ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<memcopy>:
  endbr64
  mov    %rdi,%rcx
  lea    -0x1(%rdx),%r10d
  test   %edx,%edx
  je     L130
  lea    0x1(%rdi),%rdi
  mov    %rsi,%rax
  sub    %rdi,%rax
  cmp    $0xe,%rax
  jbe    L19
  cmp    $0x6,%r10d
  jbe    L19
  cmp    $0xe,%r10d
  jbe    L67
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L34:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L34
  mov    %edx,%r9d
  and    $0xfffffff0,%r9d
  mov    %r9d,%r8d
  sub    %r9d,%r10d
  lea    (%rcx,%r8,1),%rdi
  lea    (%rsi,%r8,1),%rax
  cmp    %r9d,%edx
  je     L130
  sub    %r9d,%edx
  lea    -0x1(%rdx),%r9d
  cmp    $0x6,%r9d
  jbe    L31
L9:
  mov    (%rcx,%r8,1),%rcx
  mov    %rcx,(%rsi,%r8,1)
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  sub    %ecx,%r10d
  add    %rsi,%rdi
  add    %rsi,%rax
  cmp    %ecx,%edx
  je     L130
L31:
  movzbl (%rdi),%edx
  mov    %dl,(%rax)
  test   %r10d,%r10d
  je     L130
  movzbl 0x1(%rdi),%edx
  mov    %dl,0x1(%rax)
  cmp    $0x1,%r10d
  je     L130
  movzbl 0x2(%rdi),%edx
  mov    %dl,0x2(%rax)
  cmp    $0x2,%r10d
  je     L130
  movzbl 0x3(%rdi),%edx
  mov    %dl,0x3(%rax)
  cmp    $0x3,%r10d
  je     L130
  movzbl 0x4(%rdi),%edx
  mov    %dl,0x4(%rax)
  cmp    $0x4,%r10d
  je     L130
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x5(%rax)
  cmp    $0x5,%r10d
  je     L130
  movzbl 0x6(%rdi),%edx
  mov    %dl,0x6(%rax)
  ret
  nopl   0x0(%rax)
L19:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L99:
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L99
L130:
  ret
L67:
  mov    %rsi,%rax
  mov    %rcx,%rdi
  xor    %r8d,%r8d
  jmp    L9
```

assistant: ```c
void memcopy(void *from, void *to, unsigned nbytes) {
  unsigned char *src = (unsigned char *)from;
  unsigned char *dst = (unsigned char *)to;
  while (nbytes-- > 0)
    *dst++ = *src++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D17: %d =>

tool: D11: %d


assistant: ```c
void func(int *arg1) {
  printf("%d =>", arg1);
  printf("%d\n", *arg1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string

tool: D5: %d =>

tool: D11: %d


assistant: ```c
void func(int *arg1) {
  printf("%d =>", arg1);
  printf("%d\n", *arg1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D16: %d =>

tool: D6: %d


assistant: ```c
void func(int *arg1) {
  printf("%d =>", arg1);
  printf("%d\n", *arg1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<func>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string

tool: D14: %d =>

tool: D18: %d


assistant: ```c
void func(int *arg1) {
  printf("%d =>", arg1);
  printf("%d\n", *arg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xqueue_item_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int xqueue_item_destroy(struct xqueue_item *item) {
  free(item);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xqueue_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int xqueue_item_destroy(struct xqueue_item *item) {
  free(item);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xqueue_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int xqueue_item_destroy(struct xqueue_item *item) {
  free(item);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xqueue_item_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int xqueue_item_destroy(struct xqueue_item *item) {
  free(item);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xopen2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int xopen2(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    ;
  }
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xopen2>:
  endbr64
  sub    $0x8,%rsp
  call   <open@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int xopen2(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    ;
  }
  return fd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xopen2>:
  endbr64
  jmp    1050 <open@plt>
```

assistant: ```c
int xopen2(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    ;
  }
  return fd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xopen2>:
  endbr64
  jmp    1050 <open@plt>
```

assistant: ```c
int xopen2(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    ;
  }
  return fd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<doubles_xyzrpy_to_mat44>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <doubles_rpy_to_mat44@plt>
  mov    -0x10(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x38,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x58,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void doubles_xyzrpy_to_mat44(const double xyzrpy[6], double M[16]) {
  doubles_rpy_to_mat44(&xyzrpy[3], M);
  M[3] = xyzrpy[0];
  M[7] = xyzrpy[1];
  M[11] = xyzrpy[2];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<doubles_xyzrpy_to_mat44>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x18(%rdi),%rdi
  call   <doubles_rpy_to_mat44@plt>
  movsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x18(%rbx)
  movsd  0x8(%rbp),%xmm0
  movsd  %xmm0,0x38(%rbx)
  movsd  0x10(%rbp),%xmm0
  movsd  %xmm0,0x58(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void doubles_xyzrpy_to_mat44(const double xyzrpy[6], double M[16]) {
  doubles_rpy_to_mat44(&xyzrpy[3], M);
  M[3] = xyzrpy[0];
  M[7] = xyzrpy[1];
  M[11] = xyzrpy[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<doubles_xyzrpy_to_mat44>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x18(%rdi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <doubles_rpy_to_mat44@plt>
  movsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x18(%rbx)
  movsd  0x8(%rbp),%xmm0
  movsd  %xmm0,0x38(%rbx)
  movsd  0x10(%rbp),%xmm0
  movsd  %xmm0,0x58(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void doubles_xyzrpy_to_mat44(const double xyzrpy[6], double M[16]) {
  doubles_rpy_to_mat44(&xyzrpy[3], M);
  M[3] = xyzrpy[0];
  M[7] = xyzrpy[1];
  M[11] = xyzrpy[2];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<doubles_xyzrpy_to_mat44>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x18(%rdi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <doubles_rpy_to_mat44@plt>
  movsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x18(%rbx)
  movsd  0x8(%rbp),%xmm0
  movsd  %xmm0,0x38(%rbx)
  movsd  0x10(%rbp),%xmm0
  movsd  %xmm0,0x58(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void doubles_xyzrpy_to_mat44(const double xyzrpy[6], double M[16]) {
  doubles_rpy_to_mat44(&xyzrpy[3], M);
  M[3] = xyzrpy[0];
  M[7] = xyzrpy[1];
  M[11] = xyzrpy[2];
}
```
user: What is the c source code of the assembly code below:

```asm
<putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L7
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L6
L11:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L11
L6:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L17:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L17
L9:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
L1:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L16:
  pop    %rbx
  ret
```

assistant: ```c
void putstr(const char *s) {
  while (*s) {
    putchar(*s);
    s++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<process_teid_rate_limiter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %rdi,-0x168(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rdi
  lea    -0xe0(%rbp),%rsi
  lea    -0x150(%rbp),%rcx
  lea    -0x158(%rbp),%rdx
  mov    -0x168(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x154(%rbp)
  cmpl   $0x4,-0x154(%rbp)
  je     L15
  mov    $0xffffffff,%eax
  jmp    L13
L15:
  mov    -0x158(%rbp),%eax
  lea    -0x70(%rbp),%rcx
  lea    -0xe0(%rbp),%rdx
  lea    -0x150(%rbp),%rsi
  mov    %eax,%edi
  call   <fill_teid_rate_limiter_table@plt>
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %*s %d %s %s %s

assistant: ```c
int process_teid_rate_limiter(const char *line) {
  uint32_t teid;
  char table_name[100];
  char header_name[100];
  char teid_mode[100];
  int matches = sscanf(line, "%*s %d %s %s %s", &teid, table_name, header_name, teid_mode);
  if (4 != matches)
    return -1;
  return fill_teid_rate_limiter_table(teid, table_name, header_name, teid_mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<process_teid_rate_limiter>:
  endbr64
  sub    $0x168,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0xf0(%rsp),%r9
  lea    0x80(%rsp),%r8
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x4,%eax
  jne    L24
  lea    0xf0(%rsp),%rcx
  lea    0x80(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    0xc(%rsp),%edi
  call   <fill_teid_rate_limiter_table@plt>
L28:
  mov    0x158(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x168,%rsp
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L28
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: %*s %d %s %s %s

assistant: ```c
int process_teid_rate_limiter(const char *line) {
  uint32_t teid;
  char table_name[100];
  char header_name[100];
  char teid_mode[100];
  int matches = sscanf(line, "%*s %d %s %s %s", &teid, table_name, header_name, teid_mode);
  if (4 != matches)
    return -1;
  return fill_teid_rate_limiter_table(teid, table_name, header_name, teid_mode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_teid_rate_limiter>:
  endbr64
  push   %r13
  lea    D9(%rip),%rsi
  push   %r12
  push   %rbp
  sub    $0x160,%rsp
  lea    0xf0(%rsp),%r13
  lea    0x80(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rdx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rcx
  call   <sscanf@plt>
  cmp    $0x4,%eax
  jne    L17
  mov    0xc(%rsp),%edi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <fill_teid_rate_limiter_table@plt>
L22:
  mov    0x158(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x160,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%eax
  jmp    L22
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: %*s %d %s %s %s

assistant: ```c
int process_teid_rate_limiter(const char *line) {
  uint32_t teid;
  char table_name[100];
  char header_name[100];
  char teid_mode[100];
  int matches = sscanf(line, "%*s %d %s %s %s", &teid, table_name, header_name, teid_mode);
  if (4 != matches)
    return -1;
  return fill_teid_rate_limiter_table(teid, table_name, header_name, teid_mode);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<process_teid_rate_limiter>:
  endbr64
  push   %r13
  lea    D2(%rip),%rsi
  push   %r12
  push   %rbp
  sub    $0x160,%rsp
  lea    0xf0(%rsp),%r13
  lea    0x80(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rdx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rcx
  call   <sscanf@plt>
  cmp    $0x4,%eax
  jne    L28
  mov    0xc(%rsp),%edi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <fill_teid_rate_limiter_table@plt>
L19:
  mov    0x158(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x160,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xffffffff,%eax
  jmp    L19
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: %*s %d %s %s %s

assistant: ```c
int process_teid_rate_limiter(const char *line) {
  uint32_t teid;
  char table_name[100];
  char header_name[100];
  char teid_mode[100];
  int matches = sscanf(line, "%*s %d %s %s %s", &teid, table_name, header_name, teid_mode);
  if (4 != matches)
    return -1;
  return fill_teid_rate_limiter_table(teid, table_name, header_name, teid_mode);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L42:
  lea    -0x400(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x400(%rbp),%eax
  cmp    $0x30,%al
  jne    L58
  movzbl -0x3ff(%rbp),%eax
  test   %al,%al
  je     L38
L58:
  movl   $0x0,-0x408(%rbp)
  movl   $0x0,-0x404(%rbp)
  jmp    L6
L24:
  mov    -0x404(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0x408(%rbp)
  addl   $0x1,-0x404(%rbp)
L6:
  mov    -0x404(%rbp),%eax
  cltq
  movzbl -0x400(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L24
  mov    -0x408(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L42
L38:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D1
type: string

tool: D14: %s

tool: D1: %d


assistant: ```c
int main(void) {
  int x, sum, i;
  char string[1001];
  while (1) {
    scanf("%s", string);
    if (string[0] == '0' && string[1] == '\0')
      break;
    sum = 0, i = 0;
    while (string[i] != '\0') {
      sum += string[i] - '0';
      i++;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D4(%rip),%rbx
  lea    D6(%rip),%r12
  jmp    L37
L13:
  cmpb   $0x0,0x1(%rsp)
  je     L14
L3:
  lea    0x1(%rsp),%rdx
  mov    $0x0,%esi
L27:
  movsbl %al,%eax
  lea    -0x30(%rsi,%rax,1),%esi
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L27
L60:
  mov    %r12,%rdi
  call   <printf@plt>
L37:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  cmp    $0x30,%al
  je     L13
  mov    $0x0,%esi
  test   %al,%al
  jne    L3
  jmp    L60
L14:
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D4: %s

tool: D6: %d


assistant: ```c
int main(void) {
  int x, sum, i;
  char string[1001];
  while (1) {
    scanf("%s", string);
    if (string[0] == '0' && string[1] == '\0')
      break;
    sum = 0, i = 0;
    while (string[i] != '\0') {
      sum += string[i] - '0';
      i++;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D16(%rip),%rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsbl (%rsp),%eax
  cmp    $0x30,%al
  je     L22
  test   %al,%al
  je     L18
  movzbl 0x1(%rsp),%edx
L12:
  lea    0x2(%rsp),%rcx
  xor    %esi,%esi
  jmp    L71
  nopl   (%rax)
L49:
  movzbl (%rcx),%edi
  movsbl %dl,%eax
  add    $0x1,%rcx
  mov    %edi,%edx
L71:
  lea    -0x30(%rsi,%rax,1),%esi
  test   %dl,%dl
  jne    L49
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L15
  xchg   %ax,%ax
L22:
  movzbl 0x1(%rsp),%edx
  test   %dl,%dl
  jne    L12
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: D12: %d


tool: D16: %s

assistant: ```c
int main(void) {
  int x, sum, i;
  char string[1001];
  while (1) {
    scanf("%s", string);
    if (string[0] == '0' && string[1] == '\0')
      break;
    sum = 0, i = 0;
    while (string[i] != '\0') {
      sum += string[i] - '0';
      i++;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsbl (%rsp),%eax
  cmp    $0x30,%al
  je     L16
  xor    %esi,%esi
  test   %al,%al
  je     L11
L18:
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rdx
  lea    -0x30(%rsi,%rax,1),%esi
  movsbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L43
L11:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L16:
  cmpb   $0x0,0x1(%rsp)
  jne    L18
  mov    0x3f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x400,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_guessed: string
name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D19: %d


tool: D2: %s

assistant: ```c
int main(void) {
  int x, sum, i;
  char string[1001];
  while (1) {
    scanf("%s", string);
    if (string[0] == '0' && string[1] == '\0')
      break;
    sum = 0, i = 0;
    while (string[i] != '\0') {
      sum += string[i] - '0';
      i++;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L21
L33:
  cmpl   $0x0,-0x4(%rbp)
  jns    L28
  subl   $0x1,-0x4(%rbp)
  jmp    L21
L28:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    $0x9,%eax
  jg     L33
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  i = __VERIFIER_nondet_int();
  while (i * i > 9) {
    if (i < 0) {
      i = i - 1;
    } else {
      i = i + 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jle    L11
L12:
  lea    -0x1(%rax),%edx
  lea    0x1(%rax),%ecx
  test   %eax,%eax
  mov    %edx,%eax
  cmovns %ecx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    $0x9,%edx
  jg     L12
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  i = __VERIFIER_nondet_int();
  while (i * i > 9) {
    if (i < 0) {
      i = i - 1;
    } else {
      i = i + 1;
    }
  }
  return 0;
}
```