ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_next_operand>:
  endbr64
  push   %r13
  movslq %edx,%r9
  movabs $0xffffeffefffffbff,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi,%r9,1),%eax
  cmp    $0x2c,%al
  je     L123
  nopl   0x0(%rax)
L82:
  cmp    $0xa,%al
  je     L90
  mov    D0(%rip),%r10
  movzbl (%r10),%esi
  test   %al,%al
  je     L90
  cmp    %al,%sil
  je     L90
  add    %rbp,%r9
  movzbl (%r9),%eax
  cmp    $0x2c,%al
  ja     L13
  bt     %rax,%r13
  jae    L28
L13:
  mov    %rbx,%rcx
  mov    $0x1,%edx
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L35:
  movzbl (%r10),%esi
L17:
  cmp    %sil,%al
  mov    %rcx,%r8
  setne  %dil
  test   %al,%al
  setne  %sil
  test   %sil,%dil
  je     L108
  cmp    $0x9,%al
  je     L108
  mov    %al,(%rcx)
  movzbl (%r9,%rdx,1),%eax
  movslq %edx,%rsi
  add    $0x1,%r12d
  add    $0x1,%rdx
  add    $0x1,%rcx
  cmp    $0x2c,%al
  ja     L35
  bt     %rax,%r13
  lea    0x1(%r8),%rcx
  jb     L35
  lea    (%rbx,%rsi,1),%r8
L108:
  movb   $0x0,(%r8)
  mov    %rbx,%rdi
  call   <is_current_word_empty@plt>
  test   %rax,%rax
  je     L7
  add    $0x1,%r12d
  movslq %r12d,%r9
  movzbl 0x0(%rbp,%r9,1),%eax
  cmp    $0x2c,%al
  jne    L82
L123:
  mov    $0x2c,%eax
  mov    %ax,(%rbx)
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    %rbx,%r8
  jmp    L108
L90:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_next_operand(char *current_word, char *line, int last_position) {
  int position = last_position;
  int i = 0;
  if (line[position] == ',') {
    current_word[0] = ',';
    current_word[1] = '\0';
    return position;
  }
  if (line[position] == '\n' || line[position] == EOF || line[position] == '\0') {
    current_word[i] = '\0';
    return position;
  }
  while (line[position] != ',' && line[position] != '\n' && line[position] != ' ' && line[position] != EOF && line[position] != '\0' && line[position] != '\t') {
    current_word[i] = line[position];
    i++;
    position++;
  }
  current_word[i] = '\0';
  if (is_current_word_empty(current_word))
    position = get_next_operand(current_word, line, position + 1);
  return position;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_next_operand>:
  endbr64
  push   %r13
  movslq %edx,%r9
  movabs $0xffffeffefffffbff,%r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl (%rsi,%r9,1),%eax
  cmp    $0x2c,%al
  je     L21
  nopl   0x0(%rax)
L49:
  cmp    $0xa,%al
  je     L146
  mov    D8(%rip),%r10
  movzbl (%r10),%edi
  test   %al,%al
  je     L146
  cmp    %al,%dil
  je     L146
  cmp    $0x2c,%al
  ja     L117
  bt     %rax,%r13
  jae    L60
L117:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  add    %rbp,%r9
  jmp    L144
  nopw   0x0(%rax,%rax,1)
L9:
  bt     %rax,%r13
  lea    0x1(%rcx),%rsi
  jae    L28
L112:
  movzbl (%r10),%edi
L144:
  cmp    %dil,%al
  mov    %rsi,%rcx
  setne  %r8b
  test   %al,%al
  setne  %dil
  test   %dil,%r8b
  je     L128
  cmp    $0x9,%al
  je     L128
  mov    %al,(%rcx)
  movzbl (%r9,%rdx,1),%eax
  movslq %edx,%rdi
  add    $0x1,%r12d
  add    $0x1,%rdx
  cmp    $0x2c,%al
  jbe    L9
  add    $0x1,%rsi
  jmp    L112
  nopl   0x0(%rax,%rax,1)
L28:
  lea    (%rbx,%rdi,1),%rcx
L128:
  movb   $0x0,(%rcx)
  mov    %rbx,%rdi
  call   <is_current_word_empty@plt>
  test   %rax,%rax
  je     L102
  add    $0x1,%r12d
  movslq %r12d,%r9
  movzbl 0x0(%rbp,%r9,1),%eax
  cmp    $0x2c,%al
  jne    L49
L21:
  mov    $0x2c,%eax
  mov    %ax,(%rbx)
L102:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  mov    %rbx,%rcx
  jmp    L128
L146:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int get_next_operand(char *current_word, char *line, int last_position) {
  int position = last_position;
  int i = 0;
  if (line[position] == ',') {
    current_word[0] = ',';
    current_word[1] = '\0';
    return position;
  }
  if (line[position] == '\n' || line[position] == EOF || line[position] == '\0') {
    current_word[i] = '\0';
    return position;
  }
  while (line[position] != ',' && line[position] != '\n' && line[position] != ' ' && line[position] != EOF && line[position] != '\0' && line[position] != '\t') {
    current_word[i] = line[position];
    i++;
    position++;
  }
  current_word[i] = '\0';
  if (is_current_word_empty(current_word))
    position = get_next_operand(current_word, line, position + 1);
  return position;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gpio_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int gpio_close(int fd) {
  close(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gpio_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_close(int fd) {
  close(fd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gpio_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_close(int fd) {
  close(fd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gpio_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gpio_close(int fd) {
  close(fd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<XXH64_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <XXH64@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned int XXH64_32(const void *key, unsigned int len, unsigned int seed) {
  unsigned long long hash = XXH64(key, len, seed);
  return (unsigned int)(hash & 0xFFFFFFFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<XXH64_32>:
  endbr64
  sub    $0x8,%rsp
  call   <XXH64@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int XXH64_32(const void *key, unsigned int len, unsigned int seed) {
  unsigned long long hash = XXH64(key, len, seed);
  return (unsigned int)(hash & 0xFFFFFFFF);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<XXH64_32>:
  endbr64
  sub    $0x8,%rsp
  call   <XXH64@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int XXH64_32(const void *key, unsigned int len, unsigned int seed) {
  unsigned long long hash = XXH64(key, len, seed);
  return (unsigned int)(hash & 0xFFFFFFFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<XXH64_32>:
  endbr64
  sub    $0x8,%rsp
  call   <XXH64@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int XXH64_32(const void *key, unsigned int len, unsigned int seed) {
  unsigned long long hash = XXH64(key, len, seed);
  return (unsigned int)(hash & 0xFFFFFFFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<closeonflush_writecb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_output@plt>
  mov    %eax,%edi
  call   <evbuffer_get_length@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_free@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void closeonflush_writecb(struct bufferevent *bev, void *arg) {
  if (evbuffer_get_length(bufferevent_get_output(bev)) == 0)
    bufferevent_free(bev);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<closeonflush_writecb>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <bufferevent_get_output@plt>
  mov    %eax,%edi
  call   <evbuffer_get_length@plt>
  test   %rax,%rax
  je     L8
L10:
  pop    %rbx
  ret
L8:
  mov    %rbx,%rdi
  call   <bufferevent_free@plt>
  jmp    L10
```

assistant: ```c
void closeonflush_writecb(struct bufferevent *bev, void *arg) {
  if (evbuffer_get_length(bufferevent_get_output(bev)) == 0)
    bufferevent_free(bev);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<closeonflush_writecb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <bufferevent_get_output@plt>
  mov    %eax,%edi
  call   <evbuffer_get_length@plt>
  test   %rax,%rax
  je     L5
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <bufferevent_free@plt>
```

assistant: ```c
void closeonflush_writecb(struct bufferevent *bev, void *arg) {
  if (evbuffer_get_length(bufferevent_get_output(bev)) == 0)
    bufferevent_free(bev);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<closeonflush_writecb>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <bufferevent_get_output@plt>
  mov    %eax,%edi
  call   <evbuffer_get_length@plt>
  test   %rax,%rax
  je     L3
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <bufferevent_free@plt>
```

assistant: ```c
void closeonflush_writecb(struct bufferevent *bev, void *arg) {
  if (evbuffer_get_length(bufferevent_get_output(bev)) == 0)
    bufferevent_free(bev);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<do_parent_job>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xc65d40,%edi
  call   <usleep@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int do_parent_job() {
  usleep(13 * 1000000L);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<do_parent_job>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc65d40,%edi
  call   <usleep@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_parent_job() {
  usleep(13 * 1000000L);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_parent_job>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc65d40,%edi
  call   <usleep@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_parent_job() {
  usleep(13 * 1000000L);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_parent_job>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc65d40,%edi
  call   <usleep@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_parent_job() {
  usleep(13 * 1000000L);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gridChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L66
  cmpl   $0x1,-0x4(%rbp)
  jg     L71
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L14
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  jmp    L71
L14:
  mov    $0x58,%eax
  jmp    L71
L29:
  mov    $0x20,%eax
  jmp    L71
L66:
  mov    $0x4f,%eax
  jmp    L71
L71:
  pop    %rbp
  ret
```

assistant: ```c
char gridChar(int i) {
  switch (i) {
  case -1:
    return 'X';
  case 0:
    return ' ';
  case 1:
    return 'O';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gridChar>:
  endbr64
  mov    $0x20,%eax
  test   %edi,%edi
  je     L19
  mov    $0x4f,%eax
  cmp    $0x1,%edi
  je     L19
  mov    $0x58,%eax
  cmp    $0xffffffff,%edi
L19:
  ret
```

assistant: ```c
char gridChar(int i) {
  switch (i) {
  case -1:
    return 'X';
  case 0:
    return ' ';
  case 1:
    return 'O';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gridChar>:
  endbr64
  add    $0x1,%edi
  cmp    $0x2,%edi
  ja     L0
  lea    D6(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
char gridChar(int i) {
  switch (i) {
  case -1:
    return 'X';
  case 0:
    return ' ';
  case 1:
    return 'O';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gridChar>:
  endbr64
  add    $0x1,%edi
  cmp    $0x2,%edi
  ja     L2
  lea    D7(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
char gridChar(int i) {
  switch (i) {
  case -1:
    return 'X';
  case 0:
    return ' ';
  case 1:
    return 'O';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L27
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L27:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string
name: read_data
arguments: data_tag: D22
type: string
name: read_data
arguments: data_tag: D27
type: string

tool: D1: error memalign

tool: D22: p = %lu


tool: D27: p size = %ld


assistant: ```c
int main(int argc, char *argv[]) {
  void *p = NULL;
  int err = posix_memalign(&p, 16, 128);
  if (err) {
    printf("error memalign");
    return -1;
  }
  printf("p = %lu\n", p);
  printf("p size = %ld\n", sizeof(p));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    $0x80,%edx
  mov    $0x10,%esi
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L0
  mov    %eax,%ebx
  mov    (%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%ebx
  jmp    L25
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D18
datatype: string

tool: D22: p = %lu


tool: D20: p size = %ld


tool: D18: error memalign

assistant: ```c
int main(int argc, char *argv[]) {
  void *p = NULL;
  int err = posix_memalign(&p, 16, 128);
  if (err) {
    printf("error memalign");
    return -1;
  }
  printf("p = %lu\n", p);
  printf("p size = %ld\n", sizeof(p));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x80,%edx
  mov    $0x10,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L4
  mov    (%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L4:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L16
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string

tool: D0: p = %lu


tool: D12: p size = %ld


tool: D17: error memalign

assistant: ```c
int main(int argc, char *argv[]) {
  void *p = NULL;
  int err = posix_memalign(&p, 16, 128);
  if (err) {
    printf("error memalign");
    return -1;
  }
  printf("p = %lu\n", p);
  printf("p size = %ld\n", sizeof(p));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x80,%edx
  mov    $0x10,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  call   <posix_memalign@plt>
  test   %eax,%eax
  jne    L5
  mov    (%rsp),%rsi
  lea    D2(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L5:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L8
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string

tool: D2: p = %lu


tool: D5: p size = %ld


tool: D3: error memalign

assistant: ```c
int main(int argc, char *argv[]) {
  void *p = NULL;
  int err = posix_memalign(&p, 16, 128);
  if (err) {
    printf("error memalign");
    return -1;
  }
  printf("p = %lu\n", p);
  printf("p size = %ld\n", sizeof(p));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L21:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L5
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L21
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sum_primes(int start, int end) {
  int sum = 0;
  for (int i = start; i <= end; i++)
    if (isPrime(i))
      sum += i;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_primes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %esi,%edi
  jg     L11
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    $0x0,%ebp
L5:
  mov    %ebx,%edi
  call   <isPrime@plt>
  mov    %rax,%rdx
  lea    0x0(%rbp,%rbx,1),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L5
L6:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0x0,%ebp
  jmp    L6
```

assistant: ```c
int sum_primes(int start, int end) {
  int sum = 0;
  for (int i = start; i <= end; i++)
    if (isPrime(i))
      sum += i;
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum_primes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %esi,%edi
  jg     L6
  mov    %edi,%ebx
  mov    %esi,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%edi
  call   <isPrime@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L12
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int sum_primes(int start, int end) {
  int sum = 0;
  for (int i = start; i <= end; i++)
    if (isPrime(i))
      sum += i;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum_primes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %esi,%edi
  jg     L11
  mov    %edi,%ebx
  mov    %esi,%ebp
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%edi
  call   <isPrime@plt>
  mov    %rax,%r8
  lea    (%r12,%rbx,1),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L16
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int sum_primes(int start, int end) {
  int sum = 0;
  for (int i = start; i <= end; i++)
    if (isPrime(i))
      sum += i;
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
L2:
  addq   $0x1,-0x8(%rbp)
  cmpq   $0x3b9aca00,-0x8(%rbp)
  ja     L12
  jmp    L2
L12:
  nop
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned long long i = 0;
  while (1) {
    i++;
    if (i > 1000000000)
      break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x3b9aca01,%eax
L5:
  sub    $0x1,%rax
  jne    L5
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long i = 0;
  while (1) {
    i++;
    if (i > 1000000000)
      break;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long i = 0;
  while (1) {
    i++;
    if (i > 1000000000)
      break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPunctuation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x5f,%eax
  je     L57
  cmp    $0x5f,%eax
  jg     L23
  cmp    $0x2d,%eax
  je     L33
  cmp    $0x3a,%eax
  je     L3
  jmp    L23
L33:
  mov    $0x1,%eax
  jmp    L25
L57:
  mov    $0x1,%eax
  jmp    L25
L3:
  mov    $0x1,%eax
  jmp    L25
L23:
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
bool isPunctuation(const char character) {
  switch (character) {
  case '-':
    return true;
  case '_':
    return true;
  case ':':
    return true;
  default:
    return false;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isPunctuation>:
  endbr64
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L9
  movabs $0x4000000002001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
bool isPunctuation(const char character) {
  switch (character) {
  case '-':
    return true;
  case '_':
    return true;
  case ':':
    return true;
  default:
    return false;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isPunctuation>:
  endbr64
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L7
  movabs $0x4000000002001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPunctuation(const char character) {
  switch (character) {
  case '-':
    return true;
  case '_':
    return true;
  case ':':
    return true;
  default:
    return false;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPunctuation>:
  endbr64
  lea    -0x2d(%rdi),%ecx
  cmp    $0x32,%cl
  ja     L7
  movabs $0x4000000002001,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool isPunctuation(const char character) {
  switch (character) {
  case '-':
    return true;
  case '_':
    return true;
  case ':':
    return true;
  default:
    return false;
  }
}
```