ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm2
  pxor   %xmm4,%xmm4
  pxor   %xmm1,%xmm1
  comiss %xmm4,%xmm2
  jbe    L22
  movaps %xmm1,%xmm0
  lea    0x14(%rsp),%rbp
  nopl   0x0(%rax)
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  addss  D16(%rip),%xmm0
  movss  0x10(%rsp),%xmm2
  movss  0x8(%rsp),%xmm1
  addss  0x14(%rsp),%xmm1
  comiss %xmm0,%xmm2
  ja     L28
L22:
  movaps %xmm1,%xmm3
  movaps %xmm1,%xmm0
  lea    D27(%rip),%rdi
  divss  %xmm2,%xmm3
  movss  %xmm3,0x8(%rsp)
  call   <printf@plt>
  movss  0x8(%rsp),%xmm3
  lea    D13(%rip),%rdi
  movaps %xmm3,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: byte[4]
name: disassemble_data
arguments: data_label: D27
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D5: %f

tool: {"D16": [0x00,0x00,0x80,0x3f]}

tool: D27: Sum: %.0f

tool: D13: 
Avg: %.2f

assistant: ```c
int main() {
  float n, a, i, sum = 0;
  float avg = 0;
  scanf("%f", &n);
  for (i = 0; i < n; i++) {
    scanf("%f", &a);
    sum += a;
  }
  avg = sum / n;
  printf("Sum: %.0f", sum);
  printf("\nAvg: %.2f", avg);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <part@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L12
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort>
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L1
  mov    -0x20(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <qsort>
L1:
  nop
  leave
  ret
```

assistant: ```c
void qsort(int a[], int l, int r) {
  int m;
  m = part(a, l, r);
  if (l < m - 1)
    qsort(a, l, m - 1);
  if (m < r)
    qsort(a, m, r);
}
```
user: What is the c source code of the assembly code below?

```asm
<qsort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  call   <part@plt>
  mov    %eax,%ebx
  lea    -0x1(%rax),%edx
  cmp    %r12d,%edx
  jg     L29
L27:
  cmp    %ebx,%ebp
  jg     L15
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <qsort>
  jmp    L27
L15:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <qsort>
  jmp    L19
```

assistant: ```c
void qsort(int a[], int l, int r) {
  int m;
  m = part(a, l, r);
  if (l < m - 1)
    qsort(a, l, m - 1);
  if (m < r)
    qsort(a, m, r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D25(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D32
type_guessed: string
name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D25
type_guessed: f64
name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D32: Km: 

tool: D10: %f

tool: D25: 1.61

tool: D5: Milhas: %.2f

assistant: ```c
int main() {
  float km;
  printf("Km: ");
  scanf("%f", &km);
  printf("Milhas: %.2f", km / 1.61);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D4(%rip),%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D4
data_type: f64
name: unpack_data
arguments: tag: D0
data_type: string

tool: D22: Km: 

tool: D24: %f

tool: D4: 1.61

tool: D0: Milhas: %.2f

assistant: ```c
int main() {
  float km;
  printf("Km: ");
  scanf("%f", &km);
  printf("Milhas: %.2f", km / 1.61);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D12(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D39(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D39
datatype: f64

tool: D23: Km: 

tool: D10: %f

tool: D12: Milhas: %.2f

tool: D39: 1.61

assistant: ```c
int main() {
  float km;
  printf("Km: ");
  scanf("%f", &km);
  printf("Milhas: %.2f", km / 1.61);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D23(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D26(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D32(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D32
type_infered: f64

tool: D23: Km: 

tool: D7: %f

tool: D26: Milhas: %.2f

tool: D32: 1.61

assistant: ```c
int main() {
  float km;
  printf("Km: ");
  scanf("%f", &km);
  printf("Milhas: %.2f", km / 1.61);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jle    L8
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L22
L8:
  cmpq   $0x0,-0x10(%rbp)
  jne    L26
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jg     L22
  mov    $0x3e8,%edi
  call   <sleep@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L22
L26:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L36
L22:
  mov    $0x0,%eax
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: fork failed


assistant: ```c
int main() {
  pid_t f = fork();
  if (f > 0) {
    exit(0);
  } else if (f == 0) {
    pid_t m = fork();
    if (m > 0) {
    } else {
      sleep(1000);
      exit(0);
    }
  } else {
    printf("fork failed\n");
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L9
  jne    L27
  call   <fork@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L26
L12:
  add    $0x8,%rsp
  ret
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  jmp    L12
L26:
  mov    $0x3e8,%edi
  call   <sleep@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  jmp    L12
L27:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: fork failed


assistant: ```c
int main() {
  pid_t f = fork();
  if (f > 0) {
    exit(0);
  } else if (f == 0) {
    pid_t m = fork();
    if (m > 0) {
    } else {
      sleep(1000);
      exit(0);
    }
  } else {
    printf("fork failed\n");
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L59
  jne    L19
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fork@plt>
  test   %rax,%rax
  jle    L38
L11:
  mov    %r12d,%eax
  pop    %r12
  ret
L59:
  xor    %edi,%edi
  xor    %r12d,%r12d
  call   <exit@plt>
  jmp    L11
L38:
  mov    $0x3e8,%edi
  call   <sleep@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L11
L19:
  lea    D0(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: fork failed


assistant: ```c
int main() {
  pid_t f = fork();
  if (f > 0) {
    exit(0);
  } else if (f == 0) {
    pid_t m = fork();
    if (m > 0) {
    } else {
      sleep(1000);
      exit(0);
    }
  } else {
    printf("fork failed\n");
    return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L49
  jne    L33
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <fork@plt>
  test   %rax,%rax
  jle    L37
L31:
  mov    %r12d,%eax
  pop    %r12
  ret
L49:
  xor    %edi,%edi
  xor    %r12d,%r12d
  call   <exit@plt>
  jmp    L31
L37:
  mov    $0x3e8,%edi
  call   <sleep@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L31
L33:
  lea    D0(%rip),%rdi
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L31
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: fork failed


assistant: ```c
int main() {
  pid_t f = fork();
  if (f > 0) {
    exit(0);
  } else if (f == 0) {
    pid_t m = fork();
    if (m > 0) {
    } else {
      sleep(1000);
      exit(0);
    }
  } else {
    printf("fork failed\n");
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BLInternalFlashErase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400fd000,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x400fd008,%eax
  mov    $0xa4420002,%ecx
  mov    %rcx,(%rax)
  nop
L7:
  mov    $0x400fd008,%eax
  mov    (%rax),%rax
  and    $0x2,%eax
  test   %rax,%rax
  jne    L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BLInternalFlashErase(unsigned long ulAddress) {
  (*((volatile unsigned long *)(0x400FD000))) = ulAddress;
  (*((volatile unsigned long *)(0x400FD008))) = 0xA4420000 | 0x00000002;
  while ((*((volatile unsigned long *)(0x400FD008))) & 0x00000002) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BLInternalFlashErase>:
  endbr64
  mov    %rdi,0x400fd000
  mov    $0xa4420002,%eax
  mov    %rax,0x400fd008
L2:
  mov    0x400fd008,%rax
  test   $0x2,%al
  jne    L2
  ret
```

assistant: ```c
void BLInternalFlashErase(unsigned long ulAddress) {
  (*((volatile unsigned long *)(0x400FD000))) = ulAddress;
  (*((volatile unsigned long *)(0x400FD008))) = 0xA4420000 | 0x00000002;
  while ((*((volatile unsigned long *)(0x400FD008))) & 0x00000002) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BLInternalFlashErase>:
  endbr64
  mov    $0xa4420002,%eax
  mov    %rdi,0x400fd000
  mov    %rax,0x400fd008
  nopl   0x0(%rax)
L8:
  mov    0x400fd008,%rax
  test   $0x2,%al
  jne    L8
  ret
```

assistant: ```c
void BLInternalFlashErase(unsigned long ulAddress) {
  (*((volatile unsigned long *)(0x400FD000))) = ulAddress;
  (*((volatile unsigned long *)(0x400FD008))) = 0xA4420000 | 0x00000002;
  while ((*((volatile unsigned long *)(0x400FD008))) & 0x00000002) {
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BLInternalFlashErase>:
  endbr64
  mov    $0xa4420002,%eax
  mov    %rdi,0x400fd000
  mov    %rax,0x400fd008
  nopl   0x0(%rax)
L3:
  mov    0x400fd008,%rax
  test   $0x2,%al
  jne    L3
  ret
```

assistant: ```c
void BLInternalFlashErase(unsigned long ulAddress) {
  (*((volatile unsigned long *)(0x400FD000))) = ulAddress;
  (*((volatile unsigned long *)(0x400FD008))) = 0xA4420000 | 0x00000002;
  while ((*((volatile unsigned long *)(0x400FD008))) & 0x00000002) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x14(%rcx),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1e(%rcx),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: fn0

assistant: ```c
char *fn0() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn0");
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn0>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: fn0

assistant: ```c
char *fn0() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn0");
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn0>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: fn0

assistant: ```c
char *fn0() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn0");
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fn0>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: fn0

assistant: ```c
char *fn0() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn0");
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<IntToCharArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <IntLength@plt>
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <IntPower@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <IntLength@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L14:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    D7(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L14
  lea    D7(%rip),%rax
  leave
  ret
```

assistant: ```c
char *IntToCharArray(int x) {
  int z, e, i, a, b, c, d;
  z = x;
  d = IntPower(10, IntLength(x) - 1);
  static char ch[10];
  e = IntLength(x);
  for (i = 0; i < e; i++) {
    a = x % d;
    b = x - a;
    c = b / d;
    d = d / 10;
    ch[i] = '0' + c;
    x = a;
  }
  return ch;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<IntToCharArray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <IntLength@plt>
  lea    -0x1(%rax),%esi
  mov    $0xa,%edi
  call   <IntPower@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <IntLength@plt>
  test   %eax,%eax
  jle    L10
  lea    D19(%rip),%rsi
  lea    -0x1(%rax),%edi
  lea    0x1(%rsi),%rax
  add    %rax,%rdi
L14:
  mov    %ebp,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  mov    %ecx,%eax
  sub    %edx,%eax
  cltd
  idiv   %ebx
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%ebx
  sub    %ecx,%ebx
  lea    0x30(%rax),%edx
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  jne    L14
L10:
  lea    D19(%rip),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *IntToCharArray(int x) {
  int z, e, i, a, b, c, d;
  z = x;
  d = IntPower(10, IntLength(x) - 1);
  static char ch[10];
  e = IntLength(x);
  for (i = 0; i < e; i++) {
    a = x % d;
    b = x - a;
    c = b / d;
    d = d / 10;
    ch[i] = '0' + c;
    x = a;
  }
  return ch;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IntToCharArray>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <IntLength@plt>
  mov    $0xa,%edi
  lea    -0x1(%rax),%esi
  call   <IntPower@plt>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <IntLength@plt>
  lea    D4(%rip),%r8
  test   %eax,%eax
  jle    L5
  sub    $0x1,%eax
  lea    0x1(%r8),%rdi
  mov    %r8,%rsi
  add    %rax,%rdi
  nop
L8:
  mov    %ebp,%eax
  mov    %ebp,%ecx
  add    $0x1,%rsi
  cltd
  idiv   %ebx
  mov    %ecx,%eax
  movslq %ebx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  sub    %edx,%eax
  mov    %edx,%ebp
  cltd
  idiv   %ebx
  mov    %ebx,%edx
  mov    %ecx,%ebx
  sar    $0x1f,%edx
  sub    %edx,%ebx
  add    $0x30,%eax
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rdi
  jne    L8
L5:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *IntToCharArray(int x) {
  int z, e, i, a, b, c, d;
  z = x;
  d = IntPower(10, IntLength(x) - 1);
  static char ch[10];
  e = IntLength(x);
  for (i = 0; i < e; i++) {
    a = x % d;
    b = x - a;
    c = b / d;
    d = d / 10;
    ch[i] = '0' + c;
    x = a;
  }
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmod_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <lrint@plt>
  movapd %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L7
  movsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L16
L7:
  movsd  -0x8(%rbp),%xmm0
L16:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: f64

tool: D7: 1

assistant: ```c
double fmod_one(double x) {
  double res;
  res = x - lrint(x);
  if (res < 0.0)
    return res + 1.0;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fmod_one>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <lrint@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L10
L16:
  pop    %rbx
  ret
L10:
  addsd  D4(%rip),%xmm0
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
double fmod_one(double x) {
  double res;
  res = x - lrint(x);
  if (res < 0.0)
    return res + 1.0;
  return res;
}
```