ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  lea    D38(%rip),%rbp
  sub    $0x20,%rsp
  mov    (%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%r12
  call   <puts@plt>
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  mov    $0xc,%esi
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  movl   $0xc,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rbp
  mov    %r13,%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  movl   $0x1,0xc(%rsp)
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r13,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  mov    $0x2,%edx
  add    $0x2,%r12d
  lea    D21(%rip),%rdi
  mov    %r12d,%ecx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D7: i = %d


tool: D38: b = %p


tool: D16: adress un %p


tool: D21:  %d + %d = %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int add(int *a, int *b) {
    printf("adress un %p\n", &a);
    return *a + *b;
  }
  int i = 0;
  int *b;
  b = &i;
  printf("%s\n", argv[0]);
  printf("i = %d\n", i);
  printf("b = %p\n", b);
  *b = 12;
  printf("i = %d\n", i);
  printf("b = %p\n", b);
  int un = 1;
  int deux = 2;
  int result;
  printf("adress un %p\n", &un);
  result = add(&un, &deux);
  printf("adress un %p\n", &un);
  printf(" %d + %d = %d\n", un, deux, result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<keydown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%edx
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0x30(%rbp),%rdx
  mov    D45(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x31(%rbp)
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  movsbl -0x31(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int keydown() {
  char c;
  struct termios new, stored;
  tcgetattr(0, &stored);
  new = stored;
  new.c_lflag &= (~ICANON);
  new.c_cc[VTIME] = 0;
  tcgetattr(0, &stored);
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  c = getchar();
  tcsetattr(0, TCSANOW, &stored);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<keydown>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  movdqa 0x10(%rsp),%xmm0
  movaps %xmm0,(%rsp)
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D34(%rip),%rax
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x0,(%rax,%rdx,4)
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    %rsp,%rdx
  mov    D29(%rip),%r12
  mov    (%r12),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdx
  mov    (%r12),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  movsbl %bl,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int keydown() {
  char c;
  struct termios new, stored;
  tcgetattr(0, &stored);
  new = stored;
  new.c_lflag &= (~ICANON);
  new.c_cc[VTIME] = 0;
  tcgetattr(0, &stored);
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  c = getchar();
  tcsetattr(0, TCSANOW, &stored);
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<keydown>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  movdqa 0x10(%rsp),%xmm0
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    D4(%rip),%rax
  movaps %xmm0,(%rsp)
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D21(%rip),%rax
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x0,(%rax,%rdx,4)
  call   <tcgetattr@plt>
  mov    D10(%rip),%rax
  mov    D23(%rip),%rbp
  xor    %edi,%edi
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    0x0(%rbp),%esi
  mov    %rsp,%rdx
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  movsbl %bl,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int keydown() {
  char c;
  struct termios new, stored;
  tcgetattr(0, &stored);
  new = stored;
  new.c_lflag &= (~ICANON);
  new.c_cc[VTIME] = 0;
  tcgetattr(0, &stored);
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  c = getchar();
  tcsetattr(0, TCSANOW, &stored);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<keydown>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rsi
  call   <tcgetattr@plt>
  movdqa 0x10(%rsp),%xmm0
  xor    %edi,%edi
  mov    %r12,%rsi
  mov    D4(%rip),%rax
  movaps %xmm0,(%rsp)
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x8(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x0,(%rax,%rdx,4)
  call   <tcgetattr@plt>
  mov    D33(%rip),%rax
  mov    D24(%rip),%rbp
  xor    %edi,%edi
  mov    (%rax),%rdx
  mov    (%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    0x0(%rbp),%esi
  mov    %rsp,%rdx
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <tcsetattr@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  movsbl %bl,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int keydown() {
  char c;
  struct termios new, stored;
  tcgetattr(0, &stored);
  new = stored;
  new.c_lflag &= (~ICANON);
  new.c_cc[VTIME] = 0;
  tcgetattr(0, &stored);
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  c = getchar();
  tcsetattr(0, TCSANOW, &stored);
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rt_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x4182bed5,%eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int rt_rand(unsigned int *idum) {
  *idum = (1099087573 * (*idum));
  return *idum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rt_rand>:
  endbr64
  imul   $0x4182bed5,(%rdi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
unsigned int rt_rand(unsigned int *idum) {
  *idum = (1099087573 * (*idum));
  return *idum;
}
```
user: What is the c source code of the assembly code below?

```asm
<rt_rand>:
  endbr64
  imul   $0x4182bed5,(%rdi),%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
unsigned int rt_rand(unsigned int *idum) {
  *idum = (1099087573 * (*idum));
  return *idum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<searchKeyTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L98
  cmpq   $0x0,-0x28(%rbp)
  je     L98
  cmpq   $0x0,-0x30(%rbp)
  jne    L84
L98:
  mov    $0xffffffff,%eax
  jmp    L7
L84:
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L88:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L56
L39:
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L88
L56:
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L59
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L7
L59:
  mov    $0xfffffffe,%eax
L7:
  leave
  ret
```

assistant: ```c
int searchKeyTable(const char *table[], const int size, const char *key, int *pos) {
  if (table == NULL || key == NULL || pos == NULL) {
    return -1;
  }
  int i = 0;
  int tmp = -1;
  for (i = 0; i < size; i++) {
    if (strcmp(table[i], key) == 0) {
      tmp = i;
      break;
    }
  }
  if (tmp != -1) {
    *pos = tmp + 1;
  } else {
    return -2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<searchKeyTable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  test   %rdx,%rdx
  sete   %al
  test   %rcx,%rcx
  sete   %dl
  or     %dl,%al
  jne    L79
  mov    %rdi,%r13
  mov    %rcx,%r15
  test   %rdi,%rdi
  je     L79
  test   %esi,%esi
  jle    L13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L50:
  mov    %ebx,%r14d
  mov    0x0(%r13,%rbx,8),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L50
L13:
  mov    $0xfffffffe,%eax
  jmp    L32
L34:
  cmp    $0xffffffff,%ebx
  je     L52
  add    $0x1,%r14d
  mov    %r14d,(%r15)
  mov    $0x0,%eax
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    $0xffffffff,%eax
  jmp    L32
L52:
  mov    $0xfffffffe,%eax
  jmp    L32
```

assistant: ```c
int searchKeyTable(const char *table[], const int size, const char *key, int *pos) {
  if (table == NULL || key == NULL || pos == NULL) {
    return -1;
  }
  int i = 0;
  int tmp = -1;
  for (i = 0; i < size; i++) {
    if (strcmp(table[i], key) == 0) {
      tmp = i;
      break;
    }
  }
  if (tmp != -1) {
    *pos = tmp + 1;
  } else {
    return -2;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<searchKeyTable>:
  endbr64
  test   %rdx,%rdx
  push   %r14
  sete   %al
  test   %rcx,%rcx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sete   %dl
  or     %dl,%al
  push   %rbx
  jne    L56
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L56
  mov    %rcx,%r13
  lea    0x1(%rsi),%r12d
  mov    $0x1,%ebx
  test   %esi,%esi
  jg     L42
  jmp    L60
  nopl   0x0(%rax)
L47:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L60
L42:
  mov    -0x8(%r14,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  mov    %ebx,0x0(%r13)
  xor    %eax,%eax
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  pop    %rbx
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  mov    $0xffffffff,%eax
  jmp    L54
```

assistant: ```c
int searchKeyTable(const char *table[], const int size, const char *key, int *pos) {
  if (table == NULL || key == NULL || pos == NULL) {
    return -1;
  }
  int i = 0;
  int tmp = -1;
  for (i = 0; i < size; i++) {
    if (strcmp(table[i], key) == 0) {
      tmp = i;
      break;
    }
  }
  if (tmp != -1) {
    *pos = tmp + 1;
  } else {
    return -2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<searchKeyTable>:
  endbr64
  test   %rdx,%rdx
  push   %r14
  sete   %al
  test   %rcx,%rcx
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sete   %dl
  or     %dl,%al
  push   %rbx
  jne    L32
  mov    %rdi,%r14
  test   %rdi,%rdi
  je     L32
  mov    %rcx,%r13
  lea    0x1(%rsi),%r12d
  mov    $0x1,%ebx
  test   %esi,%esi
  jg     L2
  jmp    L49
  nopl   0x0(%rax)
L3:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L49
L2:
  mov    -0x8(%r14,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    %ebx,0x0(%r13)
  xor    %eax,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  pop    %rbx
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  mov    $0xffffffff,%eax
  jmp    L45
```

assistant: ```c
int searchKeyTable(const char *table[], const int size, const char *key, int *pos) {
  if (table == NULL || key == NULL || pos == NULL) {
    return -1;
  }
  int i = 0;
  int tmp = -1;
  for (i = 0; i < size; i++) {
    if (strcmp(table[i], key) == 0) {
      tmp = i;
      break;
    }
  }
  if (tmp != -1) {
    *pos = tmp + 1;
  } else {
    return -2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rpcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <_memory_allocate@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *rpcalloc(size_t num, size_t size) {
  size_t total;
  void *ptr;
  total = num * size;
  ptr = _memory_allocate(total);
  memset(ptr, 0, total);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rpcalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <_memory_allocate@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *rpcalloc(size_t num, size_t size) {
  size_t total;
  void *ptr;
  total = num * size;
  ptr = _memory_allocate(total);
  memset(ptr, 0, total);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rpcalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <_memory_allocate@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *rpcalloc(size_t num, size_t size) {
  size_t total;
  void *ptr;
  total = num * size;
  ptr = _memory_allocate(total);
  memset(ptr, 0, total);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rpcalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <_memory_allocate@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *rpcalloc(size_t num, size_t size) {
  size_t total;
  void *ptr;
  total = num * size;
  ptr = _memory_allocate(total);
  memset(ptr, 0, total);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdlib_ndarray_set_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stdlib_ndarray_get_ptr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L3
L5:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stdlib_ndarray_set_ptr_int16@plt>
L3:
  leave
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int16(const struct ndarray *arr, const int64_t *sub, const int16_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int16(idx, v);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stdlib_ndarray_set_int16>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  mov    %ebx,%esi
  call   <stdlib_ndarray_set_ptr_int16@plt>
L5:
  pop    %rbx
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int8_t stdlib_ndarray_set_int16(const struct ndarray *arr, const int64_t *sub, const int16_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int16(idx, v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdlib_ndarray_set_int16>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L7
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_set_ptr_int16@plt>
L7:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int16(const struct ndarray *arr, const int64_t *sub, const int16_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int16(idx, v);
}
```
user: What is the c source code of the assembly code below?

```asm
<stdlib_ndarray_set_int16>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <stdlib_ndarray_get_ptr@plt>
  test   %rax,%rax
  je     L4
  mov    %ebp,%esi
  mov    %rax,%rdi
  pop    %rbp
  jmp    1060 <stdlib_ndarray_set_ptr_int16@plt>
L4:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t stdlib_ndarray_set_int16(const struct ndarray *arr, const int64_t *sub, const int16_t v) {
  uint8_t *idx = stdlib_ndarray_get_ptr(arr, sub);
  if (idx == NULL) {
    return -1;
  }
  return stdlib_ndarray_set_ptr_int16(idx, v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L48
L13:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L40:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L1:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
L28:
  cmpl   $0x0,-0x8(%rbp)
  jg     L40
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void heapify(int *f, int n) {
  for (int i = 1; i < n; i++) {
    int p = i;
    while (p > 0) {
      if (f[p] > f[p / 2]) {
        int t = f[p];
        f[p] = f[p / 2];
        f[p / 2] = t;
      }
      p = p / 2;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapify>:
  endbr64
  mov    %rdi,%r9
  mov    $0x1,%r11d
  cmp    $0x1,%esi
  jg     L60
  ret
L17:
  cmp    $0x1,%r10d
  jle    L13
L15:
  movslq %edx,%rax
  lea    (%r9,%rax,4),%rdi
  mov    (%rdi),%ecx
  mov    %edx,%r10d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  cltq
  lea    (%r9,%rax,4),%rax
  mov    (%rax),%r8d
  cmp    %r8d,%ecx
  jle    L17
  mov    %r8d,(%rdi)
  mov    %ecx,(%rax)
  jmp    L17
L13:
  add    $0x1,%r11d
  cmp    %r11d,%esi
  je     L43
L60:
  mov    %r11d,%edx
  test   %r11d,%r11d
  jg     L15
  jmp    L13
L43:
  ret
```

assistant: ```c
void heapify(int *f, int n) {
  for (int i = 1; i < n; i++) {
    int p = i;
    while (p > 0) {
      if (f[p] > f[p / 2]) {
        int t = f[p];
        f[p] = f[p / 2];
        f[p / 2] = t;
      }
      p = p / 2;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<heapify>:
  endbr64
  cmp    $0x1,%esi
  jle    L6
  mov    $0x1,%r11d
  nop
L35:
  mov    %r11d,%eax
  movslq %r11d,%rdx
  cs nopw 0x0(%rax,%rax,1)
L10:
  sar    %eax
  lea    (%rdi,%rdx,4),%r9
  movslq %eax,%rdx
  mov    (%r9),%r8d
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%r10d
  cmp    %r10d,%r8d
  jle    L30
  mov    %r10d,(%r9)
  mov    %r8d,(%rcx)
L30:
  test   %eax,%eax
  jne    L10
  add    $0x1,%r11d
  cmp    %r11d,%esi
  jne    L35
L6:
  ret
```

assistant: ```c
void heapify(int *f, int n) {
  for (int i = 1; i < n; i++) {
    int p = i;
    while (p > 0) {
      if (f[p] > f[p / 2]) {
        int t = f[p];
        f[p] = f[p / 2];
        f[p / 2] = t;
      }
      p = p / 2;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<heapify>:
  endbr64
  movslq %esi,%r10
  mov    $0x1,%r9d
  cmp    $0x1,%esi
  jle    L30
  nopw   0x0(%rax,%rax,1)
L39:
  mov    (%rdi,%r9,4),%r8d
  mov    %r9d,%eax
  jmp    L27
  nopl   0x0(%rax)
L18:
  mov    %edx,(%rdi,%rsi,4)
  mov    %r8d,(%rcx)
  test   %eax,%eax
  je     L38
L27:
  movslq %eax,%rsi
  sar    %eax
  movslq %eax,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    (%rcx),%edx
  cmp    %r8d,%edx
  jl     L18
  mov    %edx,%r8d
  test   %eax,%eax
  jne    L27
L38:
  add    $0x1,%r9
  cmp    %r9,%r10
  jne    L39
L30:
  ret
```

assistant: ```c
void heapify(int *f, int n) {
  for (int i = 1; i < n; i++) {
    int p = i;
    while (p > 0) {
      if (f[p] > f[p / 2]) {
        int t = f[p];
        f[p] = f[p / 2];
        f[p / 2] = t;
      }
      p = p / 2;
    }
  }
}
```