ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ipaddr_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <inet_ntoa@plt>
  leave
  ret
```

assistant: ```c
const char *ipaddr_to_string(uint32_t addr) {
  struct in_addr in_addr;
  in_addr.s_addr = addr;
  return inet_ntoa(in_addr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipaddr_to_string>:
  endbr64
  sub    $0x8,%rsp
  call   <inet_ntoa@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
const char *ipaddr_to_string(uint32_t addr) {
  struct in_addr in_addr;
  in_addr.s_addr = addr;
  return inet_ntoa(in_addr);
}
```
user: What is the c source code of the assembly code below:

```asm
<ipaddr_to_string>:
  endbr64
  jmp    1050 <inet_ntoa@plt>
```

assistant: ```c
const char *ipaddr_to_string(uint32_t addr) {
  struct in_addr in_addr;
  in_addr.s_addr = addr;
  return inet_ntoa(in_addr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipaddr_to_string>:
  endbr64
  jmp    1050 <inet_ntoa@plt>
```

assistant: ```c
const char *ipaddr_to_string(uint32_t addr) {
  struct in_addr in_addr;
  in_addr.s_addr = addr;
  return inet_ntoa(in_addr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<asprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L19
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L19:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_vscprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L1
L16:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0xb8(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    %rax,%rdi
  call   <_vsnprintf@plt>
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xb4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xb4(%rbp),%eax
L1:
  leave
  ret
```

assistant: ```c
int asprintf(char **strp, const char *fmt, ...) {
  va_list ap;
  int len;
  va_start(ap, fmt);
  len = _vscprintf(fmt, ap);
  va_end(ap);
  *strp = malloc(len + 1);
  if (!*strp)
    return -1;
  va_start(ap, fmt);
  _vsnprintf(*strp, len + 1, fmt, ap);
  va_end(ap);
  (*strp)[len] = 0;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <_vscprintf@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <va_end@plt>
  lea    0x1(%r12),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L8
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    0x0(%r13),%rdi
  call   <_vsnprintf@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  movslq %r12d,%rax
  mov    0x0(%r13),%rdx
  movb   $0x0,(%rdx,%rax,1)
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0xffffffff,%r12d
  jmp    L15
```

assistant: ```c
int asprintf(char **strp, const char *fmt, ...) {
  va_list ap;
  int len;
  va_start(ap, fmt);
  len = _vscprintf(fmt, ap);
  va_end(ap);
  *strp = malloc(len + 1);
  if (!*strp)
    return -1;
  va_start(ap, fmt);
  _vsnprintf(*strp, len + 1, fmt, ap);
  va_end(ap);
  (*strp)[len] = 0;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_vscprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  lea    0x1(%r13),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L15
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    (%rbx),%rdi
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    %r14d,%esi
  call   <_vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%rbx),%rdx
  movslq %r13d,%rax
  movb   $0x0,(%rdx,%rax,1)
L11:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0xffffffff,%r13d
  jmp    L11
```

assistant: ```c
int asprintf(char **strp, const char *fmt, ...) {
  va_list ap;
  int len;
  va_start(ap, fmt);
  len = _vscprintf(fmt, ap);
  va_end(ap);
  *strp = malloc(len + 1);
  if (!*strp)
    return -1;
  va_start(ap, fmt);
  _vsnprintf(*strp, len + 1, fmt, ap);
  va_end(ap);
  (*strp)[len] = 0;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<asprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <_vscprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  lea    0x1(%r13),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L1
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    (%rbx),%rdi
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    %r14d,%esi
  call   <_vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    (%rbx),%rdx
  movslq %r13d,%rax
  movb   $0x0,(%rdx,%rax,1)
L2:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    $0xffffffff,%r13d
  jmp    L2
```

assistant: ```c
int asprintf(char **strp, const char *fmt, ...) {
  va_list ap;
  int len;
  va_start(ap, fmt);
  len = _vscprintf(fmt, ap);
  va_end(ap);
  *strp = malloc(len + 1);
  if (!*strp)
    return -1;
  va_start(ap, fmt);
  _vsnprintf(*strp, len + 1, fmt, ap);
  va_end(ap);
  (*strp)[len] = 0;
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<safe_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <remove_entry@plt>
  nop
  leave
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  free(ptr);
  remove_entry(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<safe_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <free@plt>
  mov    %rbx,%rdi
  call   <remove_entry@plt>
  pop    %rbx
  ret
```

assistant: ```c
void safe_free(void *ptr) {
  free(ptr);
  remove_entry(ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<safe_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <remove_entry@plt>
```

assistant: ```c
void safe_free(void *ptr) {
  free(ptr);
  remove_entry(ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<safe_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <remove_entry@plt>
```

assistant: ```c
void safe_free(void *ptr) {
  free(ptr);
  remove_entry(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x50,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L23:
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L27
L33:
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L33
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D31
type_infered: string
name: disassemble_data
arguments: data_tag: D49
type_infered: string

tool: D13: 


tool: D31: =

tool: D49: %s

assistant: ```c
void bar(char *s) {
  int i, len, n;
  len = strlen(s);
  n = (80 - len) / 2;
  ATKprintf("\n");
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("%s", s);
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <strlen@plt>
  mov    $0x50,%ebx
  sub    %eax,%ebx
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  cmp    $0x1,%ebx
  jle    L14
  mov    $0x0,%ebx
  lea    D18(%rip),%r12
L31:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jg     L31
  mov    %r13,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  mov    $0x0,%ebx
  lea    D18(%rip),%r12
L25:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jg     L25
L12:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    %r13,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <ATKprintf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D21
type: string

tool: D6: 


tool: D18: =

tool: D21: %s

assistant: ```c
void bar(char *s) {
  int i, len, n;
  len = strlen(s);
  n = (80 - len) / 2;
  ATKprintf("\n");
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("%s", s);
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bar>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x50,%ebx
  call   <strlen@plt>
  mov    %r13,%rdi
  sub    %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  call   <ATKprintf@plt>
  cmp    $0x1,%ebx
  jle    L13
  xor    %ebx,%ebx
  lea    D33(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <ATKprintf@plt>
  cmp    %ebx,%ebp
  jg     L23
  mov    %r14,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <ATKprintf@plt>
  nopl   0x0(%rax)
L1:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <ATKprintf@plt>
  cmp    %ebx,%ebp
  jg     L1
L7:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <ATKprintf@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r14,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <ATKprintf@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D33
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: string

tool: D21: 


tool: D33: =

tool: D18: %s

assistant: ```c
void bar(char *s) {
  int i, len, n;
  len = strlen(s);
  n = (80 - len) / 2;
  ATKprintf("\n");
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("%s", s);
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bar>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x50,%ebx
  call   <strlen@plt>
  mov    %r13,%rdi
  sub    %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  call   <ATKprintf@plt>
  cmp    $0x1,%ebx
  jle    L1
  xor    %ebx,%ebx
  lea    D32(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <ATKprintf@plt>
  cmp    %ebx,%ebp
  jg     L38
  mov    %r14,%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <ATKprintf@plt>
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <ATKprintf@plt>
  cmp    %ebx,%ebp
  jg     L12
L25:
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <ATKprintf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rsi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <ATKprintf@plt>
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string
name: extract_symbolic_data
arguments: label: D39
datatype: string

tool: D6: 


tool: D32: =

tool: D39: %s

assistant: ```c
void bar(char *s) {
  int i, len, n;
  len = strlen(s);
  n = (80 - len) / 2;
  ATKprintf("\n");
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("%s", s);
  for (i = 0; i < n; i++)
    ATKprintf("=");
  ATKprintf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<turn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L16:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x18(%rbp)
  jne    L16
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int turn(int base, int n) {
  int sum = 0;
  while (n != 0) {
    int rem = n % base;
    n = n / base;
    sum += rem;
  }
  return sum % base;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<turn>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    $0x0,%ecx
L19:
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  add    %edx,%ecx
  test   %eax,%eax
  jne    L19
L15:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  ret
L3:
  mov    %esi,%ecx
  jmp    L15
```

assistant: ```c
int turn(int base, int n) {
  int sum = 0;
  while (n != 0) {
    int rem = n % base;
    n = n / base;
    sum += rem;
  }
  return sum % base;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<turn>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L2
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L7:
  cltd
  idiv   %edi
  add    %edx,%ecx
  test   %eax,%eax
  jne    L7
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int turn(int base, int n) {
  int sum = 0;
  while (n != 0) {
    int rem = n % base;
    n = n / base;
    sum += rem;
  }
  return sum % base;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<turn>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L2
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L14:
  cltd
  idiv   %edi
  add    %edx,%ecx
  test   %eax,%eax
  jne    L14
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L2:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int turn(int base, int n) {
  int sum = 0;
  while (n != 0) {
    int rem = n % base;
    n = n / base;
    sum += rem;
  }
  return sum % base;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dbg_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1f0,%rsp
  mov    %rdi,-0x1e8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x1c0(%rbp)
  movq   $0x0,-0x1b8(%rbp)
  movq   $0x0,-0x1b0(%rbp)
  movq   $0x0,-0x1a8(%rbp)
  movq   $0x0,-0x1a0(%rbp)
  movq   $0x0,-0x198(%rbp)
  movq   $0x0,-0x190(%rbp)
  movq   $0x0,-0x188(%rbp)
  movq   $0x0,-0x180(%rbp)
  movq   $0x0,-0x178(%rbp)
  movq   $0x0,-0x170(%rbp)
  movq   $0x0,-0x168(%rbp)
  movq   $0x0,-0x160(%rbp)
  movq   $0x0,-0x158(%rbp)
  movq   $0x0,-0x150(%rbp)
  movq   $0x0,-0x148(%rbp)
  movq   $0x0,-0x140(%rbp)
  movq   $0x0,-0x138(%rbp)
  movq   $0x0,-0x130(%rbp)
  movq   $0x0,-0x128(%rbp)
  movq   $0x0,-0x120(%rbp)
  movq   $0x0,-0x118(%rbp)
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  mov    $0x0,%eax
  call   <get_logs_handler@plt>
  mov    %rax,-0x1c8(%rbp)
  mov    -0x1e8(%rbp),%rdx
  mov    -0x1d8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  lea    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <writeLogFileTimeStamp@plt>
  mov    %eax,-0x1d4(%rbp)
  mov    $0x100,%eax
  sub    -0x1d4(%rbp),%eax
  mov    -0x1d4(%rbp),%edx
  movslq %edx,%rdx
  lea    -0x1(%rdx),%rcx
  lea    -0x1c0(%rbp),%rdx
  lea    (%rdx,%rcx,1),%rdi
  mov    -0x1d8(%rbp),%ecx
  mov    -0x1e8(%rbp),%rdx
  mov    %eax,%esi
  call   <vsnprintf@plt>
  mov    %eax,-0x1d0(%rbp)
  mov    -0x1d8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x1c8(%rbp),%rcx
  mov    -0x1d0(%rbp),%edx
  lea    -0x1c0(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %eax,-0x1cc(%rbp)
  mov    -0x1c8(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  mov    -0x1cc(%rbp),%eax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int dbg_printf(const char *fmt, ...) {
  int i, iret;
  int len;
  char szPrint[256] = {0};
  FILE *fp = get_logs_handler();
  va_list ap;
  va_start(ap, fmt);
  len = writeLogFileTimeStamp(szPrint);
  iret = vsnprintf(szPrint + len - 1, 256 - len, fmt, ap);
  va_end(ap);
  i = fwrite(szPrint, 1, iret, fp);
  fflush(fp);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dbg_printf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  call   <get_logs_handler@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <writeLogFileTimeStamp@plt>
  mov    $0x100,%esi
  sub    %eax,%esi
  cltq
  lea    -0x1(%r12,%rax,1),%rdi
  mov    %r13d,%ecx
  mov    %rbp,%rdx
  call   <vsnprintf@plt>
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbx,%rcx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <fflush@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %ebp,%eax
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dbg_printf(const char *fmt, ...) {
  int i, iret;
  int len;
  char szPrint[256] = {0};
  FILE *fp = get_logs_handler();
  va_list ap;
  va_start(ap, fmt);
  len = writeLogFileTimeStamp(szPrint);
  iret = vsnprintf(szPrint + len - 1, 256 - len, fmt, ap);
  va_end(ap);
  i = fwrite(szPrint, 1, iret, fp);
  fflush(fp);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dbg_printf>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  call   <get_logs_handler@plt>
  mov    %r12,%rsi
  mov    %r14d,%edi
  mov    %rax,%rbp
  call   <va_start@plt>
  mov    %r13,%rdi
  call   <writeLogFileTimeStamp@plt>
  mov    $0x100,%esi
  mov    %r12,%rdx
  mov    %r14d,%ecx
  sub    %eax,%esi
  cltq
  lea    -0x1(%r13,%rax,1),%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %rbp,%rcx
  mov    $0x1,%esi
  call   <fwrite@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <fflush@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x118,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dbg_printf(const char *fmt, ...) {
  int i, iret;
  int len;
  char szPrint[256] = {0};
  FILE *fp = get_logs_handler();
  va_list ap;
  va_start(ap, fmt);
  len = writeLogFileTimeStamp(szPrint);
  iret = vsnprintf(szPrint + len - 1, 256 - len, fmt, ap);
  va_end(ap);
  i = fwrite(szPrint, 1, iret, fp);
  fflush(fp);
  return i;
}
```