ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zrotatemat>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rsi
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  movabs $0x3f80000000000000,%rax
  xorps  D5(%rip),%xmm0
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x3f800000,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movss  %xmm1,(%rsp)
  movss  %xmm0,0x10(%rsp)
  movss  %xmm1,0x14(%rsp)
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
zrotatemat(mat, rs, rc) float mat[4][4];
float rs, rc;
{
  float mmat[4][4];
  mmat[0][0] = rc;
  mmat[0][1] = rs;
  mmat[0][2] = 0.0;
  mmat[0][3] = 0.0;
  mmat[1][0] = -rs;
  mmat[1][1] = rc;
  mmat[1][2] = 0.0;
  mmat[1][3] = 0.0;
  mmat[2][0] = 0.0;
  mmat[2][1] = 0.0;
  mmat[2][2] = 1.0;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<zrotatemat>:
  endbr64
  cvtsd2ss %xmm1,%xmm1
  movaps %xmm1,%xmm2
  sub    $0x58,%rsp
  cvtsd2ss %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  unpcklps %xmm0,%xmm2
  xorps  D2(%rip),%xmm0
  mov    %rdi,%rsi
  mov    D3(%rip),%rax
  mov    %rsp,%rdi
  mov    %rsi,%rdx
  movq   $0x0,0x8(%rsp)
  unpcklps %xmm1,%xmm0
  movlps %xmm2,(%rsp)
  movlps %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movups %xmm0,0x18(%rsp)
  movss  D28(%rip),%xmm0
  movups %xmm0,0x28(%rsp)
  call   <matrixmult@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D3
type_guessed: f32[2]
name: extract_symbolic_data
arguments: label: D28
type_guessed: f32

tool: {"D2": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D3": [0.0,1.0]}

tool: D28: 1

assistant: ```c
zrotatemat(mat, rs, rc) float mat[4][4];
float rs, rc;
{
  float mmat[4][4];
  mmat[0][0] = rc;
  mmat[0][1] = rs;
  mmat[0][2] = 0.0;
  mmat[0][3] = 0.0;
  mmat[1][0] = -rs;
  mmat[1][1] = rc;
  mmat[1][2] = 0.0;
  mmat[1][3] = 0.0;
  mmat[2][0] = 0.0;
  mmat[2][1] = 0.0;
  mmat[2][2] = 1.0;
  mmat[2][3] = 0.0;
  mmat[3][0] = 0.0;
  mmat[3][1] = 0.0;
  mmat[3][2] = 0.0;
  mmat[3][3] = 1.0;
  matrixmult(mmat, mat, mat);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L40
L46:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L40:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L44
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  jle    L46
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jg     L46
L44:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  call   <trunk@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <needle@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string

tool: D30: Input needle height please, should be MIN - MAX
>>

tool: D3: Sorry number should be MIN - MAX! Please try again =)


tool: D37: %d

tool: D21: Thanks!


assistant: ```c
int main(void) {
  int n;
  printf("Input needle height please, should be MIN - MAX\n>>");
  while ((scanf("%d", &n) == 1) && (n < 4 || n > 10))
    printf("Sorry number should be MIN - MAX! Please try again =)\n");
  printf("Thanks!\n");
  trunk(n / 2);
  needle(n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbp
  lea    D16(%rip),%rbx
  lea    D34(%rip),%r12
  jmp    L12
L10:
  mov    %r12,%rdi
  call   <printf@plt>
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L26
  mov    0x4(%rsp),%eax
  sub    $0x4,%eax
  cmp    $0x6,%eax
  ja     L10
L26:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <trunk@plt>
  mov    0x4(%rsp),%edi
  call   <needle@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D16
type: string
name: disassemble_data
arguments: label: D34
type: string
name: disassemble_data
arguments: label: D15
type: string

tool: D25: Input needle height please, should be MIN - MAX
>>

tool: D16: %d

tool: D34: Sorry number should be MIN - MAX! Please try again =)


tool: D15: Thanks!


assistant: ```c
int main(void) {
  int n;
  printf("Input needle height please, should be MIN - MAX\n>>");
  while ((scanf("%d", &n) == 1) && (n < 4 || n > 10))
    printf("Sorry number should be MIN - MAX! Please try again =)\n");
  printf("Thanks!\n");
  trunk(n / 2);
  needle(n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D26(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  jmp    L37
  nopl   (%rax)
L33:
  mov    0x4(%rsp),%eax
  sub    $0x4,%eax
  cmp    $0x6,%eax
  jbe    L19
  mov    %r12,%rdi
  call   <printf@plt>
L37:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L33
L19:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <trunk@plt>
  mov    0x4(%rsp),%edi
  call   <needle@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string

tool: D25: Input needle height please, should be MIN - MAX
>>

tool: D11: Sorry number should be MIN - MAX! Please try again =)


tool: D26: %d

tool: D34: Thanks!


assistant: ```c
int main(void) {
  int n;
  printf("Input needle height please, should be MIN - MAX\n>>");
  while ((scanf("%d", &n) == 1) && (n < 4 || n > 10))
    printf("Sorry number should be MIN - MAX! Please try again =)\n");
  printf("Thanks!\n");
  trunk(n / 2);
  needle(n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  jmp    L28
  nopl   (%rax)
L11:
  mov    0x4(%rsp),%eax
  sub    $0x4,%eax
  cmp    $0x6,%eax
  jbe    L21
  mov    %r12,%rdi
  call   <printf@plt>
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L11
L21:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  call   <trunk@plt>
  mov    0x4(%rsp),%edi
  call   <needle@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D17: Input needle height please, should be MIN - MAX
>>

tool: D15: Sorry number should be MIN - MAX! Please try again =)


tool: D19: %d

tool: D10: Thanks!


assistant: ```c
int main(void) {
  int n;
  printf("Input needle height please, should be MIN - MAX\n>>");
  while ((scanf("%d", &n) == 1) && (n < 4 || n > 10))
    printf("Sorry number should be MIN - MAX! Please try again =)\n");
  printf("Thanks!\n");
  trunk(n / 2);
  needle(n);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <replyv@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void reply(struct evhttp_request *req, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  replyv(req, fmt, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reply>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <replyv@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void reply(struct evhttp_request *req, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  replyv(req, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reply>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <replyv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void reply(struct evhttp_request *req, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  replyv(req, fmt, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reply>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <replyv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void reply(struct evhttp_request *req, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  replyv(req, fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_putdouble_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x25,%esi
  mov    %eax,%edi
  call   <verify_inf_size@plt>
  test   %rax,%rax
  je     L4
  mov    $0xffffffff,%eax
  jmp    L12
L4:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <convert_dtocl@plt>
  mov    %eax,%edi
  call   <convert_cltos@plt>
  mov    %eax,%edi
  call   <my_puts@plt>
L12:
  leave
  ret
```

assistant: ```c
int my_putdouble_base(double f, int b) {
  if (verify_inf_size(b, 37) != 0) {
    return -1;
  }
  return my_puts(convert_cltos(convert_dtocl(f, b)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_putdouble_base>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %edi,%ebx
  mov    $0x25,%esi
  call   <verify_inf_size@plt>
  test   %rax,%rax
  jne    L14
  mov    %ebx,%edi
  movq   %rbp,%xmm0
  call   <convert_dtocl@plt>
  mov    %eax,%edi
  call   <convert_cltos@plt>
  mov    %eax,%edi
  call   <my_puts@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int my_putdouble_base(double f, int b) {
  if (verify_inf_size(b, 37) != 0) {
    return -1;
  }
  return my_puts(convert_cltos(convert_dtocl(f, b)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_putdouble_base>:
  endbr64
  push   %rbp
  mov    $0x25,%esi
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <verify_inf_size@plt>
  test   %rax,%rax
  jne    L0
  movsd  0x8(%rsp),%xmm0
  mov    %ebp,%edi
  call   <convert_dtocl@plt>
  mov    %eax,%edi
  call   <convert_cltos@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  pop    %rbp
  jmp    10b0 <my_puts@plt>
L0:
  add    $0x10,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_putdouble_base(double f, int b) {
  if (verify_inf_size(b, 37) != 0) {
    return -1;
  }
  return my_puts(convert_cltos(convert_dtocl(f, b)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_putdouble_base>:
  endbr64
  push   %rbp
  mov    $0x25,%esi
  mov    %edi,%ebp
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <verify_inf_size@plt>
  test   %rax,%rax
  jne    L6
  movsd  0x8(%rsp),%xmm0
  mov    %ebp,%edi
  call   <convert_dtocl@plt>
  mov    %eax,%edi
  call   <convert_cltos@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  pop    %rbp
  jmp    10b0 <my_puts@plt>
L6:
  add    $0x10,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_putdouble_base(double f, int b) {
  if (verify_inf_size(b, 37) != 0) {
    return -1;
  }
  return my_puts(convert_cltos(convert_dtocl(f, b)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double sync(x)
double x;
{
  extern double sin();
  return (sin(x) / x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sync>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <sin@plt>
  movq   %rbx,%xmm1
  divsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

assistant: ```c
double sync(x)
double x;
{
  extern double sin();
  return (sin(x) / x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sync>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double sync(x)
double x;
{
  extern double sin();
  return (sin(x) / x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sync>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double sync(x)
double x;
{
  extern double sin();
  return (sin(x) / x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sp_ienv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x7,-0x14(%rbp)
  ja     L84
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xc,%eax
  jmp    L47
  mov    $0x6,%eax
  jmp    L47
  mov    $0x64,%eax
  jmp    L47
  mov    $0xc8,%eax
  jmp    L47
  mov    $0x3c,%eax
  jmp    L47
  mov    $0x14,%eax
  jmp    L47
  mov    $0xa,%eax
  jmp    L47
L84:
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <xerbla_@plt>
  mov    $0x0,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D10: sp_ienv

assistant: ```c
int sp_ienv(int ispec) {
  int i;
  switch (ispec) {
  case 1:
    return (12);
  case 2:
    return (6);
  case 3:
    return (100);
  case 4:
    return (200);
  case 5:
    return (60);
  case 6:
    return (20);
  case 7:
    return (10);
  }
  i = 1;
  xerbla_("sp_ienv", &i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sp_ienv>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edi
  ja     L6
  mov    %edi,%edi
  lea    D14(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x6,%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x18,%rsp
  ret
  mov    $0x64,%eax
  jmp    L25
  mov    $0xc8,%eax
  jmp    L25
  mov    $0x3c,%eax
  jmp    L25
  mov    $0x14,%eax
  jmp    L25
  mov    $0xa,%eax
  jmp    L25
L6:
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <xerbla_@plt>
  mov    $0x0,%eax
  jmp    L25
  mov    $0xc,%eax
  jmp    L25
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: sp_ienv

assistant: ```c
int sp_ienv(int ispec) {
  int i;
  switch (ispec) {
  case 1:
    return (12);
  case 2:
    return (6);
  case 3:
    return (100);
  case 4:
    return (200);
  case 5:
    return (60);
  case 6:
    return (20);
  case 7:
    return (10);
  }
  i = 1;
  xerbla_("sp_ienv", &i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sp_ienv>:
  endbr64
  sub    $0x18,%rsp
  sub    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x6,%edi
  ja     L25
  lea    D3(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
  nop
L25:
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  movl   $0x1,0x4(%rsp)
  call   <xerbla_@plt>
  xor    %eax,%eax
  jmp    L6
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string

tool: D3: 

tool: D12: sp_ienv

assistant: ```c
int sp_ienv(int ispec) {
  int i;
  switch (ispec) {
  case 1:
    return (12);
  case 2:
    return (6);
  case 3:
    return (100);
  case 4:
    return (200);
  case 5:
    return (60);
  case 6:
    return (20);
  case 7:
    return (10);
  }
  i = 1;
  xerbla_("sp_ienv", &i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sp_ienv>:
  endbr64
  sub    $0x18,%rsp
  sub    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x6,%edi
  ja     L13
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
  nop
L13:
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  movl   $0x1,0x4(%rsp)
  call   <xerbla_@plt>
  xor    %eax,%eax
  jmp    L18
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string

tool: D2: 

tool: D11: sp_ienv

assistant: ```c
int sp_ienv(int ispec) {
  int i;
  switch (ispec) {
  case 1:
    return (12);
  case 2:
    return (6);
  case 3:
    return (100);
  case 4:
    return (200);
  case 5:
    return (60);
  case 6:
    return (20);
  case 7:
    return (10);
  }
  i = 1;
  xerbla_("sp_ienv", &i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RNDGetDevice1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <RNDGetDevice2@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
struct UPnPDevice *RNDGetDevice1(struct UPnPDevice *device, int index) {
  int c_Index = -1;
  return (RNDGetDevice2(device, index, &c_Index));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RNDGetDevice1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  call   <RNDGetDevice2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct UPnPDevice *RNDGetDevice1(struct UPnPDevice *device, int index) {
  int c_Index = -1;
  return (RNDGetDevice2(device, index, &c_Index));
}
```
user: Translate the below assembly code into C programming language:

```asm
<RNDGetDevice1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <RNDGetDevice2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct UPnPDevice *RNDGetDevice1(struct UPnPDevice *device, int index) {
  int c_Index = -1;
  return (RNDGetDevice2(device, index, &c_Index));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RNDGetDevice1>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <RNDGetDevice2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct UPnPDevice *RNDGetDevice1(struct UPnPDevice *device, int index) {
  int c_Index = -1;
  return (RNDGetDevice2(device, index, &c_Index));
}
```