ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putf8_strlen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L14
L9:
  add    $0x1,%ebp
L14:
  mov    %rbx,%rdi
  call   <putf8_seqlen@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L9
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int putf8_strlen(char *s) {
  int count = 0;
  while (*(s += putf8_seqlen(s)))
    count++;
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putf8_strlen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12d
L9:
  mov    %rbx,%rdi
  call   <putf8_seqlen@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int putf8_strlen(char *s) {
  int count = 0;
  while (*(s += putf8_seqlen(s)))
    count++;
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putf8_strlen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12d
L15:
  mov    %rbx,%rdi
  call   <putf8_seqlen@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L19
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int putf8_strlen(char *s) {
  int count = 0;
  while (*(s += putf8_seqlen(s)))
    count++;
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readwin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getyx@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <wmove@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <winch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <wmove@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int readwin(WINDOW *win, int line, int col) {
  int oldline, oldcol;
  int c;
  getyx(win, oldline, oldcol);
  wmove(win, line, col);
  c = winch(win);
  wmove(win, oldline, oldcol);
  return (c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readwin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    $0x0,%r13d
  mov    %r13d,%edx
  mov    $0x0,%r12d
  mov    %r12d,%esi
  call   <getyx@plt>
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <wmove@plt>
  mov    %rbx,%rdi
  call   <winch@plt>
  mov    %eax,%ebp
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <wmove@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int readwin(WINDOW *win, int line, int col) {
  int oldline, oldcol;
  int c;
  getyx(win, oldline, oldcol);
  wmove(win, line, col);
  c = winch(win);
  wmove(win, oldline, oldcol);
  return (c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readwin>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edx,%r13d
  mov    %r15d,%edx
  push   %r12
  mov    %esi,%r12d
  mov    %r14d,%esi
  push   %rbp
  mov    %rdi,%rbp
  call   <getyx@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <wmove@plt>
  mov    %rbp,%rdi
  call   <winch@plt>
  mov    %r15d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <wmove@plt>
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int readwin(WINDOW *win, int line, int col) {
  int oldline, oldcol;
  int c;
  getyx(win, oldline, oldcol);
  wmove(win, line, col);
  c = winch(win);
  wmove(win, oldline, oldcol);
  return (c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: string

tool: D2: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *(p + 1);
  printf("\n [%c]\n", c);
  free(p);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movb   $0x61,(%rax)
  movsbl 0x1(%rax),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *(p + 1);
  printf("\n [%c]\n", c);
  free(p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%edi
  call   <malloc@plt>
  lea    D9(%rip),%rdi
  movb   $0x61,(%rax)
  movsbl 0x1(%rax),%esi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *(p + 1);
  printf("\n [%c]\n", c);
  free(p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%edi
  call   <malloc@plt>
  lea    D5(%rip),%rdi
  movb   $0x61,(%rax)
  movsbl 0x1(%rax),%esi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: 
 [%c]


assistant: ```c
int main(void) {
  char *p = malloc(1);
  *p = 'a';
  char c = *(p + 1);
  printf("\n [%c]\n", c);
  free(p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tkeyisok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x1,%eax
  jmp    L17
L3:
  mov    $0x0,%eax
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: zdlPehvkuthSLH2345uhKSJe5lgk6ktn

assistant: ```c
int tkeyisok(char tkey[]) {
  if (strcmp(tkey, "zdlPehvkuthSLH2345uhKSJe5lgk6ktn") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tkeyisok>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: zdlPehvkuthSLH2345uhKSJe5lgk6ktn

assistant: ```c
int tkeyisok(char tkey[]) {
  if (strcmp(tkey, "zdlPehvkuthSLH2345uhKSJe5lgk6ktn") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tkeyisok>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: zdlPehvkuthSLH2345uhKSJe5lgk6ktn

assistant: ```c
int tkeyisok(char tkey[]) {
  if (strcmp(tkey, "zdlPehvkuthSLH2345uhKSJe5lgk6ktn") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<tkeyisok>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: zdlPehvkuthSLH2345uhKSJe5lgk6ktn

assistant: ```c
int tkeyisok(char tkey[]) {
  if (strcmp(tkey, "zdlPehvkuthSLH2345uhKSJe5lgk6ktn") == 0) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<executeLsCommand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %eax,%edi
  call   <opendir@plt>
  mov    %rax,-0x420(%rbp)
  jmp    L13
L4:
  mov    -0x418(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: %s	

assistant: ```c
int executeLsCommand() {
  char cwd[1024];
  DIR *dp;
  dp = opendir(getcwd(cwd, sizeof(cwd)));
  struct dirent *sd;
  while ((sd = readdir(dp)) != NULL) {
    printf("%s\t", sd->d_name);
  }
  printf("\n");
  closedir(dp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<executeLsCommand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x400,%esi
  call   <getcwd@plt>
  mov    %eax,%edi
  call   <opendir@plt>
  mov    %rax,%rbx
  lea    D1(%rip),%rbp
  jmp    L18
L21:
  mov    (%rax),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <closedir@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: %s	

assistant: ```c
int executeLsCommand() {
  char cwd[1024];
  DIR *dp;
  dp = opendir(getcwd(cwd, sizeof(cwd)));
  struct dirent *sd;
  while ((sd = readdir(dp)) != NULL) {
    printf("%s\t", sd->d_name);
  }
  printf("\n");
  closedir(dp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<executeLsCommand>:
  endbr64
  push   %rbp
  mov    $0x400,%esi
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getcwd@plt>
  mov    %eax,%edi
  call   <opendir@plt>
  mov    %rax,%rbp
  jmp    L29
L27:
  mov    (%rax),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %s	

assistant: ```c
int executeLsCommand() {
  char cwd[1024];
  DIR *dp;
  dp = opendir(getcwd(cwd, sizeof(cwd)));
  struct dirent *sd;
  while ((sd = readdir(dp)) != NULL) {
    printf("%s\t", sd->d_name);
  }
  printf("\n");
  closedir(dp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<executeLsCommand>:
  endbr64
  push   %rbp
  mov    $0x400,%esi
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <getcwd@plt>
  mov    %eax,%edi
  call   <opendir@plt>
  mov    %rax,%rbp
  jmp    L23
L5:
  mov    (%rax),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L23:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: %s	

assistant: ```c
int executeLsCommand() {
  char cwd[1024];
  DIR *dp;
  dp = opendir(getcwd(cwd, sizeof(cwd)));
  struct dirent *sd;
  while ((sd = readdir(dp)) != NULL) {
    printf("%s\t", sd->d_name);
  }
  printf("\n");
  closedir(dp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<glmProjectVector3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glmDotProduct3d@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x20(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <glmCopyVector3d@plt>
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <glmMultVectorByScalar3d@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <glmSubtractVector3d@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void glmProjectVector3d(double result[3], const double v[3], const double normal[3]) {
  double temp;
  double tempVector[3];
  temp = glmDotProduct3d(v, normal);
  glmCopyVector3d(normal, tempVector);
  glmMultVectorByScalar3d(tempVector, temp);
  glmSubtractVector3d(result, v, tempVector);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glmProjectVector3d>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rsi
  mov    %rbx,%rdi
  call   <glmDotProduct3d@plt>
  movq   %xmm0,%r14
  mov    %rsp,%r13
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <glmCopyVector3d@plt>
  movq   %r14,%xmm0
  mov    %r13,%rdi
  call   <glmMultVectorByScalar3d@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <glmSubtractVector3d@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void glmProjectVector3d(double result[3], const double v[3], const double normal[3]) {
  double temp;
  double tempVector[3];
  temp = glmDotProduct3d(v, normal);
  glmCopyVector3d(normal, tempVector);
  glmMultVectorByScalar3d(tempVector, temp);
  glmSubtractVector3d(result, v, tempVector);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmProjectVector3d>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <glmDotProduct3d@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <glmCopyVector3d@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r14,%rdi
  call   <glmMultVectorByScalar3d@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <glmSubtractVector3d@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void glmProjectVector3d(double result[3], const double v[3], const double normal[3]) {
  double temp;
  double tempVector[3];
  temp = glmDotProduct3d(v, normal);
  glmCopyVector3d(normal, tempVector);
  glmMultVectorByScalar3d(tempVector, temp);
  glmSubtractVector3d(result, v, tempVector);
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmProjectVector3d>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <glmDotProduct3d@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <glmCopyVector3d@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %r14,%rdi
  call   <glmMultVectorByScalar3d@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <glmSubtractVector3d@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void glmProjectVector3d(double result[3], const double v[3], const double normal[3]) {
  double temp;
  double tempVector[3];
  temp = glmDotProduct3d(v, normal);
  glmCopyVector3d(normal, tempVector);
  glmMultVectorByScalar3d(tempVector, temp);
  glmSubtractVector3d(result, v, tempVector);
}
```
user: What is the c source code of the assembly code below?

```asm
<aeron_counter_increment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  lock xadd %rax,(%rcx)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int64_t aeron_counter_increment(volatile int64_t *addr, int64_t value) {
  int64_t result = 0;
  do {
    __asm__ volatile("lock; xaddq %0, %1" : "=r"(result), "+m"(*addr) : "0"(value));
  } while (0);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aeron_counter_increment>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
int64_t aeron_counter_increment(volatile int64_t *addr, int64_t value) {
  int64_t result = 0;
  do {
    __asm__ volatile("lock; xaddq %0, %1" : "=r"(result), "+m"(*addr) : "0"(value));
  } while (0);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aeron_counter_increment>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
int64_t aeron_counter_increment(volatile int64_t *addr, int64_t value) {
  int64_t result = 0;
  do {
    __asm__ volatile("lock; xaddq %0, %1" : "=r"(result), "+m"(*addr) : "0"(value));
  } while (0);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<aeron_counter_increment>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
int64_t aeron_counter_increment(volatile int64_t *addr, int64_t value) {
  int64_t result = 0;
  do {
    __asm__ volatile("lock; xaddq %0, %1" : "=r"(result), "+m"(*addr) : "0"(value));
  } while (0);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_i_j>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x3c(%rbp)
  mov    -0x44(%rbp),%eax
  xor    -0x48(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L66
  mov    -0x44(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x48(%rbp),%eax
  and    $0x4,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x44(%rbp),%eax
  and    $0x2,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x48(%rbp),%eax
  and    $0x2,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x44(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x48(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jne    L22
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  test   %eax,%eax
L22:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L51
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  test   %eax,%eax
L51:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L21
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  test   %eax,%eax
L21:
  cmpl   $0x1,-0x3c(%rbp)
  jle    L66
  mov    $0x1,%eax
  jmp    L50
L66:
  mov    $0x0,%eax
L50:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int check_i_j(int i, int j) {
  int bit[4] = {0}, position = 0;
  if ((i & 8) != (j & 8)) {
    int i_d = i & 0x04, j_d = j & 0x04, i_r = i & 0x02, j_r = j & 0x02, i_c = i & 0x01, j_c = j & 0x01;
    i_d == j_d &&position++;
    i_r == j_r &&position++;
    i_c == j_c &&position++;
    if (position >= 2) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_i_j>:
  endbr64
  xor    %esi,%edi
  mov    %edi,%eax
  and    $0x8,%eax
  je     L3
  test   $0x4,%dil
  sete   %al
  movzbl %al,%eax
  mov    %edi,%edx
  and    $0x2,%edx
  cmp    $0x1,%edx
  adc    $0x0,%eax
  and    $0x1,%edi
  cmp    $0x1,%edi
  adc    $0x0,%eax
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int check_i_j(int i, int j) {
  int bit[4] = {0}, position = 0;
  if ((i & 8) != (j & 8)) {
    int i_d = i & 0x04, j_d = j & 0x04, i_r = i & 0x02, j_r = j & 0x02, i_c = i & 0x01, j_c = j & 0x01;
    i_d == j_d &&position++;
    i_r == j_r &&position++;
    i_c == j_c &&position++;
    if (position >= 2) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_i_j>:
  endbr64
  xor    %esi,%edi
  mov    %edi,%eax
  and    $0x8,%eax
  je     L18
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0x2,%edx
  and    $0x1,%eax
  and    $0x4,%edi
  jne    L23
  test   %edx,%edx
  jne    L25
  test   %eax,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  test   %edx,%edx
  jne    L28
L25:
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L18:
  ret
  nopl   (%rax)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_i_j(int i, int j) {
  int bit[4] = {0}, position = 0;
  if ((i & 8) != (j & 8)) {
    int i_d = i & 0x04, j_d = j & 0x04, i_r = i & 0x02, j_r = j & 0x02, i_c = i & 0x01, j_c = j & 0x01;
    i_d == j_d &&position++;
    i_r == j_r &&position++;
    i_c == j_c &&position++;
    if (position >= 2) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_i_j>:
  endbr64
  xor    %esi,%edi
  mov    %edi,%eax
  and    $0x8,%eax
  je     L6
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0x2,%edx
  and    $0x1,%eax
  and    $0x4,%edi
  jne    L4
  test   %edx,%edx
  jne    L39
  test   %eax,%eax
  mov    $0x1,%edx
  cmove  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  test   %edx,%edx
  jne    L38
L39:
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L6:
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_i_j(int i, int j) {
  int bit[4] = {0}, position = 0;
  if ((i & 8) != (j & 8)) {
    int i_d = i & 0x04, j_d = j & 0x04, i_r = i & 0x02, j_r = j & 0x02, i_c = i & 0x01, j_c = j & 0x01;
    i_d == j_d &&position++;
    i_r == j_r &&position++;
    i_c == j_c &&position++;
    if (position >= 2) {
      return 1;
    }
  }
  return 0;
}
```