user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x30d40,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  cmp    $0x1,%edi
  je     L101
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r14d
L101:
  mov    %r14d,%eax
  lea    -0x1(%r14),%r12d
  lea    0x0(,%r14,4),%ebp
  mov    %r14d,%r15d
  shr    $0x2,%eax
  movslq %r12d,%r13
  mov    %r12d,%edx
  sub    $0x1,%eax
  shl    $0x2,%r13
  mov    %rax,0x8(%rsp)
  mov    %r14d,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x4(%rsp)
  lea    -0x2(%r14),%eax
  cmp    $0xffffffff,%eax
  mov    %eax,(%rsp)
  mov    $0x1,%eax
  cmovge %r14d,%eax
  mov    %eax,%ebx
  mov    %eax,0x18(%rsp)
  shr    $0x2,%eax
  and    $0xfffffffc,%ebx
  sub    $0x1,%eax
  sub    %ebx,%edx
  mov    %ebx,0x1c(%rsp)
  shl    $0x4,%rax
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rbx
  mov    %rbx,0x20(%rsp)
  lea    -0x1(%rdx),%ebx
  movslq %ebx,%rcx
  mov    %ebx,0x30(%rsp)
  lea    0x0(,%rcx,4),%rbx
  mov    %rbx,0x28(%rsp)
  lea    -0x2(%rdx),%ebx
  movslq %ebx,%rdx
  mov    %ebx,0x34(%rsp)
  lea    0x0(,%rdx,4),%rbx
  mov    $0xffffffffffffffe4,%rdx
  sub    %rax,%rdx
  mov    %rbx,0x38(%rsp)
  mov    $0x64,%ebx
  mov    %rdx,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  test   %r15d,%r15d
  movdqa D18(%rip),%xmm2
  mov    %rax,%rcx
  jle    L13
  cmp    $0x2,%r12d
  jbe    L26
  mov    0x8(%rsp),%rsi
  movdqa D8(%rip),%xmm0
  mov    %r14,%rax
  lea    0x1(%rsi),%rdx
  shl    $0x4,%rdx
  add    %r14,%rdx
  nopw   0x0(%rax,%rax,1)
L116:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L116
  mov    0x4(%rsp),%eax
  cmp    %eax,%r15d
  je     L148
L93:
  movslq %eax,%rdx
  mov    %eax,(%r14,%rdx,4)
  lea    0x0(,%rdx,4),%rsi
  lea    0x1(%rax),%edx
  cmp    %edx,%r15d
  jle    L148
  add    $0x2,%eax
  mov    %edx,0x4(%r14,%rsi,1)
  cmp    %eax,%r15d
  jle    L148
  mov    %eax,0x8(%r14,%rsi,1)
L148:
  lea    (%r14,%r13,1),%rdx
  lea    (%rcx,%r13,1),%rax
  lea    -0x4(%rdx),%rsi
  sub    %rsi,%rax
  add    $0x8,%rax
  cmp    $0x8,%rax
  jbe    L47
  mov    0x10(%rsp),%rdi
  cmp    $0x2,%r12d
  lea    -0xc(%rdx),%rax
  seta   %r11b
  cmpl   $0xffffffff,(%rsp)
  setge  %r10b
  lea    (%rdi,%rdx,1),%r8
  mov    %rcx,%rdi
  sub    %r14,%rdi
  test   %r10b,%r11b
  je     L47
  nopl   0x0(%rax)
L130:
  movdqu (%rax),%xmm3
  movups %xmm3,(%rdi,%rax,1)
  sub    $0x10,%rax
  cmp    %rax,%r8
  jne    L130
  mov    0x1c(%rsp),%esi
  cmp    %esi,0x18(%rsp)
  je     L61
  mov    0x20(%rsp),%rsi
  mov    0x30(%rsp),%edx
  mov    (%r14,%rsi,1),%eax
  mov    %eax,(%rcx,%rsi,1)
  test   %edx,%edx
  js     L61
  mov    0x28(%rsp),%rsi
  mov    (%r14,%rsi,1),%eax
  mov    %eax,(%rcx,%rsi,1)
  mov    0x34(%rsp),%eax
  test   %eax,%eax
  js     L61
  mov    0x38(%rsp),%rdi
  mov    (%r14,%rdi,1),%eax
  mov    %eax,(%rcx,%rdi,1)
L61:
  sub    $0x1,%ebx
  jne    L12
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  mov    %r12d,%eax
  sub    %r14,%rcx
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L154:
  sub    $0x4,%rsi
L86:
  mov    (%rdx),%edi
  sub    $0x1,%eax
  mov    %edi,(%rcx,%rdx,1)
  mov    %rsi,%rdx
  cmp    $0xffffffff,%eax
  jne    L154
  jmp    L61
  cs nopw 0x0(%rax,%rax,1)
L13:
  test   %r12d,%r12d
  js     L61
  jmp    L148
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  jmp    L93
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: byte[16]
name: retrieve_data
arguments: label: D8
datatype: byte[16]

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j, k, n;
  int *ip, *jp;
  if (argc == 1)
    n = 200000;
  else
    n = atoi(argv[1]);
  for (k = 0; k < 100; k++) {
    ip = (int *)malloc(n * sizeof(int));
    jp = (int *)malloc(n * sizeof(int));
    for (i = 0; i < n; i++)
      ip[i] = i;
    for (j = n - 1; j >= 0; j--)
      jp[j] = ip[j];
  }
  return 0;
}
```