ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ip4_scan>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  mov    %rsp,%r14
L38:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L6
  mov    (%rsp),%rdx
  mov    %dl,(%r12,%rbp,1)
  mov    %eax,%edx
  add    %rbx,%rdx
  add    %r13d,%eax
  cmp    $0x3,%rbp
  je     L6
  cmpb   $0x2e,(%rdx)
  jne    L17
  lea    0x1(%rdx),%rbx
  lea    0x1(%rax),%r13d
  add    $0x1,%rbp
  jmp    L38
L17:
  mov    $0x0,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int ip4_scan(const char *s, char ip[4]) {
  unsigned long u = 0;
  unsigned int i = 0, j = 0, len = 0;
  while (j < 4) {
    i = scan_ulong(s, &u);
    if (!i)
      return 0;
    ip[j++] = u;
    s += i;
    len += i;
    if (j == 4)
      break;
    if (*s != '.')
      return 0;
    ++s;
    ++len;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<ip4_scan>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    0x3(%rsi),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movq   $0x0,(%rsp)
  mov    %r12,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L28
L32:
  mov    (%rsp),%rdx
  mov    %dl,(%r14)
  mov    %eax,%edx
  add    %ebp,%eax
  add    %rdx,%rbx
  cmp    %r13,%r14
  je     L10
  add    $0x1,%r14
  cmpb   $0x2e,(%rbx)
  jne    L28
  add    $0x1,%rbx
  mov    %r12,%rsi
  lea    0x1(%rax),%ebp
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  test   %eax,%eax
  jne    L32
L28:
  xor    %eax,%eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int ip4_scan(const char *s, char ip[4]) {
  unsigned long u = 0;
  unsigned int i = 0, j = 0, len = 0;
  while (j < 4) {
    i = scan_ulong(s, &u);
    if (!i)
      return 0;
    ip[j++] = u;
    s += i;
    len += i;
    if (j == 4)
      break;
    if (*s != '.')
      return 0;
    ++s;
    ++len;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ip4_scan>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    0x3(%rsi),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movq   $0x0,(%rsp)
  mov    %r12,%rsi
  call   <scan_ulong@plt>
  test   %eax,%eax
  je     L12
L48:
  mov    (%rsp),%rdx
  mov    %dl,(%r14)
  mov    %eax,%edx
  add    %ebp,%eax
  add    %rdx,%rbx
  cmp    %r13,%r14
  je     L31
  add    $0x1,%r14
  cmpb   $0x2e,(%rbx)
  jne    L12
  add    $0x1,%rbx
  mov    %r12,%rsi
  lea    0x1(%rax),%ebp
  mov    %rbx,%rdi
  call   <scan_ulong@plt>
  test   %eax,%eax
  jne    L48
L12:
  xor    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int ip4_scan(const char *s, char ip[4]) {
  unsigned long u = 0;
  unsigned int i = 0, j = 0, len = 0;
  while (j < 4) {
    i = scan_ulong(s, &u);
    if (!i)
      return 0;
    ip[j++] = u;
    s += i;
    len += i;
    if (j == 4)
      break;
    if (*s != '.')
      return 0;
    ++s;
    ++len;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stradpt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  cmpq   $0x0,-0x30(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jge    L107
L2:
  mov    $0x0,%eax
  jmp    L62
L107:
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L80
L32:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L89
L97:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L92
  addl   $0x1,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jne    L1
  mov    $0x1,%eax
  jmp    L62
L1:
  addl   $0x1,-0x18(%rbp)
L89:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jle    L97
  jmp    L60
L92:
  nop
L60:
  addl   $0x1,-0x1c(%rbp)
L80:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L32
  mov    $0x0,%eax
L62:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stradpt(char *str1, char *str2) {
  if (NULL == str1 || NULL == str2 || strlen(str1) < strlen(str2))
    return 0;
  int i = 0, j = 0, k = 0;
  for (i = 0; i <= strlen(str1) - strlen(str2) + 1; i++) {
    k = i;
    for (j = 0; j <= strlen(str2); j++) {
      if (str1[k] == str2[j])
        k++;
      else
        break;
      if (j == strlen(str2))
        return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stradpt>:
  endbr64
  test   %rdi,%rdi
  je     L70
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L67
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%ebx
  jl     L67
  mov    %r14,%r13
  mov    $0x0,%r15d
  jmp    L97
L87:
  add    $0x1,%r15d
  add    $0x1,%r13
L97:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %eax,%ebx
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  jl     L45
  mov    $0x0,%ebx
L94:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%r12d
  cmp    %ebx,%eax
  jl     L87
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  jne    L87
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L86
  add    $0x1,%rbx
  jmp    L94
L45:
  mov    $0x0,%eax
  jmp    L67
L86:
  mov    $0x1,%eax
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int stradpt(char *str1, char *str2) {
  if (NULL == str1 || NULL == str2 || strlen(str1) < strlen(str2))
    return 0;
  int i = 0, j = 0, k = 0;
  for (i = 0; i <= strlen(str1) - strlen(str2) + 1; i++) {
    k = i;
    for (j = 0; j <= strlen(str2); j++) {
      if (str1[k] == str2[j])
        k++;
      else
        break;
      if (j == strlen(str2))
        return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stradpt>:
  endbr64
  test   %rdi,%rdi
  je     L64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L29
  mov    %rdi,%r14
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L29
  mov    %r14,%r13
  xor    %r15d,%r15d
L21:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  sub    %eax,%ebx
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  jl     L29
  xor    %ebx,%ebx
  jmp    L78
  nop
L14:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  jne    L1
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L36
  add    $0x1,%rbx
L78:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L14
L1:
  add    $0x1,%r15d
  add    $0x1,%r13
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L36:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int stradpt(char *str1, char *str2) {
  if (NULL == str1 || NULL == str2 || strlen(str1) < strlen(str2))
    return 0;
  int i = 0, j = 0, k = 0;
  for (i = 0; i <= strlen(str1) - strlen(str2) + 1; i++) {
    k = i;
    for (j = 0; j <= strlen(str2); j++) {
      if (str1[k] == str2[j])
        k++;
      else
        break;
      if (j == strlen(str2))
        return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stradpt>:
  endbr64
  test   %rdi,%rdi
  je     L64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L84
  mov    %rdi,%r14
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L84
  mov    %r14,%r13
  xor    %r15d,%r15d
L34:
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  sub    %eax,%ebx
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  jl     L84
  xor    %ebx,%ebx
  jmp    L25
  nop
L33:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    %al,0x0(%r13,%rbx,1)
  jne    L23
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  je     L88
  add    $0x1,%rbx
L25:
  mov    %rbp,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L33
L23:
  add    $0x1,%r15d
  add    $0x1,%r13
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L84:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L88:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L64:
  xor    %eax,%eax
  ret
```

assistant: ```c
int stradpt(char *str1, char *str2) {
  if (NULL == str1 || NULL == str2 || strlen(str1) < strlen(str2))
    return 0;
  int i = 0, j = 0, k = 0;
  for (i = 0; i <= strlen(str1) - strlen(str2) + 1; i++) {
    k = i;
    for (j = 0; j <= strlen(str2); j++) {
      if (str1[k] == str2[j])
        k++;
      else
        break;
      if (j == strlen(str2))
        return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x4,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    %edx,%eax
  mov    %ecx,%ebx
  sub    $0x1,%ebx
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ecx,-0x14(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: string

tool: D17: a # %d  b # %d  c # %d  d = %d


assistant: ```c
int main(void) {
  int a, b;
  int c, d;
  a = 4;
  b = 7;
  c = d = 0;
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  __asm__("movl %2, %%eax;"
          "movl %3, %%ebx;"
          "subl $1, %%ebx;"
          "movl %%eax, %0;"
          "movl %%ebx, %1;"
          : "=r"(c), "=r"(d)
          : "r"(a), "r"(b)
          : "%eax", "%ebx");
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x7,%edx
  mov    $0x4,%esi
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%ecx
  mov    $0x7,%r8d
  mov    %ecx,%eax
  mov    %r8d,%ebx
  sub    $0x1,%ebx
  mov    %eax,%ecx
  mov    %ebx,%r8d
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: a # %d  b # %d  c # %d  d = %d


assistant: ```c
int main(void) {
  int a, b;
  int c, d;
  a = 4;
  b = 7;
  c = d = 0;
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  __asm__("movl %2, %%eax;"
          "movl %3, %%ebx;"
          "subl $1, %%ebx;"
          "movl %%eax, %0;"
          "movl %%ebx, %1;"
          : "=r"(c), "=r"(d)
          : "r"(a), "r"(b)
          : "%eax", "%ebx");
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x7,%edx
  mov    $0x4,%esi
  xor    %eax,%eax
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    $0x7,%r8d
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %ecx,%eax
  mov    %r8d,%ebx
  sub    $0x1,%ebx
  mov    %eax,%ecx
  mov    %ebx,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: a # %d  b # %d  c # %d  d = %d


assistant: ```c
int main(void) {
  int a, b;
  int c, d;
  a = 4;
  b = 7;
  c = d = 0;
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  __asm__("movl %2, %%eax;"
          "movl %3, %%ebx;"
          "subl $1, %%ebx;"
          "movl %%eax, %0;"
          "movl %%ebx, %1;"
          : "=r"(c), "=r"(d)
          : "r"(a), "r"(b)
          : "%eax", "%ebx");
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %rbx
  mov    %rbp,%rdi
  mov    $0x7,%edx
  mov    $0x4,%esi
  xor    %eax,%eax
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    $0x7,%r8d
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    %ecx,%eax
  mov    %r8d,%ebx
  sub    $0x1,%ebx
  mov    %eax,%ecx
  mov    %ebx,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: a # %d  b # %d  c # %d  d = %d


assistant: ```c
int main(void) {
  int a, b;
  int c, d;
  a = 4;
  b = 7;
  c = d = 0;
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  __asm__("movl %2, %%eax;"
          "movl %3, %%ebx;"
          "subl $1, %%ebx;"
          "movl %%eax, %0;"
          "movl %%ebx, %1;"
          : "=r"(c), "=r"(d)
          : "r"(a), "r"(b)
          : "%eax", "%ebx");
  printf("a # %d  b # %d  c # %d  d = %d\n", a, b, c, d);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int __attribute__((generic_vector)) A;
  float __attribute__((generic_vector)) B;
  int a;
  float b;
  A = A + a;
  A = a + A;
  B = b + B;
  A = A + A;
  A = A - a;
  A = a - A;
  B = b - B;
  A = A - A;
  A = A * a;
  A = a * A;
  B = b * B;
  A = A * A;
  A = A / a;
  A = a / A;
  B = b / B;
  A = A / A;
  A = A | a;
  A = a | A;
  A = A | A;
  A = A & a;
  A = a & A;
  A = A & A;
  A = A ^ a;
  A = a ^ A;
  A = A ^ A;
  A += A + a;
  A += a + A;
  B += b + B;
  A += A + A;
  A -= A + a;
  A -= a + A;
  B -= b + B;
  A -= A + A;
  A *= A + a;
  A *= a + A;
  B *= b + B;
  A *= A + A;
  A /= A + a;
  A /= a + A;
  B /= b + B;
  A /= A + A;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int __attribute__((generic_vector)) A;
  float __attribute__((generic_vector)) B;
  int a;
  float b;
  A = A + a;
  A = a + A;
  B = b + B;
  A = A + A;
  A = A - a;
  A = a - A;
  B = b - B;
  A = A - A;
  A = A * a;
  A = a * A;
  B = b * B;
  A = A * A;
  A = A / a;
  A = a / A;
  B = b / B;
  A = A / A;
  A = A | a;
  A = a | A;
  A = A | A;
  A = A & a;
  A = a & A;
  A = A & A;
  A = A ^ a;
  A = a ^ A;
  A = A ^ A;
  A += A + a;
  A += a + A;
  B += b + B;
  A += A + A;
  A -= A + a;
  A -= a + A;
  B -= b + B;
  A -= A + A;
  A *= A + a;
  A *= a + A;
  B *= b + B;
  A *= A + A;
  A /= A + a;
  A /= a + A;
  B /= b + B;
  A /= A + A;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int __attribute__((generic_vector)) A;
  float __attribute__((generic_vector)) B;
  int a;
  float b;
  A = A + a;
  A = a + A;
  B = b + B;
  A = A + A;
  A = A - a;
  A = a - A;
  B = b - B;
  A = A - A;
  A = A * a;
  A = a * A;
  B = b * B;
  A = A * A;
  A = A / a;
  A = a / A;
  B = b / B;
  A = A / A;
  A = A | a;
  A = a | A;
  A = A | A;
  A = A & a;
  A = a & A;
  A = A & A;
  A = A ^ a;
  A = a ^ A;
  A = A ^ A;
  A += A + a;
  A += a + A;
  B += b + B;
  A += A + A;
  A -= A + a;
  A -= a + A;
  B -= b + B;
  A -= A + A;
  A *= A + a;
  A *= a + A;
  B *= b + B;
  A *= A + A;
  A /= A + a;
  A /= a + A;
  B /= b + B;
  A /= A + A;
}
```
user: What is the c source code of the assembly code below?

```asm
<Thrd_extra_bit_information>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
L6:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <Thrd_Get_Bits1@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <Thrd_Flush_Buffer@plt>
  addl   $0x1,-0x8(%rbp)
  jmp    L6
L17:
  nop
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Thrd_extra_bit_information(int t) {
  int Byte_Count;
  unsigned int tmp;
  {
    Byte_Count = 0;
    while (1) {
      tmp = Thrd_Get_Bits1(t);
      if (!tmp) {
        break;
      }
      Thrd_Flush_Buffer(t, 8);
      Byte_Count++;
    }
    return (Byte_Count);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Thrd_extra_bit_information>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%ebp
  jmp    L7
L4:
  mov    $0x8,%esi
  mov    %ebx,%edi
  call   <Thrd_Flush_Buffer@plt>
  add    $0x1,%ebp
L7:
  mov    %ebx,%edi
  call   <Thrd_Get_Bits1@plt>
  test   %eax,%eax
  jne    L4
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int Thrd_extra_bit_information(int t) {
  int Byte_Count;
  unsigned int tmp;
  {
    Byte_Count = 0;
    while (1) {
      tmp = Thrd_Get_Bits1(t);
      if (!tmp) {
        break;
      }
      Thrd_Flush_Buffer(t, 8);
      Byte_Count++;
    }
    return (Byte_Count);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Thrd_extra_bit_information>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x8,%esi
  mov    %ebx,%edi
  add    $0x1,%r12d
  call   <Thrd_Flush_Buffer@plt>
L0:
  mov    %ebx,%edi
  call   <Thrd_Get_Bits1@plt>
  test   %eax,%eax
  jne    L5
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int Thrd_extra_bit_information(int t) {
  int Byte_Count;
  unsigned int tmp;
  {
    Byte_Count = 0;
    while (1) {
      tmp = Thrd_Get_Bits1(t);
      if (!tmp) {
        break;
      }
      Thrd_Flush_Buffer(t, 8);
      Byte_Count++;
    }
    return (Byte_Count);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Thrd_extra_bit_information>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x8,%esi
  mov    %ebx,%edi
  add    $0x1,%r12d
  call   <Thrd_Flush_Buffer@plt>
L19:
  mov    %ebx,%edi
  call   <Thrd_Get_Bits1@plt>
  test   %eax,%eax
  jne    L18
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int Thrd_extra_bit_information(int t) {
  int Byte_Count;
  unsigned int tmp;
  {
    Byte_Count = 0;
    while (1) {
      tmp = Thrd_Get_Bits1(t);
      if (!tmp) {
        break;
      }
      Thrd_Flush_Buffer(t, 8);
      Byte_Count++;
    }
    return (Byte_Count);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MoveLargestMobile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MoveLargestMobile(char *vals, int *direct, int lm) {
  int d = direct[lm];
  char tmpv = vals[lm];
  int tmpd = direct[lm];
  vals[lm] = vals[lm + d];
  direct[lm] = direct[lm + d];
  vals[lm + d] = tmpv;
  direct[lm + d] = tmpd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MoveLargestMobile>:
  endbr64
  movslq %edx,%rax
  lea    (%rsi,%rax,4),%r8
  mov    (%r8),%ecx
  add    %rdi,%rax
  movzbl (%rax),%r9d
  add    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rdi
  movzbl (%rdi),%r10d
  mov    %r10b,(%rax)
  lea    (%rsi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%r8)
  mov    %r9b,(%rdi)
  mov    %ecx,(%rax)
  ret
```

assistant: ```c
void MoveLargestMobile(char *vals, int *direct, int lm) {
  int d = direct[lm];
  char tmpv = vals[lm];
  int tmpd = direct[lm];
  vals[lm] = vals[lm + d];
  direct[lm] = direct[lm + d];
  vals[lm + d] = tmpv;
  direct[lm + d] = tmpd;
}
```