ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<od_hex_dump_ext>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rcx,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <print_u32_hex@plt>
  test   %ebx,%ebx
  mov    $0x10,%eax
  cmove  %eax,%ebx
  test   %rbp,%rbp
  je     L49
  lea    -0x1(%rbp),%rax
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  mov    %rax,0x8(%rsp)
  lea    D6(%rip),%r13
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L25:
  cmp    0x8(%rsp),%r15
  jne    L29
  mov    $0xa,%edi
  call   <putchar@plt>
L29:
  mov    %r14d,%r15d
  cmp    %rbp,%r15
  jae    L49
L20:
  mov    %r13,%rdi
  call   <print_str@plt>
  mov    (%r12,%r15,4),%edi
  call   <print_byte_hex@plt>
  mov    %r14d,%r8d
  add    $0x1,%r14d
  xor    %edx,%edx
  mov    %r14d,%eax
  div    %ebx
  test   %edx,%edx
  jne    L25
  mov    $0xa,%edi
  mov    %r8d,0x14(%rsp)
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  je     L29
  mov    0x14(%rsp),%r8d
  mov    0x18(%rsp),%rax
  mov    %r14d,%r15d
  lea    0x1(%rax,%r8,1),%rdi
  call   <print_u32_hex@plt>
  cmp    %rbp,%r15
  jb     L20
L49:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6:   

assistant: ```c
void od_hex_dump_ext(const void *data, size_t data_len, uint8_t width, uint32_t offset) {
  print_u32_hex(offset);
  if (width == 0) {
    width = (16);
  }
  for (unsigned int i = 0; i < data_len; i++) {
    print_str("  ");
    print_byte_hex(((uint8_t *)data)[i]);
    if ((((i + 1) % width) == 0) || i == (data_len - 1)) {
      putchar('\n');
      if (i != (data_len - 1)) {
        print_u32_hex((uint32_t)(offset + i + 1));
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<od_hex_dump_ext>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rcx,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <print_u32_hex@plt>
  test   %ebx,%ebx
  mov    $0x10,%eax
  cmove  %eax,%ebx
  test   %rbp,%rbp
  je     L16
  lea    -0x1(%rbp),%rax
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  mov    %rax,0x8(%rsp)
  lea    D4(%rip),%r13
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L65:
  cmp    0x8(%rsp),%r15
  jne    L36
  mov    $0xa,%edi
  call   <putchar@plt>
L36:
  mov    %r14d,%r15d
  cmp    %rbp,%r15
  jae    L16
L8:
  mov    %r13,%rdi
  call   <print_str@plt>
  mov    (%r12,%r15,4),%edi
  call   <print_byte_hex@plt>
  mov    %r14d,%r8d
  add    $0x1,%r14d
  xor    %edx,%edx
  mov    %r14d,%eax
  div    %ebx
  test   %edx,%edx
  jne    L65
  mov    $0xa,%edi
  mov    %r8d,0x14(%rsp)
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  je     L36
  mov    0x14(%rsp),%r8d
  mov    0x18(%rsp),%rax
  mov    %r14d,%r15d
  lea    0x1(%rax,%r8,1),%rdi
  call   <print_u32_hex@plt>
  cmp    %rbp,%r15
  jb     L8
L16:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string

tool: D4:   

assistant: ```c
void od_hex_dump_ext(const void *data, size_t data_len, uint8_t width, uint32_t offset) {
  print_u32_hex(offset);
  if (width == 0) {
    width = (16);
  }
  for (unsigned int i = 0; i < data_len; i++) {
    print_str("  ");
    print_byte_hex(((uint8_t *)data)[i]);
    if ((((i + 1) % width) == 0) || i == (data_len - 1)) {
      putchar('\n');
      if (i != (data_len - 1)) {
        print_u32_hex((uint32_t)(offset + i + 1));
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_array_constant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <random_pointer@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L12
L10:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void set_array_constant(void **a, uint32_t n) {
  void *p;
  uint32_t i;
  p = random_pointer();
  for (i = 0; i < n; i++) {
    a[i] = p;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_array_constant>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <random_pointer@plt>
  test   %rbx,%rbx
  je     L6
  mov    %rbp,%rdx
  lea    0x0(%rbp,%rbx,8),%rcx
L14:
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L14
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_array_constant(void **a, uint32_t n) {
  void *p;
  uint32_t i;
  p = random_pointer();
  for (i = 0; i < n; i++) {
    a[i] = p;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_array_constant>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <random_pointer@plt>
  test   %rbp,%rbp
  je     L19
  mov    %rbx,%rdi
  lea    (%rbx,%rbp,8),%rdx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rax,(%rdi)
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L5
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_array_constant(void **a, uint32_t n) {
  void *p;
  uint32_t i;
  p = random_pointer();
  for (i = 0; i < n; i++) {
    a[i] = p;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<set_array_constant>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <random_pointer@plt>
  test   %rbp,%rbp
  je     L46
  cmp    $0x1,%rbp
  je     L27
  mov    %rbp,%rcx
  movq   %rax,%xmm0
  mov    %rbx,%rdx
  shr    %rcx
  punpcklqdq %xmm0,%xmm0
  shl    $0x4,%rcx
  add    %rbx,%rcx
  nopl   0x0(%rax,%rax,1)
L30:
  movups %xmm0,(%rdx)
  add    $0x10,%rdx
  cmp    %rcx,%rdx
  jne    L30
  mov    %rbp,%rdx
  and    $0xfffffffffffffffe,%rdx
  and    $0x1,%ebp
  je     L46
L8:
  mov    %rax,(%rbx,%rdx,8)
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  xor    %edx,%edx
  jmp    L8
```

assistant: ```c
void set_array_constant(void **a, uint32_t n) {
  void *p;
  uint32_t i;
  p = random_pointer();
  for (i = 0; i < n; i++) {
    a[i] = p;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fdcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %edi,-0x824(%rbp)
  mov    %esi,-0x828(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L1
L47:
  lea    -0x810(%rbp),%rax
  mov    %rax,-0x818(%rbp)
  jmp    L51
L46:
  mov    -0x820(%rbp),%edx
  mov    -0x818(%rbp),%rcx
  mov    -0x824(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x81c(%rbp)
  cmpl   $0x0,-0x81c(%rbp)
  js     L66
  mov    -0x81c(%rbp),%eax
  cltq
  add    %rax,-0x818(%rbp)
  mov    -0x81c(%rbp),%eax
  sub    %eax,-0x820(%rbp)
L51:
  cmpl   $0x0,-0x820(%rbp)
  jg     L46
L1:
  lea    -0x810(%rbp),%rcx
  mov    -0x828(%rbp),%eax
  mov    $0x800,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x820(%rbp)
  cmpl   $0x0,-0x820(%rbp)
  jg     L47
  jmp    L63
L66:
  nop
L63:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void fdcopy(int dst, int src) {
  char buf[2048];
  int r, w;
  while ((r = read(src, buf, sizeof buf)) > 0) {
    char *p = buf;
    while (r > 0) {
      w = write(dst, p, r);
      if (w < 0)
        return;
      p += w;
      r -= w;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fdcopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
L14:
  mov    $0x800,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L27
  mov    %rsp,%rbp
L33:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  js     L27
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L33
  jmp    L14
L27:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fdcopy(int dst, int src) {
  char buf[2048];
  int r, w;
  while ((r = read(src, buf, sizeof buf)) > 0) {
    char *p = buf;
    while (r > 0) {
      w = write(dst, p, r);
      if (w < 0)
        return;
      p += w;
      r -= w;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fdcopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L21:
  mov    $0x800,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L9
  mov    %r13,%r14
  jmp    L23
  nopl   0x0(%rax)
L1:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%r14
  test   %ebx,%ebx
  jle    L21
L23:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L1
L9:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fdcopy(int dst, int src) {
  char buf[2048];
  int r, w;
  while ((r = read(src, buf, sizeof buf)) > 0) {
    char *p = buf;
    while (r > 0) {
      w = write(dst, p, r);
      if (w < 0)
        return;
      p += w;
      r -= w;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fdcopy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
L12:
  mov    $0x800,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L45
  mov    %r13,%r14
  jmp    L4
  nopl   0x0(%rax)
L19:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%r14
  test   %ebx,%ebx
  jle    L12
L4:
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L19
L45:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fdcopy(int dst, int src) {
  char buf[2048];
  int r, w;
  while ((r = read(src, buf, sizeof buf)) > 0) {
    char *p = buf;
    while (r > 0) {
      w = write(dst, p, r);
      if (w < 0)
        return;
      p += w;
      r -= w;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<checked_add_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  jns    L20
  cmpq   $0x0,-0x20(%rbp)
  jns    L20
  cmpq   $0x0,-0x8(%rbp)
  jns    L59
L20:
  cmpq   $0x0,-0x18(%rbp)
  js     L13
  cmpq   $0x0,-0x20(%rbp)
  js     L13
  cmpq   $0x0,-0x8(%rbp)
  jns    L13
L59:
  mov    $0x1,%eax
  jmp    L53
L13:
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
bool checked_add_16(int16_t a, int16_t b, int16_t *rp) {
  int16_t r = (uint16_t)a + (uint16_t)b;
  *rp = r;
  return (a < 0 && b < 0 && r >= 0) || (a >= 0 && b >= 0 && r < 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checked_add_16>:
  endbr64
  mov    %rdx,%rax
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,(%rax)
  mov    %rdi,%rax
  and    %rsi,%rax
  not    %rax
  mov    $0x1,%ecx
  or     %rdx,%rax
  jns    L6
  or     %rsi,%rdi
  not    %rdi
  and    %rdx,%rdi
  shr    $0x3f,%rdi
  mov    %rdi,%rcx
L6:
  mov    %ecx,%eax
  ret
```

assistant: ```c
bool checked_add_16(int16_t a, int16_t b, int16_t *rp) {
  int16_t r = (uint16_t)a + (uint16_t)b;
  *rp = r;
  return (a < 0 && b < 0 && r >= 0) || (a >= 0 && b >= 0 && r < 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checked_add_16>:
  endbr64
  mov    %rdx,%r8
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,(%r8)
  test   %rsi,%rdi
  jns    L8
  not    %rdx
  shr    $0x3f,%rdx
  mov    %rdx,%rax
  ret
  xchg   %ax,%ax
L8:
  mov    %rdi,%rax
  or     %rsi,%rax
  not    %rax
  and    %rdx,%rax
  shr    $0x3f,%rax
  ret
```

assistant: ```c
bool checked_add_16(int16_t a, int16_t b, int16_t *rp) {
  int16_t r = (uint16_t)a + (uint16_t)b;
  *rp = r;
  return (a < 0 && b < 0 && r >= 0) || (a >= 0 && b >= 0 && r < 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checked_add_16>:
  endbr64
  mov    %rdx,%r8
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,(%r8)
  test   %rsi,%rdi
  jns    L6
  not    %rdx
  shr    $0x3f,%rdx
  mov    %rdx,%rax
  ret
  xchg   %ax,%ax
L6:
  mov    %rdi,%rax
  or     %rsi,%rax
  not    %rax
  and    %rdx,%rax
  shr    $0x3f,%rax
  ret
```

assistant: ```c
bool checked_add_16(int16_t a, int16_t b, int16_t *rp) {
  int16_t r = (uint16_t)a + (uint16_t)b;
  *rp = r;
  return (a < 0 && b < 0 && r >= 0) || (a >= 0 && b >= 0 && r < 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UART_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400fe618,%eax
  mov    (%rax),%eax
  mov    $0x400fe618,%edx
  or     $0x1,%eax
  mov    %eax,(%rdx)
  mov    $0x400fe608,%eax
  mov    (%rax),%eax
  mov    $0x400fe608,%edx
  or     $0x1,%eax
  mov    %eax,(%rdx)
  nop
L2:
  mov    $0x400fea08,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  mov    $0x4000c030,%eax
  mov    (%rax),%eax
  mov    $0x4000c030,%edx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  mov    $0x4000c024,%eax
  movl   $0x1b,(%rax)
  mov    $0x4000c028,%eax
  movl   $0x8,(%rax)
  mov    $0x4000c02c,%eax
  movl   $0x70,(%rax)
  mov    $0x4000c030,%eax
  mov    (%rax),%eax
  mov    $0x4000c030,%edx
  or     $0x1,%eax
  mov    %eax,(%rdx)
  mov    $0x40004420,%eax
  mov    (%rax),%eax
  mov    $0x40004420,%edx
  or     $0x3,%eax
  mov    %eax,(%rdx)
  mov    $0x4000451c,%eax
  mov    (%rax),%eax
  mov    $0x4000451c,%edx
  or     $0x3,%eax
  mov    %eax,(%rdx)
  mov    $0x4000452c,%eax
  mov    (%rax),%eax
  mov    $0x0,%al
  add    $0x11,%eax
  mov    $0x4000452c,%edx
  mov    %eax,(%rdx)
  mov    $0x40004528,%eax
  mov    (%rax),%eax
  mov    $0x40004528,%edx
  and    $0xfffffffc,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UART_Init(void) {
  (*((volatile uint32_t *)0x400FE618)) |= 0x01;
  (*((volatile uint32_t *)0x400FE608)) |= 0x01;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x01) == 0) {
  };
  (*((volatile uint32_t *)0x4000C030)) &= ~0x00000001;
  (*((volatile uint32_t *)0x4000C024)) = 27;
  (*((volatile uint32_t *)0x4000C028)) = 8;
  (*((volatile uint32_t *)0x4000C02C)) = (0x00000060 | 0x00000010);
  (*((volatile uint32_t *)0x4000C030)) |= 0x00000001;
  (*((volatile uint32_t *)0x40004420)) |= 0x03;
  (*((volatile uint32_t *)0x4000451C)) |= 0x03;
  (*((volatile uint32_t *)0x4000452C)) = ((*((volatile uint32_t *)0x4000452C)) & 0xFFFFFF00) + 0x00000011;
  (*((volatile uint32_t *)0x40004528)) &= ~0x03;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UART_Init>:
  endbr64
  mov    0x400fe618,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe618
  mov    0x400fe608,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe608
L6:
  mov    0x400fea08,%eax
  test   $0x1,%al
  je     L6
  mov    0x4000c030,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x4000c030
  movl   $0x1b,0x4000c024
  movl   $0x8,0x4000c028
  movl   $0x70,0x4000c02c
  mov    0x4000c030,%eax
  or     $0x1,%eax
  mov    %eax,0x4000c030
  mov    0x40004420,%eax
  or     $0x3,%eax
  mov    %eax,0x40004420
  mov    0x4000451c,%eax
  or     $0x3,%eax
  mov    %eax,0x4000451c
  mov    0x4000452c,%eax
  mov    $0x0,%al
  add    $0x11,%eax
  mov    %eax,0x4000452c
  mov    0x40004528,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x40004528
  ret
```

assistant: ```c
void UART_Init(void) {
  (*((volatile uint32_t *)0x400FE618)) |= 0x01;
  (*((volatile uint32_t *)0x400FE608)) |= 0x01;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x01) == 0) {
  };
  (*((volatile uint32_t *)0x4000C030)) &= ~0x00000001;
  (*((volatile uint32_t *)0x4000C024)) = 27;
  (*((volatile uint32_t *)0x4000C028)) = 8;
  (*((volatile uint32_t *)0x4000C02C)) = (0x00000060 | 0x00000010);
  (*((volatile uint32_t *)0x4000C030)) |= 0x00000001;
  (*((volatile uint32_t *)0x40004420)) |= 0x03;
  (*((volatile uint32_t *)0x4000451C)) |= 0x03;
  (*((volatile uint32_t *)0x4000452C)) = ((*((volatile uint32_t *)0x4000452C)) & 0xFFFFFF00) + 0x00000011;
  (*((volatile uint32_t *)0x40004528)) &= ~0x03;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UART_Init>:
  endbr64
  mov    0x400fe618,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe618
  mov    0x400fe608,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe608
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    0x400fea08,%eax
  test   $0x1,%al
  je     L0
  mov    0x4000c030,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x4000c030
  movl   $0x1b,0x4000c024
  movl   $0x8,0x4000c028
  movl   $0x70,0x4000c02c
  mov    0x4000c030,%eax
  or     $0x1,%eax
  mov    %eax,0x4000c030
  mov    0x40004420,%eax
  or     $0x3,%eax
  mov    %eax,0x40004420
  mov    0x4000451c,%eax
  or     $0x3,%eax
  mov    %eax,0x4000451c
  mov    0x4000452c,%eax
  xor    %al,%al
  add    $0x11,%eax
  mov    %eax,0x4000452c
  mov    0x40004528,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x40004528
  ret
```

assistant: ```c
void UART_Init(void) {
  (*((volatile uint32_t *)0x400FE618)) |= 0x01;
  (*((volatile uint32_t *)0x400FE608)) |= 0x01;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x01) == 0) {
  };
  (*((volatile uint32_t *)0x4000C030)) &= ~0x00000001;
  (*((volatile uint32_t *)0x4000C024)) = 27;
  (*((volatile uint32_t *)0x4000C028)) = 8;
  (*((volatile uint32_t *)0x4000C02C)) = (0x00000060 | 0x00000010);
  (*((volatile uint32_t *)0x4000C030)) |= 0x00000001;
  (*((volatile uint32_t *)0x40004420)) |= 0x03;
  (*((volatile uint32_t *)0x4000451C)) |= 0x03;
  (*((volatile uint32_t *)0x4000452C)) = ((*((volatile uint32_t *)0x4000452C)) & 0xFFFFFF00) + 0x00000011;
  (*((volatile uint32_t *)0x40004528)) &= ~0x03;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UART_Init>:
  endbr64
  mov    0x400fe618,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe618
  mov    0x400fe608,%eax
  or     $0x1,%eax
  mov    %eax,0x400fe608
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    0x400fea08,%eax
  test   $0x1,%al
  je     L9
  mov    0x4000c030,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x4000c030
  movl   $0x1b,0x4000c024
  movl   $0x8,0x4000c028
  movl   $0x70,0x4000c02c
  mov    0x4000c030,%eax
  or     $0x1,%eax
  mov    %eax,0x4000c030
  mov    0x40004420,%eax
  or     $0x3,%eax
  mov    %eax,0x40004420
  mov    0x4000451c,%eax
  or     $0x3,%eax
  mov    %eax,0x4000451c
  mov    0x4000452c,%eax
  xor    %al,%al
  add    $0x11,%eax
  mov    %eax,0x4000452c
  mov    0x40004528,%eax
  and    $0xfffffffc,%eax
  mov    %eax,0x40004528
  ret
```

assistant: ```c
void UART_Init(void) {
  (*((volatile uint32_t *)0x400FE618)) |= 0x01;
  (*((volatile uint32_t *)0x400FE608)) |= 0x01;
  while (((*((volatile uint32_t *)0x400FEA08)) & 0x01) == 0) {
  };
  (*((volatile uint32_t *)0x4000C030)) &= ~0x00000001;
  (*((volatile uint32_t *)0x4000C024)) = 27;
  (*((volatile uint32_t *)0x4000C028)) = 8;
  (*((volatile uint32_t *)0x4000C02C)) = (0x00000060 | 0x00000010);
  (*((volatile uint32_t *)0x4000C030)) |= 0x00000001;
  (*((volatile uint32_t *)0x40004420)) |= 0x03;
  (*((volatile uint32_t *)0x4000451C)) |= 0x03;
  (*((volatile uint32_t *)0x4000452C)) = ((*((volatile uint32_t *)0x4000452C)) & 0xFFFFFF00) + 0x00000011;
  (*((volatile uint32_t *)0x40004528)) &= ~0x03;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rFFTInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  pxor   %xmm2,%xmm2
  cvtsi2sdq -0x30(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movsd  D31(%rip),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x3,%rax
  setg   %dl
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x14,%rax
  setle  %al
  and    %edx,%eax
  movzbl %al,%ebx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  sete   %al
  movzbl %al,%eax
  and    %ebx,%eax
  test   %eax,%eax
  je     L19
  movq   $0x0,-0x20(%rbp)
  jmp    L16
L1:
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x20(%rbp),%xmm1
  movsd  D36(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x30(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  addq   $0x1,-0x20(%rbp)
L16:
  mov    -0x30(%rbp),%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  cmp    %rax,-0x20(%rbp)
  jle    L1
  jmp    L21
L19:
  movq   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D31
type_infered: byte[8]
name: read_data
arguments: label: D19
type_infered: f64
name: read_data
arguments: label: D36
type_infered: byte[8]

tool: {"D31": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: D19: 0.5

tool: {"D36": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
long rFFTInit(long *fftMptr, long fftN, float *Utbl) {
  long i1, ErrVal;
  ErrVal = 0;
  *fftMptr = (long)(log(fftN) / log(2.0) + 0.5);
  if ((*fftMptr >= 4) & (*fftMptr <= 20) & (int)(pow(2, *fftMptr) + .5) == fftN)
    for (i1 = 0; i1 <= fftN / 4; i1++)
      Utbl[i1] = cos((3.1415926535897932384626433832795 * 2.0 * i1) / fftN);
  else
    ErrVal = 1;
  return ErrVal;
}
```