ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<linear_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  jmp    L1
L7:
  addl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x9,-0x4(%rbp)
  jle    L10
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int linear_search(int a[], int x) {
  int i;
  for (i = 0; i < 10; i++) {
    if (a[i] == x)
      return i;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<linear_search>:
  endbr64
  mov    $0x0,%eax
L8:
  mov    %eax,%edx
  cmp    %esi,(%rdi,%rax,4)
  je     L13
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L8
  mov    $0xffffffff,%edx
L13:
  mov    %edx,%eax
  ret
```

assistant: ```c
int linear_search(int a[], int x) {
  int i;
  for (i = 0; i < 10; i++) {
    if (a[i] == x)
      return i;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<linear_search>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  je     L7
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L2
  mov    $0xffffffff,%r8d
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int linear_search(int a[], int x) {
  int i;
  for (i = 0; i < 10; i++) {
    if (a[i] == x)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linear_search>:
  endbr64
  cmp    (%rdi),%esi
  je     L32
  cmp    0x4(%rdi),%esi
  je     L28
  cmp    0x8(%rdi),%esi
  je     L80
  cmp    0xc(%rdi),%esi
  je     L67
  cmp    0x10(%rdi),%esi
  je     L68
  cmp    0x14(%rdi),%esi
  je     L7
  cmp    0x18(%rdi),%esi
  je     L39
  cmp    0x1c(%rdi),%esi
  je     L66
  cmp    0x20(%rdi),%esi
  je     L22
  cmp    %esi,0x24(%rdi)
  mov    $0x9,%edx
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
L32:
  xor    %eax,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
L80:
  mov    $0x2,%eax
  ret
L67:
  mov    $0x3,%eax
  ret
L68:
  mov    $0x4,%eax
  ret
L7:
  mov    $0x5,%eax
  ret
L39:
  mov    $0x6,%eax
  ret
L66:
  mov    $0x7,%eax
  ret
L22:
  mov    $0x8,%eax
  ret
```

assistant: ```c
int linear_search(int a[], int x) {
  int i;
  for (i = 0; i < 10; i++) {
    if (a[i] == x)
      return i;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isShortBranch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    $0x7f,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x10,-0x1(%rbp)
  jne    L61
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xb6,%al
  jne    L61
  mov    $0x1,%eax
  jmp    L24
L61:
  cmpb   $0x1e,-0x1(%rbp)
  je     L79
  cmpb   $0x1f,-0x1(%rbp)
  jne    L109
L79:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf0,%eax
  cmp    $0xc0,%eax
  jne    L109
  mov    $0x2,%eax
  jmp    L24
L109:
  cmpb   $0x7c,-0x1(%rbp)
  je     L22
  cmpb   $0x7d,-0x1(%rbp)
  je     L22
  cmpb   $0x7e,-0x1(%rbp)
  je     L22
  cmpb   $0x7f,-0x1(%rbp)
  jne    L10
L22:
  mov    $0x3,%eax
  jmp    L24
L10:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int isShortBranch(unsigned char *instr) {
  unsigned char instr0 = instr[0] & 0x7F;
  if (instr0 == 0x10 && instr[1] == 0xB6)
    return 1;
  if (instr0 == 0x1E || instr0 == 0x1F)
    if ((instr[1] & 0xF0) == 0xC0)
      return 2;
  if (instr0 == 0x7C || instr0 == 0x7D || instr0 == 0x7E || instr0 == 0x7F)
    return 3;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isShortBranch>:
  endbr64
  movzbl (%rdi),%eax
  and    $0x7f,%eax
  cmp    $0x10,%al
  je     L2
  lea    -0x1e(%rax),%edx
  cmp    $0x1,%dl
  ja     L8
  movzbl 0x1(%rdi),%eax
  and    $0xfffffff0,%eax
  cmp    $0xc0,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
L2:
  cmpb   $0xb6,0x1(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
L8:
  sub    $0x7c,%eax
  cmp    $0x4,%al
  sbb    %eax,%eax
  and    $0x3,%eax
  ret
```

assistant: ```c
int isShortBranch(unsigned char *instr) {
  unsigned char instr0 = instr[0] & 0x7F;
  if (instr0 == 0x10 && instr[1] == 0xB6)
    return 1;
  if (instr0 == 0x1E || instr0 == 0x1F)
    if ((instr[1] & 0xF0) == 0xC0)
      return 2;
  if (instr0 == 0x7C || instr0 == 0x7D || instr0 == 0x7E || instr0 == 0x7F)
    return 3;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isShortBranch>:
  endbr64
  movzbl (%rdi),%eax
  and    $0x7f,%eax
  cmp    $0x10,%al
  je     L6
  lea    -0x1e(%rax),%edx
  cmp    $0x1,%dl
  ja     L17
  movzbl 0x1(%rdi),%eax
  and    $0xfffffff0,%eax
  cmp    $0xc0,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x7c,%eax
  cmp    $0x4,%al
  sbb    %eax,%eax
  and    $0x3,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  cmpb   $0xb6,0x1(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isShortBranch(unsigned char *instr) {
  unsigned char instr0 = instr[0] & 0x7F;
  if (instr0 == 0x10 && instr[1] == 0xB6)
    return 1;
  if (instr0 == 0x1E || instr0 == 0x1F)
    if ((instr[1] & 0xF0) == 0xC0)
      return 2;
  if (instr0 == 0x7C || instr0 == 0x7D || instr0 == 0x7E || instr0 == 0x7F)
    return 3;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isShortBranch>:
  endbr64
  movzbl (%rdi),%eax
  and    $0x7f,%eax
  cmp    $0x10,%al
  je     L15
  lea    -0x1e(%rax),%edx
  cmp    $0x1,%dl
  ja     L12
  movzbl 0x1(%rdi),%eax
  and    $0xfffffff0,%eax
  cmp    $0xc0,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  sub    $0x7c,%eax
  cmp    $0x4,%al
  sbb    %eax,%eax
  and    $0x3,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  cmpb   $0xb6,0x1(%rdi)
  sete   %al
  ret
```

assistant: ```c
int isShortBranch(unsigned char *instr) {
  unsigned char instr0 = instr[0] & 0x7F;
  if (instr0 == 0x10 && instr[1] == 0xB6)
    return 1;
  if (instr0 == 0x1E || instr0 == 0x1F)
    if ((instr[1] & 0xF0) == 0xC0)
      return 2;
  if (instr0 == 0x7C || instr0 == 0x7D || instr0 == 0x7E || instr0 == 0x7F)
    return 3;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<priklad_tri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x6f696561,-0x76(%rbp)
  movw   $0x7975,-0x72(%rbp)
  movl   $0x0,-0x90(%rbp)
  movl   $0x0,-0x8c(%rbp)
  movl   $0x0,-0x88(%rbp)
  movl   $0x0,-0x84(%rbp)
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x7c(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x9c(%rbp)
  jmp    L10
L14:
  mov    -0x9c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x9c(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x70(%rbp,%rdx,1)
  movl   $0x0,-0x98(%rbp)
  jmp    L57
L67:
  mov    -0x9c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x98(%rbp),%eax
  cltq
  movzbl -0x76(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L35
  mov    -0x98(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x98(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
L35:
  addl   $0x1,-0x98(%rbp)
L57:
  lea    -0x76(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x98(%rbp)
  jl     L67
  addl   $0x1,-0x9c(%rbp)
L10:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x9c(%rbp)
  jl     L14
  movl   $0x0,-0x94(%rbp)
  jmp    L18
L65:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0x94(%rbp),%eax
  cltq
  movzbl -0x76(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x94(%rbp)
L18:
  lea    -0x76(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x94(%rbp)
  jl     L65
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string
name: retrieve_data
arguments: label: D21
type_infered: string

tool: D12: ========== PRIKLAD 3 ==========

tool: D1: %c existuje %dx


tool: D21: ========== KONEC PRIKLADU 3 ==========

assistant: ```c
void priklad_tri() {
  printf("========== PRIKLAD 3 ==========\n");
  char str1[100];
  char vzor[6] = {'a', 'e', 'i', 'o', 'u', 'y'};
  int vzorCetnost[6] = {0, 0, 0, 0, 0, 0};
  gets(str1);
  for (int i = 0; i < strlen(str1); i++) {
    str1[i] = tolower(str1[i]);
    for (int j = 0; j < strlen(vzor); j++) {
      if (str1[i] == vzor[j]) {
        vzorCetnost[j]++;
      }
    }
  }
  for (int i = 0; i < strlen(vzor); i++) {
    printf("%c existuje %dx\n", vzor[i], vzorCetnost[i]);
  }
  printf("========== KONEC PRIKLADU 3 ==========\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<priklad_tri>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  movl   $0x6f696561,0x1a(%rsp)
  movw   $0x7975,0x1e(%rsp)
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x20(%rsp),%r13
  mov    %r13,%rdi
  call   <gets@plt>
  mov    $0x0,%r14d
  mov    %r13,%r15
  jmp    L7
L26:
  add    $0x1,%rbx
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L14
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,(%r12)
  jne    L26
  addl   $0x1,(%rsp,%rbx,4)
  jmp    L26
L14:
  add    $0x1,%r14d
  add    $0x1,%r13
L7:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  jle    L79
  mov    %r13,%r12
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13)
  mov    $0x0,%ebx
  lea    0x1a(%rsp),%rbp
  jmp    L44
L79:
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
  jmp    L29
L24:
  mov    (%rsp,%rbx,4),%edx
  movsbl 0x1a(%rsp,%rbx,1),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
L29:
  lea    0x1a(%rsp),%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L24
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D3: ========== PRIKLAD 3 ==========

tool: D6: %c existuje %dx


tool: D24: ========== KONEC PRIKLADU 3 ==========

assistant: ```c
void priklad_tri() {
  printf("========== PRIKLAD 3 ==========\n");
  char str1[100];
  char vzor[6] = {'a', 'e', 'i', 'o', 'u', 'y'};
  int vzorCetnost[6] = {0, 0, 0, 0, 0, 0};
  gets(str1);
  for (int i = 0; i < strlen(str1); i++) {
    str1[i] = tolower(str1[i]);
    for (int j = 0; j < strlen(vzor); j++) {
      if (str1[i] == vzor[j]) {
        vzorCetnost[j]++;
      }
    }
  }
  for (int i = 0; i < strlen(vzor); i++) {
    printf("%c existuje %dx\n", vzor[i], vzorCetnost[i]);
  }
  printf("========== KONEC PRIKLADU 3 ==========\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<priklad_tri>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  lea    0x1a(%rsp),%rbp
  call   <puts@plt>
  mov    $0x7975,%eax
  mov    %r14,%rdi
  mov    %r14,%r12
  movl   $0x6f696561,0x1a(%rsp)
  mov    %ax,0x1e(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <gets@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jle    L62
  nopl   0x0(%rax,%rax,1)
L49:
  movsbl (%r12),%edi
  xor    %ebx,%ebx
  call   <tolower@plt>
  mov    %al,(%r12)
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,(%r12)
  jne    L58
  addl   $0x1,(%rsp,%rbx,4)
L58:
  add    $0x1,%rbx
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L40
  mov    %r14,%rdi
  add    $0x1,%r13d
  add    $0x1,%r12
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L49
L62:
  xor    %ebx,%ebx
  lea    D26(%rip),%r12
  jmp    L64
  nop
L66:
  mov    (%rsp,%rbx,4),%edx
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L64:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L66
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type_infered: string
name: unpack_data
arguments: data_tag: D26
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string

tool: D25: ========== PRIKLAD 3 ==========

tool: D26: %c existuje %dx


tool: D15: ========== KONEC PRIKLADU 3 ==========

assistant: ```c
void priklad_tri() {
  printf("========== PRIKLAD 3 ==========\n");
  char str1[100];
  char vzor[6] = {'a', 'e', 'i', 'o', 'u', 'y'};
  int vzorCetnost[6] = {0, 0, 0, 0, 0, 0};
  gets(str1);
  for (int i = 0; i < strlen(str1); i++) {
    str1[i] = tolower(str1[i]);
    for (int j = 0; j < strlen(vzor); j++) {
      if (str1[i] == vzor[j]) {
        vzorCetnost[j]++;
      }
    }
  }
  for (int i = 0; i < strlen(vzor); i++) {
    printf("%c existuje %dx\n", vzor[i], vzorCetnost[i]);
  }
  printf("========== KONEC PRIKLADU 3 ==========\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<priklad_tri>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  lea    0x1a(%rsp),%rbp
  call   <puts@plt>
  mov    $0x7975,%eax
  mov    %r14,%rdi
  mov    %r14,%r12
  pxor   %xmm0,%xmm0
  mov    %ax,0x1e(%rsp)
  movl   $0x6f696561,0x1a(%rsp)
  movq   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <gets@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jle    L21
  nopw   0x0(%rax,%rax,1)
L47:
  movsbl (%r12),%edi
  xor    %ebx,%ebx
  call   <tolower@plt>
  mov    %al,(%r12)
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L35:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,(%r12)
  jne    L26
  addl   $0x1,(%rsp,%rbx,4)
L26:
  add    $0x1,%rbx
L28:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L35
  mov    %r14,%rdi
  add    $0x1,%r13d
  add    $0x1,%r12
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L47
L21:
  xor    %ebx,%ebx
  lea    D19(%rip),%r12
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rsp,%rbx,4),%edx
  movsbl 0x0(%rbp,%rbx,1),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
L34:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string
name: retrieve_data
arguments: label: D5
data_type: string

tool: D0: ========== PRIKLAD 3 ==========

tool: D19: %c existuje %dx


tool: D5: ========== KONEC PRIKLADU 3 ==========

assistant: ```c
void priklad_tri() {
  printf("========== PRIKLAD 3 ==========\n");
  char str1[100];
  char vzor[6] = {'a', 'e', 'i', 'o', 'u', 'y'};
  int vzorCetnost[6] = {0, 0, 0, 0, 0, 0};
  gets(str1);
  for (int i = 0; i < strlen(str1); i++) {
    str1[i] = tolower(str1[i]);
    for (int j = 0; j < strlen(vzor); j++) {
      if (str1[i] == vzor[j]) {
        vzorCetnost[j]++;
      }
    }
  }
  for (int i = 0; i < strlen(vzor); i++) {
    printf("%c existuje %dx\n", vzor[i], vzorCetnost[i]);
  }
  printf("========== KONEC PRIKLADU 3 ==========\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setMicro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  ja     L31
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <setMicroFullStep@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <setMicroHalfStep@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <setMicroQuarterStep@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <setMicroEighthStep@plt>
  jmp    L18
  mov    $0x0,%eax
  call   <setMicroSixteenthStep@plt>
  jmp    L18
L31:
  mov    $0x0,%eax
  call   <setMicroSixteenthStep@plt>
  nop
L18:
  nop
  leave
  ret
```

assistant: ```c
void setMicro(int micro_mode) {
  switch (micro_mode) {
  case 1:
    setMicroFullStep();
    break;
  case 2:
    setMicroHalfStep();
    break;
  case 3:
    setMicroQuarterStep();
    break;
  case 4:
    setMicroEighthStep();
    break;
  case 5:
    setMicroSixteenthStep();
    break;
  default:
    setMicroSixteenthStep();
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setMicro>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x5,%edi
  ja     L34
  mov    %edi,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <setMicroFullStep@plt>
L15:
  add    $0x8,%rsp
  ret
  mov    $0x0,%eax
  call   <setMicroHalfStep@plt>
  jmp    L15
  mov    $0x0,%eax
  call   <setMicroQuarterStep@plt>
  jmp    L15
  mov    $0x0,%eax
  call   <setMicroEighthStep@plt>
  jmp    L15
  mov    $0x0,%eax
  call   <setMicroSixteenthStep@plt>
  jmp    L15
L34:
  mov    $0x0,%eax
  call   <setMicroSixteenthStep@plt>
  jmp    L15
```

assistant: ```c
void setMicro(int micro_mode) {
  switch (micro_mode) {
  case 1:
    setMicroFullStep();
    break;
  case 2:
    setMicroHalfStep();
    break;
  case 3:
    setMicroQuarterStep();
    break;
  case 4:
    setMicroEighthStep();
    break;
  case 5:
    setMicroSixteenthStep();
    break;
  default:
    setMicroSixteenthStep();
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<setMicro>:
  endbr64
  cmp    $0x3,%edi
  je     L13
  jg     L35
  cmp    $0x1,%edi
  je     L38
  cmp    $0x2,%edi
  jne    L28
  xor    %eax,%eax
  jmp    10a0 <setMicroHalfStep@plt>
  nopl   0x0(%rax)
L35:
  cmp    $0x4,%edi
  jne    L28
  xor    %eax,%eax
  jmp    1090 <setMicroEighthStep@plt>
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  jmp    10c0 <setMicroSixteenthStep@plt>
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  jmp    10b0 <setMicroFullStep@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    10d0 <setMicroQuarterStep@plt>
```

assistant: ```c
void setMicro(int micro_mode) {
  switch (micro_mode) {
  case 1:
    setMicroFullStep();
    break;
  case 2:
    setMicroHalfStep();
    break;
  case 3:
    setMicroQuarterStep();
    break;
  case 4:
    setMicroEighthStep();
    break;
  case 5:
    setMicroSixteenthStep();
    break;
  default:
    setMicroSixteenthStep();
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<setMicro>:
  endbr64
  cmp    $0x3,%edi
  je     L12
  jg     L37
  cmp    $0x1,%edi
  je     L43
  cmp    $0x2,%edi
  jne    L19
  xor    %eax,%eax
  jmp    10a0 <setMicroHalfStep@plt>
  nopl   0x0(%rax)
L37:
  cmp    $0x4,%edi
  jne    L19
  xor    %eax,%eax
  jmp    1090 <setMicroEighthStep@plt>
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  jmp    10c0 <setMicroSixteenthStep@plt>
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %eax,%eax
  jmp    10b0 <setMicroFullStep@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  jmp    10d0 <setMicroQuarterStep@plt>
```

assistant: ```c
void setMicro(int micro_mode) {
  switch (micro_mode) {
  case 1:
    setMicroFullStep();
    break;
  case 2:
    setMicroHalfStep();
    break;
  case 3:
    setMicroQuarterStep();
    break;
  case 4:
    setMicroEighthStep();
    break;
  case 5:
    setMicroSixteenthStep();
    break;
  default:
    setMicroSixteenthStep();
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L30:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  addl   $0x2,-0x10(%rbp)
L10:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L30
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L17:
  lea    -0xc(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0xc(%rbp),%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L17
  mov    -0xc(%rbp),%eax
  lea    -0x435bc7(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] *= state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = copy12;
      state[local1] = state[0UL] * state[0UL];
      local1++;
    }
    output[0UL] = (state[0UL] + 957911421UL) - 962325828U;
  }
}
```