user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <imat@plt>
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <mat@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L32
L58:
  mov    -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x3c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%eax
  imul   -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x28(%rbp)
L32:
  mov    -0x28(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L58
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ludcmp@plt>
  test   %eax,%eax
  je     L27
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L72
L27:
  movl   $0x0,-0x24(%rbp)
  jmp    L8
L30:
  movl   $0x0,-0x28(%rbp)
  jmp    L13
L65:
  mov    -0x24(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
L13:
  mov    -0x28(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L65
  mov    -0x24(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <lubksb@plt>
  addl   $0x1,-0x24(%rbp)
L8:
  mov    -0x24(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L30
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L72:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 1

assistant: ```c
extern int inverse(double *A, int lda, int n) {
  double d, *B;
  int i, j, *indx;
  indx = imat(n, 1);
  B = mat(n, n);
  for (i = 0; i < n; i++)
    memcpy(B + i * n, A + lda * i, sizeof(double) * n);
  if (ludcmp(B, n, indx, &d)) {
    free(indx);
    free(B);
    return -1;
  }
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++)
      A[i + j * lda] = 0.0;
    A[j + j * lda] = 1.0;
    lubksb(B, n, indx, A + j * lda);
  }
  free(indx);
  free(B);
  return 0;
}
```