user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%rdi
  push   %r14
  push   %r13
  lea    D68(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  call   <puts@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq 0x1c(%rsp),%r14
  lea    D48(%rip),%rdi
  shl    $0x2,%r14
  lea    -0x4(%r14),%rax
  mov    %rax,0x8(%rsp)
  lea    0x0(%rbp,%rax,1),%r12
  call   <puts@plt>
  mov    0x1c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L75
  mov    %rbp,%r15
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L167:
  mov    %r15,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %ebx,0x1c(%rsp)
  jg     L167
L75:
  lea    D61(%rip),%rdi
  call   <puts@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L31
  xor    %ebx,%ebx
  lea    D31(%rip),%r13
  nopl   (%rax)
L151:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x1c(%rsp)
  jg     L151
L31:
  cmp    %rbp,%r12
  jbe    L0
  lea    -0x5(%r14),%rax
  mov    0x8(%rsp),%rbx
  mov    %rbp,%rdx
  mov    %rax,%rdi
  shr    $0x3,%rdi
  mov    %rdi,%rcx
  lea    0x1(%rdi),%rsi
  neg    %rcx
  lea    0x0(,%rsi,4),%r8
  lea    (%rbx,%rcx,4),%rcx
  cmp    %rcx,%r8
  setle  %cl
  test   %r14,%r14
  setle  %r8b
  or     %r8b,%cl
  je     L24
  cmp    $0x7,%rax
  jbe    L24
  cmp    $0x17,%rax
  jbe    L12
  mov    %rsi,%r8
  lea    -0x10(%rbp,%r14,1),%rax
  shr    $0x2,%r8
  mov    %rax,%rcx
  shl    $0x4,%r8
  sub    %r8,%rcx
  nopw   0x0(%rax,%rax,1)
L114:
  movdqa (%rdx),%xmm0
  movdqu (%rax),%xmm2
  sub    $0x10,%rax
  add    $0x10,%rdx
  pshufd $0x1b,%xmm2,%xmm1
  pshufd $0x1b,%xmm0,%xmm0
  movaps %xmm1,-0x10(%rdx)
  movups %xmm0,0x10(%rax)
  cmp    %rcx,%rax
  jne    L114
  mov    %rsi,%rdx
  and    $0xfffffffffffffffc,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    0x0(%rbp,%rcx,1),%rax
  sub    %rcx,%r12
  cmp    %rdx,%rsi
  je     L0
L14:
  sub    %rdx,%rsi
  cmp    %rdx,%rdi
  je     L139
  shl    $0x2,%rdx
  sub    $0x8,%r14
  sub    %rdx,%r14
  lea    0x0(%rbp,%rdx,1),%rcx
  mov    %rsi,%rdx
  add    %rbp,%r14
  movq   (%rcx),%xmm0
  and    $0xfffffffffffffffe,%rdx
  movq   (%r14),%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  movq   %xmm1,(%rcx)
  lea    0x0(,%rdx,4),%rcx
  movq   %xmm0,(%r14)
  add    %rcx,%rax
  sub    %rcx,%r12
  cmp    %rdx,%rsi
  je     L0
L139:
  mov    (%rax),%edx
  mov    (%r12),%ecx
  mov    %ecx,(%rax)
  mov    %edx,(%r12)
L0:
  lea    D54(%rip),%rdi
  call   <puts@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L129
  xor    %ebx,%ebx
  lea    D31(%rip),%r13
  nopl   (%rax)
L161:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x1c(%rsp)
  jg     L161
L129:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    %rbp,%rax
  nopl   0x0(%rax)
L2:
  mov    (%rax),%edx
  mov    (%r12),%ecx
  add    $0x4,%rax
  sub    $0x4,%r12
  mov    %ecx,-0x4(%rax)
  mov    %edx,0x4(%r12)
  cmp    %r12,%rax
  jb     L2
  jmp    L0
L12:
  xor    %edx,%edx
  mov    %rbp,%rax
  jmp    L14
L136:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D68
type_infered: string
name: read_data
arguments: label: D48
type_infered: string
name: read_data
arguments: label: D61
type_infered: string
name: read_data
arguments: label: D31
type_infered: string
name: read_data
arguments: label: D54
type_infered: string

tool: D16: 
Enter the no of elements in the 1st array

tool: D68: %d

tool: D48: 
Enter elements of the Array

tool: D61: 
Elements of the Array before reversing

tool: D31: %d	

tool: D54: 
Elements of the Array after reversing

assistant: ```c
int main() {
  int iaArr[10], iLen, i, iTemp;
  int *iptr1, *iptr2;
  printf("\nEnter the no of elements in the 1st array\n");
  scanf("%d", &iLen);
  iptr1 = iaArr;
  iptr2 = (iaArr + iLen - 1);
  printf("\nEnter elements of the Array\n");
  for (i = 0; i < iLen; i++)
    scanf("%d", (iptr1 + i));
  printf("\nElements of the Array before reversing\n");
  for (i = 0; i < iLen; i++)
    printf("%d\t", *(iptr1 + i));
  while (iptr1 < iptr2) {
    iTemp = *iptr1;
    *iptr1 = *iptr2;
    *iptr2 = iTemp;
    iptr1++;
    iptr2--;
  }
  iptr1 = iaArr;
  printf("\nElements of the Array after reversing\n");
  for (i = 0; i < iLen; i++)
    printf("%d\t", *(iptr1 + i));
  return 0;
}
```