ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<renderQuad>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  pxor   %xmm2,%xmm2
  movsd  D18(%rip),%xmm1
  movapd %xmm2,%xmm0
  call   <glTranslatef@plt>
  movsd  D2(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  divsd  %xmm1,%xmm3
  movapd %xmm3,%xmm1
  call   <glScalef@plt>
  test   %ebp,%ebp
  jle    L17
  mov    $0x0,%ebx
L13:
  mov    %r12d,%edi
  call   <renderQuadLine@plt>
  pxor   %xmm2,%xmm2
  mov    D10(%rip),%rax
  movq   %rax,%xmm1
  movapd %xmm2,%xmm0
  call   <glTranslatef@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L13
L17:
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: f64
name: extract_symbolic_data
arguments: label: D2
type: f64
name: extract_symbolic_data
arguments: label: D10
type: f32[2]

tool: D18: 0.5

tool: D2: 1

tool: {"D10": [0.0,-1.875]}

assistant: ```c
void renderQuad(int xSplines, int ySplines) {
  int i;
  glPushMatrix();
  glTranslatef(0.0, 0.5, 0.0);
  glScalef(1.0, 1.0 / ySplines, 1.0);
  for (i = 0; i < ySplines; ++i) {
    renderQuadLine(xSplines);
    glTranslatef(0.0, -1.0, 0.0);
  }
  glPopMatrix();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<renderQuad>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <glPushMatrix@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  movsd  D14(%rip),%xmm1
  call   <glTranslatef@plt>
  pxor   %xmm1,%xmm1
  movsd  D29(%rip),%xmm0
  cvtsi2sd %ebp,%xmm1
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm3
  movapd %xmm3,%xmm1
  call   <glScalef@plt>
  test   %ebp,%ebp
  jle    L9
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L11:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <renderQuadLine@plt>
  mov    D6(%rip),%rax
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <glTranslatef@plt>
  cmp    %ebx,%ebp
  jne    L11
L9:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <glPopMatrix@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: f64
name: parse_data
arguments: data_label: D29
data_type: f64
name: parse_data
arguments: data_label: D6
data_type: f32[2]

tool: D14: 0.5

tool: D29: 1

tool: {"D6": [0.0,-1.875]}

assistant: ```c
void renderQuad(int xSplines, int ySplines) {
  int i;
  glPushMatrix();
  glTranslatef(0.0, 0.5, 0.0);
  glScalef(1.0, 1.0 / ySplines, 1.0);
  for (i = 0; i < ySplines; ++i) {
    renderQuadLine(xSplines);
    glTranslatef(0.0, -1.0, 0.0);
  }
  glPopMatrix();
}
```
user: What is the c source code of the assembly code below:

```asm
<renderQuad>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  call   <glPushMatrix@plt>
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  movsd  D25(%rip),%xmm1
  call   <glTranslatef@plt>
  pxor   %xmm1,%xmm1
  movsd  D9(%rip),%xmm0
  cvtsi2sd %ebp,%xmm1
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm3
  movapd %xmm3,%xmm1
  call   <glScalef@plt>
  test   %ebp,%ebp
  jle    L3
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L1:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <renderQuadLine@plt>
  mov    D23(%rip),%rax
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm0
  movq   %rax,%xmm1
  call   <glTranslatef@plt>
  cmp    %ebx,%ebp
  jne    L1
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <glPopMatrix@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_infered: f64
name: unpack_data
arguments: data_label: D9
type_infered: f64
name: unpack_data
arguments: data_label: D23
type_infered: f32[2]

tool: D25: 0.5

tool: D9: 1

tool: {"D23": [0.0,-1.875]}

assistant: ```c
void renderQuad(int xSplines, int ySplines) {
  int i;
  glPushMatrix();
  glTranslatef(0.0, 0.5, 0.0);
  glScalef(1.0, 1.0 / ySplines, 1.0);
  for (i = 0; i < ySplines; ++i) {
    renderQuadLine(xSplines);
    glTranslatef(0.0, -1.0, 0.0);
  }
  glPopMatrix();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<roast_password>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  lea    D5(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <strcpy@plt>
  mov    $0x0,%ebp
  mov    $0x2,%r13d
  lea    D58(%rip),%r14
L14:
  mov    %ebp,%r12d
  movzbl (%r15,%rbp,1),%ebx
  test   %bl,%bl
  je     L10
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  xor    (%r14,%rdx,1),%bl
  movsbl %bl,%edx
  movslq %r13d,%rdi
  lea    D2(%rip),%rax
  add    %rax,%rdi
  lea    D56(%rip),%rsi
  call   <sprintf@plt>
  add    %eax,%r13d
  add    $0x1,%rbp
  cmp    $0x96,%rbp
  jne    L14
L10:
  lea    D2(%rip),%rax
  movslq %r13d,%r13
  movb   $0x0,(%rax,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D58
datatype: string
name: parse_data
arguments: label: D56
datatype: string

tool: D5: 0x

tool: D58: Tic/Toc

tool: D56: %02x

assistant: ```c
unsigned char *roast_password(char *pass) {
  static char rp[256];
  static char *roast = "Tic/Toc";
  int pos = 2;
  int x;
  strcpy(rp, "0x");
  for (x = 0; (x < 150) && pass[x]; x++)
    pos += sprintf(&rp[pos], "%02x", pass[x] ^ roast[x % strlen(roast)]);
  rp[pos] = '\0';
  return rp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<roast_password>:
  endbr64
  push   %r15
  lea    D41(%rip),%rsi
  lea    D26(%rip),%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    D29(%rip),%rdi
  call   <strcpy@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <strlen@plt>
  movslq %ebp,%rdi
  mov    %r15,%rsi
  mov    %eax,%r9d
  mov    %ebx,%eax
  cltd
  idiv   %r9d
  lea    D29(%rip),%rax
  add    %rax,%rdi
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  xor    %r13d,%ecx
  movsbl %cl,%edx
  call   <sprintf@plt>
  add    %eax,%ebp
  cmp    $0x96,%r14
  je     L2
L8:
  mov    0x8(%rsp),%rax
  mov    %r14d,%ebx
  movzbl (%rax,%r14,1),%r13d
  test   %r13b,%r13b
  jne    L20
L2:
  movslq %ebp,%rbp
  lea    D29(%rip),%rax
  movb   $0x0,(%rax,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D41
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D35
data_type: string

tool: D41: 0x

tool: D26: %02x

tool: D35: Tic/Toc

assistant: ```c
unsigned char *roast_password(char *pass) {
  static char rp[256];
  static char *roast = "Tic/Toc";
  int pos = 2;
  int x;
  strcpy(rp, "0x");
  for (x = 0; (x < 150) && pass[x]; x++)
    pos += sprintf(&rp[pos], "%02x", pass[x] ^ roast[x % strlen(roast)]);
  rp[pos] = '\0';
  return rp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<roast_password>:
  endbr64
  push   %r15
  lea    D44(%rip),%rsi
  lea    D58(%rip),%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    D49(%rip),%rdi
  call   <strcpy@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <strlen@plt>
  movslq %ebp,%rdi
  mov    %r15,%rsi
  mov    %eax,%r9d
  mov    %ebx,%eax
  cltd
  idiv   %r9d
  lea    D49(%rip),%rax
  add    %rax,%rdi
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%ecx
  xor    %r13d,%ecx
  movsbl %cl,%edx
  call   <sprintf@plt>
  add    %eax,%ebp
  cmp    $0x96,%r14
  je     L10
L6:
  mov    0x8(%rsp),%rax
  mov    %r14d,%ebx
  movzbl (%rax,%r14,1),%r13d
  test   %r13b,%r13b
  jne    L0
L10:
  movslq %ebp,%rbp
  lea    D49(%rip),%rax
  movb   $0x0,(%rax,%rbp,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D44
type: string
name: read_data
arguments: data_tag: D58
type: string
name: read_data
arguments: data_tag: D0
type: string

tool: D44: 0x

tool: D58: %02x

tool: D0: Tic/Toc

assistant: ```c
unsigned char *roast_password(char *pass) {
  static char rp[256];
  static char *roast = "Tic/Toc";
  int pos = 2;
  int x;
  strcpy(rp, "0x");
  for (x = 0; (x < 150) && pass[x]; x++)
    pos += sprintf(&rp[pos], "%02x", pass[x] ^ roast[x % strlen(roast)]);
  rp[pos] = '\0';
  return rp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L50
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L25
L50:
  cmpq   $0x0,-0x10(%rbp)
  jns    L25
  mov    $0xffffffff,%eax
  jmp    L63
L25:
  lea    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <waitpid@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L54
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L25
L54:
  mov    -0x18(%rbp),%eax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int run_cmd(char *argv[]) {
  int status = -1;
  int ret = -1;
  pid_t child = 0;
  if ((child = fork()) == 0) {
    execvp(argv[0], argv);
    exit(1);
  } else if (child < 0) {
    return -1;
  }
  do {
    ret = waitpid(child, &status, 0);
  } while (ret == -1 && errno == EINTR);
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<run_cmd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  call   <fork@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L51
  js     L55
L64:
  lea    0x4(%rsp),%rbp
L37:
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  jne    L2
  mov    D10(%rip),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L37
L2:
  mov    0x4(%rsp),%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  mov    %rbp,%rsi
  mov    0x0(%rbp),%rdi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L64
L55:
  mov    $0xffffffff,%eax
  jmp    L13
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int run_cmd(char *argv[]) {
  int status = -1;
  int ret = -1;
  pid_t child = 0;
  if ((child = fork()) == 0) {
    execvp(argv[0], argv);
    exit(1);
  } else if (child < 0) {
    return -1;
  }
  do {
    ret = waitpid(child, &status, 0);
  } while (ret == -1 && errno == EINTR);
  return status;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<run_cmd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  call   <fork@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L38
  js     L21
L49:
  lea    0x4(%rsp),%rbp
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L0:
  mov    D7(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L5
L69:
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  je     L0
L5:
  mov    0x4(%rsp),%eax
L59:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    0x0(%rbp),%rdi
  mov    %rbp,%rsi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L49
L21:
  mov    $0xffffffff,%eax
  jmp    L59
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int run_cmd(char *argv[]) {
  int status = -1;
  int ret = -1;
  pid_t child = 0;
  if ((child = fork()) == 0) {
    execvp(argv[0], argv);
    exit(1);
  } else if (child < 0) {
    return -1;
  }
  do {
    ret = waitpid(child, &status, 0);
  } while (ret == -1 && errno == EINTR);
  return status;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_cmd>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  call   <fork@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  js     L35
L26:
  lea    0x4(%rsp),%rbp
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L37:
  mov    D17(%rip),%rax
  mov    D18(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L12
L59:
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <waitpid@plt>
  cmp    $0xffffffff,%eax
  je     L37
L12:
  mov    0x4(%rsp),%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp),%rdi
  mov    %rbp,%rsi
  call   <execvp@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L26
L35:
  mov    $0xffffffff,%eax
  jmp    L11
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int run_cmd(char *argv[]) {
  int status = -1;
  int ret = -1;
  pid_t child = 0;
  if ((child = fork()) == 0) {
    execvp(argv[0], argv);
    exit(1);
  } else if (child < 0) {
    return -1;
  }
  do {
    ret = waitpid(child, &status, 0);
  } while (ret == -1 && errno == EINTR);
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CStrings__concatenate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <CStrings__len@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <CStrings__len@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  mov    %eax,%edi
  call   <CStrings__check_len@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    $0x1fff,%eax
  jle    L4
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void CStrings__concatenate(char *to, char *from) {
  int i, L = CStrings__len(to);
  CStrings__check_len(L + CStrings__len(from));
  for (i = 0; ((from[i]) && (L + i < 8 * 1024)); i++)
    to[L + i] = from[i];
  to[L + i] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CStrings__concatenate>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  call   <CStrings__len@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <CStrings__len@plt>
  lea    (%rax,%rbp,1),%edi
  call   <CStrings__check_len@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L35
  cmp    $0x1fff,%ebp
  jg     L53
  mov    $0x2001,%esi
  sub    %ebp,%esi
  mov    $0x1,%eax
  movslq %ebp,%rcx
  add    %r12,%rcx
L57:
  mov    %dl,-0x1(%rcx,%rax,1)
  mov    %eax,%edi
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L10
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L57
L10:
  add    %edi,%ebp
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%edi
  jmp    L10
L53:
  mov    $0x0,%edi
  jmp    L10
```

assistant: ```c
void CStrings__concatenate(char *to, char *from) {
  int i, L = CStrings__len(to);
  CStrings__check_len(L + CStrings__len(from));
  for (i = 0; ((from[i]) && (L + i < 8 * 1024)); i++)
    to[L + i] = from[i];
  to[L + i] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CStrings__concatenate>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <CStrings__len@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <CStrings__len@plt>
  lea    (%rax,%rbx,1),%edi
  call   <CStrings__check_len@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L18
  cmp    $0x1fff,%ebx
  jg     L18
  mov    $0x1fff,%ecx
  movslq %ebx,%rdi
  lea    0x1(%rbx),%eax
  mov    %rbp,%rsi
  sub    %ebx,%ecx
  cltq
  sub    %rdi,%rsi
  lea    0x2(%rdi,%rcx,1),%rcx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L18
L36:
  mov    %dl,-0x1(%r12,%rax,1)
  movzbl (%rsi,%rax,1),%edx
  movslq %eax,%rbx
  test   %dl,%dl
  jne    L25
L18:
  movb   $0x0,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CStrings__concatenate(char *to, char *from) {
  int i, L = CStrings__len(to);
  CStrings__check_len(L + CStrings__len(from));
  for (i = 0; ((from[i]) && (L + i < 8 * 1024)); i++)
    to[L + i] = from[i];
  to[L + i] = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CStrings__concatenate>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <CStrings__len@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <CStrings__len@plt>
  lea    (%rax,%rbx,1),%edi
  call   <CStrings__check_len@plt>
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L30
  cmp    $0x1fff,%ebx
  jg     L30
  mov    $0x1fff,%ecx
  movslq %ebx,%rdi
  lea    0x1(%rbx),%eax
  mov    %rbp,%rsi
  sub    %ebx,%ecx
  cltq
  sub    %rdi,%rsi
  lea    0x2(%rdi,%rcx,1),%rcx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L30
L23:
  mov    %dl,-0x1(%r12,%rax,1)
  movzbl (%rsi,%rax,1),%edx
  movslq %eax,%rbx
  test   %dl,%dl
  jne    L9
L30:
  movb   $0x0,(%r12,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void CStrings__concatenate(char *to, char *from) {
  int i, L = CStrings__len(to);
  CStrings__check_len(L + CStrings__len(from));
  for (i = 0; ((from[i]) && (L + i < 8 * 1024)); i++)
    to[L + i] = from[i];
  to[L + i] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utf8_strpos_getpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L38
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L97
L123:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <utf8_getsize_char@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L74
  mov    $0xffffffff,%eax
  jmp    L6
L74:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L62
  cmpq   $0x0,-0x28(%rbp)
  je     L136
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
L136:
  cmpq   $0x0,-0x30(%rbp)
  je     L53
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
L53:
  mov    -0x10(%rbp),%eax
  jmp    L6
L62:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L97:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L123
  mov    $0xffffffff,%eax
  jmp    L6
L38:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_strlen@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L8
  mov    $0xffffffff,%eax
  jmp    L6
L8:
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L77
  mov    $0xffffffff,%eax
  jmp    L6
L77:
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <utf8_strpos_getpos>
L6:
  leave
  ret
```

assistant: ```c
int utf8_strpos_getpos(const char *str, int pos, int *startpos_out, size_t *len_out) {
  int i, n, len;
  if (pos >= 0) {
    for (i = 0, n = 0; str[i];) {
      len = utf8_getsize_char(&str[i]);
      if (len < 0)
        return -1;
      else if (pos == n) {
        if (startpos_out)
          *startpos_out = i;
        if (len_out)
          *len_out = len;
        return i;
      }
      i += len;
      n++;
    }
    return -1;
  } else {
    len = utf8_strlen(str);
    if (len <= 0)
      return -1;
    int newpos = len + pos;
    if (newpos < 0)
      return -1;
    return utf8_strpos_getpos(str, newpos, startpos_out, len_out);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<utf8_strpos_getpos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%r14
  mov    %rcx,%r15
  test   %esi,%esi
  js     L66
  cmpb   $0x0,(%rdi)
  je     L145
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L39:
  call   <utf8_getsize_char@plt>
  test   %eax,%eax
  js     L119
  cmp    %ebp,%r12d
  je     L91
  add    %eax,%ebx
  add    $0x1,%ebp
  movslq %ebx,%rdi
  add    %r13,%rdi
  cmpb   $0x0,(%rdi)
  jne    L39
  mov    $0xffffffff,%ebx
  jmp    L122
L91:
  test   %r14,%r14
  je     L42
  mov    %ebx,(%r14)
L42:
  test   %r15,%r15
  je     L122
  cltq
  mov    %rax,(%r15)
  jmp    L122
L66:
  call   <utf8_strlen@plt>
  test   %eax,%eax
  jle    L99
  mov    %r12d,%esi
  add    %eax,%esi
  js     L53
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rdi
  call   <utf8_strpos_getpos>
  mov    %eax,%ebx
  jmp    L122
L145:
  mov    $0xffffffff,%ebx
  jmp    L122
L119:
  mov    $0xffffffff,%ebx
L122:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  mov    $0xffffffff,%ebx
  jmp    L122
L53:
  mov    $0xffffffff,%ebx
  jmp    L122
```

assistant: ```c
int utf8_strpos_getpos(const char *str, int pos, int *startpos_out, size_t *len_out) {
  int i, n, len;
  if (pos >= 0) {
    for (i = 0, n = 0; str[i];) {
      len = utf8_getsize_char(&str[i]);
      if (len < 0)
        return -1;
      else if (pos == n) {
        if (startpos_out)
          *startpos_out = i;
        if (len_out)
          *len_out = len;
        return i;
      }
      i += len;
      n++;
    }
    return -1;
  } else {
    len = utf8_strlen(str);
    if (len <= 0)
      return -1;
    int newpos = len + pos;
    if (newpos < 0)
      return -1;
    return utf8_strpos_getpos(str, newpos, startpos_out, len_out);
  }
}
```