ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<dirReduc>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %rdx,(%rsp)
  test   %esi,%esi
  je     L62
  xor    %r12d,%r12d
  lea    D3(%rip),%r14
  lea    D48(%rip),%r15
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L34:
  mov    0xc(%rsp),%eax
  add    $0x1,%r12d
  cmp    %eax,%r12d
  je     L62
L115:
  cmp    $0x1,%eax
  je     L62
  movslq %r12d,%rbx
  mov    %r14,%rsi
  shl    $0x3,%rbx
  lea    0x0(%r13,%rbx,1),%rbp
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L16
  mov    0x8(%r13,%rbx,1),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
L16:
  mov    0x0(%rbp),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L121
  mov    0x8(%r13,%rbx,1),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
L121:
  mov    0x0(%rbp),%rdi
  lea    D45(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  mov    0x8(%r13,%rbx,1),%rdi
  lea    D25(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
L8:
  mov    0x0(%rbp),%rdi
  lea    D25(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
  mov    0x8(%r13,%rbx,1),%rdi
  lea    D45(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L34
  xchg   %ax,%ax
L82:
  lea    0xc(%rsp),%rbp
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <deleteArrItem@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <deleteArrItem@plt>
  mov    0xc(%rsp),%eax
  xor    %r12d,%r12d
  cmp    %eax,%r12d
  jne    L115
L62:
  mov    (%rsp),%rcx
  mov    %eax,(%rcx)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D48
data_type: string
name: retrieve_data
arguments: tag: D45
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string

tool: D3: NORTH

tool: D48: SOUTH

tool: D45: WEST

tool: D25: EAST

assistant: ```c
char **dirReduc(char **arr, int sz, int *lg) {
  int i = 0;
  while (i != sz) {
    if (sz == 1)
      break;
    if ((strcmp(arr[i], "NORTH") == 0 && strcmp(arr[i + 1], "SOUTH") == 0) || (strcmp(arr[i], "SOUTH") == 0 && strcmp(arr[i + 1], "NORTH") == 0) || (strcmp(arr[i], "WEST") == 0 && strcmp(arr[i + 1], "EAST") == 0) || (strcmp(arr[i], "EAST") == 0 && strcmp(arr[i + 1], "WEST") == 0)) {
      deleteArrItem(arr, &sz, i);
      deleteArrItem(arr, &sz, i);
      i = 0;
      continue;
    }
    i++;
  }
  *lg = sz;
  return arr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dirReduc>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %rdx,(%rsp)
  test   %esi,%esi
  je     L107
  xor    %r12d,%r12d
  lea    D57(%rip),%r14
  lea    D13(%rip),%r15
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L64:
  mov    0xc(%rsp),%eax
  add    $0x1,%r12d
  cmp    %eax,%r12d
  je     L107
L105:
  cmp    $0x1,%eax
  je     L107
  movslq %r12d,%rbx
  mov    %r14,%rsi
  shl    $0x3,%rbx
  lea    0x0(%r13,%rbx,1),%rbp
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    0x8(%r13,%rbx,1),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L36
L22:
  mov    0x0(%rbp),%rdi
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L127
  mov    0x8(%r13,%rbx,1),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L36
L127:
  mov    0x0(%rbp),%rdi
  lea    D30(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
  mov    0x8(%r13,%rbx,1),%rdi
  lea    D34(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L36
L49:
  mov    0x0(%rbp),%rdi
  lea    D34(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    0x8(%r13,%rbx,1),%rdi
  lea    D30(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L64
  xchg   %ax,%ax
L36:
  lea    0xc(%rsp),%rbp
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <deleteArrItem@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <deleteArrItem@plt>
  mov    0xc(%rsp),%eax
  xor    %r12d,%r12d
  cmp    %eax,%r12d
  jne    L105
L107:
  mov    (%rsp),%rcx
  mov    %eax,(%rcx)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string

tool: D57: NORTH

tool: D13: SOUTH

tool: D30: WEST

tool: D34: EAST

assistant: ```c
char **dirReduc(char **arr, int sz, int *lg) {
  int i = 0;
  while (i != sz) {
    if (sz == 1)
      break;
    if ((strcmp(arr[i], "NORTH") == 0 && strcmp(arr[i + 1], "SOUTH") == 0) || (strcmp(arr[i], "SOUTH") == 0 && strcmp(arr[i + 1], "NORTH") == 0) || (strcmp(arr[i], "WEST") == 0 && strcmp(arr[i + 1], "EAST") == 0) || (strcmp(arr[i], "EAST") == 0 && strcmp(arr[i + 1], "WEST") == 0)) {
      deleteArrItem(arr, &sz, i);
      deleteArrItem(arr, &sz, i);
      i = 0;
      continue;
    }
    i++;
  }
  *lg = sz;
  return arr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CE_pHM_HCO3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D15(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D12(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x38(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm2
  addsd  -0x10(%rbp),%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D12
type_guessed: byte[8]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_HCO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O);
  return t0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CE_pHM_HCO3>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  movq   %xmm1,%rbx
  movq   %xmm3,%rbp
  movq   %xmm4,%r12
  movq   %xmm5,%r14
  movsd  D17(%rip),%xmm0
  subsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D15(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm6
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm6
  movsd  %xmm6,(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  movsd  (%rsp),%xmm6
  mulsd  %xmm6,%xmm0
  movq   %r12,%xmm7
  divsd  %xmm2,%xmm7
  subsd  %xmm7,%xmm0
  movapd %xmm6,%xmm1
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm1
  addsd  %xmm6,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D15
type_guessed: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_HCO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O);
  return t0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CE_pHM_HCO3>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm2
  movsd  D16(%rip),%xmm0
  movsd  %xmm1,0x28(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm5,(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D18(%rip),%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x4,%edi
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_guessed: byte[8]
name: read_data
arguments: data_tag: D18
type_guessed: byte[8]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_HCO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O);
  return t0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CE_pHM_HCO3>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm2
  movsd  D14(%rip),%xmm0
  movsd  %xmm1,0x28(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm5,(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D18(%rip),%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x4,%edi
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm0
  addsd  %xmm2,%xmm3
  subsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: byte[8]
name: read_data
arguments: data_label: D18
data_type: byte[8]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_HCO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O);
  return t0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L6:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ltrim(char *str) {
  int i = 0;
  while (isspace(str[i++]))
    ;
  strncpy(str, str + i - 1, strlen(str));
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
L9:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L9
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *str) {
  int i = 0;
  while (isspace(str[i++]))
    ;
  strncpy(str, str + i - 1, strlen(str));
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *str) {
  int i = 0;
  while (isspace(str[i++]))
    ;
  strncpy(str, str + i - 1, strlen(str));
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L9:
  movsbl (%rbx),%edi
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *str) {
  int i = 0;
  while (isspace(str[i++]))
    ;
  strncpy(str, str + i - 1, strlen(str));
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L18
L8:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
L16:
  nop
  leave
  ret
```

assistant: ```c
void skip_whitespace(const char **parsebuf) {
  while (**parsebuf && isspace(**parsebuf))
    (*parsebuf)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L2
L13:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L2
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L13
L2:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **parsebuf) {
  while (**parsebuf && isspace(**parsebuf))
    (*parsebuf)++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movsbl (%rax),%edi
  test   %dil,%dil
  jne    L0
  jmp    L12
  nopl   (%rax)
L35:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L12
L0:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
L12:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **parsebuf) {
  while (**parsebuf && isspace(**parsebuf))
    (*parsebuf)++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<skip_whitespace>:
  endbr64
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  movsbl (%rax),%edi
  test   %dil,%dil
  jne    L31
  jmp    L10
  nopl   (%rax)
L37:
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L10
L31:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L10:
  pop    %rbx
  ret
```

assistant: ```c
void skip_whitespace(const char **parsebuf) {
  while (**parsebuf && isspace(**parsebuf))
    (*parsebuf)++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_regexp>:
  endbr64
  push   %r12
  lea    D44(%rip),%rsi
  lea    D56(%rip),%r12
  push   %rbp
  lea    D82(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <tstre@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D127(%rip),%rsi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D170(%rip),%rsi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D119(%rip),%rsi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D121(%rip),%rsi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D61(%rip),%rsi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D120(%rip),%rsi
  call   <tstre@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <tstre@plt>
  mov    %r12,%rsi
  lea    D155(%rip),%rdi
  lea    D27(%rip),%r12
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D92(%rip),%rsi
  call   <tstre@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D105(%rip),%rbp
  call   <tstre@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <tstre@plt>
  lea    D45(%rip),%rsi
  lea    D131(%rip),%rdi
  call   <tstre@plt>
  mov    %rbp,%rdi
  lea    D29(%rip),%rsi
  call   <tstre@plt>
  add    $0x8,%rsp
  lea    D136(%rip),%rsi
  lea    D87(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <tstre@plt>
```

tool_calls: name: read_data
arguments: tag: D44
type_guessed: string
name: read_data
arguments: tag: D56
type_guessed: string
name: read_data
arguments: tag: D82
type_guessed: string
name: read_data
arguments: tag: D127
type_guessed: string
name: read_data
arguments: tag: D170
type_guessed: string
name: read_data
arguments: tag: D119
type_guessed: string
name: read_data
arguments: tag: D121
type_guessed: string
name: read_data
arguments: tag: D61
type_guessed: string
name: read_data
arguments: tag: D120
type_guessed: string
name: read_data
arguments: tag: D155
type_guessed: string
name: read_data
arguments: tag: D27
type_guessed: string
name: read_data
arguments: tag: D92
type_guessed: string
name: read_data
arguments: tag: D105
type_guessed: string
name: read_data
arguments: tag: D45
type_guessed: string
name: read_data
arguments: tag: D131
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D136
type_guessed: string
name: read_data
arguments: tag: D87
type_guessed: string

tool: D44: *

tool: D56: a*1?3

tool: D82: abc123

tool: D127: abc123*

tool: D170: aXc123

tool: D119: a?c123

tool: D121: abc*

tool: D61: *123

tool: D120: a*3

tool: D155: abc1X3

tool: D27: a*1?3*

tool: D92: a*1?4?

tool: D105: ab?123

tool: D45: ab\\123

tool: D131: ab\123

tool: D29: ab\?12*

tool: D136: st?sub*

tool: D87: st2sub1

assistant: ```c
void test_regexp(void) {
  tstre("abc123", "*");
  tstre("abc123", "abc123");
  tstre("abc123", "abc123*");
  tstre("abc123", "aXc123");
  tstre("abc123", "a?c123");
  tstre("abc123", "abc*");
  tstre("abc123", "*123");
  tstre("abc123", "a*3");
  tstre("abc123", "a*1?3");
  tstre("abc1X3", "a*1?3");
  tstre("abc123", "a*1?4?");
  tstre("abc123", "a*1?3*");
  tstre("ab?123", "a*1?3*");
  tstre("ab\\123", "ab\\\\123");
  tstre("ab?123", "ab\\?12*");
  tstre("st2sub1", "st?sub*");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L30
  je     L8
  lea    D46(%rip),%rbx
L12:
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,0x4(%rsp)
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jne    L12
L8:
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  lea    D46(%rip),%rbx
  cmp    $0xfffffff6,%esi
  jge    L40
L41:
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,0x4(%rsp)
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xfffffff6,%esi
  jl     L41
L40:
  mov    $0xa,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D42
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D46
type_infered: string
name: disassemble_data
arguments: data_tag: D53
type_infered: string

tool: D42: 
Enter an integer > 

tool: D10: %d

tool: D46: %d


tool: D53: That's all, have a nice day!

assistant: ```c
int main(void) {
  int value, digit;
  printf("\nEnter an integer > ");
  scanf("%d", &value);
  printf("\n");
  if (value >= 0) {
    while (value != 0) {
      digit = value % 10;
      value = value / 10;
      printf("%d\n", digit);
    }
  }
  if (value < 0) {
    while (value < -10) {
      digit = abs(value % 10);
      value = value / 10;
      printf("%d\n", digit);
    }
    digit = value % 10;
    printf("%d\n", digit);
  }
  printf("That's all, have a nice day!\n");
  return (0);
}
```