ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<link>:
  endbr64
  movslq %esi,%rax
  mov    %edi,(%rdx,%rax,4)
  test   %edi,%edi
  js     L7
  movslq %edi,%rdi
  mov    %esi,(%rcx,%rdi,4)
L7:
  ret
```

assistant: ```c
void link(int v, int p, int *child, int *parent) {
  child[p] = v;
  if (v >= 0) {
    parent[v] = p;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<link>:
  endbr64
  movslq %esi,%rax
  mov    %edi,(%rdx,%rax,4)
  test   %edi,%edi
  js     L6
  movslq %edi,%rdi
  mov    %esi,(%rcx,%rdi,4)
L6:
  ret
```

assistant: ```c
void link(int v, int p, int *child, int *parent) {
  child[p] = v;
  if (v >= 0) {
    parent[v] = p;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<processor_step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L8
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <processor_fetch@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <processor_exec@plt>
  subl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x0,-0xc(%rbp)
  jg     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void processor_step(struct processor *p, int n) {
  for (; n > 0; n--) {
    processor_fetch(p);
    processor_exec(p);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<processor_step>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L8
L1:
  mov    %rbp,%rdi
  call   <processor_fetch@plt>
  mov    %rbp,%rdi
  call   <processor_exec@plt>
  sub    $0x1,%ebx
  jne    L1
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void processor_step(struct processor *p, int n) {
  for (; n > 0; n--) {
    processor_fetch(p);
    processor_exec(p);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<processor_step>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  call   <processor_fetch@plt>
  mov    %rbp,%rdi
  call   <processor_exec@plt>
  sub    $0x1,%ebx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void processor_step(struct processor *p, int n) {
  for (; n > 0; n--) {
    processor_fetch(p);
    processor_exec(p);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<processor_step>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdi
  call   <processor_fetch@plt>
  mov    %rbp,%rdi
  call   <processor_exec@plt>
  sub    $0x1,%ebx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void processor_step(struct processor *p, int n) {
  for (; n > 0; n--) {
    processor_fetch(p);
    processor_exec(p);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L0
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L16
L0:
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L32
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jne    L32
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L32:
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L16:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D27
type: string
name: read_data
arguments: data_tag: D0
type: string

tool: D30: %f

tool: D14: %.4f is positive

tool: D27: input is zero

tool: D0: %.4f is negative

assistant: ```c
int main() {
  float n;
  scanf("%f", &n);
  if (n > 0) {
    printf("%.4f is positive", n);
  } else {
    if (n == 0) {
      printf("input is zero");
    } else {
      printf("%.4f is negative", n);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  comiss D27(%rip),%xmm0
  ja     L24
  ucomiss D27(%rip),%xmm0
  jp     L15
  jne    L15
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L6
L24:
  cvtss2sd %xmm0,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L15:
  cvtss2sd %xmm0,%xmm0
  lea    D56(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: byte[4]
name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D56
datatype: string

tool: D1: %f

tool: {"D27": [0x00,0x00,0x00,0x00]}

tool: D16: input is zero

tool: D23: %.4f is positive

tool: D56: %.4f is negative

assistant: ```c
int main() {
  float n;
  scanf("%f", &n);
  if (n > 0) {
    printf("%.4f is positive", n);
  } else {
    if (n == 0) {
      printf("input is zero");
    } else {
      printf("%.4f is negative", n);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  ja     L29
  ucomiss %xmm1,%xmm0
  jp     L14
  jne    L14
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L7
L29:
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L7
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string

tool: D19: %f

tool: D14: input is zero

tool: D24: %.4f is negative

tool: D28: %.4f is positive

assistant: ```c
int main() {
  float n;
  scanf("%f", &n);
  if (n > 0) {
    printf("%.4f is positive", n);
  } else {
    if (n == 0) {
      printf("input is zero");
    } else {
      printf("%.4f is negative", n);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  ja     L25
  ucomiss %xmm1,%xmm0
  jp     L0
  jne    L0
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L20
L25:
  lea    D16(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L20
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D36
type: string
name: unpack_data
arguments: label: D16
type: string

tool: D28: %f

tool: D3: input is zero

tool: D36: %.4f is negative

tool: D16: %.4f is positive

assistant: ```c
int main() {
  float n;
  scanf("%f", &n);
  if (n > 0) {
    printf("%.4f is positive", n);
  } else {
    if (n == 0) {
      printf("input is zero");
    } else {
      printf("%.4f is negative", n);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_bitwise_and_numbers_in_range_v2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L4
  cmpl   $0x0,-0x28(%rbp)
  js     L4
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L73
L4:
  mov    $0xffffffff,%eax
  jmp    L24
L73:
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L76:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L27
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x28(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0x4(%rbp),%eax
  or     %eax,-0x18(%rbp)
  jmp    L23
L27:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x18(%rbp)
L23:
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    $0x1e,%eax
  jbe    L76
  mov    -0x18(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int find_bitwise_and_numbers_in_range_v2(int low, int high) {
  int all_and, bit, diff, power_two, low_bit, high_bit;
  if ((low < 0) || (high < 0) || (low > high)) {
    return (~0);
  }
  diff = high - low + 1;
  all_and = 0;
  for (bit = 0; bit < ((sizeof(int) * 8) - 1); ++bit) {
    power_two = 1 << bit;
    if (power_two >= diff) {
      low_bit = low & (1 << bit);
      high_bit = high & (1 << bit);
      all_and |= low_bit & high_bit;
    } else {
      all_and &= ~(1 << bit);
    }
  }
  return (all_and);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_bitwise_and_numbers_in_range_v2>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  js     L15
  cmp    %esi,%edi
  jg     L15
  mov    %esi,%r9d
  sub    %edi,%r9d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%r8d
  and    %esi,%edi
  jmp    L35
L49:
  not    %eax
  and    %eax,%edx
L33:
  add    $0x1,%ecx
  cmp    $0x1f,%ecx
  je     L59
L35:
  mov    %r8d,%eax
  shl    %cl,%eax
  cmp    %eax,%r9d
  jge    L49
  and    %edi,%eax
  or     %eax,%edx
  jmp    L33
L15:
  mov    $0xffffffff,%edx
L59:
  mov    %edx,%eax
  ret
```

assistant: ```c
int find_bitwise_and_numbers_in_range_v2(int low, int high) {
  int all_and, bit, diff, power_two, low_bit, high_bit;
  if ((low < 0) || (high < 0) || (low > high)) {
    return (~0);
  }
  diff = high - low + 1;
  all_and = 0;
  for (bit = 0; bit < ((sizeof(int) * 8) - 1); ++bit) {
    power_two = 1 << bit;
    if (power_two >= diff) {
      low_bit = low & (1 << bit);
      high_bit = high & (1 << bit);
      all_and |= low_bit & high_bit;
    } else {
      all_and &= ~(1 << bit);
    }
  }
  return (all_and);
}
```
user: What is the c source code of the assembly code below:

```asm
<find_bitwise_and_numbers_in_range_v2>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  js     L41
  cmp    %esi,%edi
  jg     L41
  mov    %esi,%r9d
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  sub    %edi,%r9d
  and    %esi,%edi
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L35:
  and    %edi,%eax
  add    $0x1,%ecx
  or     %eax,%r8d
  cmp    $0x1f,%ecx
  je     L38
L67:
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %eax,%r9d
  jl     L35
  not    %eax
  add    $0x1,%ecx
  and    %eax,%r8d
  cmp    $0x1f,%ecx
  jne    L67
L38:
  mov    %r8d,%eax
  ret
L41:
  mov    $0xffffffff,%r8d
  jmp    L38
```

assistant: ```c
int find_bitwise_and_numbers_in_range_v2(int low, int high) {
  int all_and, bit, diff, power_two, low_bit, high_bit;
  if ((low < 0) || (high < 0) || (low > high)) {
    return (~0);
  }
  diff = high - low + 1;
  all_and = 0;
  for (bit = 0; bit < ((sizeof(int) * 8) - 1); ++bit) {
    power_two = 1 << bit;
    if (power_two >= diff) {
      low_bit = low & (1 << bit);
      high_bit = high & (1 << bit);
      all_and |= low_bit & high_bit;
    } else {
      all_and &= ~(1 << bit);
    }
  }
  return (all_and);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_bitwise_and_numbers_in_range_v2>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  js     L57
  cmp    %esi,%edi
  jg     L57
  mov    %esi,%r9d
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%edx
  sub    %edi,%r9d
  and    %esi,%edi
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L25:
  and    %edi,%eax
  add    $0x1,%ecx
  or     %eax,%r8d
  cmp    $0x1f,%ecx
  je     L6
L3:
  mov    %edx,%eax
  shl    %cl,%eax
  cmp    %eax,%r9d
  jl     L25
  not    %eax
  add    $0x1,%ecx
  and    %eax,%r8d
  cmp    $0x1f,%ecx
  jne    L3
L6:
  mov    %r8d,%eax
  ret
L57:
  mov    $0xffffffff,%r8d
  jmp    L6
```

assistant: ```c
int find_bitwise_and_numbers_in_range_v2(int low, int high) {
  int all_and, bit, diff, power_two, low_bit, high_bit;
  if ((low < 0) || (high < 0) || (low > high)) {
    return (~0);
  }
  diff = high - low + 1;
  all_and = 0;
  for (bit = 0; bit < ((sizeof(int) * 8) - 1); ++bit) {
    power_two = 1 << bit;
    if (power_two >= diff) {
      low_bit = low & (1 << bit);
      high_bit = high & (1 << bit);
      all_and |= low_bit & high_bit;
    } else {
      all_and &= ~(1 << bit);
    }
  }
  return (all_and);
}
```
user: What is the c source code of the assembly code below:

```asm
<criaVetorAleatorio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x1869f,-0x4(%rbp)
  jle    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void criaVetorAleatorio(int *vetor) {
  int i;
  srand(time(NULL));
  for (i = 0; i < 100000; i++) {
    vetor[i] = rand() % 100;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<criaVetorAleatorio>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rbp,%rbx
  add    $0x61a80,%rbp
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void criaVetorAleatorio(int *vetor) {
  int i;
  srand(time(NULL));
  for (i = 0; i < 100000; i++) {
    vetor[i] = rand() % 100;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<criaVetorAleatorio>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  lea    0x61a80(%rbp),%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void criaVetorAleatorio(int *vetor) {
  int i;
  srand(time(NULL));
  for (i = 0; i < 100000; i++) {
    vetor[i] = rand() % 100;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<criaVetorAleatorio>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  lea    0x61a80(%rbp),%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void criaVetorAleatorio(int *vetor) {
  int i;
  srand(time(NULL));
  for (i = 0; i < 100000; i++) {
    vetor[i] = rand() % 100;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<S0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L19
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double S0(double data[], int nn[]) {
  int i;
  double Ssum = 0;
  for (i = 0; i < nn[0] * nn[1]; i++)
    Ssum += data[i];
  return Ssum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<S0>:
  endbr64
  mov    (%rsi),%edx
  imul   0x4(%rsi),%edx
  test   %edx,%edx
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L7:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L7
  ret
L13:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double S0(double data[], int nn[]) {
  int i;
  double Ssum = 0;
  for (i = 0; i < nn[0] * nn[1]; i++)
    Ssum += data[i];
  return Ssum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<S0>:
  endbr64
  mov    (%rsi),%eax
  imul   0x4(%rsi),%eax
  test   %eax,%eax
  jle    L15
  sub    $0x1,%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L16:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L16
  ret
  xchg   %ax,%ax
L15:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double S0(double data[], int nn[]) {
  int i;
  double Ssum = 0;
  for (i = 0; i < nn[0] * nn[1]; i++)
    Ssum += data[i];
  return Ssum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<S0>:
  endbr64
  mov    (%rsi),%edx
  imul   0x4(%rsi),%edx
  test   %edx,%edx
  jle    L3
  cmp    $0x1,%edx
  je     L2
  mov    %edx,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L22:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L22
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L38
L4:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax)
L38:
  ret
  nopl   0x0(%rax)
L3:
  pxor   %xmm0,%xmm0
  ret
L2:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L4
```

assistant: ```c
double S0(double data[], int nn[]) {
  int i;
  double Ssum = 0;
  for (i = 0; i < nn[0] * nn[1]; i++)
    Ssum += data[i];
  return Ssum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trio_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int trio_copy(char *target, const char *source) {
  assert(target);
  assert(source);
  (void)strcpy(target, source);
  return (!(1 == 0));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trio_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int trio_copy(char *target, const char *source) {
  assert(target);
  assert(source);
  (void)strcpy(target, source);
  return (!(1 == 0));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trio_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int trio_copy(char *target, const char *source) {
  assert(target);
  assert(source);
  (void)strcpy(target, source);
  return (!(1 == 0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trio_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int trio_copy(char *target, const char *source) {
  assert(target);
  assert(source);
  (void)strcpy(target, source);
  return (!(1 == 0));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x64,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: Usage: %s -i <input video> -o <output video> [ -x <output x resolution> ] [ -y <output y resolution> ] [ -s <random seed> ] [ -sp <salt and pepper %d-%d> ] 


assistant: ```c
void print_help(const char *prg) {
  printf("Usage: %s -i <input video> -o <output video> "
         "[ -x <output x resolution> ] "
         "[ -y <output y resolution> ] "
         "[ -s <random seed> ] "
         "[ -sp <salt and pepper %d-%d> ] "
         "\n",
         prg, 1, 100);
}
```