ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_tech_level>:
  endbr64
  push   %rbp
  mov    $0x9,%edx
  lea    D22(%rip),%rsi
  mov    %rdi,%rbp
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L21
L26:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x5,%edx
  lea    D44(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L26
  mov    $0x8,%edx
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L26
  mov    $0x8,%edx
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L26
  mov    $0x6,%edx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x5,%eax
  test   %r8,%r8
  je     L26
  mov    %rbp,%rdi
  mov    $0x5,%edx
  lea    D21(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_infered: string
name: parse_data
arguments: data_tag: D44
type_infered: string
name: parse_data
arguments: data_tag: D47
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D21
type_infered: string

tool: D22: Primitive

tool: D44: Basic

tool: D47: Mediocre

tool: D20: Advanced

tool: D9: Exotic

tool: D21: Magic

assistant: ```c
int get_tech_level(const char *tech) {
  if (strncmp(tech, "Primitive", 9) == 0) {
    return 1;
  } else if (strncmp(tech, "Basic", 5) == 0) {
    return 2;
  } else if (strncmp(tech, "Mediocre", 8) == 0) {
    return 3;
  } else if (strncmp(tech, "Advanced", 8) == 0) {
    return 4;
  } else if (strncmp(tech, "Exotic", 6) == 0) {
    return 5;
  } else if (strncmp(tech, "Magic", 5) == 0) {
    return 6;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_tech_level>:
  endbr64
  push   %rbp
  mov    $0x9,%edx
  lea    D40(%rip),%rsi
  mov    %rdi,%rbp
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L23
L11:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x5,%edx
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x2,%eax
  test   %r8,%r8
  je     L11
  mov    $0x8,%edx
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x3,%eax
  test   %r8,%r8
  je     L11
  mov    $0x8,%edx
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  je     L11
  mov    $0x6,%edx
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  mov    $0x5,%eax
  test   %r8,%r8
  je     L11
  mov    %rbp,%rdi
  mov    $0x5,%edx
  lea    D21(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x6,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D40
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string
name: retrieve_data
arguments: label: D45
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D20
datatype: string
name: retrieve_data
arguments: label: D21
datatype: string

tool: D40: Primitive

tool: D24: Basic

tool: D45: Mediocre

tool: D28: Advanced

tool: D20: Exotic

tool: D21: Magic

assistant: ```c
int get_tech_level(const char *tech) {
  if (strncmp(tech, "Primitive", 9) == 0) {
    return 1;
  } else if (strncmp(tech, "Basic", 5) == 0) {
    return 2;
  } else if (strncmp(tech, "Mediocre", 8) == 0) {
    return 3;
  } else if (strncmp(tech, "Advanced", 8) == 0) {
    return 4;
  } else if (strncmp(tech, "Exotic", 6) == 0) {
    return 5;
  } else if (strncmp(tech, "Magic", 5) == 0) {
    return 6;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shm_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_shm_name@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L15
L14:
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L31
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  js     L33
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    D40(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x10(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  jns    L31
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  movl   $0xffffffff,-0x14(%rbp)
L31:
  mov    D41(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D41(%rip),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
int shm_open(const char *name, int oflag, mode_t mode) {
  int fd, old_errno;
  char *shm_name = get_shm_name(name);
  if (shm_name == NULL)
    return -1;
  fd = open(shm_name, oflag, mode);
  if (fd >= 0) {
    int fdflags = fcntl(fd, F_GETFD, 0);
    if (fdflags >= 0)
      fdflags = fcntl(fd, F_SETFD, fdflags | FD_CLOEXEC);
    if (fdflags < 0) {
      close(fd);
      fd = -1;
    }
  }
  old_errno = errno;
  free(shm_name);
  errno = old_errno;
  return fd;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shm_open>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <get_shm_name@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L35
L19:
  mov    D12(%rip),%r12
  mov    (%r12),%r13d
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13d,(%r12)
L66:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  mov    $0x0,%edx
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L64
L4:
  mov    %ebp,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebp
  jmp    L19
L64:
  mov    D24(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L19
  jmp    L4
L2:
  mov    $0xffffffff,%ebp
  jmp    L66
```

assistant: ```c
int shm_open(const char *name, int oflag, mode_t mode) {
  int fd, old_errno;
  char *shm_name = get_shm_name(name);
  if (shm_name == NULL)
    return -1;
  fd = open(shm_name, oflag, mode);
  if (fd >= 0) {
    int fdflags = fcntl(fd, F_GETFD, 0);
    if (fdflags >= 0)
      fdflags = fcntl(fd, F_SETFD, fdflags | FD_CLOEXEC);
    if (fdflags < 0) {
      close(fd);
      fd = -1;
    }
  }
  old_errno = errno;
  free(shm_name);
  errno = old_errno;
  return fd;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<shm_open>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_shm_name@plt>
  test   %rax,%rax
  je     L39
  mov    %r12d,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L19
L0:
  mov    D36(%rip),%r13
  mov    %rbp,%rdi
  mov    0x0(%r13),%ebx
  call   <free@plt>
  mov    %ebx,0x0(%r13)
L43:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L19:
  mov    D1(%rip),%rax
  xor    %edx,%edx
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L62
L57:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L62:
  mov    D29(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L0
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%r12d
  jmp    L43
```

assistant: ```c
int shm_open(const char *name, int oflag, mode_t mode) {
  int fd, old_errno;
  char *shm_name = get_shm_name(name);
  if (shm_name == NULL)
    return -1;
  fd = open(shm_name, oflag, mode);
  if (fd >= 0) {
    int fdflags = fcntl(fd, F_GETFD, 0);
    if (fdflags >= 0)
      fdflags = fcntl(fd, F_SETFD, fdflags | FD_CLOEXEC);
    if (fdflags < 0) {
      close(fd);
      fd = -1;
    }
  }
  old_errno = errno;
  free(shm_name);
  errno = old_errno;
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shm_open>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_shm_name@plt>
  test   %rax,%rax
  je     L7
  mov    %r12d,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L63
L44:
  mov    D4(%rip),%r13
  mov    %rbp,%rdi
  mov    0x0(%r13),%ebx
  call   <free@plt>
  mov    %ebx,0x0(%r13)
L50:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L63:
  mov    D33(%rip),%rax
  xor    %edx,%edx
  mov    %r12d,%edi
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L54
L57:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L54:
  mov    D2(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D39(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %eax,%eax
  jns    L44
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%r12d
  jmp    L50
```

assistant: ```c
int shm_open(const char *name, int oflag, mode_t mode) {
  int fd, old_errno;
  char *shm_name = get_shm_name(name);
  if (shm_name == NULL)
    return -1;
  fd = open(shm_name, oflag, mode);
  if (fd >= 0) {
    int fdflags = fcntl(fd, F_GETFD, 0);
    if (fdflags >= 0)
      fdflags = fcntl(fd, F_SETFD, fdflags | FD_CLOEXEC);
    if (fdflags < 0) {
      close(fd);
      fd = -1;
    }
  }
  old_errno = errno;
  free(shm_name);
  errno = old_errno;
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kaatcp_get_padding_from_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    $0x4,%eax
  sub    -0x4(%rbp),%eax
  jmp    L10
L9:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t kaatcp_get_padding_from_length(uint32_t length) {
  uint8_t padding = length % 4;
  return padding ? 4 - padding : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kaatcp_get_padding_from_length>:
  endbr64
  mov    $0x0,%eax
  test   $0x3,%dil
  je     L0
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%edi
  and    $0x3,%edi
  sub    %edi,%eax
  lea    0x4(%rax),%eax
L0:
  ret
```

assistant: ```c
uint8_t kaatcp_get_padding_from_length(uint32_t length) {
  uint8_t padding = length % 4;
  return padding ? 4 - padding : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kaatcp_get_padding_from_length>:
  endbr64
  xor    %eax,%eax
  test   $0x3,%dil
  je     L5
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%edi
  and    $0x3,%edi
  sub    %edi,%eax
  add    $0x4,%eax
L5:
  ret
```

assistant: ```c
uint8_t kaatcp_get_padding_from_length(uint32_t length) {
  uint8_t padding = length % 4;
  return padding ? 4 - padding : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kaatcp_get_padding_from_length>:
  endbr64
  xor    %eax,%eax
  test   $0x3,%dil
  je     L4
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%edi
  and    $0x3,%edi
  sub    %edi,%eax
  add    $0x4,%eax
L4:
  ret
```

assistant: ```c
uint8_t kaatcp_get_padding_from_length(uint32_t length) {
  uint8_t padding = length % 4;
  return padding ? 4 - padding : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_loopback_large_unaligned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1008,-0x30(%rbp)
  movl   $0x1409,-0x2c(%rbp)
  movl   $0x2c08,-0x28(%rbp)
  movl   $0x300c,-0x24(%rbp)
  movl   $0x3412,-0x20(%rbp)
  movl   $0x3c00,-0x1c(%rbp)
  movl   $0x8028,-0x18(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x7,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <test_loopback_all_sizes@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int test_loopback_large_unaligned(int fd) {
  int sizes[] = {(1024 * 4) + 8, (5 * 1024) + 9, (1024 * 11) + 8, (1024 * 12) + 12, (1024 * 13) + 18, (1024 * 15), (32 * 1024 + 8 * 5)};
  return test_loopback_all_sizes(fd, sizes, (int)(sizeof(sizes) / sizeof((sizes)[0])));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_loopback_large_unaligned>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1008,(%rsp)
  movl   $0x1409,0x4(%rsp)
  movl   $0x2c08,0x8(%rsp)
  movl   $0x300c,0xc(%rsp)
  movl   $0x3412,0x10(%rsp)
  movl   $0x3c00,0x14(%rsp)
  movl   $0x8028,0x18(%rsp)
  mov    %rsp,%rsi
  mov    $0x7,%edx
  call   <test_loopback_all_sizes@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_loopback_large_unaligned(int fd) {
  int sizes[] = {(1024 * 4) + 8, (5 * 1024) + 9, (1024 * 11) + 8, (1024 * 12) + 12, (1024 * 13) + 18, (1024 * 15), (32 * 1024 + 8 * 5)};
  return test_loopback_all_sizes(fd, sizes, (int)(sizeof(sizes) / sizeof((sizes)[0])));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_loopback_large_unaligned>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x7,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x140900001008,%rax
  mov    %rsp,%rsi
  movl   $0x8028,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300c00002c08,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x3c0000003412,%rax
  mov    %rax,0x10(%rsp)
  call   <test_loopback_all_sizes@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_loopback_large_unaligned(int fd) {
  int sizes[] = {(1024 * 4) + 8, (5 * 1024) + 9, (1024 * 11) + 8, (1024 * 12) + 12, (1024 * 13) + 18, (1024 * 15), (32 * 1024 + 8 * 5)};
  return test_loopback_all_sizes(fd, sizes, (int)(sizeof(sizes) / sizeof((sizes)[0])));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_loopback_large_unaligned>:
  endbr64
  sub    $0x38,%rsp
  movdqa D11(%rip),%xmm0
  mov    $0x7,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D18(%rip),%rax
  mov    %rsp,%rsi
  movl   $0x8028,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <test_loopback_all_sizes@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: byte[16]
name: read_data
arguments: data_tag: D18
type_infered: byte[8]

tool: {"D11": [0x08,0x10,0x00,0x00,0x09,0x14,0x00,0x00,0x08,0x2c,0x00,0x00,0x0c,0x30,0x00,0x00]}

tool: {"D18": [0x12,0x34,0x00,0x00,0x00,0x3c,0x00,0x00]}

assistant: ```c
int test_loopback_large_unaligned(int fd) {
  int sizes[] = {(1024 * 4) + 8, (5 * 1024) + 9, (1024 * 11) + 8, (1024 * 12) + 12, (1024 * 13) + 18, (1024 * 15), (32 * 1024 + 8 * 5)};
  return test_loopback_all_sizes(fd, sizes, (int)(sizeof(sizes) / sizeof((sizes)[0])));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse_words1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L52:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L96
  cmpl   $0x1,-0x14(%rbp)
  jne    L49
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L96:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L18
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  cmpl   $0x0,-0x14(%rbp)
  jne    L49
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L49
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
L49:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void reverse_words1(char str[]) {
  int state = 0;
  char *end = str;
  char *word_begin = str;
  while (*end != '\0') {
    end++;
    if (*end == ' ') {
      if (state == 1) {
        reverse(word_begin, end - 1);
        state = 0;
      }
      continue;
    }
    if (*end != ' ' && *end != '\0') {
      if (state == 0) {
        word_begin = end;
        state = 1;
      }
      continue;
    }
    if (*end == '\0') {
      reverse(word_begin, end - 1);
    }
  }
  reverse(str, end - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reverse_words1>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmpb   $0x0,(%rdi)
  je     L42
  mov    %rdi,%r13
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    $0x1,%r14d
  jmp    L63
L10:
  cmp    $0x1,%r12d
  jne    L1
  mov    %r13,%rdi
  call   <reverse@plt>
  mov    $0x0,%r12d
L80:
  cmpb   $0x0,(%rbx)
  je     L17
L1:
  mov    %rbx,%rsi
L63:
  lea    0x1(%rsi),%rbx
  movzbl 0x1(%rsi),%eax
  cmp    $0x20,%al
  je     L10
  test   %al,%al
  jne    L26
  mov    %r13,%rdi
  call   <reverse@plt>
  jmp    L80
L26:
  test   %r12d,%r12d
  jne    L1
  mov    %rbx,%r13
  mov    %r14d,%r12d
  jmp    L1
L42:
  mov    %rdi,%rbx
L17:
  lea    -0x1(%rbx),%rsi
  mov    %rbp,%rdi
  call   <reverse@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void reverse_words1(char str[]) {
  int state = 0;
  char *end = str;
  char *word_begin = str;
  while (*end != '\0') {
    end++;
    if (*end == ' ') {
      if (state == 1) {
        reverse(word_begin, end - 1);
        state = 0;
      }
      continue;
    }
    if (*end != ' ' && *end != '\0') {
      if (state == 0) {
        word_begin = end;
        state = 1;
      }
      continue;
    }
    if (*end == '\0') {
      reverse(word_begin, end - 1);
    }
  }
  reverse(str, end - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse_words1>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L19
  mov    %rdi,%r14
  mov    %rdi,%rbx
  xor    %r12d,%r12d
L6:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbp
  cmp    $0x20,%al
  je     L63
L130:
  test   %al,%al
  je     L110
L41:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rbx
  test   %r12d,%r12d
  jne    L120
  mov    %rbp,%r14
  cmp    $0x20,%al
  je     L123
L102:
  mov    %rbx,%rdx
  mov    $0x1,%r12d
  mov    %rbp,%rbx
  mov    %rdx,%rbp
  test   %al,%al
  jne    L41
L110:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <reverse@plt>
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
L132:
  cmpb   $0x0,(%rbx)
  jne    L6
L104:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <reverse@plt>
  nopl   0x0(%rax)
L120:
  cmp    $0x20,%al
  jne    L102
L123:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %r12d,%r12d
  call   <reverse@plt>
  jmp    L132
  nopl   0x0(%rax)
L63:
  cmp    $0x1,%r12d
  je     L85
  mov    %rbp,%rbx
L22:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbp
  cmp    $0x20,%al
  jne    L130
  movzbl 0x2(%rbx),%eax
  add    $0x2,%rbx
  cmp    $0x20,%al
  je     L22
  mov    %rbx,%rdx
  mov    %rbp,%rbx
  mov    %rdx,%rbp
  jmp    L130
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rdi),%rbp
  jmp    L104
L85:
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
  jmp    L123
```

assistant: ```c
void reverse_words1(char str[]) {
  int state = 0;
  char *end = str;
  char *word_begin = str;
  while (*end != '\0') {
    end++;
    if (*end == ' ') {
      if (state == 1) {
        reverse(word_begin, end - 1);
        state = 0;
      }
      continue;
    }
    if (*end != ' ' && *end != '\0') {
      if (state == 0) {
        word_begin = end;
        state = 1;
      }
      continue;
    }
    if (*end == '\0') {
      reverse(word_begin, end - 1);
    }
  }
  reverse(str, end - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse_words1>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L44
  mov    %rdi,%r14
  mov    %rdi,%rbx
  xor    %r12d,%r12d
L95:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbp
  cmp    $0x20,%al
  je     L4
L61:
  test   %al,%al
  je     L120
L42:
  movzbl 0x1(%rbp),%eax
  lea    0x1(%rbp),%rbx
  test   %r12d,%r12d
  jne    L119
  mov    %rbp,%r14
  cmp    $0x20,%al
  je     L107
L87:
  mov    %rbx,%rdx
  mov    $0x1,%r12d
  mov    %rbp,%rbx
  mov    %rdx,%rbp
  test   %al,%al
  jne    L42
L120:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <reverse@plt>
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
L134:
  cmpb   $0x0,(%rbx)
  jne    L95
L37:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <reverse@plt>
  nopl   0x0(%rax)
L119:
  cmp    $0x20,%al
  jne    L87
L107:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %r12d,%r12d
  call   <reverse@plt>
  jmp    L134
  nopl   0x0(%rax)
L4:
  cmp    $0x1,%r12d
  je     L45
  mov    %rbp,%rbx
L5:
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rbp
  cmp    $0x20,%al
  jne    L61
  movzbl 0x2(%rbx),%eax
  add    $0x2,%rbx
  cmp    $0x20,%al
  je     L5
  mov    %rbx,%rdx
  mov    %rbp,%rbx
  mov    %rdx,%rbp
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L44:
  lea    -0x1(%rdi),%rbp
  jmp    L37
L45:
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
  jmp    L107
```

assistant: ```c
void reverse_words1(char str[]) {
  int state = 0;
  char *end = str;
  char *word_begin = str;
  while (*end != '\0') {
    end++;
    if (*end == ' ') {
      if (state == 1) {
        reverse(word_begin, end - 1);
        state = 0;
      }
      continue;
    }
    if (*end != ' ' && *end != '\0') {
      if (state == 0) {
        word_begin = end;
        state = 1;
      }
      continue;
    }
    if (*end == '\0') {
      reverse(word_begin, end - 1);
    }
  }
  reverse(str, end - 1);
}
```