ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_args>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L73
  cmp    $0x2d,%bpl
  je     L73
  add    $0x1,%r12
  jmp    L1
L73:
  mov    $0x20,%ebp
L1:
  mov    $0x0,%edi
  mov    $0x0,%r13d
  cmpb   $0x0,(%r12)
  jne    L113
  jmp    L40
L125:
  mov    %r12,%rbx
L41:
  cmp    (%rbx),%bpl
  jne    L98
L68:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
  cmp    %bpl,(%rbx)
  je     L68
L98:
  mov    %r12,%rsi
  call   <process_arg@plt>
  test   %rax,%rax
  mov    %r12,%rdi
  cmovne %r13,%rdi
  cmpb   $0x0,(%rbx)
  je     L101
  mov    %rbx,%r12
L113:
  movzbl (%r12),%eax
  cmp    %al,%bpl
  je     L125
  mov    %r12,%rbx
  test   %al,%al
  je     L125
L132:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    %bpl,%al
  je     L41
  test   %al,%al
  jne    L132
  jmp    L41
L101:
  test   %rdi,%rdi
  je     L40
  mov    $0x0,%esi
  call   <process_arg@plt>
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void process_args(char *args) {
  char *p, *q, *arg, *prevarg;
  char separator = ' ';
  p = args;
  if (*p && *p != '-')
    separator = *p++;
  arg = NULL;
  while (*p) {
    q = p;
    while (*p && *p != separator)
      p++;
    while (*p == separator)
      *p++ = '\0';
    prevarg = arg;
    arg = q;
    if (process_arg(prevarg, arg))
      arg = NULL;
  }
  if (arg)
    process_arg(arg, NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<process_args>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L81
  cmp    $0x2d,%al
  je     L81
  mov    %eax,%ebp
  movzbl 0x1(%rdi),%eax
  add    $0x1,%r12
  xor    %edi,%edi
  xor    %r13d,%r13d
  test   %al,%al
  jne    L84
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  mov    $0x20,%ebp
  xor    %edi,%edi
  xor    %r13d,%r13d
  test   %al,%al
  je     L21
  nopl   0x0(%rax,%rax,1)
L84:
  mov    %r12,%rbx
  jmp    L73
  nopl   (%rax)
L100:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L79
L73:
  cmp    %bpl,%al
  jne    L100
L79:
  cmp    %al,%bpl
  jne    L11
  xchg   %ax,%ax
L89:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
  cmp    %bpl,(%rbx)
  je     L89
L11:
  mov    %r12,%rsi
  call   <process_arg@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  movzbl (%rbx),%eax
  cmovne %r13,%rdi
  test   %al,%al
  je     L60
  mov    %rbx,%r12
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L60:
  test   %rdi,%rdi
  je     L21
  add    $0x8,%rsp
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <process_arg@plt>
```

assistant: ```c
void process_args(char *args) {
  char *p, *q, *arg, *prevarg;
  char separator = ' ';
  p = args;
  if (*p && *p != '-')
    separator = *p++;
  arg = NULL;
  while (*p) {
    q = p;
    while (*p && *p != separator)
      p++;
    while (*p == separator)
      *p++ = '\0';
    prevarg = arg;
    arg = q;
    if (process_arg(prevarg, arg))
      arg = NULL;
  }
  if (arg)
    process_arg(arg, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_args>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L121
  cmp    $0x2d,%al
  je     L121
  mov    %eax,%ebp
  movzbl 0x1(%rdi),%eax
  add    $0x1,%r12
  xor    %edi,%edi
  xor    %r13d,%r13d
  test   %al,%al
  jne    L97
L55:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L121:
  mov    $0x20,%ebp
  xor    %edi,%edi
  xor    %r13d,%r13d
  test   %al,%al
  je     L55
  nopl   0x0(%rax,%rax,1)
L97:
  mov    %r12,%rbx
  cmp    %al,%bpl
  jne    L51
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L115:
  cmp    %bpl,%al
  je     L86
L51:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L115
L86:
  cmp    %al,%bpl
  jne    L46
  cs nopw 0x0(%rax,%rax,1)
L69:
  add    $0x1,%rbx
  movb   $0x0,-0x1(%rbx)
  cmp    %bpl,(%rbx)
  je     L69
L46:
  mov    %r12,%rsi
  call   <process_arg@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  movzbl (%rbx),%eax
  cmovne %r13,%rdi
  test   %al,%al
  je     L22
  mov    %rbx,%r12
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L22:
  test   %rdi,%rdi
  je     L55
  add    $0x8,%rsp
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <process_arg@plt>
```

assistant: ```c
void process_args(char *args) {
  char *p, *q, *arg, *prevarg;
  char separator = ' ';
  p = args;
  if (*p && *p != '-')
    separator = *p++;
  arg = NULL;
  while (*p) {
    q = p;
    while (*p && *p != separator)
      p++;
    while (*p == separator)
      *p++ = '\0';
    prevarg = arg;
    arg = q;
    if (process_arg(prevarg, arg))
      arg = NULL;
  }
  if (arg)
    process_arg(arg, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    $0x63,%eax
  jg     L6
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  jmp    L4
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
L4:
  leave
  ret
```

assistant: ```c
int inc(int pos, int n) {
  if (pos + n < 100)
    return pos + n;
  else {
    putchar('\n');
    return n;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inc>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  cmp    $0x63,%eax
  jg     L7
  ret
L7:
  push   %rbx
  mov    %esi,%ebx
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int inc(int pos, int n) {
  if (pos + n < 100)
    return pos + n;
  else {
    putchar('\n');
    return n;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inc>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  cmp    $0x63,%eax
  jg     L8
  ret
  nopl   (%rax)
L8:
  push   %rbx
  mov    $0xa,%edi
  mov    %esi,%ebx
  call   <putchar@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int inc(int pos, int n) {
  if (pos + n < 100)
    return pos + n;
  else {
    putchar('\n');
    return n;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inc>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  cmp    $0x63,%eax
  jg     L2
  ret
  nopl   (%rax)
L2:
  push   %rbx
  mov    $0xa,%edi
  mov    %esi,%ebx
  call   <putchar@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int inc(int pos, int n) {
  if (pos + n < 100)
    return pos + n;
  else {
    putchar('\n');
    return n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ring_djb_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L11:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  lea    (%rdx,%rax,1),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned ring_djb_hash(unsigned char *key, int len) {
  unsigned char *p = key;
  unsigned h = 0;
  int i;
  for (i = 0; i < len; i++) {
    h = 33 * h ^ p[i];
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ring_djb_hash>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L12:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  add    %ecx,%eax
  movzbl (%rdx),%ecx
  xor    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned ring_djb_hash(unsigned char *key, int len) {
  unsigned char *p = key;
  unsigned h = 0;
  int i;
  for (i = 0; i < len; i++) {
    h = 33 * h ^ p[i];
  }
  return h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ring_djb_hash>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  xor    %edx,%eax
  cmp    %rcx,%rdi
  jne    L1
  ret
  nop
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned ring_djb_hash(unsigned char *key, int len) {
  unsigned char *p = key;
  unsigned h = 0;
  int i;
  for (i = 0; i < len; i++) {
    h = 33 * h ^ p[i];
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ring_djb_hash>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  add    %edx,%eax
  movzbl -0x1(%rdi),%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L12
  ret
  nop
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned ring_djb_hash(unsigned char *key, int len) {
  unsigned char *p = key;
  unsigned h = 0;
  int i;
  for (i = 0; i < len; i++) {
    h = 33 * h ^ p[i];
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<av_tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L16
  cmpl   $0x5a,-0x4(%rbp)
  jg     L16
  xorl   $0x20,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int av_tolower(int c) {
  if (c >= 'A' && c <= 'Z')
    c ^= 0x20;
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<av_tolower>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%ecx
  mov    %edi,%edx
  xor    $0x20,%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int av_tolower(int c) {
  if (c >= 'A' && c <= 'Z')
    c ^= 0x20;
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<av_tolower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%edx
  mov    %edi,%eax
  xor    $0x20,%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int av_tolower(int c) {
  if (c >= 'A' && c <= 'Z')
    c ^= 0x20;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<av_tolower>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%edx
  mov    %edi,%eax
  xor    $0x20,%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int av_tolower(int c) {
  if (c >= 'A' && c <= 'Z')
    c ^= 0x20;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L9:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double sum(double **arr, int nArr) {
  int i, j;
  double s = 0.0;
  assert(nArr >= 1);
  for (i = 0; i < nArr; i++) {
    for (j = 0; j < nArr; j++) {
      s += arr[i][j];
    }
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %esi,%esi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebx,%ebx
  jle    L38
  mov    %rbp,%rcx
  lea    -0x1(%rbx),%esi
  shl    $0x3,%rsi
  lea    0x8(%rbp,%rsi,1),%rdi
  pxor   %xmm0,%xmm0
  add    $0x8,%rsi
L8:
  mov    (%rcx),%rax
  lea    (%rsi,%rax,1),%rdx
L2:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L2
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  jne    L8
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  pxor   %xmm0,%xmm0
  jmp    L10
```

assistant: ```c
double sum(double **arr, int nArr) {
  int i, j;
  double s = 0.0;
  assert(nArr >= 1);
  for (i = 0; i < nArr; i++) {
    for (j = 0; j < nArr; j++) {
      s += arr[i][j];
    }
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %esi,%esi
  setg   %dil
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L6
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  pxor   %xmm0,%xmm0
  shl    $0x3,%rax
  lea    0x8(%rbx,%rax,1),%rsi
  lea    0x8(%rax),%rcx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rdi),%rax
  lea    (%rcx,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L20:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L20
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double sum(double **arr, int nArr) {
  int i, j;
  double s = 0.0;
  assert(nArr >= 1);
  for (i = 0; i < nArr; i++) {
    for (j = 0; j < nArr; j++) {
      s += arr[i][j];
    }
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %esi,%esi
  setg   %dil
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L34
  lea    -0x1(%rbp),%eax
  mov    %ebp,%esi
  pxor   %xmm0,%xmm0
  mov    %rbx,%rdi
  lea    0x8(%rbx,%rax,8),%r9
  mov    %ebp,%eax
  and    $0xfffffffe,%esi
  shr    %eax
  lea    -0x1(%rax),%r8d
  add    $0x1,%r8
  shl    $0x4,%r8
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rdi),%rdx
  cmp    $0x1,%ebp
  je     L2
  mov    %rdx,%rax
  lea    (%r8,%rdx,1),%rcx
  nop
L39:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L39
  movslq %esi,%rax
  cmp    %ebp,%esi
  je     L52
L56:
  addsd  (%rdx,%rax,8),%xmm0
L52:
  add    $0x8,%rdi
  cmp    %r9,%rdi
  jne    L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  jmp    L56
L34:
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double sum(double **arr, int nArr) {
  int i, j;
  double s = 0.0;
  assert(nArr >= 1);
  for (i = 0; i < nArr; i++) {
    for (j = 0; j < nArr; j++) {
      s += arr[i][j];
    }
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x750,-0x50(%rbp)
  movl   $0x2ea,-0x4c(%rbp)
  movl   $0x6e90,-0x48(%rbp)
  movl   $0x12cf,-0x44(%rbp)
  movl   $0x20c8,-0x40(%rbp)
  movl   $0xb4e,-0x3c(%rbp)
  movl   $0x22104,-0x38(%rbp)
  movl   $0x47eb,-0x34(%rbp)
  movl   $0x3a40,-0x30(%rbp)
  movl   $0x13b2,-0x2c(%rbp)
  movl   $0x3d378,-0x28(%rbp)
  movl   $0x7d07,-0x24(%rbp)
  movl   $0x53b8,-0x20(%rbp)
  movl   $0x1c16,-0x1c(%rbp)
  movl   $0x585ec,-0x18(%rbp)
  movl   $0xb223,-0x14(%rbp)
  mov    $0x0,%eax
  call   <check_vect@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L15
L46:
  mov    -0xd4(%rbp),%eax
  movzbl %al,%edx
  mov    -0xd4(%rbp),%eax
  mov    %edx,-0xd0(%rbp,%rax,4)
  mov    -0xd4(%rbp),%eax
  movl   $0x0,-0x90(%rbp,%rax,4)
  addl   $0x1,-0xd4(%rbp)
L15:
  cmpl   $0xf,-0xd4(%rbp)
  jbe    L46
  lea    -0x90(%rbp),%rdx
  lea    -0xd0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <foo@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L39
L22:
  mov    -0xd4(%rbp),%eax
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0xd4(%rbp),%eax
  mov    -0x50(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  je     L38
  call   <abort@plt>
L38:
  addl   $0x1,-0xd4(%rbp)
L39:
  cmpl   $0xf,-0xd4(%rbp)
  jbe    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  unsigned int input[16], output[16], i;
  unsigned int check_results[16] = {1872, 746, 28304, 4815, 8392, 2894, 139524, 18411, 14912, 5042, 250744, 32007, 21432, 7190, 361964, 45603};
  check_vect();
  for (i = 0; i < 16; i++) {
    input[i] = i % 256;
    output[i] = 0;
    __asm__ volatile("");
  }
  foo(input, output);
  for (i = 0; i < 16; i++) {
    if (output[i] != check_results[i])
      abort();
    __asm__ volatile("");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movl   $0x750,0x80(%rsp)
  movl   $0x2ea,0x84(%rsp)
  movl   $0x6e90,0x88(%rsp)
  movl   $0x12cf,0x8c(%rsp)
  movl   $0x20c8,0x90(%rsp)
  movl   $0xb4e,0x94(%rsp)
  movl   $0x22104,0x98(%rsp)
  movl   $0x47eb,0x9c(%rsp)
  movl   $0x3a40,0xa0(%rsp)
  movl   $0x13b2,0xa4(%rsp)
  movl   $0x3d378,0xa8(%rsp)
  movl   $0x7d07,0xac(%rsp)
  movl   $0x53b8,0xb0(%rsp)
  movl   $0x1c16,0xb4(%rsp)
  movl   $0x585ec,0xb8(%rsp)
  movl   $0xb223,0xbc(%rsp)
  call   <check_vect@plt>
  mov    $0x0,%eax
L17:
  mov    %eax,(%rsp,%rax,4)
  movl   $0x0,0x40(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L17
  lea    0x40(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  lea    0x80(%rsp),%rdx
L23:
  mov    (%rdx,%rax,1),%ecx
  cmp    %ecx,0x40(%rsp,%rax,1)
  jne    L35
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L23
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xd8,%rsp
  ret
L35:
  call   <abort@plt>
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, const char *argv[]) {
  unsigned int input[16], output[16], i;
  unsigned int check_results[16] = {1872, 746, 28304, 4815, 8392, 2894, 139524, 18411, 14912, 5042, 250744, 32007, 21432, 7190, 361964, 45603};
  check_vect();
  for (i = 0; i < 16; i++) {
    input[i] = i % 256;
    output[i] = 0;
    __asm__ volatile("");
  }
  foo(input, output);
  for (i = 0; i < 16; i++) {
    if (output[i] != check_results[i])
      abort();
    __asm__ volatile("");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rbx
  movabs $0x12cf00006e90,%rax
  movl   $0x2ea,0x84(%rsp)
  mov    %rax,0x88(%rsp)
  movabs $0xb4e000020c8,%rax
  mov    %rax,0x90(%rsp)
  movabs $0x47eb00022104,%rax
  mov    %rax,0x98(%rsp)
  movabs $0x13b200003a40,%rax
  mov    %rax,0xa0(%rsp)
  movabs $0x7d070003d378,%rax
  mov    %rax,0xa8(%rsp)
  movabs $0x1c16000053b8,%rax
  mov    %rax,0xb0(%rsp)
  movabs $0xb223000585ec,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  xor    %eax,%eax
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L29:
  mov    %eax,(%rdi,%rax,4)
  movl   $0x0,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L29
  mov    %rbx,%rsi
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  mov    $0x750,%edx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0x80(%rsp,%rax,1),%edx
L2:
  cmp    %edx,(%rbx,%rax,1)
  jne    10c0 <main.cold>
  add    $0x4,%rax
  cmp    $0x40,%rax
  jne    L19
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, const char *argv[]) {
  unsigned int input[16], output[16], i;
  unsigned int check_results[16] = {1872, 746, 28304, 4815, 8392, 2894, 139524, 18411, 14912, 5042, 250744, 32007, 21432, 7190, 361964, 45603};
  check_vect();
  for (i = 0; i < 16; i++) {
    input[i] = i % 256;
    output[i] = 0;
    __asm__ volatile("");
  }
  foo(input, output);
  for (i = 0; i < 16; i++) {
    if (output[i] != check_results[i])
      abort();
    __asm__ volatile("");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <check_vect@plt>
  movabs $0x100000000,%rax
  movq   $0x0,0x40(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xb0000000a,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xd0000000c,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xf0000000e,%rax
  mov    %rax,0x38(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rsi
  mov    %rsp,%rdi
  call   <foo@plt>
  cmpl   $0x750,0x40(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x2ea,0x44(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x6e90,0x48(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x12cf,0x4c(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x20c8,0x50(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0xb4e,0x54(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x22104,0x58(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x47eb,0x5c(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x3a40,0x60(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x13b2,0x64(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x3d378,0x68(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x7d07,0x6c(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x53b8,0x70(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x1c16,0x74(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0x585ec,0x78(%rsp)
  jne    10c0 <main.cold>
  cmpl   $0xb223,0x7c(%rsp)
  jne    10c0 <main.cold>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, const char *argv[]) {
  unsigned int input[16], output[16], i;
  unsigned int check_results[16] = {1872, 746, 28304, 4815, 8392, 2894, 139524, 18411, 14912, 5042, 250744, 32007, 21432, 7190, 361964, 45603};
  check_vect();
  for (i = 0; i < 16; i++) {
    input[i] = i % 256;
    output[i] = 0;
    __asm__ volatile("");
  }
  foo(input, output);
  for (i = 0; i < 16; i++) {
    if (output[i] != check_results[i])
      abort();
    __asm__ volatile("");
  }
  return 0;
}
```