ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<inner_product>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %edx,%edx
  jne    L4
  ret
L4:
  sub    $0x18,%rsp
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%rsp)
  sub    $0x1,%edx
  add    $0x8,%rsi
  add    $0x8,%rdi
  call   <inner_product>
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
double inner_product(double *a, double *b, int n) {
  if (n == 0) {
    return 0.0;
  } else {
    return ((*a) * (*b)) + inner_product((a + 1), (b + 1), n - 1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<inner_product>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %edx,%edx
  jne    L18
  ret
  nopl   (%rax)
L18:
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  movapd %xmm0,%xmm2
  cmp    $0x1,%edx
  jne    L36
L29:
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  movsd  0x8(%rdi),%xmm2
  mulsd  0x8(%rsi),%xmm2
  cmp    $0x2,%edx
  jne    L21
  addsd  %xmm0,%xmm2
  jmp    L29
  nopl   (%rax)
L21:
  sub    $0x28,%rsp
  movsd  0x10(%rdi),%xmm0
  sub    $0x3,%edx
  add    $0x18,%rsi
  mulsd  -0x8(%rsi),%xmm0
  add    $0x18,%rdi
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <inner_product>
  addsd  0x8(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  add    $0x28,%rsp
  addsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double inner_product(double *a, double *b, int n) {
  if (n == 0) {
    return 0.0;
  } else {
    return ((*a) * (*b)) + inner_product((a + 1), (b + 1), n - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inner_product>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %edx,%edx
  jne    L16
  ret
  nopl   (%rax)
L16:
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  movapd %xmm0,%xmm2
  cmp    $0x1,%edx
  jne    L38
L21:
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  movsd  0x8(%rdi),%xmm2
  mulsd  0x8(%rsi),%xmm2
  cmp    $0x2,%edx
  jne    L14
  addsd  %xmm0,%xmm2
  jmp    L21
  nopl   (%rax)
L14:
  sub    $0x28,%rsp
  movsd  0x10(%rdi),%xmm0
  sub    $0x3,%edx
  add    $0x18,%rsi
  mulsd  -0x8(%rsi),%xmm0
  add    $0x18,%rdi
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <inner_product>
  addsd  0x8(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  add    $0x28,%rsp
  addsd  %xmm0,%xmm2
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double inner_product(double *a, double *b, int n) {
  if (n == 0) {
    return 0.0;
  } else {
    return ((*a) * (*b)) + inner_product((a + 1), (b + 1), n - 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isAbundant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L29
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  cmp    %eax,-0xc(%rbp)
  jne    L60
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  jmp    L20
L60:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L29
  movl   $0x1,-0x4(%rbp)
L29:
  subl   $0x1,-0xc(%rbp)
L59:
  cmpl   $0x1,-0xc(%rbp)
  jle    L45
  cmpl   $0x0,-0x4(%rbp)
  je     L6
L45:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int isAbundant(int number) {
  int i = (int)sqrt(number), sum = 1, isAbundant = 0;
  while (i > 1 && isAbundant == 0) {
    if (number % i == 0) {
      if (i == number / i) {
        sum += i;
      } else {
        sum += (i + number / i);
      }
      if (sum > number) {
        isAbundant = 1;
      }
    }
    i--;
  }
  return isAbundant;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isAbundant>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L33
  mov    %eax,%ecx
  mov    $0x1,%esi
  jmp    L50
L7:
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  je     L48
L50:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L7
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%edx
  lea    (%rax,%rcx,1),%edi
  add    %edi,%esi
  cmp    %ecx,%eax
  cmove  %edx,%esi
  cmp    %ebx,%esi
  jle    L7
  mov    $0x1,%eax
L12:
  pop    %rbx
  ret
L48:
  mov    $0x0,%eax
  jmp    L12
L33:
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
int isAbundant(int number) {
  int i = (int)sqrt(number), sum = 1, isAbundant = 0;
  while (i > 1 && isAbundant == 0) {
    if (number % i == 0) {
      if (i == number / i) {
        sum += i;
      } else {
        sum += (i + number / i);
      }
      if (sum > number) {
        isAbundant = 1;
      }
    }
    i--;
  }
  return isAbundant;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isAbundant>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L57
  mov    %eax,%ecx
  mov    $0x1,%esi
  jmp    L15
  nopl   0x0(%rax)
L12:
  lea    (%rax,%rcx,1),%edi
  lea    (%rsi,%rcx,1),%edx
  add    %edi,%esi
  cmp    %ecx,%eax
  cmove  %edx,%esi
  xor    %r8d,%r8d
  cmp    %r12d,%esi
  setg   %r8b
  setle  %al
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  jle    L6
L7:
  test   %al,%al
  je     L6
L15:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L12
  sub    $0x1,%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%ecx
  jg     L7
L6:
  mov    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  xor    %r8d,%r8d
  pop    %r12
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isAbundant(int number) {
  int i = (int)sqrt(number), sum = 1, isAbundant = 0;
  while (i > 1 && isAbundant == 0) {
    if (number % i == 0) {
      if (i == number / i) {
        sum += i;
      } else {
        sum += (i + number / i);
      }
      if (sum > number) {
        isAbundant = 1;
      }
    }
    i--;
  }
  return isAbundant;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isAbundant>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L43
  mov    %eax,%ecx
  mov    $0x1,%esi
  jmp    L50
  nopl   0x0(%rax)
L2:
  lea    (%rax,%rcx,1),%edi
  lea    (%rsi,%rcx,1),%edx
  add    %edi,%esi
  cmp    %ecx,%eax
  cmove  %edx,%esi
  xor    %r8d,%r8d
  cmp    %r12d,%esi
  setg   %r8b
  setle  %al
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  jle    L3
L57:
  test   %al,%al
  je     L3
L50:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L2
  sub    $0x1,%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  cmp    $0x1,%ecx
  jg     L57
L3:
  mov    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  xor    %r8d,%r8d
  pop    %r12
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isAbundant(int number) {
  int i = (int)sqrt(number), sum = 1, isAbundant = 0;
  while (i > 1 && isAbundant == 0) {
    if (number % i == 0) {
      if (i == number / i) {
        sum += i;
      } else {
        sum += (i + number / i);
      }
      if (sum > number) {
        isAbundant = 1;
      }
    }
    i--;
  }
  return isAbundant;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movw   $0x64,-0x1a(%rbp)
  movw   $0x1,-0x1c(%rbp)
  jmp    L16
L3:
  movzwl -0x1c(%rbp),%edx
  movzwl -0x1c(%rbp),%eax
  imul   %edx,%eax
  cltq
  add    %rax,-0x18(%rbp)
  movzwl -0x1c(%rbp),%eax
  add    %rax,-0x10(%rbp)
  movzwl -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x1c(%rbp)
L16:
  movzwl -0x1c(%rbp),%eax
  cmp    -0x1a(%rbp),%ax
  jbe    L3
  mov    -0x10(%rbp),%rax
  imul   %rax,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D10
type: string

tool: D15: Sum of squares ( <= 10): %i


tool: D14: Square of sums ( <= 10): %i


tool: D10: 
The difference bewteen the square of sums and sum of squares is: %i

assistant: ```c
int main(void) {
  unsigned long sum_square = 0, square_sum = 0, ans;
  unsigned short int MAX = 100, i;
  for (i = 1; i <= MAX; i++) {
    sum_square += (i * i);
    square_sum += i;
  }
  square_sum *= square_sum;
  printf("Sum of squares ( <= 10): %i\n", sum_square);
  printf("Square of sums ( <= 10): %i\n", square_sum);
  ans = square_sum - sum_square;
  printf("\nThe difference bewteen the square of sums and sum of squares is: %i", ans);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%eax
  mov    $0x0,%ebx
L2:
  mov    %eax,%edx
  imul   %eax,%edx
  movslq %edx,%rdx
  add    %rdx,%rbx
  add    $0x1,%eax
  cmp    $0x65,%eax
  jne    L2
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1852324,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x1852324,%esi
  sub    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string
name: disassemble_data
arguments: label: D27
data_type: string
name: disassemble_data
arguments: label: D29
data_type: string

tool: D8: Sum of squares ( <= 10): %i


tool: D27: Square of sums ( <= 10): %i


tool: D29: 
The difference bewteen the square of sums and sum of squares is: %i

assistant: ```c
int main(void) {
  unsigned long sum_square = 0, square_sum = 0, ans;
  unsigned short int MAX = 100, i;
  for (i = 1; i <= MAX; i++) {
    sum_square += (i * i);
    square_sum += i;
  }
  square_sum *= square_sum;
  printf("Sum of squares ( <= 10): %i\n", sum_square);
  printf("Square of sums ( <= 10): %i\n", square_sum);
  ans = square_sum - sum_square;
  printf("\nThe difference bewteen the square of sums and sum of squares is: %i", ans);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%eax
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  mov    %eax,%edx
  imul   %eax,%edx
  add    $0x1,%eax
  movslq %edx,%rdx
  add    %rdx,%rbx
  cmp    $0x65,%eax
  jne    L7
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x1852324,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x1852324,%esi
  lea    D16(%rip),%rdi
  sub    %rbx,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D29
datatype: string
name: unpack_data
arguments: data_label: D19
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string

tool: D29: Sum of squares ( <= 10): %i


tool: D19: Square of sums ( <= 10): %i


tool: D16: 
The difference bewteen the square of sums and sum of squares is: %i

assistant: ```c
int main(void) {
  unsigned long sum_square = 0, square_sum = 0, ans;
  unsigned short int MAX = 100, i;
  for (i = 1; i <= MAX; i++) {
    sum_square += (i * i);
    square_sum += i;
  }
  square_sum *= square_sum;
  printf("Sum of squares ( <= 10): %i\n", sum_square);
  printf("Square of sums ( <= 10): %i\n", square_sum);
  ans = square_sum - sum_square;
  printf("\nThe difference bewteen the square of sums and sum of squares is: %i", ans);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x529ae,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1852324,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x17ff976,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type: string
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D12
type: string

tool: D22: Sum of squares ( <= 10): %i


tool: D13: Square of sums ( <= 10): %i


tool: D12: 
The difference bewteen the square of sums and sum of squares is: %i

assistant: ```c
int main(void) {
  unsigned long sum_square = 0, square_sum = 0, ans;
  unsigned short int MAX = 100, i;
  for (i = 1; i <= MAX; i++) {
    sum_square += (i * i);
    square_sum += i;
  }
  square_sum *= square_sum;
  printf("Sum of squares ( <= 10): %i\n", sum_square);
  printf("Square of sums ( <= 10): %i\n", square_sum);
  ans = square_sum - sum_square;
  printf("\nThe difference bewteen the square of sums and sum of squares is: %i", ans);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<walk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L36
L40:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L40
  movl   $0x0,-0x10(%rbp)
  jmp    L61
L39:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L97
L90:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  jne    L73
  mov    $0x20,%edi
  call   <putchar@plt>
L73:
  addl   $0x1,-0xc(%rbp)
L97:
  cmpl   $0x7,-0xc(%rbp)
  jle    L90
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L55:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L29
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L72
L29:
  mov    $0x3f,%eax
L72:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L44:
  cmpl   $0x7,-0xc(%rbp)
  jle    L55
  subq   $0x8,-0x8(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L61:
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L39
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D15: %p: 

tool: D10: %02hhx

assistant: ```c
void walk(void *a, int bytes) {
  int i;
  int j;
  char *addr = a;
  while (((long)addr) % 8)
    addr++;
  for (i = 0; i < bytes / 8; i++) {
    printf("%p: ", addr);
    for (j = 0; j < 8; j++) {
      printf("%02hhx", addr[j]);
      if (j % 4 == 3)
        printf(" ");
    }
    for (j = 0; j < 8; j++)
      printf("%c", isprint(addr[j]) ? addr[j] : '?');
    addr -= 8;
    printf("\n");
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   $0x7,%dil
  je     L96
L86:
  add    $0x1,%rdi
  test   $0x7,%dil
  jne    L86
L96:
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x7,%esi
  jle    L27
  lea    0x8(%rdi),%r12
  movl   $0x0,0x8(%rsp)
  lea    D13(%rip),%r14
  mov    $0x3f,%r13d
  jmp    L30
L111:
  add    $0x1,%rbx
L48:
  cmp    $0x8,%rbx
  je     L10
  movsbl (%r15,%rbx,1),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x3,%eax
  jne    L111
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L111
L101:
  call   <putchar@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r12
  je     L40
L10:
  movsbl 0x0(%rbp),%edi
  call   <isprint@plt>
  mov    %r13d,%edi
  test   %rax,%rax
  je     L101
  movsbl 0x0(%rbp),%edi
  jmp    L101
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  sub    $0x8,%r12
  cmp    0xc(%rsp),%eax
  jge    L27
L30:
  lea    -0x8(%r12),%rbp
  mov    %rbp,%r15
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x8(%r12),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  jmp    L48
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D13: %02hhx

tool: D6: %p: 

assistant: ```c
void walk(void *a, int bytes) {
  int i;
  int j;
  char *addr = a;
  while (((long)addr) % 8)
    addr++;
  for (i = 0; i < bytes / 8; i++) {
    printf("%p: ", addr);
    for (j = 0; j < 8; j++) {
      printf("%02hhx", addr[j]);
      if (j % 4 == 3)
        printf(" ");
    }
    for (j = 0; j < 8; j++)
      printf("%c", isprint(addr[j]) ? addr[j] : '?');
    addr -= 8;
    printf("\n");
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   $0x7,%dil
  je     L68
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rdi
  test   $0x7,%dil
  jne    L16
L68:
  test   %esi,%esi
  lea    0x7(%rsi),%r14d
  cmovns %esi,%r14d
  sar    $0x3,%r14d
  mov    %r14d,0xc(%rsp)
  cmp    $0x7,%esi
  jle    L47
  lea    0x8(%rdi),%rbx
  xor    %r13d,%r13d
  lea    D7(%rip),%r15
  lea    D8(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbx,%rbp
  sub    $0x8,%rbx
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    $0x1,%r14d
  call   <printf@plt>
  movsbl -0x8(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L95
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%r14
L95:
  cmp    $0x8,%r14
  je     L54
  movsbl (%rbx,%r14,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L51
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L51
L54:
  mov    %rbx,%r14
  nopl   0x0(%rax,%rax,1)
L33:
  movsbl (%r14),%edi
  call   <isprint@plt>
  mov    $0x3f,%edi
  test   %rax,%rax
  je     L63
  movsbl (%r14),%edi
L63:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %rbp,%r14
  jne    L33
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0xc(%rsp)
  jg     L6
L47:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string

tool: D7: %p: 

tool: D8: %02hhx

assistant: ```c
void walk(void *a, int bytes) {
  int i;
  int j;
  char *addr = a;
  while (((long)addr) % 8)
    addr++;
  for (i = 0; i < bytes / 8; i++) {
    printf("%p: ", addr);
    for (j = 0; j < 8; j++) {
      printf("%02hhx", addr[j]);
      if (j % 4 == 3)
        printf(" ");
    }
    for (j = 0; j < 8; j++)
      printf("%c", isprint(addr[j]) ? addr[j] : '?');
    addr -= 8;
    printf("\n");
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<walk>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   $0x7,%dil
  je     L116
  nopl   0x0(%rax,%rax,1)
L55:
  add    $0x1,%rdi
  test   $0x7,%dil
  jne    L55
L116:
  test   %esi,%esi
  lea    0x7(%rsi),%r14d
  cmovns %esi,%r14d
  sar    $0x3,%r14d
  mov    %r14d,0xc(%rsp)
  cmp    $0x7,%esi
  jle    L117
  lea    0x8(%rdi),%rbx
  xor    %r13d,%r13d
  lea    D7(%rip),%r15
  lea    D16(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbx,%rbp
  sub    $0x8,%rbx
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  mov    $0x1,%r14d
  call   <printf@plt>
  movsbl -0x8(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r14
  cmp    $0x8,%r14
  je     L9
L70:
  movsbl (%rbx,%r14,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L35
  mov    $0x20,%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    $0x8,%r14
  jne    L70
L9:
  mov    %rbx,%r14
  nopl   0x0(%rax,%rax,1)
L95:
  movsbl (%r14),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L25
  movsbl (%r14),%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %rbp,%r14
  jne    L95
L64:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0xc(%rsp)
  jg     L21
L117:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x3f,%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L95
  jmp    L64
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D16
type_infered: string

tool: D7: %p: 

tool: D16: %02hhx

assistant: ```c
void walk(void *a, int bytes) {
  int i;
  int j;
  char *addr = a;
  while (((long)addr) % 8)
    addr++;
  for (i = 0; i < bytes / 8; i++) {
    printf("%p: ", addr);
    for (j = 0; j < 8; j++) {
      printf("%02hhx", addr[j]);
      if (j % 4 == 3)
        printf(" ");
    }
    for (j = 0; j < 8; j++)
      printf("%c", isprint(addr[j]) ? addr[j] : '?');
    addr -= 8;
    printf("\n");
  }
  return;
}
```