ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<rob4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rdi
  cmpl   $0x0,-0x3c(%rbp)
  jg     L47
  mov    $0x0,%eax
  jmp    L16
L47:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L45:
  cmp    %rdx,%rsp
  je     L64
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L45
L64:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L61
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L61:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x1,-0x3c(%rbp)
  jle    L20
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,0x4(%rax)
L20:
  movl   $0x2,-0x2c(%rbp)
  jmp    L42
L38:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%esi
  mov    -0x2c(%rbp),%edx
  lea    -0x2(%rdx),%ecx
  mov    -0x20(%rbp),%rdx
  movslq %ecx,%rcx
  mov    (%rdx,%rcx,4),%edx
  add    %esi,%edx
  cmp    %edx,%eax
  mov    %edx,%ecx
  cmovge %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x2c(%rbp)
L42:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L38
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
L16:
  mov    %rdi,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rob4(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int dp[numsSize];
  dp[0] = nums[0];
  if (numsSize > 1)
    dp[1] = (dp[0]) > (nums[1]) ? (dp[0]) : (nums[1]);
  for (int i = 2; i < numsSize; i++) {
    dp[i] = (nums[i] + dp[i - 2]) > (dp[i - 1]) ? (nums[i] + dp[i - 2]) : (dp[i - 1]);
  }
  return dp[numsSize - 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rob4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L61
  mov    %rdi,%r8
  mov    %esi,%edi
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L43:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L41:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L50
  orq    $0x0,-0x8(%rsp,%rax,1)
L50:
  lea    0x3(%rsp),%rcx
  mov    %rcx,%rsi
  shr    $0x2,%rsi
  and    $0xfffffffffffffffc,%rcx
  mov    (%r8),%edx
  mov    %edx,0x0(,%rsi,4)
  cmp    $0x1,%edi
  jle    L26
  mov    0x4(%r8),%eax
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    %eax,0x4(,%rsi,4)
L26:
  cmp    $0x2,%edi
  jle    L66
  mov    %edi,%r9d
  mov    $0x2,%eax
L23:
  mov    -0x8(%rcx,%rax,4),%edx
  add    (%r8,%rax,4),%edx
  mov    -0x4(%rcx,%rax,4),%esi
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L23
L66:
  sub    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rcx,%rdi,4),%eax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  leave
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rob4(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int dp[numsSize];
  dp[0] = nums[0];
  if (numsSize > 1)
    dp[1] = (dp[0]) > (nums[1]) ? (dp[0]) : (nums[1]);
  for (int i = 2; i < numsSize; i++) {
    dp[i] = (nums[i] + dp[i - 2]) > (dp[i - 1]) ? (nums[i] + dp[i - 2]) : (dp[i - 1]);
  }
  return dp[numsSize - 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rob4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L45
  movslq %esi,%rax
  mov    %rsp,%rcx
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L30
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L8
L30:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L96
L6:
  lea    0x3(%rsp),%rsi
  mov    (%r8),%edx
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rsi
  shr    $0x2,%rax
  mov    %edx,0x0(,%rax,4)
  cmp    $0x1,%edi
  je     L36
  mov    0x4(%r8),%ecx
  cmp    %ecx,%edx
  cmovge %edx,%ecx
  mov    %ecx,0x4(,%rax,4)
  cmp    $0x2,%edi
  je     L36
  lea    -0x3(%rdi),%r9d
  xor    %eax,%eax
  shl    $0x2,%r9
  jmp    L5
  xchg   %ax,%ax
L59:
  mov    0x4(%rsi,%rax,1),%edx
  add    $0x4,%rax
L5:
  add    0x8(%r8,%rax,1),%edx
  cmp    %edx,%ecx
  cmovl  %edx,%ecx
  mov    %ecx,0x8(%rsi,%rax,1)
  cmp    %r9,%rax
  jne    L59
L36:
  sub    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rsi,%rdi,4),%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  leave
  ret
  nopl   (%rax)
L96:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rob4(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int dp[numsSize];
  dp[0] = nums[0];
  if (numsSize > 1)
    dp[1] = (dp[0]) > (nums[1]) ? (dp[0]) : (nums[1]);
  for (int i = 2; i < numsSize; i++) {
    dp[i] = (nums[i] + dp[i - 2]) > (dp[i - 1]) ? (nums[i] + dp[i - 2]) : (dp[i - 1]);
  }
  return dp[numsSize - 1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rob4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L104
  movslq %esi,%rax
  mov    %rsp,%rcx
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L110
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L10
L110:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L5:
  lea    0x3(%rsp),%rcx
  mov    (%r8),%esi
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rcx
  shr    $0x2,%rax
  mov    %esi,0x0(,%rax,4)
  cmp    $0x1,%edi
  je     L47
  mov    0x4(%r8),%edx
  cmp    %edx,%esi
  cmovge %esi,%edx
  mov    %edx,0x4(,%rax,4)
  cmp    $0x2,%edi
  je     L47
  cmp    $0x4,%edi
  jle    L95
  lea    -0x5(%rdi),%eax
  mov    $0x4,%r9d
  shr    %eax
  lea    0x3(%rax),%r10d
  add    %r10,%r10
L66:
  add    -0x8(%r8,%r9,4),%esi
  movslq %r9d,%rax
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    -0x4(%r8,%r9,4),%edx
  cmp    %esi,%edx
  movd   %esi,%xmm0
  cmovl  %esi,%edx
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x8(%rcx,%r9,4)
  add    $0x2,%r9
  cmp    %r9,%r10
  jne    L66
  nopl   0x0(%rax,%rax,1)
L51:
  mov    -0x4(%rcx,%rax,4),%esi
  mov    (%r8,%rax,4),%edx
  add    -0x8(%rcx,%rax,4),%edx
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L51
L47:
  sub    $0x1,%edi
  movslq %edi,%rdi
  mov    (%rcx,%rdi,4),%eax
L104:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  leave
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L95:
  mov    $0x2,%eax
  jmp    L51
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rob4(int *nums, int numsSize) {
  if (numsSize <= 0)
    return 0;
  int dp[numsSize];
  dp[0] = nums[0];
  if (numsSize > 1)
    dp[1] = (dp[0]) > (nums[1]) ? (dp[0]) : (nums[1]);
  for (int i = 2; i < numsSize; i++) {
    dp[i] = (nums[i] + dp[i - 2]) > (dp[i - 1]) ? (nums[i] + dp[i - 2]) : (dp[i - 1]);
  }
  return dp[numsSize - 1];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<al_sisnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    $0x0,%eax
  jmp    L40
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L7
  mov    $0x0,%eax
  jmp    L40
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    $0x1,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int al_sisnum(const char *str) {
  if (!*str)
    return 0;
  while (*str)
    if (!isdigit(*str++))
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<al_sisnum>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%edx
  test   %al,%al
  je     L7
L16:
  add    $0x1,%rdi
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L37
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L16
  mov    $0x1,%edx
L7:
  mov    %edx,%eax
  ret
L37:
  mov    $0x0,%edx
  jmp    L7
```

assistant: ```c
int al_sisnum(const char *str) {
  if (!*str)
    return 0;
  while (*str)
    if (!isdigit(*str++))
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<al_sisnum>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L29
  xchg   %ax,%ax
L7:
  sub    $0x30,%eax
  add    $0x1,%rdi
  cmp    $0x9,%eax
  ja     L3
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L7
  mov    $0x1,%r8d
L29:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int al_sisnum(const char *str) {
  if (!*str)
    return 0;
  while (*str)
    if (!isdigit(*str++))
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<al_sisnum>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L15
  xchg   %ax,%ax
L1:
  sub    $0x30,%eax
  add    $0x1,%rdi
  cmp    $0x9,%eax
  ja     L24
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L1
  mov    $0x1,%r8d
L15:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L24:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int al_sisnum(const char *str) {
  if (!*str)
    return 0;
  while (*str)
    if (!isdigit(*str++))
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int swap(a, l, r)
int *a, l, r;
{
  int i;
  i = a[l];
  a[l] = a[r];
  a[r] = i;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int swap(a, l, r)
int *a, l, r;
{
  int i;
  i = a[l];
  a[l] = a[r];
  a[r] = i;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rax),%edx
  mov    (%rcx),%esi
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int swap(a, l, r)
int *a, l, r;
{
  int i;
  i = a[l];
  a[l] = a[r];
  a[r] = i;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rax),%edx
  mov    (%rcx),%esi
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int swap(a, l, r)
int *a, l, r;
{
  int i;
  i = a[l];
  a[l] = a[r];
  a[r] = i;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L21:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L25
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jle    L47
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L48
L47:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L25:
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertSort(int *num, int size) {
  for (int i = 1; i < size; i++) {
    if (num[i - 1] > num[i]) {
      int j = i;
      int tmp = num[j];
      do {
        num[j] = num[j - 1];
        j--;
      } while (j > 0 && num[j - 1] > tmp);
      num[j] = tmp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  lea    -0x1(%rsi),%r8d
  mov    $0x0,%edx
  jmp    L13
L9:
  movslq %ecx,%rcx
  mov    %esi,(%rdi,%rcx,4)
L19:
  add    $0x1,%rdx
  cmp    %r8,%rdx
  je     L0
L13:
  mov    0x4(%rdi,%rdx,4),%esi
  cmp    %esi,(%rdi,%rdx,4)
  jle    L19
  mov    %rdx,%rax
L62:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,0x4(%rdi,%rax,4)
  mov    %eax,%ecx
  test   %eax,%eax
  jle    L9
  sub    $0x1,%rax
  cmp    (%rdi,%rax,4),%esi
  jl     L62
  jmp    L9
L0:
  ret
```

assistant: ```c
void insertSort(int *num, int size) {
  for (int i = 1; i < size; i++) {
    if (num[i - 1] > num[i]) {
      int j = i;
      int tmp = num[j];
      do {
        num[j] = num[j - 1];
        j--;
      } while (j > 0 && num[j - 1] > tmp);
      num[j] = tmp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L44
  lea    -0x1(%rsi),%r11d
  mov    $0x1,%r9d
  xor    %esi,%esi
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L72:
  add    $0x1,%rsi
  add    $0x1,%r9
  cmp    %r11,%rsi
  je     L44
L63:
  mov    (%rdi,%rsi,4),%edx
  mov    (%rdi,%r9,4),%ecx
  cmp    %ecx,%edx
  jle    L72
  mov    %r9,%r8
  lea    0x0(,%rsi,4),%rax
  sub    %rsi,%r8
  lea    -0x4(,%r8,4),%r10
  jmp    L6
L13:
  mov    -0x4(%rdi,%rax,1),%edx
  lea    -0x4(%rax),%r8
  cmp    %edx,%ecx
  jge    L33
  mov    %r8,%rax
L6:
  mov    %edx,0x4(%rdi,%rax,1)
  cmp    %r10,%rax
  jne    L13
  mov    %rdi,%rax
  mov    %ecx,(%rax)
L62:
  add    $0x1,%rsi
  add    $0x1,%r9
  cmp    %r11,%rsi
  jne    L63
L44:
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  add    %rdi,%rax
  mov    %ecx,(%rax)
  jmp    L62
```

assistant: ```c
void insertSort(int *num, int size) {
  for (int i = 1; i < size; i++) {
    if (num[i - 1] > num[i]) {
      int j = i;
      int tmp = num[j];
      do {
        num[j] = num[j - 1];
        j--;
      } while (j > 0 && num[j - 1] > tmp);
      num[j] = tmp;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insertSort>:
  endbr64
  cmp    $0x1,%esi
  jle    L45
  lea    -0x1(%rsi),%r10d
  mov    $0x1,%r8d
  xor    %esi,%esi
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rsi
  add    $0x1,%r8
  cmp    %r10,%rsi
  je     L45
L84:
  mov    (%rdi,%r8,4),%ecx
  cmp    %ecx,(%rdi,%rsi,4)
  jle    L56
  mov    %r8,%rdx
  lea    0x0(,%rsi,4),%rax
  sub    %rsi,%rdx
  lea    -0x4(,%rdx,4),%r9
  jmp    L16
  xchg   %ax,%ax
L33:
  lea    -0x4(%rax),%rdx
  cmp    -0x4(%rdi,%rax,1),%ecx
  jge    L70
  mov    %rdx,%rax
L16:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,0x4(%rdi,%rax,1)
  cmp    %r9,%rax
  jne    L33
  mov    %rdi,%rax
  mov    %ecx,(%rax)
L53:
  add    $0x1,%rsi
  add    $0x1,%r8
  cmp    %r10,%rsi
  jne    L84
L45:
  ret
  nopl   0x0(%rax)
L70:
  add    %rdi,%rax
  mov    %ecx,(%rax)
  jmp    L53
```

assistant: ```c
void insertSort(int *num, int size) {
  for (int i = 1; i < size; i++) {
    if (num[i - 1] > num[i]) {
      int j = i;
      int tmp = num[j];
      do {
        num[j] = num[j - 1];
        j--;
      } while (j > 0 && num[j - 1] > tmp);
      num[j] = tmp;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__rename@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
L3:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int res = __rename(old, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rename>:
  endbr64
  push   %rbx
  call   <__rename@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L11
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
L11:
  mov    $0x0,%eax
  call   <__inc_remove_counter@plt>
  jmp    L4
```

assistant: ```c
int rename(const char *old, const char *new) {
  int res = __rename(old, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rename>:
  endbr64
  push   %r12
  call   <__rename@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L4
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int res = __rename(old, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rename>:
  endbr64
  push   %r12
  call   <__rename@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L3
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <__inc_remove_counter@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int rename(const char *old, const char *new) {
  int res = __rename(old, new);
  if (res == 0)
    __inc_remove_counter();
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<format_warn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %rsi,-0x820(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x820(%rbp),%rdx
  mov    -0x818(%rbp),%rcx
  lea    -0x810(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <warn@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void format_warn(msg, arg) char msg[], arg[];
{
  char warn_msg[2048];
  (void)sprintf(warn_msg, msg, arg);
  warn(warn_msg);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<format_warn>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rdi,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <warn@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x810,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_warn(msg, arg) char msg[], arg[];
{
  char warn_msg[2048];
  (void)sprintf(warn_msg, msg, arg);
  warn(warn_msg);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<format_warn>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <warn@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x810,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_warn(msg, arg) char msg[], arg[];
{
  char warn_msg[2048];
  (void)sprintf(warn_msg, msg, arg);
  warn(warn_msg);
}
```
user: What is the c source code of the assembly code below?

```asm
<format_warn>:
  endbr64
  push   %rbp
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <warn@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x810,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void format_warn(msg, arg) char msg[], arg[];
{
  char warn_msg[2048];
  (void)sprintf(warn_msg, msg, arg);
  warn(warn_msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<procuraTodos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L21
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L21:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int procuraTodos(int *v, int N, int x, int *posicoes, int *nPosicoes) {
  for (int i = 0; i < N; ++i) {
    if (v[i] == x) {
      posicoes[(*nPosicoes)++] = i;
    }
  }
  return (*nPosicoes) != 0;
}
```