user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x20,-0xdd(%rbp)
  movabs $0xa0a0a0a0a0a0a0a,%rax
  movabs $0xa0a0a0a0a0a0a0a,%rdx
  mov    %rax,-0xd0(%rbp)
  mov    %rdx,-0xc8(%rbp)
  mov    %rax,-0xc0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %rax,-0xb0(%rbp)
  mov    %rdx,-0xa8(%rbp)
  mov    %rax,-0xa0(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movabs $0xa0a0a0a0a0a0a0a,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0xc8,-0xd4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xdc(%rbp)
  jmp    L37
L31:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edx
  mov    -0xdc(%rbp),%eax
  cltq
  mov    %dl,-0xd0(%rbp,%rax,1)
  mov    -0xdc(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  cmp    $0x3f,%eax
  seta   %dl
  test   %dl,%dl
  jne    L168
  movabs $0x8000400200000000,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L168
  mov    -0xdc(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  mov    %al,-0xdd(%rbp)
  mov    -0xdc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xd4(%rbp)
  jmp    L65
L168:
  nop
L65:
  cmpb   $0x20,-0xdd(%rbp)
  je     L114
  mov    -0xdc(%rbp),%eax
  cltq
  movb   $0xa,-0xd0(%rbp,%rax,1)
  jmp    L144
L114:
  addl   $0x1,-0xdc(%rbp)
L37:
  cmpl   $0xc7,-0xdc(%rbp)
  jle    L31
L144:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xd4(%rbp),%eax
  mov    %eax,-0xdc(%rbp)
  jmp    L108
L160:
  mov    -0xdc(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L44
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0xdc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xd8(%rbp)
  jmp    L135
L57:
  mov    -0xd8(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xd8(%rbp)
L135:
  mov    -0xd8(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L44
  mov    -0xd8(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L57
L44:
  cmpl   $0x0,-0xdc(%rbp)
  jne    L16
  mov    $0x20,%edi
  call   <putchar@plt>
  movl   $0x0,-0xd8(%rbp)
  jmp    L38
L164:
  mov    -0xd8(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xd8(%rbp)
L38:
  mov    -0xd8(%rbp),%eax
  cltq
  movzbl -0xd0(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L164
  jmp    L162
L16:
  subl   $0x1,-0xdc(%rbp)
L108:
  cmpl   $0x0,-0xdc(%rbp)
  jns    L160
L162:
  movsbl -0xdd(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D14
datatype: string

tool: D4: Enter a sentence: 

tool: D15: Reversal of sentence:

tool: D14: %c


assistant: ```c
int main(void) {
  char end_char = ' ', a[200] = {[0 ... 200 - 1] = '\n'};
  int i, n, effective_size = 200;
  printf("Enter a sentence: ");
  for (i = 0; i < 200; i++) {
    a[i] = getchar();
    switch (a[i]) {
    case '.':
    case '!':
    case '?':
      end_char = a[i];
      effective_size = i - 1;
      break;
    default:
      break;
    }
    if (end_char != ' ') {
      a[i] = '\n';
      break;
    }
  }
  printf("Reversal of sentence:");
  for (i = effective_size; i >= 0; --i) {
    if (a[i] == ' ') {
      putchar(' ');
      for (n = i + 1; (a[n] != '\n') && (a[n] != ' '); n++)
        putchar(a[n]);
    }
    if (i == 0) {
      putchar(' ');
      for (n = 0; a[n] != ' '; n++)
        putchar(a[n]);
      break;
    }
  }
  printf("%c\n", end_char);
  return 0;
}
```