ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<exist_file>:
  endbr64
  test   %esi,%esi
  jle    L21
  movss  D8(%rip),%xmm2
  lea    -0x1(%rsi),%eax
  pxor   %xmm3,%xmm3
  lea    (%rax,%rax,2),%rax
  mulss  %xmm2,%xmm0
  lea    0xc(%rdi,%rax,4),%rdx
  cvttss2si %xmm0,%rcx
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0xc,%rdi
  cmp    %rdx,%rdi
  je     L51
L30:
  movss  (%rdi),%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rcx
  jne    L43
  movaps %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rsi
  movss  0x4(%rdi),%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%rax
  cmp    %rax,%rsi
  jne    L43
  movss  0x8(%rdi),%xmm3
  add    $0xc,%rdi
  cmp    %rdx,%rdi
  jne    L30
L51:
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L21:
  pxor   %xmm3,%xmm3
  movaps %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: byte[4]

tool: {"D8": [0x00,0x00,0x7a,0x44]}

assistant: ```c
float exist_file(float FR8[5000][3], float lat, float lon, int cells) {
  int i;
  float return_fraction = 0.0;
  for (i = 0; i < cells; i++) {
    if (((long)(1000 * lat) == (long)(1000 * FR8[i][0])) && ((long)(1000 * lon) == (long)(1000 * FR8[i][1]))) {
      return_fraction = FR8[i][2];
    }
  }
  return return_fraction;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<null_init_fini>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int null_init_fini(FILE *f) {
  (void)f;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<null_init_fini>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int null_init_fini(FILE *f) {
  (void)f;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<null_init_fini>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int null_init_fini(FILE *f) {
  (void)f;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L21
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L21:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L34
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L41
L34:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L6
L41:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D39
datatype: string

tool: D7: %d

tool: D39: Invalid input

assistant: ```c
int main() {
  int n = 0;
  int p = 0;
  int v = 0;
  int result = 0;
  scanf("%d", &n);
  scanf("%d", &p);
  scanf("%d", &v);
  if (v == 0) {
    result = (~(1 << p) & 1);
  } else if (v == 1) {
    result = n | (1 << p);
  } else {
    printf("Invalid input");
    return 1;
  }
  printf("%d", result);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L45
  cmpl   $0x0,0x10(%rsp)
  setne  %sil
  movzbl %sil,%esi
L18:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x20,%rsp
  pop    %rbx
  ret
L45:
  cmp    $0x1,%eax
  jne    L10
  mov    0x10(%rsp),%ecx
  mov    $0x1,%esi
  shl    %cl,%esi
  or     0xc(%rsp),%esi
  jmp    L18
L10:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L39
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string
name: read_data
arguments: data_tag: D27
type_infered: string

tool: D6: %d

tool: D27: Invalid input

assistant: ```c
int main() {
  int n = 0;
  int p = 0;
  int v = 0;
  int result = 0;
  scanf("%d", &n);
  scanf("%d", &p);
  scanf("%d", &v);
  if (v == 0) {
    result = (~(1 << p) & 1);
  } else if (v == 1) {
    result = n | (1 << p);
  } else {
    printf("Invalid input");
    return 1;
  }
  printf("%d", result);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  test   %esi,%esi
  jne    L45
  xor    %esi,%esi
  cmpl   $0x0,0x10(%rsp)
  setne  %sil
L30:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L31:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L45:
  cmp    $0x1,%esi
  jne    L25
  mov    0x10(%rsp),%ecx
  shl    %cl,%esi
  or     0xc(%rsp),%esi
  jmp    L30
L25:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D3
type: string

tool: D13: %d

tool: D3: Invalid input

assistant: ```c
int main() {
  int n = 0;
  int p = 0;
  int v = 0;
  int result = 0;
  scanf("%d", &n);
  scanf("%d", &p);
  scanf("%d", &v);
  if (v == 0) {
    result = (~(1 << p) & 1);
  } else if (v == 1) {
    result = n | (1 << p);
  } else {
    printf("Invalid input");
    return 1;
  }
  printf("%d", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  test   %esi,%esi
  jne    L41
  xor    %esi,%esi
  cmpl   $0x0,0x10(%rsp)
  setne  %sil
L46:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20,%rsp
  pop    %rbp
  ret
L41:
  cmp    $0x1,%esi
  jne    L34
  mov    0x10(%rsp),%ecx
  shl    %cl,%esi
  or     0xc(%rsp),%esi
  jmp    L46
L34:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L29
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string

tool: D7: %d

tool: D15: Invalid input

assistant: ```c
int main() {
  int n = 0;
  int p = 0;
  int v = 0;
  int result = 0;
  scanf("%d", &n);
  scanf("%d", &p);
  scanf("%d", &v);
  if (v == 0) {
    result = (~(1 << p) & 1);
  } else if (v == 1) {
    result = n | (1 << p);
  } else {
    printf("Invalid input");
    return 1;
  }
  printf("%d", result);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L50
L18:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L44
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L24
L44:
  addl   $0x1,-0xc(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  jmp    L8
L24:
  nop
L8:
  cmpl   $0x0,-0xc(%rbp)
  je     L68
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L25:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L25
L68:
  nop
  leave
  ret
```

assistant: ```c
void ltrim(char *str) {
  int i = 0, j, len = strlen(str);
  while (str[i] != '\0') {
    if (str[i] != 32 && str[i] != 9)
      break;
    i++;
  }
  if (i != 0)
    for (j = 0; j <= len - i; j++) {
      str[j] = str[j + i];
    }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L62
  lea    0x1(%rbx),%rcx
  mov    $0x0,%esi
  jmp    L10
L46:
  add    $0x1,%esi
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  je     L29
L10:
  cmp    $0x20,%dl
  je     L46
  cmp    $0x9,%dl
  je     L46
L29:
  test   %esi,%esi
  je     L62
  sub    %esi,%eax
  js     L62
  mov    %rbx,%rdx
  mov    %eax,%eax
  lea    0x1(%rbx,%rax,1),%rcx
  movslq %esi,%rsi
L78:
  movzbl (%rdx,%rsi,1),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L78
L62:
  pop    %rbx
  ret
```

assistant: ```c
void ltrim(char *str) {
  int i = 0, j, len = strlen(str);
  while (str[i] != '\0') {
    if (str[i] != 32 && str[i] != 9)
      break;
    i++;
  }
  if (i != 0)
    for (j = 0; j <= len - i; j++) {
      str[j] = str[j + i];
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L32
  lea    0x1(%rbx),%r8
  xor    %esi,%esi
  mov    %r8,%rcx
  jmp    L6
  nop
L37:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%esi
  test   %dl,%dl
  je     L74
L6:
  cmp    $0x20,%dl
  je     L37
  cmp    $0x9,%dl
  je     L37
  test   %esi,%esi
  jne    L74
L32:
  pop    %rbx
  ret
  xchg   %ax,%ax
L74:
  sub    %esi,%eax
  js     L32
  cltq
  mov    %rbx,%rdi
  movslq %esi,%rsi
  lea    (%r8,%rax,1),%rdx
L79:
  movzbl (%rdi,%rsi,1),%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdx,%rdi
  jne    L79
  pop    %rbx
  ret
```

assistant: ```c
void ltrim(char *str) {
  int i = 0, j, len = strlen(str);
  while (str[i] != '\0') {
    if (str[i] != 32 && str[i] != 9)
      break;
    i++;
  }
  if (i != 0)
    for (j = 0; j <= len - i; j++) {
      str[j] = str[j + i];
    }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L5
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  mov    %rdi,%rcx
  jmp    L36
  nop
L71:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  add    $0x1,%esi
  test   %dl,%dl
  je     L187
L36:
  cmp    $0x20,%dl
  je     L71
  cmp    $0x9,%dl
  je     L71
  test   %esi,%esi
  jne    L187
L5:
  pop    %rbx
  ret
  xchg   %ax,%ax
L187:
  sub    %esi,%eax
  js     L5
  movslq %esi,%rcx
  cmp    $0x6,%eax
  jbe    L1
  lea    0x1(%rax),%r8d
  cmp    $0xe,%eax
  jbe    L133
  mov    %r8d,%edi
  add    %rbx,%rcx
  xor    %edx,%edx
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L162:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%rbx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L162
  mov    %r8d,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%edx
  cmp    %edi,%r8d
  je     L5
  mov    %eax,%r9d
  sub    %edi,%r9d
  lea    0x1(%r9),%r8d
  cmp    $0x6,%r9d
  jbe    L28
L116:
  mov    (%rcx,%rdi,1),%rcx
  mov    %rcx,(%rbx,%rdi,1)
  mov    %r8d,%ecx
  and    $0xfffffff8,%ecx
  add    %ecx,%edx
  cmp    %ecx,%r8d
  je     L5
L28:
  lea    (%rsi,%rdx,1),%ecx
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%edi
  movslq %edx,%rcx
  mov    %dil,(%rbx,%rcx,1)
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%eax
  jl     L5
  lea    (%rsi,%rcx,1),%edi
  movslq %ecx,%rcx
  movslq %edi,%rdi
  movzbl (%rbx,%rdi,1),%edi
  mov    %dil,(%rbx,%rcx,1)
  lea    0x2(%rdx),%ecx
  cmp    %ecx,%eax
  jl     L5
  lea    (%rsi,%rcx,1),%edi
  movslq %ecx,%rcx
  movslq %edi,%rdi
  movzbl (%rbx,%rdi,1),%edi
  mov    %dil,(%rbx,%rcx,1)
  lea    0x3(%rdx),%ecx
  cmp    %ecx,%eax
  jl     L5
  lea    (%rsi,%rcx,1),%edi
  movslq %ecx,%rcx
  movslq %edi,%rdi
  movzbl (%rbx,%rdi,1),%edi
  mov    %dil,(%rbx,%rcx,1)
  lea    0x4(%rdx),%ecx
  cmp    %ecx,%eax
  jl     L5
  lea    (%rsi,%rcx,1),%edi
  movslq %ecx,%rcx
  movslq %edi,%rdi
  movzbl (%rbx,%rdi,1),%edi
  mov    %dil,(%rbx,%rcx,1)
  lea    0x5(%rdx),%ecx
  cmp    %ecx,%eax
  jl     L5
  lea    (%rsi,%rcx,1),%edi
  add    $0x6,%edx
  movslq %ecx,%rcx
  movslq %edi,%rdi
  movzbl (%rbx,%rdi,1),%edi
  mov    %dil,(%rbx,%rcx,1)
  cmp    %edx,%eax
  jl     L5
  lea    (%rsi,%rdx,1),%eax
  movslq %edx,%rdx
  cltq
  movzbl (%rbx,%rax,1),%eax
  mov    %al,(%rbx,%rdx,1)
  pop    %rbx
  ret
L1:
  mov    %eax,%eax
  add    %rax,%rdi
  nopw   0x0(%rax,%rax,1)
L33:
  movzbl (%rbx,%rcx,1),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rdi
  jne    L33
  pop    %rbx
  ret
L133:
  xor    %edi,%edi
  xor    %edx,%edx
  add    %rbx,%rcx
  jmp    L116
```

assistant: ```c
void ltrim(char *str) {
  int i = 0, j, len = strlen(str);
  while (str[i] != '\0') {
    if (str[i] != 32 && str[i] != 9)
      break;
    i++;
  }
  if (i != 0)
    for (j = 0; j <= len - i; j++) {
      str[j] = str[j + i];
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wmemset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L15:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L7:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
wchar_t *wmemset(wchar_t *segment, wchar_t c, size_t size) {
  wchar_t *r = segment;
  while (size--)
    *segment++ = c;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wmemset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L11
  mov    $0x0,%ecx
L9:
  mov    %esi,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L9
L11:
  ret
```

assistant: ```c
wchar_t *wmemset(wchar_t *segment, wchar_t c, size_t size) {
  wchar_t *r = segment;
  while (size--)
    *segment++ = c;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wmemset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L15
  xor    %ecx,%ecx
  xchg   %ax,%ax
L19:
  mov    %esi,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L19
L15:
  ret
```

assistant: ```c
wchar_t *wmemset(wchar_t *segment, wchar_t c, size_t size) {
  wchar_t *r = segment;
  while (size--)
    *segment++ = c;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wmemset>:
  endbr64
  mov    %rdi,%rax
  lea    -0x1(%rdx),%r9
  test   %rdx,%rdx
  je     L18
  cmp    $0x2,%r9
  jbe    L53
  mov    %rdx,%r8
  movd   %esi,%xmm1
  xor    %ecx,%ecx
  shr    $0x2,%r8
  pshufd $0x0,%xmm1,%xmm0
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rcx,%rdi
  add    $0x1,%rcx
  shl    $0x4,%rdi
  movups %xmm0,(%rax,%rdi,1)
  cmp    %rcx,%r8
  jne    L46
  mov    %rdx,%rcx
  and    $0xfffffffffffffffc,%rcx
  lea    (%rax,%rcx,4),%rdi
  sub    %rcx,%r9
  cmp    %rcx,%rdx
  je     L47
L53:
  mov    %esi,(%rdi)
  test   %r9,%r9
  je     L18
  mov    %esi,0x4(%rdi)
  cmp    $0x1,%r9
  je     L18
  mov    %esi,0x8(%rdi)
L18:
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  ret
```

assistant: ```c
wchar_t *wmemset(wchar_t *segment, wchar_t c, size_t size) {
  wchar_t *r = segment;
  while (size--)
    *segment++ = c;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x50(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L117:
  cmp    %rdx,%rsp
  je     L114
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L117
L114:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L11
  orq    $0x0,-0x8(%rsp,%rax,1)
L11:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L50
  mov    %ecx,%ebx
  mov    $0x0,%eax
L75:
  movslq 0x0(%r13,%rax,4),%rdx
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L75
  mov    $0x0,%r11d
  mov    $0x0,%eax
  lea    -0x1(%rcx),%r15d
  jmp    L49
L25:
  mov    -0x48(%rbp),%rdi
  mov    %eax,-0x4(%rdi,%r14,1)
  test   %eax,%eax
  setg   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
L118:
  add    $0x1,%r11
  cmp    %rbx,%r11
  je     L50
L49:
  mov    %r11d,%r9d
  mov    (%r12,%r11,4),%edx
  cmp    %r15d,%edx
  je     L150
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%r14
  mov    0x0(%r13,%rdx,4),%r10d
  lea    (%rax,%r11,1),%edi
  cmp    %edi,%ecx
  jle    L25
  lea    (%r10,%rax,1),%r8d
  cmp    %r8d,%ecx
  jle    L25
  movslq %edi,%rdi
  mov    -0x50(%rbp),%rdx
  add    %rdi,%rdx
  movslq %r8d,%r8
L19:
  mov    %rdx,%rsi
  sub    %rdi,%rsi
  movzbl (%rsi,%r8,1),%esi
  cmp    %sil,(%rdx)
  jne    L25
  add    $0x1,%eax
  lea    (%rax,%r9,1),%esi
  cmp    %esi,%ecx
  jle    L25
  add    $0x1,%rdx
  lea    (%r10,%rax,1),%esi
  cmp    %esi,%ecx
  jg     L19
  jmp    L25
L150:
  mov    $0x0,%eax
  jmp    L118
L50:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kasai_lcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  movslq %ecx,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,-0x50(%rbp)
  mov    %r12,%rsi
  mov    %rdi,-0x58(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r12,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L147
L69:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L69
L147:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L33
L170:
  mov    %rsp,%r13
  xor    %eax,%eax
  test   %esi,%esi
  jle    L141
  nopl   0x0(%rax)
L162:
  movslq (%r14,%rax,4),%rdx
  mov    %eax,0x0(%r13,%rdx,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L162
  lea    -0x1(%rsi),%eax
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  mov    %eax,-0x44(%rbp)
  nopl   0x0(%rax)
L168:
  movslq 0x0(%r13,%rbx,4),%rax
  mov    %ebx,%r10d
  cmp    -0x44(%rbp),%eax
  je     L104
  add    $0x1,%rax
  lea    (%rcx,%rbx,1),%r8d
  mov    (%r14,%rax,4),%r11d
  lea    0x0(,%rax,4),%r15
  cmp    %r8d,%esi
  jle    L55
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  jle    L55
  mov    -0x58(%rbp),%rax
  movslq %r8d,%r8
  movslq %r9d,%r9
  add    %r8,%rax
  jmp    L164
  xchg   %ax,%ax
L122:
  lea    0x1(%rcx),%edx
  lea    (%rdx,%r10,1),%edi
  cmp    %edi,%esi
  jle    L24
  lea    (%r11,%rdx,1),%edi
  add    $0x1,%rax
  cmp    %edi,%esi
  jle    L24
  mov    %edx,%ecx
L164:
  mov    %rax,%rdx
  sub    %r8,%rdx
  movzbl (%rdx,%r9,1),%edi
  cmp    %dil,(%rax)
  je     L122
L55:
  mov    -0x50(%rbp),%rax
  mov    %ecx,-0x4(%rax,%r15,1)
  test   %ecx,%ecx
  jne    L112
L104:
  xor    %ecx,%ecx
L144:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L168
L141:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    -0x50(%rbp),%rax
  mov    %edx,-0x4(%rax,%r15,1)
  jmp    L144
L33:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L170
L87:
  call   <__stack_chk_fail@plt>
L112:
  sub    $0x1,%ecx
  jmp    L144
```

assistant: ```c
void kasai_lcp(char *text, int *lcp, int *suffArr, int n) {
  int i;
  int invSuff[n];
  for (i = 0; i < n; i++) {
    invSuff[suffArr[i]] = i;
  }
  int k = 0;
  for (i = 0; i < n; i++) {
    if (invSuff[i] == n - 1) {
      k = 0;
      continue;
    }
    int j = suffArr[invSuff[i] + 1];
    while (i + k < n && j + k < n && text[i + k] == text[j + k]) {
      k++;
    }
    lcp[invSuff[i]] = k;
    if (k > 0) {
      k--;
    }
  }
  return;
}
```