ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Subsample_Horizontal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%ebx
  mov    0x48(%rsp),%r15d
  mov    %rdi,-0x18(%rsp)
  test   %ecx,%ecx
  jle    L15
  mov    %ecx,%eax
  mov    %r15d,%edi
  mov    %edx,%r14d
  movslq %r8d,%r12
  sar    %edi
  sub    $0x1,%eax
  mov    %rsi,%r13
  add    %r12,%r12
  mov    %edi,-0x8(%rsp)
  lea    0x1(%rsi,%rax,1),%rax
  lea    -0x1(%r8),%edi
  movslq %r9d,%rbp
  mov    %edi,-0x4(%rsp)
  imul   0x40(%rsp),%r14d
  mov    %rax,-0x10(%rsp)
  nopl   0x0(%rax)
L22:
  mov    %r14d,%eax
  mov    -0x18(%rsp),%rdi
  mov    $0x10,%r11d
  mov    %r13,%r8
  cltd
  idiv   %r15d
  cmp    -0x4(%rsp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rsp),%eax
  lea    (%rdi,%rcx,2),%r10
  lea    0x2(%r10),%r9
  cmovge %r10,%r9
  shl    $0x4,%edx
  xor    %ecx,%ecx
  xor    %edi,%edi
  add    %edx,%eax
  cltd
  idiv   %r15d
  sub    %eax,%r11d
  test   %ebx,%ebx
  jle    L6
L4:
  movswl (%r10,%rcx,1),%edx
  movswl (%r9,%rcx,1),%esi
  add    $0x1,%edi
  add    %r12,%rcx
  imul   %eax,%esi
  imul   %r11d,%edx
  add    %esi,%edx
  mov    %edx,%esi
  not    %esi
  shr    $0x1f,%esi
  lea    0x7f(%rsi,%rdx,1),%edx
  movzbl %dh,%edx
  mov    %dl,(%r8)
  add    %rbp,%r8
  cmp    %edi,%ebx
  jne    L4
L6:
  add    0x40(%rsp),%r14d
  add    $0x1,%r13
  cmp    %r13,-0x10(%rsp)
  jne    L22
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Subsample_Horizontal(signed short int *s, unsigned char *d, signed int x0, signed int lx, signed int lxs, signed int lxd, signed int ly, signed int m, signed int n) {
  signed int i;
  signed int i1;
  signed int j;
  signed int id;
  signed int c1;
  signed int c2;
  signed int v;
  signed short int *s1;
  signed short int *s2;
  unsigned char *d1;
  i1 = 0;
  while (!(i1 >= lx)) {
    d1 = d + (signed long int)i1;
    i = x0 + i1;
    id = (i * m) / n;
    s1 = s + (signed long int)id;
    s2 = id < lxs - 1 ? s1 + (signed long int)1 : s1;
    c2 = (16 * ((i * m) % n) + (n >> 1)) / n;
    c1 = 16 - c2;
    j = 0;
    while (!(j >= ly)) {
      v = c1 * (signed int)*s1 + c2 * (signed int)*s2;
      *d1 = (unsigned char)(v + (v >= 0 ? 128 : 127) >> 8);
      d1 = d1 + (signed long int)lxd;
      s1 = s1 + (signed long int)lxs;
      s2 = s2 + (signed long int)lxs;
      j = j + 1;
    }
    i1 = i1 + 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D29(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D15(%rip)
  mov    D15(%rip),%eax
  and    $0x3,%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *get_buffer(void) {
  static char buffer[4][32];
  static int bufindex = 0;
  return buffer[3 & (++bufindex)];
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_buffer>:
  endbr64
  mov    D3(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D0(%rip)
  and    $0x3,%eax
  shl    $0x5,%rax
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buffer(void) {
  static char buffer[4][32];
  static int bufindex = 0;
  return buffer[3 & (++bufindex)];
}
```
user: What is the c source code of the assembly code below?

```asm
<get_buffer>:
  endbr64
  mov    D20(%rip),%eax
  lea    D4(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,D13(%rip)
  and    $0x3,%eax
  shl    $0x5,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buffer(void) {
  static char buffer[4][32];
  static int bufindex = 0;
  return buffer[3 & (++bufindex)];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_buffer>:
  endbr64
  mov    D17(%rip),%eax
  lea    D12(%rip),%rdx
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  and    $0x3,%eax
  shl    $0x5,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buffer(void) {
  static char buffer[4][32];
  static int bufindex = 0;
  return buffer[3 & (++bufindex)];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__umask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
mode_t __umask(mode_t mask) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__umask>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
mode_t __umask(mode_t mask) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__umask>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
mode_t __umask(mode_t mask) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__umask>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
mode_t __umask(mode_t mask) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rho_tukey_without_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L9
  movsd  -0x10(%rbp),%xmm0
  movsd  D39(%rip),%xmm1
  divsd  %xmm1,%xmm0
  jmp    L5
L9:
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x10(%rbp),%xmm1
  movsd  D21(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D39(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  D21(%rip),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D39
datatype: byte[8]
name: disassemble_data
arguments: tag: D21
datatype: f64

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D21: 1

assistant: ```c
double rho_tukey_without_sqrt(const double x2, const double c) {
  double c2 = c * c;
  if (x2 > c2)
    return c2 / 6;
  else {
    double t = 1. - x2 / c2;
    return c2 / 6 * (1. - t * t * t);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rho_tukey_without_sqrt>:
  endbr64
  mulsd  %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L8
  divsd  D24(%rip),%xmm1
  movapd %xmm1,%xmm0
  ret
L8:
  divsd  %xmm1,%xmm0
  movsd  D14(%rip),%xmm2
  movapd %xmm2,%xmm4
  subsd  %xmm0,%xmm4
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  subsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  divsd  D24(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D24
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D14
type_infered: f64

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D14: 1

assistant: ```c
double rho_tukey_without_sqrt(const double x2, const double c) {
  double c2 = c * c;
  if (x2 > c2)
    return c2 / 6;
  else {
    double t = 1. - x2 / c2;
    return c2 / 6 * (1. - t * t * t);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rho_tukey_without_sqrt>:
  endbr64
  mulsd  %xmm1,%xmm1
  comisd %xmm1,%xmm0
  movapd %xmm1,%xmm2
  divsd  D0(%rip),%xmm2
  ja     L0
  divsd  %xmm1,%xmm0
  movsd  D1(%rip),%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm2
L0:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: byte[8]
name: unpack_data
arguments: tag: D1
type_infered: f64

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D1: 1

assistant: ```c
double rho_tukey_without_sqrt(const double x2, const double c) {
  double c2 = c * c;
  if (x2 > c2)
    return c2 / 6;
  else {
    double t = 1. - x2 / c2;
    return c2 / 6 * (1. - t * t * t);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rho_tukey_without_sqrt>:
  endbr64
  mulsd  %xmm1,%xmm1
  comisd %xmm1,%xmm0
  movapd %xmm1,%xmm2
  divsd  D16(%rip),%xmm2
  ja     L0
  divsd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm2
L0:
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_infered: byte[8]
name: retrieve_data
arguments: tag: D2
type_infered: f64

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: D2: 1

assistant: ```c
double rho_tukey_without_sqrt(const double x2, const double c) {
  double c2 = c * c;
  if (x2 > c2)
    return c2 / 6;
  else {
    double t = 1. - x2 / c2;
    return c2 / 6 * (1. - t * t * t);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<epj2ep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <epj2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <jd2ep@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double epj2ep(epoch)
double epoch;
{
  double dj;
  dj = epj2jd(epoch);
  return (jd2ep(dj));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<epj2ep>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <epj2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2ep@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x8,%rsp
  ret
```

assistant: ```c
double epj2ep(epoch)
double epoch;
{
  double dj;
  dj = epj2jd(epoch);
  return (jd2ep(dj));
}
```
user: Translate the below assembly code into C programming language:

```asm
<epj2ep>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <epj2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2ep@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double epj2ep(epoch)
double epoch;
{
  double dj;
  dj = epj2jd(epoch);
  return (jd2ep(dj));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<epj2ep>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%eax
  call   <epj2jd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  call   <jd2ep@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double epj2ep(epoch)
double epoch;
{
  double dj;
  dj = epj2jd(epoch);
  return (jd2ep(dj));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xcam_new0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcam_new0(size_t size) {
  void *buf = malloc(size);
  memset(buf, 0, size);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xcam_new0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xcam_new0(size_t size) {
  void *buf = malloc(size);
  memset(buf, 0, size);
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xcam_new0>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xcam_new0(size_t size) {
  void *buf = malloc(size);
  memset(buf, 0, size);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xcam_new0>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xcam_new0(size_t size) {
  void *buf = malloc(size);
  memset(buf, 0, size);
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L14
L0:
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0xffffffe,-0x4(%rbp)
  jbe    L0
  cmpl   $0xffffffe,-0x4(%rbp)
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x >= 0x0fffffff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
L3:
  add    $0x1,%eax
  cmp    $0xfffffff,%eax
  jne    L3
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x >= 0x0fffffff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x >= 0x0fffffff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x >= 0x0fffffff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prnTitles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: UPC  | Name               |   Price   |   Tax   |   Total
-----+--------------------+-----------+---------+----------- 


assistant: ```c
void prnTitles() {
  printf("UPC  | Name               |   Price   |   Tax   |   Total\n"
         "-----+--------------------+-----------+---------+----------- \n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prnTitles>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: UPC  | Name               |   Price   |   Tax   |   Total
-----+--------------------+-----------+---------+----------- 


assistant: ```c
void prnTitles() {
  printf("UPC  | Name               |   Price   |   Tax   |   Total\n"
         "-----+--------------------+-----------+---------+----------- \n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prnTitles>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: UPC  | Name               |   Price   |   Tax   |   Total
-----+--------------------+-----------+---------+----------- 


assistant: ```c
void prnTitles() {
  printf("UPC  | Name               |   Price   |   Tax   |   Total\n"
         "-----+--------------------+-----------+---------+----------- \n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prnTitles>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: UPC  | Name               |   Price   |   Tax   |   Total
-----+--------------------+-----------+---------+----------- 


assistant: ```c
void prnTitles() {
  printf("UPC  | Name               |   Price   |   Tax   |   Total\n"
         "-----+--------------------+-----------+---------+----------- \n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int temp, temp2;
  temp = *a;
  *a = *c;
  temp2 = *b;
  *b = temp;
  *c = temp2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rotr>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rdx),%eax
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int temp, temp2;
  temp = *a;
  *a = *c;
  temp2 = *b;
  *b = temp;
  *c = temp2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotr>:
  endbr64
  mov    (%rdx),%eax
  mov    (%rdi),%ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int temp, temp2;
  temp = *a;
  *a = *c;
  temp2 = *b;
  *b = temp;
  *c = temp2;
}
```
user: What is the c source code of the assembly code below:

```asm
<rotr>:
  endbr64
  mov    (%rdx),%eax
  mov    (%rdi),%ecx
  mov    %eax,(%rdi)
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int temp, temp2;
  temp = *a;
  *a = *c;
  temp2 = *b;
  *b = temp;
  *c = temp2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<less>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jge    L19
  mov    $0x1,%eax
  jmp    L15
L19:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
bool less(void *left_data, void *right_data) {
  if ((int64_t)left_data < (int64_t)right_data) {
    return true;
  }
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<less>:
  endbr64
  cmp    %rdi,%rsi
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool less(void *left_data, void *right_data) {
  if ((int64_t)left_data < (int64_t)right_data) {
    return true;
  }
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<less>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rsi
  setg   %al
  ret
```

assistant: ```c
bool less(void *left_data, void *right_data) {
  if ((int64_t)left_data < (int64_t)right_data) {
    return true;
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<less>:
  endbr64
  xor    %eax,%eax
  cmp    %rdi,%rsi
  setg   %al
  ret
```

assistant: ```c
bool less(void *left_data, void *right_data) {
  if ((int64_t)left_data < (int64_t)right_data) {
    return true;
  }
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exact_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L40
  cmpl   $0x1,-0x14(%rbp)
  jne    L1
L40:
  mov    $0x1,%eax
  jmp    L25
L1:
  movl   $0x2,-0x4(%rbp)
  jmp    L59
L30:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L49
  mov    $0x1,%eax
  jmp    L25
L49:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int exact_square(int n) {
  int i;
  if (n == 0 || n == 1)
    return 1;
  for (i = 2; i < n; i++) {
    if (i * i == n)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exact_square>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L10
  cmp    $0x2,%edi
  jle    L34
  cmp    $0x4,%edi
  je     L3
  mov    $0x2,%eax
L39:
  add    $0x1,%eax
  cmp    %eax,%edi
  je     L18
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jne    L39
  mov    $0x1,%eax
L10:
  ret
L18:
  mov    $0x0,%eax
  ret
L34:
  mov    $0x0,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int exact_square(int n) {
  int i;
  if (n == 0 || n == 1)
    return 1;
  for (i = 2; i < n; i++) {
    if (i * i == n)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exact_square>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L34
  cmp    $0x2,%edi
  jle    L22
  cmp    $0x4,%edi
  je     L34
  mov    $0x2,%eax
  jmp    L46
  nop
L33:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L3
L46:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L33
L22:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
L34:
  ret
```

assistant: ```c
int exact_square(int n) {
  int i;
  if (n == 0 || n == 1)
    return 1;
  for (i = 2; i < n; i++) {
    if (i * i == n)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<exact_square>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L4
  cmp    $0x2,%edi
  jle    L19
  cmp    $0x4,%edi
  je     L4
  mov    $0x2,%eax
  jmp    L34
  nop
L6:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  je     L32
L34:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L6
L19:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%eax
L4:
  ret
```

assistant: ```c
int exact_square(int n) {
  int i;
  if (n == 0 || n == 1)
    return 1;
  for (i = 2; i < n; i++) {
    if (i * i == n)
      return 1;
  }
  return 0;
}
```