ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<quat_to_zvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void quat_to_zvec(double vec[3], double quat[4]) {
  vec[0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  vec[1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  vec[2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quat_to_zvec>:
  endbr64
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void quat_to_zvec(double vec[3], double quat[4]) {
  vec[0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  vec[1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  vec[2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
}
```
user: What is the c source code of the assembly code below?

```asm
<quat_to_zvec>:
  endbr64
  movsd  0x10(%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  subsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void quat_to_zvec(double vec[3], double quat[4]) {
  vec[0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  vec[1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  vec[2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quat_to_zvec>:
  endbr64
  movsd  0x10(%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  movsd  (%rsi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x18(%rsi),%xmm0
  movsd  (%rsi),%xmm3
  movsd  0x8(%rsi),%xmm2
  movsd  0x10(%rsi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm3,%xmm3
  mulsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm1
  subsd  %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void quat_to_zvec(double vec[3], double quat[4]) {
  vec[0] = 2.0 * (quat[2] * quat[0] - quat[1] * quat[3]);
  vec[1] = 2.0 * (quat[1] * quat[2] + quat[0] * quat[3]);
  vec[2] = ((quat[3]) * (quat[3])) - ((quat[0]) * (quat[0])) - ((quat[1]) * (quat[1])) + ((quat[2]) * (quat[2]));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sys_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L7
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sys_memset(char *src, char ch, int size) {
  int i = 0;
  for (i = 0; i < size; i++) {
    *(src + i) = ch;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_memset>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L12
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdi
L17:
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L17
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sys_memset(char *src, char ch, int size) {
  int i = 0;
  for (i = 0; i < size; i++) {
    *(src + i) = ch;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sys_memset>:
  endbr64
  test   %edx,%edx
  jle    L7
  push   %rbx
  movsbl %sil,%esi
  mov    %edx,%ebx
  movslq %edx,%rdx
  call   <memset@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sys_memset(char *src, char ch, int size) {
  int i = 0;
  for (i = 0; i < size; i++) {
    *(src + i) = ch;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sys_memset>:
  endbr64
  test   %edx,%edx
  jle    L9
  push   %rbx
  movsbl %sil,%esi
  mov    %edx,%ebx
  movslq %edx,%rdx
  call   <memset@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sys_memset(char *src, char ch, int size) {
  int i = 0;
  for (i = 0; i < size; i++) {
    *(src + i) = ch;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scdsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x14(%rbp)
  js     L9
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  test   %rax,%rax
  jns    L22
L9:
  mov    $0x0,%eax
  jmp    L3
L22:
  mov    -0xc(%rbp),%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int scdsr(int fd) {
  int i;
  if (fd < 0 || ioctl(fd, TIOCMGET, &i) < 0)
    return 0;
  return ((i & TIOCM_DSR) ? 1 : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scdsr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L2
  lea    0x4(%rsp),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L2
  mov    D7(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scdsr(int fd) {
  int i;
  if (fd < 0 || ioctl(fd, TIOCMGET, &i) < 0)
    return 0;
  return ((i & TIOCM_DSR) ? 1 : 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scdsr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L14
  mov    D15(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L14
  mov    D17(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
  jmp    L13
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scdsr(int fd) {
  int i;
  if (fd < 0 || ioctl(fd, TIOCMGET, &i) < 0)
    return 0;
  return ((i & TIOCM_DSR) ? 1 : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scdsr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L0
  mov    D9(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %rax,%rax
  js     L0
  mov    D10(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
  jmp    L10
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int scdsr(int fd) {
  int i;
  if (fd < 0 || ioctl(fd, TIOCMGET, &i) < 0)
    return 0;
  return ((i & TIOCM_DSR) ? 1 : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa8,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L56:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L59
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L59
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L21
L59:
  addl   $0x1,-0x10(%rbp)
L34:
  cmpl   $0x2,-0x10(%rbp)
  jle    L56
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D16
type: string

tool: D17: %d

tool: D23: CRASH %d


tool: D16: NO CRASH

assistant: ```c
int main() {
  int i, h;
  const int wheeler = 168;
  for (i = 0; i < 3; i++)
    if (1 == scanf("%d", &h) && h <= wheeler) {
      printf("CRASH %d\n", h);
      return 0;
    }
  puts("NO CRASH");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3,%ebx
  lea    D17(%rip),%rbp
  jmp    L55
L25:
  sub    $0x1,%ebx
  je     L54
L55:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L25
  mov    0x4(%rsp),%esi
  cmp    $0xa8,%esi
  jg     L25
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L54:
  lea    D8(%rip),%rdi
  call   <puts@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D17: %d

tool: D14: CRASH %d


tool: D8: NO CRASH

assistant: ```c
int main() {
  int i, h;
  const int wheeler = 168;
  for (i = 0; i < 3; i++)
    if (1 == scanf("%d", &h) && h <= wheeler) {
      printf("CRASH %d\n", h);
      return 0;
    }
  puts("NO CRASH");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
L21:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L15
L13:
  sub    $0x1,%ebx
  jne    L21
  lea    D13(%rip),%rdi
  call   <puts@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  mov    0x4(%rsp),%esi
  cmp    $0xa8,%esi
  jg     L13
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string

tool: D20: %d

tool: D13: NO CRASH

tool: D18: CRASH %d


assistant: ```c
int main() {
  int i, h;
  const int wheeler = 168;
  for (i = 0; i < 3; i++)
    if (1 == scanf("%d", &h) && h <= wheeler) {
      printf("CRASH %d\n", h);
      return 0;
    }
  puts("NO CRASH");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L25
L5:
  sub    $0x1,%ebx
  jne    L9
  lea    D17(%rip),%rdi
  call   <puts@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  mov    0x4(%rsp),%esi
  cmp    $0xa8,%esi
  jg     L5
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string

tool: D16: %d

tool: D17: NO CRASH

tool: D12: CRASH %d


assistant: ```c
int main() {
  int i, h;
  const int wheeler = 168;
  for (i = 0; i < 3; i++)
    if (1 == scanf("%d", &h) && h <= wheeler) {
      printf("CRASH %d\n", h);
      return 0;
    }
  puts("NO CRASH");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<card_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4b,%al
  je     L22
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x51,%al
  je     L22
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4a,%al
  jne    L11
L22:
  movl   $0xa,-0x4(%rbp)
  jmp    L66
L11:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x41,%al
  jne    L25
  movl   $0xb,-0x4(%rbp)
  jmp    L66
L25:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L37
  cmpl   $0xa,-0x4(%rbp)
  jle    L66
L37:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L66:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: I don't understand that value!

assistant: ```c
int card_count(int val, char *card_name) {
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
    if ((val < 1) || (val > 10)) {
      puts("I don't understand that value!");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<card_count>:
  endbr64
  movzbl (%rsi),%eax
  lea    -0x4a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L29
  and    $0xffffffef,%eax
  cmp    $0x41,%al
  jne    L32
L29:
  ret
L32:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  cmp    $0x9,%eax
  ja     L18
L22:
  add    $0x8,%rsp
  ret
L18:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L22
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: I don't understand that value!

assistant: ```c
int card_count(int val, char *card_name) {
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
    if ((val < 1) || (val > 10)) {
      puts("I don't understand that value!");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<card_count>:
  endbr64
  movzbl (%rsi),%eax
  lea    -0x4a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L29
  and    $0xffffffef,%eax
  cmp    $0x41,%al
  jne    L27
L29:
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  cmp    $0x9,%eax
  ja     L8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: I don't understand that value!

assistant: ```c
int card_count(int val, char *card_name) {
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
    if ((val < 1) || (val > 10)) {
      puts("I don't understand that value!");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<card_count>:
  endbr64
  movzbl (%rsi),%eax
  lea    -0x4a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L16
  and    $0xffffffef,%eax
  cmp    $0x41,%al
  jne    L25
L16:
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <atoi@plt>
  sub    $0x1,%eax
  cmp    $0x9,%eax
  ja     L7
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L7:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: I don't understand that value!

assistant: ```c
int card_count(int val, char *card_name) {
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
    if ((val < 1) || (val > 10)) {
      puts("I don't understand that value!");
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dlog_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_sub_ui@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_divexact@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mod@plt>
  nop
  leave
  ret
```

assistant: ```c
void dlog_s(mpz_t n, mpz_t rop, mpz_t op) {
  mpz_sub_ui(rop, op, 1);
  mpz_divexact(rop, rop, n);
  mpz_mod(rop, rop, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dlog_s>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%esi
  mov    $0x1,%edx
  mov    %ebx,%edi
  call   <mpz_sub_ui@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_divexact@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpz_mod@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void dlog_s(mpz_t n, mpz_t rop, mpz_t op) {
  mpz_sub_ui(rop, op, 1);
  mpz_divexact(rop, rop, n);
  mpz_mod(rop, rop, n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dlog_s>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <mpz_sub_ui@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_divexact@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <mpz_mod@plt>
```

assistant: ```c
void dlog_s(mpz_t n, mpz_t rop, mpz_t op) {
  mpz_sub_ui(rop, op, 1);
  mpz_divexact(rop, rop, n);
  mpz_mod(rop, rop, n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dlog_s>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edx,%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <mpz_sub_ui@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  call   <mpz_divexact@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <mpz_mod@plt>
```

assistant: ```c
void dlog_s(mpz_t n, mpz_t rop, mpz_t op) {
  mpz_sub_ui(rop, op, 1);
  mpz_divexact(rop, rop, n);
  mpz_mod(rop, rop, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rev_s_m>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x2(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short int rev_s_m(const unsigned char *p) {
  unsigned short a, b;
  a = p[0];
  b = p[1];
  return (unsigned short int)((a << 8) | (b << 0));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rev_s_m>:
  endbr64
  movzbl (%rdi),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rdi),%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned short int rev_s_m(const unsigned char *p) {
  unsigned short a, b;
  a = p[0];
  b = p[1];
  return (unsigned short int)((a << 8) | (b << 0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rev_s_m>:
  endbr64
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short int rev_s_m(const unsigned char *p) {
  unsigned short a, b;
  a = p[0];
  b = p[1];
  return (unsigned short int)((a << 8) | (b << 0));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rev_s_m>:
  endbr64
  movzwl (%rdi),%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short int rev_s_m(const unsigned char *p) {
  unsigned short a, b;
  a = p[0];
  b = p[1];
  return (unsigned short int)((a << 8) | (b << 0));
}
```