ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x6b,%ebx
  jne    L1
  lea    D12(%rip),%rdi
  xor    %ebx,%ebx
  lea    D24(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L19:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebx
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string

tool: D21: X = %d


tool: D12: 



tool: D24: %s


assistant: ```c
int main() {
  enum days { Monday = 100, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday };
  int x;
  for (x = Monday; x <= Sunday; x++)
    printf("X = %d\n", x);
  x = 0;
  printf("\n\n\n");
  for (x = 0; x <= 6; x++)
    printf("%s\n", x);
  x = 0;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    $0x64,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x6b,%ebx
  jne    L14
  lea    D19(%rip),%rdi
  xor    %ebx,%ebx
  lea    D21(%rip),%rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D19
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string

tool: D18: X = %d


tool: D19: 



tool: D21: %s


assistant: ```c
int main() {
  enum days { Monday = 100, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday };
  int x;
  for (x = Monday; x <= Sunday; x++)
    printf("X = %d\n", x);
  x = 0;
  printf("\n\n\n");
  for (x = 0; x <= 6; x++)
    printf("%s\n", x);
  x = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<luaL_findstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    -0x4(%rbp),%eax
  jmp    L36
L12:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L23
  mov    $0xffffffff,%eax
L36:
  leave
  ret
```

assistant: ```c
int luaL_findstring(char *name, char *list[]) {
  int i;
  for (i = 0; list[i]; i++)
    if (strcmp(list[i], name) == 0)
      return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<luaL_findstring>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L17
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L28:
  mov    %ebx,%r13d
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  jne    L28
  mov    $0xffffffff,%r13d
L6:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    $0xffffffff,%r13d
  jmp    L6
```

assistant: ```c
int luaL_findstring(char *name, char *list[]) {
  int i;
  for (i = 0; list[i]; i++)
    if (strcmp(list[i], name) == 0)
      return i;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<luaL_findstring>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L12
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L29
L18:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L12
L29:
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int luaL_findstring(char *name, char *list[]) {
  int i;
  for (i = 0; list[i]; i++)
    if (strcmp(list[i], name) == 0)
      return i;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<luaL_findstring>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L15
  mov    %rsi,%rbp
  xor    %ebx,%ebx
  jmp    L32
L35:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L15
L32:
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L35
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int luaL_findstring(char *name, char *list[]) {
  int i;
  for (i = 0; list[i]; i++)
    if (strcmp(list[i], name) == 0)
      return i;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fact_tail@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: the factorial of: %u is %u


assistant: ```c
unsigned int main() {
  unsigned int N = 100;
  unsigned int a = 1;
  unsigned int result = 0;
  result = fact_tail(N, a);
  printf("the factorial of: %u is %u\n", N, result);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <fact_tail@plt>
  mov    %eax,%edx
  mov    $0x64,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: the factorial of: %u is %u


assistant: ```c
unsigned int main() {
  unsigned int N = 100;
  unsigned int a = 1;
  unsigned int result = 0;
  result = fact_tail(N, a);
  printf("the factorial of: %u is %u\n", N, result);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <fact_tail@plt>
  mov    $0x64,%esi
  lea    D8(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: the factorial of: %u is %u


assistant: ```c
unsigned int main() {
  unsigned int N = 100;
  unsigned int a = 1;
  unsigned int result = 0;
  result = fact_tail(N, a);
  printf("the factorial of: %u is %u\n", N, result);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x64,%edi
  call   <fact_tail@plt>
  mov    $0x64,%esi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: the factorial of: %u is %u


assistant: ```c
unsigned int main() {
  unsigned int N = 100;
  unsigned int a = 1;
  unsigned int result = 0;
  result = fact_tail(N, a);
  printf("the factorial of: %u is %u\n", N, result);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<inverse_factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L13
L34:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L43
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L13
L43:
  mov    $0xffffffff,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int inverse_factorial(uint64_t f) {
  int p = 1;
  int i = 1;
  if (f == 1) {
    return 0;
  }
  while (p < f) {
    p *= i;
    i++;
  }
  if (p == f) {
    return i - 1;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inverse_factorial>:
  endbr64
  mov    $0x0,%ecx
  cmp    $0x1,%edi
  je     L9
  jle    L16
  mov    $0x1,%eax
  mov    $0x1,%edx
L15:
  imul   %eax,%edx
  mov    %eax,%ecx
  add    $0x1,%eax
  cmp    %edx,%edi
  jg     L15
  mov    $0xffffffff,%eax
  cmovne %eax,%ecx
L9:
  mov    %ecx,%eax
  ret
L16:
  mov    $0xffffffff,%ecx
  jmp    L9
```

assistant: ```c
int inverse_factorial(uint64_t f) {
  int p = 1;
  int i = 1;
  if (f == 1) {
    return 0;
  }
  while (p < f) {
    p *= i;
    i++;
  }
  if (p == f) {
    return i - 1;
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inverse_factorial>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L11
  jle    L3
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L26:
  imul   %edx,%eax
  mov    %edx,%r8d
  lea    0x1(%rdx),%edx
  cmp    %eax,%edi
  jg     L26
  mov    $0xffffffff,%eax
  cmovne %eax,%r8d
L11:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%r8d
  jmp    L11
```

assistant: ```c
int inverse_factorial(uint64_t f) {
  int p = 1;
  int i = 1;
  if (f == 1) {
    return 0;
  }
  while (p < f) {
    p *= i;
    i++;
  }
  if (p == f) {
    return i - 1;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<inverse_factorial>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L10
  jle    L20
  mov    $0x1,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  imul   %edx,%eax
  mov    %edx,%r8d
  lea    0x1(%rdx),%edx
  cmp    %eax,%edi
  jg     L6
  mov    $0xffffffff,%eax
  cmovne %eax,%r8d
L10:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0xffffffff,%r8d
  jmp    L10
```

assistant: ```c
int inverse_factorial(uint64_t f) {
  int p = 1;
  int i = 1;
  if (f == 1) {
    return 0;
  }
  while (p < f) {
    p *= i;
    i++;
  }
  if (p == f) {
    return i - 1;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<dummy_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dummy_func() {
  pthread_exit(NULL);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dummy_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dummy_func() {
  pthread_exit(NULL);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dummy_func>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <pthread_exit@plt>
```

assistant: ```c
void dummy_func() {
  pthread_exit(NULL);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<my_env>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L5
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: 


assistant: ```c
int my_env(char **env, char **s) {
  int i;
  i = 0;
  (void)s;
  while (env[i] != NULL) {
    my_putstr(env[i]);
    my_putstr("\n");
    i = i + 1;
  }
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_env>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rax),%rbx
  lea    D1(%rip),%rbp
L14:
  call   <my_putstr@plt>
  mov    %rbp,%rdi
  call   <my_putstr@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L14
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: 


assistant: ```c
int my_env(char **env, char **s) {
  int i;
  i = 0;
  (void)s;
  while (env[i] != NULL) {
    my_putstr(env[i]);
    my_putstr("\n");
    i = i + 1;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_env>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
L8:
  call   <my_putstr@plt>
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <my_putstr@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L8
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: 


assistant: ```c
int my_env(char **env, char **s) {
  int i;
  i = 0;
  (void)s;
  while (env[i] != NULL) {
    my_putstr(env[i]);
    my_putstr("\n");
    i = i + 1;
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_env>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    0x8(%rax),%rbx
  sub    $0x8,%rsp
L3:
  call   <my_putstr@plt>
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <my_putstr@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L3
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: 


assistant: ```c
int my_env(char **env, char **s) {
  int i;
  i = 0;
  (void)s;
  while (env[i] != NULL) {
    my_putstr(env[i]);
    my_putstr("\n");
    i = i + 1;
  }
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<insert_value_in_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <allocate_enough_memory@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void insert_value_in_array(unsigned int **ptr, int *nele, int *nele_alloc, const unsigned int value, char *arrayname) {
  (void)arrayname;
  allocate_enough_memory(ptr, nele, nele_alloc);
  (*ptr)[(*nele) - 1] = value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insert_value_in_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %ecx,%r12d
  call   <allocate_enough_memory@plt>
  movslq 0x0(%rbp),%rdx
  mov    (%rbx),%rax
  mov    %r12d,-0x4(%rax,%rdx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value_in_array(unsigned int **ptr, int *nele, int *nele_alloc, const unsigned int value, char *arrayname) {
  (void)arrayname;
  allocate_enough_memory(ptr, nele, nele_alloc);
  (*ptr)[(*nele) - 1] = value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<insert_value_in_array>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <allocate_enough_memory@plt>
  movslq 0x0(%rbp),%rdx
  mov    (%rbx),%rax
  mov    %r12d,-0x4(%rax,%rdx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value_in_array(unsigned int **ptr, int *nele, int *nele_alloc, const unsigned int value, char *arrayname) {
  (void)arrayname;
  allocate_enough_memory(ptr, nele, nele_alloc);
  (*ptr)[(*nele) - 1] = value;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<insert_value_in_array>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <allocate_enough_memory@plt>
  movslq 0x0(%rbp),%rdx
  mov    (%rbx),%rax
  mov    %r12d,-0x4(%rax,%rdx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_value_in_array(unsigned int **ptr, int *nele, int *nele_alloc, const unsigned int value, char *arrayname) {
  (void)arrayname;
  allocate_enough_memory(ptr, nele, nele_alloc);
  (*ptr)[(*nele) - 1] = value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  shl    $0x2,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L37
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L14
L37:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L19
  mov    -0x8(%rbp),%rax
  jmp    L14
L19:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
L14:
  leave
  ret
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<base64_encode_alloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  lea    0x2(%rsi),%rdx
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%rbx
  lea    0x1(%rbx),%r14
  cmp    %r14,%rsi
  jbe    L32
  movq   $0x0,(%r12)
  mov    $0x0,%ebx
L14:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L22
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  jmp    L14
L22:
  mov    %r14,%rbx
  jmp    L14
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L23
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L1:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L23:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L11
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %r14,%r12
  jmp    L1
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<base64_encode_alloc>:
  endbr64
  movabs $0xaaaaaaaaaaaaaaab,%rcx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  lea    0x2(%rsi),%rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    %rdx
  lea    0x0(,%rdx,4),%r12
  lea    0x1(%r12),%r14
  cmp    %r14,%rsi
  jbe    L15
  movq   $0x0,(%rbx)
  xor    %r12d,%r12d
L0:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L15:
  mov    %rdi,%r13
  mov    %r14,%rdi
  mov    %rsi,%rbp
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L18
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <base64_encode@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    %r14,%r12
  jmp    L0
```

assistant: ```c
size_t base64_encode_alloc(const char *in, size_t inlen, char **out) {
  size_t outlen = 1 + ((((inlen) + 2) / 3) * 4);
  if (inlen > outlen) {
    *out = NULL;
    return 0;
  }
  *out = malloc(outlen);
  if (!*out)
    return outlen;
  base64_encode(in, inlen, *out, outlen);
  return outlen - 1;
}
```