ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mmult>:
  endbr64
  push   %r15
  mov    %edx,%r11d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%edx
  mov    0x40(%rsp),%r15
  mov    %r8,-0x10(%rsp)
  movzwl 0x48(%rsp),%r8d
  mov    %si,-0x12(%rsp)
  test   %si,%si
  je     L44
  test   %r9w,%r9w
  je     L44
  movzwl %r8w,%eax
  mov    %rdi,%rbx
  movzwl %dx,%edx
  mov    %r9d,%ebp
  mov    %eax,-0x8(%rsp)
  movzwl %cx,%eax
  lea    -0x1(%r11),%r13d
  xor    %r12d,%r12d
  mov    %eax,-0x4(%rsp)
  pxor   %xmm2,%xmm2
  lea    0x4(%rbx),%r14
  movzwl %r13w,%r13d
  lea    0x0(,%rdx,4),%rdi
L46:
  mov    -0x8(%rsp),%edx
  movzwl %r12w,%eax
  mov    -0x10(%rsp),%r9
  xor    %r8d,%r8d
  imul   %eax,%edx
  imul   -0x4(%rsp),%eax
  movslq %edx,%rdx
  cltq
  lea    (%r15,%rdx,4),%rcx
  lea    (%rbx,%rax,4),%r10
  add    %r13,%rax
  lea    (%r14,%rax,4),%rsi
  nopl   0x0(%rax)
L9:
  movl   $0x0,(%rcx)
  mov    %r9,%rdx
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  test   %r11w,%r11w
  je     L19
  nopl   (%rax)
L49:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rdi,%rdx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L49
L19:
  add    $0x1,%r8
  add    $0x4,%rcx
  add    $0x4,%r9
  cmp    %r8w,%bp
  ja     L9
  add    $0x1,%r12d
  cmp    %r12w,-0x12(%rsp)
  ja     L46
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmult(float *a, unsigned short ra, unsigned short ca, unsigned short dca, float *b, unsigned short cb, unsigned short dcb, float *c, unsigned short dcc) {
  unsigned short i, j, k;
  for (i = 0; i < ra; i++)
    for (j = 0; j < cb; j++) {
      c[i * dcc + j] = 0;
      for (k = 0; k < ca; k++)
        c[i * dcc + j] = c[i * dcc + j] + a[i * dca + k] * b[k * dcb + j];
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L74
L43:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L46
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L1
  mov    $0xffffffff,%eax
  jmp    L49
L46:
  cmpl   $0x0,-0xc(%rbp)
  je     L42
  mov    -0xc(%rbp),%eax
  cltq
  sub    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L74:
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  jmp    L60
L1:
  nop
  jmp    L60
L42:
  nop
L60:
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L49:
  leave
  ret
```

assistant: ```c
ssize_t readn(int fd, void *ptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (nleft == n)
        return -1;
      else
        break;
    } else if (nread == 0) {
      break;
    }
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L38
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L70:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L50
  je     L65
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L70
  jmp    L65
L50:
  cmp    %rbx,%r13
  je     L9
L65:
  mov    %r13d,%eax
  sub    %ebx,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %rdx,%rbx
  jmp    L65
L9:
  mov    $0xffffffff,%eax
  jmp    L31
```

assistant: ```c
ssize_t readn(int fd, void *ptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (nleft == n)
        return -1;
      else
        break;
    } else if (nread == 0) {
      break;
    }
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readn>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L63
  jmp    L12
  nopl   0x0(%rax)
L39:
  je     L73
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  je     L12
L63:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L39
  cmp    %rbx,%rbp
  je     L49
L73:
  mov    %ebp,%eax
  sub    %ebx,%eax
L79:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %ebx,%ebx
  jmp    L73
L49:
  mov    $0xffffffff,%eax
  jmp    L79
```

assistant: ```c
ssize_t readn(int fd, void *ptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (nleft == n)
        return -1;
      else
        break;
    } else if (nread == 0) {
      break;
    }
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readn>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L52
  jmp    L55
  nopl   0x0(%rax)
L45:
  je     L59
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  je     L55
L52:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jns    L45
  cmp    %rbx,%rbp
  je     L10
L59:
  mov    %ebp,%eax
  sub    %ebx,%eax
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %ebx,%ebx
  jmp    L59
L10:
  mov    $0xffffffff,%eax
  jmp    L35
```

assistant: ```c
ssize_t readn(int fd, void *ptr, size_t n) {
  size_t nleft;
  ssize_t nread;
  nleft = n;
  while (nleft > 0) {
    if ((nread = read(fd, ptr, nleft)) < 0) {
      if (nleft == n)
        return -1;
      else
        break;
    } else if (nread == 0) {
      break;
    }
    nleft -= nread;
    ptr += nread;
  }
  return n - nleft;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_table_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2:  <form method="get" action="">
  <table>
   <thead>
    <tr>
     <th>Purchase?</th>
     <th>Description</th>
     <th>Qty</th>
   </thead>
   <tbody>


assistant: ```c
void print_table_header(void) {
  printf(" <form method=\"get\" action=\"\">\n"
         "  <table>\n"
         "   <thead>\n"
         "    <tr>\n"
         "     <th>Purchase?</th>\n"
         "     <th>Description</th>\n"
         "     <th>Qty</th>\n"
         "   </thead>\n"
         "   <tbody>\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_table_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0:  <form method="get" action="">
  <table>
   <thead>
    <tr>
     <th>Purchase?</th>
     <th>Description</th>
     <th>Qty</th>
   </thead>
   <tbody>


assistant: ```c
void print_table_header(void) {
  printf(" <form method=\"get\" action=\"\">\n"
         "  <table>\n"
         "   <thead>\n"
         "    <tr>\n"
         "     <th>Purchase?</th>\n"
         "     <th>Description</th>\n"
         "     <th>Qty</th>\n"
         "   </thead>\n"
         "   <tbody>\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_table_header>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2:  <form method="get" action="">
  <table>
   <thead>
    <tr>
     <th>Purchase?</th>
     <th>Description</th>
     <th>Qty</th>
   </thead>
   <tbody>


assistant: ```c
void print_table_header(void) {
  printf(" <form method=\"get\" action=\"\">\n"
         "  <table>\n"
         "   <thead>\n"
         "    <tr>\n"
         "     <th>Purchase?</th>\n"
         "     <th>Description</th>\n"
         "     <th>Qty</th>\n"
         "   </thead>\n"
         "   <tbody>\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_table_header>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9:  <form method="get" action="">
  <table>
   <thead>
    <tr>
     <th>Purchase?</th>
     <th>Description</th>
     <th>Qty</th>
   </thead>
   <tbody>


assistant: ```c
void print_table_header(void) {
  printf(" <form method=\"get\" action=\"\">\n"
         "  <table>\n"
         "   <thead>\n"
         "    <tr>\n"
         "     <th>Purchase?</th>\n"
         "     <th>Description</th>\n"
         "     <th>Qty</th>\n"
         "   </thead>\n"
         "   <tbody>\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ptr_list_append_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L37:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L23
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L37
  jmp    L48
L23:
  nop
L48:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L19
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0xffffffff,%eax
  jmp    L6
L20:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L19:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int ptr_list_append_check(void ***list, int *count, void *new) {
  int i;
  void **reallocd_list;
  for (i = 0; i < *count; i++)
    if ((*list)[i] == NULL)
      break;
  if (i == *count) {
    if ((reallocd_list = xrealloc(*list, (1 + *count) * sizeof(void *))) == NULL)
      return -1;
    else {
      ++(*count);
      *list = reallocd_list;
    }
  }
  (*list)[i] = new;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ptr_list_append_check>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    (%rsi),%ebx
  test   %ebx,%ebx
  jle    L13
  mov    (%rdi),%rdx
  mov    $0x0,%eax
L18:
  cmpq   $0x0,(%rdx)
  je     L26
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %ebx,%eax
  jne    L18
L61:
  lea    0x8(,%rbx,8),%esi
  mov    0x0(%rbp),%rdi
  call   <xrealloc@plt>
  test   %rax,%rax
  je     L19
  addl   $0x1,(%r12)
  mov    %rax,0x0(%rbp)
  mov    %ebx,%eax
  jmp    L5
L13:
  mov    $0x0,%eax
L26:
  cmp    %eax,%ebx
  je     L58
L5:
  movslq %eax,%rdx
  mov    0x0(%rbp),%rcx
  mov    %r13,(%rcx,%rdx,8)
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    %eax,%ebx
  jmp    L61
L19:
  mov    $0xffffffff,%eax
  jmp    L23
```

assistant: ```c
int ptr_list_append_check(void ***list, int *count, void *new) {
  int i;
  void **reallocd_list;
  for (i = 0; i < *count; i++)
    if ((*list)[i] == NULL)
      break;
  if (i == *count) {
    if ((reallocd_list = xrealloc(*list, (1 + *count) * sizeof(void *))) == NULL)
      return -1;
    else {
      ++(*count);
      *list = reallocd_list;
    }
  }
  (*list)[i] = new;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ptr_list_append_check>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%ebx
  mov    (%rdi),%rdi
  test   %ebx,%ebx
  jle    L39
  mov    %rdi,%rax
  xor    %r8d,%r8d
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r8d
  add    $0x8,%rax
  cmp    %r8d,%ebx
  je     L32
L40:
  cmpq   $0x0,(%rax)
  mov    %rax,%rcx
  jne    L14
L1:
  mov    %r13,(%rcx)
L60:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  je     L32
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L1
  nopl   0x0(%rax)
L32:
  lea    0x8(,%rbx,8),%esi
  call   <xrealloc@plt>
  test   %rax,%rax
  je     L65
  movslq %ebx,%rcx
  addl   $0x1,0x0(%rbp)
  mov    %ebx,%r8d
  mov    %rax,(%r12)
  lea    (%rax,%rcx,8),%rcx
  jmp    L1
L65:
  or     $0xffffffff,%r8d
  jmp    L60
```

assistant: ```c
int ptr_list_append_check(void ***list, int *count, void *new) {
  int i;
  void **reallocd_list;
  for (i = 0; i < *count; i++)
    if ((*list)[i] == NULL)
      break;
  if (i == *count) {
    if ((reallocd_list = xrealloc(*list, (1 + *count) * sizeof(void *))) == NULL)
      return -1;
    else {
      ++(*count);
      *list = reallocd_list;
    }
  }
  (*list)[i] = new;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ptr_list_append_check>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%ebx
  mov    (%rdi),%rdi
  test   %ebx,%ebx
  jle    L37
  mov    %rdi,%rax
  xor    %r8d,%r8d
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x1,%r8d
  add    $0x8,%rax
  cmp    %r8d,%ebx
  je     L12
L31:
  cmpq   $0x0,(%rax)
  mov    %rax,%rcx
  jne    L59
L88:
  mov    %r13,(%rcx)
L29:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  je     L12
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L88
  nopl   0x0(%rax)
L12:
  lea    0x8(,%rbx,8),%esi
  call   <xrealloc@plt>
  test   %rax,%rax
  je     L35
  movslq %ebx,%rcx
  addl   $0x1,0x0(%rbp)
  mov    %ebx,%r8d
  mov    %rax,(%r12)
  lea    (%rax,%rcx,8),%rcx
  jmp    L88
L35:
  or     $0xffffffff,%r8d
  jmp    L29
```

assistant: ```c
int ptr_list_append_check(void ***list, int *count, void *new) {
  int i;
  void **reallocd_list;
  for (i = 0; i < *count; i++)
    if ((*list)[i] == NULL)
      break;
  if (i == *count) {
    if ((reallocd_list = xrealloc(*list, (1 + *count) * sizeof(void *))) == NULL)
      return -1;
    else {
      ++(*count);
      *list = reallocd_list;
    }
  }
  (*list)[i] = new;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x334(%rbp)
  jmp    L20
L14:
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x334(%rbp),%edx
  mov    %edx,-0x330(%rbp,%rax,4)
  mov    -0x334(%rbp),%eax
  cltq
  movl   $0x0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x334(%rbp)
L20:
  cmpl   $0x63,-0x334(%rbp)
  jle    L14
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    a[i] = i * 1;
    b[i] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  mov    $0x64,%eax
L7:
  sub    $0x1,%eax
  jne    L7
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    a[i] = i * 1;
    b[i] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    a[i] = i * 1;
    b[i] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100], b[100];
#pragma hlt distribute
  for (int i = 0; i < 100; i++) {
    a[i] = i * 1;
    b[i] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_cubic_splines>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %rcx,%rbp
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <calloc@plt>
  mov    %rax,%r8
  movq   $0x0,0x0(%rbp)
  movq   $0x0,(%rax)
  cmp    $0x2,%ebx
  jle    L28
  mov    %r13,%rax
  mov    %r12,%rcx
  lea    0x8(%r8),%rdx
  lea    -0x3(%rbx),%esi
  lea    0x10(%r8,%rsi,8),%rdi
  mov    %rbp,%rsi
  sub    %r8,%rsi
  movsd  D26(%rip),%xmm6
  movsd  D9(%rip),%xmm5
  movsd  D3(%rip),%xmm4
L24:
  movsd  (%rax),%xmm2
  movsd  0x8(%rax),%xmm1
  subsd  %xmm2,%xmm1
  movsd  0x10(%rax),%xmm0
  subsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm3
  mulsd  -0x8(%rsi,%rdx,1),%xmm3
  addsd  %xmm6,%xmm3
  movapd %xmm1,%xmm0
  subsd  %xmm5,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
  movsd  0x8(%rcx),%xmm2
  movsd  0x8(%rax),%xmm7
  movsd  0x10(%rcx),%xmm0
  subsd  %xmm2,%xmm0
  movsd  0x10(%rax),%xmm8
  subsd  %xmm7,%xmm8
  divsd  %xmm8,%xmm0
  subsd  (%rcx),%xmm2
  subsd  (%rax),%xmm7
  divsd  %xmm7,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx)
  mulsd  %xmm4,%xmm0
  movsd  0x10(%rax),%xmm2
  subsd  (%rax),%xmm2
  divsd  %xmm2,%xmm0
  mulsd  -0x8(%rdx),%xmm1
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    $0x8,%rcx
  add    $0x8,%rdx
  cmp    %rdi,%rdx
  jne    L24
L28:
  movslq %ebx,%rax
  movq   $0x0,-0x8(%rbp,%rax,8)
  mov    %ebx,%edx
  sub    $0x2,%edx
  js     L16
  movslq %edx,%rdx
  shl    $0x3,%rdx
  lea    0x0(%rbp,%rdx,1),%rax
  lea    -0x8(%rbp,%rdx,1),%rdx
  lea    -0x2(%rbx),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdx
  mov    %r8,%rcx
  sub    %rbp,%rcx
L35:
  movsd  (%rax),%xmm0
  mulsd  0x8(%rax),%xmm0
  addsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rax)
  sub    $0x8,%rax
  cmp    %rdx,%rax
  jne    L35
L16:
  mov    %r8,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
datatype: f64
name: extract_symbolic_data
arguments: data_label: D9
datatype: f64
name: extract_symbolic_data
arguments: data_label: D3
datatype: f64

tool: D26: 2

tool: D9: 1

tool: D3: 6

assistant: ```c
void get_cubic_splines(double *x, double *y, int N, double *y2) {
  int i;
  double *u, s, p;
  u = (double *)calloc(N, sizeof(double));
  y2[0] = 0.0;
  u[0] = 0.0;
  for (i = 1; i < N - 1; i++) {
    s = (x[i] - x[i - 1]) / (x[i + 1] - x[i - 1]);
    p = s * y2[i - 1] + 2.0;
    y2[i] = (s - 1.0) / p;
    u[i] = (y[i + 1] - y[i]) / (x[i + 1] - x[i]) - (y[i] - y[i - 1]) / (x[i] - x[i - 1]);
    u[i] = (6.0 * u[i] / (x[i + 1] - x[i - 1]) - s * u[i - 1]) / p;
  }
  y2[N - 1] = 0.0;
  for (i = N - 2; i >= 0; i--) {
    y2[i] = y2[i] * y2[i + 1] + u[i];
  }
  free(u);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_cubic_splines>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %edx,%edi
  push   %r12
  mov    %rsi,%r12
  mov    $0x8,%esi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  movq   $0x0,0x0(%rbp)
  mov    %rax,%r8
  movq   $0x0,(%rax)
  cmp    $0x2,%ebx
  jle    L9
  lea    -0x3(%rbx),%esi
  mov    %r13,%rax
  mov    %r12,%rcx
  movsd  D7(%rip),%xmm6
  lea    0x10(%r8,%rsi,8),%rdi
  movsd  D5(%rip),%xmm5
  mov    %rbp,%rsi
  lea    0x8(%r8),%rdx
  movsd  D0(%rip),%xmm4
  sub    %r8,%rsi
L16:
  movsd  (%rax),%xmm2
  movsd  0x8(%rax),%xmm1
  add    $0x8,%rcx
  add    $0x8,%rax
  movsd  0x8(%rax),%xmm0
  movsd  -0x8(%rsi,%rdx,1),%xmm3
  subsd  %xmm2,%xmm1
  subsd  %xmm2,%xmm0
  divsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm3
  movapd %xmm1,%xmm0
  subsd  %xmm5,%xmm0
  addsd  %xmm6,%xmm3
  divsd  %xmm3,%xmm0
  movsd  %xmm0,(%rsi,%rdx,1)
  movsd  (%rcx),%xmm2
  movsd  (%rax),%xmm7
  add    $0x8,%rdx
  movsd  0x8(%rcx),%xmm0
  movsd  0x8(%rax),%xmm8
  mulsd  -0x10(%rdx),%xmm1
  subsd  %xmm2,%xmm0
  subsd  %xmm7,%xmm8
  subsd  -0x8(%rcx),%xmm2
  subsd  -0x8(%rax),%xmm7
  divsd  %xmm8,%xmm0
  divsd  %xmm7,%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%rdx)
  mulsd  %xmm4,%xmm0
  movsd  0x8(%rax),%xmm2
  subsd  -0x8(%rax),%xmm2
  divsd  %xmm2,%xmm0
  subsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rdi,%rdx
  jne    L16
L9:
  movslq %ebx,%rax
  movq   $0x0,-0x8(%rbp,%rax,8)
  sub    $0x2,%ebx
  js     L20
  movslq %ebx,%rdx
  mov    %ebx,%ebx
  mov    %r8,%rcx
  shl    $0x3,%rdx
  shl    $0x3,%rbx
  sub    %rbp,%rcx
  lea    0x0(%rbp,%rdx,1),%rax
  lea    -0x8(%rbp,%rdx,1),%rdx
  sub    %rbx,%rdx
  nopl   0x0(%rax,%rax,1)
L24:
  movsd  (%rax),%xmm0
  mulsd  0x8(%rax),%xmm0
  addsd  (%rcx,%rax,1),%xmm0
  sub    $0x8,%rax
  movsd  %xmm0,0x8(%rax)
  cmp    %rdx,%rax
  jne    L24
L20:
  add    $0x8,%rsp
  mov    %r8,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <free@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: f64
name: read_data
arguments: tag: D5
datatype: f64
name: read_data
arguments: tag: D0
datatype: f64

tool: D7: 2

tool: D5: 1

tool: D0: 6

assistant: ```c
void get_cubic_splines(double *x, double *y, int N, double *y2) {
  int i;
  double *u, s, p;
  u = (double *)calloc(N, sizeof(double));
  y2[0] = 0.0;
  u[0] = 0.0;
  for (i = 1; i < N - 1; i++) {
    s = (x[i] - x[i - 1]) / (x[i + 1] - x[i - 1]);
    p = s * y2[i - 1] + 2.0;
    y2[i] = (s - 1.0) / p;
    u[i] = (y[i + 1] - y[i]) / (x[i + 1] - x[i]) - (y[i] - y[i - 1]) / (x[i] - x[i - 1]);
    u[i] = (6.0 * u[i] / (x[i + 1] - x[i - 1]) - s * u[i - 1]) / p;
  }
  y2[N - 1] = 0.0;
  for (i = N - 2; i >= 0; i--) {
    y2[i] = y2[i] * y2[i + 1] + u[i];
  }
  free(u);
}
```