ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_send_pulse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
L25:
  movzwl %bx,%esi
  or     $0xb0000,%esi
  mov    %esi,(%rdi)
  mov    $0x1,%esi
  call   <conv32network_endian@plt>
  mov    $0x4,%eax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    $0xffffffffffffffff,%rax
  test   %rdi,%rdi
  je     L24
  mov    %rdi,0x0(%rbp)
  jmp    L25
```

assistant: ```c
size_t cmd_send_pulse(uint32_t **bufio, uint32_t mask) {
  uint32_t *buf;
  buf = *bufio;
  if (buf == NULL) {
    buf = (uint32_t *)calloc(1, sizeof(uint32_t));
    if (buf == NULL)
      return -1;
    *bufio = buf;
  }
  buf[0] = 0x000b0000 | (0x0000ffff & mask);
  conv32network_endian(buf, 1);
  return 1 * sizeof(uint32_t);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_send_pulse>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
L28:
  movzwl %bx,%esi
  or     $0xb0000,%esi
  mov    %esi,(%rdi)
  mov    $0x1,%esi
  call   <conv32network_endian@plt>
  mov    $0x4,%eax
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    $0xffffffffffffffff,%rax
  test   %rdi,%rdi
  je     L24
  mov    %rdi,0x0(%rbp)
  jmp    L28
```

assistant: ```c
size_t cmd_send_pulse(uint32_t **bufio, uint32_t mask) {
  uint32_t *buf;
  buf = *bufio;
  if (buf == NULL) {
    buf = (uint32_t *)calloc(1, sizeof(uint32_t));
    if (buf == NULL)
      return -1;
    *bufio = buf;
  }
  buf[0] = 0x000b0000 | (0x0000ffff & mask);
  conv32network_endian(buf, 1);
  return 1 * sizeof(uint32_t);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<owal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L10
  cmpl   $0x5,-0x4(%rbp)
  jne    L54
L10:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L54:
  cmpl   $0x1,-0x4(%rbp)
  je     L41
  cmpl   $0x4,-0x4(%rbp)
  jne    L16
L41:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L16:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L2:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D22
type_infered: string

tool: D12:   **  


tool: D6:  *  * 


tool: D22: *    *


assistant: ```c
void owal(int linia) {
  if (linia == 0 || linia == 5) {
    printf("  **  \n");
  } else if (linia == 1 || linia == 4) {
    printf(" *  * \n");
  } else {
    printf("*    *\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<owal>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L14
  cmp    $0x5,%edi
  je     L14
  cmp    $0x1,%edi
  je     L31
  cmp    $0x4,%edi
  je     L31
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L14:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L31:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D22: *    *


tool: D1:   **  


tool: D4:  *  * 


assistant: ```c
void owal(int linia) {
  if (linia == 0 || linia == 5) {
    printf("  **  \n");
  } else if (linia == 1 || linia == 4) {
    printf(" *  * \n");
  } else {
    printf("*    *\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<owal>:
  endbr64
  test   %edi,%edi
  je     L34
  cmp    $0x5,%edi
  je     L34
  cmp    $0x1,%edi
  je     L28
  cmp    $0x4,%edi
  je     L28
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L28:
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L34:
  lea    D15(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D15
type_guessed: string

tool: D7: *    *


tool: D1:  *  * 


tool: D15:   **  


assistant: ```c
void owal(int linia) {
  if (linia == 0 || linia == 5) {
    printf("  **  \n");
  } else if (linia == 1 || linia == 4) {
    printf(" *  * \n");
  } else {
    printf("*    *\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<owal>:
  endbr64
  test   %edi,%edi
  je     L17
  cmp    $0x5,%edi
  je     L17
  cmp    $0x1,%edi
  je     L0
  cmp    $0x4,%edi
  je     L0
  lea    D21(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  lea    D10(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L17:
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D21: *    *


tool: D10:  *  * 


tool: D4:   **  


assistant: ```c
void owal(int linia) {
  if (linia == 0 || linia == 5) {
    printf("  **  \n");
  } else if (linia == 1 || linia == 4) {
    printf(" *  * \n");
  } else {
    printf("*    *\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<increment_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void increment_array(char array[], int size) {
  for (int i = 0; i < size; i++)
    array[i] += i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<increment_array>:
  endbr64
  test   %esi,%esi
  jle    L0
  mov    %esi,%esi
  mov    $0x0,%eax
L7:
  add    %al,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L7
L0:
  ret
```

assistant: ```c
void increment_array(char array[], int size) {
  for (int i = 0; i < size; i++)
    array[i] += i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<increment_array>:
  endbr64
  test   %esi,%esi
  jle    L15
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   (%rax)
L3:
  add    %al,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L3
L15:
  ret
```

assistant: ```c
void increment_array(char array[], int size) {
  for (int i = 0; i < size; i++)
    array[i] += i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jelio_itostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L54
  cmpl   $0x24,-0x24(%rbp)
  jbe    L55
L54:
  movl   $0xa,-0x24(%rbp)
L55:
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jns    L46
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
L46:
  cmpl   $0x0,-0x20(%rbp)
  jne    L80
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x30,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L80
L40:
  subq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x24(%rbp)
  mov    %edx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L99
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x7,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L99:
  mov    -0x20(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x24(%rbp)
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L80:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L28
  cmpl   $0x0,-0x20(%rbp)
  jne    L40
L28:
  cmpl   $0x0,-0xc(%rbp)
  je     L57
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L57
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  addl   $0x1,-0x10(%rbp)
L57:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int jelio_itostr(char *s, unsigned int size, int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = abs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jelio_itostr>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %ecx,%edi
  lea    -0x1(%rsi),%r9d
  add    %r8,%r9
  movb   $0x0,(%r9)
  lea    -0x1(%rcx),%eax
  cmp    $0x24,%eax
  mov    $0xa,%eax
  cmovae %eax,%edi
  test   %edx,%edx
  js     L68
  jne    L104
  lea    -0x1(%r9),%rax
  movb   $0x30,-0x1(%r9)
  mov    $0x1,%ebx
L45:
  lea    0x1(%rbx),%edx
  mov    %rax,%rsi
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L68:
  mov    %edx,%eax
  neg    %eax
  cmovns %eax,%edx
  mov    $0x1,%r10d
L20:
  cmp    %r8,%r9
  seta   %cl
  test   %edx,%edx
  je     L87
  test   %cl,%cl
  je     L87
  mov    %r9,%rsi
L118:
  sub    $0x1,%rsi
  mov    %edx,%ecx
  mov    %edx,%eax
  mov    $0x0,%edx
  div    %edi
  lea    0x30(%rdx),%eax
  add    $0x37,%edx
  cmp    $0x3a,%al
  cmovge %edx,%eax
  mov    %al,(%rsi)
  mov    %ecx,%eax
  mov    $0x0,%edx
  div    %edi
  mov    %eax,%edx
  mov    %r9d,%ebx
  sub    %esi,%ebx
  cmp    %rsi,%r8
  setb   %cl
  test   %eax,%eax
  je     L88
  test   %cl,%cl
  jne    L118
L88:
  test   %r10d,%r10d
  je     L117
  test   %cl,%cl
  je     L117
  lea    -0x1(%rsi),%rax
  movb   $0x2d,-0x1(%rsi)
  add    $0x1,%ebx
  jmp    L45
L104:
  mov    $0x0,%r10d
  jmp    L20
L87:
  mov    %r9,%rsi
  mov    $0x0,%ebx
  jmp    L88
L117:
  mov    %rsi,%rax
  jmp    L45
```

assistant: ```c
int jelio_itostr(char *s, unsigned int size, int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = abs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<jelio_itostr>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%eax
  lea    -0x1(%rsi),%r9d
  mov    %ecx,%edi
  lea    -0x1(%rcx),%edx
  add    %r8,%r9
  push   %r12
  cmp    $0x24,%edx
  mov    $0xa,%edx
  movb   $0x0,(%r9)
  cmovae %edx,%edi
  test   %eax,%eax
  js     L18
  jne    L108
  movb   $0x30,-0x1(%r9)
  lea    -0x1(%r9),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%edx
L69:
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  neg    %eax
  cmp    %r8,%r9
  mov    $0x1,%r10d
  seta   %dl
  jbe    L9
L106:
  mov    %r9,%rcx
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %edx,%edx
  sub    $0x1,%rcx
  div    %edi
  lea    0x30(%rdx),%esi
  add    $0x37,%edx
  cmp    $0x3a,%sil
  cmovae %edx,%esi
  mov    %sil,(%rcx)
  mov    %r9d,%esi
  sub    %ecx,%esi
  cmp    %rcx,%r8
  setb   %dl
  test   %eax,%eax
  je     L27
  test   %dl,%dl
  jne    L37
L27:
  lea    0x1(%rsi),%eax
L68:
  test   %dl,%dl
  je     L100
  test   %r10b,%r10b
  je     L100
  movb   $0x2d,-0x1(%rcx)
  mov    %eax,%r12d
  lea    -0x1(%rcx),%rsi
  lea    0x1(%rax),%edx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L108:
  cmp    %r8,%r9
  jbe    L97
  xor    %r10d,%r10d
  jmp    L106
L9:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L68
L97:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
L100:
  mov    %esi,%r12d
  mov    %eax,%edx
  mov    %rcx,%rsi
  jmp    L69
```

assistant: ```c
int jelio_itostr(char *s, unsigned int size, int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = abs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: What is the c source code of the assembly code below?

```asm
<jelio_itostr>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%eax
  lea    -0x1(%rsi),%r9d
  mov    %ecx,%edi
  lea    -0x1(%rcx),%edx
  add    %r8,%r9
  push   %r12
  cmp    $0x24,%edx
  mov    $0xa,%edx
  movb   $0x0,(%r9)
  cmovae %edx,%edi
  test   %eax,%eax
  js     L24
  jne    L4
  movb   $0x30,-0x1(%r9)
  lea    -0x1(%r9),%rsi
  mov    $0x1,%r12d
  mov    $0x2,%edx
L95:
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  neg    %eax
  cmp    %r8,%r9
  mov    $0x1,%r10d
  seta   %dl
  jbe    L41
L82:
  mov    %r9,%rcx
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %edx,%edx
  sub    $0x1,%rcx
  div    %edi
  lea    0x30(%rdx),%esi
  add    $0x37,%edx
  cmp    $0x39,%sil
  cmovbe %esi,%edx
  mov    %r9d,%esi
  sub    %ecx,%esi
  cmp    %rcx,%r8
  mov    %dl,(%rcx)
  setb   %dl
  test   %eax,%eax
  je     L51
  test   %dl,%dl
  jne    L14
L51:
  lea    0x1(%rsi),%eax
  test   %r10b,%r10b
  je     L12
L17:
  test   %dl,%dl
  je     L12
  movb   $0x2d,-0x1(%rcx)
  mov    %eax,%r12d
  lea    -0x1(%rcx),%rsi
  lea    0x1(%rax),%edx
  mov    %r8,%rdi
  call   <memmove@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L4:
  cmp    %r8,%r9
  jbe    L80
  xor    %r10d,%r10d
  jmp    L82
L41:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
  jmp    L17
L80:
  mov    %r9,%rcx
  mov    $0x1,%eax
  xor    %esi,%esi
L12:
  mov    %esi,%r12d
  mov    %eax,%edx
  mov    %rcx,%rsi
  jmp    L95
```

assistant: ```c
int jelio_itostr(char *s, unsigned int size, int i, unsigned int base) {
  char *tmp;
  unsigned int j = 0;
  int neg = 0;
  s[--size] = 0;
  tmp = s + size;
  if ((base == 0) || (base > 36))
    base = 10;
  j = 0;
  if (i < 0) {
    i = abs(i);
    neg = 1;
  }
  if (!i) {
    *(--tmp) = '0';
    j = 1;
  }
  while ((tmp > s) && (i)) {
    tmp--;
    if ((*tmp = i % base + '0') > '9')
      *tmp += ('A') - '9' - 1;
    i = i / base;
    j++;
  }
  if (neg && (tmp > s)) {
    tmp--;
    *tmp = '-';
    j++;
  }
  memmove(s, tmp, j + 1);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<munkle_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x8,-0x4(%rbp)
  jmp    L7
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jg     L2
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: %02x

assistant: ```c
void munkle_print(unsigned char *st, unsigned char *bt) {
  int i;
  for (i = 8; i > (st - bt); i--) {
    printf("%02x", bt[i - 1]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<munkle_print>:
  endbr64
  sub    %rsi,%rdi
  cmp    $0x7,%rdi
  jg     L10
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x7(%rsi),%rbx
  lea    -0x1(%rsi,%rdi,1),%r12
  lea    D8(%rip),%rbp
L15:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: %02x

assistant: ```c
void munkle_print(unsigned char *st, unsigned char *bt) {
  int i;
  for (i = 8; i > (st - bt); i--) {
    printf("%02x", bt[i - 1]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<munkle_print>:
  endbr64
  sub    %rsi,%rdi
  cmp    $0x7,%rdi
  jg     L14
  push   %r12
  lea    -0x1(%rsi,%rdi,1),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  lea    0x7(%rsi),%rbx
  nopl   0x0(%rax)
L16:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: %02x

assistant: ```c
void munkle_print(unsigned char *st, unsigned char *bt) {
  int i;
  for (i = 8; i > (st - bt); i--) {
    printf("%02x", bt[i - 1]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<munkle_print>:
  endbr64
  sub    %rsi,%rdi
  cmp    $0x7,%rdi
  jg     L8
  push   %r12
  lea    -0x1(%rsi,%rdi,1),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  lea    0x7(%rsi),%rbx
  nopl   0x0(%rax)
L9:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: %02x

assistant: ```c
void munkle_print(unsigned char *st, unsigned char *bt) {
  int i;
  for (i = 8; i > (st - bt); i--) {
    printf("%02x", bt[i - 1]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isStringEmpty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  lea    0x4(%rdx),%rcx
  mov    %eax,%edx
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    $0x1,%eax
  jmp    L24
L2:
  mov    $0x0,%eax
L24:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: undefined

assistant: ```c
int32_t isStringEmpty(const char *str) {
  int32_t length = (int32_t)str;
  if (length == 9) {
    int32_t result = strncmp(str + sizeof(int32_t), "undefined", *(int32_t *)str);
    if (result == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isStringEmpty>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x9,%edi
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  lea    0x4(%rdi),%rax
  mov    (%rdi),%edx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: undefined

assistant: ```c
int32_t isStringEmpty(const char *str) {
  int32_t length = (int32_t)str;
  if (length == 9) {
    int32_t result = strncmp(str + sizeof(int32_t), "undefined", *(int32_t *)str);
    if (result == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<isStringEmpty>:
  endbr64
  cmp    $0x9,%edi
  je     L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L6:
  sub    $0x8,%rsp
  lea    0x4(%rdi),%r8
  mov    (%rdi),%edx
  lea    D2(%rip),%rsi
  mov    %r8,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: undefined

assistant: ```c
int32_t isStringEmpty(const char *str) {
  int32_t length = (int32_t)str;
  if (length == 9) {
    int32_t result = strncmp(str + sizeof(int32_t), "undefined", *(int32_t *)str);
    if (result == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isStringEmpty>:
  endbr64
  cmp    $0x9,%edi
  je     L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rsp
  lea    0x4(%rdi),%r8
  mov    (%rdi),%edx
  lea    D5(%rip),%rsi
  mov    %r8,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string

tool: D5: undefined

assistant: ```c
int32_t isStringEmpty(const char *str) {
  int32_t length = (int32_t)str;
  if (length == 9) {
    int32_t result = strncmp(str + sizeof(int32_t), "undefined", *(int32_t *)str);
    if (result == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <pow@plt>
  mov    $0x1,%edx
  sub    %eax,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm2
  movss  D39(%rip),%xmm1
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm1,%xmm3
  movq   %xmm3,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D39
type: byte[4]
name: parse_data
arguments: label: D32
type: string

tool: D3: Enter the first term of the GP then Common Ratio then number of terms.

tool: D33: %f%f%f

tool: {"D39": [0x00,0x00,0x80,0x3f]}

tool: D32: The sum of first %.0f terms is %f


assistant: ```c
void main() {
  float n, r, a, sum;
  printf("Enter the first term of the GP then Common Ratio then number of terms.\n");
  scanf("%f%f%f", &a, &r, &n);
  sum = (a * (1 - pow(r, n))) / (1 - r);
  printf("The sum of first %.0f terms is %f\n", n, sum);
}
```