ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <palin@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: %s 

assistant: ```c
int main() {
  char str[100];
  scanf("%s ", str);
  palin(str, 0, strlen(str));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <palin@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: %s 

assistant: ```c
int main() {
  char str[100];
  scanf("%s ", str);
  palin(str, 0, strlen(str));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dtc_humantobytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <dtc_isvalid@plt>
  test   %eax,%eax
  jne    L101
  mov    $0xffffffff,%eax
  jmp    L193
L101:
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  jg     L175
  cmpl   $0x0,-0xc(%rbp)
  jns    L194
L175:
  mov    $0xffffffff,%eax
  jmp    L193
L194:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x55,%eax
  je     L121
  cmp    $0x55,%eax
  jg     L63
  cmp    $0x50,%eax
  je     L87
  cmp    $0x50,%eax
  jg     L63
  cmp    $0x42,%eax
  je     L159
  cmp    $0x43,%eax
  je     L59
  jmp    L63
L87:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L59:
  mov    -0xc(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L159:
  mov    -0xc(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L121:
  mov    -0xc(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L63:
  mov    $0xffffffff,%eax
  jmp    L193
L15:
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdi
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  je     L10
  mov    $0xffffffff,%eax
  jmp    L193
L10:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L193:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: %1X%02X

assistant: ```c
int dtc_humantobytes(const char *human, unsigned int *A, unsigned int *B) {
  if (!dtc_isvalid(human)) {
    return -1;
  }
  int mod = human[1] - '0';
  if (mod > 3 || mod < 0) {
    return -1;
  }
  unsigned int val;
  switch (human[0]) {
  case 'P':
    val = mod;
    break;
  case 'C':
    val = mod + 0x04;
    break;
  case 'B':
    val = mod + 0x08;
    break;
  case 'U':
    val = mod + 0x0C;
    break;
  default:
    return -1;
  }
  unsigned int one, two;
  if (2 != sscanf(human + 2, "%1X%02X", &one, &two)) {
    return -1;
  }
  *A = one + (val << 4);
  *B = two;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dtc_humantobytes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <dtc_isvalid@plt>
  test   %eax,%eax
  je     L88
  movsbl 0x1(%rbx),%edx
  lea    -0x30(%rdx),%r13d
  cmp    $0x3,%r13d
  ja     L121
  movzbl (%rbx),%eax
  cmp    $0x50,%al
  je     L7
  jg     L83
  cmp    $0x42,%al
  je     L3
  cmp    $0x43,%al
  jne    L38
  lea    -0x2c(%rdx),%r13d
  jmp    L7
L38:
  mov    $0xffffffff,%eax
  jmp    L36
L83:
  lea    -0x24(%rdx),%r13d
  cmp    $0x55,%al
  jne    L95
L7:
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x2(%rbx),%rdi
  lea    D3(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L143
  mov    %r13d,%eax
  shl    $0x4,%eax
  add    (%rsp),%eax
  mov    %eax,(%r12)
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
L36:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L123
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L95:
  mov    $0xffffffff,%eax
  jmp    L36
L3:
  lea    -0x28(%rdx),%r13d
  jmp    L7
L88:
  mov    $0xffffffff,%eax
  jmp    L36
L121:
  mov    $0xffffffff,%eax
  jmp    L36
L143:
  mov    $0xffffffff,%eax
  jmp    L36
L123:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %1X%02X

assistant: ```c
int dtc_humantobytes(const char *human, unsigned int *A, unsigned int *B) {
  if (!dtc_isvalid(human)) {
    return -1;
  }
  int mod = human[1] - '0';
  if (mod > 3 || mod < 0) {
    return -1;
  }
  unsigned int val;
  switch (human[0]) {
  case 'P':
    val = mod;
    break;
  case 'C':
    val = mod + 0x04;
    break;
  case 'B':
    val = mod + 0x08;
    break;
  case 'U':
    val = mod + 0x0C;
    break;
  default:
    return -1;
  }
  unsigned int one, two;
  if (2 != sscanf(human + 2, "%1X%02X", &one, &two)) {
    return -1;
  }
  *A = one + (val << 4);
  *B = two;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dtc_humantobytes>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <dtc_isvalid@plt>
  test   %eax,%eax
  je     L83
  movsbl 0x1(%rbx),%edx
  lea    -0x30(%rdx),%ebp
  cmp    $0x3,%ebp
  ja     L83
  movzbl (%rbx),%eax
  cmp    $0x50,%al
  je     L77
  jg     L102
  cmp    $0x42,%al
  je     L0
  cmp    $0x43,%al
  jne    L83
  lea    -0x2c(%rdx),%ebp
L77:
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x2(%rbx),%rdi
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L83
  mov    0x4(%rsp),%eax
  shl    $0x4,%ebp
  add    (%rsp),%ebp
  mov    %ebp,0x0(%r13)
  mov    %eax,(%r12)
  xor    %eax,%eax
L76:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L102:
  lea    -0x24(%rdx),%ebp
  cmp    $0x55,%al
  je     L77
L83:
  mov    $0xffffffff,%eax
  jmp    L76
  xchg   %ax,%ax
L0:
  lea    -0x28(%rdx),%ebp
  jmp    L77
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: %1X%02X

assistant: ```c
int dtc_humantobytes(const char *human, unsigned int *A, unsigned int *B) {
  if (!dtc_isvalid(human)) {
    return -1;
  }
  int mod = human[1] - '0';
  if (mod > 3 || mod < 0) {
    return -1;
  }
  unsigned int val;
  switch (human[0]) {
  case 'P':
    val = mod;
    break;
  case 'C':
    val = mod + 0x04;
    break;
  case 'B':
    val = mod + 0x08;
    break;
  case 'U':
    val = mod + 0x0C;
    break;
  default:
    return -1;
  }
  unsigned int one, two;
  if (2 != sscanf(human + 2, "%1X%02X", &one, &two)) {
    return -1;
  }
  *A = one + (val << 4);
  *B = two;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dtc_humantobytes>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <dtc_isvalid@plt>
  test   %eax,%eax
  je     L46
  movsbl 0x1(%rbx),%edx
  lea    -0x30(%rdx),%ebp
  cmp    $0x3,%ebp
  ja     L46
  movzbl (%rbx),%eax
  cmp    $0x50,%al
  je     L82
  jg     L72
  cmp    $0x42,%al
  je     L48
  cmp    $0x43,%al
  jne    L46
  lea    -0x2c(%rdx),%ebp
L82:
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    0x2(%rbx),%rdi
  lea    D1(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L46
  mov    0x4(%rsp),%eax
  shl    $0x4,%ebp
  add    (%rsp),%ebp
  mov    %ebp,0x0(%r13)
  mov    %eax,(%r12)
  xor    %eax,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L72:
  lea    -0x24(%rdx),%ebp
  cmp    $0x55,%al
  je     L82
L46:
  mov    $0xffffffff,%eax
  jmp    L6
  xchg   %ax,%ax
L48:
  lea    -0x28(%rdx),%ebp
  jmp    L82
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: %1X%02X

assistant: ```c
int dtc_humantobytes(const char *human, unsigned int *A, unsigned int *B) {
  if (!dtc_isvalid(human)) {
    return -1;
  }
  int mod = human[1] - '0';
  if (mod > 3 || mod < 0) {
    return -1;
  }
  unsigned int val;
  switch (human[0]) {
  case 'P':
    val = mod;
    break;
  case 'C':
    val = mod + 0x04;
    break;
  case 'B':
    val = mod + 0x08;
    break;
  case 'U':
    val = mod + 0x0C;
    break;
  default:
    return -1;
  }
  unsigned int one, two;
  if (2 != sscanf(human + 2, "%1X%02X", &one, &two)) {
    return -1;
  }
  *A = one + (val << 4);
  *B = two;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x8,-0x60(%rbp)
  movq   $0x10,-0x58(%rbp)
  movabs $0x7766554433221100,%rax
  movabs $0xffeeddccbbaa9988,%rdx
  mov    %rax,-0x40(%rbp)
  mov    %rdx,-0x38(%rbp)
  movabs $0x807060504030201,%rax
  movabs $0x100f0e0d0c0b0a09,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x706050403020100,%rax
  mov    %rax,-0x50(%rbp)
  movabs $0x887745f3749a4f97,%rax
  mov    %rax,-0x48(%rbp)
  movabs $0xc05f04a9385951fc,%rax
  movabs $0xc0b8390efeec8b3c,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x48(%rbp),%r9
  mov    -0x60(%rbp),%r8
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  lea    -0x30(%rbp),%rsi
  lea    -0x40(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x20(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <run_test@plt>
  add    $0x10,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int test3() {
  unsigned long long mlen = 8;
  const unsigned long long hlen = 16;
  const unsigned char k[16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char h[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[8] = {0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07};
  const unsigned char c[8] = {0x97, 0x4f, 0x9a, 0x74, 0xf3, 0x45, 0x77, 0x88};
  const unsigned char t[16] = {0xfc, 0x51, 0x59, 0x38, 0xa9, 0x04, 0x5f, 0xc0, 0x3c, 0x8b, 0xec, 0xfe, 0x0e, 0x39, 0xb8, 0xc0};
  return run_test(k, h, hlen, m, mlen, c, t);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test3>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movabs $0x7766554433221100,%rax
  movabs $0xffeeddccbbaa9988,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x807060504030201,%rax
  movabs $0x100f0e0d0c0b0a09,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movabs $0x706050403020100,%rax
  mov    %rax,(%rsp)
  movabs $0x887745f3749a4f97,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xc05f04a9385951fc,%rax
  movabs $0xc0b8390efeec8b3c,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rsp,%rcx
  lea    0x20(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  sub    $0x8,%rsp
  lea    0x38(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  mov    $0x8,%r8d
  mov    $0x10,%edx
  call   <run_test@plt>
  add    $0x10,%rsp
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test3() {
  unsigned long long mlen = 8;
  const unsigned long long hlen = 16;
  const unsigned char k[16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char h[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[8] = {0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07};
  const unsigned char c[8] = {0x97, 0x4f, 0x9a, 0x74, 0xf3, 0x45, 0x77, 0x88};
  const unsigned char t[16] = {0xfc, 0x51, 0x59, 0x38, 0xa9, 0x04, 0x5f, 0xc0, 0x3c, 0x8b, 0xec, 0xfe, 0x0e, 0x39, 0xb8, 0xc0};
  return run_test(k, h, hlen, m, mlen, c, t);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test3>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x10,%edx
  mov    $0x8,%r8d
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  lea    0x20(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D28(%rip),%xmm0
  sub    $0x8,%rsp
  movabs $0x706050403020100,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x887745f3749a4f97,%rax
  movaps %xmm0,0x28(%rsp)
  movdqa D4(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,0x38(%rsp)
  lea    0x38(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  call   <run_test@plt>
  pop    %rdx
  pop    %rcx
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x58,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D22
type: byte[16]
name: disassemble_data
arguments: data_label: D28
type: byte[16]
name: disassemble_data
arguments: data_label: D4
type: byte[16]

tool: {"D22": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D28": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D4": [0xfc,0x51,0x59,0x38,0xa9,0x04,0x5f,0xc0,0x3c,0x8b,0xec,0xfe,0x0e,0x39,0xb8,0xc0]}

assistant: ```c
int test3() {
  unsigned long long mlen = 8;
  const unsigned long long hlen = 16;
  const unsigned char k[16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char h[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[8] = {0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07};
  const unsigned char c[8] = {0x97, 0x4f, 0x9a, 0x74, 0xf3, 0x45, 0x77, 0x88};
  const unsigned char t[16] = {0xfc, 0x51, 0x59, 0x38, 0xa9, 0x04, 0x5f, 0xc0, 0x3c, 0x8b, 0xec, 0xfe, 0x0e, 0x39, 0xb8, 0xc0};
  return run_test(k, h, hlen, m, mlen, c, t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test3>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x10,%edx
  mov    $0x8,%r8d
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  lea    0x20(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D5(%rip),%xmm0
  sub    $0x8,%rsp
  movabs $0x706050403020100,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x887745f3749a4f97,%rax
  movaps %xmm0,0x28(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  movaps %xmm0,0x38(%rsp)
  lea    0x38(%rsp),%rax
  push   %rax
  lea    0x18(%rsp),%r9
  call   <run_test@plt>
  pop    %rdx
  pop    %rcx
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x58,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D5
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D26
datatype: byte[16]

tool: {"D22": [0x00,0x11,0x22,0x33,0x44,0x55,0x66,0x77,0x88,0x99,0xaa,0xbb,0xcc,0xdd,0xee,0xff]}

tool: {"D5": [0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x0a,0x0b,0x0c,0x0d,0x0e,0x0f,0x10]}

tool: {"D26": [0xfc,0x51,0x59,0x38,0xa9,0x04,0x5f,0xc0,0x3c,0x8b,0xec,0xfe,0x0e,0x39,0xb8,0xc0]}

assistant: ```c
int test3() {
  unsigned long long mlen = 8;
  const unsigned long long hlen = 16;
  const unsigned char k[16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char h[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char m[8] = {0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07};
  const unsigned char c[8] = {0x97, 0x4f, 0x9a, 0x74, 0xf3, 0x45, 0x77, 0x88};
  const unsigned char t[16] = {0xfc, 0x51, 0x59, 0x38, 0xa9, 0x04, 0x5f, 0xc0, 0x3c, 0x8b, 0xec, 0xfe, 0x0e, 0x39, 0xb8, 0xc0};
  return run_test(k, h, hlen, m, mlen, c, t);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<frob_norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L11:
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L32:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L32
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double frob_norm(double **X, int m, int n) {
  double r = 0.0;
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      r += pow(X[i][j], 2);
  return (sqrt(r));
}
```
user: Translate the below assembly code into C programming language:

```asm
<frob_norm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L57
  mov    %edx,%r13d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r14
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r12
  pxor   %xmm2,%xmm2
  movsd  %xmm2,0x8(%rsp)
  jmp    L35
L32:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L32
L2:
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L42
L35:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L32
  jmp    L2
L42:
  pxor   %xmm0,%xmm0
  ucomisd 0x8(%rsp),%xmm0
  ja     L11
L48:
  movsd  0x8(%rsp),%xmm0
  sqrtsd %xmm0,%xmm0
L73:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L48
L11:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L73
```

assistant: ```c
double frob_norm(double **X, int m, int n) {
  double r = 0.0;
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      r += pow(X[i][j], 2);
  return (sqrt(r));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<frob_norm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r14
  movq   $0x0,0x8(%rsp)
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L37
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%r14),%rax
  mov    $0x2,%edi
  movsd  (%rax,%rbx,1),%xmm0
  add    $0x8,%rbx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbx,%rbp
  jne    L30
L37:
  add    $0x8,%r14
  cmp    %r13,%r14
  jne    L32
  pxor   %xmm2,%xmm2
  ucomisd 0x8(%rsp),%xmm2
  ja     L31
L22:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  sqrtsd %xmm0,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L22
L31:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double frob_norm(double **X, int m, int n) {
  double r = 0.0;
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      r += pow(X[i][j], 2);
  return (sqrt(r));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<frob_norm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L22
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r14
  movq   $0x0,0x8(%rsp)
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L12
  nopw   0x0(%rax,%rax,1)
L45:
  mov    (%r14),%rax
  mov    $0x2,%edi
  movsd  (%rax,%rbx,1),%xmm0
  add    $0x8,%rbx
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %rbx,%rbp
  jne    L45
L12:
  add    $0x8,%r14
  cmp    %r13,%r14
  jne    L36
  pxor   %xmm2,%xmm2
  ucomisd 0x8(%rsp),%xmm2
  ja     L11
L7:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  sqrtsd %xmm0,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L7
L11:
  movsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double frob_norm(double **X, int m, int n) {
  double r = 0.0;
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      r += pow(X[i][j], 2);
  return (sqrt(r));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  je     L1
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
L1:
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getNumberAsBin@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int main(int argc, char *args[]) {
  int n;
  if (argc)
    n = atoi(args[1]);
  char *binBuff;
  getNumberAsBin(n, &binBuff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  test   %edi,%edi
  jne    L18
L17:
  mov    %rsp,%rsi
  mov    %eax,%edi
  call   <getNumberAsBin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L18:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  jmp    L17
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *args[]) {
  int n;
  if (argc)
    n = atoi(args[1]);
  char *binBuff;
  getNumberAsBin(n, &binBuff);
}
```