ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_qsort1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L48
  movslq %esi,%rax
  mov    %esi,%r14d
  mov    %edx,%ebx
  mov    (%rdi,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L84:
  mov    (%rsp),%rcx
  movslq %ebx,%rax
  lea    (%rcx,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L17
  sub    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %r14d,%ebx
  jg     L6
L91:
  mov    %r14d,%ebx
  sub    $0x1,%r14d
L78:
  mov    (%rsp),%r15
  movslq %ebx,%rax
  mov    0x8(%rsp),%esi
  mov    %r14d,%edx
  mov    %r12,(%r15,%rax,8)
  mov    %r15,%rdi
  call   <_qsort@plt>
  mov    0xc(%rsp),%edx
  add    $0x18,%rsp
  lea    0x1(%rbx),%esi
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <_qsort@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rsp),%rcx
  movslq %r14d,%rax
  lea    0x1(%r14),%r15d
  shl    $0x3,%rax
  add    %rax,%rcx
  cmp    %ebx,%r14d
  jge    L91
  mov    0x0(%rbp),%rdx
  mov    %rdx,(%rcx)
  cmp    %ebx,%r15d
  jge    L9
  mov    (%rsp),%rcx
  lea    0x8(%rcx,%rax,1),%r13
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x8,%r13
  cmp    %ebx,%r15d
  je     L78
L65:
  mov    0x0(%r13),%rdi
  mov    %r12,%rsi
  mov    %r15d,%r14d
  lea    0x1(%r15),%r15d
  call   <strcmp@plt>
  test   %rax,%rax
  js     L59
  mov    0x0(%r13),%rax
  mov    0x8(%rsp),%esi
  lea    -0x1(%r14),%edx
  sub    $0x1,%ebx
  mov    %rax,0x0(%rbp)
  mov    (%rsp),%rbp
  mov    %r12,0x0(%r13)
  mov    %rbp,%rdi
  call   <_qsort@plt>
  mov    0xc(%rsp),%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <_qsort@plt>
  cmp    %r14d,%ebx
  jg     L84
L48:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %r15d,%ebx
  jmp    L78
```

assistant: ```c
void _qsort1(char *v[], int left, int right) {
  if (left < right) {
    int i = left, j = right;
    char *temp = v[i];
    while (i < j) {
      while (i < j && strcmp(v[j], temp) >= 0) {
        j--;
      }
      if (i < j) {
        v[i++] = v[j];
      }
      while (i < j && strcmp(v[i], temp) < 0) {
        i++;
      }
      if (i < j) {
        v[j--] = v[i];
      }
      v[i] = temp;
      _qsort(v, left, i - 1);
      _qsort(v, i + 1, right);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_qsort1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L36
  movslq %esi,%rax
  mov    %esi,%r14d
  mov    %edx,%ebx
  mov    (%rdi,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rsp),%rcx
  movslq %ebx,%rax
  lea    (%rcx,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  js     L84
  sub    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %r14d,%ebx
  jg     L1
L77:
  mov    %r14d,%ebx
  sub    $0x1,%r14d
L63:
  mov    (%rsp),%r15
  movslq %ebx,%rax
  mov    0x8(%rsp),%esi
  mov    %r14d,%edx
  mov    %r12,(%r15,%rax,8)
  mov    %r15,%rdi
  call   <_qsort@plt>
  mov    0xc(%rsp),%edx
  add    $0x18,%rsp
  lea    0x1(%rbx),%esi
  mov    %r15,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <_qsort@plt>
  nopl   0x0(%rax,%rax,1)
L84:
  mov    (%rsp),%rcx
  movslq %r14d,%rax
  lea    0x1(%r14),%r15d
  shl    $0x3,%rax
  add    %rax,%rcx
  cmp    %ebx,%r14d
  jge    L77
  mov    0x0(%rbp),%rdx
  mov    %rdx,(%rcx)
  cmp    %ebx,%r15d
  jge    L66
  mov    (%rsp),%rcx
  lea    0x8(%rcx,%rax,1),%r13
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x8,%r13
  cmp    %ebx,%r15d
  je     L63
L93:
  mov    0x0(%r13),%rdi
  mov    %r12,%rsi
  mov    %r15d,%r14d
  lea    0x1(%r15),%r15d
  call   <strcmp@plt>
  test   %rax,%rax
  js     L31
  mov    0x0(%r13),%rax
  mov    0x8(%rsp),%esi
  lea    -0x1(%r14),%edx
  sub    $0x1,%ebx
  mov    %rax,0x0(%rbp)
  mov    (%rsp),%rbp
  mov    %r12,0x0(%r13)
  mov    %rbp,%rdi
  call   <_qsort@plt>
  mov    0xc(%rsp),%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <_qsort@plt>
  cmp    %r14d,%ebx
  jg     L14
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L66:
  mov    %r15d,%ebx
  jmp    L63
```

assistant: ```c
void _qsort1(char *v[], int left, int right) {
  if (left < right) {
    int i = left, j = right;
    char *temp = v[i];
    while (i < j) {
      while (i < j && strcmp(v[j], temp) >= 0) {
        j--;
      }
      if (i < j) {
        v[i++] = v[j];
      }
      while (i < j && strcmp(v[i], temp) < 0) {
        i++;
      }
      if (i < j) {
        v[j--] = v[i];
      }
      v[i] = temp;
      _qsort(v, left, i - 1);
      _qsort(v, i + 1, right);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x20(%rbp)
  movq   $0x2000000,-0x18(%rbp)
  movq   $0x4000000,-0x10(%rbp)
  movq   $0x6000000,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  movl   $0x3,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  int *remoteArr2 = (int *)0x04000000;
  int *remoteArr3 = (int *)0x06000000;
  *(localArr) = 0;
  *(remoteArr1) = 1;
  *(remoteArr2) = 2;
  *(remoteArr3) = 3;
  *(localArr) += 1;
  *(remoteArr1 + 1) = *(localArr);
  *(remoteArr2 + 1) = *(remoteArr1 + 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  movl   $0x1,0x2000000
  movl   $0x2,0x4000000
  movl   $0x3,0x6000000
  movl   $0x1,0x0
  movl   $0x1,0x2000004
  movl   $0x1,0x4000004
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  int *remoteArr2 = (int *)0x04000000;
  int *remoteArr3 = (int *)0x06000000;
  *(localArr) = 0;
  *(remoteArr1) = 1;
  *(remoteArr2) = 2;
  *(remoteArr3) = 3;
  *(localArr) += 1;
  *(remoteArr1 + 1) = *(localArr);
  *(remoteArr2 + 1) = *(remoteArr1 + 1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  int *remoteArr2 = (int *)0x04000000;
  int *remoteArr3 = (int *)0x06000000;
  *(localArr) = 0;
  *(remoteArr1) = 1;
  *(remoteArr2) = 2;
  *(remoteArr3) = 3;
  *(localArr) += 1;
  *(remoteArr1 + 1) = *(localArr);
  *(remoteArr2 + 1) = *(remoteArr1 + 1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  int *remoteArr2 = (int *)0x04000000;
  int *remoteArr3 = (int *)0x06000000;
  *(localArr) = 0;
  *(remoteArr1) = 1;
  *(remoteArr2) = 2;
  *(remoteArr3) = 3;
  *(localArr) += 1;
  *(remoteArr1 + 1) = *(localArr);
  *(remoteArr2 + 1) = *(remoteArr1 + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<DCSMReadZone2EXEONLY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4fffdc,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DCSMReadZone2EXEONLY(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFDC)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<DCSMReadZone2EXEONLY>:
  endbr64
  mov    0x4fffdc,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMReadZone2EXEONLY(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFDC)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<DCSMReadZone2EXEONLY>:
  endbr64
  mov    0x4fffdc,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMReadZone2EXEONLY(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFDC)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DCSMReadZone2EXEONLY>:
  endbr64
  mov    0x4fffdc,%rax
  mov    %rax,-0x8(%rsp)
  ret
```

assistant: ```c
void DCSMReadZone2EXEONLY(void) {
  volatile unsigned long temp;
  temp = (*((volatile unsigned long *)(0x00200000 + 0x002FFFDC)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x3,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int *restrict a, int *restrict b) {
  *a = 3;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int f(int *restrict a, int *restrict b) {
  *a = 3;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int f(int *restrict a, int *restrict b) {
  *a = 3;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int f(int *restrict a, int *restrict b) {
  *a = 3;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqroot>:
  endbr64
  pxor   %xmm3,%xmm3
  mov    $0x0,%edx
  ucomisd %xmm3,%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  jne    L109
  movsd  D89(%rip),%xmm4
  ucomisd %xmm4,%xmm0
  setnp  %dl
  cmove  %edx,%eax
  test   %al,%al
  jne    L109
  comisd %xmm3,%xmm0
  jb     L80
  comisd D19(%rip),%xmm0
  ja     L109
L33:
  comisd %xmm0,%xmm4
  movsd  D77(%rip),%xmm2
  movsd  D33(%rip),%xmm1
  movapd %xmm4,%xmm5
  jbe    L46
  nopl   0x0(%rax,%rax,1)
L126:
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm5
  comisd %xmm0,%xmm4
  ja     L126
L46:
  movapd %xmm3,%xmm7
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  movq   D32(%rip),%xmm10
  movsd  D37(%rip),%xmm9
  cmplesd %xmm0,%xmm7
  movsd  D73(%rip),%xmm8
  movsd  D3(%rip),%xmm11
  xorpd  %xmm10,%xmm2
  andpd  %xmm7,%xmm1
  andnpd %xmm2,%xmm7
  orpd   %xmm1,%xmm7
  movapd %xmm4,%xmm1
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L3:
  comisd %xmm4,%xmm0
  jbe    L62
L85:
  divsd  %xmm7,%xmm2
L62:
  comisd %xmm3,%xmm2
  jae    L4
  xorpd  %xmm10,%xmm2
L4:
  comisd %xmm8,%xmm2
  jb     L44
L23:
  movapd %xmm0,%xmm2
  comisd %xmm3,%xmm0
  divsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm9,%xmm1
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm6
  subsd  %xmm6,%xmm2
  jae    L3
  comisd %xmm0,%xmm11
  jbe    L62
  jmp    L85
  nopl   0x0(%rax)
L44:
  mulsd  %xmm5,%xmm1
  movapd %xmm1,%xmm0
L109:
  ret
  nopl   0x0(%rax)
L80:
  movsd  D62(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L33
  ret
```

tool_calls: name: read_data
arguments: data_label: D89
datatype: f64
name: read_data
arguments: data_label: D19
datatype: byte[16]
name: read_data
arguments: data_label: D77
datatype: byte[8]
name: read_data
arguments: data_label: D33
datatype: byte[8]
name: read_data
arguments: data_label: D32
datatype: byte[8]
name: read_data
arguments: data_label: D37
datatype: byte[8]
name: read_data
arguments: data_label: D73
datatype: byte[8]
name: read_data
arguments: data_label: D3
datatype: byte[8]
name: read_data
arguments: data_label: D62
datatype: byte[8]

tool: D89: 1

tool: {"D19": [0x76,0x3b,0x77,0x30,0xd1,0x42,0xee,0x7f,0x76,0x3b,0x77,0x30,0xd1,0x42,0xee,0xff]}

tool: {"D77": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D73": [0x3a,0x8c,0x30,0xe2,0x8e,0x79,0x45,0x3e]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D62": [0x76,0x3b,0x77,0x30,0xd1,0x42,0xee,0xff]}

assistant: ```c
double sqroot(double x) {
  if (x == 0 || x == 1 || (((x) >= 0 ? (x) : -(x)) > 1.7e+308))
    return x;
  double sqt = 1, accuracy = 1, tenp = 1;
  while (x < 1) {
    x *= 100;
    tenp /= 10;
  }
  while (accuracy >= 1.0e-8) {
    sqt = (sqt + x / sqt) / 2;
    accuracy = x - sqt * sqt;
    if (((x) >= 0 ? (x) : -(x)) > 1)
      accuracy /= ((x) >= 0 ? (x) : -(x));
    accuracy = ((accuracy) >= 0 ? (accuracy) : -(accuracy));
  }
  return sqt * tenp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<escape_cvs_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x22,%eax
  jne    L7
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L15
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  nop
L15:
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: ""

assistant: ```c
void escape_cvs_output(FILE *fp, char *s) {
  while (*s) {
    switch (*s) {
    case '"':
      fprintf(fp, "\"\"");
      break;
    default:
      fputc(*s, fp);
      break;
    }
    s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<escape_cvs_output>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L8
  mov    %rsi,%rbx
  lea    D2(%rip),%r12
  jmp    L28
L42:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
L20:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L8
L28:
  cmp    $0x22,%dil
  je     L42
  movsbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  jmp    L20
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: ""

assistant: ```c
void escape_cvs_output(FILE *fp, char *s) {
  while (*s) {
    switch (*s) {
    case '"':
      fprintf(fp, "\"\"");
      break;
    default:
      fputc(*s, fp);
      break;
    }
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<escape_cvs_output>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L44
  mov    %rsi,%rbx
  lea    D0(%rip),%r12
  jmp    L34
  nop
L41:
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L44
L34:
  cmp    $0x22,%dil
  jne    L41
  mov    %rbp,%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <fprintf@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L34
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: ""

assistant: ```c
void escape_cvs_output(FILE *fp, char *s) {
  while (*s) {
    switch (*s) {
    case '"':
      fprintf(fp, "\"\"");
      break;
    default:
      fputc(*s, fp);
      break;
    }
    s++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<escape_cvs_output>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rsi),%edi
  test   %dil,%dil
  je     L36
  mov    %rsi,%rbx
  lea    D8(%rip),%r12
  nopl   (%rax)
L39:
  cmp    $0x22,%dil
  je     L0
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L39
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <fprintf@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L39
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: ""

assistant: ```c
void escape_cvs_output(FILE *fp, char *s) {
  while (*s) {
    switch (*s) {
    case '"':
      fprintf(fp, "\"\"");
      break;
    default:
      fputc(*s, fp);
      break;
    }
    s++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L26
L17:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L23
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
L23:
  shrl   -0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x14(%rbp)
L26:
  cmpl   $0x0,-0x18(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int power(int a, unsigned int n, int p) {
  int res = 1;
  a = a % p;
  while (n > 0) {
    if (n & 1)
      res = (res * a) % p;
    n = n >> 1;
    a = (a * a) % p;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %edx,%ecx
  test   %esi,%esi
  je     L31
  mov    $0x1,%edi
  jmp    L3
L30:
  imul   %ecx,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%ecx
  shr    %esi
  je     L33
L3:
  test   $0x1,%sil
  je     L30
  mov    %edi,%eax
  imul   %ecx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%edi
  jmp    L30
L31:
  mov    $0x1,%edi
L33:
  mov    %edi,%eax
  ret
```

assistant: ```c
int power(int a, unsigned int n, int p) {
  int res = 1;
  a = a % p;
  while (n > 0) {
    if (n & 1)
      res = (res * a) % p;
    n = n >> 1;
    a = (a * a) % p;
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    $0x1,%r9d
  cltd
  idiv   %r8d
  mov    %edx,%ecx
  test   %esi,%esi
  je     L13
  nopl   0x0(%rax)
L28:
  test   $0x1,%sil
  je     L11
  mov    %r9d,%eax
  imul   %ecx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r9d
L11:
  imul   %ecx,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  shr    %esi
  mov    %edx,%ecx
  jne    L28
L13:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int power(int a, unsigned int n, int p) {
  int res = 1;
  a = a % p;
  while (n > 0) {
    if (n & 1)
      res = (res * a) % p;
    n = n >> 1;
    a = (a * a) % p;
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    $0x1,%r9d
  cltd
  idiv   %r8d
  mov    %edx,%ecx
  test   %esi,%esi
  je     L5
  nopl   0x0(%rax)
L18:
  test   $0x1,%sil
  je     L23
  mov    %r9d,%eax
  imul   %ecx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%r9d
L23:
  imul   %ecx,%ecx
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  shr    %esi
  mov    %edx,%ecx
  jne    L18
L5:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int power(int a, unsigned int n, int p) {
  int res = 1;
  a = a % p;
  while (n > 0) {
    if (n & 1)
      res = (res * a) % p;
    n = n >> 1;
    a = (a * a) % p;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply45>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L29
L36:
  movl   $0x0,-0x3c(%rbp)
  jmp    L22
L20:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L22:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L20
  addl   $0x1,-0x40(%rbp)
L29:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L36
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply45(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply45>:
  endbr64
  test   %edi,%edi
  jle    L26
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L22:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L8:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L8
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  ret
```

assistant: ```c
void multiply45(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply45>:
  endbr64
  test   %edi,%edi
  jle    L25
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L17
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L6
  pop    %rbx
  ret
L25:
  ret
```

assistant: ```c
void multiply45(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```