ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<runDoWhileLoop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D28(%rip),%r12
L1:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jg     L1
  lea    D19(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D21: Do-While loop to %d [ 

tool: D28: %d 

tool: D19: ]

assistant: ```c
void runDoWhileLoop(int limit) {
  printf("Do-While loop to %d [ ", limit);
  int i = 0;
  do {
    printf("%d ", i);
    i++;
  } while (i < limit);
  printf("]\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<runDoWhileLoop>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D16(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D29(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L5
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D29
type: string
name: retrieve_data
arguments: data_label: D3
type: string

tool: D16: %d 

tool: D29: Do-While loop to %d [ 

tool: D3: ]

assistant: ```c
void runDoWhileLoop(int limit) {
  printf("Do-While loop to %d [ ", limit);
  int i = 0;
  do {
    printf("%d ", i);
    i++;
  } while (i < limit);
  printf("]\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<runDoWhileLoop>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D0(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D24(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L3
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D23
datatype: string

tool: D0: %d 

tool: D24: Do-While loop to %d [ 

tool: D23: ]

assistant: ```c
void runDoWhileLoop(int limit) {
  printf("Do-While loop to %d [ ", limit);
  int i = 0;
  do {
    printf("%d ", i);
    i++;
  } while (i < limit);
  printf("]\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hdmi_rd_reg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    $0xd0042000,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0xd0042000,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0xd0042004,%eax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hdmi_rd_reg(unsigned long addr) {
  unsigned long data;
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  data = (*(volatile unsigned long *)(0xd0040000 + (0x2004)));
  return (data);
}
```
user: What is the c source code of the assembly code below?

```asm
<hdmi_rd_reg>:
  endbr64
  mov    $0xd0042000,%eax
  mov    %rdi,(%rax)
  mov    %rdi,(%rax)
  movabs 0xd0042004,%rax
  ret
```

assistant: ```c
unsigned int hdmi_rd_reg(unsigned long addr) {
  unsigned long data;
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  data = (*(volatile unsigned long *)(0xd0040000 + (0x2004)));
  return (data);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hdmi_rd_reg>:
  endbr64
  mov    $0xd0042000,%eax
  mov    %rdi,(%rax)
  mov    %rdi,(%rax)
  movabs 0xd0042004,%rax
  ret
```

assistant: ```c
unsigned int hdmi_rd_reg(unsigned long addr) {
  unsigned long data;
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  data = (*(volatile unsigned long *)(0xd0040000 + (0x2004)));
  return (data);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hdmi_rd_reg>:
  endbr64
  mov    $0xd0042000,%eax
  mov    %rdi,(%rax)
  mov    %rdi,(%rax)
  movabs 0xd0042004,%rax
  ret
```

assistant: ```c
unsigned int hdmi_rd_reg(unsigned long addr) {
  unsigned long data;
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  (*(volatile unsigned long *)(0xd0040000 + (0x2000)) = addr);
  data = (*(volatile unsigned long *)(0xd0040000 + (0x2004)));
  return (data);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrixSubtractF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x30(%rbp)
  mov    %dx,-0x24(%rbp)
  mov    %ax,-0x28(%rbp)
  movw   $0x0,-0x4(%rbp)
  jmp    L10
L38:
  movw   $0x0,-0x2(%rbp)
  jmp    L17
L8:
  movswl -0x28(%rbp),%edx
  movswl -0x4(%rbp),%eax
  imul   %eax,%edx
  movswl -0x2(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movswl -0x28(%rbp),%edx
  movswl -0x4(%rbp),%eax
  imul   %eax,%edx
  movswl -0x2(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movswl -0x28(%rbp),%edx
  movswl -0x4(%rbp),%eax
  imul   %eax,%edx
  movswl -0x2(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L17:
  movzwl -0x2(%rbp),%eax
  cmp    -0x28(%rbp),%ax
  jl     L8
  movzwl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4(%rbp)
L10:
  movzwl -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%ax
  jl     L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixSubtractF(float *matrixA, float *matrixB, short numRowsA, short numColsA, float *matrixC) {
  short i, j;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsA; j++)
      matrixC[numColsA * i + j] = matrixA[numColsA * i + j] - matrixB[numColsA * i + j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixSubtractF>:
  endbr64
  push   %rbx
  mov    %edx,%r10d
  mov    %ecx,%r9d
  mov    $0x0,%ecx
  movswl %r9w,%ebx
  movzwl %r9w,%r11d
  test   %dx,%dx
  jg     L10
L11:
  pop    %rbx
  ret
L23:
  movswl %cx,%edx
  imul   %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  add    %r11,%rdx
  shl    $0x2,%rdx
L4:
  movss  (%rdi,%rax,1),%xmm0
  subss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
L3:
  lea    0x1(%rcx),%eax
  mov    %eax,%ecx
  cmp    %ax,%r10w
  jle    L11
L10:
  test   %r9w,%r9w
  jg     L23
  jmp    L3
```

assistant: ```c
void matrixSubtractF(float *matrixA, float *matrixB, short numRowsA, short numColsA, float *matrixC) {
  short i, j;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsA; j++)
      matrixC[numColsA * i + j] = matrixA[numColsA * i + j] - matrixB[numColsA * i + j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrixSubtractF>:
  endbr64
  test   %dx,%dx
  jle    L24
  push   %rbx
  movswl %cx,%ebx
  mov    %edx,%r10d
  xor    %ecx,%ecx
  mov    %ebx,%r9d
  movswq %bx,%r11
  nopl   0x0(%rax)
L13:
  test   %r9w,%r9w
  jle    L20
  movswl %cx,%edx
  imul   %ebx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  add    %r11,%rdx
  shl    $0x2,%rdx
  xchg   %ax,%ax
L0:
  movss  (%rdi,%rax,1),%xmm0
  subss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
L20:
  add    $0x1,%ecx
  cmp    %cx,%r10w
  jg     L13
  pop    %rbx
  ret
L24:
  ret
```

assistant: ```c
void matrixSubtractF(float *matrixA, float *matrixB, short numRowsA, short numColsA, float *matrixC) {
  short i, j;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsA; j++)
      matrixC[numColsA * i + j] = matrixA[numColsA * i + j] - matrixB[numColsA * i + j];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<matrixSubtractF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %dx,-0x18(%rsp)
  test   %dx,%dx
  jle    L83
  mov    %ecx,%ebp
  test   %cx,%cx
  jle    L83
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r11d
  and    $0xfffffffc,%ebp
  mov    %cx,-0x14(%rsp)
  mov    %ax,-0x16(%rsp)
  movswl %cx,%eax
  shr    $0x2,%r11w
  mov    %ecx,%r15d
  mov    %eax,-0x1c(%rsp)
  mov    %ecx,%eax
  sub    $0x1,%r11d
  xor    %ebx,%ebx
  sub    %ebp,%eax
  movzwl %r11w,%r11d
  mov    %ax,-0x12(%rsp)
  movzwl %cx,%eax
  add    $0x1,%r11
  mov    %rax,-0x10(%rsp)
  shl    $0x4,%r11
  nopl   0x0(%rax)
L89:
  movswl %bx,%ecx
  imul   -0x1c(%rsp),%ecx
  movslq %ecx,%r10
  lea    0x0(,%r10,4),%rax
  lea    (%r8,%rax,1),%r9
  lea    0x4(%rax),%rdx
  lea    (%rsi,%rdx,1),%r13
  mov    %r9,%r12
  lea    (%rdi,%rdx,1),%r14
  sub    %r13,%r12
  mov    %r9,%r13
  cmp    $0x8,%r12
  seta   %r12b
  sub    %r14,%r13
  cmp    $0x8,%r13
  seta   %r13b
  test   %r13b,%r12b
  je     L114
  cmp    $0x1,%r15w
  je     L114
  cmpw   $0x2,-0x16(%rsp)
  jbe    L86
  lea    (%rdi,%rax,1),%r12
  xor    %edx,%edx
  add    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L136:
  movups (%r12,%rdx,1),%xmm0
  movups (%rax,%rdx,1),%xmm2
  subps  %xmm2,%xmm0
  movups %xmm0,(%r9,%rdx,1)
  add    $0x10,%rdx
  cmp    %r11,%rdx
  jne    L136
  cmp    %bp,-0x14(%rsp)
  je     L75
  movzwl -0x12(%rsp),%eax
  mov    %eax,%r9d
  cmp    $0x1,%ax
  je     L103
  movzwl %bp,%edx
  mov    %ebp,%eax
L116:
  add    %r10,%rdx
  movq   (%rdi,%rdx,4),%xmm0
  movq   (%rsi,%rdx,4),%xmm1
  subps  %xmm1,%xmm0
  movlps %xmm0,(%r8,%rdx,4)
  mov    %r9d,%edx
  and    $0xfffffffe,%edx
  add    %edx,%eax
  cmp    %dx,%r9w
  je     L75
L78:
  cwtl
  add    %ecx,%eax
  cltq
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
L75:
  add    $0x1,%ebx
  cmp    %bx,-0x18(%rsp)
  jg     L89
L83:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L114:
  add    -0x10(%rsp),%r10
  shl    $0x2,%r10
  jmp    L106
  nopl   0x0(%rax,%rax,1)
L87:
  add    $0x4,%rdx
L106:
  movss  (%rdi,%rax,1),%xmm0
  subss  (%rsi,%rax,1),%xmm0
  movss  %xmm0,(%r8,%rax,1)
  mov    %rdx,%rax
  cmp    %r10,%rdx
  jne    L87
  jmp    L75
L86:
  movzwl -0x14(%rsp),%r9d
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L116
L103:
  mov    %ebp,%eax
  jmp    L78
```

assistant: ```c
void matrixSubtractF(float *matrixA, float *matrixB, short numRowsA, short numColsA, float *matrixC) {
  short i, j;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsA; j++)
      matrixC[numColsA * i + j] = matrixA[numColsA * i + j] - matrixB[numColsA * i + j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<countRoutes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <factorial@plt>
  cltq
  mov    %rax,-0x40(%rbp)
  sar    $0x3f,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x44(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <reducedFactorial@plt>
  cltq
  mov    %rax,%r12
  sar    $0x3f,%rax
  mov    %rax,%r13
  mov    %r12,%rcx
  mov    %r13,%rbx
  mov    %r12,%rax
  mov    %r13,%rdx
  mov    %rcx,%rsi
  mov    %rdx,%rax
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    %rsi,%rdi
  mov    %rax,%rsi
  call   <__udivti3>
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
unsigned __int128 countRoutes(int n) {
  unsigned __int128 nfac = factorial(n);
  unsigned __int128 routes = reducedFactorial(2 * n, n) / nfac;
  return routes;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<countRoutes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <factorial@plt>
  mov    %eax,%ebx
  lea    0x0(%rbp,%rbp,1),%edi
  mov    %ebp,%esi
  mov    $0x0,%eax
  call   <reducedFactorial@plt>
  movslq %eax,%rdi
  mov    %rdi,%rsi
  sar    $0x3f,%rsi
  movslq %ebx,%rdx
  mov    %rdx,%rcx
  sar    $0x3f,%rcx
  call   <__udivti3>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned __int128 countRoutes(int n) {
  unsigned __int128 nfac = factorial(n);
  unsigned __int128 routes = reducedFactorial(2 * n, n) / nfac;
  return routes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<countRoutes>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <factorial@plt>
  lea    0x0(%rbp,%rbp,1),%edi
  mov    %ebp,%esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <reducedFactorial@plt>
  movslq %ebx,%rdx
  movslq %eax,%rdi
  mov    %rdx,%rcx
  mov    %rdi,%rsi
  sar    $0x3f,%rcx
  sar    $0x3f,%rsi
  call   <__udivti3>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned __int128 countRoutes(int n) {
  unsigned __int128 nfac = factorial(n);
  unsigned __int128 routes = reducedFactorial(2 * n, n) / nfac;
  return routes;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<countRoutes>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <factorial@plt>
  lea    0x0(%rbp,%rbp,1),%edi
  mov    %ebp,%esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <reducedFactorial@plt>
  movslq %ebx,%rdx
  movslq %eax,%rdi
  mov    %rdx,%rcx
  mov    %rdi,%rsi
  sar    $0x3f,%rcx
  sar    $0x3f,%rsi
  call   <__udivti3>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned __int128 countRoutes(int n) {
  unsigned __int128 nfac = factorial(n);
  unsigned __int128 routes = reducedFactorial(2 * n, n) / nfac;
  return routes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_colors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0xb8000,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L17
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2,(%rax)
  addl   $0x2,-0xc(%rbp)
L17:
  cmpl   $0xf9f,-0xc(%rbp)
  jle    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_colors() {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  int i;
  for (i = 1; i < 25 * 80 * 2; i += 2)
    vidmem[i] = 0x02;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<set_colors>:
  endbr64
  mov    $0xb8001,%eax
L6:
  movb   $0x2,(%rax)
  add    $0x2,%rax
  cmp    $0xb8fa1,%rax
  jne    L6
  ret
```

assistant: ```c
void set_colors() {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  int i;
  for (i = 1; i < 25 * 80 * 2; i += 2)
    vidmem[i] = 0x02;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_colors>:
  endbr64
  mov    $0xb8001,%eax
  nopl   0x0(%rax)
L6:
  movb   $0x2,(%rax)
  add    $0x2,%rax
  cmp    $0xb8fa1,%rax
  jne    L6
  ret
```

assistant: ```c
void set_colors() {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  int i;
  for (i = 1; i < 25 * 80 * 2; i += 2)
    vidmem[i] = 0x02;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_colors>:
  endbr64
  mov    $0xb8001,%eax
  nopl   0x0(%rax)
L1:
  movb   $0x2,(%rax)
  add    $0x2,%rax
  cmp    $0xb8fa1,%rax
  jne    L1
  ret
```

assistant: ```c
void set_colors() {
  unsigned char *vidmem = (unsigned char *)0xb8000;
  int i;
  for (i = 1; i < 25 * 80 * 2; i += 2)
    vidmem[i] = 0x02;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<num_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x9,-0x14(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int num_len(int num) {
  int len = 1;
  for (; num >= 10; len++) {
    num /= 10;
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_len>:
  endbr64
  cmp    $0x9,%edi
  jle    L8
  mov    $0x1,%edx
L14:
  mov    %edi,%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edi
  add    $0x1,%edx
  cmp    $0x63,%ecx
  jg     L14
L22:
  mov    %edx,%eax
  ret
L8:
  mov    $0x1,%edx
  jmp    L22
```

assistant: ```c
int num_len(int num) {
  int len = 1;
  for (; num >= 10; len++) {
    num /= 10;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<num_len>:
  endbr64
  mov    $0x1,%r8d
  cmp    $0x9,%edi
  jle    L5
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L7:
  mov    %edi,%edi
  add    $0x1,%r8d
  mov    %rdi,%rax
  imul   %rdx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%eax
  jg     L7
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_len(int num) {
  int len = 1;
  for (; num >= 10; len++) {
    num /= 10;
  }
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_len>:
  endbr64
  mov    $0x1,%r8d
  cmp    $0x9,%edi
  jle    L18
  mov    $0xcccccccd,%edx
  nopl   0x0(%rax)
L9:
  mov    %edi,%edi
  add    $0x1,%r8d
  mov    %rdi,%rax
  imul   %rdx,%rdi
  shr    $0x23,%rdi
  cmp    $0x63,%eax
  jg     L9
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int num_len(int num) {
  int len = 1;
  for (; num >= 10; len++) {
    num /= 10;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__default_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L3:
  jmp    L3
```

assistant: ```c
__attribute__((noreturn, weak)) void __default_exit(void) {
  while (true) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__default_exit>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
__attribute__((noreturn, weak)) void __default_exit(void) {
  while (true) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__default_exit>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
__attribute__((noreturn, weak)) void __default_exit(void) {
  while (true) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__default_exit>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
__attribute__((noreturn, weak)) void __default_exit(void) {
  while (true) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RB_Trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
unsigned long RB_Trace(void *pUser, const char *aFormat, ...) {
  va_list list;
  va_start(list, aFormat);
  vprintf(aFormat, list);
  va_end(list);
  return (long)(((unsigned long)((0)) << 31) | (0));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RB_Trace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long RB_Trace(void *pUser, const char *aFormat, ...) {
  va_list list;
  va_start(list, aFormat);
  vprintf(aFormat, list);
  va_end(list);
  return (long)(((unsigned long)((0)) << 31) | (0));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RB_Trace>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long RB_Trace(void *pUser, const char *aFormat, ...) {
  va_list list;
  va_start(list, aFormat);
  vprintf(aFormat, list);
  va_end(list);
  return (long)(((unsigned long)((0)) << 31) | (0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RB_Trace>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long RB_Trace(void *pUser, const char *aFormat, ...) {
  va_list list;
  va_start(list, aFormat);
  vprintf(aFormat, list);
  va_end(list);
  return (long)(((unsigned long)((0)) << 31) | (0));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<txt_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %rdi,-0x1d8(%rbp)
  mov    %rsi,-0x1e0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L27
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L27:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x1e0(%rbp),%rdx
  mov    -0x1d0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x1d0(%rbp),%ecx
  mov    -0x1e0(%rbp),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x1d0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1cc(%rbp)
  mov    -0x1d8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x1cc(%rbp),%edx
  add    %edx,%eax
  cmp    $0xff,%eax
  jle    L15
  lea    D3(%rip),%rax
  mov    %rax,%rdx
  mov    $0x400,%esi
  mov    $0x0,%edi
  call   <err_log@plt>
L15:
  mov    -0x1d8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x1d8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x1c8(%rbp)
  mov    -0x1cc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x1c8(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: dns-sd text string too long.  Try a shorter share name.


assistant: ```c
void txt_add(char *txtrecord, char *fmt, ...) {
  va_list ap;
  char buff[256];
  int len;
  char *end;
  va_start(ap, fmt);
  vsnprintf(buff, sizeof(buff), fmt, ap);
  va_end(ap);
  len = (int)strlen(buff);
  if (len + strlen(txtrecord) > 255) {
    err_log(0, 0x00000400,
            "dns-sd text string too long.  Try a shorter "
            "share name.\n");
  }
  end = txtrecord + strlen(txtrecord);
  *end = len;
  strcpy(end + 1, buff);
}
```