ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<substring>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L10
  mov    %rdi,%r9
  mov    %edx,%edx
  mov    $0x0,%eax
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%r8
L26:
  mov    %eax,%edi
  cmpb   $0x0,(%r9,%rax,1)
  je     L25
  movzbl (%r8,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  lea    0x1(%rax),%edi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
L25:
  movslq %edi,%rdi
  movb   $0x0,(%rcx,%rdi,1)
  mov    %rcx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L10:
  mov    $0x0,%edi
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: The new string is %s.


assistant: ```c
void substring(const char source[81], int start, int count, char result[81]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; ++i)
    result[i] = source[i + start];
  result[i] = '\0';
  printf("The new string is %s.\n", result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  test   %edx,%edx
  jle    L55
  mov    %rdi,%r10
  movslq %esi,%rsi
  mov    %rcx,%rdi
  mov    $0x1,%eax
  lea    0x1(%rdx),%r11d
  lea    (%r10,%rsi,1),%r9
  jmp    L14
  nopl   0x0(%rax)
L26:
  movzbl -0x1(%r9,%rax,1),%r8d
  mov    %r8b,(%rdi)
  movslq %eax,%r8
  add    $0x1,%rax
  lea    0x1(%rdx),%rdi
  cmp    %r11,%rax
  je     L1
L14:
  cmpb   $0x0,-0x1(%r10,%rax,1)
  mov    %rdi,%rdx
  jne    L26
L33:
  movb   $0x0,(%rdx)
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
  nop
L1:
  lea    0x0(%rbp,%r8,1),%rdx
  jmp    L33
L55:
  mov    %rcx,%rdx
  jmp    L33
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: The new string is %s.


assistant: ```c
void substring(const char source[81], int start, int count, char result[81]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; ++i)
    result[i] = source[i + start];
  result[i] = '\0';
  printf("The new string is %s.\n", result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  test   %edx,%edx
  jle    L38
  mov    %rdi,%r10
  movslq %esi,%rsi
  mov    %rcx,%rdi
  mov    $0x1,%eax
  lea    0x1(%rdx),%r11d
  lea    (%r10,%rsi,1),%r9
  jmp    L40
  nopl   0x0(%rax)
L19:
  movzbl -0x1(%r9,%rax,1),%r8d
  mov    %r8b,(%rdi)
  movslq %eax,%r8
  add    $0x1,%rax
  lea    0x1(%rdx),%rdi
  cmp    %r11,%rax
  je     L59
L40:
  cmpb   $0x0,-0x1(%r10,%rax,1)
  mov    %rdi,%rdx
  jne    L19
L22:
  movb   $0x0,(%rdx)
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
  nop
L59:
  lea    0x0(%rbp,%r8,1),%rdx
  jmp    L22
L38:
  mov    %rcx,%rdx
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: The new string is %s.


assistant: ```c
void substring(const char source[81], int start, int count, char result[81]) {
  int i;
  for (i = 0; i < count && source[i] != '\0'; ++i)
    result[i] = source[i + start];
  result[i] = '\0';
  printf("The new string is %s.\n", result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_utf8chrsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    $0xfe,%eax
  ja     L11
  mov    $0x1,%eax
  jmp    L13
L11:
  mov    -0x8(%rbp),%rax
  cmp    $0xfffe,%eax
  ja     L79
  mov    $0x2,%eax
  jmp    L13
L79:
  mov    -0x8(%rbp),%rax
  cmp    $0xfffffe,%eax
  ja     L1
  mov    $0x3,%eax
  jmp    L13
L1:
  mov    -0x8(%rbp),%rax
  cmp    $0xffffffff,%eax
  je     L34
  mov    $0x4,%eax
  jmp    L13
L34:
  mov    $0xffffffff,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
char ft_utf8chrsize(wchar_t c) {
  if ((unsigned int)c < 0xFF)
    return (1);
  else if ((unsigned int)c < 0xFFFF)
    return (2);
  else if ((unsigned int)c < 0xFFFFFF)
    return (3);
  else if ((unsigned int)c < 0xFFFFFFFF)
    return (4);
  else
    return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_utf8chrsize>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfe,%edi
  jbe    L16
  mov    $0x2,%eax
  cmp    $0xfffe,%edi
  jbe    L16
  mov    $0x3,%eax
  cmp    $0xfffffe,%edi
  jbe    L16
  cmp    $0xffffffff,%edi
  setne  %al
  lea    -0x1(%rax,%rax,4),%eax
L16:
  ret
```

assistant: ```c
char ft_utf8chrsize(wchar_t c) {
  if ((unsigned int)c < 0xFF)
    return (1);
  else if ((unsigned int)c < 0xFFFF)
    return (2);
  else if ((unsigned int)c < 0xFFFFFF)
    return (3);
  else if ((unsigned int)c < 0xFFFFFFFF)
    return (4);
  else
    return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_utf8chrsize>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfe,%edi
  jbe    L16
  mov    $0x2,%eax
  cmp    $0xfffe,%edi
  jbe    L16
  mov    $0x3,%eax
  cmp    $0xfffffe,%edi
  jbe    L16
  cmp    $0xffffffff,%edi
  setne  %al
  lea    -0x1(%rax,%rax,4),%eax
L16:
  ret
```

assistant: ```c
char ft_utf8chrsize(wchar_t c) {
  if ((unsigned int)c < 0xFF)
    return (1);
  else if ((unsigned int)c < 0xFFFF)
    return (2);
  else if ((unsigned int)c < 0xFFFFFF)
    return (3);
  else if ((unsigned int)c < 0xFFFFFFFF)
    return (4);
  else
    return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_utf8chrsize>:
  endbr64
  mov    $0x1,%eax
  cmp    $0xfe,%edi
  jbe    L20
  mov    $0x2,%eax
  cmp    $0xfffe,%edi
  jbe    L20
  mov    $0x3,%eax
  cmp    $0xfffffe,%edi
  jbe    L20
  cmp    $0xffffffff,%edi
  setne  %al
  lea    -0x1(%rax,%rax,4),%eax
L20:
  ret
```

assistant: ```c
char ft_utf8chrsize(wchar_t c) {
  if ((unsigned int)c < 0xFF)
    return (1);
  else if ((unsigned int)c < 0xFFFF)
    return (2);
  else if ((unsigned int)c < 0xFFFFFF)
    return (3);
  else if ((unsigned int)c < 0xFFFFFFFF)
    return (4);
  else
    return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    0x3686696a(%rdx),%eax
  xor    $0xce5d000b,%eax
  cmp    $0x97d696a1,%edx
  je     L1
  add    %eax,%eax
L15:
  add    $0x1917bd73,%eax
  mov    %eax,(%rsi)
  ret
L1:
  rol    $0x10,%eax
  mov    %eax,%ecx
  shr    %ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%eax
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy14;
  unsigned short copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else if (state[0UL] < local1) {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      } else {
        copy15 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy15;
        state[local1] >>= ((state[local1] >> 1U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 3873981069U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    0x3686696a(%rdx),%eax
  xor    $0xce5d000b,%eax
  cmp    $0x97d696a1,%edx
  je     L8
  add    %eax,%eax
  add    $0x1917bd73,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  rol    $0x10,%eax
  mov    %eax,%ecx
  shr    %ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%eax
  add    $0x1917bd73,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy14;
  unsigned short copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else if (state[0UL] < local1) {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      } else {
        copy15 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy15;
        state[local1] >>= ((state[local1] >> 1U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 3873981069U;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  lea    0x3686696a(%rdx),%eax
  xor    $0xce5d000b,%eax
  cmp    $0x97d696a1,%edx
  je     L6
  add    %eax,%eax
  add    $0x1917bd73,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  rol    $0x10,%eax
  mov    %eax,%ecx
  shr    %ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%eax
  add    $0x1917bd73,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  char copy14;
  unsigned short copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else if (state[0UL] < local1) {
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      } else {
        copy15 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy15;
        state[local1] >>= ((state[local1] >> 1U) & 7U) | 1UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] - 3873981069U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<validate_protocol_negate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x78(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L14
L30:
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L0
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <validate_protocol@plt>
  jmp    L14
L0:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <validate_protocol@plt>
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: !%100s

assistant: ```c
int validate_protocol_negate(const char *str) {
  if (!str)
    return 0;
  char proto[100];
  memset(proto, '\0', 100);
  if (sscanf(str, "!%100s", proto) != 1)
    return validate_protocol(str);
  return validate_protocol(proto);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<validate_protocol_negate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rbx
  mov    %rsp,%rbp
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L2
  mov    %rbx,%rdi
  call   <validate_protocol@plt>
L10:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rsp,%rdi
  call   <validate_protocol@plt>
  jmp    L10
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: !%100s

assistant: ```c
int validate_protocol_negate(const char *str) {
  if (!str)
    return 0;
  char proto[100];
  memset(proto, '\0', 100);
  if (sscanf(str, "!%100s", proto) != 1)
    return validate_protocol(str);
  return validate_protocol(proto);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<validate_protocol_negate>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L23
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x64,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L34
  mov    %rbp,%rdi
  call   <validate_protocol@plt>
L23:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  mov    %r12,%rdi
  call   <validate_protocol@plt>
  jmp    L23
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: !%100s

assistant: ```c
int validate_protocol_negate(const char *str) {
  if (!str)
    return 0;
  char proto[100];
  memset(proto, '\0', 100);
  if (sscanf(str, "!%100s", proto) != 1)
    return validate_protocol(str);
  return validate_protocol(proto);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<validate_protocol_negate>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L33
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    %rdi,%rbp
  mov    $0x64,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L26
  mov    %rbp,%rdi
  call   <validate_protocol@plt>
L33:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    %r12,%rdi
  call   <validate_protocol@plt>
  jmp    L33
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: !%100s

assistant: ```c
int validate_protocol_negate(const char *str) {
  if (!str)
    return 0;
  char proto[100];
  memset(proto, '\0', 100);
  if (sscanf(str, "!%100s", proto) != 1)
    return validate_protocol(str);
  return validate_protocol(proto);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L26
  cmpl   $0x0,-0x2c(%rbp)
  je     L26
  cmpl   $0x0,-0x30(%rbp)
  je     L26
  cmpq   $0x0,-0x38(%rbp)
  jne    L10
L26:
  movl   $0xffffffff,-0x18(%rbp)
  jmp    L66
L59:
  mov    -0x38(%rbp),%rdi
  mov    -0x10(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x30(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L58
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  call   <qksort>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L59
  jmp    L69
L58:
  nop
L69:
  movl   $0x0,-0x18(%rbp)
L66:
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int qksort(void *data, int size, int esize, int (*compare)(void *key1, void *key2)) {
  int i = 0;
  int j = 0;
  int k = size - 1;
  int ret = -1;
  char *ele = (char *)data;
  int new_size = 0;
  if ((NULL == data) || (0 == size) || (0 == esize) || (NULL == compare)) {
    ret = -1;
    goto LBL_RET;
  }
  while (i < k) {
    j = partition(data, esize, i, k, compare);
    if (j < 0)
      break;
    new_size = j - i + 1;
    qksort(&ele[i * esize], new_size, esize, compare);
    i = j + 1;
  }
  ret = 0;
LBL_RET:
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<qksort>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    %rcx,%r14
  lea    -0x1(%rsi),%r15d
  test   %esi,%esi
  je     L16
  test   %edx,%edx
  je     L46
  test   %rcx,%rcx
  je     L46
  test   %r15d,%r15d
  jle    L52
  mov    $0x0,%ebx
L40:
  mov    %r14,%r8
  mov    %r15d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <partition@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L6
  mov    %eax,%esi
  sub    %ebx,%esi
  add    $0x1,%esi
  imul   %r12d,%ebx
  movslq %ebx,%rdi
  add    %r13,%rdi
  mov    %r14,%rcx
  mov    %r12d,%edx
  call   <qksort>
  lea    0x1(%rbp),%ebx
  cmp    %ebx,%r15d
  jg     L40
  mov    $0x0,%eax
  jmp    L109
L16:
  mov    $0xffffffff,%eax
  jmp    L109
L46:
  mov    $0xffffffff,%eax
  jmp    L109
L52:
  mov    $0x0,%eax
  jmp    L109
L6:
  mov    $0x0,%eax
L109:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int qksort(void *data, int size, int esize, int (*compare)(void *key1, void *key2)) {
  int i = 0;
  int j = 0;
  int k = size - 1;
  int ret = -1;
  char *ele = (char *)data;
  int new_size = 0;
  if ((NULL == data) || (0 == size) || (0 == esize) || (NULL == compare)) {
    ret = -1;
    goto LBL_RET;
  }
  while (i < k) {
    j = partition(data, esize, i, k, compare);
    if (j < 0)
      break;
    new_size = j - i + 1;
    qksort(&ele[i * esize], new_size, esize, compare);
    i = j + 1;
  }
  ret = 0;
LBL_RET:
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qksort>:
  endbr64
  test   %rdi,%rdi
  je     L8
  test   %esi,%esi
  je     L8
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L28
  mov    %rcx,%r13
  test   %rcx,%rcx
  je     L28
  lea    -0x1(%rsi),%r12d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L32
L25:
  mov    %r13,%r8
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <partition@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  js     L32
  mov    %eax,%esi
  mov    %r13,%rcx
  mov    %r15d,%edx
  sub    %ebx,%esi
  imul   %r15d,%ebx
  add    $0x1,%esi
  movslq %ebx,%rdi
  lea    0x1(%r14),%ebx
  add    %rbp,%rdi
  call   <qksort>
  cmp    %ebx,%r12d
  jg     L25
L32:
  xor    %eax,%eax
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0xffffffff,%eax
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L51
```

assistant: ```c
int qksort(void *data, int size, int esize, int (*compare)(void *key1, void *key2)) {
  int i = 0;
  int j = 0;
  int k = size - 1;
  int ret = -1;
  char *ele = (char *)data;
  int new_size = 0;
  if ((NULL == data) || (0 == size) || (0 == esize) || (NULL == compare)) {
    ret = -1;
    goto LBL_RET;
  }
  while (i < k) {
    j = partition(data, esize, i, k, compare);
    if (j < 0)
      break;
    new_size = j - i + 1;
    qksort(&ele[i * esize], new_size, esize, compare);
    i = j + 1;
  }
  ret = 0;
LBL_RET:
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_mempcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x20(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  lea    -0x12(%rbp),%rdx
  add    $0x6,%rdx
  cmp    %rdx,%rax
  je     L3
  mov    $0x5b,%edx
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L43
L3:
  mov    -0x20(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  mov    $0x5c,%edx
  lea    D16(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L43
L6:
  mov    $0x1,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D35
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D38: hello

tool: D23: &dest[6] == mempcpy(dest, src, 6)

tool: D35: expression '%s' untrue at %d


tool: D16: strcmp(dest, src) == 0

assistant: ```c
int test_mempcpy(void) {
  const char *src = "hello";
  char dest[10];
  memset(dest, 'x', sizeof dest);
  do {
    if (!(&dest[6] == mempcpy(dest, src, 6))) {
      printf("expression '%s' untrue at %d\n", "&dest[6] == mempcpy(dest, src, 6)", 91);
      return 0;
    }
  } while (0);
  do {
    if (!(strcmp(dest, src) == 0)) {
      printf("expression '%s' untrue at %d\n", "strcmp(dest, src) == 0", 92);
      return 0;
    }
  } while (0);
  return 1;
}
```