ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<tbst_free>:
  endbr64
  test   %rdi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void tbst_free(struct libavl_allocator *allocator, void *block) {
  assert(allocator != NULL && block != NULL);
  free(block);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dmat_yinvx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movsd  D5(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L3
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void dmat_yinvx(const int n, const double *x, double *y) {
  const double *xi;
  double *yi;
  xi = x + n - 1;
  yi = y + n - 1;
  do {
    *yi-- = 1 / (*xi--);
  } while (xi >= x);
}
```
user: What is the c source code of the assembly code below:

```asm
<dmat_yinvx>:
  endbr64
  movslq %edi,%rdi
  lea    -0x8(,%rdi,8),%rcx
  lea    (%rsi,%rcx,1),%rax
  add    %rcx,%rdx
  movsd  D9(%rip),%xmm1
L7:
  sub    $0x8,%rax
  sub    $0x8,%rdx
  movapd %xmm1,%xmm0
  divsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rdx)
  cmp    %rax,%rsi
  jbe    L7
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void dmat_yinvx(const int n, const double *x, double *y) {
  const double *xi;
  double *yi;
  xi = x + n - 1;
  yi = y + n - 1;
  do {
    *yi-- = 1 / (*xi--);
  } while (xi >= x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dmat_yinvx>:
  endbr64
  movslq %edi,%rdi
  movsd  D3(%rip),%xmm1
  lea    -0x8(,%rdi,8),%rcx
  lea    (%rsi,%rcx,1),%rax
  add    %rcx,%rdx
  xchg   %ax,%ax
L7:
  sub    $0x8,%rax
  sub    $0x8,%rdx
  movapd %xmm1,%xmm0
  divsd  0x8(%rax),%xmm0
  movsd  %xmm0,0x8(%rdx)
  cmp    %rax,%rsi
  jbe    L7
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void dmat_yinvx(const int n, const double *x, double *y) {
  const double *xi;
  double *yi;
  xi = x + n - 1;
  yi = y + n - 1;
  do {
    *yi-- = 1 / (*xi--);
  } while (xi >= x);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dmat_yinvx>:
  endbr64
  movslq %edi,%rdi
  mov    %rsi,%r8
  mov    %rdx,%rax
  push   %rbp
  shl    $0x3,%rdi
  push   %rbx
  lea    -0x8(%rdi),%rsi
  sub    $0x10,%rdi
  lea    (%rax,%rsi,1),%rcx
  cmp    $0x7,%rsi
  lea    (%r8,%rdi,1),%r9
  seta   %bpl
  cmp    %r9,%rcx
  lea    (%r8,%rsi,1),%rdx
  setne  %bl
  test   %bl,%bpl
  je     L46
  lea    -0x1(%r8),%r10
  lea    -0x1(%rdx),%r11
  cmp    %r10,%r11
  jb     L46
  shr    $0x3,%rsi
  cmp    %r10,%r11
  movapd D19(%rip),%xmm2
  lea    0x1(%rsi),%r8
  mov    $0x1,%esi
  cmovb  %rsi,%r8
  add    %rax,%rdi
  xor    %eax,%eax
  mov    %r8,%rsi
  shr    %rsi
  neg    %rsi
  shl    $0x4,%rsi
  nopl   (%rax)
L33:
  movupd (%r9,%rax,1),%xmm1
  movapd %xmm2,%xmm0
  shufpd $0x1,%xmm1,%xmm1
  divpd  %xmm1,%xmm0
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  sub    $0x10,%rax
  cmp    %rsi,%rax
  jne    L33
  mov    %r8,%rsi
  and    $0xfffffffffffffffe,%rsi
  mov    %rsi,%rax
  neg    %rax
  shl    $0x3,%rax
  add    %rax,%rdx
  add    %rax,%rcx
  cmp    %rsi,%r8
  je     L48
  movsd  D19(%rip),%xmm0
  divsd  (%rdx),%xmm0
  movsd  %xmm0,(%rcx)
L48:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L46:
  movsd  D19(%rip),%xmm1
L32:
  sub    $0x8,%rdx
  sub    $0x8,%rcx
  movapd %xmm1,%xmm0
  divsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rcx)
  cmp    %rdx,%r8
  jbe    L32
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_guessed: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void dmat_yinvx(const int n, const double *x, double *y) {
  const double *xi;
  double *yi;
  xi = x + n - 1;
  yi = y + n - 1;
  do {
    *yi-- = 1 / (*xi--);
  } while (xi >= x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getchar2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L1:
  mov    $0x3ffe008,%eax
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L1
  mov    $0x3ffe010,%eax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getchar2(void) {
  while (!((*(volatile unsigned int *)((0x3FF0000 + 0xE008))) & 0x20))
    ;
  return (int)(*(volatile unsigned int *)((0x3FF0000 + 0xE010)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getchar2>:
  endbr64
L5:
  mov    0x3ffe008,%eax
  test   $0x20,%al
  je     L5
  mov    0x3ffe010,%eax
  ret
```

assistant: ```c
int getchar2(void) {
  while (!((*(volatile unsigned int *)((0x3FF0000 + 0xE008))) & 0x20))
    ;
  return (int)(*(volatile unsigned int *)((0x3FF0000 + 0xE010)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getchar2>:
  endbr64
  nopl   0x0(%rax)
L9:
  mov    0x3ffe008,%eax
  test   $0x20,%al
  je     L9
  mov    0x3ffe010,%eax
  ret
```

assistant: ```c
int getchar2(void) {
  while (!((*(volatile unsigned int *)((0x3FF0000 + 0xE008))) & 0x20))
    ;
  return (int)(*(volatile unsigned int *)((0x3FF0000 + 0xE010)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getchar2>:
  endbr64
  nopl   0x0(%rax)
L5:
  mov    0x3ffe008,%eax
  test   $0x20,%al
  je     L5
  mov    0x3ffe010,%eax
  ret
```

assistant: ```c
int getchar2(void) {
  while (!((*(volatile unsigned int *)((0x3FF0000 + 0xE008))) & 0x20))
    ;
  return (int)(*(volatile unsigned int *)((0x3FF0000 + 0xE010)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x3,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f(int *a, int *b) {
  int x;
  int *y;
  x = *a;
  x = *a;
  x = *a;
  x = *b;
  y = a;
  *a = 3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void f(int *a, int *b) {
  int x;
  int *y;
  x = *a;
  x = *a;
  x = *a;
  x = *b;
  y = a;
  *a = 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void f(int *a, int *b) {
  int x;
  int *y;
  x = *a;
  x = *a;
  x = *a;
  x = *b;
  y = a;
  *a = 3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  movl   $0x3,(%rdi)
  ret
```

assistant: ```c
void f(int *a, int *b) {
  int x;
  int *y;
  x = *a;
  x = *a;
  x = *a;
  x = *b;
  y = a;
  *a = 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_update_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jg     L8
  mov    $0x0,%eax
  jmp    L20
L8:
  mov    $0x0,%edi
  call   <time@plt>
  mov    -0x10(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_q_countsave@plt>
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  jmp    L20
L17:
  mov    $0x1,%eax
L20:
  leave
  ret
```

assistant: ```c
bool _update_timeout(const char *filepath, time_t timeout_interval) {
  if (timeout_interval <= 0)
    return false;
  if (_q_countsave(filepath, (time(NULL) + timeout_interval)) == false) {
    return false;
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_update_timeout>:
  endbr64
  mov    $0x0,%eax
  test   %rsi,%rsi
  jle    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  lea    (%rax,%rbx,1),%rsi
  mov    %rbp,%rdi
  call   <_q_countsave@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  ret
```

assistant: ```c
bool _update_timeout(const char *filepath, time_t timeout_interval) {
  if (timeout_interval <= 0)
    return false;
  if (_q_countsave(filepath, (time(NULL) + timeout_interval)) == false) {
    return false;
  }
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_update_timeout>:
  endbr64
  test   %rsi,%rsi
  jle    L4
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %rbp,%rdi
  lea    (%rax,%rbx,1),%rsi
  call   <_q_countsave@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool _update_timeout(const char *filepath, time_t timeout_interval) {
  if (timeout_interval <= 0)
    return false;
  if (_q_countsave(filepath, (time(NULL) + timeout_interval)) == false) {
    return false;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_update_timeout>:
  endbr64
  test   %rsi,%rsi
  jle    L9
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %rbp,%rdi
  lea    (%rax,%rbx,1),%rsi
  call   <_q_countsave@plt>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool _update_timeout(const char *filepath, time_t timeout_interval) {
  if (timeout_interval <= 0)
    return false;
  if (_q_countsave(filepath, (time(NULL) + timeout_interval)) == false) {
    return false;
  }
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<draw_symb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x1f,%al
  jle    L145
  mov    $0x1,%edx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L145:
  movzbl -0x4(%rbp),%eax
  cmp    $0x8,%al
  jne    L100
  mov    $0x2,%edx
  lea    D77(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L100:
  movzbl -0x4(%rbp),%eax
  cmp    $0xc,%al
  jne    L33
  mov    $0x2,%edx
  lea    D50(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L33:
  movzbl -0x4(%rbp),%eax
  cmp    $0xa,%al
  jne    L92
  mov    $0x2,%edx
  lea    D56(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L92:
  movzbl -0x4(%rbp),%eax
  cmp    $0xd,%al
  jne    L137
  mov    $0x2,%edx
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L137:
  movzbl -0x4(%rbp),%eax
  cmp    $0x9,%al
  jne    L91
  mov    $0x2,%edx
  lea    D66(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L91:
  movzbl -0x4(%rbp),%eax
  cmp    $0x20,%al
  jne    L90
  mov    $0x2,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L86
L90:
  mov    $0x1,%edx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L86:
  cmpl   $0x0,-0x8(%rbp)
  je     L121
  mov    $0x1,%edx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
L121:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string
name: read_data
arguments: tag: D77
data_type: string
name: read_data
arguments: tag: D50
data_type: string
name: read_data
arguments: tag: D56
data_type: string
name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D66
data_type: string
name: read_data
arguments: tag: D25
data_type: string

tool: D10:  

tool: D77: \b

tool: D50: \f

tool: D56: \n

tool: D13: \r

tool: D66: \t

tool: D25: \s

assistant: ```c
void draw_symb(char symb, int l_s) {
  if (symb > 31) {
    write(1, " ", 1);
    write(1, &symb, 1);
  } else {
    if (symb == '\010')
      write(1, "\\b", 2);
    else if (symb == '\014')
      write(1, "\\f", 2);
    else if (symb == '\012')
      write(1, "\\n", 2);
    else if (symb == '\015')
      write(1, "\\r", 2);
    else if (symb == '\011')
      write(1, "\\t", 2);
    else if (symb == '\040')
      write(1, "\\s", 2);
    else
      write(1, " ", 1);
  }
  if (l_s)
    write(1, " ", 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<draw_symb>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %dil,0xc(%rsp)
  cmp    $0x1f,%dil
  jg     L69
  sub    $0x8,%edi
  cmp    $0x18,%dil
  ja     L43
  movzbl %dil,%edi
  lea    D58(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L69:
  mov    $0x1,%edx
  lea    D22(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
L21:
  test   %ebx,%ebx
  jne    L9
L95:
  add    $0x10,%rsp
  pop    %rbx
  ret
  mov    $0x2,%edx
  lea    D83(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
  mov    $0x2,%edx
  lea    D71(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
  mov    $0x2,%edx
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
  mov    $0x2,%edx
  lea    D57(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
  mov    $0x2,%edx
  lea    D37(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
  mov    $0x2,%edx
  lea    D96(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
L43:
  mov    $0x1,%edx
  lea    D22(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L21
L9:
  mov    $0x1,%edx
  lea    D22(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L95
```

tool_calls: name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D83
type_infered: string
name: read_data
arguments: label: D71
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D57
type_infered: string
name: read_data
arguments: label: D37
type_infered: string
name: read_data
arguments: label: D96
type_infered: string

tool: D22:  

tool: D83: \b

tool: D71: \f

tool: D5: \n

tool: D57: \r

tool: D37: \t

tool: D96: \s

assistant: ```c
void draw_symb(char symb, int l_s) {
  if (symb > 31) {
    write(1, " ", 1);
    write(1, &symb, 1);
  } else {
    if (symb == '\010')
      write(1, "\\b", 2);
    else if (symb == '\014')
      write(1, "\\f", 2);
    else if (symb == '\012')
      write(1, "\\n", 2);
    else if (symb == '\015')
      write(1, "\\r", 2);
    else if (symb == '\011')
      write(1, "\\t", 2);
    else if (symb == '\040')
      write(1, "\\s", 2);
    else
      write(1, " ", 1);
  }
  if (l_s)
    write(1, " ", 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<draw_symb>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %dil,0xc(%rsp)
  cmp    $0x1f,%dil
  jg     L24
  sub    $0x8,%edi
  cmp    $0x5,%dil
  ja     L22
  lea    D47(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0x1,%edx
  lea    D89(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
L19:
  test   %ebx,%ebx
  jne    L68
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L68:
  mov    $0x1,%edx
  lea    D89(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
  mov    $0x2,%edx
  lea    D21(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
  mov    $0x2,%edx
  lea    D36(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D44(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D33(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D40(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%edx
  lea    D89(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D89
type: string
name: extract_symbolic_data
arguments: data_label: D21
type: string
name: extract_symbolic_data
arguments: data_label: D36
type: string
name: extract_symbolic_data
arguments: data_label: D44
type: string
name: extract_symbolic_data
arguments: data_label: D33
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string

tool: D89:  

tool: D21: \r

tool: D36: \b

tool: D44: \t

tool: D33: \n

tool: D40: \f

assistant: ```c
void draw_symb(char symb, int l_s) {
  if (symb > 31) {
    write(1, " ", 1);
    write(1, &symb, 1);
  } else {
    if (symb == '\010')
      write(1, "\\b", 2);
    else if (symb == '\014')
      write(1, "\\f", 2);
    else if (symb == '\012')
      write(1, "\\n", 2);
    else if (symb == '\015')
      write(1, "\\r", 2);
    else if (symb == '\011')
      write(1, "\\t", 2);
    else if (symb == '\040')
      write(1, "\\s", 2);
    else
      write(1, " ", 1);
  }
  if (l_s)
    write(1, " ", 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<draw_symb>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %dil,0xc(%rsp)
  cmp    $0x1f,%dil
  jg     L63
  sub    $0x8,%edi
  cmp    $0x5,%dil
  ja     L43
  lea    D5(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L63:
  mov    $0x1,%edx
  lea    D88(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  call   <write@plt>
L17:
  test   %ebx,%ebx
  jne    L87
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L87:
  mov    $0x1,%edx
  lea    D88(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
  mov    $0x2,%edx
  lea    D53(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  mov    $0x2,%edx
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D32(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D11(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
  mov    $0x2,%edx
  lea    D64(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0x1,%edx
  lea    D88(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_tag: D88
datatype: string
name: retrieve_data
arguments: data_tag: D53
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D32
datatype: string
name: retrieve_data
arguments: data_tag: D11
datatype: string
name: retrieve_data
arguments: data_tag: D64
datatype: string

tool: D88:  

tool: D53: \r

tool: D4: \b

tool: D32: \t

tool: D11: \n

tool: D64: \f

assistant: ```c
void draw_symb(char symb, int l_s) {
  if (symb > 31) {
    write(1, " ", 1);
    write(1, &symb, 1);
  } else {
    if (symb == '\010')
      write(1, "\\b", 2);
    else if (symb == '\014')
      write(1, "\\f", 2);
    else if (symb == '\012')
      write(1, "\\n", 2);
    else if (symb == '\015')
      write(1, "\\r", 2);
    else if (symb == '\011')
      write(1, "\\t", 2);
    else if (symb == '\040')
      write(1, "\\s", 2);
    else
      write(1, " ", 1);
  }
  if (l_s)
    write(1, " ", 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<loopPeriodSec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  D8(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
void loopPeriodSec(double *period, struct timespec *current, struct timespec *previous) {
  *period = current->tv_sec - previous->tv_sec;
  *period += ((double)(current->tv_nsec - previous->tv_nsec)) / 1000000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loopPeriodSec>:
  endbr64
  movsd  (%rsi),%xmm1
  subsd  (%rdx),%xmm1
  movsd  %xmm1,(%rdi)
  mov    0x8(%rsi),%rax
  sub    0x8(%rdx),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
void loopPeriodSec(double *period, struct timespec *current, struct timespec *previous) {
  *period = current->tv_sec - previous->tv_sec;
  *period += ((double)(current->tv_nsec - previous->tv_nsec)) / 1000000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loopPeriodSec>:
  endbr64
  movsd  (%rsi),%xmm1
  subsd  (%rdx),%xmm1
  pxor   %xmm0,%xmm0
  mov    0x8(%rsi),%rax
  sub    0x8(%rdx),%rax
  cvtsi2sd %rax,%xmm0
  divsd  D9(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
void loopPeriodSec(double *period, struct timespec *current, struct timespec *previous) {
  *period = current->tv_sec - previous->tv_sec;
  *period += ((double)(current->tv_nsec - previous->tv_nsec)) / 1000000000;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<loopPeriodSec>:
  endbr64
  movsd  (%rsi),%xmm1
  subsd  (%rdx),%xmm1
  pxor   %xmm0,%xmm0
  mov    0x8(%rsi),%rax
  sub    0x8(%rdx),%rax
  cvtsi2sd %rax,%xmm0
  divsd  D3(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
void loopPeriodSec(double *period, struct timespec *current, struct timespec *previous) {
  *period = current->tv_sec - previous->tv_sec;
  *period += ((double)(current->tv_nsec - previous->tv_nsec)) / 1000000000;
}
```