ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__udivsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L65
  mov    $0x0,%eax
  jmp    L71
L65:
  cmpl   $0x0,-0x24(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L71
L42:
  bsr    -0x28(%rbp),%eax
  xor    $0x1f,%eax
  bsr    -0x24(%rbp),%edx
  xor    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1f,-0xc(%rbp)
  jbe    L9
  mov    $0x0,%eax
  jmp    L71
L9:
  cmpl   $0x1f,-0xc(%rbp)
  jne    L12
  mov    -0x24(%rbp),%eax
  jmp    L71
L12:
  addl   $0x1,-0xc(%rbp)
  mov    $0x20,%eax
  sub    -0xc(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L18:
  mov    -0x10(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  sar    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    -0x28(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x0,-0xc(%rbp)
  jne    L18
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
unsigned __udivsi3(unsigned n, unsigned d) {
  unsigned q;
  unsigned r;
  unsigned sr;
  if (d == 0)
    return 0;
  if (n == 0)
    return 0;
  sr = __builtin_clz(d) - __builtin_clz(n);
  if (sr > 31)
    return 0;
  if (sr == 31)
    return n;
  ++sr;
  q = n << (32 - sr);
  r = n >> sr;
  unsigned carry = 0;
  for (; sr > 0; --sr) {
    r = (r << 1) | (q >> (31));
    q = (q << 1) | carry;
    const int s = (int)(d - r - 1) >> (31);
    carry = s & 1;
    r -= d & s;
  }
  q = (q << 1) | carry;
  return q;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__udivsi3>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  je     L10
  test   %esi,%esi
  je     L10
  bsr    %esi,%esi
  xor    $0x1f,%esi
  bsr    %edi,%eax
  xor    $0x1f,%eax
  sub    %eax,%esi
  mov    $0x0,%eax
  cmp    $0x1f,%esi
  ja     L0
  mov    %edi,%eax
  je     L0
  add    $0x1,%esi
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  shr    %cl,%edi
  mov    $0x0,%edx
  lea    -0x1(%r8),%r9d
L27:
  lea    (%rdi,%rdi,1),%ecx
  mov    %eax,%edi
  shr    $0x1f,%edi
  or     %ecx,%edi
  add    %eax,%eax
  or     %edx,%eax
  mov    %r9d,%edx
  sub    %edi,%edx
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%edx
  and    %r8d,%ecx
  sub    %ecx,%edi
  sub    $0x1,%esi
  jne    L27
  add    %eax,%eax
  or     %edx,%eax
  ret
L10:
  mov    $0x0,%eax
L0:
  ret
```

assistant: ```c
unsigned __udivsi3(unsigned n, unsigned d) {
  unsigned q;
  unsigned r;
  unsigned sr;
  if (d == 0)
    return 0;
  if (n == 0)
    return 0;
  sr = __builtin_clz(d) - __builtin_clz(n);
  if (sr > 31)
    return 0;
  if (sr == 31)
    return n;
  ++sr;
  q = n << (32 - sr);
  r = n >> sr;
  unsigned carry = 0;
  for (; sr > 0; --sr) {
    r = (r << 1) | (q >> (31));
    q = (q << 1) | carry;
    const int s = (int)(d - r - 1) >> (31);
    carry = s & 1;
    r -= d & s;
  }
  q = (q << 1) | carry;
  return q;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__udivsi3>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  je     L7
  test   %esi,%esi
  je     L7
  bsr    %esi,%esi
  xor    $0x1f,%esi
  bsr    %edi,%eax
  xor    $0x1f,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  cmp    $0x1f,%esi
  ja     L28
  mov    %edi,%eax
  je     L28
  add    $0x1,%esi
  mov    $0x20,%ecx
  lea    -0x1(%r8),%r9d
  xor    %edx,%edx
  sub    %esi,%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  shr    %cl,%edi
  xchg   %ax,%ax
L23:
  lea    (%rdi,%rdi,1),%ecx
  mov    %eax,%edi
  add    %eax,%eax
  shr    $0x1f,%edi
  or     %edx,%eax
  mov    %r9d,%edx
  or     %ecx,%edi
  sub    %edi,%edx
  mov    %edx,%ecx
  shr    $0x1f,%edx
  sar    $0x1f,%ecx
  and    %r8d,%ecx
  sub    %ecx,%edi
  sub    $0x1,%esi
  jne    L23
  add    %eax,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
L28:
  ret
```

assistant: ```c
unsigned __udivsi3(unsigned n, unsigned d) {
  unsigned q;
  unsigned r;
  unsigned sr;
  if (d == 0)
    return 0;
  if (n == 0)
    return 0;
  sr = __builtin_clz(d) - __builtin_clz(n);
  if (sr > 31)
    return 0;
  if (sr == 31)
    return n;
  ++sr;
  q = n << (32 - sr);
  r = n >> sr;
  unsigned carry = 0;
  for (; sr > 0; --sr) {
    r = (r << 1) | (q >> (31));
    q = (q << 1) | carry;
    const int s = (int)(d - r - 1) >> (31);
    carry = s & 1;
    r -= d & s;
  }
  q = (q << 1) | carry;
  return q;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__udivsi3>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  je     L8
  test   %esi,%esi
  je     L8
  bsr    %esi,%esi
  xor    $0x1f,%esi
  bsr    %edi,%eax
  xor    $0x1f,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  cmp    $0x1f,%esi
  ja     L33
  mov    %edi,%eax
  je     L33
  add    $0x1,%esi
  mov    $0x20,%ecx
  lea    -0x1(%r8),%r9d
  xor    %edx,%edx
  sub    %esi,%ecx
  shl    %cl,%eax
  mov    %esi,%ecx
  shr    %cl,%edi
  xchg   %ax,%ax
L41:
  lea    (%rdi,%rdi,1),%ecx
  mov    %eax,%edi
  add    %eax,%eax
  shr    $0x1f,%edi
  or     %edx,%eax
  mov    %r9d,%edx
  or     %ecx,%edi
  sub    %edi,%edx
  mov    %edx,%ecx
  shr    $0x1f,%edx
  sar    $0x1f,%ecx
  and    %r8d,%ecx
  sub    %ecx,%edi
  sub    $0x1,%esi
  jne    L41
  add    %eax,%eax
  or     %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
L33:
  ret
```

assistant: ```c
unsigned __udivsi3(unsigned n, unsigned d) {
  unsigned q;
  unsigned r;
  unsigned sr;
  if (d == 0)
    return 0;
  if (n == 0)
    return 0;
  sr = __builtin_clz(d) - __builtin_clz(n);
  if (sr > 31)
    return 0;
  if (sr == 31)
    return n;
  ++sr;
  q = n << (32 - sr);
  r = n >> sr;
  unsigned carry = 0;
  for (; sr > 0; --sr) {
    r = (r << 1) | (q >> (31));
    q = (q << 1) | carry;
    const int s = (int)(d - r - 1) >> (31);
    carry = s & 1;
    r -= d & s;
  }
  q = (q << 1) | carry;
  return q;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L15:
  mov    $0x808d0018,%edi
  call   <__raw_readb@plt>
  and    $0x20,%eax
  test   %eax,%eax
  je     L6
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L15
  jmp    L36
L6:
  nop
L36:
  mov    -0x14(%rbp),%eax
  mov    $0x808d0000,%esi
  mov    %eax,%edi
  call   <__raw_writeb@plt>
  nop
  leave
  ret
```

assistant: ```c
void putc(int c) {
  int i;
  for (i = 0; i < 1000; i++) {
    if (!(__raw_readb(0x808d0018) & 0x20))
      break;
  }
  __raw_writeb(c, 0x808d0000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x3e8,%ebx
L14:
  mov    $0x808d0018,%edi
  call   <__raw_readb@plt>
  test   $0x20,%al
  je     L1
  sub    $0x1,%ebx
  jne    L14
L1:
  mov    $0x808d0000,%esi
  mov    %ebp,%edi
  call   <__raw_writeb@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void putc(int c) {
  int i;
  for (i = 0; i < 1000; i++) {
    if (!(__raw_readb(0x808d0018) & 0x20))
      break;
  }
  __raw_writeb(c, 0x808d0000);
}
```
user: What is the c source code of the assembly code below?

```asm
<putc>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%ebx
  je     L11
L15:
  mov    $0x808d0018,%edi
  call   <__raw_readb@plt>
  test   $0x20,%al
  jne    L10
L11:
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    $0x808d0000,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <__raw_writeb@plt>
```

assistant: ```c
void putc(int c) {
  int i;
  for (i = 0; i < 1000; i++) {
    if (!(__raw_readb(0x808d0018) & 0x20))
      break;
  }
  __raw_writeb(c, 0x808d0000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putc>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x8,%rsp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L19:
  sub    $0x1,%ebx
  je     L16
L14:
  mov    $0x808d0018,%edi
  call   <__raw_readb@plt>
  test   $0x20,%al
  jne    L19
L16:
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    $0x808d0000,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <__raw_writeb@plt>
```

assistant: ```c
void putc(int c) {
  int i;
  for (i = 0; i < 1000; i++) {
    if (!(__raw_readb(0x808d0018) & 0x20))
      break;
  }
  __raw_writeb(c, 0x808d0000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    -0x18(%rbp),%eax
  jmp    L31
L19:
  cmpl   $0x0,-0x18(%rbp)
  jne    L39
  mov    -0x14(%rbp),%eax
  jmp    L31
L39:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
L31:
  leave
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int x, y;
  x = (a > b) ? a : b;
  y = a + b - x;
  if (a == 0)
    return b;
  else if (b == 0)
    return a;
  else
    return gcd(y, (x % y));
}
```
user: What is the c source code of the assembly code below?

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  je     L0
  mov    %edi,%eax
  test   %esi,%esi
  jne    L1
L0:
  ret
L1:
  sub    $0x8,%rsp
  cmp    %edi,%esi
  cmovge %esi,%eax
  add    %esi,%edi
  sub    %eax,%edi
  cltd
  idiv   %edi
  mov    %edx,%esi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  int x, y;
  x = (a > b) ? a : b;
  y = a + b - x;
  if (a == 0)
    return b;
  else if (b == 0)
    return a;
  else
    return gcd(y, (x % y));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  lea    (%rdi,%rsi,1),%ecx
  cmovge %edi,%eax
  sub    %eax,%ecx
  test   %edi,%edi
  je     L11
  test   %esi,%esi
  jne    L42
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L35:
  test   %edx,%edx
  je     L11
L42:
  cltd
  mov    %ecx,%esi
  idiv   %ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  lea    (%rdx,%rcx,1),%edi
  cmovge %edx,%eax
  sub    %eax,%edi
  mov    %edi,%ecx
  test   %esi,%esi
  jne    L35
L33:
  mov    %edx,%eax
  ret
  xchg   %ax,%ax
L11:
  mov    %esi,%edx
  mov    %edx,%eax
  ret
L4:
  mov    %edi,%edx
  jmp    L33
```

assistant: ```c
int gcd(int a, int b) {
  int x, y;
  x = (a > b) ? a : b;
  y = a + b - x;
  if (a == 0)
    return b;
  else if (b == 0)
    return a;
  else
    return gcd(y, (x % y));
}
```
user: Translate the below assembly code into C programming language:

```asm
<gcd>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  lea    (%rdi,%rsi,1),%ecx
  cmovge %edi,%eax
  sub    %eax,%ecx
  test   %edi,%edi
  je     L26
  test   %esi,%esi
  jne    L30
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L20:
  test   %edx,%edx
  je     L26
L30:
  cltd
  mov    %ecx,%esi
  idiv   %ecx
  mov    %ecx,%eax
  cmp    %ecx,%edx
  lea    (%rdx,%rcx,1),%edi
  cmovge %edx,%eax
  sub    %eax,%edi
  mov    %edi,%ecx
  test   %esi,%esi
  jne    L20
L51:
  mov    %edx,%eax
  ret
  xchg   %ax,%ax
L26:
  mov    %esi,%edx
  mov    %edx,%eax
  ret
L10:
  mov    %edi,%edx
  jmp    L51
```

assistant: ```c
int gcd(int a, int b) {
  int x, y;
  x = (a > b) ? a : b;
  y = a + b - x;
  if (a == 0)
    return b;
  else if (b == 0)
    return a;
  else
    return gcd(y, (x % y));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tpdec2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  shr    %eax
  mov    %eax,-0x24(%rbp)
  mov    -0x3c(%rbp),%eax
  and    $0xfffffffe,%eax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L32
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  add    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addq   $0x2,-0x20(%rbp)
L32:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L25
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L12
L38:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L12:
  mov    -0x3c(%rbp),%edx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  jb     L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tpdec2(unsigned char *in, unsigned n, unsigned char *out) {
  unsigned char *op, *ip, *e;
  unsigned stride = n / 2;
  e = out + (n & ~(2 - 1));
  for (op = out, ip = in; op < e; ip++, op += 2) {
    unsigned char *p = ip;
    op[0] = *p;
    op[1] = *(p += stride);
  }
  for (ip = in + stride * 2; op < out + n;)
    *op++ = *ip++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tpdec2>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  shr    %r9d
  mov    %esi,%r11d
  and    $0xfffffffe,%esi
  lea    (%rdx,%rsi,1),%r10
  cmp    %r10,%rdx
  jae    L7
  mov    %rdi,%rcx
  mov    %rdx,%rax
  mov    %r9d,%r9d
L49:
  movzbl (%rcx),%edi
  mov    %dil,(%rax)
  movzbl (%rcx,%r9,1),%edi
  mov    %dil,0x1(%rax)
  add    $0x1,%rcx
  add    $0x2,%rax
  cmp    %rax,%r10
  ja     L49
  lea    (%rdx,%rsi,1),%rdi
L1:
  add    %r8,%rsi
  add    %r11,%rdx
  cmp    %rdi,%rdx
  jbe    L9
  sub    %rdi,%rdx
  mov    $0x0,%eax
L0:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L9:
  ret
L7:
  mov    %rdx,%rdi
  jmp    L1
```

assistant: ```c
void tpdec2(unsigned char *in, unsigned n, unsigned char *out) {
  unsigned char *op, *ip, *e;
  unsigned stride = n / 2;
  e = out + (n & ~(2 - 1));
  for (op = out, ip = in; op < e; ip++, op += 2) {
    unsigned char *p = ip;
    op[0] = *p;
    op[1] = *(p += stride);
  }
  for (ip = in + stride * 2; op < out + n;)
    *op++ = *ip++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tpdec2>:
  endbr64
  mov    %esi,%r9d
  mov    %esi,%r11d
  and    $0xfffffffe,%esi
  mov    %rdi,%r8
  lea    (%rdx,%rsi,1),%r10
  shr    %r9d
  cmp    %r10,%rdx
  jae    L26
  mov    %rdi,%rcx
  mov    %rdx,%rax
  nopw   0x0(%rax,%rax,1)
L43:
  movzbl (%rcx),%edi
  add    $0x2,%rax
  add    $0x1,%rcx
  mov    %dil,-0x2(%rax)
  movzbl -0x1(%rcx,%r9,1),%edi
  mov    %dil,-0x1(%rax)
  cmp    %rax,%r10
  ja     L43
  lea    (%rdx,%rsi,1),%rdi
L18:
  add    %r11,%rdx
  lea    (%r8,%rsi,1),%rcx
  xor    %eax,%eax
  mov    %rdx,%rsi
  sub    %rdi,%rsi
  cmp    %rdi,%rdx
  jbe    L5
  xchg   %ax,%ax
L30:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L30
L5:
  ret
  nopl   0x0(%rax)
L26:
  mov    %rdx,%rdi
  jmp    L18
```

assistant: ```c
void tpdec2(unsigned char *in, unsigned n, unsigned char *out) {
  unsigned char *op, *ip, *e;
  unsigned stride = n / 2;
  e = out + (n & ~(2 - 1));
  for (op = out, ip = in; op < e; ip++, op += 2) {
    unsigned char *p = ip;
    op[0] = *p;
    op[1] = *(p += stride);
  }
  for (ip = in + stride * 2; op < out + n;)
    *op++ = *ip++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_asn_junk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  jmp    L101
L77:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L124
  addq   $0x2,-0x128(%rbp)
  addl   $0x1,-0x114(%rbp)
  jmp    L101
L124:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L88
  lea    -0x118(%rbp),%rdx
  mov    -0x128(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_asn_int@plt>
  mov    %rax,-0x128(%rbp)
  jmp    L101
L88:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2,%al
  jne    L24
  lea    -0x118(%rbp),%rdx
  mov    -0x128(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_asn_int@plt>
  mov    %rax,-0x128(%rbp)
  jmp    L101
L24:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1a,%al
  jne    L108
  lea    -0x110(%rbp),%rcx
  mov    -0x128(%rbp),%rax
  mov    $0xff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_asn_text@plt>
  mov    %rax,-0x128(%rbp)
  jmp    L101
L108:
  addq   $0x2,-0x128(%rbp)
L101:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  jmp    L13
L49:
  addq   $0x2,-0x128(%rbp)
L13:
  mov    -0x114(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x114(%rbp)
  test   %eax,%eax
  jg     L49
  mov    -0x128(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

assistant: ```c
unsigned char *get_asn_junk(unsigned char *abp) {
  int seq_cnt = 0;
  int tmp;
  char string[256];
  while (*abp) {
    if (*abp == 0x30) {
      abp += 2;
      seq_cnt++;
    } else if (*abp == 1) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 2) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 26) {
      abp = get_asn_text(abp, string, sizeof(string) - 1);
    } else {
      abp += 2;
    }
  }
  while (seq_cnt-- > 0)
    abp += 2;
  return abp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_asn_junk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L88
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
  jmp    L61
L47:
  add    $0x2,%rdi
  add    $0x1,%ebx
L43:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L33
L61:
  cmp    $0x30,%dl
  je     L47
  cmp    $0x1,%dl
  je     L77
  cmp    $0x2,%dl
  je     L86
  cmp    $0x1a,%dl
  je     L84
  add    $0x2,%rdi
  jmp    L43
L77:
  lea    0xc(%rsp),%rsi
  call   <get_asn_int@plt>
  mov    %rax,%rdi
  jmp    L43
L86:
  lea    0xc(%rsp),%rsi
  call   <get_asn_int@plt>
  mov    %rax,%rdi
  jmp    L43
L84:
  mov    $0xff,%edx
  mov    %rbp,%rsi
  call   <get_asn_text@plt>
  mov    %rax,%rdi
  jmp    L43
L33:
  lea    -0x1(%rbx),%eax
  test   %ebx,%ebx
  jle    L68
L156:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L156
  mov    %ebx,%ebx
  lea    (%rdi,%rbx,2),%rax
L11:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
L88:
  mov    %rdi,%rax
  jmp    L11
L68:
  mov    %rdi,%rax
  jmp    L11
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *get_asn_junk(unsigned char *abp) {
  int seq_cnt = 0;
  int tmp;
  char string[256];
  while (*abp) {
    if (*abp == 0x30) {
      abp += 2;
      seq_cnt++;
    } else if (*abp == 1) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 2) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 26) {
      abp = get_asn_text(abp, string, sizeof(string) - 1);
    } else {
      abp += 2;
    }
  }
  while (seq_cnt-- > 0)
    abp += 2;
  return abp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_asn_junk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L129
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  jmp    L108
  nopl   0x0(%rax)
L115:
  cmp    $0x1,%dl
  je     L97
  cmp    $0x2,%dl
  je     L97
  cmp    $0x1a,%dl
  je     L40
  add    $0x2,%rdi
L69:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
L108:
  cmp    $0x30,%dl
  jne    L115
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  add    $0x1,%ebp
  test   %dl,%dl
  jne    L108
L15:
  test   %ebp,%ebp
  je     L129
  movslq %ebp,%rbp
  lea    (%rdi,%rbp,2),%rax
L35:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L62
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L97:
  lea    0xc(%rsp),%rsi
  call   <get_asn_int@plt>
  mov    %rax,%rdi
  jmp    L69
  nop
L40:
  mov    $0xff,%edx
  mov    %rbx,%rsi
  call   <get_asn_text@plt>
  mov    %rax,%rdi
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L129:
  mov    %rdi,%rax
  jmp    L35
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *get_asn_junk(unsigned char *abp) {
  int seq_cnt = 0;
  int tmp;
  char string[256];
  while (*abp) {
    if (*abp == 0x30) {
      abp += 2;
      seq_cnt++;
    } else if (*abp == 1) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 2) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 26) {
      abp = get_asn_text(abp, string, sizeof(string) - 1);
    } else {
      abp += 2;
    }
  }
  while (seq_cnt-- > 0)
    abp += 2;
  return abp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_asn_junk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  test   %dl,%dl
  je     L80
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  jmp    L90
  nopl   0x0(%rax)
L16:
  cmp    $0x1,%dl
  je     L57
  cmp    $0x2,%dl
  je     L57
  cmp    $0x1a,%dl
  je     L117
  add    $0x2,%rdi
L120:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L103
L90:
  cmp    $0x30,%dl
  jne    L16
  movzbl 0x2(%rdi),%edx
  add    $0x2,%rdi
  add    $0x1,%ebp
  test   %dl,%dl
  jne    L90
L103:
  test   %ebp,%ebp
  je     L80
  movslq %ebp,%rbp
  lea    (%rdi,%rbp,2),%rax
L128:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L57:
  lea    0xc(%rsp),%rsi
  call   <get_asn_int@plt>
  mov    %rax,%rdi
  jmp    L120
  nop
L117:
  mov    $0xff,%edx
  mov    %rbx,%rsi
  call   <get_asn_text@plt>
  mov    %rax,%rdi
  jmp    L120
  nopw   0x0(%rax,%rax,1)
L80:
  mov    %rdi,%rax
  jmp    L128
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *get_asn_junk(unsigned char *abp) {
  int seq_cnt = 0;
  int tmp;
  char string[256];
  while (*abp) {
    if (*abp == 0x30) {
      abp += 2;
      seq_cnt++;
    } else if (*abp == 1) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 2) {
      abp = get_asn_int(abp, &tmp);
    } else if (*abp == 26) {
      abp = get_asn_text(abp, string, sizeof(string) - 1);
    } else {
      abp += 2;
    }
  }
  while (seq_cnt-- > 0)
    abp += 2;
  return abp;
}
```