ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count>:
  endbr64
  mov    %edx,%ecx
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  cmp    %ecx,%eax
  jl     L4
L13:
  cltd
  idiv   %ecx
  add    %eax,%edi
  add    %edx,%eax
  cmp    %eax,%ecx
  jle    L13
L4:
  mov    %edi,%eax
  ret
```

assistant: ```c
int count(int n, int c, int m) {
  int i;
  int j = 0;
  int r;
  j = n / c;
  n = j;
  while (n >= m) {
    j += n / m;
    r = n % m;
    n = n / m;
    n = n + r;
  }
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<count>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%ecx
  cltd
  idiv   %esi
  cmp    %ecx,%eax
  jl     L10
  mov    %eax,%r8d
  nopw   0x0(%rax,%rax,1)
L3:
  cltd
  idiv   %ecx
  add    %eax,%r8d
  add    %edx,%eax
  cmp    %eax,%ecx
  jle    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count(int n, int c, int m) {
  int i;
  int j = 0;
  int r;
  j = n / c;
  n = j;
  while (n >= m) {
    j += n / m;
    r = n % m;
    n = n / m;
    n = n + r;
  }
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%ecx
  cltd
  idiv   %esi
  cmp    %ecx,%eax
  jl     L10
  mov    %eax,%r8d
  nopw   0x0(%rax,%rax,1)
L11:
  cltd
  idiv   %ecx
  add    %eax,%r8d
  add    %edx,%eax
  cmp    %eax,%ecx
  jle    L11
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count(int n, int c, int m) {
  int i;
  int j = 0;
  int r;
  j = n / c;
  n = j;
  while (n >= m) {
    j += n / m;
    r = n % m;
    n = n / m;
    n = n + r;
  }
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: usage: bloopsawhat notes
 (ex.: bloopsawhat "a b c d e f g + a b c"


assistant: ```c
void usage() {
  printf("usage: bloopsawhat notes\n"
         " (ex.: bloopsawhat \"a b c d e f g + a b c\"\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: usage: bloopsawhat notes
 (ex.: bloopsawhat "a b c d e f g + a b c"


assistant: ```c
void usage() {
  printf("usage: bloopsawhat notes\n"
         " (ex.: bloopsawhat \"a b c d e f g + a b c\"\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: usage: bloopsawhat notes
 (ex.: bloopsawhat "a b c d e f g + a b c"


assistant: ```c
void usage() {
  printf("usage: bloopsawhat notes\n"
         " (ex.: bloopsawhat \"a b c d e f g + a b c\"\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: usage: bloopsawhat notes
 (ex.: bloopsawhat "a b c d e f g + a b c"


assistant: ```c
void usage() {
  printf("usage: bloopsawhat notes\n"
         " (ex.: bloopsawhat \"a b c d e f g + a b c\"\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chol_backward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L35
L25:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L16:
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x10(%rbp)
L35:
  cmpl   $0x0,-0x10(%rbp)
  jns    L25
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chol_backward(double a[], int n, double p[], double b[], double x[]) {
  int i, k;
  double sum;
  for (i = n - 1; i >= 0; i--) {
    sum = b[i];
    for (k = i + 1; k < n; k++)
      sum -= a[n * k + i] * x[k];
    x[i] = sum / p[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chol_backward>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%edi
  sub    $0x1,%edi
  js     L25
  push   %rbp
  push   %rbx
  mov    %rdx,%r11
  mov    %rcx,%rbx
  movslq %edi,%rdi
  mov    %esi,%ebp
  imul   %esi,%ebp
  movslq %esi,%rcx
  shl    $0x3,%rcx
  mov    %esi,%r9d
L23:
  movsd  (%rbx,%rdi,8),%xmm1
  cmp    %r9d,%esi
  jle    L6
  movslq %r9d,%rax
  movslq %ebp,%rdx
  add    %rdi,%rdx
  lea    (%r10,%rdx,8),%rdx
L19:
  movsd  (%rdx),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  subsd  %xmm0,%xmm1
  add    $0x1,%rax
  add    %rcx,%rdx
  cmp    %eax,%esi
  jg     L19
L6:
  divsd  (%r11,%rdi,8),%xmm1
  movsd  %xmm1,(%r8,%rdi,8)
  sub    $0x1,%rdi
  sub    $0x1,%r9d
  sub    %esi,%ebp
  test   %edi,%edi
  jns    L23
  pop    %rbx
  pop    %rbp
  ret
L25:
  ret
```

assistant: ```c
void chol_backward(double a[], int n, double p[], double b[], double x[]) {
  int i, k;
  double sum;
  for (i = n - 1; i >= 0; i--) {
    sum = b[i];
    for (k = i + 1; k < n; k++)
      sum -= a[n * k + i] * x[k];
    x[i] = sum / p[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chol_backward>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%edi
  sub    $0x1,%edi
  js     L35
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%r11
  movslq %edi,%rdi
  imul   %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  movslq %esi,%rcx
  shl    $0x3,%rcx
  mov    %esi,%r9d
  nopl   0x0(%rax,%rax,1)
L10:
  movsd  (%rbx,%rdi,8),%xmm1
  cmp    %r9d,%esi
  jle    L8
  movslq %ebp,%rdx
  movslq %r9d,%rax
  add    %rdi,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L31:
  movsd  (%rdx),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  add    %rcx,%rdx
  subsd  %xmm0,%xmm1
  cmp    %eax,%esi
  jg     L31
L8:
  divsd  (%r11,%rdi,8),%xmm1
  movsd  %xmm1,(%r8,%rdi,8)
  sub    $0x1,%rdi
  sub    $0x1,%r9d
  sub    %esi,%ebp
  test   %edi,%edi
  jns    L10
  pop    %rbx
  pop    %rbp
  ret
L35:
  ret
```

assistant: ```c
void chol_backward(double a[], int n, double p[], double b[], double x[]) {
  int i, k;
  double sum;
  for (i = n - 1; i >= 0; i--) {
    sum = b[i];
    for (k = i + 1; k < n; k++)
      sum -= a[n * k + i] * x[k];
    x[i] = sum / p[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chol_backward>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%edi
  sub    $0x1,%edi
  js     L21
  push   %rbp
  mov    %esi,%ebp
  mov    %rdx,%r11
  movslq %edi,%rdi
  imul   %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  movslq %esi,%rcx
  shl    $0x3,%rcx
  mov    %esi,%r9d
  nopl   0x0(%rax,%rax,1)
L18:
  movsd  (%rbx,%rdi,8),%xmm1
  cmp    %r9d,%esi
  jle    L14
  movslq %ebp,%rdx
  movslq %r9d,%rax
  add    %rdi,%rdx
  lea    (%r10,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L39:
  movsd  (%rdx),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  add    %rcx,%rdx
  subsd  %xmm0,%xmm1
  cmp    %eax,%esi
  jg     L39
L14:
  divsd  (%r11,%rdi,8),%xmm1
  movsd  %xmm1,(%r8,%rdi,8)
  sub    $0x1,%rdi
  sub    $0x1,%r9d
  sub    %esi,%ebp
  test   %edi,%edi
  jns    L18
  pop    %rbx
  pop    %rbp
  ret
L21:
  ret
```

assistant: ```c
void chol_backward(double a[], int n, double p[], double b[], double x[]) {
  int i, k;
  double sum;
  for (i = n - 1; i >= 0; i--) {
    sum = b[i];
    for (k = i + 1; k < n; k++)
      sum -= a[n * k + i] * x[k];
    x[i] = sum / p[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<connect_to_master>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D38(%rip),%rax
  mov    (%rax),%ecx
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x1c(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inet_aton@plt>
  jmp    L10
L30:
  mov    $0x186a0,%edi
  call   <usleep@plt>
  mov    D39(%rip),%rax
  mov    (%rax),%rdx
  mov    D36(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L38
L10:
  lea    -0x14(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  je     L30
  mov    -0x1c(%rbp),%eax
L38:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int connect_to_master(char *address, int port) {
  int sock_master;
  int ret;
  sock_master = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in addr_master;
  addr_master.sin_family = AF_INET;
  addr_master.sin_port = htons(port);
  inet_aton(address, &addr_master.sin_addr);
  while ((ret = connect(sock_master, (const struct sockaddr *)&addr_master, sizeof(addr_master))) == -1) {
    usleep(100 * 1000);
    if (errno == ECONNREFUSED) {
      return -1;
    }
  }
  return sock_master;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<connect_to_master>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%r13
  mov    $0x0,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    0x0(%r13),%edi
  call   <socket@plt>
  mov    %eax,%ebp
  mov    0x0(%r13),%eax
  mov    %eax,0x14(%rsp)
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <inet_aton@plt>
  lea    0xc(%rsp),%r12
L14:
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L4
  mov    $0x186a0,%edi
  call   <usleep@plt>
  mov    D11(%rip),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L14
  mov    %ebx,%ebp
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %ebp,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connect_to_master(char *address, int port) {
  int sock_master;
  int ret;
  sock_master = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in addr_master;
  addr_master.sin_family = AF_INET;
  addr_master.sin_port = htons(port);
  inet_aton(address, &addr_master.sin_addr);
  while ((ret = connect(sock_master, (const struct sockaddr *)&addr_master, sizeof(addr_master))) == -1) {
    usleep(100 * 1000);
    if (errno == ECONNREFUSED) {
      return -1;
    }
  }
  return sock_master;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<connect_to_master>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D13(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D31(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  mov    (%rbx),%eax
  lea    0xc(%rsp),%rbx
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x10(%rsp)
  call   <inet_aton@plt>
  jmp    L34
  nopl   0x0(%rax)
L36:
  mov    $0x186a0,%edi
  call   <usleep@plt>
  mov    D5(%rip),%rax
  mov    D20(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L4
L34:
  mov    $0xc,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L36
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%r12d
  jmp    L42
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connect_to_master(char *address, int port) {
  int sock_master;
  int ret;
  sock_master = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in addr_master;
  addr_master.sin_family = AF_INET;
  addr_master.sin_port = htons(port);
  inet_aton(address, &addr_master.sin_addr);
  while ((ret = connect(sock_master, (const struct sockaddr *)&addr_master, sizeof(addr_master))) == -1) {
    usleep(100 * 1000);
    if (errno == ECONNREFUSED) {
      return -1;
    }
  }
  return sock_master;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<connect_to_master>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  xor    %edx,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D29(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D39(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  mov    (%rbx),%eax
  lea    0xc(%rsp),%rbx
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,0x10(%rsp)
  call   <inet_aton@plt>
  jmp    L39
  nopl   0x0(%rax)
L38:
  mov    $0x186a0,%edi
  call   <usleep@plt>
  mov    D33(%rip),%rax
  mov    D2(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L13
L39:
  mov    $0xc,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L38
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%r12d
  jmp    L44
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int connect_to_master(char *address, int port) {
  int sock_master;
  int ret;
  sock_master = socket(AF_INET, SOCK_STREAM, 0);
  struct sockaddr_in addr_master;
  addr_master.sin_family = AF_INET;
  addr_master.sin_port = htons(port);
  inet_aton(address, &addr_master.sin_addr);
  while ((ret = connect(sock_master, (const struct sockaddr *)&addr_master, sizeof(addr_master))) == -1) {
    usleep(100 * 1000);
    if (errno == ECONNREFUSED) {
      return -1;
    }
  }
  return sock_master;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replaceExt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L52
L0:
  subl   $0x1,-0x8(%rbp)
L52:
  cmpl   $0x0,-0x8(%rbp)
  js     L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L0
L13:
  cmpl   $0x0,-0x8(%rbp)
  js     L57
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L57
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L57:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  leave
  ret
```

assistant: ```c
void replaceExt(char *str, char *ext) {
  int len, ind;
  len = strlen(str);
  ind = len - 1;
  while (ind >= 0 && str[ind] != '.' && str[ind] != '\\' && str[ind] != '/')
    ind--;
  if (ind >= 0 && str[ind] == '.') {
    str[ind] = 0;
  }
  strcat(str, ext);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<replaceExt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L55
  cltq
L23:
  mov    %eax,%esi
  movzbl (%rbx,%rax,1),%edx
  lea    -0x2e(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L12
  cmp    $0x5c,%dl
  je     L12
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L23
  jmp    L55
L12:
  test   %esi,%esi
  js     L55
  movslq %esi,%rsi
  add    %rbx,%rsi
  cmpb   $0x2e,(%rsi)
  je     L30
L55:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  movb   $0x0,(%rsi)
  jmp    L55
```

assistant: ```c
void replaceExt(char *str, char *ext) {
  int len, ind;
  len = strlen(str);
  ind = len - 1;
  while (ind >= 0 && str[ind] != '.' && str[ind] != '\\' && str[ind] != '/')
    ind--;
  if (ind >= 0 && str[ind] == '.') {
    str[ind] = 0;
  }
  strcat(str, ext);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<replaceExt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L64
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rdi
  add    %rbp,%rdx
  sub    %rcx,%rdi
  jmp    L69
  nopl   0x0(%rax)
L38:
  cmp    $0x5c,%al
  je     L22
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L64
L69:
  movzbl (%rdx),%eax
  lea    -0x2e(%rax),%ecx
  cmp    $0x1,%cl
  ja     L38
L22:
  cmp    $0x2e,%al
  je     L37
L64:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcat@plt>
  cs nopw 0x0(%rax,%rax,1)
L37:
  movb   $0x0,(%rdx)
  jmp    L64
```

assistant: ```c
void replaceExt(char *str, char *ext) {
  int len, ind;
  len = strlen(str);
  ind = len - 1;
  while (ind >= 0 && str[ind] != '.' && str[ind] != '\\' && str[ind] != '/')
    ind--;
  if (ind >= 0 && str[ind] == '.') {
    str[ind] = 0;
  }
  strcat(str, ext);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<replaceExt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L8
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rdi
  add    %rbp,%rdx
  sub    %rcx,%rdi
  jmp    L50
  nopl   0x0(%rax)
L60:
  cmp    $0x5c,%al
  je     L69
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  je     L8
L50:
  movzbl (%rdx),%eax
  lea    -0x2e(%rax),%ecx
  cmp    $0x1,%cl
  ja     L60
L69:
  cmp    $0x2e,%al
  je     L11
L8:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strcat@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  movb   $0x0,(%rdx)
  jmp    L8
```

assistant: ```c
void replaceExt(char *str, char *ext) {
  int len, ind;
  len = strlen(str);
  ind = len - 1;
  while (ind >= 0 && str[ind] != '.' && str[ind] != '\\' && str[ind] != '/')
    ind--;
  if (ind >= 0 && str[ind] == '.') {
    str[ind] = 0;
  }
  strcat(str, ext);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <iwrites@plt>
  mov    $0x0,%eax
  call   <iexit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: Hello World!


assistant: ```c
int main() {
  iwrites("Hello World!\n");
  iexit();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <iwrites@plt>
  mov    $0x0,%eax
  call   <iexit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: Hello World!


assistant: ```c
int main() {
  iwrites("Hello World!\n");
  iexit();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <iwrites@plt>
  xor    %eax,%eax
  call   <iexit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: Hello World!


assistant: ```c
int main() {
  iwrites("Hello World!\n");
  iexit();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <iwrites@plt>
  xor    %eax,%eax
  call   <iexit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: Hello World!


assistant: ```c
int main() {
  iwrites("Hello World!\n");
  iexit();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pegasus_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0xf423f,-0x8(%rbp)
  jg     L28
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <usleep@plt>
  mov    $0x0,%eax
  call   <pthread_testintr@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <usleep@plt>
  jmp    L6
L28:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sleep@plt>
  mov    -0x4(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  imul   $0xfff0bdc0,%eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <usleep@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void pegasus_sleep(int msec) {
  int seconds;
  int microsecs = msec * 1000;
  if (microsecs < 1000000) {
    usleep(microsecs / 2);
    pthread_testintr();
    usleep(microsecs / 2);
  } else {
    seconds = microsecs / 1000000;
    sleep(seconds);
    if ((seconds * 1000000) < microsecs)
      usleep(microsecs - (seconds * 1000000));
  }
}
```