ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x24(%rsp),%r12
  mov    %rbx,%rbp
L4:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L4
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  xor    %edx,%edx
L11:
  xor    %eax,%eax
  cmp    %esi,(%rbx)
  sete   %al
  add    $0x4,%rbx
  add    %eax,%edx
  cmp    %r12,%rbx
  jne    L11
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D22
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D26: %d

tool: D22: 
Entre com uma chave: 

tool: D11: 
O numero %d apareceu %d vezes!

assistant: ```c
int main() {
  int vetor[5], i, chave, cont = 0;
  for (i = 0; i < 5; i++) {
    scanf("%d", &vetor[i]);
  }
  printf("\nEntre com uma chave: ");
  scanf("%d", &chave);
  for (i = 0; i < 5; i++) {
    if (vetor[i] == chave) {
      cont++;
    }
  }
  printf("\nO numero %d apareceu %d vezes!", chave, cont);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x24(%rsp),%r12
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L16
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  cmp    0x20(%rsp),%esi
  sete   %al
  lea    D22(%rip),%rdi
  movd   %esi,%xmm2
  pshufd $0x0,%xmm2,%xmm0
  pcmpeqd 0x10(%rsp),%xmm0
  pand   D36(%rip),%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  add    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D36
type: byte[16]

tool: D9: %d

tool: D24: 
Entre com uma chave: 

tool: D22: 
O numero %d apareceu %d vezes!

tool: {"D36": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int vetor[5], i, chave, cont = 0;
  for (i = 0; i < 5; i++) {
    scanf("%d", &vetor[i]);
  }
  printf("\nEntre com uma chave: ");
  scanf("%d", &chave);
  for (i = 0; i < 5; i++) {
    if (vetor[i] == chave) {
      cont++;
    }
  }
  printf("\nO numero %d apareceu %d vezes!", chave, cont);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xabcdef00,-0x8(%rbp)
  movl   $0xffff1122,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    $0xfffffff0,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xfffffffe,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x2c,%esi
  mov    %eax,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
datatype: string

tool: D23: %x


assistant: ```c
int main(void) {
  unsigned int w1 = 0xabcdef00u, w2 = 0xffff1122u;
  unsigned int rotate(unsigned int value, int n);
  printf("%x\n", rotate(w1, 8));
  printf("%x\n", rotate(w1, -16));
  printf("%x\n", rotate(w2, 4));
  printf("%x\n", rotate(w2, -2));
  printf("%x\n", rotate(w1, 0));
  printf("%x\n", rotate(w1, 44));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x8,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xfffffff0,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2c,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: %x


assistant: ```c
int main(void) {
  unsigned int w1 = 0xabcdef00u, w2 = 0xffff1122u;
  unsigned int rotate(unsigned int value, int n);
  printf("%x\n", rotate(w1, 8));
  printf("%x\n", rotate(w1, -16));
  printf("%x\n", rotate(w2, 4));
  printf("%x\n", rotate(w2, -2));
  printf("%x\n", rotate(w1, 0));
  printf("%x\n", rotate(w1, 44));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    $0xabcdef00,%edi
  lea    D7(%rip),%rbp
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xfffffff0,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xfffffffe,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2c,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: %x


assistant: ```c
int main(void) {
  unsigned int w1 = 0xabcdef00u, w2 = 0xffff1122u;
  unsigned int rotate(unsigned int value, int n);
  printf("%x\n", rotate(w1, 8));
  printf("%x\n", rotate(w1, -16));
  printf("%x\n", rotate(w2, 4));
  printf("%x\n", rotate(w2, -2));
  printf("%x\n", rotate(w1, 0));
  printf("%x\n", rotate(w1, 44));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    $0xabcdef00,%edi
  lea    D1(%rip),%rbp
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xfffffff0,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xfffffffe,%esi
  mov    $0xffff1122,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %esi,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2c,%esi
  mov    $0xabcdef00,%edi
  call   <rotate@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D1: %x


assistant: ```c
int main(void) {
  unsigned int w1 = 0xabcdef00u, w2 = 0xffff1122u;
  unsigned int rotate(unsigned int value, int n);
  printf("%x\n", rotate(w1, 8));
  printf("%x\n", rotate(w1, -16));
  printf("%x\n", rotate(w2, 4));
  printf("%x\n", rotate(w2, -2));
  printf("%x\n", rotate(w1, 0));
  printf("%x\n", rotate(w1, 44));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  printf("%d\n", i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  printf("%d\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  printf("%d\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 1;
  printf("%d\n", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getusec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
L17:
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rax
  imul   $0xf4240,%eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
uint64_t getusec(struct timeval *tv) {
  struct timeval tv_l;
  if (tv == NULL) {
    tv = &tv_l;
    gettimeofday(tv, NULL);
  }
  return (uint64_t)tv->tv_sec * 1000000 + tv->tv_usec;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getusec>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
L23:
  imul   $0xf4240,0x8(%rdi),%eax
  add    (%rdi),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  mov    %rsp,%rbx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  mov    %rbx,%rdi
  jmp    L23
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getusec(struct timeval *tv) {
  struct timeval tv_l;
  if (tv == NULL) {
    tv = &tv_l;
    gettimeofday(tv, NULL);
  }
  return (uint64_t)tv->tv_sec * 1000000 + tv->tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getusec>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
L21:
  imul   $0xf4240,0x8(%rdi),%eax
  add    (%rdi),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L3:
  mov    %rsp,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  mov    %rbx,%rdi
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getusec(struct timeval *tv) {
  struct timeval tv_l;
  if (tv == NULL) {
    tv = &tv_l;
    gettimeofday(tv, NULL);
  }
  return (uint64_t)tv->tv_sec * 1000000 + tv->tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getusec>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
L4:
  imul   $0xf4240,0x8(%rdi),%eax
  add    (%rdi),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  mov    %rsp,%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  mov    %rbx,%rdi
  jmp    L4
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t getusec(struct timeval *tv) {
  struct timeval tv_l;
  if (tv == NULL) {
    tv = &tv_l;
    gettimeofday(tv, NULL);
  }
  return (uint64_t)tv->tv_sec * 1000000 + tv->tv_usec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x60(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L6:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L55:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L25
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L25:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L22
L81:
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x58(%rbp)
L22:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x58(%rbp)
  jl     L81
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x54(%rbp)
  jmp    L29
L69:
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L66
L71:
  mov    -0x54(%rbp),%edx
  mov    -0x50(%rbp),%eax
  add    %eax,%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x4c(%rbp)
  addl   $0x1,-0x50(%rbp)
L66:
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L71
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x54(%rbp)
L29:
  mov    -0x60(%rbp),%eax
  mov    -0x5c(%rbp),%edx
  sub    %edx,%eax
  cmp    %eax,-0x54(%rbp)
  jle    L69
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D22
datatype: string

tool: D23: %d

tool: D22: %d


assistant: ```c
int main() {
  int n, k, i, j, m, x;
  scanf("%d", &n);
  int arr[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (n - k); j++) {
    x = 0;
    for (m = 0; m <= k - 1; m++) {
      x = x + arr[j + m];
    }
    printf("%d\n", x);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L41:
  cmp    %rcx,%rsp
  je     L20
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L20:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L98
  orq    $0x0,-0x8(%rsp,%rax,1)
L98:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L30
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D21(%rip),%r14
L49:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    %ebx,-0x30(%rbp)
  jg     L49
L30:
  lea    -0x2c(%rbp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edx
  mov    $0x0,%ebx
  lea    D30(%rip),%r13
  cmp    %edx,-0x30(%rbp)
  jge    L67
L63:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L80:
  lea    (%r12,%rbx,4),%rax
  lea    -0x1(%rdx),%edx
  add    %rbx,%rdx
  lea    0x4(%r12,%rdx,4),%rdx
  mov    $0x0,%esi
L48:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L48
L94:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  add    $0x1,%rbx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  cmp    %ebx,%eax
  jl     L63
L67:
  mov    $0x0,%esi
  test   %edx,%edx
  jg     L80
  jmp    L94
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string

tool: D21: %d

tool: D30: %d


assistant: ```c
int main() {
  int n, k, i, j, m, x;
  scanf("%d", &n);
  int arr[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (n - k); j++) {
    x = 0;
    for (m = 0; m <= k - 1; m++) {
      x = x + arr[j + m];
    }
    printf("%d\n", x);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L100
L104:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L104
L100:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L31
L69:
  mov    %rsp,%rbx
  test   %ecx,%ecx
  jle    L26
  mov    %rbx,%r13
  xor    %r12d,%r12d
L81:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %r12d,-0x30(%rbp)
  jg     L81
L26:
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  xor    %r13d,%r13d
  call   <scanf@plt>
  lea    D15(%rip),%r12
  mov    -0x2c(%rbp),%edx
  cmp    %edx,-0x30(%rbp)
  jl     L53
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %esi,%esi
  test   %edx,%edx
  jle    L61
  sub    $0x1,%edx
  lea    (%rbx,%r13,4),%rax
  xor    %esi,%esi
  add    %r13,%rdx
  lea    0x4(%rbx,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L61:
  mov    %r12,%rdi
  add    $0x1,%r13
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  cmp    %r13d,%eax
  jge    L37
L53:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L31:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D12: %d

tool: D15: %d


assistant: ```c
int main() {
  int n, k, i, j, m, x;
  scanf("%d", &n);
  int arr[n];
  for (i = 0; i <= n - 1; i++) {
    scanf("%d", &arr[i]);
  }
  scanf("%d", &k);
  for (j = 0; j <= (n - k); j++) {
    x = 0;
    for (m = 0; m <= k - 1; m++) {
      x = x + arr[j + m];
    }
    printf("%d\n", x);
  }
  return 0;
}
```