ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L5
  lea    0x8(%rsp),%rax
  mov    %rax,0x10(%rsp)
L5:
  mov    0x10(%rsp),%rax
  lea    D19(%rip),%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rax
  mov    0xc(%rsp),%esi
  lea    0x10(%rsp),%rdx
  mov    %rax,0x10(%rsp)
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D19: %d

tool: D8: %d %u

assistant: ```c
int main() {
  int *p, a, b;
  if (b)
    p = &a;
  printf("%d", *p);
  p = &b;
  printf("%d %u", *p, &p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x44434241,-0xc(%rbp)
  movl   $0x80000002,-0x24(%rbp)
  mov    -0x14(%rbp),%edi
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <__cpuid@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x2c(%rbp)
  jmp    L22
L56:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0xc(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1f,-0x28(%rbp)
  jmp    L2
L41:
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L15
  mov    $0x7c,%edi
  call   <putchar@plt>
L15:
  subl   $0x1,-0x28(%rbp)
L2:
  cmpl   $0x0,-0x28(%rbp)
  jns    L41
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x2c(%rbp)
L22:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L56
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D35
type: string
name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D12
type: string

tool: D35: ------------------------------------------------------

tool: D1: (hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|

tool: D15: E%cX=%8x=|

tool: D12: %d

assistant: ```c
int main(void) {
  char n[4] = {'A', 'B', 'C', 'D'};
  uint32_t e[4];
  uint32_t leaf = 0x80000002u;
  __cpuid(leaf, e[0], e[1], e[2], e[3]);
  printf("------------------------------------------------------\n");
  printf("(hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|\n");
  printf("------------------------------------------------------\n");
  for (int j = 0; j < 4; j++) {
    printf("E%cX=%8x=|", n[j], e[j]);
    for (int32_t i = 31; i >= 0; i--) {
      printf("%d", e[j] & (1 << i) ? 1 : 0);
      if ((i % 4) == 0)
        printf("|");
    }
    printf("\n");
  }
  printf("------------------------------------------------------\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x44434241,0x14(%rsp)
  mov    0xc(%rsp),%r8d
  mov    0x8(%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    $0x80000002,%edi
  call   <__cpuid@plt>
  lea    D36(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x0,%r13d
  lea    0x14(%rsp),%r15
  lea    D5(%rip),%r14
  lea    D25(%rip),%r12
  jmp    L17
L38:
  mov    $0x7c,%edi
  call   <putchar@plt>
L61:
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L6
  mov    %ebp,%esi
  mov    %ebx,%ecx
  sar    %cl,%esi
  and    $0x1,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   $0x3,%bl
  jne    L61
  jmp    L38
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13
  cmp    $0x4,%r13
  je     L10
L17:
  mov    (%rsp,%r13,4),%ebp
  movsbl 0x0(%r13,%r15,1),%esi
  mov    %ebp,%edx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  shr    $0x1f,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1f,%ebx
  jmp    L61
L10:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D25
type: string

tool: D36: ------------------------------------------------------

tool: D10: (hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|

tool: D5: E%cX=%8x=|

tool: D25: %d

assistant: ```c
int main(void) {
  char n[4] = {'A', 'B', 'C', 'D'};
  uint32_t e[4];
  uint32_t leaf = 0x80000002u;
  __cpuid(leaf, e[0], e[1], e[2], e[3]);
  printf("------------------------------------------------------\n");
  printf("(hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|\n");
  printf("------------------------------------------------------\n");
  for (int j = 0; j < 4; j++) {
    printf("E%cX=%8x=|", n[j], e[j]);
    for (int32_t i = 31; i >= 0; i--) {
      printf("%d", e[j] & (1 << i) ? 1 : 0);
      if ((i % 4) == 0)
        printf("|");
    }
    printf("\n");
  }
  printf("------------------------------------------------------\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x80000002,%edi
  lea    D8(%rip),%r15
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rsp),%ebp
  mov    0xc(%rsp),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsp),%ecx
  mov    0x4(%rsp),%edx
  movl   $0x44434241,0x14(%rsp)
  mov    %ebp,%esi
  call   <__cpuid@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  mov    $0x41,%esi
L17:
  mov    %ebp,%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    $0x1f,%ebx
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  shr    $0x1f,%esi
  call   <printf@plt>
  nop
L57:
  sub    $0x1,%ebx
  jb     L58
L52:
  mov    %ebp,%esi
  mov    %ebx,%ecx
  xor    %eax,%eax
  mov    %r12,%rdi
  sar    %cl,%esi
  and    $0x1,%esi
  call   <printf@plt>
  test   $0x3,%bl
  jne    L57
  mov    $0x7c,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L52
L58:
  mov    $0xa,%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    $0x4,%r13
  je     L53
  mov    (%rsp,%r13,4),%ebp
  movsbl 0x14(%rsp,%r13,1),%esi
  jmp    L17
L53:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D36
type_guessed: string
name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D8: ------------------------------------------------------

tool: D36: E%cX=%8x=|

tool: D23: %d

tool: D3: (hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|

assistant: ```c
int main(void) {
  char n[4] = {'A', 'B', 'C', 'D'};
  uint32_t e[4];
  uint32_t leaf = 0x80000002u;
  __cpuid(leaf, e[0], e[1], e[2], e[3]);
  printf("------------------------------------------------------\n");
  printf("(hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|\n");
  printf("------------------------------------------------------\n");
  for (int j = 0; j < 4; j++) {
    printf("E%cX=%8x=|", n[j], e[j]);
    for (int32_t i = 31; i >= 0; i--) {
      printf("%d", e[j] & (1 << i) ? 1 : 0);
      if ((i % 4) == 0)
        printf("|");
    }
    printf("\n");
  }
  printf("------------------------------------------------------\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x80000002,%edi
  lea    D17(%rip),%r15
  push   %r14
  push   %r13
  lea    D28(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    0x1c(%rsp),%r8d
  mov    0x18(%rsp),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  movl   $0x44434241,0x24(%rsp)
  call   <__cpuid@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%rax
  mov    %rax,(%rsp)
L10:
  mov    0x8(%rsp),%rax
  mov    %r13,%rdi
  mov    $0x1e,%r14d
  mov    (%rax,%r12,4),%ebx
  mov    (%rsp),%rax
  movsbl (%rax,%r12,1),%esi
  mov    %ebx,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  shr    $0x1f,%esi
  call   <printf@plt>
  nop
L32:
  mov    %ebx,%esi
  mov    %r14d,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdi
  sar    %cl,%esi
  and    $0x1,%esi
  call   <printf@plt>
  test   $0x3,%r14b
  jne    L12
  mov    $0x7c,%edi
  call   <putchar@plt>
L12:
  sub    $0x1,%r14d
  jae    L32
  mov    $0xa,%edi
  add    $0x1,%r12
  call   <putchar@plt>
  cmp    $0x4,%r12
  jne    L10
  mov    %r15,%rdi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D17: ------------------------------------------------------

tool: D28: E%cX=%8x=|

tool: D22: %d

tool: D3: (hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|

assistant: ```c
int main(void) {
  char n[4] = {'A', 'B', 'C', 'D'};
  uint32_t e[4];
  uint32_t leaf = 0x80000002u;
  __cpuid(leaf, e[0], e[1], e[2], e[3]);
  printf("------------------------------------------------------\n");
  printf("(hi-to-lo)   |1098|7654|3210|9876|5432|1098|7654|3210|\n");
  printf("------------------------------------------------------\n");
  for (int j = 0; j < 4; j++) {
    printf("E%cX=%8x=|", n[j], e[j]);
    for (int32_t i = 31; i >= 0; i--) {
      printf("%d", e[j] & (1 << i) ? 1 : 0);
      if ((i % 4) == 0)
        printf("|");
    }
    printf("\n");
  }
  printf("------------------------------------------------------\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<valid_domainname>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %rdi,%rdi
  je     L48
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L48
  mov    %rbx,%rbp
  mov    $0x0,%r13d
  mov    $0x1,%eax
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  jmp    L170
L48:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L110:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L174:
  cmp    %rbp,%rbx
  je     L165
  testl  $0x100,0xc(%rsp)
  jne    L38
L165:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
L54:
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  test   %r14,%r14
  je     L110
  movb   $0x0,(%r14)
  mov    $0x1,%eax
  jmp    L110
L38:
  test   %eax,%eax
  cmove  %rbp,%r14
  mov    $0x0,%r13d
  mov    $0x1,%eax
  jmp    L163
L50:
  cmpb   $0x2e,0x1(%rbp)
  je     L165
  mov    $0x0,%r13d
  jmp    L163
L29:
  movzbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L165
L36:
  add    $0x1,%r13d
  cmp    $0x3f,%r13d
  jg     L28
  mov    %r15d,%eax
L163:
  movzbl 0x1(%r12),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L23
L170:
  mov    %rbp,%r12
  cmp    $0x20,%dil
  je     L174
  cmp    $0x2e,%dil
  je     L50
  cmp    $0x2d,%dil
  sete   %dl
  cmp    $0x5f,%dil
  sete   %cl
  or     %cl,%dl
  je     L29
  test   %eax,%eax
  jne    L29
  testb  $0xdf,0x1(%rbp)
  je     L29
  jmp    L36
L28:
  mov    D42(%rip),%rax
  mov    (%rax),%edx
  jmp    L54
L23:
  mov    $0x1,%eax
  jmp    L110
```

assistant: ```c
int valid_domainname(char *lbl, int type) {
  char *slbl, *lst;
  unsigned char c;
  int start, len, errset;
  if (lbl == NULL || *lbl == '\0') {
    errno = EINVAL;
    return 0;
  }
  slbl = lbl;
  lst = NULL;
  start = 1;
  len = errset = 0;
  for (;;) {
    c = (unsigned char)*lbl++;
    if (c == '\0')
      return 1;
    if (c == ' ') {
      if (lbl - 1 == slbl)
        break;
      if (!(type & (1 << 8)))
        break;
      if (!start) {
        start = 1;
        lst = lbl - 1;
      }
      if (len)
        len = 0;
      continue;
    }
    if (c == '.') {
      if (*lbl == '.')
        break;
      len = 0;
      continue;
    }
    if (((c == '-' || c == '_') && !start && *lbl != ' ' && *lbl != '\0') || isalnum(c)) {
      if (++len > 63) {
        errno = ERANGE;
        errset = 1;
        break;
      }
    } else
      break;
    if (start)
      start = 0;
  }
  if (!errset)
    errno = EINVAL;
  if (lst) {
    *lst = '\0';
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<valid_domainname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L115
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L115
  mov    %esi,%r12d
  mov    %rbx,%rbp
  xor    %r13d,%r13d
  mov    $0x1,%edx
  xor    %r14d,%r14d
L169:
  cmp    $0x20,%dil
  je     L79
  cmp    $0x2e,%dil
  je     L145
  cmp    $0x2d,%dil
  sete   %al
  cmp    $0x5f,%dil
  sete   %cl
  or     %cl,%al
  je     L114
  test   %edx,%edx
  jne    L114
  testb  $0xdf,0x1(%rbp)
  jne    L174
L114:
  call   <isalnum@plt>
  test   %rax,%rax
  je     L181
L174:
  add    $0x1,%r13d
  cmp    $0x40,%r13d
  je     L88
  xor    %edx,%edx
L126:
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  jne    L169
  mov    $0x1,%eax
  jmp    L134
  nop
L79:
  cmp    %rbp,%rbx
  je     L181
  test   $0x100,%r12d
  jne    L58
L181:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
L33:
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  test   %r14,%r14
  je     L134
  movb   $0x0,(%r14)
  mov    $0x1,%eax
L134:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L115:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L145:
  cmpb   $0x2e,0x1(%rbp)
  je     L181
  xor    %r13d,%r13d
  jmp    L126
  nopl   0x0(%rax,%rax,1)
L58:
  xor    %r13d,%r13d
  test   %edx,%edx
  jne    L126
  mov    %rbp,%r14
  mov    $0x1,%edx
  jmp    L126
L88:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  jmp    L33
```

assistant: ```c
int valid_domainname(char *lbl, int type) {
  char *slbl, *lst;
  unsigned char c;
  int start, len, errset;
  if (lbl == NULL || *lbl == '\0') {
    errno = EINVAL;
    return 0;
  }
  slbl = lbl;
  lst = NULL;
  start = 1;
  len = errset = 0;
  for (;;) {
    c = (unsigned char)*lbl++;
    if (c == '\0')
      return 1;
    if (c == ' ') {
      if (lbl - 1 == slbl)
        break;
      if (!(type & (1 << 8)))
        break;
      if (!start) {
        start = 1;
        lst = lbl - 1;
      }
      if (len)
        len = 0;
      continue;
    }
    if (c == '.') {
      if (*lbl == '.')
        break;
      len = 0;
      continue;
    }
    if (((c == '-' || c == '_') && !start && *lbl != ' ' && *lbl != '\0') || isalnum(c)) {
      if (++len > 63) {
        errno = ERANGE;
        errset = 1;
        break;
      }
    } else
      break;
    if (start)
      start = 0;
  }
  if (!errset)
    errno = EINVAL;
  if (lst) {
    *lst = '\0';
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2d392d307a2d612d,%rax
  mov    %rax,-0x3f9(%rbp)
  movb   $0x0,-0x3f1(%rbp)
  movq   $0x0,-0x3f0(%rbp)
  movq   $0x0,-0x3e8(%rbp)
  lea    -0x3e0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7b,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x3f0(%rbp),%rdx
  lea    -0x3f9(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expand@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: %s


assistant: ```c
int main() {
  char shorthand[] = "-a-z0-9-";
  char expanded[1000] = {0};
  expand(shorthand, expanded);
  printf("%s\n", expanded);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  movabs $0x2d392d307a2d612d,%rax
  mov    %rax,0x7(%rsp)
  movb   $0x0,0xf(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x7b,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x10(%rsp),%rbx
  lea    0x7(%rsp),%rdi
  mov    %rbx,%rsi
  call   <expand@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %s


assistant: ```c
int main() {
  char shorthand[] = "-a-z0-9-";
  char expanded[1000] = {0};
  expand(shorthand, expanded);
  printf("%s\n", expanded);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7b,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  movabs $0x2d392d307a2d612d,%rax
  lea    0x10(%rsp),%rbp
  lea    0x20(%rsp),%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x7(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x7(%rsp),%rdi
  call   <expand@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D7: %s


assistant: ```c
int main() {
  char shorthand[] = "-a-z0-9-";
  char expanded[1000] = {0};
  expand(shorthand, expanded);
  printf("%s\n", expanded);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x7b,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  movabs $0x2d392d307a2d612d,%rax
  lea    0x10(%rsp),%rbp
  lea    0x20(%rsp),%rdi
  movb   $0x0,0xf(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x7(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x7(%rsp),%rdi
  call   <expand@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string

tool: D5: %s


assistant: ```c
int main() {
  char shorthand[] = "-a-z0-9-";
  char expanded[1000] = {0};
  expand(shorthand, expanded);
  printf("%s\n", expanded);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Finishing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x1,%edi
  call   <Car_Delete@plt>
L2:
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  jne    L4
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <Axle_Insert@plt>
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Finishing(void) {
  if (0 == Car_GetCarAxlesNum(1)) {
    Car_Delete(1);
  }
  if (1 == Car_GetCarAxlesNum(1)) {
    Axle_Insert(1, 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Finishing>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  test   %eax,%eax
  je     L19
L11:
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  je     L5
L10:
  add    $0x8,%rsp
  ret
L19:
  mov    $0x1,%edi
  call   <Car_Delete@plt>
  jmp    L11
L5:
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <Axle_Insert@plt>
  jmp    L10
```

assistant: ```c
void Finishing(void) {
  if (0 == Car_GetCarAxlesNum(1)) {
    Car_Delete(1);
  }
  if (1 == Car_GetCarAxlesNum(1)) {
    Axle_Insert(1, 1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Finishing>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  test   %eax,%eax
  je     L9
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  je     L29
L22:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%edi
  call   <Car_Delete@plt>
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  jne    L22
L29:
  mov    $0x1,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <Axle_Insert@plt>
```

assistant: ```c
void Finishing(void) {
  if (0 == Car_GetCarAxlesNum(1)) {
    Car_Delete(1);
  }
  if (1 == Car_GetCarAxlesNum(1)) {
    Axle_Insert(1, 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Finishing>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  test   %eax,%eax
  je     L4
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  je     L9
L5:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%edi
  call   <Car_Delete@plt>
  mov    $0x1,%edi
  call   <Car_GetCarAxlesNum@plt>
  cmp    $0x1,%eax
  jne    L5
L9:
  mov    $0x1,%esi
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <Axle_Insert@plt>
```

assistant: ```c
void Finishing(void) {
  if (0 == Car_GetCarAxlesNum(1)) {
    Car_Delete(1);
  }
  if (1 == Car_GetCarAxlesNum(1)) {
    Axle_Insert(1, 1);
  }
}
```