ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<KMP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L137
  cmpl   $0x0,-0x1c(%rbp)
  jle    L137
  cmpq   $0x0,-0x28(%rbp)
  je     L137
  cmpl   $0x0,-0x20(%rbp)
  jg     L17
L137:
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    D39(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L108
L17:
  mov    -0x20(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L116
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    D39(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L108
L116:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <KMPComputeDFA@plt>
  movl   $0xffffffff,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L46:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  js     L38
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L46
L38:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L70
  addl   $0x1,-0x10(%rbp)
L70:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L130
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  jmp    L108
L130:
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L108:
  leave
  ret
```

assistant: ```c
int KMP(const char *str, int strLen, const char *pattern, int patternLen) {
  if (!str || strLen < 1 || !pattern || patternLen < 1) {
    errno = EINVAL;
    return -2;
  }
  int *dfa = (int *)calloc(patternLen, sizeof(int));
  if (!dfa) {
    errno = ENOMEM;
    return -2;
  }
  KMPComputeDFA(pattern, patternLen, dfa);
  int k = -1;
  for (int i = 0; i < strLen; ++i) {
    while (k > -1 && str[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (str[i] == pattern[k + 1]) {
      ++k;
    }
    if (k == patternLen - 1) {
      free(dfa);
      return i - k;
    }
  }
  free(dfa);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<KMP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbp
  mov    %ecx,%r15d
  test   %esi,%esi
  jle    L10
  test   %rdx,%rdx
  je     L10
  test   %ecx,%ecx
  jle    L10
  mov    $0x4,%esi
  mov    %ecx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L68
  mov    %rax,%rdx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  call   <KMPComputeDFA@plt>
  mov    $0x0,%ecx
  mov    $0xffffffff,%ebx
  lea    -0x1(%r15),%esi
  jmp    L124
L10:
  mov    D36(%rip),%rax
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L127
L68:
  mov    D30(%rip),%rax
  mov    (%rax),%edx
  mov    D20(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L127
L44:
  movslq %ebx,%rax
  movzbl 0x1(%rbp,%rax,1),%eax
  cmp    %al,0x0(%r13,%rcx,1)
  je     L95
L15:
  cmp    %ebx,%esi
  je     L19
  add    $0x1,%rcx
  cmp    %ecx,%r14d
  jle    L84
L124:
  mov    %ecx,%r15d
  test   %ebx,%ebx
  js     L44
  movzbl 0x0(%r13,%rcx,1),%edx
L70:
  movslq %ebx,%rax
  cmp    0x1(%rbp,%rax,1),%dl
  je     L95
  mov    (%r12,%rax,4),%ebx
  test   %ebx,%ebx
  jns    L70
  jmp    L44
L95:
  add    $0x1,%ebx
  jmp    L15
L19:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15d,%eax
  sub    %ebx,%eax
  jmp    L127
L84:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L127:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int KMP(const char *str, int strLen, const char *pattern, int patternLen) {
  if (!str || strLen < 1 || !pattern || patternLen < 1) {
    errno = EINVAL;
    return -2;
  }
  int *dfa = (int *)calloc(patternLen, sizeof(int));
  if (!dfa) {
    errno = ENOMEM;
    return -2;
  }
  KMPComputeDFA(pattern, patternLen, dfa);
  int k = -1;
  for (int i = 0; i < strLen; ++i) {
    while (k > -1 && str[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (str[i] == pattern[k + 1]) {
      ++k;
    }
    if (k == patternLen - 1) {
      free(dfa);
      return i - k;
    }
  }
  free(dfa);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<KMP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L82
  mov    %esi,%r14d
  test   %esi,%esi
  jle    L82
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L82
  mov    %ecx,%r12d
  test   %ecx,%ecx
  jle    L82
  mov    %rdi,%r13
  mov    $0x4,%esi
  mov    %ecx,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L61
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <KMPComputeDFA@plt>
  lea    -0x1(%r12),%edi
  xor    %esi,%esi
  mov    $0xffffffff,%eax
  nopw   0x0(%rax,%rax,1)
L140:
  movzbl 0x0(%r13,%rsi,1),%ecx
  mov    %esi,%r15d
  test   %eax,%eax
  jns    L50
  jmp    L149
  nopw   0x0(%rax,%rax,1)
L94:
  mov    0x0(%rbp,%rdx,4),%eax
  test   %eax,%eax
  js     L149
L50:
  movslq %eax,%rdx
  cmp    %cl,0x1(%rbx,%rdx,1)
  jne    L94
  lea    0x1(%rax),%r12d
L43:
  mov    %r12d,%eax
  cmp    %edi,%r12d
  je     L124
L127:
  add    $0x1,%rsi
  cmp    %esi,%r14d
  jg     L140
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L149:
  lea    0x1(%rax),%r12d
  movslq %r12d,%rdx
  cmp    %cl,(%rbx,%rdx,1)
  jne    L127
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L124:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L18
L61:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L18
```

assistant: ```c
int KMP(const char *str, int strLen, const char *pattern, int patternLen) {
  if (!str || strLen < 1 || !pattern || patternLen < 1) {
    errno = EINVAL;
    return -2;
  }
  int *dfa = (int *)calloc(patternLen, sizeof(int));
  if (!dfa) {
    errno = ENOMEM;
    return -2;
  }
  KMPComputeDFA(pattern, patternLen, dfa);
  int k = -1;
  for (int i = 0; i < strLen; ++i) {
    while (k > -1 && str[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (str[i] == pattern[k + 1]) {
      ++k;
    }
    if (k == patternLen - 1) {
      free(dfa);
      return i - k;
    }
  }
  free(dfa);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<KMP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L110
  mov    %esi,%r14d
  test   %esi,%esi
  jle    L110
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L110
  mov    %ecx,%r12d
  test   %ecx,%ecx
  jle    L110
  mov    %rdi,%r13
  mov    $0x4,%esi
  mov    %ecx,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L132
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  call   <KMPComputeDFA@plt>
  lea    -0x1(%r12),%edi
  xor    %esi,%esi
  mov    $0xffffffff,%eax
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl 0x0(%r13,%rsi,1),%ecx
  mov    %esi,%r15d
  test   %eax,%eax
  jns    L79
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0x0(%rbp,%rdx,4),%eax
  test   %eax,%eax
  js     L105
L79:
  movslq %eax,%rdx
  cmp    %cl,0x1(%rbx,%rdx,1)
  jne    L19
  lea    0x1(%rax),%r12d
L38:
  mov    %r12d,%eax
  cmp    %edi,%r12d
  je     L147
L4:
  add    $0x1,%rsi
  cmp    %esi,%r14d
  jg     L7
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L139:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  lea    0x1(%rax),%r12d
  movslq %r12d,%rdx
  cmp    %cl,(%rbx,%rdx,1)
  jne    L4
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L147:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L110:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L139
L132:
  mov    D31(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xfffffffe,%eax
  jmp    L139
```

assistant: ```c
int KMP(const char *str, int strLen, const char *pattern, int patternLen) {
  if (!str || strLen < 1 || !pattern || patternLen < 1) {
    errno = EINVAL;
    return -2;
  }
  int *dfa = (int *)calloc(patternLen, sizeof(int));
  if (!dfa) {
    errno = ENOMEM;
    return -2;
  }
  KMPComputeDFA(pattern, patternLen, dfa);
  int k = -1;
  for (int i = 0; i < strLen; ++i) {
    while (k > -1 && str[i] != pattern[k + 1]) {
      k = dfa[k];
    }
    if (str[i] == pattern[k + 1]) {
      ++k;
    }
    if (k == patternLen - 1) {
      free(dfa);
      return i - k;
    }
  }
  free(dfa);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgets_unlocked>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  leave
  ret
```

assistant: ```c
char *fgets_unlocked(char *s, int size, FILE *stream) {
  ;
  return fgets(s, size, stream);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fgets_unlocked>:
  endbr64
  sub    $0x8,%rsp
  call   <fgets@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *fgets_unlocked(char *s, int size, FILE *stream) {
  ;
  return fgets(s, size, stream);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fgets_unlocked>:
  endbr64
  jmp    1050 <fgets@plt>
```

assistant: ```c
char *fgets_unlocked(char *s, int size, FILE *stream) {
  ;
  return fgets(s, size, stream);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgets_unlocked>:
  endbr64
  jmp    1050 <fgets@plt>
```

assistant: ```c
char *fgets_unlocked(char *s, int size, FILE *stream) {
  ;
  return fgets(s, size, stream);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L79
L99:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L51
L79:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L99
  jmp    L87
L51:
  nop
  jmp    L87
L77:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L64
L87:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L77
  jmp    L75
L64:
  nop
L75:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L44
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L79
L44:
  nop
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int a[], int lo, int hi) {
  int i = lo, j = hi + 1, temp;
  while (1) {
    while (a[++i] < a[lo]) {
      if (i == hi)
        break;
    };
    while (a[lo] < a[--j]) {
      if (j == lo)
        break;
    }
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  temp = a[lo];
  a[lo] = a[j];
  a[j] = temp;
  return j;
}
```
user: What is the c source code of the assembly code below?

```asm
<partition>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%r9d
  mov    %edx,%ebp
  lea    0x1(%rdx),%ecx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r12
  lea    0x1(%rsi),%r10d
  movslq %r10d,%r10
  jmp    L63
L51:
  cmp    %ebx,%ecx
  jle    L24
  mov    %esi,(%r11,%r10,4)
  mov    %edx,(%r8)
L64:
  add    $0x1,%r10
L63:
  mov    (%r11,%r10,4),%edx
  mov    (%r12),%edi
  mov    %r10d,%ebx
  cmp    %r10d,%ebp
  je     L29
  cmp    %edi,%edx
  jl     L64
L29:
  movslq %ecx,%rax
  lea    -0x4(%r11,%rax,4),%rax
L23:
  sub    $0x1,%ecx
  mov    %rax,%r8
  mov    (%rax),%esi
  sub    $0x4,%rax
  cmp    %ecx,%r9d
  je     L51
  cmp    %esi,%edi
  jl     L23
  jmp    L51
L24:
  mov    %esi,(%r12)
  mov    %edi,(%r8)
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int partition(int a[], int lo, int hi) {
  int i = lo, j = hi + 1, temp;
  while (1) {
    while (a[++i] < a[lo]) {
      if (i == hi)
        break;
    };
    while (a[lo] < a[--j]) {
      if (j == lo)
        break;
    }
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  temp = a[lo];
  a[lo] = a[j];
  a[j] = temp;
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<partition>:
  endbr64
  movslq %esi,%rax
  push   %r12
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rax,4),%r12
  push   %rbp
  lea    0x1(%rax),%r10d
  mov    %rax,%r9
  push   %rbx
  mov    (%r12),%esi
  mov    %rdi,%rbx
  mov    %edx,%ebp
  movslq %r10d,%r10
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    (%rbx,%r10,4),%r11d
  mov    %r10d,%edx
  cmp    %esi,%r11d
  jge    L57
  cmp    %r10d,%ebp
  jne    L67
L57:
  movslq %r8d,%rax
  lea    -0x4(%rbx,%rax,4),%rax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L31:
  cmp    %ecx,%esi
  jge    L65
L63:
  sub    $0x1,%r8d
  mov    (%rax),%ecx
  mov    %rax,%rdi
  sub    $0x4,%rax
  cmp    %r8d,%r9d
  jne    L31
L65:
  cmp    %edx,%r8d
  jle    L56
  mov    %ecx,(%rbx,%r10,4)
  mov    %r11d,(%rdi)
  mov    (%r12),%esi
L67:
  add    $0x1,%r10
  jmp    L27
  nopl   0x0(%rax)
L56:
  mov    %ecx,(%r12)
  mov    %r8d,%eax
  mov    %esi,(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int partition(int a[], int lo, int hi) {
  int i = lo, j = hi + 1, temp;
  while (1) {
    while (a[++i] < a[lo]) {
      if (i == hi)
        break;
    };
    while (a[lo] < a[--j]) {
      if (j == lo)
        break;
    }
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  temp = a[lo];
  a[lo] = a[j];
  a[j] = temp;
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partition>:
  endbr64
  movslq %esi,%rax
  push   %r12
  lea    0x1(%rdx),%r8d
  lea    (%rdi,%rax,4),%r12
  push   %rbp
  lea    0x1(%rax),%r10d
  mov    %rax,%r9
  push   %rbx
  mov    (%r12),%esi
  mov    %rdi,%rbx
  mov    %edx,%ebp
  movslq %r10d,%r10
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    (%rbx,%r10,4),%r11d
  mov    %r10d,%edx
  cmp    %esi,%r11d
  jge    L54
  cmp    %r10d,%ebp
  jne    L36
L54:
  movslq %r8d,%rax
  lea    -0x4(%rbx,%rax,4),%rax
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L32:
  cmp    %ecx,%esi
  jge    L16
L65:
  sub    $0x1,%r8d
  mov    (%rax),%ecx
  mov    %rax,%rdi
  sub    $0x4,%rax
  cmp    %r8d,%r9d
  jne    L32
L16:
  cmp    %edx,%r8d
  jle    L11
  mov    %ecx,(%rbx,%r10,4)
  mov    %r11d,(%rdi)
  mov    (%r12),%esi
L36:
  add    $0x1,%r10
  jmp    L45
  nopl   0x0(%rax)
L11:
  mov    %ecx,(%r12)
  mov    %r8d,%eax
  mov    %esi,(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int partition(int a[], int lo, int hi) {
  int i = lo, j = hi + 1, temp;
  while (1) {
    while (a[++i] < a[lo]) {
      if (i == hi)
        break;
    };
    while (a[lo] < a[--j]) {
      if (j == lo)
        break;
    }
    if (i >= j)
      break;
    temp = a[i];
    a[i] = a[j];
    a[j] = temp;
  }
  temp = a[lo];
  a[lo] = a[j];
  a[j] = temp;
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_app_extadc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <ParamWrite@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x3,%edi
  call   <ParamWrite@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_app_extadc() {
  ParamWrite(0x0000, 0x0000);
  ParamWrite(0x0001, 0x0000);
  ParamWrite(0x0002, 0x000A);
  ParamWrite(0x0003, 0x000A);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_app_extadc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <ParamWrite@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x3,%edi
  call   <ParamWrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_app_extadc() {
  ParamWrite(0x0000, 0x0000);
  ParamWrite(0x0001, 0x0000);
  ParamWrite(0x0002, 0x000A);
  ParamWrite(0x0003, 0x000A);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_app_extadc>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <ParamWrite@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <ParamWrite@plt>
```

assistant: ```c
void init_app_extadc() {
  ParamWrite(0x0000, 0x0000);
  ParamWrite(0x0001, 0x0000);
  ParamWrite(0x0002, 0x000A);
  ParamWrite(0x0003, 0x000A);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<init_app_extadc>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <ParamWrite@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <ParamWrite@plt>
  mov    $0xa,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1050 <ParamWrite@plt>
```

assistant: ```c
void init_app_extadc() {
  ParamWrite(0x0000, 0x0000);
  ParamWrite(0x0001, 0x0000);
  ParamWrite(0x0002, 0x000A);
  ParamWrite(0x0003, 0x000A);
}
```
user: What is the c source code of the assembly code below?

```asm
<ipow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L23
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <ipow>
  movapd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L5
L23:
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L43
L22:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L35
  movsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L35:
  sarl   -0x1c(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L43:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L22
  movsd  -0x8(%rbp),%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: f64

tool: D1: 1

assistant: ```c
double ipow(double n, int exp) {
  double r;
  if (exp < 0)
    return 1.0 / ipow(n, -exp);
  r = 1;
  while (exp > 0) {
    if (exp & 1)
      r *= n;
    exp >>= 1;
    n *= n;
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ipow>:
  endbr64
  test   %edi,%edi
  js     L3
  movsd  D11(%rip),%xmm1
  jg     L30
L35:
  movapd %xmm1,%xmm0
  ret
L3:
  sub    $0x8,%rsp
  neg    %edi
  call   <ipow>
  movsd  D11(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
L40:
  sar    %edi
  mulsd  %xmm0,%xmm0
  test   %edi,%edi
  jle    L35
L30:
  test   $0x1,%dil
  je     L40
  mulsd  %xmm0,%xmm1
  jmp    L40
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: f64

tool: D11: 1

assistant: ```c
double ipow(double n, int exp) {
  double r;
  if (exp < 0)
    return 1.0 / ipow(n, -exp);
  r = 1;
  while (exp > 0) {
    if (exp & 1)
      r *= n;
    exp >>= 1;
    n *= n;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ipow>:
  endbr64
  test   %edi,%edi
  js     L19
  movsd  D5(%rip),%xmm1
  je     L48
  nopw   0x0(%rax,%rax,1)
L41:
  test   $0x1,%dil
  je     L29
  mulsd  %xmm0,%xmm1
L29:
  mulsd  %xmm0,%xmm0
  sar    %edi
  jne    L41
L48:
  movapd %xmm1,%xmm0
  ret
  nop
L19:
  movsd  D5(%rip),%xmm1
  neg    %edi
  movapd %xmm1,%xmm2
  xchg   %ax,%ax
L33:
  test   $0x1,%dil
  je     L27
  mulsd  %xmm0,%xmm2
L27:
  mulsd  %xmm0,%xmm0
  sar    %edi
  jne    L33
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: f64

tool: D5: 1

assistant: ```c
double ipow(double n, int exp) {
  double r;
  if (exp < 0)
    return 1.0 / ipow(n, -exp);
  r = 1;
  while (exp > 0) {
    if (exp & 1)
      r *= n;
    exp >>= 1;
    n *= n;
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ipow>:
  endbr64
  test   %edi,%edi
  js     L32
  movsd  D0(%rip),%xmm1
  je     L55
  nopw   0x0(%rax,%rax,1)
L59:
  test   $0x1,%dil
  je     L38
  mulsd  %xmm0,%xmm1
L38:
  mulsd  %xmm0,%xmm0
  sar    %edi
  jne    L59
L55:
  movapd %xmm1,%xmm0
  ret
  nop
L32:
  movsd  D0(%rip),%xmm1
  neg    %edi
  movapd %xmm1,%xmm2
  xchg   %ax,%ax
L16:
  test   $0x1,%dil
  je     L29
  mulsd  %xmm0,%xmm2
L29:
  mulsd  %xmm0,%xmm0
  sar    %edi
  jne    L16
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D0
data_type: f64

tool: D0: 1

assistant: ```c
double ipow(double n, int exp) {
  double r;
  if (exp < 0)
    return 1.0 / ipow(n, -exp);
  r = 1;
  while (exp > 0) {
    if (exp & 1)
      r *= n;
    exp >>= 1;
    n *= n;
  }
  return r;
}
```