ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_prng>:
  endbr64
  sub    $0x38,%rsp
  movdqa D6(%rip),%xmm0
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D14(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <init_by_array64@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: byte[16]
name: retrieve_data
arguments: label: D14
data_type: byte[16]

tool: {"D6": [0x45,0x23,0x01,0x00,0x00,0x00,0x00,0x00,0x56,0x34,0x02,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0x67,0x45,0x03,0x00,0x00,0x00,0x00,0x00,0x78,0x56,0x04,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void init_prng(void) {
  unsigned long long init[4] = {0x12345ULL, 0x23456ULL, 0x34567ULL, 0x45678ULL}, length = 4;
  init_by_array64(init, length);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<qadd8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xff,-0x4(%rbp)
  jle    L2
  movl   $0xff,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t qadd8(uint8_t i, uint8_t j) {
  uint16_t t = i + j;
  if (t > 255)
    t = 255;
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qadd8>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t qadd8(uint8_t i, uint8_t j) {
  uint16_t t = i + j;
  if (t > 255)
    t = 255;
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qadd8>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t qadd8(uint8_t i, uint8_t j) {
  uint16_t t = i + j;
  if (t > 255)
    t = 255;
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qadd8>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t qadd8(uint8_t i, uint8_t j) {
  uint16_t t = i + j;
  if (t > 255)
    t = 255;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getOneDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L5:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x2f,-0x1(%rbp)
  jbe    L31
  cmpb   $0x39,-0x1(%rbp)
  jbe    L28
L31:
  cmpb   $0xd,-0x1(%rbp)
  je     L28
  cmpb   $0x8,-0x1(%rbp)
  jne    L5
L28:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char getOneDigit() {
  unsigned char inChar;
  do
    inChar = getchar();
  while (((inChar < 48) || (inChar > 57)) && (inChar != 13) && (inChar != 8));
  return inChar;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getOneDigit>:
  endbr64
  push   %rbx
  movabs $0x3ff000000002100,%rbx
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x39,%al
  ja     L13
  bt     %rax,%rbx
  jae    L13
  pop    %rbx
  ret
```

assistant: ```c
char getOneDigit() {
  unsigned char inChar;
  do
    inChar = getchar();
  while (((inChar < 48) || (inChar > 57)) && (inChar != 13) && (inChar != 8));
  return inChar;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getOneDigit>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L10
  cmp    $0xd,%al
  je     L10
  cmp    $0x8,%al
  jne    L9
L10:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char getOneDigit() {
  unsigned char inChar;
  do
    inChar = getchar();
  while (((inChar < 48) || (inChar > 57)) && (inChar != 13) && (inChar != 8));
  return inChar;
}
```
user: What is the c source code of the assembly code below?

```asm
<getOneDigit>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L21
  cmp    $0xd,%al
  je     L21
  cmp    $0x8,%al
  jne    L14
L21:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char getOneDigit() {
  unsigned char inChar;
  do
    inChar = getchar();
  while (((inChar < 48) || (inChar > 57)) && (inChar != 13) && (inChar != 8));
  return inChar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D33
datatype: string
name: unpack_data
arguments: label: D32
datatype: string
name: unpack_data
arguments: label: D25
datatype: string
name: unpack_data
arguments: label: D8
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D24
datatype: string

tool: D33: Size of char = %d


tool: D32: Size of int = %d


tool: D25: Size of short = %d


tool: D8: Size of long = %d


tool: D4: Size of double = %d


tool: D24: Size of float = %d


assistant: ```c
int main(int argc, char **argv) {
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string
name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D1
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D48
type_guessed: string

tool: D9: Size of char = %d


tool: D30: Size of int = %d


tool: D38: Size of short = %d


tool: D1: Size of long = %d


tool: D15: Size of double = %d


tool: D48: Size of float = %d


assistant: ```c
int main(int argc, char **argv) {
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D58
data_type: string
name: unpack_data
arguments: tag: D40
data_type: string
name: unpack_data
arguments: tag: D38
data_type: string

tool: D11: Size of char = %d


tool: D19: Size of int = %d


tool: D8: Size of short = %d


tool: D58: Size of long = %d


tool: D40: Size of double = %d


tool: D38: Size of float = %d


assistant: ```c
int main(int argc, char **argv) {
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D3
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string

tool: D21: Size of char = %d


tool: D7: Size of int = %d


tool: D3: Size of short = %d


tool: D28: Size of long = %d


tool: D20: Size of double = %d


tool: D17: Size of float = %d


assistant: ```c
int main(int argc, char **argv) {
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<FN_unreachable_statement_continue_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L11
L15:
  nop
L11:
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  test   %rax,%rax
  jne    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void FN_unreachable_statement_continue_bad() {
  while (__infer_nondet_int()) {
    continue;
    nop();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FN_unreachable_statement_continue_bad>:
  endbr64
  sub    $0x8,%rsp
L5:
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
void FN_unreachable_statement_continue_bad() {
  while (__infer_nondet_int()) {
    continue;
    nop();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<FN_unreachable_statement_continue_bad>:
  endbr64
  sub    $0x8,%rsp
L7:
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %rax,%rax
  jne    L7
  add    $0x8,%rsp
  ret
```

assistant: ```c
void FN_unreachable_statement_continue_bad() {
  while (__infer_nondet_int()) {
    continue;
    nop();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FN_unreachable_statement_continue_bad>:
  endbr64
  sub    $0x8,%rsp
L6:
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  ret
```

assistant: ```c
void FN_unreachable_statement_continue_bad() {
  while (__infer_nondet_int()) {
    continue;
    nop();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D0: Enter three integers: 

tool: D17: %o %o %o

tool: D2: sum =  %o


assistant: ```c
int main(void) {
  int x, y, z, sum;
  printf("Enter three integers: ");
  scanf("%o %o %o", &x, &y, &z);
  sum = x + y + z;
  printf("sum =  %o\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  add    0xc(%rsp),%esi
  add    0x14(%rsp),%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D10
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D3: Enter three integers: 

tool: D10: %o %o %o

tool: D17: sum =  %o


assistant: ```c
int main(void) {
  int x, y, z, sum;
  printf("Enter three integers: ");
  scanf("%o %o %o", &x, &y, &z);
  sum = x + y + z;
  printf("sum =  %o\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    D19(%rip),%rdi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  add    0xc(%rsp),%esi
  lea    D7(%rip),%rdi
  add    0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string
name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D7
type: string

tool: D2: Enter three integers: 

tool: D19: %o %o %o

tool: D7: sum =  %o


assistant: ```c
int main(void) {
  int x, y, z, sum;
  printf("Enter three integers: ");
  scanf("%o %o %o", &x, &y, &z);
  sum = x + y + z;
  printf("sum =  %o\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rcx
  lea    D8(%rip),%rdi
  lea    0x10(%rsp),%rdx
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  add    0xc(%rsp),%esi
  lea    D5(%rip),%rdi
  add    0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D24: Enter three integers: 

tool: D8: %o %o %o

tool: D5: sum =  %o


assistant: ```c
int main(void) {
  int x, y, z, sum;
  printf("Enter three integers: ");
  scanf("%o %o %o", &x, &y, &z);
  sum = x + y + z;
  printf("sum =  %o\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L9
L11:
  addl   $0x3,-0x4(%rbp)
L9:
  cmpl   $0x9,-0x4(%rbp)
  jle    L11
  addl   $0x3,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int x;
  ;
  while (x < 10)
    x = x + 3;
  if (1)
    x = x + 3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
L7:
  add    $0x3,%eax
  cmp    $0x9,%eax
  jle    L7
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int x;
  ;
  while (x < 10)
    x = x + 3;
  if (1)
    x = x + 3;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int x;
  ;
  while (x < 10)
    x = x + 3;
  if (1)
    x = x + 3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int x;
  ;
  while (x < 10)
    x = x + 3;
  if (1)
    x = x + 3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xxsumz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  subq   $0x4,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L12
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L7
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float xxsumz(float *x, int n1, int n2) {
  int i;
  float sum = 0.0;
  x--;
  for (i = n1; i <= n2; i++)
    sum += x[i];
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xxsumz>:
  endbr64
  cmp    %edx,%esi
  jg     L3
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%rax
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L2:
  addss  -0x4(%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L2
  ret
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float xxsumz(float *x, int n1, int n2) {
  int i;
  float sum = 0.0;
  x--;
  for (i = n1; i <= n2; i++)
    sum += x[i];
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xxsumz>:
  endbr64
  cmp    %edx,%esi
  jg     L7
  movslq %esi,%rcx
  sub    %esi,%edx
  pxor   %xmm0,%xmm0
  add    %rcx,%rdx
  lea    (%rdi,%rcx,4),%rax
  lea    0x4(%rdi,%rdx,4),%rdx
  nopl   (%rax)
L19:
  addss  -0x4(%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
  ret
  nop
L7:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float xxsumz(float *x, int n1, int n2) {
  int i;
  float sum = 0.0;
  x--;
  for (i = n1; i <= n2; i++)
    sum += x[i];
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xxsumz>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jg     L35
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r9d
  cmp    $0x2,%eax
  jbe    L64
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    -0x4(%r8,%rax,4),%rdx
  mov    %r9d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x10,%rax
L25:
  movups (%rdx),%xmm1
  mov    %rax,%rdx
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L26
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%ecx
  cmp    %eax,%r9d
  je     L0
L20:
  movslq %ecx,%rax
  lea    0x1(%rcx),%edx
  addss  -0x4(%r8,%rax,4),%xmm0
  lea    0x0(,%rax,4),%rsi
  cmp    %edx,%edi
  jl     L19
  add    $0x2,%ecx
  addss  (%r8,%rax,4),%xmm0
  cmp    %ecx,%edi
  jl     L19
  addss  0x4(%r8,%rsi,1),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  pxor   %xmm0,%xmm0
L19:
  ret
  nopl   (%rax)
L0:
  ret
L64:
  pxor   %xmm0,%xmm0
  jmp    L20
```

assistant: ```c
float xxsumz(float *x, int n1, int n2) {
  int i;
  float sum = 0.0;
  x--;
  for (i = n1; i <= n2; i++)
    sum += x[i];
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L6
  mov    $0x1,%edx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,-0x14(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  cmp    $0x9,%eax
  jle    L24
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <ft_putnbr>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%edi
  call   <ft_putnbr>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  jmp    L13
L24:
  mov    -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: -

assistant: ```c
int ft_putnbr(int nbr) {
  if (nbr < 0) {
    write(1, "-", 1);
    nbr = nbr * -1;
  }
  if (nbr >= 10) {
    return nbr = ft_putnbr(nbr / 10) - ft_putnbr(nbr % 10);
  }
  nbr += 48;
  write(1, &nbr, 1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_putnbr>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  test   %edi,%edi
  js     L31
L12:
  mov    0xc(%rsp),%eax
  cmp    $0x9,%eax
  jg     L32
  add    $0x30,%eax
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    $0x0,%eax
L37:
  add    $0x10,%rsp
  pop    %rbx
  ret
L31:
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  negl   0xc(%rsp)
  jmp    L12
L32:
  movslq %eax,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <ft_putnbr>
  mov    %eax,%ebx
  mov    0xc(%rsp),%edi
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  call   <ft_putnbr>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: -

assistant: ```c
int ft_putnbr(int nbr) {
  if (nbr < 0) {
    write(1, "-", 1);
    nbr = nbr * -1;
  }
  if (nbr >= 10) {
    return nbr = ft_putnbr(nbr / 10) - ft_putnbr(nbr % 10);
  }
  nbr += 48;
  write(1, &nbr, 1);
  return (0);
}
```