ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EEPROMBlockUnlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  mov    $0x400af000,%eax
  mov    (%rax),%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %rax,-0x8(%rbp)
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  cmpq   $0x3,-0x18(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  mov    $0x400af004,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400af020,%eax
  mov    $0xffffffff,%ecx
  mov    %rcx,(%rax)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  sub    $0x8,%rax
  add    %rax,-0x10(%rbp)
  jmp    L5
L0:
  mov    -0x10(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    $0x400af020,%edx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subq   $0x1,-0x18(%rbp)
L5:
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x400af020,%eax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
unsigned long EEPROMBlockUnlock(unsigned long ulBlock, unsigned long *pulPassword, unsigned long ulCount) {
  DEBUG_ASSERT(pulPassword);
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  DEBUG_ASSERT(ulCount <= 3);
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF020))) = 0xFFFFFFFF;
  pulPassword += (ulCount - 1);
  while (ulCount) {
    (*((volatile unsigned long *)(0x400AF020))) = *pulPassword--;
    ulCount--;
  }
  return ((*((volatile unsigned long *)(0x400AF020))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<EEPROMBlockUnlock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  mov    0x400af000,%rax
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %r12,%rax
  seta   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  cmp    $0x3,%rbx
  setbe  %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <DEBUG_ASSERT@plt>
  mov    %r12,0x400af004
  mov    $0xffffffff,%eax
  mov    %rax,0x400af020
  test   %rbx,%rbx
  je     L15
  lea    -0x8(,%rbx,8),%rax
  mov    %rbx,%rdx
  neg    %rdx
  lea    (%rax,%rdx,8),%rax
  lea    0x0(%rbp,%rax,1),%rdx
L3:
  mov    (%rdx,%rbx,8),%rax
  mov    %rax,0x400af020
  sub    $0x1,%rbx
  jne    L3
L15:
  mov    0x400af020,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long EEPROMBlockUnlock(unsigned long ulBlock, unsigned long *pulPassword, unsigned long ulCount) {
  DEBUG_ASSERT(pulPassword);
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  DEBUG_ASSERT(ulCount <= 3);
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF020))) = 0xFFFFFFFF;
  pulPassword += (ulCount - 1);
  while (ulCount) {
    (*((volatile unsigned long *)(0x400AF020))) = *pulPassword--;
    ulCount--;
  }
  return ((*((volatile unsigned long *)(0x400AF020))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<EEPROMBlockUnlock>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <DEBUG_ASSERT@plt>
  mov    0x400af000,%rax
  xor    %edi,%edi
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %r12,%rax
  seta   %dil
  xor    %eax,%eax
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%rbx
  setbe  %dil
  xor    %eax,%eax
  call   <DEBUG_ASSERT@plt>
  mov    $0xffffffff,%eax
  mov    %r12,0x400af004
  mov    %rax,0x400af020
  test   %rbx,%rbx
  je     L8
  lea    -0x8(%rbp),%rsi
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rbx,8),%rax
  mov    %rax,0x400af020
  sub    $0x1,%rbx
  jne    L6
L8:
  pop    %rbx
  mov    0x400af020,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long EEPROMBlockUnlock(unsigned long ulBlock, unsigned long *pulPassword, unsigned long ulCount) {
  DEBUG_ASSERT(pulPassword);
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  DEBUG_ASSERT(ulCount <= 3);
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF020))) = 0xFFFFFFFF;
  pulPassword += (ulCount - 1);
  while (ulCount) {
    (*((volatile unsigned long *)(0x400AF020))) = *pulPassword--;
    ulCount--;
  }
  return ((*((volatile unsigned long *)(0x400AF020))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EEPROMBlockUnlock>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <DEBUG_ASSERT@plt>
  mov    0x400af000,%rax
  xor    %edi,%edi
  shr    $0x10,%rax
  and    $0x7ff,%eax
  cmp    %r12,%rax
  seta   %dil
  xor    %eax,%eax
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x3,%rbx
  setbe  %dil
  xor    %eax,%eax
  call   <DEBUG_ASSERT@plt>
  mov    $0xffffffff,%eax
  mov    %r12,0x400af004
  mov    %rax,0x400af020
  test   %rbx,%rbx
  je     L5
  lea    -0x8(%rbp),%rsi
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rsi,%rbx,8),%rax
  mov    %rax,0x400af020
  sub    $0x1,%rbx
  jne    L19
L5:
  pop    %rbx
  mov    0x400af020,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long EEPROMBlockUnlock(unsigned long ulBlock, unsigned long *pulPassword, unsigned long ulCount) {
  DEBUG_ASSERT(pulPassword);
  DEBUG_ASSERT(ulBlock < ((((*((volatile unsigned long *)(0x400AF000)))) & 0x07FF0000) >> 16));
  DEBUG_ASSERT(ulCount <= 3);
  (*((volatile unsigned long *)(0x400AF004))) = ulBlock;
  (*((volatile unsigned long *)(0x400AF020))) = 0xFFFFFFFF;
  pulPassword += (ulCount - 1);
  while (ulCount) {
    (*((volatile unsigned long *)(0x400AF020))) = *pulPassword--;
    ulCount--;
  }
  return ((*((volatile unsigned long *)(0x400AF020))));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<LOAD_EA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8b,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LOAD_EA() {
  addbyte(0x8b);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(0x24);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LOAD_EA>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8b,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LOAD_EA() {
  addbyte(0x8b);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(0x24);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<LOAD_EA>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8b,%edi
  call   <addbyte@plt>
  mov    $0x44,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  call   <addbyte@plt>
  mov    $0x24,%edi
  add    $0x8,%rsp
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void LOAD_EA() {
  addbyte(0x8b);
  addbyte(0x44);
  addbyte(0x24);
  addbyte(0x24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<credential_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xb,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  imul   $0x186a0,%rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  imul   $0x2710,%rax,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xd,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  imul   $0x3e8,%rax,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xe,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xf,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toint@plt>
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long int credential_number(char fascn[40]) {
  long int temp;
  temp = toint(fascn[11]) * 100000;
  temp += toint(fascn[12]) * 10000;
  temp += toint(fascn[13]) * 1000;
  temp += toint(fascn[14]) * 100;
  temp += toint(fascn[15]) * 10;
  temp += toint(fascn[16]);
  return (temp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<credential_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0xb(%rdi),%edi
  call   <toint@plt>
  imul   $0x186a0,%rax,%rbp
  movsbl 0xc(%rbx),%edi
  call   <toint@plt>
  imul   $0x2710,%rax,%r12
  add    %rbp,%r12
  movsbl 0xd(%rbx),%edi
  call   <toint@plt>
  imul   $0x3e8,%rax,%rbp
  add    %r12,%rbp
  movsbl 0xe(%rbx),%edi
  call   <toint@plt>
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rbp
  movsbl 0xf(%rbx),%edi
  call   <toint@plt>
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,2),%rbp
  movsbl 0x10(%rbx),%edi
  call   <toint@plt>
  add    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long int credential_number(char fascn[40]) {
  long int temp;
  temp = toint(fascn[11]) * 100000;
  temp += toint(fascn[12]) * 10000;
  temp += toint(fascn[13]) * 1000;
  temp += toint(fascn[14]) * 100;
  temp += toint(fascn[15]) * 10;
  temp += toint(fascn[16]);
  return (temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<credential_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0xb(%rdi),%edi
  call   <toint@plt>
  movsbl 0xc(%rbx),%edi
  imul   $0x186a0,%rax,%rbp
  call   <toint@plt>
  movsbl 0xd(%rbx),%edi
  imul   $0x2710,%rax,%r12
  call   <toint@plt>
  movsbl 0xe(%rbx),%edi
  add    %rbp,%r12
  imul   $0x3e8,%rax,%rbp
  call   <toint@plt>
  movsbl 0xf(%rbx),%edi
  lea    (%rax,%rax,4),%rax
  add    %r12,%rbp
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rbp
  call   <toint@plt>
  movsbl 0x10(%rbx),%edi
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,2),%rbp
  call   <toint@plt>
  pop    %rbx
  add    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long int credential_number(char fascn[40]) {
  long int temp;
  temp = toint(fascn[11]) * 100000;
  temp += toint(fascn[12]) * 10000;
  temp += toint(fascn[13]) * 1000;
  temp += toint(fascn[14]) * 100;
  temp += toint(fascn[15]) * 10;
  temp += toint(fascn[16]);
  return (temp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<credential_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0xb(%rdi),%edi
  call   <toint@plt>
  movsbl 0xc(%rbx),%edi
  imul   $0x186a0,%rax,%rbp
  call   <toint@plt>
  movsbl 0xd(%rbx),%edi
  imul   $0x2710,%rax,%r12
  call   <toint@plt>
  movsbl 0xe(%rbx),%edi
  add    %rbp,%r12
  imul   $0x3e8,%rax,%rbp
  call   <toint@plt>
  movsbl 0xf(%rbx),%edi
  lea    (%rax,%rax,4),%rax
  add    %r12,%rbp
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rbp
  call   <toint@plt>
  movsbl 0x10(%rbx),%edi
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,2),%rbp
  call   <toint@plt>
  pop    %rbx
  add    %rbp,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long int credential_number(char fascn[40]) {
  long int temp;
  temp = toint(fascn[11]) * 100000;
  temp += toint(fascn[12]) * 10000;
  temp += toint(fascn[13]) * 1000;
  temp += toint(fascn[14]) * 100;
  temp += toint(fascn[15]) * 10;
  temp += toint(fascn[16]);
  return (temp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ex3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc0(%rbp)
  movl   $0x2,-0xbc(%rbp)
  movl   $0x3,-0xb8(%rbp)
  movl   $0x9,-0xb4(%rbp)
  movl   $0x5,-0xb0(%rbp)
  movl   $0x6,-0xac(%rbp)
  movl   $0x7,-0xa8(%rbp)
  movl   $0x8,-0xa4(%rbp)
  movl   $0x0,-0xa0(%rbp)
  movl   $0x4,-0x9c(%rbp)
  movl   $0x0,-0x60(%rbp)
  movl   $0x3,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x4,-0x54(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x1,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x0,-0xd4(%rbp)
  movl   $0x0,-0xd0(%rbp)
  jmp    L9
L72:
  movl   $0x0,-0xcc(%rbp)
  jmp    L19
L75:
  mov    -0xd0(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%edx
  mov    -0xcc(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L74
  movl   $0x0,-0xc8(%rbp)
  movl   $0x0,-0xc4(%rbp)
  jmp    L83
L38:
  mov    -0xc4(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0xd0(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L108
  movl   $0x1,-0xc8(%rbp)
L108:
  addl   $0x1,-0xc4(%rbp)
L83:
  mov    -0xc4(%rbp),%eax
  cmp    -0xd4(%rbp),%eax
  jl     L38
  cmpl   $0x0,-0xc8(%rbp)
  jne    L74
  mov    -0xd4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xd4(%rbp)
  mov    -0xd0(%rbp),%edx
  movslq %edx,%rdx
  mov    -0xc0(%rbp,%rdx,4),%edx
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  jmp    L13
L74:
  addl   $0x1,-0xcc(%rbp)
L19:
  cmpl   $0x13,-0xcc(%rbp)
  jle    L75
L13:
  addl   $0x1,-0xd0(%rbp)
L9:
  cmpl   $0x9,-0xd0(%rbp)
  jle    L72
  mov    -0xd4(%rbp),%edx
  lea    -0x90(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertionSort@plt>
  mov    -0xd4(%rbp),%ecx
  lea    -0x90(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printIArray@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: Conjunto Semelhanca: 

assistant: ```c
void ex3() {
  int a[10] = {1, 2, 3, 9, 5, 6, 7, 8, 0, 4};
  int b[20] = {0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2};
  int out[10];
  int j = 0;
  for (int i = 0; i < 10; i++) {
    for (int k = 0; k < 20; k++) {
      if (a[i] == b[k]) {
        int test = 0;
        for (int l = 0; l < j; l++) {
          if (out[l] == a[i])
            test = 1;
        }
        if (!test) {
          out[j++] = a[i];
          break;
        }
      }
    }
  }
  insertionSort(out, j);
  printIArray(out, j, "Conjunto Semelhanca: ");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ex3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x4,0x24(%rsp)
  movl   $0x0,0x60(%rsp)
  movl   $0x3,0x64(%rsp)
  movl   $0x0,0x68(%rsp)
  movl   $0x4,0x6c(%rsp)
  movl   $0x0,0x70(%rsp)
  movl   $0x0,0x74(%rsp)
  movl   $0x0,0x78(%rsp)
  movl   $0x0,0x7c(%rsp)
  movl   $0x0,0x80(%rsp)
  movl   $0x0,0x84(%rsp)
  movl   $0x1,0x88(%rsp)
  movl   $0x1,0x8c(%rsp)
  movl   $0x1,0x90(%rsp)
  movl   $0x1,0x94(%rsp)
  movl   $0x1,0x98(%rsp)
  movl   $0x2,0x9c(%rsp)
  movl   $0x2,0xa0(%rsp)
  movl   $0x2,0xa4(%rsp)
  movl   $0x2,0xa8(%rsp)
  movl   $0x2,0xac(%rsp)
  mov    %rsp,%r11
  lea    0x28(%rsp),%r12
  mov    $0x0,%ebx
  lea    0xb0(%rsp),%r9
  lea    0x30(%rsp),%r10
  lea    0x34(%rsp),%rbp
  mov    $0x1,%r8d
  jmp    L47
L33:
  test   %edx,%edx
  je     L97
L88:
  add    $0x4,%rcx
  cmp    %r9,%rcx
  je     L43
L42:
  cmp    (%rcx),%esi
  jne    L88
  test   %ebx,%ebx
  jle    L97
  mov    %r10,%rax
  mov    $0x0,%edx
L20:
  cmp    (%rax),%esi
  cmove  %r8d,%edx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L20
  jmp    L33
L97:
  movslq %ebx,%rax
  mov    %esi,0x30(%rsp,%rax,4)
  lea    0x1(%rbx),%ebx
L43:
  add    $0x4,%r11
  cmp    %r12,%r11
  je     L11
L47:
  mov    (%r11),%esi
  lea    0x60(%rsp),%rcx
  lea    -0x1(%rbx),%eax
  lea    0x0(%rbp,%rax,4),%rdi
  jmp    L42
L11:
  lea    0x30(%rsp),%rbp
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <insertionSort@plt>
  lea    D6(%rip),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printIArray@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D6: Conjunto Semelhanca: 

assistant: ```c
void ex3() {
  int a[10] = {1, 2, 3, 9, 5, 6, 7, 8, 0, 4};
  int b[20] = {0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2};
  int out[10];
  int j = 0;
  for (int i = 0; i < 10; i++) {
    for (int k = 0; k < 20; k++) {
      if (a[i] == b[k]) {
        int test = 0;
        for (int l = 0; l < j; l++) {
          if (out[l] == a[i])
            test = 1;
        }
        if (!test) {
          out[j++] = a[i];
          break;
        }
      }
    }
  }
  insertionSort(out, j);
  printIArray(out, j, "Conjunto Semelhanca: ");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ex3>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x1,%r8d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r10
  lea    0x28(%rsp),%r13
  movabs $0x900000003,%rax
  mov    %rax,0x8(%rsp)
  lea    0x64(%rsp),%rbx
  movabs $0x600000005,%rax
  lea    0xb0(%rsp),%r9
  mov    %rax,0x10(%rsp)
  lea    0x30(%rsp),%r12
  movabs $0x800000007,%rax
  lea    0x34(%rsp),%r11
  mov    %rax,0x18(%rsp)
  movabs $0x400000000,%rax
  mov    %rax,0x20(%rsp)
  mov    %rax,0x68(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,0x88(%rsp)
  mov    %rax,0x90(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x98(%rsp)
  add    $0x1,%rax
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x64(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  mov    %rax,0xa0(%rsp)
  mov    %rax,0xa8(%rsp)
  nopl   0x0(%rax)
L17:
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdx
  lea    (%r11,%rax,4),%rdi
  xor    %eax,%eax
  jmp    L40
  cs nopw 0x0(%rax,%rax,1)
L25:
  cmp    %r9,%rdx
  je     L10
  mov    (%rdx),%eax
  add    $0x4,%rdx
L40:
  cmp    %esi,%eax
  jne    L25
  test   %ebp,%ebp
  je     L33
  mov    %r12,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L75:
  cmp    %esi,(%rax)
  cmove  %r8d,%ecx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L75
  test   %ecx,%ecx
  jne    L25
  nopl   0x0(%rax,%rax,1)
L33:
  movslq %ebp,%rax
  add    $0x1,%ebp
  mov    %esi,0x30(%rsp,%rax,4)
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %r13,%r10
  je     L64
  mov    (%r10),%esi
  add    $0x4,%r10
  jmp    L17
L64:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <insertionSort@plt>
  lea    D0(%rip),%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printIArray@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: Conjunto Semelhanca: 

assistant: ```c
void ex3() {
  int a[10] = {1, 2, 3, 9, 5, 6, 7, 8, 0, 4};
  int b[20] = {0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2};
  int out[10];
  int j = 0;
  for (int i = 0; i < 10; i++) {
    for (int k = 0; k < 20; k++) {
      if (a[i] == b[k]) {
        int test = 0;
        for (int l = 0; l < j; l++) {
          if (out[l] == a[i])
            test = 1;
        }
        if (!test) {
          out[j++] = a[i];
          break;
        }
      }
    }
  }
  insertionSort(out, j);
  printIArray(out, j, "Conjunto Semelhanca: ");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L19
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: Just read: '%s'


assistant: ```c
int main(void) {
  char buff[10];
  if (gets(buff) != NULL) {
    printf("Just read: '%s'\n", buff);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L11
  lea    0xe(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string

tool: D0: Just read: '%s'


assistant: ```c
int main(void) {
  char buff[10];
  if (gets(buff) != NULL) {
    printf("Just read: '%s'\n", buff);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: Just read: '%s'


assistant: ```c
int main(void) {
  char buff[10];
  if (gets(buff) != NULL) {
    printf("Just read: '%s'\n", buff);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: Just read: '%s'


assistant: ```c
int main(void) {
  char buff[10];
  if (gets(buff) != NULL) {
    printf("Just read: '%s'\n", buff);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <isendwin@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x0,%eax
  call   <endwin@plt>
L7:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shutdown(void) {
  if (!isendwin())
    endwin();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shutdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <isendwin@plt>
  test   %eax,%eax
  je     L1
L11:
  add    $0x8,%rsp
  ret
L1:
  call   <endwin@plt>
  jmp    L11
```

assistant: ```c
void shutdown(void) {
  if (!isendwin())
    endwin();
}
```