ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<literal_string2_Good>:
  endbr64
  ret
```

assistant: ```c
void literal_string2_Good() {
  int a[1];
  char s[] = "hello";
  for (int i = 0; i < 5; i++) {
    if (s[i] > 'o') {
      a[s[i]] = 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<literal_string2_Good>:
  endbr64
  ret
```

assistant: ```c
void literal_string2_Good() {
  int a[1];
  char s[] = "hello";
  for (int i = 0; i < 5; i++) {
    if (s[i] > 'o') {
      a[s[i]] = 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mpfq_clzlx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L24:
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x1c(%rbp)
L12:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L43
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L24
L43:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  jmp    L9
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <__builtin_clzl@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int mpfq_clzlx(unsigned long *x, int n) {
  int r = 0;
  for (; n > 0 && __builtin_expect(!x[n - 1], 0); --n)
    r += GMP_LIMB_BITS;
  if (n == 0)
    return r;
  r += __builtin_clzl(x[n - 1]);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mpfq_clzlx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L38
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbp
  mov    $0x0,%r12d
L14:
  cmpq   $0x0,-0x8(%rbp)
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L31
  mov    D9(%rip),%rax
  add    (%rax),%r12d
  sub    $0x8,%rbp
  sub    $0x1,%ebx
  jne    L14
  jmp    L42
L38:
  mov    $0x0,%r12d
L31:
  test   %ebx,%ebx
  je     L42
  movslq %ebx,%rbx
  mov    -0x8(%r13,%rbx,8),%rdi
  call   <__builtin_clzl@plt>
  add    %eax,%r12d
L42:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mpfq_clzlx(unsigned long *x, int n) {
  int r = 0;
  for (; n > 0 && __builtin_expect(!x[n - 1], 0); --n)
    r += GMP_LIMB_BITS;
  if (n == 0)
    return r;
  r += __builtin_clzl(x[n - 1]);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mpfq_clzlx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  jle    L25
  movslq %ebp,%rax
  xor    %r12d,%r12d
  lea    -0x8(%rdi,%rax,8),%rbx
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D2(%rip),%rax
  sub    $0x8,%rbx
  add    (%rax),%r12d
  sub    $0x1,%ebp
  je     L8
L41:
  xor    %edi,%edi
  cmpq   $0x0,(%rbx)
  mov    %rbx,%r13
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L5
L56:
  mov    0x0(%r13),%rdi
  call   <__builtin_clzl@plt>
  add    %eax,%r12d
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    $0x0,%r12d
  je     L8
  lea    -0x8(%rdi,%rbp,8),%r13
  jmp    L56
```

assistant: ```c
int mpfq_clzlx(unsigned long *x, int n) {
  int r = 0;
  for (; n > 0 && __builtin_expect(!x[n - 1], 0); --n)
    r += GMP_LIMB_BITS;
  if (n == 0)
    return r;
  r += __builtin_clzl(x[n - 1]);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpfq_clzlx>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L13
  movslq %ebp,%rax
  xor    %r12d,%r12d
  lea    -0x8(%rdi,%rax,8),%rbx
  jmp    L23
L53:
  mov    D2(%rip),%rax
  sub    $0x8,%rbx
  add    (%rax),%r12d
  sub    $0x1,%ebp
  je     L27
L23:
  xor    %edi,%edi
  cmpq   $0x0,(%rbx)
  mov    %rbx,%r13
  mov    %r12d,%r14d
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L53
L1:
  mov    0x0(%r13),%rdi
  call   <__builtin_clzl@plt>
  lea    (%r14,%rax,1),%r12d
L27:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0x0,%r12d
  je     L27
  lea    -0x8(%rdi,%rbp,8),%r13
  xor    %r14d,%r14d
  jmp    L1
```

assistant: ```c
int mpfq_clzlx(unsigned long *x, int n) {
  int r = 0;
  for (; n > 0 && __builtin_expect(!x[n - 1], 0); --n)
    r += GMP_LIMB_BITS;
  if (n == 0)
    return r;
  r += __builtin_clzl(x[n - 1]);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<readqn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L80
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L118
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
  cmpl   $0x20,-0xc(%rbp)
  jne    L51
  mov    -0x18(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movw   $0x0,(%rax)
  jmp    L89
L51:
  mov    -0xc(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L138
  cmpl   $0x9,-0x14(%rbp)
  jg     L138
  cmpl   $0x20,-0x10(%rbp)
  je     L66
  cmpl   $0x2d,-0x10(%rbp)
  jne    L72
  negl   -0x14(%rbp)
  jmp    L66
L72:
  cmpl   $0x2f,-0x10(%rbp)
  jle    L147
  cmpl   $0x39,-0x10(%rbp)
  jg     L147
  mov    -0x10(%rbp),%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,-0x14(%rbp)
  jmp    L66
L147:
  cmpl   $0x60,-0x10(%rbp)
  jle    L155
  cmpl   $0x7a,-0x10(%rbp)
  jg     L155
  mov    -0x10(%rbp),%eax
  sub    $0x60,%eax
  imul   $0xfffffff6,%eax,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L66
L155:
  cmpl   $0x40,-0x10(%rbp)
  jle    L138
  cmpl   $0x5a,-0x10(%rbp)
  jg     L138
  mov    -0x10(%rbp),%eax
  lea    -0x37(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %eax,-0x14(%rbp)
L66:
  mov    -0x18(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dx,(%rax)
L89:
  addl   $0x1,-0x18(%rbp)
L80:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L8
  jmp    L138
L118:
  nop
L138:
  mov    -0x34(%rbp),%eax
  sub    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int readqn(qnstr, iqn, n)
char *qnstr;
short *iqn;
int n;
{
  char *pqn;
  int i, ich, ic, ival;
  pqn = qnstr;
  for (i = 0; i < n; ++i) {
    if (*pqn == 0)
      break;
    ich = (*pqn & 0xff);
    ++pqn;
    ic = (*pqn & 0xff);
    ++pqn;
    if (ic == ' ') {
      iqn[i] = 0;
      continue;
    }
    ival = ic - '0';
    if (ival < 0 || ival > 9)
      break;
    if (ich != ' ') {
      if (ich == '-') {
        ival = -ival;
      } else if (ich >= '0' && ich <= '9') {
        ival += (ich - '0') * 10;
      } else if (ich >= 'a' && ich <= 'z') {
        ival = -ival - 10 * (ich - ('a' - 1));
      } else if (ich >= 'A' && ich <= 'Z') {
        ival += 10 * (ich - ('A' - 10));
      } else {
        break;
      }
    }
    iqn[i] = (short)ival;
  }
  return (n - i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readqn>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L128
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r11
  mov    %edx,%ebx
  mov    $0x0,%edx
  mov    $0x30,%ebp
  jmp    L72
L63:
  movw   $0x0,(%r11,%rdx,2)
  jmp    L8
L57:
  mov    %ebp,%esi
  sub    %edi,%esi
L78:
  mov    %si,(%r11,%rdx,2)
L8:
  lea    0x1(%r10),%r9d
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L97
L72:
  mov    %edx,%r10d
  mov    %edx,%r9d
  movzbl (%r8,%rdx,2),%ecx
  test   %cl,%cl
  je     L97
  movzbl %cl,%ecx
  movzbl 0x1(%r8,%rdx,2),%edi
  cmp    $0x20,%edi
  je     L63
  lea    -0x30(%rdi),%esi
  cmp    $0x9,%esi
  ja     L97
  cmp    $0x20,%ecx
  je     L78
  cmp    $0x2d,%ecx
  je     L57
  lea    -0x30(%rcx),%edi
  cmp    $0x9,%edi
  ja     L43
  lea    -0xf0(%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%esi
  jmp    L78
L43:
  lea    -0x61(%rcx),%edi
  cmp    $0x19,%edi
  ja     L75
  sub    $0x60,%ecx
  imul   $0xfffffff6,%ecx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%esi
  jmp    L78
L75:
  lea    -0x41(%rcx),%edi
  cmp    $0x19,%edi
  ja     L97
  lea    -0x113(%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%esi
  jmp    L78
L128:
  mov    $0x0,%r9d
  sub    %r9d,%eax
  ret
L97:
  sub    %r9d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int readqn(qnstr, iqn, n)
char *qnstr;
short *iqn;
int n;
{
  char *pqn;
  int i, ich, ic, ival;
  pqn = qnstr;
  for (i = 0; i < n; ++i) {
    if (*pqn == 0)
      break;
    ich = (*pqn & 0xff);
    ++pqn;
    ic = (*pqn & 0xff);
    ++pqn;
    if (ic == ' ') {
      iqn[i] = 0;
      continue;
    }
    ival = ic - '0';
    if (ival < 0 || ival > 9)
      break;
    if (ich != ' ') {
      if (ich == '-') {
        ival = -ival;
      } else if (ich >= '0' && ich <= '9') {
        ival += (ich - '0') * 10;
      } else if (ich >= 'a' && ich <= 'z') {
        ival = -ival - 10 * (ich - ('a' - 1));
      } else if (ich >= 'A' && ich <= 'Z') {
        ival += 10 * (ich - ('A' - 10));
      } else {
        break;
      }
    }
    iqn[i] = (short)ival;
  }
  return (n - i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readqn>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L128
  push   %rbx
  movslq %edx,%r11
  mov    %rdi,%r9
  mov    %rsi,%r10
  xor    %edx,%edx
  mov    $0x30,%ebx
  jmp    L35
  nopl   0x0(%rax)
L19:
  lea    -0x30(%r8),%esi
  cmp    $0x9,%esi
  ja     L1
  cmp    $0x20,%ecx
  je     L62
  cmp    $0x2d,%ecx
  je     L140
  lea    -0x30(%rcx),%r8d
  cmp    $0x9,%r8d
  ja     L104
  lea    (%r8,%r8,4),%ecx
  lea    (%rsi,%rcx,2),%esi
L62:
  mov    %si,(%r10,%rdx,2)
  add    $0x1,%rdx
  add    $0x1,%edi
  cmp    %r11,%rdx
  je     L1
L35:
  movzbl (%r9,%rdx,2),%ecx
  mov    %edx,%edi
  test   %cl,%cl
  je     L1
  movzbl 0x1(%r9,%rdx,2),%r8d
  cmp    $0x20,%r8d
  jne    L19
  xor    %ecx,%ecx
  add    $0x1,%edi
  mov    %cx,(%r10,%rdx,2)
  add    $0x1,%rdx
  cmp    %r11,%rdx
  jne    L35
L1:
  sub    %edi,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L140:
  mov    %ebx,%esi
  sub    %r8d,%esi
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L104:
  lea    -0x61(%rcx),%r8d
  cmp    $0x19,%r8d
  ja     L147
  sub    $0x60,%ecx
  imul   $0xfffffff6,%ecx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%esi
  jmp    L62
  cs nopw 0x0(%rax,%rax,1)
L147:
  lea    -0x41(%rcx),%r8d
  cmp    $0x19,%r8d
  ja     L1
  lea    -0x113(%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%esi
  jmp    L62
L128:
  ret
```

assistant: ```c
int readqn(qnstr, iqn, n)
char *qnstr;
short *iqn;
int n;
{
  char *pqn;
  int i, ich, ic, ival;
  pqn = qnstr;
  for (i = 0; i < n; ++i) {
    if (*pqn == 0)
      break;
    ich = (*pqn & 0xff);
    ++pqn;
    ic = (*pqn & 0xff);
    ++pqn;
    if (ic == ' ') {
      iqn[i] = 0;
      continue;
    }
    ival = ic - '0';
    if (ival < 0 || ival > 9)
      break;
    if (ich != ' ') {
      if (ich == '-') {
        ival = -ival;
      } else if (ich >= '0' && ich <= '9') {
        ival += (ich - '0') * 10;
      } else if (ich >= 'a' && ich <= 'z') {
        ival = -ival - 10 * (ich - ('a' - 1));
      } else if (ich >= 'A' && ich <= 'Z') {
        ival += 10 * (ich - ('A' - 10));
      } else {
        break;
      }
    }
    iqn[i] = (short)ival;
  }
  return (n - i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<readqn>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L91
  push   %rbx
  movslq %edx,%r11
  mov    %rdi,%r9
  mov    %rsi,%r10
  xor    %edx,%edx
  mov    $0x30,%ebx
  jmp    L41
  nopl   0x0(%rax)
L133:
  lea    -0x30(%r8),%esi
  cmp    $0x9,%esi
  ja     L39
  cmp    $0x20,%ecx
  je     L88
  cmp    $0x2d,%ecx
  je     L143
  lea    -0x30(%rcx),%r8d
  cmp    $0x9,%r8d
  ja     L99
  lea    (%r8,%r8,4),%ecx
  lea    (%rsi,%rcx,2),%esi
L88:
  mov    %si,(%r10,%rdx,2)
  add    $0x1,%rdx
  add    $0x1,%edi
  cmp    %r11,%rdx
  je     L39
L41:
  movzbl (%r9,%rdx,2),%ecx
  mov    %edx,%edi
  test   %cl,%cl
  je     L39
  movzbl 0x1(%r9,%rdx,2),%r8d
  cmp    $0x20,%r8d
  jne    L133
  xor    %ecx,%ecx
  add    $0x1,%edi
  mov    %cx,(%r10,%rdx,2)
  add    $0x1,%rdx
  cmp    %r11,%rdx
  jne    L41
L39:
  sub    %edi,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L143:
  mov    %ebx,%esi
  sub    %r8d,%esi
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L99:
  lea    -0x61(%rcx),%r8d
  cmp    $0x19,%r8d
  ja     L12
  sub    $0x60,%ecx
  imul   $0xfffffff6,%ecx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%esi
  jmp    L88
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    -0x41(%rcx),%r8d
  cmp    $0x19,%r8d
  ja     L39
  lea    -0x113(%rcx,%rcx,4),%ecx
  lea    (%rsi,%rcx,2),%esi
  jmp    L88
L91:
  ret
```

assistant: ```c
int readqn(qnstr, iqn, n)
char *qnstr;
short *iqn;
int n;
{
  char *pqn;
  int i, ich, ic, ival;
  pqn = qnstr;
  for (i = 0; i < n; ++i) {
    if (*pqn == 0)
      break;
    ich = (*pqn & 0xff);
    ++pqn;
    ic = (*pqn & 0xff);
    ++pqn;
    if (ic == ' ') {
      iqn[i] = 0;
      continue;
    }
    ival = ic - '0';
    if (ival < 0 || ival > 9)
      break;
    if (ich != ' ') {
      if (ich == '-') {
        ival = -ival;
      } else if (ich >= '0' && ich <= '9') {
        ival += (ich - '0') * 10;
      } else if (ich >= 'a' && ich <= 'z') {
        ival = -ival - 10 * (ich - ('a' - 1));
      } else if (ich >= 'A' && ich <= 'Z') {
        ival += 10 * (ich - ('A' - 10));
      } else {
        break;
      }
    }
    iqn[i] = (short)ival;
  }
  return (n - i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t_isdigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L4
  movzbl -0x1(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L4
  mov    $0x1,%eax
  jmp    L0
L4:
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
int t_isdigit(char ch) {
  volatile char xc = ch;
  volatile unsigned char xuc = ch;
  return isdigit(xc) && isdigit(xuc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t_isdigit>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xe(%rsp)
  mov    %dil,0xf(%rsp)
  movzbl 0xe(%rsp),%edi
  movzbl %dil,%edi
  call   <isdigit@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L6
L9:
  add    $0x18,%rsp
  ret
L6:
  movzbl 0xf(%rsp),%edi
  movzbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L9
```

assistant: ```c
int t_isdigit(char ch) {
  volatile char xc = ch;
  volatile unsigned char xuc = ch;
  return isdigit(xc) && isdigit(xuc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<t_isdigit>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xe(%rsp)
  mov    %dil,0xf(%rsp)
  movzbl 0xe(%rsp),%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L4
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movzbl 0xf(%rsp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int t_isdigit(char ch) {
  volatile char xc = ch;
  volatile unsigned char xuc = ch;
  return isdigit(xc) && isdigit(xuc);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<t_isdigit>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xe(%rsp)
  mov    %dil,0xf(%rsp)
  movzbl 0xe(%rsp),%edi
  call   <isdigit@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl 0xf(%rsp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  setne  %al
  add    $0x18,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int t_isdigit(char ch) {
  volatile char xc = ch;
  volatile unsigned char xuc = ch;
  return isdigit(xc) && isdigit(xuc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0xa,-0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L3
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void f4(int i) {
  unsigned long j;
  j = 10;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f4>:
  endbr64
  test   %edi,%edi
  js     L8
  ret
L8:
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f4(int i) {
  unsigned long j;
  j = 10;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f4>:
  endbr64
  test   %edi,%edi
  js     L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f4(int i) {
  unsigned long j;
  j = 10;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f4>:
  endbr64
  test   %edi,%edi
  js     L1
  ret
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f4(int i) {
  unsigned long j;
  j = 10;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
L0:
  jmp    L0
```

assistant: ```c
void _exit(int status) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_exit>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
void _exit(int status) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void _exit(int status) {
  while (1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L2:
  jmp    L2
```

assistant: ```c
void _exit(int status) {
  while (1)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<getMedianOfMedians>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x5,-0xc(%rbp)
  jg     L6
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  jmp    L13
L6:
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L24
L46:
  mov    -0x18(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L48
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insertionSort@plt>
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L46
  mov    -0x14(%rbp),%edx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getMedianOfMedians>
L13:
  leave
  ret
```

assistant: ```c
int getMedianOfMedians(int array[], int beg, int end) {
  int arraySize = end - beg + 1;
  if (arraySize <= 5)
    return beg + (arraySize / 2);
  int i = beg, medGroupsEnd = beg, medianPos, j, swapVar;
  while (i <= end) {
    j = i + 5 - 1;
    if (j > end)
      j = end;
    insertionSort(array, i, j);
    medianPos = i + (j - i + 1) / 2;
    swapVar = array[medGroupsEnd];
    array[medGroupsEnd] = array[medianPos];
    array[medianPos] = swapVar;
    medGroupsEnd++;
    i = j + 1;
  }
  return getMedianOfMedians(array, beg, medGroupsEnd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getMedianOfMedians>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r14d
  mov    %edx,%r13d
  sub    %esi,%edx
  add    $0x1,%edx
  cmp    $0x5,%edx
  jle    L21
  mov    %rdi,%r12
  lea    0x1(%rsi),%ebp
  movslq %ebp,%rbp
  mov    %esi,%r15d
  mov    %esi,%edx
  cmp    %esi,%r13d
  jl     L22
L35:
  lea    0x4(%r15),%ebx
  cmp    %r13d,%ebx
  cmovg  %r13d,%ebx
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r12,%rdi
  call   <insertionSort@plt>
  mov    -0x4(%r12,%rbp,4),%ecx
  mov    %ebx,%edx
  sub    %r15d,%edx
  add    $0x1,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %r15d,%eax
  cltq
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%edx
  mov    %edx,-0x4(%r12,%rbp,4)
  mov    %ecx,(%rax)
  mov    %ebp,%edx
  lea    0x1(%rbx),%r15d
  add    $0x1,%rbp
  cmp    %r15d,%r13d
  jge    L35
L22:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <getMedianOfMedians>
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %esi,%eax
  jmp    L23
```

assistant: ```c
int getMedianOfMedians(int array[], int beg, int end) {
  int arraySize = end - beg + 1;
  if (arraySize <= 5)
    return beg + (arraySize / 2);
  int i = beg, medGroupsEnd = beg, medianPos, j, swapVar;
  while (i <= end) {
    j = i + 5 - 1;
    if (j > end)
      j = end;
    insertionSort(array, i, j);
    medianPos = i + (j - i + 1) / 2;
    swapVar = array[medGroupsEnd];
    array[medGroupsEnd] = array[medianPos];
    array[medianPos] = swapVar;
    medGroupsEnd++;
    i = j + 1;
  }
  return getMedianOfMedians(array, beg, medGroupsEnd);
}
```