ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strdepad>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L1
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L44
L1:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  add    $0x1,%rbx
L44:
  movsbl (%rbx),%edi
  call   <is_padding@plt>
  test   %rax,%rax
  jne    L57
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  cmp    %rbp,%rbx
  je     L39
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
L39:
  lea    -0x1(%rbp,%r12,1),%rbx
  test   %r12,%r12
  je     L1
L5:
  movsbl (%rbx),%edi
  call   <is_padding@plt>
  test   %rax,%rax
  je     L1
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  jmp    L5
```

assistant: ```c
char *strdepad(char *str) {
  char *temp;
  size_t len;
  if (!str)
    return str;
  if (!*str)
    return str;
  temp = str;
  while (is_padding(*temp))
    ++temp;
  len = strlen(str);
  if (temp != str)
    memmove(str, temp, len + 1);
  if (len) {
    temp = str + (len - 1);
    while (is_padding(*temp))
      *(temp--) = 0;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strdepad>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L20
  movsbl (%rdi),%edi
  mov    %r12,%rbp
  test   %dil,%dil
  jne    L22
  jmp    L20
  nopl   (%rax)
L21:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
L22:
  call   <is_padding@plt>
  test   %rax,%rax
  jne    L21
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  cmp    %r12,%rbp
  je     L47
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L47:
  lea    -0x1(%r12,%rbx,1),%rbp
  test   %rbx,%rbx
  jne    L38
L20:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
L38:
  movsbl 0x0(%rbp),%edi
  call   <is_padding@plt>
  test   %rax,%rax
  jne    L63
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdepad(char *str) {
  char *temp;
  size_t len;
  if (!str)
    return str;
  if (!*str)
    return str;
  temp = str;
  while (is_padding(*temp))
    ++temp;
  len = strlen(str);
  if (temp != str)
    memmove(str, temp, len + 1);
  if (len) {
    temp = str + (len - 1);
    while (is_padding(*temp))
      *(temp--) = 0;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strdepad>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  jne    L35
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L53:
  add    $0x1,%rbp
L35:
  movsbl 0x0(%rbp),%edi
  call   <is_padding@plt>
  test   %rax,%rax
  jne    L53
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  cmp    %r12,%rbp
  je     L6
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L6:
  lea    -0x1(%r12,%rbx,1),%rbp
  test   %rbx,%rbx
  jne    L3
L64:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
L3:
  movsbl 0x0(%rbp),%edi
  call   <is_padding@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strdepad(char *str) {
  char *temp;
  size_t len;
  if (!str)
    return str;
  if (!*str)
    return str;
  temp = str;
  while (is_padding(*temp))
    ++temp;
  len = strlen(str);
  if (temp != str)
    memmove(str, temp, len + 1);
  if (len) {
    temp = str + (len - 1);
    while (is_padding(*temp))
      *(temp--) = 0;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L5
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%r12d
  cmp    %r12d,%ebx
  je     L47
  mov    %ebx,%eax
  sub    %r12d,%eax
  jmp    L24
L47:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L24:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int strcasecmp(char *s1, char *s2) {
  register int c1, c2;
  while (*s1 && *s2) {
    c1 = tolower((unsigned char)*s1);
    c2 = tolower((unsigned char)*s2);
    if (c1 != c2)
      return (c1 - c2);
    s1++;
    s2++;
  }
  return (int)(*s1 - *s2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L37
L7:
  cmpb   $0x0,0x0(%rbp)
  je     L37
  movzbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L13
  add    $0x1,%r12
  add    $0x1,%rbp
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L7
L37:
  movsbl %dil,%ebx
  movsbl 0x0(%rbp),%eax
  sub    %eax,%ebx
L11:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  sub    %eax,%ebx
  jmp    L11
```

assistant: ```c
int strcasecmp(char *s1, char *s2) {
  register int c1, c2;
  while (*s1 && *s2) {
    c1 = tolower((unsigned char)*s1);
    c2 = tolower((unsigned char)*s2);
    if (c1 != c2)
      return (c1 - c2);
    s1++;
    s2++;
  }
  return (int)(*s1 - *s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rsi),%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L36
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L0:
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L42
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  lea    0x1(%rbp),%rax
  test   %dil,%dil
  je     L46
  mov    %rax,%rbp
L36:
  movsbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L0
  movsbl %dil,%ebx
L42:
  sub    %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L46:
  movsbl 0x1(%rbp),%eax
L37:
  xor    %ebx,%ebx
  sub    %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(char *s1, char *s2) {
  register int c1, c2;
  while (*s1 && *s2) {
    c1 = tolower((unsigned char)*s1);
    c2 = tolower((unsigned char)*s2);
    if (c1 != c2)
      return (c1 - c2);
    s1++;
    s2++;
  }
  return (int)(*s1 - *s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rsi),%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L39
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L27:
  call   <tolower@plt>
  movzbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L19
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  lea    0x1(%rbp),%rax
  test   %dil,%dil
  je     L30
  mov    %rax,%rbp
L39:
  movsbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L27
  movsbl %dil,%ebx
L19:
  sub    %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L30:
  movsbl 0x1(%rbp),%eax
L11:
  xor    %ebx,%ebx
  sub    %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(char *s1, char *s2) {
  register int c1, c2;
  while (*s1 && *s2) {
    c1 = tolower((unsigned char)*s1);
    c2 = tolower((unsigned char)*s2);
    if (c1 != c2)
      return (c1 - c2);
    s1++;
    s2++;
  }
  return (int)(*s1 - *s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aligned_block_copy_backwards_bs64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  shl    $0x2,%rax
  sub    $0x20,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  shl    $0x2,%rax
  sub    $0x20,%rax
  add    %rax,-0x8(%rbp)
  jmp    L12
L6:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x14(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x18(%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x1c(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1c(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  subq   $0x20,-0x30(%rbp)
  subq   $0x20,-0x8(%rbp)
L12:
  subl   $0x40,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void aligned_block_copy_backwards_bs64(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t t1, t2, t3, t4;
  src += size / 8 - 8;
  dst += size / 8 - 8;
  while ((size -= 64) >= 0) {
    t1 = src[0];
    t2 = src[1];
    t3 = src[2];
    t4 = src[3];
    dst[0] = t1;
    dst[1] = t2;
    dst[2] = t3;
    dst[3] = t4;
    t1 = src[4];
    t2 = src[5];
    t3 = src[6];
    t4 = src[7];
    dst[4] = t1;
    dst[5] = t2;
    dst[6] = t3;
    dst[7] = t4;
    src -= 8;
    dst -= 8;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<aligned_block_copy_backwards_bs64>:
  endbr64
  mov    %rsi,%rax
  lea    0x7(%rdx),%esi
  test   %edx,%edx
  cmovns %edx,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  lea    -0x20(,%rsi,4),%rsi
  add    %rsi,%rax
  lea    (%rdi,%rsi,1),%rcx
  cmp    $0x3f,%edx
  jle    L17
  sub    $0x40,%edx
  shr    $0x6,%edx
  add    $0x1,%edx
  mov    %edx,%edx
  shl    $0x5,%rdx
  mov    %rax,%r9
  sub    %rdx,%r9
L19:
  mov    (%rax),%r8d
  mov    0x4(%rax),%edi
  mov    0x8(%rax),%esi
  mov    0xc(%rax),%edx
  mov    %r8d,(%rcx)
  mov    %edi,0x4(%rcx)
  mov    %esi,0x8(%rcx)
  mov    %edx,0xc(%rcx)
  mov    0x10(%rax),%r8d
  mov    0x14(%rax),%edi
  mov    0x18(%rax),%esi
  mov    0x1c(%rax),%edx
  mov    %r8d,0x10(%rcx)
  mov    %edi,0x14(%rcx)
  mov    %esi,0x18(%rcx)
  mov    %edx,0x1c(%rcx)
  sub    $0x20,%rax
  sub    $0x20,%rcx
  cmp    %r9,%rax
  jne    L19
L17:
  ret
```

assistant: ```c
void aligned_block_copy_backwards_bs64(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t t1, t2, t3, t4;
  src += size / 8 - 8;
  dst += size / 8 - 8;
  while ((size -= 64) >= 0) {
    t1 = src[0];
    t2 = src[1];
    t3 = src[2];
    t4 = src[3];
    dst[0] = t1;
    dst[1] = t2;
    dst[2] = t3;
    dst[3] = t4;
    t1 = src[4];
    t2 = src[5];
    t3 = src[6];
    t4 = src[7];
    dst[4] = t1;
    dst[5] = t2;
    dst[6] = t3;
    dst[7] = t4;
    src -= 8;
    dst -= 8;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<aligned_block_copy_backwards_bs64>:
  endbr64
  mov    %rsi,%r8
  test   %edx,%edx
  lea    0x7(%rdx),%esi
  cmovns %edx,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  lea    -0x20(,%rsi,4),%rsi
  lea    (%r8,%rsi,1),%rax
  lea    (%rdi,%rsi,1),%rcx
  cmp    $0x3f,%edx
  jle    L4
  sub    $0x40,%edx
  mov    %rax,%r9
  shr    $0x6,%edx
  add    $0x1,%edx
  shl    $0x5,%rdx
  sub    %rdx,%r9
  nopl   (%rax)
L12:
  mov    (%rax),%r8d
  mov    0x4(%rax),%edi
  sub    $0x20,%rax
  sub    $0x20,%rcx
  mov    0x28(%rax),%esi
  mov    0x2c(%rax),%edx
  mov    %r8d,0x20(%rcx)
  mov    0x30(%rax),%r8d
  mov    %edi,0x24(%rcx)
  mov    0x34(%rax),%edi
  mov    %esi,0x28(%rcx)
  mov    0x38(%rax),%esi
  mov    %edx,0x2c(%rcx)
  mov    0x3c(%rax),%edx
  mov    %r8d,0x30(%rcx)
  mov    %edi,0x34(%rcx)
  mov    %esi,0x38(%rcx)
  mov    %edx,0x3c(%rcx)
  cmp    %r9,%rax
  jne    L12
L4:
  ret
```

assistant: ```c
void aligned_block_copy_backwards_bs64(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t t1, t2, t3, t4;
  src += size / 8 - 8;
  dst += size / 8 - 8;
  while ((size -= 64) >= 0) {
    t1 = src[0];
    t2 = src[1];
    t3 = src[2];
    t4 = src[3];
    dst[0] = t1;
    dst[1] = t2;
    dst[2] = t3;
    dst[3] = t4;
    t1 = src[4];
    t2 = src[5];
    t3 = src[6];
    t4 = src[7];
    dst[4] = t1;
    dst[5] = t2;
    dst[6] = t3;
    dst[7] = t4;
    src -= 8;
    dst -= 8;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aligned_block_copy_backwards_bs64>:
  endbr64
  mov    %rsi,%r8
  test   %edx,%edx
  lea    0x7(%rdx),%esi
  cmovns %edx,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  lea    -0x20(,%rsi,4),%rsi
  lea    (%r8,%rsi,1),%rax
  lea    (%rdi,%rsi,1),%rcx
  cmp    $0x3f,%edx
  jle    L7
  sub    $0x40,%edx
  mov    %rax,%r9
  shr    $0x6,%edx
  add    $0x1,%edx
  shl    $0x5,%rdx
  sub    %rdx,%r9
  nopl   (%rax)
L10:
  mov    (%rax),%r8d
  mov    0x4(%rax),%edi
  sub    $0x20,%rax
  sub    $0x20,%rcx
  mov    0x28(%rax),%esi
  mov    0x2c(%rax),%edx
  mov    %r8d,0x20(%rcx)
  mov    0x30(%rax),%r8d
  mov    %edi,0x24(%rcx)
  mov    0x34(%rax),%edi
  mov    %esi,0x28(%rcx)
  mov    0x38(%rax),%esi
  mov    %edx,0x2c(%rcx)
  mov    0x3c(%rax),%edx
  mov    %r8d,0x30(%rcx)
  mov    %edi,0x34(%rcx)
  mov    %esi,0x38(%rcx)
  mov    %edx,0x3c(%rcx)
  cmp    %r9,%rax
  jne    L10
L7:
  ret
```

assistant: ```c
void aligned_block_copy_backwards_bs64(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t t1, t2, t3, t4;
  src += size / 8 - 8;
  dst += size / 8 - 8;
  while ((size -= 64) >= 0) {
    t1 = src[0];
    t2 = src[1];
    t3 = src[2];
    t4 = src[3];
    dst[0] = t1;
    dst[1] = t2;
    dst[2] = t3;
    dst[3] = t4;
    t1 = src[4];
    t2 = src[5];
    t3 = src[6];
    t4 = src[7];
    dst[4] = t1;
    dst[5] = t2;
    dst[6] = t3;
    dst[7] = t4;
    src -= 8;
    dst -= 8;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L43:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L12
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L12:
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
L10:
  cmpl   $0x0,-0x4(%rbp)
  jle    L9
  mov    -0x8(%rbp),%eax
  jmp    L16
L9:
  mov    $0xffffffff,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int cindex(char c, const char *str) {
  int i = 0, found = 0;
  while (*str != '\0') {
    if (*str == c) {
      found = 1;
      break;
    }
    str++;
    i++;
  }
  return (found > 0) ? i : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cindex>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L18
  mov    $0x0,%eax
L34:
  mov    %eax,%ecx
  cmp    %dl,%dil
  je     L4
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L34
  mov    $0xffffffff,%ecx
L4:
  mov    %ecx,%eax
  ret
L18:
  mov    $0xffffffff,%ecx
  jmp    L4
```

assistant: ```c
int cindex(char c, const char *str) {
  int i = 0, found = 0;
  while (*str != '\0') {
    if (*str == c) {
      found = 1;
      break;
    }
    str++;
    i++;
  }
  return (found > 0) ? i : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cindex>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L37
  xor    %eax,%eax
  jmp    L38
  nop
L27:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L37
L38:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L27
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cindex(char c, const char *str) {
  int i = 0, found = 0;
  while (*str != '\0') {
    if (*str == c) {
      found = 1;
      break;
    }
    str++;
    i++;
  }
  return (found > 0) ? i : -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cindex>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
  xor    %eax,%eax
  jmp    L9
  nop
L28:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L3
L9:
  mov    %eax,%r8d
  cmp    %dl,%dil
  jne    L28
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cindex(char c, const char *str) {
  int i = 0, found = 0;
  while (*str != '\0') {
    if (*str == c) {
      found = 1;
      break;
    }
    str++;
    i++;
  }
  return (found > 0) ? i : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L49
L8:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    -0x40(%rbp),%rax
  lea    (%rax,%rax,1),%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  imul   -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jns    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L49
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L49:
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  ja     L8
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L20
  mov    -0x18(%rbp),%rax
  jmp    L7
L20:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  if (compar(left, key) == 0) {
    return left;
  } else {
    return NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %r8,%r14
  imul   %rcx,%rdx
  lea    (%rsi,%rdx,1),%r12
  lea    (%rsi,%rcx,1),%rax
  cmp    %rax,%r12
  jbe    L0
  mov    %rcx,%r13
  lea    (%rcx,%rcx,1),%rax
  mov    %rax,0x8(%rsp)
L15:
  mov    %r12,%rax
  sub    %rbp,%rax
  mov    $0x0,%edx
  divq   0x8(%rsp)
  imul   %r13,%rax
  lea    0x0(%rbp,%rax,1),%rbx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   *%r14
  test   %eax,%eax
  cmovns %rbx,%rbp
  cmovs  %rbx,%r12
  lea    0x0(%rbp,%r13,1),%rax
  cmp    %rax,%r12
  ja     L15
L0:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   *%r14
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne %rax,%rbp
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  if (compar(left, key) == 0) {
    return left;
  } else {
    return NULL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bsearch>:
  endbr64
  imul   %rcx,%rdx
  push   %r15
  lea    (%rsi,%rcx,1),%rax
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    (%rsi,%rdx,1),%r14
  mov    %r8,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %rax,%r14
  jbe    L9
  lea    (%rcx,%rcx,1),%rax
  mov    %rcx,%r15
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r14,%rax
  xor    %edx,%edx
  mov    %rbp,%rdi
  sub    %r13,%rax
  divq   0x8(%rsp)
  imul   %r15,%rax
  lea    0x0(%r13,%rax,1),%rbx
  mov    %rbx,%rsi
  call   *%r12
  test   %eax,%eax
  cmovns %rbx,%r13
  cmovs  %rbx,%r14
  lea    0x0(%r13,%r15,1),%rax
  cmp    %rax,%r14
  ja     L3
L9:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   *%r12
  test   %eax,%eax
  mov    $0x0,%eax
  cmovne %rax,%r13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  void *left = (void *)base, *right = (void *)base + size * nmemb, *mid;
  while (left + size < right) {
    mid = left + ((right - left) / (size << 1) * size);
    if (compar(key, mid) < 0) {
      right = mid;
    } else {
      left = mid;
    }
  }
  if (compar(left, key) == 0) {
    return left;
  } else {
    return NULL;
  }
}
```