ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<optk_get_extname>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %rdi,%rdi
  je     L23
  mov    %rdi,%r12
  mov    %edx,%ebp
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %rax,%r15
  test   %ebp,%ebp
  je     L12
  mov    %rax,%r13
  xor    %ebx,%ebx
  lea    D1(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L53:
  test   %r15,%r15
  je     L42
  sub    $0x1,%r15
  movsbl (%r12,%r15,1),%esi
  cmp    $0x2e,%sil
  jne    L78
  cmpl   $0x1,0x4(%rsp)
  mov    %r15,%rax
  adc    $0x0,%rax
  add    %r13,%rbx
  sub    %rax,%rbx
  sub    $0x1,%ebp
  je     L9
  mov    %rax,%r13
L78:
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L53
L42:
  mov    %r13,%r15
L12:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L57
  mov    %rbx,(%rax)
L57:
  lea    (%r12,%r15,1),%rax
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rax,%r15
  jmp    L12
L23:
  xor    %eax,%eax
  jmp    L55
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string

tool: D1: /

assistant: ```c
char *optk_get_extname(const char *path, int with_ext_separator, int num_ext, size_t *extname_len) {
  size_t pos, last_pos, len, i;
  if (path == NULL)
    return NULL;
  last_pos = strlen(path);
  len = 0;
  i = (num_ext == 0) ? 0 : last_pos;
  while (i > 0) {
    if (path[--i] == '.') {
      pos = i + (with_ext_separator ? 0 : 1);
      len += (last_pos - pos);
      last_pos = pos;
      if (--num_ext == 0)
        break;
    }
    if (strchr("/", path[i]) != NULL)
      break;
  }
  if (extname_len != NULL)
    *extname_len = len;
  return (char *)path + last_pos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<optk_get_extname>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %rdi,%rdi
  je     L45
  mov    %rdi,%r12
  mov    %edx,%ebp
  xor    %ebx,%ebx
  call   <strlen@plt>
  mov    %rax,%r15
  test   %ebp,%ebp
  je     L71
  mov    %rax,%r13
  xor    %ebx,%ebx
  lea    D9(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L25:
  test   %r15,%r15
  je     L9
  sub    $0x1,%r15
  movsbl (%r12,%r15,1),%esi
  cmp    $0x2e,%sil
  jne    L64
  cmpl   $0x1,0x4(%rsp)
  mov    %r15,%rax
  adc    $0x0,%rax
  add    %r13,%rbx
  sub    %rax,%rbx
  sub    $0x1,%ebp
  je     L79
  mov    %rax,%r13
L64:
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L25
L9:
  mov    %r13,%r15
L71:
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L70
  mov    %rbx,(%rax)
L70:
  lea    (%r12,%r15,1),%rax
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %rax,%r15
  jmp    L71
L45:
  xor    %eax,%eax
  jmp    L46
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: /

assistant: ```c
char *optk_get_extname(const char *path, int with_ext_separator, int num_ext, size_t *extname_len) {
  size_t pos, last_pos, len, i;
  if (path == NULL)
    return NULL;
  last_pos = strlen(path);
  len = 0;
  i = (num_ext == 0) ? 0 : last_pos;
  while (i > 0) {
    if (path[--i] == '.') {
      pos = i + (with_ext_separator ? 0 : 1);
      len += (last_pos - pos);
      last_pos = pos;
      if (--num_ext == 0)
        break;
    }
    if (strchr("/", path[i]) != NULL)
      break;
  }
  if (extname_len != NULL)
    *extname_len = len;
  return (char *)path + last_pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_bt_parse_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    $0xffffffff,%eax
  jmp    L19
L15:
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  mov    $0x0,%eax
  jmp    L19
L25:
  mov    $0xffffffff,%eax
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: OK

assistant: ```c
int _bt_parse_ok(char *buf) {
  char *ok;
  if (!buf)
    return -1;
  ok = strstr(buf, "OK");
  return ok ? 0 : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_bt_parse_ok>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: OK

assistant: ```c
int _bt_parse_ok(char *buf) {
  char *ok;
  if (!buf)
    return -1;
  ok = strstr(buf, "OK");
  return ok ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_bt_parse_ok>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: OK

assistant: ```c
int _bt_parse_ok(char *buf) {
  char *ok;
  if (!buf)
    return -1;
  ok = strstr(buf, "OK");
  return ok ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_bt_parse_ok>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  call   <strstr@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: OK

assistant: ```c
int _bt_parse_ok(char *buf) {
  char *ok;
  if (!buf)
    return -1;
  ok = strstr(buf, "OK");
  return ok ? 0 : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vmachineRefresh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <qdxRefresh@plt>
  mov    $0x0,%eax
  call   <vbiosRefresh@plt>
  mov    $0x0,%eax
  call   <vfddRefresh@plt>
  mov    $0x0,%eax
  call   <vhdcRefresh@plt>
  mov    $0x0,%eax
  call   <vhddRefresh@plt>
  mov    $0x0,%eax
  call   <vkbcRefresh@plt>
  mov    $0x0,%eax
  call   <vportRefresh@plt>
  mov    $0x0,%eax
  call   <vvadpRefresh@plt>
  mov    $0x0,%eax
  call   <vramRefresh@plt>
  mov    $0x0,%eax
  call   <vcmosRefresh@plt>
  mov    $0x0,%eax
  call   <vfdcRefresh@plt>
  mov    $0x0,%eax
  call   <vdmaRefresh@plt>
  mov    $0x0,%eax
  call   <vpicRefresh@plt>
  mov    $0x0,%eax
  call   <vpitRefresh@plt>
  mov    $0x0,%eax
  call   <vcpuRefresh@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vmachineRefresh() {
  qdxRefresh();

  vbiosRefresh();

  vfddRefresh();

  vhdcRefresh();

  vhddRefresh();

  vkbcRefresh();

  vportRefresh();

  vvadpRefresh();

  vramRefresh();

  vcmosRefresh();
  vfdcRefresh();
  vdmaRefresh();

  vpicRefresh();
  vpitRefresh();

  vcpuRefresh();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vmachineRefresh>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <qdxRefresh@plt>
  mov    $0x0,%eax
  call   <vbiosRefresh@plt>
  mov    $0x0,%eax
  call   <vfddRefresh@plt>
  mov    $0x0,%eax
  call   <vhdcRefresh@plt>
  mov    $0x0,%eax
  call   <vhddRefresh@plt>
  mov    $0x0,%eax
  call   <vkbcRefresh@plt>
  mov    $0x0,%eax
  call   <vportRefresh@plt>
  mov    $0x0,%eax
  call   <vvadpRefresh@plt>
  mov    $0x0,%eax
  call   <vramRefresh@plt>
  mov    $0x0,%eax
  call   <vcmosRefresh@plt>
  mov    $0x0,%eax
  call   <vfdcRefresh@plt>
  mov    $0x0,%eax
  call   <vdmaRefresh@plt>
  mov    $0x0,%eax
  call   <vpicRefresh@plt>
  mov    $0x0,%eax
  call   <vpitRefresh@plt>
  mov    $0x0,%eax
  call   <vcpuRefresh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void vmachineRefresh() {
  qdxRefresh();

  vbiosRefresh();

  vfddRefresh();

  vhdcRefresh();

  vhddRefresh();

  vkbcRefresh();

  vportRefresh();

  vvadpRefresh();

  vramRefresh();

  vcmosRefresh();
  vfdcRefresh();
  vdmaRefresh();

  vpicRefresh();
  vpitRefresh();

  vcpuRefresh();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vmachineRefresh>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <qdxRefresh@plt>
  xor    %eax,%eax
  call   <vbiosRefresh@plt>
  xor    %eax,%eax
  call   <vfddRefresh@plt>
  xor    %eax,%eax
  call   <vhdcRefresh@plt>
  xor    %eax,%eax
  call   <vhddRefresh@plt>
  xor    %eax,%eax
  call   <vkbcRefresh@plt>
  xor    %eax,%eax
  call   <vportRefresh@plt>
  xor    %eax,%eax
  call   <vvadpRefresh@plt>
  xor    %eax,%eax
  call   <vramRefresh@plt>
  xor    %eax,%eax
  call   <vcmosRefresh@plt>
  xor    %eax,%eax
  call   <vfdcRefresh@plt>
  xor    %eax,%eax
  call   <vdmaRefresh@plt>
  xor    %eax,%eax
  call   <vpicRefresh@plt>
  xor    %eax,%eax
  call   <vpitRefresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1140 <vcpuRefresh@plt>
```

assistant: ```c
void vmachineRefresh() {
  qdxRefresh();

  vbiosRefresh();

  vfddRefresh();

  vhdcRefresh();

  vhddRefresh();

  vkbcRefresh();

  vportRefresh();

  vvadpRefresh();

  vramRefresh();

  vcmosRefresh();
  vfdcRefresh();
  vdmaRefresh();

  vpicRefresh();
  vpitRefresh();

  vcpuRefresh();
}
```
user: Translate the below assembly code into C programming language:

```asm
<vmachineRefresh>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <qdxRefresh@plt>
  xor    %eax,%eax
  call   <vbiosRefresh@plt>
  xor    %eax,%eax
  call   <vfddRefresh@plt>
  xor    %eax,%eax
  call   <vhdcRefresh@plt>
  xor    %eax,%eax
  call   <vhddRefresh@plt>
  xor    %eax,%eax
  call   <vkbcRefresh@plt>
  xor    %eax,%eax
  call   <vportRefresh@plt>
  xor    %eax,%eax
  call   <vvadpRefresh@plt>
  xor    %eax,%eax
  call   <vramRefresh@plt>
  xor    %eax,%eax
  call   <vcmosRefresh@plt>
  xor    %eax,%eax
  call   <vfdcRefresh@plt>
  xor    %eax,%eax
  call   <vdmaRefresh@plt>
  xor    %eax,%eax
  call   <vpicRefresh@plt>
  xor    %eax,%eax
  call   <vpitRefresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1140 <vcpuRefresh@plt>
```

assistant: ```c
void vmachineRefresh() {
  qdxRefresh();

  vbiosRefresh();

  vfddRefresh();

  vhdcRefresh();

  vhddRefresh();

  vkbcRefresh();

  vportRefresh();

  vvadpRefresh();

  vramRefresh();

  vcmosRefresh();
  vfdcRefresh();
  vdmaRefresh();

  vpicRefresh();
  vpitRefresh();

  vcpuRefresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<git___compare_and_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L1
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *git___compare_and_swap(void *volatile *ptr, void *oldval, void *newval) {
  if (*ptr == oldval)
    *ptr = newval;
  else
    oldval = newval;
  return oldval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<git___compare_and_swap>:
  endbr64
  mov    %rdx,%rax
  mov    (%rdi),%rdx
  cmp    %rsi,%rdx
  je     L1
L11:
  ret
L1:
  mov    %rax,(%rdi)
  mov    %rsi,%rax
  jmp    L11
```

assistant: ```c
void *git___compare_and_swap(void *volatile *ptr, void *oldval, void *newval) {
  if (*ptr == oldval)
    *ptr = newval;
  else
    oldval = newval;
  return oldval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<git___compare_and_swap>:
  endbr64
  mov    %rdx,%rax
  mov    (%rdi),%rdx
  cmp    %rsi,%rdx
  je     L9
  ret
L9:
  mov    %rax,(%rdi)
  mov    %rdx,%rax
  ret
```

assistant: ```c
void *git___compare_and_swap(void *volatile *ptr, void *oldval, void *newval) {
  if (*ptr == oldval)
    *ptr = newval;
  else
    oldval = newval;
  return oldval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<git___compare_and_swap>:
  endbr64
  mov    %rdx,%rax
  mov    (%rdi),%rdx
  cmp    %rsi,%rdx
  je     L3
  ret
L3:
  mov    %rax,(%rdi)
  mov    %rdx,%rax
  ret
```

assistant: ```c
void *git___compare_and_swap(void *volatile *ptr, void *oldval, void *newval) {
  if (*ptr == oldval)
    *ptr = newval;
  else
    oldval = newval;
  return oldval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<doInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L15
  mov    $0x0,%eax
  call   <timerReset@plt>
  mov    $0x0,%eax
  call   <displayReset@plt>
  mov    $0x0,%eax
  call   <keyboardReset@plt>
  mov    $0x0,%eax
  call   <termReset@plt>
  mov    $0x0,%eax
  call   <diskReset@plt>
  mov    $0x0,%eax
  call   <outputReset@plt>
  mov    $0x0,%eax
  call   <shutdownReset@plt>
  mov    $0x0,%eax
  call   <graphReset@plt>
  mov    $0x0,%eax
  call   <memoryReset@plt>
  mov    $0x0,%eax
  call   <mmuReset@plt>
  mov    $0x0,%eax
  call   <cpuReset@plt>
  jmp    L14
L15:
  mov    $0x0,%eax
  call   <help15@plt>
L14:
  nop
  leave
  ret
```

assistant: ```c
void doInit(char *tokens[], int n) {
  if (n == 1) {
    timerReset();
    displayReset();
    keyboardReset();
    termReset();
    diskReset();
    outputReset();
    shutdownReset();
    graphReset();
    memoryReset();
    mmuReset();
    cpuReset();
  } else {
    help15();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<doInit>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L2
  mov    $0x0,%eax
  call   <help15@plt>
L9:
  add    $0x8,%rsp
  ret
L2:
  mov    $0x0,%eax
  call   <timerReset@plt>
  mov    $0x0,%eax
  call   <displayReset@plt>
  mov    $0x0,%eax
  call   <keyboardReset@plt>
  mov    $0x0,%eax
  call   <termReset@plt>
  mov    $0x0,%eax
  call   <diskReset@plt>
  mov    $0x0,%eax
  call   <outputReset@plt>
  mov    $0x0,%eax
  call   <shutdownReset@plt>
  mov    $0x0,%eax
  call   <graphReset@plt>
  mov    $0x0,%eax
  call   <memoryReset@plt>
  mov    $0x0,%eax
  call   <mmuReset@plt>
  mov    $0x0,%eax
  call   <cpuReset@plt>
  jmp    L9
```

assistant: ```c
void doInit(char *tokens[], int n) {
  if (n == 1) {
    timerReset();
    displayReset();
    keyboardReset();
    termReset();
    diskReset();
    outputReset();
    shutdownReset();
    graphReset();
    memoryReset();
    mmuReset();
    cpuReset();
  } else {
    help15();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<doInit>:
  endbr64
  cmp    $0x1,%esi
  je     L6
  xor    %eax,%eax
  jmp    1150 <help15@plt>
L6:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <timerReset@plt>
  xor    %eax,%eax
  call   <displayReset@plt>
  xor    %eax,%eax
  call   <keyboardReset@plt>
  xor    %eax,%eax
  call   <termReset@plt>
  xor    %eax,%eax
  call   <diskReset@plt>
  xor    %eax,%eax
  call   <outputReset@plt>
  xor    %eax,%eax
  call   <shutdownReset@plt>
  xor    %eax,%eax
  call   <graphReset@plt>
  xor    %eax,%eax
  call   <memoryReset@plt>
  xor    %eax,%eax
  call   <mmuReset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1120 <cpuReset@plt>
```

assistant: ```c
void doInit(char *tokens[], int n) {
  if (n == 1) {
    timerReset();
    displayReset();
    keyboardReset();
    termReset();
    diskReset();
    outputReset();
    shutdownReset();
    graphReset();
    memoryReset();
    mmuReset();
    cpuReset();
  } else {
    help15();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<doInit>:
  endbr64
  cmp    $0x1,%esi
  je     L6
  xor    %eax,%eax
  jmp    1150 <help15@plt>
L6:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <timerReset@plt>
  xor    %eax,%eax
  call   <displayReset@plt>
  xor    %eax,%eax
  call   <keyboardReset@plt>
  xor    %eax,%eax
  call   <termReset@plt>
  xor    %eax,%eax
  call   <diskReset@plt>
  xor    %eax,%eax
  call   <outputReset@plt>
  xor    %eax,%eax
  call   <shutdownReset@plt>
  xor    %eax,%eax
  call   <graphReset@plt>
  xor    %eax,%eax
  call   <memoryReset@plt>
  xor    %eax,%eax
  call   <mmuReset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1120 <cpuReset@plt>
```

assistant: ```c
void doInit(char *tokens[], int n) {
  if (n == 1) {
    timerReset();
    displayReset();
    keyboardReset();
    termReset();
    diskReset();
    outputReset();
    shutdownReset();
    graphReset();
    memoryReset();
    mmuReset();
    cpuReset();
  } else {
    help15();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x90(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x1,-0x88(%rbp)
  movl   $0x2,-0x84(%rbp)
  movl   $0x3,-0x80(%rbp)
  movl   $0x5,-0x7c(%rbp)
  movl   $0x8,-0x78(%rbp)
  movl   $0xd,-0x74(%rbp)
  movl   $0x15,-0x70(%rbp)
  movl   $0x22,-0x6c(%rbp)
  movl   $0xe9,-0x68(%rbp)
  movl   $0x12511,-0x64(%rbp)
  movl   $0x6197ecb,-0x60(%rbp)
  movl   $0x0,-0x50(%rbp)
  movl   $0x1,-0x4c(%rbp)
  movl   $0x2,-0x48(%rbp)
  movl   $0x3,-0x44(%rbp)
  movl   $0x4,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0x7,-0x34(%rbp)
  movl   $0x8,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0xd,-0x28(%rbp)
  movl   $0x19,-0x24(%rbp)
  movl   $0x28,-0x20(%rbp)
  movl   $0x0,-0x94(%rbp)
  jmp    L24
L14:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%ebx
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <nth_fibonacci_number@plt>
  cmp    %eax,%ebx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x94(%rbp)
L24:
  cmpl   $0xc,-0x94(%rbp)
  jle    L14
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  int fibonacci_numbers[13] = {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 233, 75025, 102334155};
  unsigned int fibonacci_number_positions[13] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 13, 25, 40};
  for (int i = 0; i < 13; i++) {
    assert(fibonacci_numbers[i] == nth_fibonacci_number(fibonacci_number_positions[i]));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0xd,0x1c(%rsp)
  movl   $0x15,0x20(%rsp)
  movl   $0x22,0x24(%rsp)
  movl   $0xe9,0x28(%rsp)
  movl   $0x12511,0x2c(%rsp)
  movl   $0x6197ecb,0x30(%rsp)
  movl   $0x0,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x2,0x48(%rsp)
  movl   $0x3,0x4c(%rsp)
  movl   $0x4,0x50(%rsp)
  movl   $0x5,0x54(%rsp)
  movl   $0x6,0x58(%rsp)
  movl   $0x7,0x5c(%rsp)
  movl   $0x8,0x60(%rsp)
  movl   $0x9,0x64(%rsp)
  movl   $0xd,0x68(%rsp)
  movl   $0x19,0x6c(%rsp)
  movl   $0x28,0x70(%rsp)
  mov    $0x0,%ebx
L9:
  mov    (%rsp,%rbx,1),%ebp
  mov    0x40(%rsp,%rbx,1),%edi
  call   <nth_fibonacci_number@plt>
  cmp    %eax,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  cmp    $0x34,%rbx
  jne    L9
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int fibonacci_numbers[13] = {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 233, 75025, 102334155};
  unsigned int fibonacci_number_positions[13] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 13, 25, 40};
  for (int i = 0; i < 13; i++) {
    assert(fibonacci_numbers[i] == nth_fibonacci_number(fibonacci_number_positions[i]));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x800000005,%rax
  mov    %rax,0x14(%rsp)
  movabs $0x150000000d,%rax
  mov    %rax,0x1c(%rsp)
  movabs $0xe900000022,%rax
  mov    %rax,0x24(%rsp)
  movabs $0x6197ecb00012511,%rax
  mov    %rax,0x2c(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x44(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x4c(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x54(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x5c(%rsp)
  movabs $0xd00000009,%rax
  mov    %rax,0x64(%rsp)
  movabs $0x2800000019,%rax
  mov    %rax,0x6c(%rsp)
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rsp,%rbx,1),%ebp
  mov    0x40(%rsp,%rbx,1),%edi
L5:
  call   <nth_fibonacci_number@plt>
  xor    %edi,%edi
  cmp    %ebp,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    $0x34,%rbx
  jne    L7
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int fibonacci_numbers[13] = {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 233, 75025, 102334155};
  unsigned int fibonacci_number_positions[13] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 13, 25, 40};
  for (int i = 0; i < 13; i++) {
    assert(fibonacci_numbers[i] == nth_fibonacci_number(fibonacci_number_positions[i]));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x88,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x6197ecb,0x30(%rsp)
  mov    %rsp,%r12
  lea    0x40(%rsp),%r13
  movaps %xmm0,(%rsp)
  movdqa D1(%rip),%xmm0
  movl   $0x28,0x70(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D47(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D20(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D24(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D16(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x0(%r13,%rbx,1),%edi
  mov    (%r12,%rbx,1),%ebp
  call   <nth_fibonacci_number@plt>
  xor    %edi,%edi
  cmp    %eax,%ebp
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    $0x34,%rbx
  jne    L8
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D1
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D47
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D20
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D24
data_type: byte[16]
name: extract_symbolic_data
arguments: data_label: D16
data_type: byte[16]

tool: {"D17": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D1": [0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D47": [0x15,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0xe9,0x00,0x00,0x00,0x11,0x25,0x01,0x00]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D24": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D16": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x19,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int fibonacci_numbers[13] = {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 233, 75025, 102334155};
  unsigned int fibonacci_number_positions[13] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 13, 25, 40};
  for (int i = 0; i < 13; i++) {
    assert(fibonacci_numbers[i] == nth_fibonacci_number(fibonacci_number_positions[i]));
  }
  return 0;
}
```