ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_matrix>:
  endbr64
  mov    %rdi,%r11
  movslq %esi,%rdi
  cmp    %rdi,%rdx
  jl     L9
  mov    %rsi,%rax
  movslq %ecx,%r10
  neg    %rcx
  push   %rbp
  neg    %rax
  push   %rbx
  lea    0x1(%r8),%rsi
  mov    %rdx,%rbx
  lea    (%r9,%rax,8),%rbp
  lea    0x0(,%rcx,4),%r9
L6:
  cmp    %r10,%r8
  jl     L21
  mov    0x0(%rbp,%rdi,8),%rdx
  mov    (%r11,%rdi,8),%rcx
  mov    %r10,%rax
  add    %r9,%rdx
  nopl   0x0(%rax)
L33:
  movss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L33
L21:
  lea    0x1(%rdi),%rax
  cmp    %rdi,%rbx
  je     L41
  mov    %rax,%rdi
  jmp    L6
  nopl   0x0(%rax)
L41:
  pop    %rbx
  pop    %rbp
  ret
L9:
  ret
```

assistant: ```c
void extract_matrix(float **src, long nrl, long nrh, long ncl, long nch, float **dst) {
  int i, j, ncol = nch - ncl + 1;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      dst[i - nrl][j - ncl] = src[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<extract_matrix>:
  endbr64
  push   %r15
  movslq %esi,%r10
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,-0x78(%rsp)
  cmp    %r10,%rdx
  jl     L35
  movslq %ecx,%rdx
  mov    %rcx,%rax
  mov    %r8,%rbp
  mov    %rdx,-0x18(%rsp)
  cmp    %rdx,%r8
  jl     L35
  neg    %rsi
  mov    %r8,%rcx
  lea    0x1(%r8),%r8
  mov    %rdi,%rbx
  sub    %rdx,%rcx
  lea    (%r9,%rsi,8),%r12
  mov    %rdx,%rsi
  sub    %rax,%rdx
  lea    0x0(,%rdx,4),%rdi
  mov    %rcx,-0x68(%rsp)
  lea    0x0(,%rsi,4),%rdx
  mov    %rdi,-0x70(%rsp)
  lea    0x1(%rcx),%rdi
  mov    %rsi,%rcx
  lea    0x4(,%rsi,4),%r15
  mov    %rdi,%r9
  mov    %rdi,-0x60(%rsp)
  and    $0xfffffffffffffffc,%rdi
  add    %rdi,%rcx
  mov    %rdx,-0x50(%rsp)
  lea    (%rax,%rdi,1),%edx
  shr    $0x2,%r9
  sub    %rax,%rcx
  movslq %edx,%r13
  mov    %rdi,-0x58(%rsp)
  shl    $0x4,%r9
  lea    0x0(,%rcx,4),%rsi
  lea    0x1(%rdx),%ecx
  add    $0x2,%edx
  shl    $0x2,%r13
  movslq %ecx,%rcx
  movslq %edx,%rdx
  mov    %rsi,-0x48(%rsp)
  mov    %rcx,-0x40(%rsp)
  lea    0x0(,%rcx,4),%r14
  sub    %rax,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    %rdx,-0x30(%rsp)
  mov    %rsi,-0x38(%rsp)
  lea    0x0(,%rdx,4),%rsi
  sub    %rax,%rdx
  neg    %rax
  mov    %rsi,-0x28(%rsp)
  shl    $0x2,%rax
  lea    0x0(,%rdx,4),%rsi
  mov    %rsi,-0x20(%rsp)
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L59:
  mov    -0x70(%rsp),%rax
  mov    (%r12,%r10,8),%rsi
  mov    %r10,%r11
  mov    (%rbx,%r10,8),%rcx
  lea    (%rsi,%rax,1),%rdx
  lea    (%rcx,%r15,1),%rdi
  mov    %rdx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L85
  cmpq   $0x2,-0x68(%rsp)
  jbe    L85
  mov    -0x50(%rsp),%rax
  lea    (%rcx,%rax,1),%rdi
  xor    %eax,%eax
  nop
L83:
  movups (%rdi,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L83
  mov    -0x58(%rsp),%rdi
  cmp    %rdi,-0x60(%rsp)
  je     L93
  movss  (%rcx,%r13,1),%xmm0
  mov    -0x48(%rsp),%rax
  movss  %xmm0,(%rsi,%rax,1)
  cmp    %rbp,-0x40(%rsp)
  jg     L93
  movss  (%rcx,%r14,1),%xmm0
  mov    -0x38(%rsp),%rax
  movss  %xmm0,(%rsi,%rax,1)
  cmp    -0x30(%rsp),%rbp
  jl     L93
  mov    -0x28(%rsp),%rax
  movss  (%rcx,%rax,1),%xmm0
  mov    -0x20(%rsp),%rax
  movss  %xmm0,(%rsi,%rax,1)
L93:
  add    $0x1,%r10
  cmp    -0x78(%rsp),%r11
  jne    L59
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L85:
  mov    -0x18(%rsp),%rax
  add    -0x10(%rsp),%rsi
  nopw   0x0(%rax,%rax,1)
L5:
  movss  (%rcx,%rax,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L5
  jmp    L93
```

assistant: ```c
void extract_matrix(float **src, long nrl, long nrh, long ncl, long nch, float **dst) {
  int i, j, ncol = nch - ncl + 1;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      dst[i - nrl][j - ncl] = src[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  jmp    L75
L58:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x1c(%rbp)
L75:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L58
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L21
L62:
  lea    -0x18(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <is_asymmetric@plt>
  test   %eax,%eax
  je     L66
  lea    -0x18(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <is_transitive@plt>
  test   %eax,%eax
  je     L5
  lea    -0x18(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <show_bit@plt>
  addq   $0x1,-0x10(%rbp)
  jmp    L56
L66:
  nop
  jmp    L56
L5:
  nop
L56:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  cmp    $0x1ffffff,%rax
  jbe    L62
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: %ld


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int i = 0; i < argc; ++i)
    printf("%s\n", argv[i]);
  unsigned long cnt = 0;
  for (unsigned long long a = 0; a < (1LL << (5 * 5)); ++a) {
    if (!is_asymmetric(&a, 5))
      continue;
    if (!is_transitive(&a, 5))
      continue;
    show_bit(&a, 5);
    ++cnt;
  }
  printf("%ld\n", cnt);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L29
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L73:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L73
L29:
  movq   $0x0,(%rsp)
  mov    $0x0,%ebp
  mov    %rsp,%rbx
  jmp    L32
L63:
  mov    (%rsp),%rax
  add    $0x1,%rax
  mov    %rax,(%rsp)
  cmp    $0x1ffffff,%rax
  ja     L17
L32:
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_asymmetric@plt>
  test   %eax,%eax
  je     L63
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_transitive@plt>
  test   %eax,%eax
  je     L63
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <show_bit@plt>
  add    $0x1,%rbp
  jmp    L63
L17:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string

tool: D3: %ld


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int i = 0; i < argc; ++i)
    printf("%s\n", argv[i]);
  unsigned long cnt = 0;
  for (unsigned long long a = 0; a < (1LL << (5 * 5)); ++a) {
    if (!is_asymmetric(&a, 5))
      continue;
    if (!is_transitive(&a, 5))
      continue;
    show_bit(&a, 5);
    ++cnt;
  }
  printf("%ld\n", cnt);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L36
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopl   0x0(%rax)
L28:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  jne    L28
L36:
  movq   $0x0,(%rsp)
  xor    %ebp,%ebp
  mov    %rsp,%rbx
  xchg   %ax,%ax
L10:
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_asymmetric@plt>
  test   %eax,%eax
  je     L19
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_transitive@plt>
  test   %eax,%eax
  je     L19
  mov    $0x5,%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <show_bit@plt>
L19:
  mov    (%rsp),%rax
  add    $0x1,%rax
  mov    %rax,(%rsp)
  cmp    $0x1ffffff,%rax
  jbe    L10
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %ld


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int i = 0; i < argc; ++i)
    printf("%s\n", argv[i]);
  unsigned long cnt = 0;
  for (unsigned long long a = 0; a < (1LL << (5 * 5)); ++a) {
    if (!is_asymmetric(&a, 5))
      continue;
    if (!is_transitive(&a, 5))
      continue;
    show_bit(&a, 5);
    ++cnt;
  }
  printf("%ld\n", cnt);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopl   0x0(%rax)
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbx,%rbp
  jne    L11
L6:
  movq   $0x0,(%rsp)
  xor    %ebp,%ebp
  mov    %rsp,%rbx
  xchg   %ax,%ax
L8:
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_asymmetric@plt>
  test   %eax,%eax
  je     L16
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <is_transitive@plt>
  test   %eax,%eax
  je     L16
  mov    $0x5,%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <show_bit@plt>
L16:
  mov    (%rsp),%rax
  add    $0x1,%rax
  mov    %rax,(%rsp)
  cmp    $0x1ffffff,%rax
  jbe    L8
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %ld


assistant: ```c
int main(int argc, char const *argv[]) {
  for (int i = 0; i < argc; ++i)
    printf("%s\n", argv[i]);
  unsigned long cnt = 0;
  for (unsigned long long a = 0; a < (1LL << (5 * 5)); ++a) {
    if (!is_asymmetric(&a, 5))
      continue;
    if (!is_transitive(&a, 5))
      continue;
    show_bit(&a, 5);
    ++cnt;
  }
  printf("%ld\n", cnt);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<p012>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x3,-0x1c(%rbp)
  movl   $0x1f4,-0x8(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  mov    %eax,%edi
  call   <triangle@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0x18(%rbp)
  jmp    L25
L14:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L39
  movl   $0x0,-0xc(%rbp)
L52:
  addl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L52
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x10(%rbp)
L39:
  addl   $0x1,-0x18(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L14
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L21
  jmp    L4
L21:
  nop
  mov    -0x4(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8: The first triangle number with over %d divisors (%d) is %d.

assistant: ```c
void p012() {
  int i = 3;
  int target = 500;
  int j, tri, tri_tmp, divisor, d_count;
  while (1) {
    tri = triangle(i++);
    tri_tmp = tri;
    divisor = 1;
    for (j = 2; j <= tri_tmp; j++) {
      if (tri_tmp % j == 0) {
        d_count = 0;
        do {
          d_count++;
          tri_tmp /= j;
        } while (tri_tmp % j == 0);
        divisor *= d_count + 1;
      }
    }
    if (divisor > target) {
      break;
    }
  }
  printf("The first triangle number with over %d divisors (%d) is %d.", target, divisor, tri);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<p012>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
  jmp    L78
L0:
  add    $0x1,%edi
  cmp    %edi,%esi
  jl     L12
L37:
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L0
L4:
  mov    %r8d,%r9d
  add    $0x1,%r8d
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L4
  add    $0x2,%r9d
  imul   %r9d,%r10d
  jmp    L0
L12:
  cmp    $0x1f4,%r10d
  jg     L8
L78:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <triangle@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  jle    L78
  mov    %eax,%esi
  mov    $0x1,%r10d
  mov    $0x2,%edi
  jmp    L37
L8:
  mov    %r10d,%edx
  mov    $0x1f4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: The first triangle number with over %d divisors (%d) is %d.

assistant: ```c
void p012() {
  int i = 3;
  int target = 500;
  int j, tri, tri_tmp, divisor, d_count;
  while (1) {
    tri = triangle(i++);
    tri_tmp = tri;
    divisor = 1;
    for (j = 2; j <= tri_tmp; j++) {
      if (tri_tmp % j == 0) {
        d_count = 0;
        do {
          d_count++;
          tri_tmp /= j;
        } while (tri_tmp % j == 0);
        divisor *= d_count + 1;
      }
    }
    if (divisor > target) {
      break;
    }
  }
  printf("The first triangle number with over %d divisors (%d) is %d.", target, divisor, tri);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p012>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <triangle@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  jle    L45
  mov    %eax,%esi
  mov    $0x1,%r10d
  mov    $0x2,%edi
  jmp    L62
L30:
  add    $0x1,%edi
  cmp    %edi,%esi
  jl     L63
L62:
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L30
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %esi,%eax
  mov    %r8d,%r9d
  add    $0x1,%r8d
  cltd
  idiv   %edi
  cltd
  mov    %eax,%esi
  idiv   %edi
  test   %edx,%edx
  je     L32
  add    $0x2,%r9d
  add    $0x1,%edi
  imul   %r9d,%r10d
  cmp    %edi,%esi
  jge    L62
L63:
  cmp    $0x1f4,%r10d
  jle    L45
  mov    %r10d,%edx
  mov    $0x1f4,%esi
  lea    D3(%rip),%rdi
  pop    %rbx
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: The first triangle number with over %d divisors (%d) is %d.

assistant: ```c
void p012() {
  int i = 3;
  int target = 500;
  int j, tri, tri_tmp, divisor, d_count;
  while (1) {
    tri = triangle(i++);
    tri_tmp = tri;
    divisor = 1;
    for (j = 2; j <= tri_tmp; j++) {
      if (tri_tmp % j == 0) {
        d_count = 0;
        do {
          d_count++;
          tri_tmp /= j;
        } while (tri_tmp % j == 0);
        divisor *= d_count + 1;
      }
    }
    if (divisor > target) {
      break;
    }
  }
  printf("The first triangle number with over %d divisors (%d) is %d.", target, divisor, tri);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<p012>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <triangle@plt>
  mov    %eax,%ecx
  cmp    $0x1,%eax
  jle    L18
  mov    %eax,%esi
  mov    $0x1,%r10d
  mov    $0x2,%edi
  jmp    L15
L2:
  add    $0x1,%edi
  cmp    %edi,%esi
  jl     L55
L15:
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L2
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %esi,%eax
  mov    %r8d,%r9d
  add    $0x1,%r8d
  cltd
  idiv   %edi
  cltd
  mov    %eax,%esi
  idiv   %edi
  test   %edx,%edx
  je     L24
  add    $0x2,%r9d
  add    $0x1,%edi
  imul   %r9d,%r10d
  cmp    %edi,%esi
  jge    L15
L55:
  cmp    $0x1f4,%r10d
  jle    L18
  mov    %r10d,%edx
  mov    $0x1f4,%esi
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: The first triangle number with over %d divisors (%d) is %d.

assistant: ```c
void p012() {
  int i = 3;
  int target = 500;
  int j, tri, tri_tmp, divisor, d_count;
  while (1) {
    tri = triangle(i++);
    tri_tmp = tri;
    divisor = 1;
    for (j = 2; j <= tri_tmp; j++) {
      if (tri_tmp % j == 0) {
        d_count = 0;
        do {
          d_count++;
          tri_tmp /= j;
        } while (tri_tmp % j == 0);
        divisor *= d_count + 1;
      }
    }
    if (divisor > target) {
      break;
    }
  }
  printf("The first triangle number with over %d divisors (%d) is %d.", target, divisor, tri);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_vfork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
pid_t _vfork() {
  errno = ENOTSUP;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_vfork>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t _vfork() {
  errno = ENOTSUP;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_vfork>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t _vfork() {
  errno = ENOTSUP;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_vfork>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
pid_t _vfork() {
  errno = ENOTSUP;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mcp_init@plt>
  mov    $0xaa,%ecx
  mov    $0x64,%edx
  mov    $0x35,%esi
  mov    $0x11,%edi
  call   <send_bytes@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <all_off@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  mcp_init();
  send_bytes(0x11, 53, 0144, 0b10101010);
  sleep(5);
  all_off();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mcp_init@plt>
  mov    $0xaa,%ecx
  mov    $0x64,%edx
  mov    $0x35,%esi
  mov    $0x11,%edi
  call   <send_bytes@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <all_off@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mcp_init();
  send_bytes(0x11, 53, 0144, 0b10101010);
  sleep(5);
  all_off();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mcp_init@plt>
  mov    $0xaa,%ecx
  mov    $0x64,%edx
  mov    $0x35,%esi
  mov    $0x11,%edi
  call   <send_bytes@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <all_off@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mcp_init();
  send_bytes(0x11, 53, 0144, 0b10101010);
  sleep(5);
  all_off();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mcp_init@plt>
  mov    $0xaa,%ecx
  mov    $0x64,%edx
  mov    $0x35,%esi
  mov    $0x11,%edi
  call   <send_bytes@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <all_off@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mcp_init();
  send_bytes(0x11, 53, 0144, 0b10101010);
  sleep(5);
  all_off();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<done>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  addq   $0x1,-0x18(%rbp)
  jmp    L5
L1:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L5:
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  mov    $0x3,%ebx
  jmp    L12
L16:
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x1,%ebx
L12:
  cmp    $0xe,%ebx
  jle    L16
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execl@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: No shell!


assistant: ```c
void done(const char *shell) {
  register int i;
  const char *sp = strrchr(shell, '/');
  if (sp)
    sp++;
  else
    sp = shell;
  setuid(getuid());
  for (i = 3; i < 15; i++)
    close(i);
  execl(shell, sp, 0);
  printf("No shell!\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<done>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%r12
  test   %rax,%rax
  cmove  %rbp,%r12
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  mov    $0x3,%ebx
L3:
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x1,%ebx
  cmp    $0xf,%ebx
  jne    L3
  mov    $0x0,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <execl@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: No shell!


assistant: ```c
void done(const char *shell) {
  register int i;
  const char *sp = strrchr(shell, '/');
  if (sp)
    sp++;
  else
    sp = shell;
  setuid(getuid());
  for (i = 3; i < 15; i++)
    close(i);
  execl(shell, sp, 0);
  printf("No shell!\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<done>:
  endbr64
  push   %r12
  mov    $0x2f,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x3,%ebx
  call   <strrchr@plt>
  test   %rax,%rax
  lea    0x1(%rax),%r12
  cmove  %rbp,%r12
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %eax,%edi
  call   <setuid@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    $0xf,%ebx
  jne    L5
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %edx,%edx
  call   <execl@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10f0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: No shell!


assistant: ```c
void done(const char *shell) {
  register int i;
  const char *sp = strrchr(shell, '/');
  if (sp)
    sp++;
  else
    sp = shell;
  setuid(getuid());
  for (i = 3; i < 15; i++)
    close(i);
  execl(shell, sp, 0);
  printf("No shell!\n");
  exit(0);
}
```