ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <solve@plt>
L22:
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L23
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  while (T--) {
    solve();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EndVAR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <TXTOUT@plt>
  mov    $0x0,%eax
  call   <RecursiveReturn@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: }

assistant: ```c
void EndVAR() {
  TXTOUT("}");
  RecursiveReturn();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<EndVAR>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <TXTOUT@plt>
  mov    $0x0,%eax
  call   <RecursiveReturn@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: }

assistant: ```c
void EndVAR() {
  TXTOUT("}");
  RecursiveReturn();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EndVAR>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <TXTOUT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RecursiveReturn@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: }

assistant: ```c
void EndVAR() {
  TXTOUT("}");
  RecursiveReturn();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<EndVAR>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <TXTOUT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <RecursiveReturn@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string

tool: D0: }

assistant: ```c
void EndVAR() {
  TXTOUT("}");
  RecursiveReturn();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotate_the_rest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L42
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L30:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0x2,-0x4(%rbp)
  jle    L13
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x2,-0x8(%rbp)
  jle    L30
  addl   $0x1,-0xc(%rbp)
L42:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int rotate_the_rest(double **current_bb, int bb_length, double *pivot, double R[3][3], double **trial_bb) {
  int bb_atom_ctr, i, j;
  for (bb_atom_ctr = 0; bb_atom_ctr < bb_length; bb_atom_ctr++) {
    for (i = 0; i < 3; i++) {
      trial_bb[bb_atom_ctr][i] = 0;
      for (j = 0; j < 3; j++) {
        trial_bb[bb_atom_ctr][i] += R[i][j] * (current_bb[bb_atom_ctr][j] - pivot[j]);
      }
      trial_bb[bb_atom_ctr][i] += pivot[i];
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotate_the_rest>:
  endbr64
  test   %esi,%esi
  jle    L35
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rdx,%r9
  mov    %rcx,%rbx
  mov    %r8,%r11
  mov    %rdi,%r10
  lea    -0x1(%rsi),%eax
  lea    0x8(%r8,%rax,8),%rbp
  jmp    L19
L30:
  add    $0x8,%r11
  add    $0x8,%r10
  cmp    %rbp,%r11
  je     L50
L19:
  mov    %rbx,%r8
  mov    $0x0,%edx
L16:
  mov    %r11,%rsi
  mov    (%r11),%rax
  movq   $0x0,(%rax,%rdx,1)
  mov    %r8,%rdi
  mov    $0x0,%eax
L52:
  mov    %rdx,%rcx
  add    (%rsi),%rcx
  mov    (%r10),%r14
  movsd  (%r14,%rax,1),%xmm0
  subsd  (%r9,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L52
  mov    %rdx,%rax
  add    (%rsi),%rax
  movsd  (%rax),%xmm0
  addsd  (%r9,%rdx,1),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rdx
  add    $0x18,%r8
  cmp    $0x18,%rdx
  jne    L16
  jmp    L30
L50:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L35:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rotate_the_rest(double **current_bb, int bb_length, double *pivot, double R[3][3], double **trial_bb) {
  int bb_atom_ctr, i, j;
  for (bb_atom_ctr = 0; bb_atom_ctr < bb_length; bb_atom_ctr++) {
    for (i = 0; i < 3; i++) {
      trial_bb[bb_atom_ctr][i] = 0;
      for (j = 0; j < 3; j++) {
        trial_bb[bb_atom_ctr][i] += R[i][j] * (current_bb[bb_atom_ctr][j] - pivot[j]);
      }
      trial_bb[bb_atom_ctr][i] += pivot[i];
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotate_the_rest>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %rbp
  movslq %esi,%r11
  mov    %rcx,%rbp
  xor    %r10d,%r10d
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  nopl   (%rax)
L36:
  mov    (%r8,%r10,8),%rsi
  mov    (%rbx,%r10,8),%r9
  mov    %rbp,%rcx
  xor    %edx,%edx
L9:
  movq   $0x0,(%rsi,%rdx,1)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
L30:
  movsd  (%r9,%rax,1),%xmm0
  subsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rdx,1)
  cmp    $0x18,%rax
  jne    L30
  addsd  (%rdi,%rdx,1),%xmm1
  add    $0x18,%rcx
  movsd  %xmm1,(%rsi,%rdx,1)
  add    $0x8,%rdx
  cmp    $0x18,%rdx
  jne    L9
  add    $0x1,%r10
  cmp    %r10,%r11
  jne    L36
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotate_the_rest(double **current_bb, int bb_length, double *pivot, double R[3][3], double **trial_bb) {
  int bb_atom_ctr, i, j;
  for (bb_atom_ctr = 0; bb_atom_ctr < bb_length; bb_atom_ctr++) {
    for (i = 0; i < 3; i++) {
      trial_bb[bb_atom_ctr][i] = 0;
      for (j = 0; j < 3; j++) {
        trial_bb[bb_atom_ctr][i] += R[i][j] * (current_bb[bb_atom_ctr][j] - pivot[j]);
      }
      trial_bb[bb_atom_ctr][i] += pivot[i];
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotate_the_rest>:
  endbr64
  test   %esi,%esi
  jle    L2
  movslq %esi,%r9
  pxor   %xmm1,%xmm1
  xor    %esi,%esi
  nopl   (%rax)
L4:
  mov    (%rdi,%rsi,8),%r10
  mov    (%r8,%rsi,8),%rax
  add    $0x1,%rsi
  movq   $0x0,(%rax)
  movsd  (%r10),%xmm0
  subsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  movsd  0x8(%r10),%xmm2
  subsd  0x8(%rdx),%xmm2
  mulsd  0x8(%rcx),%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%rax)
  movsd  0x10(%r10),%xmm0
  subsd  0x10(%rdx),%xmm0
  mulsd  0x10(%rcx),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rax)
  addsd  (%rdx),%xmm0
  movq   $0x0,0x8(%rax)
  movsd  %xmm0,(%rax)
  movsd  (%r10),%xmm0
  subsd  (%rdx),%xmm0
  mulsd  0x18(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rax)
  movsd  0x8(%r10),%xmm2
  subsd  0x8(%rdx),%xmm2
  mulsd  0x20(%rcx),%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rax)
  movsd  0x10(%r10),%xmm0
  subsd  0x10(%rdx),%xmm0
  mulsd  0x28(%rcx),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rax)
  addsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rax)
  movq   $0x0,0x10(%rax)
  movsd  (%r10),%xmm0
  subsd  (%rdx),%xmm0
  mulsd  0x30(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rax)
  movsd  0x8(%r10),%xmm2
  subsd  0x8(%rdx),%xmm2
  mulsd  0x38(%rcx),%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,0x10(%rax)
  movsd  0x10(%r10),%xmm0
  subsd  0x10(%rdx),%xmm0
  mulsd  0x40(%rcx),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x10(%rax)
  addsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rax)
  cmp    %rsi,%r9
  jne    L4
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotate_the_rest(double **current_bb, int bb_length, double *pivot, double R[3][3], double **trial_bb) {
  int bb_atom_ctr, i, j;
  for (bb_atom_ctr = 0; bb_atom_ctr < bb_length; bb_atom_ctr++) {
    for (i = 0; i < 3; i++) {
      trial_bb[bb_atom_ctr][i] = 0;
      for (j = 0; j < 3; j++) {
        trial_bb[bb_atom_ctr][i] += R[i][j] * (current_bb[bb_atom_ctr][j] - pivot[j]);
      }
      trial_bb[bb_atom_ctr][i] += pivot[i];
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rsi
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D7(%rip),%rdx
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    $0x0,%eax
  call   <elapsed_time@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L16
L15:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  addl   $0x1,-0x44(%rbp)
L16:
  cmpl   $0x0,-0x44(%rbp)
  jle    L15
  mov    $0x0,%eax
  call   <elapsed_time@plt>
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: %s %s_%s

assistant: ```c
long do_test(char *prog, const char *file, char *suf) {
  char buf[50];
  snprintf(buf, 50, "%s %s_%s", prog, file, suf);
  elapsed_time();
  for (int i = 0; i < 1; i++) {
    system(buf);
  }
  return elapsed_time() / 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_test>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D4(%rip),%rdx
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    $0x0,%eax
  call   <elapsed_time@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  call   <elapsed_time@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  cltq
  add    $0x40,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string

tool: D4: %s %s_%s

assistant: ```c
long do_test(char *prog, const char *file, char *suf) {
  char buf[50];
  snprintf(buf, 50, "%s %s_%s", prog, file, suf);
  elapsed_time();
  for (int i = 0; i < 1; i++) {
    system(buf);
  }
  return elapsed_time() / 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_test>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    $0x32,%esi
  lea    D9(%rip),%rdx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  xor    %eax,%eax
  call   <elapsed_time@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <elapsed_time@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x40,%rsp
  cltq
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %s %s_%s

assistant: ```c
long do_test(char *prog, const char *file, char *suf) {
  char buf[50];
  snprintf(buf, 50, "%s %s_%s", prog, file, suf);
  elapsed_time();
  for (int i = 0; i < 1; i++) {
    system(buf);
  }
  return elapsed_time() / 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_test>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %rdx,%r9
  mov    $0x32,%esi
  lea    D7(%rip),%rdx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  xor    %eax,%eax
  call   <elapsed_time@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  xor    %eax,%eax
  call   <elapsed_time@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x40,%rsp
  cltq
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: %s %s_%s

assistant: ```c
long do_test(char *prog, const char *file, char *suf) {
  char buf[50];
  snprintf(buf, 50, "%s %s_%s", prog, file, suf);
  elapsed_time();
  for (int i = 0; i < 1; i++) {
    system(buf);
  }
  return elapsed_time() / 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<add_ramp_v>:
  endbr64
  cmp    %r8d,%ecx
  jg     L25
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%edi
  sub    %esi,%edx
  movslq %ecx,%r10
  movslq %esi,%rax
  add    %rdx,%rax
  lea    (%rax,%rax,4),%rcx
  lea    (%rcx,%rcx,4),%rcx
  lea    (%rax,%rcx,4),%rax
  add    %r10,%rax
  lea    0x194(%r9,%rax,4),%rsi
  lea    -0x1(%rdi),%r11d
  lea    0x1(%r8),%r13d
  mov    %edi,%ecx
  add    $0x1,%rdx
  imul   $0xfffffffffffffe6c,%rdx,%r12
  jmp    L118
L13:
  addl   $0x1,(%rax)
  mov    (%rax),%edx
  mov    $0x6,%r14d
  cmp    %r14d,%edx
  cmovg  %r14d,%edx
  mov    %edx,(%rax)
L83:
  add    $0x194,%rax
  cmp    %rsi,%rax
  je     L79
L91:
  cmp    %ecx,%edi
  je     L13
  cmp    %ecx,%r8d
  je     L13
  mov    (%rax),%edx
  add    $0x2,%edx
  mov    $0x6,%r15d
  cmp    %r15d,%edx
  cmovg  %r15d,%edx
  mov    %edx,(%rax)
  mov    %edx,%r15d
  sub    (%rax,%r9,4),%r15d
  cmp    $0x1,%r15d
  jle    L18
  sub    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L83
L18:
  cmp    $0xffffffff,%r15d
  jge    L83
  add    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L83
L79:
  add    $0x1,%ecx
  add    $0x4,%rsi
  add    $0x1,%r11d
  add    $0x1,%r10
  cmp    %r13d,%ecx
  je     L47
L118:
  lea    (%r12,%rsi,1),%rax
  movslq %r11d,%r9
  sub    %r10,%r9
  cmp    %ebp,%ebx
  jle    L91
  jmp    L79
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  ret
```

assistant: ```c
void add_ramp_v(int z[100][101], int ll, int rr, int bb, int tt) {
  int i, j;
  int lim = 8 - 2;
  for (j = bb; j <= tt; ++j) {
    for (i = ll; i <= rr; ++i) {
      if (j == bb || j == tt) {
        z[i][j] = ((z[i][j] + 1) < (lim)) ? (z[i][j] + 1) : (lim);
      } else {
        z[i][j] = ((z[i][j] + 2) < (lim)) ? (z[i][j] + 2) : (lim);
        if (z[i][j] - z[i][j - 1] > 1) {
          z[i][j] = z[i][j] - 1;
        } else if (z[i][j] - z[i][j - 1] < -1) {
          z[i][j] = z[i][j] + 1;
        }
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_ramp_v>:
  endbr64
  cmp    %r8d,%ecx
  jg     L68
  push   %r15
  movslq %esi,%rax
  movslq %ecx,%r10
  push   %r14
  lea    0x1(%r8),%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edx,%r12d
  sub    %esi,%edx
  add    %rdx,%rax
  push   %rbp
  add    $0x1,%rdx
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  imul   $0xfffffffffffffe6c,%rdx,%r8
  lea    (%rax,%rax,4),%rcx
  lea    (%rcx,%rcx,4),%rcx
  lea    -0x1(%rbx),%r11d
  mov    %ebx,%r9d
  lea    (%rax,%rcx,4),%rax
  add    %r10,%rax
  lea    0x194(%rdi,%rax,4),%rcx
  nopl   0x0(%rax)
L54:
  cmp    %r12d,%ebp
  jg     L40
  cmp    %r9d,%ebx
  movslq %r11d,%rdi
  sete   %sil
  cmp    %r9d,%r13d
  sete   %al
  sub    %r10,%rdi
  or     %eax,%esi
  lea    (%r8,%rcx,1),%rax
  jmp    L47
L89:
  addl   $0x1,(%rax)
  mov    (%rax),%edx
  mov    $0x6,%r15d
  cmp    %r15d,%edx
  cmovg  %r15d,%edx
  mov    %edx,(%rax)
L67:
  add    $0x194,%rax
  cmp    %rcx,%rax
  je     L40
L47:
  test   %sil,%sil
  jne    L89
  mov    (%rax),%edx
  mov    $0x6,%r15d
  add    $0x2,%edx
  cmp    %r15d,%edx
  cmovg  %r15d,%edx
  mov    %edx,(%rax)
  mov    %edx,%r15d
  sub    (%rax,%rdi,4),%r15d
  cmp    $0x1,%r15d
  jle    L92
  sub    $0x1,%edx
  add    $0x194,%rax
  mov    %edx,-0x194(%rax)
  cmp    %rcx,%rax
  jne    L47
L40:
  add    $0x1,%r9d
  add    $0x4,%rcx
  add    $0x1,%r11d
  add    $0x1,%r10
  cmp    %r14d,%r9d
  jne    L54
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L92:
  cmp    $0xffffffff,%r15d
  jge    L67
  add    $0x1,%edx
  mov    %edx,(%rax)
  jmp    L67
L68:
  ret
```

assistant: ```c
void add_ramp_v(int z[100][101], int ll, int rr, int bb, int tt) {
  int i, j;
  int lim = 8 - 2;
  for (j = bb; j <= tt; ++j) {
    for (i = ll; i <= rr; ++i) {
      if (j == bb || j == tt) {
        z[i][j] = ((z[i][j] + 1) < (lim)) ? (z[i][j] + 1) : (lim);
      } else {
        z[i][j] = ((z[i][j] + 2) < (lim)) ? (z[i][j] + 2) : (lim);
        if (z[i][j] - z[i][j - 1] > 1) {
          z[i][j] = z[i][j] - 1;
        } else if (z[i][j] - z[i][j - 1] < -1) {
          z[i][j] = z[i][j] + 1;
        }
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_ramp_v>:
  endbr64
  cmp    %r8d,%ecx
  jg     L76
  movslq %esi,%rax
  mov    %edx,%r11d
  mov    %ecx,%r9d
  movslq %ecx,%rcx
  lea    (%rax,%rax,4),%rdx
  push   %rbp
  mov    %esi,%r10d
  lea    (%rdx,%rdx,4),%rdx
  push   %rbx
  mov    %rdi,%rbx
  lea    (%rax,%rdx,4),%rdx
  add    %rcx,%rdx
  lea    (%rdi,%rdx,4),%rdi
  mov    %r11d,%edx
  sub    %esi,%edx
  mov    %r9d,%esi
  add    %rdx,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rax
  add    %rcx,%rax
  lea    0x194(%rbx,%rax,4),%rcx
  lea    0x1(%r8),%ebx
  nopw   0x0(%rax,%rax,1)
L104:
  cmp    %r11d,%r10d
  jg     L29
  cmp    %esi,%r9d
  je     L35
  cmp    %esi,%r8d
  je     L35
  mov    %rdi,%rdx
  jmp    L117
  nopl   0x0(%rax)
L120:
  sub    $0x1,%eax
  mov    %eax,(%rdx)
L92:
  add    $0x194,%rdx
  cmp    %rcx,%rdx
  je     L29
L117:
  mov    (%rdx),%eax
  mov    $0x6,%ebp
  add    $0x2,%eax
  cmp    %ebp,%eax
  cmovg  %ebp,%eax
  mov    %eax,%ebp
  sub    -0x4(%rdx),%ebp
  mov    %eax,(%rdx)
  cmp    $0x1,%ebp
  jg     L120
  cmp    $0xffffffff,%ebp
  jge    L92
  add    $0x1,%eax
  add    $0x194,%rdx
  mov    %eax,-0x194(%rdx)
  cmp    %rcx,%rdx
  jne    L117
  xchg   %ax,%ax
L29:
  add    $0x1,%esi
  add    $0x4,%rdi
  add    $0x4,%rcx
  cmp    %ebx,%esi
  jne    L104
L101:
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L128:
  addl   $0x1,(%rax)
  mov    (%rax),%edx
  mov    $0x6,%ebp
  cmp    %ebp,%edx
  cmovg  %ebp,%edx
  add    $0x194,%rax
  mov    %edx,-0x194(%rax)
  cmp    %rcx,%rax
  jne    L128
  add    $0x1,%esi
  add    $0x4,%rdi
  add    $0x4,%rcx
  cmp    %ebx,%esi
  jne    L104
  jmp    L101
L76:
  ret
```

assistant: ```c
void add_ramp_v(int z[100][101], int ll, int rr, int bb, int tt) {
  int i, j;
  int lim = 8 - 2;
  for (j = bb; j <= tt; ++j) {
    for (i = ll; i <= rr; ++i) {
      if (j == bb || j == tt) {
        z[i][j] = ((z[i][j] + 1) < (lim)) ? (z[i][j] + 1) : (lim);
      } else {
        z[i][j] = ((z[i][j] + 2) < (lim)) ? (z[i][j] + 2) : (lim);
        if (z[i][j] - z[i][j - 1] > 1) {
          z[i][j] = z[i][j] - 1;
        } else if (z[i][j] - z[i][j - 1] < -1) {
          z[i][j] = z[i][j] + 1;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L15
  mov    -0x4(%rbp),%eax
  sub    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void substring(char a[], char b[], int index) {
  int i = index;
  while (i < strlen(a)) {
    b[i - index] = a[i];
    i++;
  }
  b[i - index] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %edx,%r15d
  movslq %edx,%rax
  mov    %rax,%rbx
  mov    %rsi,%r13
  sub    %rax,%r13
  jmp    L11
L17:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %ebx,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L17
  sub    %r15d,%r12d
  movslq %r12d,%r12
  movb   $0x0,(%r14,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void substring(char a[], char b[], int index) {
  int i = index;
  while (i < strlen(a)) {
    b[i - index] = a[i];
    i++;
  }
  b[i - index] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substring>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L16:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void substring(char a[], char b[], int index) {
  int i = index;
  while (i < strlen(a)) {
    b[i - index] = a[i];
    i++;
  }
  b[i - index] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<substring>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edx,%rbx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl (%r12,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L11
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void substring(char a[], char b[], int index) {
  int i = index;
  while (i < strlen(a)) {
    b[i - index] = a[i];
    i++;
  }
  b[i - index] = '\0';
}
```