ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mus_char_to_ldouble>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L29
L17:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L29:
  cmpl   $0x7,-0x1c(%rbp)
  jle    L17
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double mus_char_to_ldouble(const unsigned char *inp) {
  double o;
  int i;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  for (i = 0; i < 8; i++)
    outp[i] = inp[i];
  return (o);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mus_char_to_ldouble>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
L16:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L16
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double mus_char_to_ldouble(const unsigned char *inp) {
  double o;
  int i;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  for (i = 0; i < 8; i++)
    outp[i] = inp[i];
  return (o);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mus_char_to_ldouble>:
  endbr64
  movsd  (%rdi),%xmm0
  ret
```

assistant: ```c
double mus_char_to_ldouble(const unsigned char *inp) {
  double o;
  int i;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  for (i = 0; i < 8; i++)
    outp[i] = inp[i];
  return (o);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mus_char_to_ldouble>:
  endbr64
  movsd  (%rdi),%xmm0
  ret
```

assistant: ```c
double mus_char_to_ldouble(const unsigned char *inp) {
  double o;
  int i;
  unsigned char *outp;
  outp = (unsigned char *)&o;
  for (i = 0; i < 8; i++)
    outp[i] = inp[i];
  return (o);
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2c_smbus_read_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%r8
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  je     L6
  mov    $0xffffffff,%eax
  jmp    L4
L6:
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
__s32 i2c_smbus_read_byte(int file) {
  union i2c_smbus_data data;
  if (i2c_smbus_access(file, 1, 0, 1, &data))
    return -1;
  else
    return 0x0FF & data.byte;
}
```
user: What is the c source code of the assembly code below:

```asm
<i2c_smbus_read_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r8
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L5
  movzbl 0x4(%rsp),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L9
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_read_byte(int file) {
  union i2c_smbus_data data;
  if (i2c_smbus_access(file, 1, 0, 1, &data))
    return -1;
  else
    return 0x0FF & data.byte;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<i2c_smbus_read_byte>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r8
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L11
  movzbl 0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L11:
  mov    $0xffffffff,%eax
  jmp    L13
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_read_byte(int file) {
  union i2c_smbus_data data;
  if (i2c_smbus_access(file, 1, 0, 1, &data))
    return -1;
  else
    return 0x0FF & data.byte;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i2c_smbus_read_byte>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r8
  call   <i2c_smbus_access@plt>
  test   %rax,%rax
  jne    L12
  movzbl 0x4(%rsp),%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L12:
  mov    $0xffffffff,%eax
  jmp    L9
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__s32 i2c_smbus_read_byte(int file) {
  union i2c_smbus_data data;
  if (i2c_smbus_access(file, 1, 0, 1, &data))
    return -1;
  else
    return 0x0FF & data.byte;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  jne    L70
L8:
  mov    %rsp,%rdx
  mov    0x8(%rbx),%rdi
  lea    D54(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L59
  cmpl   $0x0,(%rsp)
  jg     L3
L59:
  lea    D30(%rip),%rdi
  call   <usage@plt>
L3:
  lea    0x4(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  lea    D54(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L36
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%eax
  jbe    L37
L36:
  lea    D7(%rip),%rdi
  call   <usage@plt>
L37:
  mov    0x4(%rsp),%ecx
  cmp    $0x1d,%ecx
  jg     L91
  mov    $0x1,%eax
  shl    %cl,%eax
  cmp    (%rsp),%eax
  jle    L86
L91:
  mov    %rsp,%rcx
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <jerasure_matrix_to_bitmatrix@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%esi
  mov    %esi,%edx
  imul   %esi,%edx
  test   %edx,%edx
  jle    L125
  mov    %edx,%edx
  lea    (%rax,%rdx,4),%rdx
  mov    $0x0,%ebx
L26:
  add    (%rax),%ebx
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L26
L25:
  mov    (%rsp),%edi
  call   <cauchy_n_ones@plt>
  mov    %eax,%esi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%ecx
  mov    %esi,%edx
  mov    %rbp,%rdi
  call   <jerasure_print_bitmatrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L70:
  mov    $0x0,%edi
  call   <usage@plt>
  jmp    L8
L86:
  lea    D48(%rip),%rdi
  call   <usage@plt>
  jmp    L91
L125:
  mov    $0x0,%ebx
  jmp    L25
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D54
type_infered: string
name: parse_data
arguments: data_label: D30
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string
name: parse_data
arguments: data_label: D64
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D48
type_infered: string

tool: D54: %d

tool: D30: Bad n

tool: D7: Bad w

tool: D64: # Ones: %d


tool: D17: Bitmatrix has %d ones


tool: D48: n is too big

assistant: ```c
int main(int argc, char **argv) {
  int n, i, no, w;
  int *bitmatrix;
  if (argc != 3)
    usage(NULL);
  if (sscanf(argv[1], "%d", &n) == 0 || n <= 0)
    usage("Bad n");
  if (sscanf(argv[2], "%d", &w) == 0 || w <= 0 || w > 32)
    usage("Bad w");
  if (w < 30 && n >= (1 << w))
    usage("n is too big");
  bitmatrix = jerasure_matrix_to_bitmatrix(1, 1, w, &n);
  no = 0;
  for (i = 0; i < w * w; i++)
    no += bitmatrix[i];
  printf("# Ones: %d\n", cauchy_n_ones(n, w));
  printf("\n");
  printf("Bitmatrix has %d ones\n", no);
  printf("\n");
  jerasure_print_bitmatrix(bitmatrix, w, w, w);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x3,%edi
  je     L19
  xor    %edi,%edi
  call   <usage@plt>
L19:
  mov    %rsp,%r12
  lea    D44(%rip),%r13
  mov    0x8(%rbp),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L117
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L117
L4:
  mov    0x10(%rbp),%rdi
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L97
  mov    0x4(%rsp),%edx
  lea    -0x1(%rdx),%eax
  cmp    $0x1f,%eax
  jbe    L53
L97:
  lea    D9(%rip),%rdi
  call   <usage@plt>
  mov    0x4(%rsp),%edx
L53:
  cmp    $0x1d,%edx
  jg     L68
  mov    $0x1,%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  cmp    (%rsp),%eax
  jle    L71
L68:
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <jerasure_matrix_to_bitmatrix@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%r12
  mov    %esi,%ebp
  imul   %esi,%ebp
  test   %ebp,%ebp
  je     L110
  lea    (%rax,%rbp,4),%rdx
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L106:
  add    (%rax),%ebp
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L106
L110:
  mov    (%rsp),%edi
  call   <cauchy_n_ones@plt>
  lea    D28(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  mov    %esi,%ecx
  mov    %esi,%edx
  call   <jerasure_print_bitmatrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L117:
  lea    D54(%rip),%rdi
  call   <usage@plt>
  jmp    L4
L71:
  lea    D59(%rip),%rdi
  call   <usage@plt>
  mov    0x4(%rsp),%edx
  jmp    L68
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D44
type: string
name: read_data
arguments: label: D9
type: string
name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D54
type: string
name: read_data
arguments: label: D59
type: string

tool: D44: %d

tool: D9: Bad w

tool: D28: # Ones: %d


tool: D14: Bitmatrix has %d ones


tool: D54: Bad n

tool: D59: n is too big

assistant: ```c
int main(int argc, char **argv) {
  int n, i, no, w;
  int *bitmatrix;
  if (argc != 3)
    usage(NULL);
  if (sscanf(argv[1], "%d", &n) == 0 || n <= 0)
    usage("Bad n");
  if (sscanf(argv[2], "%d", &w) == 0 || w <= 0 || w > 32)
    usage("Bad w");
  if (w < 30 && n >= (1 << w))
    usage("n is too big");
  bitmatrix = jerasure_matrix_to_bitmatrix(1, 1, w, &n);
  no = 0;
  for (i = 0; i < w * w; i++)
    no += bitmatrix[i];
  printf("# Ones: %d\n", cauchy_n_ones(n, w));
  printf("\n");
  printf("Bitmatrix has %d ones\n", no);
  printf("\n");
  jerasure_print_bitmatrix(bitmatrix, w, w, w);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<echo_read_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_input@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_output@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <evbuffer_add_buffer@plt>
  nop
  leave
  ret
```

assistant: ```c
void echo_read_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *input = bufferevent_get_input(bev);
  struct evbuffer *output = bufferevent_get_output(bev);
  evbuffer_add_buffer(output, input);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<echo_read_cb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <bufferevent_get_input@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <bufferevent_get_output@plt>
  mov    %rax,%rdi
  mov    %rbp,%rsi
  call   <evbuffer_add_buffer@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void echo_read_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *input = bufferevent_get_input(bev);
  struct evbuffer *output = bufferevent_get_output(bev);
  evbuffer_add_buffer(output, input);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<echo_read_cb>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <bufferevent_get_input@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <bufferevent_get_output@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1090 <evbuffer_add_buffer@plt>
```

assistant: ```c
void echo_read_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *input = bufferevent_get_input(bev);
  struct evbuffer *output = bufferevent_get_output(bev);
  evbuffer_add_buffer(output, input);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<min_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L37:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L11:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L37
  nop
  pop    %rbp
  ret
```

assistant: ```c
void min_max(int A[], int N, int *min, int *max) {
  int i;
  *min = *max = *A;
  for (i = 1; i < N; i++) {
    if (*(A + i) > *max)
      *max = *(A + i);
    if (*(A + i) < *min)
      *min = *(A + i);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<min_max>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  cmp    $0x1,%esi
  jle    L3
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%esi
  lea    0x8(%rdi,%rsi,4),%r8
  jmp    L48
L22:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L3
L48:
  mov    %rax,%rdi
  mov    (%rax),%esi
  cmp    (%rcx),%esi
  jle    L21
  mov    %esi,(%rcx)
L21:
  mov    (%rdi),%esi
  cmp    (%rdx),%esi
  jge    L22
  mov    %esi,(%rdx)
  jmp    L22
L3:
  ret
```

assistant: ```c
void min_max(int A[], int N, int *min, int *max) {
  int i;
  *min = *max = *A;
  for (i = 1; i < N; i++) {
    if (*(A + i) > *max)
      *max = *(A + i);
    if (*(A + i) < *min)
      *min = *(A + i);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min_max>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  cmp    $0x1,%esi
  jle    L24
  sub    $0x2,%esi
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rsi,4),%rdi
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%rax),%esi
  cmp    (%rcx),%esi
  jle    L10
  mov    %esi,(%rcx)
L10:
  cmp    (%rdx),%esi
  jge    L8
  mov    %esi,(%rdx)
L8:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L27
L24:
  ret
```

assistant: ```c
void min_max(int A[], int N, int *min, int *max) {
  int i;
  *min = *max = *A;
  for (i = 1; i < N; i++) {
    if (*(A + i) > *max)
      *max = *(A + i);
    if (*(A + i) < *min)
      *min = *(A + i);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min_max>:
  endbr64
  mov    (%rdi),%eax
  mov    %eax,(%rcx)
  mov    %eax,(%rdx)
  cmp    $0x1,%esi
  jle    L10
  sub    $0x2,%esi
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rsi,4),%rdi
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rax),%esi
  cmp    (%rcx),%esi
  jle    L16
  mov    %esi,(%rcx)
L16:
  cmp    (%rdx),%esi
  jge    L13
  mov    %esi,(%rdx)
L13:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L1
L10:
  ret
```

assistant: ```c
void min_max(int A[], int N, int *min, int *max) {
  int i;
  *min = *max = *A;
  for (i = 1; i < N; i++) {
    if (*(A + i) > *max)
      *max = *(A + i);
    if (*(A + i) < *min)
      *min = *(A + i);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jodirmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <showjobs@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int jodirmd(argc, argv)
char **argv;
{
  showjobs(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jodirmd>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <showjobs@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int jodirmd(argc, argv)
char **argv;
{
  showjobs(0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jodirmd>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <showjobs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int jodirmd(argc, argv)
char **argv;
{
  showjobs(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jodirmd>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <showjobs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int jodirmd(argc, argv)
char **argv;
{
  showjobs(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L8
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(int arr[], int left, int right) {
  int mid;
  if (left < right) {
    mid = (left + right) / 2;
    mergeSort(arr, left, mid);
    mergeSort(arr, mid + 1, right);
    merge(arr, left, mid, right);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L5
  ret
L5:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSort(int arr[], int left, int right) {
  int mid;
  if (left < right) {
    mid = (left + right) / 2;
    mergeSort(arr, left, mid);
    mergeSort(arr, mid + 1, right);
    merge(arr, left, mid, right);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L12:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t strcmp(const uint8_t *a, const uint8_t *b) {
  while (*a == *b && *a != '\0') {
    a++;
    b++;
  }
  return *a - *b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  test   %al,%al
  je     L32
  cmp    %cl,%al
  jne    L32
  mov    $0x1,%edx
L11:
  movzbl (%rdi,%rdx,1),%eax
  movzbl (%rsi,%rdx,1),%ecx
  add    $0x1,%rdx
  test   %al,%al
  je     L32
  cmp    %cl,%al
  je     L11
L32:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int64_t strcmp(const uint8_t *a, const uint8_t *b) {
  while (*a == *b && *a != '\0') {
    a++;
    b++;
  }
  return *a - *b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  mov    $0x1,%edx
  cmp    %al,%cl
  je     L11
  jmp    L3
  nopl   (%rax)
L16:
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L3
L11:
  test   %al,%al
  jne    L16
L3:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int64_t strcmp(const uint8_t *a, const uint8_t *b) {
  while (*a == *b && *a != '\0') {
    a++;
    b++;
  }
  return *a - *b;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  mov    $0x1,%edx
  cmp    %al,%cl
  je     L38
  jmp    L2
  nopl   (%rax)
L23:
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L2
L38:
  test   %al,%al
  jne    L23
L2:
  sub    %ecx,%eax
  ret
```

assistant: ```c
int64_t strcmp(const uint8_t *a, const uint8_t *b) {
  while (*a == *b && *a != '\0') {
    a++;
    b++;
  }
  return *a - *b;
}
```