ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D0(%rip),%rax
  movq   %rax,%xmm0
  mov    %rbx,%rdi
  call   <calcY@plt>
  mov    D0(%rip),%rax
  movq   %rax,%xmm0
  mov    %rbx,%rdi
  call   <calcY@plt>
  movsd  (%rsp),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D0: 10000000000

tool: D1: %e


assistant: ```c
int main() {
  double x, y;
  x = 1e10;
  calcY(&y, x);
  calcY(&y, x);
  printf("%e\n", y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  movsd  D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <calcY@plt>
  mov    D9(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <calcY@plt>
  movsd  (%rsp),%xmm0
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: f64
name: extract_symbolic_data
arguments: label: D22
type: string

tool: D9: 10000000000

tool: D22: %e


assistant: ```c
int main() {
  double x, y;
  x = 1e10;
  calcY(&y, x);
  calcY(&y, x);
  printf("%e\n", y);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  movsd  D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <calcY@plt>
  mov    D22(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  call   <calcY@plt>
  movsd  (%rsp),%xmm0
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_guessed: f64
name: retrieve_data
arguments: data_label: D23
type_guessed: string

tool: D22: 10000000000

tool: D23: %e


assistant: ```c
int main() {
  double x, y;
  x = 1e10;
  calcY(&y, x);
  calcY(&y, x);
  printf("%e\n", y);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xdc(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xd8(%rbp)
  jmp    L65
L15:
  mov    -0xd8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xd4(%rbp)
  jmp    L37
L25:
  mov    -0xd8(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L60
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L53
L60:
  addl   $0x1,-0xd4(%rbp)
L37:
  mov    -0xdc(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jl     L25
  addl   $0x1,-0xd8(%rbp)
L65:
  mov    -0xdc(%rbp),%eax
  cmp    %eax,-0xd8(%rbp)
  jl     L15
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D4
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D5: %d

tool: D4: YES

tool: D19: NO

assistant: ```c
int main() {
  int a[50], n, i, j;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (a[i] == a[j]) {
        printf("YES");
        return 0;
      }
    }
  }
  printf("NO");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  jle    L19
  lea    0x10(%rsp),%rax
  lea    -0x1(%r8),%r10d
  lea    0x1(%r8),%r11d
  mov    %rax,%rdi
  mov    $0x1,%esi
  lea    0x14(%rsp),%r9
L36:
  cmp    %esi,%r8d
  jle    L12
  mov    (%rdi),%edx
  mov    %r10d,%eax
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r9,%rax,4),%rcx
  mov    %rdi,%rax
L26:
  cmp    0x4(%rax),%edx
  je     L59
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L26
L12:
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    %r11,%rsi
  jne    L36
L19:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L59:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L32:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0xe8,%rsp
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D1: %d

tool: D14: NO

tool: D8: YES

assistant: ```c
int main() {
  int a[50], n, i, j;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (a[i] == a[j]) {
        printf("YES");
        return 0;
      }
    }
  }
  printf("NO");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0xe8,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  jle    L17
  lea    -0x1(%r8),%r10d
  lea    0x1(%r8),%r11d
  mov    $0x1,%esi
  lea    0x10(%rsp),%rdi
  lea    0x14(%rsp),%r9
L48:
  cmp    %esi,%r8d
  jle    L66
  mov    %r10d,%eax
  mov    (%rdi),%edx
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r9,%rax,4),%rcx
  mov    %rdi,%rax
  jmp    L71
  xchg   %ax,%ax
L41:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L66
L71:
  cmp    0x4(%rax),%edx
  jne    L41
  lea    D20(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  xor    %eax,%eax
  add    $0xe8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    %r11,%rsi
  jne    L48
L17:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string

tool: D11: %d

tool: D20: YES

tool: D12: NO

assistant: ```c
int main() {
  int a[50], n, i, j;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (a[i] == a[j]) {
        printf("YES");
        return 0;
      }
    }
  }
  printf("NO");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0xe8,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  jle    L0
  lea    -0x1(%r8),%r10d
  lea    0x1(%r8),%r11d
  mov    $0x1,%esi
  lea    0x10(%rsp),%rdi
  lea    0x14(%rsp),%r9
L74:
  cmp    %esi,%r8d
  jle    L18
  mov    %r10d,%eax
  mov    (%rdi),%edx
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r9,%rax,4),%rcx
  mov    %rdi,%rax
  jmp    L63
  xchg   %ax,%ax
L37:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L18
L63:
  cmp    0x4(%rax),%edx
  jne    L37
  lea    D18(%rip),%rdi
  call   <printf@plt>
L49:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0xe8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    %r11,%rsi
  jne    L74
L0:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L49
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D20
data_type: string

tool: D6: %d

tool: D18: YES

tool: D20: NO

assistant: ```c
int main() {
  int a[50], n, i, j;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (a[i] == a[j]) {
        printf("YES");
        return 0;
      }
    }
  }
  printf("NO");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L19:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int str2int(char *str) {
  int length = strlen(str);
  int i = 0, ans = 0;
  for (i = 0; i < length; i++) {
    ans = ans * 10 + str[i] - '0';
  }
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str2int>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L18:
  lea    (%rax,%rax,4),%ecx
  movsbl (%rdx),%eax
  lea    -0x30(%rax,%rcx,2),%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L18
L28:
  pop    %rbx
  ret
L12:
  mov    $0x0,%eax
  jmp    L28
```

assistant: ```c
int str2int(char *str) {
  int length = strlen(str);
  int i = 0, ans = 0;
  for (i = 0; i < length; i++) {
    ans = ans * 10 + str[i] - '0';
  }
  return ans;
}
```
user: What is the c source code of the assembly code below:

```asm
<str2int>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L1:
  lea    (%rax,%rax,4),%edx
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%eax
  cmp    %rcx,%rdi
  jne    L1
  pop    %rbx
  ret
  nopl   (%rax)
L6:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int str2int(char *str) {
  int length = strlen(str);
  int i = 0, ans = 0;
  for (i = 0; i < length; i++) {
    ans = ans * 10 + str[i] - '0';
  }
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str2int>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L19:
  lea    (%rax,%rax,4),%edx
  movsbl (%rdi),%eax
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%eax
  cmp    %rdi,%rcx
  jne    L19
  pop    %rbx
  ret
  nopl   (%rax)
L18:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int str2int(char *str) {
  int length = strlen(str);
  int i = 0, ans = 0;
  for (i = 0; i < length; i++) {
    ans = ans * 10 + str[i] - '0';
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <eat_ws@plt>
  jmp    L73
L96:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L73:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L36
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L96
L36:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L145
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jle    L96
L145:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L16
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L96
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L96
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L96
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L96
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L116
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L116
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  je     L116
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L116
  mov    $0x0,%eax
  jmp    L22
L116:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  sub    -0x8(%rbp),%rax
L22:
  leave
  ret
```

assistant: ```c
int parse_tag(char *tag, char *str) {
  char *start = str;
  eat_ws(&str);
  while (((*str >= 'a') && (*str <= 'z')) || ((*str >= 'A') && (*str <= 'Z')) || ((*str >= '0') && (*str <= '9')) || (*str == '_') || (*str == '-') || (*str == '.')) {
    *tag = *str;
    tag++;
    str++;
  }
  if ((*str != ' ') && (*str != '\t') && (*str != ')') && (*str != 0))
    return (0);
  *tag = 0;
  return ((int)(str - start));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_tag>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <eat_ws@plt>
  movabs $0x4000000001ffb,%rsi
  jmp    L8
L23:
  mov    %cl,0x0(%rbp)
  add    $0x1,%rbp
  add    $0x1,%rax
  mov    %rax,0x8(%rsp)
L8:
  mov    0x8(%rsp),%rax
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L23
  lea    -0x2d(%rcx),%edx
  cmp    $0x32,%dl
  ja     L7
  bt     %rdx,%rsi
  jb     L23
L7:
  and    $0xdf,%ecx
  je     L15
  cmp    $0x9,%cl
  jne    L48
L15:
  movb   $0x0,0x0(%rbp)
  sub    %ebx,%eax
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
int parse_tag(char *tag, char *str) {
  char *start = str;
  eat_ws(&str);
  while (((*str >= 'a') && (*str <= 'z')) || ((*str >= 'A') && (*str <= 'Z')) || ((*str >= '0') && (*str <= '9')) || (*str == '_') || (*str == '-') || (*str == '.')) {
    *tag = *str;
    tag++;
    str++;
  }
  if ((*str != ' ') && (*str != '\t') && (*str != ')') && (*str != 0))
    return (0);
  *tag = 0;
  return ((int)(str - start));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_tag>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsi,0x8(%rsp)
  call   <eat_ws@plt>
  mov    0x8(%rsp),%rax
  movabs $0x4000000001ffb,%rsi
  xchg   %ax,%ax
L51:
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L41
  lea    -0x2d(%rcx),%edx
  cmp    $0x32,%dl
  ja     L0
  bt     %rdx,%rsi
  jb     L41
L0:
  and    $0xdf,%ecx
  je     L35
  cmp    $0x9,%cl
  jne    L54
L35:
  movb   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x1,%rax
  mov    %cl,0x0(%rbp)
  add    $0x1,%rbp
  mov    %rax,0x8(%rsp)
  jmp    L51
L54:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int parse_tag(char *tag, char *str) {
  char *start = str;
  eat_ws(&str);
  while (((*str >= 'a') && (*str <= 'z')) || ((*str >= 'A') && (*str <= 'Z')) || ((*str >= '0') && (*str <= '9')) || (*str == '_') || (*str == '-') || (*str == '.')) {
    *tag = *str;
    tag++;
    str++;
  }
  if ((*str != ' ') && (*str != '\t') && (*str != ')') && (*str != 0))
    return (0);
  *tag = 0;
  return ((int)(str - start));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_tag>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  lea    0x8(%rsp),%rdi
  mov    %rsi,0x8(%rsp)
  call   <eat_ws@plt>
  mov    0x8(%rsp),%rax
  movabs $0x4000000001ffb,%rsi
  xchg   %ax,%ax
L1:
  movzbl (%rax),%ecx
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L5
  lea    -0x2d(%rcx),%edx
  cmp    $0x32,%dl
  ja     L17
  bt     %rdx,%rsi
  jb     L5
L17:
  and    $0xdf,%ecx
  je     L49
  cmp    $0x9,%cl
  jne    L56
L49:
  movb   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  mov    %cl,0x0(%rbp)
  add    $0x1,%rbp
  mov    %rax,0x8(%rsp)
  jmp    L1
L56:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int parse_tag(char *tag, char *str) {
  char *start = str;
  eat_ws(&str);
  while (((*str >= 'a') && (*str <= 'z')) || ((*str >= 'A') && (*str <= 'Z')) || ((*str >= '0') && (*str <= '9')) || (*str == '_') || (*str == '-') || (*str == '.')) {
    *tag = *str;
    tag++;
    str++;
  }
  if ((*str != ' ') && (*str != '\t') && (*str != ')') && (*str != 0))
    return (0);
  *tag = 0;
  return ((int)(str - start));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_grid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %esi,-0xc8(%rbp)
  mov    %rdx,-0xd0(%rbp)
  mov    %rcx,-0xd8(%rbp)
  mov    %r8,-0xe0(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xe0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%r8d
  mov    -0xe0(%rbp),%rdi
  mov    -0xd8(%rbp),%rcx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc8(%rbp),%esi
  mov    -0xc4(%rbp),%eax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <vis_grid@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void is_grid(int x, int y, int *got, int *expect, char *legend, ...) {
  va_list argp;
  va_start(argp, legend);
  vis_grid(x, y, got, expect, legend, argp);
  va_end(argp);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_grid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %r8,%rbx
  mov    %r8,%rsi
  mov    $0x0,%r15d
  mov    %r15d,%edi
  call   <va_start@plt>
  mov    %r15d,%r9d
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <vis_grid@plt>
  mov    %r15d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void is_grid(int x, int y, int *got, int *expect, char *legend, ...) {
  va_list argp;
  va_start(argp, legend);
  vis_grid(x, y, got, expect, legend, argp);
  va_end(argp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_grid>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    %r8,%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%r9d
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <vis_grid@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void is_grid(int x, int y, int *got, int *expect, char *legend, ...) {
  va_list argp;
  va_start(argp, legend);
  vis_grid(x, y, got, expect, legend, argp);
  va_end(argp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_grid>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    %r8,%rsi
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%r9d
  mov    %rbx,%r8
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <vis_grid@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void is_grid(int x, int y, int *got, int *expect, char *legend, ...) {
  va_list argp;
  va_start(argp, legend);
  vis_grid(x, y, got, expect, legend, argp);
  va_end(argp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swizzle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swizzle(void *start, size_t len) {
  void *end = (void *)((char *)start + len - 1);
  while (start < end) {
    uint8_t tmp = *((char *)start);
    *((char *)start) = *((char *)end);
    start = (void *)((char *)start + 1);
    *((char *)end) = tmp;
    end = (void *)((char *)end - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swizzle>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L14
L19:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  mov    %cl,(%rdi)
  add    $0x1,%rdi
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jb     L19
L14:
  ret
```

assistant: ```c
void swizzle(void *start, size_t len) {
  void *end = (void *)((char *)start + len - 1);
  while (start < end) {
    uint8_t tmp = *((char *)start);
    *((char *)start) = *((char *)end);
    start = (void *)((char *)start + 1);
    *((char *)end) = tmp;
    end = (void *)((char *)end - 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swizzle>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L14
  xchg   %ax,%ax
L17:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L17
L14:
  ret
```

assistant: ```c
void swizzle(void *start, size_t len) {
  void *end = (void *)((char *)start + len - 1);
  while (start < end) {
    uint8_t tmp = *((char *)start);
    *((char *)start) = *((char *)end);
    start = (void *)((char *)start + 1);
    *((char *)end) = tmp;
    end = (void *)((char *)end - 1);
  }
}
```