ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L35
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L43
  mov    %rax,%rdx
L16:
  add    $0x1,%rbp
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jne    L16
L25:
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L36
L12:
  add    $0x1,%rbx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  movzbl (%rbx),%ecx
  test   %cl,%cl
  jne    L12
L36:
  movb   $0x0,(%rdx)
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %rax,%rdx
  jmp    L25
```

assistant: ```c
char *str2(const char *a, const char *b) {
  char *q, *p;
  p = q = malloc(strlen(a) + strlen(b) + 2);
  if (!q)
    return q;
  while (*a)
    *p++ = *a++;
  while (*b)
    *p++ = *b++;
  *p = '\0';
  return q;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str2>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  movzbl 0x0(%rbp),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L27
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbp
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jne    L45
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L40
  nopl   0x0(%rax)
L32:
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rbx
L27:
  movzbl (%rbx),%ecx
  test   %cl,%cl
  jne    L32
L40:
  movb   $0x0,(%rdx)
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str2(const char *a, const char *b) {
  char *q, *p;
  p = q = malloc(strlen(a) + strlen(b) + 2);
  if (!q)
    return q;
  while (*a)
    *p++ = *a++;
  while (*b)
    *p++ = *b++;
  *p = '\0';
  return q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str2>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L40
  movzbl 0x0(%rbp),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L44
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rbp
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  jne    L9
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L1
  nopl   0x0(%rax)
L15:
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  add    $0x1,%rbx
L44:
  movzbl (%rbx),%ecx
  test   %cl,%cl
  jne    L15
L1:
  movb   $0x0,(%rdx)
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str2(const char *a, const char *b) {
  char *q, *p;
  p = q = malloc(strlen(a) + strlen(b) + 2);
  if (!q)
    return q;
  while (*a)
    *p++ = *a++;
  while (*b)
    *p++ = *b++;
  *p = '\0';
  return q;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <faca@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int x) {
  int y;
  y = faca(x);
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <faca@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int x) {
  int y;
  y = faca(x);
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  jmp    1050 <faca@plt>
```

assistant: ```c
int main(int x) {
  int y;
  y = faca(x);
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  jmp    1050 <faca@plt>
```

assistant: ```c
int main(int x) {
  int y;
  y = faca(x);
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  jmp    L29
L86:
  add    $0x1,%r12d
L29:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L86
  movzbl 0x0(%rbp),%eax
  cmp    $0x2d,%al
  je     L34
  sub    $0x2b,%eax
  movl   $0x1,0xc(%rsp)
  test   $0xfd,%al
  je     L12
L2:
  movslq %r12d,%r13
  add    %r15,%r13
  mov    %r13,%rbp
  pxor   %xmm3,%xmm3
  movsd  %xmm3,(%rsp)
  jmp    L39
L34:
  movl   $0xffffffff,0xc(%rsp)
L12:
  add    $0x1,%r12d
  jmp    L2
L48:
  movsd  (%rsp),%xmm0
  mulsd  D8(%rip),%xmm0
  movsbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  add    $0x1,%rbp
L39:
  mov    %r12d,%ebx
  sub    %r13d,%ebx
  add    %ebp,%ebx
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L48
  cmpb   $0x2e,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  movslq %ebx,%rbx
  add    %r15,%rbx
  mov    D1(%rip),%rbp
  jmp    L53
L24:
  movsd  (%rsp),%xmm0
  mulsd  D8(%rip),%xmm0
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  movq   %rbp,%xmm2
  mulsd  D8(%rip),%xmm2
  movq   %xmm2,%rbp
  add    $0x1,%rbx
L53:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L24
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0xc(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  movq   %rbp,%xmm5
  divsd  %xmm5,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: f64
name: parse_data
arguments: data_label: D1
type: f64

tool: D8: 10

tool: D1: 1

assistant: ```c
double atof(const char *nptr) {
  double val, power;
  int i, sign;
  const char *s = nptr;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = 10.0 * val + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = 10.0 * val + (s[i] - '0');
    power *= 10;
  }
  return sign * val / power;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  jmp    L61
  nopl   (%rax)
L19:
  add    $0x1,%r12d
L61:
  movsbl 0x0(%rbp),%edi
  mov    %rbp,%r13
  add    $0x1,%rbp
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  movsbl 0x0(%r13),%edi
  cmp    $0x2d,%dil
  je     L44
  movl   $0x1,0x1c(%rsp)
  movslq %r12d,%r13
  cmp    $0x2b,%dil
  je     L9
L74:
  add    %rbx,%r13
  pxor   %xmm6,%xmm6
  mov    %r13,%r15
  movsd  %xmm6,0x8(%rsp)
  jmp    L54
  nop
L37:
  movsbl -0x1(%r15),%eax
  movsd  D14(%rip),%xmm0
  pxor   %xmm1,%xmm1
  mulsd  0x8(%rsp),%xmm0
  movsbl (%r15),%edi
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
L54:
  call   <isdigit@plt>
  mov    %r12d,%ebp
  mov    %r15,%r14
  sub    %r13d,%ebp
  add    %r15d,%ebp
  add    $0x1,%r15
  test   %rax,%rax
  jne    L37
  movsbl (%r14),%edi
  movslq %ebp,%rax
  cmp    $0x2e,%dil
  jne    L69
  add    $0x1,%ebp
  movslq %ebp,%rax
  movsbl (%rbx,%rax,1),%edi
L69:
  movsd  D10(%rip),%xmm7
  add    %rax,%rbx
  movsd  %xmm7,0x10(%rsp)
  jmp    L3
L2:
  movsbl -0x1(%rbx),%eax
  pxor   %xmm1,%xmm1
  movsbl (%rbx),%edi
  movsd  D14(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  sub    $0x30,%eax
  movsd  D14(%rip),%xmm2
  cvtsi2sd %eax,%xmm1
  mulsd  0x10(%rsp),%xmm2
  addsd  %xmm0,%xmm1
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
L3:
  call   <isdigit@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L2
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x1c(%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L44:
  movl   $0xffffffff,0x1c(%rsp)
L9:
  add    $0x1,%r12d
  movslq %r12d,%r13
  movsbl (%rbx,%r13,1),%edi
  jmp    L74
```

tool_calls: name: retrieve_data
arguments: tag: D14
type: f64
name: retrieve_data
arguments: tag: D10
type: f64

tool: D14: 10

tool: D10: 1

assistant: ```c
double atof(const char *nptr) {
  double val, power;
  int i, sign;
  const char *s = nptr;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = 10.0 * val + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = 10.0 * val + (s[i] - '0');
    power *= 10;
  }
  return sign * val / power;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atof>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  jmp    L75
  nopl   (%rax)
L45:
  add    $0x1,%r13d
L75:
  movsbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
  movzbl (%r12),%eax
  cmp    $0x2d,%al
  je     L18
  mov    $0x1,%r12d
  cmp    $0x2b,%al
  je     L20
L40:
  movslq %r13d,%r14
  pxor   %xmm6,%xmm6
  add    %rbp,%r14
  movsd  %xmm6,(%rsp)
  mov    %r14,%rbx
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L42:
  movsbl (%rbx),%eax
  movsd  D7(%rip),%xmm0
  pxor   %xmm1,%xmm1
  add    $0x1,%rbx
  mulsd  (%rsp),%xmm0
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
L82:
  mov    %r13d,%r15d
  movsbl (%rbx),%edi
  sub    %r14d,%r15d
  add    %ebx,%r15d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L42
  xor    %eax,%eax
  cmpb   $0x2e,(%rbx)
  movsd  D27(%rip),%xmm7
  sete   %al
  add    %eax,%r15d
  movsd  %xmm7,0x8(%rsp)
  movslq %r15d,%r15
  add    %r15,%rbp
  jmp    L3
  nop
L53:
  movsbl 0x0(%rbp),%eax
  pxor   %xmm1,%xmm1
  add    $0x1,%rbp
  movsd  D7(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  movsd  D7(%rip),%xmm2
  mulsd  0x8(%rsp),%xmm2
  sub    $0x30,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
L3:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L53
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L18:
  mov    $0xffffffff,%r12d
L20:
  add    $0x1,%r13d
  jmp    L40
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: f64
name: unpack_data
arguments: tag: D27
datatype: f64

tool: D7: 10

tool: D27: 1

assistant: ```c
double atof(const char *nptr) {
  double val, power;
  int i, sign;
  const char *s = nptr;
  for (i = 0; isspace(s[i]); i++)
    ;
  sign = (s[i] == '-') ? -1 : 1;
  if (s[i] == '+' || s[i] == '-')
    i++;
  for (val = 0.0; isdigit(s[i]); i++)
    val = 10.0 * val + (s[i] - '0');
  if (s[i] == '.')
    i++;
  for (power = 1.0; isdigit(s[i]); i++) {
    val = 10.0 * val + (s[i] - '0');
    power *= 10;
  }
  return sign * val / power;
}
```
user: What is the c source code of the assembly code below:

```asm
<BsyWit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,%edx
  mov    %ax,-0x14(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x18(%rbp),%edx
  movzwl -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RegWriteA_LC898122AF@plt>
  movb   $0x1,-0x9(%rbp)
  jmp    L17
L24:
  movzwl -0x14(%rbp),%eax
  lea    -0x9(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl -0x9(%rbp),%eax
  and    -0x18(%rbp),%al
  and    $0xf,%eax
  mov    %al,-0x9(%rbp)
L17:
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  jne    L24
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void BsyWit(unsigned short UsTrgAdr, unsigned char UcTrgDat) {
  unsigned char UcFlgVal;
  RegWriteA_LC898122AF(UsTrgAdr, UcTrgDat);
  UcFlgVal = 1;
  while (UcFlgVal) {
    RegReadA_LC898122AF(UsTrgAdr, &UcFlgVal);
    UcFlgVal &= (UcTrgDat & 0x0F);
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BsyWit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl %di,%ebx
  movzbl %sil,%esi
  mov    %ebx,%edi
  call   <RegWriteA_LC898122AF@plt>
  movb   $0x1,0x7(%rsp)
  lea    0x7(%rsp),%rbp
L15:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RegReadA_LC898122AF@plt>
  mov    %r12d,%eax
  and    0x7(%rsp),%al
  and    $0xf,%eax
  mov    %al,0x7(%rsp)
  test   %al,%al
  jne    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void BsyWit(unsigned short UsTrgAdr, unsigned char UcTrgDat) {
  unsigned char UcFlgVal;
  RegWriteA_LC898122AF(UsTrgAdr, UcTrgDat);
  UcFlgVal = 1;
  while (UcFlgVal) {
    RegReadA_LC898122AF(UsTrgAdr, &UcFlgVal);
    UcFlgVal &= (UcTrgDat & 0x0F);
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BsyWit>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  movzbl %sil,%esi
  push   %rbp
  push   %rbx
  movzwl %di,%ebx
  mov    %ebx,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <RegWriteA_LC898122AF@plt>
  movb   $0x1,0x7(%rsp)
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%eax
  and    %r12d,%eax
  and    $0xf,%eax
  mov    %al,0x7(%rsp)
  test   %al,%al
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void BsyWit(unsigned short UsTrgAdr, unsigned char UcTrgDat) {
  unsigned char UcFlgVal;
  RegWriteA_LC898122AF(UsTrgAdr, UcTrgDat);
  UcFlgVal = 1;
  while (UcFlgVal) {
    RegReadA_LC898122AF(UsTrgAdr, &UcFlgVal);
    UcFlgVal &= (UcTrgDat & 0x0F);
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BsyWit>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  movzbl %sil,%esi
  push   %rbp
  push   %rbx
  movzwl %di,%ebx
  mov    %ebx,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <RegWriteA_LC898122AF@plt>
  movb   $0x1,0x7(%rsp)
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RegReadA_LC898122AF@plt>
  movzbl 0x7(%rsp),%eax
  and    %r12d,%eax
  and    $0xf,%eax
  mov    %al,0x7(%rsp)
  test   %al,%al
  jne    L18
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void BsyWit(unsigned short UsTrgAdr, unsigned char UcTrgDat) {
  unsigned char UcFlgVal;
  RegWriteA_LC898122AF(UsTrgAdr, UcTrgDat);
  UcFlgVal = 1;
  while (UcFlgVal) {
    RegReadA_LC898122AF(UsTrgAdr, &UcFlgVal);
    UcFlgVal &= (UcTrgDat & 0x0F);
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_uint@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assume@plt>
  jmp    L11
L32:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  cmp    %eax,-0x8(%rbp)
  jae    L3
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L3:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L32
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 1;
  unsigned int y = __VERIFIER_nondet_uint();
  __VERIFIER_assume(y > 0);
  while (x < y) {
    if (x < y / x) {
      x *= x;
    } else {
      x++;
    }
  }
  __VERIFIER_assert(x == y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_uint@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  setne  %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assume@plt>
  cmp    $0x1,%ebx
  jbe    L48
  mov    $0x1,%ecx
  jmp    L41
L49:
  add    $0x1,%ecx
L7:
  cmp    %ebx,%ecx
  jae    L3
L41:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ecx
  cmp    %ecx,%eax
  jbe    L49
  imul   %ecx,%ecx
  jmp    L7
L48:
  mov    $0x1,%ecx
L3:
  cmp    %ecx,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 1;
  unsigned int y = __VERIFIER_nondet_uint();
  __VERIFIER_assume(y > 0);
  while (x < y) {
    if (x < y / x) {
      x *= x;
    } else {
      x++;
    }
  }
  __VERIFIER_assert(x == y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_uint@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebp
  setne  %dil
  call   <__VERIFIER_assume@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    $0x1,%ebp
  ja     L8
  mov    %ebp,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 1;
  unsigned int y = __VERIFIER_nondet_uint();
  __VERIFIER_assume(y > 0);
  while (x < y) {
    if (x < y / x) {
      x *= x;
    } else {
      x++;
    }
  }
  __VERIFIER_assert(x == y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_uint@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebp
  setne  %dil
  call   <__VERIFIER_assume@plt>
  cmp    $0x1,%ebp
  jbe    L0
L15:
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebp,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 1;
  unsigned int y = __VERIFIER_nondet_uint();
  __VERIFIER_assume(y > 0);
  while (x < y) {
    if (x < y / x) {
      x *= x;
    } else {
      x++;
    }
  }
  __VERIFIER_assert(x == y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <urandom@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", urandom());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <urandom@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", urandom());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <urandom@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", urandom());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <urandom@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("%d\n", urandom());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dynamic_vector_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  sub    -0x48(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x1,%eax
  sub    -0x38(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  imul   -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    $0x8,%esi
  mov    %rdx,%rdi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    $0x1,%eax
  sub    -0x48(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  jmp    L18
L3:
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x30(%rbp)
L18:
  mov    -0x30(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jle    L3
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct dynamic_vector ***dynamic_vector_matrix(nrl, nrh, ncl, nch)
long nch, ncl, nrh, nrl;
{
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  struct dynamic_vector ***m;
  m = (struct dynamic_vector ***)calloc(nrow + 1, sizeof(struct dynamic_vector **));
  m += 1 - nrl;
  m[nrl] = (struct dynamic_vector **)calloc(nrow * ncol + 1, sizeof(struct dynamic_vector *));
  m[nrl] += 1 - ncl;
  for (i = nrl + 1; i <= nrh; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```