ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rcx
  mov    $0x61a8,%edx
  mov    %rbp,%rdi
  push   %rcx
  mov    $0x61a8,%r9d
  mov    %rcx,%r8
  mov    $0x61a8,%esi
  push   %rcx
  call   <UpnpResponse_MediaServer_ConnectionManager_GetCurrentConnectionInfo@plt>
  pop    %rax
  pop    %rdx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D3: Invoke: UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(%d);


tool: D2: Sample String

assistant: ```c
void UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(void *upnptoken, int ConnectionID) {
  printf("Invoke: UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(%d);\r\n", ConnectionID);
  UpnpResponse_MediaServer_ConnectionManager_GetCurrentConnectionInfo(upnptoken, 25000, 25000, "Sample String", "Sample String", 25000, "Sample String", "Sample String");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rcx
  mov    $0x61a8,%edx
  mov    %rbp,%rdi
  push   %rcx
  mov    $0x61a8,%r9d
  mov    %rcx,%r8
  mov    $0x61a8,%esi
  push   %rcx
  call   <UpnpResponse_MediaServer_ConnectionManager_GetCurrentConnectionInfo@plt>
  pop    %rax
  pop    %rdx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D17
datatype: string

tool: D1: Invoke: UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(%d);


tool: D17: Sample String

assistant: ```c
void UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(void *upnptoken, int ConnectionID) {
  printf("Invoke: UpnpMediaServer_ConnectionManager_GetCurrentConnectionInfo(%d);\r\n", ConnectionID);
  UpnpResponse_MediaServer_ConnectionManager_GetCurrentConnectionInfo(upnptoken, 25000, 25000, "Sample String", "Sample String", 25000, "Sample String", "Sample String");
}
```
user: What is the c source code of the assembly code below:

```asm
<u_exact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: f64

tool: D8: 3.141592653589793

assistant: ```c
double u_exact(double x, double y) {
  double pi = 3.141592653589793;
  double value;
  value = sin(pi * x * y);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<u_exact>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <sin@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: f64

tool: D6: 3.141592653589793

assistant: ```c
double u_exact(double x, double y) {
  double pi = 3.141592653589793;
  double value;
  value = sin(pi * x * y);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<u_exact>:
  endbr64
  mulsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  jmp    1050 <sin@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: f64

tool: D0: 3.141592653589793

assistant: ```c
double u_exact(double x, double y) {
  double pi = 3.141592653589793;
  double value;
  value = sin(pi * x * y);
  return value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<u_exact>:
  endbr64
  mulsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  jmp    1050 <sin@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: f64

tool: D3: 3.141592653589793

assistant: ```c
double u_exact(double x, double y) {
  double pi = 3.141592653589793;
  double value;
  value = sin(pi * x * y);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  andl   $0x7fffffff,-0x30(%rbp)
  cmpl   $0x3fe921fb,-0x30(%rbp)
  jg     L24
  mov    -0x38(%rbp),%rax
  movsd  -0x28(%rbp),%xmm0
  mov    $0x1,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__kernel_tan@plt>
  movq   %xmm0,%rax
  jmp    L30
L24:
  cmpl   $0x7fefffff,-0x30(%rbp)
  jle    L5
  movsd  -0x38(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  jmp    L30
L5:
  mov    -0x38(%rbp),%rax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <__ieee754_rem_pio2@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  and    $0x2,%eax
  mov    $0x1,%edx
  sub    %eax,%edx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    %edx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__kernel_tan@plt>
  movq   %xmm0,%rax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double tan(double x) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    return __kernel_tan(x, z, 1);
  } else if (ix >= 0x7ff00000) {
    return x - x;
  } else {
    n = __ieee754_rem_pio2(x, y);
    return __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tan>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L8
  cmp    $0x7fefffff,%eax
  jle    L1
  subsd  %xmm0,%xmm0
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x28,%rsp
  ret
L8:
  mov    $0x1,%edi
  pxor   %xmm1,%xmm1
  call   <__kernel_tan@plt>
  jmp    L13
L1:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  add    %eax,%eax
  and    $0x2,%eax
  mov    $0x1,%edi
  sub    %eax,%edi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   <__kernel_tan@plt>
  jmp    L13
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tan(double x) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    return __kernel_tan(x, z, 1);
  } else if (ix >= 0x7ff00000) {
    return x - x;
  } else {
    n = __ieee754_rem_pio2(x, y);
    return __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tan>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L1
  cmp    $0x7fefffff,%eax
  jle    L15
  subsd  %xmm0,%xmm0
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L15:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    $0x1,%edi
  add    %eax,%eax
  and    $0x2,%eax
  sub    %eax,%edi
  call   <__kernel_tan@plt>
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x1,%edi
  pxor   %xmm1,%xmm1
  add    $0x28,%rsp
  jmp    1070 <__kernel_tan@plt>
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tan(double x) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    return __kernel_tan(x, z, 1);
  } else if (ix >= 0x7ff00000) {
    return x - x;
  } else {
    n = __ieee754_rem_pio2(x, y);
    return __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<tan>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L0
  cmp    $0x7fefffff,%eax
  jle    L39
  subsd  %xmm0,%xmm0
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L39:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    $0x1,%edi
  add    %eax,%eax
  and    $0x2,%eax
  sub    %eax,%edi
  call   <__kernel_tan@plt>
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x1,%edi
  pxor   %xmm1,%xmm1
  add    $0x28,%rsp
  jmp    1070 <__kernel_tan@plt>
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tan(double x) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    return __kernel_tan(x, z, 1);
  } else if (ix >= 0x7ff00000) {
    return x - x;
  } else {
    n = __ieee754_rem_pio2(x, y);
    return __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Base42_CopyFlipB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  add    $0x3,%eax
  and    $0xfffffffc,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L6
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0xc(%rax),%eax
  mov    %eax,-0x1c(%rbp)
  addq   $0x10,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x24(%rbp),%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x24(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  and    $0xff00ff00,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  addq   $0x10,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L17
  nop
  pop    %rbp
  ret
```

assistant: ```c
int Base42_CopyFlipB(char *ibuf, char *obuf, int n) {
  int *cs, *ct, *cse;
  int i0, i1, i2, i3;
  cs = (int *)ibuf;
  cse = cs + ((n + 3) & (~3));
  ct = (int *)obuf;
  while (cs < cse) {
    i0 = cs[0];
    i1 = cs[1];
    i2 = cs[2];
    i3 = cs[3];
    cs += 4;
    ct[0] = (i0 & 0xFF00FF00) | ((i0 >> 16) & 0x000000FF) | ((i0 << 16) & 0x00FF0000);
    ct[1] = (i1 & 0xFF00FF00) | ((i1 >> 16) & 0x000000FF) | ((i1 << 16) & 0x00FF0000);
    ct[2] = (i2 & 0xFF00FF00) | ((i2 >> 16) & 0x000000FF) | ((i2 << 16) & 0x00FF0000);
    ct[3] = (i3 & 0xFF00FF00) | ((i3 >> 16) & 0x000000FF) | ((i3 << 16) & 0x00FF0000);
    ct += 4;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Base42_CopyFlipB>:
  endbr64
  mov    %rdi,%rcx
  lea    0x3(%rdx),%eax
  and    $0xfffffffc,%eax
  cltq
  lea    (%rdi,%rax,4),%rdx
  cmp    %rdx,%rdi
  jae    L12
L13:
  mov    (%rcx),%r10d
  mov    0x4(%rcx),%r9d
  mov    0x8(%rcx),%r8d
  mov    0xc(%rcx),%edi
  add    $0x10,%rcx
  mov    %r10d,%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    %r10d,%r11d
  shl    $0x10,%r11d
  and    $0xff0000,%r11d
  or     %r11d,%eax
  and    $0xff00ff00,%r10d
  or     %r10d,%eax
  mov    %eax,(%rsi)
  mov    %r9d,%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    %r9d,%r10d
  shl    $0x10,%r10d
  and    $0xff0000,%r10d
  or     %r10d,%eax
  and    $0xff00ff00,%r9d
  or     %r9d,%eax
  mov    %eax,0x4(%rsi)
  mov    %r8d,%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    %r8d,%r9d
  shl    $0x10,%r9d
  and    $0xff0000,%r9d
  or     %r9d,%eax
  and    $0xff00ff00,%r8d
  or     %r8d,%eax
  mov    %eax,0x8(%rsi)
  mov    %edi,%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    %edi,%r8d
  shl    $0x10,%r8d
  and    $0xff0000,%r8d
  or     %r8d,%eax
  and    $0xff00ff00,%edi
  or     %edi,%eax
  mov    %eax,0xc(%rsi)
  add    $0x10,%rsi
  cmp    %rcx,%rdx
  ja     L13
L12:
  ret
```

assistant: ```c
int Base42_CopyFlipB(char *ibuf, char *obuf, int n) {
  int *cs, *ct, *cse;
  int i0, i1, i2, i3;
  cs = (int *)ibuf;
  cse = cs + ((n + 3) & (~3));
  ct = (int *)obuf;
  while (cs < cse) {
    i0 = cs[0];
    i1 = cs[1];
    i2 = cs[2];
    i3 = cs[3];
    cs += 4;
    ct[0] = (i0 & 0xFF00FF00) | ((i0 >> 16) & 0x000000FF) | ((i0 << 16) & 0x00FF0000);
    ct[1] = (i1 & 0xFF00FF00) | ((i1 >> 16) & 0x000000FF) | ((i1 << 16) & 0x00FF0000);
    ct[2] = (i2 & 0xFF00FF00) | ((i2 >> 16) & 0x000000FF) | ((i2 << 16) & 0x00FF0000);
    ct[3] = (i3 & 0xFF00FF00) | ((i3 >> 16) & 0x000000FF) | ((i3 << 16) & 0x00FF0000);
    ct += 4;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Base42_CopyFlipB>:
  endbr64
  lea    0x3(%rdx),%eax
  mov    %rdi,%rcx
  and    $0xfffffffc,%eax
  cltq
  lea    (%rdi,%rax,4),%rdx
  cmp    %rdx,%rdi
  jae    L0
  nopl   0x0(%rax)
L2:
  mov    (%rcx),%r10d
  mov    0x4(%rcx),%r9d
  add    $0x10,%rcx
  add    $0x10,%rsi
  mov    -0x8(%rcx),%r8d
  mov    -0x4(%rcx),%edi
  mov    %r10d,%eax
  mov    %r10d,%r11d
  and    $0xff00ff00,%r10d
  sar    $0x10,%eax
  shl    $0x10,%r11d
  movzbl %al,%eax
  and    $0xff0000,%r11d
  or     %r11d,%eax
  or     %r10d,%eax
  mov    %r9d,%r10d
  mov    %eax,-0x10(%rsi)
  mov    %r9d,%eax
  shl    $0x10,%r10d
  and    $0xff00ff00,%r9d
  sar    $0x10,%eax
  and    $0xff0000,%r10d
  movzbl %al,%eax
  or     %r10d,%eax
  or     %r9d,%eax
  mov    %r8d,%r9d
  mov    %eax,-0xc(%rsi)
  mov    %r8d,%eax
  shl    $0x10,%r9d
  and    $0xff00ff00,%r8d
  sar    $0x10,%eax
  and    $0xff0000,%r9d
  movzbl %al,%eax
  or     %r9d,%eax
  or     %r8d,%eax
  mov    %edi,%r8d
  mov    %eax,-0x8(%rsi)
  mov    %edi,%eax
  shl    $0x10,%r8d
  and    $0xff00ff00,%edi
  sar    $0x10,%eax
  and    $0xff0000,%r8d
  movzbl %al,%eax
  or     %r8d,%eax
  or     %edi,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdx
  ja     L2
L0:
  ret
```

assistant: ```c
int Base42_CopyFlipB(char *ibuf, char *obuf, int n) {
  int *cs, *ct, *cse;
  int i0, i1, i2, i3;
  cs = (int *)ibuf;
  cse = cs + ((n + 3) & (~3));
  ct = (int *)obuf;
  while (cs < cse) {
    i0 = cs[0];
    i1 = cs[1];
    i2 = cs[2];
    i3 = cs[3];
    cs += 4;
    ct[0] = (i0 & 0xFF00FF00) | ((i0 >> 16) & 0x000000FF) | ((i0 << 16) & 0x00FF0000);
    ct[1] = (i1 & 0xFF00FF00) | ((i1 >> 16) & 0x000000FF) | ((i1 << 16) & 0x00FF0000);
    ct[2] = (i2 & 0xFF00FF00) | ((i2 >> 16) & 0x000000FF) | ((i2 << 16) & 0x00FF0000);
    ct[3] = (i3 & 0xFF00FF00) | ((i3 >> 16) & 0x000000FF) | ((i3 << 16) & 0x00FF0000);
    ct += 4;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Base42_CopyFlipB>:
  endbr64
  lea    0x3(%rdx),%ecx
  and    $0xfffffffc,%ecx
  movslq %ecx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%rax
  cmp    %rax,%rdi
  jae    L7
  sub    $0x1,%rcx
  movdqa D8(%rip),%xmm5
  xor    %eax,%eax
  xor    %edx,%edx
  shr    $0x4,%rcx
  movdqa D14(%rip),%xmm4
  movdqa D18(%rip),%xmm3
  add    $0x1,%rcx
  nopw   0x0(%rax,%rax,1)
L17:
  movdqu (%rdi,%rax,1),%xmm1
  add    $0x1,%rdx
  movdqa %xmm1,%xmm0
  movdqa %xmm1,%xmm2
  pand   %xmm3,%xmm1
  pslld  $0x10,%xmm0
  psrad  $0x10,%xmm2
  pand   %xmm5,%xmm0
  pand   %xmm4,%xmm2
  por    %xmm2,%xmm0
  por    %xmm1,%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rdx
  jb     L17
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: byte[16]
name: retrieve_data
arguments: data_label: D14
datatype: byte[16]
name: retrieve_data
arguments: data_label: D18
datatype: byte[16]

tool: {"D8": [0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00]}

tool: {"D14": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

tool: {"D18": [0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff,0x00,0xff]}

assistant: ```c
int Base42_CopyFlipB(char *ibuf, char *obuf, int n) {
  int *cs, *ct, *cse;
  int i0, i1, i2, i3;
  cs = (int *)ibuf;
  cse = cs + ((n + 3) & (~3));
  ct = (int *)obuf;
  while (cs < cse) {
    i0 = cs[0];
    i1 = cs[1];
    i2 = cs[2];
    i3 = cs[3];
    cs += 4;
    ct[0] = (i0 & 0xFF00FF00) | ((i0 >> 16) & 0x000000FF) | ((i0 << 16) & 0x00FF0000);
    ct[1] = (i1 & 0xFF00FF00) | ((i1 >> 16) & 0x000000FF) | ((i1 << 16) & 0x00FF0000);
    ct[2] = (i2 & 0xFF00FF00) | ((i2 >> 16) & 0x000000FF) | ((i2 << 16) & 0x00FF0000);
    ct[3] = (i3 & 0xFF00FF00) | ((i3 >> 16) & 0x000000FF) | ((i3 << 16) & 0x00FF0000);
    ct += 4;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L33
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  jmp    L16
L33:
  cmpl   $0x2,-0x24(%rbp)
  jne    L47
  mov    -0x18(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L48
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <flip2@plt>
L48:
  mov    -0x4(%rbp),%eax
  jmp    L16
L47:
  cmpl   $0x4,-0x24(%rbp)
  jne    L34
  mov    -0x18(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L6
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <flip4@plt>
L6:
  mov    -0x8(%rbp),%eax
  jmp    L16
L34:
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: Fatal error in read_block(): bad elsize (%d)


assistant: ```c
int read_block(int f, void *data, int elements, int elsize) {
  if (elsize == 1) {
    return read(f, data, elements);
  } else if (elsize == 2) {
    int n;
    n = read(f, data, elements * 2) / 2;
    if (n == elements) {
      flip2((const unsigned short *)data, (unsigned short *)data, elements);
    }
    return n;
  } else if (elsize == 4) {
    int n;
    n = read(f, data, elements * 4) / 4;
    if (n == elements) {
      flip4((const unsigned int *)data, (unsigned int *)data, elements);
    }
    return n;
  } else {
    printf("Fatal error in read_block(): bad elsize (%d)\n", elsize);
    abort();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_block>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x1,%ecx
  je     L73
  cmp    $0x2,%ecx
  je     L74
  cmp    $0x4,%ecx
  je     L76
  mov    %ecx,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%ebx
L35:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  call   <read@plt>
  mov    %eax,%ebx
  jmp    L35
L74:
  lea    (%rdx,%rdx,1),%edx
  call   <read@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rax,1),%edx
  sar    %edx
  mov    %edx,%ebx
  cmp    %edx,%r12d
  jne    L35
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <flip2@plt>
  jmp    L35
L76:
  lea    0x0(,%rdx,4),%edx
  call   <read@plt>
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x2,%edx
  mov    %edx,%ebx
  cmp    %edx,%r12d
  jne    L35
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <flip4@plt>
  jmp    L35
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: D2: Fatal error in read_block(): bad elsize (%d)


assistant: ```c
int read_block(int f, void *data, int elements, int elsize) {
  if (elsize == 1) {
    return read(f, data, elements);
  } else if (elsize == 2) {
    int n;
    n = read(f, data, elements * 2) / 2;
    if (n == elements) {
      flip2((const unsigned short *)data, (unsigned short *)data, elements);
    }
    return n;
  } else if (elsize == 4) {
    int n;
    n = read(f, data, elements * 4) / 4;
    if (n == elements) {
      flip4((const unsigned int *)data, (unsigned int *)data, elements);
    }
    return n;
  } else {
    printf("Fatal error in read_block(): bad elsize (%d)\n", elsize);
    abort();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_block>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  cmp    $0x1,%ecx
  je     L33
  mov    %ecx,%esi
  cmp    $0x2,%ecx
  je     L19
  cmp    $0x4,%ecx
  je     L55
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  xor    %eax,%eax
  call   <abort@plt>
L32:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L55:
  lea    0x0(,%rdx,4),%edx
  mov    %rbp,%rsi
  call   <read@plt>
  test   %eax,%eax
  lea    0x3(%rax),%r12d
  cmovns %eax,%r12d
  sar    $0x2,%r12d
  cmp    %r12d,%r13d
  jne    L32
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <flip4@plt>
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L33:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <read@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  lea    (%rdx,%rdx,1),%edx
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rax,1),%r12d
  sar    %r12d
  cmp    %r12d,%r13d
  jne    L32
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <flip2@plt>
  jmp    L32
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: Fatal error in read_block(): bad elsize (%d)


assistant: ```c
int read_block(int f, void *data, int elements, int elsize) {
  if (elsize == 1) {
    return read(f, data, elements);
  } else if (elsize == 2) {
    int n;
    n = read(f, data, elements * 2) / 2;
    if (n == elements) {
      flip2((const unsigned short *)data, (unsigned short *)data, elements);
    }
    return n;
  } else if (elsize == 4) {
    int n;
    n = read(f, data, elements * 4) / 4;
    if (n == elements) {
      flip4((const unsigned int *)data, (unsigned int *)data, elements);
    }
    return n;
  } else {
    printf("Fatal error in read_block(): bad elsize (%d)\n", elsize);
    abort();
  }
  return 0;
}
```