ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mp_mul_radix_test>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %rcx,%rbx
  mov    %r8,%r13
  mov    %r9,%r14
  mov    %edx,%eax
  sar    %eax
  add    $0x1,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    -0x1(%rsi),%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  %xmm1,(%rcx,%rdx,8)
  cmp    %ebp,%eax
  jge    L3
  lea    0x0(,%rdx,8),%rcx
  sub    $0x8,%rcx
  lea    (%rbx,%rcx,1),%rdx
  lea    -0x8(%rbx,%rcx,1),%rcx
  lea    -0x1(%rbp),%esi
  sub    %eax,%esi
  shl    $0x3,%rsi
  sub    %rsi,%rcx
L9:
  movq   $0x0,(%rdx)
  sub    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L9
L3:
  lea    0x1(%r12),%ecx
  mov    %ecx,%edx
  shr    $0x1f,%edx
  add    %ecx,%edx
  sar    %edx
  cmp    $0x2,%eax
  jle    L21
  cltq
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
L28:
  movsd  %xmm0,(%rbx,%rax,8)
  sub    $0x1,%rax
  cmp    $0x2,%eax
  jg     L28
L21:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  movsd  %xmm0,0x10(%rbx)
  movsd  %xmm1,0x8(%rbx)
  movq   $0x0,(%rbx)
  lea    0x8(%rbx),%r15
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <rdft@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <mp_mul_csqu@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    $0xffffffff,%esi
  mov    %ebp,%edi
  call   <rdft@plt>
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <mp_mul_d2i_test@plt>
  addsd  %xmm0,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double mp_mul_radix_test(int n, int radix, int nfft, double tmpfft[], int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  double mp_mul_d2i_test(int radix, int nfft, double din[]);
  int j, ndata, radix_2;
  ndata = (nfft >> 1) + 1;
  if (ndata > n) {
    ndata = n;
  }
  tmpfft[nfft + 1] = radix - 1;
  for (j = nfft; j > ndata; j--) {
    tmpfft[j] = 0;
  }
  radix_2 = (radix + 1) / 2;
  for (j = ndata; j > 2; j--) {
    tmpfft[j] = radix_2;
  }
  tmpfft[2] = radix;
  tmpfft[1] = radix - 1;
  tmpfft[0] = 0;
  rdft(nfft, 1, &tmpfft[1], ip, w);
  mp_mul_csqu(nfft, tmpfft);
  rdft(nfft, -1, &tmpfft[1], ip, w);
  return 2 * mp_mul_d2i_test(radix, nfft, tmpfft);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mp_mul_radix_test>:
  endbr64
  push   %r15
  mov    %edx,%eax
  pxor   %xmm1,%xmm1
  mov    %r9,%r15
  push   %r14
  sar    %eax
  mov    %r8,%r14
  push   %r13
  add    $0x1,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  cmp    %edi,%eax
  cmovle %eax,%ebx
  movslq %edx,%rax
  lea    -0x1(%rsi),%edx
  cvtsi2sd %edx,%xmm1
  add    $0x1,%rax
  movsd  %xmm1,(%rcx,%rax,8)
  cmp    %ebp,%ebx
  jge    L5
  lea    0x0(,%rax,8),%rcx
  lea    -0x1(%rbp),%eax
  xor    %esi,%esi
  movsd  %xmm1,0x8(%rsp)
  sub    %ebx,%eax
  lea    0x8(,%rax,8),%rdx
  neg    %rax
  lea    -0x8(%rcx,%rax,8),%rdi
  add    %r12,%rdi
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm1
L5:
  lea    0x1(%r13),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    $0x2,%ebx
  jle    L8
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movslq %ebx,%rax
  nopl   0x0(%rax)
L26:
  movsd  %xmm0,(%r12,%rax,8)
  sub    $0x1,%rax
  cmp    $0x2,%eax
  jg     L26
L8:
  pxor   %xmm0,%xmm0
  lea    0x8(%r12),%rbx
  mov    %r15,%r8
  mov    %r14,%rcx
  cvtsi2sd %r13d,%xmm0
  mov    %rbx,%rdx
  mov    %ebp,%edi
  mov    $0x1,%esi
  movq   $0x0,(%r12)
  movsd  %xmm1,0x8(%r12)
  movsd  %xmm0,0x10(%r12)
  call   <rdft@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <mp_mul_csqu@plt>
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  call   <rdft@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <mp_mul_d2i_test@plt>
  add    $0x18,%rsp
  pop    %rbx
  addsd  %xmm0,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double mp_mul_radix_test(int n, int radix, int nfft, double tmpfft[], int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  double mp_mul_d2i_test(int radix, int nfft, double din[]);
  int j, ndata, radix_2;
  ndata = (nfft >> 1) + 1;
  if (ndata > n) {
    ndata = n;
  }
  tmpfft[nfft + 1] = radix - 1;
  for (j = nfft; j > ndata; j--) {
    tmpfft[j] = 0;
  }
  radix_2 = (radix + 1) / 2;
  for (j = ndata; j > 2; j--) {
    tmpfft[j] = radix_2;
  }
  tmpfft[2] = radix;
  tmpfft[1] = radix - 1;
  tmpfft[0] = 0;
  rdft(nfft, 1, &tmpfft[1], ip, w);
  mp_mul_csqu(nfft, tmpfft);
  rdft(nfft, -1, &tmpfft[1], ip, w);
  return 2 * mp_mul_d2i_test(radix, nfft, tmpfft);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mp_mul_radix_test>:
  endbr64
  movslq %edx,%rax
  push   %r15
  lea    -0x1(%rsi),%edx
  pxor   %xmm2,%xmm2
  push   %r14
  cvtsi2sd %edx,%xmm2
  mov    %r8,%r14
  mov    %r9,%r15
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  mov    %eax,%ebx
  sar    %ebx
  add    $0x1,%ebx
  sub    $0x18,%rsp
  cmp    %edi,%ebx
  cmovg  %edi,%ebx
  add    $0x1,%rax
  movsd  %xmm2,(%rcx,%rax,8)
  cmp    %ebp,%ebx
  jge    L1
  lea    0x0(,%rax,8),%rcx
  lea    -0x1(%rbp),%eax
  xor    %esi,%esi
  movsd  %xmm2,0x8(%rsp)
  sub    %ebx,%eax
  lea    0x8(,%rax,8),%rdx
  neg    %rax
  lea    -0x8(%rcx,%rax,8),%rdi
  add    %r12,%rdi
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm2
L1:
  lea    0x1(%r13),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    $0x2,%ebx
  jle    L57
  pxor   %xmm0,%xmm0
  lea    -0x2(%rbx),%esi
  cvtsi2sd %eax,%xmm0
  cmp    $0x3,%ebx
  je     L45
  movslq %ebx,%rax
  mov    %esi,%ecx
  movapd %xmm0,%xmm1
  shr    %ecx
  lea    -0x8(%r12,%rax,8),%rdx
  unpcklpd %xmm1,%xmm1
  lea    -0x1(%rcx),%edi
  lea    -0x10(%rdx),%rax
  shl    $0x4,%rdi
  mov    %rax,%rcx
  sub    %rdi,%rcx
  jmp    L58
  nopl   0x0(%rax)
L31:
  sub    $0x10,%rax
L58:
  movups %xmm1,(%rdx)
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L31
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  sub    %eax,%ebx
  cmp    %eax,%esi
  je     L57
L45:
  movslq %ebx,%rbx
  movsd  %xmm0,(%r12,%rbx,8)
L57:
  pxor   %xmm0,%xmm0
  lea    0x8(%r12),%rbx
  mov    %r15,%r8
  mov    %r14,%rcx
  cvtsi2sd %r13d,%xmm0
  mov    %rbx,%rdx
  mov    %ebp,%edi
  mov    $0x1,%esi
  movq   $0x0,(%r12)
  movsd  %xmm2,0x8(%r12)
  movsd  %xmm0,0x10(%r12)
  call   <rdft@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <mp_mul_csqu@plt>
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  call   <rdft@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <mp_mul_d2i_test@plt>
  add    $0x18,%rsp
  pop    %rbx
  addsd  %xmm0,%xmm0
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double mp_mul_radix_test(int n, int radix, int nfft, double tmpfft[], int ip[], double w[]) {
  void rdft(int n, int isgn, double *a, int *ip, double *w);
  void mp_mul_csqu(int nfft, double dinout[]);
  double mp_mul_d2i_test(int radix, int nfft, double din[]);
  int j, ndata, radix_2;
  ndata = (nfft >> 1) + 1;
  if (ndata > n) {
    ndata = n;
  }
  tmpfft[nfft + 1] = radix - 1;
  for (j = nfft; j > ndata; j--) {
    tmpfft[j] = 0;
  }
  radix_2 = (radix + 1) / 2;
  for (j = ndata; j > 2; j--) {
    tmpfft[j] = radix_2;
  }
  tmpfft[2] = radix;
  tmpfft[1] = radix - 1;
  tmpfft[0] = 0;
  rdft(nfft, 1, &tmpfft[1], ip, w);
  mp_mul_csqu(nfft, tmpfft);
  rdft(nfft, -1, &tmpfft[1], ip, w);
  return 2 * mp_mul_d2i_test(radix, nfft, tmpfft);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<user_cmd_skip_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L8:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <user_cmd_is_white_space@plt>
  test   %rax,%rax
  jne    L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *user_cmd_skip_spaces(char *buffer) {
  char *p = buffer;
  while (user_cmd_is_white_space(*p)) {
    p++;
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<user_cmd_skip_spaces>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L16
L6:
  add    $0x1,%rbx
L16:
  movsbl (%rbx),%edi
  call   <user_cmd_is_white_space@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *user_cmd_skip_spaces(char *buffer) {
  char *p = buffer;
  while (user_cmd_is_white_space(*p)) {
    p++;
  }
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<user_cmd_skip_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12
L13:
  movsbl (%r12),%edi
  call   <user_cmd_is_white_space@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *user_cmd_skip_spaces(char *buffer) {
  char *p = buffer;
  while (user_cmd_is_white_space(*p)) {
    p++;
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<user_cmd_skip_spaces>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12
L0:
  movsbl (%r12),%edi
  call   <user_cmd_is_white_space@plt>
  test   %rax,%rax
  jne    L18
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *user_cmd_skip_spaces(char *buffer) {
  char *p = buffer;
  while (user_cmd_is_white_space(*p)) {
    p++;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intLog10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract_value@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L1
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  je     L48
L1:
  mov    $0x1,%edi
  call   <err@plt>
  mov    $0x0,%eax
  jmp    L6
L79:
  addl   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  je     L16
  movl   $0x1,-0x14(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x10(%rbp)
L48:
  cmpq   $0x9,-0x10(%rbp)
  ja     L79
  cmpl   $0x0,-0x14(%rbp)
  jne    L38
  cmpq   $0x1,-0x10(%rbp)
  je     L31
L38:
  mov    $0x1,%eax
  jmp    L45
L31:
  mov    $0x0,%eax
L45:
  mov    %eax,%edi
  call   <set_carry@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <build_value@plt>
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
long long int intLog10(long long int x) {
  int sx;
  unsigned long long int v = extract_value(x, &sx);
  int r = 0;
  int c = 0;
  if (v == 0 || sx) {
    err(1);
    return 0;
  }
  while (v >= 10) {
    r++;
    if (v % 10)
      c = 1;
    v /= 10;
  }
  set_carry(c || v != 1);
  return build_value(r, sx);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<intLog10>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <extract_value@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rcx
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jne    L2
  mov    %ebx,%esi
  movabs $0xcccccccccccccccd,%rdi
  mov    $0x1,%r8d
  mov    %rax,%rdx
  cmp    $0x9,%rax
  ja     L65
  jmp    L5
L2:
  mov    $0x1,%edi
  call   <err@plt>
  mov    $0x0,%eax
  jmp    L21
L66:
  mov    %rdx,%rcx
L65:
  add    $0x1,%ebx
  mov    %rcx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  cmp    %rax,%rcx
  cmovne %r8d,%esi
  mov    %rcx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  ja     L66
L5:
  test   %esi,%esi
  setne  %dil
  cmp    $0x1,%rdx
  setne  %al
  or     %eax,%edi
  movzbl %dil,%edi
  call   <set_carry@plt>
  mov    0x4(%rsp),%esi
  mov    %ebx,%edi
  call   <build_value@plt>
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long int intLog10(long long int x) {
  int sx;
  unsigned long long int v = extract_value(x, &sx);
  int r = 0;
  int c = 0;
  if (v == 0 || sx) {
    err(1);
    return 0;
  }
  while (v >= 10) {
    r++;
    if (v % 10)
      c = 1;
    v /= 10;
  }
  set_carry(c || v != 1);
  return build_value(r, sx);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intLog10>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <extract_value@plt>
  test   %rax,%rax
  je     L64
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jne    L64
  mov    %rax,%rcx
  xor    %esi,%esi
  mov    $0x1,%r8d
  mov    %rax,%rdx
  movabs $0xcccccccccccccccd,%rdi
  movabs $0x1999999999999999,%r9
  cmp    $0x9,%rax
  ja     L5
L36:
  cmp    $0x1,%rdx
  setne  %dil
  or     %esi,%edi
  movzbl %dil,%edi
  call   <set_carry@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edi
  call   <build_value@plt>
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L42:
  mov    %rdx,%rcx
L5:
  mov    %rcx,%rax
  add    $0x1,%ebp
  imul   %rdi,%rax
  ror    %rax
  cmp    %r9,%rax
  mov    %rcx,%rax
  cmova  %r8d,%esi
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  ja     L42
  and    $0x1,%esi
  jmp    L36
  nopl   0x0(%rax)
L64:
  mov    $0x1,%edi
  call   <err@plt>
  xor    %eax,%eax
  jmp    L31
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long int intLog10(long long int x) {
  int sx;
  unsigned long long int v = extract_value(x, &sx);
  int r = 0;
  int c = 0;
  if (v == 0 || sx) {
    err(1);
    return 0;
  }
  while (v >= 10) {
    r++;
    if (v % 10)
      c = 1;
    v /= 10;
  }
  set_carry(c || v != 1);
  return build_value(r, sx);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intLog10>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <extract_value@plt>
  test   %rax,%rax
  je     L16
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jne    L16
  mov    %rax,%rcx
  xor    %esi,%esi
  mov    $0x1,%r8d
  mov    %rax,%rdx
  movabs $0xcccccccccccccccd,%rdi
  movabs $0x1999999999999999,%r9
  cmp    $0x9,%rax
  ja     L20
L29:
  cmp    $0x1,%rdx
  setne  %dil
  or     %esi,%edi
  movzbl %dil,%edi
  call   <set_carry@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edi
  call   <build_value@plt>
L54:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  mov    %rdx,%rcx
L20:
  mov    %rcx,%rax
  add    $0x1,%ebp
  imul   %rdi,%rax
  ror    %rax
  cmp    %r9,%rax
  mov    %rcx,%rax
  cmova  %r8d,%esi
  mul    %rdi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  ja     L14
  and    $0x1,%esi
  jmp    L29
  nopl   0x0(%rax)
L16:
  mov    $0x1,%edi
  call   <err@plt>
  xor    %eax,%eax
  jmp    L54
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long int intLog10(long long int x) {
  int sx;
  unsigned long long int v = extract_value(x, &sx);
  int r = 0;
  int c = 0;
  if (v == 0 || sx) {
    err(1);
    return 0;
  }
  while (v >= 10) {
    r++;
    if (v % 10)
      c = 1;
    v /= 10;
  }
  set_carry(c || v != 1);
  return build_value(r, sx);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bytes_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x18(%rbp)
  cmpq   $0x3ff,-0x28(%rbp)
  jg     L16
  lea    D1(%rip),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L46
L16:
  cmpq   $0xfffff,-0x28(%rbp)
  jg     L31
  lea    D21(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x400,-0x18(%rbp)
  jmp    L46
L31:
  cmpq   $0x3fffffff,-0x28(%rbp)
  jg     L38
  lea    D22(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x100000,-0x18(%rbp)
  jmp    L46
L38:
  lea    D7(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x40000000,-0x18(%rbp)
L46:
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string
name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D22
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string

tool: D1: %lldb

tool: D21: %lldkb

tool: D22: %lldmb

tool: D7: %lldgb

assistant: ```c
char *bytes_to_string(long long bytes) {
  long div = 1;
  char *str, *fmt;
  if (bytes < 1024) {
    fmt = "%lldb";
  } else if (bytes < 1024 * 1024) {
    fmt = "%lldkb";
    div = 1024;
  } else if (bytes < 1024 * 1024 * 1024) {
    fmt = "%lldmb";
    div = 1024 * 1024;
  } else {
    fmt = "%lldgb";
    div = 1024 * 1024 * 1024;
  }
  asprintf(&str, fmt, bytes / div);
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bytes_to_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  lea    D29(%rip),%rsi
  mov    $0x1,%ecx
  cmp    $0x3ff,%rdi
  jle    L1
  lea    D33(%rip),%rsi
  mov    $0x400,%ecx
  cmp    $0xfffff,%rdi
  jle    L1
  cmp    $0x40000000,%rdi
  lea    D12(%rip),%rsi
  lea    D23(%rip),%rdx
  cmovge %rdx,%rsi
  mov    $0x100000,%ecx
  mov    $0x40000000,%edx
  cmovge %rdx,%rcx
L1:
  cqto
  idiv   %rcx
  mov    %rsp,%rdi
  mov    %rax,%rdx
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D33
datatype: string
name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D23
datatype: string

tool: D29: %lldb

tool: D33: %lldkb

tool: D12: %lldmb

tool: D23: %lldgb

assistant: ```c
char *bytes_to_string(long long bytes) {
  long div = 1;
  char *str, *fmt;
  if (bytes < 1024) {
    fmt = "%lldb";
  } else if (bytes < 1024 * 1024) {
    fmt = "%lldkb";
    div = 1024;
  } else if (bytes < 1024 * 1024 * 1024) {
    fmt = "%lldmb";
    div = 1024 * 1024;
  } else {
    fmt = "%lldgb";
    div = 1024 * 1024 * 1024;
  }
  asprintf(&str, fmt, bytes / div);
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bytes_to_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  lea    D7(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x3ff,%rdi
  jle    L53
  cmp    $0xfffff,%rdi
  jg     L7
  sar    $0xa,%rdx
  lea    D28(%rip),%rsi
L53:
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L7:
  cmp    $0x3fffffff,%rdi
  jg     L40
  sar    $0x14,%rdx
  lea    D8(%rip),%rsi
  jmp    L53
  cs nopw 0x0(%rax,%rax,1)
L40:
  sar    $0x1e,%rdx
  lea    D6(%rip),%rsi
  jmp    L53
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D28
type_guessed: string
name: read_data
arguments: label: D8
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string

tool: D7: %lldb

tool: D28: %lldkb

tool: D8: %lldmb

tool: D6: %lldgb

assistant: ```c
char *bytes_to_string(long long bytes) {
  long div = 1;
  char *str, *fmt;
  if (bytes < 1024) {
    fmt = "%lldb";
  } else if (bytes < 1024 * 1024) {
    fmt = "%lldkb";
    div = 1024;
  } else if (bytes < 1024 * 1024 * 1024) {
    fmt = "%lldmb";
    div = 1024 * 1024;
  } else {
    fmt = "%lldgb";
    div = 1024 * 1024 * 1024;
  }
  asprintf(&str, fmt, bytes / div);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bytes_to_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  lea    D38(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x3ff,%rdi
  jle    L0
  cmp    $0xfffff,%rdi
  jg     L32
  sar    $0xa,%rdx
  lea    D30(%rip),%rsi
L0:
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x18,%rsp
  ret
L32:
  cmp    $0x3fffffff,%rdi
  jg     L48
  sar    $0x14,%rdx
  lea    D39(%rip),%rsi
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L48:
  sar    $0x1e,%rdx
  lea    D31(%rip),%rsi
  jmp    L0
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D31
data_type: string

tool: D38: %lldb

tool: D30: %lldkb

tool: D39: %lldmb

tool: D31: %lldgb

assistant: ```c
char *bytes_to_string(long long bytes) {
  long div = 1;
  char *str, *fmt;
  if (bytes < 1024) {
    fmt = "%lldb";
  } else if (bytes < 1024 * 1024) {
    fmt = "%lldkb";
    div = 1024;
  } else if (bytes < 1024 * 1024 * 1024) {
    fmt = "%lldmb";
    div = 1024 * 1024;
  } else {
    fmt = "%lldgb";
    div = 1024 * 1024 * 1024;
  }
  asprintf(&str, fmt, bytes / div);
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<put_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ptext@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tc_putp@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void put_name(const char *cap, const char *name) {
  if (cap) {
    ptext(name);
    tc_putp(cap);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_name>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <ptext@plt>
  mov    %rbx,%rdi
  call   <tc_putp@plt>
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void put_name(const char *cap, const char *name) {
  if (cap) {
    ptext(name);
    tc_putp(cap);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<put_name>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rdi
  call   <ptext@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <tc_putp@plt>
  xchg   %ax,%ax
L8:
  pop    %rbp
  ret
```

assistant: ```c
void put_name(const char *cap, const char *name) {
  if (cap) {
    ptext(name);
    tc_putp(cap);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<put_name>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rdi
  call   <ptext@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <tc_putp@plt>
  xchg   %ax,%ax
L8:
  pop    %rbp
  ret
```

assistant: ```c
void put_name(const char *cap, const char *name) {
  if (cap) {
    ptext(name);
    tc_putp(cap);
  }
}
```