ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L5
  push   %rbp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <cantidadcl_alloc@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  mov    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *nombre = NULL;
  const int debug = 0;
  if (argc < 2)
    return 1;
  nombre = cantidadcl_alloc(argv[1], debug);
  printf("%s\n", nombre);
  free(nombre);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L9
  push   %rbp
  mov    0x8(%rsi),%rdi
  xor    %esi,%esi
  call   <cantidadcl_alloc@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  mov    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char *nombre = NULL;
  const int debug = 0;
  if (argc < 2)
    return 1;
  nombre = cantidadcl_alloc(argv[1], debug);
  printf("%s\n", nombre);
  free(nombre);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<e_adc_absx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <e_absx@plt>
  mov    $0x0,%eax
  call   <e_adc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void e_adc_absx() {
  e_absx();
  e_adc();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<e_adc_absx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <e_absx@plt>
  mov    $0x0,%eax
  call   <e_adc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void e_adc_absx() {
  e_absx();
  e_adc();
}
```
user: What is the c source code of the assembly code below:

```asm
<e_adc_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_absx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e_adc@plt>
```

assistant: ```c
void e_adc_absx() {
  e_absx();
  e_adc();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<e_adc_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <e_absx@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <e_adc@plt>
```

assistant: ```c
void e_adc_absx() {
  e_absx();
  e_adc();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cal_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  lea    -0x40(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ext_arg@plt>
  mov    %rax,-0x58(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x50(%rbp)
  lea    -0x40(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ext_arg@plt>
  mov    %rax,-0x58(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x48(%rbp)
  movsd  -0x48(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double cal_pow(char *S) {
  char *tmp = S;
  char arg[50];
  double arg1 = 0, arg2 = 0;
  tmp = ext_arg(tmp, arg);
  arg1 = (atof(arg));
  tmp = ext_arg(tmp, arg);
  arg2 = (atof(arg));
  return pow(arg1, arg2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cal_pow>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <ext_arg@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <atof@plt>
  movq   %xmm0,%rbp
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <ext_arg@plt>
  mov    %rbx,%rdi
  call   <atof@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  call   <pow@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double cal_pow(char *S) {
  char *tmp = S;
  char arg[50];
  double arg1 = 0, arg2 = 0;
  tmp = ext_arg(tmp, arg);
  arg1 = (atof(arg));
  tmp = ext_arg(tmp, arg);
  arg2 = (atof(arg));
  return pow(arg1, arg2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cal_pow>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  call   <ext_arg@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <ext_arg@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  pop    %rbp
  pop    %r12
  jmp    10b0 <pow@plt>
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double cal_pow(char *S) {
  char *tmp = S;
  char arg[50];
  double arg1 = 0, arg2 = 0;
  tmp = ext_arg(tmp, arg);
  arg1 = (atof(arg));
  tmp = ext_arg(tmp, arg);
  arg2 = (atof(arg));
  return pow(arg1, arg2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cal_pow>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  call   <ext_arg@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <atof@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <ext_arg@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movsd  0x8(%rsp),%xmm2
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  pop    %rbp
  pop    %r12
  jmp    10b0 <pow@plt>
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double cal_pow(char *S) {
  char *tmp = S;
  char arg[50];
  double arg1 = 0, arg2 = 0;
  tmp = ext_arg(tmp, arg);
  arg1 = (atof(arg));
  tmp = ext_arg(tmp, arg);
  arg2 = (atof(arg));
  return pow(arg1, arg2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<setmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x7f,-0xc(%rbp)
  jmp    L30
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%ecx
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <setb@plt>
  subl   $0x1,-0xc(%rbp)
L30:
  mov    $0x80,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jbe    L15
L0:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L40
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1f,-0xc(%rbp)
  jmp    L57
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <setb@plt>
  subl   $0x1,-0xc(%rbp)
L57:
  mov    $0x20,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jbe    L14
L40:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int setmask(int af, u_char *adrspace, unsigned b) {
  int i;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  if (af == AF_INET6) {
    adu.in6 = (struct in6_addr *)adrspace;
    for (i = 128 - 1; i >= (128 - b); i--)
      setb((u_char *)&adu.in6->__in6_u.__u6_addr8[0], i, 1);
  }
  if (af == AF_INET) {
    adu.in = (struct in_addr *)adrspace;
    for (i = 32 - 1; i >= (32 - b); i--)
      setb((u_char *)&adu.in->s_addr, i, 1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setmask>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    D9(%rip),%rax
  cmp    %edi,(%rax)
  je     L15
L67:
  mov    D4(%rip),%rax
  cmp    %r12d,(%rax)
  je     L16
L51:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0x80,%r14d
  sub    %edx,%r14d
  cmp    $0x7f,%r14d
  ja     L67
  mov    $0x7f,%ebx
L48:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    0x0(%rbp),%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  cmp    %r14d,%ebx
  jae    L48
  jmp    L67
L16:
  mov    $0x20,%r12d
  sub    %r13d,%r12d
  cmp    $0x1f,%r12d
  ja     L51
  mov    $0x1f,%ebx
L10:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <setb@plt>
  sub    $0x1,%ebx
  cmp    %r12d,%ebx
  jae    L10
  jmp    L51
```

assistant: ```c
int setmask(int af, u_char *adrspace, unsigned b) {
  int i;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  if (af == AF_INET6) {
    adu.in6 = (struct in6_addr *)adrspace;
    for (i = 128 - 1; i >= (128 - b); i--)
      setb((u_char *)&adu.in6->__in6_u.__u6_addr8[0], i, 1);
  }
  if (af == AF_INET) {
    adu.in = (struct in_addr *)adrspace;
    for (i = 32 - 1; i >= (32 - b); i--)
      setb((u_char *)&adu.in->s_addr, i, 1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setmask>:
  endbr64
  mov    D15(%rip),%rax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmp    %edi,(%rax)
  je     L45
L44:
  mov    D26(%rip),%rax
  cmp    %r12d,(%rax)
  je     L37
L0:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    $0x80,%r14d
  sub    %edx,%r14d
  cmp    $0x7f,%r14d
  ja     L44
  mov    $0x7f,%ebx
  nopl   0x0(%rax)
L49:
  mov    0x0(%rbp),%rdi
  mov    %ebx,%esi
  mov    $0x1,%edx
  sub    $0x1,%ebx
  call   <setb@plt>
  cmp    %r14d,%ebx
  jae    L49
  mov    D26(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L0
L37:
  mov    $0x20,%r12d
  sub    %r13d,%r12d
  cmp    $0x1f,%r12d
  ja     L0
  mov    $0x1f,%ebx
L12:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <setb@plt>
  cmp    %r12d,%ebx
  jae    L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int setmask(int af, u_char *adrspace, unsigned b) {
  int i;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  if (af == AF_INET6) {
    adu.in6 = (struct in6_addr *)adrspace;
    for (i = 128 - 1; i >= (128 - b); i--)
      setb((u_char *)&adu.in6->__in6_u.__u6_addr8[0], i, 1);
  }
  if (af == AF_INET) {
    adu.in = (struct in_addr *)adrspace;
    for (i = 32 - 1; i >= (32 - b); i--)
      setb((u_char *)&adu.in->s_addr, i, 1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setmask>:
  endbr64
  mov    D18(%rip),%rax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmp    %edi,(%rax)
  je     L37
L25:
  mov    D17(%rip),%rax
  cmp    %r12d,(%rax)
  je     L32
L55:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    $0x80,%r14d
  sub    %edx,%r14d
  cmp    $0x7f,%r14d
  ja     L25
  mov    $0x7f,%ebx
  nopl   0x0(%rax)
L3:
  mov    0x0(%rbp),%rdi
  mov    %ebx,%esi
  mov    $0x1,%edx
  sub    $0x1,%ebx
  call   <setb@plt>
  cmp    %r14d,%ebx
  jae    L3
  mov    D17(%rip),%rax
  cmp    %r12d,(%rax)
  jne    L55
L32:
  mov    $0x20,%r12d
  sub    %r13d,%r12d
  cmp    $0x1f,%r12d
  ja     L55
  mov    $0x1f,%ebx
L40:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <setb@plt>
  cmp    %r12d,%ebx
  jae    L40
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int setmask(int af, u_char *adrspace, unsigned b) {
  int i;
  union {
    struct in6_addr *in6;
    struct in_addr *in;
  } adu;
  if (af == AF_INET6) {
    adu.in6 = (struct in6_addr *)adrspace;
    for (i = 128 - 1; i >= (128 - b); i--)
      setb((u_char *)&adu.in6->__in6_u.__u6_addr8[0], i, 1);
  }
  if (af == AF_INET) {
    adu.in = (struct in_addr *)adrspace;
    for (i = 32 - 1; i >= (32 - b); i--)
      setb((u_char *)&adu.in->s_addr, i, 1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<execute_rudder_action>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <calc_rudder_gain@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L77
  cmpl   $0x0,-0x1c(%rbp)
  jne    L40
  mov    $0x0,%eax
  call   <rudder_center@plt>
L40:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L54
  mov    $0x0,%eax
  call   <rudder_center@plt>
L54:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L77
  mov    $0x0,%eax
  call   <rudder_center@plt>
L77:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L102
  cmpl   $0x0,-0x1c(%rbp)
  jne    L100
  mov    $0x0,%eax
  call   <rudder_right@plt>
L100:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L66
  mov    $0x0,%eax
  call   <rudder_center@plt>
L66:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L102
  mov    $0x0,%eax
  call   <rudder_right@plt>
L102:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L9
  cmpl   $0x0,-0x1c(%rbp)
  jne    L70
  mov    $0x0,%eax
  call   <rudder_left@plt>
L70:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L83
  mov    $0x0,%eax
  call   <rudder_left@plt>
L83:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L9
  mov    $0x0,%eax
  call   <rudder_center@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void execute_rudder_action(int course, int heading, int rudder) {
  int coursediff = course - heading;
  int gain = calc_rudder_gain(coursediff);
  if (heading == course) {
    if (rudder == 0) {
      rudder_center();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
  if (heading < course) {
    if (rudder == 0) {
      rudder_right();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_right();
    }
  }
  if (heading > course) {
    if (rudder == 0) {
      rudder_left();
    }
    if (rudder > 0) {
      rudder_left();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execute_rudder_action>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  sub    %esi,%edi
  call   <calc_rudder_gain@plt>
  cmp    %ebx,%ebp
  je     L143
  jle    L103
  test   %r12d,%r12d
  je     L71
  jle    L88
  mov    $0x0,%eax
  call   <rudder_center@plt>
L84:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L143:
  test   %r12d,%r12d
  je     L167
  jle    L33
  mov    $0x0,%eax
  call   <rudder_center@plt>
  jmp    L84
L167:
  mov    $0x0,%eax
  call   <rudder_center@plt>
  jmp    L84
L33:
  jns    L84
  mov    $0x0,%eax
  call   <rudder_center@plt>
  jmp    L84
L71:
  mov    $0x0,%eax
  call   <rudder_right@plt>
  jmp    L84
L88:
  jns    L84
  mov    $0x0,%eax
  call   <rudder_right@plt>
  jmp    L84
L103:
  jge    L84
  test   %r12d,%r12d
  je     L8
  jle    L38
  mov    $0x0,%eax
  call   <rudder_left@plt>
  jmp    L84
L8:
  mov    $0x0,%eax
  call   <rudder_left@plt>
  jmp    L84
L38:
  jns    L84
  mov    $0x0,%eax
  call   <rudder_center@plt>
  jmp    L84
```

assistant: ```c
void execute_rudder_action(int course, int heading, int rudder) {
  int coursediff = course - heading;
  int gain = calc_rudder_gain(coursediff);
  if (heading == course) {
    if (rudder == 0) {
      rudder_center();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
  if (heading < course) {
    if (rudder == 0) {
      rudder_right();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_right();
    }
  }
  if (heading > course) {
    if (rudder == 0) {
      rudder_left();
    }
    if (rudder > 0) {
      rudder_left();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<execute_rudder_action>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <calc_rudder_gain@plt>
  cmp    %ebx,%ebp
  je     L39
  jle    L10
  test   %r12d,%r12d
  je     L30
  jle    L30
L39:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10a0 <rudder_center@plt>
  xchg   %ax,%ax
L10:
  jge    L49
  test   %r12d,%r12d
  js     L39
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <rudder_left@plt>
  nopw   0x0(%rax,%rax,1)
L30:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10b0 <rudder_right@plt>
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void execute_rudder_action(int course, int heading, int rudder) {
  int coursediff = course - heading;
  int gain = calc_rudder_gain(coursediff);
  if (heading == course) {
    if (rudder == 0) {
      rudder_center();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
  if (heading < course) {
    if (rudder == 0) {
      rudder_right();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_right();
    }
  }
  if (heading > course) {
    if (rudder == 0) {
      rudder_left();
    }
    if (rudder > 0) {
      rudder_left();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<execute_rudder_action>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <calc_rudder_gain@plt>
  cmp    %ebx,%ebp
  je     L26
  jle    L27
  test   %r12d,%r12d
  je     L33
  jle    L33
L26:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10a0 <rudder_center@plt>
  xchg   %ax,%ax
L27:
  jge    L34
  test   %r12d,%r12d
  js     L26
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <rudder_left@plt>
  nopw   0x0(%rax,%rax,1)
L33:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10b0 <rudder_right@plt>
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void execute_rudder_action(int course, int heading, int rudder) {
  int coursediff = course - heading;
  int gain = calc_rudder_gain(coursediff);
  if (heading == course) {
    if (rudder == 0) {
      rudder_center();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
  if (heading < course) {
    if (rudder == 0) {
      rudder_right();
    }
    if (rudder > 0) {
      rudder_center();
    }
    if (rudder < 0) {
      rudder_right();
    }
  }
  if (heading > course) {
    if (rudder == 0) {
      rudder_left();
    }
    if (rudder > 0) {
      rudder_left();
    }
    if (rudder < 0) {
      rudder_center();
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<yskiplist_gen_height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L14:
  addl   $0x1,-0x4(%rbp)
  sarl   -0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int yskiplist_gen_height(void) {
  int r = (random());
  int h = 1;
  for (; r & 1; r >>= 1)
    h++;
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<yskiplist_gen_height>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%edx
  and    $0x1,%edx
  je     L12
L15:
  add    $0x1,%edx
  sar    %eax
  test   $0x1,%al
  jne    L15
L11:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L12:
  mov    $0x1,%edx
  jmp    L11
```

assistant: ```c
int yskiplist_gen_height(void) {
  int r = (random());
  int h = 1;
  for (; r & 1; r >>= 1)
    h++;
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yskiplist_gen_height>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  mov    %eax,%r8d
  and    $0x1,%r8d
  je     L2
  nopl   0x0(%rax,%rax,1)
L11:
  sar    %eax
  add    $0x1,%r8d
  test   $0x1,%al
  jne    L11
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int yskiplist_gen_height(void) {
  int r = (random());
  int h = 1;
  for (; r & 1; r >>= 1)
    h++;
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yskiplist_gen_height>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  mov    %eax,%r8d
  and    $0x1,%r8d
  je     L12
  nopl   0x0(%rax,%rax,1)
L5:
  sar    %eax
  add    $0x1,%r8d
  test   $0x1,%al
  jne    L5
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%r8d
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int yskiplist_gen_height(void) {
  int r = (random());
  int h = 1;
  for (; r & 1; r >>= 1)
    h++;
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isM3U>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
L11:
  mov    $0x1,%eax
  jmp    L1
L21:
  mov    $0x0,%eax
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string

tool: D12: m3u

tool: D10: m3u8

assistant: ```c
char isM3U(char *filename1) {
  if (((strcmp((char *)filename1 + strlen(filename1) - 3, "m3u") == 0) || (strcmp((char *)filename1 + strlen(filename1) - 4, "m3u8") == 0))) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isM3U>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x3(%rbx,%rax,1),%rdi
  lea    D15(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L13
L9:
  pop    %rbx
  ret
L13:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x4(%rbx,%rax,1),%rdi
  lea    D17(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string

tool: D15: m3u

tool: D17: m3u8

assistant: ```c
char isM3U(char *filename1) {
  if (((strcmp((char *)filename1 + strlen(filename1) - 3, "m3u") == 0) || (strcmp((char *)filename1 + strlen(filename1) - 4, "m3u8") == 0))) {
    return 1;
  } else {
    return 0;
  }
}
```