ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rsi
  mov    $0x7,%edi
  call   <unquote@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <unquote2@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D27
type: string
name: unpack_data
arguments: data_tag: D29
type: string

tool: D6: a + 5 > 20

tool: D27: Result is %d 


tool: D29: 7 + 5 > 20

assistant: ```c
int main(void) {
  printf("Result is %d \n", unquote(7, "a + 5 > 20"));
  printf("Result is %d \n", unquote2("7 + 5 > 20"));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  mov    $0x7,%edi
  lea    D18(%rip),%rbp
  call   <unquote@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <unquote2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D18
datatype: string
name: parse_data
arguments: label: D25
datatype: string

tool: D10: a + 5 > 20

tool: D18: Result is %d 


tool: D25: 7 + 5 > 20

assistant: ```c
int main(void) {
  printf("Result is %d \n", unquote(7, "a + 5 > 20"));
  printf("Result is %d \n", unquote2("7 + 5 > 20"));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rsi
  mov    $0x7,%edi
  lea    D16(%rip),%rbp
  call   <unquote@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <unquote2@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D20
type: string
name: disassemble_data
arguments: label: D16
type: string
name: disassemble_data
arguments: label: D22
type: string

tool: D20: a + 5 > 20

tool: D16: Result is %d 


tool: D22: 7 + 5 > 20

assistant: ```c
int main(void) {
  printf("Result is %d \n", unquote(7, "a + 5 > 20"));
  printf("Result is %d \n", unquote2("7 + 5 > 20"));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movw   $0x7,-0x2(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test() {
  void *vp;
  int *ip;
  char *cp;
  struct foo *fp;
  struct bar *bp;
  short sint = 7;
  if (ip < cp) {
  }
  if (cp < fp) {
  }
  if (fp < bp) {
  }
  if (ip < 7) {
  }
  if (sint < ip) {
  }
  if (ip == cp) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test() {
  void *vp;
  int *ip;
  char *cp;
  struct foo *fp;
  struct bar *bp;
  short sint = 7;
  if (ip < cp) {
  }
  if (cp < fp) {
  }
  if (fp < bp) {
  }
  if (ip < 7) {
  }
  if (sint < ip) {
  }
  if (ip == cp) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  ret
```

assistant: ```c
void test() {
  void *vp;
  int *ip;
  char *cp;
  struct foo *fp;
  struct bar *bp;
  short sint = 7;
  if (ip < cp) {
  }
  if (cp < fp) {
  }
  if (fp < bp) {
  }
  if (ip < 7) {
  }
  if (sint < ip) {
  }
  if (ip == cp) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ber_fprintf_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%rax
  lea    D69(%rip),%r8
  mov    $0x67,%ecx
  mov    $0x40,%edx
  lea    D52(%rip),%rsi
  mov    %rax,%rdi
  call   <ber_fprintf@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x2,%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <hexdump@plt>
  lea    -0x20(%rbp),%rsi
  lea    -0x24(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rsi,%r8
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  call   <ber_sscanf@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  cmp    %rax,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%eax
  cmp    $0x40,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  cmp    $0x67,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D38
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D69
type_infered: string
name: read_data
arguments: data_label: D52
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string
name: read_data
arguments: data_label: D54
type_infered: string

tool: D38: # Testing fprintf syntax-like coding.


tool: D28: ber_fprintf("%%u%%u%%s", 64, 103, "testing_strings_123")

tool: D69: testing_strings_123

tool: D52: %u%u%s

tool: 

tool: D13: %u%u%ms

tool: D54: 


assistant: ```c
void ber_fprintf_test(uint8_t *buf, uint8_t *buf_end) {
  uint8_t *enc_out, *dec_out;
  uint32_t num1, num2;
  char *str = NULL;
  printf("# Testing fprintf syntax-like coding.\n");
  printf("ber_fprintf(\"%%u%%u%%s\", 64, 103, \"testing_strings_123\")");
  enc_out = ber_fprintf(buf_end, "%u%u%s", 64, 103, "testing_strings_123");
  hexdump("", enc_out + 1, buf_end - enc_out);
  dec_out = ber_sscanf(enc_out, "%u%u%ms", &num1, &num2, &str);
  assert(dec_out == buf_end + 1);
  assert(num1 == 64);
  assert(num2 == 103);
  assert(strcmp("testing_strings_123", str) <= 0);
  free(str);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ber_fprintf_test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  lea    D76(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%r8
  mov    $0x67,%ecx
  mov    $0x40,%edx
  lea    D77(%rip),%rsi
  mov    %rbx,%rdi
  call   <ber_fprintf@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  sub    %rax,%rdx
  sar    $0x2,%rdx
  lea    0x4(%rax),%rsi
  lea    D9(%rip),%rdi
  call   <hexdump@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D68(%rip),%rsi
  mov    %rbp,%rdi
  call   <ber_sscanf@plt>
  add    $0x4,%rbx
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x40,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x67,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x10(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D76
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string
name: disassemble_data
arguments: data_label: D77
data_type: string
name: disassemble_data
arguments: data_label: D9
data_type: string
name: disassemble_data
arguments: data_label: D68
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string

tool: D76: # Testing fprintf syntax-like coding.


tool: D5: ber_fprintf("%%u%%u%%s", 64, 103, "testing_strings_123")

tool: D35: testing_strings_123

tool: D77: %u%u%s

tool: 

tool: D68: %u%u%ms

tool: D29: 


assistant: ```c
void ber_fprintf_test(uint8_t *buf, uint8_t *buf_end) {
  uint8_t *enc_out, *dec_out;
  uint32_t num1, num2;
  char *str = NULL;
  printf("# Testing fprintf syntax-like coding.\n");
  printf("ber_fprintf(\"%%u%%u%%s\", 64, 103, \"testing_strings_123\")");
  enc_out = ber_fprintf(buf_end, "%u%u%s", 64, 103, "testing_strings_123");
  hexdump("", enc_out + 1, buf_end - enc_out);
  dec_out = ber_sscanf(enc_out, "%u%u%ms", &num1, &num2, &str);
  assert(dec_out == buf_end + 1);
  assert(num1 == 64);
  assert(num2 == 103);
  assert(strcmp("testing_strings_123", str) <= 0);
  free(str);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ber_fprintf_test>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%r8
  mov    $0x67,%ecx
  mov    %rbx,%rdi
  mov    $0x40,%edx
  lea    D41(%rip),%rsi
  call   <ber_fprintf@plt>
  mov    %rbx,%rdx
  lea    D33(%rip),%rdi
  add    $0x4,%rbx
  sub    %rax,%rdx
  mov    %rax,%rbp
  lea    0x4(%rax),%rsi
  sar    $0x2,%rdx
  call   <hexdump@plt>
  lea    0xc(%rsp),%rcx
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D72(%rip),%rsi
  call   <ber_sscanf@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x40,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x67,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rsi
  lea    D52(%rip),%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setle  %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D52
type_infered: string
name: retrieve_data
arguments: tag: D41
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D72
type_infered: string
name: retrieve_data
arguments: tag: D15
type_infered: string

tool: D14: # Testing fprintf syntax-like coding.


tool: D16: ber_fprintf("%%u%%u%%s", 64, 103, "testing_strings_123")

tool: D52: testing_strings_123

tool: D41: %u%u%s

tool: 

tool: D72: %u%u%ms

tool: D15: 


assistant: ```c
void ber_fprintf_test(uint8_t *buf, uint8_t *buf_end) {
  uint8_t *enc_out, *dec_out;
  uint32_t num1, num2;
  char *str = NULL;
  printf("# Testing fprintf syntax-like coding.\n");
  printf("ber_fprintf(\"%%u%%u%%s\", 64, 103, \"testing_strings_123\")");
  enc_out = ber_fprintf(buf_end, "%u%u%s", 64, 103, "testing_strings_123");
  hexdump("", enc_out + 1, buf_end - enc_out);
  dec_out = ber_sscanf(enc_out, "%u%u%ms", &num1, &num2, &str);
  assert(dec_out == buf_end + 1);
  assert(num1 == 64);
  assert(num2 == 103);
  assert(strcmp("testing_strings_123", str) <= 0);
  free(str);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ber_fprintf_test>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%r8
  mov    $0x67,%ecx
  mov    %rbx,%rdi
  mov    $0x40,%edx
  lea    D7(%rip),%rsi
  call   <ber_fprintf@plt>
  mov    %rbx,%rdx
  lea    D77(%rip),%rdi
  add    $0x4,%rbx
  sub    %rax,%rdx
  mov    %rax,%rbp
  lea    0x4(%rax),%rsi
  sar    $0x2,%rdx
  call   <hexdump@plt>
  lea    0xc(%rsp),%rcx
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D61(%rip),%rsi
  call   <ber_sscanf@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x40,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x67,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setle  %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D44
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D77
datatype: string
name: unpack_data
arguments: data_label: D61
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string

tool: D40: # Testing fprintf syntax-like coding.


tool: D4: ber_fprintf("%%u%%u%%s", 64, 103, "testing_strings_123")

tool: D44: testing_strings_123

tool: D7: %u%u%s

tool: 

tool: D61: %u%u%ms

tool: D10: 


assistant: ```c
void ber_fprintf_test(uint8_t *buf, uint8_t *buf_end) {
  uint8_t *enc_out, *dec_out;
  uint32_t num1, num2;
  char *str = NULL;
  printf("# Testing fprintf syntax-like coding.\n");
  printf("ber_fprintf(\"%%u%%u%%s\", 64, 103, \"testing_strings_123\")");
  enc_out = ber_fprintf(buf_end, "%u%u%s", 64, 103, "testing_strings_123");
  hexdump("", enc_out + 1, buf_end - enc_out);
  dec_out = ber_sscanf(enc_out, "%u%u%ms", &num1, &num2, &str);
  assert(dec_out == buf_end + 1);
  assert(num1 == 64);
  assert(num2 == 103);
  assert(strcmp("testing_strings_123", str) <= 0);
  free(str);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<convertEscapedChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x74,-0x4(%rbp)
  je     L34
  cmpl   $0x74,-0x4(%rbp)
  jg     L80
  cmpl   $0x6e,-0x4(%rbp)
  je     L53
  cmpl   $0x6e,-0x4(%rbp)
  jg     L80
  cmpl   $0x22,-0x4(%rbp)
  je     L109
  cmpl   $0x5c,-0x4(%rbp)
  je     L9
  jmp    L80
L53:
  mov    $0xa,%eax
  jmp    L92
L34:
  mov    $0x9,%eax
  jmp    L92
L109:
  mov    $0x22,%eax
  jmp    L92
L9:
  mov    $0x5c,%eax
  jmp    L92
L80:
  mov    -0x4(%rbp),%eax
L92:
  pop    %rbp
  ret
```

assistant: ```c
char convertEscapedChar(int ch) {
  switch (ch) {
  case 'n':
    return '\n';
  case 't':
    return '\t';
  case '"':
    return '\"';
  case '\\':
    return '\\';
  }
  return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convertEscapedChar>:
  endbr64
  cmp    $0x6e,%edi
  je     L47
  jg     L1
  mov    $0x22,%eax
  cmp    $0x22,%edi
  je     L19
  cmp    $0x5c,%edi
  jne    L41
  mov    $0x5c,%eax
L19:
  ret
L1:
  mov    $0x9,%eax
  cmp    $0x74,%edi
  je     L19
L41:
  mov    %edi,%eax
  ret
L47:
  mov    $0xa,%eax
  ret
```

assistant: ```c
char convertEscapedChar(int ch) {
  switch (ch) {
  case 'n':
    return '\n';
  case 't':
    return '\t';
  case '"':
    return '\"';
  case '\\':
    return '\\';
  }
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convertEscapedChar>:
  endbr64
  cmp    $0x6e,%edi
  je     L30
  jg     L40
  mov    $0x22,%eax
  cmp    $0x22,%edi
  je     L8
  cmp    $0x5c,%edi
  jne    L3
  mov    $0x5c,%eax
L8:
  ret
L40:
  mov    $0x9,%eax
  cmp    $0x74,%edi
  je     L8
L3:
  mov    %edi,%eax
  ret
  nopl   (%rax)
L30:
  mov    $0xa,%eax
  ret
```

assistant: ```c
char convertEscapedChar(int ch) {
  switch (ch) {
  case 'n':
    return '\n';
  case 't':
    return '\t';
  case '"':
    return '\"';
  case '\\':
    return '\\';
  }
  return ch;
}
```
user: What is the c source code of the assembly code below:

```asm
<convertEscapedChar>:
  endbr64
  cmp    $0x6e,%edi
  je     L32
  jg     L4
  mov    $0x22,%eax
  cmp    $0x22,%edi
  je     L45
  cmp    $0x5c,%edi
  jne    L27
  mov    $0x5c,%eax
L45:
  ret
L4:
  mov    $0x9,%eax
  cmp    $0x74,%edi
  je     L45
L27:
  mov    %edi,%eax
  ret
  nopl   (%rax)
L32:
  mov    $0xa,%eax
  ret
```

assistant: ```c
char convertEscapedChar(int ch) {
  switch (ch) {
  case 'n':
    return '\n';
  case 't':
    return '\t';
  case '"':
    return '\"';
  case '\\':
    return '\\';
  }
  return ch;
}
```
user: What is the c source code of the assembly code below:

```asm
<readblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L7
L53:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L55
  cmpq   $0x0,-0x8(%rbp)
  jne    L55
  mov    $0x0,%eax
  jmp    L40
L55:
  cmpq   $0x0,-0x18(%rbp)
  jne    L107
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D5(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffffffffffff,%rax
  jmp    L40
L107:
  cmpq   $0xffffffffffffffff,-0x18(%rbp)
  jne    L52
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D38(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L52
  mov    $0xffffffffffffffff,%rax
  jmp    L40
L52:
  cmpq   $0xffffffffffffffff,-0x18(%rbp)
  jne    L95
  movq   $0x0,-0x18(%rbp)
L95:
  mov    -0x18(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x10(%rbp)
L7:
  cmpq   $0x0,-0x10(%rbp)
  jne    L53
  mov    -0x8(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
ssize_t readblock(int fd, void *buf, size_t size) {
  char *bufp;
  ssize_t bytesread;
  size_t bytestoread;
  size_t totalbytes;
  for (bufp = buf, bytestoread = size, totalbytes = 0; bytestoread > 0; bufp += bytesread, bytestoread -= bytesread) {
    bytesread = read(fd, bufp, bytestoread);
    if ((bytesread == 0) && (totalbytes == 0))
      return 0;
    if (bytesread == 0) {
      errno = EINVAL;
      return -1;
    }
    if ((bytesread) == -1 && (errno != EINTR))
      return -1;
    if (bytesread == -1)
      bytesread = 0;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readblock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %rdx,%rdx
  je     L40
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  jmp    L37
L56:
  mov    D38(%rip),%rax
  mov    (%rax),%rdx
  mov    D13(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffffffffffff,%rdx
L40:
  mov    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  add    %rax,%rbp
  add    %rax,%r12
  sub    %rax,%rbx
  je     L15
L37:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %rax,%rdx
  or     %rbp,%rdx
  je     L40
  test   %rax,%rax
  je     L56
  cmp    $0xffffffffffffffff,%rax
  jne    L30
  mov    D13(%rip),%rcx
  mov    D10(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L50
  mov    %r14,%rax
  jmp    L30
L15:
  mov    %rbp,%rdx
  jmp    L40
L50:
  mov    %rax,%rdx
  jmp    L40
```

assistant: ```c
ssize_t readblock(int fd, void *buf, size_t size) {
  char *bufp;
  ssize_t bytesread;
  size_t bytestoread;
  size_t totalbytes;
  for (bufp = buf, bytestoread = size, totalbytes = 0; bytestoread > 0; bufp += bytesread, bytestoread -= bytesread) {
    bytesread = read(fd, bufp, bytestoread);
    if ((bytesread == 0) && (totalbytes == 0))
      return 0;
    if (bytesread == 0) {
      errno = EINVAL;
      return -1;
    }
    if ((bytesread) == -1 && (errno != EINTR))
      return -1;
    if (bytesread == -1)
      bytesread = 0;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readblock>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L23
  nop
L46:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rcx
  or     %r13,%rcx
  je     L23
  test   %rax,%rax
  je     L10
  cmp    $0xffffffffffffffff,%rax
  je     L15
  add    %rax,%r13
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L46
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    D24(%rip),%rax
  mov    D16(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L46
  mov    $0xffffffffffffffff,%r13
  jmp    L28
  nop
L23:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  mov    D4(%rip),%rax
  mov    $0xffffffffffffffff,%r13
  mov    (%rax),%rdx
  mov    D16(%rip),%rax
  mov    %rdx,(%rax)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readblock(int fd, void *buf, size_t size) {
  char *bufp;
  ssize_t bytesread;
  size_t bytestoread;
  size_t totalbytes;
  for (bufp = buf, bytestoread = size, totalbytes = 0; bytestoread > 0; bufp += bytesread, bytestoread -= bytesread) {
    bytesread = read(fd, bufp, bytestoread);
    if ((bytesread == 0) && (totalbytes == 0))
      return 0;
    if (bytesread == 0) {
      errno = EINVAL;
      return -1;
    }
    if ((bytesread) == -1 && (errno != EINTR))
      return -1;
    if (bytesread == -1)
      bytesread = 0;
    totalbytes += bytesread;
  }
  return totalbytes;
}
```