ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<updateZside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L19
  mov    %edi,%r12d
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %r9d,%r14d
  lea    0x2(%rdx),%ecx
  mov    %ecx,0x24(%rsp)
  lea    0x2(%rsi),%eax
  imul   %ecx,%eax
  add    %ecx,%ecx
  mov    %ecx,0x20(%rsp)
  lea    (%rax,%rax,1),%edx
  movslq %edx,%rdx
  movl   $0x2,0xc(%rsp)
  cltq
  mov    %rax,0x18(%rsp)
  movslq %r9d,%rax
  add    %rdx,%rax
  mov    %rax,0x28(%rsp)
  jmp    L52
L24:
  sub    $0x8,%rsp
  push   %r14
  mov    0x1c(%rsp),%r9d
  mov    %ebp,%r8d
  mov    %r13,%rcx
  mov    0x24(%rsp),%edx
  mov    0x20(%rsp),%esi
  mov    %r12d,%edi
  call   <count@plt>
  movzbl 0x0(%r13,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    %al,(%r15,%rbx,1)
  add    $0x1,%ebp
  add    0x28(%rsp),%rbx
  add    $0x10,%rsp
  cmp    %ebp,%r12d
  jne    L24
L25:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  mov    0x24(%rsp),%edx
  add    %edx,0x20(%rsp)
  cmp    %eax,0x10(%rsp)
  je     L19
L52:
  movslq 0x20(%rsp),%rbx
  add    0x28(%rsp),%rbx
  mov    $0x2,%ebp
  cmp    $0x2,%r12d
  jg     L24
  jmp    L25
L19:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int rank) {
  int x, y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (x = 2; x < Ix; x++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<updateZside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L26
  mov    %edx,%r14d
  lea    0x2(%rsi),%eax
  lea    0x2(%rdx),%edx
  mov    %esi,0x10(%rsp)
  imul   %edx,%eax
  mov    %edx,0x24(%rsp)
  add    %edx,%edx
  mov    $0x2,%r15d
  mov    %edx,0x20(%rsp)
  mov    %r15d,%r13d
  mov    %rcx,%rbp
  mov    %edi,%r15d
  lea    (%rax,%rax,1),%edx
  cltq
  mov    %rax,0x18(%rsp)
  movslq %edx,%rdx
  movslq %r9d,%rax
  add    %rdx,%rax
  mov    %rax,0x28(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L18:
  movslq 0x20(%rsp),%rbx
  mov    $0x2,%r8d
  add    0x28(%rsp),%rbx
  cmp    $0x2,%r15d
  jle    L34
  mov    %r15d,%r12d
  mov    %r8d,%r15d
  nopl   0x0(%rax)
L15:
  sub    $0x8,%rsp
  mov    %r15d,%r8d
  mov    %rbp,%rcx
  mov    %r14d,%edx
  mov    0x1c(%rsp),%eax
  mov    %r13d,%r9d
  mov    %r12d,%edi
  add    $0x1,%r15d
  push   %rax
  mov    0x20(%rsp),%esi
  call   <count@plt>
  movzbl 0x0(%rbp,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    0x18(%rsp),%rcx
  mov    %al,(%rcx,%rbx,1)
  add    0x28(%rsp),%rbx
  pop    %rax
  pop    %rdx
  cmp    %r15d,%r12d
  jne    L15
  mov    %r12d,%r15d
L34:
  mov    0x24(%rsp),%edx
  add    $0x1,%r13d
  add    %edx,0x20(%rsp)
  cmp    %r13d,0x10(%rsp)
  jne    L18
L26:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int rank) {
  int x, y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (x = 2; x < Ix; x++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<updateZside>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L33
  lea    0x2(%rdx),%eax
  mov    %edx,%r13d
  lea    0x2(%rsi),%edx
  imul   %eax,%edx
  cmp    $0x2,%edi
  jle    L33
  mov    %rcx,%rbp
  movslq %eax,%rcx
  add    %eax,%eax
  mov    %esi,0x10(%rsp)
  mov    %rcx,0x28(%rsp)
  cltq
  movslq %r9d,%rcx
  mov    $0x2,%r15d
  add    %rcx,%rax
  lea    (%rdx,%rdx,1),%ecx
  mov    %r15d,%r14d
  mov    %edi,%r15d
  movslq %ecx,%rcx
  add    %rcx,%rax
  mov    %rax,0x20(%rsp)
  movslq %edx,%rax
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L37:
  mov    $0x2,%r8d
  mov    0x20(%rsp),%rbx
  mov    %r15d,%r12d
  mov    %r8d,%r15d
  nopl   0x0(%rax)
L25:
  sub    $0x8,%rsp
  mov    %r15d,%r8d
  mov    %r13d,%edx
  mov    %r14d,%r9d
  mov    0x1c(%rsp),%eax
  mov    %rbp,%rcx
  mov    %r12d,%edi
  add    $0x1,%r15d
  push   %rax
  mov    0x20(%rsp),%esi
  call   <count@plt>
  movzbl 0x0(%rbp,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    0x18(%rsp),%rdx
  mov    %al,(%rdx,%rbx,1)
  add    0x28(%rsp),%rbx
  pop    %rax
  pop    %rdx
  cmp    %r15d,%r12d
  jne    L25
  mov    0x28(%rsp),%rcx
  mov    %r12d,%r15d
  add    %rcx,0x20(%rsp)
  add    $0x1,%r14d
  cmp    %r14d,0x10(%rsp)
  jne    L37
L33:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZside(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int rank) {
  int x, y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    for (x = 2; x < Ix; x++) {
      c = count(Ix, Iy, Iz, data, x, y, z);
      old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
      newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<extract_cpuinfo_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L62:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    -0x28(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <memmem@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L90
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  je     L83
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L83
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L62
L83:
  mov    -0x28(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L24
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L24
  addq   $0x2,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L31
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L74
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L89
L90:
  nop
  jmp    L89
L24:
  nop
  jmp    L89
L74:
  nop
L89:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *extract_cpuinfo_field(const char *buffer, int buflen, const char *field) {
  int fieldlen = strlen(field);
  const char *bufend = buffer + buflen;
  char *result = NULL;
  int len;
  const char *p, *q;
  p = buffer;
  for (;;) {
    p = memmem(p, bufend - p, field, fieldlen);
    if (p == NULL) {
      goto EXIT;
    }
    if (p == buffer || p[-1] == '\n') {
      break;
    }
    p += fieldlen;
  }
  p += fieldlen;
  p = memchr(p, ':', bufend - p);
  if (p == NULL || p[1] != ' ') {
    goto EXIT;
  }
  p += 2;
  q = memchr(p, '\n', bufend - p);
  if (q == NULL) {
    q = bufend;
  }
  len = q - p;
  result = malloc(len + 1);
  if (result == NULL) {
    goto EXIT;
  }
  memcpy(result, p, len);
  result[len] = '\0';
EXIT:
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<extract_cpuinfo_field>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %rdx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  movslq %ebp,%rbp
  add    %r13,%rbp
  mov    %r13,%rdi
  movslq %eax,%r15
  jmp    L8
L19:
  lea    (%rax,%r15,1),%rdi
L8:
  mov    %ebp,%esi
  sub    %edi,%esi
  mov    %r12d,%ecx
  mov    %r14,%rdx
  call   <memmem@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  cmp    %rax,%r13
  je     L16
  cmpb   $0xa,-0x1(%rax)
  jne    L19
L16:
  movslq %r12d,%rdi
  add    %rbx,%rdi
  mov    %ebp,%edx
  sub    %edi,%edx
  mov    $0x3a,%esi
  call   <memchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  cmpb   $0x20,0x1(%rax)
  jne    L77
  lea    0x2(%rax),%r12
  mov    %ebp,%edx
  sub    %r12d,%edx
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  cmove  %rbp,%rax
  sub    %r12,%rax
  mov    %rax,%rbp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebp,%rax
  movb   $0x0,(%rbx,%rax,1)
  jmp    L39
L77:
  mov    $0x0,%ebx
L39:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *extract_cpuinfo_field(const char *buffer, int buflen, const char *field) {
  int fieldlen = strlen(field);
  const char *bufend = buffer + buflen;
  char *result = NULL;
  int len;
  const char *p, *q;
  p = buffer;
  for (;;) {
    p = memmem(p, bufend - p, field, fieldlen);
    if (p == NULL) {
      goto EXIT;
    }
    if (p == buffer || p[-1] == '\n') {
      break;
    }
    p += fieldlen;
  }
  p += fieldlen;
  p = memchr(p, ':', bufend - p);
  if (p == NULL || p[1] != ' ') {
    goto EXIT;
  }
  p += 2;
  q = memchr(p, '\n', bufend - p);
  if (q == NULL) {
    q = bufend;
  }
  len = q - p;
  result = malloc(len + 1);
  if (result == NULL) {
    goto EXIT;
  }
  memcpy(result, p, len);
  result[len] = '\0';
EXIT:
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extract_cpuinfo_field>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  movslq %esi,%rbx
  add    %rbp,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r14
  mov    %r14,%r12
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L31:
  lea    (%rax,%r14,1),%rdi
  cmp    %rax,%rbp
  je     L51
  cmpb   $0xa,-0x1(%rax)
  je     L51
L25:
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  sub    %edi,%esi
  call   <memmem@plt>
  test   %rax,%rax
  jne    L31
L11:
  xor    %r12d,%r12d
L27:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %ebx,%edx
  mov    $0x3a,%esi
  sub    %edi,%edx
  call   <memchr@plt>
  test   %rax,%rax
  je     L11
  cmpb   $0x20,0x1(%rax)
  jne    L11
  lea    0x2(%rax),%rbp
  mov    $0xa,%esi
  sub    %ebp,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%edx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %edx,%ebx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *extract_cpuinfo_field(const char *buffer, int buflen, const char *field) {
  int fieldlen = strlen(field);
  const char *bufend = buffer + buflen;
  char *result = NULL;
  int len;
  const char *p, *q;
  p = buffer;
  for (;;) {
    p = memmem(p, bufend - p, field, fieldlen);
    if (p == NULL) {
      goto EXIT;
    }
    if (p == buffer || p[-1] == '\n') {
      break;
    }
    p += fieldlen;
  }
  p += fieldlen;
  p = memchr(p, ':', bufend - p);
  if (p == NULL || p[1] != ' ') {
    goto EXIT;
  }
  p += 2;
  q = memchr(p, '\n', bufend - p);
  if (q == NULL) {
    q = bufend;
  }
  len = q - p;
  result = malloc(len + 1);
  if (result == NULL) {
    goto EXIT;
  }
  memcpy(result, p, len);
  result[len] = '\0';
EXIT:
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<extract_cpuinfo_field>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  movslq %esi,%rbx
  add    %rbp,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r14
  mov    %r14,%r12
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L27:
  lea    (%rax,%r14,1),%rdi
  cmp    %rax,%rbp
  je     L37
  cmpb   $0xa,-0x1(%rax)
  je     L37
L20:
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  sub    %edi,%esi
  call   <memmem@plt>
  test   %rax,%rax
  jne    L27
L33:
  xor    %r12d,%r12d
L17:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %ebx,%edx
  mov    $0x3a,%esi
  sub    %edi,%edx
  call   <memchr@plt>
  test   %rax,%rax
  je     L33
  cmpb   $0x20,0x1(%rax)
  jne    L33
  lea    0x2(%rax),%rbp
  mov    $0xa,%esi
  sub    %ebp,%ebx
  mov    %rbp,%rdi
  mov    %ebx,%edx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %edx,%ebx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *extract_cpuinfo_field(const char *buffer, int buflen, const char *field) {
  int fieldlen = strlen(field);
  const char *bufend = buffer + buflen;
  char *result = NULL;
  int len;
  const char *p, *q;
  p = buffer;
  for (;;) {
    p = memmem(p, bufend - p, field, fieldlen);
    if (p == NULL) {
      goto EXIT;
    }
    if (p == buffer || p[-1] == '\n') {
      break;
    }
    p += fieldlen;
  }
  p += fieldlen;
  p = memchr(p, ':', bufend - p);
  if (p == NULL || p[1] != ' ') {
    goto EXIT;
  }
  p += 2;
  q = memchr(p, '\n', bufend - p);
  if (q == NULL) {
    q = bufend;
  }
  len = q - p;
  result = malloc(len + 1);
  if (result == NULL) {
    goto EXIT;
  }
  memcpy(result, p, len);
  result[len] = '\0';
EXIT:
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isgraph>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jle    L2
  cmpl   $0x7e,-0x4(%rbp)
  jg     L2
  mov    $0x1,%eax
  jmp    L29
L2:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int isgraph(int c) {
  if (c >= 33 && c <= 126)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isgraph>:
  endbr64
  sub    $0x21,%edi
  cmp    $0x5d,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isgraph(int c) {
  if (c >= 33 && c <= 126)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isgraph>:
  endbr64
  sub    $0x21,%edi
  xor    %eax,%eax
  cmp    $0x5d,%edi
  setbe  %al
  ret
```

assistant: ```c
int isgraph(int c) {
  if (c >= 33 && c <= 126)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isgraph>:
  endbr64
  sub    $0x21,%edi
  xor    %eax,%eax
  cmp    $0x5d,%edi
  setbe  %al
  ret
```

assistant: ```c
int isgraph(int c) {
  if (c >= 33 && c <= 126)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_plugin_detailed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: django256 - Django SHA-256 plugin
------------------------
Use this module to crack Django SHA-256 passwords
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Django

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("django256 - Django SHA-256 plugin\n"
          "------------------------\n"
          "Use this module to crack Django SHA-256 passwords\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Django\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D5(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string

tool: D5: django256 - Django SHA-256 plugin
------------------------
Use this module to crack Django SHA-256 passwords
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Django

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("django256 - Django SHA-256 plugin\n"
          "------------------------\n"
          "Use this module to crack Django SHA-256 passwords\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Django\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: django256 - Django SHA-256 plugin
------------------------
Use this module to crack Django SHA-256 passwords
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Django

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("django256 - Django SHA-256 plugin\n"
          "------------------------\n"
          "Use this module to crack Django SHA-256 passwords\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Django\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: django256 - Django SHA-256 plugin
------------------------
Use this module to crack Django SHA-256 passwords
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Django

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("django256 - Django SHA-256 plugin\n"
          "------------------------\n"
          "Use this module to crack Django SHA-256 passwords\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Django\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L13:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int power(int n, int m) {
  int i, sum = 1;
  for (i = 0; i < m; i++) {
    sum *= n;
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    $0x1,%edx
  mov    $0x0,%eax
L4:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L4
L13:
  mov    %edx,%eax
  ret
L14:
  mov    $0x1,%edx
  jmp    L13
```

assistant: ```c
int power(int n, int m) {
  int i, sum = 1;
  for (i = 0; i < m; i++) {
    sum *= n;
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<power>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L13
  xor    %eax,%eax
L12:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L12
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int n, int m) {
  int i, sum = 1;
  for (i = 0; i < m; i++) {
    sum *= n;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<power>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L14
  xor    %eax,%eax
L12:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L12
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int n, int m) {
  int i, sum = 1;
  for (i = 0; i < m; i++) {
    sum *= n;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<i_have_permission>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L41
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    -0x8(%rbp),%rdx
  mov    0x8(%rdx),%rdx
  cmp    %rdx,%rax
  jne    L41
  mov    $0x1,%eax
  jmp    L79
L41:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L71
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    -0x8(%rbp),%rdx
  mov    0x10(%rdx),%rdx
  cmp    %rdx,%rax
  jne    L71
  mov    $0x1,%eax
  jmp    L79
L71:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  and    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L33
  mov    $0x1,%eax
  jmp    L79
L33:
  mov    $0x0,%eax
L79:
  leave
  ret
```

assistant: ```c
int i_have_permission(const struct stat *st, int op) {
  if (st->st_mode & S_IRWXU & op) {
    if (geteuid() == st->st_uid) {
      return 1;
    }
  }
  if (st->st_mode & S_IRWXG & op) {
    if (getegid() == st->st_gid) {
      return 1;
    }
  }
  if (st->st_mode & S_IRWXO & op) {
    return 1;
  }
  return 0;
}
```