ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<identifier>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%r12
  add    $0x1,%rbx
L17:
  movsbl (%r12),%edi
  movslq %ebx,%rbp
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl (%r12),%eax
  jne    L24
  cmp    $0x24,%al
  je     L24
  movb   $0x0,0x0(%r13,%rbp,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *identifier(char *expr, char *name) {
  register int l;
  l = 0;
  while (isalnum(*expr) || *expr == '$')
    name[l++] = *expr++;
  name[l] = '\0';
  return expr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hex_deflate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  cmp    %rax,%rcx
  jb     L75
  jmp    L47
L70:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L46
L37:
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L46:
  cmpl   $0x3,-0x8(%rbp)
  jbe    L37
  movl   $0x0,-0x8(%rbp)
  jmp    L60
L21:
  mov    $0x2,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  sarl   $0x8,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L60:
  cmpl   $0x2,-0x8(%rbp)
  jbe    L21
  addl   $0x4,-0x4(%rbp)
  addq   $0x4,-0x20(%rbp)
  addq   $0x3,-0x18(%rbp)
L47:
  mov    -0x4(%rbp),%eax
  cmp    %rax,-0x30(%rbp)
  ja     L70
  jmp    L31
L75:
  nop
L31:
  pop    %rbp
  ret
```

assistant: ```c
void hex_deflate(char *dstbuf, const char *srcbuf, size_t dst_wordcount, size_t src_wordcount) {
  int32_t word;
  unsigned int i = 0, blk = 0;
  if (dst_wordcount * 8 < src_wordcount * 6)
    return;
  while (blk < src_wordcount) {
    word = 0;
    for (i = 0; i < 4; i++)
      word = (word << 6) + srcbuf[i];
    for (i = 0; i < 3; i++) {
      dstbuf[2 - i] = (word & 0xff);
      word >>= 8;
    }
    blk += 4;
    srcbuf += 4;
    dstbuf += 3;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_deflate>:
  endbr64
  shl    $0x3,%rdx
  lea    (%rcx,%rcx,2),%rax
  add    %rax,%rax
  cmp    %rax,%rdx
  jb     L4
  mov    %rdi,%r8
  mov    %rcx,%r10
  test   %rcx,%rcx
  je     L4
  push   %rbx
  lea    0x4(%rsi),%rdi
  mov    %rsi,%r9
  mov    $0x0,%ebx
  mov    $0x4,%r11d
  sub    %esi,%r11d
  jmp    L22
L54:
  mov    %al,0x2(%r8)
  movzbl %ah,%ecx
  mov    %cl,0x1(%r8)
  sar    $0x10,%eax
  mov    %al,(%r8)
  lea    (%r11,%r9,1),%eax
  add    $0x4,%r9
  add    $0x3,%r8
  add    $0x4,%rdi
  mov    %eax,%eax
  cmp    %r10,%rax
  jae    L12
L22:
  mov    %r9,%rdx
  mov    %ebx,%eax
L57:
  shl    $0x6,%eax
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L57
  jmp    L54
L12:
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void hex_deflate(char *dstbuf, const char *srcbuf, size_t dst_wordcount, size_t src_wordcount) {
  int32_t word;
  unsigned int i = 0, blk = 0;
  if (dst_wordcount * 8 < src_wordcount * 6)
    return;
  while (blk < src_wordcount) {
    word = 0;
    for (i = 0; i < 4; i++)
      word = (word << 6) + srcbuf[i];
    for (i = 0; i < 3; i++) {
      dstbuf[2 - i] = (word & 0xff);
      word >>= 8;
    }
    blk += 4;
    srcbuf += 4;
    dstbuf += 3;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_deflate>:
  endbr64
  lea    (%rcx,%rcx,2),%rax
  shl    $0x3,%rdx
  mov    %rdi,%r8
  mov    %rcx,%r9
  add    %rax,%rax
  cmp    %rax,%rdx
  jb     L34
  test   %rcx,%rcx
  je     L34
  mov    $0x4,%r10d
  lea    0x4(%rsi),%rdi
  sub    %esi,%r10d
  nopl   0x0(%rax)
L10:
  mov    %rsi,%rdx
  xor    %eax,%eax
L27:
  movsbl (%rdx),%ecx
  shl    $0x6,%eax
  add    $0x1,%rdx
  add    %ecx,%eax
  cmp    %rdx,%rdi
  jne    L27
  mov    %al,0x2(%r8)
  movzbl %ah,%ecx
  sar    $0x10,%eax
  add    $0x3,%r8
  mov    %al,-0x3(%r8)
  lea    (%r10,%rsi,1),%eax
  add    $0x4,%rdi
  add    $0x4,%rsi
  mov    %cl,-0x2(%r8)
  cmp    %r9,%rax
  jb     L10
L34:
  ret
```

assistant: ```c
void hex_deflate(char *dstbuf, const char *srcbuf, size_t dst_wordcount, size_t src_wordcount) {
  int32_t word;
  unsigned int i = 0, blk = 0;
  if (dst_wordcount * 8 < src_wordcount * 6)
    return;
  while (blk < src_wordcount) {
    word = 0;
    for (i = 0; i < 4; i++)
      word = (word << 6) + srcbuf[i];
    for (i = 0; i < 3; i++) {
      dstbuf[2 - i] = (word & 0xff);
      word >>= 8;
    }
    blk += 4;
    srcbuf += 4;
    dstbuf += 3;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hex_deflate>:
  endbr64
  lea    (%rcx,%rcx,2),%rax
  shl    $0x3,%rdx
  add    %rax,%rax
  cmp    %rax,%rdx
  jb     L22
  test   %rcx,%rcx
  je     L22
  mov    $0x4,%r8d
  sub    %esi,%r8d
  nopw   0x0(%rax,%rax,1)
L4:
  movsbl (%rsi),%eax
  movsbl 0x1(%rsi),%edx
  add    $0x3,%rdi
  shl    $0x6,%eax
  add    %edx,%eax
  movsbl 0x2(%rsi),%edx
  shl    $0x6,%eax
  add    %eax,%edx
  movsbl 0x3(%rsi),%eax
  shl    $0x6,%edx
  add    %edx,%eax
  mov    %al,-0x1(%rdi)
  mov    %ah,-0x2(%rdi)
  sar    $0x10,%eax
  mov    %al,-0x3(%rdi)
  lea    (%r8,%rsi,1),%eax
  add    $0x4,%rsi
  cmp    %rcx,%rax
  jb     L4
L22:
  ret
```

assistant: ```c
void hex_deflate(char *dstbuf, const char *srcbuf, size_t dst_wordcount, size_t src_wordcount) {
  int32_t word;
  unsigned int i = 0, blk = 0;
  if (dst_wordcount * 8 < src_wordcount * 6)
    return;
  while (blk < src_wordcount) {
    word = 0;
    for (i = 0; i < 4; i++)
      word = (word << 6) + srcbuf[i];
    for (i = 0; i < 3; i++) {
      dstbuf[2 - i] = (word & 0xff);
      word >>= 8;
    }
    blk += 4;
    srcbuf += 4;
    dstbuf += 3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<search_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L59
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
  movq   $0x0,-0x8(%rbp)
  jmp    L56
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L45
  addq   $0x1,-0x8(%rbp)
  jmp    L56
L45:
  subq   $0x1,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L31
L56:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *search_ext(char *file_name) {
  int len;
  char *ext;
  ext = file_name + strlen(file_name) - 1;
  while (ext != file_name) {
    if (*ext == '/') {
      ext = NULL;
      break;
    } else if (*ext == '.') {
      ext++;
      break;
    }
    ext--;
  }
  return ext;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<search_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  je     L55
L50:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L58
  cmp    $0x2e,%dl
  je     L28
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L50
  jmp    L55
L28:
  add    $0x1,%rax
  jmp    L55
L58:
  mov    $0x0,%eax
L55:
  pop    %rbx
  ret
```

assistant: ```c
char *search_ext(char *file_name) {
  int len;
  char *ext;
  ext = file_name + strlen(file_name) - 1;
  while (ext != file_name) {
    if (*ext == '/') {
      ext = NULL;
      break;
    } else if (*ext == '.') {
      ext++;
      break;
    }
    ext--;
  }
  return ext;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<search_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jne    L31
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L43:
  cmp    $0x2e,%dl
  je     L5
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L11
L31:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L43
  xor    %eax,%eax
L11:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *search_ext(char *file_name) {
  int len;
  char *ext;
  ext = file_name + strlen(file_name) - 1;
  while (ext != file_name) {
    if (*ext == '/') {
      ext = NULL;
      break;
    } else if (*ext == '.') {
      ext++;
      break;
    }
    ext--;
  }
  return ext;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<search_ext>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jne    L27
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    $0x2e,%dl
  je     L38
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L47
L27:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jne    L42
  xor    %eax,%eax
L47:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *search_ext(char *file_name) {
  int len;
  char *ext;
  ext = file_name + strlen(file_name) - 1;
  while (ext != file_name) {
    if (*ext == '/') {
      ext = NULL;
      break;
    } else if (*ext == '.') {
      ext++;
      break;
    }
    ext--;
  }
  return ext;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  jmp    L17
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jg     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shr(int n, char *str, int len) {
  while (n > 0) {
    str[n] = str[n - 1];
    n--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shr>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdx
  lea    (%rsi,%rdx,1),%rax
  lea    -0x1(%rsi,%rdx,1),%rcx
  lea    -0x1(%rdi),%edx
  sub    %rdx,%rcx
L7:
  movzbl -0x1(%rax),%edx
  mov    %dl,(%rax)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L7
L5:
  ret
```

assistant: ```c
void shr(int n, char *str, int len) {
  while (n > 0) {
    str[n] = str[n - 1];
    n--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shr>:
  endbr64
  test   %edi,%edi
  jle    L8
  movslq %edi,%rdx
  sub    $0x1,%edi
  movslq %edi,%rax
  lea    -0x1(%rdx),%r8
  lea    0x1(%rsi),%rdi
  sub    %rax,%r8
  add    %rsi,%r8
  mov    %r8,%rsi
  jmp    1050 <memmove@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void shr(int n, char *str, int len) {
  while (n > 0) {
    str[n] = str[n - 1];
    n--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<shr>:
  endbr64
  test   %edi,%edi
  jle    L9
  movslq %edi,%rdx
  sub    $0x1,%edi
  movslq %edi,%rax
  lea    -0x1(%rdx),%r8
  lea    0x1(%rsi),%rdi
  sub    %rax,%r8
  add    %rsi,%r8
  mov    %r8,%rsi
  jmp    1050 <memmove@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void shr(int n, char *str, int len) {
  while (n > 0) {
    str[n] = str[n - 1];
    n--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5,%edi
  call   <generate@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L33
L35:
  movl   $0x0,-0x1c(%rbp)
  jmp    L17
L48:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L48
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x20(%rbp)
L33:
  cmpl   $0x4,-0x20(%rbp)
  jle    L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: %d 

assistant: ```c
int main(void) {
  int i, j;
  int *columnSizes;
  int **res = generate(5, &columnSizes);
  for (i = 0; i < 5; i++) {
    for (j = 0; j < columnSizes[i]; j++) {
      printf("%d ", res[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x5,%edi
  call   <generate@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D6(%rip),%r13
L1:
  mov    $0x0,%ebx
  mov    (%rsp),%rax
  cmpl   $0x0,(%rax,%rbp,1)
  jle    L6
L37:
  mov    (%r12),%rax
  mov    (%rax,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  mov    (%rsp),%rax
  cmp    %ebx,(%rax,%rbp,1)
  jg     L37
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbp
  add    $0x8,%r12
  cmp    $0x14,%rbp
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d 

assistant: ```c
int main(void) {
  int i, j;
  int *columnSizes;
  int **res = generate(5, &columnSizes);
  for (i = 0; i < 5; i++) {
    for (j = 0; j < columnSizes[i]; j++) {
      printf("%d ", res[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x5,%edi
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <generate@plt>
  mov    %rax,%r12
L1:
  mov    (%rsp),%rax
  xor    %ebx,%ebx
  mov    (%rax,%rbp,1),%eax
  test   %eax,%eax
  jle    L20
  nopl   0x0(%rax)
L6:
  mov    (%r12),%rax
  mov    %r13,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    (%rsp),%rax
  cmp    %ebx,(%rax,%rbp,1)
  jg     L6
L20:
  mov    $0xa,%edi
  add    $0x4,%rbp
  add    $0x8,%r12
  call   <putchar@plt>
  cmp    $0x14,%rbp
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: %d 

assistant: ```c
int main(void) {
  int i, j;
  int *columnSizes;
  int **res = generate(5, &columnSizes);
  for (i = 0; i < 5; i++) {
    for (j = 0; j < columnSizes[i]; j++) {
      printf("%d ", res[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x5,%edi
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <generate@plt>
  mov    %rax,%r12
L10:
  mov    (%rsp),%rax
  xor    %ebx,%ebx
  mov    (%rax,%rbp,1),%eax
  test   %eax,%eax
  jle    L25
  nopl   0x0(%rax)
L27:
  mov    (%r12),%rax
  mov    %r13,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    (%rsp),%rax
  cmp    %ebx,(%rax,%rbp,1)
  jg     L27
L25:
  mov    $0xa,%edi
  add    $0x4,%rbp
  add    $0x8,%r12
  call   <putchar@plt>
  cmp    $0x14,%rbp
  jne    L10
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: %d 

assistant: ```c
int main(void) {
  int i, j;
  int *columnSizes;
  int **res = generate(5, &columnSizes);
  for (i = 0; i < 5; i++) {
    for (j = 0; j < columnSizes[i]; j++) {
      printf("%d ", res[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L50:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  jmp    L6
L2:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x53,%al
  jne    L45
  mov    -0x78(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x54,%al
  jne    L45
  mov    -0x78(%rbp),%eax
  add    $0x2,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  jne    L45
  mov    -0x78(%rbp),%eax
  add    $0x3,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x50,%al
  jne    L45
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  jmp    L101
L45:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L82
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L82
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x20,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L113
L82:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L113:
  addl   $0x1,-0x78(%rbp)
L6:
  mov    -0x74(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jne    L2
  movl   $0x0,-0x78(%rbp)
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L50
L101:
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D0
type: string

tool: D9: Insert text:

tool: D0: %s

assistant: ```c
int main() {
  int i, n = 0;
  char a[100];
  printf("Insert text:\n");
  while (1) {
    scanf("%s", a);
    i = strlen(a);
    while (i != n) {
      if ((a[n] == 'S') && (a[n + 1] == 'T') && (a[n + 2] == 'O') && (a[n + 3] == 'P')) {
        printf("\n");
        return 0;
      } else {
        if ((a[n] >= 'a') && (a[n] <= 'z')) {
          printf("%c", a[n] - 32);
        } else {
          printf("%c", a[n]);
        }
      }
      n++;
    }
    n = 0;
    printf(" ");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%r12
  jmp    L109
L14:
  cmpb   $0x54,0x1(%rbx)
  je     L7
L22:
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L71
L7:
  cmpb   $0x4f,0x2(%rbx)
  jne    L22
  cmpb   $0x50,0x3(%rbx)
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  movsbl %dil,%edi
  sub    $0x20,%edi
  call   <putchar@plt>
L71:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L89
L93:
  movzbl (%rbx),%edi
  cmp    $0x53,%dil
  je     L14
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  jbe    L1
  jmp    L22
L89:
  mov    $0x20,%edi
  call   <putchar@plt>
L109:
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L89
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%rbp
  jmp    L93
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D16: Insert text:

tool: D11: %s

assistant: ```c
int main() {
  int i, n = 0;
  char a[100];
  printf("Insert text:\n");
  while (1) {
    scanf("%s", a);
    i = strlen(a);
    while (i != n) {
      if ((a[n] == 'S') && (a[n + 1] == 'T') && (a[n + 2] == 'O') && (a[n + 3] == 'P')) {
        printf("\n");
        return 0;
      } else {
        if ((a[n] >= 'a') && (a[n] <= 'z')) {
          printf("%c", a[n] - 32);
        } else {
          printf("%c", a[n]);
        }
      }
      n++;
    }
    n = 0;
    printf(" ");
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%rdi
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x1(%rsp),%r13
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L80
  lea    -0x1(%rax),%ebx
  mov    %rbp,%r14
  add    %r13,%rbx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L104:
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  ja     L46
  sub    $0x20,%edi
  add    $0x1,%r14
  movsbl %dil,%edi
  call   <putchar@plt>
  cmp    %rbx,%r14
  je     L80
L62:
  movsbl (%r14),%edi
  cmp    $0x53,%dil
  jne    L104
  cmpb   $0x54,0x1(%r14)
  je     L76
L46:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %rbx,%r14
  jne    L62
L80:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L57
  nop
L76:
  cmpb   $0x4f,0x2(%r14)
  jne    L46
  cmpb   $0x50,0x3(%r14)
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D15
data_type: string

tool: D0: Insert text:

tool: D15: %s

assistant: ```c
int main() {
  int i, n = 0;
  char a[100];
  printf("Insert text:\n");
  while (1) {
    scanf("%s", a);
    i = strlen(a);
    while (i != n) {
      if ((a[n] == 'S') && (a[n + 1] == 'T') && (a[n + 2] == 'O') && (a[n + 3] == 'P')) {
        printf("\n");
        return 0;
      } else {
        if ((a[n] >= 'a') && (a[n] <= 'z')) {
          printf("%c", a[n] - 32);
        } else {
          printf("%c", a[n]);
        }
      }
      n++;
    }
    n = 0;
    printf(" ");
  }
  printf("\n");
}
```