ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<mon_restart>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <monLock@plt>
  mov    %r12d,%edi
  call   <_monrestart@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int mon_restart(int val) {
  int ret;
  monLock();
  ret = _monrestart(val);
  monUnlock();
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mon_restart>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <monLock@plt>
  mov    %r12d,%edi
  call   <_monrestart@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int mon_restart(int val) {
  int ret;
  monLock();
  ret = _monrestart(val);
  monUnlock();
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<StrCat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L21:
  addq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  jmp    L8
L6:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L8:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *StrCat(char *dest, const char *src) {
  char *str = dest;
  while (*dest != '\0') {
    dest++;
  }
  while ((*dest = *src) != '\0') {
    dest++;
    src++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StrCat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L2
  mov    %rdi,%rdx
L9:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L9
L18:
  movzbl (%rsi),%ecx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L15
  mov    $0x1,%ecx
L35:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdx,%rcx,1)
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L35
L15:
  ret
L2:
  mov    %rdi,%rdx
  jmp    L18
```

assistant: ```c
char *StrCat(char *dest, const char *src) {
  char *str = dest;
  while (*dest != '\0') {
    dest++;
  }
  while ((*dest = *src) != '\0') {
    dest++;
    src++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<StrCat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rdx
  je     L2
  nop
L34:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L34
L2:
  movzbl (%rsi),%ecx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L11
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdx,%rcx,1)
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L24
L11:
  ret
```

assistant: ```c
char *StrCat(char *dest, const char *src) {
  char *str = dest;
  while (*dest != '\0') {
    dest++;
  }
  while ((*dest = *src) != '\0') {
    dest++;
    src++;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<StrCat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rdx
  je     L35
  nop
L14:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L14
L35:
  movzbl (%rsi),%ecx
  mov    %cl,(%rdx)
  test   %cl,%cl
  je     L4
  mov    $0x1,%ecx
  nopw   0x0(%rax,%rax,1)
L25:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdx,%rcx,1)
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L25
L4:
  ret
```

assistant: ```c
char *StrCat(char *dest, const char *src) {
  char *str = dest;
  while (*dest != '\0') {
    dest++;
  }
  while ((*dest = *src) != '\0') {
    dest++;
    src++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_safelen_simdlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L26:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0xf,-0x4(%rbp)
  jle    L26
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L30:
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0xf,-0x4(%rbp)
  jle    L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_safelen_simdlen() {
  int i;
#pragma omp target simd simdlen(6) safelen(5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target simd safelen(5) simdlen(6)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_safelen_simdlen>:
  endbr64
  ret
```

assistant: ```c
void test_safelen_simdlen() {
  int i;
#pragma omp target simd simdlen(6) safelen(5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target simd safelen(5) simdlen(6)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_safelen_simdlen>:
  endbr64
  ret
```

assistant: ```c
void test_safelen_simdlen() {
  int i;
#pragma omp target simd simdlen(6) safelen(5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target simd safelen(5) simdlen(6)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_safelen_simdlen>:
  endbr64
  ret
```

assistant: ```c
void test_safelen_simdlen() {
  int i;
#pragma omp target simd simdlen(6) safelen(5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target simd safelen(5) simdlen(6)
  for (i = 0; i < 16; ++i)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnbld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L5:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jbe    L38
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
L38:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L16
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L16:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strnbld(char *dest, char const *src, size_t n) {
  int count = 0;
  while (count < n && (*dest = *src++)) {
    dest++;
    count++;
  }
  if (count >= n) {
    *dest = '\0';
  }
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnbld>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L48
  lea    (%rdi,%rdx,1),%r8
  mov    $0x0,%ecx
L59:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax)
  test   %dil,%dil
  je     L29
  add    $0x1,%rax
  add    $0x1,%rcx
  cmp    %r8,%rax
  jne    L59
L4:
  movb   $0x0,(%r8)
  mov    %r8,%rax
  ret
L29:
  cmp    %rcx,%rdx
  jbe    L3
  ret
L3:
  mov    %rax,%r8
  jmp    L4
L48:
  mov    %rdi,%r8
  jmp    L4
```

assistant: ```c
char *strnbld(char *dest, char const *src, size_t n) {
  int count = 0;
  while (count < n && (*dest = *src++)) {
    dest++;
    count++;
  }
  if (count >= n) {
    *dest = '\0';
  }
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strnbld>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L5
  add    %rsi,%rdx
  jmp    L38
  nopl   0x0(%rax)
L13:
  add    $0x1,%rax
  cmp    %rsi,%rdx
  je     L5
L38:
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L13
  ret
  nop
L5:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strnbld(char *dest, char const *src, size_t n) {
  int count = 0;
  while (count < n && (*dest = *src++)) {
    dest++;
    count++;
  }
  if (count >= n) {
    *dest = '\0';
  }
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strnbld>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L31
  add    %rsi,%rdx
  jmp    L33
  nopl   0x0(%rax)
L0:
  add    $0x1,%rax
  cmp    %rsi,%rdx
  je     L31
L33:
  movzbl (%rsi),%ecx
  add    $0x1,%rsi
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L0
  ret
  nop
L31:
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *strnbld(char *dest, char const *src, size_t n) {
  int count = 0;
  while (count < n && (*dest = *src++)) {
    dest++;
    count++;
  }
  if (count >= n) {
    *dest = '\0';
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L26:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jbe    L15
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L17
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L17
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L17
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  ja     L26
L17:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (tolower(*s1) && tolower(*s2) && (tolower(*s1) == tolower(*s2)) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return tolower(*s1) - tolower(*s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncasecmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  lea    0x1(%rdx),%r15
  mov    $0x1,%ebp
  jmp    L3
L28:
  add    $0x1,%rbp
L3:
  movsbl (%r12),%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L61
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L61
  movsbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L61
  cmp    %r15,%rbp
  je     L61
  cmp    %rbp,%r14
  jbe    L28
  add    $0x1,%r12
  add    $0x1,%r13
  jmp    L28
L61:
  movsbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (tolower(*s1) && tolower(*s2) && (tolower(*s1) == tolower(*s2)) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return tolower(*s1) - tolower(*s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncasecmp>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L52:
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L23
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L23
  cmp    %rbp,%r15
  je     L23
  cmp    %rbp,%r14
  jbe    L30
  add    $0x1,%r12
  add    $0x1,%r13
L30:
  add    $0x1,%rbp
L34:
  movsbl (%r12),%edi
  call   <tolower@plt>
  test   %eax,%eax
  jne    L52
L23:
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (tolower(*s1) && tolower(*s2) && (tolower(*s1) == tolower(*s2)) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return tolower(*s1) - tolower(*s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncasecmp>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L45
  cs nopw 0x0(%rax,%rax,1)
L23:
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  test   %eax,%eax
  je     L33
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L33
  cmp    %rbp,%r15
  je     L33
  cmp    %rbp,%r14
  jbe    L54
  add    $0x1,%r12
  add    $0x1,%r13
L54:
  add    $0x1,%rbp
L45:
  movsbl (%r12),%edi
  call   <tolower@plt>
  test   %eax,%eax
  jne    L23
L33:
  movsbl (%r12),%edi
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (tolower(*s1) && tolower(*s2) && (tolower(*s1) == tolower(*s2)) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return tolower(*s1) - tolower(*s2);
}
```
user: What is the c source code of the assembly code below:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L11
  mov    %rsi,%r14
  mov    %rdx,%r15
  test   %rsi,%rsi
  lea    D4(%rip),%rax
  cmove  %rax,%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  test   %r15,%r15
  lea    D4(%rip),%rax
  cmove  %rax,%r15
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  mov    $0x0,%r12d
  movslq %ebx,%rbx
  jmp    L34
L56:
  lea    (%rax,%rbx,1),%rdi
  add    $0x1,%r12d
L34:
  mov    %r14,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L56
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r13d,%ebx
  mov    %r13d,%eax
  sub    0xc(%rsp),%eax
  imul   %r12d,%eax
  lea    0x1(%rax,%rdx,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%r13
  test   %rax,%rax
  je     L4
  test   %r12d,%r12d
  je     L37
  movslq %ebx,%rax
  mov    %rax,0x10(%rsp)
L47:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  sub    %rbp,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rdx
  lea    (%rax,%rdx,1),%rdi
  mov    %r15,%rsi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  lea    (%rax,%rcx,1),%r13
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L47
L46:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
L4:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    0x18(%rsp),%r13
  jmp    L46
L11:
  mov    %rdi,0x18(%rsp)
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: 

assistant: ```c
char *str_replace(const char *orig, const char *rep, const char *with) {
  char *result;
  const char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep)
    rep = "";
  len_rep = strlen(rep);
  if (!with)
    with = "";
  len_with = strlen(with);
  ins = orig;
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  je     L46
  test   %rsi,%rsi
  mov    %rsi,%rbp
  lea    D7(%rip),%rbx
  mov    %rdx,%r12
  cmove  %rbx,%rbp
  mov    %rdi,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %r12,%r12
  cmove  %rbx,%r12
  movslq %eax,%r14
  xor    %ebx,%ebx
  mov    %r14d,0xc(%rsp)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,0x10(%rsp)
  jmp    L74
  nopl   0x0(%rax)
L73:
  lea    (%rax,%r14,1),%rdi
  add    $0x1,%ebx
L74:
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L73
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r14d
  mov    %eax,%r9d
  mov    %r14d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r9,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L46
  lea    -0x1(%rbx),%r15d
  test   %ebx,%ebx
  je     L45
  movslq %r14d,%rax
  mov    %rcx,%r14
  mov    %rax,0x10(%rsp)
L57:
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  sub    %r13,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r14
  add    %rbx,%r13
  sub    $0x1,%r15d
  jae    L57
L18:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L60:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L46:
  movq   $0x0,0x18(%rsp)
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L45:
  mov    0x18(%rsp),%r14
  jmp    L18
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: 

assistant: ```c
char *str_replace(const char *orig, const char *rep, const char *with) {
  char *result;
  const char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep)
    rep = "";
  len_rep = strlen(rep);
  if (!with)
    with = "";
  len_with = strlen(with);
  ins = orig;
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  je     L38
  test   %rsi,%rsi
  mov    %rsi,%rbp
  lea    D3(%rip),%rbx
  mov    %rdx,%r12
  cmove  %rbx,%rbp
  mov    %rdi,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %r12,%r12
  cmove  %rbx,%r12
  movslq %eax,%r14
  xor    %ebx,%ebx
  mov    %r14d,0xc(%rsp)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,0x10(%rsp)
  jmp    L65
  nopl   0x0(%rax)
L41:
  lea    (%rax,%r14,1),%rdi
  add    $0x1,%ebx
L65:
  mov    %rbp,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L41
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r14d
  mov    %eax,%r9d
  mov    %r14d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r9,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L38
  lea    -0x1(%rbx),%r15d
  test   %ebx,%ebx
  je     L8
  movslq %r14d,%rax
  mov    %rcx,%r14
  mov    %rax,0x10(%rsp)
L73:
  mov    %r13,%rdi
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  sub    %r13,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r12,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r14
  add    %rbx,%r13
  sub    $0x1,%r15d
  jae    L73
L24:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L43:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L38:
  movq   $0x0,0x18(%rsp)
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rax,%r14
  jmp    L24
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: 

assistant: ```c
char *str_replace(const char *orig, const char *rep, const char *with) {
  char *result;
  const char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep)
    rep = "";
  len_rep = strlen(rep);
  if (!with)
    with = "";
  len_with = strlen(with);
  ins = orig;
  for (count = 0; (tmp = strstr(ins, rep)); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StrAppendMax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  jmp    L17
L14:
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
char *StrAppendMax(char *target, size_t max, const char *source) {
  assert((0 != (target)));
  assert((0 != (source)));
  assert(max > 0);
  max -= strlen((target)) + 1;
  return (max > 0) ? strncat(target, source, max) : target;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<StrAppendMax>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx),%rdx
  sub    %rax,%rdx
  jne    L11
L0:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  jmp    L0
```

assistant: ```c
char *StrAppendMax(char *target, size_t max, const char *source) {
  assert((0 != (target)));
  assert((0 != (source)));
  assert(max > 0);
  max -= strlen((target)) + 1;
  return (max > 0) ? strncat(target, source, max) : target;
}
```