ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  xchg   %ax,%ax
L6:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ssl 0x14(%rsp),%xmm1
  addss  %xmm1,%xmm0
  cmp    %ebx,0x10(%rsp)
  jge    L6
  lea    D26(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D25(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string

tool: D28: %d

tool: D26: Sum: %.0f


tool: D25: Avg: %.2f


assistant: ```c
int main() {
  int n, i, m;
  float Avg, Sum;
  Sum = 0;
  i = 1;
  scanf("%d", &n);
  do {
    scanf("%d", &m);
    Sum = Sum + m;
    i++;
  } while (i <= n);
  printf("Sum: %.0f\n", Sum);
  Avg = Sum / n;
  printf("Avg: %.2f\n", Avg);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x1,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  xchg   %ax,%ax
L3:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  add    $0x1,%ebx
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ssl 0x14(%rsp),%xmm1
  addss  %xmm1,%xmm0
  cmp    %ebx,0x10(%rsp)
  jge    L3
  lea    D29(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D6(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D23: %d

tool: D29: Sum: %.0f


tool: D6: Avg: %.2f


assistant: ```c
int main() {
  int n, i, m;
  float Avg, Sum;
  Sum = 0;
  i = 1;
  scanf("%d", &n);
  do {
    scanf("%d", &m);
    Sum = Sum + m;
    i++;
  } while (i <= n);
  printf("Sum: %.0f\n", Sum);
  Avg = Sum / n;
  printf("Avg: %.2f\n", Avg);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_total_tokens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L41
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L41
  addl   $0x1,-0x4(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  movzbl -0x9(%rbp),%eax
  cmp    -0x1c(%rbp),%al
  je     L35
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str_total_tokens(char *src, char ch) {
  int i, result = 0;
  char prev = 0;
  for (i = 0; src[i]; i++) {
    if (src[i] == ch && prev != src[i])
      result++;
    prev = src[i];
  }
  if (prev != ch)
    result++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_total_tokens>:
  endbr64
  mov    %esi,%r9d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  add    $0x1,%rdi
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  jmp    L36
L2:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  mov    %eax,%ecx
  test   %dl,%dl
  je     L29
  mov    %edx,%eax
L36:
  cmp    %cl,%al
  je     L2
  cmp    %al,%r9b
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%r8d
  jmp    L2
L19:
  mov    $0x0,%r8d
L29:
  cmp    %sil,%al
  setne  %al
  movzbl %al,%eax
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str_total_tokens(char *src, char ch) {
  int i, result = 0;
  char prev = 0;
  for (i = 0; src[i]; i++) {
    if (src[i] == ch && prev != src[i])
      result++;
    prev = src[i];
  }
  if (prev != ch)
    result++;
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_total_tokens>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%r9d
  test   %al,%al
  je     L39
  add    $0x1,%rdi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  jmp    L19
  nopl   0x0(%rax)
L15:
  mov    %edx,%eax
L19:
  cmp    %cl,%al
  je     L12
  cmp    %al,%r9b
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%r8d
L12:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %eax,%ecx
  test   %dl,%dl
  jne    L15
  cmp    %sil,%al
  setne  %al
  movzbl %al,%eax
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
L39:
  xor    %r8d,%r8d
  cmp    %sil,%al
  setne  %al
  movzbl %al,%eax
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str_total_tokens(char *src, char ch) {
  int i, result = 0;
  char prev = 0;
  for (i = 0; src[i]; i++) {
    if (src[i] == ch && prev != src[i])
      result++;
    prev = src[i];
  }
  if (prev != ch)
    result++;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_total_tokens>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%r9d
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  jmp    L27
  nopl   0x0(%rax)
L1:
  mov    %edx,%eax
L27:
  cmp    %al,%cl
  je     L17
  cmp    %al,%r9b
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%r8d
L17:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %eax,%ecx
  test   %dl,%dl
  jne    L1
  cmp    %sil,%al
  setne  %al
  movzbl %al,%eax
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
L18:
  xor    %r8d,%r8d
  cmp    %sil,%al
  setne  %al
  movzbl %al,%eax
  add    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str_total_tokens(char *src, char ch) {
  int i, result = 0;
  char prev = 0;
  for (i = 0; src[i]; i++) {
    if (src[i] == ch && prev != src[i])
      result++;
    prev = src[i];
  }
  if (prev != ch)
    result++;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <AES_set_encrypt_key@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <AES_encrypt@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int aes_encrypt(const unsigned char *in, unsigned char *out, const unsigned char *key) {
  AES_KEY rkey;
  int r = AES_set_encrypt_key(key, 128, &rkey);
  AES_encrypt(in, out, &rkey);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aes_encrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  mov    $0x80,%esi
  call   <AES_set_encrypt_key@plt>
  mov    %eax,%r12d
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aes_encrypt(const unsigned char *in, unsigned char *out, const unsigned char *key) {
  AES_KEY rkey;
  int r = AES_set_encrypt_key(key, 128, &rkey);
  AES_encrypt(in, out, &rkey);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aes_encrypt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %r14,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aes_encrypt(const unsigned char *in, unsigned char *out, const unsigned char *key) {
  AES_KEY rkey;
  int r = AES_set_encrypt_key(key, 128, &rkey);
  AES_encrypt(in, out, &rkey);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aes_encrypt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  mov    %r14,%rdx
  call   <AES_set_encrypt_key@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <AES_encrypt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aes_encrypt(const unsigned char *in, unsigned char *out, const unsigned char *key) {
  AES_KEY rkey;
  int r = AES_set_encrypt_key(key, 128, &rkey);
  AES_encrypt(in, out, &rkey);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<whichfd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L2
  mov    -0xc(%rbp),%eax
  jmp    L23
L2:
  mov    $0xffffffff,%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: /dev/fd/%u

assistant: ```c
int whichfd(const char *pathname) {
  unsigned int fd;
  if (sscanf(pathname, "/dev/fd/%u", &fd) == 1)
    return fd;
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<whichfd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D4(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: /dev/fd/%u

assistant: ```c
int whichfd(const char *pathname) {
  unsigned int fd;
  if (sscanf(pathname, "/dev/fd/%u", &fd) == 1)
    return fd;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<whichfd>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: /dev/fd/%u

assistant: ```c
int whichfd(const char *pathname) {
  unsigned int fd;
  if (sscanf(pathname, "/dev/fd/%u", &fd) == 1)
    return fd;
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<whichfd>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  mov    $0xffffffff,%eax
  cmove  0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: /dev/fd/%u

assistant: ```c
int whichfd(const char *pathname) {
  unsigned int fd;
  if (sscanf(pathname, "/dev/fd/%u", &fd) == 1)
    return fd;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D39
type_infered: string

tool: D37: Binary of 25 is %ld 


tool: D19: Binary of 65535 is %ld 


tool: D20: l1: %d 


tool: D39: l2: %d 


assistant: ```c
int main() {
  printf("Binary of 25 is %ld \n", decimal_to_binary(5));
  printf("Binary of 65535 is %ld \n", decimal_to_binary(65535));
  int l1 = longest_consecutive_one(decimal_to_binary(5));
  int l2 = longest_consecutive_one(decimal_to_binary(65535));
  printf("l1: %d \n", l1);
  printf("l2: %d \n", l2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %eax,%ebp
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %eax,%ebx
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D39
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D35
type_guessed: string

tool: D39: Binary of 25 is %ld 


tool: D0: Binary of 65535 is %ld 


tool: D8: l1: %d 


tool: D35: l2: %d 


assistant: ```c
int main() {
  printf("Binary of 25 is %ld \n", decimal_to_binary(5));
  printf("Binary of 65535 is %ld \n", decimal_to_binary(65535));
  int l1 = longest_consecutive_one(decimal_to_binary(5));
  int l2 = longest_consecutive_one(decimal_to_binary(65535));
  printf("l1: %d \n", l1);
  printf("l2: %d \n", l2);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <decimal_to_binary@plt>
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    $0xffff,%edi
  mov    %eax,%r12d
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %r12d,%esi
  lea    D38(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D38
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string

tool: D24: Binary of 25 is %ld 


tool: D17: Binary of 65535 is %ld 


tool: D38: l1: %d 


tool: D29: l2: %d 


assistant: ```c
int main() {
  printf("Binary of 25 is %ld \n", decimal_to_binary(5));
  printf("Binary of 65535 is %ld \n", decimal_to_binary(65535));
  int l1 = longest_consecutive_one(decimal_to_binary(5));
  int l2 = longest_consecutive_one(decimal_to_binary(65535));
  printf("l1: %d \n", l1);
  printf("l2: %d \n", l2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <decimal_to_binary@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xffff,%edi
  call   <decimal_to_binary@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    $0xffff,%edi
  mov    %eax,%r12d
  call   <decimal_to_binary@plt>
  mov    %eax,%edi
  call   <longest_consecutive_one@plt>
  mov    %r12d,%esi
  lea    D33(%rip),%rdi
  mov    %eax,%ebp
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D3: Binary of 25 is %ld 


tool: D5: Binary of 65535 is %ld 


tool: D33: l1: %d 


tool: D2: l2: %d 


assistant: ```c
int main() {
  printf("Binary of 25 is %ld \n", decimal_to_binary(5));
  printf("Binary of 65535 is %ld \n", decimal_to_binary(65535));
  int l1 = longest_consecutive_one(decimal_to_binary(5));
  int l2 = longest_consecutive_one(decimal_to_binary(65535));
  printf("l1: %d \n", l1);
  printf("l2: %d \n", l2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<smp_ol_main_0_unpacked>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void smp_ol_main_0_unpacked(int *const red2) {
  {
    { (*red2) = 0; }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smp_ol_main_0_unpacked>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void smp_ol_main_0_unpacked(int *const red2) {
  {
    { (*red2) = 0; }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<smp_ol_main_0_unpacked>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void smp_ol_main_0_unpacked(int *const red2) {
  {
    { (*red2) = 0; }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smp_ol_main_0_unpacked>:
  endbr64
  movl   $0x0,(%rdi)
  ret
```

assistant: ```c
void smp_ol_main_0_unpacked(int *const red2) {
  {
    { (*red2) = 0; }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<http_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    D26(%rip),%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    $0x0,%eax
  call   <http_date@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    D56(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    -0x4(%rbp),%eax
  lea    D27(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    -0x4(%rbp),%eax
  lea    D55(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    -0x4(%rbp),%eax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    -0x4(%rbp),%eax
  lea    D51(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <http_header@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: string
name: disassemble_data
arguments: data_tag: D56
data_type: string
name: disassemble_data
arguments: data_tag: D27
data_type: string
name: disassemble_data
arguments: data_tag: D55
data_type: string
name: disassemble_data
arguments: data_tag: D36
data_type: string
name: disassemble_data
arguments: data_tag: D51
data_type: string

tool: D26: HTTP/1.1 %d %s

tool: D56: Date: %s

tool: D27: Server: undb

tool: D55: Connection: close

tool: D36: Content-Type: text/plain

tool: D51: Content-Length: 0

assistant: ```c
int http_error(int socket, int code, char *message) {
  http_header(socket, "HTTP/1.1 %d %s", code, message);
  http_header(socket, "Date: %s", http_date());
  http_header(socket, "Server: undb");
  http_header(socket, "Connection: close");
  http_header(socket, "Content-Type: text/plain");
  http_header(socket, "Content-Length: 0");
  http_header(socket, NULL);
}
```