ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L66:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L66
  sub    $0xaa8,%rsp
  lea    D7(%rip),%r12
  lea    D6(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  nopl   0x0(%rax)
L10:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L34
  jle    L75
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L13
L75:
  cmp    $0x1,%eax
  jle    L82
  mov    $0x1,%ebx
  xor    %r15d,%r15d
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax)
L85:
  mov    -0x4(%rbp,%rbx,4),%edi
  add    %edi,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  call   <abs@plt>
  add    %rax,%r15
  cmp    %ebx,0xc(%rsp)
  jg     L85
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L10
  nop
L34:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x61aa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  xor    %r15d,%r15d
  mov    %r14,%rdi
  mov    %r15,%rsi
  call   <printf@plt>
  jmp    L10
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D6
data_type: string

tool: D7: %d

tool: D6: %lld


assistant: ```c
int main() {
  int i, t;
  int a[100000];
  long long int sum = 0;
  while (1) {
    scanf("%d", &t);
    if (t == 0)
      break;
    for (i = 0; i < t; i++) {
      scanf("%d", &a[i]);
    }
    for (i = 1; i < t; i++) {
      a[i] += a[i - 1];
      sum += abs(a[i - 1]);
    }
    printf("%lld\n", sum);
    sum = 0;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getPress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2a,%edi
  call   <_getReg@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L24
  movss  D29(%rip),%xmm0
  jmp    L32
L24:
  movss  -0x8(%rbp),%xmm1
  movss  D53(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x29,%edi
  call   <_getReg@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L7
  movss  D29(%rip),%xmm0
  jmp    L32
L7:
  movss  -0x4(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D53(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x28,%edi
  call   <_getReg@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L35
  movss  D29(%rip),%xmm0
  jmp    L32
L35:
  movss  -0x4(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  D57(%rip),%xmm1
  divss  %xmm1,%xmm0
L32:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D29
type_infered: byte[4]
name: unpack_data
arguments: label: D53
type_infered: f32
name: unpack_data
arguments: label: D57
type_infered: f32

tool: {"D29": [0x00,0xc0,0x79,0xc4]}

tool: D53: 256

tool: D57: 4096

assistant: ```c
float getPress() {
  float ret, in;
  in = (float)_getReg(0x2A);
  if (in < 0)
    return -999.;
  ret = 256. * in;
  in = (float)_getReg(0x29);
  if (in < 0)
    return -999.;
  ret += in;
  ret *= 256.;
  in = (float)_getReg(0x28);
  if (in < 0)
    return -999.;
  ret += in;
  return ret / 4096.;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getPress>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2a,%edi
  call   <_getReg@plt>
  pxor   %xmm3,%xmm3
  cvtsi2ss %rax,%xmm3
  movss  D16(%rip),%xmm0
  pxor   %xmm1,%xmm1
  movss  %xmm3,0x8(%rsp)
  comiss %xmm3,%xmm1
  ja     L5
  mov    $0x29,%edi
  call   <_getReg@plt>
  pxor   %xmm4,%xmm4
  cvtsi2ss %rax,%xmm4
  movss  D16(%rip),%xmm0
  pxor   %xmm1,%xmm1
  movss  %xmm4,0xc(%rsp)
  comiss %xmm4,%xmm1
  ja     L5
  mov    $0x28,%edi
  call   <_getReg@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  ja     L12
  movss  D32(%rip),%xmm2
  movss  0x8(%rsp),%xmm0
  mulss  %xmm2,%xmm0
  addss  0xc(%rsp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  mulss  D17(%rip),%xmm0
L5:
  add    $0x18,%rsp
  ret
L12:
  movss  D16(%rip),%xmm0
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D32
type_guessed: f32
name: disassemble_data
arguments: data_label: D17
type_guessed: byte[4]

tool: {"D16": [0x00,0xc0,0x79,0xc4]}

tool: D32: 256

tool: {"D17": [0x00,0x00,0x80,0x39]}

assistant: ```c
float getPress() {
  float ret, in;
  in = (float)_getReg(0x2A);
  if (in < 0)
    return -999.;
  ret = 256. * in;
  in = (float)_getReg(0x29);
  if (in < 0)
    return -999.;
  ret += in;
  ret *= 256.;
  in = (float)_getReg(0x28);
  if (in < 0)
    return -999.;
  ret += in;
  return ret / 4096.;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getPress>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2a,%edi
  call   <_getReg@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm4,%xmm4
  cvtsi2ss %rax,%xmm1
  comiss %xmm1,%xmm4
  ja     L3
  mov    $0x29,%edi
  movss  %xmm1,0xc(%rsp)
  call   <_getReg@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm5,%xmm5
  cvtsi2ss %rax,%xmm0
  comiss %xmm0,%xmm5
  movss  %xmm0,0x8(%rsp)
  ja     L3
  mov    $0x28,%edi
  call   <_getReg@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm6,%xmm6
  cvtsi2ss %rax,%xmm2
  comiss %xmm2,%xmm6
  ja     L3
  movss  D4(%rip),%xmm3
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  mulss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  mulss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  addss  %xmm2,%xmm0
  mulss  D1(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L3:
  movss  D22(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: f32
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: byte[4]

tool: D4: 256

tool: {"D1": [0x00,0x00,0x80,0x39]}

tool: {"D22": [0x00,0xc0,0x79,0xc4]}

assistant: ```c
float getPress() {
  float ret, in;
  in = (float)_getReg(0x2A);
  if (in < 0)
    return -999.;
  ret = 256. * in;
  in = (float)_getReg(0x29);
  if (in < 0)
    return -999.;
  ret += in;
  ret *= 256.;
  in = (float)_getReg(0x28);
  if (in < 0)
    return -999.;
  ret += in;
  return ret / 4096.;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getPress>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2a,%edi
  call   <_getReg@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm4,%xmm4
  cvtsi2ss %rax,%xmm1
  comiss %xmm1,%xmm4
  ja     L0
  mov    $0x29,%edi
  movss  %xmm1,0xc(%rsp)
  call   <_getReg@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm5,%xmm5
  cvtsi2ss %rax,%xmm0
  comiss %xmm0,%xmm5
  movss  %xmm0,0x8(%rsp)
  ja     L0
  mov    $0x28,%edi
  call   <_getReg@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm6,%xmm6
  cvtsi2ss %rax,%xmm2
  comiss %xmm2,%xmm6
  ja     L0
  movss  D15(%rip),%xmm3
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm0
  mulss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  mulss  %xmm3,%xmm1
  movaps %xmm1,%xmm0
  addss  %xmm2,%xmm0
  mulss  D14(%rip),%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L0:
  movss  D24(%rip),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type: f32
name: parse_data
arguments: tag: D14
type: byte[4]
name: parse_data
arguments: tag: D24
type: byte[4]

tool: D15: 256

tool: {"D14": [0x00,0x00,0x80,0x39]}

tool: {"D24": [0x00,0xc0,0x79,0xc4]}

assistant: ```c
float getPress() {
  float ret, in;
  in = (float)_getReg(0x2A);
  if (in < 0)
    return -999.;
  ret = 256. * in;
  in = (float)_getReg(0x29);
  if (in < 0)
    return -999.;
  ret += in;
  ret *= 256.;
  in = (float)_getReg(0x28);
  if (in < 0)
    return -999.;
  ret += in;
  return ret / 4096.;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<draw_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <draw_top_line@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L14
L1:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <draw_inner_line@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x10(%rbp)
  addl   $0x2,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <draw_bottom_line@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D22
type_guessed: string

tool: D22: 


assistant: ```c
void draw_tree(int n, int total_hashtags) {
  int bottom_line_length = 2 * n - 1;
  int spaces_count = bottom_line_length / 2 - 1, hashtags_count = 1;
  draw_top_line(spaces_count);
  printf("\n");
  for (int i = 1; i < n - 1; i++) {
    draw_inner_line(spaces_count, hashtags_count);
    printf("\n");
    spaces_count--;
    hashtags_count += 2;
  }
  draw_bottom_line(spaces_count, bottom_line_length);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<draw_tree>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %edi,0xc(%rsp)
  lea    -0x1(%rdi,%rdi,1),%r15d
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sar    %ebx
  lea    -0x1(%rbx),%r14d
  mov    %r14d,%edi
  call   <draw_top_line@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  jle    L6
  sub    %ebp,%ebx
  lea    0x1(%rbx),%r13d
  mov    %r14d,%ebx
  mov    $0x1,%ebp
  lea    D13(%rip),%r12
L8:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <draw_inner_line@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  add    $0x2,%ebp
  cmp    %r13d,%ebx
  jne    L8
  sub    0xc(%rsp),%r14d
  lea    0x2(%r14),%r14d
L6:
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <draw_bottom_line@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string

tool: D13: 


assistant: ```c
void draw_tree(int n, int total_hashtags) {
  int bottom_line_length = 2 * n - 1;
  int spaces_count = bottom_line_length / 2 - 1, hashtags_count = 1;
  draw_top_line(spaces_count);
  printf("\n");
  for (int i = 1; i < n - 1; i++) {
    draw_inner_line(spaces_count, hashtags_count);
    printf("\n");
    spaces_count--;
    hashtags_count += 2;
  }
  draw_bottom_line(spaces_count, bottom_line_length);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<draw_tree>:
  endbr64
  lea    -0x1(%rdi,%rdi,1),%eax
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  sub    $0x18,%rsp
  lea    -0x1(%rbx),%r13d
  mov    %eax,0xc(%rsp)
  mov    %r13d,%edi
  call   <draw_top_line@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x2,%r14d
  jle    L3
  sub    %r14d,%ebx
  mov    $0x1,%r15d
  lea    0x1(%rbx),%r12d
  mov    %r13d,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r15d,%esi
  mov    %ebx,%edi
  sub    $0x1,%ebx
  add    $0x2,%r15d
  call   <draw_inner_line@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L10
  sub    %r14d,%r13d
  add    $0x2,%r13d
L3:
  mov    0xc(%rsp),%esi
  mov    %r13d,%edi
  call   <draw_bottom_line@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: 


assistant: ```c
void draw_tree(int n, int total_hashtags) {
  int bottom_line_length = 2 * n - 1;
  int spaces_count = bottom_line_length / 2 - 1, hashtags_count = 1;
  draw_top_line(spaces_count);
  printf("\n");
  for (int i = 1; i < n - 1; i++) {
    draw_inner_line(spaces_count, hashtags_count);
    printf("\n");
    spaces_count--;
    hashtags_count += 2;
  }
  draw_bottom_line(spaces_count, bottom_line_length);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<draw_tree>:
  endbr64
  lea    -0x1(%rdi,%rdi,1),%eax
  push   %r15
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  sub    $0x18,%rsp
  lea    -0x1(%rbx),%r13d
  mov    %eax,0xc(%rsp)
  mov    %r13d,%edi
  call   <draw_top_line@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x2,%r14d
  jle    L8
  sub    %r14d,%ebx
  mov    $0x1,%r15d
  lea    0x1(%rbx),%r12d
  mov    %r13d,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r15d,%esi
  mov    %ebx,%edi
  sub    $0x1,%ebx
  add    $0x2,%r15d
  call   <draw_inner_line@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L18
  sub    %r14d,%r13d
  add    $0x2,%r13d
L8:
  mov    0xc(%rsp),%esi
  mov    %r13d,%edi
  call   <draw_bottom_line@plt>
  add    $0x18,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 


assistant: ```c
void draw_tree(int n, int total_hashtags) {
  int bottom_line_length = 2 * n - 1;
  int spaces_count = bottom_line_length / 2 - 1, hashtags_count = 1;
  draw_top_line(spaces_count);
  printf("\n");
  for (int i = 1; i < n - 1; i++) {
    draw_inner_line(spaces_count, hashtags_count);
    printf("\n");
    spaces_count--;
    hashtags_count += 2;
  }
  draw_bottom_line(spaces_count, bottom_line_length);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <loop@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string

tool: D9: Started the C program 


assistant: ```c
int main() {
  printf("Started the C program \n");
  loop();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <loop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: string

tool: D7: Started the C program 


assistant: ```c
int main() {
  printf("Started the C program \n");
  loop();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: Started the C program 


assistant: ```c
int main() {
  printf("Started the C program \n");
  loop();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: Started the C program 


assistant: ```c
int main() {
  printf("Started the C program \n");
  loop();
}
```
user: What is the c source code of the assembly code below:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L25:
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L37:
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L37
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L25
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int add(double *A, double *B, int rows, int cols, double **sum) {
  *sum = calloc(rows * cols, sizeof(double));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < cols; j++) {
      (*sum)[i * cols + j] = A[i * cols + j] + B[i * cols + j];
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %ecx,%r13d
  mov    %r8,%rbx
  mov    %edx,%edi
  imul   %ecx,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %r14d,%r14d
  jle    L16
  mov    $0x0,%edi
  mov    $0x0,%esi
  mov    %r13d,%r8d
  jmp    L27
L12:
  movslq %edi,%rcx
  lea    0x0(,%rcx,8),%rax
  add    %r8,%rcx
  shl    $0x3,%rcx
L31:
  mov    (%rbx),%rdx
  movsd  0x0(%rbp,%rax,1),%xmm0
  addsd  (%r12,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L31
L5:
  add    $0x1,%esi
  add    %r13d,%edi
  cmp    %esi,%r14d
  je     L16
L27:
  test   %r13d,%r13d
  jg     L12
  jmp    L5
L16:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int add(double *A, double *B, int rows, int cols, double **sum) {
  *sum = calloc(rows * cols, sizeof(double));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < cols; j++) {
      (*sum)[i * cols + j] = A[i * cols + j] + B[i * cols + j];
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<add>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  imul   %ecx,%edi
  call   <calloc@plt>
  mov    %rax,(%r14)
  test   %r12d,%r12d
  jle    L37
  lea    -0x1(%r13),%r8d
  xor    %edi,%edi
  xor    %esi,%esi
  add    $0x1,%r8
  xchg   %ax,%ax
L27:
  test   %r13d,%r13d
  jle    L36
  movslq %edi,%rcx
  lea    0x0(,%rcx,8),%rdx
  add    %r8,%rcx
  shl    $0x3,%rcx
  nopw   0x0(%rax,%rax,1)
L3:
  movsd  (%rbx,%rdx,1),%xmm0
  addsd  0x0(%rbp,%rdx,1),%xmm0
  movsd  %xmm0,(%rax,%rdx,1)
  add    $0x8,%rdx
  cmp    %rdx,%rcx
  jne    L3
L36:
  add    $0x1,%esi
  add    %r13d,%edi
  cmp    %esi,%r12d
  jne    L27
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int add(double *A, double *B, int rows, int cols, double **sum) {
  *sum = calloc(rows * cols, sizeof(double));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < cols; j++) {
      (*sum)[i * cols + j] = A[i * cols + j] + B[i * cols + j];
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  imul   %ecx,%edi
  sub    $0x28,%rsp
  mov    %edx,0x10(%rsp)
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  test   %r14d,%r14d
  jle    L40
  test   %r12d,%r12d
  jle    L40
  mov    %rax,%rdx
  movslq %r12d,%rax
  mov    %r12d,%edi
  mov    $0x8,%r13d
  lea    0x0(,%rax,8),%r15
  mov    %r12d,%eax
  and    $0xfffffffe,%edi
  xor    %esi,%esi
  shr    %eax
  xor    %r11d,%r11d
  xor    %r14d,%r14d
  lea    -0x1(%rax),%r10d
  lea    -0x1(%r12),%eax
  mov    %eax,0x14(%rsp)
  shl    $0x3,%rax
  add    $0x1,%r10
  mov    %rax,0x18(%rsp)
  shl    $0x4,%r10
  nop
L30:
  lea    (%rdx,%r11,1),%rcx
  lea    0x0(%r13,%rbp,1),%rax
  cmp    %rax,%rcx
  lea    0x0(%r13,%rbx,1),%rax
  setne  %r8b
  cmp    %rax,%rcx
  setne  %al
  test   %al,%r8b
  je     L68
  cmpl   $0x1,0x14(%rsp)
  lea    (%r11,%rbx,1),%r9
  lea    (%r11,%rbp,1),%r8
  seta   0xf(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,0xf(%rsp)
  je     L68
  nop
L1:
  movupd (%r9,%rax,1),%xmm0
  movupd (%r8,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r10
  jne    L1
  cmp    %edi,%r12d
  je     L47
  lea    (%rsi,%rdi,1),%eax
  cltq
  movsd  (%rbx,%rax,8),%xmm0
  addsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
L47:
  add    $0x1,%r14d
  add    %r15,%r11
  add    %r12d,%esi
  add    %r15,%r13
  cmp    %r14d,0x10(%rsp)
  jne    L30
L40:
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  mov    0x18(%rsp),%rax
  lea    0x0(%r13,%rax,1),%rcx
  mov    %r11,%rax
  nopl   (%rax)
L79:
  movsd  (%rbx,%rax,1),%xmm0
  addsd  0x0(%rbp,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L79
  jmp    L47
```

assistant: ```c
int add(double *A, double *B, int rows, int cols, double **sum) {
  *sum = calloc(rows * cols, sizeof(double));
  for (int i = 0; i < rows; i++) {
    for (int j = 0; j < cols; j++) {
      (*sum)[i * cols + j] = A[i * cols + j] + B[i * cols + j];
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D13: Usage: mkres [options] <input file>
Make a resource file from input file.



tool: D2: Options:
    -n, --name <NAME>   Generate resource name, default is 'data'.
    -z, --zero          Resource with zero terminated, useful with string resource.
    -s, --static        Generate static variable, default is extern.
    -h, --help          Show this usage information and leave.



assistant: ```c
void show_usage() {
  printf("Usage: mkres [options] <input file>\n"
         "Make a resource file from input file.\n\n");
  printf("Options:\n"
         "    -n, --name <NAME>   Generate resource name, default is 'data'.\n"
         "    -z, --zero          Resource with zero terminated, useful with string resource.\n"
         "    -s, --static        Generate static variable, default is extern.\n"
         "    -h, --help          Show this usage information and leave.\n\n");
}
```