ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<new_line>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <flush_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <stream_new_line@plt>
```

assistant: ```c
void new_line(void) {
  flush_buffer();
  stream_new_line();
}
```
user: What is the c source code of the assembly code below?

```asm
<new_line>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <flush_buffer@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <stream_new_line@plt>
```

assistant: ```c
void new_line(void) {
  flush_buffer();
  stream_new_line();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SHA256_VST_KAT_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xf4240,%edi
  call   <malloc@plt>
  mov    %rax,-0x60(%rbp)
  movw   $0x61,-0x52(%rbp)
  movl   $0x0,-0x64(%rbp)
  jmp    L7
L28:
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x60(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x52(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x64(%rbp)
L7:
  cmpl   $0xf423f,-0x64(%rbp)
  jle    L28
  movabs $0x92fb14995c6ec7cd,%rax
  movabs $0x673ed784e2c7a181,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0xe2097a4489a80f1,%rax
  movabs $0xd02c11c7cc396d04,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%rax
  mov    $0xf4240,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA256_VST@plt>
  lea    -0x30(%rbp),%rsi
  lea    -0x50(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x20,%edx
  mov    %rax,%rdi
  call   <check_KAT@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: SHA256_VST_KAT_2

assistant: ```c
SHA256_VST_KAT_2() {
  unsigned char *input = malloc(sizeof(char) * 1000000);
  char to_repeat[] = "a";
  int i;
  for (i = 0; i < 1000000; i++) {
    memcpy(input + i * 1, to_repeat, 1);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0xCD, 0xC7, 0x6E, 0x5C, 0x99, 0x14, 0xFB, 0x92, 0x81, 0xA1, 0xC7, 0xE2, 0x84, 0xD7, 0x3E, 0x67, 0xF1, 0x80, 0x9A, 0x48, 0xA4, 0x97, 0x20, 0x0E, 0x04, 0x6D, 0x39, 0xCC, 0xC7, 0x11, 0x2C, 0xD0};
  SHA256_VST(input, result, 1000000);
  check_KAT(result, expected_result, 32, "SHA256_VST_KAT_2");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SHA256_VST_KAT_2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0xf4240,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movw   $0x61,0xe(%rsp)
  mov    %rax,%rbx
  lea    0xf4240(%rax),%r12
  lea    0xe(%rsp),%rbp
L5:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L5
  movabs $0x92fb14995c6ec7cd,%rax
  movabs $0x673ed784e2c7a181,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0xe2097a4489a80f1,%rax
  movabs $0xd02c11c7cc396d04,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  lea    0x10(%rsp),%rbx
  mov    $0xf4240,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <SHA256_VST@plt>
  lea    0x30(%rsp),%rsi
  lea    D5(%rip),%rcx
  mov    $0x20,%edx
  mov    %rbx,%rdi
  call   <check_KAT@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: SHA256_VST_KAT_2

assistant: ```c
SHA256_VST_KAT_2() {
  unsigned char *input = malloc(sizeof(char) * 1000000);
  char to_repeat[] = "a";
  int i;
  for (i = 0; i < 1000000; i++) {
    memcpy(input + i * 1, to_repeat, 1);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0xCD, 0xC7, 0x6E, 0x5C, 0x99, 0x14, 0xFB, 0x92, 0x81, 0xA1, 0xC7, 0xE2, 0x84, 0xD7, 0x3E, 0x67, 0xF1, 0x80, 0x9A, 0x48, 0xA4, 0x97, 0x20, 0x0E, 0x04, 0x6D, 0x39, 0xCC, 0xC7, 0x11, 0x2C, 0xD0};
  SHA256_VST(input, result, 1000000);
  check_KAT(result, expected_result, 32, "SHA256_VST_KAT_2");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SHA256_VST_KAT_2>:
  endbr64
  push   %r13
  mov    $0xf4240,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x61,%eax
  mov    %ax,0xe(%rsp)
  mov    %r13,%rbx
  lea    0xf4240(%r13),%r12
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rdi
  mov    $0x1,%edx
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L5
  movdqa D8(%rip),%xmm0
  lea    0x10(%rsp),%rbp
  mov    $0xf4240,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  movaps %xmm0,0x30(%rsp)
  movdqa D21(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <SHA256_VST@plt>
  lea    0x30(%rsp),%rsi
  mov    $0x20,%edx
  mov    %rbp,%rdi
  lea    D0(%rip),%rcx
  call   <check_KAT@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D21
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: {"D8": [0xcd,0xc7,0x6e,0x5c,0x99,0x14,0xfb,0x92,0x81,0xa1,0xc7,0xe2,0x84,0xd7,0x3e,0x67]}

tool: {"D21": [0xf1,0x80,0x9a,0x48,0xa4,0x97,0x20,0x0e,0x04,0x6d,0x39,0xcc,0xc7,0x11,0x2c,0xd0]}

tool: D0: SHA256_VST_KAT_2

assistant: ```c
SHA256_VST_KAT_2() {
  unsigned char *input = malloc(sizeof(char) * 1000000);
  char to_repeat[] = "a";
  int i;
  for (i = 0; i < 1000000; i++) {
    memcpy(input + i * 1, to_repeat, 1);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0xCD, 0xC7, 0x6E, 0x5C, 0x99, 0x14, 0xFB, 0x92, 0x81, 0xA1, 0xC7, 0xE2, 0x84, 0xD7, 0x3E, 0x67, 0xF1, 0x80, 0x9A, 0x48, 0xA4, 0x97, 0x20, 0x0E, 0x04, 0x6D, 0x39, 0xCC, 0xC7, 0x11, 0x2C, 0xD0};
  SHA256_VST(input, result, 1000000);
  check_KAT(result, expected_result, 32, "SHA256_VST_KAT_2");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SHA256_VST_KAT_2>:
  endbr64
  push   %r13
  mov    $0xf4240,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x61,%eax
  mov    %ax,0xe(%rsp)
  mov    %r13,%rbx
  lea    0xf4240(%r13),%r12
  nopl   0x0(%rax)
L16:
  mov    %rbx,%rdi
  mov    $0x1,%edx
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <memcpy@plt>
  cmp    %r12,%rbx
  jne    L16
  movdqa D16(%rip),%xmm0
  lea    0x10(%rsp),%rbp
  mov    $0xf4240,%edx
  mov    %r13,%rdi
  mov    %rbp,%rsi
  movaps %xmm0,0x30(%rsp)
  movdqa D7(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <SHA256_VST@plt>
  lea    0x30(%rsp),%rsi
  mov    $0x20,%edx
  mov    %rbp,%rdi
  lea    D20(%rip),%rcx
  call   <check_KAT@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: byte[16]
name: unpack_data
arguments: label: D7
datatype: byte[16]
name: unpack_data
arguments: label: D20
datatype: string

tool: {"D16": [0xcd,0xc7,0x6e,0x5c,0x99,0x14,0xfb,0x92,0x81,0xa1,0xc7,0xe2,0x84,0xd7,0x3e,0x67]}

tool: {"D7": [0xf1,0x80,0x9a,0x48,0xa4,0x97,0x20,0x0e,0x04,0x6d,0x39,0xcc,0xc7,0x11,0x2c,0xd0]}

tool: D20: SHA256_VST_KAT_2

assistant: ```c
SHA256_VST_KAT_2() {
  unsigned char *input = malloc(sizeof(char) * 1000000);
  char to_repeat[] = "a";
  int i;
  for (i = 0; i < 1000000; i++) {
    memcpy(input + i * 1, to_repeat, 1);
  }
  unsigned char result[32];
  unsigned char expected_result[32] = {0xCD, 0xC7, 0x6E, 0x5C, 0x99, 0x14, 0xFB, 0x92, 0x81, 0xA1, 0xC7, 0xE2, 0x84, 0xD7, 0x3E, 0x67, 0xF1, 0x80, 0x9A, 0x48, 0xA4, 0x97, 0x20, 0x0E, 0x04, 0x6D, 0x39, 0xCC, 0xC7, 0x11, 0x2C, 0xD0};
  SHA256_VST(input, result, 1000000);
  check_KAT(result, expected_result, 32, "SHA256_VST_KAT_2");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x7,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x6,%edi
  call   <addnumbers@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D4: sum = %d


tool: D13: sum2 = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("sum = %d\n", 3 + 4);
  printf("sum2 = %d\n", addnumbers(6, 5));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x6,%edi
  call   <addnumbers@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D15: sum = %d


tool: D18: sum2 = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("sum = %d\n", 3 + 4);
  printf("sum2 = %d\n", addnumbers(6, 5));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x6,%edi
  call   <addnumbers@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D18
type: string

tool: D10: sum = %d


tool: D18: sum2 = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("sum = %d\n", 3 + 4);
  printf("sum2 = %d\n", addnumbers(6, 5));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0x6,%edi
  call   <addnumbers@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D8: sum = %d


tool: D6: sum2 = %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("sum = %d\n", 3 + 4);
  printf("sum2 = %d\n", addnumbers(6, 5));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CG_DrawFlashBlendBehindHUD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <CG_DrawFlashZoomTransition@plt>
  mov    $0x0,%eax
  call   <CG_DrawFlashFade@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CG_DrawFlashBlendBehindHUD(void) {
  CG_DrawFlashZoomTransition();
  CG_DrawFlashFade();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CG_DrawFlashBlendBehindHUD>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CG_DrawFlashZoomTransition@plt>
  mov    $0x0,%eax
  call   <CG_DrawFlashFade@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void CG_DrawFlashBlendBehindHUD(void) {
  CG_DrawFlashZoomTransition();
  CG_DrawFlashFade();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CG_DrawFlashBlendBehindHUD>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CG_DrawFlashZoomTransition@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <CG_DrawFlashFade@plt>
```

assistant: ```c
void CG_DrawFlashBlendBehindHUD(void) {
  CG_DrawFlashZoomTransition();
  CG_DrawFlashFade();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CG_DrawFlashBlendBehindHUD>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CG_DrawFlashZoomTransition@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <CG_DrawFlashFade@plt>
```

assistant: ```c
void CG_DrawFlashBlendBehindHUD(void) {
  CG_DrawFlashZoomTransition();
  CG_DrawFlashFade();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_ovp_disassembled_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x93a3020,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  add    $0x4,%rax
  mov    -0x88(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <normalize_assembly_format@plt>
  mov    -0x98(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  lea    -0x78(%rbp),%rsi
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_line@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int parse_ovp_disassembled_line(const char *line, char *instruction_name, char *instruction_args) {
  char normalized_line[100] = " 0:\t";
  normalize_assembly_format(line, normalized_line + 4);
  unsigned int unused_address;
  int result = parse_line((const char *)normalized_line, &unused_address, instruction_name, instruction_args);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_ovp_disassembled_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movq   $0x93a3020,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movl   $0x0,0x70(%rsp)
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rsi
  call   <normalize_assembly_format@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rdi
  call   <parse_line@plt>
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_ovp_disassembled_line(const char *line, char *instruction_name, char *instruction_args) {
  char normalized_line[100] = " 0:\t";
  normalize_assembly_format(line, normalized_line + 4);
  unsigned int unused_address;
  int result = parse_line((const char *)normalized_line, &unused_address, instruction_name, instruction_args);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_ovp_disassembled_line>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  movq   $0x93a3020,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x70(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <normalize_assembly_format@plt>
  mov    %r12,%rdx
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %rbp,%rdi
  call   <parse_line@plt>
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  sub    $0xffffffffffffff80,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_ovp_disassembled_line(const char *line, char *instruction_name, char *instruction_args) {
  char normalized_line[100] = " 0:\t";
  normalize_assembly_format(line, normalized_line + 4);
  unsigned int unused_address;
  int result = parse_line((const char *)normalized_line, &unused_address, instruction_name, instruction_args);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_ovp_disassembled_line>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  movq   $0x93a3020,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x70(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <normalize_assembly_format@plt>
  mov    %r12,%rdx
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %rbp,%rdi
  call   <parse_line@plt>
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  sub    $0xffffffffffffff80,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_ovp_disassembled_line(const char *line, char *instruction_name, char *instruction_args) {
  char normalized_line[100] = " 0:\t";
  normalize_assembly_format(line, normalized_line + 4);
  unsigned int unused_address;
  int result = parse_line((const char *)normalized_line, &unused_address, instruction_name, instruction_args);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modulo_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L58
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L58
  mov    -0x1c(%rbp),%eax
  neg    %eax
  cmp    %eax,-0x18(%rbp)
  jl     L58
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L49
L58:
  mov    $0x5e,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <assert_failed@plt>
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x1c(%rbp),%eax
  sub    %eax,-0x4(%rbp)
L5:
  cmpl   $0x0,-0x4(%rbp)
  jns    L10
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h

assistant: ```c
int modulo_add(int x, int y, int mod) {
  int sum = x + y;
  do {
    if (!(0 <= x && x < mod && -mod <= y && y <= mod))
      assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h", 94);
  } while (0);
  if (sum >= mod)
    sum -= mod;
  if (sum < 0)
    sum += mod;
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<modulo_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  lea    (%rdi,%rsi,1),%ebp
  test   %edi,%edi
  js     L55
  cmp    %edx,%edi
  jge    L55
  mov    %edx,%eax
  neg    %eax
  cmp    %esi,%eax
  jg     L55
  cmp    %edx,%esi
  jle    L4
L55:
  mov    $0x5e,%esi
  lea    D8(%rip),%rdi
  call   <assert_failed@plt>
L4:
  cmp    %ebx,%ebp
  jl     L48
  sub    %ebx,%ebp
L37:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  add    %ebp,%ebx
  test   %ebp,%ebp
  cmovs  %ebx,%ebp
  jmp    L37
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h

assistant: ```c
int modulo_add(int x, int y, int mod) {
  int sum = x + y;
  do {
    if (!(0 <= x && x < mod && -mod <= y && y <= mod))
      assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h", 94);
  } while (0);
  if (sum >= mod)
    sum -= mod;
  if (sum < 0)
    sum += mod;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<modulo_add>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L3
  cmp    %edx,%edi
  jge    L3
  mov    %edx,%eax
  neg    %eax
  cmp    %esi,%eax
  jg     L3
  cmp    %edx,%esi
  jle    L24
L3:
  mov    $0x5e,%esi
  lea    D2(%rip),%rdi
  call   <assert_failed@plt>
L24:
  cmp    %ebx,%r12d
  jl     L41
  sub    %ebx,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  add    %r12d,%ebx
  test   %r12d,%r12d
  cmovs  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h

assistant: ```c
int modulo_add(int x, int y, int mod) {
  int sum = x + y;
  do {
    if (!(0 <= x && x < mod && -mod <= y && y <= mod))
      assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h", 94);
  } while (0);
  if (sum >= mod)
    sum -= mod;
  if (sum < 0)
    sum += mod;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<modulo_add>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L13
  cmp    %edx,%edi
  jge    L13
  mov    %edx,%eax
  neg    %eax
  cmp    %esi,%eax
  jg     L13
  cmp    %edx,%esi
  jle    L35
L13:
  mov    $0x5e,%esi
  lea    D4(%rip),%rdi
  call   <assert_failed@plt>
L35:
  cmp    %ebx,%r12d
  jl     L41
  sub    %ebx,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  add    %r12d,%ebx
  test   %r12d,%r12d
  cmovs  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h

assistant: ```c
int modulo_add(int x, int y, int mod) {
  int sum = x + y;
  do {
    if (!(0 <= x && x < mod && -mod <= y && y <= mod))
      assert_failed("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Bytewerk/uClinux-ipcam/refs/heads/master/integer.h", 94);
  } while (0);
  if (sum >= mod)
    sum -= mod;
  if (sum < 0)
    sum += mod;
  return sum;
}
```