ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<setupBoard>:
  endbr64
  mov    $0x80000a4f,%eax
  mov    $0x80000a43,%edx
  movb   $0xc,(%rax)
  movb   $0xc,-0x1(%rax)
  movl   $0xf0000000,-0x543(%rax)
  movzbl (%rdx),%eax
  and    $0x3f,%eax
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void setupBoard() {
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A4F)) = (0 | (0x04) | (0x08));
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A4E)) = (0 | (0x04) | (0x08));
  (*(volatile unsigned int *)(void *)(0x80000000 + 0x00050C)) = 0xF0000000;
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A43)) &= 0x3F;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setupBoard>:
  endbr64
  mov    $0x80000a4f,%eax
  mov    $0x80000a43,%edx
  movb   $0xc,(%rax)
  movb   $0xc,-0x1(%rax)
  movl   $0xf0000000,-0x543(%rax)
  movzbl (%rdx),%eax
  and    $0x3f,%eax
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void setupBoard() {
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A4F)) = (0 | (0x04) | (0x08));
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A4E)) = (0 | (0x04) | (0x08));
  (*(volatile unsigned int *)(void *)(0x80000000 + 0x00050C)) = 0xF0000000;
  (*(volatile unsigned char *)(void *)(0x80000000 + 0x000A43)) &= 0x3F;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<des_getParityBitFromKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x6,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x5,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x4,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x3,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  xor    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    %eax
  xor    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool des_getParityBitFromKey(uint8_t key) {
  bool parity = ((key & 0x80) >> 7) ^ ((key & 0x40) >> 6) ^ ((key & 0x20) >> 5) ^ ((key & 0x10) >> 4) ^ ((key & 0x08) >> 3) ^ ((key & 0x04) >> 2) ^ ((key & 0x02) >> 1);
  return !parity;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<des_getParityBitFromKey>:
  endbr64
  mov    %edi,%eax
  sar    $0x7,%edi
  mov    %eax,%edx
  sar    $0x6,%edx
  xor    %edx,%edi
  mov    %eax,%edx
  sar    $0x5,%edx
  xor    %edx,%edi
  mov    %eax,%edx
  sar    $0x4,%edx
  xor    %edx,%edi
  mov    %eax,%edx
  sar    $0x3,%edx
  xor    %edx,%edi
  mov    %eax,%edx
  sar    $0x2,%edx
  xor    %edx,%edi
  sar    %eax
  xor    %eax,%edi
  test   $0x1,%dil
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool des_getParityBitFromKey(uint8_t key) {
  bool parity = ((key & 0x80) >> 7) ^ ((key & 0x40) >> 6) ^ ((key & 0x20) >> 5) ^ ((key & 0x10) >> 4) ^ ((key & 0x08) >> 3) ^ ((key & 0x04) >> 2) ^ ((key & 0x02) >> 1);
  return !parity;
}
```
user: What is the c source code of the assembly code below:

```asm
<des_getParityBitFromKey>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x6,%edx
  sar    $0x7,%eax
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x5,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x4,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x3,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    %edi
  sar    $0x2,%edx
  xor    %edx,%eax
  xor    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool des_getParityBitFromKey(uint8_t key) {
  bool parity = ((key & 0x80) >> 7) ^ ((key & 0x40) >> 6) ^ ((key & 0x20) >> 5) ^ ((key & 0x10) >> 4) ^ ((key & 0x08) >> 3) ^ ((key & 0x04) >> 2) ^ ((key & 0x02) >> 1);
  return !parity;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<des_getParityBitFromKey>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    $0x6,%edx
  sar    $0x7,%eax
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x5,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x4,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    $0x3,%edx
  xor    %edx,%eax
  mov    %edi,%edx
  sar    %edi
  sar    $0x2,%edx
  xor    %edx,%eax
  xor    %edi,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool des_getParityBitFromKey(uint8_t key) {
  bool parity = ((key & 0x80) >> 7) ^ ((key & 0x40) >> 6) ^ ((key & 0x20) >> 5) ^ ((key & 0x10) >> 4) ^ ((key & 0x08) >> 3) ^ ((key & 0x04) >> 2) ^ ((key & 0x02) >> 1);
  return !parity;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L58
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L14
L53:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L47
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  jmp    L4
L47:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L4
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
L4:
  addl   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L53
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quick>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quick>
  jmp    L56
L58:
  nop
L56:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: %d 

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 50), *z = malloc(sizeof(int) * 50);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  printf("%d ", pvt);
  quick(z, size_z);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quick>:
  endbr64
  test   %esi,%esi
  jne    L39
  ret
L39:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    (%rdi),%ebp
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    $0x1,%ebx
  jle    L0
  lea    0x4(%r14),%rax
  lea    -0x2(%rbx),%edx
  lea    0x8(%r14,%rdx,4),%rcx
  mov    $0x0,%ebx
  mov    $0x0,%esi
  jmp    L8
L55:
  movslq %esi,%rdi
  mov    %edx,0x0(%r13,%rdi,4)
  add    $0x1,%esi
L38:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L22
L8:
  mov    (%rax),%edx
  cmp    %ebp,%edx
  jle    L55
  movslq %ebx,%rdi
  mov    %edx,(%r12,%rdi,4)
  add    $0x1,%ebx
  jmp    L38
L0:
  mov    $0x0,%ebx
  mov    $0x0,%esi
L22:
  mov    %r13,%rdi
  call   <quick>
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <quick>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: %d 

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 50), *z = malloc(sizeof(int) * 50);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  printf("%d ", pvt);
  quick(z, size_z);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick>:
  endbr64
  test   %esi,%esi
  je     L44
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
L42:
  mov    $0xc8,%edi
  mov    0x0(%r13),%ebp
  mov    %r13,%r15
  call   <malloc@plt>
  mov    $0xc8,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%ebx
  jle    L16
  lea    -0x2(%rbx),%edx
  lea    0x4(%r15),%rax
  xor    %ebx,%ebx
  xor    %esi,%esi
  lea    0x8(%r15,%rdx,4),%rcx
  jmp    L28
  xchg   %ax,%ax
L12:
  movslq %ebx,%rdi
  add    $0x4,%rax
  add    $0x1,%ebx
  mov    %edx,0x0(%r13,%rdi,4)
  cmp    %rcx,%rax
  je     L29
L28:
  mov    (%rax),%edx
  cmp    %ebp,%edx
  jg     L12
  movslq %esi,%rdi
  add    $0x4,%rax
  add    $0x1,%esi
  mov    %edx,(%r14,%rdi,4)
  cmp    %rcx,%rax
  jne    L28
L29:
  mov    %r14,%rdi
  call   <quick>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L42
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L16:
  mov    %r14,%rdi
  xor    %esi,%esi
  call   <quick>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
L44:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: %d 

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 50), *z = malloc(sizeof(int) * 50);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  printf("%d ", pvt);
  quick(z, size_z);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set(int *a, int *b, int a_val, int b_val) {
  *a = a_val;
  *b = b_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set>:
  endbr64
  mov    %edx,(%rdi)
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void set(int *a, int *b, int a_val, int b_val) {
  *a = a_val;
  *b = b_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set>:
  endbr64
  mov    %edx,(%rdi)
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void set(int *a, int *b, int a_val, int b_val) {
  *a = a_val;
  *b = b_val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set>:
  endbr64
  mov    %edx,(%rdi)
  mov    %ecx,(%rsi)
  ret
```

assistant: ```c
void set(int *a, int *b, int a_val, int b_val) {
  *a = a_val;
  *b = b_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<renameat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <__renameat@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int renameat(int oldfd, const char *old, int newfd, const char *new) {
  int res = __renameat(oldfd, old, newfd, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<renameat>:
  endbr64
  push   %rbx
  call   <__renameat@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L10
L18:
  mov    %ebx,%eax
  pop    %rbx
  ret
L10:
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
  jmp    L18
```

assistant: ```c
int renameat(int oldfd, const char *old, int newfd, const char *new) {
  int res = __renameat(oldfd, old, newfd, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<renameat>:
  endbr64
  push   %r12
  call   <__renameat@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int renameat(int oldfd, const char *old, int newfd, const char *new) {
  int res = __renameat(oldfd, old, newfd, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<renameat>:
  endbr64
  push   %r12
  call   <__renameat@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L2
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int renameat(int oldfd, const char *old, int newfd, const char *new) {
  int res = __renameat(oldfd, old, newfd, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<madd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L0
  mov    %ecx,%ecx
  mov    $0x0,%eax
L13:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
L0:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L16
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L10
L16:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<madd>:
  endbr64
  imul   %r8d,%ecx
  test   %ecx,%ecx
  jle    L19
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdx
  lea    0x8(%rdi),%rax
  setne  %r8b
  cmp    %rax,%rdx
  setne  %al
  test   %al,%r8b
  je     L55
  lea    -0x1(%rcx),%eax
  cmp    $0x1,%eax
  jbe    L55
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    %r8d
  shl    $0x4,%r8
  xchg   %ax,%ax
L9:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %r8,%rax
  jne    L9
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L19
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nopl   (%rax)
L55:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L18
L19:
  ret
```

assistant: ```c
void madd(double *A, double *B, double *C, int rows, int cols) {
  int N, i;
  N = rows * cols;
  for (i = 0; i < N; ++i) {
    C[i] = A[i] + B[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MMX_PACKSSDW>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x6b,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  or     $0xc0,%al
  or     -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x70,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  or     $0xc0,%al
  or     -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <addbyte@plt>
  mov    $0x8,%edi
  call   <addbyte@plt>
  nop
  leave
  ret
```

assistant: ```c
void MMX_PACKSSDW(int dst_reg, int src_reg) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x6b);
  addbyte(0xc0 | (dst_reg << 3) | src_reg);
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x70);
  addbyte(0xc0 | (dst_reg << 3) | dst_reg);
  addbyte(0x08);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MMX_PACKSSDW>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x6b,%edi
  call   <addbyte@plt>
  lea    0x0(,%r12,8),%ebx
  or     $0xc0,%bl
  mov    %ebp,%edi
  or     %ebx,%edi
  call   <addbyte@plt>
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x70,%edi
  call   <addbyte@plt>
  or     %r12d,%ebx
  mov    %ebx,%edi
  call   <addbyte@plt>
  mov    $0x8,%edi
  call   <addbyte@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MMX_PACKSSDW(int dst_reg, int src_reg) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x6b);
  addbyte(0xc0 | (dst_reg << 3) | src_reg);
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x70);
  addbyte(0xc0 | (dst_reg << 3) | dst_reg);
  addbyte(0x08);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MMX_PACKSSDW>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    0x0(,%r12,8),%ebx
  or     $0xc0,%bl
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x6b,%edi
  call   <addbyte@plt>
  mov    %ebp,%edi
  or     %ebx,%edi
  or     %r12d,%ebx
  call   <addbyte@plt>
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    $0xf,%edi
  call   <addbyte@plt>
  mov    $0x70,%edi
  call   <addbyte@plt>
  mov    %ebx,%edi
  call   <addbyte@plt>
  pop    %rbx
  mov    $0x8,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <addbyte@plt>
```

assistant: ```c
void MMX_PACKSSDW(int dst_reg, int src_reg) {
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x6b);
  addbyte(0xc0 | (dst_reg << 3) | src_reg);
  addbyte(0x66);
  addbyte(0x0f);
  addbyte(0x70);
  addbyte(0xc0 | (dst_reg << 3) | dst_reg);
  addbyte(0x08);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L1:
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x4,-0x4(%rbp)
  jle    L3
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L35:
  cmpl   $0x4,-0x8(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D1
data_type: string

tool: D18: *

tool: D1: 


assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x5,%ebp
  lea    D9(%rip),%rbx
  lea    D2(%rip),%r12
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string

tool: D9: *

tool: D2: 


assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    $0x5,%ebp
  push   %rbx
  lea    D14(%rip),%rbx
L7:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D12: 


tool: D14: *

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    $0x5,%r12d
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
L12:
  mov    $0x5,%ebx
L14:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D11: 


tool: D17: *

assistant: ```c
int main() {
  int i, j;
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```