ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decode>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
L14:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L36
  movslq %ebx,%rdx
  movzbl (%r12,%rdx,1),%eax
  cmp    $0x25,%al
  jne    L13
  movsbl 0x2(%r12,%rdx,1),%esi
  movsbl 0x1(%r12,%rdx,1),%edi
  add    $0x2,%ebx
  call   <hex2int@plt>
  jmp    L13
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decode(char *dest, char *src, char *enc) {
  int dest_index;
  int i;
  dest_index = 0;
  for (i = 0; i < strlen(src); i++) {
    if (src[i] == '%') {
      dest[dest_index] = hex2int(src[i + 1], src[i + 2]);
      i += 2;
    } else {
      dest[dest_index] = src[i];
    }
    dest_index++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<decode>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %al,0x0(%rbp)
  add    $0x1,%ebx
  add    $0x1,%rbp
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L6
  movslq %ebx,%rdx
  movzbl (%r12,%rdx,1),%eax
  cmp    $0x25,%al
  jne    L33
  movsbl 0x2(%r12,%rdx,1),%esi
  movsbl 0x1(%r12,%rdx,1),%edi
  add    $0x2,%ebx
  call   <hex2int@plt>
  jmp    L33
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void decode(char *dest, char *src, char *enc) {
  int dest_index;
  int i;
  dest_index = 0;
  for (i = 0; i < strlen(src); i++) {
    if (src[i] == '%') {
      dest[dest_index] = hex2int(src[i + 1], src[i + 2]);
      i += 2;
    } else {
      dest[dest_index] = src[i];
    }
    dest_index++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L51
  mov    $0x1,%eax
  jmp    L7
L51:
  cmpl   $0x1,-0x18(%rbp)
  jne    L28
  mov    -0x14(%rbp),%eax
  jmp    L7
L28:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L43
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <power>
  jmp    L7
L43:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <power>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int power(int a, int b) {
  if (b == 0)
    return 1;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return power(multiply(a, a), b / 2);
  else
    return multiply(a, power(a, b - 1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<power>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L23
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%esi
  je     L28
  test   $0x1,%sil
  jne    L8
  mov    %edi,%esi
  call   <multiply@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  call   <power>
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  lea    -0x1(%rsi),%esi
  call   <power>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <multiply@plt>
  jmp    L28
L23:
  ret
```

assistant: ```c
int power(int a, int b) {
  if (b == 0)
    return 1;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return power(multiply(a, a), b / 2);
  else
    return multiply(a, power(a, b - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<power>:
  endbr64
  test   %esi,%esi
  je     L3
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jne    L51
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %ebx,%eax
  mov    %edi,%esi
  shr    $0x1f,%eax
  add    %eax,%ebx
  call   <multiply@plt>
  sar    %ebx
  mov    %eax,%edi
  test   %ebx,%ebx
  je     L41
  cmp    $0x1,%ebx
  je     L32
L51:
  test   $0x1,%bl
  je     L16
  lea    -0x1(%rbx),%esi
  mov    %edi,0xc(%rsp)
  call   <power>
  mov    0xc(%rsp),%edi
  add    $0x10,%rsp
  mov    %eax,%esi
  pop    %rbx
  jmp    1050 <multiply@plt>
  nopl   0x0(%rax)
L32:
  add    $0x10,%rsp
  mov    %edi,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int power(int a, int b) {
  if (b == 0)
    return 1;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return power(multiply(a, a), b / 2);
  else
    return multiply(a, power(a, b - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  test   %esi,%esi
  je     L14
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  cmp    $0x1,%esi
  jne    L132
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %ebx,%eax
  mov    %ebp,%esi
  mov    %ebp,%edi
  shr    $0x1f,%eax
  add    %eax,%ebx
  call   <multiply@plt>
  sar    %ebx
  mov    %eax,%ebp
  test   %ebx,%ebx
  je     L80
  cmp    $0x1,%ebx
  je     L59
L132:
  test   $0x1,%bl
  je     L79
  sub    $0x1,%ebx
  je     L51
  mov    %ebp,%r12d
  cmp    $0x1,%ebx
  jne    L52
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L167:
  mov    %ebx,%eax
  mov    %r12d,%esi
  mov    %r12d,%edi
  shr    $0x1f,%eax
  add    %eax,%ebx
  call   <multiply@plt>
  sar    %ebx
  mov    %eax,%r12d
  test   %ebx,%ebx
  je     L51
  cmp    $0x1,%ebx
  je     L42
L52:
  test   $0x1,%bl
  je     L167
  sub    $0x1,%ebx
  je     L44
  mov    %r12d,%edi
  cmp    $0x1,%ebx
  jne    L192
  jmp    L199
  nopl   0x0(%rax)
L189:
  mov    %ebx,%eax
  mov    %edi,%esi
  shr    $0x1f,%eax
  add    %eax,%ebx
  call   <multiply@plt>
  sar    %ebx
  mov    %eax,%edi
  test   %ebx,%ebx
  je     L44
  cmp    $0x1,%ebx
  je     L199
L192:
  test   $0x1,%bl
  je     L189
  lea    -0x1(%rbx),%esi
  mov    %edi,0xc(%rsp)
  call   <power>
  mov    0xc(%rsp),%edi
  mov    %eax,%esi
  call   <multiply@plt>
  mov    %eax,%edi
L199:
  mov    %edi,%esi
  mov    %r12d,%edi
  call   <multiply@plt>
  mov    %eax,%r12d
L42:
  add    $0x10,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <multiply@plt>
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x10,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L51:
  mov    $0x1,%r12d
  jmp    L42
L44:
  mov    $0x1,%edi
  jmp    L199
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int power(int a, int b) {
  if (b == 0)
    return 1;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return power(multiply(a, a), b / 2);
  else
    return multiply(a, power(a, b - 1));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L34
L2:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L3:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x2,-0x14(%rbp)
  jle    L3
  addl   $0x1,-0x18(%rbp)
L34:
  cmpl   $0x6,-0x18(%rbp)
  jle    L2
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string
name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string

tool: D3: dstdevpn

tool: D1: # c::%s:len=%d


tool: D21: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdevpn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D27(%rip),%r15
  jmp    L35
L34:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L8
L35:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L33:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L33
  jmp    L34
L8:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D27
type: string
name: parse_data
arguments: tag: D25
type: string
name: parse_data
arguments: tag: D22
type: string

tool: D27: dstdevpn

tool: D25: # c::%s:len=%d


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdevpn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D29(%rip),%r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L2:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L2
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L7
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D18
type: string

tool: D29: dstdevpn

tool: D7: # c::%s:len=%d


tool: D18: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdevpn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D5(%rip),%r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L2:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L7:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L7
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L2
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D5: dstdevpn

tool: D19: # c::%s:len=%d


tool: D9: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dstdevpn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<timer_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <timer_reset@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xf423f,%eax
  jle    L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0xf4240(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void timer_add(const struct timeval *timer_a, const struct timeval *timer_b, struct timeval *ret) {
  timer_reset(ret);
  ret->tv_usec = timer_a->tv_usec + timer_b->tv_usec;
  ret->tv_sec = timer_a->tv_sec + timer_b->tv_sec;
  if (ret->tv_usec >= 1000000) {
    ret->tv_usec -= 1000000;
    ret->tv_sec += 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timer_add>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <timer_reset@plt>
  mov    (%r12),%eax
  add    0x0(%rbp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%r12),%rdx
  add    0x8(%rbp),%rdx
  mov    %rdx,0x8(%rbx)
  cmp    $0xf423f,%eax
  jle    L8
  sub    $0xf4240,%eax
  mov    %eax,(%rbx)
  add    $0x1,%rdx
  mov    %rdx,0x8(%rbx)
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void timer_add(const struct timeval *timer_a, const struct timeval *timer_b, struct timeval *ret) {
  timer_reset(ret);
  ret->tv_usec = timer_a->tv_usec + timer_b->tv_usec;
  ret->tv_sec = timer_a->tv_sec + timer_b->tv_sec;
  if (ret->tv_usec >= 1000000) {
    ret->tv_usec -= 1000000;
    ret->tv_sec += 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<timer_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <timer_reset@plt>
  mov    (%r12),%eax
  mov    0x8(%r12),%rdx
  add    0x0(%rbp),%eax
  add    0x8(%rbp),%rdx
  mov    %eax,(%rbx)
  mov    %rdx,0x8(%rbx)
  cmp    $0xf423f,%eax
  jle    L3
  sub    $0xf4240,%eax
  add    $0x1,%rdx
  mov    %eax,(%rbx)
  mov    %rdx,0x8(%rbx)
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void timer_add(const struct timeval *timer_a, const struct timeval *timer_b, struct timeval *ret) {
  timer_reset(ret);
  ret->tv_usec = timer_a->tv_usec + timer_b->tv_usec;
  ret->tv_sec = timer_a->tv_sec + timer_b->tv_sec;
  if (ret->tv_usec >= 1000000) {
    ret->tv_usec -= 1000000;
    ret->tv_sec += 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timer_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  call   <timer_reset@plt>
  mov    (%r12),%eax
  mov    0x8(%r12),%rdx
  add    0x0(%rbp),%eax
  add    0x8(%rbp),%rdx
  mov    %eax,(%rbx)
  mov    %rdx,0x8(%rbx)
  cmp    $0xf423f,%eax
  jle    L1
  sub    $0xf4240,%eax
  add    $0x1,%rdx
  mov    %eax,(%rbx)
  mov    %rdx,0x8(%rbx)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void timer_add(const struct timeval *timer_a, const struct timeval *timer_b, struct timeval *ret) {
  timer_reset(ret);
  ret->tv_usec = timer_a->tv_usec + timer_b->tv_usec;
  ret->tv_sec = timer_a->tv_sec + timer_b->tv_sec;
  if (ret->tv_usec >= 1000000) {
    ret->tv_usec -= 1000000;
    ret->tv_sec += 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bgp_route_next_until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <bgp_node_to_rnode@plt>
  mov    %eax,%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <bgp_node_to_rnode@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <route_next_until@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bgp_node_from_rnode@plt>
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct bgp_node *bgp_route_next_until(struct bgp_node *node, struct bgp_node *limit) {
  struct route_node *rnode;
  rnode = route_next_until(bgp_node_to_rnode(node), bgp_node_to_rnode(limit));
  return bgp_node_from_rnode(rnode);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bgp_route_next_until>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <bgp_node_to_rnode@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <bgp_node_to_rnode@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <route_next_until@plt>
  mov    %rax,%rdi
  call   <bgp_node_from_rnode@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct bgp_node *bgp_route_next_until(struct bgp_node *node, struct bgp_node *limit) {
  struct route_node *rnode;
  rnode = route_next_until(bgp_node_to_rnode(node), bgp_node_to_rnode(limit));
  return bgp_node_from_rnode(rnode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bgp_route_next_until>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <bgp_node_to_rnode@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <bgp_node_to_rnode@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <route_next_until@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1090 <bgp_node_from_rnode@plt>
```

assistant: ```c
struct bgp_node *bgp_route_next_until(struct bgp_node *node, struct bgp_node *limit) {
  struct route_node *rnode;
  rnode = route_next_until(bgp_node_to_rnode(node), bgp_node_to_rnode(limit));
  return bgp_node_from_rnode(rnode);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bgp_route_next_until>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  sub    $0x8,%rsp
  call   <bgp_node_to_rnode@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <bgp_node_to_rnode@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <route_next_until@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %rax,%rdi
  pop    %r12
  jmp    1090 <bgp_node_from_rnode@plt>
```

assistant: ```c
struct bgp_node *bgp_route_next_until(struct bgp_node *node, struct bgp_node *limit) {
  struct route_node *rnode;
  rnode = route_next_until(bgp_node_to_rnode(node), bgp_node_to_rnode(limit));
  return bgp_node_from_rnode(rnode);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movl   $0x0,-0x28(%rbp)
  jmp    L12
L5:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <f@plt>
  mov    %eax,(%rbx)
L12:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(void) {
  int *x, *y;
  int N;
  for (int j = 0; j < N;) {
    x[j] = f(y[j]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *x, *y;
  int N;
  for (int j = 0; j < N;) {
    x[j] = f(y[j]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *x, *y;
  int N;
  for (int j = 0; j < N;) {
    x[j] = f(y[j]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *x, *y;
  int N;
  for (int j = 0; j < N;) {
    x[j] = f(y[j]);
  }
}
```