ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <_ada_pieri_root_count@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <adafinal@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D34
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D53
datatype: string
name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D39
datatype: string
name: parse_data
arguments: label: D41
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D34: Give the dimension of the input planes :

tool: D8: %d

tool: D53: Give the dimension of the output planes :

tool: D10: Give the degree of the maps :

tool: D39: Calling Ada... 

tool: D41: ... done with the call.

tool: D6: The number of the root is: %d


assistant: ```c
int main() {
  int m, p, q;
  int root_number;
  printf("Give the dimension of the input planes :");
  scanf("%d", &m);
  printf("Give the dimension of the output planes :");
  scanf("%d", &p);
  printf("Give the degree of the maps :");
  scanf("%d", &q);
  printf("Calling Ada... \n");
  adainit();
  root_number = _ada_pieri_root_count(m, p, q);
  adafinal();
  printf("... done with the call.\n");
  printf("The number of the root is: %d\n", root_number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <adainit@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <_ada_pieri_root_count@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <adafinal@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D46
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D34
type_infered: string
name: disassemble_data
arguments: data_tag: D39
type_infered: string
name: disassemble_data
arguments: data_tag: D55
type_infered: string

tool: D5: Give the dimension of the input planes :

tool: D10: %d

tool: D46: Give the dimension of the output planes :

tool: D27: Give the degree of the maps :

tool: D34: Calling Ada... 

tool: D39: ... done with the call.

tool: D55: The number of the root is: %d


assistant: ```c
int main() {
  int m, p, q;
  int root_number;
  printf("Give the dimension of the input planes :");
  scanf("%d", &m);
  printf("Give the dimension of the output planes :");
  scanf("%d", &p);
  printf("Give the degree of the maps :");
  scanf("%d", &q);
  printf("Calling Ada... \n");
  adainit();
  root_number = _ada_pieri_root_count(m, p, q);
  adafinal();
  printf("... done with the call.\n");
  printf("The number of the root is: %d\n", root_number);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D24(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <adainit@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%edi
  call   <_ada_pieri_root_count@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <adafinal@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D31
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D40
datatype: string
name: parse_data
arguments: data_label: D69
datatype: string

tool: D5: Give the dimension of the input planes :

tool: D24: %d

tool: D31: Give the dimension of the output planes :

tool: D6: Give the degree of the maps :

tool: D12: Calling Ada... 

tool: D40: ... done with the call.

tool: D69: The number of the root is: %d


assistant: ```c
int main() {
  int m, p, q;
  int root_number;
  printf("Give the dimension of the input planes :");
  scanf("%d", &m);
  printf("Give the dimension of the output planes :");
  scanf("%d", &p);
  printf("Give the degree of the maps :");
  scanf("%d", &q);
  printf("Calling Ada... \n");
  adainit();
  root_number = _ada_pieri_root_count(m, p, q);
  adafinal();
  printf("... done with the call.\n");
  printf("The number of the root is: %d\n", root_number);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  lea    D15(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <adainit@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%edx
  mov    0xc(%rsp),%edi
  call   <_ada_pieri_root_count@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <adafinal@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D30
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D36
datatype: string
name: parse_data
arguments: data_label: D68
datatype: string
name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D51
datatype: string
name: parse_data
arguments: data_label: D17
datatype: string

tool: D30: Give the dimension of the input planes :

tool: D15: %d

tool: D36: Give the dimension of the output planes :

tool: D68: Give the degree of the maps :

tool: D34: Calling Ada... 

tool: D51: ... done with the call.

tool: D17: The number of the root is: %d


assistant: ```c
int main() {
  int m, p, q;
  int root_number;
  printf("Give the dimension of the input planes :");
  scanf("%d", &m);
  printf("Give the dimension of the output planes :");
  scanf("%d", &p);
  printf("Give the degree of the maps :");
  scanf("%d", &q);
  printf("Calling Ada... \n");
  adainit();
  root_number = _ada_pieri_root_count(m, p, q);
  adafinal();
  printf("... done with the call.\n");
  printf("The number of the root is: %d\n", root_number);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x26,%edi
  call   <addDigits@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
int main(void) {
  printf("%d\n", addDigits(38));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <addDigits@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: %d


assistant: ```c
int main(void) {
  printf("%d\n", addDigits(38));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <addDigits@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(void) {
  printf("%d\n", addDigits(38));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x26,%edi
  call   <addDigits@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(void) {
  printf("%d\n", addDigits(38));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<nextArgument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  je     L27
  mov    -0x8(%rbp),%rax
  mov    $0x24,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L14
L27:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L14:
  leave
  ret
```

assistant: ```c
const char *nextArgument(const char *start, const char **str, size_t *len) {
  const char *p = start;
  if (p[0] != '$') {
    p = strchr(p, '$');
    if (p == NULL)
      return NULL;
  }
  *len = (int)strtol(p + 1, NULL, 10);
  p = strchr(p, '\r');
  assert(p);
  *str = p + 2;
  return p + 2 + (*len) + 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nextArgument>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  cmpb   $0x24,(%rdi)
  je     L8
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
L8:
  lea    0x1(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  cltq
  mov    %rax,0x0(%rbp)
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  lea    0x2(%rbx),%rax
  mov    %rax,(%r12)
  mov    0x0(%rbp),%rax
  lea    0x4(%rbx,%rax,1),%rax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *nextArgument(const char *start, const char **str, size_t *len) {
  const char *p = start;
  if (p[0] != '$') {
    p = strchr(p, '$');
    if (p == NULL)
      return NULL;
  }
  *len = (int)strtol(p + 1, NULL, 10);
  p = strchr(p, '\r');
  assert(p);
  *str = p + 2;
  return p + 2 + (*len) + 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nextArgument>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x24,(%rdi)
  mov    %rdx,%rbx
  je     L18
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
L18:
  lea    0x1(%rbp),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  cltq
  mov    %rax,(%rbx)
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  lea    0x2(%rbp),%rax
  mov    %rax,(%r12)
  mov    (%rbx),%rax
  lea    0x4(%rbp,%rax,1),%rax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  jmp    L10
```

assistant: ```c
const char *nextArgument(const char *start, const char **str, size_t *len) {
  const char *p = start;
  if (p[0] != '$') {
    p = strchr(p, '$');
    if (p == NULL)
      return NULL;
  }
  *len = (int)strtol(p + 1, NULL, 10);
  p = strchr(p, '\r');
  assert(p);
  *str = p + 2;
  return p + 2 + (*len) + 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextArgument>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x24,(%rdi)
  mov    %rdx,%rbx
  je     L8
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
L8:
  lea    0x1(%rbp),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  cltq
  mov    %rax,(%rbx)
  call   <strchr@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <assert@plt>
  lea    0x2(%rbp),%rax
  mov    %rax,(%r12)
  mov    (%rbx),%rax
  lea    0x4(%rbp,%rax,1),%rax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  jmp    L10
```

assistant: ```c
const char *nextArgument(const char *start, const char **str, size_t *len) {
  const char *p = start;
  if (p[0] != '$') {
    p = strchr(p, '$');
    if (p == NULL)
      return NULL;
  }
  *len = (int)strtol(p + 1, NULL, 10);
  p = strchr(p, '\r');
  assert(p);
  *str = p + 2;
  return p + 2 + (*len) + 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<candy>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  movl   $0x1,(%rax)
  cmp    $0x1,%ebx
  jle    L98
  lea    0x4(%rax),%rdx
  lea    -0x2(%rbx),%ecx
  lea    0x8(%rax,%rcx,4),%rdi
  mov    %rbp,%rcx
  sub    %rax,%rcx
  jmp    L52
L72:
  movl   $0x1,(%rdx)
L104:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L79
L52:
  mov    -0x4(%rcx,%rdx,1),%esi
  cmp    %esi,(%rcx,%rdx,1)
  jle    L72
  mov    -0x4(%rdx),%esi
  add    $0x1,%esi
  mov    %esi,(%rdx)
  jmp    L104
L20:
  sub    $0x1,%rdx
  sub    $0x4,%rcx
  test   %edx,%edx
  js     L98
L89:
  mov    0x4(%rbp,%rdx,4),%edi
  cmp    %edi,0x0(%rbp,%rdx,4)
  jle    L20
  mov    0x4(%rcx),%esi
  cmp    %esi,(%rcx)
  jg     L20
  add    $0x1,%esi
  mov    %esi,(%rcx)
  jmp    L20
L98:
  mov    %rax,%rdx
  mov    %ebx,%ebx
  lea    (%rax,%rbx,4),%rcx
  mov    $0x0,%eax
L1:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L79:
  lea    -0x2(%rbx),%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rcx
  jmp    L89
L33:
  ret
```

assistant: ```c
int candy(int *ratings, int ratingsSize) {
  if (ratingsSize <= 0)
    return 0;
  int *f = (int *)malloc(sizeof(int) * ratingsSize);
  f[0] = 1;
  for (int i = 1; i < ratingsSize; ++i)
    if (ratings[i] > ratings[i - 1])
      f[i] = f[i - 1] + 1;
    else
      f[i] = 1;
  for (int i = ratingsSize - 2; i >= 0; --i)
    if (ratings[i] > ratings[i + 1] && f[i] <= f[i + 1])
      f[i] = f[i + 1] + 1;
  int result = 0;
  for (int i = 0; i < ratingsSize; ++i)
    result += f[i];
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<candy>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  jle    L21
  mov    %rdi,%rbx
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  lea    -0x2(%rbp),%edi
  movl   $0x1,(%rax)
  mov    %rax,%r8
  cmp    $0x1,%ebp
  je     L70
  mov    %edi,%edx
  mov    %rbx,%rcx
  lea    0x4(%rax),%rax
  lea    0x8(%r8,%rdx,4),%rsi
  sub    %r8,%rcx
  nopl   0x0(%rax,%rax,1)
L68:
  mov    -0x4(%rcx,%rax,1),%r9d
  mov    $0x1,%edx
  cmp    %r9d,(%rcx,%rax,1)
  jle    L47
  mov    -0x4(%rax),%edx
  add    $0x1,%edx
L47:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L68
L85:
  movslq %edi,%rsi
  shl    $0x2,%rdi
  sub    %r8,%rbx
  mov    %r8,%rdx
  shl    $0x2,%rsi
  mov    %rbx,%rcx
  lea    (%r8,%rsi,1),%rax
  sub    $0x4,%rsi
  sub    %rdi,%rsi
  add    %r8,%rsi
  nopl   0x0(%rax,%rax,1)
L57:
  mov    0x4(%rcx,%rax,1),%ebx
  cmp    %ebx,(%rcx,%rax,1)
  jle    L32
  mov    0x4(%rax),%edi
  cmp    %edi,(%rax)
  jg     L32
  add    $0x1,%edi
  mov    %edi,(%rax)
L32:
  sub    $0x4,%rax
  cmp    %rax,%rsi
  jne    L57
  lea    (%r8,%rbp,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L92:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L92
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L70:
  cmp    $0xffffffff,%edi
  jne    L85
  mov    $0x1,%eax
  jmp    L21
```

assistant: ```c
int candy(int *ratings, int ratingsSize) {
  if (ratingsSize <= 0)
    return 0;
  int *f = (int *)malloc(sizeof(int) * ratingsSize);
  f[0] = 1;
  for (int i = 1; i < ratingsSize; ++i)
    if (ratings[i] > ratings[i - 1])
      f[i] = f[i - 1] + 1;
    else
      f[i] = 1;
  for (int i = ratingsSize - 2; i >= 0; --i)
    if (ratings[i] > ratings[i + 1] && f[i] <= f[i + 1])
      f[i] = f[i + 1] + 1;
  int result = 0;
  for (int i = 0; i < ratingsSize; ++i)
    result += f[i];
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<candy>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L124
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    -0x2(%rbp),%r8d
  movl   $0x1,(%rax)
  mov    %rax,%rdi
  cmp    $0x1,%ebp
  je     L130
  mov    %r8d,%edx
  lea    0x4(%rax),%rax
  lea    0x8(%rdi,%rdx,4),%rsi
  mov    %rbx,%rdx
  sub    %rdi,%rdx
  nopl   (%rax)
L29:
  mov    -0x4(%rdx,%rax,1),%ecx
  cmp    %ecx,(%rdx,%rax,1)
  jle    L127
  mov    -0x4(%rax),%ecx
  add    $0x4,%rax
  add    $0x1,%ecx
  mov    %ecx,-0x4(%rax)
  cmp    %rsi,%rax
  jne    L29
L73:
  movslq %r8d,%rsi
  shl    $0x2,%r8
  sub    %rdi,%rbx
  mov    %rdi,%rdx
  shl    $0x2,%rsi
  mov    %rbx,%rcx
  lea    (%rsi,%rdi,1),%rax
  sub    $0x4,%rsi
  sub    %r8,%rsi
  add    %rdi,%rsi
  nopl   0x0(%rax)
L168:
  mov    0x4(%rcx,%rax,1),%ebx
  cmp    %ebx,(%rcx,%rax,1)
  jle    L60
  mov    0x4(%rax),%r8d
  cmp    %r8d,(%rax)
  jg     L60
  add    $0x1,%r8d
  mov    %r8d,(%rax)
L60:
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L168
  lea    -0x1(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L43
  mov    %ebp,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  shl    $0x4,%rax
  add    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L49:
  movdqu (%rdx),%xmm2
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L49
  movdqa %xmm0,%xmm1
  mov    %ebp,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%bpl
  je     L30
L5:
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rsi
  add    (%rdi,%rcx,4),%eax
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%ebp
  jle    L30
  add    $0x2,%edx
  add    0x4(%rdi,%rsi,1),%eax
  cmp    %ebp,%edx
  jge    L30
  add    0x8(%rdi,%rsi,1),%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L127:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L29
  jmp    L73
L124:
  ret
L43:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L130:
  cmp    $0xffffffff,%r8d
  jne    L73
  mov    $0x1,%eax
  jmp    L30
```

assistant: ```c
int candy(int *ratings, int ratingsSize) {
  if (ratingsSize <= 0)
    return 0;
  int *f = (int *)malloc(sizeof(int) * ratingsSize);
  f[0] = 1;
  for (int i = 1; i < ratingsSize; ++i)
    if (ratings[i] > ratings[i - 1])
      f[i] = f[i - 1] + 1;
    else
      f[i] = 1;
  for (int i = ratingsSize - 2; i >= 0; --i)
    if (ratings[i] > ratings[i + 1] && f[i] <= f[i + 1])
      f[i] = f[i + 1] + 1;
  int result = 0;
  for (int i = 0; i < ratingsSize; ++i)
    result += f[i];
  return result;
}
```