ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_form>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  mov    $0x1,%edx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L14
  movzbl (%rbx),%r14d
  cmp    %r13d,%r14d
  jl     L0
L14:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <read@plt>
  cmp    %r14d,%eax
  jne    L14
  cltq
  movb   $0x0,(%rbx,%rax,1)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int read_form(int fd, char *buf, int max_size) {
  int length;
  if (read(fd, buf, 1) != 1) {
    return 0;
  }
  length = (int)((unsigned)buf[0] & 0xff);
  if (length > max_size - 1) {
    return 0;
  }
  if (read(fd, buf, length) != length) {
    return 0;
  }
  buf[length] = '\0';
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getopt_long_test@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  getopt_long_test(argc, argv);
  exit(EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <getopt_long_test@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  getopt_long_test(argc, argv);
  exit(EXIT_SUCCESS);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <getopt_long_test@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  getopt_long_test(argc, argv);
  exit(EXIT_SUCCESS);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <getopt_long_test@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  getopt_long_test(argc, argv);
  exit(EXIT_SUCCESS);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L12:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  nop
  pop    %rbp
  ret
```

assistant: ```c
memcpy(unsigned char *dbuf, unsigned char *sbuf, int len) {
  int ii;
  for (ii = 0; ii < len; ii++) {
    *dbuf = *sbuf;
    dbuf++;
    sbuf++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L5
  mov    %edx,%edx
  mov    $0x0,%eax
L19:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
L5:
  ret
```

assistant: ```c
memcpy(unsigned char *dbuf, unsigned char *sbuf, int len) {
  int ii;
  for (ii = 0; ii < len; ii++) {
    *dbuf = *sbuf;
    dbuf++;
    sbuf++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L15:
  ret
```

assistant: ```c
memcpy(unsigned char *dbuf, unsigned char *sbuf, int len) {
  int ii;
  for (ii = 0; ii < len; ii++) {
    *dbuf = *sbuf;
    dbuf++;
    sbuf++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L61
  lea    0x1(%rsi),%r9
  mov    %rcx,%r8
  lea    -0x1(%rdx),%eax
  mov    %edx,%edi
  sub    %r9,%r8
  cmp    $0xe,%r8
  jbe    L112
  cmp    $0x6,%eax
  jbe    L112
  cmp    $0xe,%eax
  jbe    L89
  shr    $0x4,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L133:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L133
  mov    %edx,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r8d
  lea    (%rcx,%r8,1),%r9
  lea    (%rsi,%r8,1),%r10
  cmp    %eax,%edx
  je     L61
  mov    %edx,%edi
  sub    %eax,%edi
  lea    -0x1(%rdi),%r11d
  cmp    $0x6,%r11d
  jbe    L12
L143:
  mov    (%rsi,%r8,1),%rsi
  mov    %rsi,(%rcx,%r8,1)
  mov    %edi,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%esi
  add    %ecx,%eax
  add    %rsi,%r9
  add    %rsi,%r10
  cmp    %ecx,%edi
  je     L61
L12:
  movzbl (%r10),%ecx
  mov    %cl,(%r9)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L61
  movzbl 0x1(%r10),%ecx
  mov    %cl,0x1(%r9)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L61
  movzbl 0x2(%r10),%ecx
  mov    %cl,0x2(%r9)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L61
  movzbl 0x3(%r10),%ecx
  mov    %cl,0x3(%r9)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L61
  movzbl 0x4(%r10),%ecx
  mov    %cl,0x4(%r9)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L61
  movzbl 0x5(%r10),%ecx
  add    $0x6,%eax
  mov    %cl,0x5(%r9)
  cmp    %eax,%edx
  jle    L61
  movzbl 0x6(%r10),%eax
  mov    %al,0x6(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L112:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L86:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L86
L61:
  ret
L89:
  mov    %rsi,%r10
  mov    %rcx,%r9
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L143
```

assistant: ```c
memcpy(unsigned char *dbuf, unsigned char *sbuf, int len) {
  int ii;
  for (ii = 0; ii < len; ii++) {
    *dbuf = *sbuf;
    dbuf++;
    sbuf++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x216f6c6c6548,%rax
  mov    $0x0,%edx
  mov    %rax,-0xe0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movl   $0x0,-0x80(%rbp)
  movabs $0x21657962646f6f47,%rax
  mov    $0x0,%edx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <test@plt>
  mov    %rax,-0xe8(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D48
type_infered: string
name: read_data
arguments: tag: D65
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D48: Control:

tool: D65: 	%s


tool: D16: Test:

assistant: ```c
int main(void) {
  char a[100] = "Hello!";
  char b[100] = "Goodbye!";
  char *c;
  printf("Control:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  c = test(b);
  printf("Test:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  printf("\t%s\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movabs $0x216f6c6c6548,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  movabs $0x21657962646f6f47,%rax
  mov    $0x0,%edx
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x0,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movl   $0x0,0xd0(%rsp)
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%r13
  mov    %r13,%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x70(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <test@plt>
  mov    %rax,%rbp
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D27
type: string

tool: D22: Control:

tool: D23: 	%s


tool: D27: Test:

assistant: ```c
int main(void) {
  char a[100] = "Hello!";
  char b[100] = "Goodbye!";
  char *c;
  printf("Control:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  c = test(b);
  printf("Test:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  printf("\t%s\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edx,%edx
  pxor   %xmm0,%xmm0
  lea    D5(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  movabs $0x216f6c6c6548,%rax
  mov    %rsp,%r14
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %rdx,0x78(%rsp)
  lea    0x70(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  mov    %rax,(%rsp)
  movabs $0x21657962646f6f47,%rax
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rax,0x70(%rsp)
  movl   $0x0,0xd0(%rsp)
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <test@plt>
  lea    D18(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: string

tool: D5: Control:

tool: D12: 	%s


tool: D18: Test:

assistant: ```c
int main(void) {
  char a[100] = "Hello!";
  char b[100] = "Goodbye!";
  char *c;
  printf("Control:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  c = test(b);
  printf("Test:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  printf("\t%s\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edx,%edx
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  movabs $0x216f6c6c6548,%rax
  mov    %rsp,%r14
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %rdx,0x78(%rsp)
  lea    0x70(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  mov    %rax,(%rsp)
  movabs $0x21657962646f6f47,%rax
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rax,0x70(%rsp)
  movl   $0x0,0xd0(%rsp)
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <test@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D16: Control:

tool: D18: 	%s


tool: D2: Test:

assistant: ```c
int main(void) {
  char a[100] = "Hello!";
  char b[100] = "Goodbye!";
  char *c;
  printf("Control:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  c = test(b);
  printf("Test:\n");
  printf("\t%s\n", a);
  printf("\t%s\n", b);
  printf("\t%s\n", c);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespecSubtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jl     L29
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jl     L17
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  jmp    L14
L17:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L49
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x3b9aca00(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  jmp    L14
L49:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   $0x0,0x8(%rax)
  jmp    L14
L29:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   $0x0,0x8(%rax)
L14:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void timespecSubtract(const struct timespec *time1, const struct timespec *time2, struct timespec *delta) {
  if (time1->tv_sec >= time2->tv_sec) {
    if (time1->tv_nsec >= time2->tv_nsec) {
      delta->tv_sec = time1->tv_sec - time2->tv_sec;
      delta->tv_nsec = time1->tv_nsec - time2->tv_nsec;
    } else {
      if (time1->tv_sec > time2->tv_sec) {
        delta->tv_sec = time1->tv_sec - time2->tv_sec - 1;
        delta->tv_nsec = 1000000000L + time1->tv_nsec - time2->tv_nsec;
      } else {
        delta->tv_sec = 0;
        delta->tv_nsec = 0;
      }
    }
  } else {
    delta->tv_sec = 0;
    delta->tv_nsec = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<timespecSubtract>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rcx
  cmp    %rcx,%rax
  jl     L7
  mov    0x8(%rsi),%r8
  cmp    %r8,0x8(%rdi)
  jl     L54
  sub    %rcx,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rdi),%rax
  sub    0x8(%rsi),%rax
  jmp    L0
L54:
  cmp    %rcx,%rax
  jle    L12
  sub    %rcx,%rax
  sub    $0x1,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rdi),%rax
  add    $0x3b9aca00,%rax
  sub    0x8(%rsi),%rax
  jmp    L0
L12:
  movq   $0x0,(%rdx)
  mov    $0x0,%eax
  jmp    L0
L7:
  movq   $0x0,(%rdx)
  mov    $0x0,%eax
L0:
  mov    %rax,0x8(%rdx)
  ret
```

assistant: ```c
void timespecSubtract(const struct timespec *time1, const struct timespec *time2, struct timespec *delta) {
  if (time1->tv_sec >= time2->tv_sec) {
    if (time1->tv_nsec >= time2->tv_nsec) {
      delta->tv_sec = time1->tv_sec - time2->tv_sec;
      delta->tv_nsec = time1->tv_nsec - time2->tv_nsec;
    } else {
      if (time1->tv_sec > time2->tv_sec) {
        delta->tv_sec = time1->tv_sec - time2->tv_sec - 1;
        delta->tv_nsec = 1000000000L + time1->tv_nsec - time2->tv_nsec;
      } else {
        delta->tv_sec = 0;
        delta->tv_nsec = 0;
      }
    }
  } else {
    delta->tv_sec = 0;
    delta->tv_nsec = 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<timespecSubtract>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%r8
  cmp    %r8,%rax
  jl     L7
  mov    0x8(%rdi),%rcx
  mov    0x8(%rsi),%rsi
  cmp    %rsi,%rcx
  jl     L26
  sub    %r8,%rax
  sub    %rsi,%rcx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  cmp    %r8,%rax
  jg     L0
L7:
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
  nopl   0x0(%rax)
L0:
  sub    %r8,%rax
  add    $0x3b9aca00,%rcx
  sub    $0x1,%rax
  sub    %rsi,%rcx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
```

assistant: ```c
void timespecSubtract(const struct timespec *time1, const struct timespec *time2, struct timespec *delta) {
  if (time1->tv_sec >= time2->tv_sec) {
    if (time1->tv_nsec >= time2->tv_nsec) {
      delta->tv_sec = time1->tv_sec - time2->tv_sec;
      delta->tv_nsec = time1->tv_nsec - time2->tv_nsec;
    } else {
      if (time1->tv_sec > time2->tv_sec) {
        delta->tv_sec = time1->tv_sec - time2->tv_sec - 1;
        delta->tv_nsec = 1000000000L + time1->tv_nsec - time2->tv_nsec;
      } else {
        delta->tv_sec = 0;
        delta->tv_nsec = 0;
      }
    }
  } else {
    delta->tv_sec = 0;
    delta->tv_nsec = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<timespecSubtract>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%r8
  cmp    %r8,%rax
  jl     L3
  mov    0x8(%rdi),%rcx
  mov    0x8(%rsi),%rsi
  cmp    %rsi,%rcx
  jl     L2
  sub    %r8,%rax
  sub    %rsi,%rcx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  cmp    %r8,%rax
  jg     L0
L3:
  xor    %eax,%eax
  xor    %ecx,%ecx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
  nopl   0x0(%rax)
L0:
  sub    %r8,%rax
  add    $0x3b9aca00,%rcx
  sub    $0x1,%rax
  sub    %rsi,%rcx
  mov    %rax,(%rdx)
  mov    %rcx,0x8(%rdx)
  ret
```

assistant: ```c
void timespecSubtract(const struct timespec *time1, const struct timespec *time2, struct timespec *delta) {
  if (time1->tv_sec >= time2->tv_sec) {
    if (time1->tv_nsec >= time2->tv_nsec) {
      delta->tv_sec = time1->tv_sec - time2->tv_sec;
      delta->tv_nsec = time1->tv_nsec - time2->tv_nsec;
    } else {
      if (time1->tv_sec > time2->tv_sec) {
        delta->tv_sec = time1->tv_sec - time2->tv_sec - 1;
        delta->tv_nsec = 1000000000L + time1->tv_nsec - time2->tv_nsec;
      } else {
        delta->tv_sec = 0;
        delta->tv_nsec = 0;
      }
    }
  } else {
    delta->tv_sec = 0;
    delta->tv_nsec = 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashdjb2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x1505,-0x10(%rbp)
  jmp    L0
L13:
  mov    -0x10(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hashdjb2(const void *key) {
  const char *ptr = key;
  int c;
  unsigned hash = 5381;
  while ((c = *ptr++))
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hashdjb2>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L8
  mov    $0x1505,%eax
L5:
  mov    %eax,%esi
  shl    $0x5,%esi
  add    %esi,%eax
  movsbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L5
  ret
L8:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned hashdjb2(const void *key) {
  const char *ptr = key;
  int c;
  unsigned hash = 5381;
  while ((c = *ptr++))
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashdjb2>:
  endbr64
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L0
  nopl   0x0(%rax)
L2:
  mov    %eax,%esi
  add    $0x1,%rcx
  shl    $0x5,%esi
  add    %esi,%eax
  add    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L2
  ret
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
unsigned hashdjb2(const void *key) {
  const char *ptr = key;
  int c;
  unsigned hash = 5381;
  while ((c = *ptr++))
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hashdjb2>:
  endbr64
  movsbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L16
  nopl   0x0(%rax)
L2:
  mov    %eax,%esi
  add    $0x1,%rcx
  shl    $0x5,%esi
  add    %esi,%eax
  add    %edx,%eax
  movsbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L2
  ret
  xchg   %ax,%ax
L16:
  ret
```

assistant: ```c
unsigned hashdjb2(const void *key) {
  const char *ptr = key;
  int c;
  unsigned hash = 5381;
  while ((c = *ptr++))
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```