ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<mkrep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <copysingl@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L38
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dupmachine@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <mkclos@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L30
L38:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <mkstate@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L23
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dupmachine@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <mkopt@plt>
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mkrep(mach, lb, ub)
int mach, lb, ub;
{
  int base, tail, copy, i;
  base = copysingl(mach, lb - 1);
  if (ub == -1) {
    copy = dupmachine(mach);
    mach = link_machines(mach, link_machines(base, mkclos(copy)));
  } else {
    tail = mkstate(0);
    for (i = lb; i < ub; ++i) {
      copy = dupmachine(mach);
      tail = mkopt(link_machines(copy, tail));
    }
    mach = link_machines(mach, link_machines(base, tail));
  }
  return (mach);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkrep>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%r13d
  lea    -0x1(%rsi),%esi
  mov    $0x0,%eax
  call   <copysingl@plt>
  mov    %eax,%r14d
  cmp    $0xffffffff,%r13d
  je     L34
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <mkstate@plt>
  mov    %eax,%ebx
  cmp    %r13d,%ebp
  jge    L23
L31:
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <dupmachine@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <mkopt@plt>
  mov    %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L31
L23:
  mov    %ebx,%esi
  mov    %r14d,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%esi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <dupmachine@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <mkclos@plt>
  mov    %eax,%esi
  mov    %r14d,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  mov    %eax,%esi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <link_machines@plt>
  jmp    L6
```

assistant: ```c
int mkrep(mach, lb, ub)
int mach, lb, ub;
{
  int base, tail, copy, i;
  base = copysingl(mach, lb - 1);
  if (ub == -1) {
    copy = dupmachine(mach);
    mach = link_machines(mach, link_machines(base, mkclos(copy)));
  } else {
    tail = mkstate(0);
    for (i = lb; i < ub; ++i) {
      copy = dupmachine(mach);
      tail = mkopt(link_machines(copy, tail));
    }
    mach = link_machines(mach, link_machines(base, tail));
  }
  return (mach);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mkrep>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %esi,%r14d
  sub    $0x1,%esi
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <copysingl@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%ebx
  je     L6
  xor    %edi,%edi
  xor    %eax,%eax
  call   <mkstate@plt>
  mov    %eax,%ebp
  cmp    %ebx,%r14d
  jge    L30
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r12d,%edi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <dupmachine@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  xor    %eax,%eax
  call   <link_machines@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <mkopt@plt>
  mov    %eax,%ebp
  cmp    %r14d,%ebx
  jne    L3
L30:
  mov    %ebp,%esi
L24:
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <link_machines@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  xor    %eax,%eax
  pop    %r13
  pop    %r14
  jmp    10e0 <link_machines@plt>
  nopl   0x0(%rax)
L6:
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <dupmachine@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <mkclos@plt>
  mov    %eax,%esi
  jmp    L24
```

assistant: ```c
int mkrep(mach, lb, ub)
int mach, lb, ub;
{
  int base, tail, copy, i;
  base = copysingl(mach, lb - 1);
  if (ub == -1) {
    copy = dupmachine(mach);
    mach = link_machines(mach, link_machines(base, mkclos(copy)));
  } else {
    tail = mkstate(0);
    for (i = lb; i < ub; ++i) {
      copy = dupmachine(mach);
      tail = mkopt(link_machines(copy, tail));
    }
    mach = link_machines(mach, link_machines(base, tail));
  }
  return (mach);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mkrep>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %esi,%r14d
  sub    $0x1,%esi
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <copysingl@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%ebx
  je     L27
  xor    %edi,%edi
  xor    %eax,%eax
  call   <mkstate@plt>
  mov    %eax,%ebp
  cmp    %ebx,%r14d
  jge    L14
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %r12d,%edi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <dupmachine@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  xor    %eax,%eax
  call   <link_machines@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <mkopt@plt>
  mov    %eax,%ebp
  cmp    %r14d,%ebx
  jne    L26
L14:
  mov    %ebp,%esi
L18:
  mov    %r13d,%edi
  xor    %eax,%eax
  call   <link_machines@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  xor    %eax,%eax
  pop    %r13
  pop    %r14
  jmp    10e0 <link_machines@plt>
  nopl   0x0(%rax)
L27:
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <dupmachine@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <mkclos@plt>
  mov    %eax,%esi
  jmp    L18
```

assistant: ```c
int mkrep(mach, lb, ub)
int mach, lb, ub;
{
  int base, tail, copy, i;
  base = copysingl(mach, lb - 1);
  if (ub == -1) {
    copy = dupmachine(mach);
    mach = link_machines(mach, link_machines(base, mkclos(copy)));
  } else {
    tail = mkstate(0);
    for (i = lb; i < ub; ++i) {
      copy = dupmachine(mach);
      tail = mkopt(link_machines(copy, tail));
    }
    mach = link_machines(mach, link_machines(base, tail));
  }
  return (mach);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CubicEaseOut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  D16(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  D16(%rip),%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
datatype: f32

tool: D16: 1

assistant: ```c
float CubicEaseOut(float p) {
  float f = (p - 1);
  return f * f * f + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CubicEaseOut>:
  endbr64
  movss  D7(%rip),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: f32

tool: D7: 1

assistant: ```c
float CubicEaseOut(float p) {
  float f = (p - 1);
  return f * f * f + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CubicEaseOut>:
  endbr64
  movss  D7(%rip),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: f32

tool: D7: 1

assistant: ```c
float CubicEaseOut(float p) {
  float f = (p - 1);
  return f * f * f + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CubicEaseOut>:
  endbr64
  movss  D9(%rip),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: f32

tool: D9: 1

assistant: ```c
float CubicEaseOut(float p) {
  float f = (p - 1);
  return f * f * f + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  cmpq   $0x0,-0x10(%rbp)
  jne    L24
  mov    $0x0,%eax
  call   <fork_procs@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L24:
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <show_pstree@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <explain_wait_status@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: main: fork

assistant: ```c
int main(void) {
  pid_t pid;
  int status;
  pid = fork();
  if (pid < 0) {
    perror("main: fork");
    exit(1);
  }
  if (pid == 0) {
    fork_procs();
    exit(1);
  }
  sleep(3);
  show_pstree(pid);
  pid = wait(&status);
  explain_wait_status(pid, status);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L44
  je     L14
L2:
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <show_pstree@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    %rax,%rdi
  mov    0x4(%rsp),%esi
  call   <explain_wait_status@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L44:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L14:
  mov    $0x0,%eax
  call   <fork_procs@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: main: fork

assistant: ```c
int main(void) {
  pid_t pid;
  int status;
  pid = fork();
  if (pid < 0) {
    perror("main: fork");
    exit(1);
  }
  if (pid == 0) {
    fork_procs();
    exit(1);
  }
  sleep(3);
  show_pstree(pid);
  pid = wait(&status);
  explain_wait_status(pid, status);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  js     L40
  je     L11
L8:
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <show_pstree@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  call   <explain_wait_status@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  call   <fork_procs@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
L40:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: main: fork

assistant: ```c
int main(void) {
  pid_t pid;
  int status;
  pid = fork();
  if (pid < 0) {
    perror("main: fork");
    exit(1);
  }
  if (pid == 0) {
    fork_procs();
    exit(1);
  }
  sleep(3);
  show_pstree(pid);
  pid = wait(&status);
  explain_wait_status(pid, status);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  js     L10
  je     L22
L25:
  mov    $0x3,%edi
  call   <sleep@plt>
  mov    %rbp,%rdi
  call   <show_pstree@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  call   <explain_wait_status@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L22:
  xor    %eax,%eax
  call   <fork_procs@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L25
L10:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L25
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: main: fork

assistant: ```c
int main(void) {
  pid_t pid;
  int status;
  pid = fork();
  if (pid < 0) {
    perror("main: fork");
    exit(1);
  }
  if (pid == 0) {
    fork_procs();
    exit(1);
  }
  sleep(3);
  show_pstree(pid);
  pid = wait(&status);
  explain_wait_status(pid, status);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %rdi,-0x1b8(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %rdx,-0x1c8(%rbp)
  mov    %ecx,-0x1cc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a4(%rbp)
  jmp    L11
L36:
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1c0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    $0x9,%eax
  jle    L13
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x1c8(%rbp),%rax
  add    %rcx,%rax
  sub    $0xa,%edx
  mov    %edx,(%rax)
  mov    -0x1a4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1cc(%rbp),%eax
  sub    %edx,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x1cc(%rbp),%eax
  sub    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x1c8(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L18
L13:
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x1cc(%rbp),%eax
  sub    -0x1a4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1c8(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
L18:
  addl   $0x1,-0x1a4(%rbp)
L11:
  mov    -0x1a4(%rbp),%eax
  cmp    -0x1cc(%rbp),%eax
  jle    L36
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int adder(int inp1[], int inp2[], int result[], int max) {
  int s[100], i;
  for (i = 0; i <= max; ++i) {
    s[max - i] = inp1[max - i] + inp2[max - i];
    if (s[i] >= 10) {
      result[max - i] = s[max - i] - 10;
      result[max - (i + 1)] = s[max - (i + 1)] + 1;
    } else {
      result[max - i] = s[max - i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adder>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  js     L4
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %rdx,%r8
  mov    %rsp,%rdi
  lea    -0x1(%rcx),%esi
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rax
  jmp    L43
L33:
  mov    %edx,(%r8,%rax,1)
L6:
  add    $0x4,%rdi
  sub    $0x1,%esi
  sub    $0x4,%rax
  cmp    $0xfffffffe,%esi
  je     L4
L43:
  mov    (%r10,%rax,1),%edx
  add    (%r9,%rax,1),%edx
  mov    %edx,(%rsp,%rax,1)
  cmpl   $0x9,(%rdi)
  jle    L33
  sub    $0xa,%edx
  mov    %edx,(%r8,%rax,1)
  movslq %esi,%rcx
  mov    (%rsp,%rcx,4),%edx
  add    $0x1,%edx
  mov    %edx,(%r8,%rcx,4)
  jmp    L6
L4:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int adder(int inp1[], int inp2[], int result[], int max) {
  int s[100], i;
  for (i = 0; i <= max; ++i) {
    s[max - i] = inp1[max - i] + inp2[max - i];
    if (s[i] >= 10) {
      result[max - i] = s[max - i] - 10;
      result[max - (i + 1)] = s[max - (i + 1)] + 1;
    } else {
      result[max - i] = s[max - i];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adder>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  js     L54
  mov    %rsi,%r10
  mov    %rsp,%r11
  lea    -0x1(%rcx),%esi
  movslq %ecx,%rcx
  mov    %rdi,%r9
  mov    %rdx,%r8
  mov    %r11,%rdi
  lea    0x0(,%rcx,4),%rax
  jmp    L44
  nopl   0x0(%rax)
L32:
  movslq %esi,%rcx
  sub    $0xa,%edx
  sub    $0x1,%esi
  add    $0x4,%rdi
  mov    %edx,(%r8,%rax,1)
  mov    (%rsp,%rcx,4),%edx
  sub    $0x4,%rax
  add    $0x1,%edx
  mov    %edx,(%r8,%rcx,4)
  cmp    $0xfffffffe,%esi
  je     L54
L44:
  mov    (%r10,%rax,1),%edx
  add    (%r9,%rax,1),%edx
  mov    %edx,(%r11,%rax,1)
  cmpl   $0x9,(%rdi)
  jg     L32
  sub    $0x1,%esi
  mov    %edx,(%r8,%rax,1)
  add    $0x4,%rdi
  sub    $0x4,%rax
  cmp    $0xfffffffe,%esi
  jne    L44
L54:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int adder(int inp1[], int inp2[], int result[], int max) {
  int s[100], i;
  for (i = 0; i <= max; ++i) {
    s[max - i] = inp1[max - i] + inp2[max - i];
    if (s[i] >= 10) {
      result[max - i] = s[max - i] - 10;
      result[max - (i + 1)] = s[max - (i + 1)] + 1;
    } else {
      result[max - i] = s[max - i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<adder>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  js     L27
  mov    %rsi,%r10
  mov    %rsp,%r11
  lea    -0x1(%rcx),%esi
  movslq %ecx,%rcx
  mov    %rdi,%r9
  mov    %rdx,%r8
  mov    %r11,%rdi
  lea    0x0(,%rcx,4),%rax
  jmp    L57
  nopl   0x0(%rax)
L8:
  movslq %esi,%rcx
  sub    $0xa,%edx
  sub    $0x1,%esi
  add    $0x4,%rdi
  mov    %edx,(%r8,%rax,1)
  mov    (%rsp,%rcx,4),%edx
  sub    $0x4,%rax
  add    $0x1,%edx
  mov    %edx,(%r8,%rcx,4)
  cmp    $0xfffffffe,%esi
  je     L27
L57:
  mov    (%r10,%rax,1),%edx
  add    (%r9,%rax,1),%edx
  mov    %edx,(%r11,%rax,1)
  cmpl   $0x9,(%rdi)
  jg     L8
  sub    $0x1,%esi
  mov    %edx,(%r8,%rax,1)
  add    $0x4,%rdi
  sub    $0x4,%rax
  cmp    $0xfffffffe,%esi
  jne    L57
L27:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int adder(int inp1[], int inp2[], int result[], int max) {
  int s[100], i;
  for (i = 0; i <= max; ++i) {
    s[max - i] = inp1[max - i] + inp2[max - i];
    if (s[i] >= 10) {
      result[max - i] = s[max - i] - 10;
      result[max - (i + 1)] = s[max - (i + 1)] + 1;
    } else {
      result[max - i] = s[max - i];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<repeat_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%eax
  add    %eax,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void repeat_mem(void *dst, const int len, void *block, int block_len) {
  const int n_blocks = len / block_len;
  const int last_block_len = len - n_blocks * block_len;
  int offset;
  for (offset = 0; offset < len; offset += block_len) {
    memcpy((char *)dst + offset, block, block_len);
  }
  memcpy((char *)dst + len - last_block_len, block, last_block_len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<repeat_mem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%r13d
  mov    %rdx,%r14
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L4
  mov    %ecx,%r12d
  movslq %ecx,%r15
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L1:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    %r12d,%ebx
  add    %r15,%rbp
  cmp    %ebx,%r13d
  jg     L1
L4:
  movslq %r13d,%r13
  mov    0xc(%rsp),%edx
  movslq %edx,%rax
  sub    %rax,%r13
  mov    (%rsp),%rdi
  add    %r13,%rdi
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void repeat_mem(void *dst, const int len, void *block, int block_len) {
  const int n_blocks = len / block_len;
  const int last_block_len = len - n_blocks * block_len;
  int offset;
  for (offset = 0; offset < len; offset += block_len) {
    memcpy((char *)dst + offset, block, block_len);
  }
  memcpy((char *)dst + len - last_block_len, block, last_block_len);
}
```