ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<USBEndpointDataSend>:
  endbr64
  lea    0x102(%rdi),%rax
  test   %rsi,%rsi
  jne    L16
  movzbl 0x102(%rdi),%ecx
  and    $0x2,%ecx
  jne    L4
  movzbl %dl,%edx
  mov    %dl,(%rax)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L16:
  add    %rsi,%rax
  movzbl (%rax),%ecx
  and    $0x1,%ecx
  jne    L4
  movzbl %dh,%edx
  mov    %dl,(%rax)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long USBEndpointDataSend(unsigned long ulBase, unsigned long ulEndpoint, unsigned long ulTransType) {
  unsigned long ulTxPktRdy;
  ;

  ;
  if (ulEndpoint == 0x00000000) {
    if ((*((volatile unsigned char *)(ulBase + 0x00000102))) & 0x00000002) {
      return (-1);
    }
    ulTxPktRdy = ulTransType & 0xff;
  } else {
    if ((*((volatile unsigned char *)(ulBase + 0x00000102 + ulEndpoint))) & 0x00000001) {
      return (-1);
    }
    ulTxPktRdy = (ulTransType >> 8) & 0xff;
  }
  (*((volatile unsigned char *)(ulBase + 0x00000102 + ulEndpoint))) = ulTxPktRdy;
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <MonitorNetlinkUevent@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorNetlinkUevent();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <MonitorNetlinkUevent@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorNetlinkUevent();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MonitorNetlinkUevent@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorNetlinkUevent();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MonitorNetlinkUevent@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  MonitorNetlinkUevent();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trurl_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <trurl_vdie@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void trurl_die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  trurl_vdie(fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trurl_die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <trurl_vdie@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void trurl_die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  trurl_vdie(fmt, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trurl_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <trurl_vdie@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trurl_die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  trurl_vdie(fmt, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trurl_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <trurl_vdie@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void trurl_die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  trurl_vdie(fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<float_interpolator_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  movss  %xmm1,-0x20(%rbp)
  movss  %xmm2,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movss  %xmm3,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  mulss  -0x2c(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  divss  -0x30(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void float_interpolator_c(float *s, float s_invw, float *e, float e_invw, float t, float *r, float r_invw) {
  float ts = s[0] * s_invw;
  float te = e[0] * e_invw;
  r[0] = (ts + (te - ts) * t) / r_invw;
}
```
user: Translate the below assembly code into C programming language:

```asm
<float_interpolator_c>:
  endbr64
  mulss  (%rdi),%xmm0
  mulss  (%rsi),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  divss  %xmm3,%xmm1
  movss  %xmm1,(%rdx)
  ret
```

assistant: ```c
void float_interpolator_c(float *s, float s_invw, float *e, float e_invw, float t, float *r, float r_invw) {
  float ts = s[0] * s_invw;
  float te = e[0] * e_invw;
  r[0] = (ts + (te - ts) * t) / r_invw;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<float_interpolator_c>:
  endbr64
  mulss  (%rdi),%xmm0
  mulss  (%rsi),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  divss  %xmm3,%xmm1
  movss  %xmm1,(%rdx)
  ret
```

assistant: ```c
void float_interpolator_c(float *s, float s_invw, float *e, float e_invw, float t, float *r, float r_invw) {
  float ts = s[0] * s_invw;
  float te = e[0] * e_invw;
  r[0] = (ts + (te - ts) * t) / r_invw;
}
```
user: What is the c source code of the assembly code below:

```asm
<float_interpolator_c>:
  endbr64
  mulss  (%rdi),%xmm0
  mulss  (%rsi),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  divss  %xmm3,%xmm1
  movss  %xmm1,(%rdx)
  ret
```

assistant: ```c
void float_interpolator_c(float *s, float s_invw, float *e, float e_invw, float t, float *r, float r_invw) {
  float ts = s[0] * s_invw;
  float te = e[0] * e_invw;
  r[0] = (ts + (te - ts) * t) / r_invw;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <log_puts@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <log_putx@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <log_puts@plt>
  mov    $0x0,%eax
  call   <panic@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string

tool: D9: failed to allocate 

tool: D6:  bytes


assistant: ```c
void *xmalloc(size_t size) {
  void *p;
  p = malloc(size);
  if (p == NULL) {
    log_puts("failed to allocate ");
    log_putx(size);
    log_puts(" bytes\n");
    panic();
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D2(%rip),%rdi
  call   <log_puts@plt>
  mov    %rbp,%rdi
  call   <log_putx@plt>
  lea    D8(%rip),%rdi
  call   <log_puts@plt>
  mov    $0x0,%eax
  call   <panic@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D2: failed to allocate 

tool: D8:  bytes


assistant: ```c
void *xmalloc(size_t size) {
  void *p;
  p = malloc(size);
  if (p == NULL) {
    log_puts("failed to allocate ");
    log_putx(size);
    log_puts(" bytes\n");
    panic();
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D14(%rip),%rdi
  call   <log_puts@plt>
  mov    %rbp,%rdi
  call   <log_putx@plt>
  lea    D19(%rip),%rdi
  call   <log_puts@plt>
  xor    %eax,%eax
  call   <panic@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D14
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D14: failed to allocate 

tool: D19:  bytes


assistant: ```c
void *xmalloc(size_t size) {
  void *p;
  p = malloc(size);
  if (p == NULL) {
    log_puts("failed to allocate ");
    log_putx(size);
    log_puts(" bytes\n");
    panic();
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    D15(%rip),%rdi
  call   <log_puts@plt>
  mov    %rbp,%rdi
  call   <log_putx@plt>
  lea    D14(%rip),%rdi
  call   <log_puts@plt>
  xor    %eax,%eax
  call   <panic@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D14
type_guessed: string

tool: D15: failed to allocate 

tool: D14:  bytes


assistant: ```c
void *xmalloc(size_t size) {
  void *p;
  p = malloc(size);
  if (p == NULL) {
    log_puts("failed to allocate ");
    log_putx(size);
    log_puts(" bytes\n");
    panic();
  }
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<highscore_menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <clearscr@plt>
L4:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L4
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  jg     L4
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D40
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D37
type: string

tool: D38: Triplets - Highscores


tool: D16: 
1. 3x3 Highscores

tool: D40: 
2. 6x6 Highscores

tool: D25: 
3. 12x12 Highscores

tool: D20: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D37: %d

assistant: ```c
int highscore_menu() {
  int option;
  clearscr();
  do {
    printf("Triplets - Highscores\n");
    printf("\n1. 3x3 Highscores");
    printf("\n2. 6x6 Highscores");
    printf("\n3. 12x12 Highscores");
    printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
    scanf("%d", &option);
  } while (option < 0 || option > 3);
  return option;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<highscore_menu>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <clearscr@plt>
  lea    D8(%rip),%r13
  lea    D9(%rip),%r12
  lea    D1(%rip),%rbp
  lea    D5(%rip),%rbx
L18:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  ja     L18
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string

tool: D8: Triplets - Highscores


tool: D9: 
1. 3x3 Highscores

tool: D1: 
2. 6x6 Highscores

tool: D5: 
3. 12x12 Highscores

tool: D14: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D11: %d

assistant: ```c
int highscore_menu() {
  int option;
  clearscr();
  do {
    printf("Triplets - Highscores\n");
    printf("\n1. 3x3 Highscores");
    printf("\n2. 6x6 Highscores");
    printf("\n3. 12x12 Highscores");
    printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
    scanf("%d", &option);
  } while (option < 0 || option > 3);
  return option;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<highscore_menu>:
  endbr64
  push   %r15
  lea    D18(%rip),%r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <clearscr@plt>
  nop
L6:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  ja     L6
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D39
type_infered: string

tool: D18: Triplets - Highscores


tool: D7: 
1. 3x3 Highscores

tool: D4: 
2. 6x6 Highscores

tool: D15: 
3. 12x12 Highscores

tool: D29: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D39: %d

assistant: ```c
int highscore_menu() {
  int option;
  clearscr();
  do {
    printf("Triplets - Highscores\n");
    printf("\n1. 3x3 Highscores");
    printf("\n2. 6x6 Highscores");
    printf("\n3. 12x12 Highscores");
    printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
    scanf("%d", &option);
  } while (option < 0 || option > 3);
  return option;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<highscore_menu>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  lea    D32(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <clearscr@plt>
  nop
L12:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x3,%eax
  ja     L12
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string
name: read_data
arguments: data_tag: D32
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D47
type_infered: string
name: read_data
arguments: data_tag: D39
type_infered: string

tool: D7: Triplets - Highscores


tool: D32: 
1. 3x3 Highscores

tool: D4: 
2. 6x6 Highscores

tool: D28: 
3. 12x12 Highscores

tool: D47: 
(Choose an option and press enter).
Insert 0 to return to main menu: 

tool: D39: %d

assistant: ```c
int highscore_menu() {
  int option;
  clearscr();
  do {
    printf("Triplets - Highscores\n");
    printf("\n1. 3x3 Highscores");
    printf("\n2. 6x6 Highscores");
    printf("\n3. 12x12 Highscores");
    printf("\n(Choose an option and press enter).\nInsert 0 to return to main menu: ");
    scanf("%d", &option);
  } while (option < 0 || option > 3);
  return option;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gui_check_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *gui_check_ptr(void *ptr) {
  if (!ptr) {
    abort();
  }
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gui_check_ptr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L7
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
L7:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L17
```

assistant: ```c
void *gui_check_ptr(void *ptr) {
  if (!ptr) {
    abort();
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gui_check_ptr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L7
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *gui_check_ptr(void *ptr) {
  if (!ptr) {
    abort();
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gui_check_ptr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L5
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *gui_check_ptr(void *ptr) {
  if (!ptr) {
    abort();
  }
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L1:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <turn45@plt>
  addl   $0x2d,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int rotate(int *xdir, int *ydir, int turn) {
  int i;
  for (i = 0; i < turn; i += 45) {
    turn45(xdir, ydir);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotate>:
  endbr64
  test   %edx,%edx
  jle    L17
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <turn45@plt>
  add    $0x2d,%ebx
  cmp    %ebx,%ebp
  jg     L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rotate(int *xdir, int *ydir, int turn) {
  int i;
  for (i = 0; i < turn; i += 45) {
    turn45(xdir, ydir);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rotate>:
  endbr64
  test   %edx,%edx
  jle    L9
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x2d,%ebx
  call   <turn45@plt>
  cmp    %ebx,%ebp
  jg     L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotate(int *xdir, int *ydir, int turn) {
  int i;
  for (i = 0; i < turn; i += 45) {
    turn45(xdir, ydir);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate>:
  endbr64
  test   %edx,%edx
  jle    L6
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x2d,%ebx
  call   <turn45@plt>
  cmp    %ebx,%ebp
  jg     L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotate(int *xdir, int *ydir, int turn) {
  int i;
  for (i = 0; i < turn; i += 45) {
    turn45(xdir, ydir);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<countLeadingZeros64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  mov    $0xffffffff,%eax
  cmp    %rax,-0x18(%rbp)
  ja     L10
  movzbl -0x1(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0x1(%rbp)
  jmp    L0
L10:
  shrq   $0x20,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <countLeadingZeros32@plt>
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char countLeadingZeros64(unsigned long long a) {
  char shiftCount;
  shiftCount = 0;
  if (a < ((unsigned long long)1) << 32) {
    shiftCount += 32;
  } else {
    a >>= 32;
  }
  shiftCount += countLeadingZeros32(a);
  return shiftCount;
}
```
user: What is the c source code of the assembly code below:

```asm
<countLeadingZeros64>:
  endbr64
  push   %rbx
  mov    $0x20,%ebx
  mov    %rdi,%rax
  shr    $0x20,%rax
  je     L3
  shr    $0x20,%rdi
  mov    $0x0,%ebx
L3:
  call   <countLeadingZeros32@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char countLeadingZeros64(unsigned long long a) {
  char shiftCount;
  shiftCount = 0;
  if (a < ((unsigned long long)1) << 32) {
    shiftCount += 32;
  } else {
    a >>= 32;
  }
  shiftCount += countLeadingZeros32(a);
  return shiftCount;
}
```