ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  sub    $0x98,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,(%rsp,%rdi,4)
  mov    (%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x98,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  int a[32];
  a[1] = 3;
  a[0] = 1;
  a[i] = 2;
  return a[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  sub    $0x98,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,(%rsp,%rdi,4)
  mov    (%rsp),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x98,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo(int i) {
  int a[32];
  a[1] = 3;
  a[0] = 1;
  a[i] = 2;
  return a[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isEmptyCQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L16
  mov    $0x1,%eax
  jmp    L10
L16:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int isEmptyCQ(int *front, int *rear) {
  if (*front == -1)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isEmptyCQ>:
  endbr64
  cmpl   $0xffffffff,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isEmptyCQ(int *front, int *rear) {
  if (*front == -1)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isEmptyCQ>:
  endbr64
  xor    %eax,%eax
  cmpl   $0xffffffff,(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isEmptyCQ(int *front, int *rear) {
  if (*front == -1)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isEmptyCQ>:
  endbr64
  xor    %eax,%eax
  cmpl   $0xffffffff,(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isEmptyCQ(int *front, int *rear) {
  if (*front == -1)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ti_tema_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ti_tema_start(double const *options) {
  const int period = (int)options[0];
  return (period - 1) * 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ti_tema_start>:
  endbr64
  cvttsd2si (%rdi),%eax
  lea    -0x3(%rax,%rax,2),%eax
  ret
```

assistant: ```c
int ti_tema_start(double const *options) {
  const int period = (int)options[0];
  return (period - 1) * 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ti_tema_start>:
  endbr64
  cvttsd2si (%rdi),%eax
  lea    -0x3(%rax,%rax,2),%eax
  ret
```

assistant: ```c
int ti_tema_start(double const *options) {
  const int period = (int)options[0];
  return (period - 1) * 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ti_tema_start>:
  endbr64
  cvttsd2si (%rdi),%eax
  lea    -0x3(%rax,%rax,2),%eax
  ret
```

assistant: ```c
int ti_tema_start(double const *options) {
  const int period = (int)options[0];
  return (period - 1) * 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<utime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x8c004004,%eax
  mov    (%rax),%eax
  cmp    $0xdeadbeef,%eax
  jne    L6
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xd,%edi
  call   <dcloadsyscall@plt>
  jmp    L19
L6:
  mov    $0xffffffff,%eax
L19:
  leave
  ret
```

assistant: ```c
int utime(const char *path, char *times) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(13, path, times);
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<utime>:
  endbr64
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  jne    L0
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  mov    $0xd,%edi
  call   <dcloadsyscall@plt>
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utime(const char *path, char *times) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(13, path, times);
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utime>:
  endbr64
  mov    $0x8c004004,%eax
  mov    %rsi,%rdx
  cmpl   $0xdeadbeef,(%rax)
  jne    L9
  mov    %rdi,%rsi
  mov    $0xd,%edi
  jmp    1050 <dcloadsyscall@plt>
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utime(const char *path, char *times) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(13, path, times);
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<utime>:
  endbr64
  mov    $0x8c004004,%eax
  mov    %rsi,%rdx
  cmpl   $0xdeadbeef,(%rax)
  jne    L2
  mov    %rdi,%rsi
  mov    $0xd,%edi
  jmp    1050 <dcloadsyscall@plt>
  nopl   0x0(%rax)
L2:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utime(const char *path, char *times) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(13, path, times);
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x14,-0x10(%rbp)
  movl   $0x1e,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d %d %d %d


assistant: ```c
int main() {
  int a, b, i, z;
  a = 20;
  b = 30;
  i = (a++, b + 4);
  z = a--, b + 20;
  printf("%d %d %d %d\n", a, b, i, z);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%r8d
  mov    $0x22,%ecx
  mov    $0x1e,%edx
  mov    $0x14,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %d %d %d %d


assistant: ```c
int main() {
  int a, b, i, z;
  a = 20;
  b = 30;
  i = (a++, b + 4);
  z = a--, b + 20;
  printf("%d %d %d %d\n", a, b, i, z);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%r8d
  mov    $0x22,%ecx
  mov    $0x1e,%edx
  mov    $0x14,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %d %d %d %d


assistant: ```c
int main() {
  int a, b, i, z;
  a = 20;
  b = 30;
  i = (a++, b + 4);
  z = a--, b + 20;
  printf("%d %d %d %d\n", a, b, i, z);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x15,%r8d
  mov    $0x22,%ecx
  mov    $0x1e,%edx
  mov    $0x14,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: %d %d %d %d


assistant: ```c
int main() {
  int a, b, i, z;
  a = 20;
  b = 30;
  i = (a++, b + 4);
  z = a--, b + 20;
  printf("%d %d %d %d\n", a, b, i, z);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s_del>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x28(%rbp),%rbx
  mov    -0x30(%rbp),%r13
  mov    $0x0,%r12d
  jmp    L49
L9:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L49:
  mov    %r12d,%eax
  lea    0x1(%rax),%r12d
  cmp    %eax,-0x34(%rbp)
  jg     L9
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <s_len@plt>
  mov    %eax,%r12d
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,%r12d
  jle    L19
  mov    -0x38(%rbp),%eax
  cltq
  jmp    L47
L19:
  mov    %r12d,%eax
  sub    -0x34(%rbp),%eax
  cltq
L47:
  add    %rax,%rbx
  nop
L22:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    -0x30(%rbp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *s_del(char *from, char *to, int index, int count) {
  register int i;
  register char *f = (char *)from, *t = to;
  for (i = 0; i++ < index; *t++ = *f++)
    ;
  i = s_len(from);
  f += (i > index + count) ? count : i - index;
  while ((*t++ = *f++) != 0)
    ;
  return (to);
}
```
user: What is the c source code of the assembly code below:

```asm
<s_del>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  mov    %ecx,%r12d
  test   %edx,%edx
  jle    L5
  mov    %edx,%ebx
  mov    $0x0,%eax
L39:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L39
  lea    (%rdi,%rbx,1),%r14
  add    %rbp,%rbx
L22:
  call   <s_len@plt>
  lea    0x0(%r13,%r12,1),%ecx
  movslq %r12d,%r12
  mov    %eax,%edx
  sub    %r13d,%edx
  movslq %edx,%rdx
  cmp    %eax,%ecx
  mov    %r12,%rax
  cmovge %rdx,%rax
  lea    (%r14,%rax,1),%rcx
  mov    $0x0,%eax
L33:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L33
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %rsi,%rbx
  mov    %rdi,%r14
  jmp    L22
```

assistant: ```c
char *s_del(char *from, char *to, int index, int count) {
  register int i;
  register char *f = (char *)from, *t = to;
  for (i = 0; i++ < index; *t++ = *f++)
    ;
  i = s_len(from);
  f += (i > index + count) ? count : i - index;
  while ((*t++ = *f++) != 0)
    ;
  return (to);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<s_del>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L13
  movslq %edx,%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L15:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L15
  lea    (%rdi,%rax,1),%rbp
  lea    (%r12,%rax,1),%rbx
L7:
  call   <s_len@plt>
  lea    (%r14,%r13,1),%ecx
  mov    %eax,%edx
  sub    %r14d,%edx
  cmp    %eax,%ecx
  mov    %r13,%rax
  movslq %edx,%rdx
  cmovge %rdx,%rax
  lea    0x0(%rbp,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L25
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rsi,%rbx
  mov    %rdi,%rbp
  jmp    L7
```

assistant: ```c
char *s_del(char *from, char *to, int index, int count) {
  register int i;
  register char *f = (char *)from, *t = to;
  for (i = 0; i++ < index; *t++ = *f++)
    ;
  i = s_len(from);
  f += (i > index + count) ? count : i - index;
  while ((*t++ = *f++) != 0)
    ;
  return (to);
}
```
user: What is the c source code of the assembly code below:

```asm
<s_del>:
  endbr64
  push   %r14
  movslq %ecx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  test   %edx,%edx
  jle    L135
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi),%rcx
  mov    %rsi,%rdx
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L88
  cmp    $0x6,%eax
  jbe    L88
  cmp    $0xe,%eax
  jbe    L80
  mov    %ebp,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
L186:
  movdqu (%rdi,%rax,1),%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L186
  mov    %ebp,%r9d
  mov    %ebp,%ebx
  and    $0xfffffff0,%r9d
  mov    %r9d,%esi
  lea    0x1(%r9),%eax
  lea    (%rdi,%rsi,1),%rcx
  lea    (%r12,%rsi,1),%rdx
  cmp    %r9d,%ebp
  je     L188
  mov    %ebp,%r8d
  sub    %r9d,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L73
L75:
  mov    (%rdi,%rsi,1),%r9
  mov    %ebp,%ebx
  mov    %r9,(%r12,%rsi,1)
  mov    %r8d,%esi
  and    $0xfffffff8,%esi
  mov    %esi,%r9d
  add    %esi,%eax
  add    %r9,%rcx
  add    %r9,%rdx
  cmp    %esi,%r8d
  je     L188
L73:
  movzbl (%rcx),%esi
  mov    %ebp,%ebx
  mov    %sil,(%rdx)
  lea    0x1(%rax),%esi
  cmp    %eax,%ebp
  jle    L188
  movzbl 0x1(%rcx),%r8d
  mov    %r8b,0x1(%rdx)
  lea    0x2(%rax),%r8d
  cmp    %esi,%ebp
  jle    L188
  movzbl 0x2(%rcx),%esi
  mov    %sil,0x2(%rdx)
  lea    0x3(%rax),%esi
  cmp    %r8d,%ebp
  jle    L188
  movzbl 0x3(%rcx),%r8d
  mov    %r8b,0x3(%rdx)
  lea    0x4(%rax),%r8d
  cmp    %esi,%ebp
  jle    L188
  movzbl 0x4(%rcx),%esi
  add    $0x5,%eax
  mov    %sil,0x4(%rdx)
  cmp    %r8d,%ebp
  jle    L188
  movzbl 0x5(%rcx),%esi
  mov    %sil,0x5(%rdx)
  cmp    %eax,%ebp
  jle    L188
  movzbl 0x6(%rcx),%eax
  mov    %al,0x6(%rdx)
L188:
  lea    (%rdi,%rbx,1),%r13
  add    %r12,%rbx
L130:
  call   <s_len@plt>
  lea    0x0(%rbp,%r14,1),%ecx
  mov    %eax,%edx
  sub    %ebp,%edx
  cmp    %eax,%ecx
  mov    %r14,%rax
  movslq %edx,%rdx
  cmovge %rdx,%rax
  lea    0x0(%r13,%rax,1),%rcx
  xor    %eax,%eax
L28:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L28
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  mov    %ebp,%ebx
  xor    %eax,%eax
  nopl   0x0(%rax)
L153:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L153
  jmp    L188
  nopl   0x0(%rax,%rax,1)
L135:
  mov    %rsi,%rbx
  mov    %rdi,%r13
  jmp    L130
L80:
  mov    %rsi,%rdx
  mov    %ebp,%r8d
  mov    %rdi,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L75
```

assistant: ```c
char *s_del(char *from, char *to, int index, int count) {
  register int i;
  register char *f = (char *)from, *t = to;
  for (i = 0; i++ < index; *t++ = *f++)
    ;
  i = s_len(from);
  f += (i > index + count) ? count : i - index;
  while ((*t++ = *f++) != 0)
    ;
  return (to);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L84:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  js     L54
  mov    -0x18(%rbp),%eax
  cmp    $0x7,%eax
  jle    L9
L54:
  mov    $0x1,%eax
  jmp    L93
L9:
  mov    $0x0,%eax
L93:
  mov    %eax,%edx
  and    $0x1,%edx
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L40
  mov    -0x14(%rbp),%eax
  cmp    $0xc8,%eax
  jle    L18
L40:
  mov    $0x1,%eax
  jmp    L36
L18:
  mov    $0x0,%eax
L36:
  and    $0x1,%eax
  and    %edx,%eax
  test   %al,%al
  jne    L84
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L48
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L48:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D32
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D13: %d

tool: D32: 0

tool: D7: 1

assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
    scanf("%d", &b);
  } while ((a < 0 || a > 7) & (b < 0 || b > 200));
  int mask = 1 << a;
  int result = b & mask;
  if (result == 0) {
    printf("0");
  } else
    printf("1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rbx
L9:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%eax
  cmp    $0x7,%ecx
  jbe    L29
  cmp    $0xc8,%eax
  ja     L9
L29:
  mov    $0x1,%edx
  shl    %cl,%edx
  test   %eax,%edx
  jne    L30
  lea    D3(%rip),%rdi
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D8
datatype: string

tool: D10: %d

tool: D3: 0

tool: D8: 1

assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
    scanf("%d", &b);
  } while ((a < 0 || a > 7) & (b < 0 || b > 200));
  int mask = 1 << a;
  int result = b & mask;
  if (result == 0) {
    printf("0");
  } else
    printf("1");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    $0x7,%eax
  jbe    L39
  cmp    $0xc8,%edx
  ja     L49
L39:
  bt     %eax,%edx
  jb     L0
  lea    D28(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D28
data_type: string
name: read_data
arguments: tag: D0
data_type: string

tool: D6: %d

tool: D28: 0

tool: D0: 1

assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
    scanf("%d", &b);
  } while ((a < 0 || a > 7) & (b < 0 || b > 200));
  int mask = 1 << a;
  int result = b & mask;
  if (result == 0) {
    printf("0");
  } else
    printf("1");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%edx
  cmp    $0x7,%eax
  jbe    L21
  cmp    $0xc8,%edx
  ja     L41
L21:
  bt     %eax,%edx
  jb     L9
  lea    D10(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D3: %d

tool: D10: 0

tool: D2: 1

assistant: ```c
int main() {
  int a, b;
  do {
    scanf("%d", &a);
    scanf("%d", &b);
  } while ((a < 0 || a > 7) & (b < 0 || b > 200));
  int mask = 1 << a;
  int result = b & mask;
  if (result == 0) {
    printf("0");
  } else
    printf("1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cmdcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L12
  mov    $0x1,%eax
  jmp    L6
L12:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int cmdcmp(int *a, int *b, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmdcmp>:
  endbr64
  test   %edx,%edx
  jle    L6
  mov    %edx,%edx
  mov    $0x0,%eax
L19:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L25
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmdcmp(int *a, int *b, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmdcmp>:
  endbr64
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L31
  nop
L36:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L12
L31:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L36
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmdcmp(int *a, int *b, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cmdcmp>:
  endbr64
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L24
  nop
L19:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L12
L24:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L19
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cmdcmp(int *a, int *b, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %rdx,-0x8(%rbp)
  nop
L8:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    %rdi,-0x8(%rbp)
  movzbl (%rsi),%esi
  mov    %sil,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(register char *s, register const char *t) {
  char *dest = s;
  while ((*dest++ = *t++))
    ;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L9:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L9
  ret
```

assistant: ```c
char *strcpy(register char *s, register const char *t) {
  char *dest = s;
  while ((*dest++ = *t++))
    ;
  return s;
}
```