ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<exponent>:
  endbr64
  test   %rsi,%rsi
  jle    L11
  xor    %eax,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L3:
  add    $0x1,%rax
  imul   %rdi,%r8
  cmp    %rax,%rsi
  jne    L3
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long exponent(long base, long power) {
  long result = 1;
  long i, temp;
  for (i = 0; i < power; i++) {
    temp = result * base;
    result = temp;
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<exponent>:
  endbr64
  test   %rsi,%rsi
  jle    L5
  xor    %eax,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  imul   %rdi,%r8
  cmp    %rax,%rsi
  jne    L8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long exponent(long base, long power) {
  long result = 1;
  long i, temp;
  for (i = 0; i < power; i++) {
    temp = result * base;
    result = temp;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Cbuf_ExecuteText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L28
  cmpl   $0x2,-0x4(%rbp)
  jg     L27
  cmpl   $0x0,-0x4(%rbp)
  je     L43
  cmpl   $0x1,-0x4(%rbp)
  je     L22
  jmp    L27
L43:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Cmd_ExecuteString@plt>
  jmp    L36
L22:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Cbuf_InsertText@plt>
  jmp    L36
L28:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Cbuf_AddText@plt>
  jmp    L36
L27:
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <Com_Error@plt>
  nop
L36:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Cbuf_ExecuteText: bad exec_when

assistant: ```c
void Cbuf_ExecuteText(int exec_when, const char *text) {
  switch (exec_when) {
  case 0:
    Cmd_ExecuteString(text);
    break;
  case 1:
    Cbuf_InsertText(text);
    break;
  case 2:
    Cbuf_AddText(text);
    break;
  default:
    Com_Error(0, "Cbuf_ExecuteText: bad exec_when");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cbuf_ExecuteText>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x1,%eax
  je     L11
  cmp    $0x2,%eax
  je     L31
  test   %eax,%eax
  je     L50
  lea    D3(%rip),%rsi
  mov    $0x0,%edi
  call   <Com_Error@plt>
  jmp    L55
L50:
  call   <Cmd_ExecuteString@plt>
L55:
  add    $0x8,%rsp
  ret
L11:
  call   <Cbuf_InsertText@plt>
  jmp    L55
L31:
  call   <Cbuf_AddText@plt>
  jmp    L55
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: Cbuf_ExecuteText: bad exec_when

assistant: ```c
void Cbuf_ExecuteText(int exec_when, const char *text) {
  switch (exec_when) {
  case 0:
    Cmd_ExecuteString(text);
    break;
  case 1:
    Cbuf_InsertText(text);
    break;
  case 2:
    Cbuf_AddText(text);
    break;
  default:
    Com_Error(0, "Cbuf_ExecuteText: bad exec_when");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Cbuf_ExecuteText>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x1,%eax
  je     L21
  cmp    $0x2,%eax
  je     L7
  test   %eax,%eax
  je     L18
  lea    D1(%rip),%rsi
  xor    %edi,%edi
  jmp    10b0 <Com_Error@plt>
  nopl   (%rax)
L21:
  jmp    1090 <Cbuf_InsertText@plt>
  nopl   (%rax)
L18:
  jmp    10a0 <Cmd_ExecuteString@plt>
  nopl   (%rax)
L7:
  jmp    1080 <Cbuf_AddText@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: Cbuf_ExecuteText: bad exec_when

assistant: ```c
void Cbuf_ExecuteText(int exec_when, const char *text) {
  switch (exec_when) {
  case 0:
    Cmd_ExecuteString(text);
    break;
  case 1:
    Cbuf_InsertText(text);
    break;
  case 2:
    Cbuf_AddText(text);
    break;
  default:
    Com_Error(0, "Cbuf_ExecuteText: bad exec_when");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Cbuf_ExecuteText>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x1,%eax
  je     L25
  cmp    $0x2,%eax
  je     L11
  test   %eax,%eax
  je     L10
  lea    D3(%rip),%rsi
  xor    %edi,%edi
  jmp    10b0 <Com_Error@plt>
  nopl   (%rax)
L25:
  jmp    1090 <Cbuf_InsertText@plt>
  nopl   (%rax)
L10:
  jmp    10a0 <Cmd_ExecuteString@plt>
  nopl   (%rax)
L11:
  jmp    1080 <Cbuf_AddText@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D3: Cbuf_ExecuteText: bad exec_when

assistant: ```c
void Cbuf_ExecuteText(int exec_when, const char *text) {
  switch (exec_when) {
  case 0:
    Cmd_ExecuteString(text);
    break;
  case 1:
    Cbuf_InsertText(text);
    break;
  case 2:
    Cbuf_AddText(text);
    break;
  default:
    Com_Error(0, "Cbuf_ExecuteText: bad exec_when");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rcx
  lea    D26(%rip),%rax
  mov    %rax,%rdx
  lea    D48(%rip),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L18
L7:
  mov    -0x14(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L18:
  cmpl   $0xa,-0x14(%rbp)
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D48
datatype: string
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string

tool: D15: Cube

tool: D26: Square

tool: D48: Number

tool: D36: %-10s%-10s%-10s


tool: D12: %-10d%-10d%-10d


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("%-10s%-10s%-10s\n", "Number", "Square", "Cube");
  for (int i = 1; i < 10 + 1; i++) {
    printf("%-10d%-10d%-10d\n", i, (int)pow(i, 2), (int)pow(i, 3));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D48(%rip),%rcx
  lea    D33(%rip),%rdx
  lea    D5(%rip),%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D22(%rip),%r12
L2:
  mov    $0x3,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  mov    %rax,%rbp
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <pow@plt>
  mov    %ebp,%ecx
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D48
data_type: string
name: read_data
arguments: data_label: D33
data_type: string
name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D22
data_type: string

tool: D48: Cube

tool: D33: Square

tool: D5: Number

tool: D8: %-10s%-10s%-10s


tool: D22: %-10d%-10d%-10d


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("%-10s%-10s%-10s\n", "Number", "Square", "Cube");
  for (int i = 1; i < 10 + 1; i++) {
    printf("%-10d%-10d%-10d\n", i, (int)pow(i, 2), (int)pow(i, 3));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rcx
  xor    %eax,%eax
  lea    D3(%rip),%rdx
  push   %rbp
  lea    D48(%rip),%rsi
  lea    D43(%rip),%rdi
  push   %rbx
  lea    D22(%rip),%r12
  mov    $0x1,%ebx
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edi
  mov    $0x3,%esi
  call   <pow@plt>
  mov    %ebx,%edi
  mov    $0x2,%esi
  mov    %rax,%rbp
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type: string
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D48
type: string
name: parse_data
arguments: data_tag: D43
type: string
name: parse_data
arguments: data_tag: D22
type: string

tool: D16: Cube

tool: D3: Square

tool: D48: Number

tool: D43: %-10s%-10s%-10s


tool: D22: %-10d%-10d%-10d


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("%-10s%-10s%-10s\n", "Number", "Square", "Cube");
  for (int i = 1; i < 10 + 1; i++) {
    printf("%-10d%-10d%-10d\n", i, (int)pow(i, 2), (int)pow(i, 3));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D20(%rip),%rcx
  xor    %eax,%eax
  lea    D46(%rip),%rdx
  push   %rbp
  lea    D16(%rip),%rsi
  lea    D1(%rip),%rdi
  push   %rbx
  lea    D48(%rip),%r12
  mov    $0x1,%ebx
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  mov    $0x3,%esi
  call   <pow@plt>
  mov    %ebx,%edi
  mov    $0x2,%esi
  mov    %rax,%rbp
  call   <pow@plt>
  mov    %ebx,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D46
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D48
type: string

tool: D20: Cube

tool: D46: Square

tool: D16: Number

tool: D1: %-10s%-10s%-10s


tool: D48: %-10d%-10d%-10d


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("%-10s%-10s%-10s\n", "Number", "Square", "Cube");
  for (int i = 1; i < 10 + 1; i++) {
    printf("%-10d%-10d%-10d\n", i, (int)pow(i, 2), (int)pow(i, 3));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: cpufreq-aperf [OPTIONS]

-c [ --cpu ] CPU               The CPU core to measure - default all cores
-i [ --intervall ] seconds     Refresh rate - default 1 second
-o [ --once ]                  Exit after one intervall
-h [ --help ]                  This help text
The msr driver must be loaded for this command to work


assistant: ```c
void usage(void) {
  printf("cpufreq-aperf [OPTIONS]\n\n"
         "-c [ --cpu ] CPU               "
         "The CPU core to measure - default all cores\n"
         "-i [ --intervall ] seconds     "
         "Refresh rate - default 1 second\n"
         "-o [ --once ]                  "
         "Exit after one intervall\n"
         "-h [ --help ]                  "
         "This help text\n"
         "The msr driver must be loaded for this command to work\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: cpufreq-aperf [OPTIONS]

-c [ --cpu ] CPU               The CPU core to measure - default all cores
-i [ --intervall ] seconds     Refresh rate - default 1 second
-o [ --once ]                  Exit after one intervall
-h [ --help ]                  This help text
The msr driver must be loaded for this command to work


assistant: ```c
void usage(void) {
  printf("cpufreq-aperf [OPTIONS]\n\n"
         "-c [ --cpu ] CPU               "
         "The CPU core to measure - default all cores\n"
         "-i [ --intervall ] seconds     "
         "Refresh rate - default 1 second\n"
         "-o [ --once ]                  "
         "Exit after one intervall\n"
         "-h [ --help ]                  "
         "This help text\n"
         "The msr driver must be loaded for this command to work\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: cpufreq-aperf [OPTIONS]

-c [ --cpu ] CPU               The CPU core to measure - default all cores
-i [ --intervall ] seconds     Refresh rate - default 1 second
-o [ --once ]                  Exit after one intervall
-h [ --help ]                  This help text
The msr driver must be loaded for this command to work


assistant: ```c
void usage(void) {
  printf("cpufreq-aperf [OPTIONS]\n\n"
         "-c [ --cpu ] CPU               "
         "The CPU core to measure - default all cores\n"
         "-i [ --intervall ] seconds     "
         "Refresh rate - default 1 second\n"
         "-o [ --once ]                  "
         "Exit after one intervall\n"
         "-h [ --help ]                  "
         "This help text\n"
         "The msr driver must be loaded for this command to work\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: cpufreq-aperf [OPTIONS]

-c [ --cpu ] CPU               The CPU core to measure - default all cores
-i [ --intervall ] seconds     Refresh rate - default 1 second
-o [ --once ]                  Exit after one intervall
-h [ --help ]                  This help text
The msr driver must be loaded for this command to work


assistant: ```c
void usage(void) {
  printf("cpufreq-aperf [OPTIONS]\n\n"
         "-c [ --cpu ] CPU               "
         "The CPU core to measure - default all cores\n"
         "-i [ --intervall ] seconds     "
         "Refresh rate - default 1 second\n"
         "-o [ --once ]                  "
         "Exit after one intervall\n"
         "-h [ --help ]                  "
         "This help text\n"
         "The msr driver must be loaded for this command to work\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L96:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x20,-0x8(%rbp)
  je     L96
  cmpl   $0x9,-0x8(%rbp)
  je     L96
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L100
  cmpl   $0x2e,-0x8(%rbp)
  je     L100
  cmpl   $0x2d,-0x8(%rbp)
  je     L100
  mov    -0x8(%rbp),%eax
  jmp    L117
L100:
  cmpl   $0x2d,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L73
  cmpl   $0x2e,-0x4(%rbp)
  je     L73
  mov    -0x8(%rbp),%eax
  jmp    L117
L73:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L83
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L83
L48:
  addq   $0x1,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L83:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L48
  cmpl   $0x2e,-0x8(%rbp)
  jne    L87
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  jmp    L124
L9:
  addq   $0x1,-0x18(%rbp)
L124:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L9
L87:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L117:
  leave
  ret
```

assistant: ```c
int getop(char *s) {
  int c, next;
  while ((c = *s = getchar()) == ' ' || c == '\t')
    ;
  s++;
  *s = '\0';
  if (!isdigit(c) && c != '.' && c != '-') {
    return c;
  }
  if (c == '-') {
    next = getchar();
    if (!isdigit(next) && next != '.') {
      return c;
    } else {
      c = next;
    }
  } else {
    c = getchar();
  }
  while (isdigit(*s = c)) {
    s++;
    c = getchar();
  }
  if (c == '.') {
    *s = c;
    s++;
    while (isdigit(*s = c = getchar())) {
      s++;
    }
  }
  s++;
  *s = '\0';
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L135:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%r12d
  cmp    $0x9,%al
  je     L135
  cmp    $0x20,%r12d
  je     L135
  movb   $0x0,0x1(%rbp)
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L15
  mov    %r12d,%ebx
  sub    $0x2d,%ebx
  cmp    $0x1,%ebx
  ja     L70
L15:
  cmp    $0x2d,%r12d
  je     L41
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
L14:
  add    $0x1,%rbp
  jmp    L42
L41:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rax,%r13
  mov    %eax,%ebx
  movsbl %al,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r13d
  je     L14
  test   %rax,%rax
  jne    L14
  jmp    L70
L30:
  add    $0x1,%rbp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
L42:
  mov    %bl,0x0(%rbp)
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L30
  cmp    $0x2e,%ebx
  je     L29
L64:
  movb   $0x0,0x1(%rbp)
  mov    $0x1,%r12d
L70:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  movb   $0x2e,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L88
L51:
  add    $0x1,%rbp
L88:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
  jmp    L64
```

assistant: ```c
int getop(char *s) {
  int c, next;
  while ((c = *s = getchar()) == ' ' || c == '\t')
    ;
  s++;
  *s = '\0';
  if (!isdigit(c) && c != '.' && c != '-') {
    return c;
  }
  if (c == '-') {
    next = getchar();
    if (!isdigit(next) && next != '.') {
      return c;
    } else {
      c = next;
    }
  } else {
    c = getchar();
  }
  while (isdigit(*s = c)) {
    s++;
    c = getchar();
  }
  if (c == '.') {
    *s = c;
    s++;
    while (isdigit(*s = c = getchar())) {
      s++;
    }
  }
  s++;
  *s = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L51:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%r12d
  mov    %al,0x0(%rbp)
  cmp    $0x20,%r12d
  je     L51
  cmp    $0x9,%r12d
  je     L51
  movb   $0x0,0x1(%rbp)
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L85
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L96
L85:
  xor    %eax,%eax
  cmp    $0x2d,%r12d
  je     L28
  call   <getchar@plt>
  mov    %eax,%ebx
L7:
  add    $0x1,%rbp
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <getchar@plt>
  mov    %eax,%ebx
L93:
  mov    %bl,0x0(%rbp)
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L48
  cmp    $0x2e,%ebx
  je     L4
L25:
  movb   $0x0,0x1(%rbp)
  mov    $0x1,%r12d
L96:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movb   $0x2e,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L139
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rbp
L139:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L44
  jmp    L25
  nopl   (%rax)
L28:
  call   <getchar@plt>
  movsbl %al,%edi
  mov    %rax,%r13
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L7
  cmp    $0x2e,%r13d
  je     L7
  jmp    L96
```

assistant: ```c
int getop(char *s) {
  int c, next;
  while ((c = *s = getchar()) == ' ' || c == '\t')
    ;
  s++;
  *s = '\0';
  if (!isdigit(c) && c != '.' && c != '-') {
    return c;
  }
  if (c == '-') {
    next = getchar();
    if (!isdigit(next) && next != '.') {
      return c;
    } else {
      c = next;
    }
  } else {
    c = getchar();
  }
  while (isdigit(*s = c)) {
    s++;
    c = getchar();
  }
  if (c == '.') {
    *s = c;
    s++;
    while (isdigit(*s = c = getchar())) {
      s++;
    }
  }
  s++;
  *s = '\0';
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%r12d
  mov    %al,0x0(%rbp)
  cmp    $0x20,%r12d
  je     L16
  cmp    $0x9,%r12d
  je     L16
  movb   $0x0,0x1(%rbp)
  mov    %r12d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L115
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L109
L115:
  xor    %eax,%eax
  cmp    $0x2d,%r12d
  je     L136
  call   <getchar@plt>
  mov    %eax,%ebx
L96:
  add    $0x1,%rbp
  jmp    L135
  cs nopw 0x0(%rax,%rax,1)
L83:
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <getchar@plt>
  mov    %eax,%ebx
L135:
  mov    %bl,0x0(%rbp)
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L83
  cmp    $0x2e,%ebx
  je     L24
L31:
  movb   $0x0,0x1(%rbp)
  mov    $0x1,%r12d
L109:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  movb   $0x2e,0x0(%rbp)
  add    $0x1,%rbp
  jmp    L90
  nopw   0x0(%rax,%rax,1)
L108:
  add    $0x1,%rbp
L90:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %al,0x0(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L108
  jmp    L31
  nopl   (%rax)
L136:
  call   <getchar@plt>
  movsbl %al,%edi
  mov    %rax,%r13
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L96
  cmp    $0x2e,%r13d
  je     L96
  jmp    L109
```

assistant: ```c
int getop(char *s) {
  int c, next;
  while ((c = *s = getchar()) == ' ' || c == '\t')
    ;
  s++;
  *s = '\0';
  if (!isdigit(c) && c != '.' && c != '-') {
    return c;
  }
  if (c == '-') {
    next = getchar();
    if (!isdigit(next) && next != '.') {
      return c;
    } else {
      c = next;
    }
  } else {
    c = getchar();
  }
  while (isdigit(*s = c)) {
    s++;
    c = getchar();
  }
  if (c == '.') {
    *s = c;
    s++;
    while (isdigit(*s = c = getchar())) {
      s++;
    }
  }
  s++;
  *s = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L1:
  mov    $0x0,%eax
  call   <getc@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L1
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  leave
  ret
```

assistant: ```c
char get_key() {
  char key;
  while (1) {
    key = getc();
    if (isalpha(key))
      return toupper(key);
  }
}
```