ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <start_watchdog@plt>
  lea    0x4(%rsp),%rbx
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <sem_init@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <sem_wait@plt>
  mov    %rbx,%rdi
  call   <sem_post@plt>
  mov    %rbx,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r __attribute__((unused));
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <start_watchdog@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    %rbp,%rdi
  call   <sem_init@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <sem_wait@plt>
  mov    %rbp,%rdi
  call   <sem_post@plt>
  mov    %rbp,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r __attribute__((unused));
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <start_watchdog@plt>
  xor    %esi,%esi
  mov    $0xffffffff,%edx
  mov    %rbp,%rdi
  call   <sem_init@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <sem_init@plt>
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <sem_wait@plt>
  mov    %rbp,%rdi
  call   <sem_post@plt>
  mov    %rbp,%rdi
  call   <sem_destroy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int r __attribute__((unused));
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_vx_nn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <print_ophead@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,%ecx
  and    $0xf,%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: V%X, %X


assistant: ```c
void print_vx_nn(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, %X\n", (op & 0x0F00) >> 8, op & 0x00FF);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_vx_nn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  movzbl %bl,%edx
  sar    $0x8,%ebx
  mov    %ebx,%esi
  and    $0xf,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: V%X, %X


assistant: ```c
void print_vx_nn(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, %X\n", (op & 0x0F00) >> 8, op & 0x00FF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_vx_nn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  movzbl %bl,%edx
  sar    $0x8,%ebx
  lea    D8(%rip),%rdi
  mov    %ebx,%esi
  pop    %rbx
  and    $0xf,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: V%X, %X


assistant: ```c
void print_vx_nn(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, %X\n", (op & 0x0F00) >> 8, op & 0x00FF);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_vx_nn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  movzbl %bl,%edx
  sar    $0x8,%ebx
  lea    D9(%rip),%rdi
  mov    %ebx,%esi
  pop    %rbx
  and    $0xf,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: V%X, %X


assistant: ```c
void print_vx_nn(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, %X\n", (op & 0x0F00) >> 8, op & 0x00FF);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<secondOccur>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strleng@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L43
  addl   $0x1,-0xc(%rbp)
L43:
  cmpl   $0x2,-0xc(%rbp)
  jne    L1
  mov    -0x8(%rbp),%eax
  jmp    L11
L1:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L18
  mov    $0x1388,%eax
L11:
  leave
  ret
```

assistant: ```c
int secondOccur(char *line, char c) {
  int n = strleng(line);
  int count = 0;
  for (int i = 0; i < n; i++) {
    if (line[i] == c)
      count++;
    if (count == 2)
      return i;
  }
  return 5000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<secondOccur>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strleng@plt>
  test   %eax,%eax
  jle    L1
  mov    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%ecx
L6:
  mov    %edx,%edi
  cmp    %bpl,(%rbx,%rdx,1)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  cmp    $0x2,%ecx
  je     L9
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L6
  mov    $0x1388,%edi
L9:
  mov    %edi,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x1388,%edi
  jmp    L9
```

assistant: ```c
int secondOccur(char *line, char c) {
  int n = strleng(line);
  int count = 0;
  for (int i = 0; i < n; i++) {
    if (line[i] == c)
      count++;
    if (count == 2)
      return i;
  }
  return 5000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<secondOccur>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strleng@plt>
  test   %eax,%eax
  jle    L8
  cltq
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L50
L21:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L8
L50:
  mov    %edx,%r8d
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L21
  cmp    $0x1,%ecx
  je     L4
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    %rax,%rdx
  jne    L50
L8:
  mov    $0x1388,%r8d
L4:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int secondOccur(char *line, char c) {
  int n = strleng(line);
  int count = 0;
  for (int i = 0; i < n; i++) {
    if (line[i] == c)
      count++;
    if (count == 2)
      return i;
  }
  return 5000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<secondOccur>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strleng@plt>
  test   %eax,%eax
  jle    L1
  cltq
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L5
L21:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L1
L5:
  mov    %edx,%r8d
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L21
  cmp    $0x1,%ecx
  je     L23
  add    $0x1,%rdx
  mov    $0x1,%ecx
  cmp    %rax,%rdx
  jne    L5
L1:
  mov    $0x1388,%r8d
L23:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int secondOccur(char *line, char c) {
  int n = strleng(line);
  int count = 0;
  for (int i = 0; i < n; i++) {
    if (line[i] == c)
      count++;
    if (count == 2)
      return i;
  }
  return 5000;
}
```
user: What is the c source code of the assembly code below:

```asm
<uwsgi_no_sudirriptions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  jmp    L14
L3:
  addl   $0x1,-0x4(%rbp)
L28:
  cmpl   $0xffff,-0x4(%rbp)
  jle    L20
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int uwsgi_no_sudirriptions(struct uwsgi_sudirribe_slot **slot) {
  int i;
  for (i = 0; i < 65536; i++) {
    if (slot[i])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uwsgi_no_sudirriptions>:
  endbr64
  lea    0x80000(%rdi),%rax
L17:
  cmpq   $0x0,(%rdi)
  jne    L8
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L17
  mov    $0x1,%eax
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int uwsgi_no_sudirriptions(struct uwsgi_sudirribe_slot **slot) {
  int i;
  for (i = 0; i < 65536; i++) {
    if (slot[i])
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uwsgi_no_sudirriptions>:
  endbr64
  lea    0x80000(%rdi),%rax
  jmp    L9
  nopl   (%rax)
L14:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L22
L9:
  cmpq   $0x0,(%rdi)
  je     L14
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uwsgi_no_sudirriptions(struct uwsgi_sudirribe_slot **slot) {
  int i;
  for (i = 0; i < 65536; i++) {
    if (slot[i])
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uwsgi_no_sudirriptions>:
  endbr64
  lea    0x80000(%rdi),%rax
  jmp    L1
  nopl   (%rax)
L21:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L10
L1:
  cmpq   $0x0,(%rdi)
  je     L21
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int uwsgi_no_sudirriptions(struct uwsgi_sudirribe_slot **slot) {
  int i;
  for (i = 0; i < 65536; i++) {
    if (slot[i])
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_abi_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_abi_endian@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  jmp    L11
L2:
  mov    $0x1,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int test_abi_C(void) {
  if (!test_abi_endian()) {
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_abi_C>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_abi_endian@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_abi_C(void) {
  if (!test_abi_endian()) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_abi_C>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_abi_endian@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_abi_C(void) {
  if (!test_abi_endian()) {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_abi_C>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_abi_endian@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int test_abi_C(void) {
  if (!test_abi_endian()) {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jg     L6
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L16
L6:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <set_params@plt>
  mov    %eax,%edi
  call   <build_output@plt>
  mov    $0x0,%eax
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: Usage: ssg [min_length] [max_length] arg1 arg2 arg3...

l - letters
c - caps
n - numbers
s - special characters


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 4) {
    printf("Usage: ssg [min_length] [max_length] "
           "arg1 arg2 arg3...\n\n"
           "l - letters\nc - caps\nn - numbers\n"
           "s - special characters\n");
    return 1;
  } else
    build_output(set_params(argc, argv));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L14
  call   <set_params@plt>
  mov    %eax,%edi
  call   <build_output@plt>
  mov    $0x0,%eax
L9:
  add    $0x8,%rsp
  ret
L14:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: Usage: ssg [min_length] [max_length] arg1 arg2 arg3...

l - letters
c - caps
n - numbers
s - special characters


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 4) {
    printf("Usage: ssg [min_length] [max_length] "
           "arg1 arg2 arg3...\n\n"
           "l - letters\nc - caps\nn - numbers\n"
           "s - special characters\n");
    return 1;
  } else
    build_output(set_params(argc, argv));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L4
  call   <set_params@plt>
  mov    %eax,%edi
  call   <build_output@plt>
  xor    %eax,%eax
L16:
  add    $0x8,%rsp
  ret
L4:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: Usage: ssg [min_length] [max_length] arg1 arg2 arg3...

l - letters
c - caps
n - numbers
s - special characters


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 4) {
    printf("Usage: ssg [min_length] [max_length] "
           "arg1 arg2 arg3...\n\n"
           "l - letters\nc - caps\nn - numbers\n"
           "s - special characters\n");
    return 1;
  } else
    build_output(set_params(argc, argv));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L13
  call   <set_params@plt>
  mov    %eax,%edi
  call   <build_output@plt>
  xor    %eax,%eax
L1:
  add    $0x8,%rsp
  ret
L13:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: Usage: ssg [min_length] [max_length] arg1 arg2 arg3...

l - letters
c - caps
n - numbers
s - special characters


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 4) {
    printf("Usage: ssg [min_length] [max_length] "
           "arg1 arg2 arg3...\n\n"
           "l - letters\nc - caps\nn - numbers\n"
           "s - special characters\n");
    return 1;
  } else
    build_output(set_params(argc, argv));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getRandomFromZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getIdentityFromZero@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <randomizeArray@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *getRandomFromZero(int numOfElements) {
  int *result;
  result = getIdentityFromZero(numOfElements);
  randomizeArray(numOfElements, result);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getRandomFromZero>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <getIdentityFromZero@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <randomizeArray@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *getRandomFromZero(int numOfElements) {
  int *result;
  result = getIdentityFromZero(numOfElements);
  randomizeArray(numOfElements, result);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getRandomFromZero>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <getIdentityFromZero@plt>
  mov    %ebp,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <randomizeArray@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *getRandomFromZero(int numOfElements) {
  int *result;
  result = getIdentityFromZero(numOfElements);
  randomizeArray(numOfElements, result);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getRandomFromZero>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <getIdentityFromZero@plt>
  mov    %ebp,%edi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <randomizeArray@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *getRandomFromZero(int numOfElements) {
  int *result;
  result = getIdentityFromZero(numOfElements);
  randomizeArray(numOfElements, result);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x8(%rbp)
  movl   $0xf,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x3,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  subl   $0x9,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 10, b = 15;
  a++;
  --a;
  ++a;
  a--;
  b -= ++a + 3;
  b = a - b;
  b--;
  b = b - 9;
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 10, b = 15;
  a++;
  --a;
  ++a;
  a--;
  b -= ++a + 3;
  b = a - b;
  b--;
  b = b - 9;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 10, b = 15;
  a++;
  --a;
  ++a;
  a--;
  b -= ++a + 3;
  b = a - b;
  b--;
  b = b - 9;
  return b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 10, b = 15;
  a++;
  --a;
  ++a;
  a--;
  b -= ++a + 3;
  b = a - b;
  b--;
  b = b - 9;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_getnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    $0x0,%eax
  jmp    L52
L21:
  movl   $0x1,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  lea    -0x1c(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <my_getnbr_parse@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    $0xffffffff,%eax
  je     L28
  mov    -0x14(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L28
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L28:
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  cmp    $0xa,%eax
  jle    L47
  mov    $0x0,%eax
  jmp    L52
L47:
  mov    -0x1c(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <my_getnbr_add@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
L52:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int my_getnbr(char *str) {
  int sign;
  int nb_start;
  int nb_end;
  int n;
  int l;
  if (str[0] == '\0') {
    return (0);
  }
  sign = 1;
  nb_start = -1;
  nb_end = -1;
  l = my_getnbr_parse(str, &nb_start, &nb_end, &sign);
  if (nb_start != -1 && nb_end == -1) {
    nb_end = l;
  }
  if (nb_end - nb_start > 10) {
    return (0);
  }
  n = my_getnbr_add(str, nb_start, nb_end, sign);
  return (n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_getnbr>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L1
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  mov    %rdi,%rbx
  movl   $0x1,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <my_getnbr_parse@plt>
  mov    0x10(%rsp),%esi
  cmp    $0xffffffff,%esi
  je     L26
  cmpl   $0xffffffff,0x14(%rsp)
  je     L43
L26:
  mov    0x14(%rsp),%edx
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    $0x0,%eax
  cmp    $0xa,%ecx
  jg     L6
  mov    0xc(%rsp),%ecx
  mov    %rbx,%rdi
  call   <my_getnbr_add@plt>
  jmp    L6
L43:
  mov    %eax,0x14(%rsp)
  jmp    L26
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_getnbr(char *str) {
  int sign;
  int nb_start;
  int nb_end;
  int n;
  int l;
  if (str[0] == '\0') {
    return (0);
  }
  sign = 1;
  nb_start = -1;
  nb_end = -1;
  l = my_getnbr_parse(str, &nb_start, &nb_end, &sign);
  if (nb_start != -1 && nb_end == -1) {
    nb_end = l;
  }
  if (nb_end - nb_start > 10) {
    return (0);
  }
  n = my_getnbr_add(str, nb_start, nb_end, sign);
  return (n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_getnbr>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  jne    L1
L5:
  xor    %eax,%eax
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  movl   $0x1,0xc(%rsp)
  mov    %rdi,%rbp
  lea    0xc(%rsp),%rcx
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  call   <my_getnbr_parse@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  cmp    $0xffffffff,%esi
  je     L15
  cmp    $0xffffffff,%edx
  jne    L15
  mov    %eax,0x14(%rsp)
  mov    %eax,%edx
L15:
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0xa,%eax
  jg     L5
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rdi
  call   <my_getnbr_add@plt>
  jmp    L23
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_getnbr(char *str) {
  int sign;
  int nb_start;
  int nb_end;
  int n;
  int l;
  if (str[0] == '\0') {
    return (0);
  }
  sign = 1;
  nb_start = -1;
  nb_end = -1;
  l = my_getnbr_parse(str, &nb_start, &nb_end, &sign);
  if (nb_start != -1 && nb_end == -1) {
    nb_end = l;
  }
  if (nb_end - nb_start > 10) {
    return (0);
  }
  n = my_getnbr_add(str, nb_start, nb_end, sign);
  return (n);
}
```