user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    -0x1d4(%rbp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    -0x1d4(%rbp),%r9d
  movslq %r9d,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L1:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L1
L32:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L151
  orq    $0x0,-0x8(%rsp,%rax,1)
L151:
  lea    0x3(%rsp),%rbx
  mov    %rbx,%r12
  shr    $0x2,%r12
  and    $0xfffffffffffffffc,%rbx
  test   %r9d,%r9d
  jle    L6
  lea    -0x1d0(%rbp),%r14
  mov    $0x0,%r13d
  lea    D10(%rip),%r15
L158:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r13d
  mov    -0x1d4(%rbp),%r9d
  add    $0x4,%r14
  cmp    %r13d,%r9d
  jg     L158
  test   %r9d,%r9d
  jle    L6
  mov    %rbx,%rax
  mov    %r9d,%r10d
  mov    %r9d,%edx
  lea    (%rbx,%rdx,4),%rdx
L34:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L34
  mov    %r10d,%r10d
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  jmp    L56
L65:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rdi
  je     L85
  mov    %rdx,%rax
L63:
  cmp    (%rsi,%rax,4),%r8d
  jle    L65
  mov    (%rbx,%rax,4),%edx
  cmp    (%rbx,%rcx,4),%edx
  jl     L65
  add    $0x1,%edx
  mov    %edx,(%rbx,%rcx,4)
  jmp    L65
L85:
  add    $0x1,%rcx
  cmp    %r10,%rcx
  je     L6
L56:
  test   %ecx,%ecx
  jle    L85
  mov    -0x1d0(%rbp,%rcx,4),%r8d
  lea    -0x1(%rcx),%edi
  mov    %r11,%rax
  lea    -0x1d0(%rbp),%rsi
  jmp    L63
L6:
  mov    0x0(,%r12,4),%esi
  cmp    $0x1,%r9d
  jle    L115
  lea    0x4(%rbx),%rax
  lea    -0x2(%r9),%edx
  lea    0x8(%rbx,%rdx,4),%rcx
L150:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L150
L115:
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L145
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L145:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D4: Enter num

tool: D10: %d

tool: D14: %d


assistant: ```c
int main() {
  int i, arr[100], num, j;
  printf("Enter num\n");
  scanf("%d", &num);
  int lis[num];
  for (i = 0; i < num; i++)
    scanf("%d", &arr[i]);
  for (i = 0; i < num; ++i)
    lis[i] = 1;
  for (i = 0; i < num; ++i) {
    for (j = 0; j < i; ++j) {
      if (arr[i] > arr[j] && lis[i] < lis[j] + 1)
        lis[i] = lis[j] + 1;
    }
  }
  int max = lis[0];
  for (i = 1; i < num; ++i) {
    if (max < lis[i])
      max = lis[i];
  }
  printf("%d\n", max);
  return 0;
}
```