ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<password>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L57
  sub    $0x1,%eax
  lea    D9(%rip),%r12
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L69
  nopl   (%rax)
L90:
  movb   $0x32,(%rbx)
L78:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L57
L69:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L78
  movzbl (%rbx),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x2,%dl
  jbe    L90
  lea    -0x5a(%rax),%edx
  cmp    $0x20,%dl
  ja     L73
  movzbl %dl,%edx
  movslq (%r12,%rdx,4),%rdx
  add    %r12,%rdx
  notrack jmp *%rdx
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L73:
  add    $0x21,%eax
  mov    %al,(%rbx)
  jmp    L78
  nop
  movb   $0x39,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x37,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x38,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x36,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x35,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x34,(%rbx)
  jmp    L78
  nopl   (%rax)
  movb   $0x33,(%rbx)
  jmp    L78
  movb   $0x61,(%rbx)
  jmp    L78
```

assistant: ```c
void password(char a[]) {
  int i, n = strlen(a);
  for (i = 0; i < n; i++) {
    if (!isalpha(a[i]))
      continue;
    if (a[i] >= 'a' && a[i] <= 'c')
      a[i] = '2';
    else if (a[i] >= 'd' && a[i] <= 'f')
      a[i] = '3';
    else if (a[i] >= 'g' && a[i] <= 'i')
      a[i] = '4';
    else if (a[i] >= 'j' && a[i] <= 'l')
      a[i] = '5';
    else if (a[i] >= 'm' && a[i] <= 'o')
      a[i] = '6';
    else if (a[i] >= 'p' && a[i] <= 's')
      a[i] = '7';
    else if (a[i] >= 't' && a[i] <= 'v')
      a[i] = '8';
    else if (a[i] >= 'w' && a[i] <= 'z')
      a[i] = '9';
    else if (a[i] == 'Z')
      a[i] = 'a';
    else
      a[i] = a[i] + 1 + 'a' - 'A';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<password>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L108
  sub    $0x1,%eax
  lea    D1(%rip),%r12
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L113
  nopl   (%rax)
L61:
  movb   $0x32,(%rbx)
L134:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L108
L113:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L134
  movzbl (%rbx),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x2,%dl
  jbe    L61
  lea    -0x5a(%rax),%edx
  cmp    $0x20,%dl
  ja     L64
  movzbl %dl,%edx
  movslq (%r12,%rdx,4),%rdx
  add    %r12,%rdx
  notrack jmp *%rdx
L108:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L64:
  add    $0x21,%eax
  mov    %al,(%rbx)
  jmp    L134
  nop
  movb   $0x39,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x37,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x38,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x36,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x35,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x34,(%rbx)
  jmp    L134
  nopl   (%rax)
  movb   $0x33,(%rbx)
  jmp    L134
  movb   $0x61,(%rbx)
  jmp    L134
```

assistant: ```c
void password(char a[]) {
  int i, n = strlen(a);
  for (i = 0; i < n; i++) {
    if (!isalpha(a[i]))
      continue;
    if (a[i] >= 'a' && a[i] <= 'c')
      a[i] = '2';
    else if (a[i] >= 'd' && a[i] <= 'f')
      a[i] = '3';
    else if (a[i] >= 'g' && a[i] <= 'i')
      a[i] = '4';
    else if (a[i] >= 'j' && a[i] <= 'l')
      a[i] = '5';
    else if (a[i] >= 'm' && a[i] <= 'o')
      a[i] = '6';
    else if (a[i] >= 'p' && a[i] <= 's')
      a[i] = '7';
    else if (a[i] >= 't' && a[i] <= 'v')
      a[i] = '8';
    else if (a[i] >= 'w' && a[i] <= 'z')
      a[i] = '9';
    else if (a[i] == 'Z')
      a[i] = 'a';
    else
      a[i] = a[i] + 1 + 'a' - 'A';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ghash_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ghash_find@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L5
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
L5:
  leave
  ret
```

assistant: ```c
void *ghash_get(struct ghash *d, const void *key) {
  void **entry;
  if ((entry = ghash_find(d, key)) == 0)
    return 0;
  return *entry;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ghash_get>:
  endbr64
  sub    $0x8,%rsp
  call   <ghash_find@plt>
  test   %rax,%rax
  je     L7
  mov    (%rax),%rax
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *ghash_get(struct ghash *d, const void *key) {
  void **entry;
  if ((entry = ghash_find(d, key)) == 0)
    return 0;
  return *entry;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ghash_get>:
  endbr64
  sub    $0x8,%rsp
  call   <ghash_find@plt>
  test   %rax,%rax
  je     L0
  mov    (%rax),%rax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *ghash_get(struct ghash *d, const void *key) {
  void **entry;
  if ((entry = ghash_find(d, key)) == 0)
    return 0;
  return *entry;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ghash_get>:
  endbr64
  sub    $0x8,%rsp
  call   <ghash_find@plt>
  test   %rax,%rax
  je     L2
  mov    (%rax),%rax
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *ghash_get(struct ghash *d, const void *key) {
  void **entry;
  if ((entry = ghash_find(d, key)) == 0)
    return 0;
  return *entry;
}
```
user: What is the c source code of the assembly code below:

```asm
<isFartherThan_l2_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movss  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x28(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L37
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jmp    L21
L37:
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
L21:
  movd   %eax,%xmm0
  leave
  ret
```

assistant: ```c
float isFartherThan_l2_float(float *p1, float *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
    if (ret > dist2)
      return NAN;
  }
  return sqrt(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isFartherThan_l2_float>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mulss  %xmm0,%xmm0
  movss  %xmm0,0xc(%rsp)
  test   %edx,%edx
  jle    L34
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x8(%rsp)
L13:
  movss  (%r12,%rbx,4),%xmm0
  subss  0x0(%r13,%rbx,4),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x8(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  comiss 0xc(%rsp),%xmm0
  ja     L8
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
L39:
  movss  0x8(%rsp),%xmm0
  call   <sqrt@plt>
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    D7(%rip),%rax
  movss  (%rax),%xmm0
  jmp    L22
L34:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x8(%rsp)
  jmp    L39
```

assistant: ```c
float isFartherThan_l2_float(float *p1, float *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
    if (ret > dist2)
      return NAN;
  }
  return sqrt(ret);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isFartherThan_l2_float>:
  endbr64
  mulss  %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %edx,%edx
  jle    L7
  mov    %rdi,%r13
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  jmp    L22
  nopl   (%rax)
L13:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L27
L22:
  movss  0x0(%r13,%rbx,4),%xmm0
  subss  (%r12,%rbx,4),%xmm0
  mov    $0x2,%edi
  movss  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  comiss 0xc(%rsp),%xmm1
  jbe    L13
  mov    D6(%rip),%rax
  movss  (%rax),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  pxor   %xmm1,%xmm1
L27:
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sqrt@plt>
```

assistant: ```c
float isFartherThan_l2_float(float *p1, float *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
    if (ret > dist2)
      return NAN;
  }
  return sqrt(ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isFartherThan_l2_float>:
  endbr64
  mulss  %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %edx,%edx
  jle    L3
  mov    %rdi,%r13
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  jmp    L2
  nopl   (%rax)
L19:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L17
L2:
  movss  0x0(%r13,%rbx,4),%xmm0
  subss  (%r12,%rbx,4),%xmm0
  mov    $0x2,%edi
  movss  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm1
  comiss 0xc(%rsp),%xmm1
  jbe    L19
  mov    D0(%rip),%rax
  movss  (%rax),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  pxor   %xmm1,%xmm1
L17:
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sqrt@plt>
```

assistant: ```c
float isFartherThan_l2_float(float *p1, float *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  int i = 0;
  for (i = 0; i < len; i++) {
    ret += pow((p1[i] - p2[i]), 2);
    if (ret > dist2)
      return NAN;
  }
  return sqrt(ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %edi,-0x214(%rbp)
  mov    %rsi,-0x220(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x214(%rbp)
  jle    L0
  mov    -0x220(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    -0x210(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: <%p>Len = %d
buf = %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  if (argc > 1)
    strcpy(buf, argv[1]);
  printf("<%p>Len = %d\nbuf = %s\n", buf, strlen(buf), buf);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jg     L5
L12:
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x210,%rsp
  pop    %rbx
  ret
L5:
  mov    0x8(%rsi),%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  jmp    L12
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: <%p>Len = %d
buf = %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  if (argc > 1)
    strcpy(buf, argv[1]);
  printf("<%p>Len = %d\nbuf = %s\n", buf, strlen(buf), buf);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  cmp    $0x1,%edi
  jle    L19
  mov    0x8(%rsi),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: <%p>Len = %d
buf = %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  if (argc > 1)
    strcpy(buf, argv[1]);
  printf("<%p>Len = %d\nbuf = %s\n", buf, strlen(buf), buf);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  cmp    $0x1,%edi
  jle    L5
  mov    0x8(%rsi),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rcx
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: <%p>Len = %d
buf = %s


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[512];
  if (argc > 1)
    strcpy(buf, argv[1]);
  printf("<%p>Len = %d\nbuf = %s\n", buf, strlen(buf), buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tres>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <fill2d@plt>
  movw   $0x0,-0xa(%rbp)
  jmp    L31
L28:
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rdx
  movswq -0xa(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x8(%rbp)
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L31:
  cmpw   $0x6,-0xa(%rbp)
  jg     L28
  movw   $0x0,-0xa(%rbp)
  jmp    L18
L19:
  movswq -0xa(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x8(%rbp)
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L18:
  cmpw   $0x7,-0xa(%rbp)
  jg     L19
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long int tres(int **matriz) {
  long int soma;
  short i;
  fill2d(matriz, 7, 6);
  for (i = 0; i > 6; i++)
    soma += matriz[5][i];
  for (i = 0; i > 7; i++)
    soma += matriz[i][3];
  return soma;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tres>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  mov    $0x7,%esi
  call   <fill2d@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int tres(int **matriz) {
  long int soma;
  short i;
  fill2d(matriz, 7, 6);
  for (i = 0; i > 6; i++)
    soma += matriz[5][i];
  for (i = 0; i > 7; i++)
    soma += matriz[i][3];
  return soma;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tres>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  mov    $0x7,%esi
  call   <fill2d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int tres(int **matriz) {
  long int soma;
  short i;
  fill2d(matriz, 7, 6);
  for (i = 0; i > 6; i++)
    soma += matriz[5][i];
  for (i = 0; i > 7; i++)
    soma += matriz[i][3];
  return soma;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tres>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  mov    $0x7,%esi
  call   <fill2d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int tres(int **matriz) {
  long int soma;
  short i;
  fill2d(matriz, 7, 6);
  for (i = 0; i > 6; i++)
    soma += matriz[5][i];
  for (i = 0; i > 7; i++)
    soma += matriz[i][3];
  return soma;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<feclearexcept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L17
L1:
  mov    $0xffffffff,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int feclearexcept(int excepts) {
  if (excepts == 0)
    return 0;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<feclearexcept>:
  endbr64
  neg    %edi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int feclearexcept(int excepts) {
  if (excepts == 0)
    return 0;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<feclearexcept>:
  endbr64
  neg    %edi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int feclearexcept(int excepts) {
  if (excepts == 0)
    return 0;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<feclearexcept>:
  endbr64
  neg    %edi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int feclearexcept(int excepts) {
  if (excepts == 0)
    return 0;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L8:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L8
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D11
type_infered: string

tool: D4: time: %lu


tool: D11: asctime: %s


assistant: ```c
int main(int argc, char *argv[]) {
  time_t now;
  char *buf;
  struct tm *tmnow;
  while (1) {
    now = time(NULL);
    printf("time: %lu\n", now);
    tmnow = localtime(&now);
    buf = asctime(tmnow);
    printf("asctime: %s\n", buf);
    sleep(1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%r12
  mov    %rsp,%rbp
  lea    D7(%rip),%rbx
L9:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D7
type: string

tool: D4: time: %lu


tool: D7: asctime: %s


assistant: ```c
int main(int argc, char *argv[]) {
  time_t now;
  char *buf;
  struct tm *tmnow;
  while (1) {
    now = time(NULL);
    printf("time: %lu\n", now);
    tmnow = localtime(&now);
    buf = asctime(tmnow);
    printf("asctime: %s\n", buf);
    sleep(1);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   (%rax)
L3:
  xor    %edi,%edi
  call   <time@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D14
type: string
name: unpack_data
arguments: data_label: D13
type: string

tool: D14: time: %lu


tool: D13: asctime: %s


assistant: ```c
int main(int argc, char *argv[]) {
  time_t now;
  char *buf;
  struct tm *tmnow;
  while (1) {
    now = time(NULL);
    printf("time: %lu\n", now);
    tmnow = localtime(&now);
    buf = asctime(tmnow);
    printf("asctime: %s\n", buf);
    sleep(1);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   (%rax)
L5:
  xor    %edi,%edi
  call   <time@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rbx,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D2: time: %lu


tool: D18: asctime: %s


assistant: ```c
int main(int argc, char *argv[]) {
  time_t now;
  char *buf;
  struct tm *tmnow;
  while (1) {
    now = time(NULL);
    printf("time: %lu\n", now);
    tmnow = localtime(&now);
    buf = asctime(tmnow);
    printf("asctime: %s\n", buf);
    sleep(1);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x60(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
L5:
  movq   $0x0,-0x48(%rbp)
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x38(%rbp)
  movq   $0x0,-0x48(%rbp)
  jmp    L17
L0:
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x48(%rbp)
L17:
  mov    -0x48(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpq   $0x0,-0x38(%rbp)
  jne    L5
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D1
type: string

tool: D3: r

tool: D1: %3u, 

assistant: ```c
int main(int argc, const char **argv) {
  FILE *f = fopen(argv[1], "r");
  unsigned char buffer[32];
  size_t s = 0;
  do {
    size_t a = 0;
    s = fread(buffer, sizeof(unsigned char), 32, f);
    for (a = 0; a < s; ++a) {
      printf("%3u, ", buffer[a]);
    }
    printf("\n");
  } while (s > 0);
  fclose(f);
  return 0;
}
```