ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<fillTable>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  jg     L3
  cltq
  mov    %edi,(%rdx,%rax,4)
  mov    $0x0,%eax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fillTable(int inode, int *pos, int *table) {
  int i;
  for (i = 0; i < (*pos); i++) {
    if (inode == table[(i)])
      ;
    return -1;
  }
  table[(*pos)] = inode;
  *pos++;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fillTable>:
  endbr64
  movslq (%rsi),%rax
  test   %eax,%eax
  jg     L7
  mov    %edi,(%rdx,%rax,4)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fillTable(int inode, int *pos, int *table) {
  int i;
  for (i = 0; i < (*pos); i++) {
    if (inode == table[(i)])
      ;
    return -1;
  }
  table[(*pos)] = inode;
  *pos++;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fillTable>:
  endbr64
  movslq (%rsi),%rax
  test   %eax,%eax
  jg     L3
  mov    %edi,(%rdx,%rax,4)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fillTable(int inode, int *pos, int *table) {
  int i;
  for (i = 0; i < (*pos); i++) {
    if (inode == table[(i)])
      ;
    return -1;
  }
  table[(*pos)] = inode;
  *pos++;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<step4>:
  endbr64
  mov    %r9,%rdx
  mov    0x8(%rsp),%r8
  mov    0x10(%rsp),%rdi
  mov    %rcx,%rsi
  mov    $0x0,%r9d
  jmp    L19
L32:
  mov    %r9d,%eax
  and    $0x7,%eax
  mov    %r9d,%ecx
  and    $0xfffffff8,%ecx
  movslq (%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    (%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x4(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x42(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x8(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x84(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0xc(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0xc6(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x10(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x108(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x14(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x14a(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x18(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x18c(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x1c(%rdi),%r10
  mov    (%rdx,%r10,4),%r10d
  lea    0x1ce(%rcx,%rax,1),%eax
  cltq
  mov    %r10d,(%r8,%rax,4)
  add    $0x1,%r9d
  add    $0x20,%rsi
  cmp    $0x40,%r9d
  je     L34
L19:
  mov    $0x0,%eax
L26:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L26
  jmp    L32
L34:
  ret
```

assistant: ```c
void step4(int work_x[], int work_y[], int DATA_x[], int DATA_y[], int data_x[], int data_y[], int smem[], int reversed[], float sin_64[448], float cos_64[448], float sin_512[448], float cos_512[448]) {
  int tid, hi, lo, i, j, stride;
  stride = 64;
outer:
  for (tid = 0; tid < 64; tid++) {
  load:
    for (i = 0; i < 8; i++) {
      data_y[i] = DATA_y[tid * 8 + i];
    }
    hi = tid >> 3;
    lo = tid & 7;
    {
      smem[0 * 66 + hi * 8 + lo] = data_y[reversed[0]];
      smem[1 * 66 + hi * 8 + lo] = data_y[reversed[1]];
      smem[2 * 66 + hi * 8 + lo] = data_y[reversed[2]];
      smem[3 * 66 + hi * 8 + lo] = data_y[reversed[3]];
      smem[4 * 66 + hi * 8 + lo] = data_y[reversed[4]];
      smem[5 * 66 + hi * 8 + lo] = data_y[reversed[5]];
      smem[6 * 66 + hi * 8 + lo] = data_y[reversed[6]];
      smem[7 * 66 + hi * 8 + lo] = data_y[reversed[7]];
    };
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<step4>:
  endbr64
  mov    0x8(%rsp),%r8
  mov    0x10(%rsp),%rdi
  mov    %r9,%rdx
  mov    %rcx,%rsi
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L5
  movslq (%rdi),%r10
  mov    %r9d,%eax
  mov    %r9d,%ecx
  add    $0x1,%r9d
  and    $0x7,%eax
  and    $0xfffffff8,%ecx
  add    $0x20,%rsi
  mov    (%rdx,%r10,4),%r11d
  lea    (%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x4(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x42(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x8(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x84(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0xc(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0xc6(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x10(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x108(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x14(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x14a(%rcx,%rax,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x18(%rdi),%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x18c(%rcx,%rax,1),%r10d
  lea    0x1ce(%rcx,%rax,1),%eax
  movslq %r10d,%r10
  cltq
  mov    %r11d,(%r8,%r10,4)
  movslq 0x1c(%rdi),%r10
  mov    (%rdx,%r10,4),%r10d
  mov    %r10d,(%r8,%rax,4)
  cmp    $0x40,%r9d
  jne    L11
  ret
```

assistant: ```c
void step4(int work_x[], int work_y[], int DATA_x[], int DATA_y[], int data_x[], int data_y[], int smem[], int reversed[], float sin_64[448], float cos_64[448], float sin_512[448], float cos_512[448]) {
  int tid, hi, lo, i, j, stride;
  stride = 64;
outer:
  for (tid = 0; tid < 64; tid++) {
  load:
    for (i = 0; i < 8; i++) {
      data_y[i] = DATA_y[tid * 8 + i];
    }
    hi = tid >> 3;
    lo = tid & 7;
    {
      smem[0 * 66 + hi * 8 + lo] = data_y[reversed[0]];
      smem[1 * 66 + hi * 8 + lo] = data_y[reversed[1]];
      smem[2 * 66 + hi * 8 + lo] = data_y[reversed[2]];
      smem[3 * 66 + hi * 8 + lo] = data_y[reversed[3]];
      smem[4 * 66 + hi * 8 + lo] = data_y[reversed[4]];
      smem[5 * 66 + hi * 8 + lo] = data_y[reversed[5]];
      smem[6 * 66 + hi * 8 + lo] = data_y[reversed[6]];
      smem[7 * 66 + hi * 8 + lo] = data_y[reversed[7]];
    };
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<step4>:
  endbr64
  mov    0x8(%rsp),%r8
  mov    0x10(%rsp),%rdi
  mov    %r9,%rax
  mov    %rcx,%rdx
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rdx),%ecx
  mov    %r9d,%esi
  add    $0x20,%rdx
  and    $0xfffffff8,%esi
  mov    %ecx,(%rax)
  mov    -0x1c(%rdx),%ecx
  mov    %ecx,0x4(%rax)
  mov    -0x18(%rdx),%ecx
  mov    %ecx,0x8(%rax)
  mov    -0x14(%rdx),%ecx
  mov    %ecx,0xc(%rax)
  mov    -0x10(%rdx),%ecx
  mov    %ecx,0x10(%rax)
  mov    -0xc(%rdx),%ecx
  mov    %ecx,0x14(%rax)
  mov    -0x8(%rdx),%ecx
  mov    %ecx,0x18(%rax)
  mov    -0x4(%rdx),%ecx
  mov    %ecx,0x1c(%rax)
  mov    %r9d,%ecx
  movslq (%rdi),%r10
  add    $0x1,%r9d
  and    $0x7,%ecx
  mov    (%rax,%r10,4),%r11d
  lea    (%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x4(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0x42(%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x8(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0x84(%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0xc(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0xc6(%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x10(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0x108(%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x14(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0x14a(%rsi,%rcx,1),%r10d
  movslq %r10d,%r10
  mov    %r11d,(%r8,%r10,4)
  movslq 0x18(%rdi),%r10
  mov    (%rax,%r10,4),%r11d
  lea    0x18c(%rsi,%rcx,1),%r10d
  lea    0x1ce(%rsi,%rcx,1),%ecx
  movslq %r10d,%r10
  movslq %ecx,%rcx
  mov    %r11d,(%r8,%r10,4)
  movslq 0x1c(%rdi),%r10
  mov    (%rax,%r10,4),%r10d
  mov    %r10d,(%r8,%rcx,4)
  cmp    $0x40,%r9d
  jne    L3
  ret
```

assistant: ```c
void step4(int work_x[], int work_y[], int DATA_x[], int DATA_y[], int data_x[], int data_y[], int smem[], int reversed[], float sin_64[448], float cos_64[448], float sin_512[448], float cos_512[448]) {
  int tid, hi, lo, i, j, stride;
  stride = 64;
outer:
  for (tid = 0; tid < 64; tid++) {
  load:
    for (i = 0; i < 8; i++) {
      data_y[i] = DATA_y[tid * 8 + i];
    }
    hi = tid >> 3;
    lo = tid & 7;
    {
      smem[0 * 66 + hi * 8 + lo] = data_y[reversed[0]];
      smem[1 * 66 + hi * 8 + lo] = data_y[reversed[1]];
      smem[2 * 66 + hi * 8 + lo] = data_y[reversed[2]];
      smem[3 * 66 + hi * 8 + lo] = data_y[reversed[3]];
      smem[4 * 66 + hi * 8 + lo] = data_y[reversed[4]];
      smem[5 * 66 + hi * 8 + lo] = data_y[reversed[5]];
      smem[6 * 66 + hi * 8 + lo] = data_y[reversed[6]];
      smem[7 * 66 + hi * 8 + lo] = data_y[reversed[7]];
    };
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mov_m32abs_imm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xffffffff80000000,%rax
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  int3
L3:
  mov    $0xc7,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    $0x25,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <put32@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <put32@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: Error: destination %lx not in lower 2GB for mov_m32abs_imm32()


assistant: ```c
void mov_m32abs_imm32(unsigned int *m32, unsigned int imm32) {
  if ((long)m32 & 0xFFFFFFFF80000000LL) {
    printf("Error: destination %lx not in lower 2GB for mov_m32abs_imm32()\n", (long)m32);
    asm(" int $3; ");
  }
  put8(0xC7);
  put8(0x04);
  put8(0x25);
  put32((int)(unsigned long)m32);
  put32(imm32);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mov_m32abs_imm32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   $0xffffffff80000000,%rdi
  jne    L9
L10:
  mov    $0xc7,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    $0x25,%edi
  mov    $0x0,%eax
  call   <put8@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <put32@plt>
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <put32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  int3
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string

tool: D4: Error: destination %lx not in lower 2GB for mov_m32abs_imm32()


assistant: ```c
void mov_m32abs_imm32(unsigned int *m32, unsigned int imm32) {
  if ((long)m32 & 0xFFFFFFFF80000000LL) {
    printf("Error: destination %lx not in lower 2GB for mov_m32abs_imm32()\n", (long)m32);
    asm(" int $3; ");
  }
  put8(0xC7);
  put8(0x04);
  put8(0x25);
  put32((int)(unsigned long)m32);
  put32(imm32);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mov_m32abs_imm32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   $0xffffffff80000000,%rdi
  jne    L5
L4:
  mov    $0xc7,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    $0x25,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <put32@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <put32@plt>
  nopl   0x0(%rax)
L5:
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  int3
  jmp    L4
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: Error: destination %lx not in lower 2GB for mov_m32abs_imm32()


assistant: ```c
void mov_m32abs_imm32(unsigned int *m32, unsigned int imm32) {
  if ((long)m32 & 0xFFFFFFFF80000000LL) {
    printf("Error: destination %lx not in lower 2GB for mov_m32abs_imm32()\n", (long)m32);
    asm(" int $3; ");
  }
  put8(0xC7);
  put8(0x04);
  put8(0x25);
  put32((int)(unsigned long)m32);
  put32(imm32);
}
```
user: What is the c source code of the assembly code below:

```asm
<mov_m32abs_imm32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   $0xffffffff80000000,%rdi
  jne    L13
L3:
  mov    $0xc7,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    $0x4,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    $0x25,%edi
  xor    %eax,%eax
  call   <put8@plt>
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <put32@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1090 <put32@plt>
  nopl   0x0(%rax)
L13:
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  int3
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: Error: destination %lx not in lower 2GB for mov_m32abs_imm32()


assistant: ```c
void mov_m32abs_imm32(unsigned int *m32, unsigned int imm32) {
  if ((long)m32 & 0xFFFFFFFF80000000LL) {
    printf("Error: destination %lx not in lower 2GB for mov_m32abs_imm32()\n", (long)m32);
    asm(" int $3; ");
  }
  put8(0xC7);
  put8(0x04);
  put8(0x25);
  put32((int)(unsigned long)m32);
  put32(imm32);
}
```
user: Translate the below assembly code into C programming language:

```asm
<shlex_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L137
L25:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movsbl -0x15(%rbp),%eax
  cmp    $0x27,%eax
  je     L85
  cmp    $0x27,%eax
  jg     L115
  cmp    $0x22,%eax
  je     L85
  cmp    $0x22,%eax
  jg     L115
  cmp    $0x9,%eax
  je     L124
  cmp    $0x20,%eax
  jne    L115
L124:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L137
L85:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L147
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_token_string@plt>
  mov    %rax,(%rbx)
  jmp    L137
L147:
  mov    $0x1,%eax
  jmp    L42
L115:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L30
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_token_cmdarg@plt>
  mov    %rax,(%rbx)
  jmp    L137
L30:
  mov    $0x1,%eax
  jmp    L42
L137:
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L63
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
L63:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int shlex_split(const char *p, char *argv[], int *argv_len) {
  int pos = 0;
  while (p != NULL && *p != '\0') {
    char c = *p;
    switch (c) {
    case ' ':
    case '\t':
      p++;
      break;
    case '\'':
    case '"':
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_string(&p);
      } else
        return 1;
      break;
    default:
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_cmdarg(&p);
      } else
        return 1;
      break;
    }
  }
  argv[pos] = NULL;
  *argv_len = pos;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shlex_split>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%edx
  lea    0x8(%rsp),%r12
  test   %rdi,%rdi
  jne    L27
L28:
  movslq %edx,%rax
  movq   $0x0,0x0(%rbp,%rax,8)
  mov    %edx,(%rbx)
  mov    $0x0,%eax
L61:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L139:
  cmp    $0x27,%al
  je     L112
L69:
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L26
  lea    0x1(%rdx),%r13d
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,8),%r14
  mov    %r12,%rdi
  call   <parse_token_cmdarg@plt>
  mov    %rax,(%r14)
  mov    %r13d,%edx
  jmp    L9
L112:
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L60
  lea    0x1(%rdx),%r13d
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,8),%r14
  mov    %r12,%rdi
  call   <parse_token_string@plt>
  mov    %rax,(%r14)
  mov    %r13d,%edx
L9:
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  je     L28
L27:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L28
  cmp    $0x22,%al
  je     L112
  jg     L139
  cmp    $0x9,%al
  je     L103
  cmp    $0x20,%al
  jne    L69
L103:
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  jmp    L27
L60:
  mov    $0x1,%eax
  jmp    L61
L26:
  mov    $0x1,%eax
  jmp    L61
```

assistant: ```c
int shlex_split(const char *p, char *argv[], int *argv_len) {
  int pos = 0;
  while (p != NULL && *p != '\0') {
    char c = *p;
    switch (c) {
    case ' ':
    case '\t':
      p++;
      break;
    case '\'':
    case '"':
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_string(&p);
      } else
        return 1;
      break;
    default:
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_cmdarg(&p);
      } else
        return 1;
      break;
    }
  }
  argv[pos] = NULL;
  *argv_len = pos;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shlex_split>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  push   %r13
  push   %r12
  mov    %rdx,%r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  test   %rdi,%rdi
  je     L100
  nopw   0x0(%rax,%rax,1)
L90:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L102
L103:
  cmp    $0x22,%al
  je     L64
  jg     L22
  cmp    $0x9,%al
  je     L12
  cmp    $0x20,%al
  jne    L57
L12:
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L103
  nopl   (%rax)
L102:
  movslq %edx,%rax
  lea    (%rbx,%rax,8),%rbx
L100:
  movq   $0x0,(%rbx)
  xor    %eax,%eax
  mov    %edx,(%r12)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L22:
  cmp    $0x27,%al
  je     L64
L57:
  mov    (%r12),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L45
  mov    %rbp,%rdi
  lea    (%rbx,%rdx,8),%r14
  lea    0x1(%rdx),%r13d
  call   <parse_token_cmdarg@plt>
  movslq %r13d,%rdx
  mov    %rax,(%r14)
L23:
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jne    L90
  jmp    L102
  nopl   0x0(%rax)
L64:
  mov    (%r12),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L45
  mov    %rbp,%rdi
  lea    (%rbx,%rdx,8),%r14
  lea    0x1(%rdx),%r13d
  call   <parse_token_string@plt>
  movslq %r13d,%rdx
  mov    %rax,(%r14)
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int shlex_split(const char *p, char *argv[], int *argv_len) {
  int pos = 0;
  while (p != NULL && *p != '\0') {
    char c = *p;
    switch (c) {
    case ' ':
    case '\t':
      p++;
      break;
    case '\'':
    case '"':
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_string(&p);
      } else
        return 1;
      break;
    default:
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_cmdarg(&p);
      } else
        return 1;
      break;
    }
  }
  argv[pos] = NULL;
  *argv_len = pos;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<shlex_split>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  push   %r13
  push   %r12
  mov    %rdx,%r12
  xor    %edx,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  test   %rdi,%rdi
  je     L50
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl (%rcx),%eax
  test   %al,%al
  je     L15
L87:
  cmp    $0x22,%al
  je     L79
  jg     L8
  cmp    $0x9,%al
  je     L42
  cmp    $0x20,%al
  jne    L73
L42:
  add    $0x1,%rcx
  mov    %rcx,0x8(%rsp)
  movzbl (%rcx),%eax
  test   %al,%al
  jne    L87
  nopl   (%rax)
L15:
  movslq %edx,%rax
  lea    (%rbx,%rax,8),%rbx
L50:
  movq   $0x0,(%rbx)
  xor    %eax,%eax
  mov    %edx,(%r12)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  cmp    $0x27,%al
  je     L79
L73:
  mov    (%r12),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L38
  mov    %rbp,%rdi
  lea    (%rbx,%rdx,8),%r14
  lea    0x1(%rdx),%r13d
  call   <parse_token_cmdarg@plt>
  movslq %r13d,%rdx
  mov    %rax,(%r14)
L46:
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jne    L20
  jmp    L15
  nopl   0x0(%rax)
L79:
  mov    (%r12),%eax
  sub    $0x1,%eax
  cmp    %edx,%eax
  jle    L38
  mov    %rbp,%rdi
  lea    (%rbx,%rdx,8),%r14
  lea    0x1(%rdx),%r13d
  call   <parse_token_string@plt>
  movslq %r13d,%rdx
  mov    %rax,(%r14)
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int shlex_split(const char *p, char *argv[], int *argv_len) {
  int pos = 0;
  while (p != NULL && *p != '\0') {
    char c = *p;
    switch (c) {
    case ' ':
    case '\t':
      p++;
      break;
    case '\'':
    case '"':
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_string(&p);
      } else
        return 1;
      break;
    default:
      if (*argv_len - 1 > pos) {
        argv[pos++] = parse_token_cmdarg(&p);
      } else
        return 1;
      break;
    }
  }
  argv[pos] = NULL;
  *argv_len = pos;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<barrier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %eax,%edi
  call   <send@plt>
  lea    -0xc(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %eax,%edi
  call   <recv@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void barrier(int oob_sock) {
  int dummy = 0;
  send(oob_sock, &dummy, sizeof(dummy), 0);
  recv(oob_sock, &dummy, sizeof(dummy), 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<barrier>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  call   <send@plt>
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <recv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void barrier(int oob_sock) {
  int dummy = 0;
  send(oob_sock, &dummy, sizeof(dummy), 0);
  recv(oob_sock, &dummy, sizeof(dummy), 0);
}
```