ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<envelope>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  call   <fabs@plt>
  test   %ebx,%ebx
  jle    L19
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rbx
  nopl   (%rax)
L5:
  movss  %xmm0,0xc(%rsp)
  movss  (%r12),%xmm0
  add    $0x4,%r12
  add    $0x4,%rbp
  call   <fabs@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  mulsd  D7(%rip),%xmm1
  movaps %xmm0,%xmm2
  subss  0xc(%rsp),%xmm2
  cvtss2sd %xmm2,%xmm2
  addsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd -0x8(%rbp),%xmm2
  mulsd  D8(%rip),%xmm2
  addsd  %xmm2,%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,-0x4(%rbp)
  cmp    %rbx,%r12
  jne    L5
L19:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: byte[8]
name: parse_data
arguments: tag: D8
type: f64

tool: {"D7": [0x07,0xce,0x19,0x51,0xda,0x1b,0xee,0xbf]}

tool: D8: 1.9266

assistant: ```c
void envelope(float input[], float prev_in, float output[], int npts) {
  int i;
  float curr_abs, prev_abs;
  prev_abs = fabs(prev_in);
  for (i = 0; i < npts; i++) {
    curr_abs = fabs(input[i]);
    output[i] = curr_abs - prev_abs + (-0.9409) * output[i - 2] + 1.9266 * output[i - 1];
    prev_abs = curr_abs;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bisearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L62
L50:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   *%rdx
  cmp    $0x1,%eax
  je     L17
  cmp    $0x1,%eax
  jg     L62
  cmp    $0xffffffff,%eax
  je     L84
  test   %eax,%eax
  je     L36
  jmp    L62
L84:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L62
L17:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L62
L36:
  mov    -0x4(%rbp),%eax
  jmp    L74
L62:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L50
  mov    $0xffffffff,%eax
L74:
  leave
  ret
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  sub    $0x1,%edx
  js     L69
  mov    %rsi,%r13
  mov    %ecx,%r14d
  mov    %r8,%r15
  mov    %edx,%r12d
  mov    $0x0,%ebp
  jmp    L33
L15:
  add    $0x1,%ebx
  cmp    $0xffffffff,%eax
  cmove  %ebx,%ebp
L61:
  cmp    %r12d,%ebp
  jg     L10
L33:
  lea    0x0(%rbp,%r12,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%edi
  imul   %r14d,%edi
  movslq %edi,%rdi
  add    0x8(%rsp),%rdi
  mov    %r13,%rsi
  call   *%r15
  test   %eax,%eax
  je     L13
  cmp    $0x1,%eax
  jne    L15
  lea    -0x1(%rbx),%r12d
  jmp    L61
L10:
  movl   $0xffffffff,0x4(%rsp)
L13:
  mov    0x4(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  movl   $0xffffffff,0x4(%rsp)
  jmp    L13
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  sub    $0x1,%edx
  js     L49
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %r8,%r14
  mov    %edx,%r13d
  xor    %r15d,%r15d
L31:
  mov    0xc(%rsp),%edi
  lea    (%r15,%r13,1),%r12d
  mov    %rbp,%rsi
  sar    %r12d
  imul   %r12d,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  je     L15
  cmp    $0x1,%eax
  je     L33
  add    $0x1,%r12d
  cmp    $0xffffffff,%eax
  cmove  %r12d,%r15d
L25:
  cmp    %r15d,%r13d
  jge    L31
L49:
  mov    $0xffffffff,%r12d
L15:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  lea    -0x1(%r12),%r13d
  jmp    L25
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bisearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  sub    $0x1,%edx
  js     L11
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %r8,%r14
  mov    %edx,%r13d
  xor    %r15d,%r15d
L19:
  mov    0xc(%rsp),%edi
  lea    (%r15,%r13,1),%r12d
  mov    %rbp,%rsi
  sar    %r12d
  imul   %r12d,%edi
  movslq %edi,%rdi
  add    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  je     L36
  cmp    $0x1,%eax
  je     L27
  add    $0x1,%r12d
  cmp    $0xffffffff,%eax
  cmove  %r12d,%r15d
L40:
  cmp    %r15d,%r13d
  jge    L19
L11:
  mov    $0xffffffff,%r12d
L36:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  lea    -0x1(%r12),%r13d
  jmp    L40
```

assistant: ```c
int bisearch(void *sorted, const void *target, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  int left, middle, right;
  left = 0;
  right = size - 1;
  while (left <= right) {
    middle = (left + right) / 2;
    switch (compare(((char *)sorted + (esize * middle)), target)) {
    case -1:
      left = middle + 1;
      break;
    case 1:
      right = middle - 1;
      break;
    case 0:
      return middle;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *copy_array(double *array, size_t size) {
  double *copy = (double *)malloc(sizeof(*copy) * size);
  memcpy(copy, array, size * sizeof(*array));
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    0x0(,%rbx,8),%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *copy_array(double *array, size_t size) {
  double *copy = (double *)malloc(sizeof(*copy) * size);
  memcpy(copy, array, size * sizeof(*array));
  return copy;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_array>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,8),%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *copy_array(double *array, size_t size) {
  double *copy = (double *)malloc(sizeof(*copy) * size);
  memcpy(copy, array, size * sizeof(*array));
  return copy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_array>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,8),%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  lea    0x0(,%rbx,8),%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *copy_array(double *array, size_t size) {
  double *copy = (double *)malloc(sizeof(*copy) * size);
  memcpy(copy, array, size * sizeof(*array));
  return copy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<median4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L27
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L27:
  movsd  -0x28(%rbp),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L1
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
L1:
  movsd  -0x28(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L0
  movsd  -0x28(%rbp),%xmm0
  jmp    L42
L0:
  movsd  -0x18(%rbp),%xmm0
L42:
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L12
  movsd  -0x20(%rbp),%xmm0
  jmp    L28
L12:
  movsd  -0x30(%rbp),%xmm0
L28:
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: f64

tool: D0: 0.5

assistant: ```c
double median4(double x1, double x2, double x3, double x4) {
  double tmp;
  if (x1 > x2) {
    tmp = x2;
    x2 = x1;
    x1 = tmp;
  }
  if (x3 > x4) {
    tmp = x3;
    x3 = x4;
    x4 = tmp;
  }
  tmp = (x1 < x3) ? x3 : x1;
  tmp += (x2 < x4) ? x2 : x4;
  return tmp * 0.5;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<median4>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L2
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L2:
  comisd %xmm3,%xmm2
  jbe    L4
  movq   %xmm2,%rax
  movapd %xmm3,%xmm2
  movq   %rax,%xmm3
L4:
  maxsd  %xmm0,%xmm2
  minsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  D6(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: f64

tool: D6: 0.5

assistant: ```c
double median4(double x1, double x2, double x3, double x4) {
  double tmp;
  if (x1 > x2) {
    tmp = x2;
    x2 = x1;
    x1 = tmp;
  }
  if (x3 > x4) {
    tmp = x3;
    x3 = x4;
    x4 = tmp;
  }
  tmp = (x1 < x3) ? x3 : x1;
  tmp += (x2 < x4) ? x2 : x4;
  return tmp * 0.5;
}
```
user: Translate the below assembly code into C programming language:

```asm
<median4>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L9
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L9:
  comisd %xmm3,%xmm2
  jbe    L17
  movq   %xmm2,%rax
  movapd %xmm3,%xmm2
  movq   %rax,%xmm3
L17:
  maxsd  %xmm0,%xmm2
  minsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  D5(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: f64

tool: D5: 0.5

assistant: ```c
double median4(double x1, double x2, double x3, double x4) {
  double tmp;
  if (x1 > x2) {
    tmp = x2;
    x2 = x1;
    x1 = tmp;
  }
  if (x3 > x4) {
    tmp = x3;
    x3 = x4;
    x4 = tmp;
  }
  tmp = (x1 < x3) ? x3 : x1;
  tmp += (x2 < x4) ? x2 : x4;
  return tmp * 0.5;
}
```
user: What is the c source code of the assembly code below:

```asm
<median4>:
  endbr64
  comisd %xmm1,%xmm0
  jbe    L7
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  movq   %rax,%xmm1
L7:
  comisd %xmm3,%xmm2
  jbe    L3
  movq   %xmm2,%rax
  movapd %xmm3,%xmm2
  movq   %rax,%xmm3
L3:
  maxsd  %xmm0,%xmm2
  minsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  D8(%rip),%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: f64

tool: D8: 0.5

assistant: ```c
double median4(double x1, double x2, double x3, double x4) {
  double tmp;
  if (x1 > x2) {
    tmp = x2;
    x2 = x1;
    x1 = tmp;
  }
  if (x3 > x4) {
    tmp = x3;
    x3 = x4;
    x4 = tmp;
  }
  tmp = (x1 < x3) ? x3 : x1;
  tmp += (x2 < x4) ? x2 : x4;
  return tmp * 0.5;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L51
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L49
L51:
  mov    $0x0,%eax
L49:
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  lea    0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  cmpl   $0x0,-0x8(%rbp)
  jne    L73
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L59
L73:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
  addq   $0x1,-0x20(%rbp)
  jmp    L26
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L26
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  add    %rcx,%rax
  movb   $0x2f,(%rax)
L26:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
L59:
  leave
  ret
```

assistant: ```c
void add_path(char **path, const char *str) {
  int len1, len2;
  len1 = *path ? strlen(*path) : 0;
  len2 = strlen(str);
  *path = realloc(*path, len1 + len2 + 2);
  if (len1 == 0) {
    strcpy(*path, str);
    return;
  }
  if ((*path)[len1 - 1] == '/' && str[0] == '/')
    str += 1;
  else if ((*path)[len1 - 1] != '/' && str[0] != '/')
    (*path)[len1++] = '/';
  strcpy(*path + len1, str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L52
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%esi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %ebx,%ebx
  je     L22
  movslq %ebx,%rax
  cmpb   $0x2f,-0x1(%rdi,%rax,1)
  je     L55
  cmpb   $0x2f,(%r12)
  je     L4
  add    $0x1,%ebx
  movb   $0x2f,(%rdi,%rax,1)
L4:
  movslq %ebx,%rdi
  add    0x0(%rbp),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  cmpb   $0x2f,(%r12)
  sete   %al
  movzbl %al,%eax
  add    %rax,%r12
  jmp    L4
L52:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%esi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
L22:
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L51
```

assistant: ```c
void add_path(char **path, const char *str) {
  int len1, len2;
  len1 = *path ? strlen(*path) : 0;
  len2 = strlen(str);
  *path = realloc(*path, len1 + len2 + 2);
  if (len1 == 0) {
    strcpy(*path, str);
    return;
  }
  if ((*path)[len1 - 1] == '/' && str[0] == '/')
    str += 1;
  else if ((*path)[len1 - 1] != '/' && str[0] != '/')
    (*path)[len1++] = '/';
  strcpy(*path + len1, str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L43
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x2(%r12,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %r12d,%r12d
  je     L37
  movslq %r12d,%rax
  movzbl 0x0(%rbp),%edx
  cmpb   $0x2f,-0x1(%rdi,%rax,1)
  je     L1
  cmp    $0x2f,%dl
  je     L14
  movb   $0x2f,(%rdi,%rax,1)
  add    $0x1,%r12d
  mov    (%rbx),%rdi
  movslq %r12d,%rax
L14:
  add    %rax,%rdi
L37:
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
  xchg   %ax,%ax
L1:
  cmp    $0x2f,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rbp
  jmp    L14
  xchg   %ax,%ax
L43:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x2(%rax),%esi
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

assistant: ```c
void add_path(char **path, const char *str) {
  int len1, len2;
  len1 = *path ? strlen(*path) : 0;
  len2 = strlen(str);
  *path = realloc(*path, len1 + len2 + 2);
  if (len1 == 0) {
    strcpy(*path, str);
    return;
  }
  if ((*path)[len1 - 1] == '/' && str[0] == '/')
    str += 1;
  else if ((*path)[len1 - 1] != '/' && str[0] != '/')
    (*path)[len1++] = '/';
  strcpy(*path + len1, str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L11
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x2(%r12,%rax,1),%esi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %r12d,%r12d
  je     L2
  movslq %r12d,%rax
  movzbl 0x0(%rbp),%edx
  cmpb   $0x2f,-0x1(%rdi,%rax,1)
  je     L27
  cmp    $0x2f,%dl
  je     L40
  movb   $0x2f,(%rdi,%rax,1)
  add    $0x1,%r12d
  mov    (%rbx),%rdi
  movslq %r12d,%rax
L40:
  add    %rax,%rdi
L2:
  pop    %rbx
  mov    %rbp,%rsi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
  xchg   %ax,%ax
L27:
  cmp    $0x2f,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rbp
  jmp    L40
  xchg   %ax,%ax
L11:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  lea    0x2(%rax),%esi
  call   <realloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <strcpy@plt>
```

assistant: ```c
void add_path(char **path, const char *str) {
  int len1, len2;
  len1 = *path ? strlen(*path) : 0;
  len2 = strlen(str);
  *path = realloc(*path, len1 + len2 + 2);
  if (len1 == 0) {
    strcpy(*path, str);
    return;
  }
  if ((*path)[len1 - 1] == '/' && str[0] == '/')
    str += 1;
  else if ((*path)[len1 - 1] != '/' && str[0] != '/')
    (*path)[len1++] = '/';
  strcpy(*path + len1, str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <allocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <generate@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <output@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <summary@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <deallocate@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct student *stud = NULL;
  stud = allocate();
  generate(stud);
  output(stud);
  summary(stud);
  deallocate(stud);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <allocate@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <generate@plt>
  mov    %rbx,%rdi
  call   <output@plt>
  mov    %rbx,%rdi
  call   <summary@plt>
  mov    %rbx,%rdi
  call   <deallocate@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  struct student *stud = NULL;
  stud = allocate();
  generate(stud);
  output(stud);
  summary(stud);
  deallocate(stud);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <allocate@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <generate@plt>
  mov    %rbp,%rdi
  call   <output@plt>
  mov    %rbp,%rdi
  call   <summary@plt>
  mov    %rbp,%rdi
  call   <deallocate@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct student *stud = NULL;
  stud = allocate();
  generate(stud);
  output(stud);
  summary(stud);
  deallocate(stud);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <allocate@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <generate@plt>
  mov    %rbp,%rdi
  call   <output@plt>
  mov    %rbp,%rdi
  call   <summary@plt>
  mov    %rbp,%rdi
  call   <deallocate@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct student *stud = NULL;
  stud = allocate();
  generate(stud);
  output(stud);
  summary(stud);
  deallocate(stud);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_text_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hash_table_destroy@plt>
L15:
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <hash_table_destroy@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void extract_text_free(struct hash_table *spec_tag_ht, struct hash_table *tag_attr_ht) {
  if (spec_tag_ht)
    hash_table_destroy(spec_tag_ht);
  if (tag_attr_ht)
    hash_table_destroy(tag_attr_ht);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extract_text_free>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L11
  call   <hash_table_destroy@plt>
L11:
  test   %rbx,%rbx
  je     L1
  mov    %rbx,%rdi
  call   <hash_table_destroy@plt>
L1:
  pop    %rbx
  ret
```

assistant: ```c
void extract_text_free(struct hash_table *spec_tag_ht, struct hash_table *tag_attr_ht) {
  if (spec_tag_ht)
    hash_table_destroy(spec_tag_ht);
  if (tag_attr_ht)
    hash_table_destroy(tag_attr_ht);
}
```