ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gps_player_info_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x20(%rbp)
  jbe    L10
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L8
L10:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    $0xe,%eax
  jbe    L25
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int gps_player_info_key(char *s, char *end) {
  static char *keys[] = {"frags_", "team_", "ping_", "species_", "race_", "deaths_", "score_", "enemy_", "player_", "keyhash_", "teamname_", "playername_", "keyhash_", "kills_", "queryid"};
  int i;
  for (i = 0; i < sizeof(keys) / sizeof(char *); i++) {
    int len = strlen(keys[i]);
    if (s + len < end && strncmp(s, keys[i], len) == 0) {
      return len;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gps_player_info_key>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  lea    D8(%rip),%rbp
  lea    0x78(%rbp),%r15
  jmp    L13
L18:
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L25
L13:
  mov    0x0(%rbp),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cltq
  add    %r13,%rax
  cmp    %rax,%r14
  jbe    L18
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L18
  jmp    L5
L25:
  mov    $0x0,%ebx
L5:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int gps_player_info_key(char *s, char *end) {
  static char *keys[] = {"frags_", "team_", "ping_", "species_", "race_", "deaths_", "score_", "enemy_", "player_", "keyhash_", "teamname_", "playername_", "keyhash_", "kills_", "queryid"};
  int i;
  for (i = 0; i < sizeof(keys) / sizeof(char *); i++) {
    int len = strlen(keys[i]);
    if (s + len < end && strncmp(s, keys[i], len) == 0) {
      return len;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gps_player_info_key>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    0x70(%r14),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax)
L33:
  cmp    %r13,%r14
  je     L32
  mov    (%r14),%r15
  add    $0x8,%r14
L17:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbp
  jbe    L33
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
L41:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  xor    %r12d,%r12d
  jmp    L41
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: frags_

assistant: ```c
int gps_player_info_key(char *s, char *end) {
  static char *keys[] = {"frags_", "team_", "ping_", "species_", "race_", "deaths_", "score_", "enemy_", "player_", "keyhash_", "teamname_", "playername_", "keyhash_", "kills_", "queryid"};
  int i;
  for (i = 0; i < sizeof(keys) / sizeof(char *); i++) {
    int len = strlen(keys[i]);
    if (s + len < end && strncmp(s, keys[i], len) == 0) {
      return len;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gps_player_info_key>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D5(%rip),%rbx
  lea    0x78(%rbx),%r14
  sub    $0x8,%rsp
  jmp    L24
  nopl   (%rax)
L41:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  je     L8
L24:
  mov    (%rbx),%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cltq
  add    %rbp,%rax
  cmp    %rax,%r13
  jbe    L41
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L41
L37:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L8:
  xor    %r12d,%r12d
  jmp    L37
```

assistant: ```c
int gps_player_info_key(char *s, char *end) {
  static char *keys[] = {"frags_", "team_", "ping_", "species_", "race_", "deaths_", "score_", "enemy_", "player_", "keyhash_", "teamname_", "playername_", "keyhash_", "kills_", "queryid"};
  int i;
  for (i = 0; i < sizeof(keys) / sizeof(char *); i++) {
    int len = strlen(keys[i]);
    if (s + len < end && strncmp(s, keys[i], len) == 0) {
      return len;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init_cube>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cube_reset@plt>
  mov    $0x0,%eax
  call   <init_SD@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_cube() {
  cube_reset();
  init_SD();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_cube>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cube_reset@plt>
  mov    $0x0,%eax
  call   <init_SD@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_cube() {
  cube_reset();
  init_SD();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_cube>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cube_reset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <init_SD@plt>
```

assistant: ```c
void init_cube() {
  cube_reset();
  init_SD();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_cube>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cube_reset@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <init_SD@plt>
```

assistant: ```c
void init_cube() {
  cube_reset();
  init_SD();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<krad_get_host_and_port>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcspn@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: :

assistant: ```c
void krad_get_host_and_port(char *string, char *host, int *port) {
  *port = atoi(strchr(string, ':') + 1);
  memset(host, '\0', 128);
  memcpy(host, string, strcspn(string, ":"));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<krad_get_host_and_port>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x3a,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcspn@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: :

assistant: ```c
void krad_get_host_and_port(char *string, char *host, int *port) {
  *port = atoi(strchr(string, ':') + 1);
  memset(host, '\0', 128);
  memcpy(host, string, strcspn(string, ":"));
}
```
user: Translate the below assembly code into C programming language:

```asm
<krad_get_host_and_port>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x3a,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    $0x80,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  mov    %eax,(%rbx)
  call   <memset@plt>
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <strcspn@plt>
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    10c0 <memcpy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: :

assistant: ```c
void krad_get_host_and_port(char *string, char *host, int *port) {
  *port = atoi(strchr(string, ':') + 1);
  memset(host, '\0', 128);
  memcpy(host, string, strcspn(string, ":"));
}
```
user: Translate the below assembly code into C programming language:

```asm
<krad_get_host_and_port>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x3a,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    $0x80,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  mov    %eax,(%rbx)
  call   <memset@plt>
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  call   <strcspn@plt>
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    10c0 <memcpy@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: :

assistant: ```c
void krad_get_host_and_port(char *string, char *host, int *port) {
  *port = atoi(strchr(string, ':') + 1);
  memset(host, '\0', 128);
  memcpy(host, string, strcspn(string, ":"));
}
```
user: What is the c source code of the assembly code below:

```asm
<bfsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isValid@plt>
  test   %rax,%rax
  je     L10
  addl   $0x1,-0x4(%rbp)
L10:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bfsize(char *text, int filesize) {
  int i;
  int sz = 0;
  for (i = 0; i < filesize; i++)
    if (isValid(text[i]))
      sz++;
  sz -= sz % 2;
  return sz;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bfsize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%ebp
L14:
  movsbl (%rbx),%edi
  call   <isValid@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L14
L3:
  mov    %ebp,%eax
  shr    $0x1f,%eax
  lea    0x0(%rbp,%rax,1),%edx
  and    $0x1,%edx
  sub    %eax,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0x0,%ebp
  jmp    L3
```

assistant: ```c
int bfsize(char *text, int filesize) {
  int i;
  int sz = 0;
  for (i = 0; i < filesize; i++)
    if (isValid(text[i]))
      sz++;
  sz -= sz % 2;
  return sz;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bfsize>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L18:
  movsbl (%rbx),%edi
  call   <isValid@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  and    $0xfffffffe,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bfsize(char *text, int filesize) {
  int i;
  int sz = 0;
  for (i = 0; i < filesize; i++)
    if (isValid(text[i]))
      sz++;
  sz -= sz % 2;
  return sz;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bfsize>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L2:
  movsbl (%rbx),%edi
  call   <isValid@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  and    $0xfffffffe,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bfsize(char *text, int filesize) {
  int i;
  int sz = 0;
  for (i = 0; i < filesize; i++)
    if (isValid(text[i]))
      sz++;
  sz -= sz % 2;
  return sz;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L1
L6:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L16:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0x2,-0x14(%rbp)
  jle    L16
  addl   $0x1,-0x18(%rbp)
L1:
  cmpl   $0x6,-0x18(%rbp)
  jle    L6
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D5: dnannsumkbn

tool: D25: # c::%s:len=%d


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnannsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D18(%rip),%r15
  jmp    L14
L26:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L12
L14:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L8:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L8
  jmp    L26
L12:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: string
name: unpack_data
arguments: label: D22
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string

tool: D18: dnannsumkbn

tool: D22: # c::%s:len=%d


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnannsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D26(%rip),%r15
  push   %r14
  lea    D24(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L6:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L16:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L16
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L6
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D26
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string

tool: D26: dnannsumkbn

tool: D24: # c::%s:len=%d


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnannsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D27(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L15:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L13:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L13
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L15
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D27
data_type: string
name: unpack_data
arguments: data_tag: D29
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D27: dnannsumkbn

tool: D29: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnannsumkbn", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ExportedFunction@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  ExportedFunction();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ExportedFunction@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ExportedFunction();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ExportedFunction@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  ExportedFunction();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L39
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
L49:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L6
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L44
L6:
  addl   $0x1,-0x1c(%rbp)
  jmp    L49
L39:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L44:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_infered: string

tool: D24: %d

assistant: ```c
int main() {
  int a, b, n, i, c = 0, d, x = 0;
  scanf("%d", &n);
  a = check_prime(n);
  if (a == 0) {
    for (i = n + 1; 1; i++) {
      b = check_prime(i);
      if (b != 0) {
        printf("%d", b);
        break;
      }
    }
  } else
    printf("%d", a);
  return 0;
}
```