ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<volume_id_encode_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rdx,%r15
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L110
  mov    %rsi,%r14
  test   %rdi,%rdi
  je     L110
  movb   $0x0,(%rsi)
  cmpb   $0x0,(%rdi)
  je     L56
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L41
L91:
  lea    (%r14,%r12,1),%rdi
  mov    %eax,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  movslq %ebx,%rax
  add    %rax,%r12
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  add    %rbx,%r13
L5:
  lea    0x3(%r12),%rax
  cmp    %r15,%rax
  jae    L39
  add    $0x1,%r13
  mov    0x8(%rsp),%rax
  lea    (%rax,%r13,1),%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L25
L41:
  mov    %rbp,%rdi
  call   <volume_id_utf8_encoded_valid_unichar@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jg     L91
  movzbl 0x0(%rbp),%edi
  cmp    $0x5c,%dil
  je     L52
  movsbl %dil,%edi
  call   <needs_encoding@plt>
  test   %rax,%rax
  je     L122
L52:
  movzbl 0x0(%rbp),%edx
  lea    (%r14,%r12,1),%rdi
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  add    $0x4,%r12
  jmp    L5
L122:
  movzbl 0x0(%rbp),%eax
  mov    %al,(%r14,%r12,1)
  add    $0x1,%r12
  jmp    L5
L56:
  mov    $0x0,%r12d
L25:
  movb   $0x0,(%r14,%r12,1)
  mov    $0x1,%eax
  jmp    L31
L110:
  mov    $0x0,%eax
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    $0x0,%eax
  jmp    L31
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: \x%02x

assistant: ```c
int volume_id_encode_string(const char *str, char *str_enc, size_t len) {
  size_t i, j;
  if (str == NULL || str_enc == NULL || len == 0)
    return 0;
  str_enc[0] = '\0';
  for (i = 0, j = 0; str[i] != '\0'; i++) {
    int seqlen;
    seqlen = volume_id_utf8_encoded_valid_unichar(&str[i]);
    if (seqlen > 1) {
      memcpy(&str_enc[j], &str[i], seqlen);
      j += seqlen;
      i += (seqlen - 1);
    } else if (str[i] == '\\' || needs_encoding(str[i])) {
      sprintf(&str_enc[j], "\\x%02x", (unsigned char)str[i]);
      j += 4;
    } else {
      str_enc[j] = str[i];
      j++;
    }
    if (j + 3 >= len)
      goto err;
  }
  str_enc[j] = '\0';
  return 1;
err:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<volume_id_encode_string>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L23
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L23
  movb   $0x0,(%rsi)
  cmpb   $0x0,(%rdi)
  mov    %rsi,%r12
  je     L11
  mov    %rdi,%r15
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L103
  nopl   (%rax)
L61:
  movzbl (%r15),%edx
  cmp    $0x5c,%dl
  je     L100
  movsbl %dl,%edi
  mov    %r8,0x8(%rsp)
  call   <needs_encoding@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  je     L26
  movzbl (%r15),%edx
L100:
  movzbl %dl,%edx
  lea    D4(%rip),%rsi
  mov    %r8,%rdi
  add    $0x4,%rbx
  call   <sprintf@plt>
L14:
  lea    0x3(%rbx),%rax
  cmp    %r14,%rax
  jae    L23
L97:
  add    $0x1,%rbp
  lea    0x0(%r13,%rbp,1),%r15
  cmpb   $0x0,(%r15)
  je     L36
L103:
  mov    %r15,%rdi
  call   <volume_id_utf8_encoded_valid_unichar@plt>
  lea    (%r12,%rbx,1),%r8
  mov    %eax,%edx
  cmp    $0x1,%eax
  jle    L61
  mov    %r15,%rsi
  mov    %r8,%rdi
  mov    %eax,0x8(%rsp)
  call   <memcpy@plt>
  movslq 0x8(%rsp),%rax
  mov    %rax,%rdx
  add    %rax,%rbx
  sub    $0x1,%edx
  lea    0x3(%rbx),%rax
  movslq %edx,%rdx
  add    %rdx,%rbp
  cmp    %r14,%rax
  jb     L97
L23:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  movzbl (%r15),%eax
  add    $0x1,%rbx
  mov    %al,(%r8)
  jmp    L14
  nopl   (%rax)
L36:
  add    %rbx,%r12
L11:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: \x%02x

assistant: ```c
int volume_id_encode_string(const char *str, char *str_enc, size_t len) {
  size_t i, j;
  if (str == NULL || str_enc == NULL || len == 0)
    return 0;
  str_enc[0] = '\0';
  for (i = 0, j = 0; str[i] != '\0'; i++) {
    int seqlen;
    seqlen = volume_id_utf8_encoded_valid_unichar(&str[i]);
    if (seqlen > 1) {
      memcpy(&str_enc[j], &str[i], seqlen);
      j += seqlen;
      i += (seqlen - 1);
    } else if (str[i] == '\\' || needs_encoding(str[i])) {
      sprintf(&str_enc[j], "\\x%02x", (unsigned char)str[i]);
      j += 4;
    } else {
      str_enc[j] = str[i];
      j++;
    }
    if (j + 3 >= len)
      goto err;
  }
  str_enc[j] = '\0';
  return 1;
err:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<volume_id_encode_string>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L109
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L109
  movb   $0x0,(%rsi)
  cmpb   $0x0,(%rdi)
  mov    %rsi,%r12
  je     L45
  mov    %rdi,%r15
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L37
  nopl   (%rax)
L102:
  movzbl (%r15),%edx
  cmp    $0x5c,%dl
  je     L62
  movsbl %dl,%edi
  mov    %r8,0x8(%rsp)
  call   <needs_encoding@plt>
  mov    0x8(%rsp),%r8
  test   %rax,%rax
  je     L30
  movzbl (%r15),%edx
L62:
  movzbl %dl,%edx
  lea    D4(%rip),%rsi
  mov    %r8,%rdi
  add    $0x4,%rbx
  call   <sprintf@plt>
L67:
  lea    0x3(%rbx),%rax
  cmp    %r14,%rax
  jae    L109
L29:
  add    $0x1,%rbp
  lea    0x0(%r13,%rbp,1),%r15
  cmpb   $0x0,(%r15)
  je     L4
L37:
  mov    %r15,%rdi
  call   <volume_id_utf8_encoded_valid_unichar@plt>
  lea    (%r12,%rbx,1),%r8
  mov    %eax,%edx
  cmp    $0x1,%eax
  jle    L102
  mov    %r15,%rsi
  mov    %r8,%rdi
  mov    %eax,0x8(%rsp)
  call   <memcpy@plt>
  movslq 0x8(%rsp),%rax
  mov    %rax,%rdx
  add    %rax,%rbx
  sub    $0x1,%edx
  lea    0x3(%rbx),%rax
  movslq %edx,%rdx
  add    %rdx,%rbp
  cmp    %r14,%rax
  jb     L29
L109:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  movzbl (%r15),%eax
  add    $0x1,%rbx
  mov    %al,(%r8)
  jmp    L67
  nopl   (%rax)
L4:
  add    %rbx,%r12
L45:
  movb   $0x0,(%r12)
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: \x%02x

assistant: ```c
int volume_id_encode_string(const char *str, char *str_enc, size_t len) {
  size_t i, j;
  if (str == NULL || str_enc == NULL || len == 0)
    return 0;
  str_enc[0] = '\0';
  for (i = 0, j = 0; str[i] != '\0'; i++) {
    int seqlen;
    seqlen = volume_id_utf8_encoded_valid_unichar(&str[i]);
    if (seqlen > 1) {
      memcpy(&str_enc[j], &str[i], seqlen);
      j += seqlen;
      i += (seqlen - 1);
    } else if (str[i] == '\\' || needs_encoding(str[i])) {
      sprintf(&str_enc[j], "\\x%02x", (unsigned char)str[i]);
      j += 4;
    } else {
      str_enc[j] = str[i];
      j++;
    }
    if (j + 3 >= len)
      goto err;
  }
  str_enc[j] = '\0';
  return 1;
err:
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L3
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int length = argc;
  int i;
  for (i = 1; i < length; i++) {
    printf("%s ", argv[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D1(%rip),%rbp
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    $0x0,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int length = argc;
  int i;
  for (i = 1; i < length; i++) {
    printf("%s ", argv[i]);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L2
  lea    -0x2(%rdi),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
L16:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int length = argc;
  int i;
  for (i = 1; i < length; i++) {
    printf("%s ", argv[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L6
  lea    -0x2(%rdi),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
L4:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: %s 

assistant: ```c
int main(int argc, char *argv[]) {
  int length = argc;
  int i;
  for (i = 1; i < length; i++) {
    printf("%s ", argv[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<extract_nbit_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  cmpl   $0x20,-0x3c(%rbp)
  jg     L64
  cmpl   $0x0,-0x3c(%rbp)
  jg     L15
L64:
  mov    $0xffffffff,%eax
  jmp    L71
L15:
  mov    -0x3c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L4
L70:
  mov    -0x2c(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x3c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    $0x8,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x28(%rbp)
  jmp    L38
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L28
  mov    -0x28(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  shrl   %cl,-0x20(%rbp)
  jmp    L24
L28:
  mov    -0x28(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x20(%rbp)
L24:
  mov    -0x20(%rbp),%eax
  add    %eax,-0x24(%rbp)
  addl   $0x8,-0x28(%rbp)
  subq   $0x1,-0x10(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L17
  mov    -0x24(%rbp),%eax
  and    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x2c(%rbp)
L4:
  mov    -0x2c(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L70
  mov    $0x0,%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
int extract_nbit_words(void *packed, int bits_per_value, int nitems, int *unpacked) {
  int right_shift;
  int left_shift;
  unsigned char *offset;
  unsigned char *ptr;
  int i;
  int byteshift;
  unsigned int val;
  unsigned int tval;
  unsigned int mask;
  if (bits_per_value > 32 || bits_per_value <= 0) {
    return -1;
  }
  mask = (1 << bits_per_value) - 1;
  for (i = 0; i < nitems; i++) {
    offset = packed + (i * bits_per_value / 8);
    ptr = packed + ((i + 1) * bits_per_value / 8);
    left_shift = (i + 1) * bits_per_value % 8;
    right_shift = 8 - left_shift;
    val = 0;
    byteshift = -right_shift;
    while (offset <= ptr) {
      tval = *ptr;
      if (byteshift < 0) {
        tval = tval >> (-byteshift);
      } else {
        tval = tval << byteshift;
      }
      val += tval;
      byteshift += 8;
      ptr--;
    }
    unpacked[i] = val & mask;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_nbit_words>:
  endbr64
  mov    %rcx,%rax
  lea    -0x1(%rsi),%ecx
  cmp    $0x1f,%ecx
  ja     L72
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %esi,%ebp
  mov    $0x1,%ebx
  mov    %esi,%ecx
  shl    %cl,%ebx
  sub    $0x1,%ebx
  test   %edx,%edx
  jle    L64
  mov    %rax,%r10
  lea    -0x1(%rdx),%edx
  lea    0x4(%rax,%rdx,4),%r12
  mov    $0x0,%r9d
  jmp    L73
L49:
  movzbl (%rsi),%eax
  mov    %edx,%ecx
  neg    %ecx
  mov    %eax,%r13d
  shr    %cl,%r13d
  mov    %edx,%ecx
  shl    %cl,%eax
  test   %edx,%edx
  cmovs  %r13d,%eax
  add    %eax,%edi
  add    $0x8,%edx
  sub    $0x1,%rsi
  cmp    %rsi,%r8
  jne    L49
L37:
  and    %ebx,%edi
  mov    %edi,(%r10)
  add    $0x4,%r10
  cmp    %r12,%r10
  je     L74
L73:
  lea    0x7(%r9),%r8d
  test   %r9d,%r9d
  cmovns %r9d,%r8d
  sar    $0x3,%r8d
  movslq %r8d,%r8
  add    %r11,%r8
  add    %ebp,%r9d
  lea    0x7(%r9),%esi
  cmovns %r9d,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  add    %r11,%rsi
  mov    %r9d,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%r9,%rax,1),%edx
  and    $0x7,%edx
  sub    %eax,%edx
  sub    $0x8,%edx
  cmp    %rsi,%r8
  ja     L6
  sub    $0x1,%r8
  mov    $0x0,%edi
  jmp    L49
L6:
  mov    $0x0,%edi
  jmp    L37
L74:
  mov    $0x0,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  mov    $0xffffffff,%eax
  ret
L64:
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
int extract_nbit_words(void *packed, int bits_per_value, int nitems, int *unpacked) {
  int right_shift;
  int left_shift;
  unsigned char *offset;
  unsigned char *ptr;
  int i;
  int byteshift;
  unsigned int val;
  unsigned int tval;
  unsigned int mask;
  if (bits_per_value > 32 || bits_per_value <= 0) {
    return -1;
  }
  mask = (1 << bits_per_value) - 1;
  for (i = 0; i < nitems; i++) {
    offset = packed + (i * bits_per_value / 8);
    ptr = packed + ((i + 1) * bits_per_value / 8);
    left_shift = (i + 1) * bits_per_value % 8;
    right_shift = 8 - left_shift;
    val = 0;
    byteshift = -right_shift;
    while (offset <= ptr) {
      tval = *ptr;
      if (byteshift < 0) {
        tval = tval >> (-byteshift);
      } else {
        tval = tval << byteshift;
      }
      val += tval;
      byteshift += 8;
      ptr--;
    }
    unpacked[i] = val & mask;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<extract_nbit_words>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0x1f,%eax
  ja     L22
  push   %r13
  mov    %rcx,%r10
  mov    %esi,%ecx
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  shl    %cl,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebp
  test   %edx,%edx
  jle    L20
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r11
  xor    %r9d,%r9d
  lea    0x4(%r10,%rax,4),%r12
  nopl   0x0(%rax)
L25:
  mov    %r9d,%r13d
  add    %ebx,%r9d
  mov    %r9d,%esi
  sar    $0x3,%r13d
  mov    %r9d,%edx
  sar    $0x3,%esi
  movslq %r13d,%r13
  or     $0xfffffff8,%edx
  movslq %esi,%rsi
  add    %r11,%r13
  add    %r11,%rsi
  cmp    %rsi,%r13
  ja     L26
  sub    $0x1,%r13
  xor    %edi,%edi
  nopl   (%rax)
L3:
  movzbl (%rsi),%eax
  mov    %edx,%ecx
  neg    %ecx
  mov    %eax,%r8d
  shr    %cl,%r8d
  mov    %edx,%ecx
  shl    %cl,%eax
  test   %edx,%edx
  cmovs  %r8d,%eax
  sub    $0x1,%rsi
  add    $0x8,%edx
  add    %eax,%edi
  cmp    %r13,%rsi
  jne    L3
  and    %ebp,%edi
L39:
  mov    %edi,(%r10)
  add    $0x4,%r10
  cmp    %r10,%r12
  jne    L25
L20:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  xor    %edi,%edi
  jmp    L39
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int extract_nbit_words(void *packed, int bits_per_value, int nitems, int *unpacked) {
  int right_shift;
  int left_shift;
  unsigned char *offset;
  unsigned char *ptr;
  int i;
  int byteshift;
  unsigned int val;
  unsigned int tval;
  unsigned int mask;
  if (bits_per_value > 32 || bits_per_value <= 0) {
    return -1;
  }
  mask = (1 << bits_per_value) - 1;
  for (i = 0; i < nitems; i++) {
    offset = packed + (i * bits_per_value / 8);
    ptr = packed + ((i + 1) * bits_per_value / 8);
    left_shift = (i + 1) * bits_per_value % 8;
    right_shift = 8 - left_shift;
    val = 0;
    byteshift = -right_shift;
    while (offset <= ptr) {
      tval = *ptr;
      if (byteshift < 0) {
        tval = tval >> (-byteshift);
      } else {
        tval = tval << byteshift;
      }
      val += tval;
      byteshift += 8;
      ptr--;
    }
    unpacked[i] = val & mask;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extract_nbit_words>:
  endbr64
  lea    -0x1(%rsi),%eax
  cmp    $0x1f,%eax
  ja     L9
  push   %r12
  mov    %rcx,%r10
  mov    %esi,%ecx
  push   %rbp
  mov    $0x1,%ebp
  shl    %cl,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x1,%ebp
  test   %edx,%edx
  jle    L61
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r11
  xor    %r9d,%r9d
  lea    0x4(%r10,%rax,4),%r12
  nopl   0x0(%rax,%rax,1)
L86:
  mov    %r9d,%r8d
  add    %ebx,%r9d
  mov    %r9d,%eax
  sar    $0x3,%r8d
  mov    %r9d,%edx
  sar    $0x3,%eax
  movslq %r8d,%r8
  or     $0xfffffff8,%edx
  cltq
  add    %r11,%r8
  add    %r11,%rax
  cmp    %rax,%r8
  ja     L42
  sub    $0x1,%r8
  xor    %edi,%edi
  jmp    L17
  xchg   %ax,%ax
L44:
  mov    %edx,%ecx
  sub    $0x1,%rax
  add    $0x8,%edx
  shl    %cl,%esi
  add    %esi,%edi
  cmp    %r8,%rax
  je     L45
L17:
  movzbl (%rax),%esi
  test   %edx,%edx
  jns    L44
  mov    %edx,%ecx
  sub    $0x1,%rax
  add    $0x8,%edx
  neg    %ecx
  shr    %cl,%esi
  add    %esi,%edi
  cmp    %r8,%rax
  jne    L17
L45:
  and    %ebp,%edi
L3:
  mov    %edi,(%r10)
  add    $0x4,%r10
  cmp    %r12,%r10
  jne    L86
L61:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  xor    %edi,%edi
  jmp    L3
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int extract_nbit_words(void *packed, int bits_per_value, int nitems, int *unpacked) {
  int right_shift;
  int left_shift;
  unsigned char *offset;
  unsigned char *ptr;
  int i;
  int byteshift;
  unsigned int val;
  unsigned int tval;
  unsigned int mask;
  if (bits_per_value > 32 || bits_per_value <= 0) {
    return -1;
  }
  mask = (1 << bits_per_value) - 1;
  for (i = 0; i < nitems; i++) {
    offset = packed + (i * bits_per_value / 8);
    ptr = packed + ((i + 1) * bits_per_value / 8);
    left_shift = (i + 1) * bits_per_value % 8;
    right_shift = 8 - left_shift;
    val = 0;
    byteshift = -right_shift;
    while (offset <= ptr) {
      tval = *ptr;
      if (byteshift < 0) {
        tval = tval >> (-byteshift);
      } else {
        tval = tval << byteshift;
      }
      val += tval;
      byteshift += 8;
      ptr--;
    }
    unpacked[i] = val & mask;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x1,-0x4(%rbp)
  jle    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f1(int *x) {
  for (int j = 0; j < 2; ++j)
    x[j] += 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f1>:
  endbr64
  addl   $0x1,(%rdi)
  addl   $0x1,0x4(%rdi)
  ret
```

assistant: ```c
void f1(int *x) {
  for (int j = 0; j < 2; ++j)
    x[j] += 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f1>:
  endbr64
  addl   $0x1,(%rdi)
  addl   $0x1,0x4(%rdi)
  ret
```

assistant: ```c
void f1(int *x) {
  for (int j = 0; j < 2; ++j)
    x[j] += 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<f1>:
  endbr64
  movq   D9(%rip),%xmm1
  movq   (%rdi),%xmm0
  paddd  %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: byte[8]

tool: {"D9": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void f1(int *x) {
  for (int j = 0; j < 2; ++j)
    x[j] += 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<doubleToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  movsd  %xmm0,-0x88(%rbp)
  mov    %edi,-0x8c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x8c(%rbp)
  jne    L39
  movsd  -0x88(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%rdx
  lea    -0x70(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D28(%rip),%rdx
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  jmp    L28
L39:
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D22(%rip),%rdx
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
L28:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x78(%rbp)
  cmpq   $0x0,-0x78(%rbp)
  jne    L24
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L24:
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D22
type: string
name: retrieve_data
arguments: data_tag: D16
type: string

tool: D28: %ld

tool: D22: %f

tool: D16: Out of mem in numberToString

assistant: ```c
char *doubleToString(double number, int type) {
  char result_buffer[100];
  char *result_string;
  if (type == 2)
    snprintf(result_buffer, 100, "%ld", (long)number);
  else
    snprintf(result_buffer, 100, "%f", number);
  result_string = malloc(sizeof(char) * strlen(result_buffer) + 1);
  if (result_string == NULL) {
    printf("Out of mem in numberToString");
    exit(0);
  }
  strcpy(result_string, result_buffer);
  return result_string;
}
```