ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wait_kbc_sendready>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x64,%edi
  call   <io_in8@plt>
  test   $0x2,%al
  jne    L8
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_kbc_sendready(void) {
  for (;;) {
    if (0 == (io_in8((0x0064)) & (0x02)))
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wl_untar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x12e,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <makesubtree@plt>
  nop
  leave
  ret
```

assistant: ```c
void wl_untar(void) {
  unsigned testcode = 302;
  makesubtree(testcode, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wl_untar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x12e,%edi
  call   <makesubtree@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wl_untar(void) {
  unsigned testcode = 302;
  makesubtree(testcode, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wl_untar>:
  endbr64
  xor    %esi,%esi
  mov    $0x12e,%edi
  jmp    1050 <makesubtree@plt>
```

assistant: ```c
void wl_untar(void) {
  unsigned testcode = 302;
  makesubtree(testcode, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wl_untar>:
  endbr64
  xor    %esi,%esi
  mov    $0x12e,%edi
  jmp    1050 <makesubtree@plt>
```

assistant: ```c
void wl_untar(void) {
  unsigned testcode = 302;
  makesubtree(testcode, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printTmpSample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: Hello tmp repo sample!!


assistant: ```c
void printTmpSample(void) {
  printf("Hello tmp repo sample!!\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printTmpSample>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string

tool: D3: Hello tmp repo sample!!


assistant: ```c
void printTmpSample(void) {
  printf("Hello tmp repo sample!!\n");
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<printTmpSample>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Hello tmp repo sample!!


assistant: ```c
void printTmpSample(void) {
  printf("Hello tmp repo sample!!\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printTmpSample>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D9: Hello tmp repo sample!!


assistant: ```c
void printTmpSample(void) {
  printf("Hello tmp repo sample!!\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L7
  cmpq   $0x0,-0x20(%rbp)
  jne    L5
L7:
  mov    $0x0,%eax
  jmp    L27
L5:
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L53
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L53:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L41
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
L41:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int my_strncpy(char *in, char *dest, int n) {
  int i;
  if (in == NULL || dest == NULL)
    return (0);
  i = -1;
  while (++i < n && in[i] != '\0')
    dest[i] = in[i];
  dest[i] = '\0';
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_strncpy>:
  endbr64
  test   %rdi,%rdi
  je     L49
  test   %rsi,%rsi
  je     L49
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L55:
  mov    %eax,%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L2
  mov    %cl,(%rsi,%rax,1)
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L55
L2:
  movslq %r8d,%r8
  movb   $0x0,(%rsi,%r8,1)
  mov    $0x1,%eax
  ret
L17:
  mov    $0x0,%r8d
  jmp    L2
L49:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int my_strncpy(char *in, char *dest, int n) {
  int i;
  if (in == NULL || dest == NULL)
    return (0);
  i = -1;
  while (++i < n && in[i] != '\0')
    dest[i] = in[i];
  dest[i] = '\0';
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strncpy>:
  endbr64
  test   %rdi,%rdi
  je     L51
  test   %rsi,%rsi
  je     L51
  mov    %rsi,%r8
  test   %edx,%edx
  jle    L26
  mov    %rsi,%rcx
  lea    0x1(%rdx),%r9d
  mov    $0x1,%eax
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %dl,(%rcx)
  movslq %eax,%rdx
  add    $0x1,%rax
  lea    0x1(%r8),%rcx
  cmp    %r9,%rax
  je     L1
L55:
  movzbl -0x1(%rdi,%rax,1),%edx
  mov    %rcx,%r8
  test   %dl,%dl
  jne    L41
L26:
  movb   $0x0,(%r8)
  mov    $0x1,%eax
  ret
L51:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    (%rsi,%rdx,1),%r8
  mov    $0x1,%eax
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
int my_strncpy(char *in, char *dest, int n) {
  int i;
  if (in == NULL || dest == NULL)
    return (0);
  i = -1;
  while (++i < n && in[i] != '\0')
    dest[i] = in[i];
  dest[i] = '\0';
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_strncpy>:
  endbr64
  test   %rdi,%rdi
  je     L56
  test   %rsi,%rsi
  je     L56
  mov    %rsi,%r8
  test   %edx,%edx
  jle    L3
  mov    %rsi,%rcx
  lea    0x1(%rdx),%r9d
  mov    $0x1,%eax
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %dl,(%rcx)
  movslq %eax,%rdx
  add    $0x1,%rax
  lea    0x1(%r8),%rcx
  cmp    %r9,%rax
  je     L57
L55:
  movzbl -0x1(%rdi,%rax,1),%edx
  mov    %rcx,%r8
  test   %dl,%dl
  jne    L10
L3:
  movb   $0x0,(%r8)
  mov    $0x1,%eax
  ret
L56:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  lea    (%rsi,%rdx,1),%r8
  mov    $0x1,%eax
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
int my_strncpy(char *in, char *dest, int n) {
  int i;
  if (in == NULL || dest == NULL)
    return (0);
  i = -1;
  while (++i < n && in[i] != '\0')
    dest[i] = in[i];
  dest[i] = '\0';
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0xfe,%eax
  sub    -0x24(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movzbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x4,-0x24(%rbp)
  jne    L0
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  sub    %eax,-0x10(%rbp)
L0:
  cmpl   $0x2,-0x24(%rbp)
  jle    L23
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  sub    %eax,-0x10(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  sub    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  sub    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L33:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  sub    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L33
  mov    -0x10(%rbp),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int checksum(addr, buf, len, size)
int addr;
char buf[];
int len;
int size;
{
  char *cp = buf;
  int sum = 0xff - 1 - size - (len & 0xff);
  int i;
  if (size == 4)
    sum -= (addr >> 24) & 0xff;
  if (size >= 3)
    sum -= (addr >> 16) & 0xff;
  sum -= (addr >> 8) & 0xff;
  sum -= addr & 0xff;
  for (i = 0; i < len; ++i) {
    sum -= *cp++ & 0xff;
  }
  return sum & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checksum>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xfe,%eax
  sub    %ecx,%eax
  movzbl %dl,%edi
  sub    %edi,%eax
  cmp    $0x4,%ecx
  je     L15
  cmp    $0x2,%ecx
  jg     L0
L46:
  movzbl %bh,%ecx
  sub    %ecx,%eax
  movzbl %bl,%ebx
  sub    %ebx,%eax
  test   %edx,%edx
  jle    L10
  mov    %edx,%ecx
  add    %rsi,%rcx
L3:
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  sub    %edx,%eax
  cmp    %rcx,%rsi
  jne    L3
L10:
  movzbl %al,%eax
  pop    %rbx
  ret
L15:
  mov    %ebx,%ecx
  shr    $0x18,%ecx
  sub    %ecx,%eax
L0:
  mov    %ebx,%ecx
  sar    $0x10,%ecx
  movzbl %cl,%ecx
  sub    %ecx,%eax
  jmp    L46
```

assistant: ```c
int checksum(addr, buf, len, size)
int addr;
char buf[];
int len;
int size;
{
  char *cp = buf;
  int sum = 0xff - 1 - size - (len & 0xff);
  int i;
  if (size == 4)
    sum -= (addr >> 24) & 0xff;
  if (size >= 3)
    sum -= (addr >> 16) & 0xff;
  sum -= (addr >> 8) & 0xff;
  sum -= addr & 0xff;
  for (i = 0; i < len; ++i) {
    sum -= *cp++ & 0xff;
  }
  return sum & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  mov    $0xfe,%eax
  push   %rbx
  mov    %edi,%ebx
  movzbl %dl,%edi
  sub    %ecx,%eax
  sub    %edi,%eax
  cmp    $0x4,%ecx
  je     L40
  cmp    $0x2,%ecx
  jg     L42
L38:
  movzbl %bh,%ecx
  movzbl %bl,%ebx
  sub    %ecx,%eax
  sub    %ebx,%eax
  test   %edx,%edx
  jle    L20
  movslq %edx,%rcx
  add    %rsi,%rcx
  nopl   0x0(%rax)
L2:
  movzbl (%rsi),%edx
  add    $0x1,%rsi
  sub    %edx,%eax
  cmp    %rcx,%rsi
  jne    L2
L20:
  movzbl %al,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %ebx,%ecx
  shr    $0x18,%ecx
  sub    %ecx,%eax
L42:
  mov    %ebx,%ecx
  sar    $0x10,%ecx
  movzbl %cl,%ecx
  sub    %ecx,%eax
  jmp    L38
```

assistant: ```c
int checksum(addr, buf, len, size)
int addr;
char buf[];
int len;
int size;
{
  char *cp = buf;
  int sum = 0xff - 1 - size - (len & 0xff);
  int i;
  if (size == 4)
    sum -= (addr >> 24) & 0xff;
  if (size >= 3)
    sum -= (addr >> 16) & 0xff;
  sum -= (addr >> 8) & 0xff;
  sum -= addr & 0xff;
  for (i = 0; i < len; ++i) {
    sum -= *cp++ & 0xff;
  }
  return sum & 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_au_snd_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L35
L21:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <does_extension_match@plt>
  test   %rax,%rax
  je     L32
  mov    $0x1,%eax
  jmp    L35
L32:
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <does_extension_match@plt>
  test   %rax,%rax
  je     L42
  mov    $0x1,%eax
  jmp    L35
L42:
  mov    $0x0,%eax
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D19
data_type: string

tool: D17: au

tool: D19: snd

assistant: ```c
int is_au_snd_file(const char *filename) {
  const char *cptr;
  if (!(cptr = strrchr(filename, '.')))
    return 0;
  cptr++;
  if (does_extension_match(cptr, "au"))
    return 1;
  if (does_extension_match(cptr, "snd"))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_au_snd_file>:
  endbr64
  push   %rbx
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L12
  lea    0x1(%rax),%rbx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <does_extension_match@plt>
  mov    $0x1,%edx
  test   %rax,%rax
  je     L1
L12:
  mov    %edx,%eax
  pop    %rbx
  ret
L1:
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <does_extension_match@plt>
  test   %rax,%rax
  setne  %dl
  movzbl %dl,%edx
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D2: au

tool: D17: snd

assistant: ```c
int is_au_snd_file(const char *filename) {
  const char *cptr;
  if (!(cptr = strrchr(filename, '.')))
    return 0;
  cptr++;
  if (does_extension_match(cptr, "au"))
    return 1;
  if (does_extension_match(cptr, "snd"))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_au_snd_file>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rbp
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <does_extension_match@plt>
  mov    $0x1,%r8d
  test   %rax,%rax
  je     L10
L2:
  mov    %r8d,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <does_extension_match@plt>
  xor    %r8d,%r8d
  pop    %rbp
  test   %rax,%rax
  setne  %r8b
  mov    %r8d,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D10: au

tool: D2: snd

assistant: ```c
int is_au_snd_file(const char *filename) {
  const char *cptr;
  if (!(cptr = strrchr(filename, '.')))
    return 0;
  cptr++;
  if (does_extension_match(cptr, "au"))
    return 1;
  if (does_extension_match(cptr, "snd"))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_au_snd_file>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L16
  lea    0x1(%rax),%rbp
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <does_extension_match@plt>
  mov    $0x1,%r8d
  test   %rax,%rax
  je     L0
L16:
  mov    %r8d,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <does_extension_match@plt>
  xor    %r8d,%r8d
  pop    %rbp
  test   %rax,%rax
  setne  %r8b
  mov    %r8d,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D0: au

tool: D2: snd

assistant: ```c
int is_au_snd_file(const char *filename) {
  const char *cptr;
  if (!(cptr = strrchr(filename, '.')))
    return 0;
  cptr++;
  if (does_extension_match(cptr, "au"))
    return 1;
  if (does_extension_match(cptr, "snd"))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mul_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <set_rounding@plt>
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void mul_d(const uint32_t *fcr31, const double *source1, const double *source2, double *target) {
  set_rounding(fcr31);
  *target = *source1 * *source2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mul_d>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  call   <set_rounding@plt>
  movsd  (%r12),%xmm0
  mulsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mul_d(const uint32_t *fcr31, const double *source1, const double *source2, double *target) {
  set_rounding(fcr31);
  *target = *source1 * *source2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mul_d>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <set_rounding@plt>
  movsd  (%r12),%xmm0
  mulsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mul_d(const uint32_t *fcr31, const double *source1, const double *source2, double *target) {
  set_rounding(fcr31);
  *target = *source1 * *source2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mul_d>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <set_rounding@plt>
  movsd  (%r12),%xmm0
  mulsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void mul_d(const uint32_t *fcr31, const double *source1, const double *source2, double *target) {
  set_rounding(fcr31);
  *target = *source1 * *source2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FourByteSwap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,%edx
  jmp    L9
L12:
  movzbl (%rax),%ebx
  movzbl 0x3(%rax),%ecx
  mov    %cl,(%rax)
  lea    0x3(%rax),%rcx
  mov    %bl,(%rcx)
  movzbl 0x1(%rax),%ebx
  lea    0x1(%rax),%rcx
  movzbl 0x2(%rax),%esi
  mov    %sil,(%rcx)
  lea    0x2(%rax),%rcx
  mov    %bl,(%rcx)
  sub    $0x4,%edx
  add    $0x4,%rax
L9:
  test   %edx,%edx
  jg     L12
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void FourByteSwap(buf, nbytes) register unsigned char *buf;
register int nbytes;
{
  register unsigned char c;
  for (; nbytes > 0; nbytes -= 4, buf += 4) {
    c = buf[0];
    buf[0] = buf[3];
    buf[3] = c;
    c = buf[1];
    buf[1] = buf[2];
    buf[2] = c;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FourByteSwap>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  shr    $0x2,%eax
  lea    0x1(%rax),%eax
  mov    %eax,%eax
  lea    (%rdi,%rax,4),%rcx
L4:
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x3(%rdi)
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x1(%rdi)
  mov    %al,0x2(%rdi)
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L4
L12:
  ret
```

assistant: ```c
void FourByteSwap(buf, nbytes) register unsigned char *buf;
register int nbytes;
{
  register unsigned char c;
  for (; nbytes > 0; nbytes -= 4, buf += 4) {
    c = buf[0];
    buf[0] = buf[3];
    buf[3] = c;
    c = buf[1];
    buf[1] = buf[2];
    buf[2] = c;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<FourByteSwap>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  shr    $0x2,%eax
  lea    0x1(%rax),%eax
  lea    (%rdi,%rax,4),%rcx
  nopl   (%rax)
L4:
  movzbl (%rdi),%eax
  movzbl 0x3(%rdi),%edx
  add    $0x4,%rdi
  mov    %dl,-0x4(%rdi)
  movzbl -0x2(%rdi),%edx
  mov    %al,-0x1(%rdi)
  movzbl -0x3(%rdi),%eax
  mov    %dl,-0x3(%rdi)
  mov    %al,-0x2(%rdi)
  cmp    %rcx,%rdi
  jne    L4
L3:
  ret
```

assistant: ```c
void FourByteSwap(buf, nbytes) register unsigned char *buf;
register int nbytes;
{
  register unsigned char c;
  for (; nbytes > 0; nbytes -= 4, buf += 4) {
    c = buf[0];
    buf[0] = buf[3];
    buf[3] = c;
    c = buf[1];
    buf[1] = buf[2];
    buf[2] = c;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L13
L11:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int read_file(char *fname, char *buf, int size) {
  int num, fp;
  fp = open(fname, O_RDONLY);
  if (!fp)
    return -1;
  num = read(fp, buf, size);
  if (num < 0) {
    close(fp);
    return -1;
  }
  buf[num] = '\0';
  close(fp);
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  je     L39
  mov    %eax,%ebx
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L29
  cltq
  movb   $0x0,(%r12,%rax,1)
  mov    %ebx,%edi
  call   <close@plt>
L20:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebp
  jmp    L20
L39:
  mov    $0xffffffff,%ebp
  jmp    L20
```

assistant: ```c
int read_file(char *fname, char *buf, int size) {
  int num, fp;
  fp = open(fname, O_RDONLY);
  if (!fp)
    return -1;
  num = read(fp, buf, size);
  if (num < 0) {
    close(fp);
    return -1;
  }
  buf[num] = '\0';
  close(fp);
  return num;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_file>:
  endbr64
  mov    D2(%rip),%rax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  je     L24
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L32
  cltq
  mov    %ebp,%edi
  movb   $0x0,(%rbx,%rax,1)
  call   <close@plt>
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0xffffffff,%r12d
  jmp    L26
L32:
  mov    %ebp,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L26
```

assistant: ```c
int read_file(char *fname, char *buf, int size) {
  int num, fp;
  fp = open(fname, O_RDONLY);
  if (!fp)
    return -1;
  num = read(fp, buf, size);
  if (num < 0) {
    close(fp);
    return -1;
  }
  buf[num] = '\0';
  close(fp);
  return num;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_file>:
  endbr64
  mov    D0(%rip),%rax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  je     L21
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L16
  cltq
  mov    %ebp,%edi
  movb   $0x0,(%rbx,%rax,1)
  call   <close@plt>
L19:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%r12d
  jmp    L19
L16:
  mov    %ebp,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L19
```

assistant: ```c
int read_file(char *fname, char *buf, int size) {
  int num, fp;
  fp = open(fname, O_RDONLY);
  if (!fp)
    return -1;
  num = read(fp, buf, size);
  if (num < 0) {
    close(fp);
    return -1;
  }
  buf[num] = '\0';
  close(fp);
  return num;
}
```