ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cbm_iec_release>:
  endbr64
  jmp    1050 <cbmarch_iec_release@plt>
```

assistant: ```c
void cbm_iec_release(int HandleDevice, int Line) {
  ;
  cbmarch_iec_release(HandleDevice, Line);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L5:
  shll   $0x4,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <str2hexnum@plt>
  or     %eax,-0x4(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
unsigned long str2hex(unsigned char *str) {
  int value = 0;
  while (*str) {
    value = value << 4;
    value |= str2hexnum(*str++);
  }
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str2hex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L20
  mov    $0x0,%eax
L11:
  shl    $0x4,%eax
  mov    %eax,%ebx
  add    $0x1,%rbp
  movzbl %dil,%edi
  call   <str2hexnum@plt>
  or     %ebx,%eax
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L11
L1:
  cltq
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
unsigned long str2hex(unsigned char *str) {
  int value = 0;
  while (*str) {
    value = value << 4;
    value |= str2hexnum(*str++);
  }
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str2hex>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L12
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  shl    $0x4,%eax
  add    $0x1,%rbp
  mov    %eax,%ebx
  call   <str2hexnum@plt>
  movzbl 0x0(%rbp),%edi
  or     %ebx,%eax
  test   %dil,%dil
  jne    L19
  add    $0x8,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long str2hex(unsigned char *str) {
  int value = 0;
  while (*str) {
    value = value << 4;
    value |= str2hexnum(*str++);
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str2hex>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L10
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  shl    $0x4,%eax
  add    $0x1,%rbp
  mov    %eax,%ebx
  call   <str2hexnum@plt>
  movzbl 0x0(%rbp),%edi
  or     %ebx,%eax
  test   %dil,%dil
  jne    L19
  add    $0x8,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long str2hex(unsigned char *str) {
  int value = 0;
  while (*str) {
    value = value << 4;
    value |= str2hexnum(*str++);
  }
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L7
  mov    $0x1,%eax
  jmp    L12
L7:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L19
  mov    $0xffffffff,%eax
  jmp    L12
L19:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  if (*(float *)a > *(float *)b) {
    return 1;
  }
  if (*(float *)a < *(float *)b) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<comp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L1
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  neg    %eax
L1:
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  if (*(float *)a > *(float *)b) {
    return 1;
  }
  if (*(float *)a < *(float *)b) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<comp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L8
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L8:
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  if (*(float *)a > *(float *)b) {
    return 1;
  }
  if (*(float *)a < *(float *)b) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<comp>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0x1,%eax
  comiss %xmm1,%xmm0
  ja     L0
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
  neg    %eax
L0:
  ret
```

assistant: ```c
int comp(const void *a, const void *b) {
  if (*(float *)a > *(float *)b) {
    return 1;
  }
  if (*(float *)a < *(float *)b) {
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ace_str_join_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ace_str_alloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ace_str_join_3(const char *s1, const char *s2, const char *s3) {
  size_t length = strlen(s1) + strlen(s2) + strlen(s3) + 1;
  char *result = ace_str_alloc(length);
  strncat(result, s1, length);
  strncat(result, s2, length);
  strncat(result, s3, length);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ace_str_join_3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <ace_str_alloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *ace_str_join_3(const char *s1, const char *s2, const char *s3) {
  size_t length = strlen(s1) + strlen(s2) + strlen(s3) + 1;
  char *result = ace_str_alloc(length);
  strncat(result, s1, length);
  strncat(result, s2, length);
  strncat(result, s3, length);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ace_str_join_3>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%r13d
  movslq %r13d,%r13
  mov    %r13,%rdi
  call   <ace_str_alloc@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *ace_str_join_3(const char *s1, const char *s2, const char *s3) {
  size_t length = strlen(s1) + strlen(s2) + strlen(s3) + 1;
  char *result = ace_str_alloc(length);
  strncat(result, s1, length);
  strncat(result, s2, length);
  strncat(result, s3, length);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ace_str_join_3>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%r13d
  movslq %r13d,%r13
  mov    %r13,%rdi
  call   <ace_str_alloc@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncat@plt>
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *ace_str_join_3(const char *s1, const char *s2, const char *s3) {
  size_t length = strlen(s1) + strlen(s2) + strlen(s3) + 1;
  char *result = ace_str_alloc(length);
  strncat(result, s1, length);
  strncat(result, s2, length);
  strncat(result, s3, length);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L9:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L108
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L47
L108:
  mov    $0x1,%eax
  jmp    L84
L47:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  jg     L92
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  jle    L9
L92:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L66
L36:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L66:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L36
  movl   $0x0,-0x8(%rbp)
  jmp    L93
L16:
  movl   $0x0,-0x4(%rbp)
  jmp    L74
L39:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L74:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L39
  addl   $0x1,-0x8(%rbp)
L93:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L16
  mov    $0x0,%eax
L84:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D27
datatype: string

tool: D13: Insert matrix length (min 4x4):

tool: D29: %d %d

tool: D27: %d

assistant: ```c
int read_matrix(int ***matrix, int *n, int *m) {
  int i, j;
  do {
    printf("Insert matrix length (min 4x4):");
    scanf("%d %d", n, m);
    if (*n == 0 || *m == 0) {
      return 1;
    }
  } while (*n < 4 && *m < 4);
  *matrix = (int **)malloc(*n * sizeof(int *));
  for (i = 0; i < *n; i++) {
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  }
  for (i = 0; i < *n; i++) {
    for (j = 0; j < *m; j++) {
      scanf("%d", &(*matrix)[i][j]);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %rdx,%rbp
  lea    D16(%rip),%r13
  lea    D22(%rip),%rbx
L109:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%r15),%eax
  test   %eax,%eax
  je     L17
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  je     L74
  cmp    $0x3,%edx
  jg     L95
  cmp    $0x3,%eax
  jle    L109
L95:
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  cmpl   $0x0,(%r15)
  jle    L129
  mov    $0x0,%ebx
L90:
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%r12),%rdx
  mov    %rax,(%rdx,%rbx,8)
  mov    (%r15),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L90
  test   %eax,%eax
  jle    L42
  movq   $0x0,0x8(%rsp)
  lea    D4(%rip),%r14
  jmp    L48
L42:
  mov    $0x0,%eax
  jmp    L70
L64:
  mov    (%r12),%rax
  mov    (%rax,%r13,1),%rax
  lea    (%rax,%rbx,4),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x0(%rbp)
  jg     L64
L146:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    %eax,(%r15)
  jle    L72
L48:
  mov    0x8(%rsp),%rax
  lea    0x0(,%rax,8),%r13
  mov    $0x0,%ebx
  cmpl   $0x0,0x0(%rbp)
  jg     L64
  jmp    L146
L17:
  mov    $0x1,%eax
  jmp    L70
L74:
  mov    $0x1,%eax
  jmp    L70
L129:
  mov    $0x0,%eax
  jmp    L70
L72:
  mov    $0x0,%eax
L70:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D16: Insert matrix length (min 4x4):

tool: D22: %d %d

tool: D4: %d

assistant: ```c
int read_matrix(int ***matrix, int *n, int *m) {
  int i, j;
  do {
    printf("Insert matrix length (min 4x4):");
    scanf("%d %d", n, m);
    if (*n == 0 || *m == 0) {
      return 1;
    }
  } while (*n < 4 && *m < 4);
  *matrix = (int **)malloc(*n * sizeof(int *));
  for (i = 0; i < *n; i++) {
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  }
  for (i = 0; i < *n; i++) {
    for (j = 0; j < *m; j++) {
      scanf("%d", &(*matrix)[i][j]);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L59:
  mov    (%rbx),%edx
  test   %edx,%edx
  je     L106
  cmp    $0x3,%edx
  jg     L8
  cmp    $0x3,%eax
  jg     L8
L48:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%r14),%eax
  test   %eax,%eax
  jne    L59
L106:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    0x0(,%rax,8),%edi
  xor    %r12d,%r12d
  call   <malloc@plt>
  mov    (%r14),%edx
  mov    %rax,0x0(%rbp)
  test   %edx,%edx
  jle    L90
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx,%r12,8)
  mov    (%r14),%eax
  add    $0x1,%r12
  cmp    %r12d,%eax
  jg     L44
  test   %eax,%eax
  jle    L90
  movq   $0x0,0x8(%rsp)
  lea    D19(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L86:
  mov    0x8(%rsp),%rax
  xor    %r15d,%r15d
  lea    0x0(,%rax,8),%r12
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L47
  cs nopw 0x0(%rax,%rax,1)
L101:
  mov    0x0(%rbp),%rax
  mov    %r13,%rdi
  mov    (%rax,%r12,1),%rax
  lea    (%rax,%r15,4),%rsi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <scanf@plt>
  cmp    %r15d,(%rbx)
  jg     L101
L47:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    %eax,(%r14)
  jg     L86
L90:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D14: Insert matrix length (min 4x4):

tool: D13: %d %d

tool: D19: %d

assistant: ```c
int read_matrix(int ***matrix, int *n, int *m) {
  int i, j;
  do {
    printf("Insert matrix length (min 4x4):");
    scanf("%d %d", n, m);
    if (*n == 0 || *m == 0) {
      return 1;
    }
  } while (*n < 4 && *m < 4);
  *matrix = (int **)malloc(*n * sizeof(int *));
  for (i = 0; i < *n; i++) {
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  }
  for (i = 0; i < *n; i++) {
    for (j = 0; j < *m; j++) {
      scanf("%d", &(*matrix)[i][j]);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  jmp    L118
  nopl   0x0(%rax,%rax,1)
L90:
  mov    (%rbx),%edx
  test   %edx,%edx
  je     L67
  cmp    $0x3,%edx
  jg     L111
  cmp    $0x3,%eax
  jg     L111
L118:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%r14),%eax
  test   %eax,%eax
  jne    L90
L67:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L111:
  lea    0x0(,%rax,8),%edi
  xor    %r12d,%r12d
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    (%r14),%eax
  test   %eax,%eax
  jle    L2
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx,%r12,8)
  mov    (%r14),%eax
  add    $0x1,%r12
  cmp    %r12d,%eax
  jg     L6
  test   %eax,%eax
  jle    L2
  mov    (%rbx),%eax
  lea    D24(%rip),%r13
  movq   $0x0,0x8(%rsp)
  test   %eax,%eax
  jle    L2
  nopl   0x0(%rax)
L56:
  mov    0x8(%rsp),%rax
  xor    %r15d,%r15d
  lea    0x0(,%rax,8),%r12
L5:
  mov    0x0(%rbp),%rax
  mov    %r13,%rdi
  mov    (%rax,%r12,1),%rax
  lea    (%rax,%r15,4),%rsi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    %r15d,%eax
  jg     L5
  mov    0x8(%rsp),%ecx
  lea    0x1(%rcx),%edx
  cmp    (%r14),%edx
  jge    L2
  addq   $0x1,0x8(%rsp)
  test   %eax,%eax
  jg     L56
L2:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D17
data_type: string
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D24
data_type: string

tool: D17: Insert matrix length (min 4x4):

tool: D21: %d %d

tool: D24: %d

assistant: ```c
int read_matrix(int ***matrix, int *n, int *m) {
  int i, j;
  do {
    printf("Insert matrix length (min 4x4):");
    scanf("%d %d", n, m);
    if (*n == 0 || *m == 0) {
      return 1;
    }
  } while (*n < 4 && *m < 4);
  *matrix = (int **)malloc(*n * sizeof(int *));
  for (i = 0; i < *n; i++) {
    (*matrix)[i] = (int *)malloc(*m * sizeof(int));
  }
  for (i = 0; i < *n; i++) {
    for (j = 0; j < *m; j++) {
      scanf("%d", &(*matrix)[i][j]);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x41,-0xc(%rbp)
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
L31:
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L35:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x5a,-0xc(%rbp)
  jne    L38
  movl   $0x41,-0xc(%rbp)
  jmp    L47
L38:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L47:
  addl   $0x1,-0x10(%rbp)
L16:
  cmpl   $0x4f,-0x10(%rbp)
  jle    L35
  mov    -0x8(%rbp),%rax
  add    $0x4f,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  char *buf;
  int i, n = 'A';
  buf = malloc(80);
  if (!buf)
    return EXIT_FAILURE;
  for (i = 0; i < 80; i++) {
    buf[i] = (char)n;
    (n == 'Z') ? n = 'A' : n++;
  }
  buf[80 - 1] = '\0';
  (void)puts(buf);
  free(buf);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x50,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rax,%rdx
  lea    0x50(%rax),%rdi
  mov    $0x41,%eax
  mov    $0x41,%esi
L13:
  mov    %al,(%rdx)
  lea    0x1(%rax),%ecx
  cmp    $0x5a,%eax
  mov    %ecx,%eax
  cmove  %esi,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L13
  movb   $0x0,0x4f(%rbx)
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
L2:
  pop    %rbx
  ret
L7:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  jmp    L2
```

assistant: ```c
int main(void) {
  char *buf;
  int i, n = 'A';
  buf = malloc(80);
  if (!buf)
    return EXIT_FAILURE;
  for (i = 0; i < 80; i++) {
    buf[i] = (char)n;
    (n == 'Z') ? n = 'A' : n++;
  }
  buf[80 - 1] = '\0';
  (void)puts(buf);
  free(buf);
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x50,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L26
  movb   $0x41,(%rax)
  mov    %rax,%rbp
  xor    %edx,%edx
  mov    $0x41,%eax
  nopl   0x0(%rax)
L59:
  add    $0x1,%eax
  lea    0x1(%rdx),%ecx
  cmp    $0x4f,%edx
  je     L19
L53:
  movslq %ecx,%rsi
  mov    %al,0x0(%rbp,%rsi,1)
  cmp    $0x5a,%eax
  jne    L47
  add    $0x2,%edx
  cmp    $0x50,%edx
  je     L19
  movslq %edx,%rax
  lea    0x1(%rdx),%ecx
  movb   $0x41,0x0(%rbp,%rax,1)
  mov    $0x41,%eax
  add    $0x1,%eax
  cmp    $0x4f,%edx
  jne    L53
L19:
  movb   $0x0,0x4f(%rbp)
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    D1(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L47:
  mov    %ecx,%edx
  jmp    L59
L26:
  mov    D3(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(void) {
  char *buf;
  int i, n = 'A';
  buf = malloc(80);
  if (!buf)
    return EXIT_FAILURE;
  for (i = 0; i < 80; i++) {
    buf[i] = (char)n;
    (n == 'Z') ? n = 'A' : n++;
  }
  buf[80 - 1] = '\0';
  (void)puts(buf);
  free(buf);
  return EXIT_SUCCESS;
}
```