user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd8(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L89
L144:
  lea    -0xc0(%rbp),%rdx
  mov    -0xd4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xd4(%rbp)
L89:
  mov    -0xd8(%rbp),%eax
  cmp    %eax,-0xd4(%rbp)
  jl     L144
  movl   $0x0,-0xcc(%rbp)
  jmp    L132
L9:
  mov    -0xcc(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L29
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L84
L29:
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L84:
  addl   $0x1,-0xcc(%rbp)
L132:
  mov    -0xd8(%rbp),%eax
  cmp    %eax,-0xcc(%rbp)
  jl     L9
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xd4(%rbp)
  jmp    L5
L148:
  mov    -0xd8(%rbp),%edx
  lea    -0x60(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <next_generation@plt>
  movl   $0x0,-0xd0(%rbp)
  jmp    L119
L122:
  mov    -0xd0(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0xd0(%rbp),%eax
  cltq
  mov    %edx,-0xc0(%rbp,%rax,4)
  mov    -0xd0(%rbp),%eax
  cltq
  movl   $0x0,-0x60(%rbp,%rax,4)
  addl   $0x1,-0xd0(%rbp)
L119:
  mov    -0xd8(%rbp),%eax
  cmp    %eax,-0xd0(%rbp)
  jl     L122
  movl   $0x0,-0xcc(%rbp)
  jmp    L34
L27:
  mov    -0xcc(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L169
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L85
L169:
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L85:
  addl   $0x1,-0xcc(%rbp)
L34:
  mov    -0xd8(%rbp),%eax
  cmp    %eax,-0xcc(%rbp)
  jl     L27
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc4(%rbp)
  movl   $0x0,-0xc8(%rbp)
  jmp    L158
L23:
  mov    -0xc8(%rbp),%eax
  cltq
  mov    -0xc0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L142
  addl   $0x1,-0xc4(%rbp)
L142:
  addl   $0x1,-0xc8(%rbp)
L158:
  mov    -0xd8(%rbp),%eax
  cmp    %eax,-0xc8(%rbp)
  jl     L23
  cmpl   $0x0,-0xc4(%rbp)
  je     L95
  addl   $0x1,-0xd4(%rbp)
L5:
  cmpl   $0x3e7,-0xd4(%rbp)
  jle    L148
  jmp    L64
L95:
  nop
L64:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D63
type: string
name: disassemble_data
arguments: label: D54
type: string
name: disassemble_data
arguments: label: D46
type: string

tool: D25: %d

tool: D63: *

tool: D54: .

tool: D46: 


assistant: ```c
int main() {
  int current[21];
  int next[21];
  int length;
  scanf("%d", &length);
  int i, i1, i2, i3, i4;
  for (i = 0; i < length; i++) {
    scanf("%d", &current[i]);
  }
  for (i3 = 0; i3 < length; i3++) {
    if (current[i3] == 1) {
      printf("*");
    } else {
      printf(".");
    }
  }
  printf("\n");
  for (i = 0; i < 1000; i++) {
    next_generation(current, next, length);
    for (i1 = 0; i1 < length; i1++) {
      current[i1] = next[i1];
      next[i1] = 0;
    }
    for (i3 = 0; i3 < length; i3++) {
      if (current[i3] == 1) {
        printf("*");
      } else {
        printf(".");
      }
    }
    printf("\n");
    int number = 0;
    for (i4 = 0; i4 < length; i4++) {
      if (current[i4] == 1) {
        number++;
      }
    }
    if (number == 0) {
      break;
    }
  }
}
```