ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L13:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  imul   -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  long sum = 42;
  int ascii = 0;
  for (int i = 0; i < strlen(word); i++) {
    ascii = word[i];
    sum += (ascii * (i + 1));
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x2a,%r12d
  jmp    L9
L14:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
  add    $0x1,%rbx
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L14
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long sum = 42;
  int ascii = 0;
  for (int i = 0; i < strlen(word); i++) {
    ascii = word[i];
    sum += (ascii * (i + 1));
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L0
  nopl   (%rax)
L3:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long sum = 42;
  int ascii = 0;
  for (int i = 0; i < strlen(word); i++) {
    ascii = word[i];
    sum += (ascii * (i + 1));
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L6
  nopl   (%rax)
L0:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L6:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long sum = 42;
  int ascii = 0;
  for (int i = 0; i < strlen(word); i++) {
    ascii = word[i];
    sum += (ascii * (i + 1));
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L36
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L37
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L37
  addq   $0x1,-0x8(%rbp)
L37:
  subq   $0x1,-0x20(%rbp)
  addq   $0x8,-0x18(%rbp)
L36:
  cmpq   $0x2,-0x20(%rbp)
  jg     L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long vall(const long *w, long len) {
  long acc = 0;
  for (; len > 2; len--, w++) {
    if (*w > *(w + 1) && *(w + 1) < *(w + 2))
      acc++;
  }
  return acc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vall>:
  endbr64
  cmp    $0x2,%rsi
  jle    L47
  mov    $0x0,%edx
  jmp    L43
L4:
  sub    $0x1,%rsi
  add    $0x8,%rdi
  cmp    $0x2,%rsi
  je     L41
L43:
  mov    0x8(%rdi),%rax
  cmp    %rax,(%rdi)
  jle    L4
  cmp    0x10(%rdi),%rax
  setl   %al
  movzbl %al,%eax
  add    %rax,%rdx
  jmp    L4
L47:
  mov    $0x0,%edx
L41:
  mov    %rdx,%rax
  ret
```

assistant: ```c
long vall(const long *w, long len) {
  long acc = 0;
  for (; len > 2; len--, w++) {
    if (*w > *(w + 1) && *(w + 1) < *(w + 2))
      acc++;
  }
  return acc;
}
```
user: What is the c source code of the assembly code below?

```asm
<vall>:
  endbr64
  cmp    $0x2,%rsi
  jle    L26
  mov    (%rdi),%rdx
  sub    $0x2,%rsi
  xor    %eax,%eax
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %rdx,%rcx
  mov    0x8(%rdi,%rax,8),%rdx
  cmp    %rcx,%rdx
  jge    L29
  cmp    0x10(%rdi,%rax,8),%rdx
  jge    L29
  add    $0x1,%r8
L29:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L6
  mov    %r8,%rax
  ret
  nopl   (%rax)
L26:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long vall(const long *w, long len) {
  long acc = 0;
  for (; len > 2; len--, w++) {
    if (*w > *(w + 1) && *(w + 1) < *(w + 2))
      acc++;
  }
  return acc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vall>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x2,%rsi
  jle    L2
  nopl   (%rax)
L0:
  mov    0x8(%rdi),%rax
  cmp    %rax,(%rdi)
  jle    L24
  cmp    0x10(%rdi),%rax
  setl   %al
  movzbl %al,%eax
  add    %rax,%r8
L24:
  sub    $0x1,%rsi
  add    $0x8,%rdi
  cmp    $0x2,%rsi
  jne    L0
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
long vall(const long *w, long len) {
  long acc = 0;
  for (; len > 2; len--, w++) {
    if (*w > *(w + 1) && *(w + 1) < *(w + 2))
      acc++;
  }
  return acc;
}
```
user: What is the c source code of the assembly code below:

```asm
<readintparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L3:
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x14(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D13: r

tool: D3: Error '%s'

tool: D16: %i


assistant: ```c
int readintparam(char *fname) {
  int num;
  int pr;
  FILE *tmp;
  tmp = fopen(fname, "r");
  if (tmp == NULL) {
    printf("Error '%s'", tmp);
    return;
  }
  fscanf(tmp, "%i\n", &pr);
  fclose(tmp);
  return pr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readintparam>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L23
  mov    %rax,%rbx
  lea    0x4(%rsp),%rdx
  lea    D27(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L23:
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D27
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D3: r

tool: D27: %i


tool: D0: Error '%s'

assistant: ```c
int readintparam(char *fname) {
  int num;
  int pr;
  FILE *tmp;
  tmp = fopen(fname, "r");
  if (tmp == NULL) {
    printf("Error '%s'", tmp);
    return;
  }
  fscanf(tmp, "%i\n", &pr);
  fclose(tmp);
  return pr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readintparam>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdx
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %esi,%esi
  lea    D12(%rip),%rdi
  pop    %rbp
  jmp    10b0 <printf@plt>
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D2: r

tool: D25: %i


tool: D12: Error '%s'

assistant: ```c
int readintparam(char *fname) {
  int num;
  int pr;
  FILE *tmp;
  tmp = fopen(fname, "r");
  if (tmp == NULL) {
    printf("Error '%s'", tmp);
    return;
  }
  fscanf(tmp, "%i\n", &pr);
  fclose(tmp);
  return pr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readintparam>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdx
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  pop    %rbp
  jmp    10b0 <printf@plt>
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string

tool: D23: r

tool: D12: %i


tool: D0: Error '%s'

assistant: ```c
int readintparam(char *fname) {
  int num;
  int pr;
  FILE *tmp;
  tmp = fopen(fname, "r");
  if (tmp == NULL) {
    printf("Error '%s'", tmp);
    return;
  }
  fscanf(tmp, "%i\n", &pr);
  fclose(tmp);
  return pr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quantise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  movq   $0x0,-0x10(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L8:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L43:
  mov    -0x34(%rbp),%eax
  cltq
  imul   -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movsd  D11(%rip),%xmm0
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x1c(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L43
  movss  -0x18(%rbp),%xmm0
  comiss -0x1c(%rbp),%xmm0
  jbe    L23
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L23:
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x38(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jl     L8
  mov    -0x40(%rbp),%rax
  movss  (%rax),%xmm0
  addss  -0x18(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: f32
name: retrieve_data
arguments: data_label: D11
type: f64

tool: D0: 1e+32

tool: D11: 2

assistant: ```c
long quantise(float cb[], float vec[], int k, int m, float *se) {
  float e;
  long besti;
  float beste;
  long j;
  int i;
  besti = 0;
  beste = 1E32;
  for (j = 0; j < m; j++) {
    e = 0.0;
    for (i = 0; i < k; i++)
      e += pow(cb[j * k + i] - vec[i], 2.0);
    if (e < beste) {
      beste = e;
      besti = j;
    }
  }
  *se += beste;
  return (besti);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quantise>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %r8,0x28(%rsp)
  movslq %ecx,%rax
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  jle    L46
  mov    %edx,%r14d
  mov    $0x0,%r13d
  movss  D28(%rip),%xmm6
  movss  %xmm6,0xc(%rsp)
  mov    $0x0,%r15d
  jmp    L38
L46:
  movss  D28(%rip),%xmm6
  movss  %xmm6,0xc(%rsp)
  mov    $0x0,%r15d
L15:
  mov    0x28(%rsp),%rax
  movss  0xc(%rsp),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  mov    %r15,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  movslq %r14d,%rax
  imul   %r13,%rax
  mov    0x18(%rsp),%rcx
  lea    (%rcx,%rax,4),%rbx
  mov    0x20(%rsp),%rbp
  lea    -0x1(%r14),%edx
  add    %rdx,%rax
  lea    0x4(%rcx,%rax,4),%r12
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x8(%rsp)
L8:
  movss  (%rbx),%xmm0
  subss  0x0(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x8(%rsp),%xmm0
  movss  %xmm0,0x8(%rsp)
  add    $0x4,%rbx
  add    $0x4,%rbp
  cmp    %r12,%rbx
  jne    L8
L35:
  movss  0xc(%rsp),%xmm4
  movss  0x8(%rsp),%xmm3
  comiss %xmm3,%xmm4
  minss  %xmm4,%xmm3
  movss  %xmm3,0xc(%rsp)
  cmova  %r13,%r15
  add    $0x1,%r13
  cmp    0x10(%rsp),%r13
  jge    L15
L38:
  test   %r14d,%r14d
  jg     L26
  pxor   %xmm7,%xmm7
  movss  %xmm7,0x8(%rsp)
  jmp    L35
```

tool_calls: name: disassemble_data
arguments: tag: D28
data_type: f32
name: disassemble_data
arguments: tag: D3
data_type: f64

tool: D28: 1e+32

tool: D3: 2

assistant: ```c
long quantise(float cb[], float vec[], int k, int m, float *se) {
  float e;
  long besti;
  float beste;
  long j;
  int i;
  besti = 0;
  beste = 1E32;
  for (j = 0; j < m; j++) {
    e = 0.0;
    for (i = 0; i < k; i++)
      e += pow(cb[j * k + i] - vec[i], 2.0);
    if (e < beste) {
      beste = e;
      besti = j;
    }
  }
  *se += beste;
  return (besti);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quantise>:
  endbr64
  push   %r15
  movslq %ecx,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %r8,0x28(%rsp)
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  jle    L14
  movss  D20(%rip),%xmm4
  mov    %edx,%r12d
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  movss  %xmm4,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L13:
  pxor   %xmm2,%xmm2
  test   %r12d,%r12d
  jle    L23
  movslq %r12d,%rax
  mov    0x18(%rsp),%rdx
  lea    -0x1(%r12),%esi
  mov    0x20(%rsp),%r15
  imul   %rbp,%rax
  pxor   %xmm2,%xmm2
  lea    (%rdx,%rax,4),%r14
  add    %rsi,%rax
  lea    0x4(%rdx,%rax,4),%rbx
  nop
L25:
  movss  (%r14),%xmm0
  mov    D15(%rip),%rax
  add    $0x4,%r14
  add    $0x4,%r15
  subss  -0x4(%r15),%xmm0
  movss  %xmm2,0x8(%rsp)
  movq   %rax,%xmm1
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm2
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm2
  cmp    %rbx,%r14
  jne    L25
L23:
  movss  0xc(%rsp),%xmm3
  comiss %xmm2,%xmm3
  minss  %xmm3,%xmm2
  cmova  %rbp,%r13
  movss  %xmm2,0xc(%rsp)
  add    $0x1,%rbp
  cmp    0x10(%rsp),%rbp
  jl     L13
L26:
  mov    0x28(%rsp),%rax
  movss  0xc(%rsp),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  movss  D20(%rip),%xmm5
  xor    %r13d,%r13d
  movss  %xmm5,0xc(%rsp)
  jmp    L26
```

tool_calls: name: read_data
arguments: tag: D20
type: f32
name: read_data
arguments: tag: D15
type: f64

tool: D20: 1e+32

tool: D15: 2

assistant: ```c
long quantise(float cb[], float vec[], int k, int m, float *se) {
  float e;
  long besti;
  float beste;
  long j;
  int i;
  besti = 0;
  beste = 1E32;
  for (j = 0; j < m; j++) {
    e = 0.0;
    for (i = 0; i < k; i++)
      e += pow(cb[j * k + i] - vec[i], 2.0);
    if (e < beste) {
      beste = e;
      besti = j;
    }
  }
  *se += beste;
  return (besti);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quantise>:
  endbr64
  push   %r15
  movslq %ecx,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %r8,0x28(%rsp)
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  jle    L11
  movss  D2(%rip),%xmm4
  mov    %edx,%r12d
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  movss  %xmm4,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L13:
  pxor   %xmm2,%xmm2
  test   %r12d,%r12d
  jle    L28
  movslq %r12d,%rax
  mov    0x18(%rsp),%rdx
  lea    -0x1(%r12),%esi
  mov    0x20(%rsp),%r15
  imul   %rbp,%rax
  pxor   %xmm2,%xmm2
  lea    (%rdx,%rax,4),%r14
  add    %rsi,%rax
  lea    0x4(%rdx,%rax,4),%rbx
  nop
L3:
  movss  (%r14),%xmm0
  mov    D23(%rip),%rax
  add    $0x4,%r14
  add    $0x4,%r15
  subss  -0x4(%r15),%xmm0
  movss  %xmm2,0x8(%rsp)
  movq   %rax,%xmm1
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movss  0x8(%rsp),%xmm2
  cvtsi2ss %rax,%xmm0
  addss  %xmm0,%xmm2
  cmp    %r14,%rbx
  jne    L3
L28:
  movss  0xc(%rsp),%xmm3
  comiss %xmm2,%xmm3
  minss  %xmm3,%xmm2
  cmova  %rbp,%r13
  movss  %xmm2,0xc(%rsp)
  add    $0x1,%rbp
  cmp    0x10(%rsp),%rbp
  jl     L13
  movaps %xmm2,%xmm0
L5:
  mov    0x28(%rsp),%rax
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  add    $0x38,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  movss  D2(%rip),%xmm5
  xor    %r13d,%r13d
  movss  %xmm5,0xc(%rsp)
  movaps %xmm5,%xmm0
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: f32
name: unpack_data
arguments: data_label: D23
datatype: f64

tool: D2: 1e+32

tool: D23: 2

assistant: ```c
long quantise(float cb[], float vec[], int k, int m, float *se) {
  float e;
  long besti;
  float beste;
  long j;
  int i;
  besti = 0;
  beste = 1E32;
  for (j = 0; j < m; j++) {
    e = 0.0;
    for (i = 0; i < k; i++)
      e += pow(cb[j * k + i] - vec[i], 2.0);
    if (e < beste) {
      beste = e;
      besti = j;
    }
  }
  *se += beste;
  return (besti);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  jg     L73
  mov    $0xffffffff,%eax
  jmp    L9
L73:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L9
L8:
  movl   $0x0,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L22
L31:
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%r8d
  movzbl -0xa(%rbp),%eax
  movzbl %al,%edi
  movzbl -0xb(%rbp),%eax
  movzbl %al,%ecx
  movzbl -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,-0x20(%rbp)
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L31
  jmp    L2
L72:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L72
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string

tool: D11: rb

tool: D27: write %x %02X%02X%02X%02X


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    return -1;
  FILE *f = fopen(argv[1], "rb");
  if (!f)
    return -1;
  unsigned char x[4];
  int i = 0;
  int n = atoi(argv[2]);
  while (!feof(f)) {
    fread(x, 1, 4, f);
    printf("write %x %02X%02X%02X%02X\n", i++, x[0], x[1], x[2], x[3]);
  }
  for (; i < n;) {
    printf("write %x %02X%02X%02X%02X\n", i++, 0, 0, 0, 0);
  }
  fclose(f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L40
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  lea    D22(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L81
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    $0x0,%ebx
  lea    D28(%rip),%r14
  jmp    L46
L19:
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  lea    0x1(%rbx),%r12d
  movzbl 0x5(%rsp),%ecx
  movzbl 0x4(%rsp),%edx
  movzbl 0x7(%rsp),%r9d
  movzbl 0x6(%rsp),%r8d
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12d,%ebx
L46:
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L19
  cmp    %r13d,%ebx
  jge    L76
  lea    D28(%rip),%r12
L36:
  mov    %ebx,%esi
  add    $0x1,%ebx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebx,%r13d
  jne    L36
L76:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L66:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  mov    $0xffffffff,%eax
  jmp    L66
L81:
  mov    $0xffffffff,%eax
  jmp    L66
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_infered: string
name: extract_symbolic_data
arguments: data_label: D28
type_infered: string

tool: D22: rb

tool: D28: write %x %02X%02X%02X%02X


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 3)
    return -1;
  FILE *f = fopen(argv[1], "rb");
  if (!f)
    return -1;
  unsigned char x[4];
  int i = 0;
  int n = atoi(argv[2]);
  while (!feof(f)) {
    fread(x, 1, 4, f);
    printf("write %x %02X%02X%02X%02X\n", i++, x[0], x[1], x[2], x[3]);
  }
  for (; i < n;) {
    printf("write %x %02X%02X%02X%02X\n", i++, 0, 0, 0, 0);
  }
  fclose(f);
  return 0;
}
```