ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x8,%r14d
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L86:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L91
L77:
  cmp    $0x20,%ebp
  jne    L51
  mov    %r13d,%eax
  add    $0x1,%r12d
  add    $0x1,%r13d
  and    $0x7,%eax
  test   %eax,%eax
  jne    L86
  xor    %eax,%eax
  add    $0x1,%ebx
  xor    %r12d,%r12d
  call   <getchar@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L77
L91:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x9,%edi
  sub    $0x1,%ebx
  call   <putchar@plt>
L51:
  test   %ebx,%ebx
  jne    L20
  cmp    $0x9,%ebp
  jne    L79
  mov    $0x9,%edi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  call   <putchar@plt>
  lea    -0x1(%r13),%eax
  mov    %r14d,%edx
  and    $0x7,%eax
  sub    %eax,%edx
  add    %edx,%r13d
  jmp    L86
  xchg   %ax,%ax
L57:
  mov    $0x20,%edi
  sub    $0x1,%r12d
  call   <putchar@plt>
L79:
  test   %r12d,%r12d
  jne    L57
  mov    %ebp,%edi
  call   <putchar@plt>
  cmp    $0xa,%ebp
  je     L106
  add    $0x1,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L86
  nopl   (%rax)
L106:
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L86
```

assistant: ```c
main() {
  int pos = 0;
  int nt = 0;
  int nb = 0;
  int c;
  for (pos = 1; (c = getchar()) != 0; ++pos)
    if (c == ' ') {
      if (pos % 8 != 0)
        ++nb;
      else {
        nb = 0;
        ++nt;
      }
    } else {
      while (nt > 0) {
        --nt;
        putchar('\t');
      }
      if (c == '\t')
        nb = 0;
      else
        while (nb > 0) {
          --nb;
          putchar(' ');
        }
      putchar(c);
      if (c == '\n')
        pos = 0;
      else if (c == '\t')
        pos = pos + (8 - (pos - 1) % 8) - 1;
    }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x8,%r14d
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L26:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L96
L106:
  cmp    $0x20,%ebp
  jne    L90
  mov    %r13d,%eax
  add    $0x1,%r12d
  add    $0x1,%r13d
  and    $0x7,%eax
  test   %eax,%eax
  jne    L26
  xor    %eax,%eax
  add    $0x1,%ebx
  xor    %r12d,%r12d
  call   <getchar@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L106
L96:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L108:
  mov    $0x9,%edi
  sub    $0x1,%ebx
  call   <putchar@plt>
L90:
  test   %ebx,%ebx
  jne    L108
  cmp    $0x9,%ebp
  jne    L93
  mov    $0x9,%edi
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  call   <putchar@plt>
  lea    -0x1(%r13),%eax
  mov    %r14d,%edx
  and    $0x7,%eax
  sub    %eax,%edx
  add    %edx,%r13d
  jmp    L26
  xchg   %ax,%ax
L43:
  mov    $0x20,%edi
  sub    $0x1,%r12d
  call   <putchar@plt>
L93:
  test   %r12d,%r12d
  jne    L43
  mov    %ebp,%edi
  call   <putchar@plt>
  cmp    $0xa,%ebp
  je     L88
  add    $0x1,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L26
  nopl   (%rax)
L88:
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  jmp    L26
```

assistant: ```c
main() {
  int pos = 0;
  int nt = 0;
  int nb = 0;
  int c;
  for (pos = 1; (c = getchar()) != 0; ++pos)
    if (c == ' ') {
      if (pos % 8 != 0)
        ++nb;
      else {
        nb = 0;
        ++nt;
      }
    } else {
      while (nt > 0) {
        --nt;
        putchar('\t');
      }
      if (c == '\t')
        nb = 0;
      else
        while (nb > 0) {
          --nb;
          putchar(' ');
        }
      putchar(c);
      if (c == '\n')
        pos = 0;
      else if (c == '\t')
        pos = pos + (8 - (pos - 1) % 8) - 1;
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<getfname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L1
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L1:
  cmpq   $0x0,-0x10(%rbp)
  je     L2
  addq   $0x1,-0x10(%rbp)
  jmp    L9
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getfname(const char *path) {
  const char *fname;
  const char *bslash;
  fname = strrchr(path, '/');
  bslash = strrchr(path, '\\');
  if (bslash > fname)
    fname = bslash;
  if (fname != NULL)
    fname++;
  else
    fname = (char *)path;
  return ((char *)fname);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getfname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    $0x5c,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  cmp    %rax,%rbx
  cmovb  %rax,%rbx
  lea    0x1(%rbx),%rax
  test   %rbx,%rbx
  cmove  %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getfname(const char *path) {
  const char *fname;
  const char *bslash;
  fname = strrchr(path, '/');
  bslash = strrchr(path, '\\');
  if (bslash > fname)
    fname = bslash;
  if (fname != NULL)
    fname++;
  else
    fname = (char *)path;
  return ((char *)fname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getfname>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  cmovb  %rax,%rbx
  test   %rbx,%rbx
  lea    0x1(%rbx),%rax
  cmove  %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getfname(const char *path) {
  const char *fname;
  const char *bslash;
  fname = strrchr(path, '/');
  bslash = strrchr(path, '\\');
  if (bslash > fname)
    fname = bslash;
  if (fname != NULL)
    fname++;
  else
    fname = (char *)path;
  return ((char *)fname);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getfname>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    $0x5c,%esi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  cmovb  %rax,%rbx
  test   %rbx,%rbx
  lea    0x1(%rbx),%rax
  cmove  %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getfname(const char *path) {
  const char *fname;
  const char *bslash;
  fname = strrchr(path, '/');
  bslash = strrchr(path, '\\');
  if (bslash > fname)
    fname = bslash;
  if (fname != NULL)
    fname++;
  else
    fname = (char *)path;
  return ((char *)fname);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  lea    -0x8(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    $0x4,%eax
  je     L4
  mov    -0x8(%rbp),%eax
  sub    $0xffffff80,%eax
  mov    %eax,%edi
  call   <exit@plt>
L4:
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(int fd, int err) {
  if (write(fd, &err, sizeof(err)) != sizeof(err)) {
    exit(0x80 + err);
  }
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<error>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  call   <write@plt>
  cmp    $0x4,%eax
  jne    L15
L14:
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x18,%rsp
  ret
L15:
  mov    0xc(%rsp),%eax
  lea    0x80(%rax),%edi
  call   <exit@plt>
  jmp    L14
```

assistant: ```c
void error(int fd, int err) {
  if (write(fd, &err, sizeof(err)) != sizeof(err)) {
    exit(0x80 + err);
  }
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<error>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  cmp    $0x4,%eax
  je     L2
  mov    0xc(%rsp),%eax
  lea    0x80(%rax),%edi
  call   <exit@plt>
L2:
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void error(int fd, int err) {
  if (write(fd, &err, sizeof(err)) != sizeof(err)) {
    exit(0x80 + err);
  }
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%edx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  cmp    $0x4,%eax
  je     L6
  mov    0xc(%rsp),%eax
  lea    0x80(%rax),%edi
  call   <exit@plt>
L6:
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void error(int fd, int err) {
  if (write(fd, &err, sizeof(err)) != sizeof(err)) {
    exit(0x80 + err);
  }
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<doubleSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  lea    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    -0x70(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int doubleSize() {
  double doubArray[10];
  double *doubPtr1;
  double *doubPtr2;
  doubPtr1 = &doubArray[0];
  doubPtr2 = &doubArray[1];
  return (long int)doubPtr2 - (long int)doubPtr1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<doubleSize>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int doubleSize() {
  double doubArray[10];
  double *doubPtr1;
  double *doubPtr2;
  doubPtr1 = &doubArray[0];
  doubPtr2 = &doubArray[1];
  return (long int)doubPtr2 - (long int)doubPtr1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doubleSize>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int doubleSize() {
  double doubArray[10];
  double *doubPtr1;
  double *doubPtr2;
  doubPtr1 = &doubArray[0];
  doubPtr2 = &doubArray[1];
  return (long int)doubPtr2 - (long int)doubPtr1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_env_debug_tags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_debug_tags@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: ANDROID_DEBUG

assistant: ```c
void parse_env_debug_tags(void) {
  const char *env = getenv("ANDROID_DEBUG");
  parse_debug_tags(env);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_env_debug_tags>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  call   <parse_debug_tags@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: ANDROID_DEBUG

assistant: ```c
void parse_env_debug_tags(void) {
  const char *env = getenv("ANDROID_DEBUG");
  parse_debug_tags(env);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_env_debug_tags>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <parse_debug_tags@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: ANDROID_DEBUG

assistant: ```c
void parse_env_debug_tags(void) {
  const char *env = getenv("ANDROID_DEBUG");
  parse_debug_tags(env);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_env_debug_tags>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <getenv@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <parse_debug_tags@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: ANDROID_DEBUG

assistant: ```c
void parse_env_debug_tags(void) {
  const char *env = getenv("ANDROID_DEBUG");
  parse_debug_tags(env);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__glob_is_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L78:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5d,%eax
  je     L10
  cmp    $0x5d,%eax
  jg     L39
  cmp    $0x5c,%eax
  je     L83
  cmp    $0x5c,%eax
  jg     L39
  cmp    $0x5b,%eax
  je     L122
  cmp    $0x5b,%eax
  jg     L39
  cmp    $0x2a,%eax
  je     L145
  cmp    $0x3f,%eax
  je     L145
  jmp    L39
L83:
  cmpl   $0x0,-0x1c(%rbp)
  je     L4
L145:
  mov    $0x0,%eax
  jmp    L105
L122:
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L10:
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    $0x0,%eax
  jmp    L105
L4:
  nop
  jmp    L39
L2:
  nop
L39:
  addq   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    $0x1,%eax
L105:
  pop    %rbp
  ret
```

assistant: ```c
int __glob_is_literal(const char *p, int useesc) {
  int bracket = 0;
  for (; *p; p++) {
    switch (*p) {
    case '\\':
      if (!useesc)
        break;
    case '?':
    case '*':
      return 0;
    case '[':
      bracket = 1;
      break;
    case ']':
      if (bracket)
        return 0;
      break;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__glob_is_literal>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L43
  mov    $0x0,%edx
  mov    $0x1,%ecx
  jmp    L74
L70:
  cmp    $0x5d,%al
  jne    L97
  test   %edx,%edx
  je     L97
  mov    $0x0,%eax
  ret
L53:
  test   %esi,%esi
  je     L97
  mov    $0x0,%eax
  ret
L90:
  mov    %ecx,%edx
L97:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
L74:
  cmp    $0x5c,%al
  je     L53
  jg     L70
  cmp    $0x5b,%al
  je     L90
  cmp    $0x2a,%al
  je     L84
  cmp    $0x3f,%al
  jne    L97
  mov    $0x0,%eax
  ret
L18:
  mov    $0x1,%eax
  ret
L43:
  mov    $0x1,%eax
  ret
L84:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int __glob_is_literal(const char *p, int useesc) {
  int bracket = 0;
  for (; *p; p++) {
    switch (*p) {
    case '\\':
      if (!useesc)
        break;
    case '?':
    case '*':
      return 0;
    case '[':
      bracket = 1;
      break;
    case ']':
      if (bracket)
        return 0;
      break;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__glob_is_literal>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  xor    %edx,%edx
L1:
  cmp    $0x5c,%al
  je     L45
  jg     L119
  cmp    $0x5b,%al
  je     L64
  cmp    $0x2a,%al
  je     L27
  cmp    $0x3f,%al
  jne    L9
L27:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  cmp    $0x5d,%al
  jne    L9
  test   %edx,%edx
  jne    L27
L9:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L1
L48:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    $0x1,%edx
  jmp    L9
  nop
L45:
  test   %esi,%esi
  je     L9
  jmp    L27
```

assistant: ```c
int __glob_is_literal(const char *p, int useesc) {
  int bracket = 0;
  for (; *p; p++) {
    switch (*p) {
    case '\\':
      if (!useesc)
        break;
    case '?':
    case '*':
      return 0;
    case '[':
      bracket = 1;
      break;
    case ']':
      if (bracket)
        return 0;
      break;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__glob_is_literal>:
  endbr64
  movzbl (%rdi),%edx
  mov    %esi,%eax
  test   %dl,%dl
  je     L28
  xor    %ecx,%ecx
  test   %esi,%esi
  jne    L170
L142:
  cmp    $0x5c,%dl
  je     L199
  jg     L209
  cmp    $0x5b,%dl
  je     L76
  cmp    $0x2a,%dl
  je     L132
  cmp    $0x3f,%dl
  jne    L199
L132:
  ret
  nopw   0x0(%rax,%rax,1)
L209:
  cmp    $0x5d,%dl
  jne    L199
  test   %ecx,%ecx
  jne    L94
  nopl   0x0(%rax)
L199:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L142
L28:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L76:
  mov    $0x1,%ecx
  jmp    L199
L170:
  xor    %eax,%eax
L58:
  cmp    $0x5b,%dl
  je     L167
  jle    L88
  cmp    $0x5c,%dl
  je     L31
  cmp    $0x5d,%dl
  jne    L185
  test   %eax,%eax
  jne    L31
L185:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L58
  jmp    L28
  nopl   0x0(%rax)
L88:
  cmp    $0x2a,%dl
  je     L31
  cmp    $0x3f,%dl
  jne    L185
L31:
  xor    %eax,%eax
  ret
L167:
  mov    $0x1,%eax
  jmp    L185
L94:
  ret
```

assistant: ```c
int __glob_is_literal(const char *p, int useesc) {
  int bracket = 0;
  for (; *p; p++) {
    switch (*p) {
    case '\\':
      if (!useesc)
        break;
    case '?':
    case '*':
      return 0;
    case '[':
      bracket = 1;
      break;
    case ']':
      if (bracket)
        return 0;
      break;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FormatFraction>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %rcx,%rcx
  je     L44
L6:
  movslq %r8d,%r8
  lea    -0x1(%rbx,%r8,1),%rbp
  movb   $0x0,0x0(%rbp)
  test   %edi,%edi
  jne    L40
  movb   $0x30,(%rbx)
  movb   $0x0,0x1(%rbx)
L40:
  test   %edx,%edx
  je     L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  lea    D41(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  cmpb   $0x2d,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rbx,%rax
  cmpb   $0x30,(%rax)
  je     L97
L74:
  cmpb   $0x0,0x0(%rbp)
  jne    L64
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L100
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  mov    $0x28,%r8d
  lea    D37(%rip),%rbx
  jmp    L6
L97:
  add    $0x1,%rax
  movzbl (%rax),%edx
  mov    %dl,-0x1(%rax)
  test   %dl,%dl
  jne    L97
  jmp    L74
L5:
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  call   <SimplifyFraction@plt>
  mov    0x4(%rsp),%ecx
  cmp    $0x1,%ecx
  je     L76
  mov    (%rsp),%edx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L74
L76:
  mov    (%rsp),%edx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L74
L64:
  movb   $0x0,0x0(%rbp)
  lea    D29(%rip),%rdi
  call   <SetSgError@plt>
  mov    $0x0,%ebx
  jmp    L52
L100:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D41
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string

tool: D41: %.6g

tool: D0: %d/%d

tool: D18: %d

tool: D29: Internal Error: FormatFraction(): Buffer too small

assistant: ```c
const char *FormatFraction(int nume, int deno, int Decimal, char *Buffer, int SizeBuffer) {
  int n = 0;
  int d = 0;
  char *cp, *cpp;
  static char StaticBuffer[40];
  if (NULL == Buffer) {
    Buffer = StaticBuffer;
    SizeBuffer = sizeof StaticBuffer / sizeof(*StaticBuffer);
  }
  Buffer[SizeBuffer - 1] = '\0';
  if (nume == 0) {
    Buffer[0] = '0';
    Buffer[1] = '\0';
  }
  if (Decimal) {
    sprintf(Buffer, "%.6g", (double)nume / deno);
    cp = Buffer;
    if (*cp == '-')
      cp++;
    if (*cp == '0') {
      cpp = cp + 1;
      while (*cp)
        *cp++ = *cpp++;
    }
  } else {
    SimplifyFraction(nume, deno, &n, &d);
    if (d == 1)
      sprintf(Buffer, "%d", n);
    else
      sprintf(Buffer, "%d/%d", n, d);
  }
  if (Buffer[SizeBuffer - 1] != '\0') {
    Buffer[SizeBuffer - 1] = '\0';
    SetSgError("Internal Error: FormatFraction(): Buffer too small");
    return NULL;
  }
  return Buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  and    $0x1ff,%eax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L29
L39:
  lea    -0x34(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <srand48@plt>
  mov    -0x18(%rbp),%rax
  add    $0x800,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x10,-0x18(%rbp)
  jmp    L24
L10:
  mov    $0x0,%eax
  call   <lrand48@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  addq   $0x20,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L10
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x34(%rbp),%eax
  add    $0x200,%eax
  mov    %eax,-0x34(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L39
  mov    -0x34(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t fill_buffer(void *buf, size_t size, uint64_t offset) {
  uint8_t *p, *ptr_next_sector, *ptr_end;
  assert(size % 512 == 0);
  p = buf;
  ptr_end = p + size;
  while (p < ptr_end) {
    memmove(p, &offset, sizeof(offset));
    srand48(offset);
    ptr_next_sector = p + 512;
    p += sizeof(offset);
    for (; p < ptr_next_sector; p += sizeof(long int))
      (*(long int *)p) = lrand48();
    assert(p == ptr_next_sector);
    offset += 512;
  }
  return offset;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_buffer>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,0xc(%rsp)
  test   $0x1ff,%esi
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x0(%rbp,%rbx,4),%r12
  cmp    %r12,%rbp
  jae    L38
  add    $0x810,%rbp
  lea    0xc(%rsp),%r13
  jmp    L5
L27:
  mov    %rax,%rbp
L5:
  lea    -0x810(%rbp),%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    0xc(%rsp),%edi
  call   <srand48@plt>
  lea    -0x800(%rbp),%rbx
L2:
  mov    $0x0,%eax
  call   <lrand48@plt>
  mov    %rax,(%rbx)
  add    $0x20,%rbx
  cmp    %rbp,%rbx
  jne    L2
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  addl   $0x200,0xc(%rsp)
  lea    0x810(%rbp),%rax
  cmp    %rbp,%r12
  ja     L27
L38:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t fill_buffer(void *buf, size_t size, uint64_t offset) {
  uint8_t *p, *ptr_next_sector, *ptr_end;
  assert(size % 512 == 0);
  p = buf;
  ptr_end = p + size;
  while (p < ptr_end) {
    memmove(p, &offset, sizeof(offset));
    srand48(offset);
    ptr_next_sector = p + 512;
    p += sizeof(offset);
    for (; p < ptr_next_sector; p += sizeof(long int))
      (*(long int *)p) = lrand48();
    assert(p == ptr_next_sector);
    offset += 512;
  }
  return offset;
}
```