ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<GetDateTime3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x14(%rax),%edi
  mov    -0x28(%rbp),%rax
  mov    0x10(%rax),%esi
  mov    -0x28(%rbp),%rax
  mov    0xc(%rax),%r9d
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%r8d
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x76c(%rax),%edx
  lea    -0x20(%rbp),%rax
  push   %rdi
  push   %rsi
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D8: GetDateTime3:	

tool: D9: %d-%02d-%02d %02d:%02d:%02d

assistant: ```c
void GetDateTime3(time_t sec) {
  printf("GetDateTime3:\t");
  char timeStr[20] = {0};
  struct tm *dateTime = localtime(&sec);
  sprintf(timeStr, "%d-%02d-%02d %02d:%02d:%02d", dateTime->tm_year + 1900, dateTime->tm_mon + 1, dateTime->tm_mday, dateTime->tm_hour, dateTime->tm_min, dateTime->tm_sec);
  printf("%s\n", timeStr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetDateTime3>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x0,0x20(%rsp)
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0x4(%rax),%edx
  lea    0x1(%rdx),%ecx
  mov    (%rax),%ebx
  lea    0x76c(%rbx),%edx
  lea    0x10(%rsp),%rbx
  mov    0x14(%rax),%esi
  push   %rsi
  mov    0x10(%rax),%eax
  push   %rax
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D18: GetDateTime3:	

tool: D2: %d-%02d-%02d %02d:%02d:%02d

assistant: ```c
void GetDateTime3(time_t sec) {
  printf("GetDateTime3:\t");
  char timeStr[20] = {0};
  struct tm *dateTime = localtime(&sec);
  sprintf(timeStr, "%d-%02d-%02d %02d:%02d:%02d", dateTime->tm_year + 1900, dateTime->tm_mon + 1, dateTime->tm_mday, dateTime->tm_hour, dateTime->tm_min, dateTime->tm_sec);
  printf("%s\n", timeStr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GetDateTime3>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  lea    D0(%rip),%rdi
  lea    0x10(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdi
  pxor   %xmm0,%xmm0
  movl   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <localtime@plt>
  mov    %rbp,%rdi
  mov    0x4(%rax),%edx
  mov    0x14(%rax),%esi
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  lea    0x1(%rdx),%ecx
  mov    (%rax),%edx
  push   %rsi
  lea    D6(%rip),%rsi
  mov    0x10(%rax),%eax
  add    $0x76c,%edx
  push   %rax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D0: GetDateTime3:	

tool: D6: %d-%02d-%02d %02d:%02d:%02d

assistant: ```c
void GetDateTime3(time_t sec) {
  printf("GetDateTime3:\t");
  char timeStr[20] = {0};
  struct tm *dateTime = localtime(&sec);
  sprintf(timeStr, "%d-%02d-%02d %02d:%02d:%02d", dateTime->tm_year + 1900, dateTime->tm_mon + 1, dateTime->tm_mday, dateTime->tm_hour, dateTime->tm_min, dateTime->tm_sec);
  printf("%s\n", timeStr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetDateTime3>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %edi,0xc(%rsp)
  lea    D11(%rip),%rdi
  lea    0x10(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdi
  pxor   %xmm0,%xmm0
  movl   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <localtime@plt>
  mov    %rbp,%rdi
  mov    0x4(%rax),%edx
  mov    0x14(%rax),%esi
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  lea    0x1(%rdx),%ecx
  mov    (%rax),%edx
  push   %rsi
  lea    D18(%rip),%rsi
  mov    0x10(%rax),%eax
  add    $0x76c,%edx
  push   %rax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D11: GetDateTime3:	

tool: D18: %d-%02d-%02d %02d:%02d:%02d

assistant: ```c
void GetDateTime3(time_t sec) {
  printf("GetDateTime3:\t");
  char timeStr[20] = {0};
  struct tm *dateTime = localtime(&sec);
  sprintf(timeStr, "%d-%02d-%02d %02d:%02d:%02d", dateTime->tm_year + 1900, dateTime->tm_mon + 1, dateTime->tm_mday, dateTime->tm_hour, dateTime->tm_min, dateTime->tm_sec);
  printf("%s\n", timeStr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modified_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x61,%al
  jne    L32
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L7:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D6
data_type: string

tool: D1: xay

tool: D6: %s

assistant: ```c
void modified_print(const char *str) {
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == 'a') {
      printf("%s", "xay");
    } else {
      printf("%c", str[i]);
    }
    i++;
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<modified_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  lea    0x1(%rdi),%rbx
  lea    D14(%rip),%r12
  lea    D4(%rip),%rbp
  jmp    L46
L41:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L49:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L26
L46:
  cmp    $0x61,%al
  je     L41
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L49
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D4
type: string

tool: D14: xay

tool: D4: %s

assistant: ```c
void modified_print(const char *str) {
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == 'a') {
      printf("%s", "xay");
    } else {
      printf("%c", str[i]);
    }
    i++;
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<modified_print>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L8:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L18
L20:
  cmp    $0x61,%al
  jne    L8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L20
L18:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D8: xay

tool: D6: %s

assistant: ```c
void modified_print(const char *str) {
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == 'a') {
      printf("%s", "xay");
    } else {
      printf("%c", str[i]);
    }
    i++;
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<modified_print>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  nopl   0x0(%rax)
L10:
  cmp    $0x61,%al
  je     L26
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L10
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L26:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L10
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D13
type: string

tool: D3: xay

tool: D13: %s

assistant: ```c
void modified_print(const char *str) {
  int i = 0;
  while (str[i] != '\0') {
    if (str[i] == 'a') {
      printf("%s", "xay");
    } else {
      printf("%c", str[i]);
    }
    i++;
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string

tool: D8: hello, 

tool: D0: world

tool: D18: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("\bworld");
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type: string
name: read_data
arguments: data_tag: D4
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D23: hello, 

tool: D4: world

tool: D16: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("\bworld");
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D29
datatype: string

tool: D16: hello, 

tool: D4: world

tool: D29: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("\bworld");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string
name: parse_data
arguments: data_label: D18
datatype: string

tool: D26: hello, 

tool: D9: world

tool: D18: 


assistant: ```c
int main() {
  printf("hello, ");
  printf("\bworld");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bmemdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <bmalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L6
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *bmemdup(const void *ptr, size_t size) {
  void *out = bmalloc(size);
  if (size)
    memcpy(out, ptr, size);
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bmemdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <bmalloc@plt>
  mov    %rax,%rbp
  test   %rbx,%rbx
  jne    L1
L12:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L12
```

assistant: ```c
void *bmemdup(const void *ptr, size_t size) {
  void *out = bmalloc(size);
  if (size)
    memcpy(out, ptr, size);
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<bmemdup>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <bmalloc@plt>
  mov    %rax,%r13
  test   %r12,%r12
  jne    L0
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *bmemdup(const void *ptr, size_t size) {
  void *out = bmalloc(size);
  if (size)
    memcpy(out, ptr, size);
  return out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bmemdup>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <bmalloc@plt>
  mov    %rax,%r13
  test   %r12,%r12
  jne    L7
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *bmemdup(const void *ptr, size_t size) {
  void *out = bmalloc(size);
  if (size)
    memcpy(out, ptr, size);
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vec3_rotateX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movss  %xmm0,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x1c(%rbp),%xmm4
  movss  %xmm4,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  mulss  -0x38(%rbp),%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x18(%rbp),%xmm2
  movss  %xmm2,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  movss  -0x3c(%rbp),%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x38(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x1c(%rbp),%xmm5
  movss  %xmm5,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  mulss  -0x38(%rbp),%xmm0
  movss  %xmm0,-0x38(%rbp)
  movss  -0x18(%rbp),%xmm6
  movss  %xmm6,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  mulss  -0x3c(%rbp),%xmm0
  addss  -0x38(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x14(%rbp),%xmm1
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x10(%rbp),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  movss  -0xc(%rbp),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void vec3_rotateX(float *dst, float *b, float c) {
  float p[3], r[3];
  p[0] = dst[0] - b[0];
  p[1] = dst[1] - b[1];
  p[2] = dst[2] - b[2];
  r[0] = p[0];
  r[1] = p[1] * cosf(c) - p[2] * sinf(c);
  r[2] = p[1] * sinf(c) + p[2] * cosf(c);
  dst[0] = r[0] + b[0];
  dst[1] = r[1] + b[1];
  dst[2] = r[2] + b[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vec3_rotateX>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm4
  movss  0x0(%rbp),%xmm5
  movss  0x4(%rbx),%xmm0
  subss  0x4(%rbp),%xmm0
  movss  0x8(%rbx),%xmm1
  subss  0x8(%rbp),%xmm1
  movss  (%rbx),%xmm2
  subss  %xmm5,%xmm2
  addss  %xmm5,%xmm2
  movss  %xmm2,(%rbx)
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  subss  %xmm5,%xmm2
  addss  0x4(%rbp),%xmm2
  movss  %xmm2,0x4(%rbx)
  mulss  %xmm4,%xmm0
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  addss  0x8(%rbp),%xmm0
  movss  %xmm0,0x8(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vec3_rotateX(float *dst, float *b, float c) {
  float p[3], r[3];
  p[0] = dst[0] - b[0];
  p[1] = dst[1] - b[1];
  p[2] = dst[2] - b[2];
  r[0] = p[0];
  r[1] = p[1] * cosf(c) - p[2] * sinf(c);
  r[2] = p[1] * sinf(c) + p[2] * cosf(c);
  dst[0] = r[0] + b[0];
  dst[1] = r[1] + b[1];
  dst[2] = r[2] + b[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec3_rotateX>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0x0(%rbp),%xmm5
  movss  (%rbx),%xmm2
  movss  0x4(%rbx),%xmm0
  movss  0x8(%rbx),%xmm1
  subss  %xmm5,%xmm2
  subss  0x4(%rbp),%xmm0
  movss  0x8(%rsp),%xmm3
  subss  0x8(%rbp),%xmm1
  movss  0xc(%rsp),%xmm4
  addss  %xmm5,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  movss  %xmm2,(%rbx)
  mulss  %xmm3,%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm4,%xmm0
  subss  %xmm5,%xmm2
  addss  0x4(%rbp),%xmm2
  addss  %xmm1,%xmm0
  movss  %xmm2,0x4(%rbx)
  addss  0x8(%rbp),%xmm0
  movss  %xmm0,0x8(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vec3_rotateX(float *dst, float *b, float c) {
  float p[3], r[3];
  p[0] = dst[0] - b[0];
  p[1] = dst[1] - b[1];
  p[2] = dst[2] - b[2];
  r[0] = p[0];
  r[1] = p[1] * cosf(c) - p[2] * sinf(c);
  r[2] = p[1] * sinf(c) + p[2] * cosf(c);
  dst[0] = r[0] + b[0];
  dst[1] = r[1] + b[1];
  dst[2] = r[2] + b[2];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec3_rotateX>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0x0(%rbp),%xmm5
  movss  (%rbx),%xmm2
  movss  0x4(%rbx),%xmm0
  movss  0x8(%rbx),%xmm1
  subss  %xmm5,%xmm2
  subss  0x4(%rbp),%xmm0
  movss  0x8(%rsp),%xmm3
  subss  0x8(%rbp),%xmm1
  movss  0xc(%rsp),%xmm4
  addss  %xmm5,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  movss  %xmm2,(%rbx)
  mulss  %xmm3,%xmm1
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  mulss  %xmm4,%xmm0
  subss  %xmm5,%xmm2
  addss  0x4(%rbp),%xmm2
  addss  %xmm1,%xmm0
  movss  %xmm2,0x4(%rbx)
  addss  0x8(%rbp),%xmm0
  movss  %xmm0,0x8(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vec3_rotateX(float *dst, float *b, float c) {
  float p[3], r[3];
  p[0] = dst[0] - b[0];
  p[1] = dst[1] - b[1];
  p[2] = dst[2] - b[2];
  r[0] = p[0];
  r[1] = p[1] * cosf(c) - p[2] * sinf(c);
  r[2] = p[1] * sinf(c) + p[2] * cosf(c);
  dst[0] = r[0] + b[0];
  dst[1] = r[1] + b[1];
  dst[2] = r[2] + b[2];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<summation_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L19
L4:
  mov    -0x8(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %rax,%rdi
  call   <pow@plt>
  add    $0x10,%rsp
  add    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L4
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long summation_pow(long long value, long double power) {
  long long sum = 0;
  long long i;
  for (i = 1; i <= value; i++)
    sum += (long long)pow(i, power);
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<summation_pow>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  jle    L4
  mov    %rdi,%r12
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L26:
  push   0x28(%rsp)
  push   0x28(%rsp)
  mov    %rbx,%rdi
  call   <pow@plt>
  add    %rax,%rbp
  add    $0x1,%rbx
  add    $0x10,%rsp
  cmp    %rbx,%r12
  jge    L26
L27:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%ebp
  jmp    L27
```

assistant: ```c
long long summation_pow(long long value, long double power) {
  long long sum = 0;
  long long i;
  for (i = 1; i <= value; i++)
    sum += (long long)pow(i, power);
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<summation_pow>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  jle    L17
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L15:
  push   0x28(%rsp)
  mov    %rbx,%rdi
  add    $0x1,%rbx
  push   0x28(%rsp)
  call   <pow@plt>
  add    %rax,%r12
  pop    %rax
  pop    %rdx
  cmp    %rbx,%rbp
  jge    L15
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long long summation_pow(long long value, long double power) {
  long long sum = 0;
  long long i;
  for (i = 1; i <= value; i++)
    sum += (long long)pow(i, power);
  return sum;
}
```