ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_implementations>:
  endbr64
  push   %r13
  mov    $0x1,%esi
  mov    $0x200,%edi
  push   %r12
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x100,%edi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    $0x1,%esi
  mov    $0x100,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  movdqa D22(%rip),%xmm0
  mov    %rax,%r13
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D17(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  xchg   %ax,%ax
L18:
  mov    %eax,%edx
  and    $0x3f,%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    $0x200,%rax
  jne    L18
  xor    %eax,%eax
  call   <load_constants@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <haraka512_8x@plt>
  mov    %rsp,%rcx
  lea    0x20(%r13),%rsi
  mov    %r13,%rax
  mov    $0xffffffbe,%edx
  sub    %r13,%rcx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L25
  movzbl (%rcx,%rax,1),%edx
L9:
  cmp    %dl,(%rax)
  je     L49
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x30,%rsp
  lea    D28(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <printf@plt>
L25:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x30,%rsp
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
type_guessed: byte[16]
name: unpack_data
arguments: label: D17
type_guessed: byte[16]
name: unpack_data
arguments: label: D28
type_guessed: string

tool: {"D22": [0xbe,0x7f,0x72,0x3b,0x4e,0x80,0xa9,0x98,0x13,0xb2,0x92,0x28,0x7f,0x30,0x6f,0x62]}

tool: {"D17": [0x5a,0x6d,0x57,0x33,0x1c,0xae,0x5f,0x34,0xdd,0x92,0x77,0xb0,0x94,0x5b,0xe2,0xaa]}

tool: D28: Error: testvector incorrect.


assistant: ```c
void test_implementations() {
  unsigned char *in = (unsigned char *)calloc(64 * 8, sizeof(unsigned char));
  unsigned char *out256 = (unsigned char *)calloc(32 * 8, sizeof(unsigned char));
  unsigned char *out512 = (unsigned char *)calloc(32 * 8, sizeof(unsigned char));
  unsigned char testvector256[32] = {0x80, 0x27, 0xcc, 0xb8, 0x79, 0x49, 0x77, 0x4b, 0x78, 0xd0, 0x54, 0x5f, 0xb7, 0x2b, 0xf7, 0x0c, 0x69, 0x5c, 0x2a, 0x09, 0x23, 0xcb, 0xd4, 0x7b, 0xba, 0x11, 0x59, 0xef, 0xbf, 0x2b, 0x2c, 0x1c};
  unsigned char testvector512[32] = {0xbe, 0x7f, 0x72, 0x3b, 0x4e, 0x80, 0xa9, 0x98, 0x13, 0xb2, 0x92, 0x28, 0x7f, 0x30, 0x6f, 0x62, 0x5a, 0x6d, 0x57, 0x33, 0x1c, 0xae, 0x5f, 0x34, 0xdd, 0x92, 0x77, 0xb0, 0x94, 0x5b, 0xe2, 0xaa};
  int i;
  for (i = 0; i < 512; i++) {
    in[i] = i % 64;
  }
  load_constants();
  haraka512_8x(out512, in);
  for (i = 0; i < 32; i++) {
    if (out512[i % 32] != testvector512[i]) {
      printf("Error: testvector incorrect.\n");
      return;
    }
  }
  free(in);
  free(out256);
  free(out512);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drawper>:
  endbr64
  test   %rdx,%rdx
  je     L91
  sub    $0x8,%rsp
  mov    %edi,%ecx
  mov    %rdx,%rdi
  imul   $0x64,%ecx,%eax
  cltd
  idiv   %esi
  cmp    %esi,%ecx
  je     L114
  mov    D16(%rip),%ecx
  test   %ecx,%ecx
  je     L4
  cmp    $0x1,%ecx
  je     L12
  cmp    $0x2,%ecx
  je     L25
  cmp    $0x3,%ecx
  jne    L52
  mov    %eax,%edx
  lea    D22(%rip),%rsi
  call   <sprintf@plt>
  jmp    L1
L114:
  mov    %eax,%edx
  lea    D42(%rip),%rsi
  call   <sprintf@plt>
  jmp    L1
L4:
  mov    %eax,%edx
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
L1:
  mov    D16(%rip),%ecx
  cmp    $0x3,%ecx
  je     L14
L52:
  add    $0x1,%ecx
  mov    %ecx,D38(%rip)
L62:
  add    $0x8,%rsp
  ret
L12:
  mov    %eax,%edx
  lea    D38(%rip),%rsi
  call   <sprintf@plt>
  jmp    L1
L25:
  mov    %eax,%edx
  lea    D45(%rip),%rsi
  call   <sprintf@plt>
  jmp    L1
L14:
  movl   $0x0,D38(%rip)
  jmp    L62
L91:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D42
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D45
type_guessed: string

tool: D22: [\ %d%]

tool: D42: [ %d%]

tool: D0: [| %d%]

tool: D38: [/ %d%]

tool: D45: [- %d%]

assistant: ```c
void drawper(int file_send, int file_total, char *spOut) {
  if (NULL == spOut) {
    return;
  }
  static int iCrlmm = 0;
  int iPer = file_send * 100 / file_total;
  if (file_send == file_total) {
    sprintf(spOut, "[ %d%]\r", iPer);
  } else if (iCrlmm == 0) {
    sprintf(spOut, "[| %d%]\r", iPer);
  } else if (iCrlmm == 1) {
    sprintf(spOut, "[/ %d%]\r", iPer);
  } else if (iCrlmm == 2) {
    sprintf(spOut, "[- %d%]\r", iPer);
  } else if (iCrlmm == 3) {
    sprintf(spOut, "[\\ %d%]\r", iPer);
  }
  if (iCrlmm == 3) {
    iCrlmm = 0;
  } else {
    iCrlmm++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawper>:
  endbr64
  test   %rdx,%rdx
  je     L43
  mov    %edi,%ecx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  imul   $0x64,%ecx,%eax
  cltd
  idiv   %esi
  cmp    %esi,%ecx
  je     L82
  mov    D42(%rip),%ecx
  test   %ecx,%ecx
  je     L34
  cmp    $0x1,%ecx
  je     L96
  cmp    $0x2,%ecx
  je     L103
  cmp    $0x3,%ecx
  je     L60
L42:
  add    $0x1,%ecx
  mov    %ecx,D22(%rip)
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %eax,%edx
  lea    D22(%rip),%rsi
  call   <sprintf@plt>
L53:
  mov    D22(%rip),%ecx
  cmp    $0x3,%ecx
  jne    L42
  movl   $0x0,D22(%rip)
  add    $0x8,%rsp
  ret
L43:
  ret
  nopl   0x0(%rax)
L82:
  mov    %eax,%edx
  lea    D26(%rip),%rsi
  call   <sprintf@plt>
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L96:
  mov    %eax,%edx
  lea    D29(%rip),%rsi
  call   <sprintf@plt>
  jmp    L53
L103:
  mov    %eax,%edx
  lea    D73(%rip),%rsi
  call   <sprintf@plt>
  jmp    L53
L60:
  mov    %eax,%edx
  lea    D37(%rip),%rsi
  call   <sprintf@plt>
  jmp    L53
```

tool_calls: name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D26
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D73
type: string
name: parse_data
arguments: data_tag: D37
type: string

tool: D22: [| %d%]

tool: D26: [ %d%]

tool: D29: [/ %d%]

tool: D73: [- %d%]

tool: D37: [\ %d%]

assistant: ```c
void drawper(int file_send, int file_total, char *spOut) {
  if (NULL == spOut) {
    return;
  }
  static int iCrlmm = 0;
  int iPer = file_send * 100 / file_total;
  if (file_send == file_total) {
    sprintf(spOut, "[ %d%]\r", iPer);
  } else if (iCrlmm == 0) {
    sprintf(spOut, "[| %d%]\r", iPer);
  } else if (iCrlmm == 1) {
    sprintf(spOut, "[/ %d%]\r", iPer);
  } else if (iCrlmm == 2) {
    sprintf(spOut, "[- %d%]\r", iPer);
  } else if (iCrlmm == 3) {
    sprintf(spOut, "[\\ %d%]\r", iPer);
  }
  if (iCrlmm == 3) {
    iCrlmm = 0;
  } else {
    iCrlmm++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawper>:
  endbr64
  test   %rdx,%rdx
  je     L65
  mov    %edi,%ecx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  imul   $0x64,%ecx,%eax
  cltd
  idiv   %esi
  cmp    %esi,%ecx
  je     L3
  mov    D10(%rip),%ecx
  test   %ecx,%ecx
  je     L26
  cmp    $0x1,%ecx
  je     L95
  cmp    $0x2,%ecx
  je     L106
  cmp    $0x3,%ecx
  je     L83
L61:
  add    $0x1,%ecx
  mov    %ecx,D3(%rip)
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %eax,%edx
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
L30:
  mov    D3(%rip),%ecx
  cmp    $0x3,%ecx
  jne    L61
  movl   $0x0,D3(%rip)
  add    $0x8,%rsp
  ret
L65:
  ret
  nopl   0x0(%rax)
L3:
  mov    %eax,%edx
  lea    D41(%rip),%rsi
  call   <sprintf@plt>
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L95:
  mov    %eax,%edx
  lea    D88(%rip),%rsi
  call   <sprintf@plt>
  jmp    L30
L106:
  mov    %eax,%edx
  lea    D26(%rip),%rsi
  call   <sprintf@plt>
  jmp    L30
L83:
  mov    %eax,%edx
  lea    D11(%rip),%rsi
  call   <sprintf@plt>
  jmp    L30
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string
name: parse_data
arguments: data_label: D88
data_type: string
name: parse_data
arguments: data_label: D26
data_type: string
name: parse_data
arguments: data_label: D11
data_type: string

tool: D3: [| %d%]

tool: D41: [ %d%]

tool: D88: [/ %d%]

tool: D26: [- %d%]

tool: D11: [\ %d%]

assistant: ```c
void drawper(int file_send, int file_total, char *spOut) {
  if (NULL == spOut) {
    return;
  }
  static int iCrlmm = 0;
  int iPer = file_send * 100 / file_total;
  if (file_send == file_total) {
    sprintf(spOut, "[ %d%]\r", iPer);
  } else if (iCrlmm == 0) {
    sprintf(spOut, "[| %d%]\r", iPer);
  } else if (iCrlmm == 1) {
    sprintf(spOut, "[/ %d%]\r", iPer);
  } else if (iCrlmm == 2) {
    sprintf(spOut, "[- %d%]\r", iPer);
  } else if (iCrlmm == 3) {
    sprintf(spOut, "[\\ %d%]\r", iPer);
  }
  if (iCrlmm == 3) {
    iCrlmm = 0;
  } else {
    iCrlmm++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remove_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L21
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L37
L21:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
L37:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void remove_newline(char *buffer) {
  char *p = buffer;
  while (*p != '\0') {
    if (*p == '\n') {
      *p = '\0';
      break;
    }
    p++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_newline>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
L24:
  cmp    $0xa,%al
  je     L1
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L24
L23:
  ret
L1:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *buffer) {
  char *p = buffer;
  while (*p != '\0') {
    if (*p == '\n') {
      *p = '\0';
      break;
    }
    p++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_newline>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L23:
  cmp    $0xa,%al
  je     L5
  add    $0x1,%rdi
L12:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
  ret
L5:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *buffer) {
  char *p = buffer;
  while (*p != '\0') {
    if (*p == '\n') {
      *p = '\0';
      break;
    }
    p++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_newline>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L15:
  cmp    $0xa,%al
  je     L23
  add    $0x1,%rdi
L12:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
  ret
L23:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void remove_newline(char *buffer) {
  char *p = buffer;
  while (*p != '\0') {
    if (*p == '\n') {
      *p = '\0';
      break;
    }
    p++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wrap_get_fchost_nr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_fchost_nr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L5
  cmpl   $0x10000,-0x4(%rbp)
  jle    L36
  mov    $0x10000,%eax
  jmp    L3
L36:
  mov    -0x4(%rbp),%eax
  jmp    L3
L5:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int wrap_get_fchost_nr(struct activity *a) {
  int n = 0;
  if ((n = get_fchost_nr()) > 0) {
    if (n > 65536)
      return 65536;
    else
      return n;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wrap_get_fchost_nr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_fchost_nr@plt>
  mov    $0x10000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wrap_get_fchost_nr(struct activity *a) {
  int n = 0;
  if ((n = get_fchost_nr()) > 0) {
    if (n > 65536)
      return 65536;
    else
      return n;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wrap_get_fchost_nr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_fchost_nr@plt>
  mov    $0x10000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wrap_get_fchost_nr(struct activity *a) {
  int n = 0;
  if ((n = get_fchost_nr()) > 0) {
    if (n > 65536)
      return 65536;
    else
      return n;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrap_get_fchost_nr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_fchost_nr@plt>
  mov    $0x10000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wrap_get_fchost_nr(struct activity *a) {
  int n = 0;
  if ((n = get_fchost_nr()) > 0) {
    if (n > 65536)
      return 65536;
    else
      return n;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<program_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L17
L31:
  lea    -0x30(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <naive_scanf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x58(%rbp)
  mov    -0x5c(%rbp),%ecx
  mov    -0x58(%rbp),%edx
  lea    -0x30(%rbp),%rsi
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <solve@plt>
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <naive_printf@plt>
L17:
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <naive_scanf@plt>
  cmp    $0x1,%eax
  jne    L26
  mov    -0x5c(%rbp),%eax
  test   %eax,%eax
  jne    L31
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D1
type: string

tool: D16: %s%s

tool: D13: %d


tool: D1: %d

assistant: ```c
int program_main() {
  char s1[26 + 1], s2[26 + 1];
  int m, k;
  int ans;
  while (naive_scanf("%d", &m) == 1 && m) {
    naive_scanf("%s%s", s1, s2);
    k = strlen(s1);
    ans = solve(s1, s2, k, m);
    naive_printf("%d\n", ans);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<program_main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    D21(%rip),%rbx
  lea    D22(%rip),%r13
  lea    D4(%rip),%r12
  jmp    L34
L11:
  lea    0x30(%rsp),%r15
  lea    0x10(%rsp),%r14
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <naive_scanf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    0xc(%rsp),%ecx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <solve@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <naive_printf@plt>
L34:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <naive_scanf@plt>
  cmp    $0x1,%eax
  jne    L21
  cmpl   $0x0,0xc(%rsp)
  jne    L11
L21:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
datatype: string
name: unpack_data
arguments: data_label: D22
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D21: %d

tool: D22: %s%s

tool: D4: %d


assistant: ```c
int program_main() {
  char s1[26 + 1], s2[26 + 1];
  int m, k;
  int ans;
  while (naive_scanf("%d", &m) == 1 && m) {
    naive_scanf("%s%s", s1, s2);
    k = strlen(s1);
    ans = solve(s1, s2, k, m);
    naive_printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<program_main>:
  endbr64
  push   %r15
  lea    D15(%rip),%r15
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x30(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L39
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <naive_scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <solve@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <naive_printf@plt>
L30:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <naive_scanf@plt>
  cmp    $0x1,%eax
  je     L4
L39:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D15: %s%s

tool: D9: %d


tool: D18: %d

assistant: ```c
int program_main() {
  char s1[26 + 1], s2[26 + 1];
  int m, k;
  int ans;
  while (naive_scanf("%d", &m) == 1 && m) {
    naive_scanf("%s%s", s1, s2);
    k = strlen(s1);
    ans = solve(s1, s2, k, m);
    naive_printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<program_main>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x30(%rsp),%rbp
  lea    0x10(%rsp),%rbx
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L9:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L38
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <naive_scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <solve@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <naive_printf@plt>
L31:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <naive_scanf@plt>
  cmp    $0x1,%eax
  je     L9
L38:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string

tool: D13: %s%s

tool: D15: %d


tool: D27: %d

assistant: ```c
int program_main() {
  char s1[26 + 1], s2[26 + 1];
  int m, k;
  int ans;
  while (naive_scanf("%d", &m) == 1 && m) {
    naive_scanf("%s%s", s1, s2);
    k = strlen(s1);
    ans = solve(s1, s2, k, m);
    naive_printf("%d\n", ans);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<m_conf_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L40
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L39
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L10
L37:
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
L10:
  mov    $0x1,%eax
  jmp    L17
L40:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int m_conf_string(char *ope, char *opestr, char *val, char **val_r) {
  if (strcmp(ope, opestr) == 0) {
    if (*val_r)
      free(*val_r);
    if (val[0])
      *val_r = strdup(val);
    else
      *val_r = NULL;
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<m_conf_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L3
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L41
  call   <free@plt>
L41:
  cmpb   $0x0,(%rbx)
  jne    L7
  movq   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L36
L7:
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L36
```

assistant: ```c
int m_conf_string(char *ope, char *opestr, char *val, char **val_r) {
  if (strcmp(ope, opestr) == 0) {
    if (*val_r)
      free(*val_r);
    if (val[0])
      *val_r = strdup(val);
    else
      *val_r = NULL;
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<m_conf_string>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L26
  call   <free@plt>
L26:
  cmpb   $0x0,0x0(%rbp)
  jne    L15
  movq   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int m_conf_string(char *ope, char *opestr, char *val, char **val_r) {
  if (strcmp(ope, opestr) == 0) {
    if (*val_r)
      free(*val_r);
    if (val[0])
      *val_r = strdup(val);
    else
      *val_r = NULL;
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_conf_string>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L7
  call   <free@plt>
L7:
  cmpb   $0x0,0x0(%rbp)
  jne    L2
  movq   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int m_conf_string(char *ope, char *opestr, char *val, char **val_r) {
  if (strcmp(ope, opestr) == 0) {
    if (*val_r)
      free(*val_r);
    if (val[0])
      *val_r = strdup(val);
    else
      *val_r = NULL;
    return 1;
  }
  return 0;
}
```