ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  mov    %rsp,%rsi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x3e8,%eax,%eax
  mov    %rdx,0x10(%rsp)
  mov    %rdx,(%rsp)
  xor    %edx,%edx
  sub    %eax,%edi
  mov    D2(%rip),%rax
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  mov    %rdi,0x18(%rsp)
  mov    %rdi,0x8(%rsp)
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void set_ticker(int n_msecs) {
  struct itimerval new_timeset;
  long n_sec = n_msecs / 1000;
  long n_usecs = (n_msecs % 1000) * 1000L;
  new_timeset.it_value.tv_sec = n_sec;
  new_timeset.it_value.tv_usec = n_usecs;
  new_timeset.it_interval.tv_sec = n_sec;
  new_timeset.it_interval.tv_usec = n_usecs;
  setitimer(ITIMER_REAL, &new_timeset, NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_ticker>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  mov    %rsp,%rsi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  xor    %edx,%edx
  movslq %eax,%rcx
  imul   $0x3e8,%eax,%eax
  movq   %rcx,%xmm0
  sub    %eax,%edi
  mov    D9(%rip),%rax
  movslq %edi,%rdi
  imul   $0x3e8,%rdi,%rdi
  movq   %rdi,%xmm1
  mov    (%rax),%edi
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <setitimer@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void set_ticker(int n_msecs) {
  struct itimerval new_timeset;
  long n_sec = n_msecs / 1000;
  long n_usecs = (n_msecs % 1000) * 1000L;
  new_timeset.it_value.tv_sec = n_sec;
  new_timeset.it_value.tv_usec = n_usecs;
  new_timeset.it_interval.tv_sec = n_sec;
  new_timeset.it_interval.tv_usec = n_usecs;
  setitimer(ITIMER_REAL, &new_timeset, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<unlock_mtab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L0
  mov    D5(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lockf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void unlock_mtab(int mtablock) {
  if (mtablock >= 0) {
    lockf(mtablock, F_ULOCK, 0);
    close(mtablock);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unlock_mtab>:
  endbr64
  test   %edi,%edi
  jns    L3
  ret
L3:
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <lockf@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void unlock_mtab(int mtablock) {
  if (mtablock >= 0) {
    lockf(mtablock, F_ULOCK, 0);
    close(mtablock);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unlock_mtab>:
  endbr64
  test   %edi,%edi
  jns    L0
  ret
  nopl   0x0(%rax)
L0:
  mov    D3(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <lockf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void unlock_mtab(int mtablock) {
  if (mtablock >= 0) {
    lockf(mtablock, F_ULOCK, 0);
    close(mtablock);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unlock_mtab>:
  endbr64
  test   %edi,%edi
  jns    L5
  ret
  nopl   0x0(%rax)
L5:
  mov    D0(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <lockf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <close@plt>
```

assistant: ```c
void unlock_mtab(int mtablock) {
  if (mtablock >= 0) {
    lockf(mtablock, F_ULOCK, 0);
    close(mtablock);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<funct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L35
  cmpl   $0x0,-0x8(%rbp)
  je     L19
  mov    $0x0,%eax
  call   <f1@plt>
  jmp    L19
L35:
  cmpl   $0x0,-0xc(%rbp)
  je     L19
  mov    $0x0,%eax
  call   <f2@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void funct(int v1, int v2, int v3) {
  if (v1) {
    if (v2)
      f1();
  } else {
    if (v3)
      f2();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<funct>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L7
  test   %esi,%esi
  jne    L20
L22:
  add    $0x8,%rsp
  ret
L20:
  mov    $0x0,%eax
  call   <f1@plt>
  jmp    L22
L7:
  test   %edx,%edx
  je     L22
  mov    $0x0,%eax
  call   <f2@plt>
  jmp    L22
```

assistant: ```c
void funct(int v1, int v2, int v3) {
  if (v1) {
    if (v2)
      f1();
  } else {
    if (v3)
      f2();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<funct>:
  endbr64
  test   %edi,%edi
  je     L22
  test   %esi,%esi
  jne    L12
L25:
  ret
  nopl   (%rax)
L22:
  test   %edx,%edx
  je     L25
  xor    %eax,%eax
  jmp    1060 <f2@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  jmp    1070 <f1@plt>
```

assistant: ```c
void funct(int v1, int v2, int v3) {
  if (v1) {
    if (v2)
      f1();
  } else {
    if (v3)
      f2();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<funct>:
  endbr64
  test   %edi,%edi
  je     L22
  test   %esi,%esi
  jne    L7
L6:
  ret
  nopl   (%rax)
L22:
  test   %edx,%edx
  je     L6
  xor    %eax,%eax
  jmp    1060 <f2@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  jmp    1070 <f1@plt>
```

assistant: ```c
void funct(int v1, int v2, int v3) {
  if (v1) {
    if (v2)
      f1();
  } else {
    if (v3)
      f2();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  negl   -0x14(%rbp)
L16:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <abs@plt>
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  cmpl   $0x0,-0x4(%rbp)
  jns    L12
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L12
L49:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  subl   $0x1,-0x18(%rbp)
L12:
  cmpl   $0x0,-0x18(%rbp)
  jg     L49
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  for (; width > 0; width--)
    s[i++] = ' ';
  s[i] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %edx,%r15d
  neg    %edi
  cmovs  %r14d,%edi
  mov    %rsi,%r12
  mov    $0x0,%ebp
L30:
  movslq %edi,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x30,%eax
  mov    %al,(%r12)
  mov    %ebx,%edi
  add    $0x1,%r12
  test   %ebx,%ebx
  jne    L30
  test   %r14d,%r14d
  js     L42
L24:
  test   %r15d,%r15d
  jle    L5
  movslq %ebp,%rcx
  lea    0x0(%r13,%rcx,1),%rax
  lea    -0x1(%r15),%edx
  lea    0x1(%r13,%rdx,1),%rdx
  add    %rcx,%rdx
L46:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L46
  lea    0x0(%rbp,%r15,1),%ebp
L5:
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  movslq %ebp,%rbp
  movb   $0x2d,0x0(%r13,%rbp,1)
  lea    0x2(%rdx),%ebp
  jmp    L24
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  for (; width > 0; width--)
    s[i++] = ' ';
  s[i] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  sub    $0x18,%rsp
  neg    %edi
  mov    %edx,0xc(%rsp)
  cmovs  %r12d,%edi
  xor    %r15d,%r15d
  nopl   (%rax)
L16:
  mov    %edi,%ebx
  add    $0x1,%r14
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r15d,%ecx
  mov    %ebx,%edi
  add    $0x1,%r15d
  add    $0x30,%eax
  mov    %al,-0x1(%r14)
  test   %ebx,%ebx
  jne    L16
  test   %r12d,%r12d
  jns    L23
  movslq %r15d,%r15
  movb   $0x2d,0x0(%r13,%r15,1)
  lea    0x2(%rcx),%r15d
L23:
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  jle    L14
  movslq %r15d,%rdi
  movslq %ebx,%rdx
  mov    $0x20,%esi
  add    %ebx,%r15d
  add    %r13,%rdi
  call   <memset@plt>
L14:
  movslq %r15d,%r15
  movb   $0x0,0x0(%r13,%r15,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  for (; width > 0; width--)
    s[i++] = ' ';
  s[i] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  sub    $0x18,%rsp
  neg    %edi
  mov    %edx,0xc(%rsp)
  cmovs  %r12d,%edi
  xor    %r15d,%r15d
  nopl   (%rax)
L23:
  mov    %edi,%ebx
  add    $0x1,%r14
  imul   %rbp,%rbx
  shr    $0x23,%rbx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r15d,%ecx
  mov    %ebx,%edi
  add    $0x1,%r15d
  add    $0x30,%eax
  mov    %al,-0x1(%r14)
  test   %ebx,%ebx
  jne    L23
  test   %r12d,%r12d
  jns    L2
  movslq %r15d,%r15
  movb   $0x2d,0x0(%r13,%r15,1)
  lea    0x2(%rcx),%r15d
L2:
  mov    0xc(%rsp),%ebx
  test   %ebx,%ebx
  jle    L8
  movslq %r15d,%rdi
  movslq %ebx,%rdx
  mov    $0x20,%esi
  add    %ebx,%r15d
  add    %r13,%rdi
  call   <memset@plt>
L8:
  movslq %r15d,%r15
  movb   $0x0,0x0(%r13,%r15,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i = 0, sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    s[i++] = abs(n % 10) + '0';
  } while (n /= 10);
  if (sign < 0)
    s[i++] = '-';
  for (; width > 0; width--)
    s[i++] = ' ';
  s[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D54(%rip),%rsi
  lea    D129(%rip),%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rbp
  mov    %rbp,%rsi
  lea    D21(%rip),%r12
  mov    %r12,%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D64(%rip),%rsi
  mov    %r12,%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rsi
  lea    D31(%rip),%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rsi
  lea    D33(%rip),%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D86(%rip),%rsi
  mov    %rbp,%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D72(%rip),%rsi
  lea    D97(%rip),%rdi
  call   <isMatch@plt>
  mov    %eax,%esi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D54
datatype: string
name: parse_data
arguments: tag: D129
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D37
datatype: string
name: parse_data
arguments: tag: D21
datatype: string
name: parse_data
arguments: tag: D64
datatype: string
name: parse_data
arguments: tag: D23
datatype: string
name: parse_data
arguments: tag: D31
datatype: string
name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D33
datatype: string
name: parse_data
arguments: tag: D86
datatype: string
name: parse_data
arguments: tag: D72
datatype: string
name: parse_data
arguments: tag: D97
datatype: string

tool: D54: a*a

tool: D129: aaa

tool: D16: %d %d


tool: D37: a

tool: D21: aa

tool: D64: .*

tool: D23: c*a*b

tool: D31: aab

tool: D18: .*c

tool: D33: ab

tool: D86: ab*

tool: D72: .*a*a

tool: D97: bbbba

assistant: ```c
int main(int argc, char **argv) {
  printf("%d %d\n", isMatch("aaa", "a*a"), 1);
  printf("%d %d\n", isMatch("aa", "a"), 0);
  printf("%d %d\n", isMatch("aa", ".*"), 1);
  printf("%d %d\n", isMatch("aab", "c*a*b"), 1);
  printf("%d %d\n", isMatch("ab", ".*c"), 0);
  printf("%d %d\n", isMatch("a", "ab*"), 1);
  printf("%d %d\n", isMatch("bbbba", ".*a*a"), 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D49(%rip),%rsi
  lea    D42(%rip),%rdi
  push   %r12
  lea    D27(%rip),%r13
  lea    D45(%rip),%r12
  push   %rbp
  lea    D96(%rip),%rbp
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <isMatch@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  lea    D67(%rip),%rsi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D128(%rip),%rsi
  lea    D20(%rip),%rdi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D105(%rip),%rsi
  lea    D82(%rip),%rdi
  call   <isMatch@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D22(%rip),%rsi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D119(%rip),%rsi
  lea    D102(%rip),%rdi
  call   <isMatch@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D49
type_infered: string
name: unpack_data
arguments: tag: D42
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D45
type_infered: string
name: unpack_data
arguments: tag: D96
type_infered: string
name: unpack_data
arguments: tag: D67
type_infered: string
name: unpack_data
arguments: tag: D128
type_infered: string
name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D105
type_infered: string
name: unpack_data
arguments: tag: D82
type_infered: string
name: unpack_data
arguments: tag: D22
type_infered: string
name: unpack_data
arguments: tag: D119
type_infered: string
name: unpack_data
arguments: tag: D102
type_infered: string

tool: D49: a*a

tool: D42: aaa

tool: D27: aa

tool: D45: a

tool: D96: %d %d


tool: D67: .*

tool: D128: c*a*b

tool: D20: aab

tool: D105: .*c

tool: D82: ab

tool: D22: ab*

tool: D119: .*a*a

tool: D102: bbbba

assistant: ```c
int main(int argc, char **argv) {
  printf("%d %d\n", isMatch("aaa", "a*a"), 1);
  printf("%d %d\n", isMatch("aa", "a"), 0);
  printf("%d %d\n", isMatch("aa", ".*"), 1);
  printf("%d %d\n", isMatch("aab", "c*a*b"), 1);
  printf("%d %d\n", isMatch("ab", ".*c"), 0);
  printf("%d %d\n", isMatch("a", "ab*"), 1);
  printf("%d %d\n", isMatch("bbbba", ".*a*a"), 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rsi
  lea    D67(%rip),%rdi
  push   %r12
  lea    D36(%rip),%r13
  lea    D70(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <isMatch@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  lea    D121(%rip),%rsi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D63(%rip),%rsi
  lea    D33(%rip),%rdi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D77(%rip),%rsi
  lea    D122(%rip),%rdi
  call   <isMatch@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D94(%rip),%rsi
  call   <isMatch@plt>
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D68(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <isMatch@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D67
type_guessed: string
name: parse_data
arguments: label: D36
type_guessed: string
name: parse_data
arguments: label: D70
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D121
type_guessed: string
name: parse_data
arguments: label: D63
type_guessed: string
name: parse_data
arguments: label: D33
type_guessed: string
name: parse_data
arguments: label: D77
type_guessed: string
name: parse_data
arguments: label: D122
type_guessed: string
name: parse_data
arguments: label: D94
type_guessed: string
name: parse_data
arguments: label: D68
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string

tool: D19: a*a

tool: D67: aaa

tool: D36: aa

tool: D70: a

tool: D5: %d %d


tool: D121: .*

tool: D63: c*a*b

tool: D33: aab

tool: D77: .*c

tool: D122: ab

tool: D94: ab*

tool: D68: .*a*a

tool: D12: bbbba

assistant: ```c
int main(int argc, char **argv) {
  printf("%d %d\n", isMatch("aaa", "a*a"), 1);
  printf("%d %d\n", isMatch("aa", "a"), 0);
  printf("%d %d\n", isMatch("aa", ".*"), 1);
  printf("%d %d\n", isMatch("aab", "c*a*b"), 1);
  printf("%d %d\n", isMatch("ab", ".*c"), 0);
  printf("%d %d\n", isMatch("a", "ab*"), 1);
  printf("%d %d\n", isMatch("bbbba", ".*a*a"), 1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a52_set_fscod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  and    $0x3f,%dl
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void a52_set_fscod(uint8_t *p_a52, uint8_t i_fscod) {
  p_a52[4] &= ~0xc0;
  p_a52[4] |= (i_fscod & 0x3) << 6;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<a52_set_fscod>:
  endbr64
  mov    0x10(%rdi),%eax
  and    $0x3f,%al
  shl    $0x6,%esi
  movzbl %sil,%esi
  or     %esi,%eax
  mov    %eax,0x10(%rdi)
  ret
```

assistant: ```c
void a52_set_fscod(uint8_t *p_a52, uint8_t i_fscod) {
  p_a52[4] &= ~0xc0;
  p_a52[4] |= (i_fscod & 0x3) << 6;
}
```
user: What is the c source code of the assembly code below:

```asm
<a52_set_fscod>:
  endbr64
  mov    0x10(%rdi),%eax
  shl    $0x6,%esi
  movzbl %sil,%esi
  and    $0x3f,%al
  or     %esi,%eax
  mov    %eax,0x10(%rdi)
  ret
```

assistant: ```c
void a52_set_fscod(uint8_t *p_a52, uint8_t i_fscod) {
  p_a52[4] &= ~0xc0;
  p_a52[4] |= (i_fscod & 0x3) << 6;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<a52_set_fscod>:
  endbr64
  mov    0x10(%rdi),%eax
  shl    $0x6,%esi
  movzbl %sil,%esi
  and    $0x3f,%al
  or     %esi,%eax
  mov    %eax,0x10(%rdi)
  ret
```

assistant: ```c
void a52_set_fscod(uint8_t *p_a52, uint8_t i_fscod) {
  p_a52[4] &= ~0xc0;
  p_a52[4] |= (i_fscod & 0x3) << 6;
}
```
user: What is the c source code of the assembly code below:

```asm
<charToBinASCII>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x33,%eax
  ja     L38
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L12
  mov    $0x1,%eax
  jmp    L12
  mov    $0x2,%eax
  jmp    L12
  mov    $0x3,%eax
  jmp    L12
L38:
  mov    $0x4,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t charToBinASCII(unsigned char base) {
  switch (base) {
  case 'A':
  case 'a':
    return (0);
  case 'C':
  case 'c':
    return (1);
  case 'G':
  case 'g':
    return (2);
  case 'T':
  case 't':
    return (3);
  default:
    return (4);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<charToBinASCII>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x33,%dil
  ja     L9
  movzbl %dil,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
L9:
  mov    $0x4,%eax
  ret
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint32_t charToBinASCII(unsigned char base) {
  switch (base) {
  case 'A':
  case 'a':
    return (0);
  case 'C':
  case 'c':
    return (1);
  case 'G':
  case 'g':
    return (2);
  case 'T':
  case 't':
    return (3);
  default:
    return (4);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<charToBinASCII>:
  endbr64
  sub    $0x41,%edi
  mov    $0x4,%eax
  cmp    $0x33,%dil
  ja     L2
  movzbl %dil,%edi
  lea    D3(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L2:
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: 

assistant: ```c
uint32_t charToBinASCII(unsigned char base) {
  switch (base) {
  case 'A':
  case 'a':
    return (0);
  case 'C':
  case 'c':
    return (1);
  case 'G':
  case 'g':
    return (2);
  case 'T':
  case 't':
    return (3);
  default:
    return (4);
  }
}
```