ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<array_roll2d_y_s>:
  endbr64
  push   %r12
  mov    %rdi,%r11
  xor    %r8d,%r8d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rdx,%rbp
  xor    %edx,%edx
  push   %rbx
  lea    0x0(,%rsi,8),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %rcx,%rax
  div    %rsi
  lea    (%rdx,%rsi,1),%rax
  xor    %edx,%edx
  div    %rsi
  lea    0x1(%rsi,%rdx,1),%r12
  mov    %rdx,%r9
  and    $0x1,%r12d
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rsi
  mov    %r8,%rdx
  xor    %r10d,%r10d
  test   %r11,%r11
  je     L19
  xchg   %ax,%ax
L5:
  movsd  (%rsi,%rdx,8),%xmm0
  xor    %ecx,%ecx
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L48:
  lea    (%rdx,%r9,1),%rax
  xor    %edx,%edx
  div    %rdi
  mov    %rcx,%rax
  add    $0x1,%rcx
  and    $0x1,%eax
  movsd  (%rsi,%rdx,8),%xmm0
  movsd  %xmm0,(%rsp,%rax,8)
  mov    %rcx,%rax
  and    $0x1,%eax
  movsd  (%rsp,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rdx,8)
  cmp    %rdx,%r8
  jne    L48
  add    $0x1,%r10
  add    %rbx,%rsi
  cmp    %r10,%r11
  jne    L5
L19:
  cmp    $0x1,%r8
  mov    $0x1,%r8d
  sbb    %rax,%rax
  add    $0x2,%rax
  cmp    %r12,%rax
  je     L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void array_roll2d_y_s(size_t size0, size_t size1, double array[size0][size1], ssize_t shift) {
  ssize_t shift_y = (size1 + shift % size1) % size1;
  size_t y_init = 0;
  double tmp[2];
  do {
    size_t y1, y0 = y_init;
    for (size_t x = 0; x < size0; x++) {
      size_t i = 0;
      tmp[1] = array[x][y0];
      do {
        y1 = (y0 + shift_y) % size1;
        tmp[i % 2] = array[x][y1];
        array[x][y1] = tmp[(i + 1) % 2];
        i++;
      } while ((y0 = y1) != y_init);
    }
  } while (++y_init == (size1 + shift_y + 1) % 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<array_roll2d_y_s>:
  endbr64
  push   %r12
  mov    %rdi,%r11
  push   %rbp
  mov    %rdx,%rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    %rcx,%rax
  div    %rsi
  lea    (%rdx,%rsi,1),%rax
  xor    %edx,%edx
  div    %rsi
  lea    0x1(%rsi,%rdx,1),%r12
  and    $0x1,%r12d
  test   %rdi,%rdi
  je     L32
  mov    %rsi,%rdi
  mov    %rdx,%r9
  lea    0x0(,%rsi,8),%rbx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L11:
  mov    %rbp,%rsi
  mov    %r8,%rdx
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L6:
  movsd  (%rsi,%rdx,8),%xmm0
  xor    %ecx,%ecx
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L1:
  lea    (%rdx,%r9,1),%rax
  xor    %edx,%edx
  div    %rdi
  mov    %rcx,%rax
  add    $0x1,%rcx
  and    $0x1,%eax
  movsd  (%rsi,%rdx,8),%xmm0
  movsd  %xmm0,(%rsp,%rax,8)
  mov    %rcx,%rax
  and    $0x1,%eax
  movsd  (%rsp,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rdx,8)
  cmp    %rdx,%r8
  jne    L1
  add    $0x1,%r10
  add    %rbx,%rsi
  cmp    %r10,%r11
  jne    L6
  cmp    $0x1,%r8
  mov    $0x1,%r8d
  sbb    %rax,%rax
  add    $0x2,%rax
  cmp    %r12,%rax
  je     L11
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void array_roll2d_y_s(size_t size0, size_t size1, double array[size0][size1], ssize_t shift) {
  ssize_t shift_y = (size1 + shift % size1) % size1;
  size_t y_init = 0;
  double tmp[2];
  do {
    size_t y1, y0 = y_init;
    for (size_t x = 0; x < size0; x++) {
      size_t i = 0;
      tmp[1] = array[x][y0];
      do {
        y1 = (y0 + shift_y) % size1;
        tmp[i % 2] = array[x][y1];
        array[x][y1] = tmp[(i + 1) % 2];
        i++;
      } while ((y0 = y1) != y_init);
    }
  } while (++y_init == (size1 + shift_y + 1) % 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<predict_4x4_dc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  neg    %eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    $0x1,%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    $0x2,%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    $0x3,%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  add    $0x4,%eax
  sar    $0x3,%eax
  imul   $0x1010101,%eax,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L13:
  cmpl   $0x3,-0x10(%rbp)
  jle    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void predict_4x4_dc(uint8_t *src, int i_stride) {
  int y;
  uint32_t dc = ((src[-1 + 0 * i_stride] + src[-1 + i_stride] + src[-1 + 2 * i_stride] + src[-1 + 3 * i_stride] + src[0 - i_stride] + src[1 - i_stride] + src[2 - i_stride] + src[3 - i_stride] + 4) >> 3) * 0x01010101;
  for (y = 0; y < 4; y++) {
    uint32_t *p = (uint32_t *)src;
    *p = dc;
    src += i_stride;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<predict_4x4_dc>:
  endbr64
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%edi
  movslq %edi,%rdi
  lea    0x0(,%rdi,4),%rcx
  lea    (%rsi,%rsi,1),%r9d
  lea    -0x1(%r9),%r8d
  movslq %r8d,%r8
  mov    -0x4(%rdx),%eax
  add    (%rdx,%rdi,4),%eax
  add    (%rdx,%r8,4),%eax
  lea    -0x1(%rsi,%r9,1),%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    %esi,%edi
  neg    %edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x1,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x2,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x3,%edi
  sub    %esi,%edi
  movslq %edi,%rsi
  add    (%rdx,%rsi,4),%eax
  add    $0x4,%eax
  sar    $0x3,%eax
  imul   $0x1010101,%eax,%eax
  lea    0x4(%rcx),%rsi
  mov    %eax,(%rdx)
  add    %rsi,%rdx
  mov    %eax,(%rdx)
  add    %rsi,%rdx
  mov    %eax,(%rdx)
  mov    %eax,0x4(%rdx,%rcx,1)
  ret
```

assistant: ```c
void predict_4x4_dc(uint8_t *src, int i_stride) {
  int y;
  uint32_t dc = ((src[-1 + 0 * i_stride] + src[-1 + i_stride] + src[-1 + 2 * i_stride] + src[-1 + 3 * i_stride] + src[0 - i_stride] + src[1 - i_stride] + src[2 - i_stride] + src[3 - i_stride] + 4) >> 3) * 0x01010101;
  for (y = 0; y < 4; y++) {
    uint32_t *p = (uint32_t *)src;
    *p = dc;
    src += i_stride;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<predict_4x4_dc>:
  endbr64
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%edi
  lea    (%rsi,%rsi,1),%r9d
  movslq %edi,%rdi
  mov    -0x4(%rdx),%eax
  lea    -0x1(%r9),%r8d
  add    (%rdx,%rdi,4),%eax
  lea    0x0(,%rdi,4),%rcx
  lea    -0x1(%rsi,%r9,1),%edi
  movslq %r8d,%r8
  movslq %edi,%rdi
  add    (%rdx,%r8,4),%eax
  add    (%rdx,%rdi,4),%eax
  mov    %esi,%edi
  neg    %edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x1,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x2,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x3,%edi
  sub    %esi,%edi
  movslq %edi,%rsi
  add    (%rdx,%rsi,4),%eax
  lea    0x4(%rcx),%rsi
  add    $0x4,%eax
  sar    $0x3,%eax
  imul   $0x1010101,%eax,%eax
  mov    %eax,(%rdx)
  add    %rsi,%rdx
  mov    %eax,(%rdx)
  add    %rsi,%rdx
  mov    %eax,(%rdx)
  mov    %eax,0x4(%rdx,%rcx,1)
  ret
```

assistant: ```c
void predict_4x4_dc(uint8_t *src, int i_stride) {
  int y;
  uint32_t dc = ((src[-1 + 0 * i_stride] + src[-1 + i_stride] + src[-1 + 2 * i_stride] + src[-1 + 3 * i_stride] + src[0 - i_stride] + src[1 - i_stride] + src[2 - i_stride] + src[3 - i_stride] + 4) >> 3) * 0x01010101;
  for (y = 0; y < 4; y++) {
    uint32_t *p = (uint32_t *)src;
    *p = dc;
    src += i_stride;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<predict_4x4_dc>:
  endbr64
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%edi
  lea    (%rsi,%rsi,1),%r9d
  movslq %edi,%rdi
  mov    -0x4(%rdx),%eax
  lea    -0x1(%r9),%r8d
  add    (%rdx,%rdi,4),%eax
  lea    0x0(,%rdi,4),%rcx
  lea    -0x1(%rsi,%r9,1),%edi
  movslq %r8d,%r8
  movslq %edi,%rdi
  add    (%rdx,%r8,4),%eax
  add    (%rdx,%rdi,4),%eax
  mov    %esi,%edi
  neg    %edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x1,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x2,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  mov    $0x3,%edi
  sub    %esi,%edi
  movslq %edi,%rdi
  add    (%rdx,%rdi,4),%eax
  lea    0x4(%rcx),%rdi
  add    $0x4,%eax
  sar    $0x3,%eax
  imul   $0x1010101,%eax,%eax
  mov    %eax,(%rdx)
  add    %rdi,%rdx
  mov    %eax,(%rdx)
  add    %rdi,%rdx
  mov    %eax,(%rdx)
  mov    %eax,0x4(%rdx,%rcx,1)
  cmp    $0x1,%esi
  jne    L0
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
void predict_4x4_dc(uint8_t *src, int i_stride) {
  int y;
  uint32_t dc = ((src[-1 + 0 * i_stride] + src[-1 + i_stride] + src[-1 + 2 * i_stride] + src[-1 + 3 * i_stride] + src[0 - i_stride] + src[1 - i_stride] + src[2 - i_stride] + src[3 - i_stride] + 4) >> 3) * 0x01010101;
  for (y = 0; y < 4; y++) {
    uint32_t *p = (uint32_t *)src;
    *p = dc;
    src += i_stride;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<new_choice_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %al,-0x24(%rbp)
  movzbl -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <find_add_table@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <choice_row_append@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <encode_id@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int new_choice_row(struct ttrie__obj *tt, char *table_name, unsigned char name_len, unsigned char (*row_id)[5], unsigned char result_id[5]) {
  unsigned int table_number = find_add_table(tt, table_name, name_len);
  unsigned int row_i = choice_row_append(tt, table_number, row_id);
  encode_id(0, table_number, row_i, result_id);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<new_choice_row>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rcx,%r13
  mov    %r8,%r12
  movzbl %dl,%edx
  call   <find_add_table@plt>
  mov    %eax,%ebx
  mov    %r13,%rdx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <choice_row_append@plt>
  mov    %eax,%edx
  mov    %r12,%rcx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <encode_id@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int new_choice_row(struct ttrie__obj *tt, char *table_name, unsigned char name_len, unsigned char (*row_id)[5], unsigned char result_id[5]) {
  unsigned int table_number = find_add_table(tt, table_name, name_len);
  unsigned int row_i = choice_row_append(tt, table_number, row_id);
  encode_id(0, table_number, row_i, result_id);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<new_choice_row>:
  endbr64
  push   %r14
  movzbl %dl,%edx
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <find_add_table@plt>
  mov    %r14,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <choice_row_append@plt>
  mov    %r13,%rcx
  mov    %ebp,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <encode_id@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int new_choice_row(struct ttrie__obj *tt, char *table_name, unsigned char name_len, unsigned char (*row_id)[5], unsigned char result_id[5]) {
  unsigned int table_number = find_add_table(tt, table_name, name_len);
  unsigned int row_i = choice_row_append(tt, table_number, row_id);
  encode_id(0, table_number, row_i, result_id);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<new_choice_row>:
  endbr64
  push   %r14
  movzbl %dl,%edx
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <find_add_table@plt>
  mov    %r14,%rdx
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  call   <choice_row_append@plt>
  mov    %r13,%rcx
  mov    %ebp,%esi
  xor    %edi,%edi
  mov    %eax,%edx
  call   <encode_id@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int new_choice_row(struct ttrie__obj *tt, char *table_name, unsigned char name_len, unsigned char (*row_id)[5], unsigned char result_id[5]) {
  unsigned int table_number = find_add_table(tt, table_name, name_len);
  unsigned int row_i = choice_row_append(tt, table_number, row_id);
  encode_id(0, table_number, row_i, result_id);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<random_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x22b63cbf,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x76,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0xa(%rdx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  lea    0x21(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L3:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jg     L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void random_key(char *key) {
  int i, len = 10 + rand() % (128 - 10);
  for (i = len; i-- > 0;)
    key[i] = '!' + rand() % 94;
  key[len] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_key>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x22b63cbf,%rdx,%rdx
  sar    $0x24,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x76,%edx,%ecx
  sub    %ecx,%eax
  lea    0xa(%rax),%r13d
  test   %r13d,%r13d
  jle    L7
  mov    %eax,%edx
  lea    0x9(%rax),%ebx
  movslq %ebx,%rbx
  add    %r12,%rbx
  cltq
  lea    0x8(%r12,%rax,1),%rbp
  lea    0x9(%rdx),%eax
  sub    %rax,%rbp
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
L7:
  movslq %r13d,%r13
  movb   $0x0,(%r12,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void random_key(char *key) {
  int i, len = 10 + rand() % (128 - 10);
  for (i = len; i-- > 0;)
    key[i] = '!' + rand() % 94;
  key[len] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<random_key>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x22b63cbf,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x76,%edx,%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  lea    0xa(%rdx),%r12d
  test   %r12d,%r12d
  jle    L8
  lea    0x9(%rdx),%eax
  lea    0x8(%rbp,%rdx,1),%rbx
  movslq %eax,%r13
  mov    %eax,%eax
  add    %rbp,%r13
  sub    %rax,%rbx
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  sub    $0x1,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,0x1(%r13)
  cmp    %rbx,%r13
  jne    L9
L8:
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void random_key(char *key) {
  int i, len = 10 + rand() % (128 - 10);
  for (i = len; i-- > 0;)
    key[i] = '!' + rand() % 94;
  key[len] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<random_key>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x22b63cbf,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x76,%edx,%ecx
  sub    %ecx,%eax
  movslq %eax,%rdx
  lea    0xa(%rdx),%r12d
  test   %r12d,%r12d
  jle    L14
  lea    0x9(%rdx),%eax
  lea    0x8(%rbp,%rdx,1),%rbx
  movslq %eax,%r13
  mov    %eax,%eax
  add    %rbp,%r13
  sub    %rax,%rbx
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  sub    $0x1,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  add    $0x21,%eax
  mov    %al,0x1(%r13)
  cmp    %rbx,%r13
  jne    L3
L14:
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void random_key(char *key) {
  int i, len = 10 + rand() % (128 - 10);
  for (i = len; i-- > 0;)
    key[i] = '!' + rand() % 94;
  key[len] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getMessageID>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x3f0(%rbp)
  movq   $0x0,-0x3e8(%rbp)
  lea    -0x3e0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7b,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x404(%rbp)
  mov    -0x420(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x3f0(%rbp),%rax
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x400(%rbp)
  mov    -0x400(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x186,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <_assert@plt>
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x3f8(%rbp)
  mov    -0x3f8(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x188,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <_assert@plt>
  mov    -0x3f8(%rbp),%rax
  sub    -0x400(%rbp),%rax
  mov    %eax,-0x404(%rbp)
  mov    -0x404(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x400(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x418(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x404(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x418(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D12
datatype: string

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c

assistant: ```c
void getMessageID(char *idBuffer, char *messageLine) {
  char msg[1000] = {'\0'};
  char *ptrMsg1, *ptrMsg2;
  int length = 0;
  strcpy(msg, messageLine);
  ptrMsg1 = strchr(msg, '<');
  _assert("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c", 390, ptrMsg1);
  ptrMsg2 = strrchr(msg, '>');
  _assert("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c", 392, ptrMsg2);
  length = ptrMsg2 - ptrMsg1;
  strncpy(idBuffer, ptrMsg1 + 1, length - 1);
  idBuffer[length - 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getMessageID>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7b,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x3c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %rax,%rdx
  mov    $0x186,%esi
  lea    D1(%rip),%r13
  mov    %r13,%rdi
  call   <_assert@plt>
  mov    $0x3e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    $0x188,%esi
  mov    %r13,%rdi
  call   <_assert@plt>
  sub    %rbp,%rbx
  lea    -0x1(%rbx),%edx
  lea    0x1(%rbp),%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c

assistant: ```c
void getMessageID(char *idBuffer, char *messageLine) {
  char msg[1000] = {'\0'};
  char *ptrMsg1, *ptrMsg2;
  int length = 0;
  strcpy(msg, messageLine);
  ptrMsg1 = strchr(msg, '<');
  _assert("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c", 390, ptrMsg1);
  ptrMsg2 = strrchr(msg, '>');
  _assert("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/CS4098Group/Project/refs/heads/master/peos/os/virtual_repository/EMAILseeker.c", 392, ptrMsg2);
  length = ptrMsg2 - ptrMsg1;
  strncpy(idBuffer, ptrMsg1 + 1, length - 1);
  idBuffer[length - 1] = '\0';
}
```