ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<allocate_array>:
  endbr64
  push   %r13
  lea    -0x1(%rdi),%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%r13,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L18
  lea    -0x2(%rbx),%r13d
  mov    $0x1,%ebx
  add    $0x2,%r13
  nopl   0x0(%rax)
L12:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L12
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *allocate_array(int argc, char *argv[]) {
  int n = argc - 1;
  int *p = malloc(n * sizeof(int));
  for (int i = 0; i < n; i++) {
    *(p + i) = atoi(argv[i + 1]);
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L46:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L46
  cmpl   $0x1,-0x8(%rbp)
  jle    L42
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L17
L42:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (j = 0; s[j] != '\n'; ++j)
    ;
  if (j > 1)
    for (i = 0; i < j; ++i, --j) {
      c = s[i];
      s[i] = s[j];
      s[j] = c;
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L12
  mov    $0x1,%edx
L18:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0xa,-0x1(%rdi,%rdx,1)
  jne    L18
  cmp    $0x1,%eax
  jle    L12
  cltq
  mov    $0x0,%edx
L1:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdi,%rdx,1)
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L1
L12:
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (j = 0; s[j] != '\n'; ++j)
    ;
  if (j > 1)
    for (i = 0; i < j; ++i, --j) {
      c = s[i];
      s[i] = s[j];
      s[j] = c;
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  movzbl (%rdi),%esi
  cmp    $0xa,%sil
  je     L26
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L28:
  movslq %edx,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rdi,%rdx,1),%ecx
  cmp    $0xa,%cl
  jne    L28
  cmp    $0x1,%eax
  je     L26
  xor    %edx,%edx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl (%rdi,%rdx,1),%esi
  movzbl (%rdi,%rax,1),%ecx
L20:
  mov    %cl,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %sil,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L4
L26:
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (j = 0; s[j] != '\n'; ++j)
    ;
  if (j > 1)
    for (i = 0; i < j; ++i, --j) {
      c = s[i];
      s[i] = s[j];
      s[j] = c;
    }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L21
  mov    $0x1,%edx
  xchg   %ax,%ax
L7:
  movslq %edx,%rax
  add    $0x1,%rdx
  cmpb   $0xa,-0x1(%rdi,%rdx,1)
  jne    L7
  cmp    $0x1,%eax
  je     L21
  xor    %edx,%edx
  nopl   (%rax)
L24:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl (%rdi,%rax,1),%esi
  mov    %sil,(%rdi,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L24
L21:
  ret
```

assistant: ```c
void reverse(char s[]) {
  int i, j, c;
  for (j = 0; s[j] != '\n'; ++j)
    ;
  if (j > 1)
    for (i = 0; i < j; ++i, --j) {
      c = s[i];
      s[i] = s[j];
      s[j] = c;
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L15
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L38
L15:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L38:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L18
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  lea    -0x8(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L28
  subl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: error: position not in stack


assistant: ```c
int remove_pos(int pos, int s, struct link **stack) {
  int j;
  if (pos < 0 || pos >= s)
    printf("error: position not in stack\n");
  free(stack[pos]);
  for (j = pos + 1; j < s; j++) {
    stack[j - 1] = stack[j];
  }
  s--;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<remove_pos>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r12
  test   %edi,%edi
  js     L32
  cmp    %esi,%edi
  jge    L32
L43:
  movslq %ebp,%r13
  lea    0x0(,%r13,8),%r14
  mov    (%r12,%r13,8),%rdi
  call   <free@plt>
  lea    0x1(%rbp),%eax
  cmp    %eax,%ebx
  jle    L29
  lea    0x8(%r12,%r14,1),%rax
  lea    -0x2(%rbx),%edx
  sub    %ebp,%edx
  add    %r13,%rdx
  lea    0x10(%r12,%rdx,8),%rcx
L25:
  mov    (%rax),%rdx
  mov    %rdx,-0x8(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L25
L29:
  lea    -0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L43
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: error: position not in stack


assistant: ```c
int remove_pos(int pos, int s, struct link **stack) {
  int j;
  if (pos < 0 || pos >= s)
    printf("error: position not in stack\n");
  free(stack[pos]);
  for (j = pos + 1; j < s; j++) {
    stack[j - 1] = stack[j];
  }
  s--;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_pos>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  test   %edi,%edi
  js     L9
  cmp    %esi,%edi
  jge    L9
L1:
  movslq %ebp,%r12
  shl    $0x3,%r12
  lea    0x0(%r13,%r12,1),%r14
  mov    (%r14),%rdi
  call   <free@plt>
  lea    0x1(%rbp),%eax
  cmp    %eax,%ebx
  jle    L36
  lea    -0x2(%rbx),%eax
  lea    0x8(%r13,%r12,1),%rsi
  mov    %r14,%rdi
  sub    %ebp,%eax
  lea    0x8(,%rax,8),%rdx
  call   <memmove@plt>
L36:
  lea    -0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L9:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8: error: position not in stack


assistant: ```c
int remove_pos(int pos, int s, struct link **stack) {
  int j;
  if (pos < 0 || pos >= s)
    printf("error: position not in stack\n");
  free(stack[pos]);
  for (j = pos + 1; j < s; j++) {
    stack[j - 1] = stack[j];
  }
  s--;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remove_pos>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  test   %edi,%edi
  js     L24
  cmp    %esi,%edi
  jge    L24
L19:
  movslq %ebp,%r12
  shl    $0x3,%r12
  lea    0x0(%r13,%r12,1),%r14
  mov    (%r14),%rdi
  call   <free@plt>
  lea    0x1(%rbp),%eax
  cmp    %eax,%ebx
  jle    L33
  lea    -0x2(%rbx),%eax
  lea    0x8(%r13,%r12,1),%rsi
  mov    %r14,%rdi
  sub    %ebp,%eax
  lea    0x8(,%rax,8),%rdx
  call   <memmove@plt>
L33:
  lea    -0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: error: position not in stack


assistant: ```c
int remove_pos(int pos, int s, struct link **stack) {
  int j;
  if (pos < 0 || pos >= s)
    printf("error: position not in stack\n");
  free(stack[pos]);
  for (j = pos + 1; j < s; j++) {
    stack[j - 1] = stack[j];
  }
  s--;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_executable_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <readlink@plt>
  test   %rax,%rax
  jg     L23
  mov    $0xffffffffffffffff,%rax
  jmp    L29
L23:
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0xffffffffffffffff,%rax
  jmp    L29
L3:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L29:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: /proc/self/exe

assistant: ```c
size_t get_executable_path(char *buffer, size_t len) {
  char *path_end;
  if (readlink("/proc/self/exe", buffer, len) <= 0) {
    return -1;
  }
  path_end = strrchr(buffer, '/');
  if (path_end == NULL) {
    return -1;
  }
  ++path_end;
  *path_end = '\0';
  return (size_t)(path_end - buffer);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_executable_path>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <readlink@plt>
  mov    %rax,%rdx
  mov    $0xffffffffffffffff,%rax
  test   %rdx,%rdx
  jle    L0
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
  movb   $0x0,0x1(%rax)
  add    $0x1,%rax
  sub    %rbx,%rax
L0:
  pop    %rbx
  ret
L19:
  mov    $0xffffffffffffffff,%rax
  jmp    L0
```

tool_calls: name: unpack_data
arguments: label: D7
data_type: string

tool: D7: /proc/self/exe

assistant: ```c
size_t get_executable_path(char *buffer, size_t len) {
  char *path_end;
  if (readlink("/proc/self/exe", buffer, len) <= 0) {
    return -1;
  }
  path_end = strrchr(buffer, '/');
  if (path_end == NULL) {
    return -1;
  }
  ++path_end;
  *path_end = '\0';
  return (size_t)(path_end - buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_executable_path>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <readlink@plt>
  test   %rax,%rax
  jle    L5
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
  movb   $0x0,0x1(%rax)
  add    $0x1,%rax
  sub    %rbx,%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L5:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: /proc/self/exe

assistant: ```c
size_t get_executable_path(char *buffer, size_t len) {
  char *path_end;
  if (readlink("/proc/self/exe", buffer, len) <= 0) {
    return -1;
  }
  path_end = strrchr(buffer, '/');
  if (path_end == NULL) {
    return -1;
  }
  ++path_end;
  *path_end = '\0';
  return (size_t)(path_end - buffer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_executable_path>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <readlink@plt>
  test   %rax,%rax
  jle    L11
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L11
  movb   $0x0,0x1(%rax)
  add    $0x1,%rax
  sub    %rbx,%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L11:
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: /proc/self/exe

assistant: ```c
size_t get_executable_path(char *buffer, size_t len) {
  char *path_end;
  if (readlink("/proc/self/exe", buffer, len) <= 0) {
    return -1;
  }
  path_end = strrchr(buffer, '/');
  if (path_end == NULL) {
    return -1;
  }
  ++path_end;
  *path_end = '\0';
  return (size_t)(path_end - buffer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<multiply331>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L25
L39:
  movl   $0x0,-0x3c(%rbp)
  jmp    L12
L8:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L12:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L8
  addl   $0x1,-0x40(%rbp)
L25:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L39
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply331(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply331>:
  endbr64
  test   %edi,%edi
  jle    L24
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L28:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L6:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L6
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  ret
```

assistant: ```c
void multiply331(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply331>:
  endbr64
  test   %edi,%edi
  jle    L28
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L20
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L26
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void multiply331(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply331>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L47
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L99:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L93
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L93
  nopl   0x0(%rax)
L57:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L57
  cmp    -0x24(%rsp),%r11d
  je     L49
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L49
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L49
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L49:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L99
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L93:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L8
  mov    -0x18(%rsp),%r8
  jmp    L49
```

assistant: ```c
void multiply331(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<os_normalize_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L125
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L125
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L158
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L77
  mov    -0x8(%rbp),%rax
  movb   $0x2f,(%rax)
L77:
  addq   $0x1,-0x8(%rbp)
L158:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  subq   $0x1,-0x8(%rbp)
  jmp    L134
L150:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L134:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L41
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L150
L41:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  mov    -0x18(%rbp),%rax
  movb   $0x2f,(%rax)
L60:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L79
L62:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L110
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L7
L118:
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L118
  jmp    L79
L110:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L79:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L100
L125:
  nop
L100:
  pop    %rbp
  ret
```

assistant: ```c
void os_normalize_path(char *path) {
  char *d, *s;
  if (!path || !*path)
    return;
  s = path;
  while (*s) {
    if (*s == '\\')
      *s = '/';
    s++;
  }
  s--;
  while (s >= path && *s == '/')
    *s-- = 0;
  if (!*path)
    *path = '/';
  s = d = path;
  while (*s) {
    if (*s == '/') {
      *d++ = *s++;
      while (*s == '/')
        s++;
    } else {
      *d++ = *s++;
    }
  }
  *d = *s;
}
```
user: What is the c source code of the assembly code below?

```asm
<os_normalize_path>:
  endbr64
  test   %rdi,%rdi
  je     L67
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L130
L67:
  ret
L148:
  lea    0x1(%rax),%rcx
  movzbl 0x1(%rax),%edx
  test   %dl,%dl
  je     L108
  mov    %rcx,%rax
L130:
  cmp    $0x5c,%dl
  jne    L148
  movb   $0x2f,(%rax)
  jmp    L148
L108:
  cmp    %rax,%rdi
  ja     L147
L16:
  cmpb   $0x2f,(%rax)
  jne    L147
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmp    %rax,%rdi
  jbe    L16
L147:
  cmpb   $0x0,(%rdi)
  jne    L62
  movb   $0x2f,(%rdi)
L62:
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  jmp    L46
L133:
  lea    0x1(%rdi),%rax
  mov    %rdx,%rcx
  movb   $0x2f,-0x1(%rdx)
  cmpb   $0x2f,0x1(%rdi)
  jne    L2
L135:
  add    $0x1,%rax
  cmpb   $0x2f,(%rax)
  je     L135
  mov    %rax,%rdi
L101:
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L144
L46:
  cmp    $0x2f,%al
  je     L133
  add    $0x1,%rdi
  mov    %rdx,%rcx
  mov    %al,-0x1(%rdx)
  jmp    L101
L2:
  mov    %rax,%rdi
  jmp    L101
L144:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
void os_normalize_path(char *path) {
  char *d, *s;
  if (!path || !*path)
    return;
  s = path;
  while (*s) {
    if (*s == '\\')
      *s = '/';
    s++;
  }
  s--;
  while (s >= path && *s == '/')
    *s-- = 0;
  if (!*path)
    *path = '/';
  s = d = path;
  while (*s) {
    if (*s == '/') {
      *d++ = *s++;
      while (*s == '/')
        s++;
    } else {
      *d++ = *s++;
    }
  }
  *d = *s;
}
```