ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<doWebStart>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  lea    D3(%rip),%rax
  movq   %rcx,%xmm0
  mov    %rsp,%rdi
  movq   $0x0,0x10(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <runCmd@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D7: /etc/init.d/bitmeterweb

tool: D3: start

assistant: ```c
int doWebStart(FILE *file, int argc, char **argv) {
  const char *args[] = {"/etc/init.d/bitmeterweb", "start", 0};
  return runCmd(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vga_crt_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x3d4,%edi
  call   <out@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x3d5,%edi
  call   <out@plt>
  nop
  leave
  ret
```

assistant: ```c
void vga_crt_out(int index, int data) {
  out(0x03D4, index);
  out(0x03D5, data);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vga_crt_out>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  mov    $0x3d4,%edi
  call   <out@plt>
  mov    %ebx,%esi
  mov    $0x3d5,%edi
  call   <out@plt>
  pop    %rbx
  ret
```

assistant: ```c
void vga_crt_out(int index, int data) {
  out(0x03D4, index);
  out(0x03D5, data);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vga_crt_out>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x3d4,%edi
  call   <out@plt>
  mov    %ebp,%esi
  mov    $0x3d5,%edi
  pop    %rbp
  jmp    1050 <out@plt>
```

assistant: ```c
void vga_crt_out(int index, int data) {
  out(0x03D4, index);
  out(0x03D5, data);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vga_crt_out>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  mov    $0x3d4,%edi
  call   <out@plt>
  mov    %ebp,%esi
  mov    $0x3d5,%edi
  pop    %rbp
  jmp    1050 <out@plt>
```

assistant: ```c
void vga_crt_out(int index, int data) {
  out(0x03D4, index);
  out(0x03D5, data);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_reject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <revert@plt>
  nop
  leave
  ret
```

assistant: ```c
void update_reject(design, iteration, which1, which2, current_eval) struct Design *design;
int iteration, which1, which2;
double current_eval;
{
  void revert(), write_step();
  revert(design, which1, which2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<update_reject>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    $0x0,%eax
  call   <revert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void update_reject(design, iteration, which1, which2, current_eval) struct Design *design;
int iteration, which1, which2;
double current_eval;
{
  void revert(), write_step();
  revert(design, which1, which2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<update_reject>:
  endbr64
  mov    %edx,%esi
  xor    %eax,%eax
  mov    %ecx,%edx
  jmp    1050 <revert@plt>
```

assistant: ```c
void update_reject(design, iteration, which1, which2, current_eval) struct Design *design;
int iteration, which1, which2;
double current_eval;
{
  void revert(), write_step();
  revert(design, which1, which2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<update_reject>:
  endbr64
  mov    %edx,%esi
  xor    %eax,%eax
  mov    %ecx,%edx
  jmp    1050 <revert@plt>
```

assistant: ```c
void update_reject(design, iteration, which1, which2, current_eval) struct Design *design;
int iteration, which1, which2;
double current_eval;
{
  void revert(), write_step();
  revert(design, which1, which2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_out_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0x0,-0x4(%rbp)
  je     L6
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void _out_char(char character, void *buffer, size_t idx, size_t maxlen) {
  (void)buffer;
  (void)idx;
  (void)maxlen;
  if (character) {
    putchar(character);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_out_char>:
  endbr64
  test   %dil,%dil
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _out_char(char character, void *buffer, size_t idx, size_t maxlen) {
  (void)buffer;
  (void)idx;
  (void)maxlen;
  if (character) {
    putchar(character);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_out_char>:
  endbr64
  test   %dil,%dil
  jne    L7
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movsbl %dil,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void _out_char(char character, void *buffer, size_t idx, size_t maxlen) {
  (void)buffer;
  (void)idx;
  (void)maxlen;
  if (character) {
    putchar(character);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_out_char>:
  endbr64
  test   %dil,%dil
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movsbl %dil,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void _out_char(char character, void *buffer, size_t idx, size_t maxlen) {
  (void)buffer;
  (void)idx;
  (void)maxlen;
  if (character) {
    putchar(character);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<display_cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <display_gpio_cleanup@plt>
  mov    $0x0,%eax
  call   <display_fpga_cleanup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display_cleanup(void) {
  display_gpio_cleanup();
  display_fpga_cleanup();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<display_cleanup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <display_gpio_cleanup@plt>
  mov    $0x0,%eax
  call   <display_fpga_cleanup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display_cleanup(void) {
  display_gpio_cleanup();
  display_fpga_cleanup();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display_cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <display_gpio_cleanup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <display_fpga_cleanup@plt>
```

assistant: ```c
void display_cleanup(void) {
  display_gpio_cleanup();
  display_fpga_cleanup();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<display_cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <display_gpio_cleanup@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <display_fpga_cleanup@plt>
```

assistant: ```c
void display_cleanup(void) {
  display_gpio_cleanup();
  display_fpga_cleanup();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quickSort>:
  endbr64
  cmp    $0x1,%edi
  jle    L106
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%r8d
  movslq %r8d,%rax
  lea    (%rsi,%rax,4),%r9
  mov    $0x1,%edi
  jmp    L85
L112:
  cmp    %edi,%ebx
  je     L26
  mov    %r10d,(%rsi)
  mov    %edx,0x0(%r13)
L27:
  sub    $0x4,%r9
  sub    $0x1,%r8d
L85:
  mov    %r8d,%ebx
  mov    %r9,%r13
  mov    (%r9),%r10d
  mov    0x0(%rbp),%ecx
  cmp    %r8d,%edi
  setl   %r11b
  cmp    %ecx,%r10d
  jle    L89
  test   %r11b,%r11b
  jne    L27
L89:
  movslq %edi,%rax
  shl    $0x2,%rax
  lea    0x0(%rbp,%rax,1),%rsi
  mov    (%rsi),%edx
  cmp    %edx,%ecx
  jl     L112
  test   %r11b,%r11b
  je     L112
  lea    0x4(%rbp,%rax,1),%rax
L77:
  add    $0x1,%edi
  mov    %rax,%rsi
  mov    (%rax),%edx
  add    $0x4,%rax
  cmp    %edi,%ebx
  jle    L112
  cmp    %edx,%ecx
  jge    L77
  jmp    L112
L26:
  cmp    %edx,%ecx
  jle    L23
  mov    %ecx,(%rsi)
  mov    %edx,0x0(%rbp)
  add    $0x1,%ebx
L23:
  cmp    $0x1,%edi
  jg     L52
L115:
  sub    %ebx,%r12d
  cmp    $0x1,%r12d
  jg     L129
L62:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  mov    %rbp,%rsi
  call   <quickSort>
  jmp    L115
L129:
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r12d,%edi
  call   <quickSort>
  jmp    L62
L106:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int quickSort(int arrayLength, int *pArray) {
  int i = 1, j = arrayLength - 1;
  int tempValue;
  if (arrayLength <= 1)
    return 0;
  while (true) {
    while ((pArray[j] > pArray[0]) && (i < j))
      j--;
    while ((pArray[i] <= pArray[0]) && (i < j))
      i++;
    if (i == j)
      break;
    tempValue = pArray[i];
    pArray[i] = pArray[j];
    pArray[j] = tempValue;
    j--;
  }
  if (pArray[0] > pArray[i]) {
    tempValue = pArray[i];
    pArray[i] = pArray[0];
    pArray[0] = tempValue;
    j++;
  }
  if (i > 1)
    quickSort(i, pArray);
  if (arrayLength - j > 1)
    quickSort(arrayLength - j, &(pArray[j]));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quickSort>:
  endbr64
  cmp    $0x1,%edi
  jle    L66
  lea    -0x1(%rdi),%ecx
  push   %r14
  movslq %ecx,%rax
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    (%rsi,%rax,4),%r9
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%r8d
  jmp    L118
  nopl   0x0(%rax)
L28:
  test   %r11b,%r11b
  jne    L128
L102:
  cmp    %edi,%ecx
  je     L72
L22:
  mov    %r10d,(%rsi)
  movslq %edi,%r13
  mov    %edx,(%r9)
  mov    (%rbx),%r8d
L128:
  sub    $0x4,%r9
  sub    $0x1,%ecx
L118:
  lea    0x0(,%r13,4),%rax
  cmp    %ecx,%edi
  mov    (%r9),%r10d
  mov    %ecx,%r12d
  lea    (%rbx,%rax,1),%rsi
  setl   %r11b
  mov    (%rsi),%edx
  cmp    %edx,%r8d
  setge  %r14b
  cmp    %r8d,%r10d
  jg     L28
  test   %r11b,%r11b
  je     L102
  test   %r14b,%r14b
  je     L102
  lea    0x4(%rbx,%rax,1),%rax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    %edx,%r8d
  jl     L102
L9:
  add    $0x1,%edi
  mov    (%rax),%edx
  mov    %rax,%rsi
  add    $0x4,%rax
  cmp    %edi,%ecx
  jg     L12
  cmp    %edi,%ecx
  jne    L22
L72:
  cmp    %edx,%r8d
  jle    L105
  mov    %r8d,(%rsi)
  lea    0x1(%rdi),%r12d
  mov    %edx,(%rbx)
L105:
  cmp    $0x1,%edi
  jg     L142
  sub    %r12d,%ebp
  cmp    $0x1,%ebp
  jg     L148
L81:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L148:
  movslq %r12d,%r12
  mov    %ebp,%edi
  lea    (%rbx,%r12,4),%rsi
  call   <quickSort>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L142:
  mov    %rbx,%rsi
  sub    %r12d,%ebp
  call   <quickSort>
  cmp    $0x1,%ebp
  jle    L81
  jmp    L148
L66:
  xor    %eax,%eax
  ret
```

assistant: ```c
int quickSort(int arrayLength, int *pArray) {
  int i = 1, j = arrayLength - 1;
  int tempValue;
  if (arrayLength <= 1)
    return 0;
  while (true) {
    while ((pArray[j] > pArray[0]) && (i < j))
      j--;
    while ((pArray[i] <= pArray[0]) && (i < j))
      i++;
    if (i == j)
      break;
    tempValue = pArray[i];
    pArray[i] = pArray[j];
    pArray[j] = tempValue;
    j--;
  }
  if (pArray[0] > pArray[i]) {
    tempValue = pArray[i];
    pArray[i] = pArray[0];
    pArray[0] = tempValue;
    j++;
  }
  if (i > 1)
    quickSort(i, pArray);
  if (arrayLength - j > 1)
    quickSort(arrayLength - j, &(pArray[j]));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quickSort>:
  endbr64
  cmp    $0x1,%edi
  jle    L109
  lea    -0x1(%rdi),%ecx
  push   %r14
  movslq %ecx,%rax
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    (%rsi,%rax,4),%r9
  push   %rbp
  mov    %edi,%ebp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%r8d
  jmp    L85
  nopl   0x0(%rax)
L121:
  test   %r11b,%r11b
  jne    L45
L7:
  cmp    %edi,%ecx
  je     L20
L116:
  mov    %r10d,(%rsi)
  movslq %edi,%r13
  mov    %edx,(%r9)
  mov    (%rbx),%r8d
L45:
  sub    $0x4,%r9
  sub    $0x1,%ecx
L85:
  lea    0x0(,%r13,4),%rax
  cmp    %ecx,%edi
  mov    (%r9),%r10d
  mov    %ecx,%r12d
  lea    (%rbx,%rax,1),%rsi
  setl   %r11b
  mov    (%rsi),%edx
  cmp    %edx,%r8d
  setge  %r14b
  cmp    %r8d,%r10d
  jg     L121
  test   %r11b,%r11b
  je     L7
  test   %r14b,%r14b
  je     L7
  lea    0x4(%rbx,%rax,1),%rax
  jmp    L119
  nopl   0x0(%rax,%rax,1)
L71:
  cmp    %edx,%r8d
  jl     L7
L119:
  add    $0x1,%edi
  mov    (%rax),%edx
  mov    %rax,%rsi
  add    $0x4,%rax
  cmp    %edi,%ecx
  jg     L71
  cmp    %edi,%ecx
  jne    L116
L20:
  cmp    %edx,%r8d
  jle    L140
  mov    %r8d,(%rsi)
  lea    0x1(%rdi),%r12d
  mov    %edx,(%rbx)
L140:
  cmp    $0x1,%edi
  jg     L72
  sub    %r12d,%ebp
  cmp    $0x1,%ebp
  jg     L108
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L108:
  movslq %r12d,%r12
  mov    %ebp,%edi
  lea    (%rbx,%r12,4),%rsi
  call   <quickSort>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L72:
  mov    %rbx,%rsi
  sub    %r12d,%ebp
  call   <quickSort>
  cmp    $0x1,%ebp
  jle    L22
  jmp    L108
L109:
  xor    %eax,%eax
  ret
```

assistant: ```c
int quickSort(int arrayLength, int *pArray) {
  int i = 1, j = arrayLength - 1;
  int tempValue;
  if (arrayLength <= 1)
    return 0;
  while (true) {
    while ((pArray[j] > pArray[0]) && (i < j))
      j--;
    while ((pArray[i] <= pArray[0]) && (i < j))
      i++;
    if (i == j)
      break;
    tempValue = pArray[i];
    pArray[i] = pArray[j];
    pArray[j] = tempValue;
    j--;
  }
  if (pArray[0] > pArray[i]) {
    tempValue = pArray[i];
    pArray[i] = pArray[0];
    pArray[0] = tempValue;
    j++;
  }
  if (i > 1)
    quickSort(i, pArray);
  if (arrayLength - j > 1)
    quickSort(arrayLength - j, &(pArray[j]));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<readyAlways>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <file_isreg@plt>
  test   %rax,%rax
  je     L31
  mov    $0x1,%eax
  jmp    L26
L31:
  mov    $0x0,%eax
  call   <FS_maybeUnix@plt>
  test   %eax,%eax
  jne    L46
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <file_isselectable@plt>
  test   %eax,%eax
  jne    L46
  mov    $0x1,%eax
  jmp    L26
L46:
  mov    $0x0,%eax
L26:
  leave
  ret
```

assistant: ```c
int readyAlways(int fd) {
  if (file_isreg(fd))
    return 1;
  if (!FS_maybeUnix() && !file_isselectable(fd))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readyAlways>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <file_isreg@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L12
L1:
  pop    %rbx
  ret
L12:
  mov    $0x0,%eax
  call   <FS_maybeUnix@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L1
  mov    %ebx,%edi
  call   <file_isselectable@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L1
```

assistant: ```c
int readyAlways(int fd) {
  if (file_isreg(fd))
    return 1;
  if (!FS_maybeUnix() && !file_isselectable(fd))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<readyAlways>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <file_isreg@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L14
L9:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <FS_maybeUnix@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L9
  mov    %ebp,%edi
  call   <file_isselectable@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int readyAlways(int fd) {
  if (file_isreg(fd))
    return 1;
  if (!FS_maybeUnix() && !file_isselectable(fd))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readyAlways>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <file_isreg@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L15
L8:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  call   <FS_maybeUnix@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L8
  mov    %ebp,%edi
  call   <file_isselectable@plt>
  pop    %rbp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int readyAlways(int fd) {
  if (file_isreg(fd))
    return 1;
  if (!FS_maybeUnix() && !file_isselectable(fd))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L28:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L66
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L9
L66:
  movl   $0x2,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L64
L79:
  pxor   %xmm1,%xmm1
  cvtss2sd -0xc(%rbp),%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x10(%rbp),%xmm2
  movsd  D12(%rip),%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L64:
  movss  -0x14(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jae    L79
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L28
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L45
  jmp    L28
L9:
  nop
L45:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D12
type: f64
name: unpack_data
arguments: data_tag: D18
type: string

tool: D16: %f

tool: D12: 1

tool: D18: %d card(s)


assistant: ```c
int main() {
  float in;
  do {
    scanf("%f", &in);
    if (in == 0)
      break;
    int n = 2;
    float sum = 0.00;
    while (sum <= in) {
      sum += (1.00 / n);
      n++;
    }
    printf("%d card(s)\n", (n - 2));
  } while (in != 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rbx
  jmp    L80
L17:
  mov    $0x2,%esi
L11:
  sub    $0x2,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  ucomiss 0x4(%rsp),%xmm0
  jp     L80
  je     L36
L80:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm3
  pxor   %xmm5,%xmm5
  ucomiss %xmm5,%xmm3
  jp     L86
  je     L36
L86:
  pxor   %xmm0,%xmm0
  mov    $0x2,%esi
  movsd  D25(%rip),%xmm4
  comiss %xmm0,%xmm3
  jb     L17
L13:
  pxor   %xmm2,%xmm2
  cvtsi2sd %esi,%xmm2
  movapd %xmm4,%xmm1
  divsd  %xmm2,%xmm1
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  add    $0x1,%esi
  comiss %xmm0,%xmm3
  jae    L13
  jmp    L11
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D25
type: f64

tool: D8: %f

tool: D0: %d card(s)


tool: D25: 1

assistant: ```c
int main() {
  float in;
  do {
    scanf("%f", &in);
    if (in == 0)
      break;
    int n = 2;
    float sum = 0.00;
    while (sum <= in) {
      sum += (1.00 / n);
      n++;
    }
    printf("%d card(s)\n", (n - 2));
  } while (in != 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L13:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm3
  pxor   %xmm5,%xmm5
  mov    D11(%rip),%rax
  ucomiss %xmm5,%xmm3
  movq   %rax,%xmm4
  jp     L41
  je     L6
L41:
  pxor   %xmm6,%xmm6
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  comiss %xmm6,%xmm3
  jb     L75
  nopw   0x0(%rax,%rax,1)
L8:
  pxor   %xmm2,%xmm2
  movapd %xmm4,%xmm1
  cvtss2sd %xmm0,%xmm0
  mov    %eax,%esi
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm3
  jae    L8
  sub    $0x1,%esi
L59:
  mov    %r12,%rdi
  call   <printf@plt>
  pxor   %xmm7,%xmm7
  ucomiss 0x4(%rsp),%xmm7
  jp     L13
  jne    L13
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L75:
  xor    %esi,%esi
  jmp    L59
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D11
type: f64

tool: D13: %d card(s)


tool: D7: %f

tool: D11: 1

assistant: ```c
int main() {
  float in;
  do {
    scanf("%f", &in);
    if (in == 0)
      break;
    int n = 2;
    float sum = 0.00;
    while (sum <= in) {
      sum += (1.00 / n);
      n++;
    }
    printf("%d card(s)\n", (n - 2));
  } while (in != 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nop
L16:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm3
  pxor   %xmm5,%xmm5
  mov    D26(%rip),%rax
  ucomiss %xmm5,%xmm3
  movq   %rax,%xmm4
  jp     L75
  je     L48
L75:
  pxor   %xmm6,%xmm6
  pxor   %xmm0,%xmm0
  mov    $0x2,%eax
  comiss %xmm6,%xmm3
  jb     L36
  nopw   0x0(%rax,%rax,1)
L44:
  pxor   %xmm2,%xmm2
  movapd %xmm4,%xmm1
  cvtss2sd %xmm0,%xmm0
  mov    %eax,%esi
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm3
  jae    L44
  sub    $0x1,%esi
L39:
  mov    %r12,%rdi
  call   <printf@plt>
  pxor   %xmm7,%xmm7
  ucomiss 0x4(%rsp),%xmm7
  jp     L16
  jne    L16
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L36:
  xor    %esi,%esi
  jmp    L39
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
data_type: string
name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D26
data_type: f64

tool: D23: %d card(s)


tool: D24: %f

tool: D26: 1

assistant: ```c
int main() {
  float in;
  do {
    scanf("%f", &in);
    if (in == 0)
      break;
    int n = 2;
    float sum = 0.00;
    while (sum <= in) {
      sum += (1.00 / n);
      n++;
    }
    printf("%d card(s)\n", (n - 2));
  } while (in != 0);
  return 0;
}
```