user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x48(%rbp)
  movl   $0x0,-0x50(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  test   %eax,%eax
  jle    L111
  mov    -0x50(%rbp),%eax
  cmp    $0xf,%eax
  jle    L39
L111:
  mov    -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L36
L39:
  lea    -0x40(%rbp),%rax
  mov    $0x30,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L54
L18:
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x48(%rbp),%rax
  test   %rax,%rax
  js     L88
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    -0x48(%rbp),%rdx
  cmp    %rdx,%rax
  jge    L15
L88:
  mov    -0x48(%rbp),%rax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L36
L15:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <find_digits@plt>
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x40(%rbp,%rdx,4)
  addl   $0x1,-0x4c(%rbp)
L54:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L18
  movl   $0x0,-0x4c(%rbp)
  jmp    L53
L6:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  cmp    $0xffffffff,%eax
  jne    L47
  mov    $0x0,%eax
  jmp    L36
L47:
  mov    -0x4c(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4c(%rbp)
L53:
  mov    -0x4c(%rbp),%eax
  cmp    $0xb,%eax
  jbe    L6
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D45
data_type: string
name: disassemble_data
arguments: tag: D37
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string

tool: D7: %d

tool: D20: error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d


tool: D45: %lld

tool: D37: error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).


tool: D33: %d


assistant: ```c
int main() {
  signed long long value = 0;
  int t = 0;
  int i;
  int count_arr[12];
  scanf("%d", &t);
  if ((t < 1) || (t > 15)) {
    printf("error: T does not satisfy problem constraint (1 <= T <= 15). You entered %d\n", t);
    return 0;
  }
  memset(count_arr, -1, sizeof(count_arr));
  for (i = 0; i < t; i++) {
    scanf("%lld", &value);
    if ((value < 0) || (value > pow(10, 10))) {
      printf("error: N,%lld, does not satisfy problem constraint (0 <= N <= 10^10).\n", value);
      return 0;
    }
    count_arr[i] = find_digits(value);
  }
  for (i = 0; i < (sizeof(count_arr) / sizeof(int)); i++) {
    if (count_arr[i] == -1) {
      return 0;
    }
    printf("%d\n", count_arr[i]);
  }
  return 0;
}
```