ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str2buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L27
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <realloc_buf@plt>
  test   %rax,%rax
  je     L27
  mov    $0xffffffff,%eax
  jmp    L25
L27:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int str2buffer(unsigned char **buf, int *buf_len, int *pos, char *data, int data_len) {
  if (*buf_len < data_len) {
    if (realloc_buf(buf, buf_len, data_len) != 0) {
      return -1;
    }
  }
  memcpy(&(*buf)[*pos], data, data_len);
  *pos += data_len;
  *buf_len -= data_len;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str2buffer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r14
  mov    %r8d,%ebx
  cmp    %r8d,(%rsi)
  jge    L26
  mov    %r8d,%edx
  call   <realloc_buf@plt>
  test   %rax,%rax
  jne    L23
L26:
  movslq (%r12),%rdi
  add    0x0(%r13),%rdi
  mov    %ebx,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    %ebx,(%r12)
  sub    %ebx,0x0(%rbp)
  mov    $0x0,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int str2buffer(unsigned char **buf, int *buf_len, int *pos, char *data, int data_len) {
  if (*buf_len < data_len) {
    if (realloc_buf(buf, buf_len, data_len) != 0) {
      return -1;
    }
  }
  memcpy(&(*buf)[*pos], data, data_len);
  *pos += data_len;
  *buf_len -= data_len;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str2buffer>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  cmp    %r8d,(%rsi)
  jge    L26
  mov    %r8d,%edx
  call   <realloc_buf@plt>
  test   %rax,%rax
  jne    L6
L26:
  movslq (%r12),%rdi
  mov    %ebx,%edx
  add    (%r14),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    %ebx,(%r12)
  xor    %eax,%eax
  sub    %ebx,0x0(%rbp)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int str2buffer(unsigned char **buf, int *buf_len, int *pos, char *data, int data_len) {
  if (*buf_len < data_len) {
    if (realloc_buf(buf, buf_len, data_len) != 0) {
      return -1;
    }
  }
  memcpy(&(*buf)[*pos], data, data_len);
  *pos += data_len;
  *buf_len -= data_len;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2buffer>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  cmp    %r8d,(%rsi)
  jge    L13
  mov    %r8d,%edx
  call   <realloc_buf@plt>
  test   %rax,%rax
  jne    L28
L13:
  movslq (%r12),%rdi
  mov    %ebx,%edx
  add    (%r14),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    %ebx,(%r12)
  xor    %eax,%eax
  sub    %ebx,0x0(%rbp)
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int str2buffer(unsigned char **buf, int *buf_len, int *pos, char *data, int data_len) {
  if (*buf_len < data_len) {
    if (realloc_buf(buf, buf_len, data_len) != 0) {
      return -1;
    }
  }
  memcpy(&(*buf)[*pos], data, data_len);
  *pos += data_len;
  *buf_len -= data_len;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<presum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  ja     L63
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x357,%eax
  jmp    L63
  mov    $0x3138,%eax
  jmp    L63
  mov    $0x28a64,%eax
  jmp    L63
  mov    $0x1f95f0,%eax
  jmp    L63
  mov    $0x179a7b0,%eax
  jmp    L63
  mov    $0x112a8800,%eax
  jmp    L63
  mov    $0xc3cd1f40,%eax
  jmp    L63
  movabs $0x897695100,%rax
  jmp    L63
L63:
  pop    %rbp
  ret
```

assistant: ```c
long long int presum(int a) {
  switch (a) {
  case 2:
    return 855;
  case 3:
    return 12600;
  case 4:
    return 166500;
  case 5:
    return 2070000;
  case 6:
    return 24750000;
  case 7:
    return 288000000;
  case 8:
    return 3285000000;
  case 9:
    return 36900000000;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<presum>:
  endbr64
  cmp    $0x9,%edi
  ja     L8
  mov    %edi,%edi
  lea    D5(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x3138,%eax
  ret
  mov    $0x1f95f0,%eax
  ret
  mov    $0x179a7b0,%eax
  ret
  mov    $0x112a8800,%eax
  ret
  mov    $0xc3cd1f40,%eax
  ret
  movabs $0x897695100,%rax
  ret
L8:
  ret
  mov    $0x357,%eax
  ret
  mov    $0x28a64,%eax
  ret
```

assistant: ```c
long long int presum(int a) {
  switch (a) {
  case 2:
    return 855;
  case 3:
    return 12600;
  case 4:
    return 166500;
  case 5:
    return 2070000;
  case 6:
    return 24750000;
  case 7:
    return 288000000;
  case 8:
    return 3285000000;
  case 9:
    return 36900000000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<presum>:
  endbr64
  sub    $0x2,%edi
  cmp    $0x7,%edi
  ja     L5
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: W

assistant: ```c
long long int presum(int a) {
  switch (a) {
  case 2:
    return 855;
  case 3:
    return 12600;
  case 4:
    return 166500;
  case 5:
    return 2070000;
  case 6:
    return 24750000;
  case 7:
    return 288000000;
  case 8:
    return 3285000000;
  case 9:
    return 36900000000;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<presum>:
  endbr64
  sub    $0x2,%edi
  cmp    $0x7,%edi
  ja     L9
  lea    D1(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: W

assistant: ```c
long long int presum(int a) {
  switch (a) {
  case 2:
    return 855;
  case 3:
    return 12600;
  case 4:
    return 166500;
  case 5:
    return 2070000;
  case 6:
    return 24750000;
  case 7:
    return 288000000;
  case 8:
    return 3285000000;
  case 9:
    return 36900000000;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cert_add_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <X509V3_set_ctx_nodb@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <X509V3_set_ctx@plt>
  mov    -0x40(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <X509V3_EXT_conf_nid@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L27
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  jmp    L17
L27:
  mov    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <X509_add_ext@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <X509_EXTENSION_free@plt>
  mov    $0x1,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int cert_add_ext(X509 *issuer, X509 *subject, int nid, char *value) {
  X509_EXTENSION *ex;
  X509V3_CTX ctx;
  X509V3_set_ctx_nodb(&ctx);
  X509V3_set_ctx(&ctx, issuer, subject, NULL, NULL, 0);
  ex = X509V3_EXT_conf_nid(NULL, &ctx, nid, value);
  if (!ex) {
    ERR_print_errors_fp(stdout);
    return 0;
  }
  X509_add_ext(subject, ex, -1);
  X509_EXTENSION_free(ex);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cert_add_ext>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <X509V3_set_ctx_nodb@plt>
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <X509V3_set_ctx@plt>
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <X509V3_EXT_conf_nid@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  mov    $0xffffffff,%edx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <X509_add_ext@plt>
  mov    %rbx,%rdi
  call   <X509_EXTENSION_free@plt>
  mov    $0x1,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cert_add_ext(X509 *issuer, X509 *subject, int nid, char *value) {
  X509_EXTENSION *ex;
  X509V3_CTX ctx;
  X509V3_set_ctx_nodb(&ctx);
  X509V3_set_ctx(&ctx, issuer, subject, NULL, NULL, 0);
  ex = X509V3_EXT_conf_nid(NULL, &ctx, nid, value);
  if (!ex) {
    ERR_print_errors_fp(stdout);
    return 0;
  }
  X509_add_ext(subject, ex, -1);
  X509_EXTENSION_free(ex);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cert_add_ext>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <X509V3_set_ctx_nodb@plt>
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <X509V3_set_ctx@plt>
  xor    %edi,%edi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <X509V3_EXT_conf_nid@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rbp
  mov    $0xffffffff,%edx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <X509_add_ext@plt>
  mov    %rbp,%rdi
  call   <X509_EXTENSION_free@plt>
  mov    $0x1,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  jmp    L24
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cert_add_ext(X509 *issuer, X509 *subject, int nid, char *value) {
  X509_EXTENSION *ex;
  X509V3_CTX ctx;
  X509V3_set_ctx_nodb(&ctx);
  X509V3_set_ctx(&ctx, issuer, subject, NULL, NULL, 0);
  ex = X509V3_EXT_conf_nid(NULL, &ctx, nid, value);
  if (!ex) {
    ERR_print_errors_fp(stdout);
    return 0;
  }
  X509_add_ext(subject, ex, -1);
  X509_EXTENSION_free(ex);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cert_add_ext>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <X509V3_set_ctx_nodb@plt>
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <X509V3_set_ctx@plt>
  xor    %edi,%edi
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  call   <X509V3_EXT_conf_nid@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    $0xffffffff,%edx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <X509_add_ext@plt>
  mov    %rbp,%rdi
  call   <X509_EXTENSION_free@plt>
  mov    $0x1,%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  jmp    L15
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cert_add_ext(X509 *issuer, X509 *subject, int nid, char *value) {
  X509_EXTENSION *ex;
  X509V3_CTX ctx;
  X509V3_set_ctx_nodb(&ctx);
  X509V3_set_ctx(&ctx, issuer, subject, NULL, NULL, 0);
  ex = X509V3_EXT_conf_nid(NULL, &ctx, nid, value);
  if (!ex) {
    ERR_print_errors_fp(stdout);
    return 0;
  }
  X509_add_ext(subject, ex, -1);
  X509_EXTENSION_free(ex);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<multiply346>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L14
L1:
  movl   $0x0,-0x3c(%rbp)
  jmp    L0
L30:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L0:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L30
  addl   $0x1,-0x40(%rbp)
L14:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L1
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply346(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply346>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L20:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L27:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L27
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  ret
```

assistant: ```c
void multiply346(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiply346>:
  endbr64
  test   %edi,%edi
  jle    L26
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L22
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L19
  pop    %rbx
  ret
L26:
  ret
```

assistant: ```c
void multiply346(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply346>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L89
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L58:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L33
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L33
  nopl   0x0(%rax)
L55:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L55
  cmp    -0x24(%rsp),%r11d
  je     L45
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L45
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L45
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L45:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L58
L89:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L72:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L72
  mov    -0x18(%rsp),%r8
  jmp    L45
```

assistant: ```c
void multiply346(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x34(%rbp)
  jg     L26
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <usage_exit@plt>
L26:
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L10
L30:
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_open_rd@plt>
  mov    -0x28(%rbp),%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <do_snap_async@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    -0x28(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <do_snap_destroy@plt>
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0x24(%rbp)
L10:
  cmpl   $0x9,-0x24(%rbp)
  jle    L30
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %d


assistant: ```c
int main(int argc, char *argv[]) {
  const char *base_dir;
  const char *snap_name;
  int fd;
  int i;
  unsigned long long transid;
  if (argc < 3)
    usage_exit(argv[0]);
  base_dir = argv[1];
  snap_name = argv[2];
  for (i = 0; i < 10; i++) {
    printf("%d\n", i);
    do_open_rd(base_dir, &fd);
    do_snap_async(fd, snap_name, &transid);
    sleep(2);
    do_snap_destroy(fd, snap_name);
    close(fd);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jle    L21
L8:
  mov    0x8(%rbx),%r13
  mov    0x10(%rbx),%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L37:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  call   <do_open_rd@plt>
  lea    0x10(%rsp),%rdx
  mov    %rbp,%rsi
  mov    0xc(%rsp),%edi
  call   <do_snap_async@plt>
  mov    $0x2,%edi
  call   <sleep@plt>
  mov    %rbp,%rsi
  mov    0xc(%rsp),%edi
  call   <do_snap_destroy@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L37
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  mov    (%rsi),%rdi
  call   <usage_exit@plt>
  jmp    L8
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d


assistant: ```c
int main(int argc, char *argv[]) {
  const char *base_dir;
  const char *snap_name;
  int fd;
  int i;
  unsigned long long transid;
  if (argc < 3)
    usage_exit(argv[0]);
  base_dir = argv[1];
  snap_name = argv[2];
  for (i = 0; i < 10; i++) {
    printf("%d\n", i);
    do_open_rd(base_dir, &fd);
    do_snap_async(fd, snap_name, &transid);
    sleep(2);
    do_snap_destroy(fd, snap_name);
    close(fd);
  }
  return 0;
}
```