ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa2>:
  endbr64
  push   %r13
  mov    %rdi,%rax
  mov    %rsi,%r10
  movabs $0x2020202020202020,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x18(%rsp)
  xor    %ecx,%ecx
  mov    $0x2020,%ecx
  mov    %rdi,(%rsp)
  movl   $0x20202020,0x8(%rsp)
  mov    %cx,0xc(%rsp)
  movb   $0x20,0xe(%rsp)
  movb   $0x0,0xf(%rsp)
  test   %rax,%rax
  jns    L3
  cmp    $0xa,%edx
  jne    L3
  neg    %rax
  mov    $0xffffffffffffffff,%r12
L90:
  mov    (%rbx),%rbp
  movslq %edx,%rdi
  mov    $0x1,%r8d
  mov    %rsp,%r11
  mov    $0xe,%esi
  nopl   0x0(%rax)
L34:
  xor    %edx,%edx
  mov    %rax,%r9
  div    %rdi
  lea    0x30(%rdx),%r13d
  lea    0x57(%rdx),%ecx
  cmp    $0x9,%rdx
  cmovle %r13d,%ecx
  mov    %cl,(%r11,%rsi,1)
  cmp    %r9,%rdi
  jbe    L53
  mov    %r8,%r13
  cmp    %rbp,%r8
  jge    L100
L53:
  sub    $0x1,%rsi
  add    $0x1,%r8
  cmp    $0xffffffffffffffff,%rsi
  jne    L34
  mov    $0x10,%r13d
L100:
  cmp    $0xffffffffffffffff,%r12
  jne    L21
  sub    $0x1,%rsi
  mov    $0xf,%r13d
  movb   $0x2d,(%rsp,%rsi,1)
  sub    %rsi,%r13
L21:
  test   %rbp,%rbp
  je     L16
  cmp    %rbp,%r13
  jle    L4
L16:
  add    %r11,%rsi
  mov    %r10,%rdi
  call   <strcpy2@plt>
  mov    %r13,(%rbx)
L105:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L3:
  mov    $0x1,%r12d
  jmp    L90
  nopl   0x0(%rax,%rax,1)
L4:
  sub    %rbp,%r11
  mov    %r10,%rdi
  lea    0xf(%r11),%rsi
  call   <strcpy2@plt>
  jmp    L105
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void itoa2(long n, char *s, int base, long *digits) {
  long i, j, sign;
  unsigned long n2;
  char number[20];
  for (i = 0; i < 15; ++i) {
    number[i] = ' ';
  }
  number[15] = 0;
  if (n >= 0 || base != 10) {
    sign = 1;
  } else {
    sign = -1;
  }
  n2 = n * sign;
  for (j = 14; j >= 0; --j) {
    i = n2 % base;
    n2 /= base;
    number[j] = i < 10 ? '0' + i : 'a' + i - 10;
    if (n2 == 0 && 15 - j >= *digits)
      break;
  }
  if (sign == -1) {
    number[--j] = '-';
  }
  if (*digits == 0 || *digits < 15 - j) {
    strcpy2(s, &number[j]);
    *digits = 15 - j;
  } else {
    strcpy2(s, &number[15 - *digits]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<load_samples>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  add    $0x3000,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  lea    -0x1003(%rax),%rdx
  mov    -0x50(%rbp),%rsi
  lea    -0x28(%rbp),%rax
  mov    $0x3,%ecx
  mov    %rax,%rdi
  call   <best_flag@plt>
  movq   $0x0,-0x20(%rbp)
  jmp    L10
L23:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <get18@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addq   $0x1,-0x20(%rbp)
L10:
  mov    -0x20(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jb     L23
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void load_samples(float *samples, const unsigned char *buffer, size_t bytes, size_t num_samples) {
  const unsigned char *best = buffer + 4096 * 3;
  best_flag(&best, num_samples, bytes - 4096 - 3, 3);
  for (size_t i = 0; i < num_samples; ++i)
    samples[i] = get18(best + i * 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<load_samples>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  add    $0x3000,%rsi
  mov    %rsi,(%rsp)
  sub    $0x1003,%rdx
  mov    %rsp,%rdi
  mov    $0x3,%ecx
  mov    %rbp,%rsi
  call   <best_flag@plt>
  test   %rbp,%rbp
  je     L12
  mov    $0x0,%ebx
L8:
  lea    (%rbx,%rbx,2),%rdi
  add    (%rsp),%rdi
  call   <get18@plt>
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L8
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void load_samples(float *samples, const unsigned char *buffer, size_t bytes, size_t num_samples) {
  const unsigned char *best = buffer + 4096 * 3;
  best_flag(&best, num_samples, bytes - 4096 - 3, 3);
  for (size_t i = 0; i < num_samples; ++i)
    samples[i] = get18(best + i * 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<load_samples>:
  endbr64
  push   %r12
  add    $0x3000,%rsi
  mov    %rdi,%r12
  sub    $0x1003,%rdx
  push   %rbp
  mov    %rcx,%rbp
  mov    $0x3,%ecx
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsi,(%rsp)
  mov    %rbp,%rsi
  call   <best_flag@plt>
  test   %rbp,%rbp
  je     L26
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  lea    (%rbx,%rbx,2),%rdi
  add    (%rsp),%rdi
  call   <get18@plt>
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L4
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void load_samples(float *samples, const unsigned char *buffer, size_t bytes, size_t num_samples) {
  const unsigned char *best = buffer + 4096 * 3;
  best_flag(&best, num_samples, bytes - 4096 - 3, 3);
  for (size_t i = 0; i < num_samples; ++i)
    samples[i] = get18(best + i * 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<load_samples>:
  endbr64
  push   %r12
  add    $0x3000,%rsi
  mov    %rdi,%r12
  sub    $0x1003,%rdx
  push   %rbp
  mov    %rcx,%rbp
  mov    $0x3,%ecx
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsi,(%rsp)
  mov    %rbp,%rsi
  call   <best_flag@plt>
  test   %rbp,%rbp
  je     L22
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L5:
  lea    (%rbx,%rbx,2),%rdi
  add    (%rsp),%rdi
  call   <get18@plt>
  movss  %xmm0,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L5
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void load_samples(float *samples, const unsigned char *buffer, size_t bytes, size_t num_samples) {
  const unsigned char *best = buffer + 4096 * 3;
  best_flag(&best, num_samples, bytes - 4096 - 3, 3);
  for (size_t i = 0; i < num_samples; ++i)
    samples[i] = get18(best + i * 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pfl_fmt_human>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L25:
  movsd  -0x20(%rbp),%xmm0
  movsd  D35(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  movsd  -0x20(%rbp),%xmm0
  comisd D35(%rip),%xmm0
  jae    L25
  cmpl   $0x6,-0x4(%rbp)
  jle    L15
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D64(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <snprintf@plt>
  jmp    L29
L15:
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  movsd  -0x20(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D40(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <snprintf@plt>
  jmp    L29
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    D7(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D55(%rip),%rdx
  mov    $0x8,%esi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <snprintf@plt>
L29:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D35
datatype: f64[2]
name: parse_data
arguments: label: D64
datatype: string
name: parse_data
arguments: label: D0
datatype: byte[8]
name: parse_data
arguments: label: D40
datatype: string
name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D55
datatype: string

tool: {"D35": [1024.0,0.5]}

tool: D64: %.1e

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D40: %6dB

tool: D7: BKMGTPE

tool: D55: %6.1f%c

assistant: ```c
void pfl_fmt_human(char buf[8], double num) {
  int mag;
  for (mag = 0; num >= 1024.0; mag++)
    num /= 1024.0;
  if (mag > 6)
    snprintf(buf, 8, "%.1e", num);
  else if (mag == 0)
    snprintf(buf, 8, "%6dB", (int)(num + .5));
  else
    snprintf(buf, 8, "%6.1f%c", num, "BKMGTPE"[mag]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pfl_fmt_human>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  movsd  D16(%rip),%xmm2
  movsd  D62(%rip),%xmm1
  comisd %xmm1,%xmm0
  jb     L53
L4:
  mulsd  %xmm2,%xmm0
  add    $0x1,%eax
  comisd %xmm1,%xmm0
  jae    L4
  cmp    $0x6,%eax
  jg     L29
  test   %eax,%eax
  je     L53
  cltq
  lea    D52(%rip),%rdx
  movsbl (%rdx,%rax,1),%ecx
  lea    D39(%rip),%rdx
  mov    $0x8,%esi
  mov    $0x1,%eax
  call   <snprintf@plt>
  jmp    L54
L29:
  lea    D11(%rip),%rdx
  mov    $0x8,%esi
  mov    $0x1,%eax
  call   <snprintf@plt>
  jmp    L54
L53:
  addsd  D10(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  lea    D51(%rip),%rdx
  mov    $0x8,%esi
  mov    $0x1,%eax
  call   <snprintf@plt>
L54:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: byte[8]
name: parse_data
arguments: data_label: D62
type_infered: f64
name: parse_data
arguments: data_label: D52
type_infered: string
name: parse_data
arguments: data_label: D39
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: byte[8]
name: parse_data
arguments: data_label: D51
type_infered: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D62: 1024

tool: D52: BKMGTPE

tool: D39: %6.1f%c

tool: D11: %.1e

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D51: %6dB

assistant: ```c
void pfl_fmt_human(char buf[8], double num) {
  int mag;
  for (mag = 0; num >= 1024.0; mag++)
    num /= 1024.0;
  if (mag > 6)
    snprintf(buf, 8, "%.1e", num);
  else if (mag == 0)
    snprintf(buf, 8, "%6dB", (int)(num + .5));
  else
    snprintf(buf, 8, "%6.1f%c", num, "BKMGTPE"[mag]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pfl_fmt_human>:
  endbr64
  movsd  D50(%rip),%xmm1
  xor    %eax,%eax
  movsd  D37(%rip),%xmm2
  comisd %xmm1,%xmm0
  jb     L16
  nopl   0x0(%rax)
L3:
  mulsd  %xmm2,%xmm0
  add    $0x1,%eax
  comisd %xmm1,%xmm0
  jae    L3
  cmp    $0x6,%eax
  jg     L11
  cltq
  lea    D52(%rip),%rdx
  mov    $0x8,%esi
  movsbl (%rdx,%rax,1),%ecx
  lea    D22(%rip),%rdx
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
  nopl   (%rax)
L16:
  addsd  D40(%rip),%xmm0
  lea    D5(%rip),%rdx
  mov    $0x8,%esi
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D48(%rip),%rdx
  mov    $0x8,%esi
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D50
type: f64
name: retrieve_data
arguments: tag: D37
type: byte[8]
name: retrieve_data
arguments: tag: D52
type: string
name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D40
type: byte[8]
name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D48
type: string

tool: D50: 1024

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D52: BKMGTPE

tool: D22: %6.1f%c

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D5: %6dB

tool: D48: %.1e

assistant: ```c
void pfl_fmt_human(char buf[8], double num) {
  int mag;
  for (mag = 0; num >= 1024.0; mag++)
    num /= 1024.0;
  if (mag > 6)
    snprintf(buf, 8, "%.1e", num);
  else if (mag == 0)
    snprintf(buf, 8, "%6dB", (int)(num + .5));
  else
    snprintf(buf, 8, "%6.1f%c", num, "BKMGTPE"[mag]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pfl_fmt_human>:
  endbr64
  movsd  D35(%rip),%xmm1
  xor    %eax,%eax
  movsd  D3(%rip),%xmm2
  comisd %xmm1,%xmm0
  jb     L17
  nopl   0x0(%rax)
L2:
  mulsd  %xmm2,%xmm0
  add    $0x1,%eax
  comisd %xmm1,%xmm0
  jae    L2
  cmp    $0x6,%eax
  jg     L4
  cltq
  lea    D33(%rip),%rdx
  mov    $0x8,%esi
  movsbl (%rdx,%rax,1),%ecx
  lea    D1(%rip),%rdx
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
  nopl   (%rax)
L17:
  addsd  D2(%rip),%xmm0
  lea    D6(%rip),%rdx
  mov    $0x8,%esi
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D15(%rip),%rdx
  mov    $0x8,%esi
  mov    $0x1,%eax
  jmp    1050 <snprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D3
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D35: 1024

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D33: BKMGTPE

tool: D1: %6.1f%c

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D6: %6dB

tool: D15: %.1e

assistant: ```c
void pfl_fmt_human(char buf[8], double num) {
  int mag;
  for (mag = 0; num >= 1024.0; mag++)
    num /= 1024.0;
  if (mag > 6)
    snprintf(buf, 8, "%.1e", num);
  else if (mag == 0)
    snprintf(buf, 8, "%6dB", (int)(num + .5));
  else
    snprintf(buf, 8, "%6.1f%c", num, "BKMGTPE"[mag]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<USBEndpointDataAvail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L9
  movq   $0x102,-0x8(%rbp)
  jmp    L24
L9:
  mov    -0x20(%rbp),%rax
  add    $0x106,%rax
  mov    %rax,-0x8(%rbp)
L24:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L22
  mov    $0x0,%eax
  jmp    L20
L22:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  add    $0x108,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long USBEndpointDataAvail(unsigned long ulBase, unsigned long ulEndpoint) {
  unsigned long ulRegister;
  ;

  ;
  if (ulEndpoint == 0x00000000) {
    ulRegister = 0x00000102;
  } else {
    ulRegister = 0x00000116 + (ulEndpoint - 0x10);
  }
  if (((*((volatile unsigned short *)(ulBase + ulRegister))) & 0x00000001) == 0) {
    return (0);
  }
  return ((*((volatile unsigned short *)(ulBase + 0x00000108 + ulEndpoint))));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<USBEndpointDataAvail>:
  endbr64
  lea    0x106(%rsi),%rax
  test   %rsi,%rsi
  mov    $0x102,%edx
  cmove  %rdx,%rax
  add    %rdi,%rax
  movzwl (%rax),%edx
  mov    $0x0,%eax
  test   $0x1,%dl
  je     L5
  lea    0x108(%rdi,%rsi,1),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
L5:
  ret
```

assistant: ```c
unsigned long USBEndpointDataAvail(unsigned long ulBase, unsigned long ulEndpoint) {
  unsigned long ulRegister;
  ;

  ;
  if (ulEndpoint == 0x00000000) {
    ulRegister = 0x00000102;
  } else {
    ulRegister = 0x00000116 + (ulEndpoint - 0x10);
  }
  if (((*((volatile unsigned short *)(ulBase + ulRegister))) & 0x00000001) == 0) {
    return (0);
  }
  return ((*((volatile unsigned short *)(ulBase + 0x00000108 + ulEndpoint))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<USBEndpointDataAvail>:
  endbr64
  test   %rsi,%rsi
  mov    $0x102,%edx
  lea    0x106(%rsi),%rax
  cmove  %rdx,%rax
  add    %rdi,%rax
  movzwl (%rax),%edx
  xor    %eax,%eax
  and    $0x1,%edx
  je     L6
  lea    0x108(%rdi,%rsi,1),%rax
  movzwl (%rax),%eax
L6:
  ret
```

assistant: ```c
unsigned long USBEndpointDataAvail(unsigned long ulBase, unsigned long ulEndpoint) {
  unsigned long ulRegister;
  ;

  ;
  if (ulEndpoint == 0x00000000) {
    ulRegister = 0x00000102;
  } else {
    ulRegister = 0x00000116 + (ulEndpoint - 0x10);
  }
  if (((*((volatile unsigned short *)(ulBase + ulRegister))) & 0x00000001) == 0) {
    return (0);
  }
  return ((*((volatile unsigned short *)(ulBase + 0x00000108 + ulEndpoint))));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<USBEndpointDataAvail>:
  endbr64
  test   %rsi,%rsi
  mov    $0x102,%edx
  lea    0x106(%rsi),%rax
  cmove  %rdx,%rax
  add    %rdi,%rax
  movzwl (%rax),%edx
  xor    %eax,%eax
  and    $0x1,%edx
  je     L9
  lea    0x108(%rdi,%rsi,1),%rax
  movzwl (%rax),%eax
L9:
  ret
```

assistant: ```c
unsigned long USBEndpointDataAvail(unsigned long ulBase, unsigned long ulEndpoint) {
  unsigned long ulRegister;
  ;

  ;
  if (ulEndpoint == 0x00000000) {
    ulRegister = 0x00000102;
  } else {
    ulRegister = 0x00000116 + (ulEndpoint - 0x10);
  }
  if (((*((volatile unsigned short *)(ulBase + ulRegister))) & 0x00000001) == 0) {
    return (0);
  }
  return ((*((volatile unsigned short *)(ulBase + 0x00000108 + ulEndpoint))));
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char *buf1[], char *buf2[]) {
  char *t = *buf1;
  *buf1 = *buf2;
  *buf2 = t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char *buf1[], char *buf2[]) {
  char *t = *buf1;
  *buf1 = *buf2;
  *buf2 = t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char *buf1[], char *buf2[]) {
  char *t = *buf1;
  *buf1 = *buf2;
  *buf2 = t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char *buf1[], char *buf2[]) {
  char *t = *buf1;
  *buf1 = *buf2;
  *buf2 = t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bs_utf8_to_utf16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L26:
  cmpl   $0xc1,-0x4(%rbp)
  jle    L59
  cmpl   $0xdf,-0x4(%rbp)
  jg     L59
  mov    -0x4(%rbp),%eax
  shl    $0x6,%eax
  and    $0x7c0,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x3f,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L59:
  cmpl   $0xdf,-0x4(%rbp)
  jle    L6
  cmpl   $0xef,-0x4(%rbp)
  jg     L6
  mov    -0x4(%rbp),%eax
  shl    $0xc,%eax
  movzwl %ax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x6,%eax
  and    $0xfc0,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x3f,%eax
  add    %eax,-0x8(%rbp)
  jmp    L28
L6:
  movl   $0x20,-0x8(%rbp)
L28:
  cmpq   $0x0,-0x20(%rbp)
  je     L38
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L38:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int16_t bs_utf8_to_utf16(const char *s, char **outpos) {
  u_int8_t c;
  u_int16_t uc;
  c = *s++;
  if (c < 0x80) {
    uc = c;
  } else if (c >= 0xc2 && c <= 0xdf) {
    uc = (((u_int16_t)c & 0x1f) << 6) + (((u_int16_t)*s++) & 0x3f);
  } else if (c >= 0xe0 && c <= 0xef) {
    uc = (((u_int16_t)c & 0x0f) << 12) + ((((u_int16_t)*s++) & 0x3f) << 6);
    uc += ((u_int16_t)*s++) & 0x3f;
  } else
    uc = 32;
  if (outpos != NULL)
    *outpos = (char *)s;
  return uc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bs_utf8_to_utf16>:
  endbr64
  movsbl (%rdi),%eax
  test   %rsi,%rsi
  je     L3
  add    $0x1,%rdi
  mov    %rdi,(%rsi)
L3:
  ret
```

assistant: ```c
u_int16_t bs_utf8_to_utf16(const char *s, char **outpos) {
  u_int8_t c;
  u_int16_t uc;
  c = *s++;
  if (c < 0x80) {
    uc = c;
  } else if (c >= 0xc2 && c <= 0xdf) {
    uc = (((u_int16_t)c & 0x1f) << 6) + (((u_int16_t)*s++) & 0x3f);
  } else if (c >= 0xe0 && c <= 0xef) {
    uc = (((u_int16_t)c & 0x0f) << 12) + ((((u_int16_t)*s++) & 0x3f) << 6);
    uc += ((u_int16_t)*s++) & 0x3f;
  } else
    uc = 32;
  if (outpos != NULL)
    *outpos = (char *)s;
  return uc;
}
```
user: What is the c source code of the assembly code below:

```asm
<bs_utf8_to_utf16>:
  endbr64
  movsbl (%rdi),%eax
  test   %rsi,%rsi
  je     L1
  add    $0x1,%rdi
  mov    %rdi,(%rsi)
L1:
  ret
```

assistant: ```c
u_int16_t bs_utf8_to_utf16(const char *s, char **outpos) {
  u_int8_t c;
  u_int16_t uc;
  c = *s++;
  if (c < 0x80) {
    uc = c;
  } else if (c >= 0xc2 && c <= 0xdf) {
    uc = (((u_int16_t)c & 0x1f) << 6) + (((u_int16_t)*s++) & 0x3f);
  } else if (c >= 0xe0 && c <= 0xef) {
    uc = (((u_int16_t)c & 0x0f) << 12) + ((((u_int16_t)*s++) & 0x3f) << 6);
    uc += ((u_int16_t)*s++) & 0x3f;
  } else
    uc = 32;
  if (outpos != NULL)
    *outpos = (char *)s;
  return uc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bs_utf8_to_utf16>:
  endbr64
  movsbl (%rdi),%eax
  test   %rsi,%rsi
  je     L6
  add    $0x1,%rdi
  mov    %rdi,(%rsi)
L6:
  ret
```

assistant: ```c
u_int16_t bs_utf8_to_utf16(const char *s, char **outpos) {
  u_int8_t c;
  u_int16_t uc;
  c = *s++;
  if (c < 0x80) {
    uc = c;
  } else if (c >= 0xc2 && c <= 0xdf) {
    uc = (((u_int16_t)c & 0x1f) << 6) + (((u_int16_t)*s++) & 0x3f);
  } else if (c >= 0xe0 && c <= 0xef) {
    uc = (((u_int16_t)c & 0x0f) << 12) + ((((u_int16_t)*s++) & 0x3f) << 6);
    uc += ((u_int16_t)*s++) & 0x3f;
  } else
    uc = 32;
  if (outpos != NULL)
    *outpos = (char *)s;
  return uc;
}
```