ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i_hyperloglogGetAlpha>:
  endbr64
  cmp    $0x20,%edi
  je     L4
  movsd  D44(%rip),%xmm0
  cmp    $0x40,%edi
  je     L10
  movsd  D29(%rip),%xmm0
  cmp    $0x10,%edi
  je     L10
  mov    %edi,%edi
  pxor   %xmm0,%xmm0
  movsd  D12(%rip),%xmm1
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D3(%rip),%xmm0
  addsd  D33(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movsd  D2(%rip),%xmm0
L10:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D44
type_infered: byte[8]
name: retrieve_data
arguments: label: D29
type_infered: byte[8]
name: retrieve_data
arguments: label: D12
type_infered: f64
name: retrieve_data
arguments: label: D3
type_infered: f64
name: retrieve_data
arguments: label: D33
type_infered: f64
name: retrieve_data
arguments: label: D2
type_infered: byte[8]

tool: {"D44": [0x00,0x00,0x00,0xc0,0x20,0xb0,0xe6,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0x40,0x37,0x89,0xe5,0x3f]}

tool: D12: 1.079

tool: D3: 0.7213

tool: D33: 1

tool: {"D2": [0x00,0x00,0x00,0x00,0xd3,0x4d,0xe6,0x3f]}

assistant: ```c
double i_hyperloglogGetAlpha(unsigned int k) {
  switch (k) {
  case 16:
    return 0.673f;
  case 32:
    return 0.697f;
  case 64:
    return 0.709f;
  }
  return 0.7213 / (1.0 + 1.079 / (float)k);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i_hyperloglogGetAlpha>:
  endbr64
  cmp    $0x20,%edi
  je     L3
  movsd  D46(%rip),%xmm0
  cmp    $0x40,%edi
  je     L11
  movsd  D40(%rip),%xmm0
  cmp    $0x10,%edi
  je     L11
  mov    %edi,%edi
  pxor   %xmm0,%xmm0
  movsd  D6(%rip),%xmm1
  cvtsi2ss %rdi,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D24(%rip),%xmm0
  addsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movsd  D57(%rip),%xmm0
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D46
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D40
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
data_type: f64
name: extract_symbolic_data
arguments: data_label: D24
data_type: f64
name: extract_symbolic_data
arguments: data_label: D9
data_type: f64
name: extract_symbolic_data
arguments: data_label: D57
data_type: byte[8]

tool: {"D46": [0x00,0x00,0x00,0xc0,0x20,0xb0,0xe6,0x3f]}

tool: {"D40": [0x00,0x00,0x00,0x40,0x37,0x89,0xe5,0x3f]}

tool: D6: 1.079

tool: D24: 0.7213

tool: D9: 1

tool: {"D57": [0x00,0x00,0x00,0x00,0xd3,0x4d,0xe6,0x3f]}

assistant: ```c
double i_hyperloglogGetAlpha(unsigned int k) {
  switch (k) {
  case 16:
    return 0.673f;
  case 32:
    return 0.697f;
  case 64:
    return 0.709f;
  }
  return 0.7213 / (1.0 + 1.079 / (float)k);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_return_next>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *copy_return_next(void *dst, void *src, unsigned int src_len) {
  memcpy(dst, src, src_len);
  dst = (char *)dst + src_len;
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_return_next>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  call   <memcpy@plt>
  mov    %ebp,%ebp
  lea    (%rbx,%rbp,1),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *copy_return_next(void *dst, void *src, unsigned int src_len) {
  memcpy(dst, src, src_len);
  dst = (char *)dst + src_len;
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_return_next>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *copy_return_next(void *dst, void *src, unsigned int src_len) {
  memcpy(dst, src, src_len);
  dst = (char *)dst + src_len;
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_return_next>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *copy_return_next(void *dst, void *src, unsigned int src_len) {
  memcpy(dst, src, src_len);
  dst = (char *)dst + src_len;
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x520,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x514(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x510(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    $0x3c,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    -0x330(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    $0x64,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    -0x514(%rbp),%eax
  cmp    $0xa,%eax
  jle    L21
  mov    -0x514(%rbp),%eax
  cmp    $0x3b,%eax
  jg     L21
  mov    -0x514(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    -0x510(%rbp),%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x514(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    -0x330(%rbp),%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  add    %rcx,%rax
  mov    %rsi,%rdx
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
data_type: string
name: unpack_data
arguments: data_label: D33
data_type: string
name: unpack_data
arguments: data_label: D31
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string

tool: D23: %d

tool: 

tool: 

tool: D11: %s, %s.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  char readablility[][80] = {
      "", "unreadable", "barely readable, occasional words distinguishable", "readable with considerable difficulty", "readable with practically no difficulty", "perfectly readable",
  };
  char strength[][80] = {
      "", "Faint signals, barely perceptible", "Very weak signals", "Weak signals", "Fair signals", "Fairly good signals", "Good signals", "Moderately strong signals", "Strong signals", "Extremely strong signals",
  };
  if (num > 10 && num < 60) {
    printf("%s, %s.", strength[num % 10], readablility[num / 10]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x528,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x518(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  lea    D20(%rip),%rsi
  mov    $0x3c,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    0x1f0(%rsp),%rdi
  lea    D31(%rip),%rsi
  mov    $0x64,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    0xc(%rsp),%eax
  lea    -0xb(%rax),%edx
  cmp    $0x30,%edx
  jbe    L1
L20:
  mov    0x518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x528,%rsp
  ret
L1:
  mov    $0xa,%ecx
  cltd
  idiv   %ecx
  cltq
  imul   $0x50,%rax,%rax
  lea    0x10(%rsp,%rax,1),%rax
  movslq %edx,%rdx
  imul   $0x50,%rdx,%rdx
  lea    0x1f0(%rsp,%rdx,1),%rsi
  mov    %rax,%rdx
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
data_type: string
name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D29
data_type: string

tool: D33: %d

tool: 

tool: 

tool: D29: %s, %s.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  char readablility[][80] = {
      "", "unreadable", "barely readable, occasional words distinguishable", "readable with considerable difficulty", "readable with practically no difficulty", "perfectly readable",
  };
  char strength[][80] = {
      "", "Faint signals, barely perceptible", "Very weak signals", "Weak signals", "Fair signals", "Fairly good signals", "Good signals", "Moderately strong signals", "Strong signals", "Extremely strong signals",
  };
  if (num > 10 && num < 60) {
    printf("%s, %s.", strength[num % 10], readablility[num / 10]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x528,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x518(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x10(%rsp),%r9
  lea    0x1f0(%rsp),%r8
  lea    D39(%rip),%rsi
  mov    $0x3c,%ecx
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    -0xb(%rax),%edx
  lea    D14(%rip),%rsi
  mov    %r8,%rdi
  mov    $0x64,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  cmp    $0x30,%edx
  jbe    L21
L2:
  mov    0x518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x528,%rsp
  ret
L21:
  mov    $0xa,%ecx
  cltd
  lea    D36(%rip),%rdi
  idiv   %ecx
  cltq
  movslq %edx,%rdx
  imul   $0x50,%rax,%rax
  imul   $0x50,%rdx,%rdx
  add    %rax,%r9
  xor    %eax,%eax
  lea    (%r8,%rdx,1),%rsi
  mov    %r9,%rdx
  call   <printf@plt>
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D33
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D36
type_guessed: string

tool: D33: %d

tool: 

tool: 

tool: D36: %s, %s.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  char readablility[][80] = {
      "", "unreadable", "barely readable, occasional words distinguishable", "readable with considerable difficulty", "readable with practically no difficulty", "perfectly readable",
  };
  char strength[][80] = {
      "", "Faint signals, barely perceptible", "Very weak signals", "Weak signals", "Fair signals", "Fairly good signals", "Good signals", "Moderately strong signals", "Strong signals", "Extremely strong signals",
  };
  if (num > 10 && num < 60) {
    printf("%s, %s.", strength[num % 10], readablility[num / 10]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x528,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x518(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x10(%rsp),%r9
  lea    0x1f0(%rsp),%r8
  lea    D1(%rip),%rsi
  mov    $0x3c,%ecx
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    -0xb(%rax),%edx
  lea    D30(%rip),%rsi
  mov    %r8,%rdi
  mov    $0x64,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  cmp    $0x30,%edx
  jbe    L24
L12:
  mov    0x518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x528,%rsp
  ret
L24:
  mov    $0xa,%ecx
  cltd
  lea    D16(%rip),%rdi
  idiv   %ecx
  cltq
  movslq %edx,%rdx
  imul   $0x50,%rax,%rax
  imul   $0x50,%rdx,%rdx
  add    %rax,%r9
  xor    %eax,%eax
  lea    (%r8,%rdx,1),%rsi
  mov    %r9,%rdx
  call   <printf@plt>
  jmp    L12
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D30
type: string
name: disassemble_data
arguments: data_label: D16
type: string

tool: D23: %d

tool: 

tool: 

tool: D16: %s, %s.

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  char readablility[][80] = {
      "", "unreadable", "barely readable, occasional words distinguishable", "readable with considerable difficulty", "readable with practically no difficulty", "perfectly readable",
  };
  char strength[][80] = {
      "", "Faint signals, barely perceptible", "Very weak signals", "Weak signals", "Fair signals", "Fairly good signals", "Good signals", "Moderately strong signals", "Strong signals", "Extremely strong signals",
  };
  if (num > 10 && num < 60) {
    printf("%s, %s.", strength[num % 10], readablility[num / 10]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <c@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D68
type_infered: string
name: retrieve_data
arguments: tag: D42
type_infered: string
name: retrieve_data
arguments: tag: D55
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D78
type_infered: string

tool: D68: b

tool: D42: [%s]:Begin!


tool: D55: [%s]:Call c()!


tool: D2: [%s]:c() returned!


tool: D78: [%s]:End!


assistant: ```c
void b(void) {
  printf("[%s]:Begin!\n", __FUNCTION__);
  printf("[%s]:Call c()!\n", __FUNCTION__);
  c();
  printf("[%s]:c() returned!\n", __FUNCTION__);
  printf("[%s]:End!\n", __FUNCTION__);
}
```
user: What is the c source code of the assembly code below:

```asm
<b>:
  endbr64
  push   %rbx
  lea    D41(%rip),%rbx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <c@plt>
  mov    %rbx,%rsi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D41
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D46
type: string
name: disassemble_data
arguments: data_tag: D31
type: string
name: disassemble_data
arguments: data_tag: D0
type: string

tool: D41: b

tool: D12: [%s]:Begin!


tool: D46: [%s]:Call c()!


tool: D31: [%s]:c() returned!


tool: D0: [%s]:End!


assistant: ```c
void b(void) {
  printf("[%s]:Begin!\n", __FUNCTION__);
  printf("[%s]:Call c()!\n", __FUNCTION__);
  c();
  printf("[%s]:c() returned!\n", __FUNCTION__);
  printf("[%s]:End!\n", __FUNCTION__);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<b>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rbp
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <c@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string

tool: D25: b

tool: D11: [%s]:Begin!


tool: D27: [%s]:Call c()!


tool: D3: [%s]:c() returned!


tool: D30: [%s]:End!


assistant: ```c
void b(void) {
  printf("[%s]:Begin!\n", __FUNCTION__);
  printf("[%s]:Call c()!\n", __FUNCTION__);
  c();
  printf("[%s]:c() returned!\n", __FUNCTION__);
  printf("[%s]:End!\n", __FUNCTION__);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<b>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <c@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D31
datatype: string
name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D45
datatype: string

tool: D18: b

tool: D3: [%s]:Begin!


tool: D31: [%s]:Call c()!


tool: D0: [%s]:c() returned!


tool: D45: [%s]:End!


assistant: ```c
void b(void) {
  printf("[%s]:Begin!\n", __FUNCTION__);
  printf("[%s]:Call c()!\n", __FUNCTION__);
  c();
  printf("[%s]:c() returned!\n", __FUNCTION__);
  printf("[%s]:End!\n", __FUNCTION__);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Idexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <ldexp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D21
type: string
name: read_data
arguments: label: D36
type: string
name: read_data
arguments: label: D45
type: string
name: read_data
arguments: label: D18
type: string

tool: D7: Enter a number: 

tool: D21: %lf

tool: D36: Enter pow:

tool: D45: %d

tool: D18: %f * 2^%d = %f


assistant: ```c
double Idexp(double x, double ret) {
  int n;
  printf(gettext("Enter a number: "));
  scanf("%lf", &x);
  printf(gettext("Enter pow:"));
  scanf("%d", &n);
  ret = ldexp(x, n);
  printf("%f * 2^%d = %f\n", x, n, ret);
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Idexp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D38(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%r12d
  mov    0x8(%rsp),%rbp
  mov    %r12d,%edi
  movq   %rbp,%xmm0
  call   <ldexp@plt>
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm1
  mov    %r12d,%esi
  movq   %rbp,%xmm0
  lea    D17(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  movq   %rbx,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D42
datatype: string
name: disassemble_data
arguments: data_label: D45
datatype: string
name: disassemble_data
arguments: data_label: D38
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D42: Enter a number: 

tool: D45: %lf

tool: D38: Enter pow:

tool: D1: %d

tool: D17: %f * 2^%d = %f


assistant: ```c
double Idexp(double x, double ret) {
  int n;
  printf(gettext("Enter a number: "));
  scanf("%lf", &x);
  printf(gettext("Enter pow:"));
  scanf("%d", &n);
  ret = ldexp(x, n);
  printf("%f * 2^%d = %f\n", x, n, ret);
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Idexp>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <gettext@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <gettext@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x24(%rsp),%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x18(%rsp),%xmm2
  mov    0x24(%rsp),%ebp
  movapd %xmm2,%xmm0
  mov    %ebp,%edi
  movsd  %xmm2,0x10(%rsp)
  call   <ldexp@plt>
  movsd  0x10(%rsp),%xmm2
  mov    %ebp,%esi
  lea    D21(%rip),%rdi
  movapd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  mov    $0x2,%eax
  movapd %xmm2,%xmm0
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  movapd %xmm1,%xmm0
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D48
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D21
type_guessed: string

tool: D29: Enter a number: 

tool: D48: %lf

tool: D14: Enter pow:

tool: D19: %d

tool: D21: %f * 2^%d = %f


assistant: ```c
double Idexp(double x, double ret) {
  int n;
  printf(gettext("Enter a number: "));
  scanf("%lf", &x);
  printf(gettext("Enter pow:"));
  scanf("%d", &n);
  ret = ldexp(x, n);
  printf("%f * 2^%d = %f\n", x, n, ret);
  return (ret);
}
```