user: 下面的汇编指令对应的C源代码是什么：

```asm
<lcs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    $0x8,%esi
  lea    0x1(%rax),%r15
  mov    %rax,0x10(%rsp)
  mov    %r15,%rdi
  call   <calloc@plt>
  mov    $0x8,%esi
  mov    %r15,%rdi
  mov    %rax,0x30(%rsp)
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %rax,0x28(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %r13d,%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  js     L20
  mov    0x10(%rsp),%r15d
  sub    $0x1,%r15d
  js     L20
  movslq 0xc(%rsp),%rax
  add    %rax,%rbx
  movslq %r15d,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L99:
  mov    0xc(%rsp),%ecx
  mov    0x18(%rsp),%r15
  lea    0x1(%rcx),%eax
  and    $0x1,%eax
  mov    0x30(%rsp,%rax,8),%r13
  mov    %ecx,%eax
  and    $0x1,%eax
  mov    0x30(%rsp,%rax,8),%r14
  xchg   %ax,%ax
L63:
  movzbl (%r12,%r15,1),%eax
  mov    0x0(%r13,%r15,8),%rdx
  xor    %edi,%edi
  mov    0x8(%r14,%r15,8),%rsi
  cmp    %al,(%rbx)
  sete   %dil
  add    0x8(%r13,%r15,8),%edi
  call   <max3@plt>
  mov    %rax,(%r14,%r15,8)
  sub    $0x1,%r15
  test   %r15d,%r15d
  jns    L63
  subl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  sub    $0x1,%rbx
  cmp    $0xffffffff,%eax
  jne    L99
L20:
  xor    %r15d,%r15d
  cmpq   $0x0,0x10(%rsp)
  mov    0x0(%rbp),%r13
  lea    D2(%rip),%rbx
  je     L17
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    0x0(%rbp,%r15,8),%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15,0x10(%rsp)
  jne    L62
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x20(%rsp),%rsi
  mov    %r13,%rdx
  xor    %eax,%eax
  test   %r13,%r13
  je     L3
  nopl   0x0(%rax,%rax,1)
L87:
  lea    -0x1(%rax),%rcx
  cmp    %rdx,0x0(%rbp,%rax,8)
  jne    L11
  nopl   0x0(%rax,%rax,1)
L81:
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rdx,0x0(%rbp,%rax,8)
  je     L81
L11:
  movzbl (%r12,%rcx,1),%ecx
  add    $0x1,%rsi
  mov    %cl,-0x1(%rsi)
  sub    $0x1,%rdx
  jne    L87
  add    %r13,0x20(%rsp)
L3:
  mov    0x20(%rsp),%rax
  mov    %rbp,%rdi
  movb   $0x0,(%rax)
  call   <free@plt>
  mov    0x28(%rsp),%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x58,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: %zd

assistant: ```c
size_t lcs(char *c, const char *a, const char *b) {
  size_t *m[2];
  size_t la = strlen(a);
  size_t lb = strlen(b);
  m[0] = calloc(lb + 1, sizeof(*m[0]));
  m[1] = calloc(lb + 1, sizeof(*m[1]));
  for (int yy = la - 1; yy >= 0; yy--) {
    for (int x = lb - 1; x >= 0; x--) {
      size_t y = yy % 2;
      size_t y1 = (yy + 1) % 2;
      m[y][x] = max3((a[yy] == b[x]) + m[y1][x + 1], m[y][x + 1], m[y1][x]);
    }
  }
  size_t ret = m[0][0];
  size_t v = ret;
  size_t i = 0;
  size_t j = 0;
  for (int d = 0; d < lb; d++) {
    printf("%zd", m[0][d]);
  }
  printf("\n");
  while (v > 0) {
    while (m[0][i] == v)
      i++;
    c[j++] = b[i - 1];
    v--;
  }
  c[j] = 0;
  free(m[0]);
  free(m[1]);
  return ret;
}
```