ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_mvinnstr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x3,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L76
  lea    D5(%rip),%rbp
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L21
  mov    0x8(%rbx),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L21
  mov    0x10(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L21
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L54
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdx
  mov    0xc(%rsp),%edi
  call   <mvinnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  nopl   (%rax)
L76:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L21:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D7(%rip),%rdi
  call   <report_error@plt>
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L54:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D1(%rip),%rdi
  call   <report_error@plt>
  jmp    L76
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string

tool: D5: %d

tool: D7: BAD ARGUMENT

tool: D1: MALLOC_FAILED

assistant: ```c
void cmd_mvinnstr(int nargs, char **args) {
  int y, x, count;
  char *string;
  if (check_arg_count(nargs, 3) == 1)
    return;
  if (sscanf(args[0], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if ((string = malloc(count + 1)) == NULL) {
    report_count(1);
    report_error("MALLOC_FAILED");
    return;
  }
  report_count(2);
  report_return(mvinnstr(y, x, string, count));
  report_status(string);
  free(string);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_mvinnstr>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x3,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L67
  lea    D23(%rip),%rbp
  mov    (%rbx),%rdi
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L38
  mov    0x8(%rbx),%rdi
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L38
  mov    0x10(%rbx),%rdi
  lea    0x14(%rsp),%rdx
  mov    %rbp,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L38
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdx
  mov    0xc(%rsp),%edi
  call   <mvinnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  mov    %rbp,%rdi
  call   <report_status@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  nopl   (%rax)
L67:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L38:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D9(%rip),%rdi
  call   <report_error@plt>
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D22(%rip),%rdi
  call   <report_error@plt>
  jmp    L67
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D22
type: string

tool: D23: %d

tool: D9: BAD ARGUMENT

tool: D22: MALLOC_FAILED

assistant: ```c
void cmd_mvinnstr(int nargs, char **args) {
  int y, x, count;
  char *string;
  if (check_arg_count(nargs, 3) == 1)
    return;
  if (sscanf(args[0], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if ((string = malloc(count + 1)) == NULL) {
    report_count(1);
    report_error("MALLOC_FAILED");
    return;
  }
  report_count(2);
  report_return(mvinnstr(y, x, string, count));
  report_status(string);
  free(string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x5,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  typedef void *size_t;
  size_t p = (void *)5;
  return (int)p;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
main() {
  typedef void *size_t;
  size_t p = (void *)5;
  return (int)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
main() {
  typedef void *size_t;
  size_t p = (void *)5;
  return (int)p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
main() {
  typedef void *size_t;
  size_t p = (void *)5;
  return (int)p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D8: signbit(+0.0) = %d


tool: D0: signbit(-0.0) = %d


assistant: ```c
int main(void) {
  printf("signbit(+0.0) = %d\n", signbit(+0.0));
  printf("signbit(-0.0) = %d\n", signbit(-0.0));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D14: signbit(+0.0) = %d


tool: D13: signbit(-0.0) = %d


assistant: ```c
int main(void) {
  printf("signbit(+0.0) = %d\n", signbit(+0.0));
  printf("signbit(-0.0) = %d\n", signbit(-0.0));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D17: signbit(+0.0) = %d


tool: D5: signbit(-0.0) = %d


assistant: ```c
int main(void) {
  printf("signbit(+0.0) = %d\n", signbit(+0.0));
  printf("signbit(-0.0) = %d\n", signbit(-0.0));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string

tool: D16: signbit(+0.0) = %d


tool: D10: signbit(-0.0) = %d


assistant: ```c
int main(void) {
  printf("signbit(+0.0) = %d\n", signbit(+0.0));
  printf("signbit(-0.0) = %d\n", signbit(-0.0));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <init2@plt>
  mov    $0x0,%eax
  call   <doit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  init();
  init2();
  doit();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <init2@plt>
  mov    $0x0,%eax
  call   <doit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init2();
  doit();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <init2@plt>
  xor    %eax,%eax
  call   <doit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init2();
  doit();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <init2@plt>
  xor    %eax,%eax
  call   <doit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  init2();
  doit();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_uppercase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L15
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int to_uppercase(char *keyword, int nchar) {
  char *pos;
  for (pos = keyword; pos < (keyword + nchar); pos++) {
    *pos = toupper(*pos);
  }
  return (nchar);
}
```
user: Translate the below assembly code into C programming language:

```asm
<to_uppercase>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  movslq %esi,%rbp
  add    %rdi,%rbp
  cmp    %rbp,%rdi
  jae    L0
L5:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
L0:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int to_uppercase(char *keyword, int nchar) {
  char *pos;
  for (pos = keyword; pos < (keyword + nchar); pos++) {
    *pos = toupper(*pos);
  }
  return (nchar);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<to_uppercase>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  mov    %rbp,%r12
  add    %rdi,%rbp
  push   %rbx
  cmp    %rbp,%rdi
  jae    L9
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L11:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L11
L9:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int to_uppercase(char *keyword, int nchar) {
  char *pos;
  for (pos = keyword; pos < (keyword + nchar); pos++) {
    *pos = toupper(*pos);
  }
  return (nchar);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<to_uppercase>:
  endbr64
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  mov    %rbp,%r12
  add    %rdi,%rbp
  push   %rbx
  cmp    %rbp,%rdi
  jae    L13
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L14
L13:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int to_uppercase(char *keyword, int nchar) {
  char *pos;
  for (pos = keyword; pos < (keyword + nchar); pos++) {
    *pos = toupper(*pos);
  }
  return (nchar);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_tprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x9,-0x18(%rbp)
  jg     L71
  mov    $0x0,%eax
  jmp    L84
L71:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L5
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x0,%eax
  jmp    L84
L15:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rbp)
L5:
  cmpq   $0x0,-0x18(%rbp)
  jg     L23
  jmp    L6
L79:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L84
L6:
  cmpq   $0xa,-0x8(%rbp)
  jg     L79
  mov    $0x1,%eax
L84:
  leave
  ret
```

assistant: ```c
int is_tprime(long i) {
  if (i < 10)
    return 0;
  long i2 = i, tmp = 1;
  while (i > 0) {
    if (!is_prime(i))
      return 0;
    i /= 10;
    tmp *= 10;
  }
  while (tmp > 10) {
    tmp /= 10;
    i2 %= tmp;
    if (!is_prime(i2))
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_tprime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x9,%rdi
  jle    L25
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  movabs $0x6666666666666667,%r13
  jmp    L46
L28:
  mov    %rdx,%rbp
L46:
  mov    %rbp,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L47
  mov    %rbp,%rax
  imul   %r13
  sar    $0x2,%rdx
  mov    %rbp,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rbx,%rbx,4),%rbx
  add    %rbx,%rbx
  cmp    $0x9,%rbp
  jg     L28
  movabs $0x6666666666666667,%rbp
L27:
  cmp    $0xa,%rbx
  jle    L30
  mov    %rbx,%rax
  imul   %rbp
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rbx
  sub    %rax,%rbx
  mov    %r12,%rax
  cqto
  idiv   %rbx
  mov    %rdx,%rdi
  mov    %rdx,%r12
  call   <is_prime@plt>
  test   %eax,%eax
  jne    L27
  jmp    L47
L30:
  mov    $0x1,%eax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  ret
```

assistant: ```c
int is_tprime(long i) {
  if (i < 10)
    return 0;
  long i2 = i, tmp = 1;
  while (i > 0) {
    if (!is_prime(i))
      return 0;
    i /= 10;
    tmp *= 10;
  }
  while (tmp > 10) {
    tmp /= 10;
    i2 %= tmp;
    if (!is_prime(i2))
      return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_tprime>:
  endbr64
  cmp    $0x9,%rdi
  jle    L58
  push   %r13
  movabs $0xcccccccccccccccd,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  mov    %rbp,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L13
  mov    %rbp,%rax
  lea    (%rbx,%rbx,4),%rbx
  mul    %r13
  add    %rbx,%rbx
  mov    %rdx,%rbp
  shr    $0x3,%rbp
  jne    L2
  movabs $0xcccccccccccccccd,%rbp
  jmp    L25
  xchg   %ax,%ax
L56:
  mov    %rbx,%rax
  mul    %rbp
  mov    %r12,%rax
  mov    %rdx,%rbx
  cqto
  shr    $0x3,%rbx
  idiv   %rbx
  mov    %rdx,%rdi
  mov    %rdx,%r12
  call   <is_prime@plt>
  test   %eax,%eax
  je     L13
L25:
  cmp    $0xa,%rbx
  jg     L56
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L58:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_tprime(long i) {
  if (i < 10)
    return 0;
  long i2 = i, tmp = 1;
  while (i > 0) {
    if (!is_prime(i))
      return 0;
    i /= 10;
    tmp *= 10;
  }
  while (tmp > 10) {
    tmp /= 10;
    i2 %= tmp;
    if (!is_prime(i2))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_tprime>:
  endbr64
  cmp    $0x9,%rdi
  jle    L33
  push   %r13
  movabs $0xcccccccccccccccd,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L37:
  mov    %rbp,%rdi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L49
  mov    %rbp,%rax
  lea    (%rbx,%rbx,4),%rbx
  mul    %r13
  add    %rbx,%rbx
  mov    %rdx,%rbp
  shr    $0x3,%rbp
  jne    L37
  movabs $0xcccccccccccccccd,%rbp
  jmp    L25
  xchg   %ax,%ax
L18:
  mov    %rbx,%rax
  mul    %rbp
  mov    %r12,%rax
  mov    %rdx,%rbx
  cqto
  shr    $0x3,%rbx
  idiv   %rbx
  mov    %rdx,%rdi
  mov    %rdx,%r12
  call   <is_prime@plt>
  test   %eax,%eax
  je     L49
L25:
  cmp    $0xa,%rbx
  jg     L18
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_tprime(long i) {
  if (i < 10)
    return 0;
  long i2 = i, tmp = 1;
  while (i > 0) {
    if (!is_prime(i))
      return 0;
    i /= 10;
    tmp *= 10;
  }
  while (tmp > 10) {
    tmp /= 10;
    i2 %= tmp;
    if (!is_prime(i2))
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<godelito>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movb   $0x33,(%rax)
  mov    -0x30(%rbp),%rax
  movb   $0x0,0x1(%rax)
  movl   $0x1,-0x18(%rbp)
  jmp    L48
L51:
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rax
  lea    -0x186a0(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rax
  lea    -0x186a0(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L12
L4:
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L5:
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rax
  lea    -0x186a0(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  cmp    %eax,-0x8(%rbp)
  je     L5
  mov    -0x10(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    -0x8(%rbp),%ecx
  cltq
  mov    %cl,(%rdx,%rax,1)
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rax
  lea    -0x186a0(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x2,-0xc(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L4
  mov    -0x18(%rbp),%eax
  cltq
  imul   $0x186a0,%rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  addl   $0x1,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L51
  nop
  nop
  leave
  ret
```

assistant: ```c
void godelito(int n, char g[][100000]) {
  g[0][0] = '3';
  g[0][1] = '\0';
  int i;
  for (i = 1; i < n; i++) {
    int t = strlen(g[i - 1]), j = 0, k = 0, l = 0, e = g[i - 1][0];
    while (j < t) {
      k = 0;
      while (g[i - 1][j] == e) {
        k++;
        j++;
      }
      g[i][l] = k + '0';
      g[i][l + 1] = e;
      e = g[i - 1][j];
      l += 2;
    }
    g[i][l] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<godelito>:
  endbr64
  movb   $0x33,(%rsi)
  movb   $0x0,0x1(%rsi)
  cmp    $0x1,%edi
  jle    L16
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x186a0(%rsi),%rbp
  lea    -0x2(%rdi),%edx
  imul   $0x186a0,%rdx,%rdx
  lea    0x30d40(%rsi,%rdx,1),%r13
  mov    $0x0,%r12d
  jmp    L14
L21:
  add    $0x1,%edx
  mov    %eax,%esi
  movsbl (%rbx,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %edi,%ecx
  je     L21
L19:
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %dil,0x1(%r8)
  movslq %esi,%rax
  movsbl (%rbx,%rax,1),%edi
  lea    (%r10,%r8,1),%eax
  add    $0x2,%r8
  cmp    %esi,%r9d
  jle    L56
L43:
  movslq %esi,%rax
  movsbl (%rbx,%rax,1),%ecx
  lea    0x1(%rsi),%eax
  cltq
  mov    $0x0,%edx
  cmp    %edi,%ecx
  je     L21
  jmp    L19
L56:
  cltq
  movb   $0x0,(%r11,%rax,1)
  add    $0x186a0,%rbp
  cmp    %r13,%rbp
  je     L7
L14:
  lea    -0x186a0(%rbp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r9d
  mov    %rbp,%r11
  movsbl -0x186a0(%rbp),%edi
  mov    %rbp,%r8
  mov    %r12d,%esi
  mov    $0x2,%r10d
  sub    %ebp,%r10d
  mov    %r12d,%eax
  test   %r9d,%r9d
  jg     L43
  jmp    L56
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  ret
```

assistant: ```c
void godelito(int n, char g[][100000]) {
  g[0][0] = '3';
  g[0][1] = '\0';
  int i;
  for (i = 1; i < n; i++) {
    int t = strlen(g[i - 1]), j = 0, k = 0, l = 0, e = g[i - 1][0];
    while (j < t) {
      k = 0;
      while (g[i - 1][j] == e) {
        k++;
        j++;
      }
      g[i][l] = k + '0';
      g[i][l + 1] = e;
      e = g[i - 1][j];
      l += 2;
    }
    g[i][l] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<godelito>:
  endbr64
  mov    $0x33,%eax
  mov    %ax,(%rsi)
  cmp    $0x1,%edi
  jle    L33
  mov    %edi,%eax
  push   %r12
  mov    %rsi,%r12
  sub    $0x2,%eax
  push   %rbp
  imul   $0x186a0,%rax,%rax
  push   %rbx
  lea    0x186a0(%rsi,%rax,1),%rbx
L19:
  mov    %r12,%rdi
  mov    %r12,%rbp
  add    $0x186a0,%r12
  call   <strlen@plt>
  mov    $0x2,%r9d
  xor    %edi,%edi
  xor    %edx,%edx
  movsbl -0x186a0(%r12),%r8d
  test   %eax,%eax
  jle    L46
  nopl   0x0(%rax)
L38:
  add    $0x1,%edi
  xor    %ecx,%ecx
  movslq %edi,%rdx
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl 0x0(%rbp,%rdx,1),%esi
  mov    %edx,%edi
  add    $0x1,%ecx
  add    $0x1,%rdx
  cmp    %r8d,%esi
  je     L11
  movslq %edi,%rdx
  add    $0x30,%ecx
  mov    %r8b,-0x1(%r12,%r9,1)
  mov    %cl,-0x2(%r12,%r9,1)
  movsbl 0x0(%rbp,%rdx,1),%r8d
  movslq %r9d,%rdx
  add    $0x2,%r9
  cmp    %edi,%eax
  jg     L38
L46:
  movb   $0x0,(%r12,%rdx,1)
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  ret
```

assistant: ```c
void godelito(int n, char g[][100000]) {
  g[0][0] = '3';
  g[0][1] = '\0';
  int i;
  for (i = 1; i < n; i++) {
    int t = strlen(g[i - 1]), j = 0, k = 0, l = 0, e = g[i - 1][0];
    while (j < t) {
      k = 0;
      while (g[i - 1][j] == e) {
        k++;
        j++;
      }
      g[i][l] = k + '0';
      g[i][l + 1] = e;
      e = g[i - 1][j];
      l += 2;
    }
    g[i][l] = '\0';
  }
}
```