ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<to64>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    $0x0,%r15d
L40:
  mov    $0x0,%r12d
  jmp    L29
L63:
  mov    %r14,%r8
  mov    $0x2,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <output64chunk@plt>
L84:
  add    $0x4,%r12d
  cmp    $0x48,%r12d
  je     L48
L29:
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D14(%rip),%rax
  cmp    %ebx,(%rax)
  je     L91
  mov    %r13,%rdi
  call   <getc@plt>
  mov    %eax,%ebp
  mov    D14(%rip),%rax
  cmp    %ebp,(%rax)
  je     L63
  mov    %r13,%rdi
  call   <getc@plt>
  mov    D14(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L68
  mov    %r14,%r8
  mov    $0x0,%ecx
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <output64chunk@plt>
  jmp    L84
L68:
  mov    %r14,%r8
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <output64chunk@plt>
  jmp    L84
L48:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  add    $0x49,%r15d
  jmp    L40
L91:
  test   %r12d,%r12d
  jne    L4
L11:
  lea    (%r12,%r15,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  add    $0x1,%r12d
  jmp    L11
```

assistant: ```c
int to64(FILE *infile, FILE *outfile) {
  int c1, c2, c3, ct = 0, written = 0;
  while ((c1 = getc(infile)) != EOF) {
    c2 = getc(infile);
    if (c2 == EOF) {
      output64chunk(c1, 0, 0, 2, outfile);
    } else {
      c3 = getc(infile);
      if (c3 == EOF) {
        output64chunk(c1, c2, 0, 1, outfile);
      } else {
        output64chunk(c1, c2, c3, 0, outfile);
      }
    }
    ct += 4;
    if (ct > 71) {
      putc('\n', outfile);
      written += 73;
      ct = 0;
    }
  }
  if (ct) {
    putc('\n', outfile);
    ct++;
  }
  return written + ct;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<to64>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D8(%rip),%r13
  movl   $0x0,0xc(%rsp)
L11:
  xor    %ebx,%ebx
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L70:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %r14,%r8
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L34
  xor    %ecx,%ecx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <output64chunk@plt>
L7:
  add    $0x4,%ebx
  cmp    $0x48,%ebx
  je     L87
L99:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  je     L73
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%r15d
  cmp    %eax,0x0(%r13)
  jne    L70
  mov    %r14,%r8
  mov    $0x2,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %ebp,%edi
  add    $0x4,%ebx
  call   <output64chunk@plt>
  cmp    $0x48,%ebx
  jne    L99
L87:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  addl   $0x49,0xc(%rsp)
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <output64chunk@plt>
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L73:
  test   %ebx,%ebx
  jne    L98
L14:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L98:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    0xc(%rsp),%eax
  lea    0x1(%rbx,%rax,1),%eax
  mov    %eax,0xc(%rsp)
  jmp    L14
```

assistant: ```c
int to64(FILE *infile, FILE *outfile) {
  int c1, c2, c3, ct = 0, written = 0;
  while ((c1 = getc(infile)) != EOF) {
    c2 = getc(infile);
    if (c2 == EOF) {
      output64chunk(c1, 0, 0, 2, outfile);
    } else {
      c3 = getc(infile);
      if (c3 == EOF) {
        output64chunk(c1, c2, 0, 1, outfile);
      } else {
        output64chunk(c1, c2, c3, 0, outfile);
      }
    }
    ct += 4;
    if (ct > 71) {
      putc('\n', outfile);
      written += 73;
      ct = 0;
    }
  }
  if (ct) {
    putc('\n', outfile);
    ct++;
  }
  return written + ct;
}
```
user: Translate the below assembly code into C programming language:

```asm
<to64>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D3(%rip),%r13
  movl   $0x0,0xc(%rsp)
L13:
  xor    %ebx,%ebx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %r14,%r8
  mov    %eax,%edx
  cmp    %eax,0x0(%r13)
  je     L53
  xor    %ecx,%ecx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <output64chunk@plt>
L62:
  add    $0x4,%ebx
  cmp    $0x48,%ebx
  je     L95
L74:
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%ebp
  cmp    %eax,0x0(%r13)
  je     L89
  mov    %r12,%rdi
  call   <getc@plt>
  mov    %eax,%r15d
  cmp    %eax,0x0(%r13)
  jne    L2
  mov    %r14,%r8
  mov    $0x2,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %ebp,%edi
  add    $0x4,%ebx
  call   <output64chunk@plt>
  cmp    $0x48,%ebx
  jne    L74
L95:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  addl   $0x49,0xc(%rsp)
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L53:
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <output64chunk@plt>
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L89:
  test   %ebx,%ebx
  jne    L86
L15:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L86:
  mov    %r14,%rsi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    0xc(%rsp),%eax
  lea    0x1(%rbx,%rax,1),%eax
  mov    %eax,0xc(%rsp)
  jmp    L15
```

assistant: ```c
int to64(FILE *infile, FILE *outfile) {
  int c1, c2, c3, ct = 0, written = 0;
  while ((c1 = getc(infile)) != EOF) {
    c2 = getc(infile);
    if (c2 == EOF) {
      output64chunk(c1, 0, 0, 2, outfile);
    } else {
      c3 = getc(infile);
      if (c3 == EOF) {
        output64chunk(c1, c2, 0, 1, outfile);
      } else {
        output64chunk(c1, c2, c3, 0, outfile);
      }
    }
    ct += 4;
    if (ct > 71) {
      putc('\n', outfile);
      written += 73;
      ct = 0;
    }
  }
  if (ct) {
    putc('\n', outfile);
    ct++;
  }
  return written + ct;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<work>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xffffffff,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void work(ip, jp) int *ip, *jp;
{
  *ip = 1;
  *jp = -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<work>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0xffffffff,(%rsi)
  ret
```

assistant: ```c
void work(ip, jp) int *ip, *jp;
{
  *ip = 1;
  *jp = -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<work>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0xffffffff,(%rsi)
  ret
```

assistant: ```c
void work(ip, jp) int *ip, *jp;
{
  *ip = 1;
  *jp = -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<work>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0xffffffff,(%rsi)
  ret
```

assistant: ```c
void work(ip, jp) int *ip, *jp;
{
  *ip = 1;
  *jp = -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err(const char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err(const char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err(const char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err(const char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: skipped


assistant: ```c
int main() {
  printf("skipped\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ga_algorithm_srand_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,%edi
  call   <srand@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void ga_algorithm_srand_init() {
  struct timeval t;
  gettimeofday(&t, NULL);
  srand((t.tv_sec * 1000 + t.tv_usec / 1000));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ga_algorithm_srand_init>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%edi
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  add    %eax,%edi
  call   <srand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ga_algorithm_srand_init() {
  struct timeval t;
  gettimeofday(&t, NULL);
  srand((t.tv_sec * 1000 + t.tv_usec / 1000));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ga_algorithm_srand_init>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%edi
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %eax,%edi
  call   <srand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ga_algorithm_srand_init() {
  struct timeval t;
  gettimeofday(&t, NULL);
  srand((t.tv_sec * 1000 + t.tv_usec / 1000));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ga_algorithm_srand_init>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%edi
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  add    %eax,%edi
  call   <srand@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ga_algorithm_srand_init() {
  struct timeval t;
  gettimeofday(&t, NULL);
  srand((t.tv_sec * 1000 + t.tv_usec / 1000));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unicodeToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  cmp    $0x3ff,%rax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    $0x7f,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D23(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  addq   $0x2,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  cmp    %eax,-0x4(%rbp)
  jl     L18
  mov    -0x4(%rbp),%eax
  cltq
  lea    D23(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D23(%rip),%rax
  leave
  ret
```

assistant: ```c
char *unicodeToString(char *p, size_t len) {
  int i;
  static char buf[1024];
  assert(len + 1 < sizeof buf);
  for (i = 0; i < (signed int)len; ++i) {
    buf[i] = *p & 0x7f;
    p += 2;
  }
  buf[i] = '\0';
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unicodeToString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rax
  cmp    $0x3ff,%rax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L20
  mov    %ebp,%edi
  lea    -0x1(%rbp),%esi
  mov    $0x0,%eax
  lea    D9(%rip),%rcx
L29:
  movzbl (%rbx,%rax,2),%edx
  and    $0x7f,%edx
  mov    %dl,(%rcx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L29
L14:
  lea    D9(%rip),%rax
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%edi
  jmp    L14
```

assistant: ```c
char *unicodeToString(char *p, size_t len) {
  int i;
  static char buf[1024];
  assert(len + 1 < sizeof buf);
  for (i = 0; i < (signed int)len; ++i) {
    buf[i] = *p & 0x7f;
    p += 2;
  }
  buf[i] = '\0';
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unicodeToString>:
  endbr64
  push   %rbp
  lea    0x1(%rsi),%rax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x3ff,%rax
  setbe  %dil
  call   <assert@plt>
  test   %ebp,%ebp
  jle    L17
  movslq %ebp,%rsi
  lea    -0x1(%rbp),%ecx
  lea    D5(%rip),%r8
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rbx,%rax,2),%edx
  and    $0x7f,%edx
  mov    %dl,(%r8,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L2
  movb   $0x0,(%r8,%rsi,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D5(%rip),%r8
  xor    %esi,%esi
  movb   $0x0,(%r8,%rsi,1)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *unicodeToString(char *p, size_t len) {
  int i;
  static char buf[1024];
  assert(len + 1 < sizeof buf);
  for (i = 0; i < (signed int)len; ++i) {
    buf[i] = *p & 0x7f;
    p += 2;
  }
  buf[i] = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_is_jpeg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x3,-0x8(%rbp)
  jbe    L56
  mov    -0x8(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L56
  mov    $0x1,%eax
  jmp    L31
L56:
  cmpq   $0x4,-0x8(%rbp)
  jbe    L13
  mov    -0x8(%rbp),%rax
  lea    -0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x1,%eax
  jmp    L31
L13:
  mov    $0x0,%eax
L31:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D12: .jpg

tool: D3: .jpeg

assistant: ```c
bool path_is_jpeg(const char *path) {
  size_t n = strlen(path);
  if (n >= 4 && 0 == strcasecmp(path + n - 4, ".jpg"))
    return true;
  if (n >= 5 && 0 == strcasecmp(path + n - 5, ".jpeg"))
    return true;
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<path_is_jpeg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  cmp    $0x3,%rax
  ja     L38
L9:
  mov    $0x0,%eax
  cmp    $0x4,%rbx
  ja     L49
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  lea    -0x4(%rbp,%rax,1),%rdi
  lea    D5(%rip),%rsi
  call   <strcasecmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L9
  jmp    L36
L49:
  lea    -0x5(%rbp,%rbx,1),%rdi
  lea    D13(%rip),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L36
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string

tool: D5: .jpg

tool: D13: .jpeg

assistant: ```c
bool path_is_jpeg(const char *path) {
  size_t n = strlen(path);
  if (n >= 4 && 0 == strcasecmp(path + n - 4, ".jpg"))
    return true;
  if (n >= 5 && 0 == strcasecmp(path + n - 5, ".jpeg"))
    return true;
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<path_is_jpeg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x3,%rax
  ja     L20
L28:
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  lea    -0x4(%rbp,%rax,1),%rdi
  lea    D4(%rip),%rsi
  mov    %rax,%rbx
  call   <strcasecmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
  cmp    $0x4,%rbx
  je     L28
  lea    -0x5(%rbp,%rbx,1),%rdi
  lea    D10(%rip),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string

tool: D4: .jpg

tool: D10: .jpeg

assistant: ```c
bool path_is_jpeg(const char *path) {
  size_t n = strlen(path);
  if (n >= 4 && 0 == strcasecmp(path + n - 4, ".jpg"))
    return true;
  if (n >= 5 && 0 == strcasecmp(path + n - 5, ".jpeg"))
    return true;
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<path_is_jpeg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x3,%rax
  ja     L29
L15:
  xor    %eax,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  lea    -0x4(%rbp,%rax,1),%rdi
  lea    D9(%rip),%rsi
  mov    %rax,%rbx
  call   <strcasecmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L4
  cmp    $0x4,%rbx
  je     L15
  lea    -0x5(%rbp,%rbx,1),%rdi
  lea    D19(%rip),%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D9: .jpg

tool: D19: .jpeg

assistant: ```c
bool path_is_jpeg(const char *path) {
  size_t n = strlen(path);
  if (n >= 4 && 0 == strcasecmp(path + n - 4, ".jpg"))
    return true;
  if (n >= 5 && 0 == strcasecmp(path + n - 5, ".jpeg"))
    return true;
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <fileRead@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  fileRead();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fileRead@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  fileRead();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fileRead@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  fileRead();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fileRead@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  fileRead();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <brk@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <brk@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  void *pbrk;
  pbrk = sbrk(0);
  brk(pbrk);
  brk((void *)-1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,%rdi
  call   <brk@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <brk@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *pbrk;
  pbrk = sbrk(0);
  brk(pbrk);
  brk((void *)-1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <sbrk@plt>
  mov    %rax,%rdi
  call   <brk@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <brk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *pbrk;
  pbrk = sbrk(0);
  brk(pbrk);
  brk((void *)-1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <sbrk@plt>
  mov    %rax,%rdi
  call   <brk@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <brk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  void *pbrk;
  pbrk = sbrk(0);
  brk(pbrk);
  brk((void *)-1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safeMalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *safeMalloc(size_t size) {
  void *p = malloc(size);
  assert(p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<safeMalloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *safeMalloc(size_t size) {
  void *p = malloc(size);
  assert(p);
  return p;
}
```