user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1818(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r15
  test   %rsi,%rsi
  je     L64
  mov    %rsi,%rdi
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    %eax,%r14d
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  movslq %r14d,%rax
  mov    $0x1,%r12d
  lea    0x810(%rsp),%r14
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L17:
  mov    %rbx,%rbp
  mov    %r15,%rsi
  mov    %r14,%rdi
  sub    %r15,%rbp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <memcpy@plt>
  mov    %r14,%rdi
  movb   $0x0,0x810(%rsp,%rbp,1)
  mov    %r12d,%ebp
  call   <strdup@plt>
  mov    (%rsp),%rcx
  mov    %r13,%rsi
  mov    %rax,-0x8(%rcx,%r12,8)
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%r15
  mov    %r15,%rdi
  call   <strstr@plt>
  mov    %r12,%r9
  add    $0x1,%r12
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L17
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %r9,0x8(%rsp)
  lea    0x1(%rbp),%ebx
  call   <strchr@plt>
  mov    %r15,%rsi
  mov    %r14,%rdi
  movslq %ebx,%rbx
  sub    %r15,%rax
  shl    $0x3,%rbx
  mov    %eax,%edx
  mov    %rax,%r13
  call   <memcpy@plt>
  movslq %r13d,%r13
  mov    %r14,%rdi
  movb   $0x0,0x810(%rsp,%r13,1)
  call   <strdup@plt>
  lea    0x10(,%rbp,8),%edi
  mov    %rax,%r8
  movslq %ebp,%rax
  mov    %r8,0x10(%rsp,%rax,8)
  call   <malloc@plt>
  mov    0x8(%rsp),%r9
  mov    %rax,%r13
  mov    %r9d,%edx
  cmp    $0x2,%r9d
  jbe    L18
  add    $0x1,%r9d
  mov    (%rsp),%r12
  mov    %r9d,%eax
  shr    %eax
  sub    %r13,%r12
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%r13,%rax,1),%rdx
  mov    %r13,%rax
  nopl   0x0(%rax,%rax,1)
L76:
  movdqa (%rax,%r12,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L76
  mov    %r9d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r9d
  je     L32
  mov    %eax,%edx
  cltq
  mov    0x10(%rsp,%rax,8),%rax
  mov    %rax,0x0(%r13,%rdx,8)
L32:
  movq   $0x0,0x0(%r13,%rbx,1)
L40:
  mov    0x1818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1828,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %r15,%rdi
  mov    %rax,%r13
  call   <strdup@plt>
  movq   $0x0,0x8(%r13)
  mov    %rax,0x0(%r13)
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %esi,%esi
  mov    %r15,%rdi
  lea    0x810(%rsp),%rbp
  call   <strchr@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  sub    %r15,%rax
  mov    %eax,%edx
  mov    %rax,%rbx
  call   <memcpy@plt>
  movslq %ebx,%rbx
  mov    %rbp,%rdi
  movb   $0x0,0x810(%rsp,%rbx,1)
  mov    $0x8,%ebx
  call   <strdup@plt>
  mov    $0x10,%edi
  mov    %rax,0x10(%rsp)
  call   <malloc@plt>
  lea    0x10(%rsp),%rcx
  xor    %edx,%edx
  mov    %rcx,(%rsp)
  mov    %rax,%r13
L18:
  mov    (%rsp),%r12
  lea    0x8(%rax,%rdx,8),%rcx
  sub    %rax,%r12
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    (%r12,%rax,1),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rcx
  jne    L66
  jmp    L32
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **my_split(char *str, char *spl) {
  char **ret, *buffer[256], buf[4096];
  int i;
  if (!spl) {
    ret = (char **)malloc(2 * sizeof(char *));
    ret[0] = (char *)strdup(str);
    ret[1] = NULL;
    return (ret);
  }
  int count = 0;
  char *fptr = str;
  const int spl_len = strlen(spl);
  char *sptr = strstr(fptr, spl);
  while (sptr) {
    i = sptr - fptr;
    memcpy(buf, fptr, i);
    buf[i] = '\0';
    buffer[count++] = (char *)strdup(buf);
    fptr = sptr + spl_len;
    sptr = strstr(fptr, spl);
  }
  sptr = strchr(fptr, '\0');
  i = sptr - fptr;
  memcpy(buf, fptr, i);
  buf[i] = '\0';
  buffer[count++] = (char *)strdup(buf);
  ret = (char **)malloc((count + 1) * sizeof(char *));
  for (i = 0; i < count; i++) {
    ret[i] = buffer[i];
  }
  ret[count] = NULL;
  return (ret);
}
```