ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <mpz_init@plt>
  mov    $0x64,%esi
  mov    %r12d,%edi
  call   <mpz_fac_ui@plt>
  mov    %r12d,%edx
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <mpz_get_str@plt>
  mov    %rax,%rbp
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L13:
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  lea    -0x30(%r12,%rax,1),%r12d
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L13
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, s = 0;
  char *str = NULL;
  mpz_t f;
  mpz_init(f);
  mpz_fac_ui(f, 100);
  str = mpz_get_str(NULL, 10, f);
  for (i = 0; i < strlen(str); i++)
    s += str[i] - '0';
  free(str);
  printf("%d\n", s);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tajd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  cmpl   $0x0,-0x48(%rbp)
  jne    L17
  pxor   %xmm0,%xmm0
  jmp    L5
L17:
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <a1f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <a2f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <b1f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <b2f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x30(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <c1f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x40(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <c2f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <e1f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <e2f@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  -0x40(%rbp),%xmm1
  movsd  -0x50(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  mov    -0x48(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  movsd  -0x58(%rbp),%xmm0
  divsd  %xmm1,%xmm0
L5:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double tajd(int nsam, int segsites, double sumk) {
  double a1, a2, b1, b2, c1, c2, e1, e2;
  if (segsites == 0)
    return (0.0);
  a1 = a1f(nsam);
  a2 = a2f(nsam);
  b1 = b1f(nsam);
  b2 = b2f(nsam);
  c1 = c1f(a1, b1);
  c2 = c2f(nsam, a1, a2, b2);
  e1 = e1f(a1, c1);
  e2 = e2f(a1, a2, c2);
  if (0) {
    fprintf(stderr, "e1=%f\te2=%f\n", e1, e2);
    fprintf(stderr, "sqrt=%f top=%f\n", sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))), sumk - (segsites / a1));
    fprintf(stderr, "sumk=%f\t segs/a1=%f\n", sumk, (segsites / a1));
    exit(0);
  }
  return ((sumk - (segsites / a1)) / sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tajd>:
  endbr64
  test   %esi,%esi
  jne    L21
  pxor   %xmm0,%xmm0
  ret
L21:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  movq   %xmm0,%rbx
  call   <a1f@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %r12d,%edi
  call   <a2f@plt>
  movq   %xmm0,%r13
  mov    %r12d,%edi
  call   <b1f@plt>
  movq   %xmm0,%r14
  mov    %r12d,%edi
  call   <b2f@plt>
  movq   %xmm0,%r15
  movq   %r14,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <c1f@plt>
  movq   %xmm0,%r14
  movq   %r15,%xmm2
  movq   %r13,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r12d,%edi
  call   <c2f@plt>
  movq   %xmm0,%r12
  movq   %r14,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <e1f@plt>
  movq   %xmm0,%r14
  movq   %r12,%xmm2
  movq   %r13,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <e2f@plt>
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  movapd %xmm1,%xmm0
  divsd  0x8(%rsp),%xmm0
  movq   %rbx,%xmm3
  subsd  %xmm0,%xmm3
  movq   %xmm3,%rbx
  sub    $0x1,%ebp
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebp,%xmm0
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  movq   %r14,%xmm4
  mulsd  %xmm1,%xmm4
  movapd %xmm4,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L19
  sqrtsd %xmm1,%xmm1
L29:
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L29
```

assistant: ```c
double tajd(int nsam, int segsites, double sumk) {
  double a1, a2, b1, b2, c1, c2, e1, e2;
  if (segsites == 0)
    return (0.0);
  a1 = a1f(nsam);
  a2 = a2f(nsam);
  b1 = b1f(nsam);
  b2 = b2f(nsam);
  c1 = c1f(a1, b1);
  c2 = c2f(nsam, a1, a2, b2);
  e1 = e1f(a1, c1);
  e2 = e2f(a1, a2, c2);
  if (0) {
    fprintf(stderr, "e1=%f\te2=%f\n", e1, e2);
    fprintf(stderr, "sqrt=%f top=%f\n", sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))), sumk - (segsites / a1));
    fprintf(stderr, "sumk=%f\t segs/a1=%f\n", sumk, (segsites / a1));
    exit(0);
  }
  return ((sumk - (segsites / a1)) / sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))));
}
```
user: What is the c source code of the assembly code below?

```asm
<tajd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L13:
  mov    %edi,%ebp
  mov    %esi,%ebx
  call   <a1f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <a2f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x28(%rsp)
  call   <b1f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <b2f@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <c1f@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm4,%xmm1
  call   <c2f@plt>
  movsd  0x18(%rsp),%xmm5
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm5,%xmm1
  call   <e1f@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm4,%xmm1
  call   <e2f@plt>
  pxor   %xmm1,%xmm1
  movsd  0x10(%rsp),%xmm3
  cvtsi2sd %ebx,%xmm1
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x1,%ebx
  cvtsi2sd %ebx,%xmm0
  mulsd  %xmm1,%xmm2
  movapd %xmm1,%xmm7
  divsd  0x8(%rsp),%xmm7
  subsd  %xmm7,%xmm3
  mulsd  0x18(%rsp),%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L26
  sqrtsd %xmm1,%xmm1
L7:
  divsd  %xmm1,%xmm3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm3,%xmm0
  ret
L26:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L7
```

assistant: ```c
double tajd(int nsam, int segsites, double sumk) {
  double a1, a2, b1, b2, c1, c2, e1, e2;
  if (segsites == 0)
    return (0.0);
  a1 = a1f(nsam);
  a2 = a2f(nsam);
  b1 = b1f(nsam);
  b2 = b2f(nsam);
  c1 = c1f(a1, b1);
  c2 = c2f(nsam, a1, a2, b2);
  e1 = e1f(a1, c1);
  e2 = e2f(a1, a2, c2);
  if (0) {
    fprintf(stderr, "e1=%f\te2=%f\n", e1, e2);
    fprintf(stderr, "sqrt=%f top=%f\n", sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))), sumk - (segsites / a1));
    fprintf(stderr, "sumk=%f\t segs/a1=%f\n", sumk, (segsites / a1));
    exit(0);
  }
  return ((sumk - (segsites / a1)) / sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tajd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  jne    L24
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L24:
  mov    %edi,%ebp
  mov    %esi,%ebx
  call   <a1f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <a2f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x28(%rsp)
  call   <b1f@plt>
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <b2f@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <c1f@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm4,%xmm1
  call   <c2f@plt>
  movsd  0x18(%rsp),%xmm5
  movsd  %xmm0,0x20(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm5,%xmm1
  call   <e1f@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movsd  0x8(%rsp),%xmm0
  movapd %xmm4,%xmm1
  call   <e2f@plt>
  pxor   %xmm1,%xmm1
  movsd  0x10(%rsp),%xmm3
  cvtsi2sd %ebx,%xmm1
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x1,%ebx
  cvtsi2sd %ebx,%xmm0
  mulsd  %xmm1,%xmm2
  movapd %xmm1,%xmm7
  divsd  0x8(%rsp),%xmm7
  subsd  %xmm7,%xmm3
  mulsd  0x18(%rsp),%xmm1
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L13
  sqrtsd %xmm1,%xmm1
L16:
  divsd  %xmm1,%xmm3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  movapd %xmm3,%xmm0
  ret
L13:
  movapd %xmm1,%xmm0
  movsd  %xmm3,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm3
  movapd %xmm0,%xmm1
  jmp    L16
```

assistant: ```c
double tajd(int nsam, int segsites, double sumk) {
  double a1, a2, b1, b2, c1, c2, e1, e2;
  if (segsites == 0)
    return (0.0);
  a1 = a1f(nsam);
  a2 = a2f(nsam);
  b1 = b1f(nsam);
  b2 = b2f(nsam);
  c1 = c1f(a1, b1);
  c2 = c2f(nsam, a1, a2, b2);
  e1 = e1f(a1, c1);
  e2 = e2f(a1, a2, c2);
  if (0) {
    fprintf(stderr, "e1=%f\te2=%f\n", e1, e2);
    fprintf(stderr, "sqrt=%f top=%f\n", sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))), sumk - (segsites / a1));
    fprintf(stderr, "sumk=%f\t segs/a1=%f\n", sumk, (segsites / a1));
    exit(0);
  }
  return ((sumk - (segsites / a1)) / sqrt((e1 * segsites) + ((e2 * segsites) * (segsites - 1))));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xd(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <repChar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string
name: retrieve_data
arguments: data_tag: D49
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D43
type_guessed: string

tool: D5: Please input character to repeat: 

tool: D16: %c

tool: D49: Please input number of repititions: 

tool: D1: %d

tool: D43: 


assistant: ```c
int main() {
  int n;
  char c;
  printf("Please input character to repeat: ");
  scanf("%c", &c);
  printf("Please input number of repititions: ");
  scanf("%d", &n);
  printf("\n");
  repChar(c, n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    0x3(%rsp),%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  movsbl 0x3(%rsp),%edi
  mov    0x4(%rsp),%esi
  call   <repChar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string

tool: D36: Please input character to repeat: 

tool: D28: %c

tool: D24: Please input number of repititions: 

tool: D1: %d

tool: D25: 


assistant: ```c
int main() {
  int n;
  char c;
  printf("Please input character to repeat: ");
  scanf("%c", &c);
  printf("Please input number of repititions: ");
  scanf("%d", &n);
  printf("\n");
  repChar(c, n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x3(%rsp),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  movsbl 0x3(%rsp),%edi
  mov    0x4(%rsp),%esi
  call   <repChar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D31
type_guessed: string

tool: D26: Please input character to repeat: 

tool: D16: %c

tool: D49: Please input number of repititions: 

tool: D17: %d

tool: D31: 


assistant: ```c
int main() {
  int n;
  char c;
  printf("Please input character to repeat: ");
  scanf("%c", &c);
  printf("Please input number of repititions: ");
  scanf("%d", &n);
  printf("\n");
  repChar(c, n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x3(%rsp),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  movsbl 0x3(%rsp),%edi
  mov    0x4(%rsp),%esi
  call   <repChar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: string

tool: D22: Please input character to repeat: 

tool: D11: %c

tool: D9: Please input number of repititions: 

tool: D6: %d

tool: D37: 


assistant: ```c
int main() {
  int n;
  char c;
  printf("Please input character to repeat: ");
  scanf("%c", &c);
  printf("Please input number of repititions: ");
  scanf("%d", &n);
  printf("\n");
  repChar(c, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %edi,-0x424(%rbp)
  mov    %rsi,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x414(%rbp)
  jmp    L15
L0:
  mov    -0x414(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x414(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x410(%rbp,%rdx,1)
  addl   $0x1,-0x414(%rbp)
L15:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x414(%rbp)
  jl     L0
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D16: %s

tool: D1: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char text[1024];
  scanf("%s", &text[0]);
  int i;
  for (i = 0; i < strlen(text); i++) {
    text[i] = toupper(text[i]);
  }
  printf("%s\n", text);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rbx
  mov    %rsp,%r12
  jmp    L22
L8:
  movsbl -0x1(%rbx),%edi
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
L22:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  add    $0x1,%rbx
  lea    -0x1(%rbx),%eax
  sub    %ebp,%eax
  cmp    %eax,%edx
  jg     L8
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string

tool: D1: %s

tool: D9: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char text[1024];
  scanf("%s", &text[0]);
  int i;
  for (i = 0; i < strlen(text); i++) {
    text[i] = toupper(text[i]);
  }
  printf("%s\n", text);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rbx
  call   <scanf@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl -0x1(%rbx),%edi
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
L22:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    -0x1(%rbx),%eax
  sub    %ebp,%eax
  cmp    %eax,%r8d
  jg     L0
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string

tool: D1: %s

tool: D16: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char text[1024];
  scanf("%s", &text[0]);
  int i;
  for (i = 0; i < strlen(text); i++) {
    text[i] = toupper(text[i]);
  }
  printf("%s\n", text);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rbx
  call   <scanf@plt>
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L22:
  movsbl -0x1(%rbx),%edi
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
L7:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  lea    -0x1(%rbx),%eax
  sub    %ebp,%eax
  cmp    %eax,%r8d
  jg     L22
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x418,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D3: %s

tool: D7: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char text[1024];
  scanf("%s", &text[0]);
  int i;
  for (i = 0; i < strlen(text); i++) {
    text[i] = toupper(text[i]);
  }
  printf("%s\n", text);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<simplexNoise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movss  %xmm2,-0x2c(%rbp)
  movss  %xmm3,-0x30(%rbp)
  movss  %xmm4,-0x34(%rbp)
  movss  %xmm5,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x2c(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D1(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  movss  -0x38(%rbp),%xmm0
  movaps %xmm0,%xmm2
  mulss  -0x10(%rbp),%xmm2
  movss  -0x34(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x10(%rbp),%xmm1
  movss  -0x30(%rbp),%xmm0
  mulss  -0x10(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <simplexRawNoise@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x10(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x8(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  movss  -0x24(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L5
  movss  -0x14(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: f32

tool: D1: 1

assistant: ```c
float simplexNoise(const float octaves, const float persistence, const float scale, const float x, const float y, const float z) {
  float total = 0;
  float frequency = scale;
  float amplitude = 1;
  float maxAmplitude = 0;
  for (int i = 0; i < octaves; i++) {
    total += simplexRawNoise(x * frequency, y * frequency, z * frequency) * amplitude;
    frequency *= 2;
    maxAmplitude += amplitude;
    amplitude *= persistence;
  }
  return total / maxAmplitude;
}
```