ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L38
  mov    $0x1,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L38:
  movl   $0x0,-0x1c(%rbp)
  jmp    L22
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L22:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L19
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x7fffdbc6,%eax
  jne    L37
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L37:
  movl   $0x0,-0x18(%rbp)
  jmp    L15
L52:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L15:
  cmpl   $0x0,-0x18(%rbp)
  jle    L52
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string

tool: D22: Call this program with %i arguments


tool: D1: You win!

tool: D7: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2147474374U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L20
L26:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x7fffdbc6,0x4(%rsp)
  je     L25
L6:
  mov    0x4(%rsp),%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L26
L25:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D13
type: string

tool: D28: %u


tool: D5: Call this program with %i arguments


tool: D13: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2147474374U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L7
  lea    D23(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L7:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x7fffdbc6,%esi
  je     L39
L0:
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L39:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L0
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string

tool: D23: Call this program with %i arguments


tool: D18: %u


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2147474374U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L11
  lea    D1(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L11:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x7fffdbc6,%esi
  je     L22
L13:
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L13
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string
name: read_data
arguments: data_label: D8
data_type: string
name: read_data
arguments: data_label: D0
data_type: string

tool: D1: Call this program with %i arguments


tool: D8: %u


tool: D0: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 2147474374U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L53
  mov    -0x18(%rbp),%rax
  jmp    L56
L53:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L58
L4:
  subl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L52
  mov    -0x18(%rbp),%rax
  jmp    L56
L52:
  addq   $0x1,-0x18(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L4
  mov    $0x0,%eax
L56:
  leave
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L56
L37:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L56:
  mov    %eax,%ebp
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jg     L35
  mov    %r13,%rbx
  add    %eax,%r13d
L25:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L20
  add    $0x1,%rbx
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jge    L25
  mov    $0x0,%r13d
  jmp    L37
L35:
  mov    $0x0,%r13d
  jmp    L37
L20:
  mov    %rbx,%r13
  jmp    L37
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstr>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jne    L38
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L38:
  mov    %r12,%rdi
  mov    %eax,%ebp
  mov    %r12,%rbx
  call   <strlen@plt>
  lea    (%rax,%r12,1),%r12d
  cmp    %eax,%ebp
  jle    L36
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rbx
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jl     L46
L36:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L16
  add    $0x8,%rsp
  mov    %rbx,%r12
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L46:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jne    L21
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L21:
  mov    %r12,%rdi
  mov    %eax,%ebp
  mov    %r12,%rbx
  call   <strlen@plt>
  lea    (%rax,%r12,1),%r12d
  cmp    %eax,%ebp
  jle    L40
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rbx
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    %ebp,%eax
  jl     L4
L40:
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L22
  add    $0x8,%rsp
  mov    %rbx,%r12
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L4:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  int l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<human_readable_IPV4_from_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rsi
  mov    %eax,%edi
  call   <inet_ntop@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *human_readable_IPV4_from_number(const uint32_t ip, char *ip_str) {
  struct in_addr addr;
  addr.s_addr = ip;
  inet_ntop(AF_INET, &addr, ip_str, INET_ADDRSTRLEN);
  return ip_str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<human_readable_IPV4_from_number>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbx,%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <inet_ntop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *human_readable_IPV4_from_number(const uint32_t ip, char *ip_str) {
  struct in_addr addr;
  addr.s_addr = ip;
  inet_ntop(AF_INET, &addr, ip_str, INET_ADDRSTRLEN);
  return ip_str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<human_readable_IPV4_from_number>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %r12,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    (%rax),%ecx
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <inet_ntop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *human_readable_IPV4_from_number(const uint32_t ip, char *ip_str) {
  struct in_addr addr;
  addr.s_addr = ip;
  inet_ntop(AF_INET, &addr, ip_str, INET_ADDRSTRLEN);
  return ip_str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<human_readable_IPV4_from_number>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %r12,%rdx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    %edi,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    (%rax),%ecx
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <inet_ntop@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *human_readable_IPV4_from_number(const uint32_t ip, char *ip_str) {
  struct in_addr addr;
  addr.s_addr = ip;
  inet_ntop(AF_INET, &addr, ip_str, INET_ADDRSTRLEN);
  return ip_str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<EMACTimestampSysTimeUpdate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x400ec000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x710,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0x10(%rbp)
  je     L15
  mov    $0x0,%edx
  jmp    L10
L15:
  mov    $0x80000000,%edx
L10:
  mov    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x714,%eax
  cltq
  mov    %edx,(%rax)
  nop
L6:
  mov    -0x4(%rbp),%eax
  add    $0x700,%eax
  cltq
  mov    (%rax),%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L6
  mov    -0x4(%rbp),%eax
  add    $0x700,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x700,%edx
  movslq %edx,%rdx
  or     $0x8,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void EMACTimestampSysTimeUpdate(uint32_t ui32Base, uint32_t ui32Seconds, uint32_t ui32SubSeconds, bool bInc) {
  ASSERT(ui32Base == 0x400EC000);
  (*((volatile uint32_t *)(ui32Base + 0x00000710))) = ui32Seconds;
  (*((volatile uint32_t *)(ui32Base + 0x00000714))) = ui32SubSeconds | (bInc ? 0 : 0x80000000);
  while ((*((volatile uint32_t *)(ui32Base + 0x00000700))) & 0x00000008) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000008;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EMACTimestampSysTimeUpdate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %ecx,%r12d
  cmp    $0x400ec000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    0x710(%rbx),%eax
  cltq
  mov    %r13d,(%rax)
  lea    0x714(%rbx),%edx
  movslq %edx,%rdx
  test   %r12d,%r12d
  sete   %al
  movzbl %al,%eax
  shl    $0x1f,%eax
  or     %ebp,%eax
  mov    %eax,(%rdx)
  lea    0x700(%rbx),%eax
  cltq
L6:
  mov    (%rax),%edx
  test   $0x8,%dl
  jne    L6
  mov    (%rax),%edx
  or     $0x8,%edx
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void EMACTimestampSysTimeUpdate(uint32_t ui32Base, uint32_t ui32Seconds, uint32_t ui32SubSeconds, bool bInc) {
  ASSERT(ui32Base == 0x400EC000);
  (*((volatile uint32_t *)(ui32Base + 0x00000710))) = ui32Seconds;
  (*((volatile uint32_t *)(ui32Base + 0x00000714))) = ui32SubSeconds | (bInc ? 0 : 0x80000000);
  while ((*((volatile uint32_t *)(ui32Base + 0x00000700))) & 0x00000008) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000008;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EMACTimestampSysTimeUpdate>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400ec000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  lea    0x710(%rbx),%eax
  lea    0x714(%rbx),%edx
  cltq
  movslq %edx,%rdx
  mov    %r13d,(%rax)
  xor    %eax,%eax
  test   %r12d,%r12d
  sete   %al
  shl    $0x1f,%eax
  or     %ebp,%eax
  mov    %eax,(%rdx)
  lea    0x700(%rbx),%eax
  cltq
  nopl   0x0(%rax)
L1:
  mov    (%rax),%edx
  and    $0x8,%edx
  jne    L1
  mov    (%rax),%edx
  or     $0x8,%edx
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void EMACTimestampSysTimeUpdate(uint32_t ui32Base, uint32_t ui32Seconds, uint32_t ui32SubSeconds, bool bInc) {
  ASSERT(ui32Base == 0x400EC000);
  (*((volatile uint32_t *)(ui32Base + 0x00000710))) = ui32Seconds;
  (*((volatile uint32_t *)(ui32Base + 0x00000714))) = ui32SubSeconds | (bInc ? 0 : 0x80000000);
  while ((*((volatile uint32_t *)(ui32Base + 0x00000700))) & 0x00000008) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000008;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMACTimestampSysTimeUpdate>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400ec000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  lea    0x710(%rbx),%eax
  lea    0x714(%rbx),%edx
  cltq
  movslq %edx,%rdx
  mov    %r13d,(%rax)
  xor    %eax,%eax
  test   %r12d,%r12d
  sete   %al
  shl    $0x1f,%eax
  or     %ebp,%eax
  mov    %eax,(%rdx)
  lea    0x700(%rbx),%eax
  cltq
  nopl   0x0(%rax)
L0:
  mov    (%rax),%edx
  and    $0x8,%edx
  jne    L0
  mov    (%rax),%edx
  or     $0x8,%edx
  mov    %edx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void EMACTimestampSysTimeUpdate(uint32_t ui32Base, uint32_t ui32Seconds, uint32_t ui32SubSeconds, bool bInc) {
  ASSERT(ui32Base == 0x400EC000);
  (*((volatile uint32_t *)(ui32Base + 0x00000710))) = ui32Seconds;
  (*((volatile uint32_t *)(ui32Base + 0x00000714))) = ui32SubSeconds | (bInc ? 0 : 0x80000000);
  while ((*((volatile uint32_t *)(ui32Base + 0x00000700))) & 0x00000008) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000008;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char c, *c0 = malloc(0), *c1;
  c = *c0;
  c0 = realloc(c0, 10);
  assert(c0);
  c = *c0;
  c1 = c0;
  c0 = realloc(c0, 0);
  assert(!c0);
  c = *c1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0xa,%esi
  call   <realloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  char c, *c0 = malloc(0), *c1;
  c = *c0;
  c0 = realloc(c0, 10);
  assert(c0);
  c = *c0;
  c1 = c0;
  c0 = realloc(c0, 0);
  assert(!c0);
  c = *c1;
  return 0;
}
```