user: 请从给定的汇编指令推导出C源代码:

```asm
<transpose_alignment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x10(,%rsi,8),%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x4(%rsp)
  mov    %rcx,0x18(%rsp)
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L46
L1:
  xor    %ebx,%ebx
  cmpl   $0xffffffff,0x4(%rsp)
  mov    0x8(%rsp),%r14
  lea    0x0(,%r13,4),%r12d
  lea    D3(%rip),%r15
  jge    L99
  jmp    L122
  nopw   0x0(%rax,%rax,1)
L170:
  lea    0x1(%rbx),%eax
  add    $0x8,%r14
  cmp    %ebx,0x4(%rsp)
  jl     L122
L156:
  mov    %eax,%ebx
L99:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L170
  mov    %r15,%rdi
  add    $0x8,%r14
  call   <Die@plt>
  lea    0x1(%rbx),%eax
  cmp    %ebx,0x4(%rsp)
  jge    L156
  nopl   0x0(%rax)
L122:
  test   %r13d,%r13d
  jle    L109
  mov    0x8(%rsp),%rax
  movslq 0x4(%rsp),%rbx
  lea    0x0(,%r13,4),%rsi
  mov    %rsi,0x10(%rsp)
  mov    0x8(%rax,%rbx,8),%r12
  mov    (%rax),%rdi
  lea    (%r12,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L110
  lea    (%rdi,%rsi,1),%rax
  cmp    %rax,%r12
  jb     L132
L110:
  mov    0x10(%rsp),%r14
  mov    $0xff,%esi
  mov    %r14,%rdx
  call   <memset@plt>
  mov    %r14,%rdx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L127:
  movabs $0x8000000000006001,%r14
  xor    %r15d,%r15d
  nopl   (%rax)
L172:
  mov    0x8(%rsp),%rax
  xor    %r12d,%r12d
  lea    0x8(%rax),%r13
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L68
  jmp    L153
  xchg   %ax,%ax
L189:
  call   <SymbolIndex@plt>
L133:
  mov    0x0(%r13),%rdx
  add    $0x1,%r12
  add    $0x8,%r13
  mov    %eax,(%rdx,%r15,1)
  cmp    %rbx,%r12
  je     L153
L68:
  mov    0x0(%rbp),%rax
  movsbl (%rax,%r12,1),%edi
  lea    -0x20(%rdi),%edx
  cmp    $0x3f,%dl
  ja     L189
  bt     %rdx,%r14
  mov    $0xffffffff,%eax
  jb     L133
  jmp    L189
  nopl   0x0(%rax,%rax,1)
L153:
  add    $0x4,%r15
  add    $0x8,%rbp
  cmp    %r15,0x10(%rsp)
  jne    L172
L109:
  mov    0x18(%rsp),%rax
  mov    0x8(%rsp),%rsi
  mov    %rsi,(%rax)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  lea    D3(%rip),%rdi
  call   <Die@plt>
  jmp    L1
L132:
  xor    %eax,%eax
  xchg   %ax,%ax
L14:
  movl   $0xffffffff,(%rdi,%rax,4)
  movl   $0xffffffff,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L14
  jmp    L127
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: malloc failed

assistant: ```c
void transpose_alignment(char **aseqs, int alen, int nseq, int ***ret_aseqsT) {
  int **aseqsT;
  int acol;
  int seqidx;
  if ((aseqsT = (int **)malloc((alen + 2) * sizeof(int *))) == NULL)
    Die("malloc failed");
  for (acol = 0; acol <= alen + 1; acol++)
    if ((aseqsT[acol] = (int *)malloc(nseq * sizeof(int))) == NULL)
      Die("malloc failed");
  for (seqidx = 0; seqidx < nseq; seqidx++) {
    aseqsT[0][seqidx] = -1;
    aseqsT[alen + 1][seqidx] = -1;
  }
  for (seqidx = 0; seqidx < nseq; seqidx++)
    for (acol = 0; acol < alen; acol++)
      aseqsT[acol + 1][seqidx] = ((aseqs[seqidx][acol]) == ' ' || (aseqs[seqidx][acol]) == '.' || (aseqs[seqidx][acol]) == '_' || (aseqs[seqidx][acol]) == '-') ? -1 : SymbolIndex(aseqs[seqidx][acol]);
  *ret_aseqsT = aseqsT;
}
```