ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D81(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L14:
  mov    -0x10(%rbp),%eax
  lea    0x2a(%rax),%ecx
  mov    -0x10(%rbp),%eax
  lea    0x2a(%rax),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D91(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L30:
  cmpl   $0x3,-0x10(%rbp)
  jle    L14
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L36:
  movss  -0xc(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D53(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x8(%rbp),%eax
  imul   $0xffffff9c,%eax,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  movsd  D46(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L21:
  cmpl   $0x3,-0x10(%rbp)
  jle    L36
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D81
type_guessed: f32
name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string
name: read_data
arguments: data_tag: D67
type_guessed: string
name: read_data
arguments: data_tag: D91
type_guessed: string
name: read_data
arguments: data_tag: D57
type_guessed: string
name: read_data
arguments: data_tag: D53
type_guessed: f64
name: read_data
arguments: data_tag: D42
type_guessed: string
name: read_data
arguments: data_tag: D46
type_guessed: f64

tool: D81: 1

tool: D7: 

LibC Test


tool: D6: compile time: Mar 15 2022 -- 21:52:22

tool: D1: gcc version:  9.4.0

tool: D67: Trying printf with int parameters:

tool: D91:     [%d] : %d == 0x%02x


tool: D57: Trying basic float operations:

tool: D53: 100

tool: D42:     1.0 + (0.7 * %d) == %d.%d


tool: D46: 0.7

assistant: ```c
int main() {
  int i;
  int integer, fraction;
  float f = 1.0;
  printf("\n\nLibC Test\n\n");
  printf("compile time: "
         "Mar 15 2022"
         " -- "
         "21:52:22"
         "\n");
  printf("gcc version:  "
         "9.4.0"
         "\n");
  printf("Trying printf with int parameters:\n");
  for (i = 0; i < 4; i++) {
    printf("    [%d] : %d == 0x%02x\n", i, i + 42, i + 42);
  }
  printf("Trying basic float operations:\n");
  for (i = 0; i < 4; i++) {
    integer = (int)f;
    fraction = (int)(f * 100.0) - integer * 100;
    printf("    1.0 + (0.7 * %d) == %d.%d\n", i, integer, fraction);
    f = f + 0.7;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D97(%rip),%rdi
  call   <puts@plt>
  lea    D77(%rip),%rdi
  call   <puts@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  lea    D82(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D52(%rip),%rbp
L3:
  lea    0x2a(%rbx),%edx
  mov    %edx,%ecx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L3
  lea    D41(%rip),%rdi
  call   <puts@plt>
  movss  D98(%rip),%xmm0
  mov    $0x0,%ebx
  lea    D75(%rip),%rbp
L5:
  cvttss2si %xmm0,%edx
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D91(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  imul   $0xffffff9c,%edx,%eax
  add    %eax,%ecx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D99(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D97
datatype: string
name: unpack_data
arguments: data_tag: D77
datatype: string
name: unpack_data
arguments: data_tag: D59
datatype: string
name: unpack_data
arguments: data_tag: D82
datatype: string
name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D41
datatype: string
name: unpack_data
arguments: data_tag: D98
datatype: f32
name: unpack_data
arguments: data_tag: D75
datatype: string
name: unpack_data
arguments: data_tag: D91
datatype: f64
name: unpack_data
arguments: data_tag: D99
datatype: f64

tool: D97: 

LibC Test


tool: D77: compile time: Mar 15 2022 -- 21:52:22

tool: D59: gcc version:  9.4.0

tool: D82: Trying printf with int parameters:

tool: D52:     [%d] : %d == 0x%02x


tool: D41: Trying basic float operations:

tool: D98: 1

tool: D75:     1.0 + (0.7 * %d) == %d.%d


tool: D91: 100

tool: D99: 0.7

assistant: ```c
int main() {
  int i;
  int integer, fraction;
  float f = 1.0;
  printf("\n\nLibC Test\n\n");
  printf("compile time: "
         "Mar 15 2022"
         " -- "
         "21:52:22"
         "\n");
  printf("gcc version:  "
         "9.4.0"
         "\n");
  printf("Trying printf with int parameters:\n");
  for (i = 0; i < 4; i++) {
    printf("    [%d] : %d == 0x%02x\n", i, i + 42, i + 42);
  }
  printf("Trying basic float operations:\n");
  for (i = 0; i < 4; i++) {
    integer = (int)f;
    fraction = (int)(f * 100.0) - integer * 100;
    printf("    1.0 + (0.7 * %d) == %d.%d\n", i, integer, fraction);
    f = f + 0.7;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D52(%rip),%rdi
  lea    D98(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  lea    D63(%rip),%rdi
  call   <puts@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
L3:
  lea    0x2a(%rbx),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L3
  lea    D0(%rip),%rdi
  xor    %ebx,%ebx
  lea    D15(%rip),%rbp
  call   <puts@plt>
  movss  D71(%rip),%xmm0
L12:
  movsd  D65(%rip),%xmm1
  cvttss2si %xmm0,%edx
  cvtss2sd %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  mulsd  %xmm0,%xmm1
  imul   $0xffffff9c,%edx,%eax
  cvttsd2si %xmm1,%ecx
  add    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  D31(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    $0x4,%ebx
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D52
data_type: string
name: disassemble_data
arguments: data_label: D98
data_type: string
name: disassemble_data
arguments: data_label: D63
data_type: string
name: disassemble_data
arguments: data_label: D55
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D71
data_type: f32
name: disassemble_data
arguments: data_label: D65
data_type: f64
name: disassemble_data
arguments: data_label: D31
data_type: f64

tool: D52: 

LibC Test


tool: D98:     [%d] : %d == 0x%02x


tool: D63: compile time: Mar 15 2022 -- 21:52:22

tool: D55: gcc version:  9.4.0

tool: D23: Trying printf with int parameters:

tool: D0: Trying basic float operations:

tool: D15:     1.0 + (0.7 * %d) == %d.%d


tool: D71: 1

tool: D65: 100

tool: D31: 0.7

assistant: ```c
int main() {
  int i;
  int integer, fraction;
  float f = 1.0;
  printf("\n\nLibC Test\n\n");
  printf("compile time: "
         "Mar 15 2022"
         " -- "
         "21:52:22"
         "\n");
  printf("gcc version:  "
         "9.4.0"
         "\n");
  printf("Trying printf with int parameters:\n");
  for (i = 0; i < 4; i++) {
    printf("    [%d] : %d == 0x%02x\n", i, i + 42, i + 42);
  }
  printf("Trying basic float operations:\n");
  for (i = 0; i < 4; i++) {
    integer = (int)f;
    fraction = (int)(f * 100.0) - integer * 100;
    printf("    1.0 + (0.7 * %d) == %d.%d\n", i, integer, fraction);
    f = f + 0.7;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  lea    D50(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  lea    D95(%rip),%rdi
  call   <puts@plt>
  lea    D98(%rip),%rdi
  call   <puts@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
L0:
  lea    0x2a(%rbx),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L0
  lea    D31(%rip),%rdi
  xor    %ebx,%ebx
  lea    D2(%rip),%rbp
  call   <puts@plt>
  movss  D53(%rip),%xmm0
L13:
  movsd  D9(%rip),%xmm1
  cvttss2si %xmm0,%edx
  cvtss2sd %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  mulsd  %xmm0,%xmm1
  imul   $0xffffff9c,%edx,%eax
  cvttsd2si %xmm1,%ecx
  add    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  addsd  D4(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cmp    $0x4,%ebx
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D50
type_infered: string
name: unpack_data
arguments: data_label: D95
type_infered: string
name: unpack_data
arguments: data_label: D98
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D53
type_infered: f32
name: unpack_data
arguments: data_label: D9
type_infered: f64
name: unpack_data
arguments: data_label: D4
type_infered: f64

tool: D12: 

LibC Test


tool: D50:     [%d] : %d == 0x%02x


tool: D95: compile time: Mar 15 2022 -- 21:52:22

tool: D98: gcc version:  9.4.0

tool: D35: Trying printf with int parameters:

tool: D31: Trying basic float operations:

tool: D2:     1.0 + (0.7 * %d) == %d.%d


tool: D53: 1

tool: D9: 100

tool: D4: 0.7

assistant: ```c
int main() {
  int i;
  int integer, fraction;
  float f = 1.0;
  printf("\n\nLibC Test\n\n");
  printf("compile time: "
         "Mar 15 2022"
         " -- "
         "21:52:22"
         "\n");
  printf("gcc version:  "
         "9.4.0"
         "\n");
  printf("Trying printf with int parameters:\n");
  for (i = 0; i < 4; i++) {
    printf("    [%d] : %d == 0x%02x\n", i, i + 42, i + 42);
  }
  printf("Trying basic float operations:\n");
  for (i = 0; i < 4; i++) {
    integer = (int)f;
    fraction = (int)(f * 100.0) - integer * 100;
    printf("    1.0 + (0.7 * %d) == %d.%d\n", i, integer, fraction);
    f = f + 0.7;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x5,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L17
L12:
  mov    -0x20(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  shr    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  xor    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L12
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t calc_hash(const char *name) {
  size_t len = strlen(name);
  size_t h = len;
  size_t step = (len >> 5) + 1;
  size_t i;
  for (i = len; i >= step; i -= step)
    h = h ^ ((h << 5) + (h >> 2) + (size_t)name[i - 1]);
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    %rax,%rsi
  shr    $0x5,%rsi
  add    $0x1,%rsi
  cmp    %rsi,%rax
  jb     L16
L10:
  mov    %rcx,%rdx
  shl    $0x5,%rdx
  mov    %rcx,%rdi
  shr    $0x2,%rdi
  add    %rdi,%rdx
  movsbq -0x1(%rbx,%rax,1),%rdi
  add    %rdi,%rdx
  xor    %rdx,%rcx
  sub    %rsi,%rax
  cmp    %rax,%rsi
  jbe    L10
L16:
  mov    %rcx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t calc_hash(const char *name) {
  size_t len = strlen(name);
  size_t h = len;
  size_t step = (len >> 5) + 1;
  size_t i;
  for (i = len; i >= step; i -= step)
    h = h ^ ((h << 5) + (h >> 2) + (size_t)name[i - 1]);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calc_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rsi
  shr    $0x5,%rsi
  add    $0x1,%rsi
  cmp    %rsi,%rax
  jb     L17
  mov    %rax,%rcx
L3:
  mov    %rax,%rdx
  mov    %rax,%r8
  shr    $0x2,%r8
  shl    $0x5,%rdx
  add    %r8,%rdx
  movsbq -0x1(%rbx,%rcx,1),%r8
  sub    %rsi,%rcx
  add    %r8,%rdx
  xor    %rdx,%rax
  cmp    %rcx,%rsi
  jbe    L3
L17:
  pop    %rbx
  ret
```

assistant: ```c
size_t calc_hash(const char *name) {
  size_t len = strlen(name);
  size_t h = len;
  size_t step = (len >> 5) + 1;
  size_t i;
  for (i = len; i >= step; i -= step)
    h = h ^ ((h << 5) + (h >> 2) + (size_t)name[i - 1]);
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rsi
  shr    $0x5,%rsi
  add    $0x1,%rsi
  cmp    %rsi,%rax
  jb     L5
  mov    %rax,%rcx
L4:
  mov    %rax,%rdx
  mov    %rax,%r8
  shr    $0x2,%r8
  shl    $0x5,%rdx
  add    %r8,%rdx
  movsbq -0x1(%rbx,%rcx,1),%r8
  sub    %rsi,%rcx
  add    %r8,%rdx
  xor    %rdx,%rax
  cmp    %rcx,%rsi
  jbe    L4
L5:
  pop    %rbx
  ret
```

assistant: ```c
size_t calc_hash(const char *name) {
  size_t len = strlen(name);
  size_t h = len;
  size_t step = (len >> 5) + 1;
  size_t i;
  for (i = len; i >= step; i -= step)
    h = h ^ ((h << 5) + (h >> 2) + (size_t)name[i - 1]);
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L26
  mov    -0xc(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L40
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  shl    $0x2,%eax
  and    $0x3c,%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L36
L40:
  mov    -0xc(%rbp),%esi
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  and    $0xe,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  ror    %cl,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L36
L26:
  mov    -0xc(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  shl    $0x3,%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  mov    %eax,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    if (state[0UL] & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        state[0UL] |= (state[0UL] & 15U) << 2UL;
      } else {
        state[0UL] |= (((state[0UL] >> ((state[0UL] & 15U) | 1UL)) | (state[0UL] << (32 - ((state[0UL] & 15U) | 1UL)))) & 7U) << 2UL;
      }
    } else {
      state[0UL] |= (state[0UL] * state[0UL] & 31U) << 3UL;
    }
    output[0UL] = state[0UL] * 507365164UL >> 5U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x3686696a,%edx
  mov    %edx,%eax
  xor    $0xce5d000b,%eax
  test   $0x1,%dl
  jne    L12
  test   $0x2,%al
  je     L31
  lea    0x0(,%rax,4),%edx
  and    $0x3c,%edx
  or     %edx,%eax
  jmp    L13
L31:
  mov    %eax,%ecx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %eax,%edx
  ror    %cl,%edx
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
  jmp    L13
L12:
  mov    %eax,%edx
  imul   %eax,%edx
  shl    $0x3,%edx
  movzbl %dl,%edx
  or     %edx,%eax
L13:
  mov    %eax,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    if (state[0UL] & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        state[0UL] |= (state[0UL] & 15U) << 2UL;
      } else {
        state[0UL] |= (((state[0UL] >> ((state[0UL] & 15U) | 1UL)) | (state[0UL] << (32 - ((state[0UL] & 15U) | 1UL)))) & 7U) << 2UL;
      }
    } else {
      state[0UL] |= (state[0UL] * state[0UL] & 31U) << 3UL;
    }
    output[0UL] = state[0UL] * 507365164UL >> 5U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x3686696a,%edx
  mov    %edx,%eax
  xor    $0xce5d000b,%eax
  and    $0x1,%edx
  jne    L6
  test   $0x2,%al
  je     L0
  lea    0x0(,%rax,4),%edx
  and    $0x3c,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %eax,%edx
  imul   %eax,%edx
  shl    $0x3,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %eax,%ecx
  mov    %eax,%edx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%edx
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    if (state[0UL] & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        state[0UL] |= (state[0UL] & 15U) << 2UL;
      } else {
        state[0UL] |= (((state[0UL] >> ((state[0UL] & 15U) | 1UL)) | (state[0UL] << (32 - ((state[0UL] & 15U) | 1UL)))) & 7U) << 2UL;
      }
    } else {
      state[0UL] |= (state[0UL] * state[0UL] & 31U) << 3UL;
    }
    output[0UL] = state[0UL] * 507365164UL >> 5U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  add    $0x3686696a,%edx
  mov    %edx,%eax
  xor    $0xce5d000b,%eax
  and    $0x1,%edx
  jne    L13
  test   $0x2,%al
  je     L9
  lea    0x0(,%rax,4),%edx
  and    $0x3c,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %eax,%edx
  imul   %eax,%edx
  shl    $0x3,%edx
  movzbl %dl,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %eax,%ecx
  mov    %eax,%edx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%edx
  shl    $0x2,%edx
  and    $0x1c,%edx
  or     %edx,%eax
  imul   $0x1e3dc72c,%rax,%rax
  shr    $0x5,%rax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    if (state[0UL] & 1U) {
      if ((state[0UL] >> 1U) & 1U) {
        state[0UL] |= (state[0UL] & 15U) << 2UL;
      } else {
        state[0UL] |= (((state[0UL] >> ((state[0UL] & 15U) | 1UL)) | (state[0UL] << (32 - ((state[0UL] & 15U) | 1UL)))) & 7U) << 2UL;
      }
    } else {
      state[0UL] |= (state[0UL] * state[0UL] & 31U) << 3UL;
    }
    output[0UL] = state[0UL] * 507365164UL >> 5U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<soru_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L0
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int soru_8(int *ilk_eleman, int *son_eleman) {
  int dizi_toplam = 0;
  int *p;
  for (p = ilk_eleman; p <= son_eleman; p++) {
    dizi_toplam += *p;
  }
  return dizi_toplam;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<soru_8>:
  endbr64
  cmp    %rsi,%rdi
  ja     L6
  mov    $0x0,%eax
L0:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rsi
  jae    L0
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int soru_8(int *ilk_eleman, int *son_eleman) {
  int dizi_toplam = 0;
  int *p;
  for (p = ilk_eleman; p <= son_eleman; p++) {
    dizi_toplam += *p;
  }
  return dizi_toplam;
}
```
user: Translate the below assembly code into C programming language:

```asm
<soru_8>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  ja     L0
  nopl   0x0(%rax,%rax,1)
L10:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rsi
  jae    L10
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
int soru_8(int *ilk_eleman, int *son_eleman) {
  int dizi_toplam = 0;
  int *p;
  for (p = ilk_eleman; p <= son_eleman; p++) {
    dizi_toplam += *p;
  }
  return dizi_toplam;
}
```
user: What is the c source code of the assembly code below?

```asm
<soru_8>:
  endbr64
  cmp    %rsi,%rdi
  ja     L39
  mov    %rsi,%rdx
  mov    %rdi,%rax
  sub    %rdi,%rdx
  mov    %rdx,%rcx
  shr    $0x2,%rcx
  add    $0x1,%rcx
  cmp    $0xb,%rdx
  jbe    L68
  mov    %rcx,%rdx
  pxor   %xmm0,%xmm0
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   (%rax)
L21:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L21
  movdqa %xmm0,%xmm1
  mov    %rcx,%rdx
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffffc,%rdx
  paddd  %xmm1,%xmm0
  lea    (%rdi,%rdx,4),%rdi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %rdx,%rcx
  je     L40
L58:
  lea    0x4(%rdi),%rdx
  add    (%rdi),%eax
  cmp    %rdx,%rsi
  jb     L20
  lea    0x8(%rdi),%rdx
  add    0x4(%rdi),%eax
  cmp    %rdx,%rsi
  jb     L20
  add    0x8(%rdi),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
L20:
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  ret
L68:
  xor    %eax,%eax
  jmp    L58
```

assistant: ```c
int soru_8(int *ilk_eleman, int *son_eleman) {
  int dizi_toplam = 0;
  int *p;
  for (p = ilk_eleman; p <= son_eleman; p++) {
    dizi_toplam += *p;
  }
  return dizi_toplam;
}
```