ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_connected_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L23
  mov    -0x4(%rbp),%eax
  jmp    L3
L23:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    -0xc(%rbp),%edx
  shr    %edx
  cmp    %edx,%eax
  jae    L68
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  jmp    L3
L68:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L12
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  jmp    L3
L12:
  mov    -0xc(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
unsigned get_connected_input(unsigned y, unsigned prev_start, unsigned prev_len, unsigned prev_was_pipeline) {
  if (prev_was_pipeline)
    return y;
  if (y - prev_start < prev_len / 2) {
    return prev_start + (y - prev_start) * 2;
  } else {
    if (prev_len % 2 && prev_start + prev_len - 1 == y)
      return y;
    return prev_start + (y - (prev_start + prev_len / 2)) * 2 + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_connected_input>:
  endbr64
  mov    %edi,%eax
  test   %ecx,%ecx
  jne    L12
  sub    %esi,%eax
  mov    %edx,%ecx
  shr    %ecx
  cmp    %ecx,%eax
  jb     L17
  test   $0x1,%dl
  je     L9
  lea    -0x1(%rsi,%rdx,1),%edx
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L12
L9:
  sub    %ecx,%edi
  sub    %esi,%edi
  lea    0x1(%rsi,%rdi,2),%eax
L12:
  ret
L17:
  lea    (%rsi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned get_connected_input(unsigned y, unsigned prev_start, unsigned prev_len, unsigned prev_was_pipeline) {
  if (prev_was_pipeline)
    return y;
  if (y - prev_start < prev_len / 2) {
    return prev_start + (y - prev_start) * 2;
  } else {
    if (prev_len % 2 && prev_start + prev_len - 1 == y)
      return y;
    return prev_start + (y - (prev_start + prev_len / 2)) * 2 + 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_connected_input>:
  endbr64
  mov    %edi,%eax
  test   %ecx,%ecx
  jne    L27
  mov    %edx,%r8d
  sub    %esi,%eax
  shr    %r8d
  mov    %eax,%ecx
  cmp    %r8d,%eax
  jb     L37
  test   $0x1,%dl
  je     L17
  lea    -0x1(%rsi,%rdx,1),%eax
  cmp    %edi,%eax
  je     L27
L17:
  sub    %r8d,%ecx
  lea    0x1(%rsi,%rcx,2),%eax
L27:
  ret
  xchg   %ax,%ax
L37:
  lea    (%rsi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned get_connected_input(unsigned y, unsigned prev_start, unsigned prev_len, unsigned prev_was_pipeline) {
  if (prev_was_pipeline)
    return y;
  if (y - prev_start < prev_len / 2) {
    return prev_start + (y - prev_start) * 2;
  } else {
    if (prev_len % 2 && prev_start + prev_len - 1 == y)
      return y;
    return prev_start + (y - (prev_start + prev_len / 2)) * 2 + 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_connected_input>:
  endbr64
  mov    %edi,%eax
  test   %ecx,%ecx
  jne    L11
  mov    %edx,%r8d
  sub    %esi,%eax
  shr    %r8d
  mov    %eax,%ecx
  cmp    %r8d,%eax
  jb     L38
  test   $0x1,%dl
  je     L3
  lea    -0x1(%rsi,%rdx,1),%eax
  cmp    %edi,%eax
  je     L11
L3:
  sub    %r8d,%ecx
  lea    0x1(%rsi,%rcx,2),%eax
L11:
  ret
  xchg   %ax,%ax
L38:
  lea    (%rsi,%rax,2),%eax
  ret
```

assistant: ```c
unsigned get_connected_input(unsigned y, unsigned prev_start, unsigned prev_len, unsigned prev_was_pipeline) {
  if (prev_was_pipeline)
    return y;
  if (y - prev_start < prev_len / 2) {
    return prev_start + (y - prev_start) * 2;
  } else {
    if (prev_len % 2 && prev_start + prev_len - 1 == y)
      return y;
    return prev_start + (y - (prev_start + prev_len / 2)) * 2 + 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_242_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_242_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = *D & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_242_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  not    %esi
  and    (%rdi),%sil
  or     %edx,%esi
  mov    %eax,%edx
  not    %edx
  and    %edx,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_242_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = *D & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_242_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  not    %esi
  and    (%rdi),%sil
  or     %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_242_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = *D & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_242_1_1>:
  endbr64
  mov    %edx,%eax
  or     %esi,%eax
  not    %esi
  and    (%rdi),%sil
  or     %edx,%esi
  mov    %eax,%edx
  and    (%rdi),%al
  not    %edx
  and    %edx,%esi
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_242_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~S;
  stk2 = *D & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D12(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D38(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D7(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: f32
name: disassemble_data
arguments: data_label: D38
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D7
type_guessed: f32
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D12: 5

tool: {"D38": [0x00,0x00,0x90,0xc0]}

tool: D7: 11.25

tool: D15: Your numbers are:
v1: %.0f
v2: %.1f
v3: %.2f


assistant: ```c
main() {
  float v1 = 5.0, v2 = -4.5, v3 = 11.25;
  printf("Your numbers are:\nv1: %.0f\nv2: %.1f\nv3: %.2f\n", v1, v2, v3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D16(%rip),%xmm2
  movss  D15(%rip),%xmm1
  movss  D29(%rip),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type: f32
name: unpack_data
arguments: label: D15
type: byte[4]
name: unpack_data
arguments: label: D29
type: f32
name: unpack_data
arguments: label: D1
type: string

tool: D16: 11.25

tool: {"D15": [0x00,0x00,0x90,0xc0]}

tool: D29: 5

tool: D1: Your numbers are:
v1: %.0f
v2: %.1f
v3: %.2f


assistant: ```c
main() {
  float v1 = 5.0, v2 = -4.5, v3 = 11.25;
  printf("Your numbers are:\nv1: %.0f\nv2: %.1f\nv3: %.2f\n", v1, v2, v3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D11(%rip),%xmm2
  movss  D26(%rip),%xmm1
  lea    D2(%rip),%rdi
  movss  D10(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: f32
name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: f32

tool: D11: 11.25

tool: {"D26": [0x00,0x00,0x90,0xc0]}

tool: D2: Your numbers are:
v1: %.0f
v2: %.1f
v3: %.2f


tool: D10: 5

assistant: ```c
main() {
  float v1 = 5.0, v2 = -4.5, v3 = 11.25;
  printf("Your numbers are:\nv1: %.0f\nv2: %.1f\nv3: %.2f\n", v1, v2, v3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D24(%rip),%xmm2
  movss  D36(%rip),%xmm1
  lea    D12(%rip),%rdi
  movss  D3(%rip),%xmm0
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D24
type_infered: f32
name: read_data
arguments: tag: D36
type_infered: byte[4]
name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D3
type_infered: f32

tool: D24: 11.25

tool: {"D36": [0x00,0x00,0x90,0xc0]}

tool: D12: Your numbers are:
v1: %.0f
v2: %.1f
v3: %.2f


tool: D3: 5

assistant: ```c
main() {
  float v1 = 5.0, v2 = -4.5, v3 = 11.25;
  printf("Your numbers are:\nv1: %.0f\nv2: %.1f\nv3: %.2f\n", v1, v2, v3);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inso_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L23
L19:
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L3
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  jmp    L16
L3:
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L16:
  leave
  ret
```

assistant: ```c
int inso_strcat(char *buf, size_t sz, const char *str) {
  char *p = buf;
  while (*p)
    ++p;
  sz -= (p - buf);
  size_t len = strlen(str) + 1;
  if (len <= sz) {
    memcpy(p, str, len);
    return len;
  } else {
    return sz - len;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inso_strcat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r13
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rdi,%rbx
L26:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L26
L31:
  mov    %rbx,%rax
  sub    %rdi,%rax
  sub    %rax,%rbp
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%rdx
  cmp    %rdx,%rbp
  jae    L22
  mov    %ebp,%eax
  sub    %r12d,%eax
  mov    %eax,%r12d
L7:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    %rdi,%rbx
  jmp    L31
L22:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L7
```

assistant: ```c
int inso_strcat(char *buf, size_t sz, const char *str) {
  char *p = buf;
  while (*p)
    ++p;
  sz -= (p - buf);
  size_t len = strlen(str) + 1;
  if (len <= sz) {
    memcpy(p, str, len);
    return len;
  } else {
    return sz - len;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inso_strcat>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L9
  nopl   0x0(%rax)
L25:
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L25
  mov    %rbp,%rax
  sub    %rdi,%rax
  sub    %rax,%rbx
L9:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%rdx
  cmp    %rbx,%rdx
  jbe    L16
  mov    %ebx,%eax
  add    $0x8,%rsp
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int inso_strcat(char *buf, size_t sz, const char *str) {
  char *p = buf;
  while (*p)
    ++p;
  sz -= (p - buf);
  size_t len = strlen(str) + 1;
  if (len <= sz) {
    memcpy(p, str, len);
    return len;
  } else {
    return sz - len;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inso_strcat>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L11
  nopl   0x0(%rax)
L0:
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L0
  mov    %rbp,%rax
  sub    %rdi,%rax
  sub    %rax,%rbx
L11:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%rdx
  cmp    %rbx,%rdx
  jbe    L16
  mov    %ebx,%eax
  add    $0x8,%rsp
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int inso_strcat(char *buf, size_t sz, const char *str) {
  char *p = buf;
  while (*p)
    ++p;
  sz -= (p - buf);
  size_t len = strlen(str) + 1;
  if (len <= sz) {
    memcpy(p, str, len);
    return len;
  } else {
    return sz - len;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UART0_SendData32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3030303030303030,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x0,-0x9(%rbp)
  movb   $0x0,-0x12(%rbp)
  movb   $0x8,-0x13(%rbp)
  jmp    L5
L92:
  mov    -0x28(%rbp),%rax
  and    $0xf,%eax
  mov    %al,-0x12(%rbp)
  movzbl -0x12(%rbp),%eax
  cmp    $0x9,%eax
  jg     L58
  test   %eax,%eax
  jns    L103
  jmp    L82
L58:
  sub    $0xa,%eax
  cmp    $0x5,%eax
  ja     L82
  jmp    L75
L103:
  movzbl -0x12(%rbp),%eax
  lea    0x30(%rax),%edx
  movsbl -0x13(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %dl,-0x11(%rbp,%rax,1)
  jmp    L91
L75:
  movzbl -0x12(%rbp),%eax
  lea    0x37(%rax),%edx
  movsbl -0x13(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %dl,-0x11(%rbp,%rax,1)
  jmp    L91
L82:
  movsbl -0x13(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x58,-0x11(%rbp,%rax,1)
  nop
L91:
  shrq   $0x4,-0x28(%rbp)
  movzbl -0x13(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x13(%rbp)
L5:
  cmpq   $0x0,-0x28(%rbp)
  jne    L92
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <UART0_SendString@plt>
  cmpb   $0x8,-0x13(%rbp)
  jne    L50
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <UART0_SendString@plt>
  jmp    L97
L50:
  movsbl -0x13(%rbp),%eax
  lea    -0x11(%rbp),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <UART0_SendString@plt>
L97:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: D2: 0x

tool: D6: 0

assistant: ```c
void UART0_SendData32(unsigned long int data) {
  char hex_string[] = "00000000";
  unsigned char ch = 0;
  char index = 8;
  while (data) {
    ch = (unsigned char)(data & 0x0000000F);
    switch (ch) {
    case 0:
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
      hex_string[index - 1] = '0' + ch;
      break;
    case 10:
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
      hex_string[index - 1] = 'A' + ch - 10;
      break;
    default:
      hex_string[index - 1] = 'X';
      break;
    }
    data = data >> 4;
    index--;
  }
  UART0_SendString("0x");
  if (index == 8)
    UART0_SendString("0");
  else
    UART0_SendString(&hex_string[index]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UART0_SendData32>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3030303030303030,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x0,0x17(%rsp)
  test   %rdi,%rdi
  je     L75
  mov    $0x8,%ebx
  jmp    L29
L0:
  movsbl %bl,%eax
  sub    $0x1,%eax
  cltq
  add    $0x37,%edx
  mov    %dl,0xf(%rsp,%rax,1)
L61:
  sub    $0x1,%ebx
  shr    $0x4,%rdi
  je     L41
L29:
  mov    %edi,%edx
  and    $0xf,%edx
  cmp    $0x9,%dl
  ja     L0
  movsbl %bl,%eax
  sub    $0x1,%eax
  cltq
  add    $0x30,%edx
  mov    %dl,0xf(%rsp,%rax,1)
  jmp    L61
L41:
  lea    D23(%rip),%rdi
  call   <UART0_SendString@plt>
  cmp    $0x8,%bl
  je     L78
  movsbq %bl,%rbx
  lea    0xf(%rsp,%rbx,1),%rdi
  call   <UART0_SendString@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  pop    %rbx
  ret
L75:
  lea    D23(%rip),%rdi
  call   <UART0_SendString@plt>
L78:
  lea    D1(%rip),%rdi
  call   <UART0_SendString@plt>
  jmp    L4
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D23: 0x

tool: D1: 0

assistant: ```c
void UART0_SendData32(unsigned long int data) {
  char hex_string[] = "00000000";
  unsigned char ch = 0;
  char index = 8;
  while (data) {
    ch = (unsigned char)(data & 0x0000000F);
    switch (ch) {
    case 0:
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
      hex_string[index - 1] = '0' + ch;
      break;
    case 10:
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
      hex_string[index - 1] = 'A' + ch - 10;
      break;
    default:
      hex_string[index - 1] = 'X';
      break;
    }
    data = data >> 4;
    index--;
  }
  UART0_SendString("0x");
  if (index == 8)
    UART0_SendString("0");
  else
    UART0_SendString(&hex_string[index]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UART0_SendData32>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3030303030303030,%rax
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  test   %rdi,%rdi
  je     L4
  mov    $0x8,%ebx
  nopl   (%rax)
L31:
  mov    %edi,%eax
  movsbl %bl,%edx
  and    $0xf,%eax
  sub    $0x1,%edx
  lea    -0xa(%rax),%esi
  lea    0x30(%rax),%ecx
  add    $0x37,%eax
  movslq %edx,%rdx
  cmp    $0x6,%sil
  cmovae %ecx,%eax
  sub    $0x1,%ebx
  shr    $0x4,%rdi
  mov    %al,0xf(%rsp,%rdx,1)
  jne    L31
  lea    D21(%rip),%rdi
  call   <UART0_SendString@plt>
  cmp    $0x8,%bl
  je     L30
  movsbq %bl,%rbx
  lea    0xf(%rsp,%rbx,1),%rdi
  call   <UART0_SendString@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D21(%rip),%rdi
  call   <UART0_SendString@plt>
L30:
  lea    D29(%rip),%rdi
  call   <UART0_SendString@plt>
  jmp    L17
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type_infered: string
name: read_data
arguments: tag: D29
type_infered: string

tool: D21: 0x

tool: D29: 0

assistant: ```c
void UART0_SendData32(unsigned long int data) {
  char hex_string[] = "00000000";
  unsigned char ch = 0;
  char index = 8;
  while (data) {
    ch = (unsigned char)(data & 0x0000000F);
    switch (ch) {
    case 0:
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
      hex_string[index - 1] = '0' + ch;
      break;
    case 10:
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
      hex_string[index - 1] = 'A' + ch - 10;
      break;
    default:
      hex_string[index - 1] = 'X';
      break;
    }
    data = data >> 4;
    index--;
  }
  UART0_SendString("0x");
  if (index == 8)
    UART0_SendString("0");
  else
    UART0_SendString(&hex_string[index]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UART0_SendData32>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3030303030303030,%rax
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  test   %rdi,%rdi
  je     L52
  mov    $0x8,%ebx
  nopl   0x0(%rax)
L26:
  mov    %edi,%edx
  movsbl %bl,%eax
  and    $0xf,%edx
  sub    $0x1,%eax
  lea    -0xa(%rdx),%ecx
  cltq
  cmp    $0x5,%cl
  jbe    L67
  add    $0x30,%edx
  sub    $0x1,%ebx
  shr    $0x4,%rdi
  mov    %dl,0xf(%rsp,%rax,1)
  jne    L26
L61:
  lea    D10(%rip),%rdi
  call   <UART0_SendString@plt>
  cmp    $0x8,%bl
  je     L49
  movsbq %bl,%rbx
  lea    0xf(%rsp,%rbx,1),%rdi
  call   <UART0_SendString@plt>
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  add    $0x37,%edx
  sub    $0x1,%ebx
  shr    $0x4,%rdi
  mov    %dl,0xf(%rsp,%rax,1)
  jne    L26
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L52:
  lea    D10(%rip),%rdi
  call   <UART0_SendString@plt>
L49:
  lea    D27(%rip),%rdi
  call   <UART0_SendString@plt>
  jmp    L43
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D27
datatype: string

tool: D10: 0x

tool: D27: 0

assistant: ```c
void UART0_SendData32(unsigned long int data) {
  char hex_string[] = "00000000";
  unsigned char ch = 0;
  char index = 8;
  while (data) {
    ch = (unsigned char)(data & 0x0000000F);
    switch (ch) {
    case 0:
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
      hex_string[index - 1] = '0' + ch;
      break;
    case 10:
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
      hex_string[index - 1] = 'A' + ch - 10;
      break;
    default:
      hex_string[index - 1] = 'X';
      break;
    }
    data = data >> 4;
    index--;
  }
  UART0_SendString("0x");
  if (index == 8)
    UART0_SendString("0");
  else
    UART0_SendString(&hex_string[index]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ExtendAndFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ExtendString@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <Free@plt>
  nop
  leave
  ret
```

assistant: ```c
void ExtendAndFree(char **Buffer, char *WithThisToFree, int *BufferSize) {
  ExtendString(Buffer, WithThisToFree, BufferSize);
  Free((void **)&WithThisToFree);
}
```