ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<open_simplex_noise2_oct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  movss  %xmm2,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L18:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x38(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rdx
  mov    -0x28(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <open_simplex_noise2@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x14(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x40(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x8(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L18
  movss  -0xc(%rbp),%xmm0
  divss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: f32

tool: D9: 1

assistant: ```c
double open_simplex_noise2_oct(struct osn_context *ctx, double x, double y, int octaves, float pers) {
  float max_amp = 0;
  float amp = 1;
  float noise = 0;
  float freq = 1.0f;
  for (int i = 0; i < octaves; i++) {
    noise += open_simplex_noise2(ctx, x * freq, y * freq) * amp;
    max_amp += amp;
    amp *= pers;
    freq *= 2.0f;
  }
  noise /= max_amp;
  return noise;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<open_simplex_noise2_oct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movss  %xmm2,0x2c(%rsp)
  test   %esi,%esi
  jle    L26
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  movss  D5(%rip),%xmm2
  movss  %xmm2,0xc(%rsp)
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x10(%rsp)
  movss  %xmm2,0x28(%rsp)
  movss  %xmm4,0x14(%rsp)
L21:
  pxor   %xmm1,%xmm1
  cvtss2sd 0xc(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  0x20(%rsp),%xmm1
  mov    %r12,%rdi
  call   <open_simplex_noise2@plt>
  movss  0x28(%rsp),%xmm3
  mulss  %xmm3,%xmm0
  addss  0x10(%rsp),%xmm0
  movss  %xmm0,0x10(%rsp)
  movss  0x14(%rsp),%xmm6
  addss  %xmm3,%xmm6
  movss  %xmm6,0x14(%rsp)
  mulss  0x2c(%rsp),%xmm3
  movss  %xmm3,0x28(%rsp)
  movss  0xc(%rsp),%xmm5
  movaps %xmm5,%xmm4
  addss  %xmm5,%xmm4
  movss  %xmm4,0xc(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L21
L29:
  movss  0x10(%rsp),%xmm0
  divss  0x14(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  pxor   %xmm2,%xmm2
  movss  %xmm2,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  jmp    L29
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: f32

tool: D5: 1

assistant: ```c
double open_simplex_noise2_oct(struct osn_context *ctx, double x, double y, int octaves, float pers) {
  float max_amp = 0;
  float amp = 1;
  float noise = 0;
  float freq = 1.0f;
  for (int i = 0; i < octaves; i++) {
    noise += open_simplex_noise2(ctx, x * freq, y * freq) * amp;
    max_amp += amp;
    amp *= pers;
    freq *= 2.0f;
  }
  noise /= max_amp;
  return noise;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<open_simplex_noise2_oct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movss  %xmm2,0x2c(%rsp)
  test   %esi,%esi
  jle    L19
  movss  D2(%rip),%xmm2
  pxor   %xmm4,%xmm4
  mov    %esi,%ebp
  xor    %ebx,%ebx
  mov    %rdi,%r12
  movaps %xmm4,%xmm5
  movaps %xmm2,%xmm3
  nop
L21:
  movsd  0x18(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    %r12,%rdi
  add    $0x1,%ebx
  cvtss2sd %xmm2,%xmm1
  movss  %xmm3,0x28(%rsp)
  mulsd  %xmm1,%xmm0
  movss  %xmm5,0x14(%rsp)
  mulsd  0x20(%rsp),%xmm1
  movss  %xmm4,0x10(%rsp)
  movss  %xmm2,0xc(%rsp)
  call   <open_simplex_noise2@plt>
  movss  0x28(%rsp),%xmm3
  movss  0x10(%rsp),%xmm4
  movss  0x14(%rsp),%xmm5
  movss  0xc(%rsp),%xmm2
  mulss  %xmm3,%xmm0
  addss  %xmm3,%xmm5
  addss  %xmm2,%xmm2
  mulss  0x2c(%rsp),%xmm3
  addss  %xmm0,%xmm4
  cmp    %ebx,%ebp
  jne    L21
L1:
  divss  %xmm5,%xmm4
  add    $0x30,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  cvtss2sd %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  pxor   %xmm4,%xmm4
  movaps %xmm4,%xmm5
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: f32

tool: D2: 1

assistant: ```c
double open_simplex_noise2_oct(struct osn_context *ctx, double x, double y, int octaves, float pers) {
  float max_amp = 0;
  float amp = 1;
  float noise = 0;
  float freq = 1.0f;
  for (int i = 0; i < octaves; i++) {
    noise += open_simplex_noise2(ctx, x * freq, y * freq) * amp;
    max_amp += amp;
    amp *= pers;
    freq *= 2.0f;
  }
  noise /= max_amp;
  return noise;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<open_simplex_noise2_oct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm1,0x20(%rsp)
  movss  %xmm2,0x2c(%rsp)
  test   %esi,%esi
  jle    L1
  movss  D4(%rip),%xmm2
  pxor   %xmm4,%xmm4
  mov    %esi,%ebp
  xor    %ebx,%ebx
  mov    %rdi,%r12
  movaps %xmm4,%xmm5
  movaps %xmm2,%xmm3
  nop
L26:
  movsd  0x18(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    %r12,%rdi
  add    $0x1,%ebx
  cvtss2sd %xmm2,%xmm1
  movss  %xmm3,0x28(%rsp)
  mulsd  %xmm1,%xmm0
  movss  %xmm5,0x14(%rsp)
  mulsd  0x20(%rsp),%xmm1
  movss  %xmm4,0x10(%rsp)
  movss  %xmm2,0xc(%rsp)
  call   <open_simplex_noise2@plt>
  movss  0x28(%rsp),%xmm3
  movss  0x10(%rsp),%xmm4
  movss  0x14(%rsp),%xmm5
  movss  0xc(%rsp),%xmm2
  mulss  %xmm3,%xmm0
  addss  %xmm3,%xmm5
  addss  %xmm2,%xmm2
  mulss  0x2c(%rsp),%xmm3
  addss  %xmm0,%xmm4
  cmp    %ebx,%ebp
  jne    L26
L21:
  divss  %xmm5,%xmm4
  add    $0x30,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  cvtss2sd %xmm4,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  pxor   %xmm4,%xmm4
  movaps %xmm4,%xmm5
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: f32

tool: D4: 1

assistant: ```c
double open_simplex_noise2_oct(struct osn_context *ctx, double x, double y, int octaves, float pers) {
  float max_amp = 0;
  float amp = 1;
  float noise = 0;
  float freq = 1.0f;
  for (int i = 0; i < octaves; i++) {
    noise += open_simplex_noise2(ctx, x * freq, y * freq) * amp;
    max_amp += amp;
    amp *= pers;
    freq *= 2.0f;
  }
  noise /= max_amp;
  return noise;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<action_param_defaults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <action_param_set_type@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <action_param_defaults_neural@plt>
  nop
  leave
  ret
```

assistant: ```c
void action_param_defaults(struct XCSF *xcsf) {
  action_param_set_type(xcsf, (1));
  action_param_defaults_neural(xcsf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<action_param_defaults>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%esi
  call   <action_param_set_type@plt>
  mov    %rbx,%rdi
  call   <action_param_defaults_neural@plt>
  pop    %rbx
  ret
```

assistant: ```c
void action_param_defaults(struct XCSF *xcsf) {
  action_param_set_type(xcsf, (1));
  action_param_defaults_neural(xcsf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<action_param_defaults>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <action_param_set_type@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <action_param_defaults_neural@plt>
```

assistant: ```c
void action_param_defaults(struct XCSF *xcsf) {
  action_param_set_type(xcsf, (1));
  action_param_defaults_neural(xcsf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<action_param_defaults>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %rdi,%rbp
  call   <action_param_set_type@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <action_param_defaults_neural@plt>
```

assistant: ```c
void action_param_defaults(struct XCSF *xcsf) {
  action_param_set_type(xcsf, (1));
  action_param_defaults_neural(xcsf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MyMayFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void MyMayFree(char *p) {
  if (NULL != p) {
    free(p);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MyMayFree>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void MyMayFree(char *p) {
  if (NULL != p) {
    free(p);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<MyMayFree>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void MyMayFree(char *p) {
  if (NULL != p) {
    free(p);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MyMayFree>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void MyMayFree(char *p) {
  if (NULL != p) {
    free(p);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memleak_sqlite3_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa,%edi
  call   <sqlite3_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L3:
  nop
  leave
  ret
```

assistant: ```c
void memleak_sqlite3_malloc() {
  char *buf = sqlite3_malloc(10);
  if (buf) {
    buf[0] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memleak_sqlite3_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sqlite3_malloc@plt>
  test   %rax,%rax
  je     L0
  movb   $0x0,(%rax)
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void memleak_sqlite3_malloc() {
  char *buf = sqlite3_malloc(10);
  if (buf) {
    buf[0] = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memleak_sqlite3_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sqlite3_malloc@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void memleak_sqlite3_malloc() {
  char *buf = sqlite3_malloc(10);
  if (buf) {
    buf[0] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memleak_sqlite3_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sqlite3_malloc@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rax)
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void memleak_sqlite3_malloc() {
  char *buf = sqlite3_malloc(10);
  if (buf) {
    buf[0] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L4
L5:
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <solve@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L4
  mov    $0xa,%edi
  call   <putchar@plt>
L4:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D24
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string

tool: D23: %d

tool: D24: %lf%lf

tool: D17: %13.6lf


assistant: ```c
int main() {
  int total_test;
  double B, H;
  double ans;
  scanf("%d", &total_test);
  while (total_test-- > 0) {
    scanf("%lf%lf", &B, &H);
    printf("%13.6lf\n", solve(B, H));
    if (total_test)
      putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%r13
  lea    D5(%rip),%r12
  lea    D23(%rip),%rbp
L29:
  lea    0x8(%rsp),%rbx
L19:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jle    L11
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <solve@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L19
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L29
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D23
type_infered: string

tool: D15: %d

tool: D5: %lf%lf

tool: D23: %13.6lf


assistant: ```c
int main() {
  int total_test;
  double B, H;
  double ans;
  scanf("%d", &total_test);
  while (total_test-- > 0) {
    scanf("%lf%lf", &B, &H);
    printf("%13.6lf\n", solve(B, H));
    if (total_test)
      putchar('\n');
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
L20:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jle    L7
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <solve@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L6
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L20
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string
name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D22
datatype: string

tool: D9: %d

tool: D26: %lf%lf

tool: D22: %13.6lf


assistant: ```c
int main() {
  int total_test;
  double B, H;
  double ans;
  scanf("%d", &total_test);
  while (total_test-- > 0) {
    scanf("%lf%lf", &B, &H);
    printf("%13.6lf\n", solve(B, H));
    if (total_test)
      putchar('\n');
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
L16:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jle    L2
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <solve@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L34
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L16
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D11
type_infered: string

tool: D4: %d

tool: D28: %lf%lf

tool: D11: %13.6lf


assistant: ```c
int main() {
  int total_test;
  double B, H;
  double ans;
  scanf("%d", &total_test);
  while (total_test-- > 0) {
    scanf("%lf%lf", &B, &H);
    printf("%13.6lf\n", solve(B, H));
    if (total_test)
      putchar('\n');
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itoa_alt_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <abs@plt>
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  test   %rax,%rax
  jg     L1
  cmpl   $0x0,-0xc(%rbp)
  jns    L7
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2d,(%rax)
L7:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse_ptr@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoa_alt_ptr(int n, char *s) {
  int sign = n;
  char *p = s;
  do {
    *p++ = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    *p++ = '-';
  *p = '\0';
  reverse_ptr(s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itoa_alt_ptr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rsi,%r12
  mov    %edi,%ebp
L28:
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%edi
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r12,%r15
  add    $0x1,%r12
  add    $0x30,%eax
  mov    %al,-0x1(%r12)
  mov    %ebx,%ebp
  mov    %ebx,%edi
  call   <abs@plt>
  test   %rax,%rax
  jg     L28
  test   %r14d,%r14d
  js     L21
L22:
  movb   $0x0,(%r12)
  mov    %r13,%rdi
  call   <reverse_ptr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  movb   $0x2d,(%r12)
  lea    0x2(%r15),%r12
  jmp    L22
```

assistant: ```c
void itoa_alt_ptr(int n, char *s) {
  int sign = n;
  char *p = s;
  do {
    *p++ = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    *p++ = '-';
  *p = '\0';
  reverse_ptr(s);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itoa_alt_ptr>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L13:
  movslq %r14d,%rbx
  mov    %r14d,%eax
  mov    %r14d,%edi
  mov    %rbp,%r15
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%rbp
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebx,%r14d
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  call   <abs@plt>
  test   %rax,%rax
  jg     L13
  test   %r13d,%r13d
  jns    L2
  movb   $0x2d,0x0(%rbp)
  lea    0x2(%r15),%rbp
L2:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <reverse_ptr@plt>
```

assistant: ```c
void itoa_alt_ptr(int n, char *s) {
  int sign = n;
  char *p = s;
  do {
    *p++ = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    *p++ = '-';
  *p = '\0';
  reverse_ptr(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa_alt_ptr>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L6:
  movslq %r14d,%rbx
  mov    %r14d,%eax
  mov    %r14d,%edi
  mov    %rbp,%r15
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%rbp
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebx,%r14d
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  call   <abs@plt>
  test   %rax,%rax
  jg     L6
  test   %r13d,%r13d
  jns    L12
  movb   $0x2d,0x0(%rbp)
  lea    0x2(%r15),%rbp
L12:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <reverse_ptr@plt>
```

assistant: ```c
void itoa_alt_ptr(int n, char *s) {
  int sign = n;
  char *p = s;
  do {
    *p++ = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    *p++ = '-';
  *p = '\0';
  reverse_ptr(s);
}
```