ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<shell_q_bugreport>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  call   <myMessageBox@plt>
  mov    $0x2,%r8d
  cmp    $0x5,%eax
  je     L6
  xor    %r8d,%r8d
  cmp    $0x6,%eax
  setne  %r8b
L6:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int shell_q_bugreport(const char *text) {
  int reakce;
  switch (myMessageBox(text, 6)) {
  case 6:
    reakce = 0;
    break;
  case 5:
    reakce = 2;
    break;
  default:
    reakce = 1;
  }
  return reakce;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shell_q_bugreport>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%esi
  call   <myMessageBox@plt>
  mov    $0x2,%r8d
  cmp    $0x5,%eax
  je     L9
  xor    %r8d,%r8d
  cmp    $0x6,%eax
  setne  %r8b
L9:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int shell_q_bugreport(const char *text) {
  int reakce;
  switch (myMessageBox(text, 6)) {
  case 6:
    reakce = 0;
    break;
  case 5:
    reakce = 2;
    break;
  default:
    reakce = 1;
  }
  return reakce;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findbang>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L19
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L67
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L32
L67:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L55
L68:
  addq   $0x1,-0x18(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L68
  jmp    L65
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  jne    L62
  mov    -0x18(%rbp),%rax
  jmp    L71
L65:
  nop
L62:
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
char *findbang(p)
char *p;
{
  int quote;
  for (; *p; p++) {
    if (*p == '\'' || *p == '"') {
      quote = *p;
      p++;
      while (*p && *p != quote)
        p++;
    } else if (*p == '!')
      return (p);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findbang>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L53
  mov    $0x0,%eax
  ret
L46:
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  cmp    %cl,%al
  je     L99
  test   %al,%al
  je     L99
L85:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  cmp    %cl,%al
  je     L99
  test   %al,%al
  jne    L85
L99:
  lea    0x1(%rdx),%rdi
  movzbl 0x1(%rdx),%ecx
  test   %cl,%cl
  je     L81
L53:
  cmp    $0x27,%cl
  je     L46
  cmp    $0x22,%cl
  je     L46
  cmp    $0x21,%cl
  je     L68
  mov    %rdi,%rdx
  jmp    L99
L81:
  mov    $0x0,%eax
  ret
L68:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findbang(p)
char *p;
{
  int quote;
  for (; *p; p++) {
    if (*p == '\'' || *p == '"') {
      quote = *p;
      p++;
      while (*p && *p != quote)
        p++;
    } else if (*p == '!')
      return (p);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findbang>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L98
  jmp    L49
  nopl   (%rax)
L33:
  cmp    $0x22,%cl
  je     L34
  cmp    $0x21,%cl
  je     L50
  mov    %rdi,%rdx
L71:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  test   %cl,%cl
  je     L49
L98:
  cmp    $0x27,%cl
  jne    L33
L34:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  cmp    %cl,%al
  jne    L94
  jmp    L71
  nopl   0x0(%rax)
L6:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %cl,%al
  je     L71
L94:
  test   %al,%al
  jne    L6
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  test   %cl,%cl
  jne    L98
L49:
  xor    %eax,%eax
  ret
  nop
L50:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findbang(p)
char *p;
{
  int quote;
  for (; *p; p++) {
    if (*p == '\'' || *p == '"') {
      quote = *p;
      p++;
      while (*p && *p != quote)
        p++;
    } else if (*p == '!')
      return (p);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findbang>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L66
  jmp    L26
  nopl   (%rax)
L102:
  cmp    $0x22,%cl
  je     L32
  cmp    $0x21,%cl
  je     L20
  mov    %rdi,%rdx
L41:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  test   %cl,%cl
  je     L26
L66:
  cmp    $0x27,%cl
  jne    L102
L32:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  cmp    %cl,%al
  jne    L62
  jmp    L41
  nopl   0x0(%rax)
L63:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %cl,%al
  je     L41
L62:
  test   %al,%al
  jne    L63
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  test   %cl,%cl
  jne    L66
L26:
  xor    %eax,%eax
  ret
  nop
L20:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findbang(p)
char *p;
{
  int quote;
  for (; *p; p++) {
    if (*p == '\'' || *p == '"') {
      quote = *p;
      p++;
      while (*p && *p != quote)
        p++;
    } else if (*p == '!')
      return (p);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L6
  mov    -0x4(%rbp),%eax
  jmp    L14
L6:
  mov    -0x4(%rbp),%eax
  neg    %eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int abs(int x) {
  if (x >= 0)
    return x;
  else
    return -x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int x) {
  if (x >= 0)
    return x;
  else
    return -x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lfs2_popc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t lfs2_popc(uint32_t a) {
  a = a - ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  return (((a + (a >> 4)) & 0xf0f0f0f) * 0x1010101) >> 24;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lfs2_popc>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint32_t lfs2_popc(uint32_t a) {
  a = a - ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  return (((a + (a >> 4)) & 0xf0f0f0f) * 0x1010101) >> 24;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lfs2_popc>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint32_t lfs2_popc(uint32_t a) {
  a = a - ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  return (((a + (a >> 4)) & 0xf0f0f0f) * 0x1010101) >> 24;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lfs2_popc>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  imul   $0x1010101,%eax,%eax
  sar    $0x18,%eax
  ret
```

assistant: ```c
uint32_t lfs2_popc(uint32_t a) {
  a = a - ((a >> 1) & 0x55555555);
  a = (a & 0x33333333) + ((a >> 2) & 0x33333333);
  return (((a + (a >> 4)) & 0xf0f0f0f) * 0x1010101) >> 24;
}
```
user: What is the c source code of the assembly code below?

```asm
<longest_path_recursion>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rdx,0x10(%rsp)
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x18(%rsp)
  mov    %r9d,%ebp
  cmp    %r9d,%r8d
  je     L28
  mov    %rsi,%r12
  mov    $0xffffffff,%r13d
  test   %ecx,%ecx
  jle    L98
  movslq 0x18(%rsp),%rax
  lea    (%rdi,%rax,8),%r15
  mov    0xc(%rsp),%eax
  mov    $0x0,%ebx
  mov    $0xffffffff,%r13d
  mov    %r9d,0x1c(%rsp)
  mov    %rax,%rbp
  jmp    L32
L28:
  cmp    0x60(%rsp),%r9d
  je     L1
  mov    $0x0,%r13d
  mov    0x10(%rsp),%rcx
  mov    0x60(%rsp),%esi
L22:
  movslq %ebp,%rax
  mov    (%rcx,%rax,4),%ebp
  movslq %ebp,%rdx
  mov    (%r14,%rdx,8),%rdx
  add    (%rdx,%rax,4),%r13d
  cmp    %esi,%ebp
  jne    L22
L98:
  mov    %r13d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L98
L32:
  mov    %ebx,%r8d
  cmpl   $0x0,(%r12,%rbx,4)
  jne    L7
  mov    (%r15),%rax
  cmpl   $0x0,(%rax,%rbx,4)
  jle    L7
  movl   $0x1,(%r12,%rbx,4)
  mov    0x10(%rsp),%rdx
  mov    0x18(%rsp),%eax
  mov    %eax,(%rdx,%rbx,4)
  sub    $0x8,%rsp
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x2c(%rsp),%r9d
  mov    0x1c(%rsp),%ecx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <longest_path_recursion>
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  movl   $0x0,(%r12,%rbx,4)
  add    $0x10,%rsp
  jmp    L7
L1:
  mov    $0x0,%r13d
  jmp    L98
```

assistant: ```c
int longest_path_recursion(int **graph, int *visited, int *pred, int n, int s, int t, int source) {
  if (s == t) {
    int cost = 0, vertex = t, i;
    while (vertex != source) {
      cost += graph[pred[vertex]][vertex];
      vertex = pred[vertex];
    }
    return cost;
  }
  int max = -1, maybeMax = -1, i;
  for (i = 0; i < n; i++) {
    if (visited[i] == 0 && graph[s][i] > 0) {
      visited[i] = 1;
      pred[i] = s;
      maybeMax = longest_path_recursion(graph, visited, pred, n, i, t, source);
      if (maybeMax > max) {
        max = maybeMax;
      }
      visited[i] = 0;
    }
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<longest_path_recursion>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %r8d,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r15d
  cmp    %r9d,%ebp
  je     L28
  mov    $0xffffffff,%r13d
  test   %ecx,%ecx
  jle    L33
  movslq %ebp,%rax
  movslq %ecx,%r10
  mov    %ebp,0xc(%rsp)
  mov    %rsi,%r12
  lea    (%rdi,%rax,8),%r11
  mov    %r15d,0x60(%rsp)
  xor    %ebx,%ebx
  mov    %rdx,%r14
  mov    $0xffffffff,%r13d
  mov    %r10,%rbp
  mov    %r11,%r15
L40:
  mov    (%r12,%rbx,4),%r8d
  test   %r8d,%r8d
  jne    L59
  mov    (%r15),%rax
  mov    (%rax,%rbx,4),%esi
  test   %esi,%esi
  jle    L59
  mov    0xc(%rsp),%eax
  sub    $0x8,%rsp
  mov    %r14,%rdx
  mov    %ebx,%r8d
  movl   $0x1,(%r12,%rbx,4)
  mov    %r12,%rsi
  mov    %eax,(%r14,%rbx,4)
  mov    0x68(%rsp),%eax
  push   %rax
  mov    %r9d,0x2c(%rsp)
  mov    %ecx,0x28(%rsp)
  mov    %rdi,0x20(%rsp)
  call   <longest_path_recursion>
  movl   $0x0,(%r12,%rbx,4)
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  pop    %rax
  pop    %rdx
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  mov    0x10(%rsp),%rdi
L59:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L40
L33:
  add    $0x28,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L28:
  xor    %r13d,%r13d
  cmp    %r15d,%ebp
  je     L33
  nopl   0x0(%rax,%rax,1)
L35:
  lea    0x0(,%rbp,4),%rcx
  movslq (%rdx,%rbp,4),%rbp
  mov    (%r14,%rbp,8),%rsi
  add    (%rsi,%rcx,1),%r13d
  cmp    %r15d,%ebp
  jne    L35
  jmp    L33
```

assistant: ```c
int longest_path_recursion(int **graph, int *visited, int *pred, int n, int s, int t, int source) {
  if (s == t) {
    int cost = 0, vertex = t, i;
    while (vertex != source) {
      cost += graph[pred[vertex]][vertex];
      vertex = pred[vertex];
    }
    return cost;
  }
  int max = -1, maybeMax = -1, i;
  for (i = 0; i < n; i++) {
    if (visited[i] == 0 && graph[s][i] > 0) {
      visited[i] = 1;
      pred[i] = s;
      maybeMax = longest_path_recursion(graph, visited, pred, n, i, t, source);
      if (maybeMax > max) {
        max = maybeMax;
      }
      visited[i] = 0;
    }
  }
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<longest_path_recursion>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %r8d,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r15d
  cmp    %r9d,%ebp
  je     L76
  mov    $0xffffffff,%r13d
  test   %ecx,%ecx
  jle    L78
  movslq %ebp,%rax
  movslq %ecx,%r10
  mov    %ebp,0xc(%rsp)
  mov    %rsi,%r12
  lea    (%rdi,%rax,8),%r11
  mov    %r15d,0x60(%rsp)
  xor    %ebx,%ebx
  mov    %rdx,%r14
  mov    $0xffffffff,%r13d
  mov    %r10,%rbp
  mov    %r11,%r15
L11:
  mov    (%r12,%rbx,4),%r8d
  test   %r8d,%r8d
  jne    L51
  mov    (%r15),%rax
  mov    (%rax,%rbx,4),%esi
  test   %esi,%esi
  jle    L51
  mov    0xc(%rsp),%eax
  sub    $0x8,%rsp
  mov    %r14,%rdx
  mov    %ebx,%r8d
  movl   $0x1,(%r12,%rbx,4)
  mov    %r12,%rsi
  mov    %eax,(%r14,%rbx,4)
  mov    0x68(%rsp),%eax
  push   %rax
  mov    %r9d,0x2c(%rsp)
  mov    %ecx,0x28(%rsp)
  mov    %rdi,0x20(%rsp)
  call   <longest_path_recursion>
  movl   $0x0,(%r12,%rbx,4)
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  pop    %rax
  pop    %rdx
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  mov    0x10(%rsp),%rdi
L51:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L11
L78:
  add    $0x28,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L76:
  xor    %r13d,%r13d
  cmp    %r15d,%ebp
  je     L78
  nopl   0x0(%rax,%rax,1)
L27:
  lea    0x0(,%rbp,4),%rcx
  movslq (%rdx,%rbp,4),%rbp
  mov    (%r14,%rbp,8),%rsi
  add    (%rsi,%rcx,1),%r13d
  cmp    %r15d,%ebp
  jne    L27
  jmp    L78
```

assistant: ```c
int longest_path_recursion(int **graph, int *visited, int *pred, int n, int s, int t, int source) {
  if (s == t) {
    int cost = 0, vertex = t, i;
    while (vertex != source) {
      cost += graph[pred[vertex]][vertex];
      vertex = pred[vertex];
    }
    return cost;
  }
  int max = -1, maybeMax = -1, i;
  for (i = 0; i < n; i++) {
    if (visited[i] == 0 && graph[s][i] > 0) {
      visited[i] = 1;
      pred[i] = s;
      maybeMax = longest_path_recursion(graph, visited, pred, n, i, t, source);
      if (maybeMax > max) {
        max = maybeMax;
      }
      visited[i] = 0;
    }
  }
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<putch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    $0xe,%ah
  xor    %bx,%bx
  mov    %al,%al
  int    $0x10
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putch(char ch1) {
  __asm__ __volatile__("mov $0x0E, %%ah\n"
                       "xor %%bx , %%bx\n"
                       "movb %0  , %%al\n"
                       "int $0x10\n"
                       :
                       : "r"(ch1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putch>:
  endbr64
  mov    $0xe,%ah
  xor    %bx,%bx
  mov    %dil,%al
  int    $0x10
  ret
```

assistant: ```c
void putch(char ch1) {
  __asm__ __volatile__("mov $0x0E, %%ah\n"
                       "xor %%bx , %%bx\n"
                       "movb %0  , %%al\n"
                       "int $0x10\n"
                       :
                       : "r"(ch1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putch>:
  endbr64
  mov    $0xe,%ah
  xor    %bx,%bx
  mov    %dil,%al
  int    $0x10
  ret
```

assistant: ```c
void putch(char ch1) {
  __asm__ __volatile__("mov $0x0E, %%ah\n"
                       "xor %%bx , %%bx\n"
                       "movb %0  , %%al\n"
                       "int $0x10\n"
                       :
                       : "r"(ch1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putch>:
  endbr64
  mov    $0xe,%ah
  xor    %bx,%bx
  mov    %dil,%al
  int    $0x10
  ret
```

assistant: ```c
void putch(char ch1) {
  __asm__ __volatile__("mov $0x0E, %%ah\n"
                       "xor %%bx , %%bx\n"
                       "movb %0  , %%al\n"
                       "int $0x10\n"
                       :
                       : "r"(ch1));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mem_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L23
L16:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L20
  mov    $0x1,%eax
  jmp    L39
L20:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int mem_cmp(const void *_a, const void *_b, size_t n) {
  char *a = (char *)_a;
  char *b = (char *)_b;
  while (n--) {
    if (*a != *b)
      return 1;
    a++;
    b++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mem_cmp>:
  endbr64
  test   %rdx,%rdx
  je     L1
  mov    $0x0,%eax
L21:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L15
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
  mov    $0x0,%eax
  ret
L1:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int mem_cmp(const void *_a, const void *_b, size_t n) {
  char *a = (char *)_a;
  char *b = (char *)_b;
  while (n--) {
    if (*a != *b)
      return 1;
    a++;
    b++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mem_cmp>:
  endbr64
  test   %rdx,%rdx
  je     L1
  xor    %eax,%eax
  jmp    L5
  nopl   (%rax)
L30:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L1
L5:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L30
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mem_cmp(const void *_a, const void *_b, size_t n) {
  char *a = (char *)_a;
  char *b = (char *)_b;
  while (n--) {
    if (*a != *b)
      return 1;
    a++;
    b++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mem_cmp>:
  endbr64
  test   %rdx,%rdx
  je     L23
  xor    %eax,%eax
  jmp    L12
  nopl   (%rax)
L11:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L23
L12:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L11
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int mem_cmp(const void *_a, const void *_b, size_t n) {
  char *a = (char *)_a;
  char *b = (char *)_b;
  while (n--) {
    if (*a != *b)
      return 1;
    a++;
    b++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x33c(%rbp)
  lea    -0x33c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x338(%rbp)
  jmp    L84
L44:
  lea    -0x330(%rbp),%rdx
  mov    -0x338(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L44
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  cmp    $0x64,%eax
  jg     L44
  addl   $0x1,-0x338(%rbp)
L84:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L44
  movl   $0x0,-0x338(%rbp)
  jmp    L106
L6:
  mov    -0x338(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x334(%rbp)
  jmp    L39
L26:
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%edx
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L61
  mov    -0x338(%rbp),%eax
  cltq
  movl   $0x0,-0x330(%rbp,%rax,4)
  mov    -0x334(%rbp),%eax
  cltq
  movl   $0x0,-0x330(%rbp,%rax,4)
  jmp    L58
L61:
  addl   $0x1,-0x334(%rbp)
L39:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jl     L26
L58:
  addl   $0x1,-0x338(%rbp)
L106:
  mov    -0x33c(%rbp),%eax
  cmp    %eax,-0x338(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L99
  call   <__stack_chk_fail@plt>
L99:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int i, j, n = 0, Rudo[200];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &Rudo[i]);
    } while (Rudo[i] < 1 || Rudo[i] > 100);
  }
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (Rudo[i] == Rudo[j]) {
        Rudo[i] = 0;
        Rudo[j] = 0;
        break;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L5
  lea    0x10(%rsp),%r13
  mov    $0x0,%r12d
  lea    D8(%rip),%rbp
L72:
  mov    %r13,%rbx
L3:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x63,%eax
  ja     L3
  add    $0x1,%r12d
  mov    0xc(%rsp),%edx
  add    $0x4,%r13
  cmp    %r12d,%edx
  jg     L72
  test   %edx,%edx
  jle    L5
  mov    %edx,%r9d
  mov    $0x1,%r8d
  jmp    L0
L35:
  movl   $0x0,0xc(%rsp,%r8,4)
  movslq %eax,%rcx
  movl   $0x0,0x10(%rsp,%rcx,4)
L90:
  add    $0x1,%r8
L0:
  cmp    %r9,%r8
  je     L5
  mov    0xc(%rsp,%r8,4),%edi
  mov    %r8,%rax
  lea    0x10(%rsp),%rsi
L45:
  cmp    (%rsi,%rax,4),%edi
  je     L35
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L45
  jmp    L90
L5:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main() {
  int i, j, n = 0, Rudo[200];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &Rudo[i]);
    } while (Rudo[i] < 1 || Rudo[i] > 100);
  }
  for (i = 0; i < n; i++) {
    for (j = i + 1; j < n; j++) {
      if (Rudo[i] == Rudo[j]) {
        Rudo[i] = 0;
        Rudo[j] = 0;
        break;
      }
    }
  }
}
```