ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_get_pgn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1c,%esi
  mov    $0x0,%edi
  call   <create_mask@plt>
  and    %eax,%ebx
  mov    %ebx,%ebp
  sar    $0x10,%ebp
  mov    $0x7,%esi
  mov    $0x0,%edi
  call   <create_mask@plt>
  and    %ebp,%eax
  cmp    $0xef,%eax
  jg     L1
  mov    $0x11,%esi
  mov    $0x0,%edi
  call   <create_mask@plt>
  shl    $0x8,%ebp
  and    %ebp,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x11,%esi
  mov    $0x0,%edi
  call   <create_mask@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sar    $0x8,%eax
  and    %edx,%eax
  jmp    L10
```

assistant: ```c
int parse_get_pgn(u_int32_t can_id) {
  int PGN;
  can_id = (can_id & create_mask(0, 28));
  int PF = (can_id >> 16) & create_mask(0, 7);
  if (PF < 240) {
    PGN = ((can_id >> 16) << 8) & create_mask(0, 17);
  } else {
    PGN = (can_id >> 8) & create_mask(0, 17);
  }
  return PGN;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_get_pgn>:
  endbr64
  push   %rbp
  mov    $0x1c,%esi
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <create_mask@plt>
  mov    $0x7,%esi
  xor    %edi,%edi
  and    %eax,%ebx
  call   <create_mask@plt>
  mov    %ebx,%ebp
  mov    $0x11,%esi
  xor    %edi,%edi
  sar    $0x10,%ebp
  and    %ebp,%eax
  cmp    $0xef,%eax
  jg     L6
  call   <create_mask@plt>
  shl    $0x8,%ebp
  add    $0x8,%rsp
  and    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  call   <create_mask@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sar    $0x8,%eax
  and    %r8d,%eax
  ret
```

assistant: ```c
int parse_get_pgn(u_int32_t can_id) {
  int PGN;
  can_id = (can_id & create_mask(0, 28));
  int PF = (can_id >> 16) & create_mask(0, 7);
  if (PF < 240) {
    PGN = ((can_id >> 16) << 8) & create_mask(0, 17);
  } else {
    PGN = (can_id >> 8) & create_mask(0, 17);
  }
  return PGN;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<parse_get_pgn>:
  endbr64
  push   %rbp
  mov    $0x1c,%esi
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <create_mask@plt>
  mov    $0x7,%esi
  xor    %edi,%edi
  and    %eax,%ebx
  call   <create_mask@plt>
  mov    %ebx,%ebp
  mov    $0x11,%esi
  xor    %edi,%edi
  sar    $0x10,%ebp
  and    %ebp,%eax
  cmp    $0xef,%eax
  jg     L7
  call   <create_mask@plt>
  shl    $0x8,%ebp
  add    $0x8,%rsp
  and    %ebp,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  call   <create_mask@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sar    $0x8,%eax
  and    %r8d,%eax
  ret
```

assistant: ```c
int parse_get_pgn(u_int32_t can_id) {
  int PGN;
  can_id = (can_id & create_mask(0, 28));
  int PF = (can_id >> 16) & create_mask(0, 7);
  if (PF < 240) {
    PGN = ((can_id >> 16) << 8) & create_mask(0, 17);
  } else {
    PGN = (can_id >> 8) & create_mask(0, 17);
  }
  return PGN;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numberOfOnes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L22
L23:
  mov    -0x18(%rbp),%rax
  cqto
  shr    $0x3f,%rdx
  add    %rdx,%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  jne    L17
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <abs@plt>
  test   %rax,%rax
  jne    L23
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long numberOfOnes(long long a) {
  long long foo = 0;
  while (abs(a)) {
    if (a % 2 == 1)
      foo += 1;
    a /= 10;
  }
  return foo;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<numberOfOnes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  movabs $0x6666666666666667,%r12
  jmp    L19
L5:
  mov    %rbx,%rdx
  shr    $0x3f,%rdx
  lea    (%rbx,%rdx,1),%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  mov    %rbx,%rax
  imul   %r12
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rbx
  sub    %rax,%rbx
L19:
  mov    %rbx,%rdi
  call   <abs@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long numberOfOnes(long long a) {
  long long foo = 0;
  while (abs(a)) {
    if (a % 2 == 1)
      foo += 1;
    a /= 10;
  }
  return foo;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numberOfOnes>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movabs $0x6666666666666667,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  shr    $0x3f,%rdx
  sar    $0x3f,%rcx
  lea    (%rbx,%rdx,1),%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  sete   %al
  movzbl %al,%eax
  add    %rax,%r12
  mov    %rbx,%rax
  imul   %rbp
  mov    %rdx,%rbx
  sar    $0x2,%rbx
  sub    %rcx,%rbx
L14:
  mov    %rbx,%rdi
  call   <abs@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long numberOfOnes(long long a) {
  long long foo = 0;
  while (abs(a)) {
    if (a % 2 == 1)
      foo += 1;
    a /= 10;
  }
  return foo;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<numberOfOnes>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movabs $0x6666666666666667,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  shr    $0x3f,%rdx
  sar    $0x3f,%rcx
  lea    (%rbx,%rdx,1),%rax
  and    $0x1,%eax
  sub    %rdx,%rax
  cmp    $0x1,%rax
  sete   %al
  movzbl %al,%eax
  add    %rax,%r12
  mov    %rbx,%rax
  imul   %rbp
  mov    %rdx,%rbx
  sar    $0x2,%rbx
  sub    %rcx,%rbx
L6:
  mov    %rbx,%rdi
  call   <abs@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long numberOfOnes(long long a) {
  long long foo = 0;
  while (abs(a)) {
    if (a % 2 == 1)
      foo += 1;
    a /= 10;
  }
  return foo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %edi,-0x234(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x240(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x220(%rbp)
  mov    -0x240(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x218(%rbp)
  jmp    L23
L0:
  mov    -0x218(%rbp),%rcx
  mov    -0x224(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
L23:
  mov    -0x220(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x224(%rbp)
  cmpl   $0x0,-0x224(%rbp)
  jg     L0
  mov    -0x220(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D12: r+

tool: D1: w+

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp_s, *fp_t;
  int flag;
  char buf[512];
  fp_s = fopen(argv[1], "r+");
  fp_t = fopen(argv[2], "w+");
  while ((flag = fread(buf, 1, 512, fp_s)) > 0)
    fwrite(buf, 1, flag, fp_t);
  fclose(fp_s);
  fclose(fp_t);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rdi
  lea    D18(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    0x10(%rbx),%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    %rsp,%rbx
  jmp    L20
L5:
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L20:
  mov    %rbp,%rcx
  mov    $0x200,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L5
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D13
type: string

tool: D18: r+

tool: D13: w+

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp_s, *fp_t;
  int flag;
  char buf[512];
  fp_s = fopen(argv[1], "r+");
  fp_t = fopen(argv[2], "w+");
  while ((flag = fread(buf, 1, 512, fp_s)) > 0)
    fwrite(buf, 1, flag, fp_t);
  fclose(fp_s);
  fclose(fp_t);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x210,%rsp
  mov    0x8(%rsi),%rdi
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    0x10(%rbx),%rdi
  lea    D1(%rip),%rsi
  mov    %rsp,%rbx
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L17
L2:
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L17:
  mov    $0x200,%edx
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L2
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D8: r+

tool: D1: w+

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp_s, *fp_t;
  int flag;
  char buf[512];
  fp_s = fopen(argv[1], "r+");
  fp_t = fopen(argv[2], "w+");
  while ((flag = fread(buf, 1, 512, fp_s)) > 0)
    fwrite(buf, 1, flag, fp_t);
  fclose(fp_s);
  fclose(fp_t);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x210,%rsp
  mov    0x8(%rsi),%rdi
  lea    D11(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    0x10(%rbx),%rdi
  lea    D8(%rip),%rsi
  mov    %rsp,%rbx
  mov    %rax,%rbp
  call   <fopen@plt>
  mov    %rax,%r12
  jmp    L25
L10:
  mov    %r12,%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L25:
  mov    $0x200,%edx
  mov    %rbp,%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L10
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x210,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D11: r+

tool: D8: w+

assistant: ```c
int main(int argc, char **argv) {
  FILE *fp_s, *fp_t;
  int flag;
  char buf[512];
  fp_s = fopen(argv[1], "r+");
  fp_t = fopen(argv[2], "w+");
  while ((flag = fread(buf, 1, 512, fp_s)) > 0)
    fwrite(buf, 1, flag, fp_t);
  fclose(fp_s);
  fclose(fp_t);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_log_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x2,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <send_bytes@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: 2.

assistant: ```c
int send_log_in(int fd, const char *name) {
  size_t len = strlen(name) + 2;
  char *msg = malloc((len + 1) * sizeof(char));
  strcpy(msg, "2.");
  strcpy(msg + 2, name);
  return send_bytes(fd, msg, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<send_log_in>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x2(%rax),%ebx
  movslq %ebx,%rbx
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x2(%rbp),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <send_bytes@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: 2.

assistant: ```c
int send_log_in(int fd, const char *name) {
  size_t len = strlen(name) + 2;
  char *msg = malloc((len + 1) * sizeof(char));
  strcpy(msg, "2.");
  strcpy(msg + 2, name);
  return send_bytes(fd, msg, len);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<send_log_in>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rax),%r12d
  movslq %r12d,%r12
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x2(%rbp),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <send_bytes@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: 2.

assistant: ```c
int send_log_in(int fd, const char *name) {
  size_t len = strlen(name) + 2;
  char *msg = malloc((len + 1) * sizeof(char));
  strcpy(msg, "2.");
  strcpy(msg + 2, name);
  return send_bytes(fd, msg, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<send_log_in>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x2(%rax),%r12d
  movslq %r12d,%r12
  lea    0x1(%r12),%rdi
  call   <malloc@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x2(%rbp),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <send_bytes@plt>
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: 2.

assistant: ```c
int send_log_in(int fd, const char *name) {
  size_t len = strlen(name) + 2;
  char *msg = malloc((len + 1) * sizeof(char));
  strcpy(msg, "2.");
  strcpy(msg + 2, name);
  return send_bytes(fd, msg, len);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <sqrt@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D17(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D29(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: byte[8]
name: parse_data
arguments: data_tag: D29
datatype: byte[8]
name: parse_data
arguments: data_tag: D22
datatype: string

tool: {"D17": [0x9a,0x99,0x99,0x99,0x99,0x99,0x13,0x40]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D22: %.8lf


assistant: ```c
int main() {
  printf("%.8lf\n", 1 + 2 * sqrt(3) / (5 - 0.1));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sqrt@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  D23(%rip),%xmm0
  addsd  D25(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D25
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: {"D23": [0x9a,0x99,0x99,0x99,0x99,0x99,0x13,0x40]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D12: %.8lf


assistant: ```c
int main() {
  printf("%.8lf\n", 1 + 2 * sqrt(3) / (5 - 0.1));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  lea    D22(%rip),%rdi
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  divsd  D29(%rip),%xmm0
  addsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D22
data_type: string
name: disassemble_data
arguments: label: D29
data_type: byte[8]
name: disassemble_data
arguments: label: D26
data_type: byte[8]

tool: D22: %.8lf


tool: {"D29": [0x9a,0x99,0x99,0x99,0x99,0x99,0x13,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int main() {
  printf("%.8lf\n", 1 + 2 * sqrt(3) / (5 - 0.1));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  lea    D17(%rip),%rdi
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  divsd  D22(%rip),%xmm0
  addsd  D20(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D22
type: byte[8]
name: extract_symbolic_data
arguments: label: D20
type: byte[8]

tool: D17: %.8lf


tool: {"D22": [0x9a,0x99,0x99,0x99,0x99,0x99,0x13,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int main() {
  printf("%.8lf\n", 1 + 2 * sqrt(3) / (5 - 0.1));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getStrPtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getStrPtr(char *str) {
  char *ret = malloc(sizeof(char) * (strlen(str) + 1));
  strcpy(ret, str);
  ret[strlen(str)] = '\0';
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getStrPtr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getStrPtr(char *str) {
  char *ret = malloc(sizeof(char) * (strlen(str) + 1));
  strcpy(ret, str);
  ret[strlen(str)] = '\0';
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getStrPtr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getStrPtr(char *str) {
  char *ret = malloc(sizeof(char) * (strlen(str) + 1));
  strcpy(ret, str);
  ret[strlen(str)] = '\0';
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getStrPtr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getStrPtr(char *str) {
  char *ret = malloc(sizeof(char) * (strlen(str) + 1));
  strcpy(ret, str);
  ret[strlen(str)] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ina_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x20000008,%edi
  call   <SysCtlPeripheralEnable@plt>
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0xff,%edx
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ina_init(void) {
  SysCtlPeripheralEnable(0x20000008);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000040);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000080);
  GPIOPinWrite(0x40007000, 0x00000080, 0xff);
  GPIOPinWrite(0x40007000, 0x00000040, 0xff);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ina_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20000008,%edi
  call   <SysCtlPeripheralEnable@plt>
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0xff,%edx
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ina_init(void) {
  SysCtlPeripheralEnable(0x20000008);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000040);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000080);
  GPIOPinWrite(0x40007000, 0x00000080, 0xff);
  GPIOPinWrite(0x40007000, 0x00000040, 0xff);
}
```