ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<insert_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L7
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_value>:
  endbr64
  mov    %rdi,%r8
  cmp    %esi,%edx
  jle    L2
  movslq %edx,%rdi
  lea    (%r8,%rdi,1),%rax
  lea    -0x1(%r8,%rdi,1),%rdi
  sub    %esi,%edx
  lea    -0x1(%rdx),%edx
  sub    %rdx,%rdi
L5:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L5
L2:
  movslq %esi,%rsi
  mov    %cl,(%r8,%rsi,1)
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_value>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%edx
  jle    L7
  mov    %edx,%eax
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  sub    $0x1,%eax
  sub    %rax,%rdx
  lea    0x1(%rax),%r8
  sub    %rax,%rsi
  add    %rdi,%rsi
  lea    (%rdi,%rdx,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L7:
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_value>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cmp    %ebx,%edx
  jle    L3
  mov    %edx,%eax
  movslq %edx,%rdx
  sub    %ebx,%eax
  lea    -0x1(%rdx),%rsi
  sub    $0x1,%eax
  sub    %rax,%rdx
  lea    0x1(%rax),%r8
  sub    %rax,%rsi
  add    %rdi,%rsi
  lea    (%rdi,%rdx,1),%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L3:
  mov    %r12b,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value(unsigned char binary_stream[], const int posn, const int streamlen, const int newbit) {
  int i;
  for (i = streamlen; i > posn; i--) {
    binary_stream[i] = binary_stream[i - 1];
  }
  binary_stream[posn] = (unsigned char)newbit;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<errc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %esi,-0xc8(%rbp)
  mov    %rdx,-0xd0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc8(%rbp),%esi
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <verrc@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void errc(int status, int code, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  verrc(status, code, format, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<errc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void errc(int status, int code, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  verrc(status, code, format, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<errc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void errc(int status, int code, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  verrc(status, code, format, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<errc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <verrc@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void errc(int status, int code, const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  verrc(status, code, format, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: PASS


assistant: ```c
int main() {
#pragma xmp reflect(b)
#pragma xmp task on p(1, 1)
  { printf("PASS\n"); }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: PASS


assistant: ```c
int main() {
#pragma xmp reflect(b)
#pragma xmp task on p(1, 1)
  { printf("PASS\n"); }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: PASS


assistant: ```c
int main() {
#pragma xmp reflect(b)
#pragma xmp task on p(1, 1)
  { printf("PASS\n"); }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: PASS


assistant: ```c
int main() {
#pragma xmp reflect(b)
#pragma xmp task on p(1, 1)
  { printf("PASS\n"); }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rdx
  lea    0xe(%rsp),%rsi
  lea    D146(%rip),%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x43,0xe(%rsp)
  jne    L44
  cmpb   $0x46,0xf(%rsp)
  je     L3
L44:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  D71(%rip),%xmm1
  addsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jb     L76
  lea    D153(%rip),%rbx
L54:
  movapd %xmm0,%xmm1
  subsd  D83(%rip),%xmm1
  mulsd  D73(%rip),%xmm1
  divsd  D16(%rip),%xmm1
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  D71(%rip),%xmm1
  addsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jae    L54
L76:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  lea    D76(%rip),%rdi
  call   <puts@plt>
  movsd  0x18(%rsp),%xmm0
  movsd  D71(%rip),%xmm1
  addsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jb     L76
  lea    D153(%rip),%rbx
L28:
  movsd  D16(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  divsd  D73(%rip),%xmm1
  addsd  D83(%rip),%xmm1
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  0x18(%rsp),%xmm0
  addsd  0x20(%rsp),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  D71(%rip),%xmm1
  addsd  0x10(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jae    L28
  jmp    L76
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D146
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string
name: parse_data
arguments: tag: D33
type_infered: string
name: parse_data
arguments: tag: D71
type_infered: f64
name: parse_data
arguments: tag: D153
type_infered: string
name: parse_data
arguments: tag: D83
type_infered: byte[8]
name: parse_data
arguments: tag: D73
type_infered: byte[8]
name: parse_data
arguments: tag: D16
type_infered: byte[8]
name: parse_data
arguments: tag: D76
type_infered: string

tool: D146: %c->%c

tool: D22: %lf%lf%lf

tool: D33:    F  ->    C

tool: D71: 0.01

tool: D153: %5.1lf ->%6.1lf


tool: {"D83": [0x00,0x00,0x00,0x00,0x00,0x00,0x40,0x40]}

tool: {"D73": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: D76:    C  ->    F

assistant: ```c
int main() {
  double h, l, a, b, d;
  char c, f;
  scanf("%c->%c", &c, &f);
  scanf("%lf%lf%lf", &l, &h, &a);
  if (c == 'C' && f == 'F') {
    printf("   C  ->    F\n");
    for (; l <= h + 0.01; l = l + a) {
      b = 9 * l / 5 + 32;
      printf("%5.1lf ->%6.1lf\n", l, b);
    }
  } else {
    printf("   F  ->    C\n");
    for (; l <= h + 0.01; l = l + a) {
      b = (l - 32) * 5 / 9;
      printf("%5.1lf ->%6.1lf\n", l, b);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <MonitorParentProcessDead@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorParentProcessDead();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <MonitorParentProcessDead@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorParentProcessDead();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MonitorParentProcessDead@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorParentProcessDead();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MonitorParentProcessDead@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorParentProcessDead();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arc4_seed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <arc4_seed_urandom@plt>
  test   %rax,%rax
  jne    L28
  movl   $0x1,-0x4(%rbp)
L28:
  mov    $0x0,%eax
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  test   %rax,%rax
  jne    L12
  movl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  je     L7
  mov    $0x0,%eax
  jmp    L27
L7:
  mov    $0xffffffff,%eax
L27:
  leave
  ret
```

assistant: ```c
int arc4_seed(void) {
  int ok = 0;
  if (0 == arc4_seed_urandom())
    ok = 1;
  if (0 == arc4_seed_proc_sys_kernel_random_uuid())
    ok = 1;
  return ok ? 0 : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<arc4_seed>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <arc4_seed_urandom@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  test   %rax,%rax
  sete   %al
  test   %rbx,%rbx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  sub    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int arc4_seed(void) {
  int ok = 0;
  if (0 == arc4_seed_urandom())
    ok = 1;
  if (0 == arc4_seed_proc_sys_kernel_random_uuid())
    ok = 1;
  return ok ? 0 : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arc4_seed>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <arc4_seed_urandom@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L1
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int arc4_seed(void) {
  int ok = 0;
  if (0 == arc4_seed_urandom())
    ok = 1;
  if (0 == arc4_seed_proc_sys_kernel_random_uuid())
    ok = 1;
  return ok ? 0 : -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<arc4_seed>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <arc4_seed_urandom@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L5
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  call   <arc4_seed_proc_sys_kernel_random_uuid@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int arc4_seed(void) {
  int ok = 0;
  if (0 == arc4_seed_urandom())
    ok = 1;
  if (0 == arc4_seed_proc_sys_kernel_random_uuid())
    ok = 1;
  return ok ? 0 : -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L48
L0:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L26
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0x4(%rbp)
  jne    L48
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L58
L26:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L58
L48:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L0
L58:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_line(char *s, int max_len) {
  int c;
  int i;
  i = 0;
  while ((c = getchar()) != EOF) {
    if (i < max_len - 1) {
      s[i++] = c;
      if (c == '\n') {
        s[i++] = '\0';
        break;
      }
    } else {
      s[i++] = '\0';
      break;
    }
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%r12d
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L1
  cmp    %ebx,%r12d
  jle    L20
  lea    0x1(%rbx),%edx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    $0xa,%eax
  je     L22
  mov    %edx,%ebx
  jmp    L15
L22:
  add    $0x2,%ebx
  movslq %edx,%rdx
  movb   $0x0,0x0(%r13,%rdx,1)
  jmp    L1
L20:
  movslq %ebx,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  lea    0x1(%rbx),%ebx
L1:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_line(char *s, int max_len) {
  int c;
  int i;
  i = 0;
  while ((c = getchar()) != EOF) {
    if (i < max_len - 1) {
      s[i++] = c;
      if (c == '\n') {
        s[i++] = '\0';
        break;
      }
    } else {
      s[i++] = '\0';
      break;
    }
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D9(%rip),%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  jmp    L39
  nopl   0x0(%rax)
L34:
  lea    0x1(%r12),%edx
  cmp    %r12d,%ebx
  jle    L28
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    $0xa,%eax
  je     L0
  mov    %edx,%r12d
L39:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L34
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  mov    %edx,%r12d
  movb   $0x0,(%r14)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x2,%r12d
  movslq %edx,%rdx
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  movb   $0x0,0x0(%r13,%rdx,1)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char *s, int max_len) {
  int c;
  int i;
  i = 0;
  while ((c = getchar()) != EOF) {
    if (i < max_len - 1) {
      s[i++] = c;
      if (c == '\n') {
        s[i++] = '\0';
        break;
      }
    } else {
      s[i++] = '\0';
      break;
    }
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_line>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D3(%rip),%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  jmp    L36
  nopl   0x0(%rax)
L19:
  lea    0x1(%r12),%edx
  cmp    %r12d,%ebx
  jle    L13
  mov    %al,(%r14)
  add    $0x1,%r14
  cmp    $0xa,%eax
  je     L25
  mov    %edx,%r12d
L36:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L19
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L13:
  mov    %edx,%r12d
  movb   $0x0,(%r14)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x2,%r12d
  movslq %edx,%rdx
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  movb   $0x0,0x0(%r13,%rdx,1)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int get_line(char *s, int max_len) {
  int c;
  int i;
  i = 0;
  while ((c = getchar()) != EOF) {
    if (i < max_len - 1) {
      s[i++] = c;
      if (c == '\n') {
        s[i++] = '\0';
        break;
      }
    } else {
      s[i++] = '\0';
      break;
    }
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime_factor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L28
L20:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x14(%rbp)
  jmp    L2
L24:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: string

tool: D5: %d*

tool: D17: %d

assistant: ```c
int prime_factor(int nb) {
  int i;
  i = 2;
  while (i < nb) {
    if (nb % i == 0) {
      printf("%d*", i);
      nb /= i;
    } else {
      i++;
    }
    printf("%d", nb);
  }
  return (nb);
}
```
user: Translate the below assembly code into C programming language:

```asm
<prime_factor>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x2,%edi
  jle    L9
  mov    $0x2,%ebp
  lea    D14(%rip),%r13
  lea    D10(%rip),%r12
  jmp    L14
L3:
  add    $0x1,%ebp
L23:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jle    L9
L14:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L3
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%ebx
  jmp    L23
L9:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D14: %d*

tool: D10: %d

assistant: ```c
int prime_factor(int nb) {
  int i;
  i = 2;
  while (i < nb) {
    if (nb % i == 0) {
      printf("%d*", i);
      nb /= i;
    } else {
      i++;
    }
    printf("%d", nb);
  }
  return (nb);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prime_factor>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jle    L6
  mov    $0x2,%ebx
  lea    D18(%rip),%r13
  lea    D1(%rip),%r14
  jmp    L15
  nopl   0x0(%rax)
L28:
  add    $0x1,%ebx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jle    L6
L15:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%ebp
  test   %edx,%edx
  jne    L28
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %ebp,%r12d
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jg     L15
L6:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D18: %d

tool: D1: %d*

assistant: ```c
int prime_factor(int nb) {
  int i;
  i = 2;
  while (i < nb) {
    if (nb % i == 0) {
      printf("%d*", i);
      nb /= i;
    } else {
      i++;
    }
    printf("%d", nb);
  }
  return (nb);
}
```