user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L54:
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  imul   %eax,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3e8,%eax
  jne    L76
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L76
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L76:
  addl   $0x1,-0x18(%rbp)
L13:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3e7,%eax
  jg     L1
  cmpl   $0x0,-0xc(%rbp)
  je     L54
L1:
  cmpl   $0x0,-0xc(%rbp)
  jne    L24
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
L24:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    $0x3e7,%eax
  jg     L28
  cmpl   $0x0,-0xc(%rbp)
  je     L13
L28:
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%r8d
  mov    -0x18(%rbp),%edi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x8,%rsp
  push   %rsi
  mov    -0x10(%rbp),%esi
  push   %rsi
  mov    -0x10(%rbp),%esi
  push   %rsi
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    -0x1c(%rbp),%eax
  imul   -0x18(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D4: %d*%d + %d*%d = %d = %d*%d = %d


tool: D9: a*b*c = %d

tool: D2: 
took %lu usec


assistant: ```c
int main(void) {
  struct timeval stop, start;
  gettimeofday(&start, NULL);
  int a = 5, b = 6, c = 0, sqrtc = 0;
  int exit = 0;
  while ((a + b + sqrtc) < 1000 && exit == 0) {
    while (a + b + sqrtc < 1000 && exit == 0) {
      c = a * a + b * b;
      sqrtc = (int)sqrt(c);
      if (a + b + sqrtc == 1000 && sqrtc * sqrtc == c) {
        exit = 1;
      } else {
        b++;
      }
    }
    if (!exit) {
      a++;
      b = a + 1;
      c = 0;
    }
  }
  printf("%d*%d + %d*%d = %d = %d*%d = %d\n", a, a, b, b, c, sqrtc, sqrtc, sqrtc * sqrtc);
  printf("a*b*c = %d", a * b * sqrtc);
  gettimeofday(&stop, NULL);
  printf("\ntook %lu usec\n", stop.tv_usec - start.tv_usec);
  return 0;
}
```