ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<issafe>:
  endbr64
  movslq %esi,%r11
  mov    %edx,%esi
  mov    %rdi,%r9
  xor    %eax,%eax
  mov    %r11,%rdx
  mov    %r11,%rcx
  shl    $0x5,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L93:
  cmp    %eax,%esi
  je     L169
  cmpl   $0x1,(%rdx,%rax,4)
  je     L111
L169:
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L93
  movslq %esi,%r10
  xor    %eax,%eax
  lea    (%r9,%r10,4),%rdx
  nopl   (%rax)
L124:
  cmp    %eax,%ecx
  je     L162
  cmpl   $0x1,(%rdx)
  je     L111
L162:
  add    $0x1,%eax
  add    $0x20,%rdx
  cmp    $0x8,%eax
  jne    L124
  shl    $0x3,%r11
  mov    %esi,%r8d
  lea    0x9(%r11,%r10,1),%rax
  sub    %ecx,%r8d
  lea    (%r9,%rax,4),%rdx
  mov    %ecx,%eax
  nopw   0x0(%rax,%rax,1)
L48:
  lea    (%rax,%r8,1),%edi
  cmp    $0x7,%edi
  jg     L61
  cmp    $0x7,%eax
  jg     L61
  add    $0x24,%rdx
  add    $0x1,%eax
  cmpl   $0x1,-0x24(%rdx)
  jne    L48
L111:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L61:
  push   %rbx
  lea    (%r11,%r10,1),%rbx
  mov    %ecx,%eax
  shl    $0x2,%rbx
  lea    -0x24(%r9,%rbx,1),%rdx
L41:
  mov    %eax,%edi
  add    %r8d,%edi
  js     L24
  test   %eax,%eax
  js     L24
  sub    $0x24,%rdx
  sub    $0x1,%eax
  cmpl   $0x1,0x24(%rdx)
  jne    L41
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L24:
  lea    -0x1c(%r9,%rbx,1),%rdi
  mov    %ecx,%edx
  add    %ecx,%esi
  jmp    L148
  nopl   0x0(%rax,%rax,1)
L44:
  sub    $0x1c,%rdi
  sub    $0x1,%edx
  cmpl   $0x1,0x1c(%rdi)
  je     L16
L148:
  mov    %esi,%eax
  sub    %edx,%eax
  or     %edx,%eax
  cmp    $0x7,%eax
  jbe    L44
  lea    0x7(%r11,%r10,1),%rax
  lea    (%r9,%rax,4),%rdx
  jmp    L176
  nopl   0x0(%rax,%rax,1)
L161:
  add    $0x1c,%rdx
  add    $0x1,%ecx
  cmpl   $0x1,-0x1c(%rdx)
  je     L16
L176:
  mov    %esi,%eax
  sub    %ecx,%eax
  or     %ecx,%eax
  cmp    $0x7,%eax
  jbe    L161
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int issafe(int arr[][8], int a, int b) {
  int x = a;
  int y = b;
  for (int i = 0; i < 8; i++) {
    if (i == b)
      continue;
    if (arr[a][i] == 1)
      return 0;
  }
  for (int j = 0; j < 8; j++) {
    if (j == a)
      continue;
    if (arr[j][b] == 1)
      return 0;
  }
  while ((x < 8) && (y < 8)) {
    if (arr[++x][++y] == 1)
      return 0;
  }
  x = a;
  y = b;
  while ((x >= 0) && (y >= 0))
    if (arr[--x][--y] == 1)
      return 0;
  x = a;
  y = b;
  while ((x < 8) && (y < 8) && (x >= 0) && (y >= 0))
    if (arr[--x][++y] == 1)
      return 0;
  x = a;
  y = b;
  while ((x < 8) && (y < 8) && (x >= 0) && (y >= 0))
    if (arr[++x][--y] == 1)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<wdt_notify_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jne    L23
  mov    $0x0,%eax
  call   <wdt_turnoff@plt>
  jmp    L4
L23:
  cmpq   $0x2,-0x10(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <wdt_turnoff@plt>
L4:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int wdt_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      wdt_turnoff();
    } else if (code == 2UL) {
      wdt_turnoff();
    }
    return (0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wdt_notify_sys>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%rsi
  je     L18
  cmp    $0x2,%rsi
  je     L30
L23:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L18:
  mov    $0x0,%eax
  call   <wdt_turnoff@plt>
  jmp    L23
L30:
  mov    $0x0,%eax
  call   <wdt_turnoff@plt>
  jmp    L23
```

assistant: ```c
int wdt_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      wdt_turnoff();
    } else if (code == 2UL) {
      wdt_turnoff();
    }
    return (0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wdt_notify_sys>:
  endbr64
  sub    $0x1,%rsi
  cmp    $0x1,%rsi
  jbe    L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wdt_turnoff@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wdt_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      wdt_turnoff();
    } else if (code == 2UL) {
      wdt_turnoff();
    }
    return (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wdt_notify_sys>:
  endbr64
  sub    $0x1,%rsi
  cmp    $0x1,%rsi
  jbe    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L3:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <wdt_turnoff@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int wdt_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      wdt_turnoff();
    } else if (code == 2UL) {
      wdt_turnoff();
    }
    return (0);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crossprodslow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L47
L65:
  movl   $0x0,-0x4(%rbp)
  jmp    L72
L48:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L72:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L48
  addl   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L65
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L51:
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L56:
  movl   $0x0,-0x4(%rbp)
  jmp    L63
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L63:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L30
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L56
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L51
  nop
  pop    %rbp
  ret
```

assistant: ```c
void crossprodslow(double **x, int n, int p, double **xpx) {
  int i, j, k;
  for (j = 0; j < p; j++) {
    for (k = 0; k < p; k++) {
      xpx[j][k] = 0.0;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      for (k = 0; k < p; k++) {
        xpx[j][k] += x[i][j] * x[i][k];
      }
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crossprodslow>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %esi,%ebx
  mov    %edx,%r10d
  mov    %rcx,%r11
  test   %edx,%edx
  jle    L92
  lea    -0x1(%rdx),%eax
  lea    0x8(%rcx,%rax,8),%rdi
  mov    %edx,%esi
  shl    $0x3,%rsi
L66:
  mov    $0x0,%eax
L91:
  mov    (%rcx),%rdx
  movq   $0x0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L91
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  jne    L66
L92:
  test   %ebx,%ebx
  jle    L84
  mov    %r8,%r9
  lea    -0x1(%rbx),%eax
  lea    0x8(%r8,%rax,8),%rbx
  lea    -0x1(%r10),%eax
  lea    0x8(,%rax,8),%r8
  jmp    L97
L42:
  mov    $0x0,%eax
L37:
  mov    %rax,%rdx
  add    (%rdi),%rdx
  mov    (%r9),%rcx
  movsd  (%rcx,%rsi,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L37
  add    $0x8,%rdi
  add    $0x8,%rsi
  cmp    %r8,%rsi
  jne    L42
L45:
  add    $0x8,%r9
  cmp    %rbx,%r9
  je     L84
L97:
  test   %r10d,%r10d
  jle    L45
  mov    %r11,%rdi
  mov    $0x0,%esi
  jmp    L42
L84:
  pop    %rbx
  ret
```

assistant: ```c
void crossprodslow(double **x, int n, int p, double **xpx) {
  int i, j, k;
  for (j = 0; j < p; j++) {
    for (k = 0; k < p; k++) {
      xpx[j][k] = 0.0;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      for (k = 0; k < p; k++) {
        xpx[j][k] += x[i][j] * x[i][k];
      }
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crossprodslow>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %edx,%edx
  jle    L48
  lea    -0x1(%rdx),%eax
  mov    %edx,%r13d
  mov    %rcx,%r12
  lea    0x8(%rcx,%rax,8),%r15
  shl    $0x3,%r13
  nopl   (%rax)
L7:
  mov    (%r12),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  add    $0x8,%r12
  call   <memset@plt>
  cmp    %r15,%r12
  jne    L7
L48:
  test   %r14d,%r14d
  jle    L41
  mov    0x8(%rsp),%r11
  lea    -0x1(%r14),%eax
  lea    -0x1(%rbx),%r8d
  lea    0x8(,%r8,8),%r13
  lea    0x8(%r11,%rax,8),%r12
  xchg   %ax,%ax
L34:
  test   %ebx,%ebx
  jle    L51
  mov    (%r11),%rdi
  mov    %rbp,%r9
  mov    %rdi,%rsi
  lea    0x0(%r13,%rdi,1),%r10
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%r9),%rdx
  xor    %eax,%eax
  nopl   (%rax)
L17:
  movsd  (%rsi),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  mov    %rax,%rcx
  addsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%r8
  jne    L17
  add    $0x8,%rsi
  add    $0x8,%r9
  cmp    %rsi,%r10
  jne    L18
L51:
  add    $0x8,%r11
  cmp    %r11,%r12
  jne    L34
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void crossprodslow(double **x, int n, int p, double **xpx) {
  int i, j, k;
  for (j = 0; j < p; j++) {
    for (k = 0; k < p; k++) {
      xpx[j][k] = 0.0;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      for (k = 0; k < p; k++) {
        xpx[j][k] += x[i][j] * x[i][k];
      }
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crossprodslow>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rcx,0x20(%rsp)
  test   %edx,%edx
  jle    L76
  lea    -0x1(%rdx),%eax
  mov    %edx,%ebp
  mov    %esi,%r14d
  mov    %edx,%ebx
  mov    %rcx,%r12
  lea    0x8(%rcx,%rax,8),%r15
  lea    0x0(,%rbp,8),%r13
  xchg   %ax,%ax
L58:
  mov    (%r12),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  add    $0x8,%r12
  call   <memset@plt>
  cmp    %r15,%r12
  jne    L58
  test   %r14d,%r14d
  jle    L76
  mov    0x8(%rsp),%rsi
  lea    -0x1(%r14),%eax
  movslq %ebx,%r14
  shl    $0x3,%r14
  lea    0x8(%rsi,%rax,8),%rax
  mov    %rsi,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %ebx,%eax
  shr    %eax
  lea    -0x1(%rax),%edi
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  add    $0x1,%rdi
  mov    %eax,%r8d
  mov    %eax,0x8(%rsp)
  lea    0x0(,%rbp,8),%rax
  shl    $0x4,%rdi
  mov    %rax,0x28(%rsp)
  shl    $0x3,%r8
  nopl   0x0(%rax,%rax,1)
L59:
  mov    0x10(%rsp),%rax
  mov    0x20(%rsp),%r10
  mov    (%rax),%rcx
  mov    0x28(%rsp),%rax
  mov    %rcx,%rsi
  lea    (%rax,%rcx,1),%r13
  lea    (%rcx,%r8,1),%r9
  lea    0x8(%rcx),%r12
  nopl   0x0(%rax)
L104:
  mov    (%r10),%rax
  mov    %rsi,%rdx
  add    $0x8,%rsi
  cmp    %r12,%rax
  setne  %r15b
  cmp    $0x1,%ebx
  setne  %r11b
  test   %r11b,%r15b
  je     L31
  lea    (%rax,%r14,1),%r11
  cmp    %r11,%rdx
  setae  %r15b
  cmp    %rsi,%rax
  setae  %r11b
  or     %r15b,%r11b
  je     L31
  movsd  (%rdx),%xmm1
  xor    %r11d,%r11d
  unpcklpd %xmm1,%xmm1
  nop
L17:
  movupd (%rcx,%r11,1),%xmm0
  movupd (%rax,%r11,1),%xmm2
  mulpd  %xmm1,%xmm0
  addpd  %xmm2,%xmm0
  movups %xmm0,(%rax,%r11,1)
  add    $0x10,%r11
  cmp    %rdi,%r11
  jne    L17
  cmp    %ebx,0x8(%rsp)
  je     L52
  movsd  (%r9),%xmm0
  mulsd  (%rdx),%xmm0
  add    %r8,%rax
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L52:
  add    $0x8,%r10
  cmp    %r13,%rsi
  jne    L104
  addq   $0x8,0x10(%rsp)
  mov    0x10(%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L59
L76:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L31:
  xor    %r11d,%r11d
  nopl   0x0(%rax,%rax,1)
L33:
  movsd  (%rcx,%r11,8),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rax,%r11,8),%xmm0
  movsd  %xmm0,(%rax,%r11,8)
  add    $0x1,%r11
  cmp    %r11,%rbp
  jne    L33
  jmp    L52
```

assistant: ```c
void crossprodslow(double **x, int n, int p, double **xpx) {
  int i, j, k;
  for (j = 0; j < p; j++) {
    for (k = 0; k < p; k++) {
      xpx[j][k] = 0.0;
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      for (k = 0; k < p; k++) {
        xpx[j][k] += x[i][j] * x[i][k];
      }
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L45
L36:
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <process_free@plt>
  test   %rax,%rax
  jne    L72
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L45
L72:
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x30(%rbp)
  jne    L3
  mov    -0x28(%rbp),%rax
  jmp    L45
L3:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L45
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  cmova  %rax,%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

assistant: ```c
void *realloc(void *buf_arg, size_t newsize) {
  size_t oldsize;
  void *buf;
  if (buf_arg == NULL)
    return (malloc(newsize));
  if (process_free(buf_arg, 0, &oldsize) == 0) {
    errno = EINVAL;
    return (NULL);
  }
  if (newsize == oldsize)
    return (buf_arg);
  buf = malloc(newsize);
  if (buf == NULL)
    return (NULL);
  (void)memcpy(buf, buf_arg, ((newsize) < (oldsize) ? (newsize) : (oldsize)));
  free(buf_arg);
  return (buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<realloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbx
  mov    %rsp,%rdx
  mov    $0x0,%esi
  call   <process_free@plt>
  test   %rax,%rax
  je     L46
  mov    (%rsp),%r13
  mov    %rbx,%r12
  cmp    %rbp,%r13
  je     L6
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  cmp    %rbp,%r13
  mov    %rbp,%rdx
  cmovbe %r13,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L6
L46:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%r12d
  jmp    L6
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *realloc(void *buf_arg, size_t newsize) {
  size_t oldsize;
  void *buf;
  if (buf_arg == NULL)
    return (malloc(newsize));
  if (process_free(buf_arg, 0, &oldsize) == 0) {
    errno = EINVAL;
    return (NULL);
  }
  if (newsize == oldsize)
    return (buf_arg);
  buf = malloc(newsize);
  if (buf == NULL)
    return (NULL);
  (void)memcpy(buf, buf_arg, ((newsize) < (oldsize) ? (newsize) : (oldsize)));
  free(buf_arg);
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<realloc>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  xor    %esi,%esi
  mov    %rsp,%rdx
  mov    %rdi,%rbp
  call   <process_free@plt>
  test   %rax,%rax
  je     L2
  mov    (%rsp),%rbx
  mov    %rbp,%r13
  cmp    %r12,%rbx
  je     L66
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L66
  cmp    %r12,%rbx
  mov    %r12,%rdx
  mov    %rax,%rdi
  mov    %rbp,%rsi
  cmovbe %rbx,%rdx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x18,%rsp
  mov    %rsi,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    D13(%rip),%rax
  xor    %r13d,%r13d
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  jmp    L66
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *realloc(void *buf_arg, size_t newsize) {
  size_t oldsize;
  void *buf;
  if (buf_arg == NULL)
    return (malloc(newsize));
  if (process_free(buf_arg, 0, &oldsize) == 0) {
    errno = EINVAL;
    return (NULL);
  }
  if (newsize == oldsize)
    return (buf_arg);
  buf = malloc(newsize);
  if (buf == NULL)
    return (NULL);
  (void)memcpy(buf, buf_arg, ((newsize) < (oldsize) ? (newsize) : (oldsize)));
  free(buf_arg);
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<realloc>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  xor    %esi,%esi
  mov    %rsp,%rdx
  mov    %rdi,%rbp
  call   <process_free@plt>
  test   %rax,%rax
  je     L40
  mov    (%rsp),%rbx
  mov    %rbp,%r13
  cmp    %r12,%rbx
  je     L65
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L65
  cmp    %r12,%rbx
  mov    %r12,%rdx
  mov    %rax,%rdi
  mov    %rbp,%rsi
  cmovbe %rbx,%rdx
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  mov    %rsi,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <malloc@plt>
  nopw   0x0(%rax,%rax,1)
L40:
  mov    D17(%rip),%rax
  xor    %r13d,%r13d
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  jmp    L65
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *realloc(void *buf_arg, size_t newsize) {
  size_t oldsize;
  void *buf;
  if (buf_arg == NULL)
    return (malloc(newsize));
  if (process_free(buf_arg, 0, &oldsize) == 0) {
    errno = EINVAL;
    return (NULL);
  }
  if (newsize == oldsize)
    return (buf_arg);
  buf = malloc(newsize);
  if (buf == NULL)
    return (NULL);
  (void)memcpy(buf, buf_arg, ((newsize) < (oldsize) ? (newsize) : (oldsize)));
  free(buf_arg);
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utl_rand_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int utl_rand_memory(int range) {
  void *ptr;
  int rtn;
  ptr = malloc(1);
  rtn = (int)(long)ptr % range;
  free(ptr);
  return (rtn);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<utl_rand_memory>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  call   <free@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int utl_rand_memory(int range) {
  void *ptr;
  int rtn;
  ptr = malloc(1);
  rtn = (int)(long)ptr % range;
  free(ptr);
  return (rtn);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utl_rand_memory>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  cltd
  mov    %rax,%rdi
  idiv   %ebx
  mov    %edx,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int utl_rand_memory(int range) {
  void *ptr;
  int rtn;
  ptr = malloc(1);
  rtn = (int)(long)ptr % range;
  free(ptr);
  return (rtn);
}
```
user: What is the c source code of the assembly code below?

```asm
<utl_rand_memory>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  cltd
  mov    %rax,%rdi
  idiv   %ebx
  mov    %edx,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int utl_rand_memory(int range) {
  void *ptr;
  int rtn;
  ptr = malloc(1);
  rtn = (int)(long)ptr % range;
  free(ptr);
  return (rtn);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rpc_th_null_1_svc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *rpc_th_null_1_svc(void *argp, struct svc_req *rqstp) {
  static char *result;
  return (void *)&result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rpc_th_null_1_svc>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

assistant: ```c
void *rpc_th_null_1_svc(void *argp, struct svc_req *rqstp) {
  static char *result;
  return (void *)&result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rpc_th_null_1_svc>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

assistant: ```c
void *rpc_th_null_1_svc(void *argp, struct svc_req *rqstp) {
  static char *result;
  return (void *)&result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rpc_th_null_1_svc>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

assistant: ```c
void *rpc_th_null_1_svc(void *argp, struct svc_req *rqstp) {
  static char *result;
  return (void *)&result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opposite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  ja     L17
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D7(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x5,%eax
  jmp    L17
  mov    $0x3,%eax
  jmp    L17
  mov    $0x4,%eax
  jmp    L17
  mov    $0x1,%eax
  jmp    L17
  mov    $0x2,%eax
  jmp    L17
  mov    $0x0,%eax
  jmp    L17
L17:
  pop    %rbp
  ret
```

assistant: ```c
int opposite(int side) {
  switch (side) {
  case 0:
    return 5;
  case 1:
    return 3;
  case 2:
    return 4;
  case 3:
    return 1;
  case 4:
    return 2;
  case 5:
    return 0;
  }
}
```