ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_check_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L8
  cmpl   $0x10000000,-0xc(%rbp)
  jbe    L18
L8:
  mov    $0x11b,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L18:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h", 283));
  return word_ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_check_times>:
  endbr64
  push   %rbx
  mov    %edi,%edi
  mov    %esi,%esi
  imul   %rsi,%rdi
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    %rax,%rdi
  ja     L9
  cmp    $0x10000000,%edi
  jbe    L7
L9:
  mov    $0x11b,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L7:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h", 283));
  return word_ans;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L11
  cmp    $0x10000000,%edi
  ja     L11
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x11b,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h", 283));
  return word_ans;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L9
  cmp    $0x10000000,%edi
  ja     L9
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    $0x11b,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/cyc_include.h", 283));
  return word_ans;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_palindromo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <num_inverso@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L17
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L17:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D8
datatype: string

tool: D5: 
El nombre introducido ES un palindromo

tool: D8: 
El nombre introducido NO es un palindromo

assistant: ```c
void num_palindromo(int p) {
  if (p == num_inverso(p)) {
    printf("\nEl nombre introducido ES un palindromo");
  } else {
    printf("\nEl nombre introducido NO es un palindromo");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<num_palindromo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L2
  lea    D8(%rip),%rdi
  call   <printf@plt>
L8:
  pop    %rbx
  ret
L2:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D8: 
El nombre introducido NO es un palindromo

tool: D7: 
El nombre introducido ES un palindromo

assistant: ```c
void num_palindromo(int p) {
  if (p == num_inverso(p)) {
    printf("\nEl nombre introducido ES un palindromo");
  } else {
    printf("\nEl nombre introducido NO es un palindromo");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<num_palindromo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L5
  lea    D11(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
  nopl   (%rax)
L5:
  lea    D10(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string

tool: D11: 
El nombre introducido NO es un palindromo

tool: D10: 
El nombre introducido ES un palindromo

assistant: ```c
void num_palindromo(int p) {
  if (p == num_inverso(p)) {
    printf("\nEl nombre introducido ES un palindromo");
  } else {
    printf("\nEl nombre introducido NO es un palindromo");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_palindromo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <num_inverso@plt>
  cmp    %ebx,%eax
  je     L2
  lea    D15(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
  nopl   (%rax)
L2:
  lea    D11(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string

tool: D15: 
El nombre introducido NO es un palindromo

tool: D11: 
El nombre introducido ES un palindromo

assistant: ```c
void num_palindromo(int p) {
  if (p == num_inverso(p)) {
    printf("\nEl nombre introducido ES un palindromo");
  } else {
    printf("\nEl nombre introducido NO es un palindromo");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insertion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L43
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L3:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L38
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L18
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion(int *l, int left, int right) {
  int i, p, tmp;
  for (p = left + 1; p <= right; p++) {
    tmp = l[p];
    for (i = p; i > left && tmp < l[i - 1]; i--)
      l[i] = l[i - 1];
    l[i] = tmp;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion>:
  endbr64
  mov    %rdi,%r11
  lea    0x1(%rsi),%r8d
  cmp    %edx,%r8d
  jg     L40
  movslq %r8d,%rax
  lea    (%rdi,%rax,4),%r9
  lea    0x1(%rdx),%r10d
  jmp    L42
L12:
  movslq %edx,%rdx
  mov    %edi,(%r11,%rdx,4)
  add    $0x1,%r8d
  add    $0x4,%r9
  cmp    %r10d,%r8d
  je     L40
L42:
  mov    (%r9),%edi
  mov    %r9,%rax
  mov    %r8d,%edx
  cmp    %r8d,%esi
  jge    L12
L13:
  mov    -0x4(%rax),%ecx
  cmp    %edi,%ecx
  jle    L12
  mov    %ecx,(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    %edx,%esi
  jne    L13
  mov    %esi,%edx
  jmp    L12
L40:
  ret
```

assistant: ```c
void insertion(int *l, int left, int right) {
  int i, p, tmp;
  for (p = left + 1; p <= right; p++) {
    tmp = l[p];
    for (i = p; i > left && tmp < l[i - 1]; i--)
      l[i] = l[i - 1];
    l[i] = tmp;
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<insertion>:
  endbr64
  lea    0x1(%rsi),%r9d
  cmp    %edx,%r9d
  jg     L66
  movslq %r9d,%rax
  push   %rbx
  mov    %esi,%r8d
  lea    0x1(%rdx),%r11d
  lea    (%rdi,%rax,4),%r10
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbx
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%r10),%edi
  mov    %r10,%rsi
  mov    %r10,%rax
  mov    %r9d,%edx
  cmp    %r9d,%r8d
  jl     L35
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L72:
  sub    $0x1,%edx
  mov    %ecx,(%rax)
  lea    -0x4(%rsi),%rax
  cmp    %edx,%r8d
  je     L49
L35:
  mov    -0x4(%rax),%ecx
  mov    %rax,%rsi
  cmp    %edi,%ecx
  jg     L72
L64:
  add    $0x1,%r9d
  mov    %edi,(%rsi)
  add    $0x4,%r10
  cmp    %r9d,%r11d
  jne    L1
L26:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L49:
  mov    %rbx,%rsi
  add    $0x1,%r9d
  add    $0x4,%r10
  mov    %edi,(%rsi)
  cmp    %r9d,%r11d
  jne    L1
  jmp    L26
L66:
  ret
```

assistant: ```c
void insertion(int *l, int left, int right) {
  int i, p, tmp;
  for (p = left + 1; p <= right; p++) {
    tmp = l[p];
    for (i = p; i > left && tmp < l[i - 1]; i--)
      l[i] = l[i - 1];
    l[i] = tmp;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion>:
  endbr64
  lea    0x1(%rsi),%r10d
  movslq %r10d,%rax
  lea    (%rdi,%rax,4),%r11
  cmp    %edx,%r10d
  jg     L21
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L35:
  mov    (%r11),%r9d
  mov    %r11,%rax
  mov    %r10d,%ecx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L1:
  sub    $0x1,%ecx
  mov    %edi,(%rax)
  lea    -0x4(%rax),%rax
  cmp    %esi,%ecx
  jle    L11
L8:
  mov    -0x4(%rax),%edi
  mov    %rax,%r8
  cmp    %r9d,%edi
  jg     L1
  add    $0x1,%r10d
  mov    %r9d,(%r8)
  add    $0x4,%r11
  cmp    %edx,%r10d
  jle    L35
L64:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movslq %ecx,%rcx
  add    $0x1,%r10d
  add    $0x4,%r11
  lea    (%rbx,%rcx,4),%r8
  mov    %r9d,(%r8)
  cmp    %edx,%r10d
  jle    L35
  jmp    L64
L21:
  ret
```

assistant: ```c
void insertion(int *l, int left, int right) {
  int i, p, tmp;
  for (p = left + 1; p <= right; p++) {
    tmp = l[p];
    for (i = p; i > left && tmp < l[i - 1]; i--)
      l[i] = l[i - 1];
    l[i] = tmp;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L15:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L12
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L45
L12:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L45:
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D35
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D29
type_guessed: string

tool: D35: %d

tool: D25: ALICE


tool: D29: BOB


assistant: ```c
int main(int argc, char const *argv[]) {
  int iterations = 0;
  scanf("%d", &iterations);
  int input = 0;
  for (int i = 0; i < iterations; ++i) {
    scanf("%d", &input);
    if (input % 2 == 0) {
      printf("ALICE\n");
    } else {
      printf("BOB\n");
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movl   $0x0,0x4(%rsp)
  cmpl   $0x0,(%rsp)
  jle    L45
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
  lea    D13(%rip),%rbp
  lea    D18(%rip),%r14
  lea    D37(%rip),%r13
  jmp    L32
L24:
  mov    %r14,%rdi
  call   <printf@plt>
L31:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L45
L32:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L24
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L31
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string

tool: D13: %d

tool: D18: BOB


tool: D37: ALICE


assistant: ```c
int main(int argc, char const *argv[]) {
  int iterations = 0;
  scanf("%d", &iterations);
  int input = 0;
  for (int i = 0; i < iterations; ++i) {
    scanf("%d", &input);
    if (input % 2 == 0) {
      printf("ALICE\n");
    } else {
      printf("BOB\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  movl   $0x0,0x4(%rsp)
  test   %eax,%eax
  jle    L23
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  lea    D26(%rip),%r14
  lea    D7(%rip),%r13
  jmp    L24
  nop
L11:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jle    L23
L24:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  je     L11
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L24
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D2: %d

tool: D26: BOB


tool: D7: ALICE


assistant: ```c
int main(int argc, char const *argv[]) {
  int iterations = 0;
  scanf("%d", &iterations);
  int input = 0;
  for (int i = 0; i < iterations; ++i) {
    scanf("%d", &input);
    if (input % 2 == 0) {
      printf("ALICE\n");
    } else {
      printf("BOB\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  movl   $0x0,0x4(%rsp)
  test   %eax,%eax
  jle    L38
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  lea    D21(%rip),%r14
  lea    D12(%rip),%r13
  nopl   (%rax)
L52:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L8
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    (%rsp),%ebx
  jl     L52
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L52
  jmp    L38
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D21
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string

tool: D10: %d

tool: D21: BOB


tool: D12: ALICE


assistant: ```c
int main(int argc, char const *argv[]) {
  int iterations = 0;
  scanf("%d", &iterations);
  int input = 0;
  for (int i = 0; i < iterations; ++i) {
    scanf("%d", &input);
    if (input % 2 == 0) {
      printf("ALICE\n");
    } else {
      printf("BOB\n");
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nextGreatestLetter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6(%rbp)
  jmp    L25
L58:
  cmpb   $0x7a,-0x6(%rbp)
  jle    L13
  movzbl -0x6(%rbp),%eax
  sub    $0x1a,%eax
  jmp    L67
L13:
  movzbl -0x6(%rbp),%eax
L67:
  mov    %al,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L75
L52:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L17
  movzbl -0x5(%rbp),%eax
  jmp    L47
L17:
  addl   $0x1,-0x4(%rbp)
L75:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L52
  movzbl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6(%rbp)
L25:
  movsbl -0x20(%rbp),%eax
  lea    0x19(%rax),%edx
  movsbl -0x6(%rbp),%eax
  cmp    %eax,%edx
  jge    L58
  movzbl -0x20(%rbp),%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
char nextGreatestLetter(char *letters, int lettersSize, char target) {
  char c;
  for (char i = target + 1; i < target + 26; i++) {
    c = i > 'z' ? i - 26 : i;
    for (int j = 0; j < lettersSize; j++) {
      if (c == letters[j]) {
        return c;
      }
    }
  }
  return target;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nextGreatestLetter>:
  endbr64
  mov    %rdi,%r9
  lea    0x1(%rdx),%r8d
  movsbl %dl,%r10d
  add    $0x19,%r10d
  movsbl %r8b,%eax
  cmp    %eax,%r10d
  jl     L23
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rdi
L37:
  lea    -0x1a(%r8),%ecx
  cmp    $0x7a,%r8b
  cmovle %r8d,%ecx
  test   %esi,%esi
  jle    L27
  mov    %r9,%rax
L3:
  cmp    %cl,(%rax)
  je     L26
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L3
L27:
  add    $0x1,%r8d
  movsbl %r8b,%eax
  cmp    %r10d,%eax
  jle    L37
  mov    %edx,%ecx
  jmp    L26
L23:
  mov    %edx,%ecx
L26:
  mov    %ecx,%eax
  ret
```

assistant: ```c
char nextGreatestLetter(char *letters, int lettersSize, char target) {
  char c;
  for (char i = target + 1; i < target + 26; i++) {
    c = i > 'z' ? i - 26 : i;
    for (int j = 0; j < lettersSize; j++) {
      if (c == letters[j]) {
        return c;
      }
    }
  }
  return target;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nextGreatestLetter>:
  endbr64
  mov    %rdi,%r9
  movsbl %dl,%r10d
  lea    0x1(%rdx),%edi
  add    $0x19,%r10d
  movsbl %dil,%eax
  cmp    %eax,%r10d
  jl     L42
  lea    -0x1(%rsi),%eax
  lea    0x1(%r9,%rax,1),%rcx
L38:
  lea    -0x1a(%rdi),%r8d
  cmp    $0x7a,%dil
  cmovle %edi,%r8d
  test   %esi,%esi
  jle    L20
  mov    %r9,%rax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L20
L5:
  cmp    %r8b,(%rax)
  jne    L14
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%edi
  movsbl %dil,%eax
  cmp    %r10d,%eax
  jle    L38
L42:
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
char nextGreatestLetter(char *letters, int lettersSize, char target) {
  char c;
  for (char i = target + 1; i < target + 26; i++) {
    c = i > 'z' ? i - 26 : i;
    for (int j = 0; j < lettersSize; j++) {
      if (c == letters[j]) {
        return c;
      }
    }
  }
  return target;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nextGreatestLetter>:
  endbr64
  mov    %rdi,%r9
  movsbl %dl,%r10d
  lea    0x1(%rdx),%edi
  add    $0x19,%r10d
  movsbl %dil,%eax
  cmp    %eax,%r10d
  jl     L14
  lea    -0x1(%rsi),%eax
  lea    0x1(%r9,%rax,1),%rcx
L42:
  lea    -0x1a(%rdi),%r8d
  cmp    $0x7a,%dil
  cmovle %edi,%r8d
  test   %esi,%esi
  jle    L44
  mov    %r9,%rax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L51:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L44
L28:
  cmp    %r8b,(%rax)
  jne    L51
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%edi
  movsbl %dil,%eax
  cmp    %r10d,%eax
  jle    L42
L14:
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
char nextGreatestLetter(char *letters, int lettersSize, char target) {
  char c;
  for (char i = target + 1; i < target + 26; i++) {
    c = i > 'z' ? i - 26 : i;
    for (int j = 0; j < lettersSize; j++) {
      if (c == letters[j]) {
        return c;
      }
    }
  }
  return target;
}
```