ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mc_murmur32>:
  endbr64
  test   %esi,%esi
  lea    0x3(%rsi),%eax
  mov    %rdi,%r9
  mov    %edx,%ecx
  cmovns %esi,%eax
  mov    %esi,%edi
  mov    %eax,%r8d
  and    $0xfffffffc,%eax
  sar    $0x2,%r8d
  cltq
  mov    %r8d,%edx
  lea    (%r9,%rax,1),%rsi
  neg    %edx
  test   %r8d,%r8d
  je     L14
  movslq %edx,%rdx
L53:
  imul   $0xcc9e2d51,(%rsi,%rdx,4),%eax
  add    $0x1,%rdx
  rol    $0xf,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %ecx,%eax
  rol    $0xd,%eax
  lea    -0x19ab949c(%rax,%rax,4),%ecx
  test   %edx,%edx
  jne    L53
L14:
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L13
  cmp    $0x3,%eax
  je     L48
  cmp    $0x1,%eax
  je     L26
  xor    %ecx,%edi
  jmp    1050 <_fmix32@plt>
  nop
L26:
  xor    %edx,%edx
L3:
  movzbl (%rsi),%eax
  xor    %edx,%eax
  imul   $0xcc9e2d51,%eax,%eax
  rol    $0xf,%eax
  imul   $0x1b873593,%eax,%eax
  xor    %eax,%ecx
  xor    %ecx,%edi
  jmp    1050 <_fmix32@plt>
  nop
L48:
  movzbl 0x2(%rsi),%eax
  shl    $0x10,%eax
L67:
  movzbl 0x1(%rsi),%edx
  shl    $0x8,%edx
  xor    %eax,%edx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    L67
```

assistant: ```c
unsigned int mc_murmur32(const void *key, int len, unsigned int seed) {
  const unsigned char *data = (const unsigned char *)key;
  const int nblocks = len / 4;
  int i;
  unsigned int h1 = seed;
  unsigned int k1;
  const unsigned int c1 = 0xcc9e2d51;
  const unsigned int c2 = 0x1b873593;
  const unsigned int *blocks = (const unsigned int *)(data + nblocks * 4);
  const unsigned char *tail;
  for (i = -nblocks; i; ++i) {
    k1 = blocks[i];
    k1 *= c1;
    k1 = (k1 << 15) | (k1 >> (32 - 15));
    k1 *= c2;
    h1 ^= k1;
    h1 = (h1 << 13) | (h1 >> (32 - 13));
    h1 = h1 * 5 + 0xe6546b64;
  }
  tail = (const unsigned char *)(data + nblocks * 4);
  k1 = 0;
  switch (len & 3) {
  case 3:
    k1 ^= tail[2] << 16;
  case 2:
    k1 ^= tail[1] << 8;
  case 1:
    k1 ^= tail[0];
    k1 *= c1;
    k1 = (k1 << 15) | (k1 >> (32 - 15));
    k1 *= c2;
    h1 ^= k1;
  }
  h1 ^= len;
  h1 = _fmix32(h1);
  return h1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L2
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
L2:
  nop
  leave
  ret
```

assistant: ```c
void quicksort(char *array[], const int low, const int high) {
  int part;
  if (low < high) {
    part = partition(array, low, high);
    quicksort(array, low, part - 1);
    quicksort(array, part + 1, high);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quicksort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quicksort(char *array[], const int low, const int high) {
  int part;
  if (low < high) {
    part = partition(array, low, high);
    quicksort(array, low, part - 1);
    quicksort(array, part + 1, high);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L43
L5:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L61
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L3
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <div@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  je     L84
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x1c(%rbp)
  jmp    L61
L84:
  movl   $0x1,-0xc(%rbp)
  jmp    L66
L61:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L19
  jmp    L66
L3:
  nop
L66:
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L0:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void get_primes(int size, int *array) {
  int j, i, cnt = 1;
  int next_prime = 3;
  for (i = 1; i < size; i++) {
    int flag = 0;
    for (j = 0; j < i; j++) {
      if (array[j] == 0) {
        break;
      }
      div_t output;
      output = div(next_prime, array[j]);
      if (output.rem != 0) {
        flag = 0;
      } else {
        flag = 1;
        break;
      }
    }
    if (flag == 0) {
      array[cnt] = next_prime;
      cnt++;
    } else {
    }
    next_prime++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_primes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  cmp    $0x1,%edi
  jle    L76
  mov    %rsi,%r14
  lea    0x4(%rsi),%rbp
  mov    $0x1,%r15d
  mov    $0x1,%r13d
  jmp    L33
L77:
  movslq %r15d,%rax
  mov    %r12d,(%r14,%rax,4)
  add    $0x1,%r15d
L66:
  add    $0x1,%r13d
  add    $0x4,%rbp
  cmp    %r13d,0xc(%rsp)
  je     L76
L33:
  lea    0x2(%r13),%r12d
  mov    %r14,%rbx
  test   %r13d,%r13d
  jle    L77
L78:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L77
  mov    %r12d,%edi
  call   <div@plt>
  test   %rax,%rax
  je     L66
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L78
  jmp    L77
L76:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void get_primes(int size, int *array) {
  int j, i, cnt = 1;
  int next_prime = 3;
  for (i = 1; i < size; i++) {
    int flag = 0;
    for (j = 0; j < i; j++) {
      if (array[j] == 0) {
        break;
      }
      div_t output;
      output = div(next_prime, array[j]);
      if (output.rem != 0) {
        flag = 0;
      } else {
        flag = 1;
        break;
      }
    }
    if (flag == 0) {
      array[cnt] = next_prime;
      cnt++;
    } else {
    }
    next_prime++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_primes>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  push   %r15
  mov    $0x3,%r15d
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    0x2(%rdi),%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x4(%rsi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L20:
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L8
  mov    %r15d,%edi
  call   <div@plt>
  test   %rax,%rax
  je     L16
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L38
L8:
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %r15d,(%r12,%rax,4)
L16:
  add    $0x1,%r15d
  add    $0x4,%rbp
  cmp    %r13d,%r15d
  jne    L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  ret
```

assistant: ```c
void get_primes(int size, int *array) {
  int j, i, cnt = 1;
  int next_prime = 3;
  for (i = 1; i < size; i++) {
    int flag = 0;
    for (j = 0; j < i; j++) {
      if (array[j] == 0) {
        break;
      }
      div_t output;
      output = div(next_prime, array[j]);
      if (output.rem != 0) {
        flag = 0;
      } else {
        flag = 1;
        break;
      }
    }
    if (flag == 0) {
      array[cnt] = next_prime;
      cnt++;
    } else {
    }
    next_prime++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_primes>:
  endbr64
  cmp    $0x1,%edi
  jle    L23
  push   %r15
  mov    $0x3,%r15d
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  lea    0x2(%rdi),%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  lea    0x4(%rsi),%rbp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L39:
  mov    %r12,%rbx
  nopl   0x0(%rax,%rax,1)
L36:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L13
  mov    %r15d,%edi
  call   <div@plt>
  test   %rax,%rax
  je     L18
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L36
L13:
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %r15d,(%r12,%rax,4)
L18:
  add    $0x1,%r15d
  add    $0x4,%rbp
  cmp    %r13d,%r15d
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

assistant: ```c
void get_primes(int size, int *array) {
  int j, i, cnt = 1;
  int next_prime = 3;
  for (i = 1; i < size; i++) {
    int flag = 0;
    for (j = 0; j < i; j++) {
      if (array[j] == 0) {
        break;
      }
      div_t output;
      output = div(next_prime, array[j]);
      if (output.rem != 0) {
        flag = 0;
      } else {
        flag = 1;
        break;
      }
    }
    if (flag == 0) {
      array[cnt] = next_prime;
      cnt++;
    } else {
    }
    next_prime++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_dyna>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L29:
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L11:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x10(%rbp)
L13:
  cmpl   $0x2,-0x10(%rbp)
  jle    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D25
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string

tool: D4: Not enough memory!

tool: D25: %d numero: 

tool: D1: %d

assistant: ```c
void alloc_dyna(void) {
  int n = 0, *pn, i;
  pn = (int *)malloc(n * sizeof(int));
  if (pn == NULL) {
    printf("Not enough memory!\n");
    exit(1);
  }
  for (i = 0; i < 3; i++) {
    printf("%d numero: ", i + 1);
    scanf("%d", pn + i);
  }
  free(pn);
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_dyna>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L2:
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r14
  lea    D11(%rip),%r13
L12:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    $0x3,%ebx
  jne    L12
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D24
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string

tool: D24: %d numero: 

tool: D11: %d

tool: D21: Not enough memory!

assistant: ```c
void alloc_dyna(void) {
  int n = 0, *pn, i;
  pn = (int *)malloc(n * sizeof(int));
  if (pn == NULL) {
    printf("Not enough memory!\n");
    exit(1);
  }
  for (i = 0; i < 3; i++) {
    printf("%d numero: ", i + 1);
    scanf("%d", pn + i);
  }
  free(pn);
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_dyna>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L17:
  mov    %r12,%rbp
  xor    %ebx,%ebx
  lea    D5(%rip),%r14
  lea    D23(%rip),%r13
L27:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x3,%ebx
  jne    L27
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L19:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D5: %d numero: 

tool: D23: %d

tool: D8: Not enough memory!

assistant: ```c
void alloc_dyna(void) {
  int n = 0, *pn, i;
  pn = (int *)malloc(n * sizeof(int));
  if (pn == NULL) {
    printf("Not enough memory!\n");
    exit(1);
  }
  for (i = 0; i < 3; i++) {
    printf("%d numero: ", i + 1);
    scanf("%d", pn + i);
  }
  free(pn);
}
```
user: What is the c source code of the assembly code below:

```asm
<alloc_dyna>:
  endbr64
  push   %r14
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L8:
  mov    %r12,%rbp
  xor    %ebx,%ebx
  lea    D25(%rip),%r14
  lea    D3(%rip),%r13
L6:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x3,%ebx
  jne    L6
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L16:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D3
type: string
name: retrieve_data
arguments: tag: D13
type: string

tool: D25: %d numero: 

tool: D3: %d

tool: D13: Not enough memory!

assistant: ```c
void alloc_dyna(void) {
  int n = 0, *pn, i;
  pn = (int *)malloc(n * sizeof(int));
  if (pn == NULL) {
    printf("Not enough memory!\n");
    exit(1);
  }
  for (i = 0; i < 3; i++) {
    printf("%d numero: ", i + 1);
    scanf("%d", pn + i);
  }
  free(pn);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x7f0(%rbp)
  movq   $0x0,-0x7e8(%rbp)
  lea    -0x7f8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7f4(%rbp)
  jmp    L6
L28:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7f4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7f4(%rbp)
L6:
  mov    -0x7f8(%rbp),%eax
  cmp    %eax,-0x7f4(%rbp)
  jl     L28
  lea    -0x7e0(%rbp),%rax
  mov    %rax,-0x7f0(%rbp)
  lea    -0x7e0(%rbp),%rax
  mov    %rax,-0x7e8(%rbp)
  mov    -0x7f8(%rbp),%esi
  mov    -0x7e8(%rbp),%rcx
  mov    -0x7f0(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string

tool: D18: %d

assistant: ```c
int main() {
  int size;
  int arr[500];
  int *min = 0, *max = 0;
  scanf("%d", &size);
  for (int i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  min = &arr[0];
  max = &arr[0];
  minmax(arr, size, min, max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L14
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L11:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L11
L14:
  lea    0x10(%rsp),%rdi
  mov    %rdi,%rcx
  mov    %rdi,%rdx
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d

assistant: ```c
int main() {
  int size;
  int arr[500];
  int *min = 0, *max = 0;
  scanf("%d", &size);
  for (int i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  min = &arr[0];
  max = &arr[0];
  minmax(arr, size, min, max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L8
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L27
L8:
  mov    %r13,%rcx
  mov    %r13,%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int size;
  int arr[500];
  int *min = 0, *max = 0;
  scanf("%d", &size);
  for (int i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  min = &arr[0];
  max = &arr[0];
  minmax(arr, size, min, max);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L23
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L22
L23:
  mov    %r13,%rcx
  mov    %r13,%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int size;
  int arr[500];
  int *min = 0, *max = 0;
  scanf("%d", &size);
  for (int i = 0; i < size; i++) {
    scanf("%d", &arr[i]);
  }
  min = &arr[0];
  max = &arr[0];
  minmax(arr, size, min, max);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xdrmem_putbytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  test   %eax,%eax
  jns    L3
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  jmp    L14
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bcopy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
L14:
  leave
  ret
```

assistant: ```c
bool_t xdrmem_putbytes(XDR *xdrs, const char *addr, u_int len) {
  if ((xdrs->x_handy -= len) < 0)
    return FALSE;
  bcopy(addr, xdrs->x_private, len);
  xdrs->x_private += len;
  return TRUE;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xdrmem_putbytes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    0x4(%rdi),%eax
  sub    %edx,%eax
  mov    %eax,0x4(%rdi)
  js     L12
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  mov    (%rbx),%esi
  call   <bcopy@plt>
  add    %ebp,(%rbx)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  jmp    L14
```

assistant: ```c
bool_t xdrmem_putbytes(XDR *xdrs, const char *addr, u_int len) {
  if ((xdrs->x_handy -= len) < 0)
    return FALSE;
  bcopy(addr, xdrs->x_private, len);
  xdrs->x_private += len;
  return TRUE;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xdrmem_putbytes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  sub    %edx,0x4(%rdi)
  js     L2
  mov    %rsi,%rdi
  mov    (%rbx),%esi
  mov    %rdx,%rbp
  call   <bcopy@plt>
  mov    D18(%rip),%rax
  add    %ebp,(%rbx)
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool_t xdrmem_putbytes(XDR *xdrs, const char *addr, u_int len) {
  if ((xdrs->x_handy -= len) < 0)
    return FALSE;
  bcopy(addr, xdrs->x_private, len);
  xdrs->x_private += len;
  return TRUE;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xdrmem_putbytes>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  sub    %edx,0x4(%rdi)
  js     L8
  mov    %rsi,%rdi
  mov    (%rbx),%esi
  mov    %rdx,%rbp
  call   <bcopy@plt>
  mov    D2(%rip),%rax
  add    %ebp,(%rbx)
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool_t xdrmem_putbytes(XDR *xdrs, const char *addr, u_int len) {
  if ((xdrs->x_handy -= len) < 0)
    return FALSE;
  bcopy(addr, xdrs->x_private, len);
  xdrs->x_private += len;
  return TRUE;
}
```