ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  cmp    $0x3,%edi
  je     L62
L42:
  lea    0x120(%rsp),%rbp
  lea    0x20(%rsp),%rbx
  xor    %r14d,%r14d
  mov    $0x1,%r15d
  mov    %rbp,%rdi
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r12
  call   <Aones@plt>
  mov    0x1c(%rsp),%edx
  mov    0x18(%rsp),%esi
  mov    %rbx,%rdi
  call   <M_init@plt>
  nopl   0x0(%rax)
L22:
  add    $0x1,%r14d
  cmp    $0x3f,%r15d
  jg     L89
  xchg   %ax,%ax
L85:
  mov    %r15d,%esi
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <move@plt>
  mov    %eax,%r15d
  cmp    $0x3f,%eax
  jle    L85
  mov    %rbx,%rdi
  call   <printb@plt>
  mov    %r14d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  cmp    $0x40,%r15d
  jne    L22
  nopl   0x0(%rax)
L37:
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <move@plt>
  mov    %eax,%r15d
  cmp    $0x40,%eax
  je     L37
  test   %eax,%eax
  jne    L22
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x238,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L89:
  mov    %rbx,%rdi
  call   <printb@plt>
  mov    %r14d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L62:
  mov    0x8(%rsi),%rdi
  mov    %rsi,0x8(%rsp)
  call   <atoi@plt>
  mov    0x8(%rsp),%rsi
  sub    $0x1,%eax
  mov    0x10(%rsi),%rdi
  mov    %eax,0x18(%rsp)
  call   <atoi@plt>
  sub    $0x1,%eax
  mov    %eax,0x1c(%rsp)
  jmp    L42
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_infered: string

tool: D16: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int m = 0, n = 0;
  int mvnum = 1, i = 0;
  int M[8][8], mvchoice[(8) * (8) + 1];
  if (argc == 3)
    m = atoi(argv[1]) - 1, n = atoi(argv[2]) - 1;
  Aones(mvchoice);
  M_init(M, m, n);
  while (mvnum) {
    while (mvnum < (8) * (8))
      mvnum = move(M, mvnum, mvchoice, &m, &n);
    printb(M);
    printf("%d\n", ++i);
    while (mvnum == (8) * (8))
      mvnum = move(M, mvnum, mvchoice, &m, &n);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x238,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x228(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  cmp    $0x3,%edi
  je     L51
L62:
  lea    0x120(%rsp),%rbp
  lea    0x20(%rsp),%rbx
  xor    %r14d,%r14d
  mov    %rbp,%rdi
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r12
  call   <Aones@plt>
  mov    0x1c(%rsp),%edx
  mov    0x18(%rsp),%esi
  mov    %rbx,%rdi
  lea    D1(%rip),%r15
  call   <M_init@plt>
  mov    $0x1,%r9d
L54:
  add    $0x1,%r14d
  cmp    $0x3f,%r9d
  jg     L40
  xchg   %ax,%ax
L66:
  mov    %r9d,%esi
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <move@plt>
  mov    %eax,%r9d
  cmp    $0x3f,%eax
  jle    L66
  mov    %rbx,%rdi
  mov    %eax,0x8(%rsp)
  call   <printb@plt>
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%r9d
  cmp    $0x40,%r9d
  jne    L54
  xchg   %ax,%ax
L7:
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    $0x40,%esi
  mov    %rbx,%rdi
  call   <move@plt>
  mov    %eax,%r9d
  cmp    $0x40,%eax
  je     L7
  test   %eax,%eax
  jne    L54
  mov    0x228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x238,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  mov    %rbx,%rdi
  call   <printb@plt>
  mov    %r14d,%esi
  mov    %r15,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  jmp    L40
L51:
  mov    0x8(%rsi),%rdi
  mov    %rsi,0x8(%rsp)
  call   <atoi@plt>
  mov    0x8(%rsp),%rsi
  sub    $0x1,%eax
  mov    0x10(%rsi),%rdi
  mov    %eax,0x18(%rsp)
  call   <atoi@plt>
  sub    $0x1,%eax
  mov    %eax,0x1c(%rsp)
  jmp    L62
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int m = 0, n = 0;
  int mvnum = 1, i = 0;
  int M[8][8], mvchoice[(8) * (8) + 1];
  if (argc == 3)
    m = atoi(argv[1]) - 1, n = atoi(argv[2]) - 1;
  Aones(mvchoice);
  M_init(M, m, n);
  while (mvnum) {
    while (mvnum < (8) * (8))
      mvnum = move(M, mvnum, mvchoice, &m, &n);
    printb(M);
    printf("%d\n", ++i);
    while (mvnum == (8) * (8))
      mvnum = move(M, mvnum, mvchoice, &m, &n);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: readdir: not implemented

assistant: ```c
struct dirent *readdir(DIR *dirp) {
  (void)dirp;
  puts("readdir: not implemented");
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readdir>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: readdir: not implemented

assistant: ```c
struct dirent *readdir(DIR *dirp) {
  (void)dirp;
  puts("readdir: not implemented");
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readdir>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0: readdir: not implemented

assistant: ```c
struct dirent *readdir(DIR *dirp) {
  (void)dirp;
  puts("readdir: not implemented");
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readdir>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: readdir: not implemented

assistant: ```c
struct dirent *readdir(DIR *dirp) {
  (void)dirp;
  puts("readdir: not implemented");
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
L4:
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L4
```

assistant: ```c
int main(int argc, char const *argv[]) {
  do {
    int a = 1;
    int b = 2;
  } while (1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
L3:
  jmp    L3
```

assistant: ```c
int main(int argc, char const *argv[]) {
  do {
    int a = 1;
    int b = 2;
  } while (1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
int main(int argc, char const *argv[]) {
  do {
    int a = 1;
    int b = 2;
  } while (1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
int main(int argc, char const *argv[]) {
  do {
    int a = 1;
    int b = 2;
  } while (1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_counted_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_short@plt>
  test   %rax,%rax
  jne    L46
  mov    $0x0,%eax
  jmp    L57
L46:
  movzwl -0x12(%rbp),%eax
  test   %ax,%ax
  jne    L86
  movq   $0x0,-0x10(%rbp)
  jmp    L61
L86:
  movzwl -0x12(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L57
L32:
  movzwl -0x12(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl -0x12(%rbp),%edx
  cmp    %dx,%ax
  je     L61
  movzwl -0x12(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L57
L61:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  movzwl -0x12(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %dx,(%rax)
  mov    $0x1,%eax
L57:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int read_counted_string(unsigned short *countp, char **stringp, FILE *file) {
  unsigned short len;
  char *data;
  if (read_short(&len, file) == 0)
    return 0;
  if (len == 0) {
    data = NULL;
  } else {
    data = malloc((unsigned)len);
    if (!data)
      return 0;
    if (fread(data, sizeof(char), len, file) != len) {
      bzero(data, len);
      free(data);
      return 0;
    }
  }
  *stringp = data;
  *countp = len;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_counted_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    %rdx,%rsi
  call   <read_short@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L51
  movzwl 0x6(%rsp),%edi
  mov    $0x0,%r13d
  test   %di,%di
  jne    L57
L42:
  mov    %r13,(%r12)
  movzwl 0x6(%rsp),%eax
  mov    %ax,0x0(%rbp)
  mov    $0x1,%eax
L51:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L57:
  movzwl %di,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%eax
  test   %r13,%r13
  je     L51
  movzwl 0x6(%rsp),%edx
  mov    %rbx,%rcx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fread@plt>
  movzwl 0x6(%rsp),%esi
  cmp    %si,%ax
  je     L42
  movzwl %si,%esi
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L51
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_counted_string(unsigned short *countp, char **stringp, FILE *file) {
  unsigned short len;
  char *data;
  if (read_short(&len, file) == 0)
    return 0;
  if (len == 0) {
    data = NULL;
  } else {
    data = malloc((unsigned)len);
    if (!data)
      return 0;
    if (fread(data, sizeof(char), len, file) != len) {
      bzero(data, len);
      free(data);
      return 0;
    }
  }
  *stringp = data;
  *countp = len;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_counted_string>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <read_short@plt>
  test   %rax,%rax
  je     L58
  movzwl 0x6(%rsp),%esi
  xor    %r13d,%r13d
  test   %si,%si
  jne    L35
L16:
  mov    %r13,0x0(%rbp)
  mov    $0x1,%eax
  mov    %si,(%rbx)
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L35:
  movzwl %si,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L58
  movzwl 0x6(%rsp),%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl 0x6(%rsp),%esi
  cmp    %si,%ax
  je     L16
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r13,%rdi
  call   <free@plt>
  nop
L58:
  xor    %eax,%eax
  jmp    L38
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_counted_string(unsigned short *countp, char **stringp, FILE *file) {
  unsigned short len;
  char *data;
  if (read_short(&len, file) == 0)
    return 0;
  if (len == 0) {
    data = NULL;
  } else {
    data = malloc((unsigned)len);
    if (!data)
      return 0;
    if (fread(data, sizeof(char), len, file) != len) {
      bzero(data, len);
      free(data);
      return 0;
    }
  }
  *stringp = data;
  *countp = len;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_counted_string>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <read_short@plt>
  test   %rax,%rax
  je     L31
  movzwl 0x6(%rsp),%esi
  xor    %r13d,%r13d
  test   %si,%si
  jne    L12
L41:
  mov    %r13,0x0(%rbp)
  mov    $0x1,%eax
  mov    %si,(%rbx)
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  movzwl %si,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L31
  movzwl 0x6(%rsp),%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  mov    %rax,%rdi
  call   <fread@plt>
  movzwl 0x6(%rsp),%esi
  cmp    %si,%ax
  je     L41
  mov    %r13,%rdi
  call   <bzero@plt>
  mov    %r13,%rdi
  call   <free@plt>
  nop
L31:
  xor    %eax,%eax
  jmp    L44
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_counted_string(unsigned short *countp, char **stringp, FILE *file) {
  unsigned short len;
  char *data;
  if (read_short(&len, file) == 0)
    return 0;
  if (len == 0) {
    data = NULL;
  } else {
    data = malloc((unsigned)len);
    if (!data)
      return 0;
    if (fread(data, sizeof(char), len, file) != len) {
      bzero(data, len);
      free(data);
      return 0;
    }
  }
  *stringp = data;
  *countp = len;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<jksengine_bind_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L11
  mov    -0x10(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  jmp    L23
L11:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <jksengine_bind@plt>
L23:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: JKSEngine

assistant: ```c
int jksengine_bind_helper(ENGINE *e, const char *id) {
  ;
  if (id && (strcmp(id, "JKSEngine") != 0))
    return (0);
  return jksengine_bind(e);
}
```
user: What is the c source code of the assembly code below?

```asm
<jksengine_bind_helper>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L0
  mov    %rsi,%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L15
L0:
  mov    %rbx,%rdi
  call   <jksengine_bind@plt>
L15:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: JKSEngine

assistant: ```c
int jksengine_bind_helper(ENGINE *e, const char *id) {
  ;
  if (id && (strcmp(id, "JKSEngine") != 0))
    return (0);
  return jksengine_bind(e);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jksengine_bind_helper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L2
  mov    %rsi,%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
L2:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <jksengine_bind@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: JKSEngine

assistant: ```c
int jksengine_bind_helper(ENGINE *e, const char *id) {
  ;
  if (id && (strcmp(id, "JKSEngine") != 0))
    return (0);
  return jksengine_bind(e);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<jksengine_bind_helper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L5
  mov    %rsi,%rdi
  lea    D6(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L9
L5:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <jksengine_bind@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: JKSEngine

assistant: ```c
int jksengine_bind_helper(ENGINE *e, const char *id) {
  ;
  if (id && (strcmp(id, "JKSEngine") != 0))
    return (0);
  return jksengine_bind(e);
}
```
user: What is the c source code of the assembly code below?

```asm
<dofmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  movsd  %xmm0,-0x430(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x428(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L1
L17:
  mov    -0x430(%rbp),%rcx
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x418(%rbp)
  lea    -0x410(%rbp),%rdx
  mov    -0x418(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  mov    -0x418(%rbp),%rax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
char *dofmt(char *fmtstr, double v) {
  char buff[1024];
  char *p;
  if (!fmtstr)
    return (0);
  (void)sprintf(buff, fmtstr, v);
  p = xmalloc((unsigned)(strlen(buff) + 1));
  (void)strcpy(p, buff);
  xfree(fmtstr);
  return (p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dofmt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L24
  mov    %rsp,%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <xfree@plt>
L7:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %rbp,%rax
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    %rdi,%rbp
  jmp    L7
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dofmt(char *fmtstr, double v) {
  char buff[1024];
  char *p;
  if (!fmtstr)
    return (0);
  (void)sprintf(buff, fmtstr, v);
  p = xmalloc((unsigned)(strlen(buff) + 1));
  (void)strcpy(p, buff);
  xfree(fmtstr);
  return (p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dofmt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L23
  mov    %rsp,%r13
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <xmalloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <xfree@plt>
L6:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x410,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %r12d,%r12d
  jmp    L6
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dofmt(char *fmtstr, double v) {
  char buff[1024];
  char *p;
  if (!fmtstr)
    return (0);
  (void)sprintf(buff, fmtstr, v);
  p = xmalloc((unsigned)(strlen(buff) + 1));
  (void)strcpy(p, buff);
  xfree(fmtstr);
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dofmt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L10
  mov    %rsp,%r13
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <xmalloc@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <xfree@plt>
L8:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x410,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r12d,%r12d
  jmp    L8
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *dofmt(char *fmtstr, double v) {
  char buff[1024];
  char *p;
  if (!fmtstr)
    return (0);
  (void)sprintf(buff, fmtstr, v);
  p = xmalloc((unsigned)(strlen(buff) + 1));
  (void)strcpy(p, buff);
  xfree(fmtstr);
  return (p);
}
```