ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<getRows>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L0
  lea    D28(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D27(%rip),%rbx
L14:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L14
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D27
type_infered: string
name: disassemble_data
arguments: tag: D28
type_infered: string

tool: D24: 
Enter number of rows to print (i.e. the height): 

tool: D27: %d

tool: D28: Invalid number. Please enter a positive integer for number of rows: 

assistant: ```c
int getRows() {
  int rows;
  printf("\nEnter number of rows to print (i.e. the height): ");
  scanf("%d", &rows);
  while (rows <= 0) {
    printf("Invalid number. Please enter a positive integer for number of rows: ");
    scanf("%d", &rows);
  }
  return rows;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getRows>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L23
  lea    D6(%rip),%r12
  xchg   %ax,%ax
L26:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L26
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string

tool: D1: 
Enter number of rows to print (i.e. the height): 

tool: D7: %d

tool: D6: Invalid number. Please enter a positive integer for number of rows: 

assistant: ```c
int getRows() {
  int rows;
  printf("\nEnter number of rows to print (i.e. the height): ");
  scanf("%d", &rows);
  while (rows <= 0) {
    printf("Invalid number. Please enter a positive integer for number of rows: ");
    scanf("%d", &rows);
  }
  return rows;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getRows>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L5
  lea    D16(%rip),%r12
  xchg   %ax,%ax
L19:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L19
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D23
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string

tool: D23: 
Enter number of rows to print (i.e. the height): 

tool: D15: %d

tool: D16: Invalid number. Please enter a positive integer for number of rows: 

assistant: ```c
int getRows() {
  int rows;
  printf("\nEnter number of rows to print (i.e. the height): ");
  scanf("%d", &rows);
  while (rows <= 0) {
    printf("Invalid number. Please enter a positive integer for number of rows: ");
    scanf("%d", &rows);
  }
  return rows;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<onMouseClick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L6
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <onMouse@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void onMouseClick(int btn, int state, int x, int y) {
  if (state == GLUT_DOWN)
    onMouse(x, y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<onMouseClick>:
  endbr64
  mov    D1(%rip),%rax
  cmp    %esi,(%rax)
  je     L9
  ret
L9:
  sub    $0x8,%rsp
  mov    %ecx,%esi
  mov    %edx,%edi
  call   <onMouse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void onMouseClick(int btn, int state, int x, int y) {
  if (state == GLUT_DOWN)
    onMouse(x, y);
}
```
user: What is the c source code of the assembly code below?

```asm
<onMouseClick>:
  endbr64
  mov    D2(%rip),%rax
  cmp    %esi,(%rax)
  je     L3
  ret
L3:
  mov    %ecx,%esi
  mov    %edx,%edi
  jmp    1050 <onMouse@plt>
```

assistant: ```c
void onMouseClick(int btn, int state, int x, int y) {
  if (state == GLUT_DOWN)
    onMouse(x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<onMouseClick>:
  endbr64
  mov    D2(%rip),%rax
  cmp    %esi,(%rax)
  je     L1
  ret
L1:
  mov    %ecx,%esi
  mov    %edx,%edi
  jmp    1050 <onMouse@plt>
```

assistant: ```c
void onMouseClick(int btn, int state, int x, int y) {
  if (state == GLUT_DOWN)
    onMouse(x, y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<imprimirCriptografado>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L39:
  cmpb   $0x60,-0x5(%rbp)
  jle    L44
  cmpb   $0x7a,-0x5(%rbp)
  jg     L44
  movzbl -0x5(%rbp),%eax
  sub    $0xd,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x60,-0x5(%rbp)
  jg     L33
  movzbl -0x5(%rbp),%eax
  add    $0x1a,%eax
  mov    %al,-0x5(%rbp)
  jmp    L33
L44:
  cmpb   $0x40,-0x5(%rbp)
  jle    L33
  cmpb   $0x5a,-0x5(%rbp)
  jg     L33
  movzbl -0x5(%rbp),%eax
  sub    $0xd,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x40,-0x5(%rbp)
  jg     L33
  movzbl -0x5(%rbp),%eax
  add    $0x1a,%eax
  mov    %al,-0x5(%rbp)
L33:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  movsbl -0x5(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <putc@plt>
L6:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L39
  nop
  nop
  leave
  ret
```

assistant: ```c
void imprimirCriptografado(const char *linha) {
  char caractere;
  int i = 0;
  while (caractere = linha[i++], caractere != '\0') {
    if (((caractere) >= 'a' && (caractere) <= 'z')) {
      caractere -= 13;
      if (caractere < 'a') {
        caractere = 'z' - ('a' - caractere) + 1;
      }
    } else if (((caractere) >= 'A' && (caractere) <= 'Z')) {
      caractere -= 13;
      if (caractere < 'A') {
        caractere = 'Z' - ('A' - caractere) + 1;
      }
    }
    putc(caractere, stdout);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<imprimirCriptografado>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%rbx
  mov    D8(%rip),%rbp
  jmp    L29
L41:
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L13
  lea    -0xd(%rdx),%eax
  add    $0xd,%edx
  cmp    $0x41,%al
  cmovl  %edx,%eax
L13:
  movsbl %al,%edi
  mov    0x0(%rbp),%esi
  call   <putc@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L21
L29:
  mov    %eax,%edx
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L41
  sub    $0xd,%eax
  add    $0xd,%edx
  cmp    $0x61,%al
  cmovl  %edx,%eax
  jmp    L13
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  ret
```

assistant: ```c
void imprimirCriptografado(const char *linha) {
  char caractere;
  int i = 0;
  while (caractere = linha[i++], caractere != '\0') {
    if (((caractere) >= 'a' && (caractere) <= 'z')) {
      caractere -= 13;
      if (caractere < 'a') {
        caractere = 'z' - ('a' - caractere) + 1;
      }
    } else if (((caractere) >= 'A' && (caractere) <= 'Z')) {
      caractere -= 13;
      if (caractere < 'A') {
        caractere = 'Z' - ('A' - caractere) + 1;
      }
    }
    putc(caractere, stdout);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<imprimirCriptografado>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbp
  jmp    L49
  xchg   %ax,%ax
L28:
  lea    -0xd(%rax),%edx
  add    $0xd,%eax
  cmp    $0x61,%dl
  cmovae %edx,%eax
L56:
  mov    0x0(%rbp),%esi
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L24
L49:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L28
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L56
  lea    -0xd(%rax),%edx
  add    $0xd,%eax
  cmp    $0x41,%dl
  cmovae %edx,%eax
  jmp    L56
  nopl   0x0(%rax)
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L35:
  ret
```

assistant: ```c
void imprimirCriptografado(const char *linha) {
  char caractere;
  int i = 0;
  while (caractere = linha[i++], caractere != '\0') {
    if (((caractere) >= 'a' && (caractere) <= 'z')) {
      caractere -= 13;
      if (caractere < 'a') {
        caractere = 'z' - ('a' - caractere) + 1;
      }
    } else if (((caractere) >= 'A' && (caractere) <= 'Z')) {
      caractere -= 13;
      if (caractere < 'A') {
        caractere = 'Z' - ('A' - caractere) + 1;
      }
    }
    putc(caractere, stdout);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<imprimirCriptografado>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbp
  jmp    L0
  xchg   %ax,%ax
L59:
  lea    -0xd(%rax),%edx
  add    $0xd,%eax
  cmp    $0x61,%dl
  cmovae %edx,%eax
L12:
  mov    0x0(%rbp),%esi
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L18
L0:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L59
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L12
  lea    -0xd(%rax),%edx
  add    $0xd,%eax
  cmp    $0x41,%dl
  cmovae %edx,%eax
  jmp    L12
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L21:
  ret
```

assistant: ```c
void imprimirCriptografado(const char *linha) {
  char caractere;
  int i = 0;
  while (caractere = linha[i++], caractere != '\0') {
    if (((caractere) >= 'a' && (caractere) <= 'z')) {
      caractere -= 13;
      if (caractere < 'a') {
        caractere = 'z' - ('a' - caractere) + 1;
      }
    } else if (((caractere) >= 'A' && (caractere) <= 'Z')) {
      caractere -= 13;
      if (caractere < 'A') {
        caractere = 'Z' - ('A' - caractere) + 1;
      }
    }
    putc(caractere, stdout);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pt3mallopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mspace_mallopt@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pt3mallopt(int p, int v) {
  int result;
  result = mspace_mallopt(p, v);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pt3mallopt>:
  endbr64
  sub    $0x8,%rsp
  call   <mspace_mallopt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int pt3mallopt(int p, int v) {
  int result;
  result = mspace_mallopt(p, v);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pt3mallopt>:
  endbr64
  jmp    1050 <mspace_mallopt@plt>
```

assistant: ```c
int pt3mallopt(int p, int v) {
  int result;
  result = mspace_mallopt(p, v);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pt3mallopt>:
  endbr64
  jmp    1050 <mspace_mallopt@plt>
```

assistant: ```c
int pt3mallopt(int p, int v) {
  int result;
  result = mspace_mallopt(p, v);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readFD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x1000,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    $0x1,%esi
  mov    $0x1000,%edi
  call   <calloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L77
  mov    $0x0,%eax
  call   <abort@plt>
L77:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L1
  mov    -0x14(%rbp),%eax
  add    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L56
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L77
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L77
L1:
  nop
  jmp    L75
L56:
  nop
L75:
  cmpl   $0x0,-0x18(%rbp)
  jne    L74
  cmpl   $0x0,-0x14(%rbp)
  jns    L74
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0xffffffff,%eax
  jmp    L87
L74:
  mov    -0x18(%rbp),%eax
L87:
  leave
  ret
```

assistant: ```c
int readFD(int fd, char **buf) {
  char *p;
  size_t size = 4096;
  int s, filesize = 0;
  *buf = calloc(4096, sizeof(char));
  if (*buf == NULL)
    abort();
  do {
    p = &(*buf)[filesize];
    s = read(fd, p, 4096);
    if (s < 0)
      break;
    filesize += s;
    if (s == 0)
      break;
    size += s;
    *buf = realloc(*buf, size);
    if (*buf == NULL)
      abort();
  } while (1);
  if (filesize == 0 && s < 0) {
    free(*buf);
    *buf = NULL;
    return -1;
  }
  return filesize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readFD>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    $0x1,%esi
  mov    $0x1000,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L64
L26:
  mov    $0x0,%ebp
  mov    $0x1000,%r12d
L78:
  movslq %ebp,%rsi
  add    (%rbx),%rsi
  mov    $0x1000,%edx
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L76
  add    %eax,%ebp
  test   %eax,%eax
  je     L13
  cltq
  add    %rax,%r12
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L78
  call   <abort@plt>
  jmp    L78
L64:
  call   <abort@plt>
  jmp    L26
L76:
  test   %ebp,%ebp
  je     L33
L13:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  mov    $0xffffffff,%ebp
  jmp    L13
```

assistant: ```c
int readFD(int fd, char **buf) {
  char *p;
  size_t size = 4096;
  int s, filesize = 0;
  *buf = calloc(4096, sizeof(char));
  if (*buf == NULL)
    abort();
  do {
    p = &(*buf)[filesize];
    s = read(fd, p, 4096);
    if (s < 0)
      break;
    filesize += s;
    if (s == 0)
      break;
    size += s;
    *buf = realloc(*buf, size);
    if (*buf == NULL)
      abort();
  } while (1);
  if (filesize == 0 && s < 0) {
    free(*buf);
    *buf = NULL;
    return -1;
  }
  return filesize;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readFD>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x1000,%edi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L43
L66:
  xor    %r12d,%r12d
  mov    $0x1000,%ebx
  nopl   0x0(%rax)
L25:
  movslq %r12d,%rdx
  mov    %r13d,%edi
  lea    (%rax,%rdx,1),%rsi
  mov    $0x1000,%edx
  call   <read@plt>
  test   %eax,%eax
  js     L20
  add    %eax,%r12d
  test   %eax,%eax
  je     L35
  cltq
  mov    0x0(%rbp),%rdi
  add    %rax,%rbx
  mov    %rbx,%rsi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  jne    L25
  call   <abort@plt>
  mov    0x0(%rbp),%rax
  jmp    L25
  nopl   0x0(%rax)
L20:
  test   %r12d,%r12d
  je     L74
L35:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  call   <abort@plt>
  mov    0x0(%rbp),%rax
  jmp    L66
L74:
  mov    0x0(%rbp),%rdi
  mov    $0xffffffff,%r12d
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  jmp    L35
```

assistant: ```c
int readFD(int fd, char **buf) {
  char *p;
  size_t size = 4096;
  int s, filesize = 0;
  *buf = calloc(4096, sizeof(char));
  if (*buf == NULL)
    abort();
  do {
    p = &(*buf)[filesize];
    s = read(fd, p, 4096);
    if (s < 0)
      break;
    filesize += s;
    if (s == 0)
      break;
    size += s;
    *buf = realloc(*buf, size);
    if (*buf == NULL)
      abort();
  } while (1);
  if (filesize == 0 && s < 0) {
    free(*buf);
    *buf = NULL;
    return -1;
  }
  return filesize;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readFD>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x1000,%edi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L21
L50:
  xor    %r12d,%r12d
  mov    $0x1000,%ebx
  nopl   0x0(%rax)
L33:
  movslq %r12d,%rdx
  mov    %r13d,%edi
  lea    (%rax,%rdx,1),%rsi
  mov    $0x1000,%edx
  call   <read@plt>
  test   %eax,%eax
  js     L60
  add    %eax,%r12d
  test   %eax,%eax
  je     L2
  cltq
  mov    0x0(%rbp),%rdi
  add    %rax,%rbx
  mov    %rbx,%rsi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  jne    L33
  call   <abort@plt>
  mov    0x0(%rbp),%rax
  jmp    L33
  nopl   0x0(%rax)
L60:
  test   %r12d,%r12d
  je     L30
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  call   <abort@plt>
  mov    0x0(%rbp),%rax
  jmp    L50
L30:
  mov    0x0(%rbp),%rdi
  mov    $0xffffffff,%r12d
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  jmp    L2
```

assistant: ```c
int readFD(int fd, char **buf) {
  char *p;
  size_t size = 4096;
  int s, filesize = 0;
  *buf = calloc(4096, sizeof(char));
  if (*buf == NULL)
    abort();
  do {
    p = &(*buf)[filesize];
    s = read(fd, p, 4096);
    if (s < 0)
      break;
    filesize += s;
    if (s == 0)
      break;
    size += s;
    *buf = realloc(*buf, size);
    if (*buf == NULL)
      abort();
  } while (1);
  if (filesize == 0 && s < 0) {
    free(*buf);
    *buf = NULL;
    return -1;
  }
  return filesize;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0xfffffffe,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0xf,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0xb,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L3
L25:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L3:
  cmpl   $0x8,-0x34(%rbp)
  jle    L25
  lea    -0x30(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L46
L36:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L46:
  cmpl   $0x8,-0x34(%rbp)
  jle    L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type: string
name: extract_symbolic_data
arguments: tag: D34
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D27: 

Unsorted array is:  

tool: D34:  %d 

tool: D16: 

Sorted array is:  

assistant: ```c
int main() {
  int a[] = {7, 12, 1, -2, 0, 15, 4, 11, 9};
  int i;
  printf("\n\nUnsorted array is:  ");
  for (i = 0; i < 9; ++i)
    printf(" %d ", a[i]);
  quickSort(a, 0, 8);
  printf("\n\nSorted array is:  ");
  for (i = 0; i < 9; ++i)
    printf(" %d ", a[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x7,(%rsp)
  movl   $0xc,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0xfffffffe,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0xf,0x14(%rsp)
  movl   $0x4,0x18(%rsp)
  movl   $0xb,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  mov    %rbx,%rbp
  lea    D24(%rip),%r13
L6:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L6
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <quickSort@plt>
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D24(%rip),%rbp
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D34
data_type: string

tool: D18: 

Unsorted array is:  

tool: D24:  %d 

tool: D34: 

Sorted array is:  

assistant: ```c
int main() {
  int a[] = {7, 12, 1, -2, 0, 15, 4, 11, 9};
  int i;
  printf("\n\nUnsorted array is:  ");
  for (i = 0; i < 9; ++i)
    printf(" %d ", a[i]);
  quickSort(a, 0, 8);
  printf("\n\nSorted array is:  ");
  for (i = 0; i < 9; ++i)
    printf(" %d ", a[i]);
}
```