;
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else {
    *p++ = '+';
  }
  t = expbuf + sizeof(expbuf);
  if (exp > 9) {
    do {
      *--t = exp % 10 + '0';
    } while ((exp /= 10) > 9);
    *--t = exp + '0';
    for (; t < expbuf + sizeof(expbuf); *p++ = *t++)
      continue;
  } else {
    *p++ = '0';
    *p++ = exp + '0';
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<exponent>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dl,(%rdi)
  lea    0x2(%rdi),%r8
  mov    $0x2b,%eax
  test   %esi,%esi
  js     L74
L30:
  mov    %al,0x1(%rdi)
  cmp    $0x9,%ecx
  jle    L12
  lea    0x8(%rsp),%rdx
L34:
  mov    %rdx,%r9
  sub    $0x1,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %ecx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx)
  mov    %ecx,%esi
  mov    %eax,%ecx
  cmp    $0x63,%esi
  jg     L34
  lea    -0x2(%r9),%rax
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdx)
  lea    0x8(%rsp),%rdx
  cmp    %rdx,%rax
  jae    L14
  mov    %r8,%rdx
  lea    0x8(%rsp),%rsi
L47:
  add    $0x1,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L47
  lea    0xa(%rsp),%rax
  sub    %r9,%rax
  add    %rax,%r8
  jmp    L14
L74:
  neg    %ecx
  mov    $0x2d,%eax
  jmp    L30
L12:
  movb   $0x30,(%r8)
  add    $0x30,%ecx
  mov    %cl,0x1(%r8)
  lea    0x2(%r8),%r8
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %r8,%rax
  add    $0x18,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *exponent(unsigned char *p, int exp, unsigned char fmtch) {
  unsigned char expbuf[8], *t;
  *p++ = fmtch;
  if (exp < 0) {
    exp = -exp;
    *p++ = '-';
  } else {
    *p++ = '+';
  }
  t = expbuf + sizeof(expbuf);
  if (exp > 9) {
    do {
      *--t = exp % 10 + '0';
    } while ((exp /= 10) > 9);
    *--t = exp + '0';
    for (; t < expbuf + sizeof(expbuf); *p++ = *t++)
      continue;
  } else {
    *p++ = '0';
    *p++ = exp + '0';
  }
  return p;
}
```