ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hex_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xf,%eax
  jg     L11
  mov    $0x30,%edi
  call   <putchar@plt>
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %x 

assistant: ```c
void hex_trace(const uint8_t *buffer, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    if (buffer[i] < 0x10)
      printf("0");
    printf("%x ", buffer[i] & (~((~0) << 8)));
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_trace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r13
  lea    D6(%rip),%r12
  jmp    L38
L13:
  movzbl 0x0(%rbp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L3
L38:
  mov    %rbx,%rbp
  cmpl   $0xf,(%rbx)
  jg     L13
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L13
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %x 

assistant: ```c
void hex_trace(const uint8_t *buffer, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    if (buffer[i] < 0x10)
      printf("0");
    printf("%x ", buffer[i] & (~((~0) << 8)));
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hex_trace>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L26
L34:
  movzbl %sil,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L39
L26:
  mov    (%rbx),%esi
  cmp    $0xf,%esi
  jg     L34
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    (%rbx),%esi
  jmp    L34
  nopl   0x0(%rax)
L39:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: %x 

assistant: ```c
void hex_trace(const uint8_t *buffer, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    if (buffer[i] < 0x10)
      printf("0");
    printf("%x ", buffer[i] & (~((~0) << 8)));
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex_trace>:
  endbr64
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L44
L38:
  movzbl %sil,%esi
L29:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L25
L44:
  mov    (%rbx),%esi
  cmp    $0xf,%esi
  jg     L38
  mov    $0x30,%edi
  call   <putchar@plt>
  movzbl (%rbx),%esi
  jmp    L29
  nopl   (%rax)
L25:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L23:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %x 

assistant: ```c
void hex_trace(const uint8_t *buffer, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    if (buffer[i] < 0x10)
      printf("0");
    printf("%x ", buffer[i] & (~((~0) << 8)));
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mask_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L8:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mask_shift(int d) {
  int n;
  n = 0;
  while ((d & 1) == 0) {
    d = d >> 1;
    n++;
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mask_shift>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L15
L16:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L16
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int mask_shift(int d) {
  int n;
  n = 0;
  while ((d & 1) == 0) {
    d = d >> 1;
    n++;
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mask_shift>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L12
  nopl   0x0(%rax,%rax,1)
L19:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L19
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mask_shift(int d) {
  int n;
  n = 0;
  while ((d & 1) == 0) {
    d = d >> 1;
    n++;
  }
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<mask_shift>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L15
  nopl   0x0(%rax,%rax,1)
L2:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L2
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mask_shift(int d) {
  int n;
  n = 0;
  while ((d & 1) == 0) {
    d = d >> 1;
    n++;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<callee5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%r14d
  mov    %r14d,%edi
  call   <increment@plt>
  mov    %eax,%r13d
  mov    %r13d,%edi
  call   <increment@plt>
  mov    %eax,%r12d
  mov    %r12d,%edi
  call   <increment@plt>
  mov    %eax,%ebx
  mov    %ebx,%edi
  call   <increment@plt>
  mov    %eax,%r15d
  lea    (%r14,%r13,1),%eax
  add    %r12d,%eax
  add    %ebx,%eax
  add    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int callee5(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  register int l5 = increment(l4);
  return l1 + l2 + l3 + l4 + l5;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<callee5>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <increment@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%r13d
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <increment@plt>
  mov    %eax,%edx
  lea    (%rbx,%r13,1),%eax
  add    %r12d,%eax
  add    %ebp,%eax
  add    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int callee5(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  register int l5 = increment(l4);
  return l1 + l2 + l3 + l4 + l5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<callee5>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r13d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <increment@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  lea    (%rbx,%r13,1),%eax
  pop    %rbx
  add    %r12d,%eax
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  add    %r8d,%eax
  pop    %r13
  ret
```

assistant: ```c
int callee5(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  register int l5 = increment(l4);
  return l1 + l2 + l3 + l4 + l5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<callee5>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r13d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <increment@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <increment@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  lea    (%rbx,%r13,1),%eax
  pop    %rbx
  add    %r12d,%eax
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  add    %r8d,%eax
  pop    %r13
  ret
```

assistant: ```c
int callee5(int n) {
  register int l1 = increment(n);
  register int l2 = increment(l1);
  register int l3 = increment(l2);
  register int l4 = increment(l3);
  register int l5 = increment(l4);
  return l1 + l2 + l3 + l4 + l5;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6548,-0x18(%rbp)
  movw   $0x6f,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x12(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: A=%s
B=%s


assistant: ```c
int main() {
  char A[] = "Hello";
  char B[10];
  strcpy(B, A);
  printf("A=%s\nB=%s\n", A, B);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6548,0x8(%rsp)
  movw   $0x6f,0xc(%rsp)
  lea    0x8(%rsp),%rbx
  lea    0xe(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: A=%s
B=%s


assistant: ```c
int main() {
  char A[] = "Hello";
  char B[10];
  strcpy(B, A);
  printf("A=%s\nB=%s\n", A, B);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0xe(%rsp),%r12
  mov    $0x6f,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %ax,0xc(%rsp)
  movl   $0x6c6c6548,0x8(%rsp)
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: A=%s
B=%s


assistant: ```c
int main() {
  char A[] = "Hello";
  char B[10];
  strcpy(B, A);
  printf("A=%s\nB=%s\n", A, B);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0xe(%rsp),%r12
  mov    $0x6f,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %ax,0xc(%rsp)
  movl   $0x6c6c6548,0x8(%rsp)
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: A=%s
B=%s


assistant: ```c
int main() {
  char A[] = "Hello";
  char B[10];
  strcpy(B, A);
  printf("A=%s\nB=%s\n", A, B);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<AsciiToHex>:
  endbr64
  movl   $0x0,(%rsi)
  cmpb   $0x30,(%rdi)
  je     L1
L48:
  mov    %rdi,%rdx
  add    $0x8,%rdi
  jmp    L32
L1:
  movzbl 0x1(%rdi),%eax
  and    $0xffffffdf,%eax
  lea    0x2(%rdi),%rdx
  cmp    $0x58,%al
  cmove  %rdx,%rdi
  jmp    L48
L17:
  lea    -0x61(%rax),%r8d
  cmp    $0x5,%r8b
  ja     L72
  movsbl %al,%eax
  lea    -0x57(%rcx,%rax,1),%eax
L23:
  mov    %eax,(%rsi)
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L88
L32:
  cmpb   $0x0,(%rdx)
  je     L0
  mov    (%rsi),%ecx
  shl    $0x4,%ecx
  mov    %ecx,(%rsi)
  movzbl (%rdx),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L17
  movsbl %al,%eax
  lea    -0x30(%rcx,%rax,1),%eax
  jmp    L23
L72:
  lea    -0x41(%rax),%r8d
  cmp    $0x5,%r8b
  ja     L59
  movsbl %al,%eax
  lea    -0x37(%rcx,%rax,1),%eax
  jmp    L23
L0:
  mov    $0x1,%eax
  ret
L59:
  mov    $0x0,%eax
  ret
L88:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int AsciiToHex(char *s, unsigned int *val) {
  int n;
  *val = 0;
  if (s[0] == '0' && ((s[1] == 'x') || (s[1] == 'X')))
    s += 2;
  n = 0;
  while ((n < 8) && (s[n] != 0)) {
    *val <<= 4;
    if ((s[n] >= '0') && (s[n] <= '9'))
      *val += (s[n] - '0');
    else if ((s[n] >= 'a') && (s[n] <= 'f'))
      *val += (s[n] - 0x57);
    else if ((s[n] >= 'A') && (s[n] <= 'F'))
      *val += (s[n] - 0x37);
    else
      return 0;
    n++;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<AsciiToHex>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  je     L78
L40:
  lea    0x8(%rdi),%r8
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L97:
  lea    -0x30(%rdx,%rax,1),%eax
L59:
  add    $0x1,%rdi
  mov    %eax,(%rsi)
  cmp    %r8,%rdi
  je     L80
L75:
  movzbl (%rdi),%eax
L32:
  test   %al,%al
  je     L80
  mov    (%rsi),%edx
  shl    $0x4,%edx
  mov    %edx,(%rsi)
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L97
  lea    -0x61(%rax),%ecx
  cmp    $0x5,%cl
  ja     L109
  lea    -0x57(%rdx,%rax,1),%eax
  add    $0x1,%rdi
  mov    %eax,(%rsi)
  cmp    %r8,%rdi
  jne    L75
L80:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L109:
  lea    -0x41(%rax),%ecx
  cmp    $0x5,%cl
  ja     L47
  lea    -0x37(%rdx,%rax,1),%eax
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L78:
  movzbl 0x1(%rdi),%edx
  and    $0xffffffdf,%edx
  cmp    $0x58,%dl
  jne    L40
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  jmp    L40
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int AsciiToHex(char *s, unsigned int *val) {
  int n;
  *val = 0;
  if (s[0] == '0' && ((s[1] == 'x') || (s[1] == 'X')))
    s += 2;
  n = 0;
  while ((n < 8) && (s[n] != 0)) {
    *val <<= 4;
    if ((s[n] >= '0') && (s[n] <= '9'))
      *val += (s[n] - '0');
    else if ((s[n] >= 'a') && (s[n] <= 'f'))
      *val += (s[n] - 0x57);
    else if ((s[n] >= 'A') && (s[n] <= 'F'))
      *val += (s[n] - 0x37);
    else
      return 0;
    n++;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<writev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
ssize_t writev(int fildes, const struct iovec *iov, int iovcnt) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writev>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t writev(int fildes, const struct iovec *iov, int iovcnt) {
  errno = ENOSYS;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writev>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t writev(int fildes, const struct iovec *iov, int iovcnt) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<writev>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t writev(int fildes, const struct iovec *iov, int iovcnt) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<decodeHEX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L47
L94:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    $0x2b,%eax
  jne    L76
  movl   $0x20,-0x1c(%rbp)
  jmp    L32
L76:
  mov    -0x1c(%rbp),%eax
  cmp    $0x25,%eax
  jne    L32
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ishex@plt>
  test   %eax,%eax
  je     L78
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ishex@plt>
  test   %eax,%eax
  je     L78
  mov    -0x28(%rbp),%rax
  lea    -0x2(%rax),%rcx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L32
L78:
  mov    $0xffffffff,%eax
  jmp    L23
L32:
  cmpq   $0x0,-0x30(%rbp)
  je     L41
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L41:
  addq   $0x1,-0x18(%rbp)
L47:
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L94
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L100
  call   <__stack_chk_fail@plt>
L100:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string

tool: D5: %2x

assistant: ```c
int decodeHEX(char *s, char *dec) {
  char *o;
  char *end = s + strlen(s);
  int c;
  for (o = dec; s <= end; o++) {
    c = *s++;
    if (c == '+') {
      c = ' ';
    } else if (c == '%' && (!ishex(*s++) || !ishex(*s++) || !sscanf(s - 2, "%2x", &c))) {
      return -1;
    }
    if (dec)
      *o = c;
  }
  return o - dec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decodeHEX>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movslq %eax,%r13
  add    %rbx,%r13
  jb     L92
  mov    %r14,%rbp
  jmp    L72
L6:
  movl   $0x20,0x4(%rsp)
  mov    %r12,%rbx
L76:
  test   %r14,%r14
  je     L63
  mov    0x4(%rsp),%eax
  mov    %al,0x0(%rbp)
L63:
  add    $0x1,%rbp
  cmp    %r13,%rbx
  ja     L15
L72:
  lea    0x1(%rbx),%r12
  movsbl (%rbx),%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x2b,%eax
  je     L6
  cmp    $0x25,%eax
  je     L38
  mov    %r12,%rbx
  jmp    L76
L38:
  movsbl 0x1(%rbx),%edi
  call   <ishex@plt>
  test   %eax,%eax
  je     L78
  lea    0x3(%rbx),%r15
  movsbl 0x2(%rbx),%edi
  call   <ishex@plt>
  test   %eax,%eax
  je     L19
  lea    0x4(%rsp),%rdx
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L54
  mov    %r15,%rbx
  jmp    L76
L92:
  mov    %r14,%rbp
L15:
  mov    %ebp,%eax
  sub    %r14d,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  mov    $0xffffffff,%eax
  jmp    L32
L19:
  mov    $0xffffffff,%eax
  jmp    L32
L54:
  mov    $0xffffffff,%eax
  jmp    L32
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: %2x

assistant: ```c
int decodeHEX(char *s, char *dec) {
  char *o;
  char *end = s + strlen(s);
  int c;
  for (o = dec; s <= end; o++) {
    c = *s++;
    if (c == '+') {
      c = ' ';
    } else if (c == '%' && (!ishex(*s++) || !ishex(*s++) || !sscanf(s - 2, "%2x", &c))) {
      return -1;
    }
    if (dec)
      *o = c;
  }
  return o - dec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decodeHEX>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movslq %eax,%r14
  add    %rbx,%r14
  jb     L31
  mov    %r15,%rbp
  lea    D2(%rip),%r13
  jmp    L46
  nopl   (%rax)
L27:
  cmp    $0x25,%eax
  je     L106
  mov    %r12,%rbx
L67:
  test   %r15,%r15
  je     L49
  mov    0x14(%rsp),%eax
  mov    %al,0x0(%rbp)
L49:
  add    $0x1,%rbp
  cmp    %r14,%rbx
  ja     L86
L46:
  movsbl (%rbx),%eax
  lea    0x1(%rbx),%r12
  mov    %eax,0x14(%rsp)
  cmp    $0x2b,%eax
  jne    L27
  movl   $0x20,0x14(%rsp)
  mov    %r12,%rbx
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L106:
  movsbl 0x1(%rbx),%edi
  call   <ishex@plt>
  test   %eax,%eax
  je     L23
  movsbl 0x2(%rbx),%edi
  lea    0x3(%rbx),%rax
  mov    %rax,0x8(%rsp)
  call   <ishex@plt>
  test   %eax,%eax
  je     L23
  lea    0x14(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L23
  mov    0x8(%rsp),%rbx
  jmp    L67
  cs nopw 0x0(%rax,%rax,1)
L86:
  mov    %ebp,%eax
  sub    %r15d,%eax
L52:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L102
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L23:
  mov    $0xffffffff,%eax
  jmp    L52
L31:
  xor    %eax,%eax
  jmp    L52
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: %2x

assistant: ```c
int decodeHEX(char *s, char *dec) {
  char *o;
  char *end = s + strlen(s);
  int c;
  for (o = dec; s <= end; o++) {
    c = *s++;
    if (c == '+') {
      c = ' ';
    } else if (c == '%' && (!ishex(*s++) || !ishex(*s++) || !sscanf(s - 2, "%2x", &c))) {
      return -1;
    }
    if (dec)
      *o = c;
  }
  return o - dec;
}
```