ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  mov    $0xffffffff,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D19(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L16
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L28
  nopl   0x0(%rax)
L80:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L80
L28:
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%ebp
  je     L97
  xor    %ebx,%ebx
  cmp    %ebp,0x4(%rsp)
  je     L84
  xchg   %ax,%ax
L47:
  mov    $0x23,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jl     L47
L33:
  mov    $0x2a,%edi
  call   <putchar@plt>
L97:
  mov    $0xa,%edi
  add    $0x1,%ebp
  add    $0x2,%r12d
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jge    L15
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L84:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jl     L84
  jmp    L33
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string

tool: D10: %d

tool: D19: %d


assistant: ```c
int main() {
  int n, i = 1, a = 1, b;
  scanf("%d", &n);
  printf("%d\n", (n - 2) * (n - 2));
  while (i <= n) {
    for (a = 1; a <= n - i; a++) {
      printf(" ");
    }
    printf("*");
    if (i > 1) {
      if (i == n) {
        for (b = 0; b < i * 2 - 3; b++) {
          printf("*");
        }
      } else if (i > 1) {
        for (b = 0; b < i * 2 - 3; b++) {
          printf("#");
        }
      }
      printf("*");
    }
    printf("\n");
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  mov    $0xffffffff,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    D3(%rip),%rdi
  lea    -0x2(%rax),%esi
  xor    %eax,%eax
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L67
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L24
  nopl   0x0(%rax)
L79:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jge    L79
L24:
  mov    $0x2a,%edi
  call   <putchar@plt>
  cmp    $0x1,%ebp
  je     L75
  xor    %ebx,%ebx
  cmp    %ebp,0x4(%rsp)
  je     L86
  xchg   %ax,%ax
L90:
  mov    $0x23,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %r12d,%ebx
  jl     L90
L17:
  mov    $0x2a,%edi
  call   <putchar@plt>
L75:
  mov    $0xa,%edi
  add    $0x1,%ebp
  add    $0x2,%r12d
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jge    L15
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L86:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jg     L86
  jmp    L17
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D16: %d

tool: D3: %d


assistant: ```c
int main() {
  int n, i = 1, a = 1, b;
  scanf("%d", &n);
  printf("%d\n", (n - 2) * (n - 2));
  while (i <= n) {
    for (a = 1; a <= n - i; a++) {
      printf(" ");
    }
    printf("*");
    if (i > 1) {
      if (i == n) {
        for (b = 0; b < i * 2 - 3; b++) {
          printf("*");
        }
      } else if (i > 1) {
        for (b = 0; b < i * 2 - 3; b++) {
          printf("#");
        }
      }
      printf("*");
    }
    printf("\n");
    i++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lsx_ordered_partial_convolve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x2,-0xc(%rbp)
  jmp    L0
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x2,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lsx_ordered_partial_convolve(int n, double *a, const double *b) {
  int i;
  a[0] *= b[0];
  for (i = 2; i < n; i += 2) {
    double tmp = a[i];
    a[i] = b[i] * tmp - b[i + 1] * a[i + 1];
    a[i + 1] = b[i + 1] * tmp + b[i] * a[i + 1];
  }
  a[1] = b[i] * a[i] - b[i + 1] * a[i + 1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lsx_ordered_partial_convolve>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%r8
  movsd  (%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x2,%edi
  jle    L12
  lea    0x18(%rsi),%rax
  lea    0x18(%rdx),%rdx
  sub    $0x3,%edi
  shr    %edi
  mov    %edi,%esi
  shl    $0x4,%rsi
  lea    0x28(%rcx,%rsi,1),%rsi
L1:
  movsd  -0x8(%rax),%xmm0
  movsd  (%rax),%xmm1
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rdx),%xmm2
  movapd %xmm1,%xmm3
  mulsd  (%rdx),%xmm3
  subsd  %xmm3,%xmm2
  movsd  %xmm2,-0x8(%rax)
  mulsd  (%rdx),%xmm0
  mulsd  -0x8(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x10,%rax
  add    $0x10,%rdx
  cmp    %rsi,%rax
  jne    L1
  lea    0x4(%rdi,%rdi,1),%eax
L2:
  cltq
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  movsd  0x8(%r8,%rax,8),%xmm1
  mulsd  0x8(%rcx,%rax,8),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx)
  ret
L12:
  mov    $0x2,%eax
  jmp    L2
```

assistant: ```c
void lsx_ordered_partial_convolve(int n, double *a, const double *b) {
  int i;
  a[0] *= b[0];
  for (i = 2; i < n; i += 2) {
    double tmp = a[i];
    a[i] = b[i] * tmp - b[i + 1] * a[i + 1];
    a[i + 1] = b[i + 1] * tmp + b[i] * a[i + 1];
  }
  a[1] = b[i] * a[i] - b[i + 1] * a[i + 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lsx_ordered_partial_convolve>:
  endbr64
  movsd  (%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  mov    %rsi,%rcx
  mov    %rdx,%r8
  movsd  %xmm0,(%rsi)
  cmp    $0x2,%edi
  jle    L22
  sub    $0x3,%edi
  lea    0x18(%rsi),%rax
  lea    0x18(%rdx),%rdx
  shr    %edi
  mov    %edi,%esi
  shl    $0x4,%rsi
  lea    0x28(%rcx,%rsi,1),%rsi
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  (%rax),%xmm1
  movsd  (%rdx),%xmm3
  add    $0x10,%rax
  add    $0x10,%rdx
  movsd  -0x18(%rax),%xmm0
  movsd  -0x18(%rdx),%xmm2
  mulsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  movsd  %xmm2,-0x18(%rax)
  mulsd  -0x10(%rdx),%xmm0
  mulsd  -0x18(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L7
  lea    0x4(%rdi,%rdi,1),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    0x8(,%rax,8),%rax
L19:
  movsd  (%r8,%rdx,1),%xmm0
  movsd  (%r8,%rax,1),%xmm1
  mulsd  (%rcx,%rdx,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rcx)
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x18,%eax
  mov    $0x10,%edx
  jmp    L19
```

assistant: ```c
void lsx_ordered_partial_convolve(int n, double *a, const double *b) {
  int i;
  a[0] *= b[0];
  for (i = 2; i < n; i += 2) {
    double tmp = a[i];
    a[i] = b[i] * tmp - b[i + 1] * a[i + 1];
    a[i + 1] = b[i + 1] * tmp + b[i] * a[i + 1];
  }
  a[1] = b[i] * a[i] - b[i + 1] * a[i + 1];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_gpio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x44e07130,%eax
  movl   $0x0,(%rax)
  mov    $0x44e00408,%eax
  movl   $0x40002,(%rax)
  mov    $0x44e07154,%eax
  movl   $0xff,(%rax)
  mov    $0x4804c130,%eax
  movl   $0x0,(%rax)
  mov    $0x44e000ac,%eax
  movl   $0x40002,(%rax)
  mov    $0x481ac130,%eax
  movl   $0x0,(%rax)
  mov    $0x44e000b0,%eax
  movl   $0x40002,(%rax)
  mov    $0x481ae130,%eax
  movl   $0x0,(%rax)
  mov    $0x44e000b4,%eax
  movl   $0x40002,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_gpio() {
  (*((volatile unsigned int *)(0x44e07000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00400 + 0x08))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x44e07000 + 0x154))) = 255;
  (*((volatile unsigned int *)(0x4804c000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xac))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ac000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb0))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ae000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb4))) = (0x02) | (1 << 18);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_gpio>:
  endbr64
  movl   $0x0,0x44e07130
  movl   $0x40002,0x44e00408
  movl   $0xff,0x44e07154
  movl   $0x0,0x4804c130
  movl   $0x40002,0x44e000ac
  movl   $0x0,0x481ac130
  movl   $0x40002,0x44e000b0
  movl   $0x0,0x481ae130
  movl   $0x40002,0x44e000b4
  ret
```

assistant: ```c
void init_gpio() {
  (*((volatile unsigned int *)(0x44e07000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00400 + 0x08))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x44e07000 + 0x154))) = 255;
  (*((volatile unsigned int *)(0x4804c000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xac))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ac000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb0))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ae000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb4))) = (0x02) | (1 << 18);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<init_gpio>:
  endbr64
  movl   $0x0,0x44e07130
  movl   $0x40002,0x44e00408
  movl   $0xff,0x44e07154
  movl   $0x0,0x4804c130
  movl   $0x40002,0x44e000ac
  movl   $0x0,0x481ac130
  movl   $0x40002,0x44e000b0
  movl   $0x0,0x481ae130
  movl   $0x40002,0x44e000b4
  ret
```

assistant: ```c
void init_gpio() {
  (*((volatile unsigned int *)(0x44e07000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00400 + 0x08))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x44e07000 + 0x154))) = 255;
  (*((volatile unsigned int *)(0x4804c000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xac))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ac000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb0))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ae000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb4))) = (0x02) | (1 << 18);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<init_gpio>:
  endbr64
  movl   $0x0,0x44e07130
  movl   $0x40002,0x44e00408
  movl   $0xff,0x44e07154
  movl   $0x0,0x4804c130
  movl   $0x40002,0x44e000ac
  movl   $0x0,0x481ac130
  movl   $0x40002,0x44e000b0
  movl   $0x0,0x481ae130
  movl   $0x40002,0x44e000b4
  ret
```

assistant: ```c
void init_gpio() {
  (*((volatile unsigned int *)(0x44e07000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00400 + 0x08))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x44e07000 + 0x154))) = 255;
  (*((volatile unsigned int *)(0x4804c000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xac))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ac000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb0))) = (0x02) | (1 << 18);
  (*((volatile unsigned int *)(0x481ae000 + 0x130))) = 0x00;
  (*((volatile unsigned int *)(0x44e00000 + 0xb4))) = (0x02) | (1 << 18);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x4,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: double (1+2) is %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("double (1+2) is %d\n", 2 * 1 + 2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: double (1+2) is %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("double (1+2) is %d\n", 2 * 1 + 2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: double (1+2) is %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("double (1+2) is %d\n", 2 * 1 + 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string

tool: D1: double (1+2) is %d


assistant: ```c
int main(int argc, char *argv[]) {
  printf("double (1+2) is %d\n", 2 * 1 + 2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eio_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L1
L2:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <eio_putchar@plt>
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void eio_puts(char const *asciiz) {
  while (*asciiz)
    eio_putchar(*asciiz++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<eio_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L11
L5:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <eio_putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L11:
  pop    %rbx
  ret
```

assistant: ```c
void eio_puts(char const *asciiz) {
  while (*asciiz)
    eio_putchar(*asciiz++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eio_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L9:
  call   <eio_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L9
L2:
  pop    %rbx
  ret
```

assistant: ```c
void eio_puts(char const *asciiz) {
  while (*asciiz)
    eio_putchar(*asciiz++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eio_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L0
L14:
  call   <eio_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L14
L0:
  pop    %rbx
  ret
```

assistant: ```c
void eio_puts(char const *asciiz) {
  while (*asciiz)
    eio_putchar(*asciiz++);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_it_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,%edi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int free_it_all(ENTRY *entry) {
  free(entry->key);
  free(entry->data);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_it_all>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x4(%rdi),%edi
  call   <free@plt>
  mov    (%rbx),%edi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int free_it_all(ENTRY *entry) {
  free(entry->key);
  free(entry->data);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_it_all>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x4(%rdi),%edi
  call   <free@plt>
  mov    (%rbx),%edi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int free_it_all(ENTRY *entry) {
  free(entry->key);
  free(entry->data);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<free_it_all>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x4(%rdi),%edi
  call   <free@plt>
  mov    (%rbx),%edi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int free_it_all(ENTRY *entry) {
  free(entry->key);
  free(entry->data);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<solcon_length_current_multprec_solution_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x210,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_length_current_multprec_solution_string(int *cursor, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(528, cursor, n, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<solcon_length_current_multprec_solution_string>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%ecx
  mov    %rdi,%rsi
  mov    $0x210,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int solcon_length_current_multprec_solution_string(int *cursor, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(528, cursor, n, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_length_current_multprec_solution_string>:
  endbr64
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %rdi,%rsi
  mov    $0x210,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_length_current_multprec_solution_string(int *cursor, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(528, cursor, n, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solcon_length_current_multprec_solution_string>:
  endbr64
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %rdi,%rsi
  mov    $0x210,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_length_current_multprec_solution_string(int *cursor, int *n) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(528, cursor, n, c);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<errorFatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void errorFatal(char *s, int i, int j) {
  printf(s, i, j);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<errorFatal>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void errorFatal(char *s, int i, int j) {
  printf(s, i, j);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<errorFatal>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void errorFatal(char *s, int i, int j) {
  printf(s, i, j);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<errorFatal>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void errorFatal(char *s, int i, int j) {
  printf(s, i, j);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_countword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L22
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L6
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L15
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  addl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
L15:
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_countword(const char *s, char c) {
  int nb;
  int i;
  int check;
  i = 0;
  check = 0;
  nb = 0;
  while (s[i] != '\0') {
    if (s[i] == c && check)
      check = !check;
    else if (s[i] != c && !check) {
      nb++;
      check = !check;
    }
    i++;
  }
  return (nb);
}
```