ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x25,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L4
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  mov    $0x8,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  shl    $0x3,%eax
  and    $0x78,%eax
  or     %edi,%eax
  mov    %al,-0x9(%rbp)
  jmp    L22
L4:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  and    $0xfffffff0,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
L22:
  movzbl -0x9(%rbp),%eax
  or     $0xffffff98,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    }
    output[0UL] = state[0UL] | 844337816UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L15
  mov    %eax,%r8d
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  mov    $0x8,%ecx
  sub    %r8d,%ecx
  mov    %edx,%edi
  sar    %cl,%edi
  mov    %r8d,%ecx
  shl    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
L0:
  or     $0xffffff98,%eax
  mov    %al,(%rsi)
  ret
L15:
  shl    $0x4,%edx
  or     %edx,%eax
  jmp    L0
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    }
    output[0UL] = state[0UL] | 844337816UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L8
  mov    %eax,%r8d
  mov    $0x8,%ecx
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edi
  sub    %edi,%ecx
  mov    %edx,%edi
  sar    %cl,%edi
  mov    %r8d,%ecx
  shl    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
  or     $0xffffff98,%eax
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax)
L8:
  shl    $0x4,%edx
  or     %edx,%eax
  or     $0xffffff98,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    }
    output[0UL] = state[0UL] | 844337816UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x25,%eax
  movzbl %al,%edx
  test   $0x1,%al
  je     L4
  mov    %eax,%r8d
  mov    $0x8,%ecx
  shr    $0x3,%r8b
  and    $0xe,%r8d
  or     $0x1,%r8d
  movzbl %r8b,%edi
  sub    %edi,%ecx
  mov    %edx,%edi
  sar    %cl,%edi
  mov    %r8d,%ecx
  shl    %cl,%edx
  or     %edx,%edi
  shl    $0x3,%edi
  and    $0x78,%edi
  or     %edi,%eax
  or     $0xffffff98,%eax
  mov    %al,(%rsi)
  ret
  nopl   0x0(%rax)
L4:
  shl    $0x4,%edx
  or     %edx,%eax
  or     $0xffffff98,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = input[0UL] + (unsigned char)219;
    if (state[0UL] & (unsigned char)1) {
      state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[0UL] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)))) & (unsigned char)15) << 3UL;
    } else {
      state[0UL] |= (state[0UL] & (unsigned char)63) << 4UL;
    }
    output[0UL] = state[0UL] | 844337816UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_ceil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_ceil() {
  assert(ceil(1.5) == 2.0);
  assert(ceil(-1.5) == -1.0);
  assert(ceil(1.000001) == 2.0);
  assert(ceil(-1.000001) == -1.0);
  assert(ceil(1.0) == 1.0);
  assert(ceil(-1.0) == -1.0);
  assert(ceil(10000.000001) == 10001.0);
  assert(ceil(-10000.000001) == -10000.0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_ceil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_ceil() {
  assert(ceil(1.5) == 2.0);
  assert(ceil(-1.5) == -1.0);
  assert(ceil(1.000001) == 2.0);
  assert(ceil(-1.000001) == -1.0);
  assert(ceil(1.0) == 1.0);
  assert(ceil(-1.0) == -1.0);
  assert(ceil(10000.000001) == 10001.0);
  assert(ceil(-10000.000001) == -10000.0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_ceil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <assert@plt>
```

assistant: ```c
void test_ceil() {
  assert(ceil(1.5) == 2.0);
  assert(ceil(-1.5) == -1.0);
  assert(ceil(1.000001) == 2.0);
  assert(ceil(-1.000001) == -1.0);
  assert(ceil(1.0) == 1.0);
  assert(ceil(-1.0) == -1.0);
  assert(ceil(10000.000001) == 10001.0);
  assert(ceil(-10000.000001) == -10000.0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_ceil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1050 <assert@plt>
```

assistant: ```c
void test_ceil() {
  assert(ceil(1.5) == 2.0);
  assert(ceil(-1.5) == -1.0);
  assert(ceil(1.000001) == 2.0);
  assert(ceil(-1.000001) == -1.0);
  assert(ceil(1.0) == 1.0);
  assert(ceil(-1.0) == -1.0);
  assert(ceil(10000.000001) == 10001.0);
  assert(ceil(-10000.000001) == -10000.0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_escape>:
  endbr64
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rsi
  mov    %rsi,(%rdi)
  movzbl (%rcx),%eax
  movsbl %al,%edx
  cmp    $0x76,%al
  jg     L133
  cmp    $0x2f,%al
  jle    L158
  sub    $0x30,%eax
  cmp    $0x46,%al
  ja     L133
  movzbl %al,%eax
  lea    D5(%rip),%r8
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
L158:
  test   %al,%al
  je     L55
  cmp    $0xa,%al
  mov    $0xfffffffe,%eax
  cmove  %eax,%edx
L133:
  mov    %edx,%eax
  ret
  mov    $0x8,%edx
  jmp    L133
  mov    $0x1b,%edx
  jmp    L133
  mov    $0xc,%edx
  jmp    L133
  mov    $0xa,%edx
  jmp    L133
  mov    $0xd,%edx
  jmp    L133
  mov    $0x9,%edx
  jmp    L133
  mov    $0xb,%edx
  jmp    L133
L55:
  mov    %rcx,(%rdi)
  mov    $0x0,%edx
  jmp    L133
  sub    $0x8,%rsp
  lea    0x2(%rcx),%rax
  mov    %rax,(%rdi)
  movsbl 0x1(%rcx),%eax
  cmp    $0x5c,%eax
  je     L172
L63:
  mov    %eax,%edx
  and    $0x9f,%edx
  cmp    $0x3f,%eax
  mov    $0x7f,%eax
  cmove  %eax,%edx
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L172:
  mov    $0x0,%eax
  call   <parse_escape>
  jmp    L63
  sub    $0x30,%edx
  lea    0x2(%rcx),%r8
  mov    %r8,(%rdi)
  movsbl 0x1(%rcx),%eax
  lea    -0x30(%rax),%r9d
  cmp    $0x7,%r9d
  ja     L182
  lea    -0x30(%rax,%rdx,8),%edx
  lea    0x3(%rcx),%rax
  mov    %rax,(%rdi)
  movsbl 0x2(%rcx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x7,%ecx
  ja     L46
  lea    -0x30(%rax,%rdx,8),%edx
  jmp    L133
L46:
  mov    %r8,%rsi
L182:
  mov    %rsi,(%rdi)
  jmp    L133
  mov    $0x7,%edx
  jmp    L133
```

assistant: ```c
int parse_escape(string_ptr)
char **string_ptr;
{
  register int c = *(*string_ptr)++;
  switch (c) {
  case 'a':
    return '\a';
  case 'b':
    return '\b';
  case 'e':
    return 033;
  case 'f':
    return '\f';
  case 'n':
    return '\n';
  case 'r':
    return '\r';
  case 't':
    return '\t';
  case 'v':
    return '\v';
  case '\n':
    return -2;
  case 0:
    (*string_ptr)--;
    return 0;
  case '^':
    c = *(*string_ptr)++;
    if (c == '\\')
      c = parse_escape(string_ptr);
    if (c == '?')
      return 0177;
    return (c & 0200) | (c & 037);
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7': {
    register int i = c - '0';
    register int count = 0;
    while (++count < 3) {
      if ((c = *(*string_ptr)++) >= '0' && c <= '7') {
        i *= 8;
        i += c - '0';
      } else {
        (*string_ptr)--;
        break;
      }
    }
    return i;
  }
  default:
    return c;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sb_iir>:
  endbr64
  lea    D1(%rip),%rdx
  movslq %edi,%rdi
  movss  (%rdx,%rdi,8),%xmm1
  movss  %xmm1,0x4(%rdx,%rdi,8)
  lea    D29(%rip),%rax
  movss  (%rax,%rdi,8),%xmm2
  movss  %xmm2,0x4(%rax,%rdi,8)
  movss  %xmm0,(%rdx,%rdi,8)
  movss  D17(%rip),%xmm3
  mulss  %xmm3,%xmm1
  mulss  D8(%rip),%xmm2
  subss  %xmm2,%xmm1
  mulss  %xmm3,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax,%rdi,8)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_guessed: f32
name: retrieve_data
arguments: data_label: D8
type_guessed: byte[4]

tool: D17: 0.17529642630084405

tool: {"D8": [0x93,0x3f,0x26,0xbf]}

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[1 + 1] = {0.17529642630084405000, 0.17529642630084405000};
  float BCoef[1 + 1] = {1.00000000000000000000, -0.64940759319751051000};
  static float y[2][1 + 1];
  static float x[2][1 + 1];
  int n;
  for (n = 1; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 1; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sb_iir>:
  endbr64
  movslq %edi,%rdi
  lea    D21(%rip),%rdx
  movaps %xmm0,%xmm1
  movss  D30(%rip),%xmm3
  lea    D24(%rip),%rax
  movss  (%rdx,%rdi,8),%xmm0
  movss  %xmm1,(%rdx,%rdi,8)
  movss  (%rax,%rdi,8),%xmm2
  mulss  %xmm3,%xmm1
  movss  %xmm0,0x4(%rdx,%rdi,8)
  mulss  %xmm3,%xmm0
  movss  %xmm2,0x4(%rax,%rdi,8)
  mulss  D1(%rip),%xmm2
  subss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax,%rdi,8)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D30
datatype: f32
name: retrieve_data
arguments: label: D1
datatype: byte[4]

tool: D30: 0.17529642630084405

tool: {"D1": [0x93,0x3f,0x26,0xbf]}

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[1 + 1] = {0.17529642630084405000, 0.17529642630084405000};
  float BCoef[1 + 1] = {1.00000000000000000000, -0.64940759319751051000};
  static float y[2][1 + 1];
  static float x[2][1 + 1];
  int n;
  for (n = 1; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 1; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sb_iir>:
  endbr64
  movslq %edi,%rdi
  lea    D37(%rip),%rdx
  movaps %xmm0,%xmm1
  movss  D14(%rip),%xmm4
  movss  (%rdx,%rdi,8),%xmm0
  movaps %xmm1,%xmm3
  lea    D24(%rip),%rax
  movss  (%rax,%rdi,8),%xmm2
  unpcklps %xmm0,%xmm3
  movlps %xmm3,(%rdx,%rdi,8)
  movss  D30(%rip),%xmm3
  mulss  %xmm2,%xmm4
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm1
  subss  %xmm4,%xmm0
  addss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  unpcklps %xmm2,%xmm1
  movlps %xmm1,(%rax,%rdi,8)
  ret
```

tool_calls: name: parse_data
arguments: label: D14
type_guessed: byte[4]
name: parse_data
arguments: label: D30
type_guessed: f32

tool: {"D14": [0x93,0x3f,0x26,0xbf]}

tool: D30: 0.17529642630084405

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[1 + 1] = {0.17529642630084405000, 0.17529642630084405000};
  float BCoef[1 + 1] = {1.00000000000000000000, -0.64940759319751051000};
  static float y[2][1 + 1];
  static float x[2][1 + 1];
  int n;
  for (n = 1; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 1; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0xdb,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  movzbl -0xe(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string

tool: D13: %c

tool: D8: 
%c

assistant: ```c
int main() {
  char ch, a;
  int alph;
  scanf("%c", &ch);
  alph = 'a' + 'z';
  a = alph - ch;
  printf("\n%c", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  movsbl %sil,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D2: %c

tool: D0: 
%c

assistant: ```c
int main() {
  char ch, a;
  int alph;
  scanf("%c", &ch);
  alph = 'a' + 'z';
  a = alph - ch;
  printf("\n%c", a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  lea    D6(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D15: %c

tool: D6: 
%c

assistant: ```c
int main() {
  char ch, a;
  int alph;
  scanf("%c", &ch);
  alph = 'a' + 'z';
  a = alph - ch;
  printf("\n%c", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  mov    $0xffffffdb,%esi
  sub    0x7(%rsp),%sil
  lea    D7(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D10: %c

tool: D7: 
%c

assistant: ```c
int main() {
  char ch, a;
  int alph;
  scanf("%c", &ch);
  alph = 'a' + 'z';
  a = alph - ch;
  printf("\n%c", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x9,-0xc(%rbp)
  jle    L6
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <outnum>
  mov    %rax,-0x8(%rbp)
L6:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *outnum(char *p, int n) {
  if (n >= 10)
    p = outnum(p, n / 10);
  *p++ = (char)(n % 10 + '0');
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<outnum>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x9,%esi
  jg     L4
L13:
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rdi)
  lea    0x1(%rdi),%rax
  pop    %rbx
  ret
L4:
  movslq %esi,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  call   <outnum>
  mov    %rax,%rdi
  jmp    L13
```

assistant: ```c
char *outnum(char *p, int n) {
  if (n >= 10)
    p = outnum(p, n / 10);
  *p++ = (char)(n % 10 + '0');
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<outnum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x8,%rsp
  cmp    $0x9,%ebp
  jg     L34
L37:
  imul   $0x66666667,%rbp,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x1(%rdi),%rax
  add    $0x30,%ebx
  mov    %bl,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L34:
  imul   $0x66666667,%rbp,%r12
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r12
  sub    %eax,%r12d
  mov    %r12d,%r13d
  cmp    $0x63,%ebp
  jg     L46
L31:
  mov    $0xcccccccd,%eax
  add    $0x1,%rdi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  add    $0x30,%r12d
  mov    %r12b,-0x1(%rdi)
  jmp    L37
  xchg   %ax,%ax
L46:
  mov    $0xcccccccd,%esi
  mov    %r13,%r14
  imul   %rsi,%r14
  shr    $0x23,%r14
  mov    %r14d,%r15d
  cmp    $0x3e7,%ebp
  jg     L26
L54:
  mov    $0xcccccccd,%eax
  add    $0x1,%rdi
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  add    $0x30,%r14d
  mov    %r14b,-0x1(%rdi)
  jmp    L31
  xchg   %ax,%ax
L26:
  imul   %r15,%rsi
  shr    $0x23,%rsi
  call   <outnum>
  mov    %rax,%rdi
  jmp    L54
```

assistant: ```c
char *outnum(char *p, int n) {
  if (n >= 10)
    p = outnum(p, n / 10);
  *p++ = (char)(n % 10 + '0');
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<outnum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x8,%rsp
  cmp    $0x9,%ebp
  jg     L13
L2:
  imul   $0x66666667,%rbp,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x1(%rdi),%rax
  add    $0x30,%ebx
  mov    %bl,(%rdi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L13:
  imul   $0x66666667,%rbp,%r12
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r12
  sub    %eax,%r12d
  mov    %r12d,%r13d
  cmp    $0x63,%ebp
  jg     L22
L27:
  mov    $0xcccccccd,%eax
  add    $0x1,%rdi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  add    $0x30,%r12d
  mov    %r12b,-0x1(%rdi)
  jmp    L2
  xchg   %ax,%ax
L22:
  mov    $0xcccccccd,%esi
  mov    %r13,%r14
  imul   %rsi,%r14
  shr    $0x23,%r14
  mov    %r14d,%r15d
  cmp    $0x3e7,%ebp
  jg     L14
L17:
  mov    $0xcccccccd,%eax
  add    $0x1,%rdi
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  add    $0x30,%r14d
  mov    %r14b,-0x1(%rdi)
  jmp    L27
  xchg   %ax,%ax
L14:
  imul   %r15,%rsi
  shr    $0x23,%rsi
  call   <outnum>
  mov    %rax,%rdi
  jmp    L17
```

assistant: ```c
char *outnum(char *p, int n) {
  if (n >= 10)
    p = outnum(p, n / 10);
  *p++ = (char)(n % 10 + '0');
  return p;
}
```