ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<ht_str_hash_function>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f693b52,%edi
  call   <UINT32_C@plt>
  xor    $0x1505,%eax
  cltq
  lea    0x1(%rbx),%rcx
  movzbl (%rbx),%edx
  test   %rdx,%rdx
  je     L3
L13:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  xor    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %rdx,%rdx
  jne    L13
L3:
  pop    %rbx
  ret
```

assistant: ```c
size_t ht_str_hash_function(const void *key, size_t len) {
  const unsigned char *str = key;
  size_t hash = 5381 ^ (UINT32_C(0x2f693b52));
  size_t c;
  (void)len;
  while ((c = (size_t)*str++))
    hash = ((hash << 5) + hash) ^ c;
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ht_str_hash_function>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f693b52,%edi
  call   <UINT32_C@plt>
  movzbl (%rbx),%edx
  xor    $0x1505,%eax
  cltq
  test   %rdx,%rdx
  je     L6
  lea    0x1(%rbx),%rcx
  nopl   (%rax)
L10:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  xor    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %rdx,%rdx
  jne    L10
L6:
  pop    %rbx
  ret
```

assistant: ```c
size_t ht_str_hash_function(const void *key, size_t len) {
  const unsigned char *str = key;
  size_t hash = 5381 ^ (UINT32_C(0x2f693b52));
  size_t c;
  (void)len;
  while ((c = (size_t)*str++))
    hash = ((hash << 5) + hash) ^ c;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ht_str_hash_function>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f693b52,%edi
  call   <UINT32_C@plt>
  movzbl (%rbx),%edx
  xor    $0x1505,%eax
  cltq
  test   %rdx,%rdx
  je     L19
  lea    0x1(%rbx),%rcx
  nopl   (%rax)
L14:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  xor    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %rdx,%rdx
  jne    L14
L19:
  pop    %rbx
  ret
```

assistant: ```c
size_t ht_str_hash_function(const void *key, size_t len) {
  const unsigned char *str = key;
  size_t hash = 5381 ^ (UINT32_C(0x2f693b52));
  size_t c;
  (void)len;
  while ((c = (size_t)*str++))
    hash = ((hash << 5) + hash) ^ c;
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gsl_log1p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D15(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %rax,%xmm1
  subsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: byte[8]

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double gsl_log1p(const double x) {
  volatile double y, z;
  y = 1 + x;
  z = y - 1;
  return log(y) - (z - x) / y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gsl_log1p>:
  endbr64
  sub    $0x28,%rsp
  movsd  D2(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x10(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  subsd  0x8(%rsp),%xmm1
  divsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  add    $0x28,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double gsl_log1p(const double x) {
  volatile double y, z;
  y = 1 + x;
  z = y - 1;
  return log(y) - (z - x) / y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gsl_log1p>:
  endbr64
  sub    $0x28,%rsp
  movsd  D6(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x10(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  add    $0x28,%rsp
  subsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double gsl_log1p(const double x) {
  volatile double y, z;
  y = 1 + x;
  z = y - 1;
  return log(y) - (z - x) / y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gsl_log1p>:
  endbr64
  sub    $0x28,%rsp
  movsd  D2(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x10(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  movsd  0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  add    $0x28,%rsp
  subsd  %xmm2,%xmm1
  divsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double gsl_log1p(const double x) {
  volatile double y, z;
  y = 1 + x;
  z = y - 1;
  return log(y) - (z - x) / y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solve_dobldobl_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x60,%rsp
  mov    %rdi,-0x1038(%rbp)
  mov    %esi,-0x103c(%rbp)
  mov    %rdx,-0x1048(%rbp)
  mov    %rcx,-0x1050(%rbp)
  mov    %r8d,-0x1040(%rbp)
  mov    %r9d,-0x1054(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x103c(%rbp),%eax
  mov    %eax,-0x1010(%rbp)
  mov    -0x1040(%rbp),%eax
  mov    %eax,-0x100c(%rbp)
  mov    -0x1054(%rbp),%esi
  mov    -0x1020(%rbp),%rcx
  lea    -0x1010(%rbp),%rdx
  lea    -0x1018(%rbp),%rax
  mov    %esi,%r8d
  mov    %rax,%rsi
  mov    $0x2bc,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1024(%rbp)
  mov    -0x1018(%rbp),%edx
  mov    -0x1038(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x103c(%rbp)
  jne    L23
  mov    -0x1014(%rbp),%edx
  mov    -0x1048(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x1028(%rbp)
  jmp    L28
L12:
  mov    -0x1028(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%edx
  mov    -0x1028(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1050(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x1028(%rbp)
L28:
  mov    -0x1048(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1028(%rbp)
  jl     L12
  mov    -0x1048(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x1050(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L23:
  mov    -0x1024(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int solve_dobldobl_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  fail = _ada_use_c2phc4c(700, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<solve_dobldobl_system>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    %esi,0x10(%rsp)
  mov    %r8d,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %r9d,%r8d
  mov    $0x0,%ecx
  mov    $0x2bc,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,0x0(%r13)
  test   %r12d,%r12d
  jne    L34
  mov    0xc(%rsp),%ecx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L4
  mov    $0x0,%edx
L6:
  mov    0x10(%rsp,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  mov    0x0(%rbp),%ecx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L6
L4:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
L34:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x1028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_dobldobl_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  fail = _ada_use_c2phc4c(700, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<solve_dobldobl_system>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  lea    0x10(%rsp),%r12
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %esi,0x10(%rsp)
  mov    %rcx,%rbx
  mov    %r8d,0x14(%rsp)
  lea    0x8(%rsp),%rsi
  mov    %r9d,%r8d
  xor    %ecx,%ecx
  mov    $0x2bc,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,(%r14)
  test   %r13d,%r13d
  jne    L22
  movslq 0xc(%rsp),%rcx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L14
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  movslq 0x0(%rbp),%rcx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L28
L14:
  movb   $0x0,(%rbx,%rcx,1)
L22:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x1020,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_dobldobl_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  fail = _ada_use_c2phc4c(700, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solve_dobldobl_system>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  movd   %r8d,%xmm1
  movd   %esi,%xmm0
  mov    %rdi,%r14
  mov    %esi,%r13d
  lea    0x10(%rsp),%r12
  punpckldq %xmm1,%xmm0
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %r12,%rdx
  lea    0x8(%rsp),%rsi
  mov    %r9d,%r8d
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    $0x2bc,%edi
  movq   %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,(%r14)
  test   %r13d,%r13d
  jne    L21
  movslq 0xc(%rsp),%rcx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L13
  xor    %edx,%edx
  nopl   0x0(%rax)
L23:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  movslq 0x0(%rbp),%rcx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L23
L13:
  movb   $0x0,(%rbx,%rcx,1)
L21:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x1020,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_dobldobl_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  fail = _ada_use_c2phc4c(700, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_swift_store_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L16
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
L16:
  mov    $0x1,%eax
  jmp    L4
L27:
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string

tool: D17: :

tool: D0: %lld

assistant: ```c
int read_swift_store_value(char *buf, const char *key, long long *ret) {
  int k = 0;
  char *tmp;
  if ((tmp = strstr(buf, key)) != NULL) {
    k = strcspn(tmp, ":");
    sscanf(tmp + k + 1, "%lld", ret);
    if (*ret < 0) {
      *ret = 0;
    }
    return 1;
  } else {
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_swift_store_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  call   <strstr@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L2
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  cltq
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %rbp,%rdx
  lea    D12(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1,%eax
  cmpq   $0x0,0x0(%rbp)
  js     L5
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  movq   $0x0,0x0(%rbp)
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D11: :

tool: D12: %lld

assistant: ```c
int read_swift_store_value(char *buf, const char *key, long long *ret) {
  int k = 0;
  char *tmp;
  if ((tmp = strstr(buf, key)) != NULL) {
    k = strcspn(tmp, ":");
    sscanf(tmp + k + 1, "%lld", ret);
    if (*ret < 0) {
      *ret = 0;
    }
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_swift_store_value>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L12
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  mov    %rbp,%rdx
  lea    D16(%rip),%rsi
  cltq
  lea    0x1(%rbx,%rax,1),%rdi
  call   <sscanf@plt>
  cmpq   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  js     L15
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string
name: read_data
arguments: data_tag: D16
type_infered: string

tool: D9: :

tool: D16: %lld

assistant: ```c
int read_swift_store_value(char *buf, const char *key, long long *ret) {
  int k = 0;
  char *tmp;
  if ((tmp = strstr(buf, key)) != NULL) {
    k = strcspn(tmp, ":");
    sscanf(tmp + k + 1, "%lld", ret);
    if (*ret < 0) {
      *ret = 0;
    }
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_swift_store_value>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strstr@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L13
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  mov    %rbp,%rdx
  lea    D6(%rip),%rsi
  cltq
  lea    0x1(%rbx,%rax,1),%rdi
  call   <sscanf@plt>
  cmpq   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  js     L11
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  movq   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D5: :

tool: D6: %lld

assistant: ```c
int read_swift_store_value(char *buf, const char *key, long long *ret) {
  int k = 0;
  char *tmp;
  if ((tmp = strstr(buf, key)) != NULL) {
    k = strcspn(tmp, ":");
    sscanf(tmp + k + 1, "%lld", ret);
    if (*ret < 0) {
      *ret = 0;
    }
    return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L22
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L22:
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jne    L9
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L9:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pages@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D55
data_type: string
name: unpack_data
arguments: tag: D60
data_type: string
name: unpack_data
arguments: tag: D46
data_type: string
name: unpack_data
arguments: tag: D56
data_type: string

tool: D13: Input the number of lines that can be printed on one page: 

tool: D55: %u

tool: D60: Input failure.


tool: D46: Input the number of lines we want to print: 

tool: D56: The number of pages required for %u number of lines with %u lines per page is %u.


assistant: ```c
int main() {
  unsigned input1, input2;
  printf("Input the number of lines that can be printed on one page: ");
  if (!scanf("%u", &input1))
    die("Input failure.\n");
  printf("Input the number of lines we want to print: ");
  if (!scanf("%u", &input2))
    die("Input failure.\n");
  printf("The number of pages required for %u number of lines with %u lines per page is %u.\n", input2, input1, pages(input1, input2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L36
L1:
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L16
L26:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <pages@plt>
  mov    %eax,%ecx
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L36:
  lea    D20(%rip),%rdi
  call   <die@plt>
  jmp    L1
L16:
  lea    D20(%rip),%rdi
  call   <die@plt>
  jmp    L26
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D42
data_type: string
name: unpack_data
arguments: label: D65
data_type: string
name: unpack_data
arguments: label: D34
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D49: Input the number of lines that can be printed on one page: 

tool: D42: %u

tool: D65: Input the number of lines we want to print: 

tool: D34: The number of pages required for %u number of lines with %u lines per page is %u.


tool: D20: Input failure.


assistant: ```c
int main() {
  unsigned input1, input2;
  printf("Input the number of lines that can be printed on one page: ");
  if (!scanf("%u", &input1))
    die("Input failure.\n");
  printf("Input the number of lines we want to print: ");
  if (!scanf("%u", &input2))
    die("Input failure.\n");
  printf("The number of pages required for %u number of lines with %u lines per page is %u.\n", input2, input1, pages(input1, input2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D41(%rip),%rdi
  lea    D28(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L15
L42:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L39
L28:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <pages@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  lea    D7(%rip),%rdi
  call   <die@plt>
  jmp    L42
L39:
  lea    D7(%rip),%rdi
  call   <die@plt>
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D41
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D7
datatype: string

tool: D41: Input the number of lines that can be printed on one page: 

tool: D28: %u

tool: D27: Input the number of lines we want to print: 

tool: D16: The number of pages required for %u number of lines with %u lines per page is %u.


tool: D7: Input failure.


assistant: ```c
int main() {
  unsigned input1, input2;
  printf("Input the number of lines that can be printed on one page: ");
  if (!scanf("%u", &input1))
    die("Input failure.\n");
  printf("Input the number of lines we want to print: ");
  if (!scanf("%u", &input2))
    die("Input failure.\n");
  printf("The number of pages required for %u number of lines with %u lines per page is %u.\n", input2, input1, pages(input1, input2));
  return 0;
}
```