ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L48
L17:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L48:
  cmpl   $0x9,-0x38(%rbp)
  jle    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L32
L46:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L32:
  cmpl   $0x9,-0x34(%rbp)
  jle    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D25
datatype: string
name: read_data
arguments: data_label: D10
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D25: t2 :

tool: D10: %d 

tool: D14: %hx 

assistant: ```c
void f2(void) {
  int t2[10];
  printf("t2 :\n");
  for (int i = 0; i < 10; i++)
    printf("%d ", t2[i]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    printf("%hx ", t2 + i);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<f2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rbp
  lea    D29(%rip),%r13
L19:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D28(%rip),%rbp
L26:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D28
datatype: string

tool: D7: t2 :

tool: D29: %d 

tool: D28: %hx 

assistant: ```c
void f2(void) {
  int t2[10];
  printf("t2 :\n");
  for (int i = 0; i < 10; i++)
    printf("%d ", t2[i]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    printf("%hx ", t2 + i);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f2>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  call   <puts@plt>
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L21:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L21
  mov    $0xa,%edi
  lea    D16(%rip),%rbp
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D14
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string

tool: D3: t2 :

tool: D14: %d 

tool: D16: %hx 

assistant: ```c
void f2(void) {
  int t2[10];
  printf("t2 :\n");
  for (int i = 0; i < 10; i++)
    printf("%d ", t2[i]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    printf("%hx ", t2 + i);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<f2>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  call   <puts@plt>
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L0:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L0
  mov    $0xa,%edi
  lea    D10(%rip),%rbp
  call   <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D27: t2 :

tool: D18: %d 

tool: D10: %hx 

assistant: ```c
void f2(void) {
  int t2[10];
  printf("t2 :\n");
  for (int i = 0; i < 10; i++)
    printf("%d ", t2[i]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    printf("%hx ", t2 + i);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L41
  mov    $0x0,%eax
  jmp    L46
L41:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <log10@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L34
L33:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%edi
  mov    -0x24(%rbp),%eax
  cltd
  idiv   %edi
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    %edx,%ebx
  jne    L40
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L42
L40:
  mov    -0x18(%rbp),%eax
  jmp    L46
L42:
  addl   $0x1,-0x20(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x20(%rbp)
  jl     L33
  movl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
L46:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int isPalindrome(int n) {
  int result = 0;
  if (n < 0) {
    return 0;
  }
  int digit = log10(n), i = 0, high = pow(10.0, digit);
  ++digit;
  for (i = 0; i < digit / 2; ++i) {
    if ((int)(n / high) % 10 == (int)(n / pow(10, i)) % 10) {
      high /= 10;
      continue;
    } else
      return result;
  }
  result = 1;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isPalindrome>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L16
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  call   <log10@plt>
  mov    %eax,%r13d
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    0x1(%r13),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  test   %r13d,%r13d
  jle    L31
  mov    $0x0,%r13d
L22:
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%esi
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %esi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    %eax,%ecx
  je     L5
  mov    $0x0,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%ebp
  add    $0x1,%r13d
  cmp    %r12d,%r13d
  jl     L22
  mov    $0x1,%eax
  jmp    L27
L31:
  mov    $0x1,%eax
  jmp    L27
L16:
  ret
```

assistant: ```c
int isPalindrome(int n) {
  int result = 0;
  if (n < 0) {
    return 0;
  }
  int digit = log10(n), i = 0, high = pow(10.0, digit);
  ++digit;
  for (i = 0; i < digit / 2; ++i) {
    if ((int)(n / high) % 10 == (int)(n / pow(10, i)) % 10) {
      high /= 10;
      continue;
    } else
      return result;
  }
  result = 1;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  js     L20
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <log10@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  mov    %eax,%r14d
  call   <pow@plt>
  mov    %eax,%ebp
  lea    0x1(%r14),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  test   %r14d,%r14d
  jle    L16
L25:
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    %eax,%ecx
  je     L24
  xor    %eax,%eax
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movslq %ebp,%rax
  mov    %ebp,%edx
  add    $0x1,%r13d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%ebp
  cmp    %ebx,%r13d
  jl     L25
L16:
  mov    $0x1,%eax
  jmp    L38
```

assistant: ```c
int isPalindrome(int n) {
  int result = 0;
  if (n < 0) {
    return 0;
  }
  int digit = log10(n), i = 0, high = pow(10.0, digit);
  ++digit;
  for (i = 0; i < digit / 2; ++i) {
    if ((int)(n / high) % 10 == (int)(n / pow(10, i)) % 10) {
      high /= 10;
      continue;
    } else
      return result;
  }
  result = 1;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  js     L24
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <log10@plt>
  mov    $0xa,%edi
  mov    %eax,%esi
  mov    %eax,%r14d
  call   <pow@plt>
  mov    %eax,%ebp
  lea    0x1(%r14),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  test   %r14d,%r14d
  jle    L25
L7:
  mov    %r13d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %ebp
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cmp    %eax,%ecx
  je     L32
  xor    %eax,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  movslq %ebp,%rax
  mov    %ebp,%edx
  add    $0x1,%r13d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%ebp
  cmp    %ebx,%r13d
  jl     L7
L25:
  mov    $0x1,%eax
  jmp    L3
```

assistant: ```c
int isPalindrome(int n) {
  int result = 0;
  if (n < 0) {
    return 0;
  }
  int digit = log10(n), i = 0, high = pow(10.0, digit);
  ++digit;
  for (i = 0; i < digit / 2; ++i) {
    if ((int)(n / high) % 10 == (int)(n / pow(10, i)) % 10) {
      high /= 10;
      continue;
    } else
      return result;
  }
  result = 1;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AmbiguousReferenceErrorMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D75(%rip),%rdx
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  mov    -0x8(%rbp),%rax
  lea    D66(%rip),%rdx
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EnvPrintRouter@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D75
datatype: string
name: disassemble_data
arguments: data_label: D47
datatype: string
name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D66
datatype: string

tool: D75: Ambiguous reference to 

tool: D47: werror

tool: D17:  

tool: D66: .
It is imported from more than one module.


assistant: ```c
void AmbiguousReferenceErrorMessage(void *theEnv, const char *constructName, const char *findName) {
  EnvPrintRouter(theEnv, "werror", "Ambiguous reference to ");
  EnvPrintRouter(theEnv, "werror", constructName);
  EnvPrintRouter(theEnv, "werror", " ");
  EnvPrintRouter(theEnv, "werror", findName);
  EnvPrintRouter(theEnv, "werror", ".\nIt is imported from more than one module.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AmbiguousReferenceErrorMessage>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  lea    D16(%rip),%rdx
  lea    D28(%rip),%rbp
  mov    %rbp,%rsi
  call   <EnvPrintRouter@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EnvPrintRouter@plt>
  lea    D3(%rip),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EnvPrintRouter@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EnvPrintRouter@plt>
  lea    D29(%rip),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <EnvPrintRouter@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D29
type_guessed: string

tool: D16: Ambiguous reference to 

tool: D28: werror

tool: D3:  

tool: D29: .
It is imported from more than one module.


assistant: ```c
void AmbiguousReferenceErrorMessage(void *theEnv, const char *constructName, const char *findName) {
  EnvPrintRouter(theEnv, "werror", "Ambiguous reference to ");
  EnvPrintRouter(theEnv, "werror", constructName);
  EnvPrintRouter(theEnv, "werror", " ");
  EnvPrintRouter(theEnv, "werror", findName);
  EnvPrintRouter(theEnv, "werror", ".\nIt is imported from more than one module.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AmbiguousReferenceErrorMessage>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  lea    D15(%rip),%rdx
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <EnvPrintRouter@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D22(%rip),%rdx
  call   <EnvPrintRouter@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D23(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <EnvPrintRouter@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string
name: extract_symbolic_data
arguments: data_tag: D23
datatype: string

tool: D15: Ambiguous reference to 

tool: D24: werror

tool: D22:  

tool: D23: .
It is imported from more than one module.


assistant: ```c
void AmbiguousReferenceErrorMessage(void *theEnv, const char *constructName, const char *findName) {
  EnvPrintRouter(theEnv, "werror", "Ambiguous reference to ");
  EnvPrintRouter(theEnv, "werror", constructName);
  EnvPrintRouter(theEnv, "werror", " ");
  EnvPrintRouter(theEnv, "werror", findName);
  EnvPrintRouter(theEnv, "werror", ".\nIt is imported from more than one module.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AmbiguousReferenceErrorMessage>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  lea    D39(%rip),%rdx
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <EnvPrintRouter@plt>
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D28(%rip),%rdx
  call   <EnvPrintRouter@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EnvPrintRouter@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D19(%rip),%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <EnvPrintRouter@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D39: Ambiguous reference to 

tool: D31: werror

tool: D28:  

tool: D19: .
It is imported from more than one module.


assistant: ```c
void AmbiguousReferenceErrorMessage(void *theEnv, const char *constructName, const char *findName) {
  EnvPrintRouter(theEnv, "werror", "Ambiguous reference to ");
  EnvPrintRouter(theEnv, "werror", constructName);
  EnvPrintRouter(theEnv, "werror", " ");
  EnvPrintRouter(theEnv, "werror", findName);
  EnvPrintRouter(theEnv, "werror", ".\nIt is imported from more than one module.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<match_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L33
L21:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L20
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L23
  mov    $0x0,%eax
  jmp    L7
L23:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int match_text(char *name, char *text, int len) {
  int i, j;
  for (i = j = 0; i < len; i++, j++) {
    if (name[i] == '\'')
      i += 1;
    if (name[i] != text[j])
      return (0);
  }
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match_text>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    $0x0,%eax
L15:
  movslq %eax,%rcx
  cmpb   $0x27,(%rdi,%rcx,1)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  movslq %eax,%rcx
  movzbl (%rsi),%r8d
  cmp    %r8b,(%rdi,%rcx,1)
  jne    L0
  add    $0x1,%eax
  add    $0x1,%rsi
  cmp    %eax,%edx
  jg     L15
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int match_text(char *name, char *text, int len) {
  int i, j;
  for (i = j = 0; i < len; i++, j++) {
    if (name[i] == '\'')
      i += 1;
    if (name[i] != text[j])
      return (0);
  }
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<match_text>:
  endbr64
  test   %edx,%edx
  jle    L29
  xor    %eax,%eax
  jmp    L8
  nopl   0x0(%rax)
L11:
  add    $0x1,%eax
  add    $0x1,%rsi
  cmp    %eax,%edx
  jle    L29
L8:
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  cmp    $0x27,%cl
  jne    L4
  add    $0x1,%eax
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ecx
L4:
  cmp    %cl,(%rsi)
  je     L11
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int match_text(char *name, char *text, int len) {
  int i, j;
  for (i = j = 0; i < len; i++, j++) {
    if (name[i] == '\'')
      i += 1;
    if (name[i] != text[j])
      return (0);
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match_text>:
  endbr64
  test   %edx,%edx
  jle    L21
  xor    %eax,%eax
  jmp    L1
  nopl   0x0(%rax)
L46:
  add    $0x1,%eax
  add    $0x1,%rsi
  cmp    %eax,%edx
  jle    L21
L1:
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ecx
  cmp    $0x27,%cl
  jne    L45
  add    $0x1,%eax
  movslq %eax,%rcx
  movzbl (%rdi,%rcx,1),%ecx
L45:
  cmp    %cl,(%rsi)
  je     L46
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int match_text(char *name, char *text, int len) {
  int i, j;
  for (i = j = 0; i < len; i++, j++) {
    if (name[i] == '\'')
      i += 1;
    if (name[i] != text[j])
      return (0);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L7:
  shll   -0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash_func(const char *str) {
  int r = 0;
  int i;
  for (i = 0; str[i]; ++i) {
    r *= 2;
    r += str[i];
  }
  return r;
}
```