ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lxc_af_unix_connect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L36
  mov    $0xffffffff,%eax
  jmp    L53
L36:
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L67
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L51
L67:
  mov    $0x4,%edx
L51:
  mov    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <memcpy@plt>
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L33
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    D19(%rip),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L53
L33:
  mov    -0x18(%rbp),%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int lxc_af_unix_connect(const char *path) {
  int fd;
  struct sockaddr_un addr;
  fd = socket(PF_UNIX, SOCK_STREAM, 0);
  if (fd < 0)
    return -1;
  memset(&addr, 0, sizeof(addr));
  addr.sun_family = AF_UNIX;
  memcpy(addr.sun_path, path, path[0] ? strlen(path) : sizeof(addr.sun_path));
  if (connect(fd, (struct sockaddr *)&addr, sizeof(addr))) {
    int tmp = errno;
    close(fd);
    errno = tmp;
    return -1;
  }
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lxc_af_unix_connect>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D36(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L19
  mov    %eax,%ebx
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x4,%edx
  cmpb   $0x0,0x0(%rbp)
  jne    L12
L8:
  mov    %rbp,%rsi
  mov    (%rsp),%edi
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %ebx,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L0
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L8
L0:
  mov    D38(%rip),%rbp
  mov    0x0(%rbp),%r12d
  mov    %ebx,%edi
  call   <close@plt>
  mov    %r12d,0x0(%rbp)
  mov    $0xffffffff,%ebx
  jmp    L59
L19:
  mov    $0xffffffff,%ebx
  jmp    L59
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lxc_af_unix_connect(const char *path) {
  int fd;
  struct sockaddr_un addr;
  fd = socket(PF_UNIX, SOCK_STREAM, 0);
  if (fd < 0)
    return -1;
  memset(&addr, 0, sizeof(addr));
  addr.sun_family = AF_UNIX;
  memcpy(addr.sun_path, path, path[0] ? strlen(path) : sizeof(addr.sun_path));
  if (connect(fd, (struct sockaddr *)&addr, sizeof(addr))) {
    int tmp = errno;
    close(fd);
    errno = tmp;
    return -1;
  }
  return fd;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lxc_af_unix_connect>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L20
  mov    %rsp,%rbp
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  cmpb   $0x0,0x0(%r13)
  mov    $0x4,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  jne    L18
L67:
  mov    (%rsp),%edi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L11
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L67
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%r12d
  jmp    L29
L11:
  mov    D31(%rip),%rbp
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  mov    0x0(%rbp),%r13d
  call   <close@plt>
  mov    %r13d,0x0(%rbp)
  jmp    L29
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lxc_af_unix_connect(const char *path) {
  int fd;
  struct sockaddr_un addr;
  fd = socket(PF_UNIX, SOCK_STREAM, 0);
  if (fd < 0)
    return -1;
  memset(&addr, 0, sizeof(addr));
  addr.sun_family = AF_UNIX;
  memcpy(addr.sun_path, path, path[0] ? strlen(path) : sizeof(addr.sun_path));
  if (connect(fd, (struct sockaddr *)&addr, sizeof(addr))) {
    int tmp = errno;
    close(fd);
    errno = tmp;
    return -1;
  }
  return fd;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lxc_af_unix_connect>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  test   %eax,%eax
  js     L1
  mov    %rsp,%rbp
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  cmpb   $0x0,0x0(%r13)
  mov    $0x4,%edx
  mov    D35(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  jne    L23
L12:
  mov    (%rsp),%edi
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L20
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L23:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  jmp    L12
  nopl   0x0(%rax)
L1:
  mov    $0xffffffff,%r12d
  jmp    L16
L20:
  mov    D39(%rip),%rbp
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  mov    0x0(%rbp),%r13d
  call   <close@plt>
  mov    %r13d,0x0(%rbp)
  jmp    L16
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lxc_af_unix_connect(const char *path) {
  int fd;
  struct sockaddr_un addr;
  fd = socket(PF_UNIX, SOCK_STREAM, 0);
  if (fd < 0)
    return -1;
  memset(&addr, 0, sizeof(addr));
  addr.sun_family = AF_UNIX;
  memcpy(addr.sun_path, path, path[0] ? strlen(path) : sizeof(addr.sun_path));
  if (connect(fd, (struct sockaddr *)&addr, sizeof(addr))) {
    int tmp = errno;
    close(fd);
    errno = tmp;
    return -1;
  }
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<TimeTToTimeVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
struct timeval TimeTToTimeVal(const time_t t) {
  struct timeval tv;
  tv.tv_sec = t;
  tv.tv_usec = 0;
  return tv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimeTToTimeVal>:
  endbr64
  mov    %edi,%edx
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct timeval TimeTToTimeVal(const time_t t) {
  struct timeval tv;
  tv.tv_sec = t;
  tv.tv_usec = 0;
  return tv;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TimeTToTimeVal>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  ret
```

assistant: ```c
struct timeval TimeTToTimeVal(const time_t t) {
  struct timeval tv;
  tv.tv_sec = t;
  tv.tv_usec = 0;
  return tv;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<TimeTToTimeVal>:
  endbr64
  mov    %edi,%edx
  xor    %eax,%eax
  ret
```

assistant: ```c
struct timeval TimeTToTimeVal(const time_t t) {
  struct timeval tv;
  tv.tv_sec = t;
  tv.tv_usec = 0;
  return tv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sprint_mov_to_direct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: MOV   0x%02X, A                   

assistant: ```c
void sprint_mov_to_direct(char *str, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", A                   ",
          direct);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sprint_mov_to_direct>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  lea    D5(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: MOV   0x%02X, A                   

assistant: ```c
void sprint_mov_to_direct(char *str, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", A                   ",
          direct);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sprint_mov_to_direct>:
  endbr64
  mov    %esi,%edx
  lea    D9(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: MOV   0x%02X, A                   

assistant: ```c
void sprint_mov_to_direct(char *str, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", A                   ",
          direct);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sprint_mov_to_direct>:
  endbr64
  mov    %esi,%edx
  lea    D6(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: MOV   0x%02X, A                   

assistant: ```c
void sprint_mov_to_direct(char *str, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", A                   ",
          direct);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pkcs7_decrypt_rinfo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%esi
  call   <EVP_PKEY_CTX_new@plt>
  mov    $0xffffffff,%r14d
  test   %rax,%rax
  je     L79
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <EVP_PKEY_decrypt_init@plt>
  test   %rax,%rax
  jle    L83
  mov    %rbp,%r9
  mov    $0x0,%r8d
  mov    D33(%rip),%rax
  mov    (%rax),%ecx
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <EVP_PKEY_CTX_ctrl@plt>
  test   %rax,%rax
  jle    L96
  mov    0x0(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %rsp,%rdx
  mov    (%rax),%r8d
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <EVP_PKEY_decrypt@plt>
  test   %rax,%rax
  jle    L87
  mov    (%rsp),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L50
  mov    0x0(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    %rsp,%rdx
  mov    (%rax),%r8d
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <EVP_PKEY_decrypt@plt>
  test   %rax,%rax
  jle    L49
  mov    (%r12),%esi
  mov    0x0(%r13),%rdi
  call   <freezero@plt>
  mov    %r14,0x0(%r13)
  mov    (%rsp),%rax
  mov    %eax,(%r12)
  mov    $0x1,%r14d
  jmp    L13
L96:
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <PKCS7error@plt>
  jmp    L13
L50:
  mov    D26(%rip),%rax
  mov    (%rax),%edi
  call   <PKCS7error@plt>
  mov    $0xffffffff,%r14d
  jmp    L13
L49:
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <PKCS7error@plt>
  mov    %rbx,%rdi
  call   <EVP_PKEY_CTX_free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    $0x0,%r14d
  jmp    L79
L83:
  mov    $0xffffffff,%r14d
L13:
  mov    %rbx,%rdi
  call   <EVP_PKEY_CTX_free@plt>
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  mov    %r14d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L87:
  mov    $0xffffffff,%r14d
  jmp    L13
L102:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pkcs7_decrypt_rinfo(unsigned char **pek, int *peklen, PKCS7_RECIP_INFO *ri, EVP_PKEY *pkey) {
  EVP_PKEY_CTX *pctx = NULL;
  unsigned char *ek = NULL;
  size_t eklen;
  int ret = -1;
  pctx = EVP_PKEY_CTX_new(pkey, NULL);
  if (!pctx)
    return -1;
  if (EVP_PKEY_decrypt_init(pctx) <= 0)
    goto err;
  if (EVP_PKEY_CTX_ctrl(pctx, -1, EVP_PKEY_OP_DECRYPT, EVP_PKEY_CTRL_PKCS7_DECRYPT, 0, ri) <= 0) {
    PKCS7error(PKCS7_R_CTRL_ERROR);
    goto err;
  }
  if (EVP_PKEY_decrypt(pctx, NULL, &eklen, ri->enc_key->data, ri->enc_key->length) <= 0)
    goto err;
  ek = malloc(eklen);
  if (ek == NULL) {
    PKCS7error(ERR_R_MALLOC_FAILURE);
    goto err;
  }
  if (EVP_PKEY_decrypt(pctx, ek, &eklen, ri->enc_key->data, ri->enc_key->length) <= 0) {
    ret = 0;
    PKCS7error(ERR_R_EVP_LIB);
    goto err;
  }
  ret = 1;
  freezero(*pek, *peklen);
  *pek = ek;
  *peklen = eklen;
err:
  EVP_PKEY_CTX_free(pctx);
  if (!ret && ek)
    free(ek);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insert_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L35:
  lea    -0x14(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utf8_tounicode@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insert_char@plt>
  test   %rax,%rax
  je     L6
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x2c(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x38(%rbp)
L17:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  jmp    L23
L6:
  nop
L23:
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int insert_chars(struct current *current, int pos, const char *chars) {
  int inserted = 0;
  while (*chars) {
    int ch;
    int n = utf8_tounicode(chars, &ch);
    if (insert_char(current, pos, ch) == 0) {
      break;
    }
    inserted++;
    pos++;
    chars += n;
  }
  return inserted;
}
```
user: What is the c source code of the assembly code below:

```asm
<insert_chars>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  je     L14
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbp
  mov    $0x0,%r12d
  lea    0x4(%rsp),%r15
L0:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <utf8_tounicode@plt>
  mov    %eax,%ebx
  lea    (%r12,%r14,1),%esi
  mov    0x4(%rsp),%edx
  mov    %r13,%rdi
  call   <insert_char@plt>
  test   %rax,%rax
  je     L19
  add    $0x1,%r12d
  movslq %ebx,%rbx
  add    %rbx,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L0
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    $0x0,%r12d
  jmp    L19
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int insert_chars(struct current *current, int pos, const char *chars) {
  int inserted = 0;
  while (*chars) {
    int ch;
    int n = utf8_tounicode(chars, &ch);
    if (insert_char(current, pos, ch) == 0) {
      break;
    }
    inserted++;
    pos++;
    chars += n;
  }
  return inserted;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insert_chars>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  je     L43
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbp
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r15
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L1:
  add    %rbx,%rbp
  add    $0x1,%r12d
  cmpb   $0x0,0x0(%rbp)
  je     L39
L55:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <utf8_tounicode@plt>
  mov    0x4(%rsp),%edx
  lea    (%r12,%r14,1),%esi
  mov    %r13,%rdi
  movslq %eax,%rbx
  call   <insert_char@plt>
  test   %rax,%rax
  jne    L1
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  xor    %r12d,%r12d
  jmp    L39
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int insert_chars(struct current *current, int pos, const char *chars) {
  int inserted = 0;
  while (*chars) {
    int ch;
    int n = utf8_tounicode(chars, &ch);
    if (insert_char(current, pos, ch) == 0) {
      break;
    }
    inserted++;
    pos++;
    chars += n;
  }
  return inserted;
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_chars>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  je     L6
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%rbp
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r15
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L5:
  add    %rbx,%rbp
  add    $0x1,%r12d
  cmpb   $0x0,0x0(%rbp)
  je     L41
L17:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <utf8_tounicode@plt>
  mov    0x4(%rsp),%edx
  lea    (%r12,%r14,1),%esi
  mov    %r13,%rdi
  movslq %eax,%rbx
  call   <insert_char@plt>
  test   %rax,%rax
  jne    L5
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  xor    %r12d,%r12d
  jmp    L41
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int insert_chars(struct current *current, int pos, const char *chars) {
  int inserted = 0;
  while (*chars) {
    int ch;
    int n = utf8_tounicode(chars, &ch);
    if (insert_char(current, pos, ch) == 0) {
      break;
    }
    inserted++;
    pos++;
    chars += n;
  }
  return inserted;
}
```
user: What is the c source code of the assembly code below:

```asm
<nmm_get_cpu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nmm_get_cpu(int *cpu, int *ierr) {
  *cpu = 0;
  *ierr = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nmm_get_cpu>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x0,(%rsi)
  ret
```

assistant: ```c
void nmm_get_cpu(int *cpu, int *ierr) {
  *cpu = 0;
  *ierr = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nmm_get_cpu>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x0,(%rsi)
  ret
```

assistant: ```c
void nmm_get_cpu(int *cpu, int *ierr) {
  *cpu = 0;
  *ierr = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nmm_get_cpu>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x0,(%rsi)
  ret
```

assistant: ```c
void nmm_get_cpu(int *cpu, int *ierr) {
  *cpu = 0;
  *ierr = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D4(%rip),%rax
  cmp    %rax,-0x8(%rbp)
  jb     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
cfree(addr) char *addr;
{
  extern end;
  if (addr >= &end)
    free(addr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cfree>:
  endbr64
  cmp    D7(%rip),%rdi
  jae    L5
  ret
L5:
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
cfree(addr) char *addr;
{
  extern end;
  if (addr >= &end)
    free(addr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cfree>:
  endbr64
  cmp    D7(%rip),%rdi
  jae    L1
  ret
  xchg   %ax,%ax
L1:
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
cfree(addr) char *addr;
{
  extern end;
  if (addr >= &end)
    free(addr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cfree>:
  endbr64
  cmp    D3(%rip),%rdi
  jae    L4
  ret
  xchg   %ax,%ax
L4:
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
cfree(addr) char *addr;
{
  extern end;
  if (addr >= &end)
    free(addr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L12:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  jne    L6
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L6:
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x64,-0x4(%rbp)
  jle    L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D3: *

tool: D11: 


assistant: ```c
int main(void) {
  int star = 1;
  for (star = 1; star <= 100; star++) {
    printf("*");
    while (star % 10 == 0) {
      printf("\n");
      break;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D26(%rip),%rbp
  lea    D24(%rip),%r12
L23:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L13
  mov    %rbp,%rdi
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  cmp    %eax,%ebx
  jne    L23
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L23
L13:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string

tool: D26: *

tool: D24: 


assistant: ```c
int main(void) {
  int star = 1;
  for (star = 1; star <= 100; star++) {
    printf("*");
    while (star % 10 == 0) {
      printf("\n");
      break;
    }
  }
  return 0;
}
```