ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strendzap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L12
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strendzap(char *str, const char *pat) {
  size_t len, patlen;
  assert(str != NULL);
  assert(pat != NULL);
  len = strlen(str);
  patlen = strlen(pat);
  if (patlen <= len) {
    str += len - patlen;
    if (strcmp(str, pat) == 0)
      *str = '\0';
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strendzap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rax,%r12
  jae    L13
L17:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  sub    %rax,%r12
  add    %r12,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L17
  movb   $0x0,(%rbx)
  jmp    L17
```

assistant: ```c
char *strendzap(char *str, const char *pat) {
  size_t len, patlen;
  assert(str != NULL);
  assert(pat != NULL);
  len = strlen(str);
  patlen = strlen(pat);
  if (patlen <= len) {
    str += len - patlen;
    if (strcmp(str, pat) == 0)
      *str = '\0';
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strendzap>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jae    L17
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  sub    %rax,%rbx
  mov    %rbp,%rsi
  add    %rbx,%r12
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
char *strendzap(char *str, const char *pat) {
  size_t len, patlen;
  assert(str != NULL);
  assert(pat != NULL);
  len = strlen(str);
  patlen = strlen(pat);
  if (patlen <= len) {
    str += len - patlen;
    if (strcmp(str, pat) == 0)
      *str = '\0';
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strendzap>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jae    L18
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  sub    %rax,%rbx
  mov    %rbp,%rsi
  add    %rbx,%r12
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
char *strendzap(char *str, const char *pat) {
  size_t len, patlen;
  assert(str != NULL);
  assert(pat != NULL);
  len = strlen(str);
  patlen = strlen(pat);
  if (patlen <= len) {
    str += len - patlen;
    if (strcmp(str, pat) == 0)
      *str = '\0';
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    $0x0,%eax
  call   <g@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
f(int x) {
  if (x < 0)
    g();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <g@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
f(int x) {
  if (x < 0)
    g();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L4
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  jmp    1050 <g@plt>
```

assistant: ```c
f(int x) {
  if (x < 0)
    g();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  jmp    1050 <g@plt>
```

assistant: ```c
f(int x) {
  if (x < 0)
    g();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <corrupt_frame_outer@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  corrupt_frame_outer();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <corrupt_frame_outer@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  corrupt_frame_outer();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <corrupt_frame_outer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  corrupt_frame_outer();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <corrupt_frame_outer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  corrupt_frame_outer();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pathcon_nm7_name_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L16
  cmpl   $0x1,-0x4(%rbp)
  je     L12
  jmp    L49
L16:
  lea    D14(%rip),%rax
  jmp    L36
L12:
  lea    D8(%rip),%rax
  jmp    L36
L49:
  mov    $0x0,%eax
L36:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: string

tool: D14: o0

tool: D8: o1

assistant: ```c
const char *pathcon_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pathcon_nm7_name_out>:
  endbr64
  lea    D2(%rip),%rax
  test   %edi,%edi
  je     L6
  cmp    $0x1,%edi
  lea    D8(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D2: o0

tool: D8: o1

assistant: ```c
const char *pathcon_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathcon_nm7_name_out>:
  endbr64
  lea    D9(%rip),%rax
  test   %edi,%edi
  je     L2
  cmp    $0x1,%edi
  lea    D18(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L2:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D9: o0

tool: D18: o1

assistant: ```c
const char *pathcon_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathcon_nm7_name_out>:
  endbr64
  lea    D4(%rip),%rax
  test   %edi,%edi
  je     L0
  cmp    $0x1,%edi
  lea    D1(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D1
type: string

tool: D4: o0

tool: D1: o1

assistant: ```c
const char *pathcon_nm7_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x58(%rbp),%rax
  sub    -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L20:
  addq   $0x8,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x50(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  movq   $0x1,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L19
L3:
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: allocation failure in convert_matrix()

assistant: ```c
float **convert_matrix(float *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure in convert_matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convert_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r12
  mov    %rdx,%r15
  sub    %rsi,%r15
  sub    %rcx,%r8
  lea    0x1(%r8),%rbp
  lea    0x10(,%r15,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L20:
  mov    $0x1,%eax
  sub    0x8(%rsp),%rax
  lea    (%rbx,%rax,8),%rcx
  shl    $0x2,%r12
  sub    %r12,%r13
  mov    %r13,0x8(%rbx)
  test   %r15,%r15
  jle    L38
  shl    $0x2,%rbp
  add    $0x8,%rbx
  lea    (%rcx,%r14,8),%rdx
L9:
  mov    %rbp,%rax
  add    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  add    $0x8,%rbx
  cmp    %rdx,%rbx
  jne    L9
L38:
  mov    %rcx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  lea    D4(%rip),%rdi
  call   <nrerror@plt>
  jmp    L20
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: allocation failure in convert_matrix()

assistant: ```c
float **convert_matrix(float *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure in convert_matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convert_matrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  mov    %rdx,%r15
  push   %r14
  lea    0x1(%r8),%rax
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    %rsi,%rbp
  lea    0x10(,%rbp,8),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
L38:
  mov    $0x1,%eax
  shl    $0x2,%r12
  sub    %r14,%rax
  sub    %r12,%r13
  mov    %r13,0x8(%rbx)
  lea    (%rbx,%rax,8),%r8
  test   %rbp,%rbp
  jle    L8
  mov    0x8(%rsp),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r15,8),%rsi
  shl    $0x2,%rcx
  nopw   0x0(%rax,%rax,1)
L27:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L27
L8:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  lea    D4(%rip),%rdi
  call   <nrerror@plt>
  jmp    L38
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: allocation failure in convert_matrix()

assistant: ```c
float **convert_matrix(float *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure in convert_matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_matrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  mov    %rdx,%r15
  push   %r14
  lea    0x1(%r8),%rax
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    %rsi,%r12
  mov    %rdi,%rbp
  push   %rbx
  lea    0x10(,%r12,8),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
L39:
  mov    $0x1,%eax
  shl    $0x2,%r13
  mov    %rbp,%rdx
  sub    %r14,%rax
  sub    %r13,%rdx
  mov    %rdx,0x8(%rbx)
  lea    (%rbx,%rax,8),%r8
  test   %r12,%r12
  jle    L25
  mov    0x8(%rsp),%rcx
  lea    0x8(%rbx),%rax
  lea    (%r8,%r15,8),%rsi
  shl    $0x2,%rcx
  nopl   (%rax)
L37:
  add    %rcx,%rdx
  add    $0x8,%rax
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L37
L25:
  add    $0x18,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L26:
  lea    D7(%rip),%rdi
  call   <nrerror@plt>
  jmp    L39
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: allocation failure in convert_matrix()

assistant: ```c
float **convert_matrix(float *a, long nrl, long nrh, long ncl, long nch) {
  long i, j, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure in convert_matrix()");
  m += 1;
  m -= nrl;
  m[nrl] = a - ncl;
  for (i = 1, j = nrl + 1; i < nrow; i++, j++)
    m[j] = m[j - 1] + ncol;
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qsort_helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x28(%rsp)
  mov    %edx,0x3c(%rsp)
  mov    %ecx,0x1c(%rsp)
  cmp    %edx,%esi
  jge    L71
  mov    %esi,%r15d
  mov    %ecx,%eax
  mov    %r8,%r12
  mov    %ecx,%r13d
  imul   %esi,%r13d
  movslq %r13d,%r13
  add    %rdi,%r13
  lea    -0x1(%rsi),%r14d
  lea    0x1(%rdx),%ebp
  movslq %ecx,%rcx
  mov    %rcx,0x30(%rsp)
  mov    %r13,0x10(%rsp)
  neg    %eax
  mov    %eax,0x38(%rsp)
  jmp    L66
L4:
  cmp    %ebp,%r14d
  jge    L3
  mov    0x1c(%rsp),%edx
  mov    0x8(%rsp),%rsi
  mov    0x20(%rsp),%rdi
  call   <swap@plt>
L79:
  mov    0x30(%rsp),%rcx
  add    %rcx,0x10(%rsp)
L66:
  add    $0x1,%r14d
  mov    0x10(%rsp),%rdi
  mov    %rdi,0x20(%rsp)
  mov    %r13,%rsi
  call   *%r12
  test   %eax,%eax
  jg     L38
  cmp    %r14d,0x3c(%rsp)
  jg     L79
L38:
  movslq 0x38(%rsp),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%rbp),%ebx
  imul   0x1c(%rsp),%ebx
  movslq %ebx,%rbx
  add    0x28(%rsp),%rbx
L47:
  mov    %ebp,0x18(%rsp)
  sub    $0x1,%ebp
  mov    %rbx,0x8(%rsp)
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   *%r12
  add    (%rsp),%rbx
  cmp    %ebp,%r15d
  jge    L4
  test   %eax,%eax
  jns    L47
  jmp    L4
L3:
  mov    0x1c(%rsp),%ebx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    0x8(%rsp),%rdi
  call   <swap@plt>
  mov    0x18(%rsp),%r14d
  lea    -0x2(%r14),%edx
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r15d,%esi
  mov    0x28(%rsp),%r15
  mov    %r15,%rdi
  call   <qsort_helper>
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    0x3c(%rsp),%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  call   <qsort_helper>
L71:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void qsort_helper(void *base, int l, int r, int elem_size, int (*cmpfn)(void *, void *)) {
  if (l < r) {
    void *target = (char *)base + l * elem_size;
    int i = l - 1, j = r + 1;
    while (1) {
      do {
        i++;
      } while (cmpfn((char *)base + i * elem_size, target) <= 0 && i < r);
      do {
        j--;
      } while (cmpfn((char *)base + j * elem_size, target) >= 0 && j > l);
      if (i < j)
        swap((char *)base + i * elem_size, (char *)base + j * elem_size, elem_size);
      else
        break;
    }
    swap((char *)base + j * elem_size, target, elem_size);
    qsort_helper(base, l, j - 1, elem_size, cmpfn);
    qsort_helper(base, j + 1, r, elem_size, cmpfn);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort_helper>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%eax
  push   %r14
  mov    %r8,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %ecx,0x24(%rsp)
  mov    %eax,0x3c(%rsp)
  movslq %ecx,%rax
  neg    %ecx
  mov    %rax,0x30(%rsp)
  movslq %ecx,%rax
  mov    %rdi,0x28(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x38(%rsp)
  mov    %rax,0x8(%rsp)
  cmp    %edx,%esi
  jge    L86
L30:
  mov    0x14(%rsp),%eax
  mov    0x24(%rsp),%ebp
  mov    0x3c(%rsp),%ebx
  imul   %eax,%ebp
  sub    $0x1,%eax
  mov    %eax,0x20(%rsp)
  movslq %ebp,%rbp
  add    0x28(%rsp),%rbp
  mov    %rbp,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L50:
  addl   $0x1,0x20(%rsp)
  mov    0x18(%rsp),%rdi
  mov    %rbp,%rsi
  mov    0x20(%rsp),%r15d
  call   *%r14
  cmp    %r15d,0x38(%rsp)
  jle    L65
  test   %eax,%eax
  jle    L96
L65:
  mov    0x24(%rsp),%edx
  lea    -0x1(%rbx),%r13d
  mov    0x28(%rsp),%rax
  imul   %r13d,%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,1),%r15
  mov    %r13d,%eax
  mov    %ebx,%r13d
  mov    %r15,%r12
  mov    %eax,%ebx
  jmp    L0
  nopl   (%rax)
L68:
  cmp    0x14(%rsp),%ebx
  jle    L26
  sub    $0x1,%ebx
L0:
  mov    %r13d,0x10(%rsp)
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %r12,%r15
  call   *%r14
  mov    %ebx,%r13d
  add    0x8(%rsp),%r12
  test   %eax,%eax
  jns    L68
L26:
  mov    %ebx,%eax
  mov    %r15,%r12
  mov    %r13d,%ebx
  cmp    %eax,0x20(%rsp)
  jge    L29
  mov    0x24(%rsp),%edx
  mov    0x18(%rsp),%rdi
  mov    %r15,%rsi
  call   <swap@plt>
L96:
  mov    0x30(%rsp),%rcx
  add    %rcx,0x18(%rsp)
  jmp    L50
  nopl   0x0(%rax)
L29:
  mov    0x24(%rsp),%r15d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %r15d,%edx
  call   <swap@plt>
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%esi
  mov    %r14,%r8
  mov    0x28(%rsp),%rdi
  mov    %r15d,%ecx
  lea    -0x2(%rbx),%edx
  call   <qsort_helper>
  cmp    0x38(%rsp),%ebx
  jge    L86
  mov    0x10(%rsp),%eax
  mov    %eax,0x14(%rsp)
  jmp    L30
L86:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void qsort_helper(void *base, int l, int r, int elem_size, int (*cmpfn)(void *, void *)) {
  if (l < r) {
    void *target = (char *)base + l * elem_size;
    int i = l - 1, j = r + 1;
    while (1) {
      do {
        i++;
      } while (cmpfn((char *)base + i * elem_size, target) <= 0 && i < r);
      do {
        j--;
      } while (cmpfn((char *)base + j * elem_size, target) >= 0 && j > l);
      if (i < j)
        swap((char *)base + i * elem_size, (char *)base + j * elem_size, elem_size);
      else
        break;
    }
    swap((char *)base + j * elem_size, target, elem_size);
    qsort_helper(base, l, j - 1, elem_size, cmpfn);
    qsort_helper(base, j + 1, r, elem_size, cmpfn);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qsort_helper>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%eax
  push   %r14
  mov    %r8,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %ecx,0x24(%rsp)
  mov    %eax,0x3c(%rsp)
  movslq %ecx,%rax
  neg    %ecx
  mov    %rax,0x30(%rsp)
  movslq %ecx,%rax
  mov    %rdi,0x28(%rsp)
  mov    %esi,0x14(%rsp)
  mov    %edx,0x38(%rsp)
  mov    %rax,0x8(%rsp)
  cmp    %edx,%esi
  jge    L27
L65:
  mov    0x14(%rsp),%eax
  mov    0x24(%rsp),%ebp
  mov    0x3c(%rsp),%ebx
  imul   %eax,%ebp
  sub    $0x1,%eax
  mov    %eax,0x20(%rsp)
  movslq %ebp,%rbp
  add    0x28(%rsp),%rbp
  mov    %rbp,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L43:
  addl   $0x1,0x20(%rsp)
  mov    0x18(%rsp),%rdi
  mov    %rbp,%rsi
  mov    0x20(%rsp),%r15d
  call   *%r14
  cmp    %r15d,0x38(%rsp)
  jle    L11
  test   %eax,%eax
  jle    L35
L11:
  mov    0x24(%rsp),%edx
  lea    -0x1(%rbx),%r13d
  mov    0x28(%rsp),%rax
  imul   %r13d,%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,1),%r15
  mov    %r13d,%eax
  mov    %ebx,%r13d
  mov    %r15,%r12
  mov    %eax,%ebx
  jmp    L76
  nopl   (%rax)
L61:
  cmp    0x14(%rsp),%ebx
  jle    L21
  sub    $0x1,%ebx
L76:
  mov    %r13d,0x10(%rsp)
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %r12,%r15
  call   *%r14
  mov    %ebx,%r13d
  add    0x8(%rsp),%r12
  test   %eax,%eax
  jns    L61
L21:
  mov    %ebx,%eax
  mov    %r15,%r12
  mov    %r13d,%ebx
  cmp    %eax,0x20(%rsp)
  jge    L36
  mov    0x24(%rsp),%edx
  mov    0x18(%rsp),%rdi
  mov    %r15,%rsi
  call   <swap@plt>
L35:
  mov    0x30(%rsp),%rcx
  add    %rcx,0x18(%rsp)
  jmp    L43
  nopl   0x0(%rax)
L36:
  mov    0x24(%rsp),%r15d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %r15d,%edx
  call   <swap@plt>
  mov    0x10(%rsp),%ebx
  mov    0x14(%rsp),%esi
  mov    %r14,%r8
  mov    0x28(%rsp),%rdi
  mov    %r15d,%ecx
  lea    -0x2(%rbx),%edx
  call   <qsort_helper>
  cmp    0x38(%rsp),%ebx
  jge    L27
  mov    0x10(%rsp),%eax
  mov    %eax,0x14(%rsp)
  jmp    L65
L27:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void qsort_helper(void *base, int l, int r, int elem_size, int (*cmpfn)(void *, void *)) {
  if (l < r) {
    void *target = (char *)base + l * elem_size;
    int i = l - 1, j = r + 1;
    while (1) {
      do {
        i++;
      } while (cmpfn((char *)base + i * elem_size, target) <= 0 && i < r);
      do {
        j--;
      } while (cmpfn((char *)base + j * elem_size, target) >= 0 && j > l);
      if (i < j)
        swap((char *)base + i * elem_size, (char *)base + j * elem_size, elem_size);
      else
        break;
    }
    swap((char *)base + j * elem_size, target, elem_size);
    qsort_helper(base, l, j - 1, elem_size, cmpfn);
    qsort_helper(base, j + 1, r, elem_size, cmpfn);
  }
}
```