user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L183
L240:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L240
L183:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L74
L33:
  mov    %rax,%rdi
  mov    %rsp,-0x48(%rbp)
  mov    %rax,%rdx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rdx
  sub    %rdi,%rsi
L130:
  cmp    %rsi,%rsp
  je     L188
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L130
L74:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L33
L188:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L228
L41:
  mov    %rsp,-0x50(%rbp)
  mov    %rax,%rdx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rsi
L191:
  cmp    %rsi,%rsp
  je     L206
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L191
L228:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L41
L206:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L141
  orq    $0x0,-0x8(%rsp,%rdx,1)
L141:
  mov    %rsp,-0x58(%rbp)
  test   %ecx,%ecx
  jle    L182
  mov    -0x48(%rbp),%rbx
  mov    -0x50(%rbp),%r12
  xor    %r14d,%r14d
  lea    D0(%rip),%r15
  mov    -0x58(%rbp),%r13
  cs nopw 0x0(%rax,%rax,1)
L160:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  add    $0x4,%rbx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  add    $0x4,%r13
  cmp    %r14d,%eax
  jg     L160
  test   %eax,%eax
  jle    L182
  xor    %r15d,%r15d
  lea    D18(%rip),%rbx
  lea    D7(%rip),%r14
  jmp    L203
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r14,%rdi
  call   <printf@plt>
L215:
  add    $0x1,%r15
  cmp    %r15d,-0x3c(%rbp)
  jle    L182
L203:
  mov    -0x48(%rbp),%rax
  mov    -0x58(%rbp),%rcx
  mov    (%rax,%r15,4),%esi
  mov    -0x50(%rbp),%rax
  mov    (%rcx,%r15,4),%edx
  mov    (%rax,%r15,4),%eax
  cmp    %eax,%esi
  mov    %eax,%edi
  cmovge %esi,%edi
  cmp    %edi,%edx
  jg     L22
  cmp    %edx,%esi
  je     L196
  cmp    %edx,%eax
  je     L196
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %edx,%eax
  je     L85
  mov    %eax,%r8d
  sub    %edx,%r8d
  and    $0x1,%r8d
  jne    L22
  cmp    %edx,%eax
  jle    L22
  call   <print@plt>
  add    $0x1,%r15
  cmp    %r15d,-0x3c(%rbp)
  jg     L203
  nopl   0x0(%rax)
L182:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L214
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L196:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L215
L85:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L215
L214:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D15: %d

tool: D0: %d%d%d

tool: D18: 1


tool: D7: -1


tool: D17: 3


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  int A[t], B[t], C[t], i;
  int max, min, a, b, c;
  for (i = 0; i < t; i++)
    scanf("%d%d%d", &A[i], &B[i], &C[i]);
  for (i = 0; i < t; i++) {
    a = A[i];
    b = B[i];
    c = C[i];
    max = (a > b) ? a : b;
    min = (a < b) ? a : b;
    if (c > a && c > b) {
      printf("-1\n");
      continue;
    } else if (c == a || c == b) {
      printf("1\n");
      continue;
    } else if (max - min == c) {
      printf("3\n");
      continue;
    } else if ((max - min - c) % 2 == 0 && (max - min) > c) {
      print(max, min, c);
      continue;
    } else {
      printf("-1\n");
      continue;
    }
  }
  return 0;
}
```