ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %eax,%eax
  jle    L25
  lea    0x1c(%rsp),%rax
  lea    0x20(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    0x18(%rsp),%rax
  lea    D16(%rip),%rbx
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L58:
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  xor    %eax,%eax
  xor    %r12d,%r12d
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jle    L3
  nopl   0x0(%rax)
L39:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    $0x1,%r15d
  call   <scanf@plt>
  mov    0x20(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x20(%rsp)
  test   %eax,%eax
  jle    L34
  lea    0x24(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  imul   %r15d,%eax
  cltd
  idivl  0x18(%rsp)
  mov    0x20(%rsp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,0x20(%rsp)
  mov    %edx,%r15d
  test   %eax,%eax
  jg     L62
L34:
  mov    0x1c(%rsp),%eax
  add    %r15d,%r12d
  lea    -0x1(%rax),%edx
  mov    %edx,0x1c(%rsp)
  test   %eax,%eax
  jg     L39
L3:
  mov    %r12d,%eax
  mov    %r14,%rdi
  cltd
  idivl  0x18(%rsp)
  mov    %edx,%esi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %eax,%eax
  jg     L58
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string

tool: D4: %d


tool: D16: %d 

tool: D21: %d %d


assistant: ```c
int main(void) {
  int a, b, c, d, e, n, sum;
  scanf("%d\n", &a);
  while (a-- > 0) {
    sum = 0;
    scanf("%d %d\n", &b, &c);
    while (c-- > 0) {
      n = 1;
      scanf("%d ", &d);
      while (d-- > 0) {
        scanf("%d ", &e);
        n *= e;
        n %= b;
      }
      sum += n;
    }
    printf("%d\n", sum % b);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <check_expected@plt>
  mov    $0x0,%eax
  call   <mock@plt>
  leave
  ret
```

assistant: ```c
char *concat(int num_args, ...) {
  check_expected(num_args);
  return (char *)mock();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<concat>:
  endbr64
  sub    $0x8,%rsp
  call   <check_expected@plt>
  mov    $0x0,%eax
  call   <mock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *concat(int num_args, ...) {
  check_expected(num_args);
  return (char *)mock();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<concat>:
  endbr64
  sub    $0x8,%rsp
  call   <check_expected@plt>
  xor    %eax,%eax
  call   <mock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *concat(int num_args, ...) {
  check_expected(num_args);
  return (char *)mock();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<concat>:
  endbr64
  sub    $0x8,%rsp
  call   <check_expected@plt>
  xor    %eax,%eax
  call   <mock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *concat(int num_args, ...) {
  check_expected(num_args);
  return (char *)mock();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findOdd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findOdd(int arr[], int n) {
  int res = 0, i;
  for (i = 0; i < n; i++)
    res ^= arr[i];
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findOdd>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L9:
  xor    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
L20:
  mov    %edx,%eax
  ret
L14:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int findOdd(int arr[], int n) {
  int res = 0, i;
  for (i = 0; i < n; i++)
    res ^= arr[i];
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findOdd>:
  endbr64
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  xor    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L1
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int findOdd(int arr[], int n) {
  int res = 0, i;
  for (i = 0; i < n; i++)
    res ^= arr[i];
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<findOdd>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L37
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L58
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L44:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L44
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L62
L29:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  xor    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L30
  add    $0x2,%ecx
  xor    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L30
  xor    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L37:
  xor    %eax,%eax
L30:
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  ret
L58:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
int findOdd(int arr[], int n) {
  int res = 0, i;
  for (i = 0; i < n; i++)
    res ^= arr[i];
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writechar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L16
  cmpl   $0x2,-0x4(%rbp)
  je     L1
  jmp    L5
L16:
  movsbl -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <stdout_write@plt>
  jmp    L5
L1:
  movsbl -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <stderr_write@plt>
  nop
L5:
  nop
  leave
  ret
```

assistant: ```c
void writechar(int file, char c) {
  switch (file) {
  case 1:
    stdout_write(c);
    break;
  case 2:
    stderr_write(c);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<writechar>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L6
  cmp    $0x2,%edi
  je     L39
L26:
  add    $0x8,%rsp
  ret
L6:
  movsbl %sil,%edi
  call   <stdout_write@plt>
  jmp    L26
L39:
  movsbl %sil,%edi
  call   <stderr_write@plt>
  jmp    L26
```

assistant: ```c
void writechar(int file, char c) {
  switch (file) {
  case 1:
    stdout_write(c);
    break;
  case 2:
    stderr_write(c);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<writechar>:
  endbr64
  cmp    $0x1,%edi
  je     L3
  cmp    $0x2,%edi
  jne    L9
  movsbl %sil,%edi
  jmp    1060 <stderr_write@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  ret
  nopl   0x0(%rax)
L3:
  movsbl %sil,%edi
  jmp    1070 <stdout_write@plt>
```

assistant: ```c
void writechar(int file, char c) {
  switch (file) {
  case 1:
    stdout_write(c);
    break;
  case 2:
    stderr_write(c);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writechar>:
  endbr64
  cmp    $0x1,%edi
  je     L5
  cmp    $0x2,%edi
  jne    L14
  movsbl %sil,%edi
  jmp    1060 <stderr_write@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  ret
  nopl   0x0(%rax)
L5:
  movsbl %sil,%edi
  jmp    1070 <stdout_write@plt>
```

assistant: ```c
void writechar(int file, char c) {
  switch (file) {
  case 1:
    stdout_write(c);
    break;
  case 2:
    stderr_write(c);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isNumberMain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D106(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D103(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D74
datatype: string
name: unpack_data
arguments: data_tag: D106
datatype: string
name: unpack_data
arguments: data_tag: D103
datatype: string
name: unpack_data
arguments: data_tag: D97
datatype: string
name: unpack_data
arguments: data_tag: D35
datatype: string
name: unpack_data
arguments: data_tag: D86
datatype: string

tool: D24: 3.   

tool: D74: %d


tool: D106: 3.e3   

tool: D103: 3.2e3   

tool: D97: 1 e6

tool: D35: 1.e6

tool: D86: 3me

assistant: ```c
void isNumberMain(void) {
  printf("%d\n", isNumber("3.   "));
  printf("%d\n", isNumber("3.e3   "));
  printf("%d\n", isNumber("3.2e3   "));
  printf("%d\n", isNumber("1 e6"));
  printf("%d\n", isNumber("1.e6"));
  printf("%d\n", isNumber("3me"));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isNumberMain>:
  endbr64
  push   %rbx
  lea    D56(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <isNumber@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D61
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string
name: retrieve_data
arguments: data_label: D21
type_infered: string

tool: D56: 3.   

tool: D7: %d


tool: D61: 3.e3   

tool: D8: 3.2e3   

tool: D9: 1 e6

tool: D47: 1.e6

tool: D21: 3me

assistant: ```c
void isNumberMain(void) {
  printf("%d\n", isNumber("3.   "));
  printf("%d\n", isNumber("3.e3   "));
  printf("%d\n", isNumber("3.2e3   "));
  printf("%d\n", isNumber("1 e6"));
  printf("%d\n", isNumber("1.e6"));
  printf("%d\n", isNumber("3me"));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isNumberMain>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rdi
  lea    D60(%rip),%rbp
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D36
datatype: string
name: parse_data
arguments: label: D60
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D51
datatype: string
name: parse_data
arguments: label: D30
datatype: string

tool: D36: 3.   

tool: D60: %d


tool: D21: 3.e3   

tool: D29: 3.2e3   

tool: D20: 1 e6

tool: D51: 1.e6

tool: D30: 3me

assistant: ```c
void isNumberMain(void) {
  printf("%d\n", isNumber("3.   "));
  printf("%d\n", isNumber("3.e3   "));
  printf("%d\n", isNumber("3.2e3   "));
  printf("%d\n", isNumber("1 e6"));
  printf("%d\n", isNumber("1.e6"));
  printf("%d\n", isNumber("3me"));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isNumberMain>:
  endbr64
  push   %rbp
  lea    D58(%rip),%rdi
  lea    D62(%rip),%rbp
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <isNumber@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D58
type_infered: string
name: retrieve_data
arguments: label: D62
type_infered: string
name: retrieve_data
arguments: label: D42
type_infered: string
name: retrieve_data
arguments: label: D50
type_infered: string
name: retrieve_data
arguments: label: D68
type_infered: string
name: retrieve_data
arguments: label: D65
type_infered: string
name: retrieve_data
arguments: label: D36
type_infered: string

tool: D58: 3.   

tool: D62: %d


tool: D42: 3.e3   

tool: D50: 3.2e3   

tool: D68: 1 e6

tool: D65: 1.e6

tool: D36: 3me

assistant: ```c
void isNumberMain(void) {
  printf("%d\n", isNumber("3.   "));
  printf("%d\n", isNumber("3.e3   "));
  printf("%d\n", isNumber("3.2e3   "));
  printf("%d\n", isNumber("1 e6"));
  printf("%d\n", isNumber("1.e6"));
  printf("%d\n", isNumber("3me"));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  ja     L42
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D1(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <test0@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test1@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test2@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test3@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test4@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test5@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test6@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test7@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test8@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test9@plt>
  jmp    L117
  mov    $0x0,%eax
  call   <test10@plt>
  jmp    L117
L42:
  mov    $0x0,%eax
  call   <test0@plt>
  mov    $0x0,%eax
  call   <test1@plt>
  mov    $0x0,%eax
  call   <test2@plt>
  mov    $0x0,%eax
  call   <test3@plt>
  mov    $0x0,%eax
  call   <test4@plt>
  mov    $0x0,%eax
  call   <test5@plt>
  mov    $0x0,%eax
  call   <test6@plt>
  mov    $0x0,%eax
  call   <test7@plt>
  mov    $0x0,%eax
  call   <test8@plt>
  mov    $0x0,%eax
  call   <test9@plt>
  mov    $0x0,%eax
  call   <test10@plt>
L117:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int test = -1;
  switch (test) {
  case 0:
    test0();
    break;
  case 1:
    test1();
    break;
  case 2:
    test2();
    break;
  case 3:
    test3();
    break;
  case 4:
    test4();
    break;
  case 5:
    test5();
    break;
  case 6:
    test6();
    break;
  case 7:
    test7();
    break;
  case 8:
    test8();
    break;
  case 9:
    test9();
    break;
  case 10:
    test10();
    break;
  default:
    test0();
    test1();
    test2();
    test3();
    test4();
    test5();
    test6();
    test7();
    test8();
    test9();
    test10();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test0@plt>
  mov    $0x0,%eax
  call   <test1@plt>
  mov    $0x0,%eax
  call   <test2@plt>
  mov    $0x0,%eax
  call   <test3@plt>
  mov    $0x0,%eax
  call   <test4@plt>
  mov    $0x0,%eax
  call   <test5@plt>
  mov    $0x0,%eax
  call   <test6@plt>
  mov    $0x0,%eax
  call   <test7@plt>
  mov    $0x0,%eax
  call   <test8@plt>
  mov    $0x0,%eax
  call   <test9@plt>
  mov    $0x0,%eax
  call   <test10@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int test = -1;
  switch (test) {
  case 0:
    test0();
    break;
  case 1:
    test1();
    break;
  case 2:
    test2();
    break;
  case 3:
    test3();
    break;
  case 4:
    test4();
    break;
  case 5:
    test5();
    break;
  case 6:
    test6();
    break;
  case 7:
    test7();
    break;
  case 8:
    test8();
    break;
  case 9:
    test9();
    break;
  case 10:
    test10();
    break;
  default:
    test0();
    test1();
    test2();
    test3();
    test4();
    test5();
    test6();
    test7();
    test8();
    test9();
    test10();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test0@plt>
  xor    %eax,%eax
  call   <test1@plt>
  xor    %eax,%eax
  call   <test2@plt>
  xor    %eax,%eax
  call   <test3@plt>
  xor    %eax,%eax
  call   <test4@plt>
  xor    %eax,%eax
  call   <test5@plt>
  xor    %eax,%eax
  call   <test6@plt>
  xor    %eax,%eax
  call   <test7@plt>
  xor    %eax,%eax
  call   <test8@plt>
  xor    %eax,%eax
  call   <test9@plt>
  xor    %eax,%eax
  call   <test10@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int test = -1;
  switch (test) {
  case 0:
    test0();
    break;
  case 1:
    test1();
    break;
  case 2:
    test2();
    break;
  case 3:
    test3();
    break;
  case 4:
    test4();
    break;
  case 5:
    test5();
    break;
  case 6:
    test6();
    break;
  case 7:
    test7();
    break;
  case 8:
    test8();
    break;
  case 9:
    test9();
    break;
  case 10:
    test10();
    break;
  default:
    test0();
    test1();
    test2();
    test3();
    test4();
    test5();
    test6();
    test7();
    test8();
    test9();
    test10();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test0@plt>
  xor    %eax,%eax
  call   <test1@plt>
  xor    %eax,%eax
  call   <test2@plt>
  xor    %eax,%eax
  call   <test3@plt>
  xor    %eax,%eax
  call   <test4@plt>
  xor    %eax,%eax
  call   <test5@plt>
  xor    %eax,%eax
  call   <test6@plt>
  xor    %eax,%eax
  call   <test7@plt>
  xor    %eax,%eax
  call   <test8@plt>
  xor    %eax,%eax
  call   <test9@plt>
  xor    %eax,%eax
  call   <test10@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int test = -1;
  switch (test) {
  case 0:
    test0();
    break;
  case 1:
    test1();
    break;
  case 2:
    test2();
    break;
  case 3:
    test3();
    break;
  case 4:
    test4();
    break;
  case 5:
    test5();
    break;
  case 6:
    test6();
    break;
  case 7:
    test7();
    break;
  case 8:
    test8();
    break;
  case 9:
    test9();
    break;
  case 10:
    test10();
    break;
  default:
    test0();
    test1();
    test2();
    test3();
    test4();
    test5();
    test6();
    test7();
    test8();
    test9();
    test10();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<twobyte_memmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
  jmp    L37
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L16
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  jmp    L30
L16:
  subq   $0x1,-0x20(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
L37:
  cmpq   $0x0,-0x20(%rbp)
  jne    L20
  mov    $0x0,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h++, k--; k; k--, hw = hw << 8 | *++h)
    if (hw == nw)
      return (char *)h - 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<twobyte_memmem>:
  endbr64
  movzbl (%rdx),%r8d
  shl    $0x8,%r8d
  movzbl 0x1(%rdx),%eax
  or     %eax,%r8d
  movzbl (%rdi),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rdi),%eax
  or     %eax,%edx
  lea    0x1(%rdi),%rax
  cmp    $0x1,%rsi
  je     L13
  lea    0x2(%rdi),%rcx
  add    %rsi,%rdi
  cmp    %edx,%r8d
  je     L36
L23:
  shl    $0x8,%edx
  mov    %rcx,%rax
  movzbl (%rcx),%esi
  or     %esi,%edx
  cmp    %rdi,%rcx
  je     L8
  add    $0x1,%rcx
  cmp    %edx,%r8d
  jne    L23
L36:
  sub    $0x1,%rax
  ret
L8:
  mov    $0x0,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *twobyte_memmem(const unsigned char *h, size_t k, const unsigned char *n) {
  uint16_t nw = n[0] << 8 | n[1], hw = h[0] << 8 | h[1];
  for (h++, k--; k; k--, hw = hw << 8 | *++h)
    if (hw == nw)
      return (char *)h - 1;
  return 0;
}
```