ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_generator>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jle    L36
  lea    -0x1(%rdi),%ebp
  mov    $0x1,%r12d
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12d
  cmp    %r12d,%ebx
  je     L37
L46:
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <period@plt>
  cmp    %ebp,%eax
  jne    L0
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  je     L37
  mov    $0x1,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L37:
  mov    %ebx,%r12d
  lea    D3(%rip),%rdi
  call   <fftw_die@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: couldn't find generator for Rader


assistant: ```c
int find_generator(int p) {
  int g;
  for (g = 1; g < p; ++g)
    if (period(g, p) == p - 1)
      break;
  if (g == p)
    fftw_die("couldn't find generator for Rader\n");
  return g;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vmci_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void vmci_close(int s) {
  if (s != -1) {
    close(s);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vmci_close>:
  endbr64
  cmp    $0xffffffff,%edi
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void vmci_close(int s) {
  if (s != -1) {
    close(s);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vmci_close>:
  endbr64
  cmp    $0xffffffff,%edi
  jne    L9
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  jmp    1050 <close@plt>
```

assistant: ```c
void vmci_close(int s) {
  if (s != -1) {
    close(s);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vmci_close>:
  endbr64
  cmp    $0xffffffff,%edi
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  jmp    1050 <close@plt>
```

assistant: ```c
void vmci_close(int s) {
  if (s != -1) {
    close(s);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L24:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L3:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x9,-0x4(%rbp)
  jle    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L28:
  cmpl   $0x9,-0x8(%rbp)
  jle    L24
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: %2d

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("%2d", gcd(i, j));
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  lea    D4(%rip),%r12
L4:
  mov    $0x0,%ebx
L5:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  jne    L4
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %2d

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("%2d", gcd(i, j));
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   0x0(%rax)
L12:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <gcd@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L19
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0xa,%ebp
  jne    L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: %2d

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("%2d", gcd(i, j));
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   0x0(%rax)
L0:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <gcd@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L4
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0xa,%ebp
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: %2d

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      printf("%2d", gcd(i, j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L53
  mov    -0x18(%rbp),%rax
  jmp    L12
L53:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L54
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jae    L54
  mov    -0x28(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x10(%rbp)
  jmp    L58
L34:
  subq   $0x1,-0x8(%rbp)
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
L58:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L34
  jmp    L5
L62:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L54:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L62
L5:
  mov    -0x18(%rbp),%rax
L12:
  pop    %rbp
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t n) {
  char *dest = (char *)destination;
  char *src = (char *)source;
  if (dest == src)
    return destination;
  if (src < dest && dest < src + n) {
    src += n;
    dest += n;
    while (n-- > 0)
      *--dest = *--src;
  } else {
    while (n-- > 0)
      *dest++ = *src++;
  }
  return destination;
}
```
user: What is the c source code of the assembly code below?

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L7
  ja     L50
L22:
  mov    $0x0,%ecx
  test   %rdx,%rdx
  je     L17
L25:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L25
L7:
  ret
L17:
  ret
L50:
  lea    (%rsi,%rdx,1),%rcx
  cmp    %rcx,%rdi
  jae    L22
  lea    -0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L7
L8:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L8
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t n) {
  char *dest = (char *)destination;
  char *src = (char *)source;
  if (dest == src)
    return destination;
  if (src < dest && dest < src + n) {
    src += n;
    dest += n;
    while (n-- > 0)
      *--dest = *--src;
  } else {
    while (n-- > 0)
      *dest++ = *src++;
  }
  return destination;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  je     L22
  lea    -0x1(%rdx),%rcx
  jbe    L64
  lea    (%rsi,%rdx,1),%rdi
  cmp    %rdi,%rax
  jae    L64
  test   %rdx,%rdx
  je     L22
L63:
  movzbl (%rsi,%rcx,1),%edx
  mov    %dl,(%rax,%rcx,1)
  sub    $0x1,%rcx
  jae    L63
  ret
  xchg   %ax,%ax
L64:
  xor    %ecx,%ecx
  test   %rdx,%rdx
  je     L15
  nopw   0x0(%rax,%rax,1)
L51:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L51
L22:
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t n) {
  char *dest = (char *)destination;
  char *src = (char *)source;
  if (dest == src)
    return destination;
  if (src < dest && dest < src + n) {
    src += n;
    dest += n;
    while (n-- > 0)
      *--dest = *--src;
  } else {
    while (n-- > 0)
      *dest++ = *src++;
  }
  return destination;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memmove>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  mov    %rdx,%rsi
  cmp    %rcx,%rdi
  je     L50
  lea    -0x1(%rdx),%rax
  jbe    L192
  lea    (%rcx,%rdx,1),%rdx
  cmp    %rdx,%rdi
  jae    L192
  test   %rsi,%rsi
  je     L50
  cs nopw 0x0(%rax,%rax,1)
L183:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  jae    L183
L50:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L192:
  test   %rsi,%rsi
  je     L50
  lea    0x1(%rcx),%rdi
  mov    %r8,%rdx
  sub    %rdi,%rdx
  cmp    $0xe,%rdx
  jbe    L155
  cmp    $0x6,%rax
  jbe    L155
  cmp    $0xe,%rax
  jbe    L10
  mov    %rsi,%rdi
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rdi
  xchg   %ax,%ax
L112:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%r8,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdi,%rdx
  jne    L112
  mov    %rsi,%rdx
  and    $0xfffffffffffffff0,%rdx
  lea    (%r8,%rdx,1),%rdi
  lea    (%rcx,%rdx,1),%r9
  sub    %rdx,%rax
  cmp    %rdx,%rsi
  je     L50
  sub    %rdx,%rsi
  lea    -0x1(%rsi),%r10
  cmp    $0x6,%r10
  jbe    L0
L51:
  mov    (%rcx,%rdx,1),%rcx
  mov    %rcx,(%r8,%rdx,1)
  mov    %rsi,%rdx
  and    $0xfffffffffffffff8,%rdx
  add    %rdx,%rdi
  add    %rdx,%r9
  sub    %rdx,%rax
  cmp    %rdx,%rsi
  je     L50
L0:
  movzbl (%r9),%edx
  mov    %dl,(%rdi)
  test   %rax,%rax
  je     L50
  movzbl 0x1(%r9),%edx
  mov    %dl,0x1(%rdi)
  cmp    $0x1,%rax
  je     L50
  movzbl 0x2(%r9),%edx
  mov    %dl,0x2(%rdi)
  cmp    $0x2,%rax
  je     L50
  movzbl 0x3(%r9),%edx
  mov    %dl,0x3(%rdi)
  cmp    $0x3,%rax
  je     L50
  movzbl 0x4(%r9),%edx
  mov    %dl,0x4(%rdi)
  cmp    $0x4,%rax
  je     L50
  movzbl 0x5(%r9),%edx
  mov    %dl,0x5(%rdi)
  cmp    $0x5,%rax
  je     L50
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
  mov    %r8,%rax
  ret
  nopl   (%rax)
L155:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L119:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L119
  mov    %r8,%rax
  ret
L10:
  mov    %rcx,%r9
  mov    %r8,%rdi
  xor    %edx,%edx
  jmp    L51
```

assistant: ```c
void *memmove(void *destination, const void *source, size_t n) {
  char *dest = (char *)destination;
  char *src = (char *)source;
  if (dest == src)
    return destination;
  if (src < dest && dest < src + n) {
    src += n;
    dest += n;
    while (n-- > 0)
      *--dest = *--src;
  } else {
    while (n-- > 0)
      *dest++ = *src++;
  }
  return destination;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmpf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmpf(void *t, const void *a, const void *b) {
  (void)t;
  (void)a;
  (void)b;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmpf>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cmpf(void *t, const void *a, const void *b) {
  (void)t;
  (void)a;
  (void)b;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmpf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmpf(void *t, const void *a, const void *b) {
  (void)t;
  (void)a;
  (void)b;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmpf>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmpf(void *t, const void *a, const void *b) {
  (void)t;
  (void)a;
  (void)b;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dcircle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x18(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <circle@plt>
  nop
  leave
  ret
```

assistant: ```c
void dcircle(xc, yc, x, y) double xc, yc, x, y;
{
  double radius;
  radius = sqrt((y - yc) * (y - yc) + (x - xc) * (x - xc));
  circle(xc, yc, radius);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dcircle>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  subsd  %xmm1,%xmm3
  subsd  %xmm0,%xmm2
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  addsd  %xmm3,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L6
  sqrtsd %xmm2,%xmm2
L7:
  movq   %r14,%xmm1
  movq   %rbx,%xmm0
  mov    $0x3,%eax
  call   <circle@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
L6:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L7
```

assistant: ```c
void dcircle(xc, yc, x, y) double xc, yc, x, y;
{
  double radius;
  radius = sqrt((y - yc) * (y - yc) + (x - xc) * (x - xc));
  circle(xc, yc, radius);
}
```
user: What is the c source code of the assembly code below:

```asm
<dcircle>:
  endbr64
  subsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm3
  movapd %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  addsd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm0
  ja     L0
  sqrtsd %xmm2,%xmm2
  movapd %xmm4,%xmm0
  mov    $0x3,%eax
  jmp    1070 <circle@plt>
L0:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm4
  movsd  0x8(%rsp),%xmm1
  mov    $0x3,%eax
  movapd %xmm0,%xmm2
  add    $0x18,%rsp
  movapd %xmm4,%xmm0
  jmp    1070 <circle@plt>
```

assistant: ```c
void dcircle(xc, yc, x, y) double xc, yc, x, y;
{
  double radius;
  radius = sqrt((y - yc) * (y - yc) + (x - xc) * (x - xc));
  circle(xc, yc, radius);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dcircle>:
  endbr64
  subsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm3
  movapd %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  addsd  %xmm3,%xmm2
  ucomisd %xmm2,%xmm0
  ja     L6
  sqrtsd %xmm2,%xmm2
  movapd %xmm4,%xmm0
  mov    $0x3,%eax
  jmp    1070 <circle@plt>
L6:
  sub    $0x18,%rsp
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm4,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm4
  movsd  0x8(%rsp),%xmm1
  mov    $0x3,%eax
  movapd %xmm0,%xmm2
  add    $0x18,%rsp
  movapd %xmm4,%xmm0
  jmp    1070 <circle@plt>
```

assistant: ```c
void dcircle(xc, yc, x, y) double xc, yc, x, y;
{
  double radius;
  radius = sqrt((y - yc) * (y - yc) + (x - xc) * (x - xc));
  circle(xc, yc, radius);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L1:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L17:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L1
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, unsigned long n) {
  const char *s = src;
  char *d = dest;
  while (n--)
    *d++ = *s++;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  mov    $0x0,%ecx
L5:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L5
L3:
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, unsigned long n) {
  const char *s = src;
  char *d = dest;
  while (n--)
    *d++ = *s++;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L1
  xor    %ecx,%ecx
  xchg   %ax,%ax
L10:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L10
L1:
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, unsigned long n) {
  const char *s = src;
  char *d = dest;
  while (n--)
    *d++ = *s++;
  return dest;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<memcpy>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  lea    -0x1(%rdx),%rsi
  test   %rdx,%rdx
  je     L120
  lea    0x1(%rcx),%rdi
  mov    %r8,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L91
  cmp    $0x6,%rsi
  jbe    L91
  cmp    $0xe,%rsi
  jbe    L59
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  nopl   0x0(%rax,%rax,1)
L121:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L121
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  lea    (%rcx,%rax,1),%r9
  lea    (%r8,%rax,1),%rdi
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L120
  sub    %rax,%rdx
  lea    -0x1(%rdx),%r10
  cmp    $0x6,%r10
  jbe    L18
L54:
  mov    (%rcx,%rax,1),%rcx
  mov    %rcx,(%r8,%rax,1)
  mov    %rdx,%rax
  and    $0xfffffffffffffff8,%rax
  add    %rax,%r9
  add    %rax,%rdi
  sub    %rax,%rsi
  cmp    %rax,%rdx
  je     L120
L18:
  movzbl (%r9),%eax
  mov    %al,(%rdi)
  test   %rsi,%rsi
  je     L120
  movzbl 0x1(%r9),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x1,%rsi
  je     L120
  movzbl 0x2(%r9),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x2,%rsi
  je     L120
  movzbl 0x3(%r9),%eax
  mov    %al,0x3(%rdi)
  cmp    $0x3,%rsi
  je     L120
  movzbl 0x4(%r9),%eax
  mov    %al,0x4(%rdi)
  cmp    $0x4,%rsi
  je     L120
  movzbl 0x5(%r9),%eax
  mov    %al,0x5(%rdi)
  cmp    $0x5,%rsi
  je     L120
  movzbl 0x6(%r9),%eax
  mov    %al,0x6(%rdi)
L120:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L91:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L151:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L151
  mov    %r8,%rax
  ret
L59:
  mov    %r8,%rdi
  mov    %rcx,%r9
  xor    %eax,%eax
  jmp    L54
```

assistant: ```c
void *memcpy(void *dest, const void *src, unsigned long n) {
  const char *s = src;
  char *d = dest;
  while (n--)
    *d++ = *s++;
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <print_banner@plt>
  mov    $0x0,%eax
  call   <bind_to_cpus@plt>
  mov    $0x0,%eax
  call   <create_threads@plt>
  mov    $0x0,%eax
  call   <monitor_threads@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  print_banner();
  bind_to_cpus();
  create_threads();
  monitor_threads();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  mov    $0x0,%eax
  call   <print_banner@plt>
  mov    $0x0,%eax
  call   <bind_to_cpus@plt>
  mov    $0x0,%eax
  call   <create_threads@plt>
  mov    $0x0,%eax
  call   <monitor_threads@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  print_banner();
  bind_to_cpus();
  create_threads();
  monitor_threads();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <print_banner@plt>
  xor    %eax,%eax
  call   <bind_to_cpus@plt>
  xor    %eax,%eax
  call   <create_threads@plt>
  xor    %eax,%eax
  call   <monitor_threads@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  print_banner();
  bind_to_cpus();
  create_threads();
  monitor_threads();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_args@plt>
  xor    %eax,%eax
  call   <print_banner@plt>
  xor    %eax,%eax
  call   <bind_to_cpus@plt>
  xor    %eax,%eax
  call   <create_threads@plt>
  xor    %eax,%eax
  call   <monitor_threads@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  parse_args(argc, argv);
  print_banner();
  bind_to_cpus();
  create_threads();
  monitor_threads();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<delayus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <systemtimer_get@plt>
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L5:
  mov    $0x0,%eax
  call   <systemtimer_get@plt>
  cmp    %rax,-0x8(%rbp)
  jg     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void delayus(int us) {
  uint64_t end = systemtimer_get() + us;
  while (systemtimer_get() < end)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delayus>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <systemtimer_get@plt>
  movslq %ebx,%rbx
  add    %rax,%rbx
L0:
  mov    $0x0,%eax
  call   <systemtimer_get@plt>
  cmp    %rbx,%rax
  jl     L0
  pop    %rbx
  ret
```

assistant: ```c
void delayus(int us) {
  uint64_t end = systemtimer_get() + us;
  while (systemtimer_get() < end)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delayus>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  movslq %edi,%rbx
  call   <systemtimer_get@plt>
  add    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <systemtimer_get@plt>
  cmp    %rbx,%rax
  jl     L5
  pop    %rbx
  ret
```

assistant: ```c
void delayus(int us) {
  uint64_t end = systemtimer_get() + us;
  while (systemtimer_get() < end)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delayus>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  movslq %edi,%rbx
  call   <systemtimer_get@plt>
  add    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <systemtimer_get@plt>
  cmp    %rbx,%rax
  jl     L2
  pop    %rbx
  ret
```

assistant: ```c
void delayus(int us) {
  uint64_t end = systemtimer_get() + us;
  while (systemtimer_get() < end)
    ;
}
```