ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<KIONIX_ACCEL_disable_outputs>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x1b,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <KIONIX_ACCEL_read_bytes@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl 0x7(%rsp),%esi
  mov    $0x1b,%edi
  and    $0x7f,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  call   <KIONIX_ACCEL_write_byte@plt>
  xor    %eax,%eax
  jmp    L16
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int KIONIX_ACCEL_disable_outputs(void) {
  char ctlreg_1 = 0;
  int status = 0;
  if (KIONIX_ACCEL_read_bytes(0x1B, &ctlreg_1, 1) == 0) {
    ctlreg_1 &= ~0x80;
    KIONIX_ACCEL_write_byte(0x1B, ctlreg_1);
  } else
    status = 1;
  return status;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calcScore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L27:
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L10:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0x3,-0x8(%rbp)
  jle    L10
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x3,-0xc(%rbp)
  jle    L27
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int calcScore(int tab[4][4]) {
  int x, y, temp = 0;
  for (x = 0; x < 4; x++)
    for (y = 0; y < 4; y++)
      temp += tab[x][y];
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcScore>:
  endbr64
  lea    0x40(%rdi),%rdx
  mov    $0x0,%eax
L6:
  add    (%rdi),%eax
  add    0x4(%rdi),%eax
  add    0x8(%rdi),%eax
  add    0xc(%rdi),%eax
  add    $0x10,%rdi
  cmp    %rdx,%rdi
  jne    L6
  ret
```

assistant: ```c
int calcScore(int tab[4][4]) {
  int x, y, temp = 0;
  for (x = 0; x < 4; x++)
    for (y = 0; y < 4; y++)
      temp += tab[x][y];
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calcScore>:
  endbr64
  lea    0x40(%rdi),%rdx
  xor    %eax,%eax
L9:
  add    (%rdi),%eax
  add    $0x10,%rdi
  add    -0xc(%rdi),%eax
  add    -0x8(%rdi),%eax
  add    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L9
  ret
```

assistant: ```c
int calcScore(int tab[4][4]) {
  int x, y, temp = 0;
  for (x = 0; x < 4; x++)
    for (y = 0; y < 4; y++)
      temp += tab[x][y];
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calcScore>:
  endbr64
  movdqu (%rdi),%xmm0
  movdqu 0x10(%rdi),%xmm2
  movdqu 0x20(%rdi),%xmm1
  paddd  %xmm2,%xmm0
  paddd  %xmm0,%xmm1
  movdqu 0x30(%rdi),%xmm0
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  ret
```

assistant: ```c
int calcScore(int tab[4][4]) {
  int x, y, temp = 0;
  for (x = 0; x < 4; x++)
    for (y = 0; y < 4; y++)
      temp += tab[x][y];
  return temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decrypt_cbc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %rcx,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xffffffff,%eax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  movq   $0x0,-0x58(%rbp)
  jmp    L15
L33:
  movl   $0x8,-0x60(%rbp)
  mov    -0x70(%rbp),%rax
  sub    -0x58(%rbp),%rax
  cmp    $0x7,%rax
  ja     L11
  mov    -0x70(%rbp),%rax
  mov    %eax,%edx
  mov    -0x58(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x60(%rbp)
L11:
  movl   $0x0,-0x5c(%rbp)
  jmp    L20
L6:
  mov    -0x58(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x5c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x5c(%rbp),%eax
  cltq
  mov    %rdx,-0x20(%rbp,%rax,8)
  addl   $0x1,-0x5c(%rbp)
L20:
  mov    -0x60(%rbp),%eax
  sar    $0x2,%eax
  cmp    %eax,-0x5c(%rbp)
  jl     L6
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x78(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decrypt@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  xor    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  xor    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L47
L25:
  mov    -0x5c(%rbp),%eax
  cltq
  lea    -0x30(%rbp),%rdx
  add    %rdx,%rax
  mov    -0x5c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x58(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x80(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x5c(%rbp)
L47:
  mov    -0x5c(%rbp),%eax
  cmp    -0x60(%rbp),%eax
  jl     L25
  addq   $0x8,-0x58(%rbp)
L15:
  mov    -0x58(%rbp),%rax
  cmp    -0x70(%rbp),%rax
  jb     L33
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

assistant: ```c
void decrypt_cbc(unsigned long *in, unsigned long len, unsigned long *key, unsigned long *out) {
  unsigned long x[2], nx[2], dec[2], tea[2], offset;
  x[0] = x[1] = 0xffffffff;
  for (offset = 0; offset < len; offset += 8) {
    int blen = 8;
    if ((len - offset) < 8)
      blen = len - offset;
    int i;
    for (i = 0; i < (blen >> 2); i++)
      tea[i] = in[(offset >> 2) + i];
    nx[0] = tea[0];
    nx[1] = tea[1];
    decrypt(tea, key);
    dec[0] = tea[0] ^ x[0];
    dec[1] = tea[1] ^ x[1];
    x[0] = nx[0];
    x[1] = nx[1];
    for (i = 0; i < blen; i++)
      ((unsigned char *)out)[offset + i] = ((unsigned char *)dec)[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decrypt_cbc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L13
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %rcx,%rbx
  mov    %rsi,%r12
  mov    $0xffffffff,%eax
  mov    %rax,0x8(%rsp)
  mov    %rax,(%rsp)
  jmp    L45
L49:
  mov    %r14,0x8(%rsp)
  mov    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L15
L94:
  shr    $0x2,%rax
  mov    (%r15,%rax,8),%r14
  mov    %r14,0x30(%rsp)
  mov    0x8(%r15,%rax,8),%rax
  mov    %rax,0x38(%rsp)
  mov    $0x8,%ebp
L97:
  mov    0x38(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x30(%rsp),%rdi
  mov    0x18(%rsp),%rsi
  call   <decrypt@plt>
  mov    (%rsp),%rax
  xor    0x30(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    0x8(%rsp),%rax
  xor    0x38(%rsp),%rax
  mov    %rax,0x28(%rsp)
  mov    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %r14,(%rsp)
L73:
  mov    $0x0,%eax
L66:
  movzbl 0x20(%rsp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L66
L15:
  sub    $0x8,%r12
  add    $0x8,%rbx
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rax,%r13
  jbe    L13
L45:
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    $0x7,%r12
  ja     L94
  mov    %r12d,%ebp
  cmp    $0x3,%r12d
  jg     L68
  mov    0x30(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    0x38(%rsp),%r14
  lea    0x30(%rsp),%rdi
  mov    0x18(%rsp),%rsi
  call   <decrypt@plt>
  mov    (%rsp),%rax
  xor    0x30(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    0x8(%rsp),%rax
  xor    0x38(%rsp),%rax
  mov    %rax,0x28(%rsp)
  test   %r12d,%r12d
  jle    L49
  mov    %r14,0x8(%rsp)
  mov    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  jmp    L73
L68:
  shr    $0x2,%rax
  mov    (%r15,%rax,8),%r14
  mov    %r14,0x30(%rsp)
  jmp    L97
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void decrypt_cbc(unsigned long *in, unsigned long len, unsigned long *key, unsigned long *out) {
  unsigned long x[2], nx[2], dec[2], tea[2], offset;
  x[0] = x[1] = 0xffffffff;
  for (offset = 0; offset < len; offset += 8) {
    int blen = 8;
    if ((len - offset) < 8)
      blen = len - offset;
    int i;
    for (i = 0; i < (blen >> 2); i++)
      tea[i] = in[(offset >> 2) + i];
    nx[0] = tea[0];
    nx[1] = tea[1];
    decrypt(tea, key);
    dec[0] = tea[0] ^ x[0];
    dec[1] = tea[1] ^ x[1];
    x[0] = nx[0];
    x[1] = nx[1];
    for (i = 0; i < blen; i++)
      ((unsigned char *)out)[offset + i] = ((unsigned char *)dec)[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decrypt_cbc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L80
  mov    $0xffffffff,%ebp
  lea    (%rcx,%rsi,1),%rax
  mov    %rsi,%rbx
  mov    %rsi,%r13
  mov    %rax,0x8(%rsp)
  mov    %rbp,%r12
  lea    0x40(%rsp),%r15
  jmp    L76
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    %r13d,%esi
  mov    %r13d,%r14d
  sar    $0x2,%esi
  cmp    $0x1,%esi
  je     L43
  mov    0x40(%rsp),%rax
  mov    0x48(%rsp),%rcx
  mov    %r15,%rdi
  mov    0x10(%rsp),%rsi
  mov    %rax,0x18(%rsp)
  mov    %rcx,0x20(%rsp)
  call   <decrypt@plt>
  xor    0x40(%rsp),%r12
  xor    0x48(%rsp),%rbp
  mov    %r12,0x30(%rsp)
  mov    0x18(%rsp),%r12
  mov    %rbp,0x38(%rsp)
  mov    0x20(%rsp),%rbp
  test   %r13,%r13
  je     L37
L73:
  mov    0x8(%rsp),%rdi
  lea    -0x1(%r14),%edx
  mov    $0x1,%eax
  lea    0x30(%rsp),%rsi
  add    $0x1,%rdx
  sub    %r13,%rdi
  test   %r14d,%r14d
  cmovle %rax,%rdx
  call   <memcpy@plt>
L37:
  sub    $0x8,%r13
  mov    %rbx,%rax
  sub    %r13,%rax
  cmp    %rax,%rbx
  jbe    L80
L76:
  mov    %rbx,%rax
  sub    %r13,%rax
  cmp    $0x7,%r13
  jbe    L49
  mov    $0x2,%esi
  mov    $0x8,%r14d
L43:
  movslq %esi,%rdx
  mov    0x28(%rsp),%rcx
  shl    $0x3,%rdx
  test   %esi,%esi
  mov    $0x8,%esi
  cmovle %rsi,%rdx
  shr    $0x2,%rax
  lea    (%rcx,%rax,8),%r10
  xor    %eax,%eax
  and    $0xfffffff8,%edx
L75:
  mov    %eax,%esi
  add    $0x8,%eax
  mov    (%r10,%rsi,1),%rdi
  mov    %rdi,(%r15,%rsi,1)
  cmp    %edx,%eax
  jb     L75
  mov    0x40(%rsp),%rax
  mov    0x48(%rsp),%rcx
  mov    %r15,%rdi
  mov    0x10(%rsp),%rsi
  mov    %rax,0x20(%rsp)
  mov    %rcx,0x18(%rsp)
  call   <decrypt@plt>
  xor    0x40(%rsp),%r12
  xor    0x48(%rsp),%rbp
  mov    %r12,0x30(%rsp)
  mov    0x20(%rsp),%r12
  mov    %rbp,0x38(%rsp)
  mov    0x18(%rsp),%rbp
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L80:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void decrypt_cbc(unsigned long *in, unsigned long len, unsigned long *key, unsigned long *out) {
  unsigned long x[2], nx[2], dec[2], tea[2], offset;
  x[0] = x[1] = 0xffffffff;
  for (offset = 0; offset < len; offset += 8) {
    int blen = 8;
    if ((len - offset) < 8)
      blen = len - offset;
    int i;
    for (i = 0; i < (blen >> 2); i++)
      tea[i] = in[(offset >> 2) + i];
    nx[0] = tea[0];
    nx[1] = tea[1];
    decrypt(tea, key);
    dec[0] = tea[0] ^ x[0];
    dec[1] = tea[1] ^ x[1];
    x[0] = nx[0];
    x[1] = nx[1];
    for (i = 0; i < blen; i++)
      ((unsigned char *)out)[offset + i] = ((unsigned char *)dec)[i];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decrypt_cbc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L35
  mov    %rsi,%rbp
  mov    %rdx,%r13
  lea    0x40(%rsp),%r15
  mov    %rsi,%rbx
  movdqa D4(%rip),%xmm3
  lea    (%rcx,%rsi,1),%r12
  movaps %xmm3,(%rsp)
  jmp    L25
L42:
  mov    %ebx,%ecx
  mov    %ebx,%r14d
  sar    $0x2,%ecx
  cmp    $0x1,%ecx
  je     L62
  movdqa 0x40(%rsp),%xmm2
  mov    %r13,%rsi
  mov    %r15,%rdi
  movaps %xmm2,0x10(%rsp)
  call   <decrypt@plt>
  movdqa (%rsp),%xmm0
  movdqa 0x10(%rsp),%xmm2
  pxor   0x40(%rsp),%xmm0
  movaps %xmm2,(%rsp)
  movaps %xmm0,0x30(%rsp)
  test   %rbx,%rbx
  je     L81
L89:
  mov    %r12,%rdi
  lea    -0x1(%r14),%edx
  mov    $0x1,%eax
  add    $0x1,%rdx
  sub    %rbx,%rdi
  lea    0x30(%rsp),%rsi
  test   %r14d,%r14d
  cmovle %rax,%rdx
  call   <memcpy@plt>
L81:
  sub    $0x8,%rbx
  mov    %rbp,%rax
  sub    %rbx,%rax
  cmp    %rax,%rbp
  jbe    L35
L25:
  mov    %rbp,%rax
  sub    %rbx,%rax
  cmp    $0x7,%rbx
  jbe    L42
  mov    $0x2,%ecx
  mov    $0x8,%r14d
L62:
  movslq %ecx,%rdx
  mov    0x28(%rsp),%rsi
  shl    $0x3,%rdx
  test   %ecx,%ecx
  mov    $0x8,%ecx
  cmovle %rcx,%rdx
  shr    $0x2,%rax
  lea    (%rsi,%rax,8),%rdi
  xor    %eax,%eax
  and    $0xfffffff8,%edx
L61:
  mov    %eax,%ecx
  add    $0x8,%eax
  mov    (%rdi,%rcx,1),%rsi
  mov    %rsi,(%r15,%rcx,1)
  cmp    %edx,%eax
  jb     L61
  movdqa 0x40(%rsp),%xmm1
  mov    %r13,%rsi
  mov    %r15,%rdi
  movaps %xmm1,0x10(%rsp)
  call   <decrypt@plt>
  movdqa (%rsp),%xmm0
  movdqa 0x10(%rsp),%xmm1
  pxor   0x40(%rsp),%xmm0
  movaps %xmm1,(%rsp)
  movaps %xmm0,0x30(%rsp)
  jmp    L89
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: byte[16]

tool: {"D4": [0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0x00,0x00,0x00,0x00]}

assistant: ```c
void decrypt_cbc(unsigned long *in, unsigned long len, unsigned long *key, unsigned long *out) {
  unsigned long x[2], nx[2], dec[2], tea[2], offset;
  x[0] = x[1] = 0xffffffff;
  for (offset = 0; offset < len; offset += 8) {
    int blen = 8;
    if ((len - offset) < 8)
      blen = len - offset;
    int i;
    for (i = 0; i < (blen >> 2); i++)
      tea[i] = in[(offset >> 2) + i];
    nx[0] = tea[0];
    nx[1] = tea[1];
    decrypt(tea, key);
    dec[0] = tea[0] ^ x[0];
    dec[1] = tea[1] ^ x[1];
    x[0] = nx[0];
    x[1] = nx[1];
    for (i = 0; i < blen; i++)
      ((unsigned char *)out)[offset + i] = ((unsigned char *)dec)[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<codeSynchronization_clearCache>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void codeSynchronization_clearCache(long unsigned codeStart, long unsigned codeSize) {
  long unsigned codeEnd = codeStart + codeSize;
  __builtin___clear_cache((char *)codeStart, (char *)codeEnd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<codeSynchronization_clearCache>:
  endbr64
  ret
```

assistant: ```c
void codeSynchronization_clearCache(long unsigned codeStart, long unsigned codeSize) {
  long unsigned codeEnd = codeStart + codeSize;
  __builtin___clear_cache((char *)codeStart, (char *)codeEnd);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<codeSynchronization_clearCache>:
  endbr64
  ret
```

assistant: ```c
void codeSynchronization_clearCache(long unsigned codeStart, long unsigned codeSize) {
  long unsigned codeEnd = codeStart + codeSize;
  __builtin___clear_cache((char *)codeStart, (char *)codeEnd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<codeSynchronization_clearCache>:
  endbr64
  ret
```

assistant: ```c
void codeSynchronization_clearCache(long unsigned codeStart, long unsigned codeSize) {
  long unsigned codeEnd = codeStart + codeSize;
  __builtin___clear_cache((char *)codeStart, (char *)codeEnd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<InitPops>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  imul   %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
  call   <init_random@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L3:
  mov    $0x9,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <rand_beta@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L3
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L51:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L1:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%eax
  cltq
  add    %rsi,%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L1
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L51
  nop
  nop
  leave
  ret
```

assistant: ```c
void InitPops(double **Pops, double **OutsidePop, double **AF, int npop, int nSNP) {
  int i, j;
  *OutsidePop = malloc(sizeof(double) * nSNP);
  *Pops = malloc(sizeof(double) * nSNP * npop);
  *AF = malloc(sizeof(double) * npop);
  init_random();
  for (i = 0; i < nSNP; i++) {
    *(*(OutsidePop) + i) = (double)rand_beta(1, 9);
  }
  for (j = 0; j < npop; j++) {
    for (i = 0; i < nSNP; i++) {
      *(*(Pops) + j * nSNP + i) = *(*(OutsidePop) + i);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<InitPops>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%r13d
  mov    %r8d,%r12d
  movslq %r8d,%r15
  lea    0x0(,%r15,8),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movslq %r13d,%r14
  shl    $0x3,%r14
  mov    %r15,%rdi
  imul   %r14,%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,(%rdi)
  mov    $0x0,%eax
  call   <init_random@plt>
  test   %r12d,%r12d
  jle    L56
  mov    %r12d,%r15d
  shl    $0x3,%r15
  mov    $0x0,%r14d
L49:
  mov    $0x9,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <rand_beta@plt>
  mov    (%rbx),%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rdx,%r14,1)
  add    $0x8,%r14
  cmp    %r15,%r14
  jne    L49
L56:
  test   %r13d,%r13d
  jle    L30
  lea    -0x1(%r12),%eax
  lea    0x8(,%rax,8),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edi
  jmp    L52
L39:
  mov    (%rbx),%rdx
  movsd  (%rdx,%rax,1),%xmm0
  mov    %rcx,%rdx
  add    0x0(%rbp),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L39
L72:
  add    $0x1,%edi
  add    %r12d,%r8d
  cmp    %edi,%r13d
  je     L30
L52:
  movslq %r8d,%rcx
  shl    $0x3,%rcx
  mov    $0x0,%eax
  test   %r12d,%r12d
  jg     L39
  jmp    L72
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void InitPops(double **Pops, double **OutsidePop, double **AF, int npop, int nSNP) {
  int i, j;
  *OutsidePop = malloc(sizeof(double) * nSNP);
  *Pops = malloc(sizeof(double) * nSNP * npop);
  *AF = malloc(sizeof(double) * npop);
  init_random();
  for (i = 0; i < nSNP; i++) {
    *(*(OutsidePop) + i) = (double)rand_beta(1, 9);
  }
  for (j = 0; j < npop; j++) {
    for (i = 0; i < nSNP; i++) {
      *(*(Pops) + j * nSNP + i) = *(*(OutsidePop) + i);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<InitPops>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  movslq %ecx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r12,%rbx
  shl    $0x3,%r12
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movslq %r8d,%rdx
  lea    0x0(,%rdx,8),%r15
  mov    %rdx,(%rsp)
  mov    %rdx,%r14
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    (%rsp),%rdi
  mov    %rax,0x0(%r13)
  imul   %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  mov    %rax,0x0(%rbp)
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  mov    %rax,(%rsi)
  xor    %eax,%eax
  call   <init_random@plt>
  test   %r14d,%r14d
  jle    L17
  nopl   (%rax)
L6:
  mov    $0x9,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <rand_beta@plt>
  pxor   %xmm0,%xmm0
  mov    0x0(%r13),%rdx
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rdx,%r12,1)
  add    $0x8,%r12
  cmp    %r15,%r12
  jne    L6
L17:
  test   %ebx,%ebx
  jle    L13
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  lea    -0x1(%r14),%edi
  nopw   0x0(%rax,%rax,1)
L34:
  test   %r14d,%r14d
  jle    L9
  mov    0x0(%rbp),%rdx
  movslq %r9d,%rax
  mov    0x0(%r13),%rsi
  lea    (%rdx,%rax,8),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L49:
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rdx
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L49
L9:
  add    $0x1,%r8d
  add    %r14d,%r9d
  cmp    %r8d,%ebx
  jne    L34
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void InitPops(double **Pops, double **OutsidePop, double **AF, int npop, int nSNP) {
  int i, j;
  *OutsidePop = malloc(sizeof(double) * nSNP);
  *Pops = malloc(sizeof(double) * nSNP * npop);
  *AF = malloc(sizeof(double) * npop);
  init_random();
  for (i = 0; i < nSNP; i++) {
    *(*(OutsidePop) + i) = (double)rand_beta(1, 9);
  }
  for (j = 0; j < npop; j++) {
    for (i = 0; i < nSNP; i++) {
      *(*(Pops) + j * nSNP + i) = *(*(OutsidePop) + i);
    }
  }
}
```