ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mk_dirs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L121:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L121
  sub    $0x118,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x100108(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  test   %rdi,%rdi
  je     L2
  lea    0x100(%rsp),%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L72
  sub    $0x1,%eax
  cltq
  cmpb   $0x2f,0x100(%rsp,%rax,1)
  je     L11
L72:
  mov    D33(%rip),%rbp
  mov    %rsp,%r13
L39:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L88
  mov    D15(%rip),%rax
  mov    D24(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L59
  mov    D46(%rip),%rdx
  cmp    (%rdx),%rax
  je     L88
  mov    D39(%rip),%rdx
  cmp    (%rdx),%rax
  je     L88
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L88
  mov    %eax,%edx
  mov    %r13,%rdi
  mov    %rbx,%rsi
  sub    %ebx,%edx
  call   <strncat@plt>
  mov    %r13,%rdi
  call   <mk_dirs>
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %r12d,%r12d
L88:
  mov    0x100108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x100118,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movb   $0x0,0x100(%rsp,%rax,1)
  jmp    L72
L2:
  mov    $0xffffffff,%r12d
  jmp    L88
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mk_dirs(char *path) {
  int ret;
  int len;
  char subpath[256] = "";
  char *pos = NULL;
  char pth[(1 * 1024 * 1024)];
  if (path == NULL) {
    return -1;
  }
  strcpy(pth, path);
  if ((len = strlen(pth)) > 0 && pth[len - 1] == '/') {
    pth[len - 1] = '\0';
  }
  while ((ret = mkdir(pth, S_IRWXU)) != 0) {
    if (errno == EEXIST) {
      return 0;
    } else if (errno == EACCES || errno == EROFS) {
      return ret;
    }
    if ((pos = strrchr(pth, '/')) == NULL) {
      return ret;
    }
    strncat(subpath, pth, pos - pth);
    mk_dirs(subpath);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L9
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L29:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: malloc failure

assistant: ```c
char *str_dup(const char *str) {
  char *str_new;
  if (!str)
    return (0);
  {
    if (!((str_new) = (char *)calloc((strlen(str) + 1), sizeof(char)))) {
      perror("malloc failure");
      abort();
    }
  };
  strcpy(str_new, str);
  return str_new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_dup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L26
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
L39:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L39
L26:
  mov    %rdi,%rbp
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: malloc failure

assistant: ```c
char *str_dup(const char *str) {
  char *str_new;
  if (!str)
    return (0);
  {
    if (!((str_new) = (char *)calloc((strlen(str) + 1), sizeof(char)))) {
      perror("malloc failure");
      abort();
    }
  };
  strcpy(str_new, str);
  return str_new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_dup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L18
  nopl   (%rax)
L0:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: malloc failure

assistant: ```c
char *str_dup(const char *str) {
  char *str_new;
  if (!str)
    return (0);
  {
    if (!((str_new) = (char *)calloc((strlen(str) + 1), sizeof(char)))) {
      perror("malloc failure");
      abort();
    }
  };
  strcpy(str_new, str);
  return str_new;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_dup>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%esi
  lea    0x1(%rax),%rdi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L18
  nopl   (%rax)
L0:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: malloc failure

assistant: ```c
char *str_dup(const char *str) {
  char *str_new;
  if (!str)
    return (0);
  {
    if (!((str_new) = (char *)calloc((strlen(str) + 1), sizeof(char)))) {
      perror("malloc failure");
      abort();
    }
  };
  strcpy(str_new, str);
  return str_new;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x74(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L14
L5:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x7d(%rbp)
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x7d(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  subl   $0x1,-0x78(%rbp)
  addl   $0x1,-0x7c(%rbp)
L14:
  mov    -0x7c(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jle    L5
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_guessed: string

tool: D19: %s

assistant: ```c
int main() {
  char n[100], pom;
  int i, p, l;
  scanf("%s", n);
  l = strlen(n);
  p = l - 1;
  for (i = 0; i <= p; p--, i++) {
    pom = n[p];
    n[p] = n[i];
    n[i] = pom;
  }
  printf("%s", n);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L27
  movslq %edx,%rdx
  mov    %rsp,%rcx
  sub    $0x1,%eax
L23:
  movzbl (%rsp,%rdx,1),%esi
  movzbl (%rcx),%edi
  mov    %dil,(%rsp,%rdx,1)
  mov    %sil,(%rcx)
  sub    $0x1,%rdx
  add    $0x1,%rcx
  mov    %eax,%esi
  sub    %edx,%esi
  cmp    %edx,%esi
  jle    L23
L27:
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string

tool: D16: %s

assistant: ```c
int main() {
  char n[100], pom;
  int i, p, l;
  scanf("%s", n);
  l = strlen(n);
  p = l - 1;
  for (i = 0; i <= p; p--, i++) {
    pom = n[p];
    n[p] = n[i];
    n[i] = pom;
  }
  printf("%s", n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L19
  movslq %eax,%rdx
  mov    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x0(%rbp,%rdx,1),%esi
  movzbl (%rcx),%edi
  add    $0x1,%rcx
  mov    %dil,0x0(%rbp,%rdx,1)
  sub    $0x1,%rdx
  mov    %sil,-0x1(%rcx)
  mov    %eax,%esi
  sub    %edx,%esi
  cmp    %edx,%esi
  jle    L9
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: %s

assistant: ```c
int main() {
  char n[100], pom;
  int i, p, l;
  scanf("%s", n);
  l = strlen(n);
  p = l - 1;
  for (i = 0; i <= p; p--, i++) {
    pom = n[p];
    n[p] = n[i];
    n[i] = pom;
  }
  printf("%s", n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L3
  movslq %eax,%rdx
  mov    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl 0x0(%rbp,%rdx,1),%esi
  movzbl (%rcx),%edi
  add    $0x1,%rcx
  mov    %dil,0x0(%rbp,%rdx,1)
  sub    $0x1,%rdx
  mov    %sil,-0x1(%rcx)
  mov    %eax,%esi
  sub    %edx,%esi
  cmp    %edx,%esi
  jle    L21
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: %s

assistant: ```c
int main() {
  char n[100], pom;
  int i, p, l;
  scanf("%s", n);
  l = strlen(n);
  p = l - 1;
  for (i = 0; i <= p; p--, i++) {
    pom = n[p];
    n[p] = n[i];
    n[i] = pom;
  }
  printf("%s", n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_mark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unset_mark@plt>
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long set_mark(long i) {
  i = unset_mark(i);
  i += 1;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_mark>:
  endbr64
  sub    $0x8,%rsp
  call   <unset_mark@plt>
  add    $0x1,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long set_mark(long i) {
  i = unset_mark(i);
  i += 1;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_mark>:
  endbr64
  sub    $0x8,%rsp
  call   <unset_mark@plt>
  add    $0x8,%rsp
  add    $0x1,%rax
  ret
```

assistant: ```c
long set_mark(long i) {
  i = unset_mark(i);
  i += 1;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_mark>:
  endbr64
  sub    $0x8,%rsp
  call   <unset_mark@plt>
  add    $0x8,%rsp
  add    $0x1,%rax
  ret
```

assistant: ```c
long set_mark(long i) {
  i = unset_mark(i);
  i += 1;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jstr_NullFirstC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L51
  mov    -0x18(%rbp),%rax
  jmp    L49
L51:
  movl   $0x0,-0x4(%rbp)
  jmp    L46
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L55
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L55:
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
L50:
  mov    -0x18(%rbp),%rax
L49:
  pop    %rbp
  ret
```

assistant: ```c
char *jstr_NullFirstC(char *buf, int max, char c) {
  int x;
  if (!buf)
    return (buf);
  for ((x = 0); (buf[x] != '\0') && (x < max); (x++)) {
    if (buf[x] == c) {
      buf[x] = '\0';
    }
  }
  return (buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<jstr_NullFirstC>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%r8d
  test   %esi,%esi
  jle    L19
  test   %r8b,%r8b
  je     L19
  mov    %rdi,%rcx
  mov    $0x1,%r11d
  sub    %edi,%r11d
  jmp    L5
L12:
  movzbl 0x1(%rcx),%r8d
  lea    (%r11,%rcx,1),%r9d
  cmp    %r9d,%esi
  setg   %r10b
  test   %r8b,%r8b
  setne  %r9b
  add    $0x1,%rcx
  test   %r9b,%r10b
  je     L19
L5:
  cmp    %r8b,%dl
  jne    L12
  movb   $0x0,(%rcx)
  jmp    L12
L19:
  ret
```

assistant: ```c
char *jstr_NullFirstC(char *buf, int max, char c) {
  int x;
  if (!buf)
    return (buf);
  for ((x = 0); (buf[x] != '\0') && (x < max); (x++)) {
    if (buf[x] == c) {
      buf[x] = '\0';
    }
  }
  return (buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jstr_NullFirstC>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L4
  movzbl (%rdi),%r8d
  test   %esi,%esi
  jle    L4
  test   %r8b,%r8b
  je     L4
  mov    $0x1,%r11d
  mov    %rdi,%rcx
  sub    %edi,%r11d
  nopl   (%rax)
L19:
  cmp    %r8b,%dl
  jne    L38
  movb   $0x0,(%rcx)
L38:
  lea    (%r11,%rcx,1),%r9d
  movzbl 0x1(%rcx),%r8d
  cmp    %r9d,%esi
  setg   %r10b
  test   %r8b,%r8b
  setne  %r9b
  add    $0x1,%rcx
  test   %r9b,%r10b
  jne    L19
L4:
  ret
```

assistant: ```c
char *jstr_NullFirstC(char *buf, int max, char c) {
  int x;
  if (!buf)
    return (buf);
  for ((x = 0); (buf[x] != '\0') && (x < max); (x++)) {
    if (buf[x] == c) {
      buf[x] = '\0';
    }
  }
  return (buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jstr_NullFirstC>:
  endbr64
  mov    %rdi,%r10
  test   %rdi,%rdi
  je     L26
  movzbl (%rdi),%ecx
  test   %esi,%esi
  jle    L26
  test   %cl,%cl
  je     L26
  mov    $0x1,%r9d
  mov    %rdi,%rax
  sub    %edi,%r9d
  nopl   0x0(%rax,%rax,1)
L31:
  cmp    %cl,%dl
  jne    L19
  movb   $0x0,(%rax)
L19:
  lea    (%r9,%rax,1),%edi
  movzbl 0x1(%rax),%ecx
  cmp    %edi,%esi
  setg   %r8b
  test   %cl,%cl
  setne  %dil
  add    $0x1,%rax
  test   %dil,%r8b
  jne    L31
L26:
  mov    %r10,%rax
  ret
```

assistant: ```c
char *jstr_NullFirstC(char *buf, int max, char c) {
  int x;
  if (!buf)
    return (buf);
  for ((x = 0); (buf[x] != '\0') && (x < max); (x++)) {
    if (buf[x] == c) {
      buf[x] = '\0';
    }
  }
  return (buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reads>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reads(int size, int stride, char *buf) {
  int i, s = 0;
  for (i = 0; i < size; i += stride) {
    s |= buf[i];
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reads>:
  endbr64
  test   %edi,%edi
  jle    L10
  movslq %esi,%r9
  mov    $0x0,%ecx
  mov    $0x0,%eax
L12:
  movsbl (%rdx),%r8d
  or     %r8d,%ecx
  add    %esi,%eax
  add    %r9,%rdx
  cmp    %eax,%edi
  jg     L12
L29:
  mov    %ecx,%eax
  ret
L10:
  mov    $0x0,%ecx
  jmp    L29
```

assistant: ```c
int reads(int size, int stride, char *buf) {
  int i, s = 0;
  for (i = 0; i < size; i += stride) {
    s |= buf[i];
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reads>:
  endbr64
  test   %edi,%edi
  jle    L18
  movslq %esi,%r9
  xor    %r8d,%r8d
  xor    %eax,%eax
L19:
  movsbl (%rdx),%ecx
  add    %esi,%eax
  add    %r9,%rdx
  or     %ecx,%r8d
  cmp    %eax,%edi
  jg     L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reads(int size, int stride, char *buf) {
  int i, s = 0;
  for (i = 0; i < size; i += stride) {
    s |= buf[i];
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<floorl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldt   0x10(%rbp)
  fnstcw -0x12(%rbp)
  movzwl -0x12(%rbp),%eax
  or     $0xc,%ah
  mov    %ax,-0x14(%rbp)
  fldcw  -0x14(%rbp)
  fistpl -0x4(%rbp)
  fldcw  -0x12(%rbp)
  fildl  -0x4(%rbp)
  fldt   0x10(%rbp)
  fxch   %st(1)
  fcomip %st(1),%st
  fstp   %st(0)
  jbe    L13
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  fildl  -0x18(%rbp)
  jmp    L12
L13:
  fildl  -0x4(%rbp)
L12:
  pop    %rbp
  ret
```

assistant: ```c
long double floorl(long double x) {
  int xi = (int)x;
  return x < xi ? xi - 1 : xi;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<floorl>:
  endbr64
  fldt   0x8(%rsp)
  fnstcw -0xa(%rsp)
  movzwl -0xa(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,-0xc(%rsp)
  fld    %st(0)
  fldcw  -0xc(%rsp)
  fistpl -0x10(%rsp)
  fldcw  -0xa(%rsp)
  fildl  -0x10(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jbe    L4
  fstp   %st(0)
  mov    -0x10(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rsp)
  fildl  -0x10(%rsp)
L4:
  ret
```

assistant: ```c
long double floorl(long double x) {
  int xi = (int)x;
  return x < xi ? xi - 1 : xi;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<floorl>:
  endbr64
  fnstcw -0xa(%rsp)
  fldt   0x8(%rsp)
  movzwl -0xa(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,-0xc(%rsp)
  fld    %st(0)
  fldcw  -0xc(%rsp)
  fistpl -0x10(%rsp)
  fldcw  -0xa(%rsp)
  fildl  -0x10(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jbe    L7
  fstp   %st(0)
  mov    -0x10(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rsp)
  fildl  -0x10(%rsp)
L7:
  ret
```

assistant: ```c
long double floorl(long double x) {
  int xi = (int)x;
  return x < xi ? xi - 1 : xi;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floorl>:
  endbr64
  fnstcw -0xa(%rsp)
  fldt   0x8(%rsp)
  movzwl -0xa(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,-0xc(%rsp)
  fld    %st(0)
  fldcw  -0xc(%rsp)
  fistpl -0x10(%rsp)
  fldcw  -0xa(%rsp)
  fildl  -0x10(%rsp)
  fcomi  %st(1),%st
  fstp   %st(1)
  jbe    L2
  fstp   %st(0)
  mov    -0x10(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rsp)
  fildl  -0x10(%rsp)
L2:
  ret
```

assistant: ```c
long double floorl(long double x) {
  int xi = (int)x;
  return x < xi ? xi - 1 : xi;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ccnl_ccnb_mkBlob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x5,%edx
  mov    %rax,%rdi
  call   <ccnl_ccnb_mkField@plt>
  leave
  ret
```

assistant: ```c
int ccnl_ccnb_mkBlob(unsigned char *out, unsigned int num, unsigned int tt, char *cp, int cnt) {
  (void)tt;
  return ccnl_ccnb_mkField(out, num, 5, (unsigned char *)cp, cnt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ccnl_ccnb_mkBlob>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  call   <ccnl_ccnb_mkField@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ccnl_ccnb_mkBlob(unsigned char *out, unsigned int num, unsigned int tt, char *cp, int cnt) {
  (void)tt;
  return ccnl_ccnb_mkField(out, num, 5, (unsigned char *)cp, cnt);
}
```
user: What is the c source code of the assembly code below?

```asm
<ccnl_ccnb_mkBlob>:
  endbr64
  mov    $0x5,%edx
  jmp    1050 <ccnl_ccnb_mkField@plt>
```

assistant: ```c
int ccnl_ccnb_mkBlob(unsigned char *out, unsigned int num, unsigned int tt, char *cp, int cnt) {
  (void)tt;
  return ccnl_ccnb_mkField(out, num, 5, (unsigned char *)cp, cnt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ccnl_ccnb_mkBlob>:
  endbr64
  mov    $0x5,%edx
  jmp    1050 <ccnl_ccnb_mkField@plt>
```

assistant: ```c
int ccnl_ccnb_mkBlob(unsigned char *out, unsigned int num, unsigned int tt, char *cp, int cnt) {
  (void)tt;
  return ccnl_ccnb_mkField(out, num, 5, (unsigned char *)cp, cnt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<limat_quantize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  D14(%rip),%xmm0
  comiss -0x18(%rbp),%xmm0
  jb     L28
  movss  -0x14(%rbp),%xmm0
  jmp    L9
L28:
  movss  -0x18(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmod@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm1
  movss  D27(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x4(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jb     L26
  movss  -0x14(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  addss  -0x18(%rbp),%xmm0
  jmp    L9
L26:
  movss  -0x18(%rbp),%xmm1
  movss  D9(%rip),%xmm0
  mulss  %xmm1,%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L14
  movss  -0x14(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  jmp    L9
L14:
  movss  -0x14(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: byte[4]
name: parse_data
arguments: data_label: D27
data_type: byte[4]
name: parse_data
arguments: data_label: D9
data_type: byte[4]

tool: {"D14": [0x08,0xe5,0x3c,0x1e]}

tool: {"D27": [0x00,0x00,0x00,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0xbf]}

assistant: ```c
float limat_quantize(float value, float resolution) {
  float tmp;
  if (resolution <= 1E-20f)
    return value;
  tmp = fmod(value, resolution);
  if (tmp >= 0.5f * resolution)
    return value - tmp + resolution;
  else if (tmp <= -0.5f * resolution)
    return value - tmp - resolution;
  else
    return value - tmp;
}
```