ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<FoF_FindFather>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L12
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L14
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int FoF_FindFather(int *grp, int Id) {
  while (Id != grp[Id])
    Id = grp[Id];
  return Id;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<FoF_FindFather>:
  endbr64
L9:
  mov    %esi,%eax
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  cmp    %eax,%esi
  jne    L9
  ret
```

assistant: ```c
int FoF_FindFather(int *grp, int Id) {
  while (Id != grp[Id])
    Id = grp[Id];
  return Id;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FoF_FindFather>:
  endbr64
  mov    %esi,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  cltq
  mov    %rax,%rdx
  mov    (%rdi,%rax,4),%eax
  cmp    %edx,%eax
  jne    L2
  ret
```

assistant: ```c
int FoF_FindFather(int *grp, int Id) {
  while (Id != grp[Id])
    Id = grp[Id];
  return Id;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FoF_FindFather>:
  endbr64
  mov    %esi,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  cltq
  mov    %rax,%rdx
  mov    (%rdi,%rax,4),%eax
  cmp    %edx,%eax
  jne    L6
  ret
```

assistant: ```c
int FoF_FindFather(int *grp, int Id) {
  while (Id != grp[Id])
    Id = grp[Id];
  return Id;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L53:
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L14:
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L18
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L22
L18:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L14
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L53
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D26
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D26: %d

tool: D35: *

tool: D5:  

tool: D2: 


assistant: ```c
int main() {
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if ((i - j) % 3 == 0) {
        printf("*");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  lea    D31(%rip),%r13
  lea    D27(%rip),%r12
  lea    D33(%rip),%r14
  cmpl   $0x0,0x4(%rsp)
  jg     L20
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  mov    %r13,%rdi
  call   <printf@plt>
L45:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jle    L77
L75:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  jne    L63
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L45
L77:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L22
L20:
  mov    $0x0,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L75
  jmp    L77
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D31
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D33
type_guessed: string

tool: D10: %d

tool: D31:  

tool: D27: *

tool: D33: 


assistant: ```c
int main() {
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if ((i - j) % 3 == 0) {
        printf("*");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D26(%rip),%rdi
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D38(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L7
L59:
  xor    %r14d,%r14d
  jmp    L49
  nopl   (%rax)
L33:
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x4(%rsp)
  jle    L2
L49:
  mov    %ebx,%eax
  sub    %r14d,%eax
  imul   $0xaaaaaaab,%eax,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L33
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x4(%rsp)
  jg     L49
L2:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L59
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string

tool: D26: %d

tool: D17: 


tool: D2:  

tool: D38: *

assistant: ```c
int main() {
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if ((i - j) % 3 == 0) {
        printf("*");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%rdi
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L20
L48:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %ebx,%eax
  sub    %r14d,%eax
  imul   $0xaaaaaaab,%eax,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L24
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    0x4(%rsp),%r14d
  jl     L56
L0:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L48
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0x4(%rsp)
  jg     L56
  jmp    L0
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D30
data_type: string
name: unpack_data
arguments: data_label: D32
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D1: %d

tool: D30: 


tool: D32:  

tool: D15: *

assistant: ```c
int main() {
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if ((i - j) % 3 == 0) {
        printf("*");
      } else {
        printf(" ");
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x3fef127f,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x80,0x3f,0x89,0xf7,0xcf,0x41]}

assistant: ```c
double PW(double a, double b) {
  int32_t t = (*(1 + (int32_t *)&a)), u = (int32_t)(b * (t - 1072632447) + 1072632447);
  double p = 0;
  *(1 + (int32_t *)&p) = u;
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<PW>:
  endbr64
  movq   %xmm0,%rax
  sar    $0x20,%rax
  sub    $0x3fef127f,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  shl    $0x20,%rax
  movq   %rax,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: byte[8]

tool: {"D3": [0x00,0x00,0x80,0x3f,0x89,0xf7,0xcf,0x41]}

assistant: ```c
double PW(double a, double b) {
  int32_t t = (*(1 + (int32_t *)&a)), u = (int32_t)(b * (t - 1072632447) + 1072632447);
  double p = 0;
  *(1 + (int32_t *)&p) = u;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PW>:
  endbr64
  movq   %xmm0,%rax
  pxor   %xmm0,%xmm0
  sar    $0x20,%rax
  sub    $0x3fef127f,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  shl    $0x20,%rax
  movq   %rax,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: byte[8]

tool: {"D8": [0x00,0x00,0x80,0x3f,0x89,0xf7,0xcf,0x41]}

assistant: ```c
double PW(double a, double b) {
  int32_t t = (*(1 + (int32_t *)&a)), u = (int32_t)(b * (t - 1072632447) + 1072632447);
  double p = 0;
  *(1 + (int32_t *)&p) = u;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PW>:
  endbr64
  movq   %xmm0,%rax
  pxor   %xmm0,%xmm0
  sar    $0x20,%rax
  sub    $0x3fef127f,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  shl    $0x20,%rax
  movq   %rax,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x80,0x3f,0x89,0xf7,0xcf,0x41]}

assistant: ```c
double PW(double a, double b) {
  int32_t t = (*(1 + (int32_t *)&a)), u = (int32_t)(b * (t - 1072632447) + 1072632447);
  double p = 0;
  *(1 + (int32_t *)&p) = u;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  const char *null = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  const char *null = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  const char *null = 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  const char *null = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <_xtime@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long time(p)
long *p;
{
  long l = _xtime();
  if (p)
    *p = l;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<time>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <_xtime@plt>
  cltq
  test   %rbx,%rbx
  je     L1
  mov    %rax,(%rbx)
L1:
  pop    %rbx
  ret
```

assistant: ```c
long time(p)
long *p;
{
  long l = _xtime();
  if (p)
    *p = l;
  return l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<time>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <_xtime@plt>
  cltq
  test   %rbx,%rbx
  je     L9
  mov    %rax,(%rbx)
L9:
  pop    %rbx
  ret
```

assistant: ```c
long time(p)
long *p;
{
  long l = _xtime();
  if (p)
    *p = l;
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <_xtime@plt>
  cltq
  test   %rbx,%rbx
  je     L7
  mov    %rax,(%rbx)
L7:
  pop    %rbx
  ret
```

assistant: ```c
long time(p)
long *p;
{
  long l = _xtime();
  if (p)
    *p = l;
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x29be1cdb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L5
L20:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L33
  lea    -0xc(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  lea    -0xc(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x1,%rax
  movzbl -0x13(%rbp),%edx
  mov    %dl,(%rax)
L33:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L36
  lea    -0xc(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
L36:
  addl   $0x2,-0x10(%rbp)
L5:
  cmpl   $0x0,-0x10(%rbp)
  je     L20
  mov    -0xc(%rbp),%eax
  xor    $0xde2cc,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] != local1)) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 910028U;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%ecx
  xor    $0x29be1cdb,%ecx
  mov    %ecx,%eax
  cmp    $0x29be1cdb,%edx
  je     L7
L15:
  xor    $0xde2cc,%eax
  mov    %eax,(%rsi)
  ret
L7:
  movsbl %ch,%edx
  mov    %dl,%al
  mov    %cl,%ah
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] != local1)) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 910028U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    $0x29be1cdb,%eax
  xor    $0x29be1cdb,%ecx
  xor    %ax,%ax
  cmp    $0x29be1cdb,%edx
  cmovne %ecx,%eax
  xor    $0xde2cc,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] != local1)) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 910028U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    $0x29be1cdb,%eax
  xor    $0x29be1cdb,%ecx
  xor    %ax,%ax
  cmp    $0x29be1cdb,%edx
  cmovne %ecx,%eax
  xor    $0xde2cc,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy12;
  unsigned short copy13;
  {
    state[0UL] = input[0UL] ^ 700325083U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (!(state[0UL] != local1)) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
      }
      if (state[0UL] <= local1) {
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
        copy13 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] ^ 910028U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D83(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D67(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D20(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D56(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D53(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x4,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  mov    -0x5c(%rbp),%edx
  lea    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stdlib_strided_dmeanpn@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: f64
name: disassemble_data
arguments: data_label: D7
data_type: f64
name: disassemble_data
arguments: data_label: D83
data_type: f64
name: disassemble_data
arguments: data_label: D67
data_type: f64
name: disassemble_data
arguments: data_label: D20
data_type: f64
name: disassemble_data
arguments: data_label: D56
data_type: f64
name: disassemble_data
arguments: data_label: D8
data_type: f64
name: disassemble_data
arguments: data_label: D53
data_type: f64
name: disassemble_data
arguments: data_label: D49
data_type: string

tool: D14: 1

tool: D7: 2

tool: D83: 3

tool: D67: 4

tool: D20: 5

tool: D56: 6

tool: D8: 7

tool: D53: 8

tool: D49: mean: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dmeanpn(N, x, stride);
  printf("mean: %lf\n", v);
}
```