ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csum>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    (%rdi,%rsi,2),%rcx
  nopl   0x0(%rax)
L2:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L2
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum = 0;
  for (sum = 0; nwords > 0; nwords--)
    sum += *buf++;
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<csum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L65
  cmp    $0x7,%esi
  jle    L105
  mov    %esi,%ecx
  pxor   %xmm2,%xmm2
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  shr    $0x3,%ecx
  pxor   %xmm3,%xmm3
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L76:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  movdqa %xmm0,%xmm5
  punpcklwd %xmm4,%xmm1
  punpckhdq %xmm3,%xmm0
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpckldq %xmm3,%xmm1
  punpckhdq %xmm3,%xmm5
  paddq  %xmm5,%xmm1
  paddq  %xmm1,%xmm0
  paddq  %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L76
  movdqa %xmm2,%xmm0
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  psrldq $0x8,%xmm0
  paddq  %xmm0,%xmm2
  mov    %ecx,%r8d
  sub    %ecx,%edx
  movq   %xmm2,%rax
  lea    (%rdi,%r8,2),%rdi
  cmp    %esi,%ecx
  je     L62
L6:
  movzwl (%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x1,%edx
  je     L62
  movzwl 0x2(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x2,%edx
  je     L62
  movzwl 0x4(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x3,%edx
  je     L62
  movzwl 0x6(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x4,%edx
  je     L62
  movzwl 0x8(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x5,%edx
  je     L62
  movzwl 0xa(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x6,%edx
  je     L62
  movzwl 0xc(%rdi),%edx
  add    %rdx,%rax
L62:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   (%rax)
L65:
  mov    $0xffffffff,%eax
  ret
L105:
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum = 0;
  for (sum = 0; nwords > 0; nwords--)
    sum += *buf++;
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ChompStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L10
L11:
  nop
L10:
  leave
  ret
```

assistant: ```c
void ChompStr(char *str) {
  if (str == NULL)
    return;
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ChompStr>:
  endbr64
  test   %rdi,%rdi
  je     L29
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L5
L3:
  pop    %rbx
  ret
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L3
L29:
  ret
```

assistant: ```c
void ChompStr(char *str) {
  if (str == NULL)
    return;
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<ChompStr>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L0
  pop    %rbx
  ret
  nopl   (%rax)
L9:
  ret
  nopl   0x0(%rax)
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void ChompStr(char *str) {
  if (str == NULL)
    return;
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ChompStr>:
  endbr64
  test   %rdi,%rdi
  je     L12
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L18
  pop    %rbx
  ret
  nopl   (%rax)
L12:
  ret
  nopl   0x0(%rax)
L18:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void ChompStr(char *str) {
  if (str == NULL)
    return;
  if (str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<appendHex2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movslq %esi,%rdx
  lea    D15(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movslq %esi,%rdx
  lea    D15(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
datatype: string

tool: D15: 0123456789abcdef

assistant: ```c
void appendHex2(char **pDstStr, int n) {
  *((*pDstStr)++) = "0123456789abcdef"[n >> 4];
  *((*pDstStr)++) = "0123456789abcdef"[n & 0xf];
  **pDstStr = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<appendHex2>:
  endbr64
  mov    (%rdi),%rcx
  lea    0x1(%rcx),%rax
  mov    %rax,(%rdi)
  lea    D7(%rip),%rdx
  mov    %esi,%eax
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  mov    %al,(%rcx)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%edx
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movb   $0x0,(%rax)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: 0123456789abcdef

assistant: ```c
void appendHex2(char **pDstStr, int n) {
  *((*pDstStr)++) = "0123456789abcdef"[n >> 4];
  *((*pDstStr)++) = "0123456789abcdef"[n & 0xf];
  **pDstStr = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<appendHex2>:
  endbr64
  mov    (%rdi),%rcx
  lea    D0(%rip),%rdx
  lea    0x1(%rcx),%rax
  mov    %rax,(%rdi)
  mov    %esi,%eax
  and    $0xf,%esi
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%rsi,1),%edx
  mov    %al,(%rcx)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movb   $0x0,(%rax)
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: 0123456789abcdef

assistant: ```c
void appendHex2(char **pDstStr, int n) {
  *((*pDstStr)++) = "0123456789abcdef"[n >> 4];
  *((*pDstStr)++) = "0123456789abcdef"[n & 0xf];
  **pDstStr = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<appendHex2>:
  endbr64
  mov    (%rdi),%rcx
  lea    D2(%rip),%rdx
  lea    0x1(%rcx),%rax
  mov    %rax,(%rdi)
  mov    %esi,%eax
  and    $0xf,%esi
  sar    $0x4,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%rsi,1),%edx
  mov    %al,(%rcx)
  mov    (%rdi),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,(%rdi)
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movb   $0x0,(%rax)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: 0123456789abcdef

assistant: ```c
void appendHex2(char **pDstStr, int n) {
  *((*pDstStr)++) = "0123456789abcdef"[n >> 4];
  *((*pDstStr)++) = "0123456789abcdef"[n & 0xf];
  **pDstStr = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <func1@plt>
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  func1();
  func2();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <func1@plt>
  mov    $0x0,%eax
  call   <func2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  func1();
  func2();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <func1@plt>
  xor    %eax,%eax
  call   <func2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  func1();
  func2();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <func1@plt>
  xor    %eax,%eax
  call   <func2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  func1();
  func2();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0xffffff80,%eax
  cmp    $0x5,%eax
  ja     L49
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <expose@plt>
  jmp    L49
  mov    -0x10(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <enternotify@plt>
  jmp    L49
  mov    -0x10(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <leavenotify@plt>
  jmp    L49
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <buttonpress@plt>
  jmp    L49
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <buttonrelease@plt>
  jmp    L49
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <unmapnotify@plt>
  nop
L49:
  nop
  leave
  ret
```

assistant: ```c
void event(void *self, XEvent *e) {
  switch (e->type) {
  case Expose:
    expose(self, &e->xexpose);
    break;
  case EnterNotify:
    enternotify(self, &e->xcrossing);
    break;
  case LeaveNotify:
    leavenotify(self, &e->xcrossing);
    break;
  case ButtonPress:
    buttonpress(self, &e->xbutton);
    break;
  case ButtonRelease:
    buttonrelease(self, &e->xbutton);
    break;
  case UnmapNotify:
    unmapnotify(self, &e->xunmap);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<event>:
  endbr64
  mov    (%rsi),%eax
  add    $0xffffff80,%eax
  cmp    $0x5,%eax
  ja     L56
  sub    $0x8,%rsp
  mov    %eax,%eax
  lea    D4(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  add    $0x10,%rsi
  call   <expose@plt>
L22:
  add    $0x8,%rsp
  ret
  add    $0xc,%rsi
  call   <enternotify@plt>
  jmp    L22
  add    $0xc,%rsi
  call   <leavenotify@plt>
  jmp    L22
  add    $0x8,%rsi
  call   <buttonpress@plt>
  jmp    L22
  add    $0x8,%rsi
  call   <buttonrelease@plt>
  jmp    L22
  add    $0x4,%rsi
  call   <unmapnotify@plt>
  jmp    L22
L56:
  ret
```

assistant: ```c
void event(void *self, XEvent *e) {
  switch (e->type) {
  case Expose:
    expose(self, &e->xexpose);
    break;
  case EnterNotify:
    enternotify(self, &e->xcrossing);
    break;
  case LeaveNotify:
    leavenotify(self, &e->xcrossing);
    break;
  case ButtonPress:
    buttonpress(self, &e->xbutton);
    break;
  case ButtonRelease:
    buttonrelease(self, &e->xbutton);
    break;
  case UnmapNotify:
    unmapnotify(self, &e->xunmap);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<event>:
  endbr64
  mov    (%rsi),%eax
  add    $0xffffff80,%eax
  cmp    $0x5,%eax
  ja     L9
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nop
  add    $0x8,%rsi
  jmp    10d0 <buttonrelease@plt>
  nopl   0x0(%rax)
  add    $0x8,%rsi
  jmp    10b0 <buttonpress@plt>
  nopl   0x0(%rax)
  add    $0x4,%rsi
  jmp    10c0 <unmapnotify@plt>
  nopl   0x0(%rax)
  add    $0xc,%rsi
  jmp    10e0 <leavenotify@plt>
  nopl   0x0(%rax)
  add    $0x10,%rsi
  jmp    10f0 <expose@plt>
  nopl   0x0(%rax)
  add    $0xc,%rsi
  jmp    10a0 <enternotify@plt>
L9:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: 

assistant: ```c
void event(void *self, XEvent *e) {
  switch (e->type) {
  case Expose:
    expose(self, &e->xexpose);
    break;
  case EnterNotify:
    enternotify(self, &e->xcrossing);
    break;
  case LeaveNotify:
    leavenotify(self, &e->xcrossing);
    break;
  case ButtonPress:
    buttonpress(self, &e->xbutton);
    break;
  case ButtonRelease:
    buttonrelease(self, &e->xbutton);
    break;
  case UnmapNotify:
    unmapnotify(self, &e->xunmap);
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<event>:
  endbr64
  mov    (%rsi),%eax
  add    $0xffffff80,%eax
  cmp    $0x5,%eax
  ja     L6
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nop
  add    $0x8,%rsi
  jmp    10d0 <buttonrelease@plt>
  nopl   0x0(%rax)
  add    $0x8,%rsi
  jmp    10b0 <buttonpress@plt>
  nopl   0x0(%rax)
  add    $0x4,%rsi
  jmp    10c0 <unmapnotify@plt>
  nopl   0x0(%rax)
  add    $0xc,%rsi
  jmp    10e0 <leavenotify@plt>
  nopl   0x0(%rax)
  add    $0x10,%rsi
  jmp    10f0 <expose@plt>
  nopl   0x0(%rax)
  add    $0xc,%rsi
  jmp    10a0 <enternotify@plt>
L6:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: 

assistant: ```c
void event(void *self, XEvent *e) {
  switch (e->type) {
  case Expose:
    expose(self, &e->xexpose);
    break;
  case EnterNotify:
    enternotify(self, &e->xcrossing);
    break;
  case LeaveNotify:
    leavenotify(self, &e->xcrossing);
    break;
  case ButtonPress:
    buttonpress(self, &e->xbutton);
    break;
  case ButtonRelease:
    buttonrelease(self, &e->xbutton);
    break;
  case UnmapNotify:
    unmapnotify(self, &e->xunmap);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<outsw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L19
L17:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
L19:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void outsw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *ap = *bp++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<outsw>:
  endbr64
  test   %edx,%edx
  je     L16
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
L19:
  add    $0x2,%rsi
  movzwl -0x2(%rsi),%eax
  mov    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L19
L16:
  ret
```

assistant: ```c
void outsw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *ap = *bp++;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<outsw>:
  endbr64
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
  xchg   %ax,%ax
L5:
  movzwl (%rsi),%eax
  add    $0x2,%rsi
  mov    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L5
L15:
  ret
```

assistant: ```c
void outsw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *ap = *bp++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<outsw>:
  endbr64
  test   %edx,%edx
  je     L17
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
  xchg   %ax,%ax
L13:
  movzwl (%rsi),%eax
  add    $0x2,%rsi
  mov    %ax,(%rdi)
  cmp    %rdx,%rsi
  jne    L13
L17:
  ret
```

assistant: ```c
void outsw(void *addr, void *buf, int len) {
  volatile unsigned short *ap = (volatile unsigned short *)addr;
  unsigned short *bp = (unsigned short *)buf;
  while (len--)
    *ap = *bp++;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
L82:
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  js     L82
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L33:
  movl   $0x0,-0x34(%rbp)
  jmp    L4
L56:
  mov    -0x38(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,%edi
  call   <HexNumber@plt>
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x20(%rbp,%rdx,1)
  mov    -0x38(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L4:
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jg     L56
  movl   $0x1,-0x28(%rbp)
  movl   $0x0,-0x30(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L8
L20:
  mov    -0x30(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L108
  movl   $0x0,-0x28(%rbp)
L108:
  addl   $0x1,-0x30(%rbp)
  subl   $0x1,-0x2c(%rbp)
L8:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L20
  cmpl   $0x0,-0x28(%rbp)
  jne    L77
  addl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x38(%rbp)
L77:
  cmpl   $0x0,-0x28(%rbp)
  je     L33
  movl   $0x0,-0x30(%rbp)
  jmp    L65
L57:
  mov    -0x30(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L65:
  mov    -0x30(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L103
  call   <__stack_chk_fail@plt>
L103:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D0
type: string

tool: D12: %d

tool: D0: %c

assistant: ```c
int main() {
  int number, i = 0, j = 0, k = 0, palindrom = 1, original;
  char array[20];
  do {
    scanf("%d", &number);
  } while (number < 0);
  original = number;
  do {
    i = 0;
    while (number > 0) {
      array[i] = HexNumber(number % 16);
      number = number / 16;
      i++;
    }
    palindrom = 1;
    for (j = 0, k = i - 1; j <= k; j++, k--) {
      if (array[j] != array[k]) {
        palindrom = 0;
      }
    }
    if (palindrom == 0) {
      original++;
      number = original;
    }
  } while (palindrom == 0);
  for (j = 0; j < i; j++) {
    printf("%c", array[j]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbx
L44:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r13d
  test   %r13d,%r13d
  js     L44
  mov    $0x0,%r12d
L74:
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  jle    L14
  mov    $0x0,%ebx
L93:
  mov    %ebx,%ebp
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  add    %eax,%edi
  and    $0xf,%edi
  sub    %eax,%edi
  call   <HexNumber@plt>
  mov    %al,0x10(%rsp,%rbx,1)
  mov    0xc(%rsp),%edx
  lea    0xf(%rdx),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x4,%eax
  mov    %eax,%edi
  mov    %eax,0xc(%rsp)
  lea    0x1(%rbx),%r8d
  mov    %rbx,%rsi
  add    $0x1,%rbx
  cmp    $0xf,%edx
  jg     L93
  test   %ebp,%ebp
  js     L97
  movslq %ebp,%rbp
  mov    $0x0,%eax
  mov    $0x1,%edx
  lea    0x10(%rsp),%rcx
L25:
  movzbl (%rcx,%rbp,1),%ebx
  cmp    %bl,(%rcx,%rax,1)
  cmovne %r12d,%edx
  add    $0x1,%rax
  sub    $0x1,%rbp
  cmp    %ebp,%eax
  jle    L25
  test   %edx,%edx
  jne    L97
  add    $0x1,%r13d
  mov    %r13d,0xc(%rsp)
  jmp    L74
L97:
  test   %r8d,%r8d
  jle    L14
  lea    0x10(%rsp),%rbx
  mov    %esi,%esi
  lea    0x11(%rsp,%rsi,1),%r12
  lea    D17(%rip),%rbp
L40:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L40
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string

tool: D1: %d

tool: D17: %c

assistant: ```c
int main() {
  int number, i = 0, j = 0, k = 0, palindrom = 1, original;
  char array[20];
  do {
    scanf("%d", &number);
  } while (number < 0);
  original = number;
  do {
    i = 0;
    while (number > 0) {
      array[i] = HexNumber(number % 16);
      number = number / 16;
      i++;
    }
    palindrom = 1;
    for (j = 0, k = i - 1; j <= k; j++, k--) {
      if (array[j] != array[k]) {
        palindrom = 0;
      }
    }
    if (palindrom == 0) {
      original++;
      number = original;
    }
  } while (palindrom == 0);
  for (j = 0; j < i; j++) {
    printf("%c", array[j]);
  }
}
```