ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert_sort0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L45:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L46
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L25
L46:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L49
L25:
  subl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x8(%rbp)
  jns    L45
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L49:
  pop    %rbp
  ret
```

assistant: ```c
void insert_sort0(int *arr, int index) {
  int i, tmp = arr[index];
  for (i = index - 1; i >= 0; i--) {
    if (arr[i] > tmp) {
      arr[i + 1] = arr[i];
    } else {
      arr[i + 1] = tmp;
      return;
    }
  }
  arr[i + 1] = tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insert_sort0>:
  endbr64
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%ecx
  sub    $0x1,%esi
  js     L9
  movslq %esi,%rax
L17:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L28
  mov    %edx,0x4(%rdi,%rax,4)
  lea    -0x1(%rax),%esi
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L17
L9:
  add    $0x1,%esi
  movslq %esi,%rsi
  mov    %ecx,(%rdi,%rsi,4)
  ret
L28:
  mov    %ecx,0x4(%rdi,%rax,4)
  ret
```

assistant: ```c
void insert_sort0(int *arr, int index) {
  int i, tmp = arr[index];
  for (i = index - 1; i >= 0; i--) {
    if (arr[i] > tmp) {
      arr[i + 1] = arr[i];
    } else {
      arr[i + 1] = tmp;
      return;
    }
  }
  arr[i + 1] = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_sort0>:
  endbr64
  movslq %esi,%rcx
  mov    %rcx,%rdx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%r8
  mov    (%r8),%r9d
  test   %edx,%edx
  jle    L16
  sub    $0x1,%edx
  lea    -0x4(%rdi,%rcx,1),%rsi
  mov    %r8,%rax
  shl    $0x2,%rdx
  sub    %rdx,%rsi
  jmp    L27
  nopl   (%rax)
L31:
  mov    %ecx,(%rdx)
  cmp    %rsi,%rax
  je     L16
L27:
  mov    %rax,%rdx
  sub    $0x4,%rax
  mov    -0x4(%rdx),%ecx
  mov    %rax,%r8
  cmp    %r9d,%ecx
  jg     L31
  mov    %r9d,(%rdx)
  ret
  nopl   (%rax)
L16:
  mov    %r9d,(%r8)
  ret
```

assistant: ```c
void insert_sort0(int *arr, int index) {
  int i, tmp = arr[index];
  for (i = index - 1; i >= 0; i--) {
    if (arr[i] > tmp) {
      arr[i + 1] = arr[i];
    } else {
      arr[i + 1] = tmp;
      return;
    }
  }
  arr[i + 1] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insert_sort0>:
  endbr64
  movslq %esi,%rcx
  mov    %rcx,%rdx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%r8
  mov    (%r8),%r9d
  test   %edx,%edx
  jle    L17
  sub    $0x1,%edx
  lea    -0x4(%rdi,%rcx,1),%rsi
  mov    %r8,%rax
  shl    $0x2,%rdx
  sub    %rdx,%rsi
  jmp    L9
  nopl   (%rax)
L12:
  mov    %ecx,(%rdx)
  cmp    %rsi,%rax
  je     L17
L9:
  mov    %rax,%rdx
  sub    $0x4,%rax
  mov    -0x4(%rdx),%ecx
  mov    %rax,%r8
  cmp    %r9d,%ecx
  jg     L12
  mov    %r9d,(%rdx)
  ret
  nopl   (%rax)
L17:
  mov    %r9d,(%r8)
  ret
```

assistant: ```c
void insert_sort0(int *arr, int index) {
  int i, tmp = arr[index];
  for (i = index - 1; i >= 0; i--) {
    if (arr[i] > tmp) {
      arr[i + 1] = arr[i];
    } else {
      arr[i + 1] = tmp;
      return;
    }
  }
  arr[i + 1] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
L71:
  movl   $0x0,-0xc(%rbp)
  jmp    L103
L56:
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x4(%rbp)
L103:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L56
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L56
  cmpl   $0x0,-0x8(%rbp)
  jne    L132
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L117
L132:
  cmpl   $0x1,-0x8(%rbp)
  jne    L178
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L117
L178:
  cmpl   $0x2,-0x8(%rbp)
  jne    L190
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L117
L190:
  cmpl   $0x3,-0x8(%rbp)
  jne    L136
  mov    -0x38(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L117
L136:
  mov    -0x8(%rbp),%eax
  jmp    L167
L61:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x4(%rbp)
L117:
  cmpl   $0x0,-0x4(%rbp)
  jle    L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L61
L18:
  cmpl   $0x0,-0xc(%rbp)
  jle    L144
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
  jmp    L71
L144:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L28
  cmpl   $0x4,-0x8(%rbp)
  je     L28
  cmpl   $0x0,-0x4(%rbp)
  jg     L71
L28:
  mov    -0x8(%rbp),%eax
L167:
  leave
  ret
```

assistant: ```c
int get_token(char *line, char **token1, char **token2, char **token3, char **token4) {
  int len;
  int token_idx = 0, total = strlen(line);
search_next:
  len = 0;
  while (*line == 0x20 || *line == '\t') {
    line++;
    total--;
  }
  if (token_idx == 0)
    *token1 = line;
  else if (token_idx == 1)
    *token2 = line;
  else if (token_idx == 2)
    *token3 = line;
  else if (token_idx == 3)
    *token4 = line;
  else
    return token_idx;
  while (total > 0 && *line && *line != 0x20 && *line != '\t' && *line != '\r' && *line != '\n') {
    line++;
    len++;
    total--;
  }
  if (len > 0) {
    *line = '\0';
    line++;
    token_idx++;
    total--;
    goto search_next;
  }
  if (strlen(line) == 0 || token_idx == 4 || total <= 0)
    return token_idx;
  else
    goto search_next;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_token>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    $0x0,%r14d
  movabs $0x100002600,%r13
  jmp    L15
L161:
  mov    %r12,%rbx
  jmp    L155
L163:
  cmp    $0x1,%r14d
  je     L147
  cmp    $0x2,%r14d
  je     L2
  cmp    $0x3,%r14d
  jne    L196
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  jmp    L101
L147:
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  jmp    L101
L2:
  mov    0x18(%rsp),%rax
  mov    %rbx,(%rax)
  jmp    L101
L145:
  add    $0x1,%rbx
  add    $0x1,%edx
  sub    $0x1,%ebp
  je     L80
L183:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L80
  cmp    $0x20,%al
  ja     L145
  bt     %rax,%r13
  jae    L145
L80:
  test   %edx,%edx
  jle    L9
  movb   $0x0,(%rbx)
  lea    0x1(%rbx),%r12
  add    $0x1,%r14d
  sub    $0x1,%ebp
L15:
  movzbl (%r12),%eax
  cmp    $0x20,%al
  je     L169
  cmp    $0x9,%al
  jne    L161
L169:
  mov    %r12,%rbx
  add    %ebp,%r12d
L166:
  add    $0x1,%rbx
  mov    %r12d,%ebp
  sub    %ebx,%ebp
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L166
  cmp    $0x9,%al
  je     L166
L155:
  test   %r14d,%r14d
  jne    L163
  mov    %rbx,(%r15)
L101:
  test   %ebp,%ebp
  jle    L29
  mov    $0x0,%edx
  jmp    L183
L9:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L196
  cmp    $0x4,%r14d
  je     L196
  test   %ebp,%ebp
  jle    L196
  mov    %rbx,%r12
  jmp    L15
L29:
  mov    %rbx,%rdi
  call   <strlen@plt>
L196:
  mov    %r14d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int get_token(char *line, char **token1, char **token2, char **token3, char **token4) {
  int len;
  int token_idx = 0, total = strlen(line);
search_next:
  len = 0;
  while (*line == 0x20 || *line == '\t') {
    line++;
    total--;
  }
  if (token_idx == 0)
    *token1 = line;
  else if (token_idx == 1)
    *token2 = line;
  else if (token_idx == 2)
    *token3 = line;
  else if (token_idx == 3)
    *token4 = line;
  else
    return token_idx;
  while (total > 0 && *line && *line != 0x20 && *line != '\t' && *line != '\r' && *line != '\n') {
    line++;
    len++;
    total--;
  }
  if (len > 0) {
    *line = '\0';
    line++;
    token_idx++;
    total--;
    goto search_next;
  }
  if (strlen(line) == 0 || token_idx == 4 || total <= 0)
    return token_idx;
  else
    goto search_next;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_token>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  movabs $0x100002600,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r15d
  nopl   0x0(%rax)
L139:
  movzbl 0x0(%rbp),%eax
  cmp    $0x9,%al
  je     L137
  cmp    $0x20,%al
  jne    L15
L137:
  lea    (%r15,%rbp,1),%ecx
  nopl   0x0(%rax)
L143:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  mov    %ecx,%edx
  sub    %ebp,%edx
  cmp    $0x20,%al
  je     L143
  cmp    $0x9,%al
  je     L143
L77:
  test   %r14d,%r14d
  jne    L211
  mov    %rbp,(%rbx)
  test   %edx,%edx
  jle    L156
L121:
  mov    %edx,%r15d
  jmp    L44
  nopl   (%rax)
L75:
  add    $0x1,%rbp
  sub    $0x1,%r15d
  je     L136
L44:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L56
  cmp    $0x20,%al
  ja     L75
  bt     %rax,%r13
  jae    L75
L56:
  cmp    %r15d,%edx
  jne    L136
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L139
  jmp    L175
  nop
L136:
  movb   $0x0,0x0(%rbp)
  add    $0x1,%r14d
  add    $0x1,%rbp
  sub    $0x1,%r15d
  jmp    L139
  nopl   (%rax)
L211:
  cmp    $0x1,%r14d
  je     L58
  cmp    $0x2,%r14d
  je     L246
  cmp    $0x3,%r14d
  jne    L71
  mov    %rbp,(%r12)
  test   %edx,%edx
  jg     L121
L156:
  mov    %rbp,%rdi
  call   <strlen@plt>
L175:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L58:
  mov    (%rsp),%rax
  mov    %rbp,(%rax)
  test   %edx,%edx
  jg     L121
  jmp    L156
  nopl   0x0(%rax)
L246:
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax)
  test   %edx,%edx
  jg     L121
  jmp    L156
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r15d,%edx
  jmp    L77
L71:
  mov    $0x4,%r14d
  jmp    L175
```

assistant: ```c
int get_token(char *line, char **token1, char **token2, char **token3, char **token4) {
  int len;
  int token_idx = 0, total = strlen(line);
search_next:
  len = 0;
  while (*line == 0x20 || *line == '\t') {
    line++;
    total--;
  }
  if (token_idx == 0)
    *token1 = line;
  else if (token_idx == 1)
    *token2 = line;
  else if (token_idx == 2)
    *token3 = line;
  else if (token_idx == 3)
    *token4 = line;
  else
    return token_idx;
  while (total > 0 && *line && *line != 0x20 && *line != '\t' && *line != '\r' && *line != '\n') {
    line++;
    len++;
    total--;
  }
  if (len > 0) {
    *line = '\0';
    line++;
    token_idx++;
    total--;
    goto search_next;
  }
  if (strlen(line) == 0 || token_idx == 4 || total <= 0)
    return token_idx;
  else
    goto search_next;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_token>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  movabs $0x100002600,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%r15d
  nopl   0x0(%rax)
L72:
  movzbl 0x0(%rbp),%eax
  cmp    $0x9,%al
  je     L164
  cmp    $0x20,%al
  jne    L19
L164:
  lea    (%r15,%rbp,1),%ecx
  nopl   0x0(%rax)
L248:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  mov    %ecx,%edx
  sub    %ebp,%edx
  cmp    $0x20,%al
  je     L248
  cmp    $0x9,%al
  je     L248
L5:
  test   %r14d,%r14d
  jne    L35
  mov    %rbp,(%rbx)
  test   %edx,%edx
  jle    L100
L67:
  mov    %edx,%r15d
  jmp    L62
  nopl   (%rax)
L87:
  add    $0x1,%rbp
  sub    $0x1,%r15d
  je     L8
L62:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L13
  cmp    $0x20,%al
  ja     L87
  bt     %rax,%r13
  jae    L87
L13:
  cmp    %r15d,%edx
  jne    L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L72
  jmp    L170
  nop
L8:
  movb   $0x0,0x0(%rbp)
  add    $0x1,%r14d
  add    $0x1,%rbp
  sub    $0x1,%r15d
  jmp    L72
  nopl   (%rax)
L35:
  cmp    $0x1,%r14d
  je     L197
  cmp    $0x2,%r14d
  je     L182
  cmp    $0x3,%r14d
  jne    L133
  mov    %rbp,(%r12)
  test   %edx,%edx
  jg     L67
L100:
  mov    %rbp,%rdi
  call   <strlen@plt>
L170:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L197:
  mov    (%rsp),%rax
  mov    %rbp,(%rax)
  test   %edx,%edx
  jg     L67
  jmp    L100
  nopl   0x0(%rax)
L182:
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax)
  test   %edx,%edx
  jg     L67
  jmp    L100
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r15d,%edx
  jmp    L5
L133:
  mov    $0x4,%r14d
  jmp    L170
```

assistant: ```c
int get_token(char *line, char **token1, char **token2, char **token3, char **token4) {
  int len;
  int token_idx = 0, total = strlen(line);
search_next:
  len = 0;
  while (*line == 0x20 || *line == '\t') {
    line++;
    total--;
  }
  if (token_idx == 0)
    *token1 = line;
  else if (token_idx == 1)
    *token2 = line;
  else if (token_idx == 2)
    *token3 = line;
  else if (token_idx == 3)
    *token4 = line;
  else
    return token_idx;
  while (total > 0 && *line && *line != 0x20 && *line != '\t' && *line != '\r' && *line != '\n') {
    line++;
    len++;
    total--;
  }
  if (len > 0) {
    *line = '\0';
    line++;
    token_idx++;
    total--;
    goto search_next;
  }
  if (strlen(line) == 0 || token_idx == 4 || total <= 0)
    return token_idx;
  else
    goto search_next;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D85(%rip),%rax
  mov    %rax,%rsi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  je     L19
  lea    D91(%rip),%rax
  jmp    L30
L19:
  lea    D65(%rip),%rax
L30:
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D160(%rip),%rax
  mov    %rax,%rsi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  je     L7
  lea    D91(%rip),%rax
  jmp    L44
L7:
  lea    D65(%rip),%rax
L44:
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D50(%rip),%rax
  mov    %rax,%rsi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  je     L17
  lea    D91(%rip),%rax
  jmp    L70
L17:
  lea    D65(%rip),%rax
L70:
  mov    %rax,%rsi
  lea    D106(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D88(%rip),%rax
  mov    %rax,%rsi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  je     L13
  lea    D91(%rip),%rax
  jmp    L33
L13:
  lea    D65(%rip),%rax
L33:
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D85
type_infered: string
name: unpack_data
arguments: label: D95
type_infered: string
name: unpack_data
arguments: label: D91
type_infered: string
name: unpack_data
arguments: label: D65
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D160
type_infered: string
name: unpack_data
arguments: label: D50
type_infered: string
name: unpack_data
arguments: label: D106
type_infered: string
name: unpack_data
arguments: label: D88
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string

tool: D85: L10N

tool: D95: LOCALIZATION

tool: D91: TRUE

tool: D65: FALSE

tool: D23: 1: %s


tool: D160: 6Z4N

tool: D50: L9N

tool: D106: 2: %s


tool: D88: L10Q

tool: D20: 3: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("1: %s\n", isAbbr("LOCALIZATION", "L10N") ? "TRUE" : "FALSE");
  printf("1: %s\n", isAbbr("LOCALIZATION", "6Z4N") ? "TRUE" : "FALSE");
  printf("2: %s\n", isAbbr("LOCALIZATION", "L9N") ? "TRUE" : "FALSE");
  printf("3: %s\n", isAbbr("LOCALIZATION", "L10Q") ? "TRUE" : "FALSE");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D142(%rip),%rsi
  lea    D101(%rip),%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  lea    D137(%rip),%rsi
  lea    D115(%rip),%rax
  cmove  %rax,%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D167(%rip),%rsi
  lea    D101(%rip),%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  lea    D137(%rip),%rsi
  lea    D115(%rip),%rax
  cmove  %rax,%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rsi
  lea    D101(%rip),%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  lea    D137(%rip),%rsi
  lea    D115(%rip),%rax
  cmove  %rax,%rsi
  lea    D96(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rsi
  lea    D101(%rip),%rdi
  call   <isAbbr@plt>
  test   %rax,%rax
  lea    D137(%rip),%rsi
  lea    D115(%rip),%rax
  cmove  %rax,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D142
type_guessed: string
name: read_data
arguments: data_label: D101
type_guessed: string
name: read_data
arguments: data_label: D137
type_guessed: string
name: read_data
arguments: data_label: D115
type_guessed: string
name: read_data
arguments: data_label: D49
type_guessed: string
name: read_data
arguments: data_label: D167
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D96
type_guessed: string
name: read_data
arguments: data_label: D34
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D142: L10N

tool: D101: LOCALIZATION

tool: D137: TRUE

tool: D115: FALSE

tool: D49: 1: %s


tool: D167: 6Z4N

tool: D10: L9N

tool: D96: 2: %s


tool: D34: L10Q

tool: D3: 3: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("1: %s\n", isAbbr("LOCALIZATION", "L10N") ? "TRUE" : "FALSE");
  printf("1: %s\n", isAbbr("LOCALIZATION", "6Z4N") ? "TRUE" : "FALSE");
  printf("2: %s\n", isAbbr("LOCALIZATION", "L9N") ? "TRUE" : "FALSE");
  printf("3: %s\n", isAbbr("LOCALIZATION", "L10Q") ? "TRUE" : "FALSE");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rsi
  lea    D35(%rip),%r13
  push   %r12
  lea    D75(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D9(%rip),%rbp
  push   %rbx
  lea    D62(%rip),%rbx
  sub    $0x8,%rsp
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D98(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D47(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  lea    D42(%rip),%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D89(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  lea    D64(%rip),%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D35
datatype: string
name: parse_data
arguments: label: D75
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D62
datatype: string
name: parse_data
arguments: label: D98
datatype: string
name: parse_data
arguments: label: D47
datatype: string
name: parse_data
arguments: label: D42
datatype: string
name: parse_data
arguments: label: D89
datatype: string
name: parse_data
arguments: label: D64
datatype: string

tool: D5: L10N

tool: D35: 1: %s


tool: D75: LOCALIZATION

tool: D9: FALSE

tool: D62: TRUE

tool: D98: 6Z4N

tool: D47: L9N

tool: D42: 2: %s


tool: D89: L10Q

tool: D64: 3: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("1: %s\n", isAbbr("LOCALIZATION", "L10N") ? "TRUE" : "FALSE");
  printf("1: %s\n", isAbbr("LOCALIZATION", "6Z4N") ? "TRUE" : "FALSE");
  printf("2: %s\n", isAbbr("LOCALIZATION", "L9N") ? "TRUE" : "FALSE");
  printf("3: %s\n", isAbbr("LOCALIZATION", "L10Q") ? "TRUE" : "FALSE");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%rsi
  lea    D89(%rip),%r13
  push   %r12
  lea    D85(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D52(%rip),%rbp
  push   %rbx
  lea    D66(%rip),%rbx
  sub    $0x8,%rsp
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D45(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D82(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  lea    D97(%rip),%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  mov    %r12,%rdi
  lea    D83(%rip),%rsi
  call   <isAbbr@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  test   %rax,%rax
  cmovne %rbx,%rsi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D89
type_infered: string
name: extract_symbolic_data
arguments: label: D85
type_infered: string
name: extract_symbolic_data
arguments: label: D52
type_infered: string
name: extract_symbolic_data
arguments: label: D66
type_infered: string
name: extract_symbolic_data
arguments: label: D45
type_infered: string
name: extract_symbolic_data
arguments: label: D82
type_infered: string
name: extract_symbolic_data
arguments: label: D97
type_infered: string
name: extract_symbolic_data
arguments: label: D83
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D14: L10N

tool: D89: 1: %s


tool: D85: LOCALIZATION

tool: D52: FALSE

tool: D66: TRUE

tool: D45: 6Z4N

tool: D82: L9N

tool: D97: 2: %s


tool: D83: L10Q

tool: D12: 3: %s


assistant: ```c
int main(int argc, char **argv) {
  printf("1: %s\n", isAbbr("LOCALIZATION", "L10N") ? "TRUE" : "FALSE");
  printf("1: %s\n", isAbbr("LOCALIZATION", "6Z4N") ? "TRUE" : "FALSE");
  printf("2: %s\n", isAbbr("LOCALIZATION", "L9N") ? "TRUE" : "FALSE");
  printf("3: %s\n", isAbbr("LOCALIZATION", "L10Q") ? "TRUE" : "FALSE");
  return 0;
}
```