ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  add    $0x136ff696,%rdx
  test   $0x10,%dl
  je     L9
  lea    0x0(,%rdx,4),%rax
L17:
  movabs $0xeee1729a46ef9ea2,%rdx
  imul   %rdx,%rax
  mov    %rax,(%rcx)
  ret
L9:
  mov    %edx,%esi
  mov    %rdx,%rax
  mov    %rdx,%rdi
  sar    $0x18,%esi
  shl    $0x8,%rax
  movzbl %sil,%esi
  and    $0xff000000,%eax
  shr    $0x20,%rdi
  shl    $0x10,%rsi
  shl    $0x30,%rdi
  or     %rsi,%rax
  mov    %rdx,%rsi
  movzwl %dx,%edx
  shr    $0x30,%rsi
  or     %rdi,%rax
  shl    $0x10,%rdx
  shl    $0x20,%rsi
  or     %rsi,%rax
  mov    %rax,%rsi
  shr    $0x10,%rsi
  mov    %si,%ax
  movabs $0xffffffff0000ffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  jmp    L17
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy11 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  push   %rbx
  mov    %rsi,%rcx
  add    $0x136ff696,%rdx
  test   $0x10,%dl
  je     L7
  lea    0x0(,%rdx,4),%rax
L15:
  movabs $0xeee1729a46ef9ea2,%rdx
  pop    %rbx
  imul   %rdx,%rax
  mov    %rax,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %edx,%eax
  xor    %ebx,%ebx
  mov    %rdx,%rsi
  sar    $0x18,%eax
  shr    $0x30,%rsi
  mov    %al,%bl
  mov    %edx,%eax
  shl    $0x8,%eax
  sar    $0x18,%eax
  mov    %al,%bh
  mov    %rdx,%rax
  movzwl %dx,%edx
  shr    $0x10,%rax
  movzwl %bx,%ebx
  and    $0xffff0000,%eax
  or     %rsi,%rax
  shl    $0x10,%rax
  or     %rdx,%rax
  shl    $0x10,%rax
  or     %rbx,%rax
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy11 = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy11;
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<type_crash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,%eax
  mov    %rcx,-0x38(%rbp)
  movss  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %ax,-0x28(%rbp)
  mov    %edx,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movzwl -0x28(%rbp),%eax
  mov    %ax,-0x1a(%rbp)
  movzbl -0x2c(%rbp),%eax
  mov    %al,-0x1b(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void type_crash(int a, short b, char c, unsigned long d, float f, double g) {
  int la;
  short lb;
  char lc;
  long ld;
  float lf;
  double lg;
  long ll;
  la = a;
  lb = b;
  lc = c;
  ld = ld;
  lf = lf;
  lg = lg;
  assert(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<type_crash>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void type_crash(int a, short b, char c, unsigned long d, float f, double g) {
  int la;
  short lb;
  char lc;
  long ld;
  float lf;
  double lg;
  long ll;
  la = a;
  lb = b;
  lc = c;
  ld = ld;
  lf = lf;
  lg = lg;
  assert(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<type_crash>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void type_crash(int a, short b, char c, unsigned long d, float f, double g) {
  int la;
  short lb;
  char lc;
  long ld;
  float lf;
  double lg;
  long ll;
  la = a;
  lb = b;
  lc = c;
  ld = ld;
  lf = lf;
  lg = lg;
  assert(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<type_crash>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void type_crash(int a, short b, char c, unsigned long d, float f, double g) {
  int la;
  short lb;
  char lc;
  long ld;
  float lf;
  double lg;
  long ll;
  la = a;
  lb = b;
  lc = c;
  ld = ld;
  lf = lf;
  lg = lg;
  assert(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<amalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L18
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L12
L18:
  mov    -0x10(%rbp),%rax
  and    $0xfffffffc,%eax
  add    $0x4,%eax
  mov    %eax,%eax
  mov    %rax,-0x18(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *amalloc(int size) {
  void *p;
  void *pp;
  uint32_t *h;
  p = malloc(size + 8);
  if (((uint32_t)p & 0x3) == 0x0)
    h = (uint32_t *)p;
  else
    h = (uint32_t *)(((uint32_t)p & 0xfffffffc) + 4);
  *h = (uint32_t)p & 3;
  pp = (void *)(h + 1);
  return pp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<amalloc>:
  endbr64
  sub    $0x8,%rsp
  add    $0x8,%edi
  call   <malloc@plt>
  mov    %eax,%edx
  and    $0x3,%edx
  je     L6
  and    $0xfffffffc,%eax
  add    $0x4,%eax
  mov    %eax,%eax
L6:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *amalloc(int size) {
  void *p;
  void *pp;
  uint32_t *h;
  p = malloc(size + 8);
  if (((uint32_t)p & 0x3) == 0x0)
    h = (uint32_t *)p;
  else
    h = (uint32_t *)(((uint32_t)p & 0xfffffffc) + 4);
  *h = (uint32_t)p & 3;
  pp = (void *)(h + 1);
  return pp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<amalloc>:
  endbr64
  sub    $0x8,%rsp
  add    $0x8,%edi
  call   <malloc@plt>
  mov    %eax,%edx
  and    $0x3,%edx
  je     L6
  and    $0xfffffffc,%eax
  add    $0x4,%eax
L6:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *amalloc(int size) {
  void *p;
  void *pp;
  uint32_t *h;
  p = malloc(size + 8);
  if (((uint32_t)p & 0x3) == 0x0)
    h = (uint32_t *)p;
  else
    h = (uint32_t *)(((uint32_t)p & 0xfffffffc) + 4);
  *h = (uint32_t)p & 3;
  pp = (void *)(h + 1);
  return pp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<amalloc>:
  endbr64
  sub    $0x8,%rsp
  add    $0x8,%edi
  call   <malloc@plt>
  mov    %eax,%edx
  and    $0x3,%edx
  je     L0
  and    $0xfffffffc,%eax
  add    $0x4,%eax
L0:
  mov    %edx,(%rax)
  add    $0x4,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *amalloc(int size) {
  void *p;
  void *pp;
  uint32_t *h;
  p = malloc(size + 8);
  if (((uint32_t)p & 0x3) == 0x0)
    h = (uint32_t *)p;
  else
    h = (uint32_t *)(((uint32_t)p & 0xfffffffc) + 4);
  *h = (uint32_t)p & 3;
  pp = (void *)(h + 1);
  return pp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<apply_rlimit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <setrlimit@plt>
  test   %rax,%rax
  je     L5
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0xfa,%edi
  call   <error@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: Error setting rlimit.

assistant: ```c
void apply_rlimit(int resource, int limit) {
  struct rlimit lim;
  lim.rlim_cur = lim.rlim_max = limit;
  if (setrlimit(resource, &lim) != 0)
    error(250, 0, "Error setting rlimit.");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<apply_rlimit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  mov    %esi,(%rsp)
  mov    %rsp,%rsi
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L13
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
L13:
  lea    D9(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xfa,%edi
  call   <error@plt>
  jmp    L17
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: Error setting rlimit.

assistant: ```c
void apply_rlimit(int resource, int limit) {
  struct rlimit lim;
  lim.rlim_cur = lim.rlim_max = limit;
  if (setrlimit(resource, &lim) != 0)
    error(250, 0, "Error setting rlimit.");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<apply_rlimit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  mov    %esi,(%rsp)
  mov    %rsp,%rsi
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L17
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L17:
  lea    D1(%rip),%rdx
  xor    %esi,%esi
  mov    $0xfa,%edi
  call   <error@plt>
  jmp    L19
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: Error setting rlimit.

assistant: ```c
void apply_rlimit(int resource, int limit) {
  struct rlimit lim;
  lim.rlim_cur = lim.rlim_max = limit;
  if (setrlimit(resource, &lim) != 0)
    error(250, 0, "Error setting rlimit.");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<apply_rlimit>:
  endbr64
  sub    $0x18,%rsp
  movd   %esi,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  pshufd $0xe0,%xmm1,%xmm0
  mov    %rsp,%rsi
  movq   %xmm0,(%rsp)
  call   <setrlimit@plt>
  test   %rax,%rax
  jne    L7
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D9(%rip),%rdx
  xor    %esi,%esi
  mov    $0xfa,%edi
  call   <error@plt>
  jmp    L1
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: Error setting rlimit.

assistant: ```c
void apply_rlimit(int resource, int limit) {
  struct rlimit lim;
  lim.rlim_cur = lim.rlim_max = limit;
  if (setrlimit(resource, &lim) != 0)
    error(250, 0, "Error setting rlimit.");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mkString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  lea    D1(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    (%rbx,%rax,2),%eax
  cltd
  idiv   %r12d
  mov    %eax,%r13d
  mov    %r12d,%edi
  imul   %eax,%edi
  add    $0x1,%edi
  call   <needMem@plt>
  mov    %rax,%r15
  test   %r13d,%r13d
  jle    L5
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D1(%rip),%r14
L0:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x1,%ebx
  movslq %r12d,%rax
  add    %rax,%rbp
  cmp    %ebx,%r13d
  jne    L0
L5:
  movslq 0xc(%rsp),%rax
  movb   $0x0,(%r15,%rax,1)
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: abcdefghijklmnopABCDEFGHIJKLMNOP

assistant: ```c
char *mkString(int len) {
  static char *base = "abcdefghijklmnopABCDEFGHIJKLMNOP";
  int baseLen = strlen(base);
  int numRep = (len + 2 * baseLen) / baseLen;
  int i;
  char *p, *str = needMem((numRep * baseLen) + 1);
  for (p = str, i = 0; i < numRep; i++, p += baseLen)
    strcpy(p, base);
  str[len] = '\0';
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mkString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  lea    (%rbx,%rbp,2),%eax
  mov    %ebp,%edi
  cltd
  idiv   %ebp
  imul   %eax,%edi
  mov    %eax,%r12d
  add    $0x1,%edi
  call   <needMem@plt>
  mov    %rax,%r15
  test   %r12d,%r12d
  jle    L16
  mov    %rax,%r14
  xor    %ebx,%ebx
  nopl   (%rax)
L3:
  mov    %r14,%rdi
  mov    %r13,%rsi
  add    $0x1,%ebx
  add    %rbp,%r14
  call   <strcpy@plt>
  cmp    %ebx,%r12d
  jne    L3
L16:
  movslq 0xc(%rsp),%r14
  mov    %r15,%rax
  movb   $0x0,(%r15,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: abcdefghijklmnopABCDEFGHIJKLMNOP

assistant: ```c
char *mkString(int len) {
  static char *base = "abcdefghijklmnopABCDEFGHIJKLMNOP";
  int baseLen = strlen(base);
  int numRep = (len + 2 * baseLen) / baseLen;
  int i;
  char *p, *str = needMem((numRep * baseLen) + 1);
  for (p = str, i = 0; i < numRep; i++, p += baseLen)
    strcpy(p, base);
  str[len] = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  lea    (%rbx,%rbp,2),%eax
  mov    %ebp,%edi
  cltd
  idiv   %ebp
  imul   %eax,%edi
  mov    %eax,%r12d
  add    $0x1,%edi
  call   <needMem@plt>
  mov    %rax,%r15
  test   %r12d,%r12d
  jle    L12
  mov    %rax,%r14
  xor    %ebx,%ebx
  nopl   (%rax)
L7:
  mov    %r14,%rdi
  mov    %r13,%rsi
  add    $0x1,%ebx
  add    %rbp,%r14
  call   <strcpy@plt>
  cmp    %ebx,%r12d
  jne    L7
L12:
  movslq 0xc(%rsp),%r14
  mov    %r15,%rax
  movb   $0x0,(%r15,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: abcdefghijklmnopABCDEFGHIJKLMNOP

assistant: ```c
char *mkString(int len) {
  static char *base = "abcdefghijklmnopABCDEFGHIJKLMNOP";
  int baseLen = strlen(base);
  int numRep = (len + 2 * baseLen) / baseLen;
  int i;
  char *p, *str = needMem((numRep * baseLen) + 1);
  for (p = str, i = 0; i < numRep; i++, p += baseLen)
    strcpy(p, base);
  str[len] = '\0';
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<systickEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0xe000e014,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0xe000e018,%eax
  movl   $0x5,(%rax)
  mov    $0xe000e010,%eax
  mov    (%rax),%edx
  mov    $0xe000e010,%eax
  or     $0x7,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void systickEnable(const unsigned int period) {
  (*((volatile unsigned int *const)(0xe000e010 + 4))) = period;
  (*((volatile unsigned int *const)(0xe000e010 + 8))) = 5;
  (*((volatile unsigned int *const)(0xe000e010 + 0))) |= (1 << 0) | (1 << 1) | (1 << 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<systickEnable>:
  endbr64
  mov    %edi,%eax
  movabs %eax,0xe000e014
  mov    $0xe000e018,%eax
  movl   $0x5,(%rax)
  mov    $0xe000e010,%edx
  mov    (%rdx),%eax
  or     $0x7,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void systickEnable(const unsigned int period) {
  (*((volatile unsigned int *const)(0xe000e010 + 4))) = period;
  (*((volatile unsigned int *const)(0xe000e010 + 8))) = 5;
  (*((volatile unsigned int *const)(0xe000e010 + 0))) |= (1 << 0) | (1 << 1) | (1 << 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<systickEnable>:
  endbr64
  mov    %edi,%eax
  mov    $0xe000e010,%edx
  movabs %eax,0xe000e014
  mov    $0xe000e018,%eax
  movl   $0x5,(%rax)
  mov    (%rdx),%eax
  or     $0x7,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void systickEnable(const unsigned int period) {
  (*((volatile unsigned int *const)(0xe000e010 + 4))) = period;
  (*((volatile unsigned int *const)(0xe000e010 + 8))) = 5;
  (*((volatile unsigned int *const)(0xe000e010 + 0))) |= (1 << 0) | (1 << 1) | (1 << 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<signal_block_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L29
L17:
  mov    -0xc(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  addl   $0x1,-0xc(%rbp)
L29:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L17
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void signal_block_all() {
  int i;
  sigset_t set;
  union sigval data;
  sigemptyset(&set);
  for (i = SIGRTMIN; i <= SIGRTMAX; i++)
    sigaddset(&set, i);
  sigprocmask(SIG_BLOCK, &set, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<signal_block_all>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigemptyset@plt>
  mov    D31(%rip),%rax
  mov    (%rax),%ebx
  mov    D33(%rip),%rax
  cmp    (%rax),%ebx
  jg     L27
  lea    0x4(%rsp),%rbp
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <sigaddset@plt>
  add    $0x1,%ebx
  mov    D33(%rip),%rax
  cmp    %ebx,(%rax)
  jge    L8
L27:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void signal_block_all() {
  int i;
  sigset_t set;
  union sigval data;
  sigemptyset(&set);
  for (i = SIGRTMIN; i <= SIGRTMAX; i++)
    sigaddset(&set, i);
  sigprocmask(SIG_BLOCK, &set, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<signal_block_all>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D29(%rip),%rax
  mov    D21(%rip),%r12
  mov    (%rax),%ebx
  cmp    (%r12),%ebx
  jg     L26
  nop
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <sigaddset@plt>
  cmp    %ebx,(%r12)
  jge    L13
L26:
  mov    D1(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void signal_block_all() {
  int i;
  sigset_t set;
  union sigval data;
  sigemptyset(&set);
  for (i = SIGRTMIN; i <= SIGRTMAX; i++)
    sigaddset(&set, i);
  sigprocmask(SIG_BLOCK, &set, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signal_block_all>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D28(%rip),%rax
  mov    D19(%rip),%r12
  mov    (%rax),%ebx
  cmp    (%r12),%ebx
  jg     L13
  nop
L7:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <sigaddset@plt>
  cmp    %ebx,(%r12)
  jge    L7
L13:
  mov    D22(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void signal_block_all() {
  int i;
  sigset_t set;
  union sigval data;
  sigemptyset(&set);
  for (i = SIGRTMIN; i <= SIGRTMAX; i++)
    sigaddset(&set, i);
  sigprocmask(SIG_BLOCK, &set, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_16_le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t read_16_le(unsigned char bytes[2]) {
  uint32_t result = 0;
  for (int i = 2 - 1; i >= 0; i--)
    result = (result << 8) | bytes[i];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_16_le>:
  endbr64
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  or     %edx,%eax
  ret
```

assistant: ```c
uint16_t read_16_le(unsigned char bytes[2]) {
  uint32_t result = 0;
  for (int i = 2 - 1; i >= 0; i--)
    result = (result << 8) | bytes[i];
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_16_le>:
  endbr64
  movzwl (%rdi),%eax
  ret
```

assistant: ```c
uint16_t read_16_le(unsigned char bytes[2]) {
  uint32_t result = 0;
  for (int i = 2 - 1; i >= 0; i--)
    result = (result << 8) | bytes[i];
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_16_le>:
  endbr64
  movzwl (%rdi),%eax
  ret
```

assistant: ```c
uint16_t read_16_le(unsigned char bytes[2]) {
  uint32_t result = 0;
  for (int i = 2 - 1; i >= 0; i--)
    result = (result << 8) | bytes[i];
  return result;
}
```