ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D22(%rip),%r13
  lea    D38(%rip),%r12
L3:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x5,%ebx
  jne    L3
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rbx
  lea    D29(%rip),%rbp
L28:
  sub    $0x4,%rbx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rax
  cmp    %rax,%rbx
  jne    L28
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D38
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D29
type_guessed: string

tool: D22: vetor[%d]:

tool: D38: %d

tool: D23: Valores apontados pelo ponteiro 

tool: D29: %d


assistant: ```c
main() {
  int i;
  int vint[5];
  int *pvint;
  for (i = 0; i < 5; i++, *pvint++) {
    printf("vetor[%d]:", i);
    scanf("%d", &vint[i]);
    pvint = &vint[i];
  }
  printf("Valores apontados pelo ponteiro \n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", *--pvint);
  }
  getch();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
L14:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L14
  lea    D7(%rip),%rdi
  lea    0x14(%rsp),%rbx
  call   <puts@plt>
  lea    D38(%rip),%rbp
L27:
  mov    -0x4(%rbx),%esi
  sub    $0x4,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L27
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D39
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D38
datatype: string

tool: D39: vetor[%d]:

tool: D5: %d

tool: D7: Valores apontados pelo ponteiro 

tool: D38: %d


assistant: ```c
main() {
  int i;
  int vint[5];
  int *pvint;
  for (i = 0; i < 5; i++, *pvint++) {
    printf("vetor[%d]:", i);
    scanf("%d", &vint[i]);
    pvint = &vint[i];
  }
  printf("Valores apontados pelo ponteiro \n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", *--pvint);
  }
  getch();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
L1:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L1
  lea    D23(%rip),%rdi
  lea    0x14(%rsp),%rbx
  call   <puts@plt>
  lea    D36(%rip),%rbp
L19:
  mov    -0x4(%rbx),%esi
  sub    $0x4,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D23
datatype: string
name: disassemble_data
arguments: data_tag: D36
datatype: string

tool: D9: vetor[%d]:

tool: D16: %d

tool: D23: Valores apontados pelo ponteiro 

tool: D36: %d


assistant: ```c
main() {
  int i;
  int vint[5];
  int *pvint;
  for (i = 0; i < 5; i++, *pvint++) {
    printf("vetor[%d]:", i);
    scanf("%d", &vint[i]);
    pvint = &vint[i];
  }
  printf("Valores apontados pelo ponteiro \n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", *--pvint);
  }
  getch();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parent_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%edi
  call   <wait@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: done waiting for %d, wait returned %d


assistant: ```c
extern void parent_code(int child_pid) {
  int wait_rv = wait(NULL);
  printf("done waiting for %d, wait returned %d\n", child_pid, wait_rv);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parent_code>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <wait@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6: done waiting for %d, wait returned %d


assistant: ```c
extern void parent_code(int child_pid) {
  int wait_rv = wait(NULL);
  printf("done waiting for %d, wait returned %d\n", child_pid, wait_rv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parent_code>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <wait@plt>
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: done waiting for %d, wait returned %d


assistant: ```c
extern void parent_code(int child_pid) {
  int wait_rv = wait(NULL);
  printf("done waiting for %d, wait returned %d\n", child_pid, wait_rv);
}
```
user: What is the c source code of the assembly code below:

```asm
<parent_code>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  call   <wait@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: done waiting for %d, wait returned %d


assistant: ```c
extern void parent_code(int child_pid) {
  int wait_rv = wait(NULL);
  printf("done waiting for %d, wait returned %d\n", child_pid, wait_rv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prdec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x2c(%rbp)
  jns    L3
  mov    -0x28(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <pc@plt>
  negl   -0x2c(%rbp)
L3:
  movl   $0xa,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  cltq
  movb   $0x0,-0x13(%rbp,%rax,1)
  jmp    L10
L41:
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x13(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
L10:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L41
  cmpl   $0x9,-0x18(%rbp)
  je     L41
  jmp    L7
L1:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pc@plt>
L7:
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x13(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L1
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void prdec(struct _pfr *r, int v) {
  if (v < 0) {
    pc(r, '-');
    v = -v;
  }
  char digs[11];
  int i = 10;
  digs[i--] = 0;
  while (v || i == 9) {
    digs[i--] = '0' + (v % 10);
    v /= 10;
  }
  while (digs[++i])
    pc(r, digs[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prdec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  js     L67
L2:
  movb   $0x0,0x17(%rsp)
  lea    0x16(%rsp),%rsi
  mov    $0x9,%ecx
L39:
  mov    %ecx,%edi
  sub    $0x1,%ecx
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rsi)
  mov    %eax,%ebx
  sub    $0x1,%rsi
  test   %eax,%eax
  jne    L39
  cmp    $0x9,%ecx
  je     L39
  movslq %edi,%rax
  movzbl 0xd(%rsp,%rax,1),%esi
  test   %sil,%sil
  je     L59
  lea    0xd(%rsp,%rax,1),%rbx
L62:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <pc@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L62
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  mov    $0x2d,%esi
  call   <pc@plt>
  neg    %ebx
  jmp    L2
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prdec(struct _pfr *r, int v) {
  if (v < 0) {
    pc(r, '-');
    v = -v;
  }
  char digs[11];
  int i = 10;
  digs[i--] = 0;
  while (v || i == 9) {
    digs[i--] = '0' + (v % 10);
    v /= 10;
  }
  while (digs[++i])
    pc(r, digs[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<prdec>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  js     L48
L1:
  movb   $0x0,0x17(%rsp)
  mov    $0x9,%ecx
  lea    0xd(%rsp),%rdx
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %ebp,%eax
  mov    %ebp,%esi
  movslq %ecx,%r8
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  mov    %eax,%ebp
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,(%rdx,%rcx,1)
  sub    $0x1,%rcx
  test   %eax,%eax
  jne    L32
  lea    (%rdx,%r8,1),%rbp
  nopl   0x0(%rax,%rax,1)
L26:
  movsbl %sil,%esi
  mov    %rbx,%rdi
  add    $0x1,%rbp
  call   <pc@plt>
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  jne    L26
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    $0x2d,%esi
  neg    %ebp
  call   <pc@plt>
  jmp    L1
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void prdec(struct _pfr *r, int v) {
  if (v < 0) {
    pc(r, '-');
    v = -v;
  }
  char digs[11];
  int i = 10;
  digs[i--] = 0;
  while (v || i == 9) {
    digs[i--] = '0' + (v % 10);
    v /= 10;
  }
  while (digs[++i])
    pc(r, digs[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hasht_default_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <hashlittle2@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L16
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
uint32_t hasht_default_hash(char *key, int perm) {
  uint32_t h1 = 0;
  uint32_t h2 = 0;
  hashlittle2(key, strlen(key), &h1, &h2);
  if (h2 % 2 == 0)
    --h2;
  return (h1 + perm * h2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hasht_default_hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <strlen@plt>
  mov    %eax,%esi
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  call   <hashlittle2@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  jne    L8
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
L8:
  imul   0x4(%rsp),%ebx
  add    (%rsp),%ebx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t hasht_default_hash(char *key, int perm) {
  uint32_t h1 = 0;
  uint32_t h2 = 0;
  hashlittle2(key, strlen(key), &h1, &h2);
  if (h2 % 2 == 0)
    --h2;
  return (h1 + perm * h2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hasht_default_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <strlen@plt>
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <hashlittle2@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  imul   %eax,%ebx
  mov    (%rsp),%eax
  add    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t hasht_default_hash(char *key, int perm) {
  uint32_t h1 = 0;
  uint32_t h2 = 0;
  hashlittle2(key, strlen(key), &h1, &h2);
  if (h2 % 2 == 0)
    --h2;
  return (h1 + perm * h2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hasht_default_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <strlen@plt>
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <hashlittle2@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  imul   %eax,%ebx
  mov    (%rsp),%eax
  add    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t hasht_default_hash(char *key, int perm) {
  uint32_t h1 = 0;
  uint32_t h2 = 0;
  hashlittle2(key, strlen(key), &h1, &h2);
  if (h2 % 2 == 0)
    --h2;
  return (h1 + perm * h2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_pow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L7:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  sarl   -0x18(%rbp)
L25:
  cmpl   $0x0,-0x18(%rbp)
  jg     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _pow2(int N, int M) {
  int pw = 1, n = N;
  while (M > 0) {
    if (M & 1)
      pw *= n;
    n *= n;
    M >>= 1;
  }
  return pw;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_pow2>:
  endbr64
  test   %esi,%esi
  jle    L22
  mov    $0x1,%eax
  jmp    L3
L28:
  imul   %edi,%edi
  sar    %esi
  test   %esi,%esi
  jle    L26
L3:
  test   $0x1,%sil
  je     L28
  imul   %edi,%eax
  jmp    L28
L26:
  ret
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _pow2(int N, int M) {
  int pw = 1, n = N;
  while (M > 0) {
    if (M & 1)
      pw *= n;
    n *= n;
    M >>= 1;
  }
  return pw;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_pow2>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jle    L3
  nopl   (%rax)
L8:
  test   $0x1,%sil
  je     L5
  imul   %edi,%eax
L5:
  imul   %edi,%edi
  sar    %esi
  jne    L8
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
int _pow2(int N, int M) {
  int pw = 1, n = N;
  while (M > 0) {
    if (M & 1)
      pw *= n;
    n *= n;
    M >>= 1;
  }
  return pw;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_pow2>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  jle    L5
  nopl   (%rax)
L3:
  test   $0x1,%sil
  je     L26
  imul   %edi,%eax
L26:
  imul   %edi,%edi
  sar    %esi
  jne    L3
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
int _pow2(int N, int M) {
  int pw = 1, n = N;
  while (M > 0) {
    if (M & 1)
      pw *= n;
    n *= n;
    M >>= 1;
  }
  return pw;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x18(%rbp)
  jne    L16
  movsd  -0x20(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L4
L16:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D58(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L4:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D51
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D58
type_guessed: string
name: retrieve_data
arguments: tag: D45
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D22: 
	---------------%s----------------



tool: D51: 			SIZE	 TIME_SEC	 gflops
 

tool: D17: 			%d	%f	 %lf	


tool: D58: ---

tool: D45: 			%d	%lf 	%s	


tool: D9: 
	-----------------------------------------------------------------------------------------

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L16
  lea    D49(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D40(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L9:
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: tag: D52
type_infered: string
name: retrieve_data
arguments: tag: D38
type_infered: string
name: retrieve_data
arguments: tag: D49
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D52: 
	---------------%s----------------



tool: D38: 			SIZE	 TIME_SEC	 gflops
 

tool: D49: ---

tool: D40: 			%d	%lf 	%s	


tool: D37: 
	-----------------------------------------------------------------------------------------

tool: D0: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D7(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L1
  lea    D25(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
L8:
  add    $0x18,%rsp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string
name: parse_data
arguments: data_label: D58
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D10
type_guessed: string

tool: D7: 
	---------------%s----------------



tool: D58: 			SIZE	 TIME_SEC	 gflops
 

tool: D25: ---

tool: D12: 			%d	%lf 	%s	


tool: D0: 
	-----------------------------------------------------------------------------------------

tool: D10: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops\n \n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------------------------------");
}
```