ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L64
L83:
  mov    $0x0,%eax
  call   <soru_sor@plt>
  mov    %eax,-0x10(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L22
  movl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <cevap_karsiliklari@plt>
  addl   $0x1,-0x1c(%rbp)
  jmp    L11
L22:
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <cevap_karsiliklari@plt>
  addl   $0x1,-0x18(%rbp)
L11:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cmp    $0xa,%eax
  jne    L64
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xa,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2,-0x18(%rbp)
  jle    L47
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L42
L64:
  cmpl   $0x0,-0x14(%rbp)
  jle    L83
  jmp    L42
L47:
  nop
L42:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D19
type_infered: string

tool: D22: Sonuc = 

tool: D32: %d

tool: D23: %d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) 


tool: D19: Carpma islemine calisman lazim :)

assistant: ```c
int main() {
  srand(time(NULL));
  int sonsuz_dongu = 0;
  int dogru_cevap_sayisi = 0;
  int yanlis_cevap_sayisi = 0;
  while (sonsuz_dongu < 1) {
    int carpim_sonucu;
    carpim_sonucu = soru_sor();
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    int cevap_kontrolu;
    if (girilen_cevap == carpim_sonucu) {
      cevap_kontrolu = 1;
      cevap_karsiliklari(cevap_kontrolu);
      dogru_cevap_sayisi++;
    } else {
      cevap_kontrolu = 0;
      cevap_karsiliklari(cevap_kontrolu);
      yanlis_cevap_sayisi++;
    }
    if ((dogru_cevap_sayisi + yanlis_cevap_sayisi) == 10) {
      printf("%d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) \n", 10, dogru_cevap_sayisi, yanlis_cevap_sayisi);
      if (yanlis_cevap_sayisi >= (10 * 3) / 10) {
        printf("Carpma islemine calisman lazim :)");
      }
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    D38(%rip),%r15
  lea    0x4(%rsp),%r14
  lea    D12(%rip),%r13
  jmp    L16
L59:
  mov    $0x0,%edi
  call   <cevap_karsiliklari@plt>
  add    $0x1,%ebp
L28:
  lea    (%r12,%rbp,1),%eax
  cmp    $0xa,%eax
  je     L23
L16:
  mov    $0x0,%eax
  call   <soru_sor@plt>
  mov    %eax,%ebx
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L59
  mov    $0x1,%edi
  call   <cevap_karsiliklari@plt>
  add    $0x1,%r12d
  jmp    L28
L23:
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    $0xa,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x2,%ebp
  jg     L56
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L42
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D38
datatype: string
name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D14
datatype: string
name: disassemble_data
arguments: data_tag: D27
datatype: string

tool: D38: Sonuc = 

tool: D12: %d

tool: D14: %d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) 


tool: D27: Carpma islemine calisman lazim :)

assistant: ```c
int main() {
  srand(time(NULL));
  int sonsuz_dongu = 0;
  int dogru_cevap_sayisi = 0;
  int yanlis_cevap_sayisi = 0;
  while (sonsuz_dongu < 1) {
    int carpim_sonucu;
    carpim_sonucu = soru_sor();
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    int cevap_kontrolu;
    if (girilen_cevap == carpim_sonucu) {
      cevap_kontrolu = 1;
      cevap_karsiliklari(cevap_kontrolu);
      dogru_cevap_sayisi++;
    } else {
      cevap_kontrolu = 0;
      cevap_karsiliklari(cevap_kontrolu);
      yanlis_cevap_sayisi++;
    }
    if ((dogru_cevap_sayisi + yanlis_cevap_sayisi) == 10) {
      printf("%d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) \n", 10, dogru_cevap_sayisi, yanlis_cevap_sayisi);
      if (yanlis_cevap_sayisi >= (10 * 3) / 10) {
        printf("Carpma islemine calisman lazim :)");
      }
      break;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D32(%rip),%r15
  push   %r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %edi,%edi
  add    $0x1,%ebp
  call   <cevap_karsiliklari@plt>
  lea    (%r12,%rbp,1),%eax
  cmp    $0xa,%eax
  je     L6
L54:
  xor    %eax,%eax
  call   <soru_sor@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L31
  mov    $0x1,%edi
  add    $0x1,%r12d
  call   <cevap_karsiliklari@plt>
  lea    (%r12,%rbp,1),%eax
  cmp    $0xa,%eax
  jne    L54
L6:
  xor    %eax,%eax
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    $0xa,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  jg     L28
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L32
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D32: Sonuc = 

tool: D5: %d

tool: D16: %d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) 


tool: D7: Carpma islemine calisman lazim :)

assistant: ```c
int main() {
  srand(time(NULL));
  int sonsuz_dongu = 0;
  int dogru_cevap_sayisi = 0;
  int yanlis_cevap_sayisi = 0;
  while (sonsuz_dongu < 1) {
    int carpim_sonucu;
    carpim_sonucu = soru_sor();
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    int cevap_kontrolu;
    if (girilen_cevap == carpim_sonucu) {
      cevap_kontrolu = 1;
      cevap_karsiliklari(cevap_kontrolu);
      dogru_cevap_sayisi++;
    } else {
      cevap_kontrolu = 0;
      cevap_karsiliklari(cevap_kontrolu);
      yanlis_cevap_sayisi++;
    }
    if ((dogru_cevap_sayisi + yanlis_cevap_sayisi) == 10) {
      printf("%d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) \n", 10, dogru_cevap_sayisi, yanlis_cevap_sayisi);
      if (yanlis_cevap_sayisi >= (10 * 3) / 10) {
        printf("Carpma islemine calisman lazim :)");
      }
      break;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D1(%rip),%r15
  push   %r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  call   <soru_sor@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  je     L60
  xor    %edi,%edi
  add    $0x1,%ebp
  call   <cevap_karsiliklari@plt>
  lea    (%r12,%rbp,1),%eax
  cmp    $0xa,%eax
  jne    L64
L26:
  xor    %eax,%eax
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    $0xa,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  jg     L25
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L60:
  mov    $0x1,%edi
  add    $0x1,%r12d
  call   <cevap_karsiliklari@plt>
  lea    0x0(%rbp,%r12,1),%eax
  cmp    $0xa,%eax
  jne    L64
  jmp    L26
L25:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L37
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D23
type_infered: string
name: unpack_data
arguments: data_tag: D32
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: string

tool: D1: Sonuc = 

tool: D23: %d

tool: D32: %d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) 


tool: D21: Carpma islemine calisman lazim :)

assistant: ```c
int main() {
  srand(time(NULL));
  int sonsuz_dongu = 0;
  int dogru_cevap_sayisi = 0;
  int yanlis_cevap_sayisi = 0;
  while (sonsuz_dongu < 1) {
    int carpim_sonucu;
    carpim_sonucu = soru_sor();
    int girilen_cevap;
    printf("Sonuc = ");
    scanf("%d", &girilen_cevap);
    int cevap_kontrolu;
    if (girilen_cevap == carpim_sonucu) {
      cevap_kontrolu = 1;
      cevap_karsiliklari(cevap_kontrolu);
      dogru_cevap_sayisi++;
    } else {
      cevap_kontrolu = 0;
      cevap_karsiliklari(cevap_kontrolu);
      yanlis_cevap_sayisi++;
    }
    if ((dogru_cevap_sayisi + yanlis_cevap_sayisi) == 10) {
      printf("%d sorudan %d dogru cevabiniz %d yanlis cevabiniz var :) \n", 10, dogru_cevap_sayisi, yanlis_cevap_sayisi);
      if (yanlis_cevap_sayisi >= (10 * 3) / 10) {
        printf("Carpma islemine calisman lazim :)");
      }
      break;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printnames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L28:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L28
L38:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L15
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L15:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x58(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <printnames_util@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void printnames(char num[]) {
  int len = strlen(num);
  char str[len + 1];
  printnames_util(num, str, len, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printnames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%edx
  lea    0x1(%rax),%ecx
  movslq %ecx,%rcx
  add    $0xf,%rcx
  mov    %rcx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rax
  sub    %rcx,%rax
L7:
  cmp    %rax,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L34:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L2
  orq    $0x0,-0x8(%rsp,%rax,1)
L2:
  mov    $0x0,%ecx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <printnames_util@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    -0x8(%rbp),%rbx
  leave
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnames(char num[]) {
  int len = strlen(num);
  char str[len + 1];
  printnames_util(num, str, len, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printnames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x1(%rax),%ecx
  mov    %eax,%edx
  movslq %ecx,%rcx
  add    $0xf,%rcx
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rax
  cmp    %rsi,%rsp
  je     L1
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L16
L1:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L22
L40:
  xor    %ecx,%ecx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <printnames_util@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    -0x8(%rbp),%r12
  leave
  ret
  xchg   %ax,%ax
L22:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L40
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnames(char num[]) {
  int len = strlen(num);
  char str[len + 1];
  printnames_util(num, str, len, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printnames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x1(%rax),%ecx
  mov    %eax,%edx
  movslq %ecx,%rcx
  add    $0xf,%rcx
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rsi
  and    $0xfffffffffffffff0,%rax
  cmp    %rsi,%rsp
  je     L25
L18:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L18
L25:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L41
L21:
  xor    %ecx,%ecx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <printnames_util@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    -0x8(%rbp),%r12
  leave
  ret
  xchg   %ax,%ax
L41:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L21
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printnames(char num[]) {
  int len = strlen(num);
  char str[len + 1];
  printnames_util(num, str, len, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<fac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L6
L9:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fac(int m) {
  int fact = 1;
  int c;
  for (c = 1; c <= m; c++) {
    fact = fact * c;
  }
  return fact;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fac>:
  endbr64
  test   %edi,%edi
  jle    L4
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%edx
L28:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L28
L7:
  mov    %edx,%eax
  ret
L4:
  mov    $0x1,%edx
  jmp    L7
```

assistant: ```c
int fac(int m) {
  int fact = 1;
  int c;
  for (c = 1; c <= m; c++) {
    fact = fact * c;
  }
  return fact;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fac>:
  endbr64
  test   %edi,%edi
  jle    L3
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L7:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L7
  mov    %r8d,%eax
  ret
  nop
L3:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fac(int m) {
  int fact = 1;
  int c;
  for (c = 1; c <= m; c++) {
    fact = fact * c;
  }
  return fact;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fac>:
  endbr64
  test   %edi,%edi
  jle    L16
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L3:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L3
  mov    %r8d,%eax
  ret
  nop
L16:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fac(int m) {
  int fact = 1;
  int c;
  for (c = 1; c <= m; c++) {
    fact = fact * c;
  }
  return fact;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<complain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int complain(const char *errstr, ...) {
  int rc;
  va_list ap;
  va_start(ap, errstr);
  rc = vfprintf(stderr, errstr, ap);
  va_end(ap);
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<complain>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int complain(const char *errstr, ...) {
  int rc;
  va_list ap;
  va_start(ap, errstr);
  rc = vfprintf(stderr, errstr, ap);
  va_end(ap);
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<complain>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int complain(const char *errstr, ...) {
  int rc;
  va_list ap;
  va_start(ap, errstr);
  rc = vfprintf(stderr, errstr, ap);
  va_end(ap);
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<complain>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int complain(const char *errstr, ...) {
  int rc;
  va_list ap;
  va_start(ap, errstr);
  rc = vfprintf(stderr, errstr, ap);
  va_end(ap);
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checked_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *checked_malloc(int len) {
  void *p = malloc(len);
  assert(p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checked_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *checked_malloc(int len) {
  void *p = malloc(len);
  assert(p);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<checked_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *checked_malloc(int len) {
  void *p = malloc(len);
  assert(p);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checked_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *checked_malloc(int len) {
  void *p = malloc(len);
  assert(p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L0:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maxint(int *ar, int len) {
  int MaxEntry;
  int i;
  MaxEntry = ar[0];
  for (i = 0; i < len; i++) {
    if (ar[i] > MaxEntry) {
      MaxEntry = ar[i];
    }
  }
  return MaxEntry;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<maxint>:
  endbr64
  mov    (%rdi),%edx
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rsi
L9:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
L17:
  mov    %edx,%eax
  ret
```

assistant: ```c
int maxint(int *ar, int len) {
  int MaxEntry;
  int i;
  MaxEntry = ar[0];
  for (i = 0; i < len; i++) {
    if (ar[i] > MaxEntry) {
      MaxEntry = ar[i];
    }
  }
  return MaxEntry;
}
```