user: Translate the below assembly code into C programming language:

```asm
<Fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L64
L33:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L63:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L48
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L48
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L92
L48:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0x8(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L92
  mov    -0xc(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L63
L92:
  mov    -0x8(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x38(%rbp)
  jl     L123
  mov    -0x8(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L46
L155:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L7
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L122
L7:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L78
L122:
  subl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L155
L78:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L77
L123:
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L77:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L65
L6:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L65:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L6
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
L64:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Fold(char s[], char d[], const int linelen, int len) {
  int i, j, k;
  int breakpoint, dp;
  breakpoint = dp = 0;
  while (s[breakpoint] != '\0') {
    for (k = breakpoint; k < breakpoint + linelen && k < len; k++) {
      if (s[k] != ' ' && s[k] != '\t') {
        breakpoint = k;
        break;
      }
    }
    if (len >= breakpoint + linelen) {
      for (i = j = breakpoint + linelen; i >= breakpoint; i--) {
        if (s[i] == ' ' || s[i] == '\t') {
          j = i;
          break;
        }
      }
      breakpoint = j;
    } else {
      breakpoint = len;
    }
    for (i = k; i < breakpoint; i++, dp++) {
      d[dp] = s[i];
    }
    d[dp++] = '\n';
  }
  d[dp - 1] = '\0';
}
```