ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lrintl>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <feholdexcept@plt>
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <rintl@plt>
  mov    %rax,%r12
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <fetestexcept@plt>
  pop    %rdx
  pop    %rcx
  test   %rax,%rax
  jne    L17
L2:
  mov    %rbp,%rdi
  call   <feupdateenv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <feclearexcept@plt>
  jmp    L2
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long lrintl(long double x) {
  fenv_t env;
  long d;
  feholdexcept(&env);
  d = (long)rintl(x);
  if (fetestexcept(FE_INVALID))
    feclearexcept(FE_INEXACT);
  feupdateenv(&env);
  return (d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lrintl>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <feholdexcept@plt>
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <rintl@plt>
  mov    %rax,%r12
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <fetestexcept@plt>
  pop    %rdx
  pop    %rcx
  test   %rax,%rax
  jne    L1
L3:
  mov    %rbp,%rdi
  call   <feupdateenv@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <feclearexcept@plt>
  jmp    L3
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long lrintl(long double x) {
  fenv_t env;
  long d;
  feholdexcept(&env);
  d = (long)rintl(x);
  if (fetestexcept(FE_INVALID))
    feclearexcept(FE_INEXACT);
  feupdateenv(&env);
  return (d);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L16:
  addl   $0x1,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L16
  jmp    L0
L27:
  subl   $0x1,-0x20(%rbp)
L0:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L27
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L56
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L20
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int array[], int left, int right) {
  int p;
  int tmp;
  p = array[(left + right) / 2];
  while (left <= right) {
    while (array[left] < p)
      left++;
    while (p < array[right])
      right--;
    if (left <= right) {
      tmp = array[left];
      array[left] = array[right];
      array[right] = tmp;
      left++;
      right--;
    }
  }
  return left;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<partition>:
  endbr64
  mov    %rdi,%r11
  mov    %esi,%ecx
  lea    (%rsi,%rdx,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  jmp    L16
L19:
  mov    %r8d,(%r9)
  mov    %esi,(%r10)
  add    $0x1,%ecx
  sub    $0x1,%edx
  jmp    L16
L78:
  movslq %edx,%rax
  lea    (%r11,%rax,4),%r10
  mov    (%r10),%r8d
  cmp    %r8d,%edi
  jge    L19
L96:
  movslq %edx,%rax
  lea    -0x4(%r11,%rax,4),%rax
L4:
  sub    $0x1,%edx
  mov    %rax,%r10
  sub    $0x4,%rax
  mov    0x4(%rax),%r8d
  cmp    %edi,%r8d
  jg     L4
L41:
  cmp    %ecx,%edx
  jge    L19
L16:
  cmp    %edx,%ecx
  jg     L50
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%r11,%rax,1),%r9
  mov    (%r9),%esi
  lea    0x4(%r11,%rax,1),%rax
  cmp    %esi,%edi
  jle    L78
L48:
  add    $0x1,%ecx
  mov    %rax,%r9
  add    $0x4,%rax
  mov    -0x4(%rax),%esi
  cmp    %edi,%esi
  jl     L48
  movslq %edx,%rax
  lea    (%r11,%rax,4),%r10
  mov    (%r10),%r8d
  cmp    %r8d,%edi
  jl     L96
  jmp    L41
L50:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int partition(int array[], int left, int right) {
  int p;
  int tmp;
  p = array[(left + right) / 2];
  while (left <= right) {
    while (array[left] < p)
      left++;
    while (p < array[right])
      right--;
    if (left <= right) {
      tmp = array[left];
      array[left] = array[right];
      array[right] = tmp;
      left++;
      right--;
    }
  }
  return left;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  lea    (%rsi,%rdx,1),%ecx
  mov    %rdi,%r11
  mov    %esi,%r8d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  cmp    %edx,%esi
  jg     L43
  push   %rbx
L38:
  movslq %r8d,%rax
  movslq %edx,%rbx
  shl    $0x2,%rax
  lea    (%r11,%rbx,4),%r10
  lea    (%r11,%rax,1),%rcx
  mov    (%r10),%r9d
  lea    0x4(%r11,%rax,1),%rax
  mov    (%rcx),%esi
  cmp    %edi,%esi
  jge    L89
L83:
  mov    %rax,%rcx
  mov    (%rax),%esi
  lea    0x4(%rax),%rax
  add    $0x1,%r8d
  cmp    %edi,%esi
  jl     L83
  cmp    %r9d,%edi
  jge    L57
L23:
  lea    -0x4(%r11,%rbx,4),%rax
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %rax,%r10
  mov    (%rax),%r9d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%r9d
  jg     L74
L57:
  cmp    %r8d,%edx
  jge    L42
L70:
  cmp    %edx,%r8d
  jle    L38
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L89:
  cmp    %r9d,%edi
  jl     L23
L42:
  mov    %r9d,(%rcx)
  add    $0x1,%r8d
  sub    $0x1,%edx
  mov    %esi,(%r10)
  jmp    L70
L43:
  mov    %esi,%eax
  ret
```

assistant: ```c
int partition(int array[], int left, int right) {
  int p;
  int tmp;
  p = array[(left + right) / 2];
  while (left <= right) {
    while (array[left] < p)
      left++;
    while (p < array[right])
      right--;
    if (left <= right) {
      tmp = array[left];
      array[left] = array[right];
      array[right] = tmp;
      left++;
      right--;
    }
  }
  return left;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<partition>:
  endbr64
  lea    (%rsi,%rdx,1),%ecx
  mov    %rdi,%r11
  mov    %esi,%r8d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  cmp    %edx,%esi
  jg     L14
  push   %rbx
L15:
  movslq %r8d,%rax
  movslq %edx,%rbx
  shl    $0x2,%rax
  lea    (%r11,%rbx,4),%r10
  lea    (%r11,%rax,1),%rcx
  mov    (%r10),%r9d
  lea    0x4(%r11,%rax,1),%rax
  mov    (%rcx),%esi
  cmp    %edi,%esi
  jge    L13
L7:
  mov    %rax,%rcx
  mov    (%rax),%esi
  lea    0x4(%rax),%rax
  add    $0x1,%r8d
  cmp    %edi,%esi
  jl     L7
  cmp    %r9d,%edi
  jge    L69
L89:
  lea    -0x4(%r11,%rbx,4),%rax
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rax,%r10
  mov    (%rax),%r9d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%r9d
  jg     L26
L69:
  cmp    %r8d,%edx
  jge    L81
L73:
  cmp    %edx,%r8d
  jle    L15
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L13:
  cmp    %r9d,%edi
  jl     L89
L81:
  mov    %r9d,(%rcx)
  add    $0x1,%r8d
  sub    $0x1,%edx
  mov    %esi,(%r10)
  jmp    L73
L14:
  mov    %esi,%eax
  ret
```

assistant: ```c
int partition(int array[], int left, int right) {
  int p;
  int tmp;
  p = array[(left + right) / 2];
  while (left <= right) {
    while (array[left] < p)
      left++;
    while (p < array[right])
      right--;
    if (left <= right) {
      tmp = array[left];
      array[left] = array[right];
      array[right] = tmp;
      left++;
      right--;
    }
  }
  return left;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L29
  cmpl   $0x3,-0x14(%rbp)
  je     L29
  cmpl   $0x5,-0x14(%rbp)
  je     L29
  cmpl   $0x7,-0x14(%rbp)
  je     L29
  cmpl   $0xb,-0x14(%rbp)
  jne    L76
L29:
  mov    $0x1,%eax
  jmp    L52
L76:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L113
  mov    $0x0,%eax
  jmp    L52
L113:
  movl   $0x3,-0x4(%rbp)
  jmp    L34
L22:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L89
  mov    $0x0,%eax
  jmp    L52
L89:
  addl   $0x2,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L22
  mov    $0x1,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7 || n == 11)
    return 1;
  if (n % 2 == 0)
    return 0;
  int i;
  for (i = 3; i * i <= n; i += 2)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPrime>:
  endbr64
  cmp    $0xb,%edi
  ja     L72
  mov    $0x1,%eax
  mov    $0x8ac,%edx
  bt     %rdi,%rdx
  jae    L72
L39:
  ret
L72:
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L39
  cmp    $0x8,%edi
  jle    L57
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L39
  mov    $0x3,%ecx
L6:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L49
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L6
  jmp    L39
L49:
  mov    $0x1,%eax
  ret
L57:
  mov    $0x1,%eax
  jmp    L39
```

assistant: ```c
int isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7 || n == 11)
    return 1;
  if (n % 2 == 0)
    return 0;
  int i;
  for (i = 3; i * i <= n; i += 2)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isPrime>:
  endbr64
  cmp    $0xb,%edi
  jbe    L77
L57:
  xor    %edx,%edx
  test   $0x1,%dil
  je     L58
  cmp    $0x8,%edi
  jle    L31
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %edi,%edx
  sub    %eax,%edx
  je     L58
  mov    $0x3,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L58
L23:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L6
L31:
  mov    $0x1,%edx
L58:
  mov    %edx,%eax
  ret
  nopl   (%rax)
L77:
  mov    $0xfffffffffffff753,%rax
  mov    $0x1,%edx
  bt     %rdi,%rax
  jb     L57
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7 || n == 11)
    return 1;
  if (n % 2 == 0)
    return 0;
  int i;
  for (i = 3; i * i <= n; i += 2)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isPrime>:
  endbr64
  cmp    $0xb,%edi
  jbe    L61
L39:
  xor    %edx,%edx
  test   $0x1,%dil
  je     L51
  cmp    $0x8,%edi
  jle    L3
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %edi,%edx
  sub    %eax,%edx
  je     L51
  mov    $0x3,%ecx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L51
L74:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L37
L3:
  mov    $0x1,%edx
L51:
  mov    %edx,%eax
  ret
  nopl   (%rax)
L61:
  mov    $0xfffffffffffff753,%rax
  mov    $0x1,%edx
  bt     %rdi,%rax
  jb     L39
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int n) {
  if (n == 2 || n == 3 || n == 5 || n == 7 || n == 11)
    return 1;
  if (n % 2 == 0)
    return 0;
  int i;
  for (i = 3; i * i <= n; i += 2)
    if (n % i == 0)
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<a_fetch_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <a_barrier@plt>
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <a_ll@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <a_sc@plt>
  test   %eax,%eax
  je     L4
  mov    $0x0,%eax
  call   <a_post_llsc@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int a_fetch_and(volatile int *p, int v) {
  int old;
  a_barrier();
  do
    old = a_ll(p);
  while (!a_sc(p, old & v));
  a_post_llsc();
  return old;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<a_fetch_and>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <a_barrier@plt>
L2:
  mov    %rbp,%rdi
  call   <a_ll@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  and    %r12d,%esi
  mov    %rbp,%rdi
  call   <a_sc@plt>
  test   %eax,%eax
  je     L2
  mov    $0x0,%eax
  call   <a_post_llsc@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int a_fetch_and(volatile int *p, int v) {
  int old;
  a_barrier();
  do
    old = a_ll(p);
  while (!a_sc(p, old & v));
  a_post_llsc();
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<a_fetch_and>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <a_barrier@plt>
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdi
  call   <a_ll@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  and    %ebp,%esi
  call   <a_sc@plt>
  test   %eax,%eax
  je     L0
  xor    %eax,%eax
  call   <a_post_llsc@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int a_fetch_and(volatile int *p, int v) {
  int old;
  a_barrier();
  do
    old = a_ll(p);
  while (!a_sc(p, old & v));
  a_post_llsc();
  return old;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a_fetch_and>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <a_barrier@plt>
  nopl   0x0(%rax)
L4:
  mov    %rbx,%rdi
  call   <a_ll@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  mov    %eax,%r12d
  and    %ebp,%esi
  call   <a_sc@plt>
  test   %eax,%eax
  je     L4
  xor    %eax,%eax
  call   <a_post_llsc@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int a_fetch_and(volatile int *p, int v) {
  int old;
  a_barrier();
  do
    old = a_ll(p);
  while (!a_sc(p, old & v));
  a_post_llsc();
  return old;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PtsCmpRangeClosedOpen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <PtsCmp@plt>
  test   %rax,%rax
  jns    L23
  mov    $0xffffffff,%eax
  jmp    L16
L23:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <PtsCmp@plt>
  test   %rax,%rax
  js     L22
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <PtsCmp@plt>
  test   %rax,%rax
  jns    L22
  mov    $0x0,%eax
  jmp    L16
L22:
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int PtsCmpRangeClosedOpen(int64_t x, int64_t y1, int64_t y2) {
  if (PtsCmp(x, y1) < 0)
    return -1;
  else if ((PtsCmp(x, y1) >= 0) && (PtsCmp(x, y2) < 0))
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PtsCmpRangeClosedOpen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <PtsCmp@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  js     L0
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <PtsCmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  js     L0
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <PtsCmp@plt>
  not    %rax
  shr    $0x3f,%rax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int PtsCmpRangeClosedOpen(int64_t x, int64_t y1, int64_t y2) {
  if (PtsCmp(x, y1) < 0)
    return -1;
  else if ((PtsCmp(x, y1) >= 0) && (PtsCmp(x, y2) < 0))
    return 0;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<PtsCmpRangeClosedOpen>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <PtsCmp@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  js     L11
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <PtsCmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L11
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <PtsCmp@plt>
  not    %rax
  shr    $0x3f,%rax
L11:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int PtsCmpRangeClosedOpen(int64_t x, int64_t y1, int64_t y2) {
  if (PtsCmp(x, y1) < 0)
    return -1;
  else if ((PtsCmp(x, y1) >= 0) && (PtsCmp(x, y2) < 0))
    return 0;
  else
    return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PtsCmpRangeClosedOpen>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  call   <PtsCmp@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  js     L2
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <PtsCmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L2
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <PtsCmp@plt>
  not    %rax
  shr    $0x3f,%rax
L2:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int PtsCmpRangeClosedOpen(int64_t x, int64_t y1, int64_t y2) {
  if (PtsCmp(x, y1) < 0)
    return -1;
  else if ((PtsCmp(x, y1) >= 0) && (PtsCmp(x, y2) < 0))
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<s_copy_pmat_lo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9d,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L22:
  mov    -0x24(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L65
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L65:
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L56:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L55
  movl   $0x0,-0x4(%rbp)
L55:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L17
L39:
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   -0x34(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  add    %eax,%ecx
  mov    -0x10(%rbp),%eax
  imul   -0x38(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L39
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L56
  mov    -0x28(%rbp),%eax
  add    %eax,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s_copy_pmat_lo(int row, int bs, float *A, int sda, float *B, int sdb) {
  int i, ii, j, row2, row0;
  for (ii = 0; ii < row; ii += bs) {
    row2 = row - ii;
    if (bs < row2)
      row2 = bs;
    for (j = 0; j < ii + row2; j++) {
      row0 = j - ii;
      if (row0 < 0)
        row0 = 0;
      for (i = row0; i < row2; i++) {
        B[i + j * bs + ii * sdb] = A[i + j * bs + ii * sda];
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<s_copy_pmat_lo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x4(%rsp)
  test   %edi,%edi
  jle    L52
  mov    %esi,%r10d
  mov    %rdx,%rbx
  mov    %ecx,%edx
  mov    %r8,%rbp
  mov    %r9d,%eax
  mov    %edi,%r13d
  imul   %esi,%edx
  mov    %edx,-0xc(%rsp)
  imul   %esi,%eax
  mov    %eax,-0x8(%rsp)
  mov    $0x0,%r15d
  movl   $0x0,-0x10(%rsp)
  mov    $0x0,%r14d
  mov    $0x0,%r12d
L39:
  cmp    %r10d,%r13d
  mov    %r10d,%edx
  cmovle %r13d,%edx
  lea    (%rdx,%r12,1),%eax
  test   %eax,%eax
  jle    L26
  mov    %r14d,%edi
  mov    $0x0,%r8d
  movslq -0x10(%rsp),%r11
  movslq %r15d,%r9
L53:
  test   %edi,%edi
  mov    $0x0,%eax
  cmovns %edi,%eax
  cmp    %eax,%edx
  jle    L6
  cltq
  movslq %r8d,%rcx
  lea    (%r11,%rcx,1),%rsi
  lea    (%rbx,%rsi,4),%rsi
  add    %r9,%rcx
  lea    0x0(%rbp,%rcx,4),%rcx
L58:
  movss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L58
L6:
  add    $0x1,%edi
  add    %r10d,%r8d
  cmp    %edx,%edi
  jne    L53
L26:
  add    %r10d,%r12d
  sub    %r10d,%r13d
  sub    %r10d,%r14d
  mov    -0xc(%rsp),%edi
  add    %edi,-0x10(%rsp)
  add    -0x8(%rsp),%r15d
  cmp    %r12d,-0x4(%rsp)
  jg     L39
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void s_copy_pmat_lo(int row, int bs, float *A, int sda, float *B, int sdb) {
  int i, ii, j, row2, row0;
  for (ii = 0; ii < row; ii += bs) {
    row2 = row - ii;
    if (bs < row2)
      row2 = bs;
    for (j = 0; j < ii + row2; j++) {
      row0 = j - ii;
      if (row0 < 0)
        row0 = 0;
      for (i = row0; i < row2; i++) {
        B[i + j * bs + ii * sdb] = A[i + j * bs + ii * sda];
      }
    }
  }
}
```