ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<zipmapRawEntryLength>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <zipmapRawKeyLength@plt>
  mov    %eax,%ebp
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rdi
  call   <zipmapRawValueLength@plt>
  add    $0x8,%rsp
  add    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zipmapRawEntryLength(unsigned char *p) {
  unsigned int l = zipmapRawKeyLength(p);
  return l + zipmapRawValueLength(p + l);
}
```
user: Translate the below assembly code into C programming language:

```asm
<zipmapRawEntryLength>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <zipmapRawKeyLength@plt>
  mov    %eax,%ebp
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rdi
  call   <zipmapRawValueLength@plt>
  add    $0x8,%rsp
  add    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int zipmapRawEntryLength(unsigned char *p) {
  unsigned int l = zipmapRawKeyLength(p);
  return l + zipmapRawValueLength(p + l);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %edx,%ecx
  sar    %ecx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  jmp    L13
L19:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int fun(int n) {
  if ((n - 1) % 5 == 0)
    return n - (n - 1) / 5 - 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fun>:
  endbr64
  lea    -0x1(%rdi),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    $0x0,%eax
  cmp    %ecx,%edx
  je     L6
L14:
  ret
L6:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %eax,%edx
  lea    -0x1(%rdi,%rdx,1),%eax
  jmp    L14
```

assistant: ```c
int fun(int n) {
  if ((n - 1) % 5 == 0)
    return n - (n - 1) / 5 - 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun>:
  endbr64
  lea    -0x1(%rdi),%eax
  xor    %r8d,%r8d
  imul   $0xcccccccd,%eax,%edx
  add    $0x19999999,%edx
  cmp    $0x33333332,%edx
  ja     L7
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %edx,%eax
  lea    -0x1(%rdi,%rax,1),%r8d
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun(int n) {
  if ((n - 1) % 5 == 0)
    return n - (n - 1) / 5 - 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fun>:
  endbr64
  lea    -0x1(%rdi),%eax
  xor    %r8d,%r8d
  imul   $0xcccccccd,%eax,%edx
  add    $0x19999999,%edx
  cmp    $0x33333332,%edx
  ja     L0
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  sub    %edx,%eax
  lea    -0x1(%rdi,%rax,1),%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun(int n) {
  if ((n - 1) % 5 == 0)
    return n - (n - 1) / 5 - 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__dealer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: [%ld] %d


assistant: ```c
int __dealer(void *arg) {
  int _arg = *((int *)arg);
  printf("[%ld] %d\n", pthread_self(), _arg);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__dealer>:
  endbr64
  push   %rbx
  mov    (%rdi),%ebx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: [%ld] %d


assistant: ```c
int __dealer(void *arg) {
  int _arg = *((int *)arg);
  printf("[%ld] %d\n", pthread_self(), _arg);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__dealer>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    (%rdi),%r12d
  call   <pthread_self@plt>
  mov    %r12d,%edx
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: [%ld] %d


assistant: ```c
int __dealer(void *arg) {
  int _arg = *((int *)arg);
  printf("[%ld] %d\n", pthread_self(), _arg);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__dealer>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    (%rdi),%r12d
  call   <pthread_self@plt>
  mov    %r12d,%edx
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: [%ld] %d


assistant: ```c
int __dealer(void *arg) {
  int _arg = *((int *)arg);
  printf("[%ld] %d\n", pthread_self(), _arg);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <_DIAGASSERT@plt>
  jmp    L8
L9:
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
L4:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  char *t = s;
  _DIAGASSERT(t != NULL);
  for (; *t; ++t)
    ;
  while ((*t++ = *append++) != '\0')
    ;
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x1,%edi
  call   <_DIAGASSERT@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L0
  mov    %rbp,%rdx
L14:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L14
L32:
  mov    $0x0,%eax
L29:
  movzbl (%rbx,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L29
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rdx
  jmp    L32
```

assistant: ```c
char *strcat(char *s, const char *append) {
  char *t = s;
  _DIAGASSERT(t != NULL);
  for (; *t; ++t)
    ;
  while ((*t++ = *append++) != '\0')
    ;
  return (s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <_DIAGASSERT@plt>
  cmpb   $0x0,(%r12)
  mov    %r12,%rdx
  je     L24
  nopl   (%rax)
L5:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L5
L24:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl (%rbx,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L21
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  char *t = s;
  _DIAGASSERT(t != NULL);
  for (; *t; ++t)
    ;
  while ((*t++ = *append++) != '\0')
    ;
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <_DIAGASSERT@plt>
  cmpb   $0x0,(%r12)
  mov    %r12,%rdx
  je     L24
  nopl   (%rax)
L10:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L10
L24:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl (%rbx,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L22
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  char *t = s;
  _DIAGASSERT(t != NULL);
  for (; *t; ++t)
    ;
  while ((*t++ = *append++) != '\0')
    ;
  return (s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <run_example@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <run_example@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D17: tests/testdata/uniprot_sprot.fasta

tool: D1: tests/testdata/Rfam_11_0.fasta

assistant: ```c
int main(int argc, char **argv) {
  run_example("tests/testdata/uniprot_sprot.fasta");
  run_example("tests/testdata/Rfam_11_0.fasta");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <run_example@plt>
  lea    D13(%rip),%rdi
  call   <run_example@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string

tool: D6: tests/testdata/uniprot_sprot.fasta

tool: D13: tests/testdata/Rfam_11_0.fasta

assistant: ```c
int main(int argc, char **argv) {
  run_example("tests/testdata/uniprot_sprot.fasta");
  run_example("tests/testdata/Rfam_11_0.fasta");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <run_example@plt>
  lea    D11(%rip),%rdi
  call   <run_example@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
data_type: string
name: retrieve_data
arguments: tag: D11
data_type: string

tool: D19: tests/testdata/uniprot_sprot.fasta

tool: D11: tests/testdata/Rfam_11_0.fasta

assistant: ```c
int main(int argc, char **argv) {
  run_example("tests/testdata/uniprot_sprot.fasta");
  run_example("tests/testdata/Rfam_11_0.fasta");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <run_example@plt>
  lea    D3(%rip),%rdi
  call   <run_example@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D3
datatype: string

tool: D6: tests/testdata/uniprot_sprot.fasta

tool: D3: tests/testdata/Rfam_11_0.fasta

assistant: ```c
int main(int argc, char **argv) {
  run_example("tests/testdata/uniprot_sprot.fasta");
  run_example("tests/testdata/Rfam_11_0.fasta");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<no_mem_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: Could not allocate memory: %s


assistant: ```c
void no_mem_exit(char *where) {
  printf("Could not allocate memory: %s\n", where);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<no_mem_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: Could not allocate memory: %s


assistant: ```c
void no_mem_exit(char *where) {
  printf("Could not allocate memory: %s\n", where);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<no_mem_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: Could not allocate memory: %s


assistant: ```c
void no_mem_exit(char *where) {
  printf("Could not allocate memory: %s\n", where);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<no_mem_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: Could not allocate memory: %s


assistant: ```c
void no_mem_exit(char *where) {
  printf("Could not allocate memory: %s\n", where);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<red_srand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <srand@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void red_srand() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  srand(tv.tv_sec * 1000000 + tv.tv_usec);
}
```
user: What is the c source code of the assembly code below?

```asm
<red_srand>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%edi
  movslq %edi,%rdi
  add    0x8(%rsp),%rdi
  call   <srand@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void red_srand() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  srand(tv.tv_sec * 1000000 + tv.tv_usec);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<red_srand>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%edi
  movslq %edi,%rdi
  add    0x8(%rsp),%rdi
  call   <srand@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void red_srand() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  srand(tv.tv_sec * 1000000 + tv.tv_usec);
}
```
user: Translate the below assembly code into C programming language:

```asm
<red_srand>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%edi
  movslq %edi,%rdi
  add    0x8(%rsp),%rdi
  call   <srand@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void red_srand() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  srand(tv.tv_sec * 1000000 + tv.tv_usec);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<next_permutation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  or     -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x4(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  and    %edx,%eax
  lea    -0x1(%rax),%edx
  xor    %eax,%eax
  tzcnt  -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int next_permutation(unsigned int v) {
  unsigned int t = v | (v - 1);
  return (t + 1) | (((~t & (t + 1)) - 1) >> (__builtin_ctz(v) + 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<next_permutation>:
  endbr64
  lea    -0x1(%rdi),%eax
  or     %edi,%eax
  lea    0x1(%rax),%edx
  tzcnt  %edi,%edi
  not    %eax
  and    %edx,%eax
  sub    $0x1,%eax
  lea    0x1(%rdi),%ecx
  shr    %cl,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int next_permutation(unsigned int v) {
  unsigned int t = v | (v - 1);
  return (t + 1) | (((~t & (t + 1)) - 1) >> (__builtin_ctz(v) + 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_permutation>:
  endbr64
  lea    -0x1(%rdi),%eax
  or     %edi,%eax
  tzcnt  %edi,%edi
  lea    0x1(%rax),%edx
  not    %eax
  lea    0x1(%rdi),%ecx
  and    %edx,%eax
  sub    $0x1,%eax
  shr    %cl,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int next_permutation(unsigned int v) {
  unsigned int t = v | (v - 1);
  return (t + 1) | (((~t & (t + 1)) - 1) >> (__builtin_ctz(v) + 1));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_permutation>:
  endbr64
  lea    -0x1(%rdi),%eax
  or     %edi,%eax
  tzcnt  %edi,%edi
  lea    0x1(%rax),%edx
  not    %eax
  lea    0x1(%rdi),%ecx
  and    %edx,%eax
  sub    $0x1,%eax
  shr    %cl,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned int next_permutation(unsigned int v) {
  unsigned int t = v | (v - 1);
  return (t + 1) | (((~t & (t + 1)) - 1) >> (__builtin_ctz(v) + 1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_fifo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3d,%edi
  call   <bus_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint8_t read_fifo(void) {
  uint8_t data;
  data = bus_read(0x3D);
  return data;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_fifo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3d,%edi
  call   <bus_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t read_fifo(void) {
  uint8_t data;
  data = bus_read(0x3D);
  return data;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_fifo>:
  endbr64
  mov    $0x3d,%edi
  jmp    1050 <bus_read@plt>
```

assistant: ```c
uint8_t read_fifo(void) {
  uint8_t data;
  data = bus_read(0x3D);
  return data;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_fifo>:
  endbr64
  mov    $0x3d,%edi
  jmp    1050 <bus_read@plt>
```

assistant: ```c
uint8_t read_fifo(void) {
  uint8_t data;
  data = bus_read(0x3D);
  return data;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L5
L28:
  mov    -0x14(%rbp),%eax
  shr    %eax
  mov    %eax,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  shr    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    $0xffffffff,%eax
  jl     L24
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cmp    $0x1,%eax
  jg     L24
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  shr    %eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int xqrt(unsigned int x) {
  unsigned int i, l;
  if (x <= 0)
    return 0;
  i = x / 2;
  while (1) {
    l = i;
    i = (l + x / l) / 2;
    if (abs((int)l - i) <= 1) {
      return (i + x / i) / 2;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xqrt>:
  endbr64
  test   %edi,%edi
  je     L15
  mov    %edi,%ecx
  shr    %ecx
L7:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  add    %ecx,%eax
  mov    %ecx,%edx
  shr    %eax
  mov    %eax,%ecx
  add    $0x1,%edx
  sub    %eax,%edx
  cmp    $0x2,%edx
  ja     L7
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %eax,%edi
  add    %ecx,%edi
  shr    %edi
L15:
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned int xqrt(unsigned int x) {
  unsigned int i, l;
  if (x <= 0)
    return 0;
  i = x / 2;
  while (1) {
    l = i;
    i = (l + x / l) / 2;
    if (abs((int)l - i) <= 1) {
      return (i + x / i) / 2;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xqrt>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  je     L14
  mov    %edi,%ecx
  shr    %ecx
  nop
L10:
  mov    %r8d,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %ecx,%edx
  add    $0x1,%edx
  add    %ecx,%eax
  shr    %eax
  sub    %eax,%edx
  mov    %eax,%ecx
  cmp    $0x2,%edx
  ja     L10
  mov    %r8d,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %eax,%r8d
  add    %ecx,%r8d
  shr    %r8d
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int xqrt(unsigned int x) {
  unsigned int i, l;
  if (x <= 0)
    return 0;
  i = x / 2;
  while (1) {
    l = i;
    i = (l + x / l) / 2;
    if (abs((int)l - i) <= 1) {
      return (i + x / i) / 2;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xqrt>:
  endbr64
  mov    %edi,%r8d
  test   %edi,%edi
  je     L8
  mov    %edi,%ecx
  shr    %ecx
  nop
L10:
  mov    %r8d,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %ecx,%edx
  add    $0x1,%edx
  add    %ecx,%eax
  shr    %eax
  sub    %eax,%edx
  mov    %eax,%ecx
  cmp    $0x2,%edx
  ja     L10
  mov    %r8d,%eax
  xor    %edx,%edx
  div    %ecx
  mov    %eax,%r8d
  add    %ecx,%r8d
  shr    %r8d
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int xqrt(unsigned int x) {
  unsigned int i, l;
  if (x <= 0)
    return 0;
  i = x / 2;
  while (1) {
    l = i;
    i = (l + x / l) / 2;
    if (abs((int)l - i) <= 1) {
      return (i + x / i) / 2;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap2(int *v, double *w, int i, int j) {
  int temp;
  double temp2;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
  temp2 = w[i];
  w[i] = w[j];
  w[j] = temp2;
}
```