ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<format_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D20(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D20
type_infered: string
name: disassemble_data
arguments: tag: D37
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D33
type_infered: string

tool: D20: MarcoMerli

tool: D37: %s


tool: D21: <%20s>


tool: D33: %.5s


assistant: ```c
void format_string(void) {
  char *str = "MarcoMerli";
  printf("%s\n", str);
  printf("<%20s>\n", str);
  printf("%.5s\n", str);
}
```
user: What is the c source code of the assembly code below:

```asm
<format_string>:
  endbr64
  push   %rbx
  lea    D10(%rip),%rbx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D10: MarcoMerli

tool: D4: %s


tool: D22: <%20s>


tool: D0: %.5s


assistant: ```c
void format_string(void) {
  char *str = "MarcoMerli";
  printf("%s\n", str);
  printf("<%20s>\n", str);
  printf("%.5s\n", str);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<format_string>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rbp
  lea    D30(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D38
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D31
type_guessed: string

tool: D38: MarcoMerli

tool: D30: %s


tool: D14: <%20s>


tool: D31: %.5s


assistant: ```c
void format_string(void) {
  char *str = "MarcoMerli";
  printf("%s\n", str);
  printf("<%20s>\n", str);
  printf("%.5s\n", str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<format_string>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  lea    D7(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D5: MarcoMerli

tool: D7: %s


tool: D6: <%20s>


tool: D11: %.5s


assistant: ```c
void format_string(void) {
  char *str = "MarcoMerli";
  printf("%s\n", str);
  printf("<%20s>\n", str);
  printf("%.5s\n", str);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x1f,-0x28(%rbp)
  ja     L149
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    $0xa08a28ac,%eax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  jmp    L87
L149:
  mov    -0x28(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L103
  mov    $0x0,%eax
  jmp    L87
L103:
  mov    -0x28(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  mov    %rax,%rdx
  add    %rdx,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L145
  mov    $0x0,%eax
  jmp    L87
L145:
  mov    -0x28(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  mov    %rax,%rdx
  shl    $0x2,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L144
  mov    $0x0,%eax
  jmp    L87
L144:
  mov    -0x28(%rbp),%rcx
  movabs $0x2492492492492493,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x2,%rax
  mov    %rax,%rdx
  shl    $0x3,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L98
  mov    $0x0,%eax
  jmp    L87
L98:
  movq   $0xb,-0x18(%rbp)
L134:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L34
  mov    $0x1,%eax
  jmp    L87
L34:
  cmpq   $0x0,-0x8(%rbp)
  je     L178
  addq   $0x2,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L170
  mov    $0x1,%eax
  jmp    L87
L170:
  cmpq   $0x0,-0x8(%rbp)
  je     L175
  addq   $0x4,-0x18(%rbp)
  jmp    L134
L178:
  nop
  jmp    L59
L175:
  nop
L59:
  mov    $0x0,%eax
L87:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(unsigned long int t) {
  unsigned long int q, r, d;
  if (t < 32)
    return (0xa08a28acUL >> t) & 1;
  if ((t & 1) == 0)
    return 0;
  if (t % 3 == 0)
    return 0;
  if (t % 5 == 0)
    return 0;
  if (t % 7 == 0)
    return 0;
  for (d = 11;;) {
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 2;
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 4;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isprime>:
  endbr64
  mov    %rdi,%rcx
  cmp    $0x1f,%rdi
  jbe    L9
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L29
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  and    $0xfffffffffffffffe,%rdx
  add    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rdi
  je     L29
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdx
  add    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rdi
  je     L29
  movabs $0x2492492492492493,%rdx
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rax,%rdx
  shr    $0x2,%rdx
  lea    0x0(,%rdx,8),%rsi
  sub    %rdx,%rsi
  mov    $0x0,%eax
  cmp    %rsi,%rdi
  je     L29
  movabs $0x2e8ba2e8ba2e8ba3,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    %rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdx,%rax,2),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0x78,%rdi
  jbe    L48
  test   %rdx,%rdx
  je     L120
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0xa8,%rdi
  jbe    L69
  test   %rdx,%rdx
  je     L100
  mov    $0x13,%edi
  mov    $0xb,%esi
L79:
  add    $0x6,%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  cmp    %rsi,%rax
  jb     L56
  test   %rdx,%rdx
  je     L35
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rdi
  cmp    %rdi,%rax
  jb     L39
  add    $0x6,%rdi
  test   %rdx,%rdx
  jne    L79
  mov    $0x0,%eax
L29:
  ret
L9:
  mov    $0xa08a28ac,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L56:
  mov    $0x1,%eax
  ret
L48:
  mov    $0x1,%eax
  ret
L120:
  mov    $0x0,%eax
  ret
L69:
  mov    $0x1,%eax
  ret
L100:
  mov    $0x0,%eax
  ret
L35:
  mov    $0x0,%eax
  ret
L39:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isprime(unsigned long int t) {
  unsigned long int q, r, d;
  if (t < 32)
    return (0xa08a28acUL >> t) & 1;
  if ((t & 1) == 0)
    return 0;
  if (t % 3 == 0)
    return 0;
  if (t % 5 == 0)
    return 0;
  if (t % 7 == 0)
    return 0;
  for (d = 11;;) {
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 2;
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 4;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isprime>:
  endbr64
  mov    %rdi,%rcx
  mov    $0xa08a28ac,%r8d
  shr    %cl,%r8
  and    $0x1,%r8d
  cmp    $0x1f,%rdi
  jbe    L65
  xor    %r8d,%r8d
  test   $0x1,%dil
  je     L65
  movabs $0xaaaaaaaaaaaaaaab,%rax
  movabs $0x5555555555555555,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L65
  movabs $0xcccccccccccccccd,%rax
  movabs $0x3333333333333333,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L65
  movabs $0x6db6db6db6db6db7,%rax
  movabs $0x2492492492492492,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L65
  movabs $0x2e8ba2e8ba2e8ba3,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    %rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdx,%rax,2),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0x78,%rdi
  jbe    L107
  test   %rdx,%rdx
  je     L65
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0xa8,%rdi
  jbe    L107
  test   %rdx,%rdx
  je     L65
  mov    $0x13,%edi
  mov    $0xb,%esi
  jmp    L140
  cs nopw 0x0(%rax,%rax,1)
L12:
  test   %rdx,%rdx
  je     L114
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rdi
  cmp    %rdi,%rax
  jb     L107
  add    $0x6,%rdi
  test   %rdx,%rdx
  je     L114
L140:
  add    $0x6,%rsi
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  cmp    %rsi,%rax
  jae    L12
L107:
  mov    $0x1,%r8d
L65:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L114:
  xor    %r8d,%r8d
  jmp    L65
```

assistant: ```c
int isprime(unsigned long int t) {
  unsigned long int q, r, d;
  if (t < 32)
    return (0xa08a28acUL >> t) & 1;
  if ((t & 1) == 0)
    return 0;
  if (t % 3 == 0)
    return 0;
  if (t % 5 == 0)
    return 0;
  if (t % 7 == 0)
    return 0;
  for (d = 11;;) {
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 2;
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 4;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isprime>:
  endbr64
  mov    %rdi,%rcx
  mov    $0xa08a28ac,%r8d
  shr    %cl,%r8
  and    $0x1,%r8d
  cmp    $0x1f,%rdi
  jbe    L90
  xor    %r8d,%r8d
  test   $0x1,%dil
  je     L90
  movabs $0xaaaaaaaaaaaaaaab,%rax
  movabs $0x5555555555555555,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L90
  movabs $0xcccccccccccccccd,%rax
  movabs $0x3333333333333333,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L90
  movabs $0x6db6db6db6db6db7,%rax
  movabs $0x2492492492492492,%rdx
  imul   %rdi,%rax
  cmp    %rdx,%rax
  jbe    L90
  movabs $0x2e8ba2e8ba2e8ba3,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    %rdx
  lea    (%rdx,%rdx,4),%rax
  lea    (%rdx,%rax,2),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0x78,%rdi
  jbe    L118
  test   %rdx,%rdx
  je     L90
  movabs $0x4ec4ec4ec4ec4ec5,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  lea    (%rdx,%rax,4),%rax
  mov    %rdi,%rdx
  sub    %rax,%rdx
  cmp    $0xa8,%rdi
  jbe    L118
  test   %rdx,%rdx
  je     L90
  mov    $0x13,%edi
  mov    $0xb,%esi
  jmp    L129
  cs nopw 0x0(%rax,%rax,1)
L67:
  test   %rdx,%rdx
  je     L137
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rdi
  cmp    %rdi,%rax
  jb     L118
  add    $0x6,%rdi
  test   %rdx,%rdx
  je     L137
L129:
  add    $0x6,%rsi
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  cmp    %rsi,%rax
  jae    L67
L118:
  mov    $0x1,%r8d
L90:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L137:
  xor    %r8d,%r8d
  jmp    L90
```

assistant: ```c
int isprime(unsigned long int t) {
  unsigned long int q, r, d;
  if (t < 32)
    return (0xa08a28acUL >> t) & 1;
  if ((t & 1) == 0)
    return 0;
  if (t % 3 == 0)
    return 0;
  if (t % 5 == 0)
    return 0;
  if (t % 7 == 0)
    return 0;
  for (d = 11;;) {
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 2;
    q = t / d;
    r = t - q * d;
    if (q < d)
      return 1;
    if (r == 0)
      break;
    d += 4;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L24:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x50,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <httptestNew@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x5,-0x4(%rbp)
  jle    L24
L1:
  mov    $0x0,%eax
  call   <oosmos_RunStateMachines@plt>
  mov    $0x5,%edi
  call   <oosmos_DelayMS@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string

tool: D8: 
Test does not end on its own. Press CNTL-C to terminate.



tool: D17: www.example.com

assistant: ```c
extern int main(int argc, char *argv[]) {
  printf("\nTest does not end on its own. Press CNTL-C to terminate.\n\n");
  for (int Count = 1; Count <= 5; Count++) {
    httptestNew("www.example.com", 80, Count);
  }
  while (1) {
    oosmos_RunStateMachines();
    oosmos_DelayMS(5);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D16(%rip),%rbp
L8:
  mov    %ebx,%edx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <httptestNew@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L8
L15:
  mov    $0x0,%eax
  call   <oosmos_RunStateMachines@plt>
  mov    $0x5,%edi
  call   <oosmos_DelayMS@plt>
  jmp    L15
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D16
type_infered: string

tool: D5: 
Test does not end on its own. Press CNTL-C to terminate.



tool: D16: www.example.com

assistant: ```c
extern int main(int argc, char *argv[]) {
  printf("\nTest does not end on its own. Press CNTL-C to terminate.\n\n");
  for (int Count = 1; Count <= 5; Count++) {
    httptestNew("www.example.com", 80, Count);
  }
  while (1) {
    oosmos_RunStateMachines();
    oosmos_DelayMS(5);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L13:
  mov    %ebx,%edx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <httptestNew@plt>
  cmp    $0x6,%ebx
  jne    L13
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <oosmos_RunStateMachines@plt>
  mov    $0x5,%edi
  call   <oosmos_DelayMS@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D14: 
Test does not end on its own. Press CNTL-C to terminate.



tool: D7: www.example.com

assistant: ```c
extern int main(int argc, char *argv[]) {
  printf("\nTest does not end on its own. Press CNTL-C to terminate.\n\n");
  for (int Count = 1; Count <= 5; Count++) {
    httptestNew("www.example.com", 80, Count);
  }
  while (1) {
    oosmos_RunStateMachines();
    oosmos_DelayMS(5);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L9:
  mov    %ebx,%edx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <httptestNew@plt>
  cmp    $0x6,%ebx
  jne    L9
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  call   <oosmos_RunStateMachines@plt>
  mov    $0x5,%edi
  call   <oosmos_DelayMS@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D16
data_type: string

tool: D9: 
Test does not end on its own. Press CNTL-C to terminate.



tool: D16: www.example.com

assistant: ```c
extern int main(int argc, char *argv[]) {
  printf("\nTest does not end on its own. Press CNTL-C to terminate.\n\n");
  for (int Count = 1; Count <= 5; Count++) {
    httptestNew("www.example.com", 80, Count);
  }
  while (1) {
    oosmos_RunStateMachines();
    oosmos_DelayMS(5);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1e,-0x8(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0xa,-0xc(%rbp)
  jle    L0
  subl   $0xa,-0xc(%rbp)
L0:
  mov    $0x3c,%eax
  cltd
  idivl  -0x8(%rbp)
  imul   -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 30;
  int b = 9;
  int c;
  c = b * a;
  if (c > 10) {
    c = c - 10;
  }
  return c * (60 / a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x208,%eax
  ret
```

assistant: ```c
int main() {
  int a = 30;
  int b = 9;
  int c;
  c = b * a;
  if (c > 10) {
    c = c - 10;
  }
  return c * (60 / a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x208,%eax
  ret
```

assistant: ```c
int main() {
  int a = 30;
  int b = 9;
  int c;
  c = b * a;
  if (c > 10) {
    c = c - 10;
  }
  return c * (60 / a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<B32_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  add    $0x4,%eax
  cmp    %eax,-0x28(%rbp)
  jg     L37
  mov    $0xffffffff,%eax
  jmp    L56
L37:
  mov    -0x24(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L67:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <decode_chunk@plt>
  cmp    $0x5,%eax
  je     L61
  mov    $0xffffffff,%eax
  jmp    L56
L61:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L67
  cmpl   $0x0,-0x4(%rbp)
  jle    L45
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <decode_chunk@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L40
  mov    $0xffffffff,%eax
  jmp    L56
L45:
  movl   $0x0,-0x10(%rbp)
L40:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
L56:
  leave
  ret
```

assistant: ```c
int B32_decode(char *source, char *destination, int size_source, int size_destination) {
  int chunks, reminder, size_reminder, i;
  if (size_destination < (((size_source * 5) / 8) + 5)) {
    return -1;
  }
  chunks = size_source / 8;
  reminder = size_source % 8;
  for (i = 0; i < chunks; i++) {
    if (decode_chunk(source + (i * 8), destination + (i * 5), 8) != 5) {
      return -1;
    }
  }
  if (reminder > 0) {
    size_reminder = decode_chunk(source + (chunks * 8), destination + (chunks * 5), reminder);
    if (size_reminder < 0)
      return -1;
  } else {
    size_reminder = 0;
  }
  return (int)((chunks * 5) + size_reminder);
}
```
user: Translate the below assembly code into C programming language:

```asm
<B32_decode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,%r14d
  lea    (%rdx,%rdx,4),%edx
  lea    0x7(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x3,%eax
  add    $0x4,%eax
  cmp    %ecx,%eax
  jge    L71
  mov    %rsi,%r15
  lea    0x7(%r14),%r13d
  test   %r14d,%r14d
  cmovns %r14d,%r13d
  sar    $0x3,%r13d
  cmp    $0x7,%r14d
  jle    L49
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%r12d
L59:
  mov    $0x8,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <decode_chunk@plt>
  cmp    $0x5,%eax
  jne    L47
  add    $0x1,%r12d
  add    $0x8,%rbp
  add    $0x5,%rbx
  cmp    %r12d,%r13d
  jg     L59
L49:
  mov    %r14d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%r14,%rax,1),%edx
  and    $0x7,%edx
  sub    %eax,%edx
  mov    $0x0,%ecx
  test   %edx,%edx
  jg     L60
L21:
  lea    0x0(%r13,%r13,4),%eax
  add    %ecx,%eax
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  lea    0x0(%r13,%r13,4),%eax
  cltq
  lea    (%r15,%rax,1),%rsi
  lea    0x0(,%r13,8),%eax
  cltq
  mov    0x8(%rsp),%rdi
  add    %rax,%rdi
  call   <decode_chunk@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jns    L21
  mov    $0xffffffff,%eax
  jmp    L20
L71:
  mov    $0xffffffff,%eax
  jmp    L20
L47:
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int B32_decode(char *source, char *destination, int size_source, int size_destination) {
  int chunks, reminder, size_reminder, i;
  if (size_destination < (((size_source * 5) / 8) + 5)) {
    return -1;
  }
  chunks = size_source / 8;
  reminder = size_source % 8;
  for (i = 0; i < chunks; i++) {
    if (decode_chunk(source + (i * 8), destination + (i * 5), 8) != 5) {
      return -1;
    }
  }
  if (reminder > 0) {
    size_reminder = decode_chunk(source + (chunks * 8), destination + (chunks * 5), reminder);
    if (size_reminder < 0)
      return -1;
  } else {
    size_reminder = 0;
  }
  return (int)((chunks * 5) + size_reminder);
}
```