ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readSock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L31
L5:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L5
  jmp    L17
L20:
  nop
L17:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
int readSock(int sock, char *buf, size_t len) {
  ssize_t ret = 0;
  ssize_t bytesread = 0;
  while (bytesread < len) {
    ret = recv(sock, buf + bytesread, len - bytesread, 0);
    if (ret == 0) {
      break;
    }
    if (ret < 0) {
      return -1;
    }
    bytesread += ret;
  }
  return bytesread;
}
```
user: What is the c source code of the assembly code below:

```asm
<readSock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L16
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x0,%ebx
L32:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    $0x0,%ecx
  mov    %r12d,%edi
  call   <recv@plt>
  test   %rax,%rax
  je     L0
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L32
L0:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %rdx,%rbx
  jmp    L0
```

assistant: ```c
int readSock(int sock, char *buf, size_t len) {
  ssize_t ret = 0;
  ssize_t bytesread = 0;
  while (bytesread < len) {
    ret = recv(sock, buf + bytesread, len - bytesread, 0);
    if (ret == 0) {
      break;
    }
    if (ret < 0) {
      return -1;
    }
    bytesread += ret;
  }
  return bytesread;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readSock>:
  endbr64
  test   %rdx,%rdx
  je     L5
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L33
L13:
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L30
L33:
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <recv@plt>
  test   %rax,%rax
  jne    L13
L30:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readSock(int sock, char *buf, size_t len) {
  ssize_t ret = 0;
  ssize_t bytesread = 0;
  while (bytesread < len) {
    ret = recv(sock, buf + bytesread, len - bytesread, 0);
    if (ret == 0) {
      break;
    }
    if (ret < 0) {
      return -1;
    }
    bytesread += ret;
  }
  return bytesread;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readSock>:
  endbr64
  test   %rdx,%rdx
  je     L15
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L16
L35:
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L25
L16:
  mov    %rbp,%rdx
  xor    %ecx,%ecx
  lea    0x0(%r13,%rbx,1),%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <recv@plt>
  test   %rax,%rax
  jne    L35
L25:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readSock(int sock, char *buf, size_t len) {
  ssize_t ret = 0;
  ssize_t bytesread = 0;
  while (bytesread < len) {
    ret = recv(sock, buf + bytesread, len - bytesread, 0);
    if (ret == 0) {
      break;
    }
    if (ret < 0) {
      return -1;
    }
    bytesread += ret;
  }
  return bytesread;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<eaistr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xffffff80,%eax
  cmp    $0x7,%eax
  ja     L70
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D83(%rip),%rax
  jmp    L64
  lea    D51(%rip),%rax
  jmp    L64
  lea    D63(%rip),%rax
  jmp    L64
  lea    D81(%rip),%rax
  jmp    L64
  lea    D6(%rip),%rax
  jmp    L64
  lea    D68(%rip),%rax
  jmp    L64
  lea    D56(%rip),%rax
  jmp    L64
  lea    D92(%rip),%rax
  jmp    L64
L70:
  lea    D106(%rip),%rax
L64:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D83
type_infered: string
name: extract_symbolic_data
arguments: label: D51
type_infered: string
name: extract_symbolic_data
arguments: label: D63
type_infered: string
name: extract_symbolic_data
arguments: label: D81
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D68
type_infered: string
name: extract_symbolic_data
arguments: label: D56
type_infered: string
name: extract_symbolic_data
arguments: label: D92
type_infered: string
name: extract_symbolic_data
arguments: label: D106
type_infered: string

tool: D83: EAI_AGAIN

tool: D51: EAI_BADFLAGS

tool: D63: EAI_FAIL

tool: D81: EAI_FAMILY

tool: D6: EAI_MEMORY

tool: D68: EAI_NONAME

tool: D56: EAI_OVERFLOW

tool: D92: EAI_SYSTEM

tool: D106: UNKNOWN

assistant: ```c
const char *eaistr(int errval) {
  switch (errval) {
  case EAI_AGAIN:
    return "EAI_AGAIN";
  case EAI_BADFLAGS:
    return "EAI_BADFLAGS";
  case EAI_FAIL:
    return "EAI_FAIL";
  case EAI_FAMILY:
    return "EAI_FAMILY";
  case EAI_MEMORY:
    return "EAI_MEMORY";
  case EAI_NONAME:
    return "EAI_NONAME";
  case EAI_OVERFLOW:
    return "EAI_OVERFLOW";
  case EAI_SYSTEM:
    return "EAI_SYSTEM";
  default:
    return "UNKNOWN";
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eaistr>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x7,%edi
  ja     L5
  mov    %edi,%edi
  lea    D70(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D88(%rip),%rax
  ret
  lea    D73(%rip),%rax
  ret
  lea    D1(%rip),%rax
  ret
  lea    D86(%rip),%rax
  ret
  lea    D99(%rip),%rax
  ret
  lea    D12(%rip),%rax
  ret
  lea    D45(%rip),%rax
  ret
L5:
  lea    D34(%rip),%rax
  ret
  lea    D74(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D88
type: string
name: extract_symbolic_data
arguments: data_label: D73
type: string
name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D86
type: string
name: extract_symbolic_data
arguments: data_label: D99
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string
name: extract_symbolic_data
arguments: data_label: D45
type: string
name: extract_symbolic_data
arguments: data_label: D34
type: string
name: extract_symbolic_data
arguments: data_label: D74
type: string

tool: D88: EAI_BADFLAGS

tool: D73: EAI_FAIL

tool: D1: EAI_FAMILY

tool: D86: EAI_MEMORY

tool: D99: EAI_NONAME

tool: D12: EAI_OVERFLOW

tool: D45: EAI_SYSTEM

tool: D34: UNKNOWN

tool: D74: EAI_AGAIN

assistant: ```c
const char *eaistr(int errval) {
  switch (errval) {
  case EAI_AGAIN:
    return "EAI_AGAIN";
  case EAI_BADFLAGS:
    return "EAI_BADFLAGS";
  case EAI_FAIL:
    return "EAI_FAIL";
  case EAI_FAMILY:
    return "EAI_FAMILY";
  case EAI_MEMORY:
    return "EAI_MEMORY";
  case EAI_NONAME:
    return "EAI_NONAME";
  case EAI_OVERFLOW:
    return "EAI_OVERFLOW";
  case EAI_SYSTEM:
    return "EAI_SYSTEM";
  default:
    return "UNKNOWN";
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<eaistr>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x7,%edi
  ja     L4
  lea    D72(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D92(%rip),%rax
  ret
  lea    D7(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D97(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D61(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D2(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D65(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D58(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D98(%rip),%rax
  ret
L4:
  lea    D53(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D92
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D97
data_type: string
name: retrieve_data
arguments: data_label: D61
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D65
data_type: string
name: retrieve_data
arguments: data_label: D58
data_type: string
name: retrieve_data
arguments: data_label: D98
data_type: string
name: retrieve_data
arguments: data_label: D53
data_type: string

tool: D92: EAI_BADFLAGS

tool: D7: EAI_AGAIN

tool: D97: EAI_OVERFLOW

tool: D61: EAI_FAIL

tool: D2: EAI_SYSTEM

tool: D65: EAI_NONAME

tool: D58: EAI_MEMORY

tool: D98: EAI_FAMILY

tool: D53: UNKNOWN

assistant: ```c
const char *eaistr(int errval) {
  switch (errval) {
  case EAI_AGAIN:
    return "EAI_AGAIN";
  case EAI_BADFLAGS:
    return "EAI_BADFLAGS";
  case EAI_FAIL:
    return "EAI_FAIL";
  case EAI_FAMILY:
    return "EAI_FAMILY";
  case EAI_MEMORY:
    return "EAI_MEMORY";
  case EAI_NONAME:
    return "EAI_NONAME";
  case EAI_OVERFLOW:
    return "EAI_OVERFLOW";
  case EAI_SYSTEM:
    return "EAI_SYSTEM";
  default:
    return "UNKNOWN";
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eaistr>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x7,%edi
  ja     L1
  lea    D11(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D23(%rip),%rax
  ret
  lea    D72(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D18(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D92(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D94(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D13(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D54(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D27(%rip),%rax
  ret
L1:
  lea    D26(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D72
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D92
type_infered: string
name: parse_data
arguments: label: D94
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D54
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string

tool: D23: EAI_BADFLAGS

tool: D72: EAI_AGAIN

tool: D18: EAI_OVERFLOW

tool: D92: EAI_FAIL

tool: D94: EAI_SYSTEM

tool: D13: EAI_NONAME

tool: D54: EAI_MEMORY

tool: D27: EAI_FAMILY

tool: D26: UNKNOWN

assistant: ```c
const char *eaistr(int errval) {
  switch (errval) {
  case EAI_AGAIN:
    return "EAI_AGAIN";
  case EAI_BADFLAGS:
    return "EAI_BADFLAGS";
  case EAI_FAIL:
    return "EAI_FAIL";
  case EAI_FAMILY:
    return "EAI_FAMILY";
  case EAI_MEMORY:
    return "EAI_MEMORY";
  case EAI_NONAME:
    return "EAI_NONAME";
  case EAI_OVERFLOW:
    return "EAI_OVERFLOW";
  case EAI_SYSTEM:
    return "EAI_SYSTEM";
  default:
    return "UNKNOWN";
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<pdu_store_phonenumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L28
L1:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <pdu_digit2code@plt>
  mov    %al,(%rbx)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <pdu_digit2code@plt>
  mov    %al,(%rbx)
  subl   $0x2,-0x34(%rbp)
  addl   $0x2,-0x14(%rbp)
L28:
  cmpl   $0x1,-0x34(%rbp)
  ja     L1
  cmpl   $0x0,-0x34(%rbp)
  je     L19
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x46,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <pdu_digit2code@plt>
  mov    %al,(%rbx)
  addl   $0x2,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int pdu_store_phonenumber(char *buffer, const char *number, unsigned length) {
  int i;
  for (i = 0; length > 1; length -= 2, i += 2) {
    buffer[i] = pdu_digit2code(number[i + 1]);
    buffer[i + 1] = pdu_digit2code(number[i]);
  }
  if (length) {
    buffer[i] = 'F';
    buffer[i + 1] = pdu_digit2code(number[i]);
    i += 2;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pdu_store_phonenumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r14
  mov    %edx,%r13d
  cmp    $0x1,%edx
  jbe    L33
  lea    0x1(%rsi),%rbx
  lea    0x1(%rdi),%rbp
  lea    -0x2(%rdx),%r15d
  shr    %r15d
  mov    %r15d,%eax
  lea    0x3(%rsi,%rax,2),%r12
L29:
  movsbl (%rbx),%edi
  call   <pdu_digit2code@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbx),%edi
  call   <pdu_digit2code@plt>
  mov    %al,0x0(%rbp)
  add    $0x2,%rbx
  add    $0x2,%rbp
  cmp    %r12,%rbx
  jne    L29
  and    $0x1,%r13d
  lea    0x2(%r15,%r15,1),%ebx
L7:
  test   %r13d,%r13d
  jne    L17
L16:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    $0x0,%ebx
  jmp    L7
L17:
  movslq %ebx,%rax
  mov    0x8(%rsp),%rcx
  movb   $0x46,(%rcx,%rax,1)
  lea    0x1(%rcx,%rax,1),%rbp
  movsbl (%r14,%rax,1),%edi
  call   <pdu_digit2code@plt>
  mov    %al,0x0(%rbp)
  add    $0x2,%ebx
  jmp    L16
```

assistant: ```c
int pdu_store_phonenumber(char *buffer, const char *number, unsigned length) {
  int i;
  for (i = 0; length > 1; length -= 2, i += 2) {
    buffer[i] = pdu_digit2code(number[i + 1]);
    buffer[i + 1] = pdu_digit2code(number[i]);
  }
  if (length) {
    buffer[i] = 'F';
    buffer[i + 1] = pdu_digit2code(number[i]);
    i += 2;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pdu_store_phonenumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    $0x1,%edx
  jbe    L0
  lea    -0x2(%rdx),%r15d
  lea    0x1(%rsi),%r14
  shr    %r15d
  lea    0x1(%rdi),%rbx
  mov    %r15d,%eax
  lea    0x3(%rsi,%rax,2),%rbp
  nopl   (%rax)
L38:
  movsbl (%r14),%edi
  add    $0x2,%r14
  add    $0x2,%rbx
  call   <pdu_digit2code@plt>
  mov    %al,-0x3(%rbx)
  movsbl -0x3(%r14),%edi
  call   <pdu_digit2code@plt>
  mov    %al,-0x2(%rbx)
  cmp    %rbp,%r14
  jne    L38
  and    $0x1,%r12d
  lea    0x2(%r15,%r15,1),%r15d
L24:
  test   %r12d,%r12d
  jne    L26
L35:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%rcx
  movslq %r15d,%rax
  add    $0x2,%r15d
  movb   $0x46,(%rcx,%rax,1)
  movsbl 0x0(%r13,%rax,1),%edi
  lea    0x1(%rcx,%rax,1),%rbx
  call   <pdu_digit2code@plt>
  mov    %al,(%rbx)
  jmp    L35
  nopl   0x0(%rax)
L0:
  xor    %r15d,%r15d
  jmp    L24
```

assistant: ```c
int pdu_store_phonenumber(char *buffer, const char *number, unsigned length) {
  int i;
  for (i = 0; length > 1; length -= 2, i += 2) {
    buffer[i] = pdu_digit2code(number[i + 1]);
    buffer[i + 1] = pdu_digit2code(number[i]);
  }
  if (length) {
    buffer[i] = 'F';
    buffer[i + 1] = pdu_digit2code(number[i]);
    i += 2;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdu_store_phonenumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    $0x1,%edx
  jbe    L1
  lea    -0x2(%rdx),%r15d
  lea    0x1(%rsi),%r14
  shr    %r15d
  lea    0x1(%rdi),%rbx
  mov    %r15d,%eax
  lea    0x3(%rsi,%rax,2),%rbp
  nopl   (%rax)
L29:
  movsbl (%r14),%edi
  add    $0x2,%r14
  add    $0x2,%rbx
  call   <pdu_digit2code@plt>
  mov    %al,-0x3(%rbx)
  movsbl -0x3(%r14),%edi
  call   <pdu_digit2code@plt>
  mov    %al,-0x2(%rbx)
  cmp    %rbp,%r14
  jne    L29
  and    $0x1,%r12d
  lea    0x2(%r15,%r15,1),%r15d
L14:
  test   %r12d,%r12d
  jne    L21
L42:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    0x8(%rsp),%rcx
  movslq %r15d,%rax
  add    $0x2,%r15d
  movb   $0x46,(%rcx,%rax,1)
  movsbl 0x0(%r13,%rax,1),%edi
  lea    0x1(%rcx,%rax,1),%rbx
  call   <pdu_digit2code@plt>
  mov    %al,(%rbx)
  jmp    L42
  nopl   0x0(%rax)
L1:
  xor    %r15d,%r15d
  jmp    L14
```

assistant: ```c
int pdu_store_phonenumber(char *buffer, const char *number, unsigned length) {
  int i;
  for (i = 0; length > 1; length -= 2, i += 2) {
    buffer[i] = pdu_digit2code(number[i + 1]);
    buffer[i + 1] = pdu_digit2code(number[i]);
  }
  if (length) {
    buffer[i] = 'F';
    buffer[i + 1] = pdu_digit2code(number[i]);
    i += 2;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<st_numhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int st_numhash(x, size)
char *x;
int size;
{ return ((((int)x) < 0 ? -((int)x) : ((int)x)) % (size)); }
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<st_numhash>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int st_numhash(x, size)
char *x;
int size;
{ return ((((int)x) < 0 ? -((int)x) : ((int)x)) % (size)); }
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<st_numhash>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int st_numhash(x, size)
char *x;
int size;
{ return ((((int)x) < 0 ? -((int)x) : ((int)x)) % (size)); }
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<st_numhash>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int st_numhash(x, size)
char *x;
int size;
{ return ((((int)x) < 0 ? -((int)x) : ((int)x)) % (size)); }
```
user: What would the C source look like for the assembly code provided here?

```asm
<charCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L7
  addl   $0x1,-0x4(%rbp)
L7:
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int charCount(char c, char *s) {
  int i = 0;
  int count = 0;
  while (s[i] != 0) {
    if (s[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<charCount>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L25
  add    $0x1,%rsi
  mov    $0x0,%edx
L7:
  cmp    %al,%dil
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L7
L23:
  mov    %edx,%eax
  ret
L25:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int charCount(char c, char *s) {
  int i = 0;
  int count = 0;
  while (s[i] != 0) {
    if (s[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<charCount>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L4
  add    $0x1,%rsi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %al,%dil
  sete   %al
  add    $0x1,%rsi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int charCount(char c, char *s) {
  int i = 0;
  int count = 0;
  while (s[i] != 0) {
    if (s[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<charCount>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L9
  add    $0x1,%rsi
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L12:
  cmp    %dil,%al
  sete   %al
  add    $0x1,%rsi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  jne    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int charCount(char c, char *s) {
  int i = 0;
  int count = 0;
  while (s[i] != 0) {
    if (s[i] == c)
      count++;
    i++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <inputfloat@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <inputfloat@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <inputfloat@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L90
  movss  -0xc(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  je     L52
L90:
  movss  -0x8(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L51
  movss  -0x8(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  je     L52
L51:
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L42
L52:
  movss  -0xc(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L75
  movss  -0xc(%rbp),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jne    L75
  movss  -0x8(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L75
  movss  -0x8(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L75
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L42
L75:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L42:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D52
datatype: string
name: read_data
arguments: label: D32
datatype: string
name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D22
datatype: string

tool: D3: a

tool: D11: b

tool: D52: c

tool: D32: Triangolo scaleno


tool: D5: Triangolo equilatero


tool: D22: Triangolo isoscele


assistant: ```c
int main() {
  float a, b, c;
  a = inputfloat("a", a);
  b = inputfloat("b", b);
  c = inputfloat("c", c);
  if (a != b && b != c) {
    printf("Triangolo scaleno\n");
  } else if (a == b && b == c) {
    printf("Triangolo equilatero\n");
  } else {
    printf("Triangolo isoscele\n");
  }
}
```