user: 请从给定的汇编指令推导出C源代码：

```asm
<generateMatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  jle    L59
  lea    0x0(,%r12,4),%r14d
  mov    %rax,%rbp
  mov    %r12d,%eax
  lea    (%rbx,%rax,8),%r13
L44:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L44
  lea    -0x1(%r12),%r9d
  imul   %r12d,%r12d
  mov    %r12d,0xc(%rsp)
L46:
  movslq %r9d,%r12
  mov    %r9d,%ebp
  mov    %rbx,%r15
  mov    $0x0,%edi
  mov    $0x0,%r11d
  mov    $0x0,%r13d
  mov    $0x1,%eax
  jmp    L8
L59:
  mov    %r12d,%eax
  imul   %r12d,%eax
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L109
L138:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  mov    %r15,%r14
  mov    %ebp,%edx
  lea    0x1(%r11,%rdx,1),%r10
  shl    $0x2,%r10
  mov    %rdi,%rdx
  mov    %eax,%ecx
L65:
  mov    %ecx,%r8d
  add    $0x1,%ecx
  mov    (%r14),%rsi
  mov    %r8d,(%rsi,%rdx,1)
  add    $0x4,%rdx
  cmp    %r10,%rdx
  jne    L65
  lea    0x1(%rax,%rbp,1),%eax
L82:
  add    $0x1,%r13d
  cmp    %r9d,%r13d
  jg     L71
  lea    0x0(,%r12,4),%r10
  movslq %r13d,%rdx
  lea    (%rbx,%rdx,8),%rdx
  mov    %eax,%r14d
  mov    %r9d,%r8d
  sub    %r11d,%r8d
  add    %eax,%r8d
L60:
  mov    %eax,%esi
  add    $0x1,%eax
  mov    (%rdx),%rcx
  mov    %esi,(%rcx,%r10,1)
  add    $0x8,%rdx
  cmp    %r8d,%eax
  jne    L60
  lea    (%r14,%rbp,1),%eax
L71:
  sub    $0x1,%r9d
  mov    %r11d,%r14d
  cmp    %r11d,%r9d
  jl     L66
  lea    (%rbx,%r12,8),%r10
  movslq %r9d,%rdx
  shl    $0x2,%rdx
  mov    %r12d,%r8d
  sub    %r11d,%r8d
  add    %eax,%r8d
  mov    %rbx,%rsi
  mov    %eax,0x8(%rsp)
L86:
  mov    %eax,%ebx
  add    $0x1,%eax
  mov    (%r10),%rcx
  mov    %ebx,(%rcx,%rdx,1)
  sub    $0x4,%rdx
  cmp    %r8d,%eax
  jne    L86
  mov    %rsi,%rbx
  mov    0x8(%rsp),%ecx
  lea    (%rcx,%rbp,1),%eax
L66:
  cmp    %r14d,%r9d
  jle    L130
  movslq %r9d,%rdx
  lea    (%rbx,%rdx,8),%rdx
  mov    %eax,%r10d
  lea    -0x1(%r12),%r8d
  sub    %r11d,%r8d
  add    %eax,%r8d
L40:
  mov    %eax,%esi
  add    $0x1,%eax
  mov    (%rdx),%rcx
  mov    %esi,(%rcx,%rdi,1)
  sub    $0x8,%rdx
  cmp    %r8d,%eax
  jne    L40
  lea    -0x1(%r10,%rbp,1),%eax
L130:
  add    $0x1,%r11
  sub    $0x1,%r12
  sub    $0x2,%ebp
  add    $0x4,%rdi
  add    $0x8,%r15
  cmp    %eax,0xc(%rsp)
  jl     L138
L8:
  cmp    %r9d,%r13d
  jle    L52
  jmp    L82
L109:
  lea    -0x1(%r12),%r9d
  jmp    L46
```

assistant: ```c
int **generateMatrix(int n) {
  int **result = (int **)malloc(sizeof(int *) * n);
  int i, k;
  for (i = 0; i < n; i++) {
    result[i] = (int *)malloc(sizeof(int) * n);
  }
  int start, end;
  k = 1;
  start = 0;
  end = n - 1;
  while (k <= n * n) {
    for (i = start; i <= end; i++) {
      result[start][i] = k++;
    }
    for (i = start + 1; i <= end; i++) {
      result[i][end] = k++;
    }
    for (i = end - 1; i >= start; i--) {
      result[end][i] = k++;
    }
    for (i = end - 1; i > start; i--) {
      result[i][start] = k++;
    }
    start++;
    end--;
  }
  return result;
}
```