ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<atohx>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%rdi
  mov    %rsi,0x10(%rsp)
  call   <strlen@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L23
  mov    %eax,%eax
  mov    %r13d,%r14d
  mov    %rbx,%r15
  add    $0x2,%r13d
  add    %rbx,%rax
  add    $0x1,%r14
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L40:
  call   <tolower@plt>
  movsbl 0x1(%r15),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %ebx,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  mov    %ebp,%edi
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x27,%eax
  add    $0x30,%eax
  sub    %eax,%ebx
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x27,%eax
  add    $0x30,%eax
  sub    %eax,%ebp
  mov    %ebx,%eax
  or     %ebp,%eax
  cmp    $0xf,%eax
  ja     L45
  shl    $0x4,%ebx
  mov    %r13d,%eax
  add    $0x1,%r12
  or     %ebp,%ebx
  add    %rax,%r15
  mov    %bl,-0x1(%r12)
  movsbl (%r15),%edi
  test   %dil,%dil
  je     L4
  lea    (%r15,%r14,1),%rax
  cmp    %rax,0x8(%rsp)
  jae    L40
  cmp    %r15,0x10(%rsp)
  je     L40
L4:
  movb   $0x0,(%r12)
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    0x18(%rsp),%rax
  movb   $0x0,(%rax)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    0x18(%rsp),%r12
  jmp    L4
```

assistant: ```c
char *atohx(char *dst, const char *src, const unsigned int spacing) {
  char *ret = dst;
  const char *srcPtr = src;
  const unsigned int length = strlen(srcPtr);
  int lsb, msb;
  for (lsb = 0, msb = 0; *src; src += 2 + spacing) {
    if ((src + 1 + spacing) > srcPtr + length && src - srcPtr) {
      break;
    }
    msb = tolower(*src);
    lsb = tolower(*(src + 1));
    msb -= isdigit(msb) ? 0x30 : 0x57;
    lsb -= isdigit(lsb) ? 0x30 : 0x57;
    if ((msb < 0x0 || msb > 0xf) || (lsb < 0x0 || lsb > 0xf)) {
      *ret = 0;
      return NULL;
    }
    *dst++ = (char)(lsb | (msb << 4));
  }
  *dst = 0;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D13
datatype: string

tool: D17: main: interrupted by SIGALARM


tool: D13: Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail


assistant: ```c
void sig_handler() {
  printf("main: interrupted by SIGALARM\n");
  printf("Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail\n");
  pthread_exit((void *)0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D15
type: string

tool: D4: main: interrupted by SIGALARM


tool: D15: Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail


assistant: ```c
void sig_handler() {
  printf("main: interrupted by SIGALARM\n");
  printf("Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail\n");
  pthread_exit((void *)0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <pthread_exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D19: main: interrupted by SIGALARM


tool: D9: Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail


assistant: ```c
void sig_handler() {
  printf("main: interrupted by SIGALARM\n");
  printf("Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail\n");
  pthread_exit((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <pthread_exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: string
name: extract_symbolic_data
arguments: data_tag: D14
data_type: string

tool: D16: main: interrupted by SIGALARM


tool: D14: Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail


assistant: ```c
void sig_handler() {
  printf("main: interrupted by SIGALARM\n");
  printf("Test PASSED: *Note: Did not return EDEADLK when re-locking a spinlock already in  use, but standard says 'may' fail\n");
  pthread_exit((void *)0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<droits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
  mov    0x0(%rbp),%ebp
  lea    0x4(%rsp),%r12
  mov    D5(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x72,%esi
  call   <traiter@plt>
  mov    D0(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x77,%esi
  call   <traiter@plt>
  mov    D7(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x78,%esi
  call   <traiter@plt>
  mov    D13(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x72,%esi
  call   <traiter@plt>
  mov    D42(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x77,%esi
  call   <traiter@plt>
  mov    D74(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x78,%esi
  call   <traiter@plt>
  mov    D9(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x72,%esi
  call   <traiter@plt>
  mov    D12(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x77,%esi
  call   <traiter@plt>
  mov    D36(%rip),%rax
  mov    %ebp,%edi
  and    (%rax),%edi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    $0x2d,%edx
  mov    $0x78,%esi
  call   <traiter@plt>
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *droits(struct stat *pstat) {
  mode_t mode;
  char *modes = malloc(sizeof(10));
  int indice_mode = 0;
  mode = pstat->st_mode;
  traiter(mode & S_IRUSR, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWUSR, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXUSR, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IRGRP, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWGRP, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXGRP, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IROTH, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWOTH, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXOTH, 'x', '-', &indice_mode, modes);
  modes[indice_mode] = '\0';
  return modes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<droits>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    (%rbx),%ebx
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    %rax,%r12
  mov    D82(%rip),%rax
  mov    $0x72,%esi
  movl   $0x0,0x4(%rsp)
  mov    %r12,%r8
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D5(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D88(%rip),%rax
  mov    $0x78,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D11(%rip),%rax
  mov    $0x72,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D77(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D80(%rip),%rax
  mov    $0x78,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D41(%rip),%rax
  mov    $0x72,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D73(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D34(%rip),%rax
  mov    $0x78,%esi
  and    (%rax),%ebx
  mov    %ebx,%edi
  call   <traiter@plt>
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *droits(struct stat *pstat) {
  mode_t mode;
  char *modes = malloc(sizeof(10));
  int indice_mode = 0;
  mode = pstat->st_mode;
  traiter(mode & S_IRUSR, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWUSR, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXUSR, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IRGRP, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWGRP, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXGRP, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IROTH, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWOTH, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXOTH, 'x', '-', &indice_mode, modes);
  modes[indice_mode] = '\0';
  return modes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<droits>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    (%rbx),%ebx
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    %rax,%r12
  mov    D84(%rip),%rax
  mov    $0x72,%esi
  movl   $0x0,0x4(%rsp)
  mov    %r12,%r8
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D4(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D25(%rip),%rax
  mov    $0x78,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D0(%rip),%rax
  mov    $0x72,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D15(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D69(%rip),%rax
  mov    $0x78,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D50(%rip),%rax
  mov    $0x72,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D10(%rip),%rax
  mov    $0x77,%esi
  mov    (%rax),%edi
  and    %ebx,%edi
  call   <traiter@plt>
  mov    %r12,%r8
  mov    %r13,%rcx
  mov    $0x2d,%edx
  mov    D68(%rip),%rax
  mov    $0x78,%esi
  and    (%rax),%ebx
  mov    %ebx,%edi
  call   <traiter@plt>
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%r12,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *droits(struct stat *pstat) {
  mode_t mode;
  char *modes = malloc(sizeof(10));
  int indice_mode = 0;
  mode = pstat->st_mode;
  traiter(mode & S_IRUSR, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWUSR, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXUSR, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IRGRP, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWGRP, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXGRP, 'x', '-', &indice_mode, modes);
  traiter(mode & S_IROTH, 'r', '-', &indice_mode, modes);
  traiter(mode & S_IWOTH, 'w', '-', &indice_mode, modes);
  traiter(mode & S_IXOTH, 'x', '-', &indice_mode, modes);
  modes[indice_mode] = '\0';
  return modes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<switch_eg_impl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x64,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L3
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  nop
  jmp    *%rax
L3:
  nop
  endbr64
  movl   $0x0,-0x8(%rbp)
  nop
  jmp    L27
  endbr64
  movl   $0x0,-0x8(%rbp)
  jmp    L7
  endbr64
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
  endbr64
  mov    -0x14(%rbp),%eax
  add    $0xa,%eax
  mov    %eax,-0x8(%rbp)
L7:
  addl   $0xb,-0x8(%rbp)
  jmp    L43
  endbr64
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int switch_eg_impl(int x, int n) {
  static void *jt[7] = {&&loc_A, &&loc_def, &&loc_B, &&loc_C, &&loc_D, &&loc_def, &&loc_D};
  unsigned index = n - 100;
  int result;
  if (index > 6)
    goto loc_def;
  goto *jt[index];
loc_def:
  result = 0;
  return;
loc_C:
  result = 0;
  goto rest;
loc_A:
  result = x * 13;
  goto done;
loc_B:
  result = x + 10;
rest:
  result += 11;
  goto done;
loc_D:
  result = x * x;
done:
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<switch_eg_impl>:
  endbr64
  sub    $0x64,%esi
  cmp    $0x6,%esi
  ja     L14
  lea    D4(%rip),%rax
  mov    %esi,%esi
  jmp    *(%rax,%rsi,8)
L14:
  endbr64
  ret
  endbr64
  mov    $0x0,%eax
L10:
  add    $0xb,%eax
  ret
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rdi,%rax,4),%eax
  ret
  endbr64
  lea    0xa(%rdi),%eax
  jmp    L10
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  ret
```

assistant: ```c
int switch_eg_impl(int x, int n) {
  static void *jt[7] = {&&loc_A, &&loc_def, &&loc_B, &&loc_C, &&loc_D, &&loc_def, &&loc_D};
  unsigned index = n - 100;
  int result;
  if (index > 6)
    goto loc_def;
  goto *jt[index];
loc_def:
  result = 0;
  return;
loc_C:
  result = 0;
  goto rest;
loc_A:
  result = x * 13;
  goto done;
loc_B:
  result = x + 10;
rest:
  result += 11;
  goto done;
loc_D:
  result = x * x;
done:
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<switch_eg_impl>:
  endbr64
  sub    $0x64,%esi
  cmp    $0x6,%esi
  ja     L4
  lea    D2(%rip),%rax
  jmp    *(%rax,%rsi,8)
  cs nopw 0x0(%rax,%rax,1)
L4:
  endbr64
  ret
  nopl   (%rax)
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    $0xb,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rdi,%rax,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
  endbr64
  lea    0x15(%rdi),%eax
  ret
```

assistant: ```c
int switch_eg_impl(int x, int n) {
  static void *jt[7] = {&&loc_A, &&loc_def, &&loc_B, &&loc_C, &&loc_D, &&loc_def, &&loc_D};
  unsigned index = n - 100;
  int result;
  if (index > 6)
    goto loc_def;
  goto *jt[index];
loc_def:
  result = 0;
  return;
loc_C:
  result = 0;
  goto rest;
loc_A:
  result = x * 13;
  goto done;
loc_B:
  result = x + 10;
rest:
  result += 11;
  goto done;
loc_D:
  result = x * x;
done:
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<switch_eg_impl>:
  endbr64
  sub    $0x64,%esi
  cmp    $0x6,%esi
  ja     L7
  lea    D6(%rip),%rax
  jmp    *(%rax,%rsi,8)
  cs nopw 0x0(%rax,%rax,1)
L7:
  endbr64
  ret
  nopl   (%rax)
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    $0xb,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rdi,%rax,4),%eax
  ret
  nopl   0x0(%rax,%rax,1)
  endbr64
  lea    0x15(%rdi),%eax
  ret
```

assistant: ```c
int switch_eg_impl(int x, int n) {
  static void *jt[7] = {&&loc_A, &&loc_def, &&loc_B, &&loc_C, &&loc_D, &&loc_def, &&loc_D};
  unsigned index = n - 100;
  int result;
  if (index > 6)
    goto loc_def;
  goto *jt[index];
loc_def:
  result = 0;
  return;
loc_C:
  result = 0;
  goto rest;
loc_A:
  result = x * 13;
  goto done;
loc_B:
  result = x + 10;
rest:
  result += 11;
  goto done;
loc_D:
  result = x * x;
done:
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L9
  movsd  -0x8(%rbp),%xmm0
  jmp    L13
L9:
  movsd  D9(%rip),%xmm0
L13:
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: byte[8]
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: {"D9": [0x33,0x33,0x33,0x33,0x33,0x33,0x1b,0x40]}

tool: D0: %f


assistant: ```c
void f() {
  float x$1 = ((float)({
    double t$1 = 0x0p+0;
    (((int)t$1) ? t$1 : 0x1.b333333333333p+2);
  }));
  printf("%f\n", x$1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  movsd  D17(%rip),%xmm0
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
type: byte[8]
name: unpack_data
arguments: label: D10
type: string

tool: {"D17": [0x00,0x00,0x00,0x40,0x33,0x33,0x1b,0x40]}

tool: D10: %f


assistant: ```c
void f() {
  float x$1 = ((float)({
    double t$1 = 0x0p+0;
    (((int)t$1) ? t$1 : 0x1.b333333333333p+2);
  }));
  printf("%f\n", x$1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  movsd  D17(%rip),%xmm0
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: byte[8]
name: disassemble_data
arguments: tag: D7
type: string

tool: {"D17": [0x00,0x00,0x00,0x40,0x33,0x33,0x1b,0x40]}

tool: D7: %f


assistant: ```c
void f() {
  float x$1 = ((float)({
    double t$1 = 0x0p+0;
    (((int)t$1) ? t$1 : 0x1.b333333333333p+2);
  }));
  printf("%f\n", x$1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  movsd  D11(%rip),%xmm0
  lea    D9(%rip),%rdi
  mov    $0x1,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: byte[8]
name: read_data
arguments: tag: D9
data_type: string

tool: {"D11": [0x00,0x00,0x00,0x40,0x33,0x33,0x1b,0x40]}

tool: D9: %f


assistant: ```c
void f() {
  float x$1 = ((float)({
    double t$1 = 0x0p+0;
    (((int)t$1) ? t$1 : 0x1.b333333333333p+2);
  }));
  printf("%f\n", x$1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L6
L38:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L32
L26:
  addq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L38
  mov    $0x0,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
void *memchr(const void *_ptr, int ch, size_t len) {
  const unsigned char *ptr = _ptr;
  for (size_t i = 0; i < len; i++)
    if (ptr[i] == ch)
      return (void *)&ptr[i];
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memchr>:
  endbr64
  test   %rdx,%rdx
  je     L28
  mov    %rdi,%rax
  add    %rdx,%rdi
L14:
  mov    %rax,%rcx
  movzbl (%rax),%edx
  cmp    %esi,%edx
  je     L13
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L14
  mov    $0x0,%ecx
L13:
  mov    %rcx,%rax
  ret
L28:
  mov    $0x0,%ecx
  jmp    L13
```

assistant: ```c
void *memchr(const void *_ptr, int ch, size_t len) {
  const unsigned char *ptr = _ptr;
  for (size_t i = 0; i < len; i++)
    if (ptr[i] == ch)
      return (void *)&ptr[i];
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L7
  add    %rdi,%rdx
  jmp    L32
  nopl   0x0(%rax)
L6:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L7
L32:
  movzbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L6
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *_ptr, int ch, size_t len) {
  const unsigned char *ptr = _ptr;
  for (size_t i = 0; i < len; i++)
    if (ptr[i] == ch)
      return (void *)&ptr[i];
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memchr>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L12
  add    %rdi,%rdx
  jmp    L21
  nopl   0x0(%rax)
L8:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L12
L21:
  movzbl (%rax),%ecx
  cmp    %esi,%ecx
  jne    L8
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *memchr(const void *_ptr, int ch, size_t len) {
  const unsigned char *ptr = _ptr;
  for (size_t i = 0; i < len; i++)
    if (ptr[i] == ch)
      return (void *)&ptr[i];
  return NULL;
}
```