ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<get_num_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  jne    L12
  mov    $0x1,%eax
  jmp    L33
L12:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L17
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x1,%eax
  jmp    L33
L17:
  mov    $0x0,%eax
L33:
  leave
  ret
```

assistant: ```c
unsigned int get_num_digits(double i) {
  if ((int)i == 0)
    return (1);
  double logvalue = log10(i);
  return (logvalue >= 0 ? (unsigned int)logvalue + 1 : 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L2:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  ja     L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int clog2(size_t x) {
  unsigned int i;
  for (i = 0; ((size_t)1 << i) < x; i++)
    ;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clog2>:
  endbr64
  cmp    $0x1,%rdi
  jbe    L3
  mov    $0x0,%ecx
  mov    $0x1,%edx
L2:
  add    $0x1,%ecx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rdi,%rax
  jb     L2
L18:
  mov    %ecx,%eax
  ret
L3:
  mov    $0x0,%ecx
  jmp    L18
```

assistant: ```c
unsigned int clog2(size_t x) {
  unsigned int i;
  for (i = 0; ((size_t)1 << i) < x; i++)
    ;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<clog2>:
  endbr64
  xor    %ecx,%ecx
  cmp    $0x1,%rdi
  jbe    L9
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  add    $0x1,%ecx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rdi,%rax
  jb     L4
L9:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int clog2(size_t x) {
  unsigned int i;
  for (i = 0; ((size_t)1 << i) < x; i++)
    ;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clog2>:
  endbr64
  xor    %ecx,%ecx
  cmp    $0x1,%rdi
  jbe    L6
  mov    $0x1,%edx
  nopl   0x0(%rax)
L9:
  add    $0x1,%ecx
  mov    %rdx,%rax
  shl    %cl,%rax
  cmp    %rdi,%rax
  jb     L9
L6:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int clog2(size_t x) {
  unsigned int i;
  for (i = 0; ((size_t)1 << i) < x; i++)
    ;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x24(%rbp)
  jg     L27
  mov    $0x1,%eax
  jmp    L10
L27:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    D16(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L40
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
L40:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D16: %m[0-9]%n

tool: D11: %d: not matched


tool: D2: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, n;
  char *s;
  if (argc < 2)
    return 1;
  n = sscanf(argv[1], "%m[0-9]%n", &s, &i);
  if (n != 1)
    printf("%d: not matched\n", n);
  else {
    printf("%d\n", i);
    printf("%s\n", s);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L8
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D15(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L14
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  ret
L14:
  mov    0xc(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L8
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D15: %m[0-9]%n

tool: D7: %d: not matched


tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, n;
  char *s;
  if (argc < 2)
    return 1;
  n = sscanf(argv[1], "%m[0-9]%n", &s, &i);
  if (n != 1)
    printf("%d: not matched\n", n);
  else {
    printf("%d\n", i);
    printf("%s\n", s);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L15
  mov    0x8(%rsi),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D26(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  je     L0
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L0:
  mov    0xc(%rsp),%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D26: %m[0-9]%n

tool: D23: %d: not matched


tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, n;
  char *s;
  if (argc < 2)
    return 1;
  n = sscanf(argv[1], "%m[0-9]%n", &s, &i);
  if (n != 1)
    printf("%d: not matched\n", n);
  else {
    printf("%d\n", i);
    printf("%s\n", s);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L2
  mov    0x8(%rsi),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D10(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  je     L10
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  ret
L10:
  mov    0xc(%rsp),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L2
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D10: %m[0-9]%n

tool: D3: %d: not matched


tool: D19: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, n;
  char *s;
  if (argc < 2)
    return 1;
  n = sscanf(argv[1], "%m[0-9]%n", &s, &i);
  if (n != 1)
    printf("%d: not matched\n", n);
  else {
    printf("%d\n", i);
    printf("%s\n", s);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xd,-0x4(%rbp)
  jg     L6
  cmpl   $0x9,-0x4(%rbp)
  jge    L45
  jmp    L19
L6:
  cmpl   $0x20,-0x4(%rbp)
  jne    L19
L45:
  mov    $0x1,%eax
  jmp    L49
L19:
  mov    $0x0,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int isspace(int character) {
  switch (character) {
  case ' ':
  case '\f':
  case '\n':
  case '\r':
  case '\t':
  case '\v':
    return 1;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isspace>:
  endbr64
  cmp    $0xd,%edi
  jg     L9
  cmp    $0x8,%edi
  setg   %al
  movzbl %al,%eax
  ret
L9:
  cmp    $0x20,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isspace(int character) {
  switch (character) {
  case ' ':
  case '\f':
  case '\n':
  case '\r':
  case '\t':
  case '\v':
    return 1;
  default:
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<isspace>:
  endbr64
  cmp    $0xd,%edi
  jg     L7
  xor    %eax,%eax
  cmp    $0x8,%edi
  setg   %al
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  cmp    $0x20,%edi
  sete   %al
  ret
```

assistant: ```c
int isspace(int character) {
  switch (character) {
  case ' ':
  case '\f':
  case '\n':
  case '\r':
  case '\t':
  case '\v':
    return 1;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isspace>:
  endbr64
  cmp    $0xd,%edi
  jg     L9
  xor    %eax,%eax
  cmp    $0x8,%edi
  setg   %al
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  cmp    $0x20,%edi
  sete   %al
  ret
```

assistant: ```c
int isspace(int character) {
  switch (character) {
  case ' ':
  case '\f':
  case '\n':
  case '\r':
  case '\t':
  case '\v':
    return 1;
  default:
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L16
  mov    $0x0,%eax
  jmp    L4
L16:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L28
  mov    $0x1,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int equal(int *a, int *b, int size) {
  for (int i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<equal>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  jne    L9
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
  mov    $0x1,%eax
  ret
L17:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int equal(int *a, int *b, int size) {
  for (int i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<equal>:
  endbr64
  test   %edx,%edx
  jle    L37
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L13
  nop
L18:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L37
L13:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal(int *a, int *b, int size) {
  for (int i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<equal>:
  endbr64
  test   %edx,%edx
  jle    L25
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L35
  nop
L21:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L35:
  mov    (%rsi,%rax,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  je     L21
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int equal(int *a, int *b, int size) {
  for (int i = 0; i < size; i++) {
    if (a[i] != b[i])
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<IsIRCNickPrefixMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  je     L141
  cmpq   $0x0,-0x28(%rbp)
  je     L141
  cmpq   $0x0,-0x20(%rbp)
  jne    L36
L141:
  mov    $0x0,%eax
  jmp    L106
L36:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  je     L75
  mov    $0x0,%eax
  jmp    L106
L75:
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L114
  mov    $0x0,%eax
  jmp    L106
L114:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L100
L102:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  je     L154
  addq   $0x1,-0x10(%rbp)
L100:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L102
  jmp    L137
L154:
  nop
L137:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L61
  mov    $0x0,%eax
  jmp    L106
L61:
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %al,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movzbl -0x14(%rbp),%edx
  cmp    %dl,%al
  ja     L49
  mov    $0x0,%eax
  jmp    L106
L49:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
L106:
  leave
  ret
```

assistant: ```c
int IsIRCNickPrefixMode(char cMode, char *pcPrefix, const char *strPrefix) {
  const char *strEnd, *strMode;
  ;
  ;
  ;
  if (!cMode || !strPrefix || !pcPrefix)
    return 0;
  if (*strPrefix != '(')
    return 0;
  strPrefix++;
  strEnd = strchr(strPrefix, ')');
  if (!strEnd)
    return 0;
  for (strMode = strPrefix; strMode < strEnd; strMode++)
    if (*strMode == cMode)
      break;
  if (strMode >= strEnd)
    return 0;
  strEnd++;
  cMode = strMode - strPrefix;
  if ((unsigned char)cMode >= strlen(strEnd))
    return 0;
  *pcPrefix = strEnd[(unsigned int)cMode];
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IsIRCNickPrefixMode>:
  endbr64
  test   %rdx,%rdx
  sete   %al
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%al
  jne    L107
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edi,%ebx
  mov    $0x0,%eax
  test   %dil,%dil
  je     L133
  mov    $0x0,%eax
  cmpb   $0x28,(%rdx)
  je     L22
L133:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  lea    0x1(%rdx),%r12
  mov    $0x29,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L47
  cmp    %rax,%r12
  jae    L2
  mov    %r12,%rax
L115:
  cmp    %bl,(%rax)
  je     L9
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L115
  mov    $0x0,%eax
  jmp    L133
L9:
  cmp    %rax,%r13
  jbe    L7
  lea    0x1(%r13),%rdi
  sub    %r12,%rax
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %bl,%dl
  jbe    L133
  movsbl %bl,%eax
  movzbl 0x1(%rax,%r13,1),%eax
  mov    %al,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L133
L47:
  mov    $0x0,%eax
  jmp    L133
L2:
  mov    $0x0,%eax
  jmp    L133
L7:
  mov    $0x0,%eax
  jmp    L133
L107:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int IsIRCNickPrefixMode(char cMode, char *pcPrefix, const char *strPrefix) {
  const char *strEnd, *strMode;
  ;
  ;
  ;
  if (!cMode || !strPrefix || !pcPrefix)
    return 0;
  if (*strPrefix != '(')
    return 0;
  strPrefix++;
  strEnd = strchr(strPrefix, ')');
  if (!strEnd)
    return 0;
  for (strMode = strPrefix; strMode < strEnd; strMode++)
    if (*strMode == cMode)
      break;
  if (strMode >= strEnd)
    return 0;
  strEnd++;
  cMode = strMode - strPrefix;
  if ((unsigned char)cMode >= strlen(strEnd))
    return 0;
  *pcPrefix = strEnd[(unsigned int)cMode];
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IsIRCNickPrefixMode>:
  endbr64
  test   %rdx,%rdx
  sete   %al
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%al
  jne    L15
  test   %dil,%dil
  je     L15
  cmpb   $0x28,(%rdx)
  je     L34
L15:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L34:
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x29,%esi
  push   %rbp
  lea    0x1(%rdx),%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L63
  cmp    %rax,%rbp
  jae    L63
  mov    %rbp,%rax
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rax
  cmp    %rax,%r13
  je     L63
L72:
  cmp    %bl,(%rax)
  jne    L26
  cmp    %rax,%r13
  jbe    L63
  sub    %rbp,%rax
  lea    0x1(%r13),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %bl,%al
  jbe    L63
  movsbl %bl,%eax
  movzbl 0x1(%rax,%r13,1),%eax
  mov    %al,(%r12)
  mov    $0x1,%eax
  jmp    L14
  nopl   0x0(%rax)
L63:
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int IsIRCNickPrefixMode(char cMode, char *pcPrefix, const char *strPrefix) {
  const char *strEnd, *strMode;
  ;
  ;
  ;
  if (!cMode || !strPrefix || !pcPrefix)
    return 0;
  if (*strPrefix != '(')
    return 0;
  strPrefix++;
  strEnd = strchr(strPrefix, ')');
  if (!strEnd)
    return 0;
  for (strMode = strPrefix; strMode < strEnd; strMode++)
    if (*strMode == cMode)
      break;
  if (strMode >= strEnd)
    return 0;
  strEnd++;
  cMode = strMode - strPrefix;
  if ((unsigned char)cMode >= strlen(strEnd))
    return 0;
  *pcPrefix = strEnd[(unsigned int)cMode];
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IsIRCNickPrefixMode>:
  endbr64
  test   %rdx,%rdx
  sete   %al
  test   %rsi,%rsi
  sete   %cl
  or     %cl,%al
  jne    L84
  test   %dil,%dil
  je     L84
  cmpb   $0x28,(%rdx)
  je     L60
L84:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L60:
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x29,%esi
  push   %rbp
  lea    0x1(%rdx),%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L65
  cmp    %rax,%rbp
  jae    L65
  mov    %rbp,%rax
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L89:
  add    $0x1,%rax
  cmp    %rax,%r13
  je     L65
L68:
  cmp    %bl,(%rax)
  jne    L89
  cmp    %rax,%r13
  jbe    L65
  sub    %rbp,%rax
  lea    0x1(%r13),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %bl,%al
  jbe    L65
  movsbl %bl,%eax
  movzbl 0x1(%rax,%r13,1),%eax
  mov    %al,(%r12)
  mov    $0x1,%eax
  jmp    L31
  nopl   0x0(%rax)
L65:
  xor    %eax,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int IsIRCNickPrefixMode(char cMode, char *pcPrefix, const char *strPrefix) {
  const char *strEnd, *strMode;
  ;
  ;
  ;
  if (!cMode || !strPrefix || !pcPrefix)
    return 0;
  if (*strPrefix != '(')
    return 0;
  strPrefix++;
  strEnd = strchr(strPrefix, ')');
  if (!strEnd)
    return 0;
  for (strMode = strPrefix; strMode < strEnd; strMode++)
    if (*strMode == cMode)
      break;
  if (strMode >= strEnd)
    return 0;
  strEnd++;
  cMode = strMode - strPrefix;
  if ((unsigned char)cMode >= strlen(strEnd))
    return 0;
  *pcPrefix = strEnd[(unsigned int)cMode];
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rndTwoDecimals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm1
  movsd  D23(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  D23(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string

tool: D23: 100

tool: D10: 0.5

tool: D22: 
The rounded number is: %lf



assistant: ```c
void rndTwoDecimals(double a) {
  double num1;
  int num2;
  double num3;
  num1 = a * 100;
  num2 = floor((num1) + 0.5);
  num3 = num2 / 100.0;
  printf("\nThe rounded number is: %lf\n\n", num3);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<rndTwoDecimals>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D3(%rip),%xmm0
  addsd  D35(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D3(%rip),%xmm0
  lea    D20(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: f64
name: read_data
arguments: data_label: D35
datatype: f64
name: read_data
arguments: data_label: D20
datatype: string

tool: D3: 100

tool: D35: 0.5

tool: D20: 
The rounded number is: %lf



assistant: ```c
void rndTwoDecimals(double a) {
  double num1;
  int num2;
  double num3;
  num1 = a * 100;
  num2 = floor((num1) + 0.5);
  num3 = num2 / 100.0;
  printf("\nThe rounded number is: %lf\n\n", num3);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rndTwoDecimals>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D27(%rip),%xmm0
  addsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  lea    D18(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  divsd  D27(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type: f64
name: unpack_data
arguments: label: D8
type: f64
name: unpack_data
arguments: label: D18
type: string

tool: D27: 100

tool: D8: 0.5

tool: D18: 
The rounded number is: %lf



assistant: ```c
void rndTwoDecimals(double a) {
  double num1;
  int num2;
  double num3;
  num1 = a * 100;
  num2 = floor((num1) + 0.5);
  num3 = num2 / 100.0;
  printf("\nThe rounded number is: %lf\n\n", num3);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rndTwoDecimals>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D22(%rip),%xmm0
  addsd  D39(%rip),%xmm0
  cvttsd2si %xmm0,%edi
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  lea    D8(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  divsd  D22(%rip),%xmm0
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: label: D22
data_type: f64
name: unpack_data
arguments: label: D39
data_type: f64
name: unpack_data
arguments: label: D8
data_type: string

tool: D22: 100

tool: D39: 0.5

tool: D8: 
The rounded number is: %lf



assistant: ```c
void rndTwoDecimals(double a) {
  double num1;
  int num2;
  double num3;
  num1 = a * 100;
  num2 = floor((num1) + 0.5);
  num3 = num2 / 100.0;
  printf("\nThe rounded number is: %lf\n\n", num3);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bla2gt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  call   <this_comparison_is_not_decidable@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void bla2gt(int var) {
  if (var + 10 > INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bla2gt>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %edi,(%rax)
  jl     L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <this_comparison_is_not_decidable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bla2gt(int var) {
  if (var + 10 > INT_MIN + 10)
    this_comparison_is_not_decidable();
}
```