ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_errors_from_file>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3c8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L18
  movb   $0x0,0xa0(%rsp)
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rsp,%rbx
  lea    0xa0(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r13,%rdx
  mov    $0xa0,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  cmp    %rax,%rbx
  jne    L60
  cmpb   $0xa,(%rsp)
  je     L47
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%eax
  cmp    $0x31f,%eax
  jbe    L67
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <prompt_error_msg@plt>
  movb   $0x0,0xa0(%rsp)
  test   %rax,%rax
  jne    L87
L67:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L47
  nopl   (%rax)
L60:
  cmpb   $0x0,0xa0(%rsp)
  jne    L30
L87:
  mov    %r13,%rdi
  call   <fclose@plt>
L18:
  mov    0x3c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L30:
  mov    %r14,%rdi
  lea    0xa0(%rsp),%rsi
  call   <show_error_msg@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  jmp    L18
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void show_errors_from_file(FILE *ef, const char title[]) {
  char linebuf[160];
  char buf[sizeof(linebuf) * 5];
  if (ef == NULL)
    return;
  buf[0] = '\0';
  while (fgets(linebuf, sizeof(linebuf), ef) == linebuf) {
    if (linebuf[0] == '\n')
      continue;
    if (strlen(buf) + strlen(linebuf) + 1 >= sizeof(buf)) {
      int skip = (prompt_error_msg(title, buf) != 0);
      buf[0] = '\0';
      if (skip)
        break;
    }
    strcat(buf, linebuf);
  }
  if (buf[0] != '\0') {
    show_error_msg(title, buf);
  }
  fclose(ef);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movss  0x28(%rsp),%xmm0
  movss  0x20(%rsp),%xmm1
  add    $0x10,%rsp
  ucomiss %xmm1,%xmm0
  jp     L119
  jne    L119
  movss  0x20(%rsp),%xmm2
  ucomiss %xmm2,%xmm0
  jp     L19
  je     L168
L19:
  movss  0x24(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm4
  ucomiss %xmm1,%xmm0
  jp     L10
  je     L158
L10:
  subss  %xmm4,%xmm3
  movaps %xmm3,%xmm1
  subss  %xmm0,%xmm2
  divss  %xmm2,%xmm1
  movss  0xc(%rsp),%xmm5
  ucomiss %xmm5,%xmm1
  jp     L121
  jne    L121
  lea    D7(%rip),%rdi
  call   <printf@plt>
L173:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L119:
  movss  0x1c(%rsp),%xmm2
  subss  0x14(%rsp),%xmm2
  movaps %xmm0,%xmm3
  subss  %xmm1,%xmm3
  divss  %xmm3,%xmm2
  movss  %xmm2,0xc(%rsp)
  movss  0x20(%rsp),%xmm2
  ucomiss %xmm2,%xmm0
  jp     L143
  jne    L143
  ucomiss %xmm1,%xmm0
  jp     L62
  je     L168
L62:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L173
L168:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L173
L158:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L173
L121:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L173
L143:
  movss  0x24(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm4
  jmp    L10
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D7
type: string
name: parse_data
arguments: label: D31
type: string

tool: D0: %f %f %f %f %f %f

tool: D7: All points are on the same line.

tool: D31: All points are not on the same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, m1, m2;
  scanf("%f %f %f %f %f %f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x2 != x1) {
    m1 = (y2 - y1) / (x2 - x1);
  }
  if (x2 != x3) {
    m2 = (y3 - y2) / (x3 - x2);
  }
  if ((x1 == x2) && (x2 == x3)) {
    printf("All points are on the same line.");
  } else if (x1 == x2 && x2 != x3) {
    printf("All points are not on the same line.");
  } else if (x1 != x2 && x2 == x3) {
    printf("All points are not on the same line.");
  } else {
    if (m1 == m2) {
      printf("All points are on the same line.");
    } else {
      printf("All points are not on the same line.");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  call   <scanf@plt>
  movss  0x28(%rsp),%xmm0
  movss  0x20(%rsp),%xmm2
  pop    %rax
  pop    %rdx
  ucomiss %xmm2,%xmm0
  jp     L91
  jne    L91
  movss  0x20(%rsp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L1
  je     L35
L1:
  ucomiss %xmm2,%xmm0
  jp     L122
  je     L29
L122:
  subss  %xmm0,%xmm1
  movss  0x24(%rsp),%xmm2
  subss  0x1c(%rsp),%xmm2
  divss  %xmm1,%xmm2
  ucomiss 0xc(%rsp),%xmm2
  jp     L29
  je     L35
L29:
  lea    D20(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L91:
  movaps %xmm0,%xmm3
  movss  0x1c(%rsp),%xmm1
  subss  0x14(%rsp),%xmm1
  subss  %xmm2,%xmm3
  divss  %xmm3,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  0x20(%rsp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L122
  jne    L122
  ucomiss %xmm2,%xmm0
  jp     L29
  jne    L29
L35:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D17
datatype: string

tool: D0: %f %f %f %f %f %f

tool: D20: All points are not on the same line.

tool: D17: All points are on the same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, m1, m2;
  scanf("%f %f %f %f %f %f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x2 != x1) {
    m1 = (y2 - y1) / (x2 - x1);
  }
  if (x2 != x3) {
    m2 = (y3 - y2) / (x3 - x2);
  }
  if ((x1 == x2) && (x2 == x3)) {
    printf("All points are on the same line.");
  } else if (x1 == x2 && x2 != x3) {
    printf("All points are not on the same line.");
  } else if (x1 != x2 && x2 == x3) {
    printf("All points are not on the same line.");
  } else {
    if (m1 == m2) {
      printf("All points are on the same line.");
    } else {
      printf("All points are not on the same line.");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  sub    $0x8,%rsp
  lea    0x2c(%rsp),%rax
  push   %rax
  lea    0x30(%rsp),%r9
  lea    0x2c(%rsp),%r8
  call   <scanf@plt>
  movss  0x28(%rsp),%xmm0
  movss  0x20(%rsp),%xmm2
  pop    %rax
  pop    %rdx
  ucomiss %xmm2,%xmm0
  jp     L9
  jne    L9
  movss  0x20(%rsp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L103
  je     L5
L103:
  ucomiss %xmm2,%xmm0
  jp     L83
  je     L18
L83:
  subss  %xmm0,%xmm1
  movss  0x24(%rsp),%xmm2
  subss  0x1c(%rsp),%xmm2
  divss  %xmm1,%xmm2
  ucomiss 0xc(%rsp),%xmm2
  jp     L18
  je     L5
L18:
  lea    D13(%rip),%rdi
  call   <printf@plt>
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L9:
  movaps %xmm0,%xmm3
  movss  0x1c(%rsp),%xmm1
  subss  0x14(%rsp),%xmm1
  subss  %xmm2,%xmm3
  divss  %xmm3,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  0x20(%rsp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L83
  jne    L83
  ucomiss %xmm2,%xmm0
  jp     L18
  jne    L18
L5:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D15: %f %f %f %f %f %f

tool: D13: All points are not on the same line.

tool: D5: All points are on the same line.

assistant: ```c
int main() {
  float x1, y1, x2, y2, x3, y3, m1, m2;
  scanf("%f %f %f %f %f %f", &x1, &y1, &x2, &y2, &x3, &y3);
  if (x2 != x1) {
    m1 = (y2 - y1) / (x2 - x1);
  }
  if (x2 != x3) {
    m2 = (y3 - y2) / (x3 - x2);
  }
  if ((x1 == x2) && (x2 == x3)) {
    printf("All points are on the same line.");
  } else if (x1 == x2 && x2 != x3) {
    printf("All points are not on the same line.");
  } else if (x1 != x2 && x2 == x3) {
    printf("All points are not on the same line.");
  } else {
    if (m1 == m2) {
      printf("All points are on the same line.");
    } else {
      printf("All points are not on the same line.");
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa_alt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L18:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <abs@plt>
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  test   %rax,%rax
  jg     L18
  cmpl   $0x0,-0x4(%rbp)
  jns    L1
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoa_alt(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa_alt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r14
  mov    %rsi,%r13
  mov    %edi,%ebp
  mov    $0x0,%r12d
L20:
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  mov    %ebp,%edi
  sub    %eax,%edi
  call   <abs@plt>
  mov    %r12d,0xc(%rsp)
  add    $0x1,%r12d
  add    $0x30,%eax
  mov    %al,0x0(%r13)
  mov    %ebx,%ebp
  mov    %ebx,%edi
  call   <abs@plt>
  add    $0x1,%r13
  test   %rax,%rax
  jg     L20
  test   %r15d,%r15d
  js     L29
L15:
  movslq %r12d,%r12
  movb   $0x0,(%r14,%r12,1)
  mov    %r14,%rdi
  call   <reverse@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  movslq %r12d,%r12
  movb   $0x2d,(%r14,%r12,1)
  mov    0xc(%rsp),%eax
  lea    0x2(%rax),%r12d
  jmp    L15
```

assistant: ```c
void itoa_alt(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa_alt>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  movslq %r14d,%rbx
  mov    %r14d,%eax
  mov    %r14d,%edi
  mov    %ebp,%r15d
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%ebp
  add    $0x1,%r12
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebx,%r14d
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  add    $0x30,%eax
  mov    %al,-0x1(%r12)
  call   <abs@plt>
  test   %rax,%rax
  jg     L8
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L19
  movslq %ebp,%rbp
  movb   $0x2d,0x0(%r13,%rbp,1)
  lea    0x2(%r15),%ebp
L19:
  movslq %ebp,%rbp
  mov    %r13,%rdi
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa_alt(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa_alt>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  nopl   0x0(%rax)
L7:
  movslq %r14d,%rbx
  mov    %r14d,%eax
  mov    %r14d,%edi
  mov    %ebp,%r15d
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%eax
  add    $0x1,%ebp
  add    $0x1,%r12
  sar    $0x22,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebx,%r14d
  add    %eax,%eax
  sub    %eax,%edi
  call   <abs@plt>
  mov    %ebx,%edi
  add    $0x30,%eax
  mov    %al,-0x1(%r12)
  call   <abs@plt>
  test   %rax,%rax
  jg     L7
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L19
  movslq %ebp,%rbp
  movb   $0x2d,0x0(%r13,%rbp,1)
  lea    0x2(%r15),%ebp
L19:
  movslq %ebp,%rbp
  mov    %r13,%rdi
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa_alt(int n, char s[]) {
  int i, sign;
  sign = n;
  i = 0;
  do {
    s[i++] = abs(n % 10) + '0';
  } while ((abs(n /= 10)) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  reverse(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<G7112LinnerPCM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  cmpq   $0x0,-0x28(%rbp)
  jne    L18
L3:
  mov    $0xffffffff,%eax
  jmp    L23
L18:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L48
  mov    $0xffffffff,%eax
  jmp    L23
L48:
  movl   $0x0,-0xc(%rbp)
  jmp    L66
L42:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <alaw2linear@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %ax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L66:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L42
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
L23:
  leave
  ret
```

assistant: ```c
int G7112LinnerPCM(unsigned char *pcmBuf, int pcmBufLen, const unsigned char *g711Buf, int g711BufLen) {
  int i = 0;
  short *pbuf = (short *)pcmBuf;
  if (pcmBuf == 0x0L || g711Buf == 0x0L)
    return -1;
  if (pcmBufLen < 2 * g711BufLen)
    return -1;
  for (i = 0; i < g711BufLen; i++) {
    pbuf[i] = alaw2linear(g711Buf[i]);
  }
  return 2 * g711BufLen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<G7112LinnerPCM>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L64
  mov    %rdi,%r12
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L64
  lea    (%rcx,%rcx,1),%r14d
  cmp    %esi,%r14d
  jg     L1
  test   %ecx,%ecx
  jle    L57
  mov    %ecx,%ebp
  mov    $0x0,%ebx
L52:
  movzbl 0x0(%r13,%rbx,1),%edi
  mov    $0x0,%eax
  call   <alaw2linear@plt>
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L52
L57:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  mov    $0xffffffff,%r14d
  jmp    L57
L1:
  mov    $0xffffffff,%r14d
  jmp    L57
```

assistant: ```c
int G7112LinnerPCM(unsigned char *pcmBuf, int pcmBufLen, const unsigned char *g711Buf, int g711BufLen) {
  int i = 0;
  short *pbuf = (short *)pcmBuf;
  if (pcmBuf == 0x0L || g711Buf == 0x0L)
    return -1;
  if (pcmBufLen < 2 * g711BufLen)
    return -1;
  for (i = 0; i < g711BufLen; i++) {
    pbuf[i] = alaw2linear(g711Buf[i]);
  }
  return 2 * g711BufLen;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<G7112LinnerPCM>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L16
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L16
  lea    (%rcx,%rcx,1),%r14d
  cmp    %esi,%r14d
  jg     L16
  test   %ecx,%ecx
  jle    L27
  mov    %rdi,%r12
  movslq %ecx,%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L41:
  movzbl 0x0(%r13,%rbx,1),%edi
  xor    %eax,%eax
  call   <alaw2linear@plt>
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L41
L27:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    $0xffffffff,%r14d
  jmp    L27
```

assistant: ```c
int G7112LinnerPCM(unsigned char *pcmBuf, int pcmBufLen, const unsigned char *g711Buf, int g711BufLen) {
  int i = 0;
  short *pbuf = (short *)pcmBuf;
  if (pcmBuf == 0x0L || g711Buf == 0x0L)
    return -1;
  if (pcmBufLen < 2 * g711BufLen)
    return -1;
  for (i = 0; i < g711BufLen; i++) {
    pbuf[i] = alaw2linear(g711Buf[i]);
  }
  return 2 * g711BufLen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<G7112LinnerPCM>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L16
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L16
  lea    (%rcx,%rcx,1),%r14d
  cmp    %esi,%r14d
  jg     L16
  test   %ecx,%ecx
  jle    L25
  mov    %rdi,%r12
  movslq %ecx,%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L40:
  movzbl 0x0(%r13,%rbx,1),%edi
  xor    %eax,%eax
  call   <alaw2linear@plt>
  mov    %ax,(%r12,%rbx,2)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L40
L25:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    $0xffffffff,%r14d
  jmp    L25
```

assistant: ```c
int G7112LinnerPCM(unsigned char *pcmBuf, int pcmBufLen, const unsigned char *g711Buf, int g711BufLen) {
  int i = 0;
  short *pbuf = (short *)pcmBuf;
  if (pcmBuf == 0x0L || g711Buf == 0x0L)
    return -1;
  if (pcmBufLen < 2 * g711BufLen)
    return -1;
  for (i = 0; i < g711BufLen; i++) {
    pbuf[i] = alaw2linear(g711Buf[i]);
  }
  return 2 * g711BufLen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inputb_none_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <log_f@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: inputb:none: inputb_none_button_get()


assistant: ```c
unsigned inputb_none_get(void) {
  log_f("inputb:none: inputb_none_button_get()\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inputb_none_get>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <log_f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: inputb:none: inputb_none_button_get()


assistant: ```c
unsigned inputb_none_get(void) {
  log_f("inputb:none: inputb_none_button_get()\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inputb_none_get>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <log_f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: inputb:none: inputb_none_button_get()


assistant: ```c
unsigned inputb_none_get(void) {
  log_f("inputb:none: inputb_none_button_get()\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inputb_none_get>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <log_f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: inputb:none: inputb_none_button_get()


assistant: ```c
unsigned inputb_none_get(void) {
  log_f("inputb:none: inputb_none_button_get()\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_ji>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void check_ji(int *i, int *j) {
  if (*j < *i) {
    *j += *i;
    *i = *j - *i;
    *j = *j - *i;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_ji>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  jge    L1
  add    %edx,%eax
  mov    %eax,(%rsi)
  sub    (%rdi),%eax
  mov    %eax,(%rdi)
  sub    %eax,(%rsi)
L1:
  ret
```

assistant: ```c
void check_ji(int *i, int *j) {
  if (*j < *i) {
    *j += *i;
    *i = *j - *i;
    *j = *j - *i;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_ji>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  jge    L2
  add    %edx,%eax
  mov    %eax,(%rsi)
  sub    (%rdi),%eax
  mov    %eax,(%rdi)
  sub    %eax,(%rsi)
L2:
  ret
```

assistant: ```c
void check_ji(int *i, int *j) {
  if (*j < *i) {
    *j += *i;
    *i = *j - *i;
    *j = *j - *i;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check_ji>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  jge    L8
  add    %edx,%eax
  mov    %eax,(%rsi)
  sub    (%rdi),%eax
  mov    %eax,(%rdi)
  sub    %eax,(%rsi)
L8:
  ret
```

assistant: ```c
void check_ji(int *i, int *j) {
  if (*j < *i) {
    *j += *i;
    *i = *j - *i;
    *j = *j - *i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L2
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
L2:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rev(char *b, char *e) {
  char tmp;
  while (b < e) {
    tmp = *b;
    *b++ = *e;
    *e-- = tmp;
  }
}
```