ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcopy>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L13:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <fatal@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: out of dynamic memory

assistant: ```c
void *memcopy(void *p, int len) {
  char *q = malloc(len);
  if (!q)
    fatal("out of dynamic memory");
  memcpy(q, p, len);
  return (q);
}
```
user: What is the c source code of the assembly code below?

```asm
<prompt_use_code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D11: Use Code (R, C, I)? 

tool: D8:  %c

assistant: ```c
char prompt_use_code(void) {
  char temp_value = '\0';
  printf("Use Code (R, C, I)? ");
  scanf(" %c", &temp_value);
  return temp_value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prompt_use_code>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D12: Use Code (R, C, I)? 

tool: D14:  %c

assistant: ```c
char prompt_use_code(void) {
  char temp_value = '\0';
  printf("Use Code (R, C, I)? ");
  scanf(" %c", &temp_value);
  return temp_value;
}
```
user: What is the c source code of the assembly code below?

```asm
<prompt_use_code>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D11: Use Code (R, C, I)? 

tool: D19:  %c

assistant: ```c
char prompt_use_code(void) {
  char temp_value = '\0';
  printf("Use Code (R, C, I)? ");
  scanf(" %c", &temp_value);
  return temp_value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prompt_use_code>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D19
type: string

tool: D4: Use Code (R, C, I)? 

tool: D19:  %c

assistant: ```c
char prompt_use_code(void) {
  char temp_value = '\0';
  printf("Use Code (R, C, I)? ");
  scanf(" %c", &temp_value);
  return temp_value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execveat_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x8(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int execveat_(int fd, const char *path, char **argv, char **envp, int flags) {
  errno = -ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<execveat_>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    D9(%rip),%rdx
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execveat_(int fd, const char *path, char **argv, char **envp, int flags) {
  errno = -ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<execveat_>:
  endbr64
  mov    D19(%rip),%rax
  mov    D14(%rip),%rdx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execveat_(int fd, const char *path, char **argv, char **envp, int flags) {
  errno = -ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<execveat_>:
  endbr64
  mov    D2(%rip),%rax
  mov    D10(%rip),%rdx
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,(%rdx)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int execveat_(int fd, const char *path, char **argv, char **envp, int flags) {
  errno = -ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L2
  movsbl -0x9(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  jmp    L46
L2:
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jne    L45
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L45:
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x8(%rbp),%rax
L46:
  leave
  ret
```

assistant: ```c
char *strrchr(const char *s, int _c) {
  char c = (char)_c;
  if ('\0' == c)
    return strchr(s, c);
  const char *last = NULL;
  while (*s) {
    if (*s == c)
      last = s;
    ++s;
  }
  return (char *)last;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strrchr>:
  endbr64
  test   %sil,%sil
  je     L22
  mov    %esi,%ecx
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L21
L5:
  cmp    %dl,%cl
  cmove  %rdi,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L5
  ret
L21:
  ret
L22:
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <strchr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *strrchr(const char *s, int _c) {
  char c = (char)_c;
  if ('\0' == c)
    return strchr(s, c);
  const char *last = NULL;
  while (*s) {
    if (*s == c)
      last = s;
    ++s;
  }
  return (char *)last;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrchr>:
  endbr64
  mov    %esi,%edx
  test   %sil,%sil
  je     L12
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L9
  nopl   (%rax)
L26:
  cmp    %al,%dl
  cmove  %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L26
L9:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L12:
  xor    %esi,%esi
  jmp    1050 <strchr@plt>
```

assistant: ```c
char *strrchr(const char *s, int _c) {
  char c = (char)_c;
  if ('\0' == c)
    return strchr(s, c);
  const char *last = NULL;
  while (*s) {
    if (*s == c)
      last = s;
    ++s;
  }
  return (char *)last;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrchr>:
  endbr64
  mov    %esi,%edx
  test   %sil,%sil
  je     L21
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L0
  nopl   (%rax)
L20:
  cmp    %al,%dl
  cmove  %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L20
L0:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L21:
  xor    %esi,%esi
  jmp    1050 <strchr@plt>
```

assistant: ```c
char *strrchr(const char *s, int _c) {
  char c = (char)_c;
  if ('\0' == c)
    return strchr(s, c);
  const char *last = NULL;
  while (*s) {
    if (*s == c)
      last = s;
    ++s;
  }
  return (char *)last;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L45
  mov    $0xffffffff,%eax
  jmp    L49
L45:
  mov    $0x1,%eax
L49:
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L32
  addq   $0x1,-0x18(%rbp)
L32:
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L15:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  movsbq -0x9(%rbp),%rax
  imul   -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long int ft_atoi(char *number) {
  unsigned long int res;
  char neg;
  neg = (number[0] == '-') ? -1 : 1;
  if (number[0] == '-')
    ++number;
  res = 0;
  while (*number) {
    res *= 10;
    res += *number - '0';
    ++number;
  }
  return (res * neg);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_atoi>:
  endbr64
  cmpb   $0x2d,(%rdi)
  je     L29
  mov    $0x1,%eax
L20:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L36
  mov    $0x0,%ecx
L39:
  lea    (%rcx,%rcx,4),%rcx
  movsbl %dl,%edx
  sub    $0x30,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,2),%rcx
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L39
L8:
  movsbq %al,%rax
  imul   %rcx,%rax
  ret
L36:
  mov    $0x0,%ecx
  jmp    L8
L29:
  add    $0x1,%rdi
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
long int ft_atoi(char *number) {
  unsigned long int res;
  char neg;
  neg = (number[0] == '-') ? -1 : 1;
  if (number[0] == '-')
    ++number;
  res = 0;
  while (*number) {
    res *= 10;
    res += *number - '0';
    ++number;
  }
  return (res * neg);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_atoi>:
  endbr64
  movsbl (%rdi),%edx
  cmp    $0x2d,%dl
  je     L23
  mov    $0x1,%ecx
  xor    %eax,%eax
  test   %dl,%dl
  je     L38
  nopw   0x0(%rax,%rax,1)
L15:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rdi
  movslq %edx,%rdx
  lea    (%rdx,%rax,2),%rax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L15
  imul   %rcx,%rax
  ret
  xchg   %ax,%ax
L23:
  movsbl 0x1(%rdi),%edx
  mov    $0xffffffffffffffff,%rcx
  add    $0x1,%rdi
  xor    %eax,%eax
  test   %dl,%dl
  jne    L15
L38:
  ret
```

assistant: ```c
long int ft_atoi(char *number) {
  unsigned long int res;
  char neg;
  neg = (number[0] == '-') ? -1 : 1;
  if (number[0] == '-')
    ++number;
  res = 0;
  while (*number) {
    res *= 10;
    res += *number - '0';
    ++number;
  }
  return (res * neg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_atoi>:
  endbr64
  movsbl (%rdi),%edx
  cmp    $0x2d,%dl
  je     L5
  mov    $0x1,%ecx
  xor    %eax,%eax
  test   %dl,%dl
  je     L9
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x30,%edx
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rdi
  movslq %edx,%rdx
  lea    (%rdx,%rax,2),%rax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  imul   %rcx,%rax
  ret
  xchg   %ax,%ax
L5:
  movsbl 0x1(%rdi),%edx
  mov    $0xffffffffffffffff,%rcx
  add    $0x1,%rdi
  xor    %eax,%eax
  test   %dl,%dl
  jne    L10
L9:
  ret
```

assistant: ```c
long int ft_atoi(char *number) {
  unsigned long int res;
  char neg;
  neg = (number[0] == '-') ? -1 : 1;
  if (number[0] == '-')
    ++number;
  res = 0;
  while (*number) {
    res *= 10;
    res += *number - '0';
    ++number;
  }
  return (res * neg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movzbl -0x3(%rbp),%edx
  movzbl -0x2(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  char a;
  char c;
  char b;
  a = b + c;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char a;
  char c;
  char b;
  a = b + c;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char a;
  char c;
  char b;
  a = b + c;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char a;
  char c;
  char b;
  a = b + c;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdi
  mov    $0x0,%ebx
  lea    0x0(%rbp,%rax,1),%rcx
  test   %r13,%r13
  je     L129
L36:
  test   %rdi,%rdi
  je     L63
  movzbl (%r12,%rbx,1),%edx
  mov    %rbp,%rax
L23:
  cmp    %dl,(%rax)
  je     L29
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L23
L63:
  mov    %r13,%rsi
  sub    %rbx,%rsi
  lea    -0x1(%r12,%r13,1),%r10
  lea    0x0(%rbp,%rdi,1),%rcx
  mov    $0x0,%r11d
  mov    $0x1,%r9d
L54:
  test   %rdi,%rdi
  je     L24
  movzbl (%r10),%edx
  mov    %rbp,%rax
  mov    %r11d,%r8d
  jmp    L56
L129:
  mov    %r13,%rbx
  jmp    L63
L29:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L36
  mov    %r13,%rbx
  jmp    L63
L37:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L92
L56:
  cmp    %dl,(%rax)
  jne    L37
  sub    $0x1,%rsi
  mov    %r9d,%r8d
  jmp    L37
L92:
  sub    $0x1,%r10
  test   %r8d,%r8d
  jne    L54
L24:
  mov    %rsi,%r13
  sub    %rbx,%r13
  cmp    %rbx,%rsi
  mov    $0x0,%eax
  cmovb  %rax,%r13
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  lea    (%r12,%rbx,1),%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *s, const char *totrim) {
  int32_t i, j;
  int32_t start, end;
  int32_t slen, totrimlen, newlen;
  bool trimmed;
  char *news;
  slen = strlen(s);
  totrimlen = strlen(totrim);
  start = 0;
  for (i = 0; i < slen; i++) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        start++;
        trimmed = true;
        break;
      }
    if (!trimmed)
      break;
  }
  end = slen - start;
  for (i = slen - 1; i >= 0; i--) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        end--;
        trimmed = true;
      }
    if (!trimmed)
      break;
  }
  newlen = (end >= start) ? (end - start) : 0;
  news = malloc((newlen + 1) * sizeof(*news));
  assert(news);
  strncpy(news, s + start, newlen);
  news[newlen] = '\0';
  free(s);
  return news;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  xor    %r10d,%r10d
  xor    %edi,%edi
  lea    (%rbx,%rax,1),%rsi
  test   %r13,%r13
  je     L121
L30:
  lea    0x0(%rbp,%r10,1),%r12
  test   %rax,%rax
  je     L11
  movzbl 0x0(%rbp,%r10,1),%ecx
  mov    %rbx,%rdx
  jmp    L123
  xchg   %ax,%ax
L2:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L11
L123:
  cmp    %cl,(%rdx)
  jne    L2
  add    $0x1,%r10
  cmp    %r10,%r13
  jne    L30
  lea    0x0(%rbp,%r13,1),%r12
  xor    %edi,%edi
  nopl   0x0(%rax)
L121:
  lea    -0x1(%rbp,%r13,1),%r9
  lea    (%rbx,%rax,1),%rsi
  nopl   0x0(%rax)
L72:
  test   %rax,%rax
  je     L55
  movzbl (%r9),%ecx
  mov    %rbx,%rdx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L40:
  cmp    %cl,(%rdx)
  jne    L71
  sub    $0x1,%rdi
  mov    $0x1,%r8d
L71:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L40
  sub    $0x1,%r9
  test   %r8d,%r8d
  jne    L72
L55:
  cmp    %r10,%rdi
  jb     L95
  mov    %rdi,%rbx
  sub    %r10,%rbx
  lea    0x1(%rbx),%rdi
L37:
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  mov    %r13,%rdi
  sub    %r10,%rdi
  jmp    L121
L95:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  jmp    L37
```

assistant: ```c
char *trim(char *s, const char *totrim) {
  int32_t i, j;
  int32_t start, end;
  int32_t slen, totrimlen, newlen;
  bool trimmed;
  char *news;
  slen = strlen(s);
  totrimlen = strlen(totrim);
  start = 0;
  for (i = 0; i < slen; i++) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        start++;
        trimmed = true;
        break;
      }
    if (!trimmed)
      break;
  }
  end = slen - start;
  for (i = slen - 1; i >= 0; i--) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        end--;
        trimmed = true;
      }
    if (!trimmed)
      break;
  }
  newlen = (end >= start) ? (end - start) : 0;
  news = malloc((newlen + 1) * sizeof(*news));
  assert(news);
  strncpy(news, s + start, newlen);
  news[newlen] = '\0';
  free(s);
  return news;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  xor    %r10d,%r10d
  xor    %edi,%edi
  lea    (%rbx,%rax,1),%rsi
  test   %r13,%r13
  je     L120
L111:
  lea    0x0(%rbp,%r10,1),%r12
  test   %rax,%rax
  je     L18
  movzbl 0x0(%rbp,%r10,1),%ecx
  mov    %rbx,%rdx
  jmp    L1
  xchg   %ax,%ax
L47:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  je     L18
L1:
  cmp    %cl,(%rdx)
  jne    L47
  add    $0x1,%r10
  cmp    %r10,%r13
  jne    L111
  lea    0x0(%rbp,%r13,1),%r12
  xor    %edi,%edi
  nopl   0x0(%rax)
L120:
  lea    -0x1(%rbp,%r13,1),%r9
  lea    (%rbx,%rax,1),%rsi
  nopl   0x0(%rax)
L36:
  test   %rax,%rax
  je     L74
  movzbl (%r9),%ecx
  mov    %rbx,%rdx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L78:
  cmp    (%rdx),%cl
  jne    L71
  sub    $0x1,%rdi
  mov    $0x1,%r8d
L71:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L78
  sub    $0x1,%r9
  test   %r8d,%r8d
  jne    L36
L74:
  cmp    %r10,%rdi
  jb     L97
  mov    %rdi,%rbx
  sub    %r10,%rbx
  lea    0x1(%rbx),%rdi
L48:
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  mov    %r13,%rdi
  sub    %r10,%rdi
  jmp    L120
L97:
  mov    $0x1,%edi
  xor    %ebx,%ebx
  jmp    L48
```

assistant: ```c
char *trim(char *s, const char *totrim) {
  int32_t i, j;
  int32_t start, end;
  int32_t slen, totrimlen, newlen;
  bool trimmed;
  char *news;
  slen = strlen(s);
  totrimlen = strlen(totrim);
  start = 0;
  for (i = 0; i < slen; i++) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        start++;
        trimmed = true;
        break;
      }
    if (!trimmed)
      break;
  }
  end = slen - start;
  for (i = slen - 1; i >= 0; i--) {
    trimmed = false;
    for (j = 0; j < totrimlen; j++)
      if (totrim[j] == s[i]) {
        end--;
        trimmed = true;
      }
    if (!trimmed)
      break;
  }
  newlen = (end >= start) ? (end - start) : 0;
  news = malloc((newlen + 1) * sizeof(*news));
  assert(news);
  strncpy(news, s + start, newlen);
  news[newlen] = '\0';
  free(s);
  return news;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<normalize_hw_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  movzbl (%rax),%eax
  movsbl %al,%r12d
  mov    -0x28(%rbp),%rax
  add    $0xf,%rax
  movzbl (%rax),%eax
  movsbl %al,%ebx
  mov    -0x28(%rbp),%rax
  add    $0xd,%rax
  movzbl (%rax),%eax
  movsbl %al,%r11d
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  movzbl (%rax),%eax
  movsbl %al,%r10d
  mov    -0x28(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  movsbl %al,%r9d
  mov    -0x28(%rbp),%rax
  add    $0x9,%rax
  movzbl (%rax),%eax
  movsbl %al,%r8d
  mov    -0x28(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%eax
  movsbl %al,%edi
  mov    -0x28(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movsbl %al,%esi
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%r14d
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%r13d
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x30(%rbp),%rax
  push   %r12
  push   %rbx
  push   %r11
  push   %r10
  push   %r9
  push   %r8
  push   %rdi
  push   %rsi
  mov    %r14d,%r9d
  mov    %r13d,%r8d
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x40,%rsp
  mov    $0x1,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %c%c:%c%c:%c%c:%c%c:%c%c:%c%c

assistant: ```c
int normalize_hw_addr(const char *hw_addr, char hw_modified[]) {
  sprintf(hw_modified, "%c%c:%c%c:%c%c:%c%c:%c%c:%c%c", hw_addr[0], hw_addr[1], hw_addr[3], hw_addr[4], hw_addr[6], hw_addr[7], hw_addr[9], hw_addr[10], hw_addr[12], hw_addr[13], hw_addr[15], hw_addr[16]);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<normalize_hw_addr>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rax
  movsbl 0x1(%rdi),%ecx
  movsbl (%rdi),%edx
  movsbl 0x10(%rdi),%esi
  push   %rsi
  movsbl 0xf(%rdi),%esi
  push   %rsi
  movsbl 0xd(%rdi),%esi
  push   %rsi
  movsbl 0xc(%rdi),%esi
  push   %rsi
  movsbl 0xa(%rdi),%esi
  push   %rsi
  movsbl 0x9(%rdi),%esi
  push   %rsi
  movsbl 0x7(%rdi),%esi
  push   %rsi
  movsbl 0x6(%rdi),%esi
  push   %rsi
  movsbl 0x4(%rdi),%r9d
  movsbl 0x3(%rdi),%r8d
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x1,%eax
  add    $0x48,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: %c%c:%c%c:%c%c:%c%c:%c%c:%c%c

assistant: ```c
int normalize_hw_addr(const char *hw_addr, char hw_modified[]) {
  sprintf(hw_modified, "%c%c:%c%c:%c%c:%c%c:%c%c:%c%c", hw_addr[0], hw_addr[1], hw_addr[3], hw_addr[4], hw_addr[6], hw_addr[7], hw_addr[9], hw_addr[10], hw_addr[12], hw_addr[13], hw_addr[15], hw_addr[16]);
  return 1;
}
```