ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<switcher>:
  endbr64
  cmp    $0x7,%rdi
  ja     L7
  lea    D8(%rip),%r8
  movslq (%r8,%rdi,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  mov    %rsi,%rdx
  xor    $0xf,%rdx
  lea    0x70(%rdx),%rsi
L7:
  mov    %rsi,(%rcx)
  ret
  nop
  add    %rdx,%rsi
  shl    $0x2,%rsi
  mov    %rsi,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
  mov    %rdi,%rsi
  mov    %rsi,(%rcx)
  ret
```

assistant: ```c
void switcher(long a, long b, long c, long *dest) {
  long val;
  switch (a) {
  case 5:
    c = b ^ 15;
  case 0:
    val = c + 112;
    break;
  case 2:
  case 7:
    val = (b + c) << 2;
    break;
  case 4:
    val = a;
    break;
  default:
    val = b;
  }
  *dest = val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<switcher>:
  endbr64
  cmp    $0x7,%rdi
  ja     L0
  lea    D9(%rip),%r8
  movslq (%r8,%rdi,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  mov    %rsi,%rdx
  xor    $0xf,%rdx
  lea    0x70(%rdx),%rsi
L0:
  mov    %rsi,(%rcx)
  ret
  nop
  add    %rdx,%rsi
  shl    $0x2,%rsi
  mov    %rsi,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
  mov    %rdi,%rsi
  mov    %rsi,(%rcx)
  ret
```

assistant: ```c
void switcher(long a, long b, long c, long *dest) {
  long val;
  switch (a) {
  case 5:
    c = b ^ 15;
  case 0:
    val = c + 112;
    break;
  case 2:
  case 7:
    val = (b + c) << 2;
    break;
  case 4:
    val = a;
    break;
  default:
    val = b;
  }
  *dest = val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mysort1_rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L55
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L14:
  nop
L9:
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L62
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x10(%rbp),%xmm0
  ja     L9
L62:
  nop
L28:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L28
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L32
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  jmp    L14
L32:
  nop
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x30(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <mysort1_rev>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mysort1_rev>
  jmp    L8
L55:
  nop
L8:
  leave
  ret
```

assistant: ```c
void mysort1_rev(int N, double *data1) {
  int i, j;
  double v, t1;
  if (N <= 1)
    return;
  v = data1[0];
  i = 0;
  j = N;
  for (;;) {
    while (++i < N ? data1[i] > v : 0) {
    }
    while (data1[--j] < v) {
    }
    if (i >= j)
      break;
    t1 = data1[i];
    data1[i] = data1[j];
    data1[j] = t1;
  }
  t1 = data1[i - 1];
  data1[i - 1] = data1[0];
  data1[0] = t1;
  mysort1_rev(i - 1, data1);
  mysort1_rev(N - i, data1 + i);
}
```
user: What is the c source code of the assembly code below?

```asm
<mysort1_rev>:
  endbr64
  cmp    $0x1,%edi
  jle    L29
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  movsd  (%rsi),%xmm1
  lea    0x8(%rsi),%rsi
  mov    %edi,%edx
  mov    $0x0,%edi
  jmp    L25
L10:
  movslq %edx,%rax
  lea    -0x8(%r12,%rax,8),%rax
L28:
  sub    $0x1,%edx
  mov    %rax,%rcx
  sub    $0x8,%rax
  movsd  0x8(%rax),%xmm0
  comisd %xmm0,%xmm1
  ja     L28
  cmp    %edx,%ebx
  jge    L42
  movsd  (%rsi),%xmm2
  movsd  %xmm0,(%rsi)
  movsd  %xmm2,(%rcx)
L31:
  add    $0x8,%rsi
  mov    %ebx,%edi
L25:
  lea    0x1(%rdi),%ebx
  cmp    %ebx,%ebp
  jle    L10
  movsd  (%rsi),%xmm0
  comisd %xmm1,%xmm0
  ja     L31
  jmp    L10
L42:
  movslq %ebx,%r13
  shl    $0x3,%r13
  lea    -0x8(%r12,%r13,1),%rax
  movsd  (%rax),%xmm0
  movsd  (%r12),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%r12)
  mov    %r12,%rsi
  call   <mysort1_rev>
  lea    (%r12,%r13,1),%rsi
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <mysort1_rev>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  ret
```

assistant: ```c
void mysort1_rev(int N, double *data1) {
  int i, j;
  double v, t1;
  if (N <= 1)
    return;
  v = data1[0];
  i = 0;
  j = N;
  for (;;) {
    while (++i < N ? data1[i] > v : 0) {
    }
    while (data1[--j] < v) {
    }
    if (i >= j)
      break;
    t1 = data1[i];
    data1[i] = data1[j];
    data1[j] = t1;
  }
  t1 = data1[i - 1];
  data1[i - 1] = data1[0];
  data1[0] = t1;
  mysort1_rev(i - 1, data1);
  mysort1_rev(N - i, data1 + i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mysort1_rev>:
  endbr64
  cmp    $0x1,%edi
  jle    L52
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
L59:
  movsd  (%rsi),%xmm1
  lea    0x8(%rsi),%rbx
  mov    %r12d,%edx
  xor    %edi,%edi
  mov    $0x8,%r8d
  nopw   0x0(%rax,%rax,1)
L28:
  lea    0x1(%rdi),%ebp
  cmp    %r12d,%ebp
  jge    L66
  movsd  (%rbx),%xmm0
  comisd %xmm1,%xmm0
  ja     L56
L66:
  movslq %edx,%rax
  lea    -0x8(%rsi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %rax,%rcx
  movsd  (%rax),%xmm0
  sub    $0x8,%rax
  sub    $0x1,%edx
  comisd %xmm0,%xmm1
  ja     L55
  cmp    %edx,%ebp
  jge    L32
  movsd  (%rbx),%xmm2
  movsd  %xmm0,(%rbx)
  movsd  %xmm2,(%rcx)
L56:
  add    $0x8,%rbx
  add    $0x8,%r8
  mov    %ebp,%edi
  jmp    L28
L32:
  lea    -0x8(%rsi,%r8,1),%rax
  movsd  (%rsi),%xmm1
  sub    %ebp,%r12d
  movsd  (%rax),%xmm0
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rsi)
  call   <mysort1_rev>
  cmp    $0x1,%r12d
  jle    L75
  mov    %rbx,%rsi
  jmp    L59
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  ret
```

assistant: ```c
void mysort1_rev(int N, double *data1) {
  int i, j;
  double v, t1;
  if (N <= 1)
    return;
  v = data1[0];
  i = 0;
  j = N;
  for (;;) {
    while (++i < N ? data1[i] > v : 0) {
    }
    while (data1[--j] < v) {
    }
    if (i >= j)
      break;
    t1 = data1[i];
    data1[i] = data1[j];
    data1[j] = t1;
  }
  t1 = data1[i - 1];
  data1[i - 1] = data1[0];
  data1[0] = t1;
  mysort1_rev(i - 1, data1);
  mysort1_rev(N - i, data1 + i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mysort1_rev>:
  endbr64
  cmp    $0x1,%edi
  jle    L45
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
L70:
  movsd  (%rsi),%xmm1
  lea    0x8(%rsi),%rbx
  mov    %r12d,%edx
  xor    %edi,%edi
  mov    $0x8,%r8d
  nopw   0x0(%rax,%rax,1)
L39:
  lea    0x1(%rdi),%ebp
  cmp    %r12d,%ebp
  jge    L35
  movsd  (%rbx),%xmm0
  comisd %xmm1,%xmm0
  ja     L67
L35:
  movslq %edx,%rax
  lea    -0x8(%rsi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L72:
  mov    %rax,%rcx
  movsd  (%rax),%xmm0
  sub    $0x8,%rax
  sub    $0x1,%edx
  comisd %xmm0,%xmm1
  ja     L72
  cmp    %edx,%ebp
  jge    L4
  movsd  (%rbx),%xmm2
  movsd  %xmm0,(%rbx)
  movsd  %xmm2,(%rcx)
L67:
  add    $0x8,%rbx
  add    $0x8,%r8
  mov    %ebp,%edi
  jmp    L39
L4:
  lea    -0x8(%rsi,%r8,1),%rax
  movsd  (%rsi),%xmm1
  sub    %ebp,%r12d
  movsd  (%rax),%xmm0
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rsi)
  call   <mysort1_rev>
  cmp    $0x1,%r12d
  jle    L59
  mov    %rbx,%rsi
  jmp    L70
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  ret
```

assistant: ```c
void mysort1_rev(int N, double *data1) {
  int i, j;
  double v, t1;
  if (N <= 1)
    return;
  v = data1[0];
  i = 0;
  j = N;
  for (;;) {
    while (++i < N ? data1[i] > v : 0) {
    }
    while (data1[--j] < v) {
    }
    if (i >= j)
      break;
    t1 = data1[i];
    data1[i] = data1[j];
    data1[j] = t1;
  }
  t1 = data1[i - 1];
  data1[i - 1] = data1[0];
  data1[0] = t1;
  mysort1_rev(i - 1, data1);
  mysort1_rev(N - i, data1 + i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_plural_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <extract_plural_expression@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
unsigned long int get_plural_count(const char *header) {
  const struct expression *plural;
  unsigned long int nplurals;
  extract_plural_expression(header, &plural, &nplurals);
  return nplurals;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_plural_count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <extract_plural_expression@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long int get_plural_count(const char *header) {
  const struct expression *plural;
  unsigned long int nplurals;
  extract_plural_expression(header, &plural, &nplurals);
  return nplurals;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_plural_count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <extract_plural_expression@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long int get_plural_count(const char *header) {
  const struct expression *plural;
  unsigned long int nplurals;
  extract_plural_expression(header, &plural, &nplurals);
  return nplurals;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_plural_count>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <extract_plural_expression@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long int get_plural_count(const char *header) {
  const struct expression *plural;
  unsigned long int nplurals;
  extract_plural_expression(header, &plural, &nplurals);
  return nplurals;
}
```
user: Translate the below assembly code into C programming language:

```asm
<checked_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int checked_open(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    perror(pathname);
    exit(EXIT_FAILURE);
  }
  return fd;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checked_open>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L5
L9:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L9
```

assistant: ```c
int checked_open(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    perror(pathname);
    exit(EXIT_FAILURE);
  }
  return fd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checked_open>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int checked_open(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    perror(pathname);
    exit(EXIT_FAILURE);
  }
  return fd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checked_open>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <open@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L2
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int checked_open(const char *pathname, int flags) {
  int fd = open(pathname, flags);
  if (fd < 0) {
    perror(pathname);
    exit(EXIT_FAILURE);
  }
  return fd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mlist_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mlist_length(void **p) {
  int n;
  for (n = 0; p; p = *p, n++)
    ;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mlist_length>:
  endbr64
  test   %rdi,%rdi
  je     L6
  mov    $0x0,%eax
L14:
  mov    (%rdi),%rdi
  add    $0x1,%eax
  test   %rdi,%rdi
  jne    L14
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int mlist_length(void **p) {
  int n;
  for (n = 0; p; p = *p, n++)
    ;
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mlist_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%rdi),%rdi
  add    $0x1,%eax
  test   %rdi,%rdi
  jne    L10
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
int mlist_length(void **p) {
  int n;
  for (n = 0; p; p = *p, n++)
    ;
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<mlist_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L6
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rdi),%rdi
  add    $0x1,%eax
  test   %rdi,%rdi
  jne    L0
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
int mlist_length(void **p) {
  int n;
  for (n = 0; p; p = *p, n++)
    ;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_get_both_parts>:
  endbr64
  push   %r15
  mov    $0x4,%esi
  push   %r14
  push   %r13
  lea    D68(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x98,%rsp
  movapd D46(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x20(%rsp),%rdi
  movaps %xmm0,0x20(%rsp)
  lea    0x40(%rsp),%r15
  lea    0x60(%rsp),%r14
  movapd D35(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd D8(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movapd D37(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movapd D11(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movapd D67(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  call   <get_both_parts@plt>
  mov    %rax,%rbp
L16:
  movsd  (%r15,%rbx,1),%xmm2
  movsd  0x0(%rbp,%rbx,1),%xmm0
  mov    %r13,%rdi
  movapd %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  movsd  (%r14,%rbx,1),%xmm1
  mov    %r13,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm2
  xor    %edi,%edi
  ucomisd 0x0(%rbp,%rbx,1),%xmm2
  setnp  %dil
  cmovne %r12d,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  movsd  (%rsp),%xmm1
  xor    %edi,%edi
  ucomisd (%rax,%rbx,1),%xmm1
  setnp  %dil
  cmovne %r12d,%edi
  add    $0x8,%rbx
  call   <assert@plt>
  cmp    $0x20,%rbx
  jne    L16
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D68
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: f64[2]
name: extract_symbolic_data
arguments: data_tag: D35
type_infered: f64[2]
name: extract_symbolic_data
arguments: data_tag: D8
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: f64[2]
name: extract_symbolic_data
arguments: data_tag: D67
type_infered: f64[2]

tool: D68: %.18lf  %.18lf


tool: {"D46": [1.2,2.718]}

tool: {"D35": [3.14159,5.6]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D11": [0.2,0.718]}

tool: {"D67": [0.14159,0.6]}

assistant: ```c
void test_get_both_parts() {
  double array[] = {1.2, 2.718, 3.14159, 5.6};
  double expected_int[] = {1, 2, 3, 5};
  double expected_frac[] = {0.2, 0.718, 0.14159, 0.6};
  double *frac_part;
  int length = sizeof(array) / sizeof(double);
  double *int_part = get_both_parts(array, length, &frac_part);
  for (int i = 0; i < length; i++) {
    printf("%.18lf  %.18lf\n", int_part[i], expected_int[i]);
    printf("%.18lf  %.18lf\n", frac_part[i], expected_frac[i]);
    assert(int_part[i] == expected_int[i]);
    assert(frac_part[i] == expected_frac[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memory_error_and_abort@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: xmalloc

assistant: ```c
void *xmalloc(bytes)
int bytes;
{
  void *temp = malloc(bytes);
  if (!temp)
    memory_error_and_abort("xmalloc");
  return (temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmalloc>:
  endbr64
  push   %rbx
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L19
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L19:
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <memory_error_and_abort@plt>
  jmp    L12
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: xmalloc

assistant: ```c
void *xmalloc(bytes)
int bytes;
{
  void *temp = malloc(bytes);
  if (!temp)
    memory_error_and_abort("xmalloc");
  return (temp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xmalloc>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L1:
  mov    %r12,%rax
  pop    %r12
  ret
L14:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <memory_error_and_abort@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: xmalloc

assistant: ```c
void *xmalloc(bytes)
int bytes;
{
  void *temp = malloc(bytes);
  if (!temp)
    memory_error_and_abort("xmalloc");
  return (temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmalloc>:
  endbr64
  push   %r12
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
L0:
  mov    %r12,%rax
  pop    %r12
  ret
L3:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <memory_error_and_abort@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: xmalloc

assistant: ```c
void *xmalloc(bytes)
int bytes;
{
  void *temp = malloc(bytes);
  if (!temp)
    memory_error_and_abort("xmalloc");
  return (temp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L13:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jle    L21
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L21:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int f2(char *x, char p) {
  char *q = x;
  while (*q < p && *q != '\0') {
    q++;
  }
  return q - x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f2>:
  endbr64
  mov    %esi,%ecx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  cmp    %sil,%al
  jge    L12
  mov    %rdi,%rax
L31:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L0
  cmp    %cl,%dl
  jl     L31
L0:
  sub    %edi,%eax
  ret
L12:
  mov    %rdi,%rax
  jmp    L0
```

assistant: ```c
int f2(char *x, char p) {
  char *q = x;
  while (*q < p && *q != '\0') {
    q++;
  }
  return q - x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f2>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%ecx
  test   %al,%al
  je     L43
  cmp    %sil,%al
  jge    L43
  mov    %rdi,%rax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L17:
  cmp    %cl,%dl
  jge    L39
L21:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L17
L39:
  sub    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
int f2(char *x, char p) {
  char *q = x;
  while (*q < p && *q != '\0') {
    q++;
  }
  return q - x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%ecx
  test   %al,%al
  je     L41
  cmp    %sil,%al
  jge    L41
  mov    %rdi,%rax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    %cl,%dl
  jge    L23
L49:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L11
L23:
  sub    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
  ret
```

assistant: ```c
int f2(char *x, char p) {
  char *q = x;
  while (*q < p && *q != '\0') {
    q++;
  }
  return q - x;
}
```