ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_prop_picstyle_from_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  ja     L64
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D21(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D21(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x81,%eax
  jmp    L31
  mov    $0x82,%eax
  jmp    L31
  mov    $0x83,%eax
  jmp    L31
  mov    $0x84,%eax
  jmp    L31
  mov    $0x85,%eax
  jmp    L31
  mov    $0x86,%eax
  jmp    L31
  mov    $0x21,%eax
  jmp    L31
  mov    $0x22,%eax
  jmp    L31
  mov    $0x23,%eax
  jmp    L31
L64:
  mov    -0x4(%rbp),%eax
  mov    %eax,%r8d
  lea    D2(%rip),%rax
  mov    %rax,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x40000,%edi
  call   <bmp_printf@plt>
  mov    $0x0,%eax
L31:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: unk picstyle index: %x

assistant: ```c
int get_prop_picstyle_from_index(int index) {
  switch (index) {
  case 1:
    return 0x81;
  case 2:
    return 0x82;
  case 3:
    return 0x83;
  case 4:
    return 0x84;
  case 5:
    return 0x85;
  case 6:
    return 0x86;
  case 7:
    return 0x21;
  case 8:
    return 0x22;
  case 9:
    return 0x23;
  }
  bmp_printf((0 | (((4) << 16) & (0xFFFF0000)) | ((0) & 0xFF) << 8 | ((0) & 0xFF) << 0), 0, 0, "unk picstyle index: %x", index);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_prop_picstyle_from_index>:
  endbr64
  cmp    $0x9,%edi
  ja     L9
  mov    %edi,%eax
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x82,%eax
  ret
  mov    $0x83,%eax
  ret
  mov    $0x84,%eax
  ret
  mov    $0x85,%eax
  ret
  mov    $0x86,%eax
  ret
  mov    $0x21,%eax
  ret
  mov    $0x22,%eax
  ret
  mov    $0x23,%eax
  ret
L9:
  sub    $0x8,%rsp
  mov    %edi,%r8d
  lea    D17(%rip),%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x40000,%edi
  call   <bmp_printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
  mov    $0x81,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D17: unk picstyle index: %x

assistant: ```c
int get_prop_picstyle_from_index(int index) {
  switch (index) {
  case 1:
    return 0x81;
  case 2:
    return 0x82;
  case 3:
    return 0x83;
  case 4:
    return 0x84;
  case 5:
    return 0x85;
  case 6:
    return 0x86;
  case 7:
    return 0x21;
  case 8:
    return 0x22;
  case 9:
    return 0x23;
  }
  bmp_printf((0 | (((4) << 16) & (0xFFFF0000)) | ((0) & 0xFF) << 8 | ((0) & 0xFF) << 0), 0, 0, "unk picstyle index: %x", index);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L85
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L85:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L83
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L20
L83:
  cmpq   $0x0,-0x8(%rbp)
  jne    L68
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L31
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L31:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L68:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L3
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L20
L3:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L20:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
type: string
name: unpack_data
arguments: data_label: D58
type: string
name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D47
type: string

tool: D28: error en los argumentos

tool: D58: el numero es %d


tool: D3: 
Error en el fork

tool: D27: Es divisible entre 2

tool: D0: No es divisible entre 2

tool: D12: Es divisible entre 4

tool: D47: No es divisible entre 4

assistant: ```c
int main(int argc, char *argv[]) {
  int a;
  pid_t pid;
  if (argc != 2) {
    printf("error en los argumentos");
    exit(-1);
  }
  a = strtol(argv[1], NULL, 10);
  printf("el numero es %d\n", a);
  if ((pid = fork()) < 0) {
    perror("\nError en el fork");
    exit(-1);
  } else if (pid == 0) {
    if (a % 2 == 0)
      printf("Es divisible entre 2\n");
    else
      printf("No es divisible entre 2\n");
  } else {
    sleep(1);
    if (a % 4 == 0)
      printf("Es divisible entre 4\n");
    else
      printf("No es divisible entre 4\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L60
L91:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L93
  jne    L9
  test   $0x1,%bl
  jne    L38
  lea    D60(%rip),%rdi
  call   <puts@plt>
  jmp    L31
L60:
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L91
L93:
  lea    D53(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L31:
  mov    $0x0,%eax
  pop    %rbx
  ret
L38:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  jmp    L31
L9:
  mov    $0x1,%edi
  call   <sleep@plt>
  test   $0x3,%bl
  jne    L72
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L31
L72:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  jmp    L31
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D60
type_infered: string
name: disassemble_data
arguments: tag: D34
type_infered: string
name: disassemble_data
arguments: tag: D53
type_infered: string
name: disassemble_data
arguments: tag: D42
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D36
type_infered: string

tool: D1: el numero es %d


tool: D60: Es divisible entre 2

tool: D34: error en los argumentos

tool: D53: 
Error en el fork

tool: D42: No es divisible entre 2

tool: D2: Es divisible entre 4

tool: D36: No es divisible entre 4

assistant: ```c
int main(int argc, char *argv[]) {
  int a;
  pid_t pid;
  if (argc != 2) {
    printf("error en los argumentos");
    exit(-1);
  }
  a = strtol(argv[1], NULL, 10);
  printf("el numero es %d\n", a);
  if ((pid = fork()) < 0) {
    perror("\nError en el fork");
    exit(-1);
  } else if (pid == 0) {
    if (a % 2 == 0)
      printf("Es divisible entre 2\n");
    else
      printf("No es divisible entre 2\n");
  } else {
    sleep(1);
    if (a % 4 == 0)
      printf("Es divisible entre 4\n");
    else
      printf("No es divisible entre 4\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L77
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L77:
  mov    0x8(%rbx),%rdi
  xor    %esi,%esi
  mov    $0xa,%edx
  call   <strtol@plt>
  lea    D69(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L89
  jne    L26
  and    $0x1,%bl
  jne    L73
  lea    D57(%rip),%rdi
  call   <puts@plt>
L72:
  xor    %eax,%eax
  pop    %rbx
  ret
L26:
  mov    $0x1,%edi
  call   <sleep@plt>
  and    $0x3,%bl
  jne    L87
  lea    D37(%rip),%rdi
  call   <puts@plt>
  jmp    L72
L89:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L72
L73:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  jmp    L72
L87:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  jmp    L72
```

tool_calls: name: unpack_data
arguments: label: D48
type: string
name: unpack_data
arguments: label: D69
type: string
name: unpack_data
arguments: label: D57
type: string
name: unpack_data
arguments: label: D37
type: string
name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D29
type: string

tool: D48: error en los argumentos

tool: D69: el numero es %d


tool: D57: Es divisible entre 2

tool: D37: Es divisible entre 4

tool: D5: 
Error en el fork

tool: D20: No es divisible entre 2

tool: D29: No es divisible entre 4

assistant: ```c
int main(int argc, char *argv[]) {
  int a;
  pid_t pid;
  if (argc != 2) {
    printf("error en los argumentos");
    exit(-1);
  }
  a = strtol(argv[1], NULL, 10);
  printf("el numero es %d\n", a);
  if ((pid = fork()) < 0) {
    perror("\nError en el fork");
    exit(-1);
  } else if (pid == 0) {
    if (a % 2 == 0)
      printf("Es divisible entre 2\n");
    else
      printf("No es divisible entre 2\n");
  } else {
    sleep(1);
    if (a % 4 == 0)
      printf("Es divisible entre 4\n");
    else
      printf("No es divisible entre 4\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L27
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L27:
  mov    0x8(%rbx),%rdi
  xor    %esi,%esi
  mov    $0xa,%edx
  call   <strtol@plt>
  lea    D33(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  js     L32
  jne    L80
  and    $0x1,%bl
  jne    L40
  lea    D55(%rip),%rdi
  call   <puts@plt>
L78:
  xor    %eax,%eax
  pop    %rbx
  ret
L80:
  mov    $0x1,%edi
  call   <sleep@plt>
  and    $0x3,%bl
  jne    L62
  lea    D62(%rip),%rdi
  call   <puts@plt>
  jmp    L78
L32:
  lea    D65(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L78
L40:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L78
L62:
  lea    D67(%rip),%rdi
  call   <puts@plt>
  jmp    L78
```

tool_calls: name: read_data
arguments: data_label: D48
type_guessed: string
name: read_data
arguments: data_label: D33
type_guessed: string
name: read_data
arguments: data_label: D55
type_guessed: string
name: read_data
arguments: data_label: D62
type_guessed: string
name: read_data
arguments: data_label: D65
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D67
type_guessed: string

tool: D48: error en los argumentos

tool: D33: el numero es %d


tool: D55: Es divisible entre 2

tool: D62: Es divisible entre 4

tool: D65: 
Error en el fork

tool: D15: No es divisible entre 2

tool: D67: No es divisible entre 4

assistant: ```c
int main(int argc, char *argv[]) {
  int a;
  pid_t pid;
  if (argc != 2) {
    printf("error en los argumentos");
    exit(-1);
  }
  a = strtol(argv[1], NULL, 10);
  printf("el numero es %d\n", a);
  if ((pid = fork()) < 0) {
    perror("\nError en el fork");
    exit(-1);
  } else if (pid == 0) {
    if (a % 2 == 0)
      printf("Es divisible entre 2\n");
    else
      printf("No es divisible entre 2\n");
  } else {
    sleep(1);
    if (a % 4 == 0)
      printf("Es divisible entre 4\n");
    else
      printf("No es divisible entre 4\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<opr_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double opr_sqrt(struct lifo *stack) {
  double op = pop(stack);
  return sqrt(op);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<opr_sqrt>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L6
  sqrtsd %xmm0,%xmm0
L17:
  add    $0x8,%rsp
  ret
L6:
  call   <sqrt@plt>
  jmp    L17
```

assistant: ```c
double opr_sqrt(struct lifo *stack) {
  double op = pop(stack);
  return sqrt(op);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<opr_sqrt>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L4
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L4:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double opr_sqrt(struct lifo *stack) {
  double op = pop(stack);
  return sqrt(op);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<opr_sqrt>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L2
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rsp
  ret
L2:
  pop    %rax
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double opr_sqrt(struct lifo *stack) {
  double op = pop(stack);
  return sqrt(op);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L15
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  jmp    L2
L15:
  nop
L2:
  leave
  ret
```

assistant: ```c
void quick_sort(int *a, int p, int q) {
  if (p >= q)
    return;
  int m = partition(a, p, q);
  quick_sort(a, p, m - 1);
  quick_sort(a, m + 1, q);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quick_sort(int *a, int p, int q) {
  if (p >= q)
    return;
  int m = partition(a, p, q);
  quick_sort(a, p, m - 1);
  quick_sort(a, m + 1, q);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_pageins>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x4,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <sysctlbyname@plt>
  test   %rax,%rax
  je     L12
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  jmp    L5
L12:
  mov    -0x14(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string

tool: D15: vm.stats.vm.v_swappgsin

tool: D12: v_swappgsin

assistant: ```c
u_int get_pageins() {
  u_int pageins;
  size_t len;
  len = sizeof(pageins);
  if (sysctlbyname("vm.stats.vm.v_swappgsin", &pageins, &len, NULL, 0) != 0) {
    warnx("v_swappgsin");
    return (0);
  }
  return pageins;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_pageins>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x4,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D18(%rip),%rdi
  call   <sysctlbyname@plt>
  mov    %rax,%rdx
  mov    0xc(%rsp),%eax
  test   %rdx,%rdx
  jne    L28
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  ret
L28:
  lea    D4(%rip),%rdi
  call   <warnx@plt>
  mov    $0x0,%eax
  jmp    L24
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D18: vm.stats.vm.v_swappgsin

tool: D4: v_swappgsin

assistant: ```c
u_int get_pageins() {
  u_int pageins;
  size_t len;
  len = sizeof(pageins);
  if (sysctlbyname("vm.stats.vm.v_swappgsin", &pageins, &len, NULL, 0) != 0) {
    warnx("v_swappgsin");
    return (0);
  }
  return pageins;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_pageins>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  lea    D1(%rip),%rdi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0x4,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %rax,%r8
  mov    0xc(%rsp),%eax
  test   %r8,%r8
  jne    L24
L7:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L24:
  lea    D17(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  jmp    L7
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D1: vm.stats.vm.v_swappgsin

tool: D17: v_swappgsin

assistant: ```c
u_int get_pageins() {
  u_int pageins;
  size_t len;
  len = sizeof(pageins);
  if (sysctlbyname("vm.stats.vm.v_swappgsin", &pageins, &len, NULL, 0) != 0) {
    warnx("v_swappgsin");
    return (0);
  }
  return pageins;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_pageins>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  lea    D1(%rip),%rdi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0x4,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %rax,%r8
  mov    0xc(%rsp),%eax
  test   %r8,%r8
  jne    L12
L18:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L12:
  lea    D3(%rip),%rdi
  call   <warnx@plt>
  xor    %eax,%eax
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D1: vm.stats.vm.v_swappgsin

tool: D3: v_swappgsin

assistant: ```c
u_int get_pageins() {
  u_int pageins;
  size_t len;
  len = sizeof(pageins);
  if (sysctlbyname("vm.stats.vm.v_swappgsin", &pageins, &len, NULL, 0) != 0) {
    warnx("v_swappgsin");
    return (0);
  }
  return pageins;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_flag_names>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L44
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L44
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L85
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L26
  cmpl   $0x0,-0x1c(%rbp)
  je     L26
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
L85:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <parse_flag_name@plt>
  or     %eax,-0xc(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L43
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L66:
  addq   $0x1,-0x8(%rbp)
  jmp    L11
L43:
  nop
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t parse_flag_names(const char *str, int all) {
  const char *p = str;
  uint64_t flags = 0;
  while (1) {
    if (*p == ',' || *p == '=' || *p == '\0') {
      if ((*str != '~') || (*str == '~' && all && *++str))
        flags |= parse_flag_name(str, p - str);
      if (*p != ',')
        break;
      str = p + 1;
    }
    p++;
  }
  return flags;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_flag_names>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  movabs $0x2000100000000001,%r12
  jmp    L39
L79:
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <parse_flag_name@plt>
  or     %eax,%ebp
L23:
  cmpb   $0x2c,(%rbx)
  jne    L14
  lea    0x1(%rbx),%rdi
L52:
  add    $0x1,%rbx
L39:
  movzbl (%rbx),%eax
  cmp    $0x3d,%al
  ja     L52
  bt     %rax,%r12
  jae    L52
  cmpb   $0x7e,(%rdi)
  jne    L79
  test   %r13d,%r13d
  je     L23
  cmpb   $0x0,0x1(%rdi)
  je     L23
  add    $0x1,%rdi
  jmp    L79
L14:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t parse_flag_names(const char *str, int all) {
  const char *p = str;
  uint64_t flags = 0;
  while (1) {
    if (*p == ',' || *p == '=' || *p == '\0') {
      if ((*str != '~') || (*str == '~' && all && *++str))
        flags |= parse_flag_name(str, p - str);
      if (*p != ',')
        break;
      str = p + 1;
    }
    p++;
  }
  return flags;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_flag_names>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  movabs $0xdfffeffffffffffe,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%edx
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L26:
  movzbl (%rbx),%edx
  mov    %rbx,%rdi
L68:
  add    $0x1,%rbx
L27:
  movzbl -0x1(%rbx),%eax
  lea    -0x1(%rbx),%rsi
  cmp    $0x3d,%al
  ja     L68
  bt     %rax,%r12
  jb     L68
  cmp    $0x7e,%dl
  jne    L36
  test   %ebp,%ebp
  je     L21
  cmpb   $0x0,0x1(%rdi)
  je     L21
  add    $0x1,%rdi
L36:
  sub    %edi,%esi
  call   <parse_flag_name@plt>
  or     %eax,%r13d
  movzbl -0x1(%rbx),%eax
L21:
  cmp    $0x2c,%al
  je     L26
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint64_t parse_flag_names(const char *str, int all) {
  const char *p = str;
  uint64_t flags = 0;
  while (1) {
    if (*p == ',' || *p == '=' || *p == '\0') {
      if ((*str != '~') || (*str == '~' && all && *++str))
        flags |= parse_flag_name(str, p - str);
      if (*p != ',')
        break;
      str = p + 1;
    }
    p++;
  }
  return flags;
}
```