ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<exponential_io>:
  endbr64
  pxor   %xmm5,%xmm5
  ucomiss %xmm5,%xmm0
  jp     L42
  je     L43
L42:
  ucomiss %xmm0,%xmm1
  jp     L29
  je     L6
L29:
  movss  D17(%rip),%xmm3
  movaps %xmm0,%xmm4
  mulss  %xmm3,%xmm1
  mulss  %xmm3,%xmm2
  movss  D3(%rip),%xmm3
  divss  %xmm1,%xmm4
  comiss %xmm4,%xmm3
  ja     L2
  subss  %xmm1,%xmm0
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  divss  %xmm1,%xmm0
  subss  %xmm0,%xmm3
  movaps %xmm2,%xmm0
  cvttss2si %xmm3,%edi
  call   <powf@plt>
  movss  0xc(%rsp),%xmm2
  add    $0x18,%rsp
  addss  %xmm2,%xmm2
  subss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L43:
  pxor   %xmm0,%xmm0
  ret
  nopl   (%rax)
L2:
  cvttss2si %xmm4,%edi
  movaps %xmm2,%xmm0
  jmp    1050 <powf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: byte[4]
name: unpack_data
arguments: data_label: D3
type_infered: byte[4]

tool: {"D17": [0x00,0x00,0x00,0x3f]}

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float exponential_io(float step, float max_steps, float max_val) {
  float ratio = ((float)step / (max_steps / 2));
  if (step == 0)
    return 0;
  if (step == max_steps)
    return max_val;
  if (ratio < 1)
    return powf((float)max_val / 2, (float)step / (max_steps / 2));
  return max_val / 2 + max_val / 2 - powf(max_val / 2, 1 - ((float)step - (max_steps / 2)) / (max_steps / 2));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<HasDisp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L84
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L84
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L103
L98:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x28,%eax
  je     L11
  cmp    $0x29,%eax
  je     L108
  jmp    L62
L11:
  subl   $0x1,-0xc(%rbp)
  jmp    L62
L108:
  addl   $0x1,-0xc(%rbp)
  nop
L62:
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L103
  subq   $0x1,-0x8(%rbp)
L103:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L3
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L98
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x514,%edi
  call   <WrXError@plt>
  mov    $0x0,%eax
  jmp    L105
L84:
  movq   $0x0,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
L105:
  leave
  ret
```

assistant: ```c
char *HasDisp(char *Asc) {
  char *p;
  int Lev;
  if ((*Asc) && (Asc[strlen(Asc) - 1] == ')')) {
    p = Asc + strlen(Asc) - 2;
    Lev = 0;
    while ((p >= Asc) && (Lev != -1)) {
      switch (*p) {
      case '(':
        Lev--;
        break;
      case ')':
        Lev++;
        break;
      }
      if (Lev != -1)
        p--;
    }
    if (p < Asc) {
      WrXError(1300, Asc);
      return NULL;
    }
  } else
    p = NULL;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HasDisp>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L38
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    $0x0,%eax
  cmpb   $0x29,-0x1(%rbx,%rdx,1)
  je     L20
L64:
  pop    %rbx
  ret
L20:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  ja     L26
  mov    $0x0,%edx
  jmp    L83
L90:
  sub    $0x1,%edx
  jmp    L65
L9:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  ja     L26
L83:
  movzbl (%rax),%ecx
  cmp    $0x28,%cl
  je     L90
  cmp    $0x29,%cl
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
L65:
  cmp    $0xffffffff,%edx
  jne    L9
  cmp    %rax,%rbx
  jbe    L64
L26:
  mov    %rbx,%rsi
  mov    $0x514,%edi
  call   <WrXError@plt>
  mov    $0x0,%eax
  jmp    L64
L38:
  ret
```

assistant: ```c
char *HasDisp(char *Asc) {
  char *p;
  int Lev;
  if ((*Asc) && (Asc[strlen(Asc) - 1] == ')')) {
    p = Asc + strlen(Asc) - 2;
    Lev = 0;
    while ((p >= Asc) && (Lev != -1)) {
      switch (*p) {
      case '(':
        Lev--;
        break;
      case ')':
        Lev++;
        break;
      }
      if (Lev != -1)
        p--;
    }
    if (p < Asc) {
      WrXError(1300, Asc);
      return NULL;
    }
  } else
    p = NULL;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HasDisp>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L83
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x29,-0x1(%rbp,%rax,1)
  je     L31
L38:
  xor    %r8d,%r8d
L78:
  mov    %r8,%rax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rbp,%rax,1),%r8
  xor    %eax,%eax
L60:
  cmp    %r8,%rbp
  setbe  %dl
  cmp    $0xffffffff,%eax
  je     L39
  test   %dl,%dl
  je     L39
  movzbl (%r8),%edx
  cmp    $0x28,%dl
  je     L49
  cmp    $0x29,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
L80:
  sub    $0x1,%r8
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L49:
  sub    $0x1,%eax
  jae    L80
L39:
  cmp    %r8,%rbp
  jbe    L78
  mov    %rbp,%rsi
  mov    $0x514,%edi
  call   <WrXError@plt>
  jmp    L38
  nopl   0x0(%rax)
L83:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *HasDisp(char *Asc) {
  char *p;
  int Lev;
  if ((*Asc) && (Asc[strlen(Asc) - 1] == ')')) {
    p = Asc + strlen(Asc) - 2;
    Lev = 0;
    while ((p >= Asc) && (Lev != -1)) {
      switch (*p) {
      case '(':
        Lev--;
        break;
      case ')':
        Lev++;
        break;
      }
      if (Lev != -1)
        p--;
    }
    if (p < Asc) {
      WrXError(1300, Asc);
      return NULL;
    }
  } else
    p = NULL;
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<HasDisp>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L44
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  cmpb   $0x29,-0x1(%rbp,%rax,1)
  je     L16
L38:
  xor    %r8d,%r8d
L2:
  mov    %r8,%rax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x2(%rbp,%rax,1),%r8
  xor    %eax,%eax
L85:
  cmp    %r8,%rbp
  setbe  %dl
  cmp    $0xffffffff,%eax
  je     L72
  test   %dl,%dl
  je     L72
  movzbl (%r8),%edx
  cmp    $0x28,%dl
  je     L4
  cmp    $0x29,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
L24:
  sub    $0x1,%r8
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%eax
  jae    L24
L72:
  cmp    %r8,%rbp
  jbe    L2
  mov    %rbp,%rsi
  mov    $0x514,%edi
  call   <WrXError@plt>
  jmp    L38
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *HasDisp(char *Asc) {
  char *p;
  int Lev;
  if ((*Asc) && (Asc[strlen(Asc) - 1] == ')')) {
    p = Asc + strlen(Asc) - 2;
    Lev = 0;
    while ((p >= Asc) && (Lev != -1)) {
      switch (*p) {
      case '(':
        Lev--;
        break;
      case ')':
        Lev++;
        break;
      }
      if (Lev != -1)
        p--;
    }
    if (p < Asc) {
      WrXError(1300, Asc);
      return NULL;
    }
  } else
    p = NULL;
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L27
L29:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x18(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  int p[2];
  char buffer[10];
  int nbc;
  pipe(p);
  if (fork() == 0) {
    close(p[1]);
    dup2(p[0], 0);
    nbc = read(0, buffer, 10);
    write(1, buffer, nbc);
    exit(0);
  } else {
    close(p[0]);
    dup2(p[1], 1);
    printf("%d\n", getpid());
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <pipe@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L11
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%esi
  mov    0x4(%rsp),%edi
  call   <dup2@plt>
  lea    0xe(%rsp),%rbx
  mov    $0xa,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  mov    0x4(%rsp),%edi
  call   <close@plt>
  mov    $0x1,%esi
  mov    0x8(%rsp),%edi
  call   <dup2@plt>
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  int p[2];
  char buffer[10];
  int nbc;
  pipe(p);
  if (fork() == 0) {
    close(p[1]);
    dup2(p[0], 0);
    nbc = read(0, buffer, 10);
    write(1, buffer, nbc);
    exit(0);
  } else {
    close(p[0]);
    dup2(p[1], 1);
    printf("%d\n", getpid());
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <pipe@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L25
  mov    0x8(%rsp),%edi
  lea    0xe(%rsp),%rbp
  call   <close@plt>
  mov    0x4(%rsp),%edi
  xor    %esi,%esi
  call   <dup2@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    $0x1,%edi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <write@plt>
  xor    %edi,%edi
  call   <exit@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L25:
  mov    0x4(%rsp),%edi
  call   <close@plt>
  mov    0x8(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L0
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main() {
  int p[2];
  char buffer[10];
  int nbc;
  pipe(p);
  if (fork() == 0) {
    close(p[1]);
    dup2(p[0], 0);
    nbc = read(0, buffer, 10);
    write(1, buffer, nbc);
    exit(0);
  } else {
    close(p[0]);
    dup2(p[1], 1);
    printf("%d\n", getpid());
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <pipe@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jne    L19
  mov    0x8(%rsp),%edi
  lea    0xe(%rsp),%rbp
  call   <close@plt>
  mov    0x4(%rsp),%edi
  xor    %esi,%esi
  call   <dup2@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    $0x1,%edi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <write@plt>
  xor    %edi,%edi
  call   <exit@plt>
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L19:
  mov    0x4(%rsp),%edi
  call   <close@plt>
  mov    0x8(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L21
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string

tool: D4: %d


assistant: ```c
int main() {
  int p[2];
  char buffer[10];
  int nbc;
  pipe(p);
  if (fork() == 0) {
    close(p[1]);
    dup2(p[0], 0);
    nbc = read(0, buffer, 10);
    write(1, buffer, nbc);
    exit(0);
  } else {
    close(p[0]);
    dup2(p[1], 1);
    printf("%d\n", getpid());
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<die_v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%edi
  call   <set_warn_handler@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <warn_v@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die_v(const char *p, va_list args) {
  set_warn_handler(((void *)0));
  warn_v(p, args);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die_v>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <set_warn_handler@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <warn_v@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die_v(const char *p, va_list args) {
  set_warn_handler(((void *)0));
  warn_v(p, args);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die_v>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <set_warn_handler@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <warn_v@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

assistant: ```c
void die_v(const char *p, va_list args) {
  set_warn_handler(((void *)0));
  warn_v(p, args);
  exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<die_v>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <set_warn_handler@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <warn_v@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

assistant: ```c
void die_v(const char *p, va_list args) {
  set_warn_handler(((void *)0));
  warn_v(p, args);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <Random@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jns    L4
  neg    %rbx
L4:
  movswq -0x14(%rbp),%rax
  imul   %rbx,%rax
  lea    0x7fff(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0xf,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
short RandomInt(short range) {
  register long rawResult;
  rawResult = Random();
  if (rawResult < 0)
    rawResult *= -1;
  return (rawResult * (long)range / 32768);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomInt>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <Random@plt>
  mov    %rax,%rdi
  neg    %rdi
  cmovs  %rax,%rdi
  movswq %bx,%rbx
  imul   %rbx,%rdi
  lea    0x7fff(%rdi),%rax
  test   %rdi,%rdi
  cmovns %rdi,%rax
  sar    $0xf,%rax
  pop    %rbx
  ret
```

assistant: ```c
short RandomInt(short range) {
  register long rawResult;
  rawResult = Random();
  if (rawResult < 0)
    rawResult *= -1;
  return (rawResult * (long)range / 32768);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomInt>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  movswq %bx,%rbx
  call   <Random@plt>
  mov    %rax,%rdi
  neg    %rdi
  cmovs  %rax,%rdi
  imul   %rbx,%rdi
  pop    %rbx
  test   %rdi,%rdi
  lea    0x7fff(%rdi),%rax
  cmovns %rdi,%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
short RandomInt(short range) {
  register long rawResult;
  rawResult = Random();
  if (rawResult < 0)
    rawResult *= -1;
  return (rawResult * (long)range / 32768);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomInt>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  movswq %bx,%rbx
  call   <Random@plt>
  mov    %rax,%rdi
  neg    %rdi
  cmovs  %rax,%rdi
  imul   %rbx,%rdi
  pop    %rbx
  test   %rdi,%rdi
  lea    0x7fff(%rdi),%rax
  cmovns %rdi,%rax
  sar    $0xf,%rax
  ret
```

assistant: ```c
short RandomInt(short range) {
  register long rawResult;
  rawResult = Random();
  if (rawResult < 0)
    rawResult *= -1;
  return (rawResult * (long)range / 32768);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iwe_stream_add_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <iwe_stream_lcp_len@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <iwe_stream_event_len_adjust@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x28(%rbp)
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <likely@plt>
  test   %rax,%rax
  je     L8
  mov    -0x30(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x34(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  lea    0x4(%rdx),%rsi
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x34(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L8:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *iwe_stream_add_event(struct iw_request_info *info, char *stream, char *ends, struct iw_event *iwe, int event_len) {
  int lcp_len = iwe_stream_lcp_len(info);
  event_len = iwe_stream_event_len_adjust(info, event_len);
  if (likely((stream + event_len) < ends)) {
    iwe->len = event_len;
    memcpy(stream, (char *)iwe, IW_EV_LCP_PK_LEN);
    memcpy(stream + lcp_len, &iwe->u, event_len - lcp_len);
    stream += event_len;
  }
  return stream;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iwe_stream_add_event>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8d,%r15d
  call   <iwe_stream_lcp_len@plt>
  mov    %eax,%r12d
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <iwe_stream_event_len_adjust@plt>
  mov    %eax,%ebp
  movslq %eax,%r15
  add    %rbx,%r15
  cmp    %r14,%r15
  setb   %dil
  movzbl %dil,%edi
  call   <likely@plt>
  test   %rax,%rax
  jne    L17
L18:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %ebp,0x0(%r13)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %ebp,%edx
  sub    %r12d,%edx
  lea    0x4(%r13),%rsi
  movslq %r12d,%rdi
  add    %rbx,%rdi
  call   <memcpy@plt>
  mov    %r15,%rbx
  jmp    L18
```

assistant: ```c
char *iwe_stream_add_event(struct iw_request_info *info, char *stream, char *ends, struct iw_event *iwe, int event_len) {
  int lcp_len = iwe_stream_lcp_len(info);
  event_len = iwe_stream_event_len_adjust(info, event_len);
  if (likely((stream + event_len) < ends)) {
    iwe->len = event_len;
    memcpy(stream, (char *)iwe, IW_EV_LCP_PK_LEN);
    memcpy(stream + lcp_len, &iwe->u, event_len - lcp_len);
    stream += event_len;
  }
  return stream;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<iwe_stream_add_event>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <iwe_stream_lcp_len@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  mov    %eax,%r13d
  call   <iwe_stream_event_len_adjust@plt>
  xor    %edi,%edi
  movslq %eax,%rbp
  mov    %rbp,%rbx
  add    %r12,%rbp
  cmp    %r15,%rbp
  setb   %dil
  call   <likely@plt>
  test   %rax,%rax
  jne    L11
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  mov    D2(%rip),%rax
  mov    %ebx,(%r14)
  mov    %r12,%rdi
  mov    %r14,%rsi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    %ebx,%edx
  movslq %r13d,%rdi
  lea    0x4(%r14),%rsi
  add    %r12,%rdi
  sub    %r13d,%edx
  mov    %rbp,%r12
  call   <memcpy@plt>
  jmp    L14
```

assistant: ```c
char *iwe_stream_add_event(struct iw_request_info *info, char *stream, char *ends, struct iw_event *iwe, int event_len) {
  int lcp_len = iwe_stream_lcp_len(info);
  event_len = iwe_stream_event_len_adjust(info, event_len);
  if (likely((stream + event_len) < ends)) {
    iwe->len = event_len;
    memcpy(stream, (char *)iwe, IW_EV_LCP_PK_LEN);
    memcpy(stream + lcp_len, &iwe->u, event_len - lcp_len);
    stream += event_len;
  }
  return stream;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<iwe_stream_add_event>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <iwe_stream_lcp_len@plt>
  mov    %rbp,%rdi
  mov    %ebx,%esi
  mov    %eax,%r13d
  call   <iwe_stream_event_len_adjust@plt>
  xor    %edi,%edi
  movslq %eax,%rbp
  mov    %rbp,%rbx
  add    %r12,%rbp
  cmp    %r15,%rbp
  setb   %dil
  call   <likely@plt>
  test   %rax,%rax
  jne    L17
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L17:
  mov    D9(%rip),%rax
  mov    %ebx,(%r14)
  mov    %r12,%rdi
  mov    %r14,%rsi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    %ebx,%edx
  movslq %r13d,%rdi
  lea    0x4(%r14),%rsi
  add    %r12,%rdi
  sub    %r13d,%edx
  mov    %rbp,%r12
  call   <memcpy@plt>
  jmp    L18
```

assistant: ```c
char *iwe_stream_add_event(struct iw_request_info *info, char *stream, char *ends, struct iw_event *iwe, int event_len) {
  int lcp_len = iwe_stream_lcp_len(info);
  event_len = iwe_stream_event_len_adjust(info, event_len);
  if (likely((stream + event_len) < ends)) {
    iwe->len = event_len;
    memcpy(stream, (char *)iwe, IW_EV_LCP_PK_LEN);
    memcpy(stream + lcp_len, &iwe->u, event_len - lcp_len);
    stream += event_len;
  }
  return stream;
}
```