ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L38
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L6
L38:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edx
  mov    %r13,%rdi
  call   <binary_search@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  je     L15
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D24
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string

tool: D3: How many items? 

tool: D8: %d

tool: D0: Enter numbers: 

tool: D24: Find: 

tool: D22: Data found at position %d

tool: D32: Data not found

assistant: ```c
int main() {
  int n, find;
  printf("How many items? ");
  scanf("%d", &n);
  int *input = (int *)malloc(n * sizeof(int));
  printf("Enter numbers: ");
  for (int i = 0; i < n; i++) {
    scanf("%d", input + i);
  }
  printf("Find: ");
  scanf("%d", &find);
  int position = binary_search(input, find, n);
  if (position != -1) {
    printf("Data found at position %d", position);
  } else {
    printf("Data not found");
  }
  free(input);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<remainder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <fpclassify@plt>
  mov    %eax,-0x4(%rbp)
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L36
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L59
L36:
  mov    D26(%rip),%rax
  movsd  (%rax),%xmm0
  jmp    L40
L59:
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  je     L14
  mov    D61(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L50
L14:
  mov    D53(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    %edx,(%rax)
  mov    D26(%rip),%rax
  movsd  (%rax),%xmm0
  jmp    L40
L50:
  mov    -0x20(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <fpu_remainder@plt>
  movsd  -0x18(%rbp),%xmm0
L40:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double remainder(double x, double y) {
  int xclass, yclass;
  xclass = fpclassify(x);
  yclass = fpclassify(y);
  if (xclass == FP_NAN || yclass == FP_NAN)
    return NAN;
  if (xclass == FP_INFINITE || yclass == FP_ZERO) {
    errno = EDOM;
    return NAN;
  }
  fpu_remainder(&x, y);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<remainder>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movq   %xmm1,%rbp
  call   <fpclassify@plt>
  mov    %eax,%ebx
  movq   %rbp,%xmm0
  call   <fpclassify@plt>
  mov    D3(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %eax,%edx
  je     L13
  cmp    %ebx,%edx
  je     L13
  mov    D67(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L39
  mov    D54(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L39
  lea    0x8(%rsp),%rdi
  movq   %rbp,%xmm0
  call   <fpu_remainder@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L41
L13:
  mov    D56(%rip),%rax
  movsd  (%rax),%xmm0
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  mov    D40(%rip),%rax
  mov    (%rax),%edx
  mov    D61(%rip),%rax
  mov    %edx,(%rax)
  mov    D56(%rip),%rax
  movsd  (%rax),%xmm0
  jmp    L41
```

assistant: ```c
double remainder(double x, double y) {
  int xclass, yclass;
  xclass = fpclassify(x);
  yclass = fpclassify(y);
  if (xclass == FP_NAN || yclass == FP_NAN)
    return NAN;
  if (xclass == FP_INFINITE || yclass == FP_ZERO) {
    errno = EDOM;
    return NAN;
  }
  fpu_remainder(&x, y);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remainder>:
  endbr64
  push   %r14
  movq   %xmm1,%r14
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <fpclassify@plt>
  movq   %r14,%xmm0
  mov    %eax,%ebx
  call   <fpclassify@plt>
  mov    D4(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %ebx,%edx
  je     L15
  cmp    %eax,%edx
  je     L15
  mov    D55(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L16
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L16
  movq   %r14,%xmm0
  lea    0x8(%rsp),%rdi
  call   <fpu_remainder@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
L15:
  mov    D40(%rip),%rax
  movsd  (%rax),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double remainder(double x, double y) {
  int xclass, yclass;
  xclass = fpclassify(x);
  yclass = fpclassify(y);
  if (xclass == FP_NAN || yclass == FP_NAN)
    return NAN;
  if (xclass == FP_INFINITE || yclass == FP_ZERO) {
    errno = EDOM;
    return NAN;
  }
  fpu_remainder(&x, y);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remainder>:
  endbr64
  push   %r14
  movq   %xmm1,%r14
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <fpclassify@plt>
  movq   %r14,%xmm0
  mov    %eax,%ebx
  call   <fpclassify@plt>
  mov    D31(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %ebx,%edx
  je     L22
  cmp    %eax,%edx
  je     L22
  mov    D32(%rip),%rdx
  cmp    %ebx,(%rdx)
  je     L25
  mov    D27(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L25
  movq   %r14,%xmm0
  lea    0x8(%rsp),%rdi
  call   <fpu_remainder@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    %edx,(%rax)
L22:
  mov    D35(%rip),%rax
  movsd  (%rax),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double remainder(double x, double y) {
  int xclass, yclass;
  xclass = fpclassify(x);
  yclass = fpclassify(y);
  if (xclass == FP_NAN || yclass == FP_NAN)
    return NAN;
  if (xclass == FP_INFINITE || yclass == FP_ZERO) {
    errno = EDOM;
    return NAN;
  }
  fpu_remainder(&x, y);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L22:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ft_putchar_fd@plt>
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
L12:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  if (s) {
    i = 0;
    while (s[i]) {
      ft_putchar_fd(s[i++], fd);
    }
  }
  ft_putchar_fd('\n', fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  test   %rdi,%rdi
  je     L21
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  lea    0x1(%rdi),%rbx
L13:
  movsbl %al,%edi
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L13
L21:
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  if (s) {
    i = 0;
    while (s[i]) {
      ft_putchar_fd(s[i++], fd);
    }
  }
  ft_putchar_fd('\n', fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L15
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
  lea    0x1(%rdi),%rbx
  nopl   0x0(%rax)
L4:
  movsbl %al,%edi
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <ft_putchar_fd@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L4
L15:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  if (s) {
    i = 0;
    while (s[i]) {
      ft_putchar_fd(s[i++], fd);
    }
  }
  ft_putchar_fd('\n', fd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_putendl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L3
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  lea    0x1(%rdi),%rbx
  nopl   0x0(%rax)
L19:
  movsbl %al,%edi
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <ft_putchar_fd@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L19
L3:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putendl_fd(char const *s, int fd) {
  int i;
  if (s) {
    i = 0;
    while (s[i]) {
      ft_putchar_fd(s[i++], fd);
    }
  }
  ft_putchar_fd('\n', fd);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L45
L56:
  addq   $0x1,-0x18(%rbp)
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L27
L37:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L22
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L22:
  addq   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  cmpq   $0x0,-0x8(%rbp)
  je     L43
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L20
L43:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L20:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip(char *str) {
  char *s;
  char *e = NULL;
  for (; isspace(*str); str++)
    ;
  for (s = str; *s; s++) {
    if (!isspace(*s))
      e = s;
  }
  if (e != NULL)
    e[1] = 0;
  else
    *str = 0;
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  jmp    L28
L12:
  add    $0x1,%rbp
L28:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L26
  mov    %rbp,%rbx
  mov    $0x0,%r12d
L20:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%r12
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L20
  test   %r12,%r12
  je     L26
  movb   $0x0,0x1(%r12)
L30:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  movb   $0x0,0x0(%rbp)
  jmp    L30
```

assistant: ```c
char *strip(char *str) {
  char *s;
  char *e = NULL;
  for (; isspace(*str); str++)
    ;
  for (s = str; *s; s++) {
    if (!isspace(*s))
      e = s;
  }
  if (e != NULL)
    e[1] = 0;
  else
    *str = 0;
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  jmp    L21
  nopl   (%rax)
L5:
  add    $0x1,%r12
L21:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L3
  mov    %r12,%rbx
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L13:
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
  test   %rbp,%rbp
  je     L3
  movb   $0x0,0x1(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *str) {
  char *s;
  char *e = NULL;
  for (; isspace(*str); str++)
    ;
  for (s = str; *s; s++) {
    if (!isspace(*s))
      e = s;
  }
  if (e != NULL)
    e[1] = 0;
  else
    *str = 0;
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  jmp    L0
  nopl   (%rax)
L28:
  add    $0x1,%r12
L0:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L28
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L30
  mov    %r12,%rbx
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L21:
  call   <isspace@plt>
  test   %rax,%rax
  cmove  %rbx,%rbp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L21
  test   %rbp,%rbp
  je     L30
  movb   $0x0,0x1(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r12)
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *str) {
  char *s;
  char *e = NULL;
  for (; isspace(*str); str++)
    ;
  for (s = str; *s; s++) {
    if (!isspace(*s))
      e = s;
  }
  if (e != NULL)
    e[1] = 0;
  else
    *str = 0;
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <insert@plt>
  mov    %rax,%rbx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <insert@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D55(%rip),%r14
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D18(%rip),%r13
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D59(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <delete@plt>
  mov    %rax,%rbx
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <search@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D55
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D59
data_type: string
name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D53
data_type: string

tool: D6: insert done

tool: D55: find 10: %d


tool: D18: find 3: %d


tool: D59: find 1: %d


tool: D3: find 20: %d


tool: D53: delete done

assistant: ```c
int main() {
  struct node *root = NULL;
  root = insert(root, 10);
  insert(root, 1);
  insert(root, 20);
  printf("insert done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  root = delete (root, 1);
  printf("delete done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  xor    %edi,%edi
  lea    D58(%rip),%r15
  push   %r14
  lea    D48(%rip),%r14
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <insert@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <search@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <search@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <search@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <search@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <delete@plt>
  lea    D54(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <search@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <search@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <search@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <search@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D58
data_type: string
name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D30
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D54
data_type: string

tool: D58: find 10: %d


tool: D48: find 3: %d


tool: D30: find 1: %d


tool: D13: find 20: %d


tool: D0: insert done

tool: D54: delete done

assistant: ```c
int main() {
  struct node *root = NULL;
  root = insert(root, 10);
  insert(root, 1);
  insert(root, 20);
  printf("insert done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  root = delete (root, 1);
  printf("delete done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  xor    %edi,%edi
  lea    D10(%rip),%r15
  push   %r14
  lea    D46(%rip),%r14
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  lea    D30(%rip),%r12
  push   %rbp
  call   <insert@plt>
  mov    $0x1,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <insert@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <search@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <search@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <search@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <search@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <delete@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <search@plt>
  mov    %r15,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <search@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <search@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x14,%esi
  call   <search@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D46
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D30
type: string
name: unpack_data
arguments: label: D59
type: string
name: unpack_data
arguments: label: D14
type: string

tool: D10: find 10: %d


tool: D46: find 3: %d


tool: D19: find 1: %d


tool: D30: find 20: %d


tool: D59: insert done

tool: D14: delete done

assistant: ```c
int main() {
  struct node *root = NULL;
  root = insert(root, 10);
  insert(root, 1);
  insert(root, 20);
  printf("insert done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  root = delete (root, 1);
  printf("delete done\n");
  printf("find 10: %d\n", search(root, 10));
  printf("find 3: %d\n", search(root, 3));
  printf("find 1: %d\n", search(root, 1));
  printf("find 20: %d\n", search(root, 20));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsbl -0x7(%rbp),%edx
  movswl -0x6(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movswl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  short a;
  char b;
  int c;
  c = b + a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  short a;
  char b;
  int c;
  c = b + a;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  short a;
  char b;
  int c;
  c = b + a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  short a;
  char b;
  int c;
  c = b + a;
  return a;
}
```