ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<sys_audiodevnametonumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xa018(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  lea    0x5010(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rdi
  push   $0x400
  push   $0x14
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sys_get_audio_devs@plt>
  add    $0x10,%rsp
  test   %ebx,%ebx
  jne    L70
  mov    $0x0,%r14d
  lea    0x10(%rsp),%r15
  mov    $0xffffffff,%r13d
  cmpl   $0x0,(%rsp)
  jg     L90
  jmp    L83
L70:
  cmpl   $0x0,0x4(%rsp)
  jle    L134
  mov    $0x0,%r14d
  lea    0x5010(%rsp),%r15
  jmp    L87
L10:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L83
  add    $0x1,%r14
  cmp    %r14d,0x4(%rsp)
  jle    L50
L87:
  mov    %r14d,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r14,%rbp
  shl    $0xa,%rbp
  add    %r15,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jae    L10
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L10
L50:
  mov    $0xffffffff,%r13d
L83:
  mov    0xa018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L136
  mov    %r13d,%eax
  add    $0xa028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L148:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L83
  add    $0x1,%r14
  cmp    %r14d,(%rsp)
  jle    L96
L90:
  mov    %r14d,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r14,%rbp
  shl    $0xa,%rbp
  add    %r15,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jae    L148
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L148
L96:
  mov    $0xffffffff,%r13d
  jmp    L83
L134:
  mov    $0xffffffff,%r13d
  jmp    L83
L136:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_audiodevnametonumber(int output, const char *name) {
  char indevlist[20 * 1024], outdevlist[20 * 1024];
  int nindevs = 0, noutdevs = 0, i, canmulti, cancallback;
  sys_get_audio_devs(indevlist, &nindevs, outdevlist, &noutdevs, &canmulti, &cancallback, 20, 1024);
  if (output) {
    for (i = 0; i < noutdevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(outdevlist + i * 1024))
        comp = strlen(outdevlist + i * 1024);
      if (!strncmp(name, outdevlist + i * 1024, comp))
        return (i);
    }
  } else {
    for (i = 0; i < nindevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(indevlist + i * 1024))
        comp = strlen(indevlist + i * 1024);
      if (!strncmp(name, indevlist + i * 1024, comp))
        return (i);
    }
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sys_audiodevnametonumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa018(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%r14
  mov    %rsi,%rbp
  movl   $0x0,(%rsp)
  lea    0x5010(%rsp),%rbx
  mov    %rsp,%rsi
  mov    %edi,%r12d
  movl   $0x0,0x4(%rsp)
  mov    %rbx,%rdx
  mov    %r14,%rdi
  push   $0x400
  push   $0x14
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sys_get_audio_devs@plt>
  pop    %rcx
  pop    %rsi
  test   %r12d,%r12d
  jne    L65
  mov    (%rsp),%edx
  xor    %ebx,%ebx
  test   %edx,%edx
  jg     L73
  nopl   0x0(%rax,%rax,1)
L106:
  mov    $0xffffffff,%r13d
L18:
  mov    0xa018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0xa028,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
L33:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L18
  add    $0x1,%rbx
  cmp    %ebx,(%rsp)
  jle    L106
L73:
  mov    %rbx,%r15
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  shl    $0xa,%r15
  add    %r14,%r15
  mov    %eax,%r12d
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jae    L33
  jmp    L38
  nopl   (%rax)
L65:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L106
  xor    %r14d,%r14d
  jmp    L122
  nopl   0x0(%rax)
L137:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L18
  add    $0x1,%r14
  cmp    %r14d,0x4(%rsp)
  jle    L106
L122:
  mov    %r14,%r15
  mov    %rbp,%rdi
  mov    %r14d,%r13d
  call   <strlen@plt>
  shl    $0xa,%r15
  add    %rbx,%r15
  mov    %eax,%r12d
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jae    L137
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L137
L77:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_audiodevnametonumber(int output, const char *name) {
  char indevlist[20 * 1024], outdevlist[20 * 1024];
  int nindevs = 0, noutdevs = 0, i, canmulti, cancallback;
  sys_get_audio_devs(indevlist, &nindevs, outdevlist, &noutdevs, &canmulti, &cancallback, 20, 1024);
  if (output) {
    for (i = 0; i < noutdevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(outdevlist + i * 1024))
        comp = strlen(outdevlist + i * 1024);
      if (!strncmp(name, outdevlist + i * 1024, comp))
        return (i);
    }
  } else {
    for (i = 0; i < nindevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(indevlist + i * 1024))
        comp = strlen(indevlist + i * 1024);
      if (!strncmp(name, indevlist + i * 1024, comp))
        return (i);
    }
  }
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sys_audiodevnametonumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xa000(%rsp),%r11
L82:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L82
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa018(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  lea    0x10(%rsp),%r14
  mov    %rsi,%rbp
  movl   $0x0,(%rsp)
  lea    0x5010(%rsp),%rbx
  mov    %rsp,%rsi
  mov    %edi,%r12d
  movl   $0x0,0x4(%rsp)
  mov    %rbx,%rdx
  mov    %r14,%rdi
  push   $0x400
  push   $0x14
  lea    0x1c(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <sys_get_audio_devs@plt>
  pop    %rcx
  pop    %rsi
  test   %r12d,%r12d
  jne    L21
  mov    (%rsp),%edx
  xor    %ebx,%ebx
  test   %edx,%edx
  jg     L33
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0xffffffff,%r13d
L76:
  mov    0xa018(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0xa028,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L100:
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
L79:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L76
  add    $0x1,%rbx
  cmp    %ebx,(%rsp)
  jle    L34
L33:
  mov    %rbx,%r15
  mov    %rbp,%rdi
  mov    %ebx,%r13d
  call   <strlen@plt>
  shl    $0xa,%r15
  add    %r14,%r15
  mov    %eax,%r12d
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jae    L79
  jmp    L100
  nopl   (%rax)
L21:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L34
  xor    %r14d,%r14d
  jmp    L53
  nopl   0x0(%rax)
L78:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L76
  add    $0x1,%r14
  cmp    %r14d,0x4(%rsp)
  jle    L34
L53:
  mov    %r14,%r15
  mov    %rbp,%rdi
  mov    %r14d,%r13d
  call   <strlen@plt>
  shl    $0xa,%r15
  add    %rbx,%r15
  mov    %eax,%r12d
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jae    L78
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L78
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_audiodevnametonumber(int output, const char *name) {
  char indevlist[20 * 1024], outdevlist[20 * 1024];
  int nindevs = 0, noutdevs = 0, i, canmulti, cancallback;
  sys_get_audio_devs(indevlist, &nindevs, outdevlist, &noutdevs, &canmulti, &cancallback, 20, 1024);
  if (output) {
    for (i = 0; i < noutdevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(outdevlist + i * 1024))
        comp = strlen(outdevlist + i * 1024);
      if (!strncmp(name, outdevlist + i * 1024, comp))
        return (i);
    }
  } else {
    for (i = 0; i < nindevs; i++) {
      unsigned int comp = strlen(name);
      if (comp > strlen(indevlist + i * 1024))
        comp = strlen(indevlist + i * 1024);
      if (!strncmp(name, indevlist + i * 1024, comp))
        return (i);
    }
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<gsw_sa_from_sstar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gsw_saar@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  ucomisd D33(%rip),%xmm0
  jp     L9
  movsd  -0x8(%rbp),%xmm0
  ucomisd D33(%rip),%xmm0
  jne    L9
  movsd  -0x8(%rbp),%xmm0
  jmp    L10
L9:
  movsd  -0x8(%rbp),%xmm1
  movsd  D40(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D7(%rip),%xmm1
  mulsd  %xmm1,%xmm2
  movsd  D40(%rip),%xmm1
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
L10:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D33
data_type: f64
name: retrieve_data
arguments: label: D40
data_type: f64
name: retrieve_data
arguments: label: D7
data_type: f64

tool: D33: 9000000000000000.0

tool: D40: 1

tool: D7: 0.35

assistant: ```c
double gsw_sa_from_sstar(double sstar, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sstar * (1e0 + saar) / (1e0 - 0.35e0 * saar));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gsw_sa_from_sstar>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D8(%rip),%xmm0
  jp     L12
  je     L18
L12:
  movsd  D23(%rip),%xmm1
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  movq   %rbx,%xmm4
  mulsd  %xmm4,%xmm2
  mulsd  D9(%rip),%xmm0
  subsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L18:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: f64

tool: D8: 9000000000000000.0

tool: D23: 1

tool: D9: 0.35

assistant: ```c
double gsw_sa_from_sstar(double sstar, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sstar * (1e0 + saar) / (1e0 - 0.35e0 * saar));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gsw_sa_from_sstar>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D4(%rip),%xmm0
  jp     L2
  je     L18
L2:
  movapd %xmm0,%xmm2
  movsd  D11(%rip),%xmm1
  mulsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm2
  mulsd  0x8(%rsp),%xmm2
  subsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L18:
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: f64
name: unpack_data
arguments: label: D11
type: f64
name: unpack_data
arguments: label: D19
type: f64

tool: D4: 9000000000000000.0

tool: D11: 1

tool: D19: 0.35

assistant: ```c
double gsw_sa_from_sstar(double sstar, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sstar * (1e0 + saar) / (1e0 - 0.35e0 * saar));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gsw_sa_from_sstar>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movapd %xmm2,%xmm1
  movapd %xmm3,%xmm2
  call   <gsw_saar@plt>
  ucomisd D9(%rip),%xmm0
  jp     L11
  je     L4
L11:
  movapd %xmm0,%xmm2
  movsd  D2(%rip),%xmm1
  mulsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm2
  mulsd  0x8(%rsp),%xmm2
  subsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
L4:
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: f64
name: read_data
arguments: data_label: D2
type_guessed: f64
name: read_data
arguments: data_label: D13
type_guessed: f64

tool: D9: 9000000000000000.0

tool: D2: 1

tool: D13: 0.35

assistant: ```c
double gsw_sa_from_sstar(double sstar, double p, double lon, double lat) {
  double saar;
  saar = gsw_saar(p, lon, lat);
  if (saar == 9e15)
    return (saar);
  return (sstar * (1e0 + saar) / (1e0 - 0.35e0 * saar));
}
```
user: What is the c source code of the assembly code below:

```asm
<ntohll_util>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <little_endianess@plt>
  test   %rax,%rax
  je     L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <byteswap64@plt>
  jmp    L14
L7:
  mov    -0x4(%rbp),%eax
L14:
  leave
  ret
```

assistant: ```c
uint64_t ntohll_util(uint64_t input) {
  if (little_endianess()) {
    return byteswap64(input);
  } else {
    return input;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ntohll_util>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <little_endianess@plt>
  test   %rax,%rax
  jne    L4
L6:
  mov    %ebx,%eax
  pop    %rbx
  ret
L4:
  mov    %ebx,%edi
  call   <byteswap64@plt>
  mov    %eax,%ebx
  jmp    L6
```

assistant: ```c
uint64_t ntohll_util(uint64_t input) {
  if (little_endianess()) {
    return byteswap64(input);
  } else {
    return input;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ntohll_util>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <little_endianess@plt>
  test   %rax,%rax
  jne    L7
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r12d,%edi
  pop    %r12
  jmp    1060 <byteswap64@plt>
```

assistant: ```c
uint64_t ntohll_util(uint64_t input) {
  if (little_endianess()) {
    return byteswap64(input);
  } else {
    return input;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ntohll_util>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <little_endianess@plt>
  test   %rax,%rax
  jne    L4
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12d,%edi
  pop    %r12
  jmp    1060 <byteswap64@plt>
```

assistant: ```c
uint64_t ntohll_util(uint64_t input) {
  if (little_endianess()) {
    return byteswap64(input);
  } else {
    return input;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x13000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x8b0,%rsp
  mov    %edi,-0x138a4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x13890(%rbp)
  movq   $0x1,-0x13888(%rbp)
  movl   $0x2,-0x13894(%rbp)
  jmp    L38
L21:
  mov    -0x13894(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x13890(%rbp,%rax,8),%rdx
  mov    -0x13894(%rbp),%eax
  sub    $0x2,%eax
  cltq
  mov    -0x13890(%rbp,%rax,8),%rax
  add    %rax,%rdx
  mov    -0x13894(%rbp),%eax
  cltq
  mov    %rdx,-0x13890(%rbp,%rax,8)
  addl   $0x1,-0x13894(%rbp)
L38:
  mov    -0x13894(%rbp),%eax
  cmp    -0x138a4(%rbp),%eax
  jle    L21
  mov    -0x138a4(%rbp),%eax
  cltq
  mov    -0x13890(%rbp,%rax,8),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
long int f2(int n) {
  long int data[10000];
  data[0] = 0;
  data[1] = 1;
  for (int i = 2; i <= n; i++)
    data[i] = data[i - 1] + data[i - 2];
  return data[n];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2>:
  endbr64
  lea    -0x13000(%rsp),%r11
L32:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L32
  sub    $0x898,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13888(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x1,0x8(%rsp)
  cmp    $0x1,%edi
  jle    L31
  mov    %rsp,%rax
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsp,%rdx,8),%rcx
L6:
  mov    (%rax),%rdx
  add    0x8(%rax),%rdx
  mov    %rdx,0x10(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L6
L31:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rax
  mov    0x13888(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x13898,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int f2(int n) {
  long int data[10000];
  data[0] = 0;
  data[1] = 1;
  for (int i = 2; i <= n; i++)
    data[i] = data[i - 1] + data[i - 2];
  return data[n];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f2>:
  endbr64
  lea    -0x13000(%rsp),%r11
L48:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L48
  sub    $0x898,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13888(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x1,0x8(%rsp)
  cmp    $0x1,%edi
  jle    L22
  lea    -0x2(%rdi),%edx
  lea    0x10(%rsp),%rax
  xor    %ecx,%ecx
  lea    (%rax,%rdx,8),%rsi
  mov    $0x1,%edx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L49:
  mov    -0x8(%rax),%rcx
  add    $0x8,%rax
L18:
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L49
L22:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rax
  mov    0x13888(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x13898,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long int f2(int n) {
  long int data[10000];
  data[0] = 0;
  data[1] = 1;
  for (int i = 2; i <= n; i++)
    data[i] = data[i - 1] + data[i - 2];
  return data[n];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2>:
  endbr64
  lea    -0x13000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x898,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x13888(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  cmp    $0x1,%edi
  jle    L10
  cmp    $0x3,%edi
  jle    L43
  lea    -0x4(%rdi),%eax
  mov    $0x1,%esi
  xor    %edx,%edx
  mov    %rsp,%r9
  shr    %eax
  lea    0x3(%rax),%r8d
  mov    $0x4,%eax
  add    %r8,%r8
L48:
  add    %rsi,%rdx
  mov    %eax,%ecx
  add    %rdx,%rsi
  movq   %rdx,%xmm0
  movq   %rsi,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,-0x10(%r9,%rax,8)
  add    $0x2,%rax
  cmp    %rax,%r8
  jne    L48
L57:
  movslq %ecx,%rax
  lea    (%r9,%rax,8),%rax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    -0x8(%rax),%rdx
  add    $0x1,%ecx
  add    -0x10(%rax),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %ecx,%edi
  jge    L0
L10:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rax
  mov    0x13888(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x13898,%rsp
  ret
L43:
  mov    $0x2,%ecx
  mov    %rsp,%r9
  jmp    L57
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
long int f2(int n) {
  long int data[10000];
  data[0] = 0;
  data[1] = 1;
  for (int i = 2; i <= n; i++)
    data[i] = data[i - 1] + data[i - 2];
  return data[n];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Accept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <accept@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L7
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: accept

assistant: ```c
int Accept(int listenfd, struct sockaddr_in *clientaddr, socklen_t *addrlen) {
  int connfd;
  if ((connfd = accept(listenfd, (struct sockaddr *)clientaddr, addrlen)) == -1) {
    perror("accept");
    exit(1);
  }
  return connfd;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Accept>:
  endbr64
  push   %rbx
  call   <accept@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L1
L3:
  mov    %ebx,%eax
  pop    %rbx
  ret
L1:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: accept

assistant: ```c
int Accept(int listenfd, struct sockaddr_in *clientaddr, socklen_t *addrlen) {
  int connfd;
  if ((connfd = accept(listenfd, (struct sockaddr *)clientaddr, addrlen)) == -1) {
    perror("accept");
    exit(1);
  }
  return connfd;
}
```
user: What is the c source code of the assembly code below:

```asm
<Accept>:
  endbr64
  push   %r12
  call   <accept@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L8
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: accept

assistant: ```c
int Accept(int listenfd, struct sockaddr_in *clientaddr, socklen_t *addrlen) {
  int connfd;
  if ((connfd = accept(listenfd, (struct sockaddr *)clientaddr, addrlen)) == -1) {
    perror("accept");
    exit(1);
  }
  return connfd;
}
```
user: What is the c source code of the assembly code below:

```asm
<Accept>:
  endbr64
  push   %r12
  call   <accept@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L6
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: accept

assistant: ```c
int Accept(int listenfd, struct sockaddr_in *clientaddr, socklen_t *addrlen) {
  int connfd;
  if ((connfd = accept(listenfd, (struct sockaddr *)clientaddr, addrlen)) == -1) {
    perror("accept");
    exit(1);
  }
  return connfd;
}
```