ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_128>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x20,%eax
  jg     L3
  lea    0x8(%r12),%rdx
  cmp    $0x10,%eax
  jle    L1
  cltq
  lea    D10(%rip),%r13
  lea    -0x10(%rbp,%rax,1),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L11
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L1:
  movq   $0x0,(%r12)
  pop    %rbx
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <sscanf@plt>
  nop
L11:
  movzbl (%rbx),%r14d
  movb   $0x0,(%rbx)
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %r14b,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
data_type: string

tool: D10: %llx

assistant: ```c
int read_128(char *s, uint64_t *v) {
  int l, t;
  char save;
  l = strlen(s);
  if (l > 32)
    return 0;
  if (l > 16) {
    if (sscanf(s + (l - 16), "%llx", (long long unsigned int *)&(v[1])) == 0)
      return 0;
    save = s[l - 16];
    s[l - 16] = '\0';
    t = sscanf(s, "%llx", (long long unsigned int *)&(v[0]));
    s[l - 16] = save;
    return t;
  } else {
    v[0] = 0;
    return sscanf(s, "%llx", (long long unsigned int *)&(v[1]));
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<read_128>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x20,%eax
  jg     L5
  lea    0x8(%r12),%rdx
  cmp    $0x10,%eax
  jle    L16
  cltq
  lea    D12(%rip),%r13
  lea    -0x10(%rbp,%rax,1),%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L13
L5:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L16:
  movq   $0x0,(%r12)
  pop    %rbx
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <sscanf@plt>
  nop
L13:
  movzbl (%rbx),%r14d
  movb   $0x0,(%rbx)
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %r14b,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string

tool: D12: %llx

assistant: ```c
int read_128(char *s, uint64_t *v) {
  int l, t;
  char save;
  l = strlen(s);
  if (l > 32)
    return 0;
  if (l > 16) {
    if (sscanf(s + (l - 16), "%llx", (long long unsigned int *)&(v[1])) == 0)
      return 0;
    save = s[l - 16];
    s[l - 16] = '\0';
    t = sscanf(s, "%llx", (long long unsigned int *)&(v[0]));
    s[l - 16] = save;
    return t;
  } else {
    v[0] = 0;
    return sscanf(s, "%llx", (long long unsigned int *)&(v[1]));
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_dram_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x12,%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
size_t get_dram_row(void *phys_addr_p) {
  uint64_t phys_addr = (uint64_t)phys_addr_p;
  return phys_addr >> 18;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_dram_row>:
  endbr64
  sar    $0x12,%edi
  movslq %edi,%rax
  ret
```

assistant: ```c
size_t get_dram_row(void *phys_addr_p) {
  uint64_t phys_addr = (uint64_t)phys_addr_p;
  return phys_addr >> 18;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_dram_row>:
  endbr64
  sar    $0x12,%edi
  movslq %edi,%rax
  ret
```

assistant: ```c
size_t get_dram_row(void *phys_addr_p) {
  uint64_t phys_addr = (uint64_t)phys_addr_p;
  return phys_addr >> 18;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<opSumULongGASPI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L9
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  addq   $0x8,-0x10(%rbp)
  addq   $0x8,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void opSumULongGASPI(void *res, void *localVal, void *dstVal, const int cnt) {
  int i;
  unsigned long *rv = (unsigned long *)res;
  unsigned long *lv = (unsigned long *)localVal;
  unsigned long *dv = (unsigned long *)dstVal;
  for (i = 0; i < cnt; i++) {
    *rv = *lv + *dv;
    lv++;
    dv++;
    rv++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<opSumULongGASPI>:
  endbr64
  test   %ecx,%ecx
  jle    L14
  mov    %ecx,%ecx
  mov    $0x0,%eax
L2:
  mov    (%rdx,%rax,8),%r8
  add    (%rsi,%rax,8),%r8
  mov    %r8,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L2
L14:
  ret
```

assistant: ```c
void opSumULongGASPI(void *res, void *localVal, void *dstVal, const int cnt) {
  int i;
  unsigned long *rv = (unsigned long *)res;
  unsigned long *lv = (unsigned long *)localVal;
  unsigned long *dv = (unsigned long *)dstVal;
  for (i = 0; i < cnt; i++) {
    *rv = *lv + *dv;
    lv++;
    dv++;
    rv++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<opSumULongGASPI>:
  endbr64
  test   %ecx,%ecx
  jle    L14
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L13:
  mov    (%rdx,%rax,8),%r8
  add    (%rsi,%rax,8),%r8
  mov    %r8,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
L14:
  ret
```

assistant: ```c
void opSumULongGASPI(void *res, void *localVal, void *dstVal, const int cnt) {
  int i;
  unsigned long *rv = (unsigned long *)res;
  unsigned long *lv = (unsigned long *)localVal;
  unsigned long *dv = (unsigned long *)dstVal;
  for (i = 0; i < cnt; i++) {
    *rv = *lv + *dv;
    lv++;
    dv++;
    rv++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<opSumULongGASPI>:
  endbr64
  test   %ecx,%ecx
  jle    L9
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  lea    0x8(%rsi),%rax
  setne  %r8b
  cmp    %rax,%rdi
  setne  %al
  test   %al,%r8b
  je     L46
  lea    -0x1(%rcx),%eax
  cmp    $0x1,%eax
  jbe    L46
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    %r8d
  shl    $0x4,%r8
  nopw   0x0(%rax,%rax,1)
L5:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%rdx,%rax,1),%xmm1
  paddq  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L5
  mov    %ecx,%r8d
  and    $0xfffffffe,%r8d
  mov    %r8d,%eax
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  add    %rdx,%rax
  cmp    %r8d,%ecx
  je     L9
  mov    (%rax),%rax
  add    (%rsi),%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L46:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L55:
  mov    (%rdx,%rax,8),%r8
  add    (%rsi,%rax,8),%r8
  mov    %r8,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L55
L9:
  ret
```

assistant: ```c
void opSumULongGASPI(void *res, void *localVal, void *dstVal, const int cnt) {
  int i;
  unsigned long *rv = (unsigned long *)res;
  unsigned long *lv = (unsigned long *)localVal;
  unsigned long *dv = (unsigned long *)dstVal;
  for (i = 0; i < cnt; i++) {
    *rv = *lv + *dv;
    lv++;
    dv++;
    rv++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gentime_string_from_tm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L29
  cmpl   $0x270f,-0x14(%rbp)
  jle    L31
L29:
  mov    $0x0,%eax
  jmp    L46
L31:
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%edi
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%esi
  mov    -0x28(%rbp),%rax
  mov    0xc(%rax),%r9d
  mov    -0x28(%rbp),%rax
  mov    0x10(%rax),%r8d
  mov    -0x28(%rbp),%rax
  mov    0x18(%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x14(%rbp),%edx
  lea    -0x10(%rbp),%rax
  push   %rdi
  push   %rsi
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  add    $0x10,%rsp
  cmp    $0xffffffff,%eax
  jne    L48
  movq   $0x0,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%rax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %04u%02u%02u%02u%02u%02uZ

assistant: ```c
char *gentime_string_from_tm(struct tm *tm) {
  char *ret = NULL;
  int year;
  year = tm->tm_year + 1900;
  if (year < 0 || year > 9999)
    return (NULL);
  if (asprintf(&ret, "%04u%02u%02u%02u%02u%02uZ", year, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec) == -1)
    ret = NULL;
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gentime_string_from_tm>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    (%rdi),%eax
  lea    0x76c(%rax),%edx
  mov    $0x0,%eax
  cmp    $0x270f,%edx
  ja     L23
  mov    0x18(%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rsp,%rax
  mov    0x4(%rdi),%esi
  push   %rsi
  mov    0x8(%rdi),%esi
  push   %rsi
  mov    0xc(%rdi),%r9d
  mov    0x10(%rdi),%r8d
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  add    $0x10,%rsp
  cmp    $0xffffffff,%eax
  je     L39
L33:
  mov    (%rsp),%rax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L39:
  movq   $0x0,(%rsp)
  jmp    L33
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: %04u%02u%02u%02u%02u%02uZ

assistant: ```c
char *gentime_string_from_tm(struct tm *tm) {
  char *ret = NULL;
  int year;
  year = tm->tm_year + 1900;
  if (year < 0 || year > 9999)
    return (NULL);
  if (asprintf(&ret, "%04u%02u%02u%02u%02u%02uZ", year, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec) == -1)
    ret = NULL;
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gentime_string_from_tm>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  movq   $0x0,(%rsp)
  lea    0x76c(%rax),%edx
  cmp    $0x270f,%edx
  ja     L7
  mov    0x18(%rdi),%rax
  mov    %rsp,%r10
  lea    D2(%rip),%rsi
  lea    0x1(%rax),%rcx
  mov    0x4(%rdi),%eax
  push   %rax
  mov    0x8(%rdi),%eax
  push   %rax
  mov    0xc(%rdi),%r9d
  mov    0x10(%rdi),%r8d
  mov    %r10,%rdi
  call   <asprintf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0xffffffff,%eax
  cmovne (%rsp),%r12
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: %04u%02u%02u%02u%02u%02uZ

assistant: ```c
char *gentime_string_from_tm(struct tm *tm) {
  char *ret = NULL;
  int year;
  year = tm->tm_year + 1900;
  if (year < 0 || year > 9999)
    return (NULL);
  if (asprintf(&ret, "%04u%02u%02u%02u%02u%02uZ", year, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec) == -1)
    ret = NULL;
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gentime_string_from_tm>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  movq   $0x0,(%rsp)
  lea    0x76c(%rax),%edx
  cmp    $0x270f,%edx
  ja     L12
  mov    0x18(%rdi),%rax
  mov    %rsp,%r10
  lea    D4(%rip),%rsi
  lea    0x1(%rax),%rcx
  mov    0x4(%rdi),%eax
  push   %rax
  mov    0x8(%rdi),%eax
  push   %rax
  mov    0xc(%rdi),%r9d
  mov    0x10(%rdi),%r8d
  mov    %r10,%rdi
  call   <asprintf@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0xffffffff,%eax
  cmovne (%rsp),%r12
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: %04u%02u%02u%02u%02u%02uZ

assistant: ```c
char *gentime_string_from_tm(struct tm *tm) {
  char *ret = NULL;
  int year;
  year = tm->tm_year + 1900;
  if (year < 0 || year > 9999)
    return (NULL);
  if (asprintf(&ret, "%04u%02u%02u%02u%02u%02uZ", year, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec) == -1)
    ret = NULL;
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1e,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1e,%r8d
  mov    $0x19,%ecx
  mov    $0x14,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D3: Sum of 10, 20 and 30 = %d


tool: D13: Sum of 4, 20, 25 and 30 = %d


assistant: ```c
int main(void) {
  printf("Sum of 10, 20 and 30 = %d\n", sum(3, 10, 20, 30));
  printf("Sum of 4, 20, 25 and 30 = %d\n", sum(4, 4, 20, 25, 30));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%r8d
  mov    $0x19,%ecx
  mov    $0x14,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <sum@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D15: Sum of 10, 20 and 30 = %d


tool: D8: Sum of 4, 20, 25 and 30 = %d


assistant: ```c
int main(void) {
  printf("Sum of 10, 20 and 30 = %d\n", sum(3, 10, 20, 30));
  printf("Sum of 4, 20, 25 and 30 = %d\n", sum(4, 4, 20, 25, 30));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%ecx
  mov    $0x14,%edx
  xor    %eax,%eax
  mov    $0xa,%esi
  mov    $0x3,%edi
  call   <sum@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%r8d
  mov    $0x19,%ecx
  mov    $0x14,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <sum@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string
name: retrieve_data
arguments: data_tag: D15
datatype: string

tool: D9: Sum of 10, 20 and 30 = %d


tool: D15: Sum of 4, 20, 25 and 30 = %d


assistant: ```c
int main(void) {
  printf("Sum of 10, 20 and 30 = %d\n", sum(3, 10, 20, 30));
  printf("Sum of 4, 20, 25 and 30 = %d\n", sum(4, 4, 20, 25, 30));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1e,%ecx
  mov    $0x14,%edx
  xor    %eax,%eax
  mov    $0xa,%esi
  mov    $0x3,%edi
  call   <sum@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%r8d
  mov    $0x19,%ecx
  mov    $0x14,%edx
  mov    $0x4,%esi
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <sum@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D17: Sum of 10, 20 and 30 = %d


tool: D9: Sum of 4, 20, 25 and 30 = %d


assistant: ```c
int main(void) {
  printf("Sum of 10, 20 and 30 = %d\n", sum(3, 10, 20, 30));
  printf("Sum of 4, 20, 25 and 30 = %d\n", sum(4, 4, 20, 25, 30));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L12
  cmpl   $0x1,-0x14(%rbp)
  je     L44
  jmp    L41
L12:
  mov    $0x0,%eax
  jmp    L28
L44:
  mov    $0x1,%eax
  jmp    L28
L41:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L28:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 1;
  default:
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L9
  cmp    $0x1,%edi
  je     L9
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  lea    0x0(%rbp,%rax,1),%ebx
L9:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fib(int n) {
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 1;
  default:
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fib>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
L34:
  test   %ebx,%ebx
  je     L99
  cmp    $0x1,%ebx
  jne    L95
  add    $0x1,%r12d
L99:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L95:
  lea    -0x1(%rbx),%ebp
  xor    %r13d,%r13d
  test   %ebp,%ebp
  je     L66
L60:
  cmp    $0x1,%ebp
  je     L3
  lea    -0x1(%rbp),%r14d
  xor    %r15d,%r15d
  test   %r14d,%r14d
  je     L71
L11:
  cmp    $0x1,%r14d
  je     L90
  lea    -0x1(%r14),%edx
  xor    %ecx,%ecx
L46:
  test   %edx,%edx
  je     L89
  cmp    $0x1,%edx
  jne    L57
  add    $0x1,%ecx
L89:
  sub    $0x2,%r14d
  add    %ecx,%r15d
  test   %r14d,%r14d
  jne    L11
L71:
  sub    $0x2,%ebp
  add    %r15d,%r13d
L62:
  test   %ebp,%ebp
  jne    L60
L66:
  sub    $0x2,%ebx
  add    %r13d,%r12d
  jmp    L34
  nopl   0x0(%rax)
L3:
  add    $0x1,%r13d
  sub    $0x2,%ebx
  add    %r13d,%r12d
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L90:
  add    $0x1,%r15d
  sub    $0x2,%ebp
  add    %r15d,%r13d
  jmp    L62
  nopl   0x0(%rax)
L57:
  lea    -0x1(%rdx),%edi
  mov    %ecx,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  call   <fib>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  sub    $0x2,%edx
  add    %eax,%ecx
  jmp    L46
```

assistant: ```c
int fib(int n) {
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 1;
  default:
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fib>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
L54:
  test   %ebx,%ebx
  je     L128
  cmp    $0x1,%ebx
  jne    L17
  add    $0x1,%r12d
L128:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    -0x1(%rbx),%ebp
  xor    %r13d,%r13d
  test   %ebp,%ebp
  je     L89
L30:
  cmp    $0x1,%ebp
  je     L47
  lea    -0x1(%rbp),%r14d
  xor    %r15d,%r15d
  test   %r14d,%r14d
  je     L6
L35:
  cmp    $0x1,%r14d
  je     L44
  lea    -0x1(%r14),%edx
  xor    %ecx,%ecx
L53:
  test   %edx,%edx
  je     L18
  cmp    $0x1,%edx
  jne    L51
  add    $0x1,%ecx
L18:
  sub    $0x2,%r14d
  add    %ecx,%r15d
  test   %r14d,%r14d
  jne    L35
L6:
  sub    $0x2,%ebp
  add    %r15d,%r13d
L45:
  test   %ebp,%ebp
  jne    L30
L89:
  sub    $0x2,%ebx
  add    %r13d,%r12d
  jmp    L54
  nopl   0x0(%rax)
L47:
  add    $0x1,%r13d
  sub    $0x2,%ebx
  add    %r13d,%r12d
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%r15d
  sub    $0x2,%ebp
  add    %r15d,%r13d
  jmp    L45
  nopl   0x0(%rax)
L51:
  lea    -0x1(%rdx),%edi
  mov    %ecx,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  call   <fib>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%ecx
  sub    $0x2,%edx
  add    %eax,%ecx
  jmp    L53
```

assistant: ```c
int fib(int n) {
  switch (n) {
  case 0:
    return 0;
  case 1:
    return 1;
  default:
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<android_atomic_or>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L1:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  or     -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <android_atomic_cas@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int32_t android_atomic_or(int32_t value, volatile int32_t *ptr) {
  int32_t prev, status;
  do {
    prev = *ptr;
    status = android_atomic_cas(prev, prev | value, ptr);
  } while (__builtin_expect(status != 0, 0));
  return prev;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<android_atomic_or>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
L0:
  mov    0x0(%rbp),%rbx
  mov    %rbx,%rsi
  or     %r12,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <android_atomic_cas@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L0
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int32_t android_atomic_or(int32_t value, volatile int32_t *ptr) {
  int32_t prev, status;
  do {
    prev = *ptr;
    status = android_atomic_cas(prev, prev | value, ptr);
  } while (__builtin_expect(status != 0, 0));
  return prev;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<android_atomic_or>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%r12
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r12,%rdi
  or     %rbp,%rsi
  call   <android_atomic_cas@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setne  %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int32_t android_atomic_or(int32_t value, volatile int32_t *ptr) {
  int32_t prev, status;
  do {
    prev = *ptr;
    status = android_atomic_cas(prev, prev | value, ptr);
  } while (__builtin_expect(status != 0, 0));
  return prev;
}
```