ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<handleconn>:
  endbr64
  push   %r15
  mov    $0x7e,%ecx
  xor    %edx,%edx
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x400,%ebx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x418(%rsp)
  movabs $0x203a676f6c737973,%rax
  lea    0x20(%rsp),%rdi
  lea    0x10(%rsp),%rbp
  mov    %rdx,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%r15
  sub    %r15d,%ebx
  mov    %r15,%r12
  mov    %ebx,0xc(%rsp)
  xor    %ebx,%ebx
  jmp    L26
  nopl   0x0(%rax)
L22:
  add    %eax,%ebx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    %ebx,%ecx
  call   <shiftwrite@plt>
  cmp    $0x384,%eax
  jg     L9
L26:
  mov    0xc(%rsp),%edx
  movslq %ebx,%rsi
  mov    %r14d,%edi
  add    %r15,%rsi
  sub    %ebx,%edx
  add    %rbp,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L22
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <shiftwrite@plt>
L9:
  mov    0x418(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x428,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void handleconn(int infd, int outfd) {
  char buf[1024] = "syslog: ";
  int tag = strlen(buf);
  char *rdbuf = buf + tag;
  int rdlen = 1024 - tag;
  int rdptr = 0, rdnew;
  int rd;
  while ((rd = read(infd, rdbuf + rdptr, rdlen - rdptr)) > 0) {
    rdptr += rd;
    rdnew = shiftwrite(outfd, buf, tag, rdptr);
    if (rdnew > 900)
      return;
  };
  shiftwrite(outfd, buf, tag, rdptr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_real>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    D2(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L51
L2:
  mov    $0x0,%eax
  jmp    L32
L51:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    $0x0,%eax
  jmp    L32
L23:
  mov    $0x1,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int is_real(const char *cstr, double *d) {
  char *endptr;
  endptr = NULL;
  errno = 0;
  *d = strtod(cstr, &endptr);
  if (errno || (endptr == cstr))
    return 0;
  else if (*endptr != '\0')
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_real>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    D6(%rip),%r12
  movq   $0x0,(%r12)
  mov    %rsp,%rsi
  call   <strtod@plt>
  movsd  %xmm0,0x0(%rbp)
  mov    $0x0,%eax
  cmpq   $0x0,(%r12)
  jne    L0
  mov    (%rsp),%rax
  cmp    %rbx,%rax
  je     L29
  cmpb   $0x0,(%rax)
  sete   %al
  movzbl %al,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x0,%eax
  jmp    L0
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_real(const char *cstr, double *d) {
  char *endptr;
  endptr = NULL;
  errno = 0;
  *d = strtod(cstr, &endptr);
  if (errno || (endptr == cstr))
    return 0;
  else if (*endptr != '\0')
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_real>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D3(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  movq   $0x0,(%r12)
  call   <strtod@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%r12)
  movsd  %xmm0,0x0(%rbp)
  jne    L6
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L6
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  sete   %al
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_real(const char *cstr, double *d) {
  char *endptr;
  endptr = NULL;
  errno = 0;
  *d = strtod(cstr, &endptr);
  if (errno || (endptr == cstr))
    return 0;
  else if (*endptr != '\0')
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_real>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    D6(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  movq   $0x0,(%r12)
  call   <strtod@plt>
  xor    %eax,%eax
  cmpq   $0x0,(%r12)
  movsd  %xmm0,0x0(%rbp)
  jne    L3
  mov    (%rsp),%rdx
  cmp    %rbx,%rdx
  je     L3
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  sete   %al
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_real(const char *cstr, double *d) {
  char *endptr;
  endptr = NULL;
  errno = 0;
  *d = strtod(cstr, &endptr);
  if (errno || (endptr == cstr))
    return 0;
  else if (*endptr != '\0')
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fiat_secp256k1_msat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0xfffffc2f,%edi
  call   <UINT64_C@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rbx
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  lea    0xc(%rax),%rbx
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movl   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fiat_secp256k1_msat(uint64_t out1[5]) {
  out1[0] = UINT64_C(0xfffffffefffffc2f);
  out1[1] = UINT64_C(0xffffffffffffffff);
  out1[2] = UINT64_C(0xffffffffffffffff);
  out1[3] = UINT64_C(0xffffffffffffffff);
  out1[4] = 0x0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fiat_secp256k1_msat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xfffffc2f,%edi
  call   <UINT64_C@plt>
  mov    %eax,(%rbx)
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,0x4(%rbx)
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,0x8(%rbx)
  mov    $0xffffffff,%edi
  call   <UINT64_C@plt>
  mov    %eax,0xc(%rbx)
  movl   $0x0,0x10(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fiat_secp256k1_msat(uint64_t out1[5]) {
  out1[0] = UINT64_C(0xfffffffefffffc2f);
  out1[1] = UINT64_C(0xffffffffffffffff);
  out1[2] = UINT64_C(0xffffffffffffffff);
  out1[3] = UINT64_C(0xffffffffffffffff);
  out1[4] = 0x0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fiat_secp256k1_msat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xfffffc2f,%edi
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,(%rbx)
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,0x4(%rbx)
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,0x8(%rbx)
  call   <UINT64_C@plt>
  movl   $0x0,0x10(%rbx)
  mov    %eax,0xc(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fiat_secp256k1_msat(uint64_t out1[5]) {
  out1[0] = UINT64_C(0xfffffffefffffc2f);
  out1[1] = UINT64_C(0xffffffffffffffff);
  out1[2] = UINT64_C(0xffffffffffffffff);
  out1[3] = UINT64_C(0xffffffffffffffff);
  out1[4] = 0x0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fiat_secp256k1_msat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xfffffc2f,%edi
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,(%rbx)
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,0x4(%rbx)
  call   <UINT64_C@plt>
  mov    $0xffffffff,%edi
  mov    %eax,0x8(%rbx)
  call   <UINT64_C@plt>
  movl   $0x0,0x10(%rbx)
  mov    %eax,0xc(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void fiat_secp256k1_msat(uint64_t out1[5]) {
  out1[0] = UINT64_C(0xfffffffefffffc2f);
  out1[1] = UINT64_C(0xffffffffffffffff);
  out1[2] = UINT64_C(0xffffffffffffffff);
  out1[3] = UINT64_C(0xffffffffffffffff);
  out1[4] = 0x0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ctrls_sample_pan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x8,%edi
  call   <ctrls_value@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x7,%edi
  call   <ctrls_value@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  movsd  D15(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: f64
name: retrieve_data
arguments: tag: D15
type_infered: byte[8]

tool: D5: 87

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x35,0x40]}

assistant: ```c
double ctrls_sample_pan(int key) {
  double panHigh = ctrls_value(8);
  double panLow = ctrls_value(7);
  double m = (panHigh - panLow) / 87.0;
  return panLow + m * ((double)key - 21);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ctrls_sample_pan>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x8,%edi
  call   <ctrls_value@plt>
  movq   %xmm0,%rbx
  mov    $0x7,%edi
  call   <ctrls_value@plt>
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  subsd  D2(%rip),%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm2,%xmm0
  divsd  D16(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D16
data_type: f64

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x35,0x40]}

tool: D16: 87

assistant: ```c
double ctrls_sample_pan(int key) {
  double panHigh = ctrls_value(8);
  double panLow = ctrls_value(7);
  double m = (panHigh - panLow) / 87.0;
  return panLow + m * ((double)key - 21);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctrls_sample_pan>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  sub    $0x10,%rsp
  call   <ctrls_value@plt>
  mov    $0x7,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <ctrls_value@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %ebx,%xmm1
  subsd  D0(%rip),%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  divsd  D19(%rip),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: byte[8]
name: unpack_data
arguments: label: D19
datatype: f64

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x35,0x40]}

tool: D19: 87

assistant: ```c
double ctrls_sample_pan(int key) {
  double panHigh = ctrls_value(8);
  double panLow = ctrls_value(7);
  double m = (panHigh - panLow) / 87.0;
  return panLow + m * ((double)key - 21);
}
```
user: What is the c source code of the assembly code below?

```asm
<ctrls_sample_pan>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  sub    $0x10,%rsp
  call   <ctrls_value@plt>
  mov    $0x7,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <ctrls_value@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %ebx,%xmm1
  subsd  D0(%rip),%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  divsd  D5(%rip),%xmm2
  add    $0x10,%rsp
  pop    %rbx
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: byte[8]
name: disassemble_data
arguments: tag: D5
data_type: f64

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x35,0x40]}

tool: D5: 87

assistant: ```c
double ctrls_sample_pan(int key) {
  double panHigh = ctrls_value(8);
  double panLow = ctrls_value(7);
  double m = (panHigh - panLow) / 87.0;
  return panLow + m * ((double)key - 21);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%ebp
  jmp    L16
L66:
  sub    $0x1,%ebp
  je     L108
L16:
  mov    $0x32,%ebx
L26:
  mov    $0x0,%eax
  call   <rand@plt>
  sub    $0x1,%ebx
  jne    L26
  jmp    L66
L108:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%edx
  jmp    L27
L17:
  sub    $0x1,%edx
  je     L103
L27:
  mov    $0x32,%eax
L76:
  sub    $0x1,%eax
  jne    L76
  jmp    L17
L103:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    $0x32,%edi
  jmp    L119
L106:
  add    $0x1,%edx
  cmp    $0x32,%edx
  je     L139
L13:
  cmp    %edx,%ecx
  je     L106
  mov    $0x32,%eax
L133:
  sub    $0x1,%eax
  jne    L133
  jmp    L106
L139:
  sub    $0x1,%esi
  je     L40
L119:
  mov    $0x32,%eax
L81:
  sub    $0x1,%eax
  jne    L81
  mov    $0x0,%edx
  mov    %edi,%ecx
  sub    %esi,%ecx
  jmp    L13
L40:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D39: sched_tc5: invert_matrix: before first matrix inversion


tool: D11: sched_tc5: invert_matrix: before second matrix inversion


tool: D3: sched_tc5: invert_matrix: before form identity matrix


tool: D15: sched_tc5: invert_matrix: after form identity matrix


assistant: ```c
void invert_matrix() {
  int i, j, k;
  float t1;
  float matrix_1[50][50];
  float matrix_2[50][50];
  printf("sched_tc5: invert_matrix: before first matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] = (float)(rand() % 100);
    }
  printf("sched_tc5: invert_matrix: before second matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++)
      if (i == j)
        matrix_2[i][j] = 1;
      else
        matrix_2[i][j] = 0;
  printf("sched_tc5: invert_matrix: before form identity matrix\n");
  for (i = 0; i < 50; i++) {
    t1 = matrix_1[i][j];
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] /= t1;
      matrix_2[i][j] /= t1;
    }
    for (j = 0; j < 50; j++)
      if (i != j) {
        t1 = -matrix_1[j][i];
        for (k = 0; k < 50; k++) {
          matrix_1[j][k] += (matrix_1[i][k] * t1);
          matrix_2[j][k] += (matrix_2[i][k] * t1);
        }
      }
  }
  printf("sched_tc5: invert_matrix: after form identity matrix\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  mov    $0x32,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x32,%ebx
  nopl   (%rax)
L2:
  xor    %eax,%eax
  call   <rand@plt>
  sub    $0x1,%ebx
  jne    L2
  sub    $0x1,%ebp
  jne    L17
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D33
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: string

tool: D33: sched_tc5: invert_matrix: before first matrix inversion


tool: D12: sched_tc5: invert_matrix: before second matrix inversion


tool: D14: sched_tc5: invert_matrix: before form identity matrix


tool: D0: sched_tc5: invert_matrix: after form identity matrix


assistant: ```c
void invert_matrix() {
  int i, j, k;
  float t1;
  float matrix_1[50][50];
  float matrix_2[50][50];
  printf("sched_tc5: invert_matrix: before first matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] = (float)(rand() % 100);
    }
  printf("sched_tc5: invert_matrix: before second matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++)
      if (i == j)
        matrix_2[i][j] = 1;
      else
        matrix_2[i][j] = 0;
  printf("sched_tc5: invert_matrix: before form identity matrix\n");
  for (i = 0; i < 50; i++) {
    t1 = matrix_1[i][j];
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] /= t1;
      matrix_2[i][j] /= t1;
    }
    for (j = 0; j < 50; j++)
      if (i != j) {
        t1 = -matrix_1[j][i];
        for (k = 0; k < 50; k++) {
          matrix_1[j][k] += (matrix_1[i][k] * t1);
          matrix_2[j][k] += (matrix_2[i][k] * t1);
        }
      }
  }
  printf("sched_tc5: invert_matrix: after form identity matrix\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invert_matrix>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  mov    $0x32,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x32,%ebx
  nopl   (%rax)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  sub    $0x1,%ebx
  jne    L6
  sub    $0x1,%ebp
  jne    L12
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D12(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D35
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D1: sched_tc5: invert_matrix: before first matrix inversion


tool: D35: sched_tc5: invert_matrix: before second matrix inversion


tool: D25: sched_tc5: invert_matrix: before form identity matrix


tool: D12: sched_tc5: invert_matrix: after form identity matrix


assistant: ```c
void invert_matrix() {
  int i, j, k;
  float t1;
  float matrix_1[50][50];
  float matrix_2[50][50];
  printf("sched_tc5: invert_matrix: before first matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] = (float)(rand() % 100);
    }
  printf("sched_tc5: invert_matrix: before second matrix inversion\n");
  for (i = 0; i < 50; i++)
    for (j = 0; j < 50; j++)
      if (i == j)
        matrix_2[i][j] = 1;
      else
        matrix_2[i][j] = 0;
  printf("sched_tc5: invert_matrix: before form identity matrix\n");
  for (i = 0; i < 50; i++) {
    t1 = matrix_1[i][j];
    for (j = 0; j < 50; j++) {
      matrix_1[i][j] /= t1;
      matrix_2[i][j] /= t1;
    }
    for (j = 0; j < 50; j++)
      if (i != j) {
        t1 = -matrix_1[j][i];
        for (k = 0; k < 50; k++) {
          matrix_1[j][k] += (matrix_1[i][k] * t1);
          matrix_2[j][k] += (matrix_2[i][k] * t1);
        }
      }
  }
  printf("sched_tc5: invert_matrix: after form identity matrix\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6568,-0xe(%rbp)
  movw   $0x6f,-0xa(%rbp)
  movl   $0xffffffc9,-0x18(%rbp)
  movss  D23(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm3,%xmm3
  cvtss2sd -0x14(%rbp),%xmm3
  movq   %xmm3,%rdx
  mov    -0x18(%rbp),%ecx
  lea    -0xe(%rbp),%rax
  mov    %ecx,%r8d
  mov    $0x78,%ecx
  movq   %rdx,%xmm0
  mov    %rax,%rdx
  mov    $0xd,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0x14(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x14(%rbp),%xmm4
  movq   %xmm4,%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_guessed: f32
name: extract_symbolic_data
arguments: tag: D35
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D39
type_guessed: string

tool: D23: 12.3456789

tool: D35: Some values: %d, "%s", %f, '%c', and %d.


tool: D3: Variable precision: 1: %1f, 2: %2f, 3: %3f


tool: D39: A percent sign: %%.


assistant: ```c
int main() {
  const char foo[] = "hello";
  const int bar = -55;
  const float zip = 12.3456789;
  printf("Some values: %d, \"%s\", %f, '%c', and %d.\n", 13, foo, zip, 'x', bar);
  printf("Variable precision: 1: %1f, 2: %2f, 3: %3f\n", zip, zip, zip);
  printf("A percent sign: %%.\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6568,0x2(%rsp)
  movw   $0x6f,0x6(%rsp)
  lea    0x2(%rsp),%rdx
  mov    $0xffffffc9,%r8d
  mov    $0x78,%ecx
  mov    D40(%rip),%rax
  movq   %rax,%xmm0
  mov    $0xd,%esi
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D40(%rip),%rax
  movq   %rax,%xmm2
  movq   %rax,%xmm1
  movq   %rax,%xmm0
  lea    D29(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D40
type_guessed: byte[8]
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: {"D40": [0x00,0x00,0x00,0xe0,0xfc,0xb0,0x28,0x40]}

tool: D6: Some values: %d, "%s", %f, '%c', and %d.


tool: D29: Variable precision: 1: %1f, 2: %2f, 3: %3f


tool: D10: A percent sign: %%.


assistant: ```c
int main() {
  const char foo[] = "hello";
  const int bar = -55;
  const float zip = 12.3456789;
  printf("Some values: %d, \"%s\", %f, '%c', and %d.\n", 13, foo, zip, 'x', bar);
  printf("Variable precision: 1: %1f, 2: %2f, 3: %3f\n", zip, zip, zip);
  printf("A percent sign: %%.\n");
  return 0;
}
```