ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scroll1>:
  endbr64
  push   %r12
  mov    $0xfffe,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <delay@plt>
  mov    $0xfffe,%edi
  call   <delay@plt>
  mov    $0x7fff,%edi
  call   <delay@plt>
  nop
L15:
  mov    %ebx,%r12d
  add    $0x28,%ebx
  mov    %ebx,%edi
  call   <vdp_raddr@plt>
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <_vram_read@plt>
  mov    %r12d,%edi
  call   <vdp_waddr@plt>
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <_vram_write@plt>
  cmp    $0x398,%ebx
  jne    L15
  xor    %edi,%edi
  mov    $0x28,%esi
  call   <_vram_write_run@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void scroll1() {
  char buf[40];
  unsigned int addr = 0x0000;
  delay(65534);
  delay(65534);
  delay(32767);
  for (; addr < (0x0000 + 40 * (24 - 1)); addr += 40) {
    vdp_raddr(addr + 40);
    _vram_read(buf, sizeof(buf));
    vdp_waddr(addr);
    _vram_write(buf, sizeof(buf));
  }
  _vram_write_run(0, 40);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scroll1>:
  endbr64
  push   %r12
  mov    $0xfffe,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <delay@plt>
  mov    $0xfffe,%edi
  call   <delay@plt>
  mov    $0x7fff,%edi
  call   <delay@plt>
  nop
L11:
  mov    %ebx,%r12d
  add    $0x28,%ebx
  mov    %ebx,%edi
  call   <vdp_raddr@plt>
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <_vram_read@plt>
  mov    %r12d,%edi
  call   <vdp_waddr@plt>
  mov    $0x28,%esi
  mov    %rbp,%rdi
  call   <_vram_write@plt>
  cmp    $0x398,%ebx
  jne    L11
  xor    %edi,%edi
  mov    $0x28,%esi
  call   <_vram_write_run@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void scroll1() {
  char buf[40];
  unsigned int addr = 0x0000;
  delay(65534);
  delay(65534);
  delay(32767);
  for (; addr < (0x0000 + 40 * (24 - 1)); addr += 40) {
    vdp_raddr(addr + 40);
    _vram_read(buf, sizeof(buf));
    vdp_waddr(addr);
    _vram_write(buf, sizeof(buf));
  }
  _vram_write_run(0, 40);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printHeader>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listHeader@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: List header...


assistant: ```c
void printHeader() {
  printf("List header...\n");
  listHeader();
}
```
user: What is the c source code of the assembly code below:

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listHeader@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: List header...


assistant: ```c
void printHeader() {
  printf("List header...\n");
  listHeader();
}
```
user: What is the c source code of the assembly code below?

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <listHeader@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: List header...


assistant: ```c
void printHeader() {
  printf("List header...\n");
  listHeader();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printHeader>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <listHeader@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: List header...


assistant: ```c
void printHeader() {
  printf("List header...\n");
  listHeader();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_argv_chunks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L18
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x8,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L6
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: argv[%d] = [%s]


assistant: ```c
void print_argv_chunks(char **child_argv) {
  char **p = child_argv;
  unsigned int i = 0;
  printf("\n");
  while (*p) {
    printf("argv[%d] = [%s]\n", i, *p);
    p++;
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_argv_chunks>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x0(%rbp),%rdx
  test   %rdx,%rdx
  je     L13
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L19:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L19
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: argv[%d] = [%s]


assistant: ```c
void print_argv_chunks(char **child_argv) {
  char **p = child_argv;
  unsigned int i = 0;
  printf("\n");
  while (*p) {
    printf("argv[%d] = [%s]\n", i, *p);
    p++;
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_argv_chunks>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  call   <putchar@plt>
  mov    0x0(%rbp),%rdx
  test   %rdx,%rdx
  je     L4
  xor    %ebx,%ebx
  lea    D6(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L16
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: argv[%d] = [%s]


assistant: ```c
void print_argv_chunks(char **child_argv) {
  char **p = child_argv;
  unsigned int i = 0;
  printf("\n");
  while (*p) {
    printf("argv[%d] = [%s]\n", i, *p);
    p++;
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_argv_chunks>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0xa,%edi
  push   %rbx
  call   <putchar@plt>
  mov    0x0(%rbp),%rdx
  test   %rdx,%rdx
  je     L5
  xor    %ebx,%ebx
  lea    D9(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L0
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: argv[%d] = [%s]


assistant: ```c
void print_argv_chunks(char **child_argv) {
  char **p = child_argv;
  unsigned int i = 0;
  printf("\n");
  while (*p) {
    printf("argv[%d] = [%s]\n", i, *p);
    p++;
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L8:
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x2,-0xc(%rbp)
  jle    L8
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D28: tan

tool: D6: # c::cephes::%s


tool: D15: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "tan");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D10(%rip),%r13
  lea    D22(%rip),%r12
  lea    D5(%rip),%rbp
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L0
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D5
type: string

tool: D10: tan

tool: D22: # c::cephes::%s


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "tan");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D25(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L8
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string

tool: D25: tan

tool: D12: # c::cephes::%s


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "tan");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D9(%rip),%r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D27
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string

tool: D9: tan

tool: D27: # c::cephes::%s


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "tan");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: aaa


assistant: ```c
int main() {
  printf("aaa\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: aaa


assistant: ```c
int main() {
  printf("aaa\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: aaa


assistant: ```c
int main() {
  printf("aaa\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: aaa


assistant: ```c
int main() {
  printf("aaa\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Vist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: %s


assistant: ```c
int Vist(void *tfile) {
  int Eret = 0;
  struct dirent *myf = tfile;
  printf("%s\n", myf->d_name);
  return Eret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Vist>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %s


assistant: ```c
int Vist(void *tfile) {
  int Eret = 0;
  struct dirent *myf = tfile;
  printf("%s\n", myf->d_name);
  return Eret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Vist>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %s


assistant: ```c
int Vist(void *tfile) {
  int Eret = 0;
  struct dirent *myf = tfile;
  printf("%s\n", myf->d_name);
  return Eret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Vist>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %s


assistant: ```c
int Vist(void *tfile) {
  int Eret = 0;
  struct dirent *myf = tfile;
  printf("%s\n", myf->d_name);
  return Eret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L2:
  movl   $0x0,-0xc(%rbp)
  jmp    L60
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L21
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L21:
  addl   $0x1,-0xc(%rbp)
L60:
  mov    -0x4(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L26
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d  


assistant: ```c
void bubbleSort(int *array, int count) {
  int loopNumber = count - 1;
  for (int i = 0; i < loopNumber; i++) {
    for (int j = 0; j < loopNumber - i; j++) {
      if (array[j] > array[j + 1]) {
        array[j] = array[j] ^ array[j + 1];
        array[j + 1] = array[j] ^ array[j + 1];
        array[j] = array[j] ^ array[j + 1];
      }
    }
  }
  for (int i = 0; i < count; i++) {
    printf("%d  \n", array[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  test   %r9d,%r9d
  jle    L14
  lea    0x4(%rdi),%r10
  jmp    L15
L45:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L77
L51:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L45
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L45
L77:
  sub    $0x1,%r9d
  je     L14
L15:
  test   %r9d,%r9d
  jle    L77
  mov    %rdi,%rax
  lea    -0x1(%r9),%edx
  lea    (%r10,%rdx,4),%r8
  jmp    L51
L14:
  test   %esi,%esi
  jle    L47
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D4(%rip),%rbp
L36:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L36
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d  


assistant: ```c
void bubbleSort(int *array, int count) {
  int loopNumber = count - 1;
  for (int i = 0; i < loopNumber; i++) {
    for (int j = 0; j < loopNumber - i; j++) {
      if (array[j] > array[j + 1]) {
        array[j] = array[j] ^ array[j + 1];
        array[j + 1] = array[j] ^ array[j + 1];
        array[j] = array[j] ^ array[j + 1];
      }
    }
  }
  for (int i = 0; i < count; i++) {
    printf("%d  \n", array[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r10d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %r10d,%r10d
  jle    L3
  mov    %r10d,%edx
  lea    0x4(%rdi),%rdi
  nopl   0x0(%rax,%rax,1)
L33:
  sub    $0x1,%edx
  mov    %rbx,%rax
  mov    %rdx,%r9
  lea    (%rdi,%rdx,4),%r8
  nopl   (%rax)
L42:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L15
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L15:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L42
  mov    %r9d,%edx
  test   %r9d,%r9d
  jne    L33
L3:
  test   %esi,%esi
  jle    L47
  lea    0x4(%rbx,%r10,4),%r12
  lea    D8(%rip),%rbp
  nop
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L14
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: %d  


assistant: ```c
void bubbleSort(int *array, int count) {
  int loopNumber = count - 1;
  for (int i = 0; i < loopNumber; i++) {
    for (int j = 0; j < loopNumber - i; j++) {
      if (array[j] > array[j + 1]) {
        array[j] = array[j] ^ array[j + 1];
        array[j + 1] = array[j] ^ array[j + 1];
        array[j] = array[j] ^ array[j + 1];
      }
    }
  }
  for (int i = 0; i < count; i++) {
    printf("%d  \n", array[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r10d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %r10d,%r10d
  jle    L56
  mov    %r10d,%edx
  lea    0x4(%rdi),%rdi
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x1,%edx
  mov    %rbx,%rax
  mov    %rdx,%r9
  lea    (%rdi,%rdx,4),%r8
  nopl   (%rax)
L13:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L45
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L45:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L13
  mov    %r9d,%edx
  test   %r9d,%r9d
  jne    L6
L56:
  test   %esi,%esi
  jle    L47
  lea    0x4(%rbx,%r10,4),%r12
  lea    D4(%rip),%rbp
  nop
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L1
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: %d  


assistant: ```c
void bubbleSort(int *array, int count) {
  int loopNumber = count - 1;
  for (int i = 0; i < loopNumber; i++) {
    for (int j = 0; j < loopNumber - i; j++) {
      if (array[j] > array[j + 1]) {
        array[j] = array[j] ^ array[j + 1];
        array[j + 1] = array[j] ^ array[j + 1];
        array[j] = array[j] ^ array[j + 1];
      }
    }
  }
  for (int i = 0; i < count; i++) {
    printf("%d  \n", array[i]);
  }
}
```