ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rawsocket_checksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L6
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r8d
  shr    %r8d
  lea    0x1(%r8),%ecx
  cmp    $0x5,%r9d
  jbe    L71
  mov    %rdi,%rax
  mov    %ecx,%edi
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
L88:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L88
  movdqa %xmm0,%xmm1
  mov    %ecx,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edi
  paddd  %xmm1,%xmm0
  mov    %edi,%r10d
  movdqa %xmm0,%xmm1
  neg    %r10d
  psrldq $0x4,%xmm1
  lea    (%rsi,%r10,2),%esi
  mov    %edi,%r10d
  paddd  %xmm1,%xmm0
  lea    (%rdx,%r10,4),%r10
  movd   %xmm0,%eax
  cmp    %edi,%ecx
  je     L114
L97:
  lea    -0x2(%rsi),%edi
  add    (%r10),%eax
  cmp    $0x1,%edi
  jle    L114
  add    0x4(%r10),%eax
  cmp    $0x5,%esi
  jle    L114
  add    0x8(%r10),%eax
L114:
  neg    %r8d
  lea    (%rdx,%rcx,4),%rdx
  lea    (%r9,%r8,2),%ecx
  cmp    $0x1,%ecx
  jne    L115
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L15:
  movzwl %ax,%eax
  add    %edx,%eax
L115:
  mov    %eax,%edx
  sar    $0x10,%edx
  jne    L15
  not    %eax
  ret
L5:
  xor    %eax,%eax
  nopl   0x0(%rax)
L70:
  add    (%rdx),%eax
  jmp    L115
  nopl   0x0(%rax)
L6:
  je     L5
  mov    $0xffffffff,%eax
  ret
L71:
  mov    %rdi,%r10
  xor    %eax,%eax
  jmp    L97
```

assistant: ```c
uint16_t rawsocket_checksum(void *addr, int count) {
  int32_t sum = 0;
  uint16_t *source = (uint16_t *)addr;
  while (count > 1) {
    sum += *source++;
    count -= 2;
  }
  if (count > 0) {
    uint16_t tmp = 0;
    *(uint8_t *)&tmp = *(uint8_t *)source;
    sum += tmp;
  }
  while (sum >> 16)
    sum = (sum & 0xffff) + (sum >> 16);
  return ~sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    $0x0,%edx
  mov    %edx,%ecx
  xchg   %ebx,%esi
  cpuid
  xchg   %ebx,%esi
  mov    %eax,-0x20(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %edx,-0x14(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void main() {
  unsigned int cpu_info[4];
  __asm__ __volatile__("xchgl %%ebx, %k1; cpuid; xchgl %%ebx, %k1" : "=a"(cpu_info[0]), "=&r"(cpu_info[1]), "=c"(cpu_info[2]), "=d"(cpu_info[3]) : "0"(0U), "2"(0U));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  mov    %eax,%ecx
  xchg   %ebx,%esi
  cpuid
  xchg   %ebx,%esi
  ret
```

assistant: ```c
void main() {
  unsigned int cpu_info[4];
  __asm__ __volatile__("xchgl %%ebx, %k1; cpuid; xchgl %%ebx, %k1" : "=a"(cpu_info[0]), "=&r"(cpu_info[1]), "=c"(cpu_info[2]), "=d"(cpu_info[3]) : "0"(0U), "2"(0U));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  mov    %eax,%ecx
  xchg   %ebx,%esi
  cpuid
  xchg   %ebx,%esi
  ret
```

assistant: ```c
void main() {
  unsigned int cpu_info[4];
  __asm__ __volatile__("xchgl %%ebx, %k1; cpuid; xchgl %%ebx, %k1" : "=a"(cpu_info[0]), "=&r"(cpu_info[1]), "=c"(cpu_info[2]), "=d"(cpu_info[3]) : "0"(0U), "2"(0U));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  mov    %eax,%ecx
  xchg   %ebx,%esi
  cpuid
  xchg   %ebx,%esi
  ret
```

assistant: ```c
void main() {
  unsigned int cpu_info[4];
  __asm__ __volatile__("xchgl %%ebx, %k1; cpuid; xchgl %%ebx, %k1" : "=a"(cpu_info[0]), "=&r"(cpu_info[1]), "=c"(cpu_info[2]), "=d"(cpu_info[3]) : "0"(0U), "2"(0U));
}
```
user: What is the c source code of the assembly code below?

```asm
<LLRevBitsM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  shrl   -0x14(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned LLRevBitsM(unsigned int x, unsigned int bits) {
  unsigned int y = 0;
  while (bits--) {
    y = (y + y) + (x & 1);
    x >>= 1;
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LLRevBitsM>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L4
  mov    $0x0,%eax
L11:
  mov    %edi,%ecx
  and    $0x1,%ecx
  lea    (%rcx,%rax,2),%eax
  shr    %edi
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L11
  ret
L4:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned LLRevBitsM(unsigned int x, unsigned int bits) {
  unsigned int y = 0;
  while (bits--) {
    y = (y + y) + (x & 1);
    x >>= 1;
  }
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LLRevBitsM>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L9
  xchg   %ax,%ax
L18:
  mov    %edi,%edx
  shr    %edi
  and    $0x1,%edx
  lea    (%rdx,%r8,2),%r8d
  sub    $0x1,%eax
  jae    L18
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned LLRevBitsM(unsigned int x, unsigned int bits) {
  unsigned int y = 0;
  while (bits--) {
    y = (y + y) + (x & 1);
    x >>= 1;
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<LLRevBitsM>:
  endbr64
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L11
  xchg   %ax,%ax
L17:
  mov    %edi,%edx
  shr    %edi
  and    $0x1,%edx
  lea    (%rdx,%r8,2),%r8d
  sub    $0x1,%eax
  jae    L17
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned LLRevBitsM(unsigned int x, unsigned int bits) {
  unsigned int y = 0;
  while (bits--) {
    y = (y + y) + (x & 1);
    x >>= 1;
  }
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<duk__parse_pointer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L110
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L18
L110:
  mov    $0x0,%eax
  jmp    L90
L18:
  addq   $0x2,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x10,-0x14(%rbp)
  jmp    L54
L1:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  shlq   $0x4,-0x8(%rbp)
  cmpb   $0x2f,-0x19(%rbp)
  jbe    L0
  cmpb   $0x39,-0x19(%rbp)
  ja     L0
  movzbl -0x19(%rbp),%eax
  sub    $0x30,%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L8
L0:
  cmpb   $0x60,-0x19(%rbp)
  jbe    L30
  cmpb   $0x66,-0x19(%rbp)
  ja     L30
  movzbl -0x19(%rbp),%eax
  sub    $0x57,%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L8
L30:
  mov    $0x0,%eax
  jmp    L90
L8:
  addl   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L90:
  pop    %rbp
  ret
```

assistant: ```c
int duk__parse_pointer(const char *str, void **out) {
  const unsigned char *p;
  unsigned char ch;
  int count;
  int limit;
  long val;
  p = (const unsigned char *)str;
  if (p[0] != (unsigned char)'0' || p[1] != (unsigned char)'x') {
    return 0;
  }
  p += 2;
  for (val = 0, count = 0, limit = sizeof(void *) * 2; count < limit; count++) {
    ch = *p++;
    val <<= 4;
    if (ch >= (unsigned char)'0' && ch <= (unsigned char)'9') {
      val += ch - (unsigned char)'0';
    } else if (ch >= (unsigned char)'a' && ch <= (unsigned char)'f') {
      val += ch - (unsigned char)'a' + 0x0a;
    } else {
      return 0;
    }
  }
  *out = (void *)val;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<duk__parse_pointer>:
  endbr64
  mov    %rsi,%r8
  mov    $0x0,%eax
  cmpb   $0x30,(%rdi)
  jne    L56
  cmpb   $0x78,0x1(%rdi)
  jne    L56
  lea    0x2(%rdi),%rcx
  add    $0x12,%rdi
  mov    $0x0,%edx
  jmp    L64
L44:
  lea    -0x61(%rax),%esi
  cmp    $0x5,%sil
  ja     L58
  movzbl %al,%eax
  sub    $0x57,%eax
  cltq
  add    %rax,%rdx
L50:
  cmp    %rcx,%rdi
  je     L12
L64:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  shl    $0x4,%rdx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L44
  movzbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rax,%rdx
  jmp    L50
L12:
  mov    %rdx,(%r8)
  mov    $0x1,%eax
  ret
L58:
  mov    $0x0,%eax
L56:
  ret
```

assistant: ```c
int duk__parse_pointer(const char *str, void **out) {
  const unsigned char *p;
  unsigned char ch;
  int count;
  int limit;
  long val;
  p = (const unsigned char *)str;
  if (p[0] != (unsigned char)'0' || p[1] != (unsigned char)'x') {
    return 0;
  }
  p += 2;
  for (val = 0, count = 0, limit = sizeof(void *) * 2; count < limit; count++) {
    ch = *p++;
    val <<= 4;
    if (ch >= (unsigned char)'0' && ch <= (unsigned char)'9') {
      val += ch - (unsigned char)'0';
    } else if (ch >= (unsigned char)'a' && ch <= (unsigned char)'f') {
      val += ch - (unsigned char)'a' + 0x0a;
    } else {
      return 0;
    }
  }
  *out = (void *)val;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<duk__parse_pointer>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x30,(%rdi)
  mov    %rsi,%r8
  jne    L63
  cmpb   $0x78,0x1(%rdi)
  jne    L63
  lea    0x2(%rdi),%rcx
  xor    %edx,%edx
  add    $0x12,%rdi
  jmp    L5
L9:
  sub    $0x30,%eax
  cltq
  add    %rax,%rdx
  cmp    %rcx,%rdi
  je     L20
L5:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  shl    $0x4,%rdx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L9
  lea    -0x61(%rax),%esi
  cmp    $0x5,%sil
  ja     L29
  sub    $0x57,%eax
  cltq
  add    %rax,%rdx
  cmp    %rcx,%rdi
  jne    L5
L20:
  mov    %rdx,(%r8)
  mov    $0x1,%eax
  ret
L29:
  xor    %eax,%eax
L63:
  ret
```

assistant: ```c
int duk__parse_pointer(const char *str, void **out) {
  const unsigned char *p;
  unsigned char ch;
  int count;
  int limit;
  long val;
  p = (const unsigned char *)str;
  if (p[0] != (unsigned char)'0' || p[1] != (unsigned char)'x') {
    return 0;
  }
  p += 2;
  for (val = 0, count = 0, limit = sizeof(void *) * 2; count < limit; count++) {
    ch = *p++;
    val <<= 4;
    if (ch >= (unsigned char)'0' && ch <= (unsigned char)'9') {
      val += ch - (unsigned char)'0';
    } else if (ch >= (unsigned char)'a' && ch <= (unsigned char)'f') {
      val += ch - (unsigned char)'a' + 0x0a;
    } else {
      return 0;
    }
  }
  *out = (void *)val;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L15:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L31
L38:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L4
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jae    L15
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  int i = 1;
  for (; *s1 == *s2 && i <= n; s1++, s2++, i++)
    if (i == n)
      return 0;
  return *s1 - *s2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L24
  test   %rdx,%rdx
  je     L24
  cmp    $0x1,%rdx
  je     L17
  mov    $0x1,%ecx
L40:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  jne    L24
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jb     L24
  jne    L40
  mov    $0x0,%eax
  ret
L24:
  movsbl %al,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  int i = 1;
  for (; *s1 == *s2 && i <= n; s1++, s2++, i++)
    if (i == n)
      return 0;
  return *s1 - *s2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L50
  test   %rdx,%rdx
  je     L50
  cmp    $0x1,%rdx
  je     L29
  mov    $0x1,%ecx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jb     L50
  je     L29
L20:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  je     L22
L50:
  sub    %r8d,%eax
  ret
  nopl   (%rax)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  int i = 1;
  for (; *s1 == *s2 && i <= n; s1++, s2++, i++)
    if (i == n)
      return 0;
  return *s1 - *s2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  cmp    %r8b,%al
  jne    L69
  test   %rdx,%rdx
  je     L69
  cmp    $0x1,%rdx
  je     L38
  mov    $0x1,%ecx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  ja     L69
  je     L38
L16:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  cmp    %r8b,%al
  je     L1
L69:
  sub    %r8d,%eax
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  int i = 1;
  for (; *s1 == *s2 && i <= n; s1++, s2++, i++)
    if (i == n)
      return 0;
  return *s1 - *s2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sommaDispari>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L6
L2:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  lea    0x1(%rax),%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <sommaDispari>
  add    %ebx,%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int sommaDispari(int n) {
  if (n == 0)
    return 0;
  return (2 * (n - 1) + 1) + sommaDispari(n - 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sommaDispari>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L9
  ret
L9:
  push   %rbx
  lea    -0x1(%rdi),%ebx
  mov    %ebx,%edi
  call   <sommaDispari>
  lea    0x1(%rax,%rbx,2),%eax
  pop    %rbx
  ret
```

assistant: ```c
int sommaDispari(int n) {
  if (n == 0)
    return 0;
  return (2 * (n - 1) + 1) + sommaDispari(n - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sommaDispari>:
  endbr64
  lea    -0x1(%rdi,%rdi,1),%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L10
  nop
L1:
  add    %eax,%r8d
  sub    $0x2,%eax
  cmp    $0xffffffff,%eax
  jne    L1
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sommaDispari(int n) {
  if (n == 0)
    return 0;
  return (2 * (n - 1) + 1) + sommaDispari(n - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sommaDispari>:
  endbr64
  test   %edi,%edi
  je     L6
  lea    -0x1(%rdi),%ecx
  mov    %edi,%esi
  cmp    $0x5,%ecx
  jbe    L2
  movd   %edi,%xmm6
  mov    %edi,%edx
  movdqa D29(%rip),%xmm5
  xor    %eax,%eax
  pshufd $0x0,%xmm6,%xmm2
  shr    $0x2,%edx
  pxor   %xmm1,%xmm1
  pcmpeqd %xmm3,%xmm3
  paddd  D16(%rip),%xmm2
  movdqa D20(%rip),%xmm4
  nopw   0x0(%rax,%rax,1)
L75:
  movdqa %xmm2,%xmm0
  add    $0x1,%eax
  paddd  %xmm5,%xmm2
  paddd  %xmm3,%xmm0
  pslld  $0x1,%xmm0
  paddd  %xmm4,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %eax,%edx
  jne    L75
  movdqa %xmm1,%xmm0
  mov    %edi,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  paddd  %xmm0,%xmm1
  sub    %edx,%edi
  movdqa %xmm1,%xmm0
  lea    -0x1(%rdi),%ecx
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  cmp    %edx,%esi
  je     L83
L4:
  lea    (%rcx,%rcx,1),%edx
  lea    0x1(%rdx,%rax,1),%eax
  test   %ecx,%ecx
  je     L83
  lea    -0x1(%rdx,%rax,1),%eax
  cmp    $0x2,%edi
  je     L83
  lea    -0x3(%rdx,%rax,1),%eax
  cmp    $0x3,%edi
  je     L83
  lea    -0x5(%rdx,%rax,1),%eax
  cmp    $0x4,%edi
  je     L83
  lea    -0x7(%rdx,%rax,1),%eax
  cmp    $0x5,%edi
  lea    -0x9(%rdx,%rax,1),%edx
  cmovne %edx,%eax
L83:
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
L2:
  xor    %eax,%eax
  jmp    L4
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: byte[16]
name: parse_data
arguments: data_tag: D16
type: byte[16]
name: parse_data
arguments: data_tag: D20
type: byte[16]

tool: {"D29": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D16": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

tool: {"D20": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int sommaDispari(int n) {
  if (n == 0)
    return 0;
  return (2 * (n - 1) + 1) + sommaDispari(n - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x249f0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %u


assistant: ```c
int main() {
  volatile uint32_t a = 0xffffffff, b = 0;
  b = a & 150000;
  printf("%u\n", b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movl   $0xffffffff,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    0x8(%rsp),%eax
  and    $0x249f0,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: %u


assistant: ```c
int main() {
  volatile uint32_t a = 0xffffffff, b = 0;
  b = a & 150000;
  printf("%u\n", b);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  movl   $0xffffffff,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    0x8(%rsp),%eax
  and    $0x249f0,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %u


assistant: ```c
int main() {
  volatile uint32_t a = 0xffffffff, b = 0;
  b = a & 150000;
  printf("%u\n", b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  movl   $0xffffffff,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    0x8(%rsp),%eax
  and    $0x249f0,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: %u


assistant: ```c
int main() {
  volatile uint32_t a = 0xffffffff, b = 0;
  b = a & 150000;
  printf("%u\n", b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ccnl_str2suite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L1
L6:
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int ccnl_str2suite(char *cp) {
  if (!cp)
    return -1;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccnl_str2suite>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ccnl_str2suite(char *cp) {
  if (!cp)
    return -1;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ccnl_str2suite>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ccnl_str2suite(char *cp) {
  if (!cp)
    return -1;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_ends_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L26
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L26
  mov    $0x1,%eax
  jmp    L2
L26:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int str_ends_with(const char *s, const char *suffix) {
  size_t slen = strlen(s);
  size_t suffix_len = strlen(suffix);
  return suffix_len <= slen && !strcmp(s + slen - suffix_len, suffix);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_ends_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %rax,%rbp
  jb     L4
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
L4:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_ends_with(const char *s, const char *suffix) {
  size_t slen = strlen(s);
  size_t suffix_len = strlen(suffix);
  return suffix_len <= slen && !strcmp(s + slen - suffix_len, suffix);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_ends_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jb     L3
  sub    %rax,%rbp
  mov    %r12,%rsi
  lea    (%rbx,%rbp,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L3:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_ends_with(const char *s, const char *suffix) {
  size_t slen = strlen(s);
  size_t suffix_len = strlen(suffix);
  return suffix_len <= slen && !strcmp(s + slen - suffix_len, suffix);
}
```
user: What is the c source code of the assembly code below?

```asm
<str_ends_with>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jb     L9
  sub    %rax,%rbp
  mov    %r12,%rsi
  lea    (%rbx,%rbp,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L9:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_ends_with(const char *s, const char *suffix) {
  size_t slen = strlen(s);
  size_t suffix_len = strlen(suffix);
  return suffix_len <= slen && !strcmp(s + slen - suffix_len, suffix);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FNIEMOP_DEF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <IEMOP_MNEMONIC@plt>
  mov    $0x0,%eax
  call   <IEMOP_RAISE_INVALID_OPCODE@plt>
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: frstpm (80287XL/ign)

assistant: ```c
FNIEMOP_DEF(iemOp_frstpm) {
  IEMOP_MNEMONIC("frstpm (80287XL/ign)");
  return IEMOP_RAISE_INVALID_OPCODE();
}
```