ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<intsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L20
L29:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L6
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L6:
  addq   $0x1,-0x10(%rbp)
L20:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jl     L29
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long int intsort(int *ar, long long int len) {
  long long int i, changes;
  changes = 0;
  for (i = 0; i < len - 1; i++) {
    if (ar[i] > ar[i + 1]) {
      changes++;
      ar[i] ^= ar[i + 1];
      ar[i + 1] ^= ar[i];
      ar[i] ^= ar[i + 1];
    }
  }
  return changes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intsort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L2
  mov    %rdi,%rax
  lea    -0x4(%rdi,%rsi,4),%rdi
  mov    $0x0,%esi
  jmp    L49
L18:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L31
L49:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L18
  add    $0x1,%rsi
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L18
L2:
  mov    $0x0,%esi
L31:
  mov    %rsi,%rax
  ret
```

assistant: ```c
long long int intsort(int *ar, long long int len) {
  long long int i, changes;
  changes = 0;
  for (i = 0; i < len - 1; i++) {
    if (ar[i] > ar[i + 1]) {
      changes++;
      ar[i] ^= ar[i + 1];
      ar[i + 1] ^= ar[i];
      ar[i] ^= ar[i + 1];
    }
  }
  return changes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intsort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L22
  lea    -0x4(%rdi,%rsi,4),%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rdi),%edx
  mov    0x4(%rdi),%eax
  cmp    %eax,%edx
  jle    L7
  mov    %edx,0x4(%rdi)
  add    $0x1,%r8
  mov    %eax,(%rdi)
L7:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L13
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long int intsort(int *ar, long long int len) {
  long long int i, changes;
  changes = 0;
  for (i = 0; i < len - 1; i++) {
    if (ar[i] > ar[i + 1]) {
      changes++;
      ar[i] ^= ar[i + 1];
      ar[i + 1] ^= ar[i];
      ar[i] ^= ar[i + 1];
    }
  }
  return changes;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<intsort>:
  endbr64
  cmp    $0x1,%rsi
  jle    L12
  lea    -0x4(%rdi,%rsi,4),%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rdi),%edx
  mov    0x4(%rdi),%eax
  cmp    %eax,%edx
  jle    L27
  mov    %edx,0x4(%rdi)
  add    $0x1,%r8
  mov    %eax,(%rdi)
L27:
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L26
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long long int intsort(int *ar, long long int len) {
  long long int i, changes;
  changes = 0;
  for (i = 0; i < len - 1; i++) {
    if (ar[i] > ar[i + 1]) {
      changes++;
      ar[i] ^= ar[i + 1];
      ar[i + 1] ^= ar[i];
      ar[i] ^= ar[i + 1];
    }
  }
  return changes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aescnt_checkwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <aes_getwritecount@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xf,-0x8(%rbp)
  seta   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
uint32_t aescnt_checkwrite() {
  size_t ret = aes_getwritecount();
  return (ret > 0xF);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aescnt_checkwrite>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <aes_getwritecount@plt>
  cmp    $0xf,%rax
  seta   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint32_t aescnt_checkwrite() {
  size_t ret = aes_getwritecount();
  return (ret > 0xF);
}
```
user: What is the c source code of the assembly code below?

```asm
<aescnt_checkwrite>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <aes_getwritecount@plt>
  cmp    $0xf,%rax
  seta   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
uint32_t aescnt_checkwrite() {
  size_t ret = aes_getwritecount();
  return (ret > 0xF);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aescnt_checkwrite>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <aes_getwritecount@plt>
  cmp    $0xf,%rax
  seta   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
uint32_t aescnt_checkwrite() {
  size_t ret = aes_getwritecount();
  return (ret > 0xF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zeroit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L1:
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L23:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x63,-0x4(%rbp)
  jle    L23
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zeroit(int **scnarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 100; j++) {
      scnarr[i][j] = 0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rcx
  lea    0x1f40(%rdi),%rsi
L10:
  mov    $0x0,%eax
L6:
  mov    (%rcx),%rdx
  movl   $0x0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x190,%rax
  jne    L6
  add    $0x8,%rcx
  cmp    %rsi,%rcx
  jne    L10
  ret
```

assistant: ```c
void zeroit(int **scnarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 100; j++) {
      scnarr[i][j] = 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rsi
  lea    0x1f40(%rdi),%r8
  xor    %eax,%eax
L8:
  mov    (%rsi),%rdx
  add    $0x8,%rsi
  lea    0x8(%rdx),%rdi
  movq   $0x0,(%rdx)
  movq   $0x0,0x188(%rdx)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rdx
  lea    0x190(%rdx),%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %rsi,%r8
  jne    L8
  ret
```

assistant: ```c
void zeroit(int **scnarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 100; j++) {
      scnarr[i][j] = 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zeroit>:
  endbr64
  mov    %rdi,%rsi
  lea    0x1f40(%rdi),%r8
  xor    %eax,%eax
L1:
  mov    (%rsi),%rdx
  add    $0x8,%rsi
  lea    0x8(%rdx),%rdi
  movq   $0x0,(%rdx)
  movq   $0x0,0x188(%rdx)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rdx
  lea    0x190(%rdx),%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %rsi,%r8
  jne    L1
  ret
```

assistant: ```c
void zeroit(int **scnarr, int nrows, int ncols) {
  int i, j;
  for (i = 0; i < 1000; i++) {
    for (j = 0; j < 100; j++) {
      scnarr[i][j] = 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matmlt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    $0x1,%ebx
  jmp    L13
L33:
  mov    $0x1,%r12d
  jmp    L52
L59:
  movslq %ebx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movslq %r12d,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  mov    $0x1,%r13d
  jmp    L51
L46:
  movslq %ebx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movslq %r12d,%rax
  movsd  (%rdx,%rax,8),%xmm1
  movslq %ebx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movslq %r13d,%rax
  movsd  (%rdx,%rax,8),%xmm2
  movslq %r13d,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %r12d,%rax
  movsd  (%rdx,%rax,8),%xmm0
  mulsd  %xmm2,%xmm0
  movslq %ebx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  addsd  %xmm1,%xmm0
  movslq %r12d,%rax
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%r13d
L51:
  cmp    $0x3,%r13d
  jle    L46
  add    $0x1,%r12d
L52:
  cmp    $0x3,%r12d
  jle    L59
  add    $0x1,%ebx
L13:
  cmp    -0x34(%rbp),%ebx
  jle    L33
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void matmlt(matp, matq, matr, nby3) double matp[4][4];
double matq[10][4], matr[10][4];
int nby3;
{
  register int l, m, j;
  for (l = 1; l <= nby3; l++) {
    for (m = 1; m <= 3; m++) {
      matr[l][m] = 0.0;
      for (j = 1; j <= 3; j++) {
        matr[l][m] = matr[l][m] + (matq[l][j] * matp[j][m]);
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<matmlt>:
  endbr64
  test   %ecx,%ecx
  jle    L11
  push   %rbx
  mov    %rdi,%r11
  lea    0x20(%rsi),%r8
  lea    0x28(%rdx),%r9
  lea    -0x1(%rcx),%eax
  shl    $0x5,%rax
  lea    0x40(%rsi,%rax,1),%rbx
  lea    0x20(%rdi),%r10
  jmp    L40
L19:
  add    $0x20,%r8
  add    $0x20,%r9
  cmp    %rbx,%r8
  je     L36
L40:
  lea    0x8(%r11),%rcx
  mov    %r9,%rdi
L28:
  mov    %rdi,%rdx
  movq   $0x0,(%rdi)
  mov    $0x1,%eax
L9:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  movsd  (%rcx,%rsi,1),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L9
  add    $0x8,%rdi
  add    $0x8,%rcx
  cmp    %r10,%rcx
  jne    L28
  jmp    L19
L36:
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void matmlt(matp, matq, matr, nby3) double matp[4][4];
double matq[10][4], matr[10][4];
int nby3;
{
  register int l, m, j;
  for (l = 1; l <= nby3; l++) {
    for (m = 1; m <= 3; m++) {
      matr[l][m] = 0.0;
      for (j = 1; j <= 3; j++) {
        matr[l][m] = matr[l][m] + (matq[l][j] * matp[j][m]);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matmlt>:
  endbr64
  mov    %rdi,%rax
  test   %ecx,%ecx
  jle    L35
  lea    0x28(%rdx),%r8
  lea    -0x1(%rcx),%edx
  pxor   %xmm2,%xmm2
  shl    $0x5,%rdx
  lea    0x20(%rsi),%rdi
  lea    0x8(%rax),%r9
  lea    0x40(%rsi,%rdx,1),%r10
  lea    0x20(%rax),%rsi
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r9,%rcx
  mov    %r8,%rdx
L5:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
L9:
  movsd  0x8(%rdi,%rax,1),%xmm0
  mulsd  0x20(%rcx,%rax,4),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  cmp    $0x18,%rax
  jne    L9
  add    $0x8,%rcx
  add    $0x8,%rdx
  cmp    %rsi,%rcx
  jne    L5
  add    $0x20,%rdi
  add    $0x20,%r8
  cmp    %r10,%rdi
  jne    L38
L35:
  ret
```

assistant: ```c
void matmlt(matp, matq, matr, nby3) double matp[4][4];
double matq[10][4], matr[10][4];
int nby3;
{
  register int l, m, j;
  for (l = 1; l <= nby3; l++) {
    for (m = 1; m <= 3; m++) {
      matr[l][m] = 0.0;
      for (j = 1; j <= 3; j++) {
        matr[l][m] = matr[l][m] + (matq[l][j] * matp[j][m]);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matmlt>:
  endbr64
  test   %ecx,%ecx
  jle    L19
  sub    $0x1,%ecx
  lea    0x28(%rdx),%rax
  pxor   %xmm2,%xmm2
  add    $0x28,%rsi
  shl    $0x5,%rcx
  lea    0x48(%rdx,%rcx,1),%rdx
  nopl   0x0(%rax)
L16:
  movq   $0x0,(%rax)
  movsd  (%rsi),%xmm1
  add    $0x20,%rax
  add    $0x20,%rsi
  mulsd  0x28(%rdi),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x20(%rax)
  movsd  -0x18(%rsi),%xmm0
  mulsd  0x48(%rdi),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rax)
  movsd  -0x10(%rsi),%xmm1
  mulsd  0x68(%rdi),%xmm1
  movq   $0x0,-0x18(%rax)
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rax)
  movsd  -0x20(%rsi),%xmm1
  mulsd  0x30(%rdi),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x18(%rax)
  movsd  -0x18(%rsi),%xmm0
  mulsd  0x50(%rdi),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rax)
  movsd  -0x10(%rsi),%xmm1
  mulsd  0x70(%rdi),%xmm1
  movq   $0x0,-0x10(%rax)
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x18(%rax)
  movsd  -0x20(%rsi),%xmm1
  mulsd  0x38(%rdi),%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x10(%rax)
  movsd  -0x18(%rsi),%xmm0
  mulsd  0x58(%rdi),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rax)
  movsd  -0x10(%rsi),%xmm1
  mulsd  0x78(%rdi),%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L16
L19:
  ret
```

assistant: ```c
void matmlt(matp, matq, matr, nby3) double matp[4][4];
double matq[10][4], matr[10][4];
int nby3;
{
  register int l, m, j;
  for (l = 1; l <= nby3; l++) {
    for (m = 1; m <= 3; m++) {
      matr[l][m] = 0.0;
      for (j = 1; j <= 3; j++) {
        matr[l][m] = matr[l][m] + (matq[l][j] * matp[j][m]);
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L29:
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x30(%rbp,%rdx,4)
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x7,-0x34(%rbp)
  jle    L29
  movl   $0x0,-0x34(%rbp)
L0:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x7,-0x34(%rbp)
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
int main(void) {
  int arr[8], i;
  for (i = 0; i < 8; i++)
    arr[i] = power(2, i + 1);
  i = 0;
  do {
    printf("%d ", arr[i++]);
  } while (i < 8);
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
L8:
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,-0x4(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  jne    L8
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  lea    D3(%rip),%rbp
L28:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: %d 

assistant: ```c
int main(void) {
  int arr[8], i;
  for (i = 0; i < 8; i++)
    arr[i] = power(2, i + 1);
  i = 0;
  do {
    printf("%d ", arr[i++]);
  } while (i < 8);
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L0:
  mov    %ebp,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,-0x4(%rbx,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x9,%rbp
  jne    L0
  lea    0x20(%rsp),%r12
  lea    D0(%rip),%rbp
  xchg   %ax,%ax
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: %d 

assistant: ```c
int main(void) {
  int arr[8], i;
  for (i = 0; i < 8; i++)
    arr[i] = power(2, i + 1);
  i = 0;
  do {
    printf("%d ", arr[i++]);
  } while (i < 8);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L8:
  mov    %ebp,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,-0x4(%rbx,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x9,%rbp
  jne    L8
  lea    0x20(%rsp),%r12
  lea    D3(%rip),%rbp
  xchg   %ax,%ax
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: %d 

assistant: ```c
int main(void) {
  int arr[8], i;
  for (i = 0; i < 8; i++)
    arr[i] = power(2, i + 1);
  i = 0;
  do {
    printf("%d ", arr[i++]);
  } while (i < 8);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<primitiveTypes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x28,-0x2c(%rbp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movb   $0x41,-0x2d(%rbp)
  movabs $0x2065666661726947,%rax
  movabs $0x796d6564616341,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: f64

tool: D6: 3.6

assistant: ```c
int primitiveTypes() {
  int age = 40;
  double gpa = 3.6;
  char grade = 'A';
  char phrase[] = "Giraffe Academy";
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<primitiveTypes>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int primitiveTypes() {
  int age = 40;
  double gpa = 3.6;
  char grade = 'A';
  char phrase[] = "Giraffe Academy";
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<primitiveTypes>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int primitiveTypes() {
  int age = 40;
  double gpa = 3.6;
  char grade = 'A';
  char phrase[] = "Giraffe Academy";
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<primitiveTypes>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int primitiveTypes() {
  int age = 40;
  double gpa = 3.6;
  char grade = 'A';
  char phrase[] = "Giraffe Academy";
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tml_dr_vSub2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tml_dr_vSub2(const double *src, double *dst, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] -= src[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tml_dr_vSub2>:
  endbr64
  test   %edx,%edx
  jle    L4
  mov    %edx,%edx
  mov    $0x0,%eax
L9:
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
L4:
  ret
```

assistant: ```c
void tml_dr_vSub2(const double *src, double *dst, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] -= src[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tml_dr_vSub2>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L9:
  movsd  (%rsi,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L9
L2:
  ret
```

assistant: ```c
void tml_dr_vSub2(const double *src, double *dst, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] -= src[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tml_dr_vSub2>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L24
  lea    0x8(%rdi),%rax
  cmp    %rax,%rsi
  je     L17
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L17
  mov    %edx,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L37:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%rdi,%rax,1),%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L37
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L24
  lea    (%rcx,%rax,8),%rdx
  movsd  (%rdx),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L13:
  movsd  (%rcx,%rax,8),%xmm0
  subsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L13
L24:
  ret
```

assistant: ```c
void tml_dr_vSub2(const double *src, double *dst, int n) {
  int i;
  for (i = 0; i < n; i++)
    dst[i] -= src[i];
}
```