user: 这段汇编代码用C语言表示是什么样的？

```asm
<dumpMem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%eax
  mov    %ax,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movzwl -0x64(%rbp),%eax
  movswq %ax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x58(%rbp)
  movswq %ax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movswq %ax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movswq %ax,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L77:
  cmp    %rdx,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L77
L34:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L108
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L108:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  movzwl -0x64(%rbp),%eax
  movswq %ax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movswq %ax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movswq %ax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movswq %ax,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L48:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L48
L5:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L16
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L16:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x60(%rbp)
  movswl -0x64(%rbp),%ecx
  mov    -0x60(%rbp),%edx
  mov    -0x50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <buildLine@plt>
  movswl -0x64(%rbp),%ecx
  mov    -0x60(%rbp),%edx
  mov    -0x50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <dumpLine@plt>
  movl   $0x0,-0x5c(%rbp)
  movswl -0x64(%rbp),%eax
  mov    %eax,-0x60(%rbp)
  jmp    L37
L60:
  movswl -0x64(%rbp),%ecx
  mov    -0x60(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <buildLine@plt>
  movswl -0x64(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <areEqual@plt>
  test   %rax,%rax
  je     L56
  cmpl   $0x0,-0x5c(%rbp)
  jne    L15
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x5c(%rbp)
  jmp    L15
L56:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movswl -0x64(%rbp),%ecx
  mov    -0x60(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <dumpLine@plt>
  movl   $0x0,-0x5c(%rbp)
L15:
  movswl -0x64(%rbp),%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  movswl -0x64(%rbp),%eax
  add    %eax,-0x60(%rbp)
L37:
  cmpl   $0x3fff,-0x60(%rbp)
  jle    L60
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D24
data_type: string

tool: D22: *


tool: D24: 


assistant: ```c
void dumpMem(short wordsperline) {
  unsigned int prevLine[wordsperline];
  unsigned int currLine[wordsperline];
  int address = 0;
  buildLine(prevLine, wordsperline, address);
  dumpLine(prevLine, wordsperline, address);
  int star = 0;
  for (address = wordsperline; address < 16384; address += wordsperline) {
    buildLine(currLine, wordsperline, address);
    if (areEqual(prevLine, currLine, wordsperline)) {
      if (!star) {
        printf("*\n");
        star = 1;
      }
    } else {
      printf("\n");
      dumpLine(currLine, wordsperline, address);
      star = 0;
    }
    copy(prevLine, currLine, wordsperline);
  }
  printf("\n");
}
```