ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<cephes_nbdtr>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  ja     L30
  comisd D9(%rip),%xmm2
  ja     L30
  test   %edi,%edi
  js     L30
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mov    $0x3,%eax
  call   <cephes_incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L22
L30:
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
L22:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: f64
name: disassemble_data
arguments: label: D19
data_type: string

tool: D9: 1

tool: D19: nbdtr

assistant: ```c
double cephes_nbdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0) {
  domerr:
    mtherr("nbdtr", 1);
    return (0.0);
  }
  dk = k + 1;
  dn = n;
  return (cephes_incbet(dn, dk, p));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cephes_nbdtr>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  comisd %xmm0,%xmm3
  ja     L17
  comisd D1(%rip),%xmm0
  movapd %xmm0,%xmm2
  ja     L17
  test   %edi,%edi
  js     L17
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtsi2sd %esi,%xmm0
  cvtsi2sd %edi,%xmm1
  call   <cephes_incbet@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L17:
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: D1: 1

tool: D16: nbdtr

assistant: ```c
double cephes_nbdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0) {
  domerr:
    mtherr("nbdtr", 1);
    return (0.0);
  }
  dk = k + 1;
  dn = n;
  return (cephes_incbet(dn, dk, p));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cephes_nbdtr>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  comisd %xmm0,%xmm3
  ja     L2
  comisd D3(%rip),%xmm0
  movapd %xmm0,%xmm2
  ja     L2
  test   %edi,%edi
  js     L2
  add    $0x1,%edi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtsi2sd %esi,%xmm0
  cvtsi2sd %edi,%xmm1
  call   <cephes_incbet@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L2:
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: f64
name: parse_data
arguments: data_label: D18
datatype: string

tool: D3: 1

tool: D18: nbdtr

assistant: ```c
double cephes_nbdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if (k < 0) {
  domerr:
    mtherr("nbdtr", 1);
    return (0.0);
  }
  dk = k + 1;
  dn = n;
  return (cephes_incbet(dn, dk, p));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  movl   $0x5,-0x38(%rbp)
  movl   $0x7,-0x34(%rbp)
  movl   $0x9,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0xd,-0x28(%rbp)
  movl   $0xf,-0x24(%rbp)
  movl   $0x11,-0x20(%rbp)
  movl   $0x13,-0x1c(%rbp)
  movl   $0x15,-0x18(%rbp)
  movl   $0x17,-0x14(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L37
L1:
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x2,%rax
  and    $0x3,%eax
  test   %rax,%rax
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
L22:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x4,-0x48(%rbp)
L37:
  lea    -0x40(%rbp),%rax
  add    $0x30,%rax
  cmp    %rax,-0x48(%rbp)
  jb     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: %4d

assistant: ```c
int main() {
  int a[3][4] = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23};
  int *p;
  for (p = a[0]; p < a[0] + 12; p++) {
    if ((p - a[0]) % 4 == 0)
      printf("\n");
    printf("%4d", *p);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xb,0x14(%rsp)
  movl   $0xd,0x18(%rsp)
  movl   $0xf,0x1c(%rsp)
  movl   $0x11,0x20(%rsp)
  movl   $0x13,0x24(%rsp)
  movl   $0x15,0x28(%rsp)
  movl   $0x17,0x2c(%rsp)
  mov    %rsp,%rbx
  lea    D1(%rip),%rbp
  jmp    L14
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  lea    0x30(%rsp),%rax
  cmp    %rax,%rbx
  je     L10
L14:
  mov    %rbx,%rax
  lea    0x40(%rsp),%rdx
  sub    %rdx,%rax
  test   $0xc,%al
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L5
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: %4d

assistant: ```c
int main() {
  int a[3][4] = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23};
  int *p;
  for (p = a[0]; p < a[0] + 12; p++) {
    if ((p - a[0]) % 4 == 0)
      printf("\n");
    printf("%4d", *p);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%rbp
  lea    0x30(%rsp),%r12
  mov    %rbp,%rbx
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xb00000009,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xf0000000d,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1300000011,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x1700000015,%rax
  mov    %rax,0x28(%rsp)
  jmp    L18
  nopl   0x0(%rax)
L33:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L23
L18:
  mov    %rbx,%rax
  sub    %rbp,%rax
  test   $0xc,%al
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4: %4d

assistant: ```c
int main() {
  int a[3][4] = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23};
  int *p;
  for (p = a[0]; p < a[0] + 12; p++) {
    if ((p - a[0]) % 4 == 0)
      printf("\n");
    printf("%4d", *p);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  movdqa D36(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x30(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D11(%rip),%xmm0
  mov    %rbp,%rbx
  movaps %xmm0,0x10(%rsp)
  movdqa D30(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L46:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L47
L14:
  mov    %rbx,%rax
  sub    %rbp,%rax
  test   $0xc,%al
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D36
type_infered: byte[16]
name: parse_data
arguments: tag: D11
type_infered: byte[16]
name: parse_data
arguments: tag: D30
type_infered: byte[16]

tool: D25: %4d

tool: {"D36": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D11": [0x09,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: {"D30": [0x11,0x00,0x00,0x00,0x13,0x00,0x00,0x00,0x15,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[3][4] = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23};
  int *p;
  for (p = a[0]; p < a[0] + 12; p++) {
    if ((p - a[0]) % 4 == 0)
      printf("\n");
    printf("%4d", *p);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x4(%rbp)
  jmp    L4
L19:
  subl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 10;
  while (a != 0) {
    a = a - 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 10;
  while (a != 0) {
    a = a - 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 10;
  while (a != 0) {
    a = a - 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
void main() {
  int32_t a;
  a = 10;
  while (a != 0) {
    a = a - 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L20
  lea    D19(%rip),%rax
  jmp    L15
L20:
  lea    D25(%rip),%rax
L15:
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L10:
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L10
  nop
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string

tool: D19: parent

tool: D25: child

tool: D26: Hello world from %s


assistant: ```c
int main() {
  int status;
  int pid = fork();
  printf("Hello world from %s\n", pid ? "parent" : "child");
  while (waitpid(-1, &status, 0) > 0)
    ;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  lea    D19(%rip),%rsi
  lea    D24(%rip),%rax
  cmove  %rax,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbx
L4:
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L4
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string

tool: D19: parent

tool: D24: child

tool: D14: Hello world from %s


assistant: ```c
int main() {
  int status;
  int pid = fork();
  printf("Hello world from %s\n", pid ? "parent" : "child");
  while (waitpid(-1, &status, 0) > 0)
    ;
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <fork@plt>
  lea    D27(%rip),%rsi
  lea    D3(%rip),%rdi
  test   %eax,%eax
  lea    D0(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D0
datatype: string

tool: D27: parent

tool: D3: Hello world from %s


tool: D0: child

assistant: ```c
int main() {
  int status;
  int pid = fork();
  printf("Hello world from %s\n", pid ? "parent" : "child");
  while (waitpid(-1, &status, 0) > 0)
    ;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <fork@plt>
  lea    D6(%rip),%rsi
  lea    D1(%rip),%rdi
  test   %eax,%eax
  lea    D26(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  test   %rax,%rax
  jg     L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D6: parent

tool: D1: Hello world from %s


tool: D26: child

assistant: ```c
int main() {
  int status;
  int pid = fork();
  printf("Hello world from %s\n", pid ? "parent" : "child");
  while (waitpid(-1, &status, 0) > 0)
    ;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0x8(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D18: %d years old.


tool: D1: %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height;
  printf("%d years old.\n");
  printf("%d inches tall.\n", height);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D15: %d years old.


tool: D18: %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height;
  printf("%d years old.\n");
  printf("%d inches tall.\n", height);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D4
datatype: string

tool: D17: %d years old.


tool: D4: %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height;
  printf("%d years old.\n");
  printf("%d inches tall.\n", height);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D13: %d years old.


tool: D19: %d inches tall.


assistant: ```c
int main(int argc, char *argv[]) {
  int age = 10;
  int height;
  printf("%d years old.\n");
  printf("%d inches tall.\n", height);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putHexs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,%eax
  mov    %r9,-0x20(%rbp)
  mov    %al,-0x18(%rbp)
  jmp    L3
L14:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %eax,%r8d
  movsbl -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <putHex@plt>
  addl   $0x10,-0x10(%rbp)
  mov    D6(%rip),%rax
  lea    0x200(%rax),%r8
  movsbl -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <putfont8@plt>
  addl   $0x8,-0x10(%rbp)
  mov    0x10(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x4bda12f7,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L26
  addl   $0x18,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
L26:
  subl   $0x1,0x10(%rbp)
L3:
  cmpl   $0x0,0x10(%rbp)
  jg     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void putHexs(char *vram, int xsize, int x, int y, char c, unsigned char *s, int len) {
  extern char ascii[4096];
  for (; len > 0x00; len--) {
    putHex(vram, xsize, x, y, c, s++);
    x += 16;
    putfont8(vram, xsize, x, y, c, ascii + ' ' * 16);
    x += 8;
    if (len % 27 == 0) {
      y += 24;
      x = 0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putHexs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r9,0x8(%rsp)
  cmpl   $0x0,0x50(%rsp)
  jle    L26
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %edx,%ebp
  mov    %ecx,%r12d
  mov    0x50(%rsp),%ebx
  movsbl %r8b,%r13d
  jmp    L36
L24:
  add    $0x18,%r12d
  mov    %eax,%ebp
L18:
  sub    $0x1,%ebx
  je     L26
L36:
  mov    0x8(%rsp),%r9d
  add    0x50(%rsp),%r9d
  sub    %ebx,%r9d
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <putHex@plt>
  lea    0x10(%rbp),%edx
  mov    D9(%rip),%rax
  lea    0x200(%rax),%r9
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <putfont8@plt>
  movslq %ebx,%rax
  imul   $0x4bda12f7,%rax,%rax
  sar    $0x23,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L24
  add    $0x18,%ebp
  jmp    L18
L26:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putHexs(char *vram, int xsize, int x, int y, char c, unsigned char *s, int len) {
  extern char ascii[4096];
  for (; len > 0x00; len--) {
    putHex(vram, xsize, x, y, c, s++);
    x += 16;
    putfont8(vram, xsize, x, y, c, ascii + ' ' * 16);
    x += 8;
    if (len % 27 == 0) {
      y += 24;
      x = 0;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<putHexs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%ebx
  test   %ebx,%ebx
  jle    L16
  lea    (%rbx,%r9,1),%eax
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %eax,0x4(%rsp)
  mov    D9(%rip),%rax
  mov    %ecx,%r13d
  movsbl %r8b,%r15d
  add    $0x200,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%r9d
  mov    %r14d,%edx
  mov    %r15d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  sub    %ebx,%r9d
  call   <putHex@plt>
  mov    0x8(%rsp),%r9
  mov    %r15d,%r8d
  mov    %r13d,%ecx
  lea    0x10(%r14),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x18,%r14d
  call   <putfont8@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x4bda12f7,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%eax
  cmp    %eax,%ebx
  jne    L1
  add    $0x18,%r13d
  xor    %r14d,%r14d
L1:
  sub    $0x1,%ebx
  jne    L18
L16:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putHexs(char *vram, int xsize, int x, int y, char c, unsigned char *s, int len) {
  extern char ascii[4096];
  for (; len > 0x00; len--) {
    putHex(vram, xsize, x, y, c, s++);
    x += 16;
    putfont8(vram, xsize, x, y, c, ascii + ' ' * 16);
    x += 8;
    if (len % 27 == 0) {
      y += 24;
      x = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<putHexs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%ebx
  test   %ebx,%ebx
  jle    L25
  lea    (%rbx,%r9,1),%eax
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %eax,0x4(%rsp)
  mov    D5(%rip),%rax
  mov    %ecx,%r13d
  movsbl %r8b,%r15d
  add    $0x200,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rsp),%r9d
  mov    %r14d,%edx
  mov    %r15d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  sub    %ebx,%r9d
  call   <putHex@plt>
  mov    0x8(%rsp),%r9
  mov    %r15d,%r8d
  mov    %r13d,%ecx
  lea    0x10(%r14),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x18,%r14d
  call   <putfont8@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x4bda12f7,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  lea    (%rax,%rax,8),%eax
  cmp    %eax,%ebx
  jne    L0
  add    $0x18,%r13d
  xor    %r14d,%r14d
L0:
  sub    $0x1,%ebx
  jne    L18
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void putHexs(char *vram, int xsize, int x, int y, char c, unsigned char *s, int len) {
  extern char ascii[4096];
  for (; len > 0x00; len--) {
    putHex(vram, xsize, x, y, c, s++);
    x += 16;
    putfont8(vram, xsize, x, y, c, ascii + ' ' * 16);
    x += 8;
    if (len % 27 == 0) {
      y += 24;
      x = 0;
    }
  }
}
```