ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  mov    %rdi,%r11
  movslq %edx,%rax
  lea    0x1(%rsi),%edi
  movslq %esi,%rsi
  push   %rbp
  lea    (%r11,%rsi,8),%rbp
  push   %rbx
  mov    %rax,%rbx
  lea    (%r11,%rax,8),%rax
  mov    0x0(%rbp),%rsi
  mov    (%rax),%rdx
  mov    %ebx,%r8d
  cmp    %ebx,%edi
  jge    L71
  nop
L68:
  movslq %edi,%rax
  shl    $0x3,%rax
  lea    (%r11,%rax,1),%r10
  lea    0x8(%r11,%rax,1),%rax
  mov    (%r10),%rdx
  cmp    %rdx,%rsi
  jb     L1
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rax,%r10
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    $0x1,%edi
  cmp    %rsi,%rdx
  jbe    L56
L1:
  movslq %r8d,%rax
  lea    (%r11,%rax,8),%r9
  mov    (%r9),%rcx
  cmp    %rcx,%rsi
  jae    L20
  lea    -0x8(%r11,%rax,8),%rax
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    %rax,%r9
  mov    (%rax),%rcx
  sub    $0x8,%rax
  sub    $0x1,%r8d
  cmp    %rsi,%rcx
  ja     L34
L20:
  cmp    %r8d,%edi
  jl     L88
  mov    (%r9),%rax
  test   %r8d,%r8d
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  cmove  %eax,%r8d
  mov    %rsi,(%r9)
  cmp    %ebx,%r8d
  je     L5
L29:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L88:
  mov    %rcx,(%r10)
  mov    %rdx,(%r9)
  jmp    L68
L71:
  mov    %rdx,0x0(%rbp)
  mov    $0x1,%r8d
  mov    %rsi,(%rax)
  test   %ebx,%ebx
  je     L29
L5:
  lea    -0x1(%rbx),%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int partition(unsigned long *arr, int lo, int hi) {
  int i, j;
  unsigned long pivot, temp;
  i = lo + 1;
  j = hi;
  pivot = arr[lo];
  while (i < j) {
    while (arr[i] <= pivot) {
      i++;
    }
    while (arr[j] > pivot) {
      j--;
    }
    if (i < j) {
      temp = arr[i];
      arr[i] = arr[j];
      arr[j] = temp;
    }
  }
  arr[lo] = arr[j];
  arr[j] = pivot;
  if (j == 0) {
    j++;
  }
  if (j == hi) {
    j--;
  }
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<partition>:
  endbr64
  mov    %rdi,%r11
  movslq %edx,%rax
  lea    0x1(%rsi),%edi
  movslq %esi,%rsi
  push   %rbp
  lea    (%r11,%rsi,8),%rbp
  push   %rbx
  mov    %rax,%rbx
  lea    (%r11,%rax,8),%rax
  mov    0x0(%rbp),%rsi
  mov    (%rax),%rdx
  mov    %ebx,%r8d
  cmp    %ebx,%edi
  jge    L15
  nop
L38:
  movslq %edi,%rax
  shl    $0x3,%rax
  lea    (%r11,%rax,1),%r10
  lea    0x8(%r11,%rax,1),%rax
  mov    (%r10),%rcx
  cmp    %rcx,%rsi
  jb     L50
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %rax,%r10
  mov    (%rax),%rcx
  add    $0x8,%rax
  add    $0x1,%edi
  cmp    %rsi,%rcx
  jbe    L72
L50:
  movslq %r8d,%rax
  lea    (%r11,%rax,8),%r9
  mov    (%r9),%rdx
  cmp    %rdx,%rsi
  jae    L48
  lea    -0x8(%r11,%rax,8),%rax
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    %rax,%r9
  mov    (%rax),%rdx
  sub    $0x8,%rax
  sub    $0x1,%r8d
  cmp    %rsi,%rdx
  ja     L29
L48:
  cmp    %r8d,%edi
  jl     L71
  test   %r8d,%r8d
  mov    $0x1,%eax
  mov    %rdx,0x0(%rbp)
  cmove  %eax,%r8d
  mov    %rsi,(%r9)
  cmp    %ebx,%r8d
  je     L37
L85:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L71:
  mov    %rdx,(%r10)
  mov    %rcx,(%r9)
  jmp    L38
L15:
  mov    %rdx,0x0(%rbp)
  mov    $0x1,%r8d
  mov    %rsi,(%rax)
  test   %ebx,%ebx
  je     L85
L37:
  lea    -0x1(%rbx),%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int partition(unsigned long *arr, int lo, int hi) {
  int i, j;
  unsigned long pivot, temp;
  i = lo + 1;
  j = hi;
  pivot = arr[lo];
  while (i < j) {
    while (arr[i] <= pivot) {
      i++;
    }
    while (arr[j] > pivot) {
      j--;
    }
    if (i < j) {
      temp = arr[i];
      arr[i] = arr[j];
      arr[j] = temp;
    }
  }
  arr[lo] = arr[j];
  arr[j] = pivot;
  if (j == 0) {
    j++;
  }
  if (j == hi) {
    j--;
  }
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<seconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  test   %rax,%rax
  js     L12
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L15
L12:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L15:
  movsd  D8(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: byte[8]

tool: {"D8": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double seconds(void) {
  struct timeval t;
  gettimeofday(&t, 0);
  return 1E-6 * (1000000ULL * t.tv_sec + t.tv_usec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<seconds>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  js     L24
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L22:
  mulsd  D9(%rip),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  ret
L24:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L22
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double seconds(void) {
  struct timeval t;
  gettimeofday(&t, 0);
  return 1E-6 * (1000000ULL * t.tv_sec + t.tv_usec);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<seconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  js     L20
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L29:
  mulsd  D9(%rip),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L29
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
datatype: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double seconds(void) {
  struct timeval t;
  gettimeofday(&t, 0);
  return 1E-6 * (1000000ULL * t.tv_sec + t.tv_usec);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<seconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,(%rsp),%rax
  add    0x8(%rsp),%rax
  js     L12
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L19:
  mulsd  D1(%rip),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L19
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: byte[8]

tool: {"D1": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double seconds(void) {
  struct timeval t;
  gettimeofday(&t, 0);
  return 1E-6 * (1000000ULL * t.tv_sec + t.tv_usec);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vqes_syslog_cli>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void vqes_syslog_cli(int pri, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  printf(fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<vqes_syslog_cli>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vqes_syslog_cli(int pri, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  printf(fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vqes_syslog_cli>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vqes_syslog_cli(int pri, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  printf(fmt, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vqes_syslog_cli>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vqes_syslog_cli(int pri, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  printf(fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movb   $0x2f,-0x9(%rbp)
  movsbl -0x9(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L17
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L14
L17:
  mov    -0x18(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
const char *basename(const char *path) {
  char sep = '/';
  const char *p = strrchr(path, sep);
  if (p) {
    return p + 1;
  } else {
    return path;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *basename(const char *path) {
  char sep = '/';
  const char *p = strrchr(path, sep);
  if (p) {
    return p + 1;
  } else {
    return path;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *basename(const char *path) {
  char sep = '/';
  const char *p = strrchr(path, sep);
  if (p) {
    return p + 1;
  } else {
    return path;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *basename(const char *path) {
  char sep = '/';
  const char *p = strrchr(path, sep);
  if (p) {
    return p + 1;
  } else {
    return path;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sleep_sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L0:
  mov    $0xf423f,%edi
  call   <usleep@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x4(%rbp),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  comisd -0x20(%rbp),%xmm3
  ja     L0
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movsd  -0x18(%rbp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
void sleep_sec(double sec) {
  int i;
  for (i = 0; i < floor(sec); ++i) {
    usleep(999999);
  }
  usleep(1000000 * (sec - floor(sec)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<sleep_sec>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  D4(%rip),%xmm2
  movapd %xmm0,%xmm1
  andpd  %xmm2,%xmm1
  movsd  D25(%rip),%xmm3
  ucomisd %xmm1,%xmm3
  jbe    L18
  movapd %xmm0,%xmm5
  cvttsd2si %xmm0,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movapd %xmm1,%xmm0
  cmpnlesd %xmm5,%xmm0
  movsd  D16(%rip),%xmm3
  andpd  %xmm3,%xmm0
  subsd  %xmm0,%xmm1
  andnpd %xmm5,%xmm2
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
L18:
  movq   %xmm0,%r14
  mov    $0x0,%ebx
  jmp    L1
L6:
  mov    $0xf423f,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
L1:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  movq   %r14,%xmm4
  comisd %xmm0,%xmm4
  ja     L6
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm4,%xmm0
  mulsd  D36(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <usleep@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: byte[8]
name: read_data
arguments: tag: D25
type_guessed: byte[8]
name: read_data
arguments: tag: D16
type_guessed: byte[8]
name: read_data
arguments: tag: D36
type_guessed: byte[8]

tool: {"D4": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
void sleep_sec(double sec) {
  int i;
  for (i = 0; i < floor(sec); ++i) {
    usleep(999999);
  }
  usleep(1000000 * (sec - floor(sec)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sleep_sec>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm5
  sub    $0x10,%rsp
  movsd  D30(%rip),%xmm1
  movsd  D11(%rip),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm0,(%rsp)
  andpd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm2
  jbe    L19
  cvttsd2si %xmm5,%rax
  pxor   %xmm0,%xmm0
  movsd  D19(%rip),%xmm3
  andnpd %xmm5,%xmm1
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm2
  cmpnlesd %xmm5,%xmm2
  andpd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  orpd   %xmm1,%xmm0
  movsd  %xmm0,(%rsp)
L19:
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0xf423f,%edi
  add    $0x1,%ebx
  call   <usleep@plt>
L9:
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm4
  cvtsi2sd %ebx,%xmm0
  comisd %xmm0,%xmm4
  ja     L23
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm4,%xmm0
  mulsd  D1(%rip),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  cvttsd2si %xmm0,%edi
  jmp    1050 <usleep@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D30
data_type: byte[8]
name: disassemble_data
arguments: tag: D11
data_type: byte[8]
name: disassemble_data
arguments: tag: D19
data_type: byte[8]
name: disassemble_data
arguments: tag: D1
data_type: byte[8]

tool: {"D30": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
void sleep_sec(double sec) {
  int i;
  for (i = 0; i < floor(sec); ++i) {
    usleep(999999);
  }
  usleep(1000000 * (sec - floor(sec)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strncpy(char *dest, char *src, int n) {
  int i;
  i = 0;
  while (src[i] && i < n) {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strncpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%r8d
  test   %edx,%edx
  jle    L5
  test   %r8b,%r8b
  je     L5
  mov    $0x0,%ecx
L36:
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %ecx,%edx
  jle    L6
  test   %r8b,%r8b
  jne    L36
L6:
  movb   $0x0,(%rax,%rcx,1)
  ret
L5:
  mov    $0x0,%ecx
  jmp    L6
```

assistant: ```c
char *my_strncpy(char *dest, char *src, int n) {
  int i;
  i = 0;
  while (src[i] && i < n) {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<my_strncpy>:
  endbr64
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L1
  test   %r8b,%r8b
  je     L1
  xor    %ecx,%ecx
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L30:
  test   %r8b,%r8b
  je     L37
L44:
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %ecx,%edx
  jg     L30
L37:
  add    %rax,%rcx
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L1:
  mov    %rax,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *my_strncpy(char *dest, char *src, int n) {
  int i;
  i = 0;
  while (src[i] && i < n) {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_strncpy>:
  endbr64
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L2
  test   %r8b,%r8b
  je     L2
  xor    %ecx,%ecx
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L1:
  test   %r8b,%r8b
  je     L29
L49:
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  movzbl (%rsi,%rcx,1),%r8d
  cmp    %ecx,%edx
  jg     L1
L29:
  add    %rax,%rcx
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L2:
  mov    %rax,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *my_strncpy(char *dest, char *src, int n) {
  int i;
  i = 0;
  while (src[i] && i < n) {
    dest[i] = src[i];
    i++;
  }
  dest[i] = '\0';
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L28
L33:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  jmp    L39
L6:
  addq   $0x1,-0x18(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t len = strlen(needle);
  for (; *haystack; haystack++) {
    if (memcmp(haystack, needle, len) == 0)
      return ((char *)haystack);
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  cmpb   $0x0,(%rbx)
  je     L36
L17:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L11
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
  mov    $0x0,%eax
  jmp    L38
L36:
  mov    $0x0,%eax
  jmp    L38
L11:
  mov    %rbx,%rax
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t len = strlen(needle);
  for (; *haystack; haystack++) {
    if (memcmp(haystack, needle, len) == 0)
      return ((char *)haystack);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L17
  mov    %rax,%r12
  jmp    L35
L6:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L17
L35:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t len = strlen(needle);
  for (; *haystack; haystack++) {
    if (memcmp(haystack, needle, len) == 0)
      return ((char *)haystack);
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L21
  mov    %rax,%r12
  jmp    L33
L28:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  je     L21
L33:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  size_t len = strlen(needle);
  for (; *haystack; haystack++) {
    if (memcmp(haystack, needle, len) == 0)
      return ((char *)haystack);
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reduce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L43
L24:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L43
  mov    $0x0,%eax
  jmp    L39
L43:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L24
  jmp    L59
L79:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L59
  mov    $0x0,%eax
  jmp    L39
L59:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L79
  mov    $0x1,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int reduce(int *v, int *next, int mult) {
  int oldnext;
  while (*v < 0) {
    *v += mult;
    oldnext = *next;
    --*next;
    if (!(*next < oldnext))
      return 0;
  }
  while (*v >= mult) {
    *v -= mult;
    oldnext = *next;
    ++*next;
    if (!(*next > oldnext))
      return 0;
  }
  return 1;
}
```