ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_q>:
  endbr64
  mov    %rsi,%r8
  movaps %xmm0,%xmm5
  test   %edx,%edx
  jle    L3
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L60
  mov    %edx,%ecx
  pxor   %xmm0,%xmm0
  movdqa D2(%rip),%xmm4
  xor    %eax,%eax
  shr    $0x2,%ecx
  movaps D1(%rip),%xmm3
  movaps %xmm0,%xmm6
  shl    $0x4,%rcx
  nop
L48:
  movdqu (%r8,%rax,1),%xmm2
  movdqu (%r8,%rax,1),%xmm1
  psrld  $0x10,%xmm2
  pand   %xmm4,%xmm1
  cvtdq2ps %xmm2,%xmm2
  mulps  %xmm3,%xmm2
  cvtdq2ps %xmm1,%xmm1
  addps  %xmm2,%xmm1
  movaps %xmm1,%xmm2
  addss  %xmm6,%xmm2
  movaps %xmm1,%xmm6
  shufps $0x55,%xmm1,%xmm6
  addss  %xmm6,%xmm2
  movaps %xmm1,%xmm6
  unpckhps %xmm1,%xmm6
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm6,%xmm2
  movaps %xmm2,%xmm6
  movdqu (%rdi,%rax,1),%xmm2
  addss  %xmm1,%xmm6
  movdqu (%rdi,%rax,1),%xmm1
  add    $0x10,%rax
  psrld  $0x10,%xmm2
  cvtdq2ps %xmm2,%xmm2
  mulps  %xmm3,%xmm2
  pand   %xmm4,%xmm1
  cvtdq2ps %xmm1,%xmm1
  addps  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L48
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L41
L13:
  movslq %eax,%rsi
  pxor   %xmm1,%xmm1
  mov    (%r8,%rsi,4),%r9d
  lea    0x0(,%rsi,4),%rcx
  mov    (%rdi,%rsi,4),%esi
  cvtsi2ss %r9,%xmm1
  addss  %xmm1,%xmm6
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  lea    0x1(%rax),%esi
  addss  %xmm1,%xmm0
  cmp    %esi,%edx
  jle    L41
  mov    0x4(%r8,%rcx,1),%esi
  pxor   %xmm1,%xmm1
  add    $0x2,%eax
  cvtsi2ss %rsi,%xmm1
  mov    0x4(%rdi,%rcx,1),%esi
  addss  %xmm1,%xmm6
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%edx
  jle    L41
  mov    0x8(%r8,%rcx,1),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  mov    0x8(%rdi,%rcx,1),%eax
  addss  %xmm1,%xmm6
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm0
L41:
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  divss  %xmm1,%xmm6
  divss  %xmm1,%xmm0
  mulss  %xmm5,%xmm6
  subss  %xmm6,%xmm0
  ret
  nopl   0x0(%rax)
L3:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L60:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movaps %xmm0,%xmm6
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: byte[16]
name: parse_data
arguments: tag: D1
type_infered: byte[16]

tool: {"D2": [0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00,0xff,0xff,0x00,0x00]}

tool: {"D1": [0x00,0x00,0x80,0x47,0x00,0x00,0x80,0x47,0x00,0x00,0x80,0x47,0x00,0x00,0x80,0x47]}

assistant: ```c
float get_q(unsigned int pole_d[], unsigned int pole_l[], uint8_t len, float k) {
  int i;
  float l_str = 0;
  float d_str = 0;
  if (len < 1) {
    return 0;
  }
  for (i = 0; i < len; i++) {
    l_str += pole_l[i];
    d_str += pole_d[i];
  }
  l_str = l_str / len;
  d_str = d_str / len;
  return d_str - (k * l_str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L40
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L34
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L34:
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L41
  mov    -0x18(%rbp),%rax
  jmp    L0
L41:
  mov    -0x8(%rbp),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strrchr(const char *s, char c) {
  char *last_c;
  last_c = NULL;
  while (*s != '\0') {
    if (*s == c)
      last_c = (char *)s;
    s++;
  }
  if (*s == c)
    return ((char *)s);
  return (last_c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strrchr>:
  endbr64
  mov    %esi,%ecx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    $0x0,%edx
L24:
  cmp    %al,%cl
  cmove  %rdi,%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L24
L21:
  test   %sil,%sil
  cmove  %rdi,%rdx
  mov    %rdx,%rax
  ret
L9:
  mov    $0x0,%edx
  jmp    L21
```

assistant: ```c
char *ft_strrchr(const char *s, char c) {
  char *last_c;
  last_c = NULL;
  while (*s != '\0') {
    if (*s == c)
      last_c = (char *)s;
    s++;
  }
  if (*s == c)
    return ((char *)s);
  return (last_c);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strrchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %al,%al
  je     L13
L10:
  cmp    %al,%dl
  cmove  %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L10
L13:
  test   %sil,%sil
  cmove  %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strrchr(const char *s, char c) {
  char *last_c;
  last_c = NULL;
  while (*s != '\0') {
    if (*s == c)
      last_c = (char *)s;
    s++;
  }
  if (*s == c)
    return ((char *)s);
  return (last_c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strrchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  xor    %r8d,%r8d
  test   %al,%al
  je     L12
L0:
  cmp    %al,%dl
  cmove  %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L0
L12:
  test   %sil,%sil
  cmove  %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strrchr(const char *s, char c) {
  char *last_c;
  last_c = NULL;
  while (*s != '\0') {
    if (*s == c)
      last_c = (char *)s;
    s++;
  }
  if (*s == c)
    return ((char *)s);
  return (last_c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L2:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L5
L10:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L29
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L29:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L59
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L59:
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_2(int *s, int size) {
  int i = 0;
  int j = 0;
  int min = 0;
  for (i = 0; i < size - 1; i++) {
    min = i;
    for (j = i + 1; j < size; j++) {
      if (s[j] < s[min]) {
        min = j;
      }
    }
    if (min != i) {
      s[i] ^= s[min];
      s[min] ^= s[i];
      s[i] ^= s[min];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sort_2>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%esi
  jle    L0
  lea    -0x2(%rsi),%r10d
  add    $0x2,%r10
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  jmp    L12
L6:
  add    $0x1,%r8
  add    $0x1,%r9
  cmp    %r10,%r9
  je     L0
L12:
  mov    %r8d,%edx
  cmp    %r9d,%esi
  jle    L6
  mov    %r9,%rax
L44:
  movslq %edx,%rdi
  mov    (%rcx,%rdi,4),%edi
  cmp    %edi,(%rcx,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L44
  cmp    %r8d,%edx
  je     L6
  movslq %edx,%rdx
  lea    (%rcx,%rdx,4),%rdx
  mov    (%rcx,%r8,4),%eax
  xor    (%rdx),%eax
  mov    %eax,(%rcx,%r8,4)
  xor    (%rdx),%eax
  mov    %eax,(%rdx)
  xor    %eax,(%rcx,%r8,4)
  jmp    L6
L0:
  ret
```

assistant: ```c
void sort_2(int *s, int size) {
  int i = 0;
  int j = 0;
  int min = 0;
  for (i = 0; i < size - 1; i++) {
    min = i;
    for (j = i + 1; j < size; j++) {
      if (s[j] < s[min]) {
        min = j;
      }
    }
    if (min != i) {
      s[i] ^= s[min];
      s[min] ^= s[i];
      s[i] ^= s[min];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort_2>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%r10d
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  add    $0x2,%r10
  nopl   (%rax)
L0:
  mov    %r8d,%edx
  cmp    %r9d,%esi
  jle    L12
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  movslq %edx,%rdi
  mov    (%rcx,%rdi,4),%edi
  cmp    %edi,(%rcx,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L38
  cmp    %r8d,%edx
  je     L12
  movslq %edx,%rdx
  mov    (%rcx,%r8,4),%eax
  lea    (%rcx,%rdx,4),%rdx
  xor    (%rdx),%eax
  mov    %eax,(%rcx,%r8,4)
  xor    (%rdx),%eax
  mov    %eax,(%rdx)
  xor    %eax,(%rcx,%r8,4)
L12:
  add    $0x1,%r9
  add    $0x1,%r8
  cmp    %r10,%r9
  jne    L0
L9:
  ret
```

assistant: ```c
void sort_2(int *s, int size) {
  int i = 0;
  int j = 0;
  int min = 0;
  for (i = 0; i < size - 1; i++) {
    min = i;
    for (j = i + 1; j < size; j++) {
      if (s[j] < s[min]) {
        min = j;
      }
    }
    if (min != i) {
      s[i] ^= s[min];
      s[min] ^= s[i];
      s[i] ^= s[min];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort_2>:
  endbr64
  push   %r13
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  test   %r12d,%r12d
  jle    L19
  mov    %rdi,%rbx
  mov    %esi,%r9d
  lea    0x4(%rdi),%r11
  xor    %r10d,%r10d
L54:
  mov    %r10d,%ebp
  add    $0x1,%r10d
  cmp    %r10d,%r9d
  jle    L22
  mov    -0x4(%r11),%r13d
  mov    %r11,%rax
  mov    %ebp,%r8d
  mov    %r10d,%edx
  mov    %r13d,%esi
  jmp    L33
  xchg   %ax,%ax
L47:
  movslq %r8d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rbx,%rcx,4),%rdi
  cmp    %r9d,%edx
  je     L55
L33:
  mov    (%rax),%ecx
  mov    %rax,%rdi
  cmp    %esi,%ecx
  jge    L47
  mov    %edx,%r8d
  add    $0x1,%edx
  mov    %ecx,%esi
  add    $0x4,%rax
  cmp    %r9d,%edx
  jne    L33
L55:
  cmp    %ebp,%r8d
  je     L22
  xor    %r13d,%esi
  mov    %esi,-0x4(%r11)
  xor    (%rdi),%esi
  mov    %esi,(%rdi)
  xor    %esi,-0x4(%r11)
L22:
  add    $0x4,%r11
  cmp    %r12d,%r10d
  jne    L54
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void sort_2(int *s, int size) {
  int i = 0;
  int j = 0;
  int min = 0;
  for (i = 0; i < size - 1; i++) {
    min = i;
    for (j = i + 1; j < size; j++) {
      if (s[j] < s[min]) {
        min = j;
      }
    }
    if (min != i) {
      s[i] ^= s[min];
      s[min] ^= s[i];
      s[i] ^= s[min];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x591c8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x16d,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <yrCalc@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D32
type: string
name: retrieve_data
arguments: data_label: D71
type: string
name: retrieve_data
arguments: data_label: D38
type: string
name: retrieve_data
arguments: data_label: D44
type: string
name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D23
type: string

tool: D16: 
%d totalDays start

tool: D32: 
Enter current year --> 

tool: D71: %d

tool: D38: 
Enter current month (1-12)--> 

tool: D44: 
Enter today's day number (1-30)--> 

tool: D7: 
%d totalDays 2

tool: D23: 
Total days from 1/1/1900 to today's date is %d.

assistant: ```c
int main() {
  long totalDays;
  totalDays = 365000;
  printf("\n%d totalDays start", totalDays);
  int year, yearDays = 365, month, monthDays = 30, day, days = 1;
  printf("\nEnter current year --> ");
  scanf("%d", &year);
  printf("\nEnter current month (1-12)--> ");
  scanf("%d", &month);
  printf("\nEnter today's day number (1-30)--> ");
  scanf("%d", &day);
  printf("\n%d totalDays 2", totalDays);
  yrCalc(&totalDays, &year, &month, &day);
  printf("\nTotal days from 1/1/1900 to today's date is %d.", totalDays);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x591c8,0x10(%rsp)
  mov    $0x591c8,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%r13
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <yrCalc@plt>
  mov    0x10(%rsp),%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D24
type: string
name: parse_data
arguments: data_tag: D25
type: string
name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D48
type: string

tool: D5: 
%d totalDays start

tool: D21: 
Enter current year --> 

tool: D24: %d

tool: D25: 
Enter current month (1-12)--> 

tool: D18: 
Enter today's day number (1-30)--> 

tool: D15: 
%d totalDays 2

tool: D48: 
Total days from 1/1/1900 to today's date is %d.

assistant: ```c
int main() {
  long totalDays;
  totalDays = 365000;
  printf("\n%d totalDays start", totalDays);
  int year, yearDays = 365, month, monthDays = 30, day, days = 1;
  printf("\nEnter current year --> ");
  scanf("%d", &year);
  printf("\nEnter current month (1-12)--> ");
  scanf("%d", &month);
  printf("\nEnter today's day number (1-30)--> ");
  scanf("%d", &day);
  printf("\n%d totalDays 2", totalDays);
  yrCalc(&totalDays, &year, &month, &day);
  printf("\nTotal days from 1/1/1900 to today's date is %d.", totalDays);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x591c8,%esi
  lea    D40(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D38(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x8(%rsp),%r13
  movq   $0x591c8,0x10(%rsp)
  lea    0xc(%rsp),%r14
  call   <printf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <yrCalc@plt>
  mov    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D40
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D59
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string
name: unpack_data
arguments: tag: D42
type_infered: string

tool: D40: 
%d totalDays start

tool: D38: %d

tool: D10: 
Enter current year --> 

tool: D4: 
Enter current month (1-12)--> 

tool: D59: 
Enter today's day number (1-30)--> 

tool: D9: 
%d totalDays 2

tool: D42: 
Total days from 1/1/1900 to today's date is %d.

assistant: ```c
int main() {
  long totalDays;
  totalDays = 365000;
  printf("\n%d totalDays start", totalDays);
  int year, yearDays = 365, month, monthDays = 30, day, days = 1;
  printf("\nEnter current year --> ");
  scanf("%d", &year);
  printf("\nEnter current month (1-12)--> ");
  scanf("%d", &month);
  printf("\nEnter today's day number (1-30)--> ");
  scanf("%d", &day);
  printf("\n%d totalDays 2", totalDays);
  yrCalc(&totalDays, &year, &month, &day);
  printf("\nTotal days from 1/1/1900 to today's date is %d.", totalDays);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x591c8,%esi
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x8(%rsp),%r13
  movq   $0x591c8,0x10(%rsp)
  lea    0xc(%rsp),%r14
  call   <printf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rsi
  lea    D66(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  call   <yrCalc@plt>
  mov    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D35
datatype: string
name: unpack_data
arguments: tag: D48
datatype: string
name: unpack_data
arguments: tag: D66
datatype: string
name: unpack_data
arguments: tag: D46
datatype: string

tool: D6: 
%d totalDays start

tool: D28: %d

tool: D5: 
Enter current year --> 

tool: D35: 
Enter current month (1-12)--> 

tool: D48: 
Enter today's day number (1-30)--> 

tool: D66: 
%d totalDays 2

tool: D46: 
Total days from 1/1/1900 to today's date is %d.

assistant: ```c
int main() {
  long totalDays;
  totalDays = 365000;
  printf("\n%d totalDays start", totalDays);
  int year, yearDays = 365, month, monthDays = 30, day, days = 1;
  printf("\nEnter current year --> ");
  scanf("%d", &year);
  printf("\nEnter current month (1-12)--> ");
  scanf("%d", &month);
  printf("\nEnter today's day number (1-30)--> ");
  scanf("%d", &day);
  printf("\n%d totalDays 2", totalDays);
  yrCalc(&totalDays, &year, &month, &day);
  printf("\nTotal days from 1/1/1900 to today's date is %d.", totalDays);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shl    $0x7,%rax
  movabs $0x1b4334b500,%rdx
  and    %rdx,%rax
  mov    %rax,%rdx
  je     L10
  sar    $0x8,%ax
  shl    $0x38,%rax
  movabs $0xffffffffff00ff,%rcx
  and    %rcx,%rdx
  or     %rax,%rdx
L19:
  shr    $0x8,%rdx
  mov    %rdx,(%rsi)
  ret
L10:
  rol    $0x20,%rax
  mov    %rax,%rdx
  jmp    L19
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  unsigned int copy13;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] > local2 << (((local1 >> 1UL) & 7UL) | 1UL)) {
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 7);
          *((char *)(&state[local2]) + 7) = copy11;
        } else {
          state[local2] = state[local1] >> (((state[local1] >> 3UL) & 7UL) | 1UL);
          copy13 = *((unsigned int *)(&state[local1]) + 0);
          *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
          *((unsigned int *)(&state[local1]) + 1) = copy13;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> 1UL) >> 7UL;
  }
}
```