user: 这段汇编代码用C语言表示是什么样的?

```asm
<mutation>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r14
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  mov    %r8d,0xc(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand48@plt>
  test   %ebx,%ebx
  jle    L99
  mov    %r15,%r13
  lea    -0x1(%rbx),%eax
  lea    0x8(%r15,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbp),%eax
  lea    0x4(,%rax,4),%r15
  jmp    L85
L136:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  mov    %edx,%ebp
L70:
  mov    %r13,(%rsp)
  mov    %rbx,%rax
  add    0x0(%r13),%rax
  cmp    %ebp,(%rax)
  je     L1
  mov    %ebp,(%rax)
L55:
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L100
L111:
  mov    $0x0,%eax
  call   <drand48@plt>
  pxor   %xmm2,%xmm2
  cvtsi2ssl 0xc(%rsp),%xmm2
  movss  D5(%rip),%xmm1
  divss  %xmm2,%xmm1
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm1
  jbe    L55
  mov    (%r14,%rbx,2),%rax
  cmpl   $0x1,0xc(%rax)
  jne    L136
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  lea    0x1(%rdx),%ebp
  jmp    L70
L39:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  add    $0x1,%edx
  jmp    L143
L104:
  cmp    %edx,%ebp
  jne    L55
L1:
  mov    (%r14,%rbx,2),%rax
  cmpl   $0x1,0xc(%rax)
  je     L39
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
L143:
  mov    (%rsp),%rcx
  mov    %rbx,%rax
  add    (%rcx),%rax
  cmp    %edx,(%rax)
  je     L104
  mov    %edx,(%rax)
  jmp    L104
L100:
  add    $0x8,%r13
  cmp    0x10(%rsp),%r13
  je     L99
L85:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L111
  jmp    L100
L99:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: f32

tool: D5: 1

assistant: ```c
int **mutation(int **population, int **V, int number_of_individuals, int h_size, int v_size) {
  int iterator_virtual;
  int physical_position;
  int iterator_individual;
  int aux;
  float probability;
  srand48(time(NULL));
  h_size + 1;
  for (iterator_individual = 0; iterator_individual < number_of_individuals; iterator_individual++) {
    for (iterator_virtual = 0; iterator_virtual < v_size; iterator_virtual++) {
      probability = drand48() * 1.0;
      if (probability < (float)1 / v_size) {
        if (V[iterator_virtual][3] == 1) {
          physical_position = rand() % h_size + 1;
        } else {
          physical_position = rand() % h_size;
        }
        if (physical_position != population[iterator_individual][iterator_virtual])
          population[iterator_individual][iterator_virtual] = physical_position;
        else {
          aux = population[iterator_individual][iterator_virtual];
          while (physical_position == aux) {
            if (V[iterator_virtual][3] == 1) {
              physical_position = rand() % h_size + 1;
            } else {
              physical_position = rand() % h_size;
            }
            if (physical_position != population[iterator_individual][iterator_virtual])
              population[iterator_individual][iterator_virtual] = physical_position;
          }
        }
      }
    }
  }
  return population;
}
```