user: What would the C source look like for the assembly code provided here?

```asm
<dradf2>:
  endbr64
  mov    %esi,%eax
  push   %r15
  mov    %edi,%r9d
  mov    %esi,%r11d
  push   %r14
  imul   %edi,%eax
  mov    %rcx,%r10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdi,%rdi,1),%ebx
  mov    %rdx,-0x18(%rsp)
  mov    %eax,-0x8(%rsp)
  test   %esi,%esi
  jle    L107
  movslq %edi,%rax
  mov    -0x18(%rsp),%rdx
  movslq -0x8(%rsp),%rsi
  xor    %ecx,%ecx
  lea    0x0(,%rax,4),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L12:
  movss  (%rdx),%xmm0
  addss  (%rdx,%rsi,4),%xmm0
  movslq %eax,%rbp
  add    %ebx,%eax
  add    $0x1,%ecx
  movss  %xmm0,(%r10,%rbp,4)
  movss  (%rdx),%xmm0
  subss  (%rdx,%rsi,4),%xmm0
  movslq %eax,%rbp
  add    %rdi,%rdx
  movss  %xmm0,-0x4(%r10,%rbp,4)
  cmp    %ecx,%r11d
  jne    L12
L107:
  cmp    $0x1,%r9d
  jle    L82
  cmp    $0x2,%r9d
  je     L98
  mov    %r9d,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  test   %r11d,%r11d
  jle    L82
  movslq %r9d,%rax
  movslq -0x8(%rsp),%r14
  lea    (%r9,%r9,1),%r13d
  mov    %r10,%rdi
  mov    %rax,-0x10(%rsp)
  movslq %r13d,%r13
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  lea    0x0(,%rax,4),%r15
  shl    $0x2,%r14
  shl    $0x2,%r13
  mov    -0x18(%rsp),%rax
  lea    (%rax,%r14,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    (%rbx,%r12,2),%eax
  mov    %rsi,%rdx
  cltq
  sub    %r14,%rdx
  lea    (%r10,%rax,4),%rcx
  mov    $0x2,%eax
  nopl   (%rax)
L102:
  movss  -0x8(%r8,%rax,4),%xmm0
  movss  -0x4(%rsi,%rax,4),%xmm2
  add    $0x8,%rdx
  sub    $0x8,%rcx
  movss  -0x4(%r8,%rax,4),%xmm3
  movss  (%rsi,%rax,4),%xmm4
  movaps %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm3,%xmm5
  mulss  %xmm3,%xmm2
  mulss  %xmm4,%xmm0
  mulss  %xmm4,%xmm5
  subss  %xmm2,%xmm0
  movss  (%rdx),%xmm2
  addss  %xmm5,%xmm1
  addss  %xmm0,%xmm2
  movss  %xmm2,(%rdi,%rax,4)
  subss  (%rdx),%xmm0
  movss  %xmm0,(%rcx)
  movss  -0x4(%rdx),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rdi,%rax,4)
  movss  -0x4(%rdx),%xmm0
  add    $0x2,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rcx)
  cmp    %eax,%r9d
  jg     L102
  add    $0x1,%ebp
  add    %r9d,%r12d
  add    %r15,%rsi
  add    %r13,%rdi
  cmp    %ebp,%r11d
  jne    L21
  mov    -0x4(%rsp),%eax
  test   %eax,%eax
  jne    L82
  mov    -0x8(%rsp),%r8d
  sub    $0x1,%r9d
  add    %r9d,%r8d
L61:
  mov    -0x10(%rsp),%rdi
  mov    -0x18(%rsp),%rax
  movslq %r8d,%r8
  movslq %ebx,%rsi
  movslq %r9d,%rcx
  shl    $0x2,%rsi
  xor    %edx,%edx
  movss  D6(%rip),%xmm1
  shl    $0x2,%rdi
  lea    (%rax,%r8,4),%rax
  sub    %r8,%rcx
  add    %rdi,%r10
  nopw   0x0(%rax,%rax,1)
L43:
  movss  (%rax),%xmm0
  add    $0x1,%edx
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%r10)
  movss  (%rax,%rcx,4),%xmm0
  add    %rdi,%rax
  movss  %xmm0,-0x4(%r10)
  add    %rsi,%r10
  cmp    %edx,%r11d
  jg     L43
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L98:
  test   %r11d,%r11d
  jle    L82
  mov    -0x8(%rsp),%r8d
  mov    $0x1,%r9d
  movq   $0x2,-0x10(%rsp)
  add    $0x1,%r8d
  jmp    L61
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x80]}

assistant: ```c
void dradf2(int ido, int l1, float *cc, float *ch, float *wa1) {
  int i, k;
  float ti2, tr2;
  int t0, t1, t2, t3, t4, t5, t6;
  t1 = 0;
  t0 = (t2 = l1 * ido);
  t3 = ido << 1;
  for (k = 0; k < l1; k++) {
    ch[t1 << 1] = cc[t1] + cc[t2];
    ch[(t1 << 1) + t3 - 1] = cc[t1] - cc[t2];
    t1 += ido;
    t2 += ido;
  }
  if (ido < 2)
    return;
  if (ido == 2)
    goto L105;
  t1 = 0;
  t2 = t0;
  for (k = 0; k < l1; k++) {
    t3 = t2;
    t4 = (t1 << 1) + (ido << 1);
    t5 = t1;
    t6 = t1 + t1;
    for (i = 2; i < ido; i += 2) {
      t3 += 2;
      t4 -= 2;
      t5 += 2;
      t6 += 2;
      tr2 = wa1[i - 2] * cc[t3 - 1] + wa1[i - 1] * cc[t3];
      ti2 = wa1[i - 2] * cc[t3] - wa1[i - 1] * cc[t3 - 1];
      ch[t6] = cc[t5] + ti2;
      ch[t4] = ti2 - cc[t5];
      ch[t6 - 1] = cc[t5 - 1] + tr2;
      ch[t4 - 1] = cc[t5 - 1] - tr2;
    }
    t1 += ido;
    t2 += ido;
  }
  if (ido % 2 == 1)
    return;
L105:
  t3 = (t2 = (t1 = ido) - 1);
  t2 += t0;
  for (k = 0; k < l1; k++) {
    ch[t1] = -cc[t2];
    ch[t1 - 1] = cc[t3];
    t1 += ido << 1;
    t2 += ido;
    t3 += ido;
  }
}
```