ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<finalizer_scrub8>:
  endbr64
  movl   $0xa5a5a5a5,(%rdi)
  ret
```

assistant: ```c
void finalizer_scrub8(void *ptr) {
  uint64_t *sz_ptr = (uint64_t *)ptr;
  sz_ptr[0] = 0xa5a5a5a5a5a5a5a5ULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<direct_clear16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t direct_clear16(volatile uint16_t *addr, uint16_t dat) {
  *addr &= ~dat;
  return dat;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<direct_clear16>:
  endbr64
  mov    %esi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    (%rdi),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t direct_clear16(volatile uint16_t *addr, uint16_t dat) {
  *addr &= ~dat;
  return dat;
}
```
user: What is the c source code of the assembly code below:

```asm
<direct_clear16>:
  endbr64
  mov    %esi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    (%rdi),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t direct_clear16(volatile uint16_t *addr, uint16_t dat) {
  *addr &= ~dat;
  return dat;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<direct_clear16>:
  endbr64
  mov    %esi,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  mov    (%rdi),%edx
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rdi)
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
uint16_t direct_clear16(volatile uint16_t *addr, uint16_t dat) {
  *addr &= ~dat;
  return dat;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CleanPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  jmp    L76
L27:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L105
L78:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L105:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
L76:
  mov    -0x28(%rbp),%rax
  lea    D27(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L46
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L46
L119:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L104
L70:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L104:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
L46:
  mov    -0x28(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L119
  mov    -0x28(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x28(%rbp)
  jne    L21
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L24
L51:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
L21:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string

tool: D27: //

tool: D18: /./

tool: D17: ./

assistant: ```c
void CleanPath(char *entry) {
  char *p, *q;
  size_t len;
  while ((p = strstr(entry, "//")) != NULL) {
    p++;
    q = p + 1;
    while (*p)
      *p++ = *q++;
  }
  len = strlen(entry);
  if (entry[len - 1] == '/')
    entry[len - 1] = '\0';
  while ((p = strstr(entry, "/./")) != NULL) {
    p++;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
  if (strstr(entry, "./") == entry) {
    p = entry;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CleanPath>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D9(%rip),%rbp
L85:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L32
  lea    0x1(%rax),%rdx
  cmpb   $0x0,0x1(%rax)
  je     L85
L67:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  mov    %al,-0x1(%rdx)
  test   %al,%al
  jne    L67
  jmp    L85
L32:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  je     L4
L21:
  lea    D7(%rip),%rbp
L137:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
  lea    0x1(%rax),%rdx
  cmpb   $0x0,0x1(%rax)
  je     L137
L27:
  add    $0x1,%rdx
  movzbl 0x1(%rdx),%eax
  mov    %al,-0x1(%rdx)
  cmpb   $0x0,(%rdx)
  jne    L27
  jmp    L137
L4:
  movb   $0x0,(%rax)
  jmp    L21
L9:
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L7
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  cmpb   $0x0,(%rbx)
  je     L61
L56:
  add    $0x1,%rbx
  movzbl 0x1(%rbx),%eax
  mov    %al,-0x1(%rbx)
  cmpb   $0x0,(%rbx)
  jne    L56
  jmp    L61
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: string
name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D9: //

tool: D7: /./

tool: D18: ./

assistant: ```c
void CleanPath(char *entry) {
  char *p, *q;
  size_t len;
  while ((p = strstr(entry, "//")) != NULL) {
    p++;
    q = p + 1;
    while (*p)
      *p++ = *q++;
  }
  len = strlen(entry);
  if (entry[len - 1] == '/')
    entry[len - 1] = '\0';
  while ((p = strstr(entry, "/./")) != NULL) {
    p++;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
  if (strstr(entry, "./") == entry) {
    p = entry;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CleanPath>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L103:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L8
L19:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rdx
  je     L103
  xchg   %ax,%ax
L88:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  test   %al,%al
  jne    L88
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L19
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L23
  movb   $0x0,(%rax)
L23:
  lea    D10(%rip),%rbp
L40:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L45
L91:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rdx
  je     L40
  nopl   (%rax)
L52:
  add    $0x1,%rdx
  movzbl 0x1(%rdx),%eax
  cmpb   $0x0,(%rdx)
  mov    %al,-0x1(%rdx)
  jne    L52
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L91
L45:
  cmpb   $0x2e,(%rbx)
  jne    L98
  cmpb   $0x2f,0x1(%rbx)
  je     L83
L98:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl 0x2(%rbx),%eax
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
L83:
  cmpb   $0x0,(%rbx)
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string

tool: D0: //

tool: D10: /./

assistant: ```c
void CleanPath(char *entry) {
  char *p, *q;
  size_t len;
  while ((p = strstr(entry, "//")) != NULL) {
    p++;
    q = p + 1;
    while (*p)
      *p++ = *q++;
  }
  len = strlen(entry);
  if (entry[len - 1] == '/')
    entry[len - 1] = '\0';
  while ((p = strstr(entry, "/./")) != NULL) {
    p++;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
  if (strstr(entry, "./") == entry) {
    p = entry;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CleanPath>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L79
  nopl   0x0(%rax)
L149:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rdx
  je     L111
  cs nopw 0x0(%rax,%rax,1)
L105:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  test   %al,%al
  jne    L105
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L149
L79:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x2f,(%rax)
  jne    L139
  movb   $0x0,(%rax)
L139:
  lea    D18(%rip),%rbp
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L34
  nopl   0x0(%rax,%rax,1)
L80:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rdx
  je     L65
  xchg   %ax,%ax
L92:
  add    $0x1,%rdx
  movzbl 0x1(%rdx),%eax
  cmpb   $0x0,(%rdx)
  mov    %al,-0x1(%rdx)
  jne    L92
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L80
L34:
  cmpb   $0x2e,(%rbx)
  jne    L97
  cmpb   $0x2f,0x1(%rbx)
  jne    L97
  cmpb   $0x0,(%rbx)
  je     L97
  movzbl 0x1(%rbx),%eax
  nopl   0x0(%rax)
L43:
  add    $0x1,%rbx
  mov    %eax,%edx
  movzbl 0x1(%rbx),%eax
  mov    %al,-0x1(%rbx)
  test   %dl,%dl
  jne    L43
L97:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L111:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L79
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L111
  jmp    L79
  nopl   0x0(%rax)
L65:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L34
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L65
  jmp    L34
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string

tool: D13: //

tool: D18: /./

assistant: ```c
void CleanPath(char *entry) {
  char *p, *q;
  size_t len;
  while ((p = strstr(entry, "//")) != NULL) {
    p++;
    q = p + 1;
    while (*p)
      *p++ = *q++;
  }
  len = strlen(entry);
  if (entry[len - 1] == '/')
    entry[len - 1] = '\0';
  while ((p = strstr(entry, "/./")) != NULL) {
    p++;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
  if (strstr(entry, "./") == entry) {
    p = entry;
    q = p + 2;
    while (*p)
      *p++ = *q++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binToDec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L47
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L47:
  cmpl   $0x0,-0x10(%rbp)
  jne    L26
  cmpl   $0x0,-0x14(%rbp)
  js     L29
  jmp    L62
L28:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  subl   $0x1,-0xc(%rbp)
L62:
  cmpl   $0x0,-0xc(%rbp)
  jns    L28
  jmp    L24
L49:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  subl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x0,-0xc(%rbp)
  jns    L49
L24:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *binToDec(int number) {
  int *num = (int *)malloc(sizeof(int) * 4);
  int dividend = (number >= 0) ? number : (number * -1);
  int i = 4 - 1;
  while (dividend != 0) {
    num[i] = dividend % 2;
    dividend = dividend / 2;
    i--;
  }
  if (number >= 0) {
    while (i >= 0) {
      num[i] = 0;
      i--;
    }
  } else {
    while (i >= 0) {
      num[i] = 1;
      i--;
    }
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binToDec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  test   %ebx,%ebx
  je     L8
  lea    0xc(%rax),%rsi
  mov    $0x3,%ecx
L66:
  mov    %edx,%edi
  shr    $0x1f,%edi
  lea    (%rdx,%rdi,1),%eax
  and    $0x1,%eax
  sub    %edi,%eax
  mov    %eax,(%rsi)
  mov    %edi,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  sub    $0x1,%ecx
  sub    $0x4,%rsi
  test   %eax,%eax
  jne    L66
  test   %ebx,%ebx
  js     L87
  test   %ecx,%ecx
  js     L17
L62:
  movslq %ecx,%rax
  lea    (%r8,%rax,4),%rax
L36:
  movl   $0x0,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%ecx
  jns    L36
L17:
  mov    %r8,%rax
  pop    %rbx
  ret
L87:
  test   %ecx,%ecx
  js     L17
  movslq %ecx,%rdx
  shl    $0x2,%rdx
  lea    (%rdx,%r8,1),%rax
  lea    -0x4(%r8,%rdx,1),%rdx
  mov    %ecx,%ecx
  shl    $0x2,%rcx
  sub    %rcx,%rdx
L30:
  movl   $0x1,(%rax)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L30
  jmp    L17
L8:
  mov    $0x3,%ecx
  jmp    L62
```

assistant: ```c
int *binToDec(int number) {
  int *num = (int *)malloc(sizeof(int) * 4);
  int dividend = (number >= 0) ? number : (number * -1);
  int i = 4 - 1;
  while (dividend != 0) {
    num[i] = dividend % 2;
    dividend = dividend / 2;
    i--;
  }
  if (number >= 0) {
    while (i >= 0) {
      num[i] = 0;
      i--;
    }
  } else {
    while (i >= 0) {
      num[i] = 1;
      i--;
    }
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binToDec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  test   %ebx,%ebx
  je     L44
  lea    0xc(%r8),%rcx
  mov    $0x3,%edx
  nopl   0x0(%rax)
L8:
  mov    %eax,%esi
  sub    $0x1,%edx
  sub    $0x4,%rcx
  and    $0x1,%esi
  mov    %esi,0x4(%rcx)
  sar    %eax
  jne    L8
  test   %ebx,%ebx
  js     L127
  test   %edx,%edx
  js     L5
L64:
  movslq %edx,%rdx
  xor    %edi,%edi
  lea    0x4(,%rdx,4),%rax
  mov    %r8,%rdx
  cmp    $0x8,%eax
  jae    L115
  test   $0x4,%al
  jne    L122
  test   %eax,%eax
  jne    L111
L5:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L127:
  test   %edx,%edx
  js     L5
  movslq %edx,%rdx
  lea    (%r8,%rdx,4),%rax
L120:
  sub    $0x1,%rdx
  movl   $0x1,(%rax)
  sub    $0x4,%rax
  test   %edx,%edx
  jns    L120
  mov    %r8,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L115:
  mov    %eax,%ecx
  movq   $0x0,(%r8)
  movq   $0x0,-0x8(%r8,%rcx,1)
  lea    0x8(%r8),%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L5
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L84:
  mov    %edx,%esi
  add    $0x8,%edx
  mov    %rdi,(%rcx,%rsi,1)
  cmp    %eax,%edx
  jb     L84
  mov    %r8,%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L111:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L44:
  mov    $0x3,%edx
  jmp    L64
L122:
  mov    %eax,%eax
  movl   $0x0,(%r8)
  movl   $0x0,-0x4(%r8,%rax,1)
  jmp    L5
```

assistant: ```c
int *binToDec(int number) {
  int *num = (int *)malloc(sizeof(int) * 4);
  int dividend = (number >= 0) ? number : (number * -1);
  int i = 4 - 1;
  while (dividend != 0) {
    num[i] = dividend % 2;
    dividend = dividend / 2;
    i--;
  }
  if (number >= 0) {
    while (i >= 0) {
      num[i] = 0;
      i--;
    }
  } else {
    while (i >= 0) {
      num[i] = 1;
      i--;
    }
  }
  return num;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binToDec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  neg    %eax
  cmovs  %ebx,%eax
  test   %ebx,%ebx
  je     L50
  lea    0xc(%r8),%rcx
  mov    $0x3,%edx
  nopl   0x0(%rax)
L82:
  mov    %eax,%esi
  sub    $0x4,%rcx
  and    $0x1,%esi
  mov    %esi,0x4(%rcx)
  mov    %edx,%esi
  sub    $0x1,%edx
  sar    %eax
  jne    L82
  test   %ebx,%ebx
  js     L128
  test   %edx,%edx
  js     L62
L18:
  movslq %edx,%rdx
  xor    %edi,%edi
  lea    0x4(,%rdx,4),%rax
  mov    %r8,%rdx
  cmp    $0x8,%eax
  jae    L54
  test   $0x4,%al
  jne    L55
  test   %eax,%eax
  jne    L122
L62:
  mov    %r8,%rax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L128:
  test   %edx,%edx
  js     L62
  movslq %edx,%rdx
  lea    -0x2(%rsi),%eax
  movl   $0x1,(%r8,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  cmp    $0x1,%esi
  je     L62
  movl   $0x1,-0x4(%r8,%rcx,1)
  test   %eax,%eax
  je     L62
  movl   $0x1,(%r8)
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %eax,%ecx
  movq   $0x0,(%r8)
  movq   $0x0,-0x8(%r8,%rcx,1)
  lea    0x8(%r8),%rcx
  and    $0xfffffffffffffff8,%rcx
  sub    %rcx,%rdx
  add    %edx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L62
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L12:
  mov    %edx,%esi
  add    $0x8,%edx
  mov    %rdi,(%rcx,%rsi,1)
  cmp    %eax,%edx
  jb     L12
  mov    %r8,%rax
  pop    %rbx
  ret
  xchg   %ax,%ax
L122:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L50:
  mov    $0x3,%edx
  jmp    L18
L55:
  mov    %eax,%eax
  movl   $0x0,(%r8)
  movl   $0x0,-0x4(%r8,%rax,1)
  jmp    L62
```

assistant: ```c
int *binToDec(int number) {
  int *num = (int *)malloc(sizeof(int) * 4);
  int dividend = (number >= 0) ? number : (number * -1);
  int i = 4 - 1;
  while (dividend != 0) {
    num[i] = dividend % 2;
    dividend = dividend / 2;
    i--;
  }
  if (number >= 0) {
    while (i >= 0) {
      num[i] = 0;
      i--;
    }
  } else {
    while (i >= 0) {
      num[i] = 1;
      i--;
    }
  }
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_neighbors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  jmp    L25
L89:
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L45
L104:
  cmpl   $0x0,-0x10(%rbp)
  jne    L39
  cmpl   $0x0,-0xc(%rbp)
  je     L99
L39:
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L5
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L5
  cmpl   $0x0,-0x4(%rbp)
  js     L5
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jge    L5
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x14(%rbp)
  jmp    L5
L99:
  nop
L5:
  addl   $0x1,-0xc(%rbp)
L45:
  cmpl   $0x1,-0xc(%rbp)
  jle    L104
  addl   $0x1,-0x10(%rbp)
L25:
  cmpl   $0x1,-0x10(%rbp)
  jle    L89
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_neighbors(int i, int j, int x, int y, char **grid) {
  int neighbors = 0;
  for (int a = -1; a < 2; ++a) {
    for (int b = -1; b < 2; ++b) {
      if (a == 0 && b == 0) {
        continue;
      }
      int m = i + a;
      int n = j + b;
      if (m >= 0 && m < x && n >= 0 && n < y) {
        neighbors += grid[m][n];
      }
    }
  }
  return neighbors;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_neighbors>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r11d
  mov    %edx,%r10d
  mov    %ecx,%ebx
  lea    -0x1(%rdi),%r9d
  movslq %edi,%rdi
  lea    (%r8,%rdi,8),%r12
  mov    $0xffffffffffffffff,%rdi
  mov    $0x0,%ebp
  jmp    L49
L15:
  cmp    $0x1,%eax
  jg     L69
L39:
  add    $0x1,%eax
  add    $0x1,%ecx
L64:
  lea    -0x1(%rax),%edx
  or     %r8d,%edx
  je     L39
  test   %sil,%sil
  je     L15
  cmp    %r9d,%r10d
  jle    L15
  test   %ecx,%ecx
  js     L15
  cmp    %ebx,%ecx
  jge    L15
  movslq %ecx,%rdx
  mov    (%r12,%rdi,8),%r14
  movsbl (%r14,%rdx,1),%edx
  add    %edx,%ebp
  jmp    L15
L69:
  add    $0x1,%rdi
  add    $0x1,%r9d
  cmp    $0x2,%rdi
  je     L40
L49:
  mov    %edi,%r8d
  lea    -0x1(%r11),%ecx
  mov    $0x0,%eax
  mov    %r9d,%esi
  not    %esi
  shr    $0x1f,%esi
  jmp    L64
L40:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
int get_neighbors(int i, int j, int x, int y, char **grid) {
  int neighbors = 0;
  for (int a = -1; a < 2; ++a) {
    for (int b = -1; b < 2; ++b) {
      if (a == 0 && b == 0) {
        continue;
      }
      int m = i + a;
      int n = j + b;
      if (m >= 0 && m < x && n >= 0 && n < y) {
        neighbors += grid[m][n];
      }
    }
  }
  return neighbors;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_neighbors>:
  endbr64
  lea    -0x1(%rdi),%r9d
  movslq %edi,%rdi
  push   %r14
  mov    %edx,%r10d
  push   %r12
  mov    %ecx,%r11d
  xor    %r12d,%r12d
  push   %rbp
  lea    (%r8,%rdi,8),%rbp
  mov    $0xffffffffffffffff,%rdi
  push   %rbx
  lea    -0x1(%rsi),%ebx
L42:
  mov    %r9d,%esi
  mov    %edi,%r8d
  mov    %ebx,%edx
  mov    $0xffffffff,%eax
  not    %esi
  shr    $0x1f,%esi
L11:
  mov    %r8d,%ecx
  or     %eax,%ecx
  add    $0x1,%eax
  test   %ecx,%ecx
  je     L37
  test   %sil,%sil
  je     L18
  cmp    %r9d,%r10d
  jle    L18
  test   %edx,%edx
  js     L18
  cmp    %r11d,%edx
  jge    L18
  mov    0x0(%rbp,%rdi,8),%r14
  movslq %edx,%rcx
  movsbl (%r14,%rcx,1),%ecx
  add    %ecx,%r12d
L18:
  cmp    $0x2,%eax
  jne    L37
  add    $0x1,%rdi
  add    $0x1,%r9d
  cmp    $0x2,%rdi
  jne    L42
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x1,%edx
  jmp    L11
```

assistant: ```c
int get_neighbors(int i, int j, int x, int y, char **grid) {
  int neighbors = 0;
  for (int a = -1; a < 2; ++a) {
    for (int b = -1; b < 2; ++b) {
      if (a == 0 && b == 0) {
        continue;
      }
      int m = i + a;
      int n = j + b;
      if (m >= 0 && m < x && n >= 0 && n < y) {
        neighbors += grid[m][n];
      }
    }
  }
  return neighbors;
}
```