ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_comment_end>:
  endbr64
  lea    0x2(%rdi),%rax
  lea    -0x1(%rdi),%rdx
  cmp    %rax,%rsi
  ja     L57
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L95:
  cmp    $0x3e,%cl
  jne    L163
  cmpb   $0x2d,0x2(%rdx)
  je     L21
L163:
  mov    %rax,%rdx
L128:
  lea    0x3(%rdx),%rax
  cmp    %rsi,%rax
  jae    L37
L57:
  movzbl 0x3(%rdx),%ecx
  cmp    $0x2d,%cl
  jne    L95
  cmpb   $0x2d,-0x1(%rax)
  je     L102
L15:
  lea    0x2(%rax),%rdx
  cmp    %rdx,%rsi
  jbe    L37
  movzbl 0x2(%rax),%ecx
  cmp    $0x2d,%cl
  je     L61
  cmp    $0x3e,%cl
  jne    L128
  cmpb   $0x2d,-0x1(%rdx)
  jne    L128
  add    $0x3,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rdx,%rax
  cmpb   $0x2d,-0x1(%rax)
  jne    L15
L102:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rsi
  je     L37
  movzbl 0x1(%rax),%ecx
  cmp    $0x2d,%cl
  je     L133
  cmp    $0x3e,%cl
  jne    L128
  add    $0x2,%rax
  ret
  nopl   (%rax)
L21:
  cmpb   $0x2d,0x1(%rdx)
  jne    L163
  lea    0x4(%rdx),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  ret
L133:
  mov    %rdx,%rax
  jmp    L102
```

assistant: ```c
char *find_comment_end(char *beg, char *end) {
  char *p = beg - 1;
  while ((p += 3) < end)
    switch (p[0]) {
    case '>':
      if (p[-1] == '-' && p[-2] == '-')
        return p + 1;
      break;
    case '-':
    at_dash:
      if (p[-1] == '-') {
      at_dash_dash:
        if (++p == end)
          return NULL;
        switch (p[0]) {
        case '>':
          return p + 1;
        case '-':
          goto at_dash_dash;
        }
      } else {
        if ((p += 2) >= end)
          return NULL;
        switch (p[0]) {
        case '>':
          if (p[-1] == '-')
            return p + 1;
          break;
        case '-':
          goto at_dash;
        }
      }
    }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_comment_end>:
  endbr64
  lea    0x2(%rdi),%rax
  lea    -0x1(%rdi),%rdx
  cmp    %rax,%rsi
  ja     L130
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L41:
  cmp    $0x3e,%cl
  jne    L107
  cmpb   $0x2d,0x2(%rdx)
  je     L52
L107:
  mov    %rax,%rdx
L65:
  lea    0x3(%rdx),%rax
  cmp    %rsi,%rax
  jae    L10
L130:
  movzbl 0x3(%rdx),%ecx
  cmp    $0x2d,%cl
  jne    L41
  cmpb   $0x2d,-0x1(%rax)
  je     L109
L79:
  lea    0x2(%rax),%rdx
  cmp    %rdx,%rsi
  jbe    L10
  movzbl 0x2(%rax),%ecx
  cmp    $0x2d,%cl
  je     L27
  cmp    $0x3e,%cl
  jne    L65
  cmpb   $0x2d,-0x1(%rdx)
  jne    L65
  add    $0x3,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rdx,%rax
  cmpb   $0x2d,-0x1(%rax)
  jne    L79
L109:
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rsi
  je     L10
  movzbl 0x1(%rax),%ecx
  cmp    $0x2d,%cl
  je     L144
  cmp    $0x3e,%cl
  jne    L65
  add    $0x2,%rax
  ret
  nopl   (%rax)
L52:
  cmpb   $0x2d,0x1(%rdx)
  jne    L107
  lea    0x4(%rdx),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  ret
L144:
  mov    %rdx,%rax
  jmp    L109
```

assistant: ```c
char *find_comment_end(char *beg, char *end) {
  char *p = beg - 1;
  while ((p += 3) < end)
    switch (p[0]) {
    case '>':
      if (p[-1] == '-' && p[-2] == '-')
        return p + 1;
      break;
    case '-':
    at_dash:
      if (p[-1] == '-') {
      at_dash_dash:
        if (++p == end)
          return NULL;
        switch (p[0]) {
        case '>':
          return p + 1;
        case '-':
          goto at_dash_dash;
        }
      } else {
        if ((p += 2) >= end)
          return NULL;
        switch (p[0]) {
        case '>':
          if (p[-1] == '-')
            return p + 1;
          break;
        case '-':
          goto at_dash;
        }
      }
    }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6f207369206e7553,%rax
  movabs $0x7961646f74207475,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x79696f73,-0x26(%rbp)
  movw   $0x74,-0x22(%rbp)
  lea    -0x26(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <remove_s@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void main() {
  char str1[] = "Sun is out today";
  char str2[] = "soiyt";
  remove_s(str1, str2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6f207369206e7553,%rax
  movabs $0x7961646f74207475,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  movl   $0x79696f73,0xa(%rsp)
  movw   $0x74,0xe(%rsp)
  lea    0xa(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <remove_s@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str1[] = "Sun is out today";
  char str2[] = "soiyt";
  remove_s(str1, str2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%rsi
  mov    $0x74,%eax
  lea    0x10(%rsp),%rdi
  movb   $0x0,0x20(%rsp)
  movl   $0x79696f73,0xa(%rsp)
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <remove_s@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: byte[16]

tool: {"D4": [0x53,0x75,0x6e,0x20,0x69,0x73,0x20,0x6f,0x75,0x74,0x20,0x74,0x6f,0x64,0x61,0x79]}

assistant: ```c
void main() {
  char str1[] = "Sun is out today";
  char str2[] = "soiyt";
  remove_s(str1, str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%rsi
  mov    $0x74,%eax
  lea    0x10(%rsp),%rdi
  movb   $0x0,0x20(%rsp)
  movl   $0x79696f73,0xa(%rsp)
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <remove_s@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: byte[16]

tool: {"D9": [0x53,0x75,0x6e,0x20,0x69,0x73,0x20,0x6f,0x75,0x74,0x20,0x74,0x6f,0x64,0x61,0x79]}

assistant: ```c
void main() {
  char str1[] = "Sun is out today";
  char str2[] = "soiyt";
  remove_s(str1, str2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Arctangente>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D6: Enter a number: 

tool: D4: %lf

assistant: ```c
double Arctangente(double a) {
  printf(gettext("Enter a number: "));
  scanf("%lf", &a);
  return (atan(a));
}
```
user: What is the c source code of the assembly code below:

```asm
<Arctangente>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    D12(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <atan@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D0
type: string

tool: D12: Enter a number: 

tool: D0: %lf

assistant: ```c
double Arctangente(double a) {
  printf(gettext("Enter a number: "));
  scanf("%lf", &a);
  return (atan(a));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Arctangente>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <atan@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D12: Enter a number: 

tool: D3: %lf

assistant: ```c
double Arctangente(double a) {
  printf(gettext("Enter a number: "));
  scanf("%lf", &a);
  return (atan(a));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Arctangente>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <gettext@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <atan@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D11
type: string

tool: D1: Enter a number: 

tool: D11: %lf

assistant: ```c
double Arctangente(double a) {
  printf(gettext("Enter a number: "));
  scanf("%lf", &a);
  return (atan(a));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_file_name@plt>
  mov    $0x0,%eax
  call   <test_no_init@plt>
  mov    $0x0,%eax
  call   <test_rsyslog@plt>
  mov    $0x0,%eax
  call   <test_file_noname@plt>
  mov    $0x0,%eax
  call   <test_thread_log@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_file_name();
  test_no_init();
  test_rsyslog();
  test_file_noname();
  test_thread_log();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_file_name@plt>
  mov    $0x0,%eax
  call   <test_no_init@plt>
  mov    $0x0,%eax
  call   <test_rsyslog@plt>
  mov    $0x0,%eax
  call   <test_file_noname@plt>
  mov    $0x0,%eax
  call   <test_thread_log@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_file_name();
  test_no_init();
  test_rsyslog();
  test_file_noname();
  test_thread_log();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_file_name@plt>
  xor    %eax,%eax
  call   <test_no_init@plt>
  xor    %eax,%eax
  call   <test_rsyslog@plt>
  xor    %eax,%eax
  call   <test_file_noname@plt>
  xor    %eax,%eax
  call   <test_thread_log@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_file_name();
  test_no_init();
  test_rsyslog();
  test_file_noname();
  test_thread_log();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_file_name@plt>
  xor    %eax,%eax
  call   <test_no_init@plt>
  xor    %eax,%eax
  call   <test_rsyslog@plt>
  xor    %eax,%eax
  call   <test_file_noname@plt>
  xor    %eax,%eax
  call   <test_thread_log@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_file_name();
  test_no_init();
  test_rsyslog();
  test_file_noname();
  test_thread_log();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D55
datatype: string
name: disassemble_data
arguments: tag: D39
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string
name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D31
datatype: string

tool: D55: 


tool: D39: Usage error!


tool: D27: Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>


tool: D28:        Note**The number of integers for option n has to be positive


tool: D31:        Note**The number of integers for option i has to be positive


assistant: ```c
void usage(void) {
  printf("\n");
  printf("Usage error!\n");
  printf("Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>\n");
  printf("       Note**The number of integers for option n has to be positive\n");
  printf("       Note**The number of integers for option i has to be positive\n");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbx
  lea    D39(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D39
type_infered: string
name: unpack_data
arguments: label: D30
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D40
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D39: 


tool: D30: Usage error!


tool: D17: Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>


tool: D40:        Note**The number of integers for option n has to be positive


tool: D4:        Note**The number of integers for option i has to be positive


assistant: ```c
void usage(void) {
  printf("\n");
  printf("Usage error!\n");
  printf("Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>\n");
  printf("       Note**The number of integers for option n has to be positive\n");
  printf("       Note**The number of integers for option i has to be positive\n");
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D42
type: string
name: parse_data
arguments: tag: D28
type: string
name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D26
type: string

tool: D16: 


tool: D42: Usage error!


tool: D28: Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>


tool: D24:        Note**The number of integers for option n has to be positive


tool: D26:        Note**The number of integers for option i has to be positive


assistant: ```c
void usage(void) {
  printf("\n");
  printf("Usage error!\n");
  printf("Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>\n");
  printf("       Note**The number of integers for option n has to be positive\n");
  printf("       Note**The number of integers for option i has to be positive\n");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D38
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D26
type: string
name: unpack_data
arguments: label: D44
type: string

tool: D14: 


tool: D38: Usage error!


tool: D7: Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>


tool: D26:        Note**The number of integers for option n has to be positive


tool: D44:        Note**The number of integers for option i has to be positive


assistant: ```c
void usage(void) {
  printf("\n");
  printf("Usage error!\n");
  printf("Usage: atomic_reader -n <number of integers to read> -i <number of iterations for reader>\n");
  printf("       Note**The number of integers for option n has to be positive\n");
  printf("       Note**The number of integers for option i has to be positive\n");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MFRC522_Read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x14(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <CalulateCRC@plt>
  lea    -0xc(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L0
  mov    -0xc(%rbp),%eax
  cmp    $0x90,%eax
  je     L26
L0:
  movb   $0x2,-0xd(%rbp)
L26:
  movzbl -0xd(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned char MFRC522_Read(unsigned char blockAddr, unsigned char *recvData) {
  unsigned char status;
  unsigned int unLen;
  recvData[0] = 0x30;
  recvData[1] = blockAddr;
  CalulateCRC(recvData, 2, &recvData[2]);
  status = MFRC522_ToCard(0x0C, recvData, 4, recvData, &unLen);
  if ((status != 0) || (unLen != 0x90)) {
    status = 2;
  }
  return status;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MFRC522_Read>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x30,(%rsi)
  mov    %dil,0x1(%rsi)
  lea    0x2(%rsi),%rdx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <CalulateCRC@plt>
  lea    0x4(%rsp),%r8
  mov    %rbx,%rcx
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %dl,%dl
  jne    L14
  cmpl   $0x90,0x4(%rsp)
  setne  %al
  add    %eax,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char MFRC522_Read(unsigned char blockAddr, unsigned char *recvData) {
  unsigned char status;
  unsigned int unLen;
  recvData[0] = 0x30;
  recvData[1] = blockAddr;
  CalulateCRC(recvData, 2, &recvData[2]);
  status = MFRC522_ToCard(0x0C, recvData, 4, recvData, &unLen);
  if ((status != 0) || (unLen != 0x90)) {
    status = 2;
  }
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MFRC522_Read>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    0x2(%rsi),%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x1(%rsi)
  mov    %rbp,%rdi
  movb   $0x30,(%rsi)
  mov    $0x2,%esi
  call   <CalulateCRC@plt>
  lea    0x4(%rsp),%r8
  mov    %rbp,%rcx
  mov    %rbp,%rsi
  mov    $0x4,%edx
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8b,%r8b
  jne    L10
  cmpl   $0x90,0x4(%rsp)
  setne  %al
  add    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char MFRC522_Read(unsigned char blockAddr, unsigned char *recvData) {
  unsigned char status;
  unsigned int unLen;
  recvData[0] = 0x30;
  recvData[1] = blockAddr;
  CalulateCRC(recvData, 2, &recvData[2]);
  status = MFRC522_ToCard(0x0C, recvData, 4, recvData, &unLen);
  if ((status != 0) || (unLen != 0x90)) {
    status = 2;
  }
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MFRC522_Read>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  lea    0x2(%rsi),%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x1(%rsi)
  mov    %rbp,%rdi
  movb   $0x30,(%rsi)
  mov    $0x2,%esi
  call   <CalulateCRC@plt>
  lea    0x4(%rsp),%r8
  mov    %rbp,%rcx
  mov    %rbp,%rsi
  mov    $0x4,%edx
  mov    $0xc,%edi
  call   <MFRC522_ToCard@plt>
  mov    %eax,%r8d
  mov    $0x2,%eax
  test   %r8b,%r8b
  jne    L2
  cmpl   $0x90,0x4(%rsp)
  setne  %al
  add    %eax,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char MFRC522_Read(unsigned char blockAddr, unsigned char *recvData) {
  unsigned char status;
  unsigned int unLen;
  recvData[0] = 0x30;
  recvData[1] = blockAddr;
  CalulateCRC(recvData, 2, &recvData[2]);
  status = MFRC522_ToCard(0x0C, recvData, 4, recvData, &unLen);
  if ((status != 0) || (unLen != 0x90)) {
    status = 2;
  }
  return status;
}
```
user: What is the c source code of the assembly code below:

```asm
<Util_tplcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <tpl_peek@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L2:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Util_tplcmp(const char *filename, const char *fmt) {
  char *f = tpl_peek((1 << 0), filename);
  int cmp = -1;
  if (f) {
    cmp = strncmp(f, fmt, strlen(fmt));
    free(f);
  }
  return cmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Util_tplcmp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    $0x1,%edi
  call   <tpl_peek@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L17:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0xffffffff,%ebp
  jmp    L17
```

assistant: ```c
int Util_tplcmp(const char *filename, const char *fmt) {
  char *f = tpl_peek((1 << 0), filename);
  int cmp = -1;
  if (f) {
    cmp = strncmp(f, fmt, strlen(fmt));
    free(f);
  }
  return cmp;
}
```