ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<merge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r15d
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  lea    (%rsi,%rcx,1),%r14d
  shl    $0x2,%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r15d,%r15d
  jle    L59
  test   %ebp,%ebp
  jle    L59
  mov    %rax,%rsi
  mov    $0x1,%eax
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L107
L42:
  add    $0x1,%edx
  mov    %eax,%r8d
  mov    %edi,(%rsi)
L69:
  add    $0x1,%eax
  add    $0x4,%rsi
  cmp    %r15d,%ecx
  jge    L53
  cmp    %ebp,%edx
  jge    L53
L107:
  movslq %ecx,%rdi
  mov    (%r12,%rdi,4),%r9d
  movslq %edx,%rdi
  mov    (%rbx,%rdi,4),%edi
  cmp    %edi,%r9d
  jge    L42
  add    $0x1,%ecx
  mov    %eax,%r8d
  mov    %r9d,(%rsi)
  jmp    L69
L59:
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x0,%ecx
L53:
  cmp    %ecx,%r15d
  jle    L25
  movslq %r8d,%r9
  lea    0x0(%r13,%r9,4),%rax
  mov    %ecx,%esi
  lea    -0x1(%r15),%edi
  sub    %ecx,%edi
  add    %r9,%rdi
  lea    0x4(%r13,%rdi,4),%rdi
  movslq %ecx,%rcx
  sub    %r9,%rcx
  lea    (%r12,%rcx,4),%r9
  sub    %r13,%r9
L46:
  mov    (%r9,%rax,1),%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L46
  add    %r8d,%r15d
  sub    %esi,%r15d
  mov    %r15d,%r8d
L25:
  cmp    %edx,%ebp
  jle    L106
  movslq %r8d,%r8
  lea    0x0(%r13,%r8,4),%rax
  sub    $0x1,%ebp
  sub    %edx,%ebp
  add    %r8,%rbp
  lea    0x4(%r13,%rbp,4),%rcx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  sub    %r13,%rdx
  neg    %r8
  lea    (%rdx,%r8,4),%rdx
  add    %rdx,%rbx
L105:
  mov    (%rbx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L105
L106:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void merge(int *nums1, int m, int *nums2, int n) {
  int *nums3 = (int *)malloc(sizeof(int) * (m + n));
  int i = 0;
  int j = 0;
  int k = 0;
  while (i < m && j < n)
    if (nums1[i] < nums2[j])
      nums3[k++] = nums1[i++];
    else
      nums3[k++] = nums2[j++];
  while (i < m)
    nums3[k++] = nums1[i++];
  while (j < n)
    nums3[k++] = nums2[j++];
  memcpy(nums1, nums3, sizeof(int) * (m + n));
  free(nums3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<merge>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    (%rsi,%rcx,1),%r13d
  push   %r12
  shl    $0x2,%r13d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r14d,%r14d
  jle    L31
  test   %r15d,%r15d
  jle    L31
  mov    %rax,%rsi
  xor    %edi,%edi
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L109
  xchg   %ax,%ax
L65:
  add    $0x1,%ecx
  mov    %eax,(%rsi)
  add    $0x4,%rsi
  cmp    %r14d,%ecx
  jge    L32
L27:
  cmp    %r15d,%edx
  jge    L32
L109:
  movslq %ecx,%rax
  movslq %edx,%r8
  add    $0x1,%edi
  mov    0x0(%rbp,%rax,4),%eax
  mov    (%rbx,%r8,4),%r8d
  cmp    %r8d,%eax
  jl     L65
  mov    %r8d,%eax
  add    $0x1,%edx
  add    $0x4,%rsi
  mov    %eax,-0x4(%rsi)
  cmp    %r14d,%ecx
  jl     L27
L32:
  cmp    %ecx,%r14d
  jle    L59
  lea    -0x1(%r14),%r8d
  movslq %edi,%r9
  sub    %ecx,%r8d
  lea    0x0(,%r9,4),%rsi
  add    %r9,%r8
  lea    (%rsi,%r12,1),%rax
  lea    0x4(%r12,%r8,4),%r9
  movslq %ecx,%r8
  shl    $0x2,%r8
  sub    %rsi,%r8
  sub    %r12,%r8
  add    %rbp,%r8
  xchg   %ax,%ax
L95:
  mov    (%r8,%rax,1),%esi
  add    $0x4,%rax
  mov    %esi,-0x4(%rax)
  cmp    %r9,%rax
  jne    L95
  add    %edi,%r14d
  mov    %r14d,%edi
  sub    %ecx,%edi
L59:
  cmp    %edx,%r15d
  jle    L77
  sub    $0x1,%r15d
  movslq %edi,%rdi
  sub    %edx,%r15d
  movslq %edx,%rdx
  lea    0x0(,%rdi,4),%rcx
  shl    $0x2,%rdx
  add    %rdi,%r15
  lea    (%r12,%rcx,1),%rax
  sub    %r12,%rdx
  lea    0x4(%r12,%r15,4),%rsi
  sub    %rcx,%rdx
  add    %rdx,%rbx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rbx,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L3
L77:
  mov    %rbp,%rdi
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %edi,%edi
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L32
```

assistant: ```c
void merge(int *nums1, int m, int *nums2, int n) {
  int *nums3 = (int *)malloc(sizeof(int) * (m + n));
  int i = 0;
  int j = 0;
  int k = 0;
  while (i < m && j < n)
    if (nums1[i] < nums2[j])
      nums3[k++] = nums1[i++];
    else
      nums3[k++] = nums2[j++];
  while (i < m)
    nums3[k++] = nums1[i++];
  while (j < n)
    nums3[k++] = nums2[j++];
  memcpy(nums1, nums3, sizeof(int) * (m + n));
  free(nums3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<msync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x0,%eax
  call   <pthread_testcancel@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__libc_msync@plt>
  leave
  ret
```

assistant: ```c
int msync(void *addr, size_t len, int flags) {
  pthread_testcancel();
  return __libc_msync(addr, len, flags);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<msync>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0x0,%eax
  call   <pthread_testcancel@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__libc_msync@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int msync(void *addr, size_t len, int flags) {
  pthread_testcancel();
  return __libc_msync(addr, len, flags);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<msync>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pthread_testcancel@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <__libc_msync@plt>
```

assistant: ```c
int msync(void *addr, size_t len, int flags) {
  pthread_testcancel();
  return __libc_msync(addr, len, flags);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msync>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pthread_testcancel@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <__libc_msync@plt>
```

assistant: ```c
int msync(void *addr, size_t len, int flags) {
  pthread_testcancel();
  return __libc_msync(addr, len, flags);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  cmpq   $0x0,-0x28(%rbp)
  je     L51
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getservbyname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L51
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  jmp    L89
L42:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L68
  cmpl   $0xffff,-0x1c(%rbp)
  jg     L51
L68:
  mov    -0x1c(%rbp),%eax
  jmp    L89
L51:
  cmpq   $0x0,-0x28(%rbp)
  je     L3
  mov    -0x28(%rbp),%rax
  jmp    L18
L3:
  lea    D8(%rip),%rax
L18:
  mov    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L89:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D11
type: string

tool: 

tool: D21: Problem with specified %s port '%s'

tool: D11: .

assistant: ```c
uint16_t parse_port(const char *protocol, const char *name) {
  struct servent *service;
  char *end;
  int port;
  port = strtol(name, &end, 10);
  if (*end != '\0') {
    if (protocol && (service = getservbyname(name, protocol)) != NULL)
      return ntohs(service->s_port);
  } else if (port >= 0 || port <= 0xFFFF) {
    return port;
  }
  {
    printf("Problem with specified %s port '%s'", protocol ? protocol : "", name);
    printf(".\n");
    exit(-1);
  };
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_port>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L18
  test   %rbp,%rbp
  je     L34
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  je     L15
  mov    (%rax),%edi
  call   <ntohs@plt>
  jmp    L18
L34:
  lea    D12(%rip),%rbp
L15:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string
name: read_data
arguments: data_tag: D26
data_type: string

tool: 

tool: D7: Problem with specified %s port '%s'

tool: D26: .

assistant: ```c
uint16_t parse_port(const char *protocol, const char *name) {
  struct servent *service;
  char *end;
  int port;
  port = strtol(name, &end, 10);
  if (*end != '\0') {
    if (protocol && (service = getservbyname(name, protocol)) != NULL)
      return ntohs(service->s_port);
  } else if (port >= 0 || port <= 0xFFFF) {
    return port;
  }
  {
    printf("Problem with specified %s port '%s'", protocol ? protocol : "", name);
    printf(".\n");
    exit(-1);
  };
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_port>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0xa,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L32
  test   %rbp,%rbp
  je     L21
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  jne    L3
L59:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  xor    %eax,%eax
L32:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    D25(%rip),%rbp
  jmp    L59
  nopl   0x0(%rax)
L3:
  mov    (%rax),%edi
  call   <ntohs@plt>
  jmp    L32
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D20: Problem with specified %s port '%s'

tool: D7: .

tool: 

assistant: ```c
uint16_t parse_port(const char *protocol, const char *name) {
  struct servent *service;
  char *end;
  int port;
  port = strtol(name, &end, 10);
  if (*end != '\0') {
    if (protocol && (service = getservbyname(name, protocol)) != NULL)
      return ntohs(service->s_port);
  } else if (port >= 0 || port <= 0xFFFF) {
    return port;
  }
  {
    printf("Problem with specified %s port '%s'", protocol ? protocol : "", name);
    printf(".\n");
    exit(-1);
  };
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_port>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0xa,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L51
  test   %rbp,%rbp
  je     L21
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <getservbyname@plt>
  test   %rax,%rax
  jne    L2
L37:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  xor    %eax,%eax
L51:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  lea    D3(%rip),%rbp
  jmp    L37
  nopl   0x0(%rax)
L2:
  mov    (%rax),%edi
  call   <ntohs@plt>
  jmp    L51
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D29: Problem with specified %s port '%s'

tool: D8: .

tool: 

assistant: ```c
uint16_t parse_port(const char *protocol, const char *name) {
  struct servent *service;
  char *end;
  int port;
  port = strtol(name, &end, 10);
  if (*end != '\0') {
    if (protocol && (service = getservbyname(name, protocol)) != NULL)
      return ntohs(service->s_port);
  } else if (port >= 0 || port <= 0xFFFF) {
    return port;
  }
  {
    printf("Problem with specified %s port '%s'", protocol ? protocol : "", name);
    printf(".\n");
    exit(-1);
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vp8_filter_block2d_second_pass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%eax
  mov    0x38(%rsp),%r14d
  mov    0x40(%rsp),%rdx
  test   %r9d,%r9d
  je     L17
  mov    %rsi,%rbx
  mov    %r9d,%r13d
  mov    %r8d,%r10d
  neg    %r10d
  add    %r10d,%r10d
  movslq %r10d,%r10
  shl    $0x2,%r10
  mov    %r8d,%r11d
  neg    %r11d
  movslq %r11d,%r11
  shl    $0x2,%r11
  mov    %r8d,%ebp
  shl    $0x2,%rbp
  lea    (%r8,%r8,1),%esi
  mov    %esi,%r9d
  shl    $0x2,%r9
  lea    (%rsi,%r8,1),%r8d
  shl    $0x2,%r8
  sub    %r14d,%ecx
  lea    0x0(,%rcx,4),%rsi
  mov    %rsi,-0x18(%rsp)
  lea    -0x1(%r14),%ecx
  lea    0x4(,%rcx,4),%rsi
  mov    %rsi,-0x10(%rsp)
  mov    $0x0,%r12d
  cltq
  mov    %rax,-0x8(%rsp)
  jmp    L32
L51:
  movswl (%rdx),%eax
  imul   (%rdi,%r10,1),%eax
  movswl 0x2(%rdx),%r15d
  imul   (%rdi,%r11,1),%r15d
  add    %r15d,%eax
  movswl 0x4(%rdx),%r15d
  imul   (%rdi),%r15d
  add    %r15d,%eax
  movswl 0x6(%rdx),%r15d
  imul   (%rdi,%rbp,1),%r15d
  add    %r15d,%eax
  movswl 0x8(%rdx),%r15d
  imul   (%rdi,%r9,1),%r15d
  add    %r15d,%eax
  movswl 0xa(%rdx),%r15d
  imul   (%rdi,%r8,1),%r15d
  lea    0x40(%rax,%r15,1),%eax
  sar    $0x7,%eax
  mov    $0xff,%r15d
  cmp    %r15d,%eax
  cmovg  %r15d,%eax
  test   %eax,%eax
  mov    $0x0,%r15d
  cmovs  %r15d,%eax
  mov    %al,(%rcx)
  add    $0x4,%rdi
  add    $0x1,%rcx
  cmp    %rsi,%rdi
  jne    L51
L39:
  mov    -0x18(%rsp),%rax
  lea    (%rsi,%rax,1),%rdi
  add    -0x8(%rsp),%rbx
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  je     L17
L32:
  mov    %rbx,%rcx
  mov    -0x10(%rsp),%rax
  lea    (%rdi,%rax,1),%rsi
  test   %r14d,%r14d
  jne    L51
  mov    %rdi,%rsi
  jmp    L39
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void vp8_filter_block2d_second_pass(int *src_ptr, unsigned char *output_ptr, int output_pitch, unsigned int src_pixels_per_line, unsigned int pixel_step, unsigned int output_height, unsigned int output_width, const short *vp8_filter) {
  unsigned int i, j;
  int Temp;
  for (i = 0; i < output_height; i++) {
    for (j = 0; j < output_width; j++) {
      Temp = ((int)src_ptr[-2 * (int)pixel_step] * vp8_filter[0]) + ((int)src_ptr[-1 * (int)pixel_step] * vp8_filter[1]) + ((int)src_ptr[0] * vp8_filter[2]) + ((int)src_ptr[pixel_step] * vp8_filter[3]) + ((int)src_ptr[2 * pixel_step] * vp8_filter[4]) + ((int)src_ptr[3 * pixel_step] * vp8_filter[5]) + (128 >> 1);
      Temp = Temp >> 7;
      if (Temp < 0)
        Temp = 0;
      else if (Temp > 255)
        Temp = 255;
      output_ptr[j] = (unsigned char)Temp;
      src_ptr++;
    }
    src_ptr += src_pixels_per_line - output_width;
    output_ptr += output_pitch;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vp8_filter_block2d_second_pass>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    0x40(%rsp),%rdx
  mov    %r9d,-0xc(%rsp)
  test   %r9d,%r9d
  je     L34
  mov    %ecx,%eax
  sub    0x38(%rsp),%eax
  mov    %r8d,%ecx
  mov    %r8d,%r11d
  shl    $0x2,%rax
  neg    %ecx
  lea    (%r8,%r8,2),%r8d
  shl    $0x2,%r11
  mov    %rax,-0x8(%rsp)
  mov    0x38(%rsp),%eax
  lea    (%rcx,%rcx,1),%r9d
  movslq %ecx,%rcx
  movslq %r9d,%rbp
  neg    %r9d
  shl    $0x2,%r8
  xor    %r12d,%r12d
  sub    $0x1,%eax
  shl    $0x2,%rbp
  lea    0x0(,%rcx,4),%r10
  shl    $0x2,%r9
  lea    0x4(,%rax,4),%r14
  nopl   0x0(%rax)
L31:
  mov    0x38(%rsp),%eax
  mov    %rbx,%rcx
  lea    (%rdi,%r14,1),%rsi
  test   %eax,%eax
  je     L13
  nopl   0x0(%rax,%rax,1)
L47:
  movswl (%rdx),%eax
  movswl 0x2(%rdx),%r15d
  imul   (%rdi,%rbp,1),%eax
  imul   (%rdi,%r10,1),%r15d
  add    %r15d,%eax
  movswl 0x4(%rdx),%r15d
  imul   (%rdi),%r15d
  add    %r15d,%eax
  movswl 0x6(%rdx),%r15d
  imul   (%rdi,%r11,1),%r15d
  add    %r15d,%eax
  movswl 0x8(%rdx),%r15d
  imul   (%rdi,%r9,1),%r15d
  add    %r15d,%eax
  movswl 0xa(%rdx),%r15d
  imul   (%rdi,%r8,1),%r15d
  lea    0x40(%rax,%r15,1),%eax
  mov    $0xff,%r15d
  sar    $0x7,%eax
  cmp    %r15d,%eax
  cmovg  %r15d,%eax
  xor    %r15d,%r15d
  test   %eax,%eax
  cmovs  %r15d,%eax
  add    $0x4,%rdi
  add    $0x1,%rcx
  mov    %al,-0x1(%rcx)
  cmp    %rsi,%rdi
  jne    L47
L26:
  mov    -0x8(%rsp),%rax
  add    %r13,%rbx
  add    $0x1,%r12d
  lea    (%rsi,%rax,1),%rdi
  cmp    %r12d,-0xc(%rsp)
  jne    L31
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    %rdi,%rsi
  jmp    L26
```

assistant: ```c
void vp8_filter_block2d_second_pass(int *src_ptr, unsigned char *output_ptr, int output_pitch, unsigned int src_pixels_per_line, unsigned int pixel_step, unsigned int output_height, unsigned int output_width, const short *vp8_filter) {
  unsigned int i, j;
  int Temp;
  for (i = 0; i < output_height; i++) {
    for (j = 0; j < output_width; j++) {
      Temp = ((int)src_ptr[-2 * (int)pixel_step] * vp8_filter[0]) + ((int)src_ptr[-1 * (int)pixel_step] * vp8_filter[1]) + ((int)src_ptr[0] * vp8_filter[2]) + ((int)src_ptr[pixel_step] * vp8_filter[3]) + ((int)src_ptr[2 * pixel_step] * vp8_filter[4]) + ((int)src_ptr[3 * pixel_step] * vp8_filter[5]) + (128 >> 1);
      Temp = Temp >> 7;
      if (Temp < 0)
        Temp = 0;
      else if (Temp > 255)
        Temp = 255;
      output_ptr[j] = (unsigned char)Temp;
      src_ptr++;
    }
    src_ptr += src_pixels_per_line - output_width;
    output_ptr += output_pitch;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thin_log_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void thin_log_err(const char *message, ...) {
  va_list args;
  va_start(args, message);
  vsyslog(LOG_EMERG, message, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thin_log_err>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void thin_log_err(const char *message, ...) {
  va_list args;
  va_start(args, message);
  vsyslog(LOG_EMERG, message, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thin_log_err>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void thin_log_err(const char *message, ...) {
  va_list args;
  va_start(args, message);
  vsyslog(LOG_EMERG, message, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below?

```asm
<thin_log_err>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vsyslog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void thin_log_err(const char *message, ...) {
  va_list args;
  va_start(args, message);
  vsyslog(LOG_EMERG, message, args);
  va_end(args);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ina_set_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <ina_write@plt>
  movzbl -0x4(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    $0x16,%esi
  mov    %eax,%edi
  call   <ina_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void ina_set_reg(unsigned char addr, unsigned int configure, unsigned int calibration) {
  ina_write(addr, 0x00, configure);
  ina_write(addr, 0x16, calibration);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ina_set_reg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  movzbl %dil,%ebx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <ina_write@plt>
  mov    %ebp,%edx
  mov    $0x16,%esi
  mov    %ebx,%edi
  call   <ina_write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ina_set_reg(unsigned char addr, unsigned int configure, unsigned int calibration) {
  ina_write(addr, 0x00, configure);
  ina_write(addr, 0x16, calibration);
}
```