ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<set_boundary_set_derived>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x1,%edi
  push   %r14
  push   %r13
  mov    %edx,%r13d
  mov    $0x1,%edx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <arithmetic_sequence_sum@plt>
  mov    %eax,%r8d
  mov    %r13d,%eax
  sub    %r8d,%eax
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  test   %eax,%eax
  jle    L19
  mov    %ebx,%edi
  mov    %eax,%r12d
  mov    $0x1,%ebp
  xor    %ebx,%ebx
  lea    -0x1(%rdi),%r14d
  nopw   0x0(%rax,%rax,1)
L15:
  lea    (%r14,%rbp,1),%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <arithmetic_sequence_sum@plt>
  lea    0x0(%rbp,%rbp,1),%edx
  mov    %eax,%r8d
  mov    %r13d,%eax
  sub    %r8d,%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jge    L15
L0:
  movslq 0xc(%rsp),%rax
  mov    %rax,%rcx
  mov    %ebx,-0x4(%r15,%rax,4)
  sub    $0x2,%ecx
  js     L34
  movslq %ecx,%rax
  nopl   0x0(%rax)
L36:
  mov    0x4(%r15,%rax,4),%ecx
  lea    -0x1(%rcx),%edx
  mov    %edx,(%r15,%rax,4)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L36
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %ebx,%ebx
  jmp    L0
```

assistant: ```c
void set_boundary_set_derived(int *set, int size, int sum_upper_bound) {
  int smallest_element_max = sum_upper_bound - arithmetic_sequence_sum(1, size, 1);
  if (smallest_element_max % size == 0)
    smallest_element_max /= size;
  else
    smallest_element_max = smallest_element_max / size + 1;
  int worst_case_largest = 0;
  for (int i = 1; i <= smallest_element_max; i++) {
    int sum_of_two_smallest = i + i + 1;
    int sum_of_all_but_largest = arithmetic_sequence_sum(i, i + size - 1, 1);
    int largest_element_max = ((sum_of_two_smallest - 1) < (sum_upper_bound - sum_of_all_but_largest) ? (sum_of_two_smallest - 1) : (sum_upper_bound - sum_of_all_but_largest));
    if (largest_element_max > worst_case_largest)
      worst_case_largest = largest_element_max;
  }
  set[size - 1] = worst_case_largest;
  for (int i = size - 2; i >= 0; i--)
    set[i] = set[i + 1] - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_boundary_set_derived>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  mov    $0x1,%edx
  push   %r13
  mov    %rdi,%r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <arithmetic_sequence_sum@plt>
  mov    %eax,%r8d
  mov    %r14d,%eax
  sub    %r8d,%eax
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  test   %eax,%eax
  jle    L15
  mov    %ebx,%ecx
  mov    %eax,%r12d
  mov    $0x1,%ebp
  xor    %ebx,%ebx
  lea    -0x1(%rcx),%r15d
  nopl   0x0(%rax,%rax,1)
L6:
  lea    (%r15,%rbp,1),%esi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <arithmetic_sequence_sum@plt>
  mov    %r14d,%edx
  mov    %eax,%r8d
  lea    0x0(%rbp,%rbp,1),%eax
  sub    %r8d,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jge    L6
L22:
  movslq 0xc(%rsp),%rax
  mov    %rax,%rcx
  mov    %ebx,-0x4(%r13,%rax,4)
  sub    $0x2,%ecx
  movslq %ecx,%rbp
  js     L8
  nopl   0x0(%rax)
L48:
  sub    $0x1,%ebx
  mov    %ebx,0x0(%r13,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jns    L48
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L15:
  xor    %ebx,%ebx
  jmp    L22
```

assistant: ```c
void set_boundary_set_derived(int *set, int size, int sum_upper_bound) {
  int smallest_element_max = sum_upper_bound - arithmetic_sequence_sum(1, size, 1);
  if (smallest_element_max % size == 0)
    smallest_element_max /= size;
  else
    smallest_element_max = smallest_element_max / size + 1;
  int worst_case_largest = 0;
  for (int i = 1; i <= smallest_element_max; i++) {
    int sum_of_two_smallest = i + i + 1;
    int sum_of_all_but_largest = arithmetic_sequence_sum(i, i + size - 1, 1);
    int largest_element_max = ((sum_of_two_smallest - 1) < (sum_upper_bound - sum_of_all_but_largest) ? (sum_of_two_smallest - 1) : (sum_upper_bound - sum_of_all_but_largest));
    if (largest_element_max > worst_case_largest)
      worst_case_largest = largest_element_max;
  }
  set[size - 1] = worst_case_largest;
  for (int i = size - 2; i >= 0; i--)
    set[i] = set[i + 1] - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__profile_frequency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movl   $0x2710,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <__setitimer@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__setitimer@plt>
  mov    -0x30(%rbp),%eax
  cmp    $0x1,%eax
  jg     L7
  mov    $0x0,%eax
  jmp    L3
L7:
  mov    -0x30(%rbp),%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int __profile_frequency(void) {
  struct itimerval tim;
  tim.it_interval.tv_sec = 0;
  tim.it_interval.tv_usec = 10000;
  tim.it_value.tv_sec = 0;
  tim.it_value.tv_usec = 0;
  __setitimer(ITIMER_REAL, &tim, 0);
  __setitimer(ITIMER_REAL, 0, &tim);
  if (tim.it_interval.tv_usec < 2)
    return 0;
  return (1000000 / tim.it_interval.tv_usec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<__profile_frequency>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x2710,(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rbp
  mov    D0(%rip),%rbx
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <__setitimer@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    (%rbx),%edi
  call   <__setitimer@plt>
  mov    (%rsp),%ecx
  mov    $0x0,%eax
  cmp    $0x1,%ecx
  jle    L9
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
L9:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __profile_frequency(void) {
  struct itimerval tim;
  tim.it_interval.tv_sec = 0;
  tim.it_interval.tv_usec = 10000;
  tim.it_value.tv_sec = 0;
  tim.it_value.tv_usec = 0;
  __setitimer(ITIMER_REAL, &tim, 0);
  __setitimer(ITIMER_REAL, 0, &tim);
  if (tim.it_interval.tv_usec < 2)
    return 0;
  return (1000000 / tim.it_interval.tv_usec);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__profile_frequency>:
  endbr64
  push   %r12
  xor    %edx,%edx
  push   %rbx
  sub    $0x38,%rsp
  mov    D2(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0x2710,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    (%rbx),%edi
  mov    %r12,%rsi
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <__setitimer@plt>
  mov    (%rbx),%edi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <__setitimer@plt>
  mov    (%rsp),%ecx
  xor    %eax,%eax
  cmp    $0x1,%ecx
  jle    L16
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
L16:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __profile_frequency(void) {
  struct itimerval tim;
  tim.it_interval.tv_sec = 0;
  tim.it_interval.tv_usec = 10000;
  tim.it_value.tv_sec = 0;
  tim.it_value.tv_usec = 0;
  __setitimer(ITIMER_REAL, &tim, 0);
  __setitimer(ITIMER_REAL, 0, &tim);
  if (tim.it_interval.tv_usec < 2)
    return 0;
  return (1000000 / tim.it_interval.tv_usec);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__profile_frequency>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  push   %rbx
  sub    $0x38,%rsp
  mov    D5(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movups %xmm0,0x8(%rsp)
  mov    (%rbx),%edi
  mov    %r12,%rsi
  movl   $0x2710,(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <__setitimer@plt>
  mov    (%rbx),%edi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <__setitimer@plt>
  mov    (%rsp),%ecx
  xor    %eax,%eax
  cmp    $0x1,%ecx
  jle    L9
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
L9:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __profile_frequency(void) {
  struct itimerval tim;
  tim.it_interval.tv_sec = 0;
  tim.it_interval.tv_usec = 10000;
  tim.it_value.tv_sec = 0;
  tim.it_value.tv_usec = 0;
  __setitimer(ITIMER_REAL, &tim, 0);
  __setitimer(ITIMER_REAL, 0, &tim);
  if (tim.it_interval.tv_usec < 2)
    return 0;
  return (1000000 / tim.it_interval.tv_usec);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vendor_mac_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L13
L5:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  movslq %edx,%rax
  imul   $0x4325c53f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x4,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int vendor_mac_hash(int mac[]) {
  if (mac == NULL) {
    return -1;
  }
  return (mac[0] ^ mac[1] ^ mac[2]) % 61;
}
```
user: What is the c source code of the assembly code below:

```asm
<vendor_mac_hash>:
  endbr64
  test   %rdi,%rdi
  je     L1
  mov    (%rdi),%edx
  xor    0x4(%rdi),%edx
  xor    0x8(%rdi),%edx
  movslq %edx,%rax
  imul   $0x4325c53f,%rax,%rax
  sar    $0x24,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x3d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L1:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int vendor_mac_hash(int mac[]) {
  if (mac == NULL) {
    return -1;
  }
  return (mac[0] ^ mac[1] ^ mac[2]) % 61;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vendor_mac_hash>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    (%rdi),%edx
  xor    0x4(%rdi),%edx
  xor    0x8(%rdi),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4325c53f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x3d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int vendor_mac_hash(int mac[]) {
  if (mac == NULL) {
    return -1;
  }
  return (mac[0] ^ mac[1] ^ mac[2]) % 61;
}
```
user: What is the c source code of the assembly code below?

```asm
<vendor_mac_hash>:
  endbr64
  test   %rdi,%rdi
  je     L7
  mov    (%rdi),%edx
  xor    0x4(%rdi),%edx
  xor    0x8(%rdi),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4325c53f,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x3d,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int vendor_mac_hash(int mac[]) {
  if (mac == NULL) {
    return -1;
  }
  return (mac[0] ^ mac[1] ^ mac[2]) % 61;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  jmp    L2
L14:
  mov    $0x0,%eax
  call   <barrier@plt>
L2:
  mov    $0x40100028,%eax
  mov    (%rax),%rax
  and    $0x20,%eax
  test   %rax,%rax
  je     L14
  mov    $0x40100000,%edx
  movsbq -0x4(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void putc(char c) {
  while (!(((volatile unsigned long *)0x40100000)[5] & 0x20))
    barrier();
  ((volatile unsigned long *)0x40100000)[0] = c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<putc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    0x40100028,%rax
  test   $0x20,%al
  jne    L1
L5:
  mov    $0x0,%eax
  call   <barrier@plt>
  mov    0x40100028,%rax
  test   $0x20,%al
  je     L5
L1:
  movsbq %bl,%rbx
  mov    %rbx,0x40100000
  pop    %rbx
  ret
```

assistant: ```c
void putc(char c) {
  while (!(((volatile unsigned long *)0x40100000)[5] & 0x20))
    barrier();
  ((volatile unsigned long *)0x40100000)[0] = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<putc>:
  endbr64
  push   %rbx
  mov    0x40100028,%rax
  mov    %edi,%ebx
  test   $0x20,%al
  jne    L11
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <barrier@plt>
  mov    0x40100028,%rax
  test   $0x20,%al
  je     L3
L11:
  movsbq %bl,%rbx
  mov    %rbx,0x40100000
  pop    %rbx
  ret
```

assistant: ```c
void putc(char c) {
  while (!(((volatile unsigned long *)0x40100000)[5] & 0x20))
    barrier();
  ((volatile unsigned long *)0x40100000)[0] = c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putc>:
  endbr64
  push   %rbx
  mov    0x40100028,%rax
  mov    %edi,%ebx
  test   $0x20,%al
  jne    L12
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <barrier@plt>
  mov    0x40100028,%rax
  test   $0x20,%al
  je     L1
L12:
  movsbq %bl,%rbx
  mov    %rbx,0x40100000
  pop    %rbx
  ret
```

assistant: ```c
void putc(char c) {
  while (!(((volatile unsigned long *)0x40100000)[5] & 0x20))
    barrier();
  ((volatile unsigned long *)0x40100000)[0] = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  je     L1
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D27: 
Greatest Common Demoninator:
Please input two integers



tool: D2: %d %d

tool: D0: 
Input Error, Try again



assistant: ```c
int test_gcd(void) {
  int s, val1, val2;
  printf("\nGreatest Common Demoninator:\nPlease input two integers\n\n");
  s = scanf("%d %d", &val1, &val2);
  if (s != 2) {
    printf("\nInput Error, Try again\n\n");
    exit(0);
  }
  return gcd(val1, val2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_gcd>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L10
L0:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L10:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L0
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string

tool: D2: 
Greatest Common Demoninator:
Please input two integers



tool: D14: %d %d

tool: D16: 
Input Error, Try again



assistant: ```c
int test_gcd(void) {
  int s, val1, val2;
  printf("\nGreatest Common Demoninator:\nPlease input two integers\n\n");
  s = scanf("%d %d", &val1, &val2);
  if (s != 2) {
    printf("\nInput Error, Try again\n\n");
    exit(0);
  }
  return gcd(val1, val2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_gcd>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L11
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L11:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D13: 
Greatest Common Demoninator:
Please input two integers



tool: D3: %d %d

tool: D16: 
Input Error, Try again



assistant: ```c
int test_gcd(void) {
  int s, val1, val2;
  printf("\nGreatest Common Demoninator:\nPlease input two integers\n\n");
  s = scanf("%d %d", &val1, &val2);
  if (s != 2) {
    printf("\nInput Error, Try again\n\n");
    exit(0);
  }
  return gcd(val1, val2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_gcd>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L12
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
L12:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <gcd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D2: 
Greatest Common Demoninator:
Please input two integers



tool: D10: %d %d

tool: D6: 
Input Error, Try again



assistant: ```c
int test_gcd(void) {
  int s, val1, val2;
  printf("\nGreatest Common Demoninator:\nPlease input two integers\n\n");
  s = scanf("%d %d", &val1, &val2);
  if (s != 2) {
    printf("\nInput Error, Try again\n\n");
    exit(0);
  }
  return gcd(val1, val2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<minDeletionSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L43
L40:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L17
L20:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x19(%rbp)
  jle    L32
  addl   $0x1,-0x18(%rbp)
  jmp    L11
L32:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L20
L11:
  addq   $0x1,-0x10(%rbp)
L43:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L40
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int minDeletionSize(char **A, int ASize) {
  int retval = 0;
  size_t sl = strlen(A[0]);
  for (size_t ci = 0; ci < sl; ci++) {
    char last = A[0][ci];
    for (int i = 1; i < ASize; i++) {
      if (A[i][ci] < last) {
        retval++;
        break;
      } else {
        last = A[i][ci];
      }
    }
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minDeletionSize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    (%rdi),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L44
  lea    -0x2(%rbp),%edx
  lea    0x10(%rbx,%rdx,8),%r8
  mov    $0x0,%edi
  mov    $0x0,%r9d
  jmp    L43
L54:
  add    $0x1,%r9d
L66:
  add    $0x1,%rdi
  cmp    %rdi,%rax
  je     L45
L43:
  movzbl (%r12,%rdi,1),%ecx
  cmp    $0x1,%ebp
  jle    L66
  lea    0x8(%rbx),%rdx
L48:
  mov    %ecx,%esi
  mov    (%rdx),%rcx
  movzbl (%rcx,%rdi,1),%ecx
  cmp    %sil,%cl
  jl     L54
  add    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L48
  jmp    L66
L44:
  mov    $0x0,%r9d
L45:
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int minDeletionSize(char **A, int ASize) {
  int retval = 0;
  size_t sl = strlen(A[0]);
  for (size_t ci = 0; ci < sl; ci++) {
    char last = A[0][ci];
    for (int i = 1; i < ASize; i++) {
      if (A[i][ci] < last) {
        retval++;
        break;
      } else {
        last = A[i][ci];
      }
    }
  }
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<minDeletionSize>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L10
  lea    -0x2(%rbp),%edx
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  lea    0x10(%rbx,%rdx,8),%r9
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl (%r12,%r8,1),%ecx
  cmp    $0x1,%ebp
  jle    L19
  lea    0x8(%rbx),%rdx
  jmp    L20
L18:
  add    $0x8,%rdx
  cmp    %r9,%rdx
  je     L19
L20:
  mov    %ecx,%edi
  mov    (%rdx),%rcx
  movzbl (%rcx,%r8,1),%ecx
  cmp    %dil,%cl
  jge    L18
  add    $0x1,%r10d
L19:
  add    $0x1,%r8
  cmp    %r8,%rax
  jne    L45
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  ret
L10:
  xor    %r10d,%r10d
  pop    %rbx
  pop    %rbp
  mov    %r10d,%eax
  pop    %r12
  ret
```

assistant: ```c
int minDeletionSize(char **A, int ASize) {
  int retval = 0;
  size_t sl = strlen(A[0]);
  for (size_t ci = 0; ci < sl; ci++) {
    char last = A[0][ci];
    for (int i = 1; i < ASize; i++) {
      if (A[i][ci] < last) {
        retval++;
        break;
      } else {
        last = A[i][ci];
      }
    }
  }
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<minDeletionSize>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L55
  lea    -0x2(%rbp),%edx
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  lea    0x10(%rbx,%rdx,8),%r9
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl (%r12,%r8,1),%ecx
  cmp    $0x1,%ebp
  jle    L44
  lea    0x8(%rbx),%rdx
  jmp    L41
L32:
  add    $0x8,%rdx
  cmp    %r9,%rdx
  je     L44
L41:
  mov    %ecx,%edi
  mov    (%rdx),%rcx
  movzbl (%rcx,%r8,1),%ecx
  cmp    %dil,%cl
  jge    L32
  add    $0x1,%r10d
L44:
  add    $0x1,%r8
  cmp    %r8,%rax
  jne    L45
  pop    %rbx
  mov    %r10d,%eax
  pop    %rbp
  pop    %r12
  ret
L55:
  xor    %r10d,%r10d
  pop    %rbx
  pop    %rbp
  mov    %r10d,%eax
  pop    %r12
  ret
```

assistant: ```c
int minDeletionSize(char **A, int ASize) {
  int retval = 0;
  size_t sl = strlen(A[0]);
  for (size_t ci = 0; ci < sl; ci++) {
    char last = A[0][ci];
    for (int i = 1; i < ASize; i++) {
      if (A[i][ci] < last) {
        retval++;
        break;
      } else {
        last = A[i][ci];
      }
    }
  }
  return retval;
}
```