ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<csum>:
  endbr64
  test   %rsi,%rsi
  je     L4
  lea    (%rdi,%rsi,2),%rcx
  xor    %eax,%eax
  nop
L8:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rdi,%rcx
  jne    L8
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short csum(unsigned short *buf, unsigned long nwords) {
  unsigned long sum = 0;
  unsigned long i;
  for (i = 0; i < nwords; i++) {
    sum += buf[i];
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<csum>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L88
  lea    -0x1(%rsi),%rax
  cmp    $0x6,%rax
  jbe    L101
  mov    %rsi,%rcx
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  shr    $0x3,%rcx
  pxor   %xmm2,%xmm2
  shl    $0x4,%rcx
  add    %rdi,%rcx
  nopl   0x0(%rax,%rax,1)
L87:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  punpcklwd %xmm4,%xmm1
  movdqa %xmm1,%xmm5
  punpckldq %xmm2,%xmm1
  punpckhdq %xmm2,%xmm5
  paddq  %xmm5,%xmm1
  movdqa %xmm0,%xmm5
  punpckldq %xmm2,%xmm0
  punpckhdq %xmm2,%xmm5
  paddq  %xmm5,%xmm0
  paddq  %xmm0,%xmm1
  paddq  %xmm1,%xmm3
  cmp    %rcx,%rax
  jne    L87
  movdqa %xmm3,%xmm0
  mov    %rdx,%rcx
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffff8,%rcx
  paddq  %xmm0,%xmm3
  movq   %xmm3,%rax
  test   $0x7,%dl
  je     L46
L84:
  movzwl (%rdi,%rcx,2),%r8d
  lea    (%rcx,%rcx,1),%rsi
  add    %r8,%rax
  lea    0x1(%rcx),%r8
  cmp    %r8,%rdx
  jbe    L46
  movzwl 0x2(%rdi,%rsi,1),%r8d
  add    %r8,%rax
  lea    0x2(%rcx),%r8
  cmp    %r8,%rdx
  jbe    L46
  movzwl 0x4(%rdi,%rsi,1),%r8d
  add    %r8,%rax
  lea    0x3(%rcx),%r8
  cmp    %r8,%rdx
  jbe    L46
  movzwl 0x6(%rdi,%rsi,1),%r8d
  add    %r8,%rax
  lea    0x4(%rcx),%r8
  cmp    %r8,%rdx
  jbe    L46
  movzwl 0x8(%rdi,%rsi,1),%r8d
  add    %r8,%rax
  lea    0x5(%rcx),%r8
  cmp    %r8,%rdx
  jbe    L46
  movzwl 0xa(%rdi,%rsi,1),%r8d
  add    $0x6,%rcx
  add    %r8,%rax
  cmp    %rcx,%rdx
  jbe    L46
  movzwl 0xc(%rdi,%rsi,1),%edx
  add    %rdx,%rax
L46:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L88:
  mov    $0xffffffff,%eax
  ret
L101:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L84
```

assistant: ```c
unsigned short csum(unsigned short *buf, unsigned long nwords) {
  unsigned long sum = 0;
  unsigned long i;
  for (i = 0; i < nwords; i++) {
    sum += buf[i];
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  strcpy(&s[strlen(s)], append);
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  strcpy(&s[strlen(s)], append);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  strcpy(&s[strlen(s)], append);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcat(char *s, const char *append) {
  strcpy(&s[strlen(s)], append);
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<output_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L6:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <output_byte@plt>
  test   %eax,%eax
  jne    L6
  nop
  leave
  ret
```

assistant: ```c
output_string(ptr) char ptr[];
{
  int k;
  k = 0;
  while (output_byte(ptr[k++]))
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L2:
  movsbl (%rbx),%edi
  mov    $0x0,%eax
  call   <output_byte@plt>
  add    $0x1,%rbx
  test   %eax,%eax
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
output_string(ptr) char ptr[];
{
  int k;
  k = 0;
  while (output_byte(ptr[k++]))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L1:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <output_byte@plt>
  test   %eax,%eax
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
output_string(ptr) char ptr[];
{
  int k;
  k = 0;
  while (output_byte(ptr[k++]))
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <output_byte@plt>
  test   %eax,%eax
  jne    L9
  pop    %rbx
  ret
```

assistant: ```c
output_string(ptr) char ptr[];
{
  int k;
  k = 0;
  while (output_byte(ptr[k++]))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L83
L74:
  addl   $0x1,-0x8(%rbp)
L83:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L74
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L74
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x1,%eax
  jmp    L52
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L87:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L70
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L70
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L87
L70:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
int get_next_token(char *in, char *out, int *pos) {
  int i, t;
  for (i = 0; in[i] == ' ' || in[i] == 0x09; i++)
    ;
  if (in[i] == 0)
    return 1;
  for (t = 0; in[i] != ' ' && in[i] != 0x09 && in[i] != 0; i++, t++)
    out[t] = in[i];
  out[t] = 0;
  *pos += i;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_token>:
  endbr64
  mov    %rsi,%r8
  movzbl (%rdi),%ecx
  cmp    $0x20,%cl
  je     L13
  cmp    $0x9,%cl
  jne    L73
L13:
  mov    $0x1,%eax
L74:
  mov    %eax,%esi
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    $0x20,%cl
  je     L74
  cmp    $0x9,%cl
  je     L74
L0:
  mov    $0x1,%eax
  test   %cl,%cl
  je     L4
  movslq %esi,%rax
  add    %rax,%rdi
  movzbl (%rdi),%ecx
  test   $0xdf,%cl
  je     L101
  cmp    $0x9,%cl
  je     L101
  mov    $0x1,%eax
L48:
  mov    %cl,-0x1(%r8,%rax,1)
  lea    (%rsi,%rax,1),%r10d
  mov    %eax,%r9d
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  test   $0xdf,%cl
  je     L53
  cmp    $0x9,%cl
  jne    L48
L53:
  movslq %r9d,%r9
  movb   $0x0,(%r8,%r9,1)
  add    %r10d,(%rdx)
  mov    $0x0,%eax
L4:
  ret
L73:
  mov    $0x0,%esi
  jmp    L0
L101:
  mov    %esi,%r10d
  mov    $0x0,%r9d
  jmp    L53
```

assistant: ```c
int get_next_token(char *in, char *out, int *pos) {
  int i, t;
  for (i = 0; in[i] == ' ' || in[i] == 0x09; i++)
    ;
  if (in[i] == 0)
    return 1;
  for (t = 0; in[i] != ' ' && in[i] != 0x09 && in[i] != 0; i++, t++)
    out[t] = in[i];
  out[t] = 0;
  *pos += i;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_token>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rsi,%r8
  cmp    $0x20,%cl
  je     L51
  cmp    $0x9,%cl
  jne    L20
L51:
  mov    $0x1,%eax
  nopl   0x0(%rax)
L50:
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%esi
  add    $0x1,%rax
  cmp    $0x20,%cl
  je     L50
  cmp    $0x9,%cl
  je     L50
L7:
  mov    $0x1,%eax
  test   %cl,%cl
  je     L111
  movslq %esi,%rax
  add    %rax,%rdi
  movzbl (%rdi),%ecx
  test   $0xdf,%cl
  je     L15
  cmp    $0x9,%cl
  je     L15
  mov    $0x1,%eax
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L103:
  cmp    $0x9,%cl
  je     L1
L91:
  mov    %cl,-0x1(%r8,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  lea    (%rsi,%rax,1),%r10d
  movslq %eax,%r9
  add    $0x1,%rax
  test   $0xdf,%cl
  jne    L103
L1:
  add    %r9,%r8
L90:
  movb   $0x0,(%r8)
  xor    %eax,%eax
  add    %r10d,(%rdx)
L111:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %esi,%esi
  jmp    L7
L15:
  mov    %esi,%r10d
  jmp    L90
```

assistant: ```c
int get_next_token(char *in, char *out, int *pos) {
  int i, t;
  for (i = 0; in[i] == ' ' || in[i] == 0x09; i++)
    ;
  if (in[i] == 0)
    return 1;
  for (t = 0; in[i] != ' ' && in[i] != 0x09 && in[i] != 0; i++, t++)
    out[t] = in[i];
  out[t] = 0;
  *pos += i;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_next_token>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L102
  cmp    $0x9,%al
  jne    L79
L102:
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L109:
  movzbl (%rdi,%rcx,1),%eax
  mov    %ecx,%r8d
  add    $0x1,%rcx
  cmp    $0x20,%al
  je     L109
  cmp    $0x9,%al
  je     L109
L75:
  mov    $0x1,%r9d
  test   %al,%al
  je     L101
  test   $0xdf,%al
  je     L27
  movslq %r8d,%r9
  mov    $0x1,%ecx
  add    %r9,%rdi
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L76:
  cmp    $0x9,%al
  je     L63
L5:
  mov    %al,-0x1(%rsi,%rcx,1)
  movzbl (%rdi,%rcx,1),%eax
  lea    (%r8,%rcx,1),%r10d
  movslq %ecx,%r9
  add    $0x1,%rcx
  test   $0xdf,%al
  jne    L76
L63:
  add    %r9,%rsi
L91:
  movb   $0x0,(%rsi)
  xor    %r9d,%r9d
  add    %r10d,(%rdx)
L101:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  xor    %r8d,%r8d
  jmp    L75
L27:
  mov    %r8d,%r10d
  jmp    L91
```

assistant: ```c
int get_next_token(char *in, char *out, int *pos) {
  int i, t;
  for (i = 0; in[i] == ' ' || in[i] == 0x09; i++)
    ;
  if (in[i] == 0)
    return 1;
  for (t = 0; in[i] != ' ' && in[i] != 0x09 && in[i] != 0; i++, t++)
    out[t] = in[i];
  out[t] = 0;
  *pos += i;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x38(%rbp)
  movl   $0x16,-0x34(%rbp)
  movb   $0x69,-0x2b(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D2: %c

assistant: ```c
int main() {
  int i, j, k;
  i = 1;
  j = 22;
  char a[30];
  a[5] = 'Bari';
  printf("%c", a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x69,0x5(%rsp)
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %c

assistant: ```c
int main() {
  int i, j, k;
  i = 1;
  j = 22;
  char a[30];
  a[5] = 'Bari';
  printf("%c", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movb   $0x69,0x5(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: %c

assistant: ```c
int main() {
  int i, j, k;
  i = 1;
  j = 22;
  char a[30];
  a[5] = 'Bari';
  printf("%c", a);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movb   $0x69,0x5(%rsp)
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: %c

assistant: ```c
int main() {
  int i, j, k;
  i = 1;
  j = 22;
  char a[30];
  a[5] = 'Bari';
  printf("%c", a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<b_dpgettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x60(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x58(%rbp)
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x50(%rbp)
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L23:
  cmp    %rdx,%rsp
  je     L42
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L42:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L38
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L38:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x60(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x70(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x60(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x48(%rbp),%rax
  movb   $0x4,(%rax,%rdx,1)
  mov    -0x48(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x58(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dgettext@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x48(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jne    L49
  mov    -0x78(%rbp),%rax
  jmp    L1
L49:
  mov    -0x40(%rbp),%rax
L1:
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
const char *b_dpgettext(const char *domain, const char *context, const char *msgId) {
  size_t context_len = strlen(context) + 1;
  size_t msgId_len = strlen(msgId) + 1;
  char ctxMsgId[context_len + msgId_len];
  memcpy(ctxMsgId, context, context_len - 1);
  ctxMsgId[context_len - 1] = '\004';
  memcpy(ctxMsgId + context_len, msgId, msgId_len);
  const char *const translation = dgettext(domain, ctxMsgId);
  if (translation == ctxMsgId)
    return msgId;
  return translation;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b_dpgettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  lea    0xf(%rbx,%r12,1),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L24:
  cmp    %rdx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L10:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L30
  orq    $0x0,-0x8(%rsp,%rax,1)
L30:
  lea    -0x1(%rbx),%rdx
  mov    %r14,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movb   $0x4,-0x1(%rsp,%rbx,1)
  lea    (%rsp,%rbx,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %r15,%rdi
  call   <dgettext@plt>
  cmp    %rax,%rsp
  cmove  %r13,%rax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *b_dpgettext(const char *domain, const char *context, const char *msgId) {
  size_t context_len = strlen(context) + 1;
  size_t msgId_len = strlen(msgId) + 1;
  char ctxMsgId[context_len + msgId_len];
  memcpy(ctxMsgId, context, context_len - 1);
  ctxMsgId[context_len - 1] = '\004';
  memcpy(ctxMsgId + context_len, msgId, msgId_len);
  const char *const translation = dgettext(domain, ctxMsgId);
  if (translation == ctxMsgId)
    return msgId;
  return translation;
}
```
user: Translate the below assembly code into C programming language:

```asm
<b_dpgettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rax),%ebx
  call   <strlen@plt>
  movslq %ebx,%rbx
  mov    %rsp,%rcx
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  lea    0xf(%rbx,%r12,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L33:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L33
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L1
L46:
  lea    -0x1(%rbx),%rdx
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    (%rsp,%rbx,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  movb   $0x4,-0x1(%rsp,%rbx,1)
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <dgettext@plt>
  cmp    %rax,%rsp
  cmove  %r13,%rax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L1:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L46
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *b_dpgettext(const char *domain, const char *context, const char *msgId) {
  size_t context_len = strlen(context) + 1;
  size_t msgId_len = strlen(msgId) + 1;
  char ctxMsgId[context_len + msgId_len];
  memcpy(ctxMsgId, context, context_len - 1);
  ctxMsgId[context_len - 1] = '\004';
  memcpy(ctxMsgId + context_len, msgId, msgId_len);
  const char *const translation = dgettext(domain, ctxMsgId);
  if (translation == ctxMsgId)
    return msgId;
  return translation;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<b_dpgettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rax),%ebx
  call   <strlen@plt>
  movslq %ebx,%rbx
  mov    %rsp,%rcx
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  lea    0xf(%rbx,%r12,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L41
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L8
L41:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L5
L48:
  lea    -0x1(%rbx),%rdx
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
  lea    (%rsp,%rbx,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  movb   $0x4,-0x1(%rsp,%rbx,1)
  call   <memcpy@plt>
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <dgettext@plt>
  cmp    %rax,%rsp
  cmove  %r13,%rax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L5:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *b_dpgettext(const char *domain, const char *context, const char *msgId) {
  size_t context_len = strlen(context) + 1;
  size_t msgId_len = strlen(msgId) + 1;
  char ctxMsgId[context_len + msgId_len];
  memcpy(ctxMsgId, context, context_len - 1);
  ctxMsgId[context_len - 1] = '\004';
  memcpy(ctxMsgId + context_len, msgId, msgId_len);
  const char *const translation = dgettext(domain, ctxMsgId);
  if (translation == ctxMsgId)
    return msgId;
  return translation;
}
```