ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jne    L50
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L78:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L10
L50:
  movzbl -0x1(%rax),%edx
  cmp    $0x2f,%dl
  jne    L78
L24:
  movzbl (%rax),%edx
L10:
  test   %dl,%dl
  jne    L63
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L77:
  add    $0x1,%rax
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L16
L63:
  cmp    $0x2e,%dl
  jne    L77
L16:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jne    L48
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L3:
  sub    $0x1,%rax
  cmp    %rax,%rbp
  je     L43
L48:
  movzbl -0x1(%rax),%edx
  cmp    $0x2f,%dl
  jne    L3
L54:
  movzbl (%rax),%edx
L43:
  test   %dl,%dl
  jne    L2
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L70:
  add    $0x1,%rax
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L29
L2:
  cmp    $0x2e,%dl
  jne    L70
L29:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FileReadPermissionCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  je     L10
  mov    $0x1,%eax
  jmp    L6
L10:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
bool FileReadPermissionCheck(const char *file_name) {
  if (access(file_name, R_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<FileReadPermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool FileReadPermissionCheck(const char *file_name) {
  if (access(file_name, R_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FileReadPermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool FileReadPermissionCheck(const char *file_name) {
  if (access(file_name, R_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FileReadPermissionCheck>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool FileReadPermissionCheck(const char *file_name) {
  if (access(file_name, R_OK) != -1) {
    return true;
  } else {
    return false;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<exact_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L35
L12:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L28
  mov    $0x1,%eax
  jmp    L11
L28:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int exact_square(int num) {
  int res = 0, mult;
  for (mult = 1; res < num; mult++) {
    res = mult * mult;
    if (res == num) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exact_square>:
  endbr64
  test   %edi,%edi
  jle    L3
  cmp    $0x1,%edi
  je     L15
  mov    $0x2,%edx
L35:
  mov    %edx,%ecx
  imul   %edx,%ecx
  cmp    %ecx,%edi
  je     L23
  add    $0x1,%edx
  cmp    %ecx,%edi
  jg     L35
  mov    $0x0,%eax
  ret
L3:
  mov    $0x0,%eax
  ret
L15:
  mov    %edi,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int exact_square(int num) {
  int res = 0, mult;
  for (mult = 1; res < num; mult++) {
    res = mult * mult;
    if (res == num) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exact_square>:
  endbr64
  test   %edi,%edi
  jle    L35
  cmp    $0x1,%edi
  je     L20
  mov    $0x2,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edx,%edi
  je     L20
  add    $0x1,%eax
  cmp    %edx,%edi
  jg     L8
L35:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int exact_square(int num) {
  int res = 0, mult;
  for (mult = 1; res < num; mult++) {
    res = mult * mult;
    if (res == num) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exact_square>:
  endbr64
  test   %edi,%edi
  jle    L32
  cmp    $0x1,%edi
  je     L25
  mov    $0x2,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edx,%edi
  je     L25
  add    $0x1,%eax
  cmp    %edx,%edi
  jg     L22
L32:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int exact_square(int num) {
  int res = 0, mult;
  for (mult = 1; res < num; mult++) {
    res = mult * mult;
    if (res == num) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sn_decode_crlf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sn_decode_has@plt>
  test   %eax,%eax
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L18
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L59
  mov    $0xfffffffe,%eax
  jmp    L18
L59:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L38
  mov    $0xfffffffe,%eax
  jmp    L18
L38:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int sn_decode_crlf(char **p, char *end) {
  char *start = *p;
  if (!sn_decode_has(start, end, 2))
    return (-1);
  if (*start != '\r')
    return (-2);
  if (*(start + 1) != '\n')
    return (-2);
  *p += 2;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sn_decode_crlf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <sn_decode_has@plt>
  test   %eax,%eax
  je     L14
  cmpb   $0xd,0x0(%rbp)
  jne    L34
  cmpb   $0xa,0x1(%rbp)
  jne    L26
  addq   $0x2,(%rbx)
  mov    $0x0,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L3
L34:
  mov    $0xfffffffe,%eax
  jmp    L3
L26:
  mov    $0xfffffffe,%eax
  jmp    L3
```

assistant: ```c
int sn_decode_crlf(char **p, char *end) {
  char *start = *p;
  if (!sn_decode_has(start, end, 2))
    return (-1);
  if (*start != '\r')
    return (-2);
  if (*(start + 1) != '\n')
    return (-2);
  *p += 2;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sn_decode_crlf>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <sn_decode_has@plt>
  test   %eax,%eax
  je     L30
  cmpb   $0xd,0x0(%rbp)
  jne    L1
  cmpb   $0xa,0x1(%rbp)
  jne    L1
  addq   $0x2,(%rbx)
  xor    %eax,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xfffffffe,%eax
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int sn_decode_crlf(char **p, char *end) {
  char *start = *p;
  if (!sn_decode_has(start, end, 2))
    return (-1);
  if (*start != '\r')
    return (-2);
  if (*(start + 1) != '\n')
    return (-2);
  *p += 2;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sn_decode_crlf>:
  endbr64
  push   %rbp
  mov    $0x2,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <sn_decode_has@plt>
  test   %eax,%eax
  je     L18
  cmpb   $0xd,0x0(%rbp)
  jne    L38
  cmpb   $0xa,0x1(%rbp)
  jne    L38
  addq   $0x2,(%rbx)
  xor    %eax,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0xfffffffe,%eax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int sn_decode_crlf(char **p, char *end) {
  char *start = *p;
  if (!sn_decode_has(start, end, 2))
    return (-1);
  if (*start != '\r')
    return (-2);
  if (*(start + 1) != '\n')
    return (-2);
  *p += 2;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ctrim_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L66
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  cmpl   $0x0,-0x4(%rbp)
  js     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L15
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L15
  jmp    L18
L66:
  nop
L18:
  leave
  ret
```

assistant: ```c
void ctrim_line(char *str) {
  int i;
  if (str == NULL)
    return;
  i = strlen(str) - 1;
  while (i >= 0 && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'))
    str[i--] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctrim_line>:
  endbr64
  test   %rdi,%rdi
  je     L40
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L38
  movslq %edx,%rdx
  add    %rbx,%rdx
  movslq %eax,%rcx
  lea    -0x2(%rbx,%rcx,1),%rsi
  lea    -0x1(%rax),%eax
  sub    %rax,%rsi
  movabs $0x100002600,%rdi
  jmp    L35
L12:
  bt     %rax,%rdi
  jae    L38
  movb   $0x0,(%rcx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L38
L35:
  mov    %rdx,%rcx
  movzbl (%rdx),%eax
  cmp    $0x20,%al
  jbe    L12
L38:
  pop    %rbx
  ret
L40:
  ret
```

assistant: ```c
void ctrim_line(char *str) {
  int i;
  if (str == NULL)
    return;
  i = strlen(str) - 1;
  while (i >= 0 && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'))
    str[i--] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ctrim_line>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  sub    $0x1,%esi
  js     L30
  cltq
  movslq %esi,%rdx
  mov    %esi,%esi
  lea    -0x2(%rbx,%rax,1),%rcx
  add    %rbx,%rdx
  sub    %rsi,%rcx
  movabs $0xfffffffeffffd9ff,%rsi
  nopl   (%rax)
L17:
  movzbl (%rdx),%eax
  cmp    $0x20,%al
  ja     L30
  bt     %rax,%rsi
  jb     L30
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L17
L30:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void ctrim_line(char *str) {
  int i;
  if (str == NULL)
    return;
  i = strlen(str) - 1;
  while (i >= 0 && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'))
    str[i--] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ctrim_line>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  sub    $0x1,%esi
  js     L36
  cltq
  movslq %esi,%rdx
  mov    %esi,%esi
  lea    -0x2(%rbx,%rax,1),%rcx
  add    %rbx,%rdx
  sub    %rsi,%rcx
  movabs $0xfffffffeffffd9ff,%rsi
  nopl   (%rax)
L40:
  movzbl (%rdx),%eax
  cmp    $0x20,%al
  ja     L36
  bt     %rax,%rsi
  jb     L36
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L40
L36:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
void ctrim_line(char *str) {
  int i;
  if (str == NULL)
    return;
  i = strlen(str) - 1;
  while (i >= 0 && (str[i] == ' ' || str[i] == '\t' || str[i] == '\r' || str[i] == '\n'))
    str[i--] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_MM_EXTRACT_PS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_mm_store_si128@plt>
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int _MM_EXTRACT_PS(__m128 vec, const int LANE) {
  __attribute__((aligned(16))) int32_t tmp[4];
  _mm_store_si128((__m128i *)tmp, (*(__m128i *)&(vec)));
  return tmp[LANE];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_MM_EXTRACT_PS>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %edi,%esi
  mov    %rax,%rdi
  call   <_mm_store_si128@plt>
  movslq %ebx,%rbx
  mov    (%rsp,%rbx,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int _MM_EXTRACT_PS(__m128 vec, const int LANE) {
  __attribute__((aligned(16))) int32_t tmp[4];
  _mm_store_si128((__m128i *)tmp, (*(__m128i *)&(vec)));
  return tmp[LANE];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_MM_EXTRACT_PS>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  movslq %esi,%rbx
  mov    %r8d,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <_mm_store_si128@plt>
  mov    (%rsp,%rbx,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int _MM_EXTRACT_PS(__m128 vec, const int LANE) {
  __attribute__((aligned(16))) int32_t tmp[4];
  _mm_store_si128((__m128i *)tmp, (*(__m128i *)&(vec)));
  return tmp[LANE];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_MM_EXTRACT_PS>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  movslq %esi,%rbx
  mov    %r8d,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <_mm_store_si128@plt>
  mov    (%rsp,%rbx,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int _MM_EXTRACT_PS(__m128 vec, const int LANE) {
  __attribute__((aligned(16))) int32_t tmp[4];
  _mm_store_si128((__m128i *)tmp, (*(__m128i *)&(vec)));
  return tmp[LANE];
}
```
user: What is the c source code of the assembly code below?

```asm
<__u32_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L15
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L15:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __u32_mul(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__u32_mul>:
  endbr64
  mov    $0x1,%eax
  test   %ecx,%ecx
  jne    L4
  mov    (%rdx),%eax
  imul   (%rdi),%eax
L4:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void __u32_mul(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__u32_mul>:
  endbr64
  mov    $0x1,%eax
  test   %ecx,%ecx
  jne    L1
  mov    (%rdx),%eax
  imul   (%rdi),%eax
L1:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void __u32_mul(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__u32_mul>:
  endbr64
  mov    $0x1,%eax
  test   %ecx,%ecx
  jne    L3
  mov    (%rdx),%eax
  imul   (%rdi),%eax
L3:
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void __u32_mul(void *cc, void *k, void *v, bool n) {
  if (n) {
    *(uint32_t *)v = 1;
  } else {
    *(uint32_t *)v *= *(uint32_t *)cc;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prependToPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x28(%rbp)
  movq   $0x0,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  jmp    L8
L15:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcat@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcat@plt>
L8:
  mov    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: :

assistant: ```c
int prependToPath(const char *name, const char *prepend) {
  const char *old_value = getenv(name);
  char *new_value = NULL;
  if (old_value == NULL) {
    size_t max_length = strlen(prepend) + 1;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
  } else {
    size_t max_length = strlen(old_value) + strlen(prepend) + 2;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
    strlcat(new_value, ":", max_length);
    strlcat(new_value, old_value, max_length);
  }
  setenv(name, new_value, 1);
  free(new_value);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prependToPath>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <getenv@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%r14d
  movslq %r14d,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  mov    %r14,%rdx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strlcat@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strlcat@plt>
L15:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <setenv@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4: :

assistant: ```c
int prependToPath(const char *name, const char *prepend) {
  const char *old_value = getenv(name);
  char *new_value = NULL;
  if (old_value == NULL) {
    size_t max_length = strlen(prepend) + 1;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
  } else {
    size_t max_length = strlen(old_value) + strlen(prepend) + 2;
    new_value = malloc(max_length);
    strlcpy(new_value, prepend, max_length);
    strlcat(new_value, ":", max_length);
    strlcat(new_value, old_value, max_length);
  }
  setenv(name, new_value, 1);
  free(new_value);
  return 0;
}
```