ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__wait3>:
  endbr64
  sub    $0x8,%rsp
  mov    D27(%rip),%rax
  mov    D22(%rip),%rdx
  mov    (%rax),%eax
  or     (%rdx),%eax
  not    %eax
  test   %esi,%eax
  jne    L3
  mov    D20(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    D33(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t __wait3(int *stat_loc, int options, struct rusage *usage) {
  if ((options & ~(WNOHANG | WUNTRACED)) != 0) {
    __set_errno(EINVAL);
    return (pid_t)-1;
  }
  __set_errno(ENOSYS);
  return (pid_t)-1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__wait3>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    D19(%rip),%rdx
  mov    (%rax),%eax
  or     (%rdx),%eax
  not    %eax
  test   %esi,%eax
  jne    L0
  mov    D21(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    D32(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t __wait3(int *stat_loc, int options, struct rusage *usage) {
  if ((options & ~(WNOHANG | WUNTRACED)) != 0) {
    __set_errno(EINVAL);
    return (pid_t)-1;
  }
  __set_errno(ENOSYS);
  return (pid_t)-1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x217a3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: %d  %d


assistant: ```c
int main() {
  int a = 0x000217a3;
  printf("%d  %d\n", a, ntohl(a));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x217a3,%edi
  call   <ntohl@plt>
  mov    %eax,%edx
  mov    $0x217a3,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %d  %d


assistant: ```c
int main() {
  int a = 0x000217a3;
  printf("%d  %d\n", a, ntohl(a));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x217a3,%edi
  call   <ntohl@plt>
  mov    $0x217a3,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %d  %d


assistant: ```c
int main() {
  int a = 0x000217a3;
  printf("%d  %d\n", a, ntohl(a));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x217a3,%edi
  call   <ntohl@plt>
  mov    $0x217a3,%esi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: %d  %d


assistant: ```c
int main() {
  int a = 0x000217a3;
  printf("%d  %d\n", a, ntohl(a));
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextPermutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L26
L63:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L93
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L93:
  subl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x0,-0xc(%rbp)
  jns    L63
L1:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L5
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  jmp    L3
L5:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L72
L33:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L23
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L98
L23:
  subl   $0x1,-0xc(%rbp)
L72:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L33
L98:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
L3:
  leave
  ret
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i;
  int tmp;
  int mark = -1;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      mark = i;
      break;
    }
  }
  if (mark == -1) {
    reverse(nums, 0, numsSize - 1);
    return;
  }
  for (i = numsSize - 1; i >= mark; i--) {
    if (nums[i] > nums[mark]) {
      tmp = nums[i];
      nums[i] = nums[mark];
      nums[mark] = tmp;
      break;
    }
  }
  reverse(nums, mark + 1, numsSize - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextPermutation>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  sub    $0x2,%eax
  js     L36
  cltq
L1:
  mov    %eax,%ecx
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %edx,(%rdi,%rax,4)
  jl     L76
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L1
L36:
  lea    -0x1(%rsi),%edx
  mov    $0x0,%esi
  call   <reverse@plt>
  jmp    L67
L76:
  cmp    $0xffffffff,%eax
  je     L36
  lea    -0x1(%rsi),%r9d
  cmp    %eax,%r9d
  jl     L29
  cltq
  lea    (%rdi,%rax,4),%r11
  mov    (%r11),%esi
  movslq %r9d,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %r9d,%edx
L5:
  mov    (%rax),%r8d
  cmp    %esi,%r8d
  jg     L20
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    %ecx,%edx
  jge    L5
  jmp    L29
L20:
  mov    %esi,(%rax)
  mov    %r8d,(%r11)
L29:
  lea    0x1(%rcx),%esi
  mov    %r9d,%edx
  call   <reverse@plt>
L67:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i;
  int tmp;
  int mark = -1;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      mark = i;
      break;
    }
  }
  if (mark == -1) {
    reverse(nums, 0, numsSize - 1);
    return;
  }
  for (i = numsSize - 1; i >= mark; i--) {
    if (nums[i] > nums[mark]) {
      tmp = nums[i];
      nums[i] = nums[mark];
      nums[mark] = tmp;
      break;
    }
  }
  reverse(nums, mark + 1, numsSize - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nextPermutation>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%r11
  sub    $0x2,%eax
  js     L40
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rcx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L20:
  sub    $0x1,%eax
  sub    $0x4,%rcx
  cmp    $0xffffffff,%eax
  je     L40
L26:
  mov    (%rcx),%edi
  cmp    0x4(%rcx),%edi
  jge    L20
  lea    -0x1(%rsi),%r10d
  lea    0x4(%r11,%rdx,1),%rdx
  mov    %r10d,%r8d
  cmp    %r10d,%eax
  jle    L68
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L74:
  sub    $0x1,%r8d
  sub    $0x4,%rdx
  cmp    %r8d,%eax
  jg     L44
L68:
  mov    (%rdx),%r9d
  cmp    %r9d,%edi
  jge    L74
  mov    %edi,(%rdx)
  mov    %r9d,(%rcx)
L44:
  lea    0x1(%rax),%esi
  mov    %r10d,%edx
  mov    %r11,%rdi
  jmp    1050 <reverse@plt>
  nopl   0x0(%rax,%rax,1)
L40:
  lea    -0x1(%rsi),%edx
  mov    %r11,%rdi
  xor    %esi,%esi
  jmp    1050 <reverse@plt>
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i;
  int tmp;
  int mark = -1;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      mark = i;
      break;
    }
  }
  if (mark == -1) {
    reverse(nums, 0, numsSize - 1);
    return;
  }
  for (i = numsSize - 1; i >= mark; i--) {
    if (nums[i] > nums[mark]) {
      tmp = nums[i];
      nums[i] = nums[mark];
      nums[mark] = tmp;
      break;
    }
  }
  reverse(nums, mark + 1, numsSize - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nextPermutation>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%r11
  sub    $0x2,%eax
  js     L6
  movslq %esi,%rdx
  shl    $0x2,%rdx
  mov    -0x4(%rdi,%rdx,1),%ecx
  lea    -0x8(%rdi,%rdx,1),%rdi
  jmp    L61
L22:
  sub    $0x1,%eax
  sub    $0x4,%rdi
  cmp    $0xffffffff,%eax
  je     L6
L61:
  mov    %ecx,%r8d
  mov    (%rdi),%ecx
  cmp    %r8d,%ecx
  jge    L22
  lea    -0x1(%rsi),%r10d
  lea    -0x4(%r11,%rdx,1),%rdx
  mov    %r10d,%r8d
  cmp    %r10d,%eax
  jle    L62
  jmp    L11
  nopl   0x0(%rax)
L26:
  sub    $0x1,%r8d
  sub    $0x4,%rdx
  cmp    %r8d,%eax
  jg     L11
L62:
  mov    (%rdx),%r9d
  cmp    %r9d,%ecx
  jge    L26
  mov    %ecx,(%rdx)
  mov    %r9d,(%rdi)
L11:
  lea    0x1(%rax),%esi
  mov    %r10d,%edx
  mov    %r11,%rdi
  jmp    1050 <reverse@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  lea    -0x1(%rsi),%edx
  mov    %r11,%rdi
  xor    %esi,%esi
  jmp    1050 <reverse@plt>
```

assistant: ```c
void nextPermutation(int *nums, int numsSize) {
  int i;
  int tmp;
  int mark = -1;
  for (i = numsSize - 2; i >= 0; i--) {
    if (nums[i] < nums[i + 1]) {
      mark = i;
      break;
    }
  }
  if (mark == -1) {
    reverse(nums, 0, numsSize - 1);
    return;
  }
  for (i = numsSize - 1; i >= mark; i--) {
    if (nums[i] > nums[mark]) {
      tmp = nums[i];
      nums[i] = nums[mark];
      nums[mark] = tmp;
      break;
    }
  }
  reverse(nums, mark + 1, numsSize - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_fs_deinterleave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movss  %xmm0,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L0
L13:
  movl   $0x0,-0x14(%rbp)
  jmp    L30
L28:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x40(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L28
  addl   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jg     L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _fs_deinterleave(float **src, float *dest[], long frames, int channels, float mult_factor) {
  int i, j;
  float *d, *s = (float *)src;
  for (i = 0; i < frames; i++) {
    for (j = 0; j < channels; j++) {
      d = dest[j];
      d[i] = s[i * channels + j] * mult_factor;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_fs_deinterleave>:
  endbr64
  test   %rdx,%rdx
  jle    L18
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%r8
  lea    0x0(,%rdx,4),%rbx
  mov    $0x0,%esi
  mov    $0x0,%r10d
  mov    %ecx,%r9d
  jmp    L55
L26:
  movslq %r10d,%rax
  lea    (%r11,%rax,4),%rdi
  mov    $0x0,%eax
L36:
  mov    (%r8,%rax,8),%rdx
  movaps %xmm0,%xmm1
  mulss  (%rdi,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rsi,1)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L36
L45:
  add    %ecx,%r10d
  add    $0x4,%rsi
  cmp    %rbx,%rsi
  je     L24
L55:
  test   %ecx,%ecx
  jg     L26
  jmp    L45
L24:
  pop    %rbx
  ret
L18:
  ret
```

assistant: ```c
void _fs_deinterleave(float **src, float *dest[], long frames, int channels, float mult_factor) {
  int i, j;
  float *d, *s = (float *)src;
  for (i = 0; i < frames; i++) {
    for (j = 0; j < channels; j++) {
      d = dest[j];
      d[i] = s[i * channels + j] * mult_factor;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_fs_deinterleave>:
  endbr64
  test   %rdx,%rdx
  jle    L11
  mov    %ecx,%r11d
  push   %rbx
  mov    %rdi,%r10
  lea    0x0(,%rdx,4),%rbx
  mov    %rsi,%rdi
  xor    %ecx,%ecx
  lea    -0x1(%r11),%r8d
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L27:
  test   %r11d,%r11d
  jle    L13
  movslq %r9d,%rax
  lea    (%r10,%rax,4),%rsi
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L16:
  movss  (%rsi,%rax,4),%xmm1
  mov    (%rdi,%rax,8),%rdx
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdx,%rcx,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %r8,%rdx
  jne    L16
L13:
  add    $0x4,%rcx
  add    %r11d,%r9d
  cmp    %rcx,%rbx
  jne    L27
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void _fs_deinterleave(float **src, float *dest[], long frames, int channels, float mult_factor) {
  int i, j;
  float *d, *s = (float *)src;
  for (i = 0; i < frames; i++) {
    for (j = 0; j < channels; j++) {
      d = dest[j];
      d[i] = s[i * channels + j] * mult_factor;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_fs_deinterleave>:
  endbr64
  mov    %rsi,%r8
  test   %rdx,%rdx
  jle    L25
  test   %ecx,%ecx
  jle    L25
  movslq %ecx,%rsi
  lea    0x0(,%rdx,4),%r9
  xor    %ecx,%ecx
  lea    0x0(,%rsi,4),%r10
  nopl   (%rax)
L24:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  movss  (%rdi,%rax,4),%xmm1
  mov    (%r8,%rax,8),%rdx
  add    $0x1,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdx,%rcx,1)
  cmp    %rsi,%rax
  jne    L11
  add    $0x4,%rcx
  add    %r10,%rdi
  cmp    %rcx,%r9
  jne    L24
L25:
  ret
```

assistant: ```c
void _fs_deinterleave(float **src, float *dest[], long frames, int channels, float mult_factor) {
  int i, j;
  float *d, *s = (float *)src;
  for (i = 0; i < frames; i++) {
    for (j = 0; j < channels; j++) {
      d = dest[j];
      d[i] = s[i * channels + j] * mult_factor;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ic_transform_ir_expr_literal_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L9
L29:
  cmpl   $0x0,-0xc(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L17:
  mov    $0x1,%eax
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: ic_transform_ir_let_expr_literal_destroy: let was null

assistant: ```c
unsigned int ic_transform_ir_expr_literal_destroy(struct ic_transform_ir_expr_literal *let, unsigned int free_let) {
  if (!let) {
    puts("ic_transform_ir_let_expr_literal_destroy: let was null");
    return 0;
  }
  if (free_let) {
    free(let);
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ic_transform_ir_expr_literal_destroy>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L16
  mov    $0x1,%eax
  test   %esi,%esi
  jne    L36
L28:
  add    $0x8,%rsp
  ret
L16:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L28
L36:
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: ic_transform_ir_let_expr_literal_destroy: let was null

assistant: ```c
unsigned int ic_transform_ir_expr_literal_destroy(struct ic_transform_ir_expr_literal *let, unsigned int free_let) {
  if (!let) {
    puts("ic_transform_ir_let_expr_literal_destroy: let was null");
    return 0;
  }
  if (free_let) {
    free(let);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ic_transform_ir_expr_literal_destroy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L4
  mov    $0x1,%r12d
  test   %esi,%esi
  jne    L15
L19:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: ic_transform_ir_let_expr_literal_destroy: let was null

assistant: ```c
unsigned int ic_transform_ir_expr_literal_destroy(struct ic_transform_ir_expr_literal *let, unsigned int free_let) {
  if (!let) {
    puts("ic_transform_ir_let_expr_literal_destroy: let was null");
    return 0;
  }
  if (free_let) {
    free(let);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ic_transform_ir_expr_literal_destroy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  je     L24
  mov    $0x1,%r12d
  test   %esi,%esi
  jne    L13
L23:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  lea    D6(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L23
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: ic_transform_ir_let_expr_literal_destroy: let was null

assistant: ```c
unsigned int ic_transform_ir_expr_literal_destroy(struct ic_transform_ir_expr_literal *let, unsigned int free_let) {
  if (!let) {
    puts("ic_transform_ir_let_expr_literal_destroy: let was null");
    return 0;
  }
  if (free_let) {
    free(let);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<idbase_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x420(%rbp)
  movl   $0xffffffff,-0x41c(%rbp)
  movq   $0x0,-0x418(%rbp)
  cmpq   $0x0,-0x438(%rbp)
  je     L66
  mov    -0x438(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  jmp    L50
L153:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L148
  addl   $0x1,-0x420(%rbp)
  jmp    L32
L62:
  addq   $0x1,-0x418(%rbp)
L32:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L127
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L127
  mov    -0x418(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L62
L127:
  cmpl   $0x0,-0x420(%rbp)
  jle    L148
  mov    -0x418(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x424(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x424(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x41c(%rbp)
  cmpl   $0x0,-0x41c(%rbp)
  jne    L59
  mov    -0x424(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L59
  mov    $0xffffffff,%eax
  jmp    L40
L59:
  cmpl   $0x0,-0x41c(%rbp)
  je     L103
  lea    -0x410(%rbp),%rax
  mov    $0x1ed,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L103
  mov    $0xffffffff,%eax
  jmp    L40
L103:
  mov    -0x418(%rbp),%rax
  movb   $0x2f,(%rax)
L148:
  addq   $0x1,-0x418(%rbp)
L50:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L153
  mov    $0x0,%eax
  jmp    L40
L66:
  mov    $0xffffffff,%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int idbase_mkdir(char *path) {
  int level = -1, ret = -1;
  struct stat st;
  char fullpath[1024];
  char *p = NULL;
  if (path) {
    strcpy(fullpath, path);
    p = fullpath;
    while (*p != '\0') {
      if (*p == '/') {
        level++;
        while (*p != '\0' && *p == '/' && *(p + 1) == '/')
          ++p;
        if (level > 0) {
          *p = '\0';
          memset(&st, 0, sizeof(struct stat));
          ret = stat(fullpath, &st);
          if (ret == 0 && !S_ISDIR(st.st_mode))
            return -1;
          if (ret != 0 && mkdir(fullpath, 0755) != 0)
            return -1;
          *p = '/';
        }
      }
      ++p;
    }
    return 0;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<idbase_mkdir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L37
  mov    %rdi,%rsi
  lea    0x10(%rsp),%rdi
  call   <strcpy@plt>
  movzbl 0x10(%rsp),%edx
  test   %dl,%dl
  je     L46
  lea    0x10(%rsp),%rax
  mov    $0xffffffff,%ebp
  lea    0xc(%rsp),%r12
  jmp    L66
L25:
  mov    %rax,%rbx
L85:
  test   %ebp,%ebp
  jg     L144
L30:
  lea    0x1(%rbx),%rax
  movzbl 0x1(%rbx),%edx
  test   %dl,%dl
  je     L0
L66:
  mov    %rax,%rbx
  cmp    $0x2f,%dl
  jne    L30
  add    $0x1,%ebp
  cmpb   $0x2f,(%rax)
  jne    L85
L151:
  cmpb   $0x2f,0x1(%rax)
  jne    L25
  add    $0x1,%rax
  cmpb   $0x2f,(%rax)
  je     L151
  mov    %rax,%rbx
  jmp    L85
L144:
  movb   $0x0,(%rbx)
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  call   <stat@plt>
  test   %eax,%eax
  je     L36
  lea    0x10(%rsp),%rdi
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L158
  mov    $0xffffffff,%eax
  jmp    L103
L36:
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L107
L158:
  movb   $0x2f,(%rbx)
  jmp    L30
L0:
  mov    $0x0,%eax
L103:
  mov    0x418(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L95
  add    $0x420,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0xffffffff,%eax
  jmp    L103
L46:
  mov    $0x0,%eax
  jmp    L103
L107:
  mov    $0xffffffff,%eax
  jmp    L103
L95:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int idbase_mkdir(char *path) {
  int level = -1, ret = -1;
  struct stat st;
  char fullpath[1024];
  char *p = NULL;
  if (path) {
    strcpy(fullpath, path);
    p = fullpath;
    while (*p != '\0') {
      if (*p == '/') {
        level++;
        while (*p != '\0' && *p == '/' && *(p + 1) == '/')
          ++p;
        if (level > 0) {
          *p = '\0';
          memset(&st, 0, sizeof(struct stat));
          ret = stat(fullpath, &st);
          if (ret == 0 && !S_ISDIR(st.st_mode))
            return -1;
          if (ret != 0 && mkdir(fullpath, 0755) != 0)
            return -1;
          *p = '/';
        }
      }
      ++p;
    }
    return 0;
  }
  return -1;
}
```