ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__sanitizer_cov_trace_const_cmp2>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L29
L19:
  xor    %edi,%edi
  call   <__builtin_return_address@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <hfuzz_trace_cmp2_internal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  call   <__builtin_bswap16@plt>
  lea    0x10(%rsp),%rdi
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    %rax,0x10(%rsp)
  call   <instrumentAddConstMem@plt>
  lea    0x8(%rsp),%rdi
  xor    %edx,%edx
  mov    $0x8,%esi
  call   <instrumentAddConstMem@plt>
  mov    0x8(%rsp),%rbp
  jmp    L19
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __sanitizer_cov_trace_const_cmp2(uint16_t Arg1, uint16_t Arg2) {
  if (Arg1) {
    uint16_t bswp = __builtin_bswap16(Arg1);
    instrumentAddConstMem(&bswp, sizeof(bswp), false);
    instrumentAddConstMem(&Arg1, sizeof(Arg1), false);
  }
  hfuzz_trace_cmp2_internal((uintptr_t)__builtin_return_address(0), Arg1, Arg2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__sanitizer_cov_trace_const_cmp2>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L4
L3:
  xor    %edi,%edi
  call   <__builtin_return_address@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <hfuzz_trace_cmp2_internal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  call   <__builtin_bswap16@plt>
  lea    0x10(%rsp),%rdi
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    %rax,0x10(%rsp)
  call   <instrumentAddConstMem@plt>
  lea    0x8(%rsp),%rdi
  xor    %edx,%edx
  mov    $0x8,%esi
  call   <instrumentAddConstMem@plt>
  mov    0x8(%rsp),%rbp
  jmp    L3
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __sanitizer_cov_trace_const_cmp2(uint16_t Arg1, uint16_t Arg2) {
  if (Arg1) {
    uint16_t bswp = __builtin_bswap16(Arg1);
    instrumentAddConstMem(&bswp, sizeof(bswp), false);
    instrumentAddConstMem(&Arg1, sizeof(Arg1), false);
  }
  hfuzz_trace_cmp2_internal((uintptr_t)__builtin_return_address(0), Arg1, Arg2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%edi
  call   <f@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f(7);
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edi
  call   <f@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(7);
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edi
  call   <f@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(7);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edi
  call   <f@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f(7);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printIncSeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L21
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArr@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L55
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L11
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L8
L11:
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L31:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <printIncSeq>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L31
L55:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D7: 


assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    printf("\n");
  }
  if (len < n) {
    int i = 0;
    if (len > 0) {
      i = arr[len - 1] + 1;
    } else {
      i = 1;
    }
    for (; i <= n; i++) {
      arr[len] = i;
      printIncSeq(n, m, len + 1, arr);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printIncSeq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r14
  cmp    %esi,%edx
  je     L8
L33:
  cmp    %r12d,%ebp
  jge    L52
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L27
  movslq %ebp,%rax
  mov    -0x4(%r14,%rax,4),%ebx
  add    $0x1,%ebx
L27:
  cmp    %ebx,%r12d
  jl     L52
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%r15
  add    $0x1,%ebp
L25:
  mov    %ebx,(%r15)
  mov    %r14,%rcx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <printIncSeq>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L25
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %rcx,%rdi
  call   <printArr@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L33
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: 


assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    printf("\n");
  }
  if (len < n) {
    int i = 0;
    if (len > 0) {
      i = arr[len - 1] + 1;
    } else {
      i = 1;
    }
    for (; i <= n; i++) {
      arr[len] = i;
      printIncSeq(n, m, len + 1, arr);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printIncSeq>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edx
  je     L20
L43:
  cmp    %r12d,%ebp
  jge    L11
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L53
  movslq %ebp,%rax
  mov    -0x4(%r15,%rax,4),%ebx
  add    $0x1,%ebx
L53:
  cmp    %ebx,%r12d
  jl     L11
  movslq %ebp,%rax
  add    $0x1,%ebp
  lea    (%r15,%rax,4),%r14
L57:
  mov    %ebx,(%r14)
  mov    %r15,%rcx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <printIncSeq>
  cmp    %ebx,%r12d
  jge    L57
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rcx,%rdi
  mov    %edx,%esi
  call   <printArr@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L43
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: 


assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    printf("\n");
  }
  if (len < n) {
    int i = 0;
    if (len > 0) {
      i = arr[len - 1] + 1;
    } else {
      i = 1;
    }
    for (; i <= n; i++) {
      arr[len] = i;
      printIncSeq(n, m, len + 1, arr);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x19,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: Ejemplo de almancemaniento a memoria [ %d ]


assistant: ```c
int main(int argc, const char *argv[]) {
  int valor;
  valor = 25;
  printf("Ejemplo de almancemaniento a memoria [ %d ]\n", &valor);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x19,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Ejemplo de almancemaniento a memoria [ %d ]


assistant: ```c
int main(int argc, const char *argv[]) {
  int valor;
  valor = 25;
  printf("Ejemplo de almancemaniento a memoria [ %d ]\n", &valor);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x19,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: Ejemplo de almancemaniento a memoria [ %d ]


assistant: ```c
int main(int argc, const char *argv[]) {
  int valor;
  valor = 25;
  printf("Ejemplo de almancemaniento a memoria [ %d ]\n", &valor);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x19,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: Ejemplo de almancemaniento a memoria [ %d ]


assistant: ```c
int main(int argc, const char *argv[]) {
  int valor;
  valor = 25;
  printf("Ejemplo de almancemaniento a memoria [ %d ]\n", &valor);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<envoyerReponse200ICO>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %rdi,-0x218(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x208(%rbp)
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <longueur_fichier@plt>
  mov    %eax,-0x208(%rbp)
  mov    -0x208(%rbp),%edx
  lea    -0x202(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x200(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x202(%rbp),%rdx
  lea    -0x200(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x200(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x200(%rbp),%rax
  mov    %rax,%rdi
  call   <Emission@plt>
  cmp    $0x1,%eax
  je     L13
  mov    $0xffffffff,%eax
  jmp    L29
L13:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D11
type: string

tool: D6: %d

tool: D10: 
HTTP/1.1 200 OK
Content-type :image/vnd.microsoft.icon
Content-length: 

tool: D11: 



assistant: ```c
int envoyerReponse200ICO(char *nomFichier) {
  char req[500];
  char len[2];
  int lenght = 0;
  lenght = longueur_fichier(nomFichier);
  sprintf(len, "%d", lenght);
  strcpy(req, "\nHTTP/1.1 200 OK\r\nContent-type :image/vnd.microsoft.icon\r\nContent-length: ");
  strcat(req, len);
  strcat(req, "\n\n");
  if (Emission(req) != 1) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<envoyerReponse200ICO>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <longueur_fichier@plt>
  mov    %eax,%edx
  lea    0xe(%rsp),%rbp
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x10(%rsp),%rbx
  lea    D23(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D27(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <Emission@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string

tool: D21: %d

tool: D23: 
HTTP/1.1 200 OK
Content-type :image/vnd.microsoft.icon
Content-length: 

tool: D27: 



assistant: ```c
int envoyerReponse200ICO(char *nomFichier) {
  char req[500];
  char len[2];
  int lenght = 0;
  lenght = longueur_fichier(nomFichier);
  sprintf(len, "%d", lenght);
  strcpy(req, "\nHTTP/1.1 200 OK\r\nContent-type :image/vnd.microsoft.icon\r\nContent-length: ");
  strcat(req, len);
  strcat(req, "\n\n");
  if (Emission(req) != 1) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<envoyerReponse200ICO>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    0x10(%rsp),%rbp
  call   <longueur_fichier@plt>
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <sprintf@plt>
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <Emission@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D27
data_type: string

tool: D3: %d

tool: D28: 
HTTP/1.1 200 OK
Content-type :image/vnd.microsoft.icon
Content-length: 

tool: D27: 



assistant: ```c
int envoyerReponse200ICO(char *nomFichier) {
  char req[500];
  char len[2];
  int lenght = 0;
  lenght = longueur_fichier(nomFichier);
  sprintf(len, "%d", lenght);
  strcpy(req, "\nHTTP/1.1 200 OK\r\nContent-type :image/vnd.microsoft.icon\r\nContent-length: ");
  strcat(req, len);
  strcat(req, "\n\n");
  if (Emission(req) != 1) {
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<envoyerReponse200ICO>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    0x10(%rsp),%rbp
  call   <longueur_fichier@plt>
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <sprintf@plt>
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <Emission@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string

tool: D3: %d

tool: D15: 
HTTP/1.1 200 OK
Content-type :image/vnd.microsoft.icon
Content-length: 

tool: D18: 



assistant: ```c
int envoyerReponse200ICO(char *nomFichier) {
  char req[500];
  char len[2];
  int lenght = 0;
  lenght = longueur_fichier(nomFichier);
  sprintf(len, "%d", lenght);
  strcpy(req, "\nHTTP/1.1 200 OK\r\nContent-type :image/vnd.microsoft.icon\r\nContent-length: ");
  strcat(req, len);
  strcat(req, "\n\n");
  if (Emission(req) != 1) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<acpi_add_EndResource>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jle    L4
  mov    -0x8(%rbp),%rax
  mov    $0x79,%esi
  mov    %rax,%rdi
  call   <acpi_add_byte@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <acpi_add_byte@plt>
L4:
  mov    $0x2,%eax
  leave
  ret
```

assistant: ```c
int acpi_add_EndResource(char **data, int dlen) {
  if (dlen >= 2) {
    acpi_add_byte(data, 0x79);
    acpi_add_byte(data, 0);
  }
  return 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<acpi_add_EndResource>:
  endbr64
  cmp    $0x1,%esi
  jg     L9
  mov    $0x2,%eax
  ret
L9:
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x79,%esi
  call   <acpi_add_byte@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <acpi_add_byte@plt>
  mov    $0x2,%eax
  pop    %rbx
  ret
```

assistant: ```c
int acpi_add_EndResource(char **data, int dlen) {
  if (dlen >= 2) {
    acpi_add_byte(data, 0x79);
    acpi_add_byte(data, 0);
  }
  return 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<acpi_add_EndResource>:
  endbr64
  cmp    $0x1,%esi
  jg     L2
  mov    $0x2,%eax
  ret
  nop
L2:
  push   %rbp
  mov    $0x79,%esi
  mov    %rdi,%rbp
  call   <acpi_add_byte@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <acpi_add_byte@plt>
  mov    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int acpi_add_EndResource(char **data, int dlen) {
  if (dlen >= 2) {
    acpi_add_byte(data, 0x79);
    acpi_add_byte(data, 0);
  }
  return 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<acpi_add_EndResource>:
  endbr64
  cmp    $0x1,%esi
  jg     L9
  mov    $0x2,%eax
  ret
  nop
L9:
  push   %rbp
  mov    $0x79,%esi
  mov    %rdi,%rbp
  call   <acpi_add_byte@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <acpi_add_byte@plt>
  mov    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int acpi_add_EndResource(char **data, int dlen) {
  if (dlen >= 2) {
    acpi_add_byte(data, 0x79);
    acpi_add_byte(data, 0);
  }
  return 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<poissonsEquationExp2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L14:
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x58(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: f64

tool: D0: 1

assistant: ```c
int poissonsEquationExp2D(int *iwork, double *rwork, int nPoints, double t, double *X, double *u) {
  int i = 0;
  double K = rwork[0];
  double x, y;
  for (i = 0; i < nPoints; i++) {
    x = X[i * 3 + 0];
    y = X[i * 3 + 1];
    u[i] = K * x * (1.0 - x) * y * (1.0 - y) * exp(x * x + y * y);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<poissonsEquationExp2D>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  (%rsi),%xmm5
  movsd  %xmm5,0x18(%rsp)
  test   %edx,%edx
  jle    L15
  mov    %r8,%rbp
  lea    0x8(%rcx),%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%r8,%rax,8),%r12
L17:
  movsd  -0x8(%rbx),%xmm0
  movsd  (%rbx),%xmm4
  movsd  %xmm0,0x8(%rsp)
  mulsd  %xmm0,%xmm0
  movapd %xmm4,%xmm1
  movsd  %xmm4,0x10(%rsp)
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  %xmm3,%xmm1
  movsd  D4(%rip),%xmm0
  subsd  %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  0x10(%rsp),%xmm4
  mulsd  %xmm4,%xmm0
  movsd  D4(%rip),%xmm1
  subsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbp
  add    $0x18,%rbx
  cmp    %r12,%rbp
  jne    L17
L15:
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
int poissonsEquationExp2D(int *iwork, double *rwork, int nPoints, double t, double *X, double *u) {
  int i = 0;
  double K = rwork[0];
  double x, y;
  for (i = 0; i < nPoints; i++) {
    x = X[i * 3 + 0];
    y = X[i * 3 + 1];
    u[i] = K * x * (1.0 - x) * y * (1.0 - y) * exp(x * x + y * y);
  }
  return 0;
}
```