ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L44
L83:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x54,%eax
  je     L35
  cmp    $0x54,%eax
  jg     L107
  cmp    $0x47,%eax
  je     L96
  cmp    $0x47,%eax
  jg     L107
  cmp    $0x41,%eax
  je     L56
  cmp    $0x43,%eax
  je     L85
  jmp    L107
L56:
  movl   $0x0,-0xc(%rbp)
  jmp    L107
L85:
  movl   $0x1,-0xc(%rbp)
  jmp    L107
L96:
  movl   $0x2,-0xc(%rbp)
  jmp    L107
L35:
  movl   $0x3,-0xc(%rbp)
  nop
L107:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%eax
  or     %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L44:
  cmpl   $0x7,-0x10(%rbp)
  jbe    L83
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash(char *kmer) {
  unsigned int i, code;
  unsigned long result = 0;
  for (i = 0; i < 8; i++) {
    switch (kmer[i]) {
    case 'A':
      code = 0;
      break;
    case 'C':
      code = 1;
      break;
    case 'G':
      code = 2;
      break;
    case 'T':
      code = 3;
      break;
    }
    result |= code << i * 2;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash>:
  endbr64
  mov    $0x0,%esi
  mov    $0x0,%r8d
  mov    $0x3,%r10d
  mov    $0x1,%r9d
  jmp    L77
L14:
  cmp    $0x43,%al
  cmove  %r9d,%edx
L8:
  lea    (%rsi,%rsi,1),%ecx
  mov    %edx,%eax
  shl    %cl,%eax
  or     %rax,%r8
  add    $0x1,%rsi
  cmp    $0x8,%rsi
  je     L46
L77:
  movzbl (%rdi,%rsi,1),%eax
  cmp    $0x47,%al
  je     L49
  jg     L57
  cmp    $0x41,%al
  jne    L14
  mov    $0x0,%edx
  jmp    L8
L57:
  cmp    $0x54,%al
  cmove  %r10d,%edx
  jmp    L8
L49:
  mov    $0x2,%edx
  jmp    L8
L46:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long hash(char *kmer) {
  unsigned int i, code;
  unsigned long result = 0;
  for (i = 0; i < 8; i++) {
    switch (kmer[i]) {
    case 'A':
      code = 0;
      break;
    case 'C':
      code = 1;
      break;
    case 'G':
      code = 2;
      break;
    case 'T':
      code = 3;
      break;
    }
    result |= code << i * 2;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash>:
  endbr64
  xor    %eax,%eax
  xor    %r8d,%r8d
  mov    $0x2,%r11d
  mov    $0x3,%r10d
  mov    $0x1,%r9d
  jmp    L87
  nopl   (%rax)
L30:
  cmp    $0x43,%dl
  jne    L28
  mov    %r9d,%edx
  mov    $0x1,%esi
  shl    %cl,%edx
  or     %rdx,%r8
L81:
  add    $0x1,%rax
  cmp    $0x8,%rax
  je     L45
L87:
  movzbl (%rdi,%rax,1),%edx
  lea    (%rax,%rax,1),%ecx
  cmp    $0x47,%dl
  je     L12
  jg     L57
  cmp    $0x41,%dl
  jne    L30
  add    $0x1,%rax
  xor    %esi,%esi
  cmp    $0x8,%rax
  jne    L87
L45:
  mov    %r8,%rax
  ret
  nop
L57:
  cmp    $0x54,%dl
  jne    L28
  mov    %r10d,%edx
  mov    $0x3,%esi
  shl    %cl,%edx
  or     %rdx,%r8
  jmp    L81
  nopl   0x0(%rax)
L12:
  mov    %r11d,%edx
  mov    $0x2,%esi
  shl    %cl,%edx
  or     %rdx,%r8
  jmp    L81
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %esi,%edx
  shl    %cl,%edx
  or     %rdx,%r8
  jmp    L81
```

assistant: ```c
unsigned long hash(char *kmer) {
  unsigned int i, code;
  unsigned long result = 0;
  for (i = 0; i < 8; i++) {
    switch (kmer[i]) {
    case 'A':
      code = 0;
      break;
    case 'C':
      code = 1;
      break;
    case 'G':
      code = 2;
      break;
    case 'T':
      code = 3;
      break;
    }
    result |= code << i * 2;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_n>:
  endbr64
  cmp    $0x4,%edi
  ja     L43
  sub    $0x8,%rsp
  mov    %edi,%eax
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <_n_0@plt>
L36:
  add    $0x8,%rsp
  ret
  mov    %rsi,%rdi
  call   <_n_1@plt>
  jmp    L36
  mov    %rsi,%rdi
  call   <_n_2@plt>
  jmp    L36
  mov    %rsi,%rdi
  call   <_n_3@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <_n_4@plt>
  jmp    L36
L43:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double _n(const int i, const double omega, const double vertices_omegas[4]) {
  switch (i) {
  case 0:
    return _n_0();
  case 1:
    return _n_1(omega, vertices_omegas);
  case 2:
    return _n_2(omega, vertices_omegas);
  case 3:
    return _n_3(omega, vertices_omegas);
  case 4:
    return _n_4();
  };
  ;
  ;
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_n>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x4,%eax
  ja     L4
  lea    D8(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nop
  jmp    10b0 <_n_3@plt>
  nopl   (%rax)
  xor    %eax,%eax
  jmp    10c0 <_n_4@plt>
  nop
  xor    %eax,%eax
  jmp    10d0 <_n_0@plt>
  nopw   0x0(%rax,%rax,1)
  jmp    10a0 <_n_1@plt>
  nopl   (%rax)
  jmp    1090 <_n_2@plt>
L4:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double _n(const int i, const double omega, const double vertices_omegas[4]) {
  switch (i) {
  case 0:
    return _n_0();
  case 1:
    return _n_1(omega, vertices_omegas);
  case 2:
    return _n_2(omega, vertices_omegas);
  case 3:
    return _n_3(omega, vertices_omegas);
  case 4:
    return _n_4();
  };
  ;
  ;
  ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_n>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x4,%eax
  ja     L6
  lea    D5(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nop
  jmp    10b0 <_n_3@plt>
  nopl   (%rax)
  xor    %eax,%eax
  jmp    10c0 <_n_4@plt>
  nop
  xor    %eax,%eax
  jmp    10d0 <_n_0@plt>
  nopw   0x0(%rax,%rax,1)
  jmp    10a0 <_n_1@plt>
  nopl   (%rax)
  jmp    1090 <_n_2@plt>
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double _n(const int i, const double omega, const double vertices_omegas[4]) {
  switch (i) {
  case 0:
    return _n_0();
  case 1:
    return _n_1(omega, vertices_omegas);
  case 2:
    return _n_2(omega, vertices_omegas);
  case 3:
    return _n_3(omega, vertices_omegas);
  case 4:
    return _n_4();
  };
  ;
  ;
  ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_bits8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x4(%rbp),%edx
  sar    %edx
  and    $0x55555555,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t count_bits8(uint64_t x) {
  x -= (x >> 1) & 0x5555555555555555;
  x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_bits8>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edx
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  ret
```

assistant: ```c
uint64_t count_bits8(uint64_t x) {
  x -= (x >> 1) & 0x5555555555555555;
  x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_bits8>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edi
  sar    $0x2,%edx
  and    $0x33333333,%edx
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  ret
```

assistant: ```c
uint64_t count_bits8(uint64_t x) {
  x -= (x >> 1) & 0x5555555555555555;
  x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<count_bits8>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edi
  sar    $0x2,%edx
  and    $0x33333333,%edx
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  ret
```

assistant: ```c
uint64_t count_bits8(uint64_t x) {
  x -= (x >> 1) & 0x5555555555555555;
  x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rbx
  jmp    L37
L62:
  movsd  D65(%rip),%xmm1
  subsd  %xmm0,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%r14
  mov    %ebp,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %eax,%r13d
  lea    0x0(%rbp,%r12,1),%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0x1,%ecx
  mov    %ecx,%eax
  sub    %r13d,%eax
  sub    %edx,%ecx
  cltd
  idiv   %ecx
  imul   $0x64,%eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
L37:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L34
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%ecx
  mov    %eax,%edx
  imul   %esi,%edx
  imul   %edi,%edx
  imul   %ecx,%edx
  test   %edx,%edx
  je     L34
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D0(%rip),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ss %ecx,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm2,%xmm1
  cvttss2si %xmm1,%ebp
  cltd
  idiv   %ecx
  test   %edx,%edx
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebp
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm2,%xmm1
  cvttss2si %xmm1,%r12d
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  setg   %al
  movzbl %al,%eax
  add    %eax,%r12d
  ucomisd D9(%rip),%xmm0
  jp     L62
  jne    L62
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  add    %ebp,%r12d
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D68(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L34:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D38
type: string
name: parse_data
arguments: label: D65
type: byte[8]
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D0
type: f64
name: parse_data
arguments: label: D9
type: f64
name: parse_data
arguments: label: D68
type: byte[8]

tool: D38: %d%d%d%d

tool: {"D65": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D16: %.1lf


tool: D0: 6

tool: D9: 0.5

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

assistant: ```c
int main() {
  int ev1, ev2, at, d, n1, n2;
  double p, q, prob;
  while (scanf("%d%d%d%d", &ev1, &ev2, &at, &d) && ev1 * ev2 * at * d != 0) {
    p = (float)at / 6.0;
    q = 1 - p;
    n1 = (float)ev1 / d;
    if (ev1 % d > 0) {
      n1++;
    }
    n2 = (float)ev2 / d;
    if (ev2 % d > 0) {
      n2++;
    }
    if (p == 0.5) {
      prob = (float)n1 / (n1 + n2);
      printf("%.1lf\n", 100 * prob);
    } else {
      printf("%.1lf\n", 100 * ((1 - pow((q / p), n1)) / (1 - pow((q / p), n1 + n2))));
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmpic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L19
L67:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L19
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jbe    L47
  mov    $0x1,%eax
  jmp    L16
L47:
  mov    $0xffffffff,%eax
  jmp    L16
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L67
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L67
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int strcmpic(const char *str1, const char *str2) {
  unsigned int c1, c2;
  while (*str1 != '\0' || *str2 != '\0') {
    c1 = tolower(*str1++);
    c2 = tolower(*str2++);
    if (c1 != c2)
      return ((c1 > c2) << 1) - 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmpic>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  jmp    L34
L39:
  add    $0x1,%r12
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L35
L34:
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L39
  cmpb   $0x0,0x0(%rbp)
  jne    L39
  mov    $0x0,%eax
  jmp    L24
L35:
  cmp    %ebx,%eax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpic(const char *str1, const char *str2) {
  unsigned int c1, c2;
  while (*str1 != '\0' || *str2 != '\0') {
    c1 = tolower(*str1++);
    c2 = tolower(*str2++);
    if (c1 != c2)
      return ((c1 > c2) << 1) - 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmpic>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xchg   %ax,%ax
L0:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L26
  cmpb   $0x0,0x0(%rbp)
  je     L16
L26:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L0
  cmp    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpic(const char *str1, const char *str2) {
  unsigned int c1, c2;
  while (*str1 != '\0' || *str2 != '\0') {
    c1 = tolower(*str1++);
    c2 = tolower(*str2++);
    if (c1 != c2)
      return ((c1 > c2) << 1) - 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmpic>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xchg   %ax,%ax
L8:
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L12
  cmpb   $0x0,0x0(%rbp)
  je     L21
L12:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L8
  cmp    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcmpic(const char *str1, const char *str2) {
  unsigned int c1, c2;
  while (*str1 != '\0' || *str2 != '\0') {
    c1 = tolower(*str1++);
    c2 = tolower(*str2++);
    if (c1 != c2)
      return ((c1 > c2) << 1) - 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_i2_i2_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  shll   -0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _i2_i2_swap(void *pin, void *pout, int count) {
  unsigned char *in = (unsigned char *)pin;
  unsigned char *out = (unsigned char *)pout;
  int i;
  count *= 2;
  for (i = 0; i < count; i += 2) {
    out[i + 1] = in[i];
    out[i] = in[i + 1];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_i2_i2_swap>:
  endbr64
  add    %edx,%edx
  test   %edx,%edx
  jle    L2
  mov    $0x0,%eax
L1:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,0x1(%rsi,%rax,1)
  movzbl 0x1(%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L1
L2:
  ret
```

assistant: ```c
void _i2_i2_swap(void *pin, void *pout, int count) {
  unsigned char *in = (unsigned char *)pin;
  unsigned char *out = (unsigned char *)pout;
  int i;
  count *= 2;
  for (i = 0; i < count; i += 2) {
    out[i + 1] = in[i];
    out[i] = in[i + 1];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_i2_i2_swap>:
  endbr64
  add    %edx,%edx
  test   %edx,%edx
  jle    L0
  xor    %eax,%eax
  nopl   0x0(%rax)
L6:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,0x1(%rsi,%rax,1)
  movzbl 0x1(%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x2,%rax
  cmp    %eax,%edx
  jg     L6
L0:
  ret
```

assistant: ```c
void _i2_i2_swap(void *pin, void *pout, int count) {
  unsigned char *in = (unsigned char *)pin;
  unsigned char *out = (unsigned char *)pout;
  int i;
  count *= 2;
  for (i = 0; i < count; i += 2) {
    out[i + 1] = in[i];
    out[i] = in[i + 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x17c(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x190(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x4(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int y __attribute__((unused));
  int *x = malloc(sizeof(int) * 100);
  y = x[95];
  y = x[100];
  y = x[-1];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int y __attribute__((unused));
  int *x = malloc(sizeof(int) * 100);
  y = x[95];
  y = x[100];
  y = x[-1];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int y __attribute__((unused));
  int *x = malloc(sizeof(int) * 100);
  y = x[95];
  y = x[100];
  y = x[-1];
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int y __attribute__((unused));
  int *x = malloc(sizeof(int) * 100);
  y = x[95];
  y = x[100];
  y = x[-1];
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int b;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int b;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int b;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int b;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getremain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getremain(unsigned long sz, int dv) {
  int r;
  r = sz / dv;
  r++;
  r = r * dv;
  r = r - sz;
  return (r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getremain>:
  endbr64
  movslq %esi,%rcx
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x1,%eax
  imul   %eax,%esi
  mov    %esi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int getremain(unsigned long sz, int dv) {
  int r;
  r = sz / dv;
  r++;
  r = r * dv;
  r = r - sz;
  return (r);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getremain>:
  endbr64
  movslq %esi,%rcx
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%eax
  imul   %eax,%esi
  mov    %esi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int getremain(unsigned long sz, int dv) {
  int r;
  r = sz / dv;
  r++;
  r = r * dv;
  r = r - sz;
  return (r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getremain>:
  endbr64
  movslq %esi,%rcx
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%eax
  imul   %eax,%esi
  mov    %esi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int getremain(unsigned long sz, int dv) {
  int r;
  r = sz / dv;
  r++;
  r = r * dv;
  r = r - sz;
  return (r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D19(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D8
type: string

tool: D19: apple

tool: D23: belly

tool: D24: s1 compared with s2 r = %d


tool: D8: s2 compared with s1 r = %d


assistant: ```c
int main() {
  char *s1 = "apple";
  char *s2 = "belly";
  int r = strcmp(s1, s2);
  printf("s1 compared with s2 r = %d\n", r);
  r = strcmp(s2, s1);
  printf("s2 compared with s1 r = %d\n", r);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string

tool: D17: s1 compared with s2 r = %d


tool: D13: s2 compared with s1 r = %d


assistant: ```c
int main() {
  char *s1 = "apple";
  char *s2 = "belly";
  int r = strcmp(s1, s2);
  printf("s1 compared with s2 r = %d\n", r);
  r = strcmp(s2, s1);
  printf("s2 compared with s1 r = %d\n", r);
  return 0;
}
```