ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D61(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x30(%rbp)
  mov    D41(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    D41(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L4
L35:
  mov    -0x2c(%rbp),%edx
  mov    D59(%rip),%rax
  mov    (%rax),%ecx
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  and    %edx,%eax
  test   %eax,%eax
  jne    L91
  mov    -0x1c(%rbp),%edx
  mov    D59(%rip),%rax
  mov    (%rax),%ecx
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L50
L91:
  mov    $0x0,%eax
  jmp    L27
L50:
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  jns    L74
  mov    $0xffffffff,%eax
  jmp    L27
L74:
  mov    -0x34(%rbp),%eax
  lea    -0x30(%rbp),%rdx
  add    $0x10,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  jns    L4
  mov    $0xffffffff,%eax
  jmp    L27
L4:
  lea    -0x30(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <poll@plt>
  test   %rax,%rax
  jg     L35
  mov    $0xffffffff,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L98
  call   <__stack_chk_fail@plt>
L98:
  leave
  ret
```

assistant: ```c
int loop(int sockfd) {
  struct pollfd pollfds[2];
  pollfds[0].fd = STDIN_FILENO;
  pollfds[0].events = POLLIN;
  pollfds[1].fd = sockfd;
  pollfds[1].events = POLLIN;
  while (poll(pollfds, sizeof(pollfds) / sizeof(pollfds[0]), -1) > 0) {
    if ((pollfds[0].revents & (POLLERR | POLLHUP)) || (pollfds[1].revents & (POLLERR | POLLHUP)))
      return 0;
    if (handle_event(&pollfds[0], sockfd) < 0)
      return -1;
    if (handle_event(&pollfds[1], sockfd) < 0)
      return -1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<loop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rsp)
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  mov    %edi,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rsp,%rbp
L11:
  mov    $0xffffffff,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <poll@plt>
  test   %rax,%rax
  jle    L40
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D39(%rip),%rax
  or     (%rax),%edx
  mov    0x4(%rsp),%eax
  or     0x14(%rsp),%eax
  test   %eax,%edx
  jne    L57
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  js     L47
  lea    0x10(%rsp),%rdi
  mov    %ebx,%esi
  call   <handle_event@plt>
  test   %rax,%rax
  jns    L11
  mov    $0xffffffff,%eax
  jmp    L64
L40:
  mov    $0xffffffff,%eax
L64:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L57:
  mov    $0x0,%eax
  jmp    L64
L47:
  mov    $0xffffffff,%eax
  jmp    L64
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int loop(int sockfd) {
  struct pollfd pollfds[2];
  pollfds[0].fd = STDIN_FILENO;
  pollfds[0].events = POLLIN;
  pollfds[1].fd = sockfd;
  pollfds[1].events = POLLIN;
  while (poll(pollfds, sizeof(pollfds) / sizeof(pollfds[0]), -1) > 0) {
    if ((pollfds[0].revents & (POLLERR | POLLHUP)) || (pollfds[1].revents & (POLLERR | POLLHUP)))
      return 0;
    if (handle_event(&pollfds[0], sockfd) < 0)
      return -1;
    if (handle_event(&pollfds[1], sockfd) < 0)
      return -1;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    D39(%rip),%rax
  mov    %rsp,%rbp
  mov    %edi,0x10(%rsp)
  lea    0x10(%rsp),%r12
  mov    (%rax),%eax
  mov    %eax,(%rsp)
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L25:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  or     (%rax),%edx
  mov    0x4(%rsp),%eax
  or     0x14(%rsp),%eax
  test   %eax,%edx
  jne    L34
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  js     L66
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  js     L66
L47:
  mov    $0xffffffff,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <poll@plt>
  test   %rax,%rax
  jg     L25
L66:
  mov    $0xffffffff,%eax
L61:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  xor    %eax,%eax
  jmp    L61
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int loop(int sockfd) {
  struct pollfd pollfds[2];
  pollfds[0].fd = STDIN_FILENO;
  pollfds[0].events = POLLIN;
  pollfds[1].fd = sockfd;
  pollfds[1].events = POLLIN;
  while (poll(pollfds, sizeof(pollfds) / sizeof(pollfds[0]), -1) > 0) {
    if ((pollfds[0].revents & (POLLERR | POLLHUP)) || (pollfds[1].revents & (POLLERR | POLLHUP)))
      return 0;
    if (handle_event(&pollfds[0], sockfd) < 0)
      return -1;
    if (handle_event(&pollfds[1], sockfd) < 0)
      return -1;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<loop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    D25(%rip),%rax
  mov    %rsp,%rbp
  mov    %edi,0x10(%rsp)
  lea    0x10(%rsp),%r12
  mov    (%rax),%eax
  mov    %eax,(%rsp)
  mov    D23(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x18(%rsp)
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L26:
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D36(%rip),%rax
  or     (%rax),%edx
  mov    0x4(%rsp),%eax
  or     0x14(%rsp),%eax
  test   %eax,%edx
  jne    L39
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  js     L31
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <handle_event@plt>
  test   %rax,%rax
  js     L31
L7:
  mov    $0xffffffff,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <poll@plt>
  test   %rax,%rax
  jg     L26
L31:
  mov    $0xffffffff,%eax
L17:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  jmp    L17
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int loop(int sockfd) {
  struct pollfd pollfds[2];
  pollfds[0].fd = STDIN_FILENO;
  pollfds[0].events = POLLIN;
  pollfds[1].fd = sockfd;
  pollfds[1].events = POLLIN;
  while (poll(pollfds, sizeof(pollfds) / sizeof(pollfds[0]), -1) > 0) {
    if ((pollfds[0].revents & (POLLERR | POLLHUP)) || (pollfds[1].revents & (POLLERR | POLLHUP)))
      return 0;
    if (handle_event(&pollfds[0], sockfd) < 0)
      return -1;
    if (handle_event(&pollfds[1], sockfd) < 0)
      return -1;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L18
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
L65:
  subl   $0x1,-0xc(%rbp)
L97:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L21
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jb     L65
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L81
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  jmp    L81
L51:
  addl   $0x1,-0x10(%rbp)
L81:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L30
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jae    L51
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L5
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
L5:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L97
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L18:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] > x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] <= x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jge    L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r11d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,8),%r8
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%rdx
  lea    -0x1(%r12),%ecx
  mov    %r12d,%esi
  mov    %r11d,%ebx
  jmp    L30
L58:
  mov    %esi,%r10d
  cmp    %esi,%ebx
  jge    L85
  lea    0x1(%rbx),%eax
  movslq %ebx,%rbx
  mov    %rdi,0x0(%rbp,%rbx,8)
  cmp    %esi,%eax
  jge    L40
  cltq
L97:
  mov    %eax,%ebx
  cmp    %r8,0x0(%rbp,%rax,8)
  ja     L116
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%r10d
  jg     L97
L85:
  movslq %ebx,%rax
  mov    %r8,0x0(%rbp,%rax,8)
  lea    -0x1(%rbx),%edx
  mov    %r11d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L116:
  cmp    %r10d,%eax
  jge    L85
  cltq
  mov    0x0(%rbp,%rax,8),%rax
  mov    %rax,(%r9)
  cmp    %ebx,%ecx
  jle    L85
L18:
  sub    $0x8,%rdx
  sub    $0x1,%ecx
  sub    $0x1,%esi
L30:
  mov    %rdx,%r9
  mov    (%rdx),%rdi
  cmp    %r8,%rdi
  jbe    L58
  cmp    %ebx,%ecx
  jg     L18
  jmp    L85
L40:
  mov    %eax,%ebx
  jmp    L85
L16:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] > x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] <= x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L13
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L106:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,8),%rdi
  nopw   0x0(%rax,%rax,1)
L69:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%rcx),%rax
  cmp    %rdi,%rax
  jbe    L4
  sub    $0x1,%edx
  sub    $0x8,%rcx
  cmp    %r8d,%edx
  jg     L29
L55:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L68:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %rdi,0x0(%rbp,%rax,8)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L106
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L4:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,8),%rsi
  cmp    %edx,%r8d
  jge    L55
  mov    %rax,(%rsi)
  cmp    %edx,%ebx
  jge    L68
  movslq %ebx,%rax
  jmp    L46
  nopl   (%rax)
L25:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L68
L46:
  mov    0x0(%rbp,%rax,8),%rsi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %rdi,%rsi
  jbe    L25
  sub    $0x1,%edx
  mov    %rsi,(%rcx)
  cmp    %edx,%eax
  jl     L69
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L68
  xchg   %ax,%ax
L13:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] > x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] <= x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_sort>:
  endbr64
  cmp    %esi,%edx
  jle    L104
  push   %r12
  mov    %esi,%r9d
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
L46:
  movslq %r9d,%rax
  mov    %r12d,%edx
  mov    %r9d,%r8d
  mov    0x0(%rbp,%rax,8),%rdi
  nopw   0x0(%rax,%rax,1)
L7:
  movslq %edx,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  nopl   0x0(%rax,%rax,1)
L67:
  mov    (%rcx),%rax
  cmp    %rdi,%rax
  jbe    L16
  sub    $0x1,%edx
  sub    $0x8,%rcx
  cmp    %r8d,%edx
  jg     L67
L34:
  mov    %r8d,%ebx
  sub    $0x1,%r8d
L60:
  movslq %ebx,%rax
  mov    %r9d,%esi
  mov    %r8d,%edx
  mov    %rdi,0x0(%rbp,%rax,8)
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r9d
  cmp    %r12d,%r9d
  jl     L46
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L16:
  movslq %r8d,%rsi
  lea    0x1(%r8),%ebx
  lea    0x0(%rbp,%rsi,8),%rsi
  cmp    %edx,%r8d
  jge    L34
  mov    %rax,(%rsi)
  cmp    %edx,%ebx
  jge    L60
  movslq %ebx,%rax
  jmp    L43
  nopl   (%rax)
L64:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L60
L43:
  mov    0x0(%rbp,%rax,8),%rsi
  mov    %eax,%r8d
  lea    0x1(%rax),%ebx
  cmp    %rdi,%rsi
  jbe    L64
  sub    $0x1,%edx
  mov    %rsi,(%rcx)
  cmp    %edx,%eax
  jl     L7
  mov    %eax,%ebx
  sub    $0x1,%r8d
  jmp    L60
  xchg   %ax,%ax
L104:
  ret
```

assistant: ```c
void quick_sort(unsigned long long s[], int l, int r) {
  if (l < r) {
    int i = l, j = r;
    unsigned long long x = s[l];
    while (i < j) {
      while (i < j && s[j] > x)
        j--;
      if (i < j)
        s[i++] = s[j];
      while (i < j && s[i] <= x)
        i++;
      if (i < j)
        s[j--] = s[i];
    }
    s[i] = x;
    quick_sort(s, l, i - 1);
    quick_sort(s, i + 1, r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_num_to_coor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L14:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,(%rcx)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void convert_num_to_coor(int num, int n, int d, int *coor) {
  int i;
  for (i = 0; i < d; i++) {
    coor[i] = num / ((int)pow(n, (d - 1 - i)));
    num = num % ((int)pow(n, (d - 1 - i)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_num_to_coor>:
  endbr64
  test   %edx,%edx
  jle    L0
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,%r15
  lea    0x1(%rdx),%eax
  mov    %rax,0x8(%rsp)
  mov    $0x1,%ebp
L2:
  mov    %r14d,%r12d
  sub    %ebp,%r12d
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x4(%r15,%rbp,4)
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %rax,%rcx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%ebx
  add    $0x1,%rbp
  cmp    0x8(%rsp),%rbp
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  ret
```

assistant: ```c
void convert_num_to_coor(int num, int n, int d, int *coor) {
  int i;
  for (i = 0; i < d; i++) {
    coor[i] = num / ((int)pow(n, (d - 1 - i)));
    num = num % ((int)pow(n, (d - 1 - i)));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convert_num_to_coor>:
  endbr64
  test   %edx,%edx
  jle    L8
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  lea    -0x1(%rdx),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L7:
  mov    %ebp,%esi
  mov    %r13d,%edi
  add    $0x4,%r12
  call   <pow@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  sub    $0x1,%ebp
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,-0x4(%r12)
  call   <pow@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%ebx
  cmp    $0xffffffff,%ebp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void convert_num_to_coor(int num, int n, int d, int *coor) {
  int i;
  for (i = 0; i < d; i++) {
    coor[i] = num / ((int)pow(n, (d - 1 - i)));
    num = num % ((int)pow(n, (d - 1 - i)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_num_to_coor>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  lea    -0x1(%rdx),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  mov    %ebp,%esi
  mov    %r13d,%edi
  add    $0x4,%r12
  call   <pow@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  sub    $0x1,%ebp
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,-0x4(%r12)
  call   <pow@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %edx,%ebx
  cmp    $0xffffffff,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
void convert_num_to_coor(int num, int n, int d, int *coor) {
  int i;
  for (i = 0; i < d; i++) {
    coor[i] = num / ((int)pow(n, (d - 1 - i)));
    num = num % ((int)pow(n, (d - 1 - i)));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<css_debug_objs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L18
L7:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <css_debug_obj@plt>
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L24
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L7
L24:
  nop
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D16: <NULL>

tool: D9:  | 

assistant: ```c
void css_debug_objs(FILE *fp, struct Obj **objs) {
  int i = 0;
  struct Obj *obj = objs[i];
  if (!obj) {
    fprintf(fp, "<NULL>");
    return;
  }
  for (;;) {
    css_debug_obj(fp, obj);
    obj = objs[++i];
    if (!obj)
      break;
    fprintf(fp, " | ");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<css_debug_objs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    (%rsi),%rbp
  test   %rbp,%rbp
  je     L15
  lea    0x8(%rsi),%rbx
  lea    D18(%rip),%r13
  jmp    L37
L15:
  lea    D0(%rip),%rsi
  call   <fprintf@plt>
  jmp    L24
L27:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
L37:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <css_debug_obj@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rbp
  test   %rbp,%rbp
  jne    L27
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D18:  | 

tool: D0: <NULL>

assistant: ```c
void css_debug_objs(FILE *fp, struct Obj **objs) {
  int i = 0;
  struct Obj *obj = objs[i];
  if (!obj) {
    fprintf(fp, "<NULL>");
    return;
  }
  for (;;) {
    css_debug_obj(fp, obj);
    obj = objs[++i];
    if (!obj)
      break;
    fprintf(fp, " | ");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<css_debug_objs>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  test   %rbp,%rbp
  je     L8
  lea    0x8(%rsi),%rbx
  lea    D13(%rip),%r13
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <css_debug_obj@plt>
  mov    -0x8(%rbx),%rbp
  test   %rbp,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L8:
  add    $0x8,%rsp
  lea    D18(%rip),%rsi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string

tool: D13:  | 

tool: D18: <NULL>

assistant: ```c
void css_debug_objs(FILE *fp, struct Obj **objs) {
  int i = 0;
  struct Obj *obj = objs[i];
  if (!obj) {
    fprintf(fp, "<NULL>");
    return;
  }
  for (;;) {
    css_debug_obj(fp, obj);
    obj = objs[++i];
    if (!obj)
      break;
    fprintf(fp, " | ");
  }
}
```