ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<heapsort>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%r8
  mov    %esi,%r10d
  shr    $0x1f,%ebp
  push   %rbx
  add    %esi,%ebp
  sar    %ebp
  test   %ebp,%ebp
  jle    L68
  nopl   0x0(%rax)
L77:
  sub    $0x1,%ebp
  movslq %ebp,%rax
  lea    (%r8,%rax,4),%rcx
  mov    (%rcx),%ebx
L107:
  lea    0x1(%rbp,%rbp,1),%eax
  cmp    %eax,%r10d
  jle    L12
  mov    %ebp,%esi
  jmp    L11
  nopl   0x0(%rax)
L47:
  lea    0x4(%r8,%rcx,1),%rcx
  mov    (%rcx),%r11d
  cmp    %edi,%r11d
  jle    L58
  movslq %esi,%rax
  mov    %r11d,%edi
  mov    %rcx,%r9
  lea    (%r8,%rax,4),%rcx
  cmp    %edi,%ebx
  jge    L12
L105:
  lea    0x1(%rdx,%rdx,1),%eax
  mov    %edi,(%rcx)
  cmp    %eax,%r10d
  jle    L30
  mov    %edx,%esi
L11:
  movslq %eax,%rcx
  lea    0x1(%rax),%edx
  shl    $0x2,%rcx
  lea    (%r8,%rcx,1),%r9
  mov    (%r9),%edi
  cmp    %r10d,%edx
  jl     L47
L58:
  mov    %eax,%edx
  movslq %esi,%rax
  lea    (%r8,%rax,4),%rcx
  cmp    %edi,%ebx
  jl     L105
L12:
  mov    %ebx,(%rcx)
L94:
  test   %ebp,%ebp
  jg     L77
L68:
  sub    $0x1,%r10d
  je     L50
  mov    (%r8),%edx
  movslq %r10d,%rax
  lea    (%r8,%rax,4),%rax
  mov    (%rax),%ebx
  mov    %edx,(%rax)
  movslq %ebp,%rax
  lea    (%r8,%rax,4),%rcx
  jmp    L107
  nopl   0x0(%rax)
L30:
  mov    %r9,%rcx
  mov    %ebx,(%rcx)
  jmp    L94
L50:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapsort(int a[], int n) {
  int i = n / 2, pai, filho, t;
  for (;;) {
    if (i > 0) {
      i--;
      t = a[i];
    } else {
      n--;
      if (n == 0)
        return;
      t = a[n];
      a[n] = a[0];
    }
    pai = i;
    filho = i * 2 + 1;
    while (filho < n) {
      if ((filho + 1 < n) && (a[filho + 1] > a[filho]))
        filho++;
      if (a[filho] > t) {
        a[pai] = a[filho];
        pai = filho;
        filho = pai * 2 + 1;
      } else {
        break;
      }
    }
    a[pai] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapsort>:
  endbr64
  push   %r14
  mov    %rdi,%r8
  mov    %esi,%r10d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  push   %rbp
  add    %esi,%r12d
  push   %rbx
  sar    %r12d
  test   %r12d,%r12d
  jle    L27
  nopl   0x0(%rax,%rax,1)
L77:
  lea    -0x1(%r12),%r11d
  movslq %r11d,%rax
  lea    (%r8,%rax,4),%rax
  mov    (%rax),%ebp
L49:
  lea    0x1(%r11,%r11,1),%ebx
  cmp    %ebx,%r10d
  jle    L100
  mov    %ebx,%eax
  mov    %r11d,%esi
  jmp    L80
  nop
L44:
  lea    0x4(%r8,%rcx,1),%rcx
  mov    (%rcx),%r13d
  cmp    %edi,%r13d
  jle    L22
  movslq %esi,%rax
  mov    %r13d,%edi
  mov    %rcx,%r9
  lea    (%r8,%rax,4),%rax
  cmp    %edi,%ebp
  jge    L100
L109:
  mov    %edi,(%rax)
  lea    0x1(%rdx,%rdx,1),%eax
  cmp    %eax,%r10d
  jle    L43
  mov    %edx,%esi
L80:
  movslq %eax,%rcx
  lea    0x1(%rax),%edx
  shl    $0x2,%rcx
  lea    (%r8,%rcx,1),%r9
  mov    (%r9),%edi
  cmp    %r10d,%edx
  jl     L44
L22:
  mov    %eax,%edx
  movslq %esi,%rax
  lea    (%r8,%rax,4),%rax
  cmp    %edi,%ebp
  jl     L109
L100:
  mov    %ebp,(%rax)
  test   %r12d,%r12d
  jle    1040 <heapsort.cold>
  mov    %r11d,%r12d
  test   %r12d,%r12d
  jg     L77
L27:
  sub    $0x1,%r10d
  je     L21
  mov    (%r8),%edx
  movslq %r10d,%rax
  mov    %r12d,%r11d
  lea    (%r8,%rax,4),%rax
  mov    (%rax),%ebp
  mov    %edx,(%rax)
  movslq %r12d,%rax
  lea    (%r8,%rax,4),%rax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r9,%rax
  jmp    L100
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void heapsort(int a[], int n) {
  int i = n / 2, pai, filho, t;
  for (;;) {
    if (i > 0) {
      i--;
      t = a[i];
    } else {
      n--;
      if (n == 0)
        return;
      t = a[n];
      a[n] = a[0];
    }
    pai = i;
    filho = i * 2 + 1;
    while (filho < n) {
      if ((filho + 1 < n) && (a[filho + 1] > a[filho]))
        filho++;
      if (a[filho] > t) {
        a[pai] = a[filho];
        pai = filho;
        filho = pai * 2 + 1;
      } else {
        break;
      }
    }
    a[pai] = t;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ADS1299TestSignal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x0,-0x4(%rbp)
  je     L10
  mov    $0xd0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    $0x1,%eax
  jmp    L14
L10:
  mov    $0xc0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
unsigned char ADS1299TestSignal(unsigned char enable) {
  if (enable) {
    ADS1299WriteReg(0x02, 0xD0);
    ADS1299SetInputModeSetGain(0x05, 1);
    return 1;
  } else {
    ADS1299WriteReg(0x02, 0xC0);
    ADS1299SetInputModeSetGain(0x00, 1);
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ADS1299TestSignal>:
  endbr64
  push   %rbx
  test   %dil,%dil
  je     L17
  mov    $0xd0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    $0x1,%eax
L8:
  pop    %rbx
  ret
L17:
  mov    %edi,%ebx
  mov    $0xc0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    %ebx,%eax
  jmp    L8
```

assistant: ```c
unsigned char ADS1299TestSignal(unsigned char enable) {
  if (enable) {
    ADS1299WriteReg(0x02, 0xD0);
    ADS1299SetInputModeSetGain(0x05, 1);
    return 1;
  } else {
    ADS1299WriteReg(0x02, 0xC0);
    ADS1299SetInputModeSetGain(0x00, 1);
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ADS1299TestSignal>:
  endbr64
  sub    $0x8,%rsp
  test   %dil,%dil
  je     L8
  mov    $0xd0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  mov    $0xc0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char ADS1299TestSignal(unsigned char enable) {
  if (enable) {
    ADS1299WriteReg(0x02, 0xD0);
    ADS1299SetInputModeSetGain(0x05, 1);
    return 1;
  } else {
    ADS1299WriteReg(0x02, 0xC0);
    ADS1299SetInputModeSetGain(0x00, 1);
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ADS1299TestSignal>:
  endbr64
  sub    $0x8,%rsp
  test   %dil,%dil
  je     L7
  mov    $0xd0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  mov    $0x5,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L7:
  mov    $0xc0,%esi
  mov    $0x2,%edi
  call   <ADS1299WriteReg@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <ADS1299SetInputModeSetGain@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char ADS1299TestSignal(unsigned char enable) {
  if (enable) {
    ADS1299WriteReg(0x02, 0xD0);
    ADS1299SetInputModeSetGain(0x05, 1);
    return 1;
  } else {
    ADS1299WriteReg(0x02, 0xC0);
    ADS1299SetInputModeSetGain(0x00, 1);
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(long double **a, int l1, int l2) {
  long double *t = a[l1];
  a[l1] = a[l2];
  a[l2] = t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rcx
  mov    (%rcx),%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(long double **a, int l1, int l2) {
  long double *t = a[l1];
  a[l1] = a[l2];
  a[l2] = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(long double **a, int l1, int l2) {
  long double *t = a[l1];
  a[l1] = a[l2];
  a[l2] = t;
}
```
user: What is the c source code of the assembly code below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(long double **a, int l1, int l2) {
  long double *t = a[l1];
  a[l1] = a[l2];
  a[l2] = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heapSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buildMaxHeap@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <buildMaxHeap@plt>
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void heapSort(int *data, int size) {
  int i;
  buildMaxHeap(data, size);
  for (i = size - 1; i >= 0; --i) {
    swap(data, data + i);
    buildMaxHeap(data, i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<heapSort>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  call   <buildMaxHeap@plt>
  sub    $0x1,%ebx
  js     L15
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rbp
L13:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <buildMaxHeap@plt>
  sub    $0x1,%ebx
  sub    $0x4,%rbp
  cmp    $0xffffffff,%ebx
  jne    L13
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *data, int size) {
  int i;
  buildMaxHeap(data, size);
  for (i = size - 1; i >= 0; --i) {
    swap(data, data + i);
    buildMaxHeap(data, i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapSort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <buildMaxHeap@plt>
  sub    $0x1,%ebx
  js     L0
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rbp
  xchg   %ax,%ax
L7:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <swap@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <buildMaxHeap@plt>
  cmp    $0xffffffff,%ebx
  jne    L7
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *data, int size) {
  int i;
  buildMaxHeap(data, size);
  for (i = size - 1; i >= 0; --i) {
    swap(data, data + i);
    buildMaxHeap(data, i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapSort>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  call   <buildMaxHeap@plt>
  sub    $0x1,%ebx
  js     L11
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rbp
  xchg   %ax,%ax
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <swap@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <buildMaxHeap@plt>
  cmp    $0xffffffff,%ebx
  jne    L0
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void heapSort(int *data, int size) {
  int i;
  buildMaxHeap(data, size);
  for (i = size - 1; i >= 0; --i) {
    swap(data, data + i);
    buildMaxHeap(data, i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x428,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L9
L38:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  movslq %ebx,%rax
  mov    %edx,-0x420(%rbp,%rax,4)
  add    $0x1,%ebx
L9:
  cmp    $0xff,%ebx
  jle    L38
  mov    $0x0,%ebx
  jmp    L1
L12:
  movslq %ebx,%rax
  mov    -0x420(%rbp,%rax,4),%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    %ebx,%edx
  mov    %edx,(%rax)
  add    $0x1,%ebx
L1:
  cmp    $0xff,%ebx
  jle    L12
  nop
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
invert(r) unsigned r[256];
{
  unsigned t[256];
  register int i;
  for (i = 0; i < 256; i++)
    t[i] = r[i];
  for (i = 0; i < 256; i++)
    r[t[i]] = i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invert>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
L25:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x400,%rax
  jne    L25
  mov    $0x0,%eax
  mov    %rsp,%rcx
L21:
  mov    (%rcx,%rax,4),%edx
  mov    %eax,(%rdi,%rdx,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L21
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x418,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
invert(r) unsigned r[256];
{
  unsigned t[256];
  register int i;
  for (i = 0; i < 256; i++)
    t[i] = r[i];
  for (i = 0; i < 256; i++)
    r[t[i]] = i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<invert>:
  endbr64
  sub    $0x418,%rsp
  mov    %rdi,%r8
  mov    $0x80,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r8,%rsi
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%r9,%rax,4),%edx
  mov    %eax,(%r8,%rdx,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L0
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x418,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
invert(r) unsigned r[256];
{
  unsigned t[256];
  register int i;
  for (i = 0; i < 256; i++)
    t[i] = r[i];
  for (i = 0; i < 256; i++)
    r[t[i]] = i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<invert>:
  endbr64
  sub    $0x418,%rsp
  mov    %rdi,%r8
  mov    $0x80,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r8,%rsi
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%r9,%rax,4),%edx
  mov    %eax,(%r8,%rdx,4)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L17
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x418,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
invert(r) unsigned r[256];
{
  unsigned t[256];
  register int i;
  for (i = 0; i < 256; i++)
    t[i] = r[i];
  for (i = 0; i < 256; i++)
    r[t[i]] = i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtnewt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movss  %xmm1,-0x30(%rbp)
  movss  %xmm2,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x2c(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  -0x30(%rbp),%xmm1
  movss  D28(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L55
L17:
  lea    -0x1c(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%r8
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movd   %eax,%xmm0
  call   *%r8
  movss  -0x18(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x2c(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  -0x10(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  subss  -0x30(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L52
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L52:
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movss  -0x34(%rbp),%xmm1
  comiss %xmm0,%xmm1
  jbe    L47
  movss  -0x10(%rbp),%xmm0
  jmp    L33
L47:
  addl   $0x1,-0x14(%rbp)
L55:
  cmpl   $0x14,-0x14(%rbp)
  jle    L17
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L33:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D28
type_guessed: f32
name: parse_data
arguments: data_tag: D14
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string

tool: D28: 0.5

tool: D14: Jumped out of brackets in rtnewt

tool: D23: Maximum number of iterations exceeded in rtnewt

assistant: ```c
float rtnewt(void (*funcd)(float, float *, float *), float x1, float x2, float xacc) {
  void nrerror(char error_text[]);
  int j;
  float df, dx, f, rtn;
  rtn = 0.5 * (x1 + x2);
  for (j = 1; j <= 20; j++) {
    (*funcd)(rtn, &f, &df);
    dx = f / df;
    rtn -= dx;
    if ((x1 - rtn) * (rtn - x2) < 0.0)
      nrerror("Jumped out of brackets in rtnewt");
    if (fabs(dx) < xacc)
      return rtn;
  }
  nrerror("Maximum number of iterations exceeded in rtnewt");
  return 0.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rtnewt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  movss  %xmm0,0x14(%rsp)
  movss  %xmm1,0x18(%rsp)
  movss  %xmm2,0x1c(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  addss  %xmm1,%xmm0
  mulss  D17(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  mov    $0x14,%ebx
  lea    0x20(%rsp),%r13
  lea    0x24(%rsp),%r12
  lea    D21(%rip),%r14
  jmp    L14
L17:
  movss  0x10(%rsp),%xmm0
  call   <fabs@plt>
  movss  0x1c(%rsp),%xmm7
  comiss %xmm0,%xmm7
  ja     L2
  sub    $0x1,%ebx
  je     L12
L14:
  mov    %r13,%rsi
  mov    %r12,%rdi
  movss  0xc(%rsp),%xmm0
  call   *%rbp
  movss  0x24(%rsp),%xmm0
  movaps %xmm0,%xmm4
  divss  0x20(%rsp),%xmm4
  movss  %xmm4,0x10(%rsp)
  movss  0xc(%rsp),%xmm3
  subss  %xmm4,%xmm3
  movss  %xmm3,0xc(%rsp)
  movss  0x14(%rsp),%xmm0
  subss  %xmm3,%xmm0
  subss  0x18(%rsp),%xmm3
  mulss  %xmm3,%xmm0
  pxor   %xmm6,%xmm6
  comiss %xmm0,%xmm6
  jbe    L17
  mov    %r14,%rdi
  call   <nrerror@plt>
  jmp    L17
L12:
  lea    D22(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm2,%xmm2
  movss  %xmm2,0xc(%rsp)
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  movss  0xc(%rsp),%xmm0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: f32
name: extract_symbolic_data
arguments: data_label: D21
data_type: string
name: extract_symbolic_data
arguments: data_label: D22
data_type: string

tool: D17: 0.5

tool: D21: Jumped out of brackets in rtnewt

tool: D22: Maximum number of iterations exceeded in rtnewt

assistant: ```c
float rtnewt(void (*funcd)(float, float *, float *), float x1, float x2, float xacc) {
  void nrerror(char error_text[]);
  int j;
  float df, dx, f, rtn;
  rtn = 0.5 * (x1 + x2);
  for (j = 1; j <= 20; j++) {
    (*funcd)(rtn, &f, &df);
    dx = f / df;
    rtn -= dx;
    if ((x1 - rtn) * (rtn - x2) < 0.0)
      nrerror("Jumped out of brackets in rtnewt");
    if (fabs(dx) < xacc)
      return rtn;
  }
  nrerror("Maximum number of iterations exceeded in rtnewt");
  return 0.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rtnewt>:
  endbr64
  push   %r15
  movd   %xmm2,%r15d
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x28,%rsp
  movss  %xmm0,0x4(%rsp)
  addss  %xmm1,%xmm0
  lea    0x10(%rsp),%r13
  movss  %xmm1,0x8(%rsp)
  movss  D23(%rip),%xmm1
  lea    0x14(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mulss  %xmm0,%xmm1
  jmp    L1
  xchg   %ax,%ax
L37:
  movss  %xmm1,(%rsp)
  call   <fabs@plt>
  movd   %r15d,%xmm6
  movss  (%rsp),%xmm1
  comiss %xmm0,%xmm6
  ja     L50
  sub    $0x1,%ebx
  je     L32
L1:
  movaps %xmm1,%xmm0
  movss  %xmm1,(%rsp)
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   *%rbp
  movss  (%rsp),%xmm1
  movss  0x14(%rsp),%xmm0
  pxor   %xmm5,%xmm5
  divss  0x10(%rsp),%xmm0
  movss  0x4(%rsp),%xmm2
  subss  %xmm0,%xmm1
  subss  %xmm1,%xmm2
  movaps %xmm1,%xmm3
  subss  0x8(%rsp),%xmm3
  mulss  %xmm3,%xmm2
  comiss %xmm2,%xmm5
  jbe    L37
  mov    %r14,%rdi
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,(%rsp)
  call   <nrerror@plt>
  movss  0xc(%rsp),%xmm1
  movss  (%rsp),%xmm0
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L32:
  lea    D27(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm1,%xmm1
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x28,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: f32
name: extract_symbolic_data
arguments: data_tag: D27
type: string

tool: D4: Jumped out of brackets in rtnewt

tool: D23: 0.5

tool: D27: Maximum number of iterations exceeded in rtnewt

assistant: ```c
float rtnewt(void (*funcd)(float, float *, float *), float x1, float x2, float xacc) {
  void nrerror(char error_text[]);
  int j;
  float df, dx, f, rtn;
  rtn = 0.5 * (x1 + x2);
  for (j = 1; j <= 20; j++) {
    (*funcd)(rtn, &f, &df);
    dx = f / df;
    rtn -= dx;
    if ((x1 - rtn) * (rtn - x2) < 0.0)
      nrerror("Jumped out of brackets in rtnewt");
    if (fabs(dx) < xacc)
      return rtn;
  }
  nrerror("Maximum number of iterations exceeded in rtnewt");
  return 0.0;
}
```