ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<putword>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%eax
  mov    %al,0x1(%rdi)
  ret
```

assistant: ```c
void putword(unsigned char *p, int a) {
  p[0] = a;
  p[1] = a >> 8;
}
```
user: What is the c source code of the assembly code below:

```asm
<putword>:
  endbr64
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void putword(unsigned char *p, int a) {
  p[0] = a;
  p[1] = a >> 8;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putword>:
  endbr64
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void putword(unsigned char *p, int a) {
  p[0] = a;
  p[1] = a >> 8;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  movabs $0x3635343332313039,%rdx
  mov    %rax,-0x80(%rbp)
  mov    %rdx,-0x78(%rbp)
  movabs $0x3433323130393837,%rax
  movabs $0x3231303938373635,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movabs $0x3039383736353433,%rax
  movabs $0x3837363534333231,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movabs $0x6463626132313039,%rax
  movabs $0x6c6b6a6968676665,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x74737271706f6e6d,%rax
  movabs $0x42417a7978777675,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x4a49484746454443,%rax
  movabs $0x5251504f4e4d4c4b,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x5a59585756555453,%rax
  mov    %rax,-0x20(%rbp)
  movb   $0x0,-0x18(%rbp)
  lea    -0x80(%rbp),%rax
  mov    $0x68,%edx
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <test_output_string@plt>
  lea    -0x80(%rbp),%rax
  mov    $0x69,%edx
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <test_output_memory@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D6: test

assistant: ```c
int test_output(void) {
  const char s[] = "1234567890123456789012345678901234567890123456789012"
                   "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  test_output_string("test", s, sizeof(s) - 1);
  test_output_memory("test", (const unsigned char *)s, sizeof(s));
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_output>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  movabs $0x3635343332313039,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x3433323130393837,%rax
  movabs $0x3231303938373635,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x3039383736353433,%rax
  movabs $0x3837363534333231,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x6463626132313039,%rax
  movabs $0x6c6b6a6968676665,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x74737271706f6e6d,%rax
  movabs $0x42417a7978777675,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x4a49484746454443,%rax
  movabs $0x5251504f4e4d4c4b,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x5a59585756555453,%rax
  mov    %rax,0x60(%rsp)
  movb   $0x0,0x68(%rsp)
  mov    %rsp,%rbp
  mov    $0x68,%edx
  mov    %rbp,%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <test_output_string@plt>
  mov    $0x69,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <test_output_memory@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: test

assistant: ```c
int test_output(void) {
  const char s[] = "1234567890123456789012345678901234567890123456789012"
                   "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  test_output_string("test", s, sizeof(s) - 1);
  test_output_memory("test", (const unsigned char *)s, sizeof(s));
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_output>:
  endbr64
  push   %r12
  mov    $0x68,%edx
  push   %rbp
  lea    D25(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x88,%rsp
  movdqa D53(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movb   $0x0,0x68(%rsp)
  movabs $0x5a59585756555453,%rax
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rax,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D45(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D22(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D42(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <test_output_string@plt>
  mov    $0x69,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <test_output_memory@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x88,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
datatype: string
name: disassemble_data
arguments: label: D53
datatype: byte[16]
name: disassemble_data
arguments: label: D5
datatype: byte[16]
name: disassemble_data
arguments: label: D45
datatype: byte[16]
name: disassemble_data
arguments: label: D7
datatype: byte[16]
name: disassemble_data
arguments: label: D22
datatype: byte[16]
name: disassemble_data
arguments: label: D42
datatype: byte[16]

tool: D25: test

tool: {"D53": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36]}

tool: {"D5": [0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32]}

tool: {"D45": [0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38]}

tool: {"D7": [0x39,0x30,0x31,0x32,0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c]}

tool: {"D22": [0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x41,0x42]}

tool: {"D42": [0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50,0x51,0x52]}

assistant: ```c
int test_output(void) {
  const char s[] = "1234567890123456789012345678901234567890123456789012"
                   "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  test_output_string("test", s, sizeof(s) - 1);
  test_output_memory("test", (const unsigned char *)s, sizeof(s));
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_output>:
  endbr64
  push   %r12
  mov    $0x68,%edx
  push   %rbp
  lea    D59(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x88,%rsp
  movdqa D42(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movb   $0x0,0x68(%rsp)
  movabs $0x5a59585756555453,%rax
  movaps %xmm0,(%rsp)
  movdqa D0(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rax,0x60(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D61(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D1(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D15(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D11(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <test_output_string@plt>
  mov    $0x69,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <test_output_memory@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x88,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D59
data_type: string
name: disassemble_data
arguments: data_label: D42
data_type: byte[16]
name: disassemble_data
arguments: data_label: D0
data_type: byte[16]
name: disassemble_data
arguments: data_label: D61
data_type: byte[16]
name: disassemble_data
arguments: data_label: D1
data_type: byte[16]
name: disassemble_data
arguments: data_label: D15
data_type: byte[16]
name: disassemble_data
arguments: data_label: D11
data_type: byte[16]

tool: D59: test

tool: {"D42": [0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36]}

tool: {"D0": [0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32]}

tool: {"D61": [0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38]}

tool: {"D1": [0x39,0x30,0x31,0x32,0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69,0x6a,0x6b,0x6c]}

tool: {"D15": [0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x41,0x42]}

tool: {"D11": [0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50,0x51,0x52]}

assistant: ```c
int test_output(void) {
  const char s[] = "1234567890123456789012345678901234567890123456789012"
                   "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  test_output_string("test", s, sizeof(s) - 1);
  test_output_memory("test", (const unsigned char *)s, sizeof(s));
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <failure@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: list should not have been null

assistant: ```c
void test_new(struct list *list) {
  if (list == NULL)
    failure("list should not have been null");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_new>:
  endbr64
  test   %rdi,%rdi
  je     L3
  ret
L3:
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <failure@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: list should not have been null

assistant: ```c
void test_new(struct list *list) {
  if (list == NULL)
    failure("list should not have been null");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_new>:
  endbr64
  test   %rdi,%rdi
  je     L9
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D6(%rip),%rdi
  jmp    1050 <failure@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: list should not have been null

assistant: ```c
void test_new(struct list *list) {
  if (list == NULL)
    failure("list should not have been null");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_new>:
  endbr64
  test   %rdi,%rdi
  je     L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D7(%rip),%rdi
  jmp    1050 <failure@plt>
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: list should not have been null

assistant: ```c
void test_new(struct list *list) {
  if (list == NULL)
    failure("list should not have been null");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x61,-0x4(%rbp)
  jmp    L1
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x7a,-0x4(%rbp)
  jle    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  int i;
  i = 'a';
  while (i <= 'z') {
    ft_putchar(i);
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
L7:
  mov    %ebx,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  int i;
  i = 'a';
  while (i <= 'z') {
    ft_putchar(i);
    i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  int i;
  i = 'a';
  while (i <= 'z') {
    ft_putchar(i);
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_print_alphabet>:
  endbr64
  push   %rbx
  mov    $0x61,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    $0x7b,%ebx
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void ft_print_alphabet(void) {
  int i;
  i = 'a';
  while (i <= 'z') {
    ft_putchar(i);
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numpalin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <num_inverso@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L11
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L11:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D7: 
El nombre introducido ES un palindromo

tool: D16: 
El nombre introducido NO es un palindromo

assistant: ```c
void numpalin(int p) {
  if (p == num_inverso(p))
    printf("\nEl nombre introducido ES un palindromo");
  else
    printf("\nEl nombre introducido NO es un palindromo");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numpalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L10
  lea    D5(%rip),%rdi
  call   <printf@plt>
L19:
  pop    %rbx
  ret
L10:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D5: 
El nombre introducido NO es un palindromo

tool: D14: 
El nombre introducido ES un palindromo

assistant: ```c
void numpalin(int p) {
  if (p == num_inverso(p))
    printf("\nEl nombre introducido ES un palindromo");
  else
    printf("\nEl nombre introducido NO es un palindromo");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numpalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L6
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
  nopl   (%rax)
L6:
  lea    D7(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D5: 
El nombre introducido NO es un palindromo

tool: D7: 
El nombre introducido ES un palindromo

assistant: ```c
void numpalin(int p) {
  if (p == num_inverso(p))
    printf("\nEl nombre introducido ES un palindromo");
  else
    printf("\nEl nombre introducido NO es un palindromo");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numpalin>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L4
  lea    D6(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
  nopl   (%rax)
L4:
  lea    D4(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string

tool: D6: 
El nombre introducido NO es un palindromo

tool: D4: 
El nombre introducido ES un palindromo

assistant: ```c
void numpalin(int p) {
  if (p == num_inverso(p))
    printf("\nEl nombre introducido ES un palindromo");
  else
    printf("\nEl nombre introducido NO es un palindromo");
}
```
user: Translate the below assembly code into C programming language:

```asm
<http1_atol16>:
  endbr64
  mov    %rdi,%rdx
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  ja     L169
  movabs $0x100001200,%rcx
  bt     %rax,%rcx
  jae    L169
  lea    0x20(%rdi),%rcx
  movabs $0x100001200,%rdi
  jmp    L118
L168:
  bt     %rax,%rdi
  jae    L169
  cmp    %rcx,%rdx
  je     L101
L118:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  cmp    $0x20,%al
  jbe    L168
L169:
  movzbl (%rdx),%eax
  cmp    $0x2d,%al
  sete   %r8b
  lea    -0x2b(%rax),%r9d
  mov    $0x0,%ecx
  mov    $0x0,%edi
  test   $0xfd,%r9b
  jne    L99
L156:
  add    $0x1,%rdx
  xor    %r8d,%edi
  add    $0x1,%ecx
  movzbl (%rdx),%eax
  cmp    $0x2d,%al
  sete   %r8b
  lea    -0x2b(%rax),%r9d
  test   $0xfd,%r9b
  jne    L99
  cmp    $0x1f,%ecx
  jle    L156
L99:
  cmp    $0x30,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdx
  movzbl (%rdx),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdx
  cmpb   $0x30,(%rdx)
  jne    L26
  mov    $0x0,%eax
L54:
  add    $0x1,%rdx
  add    $0x1,%eax
  cmpb   $0x30,(%rdx)
  jne    L26
  cmp    $0x1f,%eax
  jle    L54
L26:
  mov    $0x0,%eax
  movabs $0xf000000000000000,%r8
  jmp    L128
L101:
  mov    %rcx,%rdx
  jmp    L169
L116:
  or     $0x20,%ecx
  lea    -0x61(%rcx),%r9d
  cmp    $0x5,%r9b
  ja     L1
  shl    $0x4,%rax
  movsbl %cl,%ecx
  sub    $0x57,%ecx
  movslq %ecx,%rcx
  or     %rcx,%rax
L61:
  add    $0x1,%rdx
  test   %r8,%rax
  jne    L1
L128:
  movzbl (%rdx),%ecx
  lea    -0x30(%rcx),%r9d
  cmp    $0x9,%r9b
  ja     L116
  shl    $0x4,%rax
  movsbl %cl,%ecx
  sub    $0x30,%ecx
  movslq %ecx,%rcx
  or     %rcx,%rax
  jmp    L61
L1:
  mov    %rax,%rcx
  neg    %rcx
  test   %dil,%dil
  cmovne %rcx,%rax
  test   %rsi,%rsi
  je     L50
  mov    %rdx,(%rsi)
L50:
  ret
```

assistant: ```c
long long http1_atol16(const uint8_t *buf, const uint8_t **end) {
  register unsigned long long i = 0;
  uint8_t inv = 0;
  for (int limit_ = 0; (*buf == ' ' || *buf == '\t' || *buf == '\f') && limit_ < 32; ++limit_)
    ++buf;
  for (int limit_ = 0; (*buf == '-' || *buf == '+') && limit_ < 32; ++limit_)
    inv ^= (*(buf++) == '-');
  if (*buf == '0')
    ++buf;
  if ((*buf | 32) == 'x')
    ++buf;
  for (int limit_ = 0; (*buf == '0') && limit_ < 32; ++limit_)
    ++buf;
  while (!(i & (~((~(0ULL)) >> 4)))) {
    if (*buf >= '0' && *buf <= '9') {
      i <<= 4;
      i |= *buf - '0';
    } else if ((*buf | 32) >= 'a' && (*buf | 32) <= 'f') {
      i <<= 4;
      i |= (*buf | 32) - ('a' - 10);
    } else
      break;
    ++buf;
  }
  if (inv)
    i = 0ULL - i;
  if (end)
    *end = buf;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<http1_atol16>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  mov    %rsi,%r8
  cmp    $0x20,%al
  ja     L58
  movabs $0xfffffffeffffedff,%rsi
  bt     %rax,%rsi
  jb     L219
  lea    0x20(%rdi),%rcx
  nopl   0x0(%rax)
L129:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  cmp    $0x20,%al
  jbe    L119
L58:
  cmp    $0x2d,%al
  lea    -0x2b(%rax),%ecx
  sete   %sil
  and    $0xfd,%ecx
  jne    L32
  xor    %ecx,%ecx
  xor    %edi,%edi
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L130:
  cmp    $0x20,%ecx
  je     L75
L101:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  xor    %esi,%edi
  add    $0x1,%ecx
  lea    -0x2b(%rax),%r9d
  cmp    $0x2d,%al
  sete   %sil
  and    $0xfd,%r9d
  je     L130
L75:
  cmp    $0x30,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdx
L4:
  movzbl (%rdx),%ecx
  mov    %ecx,%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  jne    L177
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
L177:
  cmp    $0x30,%cl
  jne    L79
  xor    %eax,%eax
  jmp    L50
  nopl   (%rax)
L172:
  cmp    $0x30,%cl
  jne    L79
L50:
  add    $0x1,%eax
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    $0x20,%eax
  jne    L172
L79:
  movabs $0xf000000000000000,%r9
  xor    %eax,%eax
  jmp    L159
  nopw   0x0(%rax,%rax,1)
L171:
  shl    $0x4,%rax
  movsbq %sil,%rsi
  add    $0x1,%rdx
  or     %rsi,%rax
  test   %r9,%rax
  jne    L192
L108:
  movzbl (%rdx),%ecx
L159:
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L171
  or     $0x20,%ecx
  lea    -0x61(%rcx),%esi
  cmp    $0x5,%sil
  ja     L192
  sub    $0x57,%ecx
  shl    $0x4,%rax
  add    $0x1,%rdx
  movsbq %cl,%rcx
  or     %rcx,%rax
  test   %r9,%rax
  je     L108
L192:
  mov    %rax,%rcx
  neg    %rcx
  test   %dil,%dil
  cmovne %rcx,%rax
  test   %r8,%r8
  je     L105
  mov    %rdx,(%r8)
  ret
  nopl   0x0(%rax)
L119:
  bt     %rax,%rsi
  jb     L219
  cmp    %rdx,%rcx
  jne    L129
L194:
  mov    %rcx,%rdx
  xor    %edi,%edi
  jmp    L4
  nopl   0x0(%rax)
L105:
  ret
L219:
  mov    %rdx,%rcx
  jmp    L194
L32:
  xor    %edi,%edi
  jmp    L75
```

assistant: ```c
long long http1_atol16(const uint8_t *buf, const uint8_t **end) {
  register unsigned long long i = 0;
  uint8_t inv = 0;
  for (int limit_ = 0; (*buf == ' ' || *buf == '\t' || *buf == '\f') && limit_ < 32; ++limit_)
    ++buf;
  for (int limit_ = 0; (*buf == '-' || *buf == '+') && limit_ < 32; ++limit_)
    inv ^= (*(buf++) == '-');
  if (*buf == '0')
    ++buf;
  if ((*buf | 32) == 'x')
    ++buf;
  for (int limit_ = 0; (*buf == '0') && limit_ < 32; ++limit_)
    ++buf;
  while (!(i & (~((~(0ULL)) >> 4)))) {
    if (*buf >= '0' && *buf <= '9') {
      i <<= 4;
      i |= *buf - '0';
    } else if ((*buf | 32) >= 'a' && (*buf | 32) <= 'f') {
      i <<= 4;
      i |= (*buf | 32) - ('a' - 10);
    } else
      break;
    ++buf;
  }
  if (inv)
    i = 0ULL - i;
  if (end)
    *end = buf;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<http1_atol16>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rsi,%r9
  cmp    $0x20,%al
  ja     L83
  movabs $0xfffffffeffffedff,%rcx
  bt     %rax,%rcx
  jb     L78
  lea    0x20(%rdi),%rdx
  cs nopw 0x0(%rax,%rax,1)
L163:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  jbe    L116
L83:
  cmp    $0x2d,%al
  lea    -0x2b(%rax),%edx
  sete   %cl
  and    $0xfd,%edx
  jne    L112
  xor    %edx,%edx
  xor    %r8d,%r8d
  jmp    L144
  nopl   0x0(%rax,%rax,1)
L257:
  cmp    $0x20,%edx
  je     L148
L144:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  xor    %ecx,%r8d
  add    $0x1,%edx
  lea    -0x2b(%rax),%esi
  cmp    $0x2d,%al
  sete   %cl
  and    $0xfd,%esi
  je     L257
L148:
  cmp    $0x30,%al
  je     L237
L131:
  or     $0x20,%eax
  mov    %rdi,%rdx
  cmp    $0x78,%al
  jne    L71
L170:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
L32:
  cmp    $0x30,%al
  jne    L71
  xor    %eax,%eax
  jmp    L36
  nopl   (%rax)
L5:
  cmp    $0x20,%eax
  je     L71
L36:
  add    $0x1,%rdx
  add    $0x1,%eax
  cmpb   $0x30,(%rdx)
  je     L5
L71:
  movabs $0xf000000000000000,%rdi
  xor    %eax,%eax
  jmp    L207
  nopw   0x0(%rax,%rax,1)
L108:
  shl    $0x4,%rax
  movsbq %sil,%rsi
  add    $0x1,%rdx
  or     %rsi,%rax
  test   %rdi,%rax
  jne    L66
L207:
  movzbl (%rdx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  jbe    L108
  or     $0x20,%ecx
  lea    -0x61(%rcx),%esi
  cmp    $0x5,%sil
  ja     L66
  sub    $0x57,%ecx
  shl    $0x4,%rax
  add    $0x1,%rdx
  movsbq %cl,%rcx
  or     %rcx,%rax
  test   %rdi,%rax
  je     L207
L66:
  mov    %rax,%rcx
  neg    %rcx
  test   %r8b,%r8b
  cmovne %rcx,%rax
  test   %r9,%r9
  je     L119
  mov    %rdx,(%r9)
  ret
  nopl   0x0(%rax)
L116:
  bt     %rax,%rcx
  jb     L78
  cmp    %rdx,%rdi
  jne    L163
L115:
  mov    %rdx,%rdi
  xor    %r8d,%r8d
  jmp    L131
  nopw   0x0(%rax,%rax,1)
L119:
  ret
  nopl   0x0(%rax)
L237:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  mov    %eax,%ecx
  or     $0x20,%ecx
  cmp    $0x78,%cl
  jne    L32
  mov    %rdx,%rdi
  jmp    L170
  cs nopw 0x0(%rax,%rax,1)
L78:
  mov    %rdi,%rdx
  jmp    L115
L112:
  xor    %r8d,%r8d
  jmp    L148
```

assistant: ```c
long long http1_atol16(const uint8_t *buf, const uint8_t **end) {
  register unsigned long long i = 0;
  uint8_t inv = 0;
  for (int limit_ = 0; (*buf == ' ' || *buf == '\t' || *buf == '\f') && limit_ < 32; ++limit_)
    ++buf;
  for (int limit_ = 0; (*buf == '-' || *buf == '+') && limit_ < 32; ++limit_)
    inv ^= (*(buf++) == '-');
  if (*buf == '0')
    ++buf;
  if ((*buf | 32) == 'x')
    ++buf;
  for (int limit_ = 0; (*buf == '0') && limit_ < 32; ++limit_)
    ++buf;
  while (!(i & (~((~(0ULL)) >> 4)))) {
    if (*buf >= '0' && *buf <= '9') {
      i <<= 4;
      i |= *buf - '0';
    } else if ((*buf | 32) >= 'a' && (*buf | 32) <= 'f') {
      i <<= 4;
      i |= (*buf | 32) - ('a' - 10);
    } else
      break;
    ++buf;
  }
  if (inv)
    i = 0ULL - i;
  if (end)
    *end = buf;
  return i;
}
```