user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0xb71b00,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L29
L33:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x24(%rbp)
L29:
  cmpl   $0x2dc6bf,-0x24(%rbp)
  jle    L33
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L77
L2:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L37
L132:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x24(%rbp),%eax
  add    $0xf4240,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x24(%rbp),%eax
  add    $0x1e8480,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <sum_prop_divisors@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L37
  movl   $0x1,-0x10(%rbp)
  jmp    L102
L37:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L132
L102:
  cmpl   $0x0,-0x10(%rbp)
  je     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
  jmp    L27
L1:
  mov    -0x24(%rbp),%eax
  add    $0xf4240,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L51
  mov    -0x24(%rbp),%eax
  add    $0x1e8480,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L51
  mov    -0x24(%rbp),%eax
  add    $0x1e8480,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L92:
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L22
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x28(%rbp)
L22:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <sum_prop_divisors@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L92
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  movl   $0x0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L27:
  addl   $0x1,-0x24(%rbp)
L77:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L2
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D10
type: string

tool: D7: %d --> 

tool: D26: %d



tool: D10: answer: %d


assistant: ```c
int main() {
  int curr_num, i, j, branch, curr_chain_len, big_chain_len, temp, STOP;
  int *arr = (int *)malloc(sizeof(int) * 3 * 1000000);
  for (i = 0; i < 3 * 1000000; i++) {
    arr[i] = 0;
  }
  branch = 1;
  curr_chain_len = 0;
  for (i = 1; i < 1000000; i++) {
    temp = i;
    STOP = 0;
    while (!arr[i]) {
      arr[i] = 1;
      arr[1000000 + i] = branch;
      arr[(2 * 1000000) + i] = curr_chain_len;
      curr_chain_len++;
      i = sum_prop_divisors(i);
      if (i >= 1000000) {
        STOP = 1;
        break;
      }
    }
    if (STOP) {
      i = temp;
      curr_chain_len = 0;
      branch++;
      continue;
    }
    if (branch == arr[1000000 + i]) {
      if ((curr_chain_len - arr[(2 * 1000000) + i]) > big_chain_len) {
        big_chain_len = curr_chain_len - arr[(2 * 1000000) + i];
        curr_num = i;
        j = i;
        do {
          printf("%d --> ", j);
          if (j < curr_num) {
            curr_num = j;
          }
          j = sum_prop_divisors(j);
        } while (j != i);
        printf("%d\n\n", j);
      }
    }
    curr_chain_len = 0;
    branch++;
    i = temp;
  }
  printf("answer: %d\n", curr_num);
  return 0;
}
```