user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_rand>:
  endbr64
  push   %r12
  lea    D108(%rip),%rdi
  push   %rbp
  push   %rbx
  mov    $0x989680,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0xa,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L29:
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <get_rand_int@plt>
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L29
  xor    %ebx,%ebx
  mov    %rsp,%r12
  lea    D101(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x1,%eax
  cvtsi2sdl (%r12,%rbx,4),%xmm0
  add    $0x1,%rbx
  divsd  D115(%rip),%xmm0
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L0
  movsd  D45(%rip),%xmm0
  lea    D28(%rip),%r12
  mov    $0x1,%eax
  xor    %ebp,%ebp
  mov    %r12,%rdi
  mov    $0x989680,%ebx
  call   <printf@plt>
  mov    D105(%rip),%rax
  lea    D38(%rip),%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L28:
  mov    D105(%rip),%rax
  movq   %rax,%xmm0
  call   <percentage_chance@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  sub    $0x1,%ebx
  jne    L28
  lea    D93(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2sd %ebp,%xmm0
  divsd  D115(%rip),%xmm0
  call   <printf@plt>
  mov    D105(%rip),%rax
  mov    %r12,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D108
type: string
name: extract_symbolic_data
arguments: tag: D36
type: string
name: extract_symbolic_data
arguments: tag: D101
type: string
name: extract_symbolic_data
arguments: tag: D115
type: byte[8]
name: extract_symbolic_data
arguments: tag: D45
type: byte[8]
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D105
type: f64
name: extract_symbolic_data
arguments: tag: D38
type: string
name: extract_symbolic_data
arguments: tag: D93
type: string

tool: D108: 
### RANDOM UTILITY UNIT TEST ###

tool: D36: 
Testing get_rand_int() with %d bins


tool: D101: Bin %d: %lf


tool: {"D115": [0x00,0x00,0x00,0x00,0xd0,0x12,0x63,0x41]}

tool: {"D45": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0x3f]}

tool: D28: Expected fraction: %lf


tool: D105: 0.5

tool: D38: 
Testing percentage_chance() with rate %lf


tool: D93: Percentage chance fraction: %lf


assistant: ```c
int test_rand() {
  int i;
  int num;
  int counter;
  double frac;
  int results[(10)];
  printf("\n### RANDOM UTILITY UNIT TEST ###\n");
  srand(time(NULL));
  printf("\nTesting get_rand_int() with %d bins\n", (10));
  for (i = 0; i < (10); i++)
    results[i] = 0;
  for (i = 0; i < (10000000); i++) {
    num = get_rand_int(0, (10));
    results[num]++;
  }
  for (i = 0; i < (10); i++) {
    frac = (double)results[i] / (10000000);
    printf("Bin %d: %lf\n", i, frac);
  }
  printf("Expected fraction: %lf\n", 1.0 / (10));
  printf("\nTesting percentage_chance() with rate %lf\n", (0.5));
  counter = 0;
  for (i = 0; i < (10000000); i++) {
    if (percentage_chance((0.5)))
      counter++;
  }
  printf("Percentage chance fraction: %lf\n", (double)counter / (10000000));
  printf("Expected fraction: %lf\n", (double)(0.5));
  return 0;
}
```