ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_buffer_diff_float>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  call   <diff_buffer_float@plt>
  ucomiss D22(%rip),%xmm0
  jp     L14
  jne    L14
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  pop    %rbp
  cvtss2sd %xmm0,%xmm0
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type: f32
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D22: 0

tool: D27: %s PASSED


tool: D6: 

ERROR in %s: diff = %f



assistant: ```c
void test_buffer_diff_float(int size, float *a, float *b, char *test_name) {
  float diff = diff_buffer_float(size, a, b);
  if (diff != 0.0) {
    printf("\n\nERROR in %s: diff = %f\n\n", test_name, diff);
  } else {
    printf("%s PASSED\n", test_name);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<test_buffer_diff_float>:
  endbr64
  push   %rbp
  mov    %rcx,%rbp
  call   <diff_buffer_float@plt>
  ucomiss D6(%rip),%xmm0
  jp     L16
  jne    L16
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  pop    %rbp
  cvtss2sd %xmm0,%xmm0
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type: f32
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D6: 0

tool: D8: %s PASSED


tool: D3: 

ERROR in %s: diff = %f



assistant: ```c
void test_buffer_diff_float(int size, float *a, float *b, char *test_name) {
  float diff = diff_buffer_float(size, a, b);
  if (diff != 0.0) {
    printf("\n\nERROR in %s: diff = %f\n\n", test_name, diff);
  } else {
    printf("%s PASSED\n", test_name);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computeVariables>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movsd  D29(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  D5(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  movsd  D27(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  addsd  -0x28(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type_infered: f64
name: retrieve_data
arguments: tag: D5
type_infered: f64
name: retrieve_data
arguments: tag: D27
type_infered: f64

tool: D29: 5

tool: D5: 3

tool: D27: 2

assistant: ```c
void computeVariables(double voi, double *states, double *rates, double *variables) {
  variables[0] = states[1] + 5.0 * states[1] / 3.0 + 1.0 * exp(states[1] / 2.0);
  variables[1] = 2.0 * states[0];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<computeVariables>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    0x8(%rdi),%r12
  movq   %r12,%xmm0
  mulsd  D25(%rip),%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movq   %r12,%xmm0
  mulsd  D14(%rip),%xmm0
  divsd  D16(%rip),%xmm0
  movq   %r12,%xmm2
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  movsd  0x0(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D25
type_guessed: byte[8]
name: read_data
arguments: tag: D14
type_guessed: f64
name: read_data
arguments: tag: D16
type_guessed: f64

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D14: 5

tool: D16: 3

assistant: ```c
void computeVariables(double voi, double *states, double *rates, double *variables) {
  variables[0] = states[1] + 5.0 * states[1] / 3.0 + 1.0 * exp(states[1] / 2.0);
  variables[1] = 2.0 * states[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeVariables>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movsd  0x8(%rdi),%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  D1(%rip),%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  D23(%rip),%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx)
  movsd  0x0(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: byte[8]
name: parse_data
arguments: data_label: D18
data_type: f64
name: parse_data
arguments: data_label: D23
data_type: f64

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D18: 5

tool: D23: 3

assistant: ```c
void computeVariables(double voi, double *states, double *rates, double *variables) {
  variables[0] = states[1] + 5.0 * states[1] / 3.0 + 1.0 * exp(states[1] / 2.0);
  variables[1] = 2.0 * states[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<computeVariables>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movsd  0x8(%rdi),%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  D20(%rip),%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  D24(%rip),%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rbx)
  movsd  0x0(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type: byte[8]
name: retrieve_data
arguments: data_label: D0
type: f64
name: retrieve_data
arguments: data_label: D24
type: f64

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D0: 5

tool: D24: 3

assistant: ```c
void computeVariables(double voi, double *states, double *rates, double *variables) {
  variables[0] = states[1] + 5.0 * states[1] / 3.0 + 1.0 * exp(states[1] / 2.0);
  variables[1] = 2.0 * states[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fillMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %edx,%rax
  mov    %rax,%rcx
  mov    $0x0,%ebx
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L21:
  movl   $0x0,-0x20(%rbp)
  jmp    L4
L32:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  movslq %edx,%rax
  imul   %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rax,%rcx
  add    %edi,%esi
  mov    -0x20(%rbp),%eax
  cltq
  mov    %esi,(%rcx,%rax,4)
  addl   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fillMatrix(int n, int matrix[n][n]) {
  int col, row;
  for (row = 0; row < n; ++row) {
    for (col = 0; col < n; ++col) {
      matrix[row][col] = 10 * (row + 1) + (col + 1);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fillMatrix>:
  endbr64
  movslq %edi,%r8
  test   %edi,%edi
  jle    L10
  shl    $0x2,%r8
  lea    0xb(%rdi),%ecx
  add    $0x1,%edi
  lea    (%rdi,%rdi,4),%eax
  lea    (%rdi,%rax,2),%r9d
  mov    $0xb,%edi
L6:
  mov    %rsi,%rdx
  mov    %edi,%eax
L1:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L1
  add    $0xa,%edi
  add    %r8,%rsi
  add    $0xa,%ecx
  cmp    %r9d,%ecx
  jne    L6
L10:
  ret
```

assistant: ```c
void fillMatrix(int n, int matrix[n][n]) {
  int col, row;
  for (row = 0; row < n; ++row) {
    for (col = 0; col < n; ++col) {
      matrix[row][col] = 10 * (row + 1) + (col + 1);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fillMatrix>:
  endbr64
  movslq %edi,%r8
  test   %edi,%edi
  jle    L5
  lea    0xb(%rdi),%ecx
  add    $0x1,%edi
  shl    $0x2,%r8
  lea    (%rdi,%rdi,4),%eax
  lea    (%rdi,%rax,2),%r9d
  mov    $0xb,%edi
  nopl   0x0(%rax)
L23:
  mov    %rsi,%rdx
  mov    %edi,%eax
  nopl   (%rax)
L28:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L28
  add    $0xa,%ecx
  add    $0xa,%edi
  add    %r8,%rsi
  cmp    %r9d,%ecx
  jne    L23
L5:
  ret
```

assistant: ```c
void fillMatrix(int n, int matrix[n][n]) {
  int col, row;
  for (row = 0; row < n; ++row) {
    for (col = 0; col < n; ++col) {
      matrix[row][col] = 10 * (row + 1) + (col + 1);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fillMatrix>:
  endbr64
  test   %edi,%edi
  jle    L52
  mov    %edi,%eax
  push   %r12
  mov    %edi,%r9d
  movdqa D17(%rip),%xmm4
  shr    $0x2,%eax
  push   %rbp
  movdqa D21(%rip),%xmm3
  lea    0x5(%rdi,%rdi,4),%ebp
  lea    -0x1(%rax),%r11d
  push   %rbx
  movslq %edi,%rbx
  add    %ebp,%ebp
  add    $0x1,%r11
  shl    $0x2,%rbx
  lea    -0x1(%rdi),%r12d
  and    $0xfffffffc,%r9d
  mov    $0xa,%ecx
  shl    $0x4,%r11
  xchg   %ax,%ax
L31:
  cmp    $0x2,%r12d
  jbe    L77
  movd   %ecx,%xmm5
  movdqa D11(%rip),%xmm1
  lea    (%r11,%rsi,1),%rdx
  mov    %rsi,%rax
  pshufd $0x0,%xmm5,%xmm2
  nopw   0x0(%rax,%rax,1)
L57:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm4,%xmm1
  paddd  %xmm3,%xmm0
  paddd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L57
  mov    %r9d,%eax
  cmp    %edi,%r9d
  je     L30
L34:
  lea    0x1(%rax),%r8d
  movslq %eax,%rdx
  lea    (%rsi,%rdx,4),%rdx
  lea    (%rcx,%r8,1),%r10d
  mov    %r10d,(%rdx)
  cmp    %edi,%r8d
  jge    L30
  lea    0x2(%rax),%r8d
  lea    (%rcx,%r8,1),%r10d
  mov    %r10d,0x4(%rdx)
  cmp    %r8d,%edi
  jle    L30
  lea    0x3(%rax,%rcx,1),%eax
  mov    %eax,0x8(%rdx)
L30:
  add    $0xa,%ecx
  add    %rbx,%rsi
  cmp    %ebp,%ecx
  jne    L31
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L77:
  xor    %eax,%eax
  jmp    L34
L52:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: byte[16]
name: read_data
arguments: data_tag: D21
type: byte[16]
name: read_data
arguments: data_tag: D11
type: byte[16]

tool: {"D17": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D21": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
void fillMatrix(int n, int matrix[n][n]) {
  int col, row;
  for (row = 0; row < n; ++row) {
    for (col = 0; col < n; ++col) {
      matrix[row][col] = 10 * (row + 1) + (col + 1);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L17:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x9,-0x34(%rbp)
  jle    L17
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <avg@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D2: Please enter 10 numbers: 

tool: D26: %f

tool: D10: Average is: %.3f


assistant: ```c
int main() {
  float nums[10];
  printf("Please enter 10 numbers: ");
  for (int i = 0; i < 10; i++) {
    scanf("%f", &nums[i]);
  }
  printf("Average is: %.3f\n", avg(nums));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D16(%rip),%rbp
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    %rsp,%rdi
  call   <avg@plt>
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string

tool: D17: Please enter 10 numbers: 

tool: D16: %f

tool: D10: Average is: %.3f


assistant: ```c
int main() {
  float nums[10];
  printf("Please enter 10 numbers: ");
  for (int i = 0; i < 10; i++) {
    scanf("%f", &nums[i]);
  }
  printf("Average is: %.3f\n", avg(nums));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x28(%rsp),%r12
  mov    %r13,%rbx
  call   <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    %r13,%rdi
  call   <avg@plt>
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string

tool: D24: Please enter 10 numbers: 

tool: D27: %f

tool: D21: Average is: %.3f


assistant: ```c
int main() {
  float nums[10];
  printf("Please enter 10 numbers: ");
  for (int i = 0; i < 10; i++) {
    scanf("%f", &nums[i]);
  }
  printf("Average is: %.3f\n", avg(nums));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x28(%rsp),%r12
  mov    %r13,%rbx
  call   <printf@plt>
  nopl   0x0(%rax)
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L16
  mov    %r13,%rdi
  call   <avg@plt>
  lea    D22(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D22
type: string

tool: D13: Please enter 10 numbers: 

tool: D12: %f

tool: D22: Average is: %.3f


assistant: ```c
int main() {
  float nums[10];
  printf("Please enter 10 numbers: ");
  for (int i = 0; i < 10; i++) {
    scanf("%f", &nums[i]);
  }
  printf("Average is: %.3f\n", avg(nums));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<verify_binary_clauses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L61
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    $0x1,%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jne    L66
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L66
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    $0x1,%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,%edx
  je     L25
L66:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L73
L61:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    $0x1,%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,%edx
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L22
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    $0x1,%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,%edx
  je     L25
L22:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L73
L25:
  mov    $0x1,%eax
L73:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: string

tool: D11: problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  int nb = 0;
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("problem..");
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("problem..");
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<verify_binary_clauses>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %edx,%edi
  mov    (%rax),%edx
  cmp    %esi,%edx
  je     L47
  cmp    %ecx,%edx
  jne    L11
  mov    $0x1,%edx
  sub    %r8d,%edx
  cmp    %edx,0x4(%rax)
  jne    L11
  cmp    %esi,0x8(%rax)
  jne    L11
  mov    $0x1,%ecx
  sub    %edi,%ecx
  mov    $0x1,%edx
  cmp    %ecx,0xc(%rax)
  je     L42
L11:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
L42:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L47:
  mov    $0x1,%edx
  sub    %edi,%edx
  cmp    %edx,0x4(%rax)
  jne    L86
  cmp    %ecx,0x8(%rax)
  jne    L86
  mov    $0x1,%ecx
  sub    %r8d,%ecx
  mov    $0x1,%edx
  cmp    %ecx,0xc(%rax)
  je     L42
L86:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  jmp    L42
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D18: problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  int nb = 0;
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("problem..");
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("problem..");
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<verify_binary_clauses>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edi
  cmp    %esi,%edi
  je     L87
  cmp    %ecx,%edi
  jne    L47
  mov    $0x1,%ecx
  mov    %ecx,%edi
  sub    %r8d,%edi
  cmp    %edi,0x4(%rax)
  jne    L47
  cmp    %esi,0x8(%rax)
  jne    L47
  sub    %edx,%ecx
  cmp    %ecx,0xc(%rax)
  jne    L47
  mov    $0x1,%r8d
  jmp    L20
  nopl   0x0(%rax)
L87:
  mov    $0x1,%esi
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,0x4(%rax)
  jne    L47
  cmp    %ecx,0x8(%rax)
  je     L37
L47:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    %esi,0xc(%rax)
  jne    L47
L20:
  mov    %r8d,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  int nb = 0;
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("problem..");
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("problem..");
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<verify_binary_clauses>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edi
  cmp    %esi,%edi
  je     L5
  cmp    %ecx,%edi
  jne    L20
  mov    $0x1,%ecx
  mov    %ecx,%edi
  sub    %r8d,%edi
  cmp    %edi,0x4(%rax)
  jne    L20
  cmp    %esi,0x8(%rax)
  jne    L20
  sub    %edx,%ecx
  cmp    %ecx,0xc(%rax)
  jne    L20
  mov    $0x1,%r8d
  jmp    L54
  nopl   0x0(%rax)
L5:
  mov    $0x1,%esi
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,0x4(%rax)
  jne    L20
  cmp    %ecx,0x8(%rax)
  je     L17
L20:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  sub    %r8d,%esi
  mov    $0x1,%r8d
  cmp    %esi,0xc(%rax)
  jne    L20
L54:
  mov    %r8d,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: problem..

assistant: ```c
int verify_binary_clauses(int *varssigns, int var1, int sign1, int var2, int sign2) {
  int nb = 0;
  if (var1 == *varssigns) {
    if ((*(varssigns + 1) != 1 - sign1) || (var2 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign2)) {
      printf("problem..");
      return 0;
    }
  } else {
    if ((var2 != *varssigns) || (*(varssigns + 1) != 1 - sign2) || (var1 != *(varssigns + 2)) || (*(varssigns + 3) != 1 - sign1)) {
      printf("problem..");
      return 0;
    }
  }
  return 1;
}
```