ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<sj_string_alloc_join_strings_with_separator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  movq   $0x1,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L7
L18:
  cmpl   $0x0,-0x28(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  add    %rax,-0x20(%rbp)
L6:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x28(%rbp)
L7:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc_or_die@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L15
L44:
  cmpl   $0x0,-0x24(%rbp)
  je     L24
  mov    -0x48(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,-0x18(%rbp)
L24:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L44
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sj_string_alloc_join_strings_with_separator(char const *const strings[], int count, char const *separator) {
  size_t size = 1;
  size_t separator_size = strlen(separator);
  for (int i = 0; i < count; ++i) {
    if (i)
      size += separator_size;
    size += strlen(strings[i]);
  }
  char *joined = malloc_or_die(size);
  char *end = joined;
  for (int i = 0; i < count; ++i) {
    if (i)
      end = stpcpy(end, separator);
    end = stpcpy(end, strings[i]);
  }
  return joined;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sj_string_alloc_join_strings_with_separator>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %r14d,%r14d
  jle    L10
  mov    %rax,%r15
  mov    %r14d,%r14d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
L27:
  mov    -0x8(%r12,%rbx,8),%rdi
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r14,%rbx
  je     L69
  lea    0x0(%rbp,%r15,1),%rax
  test   %ebx,%ebx
  cmovne %rax,%rbp
  add    $0x1,%rbx
  jmp    L27
L68:
  mov    (%r12,%rbp,8),%rsi
  call   <stpcpy@plt>
  mov    %rax,%rdi
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  je     L37
L42:
  test   %ebp,%ebp
  je     L68
  mov    %r13,%rsi
  call   <stpcpy@plt>
  mov    %rax,%rdi
  jmp    L68
L69:
  mov    %rbp,%rdi
  call   <malloc_or_die@plt>
  mov    %rax,%r14
  mov    %rax,%rdi
  mov    $0x0,%ebp
  jmp    L42
L10:
  mov    $0x1,%edi
  call   <malloc_or_die@plt>
  mov    %rax,%r14
L37:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sj_string_alloc_join_strings_with_separator(char const *const strings[], int count, char const *separator) {
  size_t size = 1;
  size_t separator_size = strlen(separator);
  for (int i = 0; i < count; ++i) {
    if (i)
      size += separator_size;
    size += strlen(strings[i]);
  }
  char *joined = malloc_or_die(size);
  char *end = joined;
  for (int i = 0; i < count; ++i) {
    if (i)
      end = stpcpy(end, separator);
    end = stpcpy(end, strings[i]);
  }
  return joined;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sj_string_alloc_join_strings_with_separator>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <strlen@plt>
  test   %ebx,%ebx
  jle    L11
  mov    %rax,%r14
  mov    %ebx,%eax
  mov    $0x1,%r13d
  mov    %rbp,%rbx
  sub    $0x1,%eax
  lea    0x8(%rbp,%rax,8),%r15
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L39:
  add    %r14,%r13
L10:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <strlen@plt>
  add    %rax,%r13
  cmp    %r15,%rbx
  jne    L39
  mov    %r13,%rdi
  xor    %r14d,%r14d
  call   <malloc_or_die@plt>
  mov    0xc(%rsp),%ebx
  mov    %rax,%r13
  mov    %rax,%rdi
  nopl   0x0(%rax)
L4:
  test   %r14,%r14
  je     L7
  mov    %r12,%rsi
  call   <stpcpy@plt>
  mov    %rax,%rdi
L7:
  mov    0x0(%rbp,%r14,8),%rsi
  add    $0x1,%r14
  call   <stpcpy@plt>
  mov    %rax,%rdi
  cmp    %r14,%rbx
  jne    L4
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x18,%rsp
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <malloc_or_die@plt>
```

assistant: ```c
char *sj_string_alloc_join_strings_with_separator(char const *const strings[], int count, char const *separator) {
  size_t size = 1;
  size_t separator_size = strlen(separator);
  for (int i = 0; i < count; ++i) {
    if (i)
      size += separator_size;
    size += strlen(strings[i]);
  }
  char *joined = malloc_or_die(size);
  char *end = joined;
  for (int i = 0; i < count; ++i) {
    if (i)
      end = stpcpy(end, separator);
    end = stpcpy(end, strings[i]);
  }
  return joined;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sj_string_alloc_join_strings_with_separator>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <strlen@plt>
  test   %ebx,%ebx
  jle    L10
  mov    %rax,%r13
  lea    -0x1(%rbx),%eax
  mov    %r12,%rbp
  mov    $0x1,%ebx
  lea    0x8(%r12,%rax,8),%r14
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L52:
  lea    0x0(%r13,%rdi,1),%rbx
L14:
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <strlen@plt>
  lea    (%rax,%rbx,1),%rdi
  cmp    %r14,%rbp
  jne    L52
  call   <malloc_or_die@plt>
  mov    0xc(%rsp),%ebp
  xor    %ebx,%ebx
  mov    %rax,%r13
  mov    %rax,%rdi
L12:
  test   %rbx,%rbx
  jne    L57
  mov    (%r12,%rbx,8),%rsi
  mov    $0x1,%ebx
  call   <stpcpy@plt>
  mov    %rax,%rdi
  cmp    $0x1,%rbp
  je     L20
L57:
  mov    %r15,%rsi
  call   <stpcpy@plt>
  mov    (%r12,%rbx,8),%rsi
  add    $0x1,%rbx
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,%rdi
  cmp    %rbp,%rbx
  jne    L12
L20:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x18,%rsp
  mov    $0x1,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <malloc_or_die@plt>
```

assistant: ```c
char *sj_string_alloc_join_strings_with_separator(char const *const strings[], int count, char const *separator) {
  size_t size = 1;
  size_t separator_size = strlen(separator);
  for (int i = 0; i < count; ++i) {
    if (i)
      size += separator_size;
    size += strlen(strings[i]);
  }
  char *joined = malloc_or_die(size);
  char *end = joined;
  for (int i = 0; i < count; ++i) {
    if (i)
      end = stpcpy(end, separator);
    end = stpcpy(end, strings[i]);
  }
  return joined;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Agglomerative_criterion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  lea    -0x2(%rax),%ebx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Distance@plt>
  imul   %eax,%ebx
  mov    -0x30(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Sum_S@plt>
  sub    %eax,%ebx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <Sum_S@plt>
  sub    %eax,%ebx
  mov    %ebx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float Agglomerative_criterion(int i, int j, float **delta, int r) {
  float Qij;
  Qij = (r - 2) * Distance(i, j, delta) - Sum_S(i, delta) - Sum_S(j, delta);
  return (Qij);
}
```
user: What is the c source code of the assembly code below?

```asm
<Agglomerative_criterion>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  call   <Distance@plt>
  sub    $0x2,%ebx
  imul   %eax,%ebx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <Sum_S@plt>
  sub    %eax,%ebx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <Sum_S@plt>
  sub    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float Agglomerative_criterion(int i, int j, float **delta, int r) {
  float Qij;
  Qij = (r - 2) * Distance(i, j, delta) - Sum_S(i, delta) - Sum_S(j, delta);
  return (Qij);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Agglomerative_criterion>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x2,%ebx
  sub    $0x8,%rsp
  call   <Distance@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  imul   %eax,%ebx
  call   <Sum_S@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    %eax,%ebx
  call   <Sum_S@plt>
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  sub    %eax,%ebx
  cvtsi2ss %ebx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float Agglomerative_criterion(int i, int j, float **delta, int r) {
  float Qij;
  Qij = (r - 2) * Distance(i, j, delta) - Sum_S(i, delta) - Sum_S(j, delta);
  return (Qij);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Agglomerative_criterion>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x2,%ebx
  sub    $0x8,%rsp
  call   <Distance@plt>
  mov    %rbp,%rsi
  mov    %r13d,%edi
  imul   %eax,%ebx
  call   <Sum_S@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    %eax,%ebx
  call   <Sum_S@plt>
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  sub    %eax,%ebx
  cvtsi2ss %ebx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float Agglomerative_criterion(int i, int j, float **delta, int r) {
  float Qij;
  Qij = (r - 2) * Distance(i, j, delta) - Sum_S(i, delta) - Sum_S(j, delta);
  return (Qij);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mp_mulhf_use_in1fft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %esi,%r15d
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r12
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    0x60(%rsp),%r14d
  mov    %r14d,%ebx
  sar    %ebx
  add    $0x1,%ebx
  cmp    %edi,%ebx
  jge    L19
  movslq %ebx,%rax
L24:
  mov    %eax,%ebx
  cmpl   $0x0,0x8(%r12,%rax,4)
  jne    L19
  lea    0x1(%rax),%ebx
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L24
L19:
  mov    %ebp,%r13d
  shr    $0x1f,%r13d
  add    %ebp,%r13d
  sar    %r13d
  add    $0x1,%r13d
  mov    %ebp,%eax
  sub    %ebx,%eax
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  mov    0x68(%rsp),%r9
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    0x78(%rsp),%r8
  mov    0x70(%rsp),%rcx
  mov    0x68(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%edi
  call   <mp_mul_cmul_nt_d1@plt>
  mov    0x10(%rsp),%r8
  mov    0x68(%rsp),%rcx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_d2i@plt>
  mov    0x68(%rsp),%r9
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_mul_i2d@plt>
  mov    0x78(%rsp),%r8
  mov    0x70(%rsp),%rcx
  mov    0x68(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %r14d,%edi
  call   <mp_mul_cmul_nt_d1@plt>
  mov    0x18(%rsp),%rbx
  mov    %rbx,%r8
  mov    0x68(%rsp),%rcx
  mov    %r14d,%edx
  mov    %r15d,%esi
  mov    %r13d,%edi
  call   <mp_mul_d2i@plt>
  cmpl   $0x0,(%rbx)
  je     L45
  mov    %rbx,%r8
  mov    0x10(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_add@plt>
L32:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%rdx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <mp_copy@plt>
  jmp    L32
```

assistant: ```c
void mp_mulhf_use_in1fft(int n, int radix, double in1fft[], int in2[], int out[], int tmp[], int nfft, double tmpfft[], int ip[], double w[]) {
  void mp_copy(int n, int radix, int in[], int out[]);
  void mp_add(int n, int radix, int in1[], int in2[], int out[]);
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul_nt_d1(int nfft, double d1[], double d2[], int ip[], double w[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  int n_h, shift;
  shift = (nfft >> 1) + 1;
  while (n > shift) {
    if (in2[shift + 2] != 0) {
      break;
    }
    shift++;
  }
  n_h = n / 2 + 1;
  if (n_h < n - shift) {
    n_h = n - shift;
  }
  mp_mul_i2d(n, radix, nfft, 0, in2, tmpfft);
  mp_mul_cmul_nt_d1(nfft, in1fft, tmpfft, ip, w);
  mp_mul_d2i(n, radix, nfft, tmpfft, tmp);
  mp_mul_i2d(n, radix, nfft, shift, in2, tmpfft);
  mp_mul_cmul_nt_d1(nfft, in1fft, tmpfft, ip, w);
  mp_mul_d2i(n_h, radix, nfft, tmpfft, out);
  if (out[0] != 0) {
    mp_add(n, radix, out, tmp, out);
  } else {
    mp_copy(n, radix, tmp, out);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x46,-0x30(%rbp)
  movl   $0x50,-0x2c(%rbp)
  movl   $0x5f,-0x28(%rbp)
  movl   $0x41,-0x24(%rbp)
  movl   $0x23,-0x20(%rbp)
  movl   $0x55,-0x1c(%rbp)
  movl   $0x36,-0x18(%rbp)
  movl   $0x4e,-0x14(%rbp)
  movl   $0x2d,-0x10(%rbp)
  movl   $0x44,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <print_arr@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x46,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <count_passes@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jne    L8
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
L8:
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string

tool: D5: There was %d pass.


tool: D14: There were %d passes.


assistant: ```c
int main(void) {
  int grades[10] = {70, 80, 95, 65, 35, 85, 54, 78, 45, 68};
  int result;
  print_arr(grades, 10);
  result = count_passes(grades, 10, 70);
  if (result == 1)
    printf("There was %d pass.\n", result);
  else
    printf("There were %d passes.\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x46,(%rsp)
  movl   $0x50,0x4(%rsp)
  movl   $0x5f,0x8(%rsp)
  movl   $0x41,0xc(%rsp)
  movl   $0x23,0x10(%rsp)
  movl   $0x55,0x14(%rsp)
  movl   $0x36,0x18(%rsp)
  movl   $0x4e,0x1c(%rsp)
  movl   $0x2d,0x20(%rsp)
  movl   $0x44,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_arr@plt>
  mov    $0x46,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <count_passes@plt>
  cmp    $0x1,%eax
  je     L18
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L18:
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string
name: unpack_data
arguments: label: D17
data_type: string

tool: D2: There were %d passes.


tool: D17: There was %d pass.


assistant: ```c
int main(void) {
  int grades[10] = {70, 80, 95, 65, 35, 85, 54, 78, 45, 68};
  int result;
  print_arr(grades, 10);
  result = count_passes(grades, 10, 70);
  if (result == 1)
    printf("There was %d pass.\n", result);
  else
    printf("There were %d passes.\n", result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x5000000046,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x410000005f,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x5500000023,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x4e00000036,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x440000002d,%rax
  mov    %rax,0x20(%rsp)
  call   <print_arr@plt>
  mov    $0xa,%esi
  mov    $0x46,%edx
  mov    %rbp,%rdi
  call   <count_passes@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  je     L6
  lea    D6(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D16
type: string

tool: D6: There were %d passes.


tool: D16: There was %d pass.


assistant: ```c
int main(void) {
  int grades[10] = {70, 80, 95, 65, 35, 85, 54, 78, 45, 68};
  int result;
  print_arr(grades, 10);
  result = count_passes(grades, 10, 70);
  if (result == 1)
    printf("There was %d pass.\n", result);
  else
    printf("There were %d passes.\n", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x30,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D13(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <print_arr@plt>
  mov    $0xa,%esi
  mov    $0x46,%edx
  mov    %rbp,%rdi
  call   <count_passes@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  je     L6
  lea    D20(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: byte[16]
name: unpack_data
arguments: data_label: D13
type: byte[8]
name: unpack_data
arguments: data_label: D26
type: byte[16]
name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D25
type: string

tool: {"D9": [0x46,0x00,0x00,0x00,0x50,0x00,0x00,0x00,0x5f,0x00,0x00,0x00,0x41,0x00,0x00,0x00]}

tool: {"D13": [0x2d,0x00,0x00,0x00,0x44,0x00,0x00,0x00]}

tool: {"D26": [0x23,0x00,0x00,0x00,0x55,0x00,0x00,0x00,0x36,0x00,0x00,0x00,0x4e,0x00,0x00,0x00]}

tool: D20: There were %d passes.


tool: D25: There was %d pass.


assistant: ```c
int main(void) {
  int grades[10] = {70, 80, 95, 65, 35, 85, 54, 78, 45, 68};
  int result;
  print_arr(grades, 10);
  result = count_passes(grades, 10, 70);
  if (result == 1)
    printf("There was %d pass.\n", result);
  else
    printf("There were %d passes.\n", result);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mk_change>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L4:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
L11:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  jne    L2
  mov    -0x18(%rbp),%rax
  movl   $0x2,(%rax)
L2:
  addq   $0x4,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0x5,-0x4(%rbp)
  jle    L4
  subq   $0x18,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mk_change(int *hexagram_2) {
  int cntr1;
  for (cntr1 = 0; cntr1 < 6; cntr1++) {
    if (*hexagram_2 == 0) {
      *hexagram_2 = 1;
    }
    if (*hexagram_2 == 3) {
      *hexagram_2 = 2;
    }
    hexagram_2++;
  }
  hexagram_2 -= 6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mk_change>:
  endbr64
  lea    0x18(%rdi),%rdx
  jmp    L3
L40:
  cmp    $0x3,%eax
  jne    L15
  movl   $0x2,(%rdi)
L15:
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  je     L7
L3:
  mov    (%rdi),%eax
  test   %eax,%eax
  jne    L40
  movl   $0x1,(%rdi)
  jmp    L15
L7:
  ret
```

assistant: ```c
void mk_change(int *hexagram_2) {
  int cntr1;
  for (cntr1 = 0; cntr1 < 6; cntr1++) {
    if (*hexagram_2 == 0) {
      *hexagram_2 = 1;
    }
    if (*hexagram_2 == 3) {
      *hexagram_2 = 2;
    }
    hexagram_2++;
  }
  hexagram_2 -= 6;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mk_change>:
  endbr64
  lea    0x18(%rdi),%rdx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L22:
  movl   $0x1,(%rdi)
L2:
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  je     L36
L25:
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L22
  cmp    $0x3,%eax
  jne    L2
  movl   $0x2,(%rdi)
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  jne    L25
L36:
  ret
```

assistant: ```c
void mk_change(int *hexagram_2) {
  int cntr1;
  for (cntr1 = 0; cntr1 < 6; cntr1++) {
    if (*hexagram_2 == 0) {
      *hexagram_2 = 1;
    }
    if (*hexagram_2 == 3) {
      *hexagram_2 = 2;
    }
    hexagram_2++;
  }
  hexagram_2 -= 6;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mk_change>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L115
  cmp    $0x3,%eax
  jne    L129
  movl   $0x2,(%rdi)
L129:
  mov    0x4(%rdi),%eax
  test   %eax,%eax
  je     L94
  cmp    $0x3,%eax
  jne    L50
  movl   $0x2,0x4(%rdi)
L50:
  mov    0x8(%rdi),%eax
  test   %eax,%eax
  je     L42
  cmp    $0x3,%eax
  jne    L2
  movl   $0x2,0x8(%rdi)
L2:
  mov    0xc(%rdi),%eax
  test   %eax,%eax
  je     L84
  cmp    $0x3,%eax
  jne    L102
  movl   $0x2,0xc(%rdi)
L102:
  mov    0x10(%rdi),%eax
  test   %eax,%eax
  je     L121
  cmp    $0x3,%eax
  jne    L53
  movl   $0x2,0x10(%rdi)
L53:
  mov    0x14(%rdi),%eax
  test   %eax,%eax
  jne    L30
L18:
  movl   $0x1,0x14(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L121:
  mov    0x14(%rdi),%eax
  movl   $0x1,0x10(%rdi)
  test   %eax,%eax
  je     L18
L30:
  cmp    $0x3,%eax
  jne    L113
  movl   $0x2,0x14(%rdi)
L113:
  ret
  nopl   0x0(%rax,%rax,1)
L84:
  movl   $0x1,0xc(%rdi)
  jmp    L102
  nopl   0x0(%rax)
L42:
  movl   $0x1,0x8(%rdi)
  jmp    L2
  nopl   0x0(%rax)
L94:
  movl   $0x1,0x4(%rdi)
  jmp    L50
  nopl   0x0(%rax)
L115:
  movl   $0x1,(%rdi)
  jmp    L129
```

assistant: ```c
void mk_change(int *hexagram_2) {
  int cntr1;
  for (cntr1 = 0; cntr1 < 6; cntr1++) {
    if (*hexagram_2 == 0) {
      *hexagram_2 = 1;
    }
    if (*hexagram_2 == 3) {
      *hexagram_2 = 2;
    }
    hexagram_2++;
  }
  hexagram_2 -= 6;
}
```