user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L5
L127:
  movl   $0x0,-0x74(%rbp)
  jmp    L21
L17:
  lea    -0x60(%rbp),%rcx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x74(%rbp)
L21:
  cmpl   $0x4,-0x74(%rbp)
  jle    L17
  addl   $0x1,-0x78(%rbp)
L5:
  cmpl   $0x3,-0x78(%rbp)
  jle    L127
  movl   $0x0,-0x78(%rbp)
  jmp    L145
L30:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0x60,%rax
  mov    (%rax),%eax
  mov    %eax,-0x6c(%rbp)
  movl   $0x0,-0x68(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L132
L88:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,-0x6c(%rbp)
  jge    L40
  mov    -0x74(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,-0x6c(%rbp)
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x68(%rbp)
L40:
  addl   $0x1,-0x74(%rbp)
L132:
  cmpl   $0x4,-0x74(%rbp)
  jle    L88
  movl   $0x1,-0x64(%rbp)
  movl   $0x0,-0x70(%rbp)
  jmp    L13
L89:
  mov    -0x68(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x70(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x60(%rbp,%rax,4),%eax
  cmp    %eax,-0x6c(%rbp)
  jle    L29
  movl   $0x0,-0x64(%rbp)
  nop
L29:
  addl   $0x1,-0x70(%rbp)
L13:
  cmpl   $0x3,-0x70(%rbp)
  jle    L89
  cmpl   $0x0,-0x64(%rbp)
  je     L124
  mov    -0x6c(%rbp),%ecx
  mov    -0x68(%rbp),%edx
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L152
L124:
  addl   $0x1,-0x78(%rbp)
L145:
  cmpl   $0x3,-0x78(%rbp)
  jle    L30
L152:
  cmpl   $0x0,-0x64(%rbp)
  jne    L62
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L62:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D17
type: string

tool: D14: please input matrix:

tool: D9: %d

tool: D33: a[%d][%d]=%d


tool: D17: It is not exist!

assistant: ```c
int main() {
  int i, j, k, a[4][5], max, maxj, flag;
  printf("please input matrix:\n");
  for (i = 0; i < 4; i++)
    for (j = 0; j < 5; j++)
      scanf("%d", &a[i][j]);
  for (i = 0; i < 4; i++) {
    max = a[i][0];
    maxj = 0;
    for (j = 0; j < 5; j++)
      if (a[i][j] > max) {
        max = a[i][j];
        maxj = j;
      }
    flag = 1;
    for (k = 0; k < 4; k++)
      if (max > a[k][maxj]) {
        flag = 0;
        continue;
      }
    if (flag) {
      printf("a[%d][%d]=%d\n", i, maxj, max);
      break;
    }
  }
  if (!flag)
    printf("It is not exist!\n");
  return 0;
}
```