ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_xor(uint32_t *x, uint32_t *y) {
  *x = *x ^ *y;
  *y = *x ^ *y;
  *x = *x ^ *y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap_xor>:
  endbr64
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
  ret
```

assistant: ```c
void swap_xor(uint32_t *x, uint32_t *y) {
  *x = *x ^ *y;
  *y = *x ^ *y;
  *x = *x ^ *y;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<swap_xor>:
  endbr64
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
  ret
```

assistant: ```c
void swap_xor(uint32_t *x, uint32_t *y) {
  *x = *x ^ *y;
  *y = *x ^ *y;
  *x = *x ^ *y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_xor>:
  endbr64
  mov    (%rdi),%eax
  xor    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    (%rsi),%eax
  mov    %eax,(%rsi)
  xor    %eax,(%rdi)
  ret
```

assistant: ```c
void swap_xor(uint32_t *x, uint32_t *y) {
  *x = *x ^ *y;
  *y = *x ^ *y;
  *x = *x ^ *y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_xml_attribute_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L25
  cmpq   $0x0,-0x30(%rbp)
  je     L25
  cmpq   $0x0,-0x38(%rbp)
  jne    L36
L25:
  mov    $0x0,%eax
  jmp    L47
L36:
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x13(%rbp),%rax
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <parse_xml_attribute_text@plt>
  test   %eax,%eax
  jne    L26
  mov    $0x0,%eax
  jmp    L47
L26:
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    -0x38(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x1,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int parse_xml_attribute_number(char *target, char *input, long *output) {
  char buffer[11];
  if (!target || !input || !output)
    return 0;
  if (!parse_xml_attribute_text(buffer, sizeof(buffer), target, input)) {
    return 0;
  }
  *output = atol(buffer);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_xml_attribute_number>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L39
  test   %rdi,%rdi
  je     L39
  lea    0xd(%rsp),%rax
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <parse_xml_attribute_text@plt>
  test   %eax,%eax
  je     L28
  lea    0xd(%rsp),%rdi
  call   <atol@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L28
L39:
  mov    $0x0,%eax
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x20,%rsp
  pop    %rbx
  ret
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_xml_attribute_number(char *target, char *input, long *output) {
  char buffer[11];
  if (!target || !input || !output)
    return 0;
  if (!parse_xml_attribute_text(buffer, sizeof(buffer), target, input)) {
    return 0;
  }
  *output = atol(buffer);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_xml_attribute_number>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L19
  test   %rdi,%rdi
  je     L19
  lea    0xd(%rsp),%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <parse_xml_attribute_text@plt>
  test   %eax,%eax
  je     L19
  mov    %rbp,%rdi
  call   <atol@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L36
L19:
  xor    %eax,%eax
L36:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_xml_attribute_number(char *target, char *input, long *output) {
  char buffer[11];
  if (!target || !input || !output)
    return 0;
  if (!parse_xml_attribute_text(buffer, sizeof(buffer), target, input)) {
    return 0;
  }
  *output = atol(buffer);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_xml_attribute_number>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L8
  test   %rdi,%rdi
  je     L8
  lea    0xd(%rsp),%rbp
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <parse_xml_attribute_text@plt>
  test   %eax,%eax
  je     L8
  mov    %rbp,%rdi
  call   <atol@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L47
L8:
  xor    %eax,%eax
L47:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_xml_attribute_number(char *target, char *input, long *output) {
  char buffer[11];
  if (!target || !input || !output)
    return 0;
  if (!parse_xml_attribute_text(buffer, sizeof(buffer), target, input)) {
    return 0;
  }
  *output = atol(buffer);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_gogo_foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_gogo_foo(void *args) {
  args++;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_gogo_foo>:
  endbr64
  ret
```

assistant: ```c
void test_gogo_foo(void *args) {
  args++;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_gogo_foo>:
  endbr64
  ret
```

assistant: ```c
void test_gogo_foo(void *args) {
  args++;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<euler_problem_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x64,-0x18(%rbp)
  jmp    L47
L43:
  movl   $0x64,-0x14(%rbp)
  jmp    L29
L5:
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_palindrome@plt>
  test   %rax,%rax
  je     L35
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L35
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L35:
  addl   $0x1,-0x14(%rbp)
L29:
  cmpl   $0x3e7,-0x14(%rbp)
  jle    L5
  addl   $0x1,-0x18(%rbp)
L47:
  cmpl   $0x3e7,-0x18(%rbp)
  jle    L43
  mov    -0x10(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: %d

assistant: ```c
int euler_problem_4() {
  int i, j, k, max = 0;
  char *str = (char *)malloc(sizeof(char) * 20);
  for (i = 100; i < 1000; ++i) {
    for (j = 100; j < 1000; ++j) {
      k = i * j;
      sprintf(str, "%d", k);
      if (is_palindrome(str) && k > max) {
        max = k;
      }
    }
  }
  return max;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<euler_problem_4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movl   $0x2710,0xc(%rsp)
  mov    $0x0,%ebp
  movl   $0x64,0x8(%rsp)
  lea    D7(%rip),%r15
L9:
  mov    0x8(%rsp),%r14d
  mov    0xc(%rsp),%ebx
  mov    $0x384,%r12d
L17:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <is_palindrome@plt>
  mov    %rax,%rdx
  cmp    %ebx,%ebp
  mov    %ebx,%eax
  cmovge %ebp,%eax
  test   %rdx,%rdx
  cmovne %eax,%ebp
  add    %r14d,%ebx
  sub    $0x1,%r12d
  jne    L17
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  addl   $0x64,0xc(%rsp)
  cmp    $0x3e8,%eax
  jne    L9
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d

assistant: ```c
int euler_problem_4() {
  int i, j, k, max = 0;
  char *str = (char *)malloc(sizeof(char) * 20);
  for (i = 100; i < 1000; ++i) {
    for (j = 100; j < 1000; ++j) {
      k = i * j;
      sprintf(str, "%d", k);
      if (is_palindrome(str) && k > max) {
        max = k;
      }
    }
  }
  return max;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<euler_problem_4>:
  endbr64
  push   %r15
  mov    $0x14,%edi
  xor    %r15d,%r15d
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  mov    $0x64,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  movl   $0x2710,0xc(%rsp)
  mov    %rax,%r12
L7:
  mov    0xc(%rsp),%ebx
  mov    $0x384,%ebp
L0:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <is_palindrome@plt>
  cmp    %ebx,%r15d
  mov    %rax,%r9
  mov    %ebx,%eax
  cmovge %r15d,%eax
  test   %r9,%r9
  cmovne %eax,%r15d
  add    %r13d,%ebx
  sub    $0x1,%ebp
  jne    L0
  add    $0x1,%r13d
  addl   $0x64,0xc(%rsp)
  cmp    $0x3e8,%r13d
  jne    L7
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: %d

assistant: ```c
int euler_problem_4() {
  int i, j, k, max = 0;
  char *str = (char *)malloc(sizeof(char) * 20);
  for (i = 100; i < 1000; ++i) {
    for (j = 100; j < 1000; ++j) {
      k = i * j;
      sprintf(str, "%d", k);
      if (is_palindrome(str) && k > max) {
        max = k;
      }
    }
  }
  return max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<euler_problem_4>:
  endbr64
  push   %r15
  mov    $0x14,%edi
  xor    %r15d,%r15d
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    $0x64,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <malloc@plt>
  movl   $0x2710,0xc(%rsp)
  mov    %rax,%r12
L13:
  mov    0xc(%rsp),%ebx
  mov    $0x384,%ebp
L6:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <is_palindrome@plt>
  cmp    %ebx,%r15d
  mov    %rax,%r9
  mov    %ebx,%eax
  cmovge %r15d,%eax
  test   %r9,%r9
  cmovne %eax,%r15d
  add    %r13d,%ebx
  sub    $0x1,%ebp
  jne    L6
  add    $0x1,%r13d
  addl   $0x64,0xc(%rsp)
  cmp    $0x3e8,%r13d
  jne    L13
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
int euler_problem_4() {
  int i, j, k, max = 0;
  char *str = (char *)malloc(sizeof(char) * 20);
  for (i = 100; i < 1000; ++i) {
    for (j = 100; j < 1000; ++j) {
      k = i * j;
      sprintf(str, "%d", k);
      if (is_palindrome(str) && k > max) {
        max = k;
      }
    }
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<similarity_table_distances>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L14:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L2:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x28(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L2
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void similarity_table_distances(int n, double *distance_matrix, double *distances_table) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      (*distances_table) = distance_matrix[i * n + j];
      distances_table++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<similarity_table_distances>:
  endbr64
  test   %edi,%edi
  jle    L24
  mov    %edi,%r10d
  mov    $0x8,%ecx
  mov    $0x0,%r9d
  jmp    L11
L39:
  movslq %r10d,%rax
  lea    (%rsi,%rax,8),%r8
  mov    $0x0,%eax
L6:
  movsd  (%r8,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L6
  add    %rcx,%rdx
L21:
  add    $0x8,%rcx
  add    %edi,%r10d
L11:
  add    $0x1,%r9d
  cmp    %r9d,%edi
  je     L24
  test   %r9d,%r9d
  jg     L39
  jmp    L21
L24:
  ret
```

assistant: ```c
void similarity_table_distances(int n, double *distance_matrix, double *distances_table) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      (*distances_table) = distance_matrix[i * n + j];
      distances_table++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<similarity_table_distances>:
  endbr64
  test   %edi,%edi
  jle    L0
  xor    %r9d,%r9d
  mov    %edi,%r10d
  mov    $0x8,%ecx
  add    $0x1,%r9d
  cmp    %r9d,%edi
  je     L0
  nopl   0x0(%rax)
L5:
  movslq %r10d,%rax
  lea    (%rsi,%rax,8),%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  movsd  (%r8,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L17
  add    $0x1,%r9d
  add    %rcx,%rdx
  add    %edi,%r10d
  add    $0x8,%rcx
  cmp    %r9d,%edi
  jne    L5
L0:
  ret
```

assistant: ```c
void similarity_table_distances(int n, double *distance_matrix, double *distances_table) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      (*distances_table) = distance_matrix[i * n + j];
      distances_table++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<similarity_table_distances>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rdi
  cmp    $0x1,%r9d
  jle    L74
  mov    %r9d,%esi
  mov    $0x8,%r10d
  mov    $0x1,%r8d
  nopl   0x0(%rax,%rax,1)
L73:
  movslq %esi,%rax
  lea    -0x1(%r8),%ecx
  lea    0x8(,%rax,8),%rax
  cmp    $0x2,%ecx
  jbe    L39
  lea    (%rdi,%rax,1),%rcx
  cmp    %rcx,%rdx
  je     L39
  mov    %r8d,%ecx
  lea    -0x8(%rdi,%rax,1),%r11
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopl   (%rax)
L44:
  movupd (%r11,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L44
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,8),%rcx
  cmp    %r8d,%eax
  je     L43
  add    %esi,%eax
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx)
L43:
  add    $0x1,%r8d
  add    %r10,%rdx
  add    %r9d,%esi
  add    $0x8,%r10
  cmp    %r8d,%r9d
  jne    L73
L74:
  ret
  nopl   (%rax)
L39:
  lea    -0x8(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%r10
  jne    L12
  jmp    L43
```

assistant: ```c
void similarity_table_distances(int n, double *distance_matrix, double *distances_table) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      (*distances_table) = distance_matrix[i * n + j];
      distances_table++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<candidatoCabeEnFila>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L20:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L39
L11:
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x8,-0x4(%rbp)
  jle    L20
  mov    $0x1,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int candidatoCabeEnFila(int s[9][9], int f, int candidato) {
  int c;
  for (c = 0; c < 9; c++) {
    if (s[f][c] == candidato) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<candidatoCabeEnFila>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,8),%rax
  lea    (%rdi,%rax,4),%rax
  lea    0x24(%rax),%rcx
L11:
  cmp    %edx,(%rax)
  je     L5
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L11
  mov    $0x1,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int candidatoCabeEnFila(int s[9][9], int f, int candidato) {
  int c;
  for (c = 0; c < 9; c++) {
    if (s[f][c] == candidato) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<candidatoCabeEnFila>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,8),%rax
  lea    (%rdi,%rax,4),%rax
  lea    0x24(%rax),%rcx
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    %edx,(%rax)
  je     L17
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L2
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int candidatoCabeEnFila(int s[9][9], int f, int candidato) {
  int c;
  for (c = 0; c < 9; c++) {
    if (s[f][c] == candidato) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<candidatoCabeEnFila>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,8),%rax
  lea    (%rdi,%rax,4),%rax
  cmp    (%rax),%edx
  je     L3
  cmp    0x4(%rax),%edx
  je     L3
  cmp    0x8(%rax),%edx
  je     L3
  cmp    0xc(%rax),%edx
  je     L3
  cmp    0x10(%rax),%edx
  je     L3
  cmp    0x14(%rax),%edx
  je     L3
  cmp    0x18(%rax),%edx
  je     L3
  cmp    0x1c(%rax),%edx
  je     L3
  cmp    %edx,0x20(%rax)
  setne  %al
  movzbl %al,%eax
  ret
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int candidatoCabeEnFila(int s[9][9], int f, int candidato) {
  int c;
  for (c = 0; c < 9; c++) {
    if (s[f][c] == candidato) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LCM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L26
L14:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x18(%rbp)
  jmp    L26
L11:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0xc(%rbp)
  jl     L14
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int LCM(int x, int y) {
  int hcf = 1, lcm = x * y, max, i;
  max = (x > y) ? x : y;
  for (i = 2; i < max / 2;) {
    if (x % i == 0 && y % i == 0) {
      hcf = hcf * i;
      x = x / i;
      y = y / i;
    } else
      i++;
  }
  lcm = lcm / hcf;
  return (lcm);
}
```
user: Translate the below assembly code into C programming language:

```asm
<LCM>:
  endbr64
  mov    %edi,%r10d
  imul   %esi,%r10d
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x5,%eax
  jle    L45
  mov    $0x2,%ecx
  mov    $0x1,%r9d
  jmp    L1
L2:
  add    $0x1,%ecx
L46:
  cmp    %r8d,%ecx
  jge    L26
L1:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L2
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L2
  imul   %ecx,%r9d
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  jmp    L46
L45:
  mov    $0x1,%r9d
L26:
  mov    %r10d,%eax
  cltd
  idiv   %r9d
  ret
```

assistant: ```c
int LCM(int x, int y) {
  int hcf = 1, lcm = x * y, max, i;
  max = (x > y) ? x : y;
  for (i = 2; i < max / 2;) {
    if (x % i == 0 && y % i == 0) {
      hcf = hcf * i;
      x = x / i;
      y = y / i;
    } else
      i++;
  }
  lcm = lcm / hcf;
  return (lcm);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LCM>:
  endbr64
  mov    %edi,%r11d
  mov    %esi,%eax
  imul   %esi,%r11d
  cmp    %esi,%edi
  cmovge %edi,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x5,%eax
  jle    L17
  mov    $0x2,%ecx
  mov    $0x1,%r10d
  jmp    L46
  nopl   0x0(%rax)
L50:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L49
  imul   %ecx,%r10d
  mov    %r9d,%edi
  mov    %eax,%esi
  cmp    %r8d,%ecx
  jge    L33
L46:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r9d
  test   %edx,%edx
  je     L50
L49:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jl     L46
L33:
  mov    %r11d,%eax
  cltd
  idiv   %r10d
  mov    %eax,%r11d
L17:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int LCM(int x, int y) {
  int hcf = 1, lcm = x * y, max, i;
  max = (x > y) ? x : y;
  for (i = 2; i < max / 2;) {
    if (x % i == 0 && y % i == 0) {
      hcf = hcf * i;
      x = x / i;
      y = y / i;
    } else
      i++;
  }
  lcm = lcm / hcf;
  return (lcm);
}
```
user: What is the c source code of the assembly code below:

```asm
<LCM>:
  endbr64
  mov    %edi,%r11d
  mov    %esi,%eax
  imul   %esi,%r11d
  cmp    %esi,%edi
  cmovge %edi,%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  cmp    $0x5,%eax
  jle    L41
  mov    $0x2,%ecx
  mov    $0x1,%r10d
  jmp    L20
  nopl   0x0(%rax)
L13:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L57
  imul   %ecx,%r10d
  mov    %r9d,%edi
  mov    %eax,%esi
  cmp    %r8d,%ecx
  jge    L10
L20:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r9d
  test   %edx,%edx
  je     L13
L57:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jl     L20
L10:
  mov    %r11d,%eax
  cltd
  idiv   %r10d
  mov    %eax,%r11d
L41:
  mov    %r11d,%eax
  ret
```

assistant: ```c
int LCM(int x, int y) {
  int hcf = 1, lcm = x * y, max, i;
  max = (x > y) ? x : y;
  for (i = 2; i < max / 2;) {
    if (x % i == 0 && y % i == 0) {
      hcf = hcf * i;
      x = x / i;
      y = y / i;
    } else
      i++;
  }
  lcm = lcm / hcf;
  return (lcm);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<freer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int freer(const void *key, const void *datum) {
  xfree((void *)datum);
  xfree((void *)key);
  return 0;
}
```