ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<split>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %esi,%ebp
  mov    $0x1,%esi
  sar    %ebp
  lea    0x1(%rbp),%edi
  sub    %ebp,%ebx
  call   <calloc@plt>
  lea    0x1(%rbx),%edi
  mov    $0x1,%esi
  mov    %rax,(%r14)
  call   <calloc@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  movslq %ebp,%rbp
  mov    %rax,0x0(%r13)
  mov    (%r14),%rdi
  call   <memcpy@plt>
  mov    0x0(%r13),%rdi
  lea    (%r12,%rbp,1),%rsi
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <memcpy@plt>
  mov    (%r14),%rax
  movb   $0x0,(%rax,%rbp,1)
  mov    0x0(%r13),%rax
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void split(char *x, int n, char **a, char **b) {
  *a = calloc(n / 2 + 1, sizeof(char));
  *b = calloc(n - n / 2 + 1, sizeof(char));
  memcpy(*a, x, n / 2);
  memcpy(*b, x + n / 2, n - n / 2);
  (*a)[n / 2] = 0;
  (*b)[n - n / 2] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  shr    $0x1f,%ebp
  push   %rbx
  mov    %esi,%ebx
  add    %esi,%ebp
  mov    $0x1,%esi
  sar    %ebp
  lea    0x1(%rbp),%edi
  sub    %ebp,%ebx
  call   <calloc@plt>
  lea    0x1(%rbx),%edi
  mov    $0x1,%esi
  mov    %rax,(%r14)
  call   <calloc@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  movslq %ebp,%rbp
  mov    %rax,0x0(%r13)
  mov    (%r14),%rdi
  call   <memcpy@plt>
  mov    0x0(%r13),%rdi
  lea    (%r12,%rbp,1),%rsi
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <memcpy@plt>
  mov    (%r14),%rax
  movb   $0x0,(%rax,%rbp,1)
  mov    0x0(%r13),%rax
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void split(char *x, int n, char **a, char **b) {
  *a = calloc(n / 2 + 1, sizeof(char));
  *b = calloc(n - n / 2 + 1, sizeof(char));
  memcpy(*a, x, n / 2);
  memcpy(*b, x + n / 2, n - n / 2);
  (*a)[n / 2] = 0;
  (*b)[n - n / 2] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flipAdjacent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L27:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L54
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  jmp    L53
L54:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x4(%rbp)
L53:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L14
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  jmp    L0
L14:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x4(%rbp)
L0:
  addl   $0x2,-0x8(%rbp)
L39:
  cmpl   $0x6,-0x8(%rbp)
  jle    L27
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int flipAdjacent(int d) {
  int n;
  int converted = 0;
  for (n = 0; n < 7; n += 2) {
    if (d & (1 << n)) {
      converted |= (1 << (n + 1));
    } else {
      converted &= ~(1 << (n + 1));
    }
    if (d & (1 << (n + 1))) {
      converted |= (1 << n);
    } else {
      converted &= ~(1 << n);
    }
  }
  return converted;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flipAdjacent>:
  endbr64
  mov    $0x1,%edx
  mov    $0x0,%eax
  mov    $0x1,%r8d
  jmp    L21
L23:
  mov    %r8d,%r9d
  mov    %edx,%ecx
  shl    %cl,%r9d
  mov    %r9d,%ecx
  not    %ecx
  and    %ecx,%eax
  jmp    L11
L38:
  mov    %r8d,%r10d
  mov    %esi,%ecx
  shl    %cl,%r10d
  mov    %r10d,%ecx
  not    %ecx
  and    %ecx,%eax
L22:
  add    $0x2,%edx
  cmp    $0x9,%edx
  je     L50
L21:
  lea    -0x1(%rdx),%esi
  bt     %esi,%edi
  jae    L23
  bts    %edx,%eax
L11:
  bt     %edx,%edi
  jae    L38
  bts    %esi,%eax
  jmp    L22
L50:
  ret
```

assistant: ```c
int flipAdjacent(int d) {
  int n;
  int converted = 0;
  for (n = 0; n < 7; n += 2) {
    if (d & (1 << n)) {
      converted |= (1 << (n + 1));
    } else {
      converted &= ~(1 << (n + 1));
    }
    if (d & (1 << (n + 1))) {
      converted |= (1 << n);
    } else {
      converted &= ~(1 << n);
    }
  }
  return converted;
}
```
user: What is the c source code of the assembly code below?

```asm
<flipAdjacent>:
  endbr64
  mov    %edi,%r8d
  xor    %eax,%eax
  xor    %esi,%esi
  mov    $0x1,%r9d
L4:
  lea    0x1(%rsi),%edi
  mov    %r9d,%edx
  mov    %r8d,%r10d
  mov    %r8d,%r11d
  mov    %edi,%ecx
  shl    %cl,%edx
  mov    %esi,%ecx
  sar    %cl,%r10d
  mov    %eax,%ecx
  or     %edx,%ecx
  not    %edx
  and    %eax,%edx
  and    $0x1,%r10d
  mov    %r9d,%eax
  cmovne %ecx,%edx
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %edi,%ecx
  sar    %cl,%r11d
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    %r11d,%edi
  not    %eax
  and    %edx,%eax
  and    $0x1,%edi
  cmovne %ecx,%eax
  add    $0x2,%esi
  cmp    $0x8,%esi
  jne    L4
  ret
```

assistant: ```c
int flipAdjacent(int d) {
  int n;
  int converted = 0;
  for (n = 0; n < 7; n += 2) {
    if (d & (1 << n)) {
      converted |= (1 << (n + 1));
    } else {
      converted &= ~(1 << (n + 1));
    }
    if (d & (1 << (n + 1))) {
      converted |= (1 << n);
    } else {
      converted &= ~(1 << n);
    }
  }
  return converted;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<flipAdjacent>:
  endbr64
  mov    %edi,%edx
  and    $0x1,%edx
  test   $0x2,%dil
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rdx,%rdx,1),%edx
  cmove  %eax,%edx
  mov    %edx,%eax
  or     $0x8,%eax
  test   $0x4,%dil
  cmovne %eax,%edx
  mov    %edx,%eax
  or     $0x4,%eax
  test   $0x8,%dil
  cmove  %edx,%eax
  mov    %eax,%edx
  or     $0x20,%edx
  test   $0x10,%dil
  cmovne %edx,%eax
  mov    %eax,%edx
  or     $0x10,%eax
  and    $0xffffffef,%edx
  test   $0x20,%dil
  cmove  %edx,%eax
  mov    %eax,%edx
  or     $0x80,%dl
  test   $0x40,%dil
  cmovne %edx,%eax
  mov    %eax,%edx
  and    $0xffffffbf,%eax
  or     $0x40,%edx
  and    $0x80,%edi
  cmovne %edx,%eax
  ret
```

assistant: ```c
int flipAdjacent(int d) {
  int n;
  int converted = 0;
  for (n = 0; n < 7; n += 2) {
    if (d & (1 << n)) {
      converted |= (1 << (n + 1));
    } else {
      converted &= ~(1 << (n + 1));
    }
    if (d & (1 << (n + 1))) {
      converted |= (1 << n);
    } else {
      converted &= ~(1 << n);
    }
  }
  return converted;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quickSelect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L9
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L29
L9:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L31
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L29
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L54
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <quickSelect>
  jmp    L29
L54:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <quickSelect>
L29:
  leave
  ret
```

assistant: ```c
int quickSelect(int *array, int start, int end, int indexToFind) {
  if (start >= end) {
    return array[start];
  }
  int pivot = partition(array, start, end);
  if (pivot == indexToFind) {
    return array[indexToFind];
  } else if (pivot < indexToFind) {
    return quickSelect(array, pivot + 1, end, indexToFind);
  } else {
    return quickSelect(array, start, pivot - 1, indexToFind);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quickSelect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  cmp    %edx,%esi
  jl     L55
  movslq %esi,%rbx
  mov    (%rdi,%rbx,4),%eax
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  mov    %edx,%ebp
  mov    %ecx,%r12d
  call   <partition@plt>
  cmp    %r12d,%eax
  je     L53
  jge    L12
  lea    0x1(%rax),%esi
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <quickSelect>
  jmp    L46
L53:
  movslq %r12d,%r12
  mov    0x0(%r13,%r12,4),%eax
  jmp    L46
L12:
  lea    -0x1(%rax),%edx
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <quickSelect>
  jmp    L46
```

assistant: ```c
int quickSelect(int *array, int start, int end, int indexToFind) {
  if (start >= end) {
    return array[start];
  }
  int pivot = partition(array, start, end);
  if (pivot == indexToFind) {
    return array[indexToFind];
  } else if (pivot < indexToFind) {
    return quickSelect(array, pivot + 1, end, indexToFind);
  } else {
    return quickSelect(array, start, pivot - 1, indexToFind);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<quickSelect>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jl     L54
  jmp    L57
  nop
L7:
  lea    0x1(%rax),%ebx
  cmp    %ebx,%r12d
  jle    L57
L54:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L43
  jl     L7
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%r12d
  jg     L54
L57:
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  mov    0x0(%rbp,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int quickSelect(int *array, int start, int end, int indexToFind) {
  if (start >= end) {
    return array[start];
  }
  int pivot = partition(array, start, end);
  if (pivot == indexToFind) {
    return array[indexToFind];
  } else if (pivot < indexToFind) {
    return quickSelect(array, pivot + 1, end, indexToFind);
  } else {
    return quickSelect(array, start, pivot - 1, indexToFind);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quickSelect>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jge    L21
  nopl   (%rax)
L18:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L28
  jge    L27
  lea    0x1(%rax),%ebx
  cmp    %r12d,%ebx
  jl     L18
L21:
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L27:
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%r12d
  jg     L18
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L28:
  mov    0x0(%rbp,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int quickSelect(int *array, int start, int end, int indexToFind) {
  if (start >= end) {
    return array[start];
  }
  int pivot = partition(array, start, end);
  if (pivot == indexToFind) {
    return array[indexToFind];
  } else if (pivot < indexToFind) {
    return quickSelect(array, pivot + 1, end, indexToFind);
  } else {
    return quickSelect(array, start, pivot - 1, indexToFind);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xa,-0xc(%rbp)
  jmp    L29
L3:
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L29
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
L29:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L3
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <tail@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10;
  while (--argc > 0) {
    char *arg = *++argv;
    if (*arg == '-') {
      n = atoi(++arg);
    }
  }
  tail(n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L22
  mov    %rsi,%rbx
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
  mov    $0xa,%eax
  jmp    L41
L7:
  cmp    %rbp,%rbx
  je     L18
L41:
  add    $0x8,%rbx
  mov    (%rbx),%rdx
  cmpb   $0x2d,(%rdx)
  jne    L7
  lea    0x1(%rdx),%rdi
  call   <atoi@plt>
  jmp    L7
L22:
  mov    $0xa,%eax
L18:
  mov    %eax,%edi
  call   <tail@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10;
  while (--argc > 0) {
    char *arg = *++argv;
    if (*arg == '-') {
      n = atoi(++arg);
    }
  }
  tail(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L31
  lea    -0x2(%rdi),%eax
  mov    %rsi,%rbx
  mov    $0xa,%edi
  lea    0x8(%rsi,%rax,8),%rbp
  jmp    L36
  nopl   0x0(%rax)
L16:
  cmp    %rbp,%rbx
  je     L11
L36:
  mov    0x8(%rbx),%rdx
  add    $0x8,%rbx
  cmpb   $0x2d,(%rdx)
  jne    L16
  lea    0x1(%rdx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  cmp    %rbp,%rbx
  jne    L36
L11:
  call   <tail@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    $0xa,%edi
  jmp    L11
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10;
  while (--argc > 0) {
    char *arg = *++argv;
    if (*arg == '-') {
      n = atoi(++arg);
    }
  }
  tail(n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L49
  lea    -0x2(%rdi),%eax
  mov    %rsi,%rbx
  mov    $0xa,%edi
  lea    0x8(%rsi,%rax,8),%rbp
  jmp    L55
  nopl   0x0(%rax)
L8:
  cmp    %rbp,%rbx
  je     L21
L55:
  mov    0x8(%rbx),%rdx
  add    $0x8,%rbx
  cmpb   $0x2d,(%rdx)
  jne    L8
  lea    0x1(%rdx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  cmp    %rbp,%rbx
  jne    L55
L21:
  call   <tail@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L49:
  mov    $0xa,%edi
  jmp    L21
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10;
  while (--argc > 0) {
    char *arg = *++argv;
    if (*arg == '-') {
      n = atoi(++arg);
    }
  }
  tail(n);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Libre_agregar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int Libre_agregar(size_t *len, unsigned int **arr, unsigned int l) {
  (*len)++;
  *arr = (unsigned int *)realloc(*arr, (*len) * sizeof(unsigned int));
  (*arr)[(*len) - 1] = l;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Libre_agregar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    (%rdi),%rax
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rdi)
  shl    $0x2,%rsi
  mov    0x0(%rbp),%rdi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdx
  mov    %r12d,-0x4(%rax,%rdx,4)
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Libre_agregar(size_t *len, unsigned int **arr, unsigned int l) {
  (*len)++;
  *arr = (unsigned int *)realloc(*arr, (*len) * sizeof(unsigned int));
  (*arr)[(*len) - 1] = l;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Libre_agregar>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rdi)
  mov    0x0(%rbp),%rdi
  shl    $0x2,%rsi
  call   <realloc@plt>
  mov    (%rbx),%rdx
  mov    %rax,0x0(%rbp)
  mov    %r12d,-0x4(%rax,%rdx,4)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Libre_agregar(size_t *len, unsigned int **arr, unsigned int l) {
  (*len)++;
  *arr = (unsigned int *)realloc(*arr, (*len) * sizeof(unsigned int));
  (*arr)[(*len) - 1] = l;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Libre_agregar>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    %rdi,%rbx
  lea    0x1(%rax),%rsi
  mov    %rsi,(%rdi)
  mov    0x0(%rbp),%rdi
  shl    $0x2,%rsi
  call   <realloc@plt>
  mov    (%rbx),%rdx
  mov    %rax,0x0(%rbp)
  mov    %r12d,-0x4(%rax,%rdx,4)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Libre_agregar(size_t *len, unsigned int **arr, unsigned int l) {
  (*len)++;
  *arr = (unsigned int *)realloc(*arr, (*len) * sizeof(unsigned int));
  (*arr)[(*len) - 1] = l;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<EndBSPFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <EmitBrushes@plt>
  mov    $0x0,%eax
  call   <EmitPlanes@plt>
  mov    $0x0,%eax
  call   <Q2_UnparseEntities@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EndBSPFile(void) {
  EmitBrushes();
  EmitPlanes();
  Q2_UnparseEntities();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<EndBSPFile>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <EmitBrushes@plt>
  mov    $0x0,%eax
  call   <EmitPlanes@plt>
  mov    $0x0,%eax
  call   <Q2_UnparseEntities@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void EndBSPFile(void) {
  EmitBrushes();
  EmitPlanes();
  Q2_UnparseEntities();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EndBSPFile>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <EmitBrushes@plt>
  xor    %eax,%eax
  call   <EmitPlanes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <Q2_UnparseEntities@plt>
```

assistant: ```c
void EndBSPFile(void) {
  EmitBrushes();
  EmitPlanes();
  Q2_UnparseEntities();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EndBSPFile>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <EmitBrushes@plt>
  xor    %eax,%eax
  call   <EmitPlanes@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <Q2_UnparseEntities@plt>
```

assistant: ```c
void EndBSPFile(void) {
  EmitBrushes();
  EmitPlanes();
  Q2_UnparseEntities();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f3tensor>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %edx,%r12d
  movslq %edi,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13d,%r14d
  imul   %ebx,%r14d
  movslq %r14d,%rdi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  imul   %r12d,%r14d
  movslq %r14d,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx)
  cmp    $0x1,%ebx
  je     L21
  movslq %r12d,%rdi
  shl    $0x2,%rdi
  lea    -0x1(%rbx),%esi
  shl    $0x3,%rsi
  mov    $0x0,%eax
L5:
  mov    0x0(%rbp),%rdx
  mov    %rax,%rcx
  add    $0x8,%rax
  mov    %rdi,%r11
  add    (%rdx,%rcx,1),%r11
  mov    %r11,(%rdx,%rax,1)
  cmp    %rsi,%rax
  jne    L5
L21:
  cmp    $0x1,%r13d
  je     L48
  movslq %ebx,%r11
  shl    $0x3,%r11
  mov    %ebx,%r10d
  imul   %r12d,%r10d
  movslq %r10d,%r10
  shl    $0x2,%r10
  movslq %r12d,%rdi
  shl    $0x2,%rdi
  mov    %rbp,%r9
  lea    -0x1(%r13),%eax
  lea    0x0(%rbp,%rax,8),%r12
  lea    -0x2(%rbx),%eax
  lea    0x8(,%rax,8),%r8
L20:
  mov    %r9,%rdx
  add    $0x8,%r9
  mov    %r9,%rsi
  mov    %r11,%rax
  add    (%rdx),%rax
  mov    %rax,(%r9)
  mov    (%rdx),%rdx
  mov    %r10,%rcx
  add    (%rdx),%rcx
  mov    %rcx,(%rax)
  cmp    $0x1,%ebx
  je     L59
  mov    $0x0,%eax
L30:
  mov    (%rsi),%rdx
  mov    %rax,%rcx
  add    $0x8,%rax
  mov    %rdi,%r14
  add    (%rdx,%rcx,1),%r14
  mov    %r14,(%rdx,%rax,1)
  cmp    %r8,%rax
  jne    L30
L59:
  cmp    %r12,%r9
  jne    L20
L48:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
float ***f3tensor(int nrow, int ncol, int ndep) {
  int i, j;
  float ***t;
  t = (float ***)malloc((size_t)(nrow * sizeof(float **)));
  t[0] = (float **)malloc((size_t)(nrow * ncol * sizeof(float *)));
  t[0][0] = (float *)malloc((size_t)(nrow * ncol * ndep * sizeof(float)));
  for (j = 1; j != ncol; j++)
    t[0][j] = t[0][j - 1] + ndep;
  for (i = 1; i != nrow; i++) {
    t[i] = t[i - 1] + ncol;
    t[i][0] = t[i - 1][0] + ncol * ndep;
    for (j = 1; j != ncol; j++)
      t[i][j] = t[i][j - 1] + ndep;
  }
  return t;
}
```