ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<sys$assign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    %rax,%r8
  mov    -0x30(%rbp),%rax
  mov    %rax,%r10
  mov    -0x24(%rbp),%eax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x1e,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$assign(void *devnam, unsigned short int *chan, unsigned int acmode, void *mbxnam, int flags) {
  return ({
    unsigned long resultvar;
    register long int _a5 asm("r8") = (long)(flags);
    register long int _a4 asm("r10") = (long)(mbxnam);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(chan);
    register long int _a1 asm("rdi") = (long)(devnam);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(30), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4), "r"(_a5)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sys$assign>:
  endbr64
  mov    %rcx,%r10
  movslq %r8d,%r8
  mov    %edx,%edx
  mov    $0x1e,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$assign(void *devnam, unsigned short int *chan, unsigned int acmode, void *mbxnam, int flags) {
  return ({
    unsigned long resultvar;
    register long int _a5 asm("r8") = (long)(flags);
    register long int _a4 asm("r10") = (long)(mbxnam);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(chan);
    register long int _a1 asm("rdi") = (long)(devnam);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(30), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4), "r"(_a5)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sys$assign>:
  endbr64
  mov    %rcx,%r10
  movslq %r8d,%r8
  mov    %edx,%edx
  mov    $0x1e,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$assign(void *devnam, unsigned short int *chan, unsigned int acmode, void *mbxnam, int flags) {
  return ({
    unsigned long resultvar;
    register long int _a5 asm("r8") = (long)(flags);
    register long int _a4 asm("r10") = (long)(mbxnam);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(chan);
    register long int _a1 asm("rdi") = (long)(devnam);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(30), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4), "r"(_a5)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sys$assign>:
  endbr64
  mov    %rcx,%r10
  movslq %r8d,%r8
  mov    %edx,%edx
  mov    $0x1e,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$assign(void *devnam, unsigned short int *chan, unsigned int acmode, void *mbxnam, int flags) {
  return ({
    unsigned long resultvar;
    register long int _a5 asm("r8") = (long)(flags);
    register long int _a4 asm("r10") = (long)(mbxnam);
    register long int _a3 asm("rdx") = (long)(acmode);
    register long int _a2 asm("rsi") = (long)(chan);
    register long int _a1 asm("rdi") = (long)(devnam);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(30), "r"(_a1), "r"(_a2), "r"(_a3), "r"(_a4), "r"(_a5)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DeTab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L35
L43:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  jmp    L5
L20:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L5:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L20
L10:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DeTab(char s[], char d[], const int tabwidth) {
  int i, j;
  for (i = j = 0; (d[j] = s[i]) != '\0'; i++, j++) {
    if (d[j] == '\t') {
      d[j] = ' ';
      for (; (j + 1) % tabwidth != 0;) {
        d[++j] = ' ';
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<DeTab>:
  endbr64
  mov    %rsi,%r9
  mov    %edx,%r8d
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %al,%al
  je     L18
  add    $0x1,%rdi
  mov    %rsi,%rdx
  mov    $0x0,%esi
  jmp    L46
L41:
  add    $0x1,%esi
  movslq %esi,%rdx
  add    %r9,%rdx
  movzbl (%rdi),%eax
  mov    %al,(%rdx)
  add    $0x1,%rdi
  test   %al,%al
  je     L18
L46:
  cmp    $0x9,%al
  jne    L41
  movb   $0x20,(%rdx)
  lea    0x1(%rsi),%ecx
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L41
  movslq %ecx,%rcx
L23:
  mov    %ecx,%esi
  movb   $0x20,(%r9,%rcx,1)
  lea    0x1(%rcx),%eax
  cltd
  idiv   %r8d
  add    $0x1,%rcx
  test   %edx,%edx
  jne    L23
  jmp    L41
L18:
  ret
```

assistant: ```c
void DeTab(char s[], char d[], const int tabwidth) {
  int i, j;
  for (i = j = 0; (d[j] = s[i]) != '\0'; i++, j++) {
    if (d[j] == '\t') {
      d[j] = ' ';
      for (; (j + 1) % tabwidth != 0;) {
        d[++j] = ' ';
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DeTab>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r8d
  mov    %rsi,%r9
  add    $0x1,%rdi
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %al,(%rsi)
  test   %al,%al
  je     L55
  nopl   0x0(%rax)
L35:
  lea    0x1(%rcx),%esi
  cmp    $0x9,%al
  je     L24
L19:
  mov    %esi,%ecx
L26:
  movzbl (%rdi),%eax
  movslq %ecx,%rdx
  add    $0x1,%rdi
  add    %r9,%rdx
  mov    %al,(%rdx)
  test   %al,%al
  jne    L35
L55:
  ret
  nopl   (%rax)
L24:
  mov    %esi,%eax
  movb   $0x20,(%rdx)
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L19
  add    $0x2,%ecx
  movslq %ecx,%rsi
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %esi,%ecx
  movb   $0x20,-0x1(%r9,%rsi,1)
  add    $0x1,%rsi
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L6
  jmp    L26
```

assistant: ```c
void DeTab(char s[], char d[], const int tabwidth) {
  int i, j;
  for (i = j = 0; (d[j] = s[i]) != '\0'; i++, j++) {
    if (d[j] == '\t') {
      d[j] = ' ';
      for (; (j + 1) % tabwidth != 0;) {
        d[++j] = ' ';
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DeTab>:
  endbr64
  movzbl (%rdi),%eax
  mov    %edx,%r8d
  mov    %rsi,%r9
  add    $0x1,%rdi
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %al,(%rsi)
  test   %al,%al
  je     L6
  nopl   0x0(%rax)
L2:
  lea    0x1(%rcx),%esi
  cmp    $0x9,%al
  je     L8
L35:
  mov    %esi,%ecx
L21:
  movzbl (%rdi),%eax
  movslq %ecx,%rdx
  add    $0x1,%rdi
  add    %r9,%rdx
  mov    %al,(%rdx)
  test   %al,%al
  jne    L2
L6:
  ret
  nopl   (%rax)
L8:
  mov    %esi,%eax
  movb   $0x20,(%rdx)
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L35
  add    $0x2,%ecx
  movslq %ecx,%rsi
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %esi,%ecx
  movb   $0x20,-0x1(%r9,%rsi,1)
  add    $0x1,%rsi
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L0
  jmp    L21
```

assistant: ```c
void DeTab(char s[], char d[], const int tabwidth) {
  int i, j;
  for (i = j = 0; (d[j] = s[i]) != '\0'; i++, j++) {
    if (d[j] == '\t') {
      d[j] = ' ';
      for (; (j + 1) % tabwidth != 0;) {
        d[++j] = ' ';
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L1:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D29
data_type: string

tool: D10: Entr any integer:

tool: D19: %d

tool: D17: The number  %d is a even number 


tool: D29: The number %d is odd number

assistant: ```c
int main() {
  int i, a;
  printf("Entr any integer:");
  scanf("%d", &a);
  if ((a % 2) == 0) {
    printf("The number  %d is a even number \n", a);
  } else {
    printf("The number %d is odd number", a);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L14
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L14:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
type: string
name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D32: Entr any integer:

tool: D0: %d

tool: D25: The number  %d is a even number 


tool: D6: The number %d is odd number

assistant: ```c
int main() {
  int i, a;
  printf("Entr any integer:");
  scanf("%d", &a);
  if ((a % 2) == 0) {
    printf("The number  %d is a even number \n", a);
  } else {
    printf("The number %d is odd number", a);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L23
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D27
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string

tool: D16: Entr any integer:

tool: D27: %d

tool: D14: The number  %d is a even number 


tool: D30: The number %d is odd number

assistant: ```c
int main() {
  int i, a;
  printf("Entr any integer:");
  scanf("%d", &a);
  if ((a % 2) == 0) {
    printf("The number  %d is a even number \n", a);
  } else {
    printf("The number %d is odd number", a);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  jne    L3
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D30
type_guessed: string
name: read_data
arguments: data_tag: D8
type_guessed: string
name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D30: Entr any integer:

tool: D8: %d

tool: D21: The number  %d is a even number 


tool: D3: The number %d is odd number

assistant: ```c
int main() {
  int i, a;
  printf("Entr any integer:");
  scanf("%d", &a);
  if ((a % 2) == 0) {
    printf("The number  %d is a even number \n", a);
  } else {
    printf("The number %d is odd number", a);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<commandcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L155
L53:
  addq   $0x1,-0x20(%rbp)
L155:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  jle    L57
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L53
L57:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L53
  jmp    L148
L50:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L78
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L78
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  mov    %eax,%edx
  jmp    L161
L78:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
L161:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L148:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  jle    L3
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L56
L3:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L50
L56:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x20,(%rax)
  jmp    L117
L60:
  addq   $0x1,-0x20(%rbp)
L117:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x8,%al
  jle    L14
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jle    L60
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L60
  nop
L61:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int commandcpy(char *out, char *in) {
  int i = 0;
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while ((*in) && !((((*in) > 8) && ((*in) < 14)) || ((*in) == 32))) {
    *out++ = (((*in) > 64 && (*in) < 91) ? (*in) | 32 : (*in));
    in++;
    i++;
  }
  *out++ = ' ';
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while (*out++ = *in++)
    ;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<commandcpy>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rax
  movzbl (%rsi),%edx
  lea    -0x9(%rdx),%esi
  cmp    $0x4,%sil
  jbe    L80
  cmp    $0x20,%dl
  jne    L111
L80:
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%esi
  cmp    $0x4,%sil
  jbe    L80
  cmp    $0x20,%dl
  je     L80
L111:
  movzbl (%rax),%edx
  mov    $0x0,%edi
  test   %dl,%dl
  je     L10
L61:
  mov    %edx,%esi
  lea    -0x9(%rdx),%r8d
  cmp    $0x4,%r8b
  jbe    L10
  cmp    $0x20,%dl
  je     L10
  sub    $0x41,%esi
  mov    %edx,%r8d
  or     $0x20,%r8d
  cmp    $0x1a,%sil
  cmovb  %r8d,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  add    $0x1,%rax
  add    $0x1,%edi
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L61
L10:
  movb   $0x20,(%rcx)
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%esi
  cmp    $0x4,%sil
  jbe    L98
  cmp    $0x20,%dl
  jne    L34
L98:
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x9(%rdx),%esi
  cmp    $0x4,%sil
  jbe    L98
  cmp    $0x20,%dl
  je     L98
L34:
  mov    $0x0,%edx
L112:
  movzbl (%rax,%rdx,1),%esi
  mov    %sil,0x1(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %sil,%sil
  jne    L112
  mov    %edi,%eax
  ret
```

assistant: ```c
int commandcpy(char *out, char *in) {
  int i = 0;
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while ((*in) && !((((*in) > 8) && ((*in) < 14)) || ((*in) == 32))) {
    *out++ = (((*in) > 64 && (*in) < 91) ? (*in) | 32 : (*in));
    in++;
    i++;
  }
  *out++ = ' ';
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while (*out++ = *in++)
    ;
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<commandcpy>:
  endbr64
  jmp    L58
  cs nopw 0x0(%rax,%rax,1)
L64:
  add    $0x1,%rsi
L58:
  movzbl (%rsi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L64
  cmp    $0x20,%al
  je     L64
  xor    %r8d,%r8d
  test   %al,%al
  je     L118
  nopw   0x0(%rax,%rax,1)
L115:
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L118
  cmp    $0x20,%al
  je     L118
  lea    -0x41(%rax),%ecx
  mov    %eax,%edx
  or     $0x20,%edx
  cmp    $0x1a,%cl
  cmovb  %edx,%eax
  add    $0x1,%rsi
  add    $0x1,%rdi
  add    $0x1,%r8d
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L115
L118:
  movb   $0x20,(%rdi)
  movzbl (%rsi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  ja     L101
  xchg   %ax,%ax
L76:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L76
L101:
  cmp    $0x20,%al
  je     L76
  mov    $0x1,%edx
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
L85:
  mov    %al,(%rdi,%rdx,1)
  test   %al,%al
  jne    L17
  mov    %r8d,%eax
  ret
```

assistant: ```c
int commandcpy(char *out, char *in) {
  int i = 0;
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while ((*in) && !((((*in) > 8) && ((*in) < 14)) || ((*in) == 32))) {
    *out++ = (((*in) > 64 && (*in) < 91) ? (*in) | 32 : (*in));
    in++;
    i++;
  }
  *out++ = ' ';
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while (*out++ = *in++)
    ;
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<commandcpy>:
  endbr64
  movzbl (%rsi),%eax
  mov    %rdi,%rdx
  lea    -0x9(%rax),%ecx
  cmp    $0x4,%cl
  ja     L105
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  lea    -0x9(%rax),%ecx
  cmp    $0x4,%cl
  jbe    L44
L105:
  cmp    $0x20,%al
  je     L44
  xor    %r8d,%r8d
  test   %al,%al
  je     L48
  nopl   0x0(%rax,%rax,1)
L47:
  lea    -0x9(%rax),%ecx
  cmp    $0x4,%cl
  jbe    L48
  cmp    $0x20,%al
  je     L48
  lea    -0x41(%rax),%edi
  mov    %eax,%ecx
  or     $0x20,%ecx
  cmp    $0x1a,%dil
  cmovb  %ecx,%eax
  add    $0x1,%rsi
  add    $0x1,%rdx
  add    $0x1,%r8d
  mov    %al,-0x1(%rdx)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L47
L48:
  movb   $0x20,(%rdx)
  movzbl (%rsi),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x4,%cl
  ja     L66
  nopw   0x0(%rax,%rax,1)
L94:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  lea    -0x9(%rax),%ecx
  cmp    $0x4,%cl
  jbe    L94
L66:
  cmp    $0x20,%al
  je     L94
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L78:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x1(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L78
  mov    %r8d,%eax
  ret
```

assistant: ```c
int commandcpy(char *out, char *in) {
  int i = 0;
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while ((*in) && !((((*in) > 8) && ((*in) < 14)) || ((*in) == 32))) {
    *out++ = (((*in) > 64 && (*in) < 91) ? (*in) | 32 : (*in));
    in++;
    i++;
  }
  *out++ = ' ';
  while (((((*in) > 8) && ((*in) < 14)) || ((*in) == 32)))
    in++;
  while (*out++ = *in++)
    ;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<algebra1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  lea    (%rax,%rdx,1),%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int algebra1(int x) {
  int result;
  result = 3 * x + 6 * x * x;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<algebra1>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  lea    (%rax,%rax,2),%edx
  lea    (%rdi,%rdi,2),%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int algebra1(int x) {
  int result;
  result = 3 * x + 6 * x * x;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<algebra1>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  lea    (%rax,%rax,2),%edx
  lea    (%rdi,%rdi,2),%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int algebra1(int x) {
  int result;
  result = 3 * x + 6 * x * x;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<algebra1>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  lea    (%rax,%rax,2),%edx
  lea    (%rdi,%rdi,2),%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int algebra1(int x) {
  int result;
  result = 3 * x + 6 * x * x;
  return result;
}
```