user: 这段汇编代码用C语言表示是什么样的？

```asm
<rob3>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x10(%rsp)
  test   %esi,%esi
  jle    L91
  movslq %esi,%rax
  mov    %rdi,%rbx
  lea    0x0(,%rsi,8),%edi
  mov    %esi,%r15d
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r15d,%eax
  mov    %rax,(%rsp)
  mov    %rbp,%r15
  lea    -0x1(%rax),%r13d
  lea    0x0(%rbp,%rax,8),%r12
  lea    0x0(,%rax,4),%r14d
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r14d,%edi
  add    $0x8,%r15
  call   <malloc@plt>
  mov    %rax,-0x8(%r15)
  cmp    %r12,%r15
  jne    L2
  mov    (%rsp),%r12
  xor    %eax,%eax
  shl    $0x2,%r12
  nop
L117:
  mov    (%rbx,%rax,1),%ecx
  mov    0x0(%rbp,%rax,2),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L117
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L116
  add    $0x1,%eax
  movl   $0x2,(%rsp)
  mov    %eax,0x14(%rsp)
  movq   $0x4,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L94:
  mov    (%rsp),%edi
  cmp    %edi,0x10(%rsp)
  js     L146
  mov    %edi,%eax
  mov    0x8(%rsp),%r10
  lea    -0x1(%rdi),%edi
  xor    %r12d,%r12d
  lea    -0x2(%rax),%esi
  xor    %r11d,%r11d
L32:
  mov    D5(%rip),%rax
  mov    0x0(%rbp,%r12,8),%r8
  mov    (%rax),%ecx
  lea    (%r8,%r10,1),%r9
  mov    %r11d,%eax
  add    $0x1,%r11d
  mov    %ecx,(%r9)
  cmp    %edi,%r12d
  jg     L150
  cmp    %r11d,%r12d
  jg     L49
  cmp    %r11d,%edi
  mov    %r11d,%r14d
  mov    %r12,%rdx
  cmovle %edi,%r14d
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%rbx,%rdx,4),%eax
  cmp    %edx,%esi
  jle    L121
  mov    0x10(%rbp,%rdx,8),%r15
  add    (%r15,%r10,1),%eax
L121:
  cmp    %ecx,%eax
  jle    L110
  mov    %eax,(%r9)
  mov    %eax,%ecx
L110:
  lea    0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    %edx,%r14d
  jge    L11
  cmp    %edi,%eax
  jg     L150
L49:
  cltq
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%rbx,%rax,4),%r15d
  mov    -0x8(%r8,%rax,4),%r14d
  lea    (%r14,%r15,1),%edx
  cmp    %eax,%esi
  jle    L140
  mov    0x10(%rbp,%rax,8),%rdx
  add    (%rdx,%r10,1),%r14d
  lea    (%r14,%r15,1),%edx
L140:
  cmp    %edx,%ecx
  jge    L80
  mov    %edx,(%r9)
  mov    %edx,%ecx
L80:
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L21
L150:
  add    $0x1,%r12
  add    $0x4,%r10
  add    $0x1,%edi
  add    $0x1,%esi
  cmp    %r13d,%r11d
  jne    L32
L146:
  addl   $0x1,(%rsp)
  sub    $0x1,%r13d
  mov    (%rsp),%eax
  addq   $0x4,0x8(%rsp)
  cmp    0x14(%rsp),%eax
  jne    L94
L116:
  mov    0x0(%rbp),%rax
  mov    0x18(%rsp),%rdi
  mov    -0x4(%rax,%rdi,4),%eax
L91:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int rob3(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int **array = malloc(sizeof(int *) * numsSize);
  for (int i = 0; i < numsSize; i++)
    array[i] = malloc(sizeof(int) * numsSize);
  for (int i = 0; i < numsSize; i++)
    array[i][i] = nums[i];
  for (int length = 2; length <= numsSize; length++) {
    for (int i = 0; i < numsSize - length + 1; i++) {
      int j = i + length - 1;
      array[i][j] = INT_MIN;
      for (int k = i; k <= j; k++) {
        int tmp = nums[k];
        if (k >= 2 + i && k <= j - 2)
          tmp += array[i][k - 2] + array[k + 2][j];
        else if (k <= j - 2)
          tmp += array[k + 2][j];
        else if (k >= 2 + i)
          tmp += array[i][k - 2];
        if (array[i][j] < tmp)
          array[i][j] = tmp;
      }
    }
  }
  return array[0][numsSize - 1];
}
```