ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mmc_send_initialization_stream>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  call   <regmask32@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <mmc_send_command@plt>
  test   %eax,%eax
  jne    L13
L3:
  jmp    L3
L13:
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  call   <regmask32@plt>
  mov    $0x337f07ff,%edx
  mov    $0x337f07ff,%esi
  mov    $0x48060230,%edi
  call   <regmask32@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mmc_send_initialization_stream(void) {
  regmask32(0x48060000 + 0x12c, (1 << 1), (1 << 1));
  if (!mmc_send_command(0 << 24, 0))
    while (1)
      ;
  regmask32(0x48060000 + 0x12c, (1 << 1), (0 << 1));
  regmask32(0x48060000 + 0x230, 0x337f07ff, 0x337f07ff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mmc_send_initialization_stream>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  mov    $0x2,%edx
  call   <regmask32@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <mmc_send_command@plt>
  test   %eax,%eax
  jne    L6
L0:
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  call   <regmask32@plt>
  mov    $0x337f07ff,%edx
  mov    $0x337f07ff,%esi
  mov    $0x48060230,%edi
  add    $0x8,%rsp
  jmp    1070 <regmask32@plt>
```

assistant: ```c
void mmc_send_initialization_stream(void) {
  regmask32(0x48060000 + 0x12c, (1 << 1), (1 << 1));
  if (!mmc_send_command(0 << 24, 0))
    while (1)
      ;
  regmask32(0x48060000 + 0x12c, (1 << 1), (0 << 1));
  regmask32(0x48060000 + 0x230, 0x337f07ff, 0x337f07ff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mmc_send_initialization_stream>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  mov    $0x2,%edx
  call   <regmask32@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <mmc_send_command@plt>
  test   %eax,%eax
  jne    L18
L16:
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    $0x4806012c,%edi
  call   <regmask32@plt>
  mov    $0x337f07ff,%edx
  mov    $0x337f07ff,%esi
  mov    $0x48060230,%edi
  add    $0x8,%rsp
  jmp    1070 <regmask32@plt>
```

assistant: ```c
void mmc_send_initialization_stream(void) {
  regmask32(0x48060000 + 0x12c, (1 << 1), (1 << 1));
  if (!mmc_send_command(0 << 24, 0))
    while (1)
      ;
  regmask32(0x48060000 + 0x12c, (1 << 1), (0 << 1));
  regmask32(0x48060000 + 0x230, 0x337f07ff, 0x337f07ff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zeds_device>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x7,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  ja     L15
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D15(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L8:
  nop
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L8
L15:
  nop
  pop    %rbp
  ret
```

assistant: ```c
int zeds_device(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zeds_device>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rax
  lea    0xe(%rdx),%esi
  mov    %edx,%edi
  add    $0x7,%edi
  cmovns %edi,%esi
  sar    $0x3,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L6
  mov    %edx,%edx
  lea    D3(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
L26:
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  lea    0x1(%rcx),%rcx
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  lea    0x1(%rax),%rax
  lea    0x1(%rcx),%rcx
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L41:
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  movzbl (%rdi),%edi
  mov    %dil,(%rdx)
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L32:
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  movzbl (%rdi),%edi
  mov    %dil,(%rdx)
  lea    0x1(%rcx),%rdi
  lea    0x1(%rax),%rdx
  movzbl (%rcx),%ecx
  mov    %cl,(%rax)
L12:
  movzbl (%rdi),%eax
  mov    %al,(%rdx)
  sub    $0x1,%esi
  lea    0x1(%rdi),%rcx
  lea    0x1(%rdx),%rax
  test   %esi,%esi
  jg     L26
L6:
  ret
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L41
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L32
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L12
```

assistant: ```c
int zeds_device(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zeds_device>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %rsi,%rax
  add    $0x7,%edi
  lea    0xe(%rdx),%esi
  cmovns %edi,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  sar    $0x3,%esi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L8
  lea    D1(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
L9:
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L44:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r9
  lea    0x1(%rax),%r8
  mov    %dl,(%rax)
L3:
  movzbl (%r9),%eax
  lea    0x1(%r9),%rdi
  lea    0x1(%r8),%rdx
  mov    %al,(%r8)
L34:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %esi,%esi
  jg     L9
L8:
  ret
  nop
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L34
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%r8
  mov    %rcx,%r9
  jmp    L3
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L44
```

assistant: ```c
int zeds_device(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zeds_device>:
  endbr64
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %rsi,%rax
  add    $0x7,%edi
  lea    0xe(%rdx),%esi
  cmovns %edi,%esi
  mov    %edx,%edi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  sar    $0x3,%esi
  add    %edi,%edx
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L13
  lea    D9(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
L11:
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L32:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r9
  lea    0x1(%rax),%r8
  mov    %dl,(%rax)
L12:
  movzbl (%r9),%eax
  lea    0x1(%r9),%rdi
  lea    0x1(%r8),%rdx
  mov    %al,(%r8)
L5:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %esi,%esi
  jg     L11
L13:
  ret
  nop
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L5
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%r8
  mov    %rcx,%r9
  jmp    L12
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L32
```

assistant: ```c
int zeds_device(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<minmax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L50
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L44:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x2,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L51
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L44
L51:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L53
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
L53:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L27
L50:
  nop
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: min = %d, max = %d.


assistant: ```c
void minmax(int *xs, int n) {
  if (!xs)
    return;
  int mn = *xs, mx = *xs, i = 0;
  for (i = 0; i < n && i + 1 < n; i = i + 2) {
    int lower = xs[i] < xs[i + 1] ? xs[i] : xs[i + 1];
    int upper = xs[i] > xs[i + 1] ? xs[i] : xs[i + 1];
    mn = lower < mn ? lower : mn;
    mx = upper > mx ? upper : mx;
  }
  if (i < n) {
    mn = xs[i] < mn ? xs[i] : mn;
    mx = xs[i] > mx ? xs[i] : mx;
  }
  printf("min = %d, max = %d.\n", mn, mx);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<minmax>:
  endbr64
  test   %rdi,%rdi
  je     L46
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r11d
  mov    (%rdi),%esi
  cmp    $0x1,%r11d
  jle    L32
  mov    %rdi,%rdx
  lea    -0x2(%r11),%ebx
  shr    %ebx
  mov    %ebx,%eax
  lea    0x8(%rdi,%rax,8),%r9
  mov    %esi,%edi
L31:
  mov    0x4(%rdx),%eax
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  mov    %ecx,%r8d
  cmovle %eax,%r8d
  cmp    %r8d,%esi
  cmovg  %r8d,%esi
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  cmp    %eax,%edi
  cmovl  %eax,%edi
  add    $0x8,%rdx
  cmp    %r9,%rdx
  jne    L31
  lea    0x2(%rbx,%rbx,1),%eax
L12:
  cmp    %eax,%r11d
  jle    L29
  cltq
  mov    (%r10,%rax,4),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %eax,%edi
  cmovl  %eax,%edi
L29:
  mov    %edi,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
L32:
  mov    %esi,%edi
  mov    $0x0,%eax
  jmp    L12
L46:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: min = %d, max = %d.


assistant: ```c
void minmax(int *xs, int n) {
  if (!xs)
    return;
  int mn = *xs, mx = *xs, i = 0;
  for (i = 0; i < n && i + 1 < n; i = i + 2) {
    int lower = xs[i] < xs[i + 1] ? xs[i] : xs[i + 1];
    int upper = xs[i] > xs[i + 1] ? xs[i] : xs[i + 1];
    mn = lower < mn ? lower : mn;
    mx = upper > mx ? upper : mx;
  }
  if (i < n) {
    mn = xs[i] < mn ? xs[i] : mn;
    mx = xs[i] > mx ? xs[i] : mx;
  }
  printf("min = %d, max = %d.\n", mn, mx);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minmax>:
  endbr64
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L9
  mov    (%rdi),%esi
  test   %eax,%eax
  jle    L13
  cmp    $0x1,%eax
  je     L13
  lea    -0x1(%rax),%ecx
  sub    $0x2,%eax
  lea    0x4(%rdi),%rdx
  mov    %esi,%r8d
  shr    %ecx
  shr    %eax
  lea    (%rdx,%rcx,8),%r9
  lea    0xc(%rdi,%rax,8),%r10
  mov    %esi,%ecx
  jmp    L68
L44:
  add    $0x8,%rdx
  mov    -0x4(%rdx),%ecx
  cmp    %r10,%rdx
  je     L50
L68:
  mov    (%rdx),%eax
  mov    %ecx,%edi
  cmp    %ecx,%eax
  cmovle %eax,%edi
  cmp    %edi,%esi
  cmovg  %edi,%esi
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  cmp    %r9,%rdx
  jne    L44
L45:
  mov    %r8d,%edx
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    %ecx,%esi
  lea    D9(%rip),%rdi
  cmovg  %ecx,%esi
  cmp    %ecx,%r8d
  cmovl  %ecx,%r8d
  mov    %r8d,%edx
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
  nopl   0x0(%rax)
L13:
  mov    %esi,%r8d
  jmp    L45
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: min = %d, max = %d.


assistant: ```c
void minmax(int *xs, int n) {
  if (!xs)
    return;
  int mn = *xs, mx = *xs, i = 0;
  for (i = 0; i < n && i + 1 < n; i = i + 2) {
    int lower = xs[i] < xs[i + 1] ? xs[i] : xs[i + 1];
    int upper = xs[i] > xs[i + 1] ? xs[i] : xs[i + 1];
    mn = lower < mn ? lower : mn;
    mx = upper > mx ? upper : mx;
  }
  if (i < n) {
    mn = xs[i] < mn ? xs[i] : mn;
    mx = xs[i] > mx ? xs[i] : mx;
  }
  printf("min = %d, max = %d.\n", mn, mx);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<minmax>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r10d
  test   %rdi,%rdi
  je     L60
  mov    (%rdi),%esi
  test   %r10d,%r10d
  jle    L52
  cmp    $0x1,%r10d
  je     L52
  lea    -0x2(%r10),%eax
  mov    %esi,%r8d
  mov    $0x2,%edx
  shr    %eax
  lea    0x2(%rax),%r11d
  add    %r11,%r11
  jmp    L4
  nop
L1:
  add    $0x2,%rdx
  cmp    %rdx,%r11
  je     L53
L4:
  mov    -0x4(%r9,%rdx,4),%eax
  mov    -0x8(%r9,%rdx,4),%ecx
  cmp    %ecx,%eax
  mov    %ecx,%edi
  cmovle %eax,%edi
  cmp    %edi,%esi
  cmovg  %edi,%esi
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  movslq %edx,%rax
  cmp    %edx,%r10d
  jg     L1
L37:
  mov    %r8d,%edx
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L53:
  mov    (%r9,%rax,4),%eax
  lea    D13(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  mov    %r8d,%edx
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L60:
  ret
  nopl   0x0(%rax)
L52:
  mov    %esi,%r8d
  jmp    L37
```

tool_calls: name: parse_data
arguments: tag: D13
data_type: string

tool: D13: min = %d, max = %d.


assistant: ```c
void minmax(int *xs, int n) {
  if (!xs)
    return;
  int mn = *xs, mx = *xs, i = 0;
  for (i = 0; i < n && i + 1 < n; i = i + 2) {
    int lower = xs[i] < xs[i + 1] ? xs[i] : xs[i + 1];
    int upper = xs[i] > xs[i + 1] ? xs[i] : xs[i + 1];
    mn = lower < mn ? lower : mn;
    mx = upper > mx ? upper : mx;
  }
  if (i < n) {
    mn = xs[i] < mn ? xs[i] : mn;
    mx = xs[i] > mx ? xs[i] : mx;
  }
  printf("min = %d, max = %d.\n", mn, mx);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L66
L10:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L87
  mov    $0x0,%eax
  jmp    L14
L87:
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L20
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D26(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L66
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L74
  jmp    L66
L74:
  mov    $0xffffffff,%eax
  jmp    L14
L20:
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x8(%rbp)
L66:
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    -0x38(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
ssize_t write_n(int fd, const void *buf, size_t count) {
  const char *ptr = buf;
  size_t left = count;
  while (left) {
    ssize_t written = write(fd, ptr, left);
    if (written == 0)
      return 0;
    else if (written == -1) {
      if (errno == EAGAIN || errno == EWOULDBLOCK)
        continue;
      return -1;
    }
    ptr += written;
    left -= written;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_n>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L65
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  jmp    L37
L62:
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
L77:
  test   %rbx,%rbx
  je     L65
L37:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L16
  cmp    $0xffffffff,%eax
  jne    L62
  mov    D3(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D5(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L77
  mov    D4(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L77
  jmp    L16
L65:
  mov    %r13d,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_n(int fd, const void *buf, size_t count) {
  const char *ptr = buf;
  size_t left = count;
  while (left) {
    ssize_t written = write(fd, ptr, left);
    if (written == 0)
      return 0;
    else if (written == -1) {
      if (errno == EAGAIN || errno == EWOULDBLOCK)
        continue;
      return -1;
    }
    ptr += written;
    left -= written;
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_n>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L7
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xchg   %ax,%ax
L31:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L58
  cmp    $0xffffffff,%eax
  je     L39
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L31
L7:
  mov    %r12d,%eax
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L39:
  mov    D3(%rip),%rdx
  mov    D4(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L31
  mov    D13(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_n(int fd, const void *buf, size_t count) {
  const char *ptr = buf;
  size_t left = count;
  while (left) {
    ssize_t written = write(fd, ptr, left);
    if (written == 0)
      return 0;
    else if (written == -1) {
      if (errno == EAGAIN || errno == EWOULDBLOCK)
        continue;
      return -1;
    }
    ptr += written;
    left -= written;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_n>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L59
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  xchg   %ax,%ax
L41:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L20
  cmp    $0xffffffff,%eax
  je     L35
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L41
L59:
  mov    %r12d,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L35:
  mov    D2(%rip),%rdx
  mov    D20(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L41
  mov    D16(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L41
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_n(int fd, const void *buf, size_t count) {
  const char *ptr = buf;
  size_t left = count;
  while (left) {
    ssize_t written = write(fd, ptr, left);
    if (written == 0)
      return 0;
    else if (written == -1) {
      if (errno == EAGAIN || errno == EWOULDBLOCK)
        continue;
      return -1;
    }
    ptr += written;
    left -= written;
  }
  return count;
}
```