user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x2c(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x63,-0x30(%rbp)
  movl   $0x3e7,-0x54(%rbp)
  jmp    L61
L36:
  movl   $0x3e7,-0x50(%rbp)
  jmp    L113
L124:
  mov    -0x54(%rbp),%eax
  imul   -0x50(%rbp),%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L31
L164:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x3c(%rbp)
  addl   $0x1,-0x48(%rbp)
L31:
  cmpl   $0x0,-0x3c(%rbp)
  jne    L164
  subl   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L109
L139:
  movl   $0x1,-0x40(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  jmp    L166
L42:
  mov    -0x40(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x40(%rbp)
  subl   $0x1,-0x44(%rbp)
L166:
  cmpl   $0x0,-0x44(%rbp)
  jg     L42
  mov    -0x4c(%rbp),%eax
  cltd
  idivl  -0x40(%rbp)
  mov    %eax,%edx
  mov    -0x48(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  imul   -0x40(%rbp),%eax
  sub    %eax,-0x4c(%rbp)
  subl   $0x1,-0x48(%rbp)
L109:
  cmpl   $0x0,-0x48(%rbp)
  jns    L139
  movl   $0x0,-0x38(%rbp)
  jmp    L149
L47:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  sub    -0x38(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L122
  addl   $0x1,-0x38(%rbp)
L149:
  mov    -0x24(%rbp),%eax
  sub    -0x38(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jle    L47
  jmp    L7
L122:
  nop
L7:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x38(%rbp)
  jle    L62
  addl   $0x1,-0x34(%rbp)
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L1
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L1:
  mov    -0x50(%rbp),%ecx
  mov    -0x54(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L62:
  subl   $0x1,-0x50(%rbp)
L113:
  mov    -0x50(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jg     L124
L37:
  subl   $0x1,-0x54(%rbp)
L61:
  cmpl   $0x63,-0x54(%rbp)
  jg     L36
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D16
type: string

tool: D10: %i = %i * %i


tool: D16: Biggest Palindrome: %i


assistant: ```c
int main(void) {
  int a, b, current_number, count, exponent, divider, placeholder_number, count2, count3, done, lower_limit;
  int printf_number, biggestNumber;
  int digits[6];
  biggestNumber = 1;
  done = 0;
  lower_limit = 99;
  for (a = 999; a > 99; a--) {
    for (b = 999; b > lower_limit; b--) {
      current_number = a * b;
      printf_number = current_number;
      placeholder_number = current_number;
      for (count = 0; placeholder_number != 0; count++)
        placeholder_number = placeholder_number / 10;
      count--;
      count2 = count;
      for (; count >= 0; count--) {
        divider = 1;
        for (exponent = count; exponent > 0; exponent--)
          divider = divider * 10;
        digits[count] = current_number / divider;
        current_number = current_number - divider * digits[count];
      }
      for (count3 = 0; count3 <= count2 - count3; count3++) {
        if (digits[count3] != digits[count2 - count3])
          break;
      }
      if (count3 > count2 / 2) {
        done++;
        lower_limit = b;
        if (biggestNumber < printf_number)
          biggestNumber = printf_number;
        printf("%i = %i * %i\n", printf_number, a, b);
        break;
      }
    }
  }
  printf("Biggest Palindrome: %i\n", biggestNumber);
  return 0;
}
```