ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fc_lev_bounded0>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1000,%esi
  setbe  %al
  xor    %edi,%edi
  cmp    $0x1000,%ecx
  setbe  %dil
  and    %eax,%edi
  call   <assert@plt>
  cmp    %ebp,%ebx
  je     L6
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  lea    0x0(,%rbx,4),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int32_t fc_lev_bounded0(const char32_t *seq1, int32_t len1, const char32_t *seq2, int32_t len2) {
  assert((len1 >= 0 && len1 <= 4096) && (len2 >= 0 && len2 <= 4096));
  if (len1 == len2)
    return memcmp(seq1, seq2, len1 * sizeof *seq1) != 0;
  return INT32_MAX;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L6
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L27
L6:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int get_size(const char *path) {
  struct stat st;
  int ssize;
  if ((stat(path, &st)) < 0) {
    ssize = -1;
  } else {
    ssize = st.st_size;
  }
  return ssize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L16
  mov    0x4(%rsp),%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L11
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_size(const char *path) {
  struct stat st;
  int ssize;
  if ((stat(path, &st)) < 0) {
    ssize = -1;
  } else {
    ssize = st.st_size;
  }
  return ssize;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L19
  mov    0x4(%rsp),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L9
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_size(const char *path) {
  struct stat st;
  int ssize;
  if ((stat(path, &st)) < 0) {
    ssize = -1;
  } else {
    ssize = st.st_size;
  }
  return ssize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L28
  mov    0x4(%rsp),%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_size(const char *path) {
  struct stat st;
  int ssize;
  if ((stat(path, &st)) < 0) {
    ssize = -1;
  } else {
    ssize = st.st_size;
  }
  return ssize;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jg     L19
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L13
L19:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exact_square@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D6
type: string

tool: D23: %d

tool: D26: 0 

tool: D6: %d 


assistant: ```c
int main() {
  int number, k;
  scanf("%d", &number);
  if (number <= 2) {
    printf("0 \n");
  } else {
    printf("%d \n", exact_square(number));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x2,%edi
  jg     L23
  lea    D14(%rip),%rdi
  call   <puts@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L23:
  call   <exact_square@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D0: %d

tool: D14: 0 

tool: D8: %d 


assistant: ```c
int main() {
  int number, k;
  scanf("%d", &number);
  if (number <= 2) {
    printf("0 \n");
  } else {
    printf("%d \n", exact_square(number));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x2,%edi
  jg     L19
  lea    D0(%rip),%rdi
  call   <puts@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  call   <exact_square@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L18
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string
name: extract_symbolic_data
arguments: data_label: D13
data_type: string

tool: D4: %d

tool: D0: 0 

tool: D13: %d 


assistant: ```c
int main() {
  int number, k;
  scanf("%d", &number);
  if (number <= 2) {
    printf("0 \n");
  } else {
    printf("%d \n", exact_square(number));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x2,%edi
  jg     L12
  lea    D22(%rip),%rdi
  call   <puts@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  call   <exact_square@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string

tool: D21: %d

tool: D22: 0 

tool: D10: %d 


assistant: ```c
int main() {
  int number, k;
  scanf("%d", &number);
  if (number <= 2) {
    printf("0 \n");
  } else {
    printf("%d \n", exact_square(number));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L11
  mov    $0x0,%eax
  call   <abort@plt>
L11:
  mov    -0x8(%rbp),%eax
  cmp    $0x2,%eax
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    -0x4(%rbp),%eax
  cmp    $0x3,%eax
  je     L22
  mov    $0x0,%eax
  call   <abort@plt>
L22:
  nop
  leave
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } b = {1, 2, 3};
  if (!(b.i == 1))
    abort();
  if (!(b.a.j == 2))
    abort();
  if (!(b.a.k == 3))
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } b = {1, 2, 3};
  if (!(b.i == 1))
    abort();
  if (!(b.a.j == 2))
    abort();
  if (!(b.a.k == 3))
    abort();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } b = {1, 2, 3};
  if (!(b.i == 1))
    abort();
  if (!(b.a.j == 2))
    abort();
  if (!(b.a.k == 3))
    abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  ret
```

assistant: ```c
g() {
  struct {
    int i;
    struct {
      int j, k;
    } a;
  } b = {1, 2, 3};
  if (!(b.i == 1))
    abort();
  if (!(b.a.j == 2))
    abort();
  if (!(b.a.k == 3))
    abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcalloc(size_t num, size_t size) {
  void *ptr_new = xmalloc(num * size);
  ((void)memset(ptr_new, 0, num * size));
  return ptr_new;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xcalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  imul   %rsi,%rdi
  mov    %rdi,%rbp
  call   <xmalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xcalloc(size_t num, size_t size) {
  void *ptr_new = xmalloc(num * size);
  ((void)memset(ptr_new, 0, num * size));
  return ptr_new;
}
```
user: What is the c source code of the assembly code below?

```asm
<xcalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xcalloc(size_t num, size_t size) {
  void *ptr_new = xmalloc(num * size);
  ((void)memset(ptr_new, 0, num * size));
  return ptr_new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xcalloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xcalloc(size_t num, size_t size) {
  void *ptr_new = xmalloc(num * size);
  ((void)memset(ptr_new, 0, num * size));
  return ptr_new;
}
```
user: What is the c source code of the assembly code below:

```asm
<E1_eq3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x14(%rsp)
  test   %edi,%edi
  jle    L37
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %r9,%r15
  movl   $0x0,0x1c(%rsp)
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
L11:
  mov    0x1c(%rsp),%ebx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpos@plt>
  cltq
  movsd  0x0(%rbp,%rax,8),%xmm1
  movapd %xmm1,%xmm0
  addsd  (%r14,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm0
  addsd  (%r15,%rax,8),%xmm1
  mulsd  0x0(%r13,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %ebx,0x18(%rsp)
  add    $0x1,%ebx
  mov    %ebx,0x1c(%rsp)
  cmp    %ebx,0x14(%rsp)
  je     L34
L39:
  mov    %ebx,%esi
  mov    0x18(%rsp),%edi
  call   <mpos@plt>
  cltq
  movsd  0x0(%rbp,%rax,8),%xmm0
  movapd %xmm0,%xmm1
  addsd  (%r14,%rax,8),%xmm1
  mulsd  (%r12,%rax,8),%xmm1
  addsd  (%r15,%rax,8),%xmm0
  mulsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jne    L39
  jmp    L11
L37:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L34:
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: f64

tool: D7: 0.5

assistant: ```c
double E1_eq3(int Mo, double *H, double *Da, double *Db, double *Fa, double *Fb) {
  double E1 = 0.0;
  for (int u = 0; u < Mo; u++) {
    int uu = mpos(u, u);
    E1 += 0.5 * ((H[uu] + Fa[uu]) * Da[uu] + (H[uu] + Fb[uu]) * Db[uu]);
    for (int v = u + 1; v < Mo; v++) {
      int uv = mpos(u, v);
      E1 += (H[uv] + Fa[uv]) * Da[uv] + (H[uv] + Fb[uv]) * Db[uv];
    }
  }
  return E1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<E1_eq3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  test   %edi,%edi
  jle    L27
  pxor   %xmm4,%xmm4
  mov    %rsi,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  movl   $0x0,0x1c(%rsp)
  mov    %r9,%r14
  movsd  %xmm4,0x8(%rsp)
  nopl   0x0(%rax)
L9:
  mov    0x1c(%rsp),%ebp
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %ebp,%r15d
  add    $0x1,%ebp
  call   <mpos@plt>
  mov    0x10(%rsp),%rcx
  mov    %ebp,0x1c(%rsp)
  cltq
  movsd  (%rbx,%rax,8),%xmm1
  movsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  addsd  (%r14,%rax,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,0x18(%rsp)
  je     L4
  nopl   (%rax)
L33:
  mov    %ebp,%esi
  mov    %r15d,%edi
  add    $0x1,%ebp
  call   <mpos@plt>
  mov    0x10(%rsp),%rdx
  cltq
  movsd  (%rbx,%rax,8),%xmm0
  movsd  0x0(%r13,%rax,8),%xmm1
  addsd  %xmm0,%xmm1
  addsd  (%r14,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm1
  mulsd  (%r12,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,0x18(%rsp)
  jne    L33
  jmp    L9
L27:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L4:
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: f64

tool: D5: 0.5

assistant: ```c
double E1_eq3(int Mo, double *H, double *Da, double *Db, double *Fa, double *Fb) {
  double E1 = 0.0;
  for (int u = 0; u < Mo; u++) {
    int uu = mpos(u, u);
    E1 += 0.5 * ((H[uu] + Fa[uu]) * Da[uu] + (H[uu] + Fb[uu]) * Db[uu]);
    for (int v = u + 1; v < Mo; v++) {
      int uv = mpos(u, v);
      E1 += (H[uv] + Fa[uv]) * Da[uv] + (H[uv] + Fb[uv]) * Db[uv];
    }
  }
  return E1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<E1_eq3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x18(%rsp)
  mov    %rdx,0x10(%rsp)
  test   %edi,%edi
  jle    L22
  pxor   %xmm4,%xmm4
  mov    %rsi,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  movl   $0x0,0x1c(%rsp)
  mov    %r9,%r14
  movsd  %xmm4,0x8(%rsp)
  nopl   0x0(%rax)
L20:
  mov    0x1c(%rsp),%ebp
  mov    %ebp,%esi
  mov    %ebp,%edi
  mov    %ebp,%r15d
  add    $0x1,%ebp
  call   <mpos@plt>
  mov    0x10(%rsp),%rcx
  mov    %ebp,0x1c(%rsp)
  cltq
  movsd  (%rbx,%rax,8),%xmm1
  movsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  addsd  (%r14,%rax,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,0x18(%rsp)
  je     L24
  nopl   (%rax)
L6:
  mov    %ebp,%esi
  mov    %r15d,%edi
  add    $0x1,%ebp
  call   <mpos@plt>
  mov    0x10(%rsp),%rdx
  cltq
  movsd  (%rbx,%rax,8),%xmm0
  movsd  0x0(%r13,%rax,8),%xmm1
  addsd  %xmm0,%xmm1
  addsd  (%r14,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm1
  mulsd  (%r12,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,0x18(%rsp)
  jne    L6
  jmp    L20
L22:
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
L24:
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: f64

tool: D5: 0.5

assistant: ```c
double E1_eq3(int Mo, double *H, double *Da, double *Db, double *Fa, double *Fb) {
  double E1 = 0.0;
  for (int u = 0; u < Mo; u++) {
    int uu = mpos(u, u);
    E1 += 0.5 * ((H[uu] + Fa[uu]) * Da[uu] + (H[uu] + Fb[uu]) * Db[uu]);
    for (int v = u + 1; v < Mo; v++) {
      int uv = mpos(u, v);
      E1 += (H[uv] + Fa[uv]) * Da[uv] + (H[uv] + Fb[uv]) * Db[uv];
    }
  }
  return E1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <getNSGetExecutablePath@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: -- main() returns libfoo:foo() --


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("-- main() returns libfoo:foo() --\n");
  getNSGetExecutablePath((char *)argv[0]);
  return foo();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%rdi
  call   <getNSGetExecutablePath@plt>
  mov    $0x0,%eax
  call   <foo@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: -- main() returns libfoo:foo() --


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("-- main() returns libfoo:foo() --\n");
  getNSGetExecutablePath((char *)argv[0]);
  return foo();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  mov    %rsi,%rbx
  call   <printf@plt>
  mov    (%rbx),%rdi
  call   <getNSGetExecutablePath@plt>
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <foo@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: -- main() returns libfoo:foo() --


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("-- main() returns libfoo:foo() --\n");
  getNSGetExecutablePath((char *)argv[0]);
  return foo();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rdi
  mov    %rsi,%rbx
  call   <printf@plt>
  mov    (%rbx),%rdi
  call   <getNSGetExecutablePath@plt>
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <foo@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: -- main() returns libfoo:foo() --


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("-- main() returns libfoo:foo() --\n");
  getNSGetExecutablePath((char *)argv[0]);
  return foo();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unblock_signals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void unblock_signals(void) {
  sigset_t mask;
  sigemptyset(&mask);
  sigaddset(&mask, SIGTERM);
  sigaddset(&mask, SIGINT);
  sigaddset(&mask, SIGQUIT);
  if (sigprocmask(SIG_UNBLOCK, &mask, NULL) != 0) {
    assert(0);
    abort();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unblock_signals>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    D39(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    D34(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jne    L26
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unblock_signals(void) {
  sigset_t mask;
  sigemptyset(&mask);
  sigaddset(&mask, SIGTERM);
  sigaddset(&mask, SIGINT);
  sigaddset(&mask, SIGQUIT);
  if (sigprocmask(SIG_UNBLOCK, &mask, NULL) != 0) {
    assert(0);
    abort();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unblock_signals>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D37(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D38(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D21(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  jne    L9
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  call   <assert@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L10
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unblock_signals(void) {
  sigset_t mask;
  sigemptyset(&mask);
  sigaddset(&mask, SIGTERM);
  sigaddset(&mask, SIGINT);
  sigaddset(&mask, SIGQUIT);
  if (sigprocmask(SIG_UNBLOCK, &mask, NULL) != 0) {
    assert(0);
    abort();
  }
}
```