ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <imul32_to_64@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  imul32_to_64();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <imul32_to_64@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  imul32_to_64();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm2
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x14(%rbp),%xmm2
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm3
  movq   %xmm3,%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string

tool: D7: Enter any two floating numbers: 

tool: D13: %f %f

tool: D11: The sum of squares of %.2f and %.2f is %.2f


assistant: ```c
int main() {
  float a, b, sum;
  printf("Enter any two floating numbers: ");
  scanf("%f %f", &a, &b);
  sum = (a * a) + (b * b);
  printf("The sum of squares of %.2f and %.2f is %.2f\n", a, b, sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm1,%xmm3
  addss  %xmm3,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D22(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string

tool: D29: Enter any two floating numbers: 

tool: D13: %f %f

tool: D22: The sum of squares of %.2f and %.2f is %.2f


assistant: ```c
int main() {
  float a, b, sum;
  printf("Enter any two floating numbers: ");
  scanf("%f %f", &a, &b);
  sum = (a * a) + (b * b);
  printf("The sum of squares of %.2f and %.2f is %.2f\n", a, b, sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  lea    D4(%rip),%rdi
  mov    $0x3,%eax
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm0,%xmm2
  cvtss2sd %xmm0,%xmm0
  mulss  %xmm1,%xmm3
  cvtss2sd %xmm1,%xmm1
  addss  %xmm3,%xmm2
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
data_type: string
name: unpack_data
arguments: data_label: D16
data_type: string
name: unpack_data
arguments: data_label: D4
data_type: string

tool: D14: Enter any two floating numbers: 

tool: D16: %f %f

tool: D4: The sum of squares of %.2f and %.2f is %.2f


assistant: ```c
int main() {
  float a, b, sum;
  printf("Enter any two floating numbers: ");
  scanf("%f %f", &a, &b);
  sum = (a * a) + (b * b);
  printf("The sum of squares of %.2f and %.2f is %.2f\n", a, b, sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D28(%rip),%rdi
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  lea    D3(%rip),%rdi
  mov    $0x3,%eax
  movaps %xmm0,%xmm2
  movaps %xmm1,%xmm3
  mulss  %xmm0,%xmm2
  cvtss2sd %xmm0,%xmm0
  mulss  %xmm1,%xmm3
  cvtss2sd %xmm1,%xmm1
  addss  %xmm3,%xmm2
  cvtss2sd %xmm2,%xmm2
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D14: Enter any two floating numbers: 

tool: D28: %f %f

tool: D3: The sum of squares of %.2f and %.2f is %.2f


assistant: ```c
int main() {
  float a, b, sum;
  printf("Enter any two floating numbers: ");
  scanf("%f %f", &a, &b);
  sum = (a * a) + (b * b);
  printf("The sum of squares of %.2f and %.2f is %.2f\n", a, b, sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hlt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  jmp    L9
```

assistant: ```c
__attribute__((always_)) void hlt(void) {
  while (1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hlt>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
__attribute__((always_)) void hlt(void) {
  while (1)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hlt>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
__attribute__((always_)) void hlt(void) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hlt>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
__attribute__((always_)) void hlt(void) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stbi_write_tga>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%esi
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  lea    0x0(,%rax,8),%ecx
  mov    -0x24(%rbp),%r8d
  mov    -0x20(%rbp),%edi
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  push   %rsi
  push   %rcx
  mov    -0x20(%rbp),%ecx
  push   %rcx
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  lea    D8(%rip),%rcx
  push   %rcx
  push   $0x0
  mov    -0x4(%rbp),%ecx
  push   %rcx
  push   -0x30(%rbp)
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <outfile@plt>
  sub    $0xffffffffffffff80,%rsp
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: 111 221 2222 11

assistant: ```c
int stbi_write_tga(char const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stbi_write_tga>:
  endbr64
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  test   $0x1,%cl
  sete   %cl
  movzbl %cl,%ecx
  lea    0x0(,%rcx,8),%eax
  push   %rax
  add    $0x18,%eax
  push   %rax
  push   %rdx
  push   %rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  lea    D6(%rip),%rax
  push   %rax
  push   $0x0
  push   %rcx
  push   %r8
  mov    %edx,%r8d
  mov    %esi,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  call   <outfile@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: 111 221 2222 11

assistant: ```c
int stbi_write_tga(char const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stbi_write_tga>:
  endbr64
  mov    %ecx,%eax
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  mov    %esi,%r10d
  not    %eax
  and    $0x1,%eax
  lea    0x0(,%rax,8),%ecx
  push   %rcx
  add    $0x18,%ecx
  push   %rcx
  mov    %r10d,%ecx
  push   %rdx
  push   %rsi
  lea    D8(%rip),%rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %rax
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: 111 221 2222 11

assistant: ```c
int stbi_write_tga(char const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_write_tga>:
  endbr64
  mov    %ecx,%eax
  sub    $0x8,%rsp
  mov    %ecx,%r9d
  mov    %esi,%r10d
  not    %eax
  and    $0x1,%eax
  lea    0x0(,%rax,8),%ecx
  push   %rcx
  add    $0x18,%ecx
  push   %rcx
  mov    %r10d,%ecx
  push   %rdx
  push   %rsi
  lea    D2(%rip),%rsi
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x2
  push   $0x0
  push   $0x0
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %rax
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile@plt>
  add    $0x88,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: 111 221 2222 11

assistant: ```c
int stbi_write_tga(char const *filename, int x, int y, int comp, const void *data) {
  int has_alpha = !(comp & 1);
  return outfile(filename, -1, -1, x, y, comp, data, has_alpha, 0, "111 221 2222 11", 0, 0, 2, 0, 0, 0, 0, 0, x, y, 24 + 8 * has_alpha, 8 * has_alpha);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<QEIConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x4002c000,-0x4(%rbp)
  je     L29
  cmpl   $0x4002d000,-0x4(%rbp)
  jne    L27
L29:
  mov    $0x1,%eax
  jmp    L11
L27:
  mov    $0x0,%eax
L11:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rax),%eax
  and    $0xffffffe1,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  or     -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void QEIConfigure(uint32_t ui32Base, uint32_t ui32Config, uint32_t ui32MaxPosition) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = (((*((volatile uint32_t *)(ui32Base + 0x00000000))) & ~(0x00000008 | 0x00000010 | 0x00000004 | 0x00000002)) | ui32Config);
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32MaxPosition;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<QEIConfigure>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x4002c000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  movslq %ebx,%rdx
  mov    (%rdx),%eax
  and    $0xffffffe1,%eax
  or     %r12d,%eax
  mov    %eax,(%rdx)
  add    $0xc,%ebx
  movslq %ebx,%rbx
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void QEIConfigure(uint32_t ui32Base, uint32_t ui32Config, uint32_t ui32MaxPosition) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = (((*((volatile uint32_t *)(ui32Base + 0x00000000))) & ~(0x00000008 | 0x00000010 | 0x00000004 | 0x00000002)) | ui32Config);
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32MaxPosition;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QEIConfigure>:
  endbr64
  mov    %edi,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0xef,%ah
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x4002c000,%eax
  sete   %dil
  call   <ASSERT@plt>
  movslq %ebx,%rdx
  add    $0xc,%ebx
  mov    (%rdx),%eax
  movslq %ebx,%rbx
  and    $0xffffffe1,%eax
  or     %r12d,%eax
  mov    %eax,(%rdx)
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void QEIConfigure(uint32_t ui32Base, uint32_t ui32Config, uint32_t ui32MaxPosition) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = (((*((volatile uint32_t *)(ui32Base + 0x00000000))) & ~(0x00000008 | 0x00000010 | 0x00000004 | 0x00000002)) | ui32Config);
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32MaxPosition;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QEIConfigure>:
  endbr64
  mov    %edi,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0xef,%ah
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x4002c000,%eax
  sete   %dil
  call   <ASSERT@plt>
  movslq %ebx,%rdx
  add    $0xc,%ebx
  mov    (%rdx),%eax
  movslq %ebx,%rbx
  and    $0xffffffe1,%eax
  or     %r12d,%eax
  mov    %eax,(%rdx)
  mov    %ebp,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void QEIConfigure(uint32_t ui32Base, uint32_t ui32Config, uint32_t ui32MaxPosition) {
  ASSERT((ui32Base == 0x4002C000) || (ui32Base == 0x4002D000));
  (*((volatile uint32_t *)(ui32Base + 0x00000000))) = (((*((volatile uint32_t *)(ui32Base + 0x00000000))) & ~(0x00000008 | 0x00000010 | 0x00000004 | 0x00000002)) | ui32Config);
  (*((volatile uint32_t *)(ui32Base + 0x0000000C))) = ui32MaxPosition;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printAllShortestPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L43:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L55
L44:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L55:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L44
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x8000,%eax
  jne    L46
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L46:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x0,-0x8(%rbp)
  jns    L43
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D11
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D38
type_guessed: string
name: parse_data
arguments: label: D58
type_guessed: string

tool: D25: Vertex: revert path (weight)

tool: D24: %6d

tool: D11:  -> %2d

tool: D26: MAX

tool: D38:  (%s)

tool: D58:  (%2d)

assistant: ```c
void printAllShortestPath(int checkedVertex[], int vertexWeight[], int vertexParent[], int size) {
  int i;
  printf("Vertex: revert path (weight)\n");
  for (i = size - 1; i >= 0; i--) {
    printf("%6d", i);
    int current = i;
    while (vertexParent[current] != -1) {
      current = vertexParent[current];
      printf(" -> %2d", current);
    }
    if (vertexWeight[i] == 32768) {
      printf(" (%s)", "MAX");
    } else {
      printf(" (%2d)", vertexWeight[i]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printAllShortestPath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  lea    D10(%rip),%rdi
  call   <puts@plt>
  sub    $0x1,%r13d
  js     L68
  movslq %r13d,%r13
  lea    D16(%rip),%r15
  lea    D44(%rip),%r12
  jmp    L64
L42:
  lea    D36(%rip),%rsi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L56:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r13
  test   %r13d,%r13d
  js     L68
L64:
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp,%r13,4),%ebx
  cmp    $0xffffffff,%ebx
  je     L66
L53:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%ebx
  cmp    $0xffffffff,%ebx
  jne    L53
L66:
  mov    (%r14,%r13,4),%esi
  cmp    $0x8000,%esi
  je     L42
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L56
L68:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D44
datatype: string
name: retrieve_data
arguments: tag: D36
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string
name: retrieve_data
arguments: tag: D37
datatype: string

tool: D10: Vertex: revert path (weight)

tool: D16: %6d

tool: D44:  -> %2d

tool: D36: MAX

tool: D29:  (%s)

tool: D37:  (%2d)

assistant: ```c
void printAllShortestPath(int checkedVertex[], int vertexWeight[], int vertexParent[], int size) {
  int i;
  printf("Vertex: revert path (weight)\n");
  for (i = size - 1; i >= 0; i--) {
    printf("%6d", i);
    int current = i;
    while (vertexParent[current] != -1) {
      current = vertexParent[current];
      printf(" -> %2d", current);
    }
    if (vertexWeight[i] == 32768) {
      printf(" (%s)", "MAX");
    } else {
      printf(" (%2d)", vertexWeight[i]);
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printAllShortestPath>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <puts@plt>
  sub    $0x1,%r12d
  js     L57
  movslq %r12d,%r12
  lea    D43(%rip),%r14
  lea    D27(%rip),%rbp
  lea    D48(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %r12d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx,%r12,4),%r13d
  cmp    $0xffffffff,%r13d
  je     L14
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %r13d,%rdx
  mov    (%rbx,%rdx,4),%r13d
  cmp    $0xffffffff,%r13d
  jne    L25
L14:
  mov    0x8(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  cmp    $0x8000,%esi
  je     L56
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L45:
  mov    $0xa,%edi
  sub    $0x1,%r12
  call   <putchar@plt>
  test   %r12d,%r12d
  jns    L11
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  lea    D8(%rip),%rsi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L45
```

tool_calls: name: disassemble_data
arguments: tag: D26
data_type: string
name: disassemble_data
arguments: tag: D43
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D48
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D45
data_type: string

tool: D26: Vertex: revert path (weight)

tool: D43: %6d

tool: D27:  -> %2d

tool: D48:  (%2d)

tool: D8: MAX

tool: D45:  (%s)

assistant: ```c
void printAllShortestPath(int checkedVertex[], int vertexWeight[], int vertexParent[], int size) {
  int i;
  printf("Vertex: revert path (weight)\n");
  for (i = size - 1; i >= 0; i--) {
    printf("%6d", i);
    int current = i;
    while (vertexParent[current] != -1) {
      current = vertexParent[current];
      printf(" -> %2d", current);
    }
    if (vertexWeight[i] == 32768) {
      printf(" (%s)", "MAX");
    } else {
      printf(" (%2d)", vertexWeight[i]);
    }
    printf("\n");
  }
}
```