ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<real_fc_strdup>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r14,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    0x1(%rax),%rdi
  call   <fc_real_malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *real_fc_strdup(const char *str, const char *called_as, int line, const char *file) {
  char *dest = fc_real_malloc(strlen(str) + 1, called_as, line, file);
  strcpy(dest, str);
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sss_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x8,%edx
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fwrite_base32hex@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D19: {"data":

tool: D2: ,"expire":%lld},

assistant: ```c
int sss_val(void *ctx, char *val, int vallen, long long val_expire) {
  FILE *fp = ctx;
  fputs("{\"data\":", fp);
  fwrite_base32hex(val, vallen, fp);
  fprintf(fp, ",\"expire\":%lld},", val_expire);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sss_val>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%rbp
  mov    %rdi,%rcx
  mov    $0x8,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <fwrite_base32hex@plt>
  mov    %rbp,%rdx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D19
datatype: string

tool: D16: {"data":

tool: D19: ,"expire":%lld},

assistant: ```c
int sss_val(void *ctx, char *val, int vallen, long long val_expire) {
  FILE *fp = ctx;
  fputs("{\"data\":", fp);
  fwrite_base32hex(val, vallen, fp);
  fprintf(fp, ",\"expire\":%lld},", val_expire);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sss_val>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  mov    $0x8,%edx
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rcx,%r12
  mov    %rdi,%rcx
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <fwrite_base32hex@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D10
data_type: string

tool: D13: {"data":

tool: D10: ,"expire":%lld},

assistant: ```c
int sss_val(void *ctx, char *val, int vallen, long long val_expire) {
  FILE *fp = ctx;
  fputs("{\"data\":", fp);
  fwrite_base32hex(val, vallen, fp);
  fprintf(fp, ",\"expire\":%lld},", val_expire);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sss_val>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  mov    $0x8,%edx
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  mov    %rcx,%r12
  mov    %rdi,%rcx
  push   %rbp
  mov    %rdi,%rbp
  lea    D12(%rip),%rdi
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %rbp,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <fwrite_base32hex@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string

tool: D12: {"data":

tool: D1: ,"expire":%lld},

assistant: ```c
int sss_val(void *ctx, char *val, int vallen, long long val_expire) {
  FILE *fp = ctx;
  fputs("{\"data\":", fp);
  fwrite_base32hex(val, vallen, fp);
  fprintf(fp, ",\"expire\":%lld},", val_expire);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_is_value_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L3:
  mov    $0xffffffff,%eax
  jmp    L0
L5:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int _is_value_set(const char *value) {
  if (NULL == value || '\0' == *value) {
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_is_value_set>:
  endbr64
  test   %rdi,%rdi
  je     L7
  cmpb   $0x1,(%rdi)
  sbb    %eax,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _is_value_set(const char *value) {
  if (NULL == value || '\0' == *value) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_is_value_set>:
  endbr64
  test   %rdi,%rdi
  je     L0
  cmpb   $0x1,(%rdi)
  sbb    %eax,%eax
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _is_value_set(const char *value) {
  if (NULL == value || '\0' == *value) {
    return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_is_value_set>:
  endbr64
  test   %rdi,%rdi
  je     L0
  cmpb   $0x1,(%rdi)
  sbb    %eax,%eax
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _is_value_set(const char *value) {
  if (NULL == value || '\0' == *value) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L101
L33:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L101
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L101
  jmp    L36
L60:
  addq   $0x1,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L112
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L60
L112:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L27
  mov    $0xfffffffc,%eax
  jmp    L10
L27:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L10
L101:
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <next_header@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L33
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L92
  mov    $0xffffffff,%eax
  jmp    L10
L92:
  mov    $0xfffffffe,%eax
L10:
  leave
  ret
```

assistant: ```c
int get_header(const char *header, const char *data, size_t data_len, char **value) {
  size_t len, header_len;
  header_len = strlen(header);
  while ((len = next_header(&data, &data_len)) != 0)
    if (len > header_len && strncasecmp(header, data, header_len) == 0) {
      while (header_len < len && isblank(data[header_len]))
        header_len++;
      *value = malloc(len - header_len + 1);
      if (*value == NULL)
        return -4;
      strncpy(*value, data + header_len, len - header_len);
      (*value)[len - header_len] = '\0';
      return len - header_len;
    }
  if (data_len == 0)
    return -1;
  return -2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_header>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %rcx,%r14
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %rsp,%r12
L6:
  lea    0x8(%rsp),%rdi
  mov    %r12,%rsi
  call   <next_header@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L22
  cmp    %rbx,%rbp
  jae    L6
  mov    %rbp,%rdx
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L6
L66:
  mov    0x8(%rsp),%rax
  movsbl (%rax,%rbp,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  je     L24
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  ja     L66
L24:
  mov    %rbx,%r12
  sub    %rbp,%r12
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%r14)
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  add    0x8(%rsp),%rsi
  mov    %r12,%rdx
  call   <strncpy@plt>
  mov    (%r14),%rax
  movb   $0x0,(%rax,%r12,1)
  mov    %ebx,%eax
  sub    %ebp,%eax
  jmp    L74
L22:
  cmpq   $0x1,(%rsp)
  mov    $0xfffffffe,%eax
  adc    $0x0,%eax
L74:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  mov    $0xfffffffc,%eax
  jmp    L74
```

assistant: ```c
int get_header(const char *header, const char *data, size_t data_len, char **value) {
  size_t len, header_len;
  header_len = strlen(header);
  while ((len = next_header(&data, &data_len)) != 0)
    if (len > header_len && strncasecmp(header, data, header_len) == 0) {
      while (header_len < len && isblank(data[header_len]))
        header_len++;
      *value = malloc(len - header_len + 1);
      if (*value == NULL)
        return -4;
      strncpy(*value, data + header_len, len - header_len);
      (*value)[len - header_len] = '\0';
      return len - header_len;
    }
  if (data_len == 0)
    return -1;
  return -2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_header>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x18(%rsp),%rbp
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,%r15
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %r14,%rbx
  jb     L12
L73:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <next_header@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L1
  cmpq   $0x1,0x10(%rsp)
  mov    $0xfffffffe,%eax
  adc    $0x0,%eax
L61:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L73
  jmp    L56
  nop
L80:
  add    $0x1,%r15
  cmp    %r15,%r14
  jbe    L79
L56:
  mov    0x18(%rsp),%rax
  movsbl (%rax,%r15,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L80
L79:
  mov    %r14,%rbx
  sub    %r15,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rbp
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L25
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdx
  add    %r15,%rsi
  call   <strncpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%rbx,1)
  mov    %r14d,%eax
  sub    %r15d,%eax
  jmp    L61
L25:
  mov    $0xfffffffc,%eax
  jmp    L61
```

assistant: ```c
int get_header(const char *header, const char *data, size_t data_len, char **value) {
  size_t len, header_len;
  header_len = strlen(header);
  while ((len = next_header(&data, &data_len)) != 0)
    if (len > header_len && strncasecmp(header, data, header_len) == 0) {
      while (header_len < len && isblank(data[header_len]))
        header_len++;
      *value = malloc(len - header_len + 1);
      if (*value == NULL)
        return -4;
      strncpy(*value, data + header_len, len - header_len);
      (*value)[len - header_len] = '\0';
      return len - header_len;
    }
  if (data_len == 0)
    return -1;
  return -2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_header>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x18(%rsp),%rbp
  mov    %rdx,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,%r15
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    %r14,%rbx
  jb     L86
L65:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <next_header@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L44
  cmpq   $0x1,0x10(%rsp)
  mov    $0xfffffffe,%eax
  adc    $0x0,%eax
L16:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L86:
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L65
  jmp    L71
  nop
L40:
  add    $0x1,%r15
  cmp    %r15,%r14
  jbe    L43
L71:
  mov    0x18(%rsp),%rax
  movsbl (%rax,%r15,1),%edi
  call   <isblank@plt>
  test   %rax,%rax
  jne    L40
L43:
  mov    %r14,%rbx
  sub    %r15,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rbp
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L51
  mov    0x18(%rsp),%rsi
  mov    %rbx,%rdx
  add    %r15,%rsi
  call   <strncpy@plt>
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%rbx,1)
  mov    %r14d,%eax
  sub    %r15d,%eax
  jmp    L16
L51:
  mov    $0xfffffffc,%eax
  jmp    L16
```

assistant: ```c
int get_header(const char *header, const char *data, size_t data_len, char **value) {
  size_t len, header_len;
  header_len = strlen(header);
  while ((len = next_header(&data, &data_len)) != 0)
    if (len > header_len && strncasecmp(header, data, header_len) == 0) {
      while (header_len < len && isblank(data[header_len]))
        header_len++;
      *value = malloc(len - header_len + 1);
      if (*value == NULL)
        return -4;
      strncpy(*value, data + header_len, len - header_len);
      (*value)[len - header_len] = '\0';
      return len - header_len;
    }
  if (data_len == 0)
    return -1;
  return -2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  je     L92
  lea    -0x3c(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  jmp    L116
L55:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L152
  orq    $0x0,-0x8(%rsp,%rdx,1)
L152:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L135
  mov    %r12,%r13
  mov    $0x0,%ebx
L68:
  mov    %r13,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x3c(%rbp),%edx
  add    $0x4,%r13
  cmp    %ebx,%edx
  jg     L68
  test   %edx,%edx
  jle    L142
  mov    $0x0,%ebx
  mov    $0x0,%r15d
  mov    $0xffffffff,%r13d
  mov    $0xffffffff,%r14d
  jmp    L108
L124:
  mov    (%r12,%rbx,4),%r13d
  add    $0x1,%r15d
L99:
  mov    -0x3c(%rbp),%edx
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jle    L76
L108:
  mov    (%r12,%rbx,4),%eax
  cmp    %r13d,%eax
  je     L99
  cmp    %r14d,%eax
  je     L99
  lea    0x1(%rbx),%esi
  mov    %r13d,%r8d
  mov    %r14d,%ecx
  mov    %r12,%rdi
  call   <min@plt>
  test   %rax,%rax
  jne    L124
  mov    (%r12,%rbx,4),%r14d
  add    $0x1,%r15d
  jmp    L99
L135:
  mov    $0x0,%r15d
L76:
  mov    %r15d,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    -0x48(%rbp),%rsp
  mov    -0x40(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  je     L92
L116:
  mov    %rsp,-0x48(%rbp)
  mov    -0x50(%rbp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ecx
  movslq %ecx,%rax
  lea    0xf(,%rax,4),%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  mov    %rsp,%rdx
  sub    %rsi,%rdx
L25:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L142:
  mov    $0x0,%r15d
  jmp    L76
L92:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type: string
name: parse_data
arguments: label: D37
type: string

tool: D24: %d

tool: D37: %d


assistant: ```c
int main() {
  int test;
  scanf("%d", &test);
  while (test--) {
    int n;
    scanf("%d", &n);
    int arr[n];
    int i;
    for (i = 0; i < n; i++) {
      scanf("%d", &arr[i]);
    }
    int p1 = -1, p2 = -1;
    int count = 0;
    for (i = 0; i < n; i++) {
      if (p1 == arr[i] || p2 == arr[i])
        continue;
      if (min(arr, i + 1, n, p1, p2) == 0) {
        p1 = arr[i];
        count++;
      } else {
        p2 = arr[i];
        count++;
      }
    }
    printf("%d\n", count);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  lea    -0x3c(%rbp),%rcx
  mov    %rcx,-0x58(%rbp)
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  je     L107
L132:
  mov    -0x58(%rbp),%rsi
  mov    %r12,%rdi
  mov    %rsp,-0x50(%rbp)
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L68
L12:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L12
L68:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L72
  orq    $0x0,-0x8(%rsp,%rdx,1)
L72:
  mov    %rsp,%rbx
  xor    %r13d,%r13d
  mov    %rbx,%r14
  test   %edi,%edi
  jle    L38
  nopl   0x0(%rax)
L93:
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    -0x3c(%rbp),%edx
  cmp    %r13d,%edx
  jg     L93
  test   %edx,%edx
  jle    L38
  xor    %r9d,%r9d
  xor    %r14d,%r14d
  mov    $0xffffffff,%r13d
  mov    $0xffffffff,%r15d
  jmp    L159
  nop
L128:
  mov    (%rbx,%r9,4),%r15d
  mov    -0x3c(%rbp),%edx
L75:
  add    $0x1,%r9
  cmp    %r9d,%edx
  jle    L34
L159:
  mov    (%rbx,%r9,4),%eax
  lea    0x1(%r9),%esi
  cmp    %r13d,%eax
  je     L75
  cmp    %r15d,%eax
  je     L75
  mov    %r13d,%r8d
  mov    %r15d,%ecx
  mov    %rbx,%rdi
  mov    %r9,-0x48(%rbp)
  call   <min@plt>
  add    $0x1,%r14d
  mov    -0x48(%rbp),%r9
  test   %rax,%rax
  je     L128
  mov    -0x3c(%rbp),%edx
  mov    (%rbx,%r9,4),%r13d
  add    $0x1,%r9
  cmp    %r9d,%edx
  jg     L159
L34:
  mov    %r14d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    -0x50(%rbp),%rsp
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  jne    L132
L107:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L38:
  xor    %r14d,%r14d
  jmp    L34
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D8
data_type: string

tool: D19: %d

tool: D8: %d


assistant: ```c
int main() {
  int test;
  scanf("%d", &test);
  while (test--) {
    int n;
    scanf("%d", &n);
    int arr[n];
    int i;
    for (i = 0; i < n; i++) {
      scanf("%d", &arr[i]);
    }
    int p1 = -1, p2 = -1;
    int count = 0;
    for (i = 0; i < n; i++) {
      if (p1 == arr[i] || p2 == arr[i])
        continue;
      if (min(arr, i + 1, n, p1, p2) == 0) {
        p1 = arr[i];
        count++;
      } else {
        p2 = arr[i];
        count++;
      }
    }
    printf("%d\n", count);
  }
  return 0;
}
```