ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<slg_write>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  xor    %eax,%eax
  test   %r15,%r15
  je     L9
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    $0x6,%ebp
  call   <strlcpy@plt>
  lea    D10(%rip),%rbx
  xor    %r12d,%r12d
  jmp    L12
L7:
  mov    -0x4(%rbx),%ebp
  add    $0x1,%r12d
L12:
  mov    %rbx,%rsi
  mov    %ebp,%edx
  mov    %r15,%rdi
  add    $0x14,%rbx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L7
  movslq %r12d,%r12
  lea    D6(%rip),%rax
  movslq %ebp,%rdx
  mov    %r14,%rdi
  lea    (%r12,%r12,4),%rcx
  add    %r15,%rdx
  mov    0x10(%rax,%rcx,4),%esi
  call   <xsyslog@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r13d,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D6
datatype: string

tool: D10: PANIC 

tool: D6: 

assistant: ```c
int slg_write(BIO *b, const char *in, int inl) {
  int ret = inl;
  char *buf;
  char *pp;
  int priority, i;
  static const struct {
    int strl;
    char str[10];
    int log_level;
  } mapping[] = {{6, "PANIC ", LOG_EMERG}, {6, "EMERG ", LOG_EMERG}, {4, "EMR ", LOG_EMERG}, {6, "ALERT ", LOG_ALERT}, {4, "ALR ", LOG_ALERT}, {5, "CRIT ", LOG_CRIT}, {4, "CRI ", LOG_CRIT}, {6, "ERROR ", LOG_ERR}, {4, "ERR ", LOG_ERR}, {8, "WARNING ", LOG_WARNING}, {5, "WARN ", LOG_WARNING}, {4, "WAR ", LOG_WARNING}, {7, "NOTICE ", LOG_NOTICE}, {5, "NOTE ", LOG_NOTICE}, {4, "NOT ", LOG_NOTICE}, {5, "INFO ", LOG_INFO}, {4, "INF ", LOG_INFO}, {6, "DEBUG ", LOG_DEBUG}, {4, "DBG ", LOG_DEBUG}, {0, "", LOG_ERR}};
  if ((buf = malloc(inl + 1)) == NULL) {
    return (0);
  }
  strlcpy(buf, in, inl + 1);
  i = 0;
  while (strncmp(buf, mapping[i].str, mapping[i].strl) != 0)
    i++;
  priority = mapping[i].log_level;
  pp = buf + mapping[i].strl;
  xsyslog(b, priority, pp);
  free(buf);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<slg_write>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  xor    %eax,%eax
  test   %r15,%r15
  je     L29
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %r12d,%r12d
  call   <strlcpy@plt>
  lea    D0(%rip),%rbx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%r12d
L9:
  mov    -0x4(%rbx),%ebp
  mov    %rbx,%rsi
  mov    %r15,%rdi
  add    $0x14,%rbx
  mov    %ebp,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L1
  movslq %r12d,%r12
  lea    D19(%rip),%rax
  movslq %ebp,%rdx
  mov    %r14,%rdi
  lea    (%r12,%r12,4),%rcx
  add    %r15,%rdx
  mov    0x10(%rax,%rcx,4),%esi
  call   <xsyslog@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r13d,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string

tool: D0: PANIC 

tool: D19: 

assistant: ```c
int slg_write(BIO *b, const char *in, int inl) {
  int ret = inl;
  char *buf;
  char *pp;
  int priority, i;
  static const struct {
    int strl;
    char str[10];
    int log_level;
  } mapping[] = {{6, "PANIC ", LOG_EMERG}, {6, "EMERG ", LOG_EMERG}, {4, "EMR ", LOG_EMERG}, {6, "ALERT ", LOG_ALERT}, {4, "ALR ", LOG_ALERT}, {5, "CRIT ", LOG_CRIT}, {4, "CRI ", LOG_CRIT}, {6, "ERROR ", LOG_ERR}, {4, "ERR ", LOG_ERR}, {8, "WARNING ", LOG_WARNING}, {5, "WARN ", LOG_WARNING}, {4, "WAR ", LOG_WARNING}, {7, "NOTICE ", LOG_NOTICE}, {5, "NOTE ", LOG_NOTICE}, {4, "NOT ", LOG_NOTICE}, {5, "INFO ", LOG_INFO}, {4, "INF ", LOG_INFO}, {6, "DEBUG ", LOG_DEBUG}, {4, "DBG ", LOG_DEBUG}, {0, "", LOG_ERR}};
  if ((buf = malloc(inl + 1)) == NULL) {
    return (0);
  }
  strlcpy(buf, in, inl + 1);
  i = 0;
  while (strncmp(buf, mapping[i].str, mapping[i].strl) != 0)
    i++;
  priority = mapping[i].log_level;
  pp = buf + mapping[i].strl;
  xsyslog(b, priority, pp);
  free(buf);
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stamp_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L8
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x4d,%eax
  jle    L24
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x4c,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   $0x5b5,%eax,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  imul   $0x16d,%eax,%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L3
  addl   $0x1,-0x28(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  add    %eax,-0x28(%rbp)
  subl   $0x2da,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
L24:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    -0x38(%rbp),%rdx
  lea    0x2(%rdx),%rbx
  mov    %eax,%edi
  call   <dec2bcd@plt>
  mov    %al,(%rbx)
  mov    -0x20(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    -0x38(%rbp),%rdx
  lea    0x3(%rdx),%rbx
  mov    %eax,%edi
  call   <dec2bcd@plt>
  mov    %al,(%rbx)
  jmp    L20
L8:
  nop
L20:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void stamp_now(unsigned char *stamp) {
  time_t t;
  struct tm *ptm;
  int days, leap;
  memset(stamp, 0, 4);
  time(&t);
  ptm = localtime(&t);
  if (!ptm)
    return;
  if (ptm->tm_year >= 78) {
    leap = (ptm->tm_year - 76) / 4;
    leap *= 1461;
    days = (ptm->tm_year % 4) * 365;
    if (days)
      ++days;
    days += ptm->tm_yday;
    days += leap;
    days -= 730;
    stamp[0] = days & 0xFF;
    stamp[1] = days >> 8;
  }
  stamp[2] = dec2bcd(ptm->tm_hour);
  stamp[3] = dec2bcd(ptm->tm_min);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stamp_now>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  mov    (%rax),%eax
  cmp    $0x4d,%eax
  jle    L15
  lea    -0x49(%rax),%ecx
  mov    %eax,%edx
  sub    $0x4c,%edx
  cmovns %edx,%ecx
  sar    $0x2,%ecx
  imul   $0x5b5,%ecx,%ecx
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x3,%edx
  sub    %esi,%edx
  imul   $0x16d,%edx,%edx
  and    $0x3,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  add    0x10(%rbx),%edx
  lea    -0x2da(%rdx,%rcx,1),%eax
  mov    %al,0x0(%rbp)
  movzbl %ah,%eax
  mov    %al,0x1(%rbp)
L15:
  mov    0x8(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x2(%rbp)
  mov    0x4(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x3(%rbp)
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stamp_now(unsigned char *stamp) {
  time_t t;
  struct tm *ptm;
  int days, leap;
  memset(stamp, 0, 4);
  time(&t);
  ptm = localtime(&t);
  if (!ptm)
    return;
  if (ptm->tm_year >= 78) {
    leap = (ptm->tm_year - 76) / 4;
    leap *= 1461;
    days = (ptm->tm_year % 4) * 365;
    if (days)
      ++days;
    days += ptm->tm_yday;
    days += leap;
    days -= 730;
    stamp[0] = days & 0xFF;
    stamp[1] = days >> 8;
  }
  stamp[2] = dec2bcd(ptm->tm_hour);
  stamp[3] = dec2bcd(ptm->tm_min);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stamp_now>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <memset@plt>
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbx
  mov    (%rax),%eax
  cmp    $0x4d,%eax
  jg     L32
L19:
  mov    0x8(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x2(%rbp)
  mov    0x4(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x3(%rbp)
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L32:
  lea    -0x4c(%rax),%edx
  and    $0x3,%eax
  imul   $0x16d,%eax,%ecx
  sar    $0x2,%edx
  imul   $0x5b5,%edx,%edx
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ecx
  add    0x10(%rbx),%ecx
  lea    -0x2da(%rcx,%rdx,1),%eax
  mov    %ax,0x0(%rbp)
  jmp    L19
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stamp_now(unsigned char *stamp) {
  time_t t;
  struct tm *ptm;
  int days, leap;
  memset(stamp, 0, 4);
  time(&t);
  ptm = localtime(&t);
  if (!ptm)
    return;
  if (ptm->tm_year >= 78) {
    leap = (ptm->tm_year - 76) / 4;
    leap *= 1461;
    days = (ptm->tm_year % 4) * 365;
    if (days)
      ++days;
    days += ptm->tm_yday;
    days += leap;
    days -= 730;
    stamp[0] = days & 0xFF;
    stamp[1] = days >> 8;
  }
  stamp[2] = dec2bcd(ptm->tm_hour);
  stamp[3] = dec2bcd(ptm->tm_min);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stamp_now>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <memset@plt>
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  mov    (%rax),%eax
  cmp    $0x4d,%eax
  jg     L31
L33:
  mov    0x8(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x2(%rbp)
  mov    0x4(%rbx),%edi
  call   <dec2bcd@plt>
  mov    %al,0x3(%rbp)
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L31:
  lea    -0x4c(%rax),%edx
  and    $0x3,%eax
  imul   $0x16d,%eax,%ecx
  sar    $0x2,%edx
  imul   $0x5b5,%edx,%edx
  cmp    $0x1,%eax
  sbb    $0xffffffff,%ecx
  add    0x10(%rbx),%ecx
  lea    -0x2da(%rcx,%rdx,1),%eax
  mov    %ax,0x0(%rbp)
  jmp    L33
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stamp_now(unsigned char *stamp) {
  time_t t;
  struct tm *ptm;
  int days, leap;
  memset(stamp, 0, 4);
  time(&t);
  ptm = localtime(&t);
  if (!ptm)
    return;
  if (ptm->tm_year >= 78) {
    leap = (ptm->tm_year - 76) / 4;
    leap *= 1461;
    days = (ptm->tm_year % 4) * 365;
    if (days)
      ++days;
    days += ptm->tm_yday;
    days += leap;
    days -= 730;
    stamp[0] = days & 0xFF;
    stamp[1] = days >> 8;
  }
  stamp[2] = dec2bcd(ptm->tm_hour);
  stamp[3] = dec2bcd(ptm->tm_min);
}
```
user: What is the c source code of the assembly code below?

```asm
<pop_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <longjmp@plt>
  nop
  leave
  ret
```

assistant: ```c
int pop_error(jmp_buf *env, size_t len) {
  assert(env != NULL);
  longjmp(*env, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pop_error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    (%rbx),%edi
  call   <longjmp@plt>
  pop    %rbx
  ret
```

assistant: ```c
int pop_error(jmp_buf *env, size_t len) {
  assert(env != NULL);
  longjmp(*env, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop_error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1070 <longjmp@plt>
```

assistant: ```c
int pop_error(jmp_buf *env, size_t len) {
  assert(env != NULL);
  longjmp(*env, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pop_error>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%edi
  mov    $0x1,%esi
  pop    %rbx
  jmp    1070 <longjmp@plt>
```

assistant: ```c
int pop_error(jmp_buf *env, size_t len) {
  assert(env != NULL);
  longjmp(*env, 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<savestring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *savestring(const char *arg) {
  char *tmp = (char *)malloc(strlen(arg) + 1);
  strcpy(tmp, arg);
  return (tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<savestring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *savestring(const char *arg) {
  char *tmp = (char *)malloc(strlen(arg) + 1);
  strcpy(tmp, arg);
  return (tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<savestring>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *savestring(const char *arg) {
  char *tmp = (char *)malloc(strlen(arg) + 1);
  strcpy(tmp, arg);
  return (tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_branch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfc000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x40000000,-0x4(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L9
L13:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
bool is_branch(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc000000;
  if (insn_base == 0x40000000)
    return true;
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_branch>:
  endbr64
  and    $0xfc000000,%edi
  cmp    $0x40000000,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_branch(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc000000;
  if (insn_base == 0x40000000)
    return true;
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_branch>:
  endbr64
  and    $0xfc000000,%edi
  xor    %eax,%eax
  cmp    $0x40000000,%edi
  sete   %al
  ret
```

assistant: ```c
bool is_branch(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc000000;
  if (insn_base == 0x40000000)
    return true;
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_branch>:
  endbr64
  and    $0xfc000000,%edi
  xor    %eax,%eax
  cmp    $0x40000000,%edi
  sete   %al
  ret
```

assistant: ```c
bool is_branch(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc000000;
  if (insn_base == 0x40000000)
    return true;
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<uart_outputchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0xffff0008,%eax
  mov    %rax,-0x10(%rbp)
  mov    $0xffff000c,%eax
  mov    %rax,-0x8(%rbp)
  nop
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  movzbl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_outputchar(char c) {
  volatile char *uart_cout = (char *)0xFFFF0008;
  volatile char *uart_dout = (char *)0xFFFF000C;
  while (*uart_cout != 0)
    ;
  *uart_dout = c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_outputchar>:
  endbr64
  mov    %edi,%eax
  mov    $0xffff0008,%ecx
L5:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L5
  movabs %al,0xffff000c
  ret
```

assistant: ```c
void uart_outputchar(char c) {
  volatile char *uart_cout = (char *)0xFFFF0008;
  volatile char *uart_dout = (char *)0xFFFF000C;
  while (*uart_cout != 0)
    ;
  *uart_dout = c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uart_outputchar>:
  endbr64
  mov    %edi,%eax
  mov    $0xffff0008,%ecx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L3
  movabs %al,0xffff000c
  ret
```

assistant: ```c
void uart_outputchar(char c) {
  volatile char *uart_cout = (char *)0xFFFF0008;
  volatile char *uart_dout = (char *)0xFFFF000C;
  while (*uart_cout != 0)
    ;
  *uart_dout = c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_outputchar>:
  endbr64
  mov    %edi,%eax
  mov    $0xffff0008,%ecx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L7
  movabs %al,0xffff000c
  ret
```

assistant: ```c
void uart_outputchar(char c) {
  volatile char *uart_cout = (char *)0xFFFF0008;
  volatile char *uart_dout = (char *)0xFFFF000C;
  while (*uart_cout != 0)
    ;
  *uart_dout = c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0x17,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: b = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  a = atoi(argv[1]);
  b = a * 23;
  printf("b = %d\n", b);
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  imul   $0x17,%eax,%ebx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: b = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  a = atoi(argv[1]);
  b = a * 23;
  printf("b = %d\n", b);
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D8(%rip),%rdi
  imul   $0x17,%eax,%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: b = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  a = atoi(argv[1]);
  b = a * 23;
  printf("b = %d\n", b);
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D6(%rip),%rdi
  imul   $0x17,%eax,%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: b = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  a = atoi(argv[1]);
  b = a * 23;
  printf("b = %d\n", b);
  return b;
}
```
user: What is the c source code of the assembly code below:

```asm
<fail_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L51
L48:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L1
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L51
L1:
  cmpl   $0x0,-0x4(%rbp)
  jle    L28
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L51
L28:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L51:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fail_func(const char *p, int *next) {
  next[0] = 0;
  for (int i = 1, j = 0; *(p + i);)
    if (p[j] == p[i])
      next[i++] = ++j;
    else {
      if (j > 0)
        j = next[j - 1];
      else {
        next[i++] = 0;
      }
    }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fail_func>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L49
  mov    $0x0,%edx
  mov    $0x1,%r9d
  mov    $0x1,%ecx
  jmp    L2
L27:
  add    $0x1,%edx
  add    $0x1,%r9d
  mov    %edx,(%rsi,%rcx,4)
L48:
  movslq %r9d,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  je     L49
L2:
  movslq %edx,%r8
  cmp    %al,(%rdi,%r8,1)
  je     L27
  test   %edx,%edx
  jle    L64
  mov    -0x4(%rsi,%r8,4),%edx
  jmp    L48
L64:
  add    $0x1,%r9d
  movl   $0x0,(%rsi,%rcx,4)
  jmp    L48
L49:
  ret
```

assistant: ```c
void fail_func(const char *p, int *next) {
  next[0] = 0;
  for (int i = 1, j = 0; *(p + i);)
    if (p[j] == p[i])
      next[i++] = ++j;
    else {
      if (j > 0)
        j = next[j - 1];
      else {
        next[i++] = 0;
      }
    }
}
```