user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%edx
  mov    $0x1,%edi
  push   %rbp
  lea    D4(%rip),%rbp
  sub    $0x38,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  movdqa D27(%rip),%xmm0
  mov    %r12,%rsi
  movaps %xmm0,0x10(%rsp)
  call   <binsearch@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x2,%edi
  call   <binsearch@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x3,%edi
  call   <binsearch@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x4,%edi
  call   <binsearch@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x5,%edi
  call   <binsearch@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x6,%edi
  call   <binsearch@plt>
  mov    $0x6,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x7,%edi
  call   <binsearch@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x8,%edi
  call   <binsearch@plt>
  mov    $0x8,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0x9,%edi
  call   <binsearch@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <binsearch@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    $0xb,%edi
  call   <binsearch@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D7
type: byte[16]
name: parse_data
arguments: label: D27
type: byte[16]

tool: D4: number = %d, is at position = %d


tool: {"D7": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D27": [0x09,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

assistant: ```c
main() {
  int t[8];
  t[0] = 1;
  t[1] = 3;
  t[2] = 4;
  t[3] = 6;
  t[4] = 9;
  t[5] = 11;
  t[6] = 15;
  t[7] = 17;
  printf("number = %d, is at position = %d\n", 1, binsearch(1, t, 8));
  printf("number = %d, is at position = %d\n", 2, binsearch(2, t, 8));
  printf("number = %d, is at position = %d\n", 3, binsearch(3, t, 8));
  printf("number = %d, is at position = %d\n", 4, binsearch(4, t, 8));
  printf("number = %d, is at position = %d\n", 5, binsearch(5, t, 8));
  printf("number = %d, is at position = %d\n", 6, binsearch(6, t, 8));
  printf("number = %d, is at position = %d\n", 7, binsearch(7, t, 8));
  printf("number = %d, is at position = %d\n", 8, binsearch(8, t, 8));
  printf("number = %d, is at position = %d\n", 9, binsearch(9, t, 8));
  printf("number = %d, is at position = %d\n", 10, binsearch(10, t, 8));
  printf("number = %d, is at position = %d\n", 11, binsearch(11, t, 8));
}
```