ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<DoNumTest>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf_s@plt>
  cmp    $0x1,%eax
  je     L15
  mov    %eax,%esi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <Fail@plt>
L15:
  mov    0x4(%rsp),%r8d
  cmp    %r13d,%r8d
  je     L6
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <Fail@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D15: ERROR: Expected sscanf_s to return 1, got %d.
Using "%s" in "%s".


tool: D7: ERROR: scanned number incorrectly from "%s" using "%s".
Expected %d, got %d.


assistant: ```c
void DoNumTest(char *inputstr, const char *formatstr, int checknum) {
  int num;
  int ret;
  ret = sscanf_s(inputstr, formatstr, &num);
  if (ret != 1) {
    Fail("ERROR: Expected sscanf_s to return 1, got %d.\n"
         "Using \"%s\" in \"%s\".\n",
         ret, inputstr, formatstr);
  }
  if (checknum != num) {
    Fail("ERROR: scanned number incorrectly from \"%s\" using \"%s\".\n"
         "Expected %d, got %d.\n",
         inputstr, formatstr, checknum, num);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L13
L8:
  mov    $0x0,%eax
  call   <doSth@plt>
L13:
  mov    $0x0,%eax
  call   <noerror@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  while (noerror()) {
    doSth();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L16
L10:
  mov    $0x0,%eax
  call   <doSth@plt>
L16:
  mov    $0x0,%eax
  call   <noerror@plt>
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  while (noerror()) {
    doSth();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <doSth@plt>
L12:
  xor    %eax,%eax
  call   <noerror@plt>
  test   %rax,%rax
  jne    L14
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  while (noerror()) {
    doSth();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <doSth@plt>
L10:
  xor    %eax,%eax
  call   <noerror@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  while (noerror()) {
    doSth();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L2:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy(char to[], char from[]) {
  int i;
  i = 0;
  while ((to[i] = from[i]) != '\n')
    ++i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  cmp    $0xa,%al
  je     L10
  mov    $0x1,%eax
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L4
L10:
  ret
```

assistant: ```c
void copy(char to[], char from[]) {
  int i;
  i = 0;
  while ((to[i] = from[i]) != '\n')
    ++i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  cmp    $0xa,%al
  je     L8
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L0
L8:
  ret
```

assistant: ```c
void copy(char to[], char from[]) {
  int i;
  i = 0;
  while ((to[i] = from[i]) != '\n')
    ++i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy>:
  endbr64
  movzbl (%rsi),%eax
  mov    %al,(%rdi)
  cmp    $0xa,%al
  je     L14
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%dl
  jne    L0
L14:
  ret
```

assistant: ```c
void copy(char to[], char from[]) {
  int i;
  i = 0;
  while ((to[i] = from[i]) != '\n')
    ++i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<extended_hwaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L57
  cmpq   $0x0,-0x20(%rbp)
  je     L57
  cmpl   $0x3,-0x14(%rbp)
  jle    L57
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  jmp    L8
L0:
  mov    -0x28(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  jmp    L8
L57:
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
L8:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *extended_hwaddr(int hwtype, int hwlen, unsigned char *hwaddr, int clid_len, unsigned char *clid, int *len_out) {
  if (hwlen == 0 && clid && clid_len > 3) {
    if (clid[0] == hwtype) {
      *len_out = clid_len - 1;
      return clid + 1;
    }
    *len_out = clid_len;
    return clid;
  }
  *len_out = hwlen;
  return hwaddr;
}
```
user: What is the c source code of the assembly code below:

```asm
<extended_hwaddr>:
  endbr64
  mov    %rdx,%rax
  test   %r8,%r8
  setne  %r10b
  cmp    $0x3,%ecx
  setg   %dl
  test   %dl,%r10b
  je     L13
  test   %esi,%esi
  je     L21
L13:
  mov    %esi,(%r9)
  ret
L21:
  movzbl (%r8),%edx
  mov    %ecx,%esi
  mov    %r8,%rax
  cmp    %edi,%edx
  jne    L13
  lea    -0x1(%rcx),%esi
  lea    0x1(%r8),%rax
  jmp    L13
```

assistant: ```c
unsigned char *extended_hwaddr(int hwtype, int hwlen, unsigned char *hwaddr, int clid_len, unsigned char *clid, int *len_out) {
  if (hwlen == 0 && clid && clid_len > 3) {
    if (clid[0] == hwtype) {
      *len_out = clid_len - 1;
      return clid + 1;
    }
    *len_out = clid_len;
    return clid;
  }
  *len_out = hwlen;
  return hwaddr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extended_hwaddr>:
  endbr64
  test   %r8,%r8
  mov    %rdx,%rax
  setne  %r10b
  cmp    $0x3,%ecx
  setg   %dl
  test   %dl,%r10b
  je     L0
  test   %esi,%esi
  je     L30
L0:
  mov    %esi,(%r9)
  ret
  nopl   0x0(%rax)
L30:
  movzbl (%r8),%edx
  mov    %ecx,%esi
  mov    %r8,%rax
  cmp    %edi,%edx
  jne    L0
  sub    $0x1,%esi
  add    $0x1,%rax
  jmp    L0
```

assistant: ```c
unsigned char *extended_hwaddr(int hwtype, int hwlen, unsigned char *hwaddr, int clid_len, unsigned char *clid, int *len_out) {
  if (hwlen == 0 && clid && clid_len > 3) {
    if (clid[0] == hwtype) {
      *len_out = clid_len - 1;
      return clid + 1;
    }
    *len_out = clid_len;
    return clid;
  }
  *len_out = hwlen;
  return hwaddr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<extended_hwaddr>:
  endbr64
  test   %r8,%r8
  mov    %rdx,%rax
  setne  %r10b
  cmp    $0x3,%ecx
  setg   %dl
  test   %dl,%r10b
  je     L22
  test   %esi,%esi
  je     L38
L22:
  mov    %esi,(%r9)
  ret
  nopl   0x0(%rax)
L38:
  movzbl (%r8),%edx
  mov    %ecx,%esi
  mov    %r8,%rax
  cmp    %edi,%edx
  jne    L22
  sub    $0x1,%esi
  add    $0x1,%rax
  jmp    L22
```

assistant: ```c
unsigned char *extended_hwaddr(int hwtype, int hwlen, unsigned char *hwaddr, int clid_len, unsigned char *clid, int *len_out) {
  if (hwlen == 0 && clid && clid_len > 3) {
    if (clid[0] == hwtype) {
      *len_out = clid_len - 1;
      return clid + 1;
    }
    *len_out = clid_len;
    return clid;
  }
  *len_out = hwlen;
  return hwaddr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<recursive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L53
  mov    $0x1,%eax
  jmp    L43
L53:
  cmpl   $0x270f,-0x14(%rbp)
  jg     L60
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L38
  mov    $0x0,%eax
  jmp    L43
L38:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L60:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L50:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jg     L50
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recursive>
L43:
  leave
  ret
```

assistant: ```c
bool recursive(int n, bool *used, const int *sq) {
  if (n == 1)
    return true;
  if (n < 10000) {
    if (used[n])
      return false;
    used[n] = true;
  }
  int sum = 0;
  while (n > 0) {
    sum += sq[n % 10];
    n /= 10;
  }
  return recursive(sum, used, sq);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<recursive>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L16
  mov    %edi,%ecx
  mov    %rsi,%r9
  mov    %rdx,%r8
  cmp    $0x270f,%edi
  jg     L5
  movslq %edi,%rax
  lea    (%rsi,%rax,4),%rdx
  mov    $0x0,%eax
  cmpl   $0x0,(%rdx)
  jne    L16
  movl   $0x1,(%rdx)
L5:
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L8
  mov    $0x0,%edi
L0:
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  movslq %edx,%rdx
  add    (%r8,%rdx,4),%edi
  mov    %ecx,%edx
  mov    %eax,%ecx
  cmp    $0x9,%edx
  jg     L0
L51:
  mov    %r8,%rdx
  mov    %r9,%rsi
  call   <recursive>
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%edi
  jmp    L51
L16:
  ret
```

assistant: ```c
bool recursive(int n, bool *used, const int *sq) {
  if (n == 1)
    return true;
  if (n < 10000) {
    if (used[n])
      return false;
    used[n] = true;
  }
  int sum = 0;
  while (n > 0) {
    sum += sq[n % 10];
    n /= 10;
  }
  return recursive(sum, used, sq);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<recursive>:
  endbr64
  mov    %rsi,%r10
  mov    %rdx,%r8
  mov    $0xcccccccd,%r9d
  cmp    $0x1,%edi
  je     L47
  nopl   (%rax)
L37:
  cmp    $0x270f,%edi
  jle    L15
L64:
  mov    %edi,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L26:
  mov    %edx,%eax
  mov    %edx,%ecx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  movslq %ecx,%rcx
  add    (%r8,%rcx,4),%edi
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L26
  cmp    $0x1,%edi
  jne    L37
L47:
  mov    $0x1,%r11d
  mov    %r11d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %edi,%rax
  lea    (%r10,%rax,4),%rax
  mov    (%rax),%r11d
  test   %r11d,%r11d
  jne    L3
  movl   $0x1,(%rax)
  test   %edi,%edi
  jg     L64
  mov    (%r10),%eax
  test   %eax,%eax
  jne    L45
  movl   $0x1,(%r10)
L45:
  mov    %r11d,%eax
  ret
L3:
  xor    %r11d,%r11d
  mov    %r11d,%eax
  ret
```

assistant: ```c
bool recursive(int n, bool *used, const int *sq) {
  if (n == 1)
    return true;
  if (n < 10000) {
    if (used[n])
      return false;
    used[n] = true;
  }
  int sum = 0;
  while (n > 0) {
    sum += sq[n % 10];
    n /= 10;
  }
  return recursive(sum, used, sq);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<recursive>:
  endbr64
  mov    %rsi,%r10
  mov    %rdx,%r8
  mov    $0xcccccccd,%r9d
  cmp    $0x1,%edi
  je     L15
  nopl   (%rax)
L61:
  cmp    $0x270f,%edi
  jle    L33
L40:
  mov    %edi,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L31:
  mov    %edx,%eax
  mov    %edx,%ecx
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  movslq %ecx,%rcx
  add    (%r8,%rcx,4),%edi
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L31
  cmp    $0x1,%edi
  jne    L61
L15:
  mov    $0x1,%r11d
  mov    %r11d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  movslq %edi,%rax
  lea    (%r10,%rax,4),%rax
  mov    (%rax),%r11d
  test   %r11d,%r11d
  jne    L64
  movl   $0x1,(%rax)
  test   %edi,%edi
  jg     L40
  mov    (%r10),%eax
  test   %eax,%eax
  jne    L36
  movl   $0x1,(%r10)
L36:
  mov    %r11d,%eax
  ret
L64:
  xor    %r11d,%r11d
  mov    %r11d,%eax
  ret
```

assistant: ```c
bool recursive(int n, bool *used, const int *sq) {
  if (n == 1)
    return true;
  if (n < 10000) {
    if (used[n])
      return false;
    used[n] = true;
  }
  int sum = 0;
  while (n > 0) {
    sum += sq[n % 10];
    n /= 10;
  }
  return recursive(sum, used, sq);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <timer_init@plt>
  mov    $0x0,%eax
  call   <roulette_init@plt>
  mov    $0x64,%edi
  call   <roulette_set_delay@plt>
  mov    $0x1c200,%edi
  call   <serial_set_baudrate@plt>
  mov    $0x0,%eax
  call   <serial_init@plt>
L7:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  lea    -0x110(%rbp),%rcx
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x118(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <roulette_update@plt>
  mov    $0xa,%edi
  call   <timer_wait_ms@plt>
  jmp    L7
```

assistant: ```c
int main() {
  timer_init();
  roulette_init();
  roulette_set_delay(100);
  serial_set_baudrate(115200);
  serial_init();
  char buf[256];
  while (true) {
    size_t n = read(STDIN_FILENO, buf, 256);
    write(STDOUT_FILENO, buf, n);
    roulette_update();
    timer_wait_ms(10);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <timer_init@plt>
  mov    $0x0,%eax
  call   <roulette_init@plt>
  mov    $0x64,%edi
  call   <roulette_set_delay@plt>
  mov    $0x1c200,%edi
  call   <serial_set_baudrate@plt>
  mov    $0x0,%eax
  call   <serial_init@plt>
  mov    %rsp,%rbx
L3:
  mov    $0x100,%edx
  mov    %rbx,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <read@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
  mov    $0x0,%eax
  call   <roulette_update@plt>
  mov    $0xa,%edi
  call   <timer_wait_ms@plt>
  jmp    L3
```

assistant: ```c
int main() {
  timer_init();
  roulette_init();
  roulette_set_delay(100);
  serial_set_baudrate(115200);
  serial_init();
  char buf[256];
  while (true) {
    size_t n = read(STDIN_FILENO, buf, 256);
    write(STDOUT_FILENO, buf, n);
    roulette_update();
    timer_wait_ms(10);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <timer_init@plt>
  xor    %eax,%eax
  call   <roulette_init@plt>
  mov    $0x64,%edi
  call   <roulette_set_delay@plt>
  mov    $0x1c200,%edi
  call   <serial_set_baudrate@plt>
  xor    %eax,%eax
  call   <serial_init@plt>
  mov    D6(%rip),%r12
  mov    D15(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%r12),%edi
  mov    %rbx,%rsi
  mov    $0x100,%edx
  call   <read@plt>
  mov    0x0(%rbp),%edi
  mov    %rbx,%rsi
  mov    %rax,%rdx
  call   <write@plt>
  xor    %eax,%eax
  call   <roulette_update@plt>
  mov    $0xa,%edi
  call   <timer_wait_ms@plt>
  jmp    L5
```

assistant: ```c
int main() {
  timer_init();
  roulette_init();
  roulette_set_delay(100);
  serial_set_baudrate(115200);
  serial_init();
  char buf[256];
  while (true) {
    size_t n = read(STDIN_FILENO, buf, 256);
    write(STDOUT_FILENO, buf, n);
    roulette_update();
    timer_wait_ms(10);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <timer_init@plt>
  xor    %eax,%eax
  call   <roulette_init@plt>
  mov    $0x64,%edi
  call   <roulette_set_delay@plt>
  mov    $0x1c200,%edi
  call   <serial_set_baudrate@plt>
  xor    %eax,%eax
  call   <serial_init@plt>
  mov    D5(%rip),%r12
  mov    D16(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%r12),%edi
  mov    %rbx,%rsi
  mov    $0x100,%edx
  call   <read@plt>
  mov    0x0(%rbp),%edi
  mov    %rbx,%rsi
  mov    %rax,%rdx
  call   <write@plt>
  xor    %eax,%eax
  call   <roulette_update@plt>
  mov    $0xa,%edi
  call   <timer_wait_ms@plt>
  jmp    L6
```

assistant: ```c
int main() {
  timer_init();
  roulette_init();
  roulette_set_delay(100);
  serial_set_baudrate(115200);
  serial_init();
  char buf[256];
  while (true) {
    size_t n = read(STDIN_FILENO, buf, 256);
    write(STDOUT_FILENO, buf, n);
    roulette_update();
    timer_wait_ms(10);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BootConfigRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int BootConfigRead(void) {
  int rc;
  rc = 0;
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<BootConfigRead>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int BootConfigRead(void) {
  int rc;
  rc = 0;
  return rc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BootConfigRead>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int BootConfigRead(void) {
  int rc;
  rc = 0;
  return rc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BootConfigRead>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int BootConfigRead(void) {
  int rc;
  rc = 0;
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<checkCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L46
L52:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <runIn@plt>
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L55
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <runOut@plt>
L55:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
  addl   $0x1,-0x4(%rbp)
L26:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L52
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <runCommand@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D29
datatype: string

tool: D5: <

tool: D7: >

tool: D29: |

assistant: ```c
void checkCommand(char *command, char **args) {
  int i = 0;
  int check = 0;
  while (args[i] != NULL) {
    if (strcmp(args[i], "<") == 0) {
      check++;
      runIn(command, args, i);
    }
    if (strcmp(args[i], ">") == 0) {
      check++;
      runOut(command, args, i);
    }
    if (strcmp(args[i], "|") == 0) {
      check++;
    }
    i++;
  }
  if (check == 0) {
    runCommand(command, args);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checkCommand>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L79
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D12(%rip),%r15
  lea    D18(%rip),%r14
  lea    D22(%rip),%r13
  jmp    L76
L80:
  add    $0x1,%r12d
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <runIn@plt>
  jmp    L5
L28:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L39
L76:
  mov    %ebx,0x4(%rsp)
  mov    %r15,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L80
L5:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L28
  add    $0x1,%r12d
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <runOut@plt>
  jmp    L28
L39:
  test   %r12d,%r12d
  je     L79
L71:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    %rbp,%rsi
  mov    0x8(%rsp),%rdi
  call   <runCommand@plt>
  jmp    L71
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type_guessed: string
name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string

tool: D12: <

tool: D18: >

tool: D22: |

assistant: ```c
void checkCommand(char *command, char **args) {
  int i = 0;
  int check = 0;
  while (args[i] != NULL) {
    if (strcmp(args[i], "<") == 0) {
      check++;
      runIn(command, args, i);
    }
    if (strcmp(args[i], ">") == 0) {
      check++;
      runOut(command, args, i);
    }
    if (strcmp(args[i], "|") == 0) {
      check++;
    }
    i++;
  }
  if (check == 0) {
    runCommand(command, args);
  }
}
```