ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xffffffff,%edx
  je     L24
  lea    D25(%rip),%r12
  lea    D28(%rip),%r13
  jmp    L45
  xchg   %ax,%ax
L5:
  mov    %r12,%rdi
  call   <puts@plt>
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xffffffff,%edx
  je     L24
L45:
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L5
  test   %edx,%edx
  je     L5
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  call   <tri@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L16
  xchg   %ax,%ax
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D28
type: string

tool: D0: %d

tool: D25: 1

tool: D28: %ld


assistant: ```c
void main() {
  int input;
  scanf("%d", &input);
  while (input != -1) {
    if (input % 2 == 1 || input == 0)
      printf("1\n");
    else
      printf("%ld\n", tri(input / 2));
    scanf("%d", &input);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xffffffff,%edx
  je     L32
  lea    D4(%rip),%r12
  lea    D11(%rip),%r13
  jmp    L28
  xchg   %ax,%ax
L35:
  mov    %r12,%rdi
  call   <puts@plt>
L48:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xffffffff,%edx
  je     L32
L28:
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  je     L35
  test   %edx,%edx
  je     L35
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  call   <tri@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
  xchg   %ax,%ax
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D9: %d

tool: D4: 1

tool: D11: %ld


assistant: ```c
void main() {
  int input;
  scanf("%d", &input);
  while (input != -1) {
    if (input % 2 == 1 || input == 0)
      printf("1\n");
    else
      printf("%ld\n", tri(input / 2));
    scanf("%d", &input);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x68,%al
  jne    L33
  mov    $0x1,%eax
  jmp    L35
L33:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L26
  mov    $0x1,%eax
  jmp    L35
L26:
  mov    $0x0,%eax
L35:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: 0x

assistant: ```c
bool isHex(char *str) {
  char *temp = malloc(strlen(str) + 1);
  strcpy(temp, str);
  if (temp[strlen(temp) - 1] == 'h')
    return true;
  if (!strncmp(temp, "0x", 2))
    return true;
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isHex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  mov    $0x1,%edx
  cmpb   $0x68,-0x1(%rbx,%rax,1)
  je     L9
  mov    $0x2,%edx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
L9:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string

tool: D2: 0x

assistant: ```c
bool isHex(char *str) {
  char *temp = malloc(strlen(str) + 1);
  strcpy(temp, str);
  if (temp[strlen(temp) - 1] == 'h')
    return true;
  if (!strncmp(temp, "0x", 2))
    return true;
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isHex>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1,%r8d
  cltq
  cmpb   $0x68,-0x1(%rbp,%rax,1)
  je     L7
  mov    $0x2,%edx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L7:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: 0x

assistant: ```c
bool isHex(char *str) {
  char *temp = malloc(strlen(str) + 1);
  strcpy(temp, str);
  if (temp[strlen(temp) - 1] == 'h')
    return true;
  if (!strncmp(temp, "0x", 2))
    return true;
  return false;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isHex>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1,%r8d
  cltq
  cmpb   $0x68,-0x1(%rbp,%rax,1)
  je     L4
  mov    $0x2,%edx
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
L4:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: 0x

assistant: ```c
bool isHex(char *str) {
  char *temp = malloc(strlen(str) + 1);
  strcpy(temp, str);
  if (temp[strlen(temp) - 1] == 'h')
    return true;
  if (!strncmp(temp, "0x", 2))
    return true;
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
test3() {
  int a;
  int b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
test3() {
  int a;
  int b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
test3() {
  int a;
  int b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
test3() {
  int a;
  int b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stb_log2_floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3fff,-0x4(%rbp)
  ja     L73
  cmpl   $0xf,-0x4(%rbp)
  ja     L3
  mov    -0x4(%rbp),%eax
  lea    D21(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movsbl %al,%eax
  jmp    L103
L3:
  cmpl   $0x1ff,-0x4(%rbp)
  ja     L44
  mov    -0x4(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0x5,%eax
  jmp    L103
L44:
  mov    -0x4(%rbp),%eax
  shr    $0xa,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0xa,%eax
  jmp    L103
L73:
  cmpl   $0xffffff,-0x4(%rbp)
  ja     L48
  cmpl   $0x7ffff,-0x4(%rbp)
  ja     L90
  mov    -0x4(%rbp),%eax
  shr    $0xf,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0xf,%eax
  jmp    L103
L90:
  mov    -0x4(%rbp),%eax
  shr    $0x14,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0x14,%eax
  jmp    L103
L48:
  cmpl   $0x1fffffff,-0x4(%rbp)
  ja     L98
  mov    -0x4(%rbp),%eax
  shr    $0x19,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0x19,%eax
  jmp    L103
L98:
  mov    -0x4(%rbp),%eax
  shr    $0x1e,%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  add    $0x1e,%eax
L103:
  pop    %rbp
  ret
```

assistant: ```c
int stb_log2_floor(unsigned int n) {
  static signed char log2_4[16] = {-1, 0, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3};
  if (n < (1U << 14))
    if (n < (1U << 4))
      return 0 + log2_4[n];
    else if (n < (1U << 9))
      return 5 + log2_4[n >> 5];
    else
      return 10 + log2_4[n >> 10];
  else if (n < (1U << 24))
    if (n < (1U << 19))
      return 15 + log2_4[n >> 15];
    else
      return 20 + log2_4[n >> 20];
  else if (n < (1U << 29))
    return 25 + log2_4[n >> 25];
  else
    return 30 + log2_4[n >> 30];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_pawn_moves>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_pawn_moves_white@plt>
  jmp    L8
L15:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_pawn_moves_black@plt>
L8:
  leave
  ret
```

assistant: ```c
struct node *get_pawn_moves(struct node *currentNode, char *board, int isWhitesMove, struct node *parentNode) {
  if (isWhitesMove == 1) {
    return get_pawn_moves_white(currentNode, board, parentNode);
  } else {
    return get_pawn_moves_black(currentNode, board, parentNode);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_pawn_moves>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%eax
  mov    %rcx,%rdx
  cmp    $0x1,%eax
  je     L1
  call   <get_pawn_moves_black@plt>
L10:
  add    $0x8,%rsp
  ret
L1:
  call   <get_pawn_moves_white@plt>
  jmp    L10
```

assistant: ```c
struct node *get_pawn_moves(struct node *currentNode, char *board, int isWhitesMove, struct node *parentNode) {
  if (isWhitesMove == 1) {
    return get_pawn_moves_white(currentNode, board, parentNode);
  } else {
    return get_pawn_moves_black(currentNode, board, parentNode);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_pawn_moves>:
  endbr64
  mov    %edx,%r8d
  mov    %rcx,%rdx
  cmp    $0x1,%r8d
  je     L2
  jmp    1070 <get_pawn_moves_black@plt>
  nopl   (%rax)
L2:
  jmp    1060 <get_pawn_moves_white@plt>
```

assistant: ```c
struct node *get_pawn_moves(struct node *currentNode, char *board, int isWhitesMove, struct node *parentNode) {
  if (isWhitesMove == 1) {
    return get_pawn_moves_white(currentNode, board, parentNode);
  } else {
    return get_pawn_moves_black(currentNode, board, parentNode);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_pawn_moves>:
  endbr64
  mov    %edx,%r8d
  mov    %rcx,%rdx
  cmp    $0x1,%r8d
  je     L1
  jmp    1070 <get_pawn_moves_black@plt>
  nopl   (%rax)
L1:
  jmp    1060 <get_pawn_moves_white@plt>
```

assistant: ```c
struct node *get_pawn_moves(struct node *currentNode, char *board, int isWhitesMove, struct node *parentNode) {
  if (isWhitesMove == 1) {
    return get_pawn_moves_white(currentNode, board, parentNode);
  } else {
    return get_pawn_moves_black(currentNode, board, parentNode);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  test   %edx,%edx
  je     L59
  cmp    %rax,%rcx
  je     L59
  cmp    %rcx,%rax
  jae    L43
L20:
  mov    %rcx,%rdi
  lea    0x1(%rdi),%rcx
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  movzbl (%rdi),%edi
  mov    %dil,(%rsi)
  sub    $0x1,%edx
  test   %edx,%edx
  jne    L20
  jmp    L59
L43:
  mov    %edx,%esi
  add    %rsi,%rcx
  mov    %edx,%esi
  add    %rsi,%rax
L37:
  sub    $0x1,%rcx
  sub    $0x1,%rax
  movzbl (%rcx),%esi
  mov    %sil,(%rax)
  sub    $0x1,%edx
  test   %edx,%edx
  jne    L37
L59:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
bcopy(src, dst, length) register char *src, *dst;
register unsigned int length;
{
  if (length && src != dst)
    if (dst < src)
      do
        *dst++ = *src++;
      while (--length);
    else {
      src += length;
      dst += length;
      do
        *--dst = *--src;
      while (--length);
    }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bcopy>:
  endbr64
  test   %edx,%edx
  je     L26
  cmp    %rsi,%rdi
  je     L26
  jbe    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L20:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L20
L26:
  mov    $0x0,%eax
  ret
L17:
  mov    %edx,%eax
  add    %rax,%rdi
  add    %rax,%rsi
  lea    -0x1(%rdx),%eax
  mov    $0xfffffffffffffffe,%rcx
  sub    %rax,%rcx
  mov    $0xffffffffffffffff,%rax
L46:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L46
  jmp    L26
```

assistant: ```c
bcopy(src, dst, length) register char *src, *dst;
register unsigned int length;
{
  if (length && src != dst)
    if (dst < src)
      do
        *dst++ = *src++;
      while (--length);
    else {
      src += length;
      dst += length;
      do
        *--dst = *--src;
      while (--length);
    }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bcopy>:
  endbr64
  test   %edx,%edx
  je     L6
  cmp    %rsi,%rdi
  je     L6
  jbe    L8
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L16:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L16
L6:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %edx,%eax
  mov    $0xfffffffffffffffe,%rcx
  add    %rax,%rdi
  add    %rax,%rsi
  lea    -0x1(%rdx),%eax
  sub    %rax,%rcx
  mov    $0xffffffffffffffff,%rax
  nopl   0x0(%rax)
L39:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L39
  xor    %eax,%eax
  ret
```

assistant: ```c
bcopy(src, dst, length) register char *src, *dst;
register unsigned int length;
{
  if (length && src != dst)
    if (dst < src)
      do
        *dst++ = *src++;
      while (--length);
    else {
      src += length;
      dst += length;
      do
        *--dst = *--src;
      while (--length);
    }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bcopy>:
  endbr64
  mov    %rsi,%rax
  mov    %edx,%esi
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L121
  cmp    %rax,%rdi
  je     L121
  jbe    L170
  lea    0x1(%rdi),%r8
  mov    %rax,%rdi
  lea    -0x1(%rsi),%edx
  sub    %r8,%rdi
  cmp    $0xe,%rdi
  jbe    L156
  cmp    $0x6,%edx
  jbe    L156
  cmp    $0xe,%edx
  jbe    L159
  mov    %esi,%edi
  xor    %edx,%edx
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L15:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L15
  mov    %esi,%r10d
  mov    %esi,%edx
  and    $0xfffffff0,%r10d
  mov    %r10d,%r9d
  sub    %r10d,%edx
  lea    (%rcx,%r9,1),%r8
  lea    (%rax,%r9,1),%rdi
  cmp    %r10d,%esi
  je     L121
  lea    -0x1(%rdx),%r10d
  mov    %edx,%esi
  cmp    $0x6,%r10d
  jbe    L101
L64:
  mov    (%rcx,%r9,1),%rcx
  mov    %rcx,(%rax,%r9,1)
  mov    %esi,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%edx
  add    %rcx,%r8
  add    %rcx,%rdi
  cmp    %eax,%esi
  je     L121
  lea    -0x1(%rdx),%r10d
L101:
  movzbl (%r8),%eax
  mov    %al,(%rdi)
  test   %r10d,%r10d
  je     L121
  movzbl 0x1(%r8),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%edx
  je     L121
  movzbl 0x2(%r8),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%edx
  je     L121
  movzbl 0x3(%r8),%eax
  mov    %al,0x3(%rdi)
  cmp    $0x4,%edx
  je     L121
  movzbl 0x4(%r8),%eax
  mov    %al,0x4(%rdi)
  cmp    $0x5,%edx
  je     L121
  movzbl 0x5(%r8),%eax
  mov    %al,0x5(%rdi)
  cmp    $0x6,%edx
  je     L121
  movzbl 0x6(%r8),%eax
  mov    %al,0x6(%rdi)
L121:
  xor    %eax,%eax
  ret
L170:
  mov    %esi,%edx
  mov    $0xfffffffffffffffe,%rdi
  add    %rdx,%rcx
  add    %rax,%rdx
  lea    -0x1(%rsi),%eax
  sub    %rax,%rdi
  mov    $0xffffffffffffffff,%rax
  nopl   0x0(%rax)
L144:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%rdx,%rax,1)
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L144
  xor    %eax,%eax
  ret
L159:
  mov    %esi,%edx
  mov    %rax,%rdi
  mov    %rcx,%r8
  xor    %r9d,%r9d
  jmp    L64
  nopl   0x0(%rax)
L156:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L192:
  movzbl (%rcx,%rdx,1),%edi
  mov    %dil,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L192
  jmp    L121
```

assistant: ```c
bcopy(src, dst, length) register char *src, *dst;
register unsigned int length;
{
  if (length && src != dst)
    if (dst < src)
      do
        *dst++ = *src++;
      while (--length);
    else {
      src += length;
      dst += length;
      do
        *--dst = *--src;
      while (--length);
    }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<blah>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x20,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x40,-0x18(%rbp)
  jne    L14
  nop
  mov    $0x0,%eax
  call   <aa@plt>
  jmp    L40
L14:
  nop
L40:
  cmpl   $0x1,-0x4(%rbp)
  jle    L49
  nop
  mov    $0x0,%eax
  call   <aos@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L49:
  nop
  cmpl   $0x0,-0x4(%rbp)
  jle    L12
  nop
  movl   $0x0,-0x8(%rbp)
L23:
  mov    $0x0,%eax
  call   <aob@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L19
  jmp    L23
L12:
  nop
  jmp    L31
L19:
  nop
L31:
  nop
  nop
  leave
  ret
```

assistant: ```c
blah(int code1, int code2) {
  int i;
  int n_sets;
  n_sets = (int)(code1 == 32);
  if (code2 == 64)
    goto L2;
  else
    goto L3;
L2:
  aa();
L3:
  if (n_sets > 1)
    goto L4;
  else
    goto L10;
L4:
  aos();
  i = 0;
  goto L24;
L10:
  if (n_sets > 0)
    goto L25;
  else
    goto L8;
L25:
  i = 0;
L24:
  aob();
  i = i + 1;
  if (i < n_sets)
    goto L24;
  else
    goto L8;
L8:
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<blah>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40,%esi
  je     L11
L29:
  cmp    $0x20,%ebx
  je     L22
L26:
  mov    $0x0,%eax
  pop    %rbx
  ret
L11:
  mov    $0x0,%eax
  call   <aa@plt>
  jmp    L29
L22:
  mov    $0x0,%eax
  call   <aob@plt>
  jmp    L26
```

assistant: ```c
blah(int code1, int code2) {
  int i;
  int n_sets;
  n_sets = (int)(code1 == 32);
  if (code2 == 64)
    goto L2;
  else
    goto L3;
L2:
  aa();
L3:
  if (n_sets > 1)
    goto L4;
  else
    goto L10;
L4:
  aos();
  i = 0;
  goto L24;
L10:
  if (n_sets > 0)
    goto L25;
  else
    goto L8;
L25:
  i = 0;
L24:
  aob();
  i = i + 1;
  if (i < n_sets)
    goto L24;
  else
    goto L8;
L8:
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<blah>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40,%esi
  je     L28
  cmp    $0x20,%ebx
  je     L25
L13:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  call   <aa@plt>
  cmp    $0x20,%ebx
  jne    L13
L25:
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <aob@plt>
```

assistant: ```c
blah(int code1, int code2) {
  int i;
  int n_sets;
  n_sets = (int)(code1 == 32);
  if (code2 == 64)
    goto L2;
  else
    goto L3;
L2:
  aa();
L3:
  if (n_sets > 1)
    goto L4;
  else
    goto L10;
L4:
  aos();
  i = 0;
  goto L24;
L10:
  if (n_sets > 0)
    goto L25;
  else
    goto L8;
L25:
  i = 0;
L24:
  aob();
  i = i + 1;
  if (i < n_sets)
    goto L24;
  else
    goto L8;
L8:
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blah>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40,%esi
  je     L25
  cmp    $0x20,%ebx
  je     L16
L15:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  call   <aa@plt>
  cmp    $0x20,%ebx
  jne    L15
L16:
  xor    %eax,%eax
  pop    %rbx
  jmp    1060 <aob@plt>
```

assistant: ```c
blah(int code1, int code2) {
  int i;
  int n_sets;
  n_sets = (int)(code1 == 32);
  if (code2 == 64)
    goto L2;
  else
    goto L3;
L2:
  aa();
L3:
  if (n_sets > 1)
    goto L4;
  else
    goto L10;
L4:
  aos();
  i = 0;
  goto L24;
L10:
  if (n_sets > 0)
    goto L25;
  else
    goto L8;
L25:
  i = 0;
L24:
  aob();
  i = i + 1;
  if (i < n_sets)
    goto L24;
  else
    goto L8;
L8:
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_pages_per_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L12
  mov    -0x18(%rbp),%eax
  mov    $0x1000,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x100,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L12:
  cmpl   $0x7f,-0x18(%rbp)
  jg     L36
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L36:
  movl   $0x200,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int next_pages_per_loop(const int color, const int pages) {
  int pages_next_loop;
  if (color == -1) {
    pages_next_loop = ((pages) < (4096) ? (pages) : (4096));
    pages_next_loop = ((pages_next_loop) > (256) ? (pages_next_loop) : (256));
  } else {
    if (pages < 512 / 4) {
      pages_next_loop = 0;
    } else {
      pages_next_loop = 512;
    }
  }
  return pages_next_loop;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_pages_per_loop>:
  endbr64
  cmp    $0xffffffff,%edi
  je     L6
  cmp    $0x7f,%esi
  setg   %al
  movzbl %al,%eax
  shl    $0x9,%eax
  ret
L6:
  mov    $0x1000,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    $0x100,%eax
  cmp    %eax,%esi
  cmovge %esi,%eax
  ret
```

assistant: ```c
int next_pages_per_loop(const int color, const int pages) {
  int pages_next_loop;
  if (color == -1) {
    pages_next_loop = ((pages) < (4096) ? (pages) : (4096));
    pages_next_loop = ((pages_next_loop) > (256) ? (pages_next_loop) : (256));
  } else {
    if (pages < 512 / 4) {
      pages_next_loop = 0;
    } else {
      pages_next_loop = 512;
    }
  }
  return pages_next_loop;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<next_pages_per_loop>:
  endbr64
  cmp    $0xffffffff,%edi
  je     L3
  xor    %eax,%eax
  cmp    $0x7f,%esi
  setg   %al
  shl    $0x9,%eax
  ret
  nopl   (%rax)
L3:
  mov    $0x1000,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    $0x100,%eax
  cmp    %eax,%esi
  cmovge %esi,%eax
  ret
```

assistant: ```c
int next_pages_per_loop(const int color, const int pages) {
  int pages_next_loop;
  if (color == -1) {
    pages_next_loop = ((pages) < (4096) ? (pages) : (4096));
    pages_next_loop = ((pages_next_loop) > (256) ? (pages_next_loop) : (256));
  } else {
    if (pages < 512 / 4) {
      pages_next_loop = 0;
    } else {
      pages_next_loop = 512;
    }
  }
  return pages_next_loop;
}
```