ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int ix;
  int ondev = 0;
  int q = 0, h = 0;
#pragma acc parallel vector_length(32) copy(q) copy(ondev)
  {
    int t = q;
#pragma acc loop vector reduction(+ : t)
    for (unsigned ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
      int val = ix;
      if (__builtin_acc_on_device(5)) {
        int g = 0, w = 0, v = 0;
        __asm__ volatile("mov.u32 %0,%%ctaid.x;" : "=r"(g));
        __asm__ volatile("mov.u32 %0,%%tid.y;" : "=r"(w));
        __asm__ volatile("mov.u32 %0,%%tid.x;" : "=r"(v));
        val = (g << 16) | (w << 8) | v;
        ondev = 1;
      }
      t += val;
    }
    q = t;
  }
  for (ix = 0; ix < (32 * 32 * 32 + 17); ix++) {
    int val = ix;
    if (ondev) {
      int g = 0;
      int w = 0;
      int v = ix % 32;
      val = (g << 16) | (w << 8) | v;
    }
    h += val;
  }
  if (q != h) {
    printf("t=%x expected %x\n", q, h);
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utf8_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x7f,-0xc(%rbp)
  ja     L18
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
  jmp    L32
L18:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x7ff,%eax
  jg     L45
  mov    -0xc(%rbp),%eax
  shr    $0x6,%eax
  or     $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L94
L45:
  cmpl   $0xffff,-0xc(%rbp)
  ja     L21
  mov    -0xc(%rbp),%eax
  shr    $0xc,%eax
  or     $0xffffffe0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movl   $0x2,-0x10(%rbp)
  jmp    L94
L21:
  cmpl   $0x10ffff,-0xc(%rbp)
  ja     L61
  mov    -0xc(%rbp),%eax
  shr    $0x12,%eax
  or     $0xfffffff0,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movl   $0x3,-0x10(%rbp)
L94:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L65
L84:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  shr    %cl,%eax
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  subl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
L65:
  cmpl   $0x0,-0x14(%rbp)
  jg     L84
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  jmp    L32
L61:
  nop
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movb   $0xef,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movb   $0xbf,(%rax)
  mov    -0x30(%rbp),%rax
  movb   $0xbd,(%rax)
  mov    $0x3,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int utf8_encode(int *u, char *s) {
  unsigned char *sp = (unsigned char *)s;
  unsigned int uc = *u;
  int i;
  int n;
  if (uc < 0x80) {
    *sp = uc;
    return 1;
  } else if (*u < 0x800) {
    *sp = (uc >> 6) | 0xC0;
    n = 1;
  } else if (uc < 0x10000) {
    *sp = (uc >> 12) | 0xE0;
    n = 2;
  } else if (uc <= 0x10FFFF) {
    *sp = (uc >> 18) | 0xF0;
    n = 3;
  } else {
    goto invalid;
  }
  for (i = n, ++sp; i > 0; --i, ++sp)
    *sp = ((uc >> 6 * (i - 1)) & 0x3F) | 0x80;
  return n + 1;
invalid:
  *s++ = '\xEF';
  *s++ = '\xBF';
  *s = '\xBD';
  return 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_encode>:
  endbr64
  mov    (%rdi),%edi
  cmp    $0x7f,%edi
  jbe    L49
  cmp    $0x7ff,%edi
  jg     L56
  mov    %edi,%edx
  shr    $0x6,%edx
  or     $0xffffffc0,%edx
  mov    $0x1,%eax
L28:
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  lea    -0x3(%rax,%rax,2),%ecx
  add    %ecx,%ecx
L13:
  mov    %edi,%edx
  shr    %cl,%edx
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  sub    $0x6,%ecx
  cmp    $0xfffffffa,%ecx
  jne    L13
  add    $0x1,%eax
  ret
L49:
  mov    %dil,(%rsi)
  mov    $0x1,%eax
  ret
L56:
  cmp    $0xffff,%edi
  ja     L59
  mov    %edi,%edx
  shr    $0xc,%edx
  or     $0xffffffe0,%edx
  mov    $0x2,%eax
  jmp    L28
L59:
  cmp    $0x10ffff,%edi
  ja     L39
  mov    %edi,%edx
  shr    $0x12,%edx
  or     $0xfffffff0,%edx
  mov    $0x3,%eax
  jmp    L28
L39:
  movb   $0xef,(%rsi)
  movb   $0xbf,0x1(%rsi)
  movb   $0xbd,0x2(%rsi)
  mov    $0x3,%eax
  ret
```

assistant: ```c
unsigned int utf8_encode(int *u, char *s) {
  unsigned char *sp = (unsigned char *)s;
  unsigned int uc = *u;
  int i;
  int n;
  if (uc < 0x80) {
    *sp = uc;
    return 1;
  } else if (*u < 0x800) {
    *sp = (uc >> 6) | 0xC0;
    n = 1;
  } else if (uc < 0x10000) {
    *sp = (uc >> 12) | 0xE0;
    n = 2;
  } else if (uc <= 0x10FFFF) {
    *sp = (uc >> 18) | 0xF0;
    n = 3;
  } else {
    goto invalid;
  }
  for (i = n, ++sp; i > 0; --i, ++sp)
    *sp = ((uc >> 6 * (i - 1)) & 0x3F) | 0x80;
  return n + 1;
invalid:
  *s++ = '\xEF';
  *s++ = '\xBF';
  *s = '\xBD';
  return 3;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utf8_encode>:
  endbr64
  mov    (%rdi),%edx
  cmp    $0x7f,%edx
  jbe    L54
  cmp    $0x7ff,%edx
  jg     L16
  mov    %edx,%eax
  mov    $0x2,%r8d
  mov    $0x1,%ecx
  shr    $0x6,%eax
  or     $0xffffffc0,%eax
L19:
  lea    -0x3(%rcx,%rcx,2),%ecx
  mov    %al,(%rsi)
  add    $0x1,%rsi
  add    %ecx,%ecx
L64:
  mov    %edx,%eax
  add    $0x1,%rsi
  shr    %cl,%eax
  sub    $0x6,%ecx
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,-0x1(%rsi)
  cmp    $0xfffffffa,%ecx
  jne    L64
L58:
  mov    %r8d,%eax
  ret
  nop
L16:
  cmp    $0xffff,%edx
  jbe    L33
  cmp    $0x10ffff,%edx
  ja     L12
  mov    %edx,%eax
  mov    $0x4,%r8d
  mov    $0x3,%ecx
  shr    $0x12,%eax
  or     $0xfffffff0,%eax
  jmp    L19
  nopl   (%rax)
L54:
  mov    $0x1,%r8d
  mov    %dl,(%rsi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L33:
  mov    %edx,%eax
  mov    $0x3,%r8d
  mov    $0x2,%ecx
  shr    $0xc,%eax
  or     $0xffffffe0,%eax
  jmp    L19
  nopl   (%rax)
L12:
  mov    $0xffffbfef,%eax
  movb   $0xbd,0x2(%rsi)
  mov    $0x3,%r8d
  mov    %ax,(%rsi)
  jmp    L58
```

assistant: ```c
unsigned int utf8_encode(int *u, char *s) {
  unsigned char *sp = (unsigned char *)s;
  unsigned int uc = *u;
  int i;
  int n;
  if (uc < 0x80) {
    *sp = uc;
    return 1;
  } else if (*u < 0x800) {
    *sp = (uc >> 6) | 0xC0;
    n = 1;
  } else if (uc < 0x10000) {
    *sp = (uc >> 12) | 0xE0;
    n = 2;
  } else if (uc <= 0x10FFFF) {
    *sp = (uc >> 18) | 0xF0;
    n = 3;
  } else {
    goto invalid;
  }
  for (i = n, ++sp; i > 0; --i, ++sp)
    *sp = ((uc >> 6 * (i - 1)) & 0x3F) | 0x80;
  return n + 1;
invalid:
  *s++ = '\xEF';
  *s++ = '\xBF';
  *s = '\xBD';
  return 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utf8_encode>:
  endbr64
  mov    (%rdi),%eax
  mov    %rsi,%rdx
  cmp    $0x7f,%eax
  jbe    L62
  cmp    $0x7ff,%eax
  jg     L17
  mov    %eax,%ecx
  and    $0x3f,%eax
  mov    $0x2,%r8d
  shr    $0x6,%ecx
  or     $0xffffff80,%eax
  or     $0xffffffc0,%ecx
  mov    %al,0x1(%rsi)
  mov    %cl,(%rsi)
L58:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    $0xffff,%eax
  jbe    L9
  cmp    $0x10ffff,%eax
  ja     L21
  mov    %eax,%ecx
  mov    $0x4,%r8d
  mov    $0x3,%edi
  shr    $0x12,%ecx
  or     $0xfffffff0,%ecx
L51:
  sub    $0x1,%edi
  mov    %cl,(%rdx)
  mov    %eax,%esi
  lea    (%rdi,%rdi,2),%ecx
  add    %ecx,%ecx
  shr    %cl,%esi
  sub    $0x6,%ecx
  and    $0x3f,%esi
  or     $0xffffff80,%esi
  mov    %sil,0x1(%rdx)
  mov    %eax,%esi
  shr    %cl,%esi
  mov    %esi,%ecx
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x2(%rdx)
  cmp    $0x1,%edi
  je     L58
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x3(%rdx)
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L62:
  mov    $0x1,%r8d
  mov    %al,(%rsi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    %eax,%ecx
  mov    $0x3,%r8d
  mov    $0x2,%edi
  shr    $0xc,%ecx
  or     $0xffffffe0,%ecx
  jmp    L51
  nopl   (%rax)
L21:
  mov    $0xffffbfef,%eax
  movb   $0xbd,0x2(%rsi)
  mov    $0x3,%r8d
  mov    %ax,(%rsi)
  jmp    L58
```

assistant: ```c
unsigned int utf8_encode(int *u, char *s) {
  unsigned char *sp = (unsigned char *)s;
  unsigned int uc = *u;
  int i;
  int n;
  if (uc < 0x80) {
    *sp = uc;
    return 1;
  } else if (*u < 0x800) {
    *sp = (uc >> 6) | 0xC0;
    n = 1;
  } else if (uc < 0x10000) {
    *sp = (uc >> 12) | 0xE0;
    n = 2;
  } else if (uc <= 0x10FFFF) {
    *sp = (uc >> 18) | 0xF0;
    n = 3;
  } else {
    goto invalid;
  }
  for (i = n, ++sp; i > 0; --i, ++sp)
    *sp = ((uc >> 6 * (i - 1)) & 0x3F) | 0x80;
  return n + 1;
invalid:
  *s++ = '\xEF';
  *s++ = '\xBF';
  *s = '\xBD';
  return 3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0x24(%rbp)
  movl   $0x18,-0x20(%rbp)
  movl   $0x24,-0x1c(%rbp)
  movl   $0x90,-0x18(%rbp)
  movl   $0x30,-0x14(%rbp)
  movl   $0x48,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L48
L25:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L48:
  cmpl   $0x4,-0x28(%rbp)
  jle    L25
  movl   $0x0,-0x28(%rbp)
  jmp    L27
L29:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <nok@plt>
  mov    %eax,-0x24(%rbp)
  addl   $0x1,-0x28(%rbp)
L27:
  cmpl   $0x4,-0x28(%rbp)
  jle    L29
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D0: %d 

tool: D14: res: %d


assistant: ```c
int main(int argc, char **argv) {
  srand((unsigned)time(NULL));
  int i, j, res = 1;
  int mas[5] = {24, 36, 144, 48, 72};
  for (i = 0; i < 5; ++i)
    printf("%d ", mas[i]);
  for (i = 0; i < 5; ++i)
    res = nok(res, mas[i]);
  printf("res: %d\n", res);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x18,(%rsp)
  movl   $0x24,0x4(%rsp)
  movl   $0x90,0x8(%rsp)
  movl   $0x30,0xc(%rsp)
  movl   $0x48,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  mov    %rbx,%rbp
  lea    D0(%rip),%r13
L0:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L0
  mov    $0x1,%edi
L23:
  mov    (%rbx),%esi
  call   <nok@plt>
  mov    %eax,%edi
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L23
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string

tool: D0: %d 

tool: D2: res: %d


assistant: ```c
int main(int argc, char **argv) {
  srand((unsigned)time(NULL));
  int i, j, res = 1;
  int mas[5] = {24, 36, 144, 48, 72};
  for (i = 0; i < 5; ++i)
    printf("%d ", mas[i]);
  for (i = 0; i < 5; ++i)
    res = nok(res, mas[i]);
  printf("res: %d\n", res);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  call   <time@plt>
  mov    %rbx,%rbp
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x18,%esi
  movabs $0x9000000024,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x4800000030,%rax
  mov    %rax,0xc(%rsp)
L6:
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  je     L15
  mov    0x0(%rbp),%esi
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%edi
  mov    $0x18,%esi
  add    $0x4,%rbx
  call   <nok@plt>
  mov    %eax,%edi
  cmp    %r12,%rbx
  je     L36
L46:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  call   <nok@plt>
  mov    %eax,%edi
  cmp    %r12,%rbx
  jne    L46
L36:
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string

tool: D17: %d 

tool: D2: res: %d


assistant: ```c
int main(int argc, char **argv) {
  srand((unsigned)time(NULL));
  int i, j, res = 1;
  int mas[5] = {24, 36, 144, 48, 72};
  for (i = 0; i < 5; ++i)
    printf("%d ", mas[i]);
  for (i = 0; i < 5; ++i)
    res = nok(res, mas[i]);
  printf("res: %d\n", res);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  call   <time@plt>
  mov    %rbx,%rbp
  mov    %eax,%edi
  call   <srand@plt>
  movdqa D21(%rip),%xmm0
  movl   $0x48,0x10(%rsp)
  movaps %xmm0,(%rsp)
L1:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L1
  mov    $0x1,%edi
L20:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  call   <nok@plt>
  mov    %eax,%edi
  cmp    %r12,%rbx
  jne    L20
  mov    %eax,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D21
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D5: %d 

tool: {"D21": [0x18,0x00,0x00,0x00,0x24,0x00,0x00,0x00,0x90,0x00,0x00,0x00,0x30,0x00,0x00,0x00]}

tool: D11: res: %d


assistant: ```c
int main(int argc, char **argv) {
  srand((unsigned)time(NULL));
  int i, j, res = 1;
  int mas[5] = {24, 36, 144, 48, 72};
  for (i = 0; i < 5; ++i)
    printf("%d ", mas[i]);
  for (i = 0; i < 5; ++i)
    res = nok(res, mas[i]);
  printf("res: %d\n", res);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand0max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  call   <random@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D4(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x18(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41]}

assistant: ```c
double rand0max(double max) {
  double randnum;
  randnum = (double)random();
  randnum /= ((double)((unsigned long)0xffffffff) + 1) / max;
  return randnum;
}
```
user: What is the c source code of the assembly code below?

```asm
<rand0max>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <random@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D6(%rip),%xmm1
  movq   %rbx,%xmm2
  divsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41]}

assistant: ```c
double rand0max(double max) {
  double randnum;
  randnum = (double)random();
  randnum /= ((double)((unsigned long)0xffffffff) + 1) / max;
  return randnum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand0max>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <random@plt>
  pxor   %xmm0,%xmm0
  movsd  D8(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41]}

assistant: ```c
double rand0max(double max) {
  double randnum;
  randnum = (double)random();
  randnum /= ((double)((unsigned long)0xffffffff) + 1) / max;
  return randnum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rand0max>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <random@plt>
  pxor   %xmm0,%xmm0
  movsd  D5(%rip),%xmm1
  divsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x41]}

assistant: ```c
double rand0max(double max) {
  double randnum;
  randnum = (double)random();
  randnum /= ((double)((unsigned long)0xffffffff) + 1) / max;
  return randnum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tablero_crear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L8
  cmpl   $0x6,-0x24(%rbp)
  jle    L8
  cmpl   $0x13,-0x24(%rbp)
  jle    L21
L8:
  mov    $0x0,%eax
  jmp    L51
L21:
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L51
L49:
  movl   $0x0,-0x1c(%rbp)
  jmp    L86
L12:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L6
  mov    $0x0,%eax
  jmp    L51
L6:
  addl   $0x1,-0x1c(%rbp)
L86:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    -0x18(%rbp),%rax
L51:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **tablero_crear(int size) {
  int i;
  char **tmptablero;
  if (size % 2 == 0 || !(7 <= size && size <= 19))
    return NULL;
  tmptablero = calloc(size, sizeof(*tmptablero));
  if (tmptablero == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    tmptablero[i] = calloc(size, sizeof(**tmptablero));
    if (tmptablero[i] == NULL)
      return NULL;
  }
  return tmptablero;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tablero_crear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x1,%dil
  je     L31
  mov    %edi,%ebp
  lea    -0x7(%rdi),%eax
  mov    $0x0,%r12d
  cmp    $0xc,%eax
  ja     L18
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    (%r12,%rax,8),%r13
L19:
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L63
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L19
  jmp    L18
L31:
  mov    $0x0,%r12d
  jmp    L18
L63:
  mov    %rax,%r12
L18:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **tablero_crear(int size) {
  int i;
  char **tmptablero;
  if (size % 2 == 0 || !(7 <= size && size <= 19))
    return NULL;
  tmptablero = calloc(size, sizeof(*tmptablero));
  if (tmptablero == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    tmptablero[i] = calloc(size, sizeof(**tmptablero));
    if (tmptablero[i] == NULL)
      return NULL;
  }
  return tmptablero;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tablero_crear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x1,%dil
  je     L35
  lea    -0x7(%rdi),%eax
  mov    %edi,%ebp
  cmp    $0xc,%eax
  ja     L35
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L35
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    (%r12,%rax,8),%r13
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L49
L40:
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L14
L35:
  xor    %r12d,%r12d
L49:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **tablero_crear(int size) {
  int i;
  char **tmptablero;
  if (size % 2 == 0 || !(7 <= size && size <= 19))
    return NULL;
  tmptablero = calloc(size, sizeof(*tmptablero));
  if (tmptablero == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    tmptablero[i] = calloc(size, sizeof(**tmptablero));
    if (tmptablero[i] == NULL)
      return NULL;
  }
  return tmptablero;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tablero_crear>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x1,%dil
  je     L49
  lea    -0x7(%rdi),%eax
  mov    %edi,%ebp
  cmp    $0xc,%eax
  ja     L49
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L49
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    (%r12,%rax,8),%r13
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L12
L23:
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L8
L49:
  xor    %r12d,%r12d
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **tablero_crear(int size) {
  int i;
  char **tmptablero;
  if (size % 2 == 0 || !(7 <= size && size <= 19))
    return NULL;
  tmptablero = calloc(size, sizeof(*tmptablero));
  if (tmptablero == NULL)
    return NULL;
  for (i = 0; i < size; i++) {
    tmptablero[i] = calloc(size, sizeof(**tmptablero));
    if (tmptablero[i] == NULL)
      return NULL;
  }
  return tmptablero;
}
```