ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parsekey_special>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x83,-0x4(%rbp)
  je     L2
  cmpl   $0x83,-0x4(%rbp)
  jg     L42
  cmpl   $0x82,-0x4(%rbp)
  je     L6
  cmpl   $0x82,-0x4(%rbp)
  jg     L42
  cmpl   $0x80,-0x4(%rbp)
  je     L34
  cmpl   $0x81,-0x4(%rbp)
  jmp    L42
L2:
  nop
  jmp    L42
L6:
  nop
  jmp    L42
L34:
  nop
L42:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void parsekey_special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    break;
  case GLUT_KEY_DOWN:
    break;
  case GLUT_KEY_RIGHT:
    break;
  case GLUT_KEY_LEFT:
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<parsekey_special>:
  endbr64
  ret
```

assistant: ```c
void parsekey_special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    break;
  case GLUT_KEY_DOWN:
    break;
  case GLUT_KEY_RIGHT:
    break;
  case GLUT_KEY_LEFT:
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parsekey_special>:
  endbr64
  ret
```

assistant: ```c
void parsekey_special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    break;
  case GLUT_KEY_DOWN:
    break;
  case GLUT_KEY_RIGHT:
    break;
  case GLUT_KEY_LEFT:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parsekey_special>:
  endbr64
  ret
```

assistant: ```c
void parsekey_special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    break;
  case GLUT_KEY_DOWN:
    break;
  case GLUT_KEY_RIGHT:
    break;
  case GLUT_KEY_LEFT:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0xffffffff,-0x3c(%rbp)
  jne    L15
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L15:
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <print_tm@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <print_tm@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D43
type_infered: string
name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D20
type_infered: string

tool: D43: t1 = %ld, t2 = %ld


tool: D45: gettimeofday

tool: D16: ret %d, tv.sec = %ld, tv.usec = %ld


tool: D24: t3 = %ld


tool: D18: from asctime: %s

tool: D20: from ctime: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  time_t t1, t2;
  t1 = time(&t2);
  printf("t1 = %ld, t2 = %ld\n", t1, t2);
  struct timeval tv;
  ret = gettimeofday(&tv, NULL);
  if (ret == -1)
    perror("gettimeofday");
  printf("ret %d, tv.sec = %ld, tv.usec = %ld\n", ret, tv.tv_sec, tv.tv_usec);
  struct tm *tm1 = gmtime(&t1);
  struct tm *tm2 = localtime(&t2);
  print_tm(tm1);
  print_tm(tm2);
  time_t t3 = mktime(tm2);
  printf("t3 = %ld\n", t3);
  printf("from asctime: %s", asctime(tm2));
  printf("from ctime: %s", ctime(&t3));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  call   <time@plt>
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  mov    0x10(%rsp),%rdx
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L22
L23:
  mov    0x20(%rsp),%ecx
  mov    0x24(%rsp),%edx
  mov    %ebx,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rdi
  call   <gmtime@plt>
  mov    %rax,%rbp
  lea    0x10(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <print_tm@plt>
  mov    %rbx,%rdi
  call   <print_tm@plt>
  mov    %rbx,%rdi
  call   <mktime@plt>
  mov    %rax,%rsi
  mov    %rax,0x18(%rsp)
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <asctime@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%rsi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D29(%rip),%rdi
  call   <perror@plt>
  jmp    L23
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D43
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D53
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string

tool: D43: t1 = %ld, t2 = %ld


tool: D11: ret %d, tv.sec = %ld, tv.usec = %ld


tool: D5: t3 = %ld


tool: D1: from asctime: %s

tool: D53: from ctime: %s

tool: D29: gettimeofday

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  time_t t1, t2;
  t1 = time(&t2);
  printf("t1 = %ld, t2 = %ld\n", t1, t2);
  struct timeval tv;
  ret = gettimeofday(&tv, NULL);
  if (ret == -1)
    perror("gettimeofday");
  printf("ret %d, tv.sec = %ld, tv.usec = %ld\n", ret, tv.tv_sec, tv.tv_usec);
  struct tm *tm1 = gmtime(&t1);
  struct tm *tm2 = localtime(&t2);
  print_tm(tm1);
  print_tm(tm2);
  time_t t3 = mktime(tm2);
  printf("t3 = %ld\n", t3);
  printf("from asctime: %s", asctime(tm2));
  printf("from ctime: %s", ctime(&t3));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    0x20(%rsp),%rdx
  lea    D54(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    0x30(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  je     L15
L2:
  mov    0x30(%rsp),%ecx
  mov    0x34(%rsp),%edx
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rdi
  call   <gmtime@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <print_tm@plt>
  mov    %rbp,%rdi
  call   <print_tm@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  lea    D36(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <asctime@plt>
  lea    D21(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x28(%rsp),%rdi
  call   <ctime@plt>
  lea    D39(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  lea    D59(%rip),%rdi
  mov    %eax,0xc(%rsp)
  call   <perror@plt>
  mov    0xc(%rsp),%esi
  jmp    L2
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D54
type: string
name: parse_data
arguments: tag: D56
type: string
name: parse_data
arguments: tag: D36
type: string
name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D39
type: string
name: parse_data
arguments: tag: D59
type: string

tool: D54: t1 = %ld, t2 = %ld


tool: D56: ret %d, tv.sec = %ld, tv.usec = %ld


tool: D36: t3 = %ld


tool: D21: from asctime: %s

tool: D39: from ctime: %s

tool: D59: gettimeofday

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  time_t t1, t2;
  t1 = time(&t2);
  printf("t1 = %ld, t2 = %ld\n", t1, t2);
  struct timeval tv;
  ret = gettimeofday(&tv, NULL);
  if (ret == -1)
    perror("gettimeofday");
  printf("ret %d, tv.sec = %ld, tv.usec = %ld\n", ret, tv.tv_sec, tv.tv_usec);
  struct tm *tm1 = gmtime(&t1);
  struct tm *tm2 = localtime(&t2);
  print_tm(tm1);
  print_tm(tm2);
  time_t t3 = mktime(tm2);
  printf("t3 = %ld\n", t3);
  printf("from asctime: %s", asctime(tm2));
  printf("from ctime: %s", ctime(&t3));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    0x20(%rsp),%rdx
  lea    D28(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    0x30(%rsp),%rdi
  call   <gettimeofday@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  je     L25
L20:
  mov    0x30(%rsp),%ecx
  mov    0x34(%rsp),%edx
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rdi
  call   <gmtime@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <localtime@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <print_tm@plt>
  mov    %rbp,%rdi
  call   <print_tm@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <asctime@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x28(%rsp),%rdi
  call   <ctime@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    D50(%rip),%rdi
  mov    %eax,0xc(%rsp)
  call   <perror@plt>
  mov    0xc(%rsp),%esi
  jmp    L20
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D50
datatype: string

tool: D28: t1 = %ld, t2 = %ld


tool: D2: ret %d, tv.sec = %ld, tv.usec = %ld


tool: D6: t3 = %ld


tool: D9: from asctime: %s

tool: D1: from ctime: %s

tool: D50: gettimeofday

assistant: ```c
int main(int argc, char *argv[]) {
  int ret = 0;
  time_t t1, t2;
  t1 = time(&t2);
  printf("t1 = %ld, t2 = %ld\n", t1, t2);
  struct timeval tv;
  ret = gettimeofday(&tv, NULL);
  if (ret == -1)
    perror("gettimeofday");
  printf("ret %d, tv.sec = %ld, tv.usec = %ld\n", ret, tv.tv_sec, tv.tv_usec);
  struct tm *tm1 = gmtime(&t1);
  struct tm *tm2 = localtime(&t2);
  print_tm(tm1);
  print_tm(tm2);
  time_t t3 = mktime(tm2);
  printf("t3 = %ld\n", t3);
  printf("from asctime: %s", asctime(tm2));
  printf("from ctime: %s", ctime(&t3));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<toStringSJIS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_set_buffer@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_euc2shift@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_replace_buffer@plt>
  leave
  ret
```

assistant: ```c
char *toStringSJIS(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _euc2shift((unsigned char *)str, buf);
  return _replace_buffer(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<toStringSJIS>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_set_buffer@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <_euc2shift@plt>
  mov    %rbx,%rdi
  call   <_replace_buffer@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *toStringSJIS(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _euc2shift((unsigned char *)str, buf);
  return _replace_buffer(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<toStringSJIS>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_set_buffer@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <_euc2shift@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_replace_buffer@plt>
```

assistant: ```c
char *toStringSJIS(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _euc2shift((unsigned char *)str, buf);
  return _replace_buffer(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<toStringSJIS>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_set_buffer@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <_euc2shift@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_replace_buffer@plt>
```

assistant: ```c
char *toStringSJIS(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _euc2shift((unsigned char *)str, buf);
  return _replace_buffer(buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_foldedness>:
  endbr64
  test   %esi,%esi
  jle    L16
  mulsd  D1(%rip),%xmm0
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rcx
  mov    $0x0,%edx
  movsd  D3(%rip),%xmm3
  movapd %xmm3,%xmm4
  jmp    L14
L22:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L21
L14:
  movsd  (%rax),%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  comisd %xmm2,%xmm3
  jb     L22
  addsd  %xmm0,%xmm1
  comisd %xmm4,%xmm1
  sbb    $0xffffffff,%edx
  jmp    L22
L16:
  mov    $0x0,%edx
L21:
  cmp    %edx,%esi
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D3
type_infered: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D3": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

assistant: ```c
int check_foldedness(double array[], double omega, int size) {
  int i, count = 0, folded = 0;
  double diff_upper, diff_lower;
  for (i = 0; i < size; i++) {
    diff_upper = array[i] + (omega / 2.0);
    diff_lower = array[i] - (omega / 2.0);
    if ((diff_lower <= 1E-5) && (diff_upper >= 1E-5))
      count++;
  }
  if (count == size)
    folded = 1;
  return (folded);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_foldedness>:
  endbr64
  test   %esi,%esi
  jle    L25
  mulsd  D5(%rip),%xmm0
  lea    -0x1(%rsi),%eax
  movsd  D9(%rip),%xmm3
  lea    0x8(%rdi,%rax,8),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  movsd  (%rdi),%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  comisd %xmm2,%xmm3
  jb     L4
  addsd  %xmm0,%xmm1
  comisd %xmm3,%xmm1
  sbb    $0xffffffff,%eax
L4:
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L17
  cmp    %eax,%esi
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  cmp    %eax,%esi
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: byte[8]
name: disassemble_data
arguments: data_label: D9
type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D9": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

assistant: ```c
int check_foldedness(double array[], double omega, int size) {
  int i, count = 0, folded = 0;
  double diff_upper, diff_lower;
  for (i = 0; i < size; i++) {
    diff_upper = array[i] + (omega / 2.0);
    diff_lower = array[i] - (omega / 2.0);
    if ((diff_lower <= 1E-5) && (diff_upper >= 1E-5))
      count++;
  }
  if (count == size)
    folded = 1;
  return (folded);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_foldedness>:
  endbr64
  test   %esi,%esi
  jle    L2
  mulsd  D10(%rip),%xmm0
  lea    -0x1(%rsi),%eax
  movsd  D5(%rip),%xmm3
  lea    0x8(%rdi,%rax,8),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  movsd  (%rdi),%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  comisd %xmm2,%xmm3
  jb     L1
  addsd  %xmm0,%xmm1
  comisd %xmm3,%xmm1
  sbb    $0xffffffff,%eax
L1:
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L24
  cmp    %eax,%esi
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  cmp    %eax,%esi
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: byte[8]
name: read_data
arguments: data_tag: D5
type_infered: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D5": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

assistant: ```c
int check_foldedness(double array[], double omega, int size) {
  int i, count = 0, folded = 0;
  double diff_upper, diff_lower;
  for (i = 0; i < size; i++) {
    diff_upper = array[i] + (omega / 2.0);
    diff_lower = array[i] - (omega / 2.0);
    if ((diff_lower <= 1E-5) && (diff_upper >= 1E-5))
      count++;
  }
  if (count == size)
    folded = 1;
  return (folded);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<menuCalcul>:
  endbr64
  push   %rbp
  lea    D85(%rip),%rdi
  lea    D60(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D85
type_guessed: string
name: disassemble_data
arguments: tag: D60
type_guessed: string
name: disassemble_data
arguments: tag: D74
type_guessed: string
name: disassemble_data
arguments: tag: D50
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string
name: disassemble_data
arguments: tag: D59
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D64
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D85: *************************************************

tool: D60: 
*************************************************

tool: D74: 
***************CALCULATEUR D'IMPOT***************

tool: D50: 
******************SUR LE REVENU******************

tool: D25: 
       Mode de calcul ? :                        

tool: D59: 
            1 - Chainage avant ?                 

tool: D16: 
            2 - Chainage arriere ?               

tool: D33: 
            3 - Chainage Av et Ar avec details ? 

tool: D64: 
            0 - Quitter ?                        

tool: D19: 
      Votre choix ? : 

tool: D11: %d

assistant: ```c
int menuCalcul() {
  int choix = 0;
  printf("*************************************************");
  printf("\n***************CALCULATEUR D'IMPOT***************");
  printf("\n******************SUR LE REVENU******************");
  printf("\n*************************************************");
  printf("\n       Mode de calcul ? :                        ");
  printf("\n            1 - Chainage avant ?                 ");
  printf("\n            2 - Chainage arriere ?               ");
  printf("\n            3 - Chainage Av et Ar avec details ? ");
  printf("\n            0 - Quitter ?                        ");
  printf("\n*************************************************");
  printf("\n*************************************************");
  printf("\n      Votre choix ? : ");
  scanf("%d", &choix);
  return choix;
}
```