ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ina_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20000008,%edi
  call   <SysCtlPeripheralEnable@plt>
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0xff,%edx
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  add    $0x8,%rsp
  jmp    1070 <GPIOPinWrite@plt>
```

assistant: ```c
void ina_init(void) {
  SysCtlPeripheralEnable(0x20000008);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000040);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000080);
  GPIOPinWrite(0x40007000, 0x00000080, 0xff);
  GPIOPinWrite(0x40007000, 0x00000040, 0xff);
}
```
user: What is the c source code of the assembly code below:

```asm
<ina_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x20000008,%edi
  call   <SysCtlPeripheralEnable@plt>
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinTypeGPIOOutput@plt>
  mov    $0xff,%edx
  mov    $0x80,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x40,%esi
  mov    $0x40007000,%edi
  add    $0x8,%rsp
  jmp    1070 <GPIOPinWrite@plt>
```

assistant: ```c
void ina_init(void) {
  SysCtlPeripheralEnable(0x20000008);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000040);
  GPIOPinTypeGPIOOutput(0x40007000, 0x00000080);
  GPIOPinWrite(0x40007000, 0x00000080, 0xff);
  GPIOPinWrite(0x40007000, 0x00000040, 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x11,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = 17;
  y = x++ + 1;
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x12,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = 17;
  y = x++ + 1;
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x12,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = 17;
  y = x++ + 1;
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x12,%eax
  ret
```

assistant: ```c
int main() {
  int x;
  int y;
  x = 17;
  y = x++ + 1;
  return y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stSafeCFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void stSafeCFree(void *mem) {
  if (mem != NULL) {
    free(mem);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stSafeCFree>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void stSafeCFree(void *mem) {
  if (mem != NULL) {
    free(mem);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stSafeCFree>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void stSafeCFree(void *mem) {
  if (mem != NULL) {
    free(mem);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stSafeCFree>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void stSafeCFree(void *mem) {
  if (mem != NULL) {
    free(mem);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<testrun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <clc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: %d bytes:%d


assistant: ```c
void testrun(char *a1, char *a2, int l) {
  int cc;
  cc = clc(a1, a2, l);
  printf("%d bytes:%d\n", l, cc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<testrun>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <clc@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d bytes:%d


assistant: ```c
void testrun(char *a1, char *a2, int l) {
  int cc;
  cc = clc(a1, a2, l);
  printf("%d bytes:%d\n", l, cc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testrun>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <clc@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: %d bytes:%d


assistant: ```c
void testrun(char *a1, char *a2, int l) {
  int cc;
  cc = clc(a1, a2, l);
  printf("%d bytes:%d\n", l, cc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testrun>:
  endbr64
  push   %rbp
  mov    %edx,%ebp
  call   <clc@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: %d bytes:%d


assistant: ```c
void testrun(char *a1, char *a2, int l) {
  int cc;
  cc = clc(a1, a2, l);
  printf("%d bytes:%d\n", l, cc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dircmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L118
L65:
  addq   $0x1,-0x18(%rbp)
L118:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L65
  jmp    L59
L44:
  addq   $0x1,-0x20(%rbp)
L59:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L44
  jmp    L108
L64:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L126
  mov    $0x0,%eax
  jmp    L46
L126:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  je     L87
  jmp    L43
L29:
  addq   $0x1,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L29
  subq   $0x1,-0x18(%rbp)
L87:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  je     L122
  jmp    L16
L12:
  addq   $0x1,-0x20(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L12
  subq   $0x1,-0x20(%rbp)
L122:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L108:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L64
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L46:
  leave
  ret
```

assistant: ```c
int dircmp(char *s, char *t) {
  int check_string(char);
  char *tmps, *tmpt;
  tmps = s;
  tmpt = t;
  while (check_string(*s))
    s++;
  while (check_string(*t))
    t++;
  for (; *s == *t; s++, t++) {
    if (*s == '\0')
      return 0;
    if (check_string(*s)) {
      while (check_string(*s))
        s++;
      s--;
    }
    if (check_string(*t)) {
      while (check_string(*t))
        t++;
      t--;
    }
  }
  return *s - *t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dircmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  jmp    L40
L82:
  add    $0x1,%rbp
L40:
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L82
  jmp    L113
L10:
  add    $0x1,%rbx
L113:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L10
  movzbl 0x0(%rbp),%edi
  movzbl (%rbx),%eax
  cmp    %al,%dil
  je     L111
L115:
  movsbl %dil,%edi
  movsbl %al,%eax
  sub    %eax,%edi
  mov    %edi,%r12d
L124:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  add    $0x1,%rbp
L74:
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L22
  lea    -0x1(%rbp),%r13
  jmp    L77
L109:
  add    $0x1,%rbx
L34:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L109
  lea    -0x1(%rbx),%rax
L98:
  lea    0x1(%r13),%rbp
  lea    0x1(%rax),%rbx
  movzbl 0x1(%r13),%edi
  movzbl 0x1(%rax),%eax
  cmp    %al,%dil
  jne    L115
L111:
  test   %dil,%dil
  je     L124
  movsbl %dil,%edi
  call   <check_string@plt>
  mov    %rbp,%r13
  test   %eax,%eax
  jne    L74
L77:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L34
  mov    %rbx,%rax
  jmp    L98
```

assistant: ```c
int dircmp(char *s, char *t) {
  int check_string(char);
  char *tmps, *tmpt;
  tmps = s;
  tmpt = t;
  while (check_string(*s))
    s++;
  while (check_string(*t))
    t++;
  for (; *s == *t; s++, t++) {
    if (*s == '\0')
      return 0;
    if (check_string(*s)) {
      while (check_string(*s))
        s++;
      s--;
    }
    if (check_string(*t)) {
      while (check_string(*t))
        t++;
      t--;
    }
  }
  return *s - *t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dircmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L85
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x1,%rbp
L85:
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L2
  movsbl (%rbx),%edi
  call   <check_string@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L75
L147:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <check_string@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L147
L75:
  movsbl 0x0(%rbp),%edi
  movsbl (%rbx),%eax
  cmp    %al,%dil
  je     L103
  jmp    L60
  nopl   (%rax)
L38:
  mov    %rbp,%r13
  add    $0x1,%rbp
L104:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L138
  mov    %rbx,%rax
  movsbl 0x1(%r13),%edi
  add    $0x1,%rbx
  movsbl 0x1(%rax),%eax
  cmp    %al,%dil
  jne    L60
L103:
  test   %dil,%dil
  je     L11
  call   <check_string@plt>
  test   %eax,%eax
  je     L38
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  je     L118
  nopl   0x0(%rax,%rax,1)
L30:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  call   <check_string@plt>
  test   %eax,%eax
  jne    L30
L118:
  lea    -0x1(%rbp),%r13
  jmp    L104
  nopw   0x0(%rax,%rax,1)
L83:
  add    $0x1,%rbx
L138:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L83
  lea    -0x1(%rbx),%rax
  movsbl 0x1(%r13),%edi
  movsbl 0x1(%rax),%eax
  cmp    %al,%dil
  je     L103
L60:
  sub    %eax,%edi
  mov    %edi,%r12d
L11:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dircmp(char *s, char *t) {
  int check_string(char);
  char *tmps, *tmpt;
  tmps = s;
  tmpt = t;
  while (check_string(*s))
    s++;
  while (check_string(*t))
    t++;
  for (; *s == *t; s++, t++) {
    if (*s == '\0')
      return 0;
    if (check_string(*s)) {
      while (check_string(*s))
        s++;
      s--;
    }
    if (check_string(*t)) {
      while (check_string(*t))
        t++;
      t--;
    }
  }
  return *s - *t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dircmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L146:
  add    $0x1,%rbp
L78:
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L146
  movsbl (%rbx),%edi
  call   <check_string@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L136
L96:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <check_string@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L96
L136:
  movsbl 0x0(%rbp),%edi
  movsbl (%rbx),%eax
  cmp    %al,%dil
  je     L71
  jmp    L40
  nopl   (%rax)
L105:
  mov    %rbp,%r13
  add    $0x1,%rbp
L62:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L32
  mov    %rbx,%rax
  movsbl 0x1(%r13),%edi
  add    $0x1,%rbx
  movsbl 0x1(%rax),%eax
  cmp    %al,%dil
  jne    L40
L71:
  test   %dil,%dil
  je     L20
  call   <check_string@plt>
  test   %eax,%eax
  je     L105
  movsbl 0x0(%rbp),%edi
  call   <check_string@plt>
  test   %eax,%eax
  je     L38
  nopl   0x0(%rax,%rax,1)
L51:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  call   <check_string@plt>
  test   %eax,%eax
  jne    L51
L38:
  lea    -0x1(%rbp),%r13
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rbx
L32:
  movsbl (%rbx),%edi
  call   <check_string@plt>
  test   %eax,%eax
  jne    L25
  lea    -0x1(%rbx),%rax
  movsbl 0x1(%r13),%edi
  movsbl 0x1(%rax),%eax
  cmp    %al,%dil
  je     L71
L40:
  sub    %eax,%edi
  mov    %edi,%r12d
L20:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dircmp(char *s, char *t) {
  int check_string(char);
  char *tmps, *tmpt;
  tmps = s;
  tmpt = t;
  while (check_string(*s))
    s++;
  while (check_string(*t))
    t++;
  for (; *s == *t; s++, t++) {
    if (*s == '\0')
      return 0;
    if (check_string(*s)) {
      while (check_string(*s))
        s++;
      s--;
    }
    if (check_string(*t)) {
      while (check_string(*t))
        t++;
      t--;
    }
  }
  return *s - *t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<taper_norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movss  D20(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L21
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L10:
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0xc(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x28(%rbp),%xmm1
  divss  %xmm1,%xmm0
  mulss  -0x8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  D28(%rip),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
datatype: f32
name: parse_data
arguments: data_tag: D10
datatype: f64
name: parse_data
arguments: data_tag: D28
datatype: f64

tool: D20: 3.141592654

tool: D10: 0.5

tool: D28: 1

assistant: ```c
taper_norm(g, dt, nt, ntap) float *g, *dt;
int nt, ntap;
{
  float fac;
  int i;
  float pi = 3.141592654;
  for (i = 0; i < nt - ntap; i++)
    g[i] = g[i] * (*dt);
  for (i = nt - ntap; i < nt; i++) {
    fac = (*dt) * 0.5 * (1.0 + cos(pi * ((float)(nt - i) / (float)(ntap))));
    g[i] = g[i] * fac;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<taper_norm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r12
  mov    %edx,%edi
  sub    %ecx,%edi
  test   %edi,%edi
  jle    L39
  mov    %r8,%rax
  lea    -0x1(%rdi),%esi
  lea    0x4(%r8,%rsi,4),%rsi
L20:
  movss  (%rax),%xmm0
  mulss  (%r12),%xmm0
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L20
L39:
  cmp    %edi,%edx
  jle    L26
  mov    %ecx,%ebp
  movslq %edi,%rdi
  lea    (%r8,%rdi,4),%rbx
  pxor   %xmm3,%xmm3
  cvtsi2ss %ecx,%xmm3
  movss  %xmm3,0xc(%rsp)
L17:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  divss  0xc(%rsp),%xmm0
  mulss  D16(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  cvtss2sd (%r12),%xmm1
  mulsd  D6(%rip),%xmm1
  addsd  D13(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  (%rbx),%xmm1
  movss  %xmm1,(%rbx)
  add    $0x4,%rbx
  sub    $0x1,%ebp
  jne    L17
L26:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: f32
name: read_data
arguments: label: D6
type_guessed: f64
name: read_data
arguments: label: D13
type_guessed: f64

tool: D16: 3.141592654

tool: D6: 0.5

tool: D13: 1

assistant: ```c
taper_norm(g, dt, nt, ntap) float *g, *dt;
int nt, ntap;
{
  float fac;
  int i;
  float pi = 3.141592654;
  for (i = 0; i < nt - ntap; i++)
    g[i] = g[i] * (*dt);
  for (i = nt - ntap; i < nt; i++) {
    fac = (*dt) * 0.5 * (1.0 + cos(pi * ((float)(nt - i) / (float)(ntap))));
    g[i] = g[i] * fac;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<taper_norm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  sub    %ecx,%esi
  mov    %ecx,%ebx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rsi),%ecx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rcx,4),%rcx
  nopl   0x0(%rax)
L25:
  movss  (%rax),%xmm0
  mulss  0x0(%rbp),%xmm0
  add    $0x4,%rax
  movss  %xmm0,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L25
L38:
  cmp    %esi,%edx
  jle    L5
  pxor   %xmm3,%xmm3
  movslq %esi,%rsi
  cvtsi2ss %ebx,%xmm3
  lea    (%rdi,%rsi,4),%r12
  movss  %xmm3,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L11:
  pxor   %xmm0,%xmm0
  add    $0x4,%r12
  cvtsi2ss %ebx,%xmm0
  divss  0xc(%rsp),%xmm0
  mulss  D28(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  addsd  D8(%rip),%xmm0
  cvtss2sd 0x0(%rbp),%xmm1
  mulsd  D19(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  -0x4(%r12),%xmm1
  movss  %xmm1,-0x4(%r12)
  sub    $0x1,%ebx
  jne    L11
L5:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D28
type_infered: f32
name: read_data
arguments: label: D8
type_infered: f64
name: read_data
arguments: label: D19
type_infered: f64

tool: D28: 3.141592654

tool: D8: 1

tool: D19: 0.5

assistant: ```c
taper_norm(g, dt, nt, ntap) float *g, *dt;
int nt, ntap;
{
  float fac;
  int i;
  float pi = 3.141592654;
  for (i = 0; i < nt - ntap; i++)
    g[i] = g[i] * (*dt);
  for (i = nt - ntap; i < nt; i++) {
    fac = (*dt) * 0.5 * (1.0 + cos(pi * ((float)(nt - i) / (float)(ntap))));
    g[i] = g[i] * fac;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<taper_norm>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edx,%esi
  sub    %ecx,%edx
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L6
  movslq %edx,%rax
  lea    0x4(%r12),%rcx
  mov    %edx,%r8d
  lea    (%rdi,%rax,4),%rax
  cmp    %rax,%r12
  setae  %al
  cmp    %rcx,%rdi
  setae  %cl
  or     %cl,%al
  je     L22
  cmp    $0x1,%edx
  je     L22
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L33
  mov    %edx,%ecx
  movss  (%r12),%xmm1
  mov    %rdi,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shufps $0x0,%xmm1,%xmm1
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L61:
  movups (%rax),%xmm0
  add    $0x10,%rax
  mulps  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L61
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %edx,%ecx
  je     L6
  mov    %edx,%r8d
  sub    %ecx,%r8d
  cmp    $0x1,%r8d
  je     L104
L14:
  lea    (%rdi,%rcx,4),%rcx
  movss  (%r12),%xmm1
  movq   (%rcx),%xmm0
  shufps $0xe0,%xmm1,%xmm1
  mulps  %xmm1,%xmm0
  movlps %xmm0,(%rcx)
  mov    %r8d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r8d
  je     L6
L104:
  cltq
  lea    (%rdi,%rax,4),%rax
  movss  (%rax),%xmm0
  mulss  (%r12),%xmm0
  movss  %xmm0,(%rax)
L6:
  cmp    %edx,%esi
  jle    L66
  pxor   %xmm3,%xmm3
  movslq %edx,%rdx
  cvtsi2ss %ebx,%xmm3
  lea    (%rdi,%rdx,4),%rbp
  movss  %xmm3,0xc(%rsp)
  nopl   0x0(%rax)
L16:
  pxor   %xmm0,%xmm0
  add    $0x4,%rbp
  cvtsi2ss %ebx,%xmm0
  divss  0xc(%rsp),%xmm0
  mulss  D25(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  addsd  D26(%rip),%xmm0
  cvtss2sd (%r12),%xmm1
  mulsd  D3(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulss  -0x4(%rbp),%xmm1
  movss  %xmm1,-0x4(%rbp)
  sub    $0x1,%ebx
  jne    L16
L66:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  lea    -0x1(%rdx),%ecx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rcx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L11:
  movss  (%rax),%xmm0
  mulss  (%r12),%xmm0
  add    $0x4,%rax
  movss  %xmm0,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L11
  jmp    L6
L33:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type: f32
name: extract_symbolic_data
arguments: data_tag: D26
type: f64
name: extract_symbolic_data
arguments: data_tag: D3
type: f64

tool: D25: 3.141592654

tool: D26: 1

tool: D3: 0.5

assistant: ```c
taper_norm(g, dt, nt, ntap) float *g, *dt;
int nt, ntap;
{
  float fac;
  int i;
  float pi = 3.141592654;
  for (i = 0; i < nt - ntap; i++)
    g[i] = g[i] * (*dt);
  for (i = nt - ntap; i < nt; i++) {
    fac = (*dt) * 0.5 * (1.0 + cos(pi * ((float)(nt - i) / (float)(ntap))));
    g[i] = g[i] * fac;
  }
}
```