ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tripcode_sjis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    D37(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x18(%rbp),%rdi
  lea    -0x40(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <iconv@plt>
  mov    %rax,-0x10(%rbp)
  mov    D37(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L30
  cmpq   $0xffffffffffffffff,-0x10(%rbp)
  jne    L30
  mov    D37(%rip),%rax
  mov    (%rax),%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L30
  mov    $0xffffffffffffffff,%rax
  jmp    L40
L30:
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  sub    %rdx,%rax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
size_t tripcode_sjis(iconv_t cd, char *s, size_t len, char *dest, size_t size) {
  size_t e;
  size_t l = size;
  errno = 0;
  e = iconv(cd, &s, &len, &dest, &l);
  if (errno && e == (size_t)-1) {
    if (errno != EILSEQ)
      return (size_t)-1;
  }
  dest[0] = '\0';
  return size - l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tripcode_sjis>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %r8,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r8,0x20(%rsp)
  mov    D8(%rip),%rbp
  movq   $0x0,0x0(%rbp)
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    0x20(%rsp),%r8
  call   <iconv@plt>
  mov    0x0(%rbp),%rdx
  cmp    $0xffffffffffffffff,%rax
  jne    L31
  test   %rdx,%rdx
  jne    L1
L31:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  sub    0x20(%rsp),%rax
L42:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    D13(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L31
  jmp    L42
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t tripcode_sjis(iconv_t cd, char *s, size_t len, char *dest, size_t size) {
  size_t e;
  size_t l = size;
  errno = 0;
  e = iconv(cd, &s, &len, &dest, &l);
  if (errno && e == (size_t)-1) {
    if (errno != EILSEQ)
      return (size_t)-1;
  }
  dest[0] = '\0';
  return size - l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tripcode_sjis>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x38,%rsp
  mov    D1(%rip),%rbp
  mov    %rsi,0x18(%rsp)
  lea    0x18(%rsp),%rsi
  mov    %rdx,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rcx,0x8(%rsp)
  lea    0x8(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r8,0x20(%rsp)
  lea    0x20(%rsp),%r8
  movq   $0x0,0x0(%rbp)
  call   <iconv@plt>
  mov    0x0(%rbp),%rdx
  cmp    $0xffffffffffffffff,%rax
  jne    L41
  test   %rdx,%rdx
  jne    L27
L41:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  sub    0x20(%rsp),%rax
L48:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L27:
  mov    D10(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L41
  jmp    L48
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t tripcode_sjis(iconv_t cd, char *s, size_t len, char *dest, size_t size) {
  size_t e;
  size_t l = size;
  errno = 0;
  e = iconv(cd, &s, &len, &dest, &l);
  if (errno && e == (size_t)-1) {
    if (errno != EILSEQ)
      return (size_t)-1;
  }
  dest[0] = '\0';
  return size - l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tripcode_sjis>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x38,%rsp
  mov    D0(%rip),%rbp
  mov    %rsi,0x18(%rsp)
  lea    0x18(%rsp),%rsi
  mov    %rdx,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  mov    %rcx,0x8(%rsp)
  lea    0x8(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %r8,0x20(%rsp)
  lea    0x20(%rsp),%r8
  movq   $0x0,0x0(%rbp)
  call   <iconv@plt>
  mov    0x0(%rbp),%rdx
  cmp    $0xffffffffffffffff,%rax
  jne    L40
  test   %rdx,%rdx
  jne    L5
L40:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  sub    0x20(%rsp),%rax
L1:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L5:
  mov    D7(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L40
  jmp    L1
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t tripcode_sjis(iconv_t cd, char *s, size_t len, char *dest, size_t size) {
  size_t e;
  size_t l = size;
  errno = 0;
  e = iconv(cd, &s, &len, &dest, &l);
  if (errno && e == (size_t)-1) {
    if (errno != EILSEQ)
      return (size_t)-1;
  }
  dest[0] = '\0';
  return size - l;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_curl_progress_bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x3d,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  lea    -0x6(%rax),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movzbl -0xd(%rbp),%eax
  cmp    $0x2c,%al
  jne    L9
  movzbl -0xb(%rbp),%eax
  cmp    $0x25,%al
  jne    L9
  movb   $0x0,-0xd(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  lea    D3(%rip),%rsi
  mov    %eax,%edi
  call   <dprintf@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %d
# %d%%


assistant: ```c
int parse_curl_progress_bar(int fd, const char *str, size_t len) {
  char tmp[8] = {61};
  int percent;
  memcpy(&tmp[0], str + len - 6, 6);
  if (tmp[3] == ',' && tmp[5] == '%') {
    tmp[3] = '\0';
    percent = atoi(tmp);
    dprintf(fd, "%d\n# %d%%\n", percent, percent);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_curl_progress_bar>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x3d,(%rsp)
  lea    -0x6(%rsi,%rdx,1),%rsi
  mov    %rsp,%rdi
  mov    $0x6,%edx
  call   <memcpy@plt>
  cmpb   $0x2c,0x3(%rsp)
  je     L3
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  cmpb   $0x25,0x5(%rsp)
  jne    L31
  movb   $0x0,0x3(%rsp)
  mov    %rsp,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %eax,%ecx
  lea    D8(%rip),%rsi
  mov    %ebx,%edi
  call   <dprintf@plt>
  jmp    L31
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: %d
# %d%%


assistant: ```c
int parse_curl_progress_bar(int fd, const char *str, size_t len) {
  char tmp[8] = {61};
  int percent;
  memcpy(&tmp[0], str + len - 6, 6);
  if (tmp[3] == ',' && tmp[5] == '%') {
    tmp[3] = '\0';
    percent = atoi(tmp);
    dprintf(fd, "%d\n# %d%%\n", percent, percent);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_curl_progress_bar>:
  endbr64
  push   %r12
  lea    -0x6(%rsi,%rdx,1),%rsi
  mov    %edi,%r12d
  mov    $0x6,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x3d,(%rsp)
  mov    %rbp,%rdi
  call   <memcpy@plt>
  cmpb   $0x2c,0x3(%rsp)
  je     L32
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  cmpb   $0x25,0x5(%rsp)
  jne    L15
  mov    %rbp,%rdi
  movb   $0x0,0x3(%rsp)
  call   <atoi@plt>
  lea    D9(%rip),%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  mov    %eax,%ecx
  call   <dprintf@plt>
  jmp    L15
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: %d
# %d%%


assistant: ```c
int parse_curl_progress_bar(int fd, const char *str, size_t len) {
  char tmp[8] = {61};
  int percent;
  memcpy(&tmp[0], str + len - 6, 6);
  if (tmp[3] == ',' && tmp[5] == '%') {
    tmp[3] = '\0';
    percent = atoi(tmp);
    dprintf(fd, "%d\n# %d%%\n", percent, percent);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_curl_progress_bar>:
  endbr64
  push   %r12
  lea    -0x6(%rsi,%rdx,1),%rsi
  mov    %edi,%r12d
  mov    $0x6,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x3d,(%rsp)
  mov    %rbp,%rdi
  call   <memcpy@plt>
  cmpb   $0x2c,0x3(%rsp)
  je     L37
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L37:
  cmpb   $0x25,0x5(%rsp)
  jne    L36
  mov    %rbp,%rdi
  movb   $0x0,0x3(%rsp)
  call   <atoi@plt>
  lea    D8(%rip),%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  mov    %eax,%ecx
  call   <dprintf@plt>
  jmp    L36
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: %d
# %d%%


assistant: ```c
int parse_curl_progress_bar(int fd, const char *str, size_t len) {
  char tmp[8] = {61};
  int percent;
  memcpy(&tmp[0], str + len - 6, 6);
  if (tmp[3] == ',' && tmp[5] == '%') {
    tmp[3] = '\0';
    percent = atoi(tmp);
    dprintf(fd, "%d\n# %d%%\n", percent, percent);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<half>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L5
L17:
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  D7(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L17
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void half(double *begin, double *end) {
  while (begin < end) {
    *begin /= 2;
    ++begin;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<half>:
  endbr64
  cmp    %rsi,%rdi
  jae    L7
  movsd  D4(%rip),%xmm1
L12:
  movapd %xmm1,%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
  add    $0x8,%rdi
  cmp    %rdi,%rsi
  ja     L12
L7:
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void half(double *begin, double *end) {
  while (begin < end) {
    *begin /= 2;
    ++begin;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<half>:
  endbr64
  cmp    %rsi,%rdi
  jae    L14
  movsd  D2(%rip),%xmm1
  nopl   0x0(%rax)
L10:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rdi)
  cmp    %rdi,%rsi
  ja     L10
L14:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void half(double *begin, double *end) {
  while (begin < end) {
    *begin /= 2;
    ++begin;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<half>:
  endbr64
  cmp    %rsi,%rdi
  jae    L9
  sub    $0x1,%rsi
  mov    %rdi,%rax
  sub    %rdi,%rsi
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  add    $0x1,%rcx
  cmp    $0x7,%rsi
  jbe    L12
  mov    %rcx,%rdx
  movapd D19(%rip),%xmm1
  shr    %rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax)
L24:
  movupd (%rax),%xmm0
  add    $0x10,%rax
  mulpd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L24
  mov    %rcx,%rax
  and    $0xfffffffffffffffe,%rax
  lea    (%rdi,%rax,8),%rdi
  cmp    %rax,%rcx
  je     L9
L12:
  movsd  D19(%rip),%xmm0
  mulsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdi)
L9:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void half(double *begin, double *end) {
  while (begin < end) {
    *begin /= 2;
    ++begin;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L57
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L68
L13:
  subl   $0x1,-0x8(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L63
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jae    L13
L63:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L71
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L71
L8:
  addl   $0x1,-0xc(%rbp)
L71:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L40
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L8
L40:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L68
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L68:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L6
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L57:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(unsigned int s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned int x = s[l];
    while (i < j) {
      while (i < j && s[j] <= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] > x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jge    L7
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r11d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r8d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rdx
  lea    -0x1(%r12),%ecx
  mov    %r12d,%esi
  mov    %r11d,%ebx
  jmp    L47
L77:
  mov    %esi,%r10d
  cmp    %esi,%ebx
  jge    L48
  lea    0x1(%rbx),%eax
  movslq %ebx,%rbx
  mov    %edi,0x0(%rbp,%rbx,4)
  cmp    %esi,%eax
  jge    L102
  cltq
L14:
  mov    %eax,%ebx
  cmp    %r8d,0x0(%rbp,%rax,4)
  jbe    L109
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%r10d
  jg     L14
L48:
  movslq %ebx,%rax
  mov    %r8d,0x0(%rbp,%rax,4)
  lea    -0x1(%rbx),%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L109:
  cmp    %r10d,%eax
  jge    L48
  cltq
  mov    0x0(%rbp,%rax,4),%eax
  mov    %eax,(%r9)
  cmp    %ebx,%ecx
  jle    L48
L79:
  sub    $0x4,%rdx
  sub    $0x1,%ecx
  sub    $0x1,%esi
L47:
  mov    %rdx,%r9
  mov    (%rdx),%edi
  cmp    %r8d,%edi
  ja     L77
  cmp    %ebx,%ecx
  jg     L79
  jmp    L48
L102:
  mov    %eax,%ebx
  jmp    L48
L7:
  ret
```

assistant: ```c
void quick_sort(unsigned int s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned int x = s[l];
    while (i < j) {
      while (i < j && s[j] <= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] > x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L19
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L58:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,4),%edi
  cs nopw 0x0(%rax,%rax,1)
L43:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L40:
  mov    (%rcx),%eax
  cmp    %edi,%eax
  ja     L98
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jg     L40
L84:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L73:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %edi,0x0(%rbp,%rax,4)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L58
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L98:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,4),%rsi
  cmp    %edx,%r8d
  jge    L84
  mov    %eax,(%rsi)
  cmp    %edx,%ebx
  jge    L73
  movslq %ebx,%rax
  jmp    L89
  nopl   0x0(%rax)
L38:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L73
L89:
  mov    0x0(%rbp,%rax,4),%esi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %edi,%esi
  ja     L38
  sub    $0x1,%edx
  mov    %esi,(%rcx)
  cmp    %edx,%eax
  jl     L43
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void quick_sort(unsigned int s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned int x = s[l];
    while (i < j) {
      while (i < j && s[j] <= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] > x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L20
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L76:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,4),%edi
  cs nopw 0x0(%rax,%rax,1)
L63:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L33:
  mov    (%rcx),%eax
  cmp    %edi,%eax
  ja     L1
  sub    $0x1,%edx
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jg     L33
L100:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L5:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %edi,0x0(%rbp,%rax,4)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L76
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,4),%rsi
  cmp    %edx,%r8d
  jge    L100
  mov    %eax,(%rsi)
  cmp    %edx,%ebx
  jge    L5
  movslq %ebx,%rax
  jmp    L14
  nopl   0x0(%rax)
L64:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L5
L14:
  mov    0x0(%rbp,%rax,4),%esi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %edi,%esi
  ja     L64
  sub    $0x1,%edx
  mov    %esi,(%rcx)
  cmp    %edx,%eax
  jl     L63
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L20:
  ret
```

assistant: ```c
void quick_sort(unsigned int s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned int x = s[l];
    while (i < j) {
      while (i < j && s[j] <= x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] > x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  jmp    L41
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L20
L22:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L22
  addl   $0x1,-0x8(%rbp)
L41:
  cmpl   $0x1e,-0x8(%rbp)
  jle    L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void assign(int e[], int f[], int m) {
  int i = 0, j;
  while (i < m) {
    e[i] = f[i];
    i++;
  }
  while (i <= 30) {
    e[i] = 0;
    for (j = 1; j <= m; j++)
      e[i] += e[i - j];
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<assign>:
  endbr64
  mov    %edx,%r10d
  test   %edx,%edx
  jle    L61
  mov    %edx,%ecx
  mov    $0x0,%eax
L51:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L51
  cmp    $0x1e,%r10d
  jg     L68
  mov    %r10d,%r9d
L19:
  movslq %r9d,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  sub    $0x4,%rdi
  lea    -0x1(%r10),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rdi
  lea    (%rdi,%rax,1),%rsi
L2:
  mov    %r8,%rdx
  movl   $0x0,(%r8)
  test   %r10d,%r10d
  jle    L57
  mov    %r8,%rax
L22:
  mov    -0x4(%rax),%ecx
  add    %ecx,(%rdx)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L22
L57:
  add    $0x1,%r9d
  add    $0x4,%r8
  add    $0x4,%rsi
  cmp    $0x1e,%r9d
  jle    L2
L68:
  ret
L61:
  mov    $0x0,%r9d
  jmp    L19
```

assistant: ```c
void assign(int e[], int f[], int m) {
  int i = 0, j;
  while (i < m) {
    e[i] = f[i];
    i++;
  }
  while (i <= 30) {
    e[i] = 0;
    for (j = 1; j <= m; j++)
      e[i] += e[i - j];
    i++;
  }
}
```