ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calloc_int_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %esi,0xc(%rsp)
  mov    %edx,%r13d
  mov    %edi,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L66
L13:
  test   %ebx,%ebx
  jle    L25
  mov    0x18(%rsp),%rax
  mov    %rax,%r15
  mov    %ebx,%ebx
  lea    (%rax,%rbx,8),%rax
  mov    %rax,0x10(%rsp)
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%eax
  lea    0x8(,%rax,8),%r14
  jmp    L48
L66:
  call   <error_and_exit@plt>
  jmp    L13
L82:
  call   <error_and_exit@plt>
  jmp    L32
L71:
  add    $0x8,%rbx
  cmp    %r14,%rbx
  je     L54
L49:
  mov    %rbx,%r12
  add    0x0(%rbp),%r12
  mov    %r13d,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,(%r12)
  mov    0x0(%rbp),%rax
  cmpq   $0x0,(%rax,%rbx,1)
  jne    L71
  mov    $0x0,%eax
  call   <error_and_exit@plt>
  jmp    L71
L54:
  add    $0x8,%r15
  cmp    0x10(%rsp),%r15
  je     L25
L48:
  mov    0xc(%rsp),%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %r15,%rbp
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L82
L32:
  cmpl   $0x0,0xc(%rsp)
  jle    L54
  mov    $0x0,%ebx
  jmp    L49
L25:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int ***calloc_int_array(int dim1, int dim2, int dim3) {
  int i, j;
  int ***array;
  array = calloc(sizeof(int **), dim1);
  if (array == NULL)
    error_and_exit();
  for (i = 0; i < dim1; i++) {
    array[i] = calloc(sizeof(int *), dim2);
    if (array[i] == NULL)
      error_and_exit();
    for (j = 0; j < dim2; j++) {
      array[i][j] = calloc(sizeof(int), dim3);
      if (array[i][j] == NULL)
        error_and_exit();
    }
  }
  return array;
}
```
user: What is the c source code of the assembly code below?

```asm
<calloc_int_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  mov    %ebx,%esi
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L99
L0:
  test   %ebx,%ebx
  jle    L77
  mov    0x8(%rsp),%rax
  mov    %rax,%r15
  lea    (%rax,%rbx,8),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x8(,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r13d,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L6
L28:
  test   %r13d,%r13d
  jle    L82
  xor    %ebx,%ebx
  jmp    L89
  xchg   %ax,%ax
L107:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L82
L89:
  mov    (%r15),%r14
  mov    %ebp,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  add    %rbx,%r14
  mov    %rax,(%r14)
  mov    (%r15),%rax
  cmpq   $0x0,(%rax,%rbx,1)
  jne    L107
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <error_and_exit@plt>
  cmp    %rbx,%r12
  jne    L89
  nopl   0x0(%rax,%rax,1)
L82:
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L15
L77:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L6:
  call   <error_and_exit@plt>
  jmp    L28
L99:
  call   <error_and_exit@plt>
  jmp    L0
```

assistant: ```c
int ***calloc_int_array(int dim1, int dim2, int dim3) {
  int i, j;
  int ***array;
  array = calloc(sizeof(int **), dim1);
  if (array == NULL)
    error_and_exit();
  for (i = 0; i < dim1; i++) {
    array[i] = calloc(sizeof(int *), dim2);
    if (array[i] == NULL)
      error_and_exit();
    for (j = 0; j < dim2; j++) {
      array[i][j] = calloc(sizeof(int), dim3);
      if (array[i][j] == NULL)
        error_and_exit();
    }
  }
  return array;
}
```
user: What is the c source code of the assembly code below?

```asm
<calloc_int_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%edi
  mov    %ebx,%esi
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L78
L107:
  test   %ebx,%ebx
  jle    L102
  mov    0x8(%rsp),%rax
  mov    %rax,%r15
  lea    (%rax,%rbx,8),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%r13),%eax
  lea    0x8(,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %r13d,%esi
  mov    $0x8,%edi
  call   <calloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L88
L96:
  test   %r13d,%r13d
  jle    L70
  xor    %ebx,%ebx
  jmp    L46
  xchg   %ax,%ax
L66:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L70
L46:
  mov    (%r15),%r14
  mov    %ebp,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  add    %rbx,%r14
  mov    %rax,(%r14)
  mov    (%r15),%rax
  cmpq   $0x0,(%rax,%rbx,1)
  jne    L66
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <error_and_exit@plt>
  cmp    %rbx,%r12
  jne    L46
  nopl   0x0(%rax,%rax,1)
L70:
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L76
L102:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L88:
  call   <error_and_exit@plt>
  jmp    L96
L78:
  call   <error_and_exit@plt>
  jmp    L107
```

assistant: ```c
int ***calloc_int_array(int dim1, int dim2, int dim3) {
  int i, j;
  int ***array;
  array = calloc(sizeof(int **), dim1);
  if (array == NULL)
    error_and_exit();
  for (i = 0; i < dim1; i++) {
    array[i] = calloc(sizeof(int *), dim2);
    if (array[i] == NULL)
      error_and_exit();
    for (j = 0; j < dim2; j++) {
      array[i][j] = calloc(sizeof(int), dim3);
      if (array[i][j] == NULL)
        error_and_exit();
    }
  }
  return array;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fill_tabl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L38:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cpy_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_access@plt>
  cmp    $0x2,%eax
  jne    L33
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <my_do@plt>
  mov    -0x20(%rbp),%rax
  jmp    L39
L33:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L38
  mov    -0x20(%rbp),%rax
L39:
  leave
  ret
```

assistant: ```c
char **fill_tabl(char **env, char **tabl, char **tab4, char **clear2) {
  char *str;
  int i;
  i = 0;
  while (tabl[i]) {
    str = cpy_str(tabl[i], clear2[0]);
    if ((my_access(str)) == 2) {
      my_do(str, env, tab4);
      return (tabl);
    }
    i++;
  }
  return (tabl);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fill_tabl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L3
  mov    %rdx,%r15
  mov    %rcx,%r12
  lea    0x8(%rsi),%rbp
L15:
  mov    (%r12),%rsi
  call   <cpy_str@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <my_access@plt>
  cmp    $0x2,%eax
  je     L17
  add    $0x8,%rbp
  mov    -0x8(%rbp),%rdi
  test   %rdi,%rdi
  jne    L15
  jmp    L3
L17:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <my_do@plt>
L3:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **fill_tabl(char **env, char **tabl, char **tab4, char **clear2) {
  char *str;
  int i;
  i = 0;
  while (tabl[i]) {
    str = cpy_str(tabl[i], clear2[0]);
    if ((my_access(str)) == 2) {
      my_do(str, env, tab4);
      return (tabl);
    }
    i++;
  }
  return (tabl);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_tabl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L25
  mov    %rdx,%r14
  mov    %rcx,%rbx
  lea    0x8(%rsi),%r15
  jmp    L28
  nopl   0x0(%rax)
L20:
  mov    (%r15),%rdi
  add    $0x8,%r15
  test   %rdi,%rdi
  je     L25
L28:
  mov    (%rbx),%rsi
  call   <cpy_str@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <my_access@plt>
  cmp    $0x2,%eax
  jne    L20
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <my_do@plt>
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **fill_tabl(char **env, char **tabl, char **tab4, char **clear2) {
  char *str;
  int i;
  i = 0;
  while (tabl[i]) {
    str = cpy_str(tabl[i], clear2[0]);
    if ((my_access(str)) == 2) {
      my_do(str, env, tab4);
      return (tabl);
    }
    i++;
  }
  return (tabl);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill_tabl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L27
  mov    %rdx,%r14
  mov    %rcx,%rbx
  lea    0x8(%rsi),%r15
  jmp    L10
  nopl   0x0(%rax)
L2:
  mov    (%r15),%rdi
  add    $0x8,%r15
  test   %rdi,%rdi
  je     L27
L10:
  mov    (%rbx),%rsi
  call   <cpy_str@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <my_access@plt>
  cmp    $0x2,%eax
  jne    L2
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <my_do@plt>
L27:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **fill_tabl(char **env, char **tabl, char **tab4, char **clear2) {
  char *str;
  int i;
  i = 0;
  while (tabl[i]) {
    str = cpy_str(tabl[i], clear2[0]);
    if ((my_access(str)) == 2) {
      my_do(str, env, tab4);
      return (tabl);
    }
    i++;
  }
  return (tabl);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<omp_thread_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int omp_thread_count() {
  int n = 0;
#pragma omp parallel reduction(+ : n)
  n += 1;
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<omp_thread_count>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int omp_thread_count() {
  int n = 0;
#pragma omp parallel reduction(+ : n)
  n += 1;
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<omp_thread_count>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int omp_thread_count() {
  int n = 0;
#pragma omp parallel reduction(+ : n)
  n += 1;
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<omp_thread_count>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int omp_thread_count() {
  int n = 0;
#pragma omp parallel reduction(+ : n)
  n += 1;
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<swap64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x8,%rax
  and    $0xff00ff,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  shr    $0x10,%rax
  movzwl %ax,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%esi
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  or     %esi,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t swap64(uint64_t x) {
  x = ((x & 0x00ff00ff00ff00ff) << 8) | ((x & 0xff00ff00ff00ff00) >> 8);
  x = ((x & 0x0000ffff0000ffff) << 16) | ((x & 0xffff0000ffff0000) >> 16);
  return (x << 32) | (x >> 32);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap64>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  movslq %edi,%rdi
  shr    $0x8,%rdi
  and    $0xff00ff,%edi
  or     %edi,%eax
  rol    $0x10,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  ret
```

assistant: ```c
uint64_t swap64(uint64_t x) {
  x = ((x & 0x00ff00ff00ff00ff) << 8) | ((x & 0xff00ff00ff00ff00) >> 8);
  x = ((x & 0x0000ffff0000ffff) << 16) | ((x & 0xffff0000ffff0000) >> 16);
  return (x << 32) | (x >> 32);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap64>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rdi
  mov    $0x20,%ecx
  shl    $0x8,%eax
  shr    $0x8,%rdi
  and    $0xff00ff00,%eax
  and    $0xff00ff,%edi
  or     %edi,%eax
  rol    $0x10,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
uint64_t swap64(uint64_t x) {
  x = ((x & 0x00ff00ff00ff00ff) << 8) | ((x & 0xff00ff00ff00ff00) >> 8);
  x = ((x & 0x0000ffff0000ffff) << 16) | ((x & 0xffff0000ffff0000) >> 16);
  return (x << 32) | (x >> 32);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap64>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rdi
  mov    $0x20,%ecx
  shl    $0x8,%eax
  shr    $0x8,%rdi
  and    $0xff00ff00,%eax
  and    $0xff00ff,%edi
  or     %edi,%eax
  rol    $0x10,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
uint64_t swap64(uint64_t x) {
  x = ((x & 0x00ff00ff00ff00ff) << 8) | ((x & 0xff00ff00ff00ff00) >> 8);
  x = ((x & 0x0000ffff0000ffff) << 16) | ((x & 0xffff0000ffff0000) >> 16);
  return (x << 32) | (x >> 32);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<printVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L5
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: %lf 

assistant: ```c
void printVector(double *vector, unsigned size) {
  unsigned i = 0;
  for (i = 0; i < size; i++)
    printf("%lf ", vector[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<printVector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L3
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D7(%rip),%rbp
L17:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L17
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: D7: %lf 

assistant: ```c
void printVector(double *vector, unsigned size) {
  unsigned i = 0;
  for (i = 0; i < size; i++)
    printf("%lf ", vector[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printVector>:
  endbr64
  test   %esi,%esi
  je     L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L14:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: %lf 

assistant: ```c
void printVector(double *vector, unsigned size) {
  unsigned i = 0;
  for (i = 0; i < size; i++)
    printf("%lf ", vector[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printVector>:
  endbr64
  test   %esi,%esi
  je     L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L17:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: %lf 

assistant: ```c
void printVector(double *vector, unsigned size) {
  unsigned i = 0;
  for (i = 0; i < size; i++)
    printf("%lf ", vector[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cprop_test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x9,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cprop_test1(int *data) {
  int j = 1 + 2 * 4;
  data[0] = j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cprop_test1>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test1(int *data) {
  int j = 1 + 2 * 4;
  data[0] = j;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cprop_test1>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test1(int *data) {
  int j = 1 + 2 * 4;
  data[0] = j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cprop_test1>:
  endbr64
  movl   $0x9,(%rdi)
  ret
```

assistant: ```c
void cprop_test1(int *data) {
  int j = 1 + 2 * 4;
  data[0] = j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash_wc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L3:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  cltq
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_wc(const char *chave, int tamanho) {
  int i = 0, l = 0;
  while (chave[i]) {
    l += chave[i++];
  }
  return l % tamanho;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash_wc>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L29
  add    $0x1,%rdi
  mov    $0x0,%eax
L8:
  movsbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L8
L3:
  cltd
  idiv   %esi
  movslq %edx,%rax
  ret
L29:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
unsigned long hash_wc(const char *chave, int tamanho) {
  int i = 0, l = 0;
  while (chave[i]) {
    l += chave[i++];
  }
  return l % tamanho;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_wc>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L10
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L12
  cltd
  idiv   %esi
  movslq %edx,%rax
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long hash_wc(const char *chave, int tamanho) {
  int i = 0, l = 0;
  while (chave[i]) {
    l += chave[i++];
  }
  return l % tamanho;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_wc>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  add    $0x1,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L10
  cltd
  idiv   %esi
  movslq %edx,%rax
  ret
  nopl   (%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long hash_wc(const char *chave, int tamanho) {
  int i = 0, l = 0;
  while (chave[i]) {
    l += chave[i++];
  }
  return l % tamanho;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<aFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movzbl 0x3(%rax),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D13
datatype: string

tool: D9: %p


tool: D13: %s


assistant: ```c
char aFunction(char x[2]) {
  printf("%p\n", x);
  printf("%s\n", x);
  return x[3];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aFunction>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  movzbl 0x3(%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D6: %p


tool: D19: %s


assistant: ```c
char aFunction(char x[2]) {
  printf("%p\n", x);
  printf("%s\n", x);
  return x[3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<aFunction>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  movzbl 0x3(%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: string
name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D14: %p


tool: D3: %s


assistant: ```c
char aFunction(char x[2]) {
  printf("%p\n", x);
  printf("%s\n", x);
  return x[3];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aFunction>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  movzbl 0x3(%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D18: %p


tool: D4: %s


assistant: ```c
char aFunction(char x[2]) {
  printf("%p\n", x);
  printf("%s\n", x);
  return x[3];
}
```