ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__utac__get_this_arg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edi,%edi
  jle    L24
  cmp    0x10(%rsi),%edi
  jg     L12
L35:
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  mov    0x8(%rbp),%rax
  mov    (%rax,%rbx,8),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D5(%rip),%rcx
  mov    $0x7b,%edx
  lea    D25(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <__assert_fail@plt>
  jmp    L35
L24:
  lea    D5(%rip),%rcx
  mov    $0x7b,%edx
  lea    D25(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <__assert_fail@plt>
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string

tool: D5: __utac__get_this_arg

tool: D25: libacc.c

tool: D12: i > 0 && i <= this->argsCount

assistant: ```c
void *__utac__get_this_arg(int i, struct JoinPoint *this) {
  void *retValue_acc;
  unsigned long __cil_tmp4;
  unsigned long __cil_tmp5;
  int __cil_tmp6;
  int __cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  void **__cil_tmp10;
  void **__cil_tmp11;
  int *mem_12;
  void ***mem_13;
  {
    if (i > 0) {
      {
        __cil_tmp4 = (unsigned long)this;
        __cil_tmp5 = __cil_tmp4 + 16;
        mem_12 = (int *)__cil_tmp5;
        __cil_tmp6 = *mem_12;
        if (i <= __cil_tmp6) {
        } else {
          { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
        }
      }
    } else {
      { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
    }
    __cil_tmp7 = i - 1;
    __cil_tmp8 = (unsigned long)this;
    __cil_tmp9 = __cil_tmp8 + 8;
    mem_13 = (void ***)__cil_tmp9;
    __cil_tmp10 = *mem_13;
    __cil_tmp11 = __cil_tmp10 + __cil_tmp7;
    retValue_acc = *__cil_tmp11;
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__utac__get_this_arg>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L2
  cmp    0x10(%rsi),%edi
  jg     L2
L18:
  mov    0x8(%rbp),%rax
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  mov    (%rax,%rbx,8),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  lea    D4(%rip),%rcx
  mov    $0x7b,%edx
  lea    D9(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <__assert_fail@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: D4: __utac__get_this_arg

tool: D9: libacc.c

tool: D5: i > 0 && i <= this->argsCount

assistant: ```c
void *__utac__get_this_arg(int i, struct JoinPoint *this) {
  void *retValue_acc;
  unsigned long __cil_tmp4;
  unsigned long __cil_tmp5;
  int __cil_tmp6;
  int __cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  void **__cil_tmp10;
  void **__cil_tmp11;
  int *mem_12;
  void ***mem_13;
  {
    if (i > 0) {
      {
        __cil_tmp4 = (unsigned long)this;
        __cil_tmp5 = __cil_tmp4 + 16;
        mem_12 = (int *)__cil_tmp5;
        __cil_tmp6 = *mem_12;
        if (i <= __cil_tmp6) {
        } else {
          { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
        }
      }
    } else {
      { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
    }
    __cil_tmp7 = i - 1;
    __cil_tmp8 = (unsigned long)this;
    __cil_tmp9 = __cil_tmp8 + 8;
    mem_13 = (void ***)__cil_tmp9;
    __cil_tmp10 = *mem_13;
    __cil_tmp11 = __cil_tmp10 + __cil_tmp7;
    retValue_acc = *__cil_tmp11;
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__utac__get_this_arg>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L28
  cmp    0x10(%rsi),%edi
  jg     L28
L17:
  mov    0x8(%rbp),%rax
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  mov    (%rax,%rbx,8),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L28:
  lea    D18(%rip),%rcx
  mov    $0x7b,%edx
  lea    D29(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <__assert_fail@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string

tool: D18: __utac__get_this_arg

tool: D29: libacc.c

tool: D26: i > 0 && i <= this->argsCount

assistant: ```c
void *__utac__get_this_arg(int i, struct JoinPoint *this) {
  void *retValue_acc;
  unsigned long __cil_tmp4;
  unsigned long __cil_tmp5;
  int __cil_tmp6;
  int __cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  void **__cil_tmp10;
  void **__cil_tmp11;
  int *mem_12;
  void ***mem_13;
  {
    if (i > 0) {
      {
        __cil_tmp4 = (unsigned long)this;
        __cil_tmp5 = __cil_tmp4 + 16;
        mem_12 = (int *)__cil_tmp5;
        __cil_tmp6 = *mem_12;
        if (i <= __cil_tmp6) {
        } else {
          { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
        }
      }
    } else {
      { __assert_fail("i > 0 && i <= this->argsCount", "libacc.c", 123U, "__utac__get_this_arg"); }
    }
    __cil_tmp7 = i - 1;
    __cil_tmp8 = (unsigned long)this;
    __cil_tmp9 = __cil_tmp8 + 8;
    mem_13 = (void ***)__cil_tmp9;
    __cil_tmp10 = *mem_13;
    __cil_tmp11 = __cil_tmp10 + __cil_tmp7;
    retValue_acc = *__cil_tmp11;
    return (retValue_acc);
    return (retValue_acc);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skipPastMap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L39
L15:
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L16:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skipPastMap(char *p) {
  while (*p != '.' && *p != '(' && *p != ',' && *p != '\0')
    ++p;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skipPastMap>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2e,%dl
  ja     L24
  mov    %rdi,%rax
  movabs $0x510000000001,%rcx
  bt     %rdx,%rcx
  jb     L6
L24:
  mov    %rdi,%rax
  movabs $0x510000000001,%rcx
L17:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2e,%dl
  ja     L17
  bt     %rdx,%rcx
  jae    L17
L6:
  ret
```

assistant: ```c
char *skipPastMap(char *p) {
  while (*p != '.' && *p != '(' && *p != ',' && *p != '\0')
    ++p;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<skipPastMap>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2e,%dl
  ja     L4
  movabs $0xffffaefffffffffe,%rcx
  mov    %rdi,%rax
  bt     %rdx,%rcx
  jae    L31
L4:
  movabs $0xffffaefffffffffe,%rcx
  mov    %rdi,%rax
  nopl   0x0(%rax)
L2:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x2e,%dl
  ja     L2
  bt     %rdx,%rcx
  jb     L2
L31:
  ret
```

assistant: ```c
char *skipPastMap(char *p) {
  while (*p != '.' && *p != '(' && *p != ',' && *p != '\0')
    ++p;
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipPastMap>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x2e,%dl
  ja     L17
  movabs $0xffffaefffffffffe,%rcx
  mov    %rdi,%rax
  bt     %rdx,%rcx
  jae    L33
L17:
  movabs $0xffffaefffffffffe,%rcx
  mov    %rdi,%rax
  nopl   0x0(%rax)
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x2e,%dl
  ja     L25
  bt     %rdx,%rcx
  jb     L25
L33:
  ret
```

assistant: ```c
char *skipPastMap(char *p) {
  while (*p != '.' && *p != '(' && *p != ',' && *p != '\0')
    ++p;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <println@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string

tool: D5: Hello, world!

assistant: ```c
int main() {
  println("Hello, world!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <println@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: Hello, world!

assistant: ```c
int main() {
  println("Hello, world!");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <println@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: Hello, world!

assistant: ```c
int main() {
  println("Hello, world!");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <println@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: Hello, world!

assistant: ```c
int main() {
  println("Hello, world!");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inicializa_estoque>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L3
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %d

assistant: ```c
void inicializa_estoque(int *produto) {
  do {
    scanf("%d", produto);
  } while (*produto <= 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inicializa_estoque>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D1(%rip),%rbp
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rbx)
  jle    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: %d

assistant: ```c
void inicializa_estoque(int *produto) {
  do {
    scanf("%d", produto);
  } while (*produto <= 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inicializa_estoque>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %d

assistant: ```c
void inicializa_estoque(int *produto) {
  do {
    scanf("%d", produto);
  } while (*produto <= 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inicializa_estoque>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: %d

assistant: ```c
void inicializa_estoque(int *produto) {
  do {
    scanf("%d", produto);
  } while (*produto <= 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<rs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fs@plt>
  cmp    $0x5,%eax
  je     L8
  call   <abort@plt>
L8:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fs@plt>
  cmp    $0x7,%eax
  je     L6
  call   <abort@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
rs(i) {
  if (fs(i++) != 5)
    abort();
  if (fs(++i) != 7)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rs>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <fs@plt>
  cmp    $0x5,%eax
  jne    L1
  lea    0x2(%rbx),%edi
  mov    $0x0,%eax
  call   <fs@plt>
  cmp    $0x7,%eax
  jne    L3
  pop    %rbx
  ret
L1:
  call   <abort@plt>
L3:
  call   <abort@plt>
```

assistant: ```c
rs(i) {
  if (fs(i++) != 5)
    abort();
  if (fs(++i) != 7)
    abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rs>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <fs@plt>
  cmp    $0x5,%eax
  jne    1080 <rs.cold>
  xor    %eax,%eax
  lea    0x2(%rbx),%edi
  call   <fs@plt>
  cmp    $0x7,%eax
  jne    1080 <rs.cold>
  pop    %rbx
  ret
```

assistant: ```c
rs(i) {
  if (fs(i++) != 5)
    abort();
  if (fs(++i) != 7)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<rs>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <fs@plt>
  cmp    $0x5,%eax
  jne    1080 <rs.cold>
  xor    %eax,%eax
  lea    0x2(%rbx),%edi
  call   <fs@plt>
  cmp    $0x7,%eax
  jne    1080 <rs.cold>
  pop    %rbx
  ret
```

assistant: ```c
rs(i) {
  if (fs(i++) != 5)
    abort();
  if (fs(++i) != 7)
    abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_itoa_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_nbrlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L51
L21:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jns    L54
  mov    $0xffffffffffffffff,%rax
  jmp    L10
L54:
  mov    $0x1,%eax
L10:
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jns    L58
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x2d,(%rax)
L58:
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_nbrmag@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L46
L41:
  mov    -0x20(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  mov    -0x38(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  cqto
  idivq  -0x40(%rbp)
  mov    %rax,-0x20(%rbp)
L46:
  cmpq   $0x0,-0x20(%rbp)
  jg     L41
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L51:
  leave
  ret
```

assistant: ```c
char *ft_itoa_base(long n, long base, char *digits) {
  char *res;
  char *save;
  long mag;
  long is_neg;
  long digidx;
  if (!(res = (char *)malloc(sizeof(char) * (ft_nbrlen(n, base) + 1))))
    return (NULL);
  save = res;
  is_neg = (n < 0 ? -1 : 1);
  if (n < 0)
    *res++ = '-';
  mag = ft_nbrmag(n, base);
  while (mag > 0) {
    digidx = n / (mag * is_neg);
    *res++ = digits[digidx];
    n = n % mag;
    mag = mag / base;
  }
  *res = '\0';
  return (save);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_itoa_base>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <ft_nbrlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%r15
  test   %rbx,%rbx
  js     L52
  mov    %rax,%rbp
  mov    $0x1,%r14d
L29:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <ft_nbrmag@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jle    L4
L56:
  add    $0x1,%rbp
  mov    %r14,%rsi
  imul   %rcx,%rsi
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  movzbl 0x0(%r13,%rax,1),%eax
  mov    %al,-0x1(%rbp)
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rbx
  mov    %rcx,%rax
  cqto
  idiv   %r12
  mov    %rax,%rcx
  test   %rax,%rax
  jg     L56
L4:
  movb   $0x0,0x0(%rbp)
L41:
  mov    %r15,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    $0x0,%r15d
  jmp    L41
L52:
  lea    0x1(%rax),%rbp
  movb   $0x2d,(%rax)
  mov    $0xffffffffffffffff,%r14
  jmp    L29
```

assistant: ```c
char *ft_itoa_base(long n, long base, char *digits) {
  char *res;
  char *save;
  long mag;
  long is_neg;
  long digidx;
  if (!(res = (char *)malloc(sizeof(char) * (ft_nbrlen(n, base) + 1))))
    return (NULL);
  save = res;
  is_neg = (n < 0 ? -1 : 1);
  if (n < 0)
    *res++ = '-';
  mag = ft_nbrmag(n, base);
  while (mag > 0) {
    digidx = n / (mag * is_neg);
    *res++ = digits[digidx];
    n = n % mag;
    mag = mag / base;
  }
  *res = '\0';
  return (save);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_itoa_base>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_nbrlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L16
  test   %r12,%r12
  js     L21
  mov    %rax,%rbx
  mov    $0x1,%r14d
L28:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ft_nbrmag@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jle    L39
  nopl   0x0(%rax)
L37:
  mov    %rcx,%rsi
  mov    %r12,%rax
  add    $0x1,%rbx
  imul   %r14,%rsi
  cqto
  idiv   %rsi
  movzbl 0x0(%r13,%rax,1),%eax
  mov    %al,-0x1(%rbx)
  mov    %r12,%rax
  cqto
  idiv   %rcx
  mov    %rcx,%rax
  mov    %rdx,%r12
  cqto
  idiv   %rbp
  mov    %rax,%rcx
  test   %rax,%rax
  jg     L37
L39:
  movb   $0x0,(%rbx)
L16:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  movb   $0x2d,(%rax)
  lea    0x1(%rax),%rbx
  mov    $0xffffffffffffffff,%r14
  jmp    L28
```

assistant: ```c
char *ft_itoa_base(long n, long base, char *digits) {
  char *res;
  char *save;
  long mag;
  long is_neg;
  long digidx;
  if (!(res = (char *)malloc(sizeof(char) * (ft_nbrlen(n, base) + 1))))
    return (NULL);
  save = res;
  is_neg = (n < 0 ? -1 : 1);
  if (n < 0)
    *res++ = '-';
  mag = ft_nbrmag(n, base);
  while (mag > 0) {
    digidx = n / (mag * is_neg);
    *res++ = digits[digidx];
    n = n % mag;
    mag = mag / base;
  }
  *res = '\0';
  return (save);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_itoa_base>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <ft_nbrlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L24
  test   %r12,%r12
  js     L20
  mov    %rax,%rbx
  mov    $0x1,%r14d
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ft_nbrmag@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  jle    L9
  nopl   0x0(%rax)
L35:
  mov    %rcx,%rsi
  mov    %r12,%rax
  add    $0x1,%rbx
  imul   %r14,%rsi
  cqto
  idiv   %rsi
  movzbl 0x0(%r13,%rax,1),%eax
  mov    %al,-0x1(%rbx)
  mov    %r12,%rax
  cqto
  idiv   %rcx
  mov    %rcx,%rax
  mov    %rdx,%r12
  cqto
  idiv   %rbp
  mov    %rax,%rcx
  test   %rax,%rax
  jg     L35
L9:
  movb   $0x0,(%rbx)
L24:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  movb   $0x2d,(%rax)
  lea    0x1(%rax),%rbx
  mov    $0xffffffffffffffff,%r14
  jmp    L10
```

assistant: ```c
char *ft_itoa_base(long n, long base, char *digits) {
  char *res;
  char *save;
  long mag;
  long is_neg;
  long digidx;
  if (!(res = (char *)malloc(sizeof(char) * (ft_nbrlen(n, base) + 1))))
    return (NULL);
  save = res;
  is_neg = (n < 0 ? -1 : 1);
  if (n < 0)
    *res++ = '-';
  mag = ft_nbrmag(n, base);
  while (mag > 0) {
    digidx = n / (mag * is_neg);
    *res++ = digits[digidx];
    n = n % mag;
    mag = mag / base;
  }
  *res = '\0';
  return (save);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<at_tok_start_flag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L27
L5:
  movsbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L27
L16:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L27:
  leave
  ret
```

assistant: ```c
int at_tok_start_flag(char **p_cur, char flag) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, flag);
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<at_tok_start_flag>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    $0x0,%eax
L31:
  pop    %rbx
  ret
L7:
  movq   $0x0,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L31
L2:
  mov    $0xffffffff,%eax
  jmp    L31
```

assistant: ```c
int at_tok_start_flag(char **p_cur, char flag) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, flag);
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<at_tok_start_flag>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L10
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  add    $0x1,%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  movq   $0x0,(%rbx)
L10:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int at_tok_start_flag(char **p_cur, char flag) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, flag);
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<at_tok_start_flag>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L11
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
  add    $0x1,%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L16:
  movq   $0x0,(%rbx)
L11:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int at_tok_start_flag(char **p_cur, char flag) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, flag);
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```