user: 这段汇编代码用C语言表示是什么样的?

```asm
<syntFilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L10
L26:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x24,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L23
L85:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  subss  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L23:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L85
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L88
L0:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  subss  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L88:
  cmpl   $0xa,-0x24(%rbp)
  jle    L0
  addq   $0x4,-0x20(%rbp)
  addl   $0x1,-0x28(%rbp)
L10:
  cmpl   $0x9,-0x28(%rbp)
  jle    L26
  movl   $0xa,-0x28(%rbp)
  jmp    L9
L1:
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L32
L57:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  subss  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L32:
  cmpl   $0xa,-0x24(%rbp)
  jle    L57
  addq   $0x4,-0x20(%rbp)
  addl   $0x1,-0x28(%rbp)
L9:
  mov    -0x28(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L1
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x28(%rax),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x50(%rbp),%rax
  mov    $0x28,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void syntFilter(float *Out, float *a, int len, float *mem) {
  int i;
  int j;
  float *po;
  float *pi;
  float *pa;
  float *pm;
  po = Out;
  for (i = 0; i < 10; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    pm = &mem[10 - 1];
    for (j = 1; j <= i; j++)
      *po -= (*pa++) * (*pi--);
    for (j = i + 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pm--);
    po++;
  }
  for (i = 10; i < len; i++) {
    pi = &Out[i - 1];
    pa = &a[1];
    for (j = 1; j < 10 + 1; j++)
      *po -= (*pa++) * (*pi--);
    po++;
  }
  memcpy(mem, &Out[len - 10], 10 * sizeof(float));
}
```