user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x22,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0x9,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  movl   $0xa,-0x38(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printStr@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printStr@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L69
L72:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  addl   $0x1,-0x40(%rbp)
L69:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L72
  mov    $0xa,%edi
  call   <printChar@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L39
L98:
  movl   $0x0,-0x3c(%rbp)
  jmp    L75
L81:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L5
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L5:
  addl   $0x1,-0x3c(%rbp)
L75:
  mov    -0x38(%rbp),%eax
  sub    -0x40(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x3c(%rbp)
  jl     L81
  addl   $0x1,-0x40(%rbp)
L39:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L98
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printStr@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L68
L28:
  mov    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <printInt@plt>
  mov    $0x20,%edi
  call   <printChar@plt>
  addl   $0x1,-0x40(%rbp)
L68:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L28
  mov    $0xa,%edi
  call   <printChar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D9: Bubble Sort Algorithm


tool: D16: Before sorting:


tool: D5: After sorting:


assistant: ```c
void main() {
  int array[10] = {34, 11, 9, 0, 5, 2, 4, 3, 1, 4};
  int lim = 10, i, k, temp;
  printStr("Bubble Sort Algorithm\n");
  printStr("Before sorting:\n");
  for (i = 0; i < lim; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  printChar('\n');
  for (i = 0; i < lim; i++) {
    for (k = 0; k < lim - i - 1; k++) {
      if (array[k] > array[k + 1]) {
        temp = array[k];
        array[k] = array[k + 1];
        array[k + 1] = temp;
      }
    }
  }
  printStr("After sorting:\n");
  for (i = 0; i < lim; i++) {
    printInt(array[i]);
    printChar(' ');
  }
  printChar('\n');
}
```