ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  shl    $0x2,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L25
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L15
L25:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
  mov    -0x8(%rbp),%rax
  jmp    L15
L29:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
L15:
  leave
  ret
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode_alloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  lea    0x2(%rsi),%rdx
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%rbx
  lea    0x1(%rbx),%r14
  cmp    %r14,%rsi
  jbe    L8
  movq   $0x0,(%r12)
  mov    $0x0,%ebx
L30:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L2
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  jmp    L30
L2:
  mov    %r14,%rbx
  jmp    L30
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L11
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L23:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L11:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L9
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  mov    %r14,%r12
  jmp    L23
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L1
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L8:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L1:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L26
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    %r14,%r12
  jmp    L8
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<threebyte_memmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0xc,-0x18(%rbp)
  subq   $0x3,-0x20(%rbp)
  jmp    L30
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L33
  mov    -0x18(%rbp),%rax
  sub    $0x3,%rax
  jmp    L1
L33:
  subq   $0x1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  or     -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0x8(%rbp)
L30:
  cmpq   $0x0,-0x20(%rbp)
  jne    L27
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L31
  mov    -0x18(%rbp),%rax
  sub    $0x3,%rax
  jmp    L1
L31:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
char *threebyte_memmem(const uint8_t *h, size_t k, const uint8_t *n) {
  uint32_t nw = n[0] << 24 | n[1] << 16 | n[2] << 8;
  uint32_t hw = h[0] << 24 | h[1] << 16 | h[2] << 8;
  for (h += 3, k -= 3; k; k--, hw = (hw | *h++) << 8) {
    if (hw == nw) {
      return (char *)h - 3;
    }
  }
  return hw == nw ? (char *)h - 3 : 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<threebyte_memmem>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdx),%edi
  shl    $0x18,%edi
  mov    0x4(%rdx),%ecx
  shl    $0x10,%ecx
  or     %ecx,%edi
  mov    0x8(%rdx),%edx
  shl    $0x8,%edx
  or     %edx,%edi
  mov    (%rax),%edx
  shl    $0x18,%edx
  mov    0x4(%rax),%ecx
  shl    $0x10,%ecx
  or     %ecx,%edx
  mov    0x8(%rax),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  add    $0xc,%rax
  sub    $0x3,%rsi
  mov    %rsi,%rcx
  je     L11
  cmp    %edx,%edi
  je     L3
L7:
  add    $0x4,%rax
  or     -0x4(%rax),%edx
  shl    $0x8,%edx
  sub    $0x1,%rcx
  je     L11
  cmp    %edx,%edi
  jne    L7
L3:
  sub    $0x3,%rax
  ret
L11:
  sub    $0x3,%rax
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *threebyte_memmem(const uint8_t *h, size_t k, const uint8_t *n) {
  uint32_t nw = n[0] << 24 | n[1] << 16 | n[2] << 8;
  uint32_t hw = h[0] << 24 | h[1] << 16 | h[2] << 8;
  for (h += 3, k -= 3; k; k--, hw = (hw | *h++) << 8) {
    if (hw == nw) {
      return (char *)h - 3;
    }
  }
  return hw == nw ? (char *)h - 3 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<threebyte_memmem>:
  endbr64
  mov    %rdi,%rax
  mov    0x4(%rdx),%ecx
  mov    (%rdx),%edi
  mov    0x8(%rdx),%edx
  add    $0xc,%rax
  shl    $0x10,%ecx
  shl    $0x18,%edi
  or     %ecx,%edi
  shl    $0x8,%edx
  mov    -0x8(%rax),%ecx
  or     %edx,%edi
  mov    -0xc(%rax),%edx
  shl    $0x10,%ecx
  shl    $0x18,%edx
  or     %ecx,%edx
  mov    -0x4(%rax),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  sub    $0x3,%rsi
  mov    %rsi,%rcx
  jne    L11
  jmp    L13
  nopl   0x0(%rax)
L35:
  or     (%rax),%edx
  add    $0x4,%rax
  shl    $0x8,%edx
  sub    $0x1,%rcx
  je     L13
L11:
  cmp    %edx,%edi
  jne    L35
  sub    $0x3,%rax
  ret
L13:
  sub    $0x3,%rax
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *threebyte_memmem(const uint8_t *h, size_t k, const uint8_t *n) {
  uint32_t nw = n[0] << 24 | n[1] << 16 | n[2] << 8;
  uint32_t hw = h[0] << 24 | h[1] << 16 | h[2] << 8;
  for (h += 3, k -= 3; k; k--, hw = (hw | *h++) << 8) {
    if (hw == nw) {
      return (char *)h - 3;
    }
  }
  return hw == nw ? (char *)h - 3 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<threebyte_memmem>:
  endbr64
  mov    %rdi,%rax
  mov    0x4(%rdx),%ecx
  mov    (%rdx),%edi
  mov    0x8(%rdx),%edx
  add    $0xc,%rax
  shl    $0x10,%ecx
  shl    $0x18,%edi
  or     %ecx,%edi
  shl    $0x8,%edx
  mov    -0x8(%rax),%ecx
  or     %edx,%edi
  mov    -0xc(%rax),%edx
  shl    $0x10,%ecx
  shl    $0x18,%edx
  or     %ecx,%edx
  mov    -0x4(%rax),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  sub    $0x3,%rsi
  mov    %rsi,%rcx
  jne    L16
  jmp    L29
  nopl   0x0(%rax)
L7:
  or     (%rax),%edx
  add    $0x4,%rax
  shl    $0x8,%edx
  sub    $0x1,%rcx
  je     L29
L16:
  cmp    %edx,%edi
  jne    L7
  sub    $0x3,%rax
  ret
L29:
  sub    $0x3,%rax
  cmp    %edx,%edi
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *threebyte_memmem(const uint8_t *h, size_t k, const uint8_t *n) {
  uint32_t nw = n[0] << 24 | n[1] << 16 | n[2] << 8;
  uint32_t hw = h[0] << 24 | h[1] << 16 | h[2] << 8;
  for (h += 3, k -= 3; k; k--, hw = (hw | *h++) << 8) {
    if (hw == nw) {
      return (char *)h - 3;
    }
  }
  return hw == nw ? (char *)h - 3 : 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shear>:
  endbr64
  movsd  (%rdi),%xmm5
  movsd  0x10(%rdi),%xmm4
  mov    %rdi,%rax
  movapd %xmm0,%xmm14
  movsd  0x20(%rdi),%xmm13
  movsd  0x30(%rdi),%xmm3
  movsd  0x40(%rdi),%xmm11
  movsd  0x50(%rdi),%xmm2
  movsd  0x60(%rdi),%xmm9
  movsd  0x70(%rdi),%xmm7
  movsd  0x8(%rdi),%xmm12
  movsd  0x28(%rdi),%xmm10
  movsd  0x48(%rdi),%xmm8
  movsd  0x68(%rdi),%xmm6
  cmp    $0x78,%sil
  je     L1
  cmp    $0x79,%sil
  je     L19
  mulsd  %xmm4,%xmm14
  mulsd  %xmm1,%xmm4
  addsd  %xmm5,%xmm14
  movapd %xmm0,%xmm5
  mulsd  %xmm3,%xmm5
  addsd  %xmm12,%xmm4
  mulsd  %xmm1,%xmm3
  movsd  %xmm14,(%rdi)
  movsd  %xmm4,0x8(%rdi)
  addsd  %xmm13,%xmm5
  addsd  %xmm10,%xmm3
  movsd  %xmm5,0x20(%rdi)
  movapd %xmm0,%xmm5
  mulsd  %xmm2,%xmm5
  movsd  %xmm3,0x28(%rdi)
  mulsd  %xmm7,%xmm0
  mulsd  %xmm1,%xmm2
  mulsd  %xmm7,%xmm1
  addsd  %xmm11,%xmm5
  addsd  %xmm9,%xmm0
  addsd  %xmm8,%xmm2
  addsd  %xmm6,%xmm1
  movsd  %xmm5,0x40(%rdi)
  movsd  %xmm0,0x60(%rdi)
  movsd  %xmm2,0x48(%rdi)
  movsd  %xmm1,0x68(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mulsd  %xmm12,%xmm14
  mulsd  %xmm1,%xmm12
  addsd  %xmm5,%xmm14
  movapd %xmm0,%xmm5
  mulsd  %xmm10,%xmm5
  addsd  %xmm4,%xmm12
  mulsd  %xmm1,%xmm10
  movsd  %xmm14,(%rdi)
  movsd  %xmm12,0x10(%rdi)
  addsd  %xmm13,%xmm5
  addsd  %xmm3,%xmm10
  movsd  %xmm5,0x20(%rdi)
  movapd %xmm0,%xmm5
  mulsd  %xmm8,%xmm5
  movsd  %xmm10,0x30(%rdi)
  mulsd  %xmm6,%xmm0
  mulsd  %xmm1,%xmm8
  mulsd  %xmm6,%xmm1
  addsd  %xmm11,%xmm5
  addsd  %xmm9,%xmm0
  addsd  %xmm2,%xmm8
  addsd  %xmm7,%xmm1
  movsd  %xmm5,0x40(%rdi)
  movsd  %xmm0,0x60(%rdi)
  movsd  %xmm8,0x50(%rdi)
  movsd  %xmm1,0x70(%rdi)
  ret
  nopl   0x0(%rax)
L1:
  mulsd  %xmm5,%xmm14
  mulsd  %xmm1,%xmm5
  addsd  %xmm12,%xmm14
  movapd %xmm0,%xmm12
  mulsd  %xmm13,%xmm12
  addsd  %xmm4,%xmm5
  mulsd  %xmm1,%xmm13
  movsd  %xmm14,0x8(%rdi)
  movsd  %xmm5,0x10(%rdi)
  addsd  %xmm10,%xmm12
  movapd %xmm0,%xmm10
  mulsd  %xmm11,%xmm10
  addsd  %xmm3,%xmm13
  mulsd  %xmm9,%xmm0
  mulsd  %xmm1,%xmm11
  movsd  %xmm12,0x28(%rdi)
  mulsd  %xmm1,%xmm9
  movsd  %xmm13,0x30(%rdi)
  addsd  %xmm8,%xmm10
  addsd  %xmm6,%xmm0
  addsd  %xmm2,%xmm11
  addsd  %xmm7,%xmm9
  movsd  %xmm10,0x48(%rdi)
  movsd  %xmm0,0x68(%rdi)
  movsd  %xmm11,0x50(%rdi)
  movsd  %xmm9,0x70(%rdi)
  ret
```

assistant: ```c
shear(a, dir, u, v) double a[4][4], u, v;
char dir;
{
  if (dir == 'x') {
    a[0][1] += u * a[0][0];
    a[1][1] += u * a[1][0];
    a[2][1] += u * a[2][0];
    a[3][1] += u * a[3][0];
    a[0][2] += v * a[0][0];
    a[1][2] += v * a[1][0];
    a[2][2] += v * a[2][0];
    a[3][2] += v * a[3][0];
  } else if (dir == 'y') {
    a[0][0] += u * a[0][1];
    a[1][0] += u * a[1][1];
    a[2][0] += u * a[2][1];
    a[3][0] += u * a[3][1];
    a[0][2] += v * a[0][1];
    a[1][2] += v * a[1][1];
    a[2][2] += v * a[2][1];
    a[3][2] += v * a[3][1];
  } else {
    a[0][0] += u * a[0][2];
    a[1][0] += u * a[1][2];
    a[2][0] += u * a[2][2];
    a[3][0] += u * a[3][2];
    a[0][1] += v * a[0][2];
    a[1][1] += v * a[1][2];
    a[2][1] += v * a[2][2];
    a[3][1] += v * a[3][2];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<report_ipc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <report_qs@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <report_mems@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void report_ipc(void) {
  int this_Clerk_pid = 0;
  int other_Clerk_pid = 0;
  report_qs(&this_Clerk_pid, &other_Clerk_pid);
  report_mems(this_Clerk_pid, other_Clerk_pid);
}
```
user: What is the c source code of the assembly code below:

```asm
<report_ipc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <report_qs@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <report_mems@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void report_ipc(void) {
  int this_Clerk_pid = 0;
  int other_Clerk_pid = 0;
  report_qs(&this_Clerk_pid, &other_Clerk_pid);
  report_mems(this_Clerk_pid, other_Clerk_pid);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<report_ipc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <report_qs@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <report_mems@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void report_ipc(void) {
  int this_Clerk_pid = 0;
  int other_Clerk_pid = 0;
  report_qs(&this_Clerk_pid, &other_Clerk_pid);
  report_mems(this_Clerk_pid, other_Clerk_pid);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<report_ipc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <report_qs@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <report_mems@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void report_ipc(void) {
  int this_Clerk_pid = 0;
  int other_Clerk_pid = 0;
  report_qs(&this_Clerk_pid, &other_Clerk_pid);
  report_mems(this_Clerk_pid, other_Clerk_pid);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ht_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L12:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0xc(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbq %dl,%rdx
  imul   %rdx,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int ht_hash(const char *s, const int a, const int m) {
  long hash = 0;
  const int len_s = strlen(s);
  for (int i = 0; i < len_s; i++) {
    hash += (long)pow(a, len_s - (i + 1)) * s[i];
    hash = hash % m;
  }
  return (int)hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<ht_hash>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  lea    -0x1(%rax),%ebx
  mov    $0x0,%r14d
  movslq %r12d,%r12
L25:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %rax,%rdx
  movsbq 0x0(%rbp),%rax
  imul   %rdx,%rax
  add    %r14,%rax
  cqto
  idiv   %r12
  mov    %rdx,%r14
  sub    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  jne    L25
L10:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    $0x0,%r14d
  jmp    L10
```

assistant: ```c
int ht_hash(const char *s, const int a, const int m) {
  long hash = 0;
  const int len_s = strlen(s);
  for (int i = 0; i < len_s; i++) {
    hash += (long)pow(a, len_s - (i + 1)) * s[i];
    hash = hash % m;
  }
  return (int)hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ht_hash>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L8
  lea    -0x1(%rax),%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L13:
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    $0x1,%r12d
  add    $0x1,%r14
  call   <pow@plt>
  mov    %rax,%r8
  movsbq -0x1(%r14),%rax
  imul   %r8,%rax
  add    %r13,%rax
  cqto
  idiv   %rbx
  mov    %rdx,%r13
  cmp    $0xffffffff,%r12d
  jne    L13
  pop    %rbx
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ht_hash(const char *s, const int a, const int m) {
  long hash = 0;
  const int len_s = strlen(s);
  for (int i = 0; i < len_s; i++) {
    hash += (long)pow(a, len_s - (i + 1)) * s[i];
    hash = hash % m;
  }
  return (int)hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ht_hash>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  movslq %edx,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L4
  lea    -0x1(%rax),%r12d
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L14:
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    $0x1,%r12d
  add    $0x1,%r14
  call   <pow@plt>
  mov    %rax,%r8
  movsbq -0x1(%r14),%rax
  imul   %r8,%rax
  add    %r13,%rax
  cqto
  idiv   %rbx
  mov    %rdx,%r13
  cmp    $0xffffffff,%r12d
  jne    L14
  pop    %rbx
  mov    %edx,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ht_hash(const char *s, const int a, const int m) {
  long hash = 0;
  const int len_s = strlen(s);
  for (int i = 0; i < len_s; i++) {
    hash += (long)pow(a, len_s - (i + 1)) * s[i];
    hash = hash % m;
  }
  return (int)hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cdsortp2yl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %rdx,%rdi
  mov    %ecx,%ebx
  test   %r9d,%r9d
  jle    L57
  mov    %rdx,%rax
  lea    -0x1(%r9),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L24:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L24
  test   %r8d,%r8d
  jle    L113
L42:
  movslq %ebx,%rsi
  shl    $0x2,%rsi
  lea    0x4(%r11),%rcx
  mov    $0x0,%edx
L87:
  cvttss2si (%rcx),%eax
  cltq
  addl   $0x1,(%rdi,%rax,4)
  add    $0x1,%edx
  add    %rsi,%rcx
  cmp    %edx,%r8d
  jne    L87
  test   %r9d,%r9d
  jle    L103
L113:
  mov    $0x0,%eax
  mov    $0x0,%edx
L72:
  mov    (%rdi,%rax,4),%ecx
  mov    %edx,(%rdi,%rax,4)
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %eax,%r9d
  jg     L72
  test   %r8d,%r8d
  jle    L117
L103:
  movslq %ebx,%r12
  shl    $0x2,%r12
  mov    $0x0,%ebp
  mov    %ebx,%esi
L35:
  mov    %r11,%rdx
  cvttss2si 0x4(%r11),%eax
  cltq
  lea    (%rdi,%rax,4),%r13
  mov    0x0(%r13),%r9d
  test   %ebx,%ebx
  jle    L14
  mov    %ebx,%eax
  imul   %r9d,%eax
  cltq
  lea    (%r10,%rax,4),%rcx
  mov    $0x0,%eax
L7:
  movss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L7
L14:
  add    $0x1,%r9d
  mov    %r9d,0x0(%r13)
  add    $0x1,%ebp
  add    %r12,%r11
  cmp    %ebp,%r8d
  jg     L35
L117:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L57:
  test   %r8d,%r8d
  jg     L42
  jmp    L117
```

assistant: ```c
void cdsortp2yl(float parta[], float partb[], int npic[], int idimp, int nop, int ny1) {
  int i, j, k, m, isum, ist, ip;
  for (k = 0; k < ny1; k++) {
    npic[k] = 0;
  }
  for (j = 0; j < nop; j++) {
    m = parta[1 + idimp * j];
    npic[m] += 1;
  }
  isum = 0;
  for (k = 0; k < ny1; k++) {
    ist = npic[k];
    npic[k] = isum;
    isum += ist;
  }
  for (j = 0; j < nop; j++) {
    m = parta[1 + idimp * j];
    ip = npic[m];
    for (i = 0; i < idimp; i++) {
      partb[i + idimp * ip] = parta[i + idimp * j];
    }
    npic[m] = ip + 1;
  }
  return;
}
```