ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq -0x2c(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L41:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L21:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L44
  orq    $0x0,-0x8(%rsp,%rax,1)
L44:
  mov    %rsp,%r13
  lea    D18(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,-0x2c(%rbp)
  jle    L68
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D11(%rip),%r14
L1:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%eax
  add    $0x4,%r12
  cmp    %ebx,%eax
  jg     L1
  test   %eax,%eax
  jle    L68
  mov    $0x0,%ebx
  lea    D29(%rip),%r12
L49:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,-0x2c(%rbp)
  jg     L49
L68:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D38
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D18
datatype: string
name: read_data
arguments: data_label: D29
datatype: string

tool: D38: Enter the Number of elements in the array : 

tool: D11: %d

tool: D22: The number of elements in the array is %d


tool: D18: Number of elements of the arrays is 

tool: D29: Element at %d is %d 


assistant: ```c
int main() {
  int num = 0;
  printf("Enter the Number of elements in the array : ");
  scanf("%d", &num);
  printf("The number of elements in the array is %d\n", num);
  int arr[num];
  int i = 0;
  printf("Number of elements of the arrays is \n");
  for (i = 0; i < num; i++) {
    scanf("%d", &arr[i]);
  }
  for (i = 0; i < num; i++) {
    printf("Element at %d is %d \n", i, arr[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D26(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L82
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L38
L82:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L83
L10:
  lea    D49(%rip),%rdi
  mov    %rsp,%r13
  xor    %ebx,%ebx
  call   <puts@plt>
  cmpl   $0x0,-0x2c(%rbp)
  mov    %r13,%r12
  jle    L62
  xchg   %ax,%ax
L66:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L66
  test   %eax,%eax
  jle    L62
  xor    %ebx,%ebx
  lea    D48(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L28
L62:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L83:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L10
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D36
data_type: string
name: parse_data
arguments: label: D26
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D49
data_type: string
name: parse_data
arguments: label: D48
data_type: string

tool: D36: Enter the Number of elements in the array : 

tool: D26: %d

tool: D0: The number of elements in the array is %d


tool: D49: Number of elements of the arrays is 

tool: D48: Element at %d is %d 


assistant: ```c
int main() {
  int num = 0;
  printf("Enter the Number of elements in the array : ");
  scanf("%d", &num);
  printf("The number of elements in the array is %d\n", num);
  int arr[num];
  int i = 0;
  printf("Number of elements of the arrays is \n");
  for (i = 0; i < num; i++) {
    scanf("%d", &arr[i]);
  }
  for (i = 0; i < num; i++) {
    printf("Element at %d is %d \n", i, arr[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D43(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L73
L88:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L88
L73:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L76
L8:
  lea    D10(%rip),%rdi
  mov    %rsp,%r13
  xor    %ebx,%ebx
  call   <puts@plt>
  cmpl   $0x0,-0x2c(%rbp)
  mov    %r13,%r12
  jle    L54
  xchg   %ax,%ax
L59:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L59
  test   %eax,%eax
  jle    L54
  xor    %ebx,%ebx
  lea    D30(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L86:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L86
L54:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L76:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L8
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D38
type: string
name: retrieve_data
arguments: tag: D43
type: string
name: retrieve_data
arguments: tag: D31
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D30
type: string

tool: D38: Enter the Number of elements in the array : 

tool: D43: %d

tool: D31: The number of elements in the array is %d


tool: D10: Number of elements of the arrays is 

tool: D30: Element at %d is %d 


assistant: ```c
int main() {
  int num = 0;
  printf("Enter the Number of elements in the array : ");
  scanf("%d", &num);
  printf("The number of elements in the array is %d\n", num);
  int arr[num];
  int i = 0;
  printf("Number of elements of the arrays is \n");
  for (i = 0; i < num; i++) {
    scanf("%d", &arr[i]);
  }
  for (i = 0; i < num; i++) {
    printf("Element at %d is %d \n", i, arr[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: %s 1.3.4


assistant: ```c
void version(const char *progname) {
  printf("%s "
         "1.3.4"
         "\n",
         progname);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %s 1.3.4


assistant: ```c
void version(const char *progname) {
  printf("%s "
         "1.3.4"
         "\n",
         progname);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<version>:
  endbr64
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: %s 1.3.4


assistant: ```c
void version(const char *progname) {
  printf("%s "
         "1.3.4"
         "\n",
         progname);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<version>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: %s 1.3.4


assistant: ```c
void version(const char *progname) {
  printf("%s "
         "1.3.4"
         "\n",
         progname);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  mov    $0xffffffa2,%edx
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 538836386UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x45,%eax
  mov    $0xffffffa2,%edx
  imul   %edx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 538836386UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffa2,%edx
  add    $0x45,%eax
  imul   %edx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 538836386UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0xffffffa2,%edx
  add    $0x45,%eax
  imul   %edx,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        state[0UL] += state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 538836386UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NutDecodePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  cmpb   $0x2f,-0x19(%rbp)
  je     L25
  mov    $0x0,%eax
  jmp    L15
L37:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L53
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <NutDecodeHex@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  js     L53
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <NutDecodeHex@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L53
  addq   $0x2,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
L53:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L95
  mov    -0x10(%rbp),%rax
  movb   $0x2f,(%rax)
L95:
  cmpb   $0x2e,-0x19(%rbp)
  je     L107
  cmpb   $0x2f,-0x19(%rbp)
  jne    L1
L107:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L25
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L25
L1:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
L25:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  jmp    L14
L79:
  nop
L14:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L15:
  leave
  ret
```

assistant: ```c
char *NutDecodePath(char *path) {
  int x1;
  int x2;
  char *src = path;
  char *dst = path;
  char last = *path;
  if (last != '/')
    return 0;
  while (*++src) {
    if (*src == '%' && (x1 = NutDecodeHex(*(src + 1))) >= 0 && (x2 = NutDecodeHex(*(src + 2))) >= 0) {
      src += 2;
      if ((*src = x1 * 16 + x2) == 0)
        break;
    }
    if (*src == '\\')
      *src = '/';
    if ((last != '.' && last != '/') || (*src != '.' && *src != '/'))
      *dst++ = last = *src;
  }
  *dst = 0;
  return path;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NutDecodePath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  mov    $0x0,%eax
  cmp    $0x2f,%bpl
  jne    L103
  mov    %rdi,%r13
  lea    0x1(%rdi),%rbx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L74
  mov    %rdi,%r12
  mov    %rdi,%r14
  jmp    L92
L71:
  movsbl 0x2(%r14),%edi
  call   <NutDecodeHex@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  js     L62
  movsbl 0x3(%r14),%edi
  call   <NutDecodeHex@plt>
  test   %eax,%eax
  js     L62
  lea    0x3(%r14),%rbx
  shl    $0x4,%r15d
  add    %eax,%r15d
  mov    %r15b,0x3(%r14)
  test   %r15b,%r15b
  jne    L62
  jmp    L66
L76:
  movb   $0x2f,(%rbx)
  lea    -0x2e(%rbp),%eax
  cmp    $0x1,%al
  jbe    L43
L90:
  movzbl (%rbx),%ebp
  mov    %bpl,(%r12)
  lea    0x1(%r12),%r12
L43:
  lea    0x1(%rbx),%rdx
  movzbl 0x1(%rbx),%eax
  test   %al,%al
  je     L66
  mov    %rbx,%r14
  mov    %rdx,%rbx
L92:
  cmp    $0x25,%al
  je     L71
L62:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  je     L76
  lea    -0x2e(%rbp),%edx
  cmp    $0x1,%dl
  ja     L90
  sub    $0x2e,%eax
  cmp    $0x1,%al
  ja     L90
  jmp    L43
L74:
  mov    %rdi,%r12
L66:
  movb   $0x0,(%r12)
  mov    %r13,%rax
L103:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *NutDecodePath(char *path) {
  int x1;
  int x2;
  char *src = path;
  char *dst = path;
  char last = *path;
  if (last != '/')
    return 0;
  while (*++src) {
    if (*src == '%' && (x1 = NutDecodeHex(*(src + 1))) >= 0 && (x2 = NutDecodeHex(*(src + 2))) >= 0) {
      src += 2;
      if ((*src = x1 * 16 + x2) == 0)
        break;
    }
    if (*src == '\\')
      *src = '/';
    if ((last != '.' && last != '/') || (*src != '.' && *src != '/'))
      *dst++ = last = *src;
  }
  *dst = 0;
  return path;
}
```
user: What is the c source code of the assembly code below:

```asm
<NutDecodePath>:
  endbr64
  cmpb   $0x2f,(%rdi)
  jne    L73
  push   %r15
  push   %r14
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L55
  mov    $0x2f,%r15d
  mov    %rdi,%r14
  mov    %rdi,%rbp
  jmp    L43
  nopl   0x0(%rax)
L74:
  cmp    $0x1,%dl
  jbe    L19
L138:
  mov    %al,(%r14)
  mov    %eax,%r15d
  add    $0x1,%r14
L91:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%r13
  test   %al,%al
  je     L120
L43:
  cmp    $0x25,%al
  je     L99
L125:
  movzbl 0x0(%r13),%eax
  mov    %r13,%rbp
L67:
  lea    -0x2e(%r15),%edx
  cmp    $0x5c,%al
  jne    L74
  movb   $0x2f,0x0(%rbp)
  mov    $0x2f,%eax
  cmp    $0x1,%dl
  ja     L138
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%r13
  test   %al,%al
  jne    L43
L120:
  movb   $0x0,(%r14)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L19:
  lea    -0x2e(%rax),%edx
  cmp    $0x1,%dl
  ja     L138
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L99:
  movsbl 0x2(%rbp),%edi
  call   <NutDecodeHex@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L125
  movsbl 0x3(%rbp),%edi
  call   <NutDecodeHex@plt>
  test   %eax,%eax
  js     L125
  shl    $0x4,%ebx
  lea    0x3(%rbp),%rdx
  add    %ebx,%eax
  mov    %al,0x3(%rbp)
  test   %al,%al
  je     L120
  mov    %rdx,%rbp
  jmp    L67
  nopl   0x0(%rax)
L73:
  xor    %eax,%eax
  ret
L55:
  mov    %rdi,%r14
  jmp    L120
```

assistant: ```c
char *NutDecodePath(char *path) {
  int x1;
  int x2;
  char *src = path;
  char *dst = path;
  char last = *path;
  if (last != '/')
    return 0;
  while (*++src) {
    if (*src == '%' && (x1 = NutDecodeHex(*(src + 1))) >= 0 && (x2 = NutDecodeHex(*(src + 2))) >= 0) {
      src += 2;
      if ((*src = x1 * 16 + x2) == 0)
        break;
    }
    if (*src == '\\')
      *src = '/';
    if ((last != '.' && last != '/') || (*src != '.' && *src != '/'))
      *dst++ = last = *src;
  }
  *dst = 0;
  return path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<NutDecodePath>:
  endbr64
  cmpb   $0x2f,(%rdi)
  jne    L79
  push   %r15
  push   %r14
  lea    0x1(%rdi),%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L59
  mov    $0x2f,%r15d
  mov    %rdi,%r13
  mov    %rdi,%rbp
  jmp    L101
  nopl   0x0(%rax)
L18:
  cmp    $0x1,%dl
  jbe    L162
L118:
  mov    %al,0x0(%r13)
  mov    %eax,%r15d
  add    $0x1,%r13
L134:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%r14
  test   %al,%al
  je     L149
L101:
  cmp    $0x25,%al
  je     L121
  mov    %r14,%rbp
L10:
  lea    -0x2e(%r15),%edx
  cmp    $0x5c,%al
  jne    L18
  movb   $0x2f,0x0(%rbp)
  mov    $0x2f,%eax
  cmp    $0x1,%dl
  ja     L118
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%r14
  test   %al,%al
  jne    L101
L149:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L162:
  lea    -0x2e(%rax),%edx
  cmp    $0x1,%dl
  ja     L118
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L121:
  movsbl 0x2(%rbp),%edi
  call   <NutDecodeHex@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L90
L48:
  movzbl (%r14),%eax
  mov    %r14,%rbp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L90:
  movsbl 0x3(%rbp),%edi
  call   <NutDecodeHex@plt>
  test   %eax,%eax
  js     L48
  shl    $0x4,%ebx
  lea    0x3(%rbp),%rdx
  add    %ebx,%eax
  mov    %al,0x3(%rbp)
  test   %al,%al
  je     L149
  mov    %rdx,%rbp
  jmp    L10
  nopl   (%rax)
L79:
  xor    %eax,%eax
  ret
L59:
  mov    %rdi,%r13
  jmp    L149
```

assistant: ```c
char *NutDecodePath(char *path) {
  int x1;
  int x2;
  char *src = path;
  char *dst = path;
  char last = *path;
  if (last != '/')
    return 0;
  while (*++src) {
    if (*src == '%' && (x1 = NutDecodeHex(*(src + 1))) >= 0 && (x2 = NutDecodeHex(*(src + 2))) >= 0) {
      src += 2;
      if ((*src = x1 * 16 + x2) == 0)
        break;
    }
    if (*src == '\\')
      *src = '/';
    if ((last != '.' && last != '/') || (*src != '.' && *src != '/'))
      *dst++ = last = *src;
  }
  *dst = 0;
  return path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L2
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void string_clear(char *str) {
  if (str) {
    const int len = strlen(str);
    if (len > 0)
      memset(str, 0, len);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_clear>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jg     L24
L20:
  pop    %rbx
  ret
L24:
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  jmp    L20
L11:
  ret
```

assistant: ```c
void string_clear(char *str) {
  if (str) {
    const int len = strlen(str);
    if (len > 0)
      memset(str, 0, len);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_clear>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L17
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void string_clear(char *str) {
  if (str) {
    const int len = strlen(str);
    if (len > 0)
      memset(str, 0, len);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_clear>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L11
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  jmp    1070 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void string_clear(char *str) {
  if (str) {
    const int len = strlen(str);
    if (len > 0)
      memset(str, 0, len);
  }
}
```