ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<error>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    $0x400,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: ERROR: %s


assistant: ```c
void error(const char *fmt, ...) {
  char line[1024];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(line, 1024, fmt, ap);
  va_end(ap);
  printf("ERROR: %s\n", line);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<X509_check_email>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L58
  mov    $0xfffffffe,%eax
  jmp    L45
L58:
  cmpq   $0x0,-0x18(%rbp)
  jne    L39
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L42
L39:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L42
  mov    $0xfffffffe,%eax
  jmp    L45
L42:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <do_x509_check@plt>
L45:
  leave
  ret
```

assistant: ```c
int X509_check_email(X509 *x, const char *chk, size_t chklen, unsigned int flags) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen))
    return -2;
  return do_x509_check(x, chk, chklen, flags, GEN_EMAIL, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<X509_check_email>:
  endbr64
  test   %rsi,%rsi
  je     L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  test   %rdx,%rdx
  jne    L24
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
L34:
  mov    $0x0,%r9d
  mov    D2(%rip),%rax
  mov    (%rax),%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <do_x509_check@plt>
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L34
  mov    $0xfffffffe,%eax
  jmp    L33
L10:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int X509_check_email(X509 *x, const char *chk, size_t chklen, unsigned int flags) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen))
    return -2;
  return do_x509_check(x, chk, chklen, flags, GEN_EMAIL, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<X509_check_email>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  test   %rdx,%rdx
  jne    L1
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
L15:
  mov    D5(%rip),%rax
  mov    %r13d,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %r9d,%r9d
  mov    (%rax),%r8d
  add    $0x10,%rsp
  pop    %rbp
  pop    %r13
  pop    %r14
  jmp    1070 <do_x509_check@plt>
  nop
L1:
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rdx,0x8(%rsp)
  call   <memchr@plt>
  mov    0x8(%rsp),%rdx
  test   %rax,%rax
  je     L15
  add    $0x10,%rsp
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int X509_check_email(X509 *x, const char *chk, size_t chklen, unsigned int flags) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen))
    return -2;
  return do_x509_check(x, chk, chklen, flags, GEN_EMAIL, NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<X509_check_email>:
  endbr64
  test   %rsi,%rsi
  je     L15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  test   %rdx,%rdx
  jne    L21
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
L22:
  mov    D4(%rip),%rax
  mov    %r13d,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %r9d,%r9d
  mov    (%rax),%r8d
  add    $0x10,%rsp
  pop    %rbp
  pop    %r13
  pop    %r14
  jmp    1070 <do_x509_check@plt>
  nop
L21:
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rdx,0x8(%rsp)
  call   <memchr@plt>
  mov    0x8(%rsp),%rdx
  test   %rax,%rax
  je     L22
  add    $0x10,%rsp
  mov    $0xfffffffe,%eax
  pop    %rbp
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int X509_check_email(X509 *x, const char *chk, size_t chklen, unsigned int flags) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen))
    return -2;
  return do_x509_check(x, chk, chklen, flags, GEN_EMAIL, NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %edi,%eax
  mov    %esi,-0x14(%rbp)
  mov    %eax,%r12d
  mov    $0x0,%eax
  mov    -0x14(%rbp),%ebx
  jmp    L7
L10:
  add    %eax,%eax
  mov    %r12d,%edx
  and    $0x1,%edx
  test   %edx,%edx
  je     L2
  add    $0x1,%eax
L2:
  sar    %r12d
  sub    $0x1,%ebx
L7:
  test   %ebx,%ebx
  jg     L10
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int reverse(regs, max)
register int regs;
{
  register int r, i;
  r = regs;
  regs = 0;
  for (i = max; i > 0; i--) {
    regs <<= 1;
    if (r & 1)
      regs++;
    r >>= 1;
  }
  return regs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reverse>:
  endbr64
  test   %esi,%esi
  jle    L15
  mov    $0x0,%eax
L0:
  add    %eax,%eax
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  sub    $0x1,%esi
  jne    L0
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int reverse(regs, max)
register int regs;
{
  register int r, i;
  r = regs;
  regs = 0;
  for (i = max; i > 0; i--) {
    regs <<= 1;
    if (r & 1)
      regs++;
    r >>= 1;
  }
  return regs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L13
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edi,%edx
  add    %eax,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  sub    $0x1,%esi
  jne    L19
  ret
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
int reverse(regs, max)
register int regs;
{
  register int r, i;
  r = regs;
  regs = 0;
  for (i = max; i > 0; i--) {
    regs <<= 1;
    if (r & 1)
      regs++;
    r >>= 1;
  }
  return regs;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L16
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %edi,%edx
  add    %eax,%eax
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  sub    $0x1,%esi
  jne    L18
  ret
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
int reverse(regs, max)
register int regs;
{
  register int r, i;
  r = regs;
  regs = 0;
  for (i = max; i > 0; i--) {
    regs <<= 1;
    if (r & 1)
      regs++;
    r >>= 1;
  }
  return regs;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_hist>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc60,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0xc58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0xc4a(%rsp),%rbp
  mov    %r12,%rbx
L64:
  mov    $0x1a,%edx
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  add    $0x1a,%rbx
  cmp    %rbp,%rbx
  jne    L64
  lea    0x1a(%r12),%rdx
  mov    %r12,%rax
L53:
  movb   $0x2b,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L53
  mov    %r12,%rax
L40:
  movb   $0x2b,(%rax)
  add    $0x1a,%rax
  cmp    %rbp,%rax
  jne    L40
  test   %r14d,%r14d
  jle    L56
  mov    %r13,%rsi
  lea    -0x1(%r14),%eax
  lea    0x4(%r13,%rax,4),%rdi
  mov    %r12,%rcx
L38:
  mov    (%rsi),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x2,%edx
  cmp    $0x7,%eax
  jle    L63
  mov    $0x1,%eax
L94:
  movb   $0x2a,0x1a(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L94
L63:
  add    $0x4,%rsi
  add    $0x1a,%rcx
  cmp    %rdi,%rsi
  jne    L38
L56:
  lea    0xc63(%r12),%rbp
  add    $0xc49,%r12
L5:
  lea    -0xc4a(%rbp),%rbx
L6:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1a,%rbx
  cmp    %rbx,%rbp
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%rbp
  cmp    %rbp,%r12
  jne    L5
  mov    0xc58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0xc60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L98:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_hist(int *data, int nr_data) {
  char plot[120 + 1][25 + 1];
  int i, j, k, nr_dots;
  for (i = 0; i < 120 + 1; i++)
    memset(plot[i], ' ', sizeof(plot[i]));
  for (i = 0; i < 25 + 1; i++)
    plot[0][i] = '+';
  for (i = 0; i < 120 + 1; i++)
    plot[i][0] = '+';
  for (k = 0; k < nr_data; k++) {
    nr_dots = data[k] / (100 / 25);
    for (i = 1; i < nr_dots; i++)
      plot[k + 1][i] = '*';
  }
  for (i = 0; i < 25 + 1; i++) {
    for (j = 0; j < 120 + 1; j++)
      printf("%c", plot[j][25 - i]);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_hist>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0xc4a(%rsp),%rbp
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  mov    $0x1a,%edx
  mov    $0x20,%esi
  add    $0x1a,%rbx
  call   <memset@plt>
  cmp    %rbp,%rbx
  jne    L0
  movabs $0x2b2b2b2b2b2b2b2b,%rax
  movdqa D0(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  mov    $0x2b2b,%eax
  mov    %ax,0x18(%rsp)
  mov    %r12,%rax
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax,%rax,1)
L70:
  movb   $0x2b,(%rax)
  add    $0x1a,%rax
  cmp    %rbp,%rax
  jne    L70
  test   %r13d,%r13d
  jle    L77
  lea    -0x1(%r13),%eax
  lea    0x1b(%rsp),%rcx
  lea    0x4(%r14,%rax,4),%rbp
L51:
  mov    (%r14),%edx
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    $0x7,%edx
  jle    L29
  lea    -0x2(%rax),%edx
  mov    %rcx,%rdi
  mov    $0x2a,%esi
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
L29:
  add    $0x4,%r14
  add    $0x1a,%rcx
  cmp    %rbp,%r14
  jne    L51
L77:
  lea    0xc63(%r12),%rbp
  add    $0xc49,%r12
L15:
  lea    -0xc4a(%rbp),%rbx
  nopl   0x0(%rax)
L35:
  movsbl (%rbx),%edi
  add    $0x1a,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L35
  mov    $0xa,%edi
  sub    $0x1,%rbp
  call   <putchar@plt>
  cmp    %r12,%rbp
  jne    L15
  mov    0xc58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0xc60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: byte[16]

tool: {"D0": [0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b]}

assistant: ```c
void print_hist(int *data, int nr_data) {
  char plot[120 + 1][25 + 1];
  int i, j, k, nr_dots;
  for (i = 0; i < 120 + 1; i++)
    memset(plot[i], ' ', sizeof(plot[i]));
  for (i = 0; i < 25 + 1; i++)
    plot[0][i] = '+';
  for (i = 0; i < 120 + 1; i++)
    plot[i][0] = '+';
  for (k = 0; k < nr_data; k++) {
    nr_dots = data[k] / (100 / 25);
    for (i = 1; i < nr_dots; i++)
      plot[k + 1][i] = '*';
  }
  for (i = 0; i < 25 + 1; i++) {
    for (j = 0; j < 120 + 1; j++)
      printf("%c", plot[j][25 - i]);
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_hist>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0xc4a(%rsp),%rbp
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %rbx,%rdi
  mov    $0x1a,%edx
  mov    $0x20,%esi
  add    $0x1a,%rbx
  call   <memset@plt>
  cmp    %rbp,%rbx
  jne    L70
  movabs $0x2b2b2b2b2b2b2b2b,%rax
  movdqa D6(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  mov    $0x2b2b,%eax
  mov    %ax,0x18(%rsp)
  mov    %r12,%rax
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax,%rax,1)
L45:
  movb   $0x2b,(%rax)
  add    $0x1a,%rax
  cmp    %rbp,%rax
  jne    L45
  test   %r13d,%r13d
  jle    L66
  lea    -0x1(%r13),%eax
  lea    0x1b(%rsp),%rcx
  lea    0x4(%r14,%rax,4),%rbp
L75:
  mov    (%r14),%edx
  test   %edx,%edx
  lea    0x3(%rdx),%eax
  cmovns %edx,%eax
  sar    $0x2,%eax
  cmp    $0x7,%edx
  jle    L36
  lea    -0x2(%rax),%edx
  mov    %rcx,%rdi
  mov    $0x2a,%esi
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
L36:
  add    $0x4,%r14
  add    $0x1a,%rcx
  cmp    %rbp,%r14
  jne    L75
L66:
  lea    0xc63(%r12),%rbp
  add    $0xc49,%r12
L43:
  lea    -0xc4a(%rbp),%rbx
  nopl   0x0(%rax)
L54:
  movsbl (%rbx),%edi
  add    $0x1a,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L54
  mov    $0xa,%edi
  sub    $0x1,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r12
  jne    L43
  mov    0xc58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0xc60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: byte[16]

tool: {"D6": [0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b,0x2b]}

assistant: ```c
void print_hist(int *data, int nr_data) {
  char plot[120 + 1][25 + 1];
  int i, j, k, nr_dots;
  for (i = 0; i < 120 + 1; i++)
    memset(plot[i], ' ', sizeof(plot[i]));
  for (i = 0; i < 25 + 1; i++)
    plot[0][i] = '+';
  for (i = 0; i < 120 + 1; i++)
    plot[i][0] = '+';
  for (k = 0; k < nr_data; k++) {
    nr_dots = data[k] / (100 / 25);
    for (i = 1; i < nr_dots; i++)
      plot[k + 1][i] = '*';
  }
  for (i = 0; i < 25 + 1; i++) {
    for (j = 0; j < 120 + 1; j++)
      printf("%c", plot[j][25 - i]);
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<serveBMP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D50(%rip),%rbx
  mov    %rbx,%rsi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %r13d,%edi
  call   <writeHeader@plt>
  mov    D12(%rip),%rax
  mov    %rax,(%rsp)
  movsd  D77(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    $0x200,%r15d
  movq   %xmm0,%r12
  mov    %rsp,%r14
L25:
  mov    $0x200,%ebp
  mov    D12(%rip),%rbx
L9:
  mov    $0x0,%edx
  movq   %r12,%xmm1
  movq   %rbx,%xmm0
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <calcPoint@plt>
  movq   %rbx,%xmm2
  addsd  D53(%rip),%xmm2
  movq   %xmm2,%rbx
  movsd  %xmm2,(%rsp)
  sub    $0x1,%ebp
  jne    L9
  movq   %r12,%xmm3
  addsd  D53(%rip),%xmm3
  movq   %xmm3,%r12
  mov    D12(%rip),%rax
  mov    %rax,(%rsp)
  movsd  %xmm3,0x8(%rsp)
  sub    $0x1,%r15d
  jne    L25
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D50
type: string
name: parse_data
arguments: data_label: D59
type: string
name: parse_data
arguments: data_label: D12
type: byte[8]
name: parse_data
arguments: data_label: D77
type: byte[8]
name: parse_data
arguments: data_label: D53
type: byte[8]

tool: D50: HTTP/1.0 200 OK
Content-Type: image/bmp



tool: D59: about to send=> %s


tool: {"D12": [0x50,0x1b,0xe8,0xb4,0x81,0x4e,0xbb,0x3f]}

tool: {"D77": [0x74,0xda,0x40,0xa7,0x0d,0x74,0xe2,0x3f]}

tool: {"D53": [0x11,0x11,0x11,0x11,0x11,0x11,0x21,0x3f]}

assistant: ```c
void serveBMP(int socket) {
  char *message;
  message = "HTTP/1.0 200 OK\r\n"
            "Content-Type: image/bmp\r\n"
            "\r\n";
  printf("about to send=> %s\n", message);
  write(socket, message, strlen(message));
  writeHeader(socket);
  double x = 0.14;
  double y = 0.61;
  double zoom = 60.0;
  double zoom_x = x - 2.0 / zoom;
  double zoom_y = y - 2.0 / zoom;
  double seed[2] = {zoom_x, zoom_y};
  while (zoom_y < (y - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
    while (zoom_x < (x - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
      calcPoint(socket, seed, zoom_x, zoom_y, 0);
      zoom_x = zoom_x + 2.0 / zoom / 256.0;
      seed[0] = zoom_x;
    }
    zoom_y = zoom_y + 2.0 / zoom / 256.0;
    zoom_x = x - 2.0 / zoom;
    seed[0] = zoom_x;
    seed[1] = zoom_y;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<serveBMP>:
  endbr64
  push   %r13
  mov    $0x200,%r13d
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %edi,%ebp
  lea    D42(%rip),%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x10(%rsp),%r12
  mov    %eax,%edx
  call   <write@plt>
  mov    %ebp,%edi
  call   <writeHeader@plt>
  mov    D64(%rip),%rax
  movsd  D51(%rip),%xmm1
  mov    %rax,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
L29:
  mov    D64(%rip),%rax
  mov    $0x200,%ebx
  movq   %rax,%xmm0
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <calcPoint@plt>
  movsd  (%rsp),%xmm0
  sub    $0x1,%ebx
  addsd  D59(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  jne    L10
  addsd  D59(%rip),%xmm1
  mov    D64(%rip),%rax
  mov    %rax,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  sub    $0x1,%r13d
  jne    L29
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string
name: retrieve_data
arguments: data_label: D42
type: string
name: retrieve_data
arguments: data_label: D64
type: byte[8]
name: retrieve_data
arguments: data_label: D51
type: byte[8]
name: retrieve_data
arguments: data_label: D59
type: byte[8]

tool: D9: HTTP/1.0 200 OK
Content-Type: image/bmp



tool: D42: about to send=> %s


tool: {"D64": [0x50,0x1b,0xe8,0xb4,0x81,0x4e,0xbb,0x3f]}

tool: {"D51": [0x74,0xda,0x40,0xa7,0x0d,0x74,0xe2,0x3f]}

tool: {"D59": [0x11,0x11,0x11,0x11,0x11,0x11,0x21,0x3f]}

assistant: ```c
void serveBMP(int socket) {
  char *message;
  message = "HTTP/1.0 200 OK\r\n"
            "Content-Type: image/bmp\r\n"
            "\r\n";
  printf("about to send=> %s\n", message);
  write(socket, message, strlen(message));
  writeHeader(socket);
  double x = 0.14;
  double y = 0.61;
  double zoom = 60.0;
  double zoom_x = x - 2.0 / zoom;
  double zoom_y = y - 2.0 / zoom;
  double seed[2] = {zoom_x, zoom_y};
  while (zoom_y < (y - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
    while (zoom_x < (x - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
      calcPoint(socket, seed, zoom_x, zoom_y, 0);
      zoom_x = zoom_x + 2.0 / zoom / 256.0;
      seed[0] = zoom_x;
    }
    zoom_y = zoom_y + 2.0 / zoom / 256.0;
    zoom_x = x - 2.0 / zoom;
    seed[0] = zoom_x;
    seed[1] = zoom_y;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<serveBMP>:
  endbr64
  push   %r13
  mov    $0x200,%r13d
  push   %r12
  lea    D59(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %edi,%ebp
  lea    D43(%rip),%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  lea    0x10(%rsp),%r12
  mov    %eax,%edx
  call   <write@plt>
  mov    %ebp,%edi
  call   <writeHeader@plt>
  movapd D75(%rip),%xmm0
  movsd  D78(%rip),%xmm1
  movaps %xmm0,0x10(%rsp)
L25:
  mov    D75(%rip),%rax
  mov    $0x200,%ebx
  movq   %rax,%xmm0
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %edx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  call   <calcPoint@plt>
  movsd  (%rsp),%xmm0
  sub    $0x1,%ebx
  addsd  D36(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x10(%rsp)
  jne    L27
  addsd  D36(%rip),%xmm1
  mov    D75(%rip),%rax
  mov    %rax,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  sub    $0x1,%r13d
  jne    L25
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D59
datatype: string
name: unpack_data
arguments: data_label: D43
datatype: string
name: unpack_data
arguments: data_label: D75
datatype: byte[16]
name: unpack_data
arguments: data_label: D78
datatype: byte[8]
name: unpack_data
arguments: data_label: D36
datatype: byte[8]

tool: D59: HTTP/1.0 200 OK
Content-Type: image/bmp



tool: D43: about to send=> %s


tool: {"D75": [0x50,0x1b,0xe8,0xb4,0x81,0x4e,0xbb,0x3f,0x74,0xda,0x40,0xa7,0x0d,0x74,0xe2,0x3f]}

tool: {"D78": [0x74,0xda,0x40,0xa7,0x0d,0x74,0xe2,0x3f]}

tool: {"D36": [0x11,0x11,0x11,0x11,0x11,0x11,0x21,0x3f]}

assistant: ```c
void serveBMP(int socket) {
  char *message;
  message = "HTTP/1.0 200 OK\r\n"
            "Content-Type: image/bmp\r\n"
            "\r\n";
  printf("about to send=> %s\n", message);
  write(socket, message, strlen(message));
  writeHeader(socket);
  double x = 0.14;
  double y = 0.61;
  double zoom = 60.0;
  double zoom_x = x - 2.0 / zoom;
  double zoom_y = y - 2.0 / zoom;
  double seed[2] = {zoom_x, zoom_y};
  while (zoom_y < (y - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
    while (zoom_x < (x - 2.0 / zoom + 511 * (2.0 / zoom / 256.0))) {
      calcPoint(socket, seed, zoom_x, zoom_y, 0);
      zoom_x = zoom_x + 2.0 / zoom / 256.0;
      seed[0] = zoom_x;
    }
    zoom_y = zoom_y + 2.0 / zoom / 256.0;
    zoom_x = x - 2.0 / zoom;
    seed[0] = zoom_x;
    seed[1] = zoom_y;
  }
}
```