ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<parse_sexigesimal_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <split_sexigesimal_str@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  movss  D5(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  movss  D2(%rip),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: byte[4]
name: extract_symbolic_data
arguments: label: D2
data_type: byte[4]

tool: {"D5": [0x00,0x00,0x70,0x42]}

tool: {"D2": [0x00,0x00,0x61,0x45]}

assistant: ```c
float parse_sexigesimal_str(const char *str) {
  float splitted[3];
  split_sexigesimal_str(str, &splitted);
  return splitted[0] + splitted[1] / 60 + splitted[2] / 3600;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_sexigesimal_str>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <split_sexigesimal_str@plt>
  movss  0x10(%rsp),%xmm0
  divss  D18(%rip),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  divss  D14(%rip),%xmm1
  addss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: byte[4]
name: parse_data
arguments: data_tag: D14
data_type: byte[4]

tool: {"D18": [0x00,0x00,0x70,0x42]}

tool: {"D14": [0x00,0x00,0x61,0x45]}

assistant: ```c
float parse_sexigesimal_str(const char *str) {
  float splitted[3];
  split_sexigesimal_str(str, &splitted);
  return splitted[0] + splitted[1] / 60 + splitted[2] / 3600;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_sexigesimal_str>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <split_sexigesimal_str@plt>
  movss  0x10(%rsp),%xmm0
  divss  D18(%rip),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  divss  D12(%rip),%xmm1
  addss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: byte[4]
name: parse_data
arguments: data_label: D12
data_type: byte[4]

tool: {"D18": [0x00,0x00,0x70,0x42]}

tool: {"D12": [0x00,0x00,0x61,0x45]}

assistant: ```c
float parse_sexigesimal_str(const char *str) {
  float splitted[3];
  split_sexigesimal_str(str, &splitted);
  return splitted[0] + splitted[1] / 60 + splitted[2] / 3600;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_sexigesimal_str>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <split_sexigesimal_str@plt>
  movss  0x10(%rsp),%xmm0
  divss  D11(%rip),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  divss  D19(%rip),%xmm1
  addss  %xmm1,%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: byte[4]
name: read_data
arguments: data_label: D19
data_type: byte[4]

tool: {"D11": [0x00,0x00,0x70,0x42]}

tool: {"D19": [0x00,0x00,0x61,0x45]}

assistant: ```c
float parse_sexigesimal_str(const char *str) {
  float splitted[3];
  split_sexigesimal_str(str, &splitted);
  return splitted[0] + splitted[1] / 60 + splitted[2] / 3600;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x12(%rbp),%eax
  cmp    $0x40,%al
  jle    L70
  movzbl -0x12(%rbp),%eax
  cmp    $0x5a,%al
  jle    L63
L70:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L118
L63:
  movzbl -0x12(%rbp),%eax
  sub    $0x40,%eax
  mov    %al,-0x11(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L42:
  movl   $0x0,-0xc(%rbp)
  jmp    L90
L50:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L90:
  movsbl -0x11(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L50
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L81:
  mov    -0xc(%rbp),%eax
  add    $0x41,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L81
  subl   $0x2,-0xc(%rbp)
  jmp    L73
L86:
  mov    -0xc(%rbp),%eax
  add    $0x41,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0xc(%rbp)
L73:
  cmpl   $0x0,-0xc(%rbp)
  jns    L86
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L12:
  movsbl -0x11(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L42
  mov    $0x0,%eax
L118:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D27
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string

tool: D3: Pls input a latter: 

tool: D27: %c

tool: D24: we need a capital latter.

assistant: ```c
int main(void) {
  printf("Pls input a latter: ");
  char ch;
  scanf("%c", &ch);
  if ((ch < 'A') || (ch > 'Z')) {
    printf("we need a capital latter.\n");
    return 1;
  }
  char line;
  line = ch - 'A' + 1;
  int i, j;
  for (i = 1; i <= line; i++) {
    for (j = 0; j < line - i; j++) {
      printf(" ");
    }
    for (j = 0; j < i; j++) {
      printf("%c", 'A' + j);
    }
    for (j -= 2; j >= 0; j--) {
      printf("%c", 'A' + j);
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L44
  sub    $0x40,%eax
  movsbl %al,%r13d
  lea    -0x1(%r13),%r12d
  mov    $0x42,%ebp
  jmp    L43
L44:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L11
L67:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  jne    L67
L46:
  lea    -0x41(%rbp),%eax
  test   %eax,%eax
  jle    L37
  mov    $0x41,%ebx
L93:
  mov    %ebx,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L93
  mov    %ebp,%ebx
  sub    $0x43,%ebx
  js     L37
L36:
  lea    0x41(%rbx),%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jns    L36
L37:
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  lea    0x1(%rbp),%eax
  sub    $0x40,%ebp
  cmp    %ebp,%r13d
  jl     L79
  mov    %eax,%ebp
L43:
  mov    %r12d,%r14d
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L67
  jmp    L46
L79:
  mov    $0x0,%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D25
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D16: Pls input a latter: 

tool: D25: %c

tool: D4: we need a capital latter.

assistant: ```c
int main(void) {
  printf("Pls input a latter: ");
  char ch;
  scanf("%c", &ch);
  if ((ch < 'A') || (ch > 'Z')) {
    printf("we need a capital latter.\n");
    return 1;
  }
  char line;
  line = ch - 'A' + 1;
  int i, j;
  for (i = 1; i <= line; i++) {
    for (j = 0; j < line - i; j++) {
      printf(" ");
    }
    for (j = 0; j < i; j++) {
      printf("%c", 'A' + j);
    }
    for (j -= 2; j >= 0; j--) {
      printf("%c", 'A' + j);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L3
  lea    -0x40(%rax),%ebp
  mov    $0x42,%r12d
  movzbl %bpl,%ebp
  sub    $0x1,%ebp
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  je     L69
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L8
L69:
  mov    $0x41,%ebx
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L0
  lea    -0x43(%r12),%ebx
  cmp    $0x42,%r12d
  je     L30
  nopw   0x0(%rax,%rax,1)
L27:
  lea    0x41(%rbx),%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L27
L30:
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xffffffff,%ebp
  jne    L31
  xor    %eax,%eax
L70:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L70
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D7
type: string

tool: D0: Pls input a latter: 

tool: D8: %c

tool: D7: we need a capital latter.

assistant: ```c
int main(void) {
  printf("Pls input a latter: ");
  char ch;
  scanf("%c", &ch);
  if ((ch < 'A') || (ch > 'Z')) {
    printf("we need a capital latter.\n");
    return 1;
  }
  char line;
  line = ch - 'A' + 1;
  int i, j;
  for (i = 1; i <= line; i++) {
    for (j = 0; j < line - i; j++) {
      printf(" ");
    }
    for (j = 0; j < i; j++) {
      printf("%c", 'A' + j);
    }
    for (j -= 2; j >= 0; j--) {
      printf("%c", 'A' + j);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L0
  lea    -0x40(%rax),%ebp
  mov    $0x42,%r12d
  movzbl %bpl,%ebp
  sub    $0x1,%ebp
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  je     L14
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jne    L81
L14:
  mov    $0x41,%ebx
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jne    L15
  lea    -0x43(%r12),%ebx
  cmp    $0x42,%r12d
  je     L62
  nopw   0x0(%rax,%rax,1)
L64:
  lea    0x41(%rbx),%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L64
L62:
  mov    $0xa,%edi
  sub    $0x1,%ebp
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    $0xffffffff,%ebp
  jne    L20
  xor    %eax,%eax
L54:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L54
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D20
type: string

tool: D6: Pls input a latter: 

tool: D27: %c

tool: D20: we need a capital latter.

assistant: ```c
int main(void) {
  printf("Pls input a latter: ");
  char ch;
  scanf("%c", &ch);
  if ((ch < 'A') || (ch > 'Z')) {
    printf("we need a capital latter.\n");
    return 1;
  }
  char line;
  line = ch - 'A' + 1;
  int i, j;
  for (i = 1; i <= line; i++) {
    for (j = 0; j < line - i; j++) {
      printf(" ");
    }
    for (j = 0; j < i; j++) {
      printf("%c", 'A' + j);
    }
    for (j -= 2; j >= 0; j--) {
      printf("%c", 'A' + j);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<two_raised_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L3:
  shlq   -0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  ja     L3
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long two_raised_to(unsigned int n) {
  long long rslt = 1;
  for (int i = 0; i < n; i++) {
    rslt *= 2;
  }
  return (rslt);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<two_raised_to>:
  endbr64
  test   %edi,%edi
  je     L1
  mov    $0x0,%eax
  mov    $0x1,%edx
L17:
  add    %rdx,%rdx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L17
L22:
  mov    %rdx,%rax
  ret
L1:
  mov    $0x1,%edx
  jmp    L22
```

assistant: ```c
unsigned long long two_raised_to(unsigned int n) {
  long long rslt = 1;
  for (int i = 0; i < n; i++) {
    rslt *= 2;
  }
  return (rslt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<two_raised_to>:
  endbr64
  test   %edi,%edi
  je     L11
  xor    %edx,%edx
  mov    $0x1,%eax
  nop
L5:
  add    $0x1,%edx
  add    %rax,%rax
  cmp    %edx,%edi
  jne    L5
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long long two_raised_to(unsigned int n) {
  long long rslt = 1;
  for (int i = 0; i < n; i++) {
    rslt *= 2;
  }
  return (rslt);
}
```
user: What is the c source code of the assembly code below?

```asm
<two_raised_to>:
  endbr64
  test   %edi,%edi
  je     L1
  xor    %edx,%edx
  mov    $0x1,%eax
  nop
L18:
  add    $0x1,%edx
  add    %rax,%rax
  cmp    %edx,%edi
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long long two_raised_to(unsigned int n) {
  long long rslt = 1;
  for (int i = 0; i < n; i++) {
    rslt *= 2;
  }
  return (rslt);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrix_reduction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct Matrix *matrix_reduction(struct Matrix *matrix) {
  struct Matrix *m_reduced = NULL;
  return m_reduced;
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix_reduction>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct Matrix *matrix_reduction(struct Matrix *matrix) {
  struct Matrix *m_reduced = NULL;
  return m_reduced;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_reduction>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct Matrix *matrix_reduction(struct Matrix *matrix) {
  struct Matrix *m_reduced = NULL;
  return m_reduced;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_reduction>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
struct Matrix *matrix_reduction(struct Matrix *matrix) {
  struct Matrix *m_reduced = NULL;
  return m_reduced;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hookup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <check_sockdir@plt>
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <path_join@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cli_conn@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L1
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <errx@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D10: issue

tool: D13: Cannot connect to mdm-master

assistant: ```c
int hookup(const char *sockdir) {
  char *master_addr;
  int master_fd;
  check_sockdir(sockdir);
  master_addr = path_join(sockdir, "issue");
  master_fd = cli_conn(master_addr);
  if (master_fd < 0)
    errx(2, "Cannot connect to mdm-master");
  free(master_addr);
  return master_fd;
}
```
user: What is the c source code of the assembly code below?

```asm
<hookup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <check_sockdir@plt>
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <path_join@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <cli_conn@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L16
L18:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D6(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D6
type: string

tool: D11: issue

tool: D6: Cannot connect to mdm-master

assistant: ```c
int hookup(const char *sockdir) {
  char *master_addr;
  int master_fd;
  check_sockdir(sockdir);
  master_addr = path_join(sockdir, "issue");
  master_fd = cli_conn(master_addr);
  if (master_fd < 0)
    errx(2, "Cannot connect to mdm-master");
  free(master_addr);
  return master_fd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hookup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <check_sockdir@plt>
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <path_join@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <cli_conn@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L9
L5:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D0(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D2: issue

tool: D0: Cannot connect to mdm-master

assistant: ```c
int hookup(const char *sockdir) {
  char *master_addr;
  int master_fd;
  check_sockdir(sockdir);
  master_addr = path_join(sockdir, "issue");
  master_fd = cli_conn(master_addr);
  if (master_fd < 0)
    errx(2, "Cannot connect to mdm-master");
  free(master_addr);
  return master_fd;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hookup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <check_sockdir@plt>
  mov    %rbp,%rdi
  lea    D18(%rip),%rsi
  call   <path_join@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <cli_conn@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L1
L0:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D7(%rip),%rsi
  mov    $0x2,%edi
  call   <errx@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D18: issue

tool: D7: Cannot connect to mdm-master

assistant: ```c
int hookup(const char *sockdir) {
  char *master_addr;
  int master_fd;
  check_sockdir(sockdir);
  master_addr = path_join(sockdir, "issue");
  master_fd = cli_conn(master_addr);
  if (master_fd < 0)
    errx(2, "Cannot connect to mdm-master");
  free(master_addr);
  return master_fd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getScore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x5a,%eax
  je     L65
  cmp    $0x5a,%eax
  jg     L129
  cmp    $0x59,%eax
  je     L193
  cmp    $0x59,%eax
  jg     L129
  cmp    $0x58,%eax
  je     L210
  cmp    $0x58,%eax
  jg     L129
  cmp    $0x57,%eax
  jg     L129
  cmp    $0x56,%eax
  jge    L193
  cmp    $0x4b,%eax
  jg     L99
  cmp    $0x41,%eax
  jge    L184
  jmp    L129
L78:
  sub    $0x4c,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0x3cd,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L51
  mov    %rax,%rdx
  and    $0x12,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L77
  and    $0x20,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L65
  jmp    L129
L184:
  sub    $0x41,%eax
  cmp    $0xa,%eax
  ja     L129
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L99:
  cmp    $0x55,%eax
  jg     L129
  cmp    $0x4c,%eax
  jge    L78
  jmp    L129
L51:
  mov    $0x1,%eax
  jmp    L143
  mov    $0x2,%eax
  jmp    L143
L77:
  mov    $0x3,%eax
  jmp    L143
L193:
  mov    $0x4,%eax
  jmp    L143
  mov    $0x5,%eax
  jmp    L143
L210:
  mov    $0x8,%eax
  jmp    L143
L65:
  mov    $0xa,%eax
  jmp    L143
L129:
  mov    $0x0,%eax
L143:
  pop    %rbp
  ret
```

assistant: ```c
int getScore(char ch) {
  switch (ch) {
  case 'A':
  case 'E':
  case 'I':
  case 'L':
  case 'N':
  case 'O':
  case 'R':
  case 'S':
  case 'T':
  case 'U':
    return 1;
    break;
  case 'D':
  case 'G':
    return 2;
    break;
  case 'B':
  case 'C':
  case 'M':
  case 'P':
    return 3;
    break;
  case 'F':
  case 'H':
  case 'V':
  case 'W':
  case 'Y':
    return 4;
    break;
  case 'K':
    return 5;
    break;
  case 'J':
  case 'X':
    return 8;
    break;
  case 'Q':
  case 'Z':
    return 10;
    break;
  default:
    return 0;
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getScore>:
  endbr64
  cmp    $0x4b,%dil
  jg     L18
  cmp    $0x40,%dil
  jle    L72
  sub    $0x41,%edi
  cmp    $0xa,%dil
  ja     L7
  movzbl %dil,%edi
  lea    D1(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L72:
  mov    $0x0,%eax
  ret
L6:
  mov    $0x3,%eax
  test   $0x12,%dl
  jne    L76
  cmp    $0x51,%dil
  mov    $0x0,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L18:
  cmp    $0x55,%dil
  jg     L46
  lea    -0x4c(%rdi),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  mov    $0x1,%eax
  test   $0x3cd,%edx
  je     L6
L76:
  ret
L46:
  cmp    $0x59,%dil
  je     L33
  jle    L64
  cmp    $0x5a,%dil
  mov    $0x0,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
L64:
  mov    $0x4,%eax
  cmp    $0x57,%dil
  jle    L76
  cmp    $0x58,%dil
  sete   %al
  movzbl %al,%eax
  shl    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x5,%eax
  ret
L33:
  mov    $0x4,%eax
  jmp    L76
```

assistant: ```c
int getScore(char ch) {
  switch (ch) {
  case 'A':
  case 'E':
  case 'I':
  case 'L':
  case 'N':
  case 'O':
  case 'R':
  case 'S':
  case 'T':
  case 'U':
    return 1;
    break;
  case 'D':
  case 'G':
    return 2;
    break;
  case 'B':
  case 'C':
  case 'M':
  case 'P':
    return 3;
    break;
  case 'F':
  case 'H':
  case 'V':
  case 'W':
  case 'Y':
    return 4;
    break;
  case 'K':
    return 5;
    break;
  case 'J':
  case 'X':
    return 8;
    break;
  case 'Q':
  case 'Z':
    return 10;
    break;
  default:
    return 0;
    break;
  }
}
```