ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L0
  mov    $0x0,%edi
  call   <cat@plt>
  mov    $0x0,%eax
  jmp    L58
L0:
  movl   $0x1,-0x8(%rbp)
  jmp    L7
L50:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L48
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L58
L48:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <cat@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L50
  mov    $0x0,%eax
L58:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: cat: cannot open %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i, fd;
  if (argc < 2) {
    cat(0);
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if ((fd = open(argv[i], 0, 0)) < 0) {
      printf("cat: cannot open %s\n", argv[i]);
      return 1;
    }
    cat(fd);
    close(fd);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L27
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
L10:
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    0x0(%rbp),%rdi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L16
  mov    %eax,%edi
  call   <cat@plt>
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L10
  mov    $0x0,%eax
  jmp    L21
L27:
  mov    $0x0,%edi
  call   <cat@plt>
  mov    $0x0,%eax
  jmp    L21
L16:
  mov    0x0(%rbp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: cat: cannot open %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i, fd;
  if (argc < 2) {
    cat(0);
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if ((fd = open(argv[i], 0, 0)) < 0) {
      printf("cat: cannot open %s\n", argv[i]);
      return 1;
    }
    cat(fd);
    close(fd);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L21
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L26:
  mov    (%rbx),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L20
  mov    %eax,%edi
  add    $0x8,%rbx
  call   <cat@plt>
  mov    %ebp,%edi
  call   <close@plt>
  cmp    %r12,%rbx
  jne    L26
  xor    %eax,%eax
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    (%rbx),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L32
L21:
  xor    %edi,%edi
  call   <cat@plt>
  xor    %eax,%eax
  jmp    L32
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: cat: cannot open %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i, fd;
  if (argc < 2) {
    cat(0);
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if ((fd = open(argv[i], 0, 0)) < 0) {
      printf("cat: cannot open %s\n", argv[i]);
      return 1;
    }
    cat(fd);
    close(fd);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L37
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L45:
  mov    (%rbx),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L15
  mov    %eax,%edi
  add    $0x8,%rbx
  call   <cat@plt>
  mov    %ebp,%edi
  call   <close@plt>
  cmp    %r12,%rbx
  jne    L45
  xor    %eax,%eax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    (%rbx),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L49
L37:
  xor    %edi,%edi
  call   <cat@plt>
  xor    %eax,%eax
  jmp    L49
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: cat: cannot open %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i, fd;
  if (argc < 2) {
    cat(0);
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if ((fd = open(argv[i], 0, 0)) < 0) {
      printf("cat: cannot open %s\n", argv[i]);
      return 1;
    }
    cat(fd);
    close(fd);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    D25(%rip),%eax
  lea    0x1(%rax),%esi
  mov    %esi,D6(%rip)
  lea    D6(%rip),%rdi
  call   <printf@plt>
  addl   $0x1,D6(%rip)
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %d


assistant: ```c
void foo() {
  static int x = 3;
  x++;
  printf("%d\n", x);
  x++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  mov    $0x5f,%edi
  call   <print_char@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <print_char@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_line(int n) {
  int i;
  for (i = 0; i < n; i++) {
    print_char('_');
  }
  print_char('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L0
  mov    %edi,%ebp
  mov    $0x0,%ebx
L7:
  mov    $0x5f,%edi
  call   <print_char@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L7
L0:
  mov    $0xa,%edi
  call   <print_char@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void print_line(int n) {
  int i;
  for (i = 0; i < n; i++) {
    print_char('_');
  }
  print_char('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_line>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x5f,%edi
  add    $0x1,%ebx
  call   <print_char@plt>
  cmp    %ebx,%ebp
  jne    L3
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <print_char@plt>
  nopl   0x0(%rax)
L6:
  mov    $0xa,%edi
  jmp    1050 <print_char@plt>
```

assistant: ```c
void print_line(int n) {
  int i;
  for (i = 0; i < n; i++) {
    print_char('_');
  }
  print_char('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_line>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x5f,%edi
  add    $0x1,%ebx
  call   <print_char@plt>
  cmp    %ebx,%ebp
  jne    L8
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <print_char@plt>
  nopl   0x0(%rax)
L6:
  mov    $0xa,%edi
  jmp    1050 <print_char@plt>
```

assistant: ```c
void print_line(int n) {
  int i;
  for (i = 0; i < n; i++) {
    print_char('_');
  }
  print_char('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <maxProfit@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(void) {
  int x[] = {
      1,
      2,
  };
  printf("%d\n", maxProfit(x, sizeof(x) / sizeof(int)));
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%esi
  call   <maxProfit@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(void) {
  int x[] = {
      1,
      2,
  };
  printf("%d\n", maxProfit(x, sizeof(x) / sizeof(int)));
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <maxProfit@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(void) {
  int x[] = {
      1,
      2,
  };
  printf("%d\n", maxProfit(x, sizeof(x) / sizeof(int)));
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <maxProfit@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: {"D5": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D0: %d


assistant: ```c
int main(void) {
  int x[] = {
      1,
      2,
  };
  printf("%d\n", maxProfit(x, sizeof(x) / sizeof(int)));
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DbugMalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L9
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <DbugExit@plt>
L9:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: out of memory

assistant: ```c
char *DbugMalloc(int size) {
  register char *new_malloc;
  if (!(new_malloc = (char *)malloc((unsigned int)size)))
    DbugExit("out of memory");
  return (new_malloc);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<DbugMalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L5:
  lea    D9(%rip),%rdi
  call   <DbugExit@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: out of memory

assistant: ```c
char *DbugMalloc(int size) {
  register char *new_malloc;
  if (!(new_malloc = (char *)malloc((unsigned int)size)))
    DbugExit("out of memory");
  return (new_malloc);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DbugMalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  lea    D0(%rip),%rdi
  call   <DbugExit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: out of memory

assistant: ```c
char *DbugMalloc(int size) {
  register char *new_malloc;
  if (!(new_malloc = (char *)malloc((unsigned int)size)))
    DbugExit("out of memory");
  return (new_malloc);
}
```
user: What is the c source code of the assembly code below?

```asm
<DbugMalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  lea    D7(%rip),%rdi
  call   <DbugExit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string

tool: D7: out of memory

assistant: ```c
char *DbugMalloc(int size) {
  register char *new_malloc;
  if (!(new_malloc = (char *)malloc((unsigned int)size)))
    DbugExit("out of memory");
  return (new_malloc);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<openssl_strerror_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x1,-0x28(%rbp)
  ja     L27
  mov    $0x0,%eax
  jmp    L20
L27:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L20
L13:
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <OPENSSL_strlcpy@plt>
  mov    $0x1,%eax
L20:
  leave
  ret
```

assistant: ```c
int openssl_strerror_r(int errnum, char *buf, size_t buflen) {
  char *err;
  if (buflen < 2)
    return 0;
  err = strerror(errnum);
  if (err == NULL)
    return 0;
  OPENSSL_strlcpy(buf, err, buflen);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<openssl_strerror_r>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rdx
  jbe    L16
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  call   <strerror@plt>
  mov    %rax,%rsi
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L12
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <OPENSSL_strlcpy@plt>
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  ret
```

assistant: ```c
int openssl_strerror_r(int errnum, char *buf, size_t buflen) {
  char *err;
  if (buflen < 2)
    return 0;
  err = strerror(errnum);
  if (err == NULL)
    return 0;
  OPENSSL_strlcpy(buf, err, buflen);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<openssl_strerror_r>:
  endbr64
  cmp    $0x1,%rdx
  jbe    L18
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strerror@plt>
  mov    %rax,%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L16
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <OPENSSL_strlcpy@plt>
  mov    $0x1,%eax
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int openssl_strerror_r(int errnum, char *buf, size_t buflen) {
  char *err;
  if (buflen < 2)
    return 0;
  err = strerror(errnum);
  if (err == NULL)
    return 0;
  OPENSSL_strlcpy(buf, err, buflen);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<openssl_strerror_r>:
  endbr64
  cmp    $0x1,%rdx
  jbe    L7
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strerror@plt>
  mov    %rax,%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L14
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <OPENSSL_strlcpy@plt>
  mov    $0x1,%eax
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int openssl_strerror_r(int errnum, char *buf, size_t buflen) {
  char *err;
  if (buflen < 2)
    return 0;
  err = strerror(errnum);
  if (err == NULL)
    return 0;
  OPENSSL_strlcpy(buf, err, buflen);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<max2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L9
  mov    -0x4(%rbp),%eax
  jmp    L11
L9:
  mov    -0x8(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int max2(int x, int y) {
  if (x > y) {
    return x;
  }
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max2>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max2(int x, int y) {
  if (x > y) {
    return x;
  }
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<max2>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int max2(int x, int y) {
  if (x > y) {
    return x;
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__hsail_sat_sub_u8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L15
  mov    $0x0,%eax
  jmp    L3
L15:
  mov    -0x8(%rbp),%rax
L3:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t __hsail_sat_sub_u8(uint8_t a, uint8_t b) {
  int16_t c = (uint16_t)a - (uint16_t)b;
  if (c < 0)
    return 0;
  else
    return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__hsail_sat_sub_u8>:
  endbr64
  mov    %rdi,%rax
  sub    %rsi,%rax
  mov    $0x0,%edx
  cmovs  %rdx,%rax
  ret
```

assistant: ```c
uint8_t __hsail_sat_sub_u8(uint8_t a, uint8_t b) {
  int16_t c = (uint16_t)a - (uint16_t)b;
  if (c < 0)
    return 0;
  else
    return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__hsail_sat_sub_u8>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  sub    %rsi,%rax
  cmovs  %rdx,%rax
  ret
```

assistant: ```c
uint8_t __hsail_sat_sub_u8(uint8_t a, uint8_t b) {
  int16_t c = (uint16_t)a - (uint16_t)b;
  if (c < 0)
    return 0;
  else
    return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__hsail_sat_sub_u8>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  sub    %rsi,%rax
  cmovs  %rdx,%rax
  ret
```

assistant: ```c
uint8_t __hsail_sat_sub_u8(uint8_t a, uint8_t b) {
  int16_t c = (uint16_t)a - (uint16_t)b;
  if (c < 0)
    return 0;
  else
    return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  divsd  -0x8(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  nop
  leave
  ret
```

assistant: ```c
void divide(void) {
  double divisor = pop();
  push(pop() / divisor);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<divide>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %rbx,%xmm1
  divsd  %xmm1,%xmm0
  call   <push@plt>
  pop    %rbx
  ret
```

assistant: ```c
void divide(void) {
  double divisor = pop();
  push(pop() / divisor);
}
```
user: What is the c source code of the assembly code below:

```asm
<divide>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  divsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1070 <push@plt>
```

assistant: ```c
void divide(void) {
  double divisor = pop();
  push(pop() / divisor);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <pop@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <pop@plt>
  divsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  jmp    1070 <push@plt>
```

assistant: ```c
void divide(void) {
  double divisor = pop();
  push(pop() / divisor);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  add    %ecx,%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void split(char *x, int n, char **a, char **b) {
  *a = calloc(n / 2 + 1, sizeof(char));
  *b = calloc(n - n / 2 + 1, sizeof(char));
  memcpy(*a, x, n / 2);
  memcpy(*b, x + n / 2, n - n / 2);
  (*a)[n / 2] = 0;
  (*b)[n - n / 2] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<split>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  add    %esi,%ebp
  sar    %ebp
  lea    0x1(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,(%r14)
  sub    %ebp,%ebx
  lea    0x1(%rbx),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    (%r14),%rdi
  call   <memcpy@plt>
  movslq %ebp,%rbp
  lea    (%r12,%rbp,1),%rsi
  mov    %ebx,%edx
  mov    0x0(%r13),%rdi
  call   <memcpy@plt>
  mov    (%r14),%rax
  movb   $0x0,(%rax,%rbp,1)
  movslq %ebx,%rbx
  mov    0x0(%r13),%rax
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void split(char *x, int n, char **a, char **b) {
  *a = calloc(n / 2 + 1, sizeof(char));
  *b = calloc(n - n / 2 + 1, sizeof(char));
  memcpy(*a, x, n / 2);
  memcpy(*b, x + n / 2, n - n / 2);
  (*a)[n / 2] = 0;
  (*b)[n - n / 2] = 0;
}
```