ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<nvm_operation>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%eax
  and    $0x1fffffff,%eax
  movabs %eax,0xbf80f420
  mov    %edx,%eax
  movabs %eax,0xbf80f430
  mov    $0x0,%eax
  call   <mips_intr_disable@plt>
  mov    %eax,%ebp
  mov    %ebx,%eax
  or     $0x40,%ah
  movabs %eax,0xbf80f400
  mov    $0x7,%edi
  call   <udelay@plt>
  mov    $0xbf80f410,%eax
  movl   $0xaa996655,(%rax)
  movl   $0x556699aa,(%rax)
  lea    -0x8(%rax),%rax
  movl   $0x8000,(%rax)
  mov    $0xbf80f400,%edx
L9:
  mov    (%rdx),%eax
  test   $0x80,%ah
  jne    L9
  mov    $0xbf80f404,%eax
  movl   $0x4000,(%rax)
  mov    %ebp,%edi
  call   <mips_intr_restore@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void nvm_operation(unsigned op, unsigned address, unsigned data) {
  int x;
  *(volatile unsigned *)(0xBF800000 + (0x0F420)) = address & 0x1fffffff;
  *(volatile unsigned *)(0xBF800000 + (0x0F430)) = data;
  x = mips_intr_disable();
  *(volatile unsigned *)(0xBF800000 + (0x0F400)) = 0x00004000 | op;
  udelay(7);
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0xAA996655;
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0x556699AA;
  *(volatile unsigned *)(0xBF800000 + (0x0F408)) = 0x00008000;
  while (*(volatile unsigned *)(0xBF800000 + (0x0F400)) & 0x00008000)
    continue;
  *(volatile unsigned *)(0xBF800000 + (0x0F404)) = 0x00004000;
  mips_intr_restore(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nvm_operation>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    $0xbf80f400,%r12d
  and    $0x1fffffff,%eax
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movabs %eax,0xbf80f420
  mov    %edx,%eax
  or     $0x40,%bh
  movabs %eax,0xbf80f430
  xor    %eax,%eax
  call   <mips_intr_disable@plt>
  mov    %ebx,(%r12)
  mov    $0x7,%edi
  mov    %eax,%ebp
  call   <udelay@plt>
  mov    $0xbf80f410,%eax
  movl   $0xaa996655,(%rax)
  movl   $0x556699aa,(%rax)
  movl   $0x8000,-0x8(%rax)
L3:
  mov    (%r12),%eax
  test   $0x80,%ah
  jne    L3
  mov    $0xbf80f404,%eax
  mov    %ebp,%edi
  movl   $0x4000,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <mips_intr_restore@plt>
```

assistant: ```c
void nvm_operation(unsigned op, unsigned address, unsigned data) {
  int x;
  *(volatile unsigned *)(0xBF800000 + (0x0F420)) = address & 0x1fffffff;
  *(volatile unsigned *)(0xBF800000 + (0x0F430)) = data;
  x = mips_intr_disable();
  *(volatile unsigned *)(0xBF800000 + (0x0F400)) = 0x00004000 | op;
  udelay(7);
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0xAA996655;
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0x556699AA;
  *(volatile unsigned *)(0xBF800000 + (0x0F408)) = 0x00008000;
  while (*(volatile unsigned *)(0xBF800000 + (0x0F400)) & 0x00008000)
    continue;
  *(volatile unsigned *)(0xBF800000 + (0x0F404)) = 0x00004000;
  mips_intr_restore(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nvm_operation>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    $0xbf80f400,%r12d
  and    $0x1fffffff,%eax
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movabs %eax,0xbf80f420
  mov    %edx,%eax
  or     $0x40,%bh
  movabs %eax,0xbf80f430
  xor    %eax,%eax
  call   <mips_intr_disable@plt>
  mov    %ebx,(%r12)
  mov    $0x7,%edi
  mov    %eax,%ebp
  call   <udelay@plt>
  mov    $0xbf80f410,%eax
  movl   $0xaa996655,(%rax)
  movl   $0x556699aa,(%rax)
  movl   $0x8000,-0x8(%rax)
L8:
  mov    (%r12),%eax
  test   $0x80,%ah
  jne    L8
  mov    $0xbf80f404,%eax
  mov    %ebp,%edi
  movl   $0x4000,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <mips_intr_restore@plt>
```

assistant: ```c
void nvm_operation(unsigned op, unsigned address, unsigned data) {
  int x;
  *(volatile unsigned *)(0xBF800000 + (0x0F420)) = address & 0x1fffffff;
  *(volatile unsigned *)(0xBF800000 + (0x0F430)) = data;
  x = mips_intr_disable();
  *(volatile unsigned *)(0xBF800000 + (0x0F400)) = 0x00004000 | op;
  udelay(7);
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0xAA996655;
  *(volatile unsigned *)(0xBF800000 + (0x0F410)) = 0x556699AA;
  *(volatile unsigned *)(0xBF800000 + (0x0F408)) = 0x00008000;
  while (*(volatile unsigned *)(0xBF800000 + (0x0F400)) & 0x00008000)
    continue;
  *(volatile unsigned *)(0xBF800000 + (0x0F404)) = 0x00004000;
  mips_intr_restore(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_ttymodes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_ttymodes(int pn) {
  int speed_code, n;
  ;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_ttymodes>:
  endbr64
  ret
```

assistant: ```c
void init_ttymodes(int pn) {
  int speed_code, n;
  ;
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_ttymodes>:
  endbr64
  ret
```

assistant: ```c
void init_ttymodes(int pn) {
  int speed_code, n;
  ;
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_ttymodes>:
  endbr64
  ret
```

assistant: ```c
void init_ttymodes(int pn) {
  int speed_code, n;
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cleanTokenList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  nop
L14:
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L14
  subl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L8:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x3ff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x3ff,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L29:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L8
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **cleanTokenList(char **tokenList) {
  char **tl;
  int len, i;
  len = 0;
  while (tokenList[len++])
    ;
  len--;
  len = (len + 1) / 2;
  tl = malloc((len + 1) * sizeof(char *));
  for (i = 0; i < len; i++) {
    tl[i] = malloc(1024 * sizeof(char));
    strncpy(tl[i], tokenList[i * 2], 1023);
    tl[i][1023] = 0;
  }
  tl[len] = NULL;
  return tl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanTokenList>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x1,%eax
L23:
  mov    %eax,%ebx
  add    $0x1,%rax
  cmpq   $0x0,-0x10(%r12,%rax,8)
  jne    L23
  mov    %ebx,%r13d
  shr    $0x1f,%r13d
  add    %ebx,%r13d
  sar    %r13d
  lea    0x8(,%r13,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    $0x1,%ebx
  jle    L2
  mov    $0x0,%ebx
L1:
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp,%rbx,8)
  mov    %rbx,%rax
  shl    $0x4,%rax
  mov    (%r12,%rax,1),%rsi
  mov    $0x3ff,%edx
  call   <strncpy@plt>
  mov    0x0(%rbp,%rbx,8),%rax
  movb   $0x0,0x3ff(%rax)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L1
L2:
  movslq %r13d,%r13
  movq   $0x0,0x0(%rbp,%r13,8)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **cleanTokenList(char **tokenList) {
  char **tl;
  int len, i;
  len = 0;
  while (tokenList[len++])
    ;
  len--;
  len = (len + 1) / 2;
  tl = malloc((len + 1) * sizeof(char *));
  for (i = 0; i < len; i++) {
    tl[i] = malloc(1024 * sizeof(char));
    strncpy(tl[i], tokenList[i * 2], 1023);
    tl[i][1023] = 0;
  }
  tl[len] = NULL;
  return tl;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cleanTokenList>:
  endbr64
  push   %r14
  mov    $0x1,%eax
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L24:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpq   $0x0,-0x10(%rbp,%rax,8)
  jne    L24
  sar    %r12d
  lea    0x8(,%r12,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  je     L10
  mov    %rax,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r13
  nopl   0x0(%rax)
L27:
  mov    $0x400,%edi
  add    $0x8,%rbx
  add    $0x10,%rbp
  call   <malloc@plt>
  mov    $0x3ff,%edx
  mov    %rax,-0x8(%rbx)
  mov    -0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbx),%rax
  movb   $0x0,0x3ff(%rax)
  cmp    %r13,%rbx
  jne    L27
L10:
  movslq %r12d,%r12
  mov    %r14,%rax
  movq   $0x0,(%r14,%r12,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **cleanTokenList(char **tokenList) {
  char **tl;
  int len, i;
  len = 0;
  while (tokenList[len++])
    ;
  len--;
  len = (len + 1) / 2;
  tl = malloc((len + 1) * sizeof(char *));
  for (i = 0; i < len; i++) {
    tl[i] = malloc(1024 * sizeof(char));
    strncpy(tl[i], tokenList[i * 2], 1023);
    tl[i][1023] = 0;
  }
  tl[len] = NULL;
  return tl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cleanTokenList>:
  endbr64
  push   %r14
  mov    $0x1,%eax
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L6:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmpq   $0x0,-0x10(%rbp,%rax,8)
  jne    L6
  sar    %r12d
  lea    0x8(,%r12,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  je     L5
  mov    %rax,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r13
  nopl   0x0(%rax)
L21:
  mov    $0x400,%edi
  add    $0x8,%rbx
  add    $0x10,%rbp
  call   <malloc@plt>
  mov    $0x3ff,%edx
  mov    %rax,-0x8(%rbx)
  mov    -0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbx),%rax
  movb   $0x0,0x3ff(%rax)
  cmp    %rbx,%r13
  jne    L21
L5:
  movslq %r12d,%r12
  mov    %r14,%rax
  movq   $0x0,(%r14,%r12,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **cleanTokenList(char **tokenList) {
  char **tl;
  int len, i;
  len = 0;
  while (tokenList[len++])
    ;
  len--;
  len = (len + 1) / 2;
  tl = malloc((len + 1) * sizeof(char *));
  for (i = 0; i < len; i++) {
    tl[i] = malloc(1024 * sizeof(char));
    strncpy(tl[i], tokenList[i * 2], 1023);
    tl[i][1023] = 0;
  }
  tl[len] = NULL;
  return tl;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L1
L0:
  movl   $0x5,-0x8(%rbp)
  jmp    L12
L19:
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x2,-0x8(%rbp)
L12:
  cmpl   $0x0,-0x8(%rbp)
  jg     L19
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x2,-0xc(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: n vale %d


assistant: ```c
int main() {
  int i, j, n;
  n = 0;
  for (i = 1; i <= 2; i++) {
    for (j = 5; j >= 1; j -= 2) {
      n = (n + i + j);
    }
  }
  printf("n vale %d\n", n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1b,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string

tool: D8: n vale %d


assistant: ```c
int main() {
  int i, j, n;
  n = 0;
  for (i = 1; i <= 2; i++) {
    for (j = 5; j >= 1; j -= 2) {
      n = (n + i + j);
    }
  }
  printf("n vale %d\n", n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1b,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: n vale %d


assistant: ```c
int main() {
  int i, j, n;
  n = 0;
  for (i = 1; i <= 2; i++) {
    for (j = 5; j >= 1; j -= 2) {
      n = (n + i + j);
    }
  }
  printf("n vale %d\n", n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1b,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: n vale %d


assistant: ```c
int main() {
  int i, j, n;
  n = 0;
  for (i = 1; i <= 2; i++) {
    for (j = 5; j >= 1; j -= 2) {
      n = (n + i + j);
    }
  }
  printf("n vale %d\n", n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_valid_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <check_nl_ct@plt>
  test   %eax,%eax
  jne    L7
  mov    -0x4(%rbp),%eax
  jmp    L10
L7:
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <ft_strchrrplc@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <ft_strctrim@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <is_piece@plt>
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
L10:
  leave
  ret
```

assistant: ```c
int is_valid_block(char *input) {
  int result;
  result = -1;
  if (input) {
    if (!check_nl_ct(input))
      return (result);
    ft_strchrrplc(input, '\n', '.');
    input = ft_strctrim(input, '.');
    result = is_piece(input);
  }
  return (result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_valid_block>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  call   <check_nl_ct@plt>
  test   %eax,%eax
  je     L15
  mov    $0x2e,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <ft_strchrrplc@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <ft_strctrim@plt>
  mov    %rax,%rdi
  call   <is_piece@plt>
L2:
  pop    %rbx
  ret
L4:
  mov    $0xffffffff,%eax
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int is_valid_block(char *input) {
  int result;
  result = -1;
  if (input) {
    if (!check_nl_ct(input))
      return (result);
    ft_strchrrplc(input, '\n', '.');
    input = ft_strctrim(input, '.');
    result = is_piece(input);
  }
  return (result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_valid_block>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  call   <check_nl_ct@plt>
  test   %eax,%eax
  je     L5
  mov    %rbp,%rdi
  mov    $0x2e,%edx
  mov    $0xa,%esi
  call   <ft_strchrrplc@plt>
  mov    %rbp,%rdi
  mov    $0x2e,%esi
  call   <ft_strctrim@plt>
  pop    %rbp
  mov    %rax,%rdi
  jmp    10b0 <is_piece@plt>
  xchg   %ax,%ax
L5:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L2:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int is_valid_block(char *input) {
  int result;
  result = -1;
  if (input) {
    if (!check_nl_ct(input))
      return (result);
    ft_strchrrplc(input, '\n', '.');
    input = ft_strctrim(input, '.');
    result = is_piece(input);
  }
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_valid_block>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbp
  mov    %rdi,%rbp
  call   <check_nl_ct@plt>
  test   %eax,%eax
  je     L9
  mov    %rbp,%rdi
  mov    $0x2e,%edx
  mov    $0xa,%esi
  call   <ft_strchrrplc@plt>
  mov    %rbp,%rdi
  mov    $0x2e,%esi
  call   <ft_strctrim@plt>
  pop    %rbp
  mov    %rax,%rdi
  jmp    10b0 <is_piece@plt>
  xchg   %ax,%ax
L9:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L11:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int is_valid_block(char *input) {
  int result;
  result = -1;
  if (input) {
    if (!check_nl_ct(input))
      return (result);
    ft_strchrrplc(input, '\n', '.');
    input = ft_strctrim(input, '.');
    result = is_piece(input);
  }
  return (result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  char *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rcx
  mov    (%rcx),%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  char *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  char *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *v[], int i, int j) {
  char *temp;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rdc_power_off>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rdc_reset2@plt>
  mov    $0x0,%eax
  call   <rdc_disable_clock@plt>
  mov    $0x0,%eax
  call   <rdc_enable_pg_vbat@plt>
  mov    $0x0,%eax
  call   <rdc_enable_pg_v1p2@plt>
  mov    $0x0,%eax
  call   <rdc_disable_vref@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rdc_power_off() {
  rdc_reset2();
  rdc_disable_clock();
  rdc_enable_pg_vbat();
  rdc_enable_pg_v1p2();
  rdc_disable_vref();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rdc_power_off>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rdc_reset2@plt>
  mov    $0x0,%eax
  call   <rdc_disable_clock@plt>
  mov    $0x0,%eax
  call   <rdc_enable_pg_vbat@plt>
  mov    $0x0,%eax
  call   <rdc_enable_pg_v1p2@plt>
  mov    $0x0,%eax
  call   <rdc_disable_vref@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void rdc_power_off() {
  rdc_reset2();
  rdc_disable_clock();
  rdc_enable_pg_vbat();
  rdc_enable_pg_v1p2();
  rdc_disable_vref();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rdc_power_off>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rdc_reset2@plt>
  xor    %eax,%eax
  call   <rdc_disable_clock@plt>
  xor    %eax,%eax
  call   <rdc_enable_pg_vbat@plt>
  xor    %eax,%eax
  call   <rdc_enable_pg_v1p2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <rdc_disable_vref@plt>
```

assistant: ```c
void rdc_power_off() {
  rdc_reset2();
  rdc_disable_clock();
  rdc_enable_pg_vbat();
  rdc_enable_pg_v1p2();
  rdc_disable_vref();
}
```
user: What is the c source code of the assembly code below:

```asm
<rdc_power_off>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rdc_reset2@plt>
  xor    %eax,%eax
  call   <rdc_disable_clock@plt>
  xor    %eax,%eax
  call   <rdc_enable_pg_vbat@plt>
  xor    %eax,%eax
  call   <rdc_enable_pg_v1p2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <rdc_disable_vref@plt>
```

assistant: ```c
void rdc_power_off() {
  rdc_reset2();
  rdc_disable_clock();
  rdc_enable_pg_vbat();
  rdc_enable_pg_v1p2();
  rdc_disable_vref();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_at_be16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <read_be16@plt>
  leave
  ret
```

assistant: ```c
uint16_t read_at_be16(const void *src, size_t offset) {
  const uint8_t *s = src;
  s += offset;
  return read_be16(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_at_be16>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rsi,4),%rdi
  call   <read_be16@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t read_at_be16(const void *src, size_t offset) {
  const uint8_t *s = src;
  s += offset;
  return read_be16(s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_at_be16>:
  endbr64
  lea    (%rdi,%rsi,4),%rdi
  jmp    1050 <read_be16@plt>
```

assistant: ```c
uint16_t read_at_be16(const void *src, size_t offset) {
  const uint8_t *s = src;
  s += offset;
  return read_be16(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_at_be16>:
  endbr64
  lea    (%rdi,%rsi,4),%rdi
  jmp    1050 <read_be16@plt>
```

assistant: ```c
uint16_t read_at_be16(const void *src, size_t offset) {
  const uint8_t *s = src;
  s += offset;
  return read_be16(s);
}
```