ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<memset>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  test   %edx,%edx
  je     L8
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L39
  movd   %esi,%xmm1
  mov    %edx,%esi
  mov    %rdi,%rax
  shr    $0x2,%esi
  pshufd $0x0,%xmm1,%xmm0
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L64:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L64
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%esi
  lea    (%r8,%rsi,4),%rsi
  cmp    %eax,%edx
  je     L8
L48:
  lea    0x1(%rax),%edi
  mov    %ecx,(%rsi)
  cmp    %edi,%edx
  jbe    L8
  add    $0x2,%eax
  mov    %ecx,0x4(%rsi)
  cmp    %eax,%edx
  jbe    L8
  mov    %ecx,0x8(%rsi)
L8:
  mov    %r8,%rax
  ret
L39:
  mov    %rdi,%rsi
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void *memset(void *s, int c, unsigned n) {
  uint8_t b = (uint8_t)c;
  uint8_t *p = (uint8_t *)s;
  int i;
  for (i = 0; i < n; i++)
    *p++ = b;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,%eax
  mov    %al,-0x34(%rbp)
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movapd %xmm0,%xmm4
  mulsd  -0x40(%rbp),%xmm4
  movsd  %xmm4,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movsd  %xmm0,-0x48(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movapd %xmm0,%xmm5
  mulsd  -0x48(%rbp),%xmm5
  movsd  %xmm5,-0x48(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  mulsd  -0x48(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <acos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <rad2deg@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D38(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsbl -0x34(%rbp),%eax
  cmp    $0x4e,%eax
  je     L25
  cmp    $0x4e,%eax
  jg     L37
  cmp    $0x4b,%eax
  je     L7
  cmp    $0x4d,%eax
  jmp    L37
L7:
  movsd  -0x10(%rbp),%xmm1
  movsd  D31(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L37
L25:
  movsd  -0x10(%rbp),%xmm1
  movsd  D15(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  nop
L37:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D38
type_infered: byte[8]
name: retrieve_data
arguments: label: D17
type_infered: f64
name: retrieve_data
arguments: label: D31
type_infered: f64
name: retrieve_data
arguments: label: D15
type_infered: f64

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

tool: D17: 1.1515

tool: D31: 1.609344

tool: D15: 0.8684

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2, char unit) {
  double theta, dist;
  theta = lon1 - lon2;
  dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(theta));
  dist = acos(dist);
  dist = rad2deg(dist);
  dist = dist * 60 * 1.1515;
  switch (unit) {
  case 'M':
    break;
  case 'K':
    dist = dist * 1.609344;
    break;
  case 'N':
    dist = dist * 0.8684;
    break;
  }
  return (dist);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distance>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movq   %xmm0,%r12
  movq   %xmm2,%rbp
  mov    %edi,%ebx
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x18(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movq   %xmm0,%r14
  movq   %rbp,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movapd %xmm0,%xmm4
  movq   %r14,%xmm6
  mulsd  %xmm6,%xmm4
  movsd  %xmm4,0x8(%rsp)
  movq   %r12,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movq   %xmm0,%r12
  movq   %rbp,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movq   %r12,%xmm5
  mulsd  %xmm0,%xmm5
  movsd  %xmm5,0x10(%rsp)
  movsd  0x18(%rsp),%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  mulsd  0x10(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <acos@plt>
  call   <rad2deg@plt>
  mulsd  D18(%rip),%xmm0
  mulsd  D6(%rip),%xmm0
  cmp    $0x4b,%bl
  je     L12
  cmp    $0x4e,%bl
  je     L27
L8:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L12:
  mulsd  D31(%rip),%xmm0
  jmp    L8
L27:
  mulsd  D13(%rip),%xmm0
  jmp    L8
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: byte[8]
name: parse_data
arguments: tag: D6
data_type: f64
name: parse_data
arguments: tag: D31
data_type: f64
name: parse_data
arguments: tag: D13
data_type: f64

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

tool: D6: 1.1515

tool: D31: 1.609344

tool: D13: 0.8684

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2, char unit) {
  double theta, dist;
  theta = lon1 - lon2;
  dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(theta));
  dist = acos(dist);
  dist = rad2deg(dist);
  dist = dist * 60 * 1.1515;
  switch (unit) {
  case 'M':
    break;
  case 'K':
    dist = dist * 1.609344;
    break;
  case 'N':
    dist = dist * 0.8684;
    break;
  }
  return (dist);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<distance>:
  endbr64
  push   %rbx
  subsd  %xmm3,%xmm1
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm0,%xmm5
  movapd %xmm4,%xmm0
  movsd  %xmm5,(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm6
  movapd %xmm1,%xmm0
  movsd  %xmm6,0x8(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  call   <acos@plt>
  call   <rad2deg@plt>
  mulsd  D19(%rip),%xmm0
  mulsd  D39(%rip),%xmm0
  cmp    $0x4b,%bl
  je     L18
  cmp    $0x4e,%bl
  jne    L13
  mulsd  D17(%rip),%xmm0
L13:
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mulsd  D34(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D39
type_guessed: f64
name: parse_data
arguments: data_tag: D17
type_guessed: f64
name: parse_data
arguments: data_tag: D34
type_guessed: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

tool: D39: 1.1515

tool: D17: 0.8684

tool: D34: 1.609344

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2, char unit) {
  double theta, dist;
  theta = lon1 - lon2;
  dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(theta));
  dist = acos(dist);
  dist = rad2deg(dist);
  dist = dist * 60 * 1.1515;
  switch (unit) {
  case 'M':
    break;
  case 'K':
    dist = dist * 1.609344;
    break;
  case 'N':
    dist = dist * 0.8684;
    break;
  }
  return (dist);
}
```
user: What is the c source code of the assembly code below?

```asm
<distance>:
  endbr64
  push   %rbx
  subsd  %xmm3,%xmm1
  mov    %edi,%ebx
  sub    $0x20,%rsp
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,(%rsp)
  movapd %xmm2,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movsd  (%rsp),%xmm5
  movsd  0x8(%rsp),%xmm4
  mulsd  %xmm0,%xmm5
  movapd %xmm4,%xmm0
  movsd  %xmm5,(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm1
  mulsd  %xmm0,%xmm6
  movapd %xmm1,%xmm0
  movsd  %xmm6,0x8(%rsp)
  call   <deg2rad@plt>
  mov    %eax,%edi
  call   <cos@plt>
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  call   <acos@plt>
  call   <rad2deg@plt>
  mulsd  D36(%rip),%xmm0
  mulsd  D34(%rip),%xmm0
  cmp    $0x4b,%bl
  je     L16
  cmp    $0x4e,%bl
  jne    L7
  mulsd  D27(%rip),%xmm0
L7:
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mulsd  D7(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D36
type_infered: byte[8]
name: read_data
arguments: label: D34
type_infered: f64
name: read_data
arguments: label: D27
type_infered: f64
name: read_data
arguments: label: D7
type_infered: f64

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

tool: D34: 1.1515

tool: D27: 0.8684

tool: D7: 1.609344

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2, char unit) {
  double theta, dist;
  theta = lon1 - lon2;
  dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(theta));
  dist = acos(dist);
  dist = rad2deg(dist);
  dist = dist * 60 * 1.1515;
  switch (unit) {
  case 'M':
    break;
  case 'K':
    dist = dist * 1.609344;
    break;
  case 'N':
    dist = dist * 0.8684;
    break;
  }
  return (dist);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <iterative_count@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <recursive_count@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: 


assistant: ```c
int main() {
  iterative_count(0);
  printf("\n");
  recursive_count(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <iterative_count@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <recursive_count@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: D9: 


assistant: ```c
int main() {
  iterative_count(0);
  printf("\n");
  recursive_count(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <iterative_count@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <recursive_count@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: 


assistant: ```c
int main() {
  iterative_count(0);
  printf("\n");
  recursive_count(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <iterative_count@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <recursive_count@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: 


assistant: ```c
int main() {
  iterative_count(0);
  printf("\n");
  recursive_count(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    %rsi,%rcx
  mov    (%rdi),%edx
  sub    $0x17447d68,%edx
  test   $0x8,%dl
  je     L36
  test   $0x1,%dl
  je     L24
  lea    0x0(,%rdx,4),%eax
  and    $0x1c,%eax
  or     %edx,%eax
L59:
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%rcx)
  pop    %rbx
  ret
L24:
  mov    %edx,%esi
  shl    $0x10,%esi
  movzwl %dx,%eax
  or     %esi,%eax
  mov    %edx,%ebx
  shl    $0x8,%ebx
  sar    $0x18,%ebx
  mov    %bl,%ah
  shr    $0x18,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  jmp    L59
L36:
  mov    %edx,%eax
  test   $0x1,%dl
  je     L16
  mov    %edx,%ebx
  shl    $0x8,%ebx
  sar    $0x18,%ebx
  mov    %bl,%ah
  movzbl %dh,%edx
  shl    $0x10,%edx
  and    $0xff00ffff,%eax
  or     %edx,%eax
  lea    0x0(,%rax,8),%edx
  movzbl %dl,%edx
  or     %edx,%eax
  jmp    L59
L16:
  movzbl %dh,%esi
  shl    $0x10,%esi
  shr    $0x10,%eax
  shl    $0x18,%edx
  or     %esi,%eax
  or     %edx,%eax
  jmp    L59
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  char copy14;
  unsigned short copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else if (state[0UL] & 1U) {
      copy14 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy14;
      state[0UL] |= (state[0UL] & 31U) << 3UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    }
    output[0UL] = ((state[0UL] << 7U) | (state[0UL] >> 25U)) >> 3U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    %rsi,%rcx
  sub    $0x17447d68,%eax
  mov    %eax,%esi
  and    $0x1,%esi
  test   $0x8,%al
  je     L23
  test   %esi,%esi
  je     L17
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%rcx)
  ret
L23:
  movsbl %ah,%edi
  test   %esi,%esi
  jne    L19
  mov    %eax,%edx
  shr    $0x10,%eax
  rol    $0x8,%dx
  shl    $0x10,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%rcx)
  ret
  xchg   %ax,%ax
L19:
  mov    %eax,%edx
  shl    $0x8,%eax
  movzbl %dil,%edi
  sar    $0x18,%eax
  shl    $0x10,%edi
  mov    %al,%dh
  and    $0xff00ffff,%edx
  or     %edi,%edx
  lea    0x0(,%rdx,8),%eax
  movzbl %al,%eax
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%rcx)
  ret
  xchg   %ax,%ax
L17:
  push   %rbx
  mov    %eax,%esi
  mov    %eax,%ebx
  movzwl %ax,%edx
  shl    $0x10,%esi
  shl    $0x8,%ebx
  sar    $0x18,%ebx
  or     %esi,%edx
  mov    %bl,%dh
  pop    %rbx
  mov    %al,%dl
  shr    $0x18,%eax
  shl    $0x10,%eax
  and    $0xff00ffff,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  char copy14;
  unsigned short copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else if (state[0UL] & 1U) {
      copy14 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy14;
      state[0UL] |= (state[0UL] & 31U) << 3UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    }
    output[0UL] = ((state[0UL] << 7U) | (state[0UL] >> 25U)) >> 3U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    %rsi,%r8
  sub    $0x17447d68,%eax
  mov    %eax,%esi
  and    $0x1,%esi
  test   $0x8,%al
  je     L2
  test   %esi,%esi
  je     L26
  lea    0x0(,%rax,4),%edx
  and    $0x1c,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%r8)
  ret
  nopl   0x0(%rax)
L2:
  movsbl %ah,%edi
  test   %esi,%esi
  jne    L14
  mov    %eax,%edx
  shr    $0x10,%eax
  rol    $0x8,%dx
  shl    $0x10,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %eax,%edx
  shl    $0x8,%eax
  movzbl %dil,%edi
  sar    $0x18,%eax
  shl    $0x10,%edi
  mov    %al,%dh
  and    $0xff00ffff,%edx
  or     %edi,%edx
  lea    0x0(,%rdx,8),%eax
  movzbl %al,%eax
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%r8)
  ret
  nop
L26:
  mov    %eax,%esi
  movzwl %ax,%edx
  push   %rbx
  xor    %ebx,%ebx
  shl    $0x10,%esi
  mov    %al,%bl
  or     %esi,%edx
  mov    %eax,%esi
  shr    $0x18,%eax
  shl    $0x8,%esi
  shl    $0x10,%eax
  sar    $0x18,%esi
  mov    %esi,%ecx
  mov    %cl,%bh
  mov    %bx,%dx
  pop    %rbx
  and    $0xff00ffff,%edx
  or     %edx,%eax
  rol    $0x7,%eax
  shr    $0x3,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned short copy12;
  char copy13;
  char copy14;
  unsigned short copy15;
  char copy16;
  {
    state[0UL] = (input[0UL] - 51238316UL) - 339126204U;
    if ((state[0UL] >> 3U) & 1U) {
      if (state[0UL] & 1U) {
        state[0UL] |= (state[0UL] & 7U) << 2UL;
      } else {
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy13;
      }
    } else if (state[0UL] & 1U) {
      copy14 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy14;
      state[0UL] |= (state[0UL] & 31U) << 3UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
      *((char *)(&state[0UL]) + 3) = copy16;
    }
    output[0UL] = ((state[0UL] << 7U) | (state[0UL] >> 25U)) >> 3U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L15:
  mov    $0x0,%eax
  call   <insert@plt>
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L15
  mov    $0x0,%eax
  call   <display@plt>
  mov    $0x0,%eax
  call   <find_mid@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D48: Enter number of elements you want to insert in the linked list: 

tool: D28: %d

tool: D5: Number Entered: 

tool: D7: Mid Value: %d

assistant: ```c
int main() {
  int num, i, entry;
  printf("Enter number of elements you want to insert in the linked list: ");
  scanf("%d", &num);
  printf("Number Entered: \n");
  printf("%d", num);
  for (i = 0; i < num; i++) {
    insert();
  }
  display();
  printf("Mid Value: %d", find_mid());
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L15
  mov    $0x0,%ebx
L21:
  mov    $0x0,%eax
  call   <insert@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L21
L15:
  mov    $0x0,%eax
  call   <display@plt>
  mov    $0x0,%eax
  call   <find_mid@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D36
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D10: Enter number of elements you want to insert in the linked list: 

tool: D3: %d

tool: D36: Number Entered: 

tool: D16: Mid Value: %d

assistant: ```c
int main() {
  int num, i, entry;
  printf("Enter number of elements you want to insert in the linked list: ");
  scanf("%d", &num);
  printf("Number Entered: \n");
  printf("%d", num);
  for (i = 0; i < num; i++) {
    insert();
  }
  display();
  printf("Mid Value: %d", find_mid());
  return 0;
}
```