user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x2,-0x34(%rbp)
  jne    L19
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L19:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L47
L90:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  je     L75
  cmpl   $0x2,-0x24(%rbp)
  jg     L115
  cmpl   $0x0,-0x24(%rbp)
  je     L112
  cmpl   $0x1,-0x24(%rbp)
  je     L125
  jmp    L115
L112:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Father@plt>
  jmp    L32
L125:
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Son@plt>
  jmp    L32
L75:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Daughter@plt>
  jmp    L32
L115:
  nop
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
L47:
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  test   %eax,%eax
  jne    L90
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D30
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D46
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string

tool: D28: We will schedule for %d times


tool: D0: Please input scheduling count:

tool: D30: %d

tool: D21: sched: father

tool: D46: sched: son

tool: D5: sched: daughter

assistant: ```c
int main(int argc, char *argv[]) {
  srand((unsigned)time(NULL));
  int plate[5] = {0};
  int count;
  if (argc == 2) {
    count = atoi(argv[1]);
    printf("We will schedule for %d times\n", count);
  } else {
    printf("Please input scheduling count:");
    scanf("%d", &count);
  }
  while (count--) {
    int person = rand() % 3;
    switch (person) {
    case 0:
      printf("sched: father\n");
      Father(plate);
      break;
    case 1:
      printf("sched: son\n");
      Son(plate);
      break;
    case 2:
      printf("sched: daughter\n");
      Daughter(plate);
      break;
    default:
      break;
    }
    printf("\n");
  }
}
```