user: Translate the below assembly code into C programming language:

```asm
<homogenize_eth_addr>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x11(%r15),%rdx
  mov    %eax,0xc(%rsp)
  mov    %r15,%rax
  nopl   (%rax)
L146:
  cmpb   $0x2d,(%rax)
  jne    L206
  movb   $0x3a,(%rax)
L206:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L146
  lea    D23(%rip),%rbp
  pxor   %xmm0,%xmm0
  mov    %r15,%rdi
  movb   $0x0,0x20(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%r14
  call   <strtok2@plt>
  mov    %r14,%r13
  mov    %rax,%r12
  test   %rax,%rax
  je     L80
L20:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok2@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    $0x2,%eax
  je     L113
  jg     L15
  test   %eax,%eax
  je     L210
  cmp    $0x1,%eax
  jne    L48
  mov    %r13,%rdi
  mov    %r12,%rdx
  lea    D21(%rip),%rsi
  call   <sprintf@plt>
  cltq
  add    %rax,%r13
L210:
  test   %rbx,%rbx
  je     L80
L169:
  movb   $0x3a,0x0(%r13)
  mov    %rbx,%r12
  add    $0x1,%r13
  jmp    L20
  nopl   0x0(%rax)
L15:
  cmp    $0xc,%eax
  jne    L48
  movb   $0x0,0x11(%r15)
  lea    0x10(%r15),%rax
  lea    0xa(%r15),%rdx
  lea    0x1(%r15),%rcx
L197:
  movzbl 0x1(%rdx),%esi
  sub    $0x3,%rax
  sub    $0x2,%rdx
  mov    %sil,0x3(%rax)
  movzbl 0x2(%rdx),%esi
  mov    %sil,0x2(%rax)
  movb   $0x3a,0x1(%rax)
  cmp    %rcx,%rax
  jne    L197
L48:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L113:
  mov    %r13,%rdi
  mov    %r12,%rdx
  lea    D28(%rip),%rsi
  call   <sprintf@plt>
  cltq
  add    %rax,%r13
  test   %rbx,%rbx
  jne    L169
L80:
  mov    $0x11,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    $0x1,%ebx
  call   <memcpy@plt>
  movslq 0xc(%rsp),%rbp
  mov    $0x11,%r12d
  cmp    $0x1,%ebp
  jne    L68
  jmp    L48
  nop
L84:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L48
L68:
  cmpb   $0x3a,-0x1(%r15,%rbx,1)
  mov    %ebx,%esi
  jne    L84
  cmpb   $0x3a,(%r15,%rbx,1)
  lea    (%r15,%rbx,1),%r8
  jne    L84
  lea    0x1(%rbx),%eax
  cltq
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%r15,%rax,1)
  jne    L77
  sub    %esi,%edx
  mov    %r12d,%r13d
  mov    %r8,%rsi
  sub    %edx,%r13d
  movslq %r13d,%rdi
  add    %r15,%rdi
  call   <memcpy@plt>
  cmp    %r13d,%ebx
  jge    L84
  movslq %ebx,%rax
  nopl   0x0(%rax)
L30:
  movb   $0x30,(%r15,%rax,1)
  movb   $0x30,0x1(%r15,%rax,1)
  movb   $0x3a,0x2(%r15,%rax,1)
  add    $0x3,%rax
  cmp    %eax,%r13d
  jg     L30
  jmp    L84
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type: string
name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D28
type: string

tool: D23: :

tool: D21: 0%s

tool: D28: %s

assistant: ```c
void homogenize_eth_addr(char *buf) {
  const size_t len = strlen(buf);
  for (int i = 0; i < 17; i++) {
    if (buf[i] == '-')
      buf[i] = ':';
  }
  char tmp[17] = {
      0,
  };
  char *cur = tmp;
  char *pair = strtok2(buf, ":");
  while (pair) {
    char *next = strtok2(NULL, ":");
    switch (strlen(pair)) {
    case 12: {
      char *ptr = &buf[3 * 5 + 2];
      *(ptr--) = 0;
      for (int i = 5; i >= 1; i--) {
        *(ptr--) = buf[1 + i * 2];
        *(ptr--) = buf[i * 2];
        *(ptr--) = ':';
      }
    }
      return;
    case 2:
      cur += sprintf(cur, "%s", pair);
      break;
    case 1:
      cur += sprintf(cur, "0%s", pair);
      break;
    case 0:
      break;
    default:
      return;
    }
    if (next) {
      *cur++ = ':';
    }
    pair = next;
  }
  memcpy(buf, tmp, 17);
  for (int i = 0; i < len - 1; i++) {
    if (buf[i] != ':')
      continue;
    if (buf[i + 1] != ':')
      continue;
    const int p1 = i + 1;
    int p2 = p1;
    for (; buf[p2] != 0; p2++) {
    }
    const int digits = p2 - p1;
    const int p3 = 17 - digits;
    memcpy(&buf[p3], &buf[p1], digits);
    for (int j = p1; j < p3; j += 3) {
      buf[j] = '0';
      buf[j + 1] = '0';
      buf[j + 2] = ':';
    }
  }
}
```