ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ex_fcdcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  test   %rdx,%rdx
  je     L61
  mov    %rdx,%rdi
  mov    %rdx,%rbx
  call   <strlen@plt>
  cmp    %eax,%ebp
  cmovle %ebp,%eax
  mov    %eax,%edi
  test   %eax,%eax
  jle    L88
  lea    0x1(%rbx),%rsi
  mov    %r12,%rdx
  mov    %eax,%ecx
  sub    %rsi,%rdx
  lea    -0x1(%rax),%eax
  cmp    $0xe,%rdx
  jbe    L196
  cmp    $0x6,%eax
  jbe    L196
  cmp    $0xe,%eax
  jbe    L2
  mov    %edi,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  cs nopw 0x0(%rax,%rax,1)
L83:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L83
  mov    %edi,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%edi
  je     L88
  mov    %edi,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L176
L80:
  mov    (%rbx,%rdx,1),%rsi
  mov    %rsi,(%r12,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L88
L176:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%edi
  jle    L88
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%edi
  jle    L88
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%edi
  jle    L88
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%edi
  jle    L88
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%edi
  jle    L88
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  cmp    %eax,%edi
  jle    L88
  cltq
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
L88:
  cmp    %ebp,%edi
  jge    L55
  lea    -0x1(%rbp),%edx
  pop    %rbx
  mov    $0x20,%esi
  mov    %edx,%ebp
  sub    %edi,%ebp
  movslq %edi,%rdi
  lea    0x1(%rbp),%rdx
  add    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L61:
  test   %esi,%esi
  jle    L55
  pop    %rbx
  movslq %esi,%rdx
  pop    %rbp
  mov    $0x20,%esi
  pop    %r12
  jmp    1070 <memset@plt>
  nopl   (%rax)
L196:
  mov    %edi,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L34:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L34
  jmp    L88
L2:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L80
```

assistant: ```c
void ex_fcdcpy(char *fstring, int fslen, char *sstring) {
  int i, len;
  if (sstring != 0) {
    len = strlen(sstring);
    if (len > fslen)
      len = fslen;
    for (i = 0; i < len; i++)
      *(fstring + i) = *(sstring + i);
    for (i = len; i < fslen; i++)
      *(fstring + i) = ' ';
  } else {
    for (i = 0; i < fslen; i++)
      *(fstring + i) = ' ';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strip_escapes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <resize_buffer@plt>
  test   %eax,%eax
  jne    L45
  mov    $0x0,%eax
  jmp    L35
L37:
  addq   $0x1,-0x18(%rbp)
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L43
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  jmp    L22
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
L22:
  mov    D12(%rip),%rsi
  mov    -0x8(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x8(%rbp)
  movslq %edx,%rdx
  add    %rsi,%rdx
  mov    %al,(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L37
  mov    D12(%rip),%rax
L35:
  leave
  ret
```

assistant: ```c
const char *strip_escapes(const char *s) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(s);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*s == '\\') ? *++s : *s)))
    s++;
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edx
  lea    D20(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L17
  mov    $0x0,%edx
  jmp    L36
L29:
  mov    D12(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L51
  add    $0x1,%rbx
L36:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L29
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbx
  jmp    L29
L51:
  mov    D12(%rip),%rax
L50:
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  jmp    L50
```

assistant: ```c
const char *strip_escapes(const char *s) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(s);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*s == '\\') ? *++s : *s)))
    s++;
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D21(%rip),%rsi
  lea    D13(%rip),%rdi
  lea    0x1(%rax),%edx
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L4
  xor    %edx,%edx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rbx
L23:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L20
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
L20:
  mov    D13(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  jne    L39
  mov    D13(%rip),%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
const char *strip_escapes(const char *s) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(s);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*s == '\\') ? *++s : *s)))
    s++;
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<strip_escapes>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D1(%rip),%rsi
  lea    D30(%rip),%rdi
  lea    0x1(%rax),%edx
  call   <resize_buffer@plt>
  test   %eax,%eax
  je     L3
  xor    %edx,%edx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L33:
  mov    D30(%rip),%rcx
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L49
L24:
  add    $0x1,%rbx
L1:
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jne    L33
  movzbl 0x1(%rbx),%eax
  mov    D30(%rip),%rcx
  lea    0x1(%rbx),%rsi
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  je     L49
  mov    %rsi,%rbx
  jmp    L24
  nopl   0x0(%rax)
L49:
  mov    D30(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
const char *strip_escapes(const char *s) {
  static char *buf = 0;
  static int bufsz = 0;
  const int len = strlen(s);
  int i = 0;
  if (!resize_buffer(&buf, &bufsz, len + 1))
    return 0;
  while ((buf[i++] = ((*s == '\\') ? *++s : *s)))
    s++;
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_serial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L14
  lea    D24(%rip),%rax
  mov    %rax,%rdx
  lea    D34(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <err@plt>
L14:
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x1,%rax
  je     L8
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <err@plt>
L8:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,4),%rdx
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D24
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D17: r

tool: D24: serial

tool: D34: fopen(%s)

tool: D6: fread(serial): %d

assistant: ```c
unsigned int *get_serial(size_t *len) {
  FILE *fp;
  unsigned int num[1], *p;
  fp = fopen("serial", "r");
  if (fp == NULL)
    err(1, "fopen(%s)", "serial");
  *len = fread(num, sizeof(unsigned int), 1, fp);
  if (*len != 1)
    err(1, "fread(serial): %d", *len);
  fclose(fp);
  p = malloc(sizeof(num));
  memcpy(p, num, (*len) * sizeof(unsigned int));
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_serial>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rsi
  lea    D21(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
L3:
  lea    0x4(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  mov    %rax,0x0(%rbp)
  cmp    $0x1,%rax
  jne    L40
L30:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%rdx
  shl    $0x2,%rdx
  lea    0x4(%rsp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  lea    D21(%rip),%rdx
  lea    D39(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <err@plt>
  jmp    L3
L40:
  mov    %rax,%rdx
  lea    D45(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <err@plt>
  jmp    L30
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type: string
name: disassemble_data
arguments: label: D21
type: string
name: disassemble_data
arguments: label: D39
type: string
name: disassemble_data
arguments: label: D45
type: string

tool: D27: r

tool: D21: serial

tool: D39: fopen(%s)

tool: D45: fread(serial): %d

assistant: ```c
unsigned int *get_serial(size_t *len) {
  FILE *fp;
  unsigned int num[1], *p;
  fp = fopen("serial", "r");
  if (fp == NULL)
    err(1, "fopen(%s)", "serial");
  *len = fread(num, sizeof(unsigned int), 1, fp);
  if (*len != 1)
    err(1, "fread(serial): %d", *len);
  fclose(fp);
  p = malloc(sizeof(num));
  memcpy(p, num, (*len) * sizeof(unsigned int));
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_serial>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L39
L15:
  lea    0x4(%rsp),%r13
  mov    $0x1,%edx
  mov    %rbp,%rcx
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  cmp    $0x1,%rax
  je     L2
  lea    D38(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <err@plt>
L2:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  shl    $0x2,%rdx
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L39:
  mov    %r12,%rdx
  lea    D35(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <err@plt>
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D38
datatype: string
name: unpack_data
arguments: label: D35
datatype: string

tool: D4: r

tool: D24: serial

tool: D38: fread(serial): %d

tool: D35: fopen(%s)

assistant: ```c
unsigned int *get_serial(size_t *len) {
  FILE *fp;
  unsigned int num[1], *p;
  fp = fopen("serial", "r");
  if (fp == NULL)
    err(1, "fopen(%s)", "serial");
  *len = fread(num, sizeof(unsigned int), 1, fp);
  if (*len != 1)
    err(1, "fread(serial): %d", *len);
  fclose(fp);
  p = malloc(sizeof(num));
  memcpy(p, num, (*len) * sizeof(unsigned int));
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_serial>:
  endbr64
  push   %r13
  lea    D12(%rip),%rsi
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
L26:
  lea    0x4(%rsp),%r13
  mov    $0x1,%edx
  mov    %rbp,%rcx
  mov    $0x4,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  cmp    $0x1,%rax
  je     L38
  lea    D28(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <err@plt>
L38:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  shl    $0x2,%rdx
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  mov    %r12,%rdx
  lea    D26(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <err@plt>
  jmp    L26
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string

tool: D12: r

tool: D18: serial

tool: D28: fread(serial): %d

tool: D26: fopen(%s)

assistant: ```c
unsigned int *get_serial(size_t *len) {
  FILE *fp;
  unsigned int num[1], *p;
  fp = fopen("serial", "r");
  if (fp == NULL)
    err(1, "fopen(%s)", "serial");
  *len = fread(num, sizeof(unsigned int), 1, fp);
  if (*len != 1)
    err(1, "fread(serial): %d", *len);
  fclose(fp);
  p = malloc(sizeof(num));
  memcpy(p, num, (*len) * sizeof(unsigned int));
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ec_gethostid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  call   <gethostid@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: H#%ld

assistant: ```c
int ec_gethostid(char *buf, int len) {
  (void)sprintf(buf, "H#%ld", gethostid());
  return strlen(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ec_gethostid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <gethostid@plt>
  mov    %eax,%edx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: H#%ld

assistant: ```c
int ec_gethostid(char *buf, int len) {
  (void)sprintf(buf, "H#%ld", gethostid());
  return strlen(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ec_gethostid>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <gethostid@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <strlen@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: H#%ld

assistant: ```c
int ec_gethostid(char *buf, int len) {
  (void)sprintf(buf, "H#%ld", gethostid());
  return strlen(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ec_gethostid>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <gethostid@plt>
  mov    %rbp,%rdi
  lea    D6(%rip),%rsi
  mov    %eax,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <strlen@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: H#%ld

assistant: ```c
int ec_gethostid(char *buf, int len) {
  (void)sprintf(buf, "H#%ld", gethostid());
  return strlen(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x696a,%ax
  xor    $0xb,%eax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L48
L42:
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %eax,%edx
  movzwl -0xc(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L48:
  cmpw   $0x0,-0xc(%rbp)
  je     L42
  movw   $0x0,-0xc(%rbp)
  jmp    L40
L26:
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xc(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addw   $0x2,-0xc(%rbp)
L40:
  cmpw   $0x0,-0xc(%rbp)
  je     L26
  movzwl -0xa(%rbp),%eax
  shr    $0x7,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] |= (state[local1] & (unsigned short)31) << 4UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x696a,%dx
  xor    $0xb,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
  mov    %eax,%edx
  movsbl %ah,%ecx
  mov    %al,%dh
  mov    %cl,%dl
  shr    $0x7,%dx
  mov    %dx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] |= (state[local1] & (unsigned short)31) << 4UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x696a,%dx
  xor    $0xb,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
  rol    $0x8,%ax
  shr    $0x7,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] |= (state[local1] & (unsigned short)31) << 4UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  add    $0x696a,%dx
  xor    $0xb,%edx
  mov    %edx,%eax
  shl    $0x4,%eax
  and    $0x1f0,%ax
  or     %edx,%eax
  rol    $0x8,%ax
  shr    $0x7,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] |= (state[local1] & (unsigned short)31) << 4UL;
      local1++;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      copy11 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy11;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] >> (unsigned short)7;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xfa00,%edi
  call   <fatorial@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D0: Executando Fatorial...

tool: D11: Fatorial: %d


assistant: ```c
int main() {
  printf("Executando Fatorial...\n");
  printf("Fatorial: %d\n", fatorial(64000));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0xfa00,%edi
  call   <fatorial@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D9: Executando Fatorial...

tool: D17: Fatorial: %d


assistant: ```c
int main() {
  printf("Executando Fatorial...\n");
  printf("Fatorial: %d\n", fatorial(64000));
  return 0;
}
```