ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<psoct>:
  endbr64
  mov    %edi,%edx
  xor    %esi,%esi
  test   %edi,%edi
  jns    L5
  neg    %edx
  mov    $0x2d,%esi
L5:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: %c%o

assistant: ```c
psoct(an) {
  register int n, sign;
  sign = 0;
  if ((n = an) < 0) {
    n = -n;
    sign = '-';
  }
  printf("%c%o", sign, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<up_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__up_read@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void up_read(struct rw_semaphore *sem) {
  ;
  __up_read(sem);
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<up_read>:
  endbr64
  sub    $0x8,%rsp
  call   <__up_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((always_)) void up_read(struct rw_semaphore *sem) {
  ;
  __up_read(sem);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<up_read>:
  endbr64
  jmp    1050 <__up_read@plt>
```

assistant: ```c
__attribute__((always_)) void up_read(struct rw_semaphore *sem) {
  ;
  __up_read(sem);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<up_read>:
  endbr64
  jmp    1050 <__up_read@plt>
```

assistant: ```c
__attribute__((always_)) void up_read(struct rw_semaphore *sem) {
  ;
  __up_read(sem);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<imprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x5,-0x4(%rbp)
  jle    L15
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D14
data_type: string

tool: D25: Linha %d 

tool: D29: |%d	

tool: D14:  

assistant: ```c
void imprime(int num[], int lin) {
  int i;
  printf("Linha %d ", lin);
  for (i = 0; i < 6; i++) {
    printf("|%d\t", num[i]);
  }
  printf(" \n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imprime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  add    $0x18,%rbp
  lea    D26(%rip),%r12
L7:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L7
  lea    D29(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string

tool: D2: Linha %d 

tool: D26: |%d	

tool: D29:  

assistant: ```c
void imprime(int num[], int lin) {
  int i;
  printf("Linha %d ", lin);
  for (i = 0; i < 6; i++) {
    printf("|%d\t", num[i]);
  }
  printf(" \n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<imprime>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D13(%rip),%rdi
  lea    0x18(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D9: |%d	

tool: D13: Linha %d 

tool: D0:  

assistant: ```c
void imprime(int num[], int lin) {
  int i;
  printf("Linha %d ", lin);
  for (i = 0; i < 6; i++) {
    printf("|%d\t", num[i]);
  }
  printf(" \n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imprime>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  lea    0x18(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  lea    D8(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string

tool: D3: |%d	

tool: D1: Linha %d 

tool: D8:  

assistant: ```c
void imprime(int num[], int lin) {
  int i;
  printf("Linha %d ", lin);
  for (i = 0; i < 6; i++) {
    printf("|%d\t", num[i]);
  }
  printf(" \n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <Left@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <Right@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L33
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L11
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L52
L11:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L52
L33:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L32
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L32
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L52
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L52
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Swap@plt>
L52:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <Heapify>
  nop
  leave
  ret
```

assistant: ```c
void Heapify(int A[], int i) {
  int l, r, min;
  int heap_size = length(A);
  l = Left(i);
  r = Right(i);
  if (l <= heap_size)
    if (A[l] > A[i])
      min = i;
    else
      min = l;
  else if (r <= heap_size && A[r] < A[min])
    min = r;
  else if (min != i)
    Swap(&A[i], &A[min]);
  Heapify(A, min);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Heapify>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <length@plt>
  mov    %eax,%r13d
  mov    %ebx,%edi
  call   <Left@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <Right@plt>
  cmp    %r12d,%r13d
  jl     L24
  movslq %r12d,%rdx
  movslq %ebx,%rax
  mov    0x0(%rbp,%rax,4),%eax
  cmp    %eax,0x0(%rbp,%rdx,4)
  cmovle %r12d,%ebx
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Heapify>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  cmp    %eax,%r13d
  jl     L14
  movslq %eax,%rcx
  movslq %ebx,%rdx
  mov    0x0(%rbp,%rdx,4),%edx
  cmp    %edx,0x0(%rbp,%rcx,4)
  cmovl  %eax,%ebx
  jmp    L14
```

assistant: ```c
void Heapify(int A[], int i) {
  int l, r, min;
  int heap_size = length(A);
  l = Left(i);
  r = Right(i);
  if (l <= heap_size)
    if (A[l] > A[i])
      min = i;
    else
      min = l;
  else if (r <= heap_size && A[r] < A[min])
    min = r;
  else if (min != i)
    Swap(&A[i], &A[min]);
  Heapify(A, min);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Heapify>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  nopl   (%rax)
L12:
  mov    %r14,%rdi
  call   <length@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <Left@plt>
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <Right@plt>
  cmp    %ebx,%ebp
  jl     L4
  movslq %r12d,%rax
  movslq %ebx,%rdx
  mov    (%r14,%rax,4),%eax
  cmp    %eax,(%r14,%rdx,4)
  cmovle %ebx,%r12d
  jmp    L12
  nopl   0x0(%rax)
L4:
  cmp    %eax,%ebp
  jl     L12
  movslq %eax,%rdx
  mov    0x0(%r13),%ecx
  cmp    %ecx,(%r14,%rdx,4)
  cmovl  %eax,%r12d
  jmp    L12
```

assistant: ```c
void Heapify(int A[], int i) {
  int l, r, min;
  int heap_size = length(A);
  l = Left(i);
  r = Right(i);
  if (l <= heap_size)
    if (A[l] > A[i])
      min = i;
    else
      min = l;
  else if (r <= heap_size && A[r] < A[min])
    min = r;
  else if (min != i)
    Swap(&A[i], &A[min]);
  Heapify(A, min);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Heapify>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  nopl   (%rax)
L35:
  mov    %r14,%rdi
  call   <length@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <Left@plt>
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <Right@plt>
  cmp    %ebx,%ebp
  jl     L25
  movslq %r12d,%rax
  movslq %ebx,%rdx
  mov    (%r14,%rax,4),%eax
  cmp    %eax,(%r14,%rdx,4)
  cmovle %ebx,%r12d
  jmp    L35
  nopl   0x0(%rax)
L25:
  cmp    %eax,%ebp
  jl     L35
  movslq %eax,%rdx
  mov    0x0(%r13),%ecx
  cmp    %ecx,(%r14,%rdx,4)
  cmovl  %eax,%r12d
  jmp    L35
```

assistant: ```c
void Heapify(int A[], int i) {
  int l, r, min;
  int heap_size = length(A);
  l = Left(i);
  r = Right(i);
  if (l <= heap_size)
    if (A[l] > A[i])
      min = i;
    else
      min = l;
  else if (r <= heap_size && A[r] < A[min])
    min = r;
  else if (min != i)
    Swap(&A[i], &A[min]);
  Heapify(A, min);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L38
  mov    $0x0,%ecx
  mov    -0x18(%rbp),%rax
  mulq   -0x20(%rbp)
  jno    L28
  mov    $0x1,%ecx
L28:
  mov    %rcx,%rax
  test   %rax,%rax
  je     L38
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L63
L38:
  mov    -0x20(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L63
L44:
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L49
  mov    -0x20(%rbp),%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L78
L27:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L18
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
L18:
  subq   $0x1,-0x18(%rbp)
  addq   $0x8,-0x10(%rbp)
L78:
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
L49:
  mov    -0x8(%rbp),%rax
L63:
  leave
  ret
```

assistant: ```c
void *calloc(size_t m, size_t n) {
  void *p;
  size_t *z;
  if (n && m > (size_t)-1 / n) {
    errno = ENOMEM;
    return 0;
  }
  n *= m;
  p = malloc(n);
  if (!p)
    return 0;
  if (((size_t *)p)[-1] & 7) {
    m = (n + sizeof *z - 1) / sizeof *z;
    for (z = p; m; m--, z++)
      if (*z)
        *z = 0;
  }
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calloc>:
  endbr64
  test   %rsi,%rsi
  je     L47
  mov    %rdi,%rax
  mul    %rsi
  jo     L76
L47:
  push   %rbx
  mov    %rsi,%rbx
  imul   %rdi,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L74
  testb  $0x7,-0x8(%rax)
  je     L74
  lea    0x7(%rbx),%rsi
  mov    %rsi,%rcx
  shr    $0x3,%rcx
  cmp    $0x7,%rsi
  jbe    L74
  mov    %rax,%rdx
  jmp    L20
L76:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
L42:
  add    $0x8,%rdx
  sub    $0x1,%rcx
  je     L74
L20:
  cmpq   $0x0,(%rdx)
  je     L42
  movq   $0x0,(%rdx)
  jmp    L42
L74:
  pop    %rbx
  ret
```

assistant: ```c
void *calloc(size_t m, size_t n) {
  void *p;
  size_t *z;
  if (n && m > (size_t)-1 / n) {
    errno = ENOMEM;
    return 0;
  }
  n *= m;
  p = malloc(n);
  if (!p)
    return 0;
  if (((size_t *)p)[-1] & 7) {
    m = (n + sizeof *z - 1) / sizeof *z;
    for (z = p; m; m--, z++)
      if (*z)
        *z = 0;
  }
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<calloc>:
  endbr64
  test   %rsi,%rsi
  je     L30
  mov    %rdi,%rax
  mul    %rsi
  jo     L69
L30:
  push   %rbx
  mov    %rsi,%rbx
  imul   %rdi,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  testb  $0x7,-0x8(%rax)
  je     L0
  lea    0x7(%rbx),%rsi
  shr    $0x3,%rsi
  je     L0
  lea    (%rax,%rsi,8),%rcx
  mov    %rax,%rdx
  nopl   (%rax)
L11:
  cmpq   $0x0,(%rdx)
  je     L1
  movq   $0x0,(%rdx)
L1:
  add    $0x8,%rdx
  cmp    %rdx,%rcx
  jne    L11
L0:
  pop    %rbx
  ret
L69:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
void *calloc(size_t m, size_t n) {
  void *p;
  size_t *z;
  if (n && m > (size_t)-1 / n) {
    errno = ENOMEM;
    return 0;
  }
  n *= m;
  p = malloc(n);
  if (!p)
    return 0;
  if (((size_t *)p)[-1] & 7) {
    m = (n + sizeof *z - 1) / sizeof *z;
    for (z = p; m; m--, z++)
      if (*z)
        *z = 0;
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calloc>:
  endbr64
  test   %rsi,%rsi
  je     L24
  mov    %rdi,%rax
  mul    %rsi
  jo     L42
L24:
  push   %rbx
  mov    %rsi,%rbx
  imul   %rdi,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L32
  testb  $0x7,-0x8(%rax)
  je     L32
  lea    0x7(%rbx),%rsi
  shr    $0x3,%rsi
  je     L32
  lea    (%rax,%rsi,8),%rcx
  mov    %rax,%rdx
  nopl   (%rax)
L67:
  cmpq   $0x0,(%rdx)
  je     L69
  movq   $0x0,(%rdx)
L69:
  add    $0x8,%rdx
  cmp    %rdx,%rcx
  jne    L67
L32:
  pop    %rbx
  ret
L42:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
void *calloc(size_t m, size_t n) {
  void *p;
  size_t *z;
  if (n && m > (size_t)-1 / n) {
    errno = ENOMEM;
    return 0;
  }
  n *= m;
  p = malloc(n);
  if (!p)
    return 0;
  if (((size_t *)p)[-1] & 7) {
    m = (n + sizeof *z - 1) / sizeof *z;
    for (z = p; m; m--, z++)
      if (*z)
        *z = 0;
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sim_pthread_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edi
  call   <removeentry@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_exit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((noreturn)) sim_pthread_exit(void *value_ptr) {
  removeentry(pthread_self());
  pthread_exit(value_ptr);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sim_pthread_exit>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edi
  call   <removeentry@plt>
  mov    %rbx,%rdi
  call   <pthread_exit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) sim_pthread_exit(void *value_ptr) {
  removeentry(pthread_self());
  pthread_exit(value_ptr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sim_pthread_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %eax,%edi
  call   <removeentry@plt>
  mov    %rbp,%rdi
  call   <pthread_exit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) sim_pthread_exit(void *value_ptr) {
  removeentry(pthread_self());
  pthread_exit(value_ptr);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sim_pthread_exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <pthread_self@plt>
  mov    %eax,%edi
  call   <removeentry@plt>
  mov    %rbp,%rdi
  call   <pthread_exit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

assistant: ```c
void __attribute__((noreturn)) sim_pthread_exit(void *value_ptr) {
  removeentry(pthread_self());
  pthread_exit(value_ptr);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmStep3fv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L34
L33:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jb     L25
  movss  D2(%rip),%xmm0
  jmp    L37
L25:
  pxor   %xmm0,%xmm0
L37:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L34:
  cmpq   $0x2,-0x8(%rbp)
  jbe    L33
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmStep3fv(float out[3], const float x[3], const float edge[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] >= edge[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glmStep3fv>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm3,%xmm3
L1:
  movss  (%rsi,%rax,4),%xmm2
  movss  D6(%rip),%xmm1
  movss  (%rdx,%rax,4),%xmm0
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm1
  andnps %xmm3,%xmm0
  orps   %xmm0,%xmm1
  movss  %xmm1,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L1
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmStep3fv(float out[3], const float x[3], const float edge[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] >= edge[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<glmStep3fv>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
L2:
  movss  (%rsi,%rax,4),%xmm2
  movss  (%rdx,%rax,4),%xmm0
  movss  D8(%rip),%xmm1
  cmpless %xmm2,%xmm0
  andps  %xmm0,%xmm1
  andnps %xmm3,%xmm0
  orps   %xmm0,%xmm1
  movss  %xmm1,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L2
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: byte[4]

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmStep3fv(float out[3], const float x[3], const float edge[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] >= edge[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<glmStep3fv>:
  endbr64
  movss  (%rsi),%xmm1
  comiss (%rdx),%xmm1
  movss  D28(%rip),%xmm0
  jae    L22
  pxor   %xmm0,%xmm0
L22:
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm1
  comiss 0x4(%rdx),%xmm1
  movss  D28(%rip),%xmm0
  jae    L26
  pxor   %xmm0,%xmm0
L26:
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm1
  comiss 0x8(%rdx),%xmm1
  movss  D28(%rip),%xmm0
  jae    L18
  pxor   %xmm0,%xmm0
L18:
  movss  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D28
type_guessed: byte[4]

tool: {"D28": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmStep3fv(float out[3], const float x[3], const float edge[3]) {
  for (size_t i = 0; i < 3; ++i)
    out[i] = x[i] >= edge[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imprimir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L30:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0xe,-0x4(%rbp)
  jle    L1
  addl   $0x1,-0x8(%rbp)
L38:
  cmpl   $0xe,-0x8(%rbp)
  jle    L30
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type: string
name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D29
type: string

tool: D19: CLS

tool: D18: 
		

tool: D29: 

	 Direccion = %d

assistant: ```c
void imprimir(int mapa[15][15], int d) {
  int i, j;
  system("CLS");
  for (i = 0; i < 15; i++) {
    printf("\n\t\t");
    for (j = 0; j < 15; j++) {
      printf("%c", mapa[i][j]);
    }
  }
  printf("\n\n\t Direccion = %d", d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imprimir>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r14d
  lea    D20(%rip),%rdi
  call   <system@plt>
  lea    0x3c(%r12),%rbp
  add    $0x3c0,%r12
  lea    D0(%rip),%r13
L18:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3c(%rbp),%rbx
L4:
  mov    (%rbx),%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L4
  add    $0x3c,%rbp
  cmp    %r12,%rbp
  jne    L18
  mov    %r14d,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string

tool: D20: CLS

tool: D0: 
		

tool: D26: 

	 Direccion = %d

assistant: ```c
void imprimir(int mapa[15][15], int d) {
  int i, j;
  system("CLS");
  for (i = 0; i < 15; i++) {
    printf("\n\t\t");
    for (j = 0; j < 15; j++) {
      printf("%c", mapa[i][j]);
    }
  }
  printf("\n\n\t Direccion = %d", d);
}
```