ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D18(%rip),%r14
  jmp    L0
L1:
  lea    0x2(%rbp),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %bl,(%r12,%rbp,1)
  movsbl %bl,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
L0:
  mov    %ebp,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  jne    L1
  movslq %ebp,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type_guessed: string
name: retrieve_data
arguments: tag: D12
type_guessed: string

tool: D18: 
%d_%c


tool: D12: 
%d_%s


assistant: ```c
int main() {
  char *string = malloc(sizeof(char));
  char scan;
  int n = 0;
  for (n = 0; (scan = getchar()) != '\n'; n++) {
    realloc(string, sizeof(char) * (n + 2));
    *(string + n) = scan;
    printf("\n%d_%c\n", n, *(string + n));
  }
  *(string + n) = '\0';
  printf("\n%d_%s\n", n, string);
  free(string);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%edi
  lea    D18(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L13
  nopl   0x0(%rax)
L3:
  lea    0x2(%rbp),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %bl,(%r12,%rbp,1)
  movsbl %bl,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
L13:
  xor    %eax,%eax
  mov    %ebp,%r13d
  call   <getchar@plt>
  mov    %eax,%ebx
  lea    (%r12,%rbp,1),%rax
  cmp    $0xa,%bl
  jne    L3
  movb   $0x0,(%rax)
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D18: 
%d_%c


tool: D4: 
%d_%s


assistant: ```c
int main() {
  char *string = malloc(sizeof(char));
  char scan;
  int n = 0;
  for (n = 0; (scan = getchar()) != '\n'; n++) {
    realloc(string, sizeof(char) * (n + 2));
    *(string + n) = scan;
    printf("\n%d_%c\n", n, *(string + n));
  }
  *(string + n) = '\0';
  printf("\n%d_%s\n", n, string);
  free(string);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1,%edi
  lea    D16(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L9
  nopl   0x0(%rax)
L12:
  lea    0x2(%rbp),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %bl,(%r12,%rbp,1)
  movsbl %bl,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
L9:
  xor    %eax,%eax
  mov    %ebp,%r13d
  call   <getchar@plt>
  mov    %eax,%ebx
  lea    (%r12,%rbp,1),%rax
  cmp    $0xa,%bl
  jne    L12
  movb   $0x0,(%rax)
  mov    %r12,%rdx
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string

tool: D16: 
%d_%c


tool: D13: 
%d_%s


assistant: ```c
int main() {
  char *string = malloc(sizeof(char));
  char scan;
  int n = 0;
  for (n = 0; (scan = getchar()) != '\n'; n++) {
    realloc(string, sizeof(char) * (n + 2));
    *(string + n) = scan;
    printf("\n%d_%c\n", n, *(string + n));
  }
  *(string + n) = '\0';
  printf("\n%d_%s\n", n, string);
  free(string);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<barFS_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: bar: %s


assistant: ```c
int barFS_write(const char *data) {
  printf("bar: %s\n", data);
  return (strlen(data));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<barFS_write>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: bar: %s


assistant: ```c
int barFS_write(const char *data) {
  printf("bar: %s\n", data);
  return (strlen(data));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<barFS_write>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: bar: %s


assistant: ```c
int barFS_write(const char *data) {
  printf("bar: %s\n", data);
  return (strlen(data));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<barFS_write>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: bar: %s


assistant: ```c
int barFS_write(const char *data) {
  printf("bar: %s\n", data);
  return (strlen(data));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcrop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L29:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L35
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L29
  jmp    L7
L35:
  nop
L7:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L18:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcrop(char *string) {
  char *last;
  if (string) {
    last = string + strlen(string);
    while (last > string) {
      if (!isspace(*(last - 1)))
        break;
      last--;
    }
    *last = 0;
  }
  return (string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcrop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L19
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  cmp    %rbx,%rbp
  jae    L6
L16:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L6
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L16
  mov    %rbp,%rbx
L6:
  movb   $0x0,(%rbx)
L19:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcrop(char *string) {
  char *last;
  if (string) {
    last = string + strlen(string);
    while (last > string) {
      if (!isspace(*(last - 1)))
        break;
      last--;
    }
    *last = 0;
  }
  return (string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcrop>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L18
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  cmp    %rbx,%r12
  jb     L34
  jmp    L24
  nopl   (%rax)
L32:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L24
L34:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L32
L24:
  movb   $0x0,(%rbx)
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcrop(char *string) {
  char *last;
  if (string) {
    last = string + strlen(string);
    while (last > string) {
      if (!isspace(*(last - 1)))
        break;
      last--;
    }
    *last = 0;
  }
  return (string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcrop>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L39
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  cmp    %rbx,%r12
  jb     L11
  jmp    L12
  nopl   (%rax)
L41:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L12
L11:
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L41
L12:
  movb   $0x0,(%rbx)
L39:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcrop(char *string) {
  char *last;
  if (string) {
    last = string + strlen(string);
    while (last > string) {
      if (!isspace(*(last - 1)))
        break;
      last--;
    }
    *last = 0;
  }
  return (string);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *des, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    des[i] = src[i];
    i++;
  }
  des[i] = '\0';
  return des;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L25
  mov    $0x0,%edx
L17:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L17
L6:
  movb   $0x0,(%rax,%rdx,1)
  ret
L25:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
char *strcpy(char *des, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    des[i] = src[i];
    i++;
  }
  des[i] = '\0';
  return des;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L0
  xor    %edx,%edx
L2:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L2
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *des, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    des[i] = src[i];
    i++;
  }
  des[i] = '\0';
  return des;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L5
  xor    %edx,%edx
L10:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L10
  add    %rax,%rdx
  movb   $0x0,(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rdx
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *strcpy(char *des, const char *src) {
  int i = 0;
  while (src[i] != '\0') {
    des[i] = src[i];
    i++;
  }
  des[i] = '\0';
  return des;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utc2local>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    %rax,%rdi
  movslq %ebx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rdi)
  imul   $0x64,%eax,%eax
  sub    %eax,%ebx
  mov    %ebx,0x4(%rdi)
  test   %r13,%r13
  je     L22
  mov    0x0(%r13),%eax
  cmp    $0xffffffff,%eax
  je     L22
  sub    $0x1,%eax
  mov    %eax,0x8(%rdi)
L22:
  test   %r12,%r12
  je     L83
  mov    (%r12),%eax
  cmp    $0xffffffff,%eax
  je     L83
  mov    %eax,0xc(%rdi)
L83:
  test   %rbp,%rbp
  je     L17
  mov    0x0(%rbp),%eax
  cmp    $0xffffffff,%eax
  je     L17
  mov    %eax,0x10(%rdi)
L17:
  call   <mkgmtime@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    %rax,%rdx
  test   %r13,%r13
  je     L103
  mov    0x8(%rax),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
L103:
  test   %r12,%r12
  je     L46
  mov    0xc(%rdx),%eax
  mov    %eax,(%r12)
L46:
  test   %rbp,%rbp
  je     L33
  mov    0x10(%rdx),%eax
  mov    %eax,0x0(%rbp)
L33:
  test   %r14,%r14
  je     L90
  mov    0x14(%rdx),%eax
  mov    %eax,(%r14)
L90:
  imul   $0x64,(%rdx),%eax
  add    0x4(%rdx),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utc2local(int hm, int *month, int *day, int *year, int *wday) {
  time_t t = time(NULL);
  struct tm *tm;
  tm = gmtime(&t);
  tm->tm_hour = hm / 100;
  tm->tm_min = hm % 100;
  if (month != NULL && *month != -1)
    tm->tm_mon = *month - 1;
  if (day != NULL && *day != -1)
    tm->tm_mday = *day;
  if (year != NULL && *year != -1)
    tm->tm_year = *year;
  t = mkgmtime(tm);
  tm = localtime(&t);
  if (month != NULL)
    *month = tm->tm_mon + 1;
  if (day != NULL)
    *day = tm->tm_mday;
  if (year != NULL)
    *year = tm->tm_year;
  if (wday != NULL)
    *wday = tm->tm_wday;
  return tm->tm_hour * 100 + tm->tm_min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utc2local>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <time@plt>
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    %ebp,%edx
  mov    %rax,%rdi
  movslq %ebp,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %edx,%eax
  mov    %eax,(%rdi)
  imul   $0x64,%eax,%eax
  sub    %eax,%ebp
  mov    %ebp,0x4(%rdi)
  test   %r13,%r13
  je     L71
  mov    0x0(%r13),%eax
  cmp    $0xffffffff,%eax
  je     L71
  sub    $0x1,%eax
  mov    %eax,0x8(%rdi)
L71:
  test   %r12,%r12
  je     L52
  mov    (%r12),%eax
  cmp    $0xffffffff,%eax
  je     L52
  mov    %eax,0xc(%rdi)
L52:
  test   %r15,%r15
  je     L66
  mov    (%r15),%eax
  cmp    $0xffffffff,%eax
  je     L66
  mov    %eax,0x10(%rdi)
L66:
  call   <mkgmtime@plt>
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %rax,%rdx
  test   %r13,%r13
  je     L70
  mov    0x8(%rax),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
L70:
  test   %r12,%r12
  je     L103
  mov    0xc(%rdx),%eax
  mov    %eax,(%r12)
L103:
  test   %r15,%r15
  je     L68
  mov    0x10(%rdx),%eax
  mov    %eax,(%r15)
L68:
  test   %rbx,%rbx
  je     L48
  mov    0x14(%rdx),%eax
  mov    %eax,(%rbx)
L48:
  imul   $0x64,(%rdx),%eax
  add    0x4(%rdx),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L93
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utc2local(int hm, int *month, int *day, int *year, int *wday) {
  time_t t = time(NULL);
  struct tm *tm;
  tm = gmtime(&t);
  tm->tm_hour = hm / 100;
  tm->tm_min = hm % 100;
  if (month != NULL && *month != -1)
    tm->tm_mon = *month - 1;
  if (day != NULL && *day != -1)
    tm->tm_mday = *day;
  if (year != NULL && *year != -1)
    tm->tm_year = *year;
  t = mkgmtime(tm);
  tm = localtime(&t);
  if (month != NULL)
    *month = tm->tm_mon + 1;
  if (day != NULL)
    *day = tm->tm_mday;
  if (year != NULL)
    *year = tm->tm_year;
  if (wday != NULL)
    *wday = tm->tm_wday;
  return tm->tm_hour * 100 + tm->tm_min;
}
```
user: What is the c source code of the assembly code below:

```asm
<utc2local>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <time@plt>
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    %ebp,%edx
  mov    %rax,%rdi
  movslq %ebp,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sub    %edx,%eax
  imul   $0x64,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%ebp
  movd   %ebp,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  test   %r13,%r13
  je     L100
  mov    0x0(%r13),%eax
  cmp    $0xffffffff,%eax
  je     L100
  sub    $0x1,%eax
  mov    %eax,0x8(%rdi)
L100:
  test   %r12,%r12
  je     L44
  mov    (%r12),%eax
  cmp    $0xffffffff,%eax
  je     L44
  mov    %eax,0xc(%rdi)
L44:
  test   %r15,%r15
  je     L28
  mov    (%r15),%eax
  cmp    $0xffffffff,%eax
  je     L28
  mov    %eax,0x10(%rdi)
L28:
  call   <mkgmtime@plt>
  mov    %r14,%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %rax,%rdx
  test   %r13,%r13
  je     L42
  mov    0x8(%rax),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
L42:
  test   %r12,%r12
  je     L12
  mov    0xc(%rdx),%eax
  mov    %eax,(%r12)
L12:
  test   %r15,%r15
  je     L49
  mov    0x10(%rdx),%eax
  mov    %eax,(%r15)
L49:
  test   %rbx,%rbx
  je     L108
  mov    0x14(%rdx),%eax
  mov    %eax,(%rbx)
L108:
  imul   $0x64,(%rdx),%eax
  add    0x4(%rdx),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utc2local(int hm, int *month, int *day, int *year, int *wday) {
  time_t t = time(NULL);
  struct tm *tm;
  tm = gmtime(&t);
  tm->tm_hour = hm / 100;
  tm->tm_min = hm % 100;
  if (month != NULL && *month != -1)
    tm->tm_mon = *month - 1;
  if (day != NULL && *day != -1)
    tm->tm_mday = *day;
  if (year != NULL && *year != -1)
    tm->tm_year = *year;
  t = mkgmtime(tm);
  tm = localtime(&t);
  if (month != NULL)
    *month = tm->tm_mon + 1;
  if (day != NULL)
    *day = tm->tm_mday;
  if (year != NULL)
    *year = tm->tm_year;
  if (wday != NULL)
    *wday = tm->tm_wday;
  return tm->tm_hour * 100 + tm->tm_min;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<endEMBL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L4
L17:
  mov    $0x1,%eax
  jmp    L25
L4:
  mov    $0x0,%eax
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string

tool: D4: //

tool: D19: ID   

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return ((strstr(s, "//") != NULL) || (strstr(s, "ID   ") == s));
}
```
user: What is the c source code of the assembly code below?

```asm
<endEMBL>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  lea    D1(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L10
L3:
  pop    %rbx
  ret
L10:
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D1: //

tool: D2: ID   

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return ((strstr(s, "//") != NULL) || (strstr(s, "ID   ") == s));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<endEMBL>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movl   $0x0,(%rsi)
  lea    D8(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L6
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rdi
  mov    $0x5,%edx
  lea    D5(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D8: //

tool: D5: ID   

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return ((strstr(s, "//") != NULL) || (strstr(s, "ID   ") == s));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<endEMBL>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  movl   $0x0,(%rsi)
  lea    D6(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L0
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbp,%rdi
  mov    $0x5,%edx
  lea    D15(%rip),%rsi
  call   <strncmp@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D6: //

tool: D15: ID   

assistant: ```c
int endEMBL(char *s, int *addend) {
  *addend = 0;
  return ((strstr(s, "//") != NULL) || (strstr(s, "ID   ") == s));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vc_release>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void vc_release(int handle, struct TalpaPacket_VettingDetails *packet) {
  (void)handle;
  free(packet);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vc_release>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void vc_release(int handle, struct TalpaPacket_VettingDetails *packet) {
  (void)handle;
  free(packet);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vc_release>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void vc_release(int handle, struct TalpaPacket_VettingDetails *packet) {
  (void)handle;
  free(packet);
  return;
}
```