ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x67,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] *= state[local1];
      state[local1] *= state[0UL];
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + (unsigned char)84;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<muGetNoteFromName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x40(%rbp)
  movl   $0xb,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x2,-0x34(%rbp)
  movl   $0x4,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x0,-0x4c(%rbp)
  mov    -0x58(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0xf,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x11(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L16
L33:
  addq   $0x1,-0x48(%rbp)
L16:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L49
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L49:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L60
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  mov    %eax,-0x4c(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  js     L60
  cmpl   $0x7,-0x4c(%rbp)
  jg     L60
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,-0x4c(%rbp)
  addq   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x62,%al
  jne    L76
  subl   $0x1,-0x4c(%rbp)
  addq   $0x1,-0x48(%rbp)
  jmp    L45
L76:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L45
  addl   $0x1,-0x4c(%rbp)
  addq   $0x1,-0x48(%rbp)
L45:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %eax,-0x4c(%rbp)
L60:
  mov    -0x4c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int muGetNoteFromName(const char *pName) {
  int note_map[] = {9, 11, 0, 2, 4, 5, 7};
  char *p, cpy[16];
  int note = 0;
  strncpy(cpy, pName, 15);
  cpy[15] = '\0';
  p = cpy;
  while (!isalpha(*p) && *p)
    p++;
  if (*p) {
    note = toupper(*p) - 'A';
    if (note >= 0 && note <= 7) {
      note = note_map[note];
      p++;
      if (*p == 'b')
        note--, p++;
      else if (*p == '#')
        note++, p++;
      note += atoi(p) * 12 + 0;
    }
  }
  return note;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<muGetNoteFromName>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  lea    0x20(%rsp),%rbx
  mov    $0xf,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x2f(%rsp)
  jmp    L96
L20:
  add    $0x1,%rbx
L96:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L32
  cmpb   $0x0,(%rbx)
  jne    L20
L8:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L95
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  movzbl (%rbx),%edi
  mov    $0x0,%eax
  test   %dil,%dil
  je     L8
  movsbl %dil,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cmp    $0x7,%eax
  ja     L8
  cltq
  mov    (%rsp,%rax,4),%ebp
  movzbl 0x1(%rbx),%eax
  cmp    $0x62,%al
  je     L93
  lea    0x1(%rbx),%rdi
  cmp    $0x23,%al
  je     L42
L33:
  call   <atoi@plt>
  lea    (%rax,%rax,2),%eax
  lea    0x0(%rbp,%rax,4),%eax
  jmp    L8
L93:
  sub    $0x1,%ebp
  lea    0x2(%rbx),%rdi
  jmp    L33
L42:
  add    $0x1,%ebp
  lea    0x2(%rbx),%rdi
  jmp    L33
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int muGetNoteFromName(const char *pName) {
  int note_map[] = {9, 11, 0, 2, 4, 5, 7};
  char *p, cpy[16];
  int note = 0;
  strncpy(cpy, pName, 15);
  cpy[15] = '\0';
  p = cpy;
  while (!isalpha(*p) && *p)
    p++;
  if (*p) {
    note = toupper(*p) - 'A';
    if (note >= 0 && note <= 7) {
      note = note_map[note];
      p++;
      if (*p == 'b')
        note--, p++;
      else if (*p == '#')
        note++, p++;
      note += atoi(p) * 12 + 0;
    }
  }
  return note;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<muGetNoteFromName>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0xf,%edx
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xb00000009,%rax
  lea    0x20(%rsp),%rbx
  movl   $0x7,0x18(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x200000000,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  call   <strncpy@plt>
  movb   $0x0,0x2f(%rsp)
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L52:
  cmpb   $0x0,(%rbx)
  je     L70
  add    $0x1,%rbx
L38:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L52
  movsbl (%rbx),%edi
  xor    %eax,%eax
  test   %dil,%dil
  je     L70
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cmp    $0x7,%eax
  ja     L70
  cltq
  mov    (%rsp,%rax,4),%ebp
  movzbl 0x1(%rbx),%eax
  cmp    $0x62,%al
  je     L33
  lea    0x1(%rbx),%rdi
  cmp    $0x23,%al
  jne    L44
  add    $0x1,%ebp
  lea    0x2(%rbx),%rdi
L44:
  call   <atoi@plt>
  lea    (%rax,%rax,2),%eax
  lea    0x0(%rbp,%rax,4),%eax
  nopw   0x0(%rax,%rax,1)
L70:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  sub    $0x1,%ebp
  lea    0x2(%rbx),%rdi
  jmp    L44
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int muGetNoteFromName(const char *pName) {
  int note_map[] = {9, 11, 0, 2, 4, 5, 7};
  char *p, cpy[16];
  int note = 0;
  strncpy(cpy, pName, 15);
  cpy[15] = '\0';
  p = cpy;
  while (!isalpha(*p) && *p)
    p++;
  if (*p) {
    note = toupper(*p) - 'A';
    if (note >= 0 && note <= 7) {
      note = note_map[note];
      p++;
      if (*p == 'b')
        note--, p++;
      else if (*p == '#')
        note++, p++;
      note += atoi(p) * 12 + 0;
    }
  }
  return note;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<muGetNoteFromName>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0xf,%edx
  push   %rbx
  sub    $0x48,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  mov    D8(%rip),%rax
  movl   $0x7,0x18(%rsp)
  mov    %rbx,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <strncpy@plt>
  movb   $0x0,0x2f(%rsp)
  jmp    L76
  cs nopw 0x0(%rax,%rax,1)
L88:
  cmpb   $0x0,(%rbx)
  je     L16
  add    $0x1,%rbx
L76:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L88
  movsbl (%rbx),%edi
  xor    %eax,%eax
  test   %dil,%dil
  je     L16
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x41,%eax
  cmp    $0x7,%eax
  ja     L16
  cltq
  mov    (%rsp,%rax,4),%ebp
  movzbl 0x1(%rbx),%eax
  cmp    $0x62,%al
  je     L46
  lea    0x1(%rbx),%rdi
  cmp    $0x23,%al
  jne    L69
  add    $0x1,%ebp
  lea    0x2(%rbx),%rdi
L69:
  call   <atoi@plt>
  lea    (%rax,%rax,2),%eax
  lea    0x0(%rbp,%rax,4),%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L46:
  sub    $0x1,%ebp
  lea    0x2(%rbx),%rdi
  jmp    L69
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D8
data_type: byte[8]

tool: {"D13": [0x09,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D8": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
int muGetNoteFromName(const char *pName) {
  int note_map[] = {9, 11, 0, 2, 4, 5, 7};
  char *p, cpy[16];
  int note = 0;
  strncpy(cpy, pName, 15);
  cpy[15] = '\0';
  p = cpy;
  while (!isalpha(*p) && *p)
    p++;
  if (*p) {
    note = toupper(*p) - 'A';
    if (note >= 0 && note <= 7) {
      note = note_map[note];
      p++;
      if (*p == 'b')
        note--, p++;
      else if (*p == '#')
        note++, p++;
      note += atoi(p) * 12 + 0;
    }
  }
  return note;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string

tool: D8: 1

tool: D12: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  (void)strcpy(b, "1");
  (void)strcat(b, argv[1]);
  (void)printf("%s\n", b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D13: 1

tool: D15: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  (void)strcpy(b, "1");
  (void)strcat(b, argv[1]);
  (void)printf("%s\n", b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D0: 1

tool: D2: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  (void)strcpy(b, "1");
  (void)strcat(b, argv[1]);
  (void)printf("%s\n", b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D3(%rip),%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D3: 1

tool: D6: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char b[10];
  (void)strcpy(b, "1");
  (void)strcat(b, argv[1]);
  (void)printf("%s\n", b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<binomialCoeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x50(%rbp)
  lea    0x1(%rdi),%eax
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L59:
  cmp    %rdx,%rsp
  je     L96
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L59
L96:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L111
  orq    $0x0,-0x8(%rsp,%rax,1)
L111:
  mov    %rsp,%rax
  mov    %rax,-0x60(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  js     L99
  mov    %rax,%r15
  mov    %rax,%r13
  sub    -0x50(%rbp),%r13
  mov    %rax,-0x48(%rbp)
  mov    $0x0,%r12d
  jmp    L98
L100:
  movl   $0x1,(%r15,%rbx,4)
L105:
  add    $0x1,%rbx
L54:
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <min@plt>
  mov    %ebx,%edx
  cmp    %ebx,%eax
  jl     L86
  test   %ebx,%ebx
  je     L100
  cmp    %r12d,%edx
  je     L100
  mov    0x0(%r13,%rbx,4),%eax
  add    -0x4(%r13,%rbx,4),%eax
  mov    -0x48(%rbp),%rcx
  mov    %eax,(%rcx,%rbx,4)
  jmp    L105
L86:
  add    $0x1,%r12d
  mov    -0x50(%rbp),%rax
  add    %rax,%r15
  add    %rax,%r13
  add    %rax,-0x48(%rbp)
  cmp    %r12d,-0x54(%rbp)
  jl     L99
L98:
  mov    $0x0,%ebx
  jmp    L54
L99:
  movslq %r14d,%rax
  movslq -0x54(%rbp),%rcx
  mov    -0x50(%rbp),%rdx
  shr    $0x2,%rdx
  imul   %rcx,%rdx
  add    %rdx,%rax
  mov    -0x60(%rbp),%rsi
  mov    (%rsi,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binomialCoeff(int n, int k) {
  int C[n + 1][k + 1];
  int i, j;
  for (i = 0; i <= n; i++) {
    for (j = 0; j <= min(i, k); j++) {
      if (j == 0 || j == i) {
        C[i][j] = 1;
      } else {
        C[i][j] = C[i - 1][j - 1] + C[i - 1][j];
      }
    }
  }
  return C[n][k];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binomialCoeff>:
  endbr64
  push   %rbp
  lea    0x1(%rsi),%edx
  movslq %edx,%rdx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x5c(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x68(%rbp)
  lea    0x1(%rdi),%eax
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L54
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L22
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L49
L44:
  mov    -0x68(%rbp),%rax
  mov    -0x5c(%rbp),%edx
  mov    %rsp,%rcx
  mov    %rcx,-0x78(%rbp)
  shr    $0x2,%rax
  mov    %rax,-0x70(%rbp)
  test   %edx,%edx
  js     L89
  neg    %rax
  movq   $0xffffffffffffffff,-0x58(%rbp)
  lea    (%rcx,%rax,4),%rax
  movq   $0x0,-0x48(%rbp)
  mov    %rax,-0x50(%rbp)
  nopl   (%rax)
L5:
  mov    -0x48(%rbp),%r12
  mov    -0x50(%rbp),%rbx
  xor    %r15d,%r15d
  mov    %r12d,%r14d
  sub    -0x58(%rbp),%r12
  imul   -0x70(%rbp),%r12
  jmp    L0
  nopl   0x0(%rax)
L75:
  mov    (%rbx),%eax
  add    -0x4(%rbx),%eax
L57:
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r15d
  add    $0x4,%rbx
L0:
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <min@plt>
  cmp    %r15d,%eax
  jl     L94
  test   %r15d,%r15d
  je     L78
  cmp    -0x48(%rbp),%r15d
  jne    L75
L78:
  mov    $0x1,%eax
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L94:
  addq   $0x1,-0x48(%rbp)
  mov    -0x68(%rbp),%rdx
  addq   $0x1,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  add    %rdx,-0x50(%rbp)
  cmp    %eax,-0x5c(%rbp)
  jge    L5
L89:
  movslq -0x5c(%rbp),%rdx
  imul   -0x70(%rbp),%rdx
  movslq %r13d,%rax
  mov    -0x78(%rbp),%rcx
  add    %rdx,%rax
  mov    (%rcx,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L49:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L44
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binomialCoeff(int n, int k) {
  int C[n + 1][k + 1];
  int i, j;
  for (i = 0; i <= n; i++) {
    for (j = 0; j <= min(i, k); j++) {
      if (j == 0 || j == i) {
        C[i][j] = 1;
      } else {
        C[i][j] = C[i - 1][j - 1] + C[i - 1][j];
      }
    }
  }
  return C[n][k];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<binomialCoeff>:
  endbr64
  push   %rbp
  lea    0x1(%rsi),%edx
  movslq %edx,%rdx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x5c(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x68(%rbp)
  lea    0x1(%rdi),%eax
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L32
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L32:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L75:
  mov    -0x68(%rbp),%rax
  mov    -0x5c(%rbp),%edx
  mov    %rsp,%rcx
  mov    %rcx,-0x78(%rbp)
  shr    $0x2,%rax
  mov    %rax,-0x70(%rbp)
  test   %edx,%edx
  js     L104
  neg    %rax
  movq   $0xffffffffffffffff,-0x58(%rbp)
  lea    (%rcx,%rax,4),%rax
  movq   $0x0,-0x48(%rbp)
  mov    %rax,-0x50(%rbp)
  nopl   (%rax)
L97:
  mov    -0x48(%rbp),%r12
  mov    -0x50(%rbp),%rbx
  xor    %r15d,%r15d
  mov    %r12d,%r14d
  sub    -0x58(%rbp),%r12
  imul   -0x70(%rbp),%r12
  jmp    L47
  nopl   0x0(%rax)
L68:
  mov    (%rbx),%eax
  add    -0x4(%rbx),%eax
L65:
  mov    %eax,(%rbx,%r12,4)
  add    $0x1,%r15d
  add    $0x4,%rbx
L47:
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <min@plt>
  cmp    %r15d,%eax
  jl     L102
  test   %r15d,%r15d
  je     L94
  cmp    -0x48(%rbp),%r15d
  jne    L68
L94:
  mov    $0x1,%eax
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L102:
  addq   $0x1,-0x48(%rbp)
  mov    -0x68(%rbp),%rdx
  addq   $0x1,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  add    %rdx,-0x50(%rbp)
  cmp    %eax,-0x5c(%rbp)
  jge    L97
L104:
  movslq -0x5c(%rbp),%rdx
  imul   -0x70(%rbp),%rdx
  movslq %r13d,%rax
  mov    -0x78(%rbp),%rcx
  add    %rdx,%rax
  mov    (%rcx,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L90
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L75
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binomialCoeff(int n, int k) {
  int C[n + 1][k + 1];
  int i, j;
  for (i = 0; i <= n; i++) {
    for (j = 0; j <= min(i, k); j++) {
      if (j == 0 || j == i) {
        C[i][j] = 1;
      } else {
        C[i][j] = C[i - 1][j - 1] + C[i - 1][j];
      }
    }
  }
  return C[n][k];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_sys_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rdi
  mov    %eax,%ecx
  mov    %rdx,%rsi
  pushf
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  popf
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *_sys_memcpy(void *dest, const void *src, int n) {
  asm volatile("pushf		\n"
               "cld		\n"
               "rep		\n"
               "movsb		\n"
               "popf		\n"
               :
               : "c"((unsigned int)n), "S"(src), "D"(dest));
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_sys_memcpy>:
  endbr64
  mov    %edx,%ecx
  pushf
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  popf
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *_sys_memcpy(void *dest, const void *src, int n) {
  asm volatile("pushf		\n"
               "cld		\n"
               "rep		\n"
               "movsb		\n"
               "popf		\n"
               :
               : "c"((unsigned int)n), "S"(src), "D"(dest));
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_sys_memcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  pushf
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  popf
  ret
```

assistant: ```c
void *_sys_memcpy(void *dest, const void *src, int n) {
  asm volatile("pushf		\n"
               "cld		\n"
               "rep		\n"
               "movsb		\n"
               "popf		\n"
               :
               : "c"((unsigned int)n), "S"(src), "D"(dest));
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_sys_memcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%ecx
  pushf
  cld
  rep movsb %ds:(%rsi),%es:(%rdi)
  popf
  ret
```

assistant: ```c
void *_sys_memcpy(void *dest, const void *src, int n) {
  asm volatile("pushf		\n"
               "cld		\n"
               "rep		\n"
               "movsb		\n"
               "popf		\n"
               :
               : "c"((unsigned int)n), "S"(src), "D"(dest));
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<delays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L10
L13:
  mov    $0x3e8,%edi
  call   <delay@plt>
L10:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void delays(unsigned int s) {
  while (s--) {
    delay(1000);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delays>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%ebx
  test   %edi,%edi
  je     L18
L1:
  mov    $0x3e8,%edi
  call   <delay@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L1
L18:
  pop    %rbx
  ret
```

assistant: ```c
void delays(unsigned int s) {
  while (s--) {
    delay(1000);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delays>:
  endbr64
  test   %edi,%edi
  je     L19
  push   %rbx
  lea    -0x1(%rdi),%ebx
  nopl   0x0(%rax)
L8:
  mov    $0x3e8,%edi
  call   <delay@plt>
  sub    $0x1,%ebx
  jae    L8
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void delays(unsigned int s) {
  while (s--) {
    delay(1000);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<delays>:
  endbr64
  test   %edi,%edi
  je     L4
  push   %rbx
  lea    -0x1(%rdi),%ebx
  nopl   0x0(%rax)
L8:
  mov    $0x3e8,%edi
  call   <delay@plt>
  sub    $0x1,%ebx
  jae    L8
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void delays(unsigned int s) {
  while (s--) {
    delay(1000);
  }
}
```