user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xc,%ecx
  pxor   %xmm0,%xmm0
  lea    D27(%rip),%r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D47(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rdi
  movl   $0x0,0x20(%rsp)
  lea    0x50(%rsp),%rbx
  movl   $0x0,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x30(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x64(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbp
  movl   $0x0,(%rdi)
L87:
  add    $0x1,%r13d
  mov    %r15,%rdi
  lea    -0x14(%rbp),%r14
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <printf@plt>
L56:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x4,%r14
  call   <scanf@plt>
  cmp    %rbp,%r14
  jne    L56
  lea    0x14(%r14),%rbp
  cmp    $0x5,%r13d
  jne    L87
  lea    0x10(%rsp),%r12
  lea    0x64(%rbx),%rsi
  mov    %rbx,%rdx
  xor    %eax,%eax
  mov    %r12,%rcx
L89:
  add    (%rdx),%eax
  add    $0x14,%rdx
  add    -0x10(%rdx),%eax
  add    $0x4,%rcx
  add    -0xc(%rdx),%eax
  add    -0x8(%rdx),%eax
  add    -0x4(%rdx),%eax
  mov    %eax,-0x4(%rcx)
  cmp    %rsi,%rdx
  je     L45
  mov    (%rcx),%eax
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L45:
  lea    0x30(%rsp),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdx
L2:
  add    (%rbx),%eax
  add    0x14(%rbx),%eax
  add    $0x4,%rdx
  add    $0x4,%rbx
  add    0x24(%rbx),%eax
  add    0x38(%rbx),%eax
  add    0x4c(%rbx),%eax
  mov    %eax,-0x4(%rdx)
  cmp    0x8(%rsp),%rbx
  je     L20
  mov    (%rdx),%eax
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  lea    0x14(%r12),%r13
  call   <printf@plt>
  lea    D1(%rip),%rbx
L61:
  mov    (%r12),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %r12,%r13
  jne    L61
  mov    $0xa,%edi
  lea    0x14(%rbp),%r12
  call   <putchar@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L35:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D27
data_type: string
name: read_data
arguments: data_tag: D47
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string

tool: D27: enter a row %d


tool: D47: %d

tool: D15: row totals:

tool: D1: %d 

tool: D7: column totals:

assistant: ```c
int main(void) {
  int array[5][5] = {{0}};
  int row_totals[5] = {0}, column_totals[5] = {0};
  for (int i = 0; i < 5; i++) {
    printf("enter a row %d\n", i + 1);
    for (int j = 0; j < 5; j++) {
      scanf("%d", &array[i][j]);
    }
  }
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
      row_totals[i] += array[i][j];
    }
  }
  for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
      column_totals[i] += array[j][i];
    }
  }
  printf("row totals:");
  for (int i = 0; i < 5; i++) {
    printf("%d ", row_totals[i]);
  }
  printf("\n");
  printf("column totals:");
  for (int i = 0; i < 5; i++) {
    printf("%d ", column_totals[i]);
  }
  printf("\n");
  return 0;
}
```