ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<move_to_next_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L6
L108:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    $0x0,%eax
  jmp    L77
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L115
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L115
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L108
  jmp    L115
L99:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
  mov    $0x0,%eax
  jmp    L77
L115:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L99
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L99
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L99
  mov    $0x0,%eax
L77:
  pop    %rbp
  ret
```

assistant: ```c
int move_to_next_word(unsigned char **string_pointer) {
  while ((*(*string_pointer) != ' ') && (*(*string_pointer) != '\n') && (*(*string_pointer) != '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  while ((*(*string_pointer) == ' ') || (*(*string_pointer) == '\n') || (*(*string_pointer) == '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<move_to_next_word>:
  endbr64
L29:
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L60
  cmp    $0x20,%dl
  je     L60
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  cmpb   $0x0,0x1(%rax)
  jne    L29
L35:
  mov    $0x0,%eax
  ret
L45:
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  cmpb   $0x0,0x1(%rax)
  je     L35
L60:
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L45
  cmp    $0x20,%dl
  je     L45
  jmp    L35
```

assistant: ```c
int move_to_next_word(unsigned char **string_pointer) {
  while ((*(*string_pointer) != ' ') && (*(*string_pointer) != '\n') && (*(*string_pointer) != '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  while ((*(*string_pointer) == ' ') || (*(*string_pointer) == '\n') || (*(*string_pointer) == '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<move_to_next_word>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  jmp    L56
  nopl   0x0(%rax)
L61:
  cmp    $0x20,%dl
  je     L20
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L32
L56:
  lea    -0x9(%rdx),%ecx
  add    $0x1,%rax
  cmp    $0x1,%cl
  ja     L61
  nopl   0x0(%rax,%rax,1)
L20:
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L42
  cmp    $0x20,%dl
  jne    L32
L42:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L20
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
int move_to_next_word(unsigned char **string_pointer) {
  while ((*(*string_pointer) != ' ') && (*(*string_pointer) != '\n') && (*(*string_pointer) != '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  while ((*(*string_pointer) == ' ') || (*(*string_pointer) == '\n') || (*(*string_pointer) == '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<move_to_next_word>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  jmp    L28
  nopl   0x0(%rax)
L64:
  cmp    $0x20,%dl
  je     L62
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L67
L28:
  lea    -0x9(%rdx),%ecx
  add    $0x1,%rax
  cmp    $0x1,%cl
  ja     L64
  nopl   0x0(%rax,%rax,1)
L62:
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L21
  cmp    $0x20,%dl
  jne    L67
L21:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L62
L67:
  xor    %eax,%eax
  ret
```

assistant: ```c
int move_to_next_word(unsigned char **string_pointer) {
  while ((*(*string_pointer) != ' ') && (*(*string_pointer) != '\n') && (*(*string_pointer) != '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  while ((*(*string_pointer) == ' ') || (*(*string_pointer) == '\n') || (*(*string_pointer) == '\t')) {
    (*string_pointer)++;
    if (*(*string_pointer) == '\0') {
      return 0;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string

tool: D15: hello world %d


tool: D6: arg %d: %s


assistant: ```c
int main(int argc, char **argv) {
  int Count;
  printf("hello world %d\n", argc);
  for (Count = 0; Count < argc; Count++)
    printf("arg %d: %s\n", Count, argv[Count]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edi,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L9
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L1:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
L9:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D11: hello world %d


tool: D5: arg %d: %s


assistant: ```c
int main(int argc, char **argv) {
  int Count;
  printf("hello world %d\n", argc);
  for (Count = 0; Count < argc; Count++)
    printf("arg %d: %s\n", Count, argv[Count]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D2(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L5
  xor    %ebx,%ebx
  lea    D14(%rip),%r13
  nopl   0x0(%rax)
L4:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L4
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D2: hello world %d


tool: D14: arg %d: %s


assistant: ```c
int main(int argc, char **argv) {
  int Count;
  printf("hello world %d\n", argc);
  for (Count = 0; Count < argc; Count++)
    printf("arg %d: %s\n", Count, argv[Count]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D8(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L0
  xor    %ebx,%ebx
  lea    D11(%rip),%r13
  nopl   0x0(%rax)
L6:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L6
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D11
type: string

tool: D8: hello world %d


tool: D11: arg %d: %s


assistant: ```c
int main(int argc, char **argv) {
  int Count;
  printf("hello world %d\n", argc);
  for (Count = 0; Count < argc; Count++)
    printf("arg %d: %s\n", Count, argv[Count]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IEH3nodg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <IEH3digt@plt>
  test   %eax,%eax
  je     L23
  mov    $0x0,%eax
  jmp    L40
L23:
  movsbl -0x4(%rbp),%eax
  sub    $0x2b,%eax
  cmp    $0x3a,%eax
  seta   %dl
  test   %dl,%dl
  jne    L34
  movabs $0x40000000400000d,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L34
  mov    $0x0,%eax
  jmp    L40
L34:
  mov    $0x1,%eax
L40:
  leave
  ret
```

assistant: ```c
IEH3nodg(ch) char ch;
{
  if (IEH3digt(ch))
    return (0);
  switch (ch) {
  case 'E':
  case 'e':
  case '.':
  case '+':
  case '-':
    return (0);
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IEH3nodg>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <IEH3digt@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L26
  lea    -0x2b(%rbx),%ecx
  cmp    $0x3a,%cl
  ja     L3
  movabs $0x40000000400000d,%rax
  shr    %cl,%rax
  not    %rax
  and    $0x1,%eax
L26:
  pop    %rbx
  ret
L3:
  mov    $0x1,%eax
  jmp    L26
```

assistant: ```c
IEH3nodg(ch) char ch;
{
  if (IEH3digt(ch))
    return (0);
  switch (ch) {
  case 'E':
  case 'e':
  case '.':
  case '+':
  case '-':
    return (0);
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<IEH3nodg>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <IEH3digt@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L11
  lea    -0x2b(%rbx),%ecx
  cmp    $0x3a,%cl
  ja     L10
  movabs $0x40000000400000d,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
L11:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
IEH3nodg(ch) char ch;
{
  if (IEH3digt(ch))
    return (0);
  switch (ch) {
  case 'E':
  case 'e':
  case '.':
  case '+':
  case '-':
    return (0);
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<IEH3nodg>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <IEH3digt@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L5
  lea    -0x2b(%rbx),%ecx
  cmp    $0x3a,%cl
  ja     L2
  movabs $0x40000000400000d,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
L5:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
IEH3nodg(ch) char ch;
{
  if (IEH3digt(ch))
    return (0);
  switch (ch) {
  case 'E':
  case 'e':
  case '.':
  case '+':
  case '-':
    return (0);
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<String_eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
L18:
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  cmpq   $0x0,-0x10(%rbp)
  jne    L8
  mov    $0x1,%eax
  jmp    L55
L8:
  mov    $0x0,%eax
  jmp    L55
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L55:
  leave
  ret
```

assistant: ```c
int String_eq(const char *s1, const char *s2) {
  if (s1 == NULL || s2 == NULL) {
    if (s1 == NULL && s2 == NULL)
      return 1;
    else
      return 0;
  }
  return (strcmp(s1, s2) == 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<String_eq>:
  endbr64
  test   %rdi,%rdi
  je     L4
  test   %rsi,%rsi
  jne    L5
L4:
  or     %rsi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
L5:
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int String_eq(const char *s1, const char *s2) {
  if (s1 == NULL || s2 == NULL) {
    if (s1 == NULL && s2 == NULL)
      return 1;
    else
      return 0;
  }
  return (strcmp(s1, s2) == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<String_eq>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %rsi,%rsi
  jne    L10
L1:
  xor    %eax,%eax
  or     %rsi,%rdi
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int String_eq(const char *s1, const char *s2) {
  if (s1 == NULL || s2 == NULL) {
    if (s1 == NULL && s2 == NULL)
      return 1;
    else
      return 0;
  }
  return (strcmp(s1, s2) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<String_eq>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  jne    L13
L10:
  xor    %eax,%eax
  or     %rsi,%rdi
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int String_eq(const char *s1, const char *s2) {
  if (s1 == NULL || s2 == NULL) {
    if (s1 == NULL && s2 == NULL)
      return 1;
    else
      return 0;
  }
  return (strcmp(s1, s2) == 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_computer_ranking>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D16
datatype: string

tool: D1: What is the team's Computer Ranking? 

tool: D16: %lf

assistant: ```c
double get_computer_ranking(void) {
  double value = 0.0;
  printf("What is the team's Computer Ranking? ");
  scanf("%lf", &value);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_computer_ranking>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D10: What is the team's Computer Ranking? 

tool: D4: %lf

assistant: ```c
double get_computer_ranking(void) {
  double value = 0.0;
  printf("What is the team's Computer Ranking? ");
  scanf("%lf", &value);
  return value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_computer_ranking>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string

tool: D4: What is the team's Computer Ranking? 

tool: D18: %lf

assistant: ```c
double get_computer_ranking(void) {
  double value = 0.0;
  printf("What is the team's Computer Ranking? ");
  scanf("%lf", &value);
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_computer_ranking>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D7: What is the team's Computer Ranking? 

tool: D17: %lf

assistant: ```c
double get_computer_ranking(void) {
  double value = 0.0;
  printf("What is the team's Computer Ranking? ");
  scanf("%lf", &value);
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MPU_AllocateRegionDesc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x30017c1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  call   *%rax
  leave
  ret
```

assistant: ```c
int MPU_AllocateRegionDesc(void) {
  int (*p_MPU_AllocateRegionDesc)(void);
  p_MPU_AllocateRegionDesc = (int (*)(void))0x030017c1U;
  return p_MPU_AllocateRegionDesc();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MPU_AllocateRegionDesc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x30017c1,%eax
  call   *%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int MPU_AllocateRegionDesc(void) {
  int (*p_MPU_AllocateRegionDesc)(void);
  p_MPU_AllocateRegionDesc = (int (*)(void))0x030017c1U;
  return p_MPU_AllocateRegionDesc();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MPU_AllocateRegionDesc>:
  endbr64
  mov    $0x30017c1,%eax
  jmp    *%rax
```

assistant: ```c
int MPU_AllocateRegionDesc(void) {
  int (*p_MPU_AllocateRegionDesc)(void);
  p_MPU_AllocateRegionDesc = (int (*)(void))0x030017c1U;
  return p_MPU_AllocateRegionDesc();
}
```
user: Translate the below assembly code into C programming language:

```asm
<MPU_AllocateRegionDesc>:
  endbr64
  mov    $0x30017c1,%eax
  jmp    *%rax
```

assistant: ```c
int MPU_AllocateRegionDesc(void) {
  int (*p_MPU_AllocateRegionDesc)(void);
  p_MPU_AllocateRegionDesc = (int (*)(void))0x030017c1U;
  return p_MPU_AllocateRegionDesc();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: 	Can't run this test on this platform.

assistant: ```c
int main(void) {
  puts("\tCan't run this test on this platform.");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: 	Can't run this test on this platform.

assistant: ```c
int main(void) {
  puts("\tCan't run this test on this platform.");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 	Can't run this test on this platform.

assistant: ```c
int main(void) {
  puts("\tCan't run this test on this platform.");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: 	Can't run this test on this platform.

assistant: ```c
int main(void) {
  puts("\tCan't run this test on this platform.");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HMM_SquareRootF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <_mm_set_ss@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <_mm_sqrt_ss@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <_mm_cvtss_f32@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float HMM_SquareRootF(float Float) {
  float Result;
  __m128 In = _mm_set_ss(Float);
  __m128 Out = _mm_sqrt_ss(In);
  Result = _mm_cvtss_f32(Out);
  return (Result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<HMM_SquareRootF>:
  endbr64
  sub    $0x8,%rsp
  call   <_mm_set_ss@plt>
  mov    %eax,%edi
  call   <_mm_sqrt_ss@plt>
  mov    %eax,%edi
  call   <_mm_cvtss_f32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
float HMM_SquareRootF(float Float) {
  float Result;
  __m128 In = _mm_set_ss(Float);
  __m128 Out = _mm_sqrt_ss(In);
  Result = _mm_cvtss_f32(Out);
  return (Result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<HMM_SquareRootF>:
  endbr64
  sub    $0x8,%rsp
  call   <_mm_set_ss@plt>
  mov    %eax,%edi
  call   <_mm_sqrt_ss@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <_mm_cvtss_f32@plt>
```

assistant: ```c
float HMM_SquareRootF(float Float) {
  float Result;
  __m128 In = _mm_set_ss(Float);
  __m128 Out = _mm_sqrt_ss(In);
  Result = _mm_cvtss_f32(Out);
  return (Result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HMM_SquareRootF>:
  endbr64
  sub    $0x8,%rsp
  call   <_mm_set_ss@plt>
  mov    %eax,%edi
  call   <_mm_sqrt_ss@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1080 <_mm_cvtss_f32@plt>
```

assistant: ```c
float HMM_SquareRootF(float Float) {
  float Result;
  __m128 In = _mm_set_ss(Float);
  __m128 Out = _mm_sqrt_ss(In);
  Result = _mm_cvtss_f32(Out);
  return (Result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_110_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_110_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = T | stk4;
  stk2 = *D & stk3;
  stk1 = S ^ stk2;
  *D = stk1;
}
```