ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<rtbis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movl   $0x64,-0x2c(%rbp)
  mov    -0x40(%rbp),%rax
  movq   %rax,%xmm0
  call   <func@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <func@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L56
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L56:
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L37
  movsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  jmp    L53
L37:
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
L53:
  movl   $0x0,-0x30(%rbp)
  jmp    L65
L9:
  movsd  -0x28(%rbp),%xmm1
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <func@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L70
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L70:
  movsd  -0x28(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L54
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L80
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L80
L54:
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  jmp    L92
L80:
  addl   $0x1,-0x30(%rbp)
L65:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L92:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: f32[2]
name: extract_symbolic_data
arguments: data_tag: D3
data_type: qword
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string

tool: D16: root must be bracketed in rtbis


tool: {"D11": [0.0,1.75]}

tool: D3: 9223372036854775807

tool: D36: ** Error: Too many bisection in rtbis


assistant: ```c
double rtbis(double x1, double x2, double xacc) {
  int JMAX = 100;
  int j;
  double dx, f, fmid, xmid;
  double myval;
  fmid = func(x2);
  f = func(x1);
  if (f * fmid >= 0.) {
    printf("root must be bracketed in rtbis\n");
    exit(1);
  }
  if (f < 0.) {
    myval = x1;
    dx = x2 - x1;
  } else {
    myval = x2;
    dx = x1 - x2;
  }
  for (j = 0; j < JMAX; j++) {
    dx = dx * 5.e-1;
    xmid = myval + dx;
    fmid = func(xmid);
    if (fmid <= 0.)
      myval = xmid;
    if (fabs(dx) < xacc || fmid == 0.)
      return (myval);
  }
  printf("** Error: Too many bisection in rtbis\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtbis>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%r13
  movq   %xmm1,%rbx
  movq   %xmm2,%rbp
  movapd %xmm1,%xmm0
  call   <func@plt>
  movq   %xmm0,%r12
  movq   %r13,%xmm0
  call   <func@plt>
  movsd  %xmm0,(%rsp)
  movq   %r12,%xmm5
  mulsd  %xmm0,%xmm5
  comisd D53(%rip),%xmm5
  jae    L73
L40:
  pxor   %xmm0,%xmm0
  comisd (%rsp),%xmm0
  ja     L66
  movq   %r13,%xmm5
  movq   %rbx,%xmm4
  subsd  %xmm4,%xmm5
  movsd  %xmm5,0x8(%rsp)
  mov    %rbx,(%rsp)
L34:
  mov    $0x64,%ebx
L18:
  movsd  D30(%rip),%xmm3
  mulsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm4
  addsd  (%rsp),%xmm4
  movapd %xmm4,%xmm0
  movq   %xmm4,%r12
  call   <func@plt>
  movapd %xmm0,%xmm6
  pxor   %xmm7,%xmm7
  cmpnlesd %xmm7,%xmm6
  movapd %xmm6,%xmm1
  movsd  (%rsp),%xmm2
  andpd  %xmm6,%xmm2
  movq   %r12,%xmm6
  andnpd %xmm6,%xmm1
  movapd %xmm1,%xmm7
  orpd   %xmm2,%xmm7
  movsd  %xmm7,(%rsp)
  movsd  0x8(%rsp),%xmm1
  andpd  D16(%rip),%xmm1
  movq   %rbp,%xmm4
  comisd %xmm1,%xmm4
  ja     L78
  ucomisd D53(%rip),%xmm0
  jp     L21
  je     L78
L21:
  sub    $0x1,%ebx
  jne    L18
  lea    D44(%rip),%rdi
  call   <printf@plt>
L78:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L40
L66:
  movq   %rbx,%xmm5
  movq   %r13,%xmm6
  subsd  %xmm6,%xmm5
  movsd  %xmm5,0x8(%rsp)
  mov    %r13,(%rsp)
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_label: D53
datatype: f64
name: unpack_data
arguments: data_label: D30
datatype: byte[8]
name: unpack_data
arguments: data_label: D16
datatype: qword[2]
name: unpack_data
arguments: data_label: D44
datatype: string
name: unpack_data
arguments: data_label: D48
datatype: string

tool: D53: 0

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D16": [0x7fffffffffffffff,0x0000000000000000]}

tool: D44: ** Error: Too many bisection in rtbis


tool: D48: root must be bracketed in rtbis


assistant: ```c
double rtbis(double x1, double x2, double xacc) {
  int JMAX = 100;
  int j;
  double dx, f, fmid, xmid;
  double myval;
  fmid = func(x2);
  f = func(x1);
  if (f * fmid >= 0.) {
    printf("root must be bracketed in rtbis\n");
    exit(1);
  }
  if (f < 0.) {
    myval = x1;
    dx = x2 - x1;
  } else {
    myval = x2;
    dx = x1 - x2;
  }
  for (j = 0; j < JMAX; j++) {
    dx = dx * 5.e-1;
    xmid = myval + dx;
    fmid = func(xmid);
    if (fmid <= 0.)
      myval = xmid;
    if (fabs(dx) < xacc || fmid == 0.)
      return (myval);
  }
  printf("** Error: Too many bisection in rtbis\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<rtbis>:
  endbr64
  push   %r14
  movq   %xmm2,%r14
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <func@plt>
  movq   %xmm0,%rbx
  movsd  0x8(%rsp),%xmm0
  call   <func@plt>
  pxor   %xmm7,%xmm7
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm7,%xmm0
  jb     L21
  lea    D31(%rip),%rdi
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
L21:
  pxor   %xmm5,%xmm5
  comisd %xmm2,%xmm5
  ja     L12
  movsd  0x8(%rsp),%xmm2
  subsd  %xmm1,%xmm2
L10:
  mov    $0x64,%ebx
  jmp    L48
  nop
L45:
  ucomisd %xmm5,%xmm0
  jp     L74
  je     L27
L74:
  sub    $0x1,%ebx
  je     L47
L48:
  mulsd  D22(%rip),%xmm2
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm2,%xmm4
  movsd  %xmm2,0x18(%rsp)
  addsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <func@plt>
  pxor   %xmm5,%xmm5
  movq   %r14,%xmm6
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  0x8(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm2
  cmpnlesd %xmm5,%xmm3
  andpd  %xmm3,%xmm1
  andnpd %xmm4,%xmm3
  orpd   %xmm3,%xmm1
  movapd %xmm2,%xmm3
  andpd  D3(%rip),%xmm3
  comisd %xmm3,%xmm6
  jbe    L45
L27:
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movapd %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm1,%xmm2
  jmp    L10
L47:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: f32[2]
name: retrieve_data
arguments: data_tag: D3
type_guessed: qword[2]
name: retrieve_data
arguments: data_tag: D24
type_guessed: string

tool: D31: root must be bracketed in rtbis


tool: {"D22": [0.0,1.75]}

tool: {"D3": [0x7fffffffffffffff,0x0000000000000000]}

tool: D24: ** Error: Too many bisection in rtbis


assistant: ```c
double rtbis(double x1, double x2, double xacc) {
  int JMAX = 100;
  int j;
  double dx, f, fmid, xmid;
  double myval;
  fmid = func(x2);
  f = func(x1);
  if (f * fmid >= 0.) {
    printf("root must be bracketed in rtbis\n");
    exit(1);
  }
  if (f < 0.) {
    myval = x1;
    dx = x2 - x1;
  } else {
    myval = x2;
    dx = x1 - x2;
  }
  for (j = 0; j < JMAX; j++) {
    dx = dx * 5.e-1;
    xmid = myval + dx;
    fmid = func(xmid);
    if (fmid <= 0.)
      myval = xmid;
    if (fabs(dx) < xacc || fmid == 0.)
      return (myval);
  }
  printf("** Error: Too many bisection in rtbis\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rtbis>:
  endbr64
  push   %r14
  movq   %xmm2,%r14
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <func@plt>
  movq   %xmm0,%rbx
  movsd  0x8(%rsp),%xmm0
  call   <func@plt>
  pxor   %xmm7,%xmm7
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm7,%xmm0
  jb     L37
  lea    D14(%rip),%rdi
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
L37:
  pxor   %xmm5,%xmm5
  comisd %xmm2,%xmm5
  ja     L0
  movsd  0x8(%rsp),%xmm2
  subsd  %xmm1,%xmm2
L46:
  mov    $0x64,%ebx
  jmp    L78
  nop
L42:
  ucomisd %xmm5,%xmm0
  jp     L31
  je     L4
L31:
  sub    $0x1,%ebx
  je     L53
L78:
  mulsd  D20(%rip),%xmm2
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm2,%xmm4
  movsd  %xmm2,0x18(%rsp)
  addsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <func@plt>
  pxor   %xmm5,%xmm5
  movq   %r14,%xmm6
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  0x8(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm2
  cmpnlesd %xmm5,%xmm3
  andpd  %xmm3,%xmm1
  andnpd %xmm4,%xmm3
  orpd   %xmm3,%xmm1
  movapd %xmm2,%xmm3
  andpd  D2(%rip),%xmm3
  comisd %xmm3,%xmm6
  jbe    L42
L4:
  add    $0x28,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movapd %xmm1,%xmm2
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm1,%xmm2
  jmp    L46
L53:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  pop    %rbx
  movapd %xmm1,%xmm0
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D20
type: f32[2]
name: disassemble_data
arguments: data_label: D2
type: qword[2]
name: disassemble_data
arguments: data_label: D1
type: string

tool: D14: root must be bracketed in rtbis


tool: {"D20": [0.0,1.75]}

tool: {"D2": [0x7fffffffffffffff,0x0000000000000000]}

tool: D1: ** Error: Too many bisection in rtbis


assistant: ```c
double rtbis(double x1, double x2, double xacc) {
  int JMAX = 100;
  int j;
  double dx, f, fmid, xmid;
  double myval;
  fmid = func(x2);
  f = func(x1);
  if (f * fmid >= 0.) {
    printf("root must be bracketed in rtbis\n");
    exit(1);
  }
  if (f < 0.) {
    myval = x1;
    dx = x2 - x1;
  } else {
    myval = x2;
    dx = x1 - x2;
  }
  for (j = 0; j < JMAX; j++) {
    dx = dx * 5.e-1;
    xmid = myval + dx;
    fmid = func(xmid);
    if (fmid <= 0.)
      myval = xmid;
    if (fabs(dx) < xacc || fmid == 0.)
      return (myval);
  }
  printf("** Error: Too many bisection in rtbis\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L4:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <rho_util_hash_secondary@plt>
  leave
  ret
```

assistant: ```c
int hash(const char *key) {
  char *p = (char *)key;
  unsigned int h = 0;
  while (*p) {
    h = 31 * h + *p;
    ++p;
  }
  return rho_util_hash_secondary((int)h);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  mov    $0x0,%ecx
L12:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L20:
  mov    %ecx,%edi
  call   <rho_util_hash_secondary@plt>
  add    $0x8,%rsp
  ret
L22:
  mov    $0x0,%ecx
  jmp    L20
```

assistant: ```c
int hash(const char *key) {
  char *p = (char *)key;
  unsigned int h = 0;
  while (*p) {
    h = 31 * h + *p;
    ++p;
  }
  return rho_util_hash_secondary((int)h);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L5
  xor    %ecx,%ecx
  nopl   (%rax)
L12:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L12
  mov    %ecx,%edi
  jmp    1050 <rho_util_hash_secondary@plt>
  nopl   0x0(%rax)
L5:
  xor    %edi,%edi
  jmp    1050 <rho_util_hash_secondary@plt>
```

assistant: ```c
int hash(const char *key) {
  char *p = (char *)key;
  unsigned int h = 0;
  while (*p) {
    h = 31 * h + *p;
    ++p;
  }
  return rho_util_hash_secondary((int)h);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L1
  xor    %ecx,%ecx
  nopl   (%rax)
L17:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L17
  mov    %ecx,%edi
  jmp    1050 <rho_util_hash_secondary@plt>
  nopl   0x0(%rax)
L1:
  xor    %edi,%edi
  jmp    1050 <rho_util_hash_secondary@plt>
```

assistant: ```c
int hash(const char *key) {
  char *p = (char *)key;
  unsigned int h = 0;
  while (*p) {
    h = 31 * h + *p;
    ++p;
  }
  return rho_util_hash_secondary((int)h);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tabPrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D5: %2d, 

tool: D0: %2d](%d)


assistant: ```c
void tabPrint(int *tab, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++)
    printf("%2d, ", tab[i]);
  printf("%2d](%d)\n", tab[size - 1], size);
}
```
user: What is the c source code of the assembly code below:

```asm
<tabPrint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    $0x5b,%edi
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L7
  mov    %r14,%rbx
  lea    -0x2(%r13),%eax
  lea    0x4(%r14,%rax,4),%r12
  lea    D0(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
L7:
  movslq %r13d,%rax
  mov    -0x4(%r14,%rax,4),%esi
  mov    %r13d,%edx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string

tool: D0: %2d, 

tool: D12: %2d](%d)


assistant: ```c
void tabPrint(int *tab, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++)
    printf("%2d, ", tab[i]);
  printf("%2d](%d)\n", tab[size - 1], size);
}
```
user: What is the c source code of the assembly code below?

```asm
<tabPrint>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x5b,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L9
  lea    -0x2(%r13),%eax
  mov    %r14,%rbx
  lea    D16(%rip),%rbp
  lea    0x4(%r14,%rax,4),%r12
  nopl   (%rax)
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
L9:
  movslq %r13d,%rax
  pop    %rbx
  mov    %r13d,%edx
  pop    %rbp
  mov    -0x4(%r14,%rax,4),%esi
  pop    %r12
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string

tool: D16: %2d, 

tool: D17: %2d](%d)


assistant: ```c
void tabPrint(int *tab, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++)
    printf("%2d, ", tab[i]);
  printf("%2d](%d)\n", tab[size - 1], size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tabPrint>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    $0x5b,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  call   <putchar@plt>
  cmp    $0x1,%r13d
  jle    L1
  lea    -0x2(%r13),%eax
  mov    %r14,%rbx
  lea    D4(%rip),%rbp
  lea    0x4(%r14,%rax,4),%r12
  nopl   (%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L1:
  movslq %r13d,%rax
  pop    %rbx
  mov    %r13d,%edx
  pop    %rbp
  mov    -0x4(%r14,%rax,4),%esi
  pop    %r12
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D4: %2d, 

tool: D10: %2d](%d)


assistant: ```c
void tabPrint(int *tab, int size) {
  printf("[");
  for (int i = 0; i < size - 1; i++)
    printf("%2d, ", tab[i]);
  printf("%2d](%d)\n", tab[size - 1], size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_call_by_reference>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D15: swap_call_by_reference

tool: D21: [%s] : addresses : num1 = %p, num2 = %p


tool: D8: [%s] : *num1 = %d, *num2 = %d


assistant: ```c
void swap_call_by_reference(int *num1, int *num2) {
  int tmp = *num1;
  *num1 = *num2;
  *num2 = tmp;
  printf("[%s] : addresses : num1 = %p, num2 = %p\n", __func__, num1, num2);
  printf("[%s] : *num1 = %d, *num2 = %d\n", __func__, *num1, *num2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_call_by_reference>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D29(%rip),%r12
  mov    %r12,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%ecx
  mov    (%rbx),%edx
  mov    %r12,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string

tool: D29: swap_call_by_reference

tool: D26: [%s] : addresses : num1 = %p, num2 = %p


tool: D17: [%s] : *num1 = %d, *num2 = %d


assistant: ```c
void swap_call_by_reference(int *num1, int *num2) {
  int tmp = *num1;
  *num1 = *num2;
  *num2 = tmp;
  printf("[%s] : addresses : num1 = %p, num2 = %p\n", __func__, num1, num2);
  printf("[%s] : *num1 = %d, *num2 = %d\n", __func__, *num1, *num2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<swap_call_by_reference>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    %rsi,%rcx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%rbx
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %rdi,%rdx
  lea    D29(%rip),%rdi
  mov    %eax,(%rsi)
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%ecx
  mov    (%rbx),%edx
  mov    %r12,%rsi
  pop    %rbx
  lea    D20(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D20
data_type: string

tool: D6: swap_call_by_reference

tool: D29: [%s] : addresses : num1 = %p, num2 = %p


tool: D20: [%s] : *num1 = %d, *num2 = %d


assistant: ```c
void swap_call_by_reference(int *num1, int *num2) {
  int tmp = *num1;
  *num1 = *num2;
  *num2 = tmp;
  printf("[%s] : addresses : num1 = %p, num2 = %p\n", __func__, num1, num2);
  printf("[%s] : *num1 = %d, *num2 = %d\n", __func__, *num1, *num2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_call_by_reference>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  mov    %rsi,%rcx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%eax
  mov    %rdi,%rbx
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %rdi,%rdx
  lea    D21(%rip),%rdi
  mov    %eax,(%rsi)
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%ecx
  mov    (%rbx),%edx
  mov    %r12,%rsi
  pop    %rbx
  lea    D9(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D7: swap_call_by_reference

tool: D21: [%s] : addresses : num1 = %p, num2 = %p


tool: D9: [%s] : *num1 = %d, *num2 = %d


assistant: ```c
void swap_call_by_reference(int *num1, int *num2) {
  int tmp = *num1;
  *num1 = *num2;
  *num2 = tmp;
  printf("[%s] : addresses : num1 = %p, num2 = %p\n", __func__, num1, num2);
  printf("[%s] : *num1 = %d, *num2 = %d\n", __func__, *num1, *num2);
}
```