ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L2
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  mov    %rsp,%r12
  lea    0x10(%rsi,%rax,8),%r13
  lea    D0(%rip),%rbp
  lea    D10(%rip),%r14
  jmp    L38
  nopl   0x0(%rax)
L47:
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L2
L38:
  mov    (%rbx),%rdi
  mov    %r12,%rsi
  call   <shell_exec@plt>
  test   %eax,%eax
  je     L47
  mov    %r14,%rdi
  call   <perror@plt>
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D0: return:
%s

tool: D10: shell_exec failed.

assistant: ```c
int main(int args, char *argv[]) {
  char *c;
  int i = 1;
  for (; i < args; ++i) {
    int rc = shell_exec(argv[i], &c);
    if (rc != 0) {
      perror("shell_exec failed.");
    }
    printf("return:\n%s", c);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L1
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  mov    %rsp,%rbp
  lea    0x10(%rsi,%rax,8),%r13
  lea    D13(%rip),%r12
  lea    D1(%rip),%r14
  jmp    L37
  nopl   0x0(%rax)
L51:
  mov    (%rsp),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  je     L1
L37:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <shell_exec@plt>
  test   %eax,%eax
  je     L51
  mov    %r14,%rdi
  call   <perror@plt>
  jmp    L51
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D13: return:
%s

tool: D1: shell_exec failed.

assistant: ```c
int main(int args, char *argv[]) {
  char *c;
  int i = 1;
  for (; i < args; ++i) {
    int rc = shell_exec(argv[i], &c);
    if (rc != 0) {
      perror("shell_exec failed.");
    }
    printf("return:\n%s", c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<leading_zero_num3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0xc(%rbp)
  movl   $0x10,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L12:
  shrl   -0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int leading_zero_num3(unsigned int x) {
  unsigned int y;
  unsigned int nr, c;
  nr = 32;
  c = 16;
  do {
    y = x >> c;
    if (y) {
      nr -= c;
      x = y;
    }
    c >>= 1;
  } while (c);
  return nr - x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<leading_zero_num3>:
  endbr64
  mov    $0x5,%edx
  mov    $0x10,%ecx
  mov    $0x20,%eax
  jmp    L31
L10:
  sub    %ecx,%eax
  mov    %esi,%edi
L11:
  shr    %ecx
  sub    $0x1,%edx
  je     L33
L31:
  mov    %edi,%esi
  shr    %cl,%esi
  test   %esi,%esi
  je     L11
  jmp    L10
L33:
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int leading_zero_num3(unsigned int x) {
  unsigned int y;
  unsigned int nr, c;
  nr = 32;
  c = 16;
  do {
    y = x >> c;
    if (y) {
      nr -= c;
      x = y;
    }
    c >>= 1;
  } while (c);
  return nr - x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<leading_zero_num3>:
  endbr64
  mov    $0x5,%edx
  mov    $0x10,%ecx
  mov    $0x20,%eax
L15:
  mov    %edi,%esi
  shr    %cl,%esi
  test   %esi,%esi
  je     L5
  sub    %ecx,%eax
  mov    %esi,%edi
L5:
  shr    %ecx
  sub    $0x1,%edx
  jne    L15
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int leading_zero_num3(unsigned int x) {
  unsigned int y;
  unsigned int nr, c;
  nr = 32;
  c = 16;
  do {
    y = x >> c;
    if (y) {
      nr -= c;
      x = y;
    }
    c >>= 1;
  } while (c);
  return nr - x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leading_zero_num3>:
  endbr64
  mov    %edi,%eax
  shr    $0x10,%eax
  cmovne %eax,%edi
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x10,%eax
  mov    %edi,%edx
  add    $0x10,%eax
  shr    $0x8,%edx
  je     L4
  sub    $0x8,%eax
  mov    %edx,%edi
L4:
  mov    %edi,%edx
  shr    $0x4,%edx
  je     L3
  sub    $0x4,%eax
  mov    %edx,%edi
L3:
  mov    %edi,%edx
  shr    $0x2,%edx
  je     L37
  sub    $0x2,%eax
  mov    %edx,%edi
L37:
  mov    %edi,%edx
  shr    %edx
  je     L15
  sub    $0x1,%eax
  mov    %edx,%edi
L15:
  sub    %edi,%eax
  ret
```

assistant: ```c
unsigned int leading_zero_num3(unsigned int x) {
  unsigned int y;
  unsigned int nr, c;
  nr = 32;
  c = 16;
  do {
    y = x >> c;
    if (y) {
      nr -= c;
      x = y;
    }
    c >>= 1;
  } while (c);
  return nr - x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double Mean(double *vector, int nVals) {
  int n;
  double sum = 0.0;
  for (n = 0; n < nVals; n++)
    sum += vector[n];
  return sum / nVals;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Mean>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L23:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L23
L14:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L9:
  pxor   %xmm0,%xmm0
  jmp    L14
```

assistant: ```c
double Mean(double *vector, int nVals) {
  int n;
  double sum = 0.0;
  for (n = 0; n < nVals; n++)
    sum += vector[n];
  return sum / nVals;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Mean>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L1:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L1
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double Mean(double *vector, int nVals) {
  int n;
  double sum = 0.0;
  for (n = 0; n < nVals; n++)
    sum += vector[n];
  return sum / nVals;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Mean>:
  endbr64
  test   %esi,%esi
  jle    L10
  cmp    $0x1,%esi
  je     L8
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L44:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L44
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L39
L31:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
L39:
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L10:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L31
```

assistant: ```c
double Mean(double *vector, int nVals) {
  int n;
  double sum = 0.0;
  for (n = 0; n < nVals; n++)
    sum += vector[n];
  return sum / nVals;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L56:
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L22:
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L49:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %ecx,%edx
  mov    $0xaf286bcb,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L35
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    $0xaf286bcb,%edx
  imul   %rcx,%rdx
  shr    $0x20,%rdx
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  cmp    %eax,-0x14(%rbp)
  jae    L49
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  cmp    %eax,-0x14(%rbp)
  jae    L22
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  cmp    %eax,-0x14(%rbp)
  jae    L56
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: [%d, %d, %d, %d]


assistant: ```c
void print_sum(unsigned int degree) {
  unsigned int a1, a2, a3;
  for (a1 = 0; (8 * a1 <= degree); a1++) {
    for (a2 = 0; (8 * a1 + 7 * a2 <= degree); a2++) {
      for (a3 = 0; (8 * a1 + 7 * a2 + 15 * a3 <= degree); a3++) {
        if ((degree - (a1 * 8 + a2 * 7 + a3 * 15)) % 19 == 0) {
          printf("[%d, %d, %d, %d]\n", a1, a2, a3, (degree - (a1 * 8 + a2 * 7 + a3 * 15)) / 19);
        }
      }
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_sum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  movl   $0x0,0x8(%rsp)
  mov    $0xaf286bcb,%r13d
  jmp    L86
L26:
  add    $0x1,%ebp
  add    $0xf,%ebx
  cmp    %r12d,%ebx
  ja     L27
L48:
  mov    %r12d,%r8d
  sub    %ebx,%r8d
  mov    %r8d,%edx
  imul   %r13,%rdx
  shr    $0x20,%rdx
  mov    %r8d,%eax
  sub    %edx,%eax
  shr    %eax
  add    %edx,%eax
  shr    $0x4,%eax
  lea    (%rax,%rax,8),%edx
  lea    (%rax,%rdx,2),%eax
  cmp    %eax,%r8d
  jne    L26
  mov    %r8d,%eax
  imul   %r13,%rax
  shr    $0x20,%rax
  sub    %eax,%r8d
  shr    %r8d
  add    %eax,%r8d
  shr    $0x4,%r8d
  mov    %ebp,%ecx
  mov    %r15d,%edx
  mov    0x8(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L27:
  add    $0x1,%r15d
  add    $0x7,%r14d
  cmp    %r14d,%r12d
  jb     L49
L64:
  mov    %r14d,%ebx
  mov    $0x0,%ebp
  cmp    %r14d,%r12d
  jae    L48
  jmp    L27
L49:
  addl   $0x1,0x8(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x8,%eax
  cmp    %eax,%r12d
  jb     L84
L86:
  mov    0x8(%rsp),%eax
  shl    $0x3,%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,%r14d
  mov    $0x0,%r15d
  cmp    %r12d,%eax
  jbe    L64
  jmp    L49
L84:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: [%d, %d, %d, %d]


assistant: ```c
void print_sum(unsigned int degree) {
  unsigned int a1, a2, a3;
  for (a1 = 0; (8 * a1 <= degree); a1++) {
    for (a2 = 0; (8 * a1 + 7 * a2 <= degree); a2++) {
      for (a3 = 0; (8 * a1 + 7 * a2 + 15 * a3 <= degree); a3++) {
        if ((degree - (a1 * 8 + a2 * 7 + a3 * 15)) % 19 == 0) {
          printf("[%d, %d, %d, %d]\n", a1, a2, a3, (degree - (a1 * 8 + a2 * 7 + a3 * 15)) / 19);
        }
      }
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_sum>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L74:
  lea    0x0(,%rbp,8),%eax
  xor    %r13d,%r13d
  mov    %eax,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    %eax,%r14d
  jb     L20
  nopl   0x0(%rax,%rax,1)
L36:
  mov    0x8(%rsp),%eax
  xor    %ebx,%ebx
  mov    %eax,%r15d
  cmp    %eax,%r14d
  jae    L61
  jmp    L32
L19:
  add    $0xf,%r15d
  add    $0x1,%ebx
  cmp    %r14d,%r15d
  ja     L32
L61:
  mov    %r14d,%r8d
  sub    %r15d,%r8d
  imul   $0x286bca1b,%r8d,%eax
  cmp    $0xd79435e,%eax
  ja     L19
  mov    %r8d,%eax
  mov    $0xaf286bcb,%edx
  mov    %ebx,%ecx
  mov    %ebp,%esi
  imul   %rdx,%rax
  mov    %r12,%rdi
  mov    %r13d,%edx
  add    $0xf,%r15d
  add    $0x1,%ebx
  shr    $0x20,%rax
  sub    %eax,%r8d
  shr    %r8d
  add    %eax,%r8d
  shr    $0x4,%r8d
  call   <printf@plt>
  cmp    %r14d,%r15d
  jbe    L61
L32:
  addl   $0x7,0x8(%rsp)
  mov    0x8(%rsp),%eax
  add    $0x1,%r13d
  cmp    %eax,%r14d
  jae    L36
L20:
  mov    0xc(%rsp),%eax
  add    $0x1,%ebp
  add    $0x8,%eax
  cmp    %eax,%r14d
  jae    L74
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: [%d, %d, %d, %d]


assistant: ```c
void print_sum(unsigned int degree) {
  unsigned int a1, a2, a3;
  for (a1 = 0; (8 * a1 <= degree); a1++) {
    for (a2 = 0; (8 * a1 + 7 * a2 <= degree); a2++) {
      for (a3 = 0; (8 * a1 + 7 * a2 + 15 * a3 <= degree); a3++) {
        if ((degree - (a1 * 8 + a2 * 7 + a3 * 15)) % 19 == 0) {
          printf("[%d, %d, %d, %d]\n", a1, a2, a3, (degree - (a1 * 8 + a2 * 7 + a3 * 15)) / 19);
        }
      }
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_sum>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L63:
  lea    0x0(,%rbp,8),%eax
  xor    %r13d,%r13d
  mov    %eax,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    %eax,%r14d
  jb     L53
  nopl   0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%eax
  xor    %ebx,%ebx
  mov    %eax,%r15d
  cmp    %eax,%r14d
  jae    L34
  jmp    L14
L17:
  add    $0xf,%r15d
  add    $0x1,%ebx
  cmp    %r14d,%r15d
  ja     L14
L34:
  mov    %r14d,%r8d
  sub    %r15d,%r8d
  imul   $0x286bca1b,%r8d,%eax
  cmp    $0xd79435e,%eax
  ja     L17
  mov    %r8d,%eax
  mov    $0xaf286bcb,%edx
  mov    %ebx,%ecx
  mov    %ebp,%esi
  imul   %rdx,%rax
  mov    %r12,%rdi
  mov    %r13d,%edx
  add    $0xf,%r15d
  add    $0x1,%ebx
  shr    $0x20,%rax
  sub    %eax,%r8d
  shr    %r8d
  add    %eax,%r8d
  shr    $0x4,%r8d
  call   <printf@plt>
  cmp    %r14d,%r15d
  jbe    L34
L14:
  addl   $0x7,0x8(%rsp)
  mov    0x8(%rsp),%eax
  add    $0x1,%r13d
  cmp    %eax,%r14d
  jae    L26
L53:
  mov    0xc(%rsp),%eax
  add    $0x1,%ebp
  add    $0x8,%eax
  cmp    %eax,%r14d
  jae    L63
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: [%d, %d, %d, %d]


assistant: ```c
void print_sum(unsigned int degree) {
  unsigned int a1, a2, a3;
  for (a1 = 0; (8 * a1 <= degree); a1++) {
    for (a2 = 0; (8 * a1 + 7 * a2 <= degree); a2++) {
      for (a3 = 0; (8 * a1 + 7 * a2 + 15 * a3 <= degree); a3++) {
        if ((degree - (a1 * 8 + a2 * 7 + a3 * 15)) % 19 == 0) {
          printf("[%d, %d, %d, %d]\n", a1, a2, a3, (degree - (a1 * 8 + a2 * 7 + a3 * 15)) / 19);
        }
      }
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char *s) {
  int i, j;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L4
  cltq
  mov    $0x0,%edx
L18:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L18
L4:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  int i, j;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L17
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L19
L17:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  int i, j;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L18
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L9
L18:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char *s) {
  int i, j;
  char c;
  for (i = 0, j = strlen(s) - 1; i < j; i++, j--) {
    c = s[i];
    s[i] = s[j];
    s[j] = c;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__hashmap_key_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <__hashmap_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__hashmap_key_dup(const void *key) {
  size_t len;
  char *str;
  len = strlen((const char *)key);
  str = __hashmap_alloc(len + 1);
  strcpy(str, (const char *)key);
  return (void *)str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__hashmap_key_dup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <__hashmap_alloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *__hashmap_key_dup(const void *key) {
  size_t len;
  char *str;
  len = strlen((const char *)key);
  str = __hashmap_alloc(len + 1);
  strcpy(str, (const char *)key);
  return (void *)str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__hashmap_key_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <__hashmap_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *__hashmap_key_dup(const void *key) {
  size_t len;
  char *str;
  len = strlen((const char *)key);
  str = __hashmap_alloc(len + 1);
  strcpy(str, (const char *)key);
  return (void *)str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__hashmap_key_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <__hashmap_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *__hashmap_key_dup(const void *key) {
  size_t len;
  char *str;
  len = strlen((const char *)key);
  str = __hashmap_alloc(len + 1);
  strcpy(str, (const char *)key);
  return (void *)str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intpol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L7:
  subq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  subq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double intpol(diffn, coeffs, k)
double *diffn;
double *coeffs;
int k;
{
  double s;
  int i;
  s = 0.0;
  coeffs += k;
  diffn += k;
  for (i = 0; i < k; i++) {
    s += (*--coeffs) * (*--diffn);
  }
  return (s);
}
```