user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply>:
  endbr64
  cmpb   $0x30,(%rdi)
  lea    D2(%rip),%r8
  je     L65
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmpb   $0x30,(%rsi)
  je     L4
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  movslq %eax,%r15
  lea    (%r14,%r15,1),%r12d
  lea    0x0(,%r12,4),%edx
  movslq %r12d,%rax
  mov    %edx,%edi
  mov    %edx,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memset@plt>
  mov    %r14d,%r8d
  sub    $0x1,%r8d
  js     L11
  lea    -0x1(%r15),%r9d
  movslq %r14d,%rax
  lea    -0x2(%rbp,%r15,1),%rdi
  movslq %r9d,%r10
  add    %r10,%rax
  lea    0x0(%r13,%rax,4),%r11
  movslq %r8d,%rax
  lea    (%rbx,%rax,1),%rsi
  mov    %r9d,%eax
  sub    %rax,%rdi
  nopl   0x0(%rax)
L92:
  lea    0x0(%rbp,%r10,1),%rcx
  mov    %r11,%rdx
  test   %r9d,%r9d
  js     L100
  nopl   (%rax)
L16:
  movsbl (%rcx),%r14d
  movsbl (%rsi),%eax
  sub    $0x1,%rcx
  sub    $0x30,%eax
  sub    $0x30,%r14d
  imul   %r14d,%eax
  add    %eax,(%rdx)
  sub    $0x4,%rdx
  cmp    %rdi,%rcx
  jne    L16
L100:
  sub    $0x1,%r8d
  sub    $0x4,%r11
  sub    $0x1,%rsi
  cmp    $0xffffffff,%r8d
  jne    L92
L11:
  lea    -0x1(%r12),%ebp
  test   %ebp,%ebp
  jle    L58
  movslq %ebp,%rax
  lea    -0x4(%r13,%rax,4),%rdx
  mov    0x8(%rsp),%rax
  lea    -0xc(%r13,%rax,4),%rsi
  lea    -0x2(%r12),%eax
  shl    $0x2,%rax
  sub    %rax,%rsi
  nopw   0x0(%rax,%rax,1)
L7:
  movslq 0x4(%rdx),%rax
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  add    %eax,(%rdx)
  movslq 0x4(%rdx),%rax
  sub    $0x4,%rdx
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sar    $0x22,%rax
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,0x8(%rdx)
  cmp    %rdx,%rsi
  jne    L7
L58:
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    0x0(%r13),%eax
  test   %eax,%eax
  sete   %dil
  sete   %al
  movzbl %dil,%edi
  cmp    %edi,%r12d
  jle    L27
  movzbl %al,%eax
  sub    %edi,%ebp
  lea    0x0(%r13,%rax,4),%rcx
  lea    0x1(%r8,%rbp,1),%rsi
  mov    %r8,%rax
  nopw   0x0(%rax,%rax,1)
L64:
  movzbl (%rcx),%ebx
  add    $0x1,%rax
  add    $0x4,%rcx
  lea    0x30(%rbx),%edx
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L64
  sub    %edi,%r12d
  lea    (%r8,%r12,1),%rax
L51:
  movb   $0x0,(%rax)
L4:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  mov    %r8,%rax
  ret
L27:
  mov    %r8,%rax
  jmp    L51
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: 0

assistant: ```c
char *multiply(char *num1, char *num2) {
  if (*num1 == '0' || *num2 == '0')
    return "0";
  int len1 = strlen(num1);
  int len2 = strlen(num2);
  int len = len1 + len2;
  int *arr = (int *)malloc(sizeof(int) * len);
  memset(arr, 0, sizeof(int) * len);
  for (int i = len1 - 1; i > -1; i--)
    for (int j = len2 - 1; j > -1; j--)
      arr[i + j + 1] += (num1[i] - '0') * (num2[j] - '0');
  for (int i = len - 1; i > 0; i--) {
    arr[i - 1] += arr[i] / 10;
    arr[i] %= 10;
  }
  char *s = (char *)malloc(sizeof(char) * (len + 1));
  int index = 0;
  int i = 0;
  if (arr[i] == 0)
    i++;
  while (i < len)
    s[index++] = arr[i++] + '0';
  s[index] = '\0';
  return s;
}
```