ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <lengthOfLongestSubstring@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%ebp
  call   <lengthOfLongestSubstring@plt>
  lea    D68(%rip),%rdi
  mov    %eax,%r12d
  call   <lengthOfLongestSubstring@plt>
  lea    D73(%rip),%rdi
  mov    %eax,%r13d
  call   <lengthOfLongestSubstring@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%ebx
  call   <lengthOfLongestSubstring@plt>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%r9d
  mov    %ebp,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <lengthOfLongestSubstring@plt>
  lea    D49(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D68
type_guessed: string
name: unpack_data
arguments: tag: D73
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D47
type_guessed: string
name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D49
type_guessed: string

tool: D5: abcabcbb

tool: D0: bbbbbb

tool: D68: pwwkew

tool: D73: dvdf

tool: D9: abba

tool: D47: %d, %d, %d, %d, %d.


tool: D2: abc'"#$5acefgh

tool: D49: %d.


assistant: ```c
int main(void) {
  char *a = "abcabcbb";
  char *b = "bbbbbb";
  char *c = "pwwkew";
  char *d = "dvdf";
  char *e = "abba";
  int ret1 = lengthOfLongestSubstring(a);
  int ret2 = lengthOfLongestSubstring(b);
  int ret3 = lengthOfLongestSubstring(c);
  int ret4 = lengthOfLongestSubstring(d);
  int ret5 = lengthOfLongestSubstring(e);
  printf("%d, %d, %d, %d, %d.\n", ret1, ret2, ret3, ret4, ret5);
  char *f = "abc'\"#$5acefgh";
  int ret6 = lengthOfLongestSubstring(f);
  printf("%d.\n", ret6);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    if (argv[i][0] > 127) {
      sum += 1;
    }
    sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L24
  mov    $0x0,%esi
  mov    $0x0,%eax
L28:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L28
L8:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L24:
  mov    $0x0,%esi
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    if (argv[i][0] > 127) {
      sum += 1;
    }
    sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  test   %edi,%edi
  jle    L12
  xor    %eax,%eax
L14:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L14
L12:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    if (argv[i][0] > 127) {
      sum += 1;
    }
    sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L100
  lea    -0x1(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L33
  mov    %edi,%edx
  movdqa D23(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D25(%rip),%xmm3
  shr    $0x2,%edx
  nopw   0x0(%rax,%rax,1)
L139:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L139
  movdqa %xmm0,%xmm1
  mov    %edi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%dil
  je     L140
L19:
  lea    0x1(%rax),%edx
  add    %eax,%esi
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x2(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x3(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x4(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x5(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x6(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x7(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    %edx,%esi
  lea    0x8(%rax),%edx
  cmp    %edx,%edi
  jle    L140
  add    $0x9,%eax
  add    %edx,%esi
  cmp    %eax,%edi
  jle    L140
  add    %eax,%esi
L140:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L100:
  xor    %esi,%esi
  jmp    L140
L33:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L19
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: byte[16]
name: unpack_data
arguments: label: D25
datatype: byte[16]
name: unpack_data
arguments: label: D15
datatype: string

tool: {"D23": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D25": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D15: Sum is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  int sum = 0;
  for (i = 0; i < argc; i++) {
    if (argv[i][0] > 127) {
      sum += 1;
    }
    sum += i;
  }
  printf("Sum is: %d\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unaligned_read_be16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <be16toh@plt>
  leave
  ret
```

assistant: ```c
uint16_t unaligned_read_be16(const void *_u) {
  const struct __attribute__((__packed__, __may_alias__)) { uint16_t x; } *u = _u;
  return be16toh(u->x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unaligned_read_be16>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <be16toh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t unaligned_read_be16(const void *_u) {
  const struct __attribute__((__packed__, __may_alias__)) { uint16_t x; } *u = _u;
  return be16toh(u->x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unaligned_read_be16>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <be16toh@plt>
```

assistant: ```c
uint16_t unaligned_read_be16(const void *_u) {
  const struct __attribute__((__packed__, __may_alias__)) { uint16_t x; } *u = _u;
  return be16toh(u->x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unaligned_read_be16>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <be16toh@plt>
```

assistant: ```c
uint16_t unaligned_read_be16(const void *_u) {
  const struct __attribute__((__packed__, __may_alias__)) { uint16_t x; } *u = _u;
  return be16toh(u->x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stddev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mean@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double stddev(double *x, int n) {
  int i;
  double m, ret;
  m = mean(x, n);
  ret = 0;
  for (i = 0; i < n; i++)
    ret += (x[i] - m) * (x[i] - m);
  return (sqrt(ret / (double)(n - 1)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stddev>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <mean@plt>
  test   %ebx,%ebx
  jle    L48
  movapd %xmm0,%xmm2
  mov    %rbp,%rax
  lea    -0x1(%rbx),%edx
  lea    0x8(%rbp,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L12:
  movsd  (%rax),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L12
L19:
  sub    $0x1,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L2
  sqrtsd %xmm0,%xmm0
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  pxor   %xmm0,%xmm0
  jmp    L19
L2:
  call   <sqrt@plt>
  jmp    L35
```

assistant: ```c
double stddev(double *x, int n) {
  int i;
  double m, ret;
  m = mean(x, n);
  ret = 0;
  for (i = 0; i < n; i++)
    ret += (x[i] - m) * (x[i] - m);
  return (sqrt(ret / (double)(n - 1)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stddev>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <mean@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%eax
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm2
  mov    %rbx,%rdi
  mov    %rax,%rbp
  movapd %xmm3,%xmm0
  lea    0x8(%rbx,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L33:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L33
L27:
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L26
  add    $0x8,%rsp
  sqrtsd %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L12:
  pxor   %xmm3,%xmm3
  sub    $0x1,%ebp
  movapd %xmm3,%xmm0
  jmp    L27
L26:
  pop    %rax
  pop    %rbx
  pop    %rbp
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double stddev(double *x, int n) {
  int i;
  double m, ret;
  m = mean(x, n);
  ret = 0;
  for (i = 0; i < n; i++)
    ret += (x[i] - m) * (x[i] - m);
  return (sqrt(ret / (double)(n - 1)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stddev>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <mean@plt>
  test   %ebx,%ebx
  jle    L47
  movapd %xmm0,%xmm3
  cmp    $0x1,%ebx
  je     L55
  mov    %ebx,%edx
  movapd %xmm0,%xmm4
  pxor   %xmm5,%xmm5
  mov    %rbp,%rax
  shr    %edx
  unpcklpd %xmm4,%xmm4
  movapd %xmm5,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbp,%rdx,1),%rdx
  nopl   0x0(%rax)
L1:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  subpd  %xmm4,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L1
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bl
  je     L51
L45:
  cltq
  movsd  0x0(%rbp,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L51:
  sub    $0x1,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm5
  ja     L32
  add    $0x8,%rsp
  sqrtsd %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
  nop
L47:
  pxor   %xmm5,%xmm5
  movapd %xmm5,%xmm0
  jmp    L51
L55:
  pxor   %xmm5,%xmm5
  xor    %eax,%eax
  movapd %xmm5,%xmm0
  jmp    L45
L32:
  pop    %rax
  pop    %rbx
  pop    %rbp
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double stddev(double *x, int n) {
  int i;
  double m, ret;
  m = mean(x, n);
  ret = 0;
  for (i = 0; i < n; i++)
    ret += (x[i] - m) * (x[i] - m);
  return (sqrt(ret / (double)(n - 1)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<outrigger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movss  %xmm0,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D18(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D20(%rip)
  lea    -0x30(%rbp),%rcx
  mov    %eax,%edx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <outrigger_module@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <call_module@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D20
type_infered: string

tool: D20: outrig_%d

assistant: ```c
void outrigger(float length) {
  static int outrignum = 0;
  char outrig[30];
  sprintf(outrig, "outrig_%d", outrignum++);
  outrigger_module(outrig, length);
  call_module(outrig);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<outrigger>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%edx
  lea    0x1(%rdx),%eax
  mov    %eax,D0(%rip)
  lea    0x10(%rsp),%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  movss  0xc(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <outrigger_module@plt>
  mov    %rbx,%rdi
  call   <call_module@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: outrig_%d

assistant: ```c
void outrigger(float length) {
  static int outrignum = 0;
  char outrig[30];
  sprintf(outrig, "outrig_%d", outrignum++);
  outrigger_module(outrig, length);
  call_module(outrig);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aspectRatioMatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabsf@plt>
  movsd  D6(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L3
  mov    $0x1,%eax
  jmp    L14
L3:
  mov    $0x0,%eax
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: f64

tool: D6: 0.01

assistant: ```c
int aspectRatioMatch(float aspectRatio1, float aspectRatio2) {
  if (fabsf(aspectRatio2 - aspectRatio1) <= (0.01))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aspectRatioMatch>:
  endbr64
  sub    $0x8,%rsp
  subss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  call   <fabsf@plt>
  movsd  D4(%rip),%xmm1
  comisd %xmm0,%xmm1
  setae  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: f64

tool: D4: 0.01

assistant: ```c
int aspectRatioMatch(float aspectRatio1, float aspectRatio2) {
  if (fabsf(aspectRatio2 - aspectRatio1) <= (0.01))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aspectRatioMatch>:
  endbr64
  subss  %xmm0,%xmm1
  sub    $0x8,%rsp
  movaps %xmm1,%xmm0
  call   <fabsf@plt>
  movsd  D2(%rip),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  setae  %al
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: f64

tool: D2: 0.01

assistant: ```c
int aspectRatioMatch(float aspectRatio1, float aspectRatio2) {
  if (fabsf(aspectRatio2 - aspectRatio1) <= (0.01))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<aspectRatioMatch>:
  endbr64
  subss  %xmm0,%xmm1
  sub    $0x8,%rsp
  movaps %xmm1,%xmm0
  call   <fabsf@plt>
  movsd  D0(%rip),%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  setae  %al
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: f64

tool: D0: 0.01

assistant: ```c
int aspectRatioMatch(float aspectRatio1, float aspectRatio2) {
  if (fabsf(aspectRatio2 - aspectRatio1) <= (0.01))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<catlloc_new_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L5
L17:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *catlloc_new_str(unsigned char *s1, int n1, unsigned char *s2, int n2) {
  assert(s1 != NULL);
  unsigned char *new_string;
  if (s1 == NULL) {
    new_string = malloc(n2);
    memcpy(new_string, s2, n2);
  } else {
    new_string = malloc(n1 + n2);
    memcpy(new_string, s1, n1);
    memcpy(new_string + n1, s2, n2);
  }
  return new_string;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<catlloc_new_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %ecx,%r12d
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14,%r14
  je     L11
  lea    (%rbx,%r12,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rdi
  add    %rbp,%rdi
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
L3:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L3
```

assistant: ```c
unsigned char *catlloc_new_str(unsigned char *s1, int n1, unsigned char *s2, int n2) {
  assert(s1 != NULL);
  unsigned char *new_string;
  if (s1 == NULL) {
    new_string = malloc(n2);
    memcpy(new_string, s2, n2);
  } else {
    new_string = malloc(n1 + n2);
    memcpy(new_string, s1, n1);
    memcpy(new_string + n1, s2, n2);
  }
  return new_string;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<catlloc_new_str>:
  endbr64
  push   %r14
  test   %rdi,%rdi
  mov    %rdi,%r14
  push   %r13
  setne  %dil
  mov    %ecx,%r13d
  push   %r12
  movzbl %dil,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <assert@plt>
  test   %r14,%r14
  je     L3
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *catlloc_new_str(unsigned char *s1, int n1, unsigned char *s2, int n2) {
  assert(s1 != NULL);
  unsigned char *new_string;
  if (s1 == NULL) {
    new_string = malloc(n2);
    memcpy(new_string, s2, n2);
  } else {
    new_string = malloc(n1 + n2);
    memcpy(new_string, s1, n1);
    memcpy(new_string + n1, s2, n2);
  }
  return new_string;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<catlloc_new_str>:
  endbr64
  push   %r14
  test   %rdi,%rdi
  mov    %rdi,%r14
  push   %r13
  setne  %dil
  mov    %ecx,%r13d
  push   %r12
  movzbl %dil,%edi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <assert@plt>
  test   %r14,%r14
  je     L5
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  movslq %ebx,%rdi
  mov    %r13d,%edx
  mov    %rbp,%rsi
  add    %r12,%rdi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *catlloc_new_str(unsigned char *s1, int n1, unsigned char *s2, int n2) {
  assert(s1 != NULL);
  unsigned char *new_string;
  if (s1 == NULL) {
    new_string = malloc(n2);
    memcpy(new_string, s2, n2);
  } else {
    new_string = malloc(n1 + n2);
    memcpy(new_string, s1, n1);
    memcpy(new_string + n1, s2, n2);
  }
  return new_string;
}
```