ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D18(%rip),%rbx
  mov    (%rbx),%eax
  mov    %eax,0xc(%rsp)
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x1b3a,%edi
  mov    %eax,0x8(%rsp)
  call   <htons@plt>
  mov    (%rbx),%edi
  xor    %edx,%edx
  lea    0x10(%rsp),%rbx
  mov    %eax,0x4(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <bind@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  call   <listen@plt>
  mov    %ebp,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <accept@plt>
  mov    %eax,%ebp
  xchg   %ax,%ax
L0:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x1e,%edx
  mov    %rbx,%rsi
  call   <recv@plt>
  mov    %rbx,%rdi
  call   <parse_gesture@plt>
  jmp    L0
```

assistant: ```c
int main() {
  unsigned char buffer[30];
  struct sockaddr_in server;
  memset(&server, 0, sizeof(struct sockaddr_in));
  server.sin_family = AF_INET;
  server.sin_addr.s_addr = htonl(INADDR_ANY);
  server.sin_port = htons(6970);
  int sock = socket(AF_INET, SOCK_STREAM, 0);
  bind(sock, (struct sockaddr *)&server, sizeof(server));
  listen(sock, 10);
  int conn = accept(sock, (struct sockaddr *)NULL, NULL);
  while (1) {
    recv(conn, buffer, 30, 0);
    parse_gesture(buffer);
  }
  close(conn);
  close(sock);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xc,%edx
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D13(%rip),%rbx
  mov    (%rbx),%eax
  mov    %eax,0xc(%rsp)
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0x1b3a,%edi
  mov    %eax,0x8(%rsp)
  call   <htons@plt>
  mov    (%rbx),%edi
  xor    %edx,%edx
  lea    0x10(%rsp),%rbx
  mov    %eax,0x4(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <bind@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  call   <listen@plt>
  mov    %ebp,%edi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <accept@plt>
  mov    %eax,%ebp
  xchg   %ax,%ax
L0:
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x1e,%edx
  mov    %rbx,%rsi
  call   <recv@plt>
  mov    %rbx,%rdi
  call   <parse_gesture@plt>
  jmp    L0
```

assistant: ```c
int main() {
  unsigned char buffer[30];
  struct sockaddr_in server;
  memset(&server, 0, sizeof(struct sockaddr_in));
  server.sin_family = AF_INET;
  server.sin_addr.s_addr = htonl(INADDR_ANY);
  server.sin_port = htons(6970);
  int sock = socket(AF_INET, SOCK_STREAM, 0);
  bind(sock, (struct sockaddr *)&server, sizeof(server));
  listen(sock, 10);
  int conn = accept(sock, (struct sockaddr *)NULL, NULL);
  while (1) {
    recv(conn, buffer, 30, 0);
    parse_gesture(buffer);
  }
  close(conn);
  close(sock);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handsfull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <lprcat@plt>
  mov    $0x0,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  call   <nap@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: 
You can't carry anything more!

assistant: ```c
void handsfull(void) {
  lprcat("\nYou can't carry anything more!");
  lflush();
  nap(2200);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handsfull>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <lprcat@plt>
  mov    $0x0,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  call   <nap@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: 
You can't carry anything more!

assistant: ```c
void handsfull(void) {
  lprcat("\nYou can't carry anything more!");
  lflush();
  nap(2200);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handsfull>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <lprcat@plt>
  xor    %eax,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  add    $0x8,%rsp
  jmp    1070 <nap@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: 
You can't carry anything more!

assistant: ```c
void handsfull(void) {
  lprcat("\nYou can't carry anything more!");
  lflush();
  nap(2200);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<handsfull>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <lprcat@plt>
  xor    %eax,%eax
  call   <lflush@plt>
  mov    $0x898,%edi
  add    $0x8,%rsp
  jmp    1070 <nap@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: 
You can't carry anything more!

assistant: ```c
void handsfull(void) {
  lprcat("\nYou can't carry anything more!");
  lflush();
  nap(2200);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L5
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L10
L5:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
char *find(char *s, char c) {
  int i, n;
  n = strlen(s);
  for (i = 0; i < n; i++)
    if (s[i] == c)
      return &s[i];
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L26
  mov    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rcx
L38:
  mov    %rdx,%rax
  cmp    %bl,(%rdx)
  je     L8
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L38
  mov    $0x0,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
char *find(char *s, char c) {
  int i, n;
  n = strlen(s);
  for (i = 0; i < n; i++)
    if (s[i] == c)
      return &s[i];
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  mov    %eax,%edx
  mov    %rbx,%rax
  sub    $0x1,%edx
  lea    0x1(%rbx,%rdx,1),%rdx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L13
L29:
  cmp    %bpl,(%rax)
  jne    L23
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *find(char *s, char c) {
  int i, n;
  n = strlen(s);
  for (i = 0; i < n; i++)
    if (s[i] == c)
      return &s[i];
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<find>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L39
  mov    %eax,%edx
  mov    %rbx,%rax
  sub    $0x1,%edx
  lea    0x1(%rbx,%rdx,1),%rdx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L39
L2:
  cmp    %bpl,(%rax)
  jne    L27
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *find(char *s, char c) {
  int i, n;
  n = strlen(s);
  for (i = 0; i < n; i++)
    if (s[i] == c)
      return &s[i];
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ps2_write_shadow_raml>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1ffff,%eax
  add    $0xe0000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mem_write_raml@plt>
  nop
  leave
  ret
```

assistant: ```c
void ps2_write_shadow_raml(uint32_t addr, uint32_t val, void *priv) {
  addr = (addr & 0x1ffff) + 0xe0000;
  mem_write_raml(addr, val, priv);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ps2_write_shadow_raml>:
  endbr64
  sub    $0x8,%rsp
  and    $0x1ffff,%edi
  add    $0xe0000,%edi
  call   <mem_write_raml@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ps2_write_shadow_raml(uint32_t addr, uint32_t val, void *priv) {
  addr = (addr & 0x1ffff) + 0xe0000;
  mem_write_raml(addr, val, priv);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ps2_write_shadow_raml>:
  endbr64
  and    $0x1ffff,%edi
  add    $0xe0000,%edi
  jmp    1050 <mem_write_raml@plt>
```

assistant: ```c
void ps2_write_shadow_raml(uint32_t addr, uint32_t val, void *priv) {
  addr = (addr & 0x1ffff) + 0xe0000;
  mem_write_raml(addr, val, priv);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ps2_write_shadow_raml>:
  endbr64
  and    $0x1ffff,%edi
  add    $0xe0000,%edi
  jmp    1050 <mem_write_raml@plt>
```

assistant: ```c
void ps2_write_shadow_raml(uint32_t addr, uint32_t val, void *priv) {
  addr = (addr & 0x1ffff) + 0xe0000;
  mem_write_raml(addr, val, priv);
}
```
user: What is the c source code of the assembly code below:

```asm
<count_seqerrs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L35
  mov    -0x428(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x0,%eax
  jmp    L39
L35:
  movl   $0x0,-0x41c(%rbp)
  jmp    L29
L23:
  lea    -0x410(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <keyword@plt>
  test   %rax,%rax
  je     L29
  addl   $0x1,-0x41c(%rbp)
L29:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x401,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L23
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x41c(%rbp),%eax
L39:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string
name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string

tool: D8: r

tool: D3: Could not open file %s

tool: D7: ORPHAN_ERROR

assistant: ```c
int count_seqerrs(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nseqerrs;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open file %s", filename);
    return 0;
  }
  nseqerrs = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "ORPHAN_ERROR")) {
      nseqerrs++;
    }
  }
  fclose(fin);
  return nseqerrs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_seqerrs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D25(%rip),%r12
  test   %rax,%rax
  jne    L18
  mov    %r13,%rsi
  lea    D15(%rip),%rdi
  call   <error@plt>
  jmp    L19
L26:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
L18:
  mov    %rsp,%rdi
  mov    %rbp,%rdx
  mov    $0x401,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L26
  mov    %rbp,%rdi
  call   <fclose@plt>
L19:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %ebx,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D15
type: string

tool: D3: r

tool: D25: ORPHAN_ERROR

tool: D15: Could not open file %s

assistant: ```c
int count_seqerrs(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nseqerrs;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open file %s", filename);
    return 0;
  }
  nseqerrs = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "ORPHAN_ERROR")) {
      nseqerrs++;
    }
  }
  fclose(fin);
  return nseqerrs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_seqerrs>:
  endbr64
  push   %r14
  lea    D29(%rip),%rsi
  mov    %rdi,%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L24
  jmp    L3
  nopl   0x0(%rax)
L26:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
L24:
  mov    %rbp,%rdx
  mov    $0x401,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L26
  mov    %rbp,%rdi
  call   <fclose@plt>
L20:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r14,%rsi
  lea    D0(%rip),%rdi
  call   <error@plt>
  jmp    L20
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D29
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D29: r

tool: D1: ORPHAN_ERROR

tool: D0: Could not open file %s

assistant: ```c
int count_seqerrs(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nseqerrs;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open file %s", filename);
    return 0;
  }
  nseqerrs = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "ORPHAN_ERROR")) {
      nseqerrs++;
    }
  }
  fclose(fin);
  return nseqerrs;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<count_seqerrs>:
  endbr64
  push   %r14
  lea    D7(%rip),%rsi
  mov    %rdi,%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L10
  jmp    L4
  nopl   0x0(%rax)
L13:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <keyword@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
L10:
  mov    %rbp,%rdx
  mov    $0x401,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbp,%rdi
  call   <fclose@plt>
L18:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x410,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r14,%rsi
  lea    D24(%rip),%rdi
  call   <error@plt>
  jmp    L18
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string
name: extract_symbolic_data
arguments: tag: D24
datatype: string

tool: D7: r

tool: D15: ORPHAN_ERROR

tool: D24: Could not open file %s

assistant: ```c
int count_seqerrs(char *filename) {
  FILE *fin;
  char line[1024 + 1];
  int nseqerrs;
  if ((fin = fopen(filename, "r")) == NULL) {
    error("Could not open file %s", filename);
    return 0;
  }
  nseqerrs = 0;
  while (fgets(line, 1024 + 1, fin)) {
    if (keyword(line, "ORPHAN_ERROR")) {
      nseqerrs++;
    }
  }
  fclose(fin);
  return nseqerrs;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L121
L99:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    0x0(,%rax,4),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  cmp    $0x4,%ebx
  jle    L130
  mov    $0x8,%edi
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0x4,%eax
  jmp    L90
L121:
  mov    (%rsi),%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L99
L27:
  mov    %r8d,%esi
L136:
  add    $0x1,%edx
  mov    %edx,%eax
  imul   %edx,%eax
  add    $0x4,%rdi
  cmp    %ebx,%eax
  jge    L51
L90:
  cmpl   $0x0,(%rdi,%r12,1)
  jne    L136
  lea    0x1(%rsi),%r8d
  movslq %esi,%rsi
  mov    %edx,0x0(%rbp,%rsi,4)
  cmp    %eax,%ebx
  jle    L27
  movslq %eax,%rcx
  lea    (%r12,%rcx,4),%rcx
L7:
  movl   $0x1,(%rcx)
  add    %edx,%eax
  add    %rdi,%rcx
  cmp    %eax,%ebx
  jg     L7
  mov    %r8d,%esi
  jmp    L136
L130:
  mov    $0x2,%edx
  mov    $0x0,%esi
L51:
  cmp    %edx,%ebx
  jl     L13
  movslq %edx,%rax
  lea    (%r12,%rax,4),%rax
  add    $0x1,%ebx
  jmp    L72
L15:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %ebx,%edx
  je     L13
L72:
  cmpl   $0x0,(%rax)
  jne    L15
  movslq %esi,%rcx
  mov    %edx,0x0(%rbp,%rcx,4)
  lea    0x1(%rsi),%esi
  jmp    L15
L13:
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D12
data_type: string

tool: D11: Command lines: %s <m>


tool: D12: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Command lines: %s <m>\n", argv[0]);
    exit(1);
  }
  int N = atoi(argv[1]);
  int *flag = (int *)malloc(sizeof(int) * N);
  int *prime = (int *)malloc(sizeof(int) * N);
  memset(flag, 0, sizeof(int) * N);
  int q = 0;
  int i, j;
  for (i = 2; i * i < N; i++) {
    if (flag[i]) {
      continue;
    }
    prime[q++] = i;
    for (j = i * i; j < N; j += i) {
      flag[j] = 1;
    }
  }
  for (; i <= N; i++) {
    if (flag[i] == 0)
      prime[q++] = i;
  }
  printf("%d\n", q);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L75
  mov    (%rsi),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L75:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,4),%r13d
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  cmp    $0x4,%ebx
  jle    L4
  mov    $0x8,%edi
  mov    $0x2,%edx
  xor    %esi,%esi
  mov    $0x4,%eax
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L74:
  add    $0x1,%edx
  add    $0x4,%rdi
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %ebx,%eax
  jge    L24
L44:
  mov    (%rdi,%rbp,1),%r8d
  test   %r8d,%r8d
  jne    L74
  mov    %edx,(%r12,%rsi,4)
  movslq %eax,%rcx
  lea    0x1(%rsi),%r8d
  lea    0x0(%rbp,%rcx,4),%rcx
  nopl   0x0(%rax)
L96:
  add    %edx,%eax
  movl   $0x1,(%rcx)
  add    %rdi,%rcx
  cmp    %eax,%ebx
  jg     L96
  add    $0x1,%edx
  movslq %r8d,%rsi
  add    $0x4,%rdi
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %ebx,%eax
  jl     L44
L24:
  cmp    %edx,%ebx
  jl     L40
  movslq %edx,%rax
  add    $0x1,%ebx
  lea    0x0(%rbp,%rax,4),%rax
  nopl   0x0(%rax)
L87:
  mov    (%rax),%ecx
  test   %ecx,%ecx
  jne    L83
  movslq %esi,%rcx
  add    $0x1,%esi
  mov    %edx,(%r12,%rcx,4)
L83:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%ebx
  jne    L87
L40:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x2,%edx
  xor    %esi,%esi
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D12
type: string

tool: D18: Command lines: %s <m>


tool: D12: %d


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Command lines: %s <m>\n", argv[0]);
    exit(1);
  }
  int N = atoi(argv[1]);
  int *flag = (int *)malloc(sizeof(int) * N);
  int *prime = (int *)malloc(sizeof(int) * N);
  memset(flag, 0, sizeof(int) * N);
  int q = 0;
  int i, j;
  for (i = 2; i * i < N; i++) {
    if (flag[i]) {
      continue;
    }
    prime[q++] = i;
    for (j = i * i; j < N; j += i) {
      flag[j] = 1;
    }
  }
  for (; i <= N; i++) {
    if (flag[i] == 0)
      prime[q++] = i;
  }
  printf("%d\n", q);
  return 0;
}
```