ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mc_chroma_altivec>:
  endbr64
  mov    0x8(%rsp),%eax
  mov    0x10(%rsp),%r10d
  mov    %r10d,0x8(%rsp)
  cmp    $0x8,%eax
  je     L19
  cmp    $0x4,%eax
  je     L15
  jmp    1070 <mc_chroma_2xh@plt>
  nopl   0x0(%rax)
L15:
  jmp    1080 <mc_chroma_altivec_4xh@plt>
  nopl   (%rax)
L19:
  jmp    1090 <mc_chroma_altivec_8xh@plt>
```

assistant: ```c
void mc_chroma_altivec(uint8_t *dst, int i_dst_stride, uint8_t *src, int i_src_stride, int mvx, int mvy, int i_width, int i_height) {
  if (i_width == 8)
    mc_chroma_altivec_8xh(dst, i_dst_stride, src, i_src_stride, mvx, mvy, i_height);
  else if (i_width == 4)
    mc_chroma_altivec_4xh(dst, i_dst_stride, src, i_src_stride, mvx, mvy, i_height);
  else
    mc_chroma_2xh(dst, i_dst_stride, src, i_src_stride, mvx, mvy, i_height);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <print_one@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <print_two@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <print_three@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D31
data_type: string
name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D26: ONE


tool: D31: TWO


tool: D18: THREE


tool: D11: CALYPSO running ... bye!


assistant: ```c
int main(int argc, char *argv[]) {
  print_one("ONE\n");
  print_two("TWO\n");
  print_three("THREE\n");
  printf("CALYPSO running ... bye!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <print_one@plt>
  lea    D20(%rip),%rdi
  call   <print_two@plt>
  lea    D8(%rip),%rdi
  call   <print_three@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string
name: unpack_data
arguments: data_label: D20
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string

tool: D2: ONE


tool: D20: TWO


tool: D8: THREE


tool: D10: CALYPSO running ... bye!


assistant: ```c
int main(int argc, char *argv[]) {
  print_one("ONE\n");
  print_two("TWO\n");
  print_three("THREE\n");
  printf("CALYPSO running ... bye!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <print_one@plt>
  lea    D0(%rip),%rdi
  call   <print_two@plt>
  lea    D11(%rip),%rdi
  call   <print_three@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D5: ONE


tool: D0: TWO


tool: D11: THREE


tool: D16: CALYPSO running ... bye!


assistant: ```c
int main(int argc, char *argv[]) {
  print_one("ONE\n");
  print_two("TWO\n");
  print_three("THREE\n");
  printf("CALYPSO running ... bye!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <print_one@plt>
  lea    D13(%rip),%rdi
  call   <print_two@plt>
  lea    D37(%rip),%rdi
  call   <print_three@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D37
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string

tool: D11: ONE


tool: D13: TWO


tool: D37: THREE


tool: D36: CALYPSO running ... bye!


assistant: ```c
int main(int argc, char *argv[]) {
  print_one("ONE\n");
  print_two("TWO\n");
  print_three("THREE\n");
  printf("CALYPSO running ... bye!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L30
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L30
  lea    D26(%rip),%rax
  jmp    L8
L30:
  lea    D29(%rip),%rax
L8:
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string

tool: D19: %d %d %d

tool: D26: First

tool: D29: Second

tool: D7: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, win = 1;
  scanf("%d %d %d", &a, &b, &c);
  c += c;
  printf("%s", a >= c && b >= c ? "First" : "Second");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  add    %eax,%eax
  mov    %eax,0x14(%rsp)
  lea    D20(%rip),%rsi
  cmp    0xc(%rsp),%eax
  jg     L6
  cmp    0x10(%rsp),%eax
  lea    D25(%rip),%rax
  cmovle %rax,%rsi
L6:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
type: string
name: extract_symbolic_data
arguments: label: D20
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D30
type: string

tool: D35: %d %d %d

tool: D20: Second

tool: D25: First

tool: D30: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, win = 1;
  scanf("%d %d %d", &a, &b, &c);
  c += c;
  printf("%s", a >= c && b >= c ? "First" : "Second");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    D15(%rip),%rsi
  add    %eax,%eax
  mov    %eax,0x14(%rsp)
  cmp    0xc(%rsp),%eax
  jg     L17
  cmp    0x10(%rsp),%eax
  lea    D0(%rip),%rax
  cmovle %rax,%rsi
L17:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D38
type_guessed: string

tool: D17: %d %d %d

tool: D15: Second

tool: D0: First

tool: D38: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, win = 1;
  scanf("%d %d %d", &a, &b, &c);
  c += c;
  printf("%s", a >= c && b >= c ? "First" : "Second");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    D28(%rip),%rsi
  add    %eax,%eax
  mov    %eax,0x14(%rsp)
  cmp    0xc(%rsp),%eax
  jg     L15
  cmp    0x10(%rsp),%eax
  lea    D11(%rip),%rax
  cmovle %rax,%rsi
L15:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_infered: string
name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D37
type_infered: string

tool: D19: %d %d %d

tool: D28: Second

tool: D11: First

tool: D37: %s

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b, c, win = 1;
  scanf("%d %d %d", &a, &b, &c);
  c += c;
  printf("%s", a >= c && b >= c ? "First" : "Second");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct Foo {
    int a;
  } foo;
  struct Foo bar;
  foo.a = 1;
  bar.a = 2;
  assert(foo.a == 1);
  assert(bar.a == 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct Foo {
    int a;
  } foo;
  struct Foo bar;
  foo.a = 1;
  bar.a = 2;
  assert(foo.a == 1);
  assert(bar.a == 2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct Foo {
    int a;
  } foo;
  struct Foo bar;
  foo.a = 1;
  bar.a = 2;
  assert(foo.a == 1);
  assert(bar.a == 2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct Foo {
    int a;
  } foo;
  struct Foo bar;
  foo.a = 1;
  bar.a = 2;
  assert(foo.a == 1);
  assert(bar.a == 2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0xf,-0x4(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: %i	%llu


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 15; i++)
    printf("%i\t%llu\n", i, fact(i));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L8:
  mov    %ebx,%edi
  call   <fact@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L8
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: %i	%llu


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 15; i++)
    printf("%i\t%llu\n", i, fact(i));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <fact@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: %i	%llu


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 15; i++)
    printf("%i\t%llu\n", i, fact(i));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <fact@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x10,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: %i	%llu


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 15; i++)
    printf("%i\t%llu\n", i, fact(i));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gwtSignalHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <gwtWriteSignal@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L16
  mov    $0x0,%eax
  call   <gwtResetLineState@plt>
  jmp    L2
L16:
  mov    $0x0,%eax
  call   <gwtCleanupAfterSignal@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void gwtSignalHandler(int sig) {
  gwtWriteSignal(sig);
  if (sig == SIGINT)
    gwtResetLineState();
  else
    gwtCleanupAfterSignal();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gwtSignalHandler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <gwtWriteSignal@plt>
  mov    D9(%rip),%rax
  cmp    %ebx,(%rax)
  je     L7
  mov    $0x0,%eax
  call   <gwtCleanupAfterSignal@plt>
L15:
  pop    %rbx
  ret
L7:
  mov    $0x0,%eax
  call   <gwtResetLineState@plt>
  jmp    L15
```

assistant: ```c
void gwtSignalHandler(int sig) {
  gwtWriteSignal(sig);
  if (sig == SIGINT)
    gwtResetLineState();
  else
    gwtCleanupAfterSignal();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gwtSignalHandler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <gwtWriteSignal@plt>
  mov    D3(%rip),%rax
  cmp    %ebx,(%rax)
  mov    $0x0,%eax
  je     L5
  pop    %rbx
  jmp    1090 <gwtCleanupAfterSignal@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  pop    %rbx
  jmp    1080 <gwtResetLineState@plt>
```

assistant: ```c
void gwtSignalHandler(int sig) {
  gwtWriteSignal(sig);
  if (sig == SIGINT)
    gwtResetLineState();
  else
    gwtCleanupAfterSignal();
}
```
user: What is the c source code of the assembly code below:

```asm
<gwtSignalHandler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <gwtWriteSignal@plt>
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  mov    $0x0,%eax
  je     L9
  pop    %rbx
  jmp    1090 <gwtCleanupAfterSignal@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  pop    %rbx
  jmp    1080 <gwtResetLineState@plt>
```

assistant: ```c
void gwtSignalHandler(int sig) {
  gwtWriteSignal(sig);
  if (sig == SIGINT)
    gwtResetLineState();
  else
    gwtCleanupAfterSignal();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lecture_boutons>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x379,%edi
  call   <inb@plt>
  xor    $0x70,%eax
  and    $0xfffffff0,%eax
  mov    %al,-0x5(%rbp)
  movl   $0x2020202,-0x4(%rbp)
  movsbl -0x5(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L38
  orl    $0x1,-0x4(%rbp)
L38:
  movsbl -0x5(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L21
  orl    $0x100,-0x4(%rbp)
L21:
  cmpb   $0x0,-0x5(%rbp)
  jns    L17
  orl    $0x10000,-0x4(%rbp)
L17:
  movsbl -0x5(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L15
  orl    $0x1000000,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void lecture_boutons(char boutons[4]) {
  char t = (inb(0x379) ^ 0x70) & 0xF0;
  unsigned int u = (2) | ((2) << 8) | ((2) << 16) | ((2) << 24);
  if (t & 0x10)
    u |= 1;
  if (t & 0x20)
    u |= 1 << 8;
  if (t & 0x80)
    u |= 1 << 16;
  if (t & 0x40)
    u |= 1 << 24;
  *(int *)boutons = u;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lecture_boutons>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x379,%edi
  call   <inb@plt>
  test   $0x10,%al
  sete   %dl
  movzbl %dl,%edx
  add    $0x2020202,%edx
  mov    %edx,%ecx
  or     $0x1,%ch
  test   $0x20,%al
  cmove  %ecx,%edx
  mov    %edx,%ecx
  or     $0x10000,%ecx
  xor    $0x70,%al
  cmovs  %ecx,%edx
  mov    %edx,%ecx
  or     $0x1000000,%ecx
  test   $0x40,%al
  cmovne %ecx,%edx
  mov    %edx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lecture_boutons(char boutons[4]) {
  char t = (inb(0x379) ^ 0x70) & 0xF0;
  unsigned int u = (2) | ((2) << 8) | ((2) << 16) | ((2) << 24);
  if (t & 0x10)
    u |= 1;
  if (t & 0x20)
    u |= 1 << 8;
  if (t & 0x80)
    u |= 1 << 16;
  if (t & 0x40)
    u |= 1 << 24;
  *(int *)boutons = u;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lecture_boutons>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x379,%edi
  call   <inb@plt>
  xor    %edx,%edx
  test   $0x10,%al
  sete   %dl
  add    $0x2020202,%edx
  mov    %edx,%ecx
  or     $0x1,%ch
  test   $0x20,%al
  cmove  %ecx,%edx
  mov    %edx,%ecx
  or     $0x10000,%ecx
  xor    $0x70,%al
  cmovs  %ecx,%edx
  mov    %edx,%ecx
  or     $0x1000000,%ecx
  test   $0x40,%al
  cmovne %ecx,%edx
  mov    %edx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lecture_boutons(char boutons[4]) {
  char t = (inb(0x379) ^ 0x70) & 0xF0;
  unsigned int u = (2) | ((2) << 8) | ((2) << 16) | ((2) << 24);
  if (t & 0x10)
    u |= 1;
  if (t & 0x20)
    u |= 1 << 8;
  if (t & 0x80)
    u |= 1 << 16;
  if (t & 0x40)
    u |= 1 << 24;
  *(int *)boutons = u;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lecture_boutons>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x379,%edi
  call   <inb@plt>
  xor    $0x70,%eax
  mov    %eax,%ecx
  and    $0x10,%ecx
  cmp    $0x1,%cl
  sbb    %edx,%edx
  add    $0x2020303,%edx
  cmp    $0x1,%cl
  sbb    %ecx,%ecx
  add    $0x2020203,%ecx
  test   $0x20,%al
  cmove  %ecx,%edx
  mov    %edx,%ecx
  or     $0x10000,%ecx
  test   %al,%al
  cmovs  %ecx,%edx
  mov    %edx,%ecx
  or     $0x1000000,%ecx
  test   $0x40,%al
  cmovne %ecx,%edx
  mov    %edx,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void lecture_boutons(char boutons[4]) {
  char t = (inb(0x379) ^ 0x70) & 0xF0;
  unsigned int u = (2) | ((2) << 8) | ((2) << 16) | ((2) << 24);
  if (t & 0x10)
    u |= 1;
  if (t & 0x20)
    u |= 1 << 8;
  if (t & 0x80)
    u |= 1 << 16;
  if (t & 0x40)
    u |= 1 << 24;
  *(int *)boutons = u;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x3,-0x24(%rbp)
  je     L0
  mov    $0x0,%eax
  call   <displayUsage@plt>
  mov    $0xffffffff,%eax
  jmp    L73
L0:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x20(%rbp),%rdx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rdx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movsd  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L51
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  je     L44
L51:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L74
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L74
L44:
  mov    $0x0,%eax
  call   <displayUsage@plt>
  mov    $0xfffffffe,%eax
  jmp    L73
L74:
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <milesToMinutes@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L73:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D28
datatype: string

tool: D6: %lf

tool: D28: %.1f


assistant: ```c
int main(int numArgs, char *args[]) {
  if (numArgs != 3) {
    displayUsage();
    return -1;
  }
  double miles = 0;
  double mph = 0;
  sscanf(args[1], "%lf", &miles);
  sscanf(args[2], "%lf", &mph);
  if (miles == 0 || mph == 0) {
    displayUsage();
    return -2;
  }
  double minutes = milesToMinutes(miles, mph);
  printf("%.1f\n", minutes);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L62
  mov    %rsi,%rbx
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D21(%rip),%rbp
  mov    %rbp,%rsi
  call   <sscanf@plt>
  lea    0x10(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  mov    %rbp,%rsi
  call   <sscanf@plt>
  movsd  0x8(%rsp),%xmm0
  ucomisd D0(%rip),%xmm0
  jp     L11
  je     L66
L11:
  movsd  0x10(%rsp),%xmm1
  ucomisd D0(%rip),%xmm1
  jp     L70
  je     L66
L70:
  call   <milesToMinutes@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L52:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  call   <displayUsage@plt>
  mov    $0xffffffff,%eax
  jmp    L52
L66:
  mov    $0x0,%eax
  call   <displayUsage@plt>
  mov    $0xfffffffe,%eax
  jmp    L52
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: f64
name: retrieve_data
arguments: data_tag: D25
type_guessed: string

tool: D21: %lf

tool: D0: 0

tool: D25: %.1f


assistant: ```c
int main(int numArgs, char *args[]) {
  if (numArgs != 3) {
    displayUsage();
    return -1;
  }
  double miles = 0;
  double mph = 0;
  sscanf(args[1], "%lf", &miles);
  sscanf(args[2], "%lf", &mph);
  if (miles == 0 || mph == 0) {
    displayUsage();
    return -2;
  }
  double minutes = milesToMinutes(miles, mph);
  printf("%.1f\n", minutes);
  return 0;
}
```