user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D99(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D98(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D92(%rip),%rdi
  call   <puts@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    D153(%rip),%rdi
  call   <puts@plt>
  lea    D90(%rip),%rdi
  call   <puts@plt>
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x6,0x14(%rsp)
  je     L91
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D102(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L46
  cmp    $0x2,%eax
  je     L6
  cmp    $0x3,%eax
  je     L70
  cmp    $0x4,%eax
  je     L11
  cmp    $0x5,%eax
  je     L94
L91:
  lea    D79(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
L6:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  sub    0x10(%rsp),%eax
  lea    D87(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L104:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L94:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D132(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  mov    $0x1,%eax
  cvtsi2ss %edx,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L104
L46:
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  add    0xc(%rsp),%eax
  lea    D89(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L104
L70:
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D25(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L104
L11:
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D118(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L104
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D99
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D98
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D92
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D41
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D153
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D90
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D57
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D68
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D102
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D79
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D87
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D132
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D89
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D118
type_infered: string

tool: D99: 
---------------------------------

tool: D98: %d

tool: D92: Please, choose an option of operation: 

tool: D41: * 1 = Addition 

tool: D153: * 2 = Subtraction 

tool: D90: * 3 = Multiplication 

tool: D57: * 4 = Division 

tool: D68: * 5 = MOD 

tool: D14: * 6 = Exit 

tool: D4: Please, insert the number primary: 

tool: D102: 
Please, insert the number secondary: 

tool: D79: -----BYE----- 

tool: D87: Result subtraction is: %.2f 


tool: D132: Result the mod is: %.2f 


tool: D89: Result addition is: %.2f 


tool: D25: Result multiplication is: %.2f 


tool: D118: Result division is: %.2f 


assistant: ```c
int main() {
  int numberPrimary;
  int numberSecondary;
  int option;
  float result;
  printf("\n---------------------------------\n");
  printf("Please, choose an option of operation: \n");
  printf("* 1 = Addition \n");
  printf("* 2 = Subtraction \n");
  printf("* 3 = Multiplication \n");
  printf("* 4 = Division \n");
  printf("* 5 = MOD \n");
  printf("* 6 = Exit \n");
  scanf("%d", &option);
  if (option == 6) {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("Please, insert the number primary: ");
  scanf("%d", &numberPrimary);
  printf("\nPlease, insert the number secondary: ");
  scanf("%d", &numberSecondary);
  if (option == 1) {
    result = ((numberPrimary) + (numberSecondary));
    printf("Result addition is: %.2f \n", result);
  } else if (option == 2) {
    result = ((numberPrimary) - (numberSecondary));
    printf("Result subtraction is: %.2f \n", result);
  } else if (option == 3) {
    result = ((numberPrimary) * (numberSecondary));
    printf("Result multiplication is: %.2f \n", result);
  } else if (option == 4) {
    result = ((numberPrimary) / (numberSecondary));
    printf("Result division is: %.2f \n", result);
  } else if (option == 5) {
    result = (numberPrimary % numberSecondary);
    printf("Result the mod is: %.2f \n", result);
  } else {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("\n---------------------------------\n");
}
```