ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebp
  mov    $0x1,%ebx
  lea    D9(%rip),%r12
  jmp    L67
L111:
  mov    %ebx,%edi
  jmp    L38
L82:
  mov    %ebx,%edi
L38:
  lea    0x1(%rdi),%ebx
  mov    %ebx,%esi
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  cmp    $0x3,%ebx
  jle    L70
  test   $0x1,%bl
  je     L111
  mov    $0x2,%ecx
L11:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jg     L26
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L11
  jmp    L82
L72:
  mov    %eax,%ecx
L7:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %edx,%esi
  lea    0x1(%rcx),%eax
  cmp    %ecx,%edi
  jge    L72
  cmp    $0x1,%esi
  je     L20
L12:
  cmp    $0xa,%ebp
  jg     L134
L67:
  mov    %ebx,%edi
  jmp    L38
L70:
  lea    0x3(%rdi),%r8d
  cmp    $0x1,%ebx
  jg     L135
L20:
  mov    %r8d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  jmp    L12
L26:
  lea    0x3(%rdi),%r8d
L135:
  mov    $0x1,%esi
  mov    $0x2,%ecx
  jmp    L7
L134:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: (%d;%d)


assistant: ```c
int main() {
  int i, j, n, boolean, a, b, g;
  n = 1;
  i = 1;
  while (n <= 10) {
    do {
      i++;
      boolean = 1;
      for (g = 2; g <= i / 2; g++) {
        if (i % g == 0) {
          boolean = 0;
          break;
        }
      }
    } while (boolean == 0);
    a = i;
    b = a + 2;
    if (boolean = 1) {
      for (j = 2; j <= i; j++) {
        if (b % j == 0)
          boolean = 0;
      }
      if (boolean == 1) {
        printf("(%d;%d)\n", a, b);
        n++;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r12d,%edi
  add    $0x1,%r12d
  mov    %r12d,%esi
  sar    %esi
  cmp    $0x1,%esi
  je     L0
  test   $0x1,%r12b
  je     L10
  add    $0x1,%esi
  mov    $0x2,%ecx
  jmp    L1
  nopl   0x0(%rax)
L25:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L10
L1:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L25
L0:
  lea    0x3(%rdi),%r8d
  mov    $0x1,%esi
  add    $0x2,%edi
  mov    $0x2,%ecx
  xor    %r9d,%r9d
L3:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r9d,%esi
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L3
  cmp    $0x1,%esi
  je     L29
L17:
  cmp    $0xb,%ebx
  jne    L10
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: (%d;%d)


assistant: ```c
int main() {
  int i, j, n, boolean, a, b, g;
  n = 1;
  i = 1;
  while (n <= 10) {
    do {
      i++;
      boolean = 1;
      for (g = 2; g <= i / 2; g++) {
        if (i % g == 0) {
          boolean = 0;
          break;
        }
      }
    } while (boolean == 0);
    a = i;
    b = a + 2;
    if (boolean = 1) {
      for (j = 2; j <= i; j++) {
        if (b % j == 0)
          boolean = 0;
      }
      if (boolean == 1) {
        printf("(%d;%d)\n", a, b);
        n++;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L38:
  lea    0x1(%rdi),%r12d
  mov    %r12d,%esi
  sar    %esi
  cmp    $0x1,%esi
  je     L12
  test   $0x1,%r12b
  je     L22
  add    $0x1,%esi
  mov    $0x2,%ecx
  jmp    L37
  xchg   %ax,%ax
L6:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
L37:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L6
L12:
  lea    0x3(%rdi),%r8d
  mov    $0x1,%esi
  add    $0x2,%edi
  mov    $0x2,%ecx
  xor    %r9d,%r9d
L41:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r9d,%esi
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jne    L41
  cmp    $0x1,%esi
  je     L15
  cmp    $0xb,%ebx
  je     L32
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12d,%edi
  jmp    L38
L15:
  mov    %r8d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xb,%ebx
  jne    L22
L32:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: (%d;%d)


assistant: ```c
int main() {
  int i, j, n, boolean, a, b, g;
  n = 1;
  i = 1;
  while (n <= 10) {
    do {
      i++;
      boolean = 1;
      for (g = 2; g <= i / 2; g++) {
        if (i % g == 0) {
          boolean = 0;
          break;
        }
      }
    } while (boolean == 0);
    a = i;
    b = a + 2;
    if (boolean = 1) {
      for (j = 2; j <= i; j++) {
        if (b % j == 0)
          boolean = 0;
      }
      if (boolean == 1) {
        printf("(%d;%d)\n", a, b);
        n++;
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fast_mod7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x24924924,%eax,%eax
  shr    $0x1d,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x7,%eax
  sar    $0x1f,%eax
  and    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((no)) fast_mod7(int n) {
  n = (unsigned)n * 0x24924924 >> 29;
  return n & ((n - 7) >> 31);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fast_mod7>:
  endbr64
  imul   $0x24924924,%edi,%edi
  shr    $0x1d,%edi
  lea    -0x7(%rdi),%eax
  sar    $0x1f,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int __attribute__((no)) fast_mod7(int n) {
  n = (unsigned)n * 0x24924924 >> 29;
  return n & ((n - 7) >> 31);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fast_mod7>:
  endbr64
  imul   $0x24924924,%edi,%edi
  shr    $0x1d,%edi
  lea    -0x7(%rdi),%eax
  sar    $0x1f,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int __attribute__((no)) fast_mod7(int n) {
  n = (unsigned)n * 0x24924924 >> 29;
  return n & ((n - 7) >> 31);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fast_mod7>:
  endbr64
  imul   $0x24924924,%edi,%edi
  shr    $0x1d,%edi
  lea    -0x7(%rdi),%eax
  sar    $0x1f,%eax
  and    %edi,%eax
  ret
```

assistant: ```c
int __attribute__((no)) fast_mod7(int n) {
  n = (unsigned)n * 0x24924924 >> 29;
  return n & ((n - 7) >> 31);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L48
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L48
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L48:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L26
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L26
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L40
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L40
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L40:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int small;
  if (a <= b && a <= c)
    small = a;
  if (b <= a && b <= c)
    small = b;
  if (c <= a && c <= b)
    small = c;
  return small;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%eax
  cmovle %esi,%eax
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovle %edi,%eax
  cmp    %edx,%edi
  mov    %edx,%ecx
  cmovle %edi,%ecx
  cmp    %ecx,%esi
  cmovle %esi,%eax
  cmp    %esi,%edi
  cmovg  %esi,%edi
  cmp    %edi,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int small;
  if (a <= b && a <= c)
    small = a;
  if (b <= a && b <= c)
    small = b;
  if (c <= a && c <= b)
    small = c;
  return small;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%eax
  mov    %edx,%ecx
  cmovle %esi,%eax
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovle %edi,%eax
  cmp    %edx,%edi
  cmovle %edi,%ecx
  cmp    %ecx,%esi
  cmovle %esi,%eax
  cmp    %esi,%edi
  cmovg  %esi,%edi
  cmp    %edi,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int small;
  if (a <= b && a <= c)
    small = a;
  if (b <= a && b <= c)
    small = b;
  if (c <= a && c <= b)
    small = c;
  return small;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  cmp    %edx,%esi
  mov    %edx,%eax
  mov    %edx,%ecx
  cmovle %esi,%eax
  cmp    %eax,%edi
  mov    $0x0,%eax
  cmovle %edi,%eax
  cmp    %edx,%edi
  cmovle %edi,%ecx
  cmp    %ecx,%esi
  cmovle %esi,%eax
  cmp    %esi,%edi
  cmovg  %esi,%edi
  cmp    %edi,%edx
  cmovle %edx,%eax
  ret
```

assistant: ```c
int min(int a, int b, int c) {
  int small;
  if (a <= b && a <= c)
    small = a;
  if (b <= a && b <= c)
    small = b;
  if (c <= a && c <= b)
    small = c;
  return small;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<declare_int2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <vcalloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L2
L17:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <vcalloc@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int **declare_int2(int f, int *s, int d) {
  int **r;
  int a;
  r = vcalloc(f, sizeof(int *));
  for (a = 0; a < f; a++)
    r[a] = vcalloc(s[a] + d, sizeof(int));
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<declare_int2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    $0x8,%esi
  call   <vcalloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L13
  mov    %ebp,%ebp
  mov    $0x0,%ebx
L8:
  mov    %r14d,%edi
  add    0x0(%r13,%rbx,4),%edi
  mov    $0x4,%esi
  call   <vcalloc@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L8
L13:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **declare_int2(int f, int *s, int d) {
  int **r;
  int a;
  r = vcalloc(f, sizeof(int *));
  for (a = 0; a < f; a++)
    r[a] = vcalloc(s[a] + d, sizeof(int));
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<declare_int2>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %ebp,%edi
  call   <vcalloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L19
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    0x0(%r13,%rbx,4),%edi
  mov    $0x4,%esi
  add    %r14d,%edi
  call   <vcalloc@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
L19:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **declare_int2(int f, int *s, int d) {
  int **r;
  int a;
  r = vcalloc(f, sizeof(int *));
  for (a = 0; a < f; a++)
    r[a] = vcalloc(s[a] + d, sizeof(int));
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<declare_int2>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %ebp,%edi
  call   <vcalloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L5
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x0(%r13,%rbx,4),%edi
  mov    $0x4,%esi
  add    %r14d,%edi
  call   <vcalloc@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L9
L5:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **declare_int2(int f, int *s, int d) {
  int **r;
  int a;
  r = vcalloc(f, sizeof(int *));
  for (a = 0; a < f; a++)
    r[a] = vcalloc(s[a] + d, sizeof(int));
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply320>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L6
L0:
  movl   $0x0,-0x3c(%rbp)
  jmp    L4
L25:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L4:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L25
  addl   $0x1,-0x40(%rbp)
L6:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply320(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply320>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L13:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L6:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L6
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  ret
```

assistant: ```c
void multiply320(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply320>:
  endbr64
  test   %edi,%edi
  jle    L26
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L5
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L16
  pop    %rbx
  ret
L26:
  ret
```

assistant: ```c
void multiply320(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply320>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L50
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L58:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L19
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L19
  nopl   0x0(%rax)
L67:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L67
  cmp    -0x24(%rsp),%r11d
  je     L81
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L81
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L81
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L81:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L58
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L55:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L55
  mov    -0x18(%rsp),%r8
  jmp    L81
```

assistant: ```c
void multiply320(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<caltv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long caltv(struct timeval *pstv, struct timeval *petv) {
  struct timeval result;
  result.tv_sec = petv->tv_sec - pstv->tv_sec;
  result.tv_usec = petv->tv_usec - pstv->tv_usec;
  return result.tv_sec * 1000000 + result.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<caltv>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  ret
```

assistant: ```c
unsigned long caltv(struct timeval *pstv, struct timeval *petv) {
  struct timeval result;
  result.tv_sec = petv->tv_sec - pstv->tv_sec;
  result.tv_usec = petv->tv_usec - pstv->tv_usec;
  return result.tv_sec * 1000000 + result.tv_usec;
}
```
user: What is the c source code of the assembly code below:

```asm
<caltv>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  ret
```

assistant: ```c
unsigned long caltv(struct timeval *pstv, struct timeval *petv) {
  struct timeval result;
  result.tv_sec = petv->tv_sec - pstv->tv_sec;
  result.tv_usec = petv->tv_usec - pstv->tv_usec;
  return result.tv_sec * 1000000 + result.tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<caltv>:
  endbr64
  mov    (%rsi),%eax
  sub    (%rdi),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    0x8(%rsi),%rax
  sub    0x8(%rdi),%rax
  ret
```

assistant: ```c
unsigned long caltv(struct timeval *pstv, struct timeval *petv) {
  struct timeval result;
  result.tv_sec = petv->tv_sec - pstv->tv_sec;
  result.tv_usec = petv->tv_usec - pstv->tv_usec;
  return result.tv_sec * 1000000 + result.tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TH_halfbits2float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0xf,%eax
  and    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0xa,%eax
  and    $0x1f,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0xd,%eax
  and    $0x7fe000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1f,-0x10(%rbp)
  jne    L56
  cmpl   $0x0,-0xc(%rbp)
  je     L14
  movl   $0x0,-0x14(%rbp)
  mov    $0x7fffff,%eax
  jmp    L34
L14:
  mov    $0x0,%eax
L34:
  mov    %eax,-0xc(%rbp)
  movl   $0xff,-0x10(%rbp)
  jmp    L29
L56:
  cmpl   $0x0,-0x10(%rbp)
  jne    L62
  cmpl   $0x0,-0xc(%rbp)
  je     L29
  movl   $0x71,-0x10(%rbp)
L66:
  mov    -0xc(%rbp),%eax
  and    $0x400000,%eax
  mov    %eax,-0x4(%rbp)
  shll   -0xc(%rbp)
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L66
  andl   $0x7fffff,-0xc(%rbp)
  jmp    L29
L62:
  addl   $0x70,-0x10(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  shl    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  shl    $0x17,%eax
  or     %edx,%eax
  or     -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TH_halfbits2float(unsigned short *src, float *res) {
  unsigned h = *src;
  unsigned sign = ((h >> 15) & 1);
  unsigned exponent = ((h >> 10) & 0x1f);
  unsigned mantissa = ((h & 0x3ff) << 13);
  if (exponent == 0x1f) {
    mantissa = (mantissa ? (sign = 0, 0x7fffff) : 0);
    exponent = 0xff;
  } else if (!exponent) {
    if (mantissa) {
      unsigned int msb;
      exponent = 0x71;
      do {
        msb = (mantissa & 0x400000);
        mantissa <<= 1;
        --exponent;
      } while (!msb);
      mantissa &= 0x7fffff;
    }
  } else {
    exponent += 0x70;
  }
  *(unsigned *)res = ((sign << 31) | (exponent << 23) | mantissa);
}
```