ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ieee_p_1242562249_sub_17249857350030274602_1035706684>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    0xc(%rcx),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %ebp,%ebp
  je     L7
  mov    %rsp,%rsi
  call   <ieee_p_1242562249_sub_18075413680674704129_1035706684@plt>
  mov    0xc(%rsp),%r13d
  mov    %rax,%rbp
  mov    %r13d,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%ecx
  mov    0x8(%rsp),%eax
  mov    %edx,%ebp
  sub    %ecx,%ebp
  imul   %eax,%ebp
  add    $0x1,%ebp
L29:
  mov    %ecx,(%rbx)
  mov    %edx,0x4(%rbx)
  mov    %eax,0x8(%rbx)
  mov    %ebp,0xc(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L7:
  mov    0x508(%rdi),%r13
  xor    %edi,%edi
  call   <xsi_get_transient_memory@plt>
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0xffffffff,%eax
  jmp    L29
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ieee_p_1242562249_sub_17249857350030274602_1035706684(char *t1, char *t2, char *t3, char *t4, int t5) {
  char t7[24];
  char t20[16];
  char *t0;
  char *t8;
  unsigned char t9;
  char *t10;
  char *t11;
  char *t12;
  unsigned int t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  int t18;
  unsigned int t19;
  int t21;
  char *t22;
  int t23;
  char *t24;
  char *t25;
  int t26;
LAB0:
  t8 = (t7 + 4U);
  t9 = (t3 != 0);
  if (t9 == 1)
    goto LAB3;
LAB2:
  t10 = (t7 + 12U);
  *((char **)t10) = t4;
  t11 = (t7 + 20U);
  *((int *)t11) = t5;
  t12 = (t4 + 12U);
  t13 = *((unsigned int *)t12);
  t14 = (t13 < 1);
  if (t14 != 0)
    goto LAB4;
LAB6:
LAB5:
  t12 = ieee_p_1242562249_sub_18075413680674704129_1035706684(t1, t20, t3, t4, t5);
  t15 = (t20 + 12U);
  t13 = *((unsigned int *)t15);
  t13 = (t13 * 1U);
  t0 = xsi_get_transient_memory(t13);
  memcpy(t0, t12, t13);
  t16 = (t20 + 0U);
  t18 = *((int *)t16);
  t17 = (t20 + 4U);
  t21 = *((int *)t17);
  t22 = (t20 + 8U);
  t23 = *((int *)t22);
  t24 = (t2 + 0U);
  t25 = (t24 + 0U);
  *((int *)t25) = t18;
  t25 = (t24 + 4U);
  *((int *)t25) = t21;
  t25 = (t24 + 8U);
  *((int *)t25) = t23;
  t26 = (t21 - t18);
  t19 = (t26 * t23);
  t19 = (t19 + 1);
  t25 = (t24 + 12U);
  *((unsigned int *)t25) = t19;
LAB1:
  return t0;
LAB3:
  *((char **)t8) = t3;
  goto LAB2;
LAB4:
  t15 = (t1 + 1288U);
  t16 = *((char **)t15);
  t0 = xsi_get_transient_memory(0U);
  memcpy(t0, t16, 0U);
  t15 = (t2 + 0U);
  t17 = (t15 + 0U);
  *((int *)t17) = 0;
  t17 = (t15 + 4U);
  *((int *)t17) = 1;
  t17 = (t15 + 8U);
  *((int *)t17) = -1;
  t18 = (1 - 0);
  t19 = (t18 * -1);
  t19 = (t19 + 1);
  t17 = (t15 + 12U);
  *((unsigned int *)t17) = t19;
  goto LAB1;
LAB7:
  goto LAB5;
LAB8:;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PLMin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  -0x8(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
L2:
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float PLMin(float *Items, int Size) {
  float Minimum = Items[0];
  for (int Index = 0; Index < Size; ++Index) {
    if (Items[Index] < Minimum) {
      Minimum = Items[Index];
    }
  }
  return Minimum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PLMin>:
  endbr64
  movss  (%rdi),%xmm0
  test   %esi,%esi
  jle    L1
  add    $0x4,%rdi
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%rax
  jmp    L12
L21:
  movss  (%rdi),%xmm1
  minss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  add    $0x4,%rdi
L12:
  cmp    %rax,%rdi
  jne    L21
L1:
  ret
```

assistant: ```c
float PLMin(float *Items, int Size) {
  float Minimum = Items[0];
  for (int Index = 0; Index < Size; ++Index) {
    if (Items[Index] < Minimum) {
      Minimum = Items[Index];
    }
  }
  return Minimum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PLMin>:
  endbr64
  movss  (%rdi),%xmm0
  test   %esi,%esi
  jle    L1
  add    $0x4,%rdi
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,4),%rax
  jmp    L29
  nopl   0x0(%rax)
L25:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  minss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
L29:
  cmp    %rax,%rdi
  jne    L25
L1:
  ret
```

assistant: ```c
float PLMin(float *Items, int Size) {
  float Minimum = Items[0];
  for (int Index = 0; Index < Size; ++Index) {
    if (Items[Index] < Minimum) {
      Minimum = Items[Index];
    }
  }
  return Minimum;
}
```
user: What is the c source code of the assembly code below?

```asm
<PLMin>:
  endbr64
  movss  (%rdi),%xmm0
  test   %esi,%esi
  jle    L6
  cmp    $0x1,%esi
  je     L6
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rdx
  nopl   (%rax)
L28:
  movss  (%rax),%xmm1
  add    $0x4,%rax
  minss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L28
L6:
  ret
```

assistant: ```c
float PLMin(float *Items, int Size) {
  float Minimum = Items[0];
  for (int Index = 0; Index < Size; ++Index) {
    if (Items[Index] < Minimum) {
      Minimum = Items[Index];
    }
  }
  return Minimum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L0:
  mov    -0x4(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int mod(int x, int m) {
  int r = x % m;
  return r < 0 ? r + m : r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  test   %edx,%edx
  mov    %edx,%eax
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int x, int m) {
  int r = x % m;
  return r < 0 ? r + m : r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int x, int m) {
  int r = x % m;
  return r < 0 ? r + m : r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %edx,%esi
  mov    %edx,%eax
  test   %edx,%edx
  cmovs  %esi,%eax
  ret
```

assistant: ```c
int mod(int x, int m) {
  int r = x % m;
  return r < 0 ? r + m : r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_to_leds_m$leds$red_on>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   1050 <leds$leds$red_on@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char int_to_leds_m$leds$red_on(void) {
  char result;
  result = leds$leds$red_on();
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_to_leds_m$leds$red_on>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   1050 <leds$leds$red_on@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char int_to_leds_m$leds$red_on(void) {
  char result;
  result = leds$leds$red_on();
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_to_leds_m$leds$red_on>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   1050 <leds$leds$red_on@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char int_to_leds_m$leds$red_on(void) {
  char result;
  result = leds$leds$red_on();
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_to_leds_m$leds$red_on>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   1050 <leds$leds$red_on@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char int_to_leds_m$leds$red_on(void) {
  char result;
  result = leds$leds$red_on();
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<b2to10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L2
L10:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movsbl %al,%eax
  imul   %ebx,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x18(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L10
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int b2to10(char *bin, size_t siz) {
  int i, j;
  int sum = 0;
  for (i = 0, j = siz - 1; i < siz; i++, j--) {
    sum += (bin[i] - '0') * pow(2, j);
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<b2to10>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L6
  lea    (%rdi,%rsi,1),%r12
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  lea    -0x1(%rsi,%rdi,1),%r13d
L4:
  movsbl (%rbx),%r14d
  sub    $0x30,%r14d
  mov    %r13d,%esi
  sub    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movsbl %al,%eax
  imul   %r14d,%eax
  add    %eax,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
L20:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0x0,%ebp
  jmp    L20
```

assistant: ```c
int b2to10(char *bin, size_t siz) {
  int i, j;
  int sum = 0;
  for (i = 0, j = siz - 1; i < siz; i++, j--) {
    sum += (bin[i] - '0') * pow(2, j);
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b2to10>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L18
  mov    %rdi,%r14
  lea    (%rdi,%rsi,1),%rbx
  lea    -0x1(%rsi,%rdi,1),%ebp
  xor    %r12d,%r12d
  nop
L16:
  mov    %ebp,%esi
  movsbl (%r14),%r13d
  mov    $0x2,%edi
  sub    %r14d,%esi
  add    $0x1,%r14
  call   <pow@plt>
  sub    $0x30,%r13d
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
  cmp    %rbx,%r14
  jne    L16
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int b2to10(char *bin, size_t siz) {
  int i, j;
  int sum = 0;
  for (i = 0, j = siz - 1; i < siz; i++, j--) {
    sum += (bin[i] - '0') * pow(2, j);
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<b2to10>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L0
  mov    %rdi,%r14
  lea    (%rdi,%rsi,1),%rbx
  lea    -0x1(%rsi,%rdi,1),%ebp
  xor    %r12d,%r12d
  nop
L6:
  mov    %ebp,%esi
  movsbl (%r14),%r13d
  mov    $0x2,%edi
  sub    %r14d,%esi
  add    $0x1,%r14
  call   <pow@plt>
  sub    $0x30,%r13d
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
  cmp    %rbx,%r14
  jne    L6
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int b2to10(char *bin, size_t siz) {
  int i, j;
  int sum = 0;
  for (i = 0, j = siz - 1; i < siz; i++, j--) {
    sum += (bin[i] - '0') * pow(2, j);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PutSignedInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L38
  mov    -0x24(%rbp),%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L95
L38:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L95:
  subl   $0x1,-0x20(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jbe    L1
  cmpl   $0x0,-0x24(%rbp)
  jns    L30
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  neg    %eax
  mov    %eax,%ecx
  movsbl -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <PutSignedInt>
  mov    %eax,-0x8(%rbp)
  jmp    L69
L30:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,%ecx
  movsbl -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <PutSignedInt>
  mov    %eax,-0x8(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L20
L1:
  cmpl   $0x0,-0x24(%rbp)
  jns    L23
  subl   $0x1,-0x20(%rbp)
  jmp    L23
L41:
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <append_char@plt>
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x20(%rbp)
L23:
  cmpl   $0x0,-0x20(%rbp)
  jg     L41
  cmpl   $0x0,-0x24(%rbp)
  jns    L20
  mov    -0x18(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <append_char@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L20:
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    $0x30,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <append_char@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
signed int PutSignedInt(char *pStr, char fill, signed int width, signed int value) {
  signed int num = 0;
  unsigned int absolute;
  if (value < 0) {
    absolute = -value;
  } else {
    absolute = value;
  }
  width--;
  if ((absolute / 10) > 0) {
    if (value < 0) {
      num = PutSignedInt(pStr, fill, width, -(absolute / 10));
    } else {
      num = PutSignedInt(pStr, fill, width, absolute / 10);
    }
    pStr += num;
  } else {
    if (value < 0) {
      width--;
    }
    while (width > 0) {
      append_char(pStr, fill);
      pStr++;
      num++;
      width--;
    }
    if (value < 0) {
      num += append_char(pStr, '-');
      pStr++;
    }
  }
  num += append_char(pStr, (absolute % 10) + '0');
  return num;
}
```
user: What is the c source code of the assembly code below:

```asm
<PutSignedInt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %ecx,%r13d
  mov    %esi,%r15d
  test   %ecx,%ecx
  js     L27
  mov    %ecx,%r14d
  lea    -0x1(%rdx),%ebp
  cmp    $0x9,%ecx
  ja     L45
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jle    L13
L66:
  mov    %r12,%rbx
  movsbl %r15b,%r15d
L91:
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <append_char@plt>
  add    $0x1,%rbx
  lea    0x0(%rbp,%r12,1),%eax
  sub    %ebx,%eax
  test   %eax,%eax
  jg     L91
  lea    -0x1(%rbp),%eax
  add    $0x1,%rax
  test   %ebp,%ebp
  mov    $0x1,%edx
  cmovle %rdx,%rax
  add    %rax,%r12
  test   %ebp,%ebp
  mov    $0x1,%ebx
  cmovg  %ebp,%ebx
  test   %r13d,%r13d
  jns    L13
L40:
  mov    $0x2d,%esi
  mov    %r12,%rdi
  call   <append_char@plt>
  add    %eax,%ebx
  add    $0x1,%r12
  jmp    L13
L27:
  mov    %ecx,%r14d
  neg    %r14d
  lea    -0x1(%rdx),%eax
  cmp    $0x9,%r14d
  jbe    L4
  mov    %r14d,%ecx
  mov    $0xcccccccd,%edx
  imul   %rdx,%rcx
  shr    $0x23,%rcx
  neg    %ecx
  movsbl %sil,%esi
  mov    %eax,%edx
  call   <PutSignedInt>
  mov    %eax,%ebx
  jmp    L30
L45:
  mov    %ecx,%ecx
  mov    $0xcccccccd,%eax
  imul   %rax,%rcx
  shr    $0x23,%rcx
  movsbl %sil,%esi
  mov    %ebp,%edx
  call   <PutSignedInt>
  mov    %eax,%ebx
L30:
  movslq %ebx,%rax
  add    %rax,%r12
L13:
  mov    %r14d,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%esi
  mov    %r12,%rdi
  call   <append_char@plt>
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  lea    -0x2(%rdx),%ebp
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jg     L66
  jmp    L40
```

assistant: ```c
signed int PutSignedInt(char *pStr, char fill, signed int width, signed int value) {
  signed int num = 0;
  unsigned int absolute;
  if (value < 0) {
    absolute = -value;
  } else {
    absolute = value;
  }
  width--;
  if ((absolute / 10) > 0) {
    if (value < 0) {
      num = PutSignedInt(pStr, fill, width, -(absolute / 10));
    } else {
      num = PutSignedInt(pStr, fill, width, absolute / 10);
    }
    pStr += num;
  } else {
    if (value < 0) {
      width--;
    }
    while (width > 0) {
      append_char(pStr, fill);
      pStr++;
      num++;
      width--;
    }
    if (value < 0) {
      num += append_char(pStr, '-');
      pStr++;
    }
  }
  num += append_char(pStr, (absolute % 10) + '0');
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PutSignedInt>:
  endbr64
  push   %r15
  lea    -0x1(%rdx),%r8d
  mov    %ecx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  js     L72
  cmp    $0x9,%ecx
  jg     L96
  test   %r8d,%r8d
  jle    L41
L0:
  movslq %r8d,%r13
  movsbl %sil,%r12d
  mov    %r13,%rbp
  add    %rbx,%r13
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  mov    %r12d,%esi
  add    $0x1,%rbx
  call   <append_char@plt>
  cmp    %rbx,%r13
  jne    L4
  mov    %r14d,%r12d
  test   %r15d,%r15d
  js     L74
L59:
  mov    $0xcccccccd,%eax
  mov    %r13,%rdi
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%esi
  call   <append_char@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  mov    %ecx,%r12d
  mov    $0xcccccccd,%ecx
  imul   %r12,%rcx
  shr    $0x23,%rcx
L107:
  movsbl %sil,%esi
  mov    %r8d,%edx
  mov    %rbx,%rdi
  call   <PutSignedInt>
  movslq %eax,%r13
  mov    %eax,%ebp
  add    %rbx,%r13
  jmp    L59
  nopl   0x0(%rax)
L72:
  neg    %r14d
  cmp    $0xfffffff7,%ecx
  jge    L13
  mov    %r14d,%r12d
  mov    $0xcccccccd,%ecx
  imul   %r12,%rcx
  shr    $0x23,%rcx
  neg    %ecx
  jmp    L107
  nopl   0x0(%rax)
L13:
  lea    -0x2(%rdx),%r8d
  test   %r8d,%r8d
  jg     L0
  mov    %rdi,%r13
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %r13,%rdi
  mov    $0x2d,%esi
  add    $0x1,%r13
  mov    %r14d,%r12d
  call   <append_char@plt>
  add    %eax,%ebp
  jmp    L59
L41:
  mov    %rdi,%r13
  xor    %ebp,%ebp
  mov    %ecx,%r12d
  jmp    L59
```

assistant: ```c
signed int PutSignedInt(char *pStr, char fill, signed int width, signed int value) {
  signed int num = 0;
  unsigned int absolute;
  if (value < 0) {
    absolute = -value;
  } else {
    absolute = value;
  }
  width--;
  if ((absolute / 10) > 0) {
    if (value < 0) {
      num = PutSignedInt(pStr, fill, width, -(absolute / 10));
    } else {
      num = PutSignedInt(pStr, fill, width, absolute / 10);
    }
    pStr += num;
  } else {
    if (value < 0) {
      width--;
    }
    while (width > 0) {
      append_char(pStr, fill);
      pStr++;
      num++;
      width--;
    }
    if (value < 0) {
      num += append_char(pStr, '-');
      pStr++;
    }
  }
  num += append_char(pStr, (absolute % 10) + '0');
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<PutSignedInt>:
  endbr64
  push   %r15
  lea    -0x1(%rdx),%r8d
  mov    %ecx,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  js     L88
  cmp    $0x9,%ecx
  jg     L57
  test   %r8d,%r8d
  jle    L103
L7:
  movslq %r8d,%r13
  movsbl %sil,%r12d
  mov    %r13,%rbp
  add    %rbx,%r13
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rbx,%rdi
  mov    %r12d,%esi
  add    $0x1,%rbx
  call   <append_char@plt>
  cmp    %rbx,%r13
  jne    L16
  mov    %r14d,%r12d
  test   %r15d,%r15d
  js     L29
L80:
  mov    $0xcccccccd,%eax
  mov    %r13,%rdi
  imul   %r12,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%esi
  call   <append_char@plt>
  add    $0x8,%rsp
  pop    %rbx
  add    %ebp,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %ecx,%r12d
  mov    $0xcccccccd,%ecx
  imul   %r12,%rcx
  shr    $0x23,%rcx
L38:
  movsbl %sil,%esi
  mov    %r8d,%edx
  mov    %rbx,%rdi
  call   <PutSignedInt>
  movslq %eax,%r13
  mov    %eax,%ebp
  add    %rbx,%r13
  jmp    L80
  nopl   0x0(%rax)
L88:
  neg    %r14d
  cmp    $0xfffffff7,%ecx
  jge    L49
  mov    %r14d,%r12d
  mov    $0xcccccccd,%ecx
  imul   %r12,%rcx
  shr    $0x23,%rcx
  neg    %ecx
  jmp    L38
  nopl   0x0(%rax)
L49:
  lea    -0x2(%rdx),%r8d
  test   %r8d,%r8d
  jg     L7
  mov    %rdi,%r13
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r13,%rdi
  mov    $0x2d,%esi
  add    $0x1,%r13
  mov    %r14d,%r12d
  call   <append_char@plt>
  add    %eax,%ebp
  jmp    L80
L103:
  mov    %rdi,%r13
  xor    %ebp,%ebp
  mov    %ecx,%r12d
  jmp    L80
```

assistant: ```c
signed int PutSignedInt(char *pStr, char fill, signed int width, signed int value) {
  signed int num = 0;
  unsigned int absolute;
  if (value < 0) {
    absolute = -value;
  } else {
    absolute = value;
  }
  width--;
  if ((absolute / 10) > 0) {
    if (value < 0) {
      num = PutSignedInt(pStr, fill, width, -(absolute / 10));
    } else {
      num = PutSignedInt(pStr, fill, width, absolute / 10);
    }
    pStr += num;
  } else {
    if (value < 0) {
      width--;
    }
    while (width > 0) {
      append_char(pStr, fill);
      pStr++;
      num++;
      width--;
    }
    if (value < 0) {
      num += append_char(pStr, '-');
      pStr++;
    }
  }
  num += append_char(pStr, (absolute % 10) + '0');
  return num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: hello, world


assistant: ```c
int my_main() {
  printf("hello, world\n");
  sleep(5);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D0: hello, world


assistant: ```c
int my_main() {
  printf("hello, world\n");
  sleep(5);
  return 0;
}
```