ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<earth_values>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %r14
  pxor   %xmm1,%xmm1
  movq   %xmm0,%r14
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L11:
  movsd  (%r12,%rbx,8),%xmm2
  mov    %ebx,%edi
  add    $0x1,%rbx
  movq   %r14,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <pow@plt>
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L11
  divsd  D7(%rip),%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: f64

tool: D7: 100000000

assistant: ```c
double earth_values(double term_sum[], int count, double jme) {
  int i;
  double sum = 0;
  for (i = 0; i < count; i++)
    sum += term_sum[i] * pow(jme, i);
  sum /= 1.0e8;
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checking_palindr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L17
  mov    $0x0,%eax
  jmp    L6
L17:
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L14
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int checking_palindr(char hex[], int extent) {
  for (int i = 0, j = extent - 1; i < extent / 2; i++, j--) {
    if (hex[i] != hex[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checking_palindr>:
  endbr64
  lea    -0x1(%rsi),%edx
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  cmp    $0x1,%esi
  jle    L29
  movslq %edx,%rdx
  add    %rdi,%rdx
  mov    $0x0,%eax
L23:
  movzbl (%rdx),%esi
  cmp    %sil,(%rdi,%rax,1)
  jne    L27
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jg     L23
  mov    $0x1,%eax
  ret
L29:
  mov    $0x1,%eax
  ret
L27:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int checking_palindr(char hex[], int extent) {
  for (int i = 0, j = extent - 1; i < extent / 2; i++, j--) {
    if (hex[i] != hex[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checking_palindr>:
  endbr64
  mov    %esi,%ecx
  lea    -0x1(%rsi),%edx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  cmp    $0x1,%esi
  jle    L36
  movslq %edx,%rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  jmp    L4
  nop
L5:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jle    L36
L4:
  movzbl (%rdx),%esi
  cmp    %sil,(%rdi,%rax,1)
  je     L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int checking_palindr(char hex[], int extent) {
  for (int i = 0, j = extent - 1; i < extent / 2; i++, j--) {
    if (hex[i] != hex[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<checking_palindr>:
  endbr64
  mov    %esi,%ecx
  lea    -0x1(%rsi),%edx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  cmp    $0x1,%esi
  jle    L22
  movslq %edx,%rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  jmp    L37
  nop
L3:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%ecx
  jle    L22
L37:
  movzbl (%rdx),%esi
  cmp    %sil,(%rdi,%rax,1)
  je     L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int checking_palindr(char hex[], int extent) {
  for (int i = 0, j = extent - 1; i < extent / 2; i++, j--) {
    if (hex[i] != hex[j]) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inverse_t_alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x20(%rbp),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x24(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssq -0x18(%rbp),%xmm1
  addss  -0x4(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: f64

tool: D8: 100

assistant: ```c
float inverse_t_alpha(long iter, long length, float alpha) {
  float c;
  c = length / 100.0;
  return (alpha * c / (c + iter));
}
```
user: What is the c source code of the assembly code below:

```asm
<inverse_t_alpha>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  D1(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2ss %rdi,%xmm2
  addss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: f64

tool: D1: 100

assistant: ```c
float inverse_t_alpha(long iter, long length, float alpha) {
  float c;
  c = length / 100.0;
  return (alpha * c / (c + iter));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inverse_t_alpha>:
  endbr64
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %rdi,%xmm2
  cvtsi2sd %rsi,%xmm1
  divsd  D7(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: f64

tool: D7: 100

assistant: ```c
float inverse_t_alpha(long iter, long length, float alpha) {
  float c;
  c = length / 100.0;
  return (alpha * c / (c + iter));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inverse_t_alpha>:
  endbr64
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %rdi,%xmm2
  cvtsi2sd %rsi,%xmm1
  divsd  D2(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: f64

tool: D2: 100

assistant: ```c
float inverse_t_alpha(long iter, long length, float alpha) {
  float c;
  c = length / 100.0;
  return (alpha * c / (c + iter));
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_205_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0x10(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_205_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  return stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_205_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  shl    $0x8,%esi
  or     $0xff,%sil
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  not    %esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_205_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_205_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  shl    $0x8,%esi
  mov    %edi,%eax
  or     $0xff,%sil
  shl    $0x8,%eax
  or     %edi,%eax
  not    %esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_205_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrop3_205_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  shl    $0x8,%esi
  mov    %edi,%eax
  or     $0xff,%sil
  shl    $0x8,%eax
  or     %edi,%eax
  not    %esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned xrop3_205_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | T;
  stk2 = ~stk2;
  stk1 = S | stk2;
  return stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x24(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L49:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L4
L12:
  mov    -0x20(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L65
  mov    -0x20(%rbp),%eax
  mov    -0x14(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L4
L65:
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L12
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L72
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L17
L72:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L17
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L17:
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L49
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D22: %d %d %d


tool: D20: %d

tool: D27: Numero minimo de notas = %d


assistant: ```c
int main() {
  int n_casas, gramas, cambio, n, valor, notas, ctrl, menor = 0;
  scanf("%d %d %d\n", &n_casas, &gramas, &cambio);
  for (int i = 1; i <= n_casas; i++) {
    scanf("%d", &n);
    valor = gramas * cambio;
    notas = 0;
    ctrl = n;
    while (valor >= n) {
      if (ctrl * n <= valor)
        ctrl = ctrl * n;
      else {
        valor = valor - ctrl;
        ctrl = n;
        notas++;
      }
    }
    notas = notas + valor;
    if (menor == 0)
      menor = notas;
    else if (notas < menor)
      menor = notas;
  }
  printf("Numero minimo de notas = %d\n", menor);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L18
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
  jmp    L6
L33:
  sub    %esi,%edx
  add    $0x1,%edi
  jmp    L52
L31:
  add    %edi,%edx
  cmp    %edx,%ebx
  mov    %edx,%eax
  cmovle %ebx,%eax
  test   %ebx,%ebx
  mov    %edx,%ebx
  cmovne %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,0x8(%rsp)
  jl     L7
L6:
  lea    0x14(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  imul   0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    $0x0,%edi
L52:
  mov    %ecx,%esi
L37:
  cmp    %ecx,%edx
  jl     L31
  mov    %esi,%eax
  imul   %ecx,%eax
  cmp    %eax,%edx
  jl     L33
  mov    %eax,%esi
  jmp    L37
L18:
  mov    $0x0,%ebx
L7:
  mov    %ebx,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D29
datatype: string
name: read_data
arguments: data_label: D24
datatype: string
name: read_data
arguments: data_label: D27
datatype: string

tool: D29: %d %d %d


tool: D24: %d

tool: D27: Numero minimo de notas = %d


assistant: ```c
int main() {
  int n_casas, gramas, cambio, n, valor, notas, ctrl, menor = 0;
  scanf("%d %d %d\n", &n_casas, &gramas, &cambio);
  for (int i = 1; i <= n_casas; i++) {
    scanf("%d", &n);
    valor = gramas * cambio;
    notas = 0;
    ctrl = n;
    while (valor >= n) {
      if (ctrl * n <= valor)
        ctrl = ctrl * n;
      else {
        valor = valor - ctrl;
        ctrl = n;
        notas++;
      }
    }
    notas = notas + valor;
    if (menor == 0)
      menor = notas;
    else if (notas < menor)
      menor = notas;
  }
  printf("Numero minimo de notas = %d\n", menor);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L72
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  lea    0x14(%rsp),%rbp
  lea    D1(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  imul   0x10(%rsp),%edx
  xor    %edi,%edi
  mov    0x14(%rsp),%ecx
L3:
  mov    %ecx,%esi
  jmp    L76
L78:
  mov    %esi,%eax
  imul   %ecx,%eax
  cmp    %edx,%eax
  jg     L58
  mov    %eax,%esi
L76:
  cmp    %ecx,%edx
  jge    L78
  lea    (%rdi,%rdx,1),%eax
  cmp    %eax,%r12d
  mov    %eax,%edx
  cmovle %r12d,%edx
  test   %r12d,%r12d
  cmovne %edx,%eax
  add    $0x1,%r13d
  mov    %eax,%r12d
  cmp    %r13d,0x8(%rsp)
  jge    L49
L33:
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  sub    %esi,%edx
  add    $0x1,%edi
  jmp    L3
L72:
  xor    %r12d,%r12d
  jmp    L33
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string

tool: D4: %d %d %d


tool: D1: %d

tool: D23: Numero minimo de notas = %d


assistant: ```c
int main() {
  int n_casas, gramas, cambio, n, valor, notas, ctrl, menor = 0;
  scanf("%d %d %d\n", &n_casas, &gramas, &cambio);
  for (int i = 1; i <= n_casas; i++) {
    scanf("%d", &n);
    valor = gramas * cambio;
    notas = 0;
    ctrl = n;
    while (valor >= n) {
      if (ctrl * n <= valor)
        ctrl = ctrl * n;
      else {
        valor = valor - ctrl;
        ctrl = n;
        notas++;
      }
    }
    notas = notas + valor;
    if (menor == 0)
      menor = notas;
    else if (notas < menor)
      menor = notas;
  }
  printf("Numero minimo de notas = %d\n", menor);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L59
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  lea    0x14(%rsp),%rbp
  lea    D21(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  imul   0x10(%rsp),%edx
  xor    %edi,%edi
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%edx
  jl     L13
L33:
  mov    %ecx,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %eax,%esi
  imul   %ecx,%eax
  cmp    %edx,%eax
  jle    L10
  sub    %esi,%edx
  add    $0x1,%edi
  cmp    %edx,%ecx
  jle    L33
L13:
  lea    (%rdi,%rdx,1),%eax
  cmp    %eax,%r12d
  mov    %eax,%edx
  cmovle %r12d,%edx
  test   %r12d,%r12d
  cmovne %edx,%eax
  add    $0x1,%r13d
  mov    %eax,%r12d
  cmp    %r13d,0x8(%rsp)
  jge    L39
L20:
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  xor    %r12d,%r12d
  jmp    L20
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D13: %d %d %d


tool: D21: %d

tool: D5: Numero minimo de notas = %d


assistant: ```c
int main() {
  int n_casas, gramas, cambio, n, valor, notas, ctrl, menor = 0;
  scanf("%d %d %d\n", &n_casas, &gramas, &cambio);
  for (int i = 1; i <= n_casas; i++) {
    scanf("%d", &n);
    valor = gramas * cambio;
    notas = 0;
    ctrl = n;
    while (valor >= n) {
      if (ctrl * n <= valor)
        ctrl = ctrl * n;
      else {
        valor = valor - ctrl;
        ctrl = n;
        notas++;
      }
    }
    notas = notas + valor;
    if (menor == 0)
      menor = notas;
    else if (notas < menor)
      menor = notas;
  }
  printf("Numero minimo de notas = %d\n", menor);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_getgrnam_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
L39:
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <getgrnam_r@plt>
  mov    %eax,-0x4(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L5
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L8
L5:
  nop
  jmp    L39
L8:
  nop
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _getgrnam_r(const char *name, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrnam_r(name, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return (rc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_getgrnam_r>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%rbx
L3:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <getgrnam_r@plt>
  mov    D2(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L3
  test   %eax,%eax
  je     L1
  movq   $0x0,(%rbx)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _getgrnam_r(const char *name, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrnam_r(name, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return (rc);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_getgrnam_r>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%r13
L8:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <getgrnam_r@plt>
  cmp    %eax,0x0(%r13)
  je     L8
  test   %eax,%eax
  je     L11
  movq   $0x0,(%rbx)
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _getgrnam_r(const char *name, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrnam_r(name, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return (rc);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_getgrnam_r>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%r13
L4:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <getgrnam_r@plt>
  cmp    %eax,0x0(%r13)
  je     L4
  test   %eax,%eax
  je     L15
  movq   $0x0,(%rbx)
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _getgrnam_r(const char *name, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrnam_r(name, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return (rc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skipchunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  and    $0x7,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  jmp    L24
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <nextword@plt>
  subq   $0x8,-0x20(%rbp)
L24:
  cmpq   $0x0,-0x20(%rbp)
  jne    L15
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <nextword@plt>
L20:
  nop
  leave
  ret
```

assistant: ```c
void skipchunk(int n, size_t size) {
  size_t rest = size % sizeof(size_t);
  size -= rest;
  while (size > 0) {
    nextword(n);
    size -= sizeof(size_t);
  }
  if (rest != 0)
    nextword(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipchunk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%r12
  and    $0x7,%r12d
  and    $0xfffffffffffffff8,%rbx
  je     L11
L26:
  mov    %ebp,%edi
  call   <nextword@plt>
  sub    $0x8,%rbx
  jne    L26
L11:
  test   %r12,%r12
  jne    L39
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    %ebp,%edi
  call   <nextword@plt>
  jmp    L16
```

assistant: ```c
void skipchunk(int n, size_t size) {
  size_t rest = size % sizeof(size_t);
  size -= rest;
  while (size > 0) {
    nextword(n);
    size -= sizeof(size_t);
  }
  if (rest != 0)
    nextword(n);
}
```