user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  lea    D37(%rip),%rbp
  call   <puts@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D107(%rip),%rdi
  call   <puts@plt>
  mov    $0xe,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D106(%rip),%rdi
  call   <puts@plt>
  mov    $0xc,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D34
data_type: string
name: retrieve_data
arguments: label: D37
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D42
data_type: string
name: retrieve_data
arguments: label: D84
data_type: string
name: retrieve_data
arguments: label: D107
data_type: string
name: retrieve_data
arguments: label: D106
data_type: string
name: retrieve_data
arguments: label: D85
data_type: string

tool: D34: b = a++;

tool: D37: b=%d



tool: D9: b = ++a;

tool: D39: b = a + (a++);

tool: D55: b = (a++) + a;

tool: D14: b = a + (++a);

tool: D42: b = (++a) + a;

tool: D84: b = (a++) + (a++);

tool: D107: b = (++a) + (++a);

tool: D106: b = (a++) + (++a);

tool: D85: b = (++a) + (a++);

assistant: ```c
int main(void) {
  int a, b;
  a = 5;
  b = a++;
  printf("b = a++;\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = ++a;
  printf("b = ++a;\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = a + (a++);
  printf("b = a + (a++);\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (a++) + a;
  printf("b = (a++) + a;\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = a + (++a);
  printf("b = a + (++a);\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (++a) + a;
  printf("b = (++a) + a;\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (a++) + (a++);
  printf("b = (a++) + (a++);\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (++a) + (++a);
  printf("b = (++a) + (++a);\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (a++) + (++a);
  printf("b = (a++) + (++a);\n");
  printf("b=%d\n\n", b);
  a = 5;
  b = (++a) + (a++);
  printf("b = (++a) + (a++);\n");
  printf("b=%d\n\n", b);
  return 0;
}
```