ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  shr    $0x3,%rax
  or     $0xbab5,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x2(%rdi),%esi
  test   %si,%si
  je     L5
  mov    $0x0,%eax
  lea    0x6(%rsp),%rdi
  jmp    L9
L52:
  movzwl %ax,%edx
  lea    (%rdi,%rdx,2),%rdx
  movzbl (%rdx),%ecx
  movzbl 0x1(%rdx),%r9d
  mov    %r9b,(%rdx)
  mov    %cl,0x1(%rdx)
  movzwl 0x6(%rsp),%ecx
  movzwl %ax,%edx
  movzwl %cx,%r9d
  shr    %cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  sar    %cl,%r9d
  mov    %r9w,0x6(%rsp,%rdx,2)
L44:
  add    $0x2,%eax
  cmp    %si,%ax
  jae    L5
L9:
  movzwl 0x6(%rsp),%ecx
  cmp    %ax,%cx
  jbe    L52
  movzwl %ax,%edx
  movzwl %cx,%r9d
  and    $0x6,%ecx
  or     $0x1,%ecx
  sar    %cl,%r9d
  mov    %r9w,0x6(%rsp,%rdx,2)
  jmp    L44
L5:
  movzwl 0x6(%rsp),%eax
  shr    $0x5,%rax
  and    $0xed6,%ax
  mov    %ax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL);
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> (unsigned short)5;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl (%rdi),%ecx
  movzwl 0x2(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shr    $0x3,%rcx
  or     $0xbab5,%cx
  mov    %cx,0x6(%rsp)
  test   %r8w,%r8w
  je     L4
  xor    %edx,%edx
  lea    0x6(%rsp),%r9
  jmp    L29
  nopl   (%rax)
L23:
  movzwl %cx,%eax
  and    $0x6,%ecx
  add    $0x2,%edx
  or     $0x1,%ecx
  sar    %cl,%eax
  mov    %eax,%ecx
  mov    %cx,0x6(%rsp,%rdi,2)
  cmp    %r8w,%dx
  jae    L4
L29:
  movzwl %dx,%edi
  cmp    %cx,%dx
  jb     L23
  movzwl %dx,%eax
  add    $0x2,%edx
  rolw   $0x8,(%r9,%rax,2)
  movzwl 0x6(%rsp),%eax
  mov    %eax,%ecx
  shr    %cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  sar    %cl,%eax
  mov    %eax,%ecx
  mov    %cx,0x6(%rsp,%rdi,2)
  cmp    %r8w,%dx
  jb     L29
L4:
  shr    $0x5,%cx
  and    $0x6d6,%cx
  mov    %cx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL);
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> (unsigned short)5;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl (%rdi),%ecx
  movzwl 0x2(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  shr    $0x3,%rcx
  or     $0xbab5,%cx
  mov    %cx,0x6(%rsp)
  test   %r8w,%r8w
  je     L50
  lea    0x6(%rsp),%r9
  nopl   0x0(%rax)
L19:
  movzwl %ax,%edx
  cmp    %cx,%ax
  jae    L11
  movzwl %cx,%edi
  and    $0x6,%ecx
  add    $0x2,%eax
  or     $0x1,%ecx
  sar    %cl,%edi
  mov    %di,0x6(%rsp,%rdx,2)
  mov    %edi,%ecx
  cmp    %ax,%r8w
  ja     L19
L50:
  shr    $0x5,%cx
  and    $0x6d6,%cx
  mov    %cx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L11:
  movzwl %ax,%ecx
  add    $0x2,%eax
  rolw   $0x8,(%r9,%rcx,2)
  movzwl 0x6(%rsp),%edi
  mov    %edi,%ecx
  shr    %cx
  and    $0x6,%ecx
  or     $0x1,%ecx
  sar    %cl,%edi
  mov    %di,0x6(%rsp,%rdx,2)
  mov    %edi,%ecx
  cmp    %r8w,%ax
  jb     L19
  jmp    L50
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] = state[0UL] >> ((state[0UL] & (unsigned short)7) | 1UL);
        }
      } else if (state[0UL] <= local1) {
        copy14 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy14;
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)1) & (unsigned short)7) | 1UL);
      } else {
        state[local1] = state[0UL] >> (((state[0UL] >> (unsigned short)2) & (unsigned short)7) | 1UL);
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 237099718UL) >> (unsigned short)5;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trev_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L4:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x4,-0xc(%rbp)
  jle    L14
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x4,-0x8(%rbp)
  jle    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void trev_conv(float h[], float target[], float pn[]) {
  int j, k;
  for (k = 0; k < 5; k++) {
    float tmp = 0.0;
    for (j = k; j < 5; j++)
      tmp += target[j] * h[j - k];
    pn[k] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trev_conv>:
  endbr64
  mov    $0x0,%ecx
L1:
  mov    %rcx,%rax
  pxor   %xmm1,%xmm1
  cmp    $0x4,%ecx
  jg     L14
L19:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    $0x4,%eax
  jle    L19
L14:
  movss  %xmm1,(%rdx,%rcx,4)
  add    $0x1,%rcx
  sub    $0x4,%rdi
  cmp    $0x5,%rcx
  jne    L1
  ret
```

assistant: ```c
void trev_conv(float h[], float target[], float pn[]) {
  int j, k;
  for (k = 0; k < 5; k++) {
    float tmp = 0.0;
    for (j = k; j < 5; j++)
      tmp += target[j] * h[j - k];
    pn[k] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trev_conv>:
  endbr64
  xor    %ecx,%ecx
L18:
  mov    %rcx,%rax
  pxor   %xmm1,%xmm1
L10:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    $0x5,%eax
  jne    L10
  movss  %xmm1,(%rdx,%rcx,4)
  add    $0x1,%rcx
  sub    $0x4,%rdi
  cmp    $0x5,%rcx
  jne    L18
  ret
```

assistant: ```c
void trev_conv(float h[], float target[], float pn[]) {
  int j, k;
  for (k = 0; k < 5; k++) {
    float tmp = 0.0;
    for (j = k; j < 5; j++)
      tmp += target[j] * h[j - k];
    pn[k] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trev_conv>:
  endbr64
  movups (%rsi),%xmm0
  movups (%rdi),%xmm4
  pxor   %xmm2,%xmm2
  mulps  %xmm4,%xmm0
  movaps %xmm0,%xmm1
  movaps %xmm0,%xmm3
  addss  %xmm2,%xmm1
  shufps $0x55,%xmm0,%xmm3
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  unpckhps %xmm0,%xmm3
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  0x10(%rsi),%xmm1
  mulss  0x10(%rdi),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  movups 0x4(%rsi),%xmm0
  movups (%rdi),%xmm5
  mulps  %xmm5,%xmm0
  movaps %xmm0,%xmm1
  movaps %xmm0,%xmm3
  addss  %xmm2,%xmm1
  shufps $0x55,%xmm0,%xmm3
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  unpckhps %xmm0,%xmm3
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdx)
  movss  0x8(%rsi),%xmm0
  mulss  (%rdi),%xmm0
  movss  0xc(%rsi),%xmm1
  mulss  0x4(%rdi),%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  0x10(%rsi),%xmm0
  mulss  0x8(%rdi),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdx)
  movss  0xc(%rsi),%xmm1
  mulss  (%rdi),%xmm1
  movss  0x10(%rsi),%xmm0
  mulss  0x4(%rdi),%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdx)
  movss  0x10(%rsi),%xmm0
  mulss  (%rdi),%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void trev_conv(float h[], float target[], float pn[]) {
  int j, k;
  for (k = 0; k < 5; k++) {
    float tmp = 0.0;
    for (j = k; j < 5; j++)
      tmp += target[j] * h[j - k];
    pn[k] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__arch_fetch_and_add_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lock xadd %rax,(%rdx)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *__arch_fetch_and_add_ptr(void **pointer, long int delta) {
  void *temp = (void *)delta;
  __asm__("  lock;"
          "  xadd %0,(%1);"
          : "+r"(temp)
          : "p"(pointer)
          : "memory");
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__arch_fetch_and_add_ptr>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
void *__arch_fetch_and_add_ptr(void **pointer, long int delta) {
  void *temp = (void *)delta;
  __asm__("  lock;"
          "  xadd %0,(%1);"
          : "+r"(temp)
          : "p"(pointer)
          : "memory");
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__arch_fetch_and_add_ptr>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
void *__arch_fetch_and_add_ptr(void **pointer, long int delta) {
  void *temp = (void *)delta;
  __asm__("  lock;"
          "  xadd %0,(%1);"
          : "+r"(temp)
          : "p"(pointer)
          : "memory");
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__arch_fetch_and_add_ptr>:
  endbr64
  mov    %rsi,%rax
  lock xadd %rax,(%rdi)
  ret
```

assistant: ```c
void *__arch_fetch_and_add_ptr(void **pointer, long int delta) {
  void *temp = (void *)delta;
  __asm__("  lock;"
          "  xadd %0,(%1);"
          : "+r"(temp)
          : "p"(pointer)
          : "memory");
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0x4(%rbp)
L10:
  cmpl   $0x96,-0x4(%rbp)
  jle    L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D14: 
 Aqui aparecerao 50 nomeros impares 

tool: D2: %d-

assistant: ```c
int main() {
  printf("\n Aqui aparecerao 50 nomeros impares ");
  int num;
  num = 1;
  while (num <= 150) {
    printf("%d-", num);
    num = num + 2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D15(%rip),%rbp
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    $0x97,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D17: 
 Aqui aparecerao 50 nomeros impares 

tool: D15: %d-

assistant: ```c
int main() {
  printf("\n Aqui aparecerao 50 nomeros impares ");
  int num;
  num = 1;
  while (num <= 150) {
    printf("%d-", num);
    num = num + 2;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    $0x97,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D15: 
 Aqui aparecerao 50 nomeros impares 

tool: D2: %d-

assistant: ```c
int main() {
  printf("\n Aqui aparecerao 50 nomeros impares ");
  int num;
  num = 1;
  while (num <= 150) {
    printf("%d-", num);
    num = num + 2;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax)
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    $0x97,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type: string
name: read_data
arguments: data_tag: D1
type: string

tool: D18: 
 Aqui aparecerao 50 nomeros impares 

tool: D1: %d-

assistant: ```c
int main() {
  printf("\n Aqui aparecerao 50 nomeros impares ");
  int num;
  num = 1;
  while (num <= 150) {
    printf("%d-", num);
    num = num + 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<chdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int chdir(const char *path) {
  ;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chdir>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chdir(const char *path) {
  ;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chdir>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chdir(const char *path) {
  ;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chdir>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chdir(const char *path) {
  ;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  x = 0;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cookie_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x14,-0x24(%rbp)
  je     L38
  mov    $0x0,%eax
  jmp    L31
L38:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L30:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  je     L21
  mov    $0x0,%eax
  jmp    L31
L21:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x20(%rbp)
L20:
  cmpl   $0x13,-0x4(%rbp)
  jbe    L30
  mov    $0x1,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int cookie_verify(SSL *ssl, const unsigned char *cookie, unsigned int cookie_len) {
  unsigned int i;
  if (cookie_len != 20)
    return 0;
  for (i = 0; i < 20; i++, cookie++) {
    if (*cookie != i)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<cookie_verify>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x14,%edx
  jne    L24
  mov    $0x0,%eax
L2:
  movzbl (%rsi,%rax,1),%edx
  cmp    %eax,%edx
  jne    L3
  add    $0x1,%rax
  cmp    $0x14,%rax
  jne    L2
  mov    $0x1,%eax
  ret
L3:
  mov    $0x0,%eax
L24:
  ret
```

assistant: ```c
int cookie_verify(SSL *ssl, const unsigned char *cookie, unsigned int cookie_len) {
  unsigned int i;
  if (cookie_len != 20)
    return 0;
  for (i = 0; i < 20; i++, cookie++) {
    if (*cookie != i)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cookie_verify>:
  endbr64
  xor    %eax,%eax
  cmp    $0x14,%edx
  jne    L39
  xor    %eax,%eax
  jmp    L1
  nop
L11:
  add    $0x1,%rax
  cmp    $0x14,%rax
  je     L24
L1:
  movzbl (%rsi,%rax,1),%edx
  cmp    %eax,%edx
  je     L11
  xor    %eax,%eax
L39:
  ret
  nopl   (%rax)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cookie_verify(SSL *ssl, const unsigned char *cookie, unsigned int cookie_len) {
  unsigned int i;
  if (cookie_len != 20)
    return 0;
  for (i = 0; i < 20; i++, cookie++) {
    if (*cookie != i)
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cookie_verify>:
  endbr64
  xor    %eax,%eax
  cmp    $0x14,%edx
  jne    L19
  xor    %eax,%eax
  jmp    L16
  nop
L29:
  add    $0x1,%rax
  cmp    $0x14,%rax
  je     L33
L16:
  movzbl (%rsi,%rax,1),%edx
  cmp    %eax,%edx
  je     L29
  xor    %eax,%eax
L19:
  ret
  nopl   (%rax)
L33:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cookie_verify(SSL *ssl, const unsigned char *cookie, unsigned int cookie_len) {
  unsigned int i;
  if (cookie_len != 20)
    return 0;
  for (i = 0; i < 20; i++, cookie++) {
    if (*cookie != i)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vWriteFrmtd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void vWriteFrmtd(char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vWriteFrmtd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vWriteFrmtd(char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vWriteFrmtd>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vWriteFrmtd(char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vWriteFrmtd>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vWriteFrmtd(char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2,-0x8(%rbp)
  jmp    L36
L31:
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L25
  mov    $0x0,%eax
  jmp    L21
L25:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  cmp    %rax,-0x8(%rbp)
  jl     L31
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
unsigned short int isPrime(unsigned long int number) {
  for (long i = 2; i < sqrt(number); i++)
    if (number % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPrime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2,%ebx
  jmp    L5
L23:
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jle    L27
  mov    %rbp,%rax
  mov    $0x0,%edx
  div    %rbx
  test   %rdx,%rdx
  jne    L23
  mov    $0x0,%eax
  jmp    L12
L27:
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short int isPrime(unsigned long int number) {
  for (long i = 2; i < sqrt(number); i++)
    if (number % i == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPrime>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   (%rax)
L12:
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  test   %rdx,%rdx
  je     L9
  add    $0x1,%rbx
L7:
  mov    %r12,%rdi
  call   <sqrt@plt>
  cmp    %rbx,%rax
  jg     L12
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned short int isPrime(unsigned long int number) {
  for (long i = 2; i < sqrt(number); i++)
    if (number % i == 0)
      return 0;
  return 1;
}
```