user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x148,%rsp
  movsd  D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  lea    0x10(%rsp),%r12
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  mov    D17(%rip),%rax
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x40(%rsp)
  mov    %rax,0x50(%rsp)
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm0,0x48(%rsp)
  pxor   %xmm0,%xmm0
L20:
  xor    %ebx,%ebx
L42:
  cvttsd2si %xmm0,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  je     L47
  movsd  (%r12,%rbx,8),%xmm0
  jmp    L42
L47:
  add    $0x1,%ebp
  add    $0x18,%r12
  cmp    $0x3,%ebp
  je     L71
  movsd  (%r12),%xmm0
  jmp    L20
  nopl   0x0(%rax)
L71:
  lea    0x60(%rsp),%rax
  lea    0xa8(%rsp),%rdi
  xor    %ecx,%ecx
  mov    %rax,0x8(%rsp)
L60:
  lea    -0x48(%rdi),%rax
  xor    %edx,%edx
L54:
  pxor   %xmm0,%xmm0
  lea    (%rdx,%rdx,1),%esi
  movq   $0x0,(%rax)
  add    $0x18,%rax
  cvtsi2sd %edx,%xmm0
  add    %ecx,%edx
  movsd  %xmm0,-0x10(%rax)
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rdi,%rax
  jne    L54
  add    $0x1,%ecx
  lea    0x48(%rax),%rdi
  cmp    $0x3,%ecx
  jne    L60
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  lea    D29(%rip),%r13
L65:
  mov    0x8(%rsp),%rax
  xor    %ebp,%ebp
  lea    (%r15,%rax,1),%r14
L0:
  xor    %ebx,%ebx
L17:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L17
  add    $0x1,%ebp
  add    $0x18,%r14
  cmp    $0x3,%ebp
  jne    L0
  add    $0x1,%r12d
  add    $0x48,%r15
  cmp    $0x3,%r12d
  jne    L65
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
datatype: string
name: parse_data
arguments: data_label: D38
datatype: byte[8]
name: parse_data
arguments: data_label: D19
datatype: byte[8]
name: parse_data
arguments: data_label: D17
datatype: byte[8]
name: parse_data
arguments: data_label: D29
datatype: string

tool: D22: a[%d][%d]: %f


tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D29: b[%d][%d][%d]: %f


assistant: ```c
int main() {
  double a[3][3];
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      a[i][j] = i * j;
    }
  }
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      printf("a[%d][%d]: %f\n", i, j, a[i][j]);
    }
  }
  double b[3][3][3];
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      for (int k = 0; k < 3; k++) {
        b[i][j][k] = i * j * k;
      }
    }
  }
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      for (int k = 0; k < 3; k++) {
        printf("b[%d][%d][%d]: %f\n", i, j, k, b[i][j][k]);
      }
    }
  }
  return 0;
}
```