ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L18
  movq   $0x1,-0x18(%rbp)
  jmp    L16
L18:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   %rbx,%rax
  mov    %rax,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long int factorial(int x) {
  long int resultado = x;
  if (x < 2)
    resultado = 1;
  else
    resultado = x * factorial(x - 1);
  return resultado;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L1
  ret
L1:
  push   %rbx
  mov    %edi,%ebx
  lea    -0x1(%rdi),%edi
  call   <factorial>
  movslq %ebx,%rbx
  imul   %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long int factorial(int x) {
  long int resultado = x;
  if (x < 2)
    resultado = 1;
  else
    resultado = x * factorial(x - 1);
  return resultado;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  movslq %edi,%rax
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L11
  nopw   0x0(%rax,%rax,1)
L5:
  imul   %rax,%r8
  sub    $0x1,%rax
  cmp    $0x1,%eax
  jne    L5
L11:
  mov    %r8,%rax
  ret
```

assistant: ```c
long int factorial(int x) {
  long int resultado = x;
  if (x < 2)
    resultado = 1;
  else
    resultado = x * factorial(x - 1);
  return resultado;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  movslq %edi,%rax
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jle    L9
  nopw   0x0(%rax,%rax,1)
L17:
  imul   %rax,%r8
  sub    $0x1,%rax
  cmp    $0x1,%eax
  jne    L17
L9:
  mov    %r8,%rax
  ret
```

assistant: ```c
long int factorial(int x) {
  long int resultado = x;
  if (x < 2)
    resultado = 1;
  else
    resultado = x * factorial(x - 1);
  return resultado;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<S_Search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L9
  cmpl   $0x7f,-0x4(%rbp)
  jle    L17
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int S_Search(int *arr, int key) {
  int i = 0;
  while (arr[i] != key && i < 128)
    ++i;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<S_Search>:
  endbr64
  cmp    (%rdi),%esi
  je     L21
  mov    $0x1,%eax
L8:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  setne  %cl
  cmp    $0x7f,%eax
  setle  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L8
L9:
  mov    %r8d,%eax
  ret
L21:
  mov    $0x0,%r8d
  jmp    L9
```

assistant: ```c
int S_Search(int *arr, int key) {
  int i = 0;
  while (arr[i] != key && i < 128)
    ++i;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<S_Search>:
  endbr64
  cmp    (%rdi),%esi
  je     L22
  mov    $0x1,%eax
  jmp    L16
  nop
L44:
  add    $0x1,%rax
  cmp    $0x81,%rax
  je     L24
L16:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  jne    L44
L7:
  mov    %r8d,%eax
  ret
L24:
  mov    $0x80,%r8d
  mov    %r8d,%eax
  ret
L22:
  xor    %r8d,%r8d
  jmp    L7
```

assistant: ```c
int S_Search(int *arr, int key) {
  int i = 0;
  while (arr[i] != key && i < 128)
    ++i;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<S_Search>:
  endbr64
  cmp    (%rdi),%esi
  je     L26
  mov    $0x1,%eax
  jmp    L40
  nop
L20:
  add    $0x1,%rax
  cmp    $0x81,%rax
  je     L12
L40:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  jne    L20
L10:
  mov    %r8d,%eax
  ret
L12:
  mov    $0x80,%r8d
  mov    %r8d,%eax
  ret
L26:
  xor    %r8d,%r8d
  jmp    L10
```

assistant: ```c
int S_Search(int *arr, int key) {
  int i = 0;
  while (arr[i] != key && i < 128)
    ++i;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<createArrayType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5b,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5d,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *createArrayType(char *type) {
  int len = strlen(type);
  char *ret = (char *)malloc(len + 3);
  strncpy(ret, type, len);
  free(type);
  ret[len] = '[';
  ret[len + 1] = ']';
  ret[len + 2] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<createArrayType>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x3(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
  movslq %ebx,%rbx
  movb   $0x5b,0x0(%rbp,%rbx,1)
  movb   $0x5d,0x1(%rbp,%rbx,1)
  movb   $0x0,0x2(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *createArrayType(char *type) {
  int len = strlen(type);
  char *ret = (char *)malloc(len + 3);
  strncpy(ret, type, len);
  free(type);
  ret[len] = '[';
  ret[len + 1] = ']';
  ret[len + 2] = '\0';
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<createArrayType>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x3(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x5b,(%r12,%rbx,1)
  mov    %r12,%rax
  movb   $0x5d,0x1(%r12,%rbx,1)
  movb   $0x0,0x2(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *createArrayType(char *type) {
  int len = strlen(type);
  char *ret = (char *)malloc(len + 3);
  strncpy(ret, type, len);
  free(type);
  ret[len] = '[';
  ret[len + 1] = ']';
  ret[len + 2] = '\0';
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<createArrayType>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  lea    0x3(%rbx),%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movb   $0x5b,(%r12,%rbx,1)
  mov    %r12,%rax
  movb   $0x5d,0x1(%r12,%rbx,1)
  movb   $0x0,0x2(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *createArrayType(char *type) {
  int len = strlen(type);
  char *ret = (char *)malloc(len + 3);
  strncpy(ret, type, len);
  free(type);
  ret[len] = '[';
  ret[len + 1] = ']';
  ret[len + 2] = '\0';
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  movzbl -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  movw   $0x0,-0xa(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <htobe16@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
unsigned short read16(FILE *f, unsigned char offset) {
  fseek(f, offset, SEEK_SET);
  unsigned short s = 0;
  fread(&s, sizeof(unsigned short), 1, f);
  return htobe16(s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read16>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl %sil,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  movw   $0x0,0x6(%rsp)
  lea    0x6(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  movzwl 0x6(%rsp),%edi
  call   <htobe16@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short read16(FILE *f, unsigned char offset) {
  fseek(f, offset, SEEK_SET);
  unsigned short s = 0;
  fread(&s, sizeof(unsigned short), 1, f);
  return htobe16(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read16>:
  endbr64
  push   %r12
  movzbl %sil,%esi
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %ax,0x6(%rsp)
  call   <fread@plt>
  movzwl 0x6(%rsp),%edi
  call   <htobe16@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short read16(FILE *f, unsigned char offset) {
  fseek(f, offset, SEEK_SET);
  unsigned short s = 0;
  fread(&s, sizeof(unsigned short), 1, f);
  return htobe16(s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read16>:
  endbr64
  push   %r12
  movzbl %sil,%esi
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %ax,0x6(%rsp)
  call   <fread@plt>
  movzwl 0x6(%rsp),%edi
  call   <htobe16@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short read16(FILE *f, unsigned char offset) {
  fseek(f, offset, SEEK_SET);
  unsigned short s = 0;
  fread(&s, sizeof(unsigned short), 1, f);
  return htobe16(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fb_CVLONGINTFROMD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
long long fb_CVLONGINTFROMD(double d) {
  do {
    if ((8) == sizeof(d) && (8) == sizeof(long long)) {
      long long to;
      memcpy(&to, &d, 8);
      return to;
    } else {
      return (long long)0;
    }
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fb_CVLONGINTFROMD>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long fb_CVLONGINTFROMD(double d) {
  do {
    if ((8) == sizeof(d) && (8) == sizeof(long long)) {
      long long to;
      memcpy(&to, &d, 8);
      return to;
    } else {
      return (long long)0;
    }
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fb_CVLONGINTFROMD>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x8,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long fb_CVLONGINTFROMD(double d) {
  do {
    if ((8) == sizeof(d) && (8) == sizeof(long long)) {
      long long to;
      memcpy(&to, &d, 8);
      return to;
    } else {
      return (long long)0;
    }
  } while (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fb_CVLONGINTFROMD>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x8,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long fb_CVLONGINTFROMD(double d) {
  do {
    if ((8) == sizeof(d) && (8) == sizeof(long long)) {
      long long to;
      memcpy(&to, &d, 8);
      return to;
    } else {
      return (long long)0;
    }
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ibv_create_ah>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_create_ah@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct ibv_ah *ibv_create_ah(struct ibv_pd *pd, struct ibv_ah_attr *attr) {
  dmtcp_plugin_disable_ckpt();
  struct ibv_ah *rslt = _create_ah(pd, attr);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ibv_create_ah>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <_create_ah@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct ibv_ah *ibv_create_ah(struct ibv_pd *pd, struct ibv_ah_attr *attr) {
  dmtcp_plugin_disable_ckpt();
  struct ibv_ah *rslt = _create_ah(pd, attr);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ibv_create_ah>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_create_ah@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct ibv_ah *ibv_create_ah(struct ibv_pd *pd, struct ibv_ah_attr *attr) {
  dmtcp_plugin_disable_ckpt();
  struct ibv_ah *rslt = _create_ah(pd, attr);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ibv_create_ah>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <dmtcp_plugin_disable_ckpt@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_create_ah@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <dmtcp_plugin_enable_ckpt@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct ibv_ah *ibv_create_ah(struct ibv_pd *pd, struct ibv_ah_attr *attr) {
  dmtcp_plugin_disable_ckpt();
  struct ibv_ah *rslt = _create_ah(pd, attr);
  dmtcp_plugin_enable_ckpt();
  return rslt;
}
```
user: What is the c source code of the assembly code below:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L14:
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x7a11f,-0x4(%rbp)
  jle    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay() {
  int i;
  for (i = 0; i < 500000; i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delay>:
  endbr64
  mov    $0x7a120,%eax
L1:
  sub    $0x1,%eax
  jne    L1
  ret
```

assistant: ```c
void delay() {
  int i;
  for (i = 0; i < 500000; i++)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<delay>:
  endbr64
  ret
```

assistant: ```c
void delay() {
  int i;
  for (i = 0; i < 500000; i++)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<delay>:
  endbr64
  ret
```

assistant: ```c
void delay() {
  int i;
  for (i = 0; i < 500000; i++)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mk_dirs>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L121:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L121
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x100108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  test   %rdi,%rdi
  je     L99
  mov    %rdi,%rsi
  lea    0x100(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L97
  sub    $0x1,%eax
  movslq %eax,%rdx
  cmpb   $0x2f,0x100(%rsp,%rdx,1)
  je     L9
L97:
  mov    D47(%rip),%rbp
L94:
  lea    0x100(%rsp),%rdi
  mov    0x0(%rbp),%esi
  call   <mkdir@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L6
  mov    D41(%rip),%rax
  mov    (%rax),%rax
  mov    D4(%rip),%rdx
  cmp    (%rdx),%rax
  je     L123
  mov    D34(%rip),%rdx
  cmp    (%rdx),%rax
  je     L6
  mov    D6(%rip),%rdx
  cmp    (%rdx),%rax
  je     L6
  lea    0x100(%rsp),%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  lea    0x100(%rsp),%rsi
  mov    %rsp,%rbx
  mov    %eax,%edx
  sub    %esi,%edx
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <mk_dirs>
  jmp    L94
L9:
  movb   $0x0,0x100(%rsp,%rdx,1)
  jmp    L97
L99:
  mov    $0xffffffff,%ebx
  jmp    L6
L123:
  mov    $0x0,%ebx
L6:
  mov    0x100108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %ebx,%eax
  add    $0x100118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mk_dirs(char *path) {
  int ret;
  int len;
  char subpath[256] = "";
  char *pos = NULL;
  char pth[(1 * 1024 * 1024)];
  if (path == NULL) {
    return -1;
  }
  strcpy(pth, path);
  if ((len = strlen(pth)) > 0 && pth[len - 1] == '/') {
    pth[len - 1] = '\0';
  }
  while ((ret = mkdir(pth, S_IRWXU)) != 0) {
    if (errno == EEXIST) {
      return 0;
    } else if (errno == EACCES || errno == EROFS) {
      return ret;
    }
    if ((pos = strrchr(pth, '/')) == NULL) {
      return ret;
    }
    strncat(subpath, pth, pos - pth);
    mk_dirs(subpath);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mk_dirs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0x118,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x100108(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  test   %rdi,%rdi
  je     L115
  lea    0x100(%rsp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L54
  sub    $0x1,%eax
  cltq
  cmpb   $0x2f,0x100(%rsp,%rax,1)
  je     L71
L54:
  mov    D42(%rip),%rbp
  mov    %rsp,%r13
L9:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L83
  mov    D6(%rip),%rax
  mov    D25(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L111
  mov    D10(%rip),%rdx
  cmp    (%rdx),%rax
  je     L83
  mov    D14(%rip),%rdx
  cmp    (%rdx),%rax
  je     L83
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L83
  mov    %eax,%edx
  mov    %r13,%rdi
  mov    %rbx,%rsi
  sub    %ebx,%edx
  call   <strncat@plt>
  mov    %r13,%rdi
  call   <mk_dirs>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L111:
  xor    %r12d,%r12d
L83:
  mov    0x100108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x100118,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  movb   $0x0,0x100(%rsp,%rax,1)
  jmp    L54
L115:
  mov    $0xffffffff,%r12d
  jmp    L83
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mk_dirs(char *path) {
  int ret;
  int len;
  char subpath[256] = "";
  char *pos = NULL;
  char pth[(1 * 1024 * 1024)];
  if (path == NULL) {
    return -1;
  }
  strcpy(pth, path);
  if ((len = strlen(pth)) > 0 && pth[len - 1] == '/') {
    pth[len - 1] = '\0';
  }
  while ((ret = mkdir(pth, S_IRWXU)) != 0) {
    if (errno == EEXIST) {
      return 0;
    } else if (errno == EACCES || errno == EROFS) {
      return ret;
    }
    if ((pos = strrchr(pth, '/')) == NULL) {
      return ret;
    }
    strncat(subpath, pth, pos - pth);
    mk_dirs(subpath);
  }
  return ret;
}
```