user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x3,%edx
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  lea    0x5(%rsp),%rsi
  movl   $0x636261,0x5(%rsp)
  mov    %rbp,%rdi
  lea    0xf(%rsp),%r12
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movdqa D6(%rip),%xmm0
  mov    %r12,%rdi
  mov    $0x7a79,%eax
  lea    0x40(%rsp),%rbp
  movl   $0x2a2a2a2a,0x50(%rsp)
  movaps %xmm0,0x40(%rsp)
  movl   $0x78636261,0xf(%rsp)
  mov    %ax,0x13(%rsp)
  movb   $0x0,0x15(%rsp)
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D63(%rip),%r12
  lea    0x1(%rax),%edx
  call   <strncpy@plt>
  movsbl 0x4a(%rsp),%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  lea    0x60(%rsp),%rbp
  call   <printf@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  lea    0x9(%rsp),%rsi
  movdqa D9(%rip),%xmm0
  mov    %rdx,0x78(%rsp)
  mov    $0x7a79,%edx
  movabs $0x2f69706c74,%rax
  mov    %dx,0xd(%rsp)
  mov    $0x14,%edx
  movaps %xmm0,0x60(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  mov    %rax,0x70(%rsp)
  movl   $0x0,0xc0(%rsp)
  movl   $0x78636261,0x9(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x16(%rsp),%rbp
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    %cx,0x1e(%rsp)
  movq   $0x0,0x16(%rsp)
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0xa,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x9,%edx
  call   <strncpy@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D40
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D63
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D25: %s


tool: D40: dest1 = %s


tool: {"D6": [0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a,0x2a]}

tool: D63: Hello World

tool: D30: dest2 = %s, dest2[15]= %c 


tool: {"D9": [0x68,0x74,0x74,0x70,0x3a,0x2f,0x2f,0x6d,0x61,0x6e,0x37,0x2e,0x6f,0x72,0x67,0x2f]}

tool: D23: dest3 = %s


assistant: ```c
int main(void) {
  char dest1[20];
  char src1[] = "abc";
  int n1 = 3;
  strncpy(dest1, src1, n1);
  printf("dest1 = %s\n", dest1);
  char dest2[20] = "********************";
  char src2[] = "abcxyz";
  int n2 = (int)strlen(src2) + 1;
  strncpy(dest2, src2, n2);
  printf("dest2 = %s, dest2[15]= %c \n", dest2, dest2[10]);
  char dest3[100] = "http://man7.org/tlpi/";
  char src3[6] = "abcxyz";
  int n3 = 20;
  strncpy(dest3, src3, n3);
  printf("dest3 = %s\n", dest3);
  char string[10] = {0};
  char *string2 = "Hello World";
  strncpy(string, string2, 2);
  printf("%s\n", string);
  memset(string, 0, sizeof(string));
  strncpy(string, string2, strlen(string2));
  printf("%s\n", string);
  memset(string, 0, sizeof(string));
  strncpy(string, string2, sizeof(string) - 1);
  printf("%s\n", string);
}
```