user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf80,%rsp
  mov    %edi,-0x1f74(%rbp)
  mov    %rsi,-0x1f80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1f54(%rbp)
  lea    -0x1f5c(%rbp),%rcx
  lea    -0x1f60(%rbp),%rdx
  lea    -0x1f64(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x1f58(%rbp)
  jmp    L112
L140:
  lea    -0x1f50(%rbp),%rdx
  mov    -0x1f58(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1f58(%rbp)
L112:
  mov    -0x1f60(%rbp),%eax
  cmp    %eax,-0x1f58(%rbp)
  jl     L140
  movl   $0x0,-0x1f58(%rbp)
  jmp    L85
L162:
  lea    -0xfb0(%rbp),%rdx
  mov    -0x1f58(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1f58(%rbp)
L85:
  mov    -0x1f5c(%rbp),%eax
  cmp    %eax,-0x1f58(%rbp)
  jl     L162
  movl   $0x0,-0x1f58(%rbp)
  jmp    L160
L170:
  mov    -0x1f60(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L143
  mov    -0x1f5c(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    $0x2,%eax
  je     L99
L143:
  mov    -0x1f60(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  cmp    $0x2,%eax
  jne    L185
  mov    -0x1f5c(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    $0x5,%eax
  je     L99
L185:
  mov    -0x1f60(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%eax
  cmp    $0x5,%eax
  jne    L42
  mov    -0x1f5c(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L42
L99:
  addl   $0x1,-0x1f54(%rbp)
  jmp    L16
L42:
  mov    -0x1f60(%rbp),%ecx
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%ecx
  mov    -0x1f5c(%rbp),%esi
  mov    -0x1f58(%rbp),%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,%ecx
  je     L16
  subl   $0x1,-0x1f54(%rbp)
L16:
  addl   $0x1,-0x1f58(%rbp)
L160:
  mov    -0x1f64(%rbp),%eax
  cmp    %eax,-0x1f58(%rbp)
  jl     L170
  cmpl   $0x0,-0x1f54(%rbp)
  je     L90
  cmpl   $0x0,-0x1f54(%rbp)
  jle    L31
  lea    D51(%rip),%rax
  jmp    L139
L31:
  lea    D44(%rip),%rax
  jmp    L139
L90:
  lea    D28(%rip),%rax
L139:
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D59
type_infered: string
name: unpack_data
arguments: data_label: D51
type_infered: string
name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D22
type_infered: string

tool: D23: %i %i %i

tool: D59: %i

tool: D51: A

tool: D44: B

tool: D28: draw

tool: D22: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int a[1000], b[1000], n, na, nb, i, ret = 0;
  scanf("%i %i %i", &n, &na, &nb);
  for (i = 0; i < na; i++)
    scanf("%i", &a[i]);
  for (i = 0; i < nb; i++)
    scanf("%i", &b[i]);
  for (i = 0; i < n; i++) {
    if (a[i % na] == 0 && b[i % nb] == 2 || a[i % na] == 2 && b[i % nb] == 5 || a[i % na] == 5 && b[i % nb] == 0) {
      ret++;
    } else if (a[i % na] != b[i % nb]) {
      ret--;
    }
  }
  printf("%s", ret ? ret > 0 ? "A" : "B" : "draw");
  return 0;
}
```