ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L64
L32:
  movss  -0x1c(%rbp),%xmm1
  movss  D22(%rip),%xmm0
  comiss %xmm1,%xmm0
  jbe    L15
  addl   $0x1,-0x18(%rbp)
  jmp    L97
L15:
  movss  -0x1c(%rbp),%xmm1
  movss  D52(%rip),%xmm0
  comiss %xmm1,%xmm0
  jbe    L67
  addl   $0x1,-0x14(%rbp)
  jmp    L97
L67:
  movss  -0x1c(%rbp),%xmm1
  movss  D18(%rip),%xmm0
  comiss %xmm1,%xmm0
  jbe    L55
  addl   $0x1,-0x10(%rbp)
  jmp    L97
L55:
  addl   $0x1,-0xc(%rbp)
L97:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L64:
  movss  -0x1c(%rbp),%xmm1
  movss  D43(%rip),%xmm0
  comiss %xmm1,%xmm0
  jb     L53
  movss  -0x1c(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jae    L32
L53:
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D54
type: string
name: read_data
arguments: data_tag: D22
type: byte[4]
name: read_data
arguments: data_tag: D52
type: byte[4]
name: read_data
arguments: data_tag: D18
type: byte[4]
name: read_data
arguments: data_tag: D43
type: byte[4]
name: read_data
arguments: data_tag: D75
type: string

tool: D28: Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.

tool: D54: %f

tool: {"D22": [0x00,0x00,0xa0,0x40]}

tool: {"D52": [0x00,0x00,0xe0,0x40]}

tool: {"D18": [0x00,0x00,0x10,0x41]}

tool: {"D43": [0x00,0x00,0x20,0x41]}

tool: D75: Resultats:

	Suspesos-->%d
	Aprovats-->%d
	Notables-->%d
	Excelents-->%d


assistant: ```c
int main() {
  float nota;
  int suspes = 0;
  int aprovat = 0;
  int notable = 0;
  int excelent = 0;
  printf("Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.\n");
  scanf("%f", &nota);
  while (nota <= 10 && nota >= 0) {
    if (nota < 5) {
      suspes += 1;
    } else if (nota < 7) {
      aprovat += 1;
    } else if (nota < 9) {
      notable += 1;
    } else {
      excelent += 1;
    }
    scanf("%f", &nota);
  }
  printf("Resultats:\n\n\tSuspesos-->%d\n\tAprovats-->%d\n\tNotables-->%d\n\tExcelents-->%d\n", suspes, aprovat, notable, excelent);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D72(%rip),%xmm1
  comiss %xmm0,%xmm1
  jb     L69
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L46
L69:
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L87:
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  movss  D31(%rip),%xmm4
  comiss %xmm0,%xmm4
  jbe    L30
  add    $0x1,%ebp
L34:
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D72(%rip),%xmm1
  comiss %xmm0,%xmm1
  jb     L87
L46:
  pxor   %xmm2,%xmm2
  comiss %xmm2,%xmm0
  jb     L87
  movss  D5(%rip),%xmm3
  comiss %xmm0,%xmm3
  jbe    L54
  add    $0x1,%ebx
  jmp    L34
L30:
  movss  D60(%rip),%xmm5
  comiss %xmm0,%xmm5
  jbe    L18
  add    $0x1,%r12d
  jmp    L34
L18:
  add    $0x1,%r13d
  jmp    L34
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D40
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string
name: disassemble_data
arguments: tag: D72
data_type: byte[4]
name: disassemble_data
arguments: tag: D48
data_type: string
name: disassemble_data
arguments: tag: D31
data_type: byte[4]
name: disassemble_data
arguments: tag: D5
data_type: byte[4]
name: disassemble_data
arguments: tag: D60
data_type: byte[4]

tool: D40: Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.

tool: D36: %f

tool: {"D72": [0x00,0x00,0x20,0x41]}

tool: D48: Resultats:

	Suspesos-->%d
	Aprovats-->%d
	Notables-->%d
	Excelents-->%d


tool: {"D31": [0x00,0x00,0xe0,0x40]}

tool: {"D5": [0x00,0x00,0xa0,0x40]}

tool: {"D60": [0x00,0x00,0x10,0x41]}

assistant: ```c
int main() {
  float nota;
  int suspes = 0;
  int aprovat = 0;
  int notable = 0;
  int excelent = 0;
  printf("Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.\n");
  scanf("%f", &nota);
  while (nota <= 10 && nota >= 0) {
    if (nota < 5) {
      suspes += 1;
    } else if (nota < 7) {
      aprovat += 1;
    } else if (nota < 9) {
      notable += 1;
    } else {
      excelent += 1;
    }
    scanf("%f", &nota);
  }
  printf("Resultats:\n\n\tSuspesos-->%d\n\tAprovats-->%d\n\tNotables-->%d\n\tExcelents-->%d\n", suspes, aprovat, notable, excelent);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D70(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D32(%rip),%xmm6
  comiss %xmm0,%xmm6
  jae    L50
  jmp    L61
  cs nopw 0x0(%rax,%rax,1)
L101:
  add    $0x1,%r12d
L68:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D32(%rip),%xmm3
  comiss %xmm0,%xmm3
  jb     L61
L50:
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L61
  movss  D13(%rip),%xmm2
  comiss %xmm0,%xmm2
  ja     L101
  movss  D10(%rip),%xmm4
  comiss %xmm0,%xmm4
  jbe    L6
  add    $0x1,%r13d
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L6:
  movss  D26(%rip),%xmm5
  comiss %xmm0,%xmm5
  jbe    L81
  add    $0x1,%r14d
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L81:
  add    $0x1,%r15d
  jmp    L68
  xchg   %ax,%ax
L61:
  xor    %eax,%eax
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D71(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D70
type_infered: string
name: read_data
arguments: label: D32
type_infered: byte[4]
name: read_data
arguments: label: D13
type_infered: byte[4]
name: read_data
arguments: label: D10
type_infered: byte[4]
name: read_data
arguments: label: D26
type_infered: byte[4]
name: read_data
arguments: label: D71
type_infered: string

tool: D0: Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.

tool: D70: %f

tool: {"D32": [0x00,0x00,0x20,0x41]}

tool: {"D13": [0x00,0x00,0xa0,0x40]}

tool: {"D10": [0x00,0x00,0xe0,0x40]}

tool: {"D26": [0x00,0x00,0x10,0x41]}

tool: D71: Resultats:

	Suspesos-->%d
	Aprovats-->%d
	Notables-->%d
	Excelents-->%d


assistant: ```c
int main() {
  float nota;
  int suspes = 0;
  int aprovat = 0;
  int notable = 0;
  int excelent = 0;
  printf("Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.\n");
  scanf("%f", &nota);
  while (nota <= 10 && nota >= 0) {
    if (nota < 5) {
      suspes += 1;
    } else if (nota < 7) {
      aprovat += 1;
    } else if (nota < 9) {
      notable += 1;
    } else {
      excelent += 1;
    }
    scanf("%f", &nota);
  }
  printf("Resultats:\n\n\tSuspesos-->%d\n\tAprovats-->%d\n\tNotables-->%d\n\tExcelents-->%d\n", suspes, aprovat, notable, excelent);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D77(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  lea    D52(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D69(%rip),%xmm6
  comiss %xmm0,%xmm6
  jae    L10
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L99:
  add    $0x1,%r12d
L95:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  movss  D69(%rip),%xmm3
  comiss %xmm0,%xmm3
  jb     L31
L10:
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jb     L31
  movss  D36(%rip),%xmm2
  comiss %xmm0,%xmm2
  ja     L99
  movss  D25(%rip),%xmm4
  comiss %xmm0,%xmm4
  jbe    L21
  add    $0x1,%r13d
  jmp    L95
  nopl   0x0(%rax,%rax,1)
L21:
  movss  D23(%rip),%xmm5
  comiss %xmm0,%xmm5
  jbe    L78
  add    $0x1,%r14d
  jmp    L95
  nopl   0x0(%rax,%rax,1)
L78:
  add    $0x1,%r15d
  jmp    L95
  xchg   %ax,%ax
L31:
  xor    %eax,%eax
  mov    %r15d,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D77
datatype: string
name: retrieve_data
arguments: label: D52
datatype: string
name: retrieve_data
arguments: label: D69
datatype: byte[4]
name: retrieve_data
arguments: label: D36
datatype: byte[4]
name: retrieve_data
arguments: label: D25
datatype: byte[4]
name: retrieve_data
arguments: label: D23
datatype: byte[4]
name: retrieve_data
arguments: label: D46
datatype: string

tool: D77: Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.

tool: D52: %f

tool: {"D69": [0x00,0x00,0x20,0x41]}

tool: {"D36": [0x00,0x00,0xa0,0x40]}

tool: {"D25": [0x00,0x00,0xe0,0x40]}

tool: {"D23": [0x00,0x00,0x10,0x41]}

tool: D46: Resultats:

	Suspesos-->%d
	Aprovats-->%d
	Notables-->%d
	Excelents-->%d


assistant: ```c
int main() {
  float nota;
  int suspes = 0;
  int aprovat = 0;
  int notable = 0;
  int excelent = 0;
  printf("Entra les notes dels alumnes(nota+<enter>), per acabar entra una nota no valida.\n");
  scanf("%f", &nota);
  while (nota <= 10 && nota >= 0) {
    if (nota < 5) {
      suspes += 1;
    } else if (nota < 7) {
      aprovat += 1;
    } else if (nota < 9) {
      notable += 1;
    } else {
      excelent += 1;
    }
    scanf("%f", &nota);
  }
  printf("Resultats:\n\n\tSuspesos-->%d\n\tAprovats-->%d\n\tNotables-->%d\n\tExcelents-->%d\n", suspes, aprovat, notable, excelent);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L46
L43:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  jmp    L36
L49:
  mov    $0x1,%eax
  jmp    L19
L36:
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L43
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char strtolower(char *text, int size) {
  int n;
  for (n = 0; n < size; n++) {
    if (text[n] != '\0') {
      text[n] = tolower(text[n]);
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtolower>:
  endbr64
  test   %esi,%esi
  jle    L23
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L3:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L11
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
  mov    $0x0,%eax
  jmp    L4
L23:
  mov    $0x0,%eax
  ret
L11:
  mov    $0x1,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char strtolower(char *text, int size) {
  int n;
  for (n = 0; n < size; n++) {
    if (text[n] != '\0') {
      text[n] = tolower(text[n]);
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strtolower>:
  endbr64
  test   %esi,%esi
  jle    L30
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L27:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  je     L20
L11:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L27
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
char strtolower(char *text, int size) {
  int n;
  for (n = 0; n < size; n++) {
    if (text[n] != '\0') {
      text[n] = tolower(text[n]);
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtolower>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L17:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  je     L6
L10:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
char strtolower(char *text, int size) {
  int n;
  for (n = 0; n < size; n++) {
    if (text[n] != '\0') {
      text[n] = tolower(text[n]);
    } else {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_north_east>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_north_penetration@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <get_east_penetration@plt>
  cmp    %rax,%rbx
  jge    L3
  mov    $0x0,%eax
  call   <bounce_south@plt>
  jmp    L7
L3:
  mov    $0x0,%eax
  call   <bounce_west@plt>
L7:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void do_north_east(void) {
  if (get_north_penetration() < get_east_penetration())
    bounce_south();
  else
    bounce_west();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_north_east>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <get_north_penetration@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <get_east_penetration@plt>
  cmp    %rax,%rbx
  jge    L14
  mov    $0x0,%eax
  call   <bounce_south@plt>
L8:
  pop    %rbx
  ret
L14:
  mov    $0x0,%eax
  call   <bounce_west@plt>
  jmp    L8
```

assistant: ```c
void do_north_east(void) {
  if (get_north_penetration() < get_east_penetration())
    bounce_south();
  else
    bounce_west();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_north_east>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <get_north_penetration@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <get_east_penetration@plt>
  cmp    %rax,%rbx
  mov    $0x0,%eax
  jge    L6
  pop    %rbx
  jmp    10b0 <bounce_south@plt>
  cs nopw 0x0(%rax,%rax,1)
L6:
  pop    %rbx
  jmp    10a0 <bounce_west@plt>
```

assistant: ```c
void do_north_east(void) {
  if (get_north_penetration() < get_east_penetration())
    bounce_south();
  else
    bounce_west();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_north_east>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <get_north_penetration@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <get_east_penetration@plt>
  cmp    %rax,%rbx
  mov    $0x0,%eax
  jge    L5
  pop    %rbx
  jmp    10b0 <bounce_south@plt>
  cs nopw 0x0(%rax,%rax,1)
L5:
  pop    %rbx
  jmp    10a0 <bounce_west@plt>
```

assistant: ```c
void do_north_east(void) {
  if (get_north_penetration() < get_east_penetration())
    bounce_south();
  else
    bounce_west();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_sendto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
L26:
  mov    -0x34(%rbp),%r8d
  mov    -0x30(%rbp),%rdi
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L4
  mov    D15(%rip),%rax
  mov    (%rax),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L4
  mov    $0x0,%eax
  call   <task_yield@plt>
  jmp    L26
L4:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
ssize_t sys_sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  ssize_t ret;
RETRY:
  ret = sendto(sockfd, buf, len, flags, dest_addr, addrlen);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys_sendto>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %r8,%rbp
  mov    %r9d,%ebx
  jmp    L19
L5:
  mov    $0x0,%eax
  call   <task_yield@plt>
L19:
  mov    %ebx,%r9d
  mov    %rbp,%r8
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  mov    D7(%rip),%rcx
  mov    D15(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L5
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t sys_sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  ssize_t ret;
RETRY:
  ret = sendto(sockfd, buf, len, flags, dest_addr, addrlen);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<sys_sendto>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    D4(%rip),%rdx
  mov    D16(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L19
  xor    %eax,%eax
  call   <task_yield@plt>
L14:
  mov    %ebx,%r9d
  mov    %rbp,%r8
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L0
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t sys_sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  ssize_t ret;
RETRY:
  ret = sendto(sockfd, buf, len, flags, dest_addr, addrlen);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sys_sendto>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    D7(%rip),%rdx
  mov    D15(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L15
  xor    %eax,%eax
  call   <task_yield@plt>
L14:
  mov    %ebx,%r9d
  mov    %rbp,%r8
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L11
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t sys_sendto(int sockfd, const void *buf, size_t len, int flags, const struct sockaddr *dest_addr, socklen_t addrlen) {
  ssize_t ret;
RETRY:
  ret = sendto(sockfd, buf, len, flags, dest_addr, addrlen);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Tui_Getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%edx
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    D52(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x34(%rbp)
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int Tui_Getch(void) {
  struct termios old;
  struct termios new;
  int ch;
  tcgetattr(0, &old);
  new = old;
  new.c_lflag &= ~(ICANON | ECHO);
  new.c_cc[VTIME] = 0;
  new.c_cc[VMIN] = 1;
  tcsetattr(0, TCSANOW, &new);
  ch = getchar();
  tcsetattr(0, TCSANOW, &old);
  return (ch);
}
```