ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fatfs_total_path_levels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L37
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L70
  movb   $0x2f,-0x9(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L51
L70:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L35
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L45
L35:
  movb   $0x5c,-0x9(%rbp)
  addq   $0x3,-0x18(%rbp)
  jmp    L53
L45:
  mov    $0xffffffff,%eax
  jmp    L37
L53:
  jmp    L51
L92:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  jne    L44
  addq   $0x1,-0x18(%rbp)
  jmp    L64
L44:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L85:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L92
L64:
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L85
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
L37:
  leave
  ret
```

assistant: ```c
int fatfs_total_path_levels(char *path) {
  int levels = 0;
  int length = (int)strlen(path);
  char expectedchar;
  if (!path)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  while (*path) {
    for (*path; *path;) {
      if (*path == expectedchar) {
        path++;
        break;
      }
      *path++;
    }
    levels++;
  }
  return levels - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatfs_total_path_levels>:
  endbr64
  test   %rdi,%rdi
  je     L90
  movzbl (%rdi),%ecx
  cmp    $0x2f,%cl
  je     L45
  cmpb   $0x3a,0x1(%rdi)
  je     L5
  cmpb   $0x5c,0x2(%rdi)
  jne    L72
L5:
  add    $0x3,%rdi
  mov    $0x5c,%ecx
L59:
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rax
  mov    $0x0,%esi
  test   %dl,%dl
  jne    L39
  jmp    L64
L45:
  add    $0x1,%rdi
  jmp    L59
L83:
  add    $0x1,%esi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L64
L78:
  add    $0x1,%rax
L39:
  cmp    %dl,%cl
  je     L83
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L78
  add    $0x1,%esi
L64:
  lea    -0x1(%rsi),%eax
  ret
L90:
  mov    $0xffffffff,%eax
  ret
L72:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fatfs_total_path_levels(char *path) {
  int levels = 0;
  int length = (int)strlen(path);
  char expectedchar;
  if (!path)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  while (*path) {
    for (*path; *path;) {
      if (*path == expectedchar) {
        path++;
        break;
      }
      *path++;
    }
    levels++;
  }
  return levels - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fatfs_total_path_levels>:
  endbr64
  movzbl (%rdi),%esi
  lea    0x1(%rdi),%rax
  cmp    $0x2f,%sil
  je     L30
  cmpb   $0x3a,0x1(%rdi)
  je     L46
  cmpb   $0x5c,0x2(%rdi)
  jne    L37
L46:
  lea    0x3(%rdi),%rax
  mov    $0x5c,%esi
L30:
  movzbl (%rax),%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edi
  test   %cl,%cl
  je     L37
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%sil
  je     L45
  nopw   0x0(%rax,%rax,1)
L12:
  test   %dl,%dl
  je     L83
  mov    %edx,%ecx
L84:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%sil
  jne    L12
L45:
  test   %dl,%dl
  je     L83
  mov    %edi,%r8d
  mov    %edx,%ecx
  add    $0x1,%edi
  jmp    L84
L37:
  mov    $0xffffffff,%r8d
L83:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fatfs_total_path_levels(char *path) {
  int levels = 0;
  int length = (int)strlen(path);
  char expectedchar;
  if (!path)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  while (*path) {
    for (*path; *path;) {
      if (*path == expectedchar) {
        path++;
        break;
      }
      *path++;
    }
    levels++;
  }
  return levels - 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fatfs_total_path_levels>:
  endbr64
  movzbl (%rdi),%esi
  lea    0x1(%rdi),%rax
  cmp    $0x2f,%sil
  je     L47
  cmpb   $0x3a,0x1(%rdi)
  je     L69
  cmpb   $0x5c,0x2(%rdi)
  jne    L54
L69:
  lea    0x3(%rdi),%rax
  mov    $0x5c,%esi
L47:
  movzbl (%rax),%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edi
  test   %cl,%cl
  je     L54
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%sil
  je     L74
  nopw   0x0(%rax,%rax,1)
L45:
  test   %dl,%dl
  je     L68
  mov    %edx,%ecx
L36:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%sil
  jne    L45
L74:
  test   %dl,%dl
  je     L68
  mov    %edi,%r8d
  mov    %edx,%ecx
  add    $0x1,%edi
  jmp    L36
L54:
  mov    $0xffffffff,%r8d
L68:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fatfs_total_path_levels(char *path) {
  int levels = 0;
  int length = (int)strlen(path);
  char expectedchar;
  if (!path)
    return -1;
  if (*path == '/') {
    expectedchar = '/';
    path++;
  } else if (path[1] == ':' || path[2] == '\\') {
    expectedchar = '\\';
    path += 3;
  } else
    return -1;
  while (*path) {
    for (*path; *path;) {
      if (*path == expectedchar) {
        path++;
        break;
      }
      *path++;
    }
    levels++;
  }
  return levels - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exithelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: Usage: fwcrypt [options] -i infile -o outfile
	 -e Encrypt (default)
	 -d Decrypt
	 -n No output (dry run)
	 -c Without checksum signature


assistant: ```c
void exithelp(void) {
  printf("Usage: fwcrypt [options] -i infile -o outfile\n"
         "\t -e Encrypt (default)\n"
         "\t -d Decrypt\n"
         "\t -n No output (dry run)\n"
         "\t -c Without checksum signature\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<exithelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: Usage: fwcrypt [options] -i infile -o outfile
	 -e Encrypt (default)
	 -d Decrypt
	 -n No output (dry run)
	 -c Without checksum signature


assistant: ```c
void exithelp(void) {
  printf("Usage: fwcrypt [options] -i infile -o outfile\n"
         "\t -e Encrypt (default)\n"
         "\t -d Decrypt\n"
         "\t -n No output (dry run)\n"
         "\t -c Without checksum signature\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<exithelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: Usage: fwcrypt [options] -i infile -o outfile
	 -e Encrypt (default)
	 -d Decrypt
	 -n No output (dry run)
	 -c Without checksum signature


assistant: ```c
void exithelp(void) {
  printf("Usage: fwcrypt [options] -i infile -o outfile\n"
         "\t -e Encrypt (default)\n"
         "\t -d Decrypt\n"
         "\t -n No output (dry run)\n"
         "\t -c Without checksum signature\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exithelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: Usage: fwcrypt [options] -i infile -o outfile
	 -e Encrypt (default)
	 -d Decrypt
	 -n No output (dry run)
	 -c Without checksum signature


assistant: ```c
void exithelp(void) {
  printf("Usage: fwcrypt [options] -i infile -o outfile\n"
         "\t -e Encrypt (default)\n"
         "\t -d Decrypt\n"
         "\t -n No output (dry run)\n"
         "\t -c Without checksum signature\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<impl__xmallocz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <impl__xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *impl__xmallocz(size_t size) {
  void *ret = impl__xmalloc(size);
  memset(ret, 0, size);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<impl__xmallocz>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <impl__xmalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *impl__xmallocz(size_t size) {
  void *ret = impl__xmalloc(size);
  memset(ret, 0, size);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<impl__xmallocz>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <impl__xmalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *impl__xmallocz(size_t size) {
  void *ret = impl__xmalloc(size);
  memset(ret, 0, size);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<impl__xmallocz>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <impl__xmalloc@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *impl__xmallocz(size_t size) {
  void *ret = impl__xmalloc(size);
  memset(ret, 0, size);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dct64_i386>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %rsi,-0x220(%rbp)
  mov    %rdx,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  add    $0x100,%rax
  mov    -0x228(%rbp),%rcx
  lea    -0x210(%rbp),%rdx
  mov    -0x220(%rbp),%rsi
  mov    -0x218(%rbp),%rdi
  mov    %rcx,%r8
  mov    %rax,%rcx
  call   <dct64_1@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void dct64_i386(double *a, double *b, double *c) {
  double bufs[0x40];
  dct64_1(a, b, bufs, bufs + 0x20, c);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dct64_i386>:
  endbr64
  sub    $0x218,%rsp
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x100(%rsp),%rcx
  call   <dct64_1@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x218,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dct64_i386(double *a, double *b, double *c) {
  double bufs[0x40];
  dct64_1(a, b, bufs, bufs + 0x20, c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dct64_i386>:
  endbr64
  sub    $0x218,%rsp
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x100(%rsp),%rcx
  call   <dct64_1@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x218,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dct64_i386(double *a, double *b, double *c) {
  double bufs[0x40];
  dct64_1(a, b, bufs, bufs + 0x20, c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dct64_i386>:
  endbr64
  sub    $0x218,%rsp
  mov    %rdx,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x100(%rsp),%rcx
  call   <dct64_1@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x218,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void dct64_i386(double *a, double *b, double *c) {
  double bufs[0x40];
  dct64_1(a, b, bufs, bufs + 0x20, c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testFunc1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  testFunc1();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testFunc1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testFunc1();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testFunc1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testFunc1();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testFunc1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testFunc1();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<perm_parity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L15:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L30
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L0
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
L0:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int perm_parity(int *perm, int n) {
  int i, j, ret;
  ret = 0;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (perm[i] > perm[j])
        ret = !ret;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<perm_parity>:
  endbr64
  cmp    $0x1,%esi
  jle    L74
  lea    -0x2(%rsi),%r9d
  add    $0x2,%r9
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  jmp    L35
L8:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L44
L31:
  cmp    (%rdi,%rax,4),%edx
  jle    L8
  xor    $0x1,%ecx
  jmp    L8
L44:
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L28
L35:
  cmp    %r8d,%esi
  jle    L44
  mov    -0x4(%rdi,%r8,4),%edx
  mov    %r8,%rax
  jmp    L31
L74:
  mov    $0x0,%ecx
L28:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int perm_parity(int *perm, int n) {
  int i, j, ret;
  ret = 0;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (perm[i] > perm[j])
        ret = !ret;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<perm_parity>:
  endbr64
  cmp    $0x1,%esi
  jle    L12
  lea    -0x2(%rsi),%r9d
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  add    $0x2,%r9
  nopl   0x0(%rax)
L13:
  cmp    %ecx,%esi
  jle    L7
  mov    -0x4(%rdi,%rcx,4),%edx
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L25:
  cmp    (%rdi,%rax,4),%edx
  jle    L44
  xor    $0x1,%r8d
L44:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L25
L7:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L13
  mov    %r8d,%eax
  ret
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int perm_parity(int *perm, int n) {
  int i, j, ret;
  ret = 0;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (perm[i] > perm[j])
        ret = !ret;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<perm_parity>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  lea    -0x2(%rsi),%r9d
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  add    $0x2,%r9
  nopl   0x0(%rax)
L45:
  cmp    %ecx,%esi
  jle    L47
  mov    -0x4(%rdi,%rcx,4),%edx
  mov    %rcx,%rax
  nopl   0x0(%rax,%rax,1)
L46:
  cmp    (%rdi,%rax,4),%edx
  jle    L41
  xor    $0x1,%r8d
L41:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L46
L47:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L45
  mov    %r8d,%eax
  ret
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int perm_parity(int *perm, int n) {
  int i, j, ret;
  ret = 0;
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++)
      if (perm[i] > perm[j])
        ret = !ret;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yahoo_f01_09>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  xor    $0x191265c,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <yahoo_M1Common@plt>
  leave
  ret
```

assistant: ```c
int yahoo_f01_09(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x191265C;
  return yahoo_M1Common(b, Parameter);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yahoo_f01_09>:
  endbr64
  sub    $0x8,%rsp
  xor    $0x191265c,%edi
  call   <yahoo_M1Common@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yahoo_f01_09(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x191265C;
  return yahoo_M1Common(b, Parameter);
}
```
user: Translate the below assembly code into C programming language:

```asm
<yahoo_f01_09>:
  endbr64
  xor    $0x191265c,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_09(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x191265C;
  return yahoo_M1Common(b, Parameter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<yahoo_f01_09>:
  endbr64
  xor    $0x191265c,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_09(int Salt, int Parameter) {
  unsigned b = Salt ^ 0x191265C;
  return yahoo_M1Common(b, Parameter);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  movabs $0xe80000000056046d,%rdx
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] == local2 + local1) {
          state[0UL] |= ((state[local2] + state[0UL]) & 15UL) << 2UL;
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + 0xe80000000056046dUL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  movabs $0xe80000000056046d,%rdx
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] == local2 + local1) {
          state[0UL] |= ((state[local2] + state[0UL]) & 15UL) << 2UL;
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + 0xe80000000056046dUL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movabs $0xe80000000056046d,%rdx
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] == local2 + local1) {
          state[0UL] |= ((state[local2] + state[0UL]) & 15UL) << 2UL;
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + 0xe80000000056046dUL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movabs $0xe80000000056046d,%rdx
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] == local2 + local1) {
          state[0UL] |= ((state[local2] + state[0UL]) & 15UL) << 2UL;
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + 0xe80000000056046dUL;
  }
}
```