ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D80(%rip),%eax
  xor    $0x1,%eax
  mov    %eax,D85(%rip)
  mov    D85(%rip),%eax
  test   %eax,%eax
  je     L2
  mov    D85(%rip),%rax
  mov    (%rax),%edx
  mov    D79(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glPolygonMode@plt>
  mov    D64(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glEnable@plt>
  jmp    L5
L2:
  mov    D55(%rip),%rax
  mov    (%rax),%edx
  mov    D79(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glPolygonMode@plt>
  mov    D64(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glDisable@plt>
L5:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wire(void) {
  static int w;
  if (w ^= 1) {
    glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
    glEnable(GL_BLEND);
  } else {
    glPolygonMode(GL_FRONT_AND_BACK, GL_FILL);
    glDisable(GL_BLEND);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wire>:
  endbr64
  sub    $0x8,%rsp
  mov    D14(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D75(%rip)
  cmp    $0x1,%eax
  je     L8
  mov    D75(%rip),%rax
  mov    (%rax),%esi
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <glPolygonMode@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <glEnable@plt>
L2:
  add    $0x8,%rsp
  ret
L8:
  mov    D50(%rip),%rax
  mov    (%rax),%esi
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <glPolygonMode@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <glDisable@plt>
  jmp    L2
```

assistant: ```c
void wire(void) {
  static int w;
  if (w ^= 1) {
    glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
    glEnable(GL_BLEND);
  } else {
    glPolygonMode(GL_FRONT_AND_BACK, GL_FILL);
    glDisable(GL_BLEND);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wire>:
  endbr64
  sub    $0x8,%rsp
  mov    D56(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D0(%rip)
  mov    D0(%rip),%rdx
  mov    (%rdx),%edi
  cmp    $0x1,%eax
  je     L3
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <glPolygonMode@plt>
  mov    D61(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1080 <glEnable@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  call   <glPolygonMode@plt>
  mov    D61(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <glDisable@plt>
```

assistant: ```c
void wire(void) {
  static int w;
  if (w ^= 1) {
    glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
    glEnable(GL_BLEND);
  } else {
    glPolygonMode(GL_FRONT_AND_BACK, GL_FILL);
    glDisable(GL_BLEND);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wire>:
  endbr64
  sub    $0x8,%rsp
  mov    D42(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D24(%rip)
  mov    D24(%rip),%rdx
  mov    (%rdx),%edi
  cmp    $0x1,%eax
  je     L7
  mov    D22(%rip),%rax
  mov    (%rax),%esi
  call   <glPolygonMode@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1080 <glEnable@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <glPolygonMode@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <glDisable@plt>
```

assistant: ```c
void wire(void) {
  static int w;
  if (w ^= 1) {
    glPolygonMode(GL_FRONT_AND_BACK, GL_LINE);
    glEnable(GL_BLEND);
  } else {
    glPolygonMode(GL_FRONT_AND_BACK, GL_FILL);
    glDisable(GL_BLEND);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<malloc_good>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  movl   $0x5,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void malloc_good() {
  int *p = (int *)malloc(sizeof(int));
  if (p) {
    *p = 5;
    int x = *p;
  }
  free(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc_good>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L5
  movl   $0x5,(%rax)
L5:
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void malloc_good() {
  int *p = (int *)malloc(sizeof(int));
  if (p) {
    *p = 5;
    int x = *p;
  }
  free(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<malloc_good>:
  endbr64
  mov    $0x4,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L6
  movl   $0x5,(%rax)
L6:
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

assistant: ```c
void malloc_good() {
  int *p = (int *)malloc(sizeof(int));
  if (p) {
    *p = 5;
    int x = *p;
  }
  free(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<malloc_good>:
  endbr64
  mov    $0x4,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L5
  movl   $0x5,(%rax)
L5:
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

assistant: ```c
void malloc_good() {
  int *p = (int *)malloc(sizeof(int));
  if (p) {
    *p = 5;
    int x = *p;
  }
  free(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    $0x40,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movd   %eax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: 

assistant: ```c
float bar() {
  float lookupTable[] = {-1, -1, -1, 0, -1, -1, 0, -1, -1, -1, 0, 1, -1, -1, 1, 0, -1, 0, -1, -1, -1, 0, -1, 1, -1, 0, 1, -1, -1, 0, 1, 1, -1, 1, -1, 0, -1, 1, 0, -1, -1, 1, 0, 1, -1, 1, 1, 0, 0, -1, -1, -1, 0, -1, -1, 1, 0, -1, 1, -1, 0, -1, 1, 1, 1, -1, -1, 0, 1, -1, 0, -1, 1, -1, 0, 1, 1, -1, 1, 0, 1, 0, -1, -1, 1, 0, -1, 1, 1, 0, 1, -1, 1, 0, 1, 1, 1, 1, -1, 0, 1, 1, 0, -1, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, -1, -1, 0, 1, -1, 1, 0, 1, 1, -1, 0, 1, 1, 1};
  foo(lookupTable);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D4(%rip),%rsi
  mov    $0x40,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%rdi
  call   <foo@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  pxor   %xmm0,%xmm0
  add    $0x218,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: 

assistant: ```c
float bar() {
  float lookupTable[] = {-1, -1, -1, 0, -1, -1, 0, -1, -1, -1, 0, 1, -1, -1, 1, 0, -1, 0, -1, -1, -1, 0, -1, 1, -1, 0, 1, -1, -1, 0, 1, 1, -1, 1, -1, 0, -1, 1, 0, -1, -1, 1, 0, 1, -1, 1, 1, 0, 0, -1, -1, -1, 0, -1, -1, 1, 0, -1, 1, -1, 0, -1, 1, 1, 1, -1, -1, 0, 1, -1, 0, -1, 1, -1, 0, 1, 1, -1, 1, 0, 1, 0, -1, -1, 1, 0, -1, 1, 1, 0, 1, -1, 1, 0, 1, 1, 1, 1, -1, 0, 1, 1, 0, -1, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, -1, -1, 0, 1, -1, 1, 0, 1, 1, -1, 0, 1, 1, 1};
  foo(lookupTable);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  sub    $0x218,%rsp
  lea    D1(%rip),%rsi
  mov    $0x40,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%rdi
  call   <foo@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  pxor   %xmm0,%xmm0
  add    $0x218,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: 

assistant: ```c
float bar() {
  float lookupTable[] = {-1, -1, -1, 0, -1, -1, 0, -1, -1, -1, 0, 1, -1, -1, 1, 0, -1, 0, -1, -1, -1, 0, -1, 1, -1, 0, 1, -1, -1, 0, 1, 1, -1, 1, -1, 0, -1, 1, 0, -1, -1, 1, 0, 1, -1, 1, 1, 0, 0, -1, -1, -1, 0, -1, -1, 1, 0, -1, 1, -1, 0, -1, 1, 1, 1, -1, -1, 0, 1, -1, 0, -1, 1, -1, 0, 1, 1, -1, 1, 0, 1, 0, -1, -1, 1, 0, -1, 1, 1, 0, 1, -1, 1, 0, 1, 1, 1, 1, -1, 0, 1, 1, 0, -1, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, -1, -1, 0, 1, -1, 1, 0, 1, 1, -1, 0, 1, 1, 1};
  foo(lookupTable);
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  sub    $0x218,%rsp
  lea    D2(%rip),%rsi
  mov    $0x40,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%rdi
  call   <foo@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  pxor   %xmm0,%xmm0
  add    $0x218,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: 

assistant: ```c
float bar() {
  float lookupTable[] = {-1, -1, -1, 0, -1, -1, 0, -1, -1, -1, 0, 1, -1, -1, 1, 0, -1, 0, -1, -1, -1, 0, -1, 1, -1, 0, 1, -1, -1, 0, 1, 1, -1, 1, -1, 0, -1, 1, 0, -1, -1, 1, 0, 1, -1, 1, 1, 0, 0, -1, -1, -1, 0, -1, -1, 1, 0, -1, 1, -1, 0, -1, 1, 1, 1, -1, -1, 0, 1, -1, 0, -1, 1, -1, 0, 1, 1, -1, 1, 0, 1, 0, -1, -1, 1, 0, -1, 1, 1, 0, 1, -1, 1, 0, 1, 1, 1, 1, -1, 0, 1, 1, 0, -1, 1, 1, 0, 1, 1, 1, 1, 0, 0, 1, -1, -1, 0, 1, -1, 1, 0, 1, 1, -1, 0, 1, 1, 1};
  foo(lookupTable);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<double_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L21
  mov    $0xffffffff,%eax
  jmp    L31
L21:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L6
  mov    $0x1,%eax
  jmp    L31
L6:
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int double_comp(const void *r1_ptr, const void *r2_ptr) {
  double *r1 = (double *)r1_ptr;
  double *r2 = (double *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<double_comp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L4
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
int double_comp(const void *r1_ptr, const void *r2_ptr) {
  double *r1 = (double *)r1_ptr;
  double *r2 = (double *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<double_comp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L9
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L9:
  ret
```

assistant: ```c
int double_comp(const void *r1_ptr, const void *r2_ptr) {
  double *r1 = (double *)r1_ptr;
  double *r2 = (double *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<double_comp>:
  endbr64
  movsd  (%rdi),%xmm1
  movsd  (%rsi),%xmm0
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L5
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L5:
  ret
```

assistant: ```c
int double_comp(const void *r1_ptr, const void *r2_ptr) {
  double *r1 = (double *)r1_ptr;
  double *r2 = (double *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_client>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cc_send@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void send_client(struct connection *client, int n) {
  uint8_t *buffer = malloc(n);
  int i;
  for (i = 0; i < n; i++) {
    buffer[i] = (uint8_t)i;
  }
  cc_send(client, (const char *)buffer, n);
  free(buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_client>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jle    L9
  mov    %ebp,%edx
  mov    $0x0,%eax
L18:
  mov    %rax,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L9:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <cc_send@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void send_client(struct connection *client, int n) {
  uint8_t *buffer = malloc(n);
  int i;
  for (i = 0; i < n; i++) {
    buffer[i] = (uint8_t)i;
  }
  cc_send(client, (const char *)buffer, n);
  free(buffer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_client>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L12
  movslq %r12d,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rax,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L19
L12:
  mov    %r13,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <cc_send@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
```

assistant: ```c
void send_client(struct connection *client, int n) {
  uint8_t *buffer = malloc(n);
  int i;
  for (i = 0; i < n; i++) {
    buffer[i] = (uint8_t)i;
  }
  cc_send(client, (const char *)buffer, n);
  free(buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<send_client>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L27
  lea    -0x1(%r12),%eax
  cmp    $0x2,%eax
  jbe    L61
  mov    %r12d,%edx
  movdqa D2(%rip),%xmm1
  mov    %rbp,%rax
  pxor   %xmm4,%xmm4
  shr    $0x2,%edx
  movdqa D12(%rip),%xmm5
  shl    $0x5,%rdx
  add    %rbp,%rdx
  nopl   0x0(%rax)
L48:
  movdqa %xmm1,%xmm0
  movdqa %xmm4,%xmm2
  paddd  %xmm5,%xmm1
  add    $0x20,%rax
  pcmpgtd %xmm0,%xmm2
  movdqa %xmm0,%xmm3
  punpckldq %xmm2,%xmm3
  punpckhdq %xmm2,%xmm0
  movups %xmm3,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L48
  mov    %r12d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r12b
  je     L27
L6:
  movslq %eax,%rdx
  mov    %rdx,0x0(%rbp,%rdx,8)
  lea    0x0(,%rdx,8),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L27
  movslq %edx,%rdx
  add    $0x2,%eax
  mov    %rdx,0x8(%rbp,%rcx,1)
  cmp    %eax,%r12d
  jle    L27
  cltq
  mov    %rax,0x10(%rbp,%rcx,1)
L27:
  mov    %r13,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <cc_send@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
L61:
  xor    %eax,%eax
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: byte[16]
name: read_data
arguments: data_label: D12
type_guessed: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D12": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void send_client(struct connection *client, int n) {
  uint8_t *buffer = malloc(n);
  int i;
  for (i = 0; i < n; i++) {
    buffer[i] = (uint8_t)i;
  }
  cc_send(client, (const char *)buffer, n);
  free(buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6968742079706f43,%rax
  movabs $0x676e697274732073,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    $0x11,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rcx
  lea    D17(%rip),%rax
  mov    %rax,%rdx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D24
data_type: string

tool: D17: s1 contains 

tool: D12: After s2 is copied into s1 with memcpy,

tool: D24: %s
%s"%s"


assistant: ```c
int main(void) {
  char s1[17];
  char s2[] = "Copy this string";
  memcpy(s1, s2, 17);
  printf("%s\n%s\"%s\"\n", "After s2 is copied into s1 with memcpy,", "s1 contains ", s1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x6968742079706f43,%rax
  movabs $0x676e697274732073,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movb   $0x0,0x30(%rsp)
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rbx
  mov    $0x11,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rcx
  lea    D27(%rip),%rdx
  lea    D3(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D3
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string

tool: D27: s1 contains 

tool: D3: After s2 is copied into s1 with memcpy,

tool: D19: %s
%s"%s"


assistant: ```c
int main(void) {
  char s1[17];
  char s2[] = "Copy this string";
  memcpy(s1, s2, 17);
  printf("%s\n%s\"%s\"\n", "After s2 is copied into s1 with memcpy,", "s1 contains ", s1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x11,%edx
  sub    $0x40,%rsp
  movdqa D31(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rsi
  movb   $0x0,0x30(%rsp)
  mov    %r12,%rdi
  movaps %xmm0,0x20(%rsp)
  call   <memcpy@plt>
  mov    %r12,%rcx
  lea    D17(%rip),%rdx
  lea    D9(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D31
type_infered: byte[16]
name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string
name: unpack_data
arguments: data_label: D14
type_infered: string

tool: {"D31": [0x43,0x6f,0x70,0x79,0x20,0x74,0x68,0x69,0x73,0x20,0x73,0x74,0x72,0x69,0x6e,0x67]}

tool: D17: s1 contains 

tool: D9: After s2 is copied into s1 with memcpy,

tool: D14: %s
%s"%s"


assistant: ```c
int main(void) {
  char s1[17];
  char s2[] = "Copy this string";
  memcpy(s1, s2, 17);
  printf("%s\n%s\"%s\"\n", "After s2 is copied into s1 with memcpy,", "s1 contains ", s1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x11,%edx
  sub    $0x40,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%rsi
  movb   $0x0,0x30(%rsp)
  mov    %r12,%rdi
  movaps %xmm0,0x20(%rsp)
  call   <memcpy@plt>
  mov    %r12,%rcx
  lea    D7(%rip),%rdx
  lea    D11(%rip),%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D7
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D28
data_type: string

tool: {"D9": [0x43,0x6f,0x70,0x79,0x20,0x74,0x68,0x69,0x73,0x20,0x73,0x74,0x72,0x69,0x6e,0x67]}

tool: D7: s1 contains 

tool: D11: After s2 is copied into s1 with memcpy,

tool: D28: %s
%s"%s"


assistant: ```c
int main(void) {
  char s1[17];
  char s2[] = "Copy this string";
  memcpy(s1, s2, 17);
  printf("%s\n%s\"%s\"\n", "After s2 is copied into s1 with memcpy,", "s1 contains ", s1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,-0x18(%rbp)
  test   %rbx,%rbx
  jne    L19
  mov    D13(%rip),%rbx
L19:
  test   %rbx,%rbx
  jne    L44
  mov    $0x0,%eax
  jmp    L5
L44:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  lea    (%rbx,%rax,1),%r12
  movzbl (%r12),%eax
  test   %al,%al
  jne    L23
  movq   $0x0,D13(%rip)
  mov    $0x0,%eax
  jmp    L5
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  je     L16
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
L16:
  mov    %rbx,D26(%rip)
  mov    %r12,%rax
L5:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *strtok(string, separators)
register char *string;
char *separators;
{
  register char *s1, *s2;
  static char *savestring;
  if (!string)
    string = savestring;
  if (!string)
    return 0;
  if (*(s1 = string + strspn(string, separators)) == '\0') {
    savestring = 0;
    return 0;
  }
  if (s2 = strpbrk(s1, separators)) {
    *s2++ = '\0';
  }
  savestring = s2;
  return s1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rdi,%rdi
  je     L31
L30:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  lea    (%rbx,%rax,1),%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L43
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rdx
  test   %rax,%rax
  je     L19
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rax)
L19:
  mov    %rdx,D15(%rip)
L28:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    D15(%rip),%rbx
  mov    %rbx,%rbp
  test   %rbx,%rbx
  jne    L30
  jmp    L28
L43:
  movq   $0x0,D15(%rip)
  mov    $0x0,%ebp
  jmp    L28
```

assistant: ```c
char *strtok(string, separators)
register char *string;
char *separators;
{
  register char *s1, *s2;
  static char *savestring;
  if (!string)
    string = savestring;
  if (!string)
    return 0;
  if (*(s1 = string + strspn(string, separators)) == '\0') {
    savestring = 0;
    return 0;
  }
  if (s2 = strpbrk(s1, separators)) {
    *s2++ = '\0';
  }
  savestring = s2;
  return s1;
}
```