ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sha256_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x4,%rdx
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x8,%rdx
  mov    0x8(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0xc,%rdx
  mov    0xc(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x10,%rdx
  mov    0x10(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x14,%rdx
  mov    0x14(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x18,%rdx
  mov    0x18(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x1c,%rdx
  mov    0x1c(%rax),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sha256_cpy(SHA256_CTX *restrict out, const SHA256_CTX *restrict in) {
  out->h[0] = in->h[0];
  out->h[1] = in->h[1];
  out->h[2] = in->h[2];
  out->h[3] = in->h[3];
  out->h[4] = in->h[4];
  out->h[5] = in->h[5];
  out->h[6] = in->h[6];
  out->h[7] = in->h[7];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sha256_cpy>:
  endbr64
  mov    (%rsi),%rdx
  mov    (%rdi),%rax
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%ecx
  mov    %ecx,0x4(%rax)
  mov    0x8(%rdx),%ecx
  mov    %ecx,0x8(%rax)
  mov    0xc(%rdx),%ecx
  mov    %ecx,0xc(%rax)
  mov    0x10(%rdx),%ecx
  mov    %ecx,0x10(%rax)
  mov    0x14(%rdx),%ecx
  mov    %ecx,0x14(%rax)
  mov    0x18(%rdx),%ecx
  mov    %ecx,0x18(%rax)
  mov    0x1c(%rdx),%edx
  mov    %edx,0x1c(%rax)
  ret
```

assistant: ```c
void sha256_cpy(SHA256_CTX *restrict out, const SHA256_CTX *restrict in) {
  out->h[0] = in->h[0];
  out->h[1] = in->h[1];
  out->h[2] = in->h[2];
  out->h[3] = in->h[3];
  out->h[4] = in->h[4];
  out->h[5] = in->h[5];
  out->h[6] = in->h[6];
  out->h[7] = in->h[7];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sha256_cpy>:
  endbr64
  mov    (%rsi),%rdx
  mov    (%rdi),%rax
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%ecx
  mov    %ecx,0x4(%rax)
  mov    0x8(%rdx),%ecx
  mov    %ecx,0x8(%rax)
  mov    0xc(%rdx),%ecx
  mov    %ecx,0xc(%rax)
  mov    0x10(%rdx),%ecx
  mov    %ecx,0x10(%rax)
  mov    0x14(%rdx),%ecx
  mov    %ecx,0x14(%rax)
  mov    0x18(%rdx),%ecx
  mov    %ecx,0x18(%rax)
  mov    0x1c(%rdx),%edx
  mov    %edx,0x1c(%rax)
  ret
```

assistant: ```c
void sha256_cpy(SHA256_CTX *restrict out, const SHA256_CTX *restrict in) {
  out->h[0] = in->h[0];
  out->h[1] = in->h[1];
  out->h[2] = in->h[2];
  out->h[3] = in->h[3];
  out->h[4] = in->h[4];
  out->h[5] = in->h[5];
  out->h[6] = in->h[6];
  out->h[7] = in->h[7];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sha256_cpy>:
  endbr64
  mov    (%rsi),%rdx
  mov    (%rdi),%rax
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%ecx
  mov    %ecx,0x4(%rax)
  mov    0x8(%rdx),%ecx
  mov    %ecx,0x8(%rax)
  mov    0xc(%rdx),%ecx
  mov    %ecx,0xc(%rax)
  mov    0x10(%rdx),%ecx
  mov    %ecx,0x10(%rax)
  mov    0x14(%rdx),%ecx
  mov    %ecx,0x14(%rax)
  mov    0x18(%rdx),%ecx
  mov    %ecx,0x18(%rax)
  mov    0x1c(%rdx),%edx
  mov    %edx,0x1c(%rax)
  ret
```

assistant: ```c
void sha256_cpy(SHA256_CTX *restrict out, const SHA256_CTX *restrict in) {
  out->h[0] = in->h[0];
  out->h[1] = in->h[1];
  out->h[2] = in->h[2];
  out->h[3] = in->h[3];
  out->h[4] = in->h[4];
  out->h[5] = in->h[5];
  out->h[6] = in->h[6];
  out->h[7] = in->h[7];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<genere_passwordA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4b4f4241,-0xc(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <binaireA@plt>
  mov    %rax,-0x30(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <binaireA@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0xa0,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L11:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  xor    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x13,-0x34(%rbp)
  jle    L11
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <MotPassA@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%esi
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: Mot de passe A: %c, %c, %c, %c


assistant: ```c
char *genere_passwordA(char *m) {
  char m2[4] = {'A', 'B', 'O', 'K'};
  long *decimal1 = binaireA(m);
  long *decimal2 = binaireA(m2);
  long *addition = malloc(20 * sizeof(long));
  int i;
  for (i = 0; i <= 19; ++i) {
    addition[i] = decimal1[i] ^ decimal2[i];
  }
  char *message = MotPassA(addition);
  printf("Mot de passe A: %c, %c, %c, %c\n", message[0], message[1], message[2], message[3]);
  return message;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<genere_passwordA>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4b4f4241,0x4(%rsp)
  call   <binaireA@plt>
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdi
  call   <binaireA@plt>
  mov    %rax,%rbx
  mov    $0xa0,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x0,%edx
L12:
  mov    0x0(%rbp,%rdx,1),%rcx
  xor    (%rbx,%rdx,1),%rcx
  mov    %rcx,(%rdi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0xa0,%rdx
  jne    L12
  call   <MotPassA@plt>
  mov    %rax,%rbx
  movsbl 0x2(%rax),%ecx
  movsbl 0x1(%rax),%edx
  movsbl (%rax),%esi
  movsbl 0x3(%rax),%r8d
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: Mot de passe A: %c, %c, %c, %c


assistant: ```c
char *genere_passwordA(char *m) {
  char m2[4] = {'A', 'B', 'O', 'K'};
  long *decimal1 = binaireA(m);
  long *decimal2 = binaireA(m2);
  long *addition = malloc(20 * sizeof(long));
  int i;
  for (i = 0; i <= 19; ++i) {
    addition[i] = decimal1[i] ^ decimal2[i];
  }
  char *message = MotPassA(addition);
  printf("Mot de passe A: %c, %c, %c, %c\n", message[0], message[1], message[2], message[3]);
  return message;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<genere_passwordA>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4b4f4241,0x4(%rsp)
  call   <binaireA@plt>
  lea    0x4(%rsp),%rdi
  mov    %rax,%rbp
  call   <binaireA@plt>
  mov    $0xa0,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  xor    %edx,%edx
  mov    %rax,%rdi
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp,%rdx,1),%rcx
  xor    (%rbx,%rdx,1),%rcx
  mov    %rcx,(%rdi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0xa0,%rdx
  jne    L0
  call   <MotPassA@plt>
  lea    D2(%rip),%rdi
  movsbl 0x2(%rax),%ecx
  movsbl 0x1(%rax),%edx
  mov    %rax,%r12
  movsbl (%rax),%esi
  movsbl 0x3(%rax),%r8d
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: Mot de passe A: %c, %c, %c, %c


assistant: ```c
char *genere_passwordA(char *m) {
  char m2[4] = {'A', 'B', 'O', 'K'};
  long *decimal1 = binaireA(m);
  long *decimal2 = binaireA(m2);
  long *addition = malloc(20 * sizeof(long));
  int i;
  for (i = 0; i <= 19; ++i) {
    addition[i] = decimal1[i] ^ decimal2[i];
  }
  char *message = MotPassA(addition);
  printf("Mot de passe A: %c, %c, %c, %c\n", message[0], message[1], message[2], message[3]);
  return message;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<genere_passwordA>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4b4f4241,0x4(%rsp)
  call   <binaireA@plt>
  lea    0x4(%rsp),%rdi
  mov    %rax,%rbp
  call   <binaireA@plt>
  mov    $0xa0,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%rdi
  lea    0x8(%rbx),%rax
  cmp    %rax,%rdi
  je     L25
  lea    0x8(%rbp),%rax
  cmp    %rax,%rdi
  je     L25
  movdqu (%rbx),%xmm2
  movdqu 0x0(%rbp),%xmm0
  pxor   %xmm2,%xmm0
  movups %xmm0,(%rdi)
  movdqu 0x10(%rbx),%xmm3
  movdqu 0x10(%rbp),%xmm0
  pxor   %xmm3,%xmm0
  movups %xmm0,0x10(%rdi)
  movdqu 0x20(%rbp),%xmm0
  movdqu 0x20(%rbx),%xmm4
  pxor   %xmm4,%xmm0
  movups %xmm0,0x20(%rdi)
  movdqu 0x30(%rbp),%xmm0
  movdqu 0x30(%rbx),%xmm5
  pxor   %xmm5,%xmm0
  movups %xmm0,0x30(%rdi)
  movdqu 0x40(%rbp),%xmm0
  movdqu 0x40(%rbx),%xmm6
  pxor   %xmm6,%xmm0
  movups %xmm0,0x40(%rdi)
  movdqu 0x50(%rbp),%xmm0
  movdqu 0x50(%rbx),%xmm7
  pxor   %xmm7,%xmm0
  movups %xmm0,0x50(%rdi)
  movdqu 0x60(%rbx),%xmm1
  movdqu 0x60(%rbp),%xmm0
  pxor   %xmm1,%xmm0
  movups %xmm0,0x60(%rdi)
  movdqu 0x70(%rbp),%xmm0
  movdqu 0x70(%rbx),%xmm2
  pxor   %xmm2,%xmm0
  movups %xmm0,0x70(%rdi)
  movdqu 0x80(%rbp),%xmm0
  movdqu 0x80(%rbx),%xmm3
  pxor   %xmm3,%xmm0
  movups %xmm0,0x80(%rdi)
  movdqu 0x90(%rbp),%xmm0
  movdqu 0x90(%rbx),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,0x90(%rdi)
L44:
  call   <MotPassA@plt>
  lea    D5(%rip),%rdi
  movsbl 0x2(%rax),%ecx
  movsbl 0x1(%rax),%edx
  mov    %rax,%r12
  movsbl (%rax),%esi
  movsbl 0x3(%rax),%r8d
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%rdx,1),%rax
  xor    (%rbx,%rdx,1),%rax
  mov    %rax,(%rdi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0xa0,%rdx
  jne    L1
  jmp    L44
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: Mot de passe A: %c, %c, %c, %c


assistant: ```c
char *genere_passwordA(char *m) {
  char m2[4] = {'A', 'B', 'O', 'K'};
  long *decimal1 = binaireA(m);
  long *decimal2 = binaireA(m2);
  long *addition = malloc(20 * sizeof(long));
  int i;
  for (i = 0; i <= 19; ++i) {
    addition[i] = decimal1[i] ^ decimal2[i];
  }
  char *message = MotPassA(addition);
  printf("Mot de passe A: %c, %c, %c, %c\n", message[0], message[1], message[2], message[3]);
  return message;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x3,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  je     L38
  cmpl   $0x4,-0x4(%rbp)
  jg     L20
  cmpl   $0x3,-0x4(%rbp)
  je     L24
  cmpl   $0x3,-0x4(%rbp)
  jg     L20
  cmpl   $0x1,-0x4(%rbp)
  je     L97
  cmpl   $0x2,-0x4(%rbp)
  je     L98
  jmp    L20
L97:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L98:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L24:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L38:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L20:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D9: one

tool: D4: two

tool: D17: three

tool: D6: four

assistant: ```c
int main(int argc, char **argv) {
  int foo = 3;
  switch (foo) {
  case 1:
    puts("one");
    break;
  case 2:
    puts("two");
    break;
  case 3:
    puts("three");
    break;
  case 4:
    puts("four");
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: three

assistant: ```c
int main(int argc, char **argv) {
  int foo = 3;
  switch (foo) {
  case 1:
    puts("one");
    break;
  case 2:
    puts("two");
    break;
  case 3:
    puts("three");
    break;
  case 4:
    puts("four");
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: three

assistant: ```c
int main(int argc, char **argv) {
  int foo = 3;
  switch (foo) {
  case 1:
    puts("one");
    break;
  case 2:
    puts("two");
    break;
  case 3:
    puts("three");
    break;
  case 4:
    puts("four");
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: three

assistant: ```c
int main(int argc, char **argv) {
  int foo = 3;
  switch (foo) {
  case 1:
    puts("one");
    break;
  case 2:
    puts("two");
    break;
  case 3:
    puts("three");
    break;
  case 4:
    puts("four");
    break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CE_pHM_CO3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D18(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D15(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x38(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm0,%xmm2
  addsd  -0x10(%rbp),%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type_guessed: byte[8]
name: parse_data
arguments: data_label: D15
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_CO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = K2 * (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O) / H3O;
  return t0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CE_pHM_CO3>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm0,%xmm2
  movq   %xmm1,%rbx
  movq   %xmm3,%rbp
  movq   %xmm4,%r12
  movq   %xmm5,%r14
  movsd  D9(%rip),%xmm0
  subsd  %xmm2,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D3(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm6
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm6
  movsd  %xmm6,(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm2
  movq   %rbx,%xmm0
  movsd  (%rsp),%xmm6
  mulsd  %xmm6,%xmm0
  movq   %r12,%xmm7
  divsd  %xmm2,%xmm7
  subsd  %xmm7,%xmm0
  movapd %xmm6,%xmm1
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm1
  addsd  %xmm6,%xmm1
  divsd  %xmm1,%xmm0
  divsd  %xmm6,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: byte[8]
name: disassemble_data
arguments: data_label: D3
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_CO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = K2 * (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O) / H3O;
  return t0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CE_pHM_CO3>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm2
  movsd  D14(%rip),%xmm0
  movsd  %xmm1,0x28(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm5,(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D11(%rip),%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x4,%edi
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  subsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm3,%xmm3
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D14
datatype: byte[8]
name: parse_data
arguments: label: D11
datatype: byte[8]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_CO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = K2 * (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O) / H3O;
  return t0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CE_pHM_CO3>:
  endbr64
  sub    $0x38,%rsp
  movapd %xmm0,%xmm2
  movsd  D1(%rip),%xmm0
  movsd  %xmm1,0x28(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  movsd  %xmm5,(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D17(%rip),%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm2
  divsd  %xmm5,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <pow@plt>
  movsd  (%rsp),%xmm5
  mov    $0x4,%edi
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x20(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm2
  movsd  0x28(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  add    $0x38,%rsp
  divsd  %xmm0,%xmm4
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  subsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm3,%xmm3
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: byte[8]
name: parse_data
arguments: data_label: D17
type_infered: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
double CE_pHM_CO3(double pH, double M, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = K2 * (-Kw + H3O * M + H3O * H3O) / (2.0 * K2 + H3O) / H3O;
  return t0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ip_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x3,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L20
L91:
  cmpl   $0x2e,-0x10(%rbp)
  jne    L90
  cmpl   $0xff,-0x18(%rbp)
  jbe    L57
  mov    $0x0,%eax
  jmp    L78
L57:
  shlq   $0x8,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  add    %rax,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L20
L90:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  shll   $0x3,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  subl   $0x30,-0x10(%rbp)
  cmpl   $0x9,-0x10(%rbp)
  jbe    L46
  mov    $0x0,%eax
  jmp    L78
L46:
  mov    -0x10(%rbp),%eax
  add    %eax,-0x18(%rbp)
L20:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L91
  cmpl   $0xff,-0x18(%rbp)
  ja     L12
  cmpl   $0x0,-0x14(%rbp)
  je     L95
L12:
  mov    $0x0,%eax
  jmp    L78
L95:
  shlq   $0x8,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L78:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ip_to_int(const char *addr) {
  unsigned int c, octet, t;
  unsigned long ipnum;
  int i = 3;
  octet = ipnum = 0;
  while ((c = *addr++)) {
    if (c == '.') {
      if (octet > 255)
        return 0;
      ipnum <<= 8;
      ipnum += octet;
      i--;
      octet = 0;
    } else {
      t = octet;
      octet <<= 3;
      octet += t;
      octet += t;
      c -= '0';
      if (c > 9)
        return 0;
      octet += c;
    }
  }
  if ((octet > 255) || (i != 0))
    return 0;
  ipnum <<= 8;
  return ipnum + octet;
}
```