ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<G2Bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char G2Bits(start, place)
unsigned char *start;
int place;
{
  unsigned char value;
  value = (start[place / 2] >> 4 * (place % 2)) & 0x0f;

  return (value);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<G2Bits>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  mov    %esi,%edx
  shr    $0x1f,%edx
  lea    (%rsi,%rdx,1),%ecx
  and    $0x1,%ecx
  sub    %edx,%ecx
  shl    $0x2,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned char G2Bits(start, place)
unsigned char *start;
int place;
{
  unsigned char value;
  value = (start[place / 2] >> 4 * (place % 2)) & 0x0f;

  return (value);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<G2Bits>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x1f,%eax
  shr    $0x1f,%edx
  add    %esi,%eax
  lea    (%rsi,%rdx,1),%ecx
  sar    %eax
  and    $0x1,%ecx
  cltq
  sub    %edx,%ecx
  movzbl (%rdi,%rax,1),%eax
  shl    $0x2,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned char G2Bits(start, place)
unsigned char *start;
int place;
{
  unsigned char value;
  value = (start[place / 2] >> 4 * (place % 2)) & 0x0f;

  return (value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<G2Bits>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x1f,%eax
  shr    $0x1f,%edx
  add    %esi,%eax
  lea    (%rsi,%rdx,1),%ecx
  sar    %eax
  and    $0x1,%ecx
  cltq
  sub    %edx,%ecx
  movzbl (%rdi,%rax,1),%eax
  shl    $0x2,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  ret
```

assistant: ```c
unsigned char G2Bits(start, place)
unsigned char *start;
int place;
{
  unsigned char value;
  value = (start[place / 2] >> 4 * (place % 2)) & 0x0f;

  return (value);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%r8d
  lea    D23(%rip),%rax
  mov    %rax,%rcx
  lea    D29(%rip),%rax
  mov    %rax,%rdx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <execl@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D29
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D37
datatype: string

tool: D23: /etc/passwd

tool: D29: -al

tool: D14: ls

tool: D37: /bin/ls

assistant: ```c
int main(void) {
  execl("/bin/ls", "ls", "-al", "/etc/passwd", NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  lea    D16(%rip),%rcx
  lea    D29(%rip),%rdx
  lea    D18(%rip),%rsi
  lea    D25(%rip),%rdi
  call   <execl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string

tool: D16: /etc/passwd

tool: D29: -al

tool: D18: ls

tool: D25: /bin/ls

assistant: ```c
int main(void) {
  execl("/bin/ls", "ls", "-al", "/etc/passwd", NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  lea    D37(%rip),%rcx
  lea    D2(%rip),%rdx
  lea    D27(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D37
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D37: /etc/passwd

tool: D2: -al

tool: D27: ls

tool: D9: /bin/ls

assistant: ```c
int main(void) {
  execl("/bin/ls", "ls", "-al", "/etc/passwd", NULL);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %r8d,%r8d
  lea    D39(%rip),%rcx
  lea    D7(%rip),%rdx
  lea    D38(%rip),%rsi
  lea    D30(%rip),%rdi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D39
datatype: string
name: retrieve_data
arguments: label: D7
datatype: string
name: retrieve_data
arguments: label: D38
datatype: string
name: retrieve_data
arguments: label: D30
datatype: string

tool: D39: /etc/passwd

tool: D7: -al

tool: D38: ls

tool: D30: /bin/ls

assistant: ```c
int main(void) {
  execl("/bin/ls", "ls", "-al", "/etc/passwd", NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_data_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %r8d,-0x48(%rbp)
  mov    %r9d,-0x4c(%rbp)
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x40(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <math_pow@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    $0x1,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L94
L3:
  mov    -0x20(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  je     L20
  movl   $0x0,-0x24(%rbp)
  jmp    L6
L60:
  mov    -0x20(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  imul   -0x48(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L23
L32:
  movl   $0x0,-0x1c(%rbp)
  jmp    L42
L39:
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
L42:
  mov    -0x1c(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L39
  mov    -0x4c(%rbp),%eax
  sub    0x10(%rbp),%eax
  add    %eax,-0x18(%rbp)
L23:
  mov    -0x20(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  imul   -0x48(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L47
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  imul   -0x10(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L32
L47:
  addl   $0x1,-0x24(%rbp)
L6:
  mov    -0x24(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L60
  jmp    L72
L20:
  nop
L72:
  addl   $0x1,-0x20(%rbp)
L94:
  mov    -0x20(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L3
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_data_list(int *dptr, int fnode, int m, int k, int cirlen, int brklen, int durlen) {
  int i, p, q;
  int times;
  int *ptr_list;
  int r = (math_pow((m), (k - 1)));
  int val;
  int count = 0;
  times = ((r / cirlen) > 0) ? (r / cirlen) : 1;
  ptr_list = dptr;
  for (p = 0; p < k; ++p) {
    if (p == fnode)
      continue;
    for (i = 0; i < times; ++i) {
      val = p * r + i * cirlen;
      while ((val < p * r + (i + 1) * cirlen) && (val < r * (p + 1))) {
        for (q = 0; q < durlen; ++q) {
          *ptr_list = val;
          ++ptr_list;
          ++val;
          ++count;
        }
        val = val + (brklen - durlen);
      }
    }
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_data_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,0x18(%rsp)
  mov    %edx,%edi
  mov    %ecx,%r15d
  mov    %ecx,0x1c(%rsp)
  mov    %r8d,%r12d
  mov    %r9d,%r13d
  mov    0x60(%rsp),%ebx
  lea    -0x1(%rcx),%esi
  call   <math_pow@plt>
  mov    %eax,0x10(%rsp)
  cltd
  idiv   %r12d
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %eax,%edx
  test   %r15d,%r15d
  jle    L45
  mov    %edx,%r14d
  lea    -0x1(%rbx),%eax
  lea    0x4(,%rax,4),%r10
  movl   $0x0,0x14(%rsp)
  mov    $0x0,%esi
  movl   $0x0,0xc(%rsp)
  mov    %r13d,%r9d
  sub    %ebx,%r9d
  jmp    L34
L77:
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L77
  add    %r10,%rbp
  add    %ebx,%esi
L23:
  add    %r9d,%eax
  cmp    %edi,%eax
  jge    L52
  cmp    %r8d,%eax
  jge    L52
L104:
  lea    (%rax,%rbx,1),%ecx
  mov    %rbp,%rdx
  test   %ebx,%ebx
  jg     L77
  jmp    L23
L52:
  add    %r12d,%r11d
  cmp    %r15d,%r14d
  je     L25
L50:
  mov    %r11d,%eax
  add    $0x1,%r15d
  mov    %r13d,%edx
  add    %r12d,%r13d
  cmp    %edx,%r13d
  jle    L52
  lea    (%r11,%r12,1),%edi
  cmp    %r8d,%r11d
  jl     L104
  jmp    L52
L25:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%ecx
  add    %ecx,0x14(%rsp)
  cmp    %eax,0x1c(%rsp)
  je     L0
L34:
  mov    0xc(%rsp),%edi
  cmp    %edi,0x18(%rsp)
  je     L25
  mov    0x14(%rsp),%r8d
  mov    %r8d,%r11d
  mov    $0x0,%r13d
  mov    $0x0,%r15d
  add    0x10(%rsp),%r8d
  jmp    L50
L45:
  mov    $0x0,%esi
L0:
  mov    %esi,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int get_data_list(int *dptr, int fnode, int m, int k, int cirlen, int brklen, int durlen) {
  int i, p, q;
  int times;
  int *ptr_list;
  int r = (math_pow((m), (k - 1)));
  int val;
  int count = 0;
  times = ((r / cirlen) > 0) ? (r / cirlen) : 1;
  ptr_list = dptr;
  for (p = 0; p < k; ++p) {
    if (p == fnode)
      continue;
    for (i = 0; i < times; ++i) {
      val = p * r + i * cirlen;
      while ((val < p * r + (i + 1) * cirlen) && (val < r * (p + 1))) {
        for (q = 0; q < durlen; ++q) {
          *ptr_list = val;
          ++ptr_list;
          ++val;
          ++count;
        }
        val = val + (brklen - durlen);
      }
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_data_list>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %r9d,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  lea    -0x1(%rcx),%esi
  mov    0x50(%rsp),%ebx
  mov    %ecx,0xc(%rsp)
  call   <math_pow@plt>
  cltd
  mov    %eax,0x4(%rsp)
  idiv   %r12d
  mov    $0x1,%edx
  test   %eax,%eax
  cmovg  %eax,%edx
  test   %r15d,%r15d
  jle    L73
  lea    -0x1(%rbx),%eax
  mov    %r13d,%r9d
  mov    %edx,%r14d
  lea    0x4(,%rax,4),%r10
  xor    %esi,%esi
  xor    %r8d,%r8d
  xor    %r15d,%r15d
  sub    %ebx,%r9d
L96:
  mov    0x4(%rsp),%eax
  lea    (%rsi,%rax,1),%edi
  cmp    %r15d,0x8(%rsp)
  je     L121
  xor    %r11d,%r11d
  xor    %r13d,%r13d
  nop
L19:
  mov    %r11d,%edx
  add    %r12d,%r11d
  mov    %esi,%eax
  add    $0x1,%r13d
  cmp    %r11d,%edx
  jge    L3
  cmp    %edi,%esi
  jge    L3
  lea    (%r12,%rsi,1),%esi
  nopl   0x0(%rax)
L43:
  lea    (%rax,%rbx,1),%ecx
  mov    %rbp,%rdx
  test   %ebx,%ebx
  jle    L7
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L51
  add    %r10,%rbp
  add    %ebx,%r8d
L99:
  lea    (%r9,%rcx,1),%eax
  cmp    %esi,%eax
  jge    L62
  cmp    %edi,%eax
  jl     L43
L62:
  cmp    %r13d,%r14d
  jne    L19
L121:
  add    $0x1,%r15d
  mov    %edi,%esi
  cmp    %r15d,0xc(%rsp)
  jne    L96
L131:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %eax,%ecx
  jmp    L99
L3:
  add    %r12d,%esi
  cmp    %r13d,%r14d
  jne    L19
  jmp    L121
L73:
  xor    %r8d,%r8d
  jmp    L131
```

assistant: ```c
int get_data_list(int *dptr, int fnode, int m, int k, int cirlen, int brklen, int durlen) {
  int i, p, q;
  int times;
  int *ptr_list;
  int r = (math_pow((m), (k - 1)));
  int val;
  int count = 0;
  times = ((r / cirlen) > 0) ? (r / cirlen) : 1;
  ptr_list = dptr;
  for (p = 0; p < k; ++p) {
    if (p == fnode)
      continue;
    for (i = 0; i < times; ++i) {
      val = p * r + i * cirlen;
      while ((val < p * r + (i + 1) * cirlen) && (val < r * (p + 1))) {
        for (q = 0; q < durlen; ++q) {
          *ptr_list = val;
          ++ptr_list;
          ++val;
          ++count;
        }
        val = val + (brklen - durlen);
      }
    }
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L4
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L4:
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %c

assistant: ```c
void printString(const char *str, size_t count) {
  for (; count; count--, str++)
    printf("%c", *str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printString>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
  lea    D0(%rip),%r12
L1:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %c

assistant: ```c
void printString(const char *str, size_t count) {
  for (; count; count--, str++)
    printf("%c", *str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printString>:
  endbr64
  test   %rsi,%rsi
  je     L18
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %c

assistant: ```c
void printString(const char *str, size_t count) {
  for (; count; count--, str++)
    printf("%c", *str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printString>:
  endbr64
  test   %rsi,%rsi
  je     L14
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %c

assistant: ```c
void printString(const char *str, size_t count) {
  for (; count; count--, str++)
    printf("%c", *str);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x77206f6c6c206548,%rax
  movabs $0x20202020646c726f,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x20202020,-0x30(%rbp)
  movb   $0x0,-0x2c(%rbp)
  movabs $0x77206f6c6c654820,%rax
  movabs $0x20202020646c726f,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x20202020,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <rs@plt>
  mov    %rax,%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <rs@plt>
  mov    %rax,%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string

tool: D4: %s


tool: D23: %s, %s


assistant: ```c
main() {
  char data1[] = "He llo world        ";
  char data2[] = " Hello world        ";
  printf("%s\n", data1);
  printf("%s, %s\n", data1, rs(data1, 12));
  printf("%s, %s\n", data2, rs(data2, 12));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x77206f6c6c206548,%rax
  movabs $0x20202020646c726f,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x20202020,0x10(%rsp)
  movb   $0x0,0x14(%rsp)
  movabs $0x77206f6c6c654820,%rax
  movabs $0x20202020646c726f,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movl   $0x20202020,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <rs@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rsp),%rbp
  mov    $0xc,%esi
  mov    %rbp,%rdi
  call   <rs@plt>
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D1: %s


tool: D10: %s, %s


assistant: ```c
main() {
  char data1[] = "He llo world        ";
  char data2[] = " Hello world        ";
  printf("%s\n", data1);
  printf("%s, %s\n", data1, rs(data1, 12));
  printf("%s, %s\n", data2, rs(data2, 12));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  sub    $0x48,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,0x14(%rsp)
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D31(%rip),%xmm0
  mov    %rbp,%rsi
  movl   $0x20202020,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movl   $0x20202020,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xc,%esi
  call   <rs@plt>
  mov    %rbp,%rsi
  lea    D38(%rip),%rbp
  mov    %rax,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %r12,%rdi
  call   <rs@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D26
data_type: byte[16]
name: parse_data
arguments: label: D31
data_type: byte[16]
name: parse_data
arguments: label: D38
data_type: string

tool: D11: %s


tool: {"D26": [0x48,0x65,0x20,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x20,0x20,0x20]}

tool: {"D31": [0x20,0x48,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x20,0x20,0x20]}

tool: D38: %s, %s


assistant: ```c
main() {
  char data1[] = "He llo world        ";
  char data2[] = " Hello world        ";
  printf("%s\n", data1);
  printf("%s, %s\n", data1, rs(data1, 12));
  printf("%s, %s\n", data2, rs(data2, 12));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D33(%rip),%rdi
  push   %rbp
  sub    $0x48,%rsp
  movdqa D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,0x14(%rsp)
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D21(%rip),%xmm0
  mov    %rbp,%rsi
  movl   $0x20202020,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movl   $0x20202020,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xc,%esi
  call   <rs@plt>
  mov    %rbp,%rsi
  lea    D29(%rip),%rbp
  mov    %rax,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  mov    %r12,%rdi
  call   <rs@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D33
datatype: string
name: read_data
arguments: data_label: D27
datatype: byte[16]
name: read_data
arguments: data_label: D21
datatype: byte[16]
name: read_data
arguments: data_label: D29
datatype: string

tool: D33: %s


tool: {"D27": [0x48,0x65,0x20,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x20,0x20,0x20]}

tool: {"D21": [0x20,0x48,0x65,0x6c,0x6c,0x6f,0x20,0x77,0x6f,0x72,0x6c,0x64,0x20,0x20,0x20,0x20]}

tool: D29: %s, %s


assistant: ```c
main() {
  char data1[] = "He llo world        ";
  char data2[] = " Hello world        ";
  printf("%s\n", data1);
  printf("%s, %s\n", data1, rs(data1, 12));
  printf("%s, %s\n", data2, rs(data2, 12));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_keyval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L6
L7:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
int parse_keyval(char *s, long *val) {
  char *p;
  p = strchr(s, '=');
  if (!p)
    return -1;
  *val = atol(p + 1);
  return p - s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_keyval>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x3d,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbx
  lea    0x1(%rax),%rdi
  call   <atol@plt>
  mov    %rax,(%r12)
  mov    %ebx,%eax
  sub    %ebp,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int parse_keyval(char *s, long *val) {
  char *p;
  p = strchr(s, '=');
  if (!p)
    return -1;
  *val = atol(p + 1);
  return p - s;
}
```