ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x41,-0x1(%rbp)
  jmp    L1
L4:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L1:
  cmpb   $0x5a,-0x1(%rbp)
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  char i;
  i = 'A';
  while (i < 'Z' + 1) {
    putchar(i);
    i = i + 1;
  }
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x41,%ebx
L9:
  mov    %ebx,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    $0x5b,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  char i;
  i = 'A';
  while (i < 'Z' + 1) {
    putchar(i);
    i = i + 1;
  }
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x41,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x5b,%ebx
  jne    L6
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
void main(void) {
  char i;
  i = 'A';
  while (i < 'Z' + 1) {
    putchar(i);
    i = i + 1;
  }
  putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x41,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    $0x5b,%ebx
  jne    L9
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
void main(void) {
  char i;
  i = 'A';
  while (i < 'Z' + 1) {
    putchar(i);
    i = i + 1;
  }
  putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<env_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  jmp    L0
L26:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edi
  call   <ft_putendl@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
L18:
  nop
  leave
  ret
```

assistant: ```c
void env_print(const char **env) {
  if (env) {
    while (*env)
      ft_putendl(*env++);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<env_print>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L24
L1:
  add    $0x8,%rbx
  call   <ft_putendl@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L1
L24:
  pop    %rbx
  ret
L16:
  ret
```

assistant: ```c
void env_print(const char **env) {
  if (env) {
    while (*env)
      ft_putendl(*env++);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<env_print>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L26
  nopl   (%rax)
L15:
  call   <ft_putendl@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L15
L26:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L29:
  ret
```

assistant: ```c
void env_print(const char **env) {
  if (env) {
    while (*env)
      ft_putendl(*env++);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<env_print>:
  endbr64
  test   %rdi,%rdi
  je     L22
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  nopl   (%rax)
L18:
  call   <ft_putendl@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L18
L4:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L22:
  ret
```

assistant: ```c
void env_print(const char **env) {
  if (env) {
    while (*env)
      ft_putendl(*env++);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rsrfft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  subq   $0x8,-0x38(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rbitrev@plt>
  movl   $0x1,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
L46:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L5
L44:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L44
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  shll   $0x2,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L46
  movl   $0x2,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L17
L10:
  shll   -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%r9
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%r8
  mov    -0x38(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x10(%rbp),%eax
  sub    $0x8,%rsp
  push   %rdi
  mov    %eax,%edi
  call   <rstage@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L10
  nop
  leave
  ret
```

assistant: ```c
void rsrfft(double *x, int m) {
  int n, is, id, i0, n2, n4, k;
  double t1;
  x--;
  n = 1 << m;
  rbitrev(x, m);
  is = 1;
  id = 4;
  do {
    for (i0 = is; i0 <= n; i0 += id) {
      t1 = x[i0];
      x[i0] = t1 + x[i0 + 1];
      x[i0 + 1] = t1 - x[i0 + 1];
    }
    is = 2 * id - 1;
    id = 4 * id;
  } while (is < n);
  n2 = 2;
  for (k = 2; k <= m; k++) {
    n2 = n2 * 2;
    n4 = n2 / 4;
    rstage(n, n2, n4, &x[0], &x[n4], &x[2 * n4], &x[3 * n4]);
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rsrfft>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  lea    -0x8(%rdi),%r12
  mov    $0x1,%ebp
  mov    %esi,%ecx
  shl    %cl,%ebp
  mov    %r12,%rdi
  call   <rbitrev@plt>
  mov    $0x4,%ecx
  mov    $0x1,%eax
L38:
  cmp    %ebp,%eax
  jg     L15
  movslq %ecx,%rdx
  cltq
L40:
  movsd  -0x8(%rbx,%rax,8),%xmm0
  movsd  (%rbx,%rax,8),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%rbx,%rax,8)
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    %rdx,%rax
  cmp    %eax,%ebp
  jge    L40
L15:
  lea    -0x1(%rcx,%rcx,1),%eax
  shl    $0x2,%ecx
  cmp    %eax,%ebp
  jg     L38
  cmp    $0x1,%r13d
  jle    L20
  mov    $0x2,%r14d
  mov    $0x2,%ebx
L16:
  add    %ebx,%ebx
  lea    0x3(%rbx),%edx
  cmovns %ebx,%edx
  sar    $0x2,%edx
  lea    (%rdx,%rdx,2),%eax
  cltq
  lea    (%r12,%rax,8),%rcx
  movslq %edx,%rax
  neg    %rax
  shl    $0x3,%rax
  lea    (%rcx,%rax,1),%r9
  sub    $0x8,%rsp
  push   %rcx
  lea    (%r9,%rax,1),%r8
  mov    %r12,%rcx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <rstage@plt>
  add    $0x1,%r14d
  add    $0x10,%rsp
  cmp    %r14d,%r13d
  jge    L16
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rsrfft(double *x, int m) {
  int n, is, id, i0, n2, n4, k;
  double t1;
  x--;
  n = 1 << m;
  rbitrev(x, m);
  is = 1;
  id = 4;
  do {
    for (i0 = is; i0 <= n; i0 += id) {
      t1 = x[i0];
      x[i0] = t1 + x[i0 + 1];
      x[i0 + 1] = t1 - x[i0 + 1];
    }
    is = 2 * id - 1;
    id = 4 * id;
  } while (is < n);
  n2 = 2;
  for (k = 2; k <= m; k++) {
    n2 = n2 * 2;
    n4 = n2 / 4;
    rstage(n, n2, n4, &x[0], &x[n4], &x[2 * n4], &x[3 * n4]);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rsrfft>:
  endbr64
  push   %r14
  mov    %esi,%ecx
  push   %r13
  lea    -0x8(%rdi),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  shl    %cl,%ebp
  call   <rbitrev@plt>
  mov    $0x4,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L44:
  cmp    %ebp,%eax
  jg     L34
  movslq %ecx,%rdx
  cltq
  nopl   0x0(%rax)
L40:
  movsd  (%rbx,%rax,8),%xmm1
  movsd  -0x8(%rbx,%rax,8),%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm2,-0x8(%rbx,%rax,8)
  movsd  %xmm0,(%rbx,%rax,8)
  add    %rdx,%rax
  cmp    %eax,%ebp
  jge    L40
L34:
  lea    -0x1(%rcx,%rcx,1),%eax
  shl    $0x2,%ecx
  cmp    %eax,%ebp
  jg     L44
  cmp    $0x1,%r12d
  jle    L28
  mov    $0x2,%ebx
  mov    $0x2,%r14d
  nopl   (%rax)
L17:
  add    %r14d,%r14d
  sub    $0x8,%rsp
  mov    %ebp,%edi
  add    $0x1,%ebx
  mov    %r14d,%edx
  mov    %r14d,%esi
  sar    $0x2,%edx
  lea    (%rdx,%rdx,2),%eax
  cltq
  lea    0x0(%r13,%rax,8),%rcx
  movslq %edx,%rax
  neg    %rax
  push   %rcx
  shl    $0x3,%rax
  lea    (%rcx,%rax,1),%r9
  mov    %r13,%rcx
  lea    (%r9,%rax,1),%r8
  call   <rstage@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,%r12d
  jge    L17
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rsrfft(double *x, int m) {
  int n, is, id, i0, n2, n4, k;
  double t1;
  x--;
  n = 1 << m;
  rbitrev(x, m);
  is = 1;
  id = 4;
  do {
    for (i0 = is; i0 <= n; i0 += id) {
      t1 = x[i0];
      x[i0] = t1 + x[i0 + 1];
      x[i0 + 1] = t1 - x[i0 + 1];
    }
    is = 2 * id - 1;
    id = 4 * id;
  } while (is < n);
  n2 = 2;
  for (k = 2; k <= m; k++) {
    n2 = n2 * 2;
    n4 = n2 / 4;
    rstage(n, n2, n4, &x[0], &x[n4], &x[2 * n4], &x[3 * n4]);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rsrfft>:
  endbr64
  push   %r14
  mov    %esi,%ecx
  push   %r13
  lea    -0x8(%rdi),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  shl    %cl,%ebp
  call   <rbitrev@plt>
  mov    $0x4,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L23:
  cmp    %ebp,%eax
  jg     L10
  movslq %ecx,%rdx
  cltq
  nopl   0x0(%rax)
L32:
  movsd  (%rbx,%rax,8),%xmm1
  movsd  -0x8(%rbx,%rax,8),%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm0
  movsd  %xmm2,-0x8(%rbx,%rax,8)
  movsd  %xmm0,(%rbx,%rax,8)
  add    %rdx,%rax
  cmp    %eax,%ebp
  jge    L32
L10:
  lea    -0x1(%rcx,%rcx,1),%eax
  shl    $0x2,%ecx
  cmp    %eax,%ebp
  jg     L23
  cmp    $0x1,%r12d
  jle    L41
  mov    $0x2,%ebx
  mov    $0x2,%r14d
  nopl   (%rax)
L28:
  add    %r14d,%r14d
  sub    $0x8,%rsp
  mov    %ebp,%edi
  add    $0x1,%ebx
  mov    %r14d,%edx
  mov    %r14d,%esi
  sar    $0x2,%edx
  lea    (%rdx,%rdx,2),%eax
  cltq
  lea    0x0(%r13,%rax,8),%rcx
  movslq %edx,%rax
  neg    %rax
  push   %rcx
  shl    $0x3,%rax
  lea    (%rcx,%rax,1),%r9
  mov    %r13,%rcx
  lea    (%r9,%rax,1),%r8
  call   <rstage@plt>
  pop    %rax
  pop    %rdx
  cmp    %ebx,%r12d
  jge    L28
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void rsrfft(double *x, int m) {
  int n, is, id, i0, n2, n4, k;
  double t1;
  x--;
  n = 1 << m;
  rbitrev(x, m);
  is = 1;
  id = 4;
  do {
    for (i0 = is; i0 <= n; i0 += id) {
      t1 = x[i0];
      x[i0] = t1 + x[i0 + 1];
      x[i0 + 1] = t1 - x[i0 + 1];
    }
    is = 2 * id - 1;
    id = 4 * id;
  } while (is < n);
  n2 = 2;
  for (k = 2; k <= m; k++) {
    n2 = n2 * 2;
    n4 = n2 / 4;
    rstage(n, n2, n4, &x[0], &x[n4], &x[2 * n4], &x[3 * n4]);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <syscall@plt>
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t result = syscall(SYS_time);
  if (t)
    *t = result;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  test   %rbx,%rbx
  je     L8
  mov    %eax,(%rbx)
L8:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t result = syscall(SYS_time);
  if (t)
    *t = result;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<time>:
  endbr64
  mov    D4(%rip),%rax
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rax),%edi
  call   <syscall@plt>
  test   %rbx,%rbx
  je     L5
  mov    %eax,(%rbx)
L5:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t result = syscall(SYS_time);
  if (t)
    *t = result;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<time>:
  endbr64
  mov    D9(%rip),%rax
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rax),%edi
  call   <syscall@plt>
  test   %rbx,%rbx
  je     L6
  mov    %eax,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
time_t time(time_t *t) {
  time_t result = syscall(SYS_time);
  if (t)
    *t = result;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HowManyEntries>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %rdi,-0x238(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x230(%rbp)
  mov    -0x240(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L23
L34:
  cmpq   $0x0,-0x228(%rbp)
  je     L23
  addq   $0x1,-0x230(%rbp)
  mov    -0x240(%rbp),%rax
  mov    (%rax),%rbx
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdx
  mov    -0x240(%rbp),%rax
  mov    %rdx,(%rax)
L23:
  mov    -0x238(%rbp),%rdx
  lea    -0x220(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x228(%rbp)
  cmpq   $0x0,-0x228(%rbp)
  jne    L34
  mov    -0x238(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
  mov    -0x230(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t HowManyEntries(FILE *fHandle, size_t *bytes) {
  size_t entryCount = 0;
  char buf[512], *s;
  *bytes = 0;
  while ((s = fgets(buf, 512, fHandle))) {
    if (s) {
      entryCount++;
      *bytes += strlen(s);
    }
  }
  rewind(fHandle);
  return entryCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HowManyEntries>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %rsp,%r13
L11:
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rdx
  mov    $0x200,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L0
  add    $0x1,%r12
  mov    %rax,%rdi
  call   <strlen@plt>
  add    0x0(%rbp),%rax
  jmp    L11
L0:
  mov    %rbx,%rdi
  call   <rewind@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12,%rax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t HowManyEntries(FILE *fHandle, size_t *bytes) {
  size_t entryCount = 0;
  char buf[512], *s;
  *bytes = 0;
  while ((s = fgets(buf, 512, fHandle))) {
    if (s) {
      entryCount++;
      *bytes += strlen(s);
    }
  }
  rewind(fHandle);
  return entryCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HowManyEntries>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L21:
  call   <strlen@plt>
  add    $0x1,%r12
  add    (%rbx),%rax
L10:
  mov    %rax,(%rbx)
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    $0x200,%esi
  call   <fgets@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L21
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x218,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t HowManyEntries(FILE *fHandle, size_t *bytes) {
  size_t entryCount = 0;
  char buf[512], *s;
  *bytes = 0;
  while ((s = fgets(buf, 512, fHandle))) {
    if (s) {
      entryCount++;
      *bytes += strlen(s);
    }
  }
  rewind(fHandle);
  return entryCount;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HowManyEntries>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L23:
  call   <strlen@plt>
  add    $0x1,%r12
  add    (%rbx),%rax
L5:
  mov    %rax,(%rbx)
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    $0x200,%esi
  call   <fgets@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L23
  mov    %rbp,%rdi
  call   <rewind@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x218,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t HowManyEntries(FILE *fHandle, size_t *bytes) {
  size_t entryCount = 0;
  char buf[512], *s;
  *bytes = 0;
  while ((s = fgets(buf, 512, fHandle))) {
    if (s) {
      entryCount++;
      *bytes += strlen(s);
    }
  }
  rewind(fHandle);
  return entryCount;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_argv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L25
L12:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L8
  mov    -0x38(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L29
L8:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%esi
  mov    -0x40(%rbp),%rcx
  mov    %esi,(%rcx)
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %rdx,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
L29:
  addl   $0x1,-0x1c(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **parse_argv(int argc, char *argv[], int *or_flag, int *search_words_cnt) {
  char **search_words = NULL;
  for (int i = 1; i < argc; i++) {
    if (argv[i][0] == '-') {
      *or_flag = 1;
      continue;
    } else {
      search_words = (char **)realloc(search_words, ((*search_words_cnt) + 1) * sizeof(char *));
      search_words[(*search_words_cnt)++] = strdup(argv[i]);
    }
  }
  return search_words;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_argv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L35
  mov    %rdx,%r15
  mov    %rcx,%r13
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r14
  mov    $0x0,%ebp
  jmp    L29
L18:
  movl   $0x1,(%r15)
L22:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  je     L36
L29:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  je     L18
  mov    0x0(%r13),%eax
  lea    0x8(,%rax,8),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    (%rbx),%rdi
  mov    0x0(%r13),%r12d
  lea    0x1(%r12),%eax
  mov    %eax,0x0(%r13)
  call   <strdup@plt>
  movslq %r12d,%r12
  mov    %rax,0x0(%rbp,%r12,8)
  jmp    L22
L35:
  mov    $0x0,%ebp
L36:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **parse_argv(int argc, char *argv[], int *or_flag, int *search_words_cnt) {
  char **search_words = NULL;
  for (int i = 1; i < argc; i++) {
    if (argv[i][0] == '-') {
      *or_flag = 1;
      continue;
    } else {
      search_words = (char **)realloc(search_words, ((*search_words_cnt) + 1) * sizeof(char *));
      search_words[(*search_words_cnt)++] = strdup(argv[i]);
    }
  }
  return search_words;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_argv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L53
  lea    -0x2(%rdi),%eax
  mov    %rdx,%r14
  mov    %rcx,%r15
  xor    %ebp,%ebp
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  jmp    L59
  nopl   0x0(%rax)
L24:
  mov    (%r15),%eax
  mov    %rbp,%rdi
  add    $0x8,%rbx
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  movslq (%r15),%r12
  mov    -0x8(%rbx),%rdi
  mov    %rax,%rbp
  lea    0x1(%r12),%eax
  mov    %eax,(%r15)
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%r12,8)
  cmp    %r13,%rbx
  je     L52
L59:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  jne    L24
  add    $0x8,%rbx
  movl   $0x1,(%r14)
  cmp    %r13,%rbx
  jne    L59
L52:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L53:
  xor    %ebp,%ebp
  jmp    L52
```

assistant: ```c
char **parse_argv(int argc, char *argv[], int *or_flag, int *search_words_cnt) {
  char **search_words = NULL;
  for (int i = 1; i < argc; i++) {
    if (argv[i][0] == '-') {
      *or_flag = 1;
      continue;
    } else {
      search_words = (char **)realloc(search_words, ((*search_words_cnt) + 1) * sizeof(char *));
      search_words[(*search_words_cnt)++] = strdup(argv[i]);
    }
  }
  return search_words;
}
```