ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x20,%edi
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    $0x20,%edi
  mov    %rax,%rbp
  call   <acc_malloc@plt>
  mov    $0x20,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <acc_map_data@plt>
  lea    0x4(%r13),%rax
  mov    %r12,%rdx
  mov    %rbp,%rcx
  sub    %rax,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  sub    %rax,%rcx
  cmp    $0x8,%rcx
  seta   %al
  test   %al,%dl
  je     L15
  lea    0x4(%rbp),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L15
  movups 0x0(%r13),%xmm0
  movups %xmm0,0x0(%rbp)
  movups %xmm0,(%r12)
  movups 0x10(%r13),%xmm0
  movups %xmm0,0x10(%rbp)
  movups %xmm0,0x10(%r12)
L7:
  mov    %rbp,%rdi
  call   <acc_deviceptr@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <acc_unmap_data@plt>
  mov    %r14,%rdi
  call   <acc_free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  movss  0x0(%r13),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  %xmm0,(%r12)
  movss  0x4(%r13),%xmm0
  movss  %xmm0,0x4(%rbp)
  movss  %xmm0,0x4(%r12)
  movss  0x8(%r13),%xmm0
  movss  %xmm0,0x8(%rbp)
  movss  %xmm0,0x8(%r12)
  movss  0xc(%r13),%xmm0
  movss  %xmm0,0xc(%rbp)
  movss  %xmm0,0xc(%r12)
  movss  0x10(%r13),%xmm0
  movss  %xmm0,0x10(%rbp)
  movss  %xmm0,0x10(%r12)
  movss  0x14(%r13),%xmm0
  movss  %xmm0,0x14(%rbp)
  movss  %xmm0,0x14(%r12)
  movss  0x18(%r13),%xmm0
  movss  %xmm0,0x18(%rbp)
  movss  %xmm0,0x18(%r12)
  movss  0x1c(%r13),%xmm0
  movss  %xmm0,0x1c(%rbp)
  movss  %xmm0,0x1c(%r12)
  jmp    L7
```

assistant: ```c
int main(int argc, char **argv) {
  int N = 8;
  float *a, *b, *c, *d;
  int i;
  a = (float *)malloc(N * sizeof(float));
  b = (float *)malloc(N * sizeof(float));
  c = (float *)malloc(N * sizeof(float));
  d = (float *)acc_malloc(N * sizeof(float));
  acc_map_data(c, d, N * sizeof(float));
#pragma acc data present(a [0:N]) present(c [0:N]) present(b [0:N])
  {
#pragma acc parallel
    {
      int ii;
      for (ii = 0; ii < N; ii++) {
        c[ii] = a[ii];
        b[ii] = c[ii];
      }
    }
  }
  d = (float *)acc_deviceptr(c);
  acc_unmap_data(c);
  acc_free(d);
  free(a);
  free(b);
  free(c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utf8_next_symbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L8
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  jmp    L7
L29:
  shll   -0x4(%rbp)
  addq   $0x4,-0x18(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L29
  mov    -0x18(%rbp),%rax
L7:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *utf8_next_symbol(uint8_t *utf8) {
  uint8_t b = *utf8;
  if (!(b & 0x80)) {
    return utf8 + 1;
  }
  while (b & 0x80) {
    b <<= 1;
    utf8++;
  }
  return utf8;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utf8_next_symbol>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%edx
  test   $0x80,%dl
  je     L3
L1:
  add    %edx,%edx
  add    $0x4,%rax
  test   $0x80,%dl
  jne    L1
  ret
L3:
  add    $0x4,%rax
  ret
```

assistant: ```c
uint8_t *utf8_next_symbol(uint8_t *utf8) {
  uint8_t b = *utf8;
  if (!(b & 0x80)) {
    return utf8 + 1;
  }
  while (b & 0x80) {
    b <<= 1;
    utf8++;
  }
  return utf8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_next_symbol>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  test   $0x80,%dl
  je     L12
  xchg   %ax,%ax
L0:
  add    %edx,%edx
  add    $0x4,%rax
  test   $0x80,%dl
  jne    L0
  ret
  nopl   0x0(%rax)
L12:
  add    $0x4,%rax
  ret
```

assistant: ```c
uint8_t *utf8_next_symbol(uint8_t *utf8) {
  uint8_t b = *utf8;
  if (!(b & 0x80)) {
    return utf8 + 1;
  }
  while (b & 0x80) {
    b <<= 1;
    utf8++;
  }
  return utf8;
}
```
user: What is the c source code of the assembly code below?

```asm
<utf8_next_symbol>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  test   $0x80,%dl
  je     L7
  xchg   %ax,%ax
L6:
  add    %edx,%edx
  add    $0x4,%rax
  test   $0x80,%dl
  jne    L6
  ret
  nopl   0x0(%rax)
L7:
  add    $0x4,%rax
  ret
```

assistant: ```c
uint8_t *utf8_next_symbol(uint8_t *utf8) {
  uint8_t b = *utf8;
  if (!(b & 0x80)) {
    return utf8 + 1;
  }
  while (b & 0x80) {
    b <<= 1;
    utf8++;
  }
  return utf8;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L7:
  cmp    %rdx,%rsp
  je     L22
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L22:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L0
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L0:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
L16:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L16
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
L49:
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x50(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x50(%rbp),%eax
  test   %eax,%eax
  jns    L49
  mov    %rbx,%rsp
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string

tool: D23: %d

tool: D12: %d


assistant: ```c
int main() {
  int z, l;
  scanf("%d", &z);
  int pecho[z];
  l = 0;
  do {
    scanf("%d", &pecho[l]);
    l++;
  } while (l < z);
  z--;
  do {
    printf("%d\n", pecho[z]);
    z--;
  } while (z >= 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L45:
  cmp    %rdx,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L48:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L54
  orq    $0x0,-0x8(%rsp,%rax,1)
L54:
  mov    %rsp,%r13
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D16(%rip),%r14
L13:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%eax
  add    $0x4,%r12
  cmp    %ebx,%eax
  jg     L13
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  lea    D0(%rip),%rbx
L30:
  movslq -0x2c(%rbp),%rax
  mov    0x0(%r13,%rax,4),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jns    L30
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D0
datatype: string

tool: D16: %d

tool: D0: %d


assistant: ```c
int main() {
  int z, l;
  scanf("%d", &z);
  int pecho[z];
  l = 0;
  do {
    scanf("%d", &pecho[l]);
    l++;
  } while (l < z);
  z--;
  do {
    printf("%d\n", pecho[z]);
    z--;
  } while (z >= 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L22
L69:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L69
L22:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L3
L41:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  mov    %r12,%r13
  nopl   0x0(%rax)
L5:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L5
  sub    $0x1,%eax
  lea    D7(%rip),%rbx
  mov    %eax,-0x2c(%rbp)
  xchg   %ax,%ax
L52:
  cltq
  mov    %rbx,%rdi
  mov    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jns    L52
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L3:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L41
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D14: %d

tool: D7: %d


assistant: ```c
int main() {
  int z, l;
  scanf("%d", &z);
  int pecho[z];
  l = 0;
  do {
    scanf("%d", &pecho[l]);
    l++;
  } while (l < z);
  z--;
  do {
    printf("%d\n", pecho[z]);
    z--;
  } while (z >= 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L46
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L46:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L30
L18:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  mov    %r12,%r13
  nopl   0x0(%rax)
L31:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L31
  sub    $0x1,%eax
  lea    D13(%rip),%rbx
  mov    %eax,-0x2c(%rbp)
  xchg   %ax,%ax
L51:
  cltq
  mov    %rbx,%rdi
  mov    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jns    L51
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L30:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L18
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string

tool: D10: %d

tool: D13: %d


assistant: ```c
int main() {
  int z, l;
  scanf("%d", &z);
  int pecho[z];
  l = 0;
  do {
    scanf("%d", &pecho[l]);
    l++;
  } while (l < z);
  z--;
  do {
    printf("%d\n", pecho[z]);
    z--;
  } while (z >= 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x418(%rbp)
  cmpq   $0x0,-0x418(%rbp)
  jne    L22
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L14:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L14
  mov    -0x418(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D26
type: string

tool: D9: r

tool: D18: /proc/user_beancounters

tool: D26: %s

assistant: ```c
int main() {
  char line[1024];
  FILE *file = fopen("/proc/user_beancounters", "r");
  if (file == NULL)
    exit(1);
  while (fgets(line, 1024, file))
    printf("%s", line);
  fclose(file);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L34
L33:
  lea    D15(%rip),%rbp
  jmp    L14
L34:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L33
L10:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
L14:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D13: r

tool: D16: /proc/user_beancounters

tool: D15: %s

assistant: ```c
int main() {
  char line[1024];
  FILE *file = fopen("/proc/user_beancounters", "r");
  if (file == NULL)
    exit(1);
  while (fgets(line, 1024, file))
    printf("%s", line);
  fclose(file);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  lea    D20(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
L15:
  mov    %rsp,%rbx
  lea    D1(%rip),%r12
  jmp    L43
  nopl   0x0(%rax)
L48:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L43:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L48
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string

tool: D7: r

tool: D20: /proc/user_beancounters

tool: D1: %s

assistant: ```c
int main() {
  char line[1024];
  FILE *file = fopen("/proc/user_beancounters", "r");
  if (file == NULL)
    exit(1);
  while (fgets(line, 1024, file))
    printf("%s", line);
  fclose(file);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rsi
  lea    D24(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L40
L12:
  mov    %rsp,%rbx
  lea    D11(%rip),%r12
  jmp    L43
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L43:
  mov    %rbp,%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L12
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string

tool: D22: r

tool: D24: /proc/user_beancounters

tool: D11: %s

assistant: ```c
int main() {
  char line[1024];
  FILE *file = fopen("/proc/user_beancounters", "r");
  if (file == NULL)
    exit(1);
  while (fgets(line, 1024, file))
    printf("%s", line);
  fclose(file);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<hpack_decode_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L41
  cmpl   $0x8,-0x24(%rbp)
  ja     L41
  mov    $0x1,%eax
  jmp    L85
L41:
  mov    $0x0,%eax
L85:
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L29
  movl   $0x0,-0x1c(%rbp)
L87:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L38
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L60
L38:
  cmpl   $0x1b,-0x1c(%rbp)
  jbe    L59
  mov    D38(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L60
L59:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,-0x20(%rbp)
  addl   $0x7,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L87
L29:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%eax
L60:
  leave
  ret
```

assistant: ```c
int_fast32_t hpack_decode_int(unsigned n, const uint8_t **restrict datap, size_t *restrict lengthp) {
  const uint8_t *p = *datap;
  size_t length = *lengthp;
  assert(n >= 1 && n <= 8);
  assert(length >= 1);
  unsigned mask = (1 << n) - 1;
  uint_fast32_t i = *(p++) & mask;
  length--;
  if (i == mask) {
    unsigned shift = 0;
    uint8_t b;
    do {
      if (length-- < 1) {
        errno = EINVAL;
        return -1;
      }
      if (shift >= 28) {
        errno = ERANGE;
        return -1;
      }
      b = *(p++);
      i += (b & 0x7F) << shift;
      shift += 7;
    } while (b & 0x80);
  }
  *datap = p;
  *lengthp = length;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hpack_decode_int>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    (%rsi),%r13
  mov    (%rdx),%r12
  lea    -0x1(%rdi),%eax
  cmp    $0x7,%eax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edx
  mov    %r14d,%ecx
  shl    %cl,%edx
  sub    $0x1,%edx
  lea    0x4(%r13),%rdi
  mov    %edx,%eax
  and    0x0(%r13),%eax
  lea    -0x1(%r12),%rsi
  cmp    %eax,%edx
  je     L51
L66:
  mov    %rdi,0x0(%rbp)
  mov    %rsi,(%rbx)
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  lea    -0x2(%r12),%rsi
  mov    $0x0,%ecx
  jmp    L14
L69:
  mov    %rdx,%rsi
L14:
  cmp    $0xffffffffffffffff,%rsi
  je     L39
  cmp    $0x1c,%ecx
  je     L78
  add    $0x4,%rdi
  mov    -0x4(%rdi),%r8d
  mov    %r8d,%edx
  and    $0x7f,%edx
  shl    %cl,%edx
  add    %edx,%eax
  add    $0x7,%ecx
  lea    -0x1(%rsi),%rdx
  test   $0x80,%r8b
  jne    L69
  jmp    L66
L39:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L35
L78:
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L35
```

assistant: ```c
int_fast32_t hpack_decode_int(unsigned n, const uint8_t **restrict datap, size_t *restrict lengthp) {
  const uint8_t *p = *datap;
  size_t length = *lengthp;
  assert(n >= 1 && n <= 8);
  assert(length >= 1);
  unsigned mask = (1 << n) - 1;
  uint_fast32_t i = *(p++) & mask;
  length--;
  if (i == mask) {
    unsigned shift = 0;
    uint8_t b;
    do {
      if (length-- < 1) {
        errno = EINVAL;
        return -1;
      }
      if (shift >= 28) {
        errno = ERANGE;
        return -1;
      }
      b = *(p++);
      i += (b & 0x7F) << shift;
      shift += 7;
    } while (b & 0x80);
  }
  *datap = p;
  *lengthp = length;
  return i;
}
```