ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strfin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    $0x0,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %ebx,%edx
  jb     L9
  mov    %ebx,%ebx
  mov    %rbp,%rax
  sub    %rbx,%rax
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  sub    %rbx,%rbp
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %rbp,%rax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const char *strfin(const char *s, const char *suffix) {
  char *p = strchr(s, '\0');
  unsigned int l = strlen(suffix);
  if (l > strlen(s))
    return NULL;
  p -= l;
  return strcmp(p, suffix) ? NULL : p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strfin>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jb     L16
  sub    %rbx,%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L16
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const char *strfin(const char *s, const char *suffix) {
  char *p = strchr(s, '\0');
  unsigned int l = strlen(suffix);
  if (l > strlen(s))
    return NULL;
  p -= l;
  return strcmp(p, suffix) ? NULL : p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strfin>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jb     L15
  sub    %rbx,%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L15
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L15:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
const char *strfin(const char *s, const char *suffix) {
  char *p = strchr(s, '\0');
  unsigned int l = strlen(suffix);
  if (l > strlen(s))
    return NULL;
  p -= l;
  return strcmp(p, suffix) ? NULL : p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parent_base_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dir_name@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L3
L10:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <base_name@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *parent_base_name(const char *path) {
  char *dir;
  char *parent_base;
  dir = dir_name(path);
  if (!dir)
    return NULL;
  parent_base = base_name(dir);
  free(dir);
  return parent_base;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parent_base_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <dir_name@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <base_name@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rax,%rbp
  jmp    L13
```

assistant: ```c
char *parent_base_name(const char *path) {
  char *dir;
  char *parent_base;
  dir = dir_name(path);
  if (!dir)
    return NULL;
  parent_base = base_name(dir);
  free(dir);
  return parent_base;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parent_base_name>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <dir_name@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <base_name@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *parent_base_name(const char *path) {
  char *dir;
  char *parent_base;
  dir = dir_name(path);
  if (!dir)
    return NULL;
  parent_base = base_name(dir);
  free(dir);
  return parent_base;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parent_base_name>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <dir_name@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <base_name@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *parent_base_name(const char *path) {
  char *dir;
  char *parent_base;
  dir = dir_name(path);
  if (!dir)
    return NULL;
  parent_base = base_name(dir);
  free(dir);
  return parent_base;
}
```
user: Translate the below assembly code into C programming language:

```asm
<createPrefixSumTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x14(%rbp)
  jmp    L47
L49:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L40
L38:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x15(%rbp)
  jle    L0
  addl   $0x1,-0xc(%rbp)
L0:
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L38
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L47:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L49
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *createPrefixSumTable(const char input[], int lengthOfInput, int duzinaAbecede, char abeceda[]) {
  int *C = (int *)malloc(duzinaAbecede * sizeof(int));
  char znak;
  int i = 0, j = 0, sum = 0;
  C[0] = 0;
  for (i = 1; i < duzinaAbecede; i++) {
    znak = abeceda[i];
    sum = 0;
    for (j = 0; j < lengthOfInput; j++) {
      if (input[j] < znak)
        sum++;
    }
    C[i] = sum;
  }
  return C;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<createPrefixSumTable>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %rcx,%r12
  lea    0x0(,%rdx,4),%edi
  call   <malloc@plt>
  movl   $0x0,(%rax)
  cmp    $0x1,%r13d
  jle    L37
  lea    0x1(%r12),%r10
  lea    0x4(%rax),%r9
  lea    -0x2(%r13),%edx
  lea    0x8(%rax,%rdx,4),%r11
  lea    -0x1(%rbx),%edx
  lea    0x1(%rbp,%rdx,1),%r8
L3:
  movzbl (%r10),%edi
  test   %ebx,%ebx
  jle    L47
  mov    %rbp,%rdx
  mov    $0x0,%ecx
L27:
  cmp    %dil,(%rdx)
  setl   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L27
L23:
  mov    %ecx,(%r9)
  add    $0x1,%r10
  add    $0x4,%r9
  cmp    %r11,%r9
  jne    L3
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  mov    $0x0,%ecx
  jmp    L23
```

assistant: ```c
int *createPrefixSumTable(const char input[], int lengthOfInput, int duzinaAbecede, char abeceda[]) {
  int *C = (int *)malloc(duzinaAbecede * sizeof(int));
  char znak;
  int i = 0, j = 0, sum = 0;
  C[0] = 0;
  for (i = 1; i < duzinaAbecede; i++) {
    znak = abeceda[i];
    sum = 0;
    for (j = 0; j < lengthOfInput; j++) {
      if (input[j] < znak)
        sum++;
    }
    C[i] = sum;
  }
  return C;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<createPrefixSumTable>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  lea    0x0(,%rdx,4),%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movl   $0x0,(%rax)
  cmp    $0x1,%r13d
  jle    L11
  lea    -0x2(%r13),%edx
  lea    0x1(%rbx),%r10
  lea    0x8(%rax,%rdx,4),%r11
  lea    -0x1(%rbp),%edx
  lea    0x4(%rax),%r9
  lea    0x1(%r12,%rdx,1),%r8
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl (%r10),%edi
  test   %ebp,%ebp
  jle    L13
  mov    %r12,%rdx
  xor    %ecx,%ecx
  nopl   (%rax)
L12:
  xor    %esi,%esi
  cmp    %dil,(%rdx)
  setl   %sil
  add    $0x1,%rdx
  add    %esi,%ecx
  cmp    %r8,%rdx
  jne    L12
  mov    %ecx,(%r9)
  add    $0x4,%r9
  add    $0x1,%r10
  cmp    %r11,%r9
  jne    L35
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  xor    %ecx,%ecx
  add    $0x4,%r9
  add    $0x1,%r10
  mov    %ecx,-0x4(%r9)
  cmp    %r11,%r9
  jne    L35
  jmp    L11
```

assistant: ```c
int *createPrefixSumTable(const char input[], int lengthOfInput, int duzinaAbecede, char abeceda[]) {
  int *C = (int *)malloc(duzinaAbecede * sizeof(int));
  char znak;
  int i = 0, j = 0, sum = 0;
  C[0] = 0;
  for (i = 1; i < duzinaAbecede; i++) {
    znak = abeceda[i];
    sum = 0;
    for (j = 0; j < lengthOfInput; j++) {
      if (input[j] < znak)
        sum++;
    }
    C[i] = sum;
  }
  return C;
}
```
user: Translate the below assembly code into C programming language:

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x18(%rbp),%rdx
  add    %rsi,%rdx
  imul   %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void square(int *arr, int size) {
  int i;
  for (i = 0; i < size; ++i)
    arr[i] = arr[i] * arr[i];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<square>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
L9:
  mov    (%rax),%edx
  imul   %edx,%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
L15:
  ret
```

assistant: ```c
void square(int *arr, int size) {
  int i;
  for (i = 0; i < size; ++i)
    arr[i] = arr[i] * arr[i];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<square>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
L16:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  imul   %eax,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jne    L16
L10:
  ret
```

assistant: ```c
void square(int *arr, int size) {
  int i;
  for (i = 0; i < size; ++i)
    arr[i] = arr[i] * arr[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<square>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edx
  test   %esi,%esi
  jle    L67
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L29
  shr    $0x2,%esi
  mov    %rdi,%rax
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nop
L12:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pmuludq %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L12
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L13
L65:
  movslq %eax,%rsi
  shl    $0x2,%rsi
  lea    (%rcx,%rsi,1),%r8
  mov    (%r8),%edi
  imul   %edi,%edi
  mov    %edi,(%r8)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L67
  lea    0x4(%rcx,%rsi,1),%r8
  add    $0x2,%eax
  mov    (%r8),%edi
  imul   %edi,%edi
  mov    %edi,(%r8)
  cmp    %eax,%edx
  jle    L67
  lea    0x8(%rcx,%rsi,1),%rdx
  mov    (%rdx),%eax
  imul   %eax,%eax
  mov    %eax,(%rdx)
L67:
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  ret
L29:
  xor    %eax,%eax
  jmp    L65
```

assistant: ```c
void square(int *arr, int size) {
  int i;
  for (i = 0; i < size; ++i)
    arr[i] = arr[i] * arr[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xbb8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  mov    $0xbb8,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  mov    $0xbb8,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  mov    $0xbb8,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lib_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
void lib_error(int code, char *s) {
  FILE *f;
  printf("%s\n", s);
  exit(code);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lib_error>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: %s


assistant: ```c
void lib_error(int code, char *s) {
  FILE *f;
  printf("%s\n", s);
  exit(code);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lib_error>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: %s


assistant: ```c
void lib_error(int code, char *s) {
  FILE *f;
  printf("%s\n", s);
  exit(code);
}
```
user: What is the c source code of the assembly code below?

```asm
<lib_error>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: %s


assistant: ```c
void lib_error(int code, char *s) {
  FILE *f;
  printf("%s\n", s);
  exit(code);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_single_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L22:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L62
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L79
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L1
L79:
  addl   $0x1,-0x4(%rbp)
L1:
  addl   $0x1,-0x8(%rbp)
L62:
  cmpl   $0x9,-0x8(%rbp)
  jle    L17
  cmpl   $0x1,-0x4(%rbp)
  je     L57
  addl   $0x1,-0xc(%rbp)
L47:
  cmpl   $0x5,-0xc(%rbp)
  jle    L22
  jmp    L19
L57:
  nop
L19:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_single_row(float A[6][10 + 1]) {
  int i, j, count;
  for (i = 0; i < 6; i++) {
    count = 0;
    for (j = 0; j < 10; j++)
      if (A[i][j] != 0)
        count++;
    if (count == 1)
      break;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_single_row>:
  endbr64
  add    $0x28,%rdi
  mov    $0x0,%ecx
  pxor   %xmm0,%xmm0
  movaps %xmm0,%xmm1
  jmp    L41
L56:
  add    $0x1,%edx
L0:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L77
L7:
  ucomiss (%rax),%xmm0
  jp     L56
  ucomiss (%rax),%xmm1
  je     L0
  jmp    L56
L77:
  cmp    $0x1,%edx
  je     L26
  add    $0x1,%ecx
  add    $0x2c,%rdi
  cmp    $0x6,%ecx
  je     L26
L41:
  lea    -0x28(%rdi),%rax
  mov    $0x0,%edx
  jmp    L7
L26:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int find_single_row(float A[6][10 + 1]) {
  int i, j, count;
  for (i = 0; i < 6; i++) {
    count = 0;
    for (j = 0; j < 10; j++)
      if (A[i][j] != 0)
        count++;
    if (count == 1)
      break;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_single_row>:
  endbr64
  add    $0x28,%rdi
  xor    %r8d,%r8d
  pxor   %xmm0,%xmm0
L36:
  lea    -0x28(%rdi),%rax
  xor    %edx,%edx
  nopl   (%rax)
L40:
  ucomiss (%rax),%xmm0
  jp     L3
  je     L8
L3:
  add    $0x1,%edx
L8:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L40
  cmp    $0x1,%edx
  je     L6
  add    $0x1,%r8d
  add    $0x2c,%rdi
  cmp    $0x6,%r8d
  jne    L36
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_single_row(float A[6][10 + 1]) {
  int i, j, count;
  for (i = 0; i < 6; i++) {
    count = 0;
    for (j = 0; j < 10; j++)
      if (A[i][j] != 0)
        count++;
    if (count == 1)
      break;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_single_row>:
  endbr64
  xor    %r8d,%r8d
  pxor   %xmm0,%xmm0
  mov    $0x1,%edx
L144:
  xor    %eax,%eax
  ucomiss (%rdi),%xmm0
  setp   %al
  cmovne %edx,%eax
  ucomiss 0x4(%rdi),%xmm0
  jp     L125
  je     L137
L125:
  add    $0x1,%eax
L137:
  ucomiss 0x8(%rdi),%xmm0
  jp     L167
  je     L15
L167:
  add    $0x1,%eax
L15:
  ucomiss 0xc(%rdi),%xmm0
  jp     L103
  je     L90
L103:
  add    $0x1,%eax
L90:
  ucomiss 0x10(%rdi),%xmm0
  jp     L111
  je     L170
L111:
  add    $0x1,%eax
L170:
  ucomiss 0x14(%rdi),%xmm0
  jp     L9
  je     L68
L9:
  add    $0x1,%eax
L68:
  ucomiss 0x18(%rdi),%xmm0
  jp     L156
  je     L186
L156:
  add    $0x1,%eax
L186:
  ucomiss 0x1c(%rdi),%xmm0
  jp     L19
  je     L28
L19:
  add    $0x1,%eax
L28:
  ucomiss 0x20(%rdi),%xmm0
  jp     L18
  je     L4
L18:
  add    $0x1,%eax
L4:
  ucomiss 0x24(%rdi),%xmm0
  jp     L172
  je     L162
L172:
  add    $0x1,%eax
L162:
  cmp    $0x1,%eax
  je     L79
  add    $0x1,%r8d
  add    $0x2c,%rdi
  cmp    $0x6,%r8d
  jne    L144
L79:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_single_row(float A[6][10 + 1]) {
  int i, j, count;
  for (i = 0; i < 6; i++) {
    count = 0;
    for (j = 0; j < 10; j++)
      if (A[i][j] != 0)
        count++;
    if (count == 1)
      break;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: 
 %d

assistant: ```c
main() {
  int yas;
  yas = 10;
  printf("\n %d", yas);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: 
 %d

assistant: ```c
main() {
  int yas;
  yas = 10;
  printf("\n %d", yas);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: 
 %d

assistant: ```c
main() {
  int yas;
  yas = 10;
  printf("\n %d", yas);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: 
 %d

assistant: ```c
main() {
  int yas;
  yas = 10;
  printf("\n %d", yas);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L3
L32:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <hex@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L33
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x4,%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  jmp    L18
L33:
  nop
L18:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue >= 0) {
      *intValue = (*intValue << 4) | hexValue;
      numChars++;
    } else
      break;
    (*ptr)++;
  }
  return (numChars);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hexToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  mov    (%rdi),%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L15
  mov    %rsi,%rbp
  mov    $0x0,%r12d
L36:
  movsbl %dil,%edi
  call   <hex@plt>
  mov    %eax,%edx
  test   %eax,%eax
  js     L14
  mov    0x0(%rbp),%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x1,%r12d
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L36
L14:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0x0,%r12d
  jmp    L14
```

assistant: ```c
int hexToInt(char **ptr, int *intValue) {
  int numChars = 0;
  int hexValue;
  *intValue = 0;
  while (**ptr) {
    hexValue = hex(**ptr);
    if (hexValue >= 0) {
      *intValue = (*intValue << 4) | hexValue;
      numChars++;
    } else
      break;
    (*ptr)++;
  }
  return (numChars);
}
```