ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D14: hello(%d)

tool: D10: world(%d).


assistant: ```c
int main(int argc, const char *argv[]) {
#pragma omp parallel
  {
    int ID = omp_get_thread_num();
    printf("hello(%d)", ID);
    printf("world(%d).\n", ID);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <backtrace_print@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(int unused) {
  (void)unused;
  backtrace_print(stdout);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <backtrace_print@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(int unused) {
  (void)unused;
  backtrace_print(stdout);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <backtrace_print@plt>
```

assistant: ```c
void foo(int unused) {
  (void)unused;
  backtrace_print(stdout);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <backtrace_print@plt>
```

assistant: ```c
void foo(int unused) {
  (void)unused;
  backtrace_print(stdout);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ServerName_OnChange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <UnregisterServer@plt>
  mov    $0x0,%eax
  call   <RegisterServer@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ServerName_OnChange(void) {
  UnregisterServer();
  RegisterServer();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ServerName_OnChange>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <UnregisterServer@plt>
  mov    $0x0,%eax
  call   <RegisterServer@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ServerName_OnChange(void) {
  UnregisterServer();
  RegisterServer();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ServerName_OnChange>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <UnregisterServer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RegisterServer@plt>
```

assistant: ```c
void ServerName_OnChange(void) {
  UnregisterServer();
  RegisterServer();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ServerName_OnChange>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <UnregisterServer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RegisterServer@plt>
```

assistant: ```c
void ServerName_OnChange(void) {
  UnregisterServer();
  RegisterServer();
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_non_cali_pointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L34
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3b,%eax
  seta   %dl
  test   %dl,%dl
  jne    L44
  movabs $0x800120000000000,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L44
  mov    -0x8(%rbp),%rax
  jmp    L42
L44:
  addq   $0x1,-0x8(%rbp)
  nop
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
char *find_non_cali_pointer(const char *right_part) {
  char *non_cali_pointer;
  non_cali_pointer = strdup(right_part);
  while (*non_cali_pointer != '\0') {
    switch (*non_cali_pointer) {
    case ',':
    case ')':
    case ';':
      return non_cali_pointer;
    default:
      non_cali_pointer++;
      break;
    }
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_non_cali_pointer>:
  endbr64
  sub    $0x8,%rsp
  call   <strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L43
  movabs $0x800120000000000,%rcx
  jmp    L59
L52:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L58
L59:
  cmp    $0x3b,%dl
  ja     L52
  bt     %rdx,%rcx
  jae    L52
L39:
  add    $0x8,%rsp
  ret
L58:
  mov    $0x0,%eax
  jmp    L39
L43:
  mov    $0x0,%eax
  jmp    L39
```

assistant: ```c
char *find_non_cali_pointer(const char *right_part) {
  char *non_cali_pointer;
  non_cali_pointer = strdup(right_part);
  while (*non_cali_pointer != '\0') {
    switch (*non_cali_pointer) {
    case ',':
    case ')':
    case ';':
      return non_cali_pointer;
    default:
      non_cali_pointer++;
      break;
    }
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_non_cali_pointer>:
  endbr64
  sub    $0x8,%rsp
  call   <strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L21
  movabs $0x800120000000000,%rcx
  jmp    L16
L17:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L21
L16:
  cmp    $0x3b,%dl
  ja     L17
  bt     %rdx,%rcx
  jae    L17
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_non_cali_pointer(const char *right_part) {
  char *non_cali_pointer;
  non_cali_pointer = strdup(right_part);
  while (*non_cali_pointer != '\0') {
    switch (*non_cali_pointer) {
    case ',':
    case ')':
    case ';':
      return non_cali_pointer;
    default:
      non_cali_pointer++;
      break;
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_non_cali_pointer>:
  endbr64
  sub    $0x8,%rsp
  call   <strdup@plt>
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L16
  movabs $0x800120000000000,%rcx
  jmp    L12
L33:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L12:
  cmp    $0x3b,%dl
  ja     L33
  bt     %rdx,%rcx
  jae    L33
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_non_cali_pointer(const char *right_part) {
  char *non_cali_pointer;
  non_cali_pointer = strdup(right_part);
  while (*non_cali_pointer != '\0') {
    switch (*non_cali_pointer) {
    case ',':
    case ')':
    case ';':
      return non_cali_pointer;
    default:
      non_cali_pointer++;
      break;
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L44
L32:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L40
L3:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L26
L23:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L9
  addl   $0x1,-0x1c(%rbp)
  jmp    L4
L9:
  addl   $0x1,-0xc(%rbp)
L4:
  subl   $0x1,-0x10(%rbp)
L26:
  cmpl   $0x0,-0x10(%rbp)
  jg     L23
  subl   $0x1,-0x14(%rbp)
L40:
  cmpl   $0x0,-0x14(%rbp)
  jg     L3
  addl   $0x1,-0x18(%rbp)
L44:
  cmpl   $0x0,-0x18(%rbp)
  jg     L32
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D18: %d

tool: D1: Number of possible triangles is %d

assistant: ```c
int main() {
  int n, c = 0, i, j, k, d = 0;
  scanf("%d", &n);
  for (i = n; i >= 1; i++) {
    for (j = i; j >= 1; j--) {
      for (k = j; k >= 1; k--) {
        if (j + k > i)
          c++;
        else
          d++;
      }
    }
  }
  printf("Number of possible triangles is %d", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r10d
  test   %r10d,%r10d
  jle    L24
  mov    %r10d,%r9d
  add    $0x1,%r10d
  mov    $0x0,%esi
  jmp    L50
L35:
  cmp    %edi,%eax
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%esi
  sub    $0x1,%eax
  cmp    %ecx,%eax
  jne    L35
L51:
  sub    $0x1,%r8d
  je     L58
L26:
  mov    %r8d,%ecx
  lea    (%r8,%r8,1),%eax
  test   %r8d,%r8d
  jg     L35
  jmp    L51
L58:
  add    $0x1,%r9d
  add    $0x1,%r10d
L50:
  mov    %r9d,%edi
  mov    %r9d,%r8d
  test   %r9d,%r9d
  jg     L26
  test   %r10d,%r10d
  jg     L58
L20:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L24:
  mov    $0x0,%esi
  jmp    L20
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D19: %d

tool: D6: Number of possible triangles is %d

assistant: ```c
int main() {
  int n, c = 0, i, j, k, d = 0;
  scanf("%d", &n);
  for (i = n; i >= 1; i++) {
    for (j = i; j >= 1; j--) {
      for (k = j; k >= 1; k--) {
        if (j + k > i)
          c++;
        else
          d++;
      }
    }
  }
  printf("Number of possible triangles is %d", c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L28
L12:
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D4: %d

tool: D18: Number of possible triangles is %d

assistant: ```c
int main() {
  int n, c = 0, i, j, k, d = 0;
  scanf("%d", &n);
  for (i = n; i >= 1; i++) {
    for (j = i; j >= 1; j--) {
      for (k = j; k >= 1; k--) {
        if (j + k > i)
          c++;
        else
          d++;
      }
    }
  }
  printf("Number of possible triangles is %d", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L13
L29:
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %esi,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D3: %d

tool: D14: Number of possible triangles is %d

assistant: ```c
int main() {
  int n, c = 0, i, j, k, d = 0;
  scanf("%d", &n);
  for (i = n; i >= 1; i++) {
    for (j = i; j >= 1; j--) {
      for (k = j; k >= 1; k--) {
        if (j + k > i)
          c++;
        else
          d++;
      }
    }
  }
  printf("Number of possible triangles is %d", c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ippermute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <fatalx@plt>
L35:
  movl   $0x0,-0x10(%rbp)
  jmp    L43
L40:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L43:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L40
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L29:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: Unable to allocate %d unit(s) for item 


assistant: ```c
void ippermute(int **a, int *ind, int len) {
  int i, k;
  int **rrr;
  if ((rrr = (int **)calloc((len), sizeof(int *))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  for (i = 0; i < len; i++) {
    rrr[i] = a[i];
  }
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ippermute>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
L42:
  test   %r13d,%r13d
  jle    L29
  mov    %r13d,%eax
  lea    (%rbx,%rax,8),%rsi
  mov    %rbx,%rax
  mov    %rbp,%rcx
  sub    %rbx,%rcx
L14:
  mov    (%rcx,%rax,1),%rdx
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L14
  mov    %r13d,%ecx
  mov    $0x0,%eax
L10:
  movslq (%r12,%rax,4),%rdx
  mov    (%rbx,%rdx,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L10
L29:
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    %r13d,%esi
  lea    D8(%rip),%rdi
  call   <fatalx@plt>
  jmp    L42
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: Unable to allocate %d unit(s) for item 


assistant: ```c
void ippermute(int **a, int *ind, int len) {
  int i, k;
  int **rrr;
  if ((rrr = (int **)calloc((len), sizeof(int *))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  for (i = 0; i < len; i++) {
    rrr[i] = a[i];
  }
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ippermute>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    $0x8,%esi
  push   %r12
  mov    %rdi,%r12
  mov    %edx,%edi
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L43
L49:
  test   %ebx,%ebx
  jle    L10
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rax
  lea    0x0(%rbp,%rdx,8),%rdi
  sub    %rbp,%rsi
  xchg   %ax,%ax
L45:
  mov    (%rsi,%rax,1),%rcx
  add    $0x8,%rax
  mov    %rcx,-0x8(%rax)
  cmp    %rdi,%rax
  jne    L45
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  movslq 0x0(%r13,%rax,4),%rcx
  mov    0x0(%rbp,%rcx,8),%rcx
  mov    %rcx,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L17
L10:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
  nopl   0x0(%rax)
L43:
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <fatalx@plt>
  jmp    L49
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: Unable to allocate %d unit(s) for item 


assistant: ```c
void ippermute(int **a, int *ind, int len) {
  int i, k;
  int **rrr;
  if ((rrr = (int **)calloc((len), sizeof(int *))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  for (i = 0; i < len; i++) {
    rrr[i] = a[i];
  }
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ippermute>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L42
L39:
  test   %r13d,%r13d
  jle    L80
  lea    0x8(%rbx),%rax
  cmp    %rbp,%rax
  je     L37
  lea    -0x1(%r13),%eax
  cmp    $0x2,%eax
  jbe    L37
  mov    %r13d,%edx
  mov    %rbx,%rcx
  mov    %rbp,%rax
  shr    %edx
  sub    %rbp,%rcx
  shl    $0x4,%rdx
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L64:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L64
  mov    %r13d,%eax
  mov    %r13d,%ecx
  and    $0xfffffffe,%eax
  and    $0x1,%r13d
  je     L93
  mov    (%rbx,%rax,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
L93:
  xor    %eax,%eax
  nopl   0x0(%rax)
L96:
  movslq (%r12,%rax,4),%rdx
  mov    0x0(%rbp,%rdx,8),%rdx
  mov    %rdx,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L96
L80:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
L42:
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  call   <fatalx@plt>
  jmp    L39
  nopl   0x0(%rax)
L37:
  mov    %r13d,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rax
  lea    0x0(%rbp,%rcx,8),%rdi
  sub    %rbp,%rsi
  nopl   0x0(%rax)
L90:
  mov    (%rsi,%rax,1),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rdi,%rax
  jne    L90
  jmp    L93
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: Unable to allocate %d unit(s) for item 


assistant: ```c
void ippermute(int **a, int *ind, int len) {
  int i, k;
  int **rrr;
  if ((rrr = (int **)calloc((len), sizeof(int *))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  for (i = 0; i < len; i++) {
    rrr[i] = a[i];
  }
  for (i = 0; i < len; i++) {
    k = ind[i];
    a[i] = rrr[k];
  }
  free(rrr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<s_strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  leave
  ret
```

assistant: ```c
char *s_strerror(int errnum) {
  switch (errnum) {
  default:
    return strerror(errnum);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_strerror>:
  endbr64
  sub    $0x8,%rsp
  call   <strerror@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *s_strerror(int errnum) {
  switch (errnum) {
  default:
    return strerror(errnum);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_strerror>:
  endbr64
  jmp    1050 <strerror@plt>
```

assistant: ```c
char *s_strerror(int errnum) {
  switch (errnum) {
  default:
    return strerror(errnum);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_strerror>:
  endbr64
  jmp    1050 <strerror@plt>
```

assistant: ```c
char *s_strerror(int errnum) {
  switch (errnum) {
  default:
    return strerror(errnum);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L45:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  js     L45
  mov    -0x10(%rbp),%eax
  cmp    $0x7,%eax
  jg     L45
L44:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L44
  mov    -0xc(%rbp),%eax
  cmp    $0xc8,%eax
  jg     L44
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D1: %d

tool: D26: %d


assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
  } while (a < 0 || a > 7);
  do {
    scanf("%d", &b);
  } while (b < 0 || b > 200);
  printf("%d\n", (b >> a) & 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rbx
L24:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7,(%rsp)
  ja     L24
  lea    D19(%rip),%rbx
L8:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xc8,%esi
  ja     L8
  mov    (%rsp),%ecx
  sar    %cl,%esi
  and    $0x1,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
datatype: string
name: unpack_data
arguments: data_label: D24
datatype: string

tool: D19: %d

tool: D24: %d


assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
  } while (a < 0 || a > 7);
  do {
    scanf("%d", &b);
  } while (b < 0 || b > 200);
  printf("%d\n", (b >> a) & 1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x7,(%rsp)
  ja     L0
  lea    0x4(%rsp),%rbp
  xchg   %ax,%ax
L16:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xc8,%esi
  ja     L16
  mov    (%rsp),%ecx
  lea    D8(%rip),%rdi
  sar    %cl,%esi
  and    $0x1,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D16: %d

tool: D8: %d


assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
  } while (a < 0 || a > 7);
  do {
    scanf("%d", &b);
  } while (b < 0 || b > 200);
  printf("%d\n", (b >> a) & 1);
  return 0;
}
```