ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <r_fib@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L22:
  mov    $0x0,%eax
  call   <s_fib@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L22
  mov    $0x0,%eax
  call   <s_fib@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D15: %d

tool: D28: %d


tool: D2: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int i = 0;
  scanf("%d", &n);
  printf("%d\n", r_fib(n));
  for (i = 0; i < n - 1; i++)
    s_fib();
  printf("%lld\n", s_fib());
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <r_fib@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L8
  mov    $0x0,%ebx
L13:
  mov    $0x0,%eax
  call   <s_fib@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L13
L8:
  mov    $0x0,%eax
  call   <s_fib@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D13
type: string

tool: D3: %d

tool: D15: %d


tool: D13: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int i = 0;
  scanf("%d", &n);
  printf("%d\n", r_fib(n));
  for (i = 0; i < n - 1; i++)
    s_fib();
  printf("%lld\n", s_fib());
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <r_fib@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L21
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <s_fib@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L16
L21:
  xor    %eax,%eax
  call   <s_fib@plt>
  lea    D10(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
datatype: string
name: parse_data
arguments: data_label: D8
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: D13: %d

tool: D8: %d


tool: D10: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int i = 0;
  scanf("%d", &n);
  printf("%d\n", r_fib(n));
  for (i = 0; i < n - 1; i++)
    s_fib();
  printf("%lld\n", s_fib());
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D11(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <r_fib@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L20
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <s_fib@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L15
L20:
  xor    %eax,%eax
  call   <s_fib@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string

tool: D11: %d

tool: D8: %d


tool: D21: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int i = 0;
  scanf("%d", &n);
  printf("%d\n", r_fib(n));
  for (i = 0; i < n - 1; i++)
    s_fib();
  printf("%lld\n", s_fib());
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<puthex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  movl   $0xf,-0x8(%rbp)
  jmp    L19
L21:
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L31
  movl   $0x0,-0xc(%rbp)
L31:
  cmpl   $0x0,-0xc(%rbp)
  jne    L70
  cmpl   $0x9,-0x4(%rbp)
  jg     L62
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_put@plt>
  jmp    L17
L62:
  mov    -0x4(%rbp),%eax
  add    $0x37,%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_put@plt>
  jmp    L17
L70:
  nop
L17:
  subl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0x0,-0x8(%rbp)
  jns    L21
  cmpl   $0x0,-0xc(%rbp)
  je     L64
  mov    $0x30,%edi
  call   <uart_put@plt>
L64:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: 0x

assistant: ```c
void puthex(uint64_t n) {
  int zeros = 1;
  int c;
  int i;
  uart_puts("0x");
  for (i = 15; i >= 0; i--) {
    c = (n >> (4 * i)) & 0xF;
    if (c != 0)
      zeros = 0;
    if (zeros)
      continue;
    if (c < 10)
      uart_put('0' + c);
    else
      uart_put('A' + (c - 10));
  }
  if (zeros)
    uart_put('0');
}
```
user: Translate the below assembly code into C programming language:

```asm
<puthex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  lea    D8(%rip),%rdi
  call   <uart_puts@plt>
  mov    $0x3c,%ebx
  mov    $0x1,%edx
  mov    $0x0,%r12d
  jmp    L62
L27:
  cmp    $0x9,%eax
  jle    L15
  lea    0x37(%rax),%edi
  call   <uart_put@plt>
  mov    %r12d,%edx
  jmp    L53
L15:
  lea    0x30(%rax),%edi
  call   <uart_put@plt>
  mov    %r12d,%edx
L53:
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  je     L20
L62:
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  jne    L27
  test   %edx,%edx
  je     L15
  jmp    L53
L20:
  test   %edx,%edx
  jne    L88
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L88:
  mov    $0x30,%edi
  call   <uart_put@plt>
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: 0x

assistant: ```c
void puthex(uint64_t n) {
  int zeros = 1;
  int c;
  int i;
  uart_puts("0x");
  for (i = 15; i >= 0; i--) {
    c = (n >> (4 * i)) & 0xF;
    if (c != 0)
      zeros = 0;
    if (zeros)
      continue;
    if (c < 10)
      uart_put('0' + c);
    else
      uart_put('A' + (c - 10));
  }
  if (zeros)
    uart_put('0');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puthex>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  push   %rbx
  mov    $0x3c,%ebx
  sub    $0x8,%rsp
  call   <uart_puts@plt>
  mov    $0x1,%edx
  jmp    L31
  nopl   0x0(%rax)
L41:
  test   %edx,%edx
  jne    L53
L48:
  lea    0x30(%rax),%edi
  call   <uart_put@plt>
  xor    %edx,%edx
L53:
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  je     L62
L31:
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  je     L41
  cmp    $0x9,%eax
  jle    L48
  lea    0x37(%rax),%edi
  sub    $0x4,%ebx
  call   <uart_put@plt>
  xor    %edx,%edx
  cmp    $0xfffffffc,%ebx
  jne    L31
L62:
  test   %edx,%edx
  jne    L45
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x8,%rsp
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <uart_put@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: 0x

assistant: ```c
void puthex(uint64_t n) {
  int zeros = 1;
  int c;
  int i;
  uart_puts("0x");
  for (i = 15; i >= 0; i--) {
    c = (n >> (4 * i)) & 0xF;
    if (c != 0)
      zeros = 0;
    if (zeros)
      continue;
    if (c < 10)
      uart_put('0' + c);
    else
      uart_put('A' + (c - 10));
  }
  if (zeros)
    uart_put('0');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<puthex>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D8(%rip),%rdi
  push   %rbx
  mov    $0x3c,%ebx
  sub    $0x8,%rsp
  call   <uart_puts@plt>
  mov    $0x1,%edx
  jmp    L45
  nopl   0x0(%rax)
L62:
  test   %edx,%edx
  jne    L15
L57:
  lea    0x30(%rax),%edi
  call   <uart_put@plt>
  xor    %edx,%edx
L15:
  sub    $0x4,%ebx
  cmp    $0xfffffffc,%ebx
  je     L46
L45:
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0xf,%eax
  je     L62
  cmp    $0x9,%eax
  jle    L57
  lea    0x37(%rax),%edi
  sub    $0x4,%ebx
  call   <uart_put@plt>
  xor    %edx,%edx
  cmp    $0xfffffffc,%ebx
  jne    L45
L46:
  test   %edx,%edx
  jne    L35
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x8,%rsp
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <uart_put@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: 0x

assistant: ```c
void puthex(uint64_t n) {
  int zeros = 1;
  int c;
  int i;
  uart_puts("0x");
  for (i = 15; i >= 0; i--) {
    c = (n >> (4 * i)) & 0xF;
    if (c != 0)
      zeros = 0;
    if (zeros)
      continue;
    if (c < 10)
      uart_put('0' + c);
    else
      uart_put('A' + (c - 10));
  }
  if (zeros)
    uart_put('0');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<anetWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L21:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L48
  mov    -0x8(%rbp),%eax
  jmp    L16
L48:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L16
L8:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L21
  mov    -0x8(%rbp),%eax
L16:
  leave
  ret
```

assistant: ```c
int anetWrite(int fd, char *buf, int count) {
  ssize_t nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1)
      return -1;
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<anetWrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r12d
  test   %edx,%edx
  je     L1
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L6:
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  je     L34
  cmp    $0xffffffff,%eax
  je     L40
  add    %eax,%ebx
  cltq
  add    %rax,%rbp
  cmp    %ebx,%r12d
  jne    L6
  jmp    L34
L1:
  mov    %edx,%ebx
  jmp    L34
L40:
  mov    %eax,%ebx
L34:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int anetWrite(int fd, char *buf, int count) {
  ssize_t nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1)
      return -1;
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<anetWrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L17
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%ebx
  xor    %r12d,%r12d
  jmp    L39
  xchg   %ax,%ax
L40:
  cmp    $0xffffffff,%eax
  je     L12
  add    %eax,%r12d
  cltq
  add    %rax,%r13
  cmp    %r12d,%ebx
  je     L46
L39:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  call   <write@plt>
  test   %eax,%eax
  jne    L40
L46:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  xor    %r12d,%r12d
  jmp    L46
```

assistant: ```c
int anetWrite(int fd, char *buf, int count) {
  ssize_t nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1)
      return -1;
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<anetWrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L15
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %edx,%ebx
  xor    %r12d,%r12d
  jmp    L17
  xchg   %ax,%ax
L52:
  cmp    $0xffffffff,%eax
  je     L41
  add    %eax,%r12d
  cltq
  add    %rax,%r13
  cmp    %r12d,%ebx
  je     L25
L17:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  sub    %r12d,%edx
  call   <write@plt>
  test   %eax,%eax
  jne    L52
L25:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  xor    %r12d,%r12d
  jmp    L25
```

assistant: ```c
int anetWrite(int fd, char *buf, int count) {
  ssize_t nwritten, totlen = 0;
  while (totlen != count) {
    nwritten = write(fd, buf, count - totlen);
    if (nwritten == 0)
      return totlen;
    if (nwritten == -1)
      return -1;
    totlen += nwritten;
    buf += nwritten;
  }
  return totlen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GUI_Circle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %dx,-0x4(%rbp)
  mov    %ecx,%edx
  mov    %dx,-0x8(%rbp)
  mov    %ax,-0xc(%rbp)
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0x52,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  nop
  leave
  ret
```

assistant: ```c
void GUI_Circle(unsigned short int x, unsigned short int y, unsigned short int r) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x52) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((y) >> 8) & 0xFF);
  SendChar((y)&0xFF);
  SendChar(((r) >> 8) & 0xFF);
  SendChar((r)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GUI_Circle>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0x52,%edi
  call   <SendChar@plt>
  mov    %r12d,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void GUI_Circle(unsigned short int x, unsigned short int y, unsigned short int r) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x52) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((y) >> 8) & 0xFF);
  SendChar((y)&0xFF);
  SendChar(((r) >> 8) & 0xFF);
  SendChar((r)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GUI_Circle>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0xee,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <SendChar@plt>
  mov    $0x52,%edi
  call   <SendChar@plt>
  mov    %r12d,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  mov    $0xff,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <SendChar@plt>
```

assistant: ```c
void GUI_Circle(unsigned short int x, unsigned short int y, unsigned short int r) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x52) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((y) >> 8) & 0xFF);
  SendChar((y)&0xFF);
  SendChar(((r) >> 8) & 0xFF);
  SendChar((r)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GUI_Circle>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0xee,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  call   <SendChar@plt>
  mov    $0x52,%edi
  call   <SendChar@plt>
  mov    %r12d,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  mov    $0xff,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <SendChar@plt>
```

assistant: ```c
void GUI_Circle(unsigned short int x, unsigned short int y, unsigned short int r) {
  SendChar((0XEE) & 0xFF);
  SendChar((0x52) & 0xFF);
  SendChar(((x) >> 8) & 0xFF);
  SendChar((x)&0xFF);
  SendChar(((y) >> 8) & 0xFF);
  SendChar((y)&0xFF);
  SendChar(((r) >> 8) & 0xFF);
  SendChar((r)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sstrcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L16
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L1
L16:
  mov    $0x0,%eax
L1:
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  cmpq   $0x0,-0x18(%rbp)
  jne    L39
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L39:
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *sstrcat(char **dst, const char *src) {
  size_t dlen = (*dst == NULL) ? 0 : strlen(*dst);
  size_t slen = strlen(src);
  char *tmp = realloc(*dst, dlen + slen + 1);
  if (tmp != NULL) {
    if (dlen == 0) {
      *tmp = '\0';
    }
    *dst = tmp;
    strncat(*dst, src, slen);
  }
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sstrcat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    (%rdi),%rbx
  test   %rbx,%rbx
  je     L19
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x1(%r14,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
  test   %r14,%r14
  jne    L43
  jmp    L2
L19:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x1(%rax),%rsi
  mov    $0x0,%edi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L26
L2:
  movb   $0x0,(%rbx)
L43:
  mov    %rbx,(%r12)
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
L26:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *sstrcat(char **dst, const char *src) {
  size_t dlen = (*dst == NULL) ? 0 : strlen(*dst);
  size_t slen = strlen(src);
  char *tmp = realloc(*dst, dlen + slen + 1);
  if (tmp != NULL) {
    if (dlen == 0) {
      *tmp = '\0';
    }
    *dst = tmp;
    strncat(*dst, src, slen);
  }
  return tmp;
}
```