ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bubblesort>:
  endbr64
  test   %rdi,%rdi
  je     L47
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jge    L11
  lea    0x1(%rsi),%r13d
  mov    %rdi,%r12
  movslq %r13d,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L77:
  cmp    %ebx,%r13d
  je     L73
  mov    $0xfffffffe,%eax
  movslq %ebp,%rdx
  mov    0x8(%rsp),%r14
  sub    %ebp,%eax
  add    %ebx,%eax
  mov    %eax,%eax
  add    %rdx,%rax
  lea    0x8(%r12,%rax,4),%r15
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x4,%r14
  cmp    %r15,%r14
  je     L73
L62:
  mov    (%r14),%eax
  lea    -0x4(%r14),%rdi
  cmp    %eax,-0x4(%r14)
  jle    L24
  mov    %r14,%rsi
  add    $0x4,%r14
  call   <swap@plt>
  cmp    %r15,%r14
  jne    L62
L73:
  sub    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L77
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  ret
```

assistant: ```c
void bubblesort(int *array, int left, int right) {
  if (array == NULL || left >= right)
    return;
  int i, j;
  for (i = right; i != left; --i) {
    for (j = left + 1; j != i; ++j) {
      if (array[j - 1] > array[j])
        swap(&array[j - 1], &array[j]);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bubblesort>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jge    L38
  lea    0x1(%rsi),%r13d
  mov    %rdi,%r12
  movslq %r13d,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L17:
  cmp    %ebx,%r13d
  je     L41
  mov    $0xfffffffe,%eax
  movslq %ebp,%rdx
  mov    0x8(%rsp),%r14
  sub    %ebp,%eax
  add    %ebx,%eax
  mov    %eax,%eax
  add    %rdx,%rax
  lea    0x8(%r12,%rax,4),%r15
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L54:
  add    $0x4,%r14
  cmp    %r15,%r14
  je     L41
L55:
  mov    (%r14),%eax
  lea    -0x4(%r14),%rdi
  cmp    %eax,-0x4(%r14)
  jle    L54
  mov    %r14,%rsi
  add    $0x4,%r14
  call   <swap@plt>
  cmp    %r15,%r14
  jne    L55
L41:
  sub    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L17
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  ret
```

assistant: ```c
void bubblesort(int *array, int left, int right) {
  if (array == NULL || left >= right)
    return;
  int i, j;
  for (i = right; i != left; --i) {
    for (j = left + 1; j != i; ++j) {
      if (array[j - 1] > array[j])
        swap(&array[j - 1], &array[j]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L32
  lea    D18(%rip),%rax
  jmp    L33
L32:
  lea    D31(%rip),%rax
L33:
  mov    -0x14(%rbp),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L2:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D31
type_infered: string
name: read_data
arguments: data_tag: D32
type_infered: string
name: read_data
arguments: data_tag: D0
type_infered: string

tool: 

tool: D31: s

tool: D32: Loading %d module%s.


tool: D0: Module #%d - <%s> at %x


assistant: ```c
int main(unsigned int pcount, char *pgname[], void *pgptrs[]) {
  unsigned int cur;
  printf("Loading %d module%s.\n", pcount, pcount == 1 ? "" : "s");
  for (cur = 0; cur < pcount; cur++) {
    printf("Module #%d - <%s> at %x\n", cur, pgname[cur], pgptrs[cur]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  cmp    $0x1,%edi
  je     L0
  mov    %edi,%ebp
  lea    D43(%rip),%rdx
  mov    %edi,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L7
  mov    $0x0,%ebx
  lea    D54(%rip),%r14
L33:
  mov    0x0(%r13,%rbx,8),%rcx
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  ja     L33
L7:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  lea    D18(%rip),%rdx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%r13),%rcx
  mov    (%r12),%rdx
  mov    $0x0,%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D54
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string

tool: D43: s

tool: D16: Loading %d module%s.


tool: D54: Module #%d - <%s> at %x


tool: 

assistant: ```c
int main(unsigned int pcount, char *pgname[], void *pgptrs[]) {
  unsigned int cur;
  printf("Loading %d module%s.\n", pcount, pcount == 1 ? "" : "s");
  for (cur = 0; cur < pcount; cur++) {
    printf("Module #%d - <%s> at %x\n", cur, pgname[cur], pgptrs[cur]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L37
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D19(%rip),%rdx
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L24
  xor    %ebx,%ebx
  lea    D26(%rip),%r14
  nopl   (%rax)
L6:
  mov    0x0(%r13,%rbx,8),%rcx
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  ja     L6
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  lea    D44(%rip),%rdx
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%r13),%rcx
  mov    (%r12),%rdx
  xor    %esi,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D12
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D44
type_infered: string

tool: D19: s

tool: D12: Loading %d module%s.


tool: D26: Module #%d - <%s> at %x


tool: 

assistant: ```c
int main(unsigned int pcount, char *pgname[], void *pgptrs[]) {
  unsigned int cur;
  printf("Loading %d module%s.\n", pcount, pcount == 1 ? "" : "s");
  for (cur = 0; cur < pcount; cur++) {
    printf("Module #%d - <%s> at %x\n", cur, pgname[cur], pgptrs[cur]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L35
  mov    %edi,%ebp
  mov    %edi,%esi
  lea    D21(%rip),%rdx
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  je     L25
  xor    %ebx,%ebx
  lea    D40(%rip),%r14
  nopl   (%rax)
L11:
  mov    0x0(%r13,%rbx,8),%rcx
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  ja     L11
L25:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  lea    D12(%rip),%rdx
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%r13),%rcx
  mov    (%r12),%rdx
  xor    %esi,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D40
type: string
name: unpack_data
arguments: label: D12
type: string

tool: D21: s

tool: D10: Loading %d module%s.


tool: D40: Module #%d - <%s> at %x


tool: 

assistant: ```c
int main(unsigned int pcount, char *pgname[], void *pgptrs[]) {
  unsigned int cur;
  printf("Loading %d module%s.\n", pcount, pcount == 1 ? "" : "s");
  for (cur = 0; cur < pcount; cur++) {
    printf("Module #%d - <%s> at %x\n", cur, pgname[cur], pgptrs[cur]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseElements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0x16(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  cmpb   $0x5c,-0x15(%rbp)
  jne    L67
  movb   $0x1,-0x16(%rbp)
  jmp    L103
L67:
  cmpb   $0x2c,-0x15(%rbp)
  jne    L51
  cmpb   $0x0,-0x16(%rbp)
  je     L49
L51:
  cmpb   $0x0,-0x15(%rbp)
  jne    L16
L49:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copyStringNoEscape@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jge    L102
  cmpb   $0x0,-0x15(%rbp)
  je     L102
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L103
L16:
  movb   $0x0,-0x16(%rbp)
L103:
  addl   $0x1,-0x14(%rbp)
  jmp    L15
L102:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L70:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L70
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int parseElements(char *line, char **elements, int n) {
  int i = 0, j = 0, start = 0;
  char c, escaped = 0;
  while (1) {
    c = line[i];
    if (c == '\\') {
      escaped = 1;
    } else if (c == ',' && !escaped || !c) {
      int size = i - start;
      elements[j] = (char *)calloc(size + 1, sizeof(char));
      copyStringNoEscape(elements[j], line + start * sizeof(char), size);
      elements[j][size] = '\0';
      if (++j >= n || !c) {
        break;
      }
      start = i + 1;
    } else {
      escaped = 0;
    }
    i++;
  }
  int k;
  for (k = j; k < n; k++) {
    elements[k] = NULL;
  }
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parseElements>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    $0x0,%ebx
  movb   $0x0,0xb(%rsp)
  movl   $0x0,(%rsp)
  mov    $0x0,%r12d
  jmp    L50
L38:
  sub    (%rsp),%ebp
  lea    0x1(%rbp),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  movslq %r12d,%rax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
  mov    0x10(%rsp),%r15
  add    %rax,%r15
  mov    %rdi,(%r15)
  movslq (%rsp),%rsi
  add    %r13,%rsi
  mov    %ebp,%edx
  call   <copyStringNoEscape@plt>
  movslq %ebp,%rbp
  mov    (%r15),%rax
  movb   $0x0,(%rax,%rbp,1)
  add    $0x1,%r12d
  cmp    0xc(%rsp),%r12d
  jge    L62
  test   %r14b,%r14b
  jne    L62
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp)
L64:
  add    $0x1,%rbx
L50:
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%ebp
  movzbl 0x0(%r13,%rbx,1),%eax
  cmp    $0x5c,%al
  je     L61
  test   %al,%al
  sete   %r14b
  cmp    $0x2c,%al
  sete   %dl
  movzbl 0xb(%rsp),%eax
  xor    $0x1,%eax
  test   %al,%dl
  jne    L38
  test   %r14b,%r14b
  jne    L38
  movb   $0x0,0xb(%rsp)
  jmp    L64
L62:
  cmp    0xc(%rsp),%r12d
  jge    L99
  mov    0x10(%rsp),%rsi
  mov    0x18(%rsp),%rax
  lea    0x8(%rsi,%rax,1),%rax
  mov    0xc(%rsp),%edx
  sub    $0x1,%edx
  sub    %r12d,%edx
  movslq %r12d,%rcx
  add    %rcx,%rdx
  lea    0x8(%rsi,%rdx,8),%rdx
L16:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
L99:
  mov    %r12d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  movb   $0x1,0xb(%rsp)
  jmp    L64
```

assistant: ```c
int parseElements(char *line, char **elements, int n) {
  int i = 0, j = 0, start = 0;
  char c, escaped = 0;
  while (1) {
    c = line[i];
    if (c == '\\') {
      escaped = 1;
    } else if (c == ',' && !escaped || !c) {
      int size = i - start;
      elements[j] = (char *)calloc(size + 1, sizeof(char));
      copyStringNoEscape(elements[j], line + start * sizeof(char), size);
      elements[j][size] = '\0';
      if (++j >= n || !c) {
        break;
      }
      start = i + 1;
    } else {
      escaped = 0;
    }
    i++;
  }
  int k;
  for (k = j; k < n; k++) {
    elements[k] = NULL;
  }
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parseElements>:
  endbr64
  push   %r15
  xor    %r10d,%r10d
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x14(%rsp)
  jmp    L50
  xchg   %ax,%ax
L21:
  cmp    $0x2c,%cl
  mov    %r10d,%eax
  sete   %sil
  xor    $0x1,%eax
  test   %al,%sil
  jne    L76
  test   %cl,%cl
  jne    L41
L76:
  sub    %r14d,%edx
  movslq %r15d,%rbp
  mov    0x8(%rsp),%r13
  mov    $0x1,%esi
  lea    0x0(,%rbp,8),%rax
  lea    0x1(%rdx),%edi
  mov    %edx,%ebp
  mov    %r9d,0x10(%rsp)
  add    %rax,%r13
  mov    %cl,0x6(%rsp)
  add    $0x1,%r15d
  mov    %r10b,0x7(%rsp)
  mov    %rax,0x18(%rsp)
  call   <calloc@plt>
  movslq %r14d,%rsi
  mov    %ebp,%edx
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  add    %r12,%rsi
  call   <copyStringNoEscape@plt>
  mov    0x0(%r13),%rax
  movslq %ebp,%rdx
  movb   $0x0,(%rax,%rdx,1)
  cmp    %r15d,0x14(%rsp)
  jle    L69
  movzbl 0x6(%rsp),%ecx
  test   %cl,%cl
  je     L60
  mov    0x10(%rsp),%r9d
  movzbl 0x7(%rsp),%r10d
  lea    0x1(%r9),%r14d
L42:
  add    $0x1,%rbx
L50:
  movzbl (%r12,%rbx,1),%ecx
  mov    %ebx,%r9d
  mov    %ebx,%edx
  cmp    $0x5c,%cl
  jne    L21
  mov    $0x1,%r10d
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %r10d,%r10d
  jmp    L42
  nopl   (%rax)
L60:
  mov    0x14(%rsp),%r14d
  mov    0x8(%rsp),%rax
  xor    %esi,%esi
  mov    0x18(%rsp),%rdi
  sub    $0x1,%r14d
  sub    %r15d,%r14d
  lea    0x8(%rax,%rdi,1),%rdi
  lea    0x8(,%r14,8),%rdx
  call   <memset@plt>
L69:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int parseElements(char *line, char **elements, int n) {
  int i = 0, j = 0, start = 0;
  char c, escaped = 0;
  while (1) {
    c = line[i];
    if (c == '\\') {
      escaped = 1;
    } else if (c == ',' && !escaped || !c) {
      int size = i - start;
      elements[j] = (char *)calloc(size + 1, sizeof(char));
      copyStringNoEscape(elements[j], line + start * sizeof(char), size);
      elements[j][size] = '\0';
      if (++j >= n || !c) {
        break;
      }
      start = i + 1;
    } else {
      escaped = 0;
    }
    i++;
  }
  int k;
  for (k = j; k < n; k++) {
    elements[k] = NULL;
  }
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parseElements>:
  endbr64
  push   %r15
  xor    %r10d,%r10d
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x14(%rsp)
  jmp    L29
  xchg   %ax,%ax
L2:
  cmp    $0x2c,%cl
  mov    %r10d,%eax
  sete   %sil
  xor    $0x1,%eax
  test   %al,%sil
  jne    L63
  test   %cl,%cl
  jne    L34
L63:
  sub    %r14d,%edx
  movslq %r15d,%rbp
  mov    0x8(%rsp),%r13
  mov    $0x1,%esi
  lea    0x0(,%rbp,8),%rax
  lea    0x1(%rdx),%edi
  mov    %edx,%ebp
  mov    %r9d,0x10(%rsp)
  add    %rax,%r13
  mov    %cl,0x6(%rsp)
  add    $0x1,%r15d
  mov    %r10b,0x7(%rsp)
  mov    %rax,0x18(%rsp)
  call   <calloc@plt>
  movslq %r14d,%rsi
  mov    %ebp,%edx
  mov    %rax,0x0(%r13)
  mov    %rax,%rdi
  add    %r12,%rsi
  call   <copyStringNoEscape@plt>
  mov    0x0(%r13),%rax
  movslq %ebp,%rdx
  movb   $0x0,(%rax,%rdx,1)
  cmp    %r15d,0x14(%rsp)
  jle    L78
  movzbl 0x6(%rsp),%ecx
  test   %cl,%cl
  je     L4
  mov    0x10(%rsp),%r9d
  movzbl 0x7(%rsp),%r10d
  lea    0x1(%r9),%r14d
L40:
  add    $0x1,%rbx
L29:
  movzbl (%r12,%rbx,1),%ecx
  mov    %ebx,%r9d
  mov    %ebx,%edx
  cmp    $0x5c,%cl
  jne    L2
  mov    $0x1,%r10d
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %r10d,%r10d
  jmp    L40
  nopl   (%rax)
L4:
  mov    0x14(%rsp),%r14d
  mov    0x8(%rsp),%rax
  xor    %esi,%esi
  mov    0x18(%rsp),%rdi
  sub    $0x1,%r14d
  sub    %r15d,%r14d
  lea    0x8(%rax,%rdi,1),%rdi
  lea    0x8(,%r14,8),%rdx
  call   <memset@plt>
L78:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int parseElements(char *line, char **elements, int n) {
  int i = 0, j = 0, start = 0;
  char c, escaped = 0;
  while (1) {
    c = line[i];
    if (c == '\\') {
      escaped = 1;
    } else if (c == ',' && !escaped || !c) {
      int size = i - start;
      elements[j] = (char *)calloc(size + 1, sizeof(char));
      copyStringNoEscape(elements[j], line + start * sizeof(char), size);
      elements[j][size] = '\0';
      if (++j >= n || !c) {
        break;
      }
      start = i + 1;
    } else {
      escaped = 0;
    }
    i++;
  }
  int k;
  for (k = j; k < n; k++) {
    elements[k] = NULL;
  }
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string

tool: D0: i = %d, j = %d


assistant: ```c
int main() {
  int i = 0 / 5;
  int j = -2 / 5;
  printf("i = %d, j = %d\n", i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: i = %d, j = %d


assistant: ```c
int main() {
  int i = 0 / 5;
  int j = -2 / 5;
  printf("i = %d, j = %d\n", i, j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  lea    D2(%rip),%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: i = %d, j = %d


assistant: ```c
int main() {
  int i = 0 / 5;
  int j = -2 / 5;
  printf("i = %d, j = %d\n", i, j);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  lea    D1(%rip),%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: i = %d, j = %d


assistant: ```c
int main() {
  int i = 0 / 5;
  int j = -2 / 5;
  printf("i = %d, j = %d\n", i, j);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_device_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_device_size(int fd, struct stat *st) {
  unsigned long long blksize = 0;
  int ret = 0;
  ret = -1;
  errno = ENOSYS;
  blksize = 0;
  (void)fd;
  st->st_size = blksize;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_device_size>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  movq   $0x0,(%rsi)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int get_device_size(int fd, struct stat *st) {
  unsigned long long blksize = 0;
  int ret = 0;
  ret = -1;
  errno = ENOSYS;
  blksize = 0;
  (void)fd;
  st->st_size = blksize;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_device_size>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
int get_device_size(int fd, struct stat *st) {
  unsigned long long blksize = 0;
  int ret = 0;
  ret = -1;
  errno = ENOSYS;
  blksize = 0;
  (void)fd;
  st->st_size = blksize;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_device_size>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
int get_device_size(int fd, struct stat *st) {
  unsigned long long blksize = 0;
  int ret = 0;
  ret = -1;
  errno = ENOSYS;
  blksize = 0;
  (void)fd;
  st->st_size = blksize;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signals_unblock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x14(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  test   %rax,%rax
  jne    L38
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  test   %rax,%rax
  je     L8
L38:
  mov    $0x0,%eax
  jmp    L32
L8:
  mov    $0x1,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int signals_unblock(int signo) {
  sigset_t mask;
  if (sigemptyset(&mask) || sigaddset(&mask, signo) || sigprocmask(SIG_UNBLOCK, &mask, NULL)) {
    return 0;
  }
  return 1;
}
```