ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ltom_f>:
  endbr64
  movss  (%rdi),%xmm0
  ret
```

assistant: ```c
float ltom_f(uint8_t in[4]) {
  float out = 0.0;
  uint8_t *fp = (uint8_t *)&out;
  fp[0] = in[0];
  fp[1] = in[1];
  fp[2] = in[2];
  fp[3] = in[3];
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ltom_f>:
  endbr64
  movss  (%rdi),%xmm0
  ret
```

assistant: ```c
float ltom_f(uint8_t in[4]) {
  float out = 0.0;
  uint8_t *fp = (uint8_t *)&out;
  fp[0] = in[0];
  fp[1] = in[1];
  fp[2] = in[2];
  fp[3] = in[3];
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<LCSubseq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L41
  cmpl   $0x0,-0x28(%rbp)
  jns    L55
L41:
  mov    $0x0,%eax
  jmp    L34
L55:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L44
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <LCSubseq>
  add    $0x1,%eax
  jmp    L34
L44:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <LCSubseq>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <LCSubseq>
  cmp    %eax,%ebx
  jle    L49
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <LCSubseq>
  jmp    L53
L49:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <LCSubseq>
L53:
  nop
L34:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int LCSubseq(char a[], char b[], int m, int n) {
  if (m < 0 || n < 0) {
    return 0;
  }
  if (a[m] == b[n])
    return 1 + LCSubseq(a, b, m - 1, n - 1);
  else
    return ((LCSubseq(a, b, m - 1, n) > LCSubseq(a, b, m, n - 1)) ? LCSubseq(a, b, m - 1, n) : LCSubseq(a, b, m, n - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LCSubseq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r13
  mov    $0x0,%eax
  mov    %edx,%esi
  or     %ecx,%esi
  js     L15
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %ecx,%ebx
  movslq %edx,%rax
  movslq %ecx,%rdx
  movzbl 0x0(%r13,%rdx,1),%edi
  cmp    %dil,(%r12,%rax,1)
  je     L18
  lea    -0x1(%rbp),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <LCSubseq>
  mov    %eax,%r14d
  lea    -0x1(%rbx),%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <LCSubseq>
  cmp    %eax,%r14d
  cmovge %r14d,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  lea    -0x1(%rcx),%ecx
  lea    -0x1(%rbp),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <LCSubseq>
  add    $0x1,%eax
  jmp    L15
```

assistant: ```c
int LCSubseq(char a[], char b[], int m, int n) {
  if (m < 0 || n < 0) {
    return 0;
  }
  if (a[m] == b[n])
    return 1 + LCSubseq(a, b, m - 1, n - 1);
  else
    return ((LCSubseq(a, b, m - 1, n) > LCSubseq(a, b, m, n - 1)) ? LCSubseq(a, b, m - 1, n) : LCSubseq(a, b, m, n - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LCSubseq>:
  endbr64
  push   %r15
  mov    %ecx,%eax
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  or     %edx,%eax
  js     L16
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%ebp
L20:
  movslq %ebp,%rdx
  lea    -0x1(%rbx),%r14d
  lea    -0x1(%rbp),%r8d
  movslq %ebx,%rax
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%r13,%rax,1)
  je     L18
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %r8d,0xc(%rsp)
  call   <LCSubseq>
  mov    0xc(%rsp),%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %eax,0x8(%rsp)
  call   <LCSubseq>
  mov    0xc(%rsp),%r8d
  cmp    %eax,0x8(%rsp)
  cmovg  %r14d,%ebx
  cmovle %r8d,%ebp
L33:
  mov    %ebx,%eax
  or     %ebp,%eax
  jns    L20
L16:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r15d
  mov    %r8d,%ebp
  mov    %r14d,%ebx
  jmp    L33
```

assistant: ```c
int LCSubseq(char a[], char b[], int m, int n) {
  if (m < 0 || n < 0) {
    return 0;
  }
  if (a[m] == b[n])
    return 1 + LCSubseq(a, b, m - 1, n - 1);
  else
    return ((LCSubseq(a, b, m - 1, n) > LCSubseq(a, b, m, n - 1)) ? LCSubseq(a, b, m - 1, n) : LCSubseq(a, b, m, n - 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<socket_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int socket_connect() {
  int ern, rc;
  ern = 0;
  return ern;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<socket_connect>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int socket_connect() {
  int ern, rc;
  ern = 0;
  return ern;
}
```
user: Translate the below assembly code into C programming language:

```asm
<socket_connect>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int socket_connect() {
  int ern, rc;
  ern = 0;
  return ern;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socket_connect>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int socket_connect() {
  int ern, rc;
  ern = 0;
  return ern;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L38
  mov    $0xffffffff,%eax
  jmp    L39
L38:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L34
  mov    $0x1,%eax
  jmp    L39
L34:
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int comp(void const *e1, void const *e2) {
  int *i = *((int **)e1);
  int *j = *((int **)e2);
  if (*i < *j)
    return -1;
  if (*i > *j)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<comp>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%ecx
  mov    (%rsi),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L7
  setg   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int comp(void const *e1, void const *e2) {
  int *i = *((int **)e1);
  int *j = *((int **)e2);
  if (*i < *j)
    return -1;
  if (*i > *j)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<comp>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int comp(void const *e1, void const *e2) {
  int *i = *((int **)e1);
  int *j = *((int **)e2);
  if (*i < *j)
    return -1;
  if (*i > *j)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<comp>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rsi),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int comp(void const *e1, void const *e2) {
  int *i = *((int **)e1);
  int *j = *((int **)e2);
  if (*i < *j)
    return -1;
  if (*i > *j)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<imgReadFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imgReadImgPng@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L24
  mov    -0x4(%rbp),%eax
  jmp    L2
L24:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imgReadImgTga@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  jmp    L2
L18:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imgReadImgBmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L23
  mov    -0x4(%rbp),%eax
  jmp    L2
L23:
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int imgReadFile(struct imgImage *img, const char *fn) {
  int err = -1;
  if ((err = imgReadImgPng(fn, img)) == 0)
    return err;
  if ((err = imgReadImgTga(fn, img)) == 0)
    return err;
  if ((err = imgReadImgBmp(fn, img)) == 0)
    return err;
  return err;
}
```
user: What is the c source code of the assembly code below?

```asm
<imgReadFile>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <imgReadImgPng@plt>
  test   %eax,%eax
  jne    L0
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <imgReadImgTga@plt>
  test   %eax,%eax
  je     L23
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <imgReadImgBmp@plt>
  jmp    L23
```

assistant: ```c
int imgReadFile(struct imgImage *img, const char *fn) {
  int err = -1;
  if ((err = imgReadImgPng(fn, img)) == 0)
    return err;
  if ((err = imgReadImgTga(fn, img)) == 0)
    return err;
  if ((err = imgReadImgBmp(fn, img)) == 0)
    return err;
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<imgReadFile>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <imgReadImgPng@plt>
  test   %eax,%eax
  jne    L14
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <imgReadImgTga@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <imgReadImgBmp@plt>
```

assistant: ```c
int imgReadFile(struct imgImage *img, const char *fn) {
  int err = -1;
  if ((err = imgReadImgPng(fn, img)) == 0)
    return err;
  if ((err = imgReadImgTga(fn, img)) == 0)
    return err;
  if ((err = imgReadImgBmp(fn, img)) == 0)
    return err;
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<imgReadFile>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <imgReadImgPng@plt>
  test   %eax,%eax
  jne    L12
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <imgReadImgTga@plt>
  test   %eax,%eax
  je     L18
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <imgReadImgBmp@plt>
```

assistant: ```c
int imgReadFile(struct imgImage *img, const char *fn) {
  int err = -1;
  if ((err = imgReadImgPng(fn, img)) == 0)
    return err;
  if ((err = imgReadImgTga(fn, img)) == 0)
    return err;
  if ((err = imgReadImgBmp(fn, img)) == 0)
    return err;
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<transfer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L5
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void transfer(char *strt, char *end) {
  int ind = 0;
  while (strcmp(strt, end) != 0) {
    if (strt[ind] != end[ind]) {
      strt[ind] = end[ind];
      puts(strt);
    }
    ind++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transfer>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  jmp    L25
L10:
  add    $0x1,%rbx
L25:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L21
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L10
  mov    %al,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L10
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void transfer(char *strt, char *end) {
  int ind = 0;
  while (strcmp(strt, end) != 0) {
    if (strt[ind] != end[ind]) {
      strt[ind] = end[ind];
      puts(strt);
    }
    ind++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<transfer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L29
  mov    %al,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  call   <puts@plt>
L29:
  add    $0x1,%rbx
L17:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void transfer(char *strt, char *end) {
  int ind = 0;
  while (strcmp(strt, end) != 0) {
    if (strt[ind] != end[ind]) {
      strt[ind] = end[ind];
      puts(strt);
    }
    ind++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transfer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,0x0(%rbp,%rbx,1)
  je     L20
  mov    %al,0x0(%rbp,%rbx,1)
  mov    %rbp,%rdi
  call   <puts@plt>
L20:
  add    $0x1,%rbx
L16:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void transfer(char *strt, char *end) {
  int ind = 0;
  while (strcmp(strt, end) != 0) {
    if (strt[ind] != end[ind]) {
      strt[ind] = end[ind];
      puts(strt);
    }
    ind++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EWSR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <CE_Low@plt>
  mov    $0x50,%edi
  call   <Send_Byte@plt>
  mov    $0x0,%eax
  call   <CE_High@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EWSR() {
  CE_Low();
  Send_Byte(0x50);
  CE_High();
}
```
user: Translate the below assembly code into C programming language:

```asm
<EWSR>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CE_Low@plt>
  mov    $0x50,%edi
  call   <Send_Byte@plt>
  mov    $0x0,%eax
  call   <CE_High@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void EWSR() {
  CE_Low();
  Send_Byte(0x50);
  CE_High();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EWSR>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CE_Low@plt>
  mov    $0x50,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <CE_High@plt>
```

assistant: ```c
void EWSR() {
  CE_Low();
  Send_Byte(0x50);
  CE_High();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<EWSR>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CE_Low@plt>
  mov    $0x50,%edi
  call   <Send_Byte@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <CE_High@plt>
```

assistant: ```c
void EWSR() {
  CE_Low();
  Send_Byte(0x50);
  CE_High();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex__dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x4,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L20
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x4,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L17
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D44
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D36
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D49
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string

tool: D44: HEX DUMP >>>>>>>>>

tool: D27:      :  0                          9                            19

tool: D36: .................................................................................

tool: D19: 
%05d: 

tool: D49: %2x 

tool: D22: 
END HEX<<<<<<<<

assistant: ```c
int hex__dump(char *data, unsigned int n) {
  printf("HEX DUMP >>>>>>>>>\n");
  printf("     :  0                          9                            19\n");
  printf(".................................................................................");
  unsigned int i;
  for (i = 0; i < n; ++i) {
    if ((i) % 20 == 0) {
      printf("\n%05d: ", (i / 20) * 20);
    }
    printf("%2x ", (int)data[i]);
  }
  printf("\nEND HEX<<<<<<<<\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hex__dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L36
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  mov    $0xcccccccd,%r12d
  lea    D5(%rip),%r15
  lea    D49(%rip),%r14
  jmp    L41
L6:
  movsbl 0x0(%r13,%rbx,1),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L36
L41:
  mov    %ebx,%eax
  imul   %r12,%rax
  shr    $0x24,%rax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  cmp    %ebx,%eax
  jne    L6
  mov    %ebx,%eax
  imul   %r12,%rax
  shr    $0x24,%rax
  lea    (%rax,%rax,4),%esi
  shl    $0x2,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L36:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D59
data_type: string
name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D49
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D29: HEX DUMP >>>>>>>>>

tool: D59:      :  0                          9                            19

tool: D34: .................................................................................

tool: D5: 
%05d: 

tool: D49: %2x 

tool: D27: 
END HEX<<<<<<<<

assistant: ```c
int hex__dump(char *data, unsigned int n) {
  printf("HEX DUMP >>>>>>>>>\n");
  printf("     :  0                          9                            19\n");
  printf(".................................................................................");
  unsigned int i;
  for (i = 0; i < n; ++i) {
    if ((i) % 20 == 0) {
      printf("\n%05d: ", (i / 20) * 20);
    }
    printf("%2x ", (int)data[i]);
  }
  printf("\nEND HEX<<<<<<<<\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex__dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L11
  xor    %ebx,%ebx
  lea    D15(%rip),%r13
  mov    $0xcccccccd,%r15d
  lea    D36(%rip),%r14
  jmp    L24
  nopl   0x0(%rax)
L48:
  movsbl (%r12,%rbx,1),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L11
L24:
  imul   $0xcccccccd,%ebx,%eax
  ror    $0x2,%eax
  cmp    $0xccccccc,%eax
  ja     L48
  mov    %ebx,%eax
  mov    %r14,%rdi
  imul   %r15,%rax
  shr    $0x24,%rax
  lea    (%rax,%rax,4),%esi
  xor    %eax,%eax
  shl    $0x2,%esi
  call   <printf@plt>
  jmp    L48
  nopl   0x0(%rax)
L11:
  lea    D30(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D37
type: string
name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D30
type: string

tool: D18: HEX DUMP >>>>>>>>>

tool: D37:      :  0                          9                            19

tool: D9: .................................................................................

tool: D15: %2x 

tool: D36: 
%05d: 

tool: D30: 
END HEX<<<<<<<<

assistant: ```c
int hex__dump(char *data, unsigned int n) {
  printf("HEX DUMP >>>>>>>>>\n");
  printf("     :  0                          9                            19\n");
  printf(".................................................................................");
  unsigned int i;
  for (i = 0; i < n; ++i) {
    if ((i) % 20 == 0) {
      printf("\n%05d: ", (i / 20) * 20);
    }
    printf("%2x ", (int)data[i]);
  }
  printf("\nEND HEX<<<<<<<<\n");
  return 0;
}
```