user: Translate the below assembly code into C programming language:

```asm
<lengthOfLongestSubstring>:
  endbr64
  push   %r15
  mov    $0x40,%ecx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x228,%rsp
  mov    %rdi,(%rsp)
  lea    0x10(%rsp),%r14
  mov    %r14,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  rep stos %rax,%es:(%rdi)
  je     L109
  movl   $0x0,0xc(%rsp)
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  movl   $0x0,0x8(%rsp)
  lea    D6(%rip),%rbx
L116:
  mov    0x8(%rsp),%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  mov    %r15d,%edx
  jmp    L125
  cs nopw 0x0(%rax,%rax,1)
L70:
  add    $0x1,%r12
  cmp    $0x80,%r12
  je     L25
L128:
  mov    (%r14,%r12,4),%edx
L125:
  mov    %r12d,%esi
  test   %edx,%edx
  je     L70
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    $0x80,%r12
  jne    L128
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    (%rsp),%rax
  movsbq (%rax),%rax
  mov    0x10(%rsp,%rax,4),%eax
  cmp    0x8(%rsp),%eax
  jle    L16
  cmp    %ebp,%r13d
  mov    %eax,0x8(%rsp)
  cmovl  %ebp,%r13d
  mov    0xc(%rsp),%ebp
  sub    %eax,%ebp
L16:
  mov    0x8(%rsp),%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L98:
  add    $0x1,%r12
  cmp    $0x80,%r12
  je     L129
L112:
  mov    (%r14,%r12,4),%r15d
L0:
  mov    %r12d,%esi
  test   %r15d,%r15d
  je     L98
  mov    %r15d,%edx
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    $0x80,%r12
  jne    L112
L129:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%ecx
  movsbq (%rax),%rdx
  mov    %ecx,0x10(%rsp,%rdx,4)
  test   %dl,%dl
  je     L139
  mov    0x10(%rsp),%r15d
  jmp    L116
L139:
  cmp    %ebp,%r13d
  mov    %ebp,%eax
  cmovge %r13d,%eax
L60:
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L109:
  xor    %eax,%eax
  jmp    L60
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string
name: retrieve_data
arguments: data_tag: D14
datatype: string

tool: D6: pos[%c] = %d 

tool: D18: bef: longest = %d, currentLength = %d, start = %d


tool: D14: aft: longest = %d, currentLength = %d, start = %d


assistant: ```c
int lengthOfLongestSubstring(char *s) {
  int longest = 0, currentLength = 0, start = 0, position[128] = {0};
  int i, j;
  for (i = 0; s[i]; position[s[i]] = ++i, currentLength++) {
    printf("bef: longest = %d, currentLength = %d, start = %d\n", longest, currentLength, start);
    for (j = 0; j < 128; ++j) {
      if (position[j]) {
        printf("pos[%c] = %d ", j, position[j]);
      }
    }
    printf("\n");
    if (position[s[i]] > start) {
      longest = (longest > currentLength) ? longest : currentLength;
      start = position[s[i]];
      currentLength = i - position[s[i]];
    }
    printf("aft: longest = %d, currentLength = %d, start = %d\n", longest, currentLength, start);
    for (j = 0; j < 128; ++j) {
      if (position[j]) {
        printf("pos[%c] = %d ", j, position[j]);
      }
    }
    printf("\n");
  }
  return (longest > currentLength) ? longest : currentLength;
}
```