ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<SkipLine>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbp
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    $0xa,%eax
  je     L18
L3:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L0
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SkipLine(FILE *fp) {
  int c;
  while ((c = getc(fp)) != EOF)
    if (c == '\n')
      break;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SkipLine>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbp
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    $0xa,%eax
  je     L21
L3:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    %eax,0x0(%rbp)
  jne    L7
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SkipLine(FILE *fp) {
  int c;
  while ((c = getc(fp)) != EOF)
    if (c == '\n')
      break;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GPIOPinWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  movzbl -0xc(%rbp),%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  movzbl -0x10(%rbp),%eax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPIOPinWrite(unsigned long ulPort, unsigned char ucPins, unsigned char ucVal) {
  ;
  (*((volatile unsigned long *)(ulPort + (0x00000000 + (ucPins << 2))))) = ucVal;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPIOPinWrite>:
  endbr64
  shl    $0x2,%rsi
  and    $0x3fc,%esi
  add    %rdi,%rsi
  movzbl %dl,%edx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void GPIOPinWrite(unsigned long ulPort, unsigned char ucPins, unsigned char ucVal) {
  ;
  (*((volatile unsigned long *)(ulPort + (0x00000000 + (ucPins << 2))))) = ucVal;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GPIOPinWrite>:
  endbr64
  shl    $0x2,%rsi
  movzbl %dl,%edx
  and    $0x3fc,%esi
  add    %rdi,%rsi
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void GPIOPinWrite(unsigned long ulPort, unsigned char ucPins, unsigned char ucVal) {
  ;
  (*((volatile unsigned long *)(ulPort + (0x00000000 + (ucPins << 2))))) = ucVal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GPIOPinWrite>:
  endbr64
  shl    $0x2,%rsi
  movzbl %dl,%edx
  and    $0x3fc,%esi
  add    %rdi,%rsi
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void GPIOPinWrite(unsigned long ulPort, unsigned char ucPins, unsigned char ucVal) {
  ;
  (*((volatile unsigned long *)(ulPort + (0x00000000 + (ucPins << 2))))) = ucVal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<biosal_dna_helper_reverse_complement_in_place>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L8
L11:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <biosal_dna_helper_complement_nucleotide@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x20(%rbp)
L8:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  movl   $0x0,-0x20(%rbp)
  jmp    L4
L24:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x21(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void biosal_dna_helper_reverse_complement_in_place(char *sequence) {
  int position;
  int length;
  int middle;
  char saved;
  int position2;
  length = strlen(sequence);
  middle = length / 2;
  position = 0;
  while (position < length) {
    sequence[position] = biosal_dna_helper_complement_nucleotide(sequence[position]);
    position++;
  }
  position = 0;
  while (position < middle) {
    position2 = length - 1 - position;
    saved = sequence[position2];
    sequence[position2] = sequence[position];
    sequence[position] = saved;
    position++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<biosal_dna_helper_reverse_complement_in_place>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  test   %eax,%eax
  jle    L9
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%r14
L38:
  movsbl (%rbx),%edi
  call   <biosal_dna_helper_complement_nucleotide@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L38
L9:
  cmp    $0x1,%r13d
  jle    L34
  movslq %r13d,%r13
  lea    -0x1(%rbp,%r13,1),%rdx
  mov    $0x0,%eax
L11:
  movzbl (%rdx),%ecx
  movzbl 0x0(%rbp,%rax,1),%esi
  mov    %sil,(%rdx)
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r12d
  jg     L11
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void biosal_dna_helper_reverse_complement_in_place(char *sequence) {
  int position;
  int length;
  int middle;
  char saved;
  int position2;
  length = strlen(sequence);
  middle = length / 2;
  position = 0;
  while (position < length) {
    sequence[position] = biosal_dna_helper_complement_nucleotide(sequence[position]);
    position++;
  }
  position = 0;
  while (position < middle) {
    position2 = length - 1 - position;
    saved = sequence[position2];
    sequence[position2] = sequence[position];
    sequence[position] = saved;
    position++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<biosal_dna_helper_reverse_complement_in_place>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  test   %eax,%eax
  jle    L19
  mov    %eax,%r15d
  lea    -0x1(%rax),%eax
  mov    %r13,%rbx
  mov    %rax,%rbp
  lea    0x1(%r13,%rax,1),%r14
  nopl   0x0(%rax)
L22:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <biosal_dna_helper_complement_nucleotide@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r14,%rbx
  jne    L22
  cmp    $0x1,%r15d
  jle    L19
  movslq %ebp,%rdx
  xor    %eax,%eax
  add    %r13,%rdx
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rdx),%ecx
  movzbl 0x0(%r13,%rax,1),%esi
  sub    $0x1,%rdx
  mov    %sil,0x1(%rdx)
  mov    %cl,0x0(%r13,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L0
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void biosal_dna_helper_reverse_complement_in_place(char *sequence) {
  int position;
  int length;
  int middle;
  char saved;
  int position2;
  length = strlen(sequence);
  middle = length / 2;
  position = 0;
  while (position < length) {
    sequence[position] = biosal_dna_helper_complement_nucleotide(sequence[position]);
    position++;
  }
  position = 0;
  while (position < middle) {
    position2 = length - 1 - position;
    saved = sequence[position2];
    sequence[position2] = sequence[position];
    sequence[position] = saved;
    position++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<biosal_dna_helper_reverse_complement_in_place>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  test   %eax,%eax
  jle    L26
  mov    %eax,%r15d
  lea    -0x1(%rax),%eax
  mov    %r13,%rbx
  mov    %rax,%rbp
  lea    0x1(%r13,%rax,1),%r14
  nopl   0x0(%rax)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <biosal_dna_helper_complement_nucleotide@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r14,%rbx
  jne    L19
  cmp    $0x1,%r15d
  jle    L26
  movslq %ebp,%rdx
  xor    %eax,%eax
  add    %r13,%rdx
  nopw   0x0(%rax,%rax,1)
L36:
  movzbl (%rdx),%ecx
  movzbl 0x0(%r13,%rax,1),%esi
  sub    $0x1,%rdx
  mov    %sil,0x1(%rdx)
  mov    %cl,0x0(%r13,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L36
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void biosal_dna_helper_reverse_complement_in_place(char *sequence) {
  int position;
  int length;
  int middle;
  char saved;
  int position2;
  length = strlen(sequence);
  middle = length / 2;
  position = 0;
  while (position < length) {
    sequence[position] = biosal_dna_helper_complement_nucleotide(sequence[position]);
    position++;
  }
  position = 0;
  while (position < middle) {
    position2 = length - 1 - position;
    saved = sequence[position2];
    sequence[position2] = sequence[position];
    sequence[position] = saved;
    position++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<StaticFunc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xdeadface,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: I'm a static Func %8X

assistant: ```c
void StaticFunc(void) {
  static unsigned int FuncScopeStatic = 0xDEADFACE;
  printf("I'm a static Func %8X", FuncScopeStatic);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<StaticFunc>:
  endbr64
  mov    $0xdeadface,%esi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: I'm a static Func %8X

assistant: ```c
void StaticFunc(void) {
  static unsigned int FuncScopeStatic = 0xDEADFACE;
  printf("I'm a static Func %8X", FuncScopeStatic);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<StaticFunc>:
  endbr64
  mov    $0xdeadface,%esi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: I'm a static Func %8X

assistant: ```c
void StaticFunc(void) {
  static unsigned int FuncScopeStatic = 0xDEADFACE;
  printf("I'm a static Func %8X", FuncScopeStatic);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_cas_value_from_gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L4:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoull@plt>
  leave
  ret
```

assistant: ```c
uint64_t get_cas_value_from_gets(char *a) {
  char *b = a + strlen(a);
  while (*b-- != ' ')
    ;
  return strtoull(b + 1, NULL, 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_cas_value_from_gets>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
L7:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  cmpb   $0x20,0x1(%rdi)
  jne    L7
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoull@plt>
  pop    %rbx
  ret
```

assistant: ```c
uint64_t get_cas_value_from_gets(char *a) {
  char *b = a + strlen(a);
  while (*b-- != ' ')
    ;
  return strtoull(b + 1, NULL, 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_cas_value_from_gets>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%r8
  sub    $0x1,%rdi
  cmpb   $0x20,0x1(%rdi)
  jne    L0
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r8,%rdi
  pop    %rbx
  jmp    1070 <strtoull@plt>
```

assistant: ```c
uint64_t get_cas_value_from_gets(char *a) {
  char *b = a + strlen(a);
  while (*b-- != ' ')
    ;
  return strtoull(b + 1, NULL, 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_cas_value_from_gets>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%r8
  sub    $0x1,%rdi
  cmpb   $0x20,0x1(%rdi)
  jne    L1
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r8,%rdi
  pop    %rbx
  jmp    1070 <strtoull@plt>
```

assistant: ```c
uint64_t get_cas_value_from_gets(char *a) {
  char *b = a + strlen(a);
  while (*b-- != ' ')
    ;
  return strtoull(b + 1, NULL, 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<verify_opponent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x31,%eax
  jg     L4
  mov    -0x8(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
L4:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: The maximum name length is 50 characters
                Also you can't use quotes ( " ) in your submission
                Please try again.


assistant: ```c
void verify_opponent(char *name) {
  if (strlen(name) >= 50 || strchr(name, '\"')) {
    printf("The maximum name length is 50 characters\n                Also you can't use quotes ( \" ) in your submission\n                Please try again.\n");
    exit(0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<verify_opponent>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x31,%eax
  jg     L1
  mov    $0x22,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
L1:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L19:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: The maximum name length is 50 characters
                Also you can't use quotes ( " ) in your submission
                Please try again.


assistant: ```c
void verify_opponent(char *name) {
  if (strlen(name) >= 50 || strchr(name, '\"')) {
    printf("The maximum name length is 50 characters\n                Also you can't use quotes ( \" ) in your submission\n                Please try again.\n");
    exit(0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<verify_opponent>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x31,%eax
  jg     L7
  mov    $0x22,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: The maximum name length is 50 characters
                Also you can't use quotes ( " ) in your submission
                Please try again.


assistant: ```c
void verify_opponent(char *name) {
  if (strlen(name) >= 50 || strchr(name, '\"')) {
    printf("The maximum name length is 50 characters\n                Also you can't use quotes ( \" ) in your submission\n                Please try again.\n");
    exit(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<verify_opponent>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x31,%eax
  jg     L19
  mov    $0x22,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
L19:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: The maximum name length is 50 characters
                Also you can't use quotes ( " ) in your submission
                Please try again.


assistant: ```c
void verify_opponent(char *name) {
  if (strlen(name) >= 50 || strchr(name, '\"')) {
    printf("The maximum name length is 50 characters\n                Also you can't use quotes ( \" ) in your submission\n                Please try again.\n");
    exit(0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L11:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L10:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L11
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *restrict s1, const void *restrict s2, unsigned int n) {
  char *dst = s1;
  const char *src = s2;
  while (n-- != 0)
    *dst++ = *src++;
  return s1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edi
  test   %edx,%edx
  je     L8
  mov    %edi,%edi
  mov    $0x0,%edx
L19:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rdi
  jne    L19
L8:
  ret
```

assistant: ```c
void *memcpy(void *restrict s1, const void *restrict s2, unsigned int n) {
  char *dst = s1;
  const char *src = s2;
  while (n-- != 0)
    *dst++ = *src++;
  return s1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L2
  sub    $0x8,%rsp
  mov    %edx,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memcpy(void *restrict s1, const void *restrict s2, unsigned int n) {
  char *dst = s1;
  const char *src = s2;
  while (n-- != 0)
    *dst++ = *src++;
  return s1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  je     L5
  sub    $0x8,%rsp
  mov    %edx,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memcpy(void *restrict s1, const void *restrict s2, unsigned int n) {
  char *dst = s1;
  const char *src = s2;
  while (n-- != 0)
    *dst++ = *src++;
  return s1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cbuf_chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L25
L15:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L25:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L27
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L15
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L15
L27:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cbuf_chomp(char *buf, size_t *lenptr) {
  while (*lenptr && (buf[(*lenptr) - 1] == '\n' || buf[(*lenptr) - 1] == '\r'))
    (*lenptr)--;
  buf[*lenptr] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cbuf_chomp>:
  endbr64
  mov    (%rsi),%rax
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L44
  jmp    L39
L19:
  mov    %rax,(%rsi)
  test   %rax,%rax
  je     L38
L44:
  mov    %rax,%rcx
  sub    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0xa,%dl
  je     L19
  cmp    $0xd,%dl
  je     L19
L39:
  movb   $0x0,(%rdi,%rcx,1)
  ret
L38:
  mov    %rax,%rcx
  jmp    L39
```

assistant: ```c
void cbuf_chomp(char *buf, size_t *lenptr) {
  while (*lenptr && (buf[(*lenptr) - 1] == '\n' || buf[(*lenptr) - 1] == '\r'))
    (*lenptr)--;
  buf[*lenptr] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cbuf_chomp>:
  endbr64
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L7
  jmp    L26
  xchg   %ax,%ax
L0:
  mov    %rax,(%rsi)
  test   %rax,%rax
  je     L26
L7:
  mov    %rax,%rcx
  sub    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0xa,%dl
  je     L0
  cmp    $0xd,%dl
  je     L0
  add    %rcx,%rdi
L26:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void cbuf_chomp(char *buf, size_t *lenptr) {
  while (*lenptr && (buf[(*lenptr) - 1] == '\n' || buf[(*lenptr) - 1] == '\r'))
    (*lenptr)--;
  buf[*lenptr] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cbuf_chomp>:
  endbr64
  mov    (%rsi),%rax
  test   %rax,%rax
  jne    L48
  jmp    L34
  xchg   %ax,%ax
L49:
  mov    %rax,(%rsi)
  test   %rax,%rax
  je     L34
L48:
  mov    %rax,%rcx
  sub    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  cmp    $0xa,%dl
  je     L49
  cmp    $0xd,%dl
  je     L49
  add    %rcx,%rdi
L34:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void cbuf_chomp(char *buf, size_t *lenptr) {
  while (*lenptr && (buf[(*lenptr) - 1] == '\n' || buf[(*lenptr) - 1] == '\r'))
    (*lenptr)--;
  buf[*lenptr] = '\0';
}
```