ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Reals_TenL>:
  endbr64
  movsd  D13(%rip),%xmm0
  movsd  D18(%rip),%xmm1
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L20:
  mulsd  %xmm0,%xmm0
L6:
  test   $0x1,%dil
  je     L8
  mulsd  %xmm0,%xmm1
L8:
  sar    %edi
  test   %edi,%edi
  jg     L20
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: byte[8]
name: disassemble_data
arguments: tag: D18
datatype: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double Reals_TenL(int e) {
  double _o_result;
  double r, power;
  r = (double)1;
  power = (double)10;
  for (;;) {
    if (((e)&1)) {
      r = r * power;
    }
    e = ((long long)(e) >> (1));
    if (e <= 0) {
      _o_result = r;
      return _o_result;
    }
    power = power * power;
  }
__retchk:
  Platform_Halt(-3);
  return 0;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Reals_TenL>:
  endbr64
  movsd  D10(%rip),%xmm0
  movsd  D6(%rip),%xmm1
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L28:
  mulsd  %xmm0,%xmm0
L24:
  test   $0x1,%dil
  je     L4
  mulsd  %xmm0,%xmm1
L4:
  sar    %edi
  test   %edi,%edi
  jg     L28
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type: byte[8]
name: parse_data
arguments: tag: D6
type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double Reals_TenL(int e) {
  double _o_result;
  double r, power;
  r = (double)1;
  power = (double)10;
  for (;;) {
    if (((e)&1)) {
      r = r * power;
    }
    e = ((long long)(e) >> (1));
    if (e <= 0) {
      _o_result = r;
      return _o_result;
    }
    power = power * power;
  }
__retchk:
  Platform_Halt(-3);
  return 0;
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  shl    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <g@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int sz = sizeof *(0 ? 0 : (int(*)[f()])0);
  g(sz);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  lea    0x0(,%rax,4),%edi
  call   <g@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int sz = sizeof *(0 ? 0 : (int(*)[f()])0);
  g(sz);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  lea    0x0(,%rax,4),%edi
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int sz = sizeof *(0 ? 0 : (int(*)[f()])0);
  g(sz);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  lea    0x0(,%rax,4),%edi
  call   <g@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int sz = sizeof *(0 ? 0 : (int(*)[f()])0);
  g(sz);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ingredients>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <show_ingredients@plt>
  mov    $0x0,%eax
  call   <read_user@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ingredients() {
  show_ingredients();
  read_user();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ingredients>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <show_ingredients@plt>
  mov    $0x0,%eax
  call   <read_user@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ingredients() {
  show_ingredients();
  read_user();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ingredients>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <show_ingredients@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <read_user@plt>
```

assistant: ```c
void ingredients() {
  show_ingredients();
  read_user();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ingredients>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <show_ingredients@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <read_user@plt>
```

assistant: ```c
void ingredients() {
  show_ingredients();
  read_user();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inet6_insert_padopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L39
  cmpl   $0x1,-0xc(%rbp)
  jne    L6
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L18
L6:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0xc(%rbp),%edx
  sub    $0x2,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L18
L39:
  nop
L18:
  leave
  ret
```

assistant: ```c
void inet6_insert_padopt(u_char *p, int len) {
  switch (len) {
  case 0:
    return;
  case 1:
    p[0] = IP6OPT_PAD1;
    return;
  default:
    p[0] = IP6OPT_PADN;
    p[1] = len - 2;
    memset(&p[2], 0, len - 2);
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inet6_insert_padopt>:
  endbr64
  test   %esi,%esi
  je     L7
  cmp    $0x1,%esi
  jne    L19
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  ret
L19:
  sub    $0x8,%rsp
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  lea    -0x2(%rsi),%edx
  mov    %edx,0x4(%rdi)
  add    $0x8,%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void inet6_insert_padopt(u_char *p, int len) {
  switch (len) {
  case 0:
    return;
  case 1:
    p[0] = IP6OPT_PAD1;
    return;
  default:
    p[0] = IP6OPT_PADN;
    p[1] = len - 2;
    memset(&p[2], 0, len - 2);
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<inet6_insert_padopt>:
  endbr64
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  jne    L5
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L15:
  ret
  nopl   0x0(%rax)
L5:
  mov    D11(%rip),%rax
  lea    -0x2(%rsi),%edx
  add    $0x8,%rdi
  xor    %esi,%esi
  mov    %edx,-0x4(%rdi)
  mov    (%rax),%eax
  mov    %eax,-0x8(%rdi)
  jmp    1050 <memset@plt>
```

assistant: ```c
void inet6_insert_padopt(u_char *p, int len) {
  switch (len) {
  case 0:
    return;
  case 1:
    p[0] = IP6OPT_PAD1;
    return;
  default:
    p[0] = IP6OPT_PADN;
    p[1] = len - 2;
    memset(&p[2], 0, len - 2);
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inet6_insert_padopt>:
  endbr64
  test   %esi,%esi
  je     L15
  cmp    $0x1,%esi
  jne    L5
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdi)
  ret
  nopl   0x0(%rax)
L15:
  ret
  nopl   0x0(%rax)
L5:
  mov    D9(%rip),%rax
  lea    -0x2(%rsi),%edx
  add    $0x8,%rdi
  xor    %esi,%esi
  movd   %edx,%xmm1
  movd   (%rax),%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%rdi)
  jmp    1050 <memset@plt>
```

assistant: ```c
void inet6_insert_padopt(u_char *p, int len) {
  switch (len) {
  case 0:
    return;
  case 1:
    p[0] = IP6OPT_PAD1;
    return;
  default:
    p[0] = IP6OPT_PADN;
    p[1] = len - 2;
    memset(&p[2], 0, len - 2);
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jle    L14
  mov    -0x1c(%rbp),%eax
  cmp    $0x14,%eax
  jg     L14
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <retangulo@plt>
  jmp    L31
L14:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x14,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <retangulo@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string

tool: D29: Digite as linhas: 

tool: D26: %d

tool: D18: Digite as colunas: 

tool: D14: Seus valores de entrada foram alterados para %d %d


assistant: ```c
int main() {
  int linhas, colunas, novalinha, novacoluna, x, y;
  printf("Digite as linhas: ");
  scanf("%d", &linhas);
  printf("Digite as colunas: ");
  scanf("%d", &colunas);
  if ((linhas >= 1) && (colunas <= 20))
    retangulo(linhas, colunas);
  else {
    y = abs(linhas - 1);
    novalinha = linhas + y;
    x = colunas - 20;
    novacoluna = colunas - x;
    printf("Seus valores de entrada foram alterados para %d %d\n", novalinha, novacoluna);
    retangulo(novalinha, novacoluna);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D25(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L17
  mov    0x4(%rsp),%esi
  cmp    $0x14,%esi
  jle    L36
L17:
  lea    -0x1(%rdi),%eax
  mov    %eax,%ebx
  neg    %ebx
  cmovs  %eax,%ebx
  add    %edi,%ebx
  mov    $0x14,%edx
  mov    %ebx,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %ebx,%edi
  call   <retangulo@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L36:
  call   <retangulo@plt>
  jmp    L33
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D19: Digite as linhas: 

tool: D25: %d

tool: D18: Digite as colunas: 

tool: D23: Seus valores de entrada foram alterados para %d %d


assistant: ```c
int main() {
  int linhas, colunas, novalinha, novacoluna, x, y;
  printf("Digite as linhas: ");
  scanf("%d", &linhas);
  printf("Digite as colunas: ");
  scanf("%d", &colunas);
  if ((linhas >= 1) && (colunas <= 20))
    retangulo(linhas, colunas);
  else {
    y = abs(linhas - 1);
    novalinha = linhas + y;
    x = colunas - 20;
    novacoluna = colunas - x;
    printf("Seus valores de entrada foram alterados para %d %d\n", novalinha, novacoluna);
    retangulo(novalinha, novacoluna);
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D4(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L39
  mov    0x4(%rsp),%esi
  cmp    $0x14,%esi
  jle    L29
L39:
  lea    -0x1(%rdi),%eax
  mov    $0x14,%edx
  mov    %eax,%ebp
  neg    %ebp
  cmovs  %eax,%ebp
  xor    %eax,%eax
  add    %edi,%ebp
  lea    D25(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    $0x14,%esi
  call   <retangulo@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  call   <retangulo@plt>
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string

tool: D15: Digite as linhas: 

tool: D4: %d

tool: D21: Digite as colunas: 

tool: D25: Seus valores de entrada foram alterados para %d %d


assistant: ```c
int main() {
  int linhas, colunas, novalinha, novacoluna, x, y;
  printf("Digite as linhas: ");
  scanf("%d", &linhas);
  printf("Digite as colunas: ");
  scanf("%d", &colunas);
  if ((linhas >= 1) && (colunas <= 20))
    retangulo(linhas, colunas);
  else {
    y = abs(linhas - 1);
    novalinha = linhas + y;
    x = colunas - 20;
    novacoluna = colunas - x;
    printf("Seus valores de entrada foram alterados para %d %d\n", novalinha, novacoluna);
    retangulo(novalinha, novacoluna);
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  lea    D14(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L0
  mov    0x4(%rsp),%esi
  cmp    $0x14,%esi
  jle    L10
L0:
  lea    -0x1(%rdi),%eax
  mov    $0x14,%edx
  mov    %eax,%ebp
  neg    %ebp
  cmovs  %eax,%ebp
  xor    %eax,%eax
  add    %edi,%ebp
  lea    D11(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    $0x14,%esi
  call   <retangulo@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  call   <retangulo@plt>
  jmp    L24
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D33
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D29
type: string
name: read_data
arguments: label: D11
type: string

tool: D33: Digite as linhas: 

tool: D14: %d

tool: D29: Digite as colunas: 

tool: D11: Seus valores de entrada foram alterados para %d %d


assistant: ```c
int main() {
  int linhas, colunas, novalinha, novacoluna, x, y;
  printf("Digite as linhas: ");
  scanf("%d", &linhas);
  printf("Digite as colunas: ");
  scanf("%d", &colunas);
  if ((linhas >= 1) && (colunas <= 20))
    retangulo(linhas, colunas);
  else {
    y = abs(linhas - 1);
    novalinha = linhas + y;
    x = colunas - 20;
    novacoluna = colunas - x;
    printf("Seus valores de entrada foram alterados para %d %d\n", novalinha, novacoluna);
    retangulo(novalinha, novacoluna);
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L36
L29:
  mov    -0x24(%rbp),%eax
  test   %eax,%eax
  je     L10
  jmp    L12
L20:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L69
  movl   $0x64,-0x20(%rbp)
  jmp    L12
L69:
  movl   $0x32,-0x20(%rbp)
L12:
  cmpl   $0x31,-0x14(%rbp)
  jle    L20
  jmp    L36
L10:
  movl   $0x0,-0x1c(%rbp)
  jmp    L80
L61:
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L80:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L61
L36:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int a, b, c, d, h, i, j;
  scanf("%d", &h);
  while (h--) {
    if (h != 0) {
      while (a < 50) {
        if (b < c)
          d = 100;
        else
          d = 50;
      }
    } else {
      for (i = 0; i < d; i++) {
        j = j + i;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L21
  lea    -0x1(%rdx),%eax
  test   %eax,%eax
  je     L31
L45:
  jmp    L45
L31:
  add    $0x1,%eax
  cmp    %ebx,%eax
  jl     L31
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int a, b, c, d, h, i, j;
  scanf("%d", &h);
  while (h--) {
    if (h != 0) {
      while (a < 50) {
        if (b < c)
          d = 100;
        else
          d = 50;
      }
    } else {
      for (i = 0; i < d; i++) {
        j = j + i;
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L38
  lea    -0x1(%rdx),%eax
  test   %eax,%eax
  jne    L20
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  jmp    L20
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
int main() {
  int a, b, c, d, h, i, j;
  scanf("%d", &h);
  while (h--) {
    if (h != 0) {
      while (a < 50) {
        if (b < c)
          d = 100;
        else
          d = 50;
      }
    } else {
      for (i = 0; i < d; i++) {
        j = j + i;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L23
  lea    -0x1(%rdx),%eax
  test   %eax,%eax
  jne    L5
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  jmp    L5
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int a, b, c, d, h, i, j;
  scanf("%d", &h);
  while (h--) {
    if (h != 0) {
      while (a < 50) {
        if (b < c)
          d = 100;
        else
          d = 50;
      }
    } else {
      for (i = 0; i < d; i++) {
        j = j + i;
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getBestParents>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rcx,0x8(%rsp)
  mov    0x50(%rsp),%ebx
  mov    %r8d,%r15d
  cmp    0x58(%rsp),%r9d
  je     L15
  mov    %r9d,%r14d
  cmp    %esi,%ebx
  jl     L63
  jmp    L106
L15:
  test   %esi,%esi
  jle    L87
  mov    %r8d,%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  pxor   %xmm0,%xmm0
  mov    $0x1,%edi
  jmp    L105
L71:
  mov    %edi,%edx
  shl    %cl,%edx
  not    %edx
  and    %edx,%eax
  movzwl %ax,%edx
  movsd  0x0(%r13,%rdx,8),%xmm1
  comisd %xmm0,%xmm1
  cmova  %eax,%esi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
L73:
  add    $0x1,%ecx
  cmp    %ecx,%ebp
  je     L33
L105:
  cmp    %ecx,%r12d
  jne    L71
  jmp    L73
L87:
  mov    $0x0,%esi
L33:
  movzwl %r8w,%r8d
  movzwl %si,%eax
  movsd  0x0(%r13,%r8,8),%xmm0
  comisd 0x0(%r13,%rax,8),%xmm0
  cmovbe %esi,%r15d
  mov    0x8(%rsp),%rax
  mov    %r15w,(%rax,%r8,2)
L106:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L106
L63:
  cmp    %ebx,%r12d
  je     L25
  mov    $0x1,%r8d
  mov    %ebx,%ecx
  shl    %cl,%r8d
  or     %r15d,%r8d
  mov    0x58(%rsp),%eax
  add    $0x1,%eax
  push   %rax
  lea    0x1(%rbx),%eax
  push   %rax
  mov    %r14d,%r9d
  movzwl %r8w,%r8d
  mov    0x18(%rsp),%rcx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <getBestParents>
  add    $0x10,%rsp
  jmp    L25
```

assistant: ```c
void getBestParents(int currentNode, int numNode, double *localScore, unsigned short *bestParents, unsigned short parentPattern, int num, int start, int rank) {
  double maxScore;
  unsigned short maxScorePattern = 0;
  int i;
  if (num == rank) {
    unsigned short oneLeaveParentPattern = parentPattern;
    for (maxScore = 0, i = 0; i < numNode; i++) {
      if (i != currentNode) {
        oneLeaveParentPattern = oneLeaveParentPattern & ~(1 << i);
        if (maxScore < localScore[oneLeaveParentPattern]) {
          maxScore = localScore[oneLeaveParentPattern];
          maxScorePattern = oneLeaveParentPattern;
        }
      }
    }
    bestParents[parentPattern] = (localScore[parentPattern] > localScore[maxScorePattern]) ? parentPattern : maxScorePattern;
  } else {
    for (i = start; i < numNode; i++) {
      if (i != currentNode) {
        getBestParents(currentNode, numNode, localScore, bestParents, parentPattern | (1 << i), num, i + 1, rank + 1);
      }
    }
  }
}
```