ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fuse_mnt_add_mount>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %r8,%rbx
  call   <mtab_needs_update@plt>
  test   %eax,%eax
  jne    L15
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_mount@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <add_mount_legacy@plt>
```

assistant: ```c
int fuse_mnt_add_mount(const char *progname, const char *fsname, const char *mnt, const char *type, const char *opts) {
  int res;
  if (!mtab_needs_update(mnt))
    return 0;
  res = add_mount(progname, fsname, mnt, type, opts);
  if (res == -1)
    res = add_mount_legacy(progname, fsname, mnt, type, opts);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fuse_mnt_add_mount>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %r8,%rbx
  call   <mtab_needs_update@plt>
  test   %eax,%eax
  jne    L2
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <add_mount@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    %rbx,%r8
  mov    %r13,%rcx
  pop    %rbx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <add_mount_legacy@plt>
```

assistant: ```c
int fuse_mnt_add_mount(const char *progname, const char *fsname, const char *mnt, const char *type, const char *opts) {
  int res;
  if (!mtab_needs_update(mnt))
    return 0;
  res = add_mount(progname, fsname, mnt, type, opts);
  if (res == -1)
    res = add_mount_legacy(progname, fsname, mnt, type, opts);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stat(const char *filename, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stat>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int stat(const char *filename, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stat>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int stat(const char *filename, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stat>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int stat(const char *filename, struct stat *st) {
  st->st_mode = S_IFCHR;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Protocol_Loop@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D4: Entering protocol loop...


tool: D2: type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Entering protocol loop...\n");
  printf("type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'\n");
  Protocol_Loop();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <Protocol_Loop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D7: Entering protocol loop...


tool: D12: type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Entering protocol loop...\n");
  printf("type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'\n");
  Protocol_Loop();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <Protocol_Loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D17
type: string

tool: D0: Entering protocol loop...


tool: D17: type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Entering protocol loop...\n");
  printf("type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'\n");
  Protocol_Loop();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <Protocol_Loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D7: Entering protocol loop...


tool: D16: type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Entering protocol loop...\n");
  printf("type 'CONNECT', 'CLOSE', 'SEND', or 'QUIT'\n");
  Protocol_Loop();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ffintfr8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movsd  D1(%rip),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jp     L37
  movsd  D1(%rip),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jne    L37
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L37
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jne    L37
  movq   $0x0,-0x8(%rbp)
  jmp    L21
L62:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L62
  jmp    L10
L37:
  movq   $0x0,-0x8(%rbp)
  jmp    L18
L39:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  subsd  -0x30(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L39
L10:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: f64

tool: D1: 1

assistant: ```c
int ffintfr8(int *input, long ntodo, double scale, double zero, double *output, int *status) {
  long ii;
  if (scale == 1. && zero == 0.) {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (double)input[ii];
  } else {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (input[ii] - zero) / scale;
  }
  return (*status);
}
```
user: What is the c source code of the assembly code below?

```asm
<ffintfr8>:
  endbr64
  ucomisd D17(%rip),%xmm0
  setnp  %al
  mov    $0x0,%r8d
  cmovne %r8d,%eax
  test   %al,%al
  je     L43
  ucomisd D9(%rip),%xmm1
  setnp  %al
  cmovne %r8d,%eax
  test   %al,%al
  je     L43
  test   %rsi,%rsi
  jle    L14
  mov    $0x0,%eax
L47:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L47
L14:
  mov    (%rcx),%eax
  ret
L43:
  mov    $0x0,%eax
  test   %rsi,%rsi
  jle    L14
L0:
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%rdi,%rax,4),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L0
  jmp    L14
```

tool_calls: name: parse_data
arguments: data_label: D17
data_type: f64
name: parse_data
arguments: data_label: D9
data_type: f64

tool: D17: 1

tool: D9: 0

assistant: ```c
int ffintfr8(int *input, long ntodo, double scale, double zero, double *output, int *status) {
  long ii;
  if (scale == 1. && zero == 0.) {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (double)input[ii];
  } else {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (input[ii] - zero) / scale;
  }
  return (*status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ffintfr8>:
  endbr64
  ucomisd D13(%rip),%xmm0
  mov    $0x0,%r8d
  setnp  %al
  cmovne %r8d,%eax
  test   %al,%al
  je     L38
  ucomisd D18(%rip),%xmm1
  setnp  %al
  cmovne %r8d,%eax
  test   %al,%al
  je     L38
  test   %rsi,%rsi
  jle    L23
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L59:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L59
L23:
  mov    (%rcx),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  test   %rsi,%rsi
  jle    L23
  nopw   0x0(%rax,%rax,1)
L24:
  pxor   %xmm2,%xmm2
  cvtsi2sdl (%rdi,%rax,4),%xmm2
  subsd  %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L24
  jmp    L23
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_guessed: f64
name: unpack_data
arguments: data_label: D18
type_guessed: f64

tool: D13: 1

tool: D18: 0

assistant: ```c
int ffintfr8(int *input, long ntodo, double scale, double zero, double *output, int *status) {
  long ii;
  if (scale == 1. && zero == 0.) {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (double)input[ii];
  } else {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (input[ii] - zero) / scale;
  }
  return (*status);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ffintfr8>:
  endbr64
  ucomisd D2(%rip),%xmm0
  mov    $0x0,%r8d
  movapd %xmm0,%xmm3
  setnp  %al
  cmovne %r8d,%eax
  test   %al,%al
  je     L74
  ucomisd D11(%rip),%xmm1
  setnp  %al
  cmovne %r8d,%eax
  test   %al,%al
  je     L74
  test   %rsi,%rsi
  jle    L159
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L118
  mov    %rsi,%r8
  xor    %eax,%eax
  shr    $0x2,%r8
  shl    $0x4,%r8
L30:
  movdqu (%rdi,%rax,1),%xmm0
  cvtdq2pd %xmm0,%xmm1
  pshufd $0xee,%xmm0,%xmm0
  movups %xmm1,(%rdx,%rax,2)
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,0x10(%rdx,%rax,2)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L30
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L159
L140:
  pxor   %xmm0,%xmm0
  lea    0x1(%rax),%r10
  lea    0x0(,%rax,4),%r9
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  lea    0x0(,%rax,8),%r8
  movsd  %xmm0,(%rdx,%rax,8)
  cmp    %rsi,%r10
  jge    L159
  pxor   %xmm0,%xmm0
  add    $0x2,%rax
  cvtsi2sdl 0x4(%rdi,%r9,1),%xmm0
  movsd  %xmm0,0x8(%rdx,%r8,1)
  cmp    %rax,%rsi
  jle    L159
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rdi,%r9,1),%xmm0
  movsd  %xmm0,0x10(%rdx,%r8,1)
L159:
  mov    (%rcx),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  test   %rsi,%rsi
  jle    L159
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L99
  mov    %rsi,%r8
  movapd %xmm1,%xmm5
  movapd %xmm3,%xmm4
  xor    %eax,%eax
  shr    $0x2,%r8
  unpcklpd %xmm5,%xmm5
  unpcklpd %xmm4,%xmm4
  shl    $0x4,%r8
L67:
  movdqu (%rdi,%rax,1),%xmm0
  cvtdq2pd %xmm0,%xmm2
  pshufd $0xee,%xmm0,%xmm0
  subpd  %xmm5,%xmm2
  cvtdq2pd %xmm0,%xmm0
  subpd  %xmm5,%xmm0
  divpd  %xmm4,%xmm2
  divpd  %xmm4,%xmm0
  movups %xmm2,(%rdx,%rax,2)
  movups %xmm0,0x10(%rdx,%rax,2)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L67
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L159
L141:
  pxor   %xmm0,%xmm0
  lea    0x1(%rax),%r10
  lea    0x0(,%rax,4),%r9
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  lea    0x0(,%rax,8),%r8
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  cmp    %r10,%rsi
  jle    L159
  pxor   %xmm0,%xmm0
  add    $0x2,%rax
  cvtsi2sdl 0x4(%rdi,%r9,1),%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rdx,%r8,1)
  cmp    %rax,%rsi
  jle    L159
  pxor   %xmm0,%xmm0
  mov    (%rcx),%eax
  cvtsi2sdl 0x8(%rdi,%r9,1),%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,0x10(%rdx,%r8,1)
  ret
L99:
  xor    %eax,%eax
  jmp    L141
L118:
  xor    %eax,%eax
  jmp    L140
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: f64
name: unpack_data
arguments: tag: D11
data_type: f64

tool: D2: 1

tool: D11: 0

assistant: ```c
int ffintfr8(int *input, long ntodo, double scale, double zero, double *output, int *status) {
  long ii;
  if (scale == 1. && zero == 0.) {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (double)input[ii];
  } else {
    for (ii = 0; ii < ntodo; ii++)
      output[ii] = (input[ii] - zero) / scale;
  }
  return (*status);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L23
L37:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L34
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jg     L37
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D14
data_type: string
name: parse_data
arguments: tag: D29
data_type: string

tool: D12: %d %d

tool: D14: %d

tool: D29: %d


assistant: ```c
int main() {
  int amount, current, min;
  scanf("%d %d", &amount, &min);
  for (; amount > 1; amount--) {
    scanf("%d", &current);
    if (min > current) {
      min = current;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L0
  lea    D20(%rip),%rbx
  jmp    L36
L42:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  jle    L0
L36:
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  jle    L42
  mov    %eax,0x14(%rsp)
  jmp    L42
L0:
  mov    0x14(%rsp),%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string

tool: D3: %d %d

tool: D20: %d

tool: D27: %d


assistant: ```c
int main() {
  int amount, current, min;
  scanf("%d %d", &amount, &min);
  for (; amount > 1; amount--) {
    scanf("%d", &current);
    if (min > current) {
      min = current;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L3
  lea    0x10(%rsp),%rbp
  lea    D26(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  jle    L31
  mov    %eax,0x14(%rsp)
L31:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  jg     L29
L3:
  mov    0x14(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D14: %d %d

tool: D26: %d

tool: D7: %d


assistant: ```c
int main() {
  int amount, current, min;
  scanf("%d %d", &amount, &min);
  for (; amount > 1; amount--) {
    scanf("%d", &current);
    if (min > current) {
      min = current;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0x1,0xc(%rsp)
  jle    L52
  lea    0x10(%rsp),%rbp
  lea    D25(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  jle    L53
  mov    0xc(%rsp),%ecx
  mov    %eax,0x14(%rsp)
  lea    -0x1(%rcx),%edx
  mov    %edx,0xc(%rsp)
  cmp    $0x1,%edx
  jg     L56
  mov    %eax,%esi
L31:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L53:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  jg     L56
  jmp    L31
L52:
  mov    0x14(%rsp),%esi
  jmp    L31
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D25
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string

tool: D23: %d %d

tool: D25: %d

tool: D24: %d


assistant: ```c
int main() {
  int amount, current, min;
  scanf("%d %d", &amount, &min);
  for (; amount > 1; amount--) {
    scanf("%d", &current);
    if (min > current) {
      min = current;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcm_for_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L42
  mov    D21(%rip),%eax
  test   %eax,%eax
  jne    L12
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,D22(%rip)
  jmp    L37
L12:
  cmpl   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    D22(%rip),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <lcm@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L37
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <lcm@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L37
L42:
  nop
L37:
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0x9,-0x4(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lcm_for_array(int *numbers) {
  int current_lcm = 0;
  static int firstFound = 0;
  for (int i = 0; i < 10; i++) {
    if (numbers[i] == 0)
      continue;
    if (firstFound == 0) {
      firstFound = numbers[i];
      continue;
    }
    if (current_lcm == 0) {
      current_lcm = lcm(firstFound, numbers[i]);
      continue;
    }
    current_lcm = lcm(current_lcm, numbers[i]);
  }
  return current_lcm;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lcm_for_array>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x28(%rdi),%rbp
  mov    $0x0,%edi
  jmp    L65
L14:
  mov    %esi,D6(%rip)
L26:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L20
L65:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L26
  mov    D6(%rip),%eax
  test   %eax,%eax
  je     L14
  test   %edi,%edi
  je     L4
  call   <lcm@plt>
  mov    %eax,%edi
  jmp    L26
L4:
  mov    %eax,%edi
  call   <lcm@plt>
  mov    %eax,%edi
  jmp    L26
L20:
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int lcm_for_array(int *numbers) {
  int current_lcm = 0;
  static int firstFound = 0;
  for (int i = 0; i < 10; i++) {
    if (numbers[i] == 0)
      continue;
    if (firstFound == 0) {
      firstFound = numbers[i];
      continue;
    }
    if (current_lcm == 0) {
      current_lcm = lcm(firstFound, numbers[i]);
      continue;
    }
    current_lcm = lcm(current_lcm, numbers[i]);
  }
  return current_lcm;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcm_for_array>:
  endbr64
  push   %rbp
  lea    0x28(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  jmp    L64
  nopl   (%rax)
L10:
  test   %edi,%edi
  je     L26
  call   <lcm@plt>
  mov    %eax,%edi
L41:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L5
L64:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L41
  mov    D4(%rip),%r8d
  test   %r8d,%r8d
  jne    L10
  add    $0x4,%rbx
  mov    %esi,D6(%rip)
  cmp    %rbx,%rbp
  jne    L64
L5:
  add    $0x8,%rsp
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %r8d,%edi
  call   <lcm@plt>
  mov    %eax,%edi
  jmp    L41
```

assistant: ```c
int lcm_for_array(int *numbers) {
  int current_lcm = 0;
  static int firstFound = 0;
  for (int i = 0; i < 10; i++) {
    if (numbers[i] == 0)
      continue;
    if (firstFound == 0) {
      firstFound = numbers[i];
      continue;
    }
    if (current_lcm == 0) {
      current_lcm = lcm(firstFound, numbers[i]);
      continue;
    }
    current_lcm = lcm(current_lcm, numbers[i]);
  }
  return current_lcm;
}
```