ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<print_optionhelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    D56(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <puts@plt>
```

tool_calls: name: unpack_data
arguments: label: D42
type: string
name: unpack_data
arguments: label: D44
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D36
type: string
name: unpack_data
arguments: label: D51
type: string
name: unpack_data
arguments: label: D47
type: string
name: unpack_data
arguments: label: D41
type: string
name: unpack_data
arguments: label: D56
type: string

tool: D42: available options:

tool: D44:   -q                      (quiet)

tool: D34:   -b <batch_startfile>    (load startup file)

tool: D36:   -c <coff_loadfile>      (directly run COFF file)

tool: D51:   -t <tekhex_loadfile>    (directly run TEKHEX file)

tool: D47:   -l <tldldm_loadfile>    (directly run TLDLDM file)

tool: D41:   -x <xtcldm_loadfile>    (directly run XTCLDM file)

tool: D56:   -n                      (gain speed/disable backtracing)

assistant: ```c
void print_optionhelp() {
  puts("available options:");
  puts("  -q                      (quiet)");
  puts("  -b <batch_startfile>    (load startup file)");
  puts("  -c <coff_loadfile>      (directly run COFF file)");
  puts("  -t <tekhex_loadfile>    (directly run TEKHEX file)");
  puts("  -l <tldldm_loadfile>    (directly run TLDLDM file)");
  puts("  -x <xtcldm_loadfile>    (directly run XTCLDM file)");
  puts("  -n                      (gain speed/disable backtracing)");
}
```
user: Translate the below assembly code into C programming language:

```asm
<FanChannelDutySet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  add    $0x14,%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  and    $0x1ff0000,%eax
  mov    %rax,(%rcx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void FanChannelDutySet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDuty) {
  ;
  ;
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) = (ulDuty << 16) & 0x01FF0000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FanChannelDutySet>:
  endbr64
  shl    $0x4,%rsi
  lea    0x14(%rsi,%rdi,1),%rax
  shl    $0x10,%rdx
  and    $0x1ff0000,%edx
  mov    %rdx,(%rax)
  ret
```

assistant: ```c
void FanChannelDutySet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDuty) {
  ;
  ;
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) = (ulDuty << 16) & 0x01FF0000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<FanChannelDutySet>:
  endbr64
  shl    $0x4,%rsi
  shl    $0x10,%rdx
  lea    0x14(%rsi,%rdi,1),%rax
  and    $0x1ff0000,%edx
  mov    %rdx,(%rax)
  ret
```

assistant: ```c
void FanChannelDutySet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDuty) {
  ;
  ;
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) = (ulDuty << 16) & 0x01FF0000;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<FanChannelDutySet>:
  endbr64
  shl    $0x4,%rsi
  shl    $0x10,%rdx
  lea    0x14(%rsi,%rdi,1),%rax
  and    $0x1ff0000,%edx
  mov    %rdx,(%rax)
  ret
```

assistant: ```c
void FanChannelDutySet(unsigned long ulBase, unsigned long ulChannel, unsigned long ulDuty) {
  ;
  ;
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000014 + (ulChannel * 0x10)))) = (ulDuty << 16) & 0x01FF0000;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handle_pingreq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <send_acknowledge@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L16
L18:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy_packet@plt>
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int handle_pingreq(struct pico_mqtt *mqtt, struct pico_mqtt_packet *packet) {
  do {
  } while (0);
  do {
  } while (0);
  if (send_acknowledge(mqtt, packet, 0) == -1)
    return -1;
  destroy_packet(packet);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<handle_pingreq>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%edx
  call   <send_acknowledge@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    %rbx,%rdi
  call   <destroy_packet@plt>
  mov    $0x0,%eax
L7:
  pop    %rbx
  ret
```

assistant: ```c
int handle_pingreq(struct pico_mqtt *mqtt, struct pico_mqtt_packet *packet) {
  do {
  } while (0);
  do {
  } while (0);
  if (send_acknowledge(mqtt, packet, 0) == -1)
    return -1;
  destroy_packet(packet);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_pingreq>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rsi,%rbp
  call   <send_acknowledge@plt>
  cmp    $0xffffffff,%eax
  je     L6
  mov    %rbp,%rdi
  call   <destroy_packet@plt>
  xor    %eax,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int handle_pingreq(struct pico_mqtt *mqtt, struct pico_mqtt_packet *packet) {
  do {
  } while (0);
  do {
  } while (0);
  if (send_acknowledge(mqtt, packet, 0) == -1)
    return -1;
  destroy_packet(packet);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<handle_pingreq>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rsi,%rbp
  call   <send_acknowledge@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    %rbp,%rdi
  call   <destroy_packet@plt>
  xor    %eax,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int handle_pingreq(struct pico_mqtt *mqtt, struct pico_mqtt_packet *packet) {
  do {
  } while (0);
  do {
  } while (0);
  if (send_acknowledge(mqtt, packet, 0) == -1)
    return -1;
  destroy_packet(packet);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L2
  cmpl   $0x2,-0x4(%rbp)
  je     L9
  jmp    L41
L2:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L44
L9:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L46
L41:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L46:
  mov    $0x0,%eax
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D3: No arguments

tool: D13: arg = %s


tool: D19: More than 1 argument

assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    printf("No arguments\n");
    return 0;
  case 2:
    printf("arg = %s\n", argv[1]);
    break;
  default:
    printf("More than 1 argument\n");
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L2
  cmp    $0x2,%edi
  je     L7
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L2:
  lea    D18(%rip),%rdi
  call   <puts@plt>
L5:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    0x8(%rsi),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string

tool: D24: More than 1 argument

tool: D18: No arguments

tool: D6: arg = %s


assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    printf("No arguments\n");
    return 0;
  case 2:
    printf("arg = %s\n", argv[1]);
    break;
  default:
    printf("More than 1 argument\n");
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L29
  cmp    $0x2,%edi
  je     L19
  lea    D28(%rip),%rdi
  call   <puts@plt>
L25:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L29:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L19:
  mov    0x8(%rsi),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string

tool: D28: More than 1 argument

tool: D1: No arguments

tool: D17: arg = %s


assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    printf("No arguments\n");
    return 0;
  case 2:
    printf("arg = %s\n", argv[1]);
    break;
  default:
    printf("More than 1 argument\n");
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L30
  cmp    $0x2,%edi
  je     L29
  lea    D11(%rip),%rdi
  call   <puts@plt>
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L30:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L29:
  mov    0x8(%rsi),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D17
type: string
name: read_data
arguments: data_label: D1
type: string

tool: D11: More than 1 argument

tool: D17: No arguments

tool: D1: arg = %s


assistant: ```c
int main(int argc, char **argv) {
  switch (argc) {
  case 1:
    printf("No arguments\n");
    return 0;
  case 2:
    printf("arg = %s\n", argv[1]);
    break;
  default:
    printf("More than 1 argument\n");
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fFunction>:
  endbr64
  push   %rbx
  sub    $0xc0,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  movl   $0x3,0x38(%rsp)
  movl   $0x2,0x3c(%rsp)
  movl   $0x3,0x40(%rsp)
  movl   $0x2,0x44(%rsp)
  movl   $0x1,0x48(%rsp)
  movl   $0x0,0x4c(%rsp)
  movl   $0x0,0x50(%rsp)
  movl   $0x2,0x54(%rsp)
  movl   $0x1,0x58(%rsp)
  movl   $0x3,0x5c(%rsp)
  movl   $0x3,0x60(%rsp)
  movl   $0x1,0x64(%rsp)
  movl   $0x3,0x68(%rsp)
  movl   $0x2,0x6c(%rsp)
  movl   $0x0,0x70(%rsp)
  movl   $0x1,0x74(%rsp)
  movl   $0x2,0x78(%rsp)
  movl   $0x3,0x7c(%rsp)
  movl   $0x2,0x80(%rsp)
  movl   $0x0,0x84(%rsp)
  movl   $0x1,0x88(%rsp)
  movl   $0x3,0x8c(%rsp)
  movl   $0x3,0x90(%rsp)
  movl   $0x0,0x94(%rsp)
  movl   $0x1,0x98(%rsp)
  movl   $0x0,0x9c(%rsp)
  movl   $0x2,0xa0(%rsp)
  movl   $0x1,0xa4(%rsp)
  movl   $0x0,0xa8(%rsp)
  movl   $0x3,0xac(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0x4,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  movzwl %di,%edi
  mov    $0x8,%ecx
  mov    $0x4,%edx
  call   <permute@plt>
  xor    %ebx,%eax
  mov    %eax,%esi
  movzwl %ax,%edx
  mov    %edx,%ecx
  sar    %ecx
  and    $0x3,%ecx
  mov    %edx,%eax
  sar    $0x2,%eax
  and    $0x2,%eax
  and    $0x1,%esi
  or     %esi,%eax
  cltq
  lea    (%rcx,%rax,4),%rsi
  mov    %edx,%ecx
  sar    $0x5,%ecx
  and    $0x3,%ecx
  mov    %edx,%eax
  sar    $0x6,%eax
  and    $0x2,%eax
  sar    $0x4,%edx
  and    $0x1,%edx
  or     %edx,%eax
  cltq
  lea    (%rcx,%rax,4),%rax
  mov    0x30(%rsp,%rax,4),%edi
  shl    $0x2,%edi
  add    0x70(%rsp,%rsi,4),%di
  movzwl %di,%edi
  mov    %rsp,%rsi
  mov    $0x4,%ecx
  mov    $0x4,%edx
  call   <permute@plt>
  mov    0xb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0xc0,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short fFunction(unsigned short r, unsigned short key) {
  int sZero[4][4] = {{1, 0, 3, 2}, {3, 2, 1, 0}, {0, 2, 1, 3}, {3, 1, 3, 2}};
  int sOne[4][4] = {{0, 1, 2, 3}, {2, 0, 1, 3}, {3, 0, 1, 0}, {2, 1, 0, 3}};
  int eP[8] = {4, 1, 2, 3, 2, 3, 4, 1};
  int pFour[4] = {2, 4, 3, 1};
  unsigned short expR;
  expR = permute(r, eP, 4, 8);
  expR = expR ^ key;
  expR = (sZero[((expR & 128) >> 6) + ((expR & 16) >> 4)][((expR & 64) >> 5) + ((expR & 32) >> 5)] << 2) + sOne[((expR & 8) >> 2) + (expR & 1)][((expR & 4) >> 1) + ((expR & 2) >> 1)];
  expR = permute(expR, pFour, 4, 4);
  return expR;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fFunction>:
  endbr64
  movabs $0x300000001,%rcx
  push   %rbx
  mov    %esi,%ebx
  movzwl %di,%edi
  movabs $0x200000000,%rdx
  movabs $0x100000002,%rsi
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  mov    %rcx,0x58(%rsp)
  movabs $0x200000003,%rax
  mov    %rax,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  mov    %rax,0x68(%rsp)
  movabs $0x100000000,%rax
  mov    %rcx,0x88(%rsp)
  sub    $0x1,%rcx
  mov    %rdx,0x50(%rsp)
  movabs $0x100000003,%rdx
  mov    %rax,0x70(%rsp)
  movabs $0x300000002,%rax
  mov    %rcx,0xa8(%rsp)
  movabs $0x100000004,%rcx
  mov    %rdx,0x60(%rsp)
  mov    %rax,0x78(%rsp)
  mov    %rsi,0xa0(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x20(%rsp)
  movabs $0x400000002,%rax
  mov    %rcx,0x28(%rsp)
  mov    $0x8,%ecx
  mov    %rdx,0x8(%rsp)
  mov    $0x4,%edx
  movq   $0x1,0x30(%rsp)
  movq   $0x1,0x48(%rsp)
  movq   $0x2,0x80(%rsp)
  movq   $0x3,0x90(%rsp)
  movq   $0x1,0x98(%rsp)
  mov    %rax,(%rsp)
  call   <permute@plt>
  xor    %ebx,%eax
  movzwl %ax,%edx
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %edx,%esi
  sar    $0x2,%eax
  and    $0x1,%ecx
  sar    %esi
  and    $0x2,%eax
  and    $0x3,%esi
  or     %ecx,%eax
  mov    %edx,%ecx
  cltq
  sar    $0x5,%ecx
  lea    (%rsi,%rax,4),%rsi
  mov    %edx,%eax
  sar    $0x4,%edx
  and    $0x3,%ecx
  sar    $0x6,%eax
  and    $0x1,%edx
  and    $0x2,%eax
  or     %edx,%eax
  mov    $0x4,%edx
  cltq
  lea    (%rcx,%rax,4),%rax
  mov    $0x4,%ecx
  mov    0x30(%rsp,%rax,4),%edi
  shl    $0x2,%edi
  add    0x70(%rsp,%rsi,4),%di
  mov    %rsp,%rsi
  movzwl %di,%edi
  call   <permute@plt>
  mov    0xb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0xc0,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned short fFunction(unsigned short r, unsigned short key) {
  int sZero[4][4] = {{1, 0, 3, 2}, {3, 2, 1, 0}, {0, 2, 1, 3}, {3, 1, 3, 2}};
  int sOne[4][4] = {{0, 1, 2, 3}, {2, 0, 1, 3}, {3, 0, 1, 0}, {2, 1, 0, 3}};
  int eP[8] = {4, 1, 2, 3, 2, 3, 4, 1};
  int pFour[4] = {2, 4, 3, 1};
  unsigned short expR;
  expR = permute(r, eP, 4, 8);
  expR = expR ^ key;
  expR = (sZero[((expR & 128) >> 6) + ((expR & 16) >> 4)][((expR & 64) >> 5) + ((expR & 32) >> 5)] << 2) + sOne[((expR & 8) >> 2) + (expR & 1)][((expR & 4) >> 1) + ((expR & 2) >> 1)];
  expR = permute(expR, pFour, 4, 4);
  return expR;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decimalToHexadecimal>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x3938,0x16(%rsp)
  test   %rdi,%rdi
  jle    L38
  mov    %rdi,%rdx
  add    $0x13,%rsi
  mov    %rsi,%rdi
  lea    D5(%rip),%r8
  mov    $0x12,%r9d
  sub    %esi,%r9d
  jmp    L65
  movb   $0x41,(%rdi)
L7:
  lea    0xf(%rdx),%rax
  test   %rdx,%rdx
  cmovns %rdx,%rax
  sar    $0x4,%rax
  lea    (%r9,%rdi,1),%ecx
  sub    $0x1,%rdi
  cmp    $0xf,%rdx
  jle    L56
  mov    %rax,%rdx
L65:
  mov    %rdx,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rdx,%rcx,1),%rax
  and    $0xf,%eax
  sub    %rcx,%rax
  lea    -0xa(%rax),%rcx
  cmp    $0x5,%rcx
  ja     L44
  movslq (%r8,%rcx,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  movb   $0x42,(%rdi)
  jmp    L7
  movb   $0x43,(%rdi)
  jmp    L7
  movb   $0x44,(%rdi)
  jmp    L7
  movb   $0x45,(%rdi)
  jmp    L7
  movb   $0x46,(%rdi)
  jmp    L7
L44:
  movzbl 0xe(%rsp,%rax,1),%eax
  mov    %al,(%rdi)
  jmp    L7
L38:
  mov    $0x13,%ecx
L56:
  lea    0x1(%rcx),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x28,%rsp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decimalToHexadecimal(long long number, char *str) {
  int i = 20 - 1;
  char nums[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  long reminder;
  for (; number > 0; i--) {
    reminder = number % 16;
    switch (reminder) {
    case 10:
      str[i] = 'A';
      break;
    case 11:
      str[i] = 'B';
      break;
    case 12:
      str[i] = 'C';
      break;
    case 13:
      str[i] = 'D';
      break;
    case 14:
      str[i] = 'E';
      break;
    case 15:
      str[i] = 'F';
      break;
    default:
      str[i] = nums[reminder];
      break;
    }
    number /= 16;
  }
  return (i + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<decimalToHexadecimal>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3736353433323130,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x3938,%eax
  mov    %ax,0x16(%rsp)
  test   %rdi,%rdi
  jle    L91
  mov    $0x13,%eax
  lea    D1(%rip),%r8
  nopl   0x0(%rax)
L89:
  mov    %rdi,%rcx
  mov    %eax,%r9d
  and    $0xf,%ecx
  lea    -0xa(%rcx),%rdx
  cmp    $0x5,%rdx
  ja     L24
  movslq (%r8,%rdx,4),%rdx
  add    %r8,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  mov    $0x42,%edx
  nopl   (%rax)
L31:
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  sar    $0x4,%rdi
  jne    L89
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %r9d,%eax
  add    $0x28,%rsp
  ret
  nopl   (%rax)
  mov    $0x41,%edx
  jmp    L31
  nop
  mov    $0x46,%edx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
  mov    $0x45,%edx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
  mov    $0x44,%edx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
  mov    $0x43,%edx
  jmp    L31
L24:
  movzbl 0xe(%rsp,%rcx,1),%edx
  jmp    L31
  xchg   %ax,%ax
L91:
  mov    $0x14,%r9d
  jmp    L46
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decimalToHexadecimal(long long number, char *str) {
  int i = 20 - 1;
  char nums[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  long reminder;
  for (; number > 0; i--) {
    reminder = number % 16;
    switch (reminder) {
    case 10:
      str[i] = 'A';
      break;
    case 11:
      str[i] = 'B';
      break;
    case 12:
      str[i] = 'C';
      break;
    case 13:
      str[i] = 'D';
      break;
    case 14:
      str[i] = 'E';
      break;
    case 15:
      str[i] = 'F';
      break;
    default:
      str[i] = nums[reminder];
      break;
    }
    number /= 16;
  }
  return (i + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decimalToHexadecimal>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3736353433323130,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x3938,%eax
  mov    %ax,0x16(%rsp)
  test   %rdi,%rdi
  jle    L104
  mov    $0x13,%eax
  lea    D9(%rip),%r8
  nopl   0x0(%rax)
L12:
  mov    %rdi,%rcx
  mov    %eax,%r9d
  and    $0xf,%ecx
  lea    -0xa(%rcx),%rdx
  cmp    $0x5,%rdx
  ja     L80
  movslq (%r8,%rdx,4),%rdx
  add    %r8,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
  mov    $0x42,%edx
  nopl   (%rax)
L30:
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  sar    $0x4,%rdi
  jne    L12
L75:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L109
  mov    %r9d,%eax
  add    $0x28,%rsp
  ret
  nopl   (%rax)
  mov    $0x41,%edx
  jmp    L30
  nop
  mov    $0x46,%edx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
  mov    $0x45,%edx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
  mov    $0x44,%edx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
  mov    $0x43,%edx
  jmp    L30
L80:
  movzbl 0xe(%rsp,%rcx,1),%edx
  jmp    L30
  xchg   %ax,%ax
L104:
  mov    $0x14,%r9d
  jmp    L75
L109:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decimalToHexadecimal(long long number, char *str) {
  int i = 20 - 1;
  char nums[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  long reminder;
  for (; number > 0; i--) {
    reminder = number % 16;
    switch (reminder) {
    case 10:
      str[i] = 'A';
      break;
    case 11:
      str[i] = 'B';
      break;
    case 12:
      str[i] = 'C';
      break;
    case 13:
      str[i] = 'D';
      break;
    case 14:
      str[i] = 'E';
      break;
    case 15:
      str[i] = 'F';
      break;
    default:
      str[i] = nums[reminder];
      break;
    }
    number /= 16;
  }
  return (i + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timeval_millisecond_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <timeval_clear@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x6,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   $0x3e8,%eax,%eax
  sub    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   $0x3e8,%eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,0x4(%rax)
  nop
  leave
  ret
```

assistant: ```c
void timeval_millisecond_init(struct timeval *a, unsigned int ms) {
  assert(a);
  timeval_clear(a);
  a->tv_sec = ms / 1000;
  ms -= (a->tv_sec * 1000);
  a->tv_usec = ms * 1000;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timeval_millisecond_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <timeval_clear@plt>
  mov    %ebx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void timeval_millisecond_init(struct timeval *a, unsigned int ms) {
  assert(a);
  timeval_clear(a);
  a->tv_sec = ms / 1000;
  ms -= (a->tv_sec * 1000);
  a->tv_usec = ms * 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<timeval_millisecond_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <timeval_clear@plt>
  mov    %ebx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,0x0(%rbp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ebx
  imul   $0x3e8,%ebx,%ebx
  mov    %ebx,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void timeval_millisecond_init(struct timeval *a, unsigned int ms) {
  assert(a);
  timeval_clear(a);
  a->tv_sec = ms / 1000;
  ms -= (a->tv_sec * 1000);
  a->tv_usec = ms * 1000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timeval_millisecond_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <timeval_clear@plt>
  mov    %ebx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%ebx
  imul   $0x3e8,%ebx,%ebx
  movd   %ebx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void timeval_millisecond_init(struct timeval *a, unsigned int ms) {
  assert(a);
  timeval_clear(a);
  a->tv_sec = ms / 1000;
  ms -= (a->tv_sec * 1000);
  a->tv_usec = ms * 1000;
}
```