ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  mov    $0x1,%eax
  xchg   %ax,%ax
L18:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L18
  ret
  xchg   %ax,%ax
L12:
  mov    %edi,%eax
  ret
```

assistant: ```c
int factorial(value)
int value;
{
  int local_var;
  if (value > 1) {
    value *= factorial(value - 1);
  }
  local_var = value;
  return (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jle    L15
  mov    $0x1,%eax
  xchg   %ax,%ax
L0:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L0
  ret
  xchg   %ax,%ax
L15:
  mov    %edi,%eax
  ret
```

assistant: ```c
int factorial(value)
int value;
{
  int local_var;
  if (value > 1) {
    value *= factorial(value - 1);
  }
  local_var = value;
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iterative_quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf70,%rsp
  mov    %rdi,-0x1f68(%rbp)
  mov    %esi,-0x1f6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x1f60(%rbp)
  addl   $0x1,-0x1f60(%rbp)
  mov    -0x1f60(%rbp),%eax
  cltq
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
  mov    -0x1f6c(%rbp),%eax
  sub    $0x1,%eax
  addl   $0x1,-0x1f60(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x1f60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
  jmp    L41
L5:
  mov    -0x1f60(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1f60(%rbp)
  cltq
  movsd  -0x1f50(%rbp,%rax,8),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1f5c(%rbp)
  mov    -0x1f60(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1f60(%rbp)
  cltq
  movsd  -0x1f50(%rbp,%rax,8),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1f58(%rbp)
  mov    -0x1f5c(%rbp),%edx
  mov    -0x1f58(%rbp),%ecx
  mov    -0x1f68(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x1f54(%rbp)
  mov    -0x1f54(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1f58(%rbp)
  jge    L16
  addl   $0x1,-0x1f60(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1f58(%rbp),%xmm0
  mov    -0x1f60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
  mov    -0x1f54(%rbp),%eax
  sub    $0x1,%eax
  addl   $0x1,-0x1f60(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x1f60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
L16:
  mov    -0x1f54(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1f5c(%rbp)
  jle    L41
  mov    -0x1f54(%rbp),%eax
  add    $0x1,%eax
  addl   $0x1,-0x1f60(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x1f60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
  addl   $0x1,-0x1f60(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1f5c(%rbp),%xmm0
  mov    -0x1f60(%rbp),%eax
  cltq
  movsd  %xmm0,-0x1f50(%rbp,%rax,8)
L41:
  cmpl   $0x0,-0x1f60(%rbp)
  jns    L5
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void iterative_quicksort(double array[], int array_size) {
  double stack[1000];
  int top, start, end, pivot;
  top = -1;
  stack[++top] = 0;
  stack[++top] = array_size - 1;
  while (top >= 0) {
    end = stack[top--];
    start = stack[top--];
    pivot = partition(array, start, end);
    if (pivot - 1 > start) {
      stack[++top] = start;
      stack[++top] = pivot - 1;
    }
    if (pivot + 1 < end) {
      stack[++top] = pivot + 1;
      stack[++top] = end;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<iterative_quicksort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  sub    $0x1,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x1,%ebx
  jmp    L19
L69:
  movslq %r14d,%r14
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  movsd  %xmm0,(%rsp,%r14,8)
  movslq %ebx,%rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rsp,%rcx,8)
L56:
  add    $0x1,%eax
  cmp    %r12d,%eax
  jl     L48
L19:
  test   %ebx,%ebx
  js     L12
  lea    -0x1(%rbx),%r14d
  movslq %ebx,%rax
  cvttsd2si (%rsp,%rax,8),%r12d
  movslq %r14d,%rax
  cvttsd2si (%rsp,%rax,8),%ebp
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %ebp,%edx
  jg     L69
  sub    $0x2,%ebx
  jmp    L56
L48:
  lea    0x1(%rbx),%edx
  movslq %edx,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rsp,%rdx,8)
  add    $0x2,%ebx
  movslq %ebx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  movsd  %xmm0,(%rsp,%rax,8)
  jmp    L19
L12:
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x1f50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iterative_quicksort(double array[], int array_size) {
  double stack[1000];
  int top, start, end, pivot;
  top = -1;
  stack[++top] = 0;
  stack[++top] = array_size - 1;
  while (top >= 0) {
    end = stack[top--];
    start = stack[top--];
    pivot = partition(array, start, end);
    if (pivot - 1 > start) {
      stack[++top] = start;
      stack[++top] = pivot - 1;
    }
    if (pivot + 1 < end) {
      stack[++top] = pivot + 1;
      stack[++top] = end;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iterative_quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf58,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x1,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  sub    $0x1,%esi
  movq   $0x0,(%rsp)
  mov    %rdi,%rbp
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%eax
  sub    $0x2,%r12d
  cmp    %r14d,%eax
  jl     L47
L43:
  test   %r12d,%r12d
  js     L51
L59:
  lea    -0x1(%r12),%ebx
  movslq %r12d,%r15
  mov    %rbp,%rdi
  movslq %ebx,%rbx
  cvttsd2si (%rsp,%r15,8),%r14d
  cvttsd2si (%rsp,%rbx,8),%r13d
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <partition@plt>
  lea    -0x1(%rax),%edx
  cmp    %r13d,%edx
  jle    L11
  pxor   %xmm0,%xmm0
  add    $0x1,%eax
  cvtsi2sd %r13d,%xmm0
  movsd  %xmm0,(%rsp,%rbx,8)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rsp,%r15,8)
  cmp    %r14d,%eax
  jge    L43
L47:
  pxor   %xmm0,%xmm0
  lea    0x1(%r12),%edx
  add    $0x2,%r12d
  cvtsi2sd %eax,%xmm0
  movslq %edx,%rdx
  movslq %r12d,%rax
  movsd  %xmm0,(%rsp,%rdx,8)
  pxor   %xmm0,%xmm0
  cvtsi2sd %r14d,%xmm0
  movsd  %xmm0,(%rsp,%rax,8)
  test   %r12d,%r12d
  jns    L59
  nopl   (%rax)
L51:
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1f58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iterative_quicksort(double array[], int array_size) {
  double stack[1000];
  int top, start, end, pivot;
  top = -1;
  stack[++top] = 0;
  stack[++top] = array_size - 1;
  while (top >= 0) {
    end = stack[top--];
    start = stack[top--];
    pivot = partition(array, start, end);
    if (pivot - 1 > start) {
      stack[++top] = start;
      stack[++top] = pivot - 1;
    }
    if (pivot + 1 < end) {
      stack[++top] = pivot + 1;
      stack[++top] = end;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<iterative_quicksort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf50,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x1,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x1f48(%rsp)
  xor    %eax,%eax
  sub    $0x1,%esi
  movq   $0x0,(%rsp)
  mov    %rdi,%rbp
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%eax
  sub    $0x2,%r12d
  cmp    %r14d,%eax
  jl     L3
L39:
  test   %r12d,%r12d
  js     L26
L29:
  lea    -0x1(%r12),%ebx
  movslq %r12d,%rax
  mov    %rbp,%rdi
  movslq %ebx,%rbx
  cvttsd2si (%rsp,%rax,8),%r14d
  cvttsd2si (%rsp,%rbx,8),%r13d
  mov    %r14d,%edx
  mov    %r13d,%esi
  call   <partition@plt>
  movd   %r13d,%xmm0
  lea    -0x1(%rax),%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  cmp    %r13d,%edx
  jle    L0
  add    $0x1,%eax
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,(%rsp,%rbx,8)
  cmp    %r14d,%eax
  jge    L39
L3:
  lea    0x1(%r12),%edx
  movd   %eax,%xmm0
  movd   %r14d,%xmm2
  add    $0x2,%r12d
  punpckldq %xmm2,%xmm0
  movslq %edx,%rax
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,(%rsp,%rax,8)
  test   %r12d,%r12d
  jns    L29
  nopl   0x0(%rax)
L26:
  mov    0x1f48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x1f50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void iterative_quicksort(double array[], int array_size) {
  double stack[1000];
  int top, start, end, pivot;
  top = -1;
  stack[++top] = 0;
  stack[++top] = array_size - 1;
  while (top >= 0) {
    end = stack[top--];
    start = stack[top--];
    pivot = partition(array, start, end);
    if (pivot - 1 > start) {
      stack[++top] = start;
      stack[++top] = pivot - 1;
    }
    if (pivot + 1 < end) {
      stack[++top] = pivot + 1;
      stack[++top] = end;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bbm_com_bulk_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movzwl -0x20(%rbp),%ecx
  movzwl -0x1c(%rbp),%esi
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bbm_bulk_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
signed int bbm_com_bulk_read(void *handle, unsigned short addr, unsigned char *data, unsigned short size) {
  signed int res;
  res = bbm_bulk_read(handle, addr, data, size);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bbm_com_bulk_read>:
  endbr64
  sub    $0x8,%rsp
  movzwl %cx,%ecx
  movzwl %si,%esi
  call   <bbm_bulk_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed int bbm_com_bulk_read(void *handle, unsigned short addr, unsigned char *data, unsigned short size) {
  signed int res;
  res = bbm_bulk_read(handle, addr, data, size);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<bbm_com_bulk_read>:
  endbr64
  movzwl %cx,%ecx
  movzwl %si,%esi
  jmp    1050 <bbm_bulk_read@plt>
```

assistant: ```c
signed int bbm_com_bulk_read(void *handle, unsigned short addr, unsigned char *data, unsigned short size) {
  signed int res;
  res = bbm_bulk_read(handle, addr, data, size);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bbm_com_bulk_read>:
  endbr64
  movzwl %cx,%ecx
  movzwl %si,%esi
  jmp    1050 <bbm_bulk_read@plt>
```

assistant: ```c
signed int bbm_com_bulk_read(void *handle, unsigned short addr, unsigned char *data, unsigned short size) {
  signed int res;
  res = bbm_bulk_read(handle, addr, data, size);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stricmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L18
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    $0x0,%eax
  jmp    L14
L37:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L32
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stricmp(const char *str1, const char *str2) {
  while (tolower((unsigned char)*str1) == tolower((unsigned char)*str2)) {
    if (!*str1)
      return 0;
    str1++;
    str2++;
  }
  return tolower(*(unsigned char *)str1) - tolower(*(unsigned char *)str2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stricmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  jmp    L33
L2:
  add    $0x1,%rbx
  add    $0x1,%r12
L33:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movzbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L14
  cmpb   $0x0,(%rbx)
  jne    L2
  mov    $0x0,%eax
  jmp    L39
L14:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int stricmp(const char *str1, const char *str2) {
  while (tolower((unsigned char)*str1) == tolower((unsigned char)*str2)) {
    if (!*str1)
      return 0;
    str1++;
    str2++;
  }
  return tolower(*(unsigned char *)str1) - tolower(*(unsigned char *)str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stricmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L18
L14:
  cmpb   $0x0,(%rbx)
  je     L3
  add    $0x1,%rbx
  add    $0x1,%r12
L18:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L14
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int stricmp(const char *str1, const char *str2) {
  while (tolower((unsigned char)*str1) == tolower((unsigned char)*str2)) {
    if (!*str1)
      return 0;
    str1++;
    str2++;
  }
  return tolower(*(unsigned char *)str1) - tolower(*(unsigned char *)str2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stricmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L13
L12:
  cmpb   $0x0,(%rbx)
  je     L10
  add    $0x1,%rbx
  add    $0x1,%r12
L13:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L12
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int stricmp(const char *str1, const char *str2) {
  while (tolower((unsigned char)*str1) == tolower((unsigned char)*str2)) {
    if (!*str1)
      return 0;
    str1++;
    str2++;
  }
  return tolower(*(unsigned char *)str1) - tolower(*(unsigned char *)str2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x18,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D29
data_type: string

tool: D7: x1 = %d


tool: D1: y1 = %u


tool: D29: y3 = %u


assistant: ```c
int main(void) {
  int x1 = 4294967295;
  unsigned int y1 = 4294967295;
  unsigned int y2 = y1 - 16 - 8;
  unsigned int y3 = y2 ^ y1;
  printf("x1 = %d\n", x1);
  printf("y1 = %u\n", y1);
  printf("y3 = %u\n", y3);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string

tool: D6: x1 = %d


tool: D27: y1 = %u


tool: D25: y3 = %u


assistant: ```c
int main(void) {
  int x1 = 4294967295;
  unsigned int y1 = 4294967295;
  unsigned int y2 = y1 - 16 - 8;
  unsigned int y3 = y2 ^ y1;
  printf("x1 = %d\n", x1);
  printf("y1 = %u\n", y1);
  printf("y3 = %u\n", y3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D28
type_infered: string

tool: D11: x1 = %d


tool: D5: y1 = %u


tool: D28: y3 = %u


assistant: ```c
int main(void) {
  int x1 = 4294967295;
  unsigned int y1 = 4294967295;
  unsigned int y2 = y1 - 16 - 8;
  unsigned int y3 = y2 ^ y1;
  printf("x1 = %d\n", x1);
  printf("y1 = %u\n", y1);
  printf("y3 = %u\n", y3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string
name: disassemble_data
arguments: data_tag: D25
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string

tool: D9: x1 = %d


tool: D25: y1 = %u


tool: D17: y3 = %u


assistant: ```c
int main(void) {
  int x1 = 4294967295;
  unsigned int y1 = 4294967295;
  unsigned int y2 = y1 - 16 - 8;
  unsigned int y3 = y2 ^ y1;
  printf("x1 = %d\n", x1);
  printf("y1 = %u\n", y1);
  printf("y3 = %u\n", y3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<render_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <integer_length@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L5
L4:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x3,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <render_byte@plt>
  mov    %rax,-0x20(%rbp)
  subl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *render_integer(int x, void *dest) {
  unsigned i, int_len = integer_length(x);
  for (i = int_len; i >= 1; i--)
    dest = render_byte((x >> (8 * (i - 1))) & 0xFF, dest);
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<render_integer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  call   <integer_length@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L11
L3:
  sub    $0x1,%ebp
  lea    0x0(,%rbp,8),%ecx
  mov    %r12d,%edi
  sar    %cl,%edi
  movzbl %dil,%edi
  mov    %rbx,%rsi
  call   <render_byte@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jne    L3
L11:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *render_integer(int x, void *dest) {
  unsigned i, int_len = integer_length(x);
  for (i = int_len; i >= 1; i--)
    dest = render_byte((x >> (8 * (i - 1))) & 0xFF, dest);
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<render_integer>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <integer_length@plt>
  mov    0x8(%rsp),%rsi
  test   %eax,%eax
  je     L0
  mov    %eax,%ebx
  nopl   0x0(%rax)
L1:
  sub    $0x1,%ebx
  mov    %ebp,%edi
  lea    0x0(,%rbx,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%edi
  call   <render_byte@plt>
  mov    %rax,%rsi
  test   %ebx,%ebx
  jne    L1
L0:
  add    $0x18,%rsp
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *render_integer(int x, void *dest) {
  unsigned i, int_len = integer_length(x);
  for (i = int_len; i >= 1; i--)
    dest = render_byte((x >> (8 * (i - 1))) & 0xFF, dest);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<render_integer>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <integer_length@plt>
  mov    0x8(%rsp),%rsi
  test   %eax,%eax
  je     L14
  mov    %eax,%ebx
  nopl   0x0(%rax)
L4:
  sub    $0x1,%ebx
  mov    %ebp,%edi
  lea    0x0(,%rbx,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%edi
  call   <render_byte@plt>
  mov    %rax,%rsi
  test   %ebx,%ebx
  jne    L4
L14:
  add    $0x18,%rsp
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *render_integer(int x, void *dest) {
  unsigned i, int_len = integer_length(x);
  for (i = int_len; i >= 1; i--)
    dest = render_byte((x >> (8 * (i - 1))) & 0xFF, dest);
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<t2_putcommacode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L17
L14:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <bio_write@plt>
L17:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <bio_write@plt>
  nop
  leave
  ret
```

assistant: ```c
void t2_putcommacode(int n) {
  while (--n >= 0) {
    bio_write(1, 1);
  }
  bio_write(0, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<t2_putcommacode>:
  endbr64
  push   %rbx
  sub    $0x1,%edi
  mov    %edi,%ebx
  js     L13
L10:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <bio_write@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L10
L13:
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <bio_write@plt>
  pop    %rbx
  ret
```

assistant: ```c
void t2_putcommacode(int n) {
  while (--n >= 0) {
    bio_write(1, 1);
  }
  bio_write(0, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t2_putcommacode>:
  endbr64
  sub    $0x1,%edi
  js     L6
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L12:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <bio_write@plt>
  sub    $0x1,%ebx
  jae    L12
  mov    $0x1,%esi
  xor    %edi,%edi
  pop    %rbx
  jmp    1050 <bio_write@plt>
  nopl   0x0(%rax)
L6:
  mov    $0x1,%esi
  xor    %edi,%edi
  jmp    1050 <bio_write@plt>
```

assistant: ```c
void t2_putcommacode(int n) {
  while (--n >= 0) {
    bio_write(1, 1);
  }
  bio_write(0, 1);
}
```