ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<macttOrigtopology>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <get_num@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <get_num@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  pop    %r13
  jmp    1070 <tt_origtopology@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: ttOrigTopology

assistant: ```c
char *macttOrigtopology(char *arg) {
  int tbl;
  long top;
  top = get_num("ttOrigTopology", arg);
  tbl = (int)get_num("ttOrigTopology", arg);
  return tt_origtopology(arg, tbl, top);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SHAMD5DataWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x44034000,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  nop
L28:
  mov    -0x14(%rbp),%eax
  add    $0x118,%eax
  cltq
  mov    (%rax),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L28
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L6:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%edx
  lea    0x80(%rdx),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x4,-0x4(%rbp)
L4:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void SHAMD5DataWrite(uint32_t ui32Base, uint32_t *pui32Src) {
  uint32_t ui32Counter;
  ASSERT(ui32Base == 0x44034000);
  while (((*((volatile uint32_t *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
  }
  for (ui32Counter = 0; ui32Counter < 64; ui32Counter += 4) {
    (*((volatile uint32_t *)(ui32Base + 0x00000080 + ui32Counter))) = *pui32Src++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHAMD5DataWrite>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  cmp    $0x44034000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    0x118(%rbp),%edx
  movslq %edx,%rdx
L9:
  mov    (%rdx),%eax
  test   $0x2,%al
  je     L9
  movslq %ebp,%rbp
  lea    0x80(%rbp),%rax
  lea    0xc0(%rbp),%rsi
  sub    %rbp,%rbx
  mov    %rbx,%rcx
L3:
  mov    -0x80(%rcx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5DataWrite(uint32_t ui32Base, uint32_t *pui32Src) {
  uint32_t ui32Counter;
  ASSERT(ui32Base == 0x44034000);
  while (((*((volatile uint32_t *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
  }
  for (ui32Counter = 0; ui32Counter < 64; ui32Counter += 4) {
    (*((volatile uint32_t *)(ui32Base + 0x00000080 + ui32Counter))) = *pui32Src++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SHAMD5DataWrite>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x44034000,%ebp
  sete   %dil
  call   <ASSERT@plt>
  lea    0x118(%rbp),%edx
  movslq %edx,%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rdx),%eax
  test   $0x2,%al
  je     L1
  lea    0x80(%rbp),%eax
  sub    %rbp,%rbx
  lea    0xc0(%rbp),%rsi
  cltq
  mov    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L15:
  mov    -0x80(%rcx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5DataWrite(uint32_t ui32Base, uint32_t *pui32Src) {
  uint32_t ui32Counter;
  ASSERT(ui32Base == 0x44034000);
  while (((*((volatile uint32_t *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
  }
  for (ui32Counter = 0; ui32Counter < 64; ui32Counter += 4) {
    (*((volatile uint32_t *)(ui32Base + 0x00000080 + ui32Counter))) = *pui32Src++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SHAMD5DataWrite>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x44034000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  lea    0x118(%rbx),%edx
  movslq %edx,%rdx
  nopl   0x0(%rax)
L3:
  mov    (%rdx),%eax
  test   $0x2,%al
  je     L3
  mov    0x0(%rbp),%edx
  lea    0x80(%rbx),%eax
  cltq
  mov    %edx,(%rax)
  lea    0x84(%rbx),%eax
  mov    0x4(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x88(%rbx),%eax
  mov    0x8(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x8c(%rbx),%eax
  mov    0xc(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x90(%rbx),%eax
  mov    0x10(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x94(%rbx),%eax
  mov    0x14(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x98(%rbx),%eax
  mov    0x18(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0x9c(%rbx),%eax
  mov    0x1c(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xa0(%rbx),%eax
  mov    0x20(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xa4(%rbx),%eax
  mov    0x24(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xa8(%rbx),%eax
  mov    0x28(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xac(%rbx),%eax
  mov    0x2c(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xb0(%rbx),%eax
  mov    0x30(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xb4(%rbx),%eax
  mov    0x34(%rbp),%edx
  cltq
  mov    %edx,(%rax)
  lea    0xb8(%rbx),%eax
  mov    0x38(%rbp),%edx
  add    $0xbc,%ebx
  cltq
  movslq %ebx,%rbx
  mov    %edx,(%rax)
  mov    0x3c(%rbp),%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SHAMD5DataWrite(uint32_t ui32Base, uint32_t *pui32Src) {
  uint32_t ui32Counter;
  ASSERT(ui32Base == 0x44034000);
  while (((*((volatile uint32_t *)(ui32Base + 0x00000118))) & 0x00000002) == 0) {
  }
  for (ui32Counter = 0; ui32Counter < 64; ui32Counter += 4) {
    (*((volatile uint32_t *)(ui32Base + 0x00000080 + ui32Counter))) = *pui32Src++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cftbsub_128_C>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <cft1st_128@plt>
  mov    %rbx,%rdi
  call   <cftmdl_128@plt>
  mov    %rbx,%rax
  lea    0x80(%rbx),%rdx
  movss  D8(%rip),%xmm10
L3:
  movss  (%rax),%xmm1
  movss  0x80(%rax),%xmm4
  movaps %xmm1,%xmm5
  addss  %xmm4,%xmm5
  movss  0x4(%rax),%xmm3
  movss  0x84(%rax),%xmm0
  movaps %xmm3,%xmm2
  xorps  %xmm10,%xmm2
  subss  %xmm0,%xmm2
  subss  %xmm4,%xmm1
  subss  %xmm3,%xmm0
  movss  0x100(%rax),%xmm3
  movss  0x180(%rax),%xmm9
  movaps %xmm3,%xmm7
  addss  %xmm9,%xmm7
  movss  0x104(%rax),%xmm4
  movss  0x184(%rax),%xmm8
  movaps %xmm4,%xmm6
  addss  %xmm8,%xmm6
  subss  %xmm9,%xmm3
  subss  %xmm8,%xmm4
  movaps %xmm5,%xmm8
  addss  %xmm7,%xmm8
  movss  %xmm8,(%rax)
  movaps %xmm2,%xmm8
  subss  %xmm6,%xmm8
  movss  %xmm8,0x4(%rax)
  subss  %xmm7,%xmm5
  movss  %xmm5,0x100(%rax)
  addss  %xmm6,%xmm2
  movss  %xmm2,0x104(%rax)
  movaps %xmm1,%xmm2
  subss  %xmm4,%xmm2
  movss  %xmm2,0x80(%rax)
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  %xmm2,0x84(%rax)
  addss  %xmm4,%xmm1
  movss  %xmm1,0x180(%rax)
  addss  %xmm3,%xmm0
  movss  %xmm0,0x184(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L3
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x80]}

assistant: ```c
void cftbsub_128_C(float *a) {
  int j, j1, j2, j3, l;
  float x0r, x0i, x1r, x1i, x2r, x2i, x3r, x3i;
  cft1st_128(a);
  cftmdl_128(a);
  l = 32;
  for (j = 0; j < l; j += 2) {
    j1 = j + l;
    j2 = j1 + l;
    j3 = j2 + l;
    x0r = a[j] + a[j1];
    x0i = -a[j + 1] - a[j1 + 1];
    x1r = a[j] - a[j1];
    x1i = -a[j + 1] + a[j1 + 1];
    x2r = a[j2] + a[j3];
    x2i = a[j2 + 1] + a[j3 + 1];
    x3r = a[j2] - a[j3];
    x3i = a[j2 + 1] - a[j3 + 1];
    a[j] = x0r + x2r;
    a[j + 1] = x0i - x2i;
    a[j2] = x0r - x2r;
    a[j2 + 1] = x0i + x2i;
    a[j1] = x1r - x3i;
    a[j1 + 1] = x1i - x3r;
    a[j3] = x1r + x3i;
    a[j3 + 1] = x1i + x3r;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cftbsub_128_C>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <cft1st_128@plt>
  mov    %rbx,%rdi
  call   <cftmdl_128@plt>
  mov    %rbx,%rdi
  lea    0x80(%rbx),%rax
  movss  D3(%rip),%xmm10
  nopl   0x0(%rax,%rax,1)
L3:
  movss  0x4(%rdi),%xmm3
  movss  (%rdi),%xmm1
  add    $0x8,%rdi
  movss  0x7c(%rdi),%xmm0
  movss  0x78(%rdi),%xmm4
  movss  0x178(%rdi),%xmm9
  movaps %xmm3,%xmm2
  movaps %xmm1,%xmm5
  movss  0x17c(%rdi),%xmm8
  xorps  %xmm10,%xmm2
  addss  %xmm4,%xmm5
  subss  %xmm4,%xmm1
  movss  0xfc(%rdi),%xmm4
  subss  %xmm0,%xmm2
  subss  %xmm3,%xmm0
  movss  0xf8(%rdi),%xmm3
  movaps %xmm4,%xmm6
  subss  %xmm8,%xmm4
  movaps %xmm3,%xmm7
  addss  %xmm8,%xmm6
  movaps %xmm5,%xmm8
  addss  %xmm9,%xmm7
  subss  %xmm9,%xmm3
  addss  %xmm7,%xmm8
  subss  %xmm7,%xmm5
  movss  %xmm8,-0x8(%rdi)
  movaps %xmm2,%xmm8
  addss  %xmm6,%xmm2
  subss  %xmm6,%xmm8
  movss  %xmm5,0xf8(%rdi)
  movss  %xmm2,0xfc(%rdi)
  movaps %xmm1,%xmm2
  addss  %xmm4,%xmm1
  subss  %xmm4,%xmm2
  movss  %xmm8,-0x4(%rdi)
  movss  %xmm1,0x178(%rdi)
  movss  %xmm2,0x78(%rdi)
  movaps %xmm0,%xmm2
  addss  %xmm3,%xmm0
  subss  %xmm3,%xmm2
  movss  %xmm0,0x17c(%rdi)
  movss  %xmm2,0x7c(%rdi)
  cmp    %rdi,%rax
  jne    L3
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x80]}

assistant: ```c
void cftbsub_128_C(float *a) {
  int j, j1, j2, j3, l;
  float x0r, x0i, x1r, x1i, x2r, x2i, x3r, x3i;
  cft1st_128(a);
  cftmdl_128(a);
  l = 32;
  for (j = 0; j < l; j += 2) {
    j1 = j + l;
    j2 = j1 + l;
    j3 = j2 + l;
    x0r = a[j] + a[j1];
    x0i = -a[j + 1] - a[j1 + 1];
    x1r = a[j] - a[j1];
    x1i = -a[j + 1] + a[j1 + 1];
    x2r = a[j2] + a[j3];
    x2i = a[j2 + 1] + a[j3 + 1];
    x3r = a[j2] - a[j3];
    x3i = a[j2 + 1] - a[j3 + 1];
    a[j] = x0r + x2r;
    a[j + 1] = x0i - x2i;
    a[j2] = x0r - x2r;
    a[j2 + 1] = x0i + x2i;
    a[j1] = x1r - x3i;
    a[j1 + 1] = x1i - x3r;
    a[j3] = x1r + x3i;
    a[j3 + 1] = x1i + x3r;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  -0x40(%rbp),%xmm0
  movsd  -0x40(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L48
L28:
  movl   $0x0,-0x14(%rbp)
  jmp    L42
L10:
  mov    -0x18(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x28(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L10
  jmp    L38
L19:
  mov    -0x18(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L19
  addl   $0x1,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
void init(int seed, double *dst, int nrows, int ncols, int ld, double scale) {
  const double seed1 = scale * seed + scale;
  int i, j;
  for (i = 0; i < ncols; ++i) {
    for (j = 0; j < nrows; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed1 * (1.0 + i * nrows + j));
    }
    for (; j < ld; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  pxor   %xmm3,%xmm3
  cvtsi2sd %edi,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  test   %ecx,%ecx
  jle    L48
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r11
  mov    %edx,%r10d
  mov    %ecx,%ebp
  test   %edx,%edx
  mov    $0x0,%ebx
  cmovns %edx,%ebx
  movslq %ebx,%r13
  lea    -0x1(%r8),%r12d
  sub    %ebx,%r12d
  mov    $0x0,%r9d
  mov    $0x0,%esi
  mov    $0x0,%edi
  movsd  D2(%rip),%xmm4
  mov    %edx,%ecx
  add    %r13,%r12
  lea    0x8(%r11),%r14
  jmp    L4
L39:
  pxor   %xmm1,%xmm1
  cvtsi2sd %r9d,%xmm1
  addsd  %xmm4,%xmm1
  movslq %esi,%rax
  lea    (%r11,%rax,8),%rdx
  mov    $0x0,%eax
L12:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
L14:
  cmp    %ebx,%r8d
  jle    L49
  movslq %esi,%rdx
  lea    0x0(%r13,%rdx,1),%rax
  lea    (%r11,%rax,8),%rax
  add    %r12,%rdx
  lea    (%r14,%rdx,8),%rdx
L17:
  movsd  %xmm3,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L17
L49:
  add    $0x1,%edi
  add    %r8d,%esi
  add    %r10d,%r9d
  cmp    %edi,%ebp
  je     L32
L4:
  test   %r10d,%r10d
  jg     L39
  jmp    L14
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
void init(int seed, double *dst, int nrows, int ncols, int ld, double scale) {
  const double seed1 = scale * seed + scale;
  int i, j;
  for (i = 0; i < ncols; ++i) {
    for (j = 0; j < nrows; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed1 * (1.0 + i * nrows + j));
    }
    for (; j < ld; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<init>:
  endbr64
  pxor   %xmm3,%xmm3
  cvtsi2sd %edi,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  test   %ecx,%ecx
  jle    L6
  push   %r15
  mov    %rsi,%r11
  movsd  D5(%rip),%xmm4
  mov    %edx,%r10d
  push   %r14
  lea    0x8(%r11),%r14
  push   %r13
  push   %r12
  lea    -0x1(%r8),%r12d
  push   %rbp
  mov    %ecx,%ebp
  lea    -0x1(%rdx),%ecx
  push   %rbx
  xor    %ebx,%ebx
  test   %edx,%edx
  cmovns %edx,%ebx
  xor    %r9d,%r9d
  xor    %esi,%esi
  xor    %edi,%edi
  movslq %ebx,%r13
  sub    %ebx,%r12d
  add    %r13,%r12
  nopl   0x0(%rax)
L42:
  test   %r10d,%r10d
  jle    L35
  pxor   %xmm1,%xmm1
  movslq %esi,%rax
  cvtsi2sd %r9d,%xmm1
  lea    (%r11,%rax,8),%rdx
  xor    %eax,%eax
  addsd  %xmm4,%xmm1
  nopl   0x0(%rax,%rax,1)
L53:
  pxor   %xmm0,%xmm0
  mov    %rax,%r15
  cvtsi2sd %eax,%xmm0
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%r15
  jne    L53
L35:
  cmp    %r8d,%ebx
  jge    L56
  movslq %esi,%rdx
  lea    0x0(%r13,%rdx,1),%rax
  add    %r12,%rdx
  lea    (%r11,%rax,8),%rax
  lea    (%r14,%rdx,8),%rdx
  nopl   0x0(%rax)
L39:
  movsd  %xmm3,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L39
L56:
  add    $0x1,%edi
  add    %r8d,%esi
  add    %r10d,%r9d
  cmp    %edi,%ebp
  jne    L42
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: f64

tool: D5: 1

assistant: ```c
void init(int seed, double *dst, int nrows, int ncols, int ld, double scale) {
  const double seed1 = scale * seed + scale;
  int i, j;
  for (i = 0; i < ncols; ++i) {
    for (j = 0; j < nrows; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed1 * (1.0 + i * nrows + j));
    }
    for (; j < ld; ++j) {
      const int k = i * ld + j;
      dst[k] = (double)(seed);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<itimerread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getitimer@plt>
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movsd  D3(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: byte[8]

tool: {"D3": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
float itimerread(int timerid) {
  struct itimerval thistime;
  getitimer(timerid, &thistime);
  return (float)thistime.it_value.tv_sec + 1e-6 * (float)thistime.it_value.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itimerread>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <getitimer@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D5(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssq 0x8(%rsp),%xmm1
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  cvtsd2ss %xmm0,%xmm0
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: byte[8]

tool: {"D5": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
float itimerread(int timerid) {
  struct itimerval thistime;
  getitimer(timerid, &thistime);
  return (float)thistime.it_value.tv_sec + 1e-6 * (float)thistime.it_value.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<itimerread>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <getitimer@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssq (%rsp),%xmm0
  cvtsi2ssq 0x8(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D5(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  cvtsd2ss %xmm0,%xmm0
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: byte[8]

tool: {"D5": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
float itimerread(int timerid) {
  struct itimerval thistime;
  getitimer(timerid, &thistime);
  return (float)thistime.it_value.tv_sec + 1e-6 * (float)thistime.it_value.tv_usec;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itimerread>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <getitimer@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssq (%rsp),%xmm0
  cvtsi2ssq 0x8(%rsp),%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D8(%rip),%xmm0
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  cvtsd2ss %xmm0,%xmm0
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: byte[8]

tool: {"D8": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
float itimerread(int timerid) {
  struct itimerval thistime;
  getitimer(timerid, &thistime);
  return (float)thistime.it_value.tv_sec + 1e-6 * (float)thistime.it_value.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_rpc_dtablesize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D1(%rip),%eax
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,D24(%rip)
L4:
  mov    D24(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
_rpc_dtablesize() {
  static int size;
  if (size == 0) {
    size = getdtablesize();
  }
  return (size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_rpc_dtablesize>:
  endbr64
  cmpl   $0x0,D12(%rip)
  je     L8
  mov    D12(%rip),%eax
  ret
L8:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,D26(%rip)
  mov    D26(%rip),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
_rpc_dtablesize() {
  static int size;
  if (size == 0) {
    size = getdtablesize();
  }
  return (size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_rpc_dtablesize>:
  endbr64
  mov    D9(%rip),%eax
  test   %eax,%eax
  je     L0
  ret
  nop
L0:
  sub    $0x8,%rsp
  call   <getdtablesize@plt>
  mov    %eax,D1(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
_rpc_dtablesize() {
  static int size;
  if (size == 0) {
    size = getdtablesize();
  }
  return (size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_rpc_dtablesize>:
  endbr64
  mov    D18(%rip),%eax
  test   %eax,%eax
  je     L6
  ret
  nop
L6:
  sub    $0x8,%rsp
  call   <getdtablesize@plt>
  mov    %eax,D4(%rip)
  add    $0x8,%rsp
  ret
```

assistant: ```c
_rpc_dtablesize() {
  static int size;
  if (size == 0) {
    size = getdtablesize();
  }
  return (size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fix_full_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L38
L15:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5c,%eax
  je     L21
  cmp    $0x6e,%eax
  je     L23
  jmp    L56
L21:
  addl   $0x1,-0x24(%rbp)
  jmp    L51
L23:
  cmpl   $0x0,-0x24(%rbp)
  je     L56
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0xa,(%rax)
  movl   $0x0,-0x24(%rbp)
  jmp    L51
L56:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movl   $0x0,-0x24(%rbp)
L51:
  addq   $0x1,-0x20(%rbp)
L38:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fix_full_type(char *str) {
  char *s = str;
  char *r;
  char *tmp = (char *)malloc(strlen(str));
  char *result;
  int seen_backslash = 0;
  for (r = tmp; *s != '\0'; s++) {
    switch (*s) {
    case '\\':
      ++seen_backslash;
      break;
    case 'n':
      if (seen_backslash) {
        *r++ = '\n';
        seen_backslash = 0;
        break;
      }
    default:
      *r++ = *s;
      seen_backslash = 0;
    }
  }
  *r = '\0';
  result = strdup(tmp);
  free(tmp);
  free(str);
  return result;
}
```