ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prlongname>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  jne    L43
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L41:
  movzbl 0x1(%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L30
L43:
  cmp    $0x3a,%bpl
  jne    L41
L30:
  movb   $0x0,(%rbx)
  mov    %rbx,%rax
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L40:
  cmpb   $0x7c,(%rax)
  je     L9
L51:
  mov    %rax,%rsi
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L40
L9:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %s


assistant: ```c
void prlongname(char *buf) {
  int savech;
  char *p, *savep;
  for (p = buf; *p && *p != ':'; ++p)
    ;
  savech = *(savep = p);
  for (*p = '\0'; p >= buf && *p != '|'; --p)
    ;
  (void)printf("%s\n", p + 1);
  *savep = savech;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prlongname>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  jne    L24
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl 0x1(%rbx),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L2
L24:
  cmp    $0x3a,%bpl
  jne    L9
L2:
  movb   $0x0,(%rbx)
  mov    %rbx,%rax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L41:
  cmpb   $0x7c,(%rax)
  je     L29
L32:
  mov    %rax,%rsi
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L41
L29:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string

tool: D9: %s


assistant: ```c
void prlongname(char *buf) {
  int savech;
  char *p, *savep;
  for (p = buf; *p && *p != ':'; ++p)
    ;
  savech = *(savep = p);
  for (*p = '\0'; p >= buf && *p != '|'; --p)
    ;
  (void)printf("%s\n", p + 1);
  *savep = savech;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CPrintMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x100,%rsp
  mov    %rdi,-0x20d8(%rbp)
  mov    %rsi,-0x20e0(%rbp)
  mov    %edx,-0x20e4(%rbp)
  mov    %rcx,-0x20f0(%rbp)
  mov    %r8d,-0x20e8(%rbp)
  mov    %r9,-0x20f8(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20c8(%rbp)
  mov    -0x20f8(%rbp),%rdx
  mov    -0x20cc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x20e4(%rbp),%eax
  mov    %eax,%edi
  call   <levString@plt>
  mov    %rax,%rdi
  mov    -0x20f0(%rbp),%r8
  mov    -0x20e0(%rbp),%rcx
  mov    -0x20d8(%rbp),%rdx
  lea    -0x20c0(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x20e8(%rbp),%esi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    -0x20cc(%rbp),%edx
  mov    -0x20f8(%rbp),%rcx
  lea    -0x10c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  lea    -0x10c0(%rbp),%rdx
  lea    -0x20c0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x20c8(%rbp)
  mov    -0x20cc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x20c8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: { %s(%s) %s %s, %d }: 

assistant: ```c
void CPrintMessage(char *sModuleName, char *sModuleVersion, int nMesLevel, char *sFuncName, unsigned int uiLine, char *format, ...) {
  char tagMsg[4096];
  char userInputMsg[4096];
  char *outputMsg = NULL;
  va_list pArgList;
  va_start(pArgList, format);
  do {
    sprintf(tagMsg, "{ %s(%s) %s %s, %d }: ", sModuleName, sModuleVersion, levString(nMesLevel), sFuncName, uiLine);
    vsprintf(userInputMsg, format, pArgList);
    outputMsg = strcat(tagMsg, userInputMsg);
  } while (0);
  va_end(pArgList);
  puts(outputMsg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CPrintMessage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r12
  mov    %edx,%r15d
  mov    %rcx,%r13
  mov    %r8d,%r14d
  mov    %r9,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x2018(%rsp)
  xor    %eax,%eax
  mov    %r9,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %r15d,%edi
  call   <levString@plt>
  mov    %rax,%r8
  lea    0x10(%rsp),%r15
  sub    $0x8,%rsp
  push   %r14
  mov    %r13,%r9
  mov    %r12,%rcx
  mov    0x18(%rsp),%rdx
  lea    D2(%rip),%rsi
  mov    %r15,%rdi
  call   <sprintf@plt>
  lea    0x1020(%rsp),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  add    $0x10,%rsp
  mov    0x2018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x2028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: { %s(%s) %s %s, %d }: 

assistant: ```c
void CPrintMessage(char *sModuleName, char *sModuleVersion, int nMesLevel, char *sFuncName, unsigned int uiLine, char *format, ...) {
  char tagMsg[4096];
  char userInputMsg[4096];
  char *outputMsg = NULL;
  va_list pArgList;
  va_start(pArgList, format);
  do {
    sprintf(tagMsg, "{ %s(%s) %s %s, %d }: ", sModuleName, sModuleVersion, levString(nMesLevel), sFuncName, uiLine);
    vsprintf(userInputMsg, format, pArgList);
    outputMsg = strcat(tagMsg, userInputMsg);
  } while (0);
  va_end(pArgList);
  puts(outputMsg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CPrintMessage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  xor    %r12d,%r12d
  mov    %edx,0x8(%rsp)
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %r12d,%edi
  mov    %r9,%rsi
  mov    %r9,%rbp
  mov    %rcx,%rbx
  mov    %r8d,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x2018(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    0x8(%rsp),%edi
  call   <levString@plt>
  lea    0x10(%rsp),%r10
  mov    %rbx,%r9
  mov    %r14,%rcx
  sub    $0x8,%rsp
  mov    %r10,%rdi
  mov    %rax,%r8
  mov    %r13,%rdx
  push   %r15
  lea    D6(%rip),%rsi
  lea    0x1020(%rsp),%r13
  mov    %r10,0x18(%rsp)
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    0x18(%rsp),%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  mov    %r12d,%edi
  mov    %rax,%rbp
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  pop    %rax
  pop    %rdx
  mov    0x2018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x2028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: { %s(%s) %s %s, %d }: 

assistant: ```c
void CPrintMessage(char *sModuleName, char *sModuleVersion, int nMesLevel, char *sFuncName, unsigned int uiLine, char *format, ...) {
  char tagMsg[4096];
  char userInputMsg[4096];
  char *outputMsg = NULL;
  va_list pArgList;
  va_start(pArgList, format);
  do {
    sprintf(tagMsg, "{ %s(%s) %s %s, %d }: ", sModuleName, sModuleVersion, levString(nMesLevel), sFuncName, uiLine);
    vsprintf(userInputMsg, format, pArgList);
    outputMsg = strcat(tagMsg, userInputMsg);
  } while (0);
  va_end(pArgList);
  puts(outputMsg);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CPrintMessage>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  xor    %r12d,%r12d
  mov    %edx,0x8(%rsp)
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %r12d,%edi
  mov    %r9,%rsi
  mov    %r9,%rbp
  mov    %rcx,%rbx
  mov    %r8d,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x2018(%rsp)
  xor    %eax,%eax
  call   <va_start@plt>
  mov    0x8(%rsp),%edi
  call   <levString@plt>
  lea    0x10(%rsp),%r10
  mov    %rbx,%r9
  mov    %r14,%rcx
  sub    $0x8,%rsp
  mov    %r10,%rdi
  mov    %rax,%r8
  mov    %r13,%rdx
  push   %r15
  lea    D9(%rip),%rsi
  lea    0x1020(%rsp),%r13
  mov    %r10,0x18(%rsp)
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    0x18(%rsp),%rdi
  mov    %r13,%rsi
  call   <strcat@plt>
  mov    %r12d,%edi
  mov    %rax,%rbp
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  pop    %rax
  pop    %rdx
  mov    0x2018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: { %s(%s) %s %s, %d }: 

assistant: ```c
void CPrintMessage(char *sModuleName, char *sModuleVersion, int nMesLevel, char *sFuncName, unsigned int uiLine, char *format, ...) {
  char tagMsg[4096];
  char userInputMsg[4096];
  char *outputMsg = NULL;
  va_list pArgList;
  va_start(pArgList, format);
  do {
    sprintf(tagMsg, "{ %s(%s) %s %s, %d }: ", sModuleName, sModuleVersion, levString(nMesLevel), sFuncName, uiLine);
    vsprintf(userInputMsg, format, pArgList);
    outputMsg = strcat(tagMsg, userInputMsg);
  } while (0);
  va_end(pArgList);
  puts(outputMsg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<singleNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L58:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L58
  mov    -0x14(%rbp),%eax
  neg    %eax
  and    %eax,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x2,(%rax)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L55
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L24
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L36
L24:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L36:
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *singleNumber(int *nums, int numsSize, int *returnSize) {
  int x = 0;
  for (int i = 0; i < numsSize; i++) {
    x ^= nums[i];
  }
  x &= -x;
  *returnSize = 2;
  int *res = (int *)malloc(2 * sizeof(int));
  memset(res, 0, 2 * sizeof(int));
  for (int i = 0; i < numsSize; i++) {
    if ((nums[i] & x) == 0) {
      res[0] ^= nums[i];
    } else {
      res[1] ^= nums[i];
    }
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<singleNumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L50
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  mov    $0x0,%eax
L45:
  xor    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %r12,%rdi
  jne    L45
  mov    %eax,%ecx
  neg    %ecx
  and    %ecx,%eax
  mov    %eax,%r13d
  movl   $0x2,(%rdx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L15
L8:
  xor    %edx,0x4(%rbp)
L21:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L28
L15:
  mov    (%rbx),%edx
  test   %r13d,%edx
  jne    L8
  xor    %edx,0x0(%rbp)
  jmp    L21
L50:
  movl   $0x2,(%rdx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L28:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *singleNumber(int *nums, int numsSize, int *returnSize) {
  int x = 0;
  for (int i = 0; i < numsSize; i++) {
    x ^= nums[i];
  }
  x &= -x;
  *returnSize = 2;
  int *res = (int *)malloc(2 * sizeof(int));
  memset(res, 0, 2 * sizeof(int));
  for (int i = 0; i < numsSize; i++) {
    if ((nums[i] & x) == 0) {
      res[0] ^= nums[i];
    } else {
      res[1] ^= nums[i];
    }
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<singleNumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  xor    %ecx,%ecx
  lea    0x4(%rdi,%rax,4),%r13
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L20:
  xor    (%rax),%ecx
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L20
  movl   $0x2,(%rdx)
  mov    %ecx,%eax
  mov    $0x8,%edi
  neg    %eax
  and    %eax,%ecx
  mov    %ecx,%ebp
  call   <malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  jmp    L6
  nop
L46:
  add    $0x4,%rbx
  xor    %edx,(%r12)
  cmp    %r13,%rbx
  je     L38
L6:
  mov    (%rbx),%edx
  test   %ebp,%edx
  je     L46
  add    $0x4,%rbx
  xor    %edx,0x4(%r12)
  cmp    %r13,%rbx
  jne    L6
L38:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L14:
  movl   $0x2,(%rdx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *singleNumber(int *nums, int numsSize, int *returnSize) {
  int x = 0;
  for (int i = 0; i < numsSize; i++) {
    x ^= nums[i];
  }
  x &= -x;
  *returnSize = 2;
  int *res = (int *)malloc(2 * sizeof(int));
  memset(res, 0, 2 * sizeof(int));
  for (int i = 0; i < numsSize; i++) {
    if ((nums[i] & x) == 0) {
      res[0] ^= nums[i];
    } else {
      res[1] ^= nums[i];
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<singleNumber>:
  endbr64
  push   %r13
  mov    %esi,%ecx
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  jle    L82
  lea    -0x1(%rcx),%r13d
  mov    %rdi,%rbx
  cmp    $0x2,%r13d
  jbe    L48
  mov    %ecx,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L97:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L97
  movdqa %xmm0,%xmm1
  mov    %ecx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%ebp
  test   $0x3,%cl
  je     L11
L98:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rdi
  xor    (%rbx,%rdx,4),%ebp
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jle    L11
  add    $0x2,%eax
  xor    0x4(%rbx,%rdi,1),%ebp
  cmp    %eax,%ecx
  jle    L11
  xor    0x8(%rbx,%rdi,1),%ebp
L11:
  movl   $0x2,(%rsi)
  mov    %ebp,%eax
  mov    $0x8,%edi
  neg    %eax
  and    %eax,%ebp
  call   <malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    %rbx,%rdx
  lea    0x4(%rbx,%r13,4),%rax
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L61:
  add    $0x4,%rdx
  xor    %ecx,(%r12)
  cmp    %rax,%rdx
  je     L40
L29:
  mov    (%rdx),%ecx
  test   %ebp,%ecx
  je     L61
  add    $0x4,%rdx
  xor    %ecx,0x4(%r12)
  cmp    %rax,%rdx
  jne    L29
L40:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L82:
  movl   $0x2,(%rdx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  xor    %eax,%eax
  xor    %ebp,%ebp
  jmp    L98
```

assistant: ```c
int *singleNumber(int *nums, int numsSize, int *returnSize) {
  int x = 0;
  for (int i = 0; i < numsSize; i++) {
    x ^= nums[i];
  }
  x &= -x;
  *returnSize = 2;
  int *res = (int *)malloc(2 * sizeof(int));
  memset(res, 0, 2 * sizeof(int));
  for (int i = 0; i < numsSize; i++) {
    if ((nums[i] & x) == 0) {
      res[0] ^= nums[i];
    } else {
      res[1] ^= nums[i];
    }
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply4x4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  jmp    L32
L27:
  movl   $0x0,-0x54(%rbp)
  jmp    L11
L49:
  mov    -0x58(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x58(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x54(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x58(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x54(%rbp),%eax
  cltq
  add    $0x8,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x58(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x54(%rbp),%eax
  cltq
  add    $0xc,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x58(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x54(%rbp),%eax
  add    %edx,%eax
  addss  %xmm1,%xmm0
  cltq
  movss  %xmm0,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x54(%rbp)
L11:
  cmpl   $0x3,-0x54(%rbp)
  jle    L49
  addl   $0x1,-0x58(%rbp)
L32:
  cmpl   $0x3,-0x58(%rbp)
  jle    L27
  lea    -0x50(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void multiply4x4(float *m1, const float *m2) {
  float temp[16];
  int x, y;
  for (x = 0; x < 4; x++) {
    for (y = 0; y < 4; y++) {
      temp[y + (x * 4)] = (m1[x * 4] * m2[y]) + (m1[(x * 4) + 1] * m2[y + 4]) + (m1[(x * 4) + 2] * m2[y + 8]) + (m1[(x * 4) + 3] * m2[y + 12]);
    }
  }
  memcpy(m1, temp, sizeof(float) << 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply4x4>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rcx
  mov    %rsp,%rdx
  mov    $0x0,%edi
L5:
  movss  (%rcx),%xmm5
  movss  0x4(%rcx),%xmm4
  movss  0x8(%rcx),%xmm3
  movss  0xc(%rcx),%xmm2
  mov    $0x0,%eax
L17:
  movaps %xmm5,%xmm0
  mulss  (%rsi,%rax,1),%xmm0
  movaps %xmm4,%xmm1
  mulss  0x10(%rsi,%rax,1),%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm3,%xmm1
  mulss  0x20(%rsi,%rax,1),%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm2,%xmm1
  mulss  0x30(%rsi,%rax,1),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L17
  add    $0x10,%rcx
  add    $0x4,%edi
  add    $0x10,%rdx
  cmp    $0x10,%edi
  jne    L5
  mov    %rsp,%rsi
  mov    $0x40,%edx
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x58,%rsp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void multiply4x4(float *m1, const float *m2) {
  float temp[16];
  int x, y;
  for (x = 0; x < 4; x++) {
    for (y = 0; y < 4; y++) {
      temp[y + (x * 4)] = (m1[x * 4] * m2[y]) + (m1[(x * 4) + 1] * m2[y + 4]) + (m1[(x * 4) + 2] * m2[y + 8]) + (m1[(x * 4) + 3] * m2[y + 12]);
    }
  }
  memcpy(m1, temp, sizeof(float) << 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply4x4>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%r8
  mov    %rdi,%rcx
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r9,%rdx
L11:
  movss  (%rcx),%xmm5
  movss  0x4(%rcx),%xmm4
  xor    %eax,%eax
  movss  0x8(%rcx),%xmm3
  movss  0xc(%rcx),%xmm2
L29:
  movss  (%rsi,%rax,1),%xmm0
  movss  0x10(%rsi,%rax,1),%xmm1
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rsi,%rax,1),%xmm1
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rsi,%rax,1),%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L29
  add    $0x4,%edi
  add    $0x10,%rcx
  add    $0x10,%rdx
  cmp    $0x10,%edi
  jne    L11
  mov    $0x40,%edx
  mov    %r9,%rsi
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x58,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void multiply4x4(float *m1, const float *m2) {
  float temp[16];
  int x, y;
  for (x = 0; x < 4; x++) {
    for (y = 0; y < 4; y++) {
      temp[y + (x * 4)] = (m1[x * 4] * m2[y]) + (m1[(x * 4) + 1] * m2[y + 4]) + (m1[(x * 4) + 2] * m2[y + 8]) + (m1[(x * 4) + 3] * m2[y + 12]);
    }
  }
  memcpy(m1, temp, sizeof(float) << 4);
}
```