ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<user>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  lea    D22(%rip),%r13
  lea    D11(%rip),%r15
  lea    D23(%rip),%r14
L45:
  mov    %r13,%rdi
  call   <my_putstr@plt>
  mov    $0x0,%edi
  call   <get_next_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <my_getnbr@plt>
  mov    %eax,%ebp
  mov    %r15,%rdi
  call   <my_putstr@plt>
  mov    %rbx,%rdi
  call   <my_putstr@plt>
  mov    %r14,%rdi
  call   <my_putstr@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%edi
  call   <get_next_line@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L43
  mov    %rax,%rdi
  call   <my_getnbr@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0xc(%rsp),%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    (%rsp),%rdi
  call   <remove_alums@plt>
  test   %eax,%eax
  jne    L45
  jmp    L24
L1:
  mov    $0x1,%eax
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    $0x1,%eax
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D23
type_guessed: string

tool: D22: Selection of the line: 

tool: D11: Number of alumettes in line 

tool: D23: : 

assistant: ```c
int user(unsigned char *rows, int size) {
  char *readed;
  int line;
  int alums;
  int state;
  state = 1;
  while (state != 0) {
    my_putstr("Selection of the line: ");
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    line = my_getnbr(readed);
    my_putstr("Number of alumettes in line ");
    my_putstr(readed);
    my_putstr(": ");
    free(readed);
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    alums = my_getnbr(readed);
    free(readed);
    state = remove_alums(rows, line, alums, size);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<user>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  xchg   %ax,%ax
L17:
  mov    %r13,%rdi
  call   <my_putstr@plt>
  xor    %edi,%edi
  call   <get_next_line@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    %rax,%rdi
  call   <my_getnbr@plt>
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <my_putstr@plt>
  mov    %r12,%rdi
  call   <my_putstr@plt>
  mov    %r14,%rdi
  call   <my_putstr@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <get_next_line@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L24
  mov    %rax,0x10(%rsp)
  call   <my_getnbr@plt>
  mov    0x10(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <free@plt>
  mov    0xc(%rsp),%edx
  mov    0x18(%rsp),%rdi
  mov    %ebx,%ecx
  mov    %ebp,%esi
  call   <remove_alums@plt>
  test   %eax,%eax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L24:
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D5
type: string

tool: D7: Number of alumettes in line 

tool: D6: : 

tool: D5: Selection of the line: 

assistant: ```c
int user(unsigned char *rows, int size) {
  char *readed;
  int line;
  int alums;
  int state;
  state = 1;
  while (state != 0) {
    my_putstr("Selection of the line: ");
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    line = my_getnbr(readed);
    my_putstr("Number of alumettes in line ");
    my_putstr(readed);
    my_putstr(": ");
    free(readed);
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    alums = my_getnbr(readed);
    free(readed);
    state = remove_alums(rows, line, alums, size);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<user>:
  endbr64
  push   %r15
  lea    D27(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  xchg   %ax,%ax
L3:
  mov    %r13,%rdi
  call   <my_putstr@plt>
  xor    %edi,%edi
  call   <get_next_line@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  mov    %rax,%rdi
  call   <my_getnbr@plt>
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <my_putstr@plt>
  mov    %r12,%rdi
  call   <my_putstr@plt>
  mov    %r14,%rdi
  call   <my_putstr@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <get_next_line@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
  mov    %rax,0x10(%rsp)
  call   <my_getnbr@plt>
  mov    0x10(%rsp),%rdi
  mov    %eax,0xc(%rsp)
  call   <free@plt>
  mov    0xc(%rsp),%edx
  mov    0x18(%rsp),%rdi
  mov    %ebx,%ecx
  mov    %ebp,%esi
  call   <remove_alums@plt>
  test   %eax,%eax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L10:
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type: string
name: disassemble_data
arguments: data_label: D21
type: string
name: disassemble_data
arguments: data_label: D16
type: string

tool: D27: Number of alumettes in line 

tool: D21: : 

tool: D16: Selection of the line: 

assistant: ```c
int user(unsigned char *rows, int size) {
  char *readed;
  int line;
  int alums;
  int state;
  state = 1;
  while (state != 0) {
    my_putstr("Selection of the line: ");
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    line = my_getnbr(readed);
    my_putstr("Number of alumettes in line ");
    my_putstr(readed);
    my_putstr(": ");
    free(readed);
    if ((readed = get_next_line(0)) == NULL)
      return (1);
    alums = my_getnbr(readed);
    free(readed);
    state = remove_alums(rows, line, alums, size);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<at24c_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0x28(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L12
L33:
  mov    -0x24(%rbp),%eax
  shr    $0x8,%eax
  and    $0x7,%eax
  or     $0x50,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L41
L7:
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %dl,-0x9(%rbp,%rax,1)
  addl   $0x1,-0x18(%rbp)
L41:
  cmpl   $0x0,-0x18(%rbp)
  je     L7
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L54:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cmp    $0x2710,%eax
  jle    L14
  mov    $0x0,%eax
  jmp    L12
L14:
  lea    -0x9(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <at24c_iic_write_@plt>
  cmp    $0x1,%eax
  jne    L54
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <at24c_iic_read_@plt>
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

assistant: ```c
unsigned at24c_read(unsigned addr, void *buf, unsigned nbyte) {
  char tmp[1u];
  unsigned cnt, dev;
  assert(buf != NULL);
  if (nbyte == 0)
    return 0;
  dev = (0xau << 3) | ((addr >> (1u * 8)) & 0x7);
  for (cnt = 0; cnt < 1u; ++cnt) {
    tmp[cnt] = (char)(addr >> (cnt * 8));
  }
  int retry = 0;
  while (at24c_iic_write_(dev, tmp, 1u) != 1u) {
    if (retry++ > 10000)
      return 0;
  }
  return at24c_iic_read_(dev, (char *)buf, nbyte);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<at24c_read>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13d,%ebx
  test   %r13d,%r13d
  je     L42
  mov    %r12d,%ebp
  shr    $0x8,%ebp
  and    $0x7,%ebp
  or     $0x50,%ebp
  mov    %r12b,0x7(%rsp)
  mov    $0x2712,%ebx
  lea    0x7(%rsp),%r12
L49:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_write_@plt>
  cmp    $0x1,%eax
  je     L2
  sub    $0x1,%ebx
  jne    L49
  jmp    L42
L2:
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_read_@plt>
  mov    %eax,%ebx
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned at24c_read(unsigned addr, void *buf, unsigned nbyte) {
  char tmp[1u];
  unsigned cnt, dev;
  assert(buf != NULL);
  if (nbyte == 0)
    return 0;
  dev = (0xau << 3) | ((addr >> (1u * 8)) & 0x7);
  for (cnt = 0; cnt < 1u; ++cnt) {
    tmp[cnt] = (char)(addr >> (cnt * 8));
  }
  int retry = 0;
  while (at24c_iic_write_(dev, tmp, 1u) != 1u) {
    if (retry++ > 10000)
      return 0;
  }
  return at24c_iic_read_(dev, (char *)buf, nbyte);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<at24c_read>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  test   %r13d,%r13d
  jne    L42
L44:
  xor    %eax,%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %ebx,%ebp
  mov    %bl,0x7(%rsp)
  lea    0x7(%rsp),%r14
  mov    $0x2712,%ebx
  shr    $0x8,%ebp
  and    $0x7,%ebp
  or     $0x50,%ebp
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L30:
  sub    $0x1,%ebx
  je     L44
L28:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_write_@plt>
  cmp    $0x1,%eax
  jne    L30
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_read_@plt>
  jmp    L15
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned at24c_read(unsigned addr, void *buf, unsigned nbyte) {
  char tmp[1u];
  unsigned cnt, dev;
  assert(buf != NULL);
  if (nbyte == 0)
    return 0;
  dev = (0xau << 3) | ((addr >> (1u * 8)) & 0x7);
  for (cnt = 0; cnt < 1u; ++cnt) {
    tmp[cnt] = (char)(addr >> (cnt * 8));
  }
  int retry = 0;
  while (at24c_iic_write_(dev, tmp, 1u) != 1u) {
    if (retry++ > 10000)
      return 0;
  }
  return at24c_iic_read_(dev, (char *)buf, nbyte);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<at24c_read>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  setne  %dil
  call   <assert@plt>
  test   %r13d,%r13d
  jne    L0
L5:
  xor    %eax,%eax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%ebp
  mov    %bl,0x7(%rsp)
  lea    0x7(%rsp),%r14
  mov    $0x2712,%ebx
  shr    $0x8,%ebp
  and    $0x7,%ebp
  or     $0x50,%ebp
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L27:
  sub    $0x1,%ebx
  je     L5
L51:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_write_@plt>
  cmp    $0x1,%eax
  jne    L27
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <at24c_iic_read_@plt>
  jmp    L35
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned at24c_read(unsigned addr, void *buf, unsigned nbyte) {
  char tmp[1u];
  unsigned cnt, dev;
  assert(buf != NULL);
  if (nbyte == 0)
    return 0;
  dev = (0xau << 3) | ((addr >> (1u * 8)) & 0x7);
  for (cnt = 0; cnt < 1u; ++cnt) {
    tmp[cnt] = (char)(addr >> (cnt * 8));
  }
  int retry = 0;
  while (at24c_iic_write_(dev, tmp, 1u) != 1u) {
    if (retry++ > 10000)
      return 0;
  }
  return at24c_iic_read_(dev, (char *)buf, nbyte);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crStrToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L19
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L19:
  leave
  ret
```

assistant: ```c
int crStrToInt(const char *str) {
  if (!str)
    return 0;
  return atoi(str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crStrToInt>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <atoi@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
int crStrToInt(const char *str) {
  if (!str)
    return 0;
  return atoi(str);
}
```
user: What is the c source code of the assembly code below?

```asm
<crStrToInt>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <atoi@plt>
  xchg   %ax,%ax
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int crStrToInt(const char *str) {
  if (!str)
    return 0;
  return atoi(str);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crStrToInt>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <atoi@plt>
  xchg   %ax,%ax
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int crStrToInt(const char *str) {
  if (!str)
    return 0;
  return atoi(str);
}
```
user: What is the c source code of the assembly code below:

```asm
<Resize_VariableDatabase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !

assistant: ```c
int Resize_VariableDatabase(struct VariableShare *vsh, unsigned int newsize) {
  error("The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Resize_VariableDatabase>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <error@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string

tool: D9: The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !

assistant: ```c
int Resize_VariableDatabase(struct VariableShare *vsh, unsigned int newsize) {
  error("The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Resize_VariableDatabase>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !

assistant: ```c
int Resize_VariableDatabase(struct VariableShare *vsh, unsigned int newsize) {
  error("The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Resize_VariableDatabase>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !

assistant: ```c
int Resize_VariableDatabase(struct VariableShare *vsh, unsigned int newsize) {
  error("The Variable Share Object has run out of space and there is no code implemented for resizing it (yet) !");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rumStrsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L25:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L10
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L25
L10:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rumStrsub(char *str, int f, int n) {
  int s = strlen(str);
  char *res = malloc(n + 1);
  int i;
  for (i = 0; i < n && i < s; i++) {
    res[i] = str[f + i];
  }
  res[i] = '\0';
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rumStrsub>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r13d
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  cmp    %r13d,%r12d
  mov    %r13d,%edi
  cmovle %r12d,%edi
  test   %edi,%edi
  jle    L16
  mov    %edi,%r8d
  mov    $0x0,%edx
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rsi
L12:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L12
L26:
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    $0x0,%edi
  jmp    L26
```

assistant: ```c
char *rumStrsub(char *str, int f, int n) {
  int s = strlen(str);
  char *res = malloc(n + 1);
  int i;
  for (i = 0; i < n && i < s; i++) {
    res[i] = str[f + i];
  }
  res[i] = '\0';
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rumStrsub>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%r12),%edi
  movslq %eax,%rbx
  call   <malloc@plt>
  cmp    %r12d,%ebx
  movslq %r12d,%rcx
  cmovle %rbx,%rcx
  test   %ecx,%ecx
  jle    L12
  xor    %edx,%edx
  lea    0x0(%r13,%rbp,1),%rdi
  xchg   %ax,%ax
L0:
  movzbl (%rdi,%rdx,1),%esi
  mov    %sil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rcx
  jne    L0
  add    %rax,%rcx
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rax,%rcx
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *rumStrsub(char *str, int f, int n) {
  int s = strlen(str);
  char *res = malloc(n + 1);
  int i;
  for (i = 0; i < n && i < s; i++) {
    res[i] = str[f + i];
  }
  res[i] = '\0';
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rumStrsub>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%r13),%edi
  mov    %eax,%r12d
  call   <malloc@plt>
  cmp    %r13d,%r12d
  mov    %r13d,%edx
  cmovle %r12d,%edx
  mov    %rax,%r8
  test   %edx,%edx
  jle    L43
  movslq %ebp,%rcx
  mov    %r8,%rsi
  lea    -0x1(%rdx),%eax
  mov    %edx,%edi
  lea    0x1(%rbx,%rcx,1),%r9
  sub    %r9,%rsi
  cmp    $0xe,%rsi
  jbe    L64
  cmp    $0x6,%eax
  jbe    L64
  cmp    $0xe,%eax
  jbe    L14
  mov    %edx,%esi
  add    %rbx,%rcx
  xor    %eax,%eax
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L159:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L159
  mov    %edx,%esi
  and    $0xfffffff0,%esi
  mov    %esi,%eax
  cmp    %esi,%edx
  je     L176
  mov    %edx,%edi
  sub    %esi,%edi
  lea    -0x1(%rdi),%r9d
  cmp    $0x6,%r9d
  jbe    L154
L174:
  mov    (%rcx,%rsi,1),%rcx
  mov    %rcx,(%r8,%rsi,1)
  mov    %edi,%ecx
  and    $0xfffffff8,%ecx
  add    %ecx,%eax
  cmp    %ecx,%edi
  je     L176
L154:
  lea    0x0(%rbp,%rax,1),%ecx
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  movslq %eax,%rcx
  mov    %sil,(%r8,%rcx,1)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L176
  lea    0x0(%rbp,%rcx,1),%esi
  movslq %ecx,%rcx
  movslq %esi,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%r8,%rcx,1)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L176
  lea    0x0(%rbp,%rcx,1),%esi
  movslq %ecx,%rcx
  movslq %esi,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%r8,%rcx,1)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L176
  lea    0x0(%rbp,%rcx,1),%esi
  movslq %ecx,%rcx
  movslq %esi,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%r8,%rcx,1)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L176
  lea    0x0(%rbp,%rcx,1),%esi
  movslq %ecx,%rcx
  movslq %esi,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%r8,%rcx,1)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L176
  lea    0x0(%rbp,%rcx,1),%esi
  add    $0x6,%eax
  movslq %ecx,%rcx
  movslq %esi,%rsi
  movzbl (%rbx,%rsi,1),%esi
  mov    %sil,(%r8,%rcx,1)
  cmp    %eax,%edx
  jle    L176
  add    %eax,%ebp
  cltq
  movslq %ebp,%rbp
  movzbl (%rbx,%rbp,1),%ecx
  mov    %cl,(%r8,%rax,1)
L176:
  movslq %edx,%rdx
  add    %r8,%rdx
L62:
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %edx,%edi
  xor    %eax,%eax
  add    %rbx,%rcx
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L26
  jmp    L176
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rax,%rdx
  jmp    L62
L14:
  xor    %esi,%esi
  xor    %eax,%eax
  add    %rbx,%rcx
  jmp    L174
```

assistant: ```c
char *rumStrsub(char *str, int f, int n) {
  int s = strlen(str);
  char *res = malloc(n + 1);
  int i;
  for (i = 0; i < n && i < s; i++) {
    res[i] = str[f + i];
  }
  res[i] = '\0';
  return res;
}
```