ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bf_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <get_hashv@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L1:
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp,%rax,4),%eax
  shr    $0x3,%eax
  mov    %eax,%esi
  mov    %esi,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp,%rax,4),%eax
  and    $0x7,%eax
  mov    $0x1,%edi
  mov    %eax,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  mov    %eax,%ecx
  mov    %esi,%esi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  or     %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x1,-0x14(%rbp)
  jbe    L1
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void bf_add(char *bf, char *line) {
  unsigned i, hashv[2];
  get_hashv(line, strlen(line), hashv);
  for (i = 0; i < 2; i++)
    (bf[hashv[i] / 8] |= (1 << (hashv[i] % 8)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bf_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  call   <get_hashv@plt>
  mov    (%rsp),%ecx
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  and    $0x7,%ecx
  mov    $0x1,%edx
  mov    %edx,%edi
  shl    %cl,%edi
  or     %dil,(%rbx,%rax,1)
  mov    0x4(%rsp),%ecx
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  and    $0x7,%ecx
  shl    %cl,%edx
  or     %dl,(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bf_add(char *bf, char *line) {
  unsigned i, hashv[2];
  get_hashv(line, strlen(line), hashv);
  for (i = 0; i < 2; i++)
    (bf[hashv[i] / 8] |= (1 << (hashv[i] % 8)));
}
```
user: What is the c source code of the assembly code below:

```asm
<bf_add>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <get_hashv@plt>
  mov    (%rsp),%ecx
  mov    $0x1,%edx
  mov    %edx,%edi
  mov    %ecx,%eax
  and    $0x7,%ecx
  shl    %cl,%edi
  mov    0x4(%rsp),%ecx
  shr    $0x3,%eax
  or     %dil,(%rbx,%rax,1)
  mov    %ecx,%eax
  and    $0x7,%ecx
  shr    $0x3,%eax
  shl    %cl,%edx
  or     %dl,(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bf_add(char *bf, char *line) {
  unsigned i, hashv[2];
  get_hashv(line, strlen(line), hashv);
  for (i = 0; i < 2; i++)
    (bf[hashv[i] / 8] |= (1 << (hashv[i] % 8)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bf_add>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rdx
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <get_hashv@plt>
  mov    (%rsp),%ecx
  mov    $0x1,%edx
  mov    %edx,%edi
  mov    %ecx,%eax
  and    $0x7,%ecx
  shl    %cl,%edi
  mov    0x4(%rsp),%ecx
  shr    $0x3,%eax
  or     %dil,(%rbx,%rax,1)
  mov    %ecx,%eax
  and    $0x7,%ecx
  shr    $0x3,%eax
  shl    %cl,%edx
  or     %dl,(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bf_add(char *bf, char *line) {
  unsigned i, hashv[2];
  get_hashv(line, strlen(line), hashv);
  for (i = 0; i < 2; i++)
    (bf[hashv[i] / 8] |= (1 << (hashv[i] % 8)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_setcharzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L19:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L9:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L19
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *_setcharzero(int num, unsigned char *ptr) {
  while (num--) {
    *ptr++ = 0;
  }
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_setcharzero>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %edi,%edi
  je     L2
  mov    %edi,%edi
  lea    (%rsi,%rdi,1),%rcx
  mov    %rsi,%rdx
L15:
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L15
  mov    %eax,%eax
  lea    0x1(%rsi,%rax,1),%rax
  ret
L2:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned char *_setcharzero(int num, unsigned char *ptr) {
  while (num--) {
    *ptr++ = 0;
  }
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_setcharzero>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L6
  push   %rbx
  lea    -0x1(%rdi),%ebx
  xor    %esi,%esi
  mov    %rcx,%rdi
  add    $0x1,%rbx
  mov    %rbx,%rdx
  call   <memset@plt>
  lea    (%rax,%rbx,1),%rax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned char *_setcharzero(int num, unsigned char *ptr) {
  while (num--) {
    *ptr++ = 0;
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_setcharzero>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L6
  push   %rbx
  lea    -0x1(%rdi),%ebx
  xor    %esi,%esi
  mov    %rcx,%rdi
  add    $0x1,%rbx
  mov    %rbx,%rdx
  call   <memset@plt>
  lea    (%rax,%rbx,1),%rax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rsi,%rax
  ret
```

assistant: ```c
unsigned char *_setcharzero(int num, unsigned char *ptr) {
  while (num--) {
    *ptr++ = 0;
  }
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dw_ddoti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dw_ddoti(const int nz, const double *x, const int *ind_x, const double *y) {
  double ret = 0.0;
  int i;
  for (i = 0; i < nz; i++) {
    ret += x[i] * y[ind_x[i]];
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dw_ddoti>:
  endbr64
  test   %edi,%edi
  jle    L26
  mov    %edi,%edi
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L23:
  movslq (%rdx,%rax,4),%r8
  movsd  (%rcx,%r8,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L23
L7:
  movapd %xmm1,%xmm0
  ret
L26:
  pxor   %xmm1,%xmm1
  jmp    L7
```

assistant: ```c
double dw_ddoti(const int nz, const double *x, const int *ind_x, const double *y) {
  double ret = 0.0;
  int i;
  for (i = 0; i < nz; i++) {
    ret += x[i] * y[ind_x[i]];
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dw_ddoti>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L1:
  movslq (%rdx,%rax,4),%r8
  movsd  (%rcx,%r8,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dw_ddoti(const int nz, const double *x, const int *ind_x, const double *y) {
  double ret = 0.0;
  int i;
  for (i = 0; i < nz; i++) {
    ret += x[i] * y[ind_x[i]];
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dw_ddoti>:
  endbr64
  test   %edi,%edi
  jle    L11
  movslq %edi,%rdi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L5:
  movslq (%rdx,%rax,4),%r8
  movsd  (%rcx,%r8,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L5
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dw_ddoti(const int nz, const double *x, const int *ind_x, const double *y) {
  double ret = 0.0;
  int i;
  for (i = 0; i < nz; i++) {
    ret += x[i] * y[ind_x[i]];
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x8(%rbp)
  jmp    L10
L14:
  movl   $0x3,-0x4(%rbp)
  jmp    L29
L18:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0x0,-0x4(%rbp)
  jg     L18
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0xa,-0x8(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: %d %d %d


assistant: ```c
int main() {
  int outer, inner;
  outer = 5;
  while (outer <= 10) {
    inner = 3;
    while (inner >= 1) {
      printf("%d %d %d\n", inner, outer, inner + outer);
      inner--;
    }
    outer++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebp
  lea    D5(%rip),%r12
  jmp    L14
L32:
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  je     L9
L14:
  mov    $0x3,%ebx
L3:
  lea    (%rbx,%rbp,1),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  jmp    L32
L9:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: %d %d %d


assistant: ```c
int main() {
  int outer, inner;
  outer = 5;
  while (outer <= 10) {
    inner = 3;
    while (inner >= 1) {
      printf("%d %d %d\n", inner, outer, inner + outer);
      inner--;
    }
    outer++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    $0x5,%ebp
  push   %rbx
  nopl   0x0(%rax)
L13:
  mov    $0x3,%ebx
L3:
  lea    (%rbx,%rbp,1),%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  jne    L13
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: %d %d %d


assistant: ```c
int main() {
  int outer, inner;
  outer = 5;
  while (outer <= 10) {
    inner = 3;
    while (inner >= 1) {
      printf("%d %d %d\n", inner, outer, inner + outer);
      inner--;
    }
    outer++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    $0x5,%ebp
  push   %rbx
  nopl   0x0(%rax)
L9:
  mov    $0x3,%ebx
L6:
  lea    (%rbx,%rbp,1),%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  jne    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %d %d %d


assistant: ```c
int main() {
  int outer, inner;
  outer = 5;
  while (outer <= 10) {
    inner = 3;
    while (inner >= 1) {
      printf("%d %d %d\n", inner, outer, inner + outer);
      inner--;
    }
    outer++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %al,-0x8(%rbp)
  movsbl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <write_msg_id@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write_param@plt>
  nop
  leave
  ret
```

assistant: ```c
void write_msg(int socket, char msg_id, char *param, int size) {
  write_msg_id(socket, msg_id);
  write_param(socket, param, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_msg>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  movsbl %sil,%esi
  call   <write_msg_id@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write_param@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void write_msg(int socket, char msg_id, char *param, int size) {
  write_msg_id(socket, msg_id);
  write_param(socket, param, size);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_msg>:
  endbr64
  push   %r13
  movsbl %sil,%esi
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <write_msg_id@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <write_param@plt>
```

assistant: ```c
void write_msg(int socket, char msg_id, char *param, int size) {
  write_msg_id(socket, msg_id);
  write_param(socket, param, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_msg>:
  endbr64
  push   %r13
  movsbl %sil,%esi
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <write_msg_id@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <write_param@plt>
```

assistant: ```c
void write_msg(int socket, char msg_id, char *param, int size) {
  write_msg_id(socket, msg_id);
  write_param(socket, param, size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<deleteMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void deleteMat(int **xs, int r) {
  for (int i = 0; i < r; i++)
    free(xs[i]);
  free(xs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<deleteMat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L15:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L15
L10:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void deleteMat(int **xs, int r) {
  for (int i = 0; i < r; i++)
    free(xs[i]);
  free(xs);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<deleteMat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
L10:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void deleteMat(int **xs, int r) {
  for (int i = 0; i < r; i++)
    free(xs[i]);
  free(xs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deleteMat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L15
L1:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void deleteMat(int **xs, int r) {
  for (int i = 0; i < r; i++)
    free(xs[i]);
  free(xs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<linearstep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  -0x14(%rbp),%xmm0
  ucomiss -0x18(%rbp),%xmm0
  jp     L28
  movss  -0x14(%rbp),%xmm0
  ucomiss -0x18(%rbp),%xmm0
  je     L21
L28:
  movss  -0x18(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mov    -0x1c(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <clamp@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  subss  -0x14(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  jmp    L1
L21:
  movss  -0x1c(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <step@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
L1:
  movss  -0x8(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float linearstep(float edge0, float edge1, float x) {
  float result;
  if (edge0 != edge1) {
    float xclamped = clamp(x, edge0, edge1);
    result = (xclamped - edge0) / (edge1 - edge0);
  } else {
    result = step(edge0, x);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<linearstep>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm3
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  movaps %xmm2,%xmm0
  ucomiss %xmm1,%xmm3
  jp     L27
  jne    L27
  movaps %xmm2,%xmm1
  movss  0x8(%rsp),%xmm0
  call   <step@plt>
  jmp    L19
L27:
  movss  0xc(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  call   <clamp@plt>
  movss  0x8(%rsp),%xmm4
  subss  %xmm4,%xmm0
  movss  0xc(%rsp),%xmm1
  subss  %xmm4,%xmm1
  divss  %xmm1,%xmm0
L19:
  add    $0x18,%rsp
  ret
```

assistant: ```c
float linearstep(float edge0, float edge1, float x) {
  float result;
  if (edge0 != edge1) {
    float xclamped = clamp(x, edge0, edge1);
    result = (xclamped - edge0) / (edge1 - edge0);
  } else {
    result = step(edge0, x);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linearstep>:
  endbr64
  movaps %xmm0,%xmm3
  movaps %xmm1,%xmm4
  movaps %xmm2,%xmm0
  ucomiss %xmm1,%xmm3
  jp     L16
  jne    L16
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm0
  jmp    1060 <step@plt>
  nop
L16:
  sub    $0x18,%rsp
  movaps %xmm4,%xmm2
  movaps %xmm3,%xmm1
  movss  %xmm4,0xc(%rsp)
  movss  %xmm3,0x8(%rsp)
  call   <clamp@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm4
  add    $0x18,%rsp
  subss  %xmm3,%xmm0
  subss  %xmm3,%xmm4
  divss  %xmm4,%xmm0
  ret
```

assistant: ```c
float linearstep(float edge0, float edge1, float x) {
  float result;
  if (edge0 != edge1) {
    float xclamped = clamp(x, edge0, edge1);
    result = (xclamped - edge0) / (edge1 - edge0);
  } else {
    result = step(edge0, x);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<linearstep>:
  endbr64
  movaps %xmm0,%xmm3
  movaps %xmm1,%xmm4
  movaps %xmm2,%xmm0
  ucomiss %xmm1,%xmm3
  jp     L10
  jne    L10
  movaps %xmm2,%xmm1
  movaps %xmm3,%xmm0
  jmp    1060 <step@plt>
  nop
L10:
  sub    $0x18,%rsp
  movaps %xmm4,%xmm2
  movaps %xmm3,%xmm1
  movss  %xmm4,0xc(%rsp)
  movss  %xmm3,0x8(%rsp)
  call   <clamp@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm4
  add    $0x18,%rsp
  subss  %xmm3,%xmm0
  subss  %xmm3,%xmm4
  divss  %xmm4,%xmm0
  ret
```

assistant: ```c
float linearstep(float edge0, float edge1, float x) {
  float result;
  if (edge0 != edge1) {
    float xclamped = clamp(x, edge0, edge1);
    result = (xclamped - edge0) / (edge1 - edge0);
  } else {
    result = step(edge0, x);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trimwhitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L26
L1:
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  mov    -0x18(%rbp),%rax
  jmp    L60
L59:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L54:
  subq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L54
L12:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L60:
  leave
  ret
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace((unsigned char)*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace((unsigned char)*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trimwhitespace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L7
L53:
  add    $0x1,%rbx
L7:
  movzbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L53
  cmpb   $0x0,(%rbx)
  jne    L15
L27:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L3
L43:
  movzbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L3
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L43
L3:
  movb   $0x0,0x1(%rbp)
  jmp    L27
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace((unsigned char)*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace((unsigned char)*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```