ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x18(%rsp),%xmm0
  mulsd  D7(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: byte[8]

tool: {"D7": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double get_time() {
  struct timeval t;
  struct timezone tzp;
  gettimeofday(&t, &tzp);
  return t.tv_sec + (t.tv_usec * 1e-6);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x18(%rsp),%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: byte[8]

tool: {"D5": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double get_time() {
  struct timeval t;
  struct timezone tzp;
  gettimeofday(&t, &tzp);
  return t.tv_sec + (t.tv_usec * 1e-6);
}
```
user: What is the c source code of the assembly code below:

```asm
<brainfuck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <load@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  test   %rax,%rax
  jne    L11
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <run@plt>
  test   %rax,%rax
  je     L5
L11:
  movl   $0x1,-0xc(%rbp)
L5:
  cmpq   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int brainfuck(FILE *fin, const char *filename) {
  int status = 0;
  char *text = load(fin);
  if (fclose(fin) || run(text, filename))
    status = 1;
  if (text)
    free(text);
  return status;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<brainfuck>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <load@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x1,%ebx
  test   %rax,%rax
  je     L23
L20:
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <run@plt>
  test   %rax,%rax
  setne  %bl
  movzbl %bl,%ebx
  jmp    L20
```

assistant: ```c
int brainfuck(FILE *fin, const char *filename) {
  int status = 0;
  char *text = load(fin);
  if (fclose(fin) || run(text, filename))
    status = 1;
  if (text)
    free(text);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<brainfuck>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <load@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
  test   %rax,%rax
  je     L8
L22:
  test   %r12,%r12
  je     L21
  mov    %r12,%rdi
  call   <free@plt>
L21:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %r14d,%r14d
  call   <run@plt>
  test   %rax,%rax
  setne  %r14b
  jmp    L22
```

assistant: ```c
int brainfuck(FILE *fin, const char *filename) {
  int status = 0;
  char *text = load(fin);
  if (fclose(fin) || run(text, filename))
    status = 1;
  if (text)
    free(text);
  return status;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<brainfuck>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <load@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fclose@plt>
  test   %rax,%rax
  je     L20
L25:
  test   %r12,%r12
  je     L3
  mov    %r12,%rdi
  call   <free@plt>
L3:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %r14d,%r14d
  call   <run@plt>
  test   %rax,%rax
  setne  %r14b
  jmp    L25
```

assistant: ```c
int brainfuck(FILE *fin, const char *filename) {
  int status = 0;
  char *text = load(fin);
  if (fclose(fin) || run(text, filename))
    status = 1;
  if (text)
    free(text);
  return status;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L6
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D9: argv is %d


tool: D4: argc[%d] is %s


assistant: ```c
int main(int argv, char *argc[]) {
  printf("argv is %d\n", argv);
  int i;
  for (i = 0; i < argv; i++) {
    printf("argc[%d] is %s\n", i, argc[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L16
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L18:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D9: argv is %d


tool: D0: argc[%d] is %s


assistant: ```c
int main(int argv, char *argc[]) {
  printf("argv is %d\n", argv);
  int i;
  for (i = 0; i < argv; i++) {
    printf("argc[%d] is %s\n", i, argc[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D14(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L10
  xor    %ebx,%ebx
  lea    D5(%rip),%r13
  nopl   0x0(%rax)
L8:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L8
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D5
type: string

tool: D14: argv is %d


tool: D5: argc[%d] is %s


assistant: ```c
int main(int argv, char *argc[]) {
  printf("argv is %d\n", argv);
  int i;
  for (i = 0; i < argv; i++) {
    printf("argc[%d] is %s\n", i, argc[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D2(%rip),%rdi
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L14
  xor    %ebx,%ebx
  lea    D13(%rip),%r13
  nopl   0x0(%rax)
L6:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L6
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string

tool: D2: argv is %d


tool: D13: argc[%d] is %s


assistant: ```c
int main(int argv, char *argc[]) {
  printf("argv is %d\n", argv);
  int i;
  for (i = 0; i < argv; i++) {
    printf("argc[%d] is %s\n", i, argc[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  (void)WCHAR_MIN;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  (void)WCHAR_MIN;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  (void)WCHAR_MIN;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  (void)WCHAR_MIN;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_ld_feistel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <expansion_permutation@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <s_boxes@plt>
  mov    %eax,%edi
  call   <permutation@plt>
  leave
  ret
```

assistant: ```c
uint32_t _ld_feistel(uint32_t right, uint64_t round_key) {
  uint64_t expanded_right = 0;
  uint64_t e_xor_k = 0;
  uint8_t i;
  expanded_right = expansion_permutation(right);
  e_xor_k = expanded_right ^ round_key;
  return permutation(s_boxes(e_xor_k));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ld_feistel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <expansion_permutation@plt>
  xor    %ebx,%eax
  mov    %eax,%edi
  call   <s_boxes@plt>
  mov    %eax,%edi
  call   <permutation@plt>
  pop    %rbx
  ret
```

assistant: ```c
uint32_t _ld_feistel(uint32_t right, uint64_t round_key) {
  uint64_t expanded_right = 0;
  uint64_t e_xor_k = 0;
  uint8_t i;
  expanded_right = expansion_permutation(right);
  e_xor_k = expanded_right ^ round_key;
  return permutation(s_boxes(e_xor_k));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_ld_feistel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <expansion_permutation@plt>
  xor    %ebx,%eax
  mov    %eax,%edi
  call   <s_boxes@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <permutation@plt>
```

assistant: ```c
uint32_t _ld_feistel(uint32_t right, uint64_t round_key) {
  uint64_t expanded_right = 0;
  uint64_t e_xor_k = 0;
  uint8_t i;
  expanded_right = expansion_permutation(right);
  e_xor_k = expanded_right ^ round_key;
  return permutation(s_boxes(e_xor_k));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_ld_feistel>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <expansion_permutation@plt>
  xor    %ebx,%eax
  mov    %eax,%edi
  call   <s_boxes@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <permutation@plt>
```

assistant: ```c
uint32_t _ld_feistel(uint32_t right, uint64_t round_key) {
  uint64_t expanded_right = 0;
  uint64_t e_xor_k = 0;
  uint8_t i;
  expanded_right = expansion_permutation(right);
  e_xor_k = expanded_right ^ round_key;
  return permutation(s_boxes(e_xor_k));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cpu_stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L2:
  cli
  hlt
  jmp    L2
```

assistant: ```c
void cpu_stop(void) {
  for (;;)
    asm volatile("cli; hlt;" : : : "memory");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpu_stop>:
  endbr64
L1:
  cli
  hlt
  jmp    L1
```

assistant: ```c
void cpu_stop(void) {
  for (;;)
    asm volatile("cli; hlt;" : : : "memory");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cpu_stop>:
  endbr64
  nopl   0x0(%rax)
L4:
  cli
  hlt
  jmp    L4
```

assistant: ```c
void cpu_stop(void) {
  for (;;)
    asm volatile("cli; hlt;" : : : "memory");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_stop>:
  endbr64
  nopl   0x0(%rax)
L2:
  cli
  hlt
  jmp    L2
```

assistant: ```c
void cpu_stop(void) {
  for (;;)
    asm volatile("cli; hlt;" : : : "memory");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<saa7114_set_decoder_brightness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <saa7114_write_reg@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int saa7114_set_decoder_brightness(unsigned char brightness) {
  saa7114_write_reg(0x0A, brightness);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<saa7114_set_decoder_brightness>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%esi
  mov    $0xa,%edi
  call   <saa7114_write_reg@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int saa7114_set_decoder_brightness(unsigned char brightness) {
  saa7114_write_reg(0x0A, brightness);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<saa7114_set_decoder_brightness>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%esi
  mov    $0xa,%edi
  call   <saa7114_write_reg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int saa7114_set_decoder_brightness(unsigned char brightness) {
  saa7114_write_reg(0x0A, brightness);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<saa7114_set_decoder_brightness>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%esi
  mov    $0xa,%edi
  call   <saa7114_write_reg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int saa7114_set_decoder_brightness(unsigned char brightness) {
  saa7114_write_reg(0x0A, brightness);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  (void)fd;
  (void)buf;
  (void)nbytes;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_write>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  (void)fd;
  (void)buf;
  (void)nbytes;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_write>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  (void)fd;
  (void)buf;
  (void)nbytes;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_write>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int _write(int fd, char *buf, int nbytes) {
  (void)fd;
  (void)buf;
  (void)nbytes;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clear_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void clear_bitmap(unsigned char **pixels, int w, int h) {
  int y;
  for (y = 0; y < h; y++)
    memset(pixels[y], 0, w);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rdi,%rax,8),%r12
L18:
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    (%rbx),%rdi
  call   <memset@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  ret
```

assistant: ```c
void clear_bitmap(unsigned char **pixels, int w, int h) {
  int y;
  for (y = 0; y < h; y++)
    memset(pixels[y], 0, w);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clear_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%rdi
  mov    %ebp,%edx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void clear_bitmap(unsigned char **pixels, int w, int h) {
  int y;
  for (y = 0; y < h; y++)
    memset(pixels[y], 0, w);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clear_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L15
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%rdi
  mov    %ebp,%edx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void clear_bitmap(unsigned char **pixels, int w, int h) {
  int y;
  for (y = 0; y < h; y++)
    memset(pixels[y], 0, w);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<block_variance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L2
L21:
  mov    -0x18(%rbp),%eax
  imul   -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L78
L76:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
L78:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L76
  addl   $0x1,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L21
  mov    -0x30(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L65
L59:
  mov    -0x18(%rbp),%eax
  imul   -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L35
L50:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L35:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L50
  addl   $0x1,-0x18(%rbp)
L65:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L59
  mov    -0x30(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  div    %esi
  pop    %rbp
  ret
```

assistant: ```c
unsigned int block_variance(int *in, int w, int h, int pitch) {
  int i, j;
  unsigned int avg, var;
  int dif;
  int *ino;
  avg = 0;
  for (j = 0; j < h; j++) {
    ino = in + j * pitch;
    for (i = 0; i < w; i++) {
      avg += ino[i];
    }
  }
  avg /= (h * w);
  var = 0;
  for (j = 0; j < h; j++) {
    ino = in + j * pitch;
    for (i = 0; i < w; i++) {
      dif = ino[i] - avg;
      var = var + (dif * dif);
    }
  }
  return var / (h * w);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<block_variance>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  mov    %edx,%esi
  test   %edx,%edx
  jle    L98
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%r11
  lea    -0x1(%r10),%ebp
  lea    0x4(%rdi,%rbp,4),%rdi
  neg    %rbp
  shl    $0x2,%rbp
  mov    %rdi,%rcx
  mov    $0x0,%eax
  mov    $0x0,%r9d
  lea    -0x4(%rbp),%r8
  jmp    L74
L52:
  mov    %edx,%r9d
L74:
  test   %r10d,%r10d
  jle    L67
  lea    (%r8,%rcx,1),%rdx
L72:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L72
L67:
  lea    0x1(%r9),%edx
  add    %r11,%rcx
  cmp    %edx,%esi
  jne    L52
  mov    %edx,%ebx
  imul   %r10d,%ebx
  mov    $0x0,%edx
  div    %ebx
  mov    $0x0,%esi
  mov    $0x0,%r8d
  sub    $0x4,%rbp
  jmp    L96
L24:
  mov    %edx,%r8d
L96:
  test   %r10d,%r10d
  jle    L2
  lea    0x0(%rbp,%rdi,1),%rcx
L3:
  mov    (%rcx),%edx
  sub    %eax,%edx
  imul   %edx,%edx
  add    %edx,%esi
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L3
L2:
  lea    0x1(%r8),%edx
  add    %r11,%rdi
  cmp    %r8d,%r9d
  jne    L24
L42:
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ebx
  pop    %rbx
  pop    %rbp
  ret
L98:
  mov    %edx,%ebx
  imul   %r10d,%ebx
  mov    $0x0,%esi
  jmp    L42
```

assistant: ```c
unsigned int block_variance(int *in, int w, int h, int pitch) {
  int i, j;
  unsigned int avg, var;
  int dif;
  int *ino;
  avg = 0;
  for (j = 0; j < h; j++) {
    ino = in + j * pitch;
    for (i = 0; i < w; i++) {
      avg += ino[i];
    }
  }
  avg /= (h * w);
  var = 0;
  for (j = 0; j < h; j++) {
    ino = in + j * pitch;
    for (i = 0; i < w; i++) {
      dif = ino[i] - avg;
      var = var + (dif * dif);
    }
  }
  return var / (h * w);
}
```