ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<gmx_within_tol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   D26(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D20(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  -0x8(%rbp),%xmm0
  movq   D26(%rip),%xmm3
  andpd  %xmm0,%xmm3
  movsd  -0x10(%rbp),%xmm0
  movq   D26(%rip),%xmm4
  andpd  %xmm4,%xmm0
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  jb     L2
  mov    $0x1,%eax
  jmp    L17
L2:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
type: qword
name: parse_data
arguments: data_tag: D20
type: f64

tool: D26: 9223372036854775807

tool: D20: 0.5

assistant: ```c
int gmx_within_tol(double f1, double f2, double tol) {
  if (fabs(f1 - f2) <= tol * 0.5 * (fabs(f1) + fabs(f2))) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gmx_within_tol>:
  endbr64
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  movq   D0(%rip),%xmm4
  andpd  %xmm4,%xmm3
  andpd  %xmm4,%xmm0
  andpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  comisd %xmm3,%xmm0
  setae  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: qword
name: unpack_data
arguments: tag: D5
type_guessed: f64

tool: D0: 9223372036854775807

tool: D5: 0.5

assistant: ```c
int gmx_within_tol(double f1, double f2, double tol) {
  if (fabs(f1 - f2) <= tol * 0.5 * (fabs(f1) + fabs(f2))) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gmx_within_tol>:
  endbr64
  movq   D9(%rip),%xmm4
  mulsd  D10(%rip),%xmm2
  movapd %xmm0,%xmm3
  xor    %eax,%eax
  subsd  %xmm1,%xmm3
  andpd  %xmm4,%xmm0
  andpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  andpd  %xmm4,%xmm3
  mulsd  %xmm2,%xmm0
  comisd %xmm3,%xmm0
  setae  %al
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: qword
name: unpack_data
arguments: tag: D10
type_guessed: f64

tool: D9: 9223372036854775807

tool: D10: 0.5

assistant: ```c
int gmx_within_tol(double f1, double f2, double tol) {
  if (fabs(f1 - f2) <= tol * 0.5 * (fabs(f1) + fabs(f2))) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gmx_within_tol>:
  endbr64
  movq   D19(%rip),%xmm4
  mulsd  D8(%rip),%xmm2
  movapd %xmm0,%xmm3
  xor    %eax,%eax
  subsd  %xmm1,%xmm3
  andpd  %xmm4,%xmm0
  andpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  andpd  %xmm4,%xmm3
  mulsd  %xmm2,%xmm0
  comisd %xmm3,%xmm0
  setae  %al
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: qword
name: read_data
arguments: data_label: D8
type_infered: f64

tool: D19: 9223372036854775807

tool: D8: 0.5

assistant: ```c
int gmx_within_tol(double f1, double f2, double tol) {
  if (fabs(f1 - f2) <= tol * 0.5 * (fabs(f1) + fabs(f2))) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D3: [slave 1] called with

tool: D8:  %s

assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("[slave 1] called with");
  for (i = 1; i < argc; ++i) {
    printf(" %s", argv[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L8
  lea    0x8(%r12),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r12,%rax,8),%r12
  lea    D15(%rip),%rbp
L12:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L12
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D14: [slave 1] called with

tool: D15:  %s

assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("[slave 1] called with");
  for (i = 1; i < argc; ++i) {
    printf(" %s", argv[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D4(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L14
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    D8(%rip),%rbp
  lea    0x10(%r12,%rax,8),%r12
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D4: [slave 1] called with

tool: D8:  %s

assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("[slave 1] called with");
  for (i = 1; i < argc; ++i) {
    printf(" %s", argv[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  push   %rbx
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L12
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    D12(%rip),%rbp
  lea    0x10(%r12,%rax,8),%r12
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D12
type_guessed: string

tool: D9: [slave 1] called with

tool: D12:  %s

assistant: ```c
int main(int argc, char **argv) {
  int i;
  printf("[slave 1] called with");
  for (i = 1; i < argc; ++i) {
    printf(" %s", argv[i]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xb8(%rbp)
  movl   $0x0,-0xb4(%rbp)
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L5
L126:
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  cmp    $0x7a,%eax
  jg     L135
  cmp    $0x71,%eax
  jge    L63
  cmp    $0x20,%eax
  je     L179
  cmp    $0x20,%eax
  jl     L135
  cmp    $0x70,%eax
  jg     L135
  cmp    $0x61,%eax
  jge    L150
  jmp    L135
L63:
  sub    $0x71,%eax
  cmp    $0x9,%eax
  ja     L135
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D35(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D35(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L150:
  sub    $0x61,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0x9249,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L179
  mov    %rax,%rdx
  and    $0x4924,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L96
  and    $0x2492,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L37
  jmp    L135
L179:
  addl   $0x1,-0xb4(%rbp)
  jmp    L135
L37:
  addl   $0x2,-0xb4(%rbp)
  jmp    L135
L96:
  addl   $0x3,-0xb4(%rbp)
  jmp    L135
  addl   $0x4,-0xb4(%rbp)
  nop
L135:
  addl   $0x1,-0xb8(%rbp)
L5:
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xb8(%rbp)
  jle    L126
  mov    -0xb4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L176
  call   <__stack_chk_fail@plt>
L176:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D7: %[^
]s

tool: D13: %d 


assistant: ```c
int main() {
  int i = 0, button = 0;
  char txt[160];
  scanf("%[^\n]s", txt);
  while (i <= strlen(txt)) {
    switch (txt[i]) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      button++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      button = button + 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      button = button + 3;
      break;
    case 's':
    case 'z':
      button = button + 4;
      break;
    }
    i++;
  }
  printf("%d \n", button);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D22(%rip),%rbp
  jmp    L120
L44:
  cmp    $0x60,%cl
  jg     L129
  cmp    $0x20,%cl
  je     L41
L5:
  add    $0x1,%rbx
L120:
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L91
  movzbl (%rsp,%rbx,1),%ecx
  cmp    $0x70,%cl
  jle    L44
  lea    -0x71(%rcx),%eax
  cmp    $0x9,%al
  ja     L5
  sub    $0x71,%ecx
  cmp    $0x9,%cl
  ja     L5
  movzbl %cl,%ecx
  movslq 0x0(%rbp,%rcx,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
L129:
  sub    $0x61,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0x9249,%eax
  jne    L41
  test   $0x4924,%eax
  jne    L72
  test   $0x2492,%eax
  je     L5
  add    $0x2,%r12d
  jmp    L5
L41:
  add    $0x1,%r12d
  jmp    L5
L72:
  add    $0x3,%r12d
  jmp    L5
  add    $0x4,%r12d
  jmp    L5
L91:
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D27: %[^
]s

tool: D1: %d 


assistant: ```c
int main() {
  int i = 0, button = 0;
  char txt[160];
  scanf("%[^\n]s", txt);
  while (i <= strlen(txt)) {
    switch (txt[i]) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      button++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      button = button + 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      button = button + 3;
      break;
    case 's':
    case 'z':
      button = button + 4;
      break;
    }
    i++;
  }
  printf("%d \n", button);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D29(%rip),%rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <scanf@plt>
  jmp    L82
  nopl   0x0(%rax)
L32:
  cmp    $0x60,%cl
  jg     L48
  cmp    $0x20,%cl
  je     L119
L137:
  add    $0x1,%r12
L82:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L4
  movzbl 0x0(%r13,%r12,1),%ecx
  cmp    $0x70,%cl
  jle    L32
  lea    -0x71(%rcx),%eax
  cmp    $0x9,%al
  ja     L137
  sub    $0x72,%ecx
  cmp    $0x8,%cl
  ja     L64
  movzbl %cl,%ecx
  movslq (%rbx,%rcx,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x3,%ebp
  jmp    L137
  nopl   (%rax)
L119:
  add    $0x1,%ebp
  jmp    L137
  nopl   (%rax)
  add    $0x4,%ebp
  jmp    L137
  nopl   (%rax)
L48:
  sub    $0x61,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0x9249,%eax
  jne    L119
  test   $0x4924,%eax
  jne    L15
  test   $0x2492,%eax
  je     L137
L64:
  add    $0x2,%ebp
  jmp    L137
  nopl   (%rax)
L4:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D15: %[^
]s

tool: D16: %d 


assistant: ```c
int main() {
  int i = 0, button = 0;
  char txt[160];
  scanf("%[^\n]s", txt);
  while (i <= strlen(txt)) {
    switch (txt[i]) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      button++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      button = button + 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      button = button + 3;
      break;
    case 's':
    case 'z':
      button = button + 4;
      break;
    }
    i++;
  }
  printf("%d \n", button);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%rdi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D13(%rip),%rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <scanf@plt>
  jmp    L115
  nopl   0x0(%rax)
L118:
  cmp    $0x60,%cl
  jg     L10
  cmp    $0x20,%cl
  je     L91
L140:
  add    $0x1,%r12
L115:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jl     L101
  movzbl 0x0(%r13,%r12,1),%ecx
  cmp    $0x70,%cl
  jle    L118
  lea    -0x71(%rcx),%eax
  cmp    $0x9,%al
  ja     L140
  sub    $0x72,%ecx
  cmp    $0x8,%cl
  ja     L57
  movzbl %cl,%ecx
  movslq (%rbx,%rcx,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L128:
  add    $0x3,%ebp
  jmp    L140
  nopl   (%rax)
L91:
  add    $0x1,%ebp
  jmp    L140
  nopl   (%rax)
  add    $0x4,%ebp
  jmp    L140
  nopl   (%rax)
L10:
  sub    $0x61,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   $0x9249,%eax
  jne    L91
  test   $0x4924,%eax
  jne    L128
  test   $0x2492,%eax
  je     L140
L57:
  add    $0x2,%ebp
  jmp    L140
  nopl   (%rax)
L101:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0xb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D4: %[^
]s

tool: D1: %d 


assistant: ```c
int main() {
  int i = 0, button = 0;
  char txt[160];
  scanf("%[^\n]s", txt);
  while (i <= strlen(txt)) {
    switch (txt[i]) {
    case 'a':
    case 'd':
    case 'g':
    case 'j':
    case 'm':
    case 'p':
    case 't':
    case 'w':
    case ' ':
      button++;
      break;
    case 'b':
    case 'e':
    case 'h':
    case 'k':
    case 'n':
    case 'q':
    case 'u':
    case 'x':
      button = button + 2;
      break;
    case 'c':
    case 'f':
    case 'i':
    case 'l':
    case 'o':
    case 'r':
    case 'v':
    case 'y':
      button = button + 3;
      break;
    case 's':
    case 'z':
      button = button + 4;
      break;
    }
    i++;
  }
  printf("%d \n", button);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2728(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L5
L6:
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2724(%rbp)
  mov    -0x2724(%rbp),%edx
  lea    -0x2720(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <plndrm@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0x2728(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2728(%rbp)
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string
name: unpack_data
arguments: data_label: D29
type_guessed: string

tool: D2: %d

tool: D12: %s

tool: D29: %d


assistant: ```c
int main() {
  int i, t, n, j, k, l;
  char s[10001];
  scanf("%d", &t);
  while (t--) {
    scanf("%s", s);
    l = strlen(s);
    printf("%d\n", plndrm(s, l));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L18
  lea    0x10(%rsp),%rbx
  lea    D21(%rip),%r12
  lea    D29(%rip),%rbp
L11:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <plndrm@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L11
L18:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x2730,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string

tool: D3: %d

tool: D21: %s

tool: D29: %d


assistant: ```c
int main() {
  int i, t, n, j, k, l;
  char s[10001];
  scanf("%d", &t);
  while (t--) {
    scanf("%s", s);
    l = strlen(s);
    printf("%d\n", plndrm(s, l));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L8
  lea    0x10(%rsp),%rbx
  lea    D2(%rip),%r12
  lea    D7(%rip),%rbp
  nopl   (%rax)
L3:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <plndrm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L3
L8:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2730,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string

tool: D19: %d

tool: D2: %s

tool: D7: %d


assistant: ```c
int main() {
  int i, t, n, j, k, l;
  char s[10001];
  scanf("%d", &t);
  while (t--) {
    scanf("%s", s);
    l = strlen(s);
    printf("%d\n", plndrm(s, l));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L23
  lea    0x10(%rsp),%rbx
  lea    D17(%rip),%r12
  lea    D14(%rip),%rbp
  nopl   (%rax)
L19:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <plndrm@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L19
L23:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x2730,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D20: %d

tool: D17: %s

tool: D14: %d


assistant: ```c
int main() {
  int i, t, n, j, k, l;
  char s[10001];
  scanf("%d", &t);
  while (t--) {
    scanf("%s", s);
    l = strlen(s);
    printf("%d\n", plndrm(s, l));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <usage@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int run_help(int argc, char **argv, void *st_options) {
  struct st_options *o = st_options;
  usage(argc, argv, o);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<run_help>:
  endbr64
  sub    $0x8,%rsp
  call   <usage@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int run_help(int argc, char **argv, void *st_options) {
  struct st_options *o = st_options;
  usage(argc, argv, o);
  return 0;
}
```