ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_bigposint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <bigposint_to_string@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: %s%s


assistant: ```c
void print_bigposint(char *prefix, struct bigposint *bigptr) {
  char output[10000];
  bigposint_to_string(bigptr, output);
  printf("%s%s\n", prefix, output);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_bigposint>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r12,%rsi
  call   <bigposint_to_string@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x2728,%rsp
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D4: %s%s


assistant: ```c
void print_bigposint(char *prefix, struct bigposint *bigptr) {
  char output[10000];
  bigposint_to_string(bigptr, output);
  printf("%s%s\n", prefix, output);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_bigposint>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %r12,%rsi
  call   <bigposint_to_string@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x2728,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %s%s


assistant: ```c
void print_bigposint(char *prefix, struct bigposint *bigptr) {
  char output[10000];
  bigposint_to_string(bigptr, output);
  printf("%s%s\n", prefix, output);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,-0x8(%rbp)
  mov    D17(%rip),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long int atoll(const char *nptr) {
  int tmp;
  long long int res;
  tmp = errno;
  res = strtoll(nptr, NULL, 10);
  errno = tmp;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoll>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rbx
  mov    (%rbx),%ebp
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoll@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long int atoll(const char *nptr) {
  int tmp;
  long long int res;
  tmp = errno;
  res = strtoll(nptr, NULL, 10);
  errno = tmp;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<atoll>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  xor    %esi,%esi
  push   %rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbx
  mov    (%rbx),%ebp
  call   <strtoll@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long int atoll(const char *nptr) {
  int tmp;
  long long int res;
  tmp = errno;
  res = strtoll(nptr, NULL, 10);
  errno = tmp;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<atoll>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  xor    %esi,%esi
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbx
  mov    (%rbx),%ebp
  call   <strtoll@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long long int atoll(const char *nptr) {
  int tmp;
  long long int res;
  tmp = errno;
  res = strtoll(nptr, NULL, 10);
  errno = tmp;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <implicit@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <defined@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int defined();
  defined(implicit());
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <implicit@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <defined@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int defined();
  defined(implicit());
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <implicit@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <defined@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int defined();
  defined(implicit());
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <implicit@plt>
  mov    %eax,%edi
  xor    %eax,%eax
  call   <defined@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int defined();
  defined(implicit());
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rgbatorgba>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  jmp    L1
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x3(%rax),%rdx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x4,-0x28(%rbp)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L1:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rgbatorgba(unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a, unsigned char *l, int n) {
  while (n--) {
    l[0] = r[0];
    l[1] = g[0];
    l[2] = b[0];
    l[3] = a[0];
    l += 4;
    r++;
    g++;
    b++;
    a++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rgbatorgba>:
  endbr64
  mov    %rdx,%r10
  test   %r9d,%r9d
  je     L18
  mov    %r9d,%r9d
  mov    $0x0,%eax
L7:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r8,%rax,4)
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0x1(%r8,%rax,4)
  movzbl (%r10,%rax,1),%edx
  mov    %dl,0x2(%r8,%rax,4)
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,0x3(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L7
L18:
  ret
```

assistant: ```c
void rgbatorgba(unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a, unsigned char *l, int n) {
  while (n--) {
    l[0] = r[0];
    l[1] = g[0];
    l[2] = b[0];
    l[3] = a[0];
    l += 4;
    r++;
    g++;
    b++;
    a++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rgbatorgba>:
  endbr64
  mov    %rdx,%r10
  test   %r9d,%r9d
  je     L15
  mov    %r9d,%r9d
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r8,%rax,4)
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0x1(%r8,%rax,4)
  movzbl (%r10,%rax,1),%edx
  mov    %dl,0x2(%r8,%rax,4)
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,0x3(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L16
L15:
  ret
```

assistant: ```c
void rgbatorgba(unsigned char *r, unsigned char *g, unsigned char *b, unsigned char *a, unsigned char *l, int n) {
  while (n--) {
    l[0] = r[0];
    l[1] = g[0];
    l[2] = b[0];
    l[3] = a[0];
    l += 4;
    r++;
    g++;
    b++;
    a++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x1,-0xc(%rbp)
  jne    L16
  mov    -0x14(%rbp),%eax
  cmp    $0x4d2,%eax
  jne    L16
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  je     L17
L16:
  mov    $0x0,%eax
  call   <abort@plt>
L17:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D19: %d%n

tool: D28: 1234:567

tool: D3: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, n, r;
  n = i = r = -1;
  r = sscanf("1234:567", "%d%n", &i, &n);
  printf("%d %d %d\n", r, n, i);
  if (r != 1 || i != 1234 || n != 4)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  lea    D25(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <sscanf@plt>
  mov    %eax,%ebx
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jne    L42
  cmpl   $0x4d2,(%rsp)
  je     L29
L42:
  mov    $0x0,%eax
  call   <abort@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L29:
  cmpl   $0x4,0x4(%rsp)
  jne    L42
  jmp    L39
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D25: %d%n

tool: D0: 1234:567

tool: D2: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, n, r;
  n = i = r = -1;
  r = sscanf("1234:567", "%d%n", &i, &n);
  printf("%d %d %d\n", r, n, i);
  if (r != 1 || i != 1234 || n != 4)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D20(%rip),%rsi
  lea    D13(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  call   <sscanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  lea    D14(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jne    L45
  cmpl   $0x4d2,(%rsp)
  je     L32
L45:
  xor    %eax,%eax
  call   <abort@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L32:
  cmpl   $0x4,0x4(%rsp)
  jne    L45
  jmp    L48
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D20: %d%n

tool: D13: 1234:567

tool: D14: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, n, r;
  n = i = r = -1;
  r = sscanf("1234:567", "%d%n", &i, &n);
  printf("%d %d %d\n", r, n, i);
  if (r != 1 || i != 1234 || n != 4)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rsi
  lea    D26(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  call   <sscanf@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  lea    D15(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  call   <printf@plt>
  cmp    $0x1,%ebx
  jne    L32
  cmpl   $0x4d2,(%rsp)
  je     L2
L32:
  xor    %eax,%eax
  call   <abort@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  cmpl   $0x4,0x4(%rsp)
  jne    L32
  jmp    L6
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string

tool: D4: %d%n

tool: D26: 1234:567

tool: D15: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int i, n, r;
  n = i = r = -1;
  r = sscanf("1234:567", "%d%n", &i, &n);
  printf("%d %d %d\n", r, n, i);
  if (r != 1 || i != 1234 || n != 4)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f10_dvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <allocate_vector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L55
L44:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
L55:
  mov    -0x3c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x28(%rbp)
  jle    L44
  movl   $0x0,-0x28(%rbp)
  jmp    L31
L39:
  movl   $0x0,-0x24(%rbp)
  jmp    L34
L41:
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm1
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  add    %rcx,%rdx
  movsd  (%rdx),%xmm0
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L34:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L41
  addl   $0x1,-0x28(%rbp)
L31:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L39
  movl   $0x0,-0x28(%rbp)
  jmp    L59
L37:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x28(%rbp),%xmm1
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  imul   %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x28(%rbp)
L59:
  mov    -0x28(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L37
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double f10_dvar(double **P, int Ng) {
  int i, j;
  double sum = 0, sum_sqr = 0, var = 0;
  double *Pxpy = allocate_vector(0, 2 * Ng);
  for (i = 0; i <= 2 * Ng; ++i)
    Pxpy[i] = 0;
  for (i = 0; i < Ng; ++i)
    for (j = 0; j < Ng; ++j)
      Pxpy[abs(i - j)] += P[i][j];
  for (i = 0; i < Ng; ++i) {
    sum += i * Pxpy[i];
    sum_sqr += i * i * Pxpy[i];
  }
  var = sum_sqr - sum * sum;
  free(Pxpy);
  return var;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f10_dvar>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  lea    (%rsi,%rsi,1),%ebx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <allocate_vector@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  js     L68
  lea    0x1(%rbx),%edx
  lea    (%rax,%rdx,8),%rdx
L33:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L33
L68:
  test   %r15d,%r15d
  jle    L56
  mov    %r15d,%r12d
  neg    %r12d
L4:
  lea    (%r12,%r15,1),%ebx
  mov    $0x0,%ebp
L30:
  mov    %ebx,%edi
  call   <abs@plt>
  lea    (%r14,%rax,8),%rax
  mov    0x0(%r13),%rdx
  movsd  (%rax),%xmm0
  addsd  (%rdx,%rbp,1),%xmm0
  movsd  %xmm0,(%rax)
  sub    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %r12d,%ebx
  jne    L30
  add    $0x8,%r13
  add    $0x1,%r12d
  jne    L4
  mov    %r15d,%r15d
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm3
L19:
  movsd  (%r14,%rax,8),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  mov    %eax,%edx
  imul   %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  add    $0x1,%rax
  cmp    %r15,%rax
  jne    L19
L31:
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm2
  movq   %xmm2,%rbx
  mov    %r14,%rdi
  call   <free@plt>
  movq   %rbx,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  pxor   %xmm2,%xmm2
  movapd %xmm2,%xmm3
  jmp    L31
```

assistant: ```c
double f10_dvar(double **P, int Ng) {
  int i, j;
  double sum = 0, sum_sqr = 0, var = 0;
  double *Pxpy = allocate_vector(0, 2 * Ng);
  for (i = 0; i <= 2 * Ng; ++i)
    Pxpy[i] = 0;
  for (i = 0; i < Ng; ++i)
    for (j = 0; j < Ng; ++j)
      Pxpy[abs(i - j)] += P[i][j];
  for (i = 0; i < Ng; ++i) {
    sum += i * Pxpy[i];
    sum_sqr += i * i * Pxpy[i];
  }
  var = sum_sqr - sum * sum;
  free(Pxpy);
  return var;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f10_dvar>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  xor    %edi,%edi
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%r14,%r14,1),%ebx
  mov    %ebx,%esi
  sub    $0x18,%rsp
  call   <allocate_vector@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  js     L51
  movslq %ebx,%rbx
  xor    %esi,%esi
  mov    %rax,%rdi
  lea    0x8(,%rbx,8),%rdx
  call   <memset@plt>
L51:
  test   %r14d,%r14d
  jle    L23
  mov    %r14d,%r12d
  neg    %r12d
L2:
  lea    (%r14,%r12,1),%ebx
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <abs@plt>
  mov    (%r15),%rdx
  lea    0x0(%r13,%rax,8),%rax
  movsd  (%rax),%xmm0
  addsd  (%rdx,%rbp,1),%xmm0
  add    $0x8,%rbp
  movsd  %xmm0,(%rax)
  cmp    %ebx,%r12d
  jne    L28
  add    $0x8,%r15
  add    $0x1,%r12d
  jne    L2
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movapd %xmm0,%xmm3
  nopl   0x0(%rax)
L12:
  pxor   %xmm1,%xmm1
  movsd  0x0(%r13,%rax,8),%xmm2
  mov    %eax,%edx
  cvtsi2sd %eax,%xmm1
  imul   %eax,%edx
  add    $0x1,%rax
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%r14
  jne    L12
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm0
L9:
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  pxor   %xmm0,%xmm0
  jmp    L9
```

assistant: ```c
double f10_dvar(double **P, int Ng) {
  int i, j;
  double sum = 0, sum_sqr = 0, var = 0;
  double *Pxpy = allocate_vector(0, 2 * Ng);
  for (i = 0; i <= 2 * Ng; ++i)
    Pxpy[i] = 0;
  for (i = 0; i < Ng; ++i)
    for (j = 0; j < Ng; ++j)
      Pxpy[abs(i - j)] += P[i][j];
  for (i = 0; i < Ng; ++i) {
    sum += i * Pxpy[i];
    sum_sqr += i * i * Pxpy[i];
  }
  var = sum_sqr - sum * sum;
  free(Pxpy);
  return var;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f10_dvar>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  xor    %edi,%edi
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%r14,%r14,1),%ebx
  mov    %ebx,%esi
  sub    $0x18,%rsp
  call   <allocate_vector@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  js     L30
  movslq %ebx,%rbx
  xor    %esi,%esi
  mov    %rax,%rdi
  lea    0x8(,%rbx,8),%rdx
  call   <memset@plt>
L30:
  test   %r14d,%r14d
  jle    L1
  mov    %r14d,%r12d
  neg    %r12d
L37:
  lea    (%r14,%r12,1),%ebx
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  sub    $0x1,%ebx
  call   <abs@plt>
  mov    (%r15),%rdx
  lea    0x0(%r13,%rax,8),%rax
  movsd  (%rax),%xmm0
  addsd  (%rdx,%rbp,1),%xmm0
  add    $0x8,%rbp
  movsd  %xmm0,(%rax)
  cmp    %ebx,%r12d
  jne    L2
  add    $0x8,%r15
  add    $0x1,%r12d
  jne    L37
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movapd %xmm0,%xmm3
  nopl   0x0(%rax)
L40:
  pxor   %xmm1,%xmm1
  movsd  0x0(%r13,%rax,8),%xmm2
  mov    %eax,%edx
  cvtsi2sd %eax,%xmm1
  imul   %eax,%edx
  add    $0x1,%rax
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm3
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%r14
  jne    L40
  mulsd  %xmm3,%xmm3
  subsd  %xmm3,%xmm0
L55:
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  pxor   %xmm0,%xmm0
  jmp    L55
```

assistant: ```c
double f10_dvar(double **P, int Ng) {
  int i, j;
  double sum = 0, sum_sqr = 0, var = 0;
  double *Pxpy = allocate_vector(0, 2 * Ng);
  for (i = 0; i <= 2 * Ng; ++i)
    Pxpy[i] = 0;
  for (i = 0; i < Ng; ++i)
    for (j = 0; j < Ng; ++j)
      Pxpy[abs(i - j)] += P[i][j];
  for (i = 0; i < Ng; ++i) {
    sum += i * Pxpy[i];
    sum_sqr += i * i * Pxpy[i];
  }
  var = sum_sqr - sum * sum;
  free(Pxpy);
  return var;
}
```