ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shift_string_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L19
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L19:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L10
  mov    -0x8(%rbp),%rax
  jmp    L24
L10:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L24:
  leave
  ret
```

assistant: ```c
char *shift_string_left(char *input, int cnt, char *buf) {
  char *s;
  int origlen;
  if (buf) {
    strcpy(buf, input);
    s = buf;
  } else
    s = input;
  if (!cnt)
    return (s);
  origlen = strlen(s);
  memmove(s, s + cnt, (origlen - cnt));
  *(s + (origlen - cnt)) = ('\0');
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shift_string_left>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%r12
  test   %rdx,%rdx
  je     L29
  mov    %rdx,%rbp
  mov    %rdi,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%r12
L29:
  test   %ebx,%ebx
  jne    L4
L27:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %ebx,%eax
  mov    %eax,%ebp
  movslq %ebx,%rsi
  add    %r12,%rsi
  mov    %eax,%edx
  mov    %r12,%rdi
  call   <memmove@plt>
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  jmp    L27
```

assistant: ```c
char *shift_string_left(char *input, int cnt, char *buf) {
  char *s;
  int origlen;
  if (buf) {
    strcpy(buf, input);
    s = buf;
  } else
    s = input;
  if (!cnt)
    return (s);
  origlen = strlen(s);
  memmove(s, s + cnt, (origlen - cnt));
  *(s + (origlen - cnt)) = ('\0');
  return (s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shift_string_left>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %rdx,%rdx
  je     L16
  mov    %rdx,%rbp
  mov    %rdi,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%r12
L16:
  test   %ebx,%ebx
  je     L19
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebx,%rsi
  mov    %r12,%rdi
  sub    %ebx,%eax
  add    %r12,%rsi
  movslq %eax,%rbp
  mov    %ebp,%edx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbp,1)
L19:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *shift_string_left(char *input, int cnt, char *buf) {
  char *s;
  int origlen;
  if (buf) {
    strcpy(buf, input);
    s = buf;
  } else
    s = input;
  if (!cnt)
    return (s);
  origlen = strlen(s);
  memmove(s, s + cnt, (origlen - cnt));
  *(s + (origlen - cnt)) = ('\0');
  return (s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shift_string_left>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %rdx,%rdx
  je     L13
  mov    %rdx,%rbp
  mov    %rdi,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%r12
L13:
  test   %ebx,%ebx
  je     L12
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebx,%rsi
  mov    %r12,%rdi
  sub    %ebx,%eax
  add    %r12,%rsi
  movslq %eax,%rbp
  mov    %ebp,%edx
  call   <memmove@plt>
  movb   $0x0,(%r12,%rbp,1)
L12:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *shift_string_left(char *input, int cnt, char *buf) {
  char *s;
  int origlen;
  if (buf) {
    strcpy(buf, input);
    s = buf;
  } else
    s = input;
  if (!cnt)
    return (s);
  origlen = strlen(s);
  memmove(s, s + cnt, (origlen - cnt));
  *(s + (origlen - cnt)) = ('\0');
  return (s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ip_checksum_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L49:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0xe(%rbp)
  movzwl -0xe(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x2,-0x8(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  ja     L49
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L15
L46:
  mov    -0xc(%rbp),%eax
  movzwl %ax,%edx
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  test   %eax,%eax
  jne    L46
  mov    -0xc(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short ip_checksum_1(const char *buf, size_t usize) {
  unsigned size = (unsigned)usize;
  unsigned sum = 0;
  int i;
  for (i = 0; i < size - 1; i += 2) {
    unsigned short word16 = *(unsigned short *)&buf[i];
    sum += word16;
  }
  if (size & 1) {
    unsigned short word16 = (unsigned char)buf[i];
    sum += word16;
  }
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ip_checksum_1>:
  endbr64
  cmp    $0x1,%esi
  je     L55
  mov    %rdi,%rdx
  lea    -0x2(%rsi),%r9d
  shr    %r9d
  mov    %r9d,%eax
  lea    0x2(%rdi,%rax,2),%r8
  mov    $0x0,%eax
L28:
  movzwl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x2,%rdx
  cmp    %r8,%rdx
  jne    L28
  lea    0x2(%r9,%r9,1),%edx
  test   $0x1,%sil
  jne    L10
L41:
  mov    %eax,%edx
  shr    $0x10,%edx
  je     L38
L47:
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  jne    L47
L38:
  not    %eax
  ret
L55:
  mov    $0x0,%edx
  mov    $0x0,%eax
L10:
  movslq %edx,%rdx
  movzbl (%rdi,%rdx,1),%edx
  add    %edx,%eax
  jmp    L41
```

assistant: ```c
unsigned short ip_checksum_1(const char *buf, size_t usize) {
  unsigned size = (unsigned)usize;
  unsigned sum = 0;
  int i;
  for (i = 0; i < size - 1; i += 2) {
    unsigned short word16 = *(unsigned short *)&buf[i];
    sum += word16;
  }
  if (size & 1) {
    unsigned short word16 = (unsigned char)buf[i];
    sum += word16;
  }
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ip_checksum_1>:
  endbr64
  cmp    $0x1,%esi
  je     L11
  lea    -0x2(%rsi),%r9d
  mov    %rdi,%rdx
  shr    %r9d
  mov    %r9d,%eax
  lea    0x2(%rdi,%rax,2),%r8
  xor    %eax,%eax
  nopl   (%rax)
L17:
  movzwl (%rdx),%ecx
  add    $0x2,%rdx
  add    %ecx,%eax
  cmp    %rdx,%r8
  jne    L17
  and    $0x1,%esi
  lea    0x2(%r9,%r9,1),%edx
  je     L20
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L26:
  movzwl %ax,%eax
  add    %edx,%eax
L20:
  mov    %eax,%edx
  shr    $0x10,%edx
  jne    L26
  not    %eax
  ret
  nop
L68:
  movslq %edx,%rdx
  add    %rdx,%rdi
L47:
  movzbl (%rdi),%edx
  add    %edx,%eax
  jmp    L20
  nopl   (%rax)
L11:
  xor    %eax,%eax
  jmp    L47
```

assistant: ```c
unsigned short ip_checksum_1(const char *buf, size_t usize) {
  unsigned size = (unsigned)usize;
  unsigned sum = 0;
  int i;
  for (i = 0; i < size - 1; i += 2) {
    unsigned short word16 = *(unsigned short *)&buf[i];
    sum += word16;
  }
  if (size & 1) {
    unsigned short word16 = (unsigned char)buf[i];
    sum += word16;
  }
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ip_checksum_1>:
  endbr64
  mov    %esi,%eax
  mov    %rdi,%rcx
  mov    %rsi,%r8
  sub    $0x1,%eax
  je     L64
  lea    -0x2(%rsi),%edx
  mov    %edx,%esi
  shr    %esi
  add    $0x1,%esi
  cmp    $0xd,%edx
  jbe    L44
  mov    %rdi,%rdx
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %esi,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rcx,%rdi,1),%rdi
  nopl   0x0(%rax)
L115:
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  movdqa %xmm0,%xmm3
  punpcklwd %xmm2,%xmm0
  punpckhwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rdi,%rdx
  jne    L115
  movdqa %xmm1,%xmm0
  mov    %esi,%r9d
  psrldq $0x8,%xmm0
  and    $0xfffffff8,%r9d
  paddd  %xmm0,%xmm1
  lea    (%r9,%r9,1),%edi
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%edx
  cmp    %esi,%r9d
  je     L140
L153:
  movslq %edi,%r9
  movzwl (%rcx,%r9,1),%r9d
  add    %edx,%r9d
  lea    0x2(%rdi),%edx
  cmp    %eax,%edx
  jae    L57
  movslq %edx,%rdx
  movzwl (%rcx,%rdx,1),%edx
  add    %edx,%r9d
  lea    0x4(%rdi),%edx
  cmp    %edx,%eax
  jbe    L57
  movslq %edx,%rdx
  movzwl (%rcx,%rdx,1),%edx
  add    %edx,%r9d
  lea    0x6(%rdi),%edx
  cmp    %edx,%eax
  jbe    L57
  movslq %edx,%rdx
  movzwl (%rcx,%rdx,1),%edx
  add    %edx,%r9d
  lea    0x8(%rdi),%edx
  cmp    %edx,%eax
  jbe    L57
  movslq %edx,%rdx
  movzwl (%rcx,%rdx,1),%edx
  add    %edx,%r9d
  lea    0xa(%rdi),%edx
  cmp    %edx,%eax
  jbe    L57
  movslq %edx,%rdx
  add    $0xc,%edi
  movzwl (%rcx,%rdx,1),%edx
  add    %r9d,%edx
  cmp    %edi,%eax
  jbe    L140
  movslq %edi,%rdi
  movzwl (%rcx,%rdi,1),%eax
  add    %edx,%eax
L51:
  add    %esi,%esi
  and    $0x1,%r8d
  je     L149
  movslq %esi,%rsi
  add    %rsi,%rcx
L64:
  movzbl (%rcx),%edx
  add    %edx,%eax
  jmp    L149
  nopl   0x0(%rax)
L26:
  movzwl %ax,%eax
  add    %edx,%eax
L149:
  mov    %eax,%edx
  shr    $0x10,%edx
  jne    L26
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %r9d,%eax
  jmp    L51
  nopl   (%rax)
L140:
  mov    %edx,%eax
  jmp    L51
L44:
  xor    %edi,%edi
  xor    %edx,%edx
  jmp    L153
```

assistant: ```c
unsigned short ip_checksum_1(const char *buf, size_t usize) {
  unsigned size = (unsigned)usize;
  unsigned sum = 0;
  int i;
  for (i = 0; i < size - 1; i += 2) {
    unsigned short word16 = *(unsigned short *)&buf[i];
    sum += word16;
  }
  if (size & 1) {
    unsigned short word16 = (unsigned char)buf[i];
    sum += word16;
  }
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<perm_uniform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <tprintf@plt>
  mov    $0x0,%eax
  jmp    L11
L12:
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L50:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L50
  movl   $0x0,-0x14(%rbp)
  jmp    L42
L45:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <int_uniform@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: Not enough memory!


assistant: ```c
int *perm_uniform(int n, int base, int *seed) {
  int i, j, k, *p;
  if ((p = (int *)malloc(n * sizeof(int))) == NULL) {
    tprintf("Not enough memory!\n");
    return (NULL);
  }
  for (i = 0; i < n; i++)
    p[i] = i + base;
  for (i = 0; i < n; i++) {
    j = int_uniform(i, n - 1, seed);
    k = p[i];
    p[i] = p[j];
    p[j] = k;
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<perm_uniform>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebx
  mov    %rdx,%r13
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L31
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    %rax,%rbp
  add    %r12d,%ebx
  test   %r12d,%r12d
  jle    L13
L21:
  mov    %edx,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %ebx,%edx
  jne    L21
  mov    $0x0,%ebx
  lea    -0x1(%r12),%r15d
L40:
  mov    %r13,%rdx
  mov    %r15d,%esi
  mov    %ebx,%edi
  call   <int_uniform@plt>
  mov    0x0(%rbp),%edx
  cltq
  lea    (%r14,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp)
  mov    %edx,(%rax)
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r12d
  jne    L40
L13:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  lea    D4(%rip),%rdi
  call   <tprintf@plt>
  mov    $0x0,%r14d
  jmp    L13
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: Not enough memory!


assistant: ```c
int *perm_uniform(int n, int base, int *seed) {
  int i, j, k, *p;
  if ((p = (int *)malloc(n * sizeof(int))) == NULL) {
    tprintf("Not enough memory!\n");
    return (NULL);
  }
  for (i = 0; i < n; i++)
    p[i] = i + base;
  for (i = 0; i < n; i++) {
    j = int_uniform(i, n - 1, seed);
    k = p[i];
    p[i] = p[j];
    p[j] = k;
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<perm_uniform>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L20
  test   %ebp,%ebp
  jle    L13
  mov    %ebx,%eax
  mov    %r12,%r14
  lea    0x0(%rbp,%rbx,1),%ecx
  mov    %r12,%rdx
  nopl   0x0(%rax)
L33:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %ecx,%eax
  jne    L33
  lea    -0x1(%rbp),%r15d
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r13,%rdx
  mov    %ebx,%edi
  mov    %r15d,%esi
  add    $0x1,%ebx
  call   <int_uniform@plt>
  mov    (%r14),%edx
  add    $0x4,%r14
  cltq
  lea    (%r12,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%r14)
  mov    %edx,(%rax)
  cmp    %ebx,%ebp
  jne    L25
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  lea    D1(%rip),%rdi
  call   <tprintf@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: Not enough memory!


assistant: ```c
int *perm_uniform(int n, int base, int *seed) {
  int i, j, k, *p;
  if ((p = (int *)malloc(n * sizeof(int))) == NULL) {
    tprintf("Not enough memory!\n");
    return (NULL);
  }
  for (i = 0; i < n; i++)
    p[i] = i + base;
  for (i = 0; i < n; i++) {
    j = int_uniform(i, n - 1, seed);
    k = p[i];
    p[i] = p[j];
    p[j] = k;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<perm_uniform>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  shl    $0x2,%edi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L47
  test   %r12d,%r12d
  jle    L57
  lea    -0x1(%r12),%r15d
  cmp    $0x2,%r15d
  jbe    L56
  mov    %r12d,%edx
  movd   %ebx,%xmm4
  movdqa D16(%rip),%xmm1
  movdqa D23(%rip),%xmm2
  shr    $0x2,%edx
  pshufd $0x0,%xmm4,%xmm3
  shl    $0x4,%rdx
  add    %rax,%rdx
  nopl   0x0(%rax)
L40:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm2,%xmm1
  paddd  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L40
  mov    %r12d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r12b
  je     L69
L58:
  movslq %eax,%rdx
  lea    (%rbx,%rax,1),%esi
  mov    %esi,0x0(%r13,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L69
  add    %ebx,%edx
  add    $0x2,%eax
  mov    %edx,0x4(%r13,%rcx,1)
  cmp    %eax,%r12d
  jle    L69
  add    %eax,%ebx
  mov    %ebx,0x8(%r13,%rcx,1)
L69:
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %r14,%rdx
  mov    %ebx,%edi
  mov    %r15d,%esi
  add    $0x1,%ebx
  call   <int_uniform@plt>
  mov    0x0(%rbp),%edx
  add    $0x4,%rbp
  cltq
  lea    0x0(%r13,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%rbp)
  mov    %edx,(%rax)
  cmp    %ebx,%r12d
  jne    L38
L57:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L47:
  lea    D27(%rip),%rdi
  call   <tprintf@plt>
  jmp    L57
L56:
  xor    %eax,%eax
  jmp    L58
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: byte[16]
name: unpack_data
arguments: label: D23
data_type: byte[16]
name: unpack_data
arguments: label: D27
data_type: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D23": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D27: Not enough memory!


assistant: ```c
int *perm_uniform(int n, int base, int *seed) {
  int i, j, k, *p;
  if ((p = (int *)malloc(n * sizeof(int))) == NULL) {
    tprintf("Not enough memory!\n");
    return (NULL);
  }
  for (i = 0; i < n; i++)
    p[i] = i + base;
  for (i = 0; i < n; i++) {
    j = int_uniform(i, n - 1, seed);
    k = p[i];
    p[i] = p[j];
    p[j] = k;
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <inc@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  n = atoi(argv[1]);
  inc(&n);
  printf("%d\n", n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <inc@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  n = atoi(argv[1]);
  inc(&n);
  printf("%d\n", n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <atoi@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <inc@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  n = atoi(argv[1]);
  inc(&n);
  printf("%d\n", n);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <atoi@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <inc@plt>
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  n = atoi(argv[1]);
  inc(&n);
  printf("%d\n", n);
  return 0;
}
```