ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fseek_file_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x2,-0x28(%rbp)
  je     L29
  cmpl   $0x2,-0x28(%rbp)
  jg     L6
  cmpl   $0x0,-0x28(%rbp)
  je     L21
  cmpl   $0x1,-0x28(%rbp)
  jne    L6
  movl   $0x1,-0xc(%rbp)
  jmp    L25
L29:
  movl   $0x2,-0xc(%rbp)
  jmp    L25
L21:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L6:
  mov    $0xffffffffffffffff,%rax
  jmp    L62
L25:
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x8(%rbp),%rax
L62:
  leave
  ret
```

assistant: ```c
long fseek_file_func(voidpf opaque, voidpf stream, uLong offset, int origin) {
  int fseek_origin = 0;
  long ret;
  switch (origin) {
  case (1):
    fseek_origin = 1;
    break;
  case (2):
    fseek_origin = 2;
    break;
  case (0):
    fseek_origin = 0;
    break;
  default:
    return -1;
  }
  ret = 0;
  fseek((FILE *)stream, offset, fseek_origin);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fseek_file_func>:
  endbr64
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  cmp    $0x1,%ecx
  je     L24
  cmp    $0x2,%ecx
  je     L24
  mov    $0xffffffffffffffff,%rax
  test   %ecx,%ecx
  je     L24
  ret
L24:
  sub    $0x8,%rsp
  call   <fseek@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long fseek_file_func(voidpf opaque, voidpf stream, uLong offset, int origin) {
  int fseek_origin = 0;
  long ret;
  switch (origin) {
  case (1):
    fseek_origin = 1;
    break;
  case (2):
    fseek_origin = 2;
    break;
  case (0):
    fseek_origin = 0;
    break;
  default:
    return -1;
  }
  ret = 0;
  fseek((FILE *)stream, offset, fseek_origin);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fseek_file_func>:
  endbr64
  cmp    $0x2,%ecx
  ja     L6
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  call   <fseek@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long fseek_file_func(voidpf opaque, voidpf stream, uLong offset, int origin) {
  int fseek_origin = 0;
  long ret;
  switch (origin) {
  case (1):
    fseek_origin = 1;
    break;
  case (2):
    fseek_origin = 2;
    break;
  case (0):
    fseek_origin = 0;
    break;
  default:
    return -1;
  }
  ret = 0;
  fseek((FILE *)stream, offset, fseek_origin);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fseek_file_func>:
  endbr64
  cmp    $0x2,%ecx
  ja     L1
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %ecx,%edx
  call   <fseek@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L1:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long fseek_file_func(voidpf opaque, voidpf stream, uLong offset, int origin) {
  int fseek_origin = 0;
  long ret;
  switch (origin) {
  case (1):
    fseek_origin = 1;
    break;
  case (2):
    fseek_origin = 2;
    break;
  case (0):
    fseek_origin = 0;
    break;
  default:
    return -1;
  }
  ret = 0;
  fseek((FILE *)stream, offset, fseek_origin);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<task_allocate_tid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D19(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D7(%rip)
  pop    %rbp
  ret
```

assistant: ```c
int task_allocate_tid() {
  static int tid = 0;
  return tid++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<task_allocate_tid>:
  endbr64
  mov    D18(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D10(%rip)
  ret
```

assistant: ```c
int task_allocate_tid() {
  static int tid = 0;
  return tid++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<task_allocate_tid>:
  endbr64
  mov    D14(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D0(%rip)
  ret
```

assistant: ```c
int task_allocate_tid() {
  static int tid = 0;
  return tid++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<task_allocate_tid>:
  endbr64
  mov    D7(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D15(%rip)
  ret
```

assistant: ```c
int task_allocate_tid() {
  static int tid = 0;
  return tid++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_prp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ioctl_create_prp_one_page@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ioctl_create_prp_less_than_one_page@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ioctl_create_prp_more_than_two_page@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ioctl_create_list_of_prp@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ioctl_create_fill_list_of_prp@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int test_prp(int file_desc) {
  ioctl_create_prp_one_page(file_desc);
  ioctl_create_prp_less_than_one_page(file_desc);
  ioctl_create_prp_more_than_two_page(file_desc);
  ioctl_create_list_of_prp(file_desc);
  ioctl_create_fill_list_of_prp(file_desc);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_prp>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <ioctl_create_prp_one_page@plt>
  mov    %ebx,%edi
  call   <ioctl_create_prp_less_than_one_page@plt>
  mov    %ebx,%edi
  call   <ioctl_create_prp_more_than_two_page@plt>
  mov    %ebx,%edi
  call   <ioctl_create_list_of_prp@plt>
  mov    %ebx,%edi
  call   <ioctl_create_fill_list_of_prp@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int test_prp(int file_desc) {
  ioctl_create_prp_one_page(file_desc);
  ioctl_create_prp_less_than_one_page(file_desc);
  ioctl_create_prp_more_than_two_page(file_desc);
  ioctl_create_list_of_prp(file_desc);
  ioctl_create_fill_list_of_prp(file_desc);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_prp>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <ioctl_create_prp_one_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_prp_less_than_one_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_prp_more_than_two_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_list_of_prp@plt>
  mov    %ebp,%edi
  call   <ioctl_create_fill_list_of_prp@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_prp(int file_desc) {
  ioctl_create_prp_one_page(file_desc);
  ioctl_create_prp_less_than_one_page(file_desc);
  ioctl_create_prp_more_than_two_page(file_desc);
  ioctl_create_list_of_prp(file_desc);
  ioctl_create_fill_list_of_prp(file_desc);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_prp>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <ioctl_create_prp_one_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_prp_less_than_one_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_prp_more_than_two_page@plt>
  mov    %ebp,%edi
  call   <ioctl_create_list_of_prp@plt>
  mov    %ebp,%edi
  call   <ioctl_create_fill_list_of_prp@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_prp(int file_desc) {
  ioctl_create_prp_one_page(file_desc);
  ioctl_create_prp_less_than_one_page(file_desc);
  ioctl_create_prp_more_than_two_page(file_desc);
  ioctl_create_list_of_prp(file_desc);
  ioctl_create_fill_list_of_prp(file_desc);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L4
L10:
  mov    $0x0,%eax
  call   <wo_repeated_conditionals@plt>
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L10
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long i, n;
  n = atoi(argv[1]);
  for (i = 0; i < n; i++)
    wo_repeated_conditionals();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %rax,%rax
  jle    L17
  mov    %rax,%rbp
  mov    $0x0,%ebx
L3:
  mov    $0x0,%eax
  call   <wo_repeated_conditionals@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long i, n;
  n = atoi(argv[1]);
  for (i = 0; i < n; i++)
    wo_repeated_conditionals();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %rax,%rax
  jle    L11
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L9:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <wo_repeated_conditionals@plt>
  cmp    %rbx,%rbp
  jne    L9
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long i, n;
  n = atoi(argv[1]);
  for (i = 0; i < n; i++)
    wo_repeated_conditionals();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  test   %rax,%rax
  jle    L10
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopl   (%rax)
L7:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <wo_repeated_conditionals@plt>
  cmp    %rbx,%rbp
  jne    L7
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  long i, n;
  n = atoi(argv[1]);
  for (i = 0; i < n; i++)
    wo_repeated_conditionals();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtok_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L36
L58:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  jmp    L36
L29:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
  jmp    L15
L55:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
L15:
  mov    -0x8(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
char *strtok_r(char *restrict s, const char *restrict sep, char **restrict p) {
  if (!s && !(s = *p))
    return NULL;
  s += strspn(s, sep);
  if (!*s)
    return *p = 0;
  *p = s + strcspn(s, sep);
  if (**p)
    *(*p)++ = 0;
  else
    *p = 0;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtok_r>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L52
L34:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strspn@plt>
  movslq %eax,%rbx
  add    %rbx,%r12
  cmpb   $0x0,(%r12)
  je     L23
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcspn@plt>
  cltq
  add    %r12,%rax
  cmpb   $0x0,(%rax)
  je     L39
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  movb   $0x0,(%rax)
L64:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    (%rdx),%r12
  test   %r12,%r12
  jne    L34
  jmp    L64
L23:
  movq   $0x0,0x0(%rbp)
  mov    $0x0,%r12d
  jmp    L64
L39:
  movq   $0x0,0x0(%rbp)
  jmp    L64
```

assistant: ```c
char *strtok_r(char *restrict s, const char *restrict sep, char **restrict p) {
  if (!s && !(s = *p))
    return NULL;
  s += strspn(s, sep);
  if (!*s)
    return *p = 0;
  *p = s + strcspn(s, sep);
  if (**p)
    *(*p)++ = 0;
  else
    *p = 0;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtok_r>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L22
L24:
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L0
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcspn@plt>
  cltq
  add    %r12,%rax
  cmpb   $0x0,(%rax)
  jne    L26
  movq   $0x0,0x0(%rbp)
L19:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
  mov    %r12,%rax
  mov    %rdx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  mov    (%rdx),%r12
  test   %r12,%r12
  jne    L24
  xor    %r12d,%r12d
  jmp    L19
  nopl   (%rax)
L0:
  xor    %r12d,%r12d
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strtok_r(char *restrict s, const char *restrict sep, char **restrict p) {
  if (!s && !(s = *p))
    return NULL;
  s += strspn(s, sep);
  if (!*s)
    return *p = 0;
  *p = s + strcspn(s, sep);
  if (**p)
    *(*p)++ = 0;
  else
    *p = 0;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtok_r>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L13
L25:
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <strspn@plt>
  cltq
  add    %rax,%r12
  cmpb   $0x0,(%r12)
  je     L41
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcspn@plt>
  cltq
  add    %r12,%rax
  cmpb   $0x0,(%rax)
  jne    L4
  movq   $0x0,0x0(%rbp)
L43:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
  mov    %r12,%rax
  mov    %rdx,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  mov    (%rdx),%r12
  test   %r12,%r12
  jne    L25
  xor    %r12d,%r12d
  jmp    L43
  nopl   (%rax)
L41:
  xor    %r12d,%r12d
  movq   $0x0,0x0(%rbp)
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strtok_r(char *restrict s, const char *restrict sep, char **restrict p) {
  if (!s && !(s = *p))
    return NULL;
  s += strspn(s, sep);
  if (!*s)
    return *p = 0;
  *p = s + strcspn(s, sep);
  if (**p)
    *(*p)++ = 0;
  else
    *p = 0;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ulz_bravery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L26
  movl   $0x0,-0x1c(%rbp)
L26:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L27
  movl   $0x1,-0x1c(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L36
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L36:
  cmpl   $0x1,-0x1c(%rbp)
  jle    L15
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ulz_bravery(struct ulz *u, int bravery) {
  void *weed, *upvotes;
  if (!u) {
    bravery = 0;
  }
  if (bravery < 11 / 10) {
    bravery = 11 / 10;
  }
  upvotes = malloc(bravery);
  if (upvotes) {
    weed = upvotes;
    free(weed);
  }
  if (bravery > 11 / 10) {
    free(upvotes);
  }
  return bravery;
}
```
user: What is the c source code of the assembly code below?

```asm
<ulz_bravery>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L39
  mov    %esi,%ebx
  test   %rdi,%rdi
  je     L39
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%r12d
  test   %rax,%rax
  jne    L30
  jmp    L51
L39:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x1,%r12d
  test   %rax,%rax
  je     L12
L30:
  mov    %rbp,%rdi
  call   <free@plt>
L51:
  cmp    $0x1,%r12d
  jle    L12
  mov    %rbp,%rdi
  call   <free@plt>
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ulz_bravery(struct ulz *u, int bravery) {
  void *weed, *upvotes;
  if (!u) {
    bravery = 0;
  }
  if (bravery < 11 / 10) {
    bravery = 11 / 10;
  }
  upvotes = malloc(bravery);
  if (upvotes) {
    weed = upvotes;
    free(weed);
  }
  if (bravery > 11 / 10) {
    free(upvotes);
  }
  return bravery;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ulz_bravery>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L4
  test   %rdi,%rdi
  je     L4
  mov    %esi,%edi
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L52
  mov    %rax,%rdi
  call   <free@plt>
L52:
  cmp    $0x1,%ebx
  je     L20
  mov    %r12,%rdi
  mov    %ebx,%r12d
  call   <free@plt>
L37:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%edi
  mov    $0x1,%r12d
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L37
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%r12d
  jmp    L37
```

assistant: ```c
int ulz_bravery(struct ulz *u, int bravery) {
  void *weed, *upvotes;
  if (!u) {
    bravery = 0;
  }
  if (bravery < 11 / 10) {
    bravery = 11 / 10;
  }
  upvotes = malloc(bravery);
  if (upvotes) {
    weed = upvotes;
    free(weed);
  }
  if (bravery > 11 / 10) {
    free(upvotes);
  }
  return bravery;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ulz_bravery>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L32
  test   %rdi,%rdi
  je     L32
  mov    %esi,%edi
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L42
  mov    %rax,%rdi
  call   <free@plt>
L42:
  cmp    $0x1,%ebx
  je     L6
  mov    %r12,%rdi
  mov    %ebx,%r12d
  call   <free@plt>
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%edi
  mov    $0x1,%r12d
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L47
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%r12d
  jmp    L47
```

assistant: ```c
int ulz_bravery(struct ulz *u, int bravery) {
  void *weed, *upvotes;
  if (!u) {
    bravery = 0;
  }
  if (bravery < 11 / 10) {
    bravery = 11 / 10;
  }
  upvotes = malloc(bravery);
  if (upvotes) {
    weed = upvotes;
    free(weed);
  }
  if (bravery > 11 / 10) {
    free(upvotes);
  }
  return bravery;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a8(%rbp)
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1ac(%rbp),%rdx
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L11
L16:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x1ac(%rbp),%edx
  mov    -0x1b0(%rbp),%ecx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nr_cifre@plt>
  add    %eax,-0x1a8(%rbp)
  addl   $0x1,-0x1a4(%rbp)
L11:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L16
  movl   $0x0,-0x1a4(%rbp)
  jmp    L15
L40:
  mov    -0x1ac(%rbp),%edx
  mov    -0x1b0(%rbp),%ecx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nr_cifre@plt>
  mov    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1a4(%rbp)
L15:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L40
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D40
data_type: string
name: parse_data
arguments: data_tag: D67
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D36
data_type: string
name: parse_data
arguments: data_tag: D1
data_type: string
name: parse_data
arguments: data_tag: D68
data_type: string

tool: D40: Interval de cautare: 

tool: D67: %d %d

tool: D16: Nr de componente in sir: 

tool: D36: %d

tool: D1: 
Numarul %d are %d cifre in interval.


tool: D68: 
Numarul de cifre in interval este: %d 


assistant: ```c
int main() {
  int n, a, b, s = 0, v[100], i;
  printf("Interval de cautare: ");
  scanf("%d %d", &a, &b);
  printf("Nr de componente in sir: ");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v[i]);
    s += nr_cifre(v[i], a, b);
  }
  for (i = 0; i < n; i++) {
    printf("\nNumarul %d are %d cifre in interval.\n", i + 1, nr_cifre(v[i], a, b));
  }
  printf("\nNumarul de cifre in interval este: %d \n", s);
  return 0;
}
```