ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L27
  xchg   %ax,%ax
L11:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L27:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L11
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: n is %i 


assistant: ```c
main() {
  char buf[1024];
  int n;
  while ((n = read(0, buf, 1024)) > 0) {
    printf("n is %i \n", n);
    write(1, buf, n);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L13
  xchg   %ax,%ax
L1:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L13:
  mov    $0x400,%edx
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jg     L1
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: n is %i 


assistant: ```c
main() {
  char buf[1024];
  int n;
  while ((n = read(0, buf, 1024)) > 0) {
    printf("n is %i \n", n);
    write(1, buf, n);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_dash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <copy_string_adds_newline@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L14
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fileGetContents@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
char *get_dash_string(char **str) {
  char *s = *str;
  if (*s == '-')
    *str = copy_string_adds_newline(s + 1);
  else
    *str = fileGetContents(s);
  return *str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_dash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  cmpb   $0x2d,(%rdi)
  je     L11
  call   <fileGetContents@plt>
L18:
  mov    %rax,(%rbx)
  pop    %rbx
  ret
L11:
  add    $0x1,%rdi
  call   <copy_string_adds_newline@plt>
  jmp    L18
```

assistant: ```c
char *get_dash_string(char **str) {
  char *s = *str;
  if (*s == '-')
    *str = copy_string_adds_newline(s + 1);
  else
    *str = fileGetContents(s);
  return *str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_dash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  cmpb   $0x2d,(%rdi)
  je     L4
  call   <fileGetContents@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdi
  call   <copy_string_adds_newline@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
char *get_dash_string(char **str) {
  char *s = *str;
  if (*s == '-')
    *str = copy_string_adds_newline(s + 1);
  else
    *str = fileGetContents(s);
  return *str;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_dash_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  cmpb   $0x2d,(%rdi)
  je     L2
  call   <fileGetContents@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rdi
  call   <copy_string_adds_newline@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
char *get_dash_string(char **str) {
  char *s = *str;
  if (*s == '-')
    *str = copy_string_adds_newline(s + 1);
  else
    *str = fileGetContents(s);
  return *str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<EnleverFinMot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L19:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jle    L18
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L19
L18:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EnleverFinMot(char *pt_mot, int taille_mot) {
  int i = taille_mot;
  while (i > 0 && *(pt_mot + (i - 1)) == '\n') {
    i--;
    *(pt_mot + i) = '\0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EnleverFinMot>:
  endbr64
  test   %esi,%esi
  jle    L13
  movslq %esi,%rdx
  lea    -0x1(%rdi,%rdx,1),%rax
  lea    -0x2(%rdi,%rdx,1),%rdx
  lea    -0x1(%rsi),%ecx
  sub    %rcx,%rdx
L18:
  cmpb   $0xa,(%rax)
  jne    L13
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L13:
  ret
```

assistant: ```c
void EnleverFinMot(char *pt_mot, int taille_mot) {
  int i = taille_mot;
  while (i > 0 && *(pt_mot + (i - 1)) == '\n') {
    i--;
    *(pt_mot + i) = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<EnleverFinMot>:
  endbr64
  test   %esi,%esi
  jle    L25
  movslq %esi,%rdx
  lea    -0x1(%rsi),%ecx
  lea    -0x1(%rdi,%rdx,1),%rax
  lea    -0x2(%rdi,%rdx,1),%rdx
  sub    %rcx,%rdx
  jmp    L13
  nopl   (%rax)
L6:
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L13:
  cmpb   $0xa,(%rax)
  je     L6
L25:
  ret
```

assistant: ```c
void EnleverFinMot(char *pt_mot, int taille_mot) {
  int i = taille_mot;
  while (i > 0 && *(pt_mot + (i - 1)) == '\n') {
    i--;
    *(pt_mot + i) = '\0';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<EnleverFinMot>:
  endbr64
  test   %esi,%esi
  jle    L31
  movslq %esi,%rdx
  lea    -0x1(%rsi),%ecx
  lea    -0x1(%rdi,%rdx,1),%rax
  lea    -0x2(%rdi,%rdx,1),%rdx
  sub    %rcx,%rdx
  jmp    L23
  nopl   (%rax)
L12:
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  je     L31
L23:
  cmpb   $0xa,(%rax)
  je     L12
L31:
  ret
```

assistant: ```c
void EnleverFinMot(char *pt_mot, int taille_mot) {
  int i = taille_mot;
  while (i > 0 && *(pt_mot + (i - 1)) == '\n') {
    i--;
    *(pt_mot + i) = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_imap4_fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_imap4_vprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _imap4_fprintf(FILE *out, char const *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = _imap4_vprintf(out, format, ap);
  va_end(ap);
  return rv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_imap4_fprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <_imap4_vprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _imap4_fprintf(FILE *out, char const *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = _imap4_vprintf(out, format, ap);
  va_end(ap);
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_imap4_fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_imap4_vprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _imap4_fprintf(FILE *out, char const *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = _imap4_vprintf(out, format, ap);
  va_end(ap);
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_imap4_fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_imap4_vprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _imap4_fprintf(FILE *out, char const *format, ...) {
  va_list ap;
  int rv;
  va_start(ap, format);
  rv = _imap4_vprintf(out, format, ap);
  va_end(ap);
  return rv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getMyArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <srandomdev@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L1
L18:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,(%rbx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
L1:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *getMyArray(int count, int unique) {
  int *myArray;
  int halfCount, i;
  myArray = (int *)malloc(sizeof(int) * count);
  halfCount = count / 2;
  srandomdev();
  for (i = 0; i < halfCount; i++) {
    myArray[i] = random();
    myArray[count - i - 1] = myArray[i];
  }
  myArray[i] = unique;
  return myArray;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getMyArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r15d
  movslq %edi,%rbp
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %ebx,%r12d
  shr    $0x1f,%r12d
  add    %ebx,%r12d
  sar    %r12d
  mov    $0x0,%eax
  call   <srandomdev@plt>
  cmp    $0x1,%ebx
  jle    L13
  mov    %r14,%rbx
  lea    (%r14,%rbp,2),%rax
  mov    $0x0,%ebp
  lea    -0x4(%rax,%rax,1),%r13
L16:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,(%rbx)
  mov    %r13,%rdx
  sub    %rbx,%rdx
  mov    %eax,(%rdx)
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r12d
  jg     L16
  test   %r12d,%r12d
  mov    $0x1,%eax
  cmovle %eax,%r12d
L9:
  movslq %r12d,%r12
  mov    %r15d,(%r14,%r12,4)
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    $0x0,%r12d
  jmp    L9
```

assistant: ```c
int *getMyArray(int count, int unique) {
  int *myArray;
  int halfCount, i;
  myArray = (int *)malloc(sizeof(int) * count);
  halfCount = count / 2;
  srandomdev();
  for (i = 0; i < halfCount; i++) {
    myArray[i] = random();
    myArray[count - i - 1] = myArray[i];
  }
  myArray[i] = unique;
  return myArray;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMyArray>:
  endbr64
  push   %r15
  movslq %edi,%r15
  push   %r14
  lea    0x0(,%r15,4),%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sub    $0x8,%rsp
  sar    %ebx
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <srandomdev@plt>
  cmp    $0x1,%r15d
  jle    L29
  lea    (%r12,%r15,2),%rax
  mov    %r12,%r14
  xor    %r15d,%r15d
  lea    -0x4(%rax,%rax,1),%rbp
  nop
L12:
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <random@plt>
  mov    %rbp,%rdx
  sub    %r14,%rdx
  mov    %eax,(%r14)
  add    $0x4,%r14
  mov    %eax,(%rdx)
  cmp    %r15d,%ebx
  jg     L12
  mov    $0x1,%eax
  test   %ebx,%ebx
  cmovle %eax,%ebx
  movslq %ebx,%rbx
  lea    (%r12,%rbx,4),%rax
L24:
  mov    %r13d,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L29:
  mov    %r12,%rax
  jmp    L24
```

assistant: ```c
int *getMyArray(int count, int unique) {
  int *myArray;
  int halfCount, i;
  myArray = (int *)malloc(sizeof(int) * count);
  halfCount = count / 2;
  srandomdev();
  for (i = 0; i < halfCount; i++) {
    myArray[i] = random();
    myArray[count - i - 1] = myArray[i];
  }
  myArray[i] = unique;
  return myArray;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getMyArray>:
  endbr64
  push   %r15
  movslq %edi,%r15
  push   %r14
  lea    0x0(,%r15,4),%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sub    $0x8,%rsp
  sar    %ebx
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <srandomdev@plt>
  cmp    $0x1,%r15d
  jle    L28
  lea    (%r12,%r15,2),%rax
  mov    %r12,%r14
  xor    %r15d,%r15d
  lea    -0x4(%rax,%rax,1),%rbp
  nop
L25:
  xor    %eax,%eax
  add    $0x1,%r15d
  call   <random@plt>
  mov    %rbp,%rdx
  sub    %r14,%rdx
  mov    %eax,(%r14)
  add    $0x4,%r14
  mov    %eax,(%rdx)
  cmp    %r15d,%ebx
  jg     L25
  mov    $0x1,%eax
  test   %ebx,%ebx
  cmovle %eax,%ebx
  movslq %ebx,%rbx
  lea    (%r12,%rbx,4),%rax
L1:
  mov    %r13d,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L28:
  mov    %r12,%rax
  jmp    L1
```

assistant: ```c
int *getMyArray(int count, int unique) {
  int *myArray;
  int halfCount, i;
  myArray = (int *)malloc(sizeof(int) * count);
  halfCount = count / 2;
  srandomdev();
  for (i = 0; i < halfCount; i++) {
    myArray[i] = random();
    myArray[count - i - 1] = myArray[i];
  }
  myArray[i] = unique;
  return myArray;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fmt_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L42
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L20
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x24(%rbp),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x1,-0x4(%rbp)
  ja     L8
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L42:
  cmpl   $0x0,-0x20(%rbp)
  je     L34
  mov    -0x20(%rbp),%eax
  jmp    L22
L34:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
unsigned fmt_char(char *buffer, int ch, unsigned width, char pad) {
  unsigned i;
  if (buffer != 0) {
    for (i = width; i > 1; --i)
      *buffer++ = pad;
    *buffer = ch;
  }
  return width ? width : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fmt_char>:
  endbr64
  test   %rdi,%rdi
  je     L33
  cmp    $0x1,%edx
  jbe    L12
  lea    -0x1(%rdx),%eax
  add    %rdi,%rax
L23:
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  cmp    %rax,%rdi
  jne    L23
L29:
  mov    %sil,(%rax)
L33:
  test   %edx,%edx
  mov    $0x1,%eax
  cmovne %edx,%eax
  ret
L12:
  mov    %rdi,%rax
  jmp    L29
```

assistant: ```c
unsigned fmt_char(char *buffer, int ch, unsigned width, char pad) {
  unsigned i;
  if (buffer != 0) {
    for (i = width; i > 1; --i)
      *buffer++ = pad;
    *buffer = ch;
  }
  return width ? width : 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fmt_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %rdi,%rdi
  je     L4
  mov    %esi,%ebp
  cmp    $0x1,%edx
  jbe    L17
  lea    -0x1(%rdx),%r12d
  movsbl %cl,%esi
  mov    %r12,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %r12,%rdi
L17:
  mov    %bpl,(%rdi)
L4:
  test   %ebx,%ebx
  mov    $0x1,%eax
  cmovne %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned fmt_char(char *buffer, int ch, unsigned width, char pad) {
  unsigned i;
  if (buffer != 0) {
    for (i = width; i > 1; --i)
      *buffer++ = pad;
    *buffer = ch;
  }
  return width ? width : 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fmt_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %rdi,%rdi
  je     L16
  mov    %esi,%ebp
  cmp    $0x1,%edx
  jbe    L4
  lea    -0x1(%rdx),%r12d
  movsbl %cl,%esi
  mov    %r12,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %r12,%rdi
L4:
  mov    %bpl,(%rdi)
L16:
  test   %ebx,%ebx
  mov    $0x1,%eax
  cmovne %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned fmt_char(char *buffer, int ch, unsigned width, char pad) {
  unsigned i;
  if (buffer != 0) {
    for (i = width; i > 1; --i)
      *buffer++ = pad;
    *buffer = ch;
  }
  return width ? width : 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun>:
  endbr64
  sub    $0x38,%rsp
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rdx
  sar    $0x25,%rdx
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  mov    %edx,(%rsp)
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %r8d,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %eax,%r8d
  sub    %edx,%r8d
  mov    %r8d,0x4(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  mov    %edi,0x8(%rsp)
  movslq %esi,%rax
  imul   $0x51eb851f,%rax,%rdx
  sar    $0x25,%rdx
  mov    %esi,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  mov    %edx,0xc(%rsp)
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edi,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %eax,%edi
  sub    %edx,%edi
  mov    %edi,0x10(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  mov    %esi,0x14(%rsp)
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rdx
  sar    $0x25,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  mov    %edx,0x18(%rsp)
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %esi,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %eax,%esi
  sub    %edx,%esi
  mov    %esi,0x1c(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,0x20(%rsp)
  mov    %rsp,%rsi
  mov    %rsi,%r9
  mov    $0x1,%r10d
  add    $0x20,%rsi
L48:
  cmp    $0x8,%r10d
  jg     L51
  mov    (%r9),%edi
  test   %edi,%edi
  sete   %r8b
  mov    %r9,%rax
L68:
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edi
  sete   %dl
  test   %ecx,%ecx
  sete   %cl
  or     %cl,%dl
  jne    L63
  test   %r8b,%r8b
  jne    L63
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L68
L51:
  add    $0x1,%r10
  add    $0x4,%r9
  cmp    $0x9,%r10
  jne    L48
  mov    $0x1,%eax
  jmp    L54
L63:
  mov    $0x0,%eax
L54:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x38,%rsp
  ret
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fun(int a, int b, int c) {
  int x[9], i, j;
  x[0] = a / 100;
  x[1] = a / 10 % 10;
  x[2] = a % 10;
  x[3] = b / 100;
  x[4] = b / 10 % 10;
  x[5] = b % 10;
  x[6] = c / 100;
  x[7] = c / 10 % 10;
  x[8] = c % 10;
  for (i = 0; i < 8; i++)
    for (j = i + 1; j < 9; j++) {
      if (x[i] == x[j])
        return 0;
      if (x[i] == 0)
        return 0;
      if (x[j] == 0)
        return 0;
    }
  return 1;
}
```