ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x2,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  movl   $0xfffffff6,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    -0xc(%rbp),%edx
  add    $0xc,%edx
  imul   %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   -0x14(%rbp),%eax
  neg    %eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  sub    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D37
type_infered: string

tool: D5: %d


tool: D37: PAUSE

assistant: ```c
int main(void) {
  int a = 2, b = 5, c = 10, d = -10, e = -1;
  printf("%d\n", c / 10 + b - d * e * (c + 12));
  printf("%d\n", (a * ((c + b) - (a * a))) * (-1));
  printf("%d\n", -d * -e * c * b * a);
  printf("%d\n", a + b + c + d + e);
  printf("%d\n", a * b / (-c + d) + e);
  system("PAUSE");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xffffff2a,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffea,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D5: %d


tool: D14: PAUSE

assistant: ```c
int main(void) {
  int a = 2, b = 5, c = 10, d = -10, e = -1;
  printf("%d\n", c / 10 + b - d * e * (c + 12));
  printf("%d\n", (a * ((c + b) - (a * a))) * (-1));
  printf("%d\n", -d * -e * c * b * a);
  printf("%d\n", a + b + c + d + e);
  printf("%d\n", a * b / (-c + d) + e);
  system("PAUSE");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    $0xffffff2a,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffea,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D6: %d


tool: D2: PAUSE

assistant: ```c
int main(void) {
  int a = 2, b = 5, c = 10, d = -10, e = -1;
  printf("%d\n", c / 10 + b - d * e * (c + 12));
  printf("%d\n", (a * ((c + b) - (a * a))) * (-1));
  printf("%d\n", -d * -e * c * b * a);
  printf("%d\n", a + b + c + d + e);
  printf("%d\n", a * b / (-c + d) + e);
  system("PAUSE");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0xffffff2a,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffea,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffff,%esi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string

tool: D0: %d


tool: D11: PAUSE

assistant: ```c
int main(void) {
  int a = 2, b = 5, c = 10, d = -10, e = -1;
  printf("%d\n", c / 10 + b - d * e * (c + 12));
  printf("%d\n", (a * ((c + b) - (a * a))) * (-1));
  printf("%d\n", -d * -e * c * b * a);
  printf("%d\n", a + b + c + d + e);
  printf("%d\n", a * b / (-c + d) + e);
  system("PAUSE");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uncompute_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x14,%edx
  add    %edx,%eax
  and    $0xfff,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0xfff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xc,%eax
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  add    %edx,%edx
  add    %eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x2fff,%eax
  cmp    $0x5ffe,%eax
  jbe    L8
  mov    $0x1,%edx
  jmp    L2
L8:
  mov    $0xffffffff,%edx
L2:
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uncompute_index(int index, int *real_index, int *channel, int *sign) {
  *real_index = index % (64 * 64);
  *channel = (index / (64 * 64)) % 3;
  *sign = (index / (3 * 64 * 64)) ? 1 : -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uncompute_index>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%r8
  mov    %rcx,%rdi
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x14,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0xfff,%edx
  sub    %ecx,%edx
  mov    %edx,(%rsi)
  lea    0xfff(%rax),%ecx
  test   %eax,%eax
  cmovns %eax,%ecx
  mov    %ecx,%esi
  sar    $0xc,%esi
  movslq %esi,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%esi
  mov    %esi,(%r8)
  add    $0x2fff,%eax
  cmp    $0x5fff,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void uncompute_index(int index, int *real_index, int *channel, int *sign) {
  *real_index = index % (64 * 64);
  *channel = (index / (64 * 64)) % 3;
  *sign = (index / (3 * 64 * 64)) ? 1 : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uncompute_index>:
  endbr64
  mov    %rcx,%r8
  mov    %edi,%ecx
  mov    %rdx,%r9
  mov    %edi,%eax
  sar    $0x1f,%ecx
  shr    $0x14,%ecx
  lea    (%rdi,%rcx,1),%edx
  and    $0xfff,%edx
  sub    %ecx,%edx
  test   %edi,%edi
  lea    0xfff(%rdi),%ecx
  cmovns %edi,%ecx
  mov    %edx,(%rsi)
  add    $0x2fff,%eax
  mov    %ecx,%esi
  sar    $0x1f,%ecx
  sar    $0xc,%esi
  movslq %esi,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%esi
  cmp    $0x5fff,%eax
  sbb    %eax,%eax
  mov    %esi,(%r9)
  or     $0x1,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void uncompute_index(int index, int *real_index, int *channel, int *sign) {
  *real_index = index % (64 * 64);
  *channel = (index / (64 * 64)) % 3;
  *sign = (index / (3 * 64 * 64)) ? 1 : -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uncompute_index>:
  endbr64
  mov    %rcx,%r8
  mov    %edi,%ecx
  mov    %rdx,%r9
  mov    %edi,%eax
  sar    $0x1f,%ecx
  shr    $0x14,%ecx
  lea    (%rdi,%rcx,1),%edx
  and    $0xfff,%edx
  sub    %ecx,%edx
  test   %edi,%edi
  lea    0xfff(%rdi),%ecx
  cmovns %edi,%ecx
  mov    %edx,(%rsi)
  add    $0x2fff,%eax
  mov    %ecx,%esi
  sar    $0x1f,%ecx
  sar    $0xc,%esi
  movslq %esi,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  sub    %edx,%esi
  cmp    $0x5fff,%eax
  sbb    %eax,%eax
  mov    %esi,(%r9)
  or     $0x1,%eax
  mov    %eax,(%r8)
  ret
```

assistant: ```c
void uncompute_index(int index, int *real_index, int *channel, int *sign) {
  *real_index = index % (64 * 64);
  *channel = (index / (64 * 64)) % 3;
  *sign = (index / (3 * 64 * 64)) ? 1 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<start_vet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void start_vet(char vet[], int size) {
  int i;
  for (i = 0; i < (size - 1); ++i)
    vet[i] = ' ';
  vet[i] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<start_vet>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L26:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  sub    $0x1,%esi
L0:
  movslq %esi,%rsi
  movb   $0x0,(%rdi,%rsi,1)
  ret
L25:
  mov    $0x0,%esi
  jmp    L0
```

assistant: ```c
void start_vet(char vet[], int size) {
  int i;
  for (i = 0; i < (size - 1); ++i)
    vet[i] = ' ';
  vet[i] = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<start_vet>:
  endbr64
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L2
  lea    -0x2(%rsi),%edx
  mov    $0x20,%esi
  movslq %ebx,%rbx
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %rbx,%rdi
L2:
  movb   $0x0,(%rdi)
  pop    %rbx
  ret
```

assistant: ```c
void start_vet(char vet[], int size) {
  int i;
  for (i = 0; i < (size - 1); ++i)
    vet[i] = ' ';
  vet[i] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<start_vet>:
  endbr64
  push   %rbx
  lea    -0x1(%rsi),%ebx
  test   %ebx,%ebx
  jle    L8
  lea    -0x2(%rsi),%edx
  mov    $0x20,%esi
  movslq %ebx,%rbx
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %rbx,%rdi
L8:
  movb   $0x0,(%rdi)
  pop    %rbx
  ret
```

assistant: ```c
void start_vet(char vet[], int size) {
  int i;
  for (i = 0; i < (size - 1); ++i)
    vet[i] = ' ';
  vet[i] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Selecao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L57
L18:
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L65:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L65
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L17
L61:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L42
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L42:
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L61
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L57:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d

assistant: ```c
void Selecao(int n, int v[]) {
  int i, j, k, min, x;
  for (i = 0; i < n - 1; i++) {
    for (k = 0; k < n; k++)
      printf("%d", v[k]);
    putchar('\n');
    min = i;
    for (j = i + 1; j < n; j++)
      if (v[j] < v[min])
        min = j;
    x = v[i];
    v[i] = v[min];
    v[min] = x;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Selecao>:
  endbr64
  cmp    $0x1,%edi
  jle    L27
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  lea    -0x2(%rdi),%eax
  add    $0x2,%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r14
  mov    $0x1,%r15d
  jmp    L38
L16:
  mov    (%rbx),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L16
L72:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r15d,%r13d
  jle    L67
  mov    %r15,%rax
L74:
  movslq %ebp,%rdx
  mov    (%r12,%rdx,4),%ecx
  cmp    %ecx,(%r12,%rax,4)
  cmovl  %eax,%ebp
  add    $0x1,%rax
  cmp    %eax,%r13d
  jg     L74
L67:
  mov    -0x4(%r12,%r15,4),%edx
  movslq %ebp,%rbp
  lea    (%r12,%rbp,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,-0x4(%r12,%r15,4)
  mov    %edx,(%rax)
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  je     L11
L38:
  lea    -0x1(%r15),%ebp
  mov    %r12,%rbx
  test   %r13d,%r13d
  jg     L16
  jmp    L72
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: %d

assistant: ```c
void Selecao(int n, int v[]) {
  int i, j, k, min, x;
  for (i = 0; i < n - 1; i++) {
    for (k = 0; k < n; k++)
      printf("%d", v[k]);
    putchar('\n');
    min = i;
    for (j = i + 1; j < n; j++)
      if (v[j] < v[min])
        min = j;
    x = v[i];
    v[i] = v[min];
    v[min] = x;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Selecao>:
  endbr64
  push   %r15
  lea    -0x1(%rdi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jle    L42
  mov    %rsi,(%rsp)
  mov    %edi,%ebp
  mov    %rsi,%r14
  lea    0x4(%rsi,%rax,4),%r13
  xor    %ebx,%ebx
  lea    D0(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r14,%r15
  test   %ebp,%ebp
  jle    L72
  nopl   0x0(%rax,%rax,1)
L107:
  mov    (%r15),%esi
  mov    %r12,%rdi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r13,%r15
  jne    L107
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%r8d
  cmp    %r8d,%ebp
  jle    L51
  mov    (%rsp),%rax
  mov    %r8d,%edx
  mov    (%rax),%r10d
  lea    0x4(%rax),%r9
  mov    %r9,%rax
  mov    %r10d,%esi
  jmp    L56
  nopl   0x0(%rax)
L61:
  movslq %ebx,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r14,%rcx,4),%rdi
  cmp    %edx,%ebp
  je     L9
L56:
  mov    (%rax),%ecx
  mov    %rax,%rdi
  cmp    %esi,%ecx
  jge    L61
  mov    %edx,%ebx
  add    $0x1,%edx
  mov    %ecx,%esi
  add    $0x4,%rax
  cmp    %edx,%ebp
  jne    L56
L9:
  mov    %r8d,%ebx
L96:
  mov    (%rsp),%rax
  mov    %r9,(%rsp)
  mov    %esi,(%rax)
  mov    %r10d,(%rdi)
  cmp    %ebx,0xc(%rsp)
  jne    L28
L42:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    (%rsp),%rdi
L79:
  mov    (%rsp),%rax
  mov    (%rax),%esi
  lea    0x4(%rax),%r9
  mov    %esi,%r10d
  jmp    L96
L51:
  mov    (%rsp),%rdi
  mov    %r8d,%ebx
  jmp    L79
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: %d

assistant: ```c
void Selecao(int n, int v[]) {
  int i, j, k, min, x;
  for (i = 0; i < n - 1; i++) {
    for (k = 0; k < n; k++)
      printf("%d", v[k]);
    putchar('\n');
    min = i;
    for (j = i + 1; j < n; j++)
      if (v[j] < v[min])
        min = j;
    x = v[i];
    v[i] = v[min];
    v[min] = x;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Selecao>:
  endbr64
  push   %r15
  lea    -0x1(%rdi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jle    L32
  mov    %rsi,(%rsp)
  mov    %edi,%ebp
  mov    %rsi,%r14
  lea    0x4(%rsi,%rax,4),%r13
  xor    %ebx,%ebx
  lea    D1(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L78:
  mov    %r14,%r15
  test   %ebp,%ebp
  jle    L30
  nopl   0x0(%rax,%rax,1)
L53:
  mov    (%r15),%esi
  mov    %r12,%rdi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %r13,%r15
  jne    L53
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%r8d
  cmp    %r8d,%ebp
  jle    L101
  mov    (%rsp),%rax
  mov    %r8d,%edx
  mov    (%rax),%r10d
  lea    0x4(%rax),%r9
  mov    %r9,%rax
  mov    %r10d,%esi
  jmp    L10
  nopl   0x0(%rax)
L90:
  movslq %ebx,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%r14,%rcx,4),%rdi
  cmp    %ebp,%edx
  je     L3
L10:
  mov    (%rax),%ecx
  mov    %rax,%rdi
  cmp    %esi,%ecx
  jge    L90
  mov    %edx,%ebx
  add    $0x1,%edx
  mov    %ecx,%esi
  add    $0x4,%rax
  cmp    %ebp,%edx
  jne    L10
L3:
  mov    %r8d,%ebx
L76:
  mov    (%rsp),%rax
  mov    %r9,(%rsp)
  mov    %esi,(%rax)
  mov    %r10d,(%rdi)
  cmp    %ebx,0xc(%rsp)
  jne    L78
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    $0xa,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    (%rsp),%rdi
  mov    %rdi,%rax
L41:
  mov    (%rax),%esi
  lea    0x4(%rax),%r9
  mov    %esi,%r10d
  jmp    L76
L101:
  mov    (%rsp),%rdi
  mov    %r8d,%ebx
  mov    %rdi,%rax
  jmp    L41
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d

assistant: ```c
void Selecao(int n, int v[]) {
  int i, j, k, min, x;
  for (i = 0; i < n - 1; i++) {
    for (k = 0; k < n; k++)
      printf("%d", v[k]);
    putchar('\n');
    min = i;
    for (j = i + 1; j < n; j++)
      if (v[j] < v[min])
        min = j;
    x = v[i];
    v[i] = v[min];
    v[min] = x;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<huix_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D15(%rip),%eax
  add    $0x1e,%eax
  mov    %eax,D19(%rip)
  mov    D19(%rip),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  leave
  ret
```

assistant: ```c
int huix_rand(int num) {
  static int i = 0;
  i += 30;
  srand(num + i);
  return rand();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<huix_rand>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    D17(%rip),%edx
  lea    0x1e(%rdx),%edi
  mov    %edi,D9(%rip)
  add    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int huix_rand(int num) {
  static int i = 0;
  i += 30;
  srand(num + i);
  return rand();
}
```
user: What is the c source code of the assembly code below?

```asm
<huix_rand>:
  endbr64
  sub    $0x8,%rsp
  mov    D19(%rip),%eax
  mov    %edi,%r8d
  lea    0x1e(%rax),%edi
  mov    %edi,D13(%rip)
  add    %r8d,%edi
  call   <srand@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <rand@plt>
```

assistant: ```c
int huix_rand(int num) {
  static int i = 0;
  i += 30;
  srand(num + i);
  return rand();
}
```
user: What is the c source code of the assembly code below?

```asm
<huix_rand>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%eax
  mov    %edi,%r8d
  lea    0x1e(%rax),%edi
  mov    %edi,D18(%rip)
  add    %r8d,%edi
  call   <srand@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <rand@plt>
```

assistant: ```c
int huix_rand(int num) {
  static int i = 0;
  i += 30;
  srand(num + i);
  return rand();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<q1f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x9,-0x30(%rbp)
  movl   $0x8,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x38(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L13:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    (%rax),%eax
  cmp    $0x5,%eax
  jg     L13
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D13: q1f ------

tool: D2: 
%s


tool: D14: %d


assistant: ```c
int q1f() {
  int a[] = {9, 8, 7, 6, 5, 4, 3, 2, 1};
  int *p = a + 1;
  printf("\n%s\n", "q1f ------");
  while (*p++ > 5) {
    printf("%d\n", *p);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<q1f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0x8,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  lea    D10(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rbx
  lea    D22(%rip),%r12
L14:
  mov    (%rbx),%ebp
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    $0x5,%ebp
  jg     L14
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x1,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string

tool: D10: q1f ------

tool: D6: 
%s


tool: D22: %d


assistant: ```c
int q1f() {
  int a[] = {9, 8, 7, 6, 5, 4, 3, 2, 1};
  int *p = a + 1;
  printf("\n%s\n", "q1f ------");
  while (*p++ > 5) {
    printf("%d\n", *p);
  }
  return 1;
}
```