ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mx_strvec_length>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0xffffffffffffffff,%rsi
  mov    %rbx,%rdi
  call   <mx_strvec_length_cache@plt>
  mov    %rax,%r12
  cmp    $0xffffffffffffffff,%rax
  jne    L16
  cmpq   $0x0,(%rbx)
  mov    %rbx,%rdi
  je     L18
  nopl   0x0(%rax)
L22:
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L22
  mov    %rdi,%r12
  sub    %rbx,%r12
  sar    $0x3,%r12
L36:
  mov    %r12,%rsi
  call   <mx_strvec_length_cache@plt>
L16:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L18:
  xor    %r12d,%r12d
  jmp    L36
```

assistant: ```c
size_t mx_strvec_length(char **strvec) {
  char **sv;
  size_t len;
  assert(strvec);
  sv = strvec;
  len = mx_strvec_length_cache(sv, -1);
  if (len != -1)
    return len;
  for (; *sv; sv++)
    ;
  len = sv - strvec;
  mx_strvec_length_cache(sv, len);
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<mx_strvec_length>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    $0xffffffffffffffff,%rsi
  mov    %rbx,%rdi
  call   <mx_strvec_length_cache@plt>
  mov    %rax,%r12
  cmp    $0xffffffffffffffff,%rax
  jne    L39
  cmpq   $0x0,(%rbx)
  mov    %rbx,%rdi
  je     L28
  nopl   0x0(%rax)
L35:
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L35
  mov    %rdi,%r12
  sub    %rbx,%r12
  sar    $0x3,%r12
L29:
  mov    %r12,%rsi
  call   <mx_strvec_length_cache@plt>
L39:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L28:
  xor    %r12d,%r12d
  jmp    L29
```

assistant: ```c
size_t mx_strvec_length(char **strvec) {
  char **sv;
  size_t len;
  assert(strvec);
  sv = strvec;
  len = mx_strvec_length_cache(sv, -1);
  if (len != -1)
    return len;
  for (; *sv; sv++)
    ;
  len = sv - strvec;
  mx_strvec_length_cache(sv, len);
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movss  %xmm0,-0x18(%rbp)
  movss  %xmm1,-0x1c(%rbp)
  movss  %xmm2,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x7,-0xc(%rbp)
  jg     L70
  movss  -0x18(%rbp),%xmm0
  jmp    L53
L70:
  movss  -0x1c(%rbp),%xmm0
L53:
  movss  %xmm0,-0x8(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jle    L105
  cmpl   $0xc,-0xc(%rbp)
  je     L7
  cmpl   $0xe,-0xc(%rbp)
  jne    L90
L7:
  movss  -0x18(%rbp),%xmm0
  jmp    L66
L90:
  movss  -0x20(%rbp),%xmm0
  jmp    L66
L105:
  movss  -0x1c(%rbp),%xmm0
L66:
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  movss  -0x8(%rbp),%xmm0
  movss  D1(%rip),%xmm1
  xorps  %xmm0,%xmm1
  jmp    L81
L2:
  movss  -0x8(%rbp),%xmm1
L81:
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L31
  movss  -0x4(%rbp),%xmm0
  movss  D1(%rip),%xmm2
  xorps  %xmm2,%xmm0
  jmp    L4
L31:
  movss  -0x4(%rbp),%xmm0
L4:
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
float grad(int hash_val, float x, float y, float z) {
  int h = hash_val & 15;
  float u = h < 8 ? x : y;
  float v = h < 4 ? y : h == 12 || h == 14 ? x : z;
  return ((h & 1) == 0 ? u : -u) + ((h & 2) == 0 ? v : -v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<grad>:
  endbr64
  movaps %xmm0,%xmm3
  test   $0x8,%dil
  je     L41
  movaps %xmm1,%xmm3
L41:
  test   $0xc,%dil
  je     L27
  mov    %edi,%eax
  and    $0xd,%eax
  movaps %xmm0,%xmm1
  cmp    $0xc,%eax
  je     L27
  movaps %xmm2,%xmm1
L27:
  test   $0x1,%dil
  je     L13
  xorps  D6(%rip),%xmm3
L13:
  test   $0x2,%dil
  je     L38
  xorps  D6(%rip),%xmm1
L38:
  addss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float grad(int hash_val, float x, float y, float z) {
  int h = hash_val & 15;
  float u = h < 8 ? x : y;
  float v = h < 4 ? y : h == 12 || h == 14 ? x : z;
  return ((h & 1) == 0 ? u : -u) + ((h & 2) == 0 ? v : -v);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<grad>:
  endbr64
  movaps %xmm0,%xmm3
  test   $0x8,%dil
  je     L35
  movaps %xmm1,%xmm3
L35:
  test   $0xc,%dil
  je     L55
  mov    %edi,%eax
  movaps %xmm0,%xmm1
  and    $0xd,%eax
  cmp    $0xc,%eax
  jne    L52
L55:
  test   $0x1,%dil
  je     L15
  xorps  D4(%rip),%xmm3
L15:
  and    $0x2,%edi
  je     L13
  xorps  D4(%rip),%xmm1
L13:
  addss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L52:
  movaps %xmm2,%xmm1
  jmp    L55
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: byte[16]

tool: {"D4": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float grad(int hash_val, float x, float y, float z) {
  int h = hash_val & 15;
  float u = h < 8 ? x : y;
  float v = h < 4 ? y : h == 12 || h == 14 ? x : z;
  return ((h & 1) == 0 ? u : -u) + ((h & 2) == 0 ? v : -v);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<grad>:
  endbr64
  movaps %xmm0,%xmm3
  test   $0x8,%dil
  je     L24
  movaps %xmm1,%xmm3
L24:
  test   $0xc,%dil
  je     L0
  mov    %edi,%eax
  movaps %xmm0,%xmm1
  and    $0xd,%eax
  cmp    $0xc,%eax
  jne    L19
L0:
  test   $0x1,%dil
  je     L52
  xorps  D15(%rip),%xmm3
L52:
  and    $0x2,%edi
  je     L34
  xorps  D15(%rip),%xmm1
L34:
  addss  %xmm1,%xmm3
  movaps %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  movaps %xmm2,%xmm1
  jmp    L0
```

tool_calls: name: read_data
arguments: tag: D15
data_type: byte[16]

tool: {"D15": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float grad(int hash_val, float x, float y, float z) {
  int h = hash_val & 15;
  float u = h < 8 ? x : y;
  float v = h < 4 ? y : h == 12 || h == 14 ? x : z;
  return ((h & 1) == 0 ? u : -u) + ((h & 2) == 0 ? v : -v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcpy_pic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jne    L16
  cmpl   $0x0,-0x30(%rbp)
  jns    L24
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x30(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x2c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  negl   -0x30(%rbp)
L24:
  mov    -0x30(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L30
L16:
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L12:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x30(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L12
L30:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memcpy_pic(void *dst, const void *src, int bytesPerLine, int height, int dstStride, int srcStride) {
  int i;
  void *retval = dst;
  if (dstStride == srcStride) {
    if (srcStride < 0) {
      src = (unsigned char *)src + (height - 1) * srcStride;
      dst = (unsigned char *)dst + (height - 1) * dstStride;
      srcStride = -srcStride;
    }
    memcpy(dst, src, srcStride * height);
  } else {
    for (i = 0; i < height; i++) {
      memcpy(dst, src, bytesPerLine);
      src = (unsigned char *)src + srcStride;
      dst = (unsigned char *)dst + dstStride;
    }
  }
  return retval;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memcpy_pic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  cmp    %r9d,%r8d
  je     L37
  mov    %edx,%r15d
  mov    %rdi,%r12
  mov    $0x0,%ebp
  movslq %r9d,%rax
  mov    %rax,(%rsp)
  test   %ecx,%ecx
  jle    L10
L13:
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  add    (%rsp),%rbx
  movslq %r14d,%rax
  add    %rax,%r12
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L13
L10:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rdi
  test   %r9d,%r9d
  js     L23
L49:
  mov    %r9d,%edx
  imul   %r13d,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  jmp    L10
L23:
  lea    -0x1(%r13),%edi
  mov    %edi,%eax
  imul   %r9d,%eax
  cltq
  add    %rax,%rbx
  imul   %r8d,%edi
  movslq %edi,%rdi
  add    %rcx,%rdi
  neg    %r9d
  jmp    L49
```

assistant: ```c
void *memcpy_pic(void *dst, const void *src, int bytesPerLine, int height, int dstStride, int srcStride) {
  int i;
  void *retval = dst;
  if (dstStride == srcStride) {
    if (srcStride < 0) {
      src = (unsigned char *)src + (height - 1) * srcStride;
      dst = (unsigned char *)dst + (height - 1) * dstStride;
      srcStride = -srcStride;
    }
    memcpy(dst, src, srcStride * height);
  } else {
    for (i = 0; i < height; i++) {
      memcpy(dst, src, bytesPerLine);
      src = (unsigned char *)src + srcStride;
      dst = (unsigned char *)dst + dstStride;
    }
  }
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy_pic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    %r9d,%r8d
  je     L30
  test   %ecx,%ecx
  jle    L21
  movslq %r9d,%rax
  mov    0x8(%rsp),%rbx
  mov    %edx,%r14d
  movslq %r8d,%r12
  mov    %rax,(%rsp)
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r14d,%edx
  add    $0x1,%r15d
  call   <memcpy@plt>
  add    %r12,%rbx
  add    (%rsp),%rbp
  cmp    %r15d,%r13d
  jne    L46
L21:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    0x8(%rsp),%rax
  mov    %rax,%rdi
  test   %r9d,%r9d
  jns    L19
  lea    -0x1(%rcx),%edi
  imul   %r9d,%edi
  neg    %r9d
  movslq %edi,%rdi
  add    %rdi,%rbp
  add    %rax,%rdi
L19:
  mov    %r9d,%edx
  mov    %rbp,%rsi
  imul   %r13d,%edx
  call   <memcpy@plt>
  jmp    L21
```

assistant: ```c
void *memcpy_pic(void *dst, const void *src, int bytesPerLine, int height, int dstStride, int srcStride) {
  int i;
  void *retval = dst;
  if (dstStride == srcStride) {
    if (srcStride < 0) {
      src = (unsigned char *)src + (height - 1) * srcStride;
      dst = (unsigned char *)dst + (height - 1) * dstStride;
      srcStride = -srcStride;
    }
    memcpy(dst, src, srcStride * height);
  } else {
    for (i = 0; i < height; i++) {
      memcpy(dst, src, bytesPerLine);
      src = (unsigned char *)src + srcStride;
      dst = (unsigned char *)dst + dstStride;
    }
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy_pic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  cmp    %r9d,%r8d
  je     L5
  test   %ecx,%ecx
  jle    L44
  movslq %r9d,%rax
  mov    %edx,%r14d
  mov    %rdi,%rbx
  movslq %r8d,%r12
  mov    %rax,(%rsp)
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r14d,%edx
  add    $0x1,%r15d
  call   <memcpy@plt>
  add    %r12,%rbx
  add    (%rsp),%rbp
  cmp    %r15d,%r13d
  jne    L1
L44:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  test   %r9d,%r9d
  jns    L28
  lea    -0x1(%rcx),%edi
  imul   %r9d,%edi
  neg    %r9d
  movslq %edi,%rdi
  add    %rdi,%rbp
  add    %rax,%rdi
L28:
  mov    %r9d,%edx
  mov    %rbp,%rsi
  imul   %r13d,%edx
  call   <memcpy@plt>
  jmp    L44
```

assistant: ```c
void *memcpy_pic(void *dst, const void *src, int bytesPerLine, int height, int dstStride, int srcStride) {
  int i;
  void *retval = dst;
  if (dstStride == srcStride) {
    if (srcStride < 0) {
      src = (unsigned char *)src + (height - 1) * srcStride;
      dst = (unsigned char *)dst + (height - 1) * dstStride;
      srcStride = -srcStride;
    }
    memcpy(dst, src, srcStride * height);
  } else {
    for (i = 0; i < height; i++) {
      memcpy(dst, src, bytesPerLine);
      src = (unsigned char *)src + srcStride;
      dst = (unsigned char *)dst + dstStride;
    }
  }
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  mov    -0x24(%rbp),%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  cltq
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movl   $0x3,(%rdx,%rax,4)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void g(int n, int m, int v[n + 1][m * 2]) {
#pragma omp parallel shared(v) firstprivate(n, m)
  { v[n - 1][m - 1] = 3; }
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  cltq
  sub    $0x1,%edi
  movslq %edi,%rdi
  imul   %rdi,%rax
  sub    $0x1,%esi
  movslq %esi,%rsi
  lea    (%rax,%rsi,1),%rax
  movl   $0x3,(%rdx,%rax,4)
  ret
```

assistant: ```c
void g(int n, int m, int v[n + 1][m * 2]) {
#pragma omp parallel shared(v) firstprivate(n, m)
  { v[n - 1][m - 1] = 3; }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  sub    $0x1,%edi
  sub    $0x1,%esi
  cltq
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rdi,%rax
  add    %rsi,%rax
  movl   $0x3,(%rdx,%rax,4)
  ret
```

assistant: ```c
void g(int n, int m, int v[n + 1][m * 2]) {
#pragma omp parallel shared(v) firstprivate(n, m)
  { v[n - 1][m - 1] = 3; }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g>:
  endbr64
  lea    (%rsi,%rsi,1),%eax
  sub    $0x1,%edi
  sub    $0x1,%esi
  cltq
  movslq %edi,%rdi
  movslq %esi,%rsi
  imul   %rdi,%rax
  add    %rsi,%rax
  movl   $0x3,(%rdx,%rax,4)
  ret
```

assistant: ```c
void g(int n, int m, int v[n + 1][m * 2]) {
#pragma omp parallel shared(v) firstprivate(n, m)
  { v[n - 1][m - 1] = 3; }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_line_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xe8(%rbp)
  mov    %esi,%eax
  mov    %edx,-0xf0(%rbp)
  mov    %al,-0xec(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xdc(%rbp)
  cmpq   $0x0,-0xe8(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L24
L32:
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xf0(%rbp)
  jle    L49
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L24
L49:
  mov    -0xf0(%rbp),%edx
  mov    -0xe8(%rbp),%rcx
  lea    -0xd0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movsbl -0xec(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rindex@plt>
  mov    %rax,-0xd8(%rbp)
  mov    -0xd8(%rbp),%rax
  mov    %eax,%edx
  lea    -0xd0(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xdc(%rbp)
  addl   $0x1,-0xdc(%rbp)
  mov    -0xdc(%rbp),%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int find_line_length(char *txt, char delim, int len) {
  char buf[200];
  char *cont;
  int i = 0;
  if (!txt)
    return 0;
  if (strlen(txt) < len)
    return strlen(txt);
  strncpy(buf, txt, len);
  cont = rindex(buf, (int)delim);
  i = ((int)cont - (int)buf);
  i++;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_line_length>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%ebp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jl     L1
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movsbl %r13b,%esi
  mov    %r12,%rdi
  call   <rindex@plt>
  sub    %r12d,%eax
  add    $0x1,%eax
L6:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %rbx,%rdi
  call   <strlen@plt>
  jmp    L6
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find_line_length(char *txt, char delim, int len) {
  char buf[200];
  char *cont;
  int i = 0;
  if (!txt)
    return 0;
  if (strlen(txt) < len)
    return strlen(txt);
  strncpy(buf, txt, len);
  cont = rindex(buf, (int)delim);
  i = ((int)cont - (int)buf);
  i++;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_line_length>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L1
  mov    %edx,%r12d
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L5
  mov    %rsp,%r13
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movsbl %bl,%esi
  mov    %r13,%rdi
  call   <rindex@plt>
  sub    %r13d,%eax
  add    $0x1,%eax
L48:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xd8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strlen@plt>
L1:
  xor    %eax,%eax
  jmp    L48
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find_line_length(char *txt, char delim, int len) {
  char buf[200];
  char *cont;
  int i = 0;
  if (!txt)
    return 0;
  if (strlen(txt) < len)
    return strlen(txt);
  strncpy(buf, txt, len);
  cont = rindex(buf, (int)delim);
  i = ((int)cont - (int)buf);
  i++;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_line_length>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L19
  mov    %edx,%r12d
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L45
  mov    %rsp,%r13
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movsbl %bl,%esi
  mov    %r13,%rdi
  call   <rindex@plt>
  sub    %r13d,%eax
  add    $0x1,%eax
L9:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0xd8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <strlen@plt>
L19:
  xor    %eax,%eax
  jmp    L9
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int find_line_length(char *txt, char delim, int len) {
  char buf[200];
  char *cont;
  int i = 0;
  if (!txt)
    return 0;
  if (strlen(txt) < len)
    return strlen(txt);
  strncpy(buf, txt, len);
  cont = rindex(buf, (int)delim);
  i = ((int)cont - (int)buf);
  i++;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x9,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x18,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <FIFO@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  int burst_time[] = {3, 7, 9, 3, 24};
  FIFO(burst_time);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0x9,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x18,0x10(%rsp)
  mov    %rsp,%rdi
  call   <FIFO@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int burst_time[] = {3, 7, 9, 3, 24};
  FIFO(burst_time);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000003,%rax
  mov    %rsp,%rdi
  movl   $0x18,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000009,%rax
  mov    %rax,0x8(%rsp)
  call   <FIFO@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int burst_time[] = {3, 7, 9, 3, 24};
  FIFO(burst_time);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x18,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <FIFO@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[16]

tool: {"D6": [0x03,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int burst_time[] = {3, 7, 9, 3, 24};
  FIFO(burst_time);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stranow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L38
L45:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L38
L30:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  test   %eax,%eax
  jne    L5
  cmpq   $0x0,-0x8(%rbp)
  je     L56
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L56:
  mov    $0x0,%eax
  jmp    L38
L5:
  mov    -0x8(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
char *stranow(const char *s) {
  char *p;
  int i;
  if (!s)
    return 0;
  i = strlen(s);
  p = (char *)malloc(sizeof(char) * (i + 1));
  if (!p)
    return 0;
  if (!strlcpy(p, s, (i + 1))) {
    if (p)
      free(p);
    return 0;
  }
  return p;
}
```