ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<parse_npt>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  lea    D29(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L53
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L103
  lea    0x14(%rsp),%rdx
  lea    D74(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sscanf@plt>
  movsd  D81(%rip),%xmm0
  cmp    $0x1,%eax
  je     L56
L92:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x20,%rsp
  pop    %rbx
  ret
L103:
  movl   $0x0,0xc(%rsp)
L113:
  movsd  D81(%rip),%xmm0
  cmpl   $0x3b,0x10(%rsp)
  ja     L92
  movss  0x14(%rsp),%xmm1
  comiss D31(%rip),%xmm1
  jae    L92
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L36
L98:
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0xc(%rsp),%xmm0
  mulsd  D69(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x10(%rsp),%xmm1
  mulsd  D1(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  jmp    L92
L56:
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  jmp    L98
L53:
  movsd  D81(%rip),%xmm0
  cmpl   $0x0,0xc(%rsp)
  jns    L113
  jmp    L92
L36:
  movsd  D81(%rip),%xmm0
  jmp    L92
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D74
type_infered: string
name: read_data
arguments: data_tag: D81
type_infered: byte[8]
name: read_data
arguments: data_tag: D31
type_infered: f32
name: read_data
arguments: data_tag: D69
type_infered: f64
name: read_data
arguments: data_tag: D1
type_infered: byte[8]

tool: D29: %d:%d:%f

tool: D4: %d:%f

tool: D74: %f

tool: {"D81": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D31: 60

tool: D69: 3600

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

assistant: ```c
double parse_npt(const char *str) {
  int h = 0, m = 0, n;
  float s;
  double result;
  n = sscanf(str, "%d:%d:%f", &h, &m, &s);
  if (n == 3) {
    goto done;
  }
  n = sscanf(str, "%d:%f", &m, &s);
  if (n == 2) {
    h = 0;
    goto done;
  }
  n = sscanf(str, "%f", &s);
  if (n == 1) {
    h = 0;
    m = 0;
    goto sec_only;
  }
  return -1.0;
done:
  if (h < 0)
    return -1;
  if (m > 59 || m < 0)
    return -1;
  if (s >= 60.0 || s < 0)
    return -1;
sec_only:
  result = ((h * 3600.0) + (m * 60.0) + s);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_npt>:
  endbr64
  push   %r13
  lea    D12(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    %r12,%r8
  mov    %r13,%rcx
  movl   $0x0,0x10(%rsp)
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L82
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L15
  xor    %eax,%eax
  mov    %r12,%rdx
  lea    D62(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L54
L3:
  movsd  D2(%rip),%xmm0
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  movl   $0x0,0xc(%rsp)
L79:
  mov    0x10(%rsp),%eax
  cmp    $0x3b,%eax
  ja     L3
  movss  0x14(%rsp),%xmm0
  comiss D22(%rip),%xmm0
  jae    L3
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L3
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl 0xc(%rsp),%xmm1
  mulsd  D4(%rip),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  D21(%rip),%xmm2
  addsd  %xmm2,%xmm1
L77:
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  jmp    L41
  nopl   0x0(%rax)
L82:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L79
  jmp    L3
  nopl   (%rax)
L54:
  movss  0x14(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  jmp    L77
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D62
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: byte[8]
name: unpack_data
arguments: label: D22
type_guessed: f32
name: unpack_data
arguments: label: D4
type_guessed: f64
name: unpack_data
arguments: label: D21
type_guessed: byte[8]

tool: D12: %d:%d:%f

tool: D7: %d:%f

tool: D62: %f

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D22: 60

tool: D4: 3600

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

assistant: ```c
double parse_npt(const char *str) {
  int h = 0, m = 0, n;
  float s;
  double result;
  n = sscanf(str, "%d:%d:%f", &h, &m, &s);
  if (n == 3) {
    goto done;
  }
  n = sscanf(str, "%d:%f", &m, &s);
  if (n == 2) {
    h = 0;
    goto done;
  }
  n = sscanf(str, "%f", &s);
  if (n == 1) {
    h = 0;
    m = 0;
    goto sec_only;
  }
  return -1.0;
done:
  if (h < 0)
    return -1;
  if (m > 59 || m < 0)
    return -1;
  if (s >= 60.0 || s < 0)
    return -1;
sec_only:
  result = ((h * 3600.0) + (m * 60.0) + s);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_npt>:
  endbr64
  push   %r13
  lea    D1(%rip),%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r12
  lea    0x10(%rsp),%r13
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    %r12,%r8
  mov    %r13,%rcx
  movl   $0x0,0x10(%rsp)
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L81
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D21(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L82
  xor    %eax,%eax
  mov    %r12,%rdx
  lea    D46(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L28
L6:
  movsd  D26(%rip),%xmm0
L70:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L82:
  movl   $0x0,0xc(%rsp)
  xor    %eax,%eax
L15:
  mov    0x10(%rsp),%edx
  cmp    $0x3b,%edx
  ja     L6
  movss  0x14(%rsp),%xmm0
  comiss D5(%rip),%xmm0
  jae    L6
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L6
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm1
  mulsd  D40(%rip),%xmm1
  cvtsi2sd %edx,%xmm2
  mulsd  D32(%rip),%xmm2
  addsd  %xmm2,%xmm1
L19:
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  jmp    L70
  nopl   0x0(%rax)
L81:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L15
  jmp    L6
  nopl   (%rax)
L28:
  movss  0x14(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  jmp    L19
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D46
type: string
name: extract_symbolic_data
arguments: data_tag: D26
type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D5
type: f32
name: extract_symbolic_data
arguments: data_tag: D40
type: f64
name: extract_symbolic_data
arguments: data_tag: D32
type: byte[8]

tool: D1: %d:%d:%f

tool: D21: %d:%f

tool: D46: %f

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D5: 60

tool: D40: 3600

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x4e,0x40]}

assistant: ```c
double parse_npt(const char *str) {
  int h = 0, m = 0, n;
  float s;
  double result;
  n = sscanf(str, "%d:%d:%f", &h, &m, &s);
  if (n == 3) {
    goto done;
  }
  n = sscanf(str, "%d:%f", &m, &s);
  if (n == 2) {
    h = 0;
    goto done;
  }
  n = sscanf(str, "%f", &s);
  if (n == 1) {
    h = 0;
    m = 0;
    goto sec_only;
  }
  return -1.0;
done:
  if (h < 0)
    return -1;
  if (m > 59 || m < 0)
    return -1;
  if (s >= 60.0 || s < 0)
    return -1;
sec_only:
  result = ((h * 3600.0) + (m * 60.0) + s);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<out2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <writeop@plt>
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <wrc@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <wrn@plt>
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <wrc@plt>
  nop
  leave
  ret
```

assistant: ```c
void out2(x, y) {
  writeop(x);
  wrc(' ');
  wrn(y);
  wrc(' ');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<out2>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <writeop@plt>
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <wrc@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <wrn@plt>
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <wrc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void out2(x, y) {
  writeop(x);
  wrc(' ');
  wrn(y);
  wrc(' ');
}
```
user: Translate the below assembly code into C programming language:

```asm
<out2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <writeop@plt>
  mov    $0x20,%edi
  xor    %eax,%eax
  call   <wrc@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <wrn@plt>
  mov    $0x20,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <wrc@plt>
```

assistant: ```c
void out2(x, y) {
  writeop(x);
  wrc(' ');
  wrn(y);
  wrc(' ');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<out2>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  call   <writeop@plt>
  mov    $0x20,%edi
  xor    %eax,%eax
  call   <wrc@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <wrn@plt>
  mov    $0x20,%edi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <wrc@plt>
```

assistant: ```c
void out2(x, y) {
  writeop(x);
  wrc(' ');
  wrn(y);
  wrc(' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L42:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    $0x0,%eax
  jmp    L5
L52:
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L42
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L16
  mov    $0xffffffff,%eax
  jmp    L5
L16:
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(char *str1, char *str2) {
  int i;
  for (i = 0; str1[i] == str2[i]; i++)
    if (str1[i] == '\0' && str2[i] == '\0')
      return 0;
  if (str1[i] < str2[i])
    return -1;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  cmp    %cl,%al
  jne    L29
  mov    $0x1,%edx
L5:
  or     %cl,%al
  je     L21
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  je     L5
L29:
  cmp    %cl,%al
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
L21:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strcmp(char *str1, char *str2) {
  int i;
  for (i = 0; str1[i] == str2[i]; i++)
    if (str1[i] == '\0' && str2[i] == '\0')
      return 0;
  if (str1[i] < str2[i])
    return -1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L22
  mov    $0x1,%eax
  jmp    L28
  nopl   (%rax)
L1:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L22
L28:
  test   %dl,%dl
  jne    L1
  xor    %eax,%eax
  ret
L22:
  xor    %eax,%eax
  cmp    %cl,%dl
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int strcmp(char *str1, char *str2) {
  int i;
  for (i = 0; str1[i] == str2[i]; i++)
    if (str1[i] == '\0' && str2[i] == '\0')
      return 0;
  if (str1[i] < str2[i])
    return -1;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L8
  mov    $0x1,%eax
  jmp    L36
  nopl   (%rax)
L39:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L8
L36:
  test   %dl,%dl
  jne    L39
  xor    %eax,%eax
  ret
L8:
  xor    %eax,%eax
  cmp    %cl,%dl
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int strcmp(char *str1, char *str2) {
  int i;
  for (i = 0; str1[i] == str2[i]; i++)
    if (str1[i] == '\0' && str2[i] == '\0')
      return 0;
  if (str1[i] < str2[i])
    return -1;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stack_push_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L21
L7:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stack_push@plt>
  test   %rax,%rax
  je     L24
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L21
L24:
  mov    $0x0,%eax
L21:
  leave
  ret
```

assistant: ```c
int stack_push_dup(struct stack **s, const void *data, size_t dlen) {
  void *dup = malloc(dlen);
  if (dup == NULL)
    return -1;
  memcpy(dup, data, dlen);
  if (stack_push(s, dup)) {
    free(dup);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stack_push_dup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <stack_push@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L4
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L24
L5:
  mov    $0xffffffff,%eax
  jmp    L24
```

assistant: ```c
int stack_push_dup(struct stack **s, const void *data, size_t dlen) {
  void *dup = malloc(dlen);
  if (dup == NULL)
    return -1;
  memcpy(dup, data, dlen);
  if (stack_push(s, dup)) {
    free(dup);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stack_push_dup>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <stack_push@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L13
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  or     $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int stack_push_dup(struct stack **s, const void *data, size_t dlen) {
  void *dup = malloc(dlen);
  if (dup == NULL)
    return -1;
  memcpy(dup, data, dlen);
  if (stack_push(s, dup)) {
    free(dup);
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stack_push_dup>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <stack_push@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L23
L8:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  or     $0xffffffff,%eax
  jmp    L8
```

assistant: ```c
int stack_push_dup(struct stack **s, const void *data, size_t dlen) {
  void *dup = malloc(dlen);
  if (dup == NULL)
    return -1;
  memcpy(dup, data, dlen);
  if (stack_push(s, dup)) {
    free(dup);
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<u_in_ranges>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L0
  mov    $0x0,%eax
  jmp    L30
L0:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L52
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L12
L52:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L45
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L12
L45:
  mov    $0x1,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int u_in_ranges(int u, int r[][2], int len) {
  int n = 0, m = len - 1, i;
  for (;;) {
    if (n > m)
      return 0;
    i = (n + m) / 2;
    if (u < r[i][0])
      m = i - 1;
    else if (u > r[i][1])
      n = i + 1;
    else
      return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<u_in_ranges>:
  endbr64
  sub    $0x1,%edx
  js     L38
  mov    $0x0,%r8d
  jmp    L23
L3:
  cmp    %edi,0x4(%rcx)
  jge    L19
  lea    0x1(%rax),%r8d
L28:
  cmp    %edx,%r8d
  jg     L4
L23:
  lea    (%r8,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  lea    (%rsi,%rcx,8),%rcx
  cmp    %edi,(%rcx)
  jle    L3
  lea    -0x1(%rax),%edx
  jmp    L28
L38:
  mov    $0x0,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int u_in_ranges(int u, int r[][2], int len) {
  int n = 0, m = len - 1, i;
  for (;;) {
    if (n > m)
      return 0;
    i = (n + m) / 2;
    if (u < r[i][0])
      m = i - 1;
    else if (u > r[i][1])
      n = i + 1;
    else
      return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u_in_ranges>:
  endbr64
  sub    $0x1,%edx
  js     L22
  xor    %ecx,%ecx
  jmp    L51
  nopl   (%rax)
L52:
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L22
L51:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  lea    (%rsi,%r8,8),%r8
  cmp    %edi,(%r8)
  jg     L52
  cmp    %edi,0x4(%r8)
  jge    L48
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jge    L51
L22:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int u_in_ranges(int u, int r[][2], int len) {
  int n = 0, m = len - 1, i;
  for (;;) {
    if (n > m)
      return 0;
    i = (n + m) / 2;
    if (u < r[i][0])
      m = i - 1;
    else if (u > r[i][1])
      n = i + 1;
    else
      return 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<u_in_ranges>:
  endbr64
  sub    $0x1,%edx
  js     L21
  xor    %ecx,%ecx
  jmp    L42
  nopl   (%rax)
L0:
  lea    -0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L21
L42:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%r8
  lea    (%rsi,%r8,8),%r8
  cmp    %edi,(%r8)
  jg     L0
  cmp    %edi,0x4(%r8)
  jge    L8
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jge    L42
L21:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int u_in_ranges(int u, int r[][2], int len) {
  int n = 0, m = len - 1, i;
  for (;;) {
    if (n > m)
      return 0;
    i = (n + m) / 2;
    if (u < r[i][0])
      m = i - 1;
    else if (u > r[i][1])
      n = i + 1;
    else
      return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CMAC_CTX_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <CMAC_CTX_cleanup@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L4
L12:
  nop
L4:
  leave
  ret
```

assistant: ```c
void CMAC_CTX_free(CMAC_CTX *ctx) {
  if (ctx == NULL)
    return;
  CMAC_CTX_cleanup(ctx);
  free(ctx);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CMAC_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbx
  mov    %rdi,%rbx
  call   <CMAC_CTX_cleanup@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L7:
  ret
```

assistant: ```c
void CMAC_CTX_free(CMAC_CTX *ctx) {
  if (ctx == NULL)
    return;
  CMAC_CTX_cleanup(ctx);
  free(ctx);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CMAC_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  call   <CMAC_CTX_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void CMAC_CTX_free(CMAC_CTX *ctx) {
  if (ctx == NULL)
    return;
  CMAC_CTX_cleanup(ctx);
  free(ctx);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CMAC_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  call   <CMAC_CTX_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void CMAC_CTX_free(CMAC_CTX *ctx) {
  if (ctx == NULL)
    return;
  CMAC_CTX_cleanup(ctx);
  free(ctx);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fstrncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L14
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fstrncpy(char *dest, const char *src, int n) {
  int i;
  for (i = 0; i < n && src[i] != 0x00 && src[i] != 0x01; i++)
    dest[i] = src[i];
  return i;
}
```