ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L25
L48:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L48
  movl   $0x1,-0xc(%rbp)
  jmp    L21
L52:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x3,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L55
  mov    $0xa,%edi
  call   <putchar@plt>
L55:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L52
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D57
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D59
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string

tool: D57: Enter number of days in month: 

tool: D59: %d

tool: D37: Enter starting day of the week: 

tool: D9:     

tool: D22: %4d

assistant: ```c
int main(void) {
  int days_in_month, starting_day, i;
  printf("Enter number of days in month: ");
  scanf("%d", &days_in_month);
  printf("Enter starting day of the week: ");
  scanf("%d", &starting_day);
  for (i = 1; i < starting_day; i++)
    printf("    ");
  for (i = 1; i <= days_in_month; i++) {
    printf("%4d", i);
    if ((i + starting_day - 1) % 7 == 0)
      printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D36(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L32
  mov    $0x1,%ebx
  lea    D42(%rip),%rbp
L74:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L74
L32:
  cmpl   $0x0,(%rsp)
  jle    L20
  mov    $0x1,%ebx
  lea    D33(%rip),%rbp
  jmp    L68
L72:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L20
L68:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  add    0x4(%rsp),%edx
  sub    $0x1,%edx
  movslq %edx,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  cmp    %ecx,%edx
  jne    L72
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L72
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D48
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D42
type_guessed: string
name: parse_data
arguments: data_tag: D33
type_guessed: string

tool: D48: Enter number of days in month: 

tool: D36: %d

tool: D19: Enter starting day of the week: 

tool: D42:     

tool: D33: %4d

assistant: ```c
int main(void) {
  int days_in_month, starting_day, i;
  printf("Enter number of days in month: ");
  scanf("%d", &days_in_month);
  printf("Enter starting day of the week: ");
  scanf("%d", &starting_day);
  for (i = 1; i < starting_day; i++)
    printf("    ");
  for (i = 1; i <= days_in_month; i++) {
    printf("%4d", i);
    if ((i + starting_day - 1) % 7 == 0)
      printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  lea    D23(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L52
  mov    $0x1,%ebx
  lea    D33(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L34
L52:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L74
  mov    $0x1,%ebx
  lea    D14(%rip),%rbp
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L74
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %ebx,%eax
  sub    $0x1,%eax
  imul   $0xb6db6db7,%eax,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  ja     L6
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,(%rsp)
  jge    L10
L74:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D33
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string

tool: D20: Enter number of days in month: 

tool: D23: %d

tool: D27: Enter starting day of the week: 

tool: D33:     

tool: D14: %4d

assistant: ```c
int main(void) {
  int days_in_month, starting_day, i;
  printf("Enter number of days in month: ");
  scanf("%d", &days_in_month);
  printf("Enter starting day of the week: ");
  scanf("%d", &starting_day);
  for (i = 1; i < starting_day; i++)
    printf("    ");
  for (i = 1; i <= days_in_month; i++) {
    printf("%4d", i);
    if ((i + starting_day - 1) % 7 == 0)
      printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  lea    D41(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L6
  mov    $0x1,%ebx
  lea    D13(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L15
L6:
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %ebx,%eax
  sub    $0x1,%eax
  imul   $0xb6db6db7,%eax,%eax
  add    $0x12492492,%eax
  cmp    $0x24924924,%eax
  jbe    L30
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L10
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,(%rsp)
  jge    L10
  jmp    L20
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D41
type_infered: string
name: extract_symbolic_data
arguments: data_label: D48
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D33: Enter number of days in month: 

tool: D41: %d

tool: D48: Enter starting day of the week: 

tool: D13:     

tool: D5: %4d

assistant: ```c
int main(void) {
  int days_in_month, starting_day, i;
  printf("Enter number of days in month: ");
  scanf("%d", &days_in_month);
  printf("Enter starting day of the week: ");
  scanf("%d", &starting_day);
  for (i = 1; i < starting_day; i++)
    printf("    ");
  for (i = 1; i <= days_in_month; i++) {
    printf("%4d", i);
    if ((i + starting_day - 1) % 7 == 0)
      printf("\n");
  }
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LZ4IO_baseName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x18(%rbp),%rax
  mov    $0x5c,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
L0:
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  jmp    L19
L3:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L19:
  leave
  ret
```

assistant: ```c
const char *LZ4IO_baseName(const char *input_filename) {
  const char *b = strrchr(input_filename, '/');
  if (!b)
    b = strrchr(input_filename, '\\');
  if (!b)
    return input_filename;
  return b + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LZ4IO_baseName>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L5
L18:
  add    $0x1,%rax
L2:
  pop    %rbx
  ret
L5:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbx,%rax
  jmp    L2
```

assistant: ```c
const char *LZ4IO_baseName(const char *input_filename) {
  const char *b = strrchr(input_filename, '/');
  if (!b)
    b = strrchr(input_filename, '\\');
  if (!b)
    return input_filename;
  return b + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<LZ4IO_baseName>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L10
L12:
  add    $0x1,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L10:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L12
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *LZ4IO_baseName(const char *input_filename) {
  const char *b = strrchr(input_filename, '/');
  if (!b)
    b = strrchr(input_filename, '\\');
  if (!b)
    return input_filename;
  return b + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LZ4IO_baseName>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L19
L5:
  add    $0x1,%rax
  pop    %rbx
  ret
  nopl   (%rax)
L19:
  mov    $0x5c,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *LZ4IO_baseName(const char *input_filename) {
  const char *b = strrchr(input_filename, '/');
  if (!b)
    b = strrchr(input_filename, '\\');
  if (!b)
    return input_filename;
  return b + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decodeMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L35:
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L21:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L21
  addl   $0x1,-0x18(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  cmp    %eax,-0x18(%rbp)
  jl     L35
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *decodeMatrix(char *text, int key) {
  const int size = strlen(text);
  char *output = malloc(sizeof(char) * strlen(text));
  for (int i = 0, c = 0; i < size / key; i++) {
    for (int j = 0; j < key; j++) {
      output[c++] = text[i + j * (size / key)];
    }
  }
  output[size] = '\0';
  return output;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decodeMatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r10
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %eax,%eax
  jle    L21
  mov    %eax,%r13d
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  movslq %eax,%rdi
  mov    %ebx,%r11d
  add    %r10,%r11
  jmp    L44
L10:
  lea    0x0(%rbp,%r8,1),%rcx
  movslq %r9d,%rax
  lea    (%r10,%rax,1),%rdx
  add    %r11,%rax
L45:
  movzbl (%rcx),%esi
  mov    %sil,(%rdx)
  add    %rdi,%rcx
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L45
  add    %ebx,%r9d
L39:
  add    $0x1,%r8
  cmp    %r13,%r8
  je     L21
L44:
  test   %ebx,%ebx
  jg     L10
  jmp    L39
L21:
  movslq %r12d,%r12
  movb   $0x0,(%r10,%r12,1)
  mov    %r10,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *decodeMatrix(char *text, int key) {
  const int size = strlen(text);
  char *output = malloc(sizeof(char) * strlen(text));
  for (int i = 0, c = 0; i < size / key; i++) {
    for (int j = 0; j < key; j++) {
      output[c++] = text[i + j * (size / key)];
    }
  }
  output[size] = '\0';
  return output;
}
```
user: What is the c source code of the assembly code below?

```asm
<decodeMatrix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r11
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %eax,%eax
  jle    L4
  movslq %eax,%r8
  movslq %ebx,%rax
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  add    %r11,%rax
L3:
  test   %ebx,%ebx
  jle    L32
  movslq %r10d,%rdi
  lea    0x0(%rbp,%r9,1),%rcx
  lea    (%r11,%rdi,1),%rdx
  add    %rax,%rdi
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl (%rcx),%esi
  add    $0x1,%rdx
  add    %r8,%rcx
  mov    %sil,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L38
  add    %ebx,%r10d
L32:
  add    $0x1,%r9
  cmp    %r8,%r9
  jne    L3
L4:
  movb   $0x0,(%r11,%r12,1)
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *decodeMatrix(char *text, int key) {
  const int size = strlen(text);
  char *output = malloc(sizeof(char) * strlen(text));
  for (int i = 0, c = 0; i < size / key; i++) {
    for (int j = 0; j < key; j++) {
      output[c++] = text[i + j * (size / key)];
    }
  }
  output[size] = '\0';
  return output;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decodeMatrix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r11
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %eax,%eax
  jle    L29
  test   %ebx,%ebx
  jle    L29
  movslq %eax,%r8
  movslq %ebx,%rax
  xor    %r9d,%r9d
  xor    %r10d,%r10d
  add    %r11,%rax
  nopl   0x0(%rax)
L25:
  movslq %r10d,%rdi
  lea    0x0(%rbp,%r9,1),%rcx
  lea    (%r11,%rdi,1),%rdx
  add    %rax,%rdi
  nopw   0x0(%rax,%rax,1)
L28:
  movzbl (%rcx),%esi
  add    $0x1,%rdx
  add    %r8,%rcx
  mov    %sil,-0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L28
  add    $0x1,%r9
  add    %ebx,%r10d
  cmp    %r8,%r9
  jne    L25
L29:
  movb   $0x0,(%r11,%r12,1)
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *decodeMatrix(char *text, int key) {
  const int size = strlen(text);
  char *output = malloc(sizeof(char) * strlen(text));
  for (int i = 0, c = 0; i < size / key; i++) {
    for (int j = 0; j < key; j++) {
      output[c++] = text[i + j * (size / key)];
    }
  }
  output[size] = '\0';
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L22
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L22:
  lea    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readdir_r@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  je     L18
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
L18:
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  je     L21
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L22
L21:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D32
type_guessed: string

tool: D3: .

tool: D16: opening directory failed

tool: D37: readdir_r error

tool: D32: inode: %lld, name: %s


assistant: ```c
int main(int argc, char **argv) {
  char *d_to_open = ".";
  DIR *dstream = opendir(d_to_open);
  if (dstream == NULL) {
    perror("opening directory failed");
    exit(2);
  }
  struct dirent d;
  struct dirent *result;
  for (;;) {
    int ret = readdir_r(dstream, &d, &result);
    if (ret != 0) {
      perror("readdir_r error");
      exit(3);
    }
    if (!result) {
      break;
    }
    printf("inode: %lld, name: %s\n", (long long)d.d_ino, d.d_name);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
L28:
  lea    0x8(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D25(%rip),%r14
  lea    D33(%rip),%r13
  jmp    L41
L33:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L28
L30:
  cmpq   $0x0,0x8(%rsp)
  je     L57
  mov    0x10(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
L41:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readdir_r@plt>
  test   %eax,%eax
  je     L30
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L30
L57:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D33
type_infered: string
name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D7: .

tool: D25: readdir_r error

tool: D33: inode: %lld, name: %s


tool: D1: opening directory failed

assistant: ```c
int main(int argc, char **argv) {
  char *d_to_open = ".";
  DIR *dstream = opendir(d_to_open);
  if (dstream == NULL) {
    perror("opening directory failed");
    exit(2);
  }
  struct dirent d;
  struct dirent *result;
  for (;;) {
    int ret = readdir_r(dstream, &d, &result);
    if (ret != 0) {
      perror("readdir_r error");
      exit(3);
    }
    if (!result) {
      break;
    }
    printf("inode: %lld, name: %s\n", (long long)d.d_ino, d.d_name);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L37:
  lea    0x8(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    D39(%rip),%r14
  lea    D23(%rip),%r13
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L25:
  cmpq   $0x0,0x8(%rsp)
  je     L19
L23:
  mov    0x10(%rsp),%edx
  mov    0x18(%rsp),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
L38:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readdir_r@plt>
  test   %eax,%eax
  je     L25
  mov    %r14,%rdi
  call   <perror@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  cmpq   $0x0,0x8(%rsp)
  jne    L23
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  lea    D17(%rip),%rdi
  call   <perror@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L37
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D39
type_infered: string
name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D17
type_infered: string

tool: D25: .

tool: D39: readdir_r error

tool: D23: inode: %lld, name: %s


tool: D17: opening directory failed

assistant: ```c
int main(int argc, char **argv) {
  char *d_to_open = ".";
  DIR *dstream = opendir(d_to_open);
  if (dstream == NULL) {
    perror("opening directory failed");
    exit(2);
  }
  struct dirent d;
  struct dirent *result;
  for (;;) {
    int ret = readdir_r(dstream, &d, &result);
    if (ret != 0) {
      perror("readdir_r error");
      exit(3);
    }
    if (!result) {
      break;
    }
    printf("inode: %lld, name: %s\n", (long long)d.d_ino, d.d_name);
  }
  return 0;
}
```