ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  cmpl   $0x2,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int two;
  int equals_two;
  two = 2;
  equals_two = (two == 2);
  assert((equals_two != 0));
  assert((equals_two == 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int two;
  int equals_two;
  two = 2;
  equals_two = (two == 2);
  assert((equals_two != 0));
  assert((equals_two == 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int two;
  int equals_two;
  two = 2;
  equals_two = (two == 2);
  assert((equals_two != 0));
  assert((equals_two == 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int two;
  int equals_two;
  two = 2;
  equals_two = (two == 2);
  assert((equals_two != 0));
  assert((equals_two == 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_int_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rdx
  mov    %rsi,%rax
  mov    (%rdx),%r12d
  mov    (%rax),%ebx
  cmp    %ebx,%r12d
  jge    L17
  mov    $0xffffffff,%eax
  jmp    L2
L17:
  cmp    %ebx,%r12d
  jne    L9
  mov    $0x0,%eax
  jmp    L2
L9:
  mov    $0x1,%eax
L2:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  register int key1_v = *((int *)key1);
  register int key2_v = *((int *)key2);
  if (key1_v < key2_v)
    return -1;
  else if (key1_v == key2_v)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare_int_keys>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L2
  setne  %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  register int key1_v = *((int *)key1);
  register int key2_v = *((int *)key2);
  if (key1_v < key2_v)
    return -1;
  else if (key1_v == key2_v)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare_int_keys>:
  endbr64
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,(%rdi)
  jl     L7
  setne  %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  register int key1_v = *((int *)key1);
  register int key2_v = *((int *)key2);
  if (key1_v < key2_v)
    return -1;
  else if (key1_v == key2_v)
    return 0;
  else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<compare_int_keys>:
  endbr64
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,(%rdi)
  jl     L1
  setne  %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  register int key1_v = *((int *)key1);
  register int key2_v = *((int *)key2);
  if (key1_v < key2_v)
    return -1;
  else if (key1_v == key2_v)
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<int_comparator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <compare_ints@plt>
  leave
  ret
```

assistant: ```c
int int_comparator(const void *vs_a, const void *vs_b, void *context) {
  int a = *((int *)vs_a);
  int b = *((int *)vs_b);
  int descending = *((int *)context);
  return compare_ints(a, b, descending);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_comparator>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <compare_ints@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int int_comparator(const void *vs_a, const void *vs_b, void *context) {
  int a = *((int *)vs_a);
  int b = *((int *)vs_b);
  int descending = *((int *)context);
  return compare_ints(a, b, descending);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_comparator>:
  endbr64
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  jmp    1050 <compare_ints@plt>
```

assistant: ```c
int int_comparator(const void *vs_a, const void *vs_b, void *context) {
  int a = *((int *)vs_a);
  int b = *((int *)vs_b);
  int descending = *((int *)context);
  return compare_ints(a, b, descending);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<int_comparator>:
  endbr64
  mov    (%rdx),%edx
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  jmp    1050 <compare_ints@plt>
```

assistant: ```c
int int_comparator(const void *vs_a, const void *vs_b, void *context) {
  int a = *((int *)vs_a);
  int b = *((int *)vs_b);
  int descending = *((int *)context);
  return compare_ints(a, b, descending);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <initialize@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <mid_ellipse@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <print@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  initialize(100, 100);
  mid_ellipse(20, 20, 7, 3);
  print(100, 100);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <initialize@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <mid_ellipse@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initialize(100, 100);
  mid_ellipse(20, 20, 7, 3);
  print(100, 100);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <initialize@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <mid_ellipse@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initialize(100, 100);
  mid_ellipse(20, 20, 7, 3);
  print(100, 100);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <initialize@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x14,%esi
  mov    $0x14,%edi
  call   <mid_ellipse@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  initialize(100, 100);
  mid_ellipse(20, 20, 7, 3);
  print(100, 100);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_full_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L14
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_full_name(char *path) {
  char *fullname;
  char *full_name_iter;
  char *path_iter;
  char *last_slash = strrchr(path, '/');
  fullname = calloc(strlen(path) - (last_slash - path) + 1, sizeof(char));
  full_name_iter = fullname;
  path_iter = last_slash + 1;
  while (*path_iter != '\0') {
    *full_name_iter = *path_iter;
    full_name_iter++;
    path_iter++;
  }
  *full_name_iter = '\0';
  return fullname;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_full_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    %eax,%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  movzbl 0x1(%rbx),%edx
  test   %dl,%dl
  je     L18
  lea    0x1(%rbx),%rsi
  mov    %rax,%rcx
L29:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L29
L14:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %rax,%rcx
  jmp    L14
```

assistant: ```c
char *get_full_name(char *path) {
  char *fullname;
  char *full_name_iter;
  char *path_iter;
  char *last_slash = strrchr(path, '/');
  fullname = calloc(strlen(path) - (last_slash - path) + 1, sizeof(char));
  full_name_iter = fullname;
  path_iter = last_slash + 1;
  while (*path_iter != '\0') {
    *full_name_iter = *path_iter;
    full_name_iter++;
    path_iter++;
  }
  *full_name_iter = '\0';
  return fullname;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_full_name>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%edi
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    %eax,%edi
  call   <calloc@plt>
  movzbl 0x1(%rbx),%edx
  test   %dl,%dl
  je     L3
  lea    0x1(%rbx),%rsi
  mov    %rax,%rcx
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%rsi
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L12
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rax,%rcx
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *get_full_name(char *path) {
  char *fullname;
  char *full_name_iter;
  char *path_iter;
  char *last_slash = strrchr(path, '/');
  fullname = calloc(strlen(path) - (last_slash - path) + 1, sizeof(char));
  full_name_iter = fullname;
  path_iter = last_slash + 1;
  while (*path_iter != '\0') {
    *full_name_iter = *path_iter;
    full_name_iter++;
    path_iter++;
  }
  *full_name_iter = '\0';
  return fullname;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_full_name>:
  endbr64
  push   %rbp
  mov    $0x2f,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%edi
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    %eax,%edi
  call   <calloc@plt>
  movzbl 0x1(%rbx),%edx
  test   %dl,%dl
  je     L17
  lea    0x1(%rbx),%rsi
  mov    %rax,%rcx
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%rsi
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L18
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rax,%rcx
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *get_full_name(char *path) {
  char *fullname;
  char *full_name_iter;
  char *path_iter;
  char *last_slash = strrchr(path, '/');
  fullname = calloc(strlen(path) - (last_slash - path) + 1, sizeof(char));
  full_name_iter = fullname;
  path_iter = last_slash + 1;
  while (*path_iter != '\0') {
    *full_name_iter = *path_iter;
    full_name_iter++;
    path_iter++;
  }
  *full_name_iter = '\0';
  return fullname;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   -0x4(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1)
    return n;
  else
    return n * factorial(n - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<factorial>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jne    L2
L14:
  mov    %ebx,%eax
  pop    %rbx
  ret
L2:
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %eax,%ebx
  jmp    L14
```

assistant: ```c
int factorial(int n) {
  if (n == 1)
    return n;
  else
    return n * factorial(n - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L6
  xchg   %ax,%ax
L17:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L17
L6:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1)
    return n;
  else
    return n * factorial(n - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L0
  xchg   %ax,%ax
L5:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L5
L0:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n == 1)
    return n;
  else
    return n * factorial(n - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_extreme_sols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edx,%rbx
  lea    0x0(,%rbx,8),%r14
  lea    0xf(%r14),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L201:
  cmp    %rdx,%rsp
  je     L45
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L201
L45:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L175
  orq    $0x0,-0x8(%rsp,%rax,1)
L175:
  mov    %rsp,%r12
  mov    %edi,%esi
  call   <new_matrix_double@plt>
  mov    %rax,%rdi
  lea    0xf(,%rbx,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L23:
  cmp    %rcx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L31:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L97
  orq    $0x0,-0x8(%rsp,%rax,1)
L97:
  mov    %rsp,%rsi
  test   %rbx,%rbx
  je     L106
  mov    $0x0,%eax
L121:
  movq   $0x0,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L121
  movslq %r15d,%r15
  test   %r15,%r15
  je     L172
L77:
  mov    $0x0,%ecx
  jmp    L195
L136:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L94
L21:
  movsd  (%rdx,%rax,8),%xmm0
  comisd (%r12,%rax,8),%xmm0
  jbe    L136
  movsd  %xmm0,(%r12,%rax,8)
  mov    %ecx,(%rsi,%rax,4)
  jmp    L136
L94:
  add    $0x1,%rcx
  cmp    %rcx,%r15
  je     L172
L195:
  test   %rbx,%rbx
  je     L94
  mov    0x0(%r13,%rcx,8),%rdx
  mov    $0x0,%eax
  jmp    L21
L172:
  test   %rbx,%rbx
  je     L155
  mov    %rsi,%r8
  mov    %rdi,%rcx
  add    %rdi,%r14
L10:
  movslq (%r8),%rax
  lea    0x0(%r13,%rax,8),%rsi
  mov    $0x0,%eax
L72:
  mov    (%rsi),%rdx
  movsd  (%rdx,%rax,8),%xmm0
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L72
  add    $0x4,%r8
  add    $0x8,%rcx
  cmp    %rcx,%r14
  jne    L10
L155:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    %rdi,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L106:
  movslq %r15d,%r15
  test   %r15,%r15
  jne    L77
  jmp    L155
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double **get_extreme_sols(double **front, int frontlen, int vlen) {
  size_t i, j;
  double max_fit[vlen], cur_fit;
  double **extreme_sols = new_matrix_double(vlen, vlen);
  int positions[vlen];
  for (i = 0; i < vlen; i++) {
    max_fit[i] = 0;
  }
  for (i = 0; i < frontlen; i++) {
    for (j = 0; j < vlen; j++) {
      cur_fit = front[i][j];
      if (cur_fit > max_fit[j]) {
        max_fit[j] = cur_fit;
        positions[j] = i;
      }
    }
  }
  for (i = 0; i < vlen; i++) {
    for (j = 0; j < vlen; j++) {
      extreme_sols[i][j] = front[positions[i]][j];
    }
  }
  return (extreme_sols);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L23:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D34
data_type: string
name: read_data
arguments: tag: D35
data_type: string
name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D21
data_type: string

tool: D34: Kacinci eleman bulunacak?

tool: D35: %d

tool: D12: %d
%d


tool: D21: %d


assistant: ```c
int main() {
  int n, aktif = 1, aktif1 = 1;
  printf("Kacinci eleman bulunacak?\n");
  scanf("%d", &n);
  printf("%d\n%d\n", aktif, aktif1);
  int sonuc;
  for (int i = 0; i < n - 2; i++) {
    sonuc = aktif + aktif1;
    printf("%d\n", sonuc);
    aktif = aktif1;
    aktif1 = sonuc;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2,0x4(%rsp)
  jle    L5
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  mov    $0x1,%edx
  lea    D27(%rip),%r13
L17:
  mov    %ebx,%r12d
  add    %edx,%ebx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  mov    %r12d,%edx
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    %ebp,%eax
  jg     L17
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D35
type: string
name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D27
type: string

tool: D35: Kacinci eleman bulunacak?

tool: D24: %d

tool: D25: %d
%d


tool: D27: %d


assistant: ```c
int main() {
  int n, aktif = 1, aktif1 = 1;
  printf("Kacinci eleman bulunacak?\n");
  scanf("%d", &n);
  printf("%d\n%d\n", aktif, aktif1);
  int sonuc;
  for (int i = 0; i < n - 2; i++) {
    sonuc = aktif + aktif1;
    printf("%d\n", sonuc);
    aktif = aktif1;
    aktif1 = sonuc;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  xor    %eax,%eax
  mov    $0x1,%edx
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x2,0x4(%rsp)
  jle    L14
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  mov    $0x1,%edx
  lea    D29(%rip),%r13
  nopl   (%rax)
L11:
  mov    %ebx,%r12d
  add    %edx,%ebx
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %r12d,%edx
  sub    $0x2,%eax
  cmp    %ebp,%eax
  jg     L11
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string
name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D29
datatype: string

tool: D2: Kacinci eleman bulunacak?

tool: D24: %d

tool: D8: %d
%d


tool: D29: %d


assistant: ```c
int main() {
  int n, aktif = 1, aktif1 = 1;
  printf("Kacinci eleman bulunacak?\n");
  scanf("%d", &n);
  printf("%d\n%d\n", aktif, aktif1);
  int sonuc;
  for (int i = 0; i < n - 2; i++) {
    sonuc = aktif + aktif1;
    printf("%d\n", sonuc);
    aktif = aktif1;
    aktif1 = sonuc;
  }
  return 0;
}
```