ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_VDBG_malloc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x40(%rsi),%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L0
  lea    -0x40(%rdi),%rbp
  mov    %rbp,%rdi
  call   <_ripremove@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <realloc@plt>
  mov    %rax,%rbp
L11:
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <_insert@plt>
  nopl   0x0(%rax)
L0:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memset@plt>
  jmp    L11
```

assistant: ```c
extern void *_VDBG_malloc(void *ptr, long bytes, char *file, long line) {
  bytes += 64;
  if (ptr) {
    ptr = (void *)(((char *)ptr) - 64);
    _ripremove(ptr);
    ptr = realloc(ptr, bytes);
  } else {
    ptr = malloc(bytes);
    memset(ptr, 0, bytes);
  }
  return _insert(ptr, bytes, file, line);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_VDBG_malloc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x40(%rsi),%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  lea    -0x40(%rdi),%rbp
  mov    %rbp,%rdi
  call   <_ripremove@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <realloc@plt>
  mov    %rax,%rbp
L7:
  add    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <_insert@plt>
  nopl   0x0(%rax)
L10:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <memset@plt>
  jmp    L7
```

assistant: ```c
extern void *_VDBG_malloc(void *ptr, long bytes, char *file, long line) {
  bytes += 64;
  if (ptr) {
    ptr = (void *)(((char *)ptr) - 64);
    _ripremove(ptr);
    ptr = realloc(ptr, bytes);
  } else {
    ptr = malloc(bytes);
    memset(ptr, 0, bytes);
  }
  return _insert(ptr, bytes, file, line);
}
```
user: What is the c source code of the assembly code below?

```asm
<skipspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L6
L13:
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skipspace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skipspace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
L12:
  add    $0x1,%rbx
L6:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *skipspace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipspace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r12
L7:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipspace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skipspace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%r12
L5:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skipspace(const char *s) {
  while (isspace(*s))
    ++s;
  return (char *)s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copyString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x14,-0x4(%rbp)
  jle    L4
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copyString(char *text, char *copiedText) {
  int check = 0;
  while (check <= 20) {
    copiedText[check] = text[check];
    check++;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copyString>:
  endbr64
  mov    $0x0,%eax
L8:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L8
  ret
```

assistant: ```c
void copyString(char *text, char *copiedText) {
  int check = 0;
  while (check <= 20) {
    copiedText[check] = text[check];
    check++;
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copyString>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L2
  ret
```

assistant: ```c
void copyString(char *text, char *copiedText) {
  int check = 0;
  while (check <= 20) {
    copiedText[check] = text[check];
    check++;
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copyString>:
  endbr64
  lea    0x1(%rdi),%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L19
  movdqu (%rdi),%xmm0
  movups %xmm0,(%rsi)
  movzbl 0x10(%rdi),%eax
  mov    %al,0x10(%rsi)
  movzbl 0x11(%rdi),%eax
  mov    %al,0x11(%rsi)
  movzbl 0x12(%rdi),%eax
  mov    %al,0x12(%rsi)
  movzbl 0x13(%rdi),%eax
  mov    %al,0x13(%rsi)
  movzbl 0x14(%rdi),%eax
  mov    %al,0x14(%rsi)
  ret
L19:
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L1
  ret
```

assistant: ```c
void copyString(char *text, char *copiedText) {
  int check = 0;
  while (check <= 20) {
    copiedText[check] = text[check];
    check++;
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binbuf_read_via_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %rsi,-0x410(%rbp)
  mov    %rdx,-0x418(%rbp)
  mov    %ecx,-0x41c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f8(%rbp),%rcx
  lea    -0x3f0(%rbp),%rdx
  mov    -0x410(%rbp),%rsi
  mov    -0x418(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x3e8,%r9d
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D18(%rip),%rdx
  mov    %rax,%rdi
  call   <open_via_path@plt>
  add    $0x10,%rsp
  mov    %eax,-0x3fc(%rbp)
  cmpl   $0x0,-0x3fc(%rbp)
  jns    L13
  mov    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L19
L13:
  mov    -0x3fc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x3f8(%rbp),%rsi
  mov    -0x41c(%rbp),%ecx
  lea    -0x3f0(%rbp),%rdx
  mov    -0x408(%rbp),%rax
  mov    %rax,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  je     L20
  mov    $0x1,%eax
  jmp    L19
L20:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string

tool: 

tool: D14: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, const char *filename, const char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x400,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x3e8,%r9d
  lea    0x18(%rsp),%r8
  lea    D0(%rip),%rdx
  call   <open_via_path@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  js     L22
  mov    %eax,%edi
  call   <close@plt>
  lea    0x10(%rsp),%rdx
  mov    %r12d,%ecx
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L19:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x400,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L19
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string

tool: 

tool: D8: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, const char *filename, const char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r14
  mov    $0x3e8,%r9d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  lea    D4(%rip),%rdx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  sub    $0x8,%rsp
  push   $0x0
  mov    %r14,%rcx
  lea    0x18(%rsp),%r8
  call   <open_via_path@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L20
  mov    %eax,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L9:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x408,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L9
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: 

tool: D0: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, const char *filename, const char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<binbuf_read_via_path>:
  endbr64
  push   %r14
  mov    $0x3e8,%r9d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  lea    D8(%rip),%rdx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3f8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  sub    $0x8,%rsp
  push   $0x0
  mov    %r14,%rcx
  lea    0x18(%rsp),%r8
  call   <open_via_path@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L21
  mov    %eax,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <binbuf_read@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L1:
  mov    0x3f8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x408,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L21:
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L1
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: 

tool: D12: %s: can't open

assistant: ```c
int binbuf_read_via_path(struct _binbuf *b, const char *filename, const char *dirname, int crflag) {
  int filedesc;
  char buf[1000], *bufptr;
  if ((filedesc = open_via_path(dirname, filename, "", buf, &bufptr, 1000, 0)) < 0) {
    error("%s: can't open", filename);
    return (1);
  } else
    close(filedesc);
  if (binbuf_read(b, bufptr, buf, crflag))
    return (1);
  else
    return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chk_no_err_only>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movzwl (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xe,%rax
  movzwl (%rax),%eax
  or     %edx,%eax
  test   %ax,%ax
  je     L10
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L14
L10:
  mov    -0x10(%rbp),%rax
  movw   $0x0,(%rax)
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int chk_no_err_only(unsigned short *chk_syndrome_list, unsigned short *err_info) {
  if ((chk_syndrome_list[0] | chk_syndrome_list[1] | chk_syndrome_list[2] | chk_syndrome_list[3] | chk_syndrome_list[4] | chk_syndrome_list[5] | chk_syndrome_list[6] | chk_syndrome_list[7]) != 0x0) {
    return -EINVAL;
  } else {
    err_info[0] = 0x0;
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chk_no_err_only>:
  endbr64
  movzwl (%rdi),%eax
  or     0x2(%rdi),%ax
  or     0x4(%rdi),%ax
  or     0x6(%rdi),%ax
  or     0x8(%rdi),%ax
  or     0xa(%rdi),%ax
  or     0xc(%rdi),%ax
  or     0xe(%rdi),%ax
  je     L3
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
L3:
  movw   $0x0,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int chk_no_err_only(unsigned short *chk_syndrome_list, unsigned short *err_info) {
  if ((chk_syndrome_list[0] | chk_syndrome_list[1] | chk_syndrome_list[2] | chk_syndrome_list[3] | chk_syndrome_list[4] | chk_syndrome_list[5] | chk_syndrome_list[6] | chk_syndrome_list[7]) != 0x0) {
    return -EINVAL;
  } else {
    err_info[0] = 0x0;
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chk_no_err_only>:
  endbr64
  movzwl (%rdi),%eax
  or     0x2(%rdi),%ax
  or     0x4(%rdi),%ax
  or     0x6(%rdi),%ax
  or     0x8(%rdi),%ax
  or     0xa(%rdi),%ax
  or     0xc(%rdi),%ax
  or     0xe(%rdi),%ax
  je     L4
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  mov    %ax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int chk_no_err_only(unsigned short *chk_syndrome_list, unsigned short *err_info) {
  if ((chk_syndrome_list[0] | chk_syndrome_list[1] | chk_syndrome_list[2] | chk_syndrome_list[3] | chk_syndrome_list[4] | chk_syndrome_list[5] | chk_syndrome_list[6] | chk_syndrome_list[7]) != 0x0) {
    return -EINVAL;
  } else {
    err_info[0] = 0x0;
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<chk_no_err_only>:
  endbr64
  movzwl (%rdi),%eax
  or     0x2(%rdi),%ax
  or     0x4(%rdi),%ax
  or     0x6(%rdi),%ax
  or     0x8(%rdi),%ax
  or     0xa(%rdi),%ax
  or     0xc(%rdi),%ax
  or     0xe(%rdi),%ax
  je     L7
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  mov    %ax,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int chk_no_err_only(unsigned short *chk_syndrome_list, unsigned short *err_info) {
  if ((chk_syndrome_list[0] | chk_syndrome_list[1] | chk_syndrome_list[2] | chk_syndrome_list[3] | chk_syndrome_list[4] | chk_syndrome_list[5] | chk_syndrome_list[6] | chk_syndrome_list[7]) != 0x0) {
    return -EINVAL;
  } else {
    err_info[0] = 0x0;
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<addInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rcx,(%rdx)
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
int *addInt(int dataArray[], size_t *p_index, int data) {
  assert(p_index != NULL);
  dataArray[*p_index] = data;
  return dataArray + (*p_index)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<addInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%rax
  mov    %r12d,0x0(%rbp,%rax,4)
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  lea    0x0(%rbp,%rax,4),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *addInt(int dataArray[], size_t *p_index, int data) {
  assert(p_index != NULL);
  dataArray[*p_index] = data;
  return dataArray + (*p_index)++;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<addInt>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    (%rbx),%rax
  lea    (%r12,%rax,4),%r8
  add    $0x1,%rax
  mov    %ebp,(%r8)
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *addInt(int dataArray[], size_t *p_index, int data) {
  assert(p_index != NULL);
  dataArray[*p_index] = data;
  return dataArray + (*p_index)++;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addInt>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <assert@plt>
  mov    (%rbx),%rax
  lea    (%r12,%rax,4),%r8
  add    $0x1,%rax
  mov    %ebp,(%r8)
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *addInt(int dataArray[], size_t *p_index, int data) {
  assert(p_index != NULL);
  dataArray[*p_index] = data;
  return dataArray + (*p_index)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crackers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   $0x457,%eax,%ecx
  mov    -0x28(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L7
  cmpl   $0x1,-0x24(%rbp)
  jne    L23
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x2c(%rbp),%eax
  mov    -0x28(%rbp),%edx
  add    $0x1,%edx
  imul   -0x28(%rbp),%edx
  sub    %edx,%eax
  sar    %eax
  jmp    L54
L23:
  mov    -0x2c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jg     L19
  mov    $0x0,%eax
  jmp    L54
L19:
  movl   $0x7fffffff,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L34
L13:
  mov    -0x18(%rbp),%eax
  movslq %eax,%r12
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <crackers>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  mov    %rdx,%rcx
  mov    %esi,%edx
  mov    %eax,%esi
  call   <crackers>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <max@plt>
  lea    (%r12,%rax,1),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <min@plt>
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x2c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L13
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
L7:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
L54:
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int crackers(int m, int a, int b, int *memory) {
  int index = b * 1111 + a * 11 + m;
  if (memory[index] < 0) {
    if (m == 1)
      return (b * (b + 1) - a * (a + 1)) >> 1;
    if (b <= a)
      return 0;
    int least = 2147483647;
    for (int i = a + 1; i < b + 1; i++) {
      least = min(i + max(crackers(m - 1, a, i - 1, memory), crackers(m, i, b, memory)), least);
    }
    memory[index] = least;
  }
  return memory[index];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<crackers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  mov    %edx,%ebp
  imul   $0x457,%edx,%eax
  lea    (%rsi,%rsi,4),%edx
  lea    (%rsi,%rdx,2),%edx
  add    %edx,%eax
  add    %edi,%eax
  cltq
  lea    (%rcx,%rax,4),%r14
  cmpl   $0x0,(%r14)
  js     L64
L3:
  mov    (%r14),%eax
L43:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  mov    %esi,%ebx
  mov    %rcx,%r12
  cmp    $0x1,%edi
  je     L9
  mov    $0x0,%eax
  cmp    %esi,%ebp
  jle    L43
  lea    0x1(%rsi),%r13d
  movl   $0x7fffffff,(%rsp)
  cmp    %r13d,%ebp
  jl     L58
  movslq %r13d,%r15
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
L37:
  mov    %r12,%rcx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    0x4(%rsp),%edi
  call   <crackers>
  mov    %eax,0x8(%rsp)
  lea    -0x1(%r13),%edx
  mov    %r12,%rcx
  mov    %ebx,%esi
  mov    0xc(%rsp),%edi
  call   <crackers>
  mov    %eax,%edi
  mov    0x8(%rsp),%esi
  call   <max@plt>
  lea    (%r15,%rax,1),%rdi
  mov    (%rsp),%esi
  call   <min@plt>
  mov    %eax,(%rsp)
  add    $0x1,%r13d
  add    $0x1,%r15
  cmp    %r13d,%ebp
  jge    L37
L58:
  mov    (%rsp),%eax
  mov    %eax,(%r14)
  jmp    L3
L9:
  lea    0x1(%rbp),%eax
  imul   %ebp,%eax
  lea    0x1(%rsi),%edx
  imul   %esi,%edx
  sub    %edx,%eax
  sar    %eax
  jmp    L43
```

assistant: ```c
int crackers(int m, int a, int b, int *memory) {
  int index = b * 1111 + a * 11 + m;
  if (memory[index] < 0) {
    if (m == 1)
      return (b * (b + 1) - a * (a + 1)) >> 1;
    if (b <= a)
      return 0;
    int least = 2147483647;
    for (int i = a + 1; i < b + 1; i++) {
      least = min(i + max(crackers(m - 1, a, i - 1, memory), crackers(m, i, b, memory)), least);
    }
    memory[index] = least;
  }
  return memory[index];
}
```