ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_one_loop>:
  endbr64
  mov    (%rsi),%ecx
  mov    $0x0,%edx
  mov    $0x5f5e100,%eax
L5:
  add    %edx,%ecx
  add    %edi,%edx
  sub    $0x1,%eax
  jne    L5
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void do_one_loop(int i, int *n) {
  int j;
  for (j = 0; j < 100000000; j++)
    (*n) = (*n) + i * j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_one_loop>:
  endbr64
  mov    (%rsi),%ecx
  xor    %edx,%edx
  mov    $0x5f5e100,%eax
  nopl   (%rax)
L7:
  add    %edx,%ecx
  add    %edi,%edx
  sub    $0x1,%eax
  jne    L7
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void do_one_loop(int i, int *n) {
  int j;
  for (j = 0; j < 100000000; j++)
    (*n) = (*n) + i * j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_one_loop>:
  endbr64
  movd   %edi,%xmm7
  mov    (%rsi),%edx
  movdqa D8(%rip),%xmm2
  xor    %eax,%eax
  pshufd $0x0,%xmm7,%xmm4
  movdqa D16(%rip),%xmm6
  pxor   %xmm3,%xmm3
  movdqa %xmm4,%xmm5
  psrlq  $0x20,%xmm5
  xchg   %ax,%ax
L0:
  movdqa %xmm2,%xmm0
  add    $0x1,%eax
  paddd  %xmm6,%xmm2
  movdqa %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm4,%xmm1
  pmuludq %xmm5,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm3
  cmp    $0x17d7840,%eax
  jne    L0
  movdqa %xmm3,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movd   %xmm3,%eax
  add    %edx,%eax
  mov    %eax,(%rsi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: byte[16]
name: read_data
arguments: data_tag: D16
datatype: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D16": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void do_one_loop(int i, int *n) {
  int j;
  for (j = 0; j < 100000000; j++)
    (*n) = (*n) + i * j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<econfig_trimQuotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  ja     L0
  mov    -0x18(%rbp),%rax
  jmp    L23
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L36
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L33
L36:
  mov    -0x18(%rbp),%rax
  jmp    L23
L33:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L23:
  leave
  ret
```

assistant: ```c
char *econfig_trimQuotes(char *str) {
  unsigned len = strlen(str);
  if (len < 2) {
    return str;
  }
  if (str[0] != '"' || str[len - 1] != '"') {
    return str;
  }
  str[len - 1] = 0;
  str++;
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<econfig_trimQuotes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L17
  cmpb   $0x22,(%rbx)
  jne    L17
  lea    -0x1(%rax),%eax
  add    %rbx,%rax
  cmpb   $0x22,(%rax)
  jne    L17
  movb   $0x0,(%rax)
  add    $0x1,%rbx
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *econfig_trimQuotes(char *str) {
  unsigned len = strlen(str);
  if (len < 2) {
    return str;
  }
  if (str[0] != '"' || str[len - 1] != '"') {
    return str;
  }
  str[len - 1] = 0;
  str++;
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<econfig_trimQuotes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L7
  cmpb   $0x22,(%r12)
  je     L11
L7:
  mov    %r12,%rax
  pop    %r12
  ret
L11:
  sub    $0x1,%eax
  add    %r12,%rax
  cmpb   $0x22,(%rax)
  jne    L7
  add    $0x1,%r12
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *econfig_trimQuotes(char *str) {
  unsigned len = strlen(str);
  if (len < 2) {
    return str;
  }
  if (str[0] != '"' || str[len - 1] != '"') {
    return str;
  }
  str[len - 1] = 0;
  str++;
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<econfig_trimQuotes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cmp    $0x1,%eax
  jbe    L11
  cmpb   $0x22,(%r12)
  je     L16
L11:
  mov    %r12,%rax
  pop    %r12
  ret
L16:
  sub    $0x1,%eax
  add    %r12,%rax
  cmpb   $0x22,(%rax)
  jne    L11
  add    $0x1,%r12
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *econfig_trimQuotes(char *str) {
  unsigned len = strlen(str);
  if (len < 2) {
    return str;
  }
  if (str[0] != '"' || str[len - 1] != '"') {
    return str;
  }
  str[len - 1] = 0;
  str++;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<unlock_mutex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  jmp    L4
L8:
  mov    $0xffffffff,%eax
L4:
  leave
  ret
```

assistant: ```c
int unlock_mutex(pthread_mutex_t *mtx) {
  if (pthread_mutex_unlock(mtx) == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<unlock_mutex>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unlock_mutex(pthread_mutex_t *mtx) {
  if (pthread_mutex_unlock(mtx) == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unlock_mutex>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_mutex_unlock@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unlock_mutex(pthread_mutex_t *mtx) {
  if (pthread_mutex_unlock(mtx) == 0) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sigvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sigvec(int sig, struct sigvec *vec, struct sigvec *ovec) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sigvec>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigvec(int sig, struct sigvec *vec, struct sigvec *ovec) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sigvec>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigvec(int sig, struct sigvec *vec, struct sigvec *ovec) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<sigvec>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sigvec(int sig, struct sigvec *vec, struct sigvec *ovec) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<asm_bsf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  bsf    %rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long asm_bsf(unsigned long x) {
  asm("bsfq %0, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<asm_bsf>:
  endbr64
  mov    %rdi,%rax
  bsf    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bsf(unsigned long x) {
  asm("bsfq %0, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<asm_bsf>:
  endbr64
  mov    %rdi,%rax
  bsf    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bsf(unsigned long x) {
  asm("bsfq %0, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<asm_bsf>:
  endbr64
  mov    %rdi,%rax
  bsf    %rax,%rax
  ret
```

assistant: ```c
unsigned long asm_bsf(unsigned long x) {
  asm("bsfq %0, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validatey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L25
L4:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L31
  cmpl   $0x5,-0x4(%rbp)
  je     L31
  movl   $0x0,-0x8(%rbp)
  jmp    L42
L31:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L25:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
L42:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int validatey(int y) {
  int tmp, retval = 1;
  while (y) {
    tmp = y % 10;
    if (tmp != 3 && tmp != 5) {
      retval = 0;
      break;
    }
    y /= 10;
  }
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<validatey>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  je     L19
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  sub    $0x3,%eax
  test   $0xfffffffd,%eax
  jne    L8
L21:
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  je     L37
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  sub    $0x3,%eax
  test   $0xfffffffd,%eax
  je     L21
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
L19:
  mov    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int validatey(int y) {
  int tmp, retval = 1;
  while (y) {
    tmp = y % 10;
    if (tmp != 3 && tmp != 5) {
      retval = 0;
      break;
    }
    y /= 10;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<validatey>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  jne    L21
  jmp    L2
  nopl   0x0(%rax)
L8:
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%ecx
  je     L2
L21:
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  add    %esi,%esi
  sub    %esi,%edx
  sub    $0x3,%edx
  and    $0xfffffffd,%edx
  je     L8
  xor    %eax,%eax
  ret
  nopl   (%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int validatey(int y) {
  int tmp, retval = 1;
  while (y) {
    tmp = y % 10;
    if (tmp != 3 && tmp != 5) {
      retval = 0;
      break;
    }
    y /= 10;
  }
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validatey>:
  endbr64
  mov    %edi,%ecx
  test   %edi,%edi
  jne    L13
  jmp    L10
  nopl   0x0(%rax)
L38:
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%ecx
  je     L10
L13:
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  mov    %ecx,%edx
  add    %esi,%esi
  sub    %esi,%edx
  sub    $0x3,%edx
  and    $0xfffffffd,%edx
  je     L38
  xor    %eax,%eax
  ret
  nopl   (%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int validatey(int y) {
  int tmp, retval = 1;
  while (y) {
    tmp = y % 10;
    if (tmp != 3 && tmp != 5) {
      retval = 0;
      break;
    }
    y /= 10;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x1f(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <read@plt>
  cmp    $0x1,%eax
  je     L118
  mov    $0x0,%eax
  jmp    L41
L118:
  movzbl -0x1f(%rbp),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  mov    %eax,(%rbx)
  lea    -0x1f(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <read@plt>
  cmp    $0x1,%eax
  je     L37
  mov    $0x0,%eax
  jmp    L41
L37:
  mov    (%rbx),%edx
  movzbl -0x1f(%rbp),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %edx,%eax
  mov    %eax,(%rbx)
  lea    -0x1e(%rbp),%rax
  mov    $0x6,%edx
  mov    %rax,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <read@plt>
  cmp    $0x6,%eax
  je     L73
  mov    $0x0,%eax
  jmp    L41
L73:
  movzbl -0x1e(%rbp),%eax
  test   %al,%al
  jne    L75
  movzbl -0x1d(%rbp),%eax
  test   %al,%al
  jne    L75
  movzbl -0x1c(%rbp),%eax
  test   %al,%al
  jne    L75
  movzbl -0x1b(%rbp),%eax
  test   %al,%al
  jne    L75
  movzbl -0x1a(%rbp),%eax
  test   %al,%al
  jne    L75
  movzbl -0x19(%rbp),%eax
  test   %al,%al
  je     L70
L75:
  mov    $0x0,%eax
  jmp    L41
L70:
  mov    $0x1,%eax
L41:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L132
  call   <__stack_chk_fail@plt>
L132:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
getint(f, i) register f;
register *i;
{
  char c, buf[6];
  if (read(f, &c, 1) != 1)
    return (0);
  *i = c & 0377;
  if (read(f, &c, 1) != 1)
    return (0);
  *i |= (c & 0377) << 8;
  if (read(f, buf, 6) != 6)
    return (0);
  if (buf[0] || buf[1] || buf[2] || buf[3] || buf[4] || buf[5])
    return (0);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rsi
  mov    $0x1,%edx
  call   <read@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  je     L47
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  movzbl 0x1(%rsp),%eax
  mov    %eax,0x0(%rbp)
  lea    0x1(%rsp),%rsi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  jne    L15
  movsbl 0x1(%rsp),%eax
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,0x0(%rbp)
  lea    0x2(%rsp),%rsi
  mov    $0x6,%edx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x6,%edx
  jne    L15
  movzbl 0x2(%rsp),%eax
  or     0x3(%rsp),%al
  or     0x4(%rsp),%al
  or     0x5(%rsp),%al
  or     0x6(%rsp),%al
  or     0x7(%rsp),%al
  sete   %al
  movzbl %al,%eax
  jmp    L15
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
getint(f, i) register f;
register *i;
{
  char c, buf[6];
  if (read(f, &c, 1) != 1)
    return (0);
  *i = c & 0377;
  if (read(f, &c, 1) != 1)
    return (0);
  *i |= (c & 0377) << 8;
  if (read(f, buf, 6) != 6)
    return (0);
  if (buf[0] || buf[1] || buf[2] || buf[3] || buf[4] || buf[5])
    return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getint>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%r12
  mov    %r12,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L46
L49:
  xor    %eax,%eax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  movzbl 0x1(%rsp),%eax
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L49
  movsbl 0x1(%rsp),%eax
  lea    0x2(%rsp),%rsi
  mov    $0x6,%edx
  mov    %ebp,%edi
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,(%rbx)
  xor    %eax,%eax
  call   <read@plt>
  cmp    $0x6,%eax
  jne    L49
  movzbl 0x2(%rsp),%eax
  or     0x3(%rsp),%al
  or     0x4(%rsp),%al
  or     0x5(%rsp),%al
  or     0x6(%rsp),%al
  or     0x7(%rsp),%al
  sete   %al
  movzbl %al,%eax
  jmp    L35
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
getint(f, i) register f;
register *i;
{
  char c, buf[6];
  if (read(f, &c, 1) != 1)
    return (0);
  *i = c & 0377;
  if (read(f, &c, 1) != 1)
    return (0);
  *i |= (c & 0377) << 8;
  if (read(f, buf, 6) != 6)
    return (0);
  if (buf[0] || buf[1] || buf[2] || buf[3] || buf[4] || buf[5])
    return (0);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getint>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%r12
  mov    %r12,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  je     L45
L28:
  xor    %eax,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl 0x1(%rsp),%eax
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  xor    %eax,%eax
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L28
  movsbl 0x1(%rsp),%eax
  lea    0x2(%rsp),%rsi
  mov    $0x6,%edx
  mov    %ebp,%edi
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,(%rbx)
  xor    %eax,%eax
  call   <read@plt>
  cmp    $0x6,%eax
  jne    L28
  movzbl 0x2(%rsp),%eax
  or     0x3(%rsp),%al
  or     0x4(%rsp),%al
  or     0x5(%rsp),%al
  or     0x6(%rsp),%al
  or     0x7(%rsp),%al
  sete   %al
  movzbl %al,%eax
  jmp    L18
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
getint(f, i) register f;
register *i;
{
  char c, buf[6];
  if (read(f, &c, 1) != 1)
    return (0);
  *i = c & 0377;
  if (read(f, &c, 1) != 1)
    return (0);
  *i |= (c & 0377) << 8;
  if (read(f, buf, 6) != 6)
    return (0);
  if (buf[0] || buf[1] || buf[2] || buf[3] || buf[4] || buf[5])
    return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L40:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L2
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L14
L2:
  movl   $0x0,-0x10(%rbp)
  jmp    L44
L48:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L63:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L63
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L48
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L40
L14:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type: string
name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D34
type: string

tool: D27: %d %d

tool: D26: #

tool: D34: 


assistant: ```c
int main(void) {
  int height, width, i, j;
  while (1) {
    scanf("%d %d", &height, &width);
    if (height == 0 && width == 0)
      break;
    for (i = 0; i < height; i++) {
      for (j = 0; j < width; j++)
        printf("#");
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%r14
  lea    D23(%rip),%rbp
  lea    D22(%rip),%r13
  jmp    L80
L26:
  cmpl   $0x0,0x4(%rsp)
  je     L64
L71:
  mov    %r13,%rdi
  call   <printf@plt>
L80:
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L26
  jle    L71
  mov    $0x0,%r12d
  jmp    L81
L22:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L22
L68:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,(%rsp)
  jle    L71
L81:
  mov    $0x0,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L22
  jmp    L68
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string

tool: D13: %d %d

tool: D23: #

tool: D22: 


assistant: ```c
int main(void) {
  int height, width, i, j;
  while (1) {
    scanf("%d %d", &height, &width);
    if (height == 0 && width == 0)
      break;
    for (i = 0; i < height; i++) {
      for (j = 0; j < width; j++)
        printf("#");
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  mov    %rsp,%r14
  jmp    L20
L31:
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L4
L75:
  mov    %r12,%rdi
  call   <printf@plt>
L20:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  test   %ecx,%ecx
  je     L31
  jle    L75
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L44:
  mov    0x4(%rsp),%eax
  xor    %r13d,%r13d
  test   %eax,%eax
  jle    L78
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %rbx,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jg     L72
L78:
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jg     L44
  jmp    L75
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D8
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D5: 


tool: D8: #

tool: D7: %d %d

assistant: ```c
int main(void) {
  int height, width, i, j;
  while (1) {
    scanf("%d %d", &height, &width);
    if (height == 0 && width == 0)
      break;
    for (i = 0; i < height; i++) {
      for (j = 0; j < width; j++)
        printf("#");
      printf("\n");
    }
    printf("\n");
  }
  return 0;
}
```