ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_isfloat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L29
L7:
  xor    %r12d,%r12d
L37:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  mov    $0x2,%r13d
  test   %dil,%dil
  je     L41
L45:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L40
  cmpb   $0x2e,(%rbx)
  jne    L70
  test   %r12d,%r12d
  jne    L70
  mov    $0x1,%r12d
L40:
  movslq %r13d,%rbx
  add    $0x1,%r13d
  add    %rbp,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
L41:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L70:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L7
  cmpb   $0x2e,0x0(%rbp)
  jne    L70
  mov    $0x1,%r12d
  jmp    L37
```

assistant: ```c
int string_isfloat(const char *str) {
  int seen_dp = 0;
  int i = 1;
  if (str[0] != '-' && str[0] != '+' && isdigit((int)str[0]) == 0) {
    if (str[0] == '.') {
      seen_dp = 1;
    } else
      return 0;
  }
  while (str[i] != '\0') {
    if (isdigit((int)str[i]) != 0) {
      i++;
      continue;
    } else if (str[i] == '.') {
      if (seen_dp == 1) {
        return 0;
      }
      i++;
      seen_dp = 1;
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_isfloat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L46
L2:
  xor    %r12d,%r12d
L9:
  movsbl 0x1(%rbp),%edi
  lea    0x1(%rbp),%rbx
  mov    $0x2,%r13d
  test   %dil,%dil
  je     L65
L36:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L59
  cmpb   $0x2e,(%rbx)
  jne    L5
  test   %r12d,%r12d
  jne    L5
  mov    $0x1,%r12d
L59:
  movslq %r13d,%rbx
  add    $0x1,%r13d
  add    %rbp,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L36
L65:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L46:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L2
  cmpb   $0x2e,0x0(%rbp)
  jne    L5
  mov    $0x1,%r12d
  jmp    L9
```

assistant: ```c
int string_isfloat(const char *str) {
  int seen_dp = 0;
  int i = 1;
  if (str[0] != '-' && str[0] != '+' && isdigit((int)str[0]) == 0) {
    if (str[0] == '.') {
      seen_dp = 1;
    } else
      return 0;
  }
  while (str[i] != '\0') {
    if (isdigit((int)str[i]) != 0) {
      i++;
      continue;
    } else if (str[i] == '.') {
      if (seen_dp == 1) {
        return 0;
      }
      i++;
      seen_dp = 1;
      continue;
    }
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L15
L1:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L40:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L0
  mov    -0x10(%rbp),%rax
  jmp    L44
L0:
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *p1;
  const char *p2;
  p1 = s1;
  while (*p1 != '\0') {
    p2 = s2;
    while (*p2 != '\0') {
      if (*p1 == *p2)
        return ((char *)p1);
      p2++;
    }
    p1++;
  }
  return (((void *)0));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L42
  movzbl (%rsi),%edi
L9:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  je     L4
L25:
  cmp    %r8b,%dl
  je     L15
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L25
L4:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L9
  mov    $0x0,%eax
L15:
  ret
L42:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *p1;
  const char *p2;
  p1 = s1;
  while (*p1 != '\0') {
    p2 = s2;
    while (*p2 != '\0') {
      if (*p1 == *p2)
        return ((char *)p1);
      p2++;
    }
    p1++;
  }
  return (((void *)0));
}
```
user: What is the c source code of the assembly code below?

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L41
  movzbl (%rsi),%edi
L57:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L47
  jmp    L20
  nop
L32:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L20
L47:
  cmp    %r8b,%dl
  jne    L32
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L57
L41:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *p1;
  const char *p2;
  p1 = s1;
  while (*p1 != '\0') {
    p2 = s2;
    while (*p2 != '\0') {
      if (*p1 == *p2)
        return ((char *)p1);
      p2++;
    }
    p1++;
  }
  return (((void *)0));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L19
  movzbl (%rsi),%edi
L52:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L5
  jmp    L46
  nop
L35:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L46
L5:
  cmp    %r8b,%dl
  jne    L35
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L52
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *p1;
  const char *p2;
  p1 = s1;
  while (*p1 != '\0') {
    p2 = s2;
    while (*p2 != '\0') {
      if (*p1 == *p2)
        return ((char *)p1);
      p2++;
    }
    p1++;
  }
  return (((void *)0));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ln_get_lunar_sdiam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_lunar_earth_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: f64

tool: D6: 358473400

assistant: ```c
double ln_get_lunar_sdiam(double JD) {
  double So = 358473400;
  double dist;
  dist = ln_get_lunar_earth_dist(JD);
  return So / dist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ln_get_lunar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_lunar_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D8(%rip),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: f64

tool: D8: 358473400

assistant: ```c
double ln_get_lunar_sdiam(double JD) {
  double So = 358473400;
  double dist;
  dist = ln_get_lunar_earth_dist(JD);
  return So / dist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ln_get_lunar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_lunar_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: f64

tool: D2: 358473400

assistant: ```c
double ln_get_lunar_sdiam(double JD) {
  double So = 358473400;
  double dist;
  dist = ln_get_lunar_earth_dist(JD);
  return So / dist;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ln_get_lunar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_lunar_earth_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D7(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: f64

tool: D7: 358473400

assistant: ```c
double ln_get_lunar_sdiam(double JD) {
  double So = 358473400;
  double dist;
  dist = ln_get_lunar_earth_dist(JD);
  return So / dist;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movl   $0xa,-0x28(%rbp)
  movl   $0x14,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x2c(%rbp),%rdx
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%eax
  lea    -0x28(%rbp),%rdx
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  lea    -0x24(%rbp),%rdx
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x18(%rbp),%rdx
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D37
datatype: string
name: unpack_data
arguments: data_tag: D22
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D41
datatype: string

tool: D37: int x value : %d, int x address : %p


tool: D22: int y value : %d, int y address : %p


tool: D39: int z value : %d, int z address : %p


tool: D15: int *a value : %d, int *a address : %p


tool: D10: int *b value : %d, int *b address : %p


tool: D41: int *c value : %d, int *c address : %p


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 0;
  int y = 10;
  int z = 20;
  printf("int x value : %d, int x address : %p\n", x, &x);
  printf("int y value : %d, int y address : %p\n", y, &y);
  printf("int z value : %d, int z address : %p\n", z, &z);
  int *a = &x;
  int *b = &y;
  int *c = &z;
  printf("int *a value : %d, int *a address : %p\n", *a, &a);
  printf("int *b value : %d, int *b address : %p\n", *b, &b);
  printf("int *c value : %d, int *c address : %p\n", *c, &c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0xa,0x8(%rsp)
  movl   $0x14,0xc(%rsp)
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  mov    $0x0,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rbp
  mov    %rbp,%rdx
  mov    0x8(%rsp),%esi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdx
  mov    0xc(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,0x10(%rsp)
  mov    %rbp,0x18(%rsp)
  mov    %rbx,0x20(%rsp)
  lea    0x10(%rsp),%rdx
  mov    0x4(%rsp),%esi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rdx
  mov    0x18(%rsp),%rax
  mov    (%rax),%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rdx
  mov    0x20(%rsp),%rax
  mov    (%rax),%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D31
type: string
name: disassemble_data
arguments: tag: D43
type: string
name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D56
type: string
name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D0
type: string

tool: D31: int x value : %d, int x address : %p


tool: D43: int y value : %d, int y address : %p


tool: D19: int z value : %d, int z address : %p


tool: D56: int *a value : %d, int *a address : %p


tool: D12: int *b value : %d, int *b address : %p


tool: D0: int *c value : %d, int *c address : %p


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 0;
  int y = 10;
  int z = 20;
  printf("int x value : %d, int x address : %p\n", x, &x);
  printf("int y value : %d, int y address : %p\n", y, &y);
  printf("int z value : %d, int z address : %p\n", z, &z);
  int *a = &x;
  int *b = &y;
  int *c = &z;
  printf("int *a value : %d, int *a address : %p\n", *a, &a);
  printf("int *b value : %d, int *b address : %p\n", *b, &b);
  printf("int *c value : %d, int *c address : %p\n", *c, &c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  lea    D41(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x8(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  mov    %r12,%rdx
  movl   $0xa,0x8(%rsp)
  lea    0xc(%rsp),%rbx
  movl   $0x14,0xc(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdx
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    0x10(%rsp),%rdx
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  mov    %r12,0x10(%rsp)
  mov    %rbp,0x18(%rsp)
  mov    %rbx,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    0x18(%rsp),%rdx
  lea    D29(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  lea    0x20(%rsp),%rdx
  lea    D25(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D41
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D48
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string

tool: D41: int x value : %d, int x address : %p


tool: D36: int y value : %d, int y address : %p


tool: D48: int z value : %d, int z address : %p


tool: D1: int *a value : %d, int *a address : %p


tool: D29: int *b value : %d, int *b address : %p


tool: D25: int *c value : %d, int *c address : %p


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 0;
  int y = 10;
  int z = 20;
  printf("int x value : %d, int x address : %p\n", x, &x);
  printf("int y value : %d, int y address : %p\n", y, &y);
  printf("int z value : %d, int z address : %p\n", z, &z);
  int *a = &x;
  int *b = &y;
  int *c = &z;
  printf("int *a value : %d, int *a address : %p\n", *a, &a);
  printf("int *b value : %d, int *b address : %p\n", *b, &b);
  printf("int *c value : %d, int *c address : %p\n", *c, &c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  lea    D10(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    0x8(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  mov    %r12,%rdx
  movl   $0xa,0x8(%rsp)
  lea    0xc(%rsp),%rbx
  movl   $0x14,0xc(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdx
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    0x10(%rsp),%rdx
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  mov    %r12,0x10(%rsp)
  mov    %rbp,0x18(%rsp)
  mov    %rbx,0x20(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    0x18(%rsp),%rdx
  lea    D30(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%rax
  lea    0x20(%rsp),%rdx
  lea    D2(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D7
data_type: string
name: disassemble_data
arguments: data_tag: D5
data_type: string
name: disassemble_data
arguments: data_tag: D30
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D10: int x value : %d, int x address : %p


tool: D18: int y value : %d, int y address : %p


tool: D7: int z value : %d, int z address : %p


tool: D5: int *a value : %d, int *a address : %p


tool: D30: int *b value : %d, int *b address : %p


tool: D2: int *c value : %d, int *c address : %p


assistant: ```c
int main(int argc, char *argv[]) {
  int x = 0;
  int y = 10;
  int z = 20;
  printf("int x value : %d, int x address : %p\n", x, &x);
  printf("int y value : %d, int y address : %p\n", y, &y);
  printf("int z value : %d, int z address : %p\n", z, &z);
  int *a = &x;
  int *b = &y;
  int *c = &z;
  printf("int *a value : %d, int *a address : %p\n", *a, &a);
  printf("int *b value : %d, int *b address : %p\n", *b, &b);
  printf("int *c value : %d, int *c address : %p\n", *c, &c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readHB_newmat_double>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r15
  mov    %rcx,%rbx
  mov    %r8,%r12
  mov    %r9,%r13
  mov    0x60(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <readHB_info@plt>
  mov    (%r15),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L16
L53:
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L8
L46:
  mov    0x10(%rsp),%rax
  movzbl (%rax),%eax
  cmp    $0x43,%al
  je     L55
  cmp    $0x50,%al
  jne    L26
L76:
  mov    (%r14),%rcx
  mov    0x0(%r13),%rdx
  mov    (%r12),%rsi
  mov    %rbp,%rdi
  call   <readHB_mat_double@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  lea    D26(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L53
L8:
  lea    D13(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L46
L55:
  mov    (%rbx),%edi
  shl    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L76
  lea    D28(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L76
L26:
  mov    (%rbx),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L76
  lea    D28(%rip),%rdi
  call   <IOHBTerminate@plt>
  jmp    L76
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D13
type: string
name: read_data
arguments: data_tag: D28
type: string

tool: D26: Insufficient memory for colptr.


tool: D13: Insufficient memory for rowind.


tool: D28: Insufficient memory for val.


assistant: ```c
int readHB_newmat_double(const char *filename, int *M, int *N, int *nonzeros, int **colptr, int **rowind, double **val) {
  int Nrhs;
  char *Type;
  readHB_info(filename, M, N, nonzeros, &Type, &Nrhs);
  *colptr = (int *)malloc((*N + 1) * sizeof(int));
  if (*colptr == NULL)
    IOHBTerminate("Insufficient memory for colptr.\n");
  *rowind = (int *)malloc(*nonzeros * sizeof(int));
  if (*rowind == NULL)
    IOHBTerminate("Insufficient memory for rowind.\n");
  if (Type[0] == 'C') {
    *val = (double *)malloc(*nonzeros * sizeof(double) * 2);
    if (*val == NULL)
      IOHBTerminate("Insufficient memory for val.\n");
  } else {
    if (Type[0] != 'P') {
      *val = (double *)malloc(*nonzeros * sizeof(double));
      if (*val == NULL)
        IOHBTerminate("Insufficient memory for val.\n");
    }
  }
  return readHB_mat_double(filename, *colptr, *rowind, *val);
}
```