ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<nlopt_compute_rescaling>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  shl    $0x3,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L119
  test   %ebp,%ebp
  je     L119
  cmp    $0x1,%ebp
  je     L68
  mov    %ebp,%edx
  movapd D12(%rip),%xmm0
  shr    %edx
  shl    $0x4,%rdx
  add    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L73:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L73
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bpl
  je     L112
L97:
  mov    D12(%rip),%rsi
  mov    %rsi,(%r8,%rax,8)
L112:
  cmp    $0x1,%ebp
  je     L119
  movsd  (%rbx),%xmm2
  lea    -0x2(%rbp),%edi
  mov    %ebp,%edx
  mov    $0x1,%eax
  movapd %xmm2,%xmm0
  jmp    L126
  nop
L9:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L119
L126:
  movapd %xmm0,%xmm1
  movsd  (%rbx,%rax,8),%xmm0
  mov    %eax,%ecx
  ucomisd %xmm1,%xmm0
  jp     L74
  je     L9
L74:
  cmp    %ebp,%ecx
  jae    L119
  lea    (%r8,%rdx,8),%rdx
  lea    0x8(%r8),%rcx
  cmp    %rdx,%rbx
  lea    0x8(%rbx),%r9
  lea    -0x1(%rbp),%esi
  mov    %rcx,%rax
  setae  %dl
  cmp    %r9,%rcx
  setae  %r9b
  or     %r9b,%dl
  je     L53
  lea    0x10(%rbx),%rdx
  cmp    %rdx,%rcx
  setne  %r9b
  cmp    $0x2,%ebp
  setne  %dl
  test   %dl,%r9b
  je     L53
  mov    %esi,%edx
  movapd %xmm2,%xmm1
  shr    %edx
  unpcklpd %xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%r8,%rdx,1),%rcx
  mov    %rbx,%rdx
  sub    %r8,%rdx
L160:
  movupd (%rax,%rdx,1),%xmm0
  add    $0x10,%rax
  divpd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rcx
  jne    L160
  mov    %esi,%eax
  or     $0x1,%eax
  and    $0x1,%esi
  je     L119
  movsd  (%rbx,%rax,8),%xmm0
  divsd  (%rbx),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
L119:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L68:
  xor    %eax,%eax
  jmp    L97
L53:
  mov    %rbx,%rax
  lea    0x10(%r8,%rdi,8),%rdx
  sub    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L156:
  movsd  (%rax,%rcx,1),%xmm0
  add    $0x8,%rcx
  divsd  (%rbx),%xmm0
  movsd  %xmm0,-0x8(%rcx)
  cmp    %rcx,%rdx
  jne    L156
  jmp    L119
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: f64[2]

tool: {"D12": [1.0,1.0]}

assistant: ```c
double *nlopt_compute_rescaling(unsigned n, const double *dx) {
  double *s = (double *)malloc(sizeof(double) * n);
  unsigned i;
  if (!s)
    return NULL;
  for (i = 0; i < n; ++i)
    s[i] = 1.0;
  if (n == 1)
    return s;
  for (i = 1; i < n && dx[i] == dx[i - 1]; ++i)
    ;
  if (i < n) {
    for (i = 1; i < n; ++i)
      s[i] = dx[i] / dx[0];
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<old_str_extract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L97
  cmpq   $0x0,-0x40(%rbp)
  je     L97
  cmpq   $0x0,-0x28(%rbp)
  je     L97
  movl   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L111
L24:
  addq   $0x1,-0x18(%rbp)
L111:
  mov    -0x10(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L29
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L29:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L35
  mov    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L87
L72:
  addl   $0x1,-0x20(%rbp)
L87:
  mov    -0x8(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L128
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
L128:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L114
  mov    -0x20(%rbp),%eax
  cltq
  neg    %rax
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L78
L97:
  nop
  jmp    L78
L35:
  nop
  jmp    L78
L114:
  nop
L78:
  leave
  ret
```

assistant: ```c
void old_str_extract(const char *input, char *output, const char *start, const char *end) {
  if (!start || !end || !input)
    return;
  int i = 0, tmp;
  char *proc = (char *)input;
  size_t stl = strlen(start);
  size_t edl = strlen(end);
  while ((tmp = strncmp(proc, start, stl)) && *proc)
    proc++;
  if (tmp)
    return;
  proc += stl;
  while ((tmp = strncmp(proc, end, edl)) && *proc++)
    i++;
  if (tmp)
    return;
  proc -= i;
  strncpy(output, proc, i);
  output[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<old_str_extract>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rcx,%rcx
  sete   %al
  test   %rdi,%rdi
  sete   %dl
  or     %dl,%al
  jne    L1
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rcx,%r12
  test   %r13,%r13
  je     L1
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  jmp    L97
L29:
  add    $0x1,%rbp
L97:
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L91
  cmpb   $0x0,0x0(%rbp)
  jne    L29
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L91:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  add    %r15,%rbp
  jmp    L58
L35:
  add    $0x1,%ebx
L58:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L68
  add    $0x1,%rbp
  cmpb   $0x0,-0x1(%rbp)
  jne    L35
  jmp    L1
L68:
  movslq %ebx,%r12
  mov    %rbp,%rsi
  sub    %r12,%rsi
  mov    %ebx,%edx
  mov    %r14,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%r12,1)
  jmp    L1
```

assistant: ```c
void old_str_extract(const char *input, char *output, const char *start, const char *end) {
  if (!start || !end || !input)
    return;
  int i = 0, tmp;
  char *proc = (char *)input;
  size_t stl = strlen(start);
  size_t edl = strlen(end);
  while ((tmp = strncmp(proc, start, stl)) && *proc)
    proc++;
  if (tmp)
    return;
  proc += stl;
  while ((tmp = strncmp(proc, end, edl)) && *proc++)
    i++;
  if (tmp)
    return;
  proc -= i;
  strncpy(output, proc, i);
  output[i] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<old_str_extract>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  sete   %al
  test   %rdi,%rdi
  sete   %dl
  or     %dl,%al
  jne    L49
  test   %r14,%r14
  je     L49
  mov    %rdi,%rbx
  mov    %r14,%rdi
  mov    %rsi,%r13
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %rax,%r15
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L17:
  cmpb   $0x0,(%rbx)
  je     L49
  add    $0x1,%rbx
L13:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L17
  mov    %rbp,%rdi
  add    %r15,%rbx
  call   <strlen@plt>
  mov    %rax,%r14
  jmp    L27
  xchg   %ax,%ax
L50:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L49
  add    $0x1,%r12d
L27:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L50
  movslq %r12d,%rbp
  mov    %rbx,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  sub    %rbp,%rsi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void old_str_extract(const char *input, char *output, const char *start, const char *end) {
  if (!start || !end || !input)
    return;
  int i = 0, tmp;
  char *proc = (char *)input;
  size_t stl = strlen(start);
  size_t edl = strlen(end);
  while ((tmp = strncmp(proc, start, stl)) && *proc)
    proc++;
  if (tmp)
    return;
  proc += stl;
  while ((tmp = strncmp(proc, end, edl)) && *proc++)
    i++;
  if (tmp)
    return;
  proc -= i;
  strncpy(output, proc, i);
  output[i] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<old_str_extract>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  sete   %al
  test   %rdi,%rdi
  sete   %dl
  or     %dl,%al
  jne    L26
  test   %r14,%r14
  je     L26
  mov    %rdi,%rbx
  mov    %r14,%rdi
  mov    %rsi,%r13
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %rax,%r15
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L29:
  cmpb   $0x0,(%rbx)
  je     L26
  add    $0x1,%rbx
L33:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L29
  mov    %rbp,%rdi
  add    %r15,%rbx
  call   <strlen@plt>
  mov    %rax,%r14
  jmp    L10
  xchg   %ax,%ax
L44:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L26
  add    $0x1,%r12d
L10:
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L44
  movslq %r12d,%rbp
  mov    %rbx,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  sub    %rbp,%rsi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void old_str_extract(const char *input, char *output, const char *start, const char *end) {
  if (!start || !end || !input)
    return;
  int i = 0, tmp;
  char *proc = (char *)input;
  size_t stl = strlen(start);
  size_t edl = strlen(end);
  while ((tmp = strncmp(proc, start, stl)) && *proc)
    proc++;
  if (tmp)
    return;
  proc += stl;
  while ((tmp = strncmp(proc, end, edl)) && *proc++)
    i++;
  if (tmp)
    return;
  proc -= i;
  strncpy(output, proc, i);
  output[i] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inet_net_ntop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  jne    L17
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <inet_net_ntop_ipv4@plt>
  jmp    L0
L17:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
char *inet_net_ntop(int af, const void *src, int bits, char *dst, size_t size) {
  switch (af) {
  case AF_INET:
    return (inet_net_ntop_ipv4(src, bits, dst, size));
  default:
    __set_errno(EAFNOSUPPORT);
    return (NULL);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inet_net_ntop>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x80,%edi
  jne    L19
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  call   <inet_net_ntop_ipv4@plt>
L7:
  add    $0x8,%rsp
  ret
L19:
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
char *inet_net_ntop(int af, const void *src, int bits, char *dst, size_t size) {
  switch (af) {
  case AF_INET:
    return (inet_net_ntop_ipv4(src, bits, dst, size));
  default:
    __set_errno(EAFNOSUPPORT);
    return (NULL);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inet_net_ntop>:
  endbr64
  cmp    $0x80,%edi
  jne    L4
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  jmp    1070 <inet_net_ntop_ipv4@plt>
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *inet_net_ntop(int af, const void *src, int bits, char *dst, size_t size) {
  switch (af) {
  case AF_INET:
    return (inet_net_ntop_ipv4(src, bits, dst, size));
  default:
    __set_errno(EAFNOSUPPORT);
    return (NULL);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inet_net_ntop>:
  endbr64
  cmp    $0x80,%edi
  jne    L7
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  jmp    1070 <inet_net_ntop_ipv4@plt>
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *inet_net_ntop(int af, const void *src, int bits, char *dst, size_t size) {
  switch (af) {
  case AF_INET:
    return (inet_net_ntop_ipv4(src, bits, dst, size));
  default:
    __set_errno(EAFNOSUPPORT);
    return (NULL);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D45
datatype: string

tool: D25: Two values to swap:

tool: D3: %d

tool: D45: %d %d


assistant: ```c
int main() {
  int swap_tmp, a, b;
  printf("Two values to swap:");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("%d %d\n", a, b);
  swap_tmp = (int)a;
  a = (int)b;
  b = swap_tmp;
  printf("%d %d\n", a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D2
type_infered: string
name: disassemble_data
arguments: label: D26
type_infered: string

tool: D19: Two values to swap:

tool: D2: %d

tool: D26: %d %d


assistant: ```c
int main() {
  int swap_tmp, a, b;
  printf("Two values to swap:");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("%d %d\n", a, b);
  swap_tmp = (int)a;
  a = (int)b;
  b = swap_tmp;
  printf("%d %d\n", a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D6(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: string
name: parse_data
arguments: label: D6
type_guessed: string
name: parse_data
arguments: label: D15
type_guessed: string

tool: D13: Two values to swap:

tool: D6: %d

tool: D15: %d %d


assistant: ```c
int main() {
  int swap_tmp, a, b;
  printf("Two values to swap:");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("%d %d\n", a, b);
  swap_tmp = (int)a;
  a = (int)b;
  b = swap_tmp;
  printf("%d %d\n", a, b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D11(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string

tool: D25: Two values to swap:

tool: D11: %d

tool: D19: %d %d


assistant: ```c
int main() {
  int swap_tmp, a, b;
  printf("Two values to swap:");
  scanf("%d", &a);
  scanf("%d", &b);
  printf("%d %d\n", a, b);
  swap_tmp = (int)a;
  a = (int)b;
  b = swap_tmp;
  printf("%d %d\n", a, b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<untab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L27
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L9:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void untab(s) char *s;
{
  while (*s) {
    if (*s == 9)
      *s = 32;
    s++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<untab>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
L32:
  ret
L17:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
L0:
  cmp    $0x9,%al
  jne    L17
  movb   $0x20,(%rdi)
  jmp    L17
```

assistant: ```c
void untab(s) char *s;
{
  while (*s) {
    if (*s == 9)
      *s = 32;
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<untab>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L25:
  cmp    $0x9,%al
  jne    L8
  movb   $0x20,(%rdi)
L8:
  add    $0x1,%rdi
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L25
  ret
```

assistant: ```c
void untab(s) char *s;
{
  while (*s) {
    if (*s == 9)
      *s = 32;
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<untab>:
  endbr64
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x1,%rdi
L5:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
L7:
  cmp    $0x9,%al
  jne    L11
  movb   $0x20,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L7
  ret
  nop
L21:
  ret
```

assistant: ```c
void untab(s) char *s;
{
  while (*s) {
    if (*s == 9)
      *s = 32;
    s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mfm_subs_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L47
L7:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jne    L16
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  jmp    L56
L16:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L24
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x25,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x66,(%rax)
  jmp    L56
L24:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
L56:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x10(%rbp)
L47:
  mov    -0x10(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: %f

assistant: ```c
void mfm_subs_write(char *dest, char *orig, char *files) {
  int files_len = strlen(files);
  char *prev = orig;
  char *next;
  while (next = strstr(prev, "%f")) {
    if (next == orig) {
      strcpy(dest, files);
      dest += files_len;
    } else if (next[-1] == '%') {
      int delta = next - 1 - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      *dest++ = '%';
      *dest++ = 'f';
    } else {
      int delta = next - prev;
      memcpy(dest, prev, delta);
      dest += delta;
      strcpy(dest, files);
      dest += files_len;
    }
    prev = next + 2;
  }
  strcpy(dest, prev);
}
```