ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L61
  lea    D4(%rip),%rbx
  je     L30
  nopl   0x0(%rax)
L46:
  movslq %esi,%rax
  mov    %esi,%edx
  mov    %rbx,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rsi
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  mov    %esi,0x4(%rsp)
  jne    L46
L30:
  lea    D54(%rip),%rdi
  call   <puts@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L61:
  mov    %esi,%eax
  neg    %eax
  mov    %eax,0x4(%rsp)
  cmp    $0xfffffff6,%esi
  jge    L54
  lea    D4(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L36:
  movslq %eax,%rdx
  mov    %eax,%ecx
  mov    %rbx,%rdi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x6d,%edx
  jg     L36
L54:
  neg    %eax
  lea    D42(%rip),%rdi
  mov    %eax,0x4(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D49
datatype: string
name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D54
datatype: string
name: retrieve_data
arguments: tag: D42
datatype: string

tool: D13: 
Enter an integer > 

tool: D49: %d

tool: D4: %d


tool: D54: That's all, have a nice day!

tool: D42: %d
That's all, have a nice day!


assistant: ```c
int main(void) {
  int number, rem;
  printf("\nEnter an integer > ");
  scanf("%d", &number);
  printf("\n");
  if (number < 0) {
    number = abs(number);
    while (number > 10) {
      rem = number % 10;
      printf("%d\n", rem);
      number = number / 10;
    }
    number = number - 2 * number;
    printf("%d\nThat's all, have a nice day!\n", number);
  } else {
    while (number != 0) {
      rem = number % 10;
      printf("%d\n", rem);
      number = number / 10;
    }
    printf("That's all, have a nice day!\n");
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L4
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int do_test(void) {
  if (foo(2) != 3)
    abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  jne    L10
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L7
```

assistant: ```c
int do_test(void) {
  if (foo(2) != 3)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L6
  xor    %eax,%eax
  call   <abort@plt>
L6:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_test(void) {
  if (foo(2) != 3)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<do_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <foo@plt>
  cmp    $0x3,%eax
  je     L2
  xor    %eax,%eax
  call   <abort@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_test(void) {
  if (foo(2) != 3)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<println>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <terminal_handle_newline@plt>
  nop
  leave
  ret
```

assistant: ```c
void println(const char *data) {
  print(data);
  terminal_handle_newline();
}
```
user: What is the c source code of the assembly code below:

```asm
<println>:
  endbr64
  sub    $0x8,%rsp
  call   <print@plt>
  mov    $0x0,%eax
  call   <terminal_handle_newline@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void println(const char *data) {
  print(data);
  terminal_handle_newline();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<println>:
  endbr64
  sub    $0x8,%rsp
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <terminal_handle_newline@plt>
```

assistant: ```c
void println(const char *data) {
  print(data);
  terminal_handle_newline();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<println>:
  endbr64
  sub    $0x8,%rsp
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <terminal_handle_newline@plt>
```

assistant: ```c
void println(const char *data) {
  print(data);
  terminal_handle_newline();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yy_2_ValidXmlAttribute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yy_2_ValidXmlAttribute(char *yytext, int yyleng) {
  ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yy_2_ValidXmlAttribute>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ValidXmlAttribute(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yy_2_ValidXmlAttribute>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ValidXmlAttribute(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yy_2_ValidXmlAttribute>:
  endbr64
  ret
```

assistant: ```c
void yy_2_ValidXmlAttribute(char *yytext, int yyleng) {
  ;
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<generateHashValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L41:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0x2e,-0xd(%rbp)
  je     L46
  cmpb   $0x5c,-0xd(%rbp)
  jne    L58
  movb   $0x2f,-0xd(%rbp)
L58:
  cmpb   $0x2f,-0xd(%rbp)
  jne    L55
  movb   $0x2f,-0xd(%rbp)
L55:
  movsbq -0xd(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  add    $0x77,%eax
  cltq
  imul   %rdx,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  jmp    L35
L46:
  nop
L35:
  mov    -0x8(%rbp),%rax
  sar    $0xa,%rax
  xor    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  sar    $0x14,%rax
  xor    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  and    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long generateHashValue(const char *fname, const int size) {
  int i;
  long hash;
  char letter;
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    letter = tolower(fname[i]);
    if (letter == '.')
      break;
    if (letter == '\\')
      letter = '/';
    if (letter == '/')
      letter = '/';
    hash += (long)(letter) * (i + 119);
    i++;
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20));
  hash &= (size - 1);
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generateHashValue>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L60
  mov    $0x77,%ebx
  mov    $0x0,%ebp
  mov    $0x2f,%r14d
  jmp    L62
L67:
  mov    %r14d,%edx
L4:
  movsbq %dl,%rdx
  imul   %rbx,%rdx
  add    %rdx,%rbp
  add    $0x1,%rbx
  movzbl -0x77(%r12,%rbx,1),%edi
  test   %dil,%dil
  je     L10
L62:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  cmp    $0x2e,%al
  je     L10
  cmp    $0x2f,%al
  je     L67
  cmp    $0x5c,%al
  jne    L4
  jmp    L67
L60:
  mov    $0x0,%ebp
L10:
  mov    %rbp,%rdx
  sar    $0xa,%rdx
  mov    %rbp,%rax
  sar    $0x14,%rax
  xor    %rax,%rdx
  xor    %rbp,%rdx
  lea    -0x1(%r13),%eax
  cltq
  and    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long generateHashValue(const char *fname, const int size) {
  int i;
  long hash;
  char letter;
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    letter = tolower(fname[i]);
    if (letter == '.')
      break;
    if (letter == '\\')
      letter = '/';
    if (letter == '/')
      letter = '/';
    hash += (long)(letter) * (i + 119);
    i++;
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20));
  hash &= (size - 1);
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<generateHashValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  lea    -0x1(%rsi),%r12d
  mov    $0x77,%r13d
  xor    %ebx,%ebx
  movslq %r12d,%r12
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    $0x5c,%al
  je     L37
L73:
  imul   %r13,%rdx
  add    $0x1,%r13
  movsbl -0x77(%rbp,%r13,1),%edi
  add    %rdx,%rbx
  test   %dil,%dil
  je     L68
L79:
  call   <tolower@plt>
  movsbq %al,%rdx
  cmp    $0x2e,%al
  je     L68
  cmp    $0x2f,%al
  jne    L11
L37:
  mov    $0x2f,%edx
  jmp    L73
  nopw   0x0(%rax,%rax,1)
L68:
  mov    %rbx,%rax
  mov    %rbx,%rdx
  sar    $0xa,%rax
  sar    $0x14,%rdx
  xor    %rdx,%rax
  xor    %rbx,%rax
  and    %r12,%rax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  xor    %eax,%eax
  jmp    L34
```

assistant: ```c
long generateHashValue(const char *fname, const int size) {
  int i;
  long hash;
  char letter;
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    letter = tolower(fname[i]);
    if (letter == '.')
      break;
    if (letter == '\\')
      letter = '/';
    if (letter == '/')
      letter = '/';
    hash += (long)(letter) * (i + 119);
    i++;
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20));
  hash &= (size - 1);
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<generateHashValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L36
  lea    -0x1(%rsi),%r12d
  mov    $0x77,%r13d
  xor    %ebx,%ebx
  movslq %r12d,%r12
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L30:
  cmp    $0x5c,%al
  je     L24
  movsbq %al,%rax
  imul   %r13,%rax
L7:
  add    $0x1,%r13
  add    %rax,%rbx
  movsbl -0x77(%rbp,%r13,1),%edi
  test   %dil,%dil
  je     L50
L29:
  call   <tolower@plt>
  cmp    $0x2e,%al
  je     L50
  cmp    $0x2f,%al
  jne    L30
L24:
  lea    0x0(%r13,%r13,2),%rax
  shl    $0x4,%rax
  sub    %r13,%rax
  jmp    L7
  nopl   0x0(%rax)
L50:
  mov    %rbx,%rax
  mov    %rbx,%rdx
  sar    $0xa,%rax
  sar    $0x14,%rdx
  xor    %rdx,%rax
  xor    %rbx,%rax
  and    %r12,%rax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  xor    %eax,%eax
  jmp    L0
```

assistant: ```c
long generateHashValue(const char *fname, const int size) {
  int i;
  long hash;
  char letter;
  hash = 0;
  i = 0;
  while (fname[i] != '\0') {
    letter = tolower(fname[i]);
    if (letter == '.')
      break;
    if (letter == '\\')
      letter = '/';
    if (letter == '/')
      letter = '/';
    hash += (long)(letter) * (i + 119);
    i++;
  }
  hash = (hash ^ (hash >> 10) ^ (hash >> 20));
  hash &= (size - 1);
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashFunction1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
int hashFunction1(char key[20]) {
  int i, sum;
  sum = 0;
  for (i = 0; i < strlen(key); i++)
    sum += key[i];
  return (sum % 101);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashFunction1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L3
L10:
  movsbl (%r12,%rbx,1),%eax
  add    %eax,%ebp
  add    $0x1,%rbx
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  movslq %ebp,%rax
  imul   $0x288df0cb,%rax,%rax
  sar    $0x24,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int hashFunction1(char key[20]) {
  int i, sum;
  sum = 0;
  for (i = 0; i < strlen(key); i++)
    sum += key[i];
  return (sum % 101);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashFunction1>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L19
  nopl   0x0(%rax)
L1:
  movsbl (%r12,%rbx,1),%eax
  add    $0x1,%rbx
  add    %eax,%ebp
L19:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  movslq %ebp,%rax
  mov    %ebp,%edx
  pop    %rbx
  imul   $0x288df0cb,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x24,%rax
  sub    %edx,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %edx,%eax
  ret
```

assistant: ```c
int hashFunction1(char key[20]) {
  int i, sum;
  sum = 0;
  for (i = 0; i < strlen(key); i++)
    sum += key[i];
  return (sum % 101);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hashFunction1>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L14
  nopl   0x0(%rax)
L5:
  movsbl (%r12,%rbx,1),%eax
  add    $0x1,%rbx
  add    %eax,%ebp
L14:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  movslq %ebp,%rax
  mov    %ebp,%edx
  pop    %rbx
  imul   $0x288df0cb,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x24,%rax
  sub    %edx,%eax
  imul   $0x65,%eax,%edx
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %edx,%eax
  ret
```

assistant: ```c
int hashFunction1(char key[20]) {
  int i, sum;
  sum = 0;
  for (i = 0; i < strlen(key); i++)
    sum += key[i];
  return (sum % 101);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<llabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L15
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L19
L15:
  mov    -0x8(%rbp),%rax
L19:
  pop    %rbp
  ret
```

assistant: ```c
long long int llabs(long long int num) {
  if (num < 0)
    return -num;
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long int llabs(long long int num) {
  if (num < 0)
    return -num;
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long int llabs(long long int num) {
  if (num < 0)
    return -num;
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long int llabs(long long int num) {
  if (num < 0)
    return -num;
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x10(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ftell@plt>
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long get_size(FILE *file) {
  long pos = ftell(file);
  long size;
  fseek(file, 0L, SEEK_END);
  size = ftell(file);
  fseek(file, pos, SEEK_SET);
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <ftell@plt>
  mov    %rax,%r12
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbx,%rdi
  call   <ftell@plt>
  mov    %rax,%rbp
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fseek@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long get_size(FILE *file) {
  long pos = ftell(file);
  long size;
  fseek(file, 0L, SEEK_END);
  size = ftell(file);
  fseek(file, pos, SEEK_SET);
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_size>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ftell@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long get_size(FILE *file) {
  long pos = ftell(file);
  long size;
  fseek(file, 0L, SEEK_END);
  size = ftell(file);
  fseek(file, pos, SEEK_SET);
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_size>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ftell@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %rbp,%rdi
  call   <ftell@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  call   <fseek@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long get_size(FILE *file) {
  long pos = ftell(file);
  long size;
  fseek(file, 0L, SEEK_END);
  size = ftell(file);
  fseek(file, pos, SEEK_SET);
  return size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shellsort_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L76
L42:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L76:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L42
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L57
L37:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L62
L54:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L3
L71:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L3:
  cmpl   $0x0,-0xc(%rbp)
  js     L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L71
L32:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L62:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L54
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L57:
  cmpl   $0x0,-0x14(%rbp)
  jg     L37
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shellsort_d(int n, double a[]) {
  int h, i, j;
  double x;
  h = 1;
  while (h <= n)
    h = 3 * h + 1;
  h /= 9;
  while (h > 0) {
    for (i = h; i < n; i++) {
      x = a[i];
      for (j = i - h; j >= 0 && a[j] > x; j -= h)
        a[j + h] = a[j];
      a[j + h] = x;
    }
    h /= 3;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shellsort_d>:
  endbr64
  test   %edi,%edi
  jle    L97
  mov    %edi,%r11d
  mov    %rsi,%r10
  mov    $0x1,%eax
L7:
  lea    0x1(%rax,%rax,2),%eax
  cmp    %eax,%r11d
  jge    L7
  movslq %eax,%rcx
  imul   $0x38e38e39,%rcx,%rcx
  sar    $0x21,%rcx
  cltd
  sub    %edx,%ecx
  cmp    $0x8,%eax
  jle    L115
  push   %rbx
  jmp    L93
L115:
  ret
L68:
  add    %ecx,%edx
  movslq %edx,%rdx
  movsd  %xmm1,(%r10,%rdx,8)
  add    $0x1,%r8d
  add    $0x8,%r9
  cmp    %ebx,%r8d
  je     L1
L100:
  movsd  (%r9,%rsi,8),%xmm1
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L68
L55:
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L68
  movsd  %xmm0,(%rax,%rsi,8)
  add    %rdi,%rax
  sub    %ecx,%edx
  jns    L55
  jmp    L68
L1:
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  cmp    $0x2,%ecx
  jle    L23
  mov    %eax,%ecx
L93:
  cmp    %ecx,%r11d
  jle    L1
  mov    %r10,%r9
  mov    %r11d,%ebx
  sub    %ecx,%ebx
  mov    %ecx,%edi
  neg    %edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  mov    $0x0,%r8d
  movslq %ecx,%rsi
  jmp    L100
L23:
  pop    %rbx
  ret
L97:
  ret
```

assistant: ```c
void shellsort_d(int n, double a[]) {
  int h, i, j;
  double x;
  h = 1;
  while (h <= n)
    h = 3 * h + 1;
  h /= 9;
  while (h > 0) {
    for (i = h; i < n; i++) {
      x = a[i];
      for (j = i - h; j >= 0 && a[j] > x; j -= h)
        a[j + h] = a[j];
      a[j + h] = x;
    }
    h /= 3;
  }
}
```