ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply264>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L82
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L71:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L76
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L76
  nopl   0x0(%rax)
L3:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L3
  cmp    -0x24(%rsp),%r11d
  je     L61
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L61
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L61
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L61:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L71
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L93:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L93
  mov    -0x18(%rsp),%r8
  jmp    L61
```

assistant: ```c
void multiply264(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<LU_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L77
L70:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L79:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L23
L66:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L34
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L7
L34:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L7:
  addl   $0x1,-0x14(%rbp)
L23:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jle    L66
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L79
  addl   $0x1,-0x1c(%rbp)
L77:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L70
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **LU_product(double **matrix, int n) {
  double **B = (double **)malloc(sizeof(double *) * n);
  int i = 0;
  int j = 0;
  int k = 0;
  double temp;
  for (i = 0; i < n; i++) {
    B[i] = (double *)malloc(sizeof(double) * n);
    for (j = 0; j < n; j++) {
      temp = 0;
      for (k = 0; k <= (i < j ? i : j); k++) {
        if (i == k) {
          temp += 1 * matrix[k][j];
        } else {
          temp += matrix[i][k] * matrix[k][j];
        }
      }
      B[i][j] = temp;
    }
  }
  return B;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LU_product>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  lea    0x0(,%rsi,8),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r13d,%r13d
  jle    L25
  mov    %rbp,%r12
  mov    $0x0,%ebx
  mov    %rax,%r15
  sub    %rbp,%r15
  jmp    L86
L54:
  mov    0x0(%rbp,%rax,8),%rcx
  addsd  (%rcx,%rdx,1),%xmm1
L91:
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L31
L21:
  cmp    %eax,%ebx
  je     L54
  mov    (%r12),%rsi
  mov    0x0(%rbp,%rax,8),%rcx
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rdx,1),%xmm0
  addsd  %xmm0,%xmm1
  jmp    L91
L31:
  mov    (%r9),%rax
  movsd  %xmm1,(%rax,%rdx,1)
  lea    0x1(%r8),%eax
  add    $0x8,%rdx
  cmp    %eax,%r13d
  je     L18
  mov    %eax,%r8d
L41:
  cmp    %r8d,%ebx
  mov    %r8d,%eax
  cmovle %ebx,%eax
  pxor   %xmm1,%xmm1
  test   %eax,%eax
  js     L31
  lea    0x1(%rax),%edi
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  jmp    L21
L18:
  lea    0x1(%rbx),%eax
  add    $0x8,%r12
  cmp    %r8d,%ebx
  je     L25
  mov    %eax,%ebx
L86:
  mov    %r14d,%edi
  call   <malloc@plt>
  lea    (%r15,%r12,1),%r9
  mov    %rax,(%r9)
  mov    $0x0,%edx
  mov    $0x0,%r8d
  jmp    L41
L25:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **LU_product(double **matrix, int n) {
  double **B = (double **)malloc(sizeof(double *) * n);
  int i = 0;
  int j = 0;
  int k = 0;
  double temp;
  for (i = 0; i < n; i++) {
    B[i] = (double *)malloc(sizeof(double) * n);
    for (j = 0; j < n; j++) {
      temp = 0;
      for (k = 0; k <= (i < j ? i : j); k++) {
        if (i == k) {
          temp += 1 * matrix[k][j];
        } else {
          temp += matrix[i][k] * matrix[k][j];
        }
      }
      B[i][j] = temp;
    }
  }
  return B;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LU_product>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  lea    0x0(,%rsi,8),%ebx
  mov    %ebx,%edi
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L2
  sub    %r14,%rax
  mov    %r14,%r15
  xor    %r13d,%r13d
  mov    %rax,%rbp
L25:
  mov    %ebx,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  pxor   %xmm2,%xmm2
  mov    %rax,0x0(%rbp,%r15,1)
  mov    %rax,%r9
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    %edi,%r13d
  mov    %edi,%ecx
  movapd %xmm2,%xmm1
  cmovle %r13d,%ecx
  xor    %eax,%eax
  add    $0x1,%ecx
  movslq %ecx,%rcx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L77:
  mov    (%r15),%r10
  movsd  (%r10,%rax,8),%xmm0
  mulsd  (%rdx,%rsi,1),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  je     L16
L28:
  mov    (%r14,%rax,8),%rdx
  cmp    %eax,%r13d
  jne    L77
  add    $0x1,%rax
  addsd  (%rdx,%rsi,1),%xmm1
  cmp    %rax,%rcx
  jne    L28
L16:
  lea    0x1(%rdi),%eax
  movsd  %xmm1,(%r9,%rsi,1)
  add    $0x8,%rsi
  cmp    %eax,%r12d
  je     L72
  mov    %eax,%edi
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L72:
  lea    0x1(%r13),%eax
  add    $0x8,%r15
  cmp    %edi,%r13d
  je     L2
  mov    %eax,%r13d
  jmp    L25
L2:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **LU_product(double **matrix, int n) {
  double **B = (double **)malloc(sizeof(double *) * n);
  int i = 0;
  int j = 0;
  int k = 0;
  double temp;
  for (i = 0; i < n; i++) {
    B[i] = (double *)malloc(sizeof(double) * n);
    for (j = 0; j < n; j++) {
      temp = 0;
      for (k = 0; k <= (i < j ? i : j); k++) {
        if (i == k) {
          temp += 1 * matrix[k][j];
        } else {
          temp += matrix[i][k] * matrix[k][j];
        }
      }
      B[i][j] = temp;
    }
  }
  return B;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LU_product>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  lea    0x0(,%rsi,8),%ebx
  mov    %ebx,%edi
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  jle    L7
  sub    %r14,%rax
  mov    %r14,%r15
  xor    %r13d,%r13d
  mov    %rax,%rbp
L61:
  mov    %ebx,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  pxor   %xmm2,%xmm2
  mov    %rax,0x0(%rbp,%r15,1)
  mov    %rax,%r9
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %edi,%r13d
  mov    %edi,%ecx
  movapd %xmm2,%xmm1
  cmovle %r13d,%ecx
  xor    %eax,%eax
  add    $0x1,%ecx
  movslq %ecx,%rcx
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L45:
  mov    (%r15),%r10
  movsd  (%r10,%rax,8),%xmm0
  mulsd  (%rdx,%rsi,1),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  je     L22
L59:
  mov    (%r14,%rax,8),%rdx
  cmp    %eax,%r13d
  jne    L45
  add    $0x1,%rax
  addsd  (%rdx,%rsi,1),%xmm1
  cmp    %rax,%rcx
  jne    L59
L22:
  lea    0x1(%rdi),%eax
  movsd  %xmm1,(%r9,%rsi,1)
  add    $0x8,%rsi
  cmp    %eax,%r12d
  je     L42
  mov    %eax,%edi
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L42:
  lea    0x1(%r13),%eax
  add    $0x8,%r15
  cmp    %edi,%r13d
  je     L7
  mov    %eax,%r13d
  jmp    L61
L7:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **LU_product(double **matrix, int n) {
  double **B = (double **)malloc(sizeof(double *) * n);
  int i = 0;
  int j = 0;
  int k = 0;
  double temp;
  for (i = 0; i < n; i++) {
    B[i] = (double *)malloc(sizeof(double) * n);
    for (j = 0; j < n; j++) {
      temp = 0;
      for (k = 0; k <= (i < j ? i : j); k++) {
        if (i == k) {
          temp += 1 * matrix[k][j];
        } else {
          temp += matrix[i][k] * matrix[k][j];
        }
      }
      B[i][j] = temp;
    }
  }
  return B;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Sys_PutChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <errnoThrow@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <errnoThrow@plt>
  nop
  leave
  ret
```

assistant: ```c
void Sys_PutChar(unsigned c) {
  unsigned ret;
  ret = putchar(c);
  errnoThrow(ret != c);
  ret = fflush(stdout);
  errnoThrow(ret != 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Sys_PutChar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <putchar@plt>
  cmp    %eax,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <errnoThrow@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  test   %eax,%eax
  setne  %dil
  movzbl %dil,%edi
  call   <errnoThrow@plt>
  pop    %rbx
  ret
```

assistant: ```c
void Sys_PutChar(unsigned c) {
  unsigned ret;
  ret = putchar(c);
  errnoThrow(ret != c);
  ret = fflush(stdout);
  errnoThrow(ret != 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Sys_PutChar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <putchar@plt>
  xor    %edi,%edi
  cmp    %eax,%ebx
  setne  %dil
  call   <errnoThrow@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  xor    %edi,%edi
  pop    %rbx
  test   %eax,%eax
  setne  %dil
  jmp    1090 <errnoThrow@plt>
```

assistant: ```c
void Sys_PutChar(unsigned c) {
  unsigned ret;
  ret = putchar(c);
  errnoThrow(ret != c);
  ret = fflush(stdout);
  errnoThrow(ret != 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Sys_PutChar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <putchar@plt>
  xor    %edi,%edi
  cmp    %eax,%ebx
  setne  %dil
  call   <errnoThrow@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  xor    %edi,%edi
  pop    %rbx
  test   %eax,%eax
  setne  %dil
  jmp    1090 <errnoThrow@plt>
```

assistant: ```c
void Sys_PutChar(unsigned c) {
  unsigned ret;
  ret = putchar(c);
  errnoThrow(ret != c);
  ret = fflush(stdout);
  errnoThrow(ret != 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_block_number_in_tweak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  shr    $0x28,%rax
  and    $0xf,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x20,%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1c(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x24(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x28(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x2c(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_block_number_in_tweak(uint8_t *tweak, const uint64_t block_no) {
  tweak[6] = (tweak[6] & 0xf0) ^ ((block_no >> 40ULL) & 0x0f);
  tweak[7] = ((block_no >> 32ULL) & 0xff);
  tweak[8] = ((block_no >> 24ULL) & 0xff);
  tweak[9] = ((block_no >> 16ULL) & 0xff);
  tweak[10] = ((block_no >> 8ULL) & 0xff);
  tweak[11] = ((block_no >> 0ULL) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_block_number_in_tweak>:
  endbr64
  mov    %rsi,%rax
  mov    0x18(%rdi),%edx
  and    $0xf0,%edx
  mov    %rsi,%rcx
  shr    $0x28,%rcx
  and    $0xf,%ecx
  or     %ecx,%edx
  mov    %edx,0x18(%rdi)
  mov    %rsi,%rdx
  shr    $0x20,%rdx
  and    $0xff,%edx
  mov    %edx,0x1c(%rdi)
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %edx,0x20(%rdi)
  mov    %rsi,%rdx
  shr    $0x10,%rdx
  and    $0xff,%edx
  mov    %edx,0x24(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x28(%rdi)
  and    $0xff,%eax
  mov    %eax,0x2c(%rdi)
  ret
```

assistant: ```c
void set_block_number_in_tweak(uint8_t *tweak, const uint64_t block_no) {
  tweak[6] = (tweak[6] & 0xf0) ^ ((block_no >> 40ULL) & 0x0f);
  tweak[7] = ((block_no >> 32ULL) & 0xff);
  tweak[8] = ((block_no >> 24ULL) & 0xff);
  tweak[9] = ((block_no >> 16ULL) & 0xff);
  tweak[10] = ((block_no >> 8ULL) & 0xff);
  tweak[11] = ((block_no >> 0ULL) & 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_block_number_in_tweak>:
  endbr64
  mov    0x18(%rdi),%edx
  mov    %rsi,%rcx
  mov    %rsi,%rax
  shr    $0x28,%rcx
  and    $0xf0,%edx
  and    $0xf,%ecx
  or     %ecx,%edx
  mov    %edx,0x18(%rdi)
  mov    %rsi,%rdx
  shr    $0x20,%rdx
  and    $0xff,%edx
  mov    %edx,0x1c(%rdi)
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %edx,0x20(%rdi)
  mov    %rsi,%rdx
  shr    $0x10,%rdx
  and    $0xff,%edx
  mov    %edx,0x24(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x28(%rdi)
  mov    %eax,0x2c(%rdi)
  ret
```

assistant: ```c
void set_block_number_in_tweak(uint8_t *tweak, const uint64_t block_no) {
  tweak[6] = (tweak[6] & 0xf0) ^ ((block_no >> 40ULL) & 0x0f);
  tweak[7] = ((block_no >> 32ULL) & 0xff);
  tweak[8] = ((block_no >> 24ULL) & 0xff);
  tweak[9] = ((block_no >> 16ULL) & 0xff);
  tweak[10] = ((block_no >> 8ULL) & 0xff);
  tweak[11] = ((block_no >> 0ULL) & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_block_number_in_tweak>:
  endbr64
  mov    0x18(%rdi),%edx
  mov    %rsi,%rax
  shr    $0x28,%rsi
  mov    %rdi,%rcx
  and    $0xf,%esi
  mov    %eax,%edi
  and    $0xf0,%edx
  shr    $0x18,%edi
  or     %esi,%edx
  mov    %rax,%rsi
  movd   %edi,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdx
  shr    $0x10,%rsi
  shr    $0x20,%rdx
  movzbl %sil,%esi
  movzbl %dl,%edx
  movd   %esi,%xmm2
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  movzbl %ah,%edx
  and    $0xff,%eax
  punpckldq %xmm3,%xmm0
  mov    %edx,0x28(%rcx)
  punpcklqdq %xmm1,%xmm0
  mov    %eax,0x2c(%rcx)
  movups %xmm0,0x18(%rcx)
  ret
```

assistant: ```c
void set_block_number_in_tweak(uint8_t *tweak, const uint64_t block_no) {
  tweak[6] = (tweak[6] & 0xf0) ^ ((block_no >> 40ULL) & 0x0f);
  tweak[7] = ((block_no >> 32ULL) & 0xff);
  tweak[8] = ((block_no >> 24ULL) & 0xff);
  tweak[9] = ((block_no >> 16ULL) & 0xff);
  tweak[10] = ((block_no >> 8ULL) & 0xff);
  tweak[11] = ((block_no >> 0ULL) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_exist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: r

assistant: ```c
int path_exist(char *path) {
  FILE *file;
  int retval = 0;
  file = fopen(path, "r");
  retval = (file != NULL);
  fclose(file);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<path_exist>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <fclose@plt>
  test   %rbx,%rbx
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: r

assistant: ```c
int path_exist(char *path) {
  FILE *file;
  int retval = 0;
  file = fopen(path, "r");
  retval = (file != NULL);
  fclose(file);
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<path_exist>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: r

assistant: ```c
int path_exist(char *path) {
  FILE *file;
  int retval = 0;
  file = fopen(path, "r");
  retval = (file != NULL);
  fclose(file);
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<path_exist>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  setne  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: r

assistant: ```c
int path_exist(char *path) {
  FILE *file;
  int retval = 0;
  file = fopen(path, "r");
  retval = (file != NULL);
  fclose(file);
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<be_openssl_readcb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <consider_reading@plt>
  nop
  leave
  ret
```

assistant: ```c
void be_openssl_readcb(struct bufferevent *bev_base, void *ctx) {
  struct bufferevent_openssl *bev_ssl = ctx;
  consider_reading(bev_ssl);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<be_openssl_readcb>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <consider_reading@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void be_openssl_readcb(struct bufferevent *bev_base, void *ctx) {
  struct bufferevent_openssl *bev_ssl = ctx;
  consider_reading(bev_ssl);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<be_openssl_readcb>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <consider_reading@plt>
```

assistant: ```c
void be_openssl_readcb(struct bufferevent *bev_base, void *ctx) {
  struct bufferevent_openssl *bev_ssl = ctx;
  consider_reading(bev_ssl);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be_openssl_readcb>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <consider_reading@plt>
```

assistant: ```c
void be_openssl_readcb(struct bufferevent *bev_base, void *ctx) {
  struct bufferevent_openssl *bev_ssl = ctx;
  consider_reading(bev_ssl);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<decrease>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L16:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <enter_critical@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <exit_critical@plt>
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void decrease(int thread, int iterations, volatile int *data) {
  for (int i = 0; i < iterations; i++) {
    int a;
    enter_critical(thread);
    a = *data;
    a--;
    *data = a;
    exit_critical(thread);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decrease>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %rdx,%r12
  mov    $0x0,%ebx
L14:
  mov    %ebp,%edi
  call   <enter_critical@plt>
  mov    (%r12),%eax
  sub    $0x1,%eax
  mov    %eax,(%r12)
  mov    %ebp,%edi
  call   <exit_critical@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void decrease(int thread, int iterations, volatile int *data) {
  for (int i = 0; i < iterations; i++) {
    int a;
    enter_critical(thread);
    a = *data;
    a--;
    *data = a;
    exit_critical(thread);
  }
}
```