user: 下面的汇编指令对应的C源代码是什么:

```asm
<process_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  jmp    L53
L45:
  lea    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  lea    D27(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x4,%edx
  lea    D24(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L32
  mov    -0x10(%rbp),%rax
  mov    $0x5,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L44
L32:
  mov    -0x34(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L53
L44:
  mov    -0x48(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <add_parsed_line@plt>
  mov    -0x34(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x50(%rbp)
  je     L53
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,(%rax)
L53:
  mov    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L45
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D27
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string

tool: D27: 


tool: D24: Bulk

tool: D8: Error

assistant: ```c
void process_buffer(struct iptrie *result, char *buffer, int buflen, int *offset, struct amp_asn_info *info, int *outstanding) {
  char *line;
  char *lineptr = NULL;
  int linelen;
  while (strchr(buffer, '\n') != NULL) {
    line = strtok_r(buffer, "\n", &lineptr);
    linelen = strlen(line) + 1;
    if (strncmp(line, "Bulk", 4) == 0 || strncmp(line, "Error", 5) == 0) {
      memmove(buffer, buffer + linelen, buflen - linelen);
      *offset = *offset - linelen;
      buffer[*offset] = '\0';
      continue;
    }
    add_parsed_line(result, line, info);
    memmove(buffer, buffer + linelen, buflen - linelen);
    *offset = *offset - linelen;
    buffer[*offset] = '\0';
    if (outstanding) {
      (*outstanding)--;
    }
  }
}
```