ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  cmpq   $0x0,0x10(%rsp)
  jle    L7
  mov    $0x1,%r12d
  xor    %ebp,%ebp
  mov    $0x1,%ebx
  mov    $0xffffffffffffffff,%r13
  lea    0x8(%rsp),%r15
  jmp    L74
  nopl   (%rax)
L9:
  lea    0x1(%r12),%rax
  cmp    $0x1,%r12
  je     L17
  sub    %r12,%rbp
  mov    %rax,%r12
L4:
  mov    $0x1,%esi
  call   <add@plt>
  mov    0x8(%rsp),%rdi
  call   <sum@plt>
  mov    0x8(%rsp),%r13
  mov    %rax,%r8
  mov    %rbx,%rax
  add    $0x1,%rbx
  sub    %r8,%rax
  add    %rax,%rbp
  cmp    %rbx,0x10(%rsp)
  jl     L10
L74:
  mov    %r14,%rdi
  mov    %r15,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  cmp    %r13,%rdi
  jl     L9
  mov    $0x1,%r12d
  jmp    L4
  xchg   %ax,%ax
L17:
  mov    $0x2,%r12d
  jmp    L4
L7:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %lli

assistant: ```c
int main(int argc, const char *argv[]) {
  long long i, j, n, last = -1, ret = 0, continuing = 1;
  scanf("%lli", &n);
  for (i = 1; i <= n; ++i) {
    scanf("%lli", &j);
    if (j < last) {
      ++continuing;
      if (continuing > 2)
        ret -= continuing - 1;
    } else
      continuing = 1;
    add(j, 1);
    ret += i - sum(j);
    last = j;
  }
  printf("%lli", ret);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<add_dmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8,-0x68(%rbp)
  mov    %r9,-0x70(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  jmp    L20
L14:
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L38
L9:
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x38(%rbp)
L38:
  mov    -0x38(%rbp),%rax
  cmp    -0x68(%rbp),%rax
  jle    L9
  addq   $0x1,-0x40(%rbp)
L20:
  mov    -0x40(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jle    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_dmatrix(double **m1, long nrl, long nrh, long ncl, long nch, double **m2, double **m3) {
  long i, j;
  double x, y, z, *Xi, *Yi, *Zi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    Zi = m3[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = Yi[j];
      z = x + y;
      Zi[j] = z;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<add_dmatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L6
  mov    %rdi,%rbx
  mov    %rsi,%r10
  mov    %rcx,%r11
  mov    %r8,%rbp
  lea    0x1(%rdx),%r8
  lea    0x1(%rbp),%rdi
L17:
  mov    (%rbx,%r10,8),%rdx
  mov    (%r9,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %rbp,%r11
  jg     L15
  mov    %r11,%rax
L32:
  movsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L32
L15:
  add    $0x1,%r10
  cmp    %r8,%r10
  jne    L17
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void add_dmatrix(double **m1, long nrl, long nrh, long ncl, long nch, double **m2, double **m3) {
  long i, j;
  double x, y, z, *Xi, *Yi, *Zi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    Zi = m3[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = Yi[j];
      z = x + y;
      Zi[j] = z;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_dmatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x20(%rsp),%r12
  cmp    %rdx,%rsi
  jg     L14
  mov    %r8,%rbp
  mov    %rdi,%rbx
  mov    %rsi,%r10
  mov    %rcx,%r11
  lea    0x1(%rdx),%r8
  lea    0x1(%rbp),%rdi
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    (%rbx,%r10,8),%rdx
  mov    (%r9,%r10,8),%rcx
  mov    (%r12,%r10,8),%rsi
  cmp    %rbp,%r11
  jg     L12
  mov    %r11,%rax
  nopl   0x0(%rax)
L20:
  movsd  (%rdx,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L20
L12:
  add    $0x1,%r10
  cmp    %r8,%r10
  jne    L10
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void add_dmatrix(double **m1, long nrl, long nrh, long ncl, long nch, double **m2, double **m3) {
  long i, j;
  double x, y, z, *Xi, *Yi, *Zi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    Zi = m3[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = Yi[j];
      z = x + y;
      Zi[j] = z;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<add_dmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x10(%rsp)
  cmp    %rdx,%rsi
  jg     L14
  mov    %rcx,%rax
  cmp    %r8,%rcx
  jg     L14
  mov    %r8,%rcx
  mov    %rdi,%rbx
  mov    %rsi,%r11
  mov    %r9,%r15
  sub    %rax,%rcx
  lea    0x1(%rdx),%rsi
  lea    0x0(,%rax,8),%r12
  lea    0x1(%rcx),%rdi
  mov    %rsi,-0x30(%rsp)
  lea    0x8(%r12),%r14
  mov    %rdi,%rbp
  mov    %rdi,-0x20(%rsp)
  and    $0xfffffffffffffffe,%rdi
  lea    0x1(%r8),%r13
  add    %rdi,%rax
  mov    %rcx,-0x28(%rsp)
  shr    %rbp
  mov    %rdi,-0x18(%rsp)
  mov    %rax,%rdx
  shl    $0x4,%rbp
  shl    $0x3,%rdx
  nopl   0x0(%rax)
L0:
  mov    0x38(%rsp),%rax
  mov    (%r15,%r11,8),%rsi
  mov    (%rbx,%r11,8),%rcx
  mov    (%rax,%r11,8),%rdi
  lea    (%rsi,%r14,1),%rax
  lea    (%rdi,%r12,1),%r8
  cmp    %rax,%r8
  lea    (%rcx,%r14,1),%rax
  setne  %r9b
  cmp    %rax,%r8
  setne  %al
  test   %al,%r9b
  je     L83
  cmpq   $0x1,-0x28(%rsp)
  jbe    L83
  lea    (%rcx,%r12,1),%r10
  lea    (%rsi,%r12,1),%r9
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  movupd (%r10,%rax,1),%xmm0
  movupd (%r9,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rbp,%rax
  jne    L1
  mov    -0x18(%rsp),%r10
  cmp    %r10,-0x20(%rsp)
  je     L3
  movsd  (%rcx,%rdx,1),%xmm0
  addsd  (%rsi,%rdx,1),%xmm0
  movsd  %xmm0,(%rdi,%rdx,1)
L3:
  add    $0x1,%r11
  cmp    -0x30(%rsp),%r11
  jne    L0
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  mov    -0x10(%rsp),%rax
  nopl   (%rax)
L2:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L2
  jmp    L3
```

assistant: ```c
void add_dmatrix(double **m1, long nrl, long nrh, long ncl, long nch, double **m2, double **m3) {
  long i, j;
  double x, y, z, *Xi, *Yi, *Zi;
  for (i = nrl; i <= nrh; i++) {
    Xi = m1[i];
    Yi = m2[i];
    Zi = m3[i];
    for (j = ncl; j <= nch; j++) {
      x = Xi[j];
      y = Yi[j];
      z = x + y;
      Zi[j] = z;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pcibx_cmd_clearbitstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <prsendinfo@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x77,%esi
  mov    %rax,%rdi
  call   <pcibx_write@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: Clear 32/64 bit status

assistant: ```c
void pcibx_cmd_clearbitstat(struct pcibx_device *dev) {
  prsendinfo("Clear 32/64 bit status");
  pcibx_write(dev, 0x77, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pcibx_cmd_clearbitstat>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <prsendinfo@plt>
  mov    $0x0,%edx
  mov    $0x77,%esi
  mov    %rbx,%rdi
  call   <pcibx_write@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: Clear 32/64 bit status

assistant: ```c
void pcibx_cmd_clearbitstat(struct pcibx_device *dev) {
  prsendinfo("Clear 32/64 bit status");
  pcibx_write(dev, 0x77, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pcibx_cmd_clearbitstat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <prsendinfo@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x77,%esi
  pop    %rbp
  jmp    1060 <pcibx_write@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: Clear 32/64 bit status

assistant: ```c
void pcibx_cmd_clearbitstat(struct pcibx_device *dev) {
  prsendinfo("Clear 32/64 bit status");
  pcibx_write(dev, 0x77, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pcibx_cmd_clearbitstat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <prsendinfo@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  mov    $0x77,%esi
  pop    %rbp
  jmp    1060 <pcibx_write@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: Clear 32/64 bit status

assistant: ```c
void pcibx_cmd_clearbitstat(struct pcibx_device *dev) {
  prsendinfo("Clear 32/64 bit status");
  pcibx_write(dev, 0x77, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imprimir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4:  Vetor[%i]=%i 


assistant: ```c
void imprimir(int *vet, int tam) {
  int i;
  for (i = 0; i < tam; i++) {
    printf(" Vetor[%i]=%i \n", i, vet[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imprimir>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L18:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7:  Vetor[%i]=%i 


assistant: ```c
void imprimir(int *vet, int tam) {
  int i;
  for (i = 0; i < tam; i++) {
    printf(" Vetor[%i]=%i \n", i, vet[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imprimir>:
  endbr64
  test   %esi,%esi
  jle    L6
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1:  Vetor[%i]=%i 


assistant: ```c
void imprimir(int *vet, int tam) {
  int i;
  for (i = 0; i < tam; i++) {
    printf(" Vetor[%i]=%i \n", i, vet[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<imprimir>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6:  Vetor[%i]=%i 


assistant: ```c
void imprimir(int *vet, int tam) {
  int i;
  for (i = 0; i < tam; i++) {
    printf(" Vetor[%i]=%i \n", i, vet[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cvs_check_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L29
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6f,%al
  jne    L19
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6b,%al
  jne    L19
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L19
  mov    $0x1,%eax
  jmp    L0
L19:
  mov    $0x0,%eax
  jmp    L0
L29:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int cvs_check_ok(char *c, int n) {
  if (n > 0) {
    return (c[n - 3] == 'o' && c[n - 2] == 'k' && c[n - 1] == '\012');
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvs_check_ok>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L34
  movslq %esi,%rsi
  cmpb   $0x6f,-0x3(%rdi,%rsi,1)
  je     L38
L34:
  ret
L38:
  cmpb   $0x6b,-0x2(%rdi,%rsi,1)
  jne    L34
  cmpb   $0xa,-0x1(%rdi,%rsi,1)
  sete   %al
  movzbl %al,%eax
  jmp    L34
```

assistant: ```c
int cvs_check_ok(char *c, int n) {
  if (n > 0) {
    return (c[n - 3] == 'o' && c[n - 2] == 'k' && c[n - 1] == '\012');
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cvs_check_ok>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L2
  movslq %esi,%rsi
  cmpb   $0x6f,-0x3(%rdi,%rsi,1)
  je     L24
L2:
  ret
  nopl   (%rax)
L24:
  cmpb   $0x6b,-0x2(%rdi,%rsi,1)
  jne    L2
  xor    %eax,%eax
  cmpb   $0xa,-0x1(%rdi,%rsi,1)
  sete   %al
  ret
```

assistant: ```c
int cvs_check_ok(char *c, int n) {
  if (n > 0) {
    return (c[n - 3] == 'o' && c[n - 2] == 'k' && c[n - 1] == '\012');
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<cvs_check_ok>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jle    L24
  movslq %esi,%rsi
  cmpb   $0x6f,-0x3(%rdi,%rsi,1)
  je     L26
L24:
  ret
  nopl   (%rax)
L26:
  cmpb   $0x6b,-0x2(%rdi,%rsi,1)
  jne    L24
  xor    %eax,%eax
  cmpb   $0xa,-0x1(%rdi,%rsi,1)
  sete   %al
  ret
```

assistant: ```c
int cvs_check_ok(char *c, int n) {
  if (n > 0) {
    return (c[n - 3] == 'o' && c[n - 2] == 'k' && c[n - 1] == '\012');
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x24(%rbp)
  jmp    L8
L17:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0x24(%rbp)
L8:
  cmpl   $0x3f,-0x24(%rbp)
  jle    L17
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  lea    -0x20(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <creat@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: /tmp/file.%d


assistant: ```c
int main(int argc, char **argv) {
  char filename[24];
  {
    int i;
    for (i = 3; i < 64; i++)
      close(i);
  };
  sprintf(filename, "/tmp/file.%d\n", getpid());
  creat(filename, 0);
  unlink(filename);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3,%ebx
L7:
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  jne    L7
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%edx
  mov    %rsp,%rbx
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <creat@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string

tool: D5: /tmp/file.%d


assistant: ```c
int main(int argc, char **argv) {
  char filename[24];
  {
    int i;
    for (i = 3; i < 64; i++)
      close(i);
  };
  sprintf(filename, "/tmp/file.%d\n", getpid());
  creat(filename, 0);
  unlink(filename);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  nop
L7:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    $0x40,%ebx
  jne    L7
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <creat@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: /tmp/file.%d


assistant: ```c
int main(int argc, char **argv) {
  char filename[24];
  {
    int i;
    for (i = 3; i < 64; i++)
      close(i);
  };
  sprintf(filename, "/tmp/file.%d\n", getpid());
  creat(filename, 0);
  unlink(filename);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x3,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  nop
L5:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <close@plt>
  cmp    $0x40,%ebx
  jne    L5
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <creat@plt>
  mov    %rbp,%rdi
  call   <unlink@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: /tmp/file.%d


assistant: ```c
int main(int argc, char **argv) {
  char filename[24];
  {
    int i;
    for (i = 3; i < 64; i++)
      close(i);
  };
  sprintf(filename, "/tmp/file.%d\n", getpid());
  creat(filename, 0);
  unlink(filename);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<__printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xb8(%rbp)
  mov    %rdx,-0xb0(%rbp)
  mov    %rcx,-0xa8(%rbp)
  mov    %r8,-0xa0(%rbp)
  mov    %r9,-0x98(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x90(%rbp)
  movaps %xmm1,-0x80(%rbp)
  movaps %xmm2,-0x70(%rbp)
  movaps %xmm3,-0x60(%rbp)
  movaps %xmm4,-0x50(%rbp)
  movaps %xmm5,-0x40(%rbp)
  movaps %xmm6,-0x30(%rbp)
  movaps %xmm7,-0x20(%rbp)
L2:
  mov    -0xd8(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_lock_file@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xc4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    %eax,%ebx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_unlock_file@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __printf(const char *fmt, ...) {
  register int retval;
  va_list argv;
  va_start(argv, fmt);
  _lock_file(stdout);
  retval = __pformat(0x2000 | 0x4000, stdout, 0, fmt, argv);
  _unlock_file(stdout);
  va_end(argv);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D1(%rip),%r12
  mov    (%r12),%edi
  call   <_lock_file@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    $0x0,%edx
  mov    (%r12),%esi
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    %eax,%ebx
  mov    (%r12),%edi
  call   <_unlock_file@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __printf(const char *fmt, ...) {
  register int retval;
  va_list argv;
  va_start(argv, fmt);
  _lock_file(stdout);
  retval = __pformat(0x2000 | 0x4000, stdout, 0, fmt, argv);
  _unlock_file(stdout);
  va_end(argv);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__printf>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rbx
  mov    (%rbx),%edi
  call   <_lock_file@plt>
  mov    (%rbx),%esi
  mov    %ebp,%r8d
  mov    %r12,%rcx
  xor    %edx,%edx
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    (%rbx),%edi
  mov    %eax,%r12d
  call   <_unlock_file@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __printf(const char *fmt, ...) {
  register int retval;
  va_list argv;
  va_start(argv, fmt);
  _lock_file(stdout);
  retval = __pformat(0x2000 | 0x4000, stdout, 0, fmt, argv);
  _unlock_file(stdout);
  va_end(argv);
  return retval;
}
```