ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<syscon_load_quaddobl_Laurential>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rsi
  call   <syscon_quaddobl_Laurent_size_limit@plt>
  mov    $0x4,%esi
  mov    (%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rsi
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    $0x239,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,%r12d
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L21
  mov    %rbx,%rax
  mov    %rbp,%rdx
  mov    %edi,%ecx
  lea    (%rbx,%rcx,4),%rsi
L3:
  mov    (%rax),%ecx
  mov    %cl,(%rdx)
  add    $0x4,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L3
L21:
  movslq %edi,%rdi
  movb   $0x0,0x0(%rbp,%rdi,1)
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %r12d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_load_quaddobl_Laurential(int k, int *nc, char *p) {
  int fail, i, szl;
  int *buffer;
  int size = k;
  double *c;
  fail = syscon_quaddobl_Laurent_size_limit(k, &szl);
  buffer = (int *)calloc(szl, sizeof(int));
  fail = _ada_use_c2phc(569, &size, buffer, c);
  for (i = 0; i < size; i++)
    p[i] = (char)buffer[i];
  p[size] = '\0';
  free(buffer);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<syscon_load_quaddobl_Laurential>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %edi,0x4(%rsp)
  call   <syscon_quaddobl_Laurent_size_limit@plt>
  mov    (%rsp),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  lea    0x4(%rsp),%rsi
  xor    %ecx,%ecx
  mov    $0x239,%edi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <_ada_use_c2phc@plt>
  mov    0x4(%rsp),%r8d
  mov    %eax,%r12d
  test   %r8d,%r8d
  jle    L15
  mov    %r8d,%eax
  mov    %rbp,%rdx
  mov    %rbx,%rcx
  lea    0x0(%rbp,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rdx),%esi
  add    $0x4,%rdx
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rdi,%rdx
  jne    L20
L15:
  movslq %r8d,%r8
  mov    %rbp,%rdi
  movb   $0x0,(%rbx,%r8,1)
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_load_quaddobl_Laurential(int k, int *nc, char *p) {
  int fail, i, szl;
  int *buffer;
  int size = k;
  double *c;
  fail = syscon_quaddobl_Laurent_size_limit(k, &szl);
  buffer = (int *)calloc(szl, sizeof(int));
  fail = _ada_use_c2phc(569, &size, buffer, c);
  for (i = 0; i < size; i++)
    p[i] = (char)buffer[i];
  p[size] = '\0';
  free(buffer);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L33
L14:
  mov    -0x7e4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L41
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L41:
  cmpl   $0x50,-0x7e4(%rbp)
  jle    L33
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L33:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getlines@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: the line's long is %d


assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlines(line, 1000)) > 0) {
    printf("the line's long is %d\n", len);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s\n", longest);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  lea    D9(%rip),%r12
L21:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getlines@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L18
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jl     L47
L3:
  cmp    $0x50,%ebx
  jle    L21
  lea    0x3f0(%rsp),%rdi
  call   <puts@plt>
  jmp    L21
L47:
  mov    %rsp,%rsi
  lea    0x3f0(%rsp),%rdi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L3
L18:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: the line's long is %d


assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlines(line, 1000)) > 0) {
    printf("the line's long is %d\n", len);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s\n", longest);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L54:
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getlines@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L4
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L38
L2:
  cmp    $0x50,%ebx
  jle    L54
  lea    0x3f0(%rsp),%rdi
  call   <puts@plt>
  jmp    L54
L38:
  lea    0x3f0(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <copy@plt>
  jmp    L2
  nopl   (%rax)
L4:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: the line's long is %d


assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlines(line, 1000)) > 0) {
    printf("the line's long is %d\n", len);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s\n", longest);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax)
L3:
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getlines@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L24
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L19
L55:
  cmp    $0x50,%ebx
  jle    L3
  lea    0x3f0(%rsp),%rdi
  call   <puts@plt>
  jmp    L3
L19:
  lea    0x3f0(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <copy@plt>
  jmp    L55
  nopl   (%rax)
L24:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: the line's long is %d


assistant: ```c
main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlines(line, 1000)) > 0) {
    printf("the line's long is %d\n", len);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
    if (len > 80) {
      printf("%s\n", longest);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  shr    %rax
  imul   %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type: string
name: read_data
arguments: data_label: D13
type: string

tool: D14: %llu %llu

tool: D13: %llu

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long long int a, b;
  scanf("%llu %llu", &a, &b);
  printf("%llu", (a + b) * (b / 2));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    %rax,%rsi
  add    0x8(%rsp),%rsi
  shr    %rax
  imul   %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D8
type: string

tool: D7: %llu %llu

tool: D8: %llu

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long long int a, b;
  scanf("%llu %llu", &a, &b);
  printf("%llu", (a + b) * (b / 2));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  add    %rax,%rsi
  shr    %rax
  imul   %rax,%rsi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string
name: retrieve_data
arguments: data_tag: D3
type: string

tool: D6: %llu %llu

tool: D3: %llu

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long long int a, b;
  scanf("%llu %llu", &a, &b);
  printf("%llu", (a + b) * (b / 2));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rsi
  lea    D11(%rip),%rdi
  add    %rax,%rsi
  shr    %rax
  imul   %rax,%rsi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
data_type: string
name: unpack_data
arguments: data_tag: D11
data_type: string

tool: D12: %llu %llu

tool: D11: %llu

assistant: ```c
int main(int argc, char const *argv[]) {
  unsigned long long int a, b;
  scanf("%llu %llu", &a, &b);
  printf("%llu", (a + b) * (b / 2));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  sarl   -0x14(%rbp)
L2:
  cmpl   $0x3f,-0x14(%rbp)
  jg     L9
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t min_run(uint32_t n) {
  uint32_t r;
  r = 0;
  while (n >= 64) {
    r |= n & 1u;
    n >>= 1;
  }
  return n + r;
}
```
user: What is the c source code of the assembly code below:

```asm
<min_run>:
  endbr64
  cmp    $0x3f,%edi
  jle    L19
  mov    $0x0,%eax
L27:
  mov    %edi,%edx
  and    $0x1,%edx
  or     %edx,%eax
  sar    %edi
  cmp    $0x3f,%edi
  jg     L27
L17:
  add    %edi,%eax
  ret
L19:
  mov    $0x0,%eax
  jmp    L17
```

assistant: ```c
uint32_t min_run(uint32_t n) {
  uint32_t r;
  r = 0;
  while (n >= 64) {
    r |= n & 1u;
    n >>= 1;
  }
  return n + r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<min_run>:
  endbr64
  cmp    $0x3f,%edi
  jle    L7
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %edi,%edx
  sar    %edi
  and    $0x1,%edx
  or     %edx,%eax
  cmp    $0x3f,%edi
  jg     L13
  add    %edi,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t min_run(uint32_t n) {
  uint32_t r;
  r = 0;
  while (n >= 64) {
    r |= n & 1u;
    n >>= 1;
  }
  return n + r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<min_run>:
  endbr64
  cmp    $0x3f,%edi
  jle    L18
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %edi,%edx
  sar    %edi
  and    $0x1,%edx
  or     %edx,%eax
  cmp    $0x3f,%edi
  jg     L10
  add    %edi,%eax
  ret
  nopl   0x0(%rax)
L18:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t min_run(uint32_t n) {
  uint32_t r;
  r = 0;
  while (n >= 64) {
    r |= n & 1u;
    n >>= 1;
  }
  return n + r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ftell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
long int ftell(FILE *stream) {
  errno = ESPIPE;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ftell>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int ftell(FILE *stream) {
  errno = ESPIPE;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ftell>:
  endbr64
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int ftell(FILE *stream) {
  errno = ESPIPE;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ftell>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
long int ftell(FILE *stream) {
  errno = ESPIPE;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x10,%eax
  jle    L0
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L0:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D73
data_type: string
name: read_data
arguments: tag: D77
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D49
data_type: string
name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D71
data_type: string

tool: D6: Masukkan umur anda = 

tool: D73: %i

tool: D77: Anda layak mendapatkan SIM


tool: D8: Anda layak mendapatkan KTP

tool: D23: Anda belum layak mendapatkan SIM


tool: D49: Anda belum layak mendapatkan KTP

tool: D12: 



tool: D71: PAUSE

assistant: ```c
int main(int argc, char *argv[]) {
  int umur;
  printf("Masukkan umur anda = ");
  scanf("%i", &umur);
  if (umur >= 17) {
    printf("Anda layak mendapatkan SIM\n");
    printf("Anda layak mendapatkan KTP");
  } else {
    printf("Anda belum layak mendapatkan SIM\n");
    printf("Anda belum layak mendapatkan KTP");
  }
  printf("\n\n");
  system("PAUSE");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x10,0x4(%rsp)
  jle    L15
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
L2:
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L15:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D68
type: string
name: read_data
arguments: label: D27
type: string
name: read_data
arguments: label: D74
type: string
name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D73
type: string
name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D42
type: string
name: read_data
arguments: label: D15
type: string

tool: D68: Masukkan umur anda = 

tool: D27: %i

tool: D74: Anda layak mendapatkan SIM


tool: D1: Anda layak mendapatkan KTP

tool: D73: 



tool: D14: PAUSE

tool: D42: Anda belum layak mendapatkan SIM


tool: D15: Anda belum layak mendapatkan KTP

assistant: ```c
int main(int argc, char *argv[]) {
  int umur;
  printf("Masukkan umur anda = ");
  scanf("%i", &umur);
  if (umur >= 17) {
    printf("Anda layak mendapatkan SIM\n");
    printf("Anda layak mendapatkan KTP");
  } else {
    printf("Anda belum layak mendapatkan SIM\n");
    printf("Anda belum layak mendapatkan KTP");
  }
  printf("\n\n");
  system("PAUSE");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D58(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x10,0x4(%rsp)
  jle    L12
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
L21:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L12:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D58
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D62
data_type: string
name: retrieve_data
arguments: data_tag: D46
data_type: string
name: retrieve_data
arguments: data_tag: D23
data_type: string
name: retrieve_data
arguments: data_tag: D41
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string
name: retrieve_data
arguments: data_tag: D51
data_type: string

tool: D58: Masukkan umur anda = 

tool: D11: %i

tool: D62: Anda layak mendapatkan SIM


tool: D46: Anda layak mendapatkan KTP

tool: D23: 



tool: D41: PAUSE

tool: D3: Anda belum layak mendapatkan SIM


tool: D51: Anda belum layak mendapatkan KTP

assistant: ```c
int main(int argc, char *argv[]) {
  int umur;
  printf("Masukkan umur anda = ");
  scanf("%i", &umur);
  if (umur >= 17) {
    printf("Anda layak mendapatkan SIM\n");
    printf("Anda layak mendapatkan KTP");
  } else {
    printf("Anda belum layak mendapatkan SIM\n");
    printf("Anda belum layak mendapatkan KTP");
  }
  printf("\n\n");
  system("PAUSE");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x10,0x4(%rsp)
  jle    L15
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
L4:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D39
datatype: string
name: retrieve_data
arguments: data_label: D61
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D39: Masukkan umur anda = 

tool: D61: %i

tool: D21: Anda layak mendapatkan SIM


tool: D10: Anda layak mendapatkan KTP

tool: D5: 



tool: D23: PAUSE

tool: D2: Anda belum layak mendapatkan SIM


tool: D3: Anda belum layak mendapatkan KTP

assistant: ```c
int main(int argc, char *argv[]) {
  int umur;
  printf("Masukkan umur anda = ");
  scanf("%i", &umur);
  if (umur >= 17) {
    printf("Anda layak mendapatkan SIM\n");
    printf("Anda layak mendapatkan KTP");
  } else {
    printf("Anda belum layak mendapatkan SIM\n");
    printf("Anda belum layak mendapatkan KTP");
  }
  printf("\n\n");
  system("PAUSE");
  return 0;
}
```