ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<joystickb_adjust_analog>:
  endbr64
  mov    $0x0,%eax
  cmp    %edx,%esi
  jge    L9
  cmp    %edi,%esi
  jge    L22
  mov    $0x10000,%eax
  cmp    %edi,%edx
  jle    L9
  lea    0x1(%rdx),%eax
  mov    %eax,%ecx
  add    %esi,%ecx
  je     L57
L51:
  sub    %esi,%edi
  movslq %edi,%rax
  shl    $0x11,%rax
  sub    %esi,%edx
  movslq %edx,%rcx
  cqto
  idiv   %rcx
  sub    $0x10000,%eax
  mov    $0x10000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    $0xffff0000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L57:
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  mov    %eax,%edx
  cmp    %edi,%ecx
  jge    L51
  add    $0x1,%edi
  jmp    L51
L22:
  mov    $0xffff0000,%eax
L9:
  ret
```

assistant: ```c
int joystickb_adjust_analog(int value, int low_limit, int high_limit) {
  int r;
  int a;
  int b;
  int c;
  if (low_limit >= high_limit)
    return 0;
  if (value <= low_limit)
    return -65536;
  if (value >= high_limit)
    return 65536;
  if (-low_limit == high_limit + 1) {
    ++high_limit;
    if (value > high_limit / 2)
      ++value;
  }
  a = value - low_limit;
  b = 65536 * 2;
  c = high_limit - low_limit;
  r = a * (long long)b / c;
  r -= 65536;
  if (r < -65536)
    r = -65536;
  if (r > 65536)
    r = 65536;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<joystickb_adjust_analog>:
  endbr64
  mov    %esi,%ecx
  xor    %eax,%eax
  cmp    %edx,%esi
  jge    L12
  cmp    %edi,%esi
  jge    L36
  mov    $0x10000,%eax
  cmp    %edi,%edx
  jle    L12
  mov    %ecx,%eax
  lea    0x1(%rdx),%esi
  neg    %eax
  cmp    %esi,%eax
  je     L14
L2:
  sub    %ecx,%edi
  sub    %ecx,%edx
  movslq %edi,%rax
  movslq %edx,%rcx
  shl    $0x11,%rax
  cqto
  idiv   %rcx
  mov    $0x10000,%edx
  sub    $0x10000,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    $0xffff0000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L36:
  mov    $0xffff0000,%eax
L12:
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %eax,%esi
  mov    %eax,%edx
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  cmp    %edi,%esi
  setl   %al
  add    %eax,%edi
  jmp    L2
```

assistant: ```c
int joystickb_adjust_analog(int value, int low_limit, int high_limit) {
  int r;
  int a;
  int b;
  int c;
  if (low_limit >= high_limit)
    return 0;
  if (value <= low_limit)
    return -65536;
  if (value >= high_limit)
    return 65536;
  if (-low_limit == high_limit + 1) {
    ++high_limit;
    if (value > high_limit / 2)
      ++value;
  }
  a = value - low_limit;
  b = 65536 * 2;
  c = high_limit - low_limit;
  r = a * (long long)b / c;
  r -= 65536;
  if (r < -65536)
    r = -65536;
  if (r > 65536)
    r = 65536;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<joystickb_adjust_analog>:
  endbr64
  mov    %esi,%ecx
  xor    %eax,%eax
  cmp    %edx,%esi
  jge    L49
  cmp    %edi,%esi
  jge    L27
  mov    $0x10000,%eax
  cmp    %edi,%edx
  jle    L49
  mov    %ecx,%eax
  lea    0x1(%rdx),%esi
  neg    %eax
  cmp    %esi,%eax
  je     L25
L15:
  sub    %ecx,%edi
  sub    %ecx,%edx
  movslq %edi,%rax
  movslq %edx,%rcx
  shl    $0x11,%rax
  cqto
  idiv   %rcx
  mov    $0x10000,%edx
  sub    $0x10000,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    $0xffff0000,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
L27:
  mov    $0xffff0000,%eax
L49:
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %eax,%esi
  mov    %eax,%edx
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  cmp    %edi,%esi
  setl   %al
  add    %eax,%edi
  jmp    L15
```

assistant: ```c
int joystickb_adjust_analog(int value, int low_limit, int high_limit) {
  int r;
  int a;
  int b;
  int c;
  if (low_limit >= high_limit)
    return 0;
  if (value <= low_limit)
    return -65536;
  if (value >= high_limit)
    return 65536;
  if (-low_limit == high_limit + 1) {
    ++high_limit;
    if (value > high_limit / 2)
      ++value;
  }
  a = value - low_limit;
  b = 65536 * 2;
  c = high_limit - low_limit;
  r = a * (long long)b / c;
  r -= 65536;
  if (r < -65536)
    r = -65536;
  if (r > 65536)
    r = 65536;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_log>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D48(%rip),%rdi
  call   <is_file@plt>
  test   %rax,%rax
  je     L15
  lea    D56(%rip),%rsi
  lea    D48(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
L43:
  test   %rbx,%rbx
  je     L8
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <ctime@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %rbp,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  lea    D64(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vfprintf@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  lea    D54(%rip),%rsi
  lea    D48(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  jmp    L43
L8:
  lea    D60(%rip),%rdi
  call   <warning@plt>
  jmp    L42
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D56
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D64
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D54
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D60
type_guessed: string

tool: D48: /var/log/ilenia

tool: D56: a

tool: D64: %s: 

tool: D54: w

tool: D60: Cannot open or create the log file!

assistant: ```c
void do_log(const char *format, ...) {
  FILE *stream;
  va_list ap;
  assert(format != NULL);
  if (is_file("/var/log/ilenia"))
    stream = fopen("/var/log/ilenia", "a");
  else
    stream = fopen("/var/log/ilenia", "w");
  if (stream == NULL) {
    warning("Cannot open or create the log file!");
    return;
  }
  time_t t = time(NULL);
  char *times = ctime(&t);
  *(times + strlen(times) - 1) = 0;
  va_start(ap, format);
  fprintf(stream, "%s: ", times);
  vfprintf(stream, format, ap);
  fprintf(stream, "\n");
  va_end(ap);
  fclose(stream);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_log>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D45(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <is_file@plt>
  test   %rax,%rax
  je     L33
  mov    %rbp,%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rbp,%rbp
  je     L27
L12:
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14d,%edi
  cltq
  movb   $0x0,-0x1(%r13,%rax,1)
  call   <va_start@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  call   <fprintf@plt>
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vfprintf@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %rbp,%rdi
  lea    D17(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rbp,%rbp
  jne    L12
L27:
  lea    D30(%rip),%rdi
  call   <warning@plt>
  jmp    L18
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D45
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D30
data_type: string

tool: D45: /var/log/ilenia

tool: D13: a

tool: D15: %s: 

tool: D17: w

tool: D30: Cannot open or create the log file!

assistant: ```c
void do_log(const char *format, ...) {
  FILE *stream;
  va_list ap;
  assert(format != NULL);
  if (is_file("/var/log/ilenia"))
    stream = fopen("/var/log/ilenia", "a");
  else
    stream = fopen("/var/log/ilenia", "w");
  if (stream == NULL) {
    warning("Cannot open or create the log file!");
    return;
  }
  time_t t = time(NULL);
  char *times = ctime(&t);
  *(times + strlen(times) - 1) = 0;
  va_start(ap, format);
  fprintf(stream, "%s: ", times);
  vfprintf(stream, format, ap);
  fprintf(stream, "\n");
  va_end(ap);
  fclose(stream);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_log>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D25(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <is_file@plt>
  test   %rax,%rax
  je     L3
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rbp,%rbp
  je     L2
L11:
  xor    %edi,%edi
  xor    %r14d,%r14d
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <ctime@plt>
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %r14d,%edi
  cltq
  movb   $0x0,-0x1(%r13,%rax,1)
  call   <va_start@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D17(%rip),%rsi
  call   <fprintf@plt>
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vfprintf@plt>
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rbp,%rbp
  jne    L11
L2:
  lea    D37(%rip),%rdi
  call   <warning@plt>
  jmp    L46
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D37
data_type: string

tool: D25: /var/log/ilenia

tool: D10: a

tool: D17: %s: 

tool: D16: w

tool: D37: Cannot open or create the log file!

assistant: ```c
void do_log(const char *format, ...) {
  FILE *stream;
  va_list ap;
  assert(format != NULL);
  if (is_file("/var/log/ilenia"))
    stream = fopen("/var/log/ilenia", "a");
  else
    stream = fopen("/var/log/ilenia", "w");
  if (stream == NULL) {
    warning("Cannot open or create the log file!");
    return;
  }
  time_t t = time(NULL);
  char *times = ctime(&t);
  *(times + strlen(times) - 1) = 0;
  va_start(ap, format);
  fprintf(stream, "%s: ", times);
  vfprintf(stream, format, ap);
  fprintf(stream, "\n");
  va_end(ap);
  fclose(stream);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quicly_decode64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    $0x30,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    $0x28,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x14,%rax
  mov    (%rax),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x18,%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x20(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t quicly_decode64(const uint8_t **src) {
  uint64_t v = (uint64_t)(*src)[0] << 56 | (uint64_t)(*src)[1] << 48 | (uint64_t)(*src)[2] << 40 | (uint64_t)(*src)[3] << 32 | (uint64_t)(*src)[4] << 24 | (uint64_t)(*src)[5] << 16 | (uint64_t)(*src)[6] << 8 | (*src)[7];
  *src += 8;
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicly_decode64>:
  endbr64
  mov    (%rdi),%rdx
  mov    0x10(%rdx),%eax
  shl    $0x18,%eax
  mov    0x14(%rdx),%ecx
  shl    $0x10,%ecx
  or     %ecx,%eax
  or     0x1c(%rdx),%eax
  mov    0x18(%rdx),%ecx
  shl    $0x8,%ecx
  or     %ecx,%eax
  add    $0x20,%rdx
  mov    %rdx,(%rdi)
  ret
```

assistant: ```c
uint64_t quicly_decode64(const uint8_t **src) {
  uint64_t v = (uint64_t)(*src)[0] << 56 | (uint64_t)(*src)[1] << 48 | (uint64_t)(*src)[2] << 40 | (uint64_t)(*src)[3] << 32 | (uint64_t)(*src)[4] << 24 | (uint64_t)(*src)[5] << 16 | (uint64_t)(*src)[6] << 8 | (*src)[7];
  *src += 8;
  return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quicly_decode64>:
  endbr64
  mov    (%rdi),%rdx
  mov    0x10(%rdx),%eax
  mov    0x14(%rdx),%ecx
  add    $0x20,%rdx
  shl    $0x10,%ecx
  shl    $0x18,%eax
  or     %ecx,%eax
  mov    -0x8(%rdx),%ecx
  or     -0x4(%rdx),%eax
  mov    %rdx,(%rdi)
  shl    $0x8,%ecx
  or     %ecx,%eax
  ret
```

assistant: ```c
uint64_t quicly_decode64(const uint8_t **src) {
  uint64_t v = (uint64_t)(*src)[0] << 56 | (uint64_t)(*src)[1] << 48 | (uint64_t)(*src)[2] << 40 | (uint64_t)(*src)[3] << 32 | (uint64_t)(*src)[4] << 24 | (uint64_t)(*src)[5] << 16 | (uint64_t)(*src)[6] << 8 | (*src)[7];
  *src += 8;
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<quicly_decode64>:
  endbr64
  mov    (%rdi),%rdx
  mov    0x10(%rdx),%eax
  mov    0x14(%rdx),%ecx
  add    $0x20,%rdx
  shl    $0x10,%ecx
  shl    $0x18,%eax
  or     %ecx,%eax
  mov    -0x8(%rdx),%ecx
  or     -0x4(%rdx),%eax
  mov    %rdx,(%rdi)
  shl    $0x8,%ecx
  or     %ecx,%eax
  ret
```

assistant: ```c
uint64_t quicly_decode64(const uint8_t **src) {
  uint64_t v = (uint64_t)(*src)[0] << 56 | (uint64_t)(*src)[1] << 48 | (uint64_t)(*src)[2] << 40 | (uint64_t)(*src)[3] << 32 | (uint64_t)(*src)[4] << 24 | (uint64_t)(*src)[5] << 16 | (uint64_t)(*src)[6] << 8 | (*src)[7];
  *src += 8;
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x14(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L29
L0:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L29:
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  js     L0
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L4
L62:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L24
  mov    $0x30,%eax
  jmp    L63
L24:
  mov    $0x31,%eax
L63:
  mov    %al,-0x1d(%rbp)
  movsbl -0x1d(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L4:
  cmpl   $0x30,-0x18(%rbp)
  jne    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D37
datatype: string

tool: D5: give a number


tool: D28: %i

tool: D37: lathos! give a number


assistant: ```c
int main() {
  const int div_num = 2;
  int n, n2;
  int piliko, ypoloipo;
  char ypol_char;
  printf("give a number\n");
  scanf("%i", &n);
  while (n < 0) {
    printf("lathos! give a number\n");
    scanf("%i", &n);
  }
  n2 = n;
  while (n2 != '0') {
    piliko = n2 / div_num;
    ypoloipo = n2 % div_num;
    ypol_char = (ypoloipo == 0 ? '0' : '1');
    putchar(ypol_char);
    n2 = piliko;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  jns    L1
  lea    D39(%rip),%r13
  lea    0x4(%rsp),%r12
  lea    D7(%rip),%rbx
L47:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  test   %ebp,%ebp
  js     L47
L1:
  cmp    $0x30,%ebp
  je     L36
L45:
  mov    %ebp,%eax
  mov    %ebp,%ebx
  shr    $0x1f,%ebx
  add    %ebp,%ebx
  sar    %ebx
  mov    %ebx,%ebp
  and    $0x1,%eax
  lea    0x30(%rax),%edi
  call   <putchar@plt>
  cmp    $0x30,%ebx
  jne    L45
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string

tool: D26: give a number


tool: D7: %i

tool: D39: lathos! give a number


assistant: ```c
int main() {
  const int div_num = 2;
  int n, n2;
  int piliko, ypoloipo;
  char ypol_char;
  printf("give a number\n");
  scanf("%i", &n);
  while (n < 0) {
    printf("lathos! give a number\n");
    scanf("%i", &n);
  }
  n2 = n;
  while (n2 != '0') {
    piliko = n2 / div_num;
    ypoloipo = n2 % div_num;
    ypol_char = (ypoloipo == 0 ? '0' : '1');
    putchar(ypol_char);
    n2 = piliko;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jns    L0
  lea    D23(%rip),%r13
L33:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  js     L33
  cmp    $0x30,%ebx
  je     L40
L16:
  mov    %ebx,%edi
  sar    %ebx
  and    $0x1,%edi
  add    $0x30,%edi
  call   <putchar@plt>
L0:
  cmp    $0x30,%ebx
  jne    L16
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D23
data_type: string

tool: D24: give a number


tool: D3: %i

tool: D23: lathos! give a number


assistant: ```c
int main() {
  const int div_num = 2;
  int n, n2;
  int piliko, ypoloipo;
  char ypol_char;
  printf("give a number\n");
  scanf("%i", &n);
  while (n < 0) {
    printf("lathos! give a number\n");
    scanf("%i", &n);
  }
  n2 = n;
  while (n2 != '0') {
    piliko = n2 / div_num;
    ypoloipo = n2 % div_num;
    ypol_char = (ypoloipo == 0 ? '0' : '1');
    putchar(ypol_char);
    n2 = piliko;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%rdi
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jns    L46
  lea    D2(%rip),%r13
L33:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  js     L33
  cmp    $0x30,%ebx
  je     L32
L29:
  mov    %ebx,%edi
  sar    %ebx
  and    $0x1,%edi
  add    $0x30,%edi
  call   <putchar@plt>
L46:
  cmp    $0x30,%ebx
  jne    L29
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D5: give a number


tool: D10: %i

tool: D2: lathos! give a number


assistant: ```c
int main() {
  const int div_num = 2;
  int n, n2;
  int piliko, ypoloipo;
  char ypol_char;
  printf("give a number\n");
  scanf("%i", &n);
  while (n < 0) {
    printf("lathos! give a number\n");
    scanf("%i", &n);
  }
  n2 = n;
  while (n2 != '0') {
    piliko = n2 / div_num;
    ypoloipo = n2 % div_num;
    ypol_char = (ypoloipo == 0 ? '0' : '1');
    putchar(ypol_char);
    n2 = piliko;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<average_block_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L11
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <total_block_size@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <count_blocks@plt>
  lea    0x1(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x14(%rbp)
  jmp    L1
L11:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <total_block_size@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <count_blocks@plt>
  lea    0x1(%rax),%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int average_block_size(const int *mem, int avg_allocs) {
  int average = 0;
  if (avg_allocs) {
    average = total_block_size(mem, 1) / (count_blocks(mem, 1) + 1);
  } else {
    average = total_block_size(mem, 0) / (count_blocks(mem, 0) + 1);
  }
  return average;
}
```