ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cCamCryptVG_ReorderAndEncrypt>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <cCamCryptVG_Reorder16A@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %r12,%rcx
  mov    $0x10,%edx
  call   <cAES_Encrypt@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <cCamCryptVG_Reorder16A@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cCamCryptVG_ReorderAndEncrypt(struct s_reader *reader, unsigned char *p) {
  unsigned char tmp[16];
  cCamCryptVG_Reorder16A(tmp, p);
  cAES_Encrypt(reader, tmp, 16, tmp);
  cCamCryptVG_Reorder16A(p, tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cCamCryptVG_ReorderAndEncrypt>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <cCamCryptVG_Reorder16A@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %r12,%rcx
  mov    $0x10,%edx
  call   <cAES_Encrypt@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <cCamCryptVG_Reorder16A@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cCamCryptVG_ReorderAndEncrypt(struct s_reader *reader, unsigned char *p) {
  unsigned char tmp[16];
  cCamCryptVG_Reorder16A(tmp, p);
  cAES_Encrypt(reader, tmp, 16, tmp);
  cCamCryptVG_Reorder16A(p, tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SinCos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void SinCos(float angle, float *sine, float *cosine) {
  *sine = (float)sin(angle);
  *cosine = (float)cos(angle);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SinCos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0xc(%rsp),%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SinCos(float angle, float *sine, float *cosine) {
  *sine = (float)sin(angle);
  *cosine = (float)cos(angle);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SinCos>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x0(%rbp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SinCos(float angle, float *sine, float *cosine) {
  *sine = (float)sin(angle);
  *cosine = (float)cos(angle);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SinCos>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x0(%rbp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void SinCos(float angle, float *sine, float *cosine) {
  *sine = (float)sin(angle);
  *cosine = (float)cos(angle);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<badfmt2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4d0,%rsp
  mov    %rdi,-0x4c8(%rbp)
  mov    %esi,-0x4cc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4cc(%rbp),%ecx
  mov    -0x4c8(%rbp),%rdx
  lea    -0x4c0(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x4c0(%rbp),%rax
  mov    %rax,%rdi
  call   <badfmt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: %s (column %d)

assistant: ```c
void badfmt2(const char *s, int col) {
  char temp[(120 * 10)];
  (void)sprintf(temp, "%s (column %d)", s, col);
  badfmt(temp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<badfmt2>:
  endbr64
  push   %rbx
  sub    $0x4c0,%rsp
  mov    %rdi,%rdx
  mov    %esi,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <badfmt@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x4c0,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: %s (column %d)

assistant: ```c
void badfmt2(const char *s, int col) {
  char temp[(120 * 10)];
  (void)sprintf(temp, "%s (column %d)", s, col);
  badfmt(temp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<badfmt2>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %esi,%ecx
  lea    D8(%rip),%rsi
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <badfmt@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x4c0,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: %s (column %d)

assistant: ```c
void badfmt2(const char *s, int col) {
  char temp[(120 * 10)];
  (void)sprintf(temp, "%s (column %d)", s, col);
  badfmt(temp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<badfmt2>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %esi,%ecx
  lea    D1(%rip),%rsi
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4b8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <badfmt@plt>
  mov    0x4b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x4c0,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D1: %s (column %d)

assistant: ```c
void badfmt2(const char *s, int col) {
  char temp[(120 * 10)];
  (void)sprintf(temp, "%s (column %d)", s, col);
  badfmt(temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<makePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,-0x418(%rbp)
  jmp    L62
L47:
  mov    -0x418(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L49
  mov    -0x418(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L49
  mov    -0x418(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x418(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L49:
  mov    -0x418(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  jne    L56
  lea    -0x410(%rbp),%rax
  mov    $0x1fd,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L56:
  mov    -0x418(%rbp),%rax
  movb   $0x2f,(%rax)
L62:
  mov    -0x418(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L47
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  jne    L25
  lea    -0x410(%rbp),%rax
  mov    $0x1fd,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L25:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
void makePath(char *Path) {
  char T[1024], *P;
  strcpy(T, Path);
  P = T;
  while ((P = strchr(P + 1, '/'))) {
    if (P[1] == '.' && P[2] == '/') {
      strcpy(P, P + 2);
    }
    *P = 0;
    if (!file_exists(T))
      mkdir(T, 0775);
    *P = '/';
  }
  if (!file_exists(T))
    mkdir(T, 0775);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makePath>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rbp
  jmp    L47
L42:
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L68
L93:
  movb   $0x2f,(%rbx)
L47:
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L98
  cmpb   $0x2e,0x1(%rbx)
  jne    L42
  cmpb   $0x2f,0x2(%rbx)
  jne    L42
  lea    0x2(%rbx),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L42
L68:
  mov    $0x1fd,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L93
L98:
  mov    %rsp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L62
L97:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  mov    %rsp,%rdi
  mov    $0x1fd,%esi
  call   <mkdir@plt>
  jmp    L97
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void makePath(char *Path) {
  char T[1024], *P;
  strcpy(T, Path);
  P = T;
  while ((P = strchr(P + 1, '/'))) {
    if (P[1] == '.' && P[2] == '/') {
      strcpy(P, P + 2);
    }
    *P = 0;
    if (!file_exists(T))
      mkdir(T, 0775);
    *P = '/';
  }
  if (!file_exists(T))
    mkdir(T, 0775);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<makePath>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <strcpy@plt>
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L53:
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L78
L30:
  movb   $0x2f,(%rbx)
L16:
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L59
  cmpb   $0x2e,0x1(%rbx)
  jne    L53
  cmpb   $0x2f,0x2(%rbx)
  jne    L53
  mov    %rbx,%rdi
  lea    0x2(%rbx),%rsi
  call   <strcpy@plt>
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  jne    L30
  nopw   0x0(%rax,%rax,1)
L78:
  mov    $0x1fd,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L30
  nop
L59:
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L46
L82:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L46:
  mov    $0x1fd,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L82
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void makePath(char *Path) {
  char T[1024], *P;
  strcpy(T, Path);
  P = T;
  while ((P = strchr(P + 1, '/'))) {
    if (P[1] == '.' && P[2] == '/') {
      strcpy(P, P + 2);
    }
    *P = 0;
    if (!file_exists(T))
      mkdir(T, 0775);
    *P = '/';
  }
  if (!file_exists(T))
    mkdir(T, 0775);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<makePath>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rbp,%rbx
  call   <strcpy@plt>
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L98:
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L66
L54:
  movb   $0x2f,(%rbx)
L30:
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L88
  cmpb   $0x2e,0x1(%rbx)
  jne    L98
  cmpb   $0x2f,0x2(%rbx)
  jne    L98
  mov    %rbx,%rdi
  lea    0x2(%rbx),%rsi
  call   <strcpy@plt>
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  jne    L54
  nopw   0x0(%rax,%rax,1)
L66:
  mov    $0x1fd,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L54
  nop
L88:
  mov    %rbp,%rdi
  call   <file_exists@plt>
  test   %eax,%eax
  je     L87
L92:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L87:
  mov    $0x1fd,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L92
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void makePath(char *Path) {
  char T[1024], *P;
  strcpy(T, Path);
  P = T;
  while ((P = strchr(P + 1, '/'))) {
    if (P[1] == '.' && P[2] == '/') {
      strcpy(P, P + 2);
    }
    *P = 0;
    if (!file_exists(T))
      mkdir(T, 0775);
    *P = '/';
  }
  if (!file_exists(T))
    mkdir(T, 0775);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cpufreq_modify_policy_governor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L13
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x13,%eax
  jle    L3
L13:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L23
L3:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sysfs_modify_policy_governor@plt>
L23:
  leave
  ret
```

assistant: ```c
int cpufreq_modify_policy_governor(unsigned int cpu, char *governor) {
  if ((!governor) || (strlen(governor) > 19))
    return -EINVAL;
  return sysfs_modify_policy_governor(cpu, governor);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cpufreq_modify_policy_governor>:
  endbr64
  test   %rsi,%rsi
  je     L22
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    $0x13,%eax
  jle    L8
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <sysfs_modify_policy_governor@plt>
  jmp    L15
L22:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int cpufreq_modify_policy_governor(unsigned int cpu, char *governor) {
  if ((!governor) || (strlen(governor) > 19))
    return -EINVAL;
  return sysfs_modify_policy_governor(cpu, governor);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cpufreq_modify_policy_governor>:
  endbr64
  test   %rsi,%rsi
  je     L15
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x13,%eax
  jle    L6
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <sysfs_modify_policy_governor@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int cpufreq_modify_policy_governor(unsigned int cpu, char *governor) {
  if ((!governor) || (strlen(governor) > 19))
    return -EINVAL;
  return sysfs_modify_policy_governor(cpu, governor);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cpufreq_modify_policy_governor>:
  endbr64
  test   %rsi,%rsi
  je     L7
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x13,%eax
  jle    L8
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <sysfs_modify_policy_governor@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int cpufreq_modify_policy_governor(unsigned int cpu, char *governor) {
  if ((!governor) || (strlen(governor) > 19))
    return -EINVAL;
  return sysfs_modify_policy_governor(cpu, governor);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L25:
  mov    -0x10(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L25
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D25
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D3: Enter the value of n

tool: D25: %d

tool: D11: Sum of the series = %d

assistant: ```c
int main() {
  int n, i, s = 0;
  printf("Enter the value of n\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++)
    s = s + (i * i);
  printf("Sum of the series = %d", s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  js     L17
  add    $0x1,%ecx
  mov    $0x0,%esi
  mov    $0x0,%eax
L29:
  mov    %eax,%edx
  imul   %eax,%edx
  add    %edx,%esi
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L29
L22:
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L17:
  mov    $0x0,%esi
  jmp    L22
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D22
data_type: string

tool: D5: Enter the value of n

tool: D3: %d

tool: D22: Sum of the series = %d

assistant: ```c
int main() {
  int n, i, s = 0;
  printf("Enter the value of n\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++)
    s = s + (i * i);
  printf("Sum of the series = %d", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  js     L19
  add    $0x1,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  mov    %eax,%edx
  imul   %eax,%edx
  add    $0x1,%eax
  add    %edx,%esi
  cmp    %eax,%ecx
  jne    L10
L15:
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  xor    %esi,%esi
  jmp    L15
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D29
type: string

tool: D16: Enter the value of n

tool: D24: %d

tool: D29: Sum of the series = %d

assistant: ```c
int main() {
  int n, i, s = 0;
  printf("Enter the value of n\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++)
    s = s + (i * i);
  printf("Sum of the series = %d", s);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  js     L26
  lea    0x1(%rcx),%edi
  cmp    $0x11,%ecx
  jle    L65
  mov    %edi,%edx
  movdqa D22(%rip),%xmm3
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  movdqa D29(%rip),%xmm4
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L75:
  movdqa %xmm3,%xmm0
  add    $0x1,%eax
  paddd  %xmm4,%xmm3
  movdqa %xmm0,%xmm2
  pmuludq %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm0,%xmm0
  pshufd $0x8,%xmm2,%xmm2
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm2
  paddd  %xmm2,%xmm1
  cmp    %edx,%eax
  jne    L75
  movdqa %xmm1,%xmm0
  mov    %edi,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  and    $0x3,%edi
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%esi
  je     L17
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %eax,%edx
  imul   %eax,%edx
  add    $0x1,%eax
  add    %edx,%esi
  cmp    %eax,%ecx
  jge    L37
L17:
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L26:
  xor    %esi,%esi
  jmp    L17
L65:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L37
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D29
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D47
type_infered: string

tool: D9: Enter the value of n

tool: D6: %d

tool: {"D22": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D29": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D47: Sum of the series = %d

assistant: ```c
int main() {
  int n, i, s = 0;
  printf("Enter the value of n\n");
  scanf("%d", &n);
  for (i = 0; i <= n; i++)
    s = s + (i * i);
  printf("Sum of the series = %d", s);
  return 0;
}
```