ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<start_dev_log>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <log_int@plt>
  lea    D74(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  cmp    $0x1,%r12d
  jne    L29
L20:
  mov    %ebp,%eax
  add    %ebx,%eax
  je     L27
  test   %ebp,%ebp
  jle    L76
  test   %ebx,%ebx
  jne    L128
  lea    D82(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <log_int@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L27
L5:
  mov    $0x73,%edi
  mov    $0x0,%eax
  call   <log_char@plt>
L81:
  test   %ebx,%ebx
  jle    L27
  mov    $0x2c,%edi
  mov    $0x0,%eax
  call   <log_char@plt>
  jmp    L121
L29:
  mov    $0x73,%edi
  mov    $0x0,%eax
  call   <log_char@plt>
  jmp    L20
L128:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  mov    $0x0,%eax
  call   <log_int@plt>
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L81
  jmp    L5
L122:
  mov    $0x73,%edi
  mov    $0x0,%eax
  call   <log_char@plt>
  jmp    L27
L76:
  test   %ebx,%ebx
  jle    L27
L121:
  lea    D82(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <log_int@plt>
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  cmp    $0x1,%ebx
  jne    L122
L27:
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D61
datatype: string
name: retrieve_data
arguments: data_tag: D74
datatype: string
name: retrieve_data
arguments: data_tag: D82
datatype: string
name: retrieve_data
arguments: data_tag: D56
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D53
datatype: string
name: retrieve_data
arguments: data_tag: D49
datatype: string

tool: D61:     

tool: D74:  Colonist Unit

tool: D82:  and 

tool: D56:  Colonial Mining Unit

tool: D23: , 

tool: D53:  Colonial Manufacturing Unit

tool: D49:  were built

assistant: ```c
start_dev_log(num_CUs, num_IUs, num_AUs) int num_CUs, num_IUs, num_AUs;
{
  log_string("    ");
  log_int(num_CUs);
  log_string(" Colonist Unit");
  if (num_CUs != 1)
    log_char('s');
  if (num_IUs + num_AUs == 0)
    goto done;
  if (num_IUs > 0) {
    if (num_AUs == 0)
      log_string(" and ");
    else
      log_string(", ");
    log_int(num_IUs);
    log_string(" Colonial Mining Unit");
    if (num_IUs != 1)
      log_char('s');
  }
  if (num_AUs > 0) {
    if (num_IUs > 0)
      log_char(',');
    log_string(" and ");
    log_int(num_AUs);
    log_string(" Colonial Manufacturing Unit");
    if (num_AUs != 1)
      log_char('s');
  }
done:
  log_string(" were built");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<start_dev_log>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  lea    D27(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <log_string@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D67(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%r12d
  je     L64
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
L64:
  mov    %ebp,%eax
  add    %ebx,%eax
  je     L47
  test   %ebp,%ebp
  jle    L24
  test   %ebx,%ebx
  je     L113
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L95
L75:
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
L95:
  test   %ebx,%ebx
  jle    L47
  mov    $0x2c,%edi
  xor    %eax,%eax
  call   <log_char@plt>
  jmp    L67
  nopl   (%rax)
L24:
  test   %ebx,%ebx
  jle    L47
L67:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebx
  jne    L102
L47:
  pop    %rbx
  lea    D49(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <log_string@plt>
  nopl   0x0(%rax,%rax,1)
L113:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D35(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L47
  jmp    L75
  nop
L102:
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
  jmp    L47
```

tool_calls: name: disassemble_data
arguments: label: D27
type: string
name: disassemble_data
arguments: label: D67
type: string
name: disassemble_data
arguments: label: D37
type: string
name: disassemble_data
arguments: label: D35
type: string
name: disassemble_data
arguments: label: D41
type: string
name: disassemble_data
arguments: label: D38
type: string
name: disassemble_data
arguments: label: D49
type: string

tool: D27:     

tool: D67:  Colonist Unit

tool: D37: , 

tool: D35:  Colonial Mining Unit

tool: D41:  and 

tool: D38:  Colonial Manufacturing Unit

tool: D49:  were built

assistant: ```c
start_dev_log(num_CUs, num_IUs, num_AUs) int num_CUs, num_IUs, num_AUs;
{
  log_string("    ");
  log_int(num_CUs);
  log_string(" Colonist Unit");
  if (num_CUs != 1)
    log_char('s');
  if (num_IUs + num_AUs == 0)
    goto done;
  if (num_IUs > 0) {
    if (num_AUs == 0)
      log_string(" and ");
    else
      log_string(", ");
    log_int(num_IUs);
    log_string(" Colonial Mining Unit");
    if (num_IUs != 1)
      log_char('s');
  }
  if (num_AUs > 0) {
    if (num_IUs > 0)
      log_char(',');
    log_string(" and ");
    log_int(num_AUs);
    log_string(" Colonial Manufacturing Unit");
    if (num_AUs != 1)
      log_char('s');
  }
done:
  log_string(" were built");
}
```
user: Translate the below assembly code into C programming language:

```asm
<start_dev_log>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  lea    D40(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <log_string@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%r12d
  je     L26
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
L26:
  mov    %ebp,%eax
  add    %ebx,%eax
  je     L69
  test   %ebp,%ebp
  jle    L110
  test   %ebx,%ebx
  je     L7
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D75(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L29
L95:
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
L29:
  test   %ebx,%ebx
  jle    L69
  mov    $0x2c,%edi
  xor    %eax,%eax
  call   <log_char@plt>
  jmp    L20
  nopl   (%rax)
L110:
  test   %ebx,%ebx
  jle    L69
L20:
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebx,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D77(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebx
  jne    L30
L69:
  pop    %rbx
  lea    D86(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <log_string@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  call   <log_string@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <log_int@plt>
  xor    %eax,%eax
  lea    D75(%rip),%rdi
  call   <log_string@plt>
  cmp    $0x1,%ebp
  je     L69
  jmp    L95
  nop
L30:
  mov    $0x73,%edi
  xor    %eax,%eax
  call   <log_char@plt>
  jmp    L69
```

tool_calls: name: parse_data
arguments: label: D40
type_infered: string
name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D78
type_infered: string
name: parse_data
arguments: label: D75
type_infered: string
name: parse_data
arguments: label: D67
type_infered: string
name: parse_data
arguments: label: D77
type_infered: string
name: parse_data
arguments: label: D86
type_infered: string

tool: D40:     

tool: D26:  Colonist Unit

tool: D78: , 

tool: D75:  Colonial Mining Unit

tool: D67:  and 

tool: D77:  Colonial Manufacturing Unit

tool: D86:  were built

assistant: ```c
start_dev_log(num_CUs, num_IUs, num_AUs) int num_CUs, num_IUs, num_AUs;
{
  log_string("    ");
  log_int(num_CUs);
  log_string(" Colonist Unit");
  if (num_CUs != 1)
    log_char('s');
  if (num_IUs + num_AUs == 0)
    goto done;
  if (num_IUs > 0) {
    if (num_AUs == 0)
      log_string(" and ");
    else
      log_string(", ");
    log_int(num_IUs);
    log_string(" Colonial Mining Unit");
    if (num_IUs != 1)
      log_char('s');
  }
  if (num_AUs > 0) {
    if (num_IUs > 0)
      log_char(',');
    log_string(" and ");
    log_int(num_AUs);
    log_string(" Colonial Manufacturing Unit");
    if (num_AUs != 1)
      log_char('s');
  }
done:
  log_string(" were built");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UTD1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L7
  movsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L1
L7:
  movsd  -0x8(%rbp),%xmm0
L1:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: f64

tool: D7: 4294967296

assistant: ```c
double UTD1(u)
unsigned u;
{
  double d;
  d = (int)u;
  return ((int)u < 0) ? d + 4294967296.0 : d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UTD1>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  test   %edi,%edi
  js     L5
L9:
  ret
L5:
  addsd  D3(%rip),%xmm0
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D3
type: f64

tool: D3: 4294967296

assistant: ```c
double UTD1(u)
unsigned u;
{
  double d;
  d = (int)u;
  return ((int)u < 0) ? d + 4294967296.0 : d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UTD1>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  test   %edi,%edi
  js     L6
  ret
  nopl   0x0(%rax)
L6:
  addsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: f64

tool: D0: 4294967296

assistant: ```c
double UTD1(u)
unsigned u;
{
  double d;
  d = (int)u;
  return ((int)u < 0) ? d + 4294967296.0 : d;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UTD1>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  test   %edi,%edi
  js     L5
  ret
  nopl   0x0(%rax)
L5:
  addsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: f64

tool: D0: 4294967296

assistant: ```c
double UTD1(u)
unsigned u;
{
  double d;
  d = (int)u;
  return ((int)u < 0) ? d + 4294967296.0 : d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<control_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int control_close(int fd) {
  close(fd);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<control_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int control_close(int fd) {
  close(fd);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<control_close>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int control_close(int fd) {
  close(fd);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L19:
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x9,-0x4(%rbp)
  jle    L19
  nop
  pop    %rbp
  ret
```

assistant: ```c
void loop() {
  for (int i = 0; i < 10; i++)
    i + 2;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<loop>:
  endbr64
  ret
```

assistant: ```c
void loop() {
  for (int i = 0; i < 10; i++)
    i + 2;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<loop>:
  endbr64
  ret
```

assistant: ```c
void loop() {
  for (int i = 0; i < 10; i++)
    i + 2;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<loop>:
  endbr64
  ret
```

assistant: ```c
void loop() {
  for (int i = 0; i < 10; i++)
    i + 2;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<debug_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x10,-0x28(%rbp)
L26:
  mov    -0x34(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x9,-0x24(%rbp)
  jg     L19
  mov    -0x24(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x29(%rbp)
  jmp    L24
L19:
  mov    -0x24(%rbp),%eax
  add    $0x57,%eax
  mov    %al,-0x29(%rbp)
L24:
  subl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x29(%rbp),%edx
  mov    %dl,-0x20(%rbp,%rax,1)
  sarl   $0x4,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L26
  mov    -0x28(%rbp),%edx
  mov    $0x10,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x20(%rbp),%rcx
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <debug_data@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void debug_hex(uint64_t n) {
  char buf[16];
  int i = sizeof buf;
  do {
    int m = n & 15;
    char c;
    if (m < 10)
      c = '0' + m;
    else
      c = 'a' + (m - 10);
    buf[--i] = c;
    n >>= 4;
  } while (n);
  debug_data(buf + i, sizeof buf - i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<debug_hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xf,%eax
  jmp    L9
L15:
  mov    %rdx,%rax
L9:
  mov    %edi,%ecx
  and    $0xf,%ecx
  lea    0x30(%rcx),%esi
  lea    0x57(%rcx),%edx
  cmp    $0x9,%ecx
  cmovle %esi,%edx
  mov    %dl,(%rsp,%rax,1)
  lea    -0x1(%rax),%rdx
  sar    $0x4,%edi
  jne    L15
  mov    $0x10,%esi
  sub    %eax,%esi
  movslq %eax,%rcx
  lea    (%rsp,%rcx,1),%rdi
  call   <debug_data@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void debug_hex(uint64_t n) {
  char buf[16];
  int i = sizeof buf;
  do {
    int m = n & 15;
    char c;
    if (m < 10)
      c = '0' + m;
    else
      c = 'a' + (m - 10);
    buf[--i] = c;
    n >>= 4;
  } while (n);
  debug_data(buf + i, sizeof buf - i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<debug_hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0xf,%eax
  mov    %rsp,%r8
  xchg   %ax,%ax
L17:
  mov    %edi,%ecx
  and    $0xf,%ecx
  cmp    $0x9,%ecx
  lea    0x30(%rcx),%esi
  lea    0x57(%rcx),%edx
  movslq %eax,%rcx
  cmovle %esi,%edx
  mov    %dl,(%r8,%rax,1)
  sub    $0x1,%rax
  sar    $0x4,%edi
  jne    L17
  mov    $0x10,%esi
  lea    (%r8,%rcx,1),%rdi
  sub    %ecx,%esi
  call   <debug_data@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void debug_hex(uint64_t n) {
  char buf[16];
  int i = sizeof buf;
  do {
    int m = n & 15;
    char c;
    if (m < 10)
      c = '0' + m;
    else
      c = 'a' + (m - 10);
    buf[--i] = c;
    n >>= 4;
  } while (n);
  debug_data(buf + i, sizeof buf - i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<debug_hex>:
  endbr64
  mov    %edi,%ecx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  and    $0xf,%ecx
  cmp    $0xa,%ecx
  lea    0x57(%rcx),%esi
  lea    0x30(%rcx),%edx
  cmovge %esi,%edx
  mov    %dl,0xf(%rsp)
  mov    %edi,%edx
  sar    $0x4,%edx
  je     L157
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0x8,%edx
  mov    %sil,0xe(%rsp)
  je     L10
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0xc,%edx
  mov    %sil,0xd(%rsp)
  je     L139
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0x10,%edx
  mov    %sil,0xc(%rsp)
  je     L100
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0x14,%edx
  mov    %sil,0xb(%rsp)
  je     L34
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0x18,%edx
  mov    %sil,0xa(%rsp)
  je     L48
  and    $0xf,%edx
  cmp    $0xa,%edx
  lea    0x57(%rdx),%esi
  lea    0x30(%rdx),%ecx
  mov    %edi,%edx
  cmovl  %ecx,%esi
  sar    $0x1c,%edx
  mov    %sil,0x9(%rsp)
  je     L132
  and    $0xf,%edx
  cmp    $0x9,%edx
  jle    L107
  add    $0x57,%edx
  mov    %dl,0x8(%rsp)
L176:
  movabs $0x6666666666666666,%rax
  xor    %edx,%edx
  mov    %rax,(%rsp)
L2:
  mov    $0x10,%esi
  lea    (%rsp,%rdx,1),%rdi
  sub    %edx,%esi
  call   <debug_data@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L167
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L107:
  add    $0x30,%edx
  mov    %dl,0x8(%rsp)
  mov    $0x8,%edx
  test   %edi,%edi
  js     L176
  jmp    L2
L48:
  mov    $0xa,%edx
  jmp    L2
  nopl   0x0(%rax)
L157:
  mov    $0xf,%edx
  jmp    L2
  nop
L10:
  mov    $0xe,%edx
  jmp    L2
L139:
  mov    $0xd,%edx
  jmp    L2
L100:
  mov    $0xc,%edx
  jmp    L2
L34:
  mov    $0xb,%edx
  jmp    L2
L132:
  mov    $0x9,%edx
  jmp    L2
L167:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void debug_hex(uint64_t n) {
  char buf[16];
  int i = sizeof buf;
  do {
    int m = n & 15;
    char c;
    if (m < 10)
      c = '0' + m;
    else
      c = 'a' + (m - 10);
    buf[--i] = c;
    n >>= 4;
  } while (n);
  debug_data(buf + i, sizeof buf - i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L2
L18:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string

tool: D13: This program prints a table of squares.

tool: D10: Enter number of entries in table: 

tool: D19: %d

tool: D31: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L13
  mov    $0x1,%ebx
  lea    D31(%rip),%rbp
L22:
  mov    %ebx,%edx
  imul   %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L22
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string

tool: D13: This program prints a table of squares.

tool: D36: Enter number of entries in table: 

tool: D11: %d

tool: D31: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L4
  mov    $0x1,%ebx
  lea    D18(%rip),%rbp
  nopl   0x0(%rax)
L29:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L29
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
data_type: string
name: disassemble_data
arguments: label: D20
data_type: string
name: disassemble_data
arguments: label: D28
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string

tool: D29: This program prints a table of squares.

tool: D20: Enter number of entries in table: 

tool: D28: %d

tool: D18: %10d%10d


assistant: ```c
int main(void) {
  int i, n;
  printf("This program prints a table of squares.\n");
  printf("Enter number of entries in table: ");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
    printf("%10d%10d\n", i, i * i);
  return 0;
}
```