ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D2(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  mov    %edx,%esi
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,%r9d
  mov    %edx,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %eax,%r8
  cltd
  imul   $0x66666667,%r8,%r8
  sar    $0x21,%r8
  sub    %edx,%r8d
  lea    (%r8,%r8,4),%edx
  mov    %r8d,%ecx
  sub    %edx,%eax
  mov    %r9d,%edx
  mov    %eax,%r8d
  mov    %eax,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D19: %d

tool: D2: %d quarters, %d dimes, %d nickels and %d pennies


assistant: ```c
int main() {
  int pennies;
  scanf("%d", &pennies);
  int quarters = pennies / 25;
  pennies %= 25;
  int dimes = pennies / 10;
  pennies %= 10;
  int nickels = pennies / 5;
  pennies %= 5;
  printf("%d quarters, %d dimes, %d nickels and %d pennies\n", quarters, dimes, nickels, pennies);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D14(%rip),%rdi
  mov    %rdx,%rax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  mov    %edx,%esi
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %eax,%r9d
  mov    %edx,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  movslq %eax,%r8
  cltd
  imul   $0x66666667,%r8,%r8
  sar    $0x21,%r8
  sub    %edx,%r8d
  lea    (%r8,%r8,4),%edx
  mov    %r8d,%ecx
  sub    %edx,%eax
  mov    %r9d,%edx
  mov    %eax,%r8d
  mov    %eax,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string

tool: D1: %d

tool: D14: %d quarters, %d dimes, %d nickels and %d pennies


assistant: ```c
int main() {
  int pennies;
  scanf("%d", &pennies);
  int quarters = pennies / 25;
  pennies %= 25;
  int dimes = pennies / 10;
  pennies %= 10;
  int nickels = pennies / 5;
  pennies %= 5;
  printf("%d quarters, %d dimes, %d nickels and %d pennies\n", quarters, dimes, nickels, pennies);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<geopm_signal_to_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
uint64_t geopm_signal_to_field(double signal) {
  uint64_t result;
  memcpy(&result, &signal, sizeof(result));
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<geopm_signal_to_field>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t geopm_signal_to_field(double signal) {
  uint64_t result;
  memcpy(&result, &signal, sizeof(result));
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<geopm_signal_to_field>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t geopm_signal_to_field(double signal) {
  uint64_t result;
  memcpy(&result, &signal, sizeof(result));
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<geopm_signal_to_field>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t geopm_signal_to_field(double signal) {
  uint64_t result;
  memcpy(&result, &signal, sizeof(result));
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: Hello, C

assistant: ```c
int main() {
  puts("Hello, C");
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: Hello, C

assistant: ```c
int main() {
  puts("Hello, C");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: Hello, C

assistant: ```c
int main() {
  puts("Hello, C");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: Hello, C

assistant: ```c
int main() {
  puts("Hello, C");
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sendMessage>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <getTrID@plt>
  mov    %eax,%r14d
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <integerLength@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x72(%rax),%ebx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <integerLength@plt>
  movslq %ebp,%rbp
  cltq
  lea    0x9(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  sub    $0x8,%rsp
  lea    D41(%rip),%r13
  push   %r13
  mov    %ebx,%r9d
  lea    D9(%rip),%r8
  mov    %r14d,%ecx
  lea    D72(%rip),%rdx
  lea    D24(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %ebx,%rbx
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,(%rsp)
  lea    D48(%rip),%r9
  lea    D56(%rip),%r8
  lea    D14(%rip),%rcx
  mov    %rbp,%rdx
  lea    D57(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <sendData@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D41
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D72
type: string
name: read_data
arguments: label: D24
type: string
name: read_data
arguments: label: D48
type: string
name: read_data
arguments: label: D56
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D57
type: string

tool: D41: 


tool: D9:  A 

tool: D72: MSG 

tool: D24: %s%d%s%d%s

tool: D48: X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22


tool: D56: Content-Type: text/plain; charset=UTF-8


tool: D14: MIME-Version: 1.0


tool: D57: %s%s%s%s%s

assistant: ```c
int sendMessage(int sock, char *message) {
  int tr = getTrID();
  int trLen = integerLength(tr);
  int headerLen = strlen("MIME-Version: 1.0\r\n") + strlen("Content-Type: text/plain; charset=UTF-8\r\n") + strlen("X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n") + strlen("\r\n") + strlen(message);
  char *line1 = malloc(strlen("MSG ") + trLen + strlen(" A ") + integerLength(headerLen) + strlen("\r\n"));
  sprintf(line1, "%s%d%s%d%s", "MSG ", tr, " A ", headerLen, "\r\n");
  char *mess = malloc(strlen(line1) + headerLen + 1);
  sprintf(mess, "%s%s%s%s%s", line1, "MIME-Version: 1.0\r\n", "Content-Type: text/plain; charset=UTF-8\r\n", "X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n", "\r\n");
  return sendData(sock, mess);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sendMessage>:
  endbr64
  push   %r15
  xor    %eax,%eax
  lea    D49(%rip),%r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getTrID@plt>
  mov    %eax,%r14d
  mov    %eax,%edi
  xor    %eax,%eax
  call   <integerLength@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  lea    0x72(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%edi
  call   <integerLength@plt>
  cltq
  lea    0x9(%r12,%rax,1),%rdi
  call   <malloc@plt>
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r14d,%ecx
  push   %r15
  mov    %rax,%r12
  lea    D47(%rip),%r8
  mov    %rax,%rdi
  lea    D7(%rip),%rdx
  lea    D37(%rip),%rsi
  xor    %eax,%eax
  movslq %ebx,%rbx
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r15,(%rsp)
  lea    D73(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  lea    D18(%rip),%r9
  lea    D55(%rip),%r8
  lea    D45(%rip),%rcx
  call   <sprintf@plt>
  add    $0x18,%rsp
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <sendData@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D49
type_infered: string
name: retrieve_data
arguments: tag: D47
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D73
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D55
type_infered: string
name: retrieve_data
arguments: tag: D45
type_infered: string

tool: D49: 


tool: D47:  A 

tool: D7: MSG 

tool: D37: %s%d%s%d%s

tool: D73: %s%s%s%s%s

tool: D18: X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22


tool: D55: Content-Type: text/plain; charset=UTF-8


tool: D45: MIME-Version: 1.0


assistant: ```c
int sendMessage(int sock, char *message) {
  int tr = getTrID();
  int trLen = integerLength(tr);
  int headerLen = strlen("MIME-Version: 1.0\r\n") + strlen("Content-Type: text/plain; charset=UTF-8\r\n") + strlen("X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n") + strlen("\r\n") + strlen(message);
  char *line1 = malloc(strlen("MSG ") + trLen + strlen(" A ") + integerLength(headerLen) + strlen("\r\n"));
  sprintf(line1, "%s%d%s%d%s", "MSG ", tr, " A ", headerLen, "\r\n");
  char *mess = malloc(strlen(line1) + headerLen + 1);
  sprintf(mess, "%s%s%s%s%s", line1, "MIME-Version: 1.0\r\n", "Content-Type: text/plain; charset=UTF-8\r\n", "X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n", "\r\n");
  return sendData(sock, mess);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sendMessage>:
  endbr64
  push   %r15
  xor    %eax,%eax
  lea    D60(%rip),%r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getTrID@plt>
  mov    %eax,%r14d
  mov    %eax,%edi
  xor    %eax,%eax
  call   <integerLength@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <strlen@plt>
  lea    0x72(%rax),%ebx
  xor    %eax,%eax
  mov    %ebx,%edi
  call   <integerLength@plt>
  cltq
  lea    0x9(%r12,%rax,1),%rdi
  call   <malloc@plt>
  sub    $0x8,%rsp
  mov    %ebx,%r9d
  mov    %r14d,%ecx
  push   %r15
  mov    %rax,%r12
  lea    D45(%rip),%r8
  mov    %rax,%rdi
  lea    D57(%rip),%rdx
  lea    D55(%rip),%rsi
  xor    %eax,%eax
  movslq %ebx,%rbx
  call   <sprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r15,(%rsp)
  lea    D70(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  lea    D56(%rip),%r9
  lea    D66(%rip),%r8
  lea    D12(%rip),%rcx
  call   <sprintf@plt>
  add    $0x18,%rsp
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <sendData@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D60
datatype: string
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D57
datatype: string
name: disassemble_data
arguments: tag: D55
datatype: string
name: disassemble_data
arguments: tag: D70
datatype: string
name: disassemble_data
arguments: tag: D56
datatype: string
name: disassemble_data
arguments: tag: D66
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string

tool: D60: 


tool: D45:  A 

tool: D57: MSG 

tool: D55: %s%d%s%d%s

tool: D70: %s%s%s%s%s

tool: D56: X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22


tool: D66: Content-Type: text/plain; charset=UTF-8


tool: D12: MIME-Version: 1.0


assistant: ```c
int sendMessage(int sock, char *message) {
  int tr = getTrID();
  int trLen = integerLength(tr);
  int headerLen = strlen("MIME-Version: 1.0\r\n") + strlen("Content-Type: text/plain; charset=UTF-8\r\n") + strlen("X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n") + strlen("\r\n") + strlen(message);
  char *line1 = malloc(strlen("MSG ") + trLen + strlen(" A ") + integerLength(headerLen) + strlen("\r\n"));
  sprintf(line1, "%s%d%s%d%s", "MSG ", tr, " A ", headerLen, "\r\n");
  char *mess = malloc(strlen(line1) + headerLen + 1);
  sprintf(mess, "%s%s%s%s%s", line1, "MIME-Version: 1.0\r\n", "Content-Type: text/plain; charset=UTF-8\r\n", "X-MMS-IM-Format: FN=Arial; EF=I; CO=0; CS=0; PF=22\r\n", "\r\n");
  return sendData(sock, mess);
}
```
user: Translate the below assembly code into C programming language:

```asm
<restart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initscreens@plt>
  mov    $0x0,%eax
  call   <drawtitle@plt>
  mov    $0x0,%eax
  call   <initscreens@plt>
  mov    $0x0,%eax
  call   <setup@plt>
  mov    $0x0,%eax
  call   <main_loop@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void restart() {
  initscreens();
  drawtitle();
  initscreens();
  setup();
  main_loop();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<restart>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscreens@plt>
  mov    $0x0,%eax
  call   <drawtitle@plt>
  mov    $0x0,%eax
  call   <initscreens@plt>
  mov    $0x0,%eax
  call   <setup@plt>
  mov    $0x0,%eax
  call   <main_loop@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void restart() {
  initscreens();
  drawtitle();
  initscreens();
  setup();
  main_loop();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<restart>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscreens@plt>
  xor    %eax,%eax
  call   <drawtitle@plt>
  xor    %eax,%eax
  call   <initscreens@plt>
  xor    %eax,%eax
  call   <setup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <main_loop@plt>
```

assistant: ```c
void restart() {
  initscreens();
  drawtitle();
  initscreens();
  setup();
  main_loop();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<restart>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscreens@plt>
  xor    %eax,%eax
  call   <drawtitle@plt>
  xor    %eax,%eax
  call   <initscreens@plt>
  xor    %eax,%eax
  call   <setup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <main_loop@plt>
```

assistant: ```c
void restart() {
  initscreens();
  drawtitle();
  initscreens();
  setup();
  main_loop();
}
```
user: What is the c source code of the assembly code below?

```asm
<CreatePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L52
  addq   $0x2,-0x428(%rbp)
L52:
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x418(%rbp)
  jmp    L11
L21:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x419(%rbp)
  cmpb   $0x2f,-0x419(%rbp)
  je     L10
  cmpb   $0x5c,-0x419(%rbp)
  jne    L17
L10:
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  mov    %eax,%edx
  mov    -0x428(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_mkdir@plt>
L17:
  addq   $0x1,-0x418(%rbp)
L11:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmpb   $0x3a,0x1(%rdi)
  je     L84
L89:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L68
  mov    %rsp,%r13
  jmp    L67
L84:
  add    $0x2,%rbp
  jmp    L89
L31:
  mov    %rbx,%r12
  sub    %rbp,%r12
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%r12,1)
  mov    %r13,%rdi
  call   <Q_mkdir@plt>
L8:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L68
L67:
  cmp    $0x2f,%al
  je     L31
  cmp    $0x5c,%al
  jne    L8
  jmp    L31
L68:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L79
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L79:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  jne    L63
  jmp    L40
  nopl   0x0(%rax)
L57:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L40
L63:
  cmp    $0x2f,%al
  je     L76
  cmp    $0x5c,%al
  jne    L57
L76:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L63
L40:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movzbl 0x1(%rdi),%eax
  cmp    $0x3a,%al
  jne    L11
  movzbl 0x3(%rdi),%eax
  add    $0x2,%rbp
L11:
  lea    0x1(%rbp),%rbx
  mov    %rsp,%r13
  test   %al,%al
  je     L27
  nopw   0x0(%rax,%rax,1)
L67:
  cmp    $0x2f,%al
  je     L1
  cmp    $0x5c,%al
  je     L1
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L67
L27:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L1:
  mov    %rbx,%r12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  sub    %rbp,%r12
  mov    %r12d,%edx
  call   <memcpy@plt>
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%r12,1)
  call   <Q_mkdir@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L67
  jmp    L27
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<doicoso>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L10:
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <luythua@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <chuyendoi@plt>
  imul   %ebx,%eax
  add    %eax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int doicoso(char *s) {
  int i, j, tg;
  i = strlen(s);
  tg = 0;
  for (j = 0; j < i; j++)
    tg = tg + luythua(i - j - 1) * chuyendoi(s[j]);
  return tg;
}
```