ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cypher>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  test   %al,%al
  jne    L52
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L5:
  sub    $0xd,%eax
  mov    %al,(%rdx)
L59:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L43
L52:
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  lea    -0x4e(%rcx),%r8d
  cmp    $0xc,%r8b
  jbe    L5
  sub    $0x41,%ecx
  cmp    $0xc,%cl
  ja     L59
  add    $0xd,%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L52
L43:
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: %si 

assistant: ```c
void cypher(char arr[100]) {
  int i;
  char ch;
  for (i = 0; arr[i] != '\0'; ++i) {
    if (arr[i] >= 78 && arr[i] <= 90 || arr[i] >= 110 && arr[i] <= 122) {
      arr[i] = arr[i] - 13;
    } else if (arr[i] <= 77 && arr[i] >= 65 || arr[i] <= 109 && arr[i] >= 97) {
      arr[i] = arr[i] + 13;
    }
  }
  printf("%si ", arr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cypher>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  test   %al,%al
  jne    L11
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L2:
  sub    $0xd,%eax
  mov    %al,(%rdx)
L31:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L28
L11:
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  lea    -0x4e(%rcx),%r8d
  cmp    $0xc,%r8b
  jbe    L2
  sub    $0x41,%ecx
  cmp    $0xc,%cl
  ja     L31
  add    $0xd,%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L11
L28:
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: %si 

assistant: ```c
void cypher(char arr[100]) {
  int i;
  char ch;
  for (i = 0; arr[i] != '\0'; ++i) {
    if (arr[i] >= 78 && arr[i] <= 90 || arr[i] >= 110 && arr[i] <= 122) {
      arr[i] = arr[i] - 13;
    } else if (arr[i] <= 77 && arr[i] >= 65 || arr[i] <= 109 && arr[i] >= 97) {
      arr[i] = arr[i] + 13;
    }
  }
  printf("%si ", arr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trimwhitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L46
L21:
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x18(%rbp),%rax
  jmp    L36
L7:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L61
L25:
  subq   $0x1,-0x8(%rbp)
L61:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
L14:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trimwhitespace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L35
L53:
  add    $0x1,%rbx
L35:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L53
  cmpb   $0x0,(%rbx)
  jne    L27
L52:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rbp
  cmp    %rbp,%rbx
  jae    L36
L22:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L36
  sub    $0x1,%rbp
  cmp    %rbp,%rbx
  jne    L22
L36:
  movb   $0x0,0x1(%rbp)
  jmp    L52
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trimwhitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L53
L36:
  add    $0x1,%r12
L53:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
  cmpb   $0x0,(%r12)
  jne    L41
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L41:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L22
  jmp    L67
  xchg   %ax,%ax
L7:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L67
L22:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
L67:
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<trimwhitespace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  jmp    L35
L47:
  add    $0x1,%r12
L35:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L47
  cmpb   $0x0,(%r12)
  jne    L62
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L62:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L10
  jmp    L50
  xchg   %ax,%ax
L6:
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L50
L10:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L6
L50:
  movb   $0x0,0x1(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *trimwhitespace(char *str) {
  char *end;
  while (isspace(*str))
    str++;
  if (*str == 0)
    return str;
  end = str + strlen(str) - 1;
  while (end > str && isspace(*end))
    end--;
  *(end + 1) = 0;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initiateArray2val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initiateArray2val(double *A, int n, double val) {
  int i;
  for (i = 0; i < n; i++) {
    A[i] = val;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initiateArray2val>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L6:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
L3:
  ret
```

assistant: ```c
void initiateArray2val(double *A, int n, double val) {
  int i;
  for (i = 0; i < n; i++) {
    A[i] = val;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initiateArray2val>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L18:
  movsd  %xmm0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L18
L15:
  ret
```

assistant: ```c
void initiateArray2val(double *A, int n, double val) {
  int i;
  for (i = 0; i < n; i++) {
    A[i] = val;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<initiateArray2val>:
  endbr64
  test   %esi,%esi
  jle    L10
  cmp    $0x1,%esi
  je     L42
  mov    %esi,%edx
  movapd %xmm0,%xmm1
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L24:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L24
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L3
L15:
  cltq
  movsd  %xmm0,(%rdi,%rax,8)
L10:
  ret
  xchg   %ax,%ax
L3:
  ret
L42:
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
void initiateArray2val(double *A, int n, double val) {
  int i;
  for (i = 0; i < n; i++) {
    A[i] = val;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<echo_command_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L19
L11:
  cmpl   $0x0,-0xc(%rbp)
  jle    L5
  lea    D10(%rip),%rax
  jmp    L39
L5:
  lea    D25(%rip),%rax
L39:
  mov    -0x18(%rbp),%rdx
  lea    0x8(%rdx),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    (%rdx),%rdx
  mov    -0x8(%rbp),%rdi
  mov    %rax,%rcx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
L19:
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L11
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string

tool: D13: %%

tool: D10:  

tool: 

tool: D29: %s%s

assistant: ```c
void echo_command_line(FILE *F, int argc, char **argv) {
  fprintf(F, "%%");
  while (--argc >= 0)
    fprintf(F, "%s%s", *argv++, (argc > 0) ? " " : "");
  fprintf(F, "\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<echo_command_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  lea    D11(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  sub    $0x1,%ebx
  js     L5
  lea    D42(%rip),%r14
  lea    D36(%rip),%r13
  jmp    L0
L39:
  add    $0x8,%rbp
  mov    -0x8(%rbp),%rdx
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  je     L5
L0:
  test   %ebx,%ebx
  jne    L39
  lea    D15(%rip),%rcx
  mov    0x0(%rbp),%rdx
  lea    D36(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L5:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D42
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D15
type_infered: string

tool: D11: %%

tool: D42:  

tool: D36: %s%s

tool: 

assistant: ```c
void echo_command_line(FILE *F, int argc, char **argv) {
  fprintf(F, "%%");
  while (--argc >= 0)
    fprintf(F, "%s%s", *argv++, (argc > 0) ? " " : "");
  fprintf(F, "\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<echo_command_line>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    D35(%rip),%rsi
  call   <fprintf@plt>
  sub    $0x1,%ebx
  js     L21
  lea    D11(%rip),%r13
  lea    D12(%rip),%r14
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x8,%rbp
  sub    $0x1,%ebx
L26:
  mov    0x0(%rbp),%rdx
  test   %ebx,%ebx
  jne    L5
  lea    D22(%rip),%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L21:
  pop    %rbx
  mov    %r12,%rsi
  pop    %rbp
  mov    $0xa,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <fputc@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D12
data_type: string
name: retrieve_data
arguments: data_tag: D22
data_type: string

tool: D35: %%

tool: D11: %s%s

tool: D12:  

tool: 

assistant: ```c
void echo_command_line(FILE *F, int argc, char **argv) {
  fprintf(F, "%%");
  while (--argc >= 0)
    fprintf(F, "%s%s", *argv++, (argc > 0) ? " " : "");
  fprintf(F, "\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<echo_command_line>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    D3(%rip),%rsi
  call   <fprintf@plt>
  sub    $0x1,%ebx
  js     L25
  lea    D8(%rip),%r13
  lea    D24(%rip),%r14
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x8,%rbp
  sub    $0x1,%ebx
L6:
  mov    0x0(%rbp),%rdx
  test   %ebx,%ebx
  jne    L1
  lea    D14(%rip),%rcx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L25:
  pop    %rbx
  mov    %r12,%rsi
  pop    %rbp
  mov    $0xa,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <fputc@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string
name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D3: %%

tool: D8: %s%s

tool: D24:  

tool: 

assistant: ```c
void echo_command_line(FILE *F, int argc, char **argv) {
  fprintf(F, "%%");
  while (--argc >= 0)
    fprintf(F, "%s%s", *argv++, (argc > 0) ? " " : "");
  fprintf(F, "\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PMatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  jmp    L57
L58:
  movzbl (%r12),%eax
  movsbl %al,%edx
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <MatchClass@plt>
  test   %eax,%eax
  jne    L74
  mov    $0x0,%eax
  jmp    L7
L74:
  add    $0x1,%r12
  add    $0x1,%rbx
L57:
  movzbl (%r12),%eax
  test   %al,%al
  je     L11
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L58
L11:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L64
  movzbl (%rbx),%eax
  test   %al,%al
  je     L48
L64:
  mov    $0x0,%eax
  jmp    L7
L48:
  mov    $0x1,%eax
L7:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int PMatch(control, string)
register char *control;
register char *string;
{
  while (*string && *control) {
    if (!MatchClass(*control, *string)) {
      return (0);
    }
    string++;
    control++;
  }
  if (*string || *control) {
    return (0);
  }
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PMatch>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L77
L54:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L70
  movsbl %sil,%esi
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <MatchClass@plt>
  test   %eax,%eax
  je     L0
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  jne    L54
L77:
  mov    $0x1,%eax
  cmpb   $0x0,(%rbx)
  je     L0
  jmp    L48
L70:
  test   %sil,%sil
  je     L12
L48:
  mov    $0x0,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    $0x1,%eax
  jmp    L0
```

assistant: ```c
int PMatch(control, string)
register char *control;
register char *string;
{
  while (*string && *control) {
    if (!MatchClass(*control, *string)) {
      return (0);
    }
    string++;
    control++;
  }
  if (*string || *control) {
    return (0);
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PMatch>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  jne    L42
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
  call   <MatchClass@plt>
  test   %eax,%eax
  je     L17
  movsbl 0x1(%rbp),%esi
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %sil,%sil
  je     L32
L42:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L41
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L32:
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int PMatch(control, string)
register char *control;
register char *string;
{
  while (*string && *control) {
    if (!MatchClass(*control, *string)) {
      return (0);
    }
    string++;
    control++;
  }
  if (*string || *control) {
    return (0);
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PMatch>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  jne    L20
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  call   <MatchClass@plt>
  test   %eax,%eax
  je     L28
  movsbl 0x1(%rbp),%esi
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %sil,%sil
  je     L41
L20:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L41:
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int PMatch(control, string)
register char *control;
register char *string;
{
  while (*string && *control) {
    if (!MatchClass(*control, *string)) {
      return (0);
    }
    string++;
    control++;
  }
  if (*string || *control) {
    return (0);
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uwsgi_response_prepare_headers_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x13(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <uwsgi_num2str2@plt>
  lea    -0x13(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <uwsgi_response_prepare_headers@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int uwsgi_response_prepare_headers_int(struct wsgi_request *wsgi_req, int status) {
  char status_str[11];
  uwsgi_num2str2(status, status_str);
  return uwsgi_response_prepare_headers(wsgi_req, status_str, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uwsgi_response_prepare_headers_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbp
  mov    %rbp,%rsi
  call   <uwsgi_num2str2@plt>
  mov    $0x3,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <uwsgi_response_prepare_headers@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uwsgi_response_prepare_headers_int(struct wsgi_request *wsgi_req, int status) {
  char status_str[11];
  uwsgi_num2str2(status, status_str);
  return uwsgi_response_prepare_headers(wsgi_req, status_str, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uwsgi_response_prepare_headers_int>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%r12
  mov    %r12,%rsi
  call   <uwsgi_num2str2@plt>
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <uwsgi_response_prepare_headers@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uwsgi_response_prepare_headers_int(struct wsgi_request *wsgi_req, int status) {
  char status_str[11];
  uwsgi_num2str2(status, status_str);
  return uwsgi_response_prepare_headers(wsgi_req, status_str, 3);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<uwsgi_response_prepare_headers_int>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%r12
  mov    %r12,%rsi
  call   <uwsgi_num2str2@plt>
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <uwsgi_response_prepare_headers@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uwsgi_response_prepare_headers_int(struct wsgi_request *wsgi_req, int status) {
  char status_str[11];
  uwsgi_num2str2(status, status_str);
  return uwsgi_response_prepare_headers(wsgi_req, status_str, 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func_e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x4c4b3f,-0x4(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func_e() {
  int i;
  for (i = 0; i < 5 * (1000 * 1000); i++) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func_e>:
  endbr64
  mov    $0x4c4b40,%eax
L5:
  sub    $0x1,%eax
  jne    L5
  ret
```

assistant: ```c
void func_e() {
  int i;
  for (i = 0; i < 5 * (1000 * 1000); i++) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_e>:
  endbr64
  ret
```

assistant: ```c
void func_e() {
  int i;
  for (i = 0; i < 5 * (1000 * 1000); i++) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func_e>:
  endbr64
  ret
```

assistant: ```c
void func_e() {
  int i;
  for (i = 0; i < 5 * (1000 * 1000); i++) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<tok_ext_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0xb3,%eax
  cmp    $0x1b,%eax
  seta   %dl
  test   %dl,%dl
  jne    L41
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0x2000d3,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L61
  mov    %rax,%rdx
  and    $0xc02000,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L11
  and    $0x8000024,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L22
  jmp    L41
L61:
  mov    $0x1,%eax
  jmp    L3
L22:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
  mov    $0x1,%eax
  jmp    L3
L11:
  mov    $0x2,%eax
  jmp    L3
L41:
  mov    $0x0,%eax
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: unsupported token

assistant: ```c
int tok_ext_size(int t) {
  switch (t) {
  case 0xb3:
  case 0xc8:
  case 0xb4:
  case 0xb7:
  case 0xb9:
  case 0xba:
    return 1;
  case 0xb5:
  case 0xb8:
  case 0xce:
    error("unsupported token");
    return 1;
  case 0xc0:
  case 0xc9:
  case 0xca:
    return 2;
  default:
    return 0;
  }
}
```