ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<char_entity>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  cmp    $0x3c,%ebx
  je     L22
  jg     L35
  cmp    $0x22,%ebx
  je     L15
  cmp    $0x26,%ebx
  jne    L27
  lea    D20(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x5,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L35:
  cmp    $0x3e,%ebx
  jne    L27
  lea    D23(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x4,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L15:
  lea    D34(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x6,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L22:
  lea    D27(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x4,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D34
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string

tool: D20: &amp;

tool: D23: &gt;

tool: D34: &quot;

tool: D27: &lt;

assistant: ```c
bool char_entity(char const **tag, size_t *ps, int c) {
  assert(tag != NULL);
  assert(ps != NULL);
  switch (c) {
  case '<':
    *tag = "&lt;";
    *ps = 4;
    return true;
  case '>':
    *tag = "&gt;";
    *ps = 4;
    return true;
  case '&':
    *tag = "&amp;";
    *ps = 5;
    return true;
  case '"':
    *tag = "&quot;";
    *ps = 6;
    return true;
  default:
    return false;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<char_entity>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  cmp    $0x3c,%ebx
  je     L22
  jg     L40
  cmp    $0x22,%ebx
  je     L23
  cmp    $0x26,%ebx
  jne    L2
  lea    D2(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x5,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L40:
  cmp    $0x3e,%ebx
  jne    L2
  lea    D26(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x4,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L23:
  lea    D27(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x6,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L22:
  lea    D38(%rip),%rax
  pop    %rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
  movq   $0x4,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D27
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string

tool: D2: &amp;

tool: D26: &gt;

tool: D27: &quot;

tool: D38: &lt;

assistant: ```c
bool char_entity(char const **tag, size_t *ps, int c) {
  assert(tag != NULL);
  assert(ps != NULL);
  switch (c) {
  case '<':
    *tag = "&lt;";
    *ps = 4;
    return true;
  case '>':
    *tag = "&gt;";
    *ps = 4;
    return true;
  case '&':
    *tag = "&amp;";
    *ps = 5;
    return true;
  case '"':
    *tag = "&quot;";
    *ps = 6;
    return true;
  default:
    return false;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x18(%rbp)
  movl   $0x7b,-0xc(%rbp)
  jmp    L23
L62:
  movl   $0x0,-0x14(%rbp)
  jmp    L34
L21:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L11
  movl   $0x0,-0x10(%rbp)
  jmp    L70
L38:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L48
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L12
L48:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L12:
  addl   $0x1,-0x10(%rbp)
L70:
  cmpl   $0x4,-0x10(%rbp)
  jle    L38
L11:
  addl   $0x1,-0x14(%rbp)
L34:
  cmpl   $0x4,-0x14(%rbp)
  jle    L21
  addl   $0x1,-0x18(%rbp)
L23:
  cmpl   $0x4,-0x18(%rbp)
  jle    L62
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: 


assistant: ```c
void main(void) {
  int i, j, k, a, b;
  int res;
  i = 0;
  res = 123;
  while (i < 5) {
    j = 0;
    while (j < 5) {
      k = (i + j) / 2;
      if (k > i) {
        a = 0;
        while (a < 5) {
          b = (a + k) / 2;
          if (b > j)
            res = res + b;
          else
            res = res + k;
          a = a + 1;
        }
      }
      j = j + 1;
    }
    i = i + 1;
  }
  print_int(res);
  print_string("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7b,%edi
  mov    $0x0,%r9d
  jmp    L55
L46:
  add    $0x1,%esi
  cmp    $0x5,%esi
  je     L24
L2:
  lea    (%rsi,%r9,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r9d,%edx
  jle    L46
  mov    %edx,%ecx
  lea    0x5(%rdx),%r10d
L45:
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  lea    (%rdi,%rax,1),%r8d
  add    %edx,%edi
  cmp    %esi,%eax
  cmovg  %r8d,%edi
  add    $0x1,%ecx
  cmp    %ecx,%r10d
  jne    L45
  jmp    L46
L24:
  add    $0x1,%r9d
  cmp    $0x5,%r9d
  je     L32
L55:
  mov    $0x0,%esi
  jmp    L2
L32:
  call   <print_int@plt>
  lea    D7(%rip),%rdi
  call   <print_string@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: 


assistant: ```c
void main(void) {
  int i, j, k, a, b;
  int res;
  i = 0;
  res = 123;
  while (i < 5) {
    j = 0;
    while (j < 5) {
      k = (i + j) / 2;
      if (k > i) {
        a = 0;
        while (a < 5) {
          b = (a + k) / 2;
          if (b > j)
            res = res + b;
          else
            res = res + k;
          a = a + 1;
        }
      }
      j = j + 1;
    }
    i = i + 1;
  }
  print_int(res);
  print_string("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7b,%edi
  xor    %r9d,%r9d
L38:
  xor    %ecx,%ecx
L39:
  lea    (%r9,%rcx,1),%eax
  sar    %eax
  cmp    %r9d,%eax
  jg     L20
L25:
  add    $0x1,%ecx
  cmp    $0x5,%ecx
  jne    L39
  add    $0x1,%r9d
  cmp    $0x5,%r9d
  jne    L38
  call   <print_int@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <print_string@plt>
  nopl   0x0(%rax)
L20:
  mov    %eax,%edx
  lea    0x5(%rax),%r10d
L17:
  mov    %edx,%esi
  sar    %esi
  lea    (%rdi,%rsi,1),%r8d
  add    %eax,%edi
  cmp    %ecx,%esi
  cmovg  %r8d,%edi
  add    $0x1,%edx
  cmp    %r10d,%edx
  jne    L17
  jmp    L25
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string

tool: D6: 


assistant: ```c
void main(void) {
  int i, j, k, a, b;
  int res;
  i = 0;
  res = 123;
  while (i < 5) {
    j = 0;
    while (j < 5) {
      k = (i + j) / 2;
      if (k > i) {
        a = 0;
        while (a < 5) {
          b = (a + k) / 2;
          if (b > j)
            res = res + b;
          else
            res = res + k;
          a = a + 1;
        }
      }
      j = j + 1;
    }
    i = i + 1;
  }
  print_int(res);
  print_string("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  xor    %edx,%edx
  mov    $0x7b,%edi
L133:
  mov    %edx,%r9d
  mov    %edx,%ecx
  mov    %edx,%eax
  add    $0x1,%edx
  mov    %edx,%r8d
  sar    %r9d
  sar    %r8d
  cmp    %ecx,%r9d
  jg     L128
  cmp    %ecx,%r8d
  jg     L139
L33:
  mov    %esi,%r8d
  sar    %r8d
  cmp    %ecx,%r8d
  jg     L88
L110:
  lea    0x3(%rax),%r8d
  sar    %r8d
  cmp    %ecx,%r8d
  jg     L118
L91:
  add    $0x4,%eax
  sar    %eax
  cmp    %ecx,%eax
  jg     L82
L43:
  add    $0x1,%esi
  cmp    $0x5,%edx
  jne    L133
  call   <print_int@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <print_string@plt>
  cs nopw 0x0(%rax,%rax,1)
L88:
  lea    0x3(%r8),%r9d
  lea    (%rdi,%r8,2),%edi
  sar    %r9d
  add    %r8d,%edi
  cmp    $0x3,%r9d
  jne    L31
  add    $0x3,%edi
L131:
  lea    0x4(%r8),%r9d
  add    %edi,%r8d
  add    $0x3,%edi
  sar    %r9d
  cmp    $0x3,%r9d
  cmovne %r8d,%edi
  lea    0x3(%rax),%r8d
  sar    %r8d
  cmp    %ecx,%r8d
  jle    L91
L118:
  add    $0x4,%eax
  lea    (%rdi,%r8,4),%edi
  sar    %eax
  add    %r8d,%edi
  cmp    %ecx,%eax
  jle    L43
  nopl   0x0(%rax,%rax,1)
L82:
  lea    (%rdi,%rax,4),%edi
  add    %eax,%edi
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L139:
  lea    (%rdi,%r8,2),%edi
  cmp    $0x1,%r8d
  je     L52
  add    $0x2,%edi
L81:
  add    $0x4,%r8d
  sar    %r8d
  lea    0x2(%rdi,%r8,1),%edi
  mov    %esi,%r8d
  sar    %r8d
  cmp    %ecx,%r8d
  jle    L110
  lea    (%rdi,%r8,2),%edi
  add    %r8d,%edi
  nop
L31:
  add    %r8d,%edi
  jmp    L131
  nopl   (%rax)
L128:
  lea    0x1(%rdi,%r9,1),%r10d
  lea    0x2(%r9),%edi
  add    $0x4,%r9d
  sar    %edi
  sar    %r9d
  lea    0x2(%r10,%rdi,1),%edi
  add    %r9d,%edi
  cmp    %ecx,%r8d
  jle    L33
  lea    (%rdi,%r8,2),%edi
  nop
L52:
  add    %r8d,%edi
  jmp    L81
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: 


assistant: ```c
void main(void) {
  int i, j, k, a, b;
  int res;
  i = 0;
  res = 123;
  while (i < 5) {
    j = 0;
    while (j < 5) {
      k = (i + j) / 2;
      if (k > i) {
        a = 0;
        while (a < 5) {
          b = (a + k) / 2;
          if (b > j)
            res = res + b;
          else
            res = res + k;
          a = a + 1;
        }
      }
      j = j + 1;
    }
    i = i + 1;
  }
  print_int(res);
  print_string("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xd,-0x14(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <doubler@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L40
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L1
L40:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L1:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <doubler@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L56
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L22
L56:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  lea    -0x14(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <doubler@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L8
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L38
L8:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <doubler@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L4
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L44
L4:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D75
type_guessed: string
name: unpack_data
arguments: data_tag: D61
type_guessed: string
name: unpack_data
arguments: data_tag: D48
type_guessed: string

tool: D75: Failed doubling NULL

tool: D61: Doubling NULL gave us: %d


tool: D48: Doubling %d gave us: %d


assistant: ```c
int main() {
  int ret_value;
  int value = 13;
  int result;
  ret_value = doubler(NULL, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(NULL, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(&value, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  ret_value = doubler(&value, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xd,(%rsp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <doubler@plt>
  test   %eax,%eax
  je     L65
  lea    D21(%rip),%rdi
  call   <puts@plt>
L28:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edi
  call   <doubler@plt>
  test   %eax,%eax
  je     L72
  lea    D21(%rip),%rdi
  call   <puts@plt>
L66:
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <doubler@plt>
  test   %eax,%eax
  je     L70
  lea    D21(%rip),%rdi
  call   <puts@plt>
L57:
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <doubler@plt>
  test   %eax,%eax
  je     L61
  lea    D21(%rip),%rdi
  call   <puts@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L65:
  mov    0x4(%rsp),%esi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L72:
  mov    0x4(%rsp),%esi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L66
L70:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L61:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_infered: string
name: retrieve_data
arguments: tag: D69
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string

tool: D21: Failed doubling NULL

tool: D69: Doubling NULL gave us: %d


tool: D39: Doubling %d gave us: %d


assistant: ```c
int main() {
  int ret_value;
  int value = 13;
  int result;
  ret_value = doubler(NULL, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(NULL, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(&value, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  ret_value = doubler(&value, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %edi,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xd,(%rsp)
  call   <doubler@plt>
  test   %eax,%eax
  je     L48
  lea    D20(%rip),%rdi
  call   <puts@plt>
L50:
  lea    0x4(%rsp),%r12
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <doubler@plt>
  test   %eax,%eax
  je     L46
  lea    D20(%rip),%rdi
  call   <puts@plt>
L41:
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <doubler@plt>
  test   %eax,%eax
  je     L63
  lea    D20(%rip),%rdi
  call   <puts@plt>
L23:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <doubler@plt>
  test   %eax,%eax
  je     L18
  lea    D20(%rip),%rdi
  call   <puts@plt>
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L48:
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L50
L18:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L63:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D79(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
L46:
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L41
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D20
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string
name: parse_data
arguments: tag: D79
type_infered: string

tool: D20: Failed doubling NULL

tool: D26: Doubling NULL gave us: %d


tool: D79: Doubling %d gave us: %d


assistant: ```c
int main() {
  int ret_value;
  int value = 13;
  int result;
  ret_value = doubler(NULL, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(NULL, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(&value, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  ret_value = doubler(&value, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %edi,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xd,(%rsp)
  call   <doubler@plt>
  test   %eax,%eax
  je     L39
  lea    D15(%rip),%rdi
  call   <puts@plt>
L74:
  lea    0x4(%rsp),%r12
  xor    %edi,%edi
  mov    %r12,%rsi
  call   <doubler@plt>
  test   %eax,%eax
  je     L73
  lea    D15(%rip),%rdi
  call   <puts@plt>
L36:
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <doubler@plt>
  test   %eax,%eax
  je     L27
  lea    D15(%rip),%rdi
  call   <puts@plt>
L38:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <doubler@plt>
  test   %eax,%eax
  je     L81
  lea    D15(%rip),%rdi
  call   <puts@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L74
L81:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L40
L27:
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L38
L73:
  mov    0x4(%rsp),%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L36
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type: string
name: read_data
arguments: data_label: D30
type: string
name: read_data
arguments: data_label: D59
type: string

tool: D15: Failed doubling NULL

tool: D30: Doubling NULL gave us: %d


tool: D59: Doubling %d gave us: %d


assistant: ```c
int main() {
  int ret_value;
  int value = 13;
  int result;
  ret_value = doubler(NULL, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(NULL, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling NULL gave us: %d\n", result);
  }
  ret_value = doubler(&value, NULL);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  ret_value = doubler(&value, &result);
  if (ret_value != 0) {
    printf("Failed doubling NULL\n");
  } else {
    printf("Doubling %d gave us: %d\n", value, result);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L10:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <xingenc_read_stat@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D15
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: f32[2]

tool: D15: [P %f]


tool: {"D7": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0;
  while (1) {
    if (xingenc_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  lea    D14(%rip),%rbp
  jmp    L10
L28:
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
L14:
  mov    D10(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
L10:
  mov    %rbx,%rdi
  call   <xingenc_read_stat@plt>
  test   %rax,%rax
  je     L28
  jmp    L14
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: f32[2]

tool: D14: [P %f]


tool: {"D10": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0;
  while (1) {
    if (xingenc_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  call   <xingenc_read_stat@plt>
  test   %rax,%rax
  jne    L10
  movsd  (%rsp),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
L10:
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <usleep@plt>
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: f32[2]

tool: D7: [P %f]


tool: {"D6": [0.0,9.9073486328125]}

assistant: ```c
int main(int argc, char **argv) {
  double current = 0;
  while (1) {
    if (xingenc_read_stat(&current) == 0)
      printf("[P %f]\n", current);
    usleep(0.5 * 1000000);
  }
}
```