ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x8,%edx
  lea    D0(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x5,%edx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  shr    $0x3f,%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string
name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D0: blubber

tool: D8: fnord

assistant: ```c
int main() {
  const char *test = "blubber";
  assert(memcmp(test, "blubber", 8) == 0);
  assert(memcmp(test, "fnord", 5) < 0);
  assert(memcmp(test, 0, 0) == 0);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%edx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  shr    $0x3f,%rax
  mov    %rax,%rdi
  call   <assert@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: string

tool: D1: blubber

tool: D11: fnord

assistant: ```c
int main() {
  const char *test = "blubber";
  assert(memcmp(test, "blubber", 8) == 0);
  assert(memcmp(test, "fnord", 5) < 0);
  assert(memcmp(test, 0, 0) == 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  shr    $0x3f,%rax
  mov    %rax,%rdi
  call   <assert@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D13: blubber

tool: D19: fnord

assistant: ```c
int main() {
  const char *test = "blubber";
  assert(memcmp(test, "blubber", 8) == 0);
  assert(memcmp(test, "fnord", 5) < 0);
  assert(memcmp(test, 0, 0) == 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jacFun_name_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  cmpl   $0x1,-0x4(%rbp)
  je     L23
  jmp    L39
L6:
  lea    D11(%rip),%rax
  jmp    L5
L23:
  lea    D19(%rip),%rax
  jmp    L5
L39:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D11: i0

tool: D19: i1

assistant: ```c
const char *jacFun_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<jacFun_name_in>:
  endbr64
  lea    D17(%rip),%rax
  test   %edi,%edi
  je     L2
  cmp    $0x1,%edi
  lea    D2(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L2:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D17: i0

tool: D2: i1

assistant: ```c
const char *jacFun_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<jacFun_name_in>:
  endbr64
  lea    D15(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D12(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D12
datatype: string

tool: D15: i0

tool: D12: i1

assistant: ```c
const char *jacFun_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jacFun_name_in>:
  endbr64
  lea    D3(%rip),%rax
  test   %edi,%edi
  je     L7
  cmp    $0x1,%edi
  lea    D19(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string

tool: D3: i0

tool: D19: i1

assistant: ```c
const char *jacFun_name_in(int i) {
  switch (i) {
  case 0:
    return "i0";
  case 1:
    return "i1";
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L13
  mov    $0x1,%eax
  jmp    L17
L13:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: hello container world [%s]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    return 1;
  }
  printf("hello container world [%s]\n", argv[1]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: hello container world [%s]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    return 1;
  }
  printf("hello container world [%s]\n", argv[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L8
  mov    $0x1,%eax
  ret
L8:
  push   %rax
  mov    0x8(%rsi),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: hello container world [%s]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    return 1;
  }
  printf("hello container world [%s]\n", argv[1]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  je     L9
  mov    $0x1,%eax
  ret
L9:
  push   %rax
  mov    0x8(%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rdx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: hello container world [%s]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    return 1;
  }
  printf("hello container world [%s]\n", argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<chuul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    D10(%rip),%rdx
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nicename@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L11:
  mov    $0xa,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %ebx,%eax
  lea    0x21(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string
name: read_data
arguments: tag: D19
type_infered: string

tool: D10: MM 40

tool: D17: chuul

tool: D19: %d: %d hp, 16 AC

assistant: ```c
void chuul(unsigned count) {
  int i;
  nicename(count, "chuul", "MM 40");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp, 16 AC", i + 1, d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + 33);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chuul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    D18(%rip),%rdx
  lea    D16(%rip),%rsi
  call   <nicename@plt>
  test   %r12d,%r12d
  je     L10
  mov    $0x0,%ebp
  lea    D25(%rip),%r13
L6:
  mov    $0xa,%edi
  call   <d@plt>
  mov    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    %eax,%ebx
  mov    $0xa,%edi
  call   <d@plt>
  add    $0x1,%ebp
  lea    0x21(%rbx,%rax,1),%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%ebp
  jne    L6
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string

tool: D18: MM 40

tool: D16: chuul

tool: D25: %d: %d hp, 16 AC

assistant: ```c
void chuul(unsigned count) {
  int i;
  nicename(count, "chuul", "MM 40");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp, 16 AC", i + 1, d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + 33);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chuul>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdx
  lea    D16(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <nicename@plt>
  test   %ebp,%ebp
  je     L9
  xor    %r13d,%r13d
  lea    D22(%rip),%r12
  nopl   (%rax)
L1:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <d@plt>
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    %r12,%rdi
  mov    %r13d,%esi
  lea    0x21(%rbx,%rax,1),%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebp,%r13d
  jne    L1
L9:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D22
data_type: string

tool: D3: MM 40

tool: D16: chuul

tool: D22: %d: %d hp, 16 AC

assistant: ```c
void chuul(unsigned count) {
  int i;
  nicename(count, "chuul", "MM 40");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp, 16 AC", i + 1, d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + 33);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chuul>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdx
  lea    D18(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <nicename@plt>
  test   %ebp,%ebp
  je     L18
  xor    %r13d,%r13d
  lea    D11(%rip),%r12
  nopl   (%rax)
L7:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <d@plt>
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    $0xa,%edi
  add    %eax,%ebx
  call   <d@plt>
  mov    %r12,%rdi
  mov    %r13d,%esi
  lea    0x21(%rbx,%rax,1),%edx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebp,%r13d
  jne    L7
L18:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D18
datatype: string
name: extract_symbolic_data
arguments: data_label: D11
datatype: string

tool: D17: MM 40

tool: D18: chuul

tool: D11: %d: %d hp, 16 AC

assistant: ```c
void chuul(unsigned count) {
  int i;
  nicename(count, "chuul", "MM 40");
  for (i = 0; i < count; i++) {
    printf("%d: %d hp, 16 AC", i + 1, d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + d(10) + 33);
    (void)putchar('\n');
  }
  (void)putchar('\n');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_end_of_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L54
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L22:
  addq   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    -0x8(%rbp),%rax
  jmp    L47
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L20
  mov    -0x8(%rbp),%rax
  jmp    L47
L20:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L47:
  leave
  ret
```

assistant: ```c
char *find_end_of_text(char *string) {
  char *end = string;
  while (*string != '\0') {
    if (!isspace(*string)) {
      end = string;
    }
    string++;
  }
  if (*end == '\0') {
    return end;
  }
  if (isspace(*end)) {
    return end;
  }
  return end + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_end_of_text>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L35
  mov    %rbx,%rbp
L2:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%rbp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L2
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L30
  movsbl %dil,%edi
  call   <isspace@plt>
  cmp    $0x1,%rax
  adc    $0x0,%rbp
L30:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    %rbx,%rbp
  jmp    L30
```

assistant: ```c
char *find_end_of_text(char *string) {
  char *end = string;
  while (*string != '\0') {
    if (!isspace(*string)) {
      end = string;
    }
    string++;
  }
  if (*end == '\0') {
    return end;
  }
  if (isspace(*end)) {
    return end;
  }
  return end + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_end_of_text>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
  mov    %r12,%rbx
  nopl   0x0(%rax)
L20:
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%r12
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L20
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L3
  call   <isspace@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *find_end_of_text(char *string) {
  char *end = string;
  while (*string != '\0') {
    if (!isspace(*string)) {
      end = string;
    }
    string++;
  }
  if (*end == '\0') {
    return end;
  }
  if (isspace(*end)) {
    return end;
  }
  return end + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_end_of_text>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L22
  mov    %r12,%rbx
  nopl   0x0(%rax)
L27:
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%r12
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L27
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L22
  call   <isspace@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12
L22:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *find_end_of_text(char *string) {
  char *end = string;
  while (*string != '\0') {
    if (!isspace(*string)) {
      end = string;
    }
    string++;
  }
  if (*end == '\0') {
    return end;
  }
  if (isspace(*end)) {
    return end;
  }
  return end + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rb_grandparent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rb_parent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L7
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rb_parent@plt>
L7:
  leave
  ret
```

assistant: ```c
struct rb_node *rb_grandparent(struct rb_node *node) {
  struct rb_node *parent = rb_parent(node);
  if (parent == NULL)
    return NULL;
  return rb_parent(parent);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rb_grandparent>:
  endbr64
  sub    $0x8,%rsp
  call   <rb_parent@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rdi
  call   <rb_parent@plt>
L4:
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct rb_node *rb_grandparent(struct rb_node *node) {
  struct rb_node *parent = rb_parent(node);
  if (parent == NULL)
    return NULL;
  return rb_parent(parent);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rb_grandparent>:
  endbr64
  sub    $0x8,%rsp
  call   <rb_parent@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1050 <rb_parent@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct rb_node *rb_grandparent(struct rb_node *node) {
  struct rb_node *parent = rb_parent(node);
  if (parent == NULL)
    return NULL;
  return rb_parent(parent);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rb_grandparent>:
  endbr64
  sub    $0x8,%rsp
  call   <rb_parent@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1050 <rb_parent@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct rb_node *rb_grandparent(struct rb_node *node) {
  struct rb_node *parent = rb_parent(node);
  if (parent == NULL)
    return NULL;
  return rb_parent(parent);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fgetline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L49
L8:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %r12d,%edx
  mov    %dl,(%rax)
L49:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L40
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,%r12d
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%r12d
  je     L40
  cmp    $0xa,%r12d
  jne    L8
L40:
  cmp    $0xa,%r12d
  jne    L11
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
L11:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int fgetline(char *s, int lim, FILE *stream) {
  register int c, i;
  i = 0;
  while (--lim > 0 && (c = getc(stream)) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fgetline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  cmp    $0x1,%esi
  jle    L47
  mov    %rdx,%r13
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L35:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L44
  cmp    $0xa,%eax
  je     L44
  add    $0x1,%ebx
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L35
  mov    %r12d,%ebx
  jmp    L61
L47:
  mov    $0x0,%ebx
L44:
  cmp    $0xa,%eax
  je     L17
L61:
  movslq %ebx,%rax
  movb   $0x0,(%r14,%rax,1)
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  movslq %ebx,%rax
  movb   $0xa,(%r14,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L61
```

assistant: ```c
int fgetline(char *s, int lim, FILE *stream) {
  register int c, i;
  i = 0;
  while (--lim > 0 && (c = getc(stream)) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fgetline>:
  endbr64
  push   %r15
  mov    %rdi,%rcx
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  jle    L41
  mov    D3(%rip),%r13
  mov    %rdx,%r12
  mov    %rdi,%rbx
  xor    %r15d,%r15d
  jmp    L56
  nopl   0x0(%rax)
L62:
  lea    0x1(%r15),%edx
  cmp    $0xa,%eax
  je     L18
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rbx
  cmp    %ebp,%edx
  je     L11
  mov    %edx,%r15d
L56:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %rbx,%rcx
  cmp    %eax,0x0(%r13)
  jne    L62
  cmp    $0xa,%eax
  je     L21
L41:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  lea    0x1(%r15),%edx
  nopl   (%rax)
L18:
  movslq %edx,%rcx
  movb   $0xa,(%rbx)
  mov    %rcx,%r15
  add    %r14,%rcx
  jmp    L41
  xchg   %ax,%ax
L11:
  movslq %ebp,%rcx
  mov    %ebp,%r15d
  add    %r14,%rcx
  jmp    L41
```

assistant: ```c
int fgetline(char *s, int lim, FILE *stream) {
  register int c, i;
  i = 0;
  while (--lim > 0 && (c = getc(stream)) != EOF && c != '\n')
    s[i++] = c;
  if (c == '\n')
    s[i++] = '\n';
  s[i] = '\0';
  return (i);
}
```