ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_char_optim>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,0x1c(%rsp)
  test   %r14d,%r14d
  jle    L5
  test   %esi,%esi
  lea    0x3(%rsi),%r15d
  movq   $0x0,0x8(%rsp)
  lea    D1(%rip),%rbp
  cmovns %esi,%r15d
  sar    $0x2,%r15d
  mov    %r15d,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L34:
  mov    0x10(%rsp),%r13
  xor    %r12d,%r12d
  add    0x8(%rsp),%r13
  cmpl   $0x3,0x1c(%rsp)
  jle    L28
  nopl   0x0(%rax)
L44:
  movzbl 0x0(%r13),%r15d
  mov    $0x4,%ebx
L48:
  mov    %r15d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  shr    $0x2,%r15b
  and    $0x3,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L48
  add    $0x1,%r12d
  add    %r14,%r13
  cmp    0x18(%rsp),%r12d
  jl     L44
L28:
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    %r14,%rax
  jne    L34
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: %d 

assistant: ```c
void print_char_optim(unsigned char *out, int N, int M) {
  int j, ip, i4;
  unsigned char res, res1;
  for (j = 0; j < M; j++) {
    for (ip = 0; ip < N / 4; ip++) {
      res = out[ip * M + j];
      for (i4 = 0; i4 < 4; i4++) {
        res1 = res % 4;
        printf("%d ", res1);
        res >>= 2;
      }
    }
    printf("\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_char_optim>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %esi,0x1c(%rsp)
  test   %r14d,%r14d
  jle    L40
  test   %esi,%esi
  lea    0x3(%rsi),%r15d
  movq   $0x0,0x8(%rsp)
  lea    D0(%rip),%rbp
  cmovns %esi,%r15d
  sar    $0x2,%r15d
  mov    %r15d,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L35:
  mov    0x10(%rsp),%r13
  xor    %r12d,%r12d
  add    0x8(%rsp),%r13
  cmpl   $0x3,0x1c(%rsp)
  jle    L15
  nopl   0x0(%rax)
L6:
  movzbl 0x0(%r13),%r15d
  mov    $0x4,%ebx
L38:
  mov    %r15d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  shr    $0x2,%r15b
  and    $0x3,%esi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L38
  add    $0x1,%r12d
  add    %r14,%r13
  cmp    0x18(%rsp),%r12d
  jl     L6
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    %rax,%r14
  jne    L35
L40:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
void print_char_optim(unsigned char *out, int N, int M) {
  int j, ip, i4;
  unsigned char res, res1;
  for (j = 0; j < M; j++) {
    for (ip = 0; ip < N / 4; ip++) {
      res = out[ip * M + j];
      for (i4 = 0; i4 < 4; i4++) {
        res1 = res % 4;
        printf("%d ", res1);
        res >>= 2;
      }
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L16
L1:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x24(%rbp)
L16:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L1
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%ecx
  mov    -0x30(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    -0x20(%rbp),%rsi
  mov    %eax,%edi
  call   <producer_consumer@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D6
type: string
name: unpack_data
arguments: tag: D19
type: string

tool: D8: %d %d %d

tool: D6: %d

tool: D19: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  int i, n, size, nt;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(size, vec, n, nt);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(vec);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmpl   $0x0,0xc(%rsp)
  jle    L10
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D11(%rip),%r12
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L18
L10:
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %xmm0,%rbx
  mov    0x14(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    0x10(%rsp),%edi
  call   <producer_consumer@plt>
  mov    $0x0,%eax
  call   <omp_get_wtime@plt>
  movq   %rbx,%xmm1
  subsd  %xmm1,%xmm0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D3: %d %d %d

tool: D11: %d

tool: D7: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  int i, n, size, nt;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(size, vec, n, nt);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(vec);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L17
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D26(%rip),%r12
L0:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L0
L17:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x24(%rsp),%ecx
  mov    0x1c(%rsp),%edx
  mov    %r13,%rsi
  mov    0x20(%rsp),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <producer_consumer@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string
name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D2: %d %d %d

tool: D26: %d

tool: D3: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  int i, n, size, nt;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(size, vec, n, nt);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(vec);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  lea    0x1c(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L25
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D11(%rip),%r12
L20:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L20
L25:
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  mov    0x24(%rsp),%ecx
  mov    0x1c(%rsp),%edx
  mov    %r13,%rsi
  mov    0x20(%rsp),%edi
  movsd  %xmm0,0x8(%rsp)
  call   <producer_consumer@plt>
  xor    %eax,%eax
  call   <omp_get_wtime@plt>
  subsd  0x8(%rsp),%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D15: %d %d %d

tool: D11: %d

tool: D2: %lf


assistant: ```c
int main(int argc, char *argv[]) {
  double start, end;
  int i, n, size, nt;
  int *vec;
  scanf("%d %d %d", &nt, &n, &size);
  vec = (int *)malloc(n * sizeof(int));
  for (i = 0; i < n; i++)
    scanf("%d", &vec[i]);
  start = omp_get_wtime();
  producer_consumer(size, vec, n, nt);
  end = omp_get_wtime();
  printf("%lf\n", end - start);
  free(vec);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hash_table_del_test2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  hash_table_del_test2();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hash_table_del_test2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hash_table_del_test2();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hash_table_del_test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hash_table_del_test2();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hash_table_del_test2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  hash_table_del_test2();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<core___core__Float___Numeric__to_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  nop
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double core___core__Float___Numeric__to_f(double self) {
  double var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<core___core__Float___Numeric__to_f>:
  endbr64
  ret
```

assistant: ```c
double core___core__Float___Numeric__to_f(double self) {
  double var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<core___core__Float___Numeric__to_f>:
  endbr64
  ret
```

assistant: ```c
double core___core__Float___Numeric__to_f(double self) {
  double var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<core___core__Float___Numeric__to_f>:
  endbr64
  ret
```

assistant: ```c
double core___core__Float___Numeric__to_f(double self) {
  double var;
  var = self;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: What is the c source code of the assembly code below:

```asm
<cpuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cpuid
  mov    %ebx,%esi
  mov    %eax,-0x18(%rbp)
  mov    %esi,-0x14(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int cpuid(unsigned int op) {
  unsigned int ret;
  unsigned dummy2, dummy3, dummy4;
  asm volatile("cpuid" : "=a"(ret), "=b"(dummy2), "=c"(dummy3), "=d"(dummy4) : "a"(op));
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cpuid>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  cpuid
  pop    %rbx
  ret
```

assistant: ```c
unsigned int cpuid(unsigned int op) {
  unsigned int ret;
  unsigned dummy2, dummy3, dummy4;
  asm volatile("cpuid" : "=a"(ret), "=b"(dummy2), "=c"(dummy3), "=d"(dummy4) : "a"(op));
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cpuid>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  cpuid
  pop    %rbx
  ret
```

assistant: ```c
unsigned int cpuid(unsigned int op) {
  unsigned int ret;
  unsigned dummy2, dummy3, dummy4;
  asm volatile("cpuid" : "=a"(ret), "=b"(dummy2), "=c"(dummy3), "=d"(dummy4) : "a"(op));
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<cpuid>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  cpuid
  pop    %rbx
  ret
```

assistant: ```c
unsigned int cpuid(unsigned int op) {
  unsigned int ret;
  unsigned dummy2, dummy3, dummy4;
  asm volatile("cpuid" : "=a"(ret), "=b"(dummy2), "=c"(dummy3), "=d"(dummy4) : "a"(op));
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QuoteKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L22
L23:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  sar    $0x4,%al
  and    $0x7,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  cmp    $0x9,%eax
  jle    L25
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xf,%eax
  add    $0x57,%eax
  mov    %eax,%ecx
  jmp    L44
L25:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xf,%eax
  add    $0x30,%eax
  mov    %eax,%ecx
L44:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %cl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L9
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x28,(%rax)
  jmp    L8
L9:
  subl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x29,(%rax)
L8:
  addq   $0x1,-0x20(%rbp)
L22:
  cmpl   $0x0,-0x4(%rbp)
  jne    L23
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *QuoteKey(char *S, char *Key) {
  int c0;
  c0 = 1;
  while (c0) {
    *S++ = '0' + ((*Key >> 4) & 0x7);
    *S++ = ((*Key & 0xf) > 9) ? (*Key & 0xf) + 'a' - 10 : (*Key & 0xf) + '0';
    if (*Key & 0x80) {
      c0++;
      *S++ = '(';
    } else {
      c0--;
      *S++ = ')';
    }
    Key++;
  }
  *S = 0;
  return S;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QuoteKey>:
  endbr64
  mov    %rsi,%rdx
  add    $0x3,%rdi
  mov    $0x1,%esi
  mov    $0x29,%r9d
  mov    $0x28,%r10d
  jmp    L1
L49:
  and    $0xf,%eax
  add    $0x30,%eax
L38:
  mov    %al,-0x2(%rcx)
  cmpb   $0x0,(%rdx)
  js     L3
  sub    $0x1,%esi
  mov    %r9d,%eax
L32:
  mov    %al,-0x1(%rcx)
  add    $0x1,%rdx
  add    $0x3,%rdi
  test   %esi,%esi
  je     L2
L1:
  mov    %rdi,%rcx
  movzbl (%rdx),%eax
  sar    $0x4,%al
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,-0x3(%rdi)
  movzbl (%rdx),%eax
  mov    %eax,%r8d
  and    $0xf,%r8d
  cmp    $0x9,%r8b
  jle    L49
  mov    %r8d,%eax
  add    $0x57,%eax
  jmp    L38
L3:
  add    $0x1,%esi
  mov    %r10d,%eax
  jmp    L32
L2:
  movb   $0x0,(%rcx)
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *QuoteKey(char *S, char *Key) {
  int c0;
  c0 = 1;
  while (c0) {
    *S++ = '0' + ((*Key >> 4) & 0x7);
    *S++ = ((*Key & 0xf) > 9) ? (*Key & 0xf) + 'a' - 10 : (*Key & 0xf) + '0';
    if (*Key & 0x80) {
      c0++;
      *S++ = '(';
    } else {
      c0--;
      *S++ = ')';
    }
    Key++;
  }
  *S = 0;
  return S;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<QuoteKey>:
  endbr64
  mov    $0x1,%ecx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L27:
  movb   $0x29,-0x1(%rax)
  sub    $0x1,%ecx
  je     L30
L23:
  mov    %rax,%rdi
L12:
  movzbl (%rsi),%eax
  sar    $0x4,%al
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,(%rdi)
  movzbl (%rsi),%eax
  and    $0xf,%eax
  lea    0x57(%rax),%r8d
  lea    0x30(%rax),%edx
  cmp    $0xa,%al
  mov    %r8d,%eax
  cmovl  %edx,%eax
  add    $0x1,%rsi
  mov    %al,0x1(%rdi)
  movzbl -0x1(%rsi),%edx
  lea    0x3(%rdi),%rax
  test   %dl,%dl
  jns    L27
  movb   $0x28,-0x1(%rax)
  add    $0x1,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L30:
  movb   $0x0,0x3(%rdi)
  ret
```

assistant: ```c
char *QuoteKey(char *S, char *Key) {
  int c0;
  c0 = 1;
  while (c0) {
    *S++ = '0' + ((*Key >> 4) & 0x7);
    *S++ = ((*Key & 0xf) > 9) ? (*Key & 0xf) + 'a' - 10 : (*Key & 0xf) + '0';
    if (*Key & 0x80) {
      c0++;
      *S++ = '(';
    } else {
      c0--;
      *S++ = ')';
    }
    Key++;
  }
  *S = 0;
  return S;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QuoteKey>:
  endbr64
  mov    $0x1,%ecx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L1:
  movb   $0x29,-0x1(%rax)
  sub    $0x1,%ecx
  je     L8
L19:
  mov    %rax,%rdi
L20:
  movzbl (%rsi),%eax
  sar    $0x4,%al
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,(%rdi)
  movzbl (%rsi),%eax
  and    $0xf,%eax
  lea    0x57(%rax),%r8d
  lea    0x30(%rax),%edx
  cmp    $0xa,%al
  mov    %r8d,%eax
  cmovl  %edx,%eax
  add    $0x1,%rsi
  mov    %al,0x1(%rdi)
  movzbl -0x1(%rsi),%edx
  lea    0x3(%rdi),%rax
  test   %dl,%dl
  jns    L1
  movb   $0x28,-0x1(%rax)
  add    $0x1,%ecx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L8:
  movb   $0x0,0x3(%rdi)
  ret
```

assistant: ```c
char *QuoteKey(char *S, char *Key) {
  int c0;
  c0 = 1;
  while (c0) {
    *S++ = '0' + ((*Key >> 4) & 0x7);
    *S++ = ((*Key & 0xf) > 9) ? (*Key & 0xf) + 'a' - 10 : (*Key & 0xf) + '0';
    if (*Key & 0x80) {
      c0++;
      *S++ = '(';
    } else {
      c0--;
      *S++ = ')';
    }
    Key++;
  }
  *S = 0;
  return S;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readEncUInt32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
L7:
  cmpl   $0x1c,-0x14(%rbp)
  jg     L19
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <readUInt8@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x7f,%eax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  or     %rax,-0x10(%rbp)
  addl   $0x7,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <hasNextByte@plt>
  test   %rax,%rax
  jne    L7
  jmp    L9
L19:
  nop
L9:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long readEncUInt32(FILE *f) {
  unsigned long result = 0, temp;
  int shift = 0;
  do {
    if (shift > 4 * 7)
      break;
    temp = readUInt8(f);
    result |= (0x7f & temp) << shift;
    shift += 7;
  } while (hasNextByte(temp));
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readEncUInt32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L2:
  mov    %r12,%rdi
  call   <readUInt8@plt>
  mov    %rax,%rdi
  and    $0x7f,%eax
  mov    %ebx,%ecx
  shl    %cl,%rax
  or     %rax,%rbp
  add    $0x7,%ebx
  call   <hasNextByte@plt>
  test   %rax,%rax
  je     L17
  cmp    $0x23,%ebx
  jne    L2
L17:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long readEncUInt32(FILE *f) {
  unsigned long result = 0, temp;
  int shift = 0;
  do {
    if (shift > 4 * 7)
      break;
    temp = readUInt8(f);
    result |= (0x7f & temp) << shift;
    shift += 7;
  } while (hasNextByte(temp));
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readEncUInt32>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L11:
  mov    %rbp,%rdi
  call   <readUInt8@plt>
  mov    %ebx,%ecx
  add    $0x7,%ebx
  mov    %rax,%rdi
  and    $0x7f,%eax
  shl    %cl,%rax
  or     %rax,%r12
  call   <hasNextByte@plt>
  cmp    $0x1c,%ebx
  jg     L2
  test   %rax,%rax
  jne    L11
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long readEncUInt32(FILE *f) {
  unsigned long result = 0, temp;
  int shift = 0;
  do {
    if (shift > 4 * 7)
      break;
    temp = readUInt8(f);
    result |= (0x7f & temp) << shift;
    shift += 7;
  } while (hasNextByte(temp));
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readEncUInt32>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L5:
  mov    %rbp,%rdi
  call   <readUInt8@plt>
  mov    %ebx,%ecx
  add    $0x7,%ebx
  mov    %rax,%rdi
  and    $0x7f,%eax
  shl    %cl,%rax
  or     %rax,%r12
  call   <hasNextByte@plt>
  cmp    $0x1c,%ebx
  jg     L13
  test   %rax,%rax
  jne    L5
L13:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long readEncUInt32(FILE *f) {
  unsigned long result = 0, temp;
  int shift = 0;
  do {
    if (shift > 4 * 7)
      break;
    temp = readUInt8(f);
    result |= (0x7f & temp) << shift;
    shift += 7;
  } while (hasNextByte(temp));
  return result;
}
```