ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_gets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L22
  cmpl   $0x0,-0x8(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L49
L22:
  cmpl   $0xa,-0x4(%rbp)
  je     L68
  cmpl   $0xd,-0x4(%rbp)
  je     L68
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L34
L68:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
L49:
  leave
  ret
```

assistant: ```c
char *_gets(int fd, char *buf, int len) {
  int ch, i = 0;
  while (i < len) {
    if ((ch = __getchar(fd)) == (-1) && i == 0)
      return NULL;
    if (ch == '\n' || ch == '\r')
      break;
    buf[i++] = ch;
  }
  buf[i] = 0;
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_gets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %edx,%edx
  jle    L24
  mov    %edi,%r14d
  mov    %edx,%r13d
  mov    %rsi,%r12
  mov    $0x0,%ebx
  jmp    L55
L0:
  cmp    $0xa,%eax
  je     L9
  cmp    $0xd,%eax
  je     L9
  add    $0x1,%ebx
  mov    %al,(%r12)
  add    $0x1,%r12
  cmp    %ebx,%r13d
  je     L63
L55:
  mov    %r14d,%edi
  call   <__getchar@plt>
  test   %ebx,%ebx
  jne    L0
  cmp    $0xffffffff,%eax
  jne    L0
  mov    $0x0,%eax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  mov    %r13d,%ebx
L9:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  jmp    L19
L24:
  mov    $0x0,%ebx
  jmp    L9
```

assistant: ```c
char *_gets(int fd, char *buf, int len) {
  int ch, i = 0;
  while (i < len) {
    if ((ch = __getchar(fd)) == (-1) && i == 0)
      return NULL;
    if (ch == '\n' || ch == '\r')
      break;
    buf[i++] = ch;
  }
  buf[i] = 0;
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<_gets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L49
  mov    %edi,%r14d
  mov    %rsi,%r13
  xor    %ebx,%ebx
L61:
  mov    %r14d,%edi
  call   <__getchar@plt>
  cmp    $0xffffffff,%eax
  je     L28
  cmp    $0xa,%eax
  je     L0
  cmp    $0xd,%eax
  je     L0
L29:
  add    $0x1,%ebx
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    %ebx,%r12d
  jne    L61
  add    %rbp,%r12
L36:
  movb   $0x0,(%r12)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  test   %ebx,%ebx
  jne    L29
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L0:
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%r12
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rsi,%r12
  jmp    L36
```

assistant: ```c
char *_gets(int fd, char *buf, int len) {
  int ch, i = 0;
  while (i < len) {
    if ((ch = __getchar(fd)) == (-1) && i == 0)
      return NULL;
    if (ch == '\n' || ch == '\r')
      break;
    buf[i++] = ch;
  }
  buf[i] = 0;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_gets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L48
  mov    %edi,%r14d
  mov    %rsi,%r13
  xor    %ebx,%ebx
L10:
  mov    %r14d,%edi
  call   <__getchar@plt>
  cmp    $0xffffffff,%eax
  je     L75
  cmp    $0xa,%eax
  je     L23
  cmp    $0xd,%eax
  je     L23
L59:
  add    $0x1,%ebx
  mov    %al,0x0(%r13)
  add    $0x1,%r13
  cmp    %ebx,%r12d
  jne    L10
  add    %rbp,%r12
L43:
  movb   $0x0,(%r12)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  test   %ebx,%ebx
  jne    L59
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L23:
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%r12
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %rsi,%r12
  jmp    L43
```

assistant: ```c
char *_gets(int fd, char *buf, int len) {
  int ch, i = 0;
  while (i < len) {
    if ((ch = __getchar(fd)) == (-1) && i == 0)
      return NULL;
    if (ch == '\n' || ch == '\r')
      break;
    buf[i++] = ch;
  }
  buf[i] = 0;
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<agbnp3_errprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void agbnp3_errprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
#pragma omp critical
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<agbnp3_errprint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void agbnp3_errprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
#pragma omp critical
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<agbnp3_errprint>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void agbnp3_errprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
#pragma omp critical
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<agbnp3_errprint>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void agbnp3_errprint(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
#pragma omp critical
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x18000(%rsp),%r11
L36:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L36
  sub    $0x6c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x186b4(%rbp)
  lea    -0x186b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x186b8(%rbp)
L8:
  mov    -0x186b8(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  test   %al,%al
  je     L28
  mov    -0x186b8(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  cmp    $0x40,%al
  jle    L29
  mov    -0x186b8(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  cmp    $0x5a,%al
  jg     L29
  addl   $0x1,-0x186b4(%rbp)
L29:
  addl   $0x1,-0x186b8(%rbp)
  jmp    L8
L28:
  nop
  mov    -0x186b4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D1: %s

tool: D18: %i


assistant: ```c
int main() {
  int i, count = 0;
  char array[100000];
  scanf("%s", array);
  for (i = 0;; i++) {
    if (array[i] == '\0')
      break;
    if (array[i] >= 'A' && array[i] <= 'Z')
      count++;
  }
  printf("%i\n", count + 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  lea    -0x18000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x6b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L5
  lea    0x1(%rsp),%rdx
  mov    $0x0,%esi
L19:
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%esi
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L19
L18:
  add    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x186b8,%rsp
  ret
L5:
  mov    $0x0,%esi
  jmp    L18
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D3: %s

tool: D13: %i


assistant: ```c
int main() {
  int i, count = 0;
  char array[100000];
  scanf("%s", array);
  for (i = 0;; i++) {
    if (array[i] == '\0')
      break;
    if (array[i] >= 'A' && array[i] <= 'Z')
      count++;
  }
  printf("%i\n", count + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  lea    -0x18000(%rsp),%r11
L44:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L44
  sub    $0x6b8,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L36
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopl   (%rax)
L0:
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%esi
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L0
L31:
  add    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x186b8,%rsp
  ret
L36:
  xor    %esi,%esi
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D5: %s

tool: D7: %i


assistant: ```c
int main() {
  int i, count = 0;
  char array[100000];
  scanf("%s", array);
  for (i = 0;; i++) {
    if (array[i] == '\0')
      break;
    if (array[i] >= 'A' && array[i] <= 'Z')
      count++;
  }
  printf("%i\n", count + 1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  lea    -0x18000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0x6b8,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L24
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopl   (%rax)
L18:
  sub    $0x41,%eax
  cmp    $0x1a,%al
  adc    $0x0,%esi
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L18
L9:
  add    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x186b8,%rsp
  ret
L24:
  xor    %esi,%esi
  jmp    L9
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D12: %s

tool: D1: %i


assistant: ```c
int main() {
  int i, count = 0;
  char array[100000];
  scanf("%s", array);
  for (i = 0;; i++) {
    if (array[i] == '\0')
      break;
    if (array[i] >= 'A' && array[i] <= 'Z')
      count++;
  }
  printf("%i\n", count + 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcat5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <Malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rdi
  mov    -0x38(%rbp),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x48(%rbp)
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: %s%s%s%s%s

assistant: ```c
char *strcat5(char *s1, char *s2, char *s3, char *s4, char *s5) {
  char *s;
  s = (char *)Malloc(strlen(s1) + strlen(s2) + strlen(s3) + strlen(s4) + strlen(s5) + 1);
  sprintf(s, "%s%s%s%s%s", s1, s2, s3, s4, s5);
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcat5>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rcx,%r14
  mov    %r8,%r15
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,0x8(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,0x10(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,0x18(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  add    0x8(%rsp),%rbx
  add    0x10(%rsp),%rbx
  add    0x18(%rsp),%rbx
  lea    0x1(%rbx,%rax,1),%rdi
  call   <Malloc@plt>
  mov    %rax,%rbx
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: %s%s%s%s%s

assistant: ```c
char *strcat5(char *s1, char *s2, char *s3, char *s4, char *s5) {
  char *s;
  s = (char *)Malloc(strlen(s1) + strlen(s2) + strlen(s3) + strlen(s4) + strlen(s5) + 1);
  sprintf(s, "%s%s%s%s%s", s1, s2, s3, s4, s5);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcat5>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  mov    0x18(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  add    0x8(%rsp),%rbx
  add    0x10(%rsp),%rbx
  add    %r13,%rbx
  lea    0x1(%rbx,%rax,1),%rdi
  call   <Malloc@plt>
  sub    $0x8,%rsp
  mov    %r15,%r8
  mov    %r14,%rcx
  push   %rbp
  mov    0x28(%rsp),%r9
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: %s%s%s%s%s

assistant: ```c
char *strcat5(char *s1, char *s2, char *s3, char *s4, char *s5) {
  char *s;
  s = (char *)Malloc(strlen(s1) + strlen(s2) + strlen(s3) + strlen(s4) + strlen(s5) + 1);
  sprintf(s, "%s%s%s%s%s", s1, s2, s3, s4, s5);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat5>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %rax,0x8(%rsp)
  call   <strlen@plt>
  mov    0x18(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  add    0x8(%rsp),%rbx
  add    0x10(%rsp),%rbx
  add    %r13,%rbx
  lea    0x1(%rbx,%rax,1),%rdi
  call   <Malloc@plt>
  sub    $0x8,%rsp
  mov    %r15,%r8
  mov    %r14,%rcx
  push   %rbp
  mov    0x28(%rsp),%r9
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: %s%s%s%s%s

assistant: ```c
char *strcat5(char *s1, char *s2, char *s3, char *s4, char *s5) {
  char *s;
  s = (char *)Malloc(strlen(s1) + strlen(s2) + strlen(s3) + strlen(s4) + strlen(s5) + 1);
  sprintf(s, "%s%s%s%s%s", s1, s2, s3, s4, s5);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putstr_non_printable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L3
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L22
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putnbr_16_base@plt>
  jmp    L16
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
L16:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_putstr_non_printable(char *str) {
  while (str[0]) {
    if (str[0] <= 31) {
      ft_putchar('\\');
      ft_putnbr_16_base(str[0]);
    } else
      ft_putchar(str[0]);
    str++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_putstr_non_printable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L21
L4:
  pop    %rbx
  ret
L35:
  movsbl %dil,%edi
  call   <ft_putchar@plt>
L39:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L4
L21:
  cmp    $0x1f,%dil
  jg     L35
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  movsbl (%rbx),%edi
  call   <ft_putnbr_16_base@plt>
  jmp    L39
```

assistant: ```c
void ft_putstr_non_printable(char *str) {
  while (str[0]) {
    if (str[0] <= 31) {
      ft_putchar('\\');
      ft_putnbr_16_base(str[0]);
    } else
      ft_putchar(str[0]);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putstr_non_printable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L20
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x5c,%edi
  add    $0x1,%rbx
  call   <ft_putchar@plt>
  movsbl -0x1(%rbx),%edi
  call   <ft_putnbr_16_base@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L28
L20:
  cmp    $0x1f,%dil
  jle    L0
  call   <ft_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L20
L28:
  pop    %rbx
  ret
```

assistant: ```c
void ft_putstr_non_printable(char *str) {
  while (str[0]) {
    if (str[0] <= 31) {
      ft_putchar('\\');
      ft_putnbr_16_base(str[0]);
    } else
      ft_putchar(str[0]);
    str++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_putstr_non_printable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L28
L31:
  cmp    $0x1f,%dil
  jg     L34
  mov    $0x5c,%edi
  add    $0x1,%rbx
  call   <ft_putchar@plt>
  movsbl -0x1(%rbx),%edi
  call   <ft_putnbr_16_base@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L31
L28:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  call   <ft_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L31
  pop    %rbx
  ret
```

assistant: ```c
void ft_putstr_non_printable(char *str) {
  while (str[0]) {
    if (str[0] <= 31) {
      ft_putchar('\\');
      ft_putnbr_16_base(str[0]);
    } else
      ft_putchar(str[0]);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  rol    %rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        } else {
          state[local1] *= state[0UL];
        }
      } else if (state[0UL] == local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = copy13;
        copy14 = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
      } else {
        state[0UL] |= (state[0UL] * state[0UL] & 63UL) << 4UL;
        state[local1] = (state[0UL] << (((state[0UL] >> 4UL) & 15UL) | 1UL)) | (state[0UL] >> (64 - (((state[0UL] >> 4UL) & 15UL) | 1UL)));
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 1UL) | (state[0UL] >> 63UL);
  }
}
```