ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DoShortNumTest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdx
  call   <sscanf_s@plt>
  cmp    $0x1,%eax
  je     L22
  mov    %eax,%esi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <Fail@plt>
L22:
  movswl 0x6(%rsp),%r8d
  cmp    %bx,%r8w
  je     L14
  movswl %bx,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <Fail@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D12: ERROR: Expected sscanf_s to return 1, got %d.
Using "%s" in "%s".


tool: D18: ERROR: scanned number incorrectly from "%s" using "%s".
Expected %hd, got %hd.


assistant: ```c
void DoShortNumTest(char *inputstr, const char *formatstr, short checknum) {
  short num;
  int ret;
  ret = sscanf_s(inputstr, formatstr, &num);
  if (ret != 1) {
    Fail("ERROR: Expected sscanf_s to return 1, got %d.\n"
         "Using \"%s\" in \"%s\".\n",
         ret, inputstr, formatstr);
  }
  if (checknum != num) {
    Fail("ERROR: scanned number incorrectly from \"%s\" using \"%s\".\n"
         "Expected %hd, got %hd.\n",
         inputstr, formatstr, checknum, num);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<DoShortNumTest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdx
  call   <sscanf_s@plt>
  cmp    $0x1,%eax
  je     L3
  mov    %eax,%esi
  mov    %r12,%rcx
  mov    %rbp,%rdx
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <Fail@plt>
L3:
  movswl 0x6(%rsp),%r8d
  cmp    %bx,%r8w
  je     L0
  movswl %bx,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <Fail@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D15: ERROR: Expected sscanf_s to return 1, got %d.
Using "%s" in "%s".


tool: D11: ERROR: scanned number incorrectly from "%s" using "%s".
Expected %hd, got %hd.


assistant: ```c
void DoShortNumTest(char *inputstr, const char *formatstr, short checknum) {
  short num;
  int ret;
  ret = sscanf_s(inputstr, formatstr, &num);
  if (ret != 1) {
    Fail("ERROR: Expected sscanf_s to return 1, got %d.\n"
         "Using \"%s\" in \"%s\".\n",
         ret, inputstr, formatstr);
  }
  if (checknum != num) {
    Fail("ERROR: scanned number incorrectly from \"%s\" using \"%s\".\n"
         "Expected %hd, got %hd.\n",
         inputstr, formatstr, checknum, num);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<whoWin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x61,-0xa(%rbp)
  jmp    L45
L30:
  movb   $0x61,-0x9(%rbp)
  jmp    L3
L60:
  movsbq -0xa(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    -0x9da(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movsbl -0x9(%rbp),%eax
  sub    $0x61,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x57,%al
  jne    L18
  addl   $0x1,-0x8(%rbp)
  jmp    L44
L18:
  movsbq -0xa(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    -0x9da(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  movsbl -0x9(%rbp),%eax
  sub    $0x61,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x42,%al
  jne    L44
  addl   $0x1,-0x4(%rbp)
L44:
  movzbl -0x9(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x9(%rbp)
L3:
  movsbl -0x9(%rbp),%eax
  mov    -0x24(%rbp),%edx
  add    $0x61,%edx
  cmp    %edx,%eax
  jne    L60
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L45:
  movsbl -0xa(%rbp),%eax
  mov    -0x24(%rbp),%edx
  add    $0x61,%edx
  cmp    %edx,%eax
  jne    L30
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void whoWin(int *numW, int *numB, int dimension, char board[][26]) {
  int countW = 0;
  int countB = 0;
  for (char row = 'a'; row != 'a' + dimension; row++) {
    for (char col = 'a'; col != 'a' + dimension; col++) {
      if (board[row - 'a'][col - 'a'] == 'W') {
        countW = countW + 1;
      } else if (board[row - 'a'][col - 'a'] == 'B') {
        countB = countB + 1;
      }
    }
  }
  *numW = countW;
  *numB = countB;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<whoWin>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rcx,%rbx
  lea    0x61(%rdx),%esi
  mov    $0x61,%r9d
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x61,%ebp
  test   %edx,%edx
  jne    L37
L6:
  mov    %r8d,(%r10)
  mov    %ecx,(%r11)
  pop    %rbx
  pop    %rbp
  ret
L23:
  cmp    $0x42,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
L11:
  add    $0x1,%edx
  movsbl %dl,%eax
  cmp    %esi,%eax
  je     L47
L29:
  sub    $0x61,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x57,%al
  jne    L23
  add    $0x1,%r8d
  jmp    L11
L47:
  add    $0x1,%r9d
  movsbl %r9b,%eax
  cmp    %esi,%eax
  je     L6
L37:
  movsbq %r9b,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  lea    -0x9da(%rbx,%rax,2),%rdi
  mov    $0x61,%edx
  mov    %ebp,%eax
  jmp    L29
```

assistant: ```c
void whoWin(int *numW, int *numB, int dimension, char board[][26]) {
  int countW = 0;
  int countB = 0;
  for (char row = 'a'; row != 'a' + dimension; row++) {
    for (char col = 'a'; col != 'a' + dimension; col++) {
      if (board[row - 'a'][col - 'a'] == 'W') {
        countW = countW + 1;
      } else if (board[row - 'a'][col - 'a'] == 'B') {
        countB = countB + 1;
      }
    }
  }
  *numW = countW;
  *numB = countB;
}
```
user: What is the c source code of the assembly code below?

```asm
<whoWin>:
  endbr64
  push   %rbx
  mov    %rsi,%r11
  mov    %rcx,%rbx
  mov    %rdi,%r10
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  lea    0x61(%rdx),%esi
  mov    $0x61,%r9d
  test   %edx,%edx
  je     L33
L51:
  movsbq %r9b,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  mov    $0x61,%edx
  lea    -0x9da(%rbx,%rax,2),%rdi
  mov    $0x61,%eax
  jmp    L32
L40:
  cmp    $0x42,%al
  sete   %al
  add    $0x1,%edx
  movzbl %al,%eax
  add    %eax,%ecx
  movsbl %dl,%eax
  cmp    %esi,%eax
  je     L30
L32:
  sub    $0x61,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  cmp    $0x57,%al
  jne    L40
  add    $0x1,%edx
  add    $0x1,%r8d
  movsbl %dl,%eax
  cmp    %esi,%eax
  jne    L32
L30:
  add    $0x1,%r9d
  movsbl %r9b,%eax
  cmp    %esi,%eax
  jne    L51
L33:
  mov    %r8d,(%r10)
  pop    %rbx
  mov    %ecx,(%r11)
  ret
```

assistant: ```c
void whoWin(int *numW, int *numB, int dimension, char board[][26]) {
  int countW = 0;
  int countB = 0;
  for (char row = 'a'; row != 'a' + dimension; row++) {
    for (char col = 'a'; col != 'a' + dimension; col++) {
      if (board[row - 'a'][col - 'a'] == 'W') {
        countW = countW + 1;
      } else if (board[row - 'a'][col - 'a'] == 'B') {
        countB = countB + 1;
      }
    }
  }
  *numW = countW;
  *numB = countB;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<whoWin>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r11
  test   %edx,%edx
  je     L36
  push   %rbx
  lea    0x61(%rdx),%edi
  mov    %rcx,%rbx
  mov    $0x61,%r9d
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L18:
  movsbq %r9b,%rax
  lea    (%rax,%rax,2),%rdx
  lea    (%rax,%rdx,4),%rax
  mov    $0x61,%edx
  lea    -0x9da(%rbx,%rax,2),%rsi
  mov    $0x61,%eax
  jmp    L23
L25:
  cmp    $0x42,%al
  sete   %al
  add    $0x1,%edx
  movzbl %al,%eax
  add    %eax,%ecx
  movsbl %dl,%eax
  cmp    %eax,%edi
  je     L4
L23:
  sub    $0x61,%eax
  cltq
  movzbl (%rsi,%rax,1),%eax
  cmp    $0x57,%al
  jne    L25
  add    $0x1,%edx
  add    $0x1,%r8d
  movsbl %dl,%eax
  cmp    %eax,%edi
  jne    L23
L4:
  add    $0x1,%r9d
  cmp    %dl,%r9b
  jne    L18
  mov    %r8d,(%r10)
  pop    %rbx
  mov    %ecx,(%r11)
  ret
L36:
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  mov    %r8d,(%rdi)
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void whoWin(int *numW, int *numB, int dimension, char board[][26]) {
  int countW = 0;
  int countB = 0;
  for (char row = 'a'; row != 'a' + dimension; row++) {
    for (char col = 'a'; col != 'a' + dimension; col++) {
      if (board[row - 'a'][col - 'a'] == 'W') {
        countW = countW + 1;
      } else if (board[row - 'a'][col - 'a'] == 'B') {
        countB = countB + 1;
      }
    }
  }
  *numW = countW;
  *numB = countB;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_is_word_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_wide_char@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L64
L31:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <iswalnum@plt>
  test   %rax,%rax
  je     L60
  mov    $0x1,%eax
  jmp    L64
L60:
  cmpl   $0x7c,-0x4(%rbp)
  je     L25
  cmpl   $0x7c,-0x4(%rbp)
  jg     L17
  cmpl   $0x2d,-0x4(%rbp)
  je     L25
  cmpl   $0x5f,-0x4(%rbp)
  jne    L17
L25:
  mov    $0x1,%eax
  jmp    L64
L17:
  mov    $0x0,%eax
L64:
  leave
  ret
```

assistant: ```c
int string_is_word_char(const char *string) {
  wint_t c = utf8_wide_char(string);
  if (c == WEOF)
    return 0;
  if (iswalnum(c))
    return 1;
  switch (c) {
  case '-':
  case '_':
  case '|':
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_is_word_char>:
  endbr64
  push   %rbx
  call   <utf8_wide_char@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  mov    D6(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L34
  mov    %ebx,%edi
  call   <iswalnum@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L34
  cmp    $0x5f,%ebx
  je     L46
  cmp    $0x7c,%ebx
  je     L11
  cmp    $0x2d,%ebx
  sete   %al
  movzbl %al,%eax
L34:
  pop    %rbx
  ret
L46:
  mov    $0x1,%eax
  jmp    L34
L11:
  mov    $0x1,%eax
  jmp    L34
```

assistant: ```c
int string_is_word_char(const char *string) {
  wint_t c = utf8_wide_char(string);
  if (c == WEOF)
    return 0;
  if (iswalnum(c))
    return 1;
  switch (c) {
  case '-':
  case '_':
  case '|':
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_is_word_char>:
  endbr64
  push   %rbx
  call   <utf8_wide_char@plt>
  mov    D7(%rip),%rdx
  mov    %eax,%ebx
  xor    %eax,%eax
  cmp    %ebx,(%rdx)
  je     L22
  mov    %ebx,%edi
  call   <iswalnum@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L22
  cmp    $0x5f,%ebx
  je     L22
  cmp    $0x7c,%ebx
  je     L22
  xor    %eax,%eax
  cmp    $0x2d,%ebx
  sete   %al
L22:
  pop    %rbx
  ret
```

assistant: ```c
int string_is_word_char(const char *string) {
  wint_t c = utf8_wide_char(string);
  if (c == WEOF)
    return 0;
  if (iswalnum(c))
    return 1;
  switch (c) {
  case '-':
  case '_':
  case '|':
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<string_is_word_char>:
  endbr64
  push   %rbx
  call   <utf8_wide_char@plt>
  mov    D2(%rip),%rdx
  mov    %eax,%ebx
  xor    %eax,%eax
  cmp    %ebx,(%rdx)
  je     L23
  mov    %ebx,%edi
  call   <iswalnum@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L23
  cmp    $0x5f,%ebx
  je     L23
  cmp    $0x7c,%ebx
  je     L23
  xor    %eax,%eax
  cmp    $0x2d,%ebx
  sete   %al
L23:
  pop    %rbx
  ret
```

assistant: ```c
int string_is_word_char(const char *string) {
  wint_t c = utf8_wide_char(string);
  if (c == WEOF)
    return 0;
  if (iswalnum(c))
    return 1;
  switch (c) {
  case '-':
  case '_':
  case '|':
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<floyd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L44
L71:
  movl   $0x1,-0xc(%rbp)
  jmp    L77
L50:
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x5f5e100,%eax
  je     L57
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L41:
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%esi
  mov    -0x4(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  add    %esi,%eax
  cmp    %eax,%edx
  jle    L69
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%esi
  mov    -0x4(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0xfa8,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  add    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
L69:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L41
L57:
  addl   $0x1,-0xc(%rbp)
L77:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L50
  addl   $0x1,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L71
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int n) {
  int i, j, k, u;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      if (dist[i][k] != 100000000) {
        for (j = 1; j <= n; j++) {
          if (dist[i][j] > dist[i][k] + dist[k][j]) {
            dist[i][j] = dist[i][k] + dist[k][j];
          }
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<floyd>:
  endbr64
  test   %esi,%esi
  jle    L46
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%r9d
  imul   $0xfa8,%r9,%rax
  lea    0x1f54(%rdi,%rax,1),%r11
  lea    0xfa8(%rdi),%rbx
  mov    %r9,%rax
  neg    %rax
  lea    -0x8(,%rax,4),%r12
  mov    $0xfffffffffffffffc,%r10
  mov    %rbx,%rbp
  add    $0x2,%r9
  jmp    L15
L31:
  add    $0x1,%rax
  cmp    %rax,%r9
  je     L44
L80:
  mov    (%r8,%rax,4),%edx
  add    (%rdi),%edx
  cmp    %edx,(%rsi,%rax,4)
  jle    L31
  mov    %edx,(%rsi,%rax,4)
  jmp    L31
L44:
  add    $0xfa8,%rcx
  cmp    %r11,%rcx
  je     L99
L83:
  lea    (%rcx,%r10,1),%rsi
  mov    %rcx,%rdi
  cmpl   $0x5f5e100,(%rcx)
  je     L44
  mov    $0x1,%eax
  jmp    L80
L99:
  add    $0x4,%r11
  add    $0xfa8,%rbx
  sub    $0x4,%r10
  cmp    %r12,%r10
  je     L54
L15:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  sub    %r10,%rcx
  jmp    L83
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int n) {
  int i, j, k, u;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      if (dist[i][k] != 100000000) {
        for (j = 1; j <= n; j++) {
          if (dist[i][j] > dist[i][k] + dist[k][j]) {
            dist[i][j] = dist[i][k] + dist[k][j];
          }
        }
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<floyd>:
  endbr64
  test   %esi,%esi
  jle    L24
  lea    -0x1(%rsi),%r8d
  lea    0xfa8(%rdi),%r11
  push   %rbx
  mov    $0xfffffffffffffffc,%r9
  imul   $0xfa8,%r8,%rax
  lea    0x1f54(%rdi,%rax,1),%r10
  mov    %r8,%rax
  mov    %r11,%rdi
  add    $0x2,%r8
  neg    %rax
  lea    -0x8(,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r11,%rcx
  sub    %r9,%rcx
  jmp    L6
L88:
  add    $0xfa8,%rcx
  cmp    %r10,%rcx
  je     L31
L6:
  mov    (%rcx),%edx
  lea    (%rcx,%r9,1),%rsi
  cmp    $0x5f5e100,%edx
  je     L88
  mov    $0x1,%eax
  jmp    L65
  nopl   0x0(%rax)
L42:
  mov    (%rcx),%edx
L65:
  add    (%rdi,%rax,4),%edx
  cmp    %edx,(%rsi,%rax,4)
  jle    L46
  mov    %edx,(%rsi,%rax,4)
L46:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L42
  add    $0xfa8,%rcx
  cmp    %r10,%rcx
  jne    L6
L31:
  sub    $0x4,%r9
  add    $0x4,%r10
  add    $0xfa8,%rdi
  cmp    %rbx,%r9
  jne    L29
  pop    %rbx
  ret
L24:
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int n) {
  int i, j, k, u;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      if (dist[i][k] != 100000000) {
        for (j = 1; j <= n; j++) {
          if (dist[i][j] > dist[i][k] + dist[k][j]) {
            dist[i][j] = dist[i][k] + dist[k][j];
          }
        }
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<floyd>:
  endbr64
  test   %esi,%esi
  jle    L49
  lea    -0x1(%rsi),%r8d
  lea    0xfa8(%rdi),%r11
  push   %rbx
  mov    $0xfffffffffffffffc,%r9
  imul   $0xfa8,%r8,%rax
  lea    0x1f54(%rdi,%rax,1),%r10
  mov    %r8,%rax
  mov    %r11,%rdi
  add    $0x2,%r8
  neg    %rax
  lea    -0x8(,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r11,%rcx
  sub    %r9,%rcx
  jmp    L27
L62:
  add    $0xfa8,%rcx
  cmp    %r10,%rcx
  je     L21
L27:
  mov    (%rcx),%edx
  lea    (%rcx,%r9,1),%rsi
  cmp    $0x5f5e100,%edx
  je     L62
  mov    $0x1,%eax
  jmp    L37
  nopl   0x0(%rax)
L56:
  mov    (%rcx),%edx
L37:
  add    (%rdi,%rax,4),%edx
  cmp    %edx,(%rsi,%rax,4)
  jle    L53
  mov    %edx,(%rsi,%rax,4)
L53:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L56
  add    $0xfa8,%rcx
  cmp    %r10,%rcx
  jne    L27
L21:
  sub    $0x4,%r9
  add    $0x4,%r10
  add    $0xfa8,%rdi
  cmp    %rbx,%r9
  jne    L10
  pop    %rbx
  ret
L49:
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int n) {
  int i, j, k, u;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      if (dist[i][k] != 100000000) {
        for (j = 1; j <= n; j++) {
          if (dist[i][j] > dist[i][k] + dist[k][j]) {
            dist[i][j] = dist[i][k] + dist[k][j];
          }
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mouse_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <mouse_wait@plt>
  mov    $0x60,%edi
  call   <inportb@plt>
  pop    %rbp
  ret
```

assistant: ```c
unsigned char mouse_read() {
  mouse_wait(0);
  return inportb(0x60);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mouse_read>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <mouse_wait@plt>
  mov    $0x60,%edi
  call   <inportb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char mouse_read() {
  mouse_wait(0);
  return inportb(0x60);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mouse_read>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <mouse_wait@plt>
  mov    $0x60,%edi
  add    $0x8,%rsp
  jmp    1060 <inportb@plt>
```

assistant: ```c
unsigned char mouse_read() {
  mouse_wait(0);
  return inportb(0x60);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mouse_read>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <mouse_wait@plt>
  mov    $0x60,%edi
  add    $0x8,%rsp
  jmp    1060 <inportb@plt>
```

assistant: ```c
unsigned char mouse_read() {
  mouse_wait(0);
  return inportb(0x60);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L6
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mem_reverse(char *ptr, char *ptr_end) {
  char tmp_char;
  while (ptr < ptr_end) {
    tmp_char = *ptr_end;
    *ptr_end-- = *ptr;
    *ptr++ = tmp_char;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mem_reverse>:
  endbr64
  cmp    %rsi,%rdi
  jae    L6
L18:
  movzbl (%rsi),%eax
  sub    $0x1,%rsi
  movzbl (%rdi),%edx
  mov    %dl,0x1(%rsi)
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  ja     L18
L6:
  ret
```

assistant: ```c
void mem_reverse(char *ptr, char *ptr_end) {
  char tmp_char;
  while (ptr < ptr_end) {
    tmp_char = *ptr_end;
    *ptr_end-- = *ptr;
    *ptr++ = tmp_char;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mem_reverse>:
  endbr64
  cmp    %rsi,%rdi
  jae    L0
  nopl   0x0(%rax)
L13:
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  sub    $0x1,%rsi
  add    $0x1,%rdi
  mov    %dl,0x1(%rsi)
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  ja     L13
L0:
  ret
```

assistant: ```c
void mem_reverse(char *ptr, char *ptr_end) {
  char tmp_char;
  while (ptr < ptr_end) {
    tmp_char = *ptr_end;
    *ptr_end-- = *ptr;
    *ptr++ = tmp_char;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_reverse>:
  endbr64
  cmp    %rsi,%rdi
  jae    L17
  nopl   0x0(%rax)
L3:
  movzbl (%rsi),%eax
  movzbl (%rdi),%edx
  sub    $0x1,%rsi
  add    $0x1,%rdi
  mov    %dl,0x1(%rsi)
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  ja     L3
L17:
  ret
```

assistant: ```c
void mem_reverse(char *ptr, char *ptr_end) {
  char tmp_char;
  while (ptr < ptr_end) {
    tmp_char = *ptr_end;
    *ptr_end-- = *ptr;
    *ptr++ = tmp_char;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tst_unsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <imaxabs@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void tst_unsigned(unsigned *pu, unsigned long *pl, unsigned long long *pll, uintmax_t *pm) {
  *pu = abs(*pu);
  *pl = labs(*pl);
  *pll = llabs(*pll);
  *pm = imaxabs(*pm);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tst_unsigned>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  mov    (%rcx),%edi
  call   <imaxabs@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tst_unsigned(unsigned *pu, unsigned long *pl, unsigned long long *pll, uintmax_t *pm) {
  *pu = abs(*pu);
  *pl = labs(*pl);
  *pll = llabs(*pll);
  *pm = imaxabs(*pm);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tst_unsigned>:
  endbr64
  push   %rbx
  mov    (%rcx),%edi
  mov    %rcx,%rbx
  call   <imaxabs@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void tst_unsigned(unsigned *pu, unsigned long *pl, unsigned long long *pll, uintmax_t *pm) {
  *pu = abs(*pu);
  *pl = labs(*pl);
  *pll = llabs(*pll);
  *pm = imaxabs(*pm);
}
```