ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix_multiplication>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,-0x4(%rsp)
  mov    %r9d,-0x8(%rsp)
  mov    0x38(%rsp),%ebx
  test   %ecx,%ecx
  jle    L47
  mov    %rdi,%r14
  mov    %rsi,%r11
  mov    %rdx,%r12
  mov    %r8d,%ebp
  movslq %ecx,%rsi
  shl    $0x3,%rsi
  mov    $0x0,%r15d
  lea    -0x1(%r8),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rdx),%r13
  jmp    L28
L48:
  mov    %r8,%rcx
  movq   $0x0,(%r8)
  test   %ebp,%ebp
  jle    L33
  movslq %r10d,%rdx
  lea    (%r12,%rdx,8),%rax
  add    -0x10(%rsp),%rdx
  lea    0x0(%r13,%rdx,8),%rdi
  mov    %r11,%rdx
L67:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L67
L33:
  add    $0x1,%r9d
  add    %rsi,%r8
  add    -0x8(%rsp),%r10d
  cmp    %r9d,%ebx
  jne    L48
L37:
  add    $0x1,%r15d
  add    $0x8,%r14
  add    $0x8,%r11
  cmp    %r15d,-0x4(%rsp)
  je     L47
L28:
  mov    %r14,%r8
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  test   %ebx,%ebx
  jg     L48
  jmp    L37
L47:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int matrix_multiplication(double *output, double *A, double *B, int row_a, int col_a, int row_b, int col_b) {
  int i, j, k;
  for (i = 0; i < row_a; i++) {
    for (j = 0; j < col_b; j++) {
      output[i + j * row_a] = 0;
      for (k = 0; k < col_a; k++) {
        output[i + j * row_a] = output[i + j * row_a] + (A[i + k * row_a] * B[k + j * row_b]);
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_multiplication>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  mov    %ecx,-0x4(%rsp)
  test   %ecx,%ecx
  jle    L4
  mov    %rsi,%r10
  movslq %ecx,%rsi
  mov    %rdi,%r15
  mov    %rdx,%r12
  mov    %r8d,%ebx
  mov    %r9d,%ebp
  shl    $0x3,%rsi
  pxor   %xmm2,%xmm2
  movl   $0x0,-0x8(%rsp)
  lea    -0x1(%r8),%r14d
  lea    0x8(%rdx),%r13
  nopl   0x0(%rax)
L31:
  mov    %r15,%rcx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  test   %r11d,%r11d
  jle    L25
  xchg   %ax,%ax
L58:
  movq   $0x0,(%rcx)
  test   %ebx,%ebx
  jle    L30
  movslq %r9d,%rdx
  movapd %xmm2,%xmm1
  lea    (%r12,%rdx,8),%rax
  add    %r14,%rdx
  lea    0x0(%r13,%rdx,8),%rdi
  mov    %r10,%rdx
  nopl   0x0(%rax)
L29:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdi
  jne    L29
L30:
  add    $0x1,%r8d
  add    %rsi,%rcx
  add    %ebp,%r9d
  cmp    %r8d,%r11d
  jne    L58
L25:
  addl   $0x1,-0x8(%rsp)
  add    $0x8,%r10
  mov    -0x8(%rsp),%eax
  add    $0x8,%r15
  cmp    %eax,-0x4(%rsp)
  jne    L31
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int matrix_multiplication(double *output, double *A, double *B, int row_a, int col_a, int row_b, int col_b) {
  int i, j, k;
  for (i = 0; i < row_a; i++) {
    for (j = 0; j < col_b; j++) {
      output[i + j * row_a] = 0;
      for (k = 0; k < col_a; k++) {
        output[i + j * row_a] = output[i + j * row_a] + (A[i + k * row_a] * B[k + j * row_b]);
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_multiplication>:
  endbr64
  movslq %ecx,%rax
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%ebp
  test   %eax,%eax
  jle    L24
  test   %ebp,%ebp
  jle    L24
  mov    %rax,-0x8(%rsp)
  mov    %rsi,%r10
  mov    %rdi,%r15
  mov    %rdx,%r12
  mov    %r8d,%r11d
  pxor   %xmm2,%xmm2
  lea    -0x1(%r8),%r14d
  mov    %r9d,%ebx
  movq   $0x0,-0x10(%rsp)
  lea    0x0(,%rax,8),%rsi
  lea    0x8(%rdx),%r13
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r15,%rcx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L1:
  movq   $0x0,(%rcx)
  test   %r11d,%r11d
  jle    L53
  movslq %r9d,%rdx
  movapd %xmm2,%xmm1
  lea    (%r12,%rdx,8),%rax
  add    %r14,%rdx
  lea    0x0(%r13,%rdx,8),%rdi
  mov    %r10,%rdx
  nopw   0x0(%rax,%rax,1)
L44:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdi
  jne    L44
L53:
  add    $0x1,%r8d
  add    %rsi,%rcx
  add    %ebx,%r9d
  cmp    %r8d,%ebp
  jne    L1
  addq   $0x1,-0x10(%rsp)
  add    $0x8,%r15
  mov    -0x10(%rsp),%rax
  add    $0x8,%r10
  cmp    -0x8(%rsp),%rax
  jne    L33
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int matrix_multiplication(double *output, double *A, double *B, int row_a, int col_a, int row_b, int col_b) {
  int i, j, k;
  for (i = 0; i < row_a; i++) {
    for (j = 0; j < col_b; j++) {
      output[i + j * row_a] = 0;
      for (k = 0; k < col_a; k++) {
        output[i + j * row_a] = output[i + j * row_a] + (A[i + k * row_a] * B[k + j * row_b]);
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L4
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L23
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D16
type: string

tool: D8: %d

tool: D16: sum=%.5lf


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, i;
  double sum = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    sum += 1 / fact(i);
  }
  printf("sum=%.5lf\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L9
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
  mov    $0x1,%ebx
  mov    $0x1,%ebp
L18:
  mov    %ebx,%edi
  call   <fact@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jge    L18
L0:
  movsd  0x8(%rsp),%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L0
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D18
type: string

tool: D7: %d

tool: D18: sum=%.5lf


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, i;
  double sum = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    sum += 1 / fact(i);
  }
  printf("sum=%.5lf\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L20
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L6:
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  call   <fact@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %ebx,0x14(%rsp)
  jge    L6
L20:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D19
data_type: string

tool: D13: %d

tool: D19: sum=%.5lf


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, i;
  double sum = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    sum += 1 / fact(i);
  }
  printf("sum=%.5lf\n", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L24
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L25:
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  call   <fact@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %ebx,0x14(%rsp)
  jge    L25
L24:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D15: %d

tool: D10: sum=%.5lf


assistant: ```c
int main(int argc, const char *argv[]) {
  int n, i;
  double sum = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    sum += 1 / fact(i);
  }
  printf("sum=%.5lf\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcsdealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void wcsdealloc(void *ptr) {
  free(ptr);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcsdealloc>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wcsdealloc(void *ptr) {
  free(ptr);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcsdealloc>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void wcsdealloc(void *ptr) {
  free(ptr);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcsdealloc>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void wcsdealloc(void *ptr) {
  free(ptr);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ZOLu33026715730109_br_find_bin_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <ZOLu33026715730109_br_find_prefix@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L27
L28:
  mov    $0x0,%eax
  jmp    L27
L2:
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ZOLu33026715730109_br_build_path@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: bin

assistant: ```c
char *ZOLu33026715730109_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = ZOLu33026715730109_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = ZOLu33026715730109_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: What is the c source code of the assembly code below?

```asm
<ZOLu33026715730109_br_find_bin_dir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%edi
  call   <ZOLu33026715730109_br_find_prefix@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <ZOLu33026715730109_br_build_path@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <free@plt>
L24:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %rbp,%r12
  test   %rbp,%rbp
  je     L24
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: bin

assistant: ```c
char *ZOLu33026715730109_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = ZOLu33026715730109_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = ZOLu33026715730109_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ZOLu33026715730109_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <ZOLu33026715730109_br_find_prefix@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <ZOLu33026715730109_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  test   %r12,%r12
  je     L6
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L6:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: bin

assistant: ```c
char *ZOLu33026715730109_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = ZOLu33026715730109_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = ZOLu33026715730109_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: What is the c source code of the assembly code below:

```asm
<ZOLu33026715730109_br_find_bin_dir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <ZOLu33026715730109_br_find_prefix@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbp
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <ZOLu33026715730109_br_build_path@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  test   %r12,%r12
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax)
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: bin

assistant: ```c
char *ZOLu33026715730109_br_find_bin_dir(const char *default_bin_dir) {
  char *prefix, *dir;
  prefix = ZOLu33026715730109_br_find_prefix((const char *)((char *)0));
  if (prefix == (char *)((char *)0)) {
    if (default_bin_dir != (const char *)((char *)0))
      return strdup(default_bin_dir);
    else
      return (char *)((char *)0);
  }
  dir = ZOLu33026715730109_br_build_path(prefix, "bin");
  free(prefix);
  return dir;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pthread_attr_setscope>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pthread_attr_setscope(pthread_attr_t *attr, int scope) {
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pthread_attr_setscope>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int pthread_attr_setscope(pthread_attr_t *attr, int scope) {
  ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pthread_attr_setscope>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pthread_attr_setscope(pthread_attr_t *attr, int scope) {
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pthread_attr_setscope>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int pthread_attr_setscope(pthread_attr_t *attr, int scope) {
  ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L33:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  cmp    %rax,-0x28(%rbp)
  jbe    L24
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  jmp    L24
L31:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L24:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  cmp    %rax,-0x28(%rbp)
  ja     L31
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  size_t i = 0;
  char *str = dest;
  while (i++ < n && (*dest++ = *src++))
    ;
  while (i++ < n)
    *dest++ = '\0';
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  lea    (%rdi,%rdx,1),%r10
  mov    %rdi,%r8
  mov    $0x0,%ecx
L12:
  mov    %rcx,%r11
  add    $0x1,%rcx
  cmp    %r10,%r8
  je     L5
  add    $0x1,%r8
  movzbl -0x1(%rsi,%rcx,1),%r9d
  mov    %r9b,-0x1(%r8)
  test   %r9b,%r9b
  jne    L12
  mov    %r8,%r10
L5:
  mov    %r10,%rsi
  cmp    %rdx,%rcx
  jae    L1
L30:
  add    $0x1,%rsi
  movb   $0x0,-0x1(%rsi)
  lea    0x1(%rsi,%r11,1),%rcx
  sub    %r10,%rcx
  cmp    %rcx,%rdx
  ja     L30
  ret
L1:
  ret
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  size_t i = 0;
  char *str = dest;
  while (i++ < n && (*dest++ = *src++))
    ;
  while (i++ < n)
    *dest++ = '\0';
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncpy>:
  endbr64
  push   %r12
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%r12
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L7
  nopl   0x0(%rax)
L37:
  movzbl -0x1(%rsi,%rax,1),%edi
  add    $0x1,%rcx
  mov    %dil,-0x1(%rcx)
  test   %dil,%dil
  je     L5
L7:
  mov    %rax,%r9
  add    $0x1,%rax
  cmp    %r8,%rcx
  jne    L37
L11:
  lea    0x2(%r9),%rcx
  cmp    %rdx,%rax
  jae    L20
  lea    -0x1(%rdx),%r10
  mov    $0x1,%eax
  mov    %r8,%rdi
  sub    %r9,%r10
  cmp    %rcx,%rdx
  cmovb  %rax,%r10
  xor    %esi,%esi
  mov    %r10,%rdx
  call   <memset@plt>
L20:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L5:
  mov    %rcx,%r8
  jmp    L11
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  size_t i = 0;
  char *str = dest;
  while (i++ < n && (*dest++ = *src++))
    ;
  while (i++ < n)
    *dest++ = '\0';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncpy>:
  endbr64
  push   %r12
  lea    (%rdi,%rdx,1),%r9
  mov    %rdi,%r12
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax)
L13:
  movzbl -0x1(%rsi,%rax,1),%edi
  add    $0x1,%rcx
  mov    %dil,-0x1(%rcx)
  test   %dil,%dil
  je     L43
L5:
  mov    %rax,%r8
  add    $0x1,%rax
  cmp    %r9,%rcx
  jne    L13
L48:
  cmp    %rdx,%rax
  jae    L33
  lea    -0x1(%rdx),%r10
  mov    $0x1,%eax
  mov    %r9,%rdi
  sub    %r8,%r10
  add    $0x2,%r8
  cmp    %r8,%rdx
  cmovb  %rax,%r10
  xor    %esi,%esi
  mov    %r10,%rdx
  call   <memset@plt>
L33:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L43:
  mov    %rcx,%r9
  jmp    L48
```

assistant: ```c
char *strncpy(char *dest, const char *src, size_t n) {
  size_t i = 0;
  char *str = dest;
  while (i++ < n && (*dest++ = *src++))
    ;
  while (i++ < n)
    *dest++ = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void t() {
  int a, b, c[10];
#pragma acc update self(a) if_present
#pragma acc update device(b) async if_present
#pragma acc update host(c [1:3]) wait(4) if_present
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5) if_present
#pragma acc update self(a)
#pragma acc update device(b) async
#pragma acc update host(c [1:3]) wait(4)
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5)
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t>:
  endbr64
  ret
```

assistant: ```c
void t() {
  int a, b, c[10];
#pragma acc update self(a) if_present
#pragma acc update device(b) async if_present
#pragma acc update host(c [1:3]) wait(4) if_present
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5) if_present
#pragma acc update self(a)
#pragma acc update device(b) async
#pragma acc update host(c [1:3]) wait(4)
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5)
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t>:
  endbr64
  ret
```

assistant: ```c
void t() {
  int a, b, c[10];
#pragma acc update self(a) if_present
#pragma acc update device(b) async if_present
#pragma acc update host(c [1:3]) wait(4) if_present
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5) if_present
#pragma acc update self(a)
#pragma acc update device(b) async
#pragma acc update host(c [1:3]) wait(4)
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5)
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<t>:
  endbr64
  ret
```

assistant: ```c
void t() {
  int a, b, c[10];
#pragma acc update self(a) if_present
#pragma acc update device(b) async if_present
#pragma acc update host(c [1:3]) wait(4) if_present
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5) if_present
#pragma acc update self(a)
#pragma acc update device(b) async
#pragma acc update host(c [1:3]) wait(4)
#pragma acc update self(c) device(b) host(a) async(10) if (a == 5)
}
```