ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x2c(%rbp)
  jg     L32
  mov    $0x0,%eax
  jmp    L45
L32:
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L28
L6:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  movslq %eax,%rdx
  mov    -0x14(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  movl   $0x0,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    $0x1,%edx
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  add    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    $0x1,%edx
  imul   %edx,%eax
  mov    -0x14(%rbp),%edx
  sub    $0x2,%edx
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    $0x1,%edx
  imul   %edx,%eax
  mov    -0x10(%rbp),%edx
  sub    $0x2,%edx
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    $0x1,%edx
  imul   %edx,%eax
  mov    -0xc(%rbp),%edx
  sub    $0x2,%edx
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

assistant: ```c
int count(int array[], int size) {
  if (size <= 1)
    return 0;
  int rem[3] = {0};
  for (int i = 0; i < size; i++) {
    rem[array[i] % 3]++;
  }
  int result = 0;
  result += rem[0] * (rem[0] - 1) / 2;
  result += rem[1] * rem[2];
  result += rem[0] * (rem[0] - 1) * (rem[0] - 2) / 6;
  result += rem[1] * (rem[1] - 1) * (rem[1] - 2) / 6;
  result += rem[2] * (rem[2] - 1) * (rem[2] - 2) / 6;
  result += rem[0] * rem[1] * rem[2];
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L16
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
L15:
  mov    (%rdx),%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%esi
  mov    %ecx,%eax
  sub    %esi,%eax
  cltq
  addl   $0x1,0xc(%rsp,%rax,4)
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L15
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  imul   %eax,%edx
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%esi
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  mov    %edi,%r8d
  imul   %esi,%r8d
  add    %r8d,%ecx
  lea    -0x2(%rax),%r8d
  imul   %edx,%r8d
  movslq %r8d,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  add    %ecx,%edx
  lea    -0x1(%rdi),%r8d
  imul   %edi,%r8d
  lea    -0x2(%rdi),%ecx
  imul   %ecx,%r8d
  movslq %r8d,%rcx
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  sar    $0x1f,%r8d
  sub    %r8d,%ecx
  add    %edx,%ecx
  lea    -0x1(%rsi),%r8d
  imul   %esi,%r8d
  lea    -0x2(%rsi),%edx
  imul   %edx,%r8d
  movslq %r8d,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  add    %ecx,%edx
  imul   %edi,%eax
  imul   %esi,%eax
  add    %edx,%eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count(int array[], int size) {
  if (size <= 1)
    return 0;
  int rem[3] = {0};
  for (int i = 0; i < size; i++) {
    rem[array[i] % 3]++;
  }
  int result = 0;
  result += rem[0] * (rem[0] - 1) / 2;
  result += rem[1] * rem[2];
  result += rem[0] * (rem[0] - 1) * (rem[0] - 2) / 6;
  result += rem[1] * (rem[1] - 1) * (rem[1] - 2) / 6;
  result += rem[2] * (rem[2] - 1) * (rem[2] - 2) / 6;
  result += rem[0] * rem[1] * rem[2];
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L6
  movq   $0x0,0xc(%rsp)
  lea    -0x1(%rsi),%eax
  movl   $0x0,0x14(%rsp)
  lea    0x4(%rdi,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L10:
  movslq (%rdi),%rax
  add    $0x4,%rdi
  mov    %rax,%rdx
  imul   $0x55555556,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0xc(%rsp,%rax,4)
  cmp    %rsi,%rdi
  jne    L10
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%esi
  lea    -0x1(%rax),%edx
  mov    %edi,%r8d
  imul   %eax,%edx
  imul   %esi,%r8d
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  add    %r8d,%ecx
  lea    -0x2(%rax),%r8d
  imul   %edx,%r8d
  imul   %edi,%eax
  movslq %r8d,%rdx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rdx,%rdx
  imul   %esi,%eax
  shr    $0x20,%rdx
  sub    %r8d,%edx
  lea    -0x1(%rdi),%r8d
  imul   %edi,%r8d
  add    %ecx,%edx
  lea    -0x2(%rdi),%ecx
  imul   %ecx,%r8d
  movslq %r8d,%rcx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %r8d,%ecx
  lea    -0x1(%rsi),%r8d
  imul   %esi,%r8d
  add    %edx,%ecx
  lea    -0x2(%rsi),%edx
  imul   %edx,%r8d
  movslq %r8d,%rdx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %r8d,%edx
  add    %ecx,%edx
  add    %edx,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x28,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count(int array[], int size) {
  if (size <= 1)
    return 0;
  int rem[3] = {0};
  for (int i = 0; i < size; i++) {
    rem[array[i] % 3]++;
  }
  int result = 0;
  result += rem[0] * (rem[0] - 1) / 2;
  result += rem[1] * rem[2];
  result += rem[0] * (rem[0] - 1) * (rem[0] - 2) / 6;
  result += rem[1] * (rem[1] - 1) * (rem[1] - 2) / 6;
  result += rem[2] * (rem[2] - 1) * (rem[2] - 2) / 6;
  result += rem[0] * rem[1] * rem[2];
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L15
  movq   $0x0,0xc(%rsp)
  lea    -0x1(%rsi),%eax
  movl   $0x0,0x14(%rsp)
  lea    0x4(%rdi,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L29:
  movslq (%rdi),%rax
  add    $0x4,%rdi
  mov    %rax,%rdx
  imul   $0x55555556,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  addl   $0x1,0xc(%rsp,%rax,4)
  cmp    %rdi,%rsi
  jne    L29
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%edi
  mov    0x14(%rsp),%esi
  lea    -0x1(%rax),%edx
  mov    %edi,%r8d
  imul   %eax,%edx
  imul   %esi,%r8d
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  add    %r8d,%ecx
  lea    -0x2(%rax),%r8d
  imul   %edx,%r8d
  imul   %edi,%eax
  movslq %r8d,%rdx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rdx,%rdx
  imul   %esi,%eax
  shr    $0x20,%rdx
  sub    %r8d,%edx
  lea    -0x1(%rdi),%r8d
  imul   %edi,%r8d
  add    %ecx,%edx
  lea    -0x2(%rdi),%ecx
  imul   %ecx,%r8d
  movslq %r8d,%rcx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %r8d,%ecx
  lea    -0x1(%rsi),%r8d
  imul   %esi,%r8d
  add    %edx,%ecx
  lea    -0x2(%rsi),%edx
  imul   %edx,%r8d
  movslq %r8d,%rdx
  sar    $0x1f,%r8d
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %r8d,%edx
  add    %ecx,%edx
  add    %edx,%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count(int array[], int size) {
  if (size <= 1)
    return 0;
  int rem[3] = {0};
  for (int i = 0; i < size; i++) {
    rem[array[i] % 3]++;
  }
  int result = 0;
  result += rem[0] * (rem[0] - 1) / 2;
  result += rem[1] * rem[2];
  result += rem[0] * (rem[0] - 1) * (rem[0] - 2) / 6;
  result += rem[1] * (rem[1] - 1) * (rem[1] - 2) / 6;
  result += rem[2] * (rem[2] - 1) * (rem[2] - 2) / 6;
  result += rem[0] * rem[1] * rem[2];
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fatorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L14
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fatorial>
  imul   -0x4(%rbp),%eax
  jmp    L7
L14:
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int fatorial(int n) {
  if (n > 0)
    return fatorial(n - 1) * n;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fatorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jg     L2
  ret
L2:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <fatorial>
  imul   %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int fatorial(int n) {
  if (n > 0)
    return fatorial(n - 1) * n;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fatorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L7
  nopl   (%rax)
L13:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L13
  ret
  nopl   0x0(%rax)
L7:
  ret
```

assistant: ```c
int fatorial(int n) {
  if (n > 0)
    return fatorial(n - 1) * n;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fatorial>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L2
  nopl   (%rax)
L16:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L16
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
int fatorial(int n) {
  if (n > 0)
    return fatorial(n - 1) * n;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bit_scan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xaaaaaaaa,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xcccccccc,%eax
  test   %eax,%eax
  je     L73
  mov    $0x2,%eax
  jmp    L58
L73:
  mov    $0x0,%eax
L58:
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf0f0f0f0,%eax
  test   %eax,%eax
  je     L70
  mov    $0x4,%eax
  jmp    L52
L70:
  mov    $0x0,%eax
L52:
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xff00ff00,%eax
  test   %eax,%eax
  je     L37
  mov    $0x8,%eax
  jmp    L54
L37:
  mov    $0x0,%eax
L54:
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  je     L50
  mov    $0x10,%eax
  jmp    L56
L50:
  mov    $0x0,%eax
L56:
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bit_scan(unsigned int x) {
  int res = 0;
  res |= (x & 0xaaaaaaaa) ? 1 : 0;
  res |= (x & 0xcccccccc) ? 2 : 0;
  res |= (x & 0xf0f0f0f0) ? 4 : 0;
  res |= (x & 0xff00ff00) ? 8 : 0;
  res |= (x & 0xffff0000) ? 16 : 0;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bit_scan>:
  endbr64
  test   $0xf0f0f0f0,%edi
  setne  %al
  movzbl %al,%eax
  shl    $0x2,%eax
  test   $0xcccccccc,%edi
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%edx
  or     %edx,%eax
  test   $0xaaaaaaaa,%edi
  setne  %dl
  movzbl %dl,%edx
  or     %edx,%eax
  test   $0xff00ff00,%edi
  setne  %dl
  movzbl %dl,%edx
  shl    $0x3,%edx
  or     %eax,%edx
  test   $0xffff0000,%edi
  setne  %al
  movzbl %al,%eax
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int bit_scan(unsigned int x) {
  int res = 0;
  res |= (x & 0xaaaaaaaa) ? 1 : 0;
  res |= (x & 0xcccccccc) ? 2 : 0;
  res |= (x & 0xf0f0f0f0) ? 4 : 0;
  res |= (x & 0xff00ff00) ? 8 : 0;
  res |= (x & 0xffff0000) ? 16 : 0;
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<bit_scan>:
  endbr64
  xor    %eax,%eax
  test   $0xf0f0f0f0,%edi
  setne  %al
  xor    %edx,%edx
  shl    $0x2,%eax
  test   $0xcccccccc,%edi
  setne  %dl
  add    %edx,%edx
  or     %edx,%eax
  xor    %edx,%edx
  test   $0xaaaaaaaa,%edi
  setne  %dl
  or     %edx,%eax
  xor    %edx,%edx
  test   $0xff00ff00,%edi
  setne  %dl
  shl    $0x3,%edx
  or     %eax,%edx
  xor    %eax,%eax
  and    $0xffff0000,%edi
  setne  %al
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int bit_scan(unsigned int x) {
  int res = 0;
  res |= (x & 0xaaaaaaaa) ? 1 : 0;
  res |= (x & 0xcccccccc) ? 2 : 0;
  res |= (x & 0xf0f0f0f0) ? 4 : 0;
  res |= (x & 0xff00ff00) ? 8 : 0;
  res |= (x & 0xffff0000) ? 16 : 0;
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bit_scan>:
  endbr64
  xor    %eax,%eax
  test   $0xf0f0f0f0,%edi
  setne  %al
  xor    %edx,%edx
  shl    $0x2,%eax
  test   $0xcccccccc,%edi
  setne  %dl
  add    %edx,%edx
  or     %edx,%eax
  xor    %edx,%edx
  test   $0xaaaaaaaa,%edi
  setne  %dl
  or     %edx,%eax
  xor    %edx,%edx
  test   $0xff00ff00,%edi
  setne  %dl
  shl    $0x3,%edx
  or     %eax,%edx
  xor    %eax,%eax
  and    $0xffff0000,%edi
  setne  %al
  shl    $0x4,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int bit_scan(unsigned int x) {
  int res = 0;
  res |= (x & 0xaaaaaaaa) ? 1 : 0;
  res |= (x & 0xcccccccc) ? 2 : 0;
  res |= (x & 0xf0f0f0f0) ? 4 : 0;
  res |= (x & 0xff00ff00) ? 8 : 0;
  res |= (x & 0xffff0000) ? 16 : 0;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_isdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_isdir(char *path) {
  (void)path;
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_isdir>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_isdir(char *path) {
  (void)path;
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_isdir>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isdir(char *path) {
  (void)path;
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_isdir>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_isdir(char *path) {
  (void)path;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zenith2time>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%ebx
  movsd  %xmm0,0x20(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,0x10(%rsp)
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <declination@plt>
  lea    0x38(%rsp),%r14
  lea    0x30(%rsp),%r15
  mulsd  D60(%rip),%xmm0
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sincos@plt>
  movsd  0x30(%rsp),%xmm4
  movsd  %xmm4,0x18(%rsp)
  mov    0x38(%rsp),%rbp
  movsd  D60(%rip),%xmm0
  mulsd  0x28(%rsp),%xmm0
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <sincos@plt>
  movsd  D60(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  call   <cos@plt>
  movq   %rbp,%xmm1
  mulsd  0x38(%rsp),%xmm1
  subsd  %xmm1,%xmm0
  divsd  0x18(%rsp),%xmm0
  divsd  0x30(%rsp),%xmm0
  movapd %xmm0,%xmm1
  andpd  D29(%rip),%xmm1
  comisd D20(%rip),%xmm1
  ja     L14
  call   <acos@plt>
  movq   %xmm0,%r14
  movapd %xmm0,%xmm1
  divsd  D44(%rip),%xmm1
  movsd  D20(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D87(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  call   <standard_time@plt>
  mov    %eax,0x0(%r13)
  pxor   %xmm1,%xmm1
  movq   %r14,%xmm7
  subsd  %xmm7,%xmm1
  divsd  D44(%rip),%xmm1
  movsd  D20(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D87(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  call   <standard_time@plt>
  mov    %eax,(%r12)
  mov    $0x0,%eax
L2:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D60
type_guessed: byte[8]
name: read_data
arguments: data_tag: D29
type_guessed: qword[2]
name: read_data
arguments: data_tag: D20
type_guessed: f64[2]
name: read_data
arguments: data_tag: D44
type_guessed: f64
name: read_data
arguments: data_tag: D87
type_guessed: f32[2]

tool: {"D60": [0x18,0x39,0x35,0x9d,0x46,0xdf,0x91,0x3f]}

tool: {"D29": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D20": [1.0,3.1415926]}

tool: D44: 3.1415926

tool: {"D87": [0.0,7.1591796875]}

assistant: ```c
int zenith2time(int day, double zenith_angle, double latitude, double longitude, double long_std, int *time1, int *time2) {
  double delta = 3.1415926 / 180.0 * declination(day);
  double phi = 3.1415926 / 180.0 * latitude;
  double theta = 3.1415926 / 180.0 * zenith_angle;
  double cos_omega = (cos(theta) - sin(delta) * sin(phi)) / cos(delta) / cos(phi);
  double omega1 = 0, omega2 = 0;
  int lat1 = 0, lat2 = 0;
  if (fabs(cos_omega) > 1.0)
    return -1;
  omega1 = acos(cos_omega);
  omega2 = 0.0 - omega1;
  lat1 = 43200 * (1 - omega1 / 3.1415926);
  lat2 = 43200 * (1 - omega2 / 3.1415926);
  *time1 = standard_time(lat1, day, longitude, long_std);
  *time2 = standard_time(lat2, day, longitude, long_std);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zenith2time>:
  endbr64
  push   %r15
  movq   %xmm2,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x48,%rsp
  movsd  %xmm1,0x20(%rsp)
  lea    0x38(%rsp),%r13
  lea    0x30(%rsp),%r14
  movsd  %xmm3,0x28(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <declination@plt>
  mulsd  D63(%rip),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm4
  mov    %r14,%rsi
  movsd  D63(%rip),%xmm5
  movsd  0x38(%rsp),%xmm2
  movsd  0x30(%rsp),%xmm7
  mov    %r13,%rdi
  mulsd  %xmm4,%xmm5
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm7,0x8(%rsp)
  movapd %xmm5,%xmm0
  call   <sincos@plt>
  movsd  D63(%rip),%xmm6
  mulsd  0x10(%rsp),%xmm6
  movapd %xmm6,%xmm0
  call   <cos@plt>
  movsd  0x18(%rsp),%xmm2
  mulsd  0x38(%rsp),%xmm2
  subsd  %xmm2,%xmm0
  divsd  0x8(%rsp),%xmm0
  divsd  0x30(%rsp),%xmm0
  movapd %xmm0,%xmm2
  andpd  D100(%rip),%xmm2
  comisd D53(%rip),%xmm2
  ja     L18
  call   <acos@plt>
  movsd  0x28(%rsp),%xmm1
  mov    %r12d,%esi
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x10(%rsp)
  movsd  D53(%rip),%xmm0
  divsd  D45(%rip),%xmm2
  movsd  %xmm1,0x8(%rsp)
  subsd  %xmm2,%xmm0
  mulsd  D73(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  movq   %r15,%xmm0
  call   <standard_time@plt>
  movsd  0x10(%rsp),%xmm3
  pxor   %xmm2,%xmm2
  movsd  D53(%rip),%xmm0
  mov    %eax,0x0(%rbp)
  movsd  0x8(%rsp),%xmm1
  mov    %r12d,%esi
  subsd  %xmm3,%xmm2
  divsd  D45(%rip),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  D73(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  movq   %r15,%xmm0
  call   <standard_time@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
L11:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L18:
  mov    $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: data_tag: D63
data_type: byte[8]
name: retrieve_data
arguments: data_tag: D100
data_type: qword[2]
name: retrieve_data
arguments: data_tag: D53
data_type: f64[2]
name: retrieve_data
arguments: data_tag: D45
data_type: f64
name: retrieve_data
arguments: data_tag: D73
data_type: f32[2]

tool: {"D63": [0x18,0x39,0x35,0x9d,0x46,0xdf,0x91,0x3f]}

tool: {"D100": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D53": [1.0,3.1415926]}

tool: D45: 3.1415926

tool: {"D73": [0.0,7.1591796875]}

assistant: ```c
int zenith2time(int day, double zenith_angle, double latitude, double longitude, double long_std, int *time1, int *time2) {
  double delta = 3.1415926 / 180.0 * declination(day);
  double phi = 3.1415926 / 180.0 * latitude;
  double theta = 3.1415926 / 180.0 * zenith_angle;
  double cos_omega = (cos(theta) - sin(delta) * sin(phi)) / cos(delta) / cos(phi);
  double omega1 = 0, omega2 = 0;
  int lat1 = 0, lat2 = 0;
  if (fabs(cos_omega) > 1.0)
    return -1;
  omega1 = acos(cos_omega);
  omega2 = 0.0 - omega1;
  lat1 = 43200 * (1 - omega1 / 3.1415926);
  lat2 = 43200 * (1 - omega2 / 3.1415926);
  *time1 = standard_time(lat1, day, longitude, long_std);
  *time2 = standard_time(lat2, day, longitude, long_std);
  return 0;
}
```