user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L89:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L89
  sub    $0xe70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e68(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L158
  lea    D27(%rip),%r12
  lea    D8(%rip),%rbp
  lea    0x21(%rsp),%rbx
  jmp    L187
L8:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L60
L47:
  movzbl (%rax),%edx
  movzbl 0x1(%rax),%ecx
  cmp    %cl,%dl
  jle    L8
  mov    %cl,(%rax)
  mov    %dl,0x1(%rax)
  jmp    L8
L60:
  add    $0x1,%edi
  cmp    %r8d,%edi
  je     L119
L167:
  lea    0x20(%rsp),%rax
  cmp    $0x1,%r8d
  jg     L47
  jmp    L60
L119:
  lea    -0x1(%r8),%eax
  cltq
  movzbl 0x20(%rsp,%rax,1),%eax
  mov    %al,0x1b(%rsp)
  cmp    $0x1,%r8d
  jle    L179
  mov    $0x1,%eax
  lea    0x1f(%rsp),%rcx
L139:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,0x1b(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L139
L179:
  lea    0x10(%rsp),%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpq   $0x0,0x10(%rsp)
  je     L78
  mov    $0x1,%r13d
  mov    $0x0,%r14d
L32:
  mov    %r13,%rsi
  mov    0xc(%rsp),%edi
  call   <pow@plt>
  add    %rax,%r14
  mov    %r13,%rdi
  add    $0x1,%r13
  mov    0x10(%rsp),%rcx
  cmp    %r14,%rcx
  ja     L32
  test   %rdi,%rdi
  je     L78
  movslq 0xc(%rsp),%rsi
  lea    0x40(%rsp),%r8
  lea    (%r8,%rdi,1),%r13
L111:
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  movzbl 0x1b(%rsp,%rdx,1),%eax
  cmp    $0x1,%rdx
  sbb    $0x0,%rcx
  mov    %al,-0x1(%r13)
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,%rcx
  sub    $0x1,%r13
  cmp    %r8,%r13
  jne    L111
  mov    %rax,0x10(%rsp)
  lea    0x0(%r13,%rdi,1),%r14
L34:
  movsbl 0x0(%r13),%edi
  call   <putchar@plt>
  add    $0x1,%r13
  cmp    %r14,%r13
  jne    L34
L78:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L158
L187:
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  lea    0x50(%rsp),%rdi
  mov    $0x4e10,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movl   $0x6e616d75,0x1b(%rsp)
  movb   $0x6b,0x1f(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    $0x0,%edi
  lea    -0x2(%r8),%esi
  add    %rbx,%rsi
  test   %r8d,%r8d
  jg     L167
  jmp    L119
L158:
  mov    0x4e68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  mov    $0x0,%eax
  add    $0x4e70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D27: %d

tool: D8: %s

tool: D18: %llu

assistant: ```c
int main() {
  unsigned long long a, j;
  int times;
  scanf("%d", &times);
  while (times--) {
    char s[20000] = {0}, std[5] = {'u', 'm', 'a', 'n', 'k'}, s2[20000] = {0};
    int sac;
    scanf("%d", &sac);
    int sa;
    char word[27];
    scanf("%s", word);
    int i1, j1;
    for (i1 = 0; i1 < sac; i1++) {
      for (j1 = 0; j1 < sac - 1; j1++) {
        if (word[j1] > word[j1 + 1]) {
          int zw = word[j1];
          word[j1] = word[j1 + 1];
          word[j1 + 1] = zw;
        }
      }
    }
    std[0] = word[sac - 1];
    for (i1 = 1; i1 < sac; i1++)
      std[i1] = word[i1 - 1];
    scanf("%llu", &a);
    unsigned long long sum = 0, i = 1;
    while (a > sum) {
      sum = sum + pow(sac, i);
      i++;
    }
    i--;
    unsigned long long ch = i;
    while (i--) {
      s[i] = std[a % sac];
      if (a % sac == 0)
        a--;
      a = a / sac;
    }
    for (j = 0; j < ch; j++)
      printf("%c", s[j]);
    printf("\n");
  }
  return 0;
}
```