ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<from_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L9
  cmp    $0x10,%esi
  sete   %al
  cmp    $0x60,%edi
  jle    L45
  test   %al,%al
  je     L45
  lea    -0x57(%rdi),%eax
  cmp    $0x67,%edi
  mov    $0xffffffff,%edx
  cmovge %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
L9:
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  lea    -0x41(%rdi),%edx
  cmp    $0x5,%edx
  ja     L25
  test   %al,%al
  je     L25
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int from_digit(int c, int r) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((r == 16) && (c >= 'a') && (c <= 'f'))
    return (c - 'a') + 10;
  if ((r == 16) && (c >= 'A') && (c <= 'F'))
    return (c - 'A') + 10;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<from_digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L16
  cmp    $0x10,%esi
  sete   %al
  cmp    $0x60,%edi
  jle    L32
  test   %al,%al
  je     L32
  lea    -0x57(%rdi),%eax
  cmp    $0x67,%edi
  mov    $0xffffffff,%edx
  cmovge %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
L16:
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  lea    -0x41(%rdi),%edx
  cmp    $0x5,%edx
  ja     L39
  test   %al,%al
  je     L39
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int from_digit(int c, int r) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((r == 16) && (c >= 'a') && (c <= 'f'))
    return (c - 'a') + 10;
  if ((r == 16) && (c >= 'A') && (c <= 'F'))
    return (c - 'A') + 10;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L19
L2:
  mov    -0x24(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  or     %ax,-0x2(%rbp)
  subl   $0x1,-0x24(%rbp)
L19:
  cmpl   $0x0,-0x24(%rbp)
  jne    L2
  movzwl -0x2(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(unsigned char *p, short *s, int c) {
  short or = 0;
  while (c) {
    or = or | s[c];
    c--;
  }
  *p = (unsigned char) or ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  test   %edx,%edx
  je     L4
  movslq %edx,%rdx
  mov    $0x0,%eax
L14:
  or     (%rsi,%rdx,2),%ax
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L14
L27:
  mov    %al,(%rdi)
  ret
L4:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
void f(unsigned char *p, short *s, int c) {
  short or = 0;
  while (c) {
    or = or | s[c];
    c--;
  }
  *p = (unsigned char) or ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  test   %edx,%edx
  je     L11
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L2:
  or     (%rsi,%rdx,2),%ax
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L2
  mov    %al,(%rdi)
  ret
  nop
L11:
  xor    %eax,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void f(unsigned char *p, short *s, int c) {
  short or = 0;
  while (c) {
    or = or | s[c];
    c--;
  }
  *p = (unsigned char) or ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  test   %edx,%edx
  je     L40
  lea    -0x1(%rdx),%ecx
  mov    %edx,%r10d
  cmp    $0x2,%ecx
  jbe    L4
  movslq %edx,%rax
  mov    %edx,%r8d
  pxor   %xmm1,%xmm1
  shr    $0x2,%r8d
  lea    -0x6(%rsi,%rax,2),%rcx
  lea    -0x1(%r8),%r9d
  lea    -0x8(%rcx),%rax
  shl    $0x3,%r9
  mov    %rax,%r8
  sub    %r9,%r8
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L50:
  sub    $0x8,%rax
L31:
  movq   (%rcx),%xmm0
  mov    %rax,%rcx
  pshuflw $0x1b,%xmm0,%xmm0
  por    %xmm0,%xmm1
  cmp    %r8,%rax
  jne    L50
  pextrw $0x1,%xmm1,%ecx
  pextrw $0x0,%xmm1,%eax
  or     %ecx,%eax
  pextrw $0x2,%xmm1,%ecx
  or     %ecx,%eax
  pextrw $0x3,%xmm1,%ecx
  or     %ecx,%eax
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  sub    %ecx,%edx
  cmp    %ecx,%r10d
  je     L55
  lea    -0x1(%rdx),%ecx
L27:
  movslq %edx,%r8
  lea    (%r8,%r8,1),%r9
  or     (%rsi,%r8,2),%ax
  test   %ecx,%ecx
  je     L55
  or     -0x2(%rsi,%r9,1),%ax
  cmp    $0x2,%edx
  je     L55
  or     -0x4(%rsi,%r9,1),%ax
L55:
  mov    %al,(%rdi)
  ret
  xchg   %ax,%ax
L40:
  xor    %eax,%eax
  mov    %al,(%rdi)
  ret
L4:
  xor    %eax,%eax
  jmp    L27
```

assistant: ```c
void f(unsigned char *p, short *s, int c) {
  short or = 0;
  while (c) {
    or = or | s[c];
    c--;
  }
  *p = (unsigned char) or ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D20
datatype: string

tool: D4: Starting network server...


tool: D27: python /kovan/network/networkHandler.py

tool: D20: Terminating server..


assistant: ```c
int main() {
  printf("Starting network server...\n");
  system("python /kovan/network/networkHandler.py");
  printf("Terminating server..\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <system@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string

tool: D16: Starting network server...


tool: D10: python /kovan/network/networkHandler.py

tool: D19: Terminating server..


assistant: ```c
int main() {
  printf("Starting network server...\n");
  system("python /kovan/network/networkHandler.py");
  printf("Terminating server..\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <system@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string

tool: D4: Starting network server...


tool: D28: python /kovan/network/networkHandler.py

tool: D23: Terminating server..


assistant: ```c
int main() {
  printf("Starting network server...\n");
  system("python /kovan/network/networkHandler.py");
  printf("Terminating server..\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <system@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D2: Starting network server...


tool: D17: python /kovan/network/networkHandler.py

tool: D13: Terminating server..


assistant: ```c
int main() {
  printf("Starting network server...\n");
  system("python /kovan/network/networkHandler.py");
  printf("Terminating server..\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_odd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L29
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L29:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_odd(int *arr, int size, int *arr_ind, int *ind_size) {
  *ind_size = 0;
  for (int i = 0; i < size; i++) {
    if (arr[i] % 2 == 1) {
      arr_ind[*ind_size] = i;
      (*ind_size)++;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_odd>:
  endbr64
  mov    %rdi,%r9
  movl   $0x0,(%rcx)
  test   %esi,%esi
  jle    L13
  mov    %esi,%esi
  mov    $0x0,%edi
  jmp    L20
L18:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L13
L20:
  mov    (%r9,%rdi,4),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %r8d,%eax
  and    $0x1,%eax
  sub    %r8d,%eax
  cmp    $0x1,%eax
  jne    L18
  movslq (%rcx),%rax
  mov    %edi,(%rdx,%rax,4)
  addl   $0x1,(%rcx)
  jmp    L18
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_odd(int *arr, int size, int *arr_ind, int *ind_size) {
  *ind_size = 0;
  for (int i = 0; i < size; i++) {
    if (arr[i] % 2 == 1) {
      arr_ind[*ind_size] = i;
      (*ind_size)++;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_odd>:
  endbr64
  movl   $0x0,(%rcx)
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L21
  movslq %esi,%rsi
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%r9,%rdi,4),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %r8d,%eax
  and    $0x1,%eax
  sub    %r8d,%eax
  cmp    $0x1,%eax
  jne    L0
  movslq (%rcx),%rax
  mov    %edi,(%rdx,%rax,4)
  addl   $0x1,(%rcx)
L0:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L26
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_odd(int *arr, int size, int *arr_ind, int *ind_size) {
  *ind_size = 0;
  for (int i = 0; i < size; i++) {
    if (arr[i] % 2 == 1) {
      arr_ind[*ind_size] = i;
      (*ind_size)++;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_odd>:
  endbr64
  movl   $0x0,(%rcx)
  mov    %rdi,%r9
  test   %esi,%esi
  jle    L3
  movslq %esi,%rsi
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%r9,%rdi,4),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %r8d,%eax
  and    $0x1,%eax
  sub    %r8d,%eax
  cmp    $0x1,%eax
  jne    L10
  movslq (%rcx),%rax
  mov    %edi,(%rdx,%rax,4)
  addl   $0x1,(%rcx)
L10:
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L9
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_odd(int *arr, int size, int *arr_ind, int *ind_size) {
  *ind_size = 0;
  for (int i = 0; i < size; i++) {
    if (arr[i] % 2 == 1) {
      arr_ind[*ind_size] = i;
      (*ind_size)++;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<Vizinho>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L34:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  sub    %esi,%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L10
  mov    $0x0,%eax
  jmp    L4
L10:
  addl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L34
  mov    $0x1,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int Vizinho(int Q[], int d, int P[]) {
  for (int i = 0; d > 0; i++) {
    P[i] = Q[i] - (d % 2);
    d /= 2;
    if (P[i] < 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Vizinho>:
  endbr64
  mov    %rdx,%r8
  test   %esi,%esi
  jle    L14
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%eax
  and    $0x1,%eax
  add    (%rdi),%edx
  sub    %eax,%edx
  mov    %edx,(%r8)
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  test   %edx,%edx
  js     L9
  mov    $0x4,%ecx
L5:
  test   %eax,%eax
  jle    L2
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%esi
  and    $0x1,%esi
  add    (%rdi,%rcx,1),%edx
  sub    %esi,%edx
  mov    %edx,(%r8,%rcx,1)
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %esi,%eax
  sar    %eax
  add    $0x4,%rcx
  test   %edx,%edx
  jns    L5
  mov    $0x0,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Vizinho(int Q[], int d, int P[]) {
  for (int i = 0; d > 0; i++) {
    P[i] = Q[i] - (d % 2);
    d /= 2;
    if (P[i] < 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Vizinho>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    (%rdi),%eax
  mov    %esi,%ecx
  sar    %esi
  and    $0x1,%ecx
  sub    %ecx,%eax
  mov    $0x4,%ecx
  mov    %eax,(%rdx)
  test   %eax,%eax
  jns    L44
  jmp    L35
L32:
  mov    (%rdi,%rcx,1),%eax
  mov    %esi,%r8d
  sar    %esi
  and    $0x1,%r8d
  sub    %r8d,%eax
  mov    %eax,(%rdx,%rcx,1)
  add    $0x4,%rcx
  test   %eax,%eax
  js     L35
L44:
  test   %esi,%esi
  jne    L32
L29:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Vizinho(int Q[], int d, int P[]) {
  for (int i = 0; d > 0; i++) {
    P[i] = Q[i] - (d % 2);
    d /= 2;
    if (P[i] < 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Vizinho>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    (%rdi),%eax
  mov    %esi,%ecx
  sar    %esi
  and    $0x1,%ecx
  sub    %ecx,%eax
  mov    $0x4,%ecx
  mov    %eax,(%rdx)
  test   %eax,%eax
  jns    L22
  jmp    L3
L45:
  mov    (%rdi,%rcx,1),%eax
  mov    %esi,%r8d
  sar    %esi
  and    $0x1,%r8d
  sub    %r8d,%eax
  mov    %eax,(%rdx,%rcx,1)
  add    $0x4,%rcx
  test   %eax,%eax
  js     L3
L22:
  test   %esi,%esi
  jne    L45
L24:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Vizinho(int Q[], int d, int P[]) {
  for (int i = 0; d > 0; i++) {
    P[i] = Q[i] - (d % 2);
    d /= 2;
    if (P[i] < 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_compass_jday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jle    L65
  cmpl   $0x1f,-0x24(%rbp)
  jg     L65
  cmpl   $0x0,-0x28(%rbp)
  jle    L65
  cmpl   $0xc,-0x28(%rbp)
  jg     L65
  cmpl   $0x0,-0x2c(%rbp)
  jle    L65
  cmpl   $0xfa0,-0x2c(%rbp)
  jle    L115
L65:
  mov    $0xffffffff,%eax
  jmp    L101
L115:
  cmpl   $0x2,-0x28(%rbp)
  jle    L98
  subl   $0x3,-0x28(%rbp)
  jmp    L19
L98:
  addl   $0x9,-0x28(%rbp)
  subl   $0x1,-0x2c(%rbp)
L19:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0xffffff9c,%eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x23ab1,%eax,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  imul   $0x5b5,%eax,%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %eax,%ecx
  mov    -0x28(%rbp),%eax
  imul   $0x99,%eax,%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  add    $0x1a431f,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x18(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <_compass_jdate@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  je     L52
  mov    $0xffffffff,%eax
  jmp    L101
L52:
  mov    -0xc(%rbp),%eax
L101:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int _compass_jday(int d, int m, int y) {
  int c, ya, j, dd;
  if (!(1 <= d && d <= 31 && 1 <= m && m <= 12 && 1 <= y && y <= 4000))
    return -1;
  if (m >= 3)
    m -= 3;
  else
    m += 9, y--;
  c = y / 100;
  ya = y - 100 * c;
  j = (146097 * c) / 4 + (1461 * ya) / 4 + (153 * m + 2) / 5 + d + 1721119;
  _compass_jdate(j, &dd, NULL, NULL);
  if (d != dd)
    return -1;
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_compass_jday>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdi),%eax
  cmp    $0x1e,%eax
  ja     L81
  mov    %edi,%ebx
  mov    %edx,%ecx
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L45
  lea    -0x1(%rdx),%eax
  cmp    $0xf9f,%eax
  ja     L5
  cmp    $0x2,%esi
  jle    L82
  sub    $0x3,%esi
L16:
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0xffffff9c,%eax,%edi
  add    %edi,%ecx
  imul   $0x5b5,%ecx,%ecx
  lea    0x3(%rcx),%edx
  test   %ecx,%ecx
  cmovns %ecx,%edx
  sar    $0x2,%edx
  imul   $0x23ab1,%eax,%eax
  lea    0x3(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0x2,%eax
  add    %edx,%eax
  imul   $0x99,%esi,%edx
  add    $0x2,%edx
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x21,%rcx
  sar    $0x1f,%edx
  sub    %edx,%ecx
  add    %ecx,%eax
  lea    0x1a431f(%rbx,%rax,1),%ebp
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %ebp,%edi
  call   <_compass_jdate@plt>
  cmp    %ebx,0x4(%rsp)
  mov    $0xffffffff,%eax
  cmovne %eax,%ebp
L80:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L82:
  add    $0x9,%esi
  sub    $0x1,%ecx
  jmp    L16
L81:
  mov    $0xffffffff,%ebp
  jmp    L80
L45:
  mov    $0xffffffff,%ebp
  jmp    L80
L5:
  mov    $0xffffffff,%ebp
  jmp    L80
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _compass_jday(int d, int m, int y) {
  int c, ya, j, dd;
  if (!(1 <= d && d <= 31 && 1 <= m && m <= 12 && 1 <= y && y <= 4000))
    return -1;
  if (m >= 3)
    m -= 3;
  else
    m += 9, y--;
  c = y / 100;
  ya = y - 100 * c;
  j = (146097 * c) / 4 + (1461 * ya) / 4 + (153 * m + 2) / 5 + d + 1721119;
  _compass_jdate(j, &dd, NULL, NULL);
  if (d != dd)
    return -1;
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_compass_jday>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdi),%eax
  cmp    $0x1e,%eax
  ja     L47
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L47
  lea    -0x1(%rdx),%eax
  cmp    $0xf9f,%eax
  ja     L47
  mov    %edi,%ebx
  cmp    $0x2,%esi
  jg     L15
  add    $0x9,%esi
  mov    %eax,%edx
L19:
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0xffffff9c,%eax,%ecx
  add    %edx,%ecx
  imul   $0x5b5,%ecx,%ecx
  test   %ecx,%ecx
  lea    0x3(%rcx),%edx
  cmovns %ecx,%edx
  imul   $0x23ab1,%eax,%eax
  mov    $0xcccccccd,%ecx
  imul   $0x99,%esi,%esi
  sar    $0x2,%edx
  sar    $0x2,%eax
  add    %edx,%eax
  lea    0x2(%rsi),%edx
  lea    0x4(%rsp),%rsi
  imul   %rcx,%rdx
  xor    %ecx,%ecx
  shr    $0x22,%rdx
  add    %edx,%eax
  xor    %edx,%edx
  lea    0x1a431f(%rbx,%rax,1),%r12d
  mov    %r12d,%edi
  call   <_compass_jdate@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L47
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  sub    $0x3,%esi
  jmp    L19
L47:
  mov    $0xffffffff,%r12d
  jmp    L77
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _compass_jday(int d, int m, int y) {
  int c, ya, j, dd;
  if (!(1 <= d && d <= 31 && 1 <= m && m <= 12 && 1 <= y && y <= 4000))
    return -1;
  if (m >= 3)
    m -= 3;
  else
    m += 9, y--;
  c = y / 100;
  ya = y - 100 * c;
  j = (146097 * c) / 4 + (1461 * ya) / 4 + (153 * m + 2) / 5 + d + 1721119;
  _compass_jdate(j, &dd, NULL, NULL);
  if (d != dd)
    return -1;
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_compass_jday>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x1(%rdi),%eax
  cmp    $0x1e,%eax
  ja     L10
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L10
  lea    -0x1(%rdx),%eax
  cmp    $0xf9f,%eax
  ja     L10
  mov    %edi,%ebx
  cmp    $0x2,%esi
  jg     L0
  add    $0x9,%esi
  mov    %eax,%edx
L41:
  mov    %edx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x25,%rax
  imul   $0xffffff9c,%eax,%ecx
  add    %edx,%ecx
  imul   $0x5b5,%ecx,%ecx
  test   %ecx,%ecx
  lea    0x3(%rcx),%edx
  cmovns %ecx,%edx
  imul   $0x23ab1,%eax,%eax
  mov    $0xcccccccd,%ecx
  imul   $0x99,%esi,%esi
  sar    $0x2,%edx
  sar    $0x2,%eax
  add    %edx,%eax
  lea    0x2(%rsi),%edx
  lea    0x4(%rsp),%rsi
  imul   %rcx,%rdx
  xor    %ecx,%ecx
  shr    $0x22,%rdx
  add    %edx,%eax
  xor    %edx,%edx
  lea    0x1a431f(%rbx,%rax,1),%r12d
  mov    %r12d,%edi
  call   <_compass_jdate@plt>
  cmp    %ebx,0x4(%rsp)
  jne    L10
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  sub    $0x3,%esi
  jmp    L41
L10:
  mov    $0xffffffff,%r12d
  jmp    L1
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _compass_jday(int d, int m, int y) {
  int c, ya, j, dd;
  if (!(1 <= d && d <= 31 && 1 <= m && m <= 12 && 1 <= y && y <= 4000))
    return -1;
  if (m >= 3)
    m -= 3;
  else
    m += 9, y--;
  c = y / 100;
  ya = y - 100 * c;
  j = (146097 * c) / 4 + (1461 * ya) / 4 + (153 * m + 2) / 5 + d + 1721119;
  _compass_jdate(j, &dd, NULL, NULL);
  if (d != dd)
    return -1;
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L13:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x9,-0x8(%rbp)
  jle    L13
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum += i;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum += i;
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2d,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    sum += i;
  }
  return sum;
}
```