ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  -0x2c(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double params(int a, int b, int c, int d, int e, int f, float g, double h) {
  double x = a + b + c + d + e + f + g + h;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<params>:
  endbr64
  movaps %xmm0,%xmm2
  add    %esi,%edi
  add    %edx,%edi
  add    %ecx,%edi
  add    %r8d,%edi
  add    %r9d,%edi
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  addss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double params(int a, int b, int c, int d, int e, int f, float g, double h) {
  double x = a + b + c + d + e + f + g + h;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<params>:
  endbr64
  add    %esi,%edi
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  add    %edx,%edi
  add    %ecx,%edi
  add    %r8d,%edi
  add    %r9d,%edi
  cvtsi2ss %edi,%xmm0
  addss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double params(int a, int b, int c, int d, int e, int f, float g, double h) {
  double x = a + b + c + d + e + f + g + h;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<params>:
  endbr64
  add    %esi,%edi
  movaps %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  add    %edx,%edi
  add    %ecx,%edi
  add    %r8d,%edi
  add    %r9d,%edi
  cvtsi2ss %edi,%xmm0
  addss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double params(int a, int b, int c, int d, int e, int f, float g, double h) {
  double x = a + b + c + d + e + f + g + h;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L24:
  movl   $0x1,-0x8(%rbp)
  jmp    L17
L6:
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L33:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jne    L37
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L37:
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x1f3,-0x4(%rbp)
  jle    L33
  addl   $0x1,-0x8(%rbp)
L17:
  cmpl   $0x1f3,-0x8(%rbp)
  jle    L6
  addl   $0x1,-0xc(%rbp)
L18:
  cmpl   $0x1f3,-0xc(%rbp)
  jle    L24
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: side1 is :%4d, side2 is : %4d, hypotenuse is : %4d


assistant: ```c
int main(void) {
  int side1, side2, hypotenuse = 0;
  for (side1 = 1; side1 < 500; side1++) {
    for (side2 = 1; side2 < 500; side2++) {
      for (hypotenuse = 1; hypotenuse < 500; hypotenuse++) {
        if ((hypotenuse * hypotenuse) == (side1 * side1) + (side2 * side2)) {
          printf("side1 is :%4d, side2 is : %4d, hypotenuse is : %4d\n", side1, side2, hypotenuse);
        }
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%r13d
  lea    D4(%rip),%r14
  jmp    L56
L63:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L10
L44:
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %ebp,%eax
  jne    L63
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L63
L10:
  add    $0x1,%r12d
  cmp    $0x1f4,%r12d
  je     L61
L71:
  mov    %r12d,%ebp
  imul   %r12d,%ebp
  add    %r15d,%ebp
  mov    $0x1,%ebx
  jmp    L44
L61:
  add    $0x1,%r13d
  cmp    $0x1f4,%r13d
  je     L32
L56:
  mov    %r13d,%r15d
  imul   %r13d,%r15d
  mov    $0x1,%r12d
  jmp    L71
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: side1 is :%4d, side2 is : %4d, hypotenuse is : %4d


assistant: ```c
int main(void) {
  int side1, side2, hypotenuse = 0;
  for (side1 = 1; side1 < 500; side1++) {
    for (side2 = 1; side2 < 500; side2++) {
      for (hypotenuse = 1; hypotenuse < 500; hypotenuse++) {
        if ((hypotenuse * hypotenuse) == (side1 * side1) + (side2 * side2)) {
          printf("side1 is :%4d, side2 is : %4d, hypotenuse is : %4d\n", side1, side2, hypotenuse);
        }
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L23:
  mov    %r12d,%r14d
  mov    $0x1,%ebp
  imul   %r12d,%r14d
L19:
  mov    %ebp,%r15d
  mov    $0x1,%ebx
  imul   %ebp,%r15d
  add    %r14d,%r15d
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L37
L9:
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %r15d,%eax
  jne    L24
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  jne    L9
L37:
  add    $0x1,%ebp
  cmp    $0x1f4,%ebp
  jne    L19
  add    $0x1,%r12d
  cmp    $0x1f4,%r12d
  jne    L23
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: side1 is :%4d, side2 is : %4d, hypotenuse is : %4d


assistant: ```c
int main(void) {
  int side1, side2, hypotenuse = 0;
  for (side1 = 1; side1 < 500; side1++) {
    for (side2 = 1; side2 < 500; side2++) {
      for (hypotenuse = 1; hypotenuse < 500; hypotenuse++) {
        if ((hypotenuse * hypotenuse) == (side1 * side1) + (side2 * side2)) {
          printf("side1 is :%4d, side2 is : %4d, hypotenuse is : %4d\n", side1, side2, hypotenuse);
        }
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L46:
  mov    %r12d,%r14d
  mov    $0x1,%ebp
  imul   %r12d,%r14d
L21:
  mov    %ebp,%r15d
  mov    $0x2,%ebx
  imul   %ebp,%r15d
  add    %r14d,%r15d
  jmp    L56
  nopl   0x0(%rax)
L43:
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  je     L49
L56:
  mov    %ebx,%eax
  imul   %ebx,%eax
  cmp    %r15d,%eax
  jne    L43
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x1f4,%ebx
  jne    L56
L49:
  add    $0x1,%ebp
  cmp    $0x1f4,%ebp
  jne    L21
  add    $0x1,%r12d
  cmp    $0x1f4,%r12d
  jne    L46
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: side1 is :%4d, side2 is : %4d, hypotenuse is : %4d


assistant: ```c
int main(void) {
  int side1, side2, hypotenuse = 0;
  for (side1 = 1; side1 < 500; side1++) {
    for (side2 = 1; side2 < 500; side2++) {
      for (hypotenuse = 1; hypotenuse < 500; hypotenuse++) {
        if ((hypotenuse * hypotenuse) == (side1 * side1) + (side2 * side2)) {
          printf("side1 is :%4d, side2 is : %4d, hypotenuse is : %4d\n", side1, side2, hypotenuse);
        }
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setseed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <ssecs@plt>
  imul   $0x4cb2f,%rax,%rax
  mov    %rax,%rdi
  call   <abs@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  neg    %rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rbx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <iran1@plt>
  imul   %rbx,%rax
  mov    %rax,%rdi
  call   <abs@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void setseed(long *iseed) {
  long int ssecs(void);
  long iran1(long *idum);
  long ran1seed;
  *iseed = abs(314159 * ssecs());
  ran1seed = -(*iseed);
  *iseed = abs(*iseed * iran1(&ran1seed));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setseed>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ssecs@plt>
  imul   $0x4cb2f,%rax,%rdi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    %rax,0x0(%rbp)
  neg    %rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  call   <iran1@plt>
  imul   %rax,%rbx
  mov    %rbx,%rdi
  call   <abs@plt>
  mov    %rax,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setseed(long *iseed) {
  long int ssecs(void);
  long iran1(long *idum);
  long ran1seed;
  *iseed = abs(314159 * ssecs());
  ran1seed = -(*iseed);
  *iseed = abs(*iseed * iran1(&ran1seed));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setseed>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ssecs@plt>
  imul   $0x4cb2f,%rax,%rdi
  call   <abs@plt>
  mov    %rsp,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rax,%rbx
  neg    %rax
  mov    %rax,(%rsp)
  call   <iran1@plt>
  imul   %rax,%rbx
  mov    %rbx,%rdi
  call   <abs@plt>
  mov    %rax,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setseed(long *iseed) {
  long int ssecs(void);
  long iran1(long *idum);
  long ran1seed;
  *iseed = abs(314159 * ssecs());
  ran1seed = -(*iseed);
  *iseed = abs(*iseed * iran1(&ran1seed));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setseed>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ssecs@plt>
  imul   $0x4cb2f,%rax,%rdi
  call   <abs@plt>
  mov    %rsp,%rdi
  mov    %rax,0x0(%rbp)
  mov    %rax,%rbx
  neg    %rax
  mov    %rax,(%rsp)
  call   <iran1@plt>
  imul   %rax,%rbx
  mov    %rbx,%rdi
  call   <abs@plt>
  mov    %rax,0x0(%rbp)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setseed(long *iseed) {
  long int ssecs(void);
  long iran1(long *idum);
  long ran1seed;
  *iseed = abs(314159 * ssecs());
  ran1seed = -(*iseed);
  *iseed = abs(*iseed * iran1(&ran1seed));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MysqlGetRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L11
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mysql_fetch_row@plt>
L11:
  leave
  ret
```

assistant: ```c
MYSQL_ROW MysqlGetRow(MYSQL_RES *sqlResult) {
  if (sqlResult == NULL)
    return 0;
  return mysql_fetch_row(sqlResult);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MysqlGetRow>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <mysql_fetch_row@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
MYSQL_ROW MysqlGetRow(MYSQL_RES *sqlResult) {
  if (sqlResult == NULL)
    return 0;
  return mysql_fetch_row(sqlResult);
}
```
user: Translate the below assembly code into C programming language:

```asm
<MysqlGetRow>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <mysql_fetch_row@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
MYSQL_ROW MysqlGetRow(MYSQL_RES *sqlResult) {
  if (sqlResult == NULL)
    return 0;
  return mysql_fetch_row(sqlResult);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MysqlGetRow>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <mysql_fetch_row@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
MYSQL_ROW MysqlGetRow(MYSQL_RES *sqlResult) {
  if (sqlResult == NULL)
    return 0;
  return mysql_fetch_row(sqlResult);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  test   %eax,%eax
  je     L5
  mov    -0x4(%rbp),%eax
  jmp    L35
L5:
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x4,-0x4(%rbp)
  jle    L11
  mov    $0xffffffff,%eax
L35:
  leave
  ret
```

assistant: ```c
int findindex(const int *myarray, int (*comp)(const int, const int), const int val) {
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      return i;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<findindex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%ebx
L3:
  mov    %ebx,%r14d
  mov    0x0(%r13,%rbx,4),%edi
  mov    %ebp,%esi
  call   *%r12
  test   %eax,%eax
  jne    L2
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L3
  mov    $0xffffffff,%r14d
L2:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int findindex(const int *myarray, int (*comp)(const int, const int), const int val) {
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<findindex>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
L4:
  mov    (%r14,%rbx,4),%edi
  mov    %ebx,%r13d
  mov    %ebp,%esi
  call   *%r12
  test   %eax,%eax
  jne    L12
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L4
  mov    $0xffffffff,%r13d
L12:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int findindex(const int *myarray, int (*comp)(const int, const int), const int val) {
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findindex>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
L2:
  mov    (%r14,%rbx,4),%edi
  mov    %ebx,%r13d
  mov    %ebp,%esi
  call   *%r12
  test   %eax,%eax
  jne    L8
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L2
  mov    $0xffffffff,%r13d
L8:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int findindex(const int *myarray, int (*comp)(const int, const int), const int val) {
  for (int i = 0; i < 5; i++) {
    if (comp(myarray[i], val))
      return i;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getMonth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb(%rbp),%rcx
  lea    -0xa(%rbp),%rdx
  lea    -0x9(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x7,%edi
  call   <int80@plt>
  add    $0x10,%rsp
  movzbl -0xa(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
char getMonth() {
  char y;
  char mo;
  char d;
  int80(7, &d, &mo, &y, 0, 0, 0);
  return mo;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getMonth>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rcx
  lea    0x6(%rsp),%rdx
  lea    0x7(%rsp),%rsi
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x7,%edi
  call   <int80@plt>
  movzbl 0x16(%rsp),%eax
  add    $0x10,%rsp
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getMonth() {
  char y;
  char mo;
  char d;
  int80(7, &d, &mo, &y, 0, 0, 0);
  return mo;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getMonth>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x7,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rcx
  lea    0x6(%rsp),%rdx
  lea    0x7(%rsp),%rsi
  sub    $0x8,%rsp
  push   $0x0
  call   <int80@plt>
  movzbl 0x16(%rsp),%eax
  pop    %rdx
  pop    %rcx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getMonth() {
  char y;
  char mo;
  char d;
  int80(7, &d, &mo, &y, 0, 0, 0);
  return mo;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getMonth>:
  endbr64
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x7,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rcx
  lea    0x6(%rsp),%rdx
  lea    0x7(%rsp),%rsi
  sub    $0x8,%rsp
  push   $0x0
  call   <int80@plt>
  movzbl 0x16(%rsp),%eax
  pop    %rdx
  pop    %rcx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char getMonth() {
  char y;
  char mo;
  char d;
  int80(7, &d, &mo, &y, 0, 0, 0);
  return mo;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<log_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <log_vwrite@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_error(const char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_vwrite(1, msg, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <log_vwrite@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_error(const char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_vwrite(1, msg, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<log_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <log_vwrite@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_error(const char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_vwrite(1, msg, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<log_error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <log_vwrite@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_error(const char *msg, ...) {
  va_list ap;
  va_start(ap, msg);
  log_vwrite(1, msg, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argparse_help_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <argparse_usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *self, const struct argparse_option *option) {
  (void)option;
  argparse_usage(self);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int argparse_help_cb(struct argparse *self, const struct argparse_option *option) {
  (void)option;
  argparse_usage(self);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
int argparse_help_cb(struct argparse *self, const struct argparse_option *option) {
  (void)option;
  argparse_usage(self);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<argparse_help_cb>:
  endbr64
  sub    $0x8,%rsp
  call   <argparse_usage@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
int argparse_help_cb(struct argparse *self, const struct argparse_option *option) {
  (void)option;
  argparse_usage(self);
  exit(0);
}
```