ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<lldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
lldiv_t lldiv(long long numer, long long denom) {
  lldiv_t ret;
  ret.quot = numer / denom;
  ret.rem = numer % denom;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ceil_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0xffff,-0x14(%rbp)
  jle    L2
  mov    $0x10,%eax
  jmp    L34
L2:
  mov    $0x0,%eax
L34:
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  cmpl   $0xff,-0x14(%rbp)
  jle    L35
  mov    $0x8,%eax
  jmp    L60
L35:
  mov    $0x0,%eax
L60:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0x8(%rbp)
  cmpl   $0xf,-0x14(%rbp)
  jle    L69
  mov    $0x4,%eax
  jmp    L77
L69:
  mov    $0x0,%eax
L77:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0x8(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jle    L23
  mov    $0x2,%eax
  jmp    L11
L23:
  mov    $0x0,%eax
L11:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  or     %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    %eax
  or     %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ceil_log2(uint32_t v) {
  uint32_t r, shift;
  v--;
  r = (v > 0xFFFF) << 4;
  v >>= r;
  shift = (v > 0xFF) << 3;
  v >>= shift;
  r |= shift;
  shift = (v > 0xF) << 2;
  v >>= shift;
  r |= shift;
  shift = (v > 0x3) << 1;
  v >>= shift;
  r |= shift;
  r |= (v >> 1);
  return r + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ceil_log2>:
  endbr64
  sub    $0x1,%edi
  cmp    $0xffff,%edi
  setg   %al
  movzbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  sar    %cl,%edi
  cmp    $0xff,%edi
  setg   %cl
  movzbl %cl,%ecx
  shl    $0x3,%ecx
  sar    %cl,%edi
  mov    %ecx,%edx
  or     %eax,%edx
  cmp    $0xf,%edi
  setg   %cl
  movzbl %cl,%ecx
  shl    $0x2,%ecx
  sar    %cl,%edi
  or     %ecx,%edx
  cmp    $0x3,%edi
  setg   %cl
  movzbl %cl,%ecx
  add    %ecx,%ecx
  or     %ecx,%edx
  mov    %edi,%eax
  sar    %cl,%eax
  sar    %eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
uint32_t ceil_log2(uint32_t v) {
  uint32_t r, shift;
  v--;
  r = (v > 0xFFFF) << 4;
  v >>= r;
  shift = (v > 0xFF) << 3;
  v >>= shift;
  r |= shift;
  shift = (v > 0xF) << 2;
  v >>= shift;
  r |= shift;
  shift = (v > 0x3) << 1;
  v >>= shift;
  r |= shift;
  r |= (v >> 1);
  return r + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ceil_log2>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0xffff,%edi
  setg   %al
  shl    $0x4,%eax
  mov    %eax,%ecx
  sar    %cl,%edi
  xor    %ecx,%ecx
  cmp    $0xff,%edi
  setg   %cl
  shl    $0x3,%ecx
  sar    %cl,%edi
  mov    %ecx,%edx
  xor    %ecx,%ecx
  or     %eax,%edx
  cmp    $0xf,%edi
  setg   %cl
  shl    $0x2,%ecx
  sar    %cl,%edi
  or     %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x3,%edi
  mov    %edi,%eax
  setg   %cl
  add    %ecx,%ecx
  sar    %cl,%eax
  or     %ecx,%edx
  sar    %eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
uint32_t ceil_log2(uint32_t v) {
  uint32_t r, shift;
  v--;
  r = (v > 0xFFFF) << 4;
  v >>= r;
  shift = (v > 0xFF) << 3;
  v >>= shift;
  r |= shift;
  shift = (v > 0xF) << 2;
  v >>= shift;
  r |= shift;
  shift = (v > 0x3) << 1;
  v >>= shift;
  r |= shift;
  r |= (v >> 1);
  return r + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ceil_log2>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0xffff,%edi
  setg   %al
  shl    $0x4,%eax
  mov    %eax,%ecx
  sar    %cl,%edi
  xor    %ecx,%ecx
  cmp    $0xff,%edi
  setg   %cl
  shl    $0x3,%ecx
  sar    %cl,%edi
  mov    %ecx,%edx
  xor    %ecx,%ecx
  or     %eax,%edx
  cmp    $0xf,%edi
  setg   %cl
  shl    $0x2,%ecx
  sar    %cl,%edi
  or     %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x3,%edi
  mov    %edi,%eax
  setg   %cl
  add    %ecx,%ecx
  sar    %cl,%eax
  or     %ecx,%edx
  sar    %eax
  or     %edx,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
uint32_t ceil_log2(uint32_t v) {
  uint32_t r, shift;
  v--;
  r = (v > 0xFFFF) << 4;
  v >>= r;
  shift = (v > 0xFF) << 3;
  v >>= shift;
  r |= shift;
  shift = (v > 0xF) << 2;
  v >>= shift;
  r |= shift;
  shift = (v > 0x3) << 1;
  v >>= shift;
  r |= shift;
  r |= (v >> 1);
  return r + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getStrengthModifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x4,-0x4(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  jg     L53
  mov    -0x14(%rbp),%eax
  sub    $0x7,%eax
  jmp    L21
L53:
  cmpl   $0x1e,-0x14(%rbp)
  jg     L5
  subl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x14,-0x14(%rbp)
  jg     L30
  subl   $0x1,-0x4(%rbp)
L30:
  cmpl   $0x12,-0x14(%rbp)
  jg     L19
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x10,-0x14(%rbp)
  jg     L42
  subl   $0x1,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int getStrengthModifier(int str) {
  int mod = 4;
  if (str < 8)
    return str - 7;
  if (str < 31)
    mod--;
  if (str < 21)
    mod--;
  if (str < 19)
    mod--;
  if (str < 17)
    mod--;
  return mod;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getStrengthModifier>:
  endbr64
  cmp    $0x7,%edi
  jle    L3
  mov    $0x4,%eax
  cmp    $0x1e,%edi
  jg     L6
  cmp    $0x15,%edi
  setge  %al
  movzbl %al,%eax
  add    $0x2,%eax
L6:
  cmp    $0x13,%edi
  setl   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  cmp    $0x11,%edi
  setl   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
L3:
  lea    -0x7(%rdi),%eax
  ret
```

assistant: ```c
int getStrengthModifier(int str) {
  int mod = 4;
  if (str < 8)
    return str - 7;
  if (str < 31)
    mod--;
  if (str < 21)
    mod--;
  if (str < 19)
    mod--;
  if (str < 17)
    mod--;
  return mod;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getStrengthModifier>:
  endbr64
  cmp    $0x7,%edi
  jle    L10
  cmp    $0x1e,%edi
  jle    L23
  mov    $0x4,%eax
L14:
  xor    %edx,%edx
  cmp    $0x13,%edi
  setl   %dl
  sub    %edx,%eax
L21:
  xor    %edx,%edx
  cmp    $0x11,%edi
  setl   %dl
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    $0x14,%edi
  jg     L39
  mov    $0x2,%eax
  jmp    L14
  nopl   0x0(%rax)
L10:
  lea    -0x7(%rdi),%eax
  ret
L39:
  mov    $0x3,%eax
  jmp    L21
```

assistant: ```c
int getStrengthModifier(int str) {
  int mod = 4;
  if (str < 8)
    return str - 7;
  if (str < 31)
    mod--;
  if (str < 21)
    mod--;
  if (str < 19)
    mod--;
  if (str < 17)
    mod--;
  return mod;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getStrengthModifier>:
  endbr64
  cmp    $0x7,%edi
  jle    L26
  cmp    $0x1e,%edi
  jle    L0
  mov    $0x3,%edx
  mov    $0x4,%eax
  cmp    $0x12,%edi
  jg     L41
L6:
  cmp    $0x10,%edi
  jg     L13
  lea    -0x1(%rdx),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  cmp    $0x14,%edi
  jg     L49
  mov    $0x1,%edx
  mov    $0x2,%eax
  cmp    $0x12,%edi
  jle    L6
L41:
  ret
  nopl   (%rax)
L26:
  lea    -0x7(%rdi),%eax
  ret
L13:
  mov    %edx,%eax
  ret
L49:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int getStrengthModifier(int str) {
  int mod = 4;
  if (str < 8)
    return str - 7;
  if (str < 31)
    mod--;
  if (str < 21)
    mod--;
  if (str < 19)
    mod--;
  if (str < 17)
    mod--;
  return mod;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088>:
  endbr64
  cmp    $0x3,%dl
  je     L4
  ret
L4:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x79a8(%rdi),%rbp
  mov    0xc6e4(%rdi),%edx
  mov    0x47b0(%rdi),%rsi
  mov    0x79e0(%rdi),%rax
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  mov    0xc6e4(%rbx),%edx
  mov    $0x64,%ecx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <xsi_driver_first_trans_delta@plt>
  mov    $0x64,%edx
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <xsi_driver_intertial_reject@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088(char *t0, char *t1, unsigned char t2) {
  char t4[8];
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  unsigned int t15;
  char *t16;
  char *t17;
  unsigned int t18;
  unsigned int t19;
  char *t20;
LAB0:
  t5 = (t4 + 4U);
  *((unsigned char *)t5) = t2;
  t6 = (t2 == (unsigned char)3);
  if (t6 != 0)
    goto LAB2;
LAB4:
LAB3:
LAB1:
  return;
LAB2:
  t7 = (t0 + 18352U);
  t8 = *((char **)t7);
  t7 = (t0 + 31144);
  t9 = (t7 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  t13 = (t0 + 50904U);
  t14 = (t13 + 12U);
  t15 = *((unsigned int *)t14);
  t15 = (t15 * 1U);
  memcpy(t12, t8, t15);
  t16 = (t0 + 50904U);
  t17 = (t16 + 12U);
  t18 = *((unsigned int *)t17);
  t19 = (1U * t18);
  xsi_driver_first_trans_delta(t7, 0U, t19, 100LL);
  t20 = (t0 + 31144);
  xsi_driver_intertial_reject(t20, 100LL, 100LL);
  goto LAB3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088>:
  endbr64
  cmp    $0x3,%dl
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  push   %rbp
  lea    0x79a8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x79e0(%rdi),%rax
  mov    0xc6e4(%rdi),%edx
  mov    0x47b0(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  mov    0xc6e4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    $0x64,%ecx
  call   <xsi_driver_first_trans_delta@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x64,%edx
  pop    %rbx
  mov    $0x64,%esi
  pop    %rbp
  jmp    1090 <xsi_driver_intertial_reject@plt>
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088(char *t0, char *t1, unsigned char t2) {
  char t4[8];
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  unsigned int t15;
  char *t16;
  char *t17;
  unsigned int t18;
  unsigned int t19;
  char *t20;
LAB0:
  t5 = (t4 + 4U);
  *((unsigned char *)t5) = t2;
  t6 = (t2 == (unsigned char)3);
  if (t6 != 0)
    goto LAB2;
LAB4:
LAB3:
LAB1:
  return;
LAB2:
  t7 = (t0 + 18352U);
  t8 = *((char **)t7);
  t7 = (t0 + 31144);
  t9 = (t7 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  t13 = (t0 + 50904U);
  t14 = (t13 + 12U);
  t15 = *((unsigned int *)t14);
  t15 = (t15 * 1U);
  memcpy(t12, t8, t15);
  t16 = (t0 + 50904U);
  t17 = (t16 + 12U);
  t18 = *((unsigned int *)t17);
  t19 = (1U * t18);
  xsi_driver_first_trans_delta(t7, 0U, t19, 100LL);
  t20 = (t0 + 31144);
  xsi_driver_intertial_reject(t20, 100LL, 100LL);
  goto LAB3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088>:
  endbr64
  cmp    $0x3,%dl
  je     L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  push   %rbp
  lea    0x79a8(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    0x79e0(%rdi),%rax
  mov    0xc6e4(%rdi),%edx
  mov    0x47b0(%rdi),%rsi
  mov    0x38(%rax),%rdi
  call   <memcpy@plt>
  mov    0xc6e4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  mov    $0x64,%ecx
  call   <xsi_driver_first_trans_delta@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x64,%edx
  pop    %rbx
  mov    $0x64,%esi
  pop    %rbp
  jmp    1090 <xsi_driver_intertial_reject@plt>
```

assistant: ```c
void xilinxcorelib_a_2866867632_0543512595_sub_4127058543_1984854088(char *t0, char *t1, unsigned char t2) {
  char t4[8];
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  unsigned int t15;
  char *t16;
  char *t17;
  unsigned int t18;
  unsigned int t19;
  char *t20;
LAB0:
  t5 = (t4 + 4U);
  *((unsigned char *)t5) = t2;
  t6 = (t2 == (unsigned char)3);
  if (t6 != 0)
    goto LAB2;
LAB4:
LAB3:
LAB1:
  return;
LAB2:
  t7 = (t0 + 18352U);
  t8 = *((char **)t7);
  t7 = (t0 + 31144);
  t9 = (t7 + 56U);
  t10 = *((char **)t9);
  t11 = (t10 + 56U);
  t12 = *((char **)t11);
  t13 = (t0 + 50904U);
  t14 = (t13 + 12U);
  t15 = *((unsigned int *)t14);
  t15 = (t15 * 1U);
  memcpy(t12, t8, t15);
  t16 = (t0 + 50904U);
  t17 = (t16 + 12U);
  t18 = *((unsigned int *)t17);
  t19 = (1U * t18);
  xsi_driver_first_trans_delta(t7, 0U, t19, 100LL);
  t20 = (t0 + 31144);
  xsi_driver_intertial_reject(t20, 100LL, 100LL);
  goto LAB3;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Dmm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L47
L49:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x24(%rbp),%esi
  mov    -0x4(%rbp),%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L35
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  add    $0xa,%edx
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
L35:
  addl   $0x1,-0x4(%rbp)
L47:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L49
  jmp    L1
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jle    L22
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L9
L22:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Dmm(int *m, int *sq, int a) {
  int b;
  for (b = 1; b <= sq[0]; b++) {
    m[a + b] -= sq[b];
    if (m[a + b] < 0) {
      m[a + b] += 10;
      m[a + b + 1]--;
    }
  }
  while (m[0] > 1 && m[m[0]] == 0)
    m[0]--;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Dmm>:
  endbr64
  cmpl   $0x0,(%rsi)
  jle    L23
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    $0x1,%edx
  jmp    L52
L50:
  add    $0xa,%eax
  mov    %eax,0x4(%rcx)
  subl   $0x1,0x8(%rcx)
L68:
  add    $0x1,%rdx
  add    $0x4,%rcx
  cmp    %edx,(%rsi)
  jl     L23
L52:
  mov    0x4(%rcx),%eax
  sub    (%rsi,%rdx,4),%eax
  js     L50
  mov    %eax,0x4(%rcx)
  jmp    L68
L23:
  mov    (%rdi),%ecx
  cmp    $0x1,%ecx
  jle    L0
  lea    -0x1(%rcx),%eax
  cltq
  movslq %ecx,%rdx
  sub    $0x2,%rdx
  lea    -0x2(%rcx),%ecx
  sub    %rcx,%rdx
L65:
  cmpl   $0x0,0x4(%rdi,%rax,4)
  jne    L0
  mov    %eax,(%rdi)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L65
L0:
  ret
```

assistant: ```c
void Dmm(int *m, int *sq, int a) {
  int b;
  for (b = 1; b <= sq[0]; b++) {
    m[a + b] -= sq[b];
    if (m[a + b] < 0) {
      m[a + b] += 10;
      m[a + b + 1]--;
    }
  }
  while (m[0] > 1 && m[m[0]] == 0)
    m[0]--;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Dmm>:
  endbr64
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jle    L61
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    $0x1,%edx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %eax,0x4(%rcx)
  add    $0x1,%rdx
  add    $0x4,%rcx
  cmp    %edx,(%rsi)
  jl     L61
L14:
  mov    0x4(%rcx),%eax
  sub    (%rsi,%rdx,4),%eax
  jns    L16
  add    $0xa,%eax
  subl   $0x1,0x8(%rcx)
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %eax,(%rcx)
  cmp    %edx,(%rsi)
  jge    L14
L61:
  mov    (%rdi),%ecx
  cmp    $0x1,%ecx
  jle    L83
  movslq %ecx,%rdx
  lea    -0x1(%rcx),%eax
  sub    $0x2,%ecx
  sub    $0x2,%rdx
  cltq
  sub    %rcx,%rdx
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L88:
  mov    %eax,(%rdi)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  je     L83
L52:
  mov    0x4(%rdi,%rax,4),%ecx
  test   %ecx,%ecx
  je     L88
L83:
  ret
```

assistant: ```c
void Dmm(int *m, int *sq, int a) {
  int b;
  for (b = 1; b <= sq[0]; b++) {
    m[a + b] -= sq[b];
    if (m[a + b] < 0) {
      m[a + b] += 10;
      m[a + b + 1]--;
    }
  }
  while (m[0] > 1 && m[m[0]] == 0)
    m[0]--;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Dmm>:
  endbr64
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jle    L73
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rcx
  mov    $0x1,%edx
  nopl   0x0(%rax,%rax,1)
L83:
  mov    0x4(%rcx),%eax
  sub    (%rsi,%rdx,4),%eax
  js     L22
  mov    %eax,0x4(%rcx)
  add    $0x1,%rdx
  add    $0x4,%rcx
  cmp    %edx,(%rsi)
  jge    L83
L73:
  mov    (%rdi),%ecx
  cmp    $0x1,%ecx
  jle    L3
  movslq %ecx,%rdx
  lea    -0x1(%rcx),%eax
  sub    $0x2,%ecx
  sub    $0x2,%rdx
  cltq
  sub    %rcx,%rdx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %eax,(%rdi)
  sub    $0x1,%rax
  cmp    %rax,%rdx
  je     L3
L9:
  mov    0x4(%rdi,%rax,4),%ecx
  test   %ecx,%ecx
  je     L60
L3:
  ret
  nopl   0x0(%rax)
L22:
  add    $0xa,%eax
  subl   $0x1,0x8(%rcx)
  add    $0x1,%rdx
  add    $0x4,%rcx
  mov    %eax,(%rcx)
  cmp    %edx,(%rsi)
  jge    L83
  jmp    L73
```

assistant: ```c
void Dmm(int *m, int *sq, int a) {
  int b;
  for (b = 1; b <= sq[0]; b++) {
    m[a + b] -= sq[b];
    if (m[a + b] < 0) {
      m[a + b] += 10;
      m[a + b + 1]--;
    }
  }
  while (m[0] > 1 && m[m[0]] == 0)
    m[0]--;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L7
  movzbl -0x4(%rbp),%eax
  jmp    L5
L7:
  mov    $0x2e,%eax
L5:
  leave
  ret
```

assistant: ```c
char printable(char c) {
  if (isprint(c)) {
    return c;
  } else {
    return '.';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <isprint@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char printable(char c) {
  if (isprint(c)) {
    return c;
  } else {
    return '.';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<printable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <isprint@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char printable(char c) {
  if (isprint(c)) {
    return c;
  } else {
    return '.';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <isprint@plt>
  test   %rax,%rax
  mov    $0x2e,%eax
  cmovne %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char printable(char c) {
  if (isprint(c)) {
    return c;
  } else {
    return '.';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  je     L39
  imul   %eax,%eax
L15:
  test   %eax,%eax
  je     L2
  add    %eax,%eax
L8:
  add    $0x17c2d8f4,%eax
  mov    %eax,(%rsi)
  ret
L39:
  mov    %eax,%edx
  shr    $0x10,%edx
  movzwl %ax,%ecx
  shl    $0x10,%eax
  or     %ecx,%eax
  mov    %dx,%ax
  jmp    L15
L2:
  movsbl %ah,%edx
  mov    %eax,%ecx
  sar    $0x18,%ecx
  mov    %cl,%ah
  shl    $0x18,%edx
  and    $0xffffff,%eax
  or     %edx,%eax
  jmp    L8
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy13;
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 398645492UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  je     L7
  imul   %eax,%eax
  mov    %eax,%edx
  test   %eax,%eax
  je     L13
  lea    (%rax,%rax,1),%edx
  add    $0x17c2d8f4,%edx
  mov    %edx,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %edx,%edx
L13:
  and    $0xff00ff,%edx
  add    $0x17c2d8f4,%edx
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy13;
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 398645492UL;
  }
}
```