ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L49
L50:
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L69:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L69
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L50
  movl   $0x1,-0x8(%rbp)
  jmp    L65
L41:
  movl   $0x1,-0x4(%rbp)
  jmp    L22
L43:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L43
  addl   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L41
  nop
  nop
  leave
  ret
```

assistant: ```c
void test(int M) {
  int c2, c4;
  int i, j;
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(1);
        hash(c2);
        hash(c4);
      };
    }
  }
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(2);
        hash(c2);
        hash(c4);
      };
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x1,%r12d
  test   %edi,%edi
  jle    L0
L20:
  mov    $0x1,%ebx
L47:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L47
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L20
  mov    $0x1,%r12d
L42:
  mov    $0x1,%ebx
L29:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L29
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L42
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test(int M) {
  int c2, c4;
  int i, j;
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(1);
        hash(c2);
        hash(c4);
      };
    }
  }
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(2);
        hash(c2);
        hash(c4);
      };
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopl   0x0(%rax)
L30:
  mov    $0x1,%ebx
  nopl   (%rax)
L7:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L7
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L30
  mov    $0x1,%r12d
  nop
L22:
  mov    $0x1,%ebx
  nopl   (%rax)
L38:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L38
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  ret
```

assistant: ```c
void test(int M) {
  int c2, c4;
  int i, j;
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(1);
        hash(c2);
        hash(c4);
      };
    }
  }
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(2);
        hash(c2);
        hash(c4);
      };
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  test   %edi,%edi
  jle    L48
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopl   0x0(%rax)
L31:
  mov    $0x1,%ebx
  nopl   (%rax)
L45:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L45
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L31
  mov    $0x1,%r12d
  nop
L47:
  mov    $0x1,%ebx
  nopl   (%rax)
L38:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%ebp
  jge    L38
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jge    L47
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  ret
```

assistant: ```c
void test(int M) {
  int c2, c4;
  int i, j;
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(1);
        hash(c2);
        hash(c4);
      };
    }
  }
  for (c2 = 1; c2 <= M; c2++) {
    for (c4 = 1; c4 <= M; c4++) {
      {
        hash(2);
        hash(c2);
        hash(c4);
      };
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psmat4_rotation_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <mat4_rotation_x@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_rotation_x(struct mat4 *result, float angle) {
  mat4_rotation_x((float *)result, angle);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psmat4_rotation_x>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat4_rotation_x@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_rotation_x(struct mat4 *result, float angle) {
  mat4_rotation_x((float *)result, angle);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<psmat4_rotation_x>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_rotation_x@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_rotation_x(struct mat4 *result, float angle) {
  mat4_rotation_x((float *)result, angle);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psmat4_rotation_x>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_rotation_x@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_rotation_x(struct mat4 *result, float angle) {
  mat4_rotation_x((float *)result, angle);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  const float x = **((const float **)a);
  const float y = **((const float **)b);
  return (x < y) - (x > y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmp>:
  endbr64
  mov    (%rdi),%rax
  movss  (%rax),%xmm1
  mov    (%rsi),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  comiss %xmm0,%xmm1
  seta   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  const float x = **((const float **)a);
  const float y = **((const float **)b);
  return (x < y) - (x > y);
}
```
user: What is the c source code of the assembly code below:

```asm
<cmp>:
  endbr64
  mov    (%rdi),%rax
  movss  (%rax),%xmm1
  mov    (%rsi),%rax
  movss  (%rax),%xmm0
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comiss %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  const float x = **((const float **)a);
  const float y = **((const float **)b);
  return (x < y) - (x > y);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmp>:
  endbr64
  mov    (%rdi),%rax
  movss  (%rax),%xmm1
  mov    (%rsi),%rax
  movss  (%rax),%xmm0
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  xor    %edx,%edx
  comiss %xmm0,%xmm1
  seta   %dl
  sub    %edx,%eax
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  const float x = **((const float **)a);
  const float y = **((const float **)b);
  return (x < y) - (x > y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<update_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  cmpl   $0xffff,-0x4(%rbp)
  jle    L3
  subl   $0xffff,-0x4(%rbp)
L3:
  addq   $0x4,-0x18(%rbp)
  subq   $0x2,-0x20(%rbp)
L1:
  cmpq   $0x0,-0x20(%rbp)
  jne    L9
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_checksum(void *buf, size_t size, uint16_t *sum) {
  uint32_t csum = *sum;
  while (size) {
    csum += *(uint16_t *)buf;
    if (csum > 0xffff)
      csum -= 0xffff;
    buf = (uint16_t *)buf + 1;
    size -= 2;
  }
  *sum = csum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<update_checksum>:
  endbr64
  mov    (%rdx),%eax
  test   %rsi,%rsi
  je     L7
L8:
  add    (%rdi),%eax
  lea    -0xffff(%rax),%ecx
  cmp    $0xffff,%eax
  cmovg  %ecx,%eax
  add    $0x4,%rdi
  sub    $0x2,%rsi
  jne    L8
L7:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void update_checksum(void *buf, size_t size, uint16_t *sum) {
  uint32_t csum = *sum;
  while (size) {
    csum += *(uint16_t *)buf;
    if (csum > 0xffff)
      csum -= 0xffff;
    buf = (uint16_t *)buf + 1;
    size -= 2;
  }
  *sum = csum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<update_checksum>:
  endbr64
  mov    (%rdx),%eax
  test   %rsi,%rsi
  je     L13
  nopl   0x0(%rax,%rax,1)
L5:
  add    (%rdi),%eax
  cmp    $0xffff,%eax
  lea    -0xffff(%rax),%ecx
  cmovg  %ecx,%eax
  add    $0x4,%rdi
  sub    $0x2,%rsi
  jne    L5
L13:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void update_checksum(void *buf, size_t size, uint16_t *sum) {
  uint32_t csum = *sum;
  while (size) {
    csum += *(uint16_t *)buf;
    if (csum > 0xffff)
      csum -= 0xffff;
    buf = (uint16_t *)buf + 1;
    size -= 2;
  }
  *sum = csum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_checksum>:
  endbr64
  mov    (%rdx),%eax
  test   %rsi,%rsi
  je     L11
  nopl   0x0(%rax,%rax,1)
L1:
  add    (%rdi),%eax
  cmp    $0xffff,%eax
  lea    -0xffff(%rax),%ecx
  cmovg  %ecx,%eax
  add    $0x4,%rdi
  sub    $0x2,%rsi
  jne    L1
L11:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void update_checksum(void *buf, size_t size, uint16_t *sum) {
  uint32_t csum = *sum;
  while (size) {
    csum += *(uint16_t *)buf;
    if (csum > 0xffff)
      csum -= 0xffff;
    buf = (uint16_t *)buf + 1;
    size -= 2;
  }
  *sum = csum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L124:
  cmp    %rdx,%rsp
  je     L92
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L124
L92:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L76
  orq    $0x0,-0x8(%rsp,%rax,1)
L76:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L83
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
  jmp    L80
L99:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D16(%rip),%xmm0
  subss  D22(%rip),%xmm0
L90:
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L83
L80:
  mov    $0x0,%eax
  call   <rand_float@plt>
  cvtss2sd %xmm0,%xmm0
  movsd  D18(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L99
  pxor   %xmm0,%xmm0
  divss  %xmm0,%xmm0
  jmp    L90
L83:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L102
  mov    $0x0,%ebx
L79:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <stdlib_strided_dsnansumors@plt>
  ucomisd %xmm0,%xmm0
  jp     L67
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L79
L102:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
L123:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L67:
  lea    D12(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm3
  subsd  %xmm3,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L123
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: byte[4]
name: parse_data
arguments: label: D22
data_type: byte[4]
name: parse_data
arguments: label: D18
data_type: f64
name: parse_data
arguments: label: D12
data_type: string

tool: {"D16": [0x00,0x40,0x9c,0x46]}

tool: {"D22": [0x00,0x40,0x1c,0x46]}

tool: D18: 0.2

tool: D12: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    if (rand_float() < 0.2) {
      x[i] = 0.0f / 0.0f;
    } else {
      x[i] = (rand_float() * 20000.0f) - 10000.0f;
    }
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsnansumors(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: byte[8]
name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D13: %lf

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D6: %.5f


assistant: ```c
int main() {
  double x;
  scanf("%lf", &x);
  printf("%.5f\n", pow(x, 1 / x));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D18
type_guessed: string

tool: D13: %lf

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D18: %.5f


assistant: ```c
int main() {
  double x;
  scanf("%lf", &x);
  printf("%.5f\n", pow(x, 1 / x));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: string
name: unpack_data
arguments: tag: D0
type_infered: byte[8]
name: unpack_data
arguments: tag: D26
type_infered: string

tool: D17: %lf

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D26: %.5f


assistant: ```c
int main() {
  double x;
  scanf("%lf", &x);
  printf("%.5f\n", pow(x, 1 / x));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D12(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: byte[8]
name: parse_data
arguments: label: D28
type_guessed: string

tool: D18: %lf

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D28: %.5f


assistant: ```c
int main() {
  double x;
  scanf("%lf", &x);
  printf("%.5f\n", pow(x, 1 / x));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L43:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L2
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isletter@plt>
  test   %eax,%eax
  je     L43
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L40:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isletter@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L40
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L56
  mov    $0x1,%eax
  jmp    L52
L56:
  mov    $0x0,%eax
L52:
  leave
  ret
```

assistant: ```c
int getword(char *buf) {
  char *s;
  int c;
  while ((c = getchar()) != -1 && isletter(c) == 0)
    ;
  for (s = buf; (c = isletter(c)) != 0; c = getchar())
    *s++ = c;
  *s = 0;
  if (s > buf)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
L21:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L28
  mov    %eax,%edi
  call   <isletter@plt>
  test   %eax,%eax
  je     L21
L28:
  mov    %rbp,%r12
L16:
  mov    %ebx,%edi
  call   <isletter@plt>
  test   %eax,%eax
  je     L39
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  jmp    L16
L39:
  movb   $0x0,(%r12)
  cmp    %rbp,%r12
  seta   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getword(char *buf) {
  char *s;
  int c;
  while ((c = getchar()) != -1 && isletter(c) == 0)
    ;
  for (s = buf; (c = isletter(c)) != 0; c = getchar())
    *s++ = c;
  *s = 0;
  if (s > buf)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L49
  nopl   (%rax)
L0:
  mov    %eax,%edi
  call   <isletter@plt>
  test   %eax,%eax
  jne    L15
L49:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  jne    L0
L15:
  mov    %rbx,%r12
  jmp    L22
  xchg   %ax,%ax
L1:
  mov    %al,(%r12)
  xor    %eax,%eax
  add    $0x1,%r12
  call   <getchar@plt>
  mov    %eax,%ebp
L22:
  mov    %ebp,%edi
  call   <isletter@plt>
  test   %eax,%eax
  jne    L1
  xor    %eax,%eax
  cmp    %rbx,%r12
  movb   $0x0,(%r12)
  pop    %rbx
  seta   %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getword(char *buf) {
  char *s;
  int c;
  while ((c = getchar()) != -1 && isletter(c) == 0)
    ;
  for (s = buf; (c = isletter(c)) != 0; c = getchar())
    *s++ = c;
  *s = 0;
  if (s > buf)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L28
  nopl   (%rax)
L0:
  mov    %eax,%edi
  call   <isletter@plt>
  test   %eax,%eax
  jne    L48
L28:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  jne    L0
L48:
  mov    %rbx,%r12
  jmp    L45
  xchg   %ax,%ax
L37:
  mov    %al,(%r12)
  xor    %eax,%eax
  add    $0x1,%r12
  call   <getchar@plt>
  mov    %eax,%ebp
L45:
  mov    %ebp,%edi
  call   <isletter@plt>
  test   %eax,%eax
  jne    L37
  xor    %eax,%eax
  cmp    %rbx,%r12
  movb   $0x0,(%r12)
  pop    %rbx
  seta   %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getword(char *buf) {
  char *s;
  int c;
  while ((c = getchar()) != -1 && isletter(c) == 0)
    ;
  for (s = buf; (c = isletter(c)) != 0; c = getchar())
    *s++ = c;
  *s = 0;
  if (s > buf)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2fs_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  add    %rax,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    $0x7,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x8(%rbp),%edx
  not    %edx
  and    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f2fs_clear_bit(unsigned int nr, char *addr) {
  int mask;
  int ret;
  addr += (nr >> 3);
  mask = 1 << (7 - (nr & 0x07));
  ret = mask & *addr;
  *addr &= ~mask;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f2fs_clear_bit>:
  endbr64
  mov    %edi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  add    %rax,%rsi
  not    %edi
  mov    %edi,%ecx
  and    $0x7,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  movzbl (%rsi),%eax
  mov    %edx,%ecx
  not    %ecx
  and    %eax,%ecx
  mov    %cl,(%rsi)
  movsbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int f2fs_clear_bit(unsigned int nr, char *addr) {
  int mask;
  int ret;
  addr += (nr >> 3);
  mask = 1 << (7 - (nr & 0x07));
  ret = mask & *addr;
  *addr &= ~mask;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f2fs_clear_bit>:
  endbr64
  mov    %edi,%eax
  not    %edi
  mov    $0x1,%edx
  mov    %edi,%ecx
  shr    $0x3,%eax
  and    $0x7,%ecx
  add    %rax,%rsi
  shl    %cl,%edx
  movsbl (%rsi),%eax
  mov    %edx,%ecx
  not    %ecx
  and    %eax,%ecx
  and    %edx,%eax
  mov    %cl,(%rsi)
  ret
```

assistant: ```c
int f2fs_clear_bit(unsigned int nr, char *addr) {
  int mask;
  int ret;
  addr += (nr >> 3);
  mask = 1 << (7 - (nr & 0x07));
  ret = mask & *addr;
  *addr &= ~mask;
  return ret;
}
```