user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<smallest>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,%rbx
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    $0x18,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  movsbl %bl,%edx
  lea    0x10(%rsp),%rdi
  lea    D18(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    $0xffffffff,%r12d
  lea    0x10(%rsp),%rbx
L33:
  add    $0x1,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <smallest_idx_between@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L33
  cltq
  movzbl 0x10(%rsp,%rax,1),%ecx
  mov    %cl,0x7(%rsp)
  lea    0x10(%rsp,%rax,1),%rbx
  lea    0x10(%rsp),%r14
  mov    $0x1,%r13d
  sub    %r14,%r13
  jmp    L21
L86:
  movzbl 0x1(%rbx),%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
L21:
  mov    %r14,%rdi
  call   <strlen@plt>
  cltq
  lea    0x0(%r13,%rbx,1),%rdx
  cmp    %rdx,%rax
  ja     L86
  lea    0x10(%rsp),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,0x10(%rsp,%rax,1)
  test   %r12d,%r12d
  jle    L8
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  movb   $0x0,0x10(%rsp,%rax,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %eax,%r12d
  jge    L32
  movslq %eax,%rcx
  lea    0x10(%rsp,%rcx,1),%rdx
  lea    -0x1(%r14,%rcx,1),%rcx
  sub    %r12d,%eax
  lea    -0x1(%rax),%eax
  sub    %rax,%rcx
L13:
  movzbl -0x1(%rdx),%eax
  mov    %al,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L13
  mov    %r12d,%eax
L32:
  cltq
  movzbl 0x7(%rsp),%ecx
  mov    %cl,0x10(%rsp,%rax,1)
  lea    0x10(%rsp),%rdi
  call   <atoi@plt>
L99:
  mov    %rax,(%r15)
  cmpb   $0x30,0x7(%rsp)
  jne    L109
  movslq %ebp,%rax
  mov    $0x0,%edx
  cmp    $0x1,%ebp
  jg     L109
L3:
  mov    %rdx,0x8(%r15)
  mov    %rax,0x10(%r15)
  movsbl 0x7(%rsp),%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    0x8(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    %r15,%rax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %rax,%rcx
  mov    %rax,(%r15)
  movsbl 0x7(%rsp),%edx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  jmp    L99
L109:
  movslq %ebp,%rdx
  movslq %r12d,%rax
  jmp    L3
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D18: %lld

tool: D25: n: %lld ; m_i: %d ; tmp: %d ; %c


tool: D8: %c%lld

assistant: ```c
long long *smallest(long long n) {
  long long *result = malloc(3 * sizeof *result);
  char temp[100];
  sprintf(temp, "%lld", n);
  int min_idx = 0;
  int tmp = -1;
  do {
    tmp++;
    min_idx = smallest_idx_between(temp, tmp, strlen(temp));
  } while (min_idx == 0);
  char temp_char = temp[min_idx];
  for (size_t i = min_idx + 1; i < strlen(temp); ++i)
    temp[i - 1] = temp[i];
  temp[strlen(temp) - 1] = '\0';
  if (tmp > 0) {
    temp[strlen(temp) + 1] = '\0';
    int i;
    for (i = strlen(temp); i >= tmp + 1; --i) {
      temp[i] = temp[i - 1];
    }
    temp[i] = temp_char;
    result[0] = atoi(temp);
  } else {
    result[0] = atoi(temp);
    sprintf(temp, "%c%lld", temp_char, result[0]);
    result[0] = atoi(temp);
  }
  if (temp_char != '0' || min_idx > 1) {
    result[1] = min_idx;
    result[2] = tmp;
  } else {
    result[1] = 0;
    result[2] = min_idx;
  }
  printf("n: %lld ; m_i: %d ; tmp: %d ; %c\n", n, min_idx, tmp, temp_char);
  return result;
}
```