ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<alloc2d>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L0
  mov    %rax,%rbx
  lea    (%rax,%r12,8),%r12
  nop
L2:
  mov    $0x4,%esi
  mov    %ebp,%edi
  add    $0x8,%rbx
  call   <calloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L2
L0:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **alloc2d(int m, int n) {
  int **res = (int **)calloc(m, sizeof(int *));
  int i;
  for (i = 0; i < m; i++) {
    res[i] = (int *)calloc(n, sizeof(int));
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<numJewelsInStones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x9c(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movw   $0x0,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  movl   $0x0,-0x98(%rbp)
  jmp    L48
L28:
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movslq %eax,%rdx
  movzbl -0x90(%rbp,%rdx,1),%edx
  add    $0x1,%edx
  cltq
  mov    %dl,-0x90(%rbp,%rax,1)
  addl   $0x1,-0x98(%rbp)
L48:
  mov    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x98(%rbp)
  jl     L28
  movl   $0x0,-0x94(%rbp)
  jmp    L30
L14:
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xa8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  movzbl %al,%eax
  add    %eax,-0x9c(%rbp)
  addl   $0x1,-0x94(%rbp)
L30:
  mov    -0xa8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x94(%rbp)
  jl     L14
  mov    -0x9c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int numJewelsInStones(char *J, char *S) {
  int cnt = 0;
  unsigned char arr['z' + 1] = {0};
  for (int i = 0; i < strlen(S); i++) {
    arr[S[i]]++;
  }
  for (int i = 0; i < strlen(J); i++) {
    cnt += arr[J[i]];
  }
  return cnt;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<numJewelsInStones>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movw   $0x0,0x78(%rsp)
  movb   $0x0,0x7a(%rsp)
  mov    $0x0,%ebx
  jmp    L35
L41:
  movsbq (%r12,%rbx,1),%rax
  addb   $0x1,(%rsp,%rax,1)
  add    $0x1,%rbx
L35:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L41
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L7
L5:
  movsbq 0x0(%rbp,%rbx,1),%rax
  movzbl (%rsp,%rax,1),%eax
  add    %eax,%r12d
  add    $0x1,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    %r12d,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numJewelsInStones(char *J, char *S) {
  int cnt = 0;
  unsigned char arr['z' + 1] = {0};
  for (int i = 0; i < strlen(S); i++) {
    arr[S[i]]++;
  }
  for (int i = 0; i < strlen(J); i++) {
    cnt += arr[J[i]];
  }
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<numJewelsInStones>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x7a(%rsp)
  movq   $0x0,0x70(%rsp)
  mov    %ax,0x78(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L37:
  movsbq (%r12,%rbx,1),%rax
  add    $0x1,%rbx
  addb   $0x1,(%rsp,%rax,1)
L13:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L37
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L36
L38:
  movsbq 0x0(%rbp,%rbx,1),%rax
  add    $0x1,%rbx
  movzbl (%rsp,%rax,1),%eax
  add    %eax,%r12d
L36:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L38
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x90,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numJewelsInStones(char *J, char *S) {
  int cnt = 0;
  unsigned char arr['z' + 1] = {0};
  for (int i = 0; i < strlen(S); i++) {
    arr[S[i]]++;
  }
  for (int i = 0; i < strlen(J); i++) {
    cnt += arr[J[i]];
  }
  return cnt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<numJewelsInStones>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x7a(%rsp)
  movq   $0x0,0x70(%rsp)
  mov    %ax,0x78(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L9:
  movsbq (%r12,%rbx,1),%rax
  add    $0x1,%rbx
  addb   $0x1,(%rsp,%rax,1)
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L7
L24:
  movsbq 0x0(%rbp,%rbx,1),%rax
  add    $0x1,%rbx
  movzbl (%rsp,%rax,1),%eax
  add    %eax,%r12d
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L24
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x90,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numJewelsInStones(char *J, char *S) {
  int cnt = 0;
  unsigned char arr['z' + 1] = {0};
  for (int i = 0; i < strlen(S); i++) {
    arr[S[i]]++;
  }
  for (int i = 0; i < strlen(J); i++) {
    cnt += arr[J[i]];
  }
  return cnt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movabs $0x7665206f6c6c6568,%rax
  movabs $0x21656e6f797265,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: write fd = %d


assistant: ```c
void *func(void *fd) {
  printf("write fd = %d\n", *(int *)fd);
  char str[] = "hello everyone!";
  write(*(int *)fd, str, strlen(str));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  movabs $0x7665206f6c6c6568,%rax
  movabs $0x21656e6f797265,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: write fd = %d


assistant: ```c
void *func(void *fd) {
  printf("write fd = %d\n", *(int *)fd);
  char str[] = "hello everyone!";
  write(*(int *)fd, str, strlen(str));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    (%rdi),%esi
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  movdqa D11(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  call   <strlen@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: byte[16]

tool: D14: write fd = %d


tool: {"D11": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x65,0x76,0x65,0x72,0x79,0x6f,0x6e,0x65,0x21,0x00]}

assistant: ```c
void *func(void *fd) {
  printf("write fd = %d\n", *(int *)fd);
  char str[] = "hello everyone!";
  write(*(int *)fd, str, strlen(str));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    (%rdi),%esi
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  movdqa D0(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  call   <strlen@plt>
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: byte[16]

tool: D5: write fd = %d


tool: {"D0": [0x68,0x65,0x6c,0x6c,0x6f,0x20,0x65,0x76,0x65,0x72,0x79,0x6f,0x6e,0x65,0x21,0x00]}

assistant: ```c
void *func(void *fd) {
  printf("write fd = %d\n", *(int *)fd);
  char str[] = "hello everyone!";
  write(*(int *)fd, str, strlen(str));
}
```
user: What is the c source code of the assembly code below:

```asm
<httpd_quote_meta>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    (%rax,%rax,2),%rax
  lea    0x1(%rax,%rax,1),%rdi
  lea    D3(%rip),%rcx
  mov    $0xc1e,%edx
  lea    D0(%rip),%rsi
  mov    $0x0,%eax
  call   <aMalloc_@plt>
  cltq
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L28
  lea    0x1(%rbx),%rsi
  mov    %rax,%rcx
  jmp    L106
L59:
  cmp    $0x3e,%dl
  jne    L48
  movl   $0x3b746726,(%rcx)
  add    $0x4,%rcx
  mov    %rsi,%rdi
  jmp    L100
L4:
  movl   $0x3b746c26,(%rcx)
  add    $0x4,%rcx
  mov    %rsi,%rdi
L100:
  movzbl (%rdi),%edx
  add    $0x1,%rsi
  test   %dl,%dl
  je     L107
L106:
  cmp    $0x3c,%dl
  je     L4
  jg     L59
  cmp    $0x22,%dl
  je     L94
  cmp    $0x26,%dl
  jne    L48
  movl   $0x706d6126,(%rcx)
  movb   $0x3b,0x4(%rcx)
  add    $0x5,%rcx
  mov    %rsi,%rdi
  jmp    L100
L94:
  movl   $0x6f757126,(%rcx)
  movw   $0x3b74,0x4(%rcx)
  add    $0x6,%rcx
  mov    %rsi,%rdi
  jmp    L100
L48:
  mov    %rsi,%rdi
  mov    %dl,(%rcx)
  lea    0x1(%rcx),%rcx
  jmp    L100
L28:
  mov    %rax,%rcx
L107:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D0
type: string

tool: D3: httpd_quote_meta

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c

assistant: ```c
char *httpd_quote_meta(const char *p1) {
  char *buf = (char *)aMalloc_(strlen(p1) * 6 + 1, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c", 3102, __FUNCTION__);
  char *p2 = buf;
  while (*p1) {
    switch (*p1) {
    case '<':
      memcpy(p2, "&lt;", 4);
      p2 += 4;
      p1++;
      break;
    case '>':
      memcpy(p2, "&gt;", 4);
      p2 += 4;
      p1++;
      break;
    case '&':
      memcpy(p2, "&amp;", 5);
      p2 += 5;
      p1++;
      break;
    case '"':
      memcpy(p2, "&quot;", 6);
      p2 += 6;
      p1++;
      break;
    default:
      *(p2++) = *(p1++);
    }
  }
  *p2 = 0;
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<httpd_quote_meta>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D15(%rip),%rcx
  mov    $0xc1e,%edx
  lea    D16(%rip),%rsi
  lea    (%rax,%rax,2),%rax
  lea    0x1(%rax,%rax,1),%rdi
  xor    %eax,%eax
  call   <aMalloc_@plt>
  movzbl (%rbx),%edx
  cltq
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L45
  jmp    L79
  xchg   %ax,%ax
L109:
  cmp    $0x26,%dl
  jne    L56
  movl   $0x706d6126,(%rcx)
  add    $0x5,%rcx
  movb   $0x3b,-0x1(%rcx)
L16:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L79
L45:
  add    $0x1,%rbx
  cmp    $0x3c,%dl
  je     L27
  jg     L4
  cmp    $0x22,%dl
  jne    L109
  mov    $0x3b74,%edx
  movl   $0x6f757126,(%rcx)
  add    $0x6,%rcx
  mov    %dx,-0x2(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L45
L79:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  cmp    $0x3e,%dl
  jne    L56
  movl   $0x3b746726,(%rcx)
  add    $0x4,%rcx
  jmp    L16
  nopl   0x0(%rax)
L27:
  movl   $0x3b746c26,(%rcx)
  add    $0x4,%rcx
  jmp    L16
  nopl   0x0(%rax)
L56:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L16
```

tool_calls: name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D15: httpd_quote_meta

tool: D16: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c

assistant: ```c
char *httpd_quote_meta(const char *p1) {
  char *buf = (char *)aMalloc_(strlen(p1) * 6 + 1, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c", 3102, __FUNCTION__);
  char *p2 = buf;
  while (*p1) {
    switch (*p1) {
    case '<':
      memcpy(p2, "&lt;", 4);
      p2 += 4;
      p1++;
      break;
    case '>':
      memcpy(p2, "&gt;", 4);
      p2 += 4;
      p1++;
      break;
    case '&':
      memcpy(p2, "&amp;", 5);
      p2 += 5;
      p1++;
      break;
    case '"':
      memcpy(p2, "&quot;", 6);
      p2 += 6;
      p1++;
      break;
    default:
      *(p2++) = *(p1++);
    }
  }
  *p2 = 0;
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<httpd_quote_meta>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    D1(%rip),%rcx
  mov    $0xc1e,%edx
  lea    D5(%rip),%rsi
  lea    (%rax,%rax,2),%rax
  lea    0x1(%rax,%rax,1),%rdi
  xor    %eax,%eax
  call   <aMalloc_@plt>
  movzbl (%rbx),%edx
  cltq
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L101
  jmp    L86
  xchg   %ax,%ax
L34:
  cmp    $0x26,%dl
  jne    L27
  movl   $0x706d6126,(%rcx)
  add    $0x5,%rcx
  movb   $0x3b,-0x1(%rcx)
L25:
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L86
L101:
  add    $0x1,%rbx
  cmp    $0x3c,%dl
  je     L88
  jg     L99
  cmp    $0x22,%dl
  jne    L34
  mov    $0x3b74,%edx
  movl   $0x6f757126,(%rcx)
  add    $0x6,%rcx
  mov    %dx,-0x2(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L101
L86:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L99:
  cmp    $0x3e,%dl
  jne    L27
  movl   $0x3b746726,(%rcx)
  add    $0x4,%rcx
  jmp    L25
  nopl   0x0(%rax)
L88:
  movl   $0x3b746c26,(%rcx)
  add    $0x4,%rcx
  jmp    L25
  nopl   0x0(%rax)
L27:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D1: httpd_quote_meta

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c

assistant: ```c
char *httpd_quote_meta(const char *p1) {
  char *buf = (char *)aMalloc_(strlen(p1) * 6 + 1, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/common/httpd.c", 3102, __FUNCTION__);
  char *p2 = buf;
  while (*p1) {
    switch (*p1) {
    case '<':
      memcpy(p2, "&lt;", 4);
      p2 += 4;
      p1++;
      break;
    case '>':
      memcpy(p2, "&gt;", 4);
      p2 += 4;
      p1++;
      break;
    case '&':
      memcpy(p2, "&amp;", 5);
      p2 += 5;
      p1++;
      break;
    case '"':
      memcpy(p2, "&quot;", 6);
      p2 += 6;
      p1++;
      break;
    default:
      *(p2++) = *(p1++);
    }
  }
  *p2 = 0;
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<choose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L16:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L16
  movl   $0x1,-0xc(%rbp)
  jmp    L6
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L11
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long choose(int a, int b) {
  b = min(b, a - b);
  long long res = 1;
  int i;
  for (i = 0; i < b; i++)
    res *= (a - i);
  for (i = 1; i <= b; i++)
    res /= i;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<choose>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <min@plt>
  test   %eax,%eax
  jle    L17
  movslq %ebx,%rdi
  lea    -0x1(%rax),%esi
  lea    -0x1(%rdi),%rdx
  sub    %rsi,%rdx
  mov    $0x1,%eax
L19:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L19
  add    $0x2,%rsi
  mov    $0x1,%ecx
L8:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L8
L5:
  pop    %rbx
  ret
L17:
  mov    $0x1,%eax
  jmp    L5
```

assistant: ```c
long long choose(int a, int b) {
  b = min(b, a - b);
  long long res = 1;
  int i;
  for (i = 0; i < b; i++)
    res *= (a - i);
  for (i = 1; i <= b; i++)
    res /= i;
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<choose>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <min@plt>
  test   %eax,%eax
  jle    L38
  movslq %ebx,%rdi
  lea    -0x1(%rax),%esi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  jmp    L29
  nopl   (%rax)
L28:
  sub    $0x1,%rdx
L29:
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cmp    %rcx,%rdx
  jne    L28
  add    $0x2,%rsi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L31:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L31
  pop    %rbx
  ret
L38:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
long long choose(int a, int b) {
  b = min(b, a - b);
  long long res = 1;
  int i;
  for (i = 0; i < b; i++)
    res *= (a - i);
  for (i = 1; i <= b; i++)
    res /= i;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<choose>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    %ebx,%esi
  sub    %edi,%esi
  call   <min@plt>
  test   %eax,%eax
  jle    L9
  movslq %ebx,%rdi
  lea    -0x1(%rax),%esi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  jmp    L24
  nopl   (%rax)
L7:
  sub    $0x1,%rdx
L24:
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cmp    %rcx,%rdx
  jne    L7
  add    $0x2,%rsi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L16:
  cqto
  idiv   %rcx
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L16
  pop    %rbx
  ret
L9:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
long long choose(int a, int b) {
  b = min(b, a - b);
  long long res = 1;
  int i;
  for (i = 0; i < b; i++)
    res *= (a - i);
  for (i = 1; i <= b; i++)
    res /= i;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute_fst>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x53,%al
  je     L108
  jg     L51
  cmp    $0x4d,%al
  je     L132
  cmp    $0x50,%al
  jne    L22
  mov    $0x2,%edx
L27:
  cmpb   $0x4f,0x1(%rdi)
  jne    L90
  mov    $0x2,%eax
L103:
  cltq
  cmpb   $0x50,(%rdi,%rax,1)
  mov    $0xffffffff,%eax
  cmovne %eax,%edx
L29:
  mov    %edx,%eax
  ret
L22:
  mov    $0xffffffff,%edx
  jmp    L29
L51:
  mov    $0x5,%edx
  cmp    $0x54,%al
  je     L27
  mov    $0xffffffff,%edx
  jmp    L29
L132:
  mov    $0xffffffff,%edx
  cmpb   $0x4f,0x1(%rdi)
  jne    L29
  movzbl 0x2(%rdi),%eax
  mov    $0x0,%edx
  cmp    $0x50,%al
  je     L29
  mov    $0xffffffff,%edx
  cmp    $0x54,%al
  jne    L29
  cmpb   $0x48,0x3(%rdi)
  sete   %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx,%rdx,1),%edx
  jmp    L29
L108:
  mov    $0xffffffff,%edx
  cmpb   $0x54,0x1(%rdi)
  jne    L29
  movzbl 0x2(%rdi),%eax
  cmp    $0x41,%al
  je     L73
  mov    $0xffffffff,%edx
  cmp    $0x4f,%al
  jne    L29
  mov    $0x4,%edx
  mov    $0x3,%eax
  jmp    L103
L73:
  cmpb   $0x52,0x3(%rdi)
  sete   %dl
  movzbl %dl,%edx
  lea    -0x1(,%rdx,4),%edx
  jmp    L29
L90:
  mov    $0xffffffff,%edx
  jmp    L29
```

assistant: ```c
int compute_fst(const char *token) {
  int pos = 0;
  int total = 0;
NODE_0:
  switch (token[pos++]) {
  case 'M':
    goto NODE_1;
  case 'P':
    total += 2;
    goto NODE_4;
  case 'T':
    total += 5;
    goto NODE_4;
  case 'S':
    total += 3;
    goto NODE_6;
  default:
    return -1;
  }
NODE_1:
  switch (token[pos++]) {
  case 'O':
    goto NODE_2;
  default:
    return -1;
  }
NODE_2:
  switch (token[pos++]) {
  case 'T':
    total += 1;
    goto NODE_3;
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_3:
  switch (token[pos++]) {
  case 'H':
    goto NODE_9;
  default:
    return -1;
  }
NODE_4:
  switch (token[pos++]) {
  case 'O':
    goto NODE_5;
  default:
    return -1;
  }
NODE_5:
  switch (token[pos++]) {
  case 'P':
    goto NODE_9;
  default:
    return -1;
  }
NODE_6:
  switch (token[pos++]) {
  case 'T':
    goto NODE_7;
  default:
    return -1;
  }
NODE_7:
  switch (token[pos++]) {
  case 'O':
    total += 1;
    goto NODE_5;
  case 'A':
    goto NODE_8;
  default:
    return -1;
  }
NODE_8:
  switch (token[pos++]) {
  case 'R':
    goto NODE_9;
  default:
    return -1;
  }
NODE_9:
  goto END;
END:
  return total;
}
```