ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd_nrf8001_decode_data_ack_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  je     L9
  mov    $0x0,%eax
  call   <fd_nrf8001_error@plt>
  jmp    L14
L9:
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fd_nrf8001_data_ack_event@plt>
L14:
  leave
  ret
```

assistant: ```c
void fd_nrf8001_decode_data_ack_event(uint8_t *buffer, uint32_t length) {
  if (length != 2) {
    fd_nrf8001_error();
    return;
  }
  uint8_t service_pipe_number = buffer[1];
  fd_nrf8001_data_ack_event(service_pipe_number);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fd_nrf8001_decode_data_ack_event>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%esi
  je     L3
  mov    $0x0,%eax
  call   <fd_nrf8001_error@plt>
L12:
  add    $0x8,%rsp
  ret
L3:
  mov    0x4(%rdi),%edi
  call   <fd_nrf8001_data_ack_event@plt>
  jmp    L12
```

assistant: ```c
void fd_nrf8001_decode_data_ack_event(uint8_t *buffer, uint32_t length) {
  if (length != 2) {
    fd_nrf8001_error();
    return;
  }
  uint8_t service_pipe_number = buffer[1];
  fd_nrf8001_data_ack_event(service_pipe_number);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fd_nrf8001_decode_data_ack_event>:
  endbr64
  cmp    $0x2,%esi
  je     L9
  xor    %eax,%eax
  jmp    1070 <fd_nrf8001_error@plt>
L9:
  mov    0x4(%rdi),%edi
  jmp    1060 <fd_nrf8001_data_ack_event@plt>
```

assistant: ```c
void fd_nrf8001_decode_data_ack_event(uint8_t *buffer, uint32_t length) {
  if (length != 2) {
    fd_nrf8001_error();
    return;
  }
  uint8_t service_pipe_number = buffer[1];
  fd_nrf8001_data_ack_event(service_pipe_number);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fd_nrf8001_decode_data_ack_event>:
  endbr64
  cmp    $0x2,%esi
  je     L8
  xor    %eax,%eax
  jmp    1070 <fd_nrf8001_error@plt>
L8:
  mov    0x4(%rdi),%edi
  jmp    1060 <fd_nrf8001_data_ack_event@plt>
```

assistant: ```c
void fd_nrf8001_decode_data_ack_event(uint8_t *buffer, uint32_t length) {
  if (length != 2) {
    fd_nrf8001_error();
    return;
  }
  uint8_t service_pipe_number = buffer[1];
  fd_nrf8001_data_ack_event(service_pipe_number);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L21
L29:
  mov    $0x0,%eax
L21:
  leave
  ret
```

assistant: ```c
int endswith(const char *line, char c) {
  int len = strlen(line);
  return (len && line[len - 1] == c);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<endswith>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  test   %eax,%eax
  je     L8
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int endswith(const char *line, char c) {
  int len = strlen(line);
  return (len && line[len - 1] == c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L9
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int endswith(const char *line, char c) {
  int len = strlen(line);
  return (len && line[len - 1] == c);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<endswith>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L1
  cltq
  cmp    %bpl,-0x1(%rbx,%rax,1)
  sete   %al
  movzbl %al,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int endswith(const char *line, char c) {
  int len = strlen(line);
  return (len && line[len - 1] == c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strnew@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  cmp    %eax,-0x1c(%rbp)
  jbe    L16
L14:
  mov    $0x0,%eax
  jmp    L13
L16:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ft_strncpy@plt>
L13:
  leave
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *str;
  str = ft_strnew(len);
  if (!str || !s || ft_strlen(s) < start)
    return (NULL);
  return (ft_strncpy(str, s + start, len));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strsub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r13
  mov    %rdx,%rdi
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L28
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L28
  mov    %rbx,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %ebp,%edx
  jb     L11
  mov    %ebp,%ebp
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <ft_strncpy@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    $0x0,%eax
  jmp    L11
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *str;
  str = ft_strnew(len);
  if (!str || !s || ft_strlen(s) < start)
    return (NULL);
  return (ft_strncpy(str, s + start, len));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strsub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L10
  test   %rbx,%rbx
  je     L10
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <ft_strlen@plt>
  cmp    %ebp,%eax
  jb     L10
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <ft_strncpy@plt>
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *str;
  str = ft_strnew(len);
  if (!str || !s || ft_strlen(s) < start)
    return (NULL);
  return (ft_strncpy(str, s + start, len));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strsub>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <ft_strnew@plt>
  test   %rax,%rax
  je     L6
  test   %rbx,%rbx
  je     L6
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <ft_strlen@plt>
  cmp    %ebp,%eax
  jb     L6
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <ft_strncpy@plt>
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strsub(char const *s, unsigned int start, size_t len) {
  char *str;
  str = ft_strnew(len);
  if (!str || !s || ft_strlen(s) < start)
    return (NULL);
  return (ft_strncpy(str, s + start, len));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L2
L1:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x9,%eax
  jle    L19
  mov    -0x18(%rbp),%eax
  cmp    $0x14,%eax
  jg     L19
  addl   $0x1,-0x14(%rbp)
  jmp    L28
L19:
  addl   $0x1,-0x10(%rbp)
L28:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L1
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string

tool: D13: %d

tool: D15: %d in
%d out


assistant: ```c
int main(void) {
  int x, in = 0, out = 0, i, valor;
  scanf("%d", &x);
  for (i = 1; i <= x; i++) {
    scanf("%d", &valor);
    if (valor >= 10 && valor <= 20) {
      in++;
    } else {
      out++;
    }
  }
  printf("%d in\n%d out\n", in, out);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L21
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D28(%rip),%r13
  jmp    L43
L10:
  add    $0x1,%r12d
L20:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L39
L43:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0xa,%eax
  cmp    $0xa,%eax
  ja     L10
  add    $0x1,%ebp
  jmp    L20
L21:
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L39:
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D28: %d

tool: D6: %d in
%d out


assistant: ```c
int main(void) {
  int x, in = 0, out = 0, i, valor;
  scanf("%d", &x);
  for (i = 1; i <= x; i++) {
    scanf("%d", &valor);
    if (valor >= 10 && valor <= 20) {
      in++;
    } else {
      out++;
    }
  }
  printf("%d in\n%d out\n", in, out);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L11
  mov    $0x1,%ebx
  xor    %r13d,%r13d
  lea    0x4(%rsp),%r14
  xor    %r12d,%r12d
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%r12d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L3
L53:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0xa,%eax
  cmp    $0xa,%eax
  jbe    L43
  add    $0x1,%r13d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L53
L3:
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L3
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D14: %d

tool: D1: %d in
%d out


assistant: ```c
int main(void) {
  int x, in = 0, out = 0, i, valor;
  scanf("%d", &x);
  for (i = 1; i <= x; i++) {
    scanf("%d", &valor);
    if (valor >= 10 && valor <= 20) {
      in++;
    } else {
      out++;
    }
  }
  printf("%d in\n%d out\n", in, out);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L69
  mov    $0x1,%ebx
  xor    %r13d,%r13d
  lea    0x4(%rsp),%r14
  xor    %r12d,%r12d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%r12d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L1
L30:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0xa,%eax
  cmp    $0xa,%eax
  jbe    L38
  add    $0x1,%r13d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L30
L1:
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L69:
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L1
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D17: %d

tool: D2: %d in
%d out


assistant: ```c
int main(void) {
  int x, in = 0, out = 0, i, valor;
  scanf("%d", &x);
  for (i = 1; i <= x; i++) {
    scanf("%d", &valor);
    if (valor >= 10 && valor <= 20) {
      in++;
    } else {
      out++;
    }
  }
  printf("%d in\n%d out\n", in, out);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hilbert_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L8
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hilbert_left@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setheading@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hilbert_right>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x5a,%edi
  call   <turnleft@plt>
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hilbert_right>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hilbert_left@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setheading@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void hilbert_right(int len, int level) {
  int bearing;
  if (level > 0) {
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
    forwd(len);
    bearing = heading();
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnleft(90);
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hilbert_right>:
  endbr64
  test   %esi,%esi
  jg     L2
  ret
L2:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,%r12d
  mov    $0x5a,%edi
  call   <turnright@plt>
  sub    $0x1,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <hilbert_left@plt>
  mov    %r12d,%edi
  call   <setheading@plt>
  mov    %ebp,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,%r12d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <hilbert_right>
  mov    %r12d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %ebp,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,%r12d
  mov    $0x5a,%edi
  call   <turnleft@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <hilbert_right>
  mov    %r12d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %ebp,%edi
  call   <forwd@plt>
  mov    $0x0,%eax
  call   <heading@plt>
  mov    %eax,%r12d
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <hilbert_left@plt>
  mov    %r12d,%edi
  call   <setheading@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void hilbert_right(int len, int level) {
  int bearing;
  if (level > 0) {
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
    forwd(len);
    bearing = heading();
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnleft(90);
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hilbert_right>:
  endbr64
  test   %esi,%esi
  jg     L1
  ret
  nopl   0x0(%rax)
L1:
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x1,%ebp
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnright@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <hilbert_left@plt>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <hilbert_right>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnleft@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <hilbert_right>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnright@plt>
  mov    %r12d,%edi
  mov    %ebp,%esi
  call   <hilbert_left@plt>
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  pop    %r13
  jmp    10b0 <setheading@plt>
```

assistant: ```c
void hilbert_right(int len, int level) {
  int bearing;
  if (level > 0) {
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
    forwd(len);
    bearing = heading();
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnleft(90);
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hilbert_right>:
  endbr64
  test   %esi,%esi
  jg     L7
  ret
  nopl   0x0(%rax)
L7:
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x1,%ebp
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnright@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <hilbert_left@plt>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r13d
  call   <hilbert_right>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnleft@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <hilbert_right>
  mov    %r13d,%edi
  call   <setheading@plt>
  mov    $0x5a,%edi
  call   <turnright@plt>
  mov    %r12d,%edi
  call   <forwd@plt>
  xor    %eax,%eax
  call   <heading@plt>
  mov    $0x5a,%edi
  mov    %eax,%r13d
  call   <turnright@plt>
  mov    %r12d,%edi
  mov    %ebp,%esi
  call   <hilbert_left@plt>
  pop    %rbp
  mov    %r13d,%edi
  pop    %r12
  pop    %r13
  jmp    10b0 <setheading@plt>
```

assistant: ```c
void hilbert_right(int len, int level) {
  int bearing;
  if (level > 0) {
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
    forwd(len);
    bearing = heading();
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnleft(90);
    hilbert_right(len, level - 1);
    setheading(bearing);
    turnright(90);
    forwd(len);
    bearing = heading();
    turnright(90);
    hilbert_left(len, level - 1);
    setheading(bearing);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x2,%edi
  call   <f@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int g(int *f1) {
  f(2);
  return *f1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <f@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int g(int *f1) {
  f(2);
  return *f1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <f@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int g(int *f1) {
  f(2);
  return *f1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <f@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
int g(int *f1) {
  f(2);
  return *f1;
}
```