ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  lea    D7(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L33:
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <getaline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jle    L26
  mov    %rbx,%rdi
  call   <cleanaline@plt>
  cmpb   $0xa,(%rsp)
  je     L33
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x2728,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: %s

assistant: ```c
int main(void) {
  int len;
  char line[10000];
  while ((len = getaline(line, 10000)) > 0) {
    cleanaline(line, len);
    if (line[0] == '\n')
      continue;
    printf("%s", line);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SPI_set_high_speed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe0068004,%eax
  movb   $0x1,(%rax)
  mov    $0xe0068010,%eax
  movb   $0x6,(%rax)
  mov    $0xe0068004,%eax
  movb   $0x2,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SPI_set_high_speed() {
  (*((volatile unsigned char *)0xE0068004)) = 0x01;
  (*((volatile unsigned char *)0xE0068010)) = 6;
  (*((volatile unsigned char *)0xE0068004)) = 0x02;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SPI_set_high_speed>:
  endbr64
  mov    $0xe0068004,%eax
  movb   $0x1,(%rax)
  mov    $0xe0068010,%edx
  movb   $0x6,(%rdx)
  movb   $0x2,(%rax)
  ret
```

assistant: ```c
void SPI_set_high_speed() {
  (*((volatile unsigned char *)0xE0068004)) = 0x01;
  (*((volatile unsigned char *)0xE0068010)) = 6;
  (*((volatile unsigned char *)0xE0068004)) = 0x02;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SPI_set_high_speed>:
  endbr64
  mov    $0xe0068004,%eax
  mov    $0xe0068010,%edx
  movb   $0x1,(%rax)
  movb   $0x6,(%rdx)
  movb   $0x2,(%rax)
  ret
```

assistant: ```c
void SPI_set_high_speed() {
  (*((volatile unsigned char *)0xE0068004)) = 0x01;
  (*((volatile unsigned char *)0xE0068010)) = 6;
  (*((volatile unsigned char *)0xE0068004)) = 0x02;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SPI_set_high_speed>:
  endbr64
  mov    $0xe0068004,%eax
  mov    $0xe0068010,%edx
  movb   $0x1,(%rax)
  movb   $0x6,(%rdx)
  movb   $0x2,(%rax)
  ret
```

assistant: ```c
void SPI_set_high_speed() {
  (*((volatile unsigned char *)0xE0068004)) = 0x01;
  (*((volatile unsigned char *)0xE0068010)) = 6;
  (*((volatile unsigned char *)0xE0068004)) = 0x02;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y[10];
  x = y[2];
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y[10];
  x = y[2];
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y[10];
  x = y[2];
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y[10];
  x = y[2];
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FIRfilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L1:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L1
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double FIRfilter(double *fifo, double *coefficients, unsigned int taps) {
  double filtered = 0;
  unsigned int i = 0;
  for (i = 0; i < taps; i++) {
    filtered += coefficients[i] * fifo[i];
  }
  return filtered;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FIRfilter>:
  endbr64
  test   %edx,%edx
  je     L21
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L7:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L7
L23:
  movapd %xmm1,%xmm0
  ret
L21:
  pxor   %xmm1,%xmm1
  jmp    L23
```

assistant: ```c
double FIRfilter(double *fifo, double *coefficients, unsigned int taps) {
  double filtered = 0;
  unsigned int i = 0;
  for (i = 0; i < taps; i++) {
    filtered += coefficients[i] * fifo[i];
  }
  return filtered;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<FIRfilter>:
  endbr64
  test   %edx,%edx
  je     L14
  mov    %edx,%edx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L18:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L18
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L14:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double FIRfilter(double *fifo, double *coefficients, unsigned int taps) {
  double filtered = 0;
  unsigned int i = 0;
  for (i = 0; i < taps; i++) {
    filtered += coefficients[i] * fifo[i];
  }
  return filtered;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FIRfilter>:
  endbr64
  test   %edx,%edx
  je     L19
  cmp    $0x1,%edx
  je     L5
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L42:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rdi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L42
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L12
L29:
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L12:
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm0,%xmm0
  ret
L5:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L29
```

assistant: ```c
double FIRfilter(double *fifo, double *coefficients, unsigned int taps) {
  double filtered = 0;
  unsigned int i = 0;
  for (i = 0; i < taps; i++) {
    filtered += coefficients[i] * fifo[i];
  }
  return filtered;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L13
L11:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L13:
  cmpl   $0x0,-0x18(%rbp)
  jg     L11
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int Rem;
  while (b > 0) {
    Rem = a % b;
    a = b;
    b = Rem;
  }
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jle    L18
L9:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jg     L9
L17:
  mov    %ecx,%eax
  ret
L18:
  mov    %edi,%ecx
  jmp    L17
```

assistant: ```c
int gcd(int a, int b) {
  int Rem;
  while (b > 0) {
    Rem = a % b;
    a = b;
    b = Rem;
  }
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  jle    L12
  nopl   0x0(%rax)
L16:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jg     L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int Rem;
  while (b > 0) {
    Rem = a % b;
    a = b;
    b = Rem;
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  jle    L9
  nopl   0x0(%rax)
L16:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jg     L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int Rem;
  while (b > 0) {
    Rem = a % b;
    a = b;
    b = Rem;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x19,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D48(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D48
type: string

tool: D18: tutorialspoint

tool: D21: String = %s,  Address = %p


tool: D48: .com

assistant: ```c
int main() {
  char *str;
  str = (char *)malloc(15);
  strcpy(str, "tutorialspoint");
  printf("String = %s,  Address = %p\n", str, str);
  str = (char *)realloc(str, 25);
  strcat(str, ".com");
  printf("String = %s,  Address = %p\n", str, str);
  free(str);
  str = NULL;
  printf("String = %s,  Address = %p\n", str, str);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xf,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x19,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string

tool: D13: tutorialspoint

tool: D20: String = %s,  Address = %p


tool: D14: .com

assistant: ```c
int main() {
  char *str;
  str = (char *)malloc(15);
  strcpy(str, "tutorialspoint");
  printf("String = %s,  Address = %p\n", str, str);
  str = (char *)realloc(str, 25);
  strcat(str, ".com");
  printf("String = %s,  Address = %p\n", str, str);
  free(str);
  str = NULL;
  printf("String = %s,  Address = %p\n", str, str);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xf,%edi
  lea    D24(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D11(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x19,%esi
  call   <realloc@plt>
  lea    D21(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D24: String = %s,  Address = %p


tool: D11: tutorialspoint

tool: D21: .com

assistant: ```c
int main() {
  char *str;
  str = (char *)malloc(15);
  strcpy(str, "tutorialspoint");
  printf("String = %s,  Address = %p\n", str, str);
  str = (char *)realloc(str, 25);
  strcat(str, ".com");
  printf("String = %s,  Address = %p\n", str, str);
  free(str);
  str = NULL;
  printf("String = %s,  Address = %p\n", str, str);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xf,%edi
  lea    D12(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D26(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x19,%esi
  call   <realloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D2
type: string

tool: D12: String = %s,  Address = %p


tool: D26: tutorialspoint

tool: D2: .com

assistant: ```c
int main() {
  char *str;
  str = (char *)malloc(15);
  strcpy(str, "tutorialspoint");
  printf("String = %s,  Address = %p\n", str, str);
  str = (char *)realloc(str, 25);
  strcat(str, ".com");
  printf("String = %s,  Address = %p\n", str, str);
  free(str);
  str = NULL;
  printf("String = %s,  Address = %p\n", str, str);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_tag_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L20
  mov    $0x0,%eax
  jmp    L1
L20:
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L39
  mov    $0x1,%eax
  jmp    L1
L39:
  mov    $0xffffffff,%eax
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string

tool: D8: implemented

tool: D17: unimplemented

assistant: ```c
int get_tag_id(char *tag) {
  if (strcasecmp(tag, "implemented") == 0) {
    return 0;
  }
  if (strcasecmp(tag, "unimplemented") == 0) {
    return 1;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_tag_id>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D11(%rip),%rsi
  call   <strcasecmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L12
L16:
  pop    %rbx
  ret
L12:
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string

tool: D11: implemented

tool: D18: unimplemented

assistant: ```c
int get_tag_id(char *tag) {
  if (strcasecmp(tag, "implemented") == 0) {
    return 0;
  }
  if (strcasecmp(tag, "unimplemented") == 0) {
    return 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_tag_id>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcasecmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  pop    %rbp
  ret
L8:
  mov    %rbp,%rdi
  lea    D14(%rip),%rsi
  call   <strcasecmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D17: implemented

tool: D14: unimplemented

assistant: ```c
int get_tag_id(char *tag) {
  if (strcasecmp(tag, "implemented") == 0) {
    return 0;
  }
  if (strcasecmp(tag, "unimplemented") == 0) {
    return 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_tag_id>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcasecmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L7
  pop    %rbp
  ret
L7:
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <strcasecmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D5
data_type: string

tool: D0: implemented

tool: D5: unimplemented

assistant: ```c
int get_tag_id(char *tag) {
  if (strcasecmp(tag, "implemented") == 0) {
    return 0;
  }
  if (strcasecmp(tag, "unimplemented") == 0) {
    return 1;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<OneWireBusReset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  or     $0x1,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void OneWireBusReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x00000001;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<OneWireBusReset>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void OneWireBusReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x00000001;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<OneWireBusReset>:
  endbr64
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void OneWireBusReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) |= 0x00000001;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ints_array_htons>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <htons@plt>
  mov    %ax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void ints_array_htons(short *netshort, int nmemb) {
  int i;
  for (i = 0; i < nmemb; i++)
    netshort[i] = htons(netshort[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ints_array_htons>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x2(%rdi,%rax,2),%rbp
L17:
  movswl (%rbx),%edi
  call   <htons@plt>
  mov    %ax,(%rbx)
  add    $0x2,%rbx
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  ret
```

assistant: ```c
void ints_array_htons(short *netshort, int nmemb) {
  int i;
  for (i = 0; i < nmemb; i++)
    netshort[i] = htons(netshort[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ints_array_htons>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x2(%rdi,%rax,2),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  movswl (%rbx),%edi
  add    $0x2,%rbx
  call   <htons@plt>
  mov    %ax,-0x2(%rbx)
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void ints_array_htons(short *netshort, int nmemb) {
  int i;
  for (i = 0; i < nmemb; i++)
    netshort[i] = htons(netshort[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ints_array_htons>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x2(%rdi,%rax,2),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  movswl (%rbx),%edi
  add    $0x2,%rbx
  call   <htons@plt>
  mov    %ax,-0x2(%rbx)
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void ints_array_htons(short *netshort, int nmemb) {
  int i;
  for (i = 0; i < nmemb; i++)
    netshort[i] = htons(netshort[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<heaviside>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L11
  mov    $0x1,%eax
  jmp    L18
L11:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int heaviside(double x) {
  if (x > 0) {
    return 1;
  } else {
    return 0;
  }
}
```