ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calc_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x80,-0x110(%rbp)
  mov    -0x130(%rbp),%rax
  lea    0x10(%rax),%rcx
  lea    -0x90(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <get32_le@plt>
  sar    $0x3,%eax
  and    $0x3f,%eax
  mov    %eax,-0x114(%rbp)
  cmpl   $0x37,-0x114(%rbp)
  ja     L8
  mov    $0x38,%eax
  sub    -0x114(%rbp),%eax
  mov    %eax,-0x114(%rbp)
  jmp    L3
L8:
  mov    $0x78,%eax
  sub    -0x114(%rbp),%eax
  mov    %eax,-0x114(%rbp)
L3:
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rcx
  mov    -0x130(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <call_hash@plt>
  lea    -0x90(%rbp),%rcx
  mov    -0x130(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <call_hash@plt>
  mov    -0x130(%rbp),%rcx
  mov    -0x128(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void calc_response(char *result, char *field) {
  char buf1[128];
  char buf2[128];
  unsigned int i;
  memset(buf1, 0, 64);
  *buf1 = 128;
  memcpy(buf2, field + 16, 8);
  i = (get32_le((buf2)) >> 3) & 0x3f;
  if (i < 56) {
    i = 56 - i;
  } else {
    i = 120 - i;
  }
  call_hash(field, buf1, i);
  call_hash(field, buf2, 8);
  memcpy(result, field, 16);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calc_response>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x40,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movb   $0x80,(%rsp)
  lea    0x10(%rbx),%rsi
  lea    0x80(%rsp),%r12
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <get32_le@plt>
  sar    $0x3,%eax
  and    $0x3f,%eax
  cmp    $0x37,%eax
  ja     L23
  mov    $0x38,%edx
  sub    %eax,%edx
L21:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <call_hash@plt>
  lea    0x80(%rsp),%rsi
  mov    $0x8,%edx
  mov    %rbx,%rdi
  call   <call_hash@plt>
  mov    $0x10,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x78,%edx
  sub    %eax,%edx
  jmp    L21
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void calc_response(char *result, char *field) {
  char buf1[128];
  char buf2[128];
  unsigned int i;
  memset(buf1, 0, 64);
  *buf1 = 128;
  memcpy(buf2, field + 16, 8);
  i = (get32_le((buf2)) >> 3) & 0x3f;
  if (i < 56) {
    i = 56 - i;
  } else {
    i = 120 - i;
  }
  call_hash(field, buf1, i);
  call_hash(field, buf2, 8);
  memcpy(result, field, 16);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calc_response>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x80(%rsp),%r13
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x10(%rbp),%rsi
  mov    %r13,%rdi
  movb   $0x80,(%rsp)
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <get32_le@plt>
  sar    $0x3,%eax
  and    $0x3f,%eax
  cmp    $0x37,%eax
  ja     L29
  mov    $0x38,%edx
  sub    %eax,%edx
L9:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    $0x8,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L29:
  mov    $0x78,%edx
  sub    %eax,%edx
  jmp    L9
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void calc_response(char *result, char *field) {
  char buf1[128];
  char buf2[128];
  unsigned int i;
  memset(buf1, 0, 64);
  *buf1 = 128;
  memcpy(buf2, field + 16, 8);
  i = (get32_le((buf2)) >> 3) & 0x3f;
  if (i < 56) {
    i = 56 - i;
  } else {
    i = 120 - i;
  }
  call_hash(field, buf1, i);
  call_hash(field, buf2, 8);
  memcpy(result, field, 16);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_response>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x80(%rsp),%r13
  mov    %r14,%rdi
  call   <memset@plt>
  lea    0x10(%rbp),%rsi
  mov    %r13,%rdi
  movb   $0x80,(%rsp)
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  call   <get32_le@plt>
  sar    $0x3,%eax
  and    $0x3f,%eax
  cmp    $0x37,%eax
  ja     L22
  mov    $0x38,%edx
  sub    %eax,%edx
L25:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    $0x8,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <call_hash@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x78,%edx
  sub    %eax,%edx
  jmp    L25
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void calc_response(char *result, char *field) {
  char buf1[128];
  char buf2[128];
  unsigned int i;
  memset(buf1, 0, 64);
  *buf1 = 128;
  memcpy(buf2, field + 16, 8);
  i = (get32_le((buf2)) >> 3) & 0x3f;
  if (i < 56) {
    i = 56 - i;
  } else {
    i = 120 - i;
  }
  call_hash(field, buf1, i);
  call_hash(field, buf2, 8);
  memcpy(result, field, 16);
}
```
user: What is the c source code of the assembly code below:

```asm
<return_ketjeJrSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L37
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L37:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  js     L27
  mov    -0x4(%rbp),%eax
  jmp    L26
L27:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int return_ketjeJrSize(int len) {
  int result = 0;
  if (len % 2 == 0) {
    result = len - 2;
  } else {
    result = len - 1;
  }
  if (result >= 0)
    return result;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<return_ketjeJrSize>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  lea    -0x2(%rax,%rdi,1),%eax
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int return_ketjeJrSize(int len) {
  int result = 0;
  if (len % 2 == 0) {
    result = len - 2;
  } else {
    result = len - 1;
  }
  if (result >= 0)
    return result;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<return_ketjeJrSize>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  and    $0x1,%eax
  lea    -0x2(%rax,%rdi,1),%eax
  test   %eax,%eax
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int return_ketjeJrSize(int len) {
  int result = 0;
  if (len % 2 == 0) {
    result = len - 2;
  } else {
    result = len - 1;
  }
  if (result >= 0)
    return result;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<return_ketjeJrSize>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  and    $0x1,%eax
  lea    -0x2(%rax,%rdi,1),%eax
  test   %eax,%eax
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int return_ketjeJrSize(int len) {
  int result = 0;
  if (len % 2 == 0) {
    result = len - 2;
  } else {
    result = len - 1;
  }
  if (result >= 0)
    return result;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  cmpl   $0x0,-0x1c(%rbp)
  js     L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x20(%rbp)
  jl     L6
L11:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L47
L6:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L25:
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L25
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L47:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: Error substring. Indice fuera de memoria.


assistant: ```c
char *substring(char *input, int start, int end) {
  char *substring = NULL;
  if (input == NULL || start < 0 || end >= strlen(input)) {
    printf("Error substring. Indice fuera de memoria.\n");
    return NULL;
  }
  int n = end - start + 1;
  substring = malloc((n + 1) * sizeof(char));
  for (int i = 0; i < n; i++) {
    substring[i] = input[i + start];
  }
  substring[n] = '\0';
  return substring;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L49
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%r13d
  test   %esi,%esi
  js     L49
  call   <strlen@plt>
  cmp    %r13d,%eax
  jle    L49
  sub    %r12d,%r13d
  lea    0x1(%r13),%ebp
  lea    0x2(%r13),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L37
  mov    %r13d,%edx
  mov    $0x0,%ecx
  movslq %r12d,%r12
  lea    (%rbx,%r12,1),%rdi
L46:
  movzbl (%rdi,%rcx,1),%esi
  mov    %sil,(%rax,%rcx,1)
  mov    %rcx,%rsi
  add    $0x1,%rcx
  cmp    %rdx,%rsi
  jne    L46
L37:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: Error substring. Indice fuera de memoria.


assistant: ```c
char *substring(char *input, int start, int end) {
  char *substring = NULL;
  if (input == NULL || start < 0 || end >= strlen(input)) {
    printf("Error substring. Indice fuera de memoria.\n");
    return NULL;
  }
  int n = end - start + 1;
  substring = malloc((n + 1) * sizeof(char));
  for (int i = 0; i < n; i++) {
    substring[i] = input[i + start];
  }
  substring[n] = '\0';
  return substring;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L33
  movslq %esi,%r12
  test   %r12d,%r12d
  js     L33
  mov    %edx,%ebx
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L33
  sub    %r12d,%ebx
  lea    0x1(%rbx),%r13d
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  test   %r13d,%r13d
  jle    L9
  mov    %ebx,%ecx
  xor    %edx,%edx
  lea    0x0(%rbp,%r12,1),%rdi
  cs nopw 0x0(%rax,%rax,1)
L16:
  movzbl (%rdi,%rdx,1),%esi
  mov    %sil,(%rax,%rdx,1)
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmp    %rcx,%rsi
  jne    L16
L9:
  movslq %r13d,%r13
  movb   $0x0,(%rax,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: Error substring. Indice fuera de memoria.


assistant: ```c
char *substring(char *input, int start, int end) {
  char *substring = NULL;
  if (input == NULL || start < 0 || end >= strlen(input)) {
    printf("Error substring. Indice fuera de memoria.\n");
    return NULL;
  }
  int n = end - start + 1;
  substring = malloc((n + 1) * sizeof(char));
  for (int i = 0; i < n; i++) {
    substring[i] = input[i + start];
  }
  substring[n] = '\0';
  return substring;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<c_strlen_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L15
L8:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
L15:
  nop
  leave
  ret
```

assistant: ```c
void c_strlen_(char **in_ptr, int *out_ptr) {
  if (*in_ptr == NULL)
    *out_ptr = 0;
  else
    *out_ptr = strlen(*in_ptr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c_strlen_>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rdi),%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L2
  call   <strlen@plt>
L2:
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void c_strlen_(char **in_ptr, int *out_ptr) {
  if (*in_ptr == NULL)
    *out_ptr = 0;
  else
    *out_ptr = strlen(*in_ptr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<c_strlen_>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rsi,%rbx
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  call   <strlen@plt>
L3:
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void c_strlen_(char **in_ptr, int *out_ptr) {
  if (*in_ptr == NULL)
    *out_ptr = 0;
  else
    *out_ptr = strlen(*in_ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<c_strlen_>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdi
  mov    %rsi,%rbx
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  call   <strlen@plt>
L7:
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void c_strlen_(char **in_ptr, int *out_ptr) {
  if (*in_ptr == NULL)
    *out_ptr = 0;
  else
    *out_ptr = strlen(*in_ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D54(%rip),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D87(%rip),%rax
  mov    %rax,%rdx
  lea    D42(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L18
L3:
  movsd  -0x8(%rbp),%xmm1
  movsd  D43(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x28(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x8(%rbp),%xmm1
  movsd  D55(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L18:
  movsd  D45(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L3
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D54
type: string
name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D87
type: string
name: unpack_data
arguments: data_label: D42
type: string
name: unpack_data
arguments: data_label: D24
type: string
name: unpack_data
arguments: data_label: D11
type: string
name: unpack_data
arguments: data_label: D43
type: byte[8]
name: unpack_data
arguments: data_label: D32
type: string
name: unpack_data
arguments: data_label: D55
type: byte[8]
name: unpack_data
arguments: data_label: D45
type: byte[8]

tool: D54: (exp(-0.1*(x))*1.0*cos(x))

tool: D5: FUNC(x) = %s


tool: D87: y = FUNC(x)

tool: D42: x

tool: D24: 
 %10s %25s


tool: D11: -----------------------------------------

tool: {"D43": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

tool: D32: %15f %20f


tool: {"D55": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0xd9,0x3f]}

tool: {"D45": [0xa1,0x62,0x9c,0xbf,0x09,0xeb,0x19,0x40]}

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("FUNC(x) = %s\n", "(exp(-0.1*(x))*1.0*cos(x))");
  printf("\n %10s %25s\n", "x", "y = FUNC(x)");
  printf("-----------------------------------------\n");
  for (double x = 0.0; x < 2 * 3.14159 + (3.14159 / 8) / 2; x += (3.14159 / 8))
    printf("%15f %20f\n", x, (exp(-0.1 * (x)) * 1.0 * cos(x)));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  lea    D89(%rip),%rsi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdx
  lea    D63(%rip),%rsi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  mov    $0x11,%ebx
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  lea    D64(%rip),%rbp
L5:
  movsd  D52(%rip),%xmm0
  mulsd  0x8(%rsp),%xmm0
  call   <exp@plt>
  movq   %xmm0,%r14
  movsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movq   %r14,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  D40(%rip),%xmm3
  addsd  0x8(%rsp),%xmm3
  movsd  %xmm3,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D89
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D57
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D63
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D51
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D64
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D52
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D40
type_guessed: byte[8]

tool: D89: (exp(-0.1*(x))*1.0*cos(x))

tool: D57: FUNC(x) = %s


tool: D34: y = FUNC(x)

tool: D63: x

tool: D50: 
 %10s %25s


tool: D51: -----------------------------------------

tool: D64: %15f %20f


tool: {"D52": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

tool: {"D40": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0xd9,0x3f]}

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("FUNC(x) = %s\n", "(exp(-0.1*(x))*1.0*cos(x))");
  printf("\n %10s %25s\n", "x", "y = FUNC(x)");
  printf("-----------------------------------------\n");
  for (double x = 0.0; x < 2 * 3.14159 + (3.14159 / 8) / 2; x += (3.14159 / 8))
    printf("%15f %20f\n", x, (exp(-0.1 * (x)) * 1.0 * cos(x)));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  push   %rbx
  lea    D59(%rip),%rbp
  mov    $0x11,%ebx
  sub    $0x18,%rsp
  call   <printf@plt>
  lea    D55(%rip),%rdx
  lea    D98(%rip),%rsi
  xor    %eax,%eax
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    D97(%rip),%rdi
  call   <puts@plt>
  movsd  D63(%rip),%xmm1
  pxor   %xmm2,%xmm2
  jmp    L13
  nopl   0x0(%rax)
L0:
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <cos@plt>
  movsd  (%rsp),%xmm2
  movapd %xmm0,%xmm1
L13:
  movsd  D18(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  mulsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  mov    %rbp,%rdi
  mov    $0x2,%eax
  mulsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  movsd  (%rsp),%xmm2
  addsd  D35(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D49
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D59
type_infered: string
name: read_data
arguments: data_label: D55
type_infered: string
name: read_data
arguments: data_label: D98
type_infered: string
name: read_data
arguments: data_label: D71
type_infered: string
name: read_data
arguments: data_label: D97
type_infered: string
name: read_data
arguments: data_label: D63
type_infered: f64
name: read_data
arguments: data_label: D18
type_infered: byte[8]
name: read_data
arguments: data_label: D35
type_infered: byte[8]

tool: D49: (exp(-0.1*(x))*1.0*cos(x))

tool: D3: FUNC(x) = %s


tool: D59: %15f %20f


tool: D55: y = FUNC(x)

tool: D98: x

tool: D71: 
 %10s %25s


tool: D97: -----------------------------------------

tool: D63: 1

tool: {"D18": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

tool: {"D35": [0x6e,0x86,0x1b,0xf0,0xf9,0x21,0xd9,0x3f]}

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("FUNC(x) = %s\n", "(exp(-0.1*(x))*1.0*cos(x))");
  printf("\n %10s %25s\n", "x", "y = FUNC(x)");
  printf("-----------------------------------------\n");
  for (double x = 0.0; x < 2 * 3.14159 + (3.14159 / 8) / 2; x += (3.14159 / 8))
    printf("%15f %20f\n", x, (exp(-0.1 * (x)) * 1.0 * cos(x)));
  return 0;
}
```