ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<groupRecognize>:
  endbr64
  test   %ecx,%ecx
  jle    L3
  push   %r15
  lea    -0x1(%rcx),%eax
  push   %r14
  lea    0x8(%rdx,%rax,8),%r15
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L13:
  mov    (%rbx),%rdx
  mov    0x0(%rbp),%rsi
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12,%rdi
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <recognize@plt>
  cmp    %r15,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void groupRecognize(double **neurons, double **images, double **result, int num_images, int rec_images_num, int data_dim) {
  int i;
  for (i = 0; i < num_images; i++) {
    recognize(neurons, images[i], result[i], rec_images_num, data_dim);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<host_to_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L20
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    $0x4,%eax
  je     L41
L20:
  mov    $0xffffffff,%eax
  jmp    L26
L41:
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  jmp    L26
L25:
  mov    $0xffffffff,%eax
L26:
  leave
  ret
```

assistant: ```c
int host_to_addr(const char *name, struct in_addr *addr) {
  struct hostent *host;
  if ((host = gethostbyname(name)) != NULL) {
    if (host->h_addrtype != AF_INET || host->h_length != sizeof(struct in_addr))
      return -1;
    memcpy(addr, host->h_addr_list[0], sizeof(struct in_addr));
    return 0;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<host_to_addr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L9
  mov    D5(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,(%rax)
  jne    L30
  cmpl   $0x4,0x8(%rax)
  jne    L45
  mov    0x10(%rax),%rax
  mov    $0x4,%edx
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L26:
  pop    %rbx
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L26
L30:
  mov    $0xffffffff,%eax
  jmp    L26
L45:
  mov    $0xffffffff,%eax
  jmp    L26
```

assistant: ```c
int host_to_addr(const char *name, struct in_addr *addr) {
  struct hostent *host;
  if ((host = gethostbyname(name)) != NULL) {
    if (host->h_addrtype != AF_INET || host->h_length != sizeof(struct in_addr))
      return -1;
    memcpy(addr, host->h_addr_list[0], sizeof(struct in_addr));
    return 0;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<host_to_addr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L9
  mov    D1(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,(%rax)
  jne    L9
  cmpl   $0x4,0x8(%rax)
  jne    L9
  mov    0x10(%rax),%rax
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    (%rax),%esi
  call   <memcpy@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L9:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int host_to_addr(const char *name, struct in_addr *addr) {
  struct hostent *host;
  if ((host = gethostbyname(name)) != NULL) {
    if (host->h_addrtype != AF_INET || host->h_length != sizeof(struct in_addr))
      return -1;
    memcpy(addr, host->h_addr_list[0], sizeof(struct in_addr));
    return 0;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<host_to_addr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L10
  mov    D0(%rip),%rdx
  mov    (%rdx),%rcx
  cmp    %rcx,(%rax)
  jne    L10
  cmpl   $0x4,0x8(%rax)
  jne    L10
  mov    0x10(%rax),%rax
  mov    %rbp,%rdi
  mov    $0x4,%edx
  mov    (%rax),%esi
  call   <memcpy@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L10:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int host_to_addr(const char *name, struct in_addr *addr) {
  struct hostent *host;
  if ((host = gethostbyname(name)) != NULL) {
    if (host->h_addrtype != AF_INET || host->h_length != sizeof(struct in_addr))
      return -1;
    memcpy(addr, host->h_addr_list[0], sizeof(struct in_addr));
    return 0;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  jle    L9
  cmpl   $0x24,-0x34(%rbp)
  jle    L34
L9:
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L31
L34:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L58:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  lea    D6(%rip),%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rax)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L58
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L5
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
L5:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L18
  mov    -0x30(%rbp),%rax
L31:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(unsigned long value, char *str, int base) {
  char *ptr, *low;
  if (base < 2 || base > 36) {
    *str = 0;
    return str;
  }
  ptr = low = str;
  do {
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[value % base];
    value /= base;
  } while (value);
  *ptr-- = 0;
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itoa>:
  endbr64
  mov    %rsi,%r9
  lea    -0x2(%rdx),%eax
  movslq %edx,%r8
  lea    D3(%rip),%r10
  cmp    $0x22,%eax
  ja     L38
L36:
  mov    %rsi,%rcx
  add    $0x1,%rsi
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %r8
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  mov    %rdi,%rdx
  mov    %rax,%rdi
  cmp    %rdx,%r8
  jbe    L36
  movb   $0x0,(%rsi)
  cmp    %r9,%rcx
  jbe    L49
  mov    %r9,%rax
L25:
  movzbl (%rax),%edx
  add    $0x1,%rax
  movzbl (%rcx),%esi
  mov    %sil,-0x1(%rax)
  sub    $0x1,%rcx
  mov    %dl,0x1(%rcx)
  cmp    %rcx,%rax
  jb     L25
L49:
  mov    %r9,%rax
  ret
L38:
  movb   $0x0,(%rsi)
  jmp    L49
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(unsigned long value, char *str, int base) {
  char *ptr, *low;
  if (base < 2 || base > 36) {
    *str = 0;
    return str;
  }
  ptr = low = str;
  do {
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[value % base];
    value /= base;
  } while (value);
  *ptr-- = 0;
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  mov    %rsi,%r10
  lea    -0x2(%rdx),%eax
  lea    D0(%rip),%r11
  movslq %edx,%rsi
  mov    %r10,%r8
  cmp    $0x22,%eax
  ja     L33
  nopl   0x0(%rax)
L41:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %r8,%rcx
  mov    %rdi,%r9
  div    %rsi
  lea    0x1(%r8),%r8
  movzbl (%r11,%rdx,1),%edx
  mov    %rax,%rdi
  mov    %dl,-0x1(%r8)
  cmp    %rsi,%r9
  jae    L41
  movb   $0x0,(%r8)
  cmp    %r10,%rcx
  jbe    L24
  mov    %r10,%rax
  jmp    L30
  nopl   0x0(%rax)
L17:
  movzbl (%rcx),%edx
L30:
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  mov    %sil,0x1(%rcx)
  cmp    %rcx,%rax
  jb     L17
L24:
  mov    %r10,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  movb   $0x0,(%r10)
  mov    %r10,%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(unsigned long value, char *str, int base) {
  char *ptr, *low;
  if (base < 2 || base > 36) {
    *str = 0;
    return str;
  }
  ptr = low = str;
  do {
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[value % base];
    value /= base;
  } while (value);
  *ptr-- = 0;
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itoa>:
  endbr64
  mov    %rsi,%r9
  lea    -0x2(%rdx),%eax
  lea    D2(%rip),%r10
  movslq %edx,%rsi
  mov    %r9,%r8
  cmp    $0x22,%eax
  ja     L33
  nopl   0x0(%rax)
L26:
  mov    %rdi,%rax
  xor    %edx,%edx
  mov    %r8,%rcx
  div    %rsi
  lea    0x1(%r8),%r8
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,-0x1(%r8)
  mov    %rdi,%rdx
  mov    %rax,%rdi
  cmp    %rsi,%rdx
  jae    L26
  movb   $0x0,(%r8)
  mov    %r9,%rax
  cmp    %r9,%rcx
  jbe    L37
  nop
L5:
  movzbl (%rax),%edx
  movzbl (%rcx),%esi
  add    $0x1,%rax
  sub    $0x1,%rcx
  mov    %sil,-0x1(%rax)
  mov    %dl,0x1(%rcx)
  cmp    %rcx,%rax
  jb     L5
L37:
  mov    %r9,%rax
  ret
  xchg   %ax,%ax
L33:
  movb   $0x0,(%r9)
  mov    %r9,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(unsigned long value, char *str, int base) {
  char *ptr, *low;
  if (base < 2 || base > 36) {
    *str = 0;
    return str;
  }
  ptr = low = str;
  do {
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[value % base];
    value /= base;
  } while (value);
  *ptr-- = 0;
  while (low < ptr) {
    char tmp = *low;
    *low++ = *ptr;
    *ptr-- = tmp;
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<printhelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D74
type_guessed: string
name: disassemble_data
arguments: data_label: D77
type_guessed: string
name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D6
type_guessed: string
name: disassemble_data
arguments: data_label: D78
type_guessed: string
name: disassemble_data
arguments: data_label: D60
type_guessed: string
name: disassemble_data
arguments: data_label: D4
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string

tool: D74: Usage: %s OPTIONS*


tool: D77:   -c  Convert hex string into characters

tool: D28:   -h  Convert characters into a hex string

tool: D6:   -t  Parse as TLV

tool: D78: The options can be chained in any order, e.g.:

tool: D60:   $ echo Hello | %s -h -c


tool: D4:   Hello

tool: D29: i.e. Hello was converted to hex and back again

assistant: ```c
void printhelp(char *name) {
  printf("Usage: %s OPTIONS*\n", name);
  printf("\n");
  printf("  -c  Convert hex string into characters\n");
  printf("  -h  Convert characters into a hex string\n");
  printf("  -t  Parse as TLV\n");
  printf("\n");
  printf("The options can be chained in any order, e.g.:\n");
  printf("  $ echo Hello | %s -h -c\n", name);
  printf("  Hello\n");
  printf("i.e. Hello was converted to hex and back again\n");
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printhelp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D68
type: string
name: unpack_data
arguments: data_label: D63
type: string
name: unpack_data
arguments: data_label: D19
type: string
name: unpack_data
arguments: data_label: D7
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D54
type: string
name: unpack_data
arguments: data_label: D45
type: string

tool: D10: Usage: %s OPTIONS*


tool: D68:   -c  Convert hex string into characters

tool: D63:   -h  Convert characters into a hex string

tool: D19:   -t  Parse as TLV

tool: D7: The options can be chained in any order, e.g.:

tool: D15:   $ echo Hello | %s -h -c


tool: D54:   Hello

tool: D45: i.e. Hello was converted to hex and back again

assistant: ```c
void printhelp(char *name) {
  printf("Usage: %s OPTIONS*\n", name);
  printf("\n");
  printf("  -c  Convert hex string into characters\n");
  printf("  -h  Convert characters into a hex string\n");
  printf("  -t  Parse as TLV\n");
  printf("\n");
  printf("The options can be chained in any order, e.g.:\n");
  printf("  $ echo Hello | %s -h -c\n", name);
  printf("  Hello\n");
  printf("i.e. Hello was converted to hex and back again\n");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printhelp>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D77(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D24
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D33
datatype: string
name: read_data
arguments: data_tag: D60
datatype: string
name: read_data
arguments: data_tag: D77
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D34
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D24: Usage: %s OPTIONS*


tool: D20:   -c  Convert hex string into characters

tool: D33:   -h  Convert characters into a hex string

tool: D60:   -t  Parse as TLV

tool: D77: The options can be chained in any order, e.g.:

tool: D7:   $ echo Hello | %s -h -c


tool: D34:   Hello

tool: D17: i.e. Hello was converted to hex and back again

assistant: ```c
void printhelp(char *name) {
  printf("Usage: %s OPTIONS*\n", name);
  printf("\n");
  printf("  -c  Convert hex string into characters\n");
  printf("  -h  Convert characters into a hex string\n");
  printf("  -t  Parse as TLV\n");
  printf("\n");
  printf("The options can be chained in any order, e.g.:\n");
  printf("  $ echo Hello | %s -h -c\n", name);
  printf("  Hello\n");
  printf("i.e. Hello was converted to hex and back again\n");
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printhelp>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D48
type_infered: string
name: parse_data
arguments: data_label: D37
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D28
type_infered: string
name: parse_data
arguments: data_label: D64
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D65
type_infered: string

tool: D48: Usage: %s OPTIONS*


tool: D37:   -c  Convert hex string into characters

tool: D11:   -h  Convert characters into a hex string

tool: D28:   -t  Parse as TLV

tool: D64: The options can be chained in any order, e.g.:

tool: D29:   $ echo Hello | %s -h -c


tool: D8:   Hello

tool: D65: i.e. Hello was converted to hex and back again

assistant: ```c
void printhelp(char *name) {
  printf("Usage: %s OPTIONS*\n", name);
  printf("\n");
  printf("  -c  Convert hex string into characters\n");
  printf("  -h  Convert characters into a hex string\n");
  printf("  -t  Parse as TLV\n");
  printf("\n");
  printf("The options can be chained in any order, e.g.:\n");
  printf("  $ echo Hello | %s -h -c\n", name);
  printf("  Hello\n");
  printf("i.e. Hello was converted to hex and back again\n");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InsSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L31:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0x0,-0x8(%rbp)
  jle    L36
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L31
L36:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <ShowData@plt>
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  nop
  nop
  leave
  ret
```

assistant: ```c
void InsSort(int num[], int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--)
      num[j] = num[j - 1];
    num[j] = temp;
    ShowData(num, 8);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<InsSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L60
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  lea    0x4(%rdi),%rbp
  mov    $0x1,%ebx
  jmp    L4
L33:
  movslq %edx,%rdx
  mov    %esi,(%r12,%rdx,4)
  mov    $0x8,%esi
  mov    %r12,%rdi
  call   <ShowData@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r13d
  je     L65
L4:
  mov    0x0(%rbp),%esi
  mov    %rbp,%rax
  mov    %ebx,%edx
  test   %ebx,%ebx
  jle    L33
L62:
  mov    -0x4(%rax),%ecx
  cmp    %esi,%ecx
  jle    L33
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L62
  jmp    L33
L65:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  ret
```

assistant: ```c
void InsSort(int num[], int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--)
      num[j] = num[j - 1];
    num[j] = temp;
    ShowData(num, 8);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<InsSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L24
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    0x4(%rdi),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r12),%esi
  mov    %r12,%rax
  nop
L29:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %esi,%edx
  jle    L21
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rax,%rbx
  jne    L29
  mov    %rbx,%rcx
L21:
  mov    %esi,(%rcx)
  mov    %rbx,%rdi
  mov    $0x8,%esi
  add    $0x1,%r13d
  add    $0x4,%r12
  call   <ShowData@plt>
  cmp    %r13d,%ebp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  ret
```

assistant: ```c
void InsSort(int num[], int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--)
      num[j] = num[j - 1];
    num[j] = temp;
    ShowData(num, 8);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<InsSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L26
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    0x4(%rdi),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L25:
  mov    (%r12),%esi
  mov    %r12,%rax
  nop
L22:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %esi,%edx
  jle    L37
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rbx,%rax
  jne    L22
  mov    %rbx,%rcx
L37:
  mov    %esi,(%rcx)
  mov    %rbx,%rdi
  mov    $0x8,%esi
  add    $0x1,%r13d
  add    $0x4,%r12
  call   <ShowData@plt>
  cmp    %r13d,%ebp
  jne    L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  ret
```

assistant: ```c
void InsSort(int num[], int n) {
  int i, j, temp;
  for (i = 1; i < n; i++) {
    temp = num[i];
    for (j = i; j > 0 && num[j - 1] > temp; j--)
      num[j] = num[j - 1];
    num[j] = temp;
    ShowData(num, 8);
  }
}
```