ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<GenerarNombre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <validarMemoria@plt>
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  call   <errorMemoria@plt>
L3:
  mov    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: %dx%d

assistant: ```c
char *GenerarNombre(int dimension) {
  char *nombre = NULL;
  if (validarMemoria((void **)(&nombre), 6))
    errorMemoria();
  sprintf(nombre, "%dx%d", dimension, dimension);
  return nombre;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GenerarNombre>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    $0x6,%esi
  call   <validarMemoria@plt>
  test   %rax,%rax
  jne    L6
L28:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  lea    D2(%rip),%rsi
  mov    (%rsp),%rdi
  call   <sprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  call   <errorMemoria@plt>
  jmp    L28
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: %dx%d

assistant: ```c
char *GenerarNombre(int dimension) {
  char *nombre = NULL;
  if (validarMemoria((void **)(&nombre), 6))
    errorMemoria();
  sprintf(nombre, "%dx%d", dimension, dimension);
  return nombre;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GenerarNombre>:
  endbr64
  push   %r12
  mov    $0x6,%esi
  mov    %edi,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <validarMemoria@plt>
  test   %rax,%rax
  jne    L0
L9:
  mov    (%rsp),%rdi
  mov    %r12d,%ecx
  mov    %r12d,%edx
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x10,%rsp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <errorMemoria@plt>
  jmp    L9
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: %dx%d

assistant: ```c
char *GenerarNombre(int dimension) {
  char *nombre = NULL;
  if (validarMemoria((void **)(&nombre), 6))
    errorMemoria();
  sprintf(nombre, "%dx%d", dimension, dimension);
  return nombre;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GenerarNombre>:
  endbr64
  push   %r12
  mov    $0x6,%esi
  mov    %edi,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <validarMemoria@plt>
  test   %rax,%rax
  jne    L1
L21:
  mov    (%rsp),%rdi
  mov    %r12d,%ecx
  mov    %r12d,%edx
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <errorMemoria@plt>
  jmp    L21
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: %dx%d

assistant: ```c
char *GenerarNombre(int dimension) {
  char *nombre = NULL;
  if (validarMemoria((void **)(&nombre), 6))
    errorMemoria();
  sprintf(nombre, "%dx%d", dimension, dimension);
  return nombre;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ib_map_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ib_map_find@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L4
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ib_map_erase@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
int ib_map_remove(struct ib_hash_map *hm, const void *key) {
  struct ib_hash_entry *entry;
  entry = ib_map_find(hm, key);
  if (entry == NULL) {
    return -1;
  }
  ib_map_erase(hm, entry);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ib_map_remove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ib_map_find@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <ib_map_erase@plt>
  mov    $0x0,%eax
L1:
  pop    %rbx
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int ib_map_remove(struct ib_hash_map *hm, const void *key) {
  struct ib_hash_entry *entry;
  entry = ib_map_find(hm, key);
  if (entry == NULL) {
    return -1;
  }
  ib_map_erase(hm, entry);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ib_map_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ib_map_find@plt>
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <ib_map_erase@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ib_map_remove(struct ib_hash_map *hm, const void *key) {
  struct ib_hash_entry *entry;
  entry = ib_map_find(hm, key);
  if (entry == NULL) {
    return -1;
  }
  ib_map_erase(hm, entry);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ib_map_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <ib_map_find@plt>
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <ib_map_erase@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ib_map_remove(struct ib_hash_map *hm, const void *key) {
  struct ib_hash_entry *entry;
  entry = ib_map_find(hm, key);
  if (entry == NULL) {
    return -1;
  }
  ib_map_erase(hm, entry);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L99
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L98
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L23
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L23
  addl   $0x1,-0x8(%rbp)
  jmp    L22
L23:
  cmpl   $0x0,-0x8(%rbp)
  jle    L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L22:
  addl   $0x1,-0x4(%rbp)
L98:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L87
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L53
L87:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L53
L99:
  nop
L53:
  pop    %rbp
  ret
```

assistant: ```c
void trim(char *s) {
  if (s[0] == 0)
    return;
  int cnt = s[0] == ' ' ? 1 : 0;
  int i = 0;
  for (i = 1; s[i] != 0; i++) {
    if (s[i] == ' ' && s[i - 1] == ' ')
      cnt++;
    else if (cnt > 0) {
      s[i - cnt] = s[i];
    }
  }
  if (s[i - cnt - 1] == ' ')
    s[i - cnt - 1] = 0;
  else
    s[i - cnt] = 0;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  cmp    $0x20,%al
  sete   %r8b
  movzbl %r8b,%r8d
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L50
  lea    0x2(%rdi),%rdx
  mov    $0x1,%ecx
  jmp    L8
L40:
  cmpb   $0x20,-0x2(%rdx)
  jne    L57
  add    $0x1,%r8d
L72:
  add    $0x1,%ecx
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L62
L8:
  cmp    $0x20,%al
  je     L40
L57:
  test   %r8d,%r8d
  jle    L72
  mov    %ecx,%esi
  sub    %r8d,%esi
  movslq %esi,%rsi
  mov    %al,(%rdi,%rsi,1)
  jmp    L72
L50:
  mov    $0x1,%ecx
L62:
  sub    %r8d,%ecx
  movslq %ecx,%rcx
  lea    -0x1(%rdi,%rcx,1),%rax
  cmpb   $0x20,(%rax)
  je     L36
  movb   $0x0,(%rdi,%rcx,1)
L25:
  ret
L36:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
void trim(char *s) {
  if (s[0] == 0)
    return;
  int cnt = s[0] == ' ' ? 1 : 0;
  int i = 0;
  for (i = 1; s[i] != 0; i++) {
    if (s[i] == ' ' && s[i - 1] == ' ')
      cnt++;
    else if (cnt > 0) {
      s[i - cnt] = s[i];
    }
  }
  if (s[i - cnt - 1] == ' ')
    s[i - cnt - 1] = 0;
  else
    s[i - cnt] = 0;
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L74
  xor    %r8d,%r8d
  cmp    $0x20,%al
  movzbl 0x1(%rdi),%eax
  sete   %r8b
  test   %al,%al
  je     L42
  lea    0x2(%rdi),%rdx
  mov    $0x1,%ecx
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L24:
  test   %r8d,%r8d
  je     L61
  mov    %ecx,%esi
  sub    %r8d,%esi
  movslq %esi,%rsi
  mov    %al,(%rdi,%rsi,1)
L61:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%ecx
  test   %al,%al
  je     L92
L21:
  cmp    $0x20,%al
  jne    L24
  cmpb   $0x20,-0x2(%rdx)
  jne    L24
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r8d
  add    $0x1,%ecx
  test   %al,%al
  jne    L21
  nopw   0x0(%rax,%rax,1)
L92:
  sub    %r8d,%ecx
  movslq %ecx,%rcx
  lea    -0x1(%rdi,%rcx,1),%rax
  cmpb   $0x20,(%rax)
  je     L77
  movb   $0x0,(%rdi,%rcx,1)
L74:
  ret
  nopl   (%rax)
L77:
  movb   $0x0,(%rax)
  ret
  nopl   0x0(%rax)
L42:
  mov    $0x1,%ecx
  jmp    L92
```

assistant: ```c
void trim(char *s) {
  if (s[0] == 0)
    return;
  int cnt = s[0] == ' ' ? 1 : 0;
  int i = 0;
  for (i = 1; s[i] != 0; i++) {
    if (s[i] == ' ' && s[i - 1] == ' ')
      cnt++;
    else if (cnt > 0) {
      s[i - cnt] = s[i];
    }
  }
  if (s[i - cnt - 1] == ' ')
    s[i - cnt - 1] = 0;
  else
    s[i - cnt] = 0;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  xor    %r8d,%r8d
  cmp    $0x20,%al
  movzbl 0x1(%rdi),%eax
  sete   %r8b
  test   %al,%al
  je     L54
  lea    0x2(%rdi),%rdx
  mov    $0x1,%ecx
  jmp    L71
  nopw   0x0(%rax,%rax,1)
L26:
  test   %r8d,%r8d
  je     L1
  mov    %ecx,%esi
  sub    %r8d,%esi
  movslq %esi,%rsi
  mov    %al,(%rdi,%rsi,1)
L1:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%ecx
  test   %al,%al
  je     L11
L71:
  cmp    $0x20,%al
  jne    L26
  cmpb   $0x20,-0x2(%rdx)
  jne    L26
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  add    $0x1,%r8d
  add    $0x1,%ecx
  test   %al,%al
  jne    L71
  nopw   0x0(%rax,%rax,1)
L11:
  sub    %r8d,%ecx
  movslq %ecx,%rcx
  lea    -0x1(%rdi,%rcx,1),%rax
  cmpb   $0x20,(%rax)
  je     L34
  movb   $0x0,(%rdi,%rcx,1)
L17:
  ret
  nopl   (%rax)
L34:
  movb   $0x0,(%rax)
  ret
  nopl   0x0(%rax)
L54:
  mov    $0x1,%ecx
  jmp    L11
```

assistant: ```c
void trim(char *s) {
  if (s[0] == 0)
    return;
  int cnt = s[0] == ' ' ? 1 : 0;
  int i = 0;
  for (i = 1; s[i] != 0; i++) {
    if (s[i] == ' ' && s[i - 1] == ' ')
      cnt++;
    else if (cnt > 0) {
      s[i - cnt] = s[i];
    }
  }
  if (s[i - cnt - 1] == ' ')
    s[i - cnt - 1] = 0;
  else
    s[i - cnt] = 0;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<df2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  movq   %xmm0,%rbp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movq   %xmm5,%rbx
  mov    %edi,%r14d
  mov    %esi,%r15d
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  shl    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  0x8(%rsp),%xmm0
  movapd %xmm0,%xmm6
  movsd  %xmm0,0x18(%rsp)
  xorpd  D22(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  movq   %rbx,%xmm0
  mulsd  %xmm6,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rbx
  mov    D8(%rip),%rax
  mov    %rax,0x30(%rsp)
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
  test   %r15d,%r15d
  jne    L16
L22:
  movsd  %xmm0,0x38(%rsp)
  movsd  %xmm1,0x40(%rsp)
  movsd  0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  call   <exp@plt>
  movq   %xmm0,%rbx
  mov    D8(%rip),%rax
  mov    %rax,0x50(%rsp)
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
  test   %r14d,%r14d
  jne    L20
L39:
  movsd  %xmm0,0x58(%rsp)
  movsd  %xmm1,0x60(%rsp)
  lea    0x30(%rsp),%rdx
  lea    0x50(%rsp),%rdi
  mov    %r13,%r9
  mov    %r12,%r8
  mov    $0x2,%ecx
  mov    $0x2,%esi
  movq   %rbp,%xmm0
  call   <dfs@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  movsd  0x18(%rsp),%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  0x28(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  movq   %rbx,%xmm0
  mulsd  D58(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm1
  jmp    L22
L20:
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  0x20(%rsp),%xmm0
  cvttsd2si %xmm0,%edi
  call   <cos@plt>
  movq   %rbx,%xmm0
  mulsd  D58(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  movq   %rbx,%xmm1
  mulsd  %xmm1,%xmm1
  jmp    L39
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: f64
name: disassemble_data
arguments: data_label: D22
datatype: byte[16]
name: disassemble_data
arguments: data_label: D58
datatype: byte[8]

tool: D8: 1

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double df2(const double x, const double sf, const double f0p, const double wbp, const double f0z, const double wbz, const int fp, const int fz, double *buf, int *bufp) {
  double a[3], b[3];
  double p, e;
  p = 4 * atan(1.0) / sf;
  e = exp(-p * wbz);
  a[0] = 1.0;
  if (fz) {
    a[1] = -2 * e * cos(2 * p * f0z);
    a[2] = e * e;
  } else {
    a[1] = 0;
    a[2] = 0;
  }
  e = exp(-p * wbp);
  b[0] = 1.0;
  if (fp) {
    b[1] = -2 * e * cos(2 * p * f0p);
    b[2] = e * e;
  } else {
    b[1] = 0;
    b[2] = 0;
  }
  return (dfs(x, b, 2, a, 2, buf, bufp));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<df2>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x70,%rsp
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm1,(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm5,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    D29(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  movsd  0x10(%rsp),%xmm5
  shl    $0x2,%eax
  cvtsi2sd %eax,%xmm0
  divsd  (%rsp),%xmm0
  movapd %xmm0,%xmm1
  xorpd  D34(%rip),%xmm1
  movsd  %xmm0,0x18(%rsp)
  mulsd  %xmm1,%xmm5
  movsd  %xmm1,(%rsp)
  movapd %xmm5,%xmm0
  call   <exp@plt>
  mov    D29(%rip),%rax
  test   %r13d,%r13d
  pxor   %xmm2,%xmm2
  movsd  (%rsp),%xmm1
  mov    %rax,0x30(%rsp)
  jne    L48
L0:
  movsd  0x8(%rsp),%xmm0
  movups %xmm2,0x38(%rsp)
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  mov    D29(%rip),%rax
  pxor   %xmm1,%xmm1
  mov    %rax,0x50(%rsp)
  test   %r12d,%r12d
  jne    L26
L31:
  lea    0x30(%rsp),%rdx
  lea    0x50(%rsp),%rdi
  mov    %rbp,%r9
  mov    %rbx,%r8
  mov    $0x2,%ecx
  mov    $0x2,%esi
  movq   %r14,%xmm0
  movups %xmm1,0x58(%rsp)
  call   <dfs@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  movsd  0x18(%rsp),%xmm7
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm7,%xmm2
  addsd  %xmm7,%xmm2
  mulsd  0x28(%rsp),%xmm2
  cvttsd2si %xmm2,%edi
  call   <cos@plt>
  movsd  0x10(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  movsd  D45(%rip),%xmm2
  cvtsi2sd %eax,%xmm3
  movsd  (%rsp),%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm2
  unpcklpd %xmm0,%xmm2
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L26:
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  addsd  %xmm1,%xmm1
  mulsd  0x20(%rsp),%xmm1
  cvttsd2si %xmm1,%edi
  call   <cos@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm2,%xmm2
  movsd  D45(%rip),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm1
  unpcklpd %xmm0,%xmm1
  jmp    L31
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
datatype: f64
name: read_data
arguments: data_label: D34
datatype: byte[16]
name: read_data
arguments: data_label: D45
datatype: byte[8]

tool: D29: 1

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

assistant: ```c
double df2(const double x, const double sf, const double f0p, const double wbp, const double f0z, const double wbz, const int fp, const int fz, double *buf, int *bufp) {
  double a[3], b[3];
  double p, e;
  p = 4 * atan(1.0) / sf;
  e = exp(-p * wbz);
  a[0] = 1.0;
  if (fz) {
    a[1] = -2 * e * cos(2 * p * f0z);
    a[2] = e * e;
  } else {
    a[1] = 0;
    a[2] = 0;
  }
  e = exp(-p * wbp);
  b[0] = 1.0;
  if (fp) {
    b[1] = -2 * e * cos(2 * p * f0p);
    b[2] = e * e;
  } else {
    b[1] = 0;
    b[2] = 0;
  }
  return (dfs(x, b, 2, a, 2, buf, bufp));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<irqDispatcher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L34
  cmpl   $0x1,-0x4(%rbp)
  je     L37
  jmp    L36
L34:
  mov    $0x0,%eax
  call   <timerTick@plt>
  jmp    L29
L37:
  mov    $0x0,%eax
  call   <addToBuffer@plt>
  nop
L29:
  nop
L36:
  leave
  ret
```

assistant: ```c
void irqDispatcher(int irq) {
  switch (irq) {
  case 0:
    timerTick();
    break;
  case 1:
    addToBuffer();
    break;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<irqDispatcher>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L30
  cmp    $0x1,%edi
  je     L3
L28:
  add    $0x8,%rsp
  ret
L30:
  mov    $0x0,%eax
  call   <timerTick@plt>
  jmp    L28
L3:
  mov    $0x0,%eax
  call   <addToBuffer@plt>
  jmp    L28
```

assistant: ```c
void irqDispatcher(int irq) {
  switch (irq) {
  case 0:
    timerTick();
    break;
  case 1:
    addToBuffer();
    break;
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<irqDispatcher>:
  endbr64
  test   %edi,%edi
  je     L12
  cmp    $0x1,%edi
  jne    L3
  xor    %eax,%eax
  jmp    1070 <addToBuffer@plt>
  nopl   0x0(%rax)
L3:
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  jmp    1060 <timerTick@plt>
```

assistant: ```c
void irqDispatcher(int irq) {
  switch (irq) {
  case 0:
    timerTick();
    break;
  case 1:
    addToBuffer();
    break;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<irqDispatcher>:
  endbr64
  test   %edi,%edi
  je     L9
  cmp    $0x1,%edi
  jne    L0
  xor    %eax,%eax
  jmp    1070 <addToBuffer@plt>
  nopl   0x0(%rax)
L0:
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  jmp    1060 <timerTick@plt>
```

assistant: ```c
void irqDispatcher(int irq) {
  switch (irq) {
  case 0:
    timerTick();
    break;
  case 1:
    addToBuffer();
    break;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  lea    D10(%rip),%rdx
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <print_base@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D28: Decimal: 

tool: D1: 


assistant: ```c
void print_decimal(int num) {
  static char map[] = {
      '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
  };
  printf("Decimal: ");
  print_base(num, 10, map);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_decimal>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdx
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <print_base@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D12: Decimal: 

tool: D11: 


assistant: ```c
void print_decimal(int num) {
  static char map[] = {
      '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
  };
  printf("Decimal: ");
  print_base(num, 10, map);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_decimal>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  lea    D20(%rip),%rdx
  call   <print_base@plt>
  lea    D27(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string
name: read_data
arguments: label: D27
type_infered: string

tool: D1: Decimal: 

tool: D27: 


assistant: ```c
void print_decimal(int num) {
  static char map[] = {
      '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
  };
  printf("Decimal: ");
  print_base(num, 10, map);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_decimal>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  lea    D1(%rip),%rdx
  call   <print_base@plt>
  lea    D10(%rip),%rdi
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string

tool: D0: Decimal: 

tool: D10: 


assistant: ```c
void print_decimal(int num) {
  static char map[] = {
      '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
  };
  printf("Decimal: ");
  print_base(num, 10, map);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<expand_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_wildcard@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *expand_filename(const char *string) {
  char *filename = NULL;
  if (find_wildcard(string, strlen(string))) {
  }
  return filename;
}
```