ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  movl   $0x5,-0x68(%rbp)
  movl   $0x7,-0x64(%rbp)
  movl   $0xa,-0x60(%rbp)
  movl   $0x4,-0x5c(%rbp)
  movl   $0x1,-0x58(%rbp)
  movl   $0x7,-0x54(%rbp)
  movl   $0x9,-0x50(%rbp)
  movl   $0x8,-0x4c(%rbp)
  movl   $0x6,-0x48(%rbp)
  lea    -0x40(%rbp),%rcx
  lea    -0x70(%rbp),%rax
  mov    $0xb,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copyAndSort@plt>
  lea    -0x40(%rbp),%rax
  mov    $0xb,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t unsorted[11] = {3, 2, 5, 7, 10, 4, 1, 7, 9, 8, 6};
  uint64_t sorted[11];
  copyAndSort(unsorted, sorted, 11);
  printArray(sorted, 11);
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x8,0x24(%rsp)
  movl   $0x6,0x28(%rsp)
  lea    0x30(%rsp),%rbx
  mov    %rsp,%rdi
  mov    $0xb,%edx
  mov    %rbx,%rsi
  call   <copyAndSort@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x70,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t unsorted[11] = {3, 2, 5, 7, 10, 4, 1, 7, 9, 8, 6};
  uint64_t sorted[11];
  copyAndSort(unsorted, sorted, 11);
  printArray(sorted, 11);
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xb,%edx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x200000003,%rax
  lea    0x30(%rsp),%rbp
  mov    %rsp,%rdi
  movl   $0x6,0x28(%rsp)
  mov    %rbp,%rsi
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x40000000a,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000001,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x800000009,%rax
  mov    %rax,0x20(%rsp)
  call   <copyAndSort@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x70,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  uint64_t unsorted[11] = {3, 2, 5, 7, 10, 4, 1, 7, 9, 8, 6};
  uint64_t sorted[11];
  copyAndSort(unsorted, sorted, 11);
  printArray(sorted, 11);
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<processFloatVar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L27
  movss  -0x18(%rbp),%xmm0
  mov    -0x38(%rbp),%rax
  movss  %xmm0,(%rax)
L27:
  movl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: %f

assistant: ```c
int processFloatVar(char *buf, char *matchStr, float *varp) {
  int retVal = 0;
  int len = strlen(matchStr);
  int varCount;
  float temp = 0;
  if (strncmp(buf, matchStr, len) == 0) {
    varCount = sscanf(&buf[len + 1], "%f", &temp);
    if (varCount == 1)
      *varp = temp;
    retVal = 1;
  }
  return (retVal);
}
```
user: Translate the below assembly code into C programming language:

```asm
<processFloatVar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  movl   $0x0,0x4(%rsp)
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  lea    0x4(%rsp),%rdx
  movslq %ebp,%rbp
  lea    0x1(%r13,%rbp,1),%rdi
  lea    D8(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L0
  mov    $0x1,%eax
  jmp    L17
L0:
  movss  0x4(%rsp),%xmm0
  movss  %xmm0,(%r12)
  jmp    L17
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: %f

assistant: ```c
int processFloatVar(char *buf, char *matchStr, float *varp) {
  int retVal = 0;
  int len = strlen(matchStr);
  int varCount;
  float temp = 0;
  if (strncmp(buf, matchStr, len) == 0) {
    varCount = sscanf(&buf[len + 1], "%f", &temp);
    if (varCount == 1)
      *varp = temp;
    retVal = 1;
  }
  return (retVal);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<processFloatVar>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x4(%rsp)
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L47
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L47:
  lea    0x4(%rsp),%rdx
  lea    0x1(%r12,%rbx,1),%rdi
  lea    D5(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L23
  mov    $0x1,%eax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L23:
  movss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%r13)
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %f

assistant: ```c
int processFloatVar(char *buf, char *matchStr, float *varp) {
  int retVal = 0;
  int len = strlen(matchStr);
  int varCount;
  float temp = 0;
  if (strncmp(buf, matchStr, len) == 0) {
    varCount = sscanf(&buf[len + 1], "%f", &temp);
    if (varCount == 1)
      *varp = temp;
    retVal = 1;
  }
  return (retVal);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<processFloatVar>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0x0,0x4(%rsp)
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L27
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  lea    0x4(%rsp),%rdx
  lea    0x1(%r12,%rbx,1),%rdi
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L16
  mov    $0x1,%eax
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L16:
  movss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%r13)
  jmp    L9
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %f

assistant: ```c
int processFloatVar(char *buf, char *matchStr, float *varp) {
  int retVal = 0;
  int len = strlen(matchStr);
  int varCount;
  float temp = 0;
  if (strncmp(buf, matchStr, len) == 0) {
    varCount = sscanf(&buf[len + 1], "%f", &temp);
    if (varCount == 1)
      *varp = temp;
    retVal = 1;
  }
  return (retVal);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scalarVectorMult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x3,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L14:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scalarVectorMult(float *vector, const int scalar) {
  int i;
  int length = (sizeof(vector) / sizeof((vector)[0])) + 1;
  for (i = 0; i < length; i++) {
    vector[i] *= scalar;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<scalarVectorMult>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  movaps %xmm0,%xmm1
  mulss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rdi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void scalarVectorMult(float *vector, const int scalar) {
  int i;
  int length = (sizeof(vector) / sizeof((vector)[0])) + 1;
  for (i = 0; i < length; i++) {
    vector[i] *= scalar;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scalarVectorMult>:
  endbr64
  pxor   %xmm0,%xmm0
  movss  (%rdi),%xmm1
  cvtsi2ss %esi,%xmm0
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  mulss  0x8(%rdi),%xmm0
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void scalarVectorMult(float *vector, const int scalar) {
  int i;
  int length = (sizeof(vector) / sizeof((vector)[0])) + 1;
  for (i = 0; i < length; i++) {
    vector[i] *= scalar;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scalarVectorMult>:
  endbr64
  pxor   %xmm0,%xmm0
  movq   (%rdi),%xmm1
  cvtsi2ss %esi,%xmm0
  movaps %xmm0,%xmm2
  shufps $0xe0,%xmm2,%xmm2
  mulss  0x8(%rdi),%xmm0
  mulps  %xmm2,%xmm1
  movss  %xmm0,0x8(%rdi)
  movlps %xmm1,(%rdi)
  ret
```

assistant: ```c
void scalarVectorMult(float *vector, const int scalar) {
  int i;
  int length = (sizeof(vector) / sizeof((vector)[0])) + 1;
  for (i = 0; i < length; i++) {
    vector[i] *= scalar;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,%r12
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r15
  test   %rsi,%rsi
  je     L78
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L22:
  mov    (%r14,%rbx,8),%rdi
  call   <string_len@plt>
  cltq
  add    %rax,%rbp
  mov    %rbx,0x18(%rsp)
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jne    L22
  mov    %r12,%rdi
  call   <string_len@plt>
  cltq
  imul   0x18(%rsp),%rax
  lea    0x1(%rbp,%rax,1),%rax
  cmp    %rax,%r15
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  jmp    L96
L55:
  mov    %r13d,%ebp
  jmp    L39
L19:
  movzbl (%r12,%rbx,1),%edx
  mov    0x8(%rsp),%rax
  add    0x10(%rsp),%rax
  mov    %dl,(%rax,%rbx,1)
  add    $0x1,%rbx
L18:
  lea    0x0(%rbp,%rbx,1),%r13d
  mov    %r12,%rdi
  call   <string_len@plt>
  cmp    %ebx,%eax
  jg     L19
L42:
  lea    0x1(%r15),%rax
  add    $0x8,%r14
  cmp    0x18(%rsp),%r15
  je     L48
  mov    %rax,%r15
L96:
  mov    %r14,%rbx
  mov    (%r14),%rdi
  call   <string_len@plt>
  movslq %eax,%rdi
  test   %rdi,%rdi
  je     L55
  mov    $0x0,%edx
  movslq %r13d,%rsi
  add    0x8(%rsp),%rsi
L101:
  mov    (%rbx),%rcx
  movzbl (%rcx,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L101
  lea    (%rax,%r13,1),%ebp
L39:
  cmp    0x18(%rsp),%r15
  jb     L53
  movslq %ebp,%rax
  mov    0x8(%rsp),%rsi
  movb   $0x0,(%rsi,%rax,1)
  mov    %ebp,%r13d
  jmp    L42
L53:
  mov    $0x0,%ebx
  movslq %ebp,%rax
  mov    %rax,0x10(%rsp)
  jmp    L18
L78:
  mov    %rdx,%rdi
  call   <string_len@plt>
  movslq %eax,%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  cmp    %r15,%rax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
L48:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void string_join(char *stringArray[], size_t capacity, char *separator, char *res, size_t maxRes) {
  int i, k, l, pos = 0;
  size_t currentStrLength, totalCharLength = 0;
  for (i = 0; i < capacity; i++) {
    totalCharLength = totalCharLength + string_len(stringArray[i]);
  }
  totalCharLength = totalCharLength + ((capacity - 1) * string_len(separator)) + 1;
  assert(maxRes >= totalCharLength);
  for (i = 0; i < capacity; i++) {
    currentStrLength = string_len(stringArray[i]);
    for (k = 0; k < currentStrLength; k++) {
      res[pos] = stringArray[i][k];
      pos++;
    }
    if (i < capacity - 1) {
      for (l = 0; l < string_len(separator); l++) {
        res[pos] = separator[l];
        pos++;
      }
    } else {
      res[pos] = '\0';
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readable_fs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D49(%rip),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L21
L23:
  mov    -0x48(%rbp),%rax
  shr    $0xa,%rax
  mov    %rax,-0x48(%rbp)
  addl   $0x1,-0x34(%rbp)
L21:
  cmpq   $0x400,-0x48(%rbp)
  ja     L23
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rsi
  mov    -0x48(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  mov    -0x50(%rbp),%rax
  mov    %rsi,%r8
  lea    D25(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x50(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D49
type_guessed: string
name: retrieve_data
arguments: tag: D25
type_guessed: string

tool: D20: B

tool: D5: KB

tool: D26: MB

tool: D49: GB

tool: D25: %.*zu %s

assistant: ```c
char *readable_fs(size_t size, char *buf) {
  int i = 0;
  const char *units[] = {"B", "KB", "MB", "GB"};
  while (size > 1024) {
    size /= 1024;
    i++;
  }
  sprintf(buf, "%.*zu %s", i, size, units[i]);
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readable_fs>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,(%rsp)
  lea    D10(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D34(%rip),%rax
  mov    %rax,0x18(%rsp)
  cmp    $0x400,%rdi
  jbe    L19
  mov    $0x0,%edx
L2:
  mov    %rcx,%rax
  shr    $0xa,%rcx
  add    $0x1,%edx
  cmp    $0x1003ff,%rax
  ja     L2
L22:
  movslq %edx,%rax
  mov    (%rsp,%rax,8),%r8
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %rbx,%rax
  add    $0x30,%rsp
  pop    %rbx
  ret
L19:
  mov    $0x0,%edx
  jmp    L22
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D38
type: string
name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D44
type: string
name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D23
type: string

tool: D38: B

tool: D10: KB

tool: D44: MB

tool: D34: GB

tool: D23: %.*zu %s

assistant: ```c
char *readable_fs(size_t size, char *buf) {
  int i = 0;
  const char *units[] = {"B", "KB", "MB", "GB"};
  while (size > 1024) {
    size /= 1024;
    i++;
  }
  sprintf(buf, "%.*zu %s", i, size, units[i]);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readable_fs>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  mov    %rsi,%r12
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D32(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D45(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D35(%rip),%rax
  mov    %rax,0x18(%rsp)
  cmp    $0x400,%rdi
  jbe    L36
  xor    %edx,%edx
  nopl   (%rax)
L16:
  shr    $0xa,%rcx
  add    $0x1,%edx
  cmp    $0x400,%rcx
  ja     L16
  movslq %edx,%rax
  mov    (%rsp,%rax,8),%r8
L17:
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L36:
  lea    D13(%rip),%r8
  xor    %edx,%edx
  jmp    L17
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D32
datatype: string
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D13
datatype: string

tool: D32: KB

tool: D45: MB

tool: D35: GB

tool: D14: %.*zu %s

tool: D13: B

assistant: ```c
char *readable_fs(size_t size, char *buf) {
  int i = 0;
  const char *units[] = {"B", "KB", "MB", "GB"};
  while (size > 1024) {
    size /= 1024;
    i++;
  }
  sprintf(buf, "%.*zu %s", i, size, units[i]);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readable_fs>:
  endbr64
  push   %r12
  mov    %rdi,%rcx
  lea    D3(%rip),%rdi
  mov    %rsi,%r12
  movq   %rdi,%xmm0
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  lea    D9(%rip),%rax
  movq   %rax,%xmm1
  lea    D17(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  mov    %rax,0x18(%rsp)
  movups %xmm0,0x8(%rsp)
  cmp    $0x400,%rcx
  jbe    L16
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L30:
  shr    $0xa,%rcx
  add    $0x1,%edx
  cmp    $0x400,%rcx
  ja     L30
  movslq %edx,%rax
  mov    (%rsp,%rax,8),%r8
L19:
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x30,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L16:
  lea    D30(%rip),%r8
  xor    %edx,%edx
  jmp    L19
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string
name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D30
datatype: string

tool: D3: KB

tool: D9: MB

tool: D17: GB

tool: D4: %.*zu %s

tool: D30: B

assistant: ```c
char *readable_fs(size_t size, char *buf) {
  int i = 0;
  const char *units[] = {"B", "KB", "MB", "GB"};
  while (size > 1024) {
    size /= 1024;
    i++;
  }
  sprintf(buf, "%.*zu %s", i, size, units[i]);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<series3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L9
L53:
  movl   $0x1,-0x8(%rbp)
  jmp    L38
L28:
  mov    -0x10(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L28
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L51
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L21
L51:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    -0x10(%rbp),%eax
  add    %eax,-0x4(%rbp)
  movl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L53
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D6: %d!

tool: D36: +

tool: D5: .

tool: D4: 
Sum of the above series is %d


assistant: ```c
void series3(int n) {
  int fact = 1, i, j;
  int sum = 0;
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= i; j++)
      fact = fact * j;
    printf("%d!", i);
    i != n ? printf("+") : printf(".");
    sum += fact;
    fact = 1;
  }
  printf("\nSum of the above series is %d\n", sum);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<series3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    $0x2,%ebp
  mov    $0x0,%r14d
  mov    $0x1,%r12d
  lea    D4(%rip),%r15
  test   %edi,%edi
  jg     L9
L17:
  mov    %r14d,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    $0x2e,%edi
  call   <putchar@plt>
L41:
  add    %ebx,%r14d
  add    $0x1,%r12d
  add    $0x1,%ebp
  cmp    %r12d,%r13d
  jl     L17
L9:
  mov    $0x1,%eax
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L20
L14:
  imul   %eax,%ebx
  add    $0x1,%eax
  cmp    %ebp,%eax
  jne    L14
L20:
  mov    %r12d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%r13d
  je     L15
  mov    $0x2b,%edi
  call   <putchar@plt>
  jmp    L41
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D5
type: string

tool: D4: %d!

tool: D5: 
Sum of the above series is %d


assistant: ```c
void series3(int n) {
  int fact = 1, i, j;
  int sum = 0;
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= i; j++)
      fact = fact * j;
    printf("%d!", i);
    i != n ? printf("+") : printf(".");
    sum += fact;
    fact = 1;
  }
  printf("\nSum of the above series is %d\n", sum);
}
```