ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x7a,0x63(%rbp)
  movb   $0x78,0x63(%rbx)
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 100;
  char fill = 'o';
  char *s1 = (char *)malloc(size);
  memset(s1, fill, size);
  char *s2 = (char *)malloc(size);
  memset(s2, fill, size);
  s1[size - 1] = 'z';
  s2[size - 1] = 'x';
  int r = strcmp(s1, s2);
  assert(r == 1);
  free(s1);
  free(s2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x7a,0x63(%r12)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x78,0x63(%rbp)
  call   <strcmp@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 100;
  char fill = 'o';
  char *s1 = (char *)malloc(size);
  memset(s1, fill, size);
  char *s2 = (char *)malloc(size);
  memset(s2, fill, size);
  s1[size - 1] = 'z';
  s2[size - 1] = 'x';
  int r = strcmp(s1, s2);
  assert(r == 1);
  free(s1);
  free(s2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    $0x64,%edx
  mov    $0x6f,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x7a,0x63(%r12)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x78,0x63(%rbp)
  call   <strcmp@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  size_t size = 100;
  char fill = 'o';
  char *s1 = (char *)malloc(size);
  memset(s1, fill, size);
  char *s2 = (char *)malloc(size);
  memset(s2, fill, size);
  s1[size - 1] = 'z';
  s2[size - 1] = 'x';
  int r = strcmp(s1, s2);
  assert(r == 1);
  free(s1);
  free(s2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<swapp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapp(int *a, int *b) {
  int t = *a;
  *a = *b;
  *b = t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swapp>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swapp(int *a, int *b) {
  int t = *a;
  *a = *b;
  *b = t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swapp>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swapp(int *a, int *b) {
  int t = *a;
  *a = *b;
  *b = t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swapp>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swapp(int *a, int *b) {
  int t = *a;
  *a = *b;
  *b = t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quickSortSeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L4
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSortSeq>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSortSeq>
L4:
  nop
  leave
  ret
```

assistant: ```c
void quickSortSeq(int *arr, int left, int right) {
  int mid;
  if (left < right) {
    mid = partition(arr, left, right);
    quickSortSeq(arr, left, mid - 1);
    quickSortSeq(arr, mid + 1, right);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quickSortSeq>:
  endbr64
  cmp    %edx,%esi
  jl     L1
  ret
L1:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSortSeq>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quickSortSeq>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quickSortSeq(int *arr, int left, int right) {
  int mid;
  if (left < right) {
    mid = partition(arr, left, right);
    quickSortSeq(arr, left, mid - 1);
    quickSortSeq(arr, mid + 1, right);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ar_sr_extract_time_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <sdnv_decode@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sdnv_decode@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x386d4380(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ar_sr_extract_time_of(uint8_t *ar, struct timeval *tv) {
  int off = 3;
  off += sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_sec);
  sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_usec);
  tv->tv_sec += 946684800;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ar_sr_extract_time_of>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0xc(%rdi),%rdi
  call   <sdnv_decode@plt>
  lea    0x8(%rbx),%rsi
  add    $0x3,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdi
  call   <sdnv_decode@plt>
  addq   $0x386d4380,(%rbx)
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ar_sr_extract_time_of(uint8_t *ar, struct timeval *tv) {
  int off = 3;
  off += sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_sec);
  sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_usec);
  tv->tv_sec += 946684800;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ar_sr_extract_time_of>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0xc(%rdi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sdnv_decode@plt>
  lea    0x8(%rbx),%rsi
  add    $0x3,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdi
  call   <sdnv_decode@plt>
  addq   $0x386d4380,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ar_sr_extract_time_of(uint8_t *ar, struct timeval *tv) {
  int off = 3;
  off += sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_sec);
  sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_usec);
  tv->tv_sec += 946684800;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ar_sr_extract_time_of>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0xc(%rdi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sdnv_decode@plt>
  lea    0x8(%rbx),%rsi
  add    $0x3,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rdi
  call   <sdnv_decode@plt>
  addq   $0x386d4380,(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ar_sr_extract_time_of(uint8_t *ar, struct timeval *tv) {
  int off = 3;
  off += sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_sec);
  sdnv_decode((uint8_t *)ar + off, (uint64_t *)&tv->tv_usec);
  tv->tv_sec += 946684800;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <spi_n@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L29
  mov    -0xc(%rbp),%eax
  jmp    L8
L29:
  mov    -0x10(%rbp),%eax
  movzbl %al,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int spi(int fd, uint8_t tx) {
  uint8_t rx;
  int ret;
  if ((ret = spi_n(fd, &tx, &rx, 1)) < 0)
    return ret;
  return 0xff & rx;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<spi>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x1,%ecx
  call   <spi_n@plt>
  test   %eax,%eax
  js     L1
  movzbl 0x14(%rsp),%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x28,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spi(int fd, uint8_t tx) {
  uint8_t rx;
  int ret;
  if ((ret = spi_n(fd, &tx, &rx, 1)) < 0)
    return ret;
  return 0xff & rx;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spi>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%ecx
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <spi_n@plt>
  test   %eax,%eax
  js     L4
  movzbl 0x14(%rsp),%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spi(int fd, uint8_t tx) {
  uint8_t rx;
  int ret;
  if ((ret = spi_n(fd, &tx, &rx, 1)) < 0)
    return ret;
  return 0xff & rx;
}
```
user: What is the c source code of the assembly code below:

```asm
<spi>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%ecx
  mov    %esi,0xc(%rsp)
  lea    0x14(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <spi_n@plt>
  test   %eax,%eax
  js     L19
  movzbl 0x14(%rsp),%eax
L19:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int spi(int fd, uint8_t tx) {
  uint8_t rx;
  int ret;
  if ((ret = spi_n(fd, &tx, &rx, 1)) < 0)
    return ret;
  return 0xff & rx;
}
```
user: What is the c source code of the assembly code below?

```asm
<cli_run_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cli_int_generate_pipeline@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cli_int_validate_pipeline@plt>
  mov    %eax,-0xc(%rbp)
L3:
  cmpl   $0x0,-0xc(%rbp)
  jne    L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cli_int_execute_pipeline@plt>
  mov    %eax,-0xc(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cli_int_free_pipeline@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cli_run_command(struct cli_def *cli, const char *command) {
  int rc = -1;
  struct cli_pipeline *pipeline;
  pipeline = cli_int_generate_pipeline(cli, command);
  if (pipeline)
    rc = cli_int_validate_pipeline(cli, pipeline);
  if (rc == 0) {
    rc = cli_int_execute_pipeline(cli, pipeline);
  }
  cli_int_free_pipeline(pipeline);
  return rc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cli_run_command>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <cli_int_generate_pipeline@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L38
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <cli_int_validate_pipeline@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L19
L25:
  mov    %rbx,%rdi
  call   <cli_int_free_pipeline@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <cli_int_execute_pipeline@plt>
  mov    %eax,%ebp
  jmp    L25
L38:
  mov    $0xffffffff,%ebp
  jmp    L25
```

assistant: ```c
int cli_run_command(struct cli_def *cli, const char *command) {
  int rc = -1;
  struct cli_pipeline *pipeline;
  pipeline = cli_int_generate_pipeline(cli, command);
  if (pipeline)
    rc = cli_int_validate_pipeline(cli, pipeline);
  if (rc == 0) {
    rc = cli_int_execute_pipeline(cli, pipeline);
  }
  cli_int_free_pipeline(pipeline);
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<cli_run_command>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  call   <cli_int_generate_pipeline@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L20
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <cli_int_validate_pipeline@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L3
L19:
  mov    %rbp,%rdi
  call   <cli_int_free_pipeline@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cli_int_execute_pipeline@plt>
  mov    %eax,%r12d
  jmp    L19
L20:
  mov    $0xffffffff,%r12d
  jmp    L19
```

assistant: ```c
int cli_run_command(struct cli_def *cli, const char *command) {
  int rc = -1;
  struct cli_pipeline *pipeline;
  pipeline = cli_int_generate_pipeline(cli, command);
  if (pipeline)
    rc = cli_int_validate_pipeline(cli, pipeline);
  if (rc == 0) {
    rc = cli_int_execute_pipeline(cli, pipeline);
  }
  cli_int_free_pipeline(pipeline);
  return rc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cli_run_command>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  call   <cli_int_generate_pipeline@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <cli_int_validate_pipeline@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L36
L30:
  mov    %rbp,%rdi
  call   <cli_int_free_pipeline@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L36:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cli_int_execute_pipeline@plt>
  mov    %eax,%r12d
  jmp    L30
L34:
  mov    $0xffffffff,%r12d
  jmp    L30
```

assistant: ```c
int cli_run_command(struct cli_def *cli, const char *command) {
  int rc = -1;
  struct cli_pipeline *pipeline;
  pipeline = cli_int_generate_pipeline(cli, command);
  if (pipeline)
    rc = cli_int_validate_pipeline(cli, pipeline);
  if (rc == 0) {
    rc = cli_int_execute_pipeline(cli, pipeline);
  }
  cli_int_free_pipeline(pipeline);
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kl_str_match_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L0:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
L23:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int kl_str_match_len(const char *s1, const char *s2) {
  int r = 0;
  while (s1[r] == s2[r] && s1[r]) {
    r++;
  }
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<kl_str_match_len>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L6
  test   %al,%al
  je     L6
  mov    $0x1,%eax
L10:
  mov    %eax,%r8d
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L10
L25:
  mov    %r8d,%eax
  ret
L6:
  mov    $0x0,%r8d
  jmp    L25
```

assistant: ```c
int kl_str_match_len(const char *s1, const char *s2) {
  int r = 0;
  while (s1[r] == s2[r] && s1[r]) {
    r++;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kl_str_match_len>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L4
  test   %al,%al
  je     L4
  mov    $0x1,%eax
  nopl   0x0(%rax)
L5:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  mov    %eax,%r8d
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L5
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int kl_str_match_len(const char *s1, const char *s2) {
  int r = 0;
  while (s1[r] == s2[r] && s1[r]) {
    r++;
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kl_str_match_len>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %al,(%rsi)
  jne    L1
  test   %al,%al
  je     L1
  mov    $0x1,%eax
  nopl   0x0(%rax)
L25:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  mov    %eax,%r8d
  sete   %cl
  test   %dl,%dl
  setne  %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L25
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int kl_str_match_len(const char *s1, const char *s2) {
  int r = 0;
  while (s1[r] == s2[r] && s1[r]) {
    r++;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Int24_To_Int8_Dither>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Int24_To_Int8_Dither(void *destinationBuffer, signed int destinationStride, void *sourceBuffer, signed int sourceStride, unsigned int count, struct PaUtilTriangularDitherGenerator *ditherGenerator) {
  (void)destinationBuffer;
  (void)destinationStride;
  (void)sourceBuffer;
  (void)sourceStride;
  (void)count;
  (void)ditherGenerator;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Int24_To_Int8_Dither>:
  endbr64
  ret
```

assistant: ```c
void Int24_To_Int8_Dither(void *destinationBuffer, signed int destinationStride, void *sourceBuffer, signed int sourceStride, unsigned int count, struct PaUtilTriangularDitherGenerator *ditherGenerator) {
  (void)destinationBuffer;
  (void)destinationStride;
  (void)sourceBuffer;
  (void)sourceStride;
  (void)count;
  (void)ditherGenerator;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Int24_To_Int8_Dither>:
  endbr64
  ret
```

assistant: ```c
void Int24_To_Int8_Dither(void *destinationBuffer, signed int destinationStride, void *sourceBuffer, signed int sourceStride, unsigned int count, struct PaUtilTriangularDitherGenerator *ditherGenerator) {
  (void)destinationBuffer;
  (void)destinationStride;
  (void)sourceBuffer;
  (void)sourceStride;
  (void)count;
  (void)ditherGenerator;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getlinee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L49:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L26
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L26
  cmpl   $0xa,-0x4(%rbp)
  jne    L49
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L2
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void getlinee(char s[], int limit) {
  int c, i;
  for (i = 0; i < limit - 1 && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (s[i] == '\n')
    s[i++] = '\n';
  s[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getlinee>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  cmp    $0x1,%esi
  jle    L19
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r13d
  mov    $0x0,%ebx
L48:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L39
  cmp    $0xa,%eax
  je     L39
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r13d,%ebx
  jne    L48
  mov    %r13d,%ebx
L39:
  movslq %ebx,%rax
  cmpb   $0xa,(%r12,%rax,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%ebx
  jmp    L39
```

assistant: ```c
void getlinee(char s[], int limit) {
  int c, i;
  for (i = 0; i < limit - 1 && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (s[i] == '\n')
    s[i++] = '\n';
  s[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getlinee>:
  endbr64
  push   %r14
  mov    %rdi,%rdx
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L49
  mov    D3(%rip),%rbp
  mov    %rdi,%r13
  xor    %r14d,%r14d
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L58:
  cmp    $0xa,%eax
  je     L49
  add    $0x1,%r14d
  mov    %al,(%rdx)
  lea    0x1(%rdx),%r13
  cmp    %ebx,%r14d
  je     L68
L36:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %r13,%rdx
  cmp    %eax,0x0(%rbp)
  jne    L58
L49:
  cmpb   $0xa,(%rdx)
  jne    L65
  add    $0x1,%r14d
  movslq %r14d,%r14
  lea    (%r12,%r14,1),%rdx
L65:
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L68:
  movslq %r14d,%rdx
  add    %r12,%rdx
  jmp    L49
```

assistant: ```c
void getlinee(char s[], int limit) {
  int c, i;
  for (i = 0; i < limit - 1 && (c = getchar()) != EOF && c != '\n'; i++)
    s[i] = c;
  if (s[i] == '\n')
    s[i++] = '\n';
  s[i] = '\0';
}
```