ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movdqa D35(%rip),%xmm0
  mov    $0xe,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D16(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D27(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <printMajority@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D17
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D16
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D27
data_type: byte[16]

tool: {"D35": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D17": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D16": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D27": [0x06,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a[] = {1, 3, 3, 3, 2, 1, 1, 3, 6, 3, 3, 3, 3, 3};
  int size = sizeof(a) / sizeof(*a);
  printMajority(a, size);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f4@plt>
  mov    $0x0,%eax
  call   <f5@plt>
  mov    $0x0,%eax
  call   <f6@plt>
  mov    $0x0,%eax
  call   <pf1@plt>
  mov    $0x0,%eax
  call   <pf2@plt>
  mov    $0x0,%eax
  call   <pf3@plt>
  mov    $0x0,%eax
  call   <pf4@plt>
  mov    $0x0,%eax
  call   <pf5@plt>
  mov    $0x0,%eax
  call   <pf6@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  f4();
  f5();
  f6();
  pf1();
  pf2();
  pf3();
  pf4();
  pf5();
  pf6();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f4@plt>
  mov    $0x0,%eax
  call   <f5@plt>
  mov    $0x0,%eax
  call   <f6@plt>
  mov    $0x0,%eax
  call   <pf1@plt>
  mov    $0x0,%eax
  call   <pf2@plt>
  mov    $0x0,%eax
  call   <pf3@plt>
  mov    $0x0,%eax
  call   <pf4@plt>
  mov    $0x0,%eax
  call   <pf5@plt>
  mov    $0x0,%eax
  call   <pf6@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  f4();
  f5();
  f6();
  pf1();
  pf2();
  pf3();
  pf4();
  pf5();
  pf6();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f4@plt>
  xor    %eax,%eax
  call   <f5@plt>
  xor    %eax,%eax
  call   <f6@plt>
  xor    %eax,%eax
  call   <pf1@plt>
  xor    %eax,%eax
  call   <pf2@plt>
  xor    %eax,%eax
  call   <pf3@plt>
  xor    %eax,%eax
  call   <pf4@plt>
  xor    %eax,%eax
  call   <pf5@plt>
  xor    %eax,%eax
  call   <pf6@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  f4();
  f5();
  f6();
  pf1();
  pf2();
  pf3();
  pf4();
  pf5();
  pf6();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exit_self_inserting>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <char_to_string@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert_string@plt>
  mov    $0x0,%eax
  call   <exit_minibuffer@plt>
  nop
  leave
  ret
```

assistant: ```c
void exit_self_inserting(int c) {
  char *str = char_to_string(c);
  insert_string(str, strlen(str));
  exit_minibuffer();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exit_self_inserting>:
  endbr64
  push   %rbx
  call   <char_to_string@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <insert_string@plt>
  mov    $0x0,%eax
  call   <exit_minibuffer@plt>
  pop    %rbx
  ret
```

assistant: ```c
void exit_self_inserting(int c) {
  char *str = char_to_string(c);
  insert_string(str, strlen(str));
  exit_minibuffer();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<exit_self_inserting>:
  endbr64
  push   %rbp
  call   <char_to_string@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <insert_string@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <exit_minibuffer@plt>
```

assistant: ```c
void exit_self_inserting(int c) {
  char *str = char_to_string(c);
  insert_string(str, strlen(str));
  exit_minibuffer();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exit_self_inserting>:
  endbr64
  push   %rbp
  call   <char_to_string@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <insert_string@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <exit_minibuffer@plt>
```

assistant: ```c
void exit_self_inserting(int c) {
  char *str = char_to_string(c);
  insert_string(str, strlen(str));
  exit_minibuffer();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<btrfs_tree_unlock_rw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L63
  cmpl   $0x3,-0xc(%rbp)
  jne    L4
L63:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <btrfs_tree_unlock@plt>
  jmp    L61
L4:
  cmpl   $0x4,-0xc(%rbp)
  jne    L28
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <btrfs_tree_read_unlock_blocking@plt>
  jmp    L61
L28:
  cmpl   $0x2,-0xc(%rbp)
  jne    L22
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <btrfs_tree_read_unlock@plt>
  jmp    L61
L22:
  mov    $0x0,%eax
  call   <BUG@plt>
L61:
  nop
  leave
  ret
```

assistant: ```c
void btrfs_tree_unlock_rw(struct extent_buffer *eb, int rw) {
  if (rw == 1 || rw == 3) {
    btrfs_tree_unlock(eb);
  } else if (rw == 4) {
    btrfs_tree_read_unlock_blocking(eb);
  } else if (rw == 2) {
    btrfs_tree_read_unlock(eb);
  } else {
    BUG();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<btrfs_tree_unlock_rw>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%eax
  je     L30
  cmp    $0x4,%esi
  je     L53
  cmp    $0x2,%esi
  je     L52
  mov    $0x0,%eax
  call   <BUG@plt>
L48:
  add    $0x8,%rsp
  ret
L30:
  call   <btrfs_tree_unlock@plt>
  jmp    L48
L53:
  call   <btrfs_tree_read_unlock_blocking@plt>
  jmp    L48
L52:
  call   <btrfs_tree_read_unlock@plt>
  jmp    L48
```

assistant: ```c
void btrfs_tree_unlock_rw(struct extent_buffer *eb, int rw) {
  if (rw == 1 || rw == 3) {
    btrfs_tree_unlock(eb);
  } else if (rw == 4) {
    btrfs_tree_read_unlock_blocking(eb);
  } else if (rw == 2) {
    btrfs_tree_read_unlock(eb);
  } else {
    BUG();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<btrfs_tree_unlock_rw>:
  endbr64
  mov    %esi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%eax
  je     L6
  cmp    $0x4,%esi
  je     L12
  cmp    $0x2,%esi
  je     L25
  xor    %eax,%eax
  jmp    10b0 <BUG@plt>
  nop
L6:
  jmp    10a0 <btrfs_tree_unlock@plt>
  nopl   (%rax)
L25:
  jmp    1090 <btrfs_tree_read_unlock@plt>
  nopl   (%rax)
L12:
  jmp    1080 <btrfs_tree_read_unlock_blocking@plt>
```

assistant: ```c
void btrfs_tree_unlock_rw(struct extent_buffer *eb, int rw) {
  if (rw == 1 || rw == 3) {
    btrfs_tree_unlock(eb);
  } else if (rw == 4) {
    btrfs_tree_read_unlock_blocking(eb);
  } else if (rw == 2) {
    btrfs_tree_read_unlock(eb);
  } else {
    BUG();
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<btrfs_tree_unlock_rw>:
  endbr64
  mov    %esi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%eax
  je     L20
  cmp    $0x4,%esi
  je     L6
  cmp    $0x2,%esi
  je     L26
  xor    %eax,%eax
  jmp    10b0 <BUG@plt>
  nop
L20:
  jmp    10a0 <btrfs_tree_unlock@plt>
  nopl   (%rax)
L26:
  jmp    1090 <btrfs_tree_read_unlock@plt>
  nopl   (%rax)
L6:
  jmp    1080 <btrfs_tree_read_unlock_blocking@plt>
```

assistant: ```c
void btrfs_tree_unlock_rw(struct extent_buffer *eb, int rw) {
  if (rw == 1 || rw == 3) {
    btrfs_tree_unlock(eb);
  } else if (rw == 4) {
    btrfs_tree_read_unlock_blocking(eb);
  } else if (rw == 2) {
    btrfs_tree_read_unlock(eb);
  } else {
    BUG();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<avl_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  cmpq   $0x0,-0x10(%rbp)
  je     L20
  mov    $0x1,%eax
  jmp    L17
L20:
  mov    $0x0,%eax
L17:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void avl_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<avl_free>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void avl_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<avl_free>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void avl_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<avl_free>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void avl_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile


assistant: ```c
void usage(char const *progname) {
  {
    printf((char const *__restrict)"usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile\n", progname);
    exit(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile


assistant: ```c
void usage(char const *progname) {
  {
    printf((char const *__restrict)"usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile\n", progname);
    exit(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile


assistant: ```c
void usage(char const *progname) {
  {
    printf((char const *__restrict)"usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile\n", progname);
    exit(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D6
datatype: string

tool: D6: usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile


assistant: ```c
void usage(char const *progname) {
  {
    printf((char const *__restrict)"usage: %s Experimentspecification gaborimagedir graph_directory output_directory maskfile\n", progname);
    exit(1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  subl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jg     L13
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = argc - 1; i > 0; i--)
    reverse(argv[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%ebx
  test   %ebx,%ebx
  jle    L18
  mov    %rsi,%rbp
  movslq %ebx,%rbx
L8:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <reverse@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L8
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = argc - 1; i > 0; i--)
    reverse(argv[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L2
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <reverse@plt>
  test   %ebx,%ebx
  jg     L0
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = argc - 1; i > 0; i--)
    reverse(argv[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L17
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <reverse@plt>
  test   %ebx,%ebx
  jg     L7
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = argc - 1; i > 0; i--)
    reverse(argv[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L48
L40:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  je     L5
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  jne    L29
L5:
  mov    $0x0,%eax
  jmp    L13
L29:
  lea    -0xc(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L40
  mov    $0x1,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!_is_hex(tmpBuf[0]) || !_is_hex(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)NULL, 16);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L4
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  sub    $0x1,%edx
  shr    %edx
  mov    %edx,%edx
  lea    0x2(%rdi,%rdx,2),%r13
  lea    0x4(%rsp),%r12
L12:
  movzbl (%rbx),%edi
  mov    %dil,0x4(%rsp)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  movsbl %dil,%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  je     L5
  movsbl 0x5(%rsp),%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  je     L5
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %al,0x0(%rbp)
  add    $0x2,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L12
  mov    $0x1,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x1,%eax
  jmp    L5
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!_is_hex(tmpBuf[0]) || !_is_hex(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)NULL, 16);
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L3
  sub    $0x1,%edx
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbp
  shr    %edx
  lea    0x2(%rdi,%rdx,2),%r13
  jmp    L52
  nopl   (%rax)
L18:
  movsbl 0x5(%rsp),%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  je     L5
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <strtol@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbx
  je     L3
L52:
  movsbl (%rbx),%edi
  movzbl 0x1(%rbx),%eax
  movb   $0x0,0x6(%rsp)
  mov    %dil,0x4(%rsp)
  mov    %al,0x5(%rsp)
  call   <_is_hex@plt>
  test   %eax,%eax
  jne    L18
L5:
  xor    %eax,%eax
L63:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%eax
  jmp    L63
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!_is_hex(tmpBuf[0]) || !_is_hex(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)NULL, 16);
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L69
  sub    $0x1,%edx
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbp
  shr    %edx
  lea    0x2(%rdi,%rdx,2),%r13
  jmp    L23
  nopl   (%rax)
L7:
  movsbl 0x5(%rsp),%edi
  call   <_is_hex@plt>
  test   %eax,%eax
  je     L34
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <strtol@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbx
  je     L69
L23:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  movb   $0x0,0x6(%rsp)
  mov    %dil,%al
  mov    0x1(%rbx),%ah
  mov    %ax,0x4(%rsp)
  call   <_is_hex@plt>
  test   %eax,%eax
  jne    L7
L34:
  xor    %eax,%eax
L56:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  mov    $0x1,%eax
  jmp    L56
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!_is_hex(tmpBuf[0]) || !_is_hex(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)NULL, 16);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CANDataRegRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CANDataRegRead(unsigned char *pucData, unsigned long *pulRegister, int iSize) {
  int iIdx;
  unsigned char *pucRegister = (unsigned char *)pulRegister;
  for (iIdx = 0; iIdx < iSize; iIdx++) {
    pucData[iIdx] = (*((volatile unsigned char *)(pucRegister++)));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CANDataRegRead>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  add    %rsi,%rdx
L18:
  mov    %rsi,%rax
  add    $0x1,%rsi
  movzbl (%rax),%eax
  mov    %al,(%rdi)
  add    $0x1,%rdi
  cmp    %rdx,%rsi
  jne    L18
L17:
  ret
```

assistant: ```c
void CANDataRegRead(unsigned char *pucData, unsigned long *pulRegister, int iSize) {
  int iIdx;
  unsigned char *pucRegister = (unsigned char *)pulRegister;
  for (iIdx = 0; iIdx < iSize; iIdx++) {
    pucData[iIdx] = (*((volatile unsigned char *)(pucRegister++)));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CANDataRegRead>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  add    %rsi,%rdx
  xchg   %ax,%ax
L18:
  mov    %rsi,%rax
  add    $0x1,%rsi
  add    $0x1,%rdi
  movzbl (%rax),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rsi
  jne    L18
L11:
  ret
```

assistant: ```c
void CANDataRegRead(unsigned char *pucData, unsigned long *pulRegister, int iSize) {
  int iIdx;
  unsigned char *pucRegister = (unsigned char *)pulRegister;
  for (iIdx = 0; iIdx < iSize; iIdx++) {
    pucData[iIdx] = (*((volatile unsigned char *)(pucRegister++)));
  }
}
```