ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<insertion_asm>:
  endbr64
  mov    $0x1,%r10d
  jmp    L37
  nopl   0x0(%rax)
L3:
  add    $0x1,%r10
  cmp    %r10d,%esi
  jle    L0
L37:
  mov    (%rdi,%r10,4),%r9d
  mov    -0x4(%rdi,%r10,4),%edx
  cmp    %edx,%r9d
  jge    L3
  lea    -0x1(%r10),%rax
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %edx,0x4(%rdi,%rax,4)
  mov    -0x4(%rdi,%rax,4),%edx
  test   %eax,%eax
  lea    0x0(,%rax,4),%r11
  setg   %r8b
  cmp    %edx,%r9d
  setl   %cl
  sub    $0x1,%rax
  test   %cl,%r8b
  jne    L14
  add    $0x1,%r10
  mov    %r9d,(%rdi,%r11,1)
  cmp    %r10d,%esi
  jg     L37
L0:
  ret
```

assistant: ```c
void insertion_asm(int nums[], int len) {
  int i = 1;
  int j;
  int temp1, temp2;
insertion_outer:
  temp1 = nums[i];
  temp2 = nums[i - 1];
  if (temp2 <= temp1)
    goto insertion_if;
  j = i;
insertion_inner:
  nums[j] = temp2;
  j--;
  temp2 = nums[j - 1];
  if (j > 0 && (temp2 > temp1))
    goto insertion_inner;
  nums[j] = temp1;
insertion_if:
  i++;
  if (i < len)
    goto insertion_outer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertion_asm>:
  endbr64
  mov    $0x1,%r10d
  jmp    L20
  nopl   0x0(%rax)
L40:
  add    $0x1,%r10
  cmp    %r10d,%esi
  jle    L43
L20:
  mov    (%rdi,%r10,4),%r9d
  mov    -0x4(%rdi,%r10,4),%edx
  cmp    %edx,%r9d
  jge    L40
  lea    -0x1(%r10),%rax
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %edx,0x4(%rdi,%rax,4)
  mov    -0x4(%rdi,%rax,4),%edx
  test   %eax,%eax
  lea    0x0(,%rax,4),%r11
  setg   %r8b
  cmp    %edx,%r9d
  setl   %cl
  sub    $0x1,%rax
  test   %cl,%r8b
  jne    L37
  add    $0x1,%r10
  mov    %r9d,(%rdi,%r11,1)
  cmp    %r10d,%esi
  jg     L20
L43:
  ret
```

assistant: ```c
void insertion_asm(int nums[], int len) {
  int i = 1;
  int j;
  int temp1, temp2;
insertion_outer:
  temp1 = nums[i];
  temp2 = nums[i - 1];
  if (temp2 <= temp1)
    goto insertion_if;
  j = i;
insertion_inner:
  nums[j] = temp2;
  j--;
  temp2 = nums[j - 1];
  if (j > 0 && (temp2 > temp1))
    goto insertion_inner;
  nums[j] = temp1;
insertion_if:
  i++;
  if (i < len)
    goto insertion_outer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int test1(unsigned long int var_a, unsigned long int var_b) {
  unsigned long int var_z = var_a * var_b;
  return var_z;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
unsigned long int test1(unsigned long int var_a, unsigned long int var_b) {
  unsigned long int var_z = var_a * var_b;
  return var_z;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
unsigned long int test1(unsigned long int var_a, unsigned long int var_b) {
  unsigned long int var_z = var_a * var_b;
  return var_z;
}
```
user: What is the c source code of the assembly code below:

```asm
<test1>:
  endbr64
  mov    %rdi,%rax
  imul   %rsi,%rax
  ret
```

assistant: ```c
unsigned long int test1(unsigned long int var_a, unsigned long int var_b) {
  unsigned long int var_z = var_a * var_b;
  return var_z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rfbLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int rfbLog(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stdout, fmt, arglist);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rfbLog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rfbLog(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stdout, fmt, arglist);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rfbLog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rfbLog(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stdout, fmt, arglist);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfbLog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rfbLog(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stdout, fmt, arglist);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rhs_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    -0x38(%rbp),%edx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <vx@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x38(%rbp),%edx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <vy@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x30(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x34(%rbp),%edx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <c@plt>
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x34(%rbp),%edx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <c@plt>
  mulsd  -0x40(%rbp),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x38(%rbp),%edx
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <vx@plt>
  addsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: f64

tool: D3: 1

assistant: ```c
double rhs_x(double x, double y, double s1, double s2, int I, int Typ) {
  double dummy;
  double c(double x, double y, int I);
  double vx(double x, double y, int Typ);
  double vy(double x, double y, int Typ);
  dummy = (1.0 - vx(x, y, Typ) * s1 - vy(x, y, Typ) * s2);
  return ((c(x, y, I) * c(x, y, I) * s1 / dummy) + vx(x, y, Typ));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rhs_x>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  movsd  %xmm2,(%rsp)
  movq   %xmm3,%r15
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %esi,%edi
  call   <vx@plt>
  movq   %xmm0,%r14
  mov    %r12d,%edi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <vy@plt>
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  D1(%rip),%xmm2
  subsd  %xmm0,%xmm2
  movq   %r15,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
  mov    %r13d,%edi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <c@plt>
  movq   %xmm0,%r14
  mov    %r13d,%edi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <c@plt>
  movq   %r14,%xmm6
  mulsd  %xmm6,%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  mov    %r12d,%edi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <vx@plt>
  addsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
double rhs_x(double x, double y, double s1, double s2, int I, int Typ) {
  double dummy;
  double c(double x, double y, int I);
  double vx(double x, double y, int Typ);
  double vy(double x, double y, int Typ);
  dummy = (1.0 - vx(x, y, Typ) * s1 - vy(x, y, Typ) * s2);
  return ((c(x, y, I) * c(x, y, I) * s1 / dummy) + vx(x, y, Typ));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rhs_x>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x38,%rsp
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm0,0x20(%rsp)
  call   <vx@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm4,%xmm0
  call   <vy@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm4
  mov    %r12d,%edi
  movapd %xmm0,%xmm3
  movsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  mulsd  %xmm2,%xmm0
  movsd  D4(%rip),%xmm2
  subsd  %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm2
  movapd %xmm4,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <c@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  mov    %r12d,%edi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm4,%xmm0
  call   <c@plt>
  movsd  0x20(%rsp),%xmm4
  mulsd  0x10(%rsp),%xmm0
  mov    %ebp,%edi
  mulsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm4,%xmm0
  call   <vx@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: f64

tool: D4: 1

assistant: ```c
double rhs_x(double x, double y, double s1, double s2, int I, int Typ) {
  double dummy;
  double c(double x, double y, int I);
  double vx(double x, double y, int Typ);
  double vy(double x, double y, int Typ);
  dummy = (1.0 - vx(x, y, Typ) * s1 - vy(x, y, Typ) * s2);
  return ((c(x, y, I) * c(x, y, I) * s1 / dummy) + vx(x, y, Typ));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rhs_x>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x38,%rsp
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movsd  %xmm0,0x20(%rsp)
  call   <vx@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  mov    %ebp,%edi
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm4,%xmm0
  call   <vy@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm4
  mov    %r12d,%edi
  movapd %xmm0,%xmm3
  movsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  mulsd  %xmm2,%xmm0
  movsd  D7(%rip),%xmm2
  subsd  %xmm0,%xmm2
  movsd  0x10(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm2
  movapd %xmm4,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <c@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm1
  mov    %r12d,%edi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm4,%xmm0
  call   <c@plt>
  movsd  0x20(%rsp),%xmm4
  mulsd  0x10(%rsp),%xmm0
  mov    %ebp,%edi
  mulsd  0x8(%rsp),%xmm0
  movsd  0x28(%rsp),%xmm1
  divsd  0x18(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm4,%xmm0
  call   <vx@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double rhs_x(double x, double y, double s1, double s2, int I, int Typ) {
  double dummy;
  double c(double x, double y, int I);
  double vx(double x, double y, int Typ);
  double vy(double x, double y, int Typ);
  dummy = (1.0 - vx(x, y, Typ) * s1 - vy(x, y, Typ) * s2);
  return ((c(x, y, I) * c(x, y, I) * s1 / dummy) + vx(x, y, Typ));
}
```
user: Translate the below assembly code into C programming language:

```asm
<LOGGER_DBG>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x8e0,%rsp
  mov    %rdi,-0x8d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L17
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L17:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x8d8(%rbp),%rdx
  mov    -0x8c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x8c4(%rbp),%edx
  mov    -0x8d8(%rbp),%rcx
  lea    -0x8c0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0x8c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    -0x8c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: %s

assistant: ```c
void LOGGER_DBG(const char *fmt, ...) {
  if (2 < 0) {
    return;
  }
  va_list ap;
  char buf[2048];
  va_start(ap, fmt);
  vsprintf((char *)buf, (const char *)fmt, ap);
  va_end(ap);
  printf("%s", buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LOGGER_DBG>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %s

assistant: ```c
void LOGGER_DBG(const char *fmt, ...) {
  if (2 < 0) {
    return;
  }
  va_list ap;
  char buf[2048];
  va_start(ap, fmt);
  vsprintf((char *)buf, (const char *)fmt, ap);
  va_end(ap);
  printf("%s", buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LOGGER_DBG>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_infered: string

tool: D3: %s

assistant: ```c
void LOGGER_DBG(const char *fmt, ...) {
  if (2 < 0) {
    return;
  }
  va_list ap;
  char buf[2048];
  va_start(ap, fmt);
  vsprintf((char *)buf, (const char *)fmt, ap);
  va_end(ap);
  printf("%s", buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LOGGER_DBG>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x810,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: %s

assistant: ```c
void LOGGER_DBG(const char *fmt, ...) {
  if (2 < 0) {
    return;
  }
  va_list ap;
  char buf[2048];
  va_start(ap, fmt);
  vsprintf((char *)buf, (const char *)fmt, ap);
  va_end(ap);
  printf("%s", buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D9
datatype: string

tool: D3: Unitialized x = %i


tool: D9: x with 1+2=%i


assistant: ```c
int main() {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1+2=%i\n", x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string
name: disassemble_data
arguments: data_tag: D17
type: string

tool: D5: Unitialized x = %i


tool: D17: x with 1+2=%i


assistant: ```c
int main() {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1+2=%i\n", x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D0: Unitialized x = %i


tool: D9: x with 1+2=%i


assistant: ```c
int main() {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1+2=%i\n", x);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D0: Unitialized x = %i


tool: D7: x with 1+2=%i


assistant: ```c
int main() {
  int x;
  printf("Unitialized x = %i\n", x);
  x = 1 + 2;
  printf("x with 1+2=%i\n", x);
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  mov    $0xffffffff,%eax
  jmp    L14
L8:
  mov    $0x1,%eax
L14:
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
L51:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L51
  cmpl   $0x0,-0x4(%rbp)
  jns    L39
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L39
L10:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i, sign;
  void reverse(char[], int);
  sign = (n < 0 ? -1 : 1);
  i = 0;
  do {
    s[i++] = (n % 10) * sign + '0';
  } while ((n /= 10) != 0);
  if (sign < 0)
    s[i++] = '-';
  while (i < width) {
    s[i++] = ' ';
  }
  s[i] = '\0';
  reverse(s, i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%r8
  mov    %edx,%r10d
  sar    $0x1f,%edi
  or     $0x1,%edi
  mov    $0x0,%ecx
L30:
  mov    %ecx,%r9d
  add    $0x1,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%r11d
  add    %r11d,%r11d
  sub    %r11d,%eax
  imul   %edi,%eax
  add    $0x30,%eax
  mov    %al,(%rsi)
  mov    %edx,%eax
  add    $0x1,%rsi
  test   %edx,%edx
  jne    L30
  test   %edi,%edi
  js     L40
L22:
  cmp    %ecx,%r10d
  jle    L31
  movslq %ecx,%rdx
  lea    (%r8,%rdx,1),%rax
  lea    0x1(%r8,%rdx,1),%rdx
  lea    -0x1(%r10),%esi
  sub    %ecx,%esi
  add    %rsi,%rdx
L4:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L45:
  movslq %r10d,%rax
  movb   $0x0,(%r8,%rax,1)
  mov    %r10d,%esi
  mov    %r8,%rdi
  call   <reverse@plt>
  add    $0x8,%rsp
  ret
L40:
  movslq %ecx,%rcx
  movb   $0x2d,(%r8,%rcx,1)
  lea    0x2(%r9),%ecx
  jmp    L22
L31:
  mov    %ecx,%r10d
  jmp    L45
```

assistant: ```c
void itoa(int n, char s[], int width) {
  int i, sign;
  void reverse(char[], int);
  sign = (n < 0 ? -1 : 1);
  i = 0;
  do {
    s[i++] = (n % 10) * sign + '0';
  } while ((n /= 10) != 0);
  if (sign < 0)
    s[i++] = '-';
  while (i < width) {
    s[i++] = ' ';
  }
  s[i] = '\0';
  reverse(s, i);
}
```