user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_ccv_median>:
  endbr64
  push   %r15
  push   %r14
  movslq %esi,%r14
  push   %r13
  mov    %edx,%r13d
  add    %r14d,%edx
  mov    %edx,%r15d
  push   %r12
  shr    $0x1f,%r15d
  push   %rbp
  mov    %rdi,%rbp
  add    %edx,%r15d
  push   %rbx
  sar    %r15d
  cmp    %r13d,%r14d
  jge    L148
  lea    0x1(%r14),%r10d
  cmp    %r13d,%r10d
  je     L11
  nopl   (%rax)
L38:
  mov    %edx,%eax
  movslq %r13d,%rcx
  shr    $0x1f,%eax
  lea    0x0(%rbp,%rcx,4),%rdi
  add    %edx,%eax
  mov    (%rdi),%esi
  sar    %eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%edx
  cmp    %esi,%edx
  jle    L146
  mov    %esi,(%rax)
  mov    %edx,%esi
  mov    %edx,(%rdi)
L146:
  movslq %r14d,%rdx
  shl    $0x2,%rdx
  lea    0x0(%rbp,%rdx,1),%r12
  mov    (%r12),%ecx
  cmp    %esi,%ecx
  jle    L8
  mov    %esi,(%r12)
  mov    %ecx,(%rdi)
  mov    (%r12),%ecx
L8:
  mov    (%rax),%esi
  cmp    %ecx,%esi
  jle    L24
  mov    %ecx,(%rax)
  mov    %esi,(%r12)
  mov    (%rax),%esi
L24:
  lea    0x4(%rbp,%rdx,1),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  movslq %r10d,%rax
  mov    %esi,(%rdx)
  mov    (%r12),%esi
  lea    0x4(%rbp,%rax,4),%r9
  mov    %r13d,%edx
  nopl   0x0(%rax)
L124:
  mov    (%r9),%r11d
  add    $0x1,%r10d
  mov    %r9,%rbx
  cmp    %esi,%r11d
  jl     L104
  movslq %edx,%rax
  lea    -0x4(%rbp,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %rax,%rdi
  mov    (%rax),%ecx
  mov    %edx,%r8d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %esi,%ecx
  jg     L74
  cmp    %edx,%r10d
  jg     L93
  mov    %ecx,(%r9)
  mov    %r11d,(%rdi)
  mov    (%r12),%esi
L104:
  add    $0x4,%r9
  jmp    L124
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %ecx,(%r12)
  mov    %esi,(%rdi)
  cmp    %edx,%r15d
  jge    L58
  lea    -0x2(%r8),%r13d
  mov    %r12,%rbx
  cmp    %r14d,%r13d
  jle    L148
L129:
  lea    0x1(%r14),%r10d
  cmp    %r13d,%r10d
  je     L42
  lea    (%r14,%r13,1),%edx
  jmp    L38
L58:
  mov    %r10d,%r14d
  cmp    %r14d,%r13d
  jg     L129
L148:
  movslq %r15d,%r15
  pop    %rbx
  mov    0x0(%rbp,%r15,4),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  lea    (%rdi,%r14,4),%rbx
L42:
  movslq %r13d,%r13
  mov    (%rbx),%edx
  lea    0x0(%rbp,%r13,4),%rax
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jle    L148
  mov    %ecx,(%rbx)
  mov    %edx,(%rax)
  jmp    L148
```

assistant: ```c
int _ccv_median(int *buf, int low, int high) {
  int middle, ll, hh, w;
  int median = (low + high) / 2;
  for (;;) {
    if (high <= low)
      return buf[median];
    if (high == low + 1) {
      if (buf[low] > buf[high])
        ((w) = (buf[low]), (buf[low]) = (buf[high]), (buf[high]) = (w));
      return buf[median];
    }
    middle = (low + high) / 2;
    if (buf[middle] > buf[high])
      ((w) = (buf[middle]), (buf[middle]) = (buf[high]), (buf[high]) = (w));
    if (buf[low] > buf[high])
      ((w) = (buf[low]), (buf[low]) = (buf[high]), (buf[high]) = (w));
    if (buf[middle] > buf[low])
      ((w) = (buf[middle]), (buf[middle]) = (buf[low]), (buf[low]) = (w));
    ((w) = (buf[middle]), (buf[middle]) = (buf[low + 1]), (buf[low + 1]) = (w));
    ll = low + 1;
    hh = high;
    for (;;) {
      do
        ll++;
      while (buf[low] > buf[ll]);
      do
        hh--;
      while (buf[hh] > buf[low]);
      if (hh < ll)
        break;
      ((w) = (buf[ll]), (buf[ll]) = (buf[hh]), (buf[hh]) = (w));
    }
    ((w) = (buf[low]), (buf[low]) = (buf[hh]), (buf[hh]) = (w));
    if (hh <= median)
      low = ll;
    else if (hh >= median)
      high = hh - 1;
  }
}
```