ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  sub    $0x58,%rsp
  movsd  D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  lea    0x20(%rsp),%rbp
  mov    %rbp,%rdi
  movsd  %xmm0,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  mov    D15(%rip),%rax
  movsd  %xmm0,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  mov    D9(%rip),%rax
  mov    %rax,0x40(%rsp)
  call   <printArray@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <isSorted@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <min@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rsp)
  call   <max@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x10(%rsp)
  call   <avg@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <sum@plt>
  movsd  0x18(%rsp),%xmm3
  mov    %r12d,%esi
  mov    $0x4,%eax
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <toIndex@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printArray@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: f64
name: unpack_data
arguments: data_label: D11
type_guessed: f64
name: unpack_data
arguments: data_label: D15
type_guessed: f64
name: unpack_data
arguments: data_label: D9
type_guessed: f64
name: unpack_data
arguments: data_label: D32
type_guessed: string

tool: D8: 3

tool: D11: 2

tool: D15: 4

tool: D9: 5.5

tool: D32: 
%f
%f
%f
%f
%d


assistant: ```c
int main() {
  double i[] = {3.0, 2.0, 3.0, 4.0, 5.5};
  printArray(i, 5);
  printf("\n%f\n%f\n%f\n%f\n%d\n", sum(i, 5), avg(i, 5), max(i, 5), min(i, 5), isSorted(i, 5));
  toIndex(i, 5);
  printArray(i, 5);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  sub    $0x58,%rsp
  movapd D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    D22(%rip),%rax
  movaps %xmm0,0x20(%rsp)
  movapd D39(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x40(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <printArray@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <isSorted@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <min@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rsp)
  call   <max@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x10(%rsp)
  call   <avg@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <sum@plt>
  movsd  0x18(%rsp),%xmm3
  mov    %r12d,%esi
  mov    $0x4,%eax
  movsd  0x10(%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <toIndex@plt>
  mov    %rbp,%rdi
  mov    $0x5,%esi
  call   <printArray@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
data_type: f64[2]
name: extract_symbolic_data
arguments: label: D22
data_type: f64
name: extract_symbolic_data
arguments: label: D39
data_type: f64[2]
name: extract_symbolic_data
arguments: label: D15
data_type: string

tool: {"D12": [3.0,2.0]}

tool: D22: 5.5

tool: {"D39": [3.0,4.0]}

tool: D15: 
%f
%f
%f
%f
%d


assistant: ```c
int main() {
  double i[] = {3.0, 2.0, 3.0, 4.0, 5.5};
  printArray(i, 5);
  printf("\n%f\n%f\n%f\n%f\n%d\n", sum(i, 5), avg(i, 5), max(i, 5), min(i, 5), isSorted(i, 5));
  toIndex(i, 5);
  printArray(i, 5);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int get_integer(char **msg) {
  int x;
  memcpy(&x, *msg, 4);
  (*msg) += 4;
  return ntohl(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_integer>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    (%rbx),%rsi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_integer(char **msg) {
  int x;
  memcpy(&x, *msg, 4);
  (*msg) += 4;
  return ntohl(x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_integer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_integer(char **msg) {
  int x;
  memcpy(&x, *msg, 4);
  (*msg) += 4;
  return ntohl(x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_integer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rbx),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  mov    0x4(%rsp),%edi
  call   <ntohl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_integer(char **msg) {
  int x;
  memcpy(&x, *msg, 4);
  (*msg) += 4;
  return ntohl(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sys$schdwk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%r10
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x11,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$schdwk(unsigned int *pidadr, void *prcnam, signed long long *daytim, signed long long *reptim) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(reptim);
    register long int _a3 asm("rdx") = (long)(daytim);
    register long int _a2 asm("rsi") = (long)(prcnam);
    register long int _a1 asm("rdi") = (long)(pidadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(17), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sys$schdwk>:
  endbr64
  mov    %rcx,%r10
  mov    $0x11,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$schdwk(unsigned int *pidadr, void *prcnam, signed long long *daytim, signed long long *reptim) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(reptim);
    register long int _a3 asm("rdx") = (long)(daytim);
    register long int _a2 asm("rsi") = (long)(prcnam);
    register long int _a1 asm("rdi") = (long)(pidadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(17), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sys$schdwk>:
  endbr64
  mov    %rcx,%r10
  mov    $0x11,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$schdwk(unsigned int *pidadr, void *prcnam, signed long long *daytim, signed long long *reptim) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(reptim);
    register long int _a3 asm("rdx") = (long)(daytim);
    register long int _a2 asm("rsi") = (long)(prcnam);
    register long int _a1 asm("rdi") = (long)(pidadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(17), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sys$schdwk>:
  endbr64
  mov    %rcx,%r10
  mov    $0x11,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$schdwk(unsigned int *pidadr, void *prcnam, signed long long *daytim, signed long long *reptim) {
  return ({
    unsigned long resultvar;
    register long int _a4 asm("r10") = (long)(reptim);
    register long int _a3 asm("rdx") = (long)(daytim);
    register long int _a2 asm("rsi") = (long)(prcnam);
    register long int _a1 asm("rdi") = (long)(pidadr);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(17), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string

tool: D3: You may think it's cold at %d...

tool: D22: 
But it's way more cold at %d!

tool: D24: 
	Brrrr..

assistant: ```c
int main() {
  int t = 10;
  printf("You may think it's cold at %d...", +t);
  printf("\nBut it's way more cold at %d!", -t);
  puts("\n\tBrrrr..");
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffff6,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string

tool: D18: You may think it's cold at %d...

tool: D3: 
But it's way more cold at %d!

tool: D24: 
	Brrrr..

assistant: ```c
int main() {
  int t = 10;
  printf("You may think it's cold at %d...", +t);
  printf("\nBut it's way more cold at %d!", -t);
  puts("\n\tBrrrr..");
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffff6,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D1
type: string

tool: D5: You may think it's cold at %d...

tool: D19: 
But it's way more cold at %d!

tool: D1: 
	Brrrr..

assistant: ```c
int main() {
  int t = 10;
  printf("You may think it's cold at %d...", +t);
  printf("\nBut it's way more cold at %d!", -t);
  puts("\n\tBrrrr..");
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffff6,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string

tool: D9: You may think it's cold at %d...

tool: D26: 
But it's way more cold at %d!

tool: D11: 
	Brrrr..

assistant: ```c
int main() {
  int t = 10;
  printf("You may think it's cold at %d...", +t);
  printf("\nBut it's way more cold at %d!", -t);
  puts("\n\tBrrrr..");
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *strerror(int errnum) {
  (void)errnum;
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strerror>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strerror(int errnum) {
  (void)errnum;
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strerror>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strerror(int errnum) {
  (void)errnum;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strerror>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strerror(int errnum) {
  (void)errnum;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<change_rows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L13:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rsi,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x4,-0x8(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void change_rows(int con[500][5], int i, int j) {
  int t;
  int k = 0;
  for (k = 0; k < 5; k++) {
    t = con[i][k];
    con[i][k] = con[j][k];
    con[j][k] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<change_rows>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,4),%rax
  lea    (%rdi,%rax,4),%rcx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdi,%rax,4),%rdx
  mov    $0x0,%eax
L6:
  mov    (%rcx,%rax,1),%esi
  mov    (%rdx,%rax,1),%edi
  mov    %edi,(%rcx,%rax,1)
  mov    %esi,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L6
  ret
```

assistant: ```c
void change_rows(int con[500][5], int i, int j) {
  int t;
  int k = 0;
  for (k = 0; k < 5; k++) {
    t = con[i][k];
    con[i][k] = con[j][k];
    con[j][k] = t;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_rows>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rsi,4),%rax
  lea    (%rdi,%rax,4),%rcx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdi,%rax,4),%rdx
  xor    %eax,%eax
L2:
  mov    (%rcx,%rax,1),%esi
  mov    (%rdx,%rax,1),%edi
  mov    %edi,(%rcx,%rax,1)
  mov    %esi,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L2
  ret
```

assistant: ```c
void change_rows(int con[500][5], int i, int j) {
  int t;
  int k = 0;
  for (k = 0; k < 5; k++) {
    t = con[i][k];
    con[i][k] = con[j][k];
    con[j][k] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<change_rows>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rsi,4),%rcx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rcx
  shl    $0x2,%rdx
  lea    (%rdi,%rcx,1),%rsi
  lea    (%rdi,%rdx,1),%rax
  lea    0x10(%rcx),%rdi
  cmp    %rdx,%rdi
  jle    L10
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jg     L6
L10:
  movdqu (%rsi),%xmm0
  movdqu (%rax),%xmm1
  movups %xmm1,(%rsi)
  mov    0x10(%rax),%ecx
  movups %xmm0,(%rax)
  mov    0x10(%rsi),%edx
  mov    %ecx,0x10(%rsi)
  mov    %edx,0x10(%rax)
  ret
  nop
L6:
  mov    (%rsi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    0x4(%rax),%ecx
  mov    %edx,(%rax)
  mov    0x4(%rsi),%edx
  mov    %ecx,0x4(%rsi)
  mov    0x8(%rax),%ecx
  mov    %edx,0x4(%rax)
  mov    0x8(%rsi),%edx
  mov    %ecx,0x8(%rsi)
  mov    0xc(%rax),%ecx
  mov    %edx,0x8(%rax)
  mov    0xc(%rsi),%edx
  mov    %ecx,0xc(%rsi)
  mov    0x10(%rax),%ecx
  mov    %edx,0xc(%rax)
  mov    0x10(%rsi),%edx
  mov    %ecx,0x10(%rsi)
  mov    %edx,0x10(%rax)
  ret
```

assistant: ```c
void change_rows(int con[500][5], int i, int j) {
  int t;
  int k = 0;
  for (k = 0; k < 5; k++) {
    t = con[i][k];
    con[i][k] = con[j][k];
    con[j][k] = t;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<orgfx_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
L8:
  mov    $0xb8000004,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void orgfx_wait(unsigned int reg_spaces) {
  while (*((volatile unsigned int *)((0xB8000000 + 0x04))) & (1 << 0))
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<orgfx_wait>:
  endbr64
  mov    $0xb8000004,%edx
L9:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L9
  ret
```

assistant: ```c
void orgfx_wait(unsigned int reg_spaces) {
  while (*((volatile unsigned int *)((0xB8000000 + 0x04))) & (1 << 0))
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<orgfx_wait>:
  endbr64
  mov    $0xb8000004,%edx
  nopl   0x0(%rax)
L6:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L6
  ret
```

assistant: ```c
void orgfx_wait(unsigned int reg_spaces) {
  while (*((volatile unsigned int *)((0xB8000000 + 0x04))) & (1 << 0))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<orgfx_wait>:
  endbr64
  mov    $0xb8000004,%edx
  nopl   0x0(%rax)
L5:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L5
  ret
```

assistant: ```c
void orgfx_wait(unsigned int reg_spaces) {
  while (*((volatile unsigned int *)((0xB8000000 + 0x04))) & (1 << 0))
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_version_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L38
L22:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L46
  addq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_version_line@plt>
  test   %rax,%rax
  je     L17
  mov    -0x38(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x48(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  jmp    L47
L17:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  sub    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L38:
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
  jmp    L12
L46:
  nop
L12:
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L47:
  leave
  ret
```

assistant: ```c
int get_version_line(const uint8_t *in, size_t in_len, const uint8_t **ver, size_t *ver_len, const uint8_t **rest, size_t *rest_len) {
  const uint8_t *cur;
  size_t cur_len;
  cur = in;
  cur_len = in_len;
  while (cur_len > 0) {
    const uint8_t *end = memchr(cur, '\n', cur_len);
    if (end == NULL)
      break;
    end++;
    if (is_version_line(cur, end - cur)) {
      *ver = cur;
      *ver_len = end - cur;
      *rest = end;
      *rest_len = (in + in_len) - end;
      return 0;
    }
    cur_len -= end - cur;
    cur = end;
  }
  *ver = NULL;
  *ver_len = 0;
  *rest = cur;
  *rest_len = in + in_len - cur;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_version_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %r9,0x18(%rsp)
  test   %rsi,%rsi
  je     L17
  mov    %rsi,%r13
  mov    %rdi,%r12
  jmp    L21
L20:
  mov    %rbx,%r12
L21:
  mov    %r13,%rdx
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L49
  lea    0x4(%rax),%rbx
  mov    %rbx,%rbp
  sub    %r12,%rbp
  sar    $0x2,%rbp
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <is_version_line@plt>
  test   %rax,%rax
  jne    L0
  sub    %rbp,%r13
  jne    L20
  mov    %rbx,%r12
L49:
  lea    (%r15,%r14,4),%rax
  sub    %r12,%rax
  sar    $0x2,%rax
  mov    $0x0,%edx
  mov    $0x0,%ebp
L66:
  mov    (%rsp),%rcx
  mov    %rdx,(%rcx)
  mov    0x8(%rsp),%rcx
  mov    %rbp,(%rcx)
  mov    0x10(%rsp),%rcx
  mov    %r12,(%rcx)
  mov    0x18(%rsp),%rcx
  mov    %rax,(%rcx)
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  lea    (%r15,%r14,4),%rax
  sub    %rbx,%rax
  sar    $0x2,%rax
  mov    %r12,%rdx
  mov    %rbx,%r12
  jmp    L66
L17:
  mov    %rdi,%r12
  jmp    L49
```

assistant: ```c
int get_version_line(const uint8_t *in, size_t in_len, const uint8_t **ver, size_t *ver_len, const uint8_t **rest, size_t *rest_len) {
  const uint8_t *cur;
  size_t cur_len;
  cur = in;
  cur_len = in_len;
  while (cur_len > 0) {
    const uint8_t *end = memchr(cur, '\n', cur_len);
    if (end == NULL)
      break;
    end++;
    if (is_version_line(cur, end - cur)) {
      *ver = cur;
      *ver_len = end - cur;
      *rest = end;
      *rest_len = (in + in_len) - end;
      return 0;
    }
    cur_len -= end - cur;
    cur = end;
  }
  *ver = NULL;
  *ver_len = 0;
  *rest = cur;
  *rest_len = in + in_len - cur;
  return 0;
}
```