user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x30(%rbp)
  movl   $0x7,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x9,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L65
L51:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x28,%rax
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x2c,%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  add    %rax,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x30,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L65:
  cmpl   $0x2,-0x38(%rbp)
  jle    L51
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L54
L11:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x30,%rax
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x2c,%rax
  mov    (%rax),%eax
  add    %eax,%ecx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x28,%rax
  mov    (%rax),%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L54:
  cmpl   $0x2,-0x38(%rbp)
  jle    L11
  movl   $0x0,-0x34(%rbp)
  jmp    L45
L19:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  cltq
  add    $0x3,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  add    $0x6,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L45:
  cmpl   $0x2,-0x34(%rbp)
  jle    L19
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D53
datatype: string
name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string

tool: D21: Presenting the Magic Square:



tool: D26: %d  %d  %d


tool: D53: Sum for row %d is %d


tool: D32: Sum for column %d is %d


tool: D36: Sum for diagonal NW/SE is %d


tool: D14: Sum for diagonal NE/SW is %d


assistant: ```c
int main() {
  int r, c;
  int m[3][3] = {8, 7, 6, 3, 5, 7, 4, 9, 5};
  puts("Presenting the Magic Square:\n\n");
  for (r = 0; r < 3; r++)
    printf("%d  %d  %d\n", m[r][0], m[r][1], m[r][2]);
  putchar('\n');
  for (r = 0; r < 3; r++)
    printf("Sum for row %d is %d\n", r + 1, m[r][0] + m[r][1] + m[r][2]);
  for (c = 0; c < 3; c++)
    printf("Sum for column %d is %d\n", c + 1, m[0][c] + m[1][c] + m[2][c]);
  printf("Sum for diagonal NW/SE is %d\n", m[0][0] + m[1][1] + m[2][2]);
  printf("Sum for diagonal NE/SW is %d\n", m[0][2] + m[1][1] + m[2][0]);
  return 0;
}
```