user: What would the C source look like for the assembly code provided here?

```asm
<get_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x218(%rbp)
  movl   $0x0,-0x214(%rbp)
  movl   $0x0,-0x208(%rbp)
  movl   $0x0,-0x204(%rbp)
  movl   $0x0,-0x210(%rbp)
  movl   $0x0,-0x20c(%rbp)
  cmpl   $0x2,-0x22c(%rbp)
  jne    L28
  mov    -0x228(%rbp),%rax
  mov    0x4(%rax),%eax
  jmp    L54
L28:
  cmpl   $0x3,-0x22c(%rbp)
  jne    L44
  mov    -0x228(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x210(%rbp)
  mov    -0x228(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0x210(%rbp)
  jge    L47
  mov    -0x228(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x210(%rbp)
L47:
  mov    -0x228(%rbp),%rax
  add    $0x2c,%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0x210(%rbp)
  jge    L102
  mov    -0x228(%rbp),%rax
  add    $0x2c,%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x210(%rbp)
L102:
  mov    -0x210(%rbp),%eax
  jmp    L54
L44:
  movl   $0x0,-0x218(%rbp)
  jmp    L60
L98:
  movl   $0x0,-0x214(%rbp)
  jmp    L50
L134:
  cmpl   $0x0,-0x214(%rbp)
  jle    L130
  mov    -0x218(%rbp),%eax
  cmp    -0x214(%rbp),%eax
  je     L130
  mov    -0x218(%rbp),%eax
  cmp    -0x214(%rbp),%eax
  jge    L130
  lea    -0x200(%rbp),%rdi
  mov    -0x228(%rbp),%rcx
  mov    -0x22c(%rbp),%edx
  mov    -0x214(%rbp),%esi
  mov    -0x218(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <delete_com@plt>
  mov    -0x218(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x228(%rbp),%rax
  add    %rax,%rdx
  mov    -0x214(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ebx
  mov    -0x22c(%rbp),%eax
  lea    -0x2(%rax),%edx
  lea    -0x200(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get_max>
  add    %ebx,%eax
  mov    %eax,-0x210(%rbp)
  mov    -0x20c(%rbp),%edx
  mov    -0x210(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x20c(%rbp)
L130:
  addl   $0x1,-0x214(%rbp)
L50:
  mov    -0x214(%rbp),%eax
  cmp    -0x22c(%rbp),%eax
  jl     L134
  addl   $0x1,-0x218(%rbp)
L60:
  mov    -0x218(%rbp),%eax
  cmp    -0x22c(%rbp),%eax
  jl     L98
  mov    -0x20c(%rbp),%eax
L54:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L100
  call   <__stack_chk_fail@plt>
L100:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int get_max(int comb[11][11], int goods_num) {
  int i = 0;
  int j = 0;
  int x = 0;
  int y = 0;
  int temp_comb[11][11];
  int temp_max = 0;
  int max_price = 0;
  if (goods_num == 2)
    return comb[0][1];
  if (goods_num == 3) {
    temp_max = comb[0][1];
    if (temp_max < comb[0][2])
      temp_max = comb[0][2];
    if (temp_max < comb[1][2])
      temp_max = comb[1][2];
    return temp_max;
  }
  for (i = 0; i < goods_num; i++) {
    for (j = 0; j < goods_num; j++) {
      if ((j > 0) && (i != j) && (i < j)) {
        delete_com(i, j, goods_num, comb, temp_comb);
        temp_max = comb[i][j] + get_max(temp_comb, goods_num - 2);
        max_price = max_price > temp_max ? max_price : temp_max;
      }
    }
  }
  return max_price;
}
```