user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<addBinary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    %eax,-0x2c(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x28(%rbp)
  movb   $0x30,-0x35(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L68
  mov    -0x30(%rbp),%eax
  add    $0x2,%eax
  jmp    L51
L68:
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
L51:
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L48
L59:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rsi
  mov    -0x20(%rbp),%rdx
  lea    (%rsi,%rdx,1),%rbx
  lea    -0x35(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <addChar@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x34(%rbp)
L48:
  mov    -0x34(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L72
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L59
  jmp    L72
L82:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  lea    -0x35(%rbp),%rdx
  mov    $0x30,%esi
  mov    %eax,%edi
  call   <addChar@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x34(%rbp)
L72:
  mov    -0x34(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L82
  jmp    L85
L10:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  lea    -0x35(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x30,%edi
  call   <addChar@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x34(%rbp)
L85:
  mov    -0x34(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L10
  movzbl -0x35(%rbp),%eax
  cmp    $0x31,%al
  jne    L110
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x35(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L79
L110:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L79:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *addBinary(char *a, char *b) {
  char *c;
  int aSize = reverse(a);
  int bSize = reverse(b);
  int cSize;
  int i = 0, j = 0;
  char tag = '0';
  cSize = aSize > bSize ? aSize + 2 : bSize + 2;
  c = (char *)malloc(sizeof(char) * cSize);
  while ((i < aSize) && (i < bSize)) {
    c[i] = addChar(a[i], b[i], &tag);
    i++;
  }
  while (i < aSize) {
    c[i] = addChar(a[i], '0', &tag);
    i++;
  }
  while (i < bSize) {
    c[i] = addChar('0', b[i], &tag);
    i++;
  }
  if (tag == '1') {
    c[i++] = tag;
    c[i] = '\0';
  } else {
    c[i] = '\0';
  }
  reverse(c);
  return c;
}
```