ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bb_alb_modis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  %xmm6,-0x48(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D43(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  -0x38(%rbp),%xmm2
  movsd  D46(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm2
  movsd  D36(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm2
  movsd  D19(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D43
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D46
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: f64

tool: D19: 0.22831

tool: D43: 0.15982

tool: D46: 0.09132

tool: D36: 0.10959

assistant: ```c
double bb_alb_modis(double redchan, double nirchan, double chan3, double chan4, double chan5, double chan6, double chan7) {
  double result;
  result = (0.22831 * redchan + 0.15982 * nirchan + 0.09132 * (chan3 + chan4 + chan5) + 0.10959 * chan6 + 0.22831 * chan7);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bb_alb_modis>:
  endbr64
  movsd  D37(%rip),%xmm7
  mulsd  %xmm7,%xmm0
  mulsd  D19(%rip),%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm2
  mulsd  D5(%rip),%xmm2
  addsd  %xmm2,%xmm0
  mulsd  D2(%rip),%xmm5
  addsd  %xmm5,%xmm0
  mulsd  %xmm7,%xmm6
  addsd  %xmm6,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D37
data_type: f64
name: read_data
arguments: data_tag: D19
data_type: f64
name: read_data
arguments: data_tag: D5
data_type: f64
name: read_data
arguments: data_tag: D2
data_type: f64

tool: D37: 0.22831

tool: D19: 0.15982

tool: D5: 0.09132

tool: D2: 0.10959

assistant: ```c
double bb_alb_modis(double redchan, double nirchan, double chan3, double chan4, double chan5, double chan6, double chan7) {
  double result;
  result = (0.22831 * redchan + 0.15982 * nirchan + 0.09132 * (chan3 + chan4 + chan5) + 0.10959 * chan6 + 0.22831 * chan7);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bb_alb_modis>:
  endbr64
  movsd  D28(%rip),%xmm7
  mulsd  D36(%rip),%xmm1
  addsd  %xmm3,%xmm2
  mulsd  D8(%rip),%xmm5
  mulsd  %xmm7,%xmm0
  addsd  %xmm4,%xmm2
  mulsd  D10(%rip),%xmm2
  mulsd  %xmm7,%xmm6
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
data_type: f64
name: unpack_data
arguments: tag: D36
data_type: f64
name: unpack_data
arguments: tag: D8
data_type: f64
name: unpack_data
arguments: tag: D10
data_type: f64

tool: D28: 0.22831

tool: D36: 0.15982

tool: D8: 0.10959

tool: D10: 0.09132

assistant: ```c
double bb_alb_modis(double redchan, double nirchan, double chan3, double chan4, double chan5, double chan6, double chan7) {
  double result;
  result = (0.22831 * redchan + 0.15982 * nirchan + 0.09132 * (chan3 + chan4 + chan5) + 0.10959 * chan6 + 0.22831 * chan7);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bb_alb_modis>:
  endbr64
  movsd  D4(%rip),%xmm7
  mulsd  D6(%rip),%xmm1
  addsd  %xmm3,%xmm2
  mulsd  D39(%rip),%xmm5
  mulsd  %xmm7,%xmm0
  addsd  %xmm4,%xmm2
  mulsd  D28(%rip),%xmm2
  mulsd  %xmm7,%xmm6
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: f64
name: disassemble_data
arguments: label: D6
type_guessed: f64
name: disassemble_data
arguments: label: D39
type_guessed: f64
name: disassemble_data
arguments: label: D28
type_guessed: f64

tool: D4: 0.22831

tool: D6: 0.15982

tool: D39: 0.10959

tool: D28: 0.09132

assistant: ```c
double bb_alb_modis(double redchan, double nirchan, double chan3, double chan4, double chan5, double chan6, double chan7) {
  double result;
  result = (0.22831 * redchan + 0.15982 * nirchan + 0.09132 * (chan3 + chan4 + chan5) + 0.10959 * chan6 + 0.22831 * chan7);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mbr_partition_get_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1c2,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L14
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L16
L14:
  nop
L16:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int mbr_partition_get_type(unsigned size, unsigned char *partition, unsigned int *partition_type) {
  unsigned int type_offset = 0x1BE + 0x04;
  if (size < type_offset) {
    goto end;
  }
  *partition_type = partition[type_offset];
end:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mbr_partition_get_type>:
  endbr64
  cmp    $0x1c1,%edi
  jbe    L9
  movzbl 0x1c2(%rsi),%eax
  mov    %eax,(%rdx)
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int mbr_partition_get_type(unsigned size, unsigned char *partition, unsigned int *partition_type) {
  unsigned int type_offset = 0x1BE + 0x04;
  if (size < type_offset) {
    goto end;
  }
  *partition_type = partition[type_offset];
end:
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mbr_partition_get_type>:
  endbr64
  cmp    $0x1c1,%edi
  jbe    L4
  movzbl 0x1c2(%rsi),%eax
  mov    %eax,(%rdx)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int mbr_partition_get_type(unsigned size, unsigned char *partition, unsigned int *partition_type) {
  unsigned int type_offset = 0x1BE + 0x04;
  if (size < type_offset) {
    goto end;
  }
  *partition_type = partition[type_offset];
end:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbr_partition_get_type>:
  endbr64
  cmp    $0x1c1,%edi
  jbe    L0
  movzbl 0x1c2(%rsi),%eax
  mov    %eax,(%rdx)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int mbr_partition_get_type(unsigned size, unsigned char *partition, unsigned int *partition_type) {
  unsigned int type_offset = 0x1BE + 0x04;
  if (size < type_offset) {
    goto end;
  }
  *partition_type = partition[type_offset];
end:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *(sdup)(char *src) {
  size_t n = 1 + strlen(src);
  char *x = malloc(n);
  memcpy(x, src, n);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *(sdup)(char *src) {
  size_t n = 1 + strlen(src);
  char *x = malloc(n);
  memcpy(x, src, n);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *(sdup)(char *src) {
  size_t n = 1 + strlen(src);
  char *x = malloc(n);
  memcpy(x, src, n);
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *(sdup)(char *src) {
  size_t n = 1 + strlen(src);
  char *x = malloc(n);
  memcpy(x, src, n);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fixup_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L15
L20:
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3a,(%rax)
L15:
  mov    -0x30(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L35
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L28
L35:
  mov    -0x30(%rbp),%rax
L28:
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fixup_address(const char *target_addr, const char *remote_chan_addr, char *dest) {
  const char *p, *colon;
  int i = 0;
  p = target_addr;
  colon = strrchr(p, ':');
  if (colon) {
    i = colon - p + 1;
    memcpy(dest, target_addr, i);
  } else {
    strcpy(dest, target_addr);
    i = strlen(dest);
    dest[i++] = ':';
  }
  colon = strrchr(remote_chan_addr, ':');
  p = (colon ? (colon + 1) : remote_chan_addr);
  strcpy(dest + i, p);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fixup_address>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x3a,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L4
  sub    %r13,%rax
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
L13:
  mov    $0x3a,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  cltq
  movb   $0x3a,0x0(%rbp,%rax,1)
  jmp    L13
```

assistant: ```c
int fixup_address(const char *target_addr, const char *remote_chan_addr, char *dest) {
  const char *p, *colon;
  int i = 0;
  p = target_addr;
  colon = strrchr(p, ':');
  if (colon) {
    i = colon - p + 1;
    memcpy(dest, target_addr, i);
  } else {
    strcpy(dest, target_addr);
    i = strlen(dest);
    dest[i++] = ':';
  }
  colon = strrchr(remote_chan_addr, ':');
  p = (colon ? (colon + 1) : remote_chan_addr);
  strcpy(dest + i, p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fixup_address>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x3a,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L1
  sub    %r13,%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
L9:
  mov    %r12,%rdi
  mov    $0x3a,%esi
  movslq %ebx,%rbx
  call   <strrchr@plt>
  lea    0x0(%rbp,%rbx,1),%rdi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%r12
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L1:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  cltq
  movb   $0x3a,0x0(%rbp,%rax,1)
  jmp    L9
```

assistant: ```c
int fixup_address(const char *target_addr, const char *remote_chan_addr, char *dest) {
  const char *p, *colon;
  int i = 0;
  p = target_addr;
  colon = strrchr(p, ':');
  if (colon) {
    i = colon - p + 1;
    memcpy(dest, target_addr, i);
  } else {
    strcpy(dest, target_addr);
    i = strlen(dest);
    dest[i++] = ':';
  }
  colon = strrchr(remote_chan_addr, ':');
  p = (colon ? (colon + 1) : remote_chan_addr);
  strcpy(dest + i, p);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fixup_address>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x3a,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  sub    %r13,%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    0x1(%rax),%ebx
  mov    %ebx,%edx
  call   <memcpy@plt>
L1:
  mov    %r12,%rdi
  mov    $0x3a,%esi
  movslq %ebx,%rbx
  call   <strrchr@plt>
  lea    0x0(%rbp,%rbx,1),%rdi
  test   %rax,%rax
  lea    0x1(%rax),%rdx
  cmovne %rdx,%r12
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  cltq
  movb   $0x3a,0x0(%rbp,%rax,1)
  jmp    L1
```

assistant: ```c
int fixup_address(const char *target_addr, const char *remote_chan_addr, char *dest) {
  const char *p, *colon;
  int i = 0;
  p = target_addr;
  colon = strrchr(p, ':');
  if (colon) {
    i = colon - p + 1;
    memcpy(dest, target_addr, i);
  } else {
    strcpy(dest, target_addr);
    i = strlen(dest);
    dest[i++] = ':';
  }
  colon = strrchr(remote_chan_addr, ':');
  p = (colon ? (colon + 1) : remote_chan_addr);
  strcpy(dest + i, p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L19
L34:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L26:
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L17
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L34
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *m1, const void *m2, size_t n) {
  const char *c1 = m1;
  const char *c2 = m2;
  if (!n) {
    return 0;
  }
  while ((--n > 0) && (*c1 == *c2)) {
    c1++;
    c2++;
  }
  return *c1 - *c2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L6
  mov    %rdi,%rax
  sub    $0x1,%rdx
  je     L9
  add    %rdx,%rdi
L37:
  movzbl (%rsi),%ecx
  cmp    %cl,(%rax)
  jne    L9
  add    $0x1,%rax
  add    $0x1,%rsi
  cmp    %rdi,%rax
  jne    L37
L9:
  movsbl (%rax),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
L6:
  ret
```

assistant: ```c
int memcmp(const void *m1, const void *m2, size_t n) {
  const char *c1 = m1;
  const char *c2 = m2;
  if (!n) {
    return 0;
  }
  while ((--n > 0) && (*c1 == *c2)) {
    c1++;
    c2++;
  }
  return *c1 - *c2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L27
  mov    %rdi,%rcx
  sub    $0x1,%rdx
  je     L62
  lea    (%rdi,%rdx,1),%rdi
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L66:
  lea    0x1(%rcx),%rax
  lea    0x1(%rsi),%rdx
  cmp    %rdi,%rax
  je     L0
  mov    %rdx,%rsi
  mov    %rax,%rcx
L42:
  movsbl (%rcx),%eax
  movsbl (%rsi),%edx
  cmp    %dl,%al
  je     L66
  sub    %edx,%eax
L27:
  ret
L0:
  movsbl 0x1(%rcx),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jmp    L27
L62:
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jmp    L27
```

assistant: ```c
int memcmp(const void *m1, const void *m2, size_t n) {
  const char *c1 = m1;
  const char *c2 = m2;
  if (!n) {
    return 0;
  }
  while ((--n > 0) && (*c1 == *c2)) {
    c1++;
    c2++;
  }
  return *c1 - *c2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L54
  mov    %rdi,%rcx
  sub    $0x1,%rdx
  je     L27
  lea    (%rdi,%rdx,1),%rdi
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L50:
  lea    0x1(%rcx),%rax
  lea    0x1(%rsi),%rdx
  cmp    %rdi,%rax
  je     L22
  mov    %rdx,%rsi
  mov    %rax,%rcx
L46:
  movsbl (%rcx),%eax
  movsbl (%rsi),%edx
  cmp    %dl,%al
  je     L50
  sub    %edx,%eax
L54:
  ret
L22:
  movsbl 0x1(%rcx),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jmp    L54
L27:
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jmp    L54
```

assistant: ```c
int memcmp(const void *m1, const void *m2, size_t n) {
  const char *c1 = m1;
  const char *c2 = m2;
  if (!n) {
    return 0;
  }
  while ((--n > 0) && (*c1 == *c2)) {
    c1++;
    c2++;
  }
  return *c1 - *c2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shift_to_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L3:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x24(%rbp)
  jg     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shift_to_left(int *Arr, int start, int k, int len) {
  int i;
  for (i = start; (i + k) < len; i++) {
    Arr[i] = Arr[i + k];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shift_to_left>:
  endbr64
  mov    %esi,%eax
  lea    (%rsi,%rdx,1),%esi
  cmp    %esi,%ecx
  jle    L18
  cltq
  lea    (%rdi,%rax,4),%rax
  movslq %edx,%rdx
L12:
  mov    (%rax,%rdx,4),%edi
  mov    %edi,(%rax)
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %esi,%ecx
  jg     L12
L18:
  ret
```

assistant: ```c
void shift_to_left(int *Arr, int start, int k, int len) {
  int i;
  for (i = start; (i + k) < len; i++) {
    Arr[i] = Arr[i + k];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shift_to_left>:
  endbr64
  movslq %esi,%rax
  lea    (%rax,%rdx,1),%esi
  cmp    %esi,%ecx
  jle    L14
  lea    (%rdi,%rax,4),%rax
  movslq %edx,%rdx
  nopl   (%rax)
L0:
  mov    (%rax,%rdx,4),%edi
  add    $0x1,%esi
  add    $0x4,%rax
  mov    %edi,-0x4(%rax)
  cmp    %esi,%ecx
  jg     L0
L14:
  ret
```

assistant: ```c
void shift_to_left(int *Arr, int start, int k, int len) {
  int i;
  for (i = start; (i + k) < len; i++) {
    Arr[i] = Arr[i + k];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift_to_left>:
  endbr64
  mov    %edx,%r10d
  add    %esi,%edx
  cmp    %edx,%ecx
  jle    L14
  push   %r12
  movslq %esi,%rax
  lea    0x1(%rsi,%r10,1),%r12d
  mov    %ecx,%r11d
  movslq %r10d,%r8
  sub    %r12d,%r11d
  lea    0x0(,%rax,4),%r9
  push   %rbp
  lea    0x1(%rax,%r8,1),%rax
  push   %rbx
  shl    $0x2,%rax
  cmp    $0x2,%r11d
  seta   %bpl
  cmp    %r12d,%ecx
  setge  %bl
  test   %bl,%bpl
  je     L63
  mov    %r9,%rbx
  sub    %rax,%rbx
  cmp    $0x8,%rbx
  jbe    L63
  add    $0x1,%r11d
  mov    $0x1,%r8d
  cmp    %r12d,%ecx
  cmovl  %r8d,%r11d
  lea    -0x4(%rdi,%rax,1),%rbx
  add    %rdi,%r9
  xor    %eax,%eax
  mov    %r11d,%r8d
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   0x0(%rax)
L26:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%r9,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L26
  mov    %r11d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%edx
  add    %eax,%esi
  cmp    %eax,%r11d
  je     L15
  movslq %edx,%rdx
  movslq %esi,%rax
  mov    (%rdi,%rdx,4),%edx
  mov    %edx,(%rdi,%rax,4)
  lea    0x1(%rsi),%eax
  lea    (%r10,%rax,1),%edx
  cmp    %edx,%ecx
  jle    L15
  movslq %edx,%rdx
  cltq
  mov    (%rdi,%rdx,4),%edx
  lea    0x0(,%rax,4),%r8
  mov    %edx,(%rdi,%rax,4)
  lea    0x2(%rsi,%r10,1),%eax
  cmp    %eax,%ecx
  jle    L15
  cltq
  mov    (%rdi,%rax,4),%eax
  mov    %eax,0x4(%rdi,%r8,1)
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  lea    (%rdi,%r9,1),%rax
  nopl   0x0(%rax)
L31:
  mov    (%rax,%r8,4),%esi
  add    $0x1,%edx
  add    $0x4,%rax
  mov    %esi,-0x4(%rax)
  cmp    %edx,%ecx
  jg     L31
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L14:
  ret
```

assistant: ```c
void shift_to_left(int *Arr, int start, int k, int len) {
  int i;
  for (i = start; (i + k) < len; i++) {
    Arr[i] = Arr[i + k];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  movl   $0x2,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    $0x2710,%eax
  jne    L4
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string

tool: D19: Hello World!


tool: D12: Hello World for the %dth time


assistant: ```c
int main() {
  write(1, "Hello World!\n", 13);
  int i = 2;
  volatile int j = 0;
  while (1) {
    j++;
    if (j == 10000) {
      printf("Hello World for the %dth time\n", i++);
      j = 0;
    }
  }
  return 0;
}
```