ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<run_dispatcher>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L41:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L41
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <get_servers_amount@plt>
  mov    %rbp,%rdi
  mov    %eax,%r15d
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  call   <get_servers_hosts@plt>
  mov    %r15d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <get_servers_ports@plt>
  mov    %rax,%r14
  test   %r15d,%r15d
  je     L44
  lea    -0x1(%r15),%eax
  mov    %r13,%rbp
  lea    0x8(%r13,%rax,8),%r15
  jmp    L42
  nopl   (%rax)
L25:
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L44
L42:
  mov    0x0(%rbp),%rdi
  call   <is_ip@plt>
  test   %rax,%rax
  jne    L25
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <get_ip_from_hostname@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r15,%rbp
  jne    L42
L44:
  lea    0x1c(%rsp),%r15
  lea    0x20(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %r12d,%r12d
L38:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <listen_udp_packet@plt>
  mov    (%r14,%r12,4),%esi
  mov    0x1c(%rsp),%ecx
  mov    %ebx,%r8d
  mov    0x0(%r13,%r12,8),%rdi
  mov    %rbp,%rdx
  add    $0x1,%r12
  call   <send_udp_packet@plt>
  cmp    %r12d,0xc(%rsp)
  jbe    L54
  jmp    L38
```

assistant: ```c
void run_dispatcher(char **servers_list, int socket_) {
  char message[65507];
  unsigned int message_length;
  unsigned int servers_amount = get_servers_amount(servers_list);
  char **servers_hosts = get_servers_hosts(servers_list, servers_amount);
  int *servers_ports = get_servers_ports(servers_list, servers_amount);
  unsigned int i;
  for (i = 0; i < servers_amount; i++) {
    if (is_ip(servers_hosts[i]) == 0) {
      servers_hosts[i] = get_ip_from_hostname(servers_hosts[i]);
    }
  }
  while (1) {
    for (i = 0; i < servers_amount; i++) {
      listen_udp_packet(message, &message_length, socket_);
      send_udp_packet(servers_hosts[i], servers_ports[i], message, message_length, socket_);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<run_dispatcher>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x10000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <get_servers_amount@plt>
  mov    %rbp,%rdi
  mov    %eax,%r15d
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  call   <get_servers_hosts@plt>
  mov    %r15d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <get_servers_ports@plt>
  mov    %rax,%r14
  test   %r15d,%r15d
  je     L59
  lea    -0x1(%r15),%eax
  mov    %r13,%rbp
  lea    0x8(%r13,%rax,8),%r15
  jmp    L14
  nopl   (%rax)
L38:
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L59
L14:
  mov    0x0(%rbp),%rdi
  call   <is_ip@plt>
  test   %rax,%rax
  jne    L38
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <get_ip_from_hostname@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r15,%rbp
  jne    L14
L59:
  lea    0x1c(%rsp),%r15
  lea    0x20(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
L8:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <listen_udp_packet@plt>
  mov    (%r14,%r12,4),%esi
  mov    0x1c(%rsp),%ecx
  mov    %ebx,%r8d
  mov    0x0(%r13,%r12,8),%rdi
  mov    %rbp,%rdx
  add    $0x1,%r12
  call   <send_udp_packet@plt>
  cmp    %r12d,0xc(%rsp)
  jbe    L0
  jmp    L8
```

assistant: ```c
void run_dispatcher(char **servers_list, int socket_) {
  char message[65507];
  unsigned int message_length;
  unsigned int servers_amount = get_servers_amount(servers_list);
  char **servers_hosts = get_servers_hosts(servers_list, servers_amount);
  int *servers_ports = get_servers_ports(servers_list, servers_amount);
  unsigned int i;
  for (i = 0; i < servers_amount; i++) {
    if (is_ip(servers_hosts[i]) == 0) {
      servers_hosts[i] = get_ip_from_hostname(servers_hosts[i]);
    }
  }
  while (1) {
    for (i = 0; i < servers_amount; i++) {
      listen_udp_packet(message, &message_length, socket_);
      send_udp_packet(servers_hosts[i], servers_ports[i], message, message_length, socket_);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  sleep(10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  sleep(10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  sleep(10);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  sleep(10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<udpsend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x43,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <iptoaddr@plt>
  mov    -0x10(%rbp),%edi
  lea    -0x14(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x2c(%rbp),%eax
  mov    %edi,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L13
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <eprintf@plt>
L13:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: sendto:

assistant: ```c
ssize_t udpsend(unsigned char ip[4], int fd, void *data, size_t n) {
  struct sockaddr addr;
  socklen_t addrlen = sizeof addr;
  ssize_t sent;
  iptoaddr(&addr, ip, 67);
  if ((sent = sendto(fd, data, n, 0, &addr, addrlen)) == -1)
    eprintf("sendto:");
  return sent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<udpsend>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    $0x43,%edx
  mov    %rdi,%rsi
  mov    %r13,%rdi
  call   <iptoaddr@plt>
  mov    $0x4,%r9d
  mov    %r13,%r8
  mov    $0x0,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <sendto@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L25
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  lea    D9(%rip),%rdi
  call   <eprintf@plt>
  jmp    L5
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: sendto:

assistant: ```c
ssize_t udpsend(unsigned char ip[4], int fd, void *data, size_t n) {
  struct sockaddr addr;
  socklen_t addrlen = sizeof addr;
  ssize_t sent;
  iptoaddr(&addr, ip, 67);
  if ((sent = sendto(fd, data, n, 0, &addr, addrlen)) == -1)
    eprintf("sendto:");
  return sent;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<udpsend>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x43,%edx
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <iptoaddr@plt>
  mov    %r12d,%edi
  mov    $0x4,%r9d
  xor    %ecx,%ecx
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <sendto@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L6
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D7(%rip),%rdi
  call   <eprintf@plt>
  jmp    L8
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: sendto:

assistant: ```c
ssize_t udpsend(unsigned char ip[4], int fd, void *data, size_t n) {
  struct sockaddr addr;
  socklen_t addrlen = sizeof addr;
  ssize_t sent;
  iptoaddr(&addr, ip, 67);
  if ((sent = sendto(fd, data, n, 0, &addr, addrlen)) == -1)
    eprintf("sendto:");
  return sent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<udpsend>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %esi,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x43,%edx
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <iptoaddr@plt>
  mov    %r12d,%edi
  mov    $0x4,%r9d
  xor    %ecx,%ecx
  mov    %rbx,%r8
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <sendto@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L28
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D3(%rip),%rdi
  call   <eprintf@plt>
  jmp    L19
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: sendto:

assistant: ```c
ssize_t udpsend(unsigned char ip[4], int fd, void *data, size_t n) {
  struct sockaddr addr;
  socklen_t addrlen = sizeof addr;
  ssize_t sent;
  iptoaddr(&addr, ip, 67);
  if ((sent = sendto(fd, data, n, 0, &addr, addrlen)) == -1)
    eprintf("sendto:");
  return sent;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_current_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned int get_current_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int get_current_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int get_current_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_current_time>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int get_current_time() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<enqueue_entity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <update_curr@plt>
  cmpl   $0x0,-0x14(%rbp)
  je     L2
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <enqueue_sleeper@plt>
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <update_stats_enqueue@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__enqueue_entity@plt>
  nop
  leave
  ret
```

assistant: ```c
void enqueue_entity(struct cfs_rq *cfs_rq, struct sched_entity *se, int wakeup) {
  update_curr(cfs_rq);
  if (wakeup)
    enqueue_sleeper(cfs_rq, se);
  update_stats_enqueue(cfs_rq, se);
  __enqueue_entity(cfs_rq, se);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<enqueue_entity>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <update_curr@plt>
  test   %r12d,%r12d
  jne    L8
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <update_stats_enqueue@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__enqueue_entity@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <enqueue_sleeper@plt>
  jmp    L15
```

assistant: ```c
void enqueue_entity(struct cfs_rq *cfs_rq, struct sched_entity *se, int wakeup) {
  update_curr(cfs_rq);
  if (wakeup)
    enqueue_sleeper(cfs_rq, se);
  update_stats_enqueue(cfs_rq, se);
  __enqueue_entity(cfs_rq, se);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<enqueue_entity>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <update_curr@plt>
  test   %ebx,%ebx
  jne    L5
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <update_stats_enqueue@plt>
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <__enqueue_entity@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <enqueue_sleeper@plt>
  jmp    L10
```

assistant: ```c
void enqueue_entity(struct cfs_rq *cfs_rq, struct sched_entity *se, int wakeup) {
  update_curr(cfs_rq);
  if (wakeup)
    enqueue_sleeper(cfs_rq, se);
  update_stats_enqueue(cfs_rq, se);
  __enqueue_entity(cfs_rq, se);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<enqueue_entity>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <update_curr@plt>
  test   %ebx,%ebx
  jne    L10
L7:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <update_stats_enqueue@plt>
  pop    %rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <__enqueue_entity@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <enqueue_sleeper@plt>
  jmp    L7
```

assistant: ```c
void enqueue_entity(struct cfs_rq *cfs_rq, struct sched_entity *se, int wakeup) {
  update_curr(cfs_rq);
  if (wakeup)
    enqueue_sleeper(cfs_rq, se);
  update_stats_enqueue(cfs_rq, se);
  __enqueue_entity(cfs_rq, se);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<T_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  cmpl   $0x0,-0xc(%rbp)
  je     L25
  mov    -0xc(%rbp),%eax
  jmp    L37
L25:
  mov    $0x1,%eax
L37:
  mov    %eax,%edi
  call   <malloc@plt>
  jmp    L15
L10:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
L15:
  leave
  ret
```

assistant: ```c
void *T_realloc(void *block, unsigned int len) {
  if (block == NULL)
    return (void *)malloc(len ? len : 1);
  return (void *)realloc(block, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<T_realloc>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  call   <realloc@plt>
L13:
  add    $0x8,%rsp
  ret
L17:
  test   %esi,%esi
  mov    $0x1,%eax
  cmovne %esi,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  jmp    L13
```

assistant: ```c
void *T_realloc(void *block, unsigned int len) {
  if (block == NULL)
    return (void *)malloc(len ? len : 1);
  return (void *)realloc(block, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<T_realloc>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1070 <realloc@plt>
  xchg   %ax,%ax
L0:
  test   %esi,%esi
  mov    $0x1,%eax
  cmovne %esi,%eax
  mov    %eax,%edi
  jmp    1060 <malloc@plt>
```

assistant: ```c
void *T_realloc(void *block, unsigned int len) {
  if (block == NULL)
    return (void *)malloc(len ? len : 1);
  return (void *)realloc(block, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<T_realloc>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1070 <realloc@plt>
  xchg   %ax,%ax
L0:
  test   %esi,%esi
  mov    $0x1,%eax
  cmovne %esi,%eax
  mov    %eax,%edi
  jmp    1060 <malloc@plt>
```

assistant: ```c
void *T_realloc(void *block, unsigned int len) {
  if (block == NULL)
    return (void *)malloc(len ? len : 1);
  return (void *)realloc(block, len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<floatarrmwith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L10
L0:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movss  (%rax),%xmm0
  mulss  -0x24(%rbp),%xmm0
  movss  %xmm0,(%rax)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floatarrmwith(float *in, size_t size, float a) {
  float *pt, *fpt;
  fpt = in + size;
  pt = in;
  while (pt < fpt)
    *pt++ *= a;
}
```
user: What is the c source code of the assembly code below:

```asm
<floatarrmwith>:
  endbr64
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L13
L14:
  add    $0x4,%rdi
  movaps %xmm0,%xmm1
  mulss  -0x4(%rdi),%xmm1
  movss  %xmm1,-0x4(%rdi)
  cmp    %rdi,%rax
  ja     L14
L13:
  ret
```

assistant: ```c
void floatarrmwith(float *in, size_t size, float a) {
  float *pt, *fpt;
  fpt = in + size;
  pt = in;
  while (pt < fpt)
    *pt++ *= a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<floatarrmwith>:
  endbr64
  lea    (%rdi,%rsi,4),%rax
  cmp    %rax,%rdi
  jae    L14
  nopl   (%rax)
L10:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  mulss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%rdi)
  cmp    %rdi,%rax
  ja     L10
L14:
  ret
```

assistant: ```c
void floatarrmwith(float *in, size_t size, float a) {
  float *pt, *fpt;
  fpt = in + size;
  pt = in;
  while (pt < fpt)
    *pt++ *= a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floatarrmwith>:
  endbr64
  shl    $0x2,%rsi
  mov    %rdi,%rdx
  lea    (%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L30
  sub    $0x1,%rsi
  mov    %rdi,%rax
  mov    %rsi,%r8
  shr    $0x2,%r8
  lea    0x1(%r8),%rdi
  cmp    $0xb,%rsi
  jbe    L27
  mov    %rdi,%rcx
  movaps %xmm0,%xmm2
  shr    $0x2,%rcx
  shufps $0x0,%xmm2,%xmm2
  shl    $0x4,%rcx
  add    %rdx,%rcx
  nopl   (%rax)
L8:
  movups (%rax),%xmm1
  add    $0x10,%rax
  mulps  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L8
  mov    %rdi,%rcx
  and    $0xfffffffffffffffc,%rcx
  lea    (%rdx,%rcx,4),%rax
  cmp    %rcx,%rdi
  je     L38
L28:
  sub    %rcx,%rdi
  cmp    %rcx,%r8
  je     L23
  lea    (%rdx,%rcx,4),%rdx
  movaps %xmm0,%xmm2
  movq   (%rdx),%xmm1
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm1
  movlps %xmm1,(%rdx)
  mov    %rdi,%rdx
  and    $0xfffffffffffffffe,%rdx
  lea    (%rax,%rdx,4),%rax
  cmp    %rdx,%rdi
  je     L30
L23:
  mulss  (%rax),%xmm0
  movss  %xmm0,(%rax)
L30:
  ret
  nopl   0x0(%rax)
L38:
  ret
L27:
  xor    %ecx,%ecx
  jmp    L28
```

assistant: ```c
void floatarrmwith(float *in, size_t size, float a) {
  float *pt, *fpt;
  fpt = in + size;
  pt = in;
  while (pt < fpt)
    *pt++ *= a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L22
L39:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L12:
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L42
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L42:
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L12
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L22:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D6: %d

tool: D23: %d %d

tool: D25: Case %d: %d


assistant: ```c
int main() {
  int n, i, a, b, sum = 0, j;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d %d", &a, &b);
    sum = 0;
    for (j = a; j <= b; j++) {
      if (j % 2 == 1) {
        sum = sum + j;
      }
    }
    printf("Case %d: %d\n", i, sum);
  }
  return 0;
}
```