ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<make_hex_string_learning>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <num_hex_digits@plt>
  test   $0x1,%al
  je     L33
  movb   $0x30,0x0(%rbp)
  add    $0x1,%rbp
L33:
  movb   $0x0,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  js     L15
  nopl   (%rax)
L13:
  mov    %rbx,%rdx
  sar    $0x4,%rbx
  and    $0xf,%edx
  movzbl (%rsp,%rdx,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  sub    $0x1,%rax
  jae    L13
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: byte[16]

tool: {"D0": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x61,0x62,0x63,0x64,0x65,0x66]}

assistant: ```c
void make_hex_string_learning(long n, char *s) {
  const char hex_lookup[] = "0123456789abcdef";
  long len = num_hex_digits(n);
  if (len & 1) {
    *s++ = '0';
  }
  s[len] = '\0';
  for (--len; len >= 0; n >>= 4, --len) {
    s[len] = hex_lookup[n & 0xf];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L10
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L17
L10:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L17:
  leave
  ret
```

assistant: ```c
int stty(int fd, const struct sgttyb *params) {
  if (params == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stty>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L12
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
L18:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L12:
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  jmp    L18
```

assistant: ```c
int stty(int fd, const struct sgttyb *params) {
  if (params == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stty>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L9
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L9:
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int stty(int fd, const struct sgttyb *params) {
  if (params == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stty>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L5
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L5:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int stty(int fd, const struct sgttyb *params) {
  if (params == NULL) {
    __set_errno(EINVAL);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hs01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  movsd  D17(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  D9(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: f64
name: disassemble_data
arguments: data_tag: D9
type_guessed: f64

tool: D17: 10

tool: D9: 1

assistant: ```c
void hs01(double *p, double *x, int m, int n, void *data) {
  double t;
  t = p[0] * p[0];
  x[0] = 10.0 * (p[1] - t);
  x[1] = 1.0 - p[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hs01>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D10(%rip),%xmm0
  subsd  (%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: f64
name: unpack_data
arguments: tag: D10
type_infered: f64

tool: D4: 10

tool: D10: 1

assistant: ```c
void hs01(double *p, double *x, int m, int n, void *data) {
  double t;
  t = p[0] * p[0];
  x[0] = 10.0 * (p[1] - t);
  x[1] = 1.0 - p[0];
}
```
user: What is the c source code of the assembly code below:

```asm
<hs01>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D14(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D1(%rip),%xmm0
  subsd  (%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
datatype: f64
name: retrieve_data
arguments: label: D1
datatype: f64

tool: D14: 10

tool: D1: 1

assistant: ```c
void hs01(double *p, double *x, int m, int n, void *data) {
  double t;
  t = p[0] * p[0];
  x[0] = 10.0 * (p[1] - t);
  x[1] = 1.0 - p[0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hs01>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  D2(%rip),%xmm0
  subsd  (%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
datatype: f64
name: read_data
arguments: data_label: D2
datatype: f64

tool: D12: 10

tool: D2: 1

assistant: ```c
void hs01(double *p, double *x, int m, int n, void *data) {
  double t;
  t = p[0] * p[0];
  x[0] = 10.0 * (p[1] - t);
  x[1] = 1.0 - p[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sto_key_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int sto_key_empty(char key[16]) {
  char empty[16] = {0};
  return !memcmp(key, empty, 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sto_key_empty>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x10,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sto_key_empty(char key[16]) {
  char empty[16] = {0};
  return !memcmp(key, empty, 16);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sto_key_empty>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x10,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sto_key_empty(char key[16]) {
  char empty[16] = {0};
  return !memcmp(key, empty, 16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sto_key_empty>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x10,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sto_key_empty(char key[16]) {
  char empty[16] = {0};
  return !memcmp(key, empty, 16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pv_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pv_dup(char *p, char *ep) {
  int n = ep - p;
  char *rv = (char *)malloc(n + 1);
  memcpy(rv, p, n);
  rv[n] = 0;
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pv_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  sub    %rdi,%rsi
  mov    %rsi,%rbx
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *pv_dup(char *p, char *ep) {
  int n = ep - p;
  char *rv = (char *)malloc(n + 1);
  memcpy(rv, p, n);
  rv[n] = 0;
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pv_dup>:
  endbr64
  push   %r13
  sub    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *pv_dup(char *p, char *ep) {
  int n = ep - p;
  char *rv = (char *)malloc(n + 1);
  memcpy(rv, p, n);
  rv[n] = 0;
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pv_dup>:
  endbr64
  push   %r13
  sub    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *pv_dup(char *p, char *ep) {
  int n = ep - p;
  char *rv = (char *)malloc(n + 1);
  memcpy(rv, p, n);
  rv[n] = 0;
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hxd_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  lea    D4(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: helps

assistant: ```c
const char *hxd_help(struct hexdump *X) {
  (void)X;
  return "helps";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hxd_help>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: helps

assistant: ```c
const char *hxd_help(struct hexdump *X) {
  (void)X;
  return "helps";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hxd_help>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: helps

assistant: ```c
const char *hxd_help(struct hexdump *X) {
  (void)X;
  return "helps";
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hxd_help>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: helps

assistant: ```c
const char *hxd_help(struct hexdump *X) {
  (void)X;
  return "helps";
}
```
user: What is the c source code of the assembly code below:

```asm
<computed_goto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  endbr64
  shll   -0x14(%rbp)
  lea    -0xe(%rip),%rax        # 1104 <computed_goto+0xb>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x11,-0x14(%rbp)
  jle    L0
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L4:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0xf,-0x14(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  nop
  jmp    *%rax
L0:
  cmpl   $0xc,-0x14(%rbp)
  jg     L4
  endbr64
  mov    $0x5,%eax
  pop    %rbp
  ret
```

assistant: ```c
int computed_goto(int x) {
start:
  x = x << 1;
  void *location = &&start;
  if (x > 17)
    location = &&done;
  while (x > 12) {
    --x;
    if (x == 15)
      goto *location;
  }
done:
  return 5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<computed_goto>:
  endbr64
  endbr64
  add    %edi,%edi
  cmp    $0x12,%edi
  lea    -0x10(%rip),%rax        # 10fd <computed_goto+0x4>
  lea    D7(%rip),%rdx
  cmovge %rdx,%rax
L5:
  cmp    $0xc,%edi
  jle    L10
  sub    $0x1,%edi
  cmp    $0xf,%edi
  jne    L5
  jmp    *%rax
L10:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int computed_goto(int x) {
start:
  x = x << 1;
  void *location = &&start;
  if (x > 17)
    location = &&done;
  while (x > 12) {
    --x;
    if (x == 15)
      goto *location;
  }
done:
  return 5;
}
```
user: What is the c source code of the assembly code below:

```asm
<computed_goto>:
  endbr64
  endbr64
  add    %edi,%edi
  lea    -0xd(%rip),%rax        # 1104 <computed_goto+0x4>
  lea    D6(%rip),%rdx
  cmp    $0x12,%edi
  cmovge %rdx,%rax
  jmp    L5
  nopl   0x0(%rax)
L19:
  sub    $0x1,%edi
  cmp    $0xf,%edi
  je     L20
L5:
  cmp    $0xc,%edi
  jg     L19
  endbr64
  mov    $0x5,%eax
  ret
  nop
L20:
  jmp    *%rax
```

assistant: ```c
int computed_goto(int x) {
start:
  x = x << 1;
  void *location = &&start;
  if (x > 17)
    location = &&done;
  while (x > 12) {
    --x;
    if (x == 15)
      goto *location;
  }
done:
  return 5;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<computed_goto>:
  endbr64
  endbr64
  add    %edi,%edi
  lea    -0xd(%rip),%rax        # 1104 <computed_goto+0x4>
  lea    D8(%rip),%rdx
  cmp    $0x12,%edi
  cmovge %rdx,%rax
  jmp    L20
  nopl   0x0(%rax)
L10:
  sub    $0x1,%edi
  cmp    $0xf,%edi
  je     L0
L20:
  cmp    $0xc,%edi
  jg     L10
  endbr64
  mov    $0x5,%eax
  ret
  nop
L0:
  jmp    *%rax
```

assistant: ```c
int computed_goto(int x) {
start:
  x = x << 1;
  void *location = &&start;
  if (x > 17)
    location = &&done;
  while (x > 12) {
    --x;
    if (x == 15)
      goto *location;
  }
done:
  return 5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_pkt_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x3ff,-0x24(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L22
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bcopy@plt>
  jmp    L23
L13:
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  subl   $0x40,-0x24(%rbp)
L22:
  cmpl   $0x0,-0x24(%rbp)
  jg     L13
L23:
  leave
  ret
```

assistant: ```c
void _pkt_copy(const void *_src, void *_dst, int l) {
  const uint64_t *src = _src;
  uint64_t *dst = _dst;
  if (__builtin_expect(!!(l >= 1024), 0)) {
    bcopy(src, dst, l);
    return;
  }
  for (; l > 0; l -= 64) {
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_pkt_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x3ff,%edx
  setg   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L8
  test   %r12d,%r12d
  jle    L1
  lea    -0x1(%r12),%eax
  shr    $0x6,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x5,%rax
  add    %rbx,%rax
L6:
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    0x4(%rbx),%edx
  mov    %edx,0x4(%rbp)
  mov    0x8(%rbx),%edx
  mov    %edx,0x8(%rbp)
  mov    0xc(%rbx),%edx
  mov    %edx,0xc(%rbp)
  mov    0x10(%rbx),%edx
  mov    %edx,0x10(%rbp)
  mov    0x14(%rbx),%edx
  mov    %edx,0x14(%rbp)
  mov    0x18(%rbx),%edx
  mov    %edx,0x18(%rbp)
  add    $0x20,%rbx
  add    $0x20,%rbp
  mov    -0x4(%rbx),%edx
  mov    %edx,-0x4(%rbp)
  cmp    %rbx,%rax
  jne    L6
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcopy@plt>
  jmp    L1
```

assistant: ```c
void _pkt_copy(const void *_src, void *_dst, int l) {
  const uint64_t *src = _src;
  uint64_t *dst = _dst;
  if (__builtin_expect(!!(l >= 1024), 0)) {
    bcopy(src, dst, l);
    return;
  }
  for (; l > 0; l -= 64) {
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_pkt_copy>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  cmp    $0x3ff,%edx
  setg   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L6
  test   %r13d,%r13d
  jle    L25
  lea    -0x1(%r13),%eax
  shr    $0x6,%eax
  add    $0x1,%eax
  shl    $0x5,%rax
  add    %rbp,%rax
L13:
  mov    0x0(%rbp),%edx
  add    $0x20,%rbp
  add    $0x20,%r12
  mov    %edx,-0x20(%r12)
  mov    -0x1c(%rbp),%edx
  mov    %edx,-0x1c(%r12)
  mov    -0x18(%rbp),%edx
  mov    %edx,-0x18(%r12)
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x14(%r12)
  mov    -0x10(%rbp),%edx
  mov    %edx,-0x10(%r12)
  mov    -0xc(%rbp),%edx
  mov    %edx,-0xc(%r12)
  mov    -0x8(%rbp),%edx
  mov    %edx,-0x8(%r12)
  mov    -0x4(%rbp),%edx
  mov    %edx,-0x4(%r12)
  cmp    %rbp,%rax
  jne    L13
L25:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <bcopy@plt>
```

assistant: ```c
void _pkt_copy(const void *_src, void *_dst, int l) {
  const uint64_t *src = _src;
  uint64_t *dst = _dst;
  if (__builtin_expect(!!(l >= 1024), 0)) {
    bcopy(src, dst, l);
    return;
  }
  for (; l > 0; l -= 64) {
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_pkt_copy>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  cmp    $0x3ff,%edx
  push   %rbp
  setg   %dil
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L36
  test   %r13d,%r13d
  jle    L17
  lea    0x1f(%r12),%rax
  sub    %rbp,%rax
  cmp    $0x3e,%rax
  jbe    L16
  lea    -0x1(%r13),%edx
  xor    %eax,%eax
  xor    %ecx,%ecx
  shr    $0x6,%edx
  lea    0x1(%rdx),%edx
  nopl   0x0(%rax,%rax,1)
L3:
  movdqu 0x10(%r12,%rax,1),%xmm0
  movdqu (%r12,%rax,1),%xmm1
  add    $0x1,%ecx
  movups %xmm1,0x0(%rbp,%rax,1)
  movups %xmm0,0x10(%rbp,%rax,1)
  add    $0x20,%rax
  cmp    %edx,%ecx
  jb     L3
L17:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <bcopy@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  lea    -0x1(%r13),%eax
  shr    $0x6,%eax
  add    $0x1,%eax
  shl    $0x5,%rax
  add    %rbp,%rax
  nopl   0x0(%rax)
L11:
  mov    (%r12),%edx
  add    $0x20,%r12
  add    $0x20,%rbp
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%r12),%edx
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%r12),%edx
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%r12),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%r12),%edx
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%r12),%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%r12),%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%r12),%edx
  mov    %edx,-0x4(%rbp)
  cmp    %rax,%rbp
  jne    L11
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void _pkt_copy(const void *_src, void *_dst, int l) {
  const uint64_t *src = _src;
  uint64_t *dst = _dst;
  if (__builtin_expect(!!(l >= 1024), 0)) {
    bcopy(src, dst, l);
    return;
  }
  for (; l > 0; l -= 64) {
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
    *dst++ = *src++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<have_clmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <cpuid@plt>
  mov    -0x18(%rbp),%eax
  and    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x80000,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L18
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    $0x1,%eax
  jmp    L12
L18:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int have_clmul(void) {
  unsigned eax, ebx, ecx, edx;
  int has_pclmulqdq;
  int has_sse41;
  cpuid(1, &eax, &ebx, &ecx, &edx);
  has_pclmulqdq = ecx & 0x2;
  has_sse41 = ecx & 0x80000;
  return has_pclmulqdq && has_sse41;
}
```