ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x64,0x4(%rsp)
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%ebx
  lea    D20(%rip),%rbp
L22:
  mov    $0x0,%eax
  call   <_get_float@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L22
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%ebx
  lea    D17(%rip),%rbp
L10:
  lea    0x4(%rsp),%rdi
  call   <_get_int_random_number@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D17
type: string

tool: D18: float random

tool: D20: %f 


tool: D36: int random

tool: D17: %d 


assistant: ```c
int main() {
  int t;
  int max_int;
  max_int = 100;
  printf("float random\n");
  t = 1;
  while (t <= 10) {
    printf("%f \n", _get_float());
    t = t + 1;
  }
  printf("int random\n");
  t = 1;
  while (t <= 10) {
    printf("%d \n", _get_int_random_number(&max_int));
    t = t + 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x64,0x4(%rsp)
  call   <puts@plt>
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <_get_float@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  lea    D20(%rip),%rdi
  mov    $0xa,%ebx
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  lea    D37(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r12,%rdi
  call   <_get_int_random_number@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D37
type_infered: string

tool: D11: float random

tool: D5: %f 


tool: D20: int random

tool: D37: %d 


assistant: ```c
int main() {
  int t;
  int max_int;
  max_int = 100;
  printf("float random\n");
  t = 1;
  while (t <= 10) {
    printf("%f \n", _get_float());
    t = t + 1;
  }
  printf("int random\n");
  t = 1;
  while (t <= 10) {
    printf("%d \n", _get_int_random_number(&max_int));
    t = t + 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%rdi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x64,0x4(%rsp)
  call   <puts@plt>
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <_get_float@plt>
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  lea    D39(%rip),%rdi
  mov    $0xa,%ebx
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  lea    D18(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdi
  call   <_get_int_random_number@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D36
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D39
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string

tool: D36: float random

tool: D0: %f 


tool: D39: int random

tool: D18: %d 


assistant: ```c
int main() {
  int t;
  int max_int;
  max_int = 100;
  printf("float random\n");
  t = 1;
  while (t <= 10) {
    printf("%f \n", _get_float());
    t = t + 1;
  }
  printf("int random\n");
  t = 1;
  while (t <= 10) {
    printf("%d \n", _get_int_random_number(&max_int));
    t = t + 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<new_thread_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: New thread %%d stack at %x


assistant: ```c
void *new_thread_2(void *new_buf) {
  int i;
  sprintf((char *)new_buf, "New thread %%d stack at %x\n", &i);
  return (new_buf);
  PANIC();
}
```
user: Translate the below assembly code into C programming language:

```asm
<new_thread_2>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: New thread %%d stack at %x


assistant: ```c
void *new_thread_2(void *new_buf) {
  int i;
  sprintf((char *)new_buf, "New thread %%d stack at %x\n", &i);
  return (new_buf);
  PANIC();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<new_thread_2>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: New thread %%d stack at %x


assistant: ```c
void *new_thread_2(void *new_buf) {
  int i;
  sprintf((char *)new_buf, "New thread %%d stack at %x\n", &i);
  return (new_buf);
  PANIC();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<new_thread_2>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: New thread %%d stack at %x


assistant: ```c
void *new_thread_2(void *new_buf) {
  int i;
  sprintf((char *)new_buf, "New thread %%d stack at %x\n", &i);
  return (new_buf);
  PANIC();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x48(%rbp)
  movabs $0x76207a6576756f50,%rax
  movabs $0x6420656d2073756f,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x6c65757120657269,%rax
  movabs $0x20616c206520656c,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x2074636572726f63,%rax
  movabs $0x69746e6f6e6f7270,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x6f697461,-0x10(%rbp)
  movw   $0x3f6e,-0xc(%rbp)
  movb   $0x0,-0xa(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x41(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x41(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x48(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: 
%s


assistant: ```c
int main(void) {
  int ret = 0;
  char source[] = "Pouvez vous me dire quelle e la correct pronontiation?", dest[] = {};
  strcpy(dest, source);
  printf("\n%s\n", dest);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x76207a6576756f50,%rax
  movabs $0x6420656d2073756f,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x6c65757120657269,%rax
  movabs $0x20616c206520656c,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x2074636572726f63,%rax
  movabs $0x69746e6f6e6f7270,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movl   $0x6f697461,0x40(%rsp)
  movw   $0x3f6e,0x44(%rsp)
  movb   $0x0,0x46(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xf(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: 
%s


assistant: ```c
int main(void) {
  int ret = 0;
  char source[] = "Pouvez vous me dire quelle e la correct pronontiation?", dest[] = {};
  strcpy(dest, source);
  printf("\n%s\n", dest);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x50,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    $0x3f6e,%eax
  lea    0x10(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rbp,%rdi
  movl   $0x6f697461,0x40(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D36(%rip),%xmm0
  mov    %ax,0x44(%rsp)
  movb   $0x0,0x46(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
datatype: byte[16]
name: read_data
arguments: label: D26
datatype: byte[16]
name: read_data
arguments: label: D36
datatype: byte[16]
name: read_data
arguments: label: D5
datatype: string

tool: {"D18": [0x50,0x6f,0x75,0x76,0x65,0x7a,0x20,0x76,0x6f,0x75,0x73,0x20,0x6d,0x65,0x20,0x64]}

tool: {"D26": [0x69,0x72,0x65,0x20,0x71,0x75,0x65,0x6c,0x6c,0x65,0x20,0x65,0x20,0x6c,0x61,0x20]}

tool: {"D36": [0x63,0x6f,0x72,0x72,0x65,0x63,0x74,0x20,0x70,0x72,0x6f,0x6e,0x6f,0x6e,0x74,0x69]}

tool: D5: 
%s


assistant: ```c
int main(void) {
  int ret = 0;
  char source[] = "Pouvez vous me dire quelle e la correct pronontiation?", dest[] = {};
  strcpy(dest, source);
  printf("\n%s\n", dest);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x50,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rbp
  mov    $0x3f6e,%eax
  lea    0x10(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  movdqa D35(%rip),%xmm0
  mov    %rbp,%rdi
  movl   $0x6f697461,0x40(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D3(%rip),%xmm0
  mov    %ax,0x44(%rsp)
  movb   $0x0,0x46(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: byte[16]
name: read_data
arguments: data_tag: D35
type_infered: byte[16]
name: read_data
arguments: data_tag: D3
type_infered: byte[16]
name: read_data
arguments: data_tag: D37
type_infered: string

tool: {"D0": [0x50,0x6f,0x75,0x76,0x65,0x7a,0x20,0x76,0x6f,0x75,0x73,0x20,0x6d,0x65,0x20,0x64]}

tool: {"D35": [0x69,0x72,0x65,0x20,0x71,0x75,0x65,0x6c,0x6c,0x65,0x20,0x65,0x20,0x6c,0x61,0x20]}

tool: {"D3": [0x63,0x6f,0x72,0x72,0x65,0x63,0x74,0x20,0x70,0x72,0x6f,0x6e,0x6f,0x6e,0x74,0x69]}

tool: D37: 
%s


assistant: ```c
int main(void) {
  int ret = 0;
  char source[] = "Pouvez vous me dire quelle e la correct pronontiation?", dest[] = {};
  strcpy(dest, source);
  printf("\n%s\n", dest);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<piLeibniz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  movsd  D18(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  negl   -0x18(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movsd  -0x10(%rbp),%xmm1
  movsd  D17(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: f64
name: unpack_data
arguments: tag: D8
type_infered: f64
name: unpack_data
arguments: tag: D17
type_infered: f32[2]

tool: D18: 1

tool: D8: 2

tool: {"D17": [0.0,2.25]}

assistant: ```c
double piLeibniz(int n) {
  double sum = 0;
  int sign = 1;
  double denom = 1.;
  for (int i = 0; i < n; i++) {
    sum += sign / denom;
    sign *= -1;
    denom += 2.;
  }
  return 4 * sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<piLeibniz>:
  endbr64
  test   %edi,%edi
  jle    L27
  mov    $0x0,%edx
  movsd  D21(%rip),%xmm2
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  movsd  D15(%rip),%xmm3
L26:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  neg    %eax
  addsd  %xmm3,%xmm2
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L26
L2:
  mulsd  D29(%rip),%xmm0
  ret
L27:
  pxor   %xmm0,%xmm0
  jmp    L2
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: f64
name: parse_data
arguments: tag: D15
type_infered: f64
name: parse_data
arguments: tag: D29
type_infered: f32[2]

tool: D21: 1

tool: D15: 2

tool: {"D29": [0.0,2.25]}

assistant: ```c
double piLeibniz(int n) {
  double sum = 0;
  int sign = 1;
  double denom = 1.;
  for (int i = 0; i < n; i++) {
    sum += sign / denom;
    sign *= -1;
    denom += 2.;
  }
  return 4 * sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<piLeibniz>:
  endbr64
  test   %edi,%edi
  jle    L0
  movsd  D27(%rip),%xmm2
  xor    %edx,%edx
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  movsd  D2(%rip),%xmm3
  nopl   0x0(%rax,%rax,1)
L3:
  pxor   %xmm1,%xmm1
  add    $0x1,%edx
  cvtsi2sd %eax,%xmm1
  neg    %eax
  divsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm2
  addsd  %xmm1,%xmm0
  cmp    %edx,%edi
  jne    L3
  mulsd  D12(%rip),%xmm0
  ret
  xchg   %ax,%ax
L0:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type: f64
name: parse_data
arguments: data_label: D2
type: f64
name: parse_data
arguments: data_label: D12
type: f32[2]

tool: D27: 1

tool: D2: 2

tool: {"D12": [0.0,2.25]}

assistant: ```c
double piLeibniz(int n) {
  double sum = 0;
  int sign = 1;
  double denom = 1.;
  for (int i = 0; i < n; i++) {
    sum += sign / denom;
    sign *= -1;
    denom += 2.;
  }
  return 4 * sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<piLeibniz>:
  endbr64
  test   %edi,%edi
  jle    L6
  movsd  D21(%rip),%xmm2
  xor    %edx,%edx
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  movsd  D7(%rip),%xmm3
  nopl   0x0(%rax,%rax,1)
L14:
  pxor   %xmm1,%xmm1
  add    $0x1,%edx
  cvtsi2sd %eax,%xmm1
  neg    %eax
  divsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm2
  addsd  %xmm1,%xmm0
  cmp    %edx,%edi
  jne    L14
  mulsd  D26(%rip),%xmm0
  ret
  xchg   %ax,%ax
L6:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type: f64
name: disassemble_data
arguments: data_label: D7
type: f64
name: disassemble_data
arguments: data_label: D26
type: f32[2]

tool: D21: 1

tool: D7: 2

tool: {"D26": [0.0,2.25]}

assistant: ```c
double piLeibniz(int n) {
  double sum = 0;
  int sign = 1;
  double denom = 1.;
  for (int i = 0; i < n; i++) {
    sum += sign / denom;
    sign *= -1;
    denom += 2.;
  }
  return 4 * sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<testArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D101(%rip),%xmm0
  movsd  %xmm0,-0x70(%rbp)
  movsd  D39(%rip),%xmm0
  movsd  %xmm0,-0x68(%rbp)
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  D92(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D115(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D41(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D101(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D39(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L34
L0:
  movl   $0x0,-0x74(%rbp)
  jmp    L42
L44:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x70(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x74(%rbp)
L42:
  cmpl   $0x3,-0x74(%rbp)
  jle    L44
  addl   $0x1,-0x78(%rbp)
L34:
  cmpl   $0x2,-0x78(%rbp)
  jle    L0
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D101
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D39
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D15
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D0
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D92
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D5
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D115
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D41
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D19
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D20
type_infered: string

tool: {"D101": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D92": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D115": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: D20: num = %.2f


assistant: ```c
testArray() {
  double array[3][4] = {{1, 2, 3, 4}, {5, 6, 7, 8}, {9, 0, 1, 2}};
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 4; j++) {
      printf("num = %.2f\n", array[i][j]);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movsd  D6(%rip),%xmm1
  movsd  %xmm1,(%rsp)
  movsd  D90(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    D17(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D16(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D27(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D55(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D18(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D89(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D86(%rip),%rax
  mov    %rax,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movsd  %xmm1,0x50(%rsp)
  movsd  %xmm0,0x58(%rsp)
  lea    0x20(%rsp),%rbp
  lea    0x80(%rsp),%r13
  lea    D45(%rip),%r12
L8:
  lea    -0x20(%rbp),%rbx
L20:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L20
  add    $0x20,%rbp
  cmp    %r13,%rbp
  jne    L8
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: byte[8]
name: unpack_data
arguments: tag: D90
type_infered: byte[8]
name: unpack_data
arguments: tag: D17
type_infered: byte[8]
name: unpack_data
arguments: tag: D16
type_infered: byte[8]
name: unpack_data
arguments: tag: D27
type_infered: byte[8]
name: unpack_data
arguments: tag: D55
type_infered: byte[8]
name: unpack_data
arguments: tag: D18
type_infered: byte[8]
name: unpack_data
arguments: tag: D89
type_infered: byte[8]
name: unpack_data
arguments: tag: D86
type_infered: byte[8]
name: unpack_data
arguments: tag: D45
type_infered: string

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D90": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D55": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D86": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: D45: num = %.2f


assistant: ```c
testArray() {
  double array[3][4] = {{1, 2, 3, 4}, {5, 6, 7, 8}, {9, 0, 1, 2}};
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 4; j++) {
      printf("num = %.2f\n", array[i][j]);
    }
  }
}
```