ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<maximoR3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  cmp    $0x1,%ebp
  je     L231
L100:
  sub    $0x1,%rbp
  mov    %rbp,%r14
  cmp    $0x1,%r14d
  je     L23
L266:
  sub    $0x1,%r14
  mov    %r14,%r15
  cmp    $0x1,%r15d
  je     L281
L8:
  sub    $0x1,%r15
  mov    %r15,%rdx
L15:
  cmp    $0x1,%edx
  je     L9
  sub    $0x1,%rdx
  mov    %rdx,%rcx
L45:
  cmp    $0x1,%ecx
  je     L298
  sub    $0x1,%rcx
  mov    %rcx,%r12
L168:
  cmp    $0x1,%r12d
  je     L229
  lea    -0x2(%r12),%r13
  lea    -0x2(%r12),%eax
  mov    %r13,%rdi
  sub    %rax,%rdi
  mov    %rdi,0x8(%rsp)
L252:
  cmp    0x8(%rsp),%r13
  je     L115
  mov    %r13,%r8
L70:
  cmp    $0x1,%r8d
  je     L270
  sub    $0x1,%r8
  mov    %r8,%r9
  cmp    $0x1,%r9d
  je     L66
L278:
  lea    -0x1(%r9),%edi
  mov    %rbx,%rsi
  mov    %rdx,0x28(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  call   <maximoR3>
  mov    0x10(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    %eax,%r10d
  mov    0x20(%rsp),%rcx
  mov    0x28(%rsp),%rdx
  sub    $0x1,%r9
  mov    (%rbx,%r9,4),%eax
  cmp    %eax,%r10d
  jl     L222
  cmp    $0x1,%r9d
  jne    L278
  nopl   0x0(%rax,%rax,1)
L66:
  mov    (%rbx),%eax
L222:
  mov    (%rbx,%r8,4),%esi
  cmp    %eax,%esi
  jle    L70
  sub    $0x1,%r13
  mov    0x4(%rbx,%r13,4),%eax
  cmp    %esi,%eax
  jle    L252
L87:
  sub    $0x1,%r12
  mov    (%rbx,%r12,4),%esi
  cmp    %eax,%esi
  jle    L168
L54:
  mov    (%rbx,%rcx,4),%eax
  cmp    %esi,%eax
  jle    L45
L291:
  mov    (%rbx,%rdx,4),%ecx
  cmp    %eax,%ecx
  jle    L15
L52:
  mov    (%rbx,%r15,4),%eax
  cmp    %ecx,%eax
  jg     L5
L303:
  cmp    $0x1,%r15d
  jne    L8
L281:
  mov    (%rbx),%eax
L5:
  mov    (%rbx,%r14,4),%edx
  cmp    %eax,%edx
  jg     L264
  cmp    $0x1,%r14d
  jne    L266
L23:
  mov    (%rbx),%edx
L264:
  mov    (%rbx,%rbp,4),%eax
  cmp    %edx,%eax
  jg     L99
  cmp    $0x1,%ebp
  jne    L100
L231:
  mov    (%rbx),%eax
L99:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L270:
  sub    $0x1,%r13
  mov    (%rbx),%esi
  mov    0x4(%rbx,%r13,4),%eax
  cmp    %esi,%eax
  jle    L252
  jmp    L87
L115:
  sub    $0x1,%r12
  mov    (%rbx),%eax
  mov    (%rbx,%r12,4),%esi
  cmp    %eax,%esi
  jle    L168
  jmp    L54
L229:
  mov    (%rbx),%esi
  mov    (%rbx,%rcx,4),%eax
  cmp    %esi,%eax
  jle    L45
  jmp    L291
L298:
  mov    (%rbx),%eax
  mov    (%rbx,%rdx,4),%ecx
  cmp    %eax,%ecx
  jle    L15
  jmp    L52
L9:
  mov    (%rbx),%ecx
  mov    (%rbx,%r15,4),%eax
  cmp    %ecx,%eax
  jle    L303
  jmp    L5
```

assistant: ```c
int maximoR3(int n, int v[]) {
  if (n == 1)
    return v[0];
  if ((maximoR3(n - 1, v)) < v[n - 1])
    return v[n - 1];
  else
    return maximoR3(n - 1, v);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<maximoR3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  cmp    $0x1,%ebp
  je     L150
L276:
  sub    $0x1,%rbp
  mov    %rbp,%r14
  cmp    $0x1,%r14d
  je     L281
L69:
  sub    $0x1,%r14
  mov    %r14,%r15
  cmp    $0x1,%r15d
  je     L205
L296:
  sub    $0x1,%r15
  mov    %r15,%rdx
L81:
  cmp    $0x1,%edx
  je     L64
  sub    $0x1,%rdx
  mov    %rdx,%rcx
L27:
  cmp    $0x1,%ecx
  je     L192
  sub    $0x1,%rcx
  mov    %rcx,%r12
L243:
  cmp    $0x1,%r12d
  je     L128
  lea    -0x2(%r12),%r13
  lea    -0x2(%r12),%eax
  mov    %r13,%rdi
  sub    %rax,%rdi
  mov    %rdi,0x8(%rsp)
L0:
  cmp    0x8(%rsp),%r13
  je     L10
  mov    %r13,%r8
L49:
  cmp    $0x1,%r8d
  je     L259
  sub    $0x1,%r8
  mov    %r8,%r9
  cmp    $0x1,%r9d
  je     L92
L262:
  lea    -0x1(%r9),%edi
  mov    %rbx,%rsi
  mov    %rdx,0x28(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  call   <maximoR3>
  mov    0x10(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    %eax,%r10d
  mov    0x20(%rsp),%rcx
  mov    0x28(%rsp),%rdx
  sub    $0x1,%r9
  mov    (%rbx,%r9,4),%eax
  cmp    %eax,%r10d
  jl     L216
  cmp    $0x1,%r9d
  jne    L262
  nopl   0x0(%rax,%rax,1)
L92:
  mov    (%rbx),%eax
L216:
  mov    (%rbx,%r8,4),%esi
  cmp    %eax,%esi
  jle    L49
  sub    $0x1,%r13
  mov    0x4(%rbx,%r13,4),%eax
  cmp    %esi,%eax
  jle    L0
L195:
  sub    $0x1,%r12
  mov    (%rbx,%r12,4),%esi
  cmp    %eax,%esi
  jle    L243
L186:
  mov    (%rbx,%rcx,4),%eax
  cmp    %esi,%eax
  jle    L27
L233:
  mov    (%rbx,%rdx,4),%ecx
  cmp    %eax,%ecx
  jle    L81
L149:
  mov    (%rbx,%r15,4),%eax
  cmp    %ecx,%eax
  jg     L131
L148:
  cmp    $0x1,%r15d
  jne    L296
L205:
  mov    (%rbx),%eax
L131:
  mov    (%rbx,%r14,4),%edx
  cmp    %eax,%edx
  jg     L117
  cmp    $0x1,%r14d
  jne    L69
L281:
  mov    (%rbx),%edx
L117:
  mov    (%rbx,%rbp,4),%eax
  cmp    %edx,%eax
  jg     L168
  cmp    $0x1,%ebp
  jne    L276
L150:
  mov    (%rbx),%eax
L168:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L259:
  sub    $0x1,%r13
  mov    (%rbx),%esi
  mov    0x4(%rbx,%r13,4),%eax
  cmp    %esi,%eax
  jle    L0
  jmp    L195
L10:
  sub    $0x1,%r12
  mov    (%rbx),%eax
  mov    (%rbx,%r12,4),%esi
  cmp    %eax,%esi
  jle    L243
  jmp    L186
L128:
  mov    (%rbx),%esi
  mov    (%rbx,%rcx,4),%eax
  cmp    %esi,%eax
  jle    L27
  jmp    L233
L192:
  mov    (%rbx),%eax
  mov    (%rbx,%rdx,4),%ecx
  cmp    %eax,%ecx
  jle    L81
  jmp    L149
L64:
  mov    (%rbx),%ecx
  mov    (%rbx,%r15,4),%eax
  cmp    %ecx,%eax
  jle    L148
  jmp    L131
```

assistant: ```c
int maximoR3(int n, int v[]) {
  if (n == 1)
    return v[0];
  if ((maximoR3(n - 1, v)) < v[n - 1])
    return v[n - 1];
  else
    return maximoR3(n - 1, v);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void swap(char *a, char *b) {
  char temp;
  temp = *a;
  *a = *b;
  *b = temp;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<argb32p_rgb32_inplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L11
  cmpb   $0xff,-0x1(%rbp)
  jne    L23
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L11
L23:
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <premul_nozero@plt>
  and    $0xffffff,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  or     $0xff000000,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L11:
  nop
  leave
  ret
```

assistant: ```c
void argb32p_rgb32_inplace(unsigned int *dest, unsigned int *src) {
  unsigned char alpha = *src >> 24;
  if (alpha == 0x00) {
  } else if (alpha == 0xFF) {
    *dest = *src;
  } else {
    alpha = 0xff - alpha;
    *dest = ((premul_nozero(*dest, alpha) & 0xFFFFFF) + *src) | 0xFF000000;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<argb32p_rgb32_inplace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    (%rsi),%eax
  mov    %eax,%esi
  shr    $0x18,%esi
  je     L18
  mov    %rdi,%rbp
  cmp    $0xff,%sil
  jne    L28
  mov    %eax,(%rdi)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  not    %esi
  movzbl %sil,%esi
  mov    (%rdi),%edi
  call   <premul_nozero@plt>
  and    $0xffffff,%eax
  add    (%rbx),%eax
  or     $0xff000000,%eax
  mov    %eax,0x0(%rbp)
  jmp    L18
```

assistant: ```c
void argb32p_rgb32_inplace(unsigned int *dest, unsigned int *src) {
  unsigned char alpha = *src >> 24;
  if (alpha == 0x00) {
  } else if (alpha == 0xFF) {
    *dest = *src;
  } else {
    alpha = 0xff - alpha;
    *dest = ((premul_nozero(*dest, alpha) & 0xFFFFFF) + *src) | 0xFF000000;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argb32p_rgb32_inplace>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  mov    %eax,%esi
  shr    $0x18,%esi
  je     L17
  mov    %rdi,%rbp
  cmp    $0xff,%esi
  jne    L6
L3:
  mov    %eax,0x0(%rbp)
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rdi),%edi
  not    %esi
  movzbl %sil,%esi
  call   <premul_nozero@plt>
  and    $0xffffff,%eax
  add    (%rbx),%eax
  or     $0xff000000,%eax
  jmp    L3
```

assistant: ```c
void argb32p_rgb32_inplace(unsigned int *dest, unsigned int *src) {
  unsigned char alpha = *src >> 24;
  if (alpha == 0x00) {
  } else if (alpha == 0xFF) {
    *dest = *src;
  } else {
    alpha = 0xff - alpha;
    *dest = ((premul_nozero(*dest, alpha) & 0xFFFFFF) + *src) | 0xFF000000;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<argb32p_rgb32_inplace>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  mov    %eax,%esi
  shr    $0x18,%esi
  je     L1
  mov    %rdi,%rbp
  cmp    $0xff,%esi
  jne    L11
L19:
  mov    %eax,0x0(%rbp)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%rdi),%edi
  not    %esi
  movzbl %sil,%esi
  call   <premul_nozero@plt>
  and    $0xffffff,%eax
  add    (%rbx),%eax
  or     $0xff000000,%eax
  jmp    L19
```

assistant: ```c
void argb32p_rgb32_inplace(unsigned int *dest, unsigned int *src) {
  unsigned char alpha = *src >> 24;
  if (alpha == 0x00) {
  } else if (alpha == 0xFF) {
    *dest = *src;
  } else {
    alpha = 0xff - alpha;
    *dest = ((premul_nozero(*dest, alpha) & 0xFFFFFF) + *src) | 0xFF000000;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfbc(%rbp)
  jmp    L53
L75:
  lea    -0xfc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfc0(%rbp),%eax
  cmp    $0x2a,%eax
  je     L7
  mov    -0xfc0(%rbp),%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfbc(%rbp)
L53:
  cmpl   $0x3e7,-0xfbc(%rbp)
  jle    L75
  jmp    L88
L7:
  nop
L88:
  movl   $0x0,-0xfb4(%rbp)
  jmp    L61
L109:
  movl   $0x0,-0xfb8(%rbp)
  jmp    L98
L66:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L99
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,-0xfc0(%rbp)
  mov    -0xfb8(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfb8(%rbp),%eax
  add    $0x1,%eax
  mov    -0xfc0(%rbp),%edx
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
L99:
  addl   $0x1,-0xfb8(%rbp)
L98:
  mov    -0xfbc(%rbp),%eax
  sub    -0xfb4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfb8(%rbp)
  jl     L66
  addl   $0x1,-0xfb4(%rbp)
L61:
  mov    -0xfbc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L109
  movl   $0x0,-0xfb8(%rbp)
  jmp    L24
L47:
  mov    -0xfb8(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xfb8(%rbp)
L24:
  mov    -0xfb8(%rbp),%eax
  cmp    -0xfbc(%rbp),%eax
  jl     L47
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D14: %d

tool: D9: %d


assistant: ```c
int main() {
  int arr[1000];
  int i, l, c, tmp;
  for (i = 0; i < 1000; i++) {
    scanf("%d", &tmp);
    if (tmp == 42)
      break;
    arr[i] = tmp;
  }
  for (c = 0; c < (i - 1); c++) {
    for (l = 0; l < i - c - 1; l++) {
      if (arr[l] > arr[l + 1]) {
        tmp = arr[l];
        arr[l] = arr[l + 1];
        arr[l + 1] = tmp;
      }
    }
  }
  for (l = 0; l < i; l++) {
    printf("%d\n", arr[l]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%r13
  mov    $0x0,%ebx
  lea    D0(%rip),%r14
L118:
  lea    0xc(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2a,%eax
  je     L63
  mov    %eax,0x0(%r13)
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    $0x3e8,%ebx
  jne    L118
  mov    $0x3e7,%edi
  jmp    L79
L63:
  lea    -0x1(%rbx),%edi
  test   %edi,%edi
  jle    L90
L79:
  mov    $0x0,%r8d
  lea    0x4(%rbp),%r10
  mov    $0x1,%r9d
  jmp    L84
L17:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L40
L131:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L17
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  mov    %edx,%r12d
  mov    %r9d,%r8d
  jmp    L17
L40:
  sub    $0x1,%edi
  je     L80
L84:
  test   %edi,%edi
  jle    L40
  lea    -0x1(%rdi),%eax
  lea    (%r10,%rax,4),%rsi
  mov    %rbp,%rax
  jmp    L131
L80:
  test   %r8b,%r8b
  je     L90
  mov    %r12d,0xc(%rsp)
L90:
  test   %ebx,%ebx
  jle    L46
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%r12
  lea    D9(%rip),%rbx
L128:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L128
L46:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0xfc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string

tool: D0: %d

tool: D9: %d


assistant: ```c
int main() {
  int arr[1000];
  int i, l, c, tmp;
  for (i = 0; i < 1000; i++) {
    scanf("%d", &tmp);
    if (tmp == 42)
      break;
    arr[i] = tmp;
  }
  for (c = 0; c < (i - 1); c++) {
    for (l = 0; l < i - c - 1; l++) {
      if (arr[l] > arr[l + 1]) {
        tmp = arr[l];
        arr[l] = arr[l + 1];
        arr[l + 1] = tmp;
      }
    }
  }
  for (l = 0; l < i; l++) {
    printf("%d\n", arr[l]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  jmp    L123
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L90
L123:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2a,%eax
  jne    L20
  lea    -0x1(%rbx),%r9d
  mov    %r9d,%r10d
  test   %r9d,%r9d
  jle    L84
L15:
  xor    %r8d,%r8d
  lea    -0x2(%rbp),%ebx
  lea    0x14(%rsp),%r11
  xor    %edi,%edi
  nopl   0x0(%rax)
L122:
  mov    %r9d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L63
  mov    %ebx,%edx
  lea    0x10(%rsp),%rax
  sub    %edi,%edx
  lea    (%r11,%rdx,4),%rsi
  xchg   %ax,%ax
L42:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L33
  mov    %ecx,(%rax)
  mov    %edx,%r12d
  mov    $0x1,%r8d
  mov    %edx,0x4(%rax)
L33:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L42
L63:
  add    $0x1,%edi
  cmp    %edi,%r10d
  jg     L122
  test   %r8b,%r8b
  je     L84
  mov    %r12d,0xc(%rsp)
L84:
  test   %ebp,%ebp
  je     L58
  lea    0x10(%rsp),%rbx
  lea    0x14(%rsp,%r9,4),%r12
  lea    D17(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L65:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L65
L58:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L90:
  mov    $0x3e7,%r10d
  mov    $0x3e8,%ebp
  mov    $0x3e7,%r9d
  jmp    L15
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D17
type_infered: string

tool: D11: %d

tool: D17: %d


assistant: ```c
int main() {
  int arr[1000];
  int i, l, c, tmp;
  for (i = 0; i < 1000; i++) {
    scanf("%d", &tmp);
    if (tmp == 42)
      break;
    arr[i] = tmp;
  }
  for (c = 0; c < (i - 1); c++) {
    for (l = 0; l < i - c - 1; l++) {
      if (arr[l] > arr[l + 1]) {
        tmp = arr[l];
        arr[l] = arr[l + 1];
        arr[l + 1] = tmp;
      }
    }
  }
  for (l = 0; l < i; l++) {
    printf("%d\n", arr[l]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  jmp    L91
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %eax,0x10(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L65
L91:
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0x2a,%eax
  jne    L2
  lea    -0x1(%rbx),%r9d
  mov    %r9d,%r10d
  test   %r9d,%r9d
  jle    L128
L35:
  xor    %r8d,%r8d
  lea    -0x2(%rbp),%ebx
  lea    0x14(%rsp),%r11
  xor    %edi,%edi
  nopl   0x0(%rax)
L73:
  mov    %r9d,%eax
  sub    %edi,%eax
  test   %eax,%eax
  jle    L70
  mov    %ebx,%eax
  lea    0x10(%rsp),%rdx
  sub    %edi,%eax
  lea    (%r11,%rax,4),%rsi
  xchg   %ax,%ax
L3:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %ecx,%eax
  jge    L76
  movq   %xmm1,(%rdx)
  movd   %xmm0,%r12d
  mov    $0x1,%r8d
L76:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L3
L70:
  add    $0x1,%edi
  cmp    %edi,%r10d
  jg     L73
  test   %r8b,%r8b
  je     L128
  mov    %r12d,0xc(%rsp)
L128:
  test   %ebp,%ebp
  je     L85
  lea    0x10(%rsp),%rbx
  lea    0x14(%rsp,%r9,4),%r12
  lea    D17(%rip),%rbp
  nopl   0x0(%rax)
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
L85:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  mov    $0x3e7,%r10d
  mov    $0x3e8,%ebp
  mov    $0x3e7,%r9d
  jmp    L35
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D12: %d

tool: D17: %d


assistant: ```c
int main() {
  int arr[1000];
  int i, l, c, tmp;
  for (i = 0; i < 1000; i++) {
    scanf("%d", &tmp);
    if (tmp == 42)
      break;
    arr[i] = tmp;
  }
  for (c = 0; c < (i - 1); c++) {
    for (l = 0; l < i - c - 1; l++) {
      if (arr[l] > arr[l + 1]) {
        tmp = arr[l];
        arr[l] = arr[l + 1];
        arr[l + 1] = tmp;
      }
    }
  }
  for (l = 0; l < i; l++) {
    printf("%d\n", arr[l]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_etype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jle    L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jle    L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  jle    L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <lprintf@plt>
  lea    D16(%rip),%rax
  mov    %rax,-0x8(%rbp)
L0:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D53
type_infered: string
name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D31
type_infered: string

tool: 

tool: D53: %skey

tool: D16: ,

tool: D32: %srep

tool: D31: %srel

assistant: ```c
void print_etype(int type) {
  char *sep = "";
  if ((type & (1 << 0)) > 0) {
    lprintf("%skey", sep);
    sep = ",";
  }
  if ((type & (1 << 1)) > 0) {
    lprintf("%srep", sep);
    sep = ",";
  }
  if ((type & (1 << 2)) > 0) {
    lprintf("%srel", sep);
    sep = ",";
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_etype>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D3(%rip),%rsi
  test   $0x1,%dil
  jne    L17
L3:
  test   $0x2,%bl
  jne    L24
L41:
  test   $0x4,%bl
  jne    L35
L8:
  pop    %rbx
  ret
L17:
  lea    D18(%rip),%rdi
  call   <lprintf@plt>
  lea    D23(%rip),%rsi
  jmp    L3
L24:
  lea    D51(%rip),%rdi
  call   <lprintf@plt>
  lea    D23(%rip),%rsi
  jmp    L41
L35:
  lea    D59(%rip),%rdi
  call   <lprintf@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D23
datatype: string
name: parse_data
arguments: data_label: D51
datatype: string
name: parse_data
arguments: data_label: D59
datatype: string

tool: 

tool: D18: %skey

tool: D23: ,

tool: D51: %srep

tool: D59: %srel

assistant: ```c
void print_etype(int type) {
  char *sep = "";
  if ((type & (1 << 0)) > 0) {
    lprintf("%skey", sep);
    sep = ",";
  }
  if ((type & (1 << 1)) > 0) {
    lprintf("%srep", sep);
    sep = ",";
  }
  if ((type & (1 << 2)) > 0) {
    lprintf("%srel", sep);
    sep = ",";
  }
}
```