ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<StrConcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <assert@plt>
  cmpb   $0x0,(%r12)
  mov    %r12,%rax
  je     L37
  nopl   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L25
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L7
L5:
  mov    %dl,(%rax)
  add    $0x1,%rbx
  add    $0x1,%rax
L37:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L5
L7:
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *StrConcat(char *pcDest, const char *pcSrc) {
  assert(pcDest);
  assert(pcSrc);
  char *pc = pcDest;
  while (*pc != '\0') {
    pc++;
  }
  while (*pcSrc != '\0') {
    *pc = *pcSrc;
    pcSrc++;
    pc++;
  }
  *pc = '\0';
  return pcDest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_cmpge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0xfffffffe,%esi
  mov    %eax,%edi
  call   <emit_andimm@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmp@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_orrge_imm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_cmpge(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s2, s1);
  emit_orrge_imm(sr, 1, sr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<emit_cmpge>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    $0xfffffffe,%esi
  mov    %edx,%edi
  call   <emit_andimm@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <emit_cmp@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_orrge_imm@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void emit_cmpge(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s2, s1);
  emit_orrge_imm(sr, 1, sr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<emit_cmpge>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %edx,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0xfffffffe,%esi
  push   %rbp
  mov    %edx,%ebp
  call   <emit_andimm@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmp@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <emit_orrge_imm@plt>
```

assistant: ```c
void emit_cmpge(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s2, s1);
  emit_orrge_imm(sr, 1, sr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emit_cmpge>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %edx,%edi
  push   %r12
  mov    %esi,%r12d
  mov    $0xfffffffe,%esi
  push   %rbp
  mov    %edx,%ebp
  call   <emit_andimm@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmp@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <emit_orrge_imm@plt>
```

assistant: ```c
void emit_cmpge(int s1, int s2, int sr, int temp) {
  emit_andimm(sr, ~1, sr);
  emit_cmp(s2, s1);
  emit_orrge_imm(sr, 1, sr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bi_sftadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x3c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L54
L28:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L54:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L28
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L33
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L9
  movq   $0x0,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L15
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  mov    %edx,%edx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  shr    $0x20,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int bi_sftadd(int a_len, unsigned long *a_data, int b_len, unsigned long *b_data, int s_len) {
  unsigned long carry;
  unsigned long long sum;
  int i, b_len_s, len_max;
  b_len_s = b_len + s_len;
  len_max = (a_len < b_len_s) ? b_len_s : a_len;
  for (i = a_len; i < len_max; i++)
    a_data[i] = 0;
  for (i = b_len; i < len_max - s_len; i++)
    b_data[i] = 0;
  carry = 0;
  for (i = s_len; i < len_max; i++) {
    sum = a_data[i];
    sum = sum + b_data[i - s_len] + carry;
    a_data[i] = (unsigned long)(sum & (((unsigned long long)0x1 << 32) - 1));
    carry = (unsigned long)(sum >> 32);
  }
  a_data[len_max] = carry;
  return len_max + carry;
}
```
user: What is the c source code of the assembly code below:

```asm
<bi_sftadd>:
  endbr64
  mov    %edx,%r9d
  mov    %rcx,%r10
  lea    (%rdx,%r8,1),%eax
  cmp    %edi,%eax
  cmovl  %edi,%eax
  cmp    %eax,%edi
  jge    L2
  movslq %edi,%r11
  lea    (%rsi,%r11,8),%rdx
  mov    %eax,%ecx
  sub    %edi,%ecx
  lea    -0x1(%rcx),%ecx
  add    %r11,%rcx
  lea    0x8(%rsi,%rcx,8),%rcx
L5:
  movq   $0x0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L5
L2:
  mov    %eax,%ecx
  sub    %r8d,%ecx
  cmp    %ecx,%r9d
  jge    L28
  movslq %r9d,%rdi
  lea    (%r10,%rdi,8),%rdx
  sub    %r9d,%ecx
  lea    -0x1(%rcx),%ecx
  add    %rdi,%rcx
  lea    0x8(%r10,%rcx,8),%rcx
L34:
  movq   $0x0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L34
L28:
  cmp    %eax,%r8d
  jge    L11
  movslq %r8d,%r8
  mov    %r8,%rdx
  neg    %rdx
  lea    (%r10,%rdx,8),%r9
  mov    $0x0,%ecx
L54:
  mov    (%rsi,%r8,8),%rdx
  add    (%r9,%r8,8),%rdx
  lea    (%rdx,%rcx,1),%rdi
  lea    (%rdx,%rcx,1),%edx
  mov    %rdx,(%rsi,%r8,8)
  shr    $0x20,%rdi
  mov    %rdi,%rcx
  add    $0x1,%r8
  cmp    %r8d,%eax
  jg     L54
L38:
  movslq %eax,%rdx
  mov    %rcx,(%rsi,%rdx,8)
  add    %ecx,%eax
  ret
L11:
  mov    $0x0,%ecx
  jmp    L38
```

assistant: ```c
int bi_sftadd(int a_len, unsigned long *a_data, int b_len, unsigned long *b_data, int s_len) {
  unsigned long carry;
  unsigned long long sum;
  int i, b_len_s, len_max;
  b_len_s = b_len + s_len;
  len_max = (a_len < b_len_s) ? b_len_s : a_len;
  for (i = a_len; i < len_max; i++)
    a_data[i] = 0;
  for (i = b_len; i < len_max - s_len; i++)
    b_data[i] = 0;
  carry = 0;
  for (i = s_len; i < len_max; i++) {
    sum = a_data[i];
    sum = sum + b_data[i - s_len] + carry;
    a_data[i] = (unsigned long)(sum & (((unsigned long long)0x1 << 32) - 1));
    carry = (unsigned long)(sum >> 32);
  }
  a_data[len_max] = carry;
  return len_max + carry;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bi_sftadd>:
  endbr64
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  lea    (%r14,%r8,1),%r12d
  cmp    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  cmovl  %edi,%r12d
  push   %rbx
  mov    %r8d,%ebx
  cmp    %r12d,%edi
  jge    L14
  mov    %r12d,%eax
  sub    %edi,%eax
  movslq %edi,%rdi
  sub    $0x1,%eax
  lea    (%rsi,%rdi,8),%rdi
  xor    %esi,%esi
  lea    0x8(,%rax,8),%rdx
  call   <memset@plt>
L14:
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    %eax,%r14d
  jge    L6
  sub    %r14d,%eax
  lea    0x0(%r13,%r14,8),%rdi
  xor    %esi,%esi
  sub    $0x1,%eax
  lea    0x8(,%rax,8),%rdx
  call   <memset@plt>
L6:
  xor    %ecx,%ecx
  xor    %edx,%edx
  cmp    %r12d,%ebx
  jge    L21
  movslq %ebx,%r8
  xor    %edx,%edx
  mov    %r8,%rax
  neg    %rax
  lea    0x0(%r13,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L12:
  mov    0x0(%rbp,%r8,8),%rax
  add    (%rsi,%r8,8),%rax
  lea    (%rax,%rdx,1),%rcx
  add    %edx,%eax
  mov    %eax,%eax
  shr    $0x20,%rcx
  mov    %rax,0x0(%rbp,%r8,8)
  add    $0x1,%r8
  mov    %rcx,%rdx
  cmp    %r8d,%r12d
  jg     L12
L21:
  movslq %r12d,%rax
  pop    %rbx
  mov    %rdx,0x0(%rbp,%rax,8)
  pop    %rbp
  lea    (%r12,%rcx,1),%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bi_sftadd(int a_len, unsigned long *a_data, int b_len, unsigned long *b_data, int s_len) {
  unsigned long carry;
  unsigned long long sum;
  int i, b_len_s, len_max;
  b_len_s = b_len + s_len;
  len_max = (a_len < b_len_s) ? b_len_s : a_len;
  for (i = a_len; i < len_max; i++)
    a_data[i] = 0;
  for (i = b_len; i < len_max - s_len; i++)
    b_data[i] = 0;
  carry = 0;
  for (i = s_len; i < len_max; i++) {
    sum = a_data[i];
    sum = sum + b_data[i - s_len] + carry;
    a_data[i] = (unsigned long)(sum & (((unsigned long long)0x1 << 32) - 1));
    carry = (unsigned long)(sum >> 32);
  }
  a_data[len_max] = carry;
  return len_max + carry;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bi_sftadd>:
  endbr64
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  lea    (%r14,%r8,1),%r12d
  cmp    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  cmovl  %edi,%r12d
  push   %rbx
  mov    %r8d,%ebx
  cmp    %r12d,%edi
  jge    L18
  mov    %r12d,%eax
  sub    %edi,%eax
  movslq %edi,%rdi
  sub    $0x1,%eax
  lea    (%rsi,%rdi,8),%rdi
  xor    %esi,%esi
  lea    0x8(,%rax,8),%rdx
  call   <memset@plt>
L18:
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    %eax,%r14d
  jge    L26
  sub    %r14d,%eax
  lea    0x0(%r13,%r14,8),%rdi
  xor    %esi,%esi
  sub    $0x1,%eax
  lea    0x8(,%rax,8),%rdx
  call   <memset@plt>
L26:
  xor    %ecx,%ecx
  xor    %edx,%edx
  cmp    %r12d,%ebx
  jge    L28
  movslq %ebx,%r8
  xor    %edx,%edx
  mov    %r8,%rax
  neg    %rax
  lea    0x0(%r13,%rax,8),%rsi
  nopl   0x0(%rax,%rax,1)
L22:
  mov    0x0(%rbp,%r8,8),%rax
  add    (%rsi,%r8,8),%rax
  lea    (%rax,%rdx,1),%rcx
  add    %edx,%eax
  mov    %eax,%eax
  shr    $0x20,%rcx
  mov    %rax,0x0(%rbp,%r8,8)
  add    $0x1,%r8
  mov    %rcx,%rdx
  cmp    %r8d,%r12d
  jg     L22
L28:
  movslq %r12d,%rax
  pop    %rbx
  mov    %rdx,0x0(%rbp,%rax,8)
  pop    %rbp
  lea    (%r12,%rcx,1),%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bi_sftadd(int a_len, unsigned long *a_data, int b_len, unsigned long *b_data, int s_len) {
  unsigned long carry;
  unsigned long long sum;
  int i, b_len_s, len_max;
  b_len_s = b_len + s_len;
  len_max = (a_len < b_len_s) ? b_len_s : a_len;
  for (i = a_len; i < len_max; i++)
    a_data[i] = 0;
  for (i = b_len; i < len_max - s_len; i++)
    b_data[i] = 0;
  carry = 0;
  for (i = s_len; i < len_max; i++) {
    sum = a_data[i];
    sum = sum + b_data[i - s_len] + carry;
    a_data[i] = (unsigned long)(sum & (((unsigned long long)0x1 << 32) - 1));
    carry = (unsigned long)(sum >> 32);
  }
  a_data[len_max] = carry;
  return len_max + carry;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  movl   $0xfffffffd,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <f@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: a=%d b=%d


assistant: ```c
int main(void) {
  int a = 1, b = -3;
  f(a, &b);
  printf("a=%d b=%d\n", a, b);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffd,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edi
  call   <f@plt>
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: a=%d b=%d


assistant: ```c
int main(void) {
  int a = 1, b = -3;
  f(a, &b);
  printf("a=%d b=%d\n", a, b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0xfffffffd,0x4(%rsp)
  call   <f@plt>
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: a=%d b=%d


assistant: ```c
int main(void) {
  int a = 1, b = -3;
  f(a, &b);
  printf("a=%d b=%d\n", a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0xfffffffd,0x4(%rsp)
  call   <f@plt>
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: a=%d b=%d


assistant: ```c
int main(void) {
  int a = 1, b = -3;
  f(a, &b);
  printf("a=%d b=%d\n", a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x7fffffff,-0x4(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int w = ~(int)0;
  if (w != 0x7fffffff)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int w = ~(int)0;
  if (w != 0x7fffffff)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int w = ~(int)0;
  if (w != 0x7fffffff)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int w = ~(int)0;
  if (w != 0x7fffffff)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L50
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  shr    %rax
  mov    %rax,-0x10(%rbp)
  jmp    L49
L31:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdi
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <sift@plt>
  subq   $0x1,-0x10(%rbp)
L49:
  cmpq   $0x0,-0x10(%rbp)
  jne    L31
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L21
L10:
  mov    -0x10(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sift@plt>
  subq   $0x1,-0x10(%rbp)
L21:
  cmpq   $0x0,-0x10(%rbp)
  jne    L10
  jmp    L12
L50:
  nop
L12:
  leave
  ret
```

assistant: ```c
void qsort(void *_base, size_t nel, size_t width, int (*cmp)(const void *, const void *)) {
  char *base = _base;
  size_t i;
  if (!nel)
    return;
  for (i = (nel + 1) / 2; i; i--)
    sift(base, i - 1, nel - 1, width, cmp);
  for (i = nel - 1; i; i--) {
    swap(base, base + i * width, width);
    sift(base, 0, i - 1, width, cmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<qsort>:
  endbr64
  test   %rsi,%rsi
  je     L12
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r14
  lea    0x1(%rsi),%rax
  mov    %rax,%r12
  shr    %r12
  cmp    $0x1,%rax
  jbe    L49
  lea    -0x1(%rsi),%r15
L34:
  sub    $0x1,%r12
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <sift@plt>
  test   %r12,%r12
  jne    L34
L49:
  sub    $0x1,%rbx
  je     L32
  mov    %rbx,%r12
  imul   %rbp,%r12
  add    %r13,%r12
L2:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  sub    $0x1,%rbx
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <sift@plt>
  sub    %rbp,%r12
  test   %rbx,%rbx
  jne    L2
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  ret
```

assistant: ```c
void qsort(void *_base, size_t nel, size_t width, int (*cmp)(const void *, const void *)) {
  char *base = _base;
  size_t i;
  if (!nel)
    return;
  for (i = (nel + 1) / 2; i; i--)
    sift(base, i - 1, nel - 1, width, cmp);
  for (i = nel - 1; i; i--) {
    swap(base, base + i * width, width);
    sift(base, 0, i - 1, width, cmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<qsort>:
  endbr64
  test   %rsi,%rsi
  je     L22
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%rsi),%r12
  shr    %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%rbx
  je     L44
  nopl   0x0(%rax,%rax,1)
L15:
  sub    $0x1,%r12
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <sift@plt>
  test   %r12,%r12
  jne    L15
L44:
  test   %rbx,%rbx
  je     L18
  mov    %rbx,%r12
  imul   %rbp,%r12
  add    %r13,%r12
  nopl   0x0(%rax)
L8:
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  sub    $0x1,%rbx
  call   <swap@plt>
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  xor    %esi,%esi
  mov    %r13,%rdi
  sub    %rbp,%r12
  call   <sift@plt>
  test   %rbx,%rbx
  jne    L8
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  ret
```

assistant: ```c
void qsort(void *_base, size_t nel, size_t width, int (*cmp)(const void *, const void *)) {
  char *base = _base;
  size_t i;
  if (!nel)
    return;
  for (i = (nel + 1) / 2; i; i--)
    sift(base, i - 1, nel - 1, width, cmp);
  for (i = nel - 1; i; i--) {
    swap(base, base + i * width, width);
    sift(base, 0, i - 1, width, cmp);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort>:
  endbr64
  test   %rsi,%rsi
  je     L24
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%rsi),%r12
  shr    %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    -0x1(%rsi),%rbx
  je     L28
  nopl   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%r12
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <sift@plt>
  test   %r12,%r12
  jne    L27
L28:
  test   %rbx,%rbx
  je     L49
  mov    %rbp,%r12
  imul   %rbx,%r12
  add    %r13,%r12
  nopl   0x0(%rax)
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  sub    $0x1,%rbx
  call   <swap@plt>
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  xor    %esi,%esi
  mov    %r13,%rdi
  sub    %rbp,%r12
  call   <sift@plt>
  test   %rbx,%rbx
  jne    L33
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  ret
```

assistant: ```c
void qsort(void *_base, size_t nel, size_t width, int (*cmp)(const void *, const void *)) {
  char *base = _base;
  size_t i;
  if (!nel)
    return;
  for (i = (nel + 1) / 2; i; i--)
    sift(base, i - 1, nel - 1, width, cmp);
  for (i = nel - 1; i; i--) {
    swap(base, base + i * width, width);
    sift(base, 0, i - 1, width, cmp);
  }
}
```