ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D64(%rip),%rdi
  call   <scanf@plt>
  lea    D79(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x4,%eax
  ja     L26
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%eax
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D64
data_type: string
name: unpack_data
arguments: tag: D79
data_type: string

tool: D18: 
Selecciona una opcion: 


tool: D19: [1] Obtener una raiz de grado n


tool: D21: [2] Resolver una ecuacion de segundo grado


tool: D46: [3] Mostrar los senos y cosenos de 30, 45, 60 y 90 grados


tool: D15: [4] Salir


tool: D17: Opcion: 

tool: D64: %d

tool: D79: 


assistant: ```c
int menu() {
  printf("\nSelecciona una opcion: \n");
  printf("[1] Obtener una raiz de grado n\n");
  printf("[2] Resolver una ecuacion de segundo grado\n");
  printf("[3] Mostrar los senos y cosenos de 30, 45, 60 y 90 grados\n");
  printf("[4] Salir\n");
  printf("Opcion: ");
  int n;
  scanf("%d", &n);
  printf("\n");
  if (n < 0 || n > 4)
    return -1;
  else
    return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<menu>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D60(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x4,%eax
  ja     L25
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
  jmp    L23
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D60
type_infered: string
name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D37
type_infered: string
name: unpack_data
arguments: data_label: D48
type_infered: string

tool: D7: 
Selecciona una opcion: 


tool: D29: [1] Obtener una raiz de grado n


tool: D43: [2] Resolver una ecuacion de segundo grado


tool: D60: [3] Mostrar los senos y cosenos de 30, 45, 60 y 90 grados


tool: D38: [4] Salir


tool: D13: Opcion: 

tool: D37: %d

tool: D48: 


assistant: ```c
int menu() {
  printf("\nSelecciona una opcion: \n");
  printf("[1] Obtener una raiz de grado n\n");
  printf("[2] Resolver una ecuacion de segundo grado\n");
  printf("[3] Mostrar los senos y cosenos de 30, 45, 60 y 90 grados\n");
  printf("[4] Salir\n");
  printf("Opcion: ");
  int n;
  scanf("%d", &n);
  printf("\n");
  if (n < 0 || n > 4)
    return -1;
  else
    return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L8
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x34(%rbp),%eax
  jmp    L28
L8:
  mov    $0x0,%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string

tool: D7: %s/file%d

tool: D16: unlink

assistant: ```c
int remove_file(const char *dir, int n) {
  int ret;
  char name[32];
  snprintf(name, sizeof(name), "%s/file%d", dir, n);
  ret = unlink(name);
  if (ret < 0) {
    perror("unlink");
    return ret;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_file>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rcx
  mov    %esi,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D14(%rip),%rdx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    $0x0,%ebx
  test   %eax,%eax
  js     L22
L20:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %ebx,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L22:
  mov    %eax,%ebx
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L20
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D14: %s/file%d

tool: D2: unlink

assistant: ```c
int remove_file(const char *dir, int n) {
  int ret;
  char name[32];
  snprintf(name, sizeof(name), "%s/file%d", dir, n);
  ret = unlink(name);
  if (ret < 0) {
    perror("unlink");
    return ret;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<remove_file>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  mov    %esi,%r8d
  lea    D5(%rip),%rdx
  mov    $0x20,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <unlink@plt>
  test   %eax,%eax
  js     L7
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L7:
  lea    D14(%rip),%rdi
  mov    %eax,%r12d
  call   <perror@plt>
  jmp    L17
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string

tool: D5: %s/file%d

tool: D14: unlink

assistant: ```c
int remove_file(const char *dir, int n) {
  int ret;
  char name[32];
  snprintf(name, sizeof(name), "%s/file%d", dir, n);
  ret = unlink(name);
  if (ret < 0) {
    perror("unlink");
    return ret;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<remove_file>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  mov    %esi,%r8d
  lea    D11(%rip),%rdx
  mov    $0x20,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <unlink@plt>
  test   %eax,%eax
  js     L6
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L6:
  lea    D19(%rip),%rdi
  mov    %eax,%r12d
  call   <perror@plt>
  jmp    L2
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: string
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D11: %s/file%d

tool: D19: unlink

assistant: ```c
int remove_file(const char *dir, int n) {
  int ret;
  char name[32];
  snprintf(name, sizeof(name), "%s/file%d", dir, n);
  ret = unlink(name);
  if (ret < 0) {
    perror("unlink");
    return ret;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<init_server>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <isns_security_init@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x0,%eax
  jmp    L4
L7:
  mov    $0x1,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int init_server(void) {
  if (!isns_security_init())
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<init_server>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <isns_security_init@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int init_server(void) {
  if (!isns_security_init())
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_server>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isns_security_init@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int init_server(void) {
  if (!isns_security_init())
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_server>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isns_security_init@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int init_server(void) {
  if (!isns_security_init())
    return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decode_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L47
  cmpb   $0x39,-0x4(%rbp)
  jg     L47
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L37
L47:
  cmpb   $0x60,-0x4(%rbp)
  jle    L68
  cmpb   $0x7a,-0x4(%rbp)
  jg     L68
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L37
L68:
  cmpb   $0x40,-0x4(%rbp)
  jle    L12
  cmpb   $0x5a,-0x4(%rbp)
  jg     L12
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L37
L12:
  mov    $0xffffffff,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int decode_digit(digitchar)
char digitchar;
{
  if ('0' <= digitchar && digitchar <= '9')
    return digitchar - '0';
  if ('a' <= digitchar && digitchar <= 'z')
    return digitchar - 'a' + 10;
  if ('A' <= digitchar && digitchar <= 'Z')
    return digitchar - 'A' + 10;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L14
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L3
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x1a,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L14:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L3:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int decode_digit(digitchar)
char digitchar;
{
  if ('0' <= digitchar && digitchar <= '9')
    return digitchar - '0';
  if ('a' <= digitchar && digitchar <= 'z')
    return digitchar - 'a' + 10;
  if ('A' <= digitchar && digitchar <= 'Z')
    return digitchar - 'A' + 10;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<decode_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L11
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x1a,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl %al,%eax
  ret
```

assistant: ```c
int decode_digit(digitchar)
char digitchar;
{
  if ('0' <= digitchar && digitchar <= '9')
    return digitchar - '0';
  if ('a' <= digitchar && digitchar <= 'z')
    return digitchar - 'a' + 10;
  if ('A' <= digitchar && digitchar <= 'Z')
    return digitchar - 'A' + 10;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decode_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L18
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x1a,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl %al,%eax
  ret
```

assistant: ```c
int decode_digit(digitchar)
char digitchar;
{
  if ('0' <= digitchar && digitchar <= '9')
    return digitchar - '0';
  if ('a' <= digitchar && digitchar <= 'z')
    return digitchar - 'a' + 10;
  if ('A' <= digitchar && digitchar <= 'Z')
    return digitchar - 'A' + 10;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ssl_get_error_description>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  call   <ERR_get_error@plt>
  mov    %rax,-0x8(%rbp)
L21:
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L14
L25:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ERR_error_string_n@plt>
  mov    $0x1,%eax
L14:
  leave
  ret
```

assistant: ```c
int ssl_get_error_description(unsigned long error, char *buffer, size_t length) {
  if (SSL_ERROR_NONE == error)
    error = ERR_get_error();
  if (SSL_ERROR_NONE == error)
    return 0;
  ERR_error_string_n(error, buffer, length);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssl_get_error_description>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    D0(%rip),%rax
  cmp    %rdi,(%rax)
  je     L3
L11:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <ERR_error_string_n@plt>
  mov    $0x1,%eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%eax
  call   <ERR_get_error@plt>
  mov    %rax,%rdi
  mov    D0(%rip),%rax
  cmp    %rdi,(%rax)
  jne    L11
  mov    $0x0,%eax
  jmp    L21
```

assistant: ```c
int ssl_get_error_description(unsigned long error, char *buffer, size_t length) {
  if (SSL_ERROR_NONE == error)
    error = ERR_get_error();
  if (SSL_ERROR_NONE == error)
    return 0;
  ERR_error_string_n(error, buffer, length);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssl_get_error_description>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    D6(%rip),%rbx
  cmp    %rdi,(%rbx)
  je     L5
L0:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <ERR_error_string_n@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  xor    %eax,%eax
  call   <ERR_get_error@plt>
  mov    %rax,%rdi
  cmp    %rax,(%rbx)
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ssl_get_error_description(unsigned long error, char *buffer, size_t length) {
  if (SSL_ERROR_NONE == error)
    error = ERR_get_error();
  if (SSL_ERROR_NONE == error)
    return 0;
  ERR_error_string_n(error, buffer, length);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssl_get_error_description>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    D8(%rip),%rbx
  cmp    %rdi,(%rbx)
  je     L0
L12:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <ERR_error_string_n@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  xor    %eax,%eax
  call   <ERR_get_error@plt>
  mov    %rax,%rdi
  cmp    %rax,(%rbx)
  jne    L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int ssl_get_error_description(unsigned long error, char *buffer, size_t length) {
  if (SSL_ERROR_NONE == error)
    error = ERR_get_error();
  if (SSL_ERROR_NONE == error)
    return 0;
  ERR_error_string_n(error, buffer, length);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_111_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  notb   -0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_111_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_111_0_0>:
  endbr64
  xor    (%rdi),%sil
  not    %edx
  or     %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_111_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_111_0_0>:
  endbr64
  xor    (%rdi),%sil
  not    %edx
  or     %edx,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_111_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lgamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <lgamma_r@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double lgamma(double __d) {
  signed int __local_signgam = 0;
  double return_value_lgamma_r$1;
  return_value_lgamma_r$1 = lgamma_r(__d, &__local_signgam);
  return return_value_lgamma_r$1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lgamma>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <lgamma_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double lgamma(double __d) {
  signed int __local_signgam = 0;
  double return_value_lgamma_r$1;
  return_value_lgamma_r$1 = lgamma_r(__d, &__local_signgam);
  return return_value_lgamma_r$1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lgamma>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <lgamma_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double lgamma(double __d) {
  signed int __local_signgam = 0;
  double return_value_lgamma_r$1;
  return_value_lgamma_r$1 = lgamma_r(__d, &__local_signgam);
  return return_value_lgamma_r$1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lgamma>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <lgamma_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double lgamma(double __d) {
  signed int __local_signgam = 0;
  double return_value_lgamma_r$1;
  return_value_lgamma_r$1 = lgamma_r(__d, &__local_signgam);
  return return_value_lgamma_r$1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<z_now_ms_sprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <z_ms_sprint@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void z_now_ms_sprint(char *buf) {
  struct timeval t;
  gettimeofday(&t, NULL);
  z_ms_sprint(&t, buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<z_now_ms_sprint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <z_ms_sprint@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_now_ms_sprint(char *buf) {
  struct timeval t;
  gettimeofday(&t, NULL);
  z_ms_sprint(&t, buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<z_now_ms_sprint>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <z_ms_sprint@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_now_ms_sprint(char *buf) {
  struct timeval t;
  gettimeofday(&t, NULL);
  z_ms_sprint(&t, buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<z_now_ms_sprint>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <z_ms_sprint@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void z_now_ms_sprint(char *buf) {
  struct timeval t;
  gettimeofday(&t, NULL);
  z_ms_sprint(&t, buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L5
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: Press [ENTER] to continue


assistant: ```c
void wait() {
  printf("Press [ENTER] to continue\n");
  while (getchar() != '\n')
    ;
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wait>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L5
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D4: Press [ENTER] to continue


assistant: ```c
void wait() {
  printf("Press [ENTER] to continue\n");
  while (getchar() != '\n')
    ;
  getchar();
}
```