ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<adler32_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x4,-0xc(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  sub    $0x4,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L3
  jmp    L17
L21:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int adler32_checksum(char *buf, int len) {
  int i;
  unsigned int s1, s2;
  s1 = s2 = 0;
  for (i = 0; i < (len - 4); i += 4) {
    s2 += 4 * (s1 + buf[i]) + 3 * buf[i + 1] + 2 * buf[i + 2] + buf[i + 3] + 10 * 0;
    s1 += (buf[i + 0] + buf[i + 1] + buf[i + 2] + buf[i + 3] + 4 * 0);
  }
  for (; i < len; i++) {
    s1 += (buf[i] + 0);
    s2 += s1;
  }
  return (s1 & 0xffff) + (s2 << 16);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adler32_checksum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r10d
  cmp    $0x4,%esi
  jle    L24
  mov    %rdi,%rcx
  lea    -0x5(%rsi),%ebp
  shr    $0x2,%ebp
  mov    %ebp,%eax
  lea    0x4(%rdi,%rax,4),%r11
  mov    $0x0,%r8d
  mov    $0x0,%eax
L26:
  movsbl 0x1(%rcx),%esi
  movsbl 0x2(%rcx),%r12d
  movsbl (%rcx),%edx
  lea    (%rdx,%rax,1),%r9d
  lea    (%rsi,%rsi,2),%edi
  lea    (%rdi,%r9,4),%edi
  movsbl 0x3(%rcx),%r9d
  add    %r9d,%edi
  lea    (%rdi,%r12,2),%edi
  add    %edi,%r8d
  add    %esi,%edx
  add    %r12d,%edx
  add    %r9d,%edx
  add    %edx,%eax
  add    $0x4,%rcx
  cmp    %r11,%rcx
  jne    L26
  lea    0x4(,%rbp,4),%edx
L38:
  cmp    %edx,%r10d
  jle    L45
  movslq %edx,%rdx
L5:
  movsbl (%rbx,%rdx,1),%ecx
  add    %ecx,%eax
  add    %eax,%r8d
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jg     L5
L45:
  movzwl %ax,%eax
  shl    $0x10,%r8d
  add    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  mov    $0x0,%r8d
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L38
```

assistant: ```c
unsigned int adler32_checksum(char *buf, int len) {
  int i;
  unsigned int s1, s2;
  s1 = s2 = 0;
  for (i = 0; i < (len - 4); i += 4) {
    s2 += 4 * (s1 + buf[i]) + 3 * buf[i + 1] + 2 * buf[i + 2] + buf[i + 3] + 10 * 0;
    s1 += (buf[i + 0] + buf[i + 1] + buf[i + 2] + buf[i + 3] + 4 * 0);
  }
  for (; i < len; i++) {
    s1 += (buf[i] + 0);
    s2 += s1;
  }
  return (s1 & 0xffff) + (s2 << 16);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<adler32_checksum>:
  endbr64
  push   %r12
  mov    %esi,%r10d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x4,%esi
  jle    L43
  lea    -0x5(%rsi),%ebp
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  shr    $0x2,%ebp
  mov    %ebp,%eax
  lea    0x4(%rdi,%rax,4),%r11
  xor    %eax,%eax
  nopl   0x0(%rax)
L42:
  movsbl 0x1(%rcx),%esi
  movsbl (%rcx),%edx
  add    $0x4,%rcx
  movsbl -0x2(%rcx),%r12d
  lea    (%rdx,%rax,1),%r9d
  lea    (%rsi,%rsi,2),%edi
  add    %esi,%edx
  lea    (%rdi,%r9,4),%edi
  movsbl -0x1(%rcx),%r9d
  add    %r12d,%edx
  add    %r9d,%edi
  add    %r9d,%edx
  lea    (%rdi,%r12,2),%edi
  add    %edx,%eax
  add    %edi,%r8d
  cmp    %rcx,%r11
  jne    L42
  lea    0x4(,%rbp,4),%edx
L1:
  cmp    %edx,%r10d
  jle    L22
  movslq %edx,%rdx
L10:
  movsbl (%rbx,%rdx,1),%ecx
  add    $0x1,%rdx
  add    %ecx,%eax
  add    %eax,%r8d
  cmp    %edx,%r10d
  jg     L10
L22:
  movzwl %ax,%eax
  shl    $0x10,%r8d
  pop    %rbx
  pop    %rbp
  add    %r8d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L43:
  xor    %r8d,%r8d
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L1
```

assistant: ```c
unsigned int adler32_checksum(char *buf, int len) {
  int i;
  unsigned int s1, s2;
  s1 = s2 = 0;
  for (i = 0; i < (len - 4); i += 4) {
    s2 += 4 * (s1 + buf[i]) + 3 * buf[i + 1] + 2 * buf[i + 2] + buf[i + 3] + 10 * 0;
    s1 += (buf[i + 0] + buf[i + 1] + buf[i + 2] + buf[i + 3] + 4 * 0);
  }
  for (; i < len; i++) {
    s1 += (buf[i] + 0);
    s2 += s1;
  }
  return (s1 & 0xffff) + (s2 << 16);
}
```
user: What is the c source code of the assembly code below:

```asm
<adler32_checksum>:
  endbr64
  push   %r12
  mov    %esi,%r11d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0x4,%esi
  jle    L67
  lea    -0x5(%rsi),%ebp
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  shr    $0x2,%ebp
  mov    %ebp,%eax
  lea    0x4(%rdi,%rax,4),%r10
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movsbl 0x1(%rcx),%esi
  movsbl (%rcx),%edx
  add    $0x4,%rcx
  movsbl -0x2(%rcx),%r12d
  lea    (%rdx,%rax,1),%r9d
  lea    (%rsi,%rsi,2),%edi
  add    %esi,%edx
  lea    (%rdi,%r9,4),%edi
  movsbl -0x1(%rcx),%r9d
  add    %r12d,%edx
  add    %r9d,%edi
  add    %r9d,%edx
  lea    (%rdi,%r12,2),%edi
  add    %edx,%eax
  add    %edi,%r8d
  cmp    %rcx,%r10
  jne    L22
  lea    0x4(,%rbp,4),%edx
L29:
  cmp    %edx,%r11d
  jle    L53
  movslq %edx,%rcx
  movsbl (%rbx,%rcx,1),%ecx
  add    %ecx,%eax
  lea    0x1(%rdx),%ecx
  add    %eax,%r8d
  cmp    %ecx,%r11d
  jle    L53
  movslq %ecx,%rcx
  movsbl (%rbx,%rcx,1),%ecx
  add    %ecx,%eax
  lea    0x2(%rdx),%ecx
  add    %eax,%r8d
  cmp    %ecx,%r11d
  jle    L53
  movslq %ecx,%rcx
  movsbl (%rbx,%rcx,1),%ecx
  add    %ecx,%eax
  lea    0x3(%rdx),%ecx
  add    %eax,%r8d
  cmp    %ecx,%r11d
  jle    L53
  movslq %ecx,%rcx
  add    $0x4,%edx
  movsbl (%rbx,%rcx,1),%ecx
  add    %ecx,%eax
  add    %eax,%r8d
  cmp    %edx,%r11d
  jle    L53
  movslq %edx,%rdx
  movsbl (%rbx,%rdx,1),%edx
  add    %edx,%eax
  add    %eax,%r8d
L53:
  movzwl %ax,%eax
  shl    $0x10,%r8d
  pop    %rbx
  pop    %rbp
  add    %r8d,%eax
  pop    %r12
  ret
L67:
  xor    %r8d,%r8d
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L29
```

assistant: ```c
unsigned int adler32_checksum(char *buf, int len) {
  int i;
  unsigned int s1, s2;
  s1 = s2 = 0;
  for (i = 0; i < (len - 4); i += 4) {
    s2 += 4 * (s1 + buf[i]) + 3 * buf[i + 1] + 2 * buf[i + 2] + buf[i + 3] + 10 * 0;
    s1 += (buf[i + 0] + buf[i + 1] + buf[i + 2] + buf[i + 3] + 4 * 0);
  }
  for (; i < len; i++) {
    s1 += (buf[i] + 0);
    s2 += s1;
  }
  return (s1 & 0xffff) + (s2 << 16);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBOTGSessionRequest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  movzbl (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x60,%rdx
  or     $0x1,%eax
  mov    %al,(%rdx)
  jmp    L6
L19:
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  movzbl (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x60,%rdx
  and    $0xfffffffe,%eax
  mov    %al,(%rdx)
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBOTGSessionRequest(uint32_t ui32Base, bool bStart) {
  ;
  if (bStart) {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) |= 0x00000001;
  } else {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) &= ~0x00000001;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<USBOTGSessionRequest>:
  endbr64
  test   %esi,%esi
  je     L6
  movzbl 0x60(%rdi),%eax
  or     $0x1,%eax
  mov    %al,0x60(%rdi)
  ret
L6:
  movzbl 0x60(%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %al,0x60(%rdi)
  ret
```

assistant: ```c
void USBOTGSessionRequest(uint32_t ui32Base, bool bStart) {
  ;
  if (bStart) {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) |= 0x00000001;
  } else {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) &= ~0x00000001;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<USBOTGSessionRequest>:
  endbr64
  movzbl 0x60(%rdi),%eax
  test   %esi,%esi
  je     L6
  or     $0x1,%eax
  mov    %al,0x60(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  and    $0xfffffffe,%eax
  mov    %al,0x60(%rdi)
  ret
```

assistant: ```c
void USBOTGSessionRequest(uint32_t ui32Base, bool bStart) {
  ;
  if (bStart) {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) |= 0x00000001;
  } else {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) &= ~0x00000001;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<USBOTGSessionRequest>:
  endbr64
  movzbl 0x60(%rdi),%eax
  test   %esi,%esi
  je     L7
  or     $0x1,%eax
  mov    %al,0x60(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  and    $0xfffffffe,%eax
  mov    %al,0x60(%rdi)
  ret
```

assistant: ```c
void USBOTGSessionRequest(uint32_t ui32Base, bool bStart) {
  ;
  if (bStart) {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) |= 0x00000001;
  } else {
    (*((volatile unsigned char *)(ui32Base + 0x00000060))) &= ~0x00000001;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(501, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(501, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x38,%rsp
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x1f5,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(501, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x38,%rsp
  unpcklpd %xmm1,%xmm0
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  mov    $0x1f5,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma, double regamma, double imgamma) {
  int fail, *b;
  double c[2];
  c[0] = regamma;
  c[1] = imgamma;
  fail = _ada_use_c2phc4c(501, &fixed_gamma, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetDate_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x10(%rbp),%eax
  imul   $0xf4240,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
unsigned long GetDate_us(void) {
  static unsigned long InitDate = 0;
  struct timespec t1;
  clock_gettime(CLOCK_MONOTONIC, &t1);
  return (t1.tv_sec * 1000000 + t1.tv_nsec / 1000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetDate_us>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  imul   $0xf4240,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetDate_us(void) {
  static unsigned long InitDate = 0;
  struct timespec t1;
  clock_gettime(CLOCK_MONOTONIC, &t1);
  return (t1.tv_sec * 1000000 + t1.tv_nsec / 1000);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetDate_us>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0xf4240,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  cltq
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetDate_us(void) {
  static unsigned long InitDate = 0;
  struct timespec t1;
  clock_gettime(CLOCK_MONOTONIC, &t1);
  return (t1.tv_sec * 1000000 + t1.tv_nsec / 1000);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetDate_us>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0xf4240,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  cltq
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetDate_us(void) {
  static unsigned long InitDate = 0;
  struct timespec t1;
  clock_gettime(CLOCK_MONOTONIC, &t1);
  return (t1.tv_sec * 1000000 + t1.tv_nsec / 1000);
}
```
user: What is the c source code of the assembly code below?

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <lastNode@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_quickSort@plt>
  nop
  leave
  ret
```

assistant: ```c
void quickSort(struct Node *head) {
  struct Node *h = lastNode(head);
  _quickSort(head, h);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quickSort>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <lastNode@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <_quickSort@plt>
  pop    %rbx
  ret
```

assistant: ```c
void quickSort(struct Node *head) {
  struct Node *h = lastNode(head);
  _quickSort(head, h);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <lastNode@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <_quickSort@plt>
```

assistant: ```c
void quickSort(struct Node *head) {
  struct Node *h = lastNode(head);
  _quickSort(head, h);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <lastNode@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1060 <_quickSort@plt>
```

assistant: ```c
void quickSort(struct Node *head) {
  struct Node *h = lastNode(head);
  _quickSort(head, h);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fmt1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x60(%rbp)
  mov    %rcx,-0x68(%rbp)
  mov    %al,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsbl -0x58(%rbp),%ecx
  mov    -0x54(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  lea    D1(%rip),%rdx
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  test   %eax,%eax
  js     L27
  mov    -0x48(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x68(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jbe    L24
L27:
  mov    $0xffffffff,%eax
  jmp    L25
L24:
  mov    -0x60(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x60(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%rax
  sub    -0x48(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x68(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: %d%c

assistant: ```c
int fmt1(int t, char s, char **buf, size_t *buflen) {
  char tmp[50];
  size_t len;
  len = (size_t)snprintf(tmp, sizeof(tmp), "%d%c", t, s);
  if ((int)len < 0 || len + 1 > *buflen)
    return (-1);
  strcpy(*buf, tmp);
  *buf += len;
  *buflen -= len;
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fmt1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  movsbl %sil,%r8d
  mov    %edi,%ecx
  lea    D9(%rip),%rdx
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L12
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    0x0(%rbp),%rax
  ja     L15
  mov    %rsp,%rsi
  mov    (%r12),%rdi
  call   <strcpy@plt>
  add    %rbx,(%r12)
  sub    %rbx,0x0(%rbp)
  mov    $0x0,%eax
L45:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L45
L15:
  mov    $0xffffffff,%eax
  jmp    L45
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d%c

assistant: ```c
int fmt1(int t, char s, char **buf, size_t *buflen) {
  char tmp[50];
  size_t len;
  len = (size_t)snprintf(tmp, sizeof(tmp), "%d%c", t, s);
  if ((int)len < 0 || len + 1 > *buflen)
    return (-1);
  strcpy(*buf, tmp);
  *buf += len;
  *buflen -= len;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmt1>:
  endbr64
  push   %r13
  movsbl %sil,%r8d
  mov    $0x32,%esi
  push   %r12
  mov    %rdx,%r12
  lea    D4(%rip),%rdx
  push   %rbp
  mov    %rcx,%rbp
  mov    %edi,%ecx
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L32
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    0x0(%rbp),%rax
  ja     L32
  mov    (%r12),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  add    %rbx,(%r12)
  xor    %eax,%eax
  sub    %rbx,0x0(%rbp)
L33:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xffffffff,%eax
  jmp    L33
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: %d%c

assistant: ```c
int fmt1(int t, char s, char **buf, size_t *buflen) {
  char tmp[50];
  size_t len;
  len = (size_t)snprintf(tmp, sizeof(tmp), "%d%c", t, s);
  if ((int)len < 0 || len + 1 > *buflen)
    return (-1);
  strcpy(*buf, tmp);
  *buf += len;
  *buflen -= len;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmt1>:
  endbr64
  push   %r13
  movsbl %sil,%r8d
  mov    $0x32,%esi
  push   %r12
  mov    %rdx,%r12
  lea    D1(%rip),%rdx
  push   %rbp
  mov    %rcx,%rbp
  mov    %edi,%ecx
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  test   %eax,%eax
  js     L29
  mov    %rax,%rbx
  lea    0x1(%rax),%rax
  cmp    0x0(%rbp),%rax
  ja     L29
  mov    (%r12),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  add    %rbx,(%r12)
  xor    %eax,%eax
  sub    %rbx,0x0(%rbp)
L16:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0xffffffff,%eax
  jmp    L16
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: %d%c

assistant: ```c
int fmt1(int t, char s, char **buf, size_t *buflen) {
  char tmp[50];
  size_t len;
  len = (size_t)snprintf(tmp, sizeof(tmp), "%d%c", t, s);
  if ((int)len < 0 || len + 1 > *buflen)
    return (-1);
  strcpy(*buf, tmp);
  *buf += len;
  *buflen -= len;
  return (0);
}
```