ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xmalloc>:
  endbr64
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L5
  call   <malloc@plt>
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1090 <check_alloc@plt>
  nopl   (%rax)
L5:
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <__builtin_unreachable@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1090 <check_alloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((size == 0)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return check_alloc(malloc(size));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmalloc>:
  endbr64
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L0
  call   <malloc@plt>
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1090 <check_alloc@plt>
  nopl   (%rax)
L0:
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <__builtin_unreachable@plt>
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  add    $0x18,%rsp
  mov    %eax,%edi
  jmp    1090 <check_alloc@plt>
```

assistant: ```c
void *xmalloc(size_t size) {
  do {
#pragma GCC diagnostic push

#pragma GCC diagnostic ignored "-Wpragmas"

#pragma GCC diagnostic ignored "-Wtautological-compare"
    if ((size == 0)) {
      __builtin_unreachable();
    }
#pragma GCC diagnostic pop
  } while (0);
  return check_alloc(malloc(size));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<t22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x98(%rbp)
  jmp    L17
L66:
  mov    -0x98(%rbp),%eax
  cltq
  movl   $0x0,-0x90(%rbp,%rax,4)
  addl   $0x1,-0x98(%rbp)
L17:
  cmpl   $0x1f,-0x98(%rbp)
  jle    L66
  movl   $0x0,-0x94(%rbp)
  jmp    L27
L11:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x94(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  addl   $0x1,-0x94(%rbp)
L27:
  cmpl   $0x1f,-0x94(%rbp)
  jle    L11
  movl   $0x0,-0x98(%rbp)
  jmp    L15
L67:
  mov    -0x98(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x98(%rbp)
L15:
  cmpl   $0x1f,-0x98(%rbp)
  jle    L67
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
void t22() {
  int arr[32], i;
  for (i = 0; i < 32; i++)
    arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(8) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
#pragma acc atomic
      arr[j]++;
    }
  }
  for (i = 0; i < 32; i++)
    assert(arr[i] == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<t22>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x80(%rsp),%rbp
  mov    %rbx,%rax
L37:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L37
  mov    %rbx,%rax
L1:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L1
L17:
  cmpl   $0x1,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L17
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t22() {
  int arr[32], i;
  for (i = 0; i < 32; i++)
    arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(8) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
#pragma acc atomic
      arr[j]++;
    }
  }
  for (i = 0; i < 32; i++)
    assert(arr[i] == 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<t22>:
  endbr64
  push   %rbp
  mov    $0x10,%ecx
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x80(%rsp),%rbp
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rbx,%rax
  nopl   0x0(%rax)
L8:
  addl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L8
  nopl   0x0(%rax)
L12:
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %rbx,%rbp
  jne    L12
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t22() {
  int arr[32], i;
  for (i = 0; i < 32; i++)
    arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(8) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
#pragma acc atomic
      arr[j]++;
    }
  }
  for (i = 0; i < 32; i++)
    assert(arr[i] == 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<t22>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x80(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %edi,%edi
  cmpl   $0x1,(%rbx)
  sete   %dil
  add    $0x4,%rbx
  call   <assert@plt>
  cmp    %rbp,%rbx
  jne    L7
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: byte[16]

tool: {"D5": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void t22() {
  int arr[32], i;
  for (i = 0; i < 32; i++)
    arr[i] = 0;
#pragma acc parallel copy(arr) num_gangs(8) num_workers(8) vector_length(32)
  {
    int j;
#pragma acc loop gang
    for (j = 0; j < 32; j++) {
#pragma acc atomic
      arr[j]++;
    }
  }
  for (i = 0; i < 32; i++)
    assert(arr[i] == 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1f,-0x4(%rbp)
  movl   $0x80000000,-0x8(%rbp)
  jmp    L16
L28:
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L34
  mov    -0x4(%rbp),%eax
  jmp    L18
L34:
  subl   $0x1,-0x4(%rbp)
  shrl   -0x8(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jne    L28
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsr>:
  endbr64
  test   %edi,%edi
  js     L18
  mov    $0x40000000,%edx
  mov    $0x1e,%eax
L11:
  test   %edx,%edi
  jne    L0
  shr    %edx
  sub    $0x1,%eax
  jne    L11
  ret
L18:
  mov    $0x1f,%eax
L0:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bsr>:
  endbr64
  mov    $0x1f,%eax
  mov    $0x80000000,%edx
  jmp    L11
L0:
  shr    %edx
  sub    $0x1,%eax
  je     L14
L11:
  test   %edx,%edi
  je     L0
L14:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bsr>:
  endbr64
  mov    $0x1f,%eax
  mov    $0x80000000,%edx
  jmp    L5
L12:
  shr    %edx
  sub    $0x1,%eax
  je     L16
L5:
  test   %edx,%edi
  je     L12
L16:
  ret
```

assistant: ```c
int bsr(int v) {
  unsigned int res;
  int i;
  for (i = 31, res = (1 << 31); i; i--, res >>= 1) {
    if (v & res) {
      return i;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L27
  cmpl   $0x0,-0x8(%rbp)
  jne    L45
L27:
  cmpl   $0x0,-0x4(%rbp)
  je     L22
L45:
  mov    $0x1,%eax
  jmp    L64
L22:
  mov    $0x0,%eax
L64:
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L7
  cmpl   $0x0,-0x8(%rbp)
  jne    L42
  cmpl   $0x0,-0x4(%rbp)
  je     L42
L7:
  mov    $0x1,%eax
  jmp    L49
L42:
  mov    $0x0,%eax
L49:
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%edx
  sub    %eax,%edx
  add    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D32
data_type: string

tool: D32: %d


assistant: ```c
main() {
  int x, y, z;
  x = 2;
  y = 1;
  z = 0;
  x = x && y || z;
  printf("%d\n", x);
  printf("%d\n", x || !y && z);
  x = y = 1;
  z = x++ - 1;
  printf("%d\n", x);
  printf("%d\n", z);
  z += -x++ + ++y;
  printf("%d\n", x);
  printf("%d\n", z);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: %d


assistant: ```c
main() {
  int x, y, z;
  x = 2;
  y = 1;
  z = 0;
  x = x && y || z;
  printf("%d\n", x);
  printf("%d\n", x || !y && z);
  x = y = 1;
  z = x++ - 1;
  printf("%d\n", x);
  printf("%d\n", z);
  z += -x++ + ++y;
  printf("%d\n", x);
  printf("%d\n", z);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %d


assistant: ```c
main() {
  int x, y, z;
  x = 2;
  y = 1;
  z = 0;
  x = x && y || z;
  printf("%d\n", x);
  printf("%d\n", x || !y && z);
  x = y = 1;
  z = x++ - 1;
  printf("%d\n", x);
  printf("%d\n", z);
  z += -x++ + ++y;
  printf("%d\n", x);
  printf("%d\n", z);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: %d


assistant: ```c
main() {
  int x, y, z;
  x = 2;
  y = 1;
  z = 0;
  x = x && y || z;
  printf("%d\n", x);
  printf("%d\n", x || !y && z);
  x = y = 1;
  z = x++ - 1;
  printf("%d\n", x);
  printf("%d\n", z);
  z += -x++ + ++y;
  printf("%d\n", x);
  printf("%d\n", z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<next_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
L8:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <get@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L4
  mov    $0xffffffff,%eax
  jmp    L11
L4:
  addl   $0x1,-0x1c(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L8
  mov    -0x1c(%rbp),%eax
L11:
  leave
  ret
```

assistant: ```c
int next_line(struct editor *ed, int pos) {
  while (1) {
    int ch = get(ed, pos);
    if (ch < 0)
      return -1;
    pos++;
    if (ch == '\n')
      return pos;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
L11:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get@plt>
  test   %eax,%eax
  js     L10
  add    $0x1,%ebx
  cmp    $0xa,%eax
  jne    L11
  mov    %ebx,%eax
  jmp    L14
L10:
  mov    $0xffffffff,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int next_line(struct editor *ed, int pos) {
  while (1) {
    int ch = get(ed, pos);
    if (ch < 0)
      return -1;
    pos++;
    if (ch == '\n')
      return pos;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_line>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax)
L23:
  add    $0x1,%ebx
  cmp    $0xa,%eax
  je     L11
L13:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get@plt>
  test   %eax,%eax
  jns    L23
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int next_line(struct editor *ed, int pos) {
  while (1) {
    int ch = get(ed, pos);
    if (ch < 0)
      return -1;
    pos++;
    if (ch == '\n')
      return pos;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<next_line>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L28
  nopl   0x0(%rax)
L18:
  add    $0x1,%ebx
  cmp    $0xa,%eax
  je     L27
L28:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <get@plt>
  test   %eax,%eax
  jns    L18
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int next_line(struct editor *ed, int pos) {
  while (1) {
    int ch = get(ed, pos);
    if (ch < 0)
      return -1;
    pos++;
    if (ch == '\n')
      return pos;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<insert_expansion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L4:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L4
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_expansion(char *destination, char c, unsigned int times, unsigned int *starting_index) {
  unsigned int i;
  for (i = 0; i < times; i++) {
    destination[*starting_index + i] = c;
  }
  *starting_index += times;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insert_expansion>:
  endbr64
  test   %edx,%edx
  je     L0
  mov    $0x0,%eax
L10:
  mov    %eax,%r8d
  add    (%rcx),%r8d
  mov    %sil,(%rdi,%r8,1)
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L10
L0:
  add    %edx,(%rcx)
  ret
```

assistant: ```c
void insert_expansion(char *destination, char c, unsigned int times, unsigned int *starting_index) {
  unsigned int i;
  for (i = 0; i < times; i++) {
    destination[*starting_index + i] = c;
  }
  *starting_index += times;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insert_expansion>:
  endbr64
  test   %edx,%edx
  je     L15
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %eax,%r8d
  add    $0x1,%eax
  add    (%rcx),%r8d
  mov    %sil,(%rdi,%r8,1)
  cmp    %eax,%edx
  jne    L1
L15:
  add    %edx,(%rcx)
  ret
```

assistant: ```c
void insert_expansion(char *destination, char c, unsigned int times, unsigned int *starting_index) {
  unsigned int i;
  for (i = 0; i < times; i++) {
    destination[*starting_index + i] = c;
  }
  *starting_index += times;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insert_expansion>:
  endbr64
  test   %edx,%edx
  je     L2
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %eax,%r8d
  add    $0x1,%eax
  add    (%rcx),%r8d
  mov    %sil,(%rdi,%r8,1)
  cmp    %eax,%edx
  jne    L15
L2:
  add    %edx,(%rcx)
  ret
```

assistant: ```c
void insert_expansion(char *destination, char c, unsigned int times, unsigned int *starting_index) {
  unsigned int i;
  for (i = 0; i < times; i++) {
    destination[*starting_index + i] = c;
  }
  *starting_index += times;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<notYetImplemented>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: 
Not yet implemented


assistant: ```c
void notYetImplemented() {
  printf("\nNot yet implemented\n");
  exit(2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<notYetImplemented>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: 
Not yet implemented


assistant: ```c
void notYetImplemented() {
  printf("\nNot yet implemented\n");
  exit(2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<notYetImplemented>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type: string

tool: D2: 
Not yet implemented


assistant: ```c
void notYetImplemented() {
  printf("\nNot yet implemented\n");
  exit(2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<notYetImplemented>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: 
Not yet implemented


assistant: ```c
void notYetImplemented() {
  printf("\nNot yet implemented\n");
  exit(2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printGrid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L86:
  mov    $0x2d,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0x16,-0x10(%rbp)
  jle    L86
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0xa,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L25:
  mov    $0x7c,%edi
  call   <putchar@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L88
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L88
  mov    $0x50,%edi
  call   <putchar@plt>
  jmp    L43
L88:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L43:
  addl   $0x1,-0x10(%rbp)
L15:
  cmpl   $0x14,-0x10(%rbp)
  jle    L39
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x14,-0xc(%rbp)
  jle    L25
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L49:
  mov    $0x5f,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L3:
  cmpl   $0x16,-0x10(%rbp)
  jle    L49
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string

tool: D16: cls

tool: D10: |


assistant: ```c
void printGrid(char grid[21][21]) {
  int x, y, middleRow, middleColumn;
  system("cls");
  for (x = 0; x < (21 + 2); ++x)
    putchar('-');
  putchar('\n');
  middleRow = (21 - 1) / 2;
  middleColumn = (21 - 1) / 2;
  for (y = 0; y < 21; y++) {
    putchar('|');
    for (x = 0; x < 21; x++) {
      if ((x == middleColumn) && (y == middleRow))
        putchar('P');
      else
        putchar(grid[x][y]);
    }
    printf("|\n");
  }
  for (x = 0; x < (21 + 2); ++x)
    putchar('_');
  putchar('\n');
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printGrid>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  lea    D17(%rip),%rdi
  call   <system@plt>
  mov    $0x17,%ebx
L3:
  mov    $0x2d,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%r12d
  lea    D2(%rip),%r14
  jmp    L52
L55:
  mov    $0x50,%edi
  call   <putchar@plt>
L8:
  add    $0x1,%ebx
  add    $0x15,%rbp
L4:
  cmp    $0xb,%ebx
  jne    L53
  cmp    $0xa,%r12d
  je     L55
L53:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
  cmp    $0x14,%ebx
  jle    L8
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r12
  cmp    $0x15,%r12
  je     L72
L52:
  mov    $0x7c,%edi
  call   <putchar@plt>
  lea    0x0(%r13,%r12,1),%rbp
  mov    $0x1,%ebx
  jmp    L4
L72:
  mov    $0x17,%ebx
L9:
  mov    $0x5f,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D17: cls

tool: D2: |


assistant: ```c
void printGrid(char grid[21][21]) {
  int x, y, middleRow, middleColumn;
  system("cls");
  for (x = 0; x < (21 + 2); ++x)
    putchar('-');
  putchar('\n');
  middleRow = (21 - 1) / 2;
  middleColumn = (21 - 1) / 2;
  for (y = 0; y < 21; y++) {
    putchar('|');
    for (x = 0; x < 21; x++) {
      if ((x == middleColumn) && (y == middleRow))
        putchar('P');
      else
        putchar(grid[x][y]);
    }
    printf("|\n");
  }
  for (x = 0; x < (21 + 2); ++x)
    putchar('_');
  putchar('\n');
  return;
}
```