ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<rgb16tobgr24>:
  endbr64
  shr    %edx
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L0
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rcx),%eax
  add    $0x4,%rcx
  add    $0xc,%rsi
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0xf8,%edx
  mov    %edx,-0xc(%rsi)
  mov    %eax,%edx
  shl    $0x3,%eax
  sar    $0x3,%edx
  and    $0xff,%eax
  and    $0xfc,%edx
  mov    %edx,-0x8(%rsi)
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdi
  ja     L13
L0:
  ret
```

assistant: ```c
void rgb16tobgr24(const uint8_t *src, uint8_t *dst, unsigned int src_size) {
  const uint16_t *end;
  uint8_t *d = (uint8_t *)dst;
  const uint16_t *s = (const uint16_t *)src;
  end = s + src_size / 2;
  while (s < end) {
    register uint16_t bgr;
    bgr = *s++;
    *d++ = (bgr & 0xF800) >> 8;
    *d++ = (bgr & 0x7E0) >> 3;
    *d++ = (bgr & 0x1F) << 3;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rgb16tobgr24>:
  endbr64
  shr    %edx
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L13
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rcx),%eax
  add    $0x4,%rcx
  add    $0xc,%rsi
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0xf8,%edx
  mov    %edx,-0xc(%rsi)
  mov    %eax,%edx
  shl    $0x3,%eax
  sar    $0x3,%edx
  and    $0xff,%eax
  and    $0xfc,%edx
  mov    %edx,-0x8(%rsi)
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdi
  ja     L5
L13:
  ret
```

assistant: ```c
void rgb16tobgr24(const uint8_t *src, uint8_t *dst, unsigned int src_size) {
  const uint16_t *end;
  uint8_t *d = (uint8_t *)dst;
  const uint16_t *s = (const uint16_t *)src;
  end = s + src_size / 2;
  while (s < end) {
    register uint16_t bgr;
    bgr = *s++;
    *d++ = (bgr & 0xF800) >> 8;
    *d++ = (bgr & 0x7E0) >> 3;
    *d++ = (bgr & 0x1F) << 3;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<utimensat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <futimesat@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int utimensat(int dfd, const char *pathname, const struct timespec times[2], int flags) {
  struct timeval tvs[2];
  if (flags) {
  }
  tvs[0].tv_sec = times[0].tv_sec;
  tvs[0].tv_usec = times[0].tv_nsec / 1000;
  tvs[1].tv_sec = times[1].tv_sec;
  tvs[1].tv_usec = times[1].tv_nsec / 1000;
  return futimesat(dfd, pathname, tvs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utimensat>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x4(%rdx),%eax
  mov    %eax,0x4(%rsp)
  mov    (%rdx),%ecx
  movslq %ecx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,(%rsp)
  mov    0xc(%rdx),%eax
  mov    %eax,0xc(%rsp)
  mov    0x8(%rdx),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x8(%rsp)
  mov    %rsp,%rdx
  call   <futimesat@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utimensat(int dfd, const char *pathname, const struct timespec times[2], int flags) {
  struct timeval tvs[2];
  if (flags) {
  }
  tvs[0].tv_sec = times[0].tv_sec;
  tvs[0].tv_usec = times[0].tv_nsec / 1000;
  tvs[1].tv_sec = times[1].tv_sec;
  tvs[1].tv_usec = times[1].tv_nsec / 1000;
  return futimesat(dfd, pathname, tvs);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utimensat>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    0x4(%rdx),%eax
  mov    %eax,0x4(%rsp)
  movslq (%rdx),%rax
  mov    %rax,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  mov    %eax,(%rsp)
  mov    0xc(%rdx),%eax
  mov    %eax,0xc(%rsp)
  movslq 0x8(%rdx),%rax
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %rsp,%rdx
  mov    %eax,0x8(%rsp)
  call   <futimesat@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utimensat(int dfd, const char *pathname, const struct timespec times[2], int flags) {
  struct timeval tvs[2];
  if (flags) {
  }
  tvs[0].tv_sec = times[0].tv_sec;
  tvs[0].tv_usec = times[0].tv_nsec / 1000;
  tvs[1].tv_sec = times[1].tv_sec;
  tvs[1].tv_usec = times[1].tv_nsec / 1000;
  return futimesat(dfd, pathname, tvs);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utimensat>:
  endbr64
  sub    $0x28,%rsp
  movd   0xc(%rdx),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq (%rdx),%rax
  mov    %rax,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  movd   %eax,%xmm0
  movslq 0x8(%rdx),%rax
  mov    %rax,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  movd   %eax,%xmm1
  mov    0x4(%rdx),%eax
  mov    %rsp,%rdx
  punpckldq %xmm2,%xmm1
  movd   %eax,%xmm3
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <futimesat@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utimensat(int dfd, const char *pathname, const struct timespec times[2], int flags) {
  struct timeval tvs[2];
  if (flags) {
  }
  tvs[0].tv_sec = times[0].tv_sec;
  tvs[0].tv_usec = times[0].tv_nsec / 1000;
  tvs[1].tv_sec = times[1].tv_sec;
  tvs[1].tv_usec = times[1].tv_nsec / 1000;
  return futimesat(dfd, pathname, tvs);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *my_strdup(const char *str) {
  char *p = malloc(strlen(str) + 1);
  strcpy(p, str);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *my_strdup(const char *str) {
  char *p = malloc(strlen(str) + 1);
  strcpy(p, str);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strdup(const char *str) {
  char *p = malloc(strlen(str) + 1);
  strcpy(p, str);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *my_strdup(const char *str) {
  char *p = malloc(strlen(str) + 1);
  strcpy(p, str);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  add    $0x20,%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D27: please input a UpperCase char:

tool: D6: %c

tool: D14: %c


assistant: ```c
int main() {
  char a;
  printf("please input a UpperCase char:\n");
  scanf("%c", &a);
  printf("%c\n", a + 32);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x7(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  add    $0x20,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string

tool: D18: please input a UpperCase char:

tool: D13: %c

tool: D29: %c


assistant: ```c
int main() {
  char a;
  printf("please input a UpperCase char:\n");
  scanf("%c", &a);
  printf("%c\n", a + 32);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x7(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  add    $0x20,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string

tool: D19: please input a UpperCase char:

tool: D9: %c

tool: D17: %c


assistant: ```c
int main() {
  char a;
  printf("please input a UpperCase char:\n");
  scanf("%c", &a);
  printf("%c\n", a + 32);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x7(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x7(%rsp),%esi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  add    $0x20,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D6: please input a UpperCase char:

tool: D13: %c

tool: D8: %c


assistant: ```c
int main() {
  char a;
  printf("please input a UpperCase char:\n");
  scanf("%c", &a);
  printf("%c\n", a + 32);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_uchar_rule>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %al,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <add_rule@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: %u

assistant: ```c
struct rule *add_uchar_rule(struct qserver *server, char *key, unsigned char value) {
  char buf[24];
  sprintf(buf, "%u", (unsigned)value);
  return add_rule(server, key, buf, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_uchar_rule>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl %dl,%edx
  mov    %rsp,%r12
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <add_rule@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type: string

tool: D4: %u

assistant: ```c
struct rule *add_uchar_rule(struct qserver *server, char *key, unsigned char value) {
  char buf[24];
  sprintf(buf, "%u", (unsigned)value);
  return add_rule(server, key, buf, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_uchar_rule>:
  endbr64
  push   %r13
  movzbl %dl,%edx
  push   %r12
  mov    %rsi,%r12
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  xor    %ecx,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_rule@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: %u

assistant: ```c
struct rule *add_uchar_rule(struct qserver *server, char *key, unsigned char value) {
  char buf[24];
  sprintf(buf, "%u", (unsigned)value);
  return add_rule(server, key, buf, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<add_uchar_rule>:
  endbr64
  push   %r13
  movzbl %dl,%edx
  push   %r12
  mov    %rsi,%r12
  lea    D5(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  xor    %ecx,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_rule@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: %u

assistant: ```c
struct rule *add_uchar_rule(struct qserver *server, char *key, unsigned char value) {
  char buf[24];
  sprintf(buf, "%u", (unsigned)value);
  return add_rule(server, key, buf, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  cmpw   $0x3f,-0x4(%rbp)
  jne    L3
  movw   $0xffff,D16(%rip)
  jmp    L7
L3:
  movzwl -0x4(%rbp),%eax
  and    $0x1f,%eax
  mov    %ax,D21(%rip)
L7:
  lea    D21(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short *lit(unsigned short v, unsigned short is_a) {
  static unsigned short value;
  if (v == 0x003F)
    value = 0xFFFF;
  else
    value = v & 0x001F;
  return &value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lit>:
  endbr64
  mov    %edi,%eax
  and    $0x1f,%eax
  cmp    $0x3f,%di
  mov    $0xffffffff,%edx
  cmove  %edx,%eax
  mov    %ax,D12(%rip)
  lea    D12(%rip),%rax
  ret
```

assistant: ```c
unsigned short *lit(unsigned short v, unsigned short is_a) {
  static unsigned short value;
  if (v == 0x003F)
    value = 0xFFFF;
  else
    value = v & 0x001F;
  return &value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lit>:
  endbr64
  mov    %edi,%eax
  mov    $0xffffffff,%edx
  and    $0x1f,%eax
  cmp    $0x3f,%di
  cmove  %edx,%eax
  mov    %ax,D3(%rip)
  lea    D3(%rip),%rax
  ret
```

assistant: ```c
unsigned short *lit(unsigned short v, unsigned short is_a) {
  static unsigned short value;
  if (v == 0x003F)
    value = 0xFFFF;
  else
    value = v & 0x001F;
  return &value;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lit>:
  endbr64
  mov    %edi,%eax
  mov    $0xffffffff,%edx
  and    $0x1f,%eax
  cmp    $0x3f,%di
  cmove  %edx,%eax
  mov    %ax,D13(%rip)
  lea    D13(%rip),%rax
  ret
```

assistant: ```c
unsigned short *lit(unsigned short v, unsigned short is_a) {
  static unsigned short value;
  if (v == 0x003F)
    value = 0xFFFF;
  else
    value = v & 0x001F;
  return &value;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x1,-0x10(%rbp)
  jmp    L21
L2:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D6
type_infered: string

tool: D11: %llu

tool: D6: %llu


assistant: ```c
main() {
  unsigned long long num, n, j;
  scanf("%llu", &num);
  for (j = 1; j <= num; j++) {
    scanf("%llu", &n);
    printf("%llu\n", (n) * (n + 1) + 3 * n);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L13
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    D0(%rip),%r12
  lea    D10(%rip),%rbp
L17:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    0x4(%rax),%rsi
  imul   %rax,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jae    L17
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D0: %llu

tool: D10: %llu


assistant: ```c
main() {
  unsigned long long num, n, j;
  scanf("%llu", &num);
  for (j = 1; j <= num; j++) {
    scanf("%llu", &n);
    printf("%llu\n", (n) * (n + 1) + 3 * n);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L3
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    %r12,%rdi
  lea    0x4(%rax),%rsi
  imul   %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbx,0x8(%rsp)
  jae    L19
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D15: %llu

tool: D0: %llu


assistant: ```c
main() {
  unsigned long long num, n, j;
  scanf("%llu", &num);
  for (j = 1; j <= num; j++) {
    scanf("%llu", &n);
    printf("%llu\n", (n) * (n + 1) + 3 * n);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L24
  mov    $0x1,%ebx
  lea    0x10(%rsp),%r13
  lea    D8(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    %r12,%rdi
  lea    0x4(%rax),%rsi
  imul   %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbx,0x8(%rsp)
  jae    L5
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D8
type: string

tool: D6: %llu

tool: D8: %llu


assistant: ```c
main() {
  unsigned long long num, n, j;
  scanf("%llu", &num);
  for (j = 1; j <= num; j++) {
    scanf("%llu", &n);
    printf("%llu\n", (n) * (n + 1) + 3 * n);
  }
  return 0;
}
```