ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flip_authors_names>:
  endbr64
  push   %r15
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xff,%edi
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    $0xff,%edi
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  movb   $0x0,(%rbx)
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L42
  mov    %rax,%rsi
  lea    D26(%rip),%r12
  lea    D8(%rip),%rbp
  nopl   0x0(%rax)
L35:
  mov    %r13,%rdi
  call   <strcpy@plt>
  lea    D42(%rip),%rsi
  jmp    L15
  nopl   0x0(%rax)
L44:
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L13
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
L15:
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L44
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L51:
  mov    %r14,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L35
L42:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   (%rax)
L13:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L51
```

tool_calls: name: read_data
arguments: label: D11
data_type: string
name: read_data
arguments: label: D26
data_type: string
name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D42
data_type: string
name: read_data
arguments: label: D23
data_type: string

tool: D11: ,

tool: D26: and

tool: D8: . 

tool: D42: ., 

tool: D23: , 

assistant: ```c
void flip_authors_names(char *flipped_names, const char *authors_names) {
  char *tmpstr = malloc(255 * sizeof(char));
  char *tmpLastname = malloc(255 * sizeof(char));
  strcpy(tmpstr, authors_names);
  flipped_names[0] = '\0';
  char *token = strtok(tmpstr, ",");
  while (token != NULL) {
    strcpy(tmpLastname, token);
    token = strtok(NULL, "., ");
    while (token != NULL && strcmp(token, "and") != 0) {
      strcat(flipped_names, token);
      strcat(flipped_names, ". ");
      token = strtok(NULL, ". ");
    }
    strcat(flipped_names, tmpLastname);
    if (token != NULL) {
      strcat(flipped_names, ", ");
    }
    token = strtok(NULL, ",");
  }
  free(tmpstr);
  free(tmpLastname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<flip_authors_names>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xff,%edi
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    $0xff,%edi
  mov    %rax,%r15
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  movb   $0x0,(%rbx)
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L46
  mov    %rax,%rsi
  lea    D24(%rip),%r12
  lea    D7(%rip),%rbp
  nopl   0x0(%rax)
L56:
  mov    %r13,%rdi
  call   <strcpy@plt>
  lea    D19(%rip),%rsi
  jmp    L35
  nopl   0x0(%rax)
L50:
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
L35:
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L50
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L41:
  mov    %r14,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L56
L46:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   (%rax)
L9:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  jmp    L41
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D9
datatype: string

tool: D3: ,

tool: D24: and

tool: D7: . 

tool: D19: ., 

tool: D9: , 

assistant: ```c
void flip_authors_names(char *flipped_names, const char *authors_names) {
  char *tmpstr = malloc(255 * sizeof(char));
  char *tmpLastname = malloc(255 * sizeof(char));
  strcpy(tmpstr, authors_names);
  flipped_names[0] = '\0';
  char *token = strtok(tmpstr, ",");
  while (token != NULL) {
    strcpy(tmpLastname, token);
    token = strtok(NULL, "., ");
    while (token != NULL && strcmp(token, "and") != 0) {
      strcat(flipped_names, token);
      strcat(flipped_names, ". ");
      token = strtok(NULL, ". ");
    }
    strcat(flipped_names, tmpLastname);
    if (token != NULL) {
      strcat(flipped_names, ", ");
    }
    token = strtok(NULL, ",");
  }
  free(tmpstr);
  free(tmpLastname);
}
```
user: What is the c source code of the assembly code below:

```asm
<Print_Read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3,%al
  jg     L75
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L26:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    $0xa,%edi
  call   <putchar@plt>
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x4,%al
  jne    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L80
L75:
  movl   $0x0,-0x4(%rbp)
  jmp    L84
L73:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L92
  cmpl   $0x0,-0x4(%rbp)
  je     L92
  mov    $0xa,%edi
  call   <putchar@plt>
L92:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L84:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L73
  mov    $0xa,%edi
  call   <putchar@plt>
L80:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
void Print_Read(char *s, int width) {
  int i;
  if (s[0] < 4) {
    for (i = 0; s[i] != 4; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%d", s[i]);
    }
    printf("\n");
  } else {
    for (i = 0; s[i] != '\0'; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%c", s[i]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print_Read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    $0x0,%ebp
  cmpb   $0x3,(%rdi)
  jg     L30
  mov    $0x0,%ebp
  lea    D5(%rip),%r13
L85:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x4,(%rbx)
  je     L21
  mov    %ebp,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  jne    L85
  test   %ebp,%ebp
  je     L85
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L85
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L63
  mov    %ebp,%eax
  cltd
  idiv   %r12d
  test   %edx,%edx
  jne    L30
  test   %ebp,%ebp
  je     L30
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L30
L63:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L35
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: %d

assistant: ```c
void Print_Read(char *s, int width) {
  int i;
  if (s[0] < 4) {
    for (i = 0; s[i] != 4; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%d", s[i]);
    }
    printf("\n");
  } else {
    for (i = 0; s[i] != '\0'; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%c", s[i]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print_Read>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  cmp    $0x3,%sil
  jg     L9
  lea    D3(%rip),%r13
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rbp
L18:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl (%r12,%rbp,1),%esi
  mov    %ebp,%eax
  cmp    $0x4,%sil
  je     L58
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  movsbl (%r12,%rbp,1),%esi
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xa,%edi
  call   <putchar@plt>
  movzbl (%r12,%rbp,1),%esi
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbp
L9:
  movsbl %sil,%edi
  call   <putchar@plt>
  movzbl (%r12,%rbp,1),%esi
  mov    %ebp,%eax
  test   %sil,%sil
  je     L58
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L11
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d

assistant: ```c
void Print_Read(char *s, int width) {
  int i;
  if (s[0] < 4) {
    for (i = 0; s[i] != 4; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%d", s[i]);
    }
    printf("\n");
  } else {
    for (i = 0; s[i] != '\0'; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%c", s[i]);
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Print_Read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x3,(%rdi)
  jle    L40
  mov    $0x1,%r12d
  sub    %edi,%r12d
  nopl   0x0(%rax)
L55:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  lea    (%r12,%rbx,1),%eax
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L68
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L55
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L55
L68:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L40:
  mov    $0x1,%r12d
  lea    D5(%rip),%r13
  sub    %edi,%r12d
  nopl   0x0(%rax,%rax,1)
L35:
  movsbl (%rbx),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  lea    (%r12,%rbx,1),%eax
  add    $0x1,%rbx
  cmpb   $0x4,(%rbx)
  je     L68
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L35
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L35
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: %d

assistant: ```c
void Print_Read(char *s, int width) {
  int i;
  if (s[0] < 4) {
    for (i = 0; s[i] != 4; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%d", s[i]);
    }
    printf("\n");
  } else {
    for (i = 0; s[i] != '\0'; i++) {
      if (i % width == 0 && i != 0)
        printf("\n");
      printf("%c", s[i]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_set_random_book>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_random_book@plt>
  nop
  leave
  ret
```

assistant: ```c
void init_set_random_book(mpz_t book) {
  mpz_init(book);
  set_random_book(book);
}
```
user: What is the c source code of the assembly code below:

```asm
<init_set_random_book>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <mpz_init@plt>
  mov    %ebx,%edi
  call   <set_random_book@plt>
  pop    %rbx
  ret
```

assistant: ```c
void init_set_random_book(mpz_t book) {
  mpz_init(book);
  set_random_book(book);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<init_set_random_book>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <mpz_init@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <set_random_book@plt>
```

assistant: ```c
void init_set_random_book(mpz_t book) {
  mpz_init(book);
  set_random_book(book);
}
```
user: What is the c source code of the assembly code below?

```asm
<init_set_random_book>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <mpz_init@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <set_random_book@plt>
```

assistant: ```c
void init_set_random_book(mpz_t book) {
  mpz_init(book);
  set_random_book(book);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_close_line_box>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%ebx
  jmp    L15
L18:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
L15:
  cmp    -0x14(%rbp),%ebx
  jl     L18
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string

tool: D2:  

tool: D5: |


assistant: ```c
void print_close_line_box(int no_spaces) {
  register int i;
  for (i = 0; i < no_spaces; i++) {
    printf(" ");
  }
  printf("|\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_close_line_box>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D17(%rip),%r12
L19:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L19
L12:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D17:  

tool: D3: |


assistant: ```c
void print_close_line_box(int no_spaces) {
  register int i;
  for (i = 0; i < no_spaces; i++) {
    printf(" ");
  }
  printf("|\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_close_line_box>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L14
  pop    %rbx
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
  nop
L13:
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D6:  

tool: D2: |


assistant: ```c
void print_close_line_box(int no_spaces) {
  register int i;
  for (i = 0; i < no_spaces; i++) {
    printf(" ");
  }
  printf("|\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_close_line_box>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L17
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
  nop
L0:
  lea    D11(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D11
type: string

tool: D24:  

tool: D11: |


assistant: ```c
void print_close_line_box(int no_spaces) {
  register int i;
  for (i = 0; i < no_spaces; i++) {
    printf(" ");
  }
  printf("|\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sysFindrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L7
  mov    -0x1c(%rbp),%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jge    L3
L7:
  mov    $0xffffffff,%eax
  jmp    L41
L3:
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0xc(%rbp),%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L55
  mov    -0x10(%rbp),%eax
  sub    0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L55
L5:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    0x10(%rbp),%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <mystrcmp@plt>
  test   %eax,%eax
  jne    L25
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  jmp    L41
L25:
  subl   $0x1,-0xc(%rbp)
L55:
  cmpl   $0x0,-0xc(%rbp)
  jns    L5
  mov    $0xffffffff,%eax
L41:
  leave
  ret
```

assistant: ```c
int sysFindrev(char *dst, int i, int ldst, char *src, int j, int lsrc, int len) {
  if ((j < 0) || (j + len > lsrc))
    return (-1);
  src += j;
  if (i + len > ldst)
    i = ldst - len;
  while (i >= 0) {
    if (!mystrcmp(dst + i, src, len))
      return ((i) << 1);
    i--;
  }
  return (-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sysFindrev>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x30(%rsp),%r13d
  test   %r8d,%r8d
  js     L34
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%eax
  lea    (%r8,%r13,1),%edx
  cmp    %r9d,%edx
  jg     L30
  movslq %r8d,%r8
  lea    (%rcx,%r8,1),%r12
  lea    0x0(%r13,%rsi,1),%ecx
  mov    %eax,%edx
  sub    %r13d,%edx
  cmp    %eax,%ecx
  cmovg  %edx,%ebx
  test   %ebx,%ebx
  js     L2
  movslq %ebx,%rax
  add    %rax,%rbp
L59:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mystrcmp@plt>
  test   %eax,%eax
  je     L62
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  jne    L59
  mov    %ebx,%eax
  jmp    L52
L62:
  lea    (%rbx,%rbx,1),%eax
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L52
L30:
  mov    $0xffffffff,%eax
  jmp    L52
L2:
  mov    $0xffffffff,%eax
  jmp    L52
```

assistant: ```c
int sysFindrev(char *dst, int i, int ldst, char *src, int j, int lsrc, int len) {
  if ((j < 0) || (j + len > lsrc))
    return (-1);
  src += j;
  if (i + len > ldst)
    i = ldst - len;
  while (i >= 0) {
    if (!mystrcmp(dst + i, src, len))
      return ((i) << 1);
    i--;
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sysFindrev>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x30(%rsp),%r13d
  test   %r8d,%r8d
  js     L38
  mov    %edx,%eax
  lea    (%r8,%r13,1),%edx
  cmp    %r9d,%edx
  jg     L38
  movslq %r8d,%r8
  mov    %eax,%edx
  mov    %esi,%ebx
  lea    (%rcx,%r8,1),%r12
  lea    0x0(%r13,%rsi,1),%ecx
  sub    %r13d,%edx
  cmp    %eax,%ecx
  cmovg  %edx,%ebx
  test   %ebx,%ebx
  js     L38
  mov    %rdi,%rbp
  movslq %ebx,%rax
  add    %rax,%rbp
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  je     L38
L50:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mystrcmp@plt>
  test   %eax,%eax
  jne    L12
  add    $0x8,%rsp
  lea    (%rbx,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L38:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sysFindrev(char *dst, int i, int ldst, char *src, int j, int lsrc, int len) {
  if ((j < 0) || (j + len > lsrc))
    return (-1);
  src += j;
  if (i + len > ldst)
    i = ldst - len;
  while (i >= 0) {
    if (!mystrcmp(dst + i, src, len))
      return ((i) << 1);
    i--;
  }
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sysFindrev>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x30(%rsp),%r13d
  test   %r8d,%r8d
  js     L25
  mov    %edx,%eax
  lea    (%r8,%r13,1),%edx
  cmp    %r9d,%edx
  jg     L25
  movslq %r8d,%r8
  mov    %eax,%edx
  mov    %esi,%ebx
  lea    (%rcx,%r8,1),%r12
  lea    0x0(%r13,%rsi,1),%ecx
  sub    %r13d,%edx
  cmp    %eax,%ecx
  cmovg  %edx,%ebx
  test   %ebx,%ebx
  js     L25
  mov    %rdi,%rbp
  movslq %ebx,%rax
  add    %rax,%rbp
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L36:
  sub    $0x1,%ebx
  sub    $0x1,%rbp
  cmp    $0xffffffff,%ebx
  je     L25
L0:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mystrcmp@plt>
  test   %eax,%eax
  jne    L36
  add    $0x8,%rsp
  lea    (%rbx,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L25:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sysFindrev(char *dst, int i, int ldst, char *src, int j, int lsrc, int len) {
  if ((j < 0) || (j + len > lsrc))
    return (-1);
  src += j;
  if (i + len > ldst)
    i = ldst - len;
  while (i >= 0) {
    if (!mystrcmp(dst + i, src, len))
      return ((i) << 1);
    i--;
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<apply_homography>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  movsd  0x10(%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x30,%rax
  movsd  0x10(%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void apply_homography(double y[2], double H[3][3], double x[2]) {
  double X = H[0][0] * x[0] + H[0][1] * x[1] + H[0][2];
  double Y = H[1][0] * x[0] + H[1][1] * x[1] + H[1][2];
  double Z = H[2][0] * x[0] + H[2][1] * x[1] + H[2][2];
  y[0] = X / Z;
  y[1] = Y / Z;
}
```