ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<bsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  test   %rdx,%rdx
  je     L5
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r13
  cmp    $0x1,%rdx
  je     L88
L39:
  mov    %rbx,%r15
  mov    0x8(%rsp),%rax
  mov    %r14,%rdi
  shr    %r15
  movslq %r15d,%r15
  mov    %r15,%r12
  imul   %r13,%r12
  add    %rbp,%r12
  mov    %r12,%rsi
  call   *%rax
  test   %eax,%eax
  je     L21
  js     L51
  sub    $0x1,%rbx
  lea    (%r12,%r13,1),%rbp
  sub    %r15,%rbx
L67:
  test   %rbx,%rbx
  je     L5
  cmp    $0x1,%rbx
  jne    L39
L88:
  mov    0x8(%rsp),%rax
  mov    %rbp,%r12
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   *%rax
  test   %eax,%eax
  jne    L5
L21:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  mov    %r15,%rbx
  jmp    L67
  nopl   (%rax)
L5:
  xor    %r12d,%r12d
  jmp    L21
```

assistant: ```c
void *bsearch(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  int midn, c;
  void *midp;
  for (;;) {
    if (nmemb == 0)
      return NULL;
    else if (nmemb == 1) {
      if ((*compar)(key, base) == 0)
        return (void *)base;
      else
        return NULL;
    }
    midn = nmemb >> 1;
    midp = (char *)base + midn * size;
    c = (*compar)(key, midp);
    if (c == 0)
      return midp;
    else if (c < 0)
      nmemb = midn;
    else {
      base = (char *)midp + size;
      nmemb = nmemb - midn - 1;
    }
    continue;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bytesToHuman>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jns    L52
  mov    -0x18(%rbp),%rax
  movb   $0x2d,(%rax)
  addq   $0x1,-0x18(%rbp)
  negq   -0x20(%rbp)
L52:
  cmpq   $0x3ff,-0x20(%rbp)
  jg     L62
  pxor   %xmm2,%xmm2
  cvtsi2sdq -0x20(%rbp),%xmm2
  movq   %xmm2,%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D41(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L7
L62:
  cmpq   $0xfffff,-0x20(%rbp)
  jg     L72
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x20(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L7
L72:
  cmpq   $0x3fffffff,-0x20(%rbp)
  jg     L26
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x20(%rbp),%xmm0
  movsd  D13(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D32(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L7
L26:
  movabs $0xffffffffff,%rax
  cmp    %rax,-0x20(%rbp)
  jg     L7
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x20(%rbp),%xmm0
  movsd  D48(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D41
data_type: string
name: extract_symbolic_data
arguments: tag: D61
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D32
data_type: string
name: extract_symbolic_data
arguments: tag: D48
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D20
data_type: string

tool: D41: %lluB

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x90,0x40]}

tool: D33: %.2fK

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x41]}

tool: D32: %.2fM

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x41]}

tool: D20: %.2fG

assistant: ```c
void bytesToHuman(char *s, long long n) {
  double d;
  if (n < 0) {
    *s = '-';
    s++;
    n = -n;
  }
  if (n < 1024) {
    sprintf(s, "%lluB", n);
    return;
  } else if (n < (1024 * 1024)) {
    d = (double)n / (1024);
    sprintf(s, "%.2fK", d);
  } else if (n < (1024LL * 1024 * 1024)) {
    d = (double)n / (1024 * 1024);
    sprintf(s, "%.2fM", d);
  } else if (n < (1024LL * 1024 * 1024 * 1024)) {
    d = (double)n / (1024LL * 1024 * 1024);
    sprintf(s, "%.2fG", d);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bytesToHuman>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  js     L70
L30:
  cmp    $0x3ff,%rsi
  jle    L66
  cmp    $0xfffff,%rsi
  jle    L18
  cmp    $0x3fffffff,%rsi
  jle    L46
  movabs $0xffffffffff,%rax
  cmp    %rax,%rsi
  jg     L62
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D0(%rip),%xmm0
  lea    D15(%rip),%rsi
  call   <sprintf@plt>
  jmp    L62
L70:
  movb   $0x2d,(%rdi)
  add    $0x1,%rdi
  neg    %rsi
  jmp    L30
L66:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  lea    D39(%rip),%rsi
  call   <sprintf@plt>
  jmp    L62
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D18(%rip),%xmm0
  lea    D66(%rip),%rsi
  call   <sprintf@plt>
L62:
  add    $0x8,%rsp
  ret
L46:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D41(%rip),%xmm0
  lea    D14(%rip),%rsi
  call   <sprintf@plt>
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D39
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D66
datatype: string
name: extract_symbolic_data
arguments: label: D41
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D14
datatype: string

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D15: %.2fG

tool: D39: %lluB

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D66: %.2fK

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D14: %.2fM

assistant: ```c
void bytesToHuman(char *s, long long n) {
  double d;
  if (n < 0) {
    *s = '-';
    s++;
    n = -n;
  }
  if (n < 1024) {
    sprintf(s, "%lluB", n);
    return;
  } else if (n < (1024 * 1024)) {
    d = (double)n / (1024);
    sprintf(s, "%.2fK", d);
  } else if (n < (1024LL * 1024 * 1024)) {
    d = (double)n / (1024 * 1024);
    sprintf(s, "%.2fM", d);
  } else if (n < (1024LL * 1024 * 1024 * 1024)) {
    d = (double)n / (1024LL * 1024 * 1024);
    sprintf(s, "%.2fG", d);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bytesToHuman>:
  endbr64
  test   %rsi,%rsi
  jns    L11
  movb   $0x2d,(%rdi)
  neg    %rsi
  add    $0x1,%rdi
L11:
  cmp    $0x3ff,%rsi
  jle    L33
  cmp    $0xfffff,%rsi
  jle    L3
  cmp    $0x3fffffff,%rsi
  jle    L22
  movabs $0xffffffffff,%rax
  cmp    %rax,%rsi
  jle    L37
  ret
  xchg   %ax,%ax
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D9(%rip),%xmm0
  lea    D17(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L33:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  lea    D4(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L22:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D57(%rip),%xmm0
  lea    D42(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L37:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D6(%rip),%xmm0
  lea    D46(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_infered: byte[8]
name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string
name: parse_data
arguments: data_tag: D57
type_infered: byte[8]
name: parse_data
arguments: data_tag: D42
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: byte[8]
name: parse_data
arguments: data_tag: D46
type_infered: string

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D17: %.2fK

tool: D4: %lluB

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D42: %.2fM

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D46: %.2fG

assistant: ```c
void bytesToHuman(char *s, long long n) {
  double d;
  if (n < 0) {
    *s = '-';
    s++;
    n = -n;
  }
  if (n < 1024) {
    sprintf(s, "%lluB", n);
    return;
  } else if (n < (1024 * 1024)) {
    d = (double)n / (1024);
    sprintf(s, "%.2fK", d);
  } else if (n < (1024LL * 1024 * 1024)) {
    d = (double)n / (1024 * 1024);
    sprintf(s, "%.2fM", d);
  } else if (n < (1024LL * 1024 * 1024 * 1024)) {
    d = (double)n / (1024LL * 1024 * 1024);
    sprintf(s, "%.2fG", d);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bytesToHuman>:
  endbr64
  test   %rsi,%rsi
  jns    L40
  movb   $0x2d,(%rdi)
  neg    %rsi
  add    $0x1,%rdi
L40:
  cmp    $0x3ff,%rsi
  jle    L5
  cmp    $0xfffff,%rsi
  jle    L31
  cmp    $0x3fffffff,%rsi
  jle    L39
  movabs $0xffffffffff,%rax
  cmp    %rax,%rsi
  jle    L21
  ret
  xchg   %ax,%ax
L31:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D43(%rip),%xmm0
  lea    D33(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  lea    D60(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L39:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D56(%rip),%xmm0
  lea    D66(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L21:
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mulsd  D10(%rip),%xmm0
  lea    D35(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: unpack_data
arguments: label: D43
datatype: byte[8]
name: unpack_data
arguments: label: D33
datatype: string
name: unpack_data
arguments: label: D60
datatype: string
name: unpack_data
arguments: label: D56
datatype: byte[8]
name: unpack_data
arguments: label: D66
datatype: string
name: unpack_data
arguments: label: D10
datatype: byte[8]
name: unpack_data
arguments: label: D35
datatype: string

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0x50,0x3f]}

tool: D33: %.2fK

tool: D60: %lluB

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3e]}

tool: D66: %.2fM

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x3e]}

tool: D35: %.2fG

assistant: ```c
void bytesToHuman(char *s, long long n) {
  double d;
  if (n < 0) {
    *s = '-';
    s++;
    n = -n;
  }
  if (n < 1024) {
    sprintf(s, "%lluB", n);
    return;
  } else if (n < (1024 * 1024)) {
    d = (double)n / (1024);
    sprintf(s, "%.2fK", d);
  } else if (n < (1024LL * 1024 * 1024)) {
    d = (double)n / (1024 * 1024);
    sprintf(s, "%.2fM", d);
  } else if (n < (1024LL * 1024 * 1024 * 1024)) {
    d = (double)n / (1024LL * 1024 * 1024);
    sprintf(s, "%.2fG", d);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ways>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  movl   $0x1,-0x10(%rbp)
  jmp    L15
L24:
  cmpl   $0x1,-0x14(%rbp)
  jne    L16
  movl   $0x1,-0x10(%rbp)
  jmp    L15
L16:
  cmpl   $0x2,-0x14(%rbp)
  jne    L36
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ways>
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L36:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  test   %eax,%eax
  je     L104
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L112
L104:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ways>
  mov    %eax,-0xc(%rbp)
L112:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  test   %eax,%eax
  je     L49
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L49:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <ways>
  mov    %eax,-0x8(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  test   %eax,%eax
  je     L58
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D57(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L94
L58:
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,%edi
  call   <ways>
  mov    %eax,-0x4(%rbp)
L94:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  lea    D57(%rip),%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rcx,%rdx,1)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ways(int steps) {
  int counts;
  int count1 = 0;
  int count2 = 0;
  int count3 = 0;
  static int data[1000];
  if (steps == 0)
    counts = 1;
  else if (steps == 1)
    counts = 1;
  else if (steps == 2) {
    count1 = ways(steps - 1);
    count2 = 1;
    counts = count1 + count2;
  } else {
    if (data[steps - 1])
      count1 = data[steps - 1];
    else
      count1 = ways(steps - 1);
    if (data[steps - 2])
      count2 = data[steps - 2];
    else
      count2 = ways(steps - 2);
    if (data[steps - 3])
      count3 = data[steps - 3];
    else
      count3 = ways(steps - 3);
    counts = count1 + count2 + count3;
  }
  data[steps] = counts;
  return counts;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ways>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  ja     L93
L15:
  movslq %ebx,%rbx
  lea    D2(%rip),%rdx
  mov    %eax,(%rdx,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L93:
  cmp    $0x2,%edi
  je     L37
  lea    -0x1(%rdi),%edi
  movslq %edi,%rdx
  lea    D2(%rip),%rax
  mov    (%rax,%rdx,4),%ebp
  test   %ebp,%ebp
  je     L40
L86:
  lea    -0x2(%rbx),%edi
  movslq %edi,%rdx
  lea    D2(%rip),%rax
  mov    (%rax,%rdx,4),%r12d
  test   %r12d,%r12d
  je     L17
L58:
  lea    -0x3(%rbx),%edi
  movslq %edi,%rdx
  lea    D2(%rip),%rax
  mov    (%rax,%rdx,4),%edx
  test   %edx,%edx
  je     L56
L50:
  lea    0x0(%rbp,%r12,1),%eax
  add    %edx,%eax
  jmp    L15
L37:
  mov    $0x1,%edi
  call   <ways>
  add    $0x1,%eax
  jmp    L15
L40:
  call   <ways>
  mov    %eax,%ebp
  jmp    L86
L17:
  call   <ways>
  mov    %eax,%r12d
  jmp    L58
L56:
  call   <ways>
  mov    %eax,%edx
  jmp    L50
```

assistant: ```c
int ways(int steps) {
  int counts;
  int count1 = 0;
  int count2 = 0;
  int count3 = 0;
  static int data[1000];
  if (steps == 0)
    counts = 1;
  else if (steps == 1)
    counts = 1;
  else if (steps == 2) {
    count1 = ways(steps - 1);
    count2 = 1;
    counts = count1 + count2;
  } else {
    if (data[steps - 1])
      count1 = data[steps - 1];
    else
      count1 = ways(steps - 1);
    if (data[steps - 2])
      count2 = data[steps - 2];
    else
      count2 = ways(steps - 2);
    if (data[steps - 3])
      count3 = data[steps - 3];
    else
      count3 = ways(steps - 3);
    counts = count1 + count2 + count3;
  }
  data[steps] = counts;
  return counts;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ways>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%ebx
  ja     L83
L19:
  mov    %eax,(%r12,%rbx,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L83:
  cmp    $0x2,%ebx
  je     L17
  lea    -0x1(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%ebp
  test   %ebp,%ebp
  je     L12
L2:
  lea    -0x2(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%r13d
  test   %r13d,%r13d
  je     L22
L11:
  lea    -0x3(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%edx
  test   %edx,%edx
  je     L37
L4:
  lea    0x0(%rbp,%r13,1),%eax
  add    %edx,%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L37:
  call   <ways>
  mov    %eax,%edx
  jmp    L4
  nopl   0x0(%rax)
L22:
  call   <ways>
  mov    %eax,%r13d
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L12:
  call   <ways>
  mov    %eax,%ebp
  jmp    L2
  nopl   0x0(%rax)
L17:
  mov    $0x1,%edi
  call   <ways>
  add    $0x1,%eax
  jmp    L19
```

assistant: ```c
int ways(int steps) {
  int counts;
  int count1 = 0;
  int count2 = 0;
  int count3 = 0;
  static int data[1000];
  if (steps == 0)
    counts = 1;
  else if (steps == 1)
    counts = 1;
  else if (steps == 2) {
    count1 = ways(steps - 1);
    count2 = 1;
    counts = count1 + count2;
  } else {
    if (data[steps - 1])
      count1 = data[steps - 1];
    else
      count1 = ways(steps - 1);
    if (data[steps - 2])
      count2 = data[steps - 2];
    else
      count2 = ways(steps - 2);
    if (data[steps - 3])
      count3 = data[steps - 3];
    else
      count3 = ways(steps - 3);
    counts = count1 + count2 + count3;
  }
  data[steps] = counts;
  return counts;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ways>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%ebx
  ja     L72
L54:
  mov    %eax,(%r12,%rbx,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L72:
  cmp    $0x2,%ebx
  je     L32
  lea    -0x1(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%ebp
  test   %ebp,%ebp
  je     L66
L71:
  lea    -0x2(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%r13d
  test   %r13d,%r13d
  je     L1
L65:
  lea    -0x3(%rbx),%edi
  movslq %edi,%rax
  mov    (%r12,%rax,4),%edx
  test   %edx,%edx
  je     L50
L29:
  lea    0x0(%rbp,%r13,1),%eax
  add    %edx,%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L50:
  call   <ways>
  mov    %eax,%edx
  jmp    L29
  nopl   0x0(%rax)
L1:
  call   <ways>
  mov    %eax,%r13d
  jmp    L65
  nopw   0x0(%rax,%rax,1)
L66:
  call   <ways>
  mov    %eax,%ebp
  jmp    L71
  nopl   0x0(%rax)
L32:
  mov    $0x1,%edi
  call   <ways>
  add    $0x1,%eax
  jmp    L54
```

assistant: ```c
int ways(int steps) {
  int counts;
  int count1 = 0;
  int count2 = 0;
  int count3 = 0;
  static int data[1000];
  if (steps == 0)
    counts = 1;
  else if (steps == 1)
    counts = 1;
  else if (steps == 2) {
    count1 = ways(steps - 1);
    count2 = 1;
    counts = count1 + count2;
  } else {
    if (data[steps - 1])
      count1 = data[steps - 1];
    else
      count1 = ways(steps - 1);
    if (data[steps - 2])
      count2 = data[steps - 2];
    else
      count2 = ways(steps - 2);
    if (data[steps - 3])
      count3 = data[steps - 3];
    else
      count3 = ways(steps - 3);
    counts = count1 + count2 + count3;
  }
  data[steps] = counts;
  return counts;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rftfsub>:
  endbr64
  mov    %edi,%r11d
  mov    %rsi,%r10
  mov    %edx,%esi
  mov    %edi,%r9d
  sar    %r9d
  lea    (%rdx,%rdx,1),%eax
  cltd
  idiv   %r9d
  cmp    $0x2,%r9d
  jle    L7
  mov    %eax,%r8d
  neg    %r8d
  movslq %r8d,%r8
  shl    $0x2,%r8
  cltq
  movslq %esi,%rsi
  sub    %rax,%rsi
  lea    (%rcx,%rsi,4),%rsi
  lea    0x0(,%rax,4),%rdi
  add    %rdi,%rcx
  movslq %r11d,%r11
  lea    (%r10,%r11,4),%rax
  lea    0xc(%r10),%rdx
  sub    $0x3,%r9d
  shr    %r9d
  mov    %r9d,%r9d
  lea    0x14(%r10,%r9,8),%r9
  movss  D6(%rip),%xmm6
L16:
  movaps %xmm6,%xmm0
  subss  (%rsi),%xmm0
  movss  (%rcx),%xmm4
  movss  -0x4(%rdx),%xmm3
  movaps %xmm3,%xmm5
  subss  -0x8(%rax),%xmm5
  movss  (%rdx),%xmm2
  movaps %xmm2,%xmm7
  addss  -0x4(%rax),%xmm7
  movaps %xmm0,%xmm1
  mulss  %xmm5,%xmm1
  movaps %xmm4,%xmm8
  mulss  %xmm7,%xmm8
  subss  %xmm8,%xmm1
  mulss  %xmm7,%xmm0
  mulss  %xmm5,%xmm4
  addss  %xmm4,%xmm0
  subss  %xmm1,%xmm3
  movss  %xmm3,-0x4(%rdx)
  subss  %xmm0,%xmm2
  movss  %xmm2,(%rdx)
  addss  -0x8(%rax),%xmm1
  movss  %xmm1,-0x8(%rax)
  movss  -0x4(%rax),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,-0x4(%rax)
  add    %r8,%rsi
  add    %rdi,%rcx
  sub    $0x8,%rax
  add    $0x8,%rdx
  cmp    %r9,%rdx
  jne    L16
L7:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void rftfsub(int n, float *a, int nc, float *c) {
  int j, k, kk, ks, m;
  float wkr, wki, xr, xi, yr, yi;
  m = n >> 1;
  ks = 2 * nc / m;
  kk = 0;
  for (j = 2; j < m; j += 2) {
    k = n - j;
    kk += ks;
    wkr = 0.5f - c[nc - kk];
    wki = c[kk];
    xr = a[j] - a[k];
    xi = a[j + 1] + a[k + 1];
    yr = wkr * xr - wki * xi;
    yi = wkr * xi + wki * xr;
    a[j] -= yr;
    a[j + 1] -= yi;
    a[k] += yr;
    a[k + 1] -= yi;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rftfsub>:
  endbr64
  movslq %edi,%r11
  mov    %rsi,%r10
  movslq %edx,%rsi
  lea    (%rsi,%rsi,1),%eax
  mov    %r11d,%r9d
  sar    %r9d
  cltd
  idiv   %r9d
  cmp    $0x2,%r9d
  jle    L2
  mov    %eax,%r8d
  sub    $0x3,%r9d
  lea    0xc(%r10),%rdx
  cltq
  neg    %r8d
  sub    %rax,%rsi
  shr    %r9d
  lea    0x0(,%rax,4),%rdi
  movslq %r8d,%r8
  lea    (%rcx,%rsi,4),%rsi
  lea    (%r10,%r11,4),%rax
  add    %rdi,%rcx
  movss  D1(%rip),%xmm6
  shl    $0x2,%r8
  lea    0x14(%r10,%r9,8),%r9
  nopl   0x0(%rax)
L0:
  movss  -0x4(%rdx),%xmm3
  movss  (%rdx),%xmm2
  movaps %xmm6,%xmm0
  add    $0x8,%rdx
  movss  -0x4(%rax),%xmm7
  subss  (%rsi),%xmm0
  sub    $0x8,%rax
  add    %r8,%rsi
  movss  (%rcx),%xmm4
  movaps %xmm3,%xmm5
  subss  (%rax),%xmm5
  add    %rdi,%rcx
  addss  %xmm2,%xmm7
  movaps %xmm0,%xmm1
  movaps %xmm4,%xmm8
  mulss  %xmm5,%xmm1
  mulss  %xmm7,%xmm8
  mulss  %xmm7,%xmm0
  mulss  %xmm5,%xmm4
  subss  %xmm8,%xmm1
  addss  %xmm4,%xmm0
  subss  %xmm1,%xmm3
  subss  %xmm0,%xmm2
  movss  %xmm3,-0xc(%rdx)
  movss  %xmm2,-0x8(%rdx)
  addss  (%rax),%xmm1
  movss  %xmm1,(%rax)
  movss  0x4(%rax),%xmm1
  subss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rax)
  cmp    %rdx,%r9
  jne    L0
L2:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void rftfsub(int n, float *a, int nc, float *c) {
  int j, k, kk, ks, m;
  float wkr, wki, xr, xi, yr, yi;
  m = n >> 1;
  ks = 2 * nc / m;
  kk = 0;
  for (j = 2; j < m; j += 2) {
    k = n - j;
    kk += ks;
    wkr = 0.5f - c[nc - kk];
    wki = c[kk];
    xr = a[j] - a[k];
    xi = a[j + 1] + a[k + 1];
    yr = wkr * xr - wki * xi;
    yi = wkr * xi + wki * xr;
    a[j] -= yr;
    a[j + 1] -= yi;
    a[k] += yr;
    a[k + 1] -= yi;
  }
}
```