ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<IncrementCurtimes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  xor    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    $0xac44,%edi
  movq   %rax,%xmm0
  call   <fmod@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L9
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void IncrementCurtimes(double timeval[], int harmonics, double increment, double detune) {
  int i;
  for (i = 0; i < harmonics; i++) {
    timeval[i] += increment * (2 ^ i) + detune;
    timeval[i] = fmod(timeval[i], 44100);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IncrementCurtimes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L17:
  mov    %ebx,%eax
  xor    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  0x0(%rbp,%rbx,8),%xmm0
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  mov    $0xac44,%edi
  call   <fmod@plt>
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L17
L3:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void IncrementCurtimes(double timeval[], int harmonics, double increment, double detune) {
  int i;
  for (i = 0; i < harmonics; i++) {
    timeval[i] += increment * (2 ^ i) + detune;
    timeval[i] = fmod(timeval[i], 44100);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IncrementCurtimes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  test   %esi,%esi
  jle    L5
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  mov    $0xac44,%edi
  xor    $0x2,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  call   <fmod@plt>
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L7
L5:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void IncrementCurtimes(double timeval[], int harmonics, double increment, double detune) {
  int i;
  for (i = 0; i < harmonics; i++) {
    timeval[i] += increment * (2 ^ i) + detune;
    timeval[i] = fmod(timeval[i], 44100);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IncrementCurtimes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  test   %esi,%esi
  jle    L4
  mov    %rdi,%r12
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  mov    $0xac44,%edi
  xor    $0x2,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  addsd  (%r12,%rbx,8),%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  call   <fmod@plt>
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
L4:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void IncrementCurtimes(double timeval[], int harmonics, double increment, double detune) {
  int i;
  for (i = 0; i < harmonics; i++) {
    timeval[i] += increment * (2 ^ i) + detune;
    timeval[i] = fmod(timeval[i], 44100);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<start_vis5d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x800,%rsp
  mov    %rdi,-0x7f8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x7e0(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x7f8(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x7f0(%rbp)
  cmpq   $0x0,-0x7f0(%rbp)
  je     L11
  lea    -0x7e0(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x7f0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x3f0(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x7e8(%rbp)
  cmpq   $0x0,-0x7e8(%rbp)
  je     L18
  mov    -0x7e8(%rbp),%rax
  movb   $0x0,(%rax)
L18:
  lea    -0x3f0(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L11:
  lea    -0x7e0(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D66
type_guessed: string
name: parse_data
arguments: data_label: D51
type_guessed: string
name: parse_data
arguments: data_label: D33
type_guessed: string
name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D52
type_guessed: string

tool: D8: Starting Vis5D...

tool: D4: vis5d 

tool: D66: r

tool: D51: vis5d_options

tool: D33:  

tool: D38:  &

tool: D52: command:  %s


assistant: ```c
int start_vis5d(char *filename) {
  FILE *f;
  char command[1000];
  char line[1000];
  char *sub;
  printf("Starting Vis5D...\n");
  strcpy(command, "vis5d ");
  strcat(command, filename);
  f = fopen("vis5d_options", "r");
  if (f) {
    strcat(command, " ");
    fgets(line, 1000, f);
    sub = strchr(line, '\n');
    if (sub != 0)
      sub[0] = 0;
    strcat(command, line);
  }
  strcat(command, " &");
  printf("command:  %s\n", command);
  system(command);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<start_vis5d>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D69(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    %rsp,%rdi
  lea    D47(%rip),%rsi
  call   <strcat@plt>
  lea    0x3f0(%rsp),%rbp
  mov    %rbx,%rdx
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rax)
L17:
  lea    0x3f0(%rsp),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
L8:
  mov    %rsp,%rbx
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D69
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D47
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D40
type: string

tool: D17: Starting Vis5D...

tool: D3: vis5d 

tool: D69: r

tool: D10: vis5d_options

tool: D47:  

tool: D14:  &

tool: D40: command:  %s


assistant: ```c
int start_vis5d(char *filename) {
  FILE *f;
  char command[1000];
  char line[1000];
  char *sub;
  printf("Starting Vis5D...\n");
  strcpy(command, "vis5d ");
  strcat(command, filename);
  f = fopen("vis5d_options", "r");
  if (f) {
    strcat(command, " ");
    fgets(line, 1000, f);
    sub = strchr(line, '\n');
    if (sub != 0)
      sub[0] = 0;
    strcat(command, line);
  }
  strcat(command, " &");
  printf("command:  %s\n", command);
  system(command);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<start_vis5d>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D43(%rip),%rdi
  push   %rbp
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D16(%rip),%rsi
  lea    D55(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%r12
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    0x3f0(%rsp),%r13
  mov    $0x3e8,%esi
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <fgets@plt>
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  movb   $0x0,(%rax)
L12:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L5:
  lea    D59(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D43
type: string
name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D55
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D59
type: string
name: read_data
arguments: data_label: D2
type: string

tool: D43: Starting Vis5D...

tool: D8: vis5d 

tool: D16: r

tool: D55: vis5d_options

tool: D23:  

tool: D59:  &

tool: D2: command:  %s


assistant: ```c
int start_vis5d(char *filename) {
  FILE *f;
  char command[1000];
  char line[1000];
  char *sub;
  printf("Starting Vis5D...\n");
  strcpy(command, "vis5d ");
  strcat(command, filename);
  f = fopen("vis5d_options", "r");
  if (f) {
    strcat(command, " ");
    fgets(line, 1000, f);
    sub = strchr(line, '\n');
    if (sub != 0)
      sub[0] = 0;
    strcat(command, line);
  }
  strcat(command, " &");
  printf("command:  %s\n", command);
  system(command);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<start_vis5d>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D34(%rip),%rdi
  push   %rbp
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D5(%rip),%rsi
  lea    D25(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%r12
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    0x3f0(%rsp),%r13
  mov    $0x3e8,%esi
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <fgets@plt>
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  movb   $0x0,(%rax)
L21:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
L18:
  lea    D53(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D53
type: string
name: disassemble_data
arguments: tag: D24
type: string

tool: D34: Starting Vis5D...

tool: D22: vis5d 

tool: D5: r

tool: D25: vis5d_options

tool: D12:  

tool: D53:  &

tool: D24: command:  %s


assistant: ```c
int start_vis5d(char *filename) {
  FILE *f;
  char command[1000];
  char line[1000];
  char *sub;
  printf("Starting Vis5D...\n");
  strcpy(command, "vis5d ");
  strcat(command, filename);
  f = fopen("vis5d_options", "r");
  if (f) {
    strcat(command, " ");
    fgets(line, 1000, f);
    sub = strchr(line, '\n');
    if (sub != 0)
      sub[0] = 0;
    strcat(command, line);
  }
  strcat(command, " &");
  printf("command:  %s\n", command);
  system(command);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<setCorrectActionOption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <exists@plt>
  test   %rax,%rax
  je     L1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x63,%al
  jne    L38
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movb   $0x75,(%rax)
  jmp    L38
L1:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x75,%al
  jne    L38
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movb   $0x63,(%rax)
L38:
  nop
  leave
  ret
```

assistant: ```c
void setCorrectActionOption(const char *archiveFileName, char *argv[]) {
  if (exists(archiveFileName)) {
    if (argv[1][0] == 'c')
      argv[1][0] = 'u';
  } else {
    if (argv[1][0] == 'u')
      argv[1][0] = 'c';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<setCorrectActionOption>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <exists@plt>
  test   %rax,%rax
  je     L7
  mov    0x8(%rbx),%rax
  cmpb   $0x63,(%rax)
  je     L32
L12:
  pop    %rbx
  ret
L32:
  movb   $0x75,(%rax)
  jmp    L12
L7:
  mov    0x8(%rbx),%rax
  cmpb   $0x75,(%rax)
  jne    L12
  movb   $0x63,(%rax)
  jmp    L12
```

assistant: ```c
void setCorrectActionOption(const char *archiveFileName, char *argv[]) {
  if (exists(archiveFileName)) {
    if (argv[1][0] == 'c')
      argv[1][0] = 'u';
  } else {
    if (argv[1][0] == 'u')
      argv[1][0] = 'c';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setCorrectActionOption>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <exists@plt>
  test   %rax,%rax
  mov    0x8(%rbx),%rax
  je     L11
  cmpb   $0x63,(%rax)
  je     L1
L2:
  pop    %rbx
  ret
  nopl   (%rax)
L11:
  cmpb   $0x75,(%rax)
  jne    L2
  movb   $0x63,(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x75,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void setCorrectActionOption(const char *archiveFileName, char *argv[]) {
  if (exists(archiveFileName)) {
    if (argv[1][0] == 'c')
      argv[1][0] = 'u';
  } else {
    if (argv[1][0] == 'u')
      argv[1][0] = 'c';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<setCorrectActionOption>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <exists@plt>
  test   %rax,%rax
  mov    0x8(%rbx),%rax
  je     L6
  cmpb   $0x63,(%rax)
  je     L25
L26:
  pop    %rbx
  ret
  nopl   (%rax)
L6:
  cmpb   $0x75,(%rax)
  jne    L26
  movb   $0x63,(%rax)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movb   $0x75,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void setCorrectActionOption(const char *archiveFileName, char *argv[]) {
  if (exists(archiveFileName)) {
    if (argv[1][0] == 'c')
      argv[1][0] = 'u';
  } else {
    if (argv[1][0] == 'u')
      argv[1][0] = 'c';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<zcm_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L11
L1:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
void *zcm_malloc(uint32_t sz) {
  if (sz)
    return malloc(sz);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<zcm_malloc>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  jne    L0
  ret
L0:
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *zcm_malloc(uint32_t sz) {
  if (sz)
    return malloc(sz);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zcm_malloc>:
  endbr64
  test   %rdi,%rdi
  jne    L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *zcm_malloc(uint32_t sz) {
  if (sz)
    return malloc(sz);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zcm_malloc>:
  endbr64
  test   %rdi,%rdi
  jne    L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *zcm_malloc(uint32_t sz) {
  if (sz)
    return malloc(sz);
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<did_you_mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L8
L31:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <levenshtein_dist@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L40
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L40:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L60
  cmpl   $0x0,-0xc(%rbp)
  jns    L32
L60:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L32:
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L31
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L1
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int did_you_mean(const char *input, const char **words, const int nwords, char **word) {
  int i;
  int least_dist = -1;
  int closest_word;
  int dist;
  for (i = 0; i < nwords; i++) {
    dist = levenshtein_dist(input, words[i]);
    if (dist == 0) {
      closest_word = i;
      least_dist = 0;
      break;
    }
    if (dist <= least_dist || least_dist < 0) {
      closest_word = i;
      least_dist = dist;
    }
  }
  word = malloc(strlen(words[closest_word]) * sizeof(*word));
  for (i = 0; i < strlen(words[i]); i++)
    (*word)[i] = (words[closest_word])[i];
  return least_dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<did_you_mean>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  test   %edx,%edx
  jle    L11
  mov    %rdi,%r15
  mov    %edx,%r14d
  mov    $0x0,%ebp
  mov    $0xffffffff,%r13d
  jmp    L88
L36:
  mov    0x8(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    %ebx,%r13d
L16:
  add    $0x1,%rbp
  cmp    %r14,%rbp
  je     L75
L88:
  mov    %ebp,0x8(%rsp)
  mov    (%r12,%rbp,8),%rsi
  mov    %r15,%rdi
  call   <levenshtein_dist@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L49
  cmp    %r13d,%eax
  jle    L36
  test   %r13d,%r13d
  jns    L16
  jmp    L36
L75:
  mov    0xc(%rsp),%eax
  mov    %eax,0x8(%rsp)
  mov    %r13d,%ebx
L49:
  movslq 0x8(%rsp),%rax
  lea    (%r12,%rax,8),%r14
  mov    (%r14),%rdi
  call   <strlen@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebp
L33:
  mov    (%r12,%rbp,8),%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L34
  mov    (%r14),%rax
  movzbl (%rax,%rbp,1),%edx
  mov    0x0(%r13),%rax
  mov    %dl,(%rax,%rbp,1)
  add    $0x1,%rbp
  jmp    L33
L11:
  movl   $0x0,0x8(%rsp)
  mov    $0xffffffff,%ebx
  jmp    L49
L34:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int did_you_mean(const char *input, const char **words, const int nwords, char **word) {
  int i;
  int least_dist = -1;
  int closest_word;
  int dist;
  for (i = 0; i < nwords; i++) {
    dist = levenshtein_dist(input, words[i]);
    if (dist == 0) {
      closest_word = i;
      least_dist = 0;
      break;
    }
    if (dist <= least_dist || least_dist < 0) {
      closest_word = i;
      least_dist = dist;
    }
  }
  word = malloc(strlen(words[closest_word]) * sizeof(*word));
  for (i = 0; i < strlen(words[i]); i++)
    (*word)[i] = (words[closest_word])[i];
  return least_dist;
}
```