ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<__str_reverse__>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L16
  movslq %esi,%rsi
  xor    %eax,%eax
L19:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L19
L16:
  ret
```

assistant: ```c
void __str_reverse__(char str[], ssize_t len) {
  for (int i = 0, j = len - 1; i < j; ++i, --j) {
    char tmp = str[i];
    str[i] = str[j];
    str[j] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__str_reverse__>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  xor    %eax,%eax
L9:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L9
L6:
  ret
```

assistant: ```c
void __str_reverse__(char str[], ssize_t len) {
  for (int i = 0, j = len - 1; i < j; ++i, --j) {
    char tmp = str[i];
    str[i] = str[j];
    str[j] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<distance_l2_m128d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L24
L39:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    (%rdx),%rsi
  mov    (%rax),%rdi
  call   <_mm_sub_pd@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_mul_pd@plt>
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_mm_add_pd@plt>
  mov    %rax,-0x30(%rbp)
  addl   $0x1,-0x3c(%rbp)
L24:
  mov    -0x54(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x3c(%rbp)
  jl     L39
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_store_pd@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  shll   -0x3c(%rbp)
  jmp    L2
L8:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  addl   $0x1,-0x3c(%rbp)
L2:
  mov    -0x3c(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L8
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  double fsum[2];
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  _mm_store_pd(fsum, sum);
  ret = fsum[0] + fsum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %edx,%r13d
  shr    $0x1f,%r13d
  add    %edx,%r13d
  sar    %r13d
  cmp    $0x1,%edx
  jle    L50
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L47:
  mov    0x0(%rbp),%rsi
  mov    (%r12),%rdi
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %eax,%esi
  mov    (%rsp),%rdi
  call   <_mm_add_pd@plt>
  mov    %rax,(%rsp)
  add    $0x1,%ebx
  add    $0x8,%r12
  add    $0x8,%rbp
  cmp    %r13d,%ebx
  jl     L47
  test   %r13d,%r13d
  mov    $0x1,%eax
  cmovle %eax,%r13d
L8:
  lea    0x10(%rsp),%rdi
  mov    (%rsp),%rsi
  call   <_mm_store_pd@plt>
  movsd  0x10(%rsp),%xmm0
  addsd  0x18(%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    %r13d,%r13d
  mov    0xc(%rsp),%eax
  cmp    %r13d,%eax
  jle    L28
  movslq %r13d,%rbx
  sub    $0x1,%eax
  sub    %r13d,%eax
  lea    0x1(%rbx,%rax,1),%rbp
L65:
  movsd  (%r14,%rbx,8),%xmm0
  subsd  (%r15,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L65
L28:
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm2
  ucomisd %xmm2,%xmm0
  ja     L9
  sqrtsd %xmm2,%xmm2
  movapd %xmm2,%xmm0
L39:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  mov    $0x0,%r13d
  jmp    L8
L9:
  movsd  (%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L39
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  double fsum[2];
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  _mm_store_pd(fsum, sum);
  ret = fsum[0] + fsum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x38,%rsp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %ebp,(%rsp)
  cmp    $0x1,%edx
  jle    L48
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r15d,%r15d
  nopl   (%rax)
L32:
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  add    $0x1,%r15d
  add    $0x8,%rbp
  add    $0x8,%rbx
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <_mm_add_pd@plt>
  mov    %rax,%r14
  cmp    (%rsp),%r15d
  jl     L32
  mov    (%rsp),%edx
  mov    $0x1,%eax
  test   %edx,%edx
  cmovle %eax,%edx
  mov    %edx,%ebp
  add    %ebp,%ebp
L2:
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  call   <_mm_store_pd@plt>
  mov    0xc(%rsp),%ecx
  movsd  0x10(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm1
  cmp    %ebp,%ecx
  jle    L8
  sub    $0x1,%ecx
  movslq %ebp,%rax
  mov    %ecx,%ebx
  sub    %ebp,%ebx
  lea    0x1(%rax),%rbp
  add    %rbp,%rbx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rbp
L24:
  movsd  (%r12,%rax,8),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,(%rsp)
  subsd  0x0(%r13,%rax,8),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  mov    %rbp,%rax
  addsd  %xmm0,%xmm1
  cmp    %rbp,%rbx
  jne    L28
L8:
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L72
  sqrtsd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  xor    %ebp,%ebp
  jmp    L2
L72:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1110 <sqrt@plt>
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  double fsum[2];
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  _mm_store_pd(fsum, sum);
  ret = fsum[0] + fsum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x38,%rsp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %ebp,(%rsp)
  cmp    $0x1,%edx
  jle    L58
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r15d,%r15d
  nopl   (%rax)
L45:
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  add    $0x1,%r15d
  add    $0x8,%rbp
  add    $0x8,%rbx
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <_mm_add_pd@plt>
  mov    %rax,%r14
  cmp    (%rsp),%r15d
  jl     L45
  mov    (%rsp),%edx
  mov    $0x1,%eax
  test   %edx,%edx
  cmovle %eax,%edx
  mov    %edx,%ebp
  add    %ebp,%ebp
L59:
  lea    0x10(%rsp),%rdi
  mov    %r14,%rsi
  call   <_mm_store_pd@plt>
  mov    0xc(%rsp),%ecx
  movsd  0x10(%rsp),%xmm1
  addsd  0x18(%rsp),%xmm1
  cmp    %ebp,%ecx
  jle    L2
  sub    $0x1,%ecx
  movslq %ebp,%rax
  mov    %ecx,%ebx
  sub    %ebp,%ebx
  lea    0x1(%rax),%rbp
  add    %rbp,%rbx
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbp
L39:
  movsd  (%r12,%rax,8),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,(%rsp)
  subsd  0x0(%r13,%rax,8),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  mov    %rbp,%rax
  addsd  %xmm0,%xmm1
  cmp    %rbp,%rbx
  jne    L1
L2:
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L44
  sqrtsd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  xor    %ebp,%ebp
  jmp    L59
L44:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x38,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1110 <sqrt@plt>
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  double fsum[2];
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  _mm_store_pd(fsum, sum);
  ret = fsum[0] + fsum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebp
  mov    $0xfffff,%r13d
  mov    %rsp,%r14
  lea    0x4(%rsp),%r15
  jmp    L35
L19:
  cmp    $0x3e7,%ebx
  jg     L36
L14:
  add    $0x10624d,%r13d
  add    $0x1,%ebp
L35:
  lea    -0x1(%rbp),%r12d
  mov    %r12d,%edx
  lea    D8(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r13d,%eax
  sar    $0x14,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  sar    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x4(%rsp)
  mov    %edx,%eax
  and    $0x3ff,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edx
  shr    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x5(%rsp)
  mov    %edx,%eax
  and    $0x3ff,%eax
  lea    (%rax,%rax,4),%eax
  shr    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    %r14,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %r15,%rdi
  call   <atoi@plt>
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  je     L14
  mov    %ebp,%ebx
  movslq %ebp,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x23,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebp
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L19
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D8: %03d

tool: D18: % d 

assistant: ```c
int main(int argc, char *argv[]) {
  char ta[4], tb[4];
  int i, j, k, bi, sc, sh;
  bi = 4096;
  sc = 2580;
  sh = 8;
  for (i = 0; i < 1000; i++) {
    sprintf(ta, "%03d", i);
    j = i;
    j = (i * 1073741 + 1048575) >> 20;
    j = j * 10;
    tb[0] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[1] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[2] = '0' + (j >> 10);
    j &= 1023;
    tb[3] = 0;
    printf("% d ", atoi(ta) - atoi(tb));
    if (i && !((i + 1) % 25))
      printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0xfffff,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r13
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L17:
  cmp    $0x3e8,%r12d
  je     L38
L48:
  add    $0x10624d,%ebx
L53:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <sprintf@plt>
  mov    %ebx,%eax
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  sar    $0x14,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%ecx
  sar    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x4(%rsp)
  mov    %ecx,%eax
  and    $0x3ff,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%ecx
  shr    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x5(%rsp)
  mov    %ecx,%eax
  and    $0x3ff,%eax
  lea    (%rax,%rax,4),%eax
  shr    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x6(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r15d
  call   <atoi@plt>
  mov    %r15d,%esi
  lea    D10(%rip),%rdi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%r12d
  je     L48
  imul   $0xc28f5c29,%r12d,%eax
  cmp    $0xa3d70a3,%eax
  ja     L17
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x3e8,%r12d
  jne    L48
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string

tool: D13: %03d

tool: D10: % d 

assistant: ```c
int main(int argc, char *argv[]) {
  char ta[4], tb[4];
  int i, j, k, bi, sc, sh;
  bi = 4096;
  sc = 2580;
  sh = 8;
  for (i = 0; i < 1000; i++) {
    sprintf(ta, "%03d", i);
    j = i;
    j = (i * 1073741 + 1048575) >> 20;
    j = j * 10;
    tb[0] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[1] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[2] = '0' + (j >> 10);
    j &= 1023;
    tb[3] = 0;
    printf("% d ", atoi(ta) - atoi(tb));
    if (i && !((i + 1) % 25))
      printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0xfffff,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rsp,%r13
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x3e8,%r12d
  je     L55
L43:
  add    $0x10624d,%ebx
L57:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  call   <sprintf@plt>
  mov    %ebx,%eax
  xor    %ecx,%ecx
  mov    %rbp,%rdi
  sar    $0x14,%eax
  movb   $0x0,0x3(%rsp)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,%edx
  sar    $0xa,%eax
  and    $0x3ff,%edx
  add    $0x30,%eax
  lea    (%rdx,%rdx,4),%edx
  mov    %al,%cl
  lea    (%rdx,%rdx,1),%esi
  shr    $0x9,%edx
  mov    %esi,%eax
  add    $0x30,%edx
  and    $0x3ff,%eax
  mov    %dl,%ch
  lea    (%rax,%rax,4),%eax
  mov    %cx,(%rsp)
  shr    $0x9,%eax
  add    $0x30,%eax
  mov    %al,0x2(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r15d
  call   <atoi@plt>
  mov    %r15d,%esi
  lea    D6(%rip),%rdi
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%r12d
  je     L43
  imul   $0xc28f5c29,%r12d,%eax
  cmp    $0xa3d70a3,%eax
  ja     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x3e8,%r12d
  jne    L43
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D1: %03d

tool: D6: % d 

assistant: ```c
int main(int argc, char *argv[]) {
  char ta[4], tb[4];
  int i, j, k, bi, sc, sh;
  bi = 4096;
  sc = 2580;
  sh = 8;
  for (i = 0; i < 1000; i++) {
    sprintf(ta, "%03d", i);
    j = i;
    j = (i * 1073741 + 1048575) >> 20;
    j = j * 10;
    tb[0] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[1] = '0' + (j >> 10);
    j &= 1023;
    j = j * 10;
    tb[2] = '0' + (j >> 10);
    j &= 1023;
    tb[3] = 0;
    printf("% d ", atoi(ta) - atoi(tb));
    if (i && !((i + 1) % 25))
      printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<display_bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0x12,%esi
  mov    $0x2d,%edi
  call   <my_putnchar@plt>
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void display_bar() {
  my_putchar('|');
  my_putnchar('-', 20 - 2);
  my_putchar('|');
  my_putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0x12,%esi
  mov    $0x2d,%edi
  call   <my_putnchar@plt>
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void display_bar() {
  my_putchar('|');
  my_putnchar('-', 20 - 2);
  my_putchar('|');
  my_putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<display_bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0x12,%esi
  mov    $0x2d,%edi
  call   <my_putnchar@plt>
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <my_putchar@plt>
```

assistant: ```c
void display_bar() {
  my_putchar('|');
  my_putnchar('-', 20 - 2);
  my_putchar('|');
  my_putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<display_bar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0x12,%esi
  mov    $0x2d,%edi
  call   <my_putnchar@plt>
  mov    $0x7c,%edi
  call   <my_putchar@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <my_putchar@plt>
```

assistant: ```c
void display_bar() {
  my_putchar('|');
  my_putnchar('-', 20 - 2);
  my_putchar('|');
  my_putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_big_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  movb   $0x1,(%rax)
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int is_big_endian(void) {
  int i = 0;
  ((char *)(&i))[0] = 1;
  return (i != 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_big_endian>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_big_endian(void) {
  int i = 0;
  ((char *)(&i))[0] = 1;
  return (i != 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_big_endian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_big_endian(void) {
  int i = 0;
  ((char *)(&i))[0] = 1;
  return (i != 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_big_endian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_big_endian(void) {
  int i = 0;
  ((char *)(&i))[0] = 1;
  return (i != 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L7:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movq   %rax,%xmm0
  call   <round@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x1f,-0x14(%rbp)
  jle    L7
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void foo(double *output, double *input) {
  int i = 0;
  for (i = 0; i < 32; i++)
    output[i] = __builtin_round(input[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L8:
  movsd  0x0(%rbp,%rbx,1),%xmm0
  call   <round@plt>
  movsd  %xmm0,(%r12,%rbx,1)
  add    $0x8,%rbx
  cmp    $0x100,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void foo(double *output, double *input) {
  int i = 0;
  for (i = 0; i < 32; i++)
    output[i] = __builtin_round(input[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L4:
  movsd  0x0(%rbp,%rbx,1),%xmm0
  call   <round@plt>
  movsd  %xmm0,(%r12,%rbx,1)
  add    $0x8,%rbx
  cmp    $0x100,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void foo(double *output, double *input) {
  int i = 0;
  for (i = 0; i < 32; i++)
    output[i] = __builtin_round(input[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L0:
  movsd  0x0(%rbp,%rbx,1),%xmm0
  call   <round@plt>
  movsd  %xmm0,(%r12,%rbx,1)
  add    $0x8,%rbx
  cmp    $0x100,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void foo(double *output, double *input) {
  int i = 0;
  for (i = 0; i < 32; i++)
    output[i] = __builtin_round(input[i]);
}
```