ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<random_number>:
  endbr64
  push   %rbp
  lea    0x1(%rsi),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jl     L1
  mov    %ebp,%ebx
  mov    %edi,%ebp
L1:
  xor    %edi,%edi
  sub    %ebx,%ebp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  add    $0x8,%rsp
  cltd
  cvtsi2sd %ebx,%xmm1
  pop    %rbx
  idiv   %ebp
  pop    %rbp
  cvtsi2sd %edx,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double random_number(int min_num, int max_num) {
  int result = 0, low_num = 0, hi_num = 0;
  if (min_num < max_num) {
    low_num = min_num;
    hi_num = max_num + 1;
  } else {
    low_num = max_num + 1;
    hi_num = min_num;
  }
  srand(time(NULL));
  result = (double)(rand() % (hi_num - low_num)) + low_num;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_number>:
  endbr64
  push   %rbp
  lea    0x1(%rsi),%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jl     L8
  mov    %ebp,%ebx
  mov    %edi,%ebp
L8:
  xor    %edi,%edi
  sub    %ebx,%ebp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  add    $0x8,%rsp
  cltd
  cvtsi2sd %ebx,%xmm1
  pop    %rbx
  idiv   %ebp
  pop    %rbp
  cvtsi2sd %edx,%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double random_number(int min_num, int max_num) {
  int result = 0, low_num = 0, hi_num = 0;
  if (min_num < max_num) {
    low_num = min_num;
    hi_num = max_num + 1;
  } else {
    low_num = max_num + 1;
    hi_num = min_num;
  }
  srand(time(NULL));
  result = (double)(rand() % (hi_num - low_num)) + low_num;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L27
L16:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rotr@plt>
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
data_type: string
name: disassemble_data
arguments: tag: D68
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D40
data_type: string

tool: D25: %d

tool: D68: 
%d

tool: D1:  %d

tool: D40:  %d


assistant: ```c
int main() {
  int n, i, a, b, c;
  i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  while (i < n) {
    rotr(&a, &b, &c);
    i++;
  }
  printf("\n%d", a);
  printf(" %d", b);
  printf(" %d\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L25
  mov    $0x0,%ebx
  lea    0x14(%rsp),%rbp
L3:
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %rbp,%rdx
  call   <rotr@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x8(%rsp)
  jg     L3
L25:
  mov    0xc(%rsp),%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D38
data_type: string
name: parse_data
arguments: data_label: D31
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D14
data_type: string

tool: D38: %d

tool: D31: 
%d

tool: D10:  %d

tool: D14:  %d


assistant: ```c
int main() {
  int n, i, a, b, c;
  i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  while (i < n) {
    rotr(&a, &b, &c);
    i++;
  }
  printf("\n%d", a);
  printf(" %d", b);
  printf(" %d\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  lea    0x14(%rsp),%r13
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L5
  xor    %ebx,%ebx
  xchg   %ax,%ax
L6:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L6
L5:
  mov    0xc(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string
name: retrieve_data
arguments: data_label: D36
data_type: string

tool: D0: %d

tool: D13: 
%d

tool: D12:  %d

tool: D36:  %d


assistant: ```c
int main() {
  int n, i, a, b, c;
  i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  while (i < n) {
    rotr(&a, &b, &c);
    i++;
  }
  printf("\n%d", a);
  printf(" %d", b);
  printf(" %d\n", c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  lea    0x14(%rsp),%r13
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L25
  xor    %ebx,%ebx
  xchg   %ax,%ax
L11:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L11
L25:
  mov    0xc(%rsp),%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string

tool: D29: %d

tool: D38: 
%d

tool: D3:  %d

tool: D37:  %d


assistant: ```c
int main() {
  int n, i, a, b, c;
  i = 0;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &n);
  while (i < n) {
    rotr(&a, &b, &c);
    i++;
  }
  printf("\n%d", a);
  printf(" %d", b);
  printf(" %d\n", c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L19
L15:
  mov    -0x14(%rbp),%eax
  lea    -0x20(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xffffff60,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L7:
  movslq %ebp,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  add    $0x64,%ebp
  cmp    $0x140,%ebx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xffffff60,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  movslq %r12d,%rdx
  mov    %r12d,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x1f,%eax
  add    $0x14,%ebx
  add    $0x64,%r12d
  sar    $0x21,%rdx
  sub    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = 5 * (fahr - 32) / 9;
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<srt_is_end_of_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L15:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0xa,%eax
  jg     L12
  cmp    $0x9,%eax
  jge    L69
  jmp    L45
L12:
  cmp    $0x20,%eax
  je     L69
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L62
L69:
  nop
L62:
  addl   $0x1,-0x4(%rbp)
L73:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  cmpl   $0x0,-0x8(%rbp)
  jne    L15
L18:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int srt_is_end_of_block(const char *str) {
  int ret = 1;
  unsigned int i;
  assert(str != NULL);
  for (i = 0; str[i] != '\0' && ret; i++) {
    switch (str[i]) {
    case ' ':
    case '\t':
    case '\n':
      break;
    default:
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<srt_is_end_of_block>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L50
  mov    $0x0,%edx
  jmp    L65
L69:
  cmp    $0x20,%al
  jne    L84
L73:
  add    $0x1,%edx
  mov    %edx,%eax
  movzbl (%rbx,%rax,1),%eax
  test   %al,%al
  je     L43
L65:
  cmp    $0xa,%al
  jg     L69
  cmp    $0x8,%al
  jg     L73
  mov    $0x0,%eax
L18:
  pop    %rbx
  ret
L43:
  mov    $0x1,%eax
  jmp    L18
L50:
  mov    $0x1,%eax
  jmp    L18
L84:
  mov    $0x0,%eax
  jmp    L18
```

assistant: ```c
int srt_is_end_of_block(const char *str) {
  int ret = 1;
  unsigned int i;
  assert(str != NULL);
  for (i = 0; str[i] != '\0' && ret; i++) {
    switch (str[i]) {
    case ' ':
    case '\t':
    case '\n':
      break;
    default:
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<srt_is_end_of_block>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L46
  xor    %edx,%edx
  nopl   0x0(%rax)
L40:
  cmp    $0xa,%al
  jg     L37
  cmp    $0x8,%al
  jg     L15
L31:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L37:
  cmp    $0x20,%al
  jne    L31
L15:
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  movzbl (%rbx,%rax,1),%eax
  test   %al,%al
  jne    L40
L46:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int srt_is_end_of_block(const char *str) {
  int ret = 1;
  unsigned int i;
  assert(str != NULL);
  for (i = 0; str[i] != '\0' && ret; i++) {
    switch (str[i]) {
    case ' ':
    case '\t':
    case '\n':
      break;
    default:
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<srt_is_end_of_block>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L36
  xor    %edx,%edx
  nopl   0x0(%rax)
L43:
  cmp    $0xa,%al
  jg     L11
  cmp    $0x8,%al
  jg     L10
L42:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L11:
  cmp    $0x20,%al
  jne    L42
L10:
  lea    0x1(%rdx),%eax
  mov    %rax,%rdx
  movzbl (%rbx,%rax,1),%eax
  test   %al,%al
  jne    L43
L36:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int srt_is_end_of_block(const char *str) {
  int ret = 1;
  unsigned int i;
  assert(str != NULL);
  for (i = 0; str[i] != '\0' && ret; i++) {
    switch (str[i]) {
    case ' ':
    case '\t':
    case '\n':
      break;
    default:
      ret = 0;
      break;
    }
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  jmp    L16
L1:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gcd>
L16:
  leave
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L0
  ret
L0:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cqto
  idiv   %rsi
  mov    %rdx,%rsi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  test   %rsi,%rsi
  jne    L29
  jmp    L0
  nopl   0x0(%rax)
L10:
  mov    %rdx,%r8
L29:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L10
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L0:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  test   %rsi,%rsi
  jne    L1
  jmp    L11
  nopl   0x0(%rax)
L0:
  mov    %rdx,%r8
L1:
  cqto
  idiv   %r8
  mov    %r8,%rax
  test   %rdx,%rdx
  jne    L0
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L11:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  if (b == 0) {
    return a;
  } else {
    return gcd(b, a % b);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L11
L2:
  mov    $0x0,%eax
  call   <baz@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void bar(void) {
  int j;
  for (; foo(j); ++j)
    baz();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bar>:
  endbr64
  push   %rbx
  jmp    L6
L5:
  mov    $0x0,%eax
  call   <baz@plt>
  add    $0x1,%ebx
L6:
  mov    %ebx,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void bar(void) {
  int j;
  for (; foo(j); ++j)
    baz();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bar>:
  endbr64
  push   %rbx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <baz@plt>
L3:
  mov    %ebx,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void bar(void) {
  int j;
  for (; foo(j); ++j)
    baz();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bar>:
  endbr64
  push   %rbx
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <baz@plt>
L3:
  mov    %ebx,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L13
  pop    %rbx
  ret
```

assistant: ```c
void bar(void) {
  int j;
  for (; foo(j); ++j)
    baz();
}
```
user: Translate the below assembly code into C programming language:

```asm
<willusmath_is_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  setnp  %al
  mov    $0x0,%edx
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  cmovne %edx,%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L64
  cmpl   $0x0,-0x8(%rbp)
  jne    L22
L64:
  cmpl   $0x0,-0xc(%rbp)
  je     L74
  cmpl   $0x0,-0x4(%rbp)
  jne    L22
L74:
  cmpl   $0x0,-0x8(%rbp)
  je     L91
  cmpl   $0x0,-0x4(%rbp)
  jne    L22
L91:
  cmpl   $0x0,-0xc(%rbp)
  jne    L25
  cmpl   $0x0,-0x8(%rbp)
  jne    L25
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
L22:
  mov    $0x1,%eax
  jmp    L85
L25:
  mov    $0x0,%eax
L85:
  pop    %rbp
  ret
```

assistant: ```c
int willusmath_is_nan(double x) {
  int isz, isgt, islt;
  isz = (x == 0.);
  isgt = (x > 0.);
  islt = (x < 0.);
  return ((isz && isgt) || (isz && islt) || (isgt && islt) || (!isz && !isgt && !islt));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<willusmath_is_nan>:
  endbr64
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  comisd %xmm1,%xmm0
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int willusmath_is_nan(double x) {
  int isz, isgt, islt;
  isz = (x == 0.);
  isgt = (x > 0.);
  islt = (x < 0.);
  return ((isz && isgt) || (isz && islt) || (isgt && islt) || (!isz && !isgt && !islt));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<willusmath_is_nan>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  ucomisd %xmm1,%xmm0
  setnp  %al
  cmovne %edx,%eax
  comisd %xmm1,%xmm0
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int willusmath_is_nan(double x) {
  int isz, isgt, islt;
  isz = (x == 0.);
  isgt = (x > 0.);
  islt = (x < 0.);
  return ((isz && isgt) || (isz && islt) || (isgt && islt) || (!isz && !isgt && !islt));
}
```
user: Translate the below assembly code into C programming language:

```asm
<willusmath_is_nan>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0x0,%edx
  ucomisd %xmm1,%xmm0
  setnp  %al
  cmovne %edx,%eax
  comisd %xmm1,%xmm0
  setne  %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int willusmath_is_nan(double x) {
  int isz, isgt, islt;
  isz = (x == 0.);
  isgt = (x > 0.);
  islt = (x < 0.);
  return ((isz && isgt) || (isz && islt) || (isgt && islt) || (!isz && !isgt && !islt));
}
```