ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int strcpy(char *dst, char *src) {
  int n = strlen(src);
  for (int i = 0; i < n; i++) {
    dst[i] = src[i];
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  mov    %eax,%eax
  mov    $0x0,%edx
L5:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L5
L9:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strcpy(char *dst, char *src) {
  int n = strlen(src);
  for (int i = 0; i < n; i++) {
    dst[i] = src[i];
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L10
  cltq
  xor    %edx,%edx
L3:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,0x0(%rbp,%rdx,1)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L3
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int strcpy(char *dst, char *src) {
  int n = strlen(src);
  for (int i = 0; i < n; i++) {
    dst[i] = src[i];
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edx
  test   %edx,%edx
  jle    L4
  lea    0x1(%rbx),%rdi
  mov    %rbp,%rcx
  lea    -0x1(%rdx),%eax
  mov    %edx,%esi
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L38
  cmp    $0x6,%eax
  jbe    L38
  cmp    $0xe,%eax
  jbe    L14
  mov    %edx,%ecx
  xor    %eax,%eax
  shr    $0x4,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L15:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,0x0(%rbp,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L15
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  je     L4
  mov    %edx,%esi
  sub    %ecx,%esi
  lea    -0x1(%rsi),%edi
  cmp    $0x6,%edi
  jbe    L20
L61:
  mov    (%rbx,%rcx,1),%rdi
  mov    %rdi,0x0(%rbp,%rcx,1)
  mov    %esi,%ecx
  and    $0xfffffff8,%ecx
  add    %ecx,%eax
  cmp    %ecx,%esi
  je     L4
L20:
  movslq %eax,%rcx
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x2(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x3(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  movslq %ecx,%rcx
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  lea    0x5(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  movslq %ecx,%rcx
  add    $0x6,%eax
  movzbl (%rbx,%rcx,1),%esi
  mov    %sil,0x0(%rbp,%rcx,1)
  cmp    %eax,%edx
  jle    L4
  cltq
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rbx,%rax,1),%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L61
```

assistant: ```c
int strcpy(char *dst, char *src) {
  int n = strlen(src);
  for (int i = 0; i < n; i++) {
    dst[i] = src[i];
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<safe_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L19
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L8
L19:
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
size_t safe_read(int fd, void *buf, size_t count) {
  int r;
  do {
    r = read(fd, buf, count);
  } while (r == -1 && errno == EINTR);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<safe_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
L13:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L16
  mov    D8(%rip),%rcx
  mov    D9(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L13
L16:
  cltq
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t safe_read(int fd, void *buf, size_t count) {
  int r;
  do {
    r = read(fd, buf, count);
  } while (r == -1 && errno == EINTR);
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<safe_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L2:
  mov    D9(%rip),%rax
  mov    D12(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L17
L1:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L2
  pop    %rbx
  cltq
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  pop    %rbx
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t safe_read(int fd, void *buf, size_t count) {
  int r;
  do {
    r = read(fd, buf, count);
  } while (r == -1 && errno == EINTR);
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<safe_read>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L7:
  mov    D11(%rip),%rax
  mov    D18(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L13
L4:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L7
  pop    %rbx
  cltq
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  pop    %rbx
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t safe_read(int fd, void *buf, size_t count) {
  int r;
  do {
    r = read(fd, buf, count);
  } while (r == -1 && errno == EINTR);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sky_gps_endian_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void sky_gps_endian_swap(struct gps_t *p) {
  assert(p != NULL);
  ;
  ;
  ;
  ;
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sky_gps_endian_swap>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sky_gps_endian_swap(struct gps_t *p) {
  assert(p != NULL);
  ;
  ;
  ;
  ;
  ;
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sky_gps_endian_swap>:
  endbr64
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void sky_gps_endian_swap(struct gps_t *p) {
  assert(p != NULL);
  ;
  ;
  ;
  ;
  ;
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sky_gps_endian_swap>:
  endbr64
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void sky_gps_endian_swap(struct gps_t *p) {
  assert(p != NULL);
  ;
  ;
  ;
  ;
  ;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shell_prompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x118(%rbp)
  movb   $0x0,-0x110(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <io_printf@plt>
  movl   $0x0,-0x114(%rbp)
  jmp    L69
L58:
  mov    $0x0,%eax
  call   <keyboard_get_pointer@plt>
  test   %rax,%rax
  jle    L69
  mov    $0x0,%eax
  call   <keyboard_pull@plt>
  mov    %al,-0x119(%rbp)
  cmpb   $0x8,-0x119(%rbp)
  jne    L15
  mov    -0x118(%rbp),%eax
  test   %eax,%eax
  jle    L69
  movsbl -0x119(%rbp),%eax
  mov    %eax,%edi
  call   <io_put_char@plt>
  lea    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <shell_remove_from_buffer@plt>
  jmp    L69
L15:
  mov    -0x118(%rbp),%eax
  cmp    $0xfe,%eax
  jg     L55
  movsbl -0x119(%rbp),%eax
  mov    %eax,%edi
  call   <io_put_char@plt>
  movsbl -0x119(%rbp),%edx
  lea    -0x118(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  je     L69
  movl   $0x1,-0x114(%rbp)
  jmp    L69
L55:
  cmpb   $0xa,-0x119(%rbp)
  jne    L116
  movsbl -0x119(%rbp),%eax
  mov    %eax,%edi
  call   <io_put_char@plt>
L116:
  movsbl -0x119(%rbp),%edx
  lea    -0x118(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  je     L69
  movl   $0x1,-0x114(%rbp)
L69:
  cmpl   $0x0,-0x114(%rbp)
  je     L58
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: $>

assistant: ```c
void shell_prompt() {
  char command[256];
  memset(command, 0, 256);
  int command_index = 0;
  command[0] = '\0';
  io_printf("$>");
  int processed = 0;
  while (!processed) {
    if (keyboard_get_pointer() > 0) {
      char keyPress = keyboard_pull();
      if (keyPress == '\b') {
        if (command_index > 0) {
          io_put_char(keyPress);
          shell_remove_from_buffer(command, &command_index);
        }
      } else if (command_index < 255) {
        io_put_char(keyPress);
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      } else {
        if (keyPress == '\n') {
          io_put_char(keyPress);
        }
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shell_prompt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x100,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movl   $0x0,0xc(%rsp)
  movb   $0x0,0x10(%rsp)
  lea    D1(%rip),%rdi
  call   <io_printf@plt>
  lea    0xc(%rsp),%rbp
  jmp    L75
L36:
  cmpl   $0x0,0xc(%rsp)
  jle    L75
  mov    $0x8,%edi
  call   <io_put_char@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <shell_remove_from_buffer@plt>
  jmp    L75
L86:
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <io_put_char@plt>
  lea    0x10(%rsp),%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  je     L75
L91:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  movsbl %bl,%edx
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  jne    L91
L75:
  mov    $0x0,%eax
  call   <keyboard_get_pointer@plt>
  test   %rax,%rax
  jle    L75
  mov    $0x0,%eax
  call   <keyboard_pull@plt>
  mov    %eax,%ebx
  cmp    $0x8,%al
  je     L36
  cmpl   $0xfe,0xc(%rsp)
  jle    L86
  cmp    $0xa,%al
  jne    L25
  mov    $0xa,%edi
  call   <io_put_char@plt>
  jmp    L25
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: $>

assistant: ```c
void shell_prompt() {
  char command[256];
  memset(command, 0, 256);
  int command_index = 0;
  command[0] = '\0';
  io_printf("$>");
  int processed = 0;
  while (!processed) {
    if (keyboard_get_pointer() > 0) {
      char keyPress = keyboard_pull();
      if (keyPress == '\b') {
        if (command_index > 0) {
          io_put_char(keyPress);
          shell_remove_from_buffer(command, &command_index);
        }
      } else if (command_index < 255) {
        io_put_char(keyPress);
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      } else {
        if (keyPress == '\n') {
          io_put_char(keyPress);
        }
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shell_prompt>:
  endbr64
  push   %r12
  mov    $0x100,%edx
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    D4(%rip),%rdi
  movb   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <io_printf@plt>
  nopl   0x0(%rax)
L47:
  xor    %eax,%eax
  call   <keyboard_get_pointer@plt>
  test   %rax,%rax
  jle    L47
  xor    %eax,%eax
  call   <keyboard_pull@plt>
  cmp    $0x8,%al
  je     L81
  movsbl %al,%r12d
  cmpl   $0xfe,0xc(%rsp)
  mov    %r12d,%edi
  jle    L60
  cmp    $0xa,%al
  je     L57
L64:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  je     L47
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L47
  mov    $0x8,%edi
  call   <io_put_char@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <shell_remove_from_buffer@plt>
  jmp    L47
L57:
  mov    $0xa,%edi
L60:
  call   <io_put_char@plt>
  jmp    L64
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: $>

assistant: ```c
void shell_prompt() {
  char command[256];
  memset(command, 0, 256);
  int command_index = 0;
  command[0] = '\0';
  io_printf("$>");
  int processed = 0;
  while (!processed) {
    if (keyboard_get_pointer() > 0) {
      char keyPress = keyboard_pull();
      if (keyPress == '\b') {
        if (command_index > 0) {
          io_put_char(keyPress);
          shell_remove_from_buffer(command, &command_index);
        }
      } else if (command_index < 255) {
        io_put_char(keyPress);
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      } else {
        if (keyPress == '\n') {
          io_put_char(keyPress);
        }
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shell_prompt>:
  endbr64
  push   %r12
  mov    $0x100,%edx
  xor    %esi,%esi
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%rbp
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    D6(%rip),%rdi
  movb   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <io_printf@plt>
  nopl   0x0(%rax)
L75:
  xor    %eax,%eax
  call   <keyboard_get_pointer@plt>
  test   %rax,%rax
  jle    L75
  xor    %eax,%eax
  call   <keyboard_pull@plt>
  cmp    $0x8,%al
  je     L8
  movsbl %al,%r12d
  cmpl   $0xfe,0xc(%rsp)
  mov    %r12d,%edi
  jle    L12
  cmp    $0xa,%al
  je     L52
L70:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <shell_update_buffer@plt>
  test   %rax,%rax
  je     L75
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L75
  mov    $0x8,%edi
  call   <io_put_char@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <shell_remove_from_buffer@plt>
  jmp    L75
L52:
  mov    $0xa,%edi
L12:
  call   <io_put_char@plt>
  jmp    L70
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: $>

assistant: ```c
void shell_prompt() {
  char command[256];
  memset(command, 0, 256);
  int command_index = 0;
  command[0] = '\0';
  io_printf("$>");
  int processed = 0;
  while (!processed) {
    if (keyboard_get_pointer() > 0) {
      char keyPress = keyboard_pull();
      if (keyPress == '\b') {
        if (command_index > 0) {
          io_put_char(keyPress);
          shell_remove_from_buffer(command, &command_index);
        }
      } else if (command_index < 255) {
        io_put_char(keyPress);
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      } else {
        if (keyPress == '\n') {
          io_put_char(keyPress);
        }
        if (shell_update_buffer(command, &command_index, keyPress)) {
          processed = 1;
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ToBinary8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L18:
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  mov    %eax,-0xc(%rbp)
  shll   -0x14(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L9
  mov    -0x8(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L22
L9:
  mov    -0x8(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L22:
  addl   $0x1,-0x10(%rbp)
L3:
  cmpl   $0x7,-0x10(%rbp)
  jle    L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
datatype: string
name: unpack_data
arguments: data_label: D22
datatype: string

tool: D23: 0

tool: D22: 1

assistant: ```c
char *ToBinary8(int nombreNatif) {
  static char buffer[1 + sizeof(int) * 8] = {0};
  char *BinaryChar8 = buffer - 1 + sizeof(int) * 8;
  *BinaryChar8 = 0;
  int iBit;
  for (iBit = 0; iBit < 8; iBit++) {
    int valeurBit = nombreNatif & 0x80;
    nombreNatif <<= 1;
    if (valeurBit == 0)
      strcat(BinaryChar8, "0");
    else
      strcat(BinaryChar8, "1");
  }
  return BinaryChar8;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ToBinary8>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  movb   $0x0,D0(%rip)
  mov    $0x8,%ebp
  lea    D17(%rip),%r14
  lea    D0(%rip),%r12
  lea    D2(%rip),%r13
  jmp    L12
L2:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L20:
  sub    $0x1,%ebp
  je     L1
L12:
  mov    %ebx,%eax
  and    $0x80,%eax
  add    %ebx,%ebx
  test   %eax,%eax
  jne    L2
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L20
L1:
  lea    D0(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D17: 1

tool: D2: 0

assistant: ```c
char *ToBinary8(int nombreNatif) {
  static char buffer[1 + sizeof(int) * 8] = {0};
  char *BinaryChar8 = buffer - 1 + sizeof(int) * 8;
  *BinaryChar8 = 0;
  int iBit;
  for (iBit = 0; iBit < 8; iBit++) {
    int valeurBit = nombreNatif & 0x80;
    nombreNatif <<= 1;
    if (valeurBit == 0)
      strcat(BinaryChar8, "0");
    else
      strcat(BinaryChar8, "1");
  }
  return BinaryChar8;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ToBinary8>:
  endbr64
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  movb   $0x0,D9(%rip)
  jmp    L13
  nopl   0x0(%rax)
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  je     L4
L13:
  mov    %ebx,%eax
  add    %ebx,%ebx
  and    $0x80,%eax
  test   %eax,%eax
  je     L6
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  jne    L13
L4:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D21: 1

tool: D2: 0

assistant: ```c
char *ToBinary8(int nombreNatif) {
  static char buffer[1 + sizeof(int) * 8] = {0};
  char *BinaryChar8 = buffer - 1 + sizeof(int) * 8;
  *BinaryChar8 = 0;
  int iBit;
  for (iBit = 0; iBit < 8; iBit++) {
    int valeurBit = nombreNatif & 0x80;
    nombreNatif <<= 1;
    if (valeurBit == 0)
      strcat(BinaryChar8, "0");
    else
      strcat(BinaryChar8, "1");
  }
  return BinaryChar8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ToBinary8>:
  endbr64
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %edi,%ebx
  movb   $0x0,D35(%rip)
  jmp    L15
  nopl   0x0(%rax)
L36:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  je     L23
L15:
  mov    %ebx,%eax
  add    %ebx,%ebx
  and    $0x80,%eax
  test   %eax,%eax
  je     L36
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  sub    $0x1,%ebp
  jne    L15
L23:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string

tool: D17: 1

tool: D16: 0

assistant: ```c
char *ToBinary8(int nombreNatif) {
  static char buffer[1 + sizeof(int) * 8] = {0};
  char *BinaryChar8 = buffer - 1 + sizeof(int) * 8;
  *BinaryChar8 = 0;
  int iBit;
  for (iBit = 0; iBit < 8; iBit++) {
    int valeurBit = nombreNatif & 0x80;
    nombreNatif <<= 1;
    if (valeurBit == 0)
      strcat(BinaryChar8, "0");
    else
      strcat(BinaryChar8, "1");
  }
  return BinaryChar8;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isHexadecimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x36,%eax
  seta   %dl
  test   %dl,%dl
  jne    L16
  movabs $0x7e0000007e03ff,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L16
  mov    $0x1,%eax
  jmp    L29
L16:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int isHexadecimal(int c) {
  switch (c) {
  case '0' ... '9':
  case 'A' ... 'F':
  case 'a' ... 'f':
    return 1;
  }
  return 0;
}
```