ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<powl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x44(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %rax,%rdi
  call   <frexpl@plt>
  add    $0x10,%rsp
  fstpt  -0x40(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  fildl  -0x54(%rbp)
  fldt   0x20(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x30(%rbp)
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  call   <floorl@plt>
  add    $0x10,%rsp
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  fildl  -0x54(%rbp)
  fldt   -0x30(%rbp)
  fsubp  %st,%st(1)
  fstpt  -0x30(%rbp)
  push   -0x38(%rbp)
  push   -0x40(%rbp)
  call   <logl@plt>
  add    $0x10,%rsp
  fldt   0x20(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <expl@plt>
  add    $0x10,%rsp
  fstpt  -0x20(%rbp)
  mov    D7(%rip),%rax
  fldt   (%rax)
  fldt   -0x30(%rbp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <expl@plt>
  add    $0x10,%rsp
  fldt   -0x20(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
  mov    -0x44(%rbp),%eax
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  mov    %eax,%edi
  call   <ldexpl@plt>
  add    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
long double powl(long double x, long double y) {
  long double base, yExp;
  long double result;
  int exp;
  base = frexpl(x, &exp);
  yExp = y * exp;
  exp = floorl(yExp);
  yExp -= exp;
  result = expl(logl(base) * y);
  result *= expl(M_LN2 * yExp);
  return ldexpl(result, exp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<powl>:
  endbr64
  push   %r15
  push   %r14
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x34(%rsp),%rdi
  push   0x68(%rsp)
  push   0x68(%rsp)
  call   <frexpl@plt>
  fstpt  0x10(%rsp)
  mov    0x10(%rsp),%r14
  mov    0x18(%rsp),%r15d
  fildl  0x44(%rsp)
  fldt   0x80(%rsp)
  fmulp  %st,%st(1)
  fld    %st(0)
  fstpt  0x10(%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <floorl@plt>
  mov    %eax,%ebx
  add    $0x20,%rsp
  push   %r15
  push   %r14
  call   <logl@plt>
  fldt   0x80(%rsp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <expl@plt>
  fstpt  0x30(%rsp)
  add    $0x10,%rsp
  mov    %ebx,0x3c(%rsp)
  fildl  0x3c(%rsp)
  fldt   0x10(%rsp)
  fsubp  %st,%st(1)
  mov    D7(%rip),%rax
  fldt   (%rax)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  mov    %ebx,%edi
  call   <ldexpl@plt>
  add    $0x20,%rsp
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  pop    %rbx
  pop    %r14
  pop    %r15
  ret
L1:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double powl(long double x, long double y) {
  long double base, yExp;
  long double result;
  int exp;
  base = frexpl(x, &exp);
  yExp = y * exp;
  exp = floorl(yExp);
  yExp -= exp;
  result = expl(logl(base) * y);
  result *= expl(M_LN2 * yExp);
  return ldexpl(result, exp);
}
```
user: What is the c source code of the assembly code below?

```asm
<powl>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  fldt   0x60(%rsp)
  lea    0x34(%rsp),%rdi
  fstpt  (%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  push   0x58(%rsp)
  push   0x58(%rsp)
  call   <frexpl@plt>
  sub    $0x10,%rsp
  fstpt  0x40(%rsp)
  fildl  0x54(%rsp)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x30(%rsp)
  call   <floorl@plt>
  mov    %eax,%ebp
  pop    %rax
  pop    %rdx
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  call   <logl@plt>
  fldt   0x10(%rsp)
  sub    $0x10,%rsp
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  mov    D2(%rip),%rax
  fstpt  0x40(%rsp)
  pop    %rcx
  pop    %rsi
  mov    %ebp,0x10(%rsp)
  fildl  0x10(%rsp)
  fldt   0x20(%rsp)
  fsubp  %st,%st(1)
  fldt   (%rax)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  pop    %rdi
  pop    %r8
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  fldt   0x20(%rsp)
  mov    %ebp,%edi
  fmulp  %st,%st(1)
  fstpt  0x50(%rsp)
  add    $0x40,%rsp
  pop    %rbp
  jmp    10e0 <ldexpl@plt>
L7:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double powl(long double x, long double y) {
  long double base, yExp;
  long double result;
  int exp;
  base = frexpl(x, &exp);
  yExp = y * exp;
  exp = floorl(yExp);
  yExp -= exp;
  result = expl(logl(base) * y);
  result *= expl(M_LN2 * yExp);
  return ldexpl(result, exp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<powl>:
  endbr64
  push   %rbp
  sub    $0x40,%rsp
  fldt   0x60(%rsp)
  lea    0x34(%rsp),%rdi
  fstpt  (%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  push   0x58(%rsp)
  push   0x58(%rsp)
  call   <frexpl@plt>
  sub    $0x10,%rsp
  fstpt  0x40(%rsp)
  fildl  0x54(%rsp)
  fldt   0x20(%rsp)
  fmulp  %st,%st(1)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x30(%rsp)
  call   <floorl@plt>
  mov    %eax,%ebp
  pop    %rax
  pop    %rdx
  fldt   0x30(%rsp)
  fstpt  (%rsp)
  call   <logl@plt>
  fldt   0x10(%rsp)
  sub    $0x10,%rsp
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  mov    D3(%rip),%rax
  fstpt  0x40(%rsp)
  pop    %rcx
  pop    %rsi
  mov    %ebp,0x10(%rsp)
  fildl  0x10(%rsp)
  fldt   0x20(%rsp)
  fsubp  %st,%st(1)
  fldt   (%rax)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  call   <expl@plt>
  pop    %rdi
  pop    %r8
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  fldt   0x20(%rsp)
  mov    %ebp,%edi
  fmulp  %st,%st(1)
  fstpt  0x50(%rsp)
  add    $0x40,%rsp
  pop    %rbp
  jmp    10e0 <ldexpl@plt>
L3:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double powl(long double x, long double y) {
  long double base, yExp;
  long double result;
  int exp;
  base = frexpl(x, &exp);
  yExp = y * exp;
  exp = floorl(yExp);
  yExp -= exp;
  result = expl(logl(base) * y);
  result *= expl(M_LN2 * yExp);
  return ldexpl(result, exp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%eax
  nop
  pop    %rbp
  ret
```

assistant: ```c
void baz(void) {
  register int xyzzy asm("0") = 1;
  asm volatile("" : : "r"(xyzzy));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baz>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
void baz(void) {
  register int xyzzy asm("0") = 1;
  asm volatile("" : : "r"(xyzzy));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<baz>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
void baz(void) {
  register int xyzzy asm("0") = 1;
  asm volatile("" : : "r"(xyzzy));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<baz>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
void baz(void) {
  register int xyzzy asm("0") = 1;
  asm volatile("" : : "r"(xyzzy));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L25:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L25
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x10(%rbp),%xmm2
  movd   %xmm2,%eax
  movd   %eax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D36
type: string

tool: D31: %d

tool: D12: Sum: %d


tool: D36: Avg: %.2f


assistant: ```c
int main() {
  int n;
  int number;
  int sum;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &number);
    sum = sum + number;
  }
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", (float)sum / n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L12
  mov    $0x0,%ebx
  lea    D19(%rip),%r12
L14:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L14
L12:
  pxor   %xmm2,%xmm2
  cvtsi2ss %ebp,%xmm2
  movd   %xmm2,%ebx
  movaps %xmm2,%xmm0
  lea    D30(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rsp),%xmm1
  movd   %ebx,%xmm0
  divss  %xmm1,%xmm0
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
data_type: string
name: read_data
arguments: data_label: D30
data_type: string
name: read_data
arguments: data_label: D33
data_type: string

tool: D19: %d

tool: D30: Sum: %d


tool: D33: Avg: %.2f


assistant: ```c
int main() {
  int n;
  int number;
  int sum;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &number);
    sum = sum + number;
  }
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", (float)sum / n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L5
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax)
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x14(%rsp),%ebp
  cmp    %ebx,0x10(%rsp)
  jg     L7
L5:
  pxor   %xmm0,%xmm0
  lea    D20(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D10(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D20
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D23: %d

tool: D20: Sum: %d


tool: D10: Avg: %.2f


assistant: ```c
int main() {
  int n;
  int number;
  int sum;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &number);
    sum = sum + number;
  }
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", (float)sum / n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L1
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r13
  nopl   0x0(%rax)
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  add    0x14(%rsp),%ebp
  cmp    %ebx,0x10(%rsp)
  jg     L8
L1:
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%rdi
  cvtsi2ss %ebp,%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  lea    D16(%rip),%rdi
  cvtsi2ssl 0x10(%rsp),%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D28: %d

tool: D14: Sum: %d


tool: D16: Avg: %.2f


assistant: ```c
int main() {
  int n;
  int number;
  int sum;
  scanf("%d", &n);
  for (int i = 0; i < n; i++) {
    scanf("%d", &number);
    sum = sum + number;
  }
  printf("Sum: %d\n", sum);
  printf("Avg: %.2f\n", (float)sum / n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ops_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ops_copy(double *x, double *y, int nlf) {
  int i;
  for (i = 0; i < nlf; i++) {
    x[i] = y[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ops_copy>:
  endbr64
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  mov    $0x0,%eax
L17:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L19:
  ret
```

assistant: ```c
void ops_copy(double *x, double *y, int nlf) {
  int i;
  for (i = 0; i < nlf; i++) {
    x[i] = y[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ops_copy>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L11:
  ret
```

assistant: ```c
void ops_copy(double *x, double *y, int nlf) {
  int i;
  for (i = 0; i < nlf; i++) {
    x[i] = y[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ops_copy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L10
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L18
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L18
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L4:
  movupd (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L4
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L10
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L35:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L35
L10:
  ret
```

assistant: ```c
void ops_copy(double *x, double *y, int nlf) {
  int i;
  for (i = 0; i < nlf; i++) {
    x[i] = y[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tu_strbtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L76
L20:
  mov    $0x0,%eax
  jmp    L95
L76:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L81
  mov    $0x0,%eax
  jmp    L95
L81:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L62
L77:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L117
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L108
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L100
L117:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L101
  movl   $0x1,-0x10(%rbp)
  jmp    L108
L101:
  movl   $0x0,-0x10(%rbp)
L108:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L62:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
L100:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L3
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
L3:
  mov    -0x8(%rbp),%rax
L95:
  leave
  ret
```

assistant: ```c
char *tu_strbtok(char **str, unsigned int *match_length, const char *delimiter) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiter_length;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiter_length = strlen(delimiter);
  if (delimiter_length == 0)
    return NULL;
  start_ptr = *str;
  cur_delimiter = 0;
  while (**str) {
    (*match_length)++;
    if (**str == *(delimiter + cur_delimiter)) {
      cur_delimiter++;
      if (cur_delimiter == delimiter_length) {
        (*match_length) -= delimiter_length;
        (*str)++;
        break;
      }
    } else {
      if (**str == *delimiter)
        cur_delimiter = 1;
      else
        cur_delimiter = 0;
    }
    (*str)++;
  }
  if (cur_delimiter != delimiter_length)
    *match_length = 0;
  return start_ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tu_strbtok>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    (%rdi),%r9
  test   %r9,%r9
  je     L70
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L9
  mov    (%rbx),%r9
  cmpb   $0x0,(%r9)
  je     L92
  mov    $0x0,%esi
  jmp    L111
L21:
  sub    %esi,%edi
  mov    %edi,0x0(%rbp)
  addq   $0x1,(%rbx)
  jmp    L70
L113:
  cmp    %cl,(%r12)
  sete   %sil
  movzbl %sil,%esi
L49:
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rbx)
  cmpb   $0x0,0x1(%rdx)
  je     L112
L111:
  mov    0x0(%rbp),%edi
  lea    0x1(%rdi),%edx
  mov    %edx,0x0(%rbp)
  mov    (%rbx),%rdx
  movzbl (%rdx),%ecx
  mov    %esi,%r8d
  cmp    (%r12,%r8,1),%cl
  jne    L113
  lea    0x1(%rsi),%ecx
  cmp    %ecx,%eax
  je     L21
  mov    %ecx,%esi
  jmp    L49
L112:
  cmp    %eax,%esi
  je     L70
L92:
  movl   $0x0,0x0(%rbp)
L70:
  mov    %r9,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  mov    %rdi,%r9
  jmp    L70
L9:
  mov    $0x0,%r9d
  jmp    L70
```

assistant: ```c
char *tu_strbtok(char **str, unsigned int *match_length, const char *delimiter) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiter_length;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiter_length = strlen(delimiter);
  if (delimiter_length == 0)
    return NULL;
  start_ptr = *str;
  cur_delimiter = 0;
  while (**str) {
    (*match_length)++;
    if (**str == *(delimiter + cur_delimiter)) {
      cur_delimiter++;
      if (cur_delimiter == delimiter_length) {
        (*match_length) -= delimiter_length;
        (*str)++;
        break;
      }
    } else {
      if (**str == *delimiter)
        cur_delimiter = 1;
      else
        cur_delimiter = 0;
    }
    (*str)++;
  }
  if (cur_delimiter != delimiter_length)
    *match_length = 0;
  return start_ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tu_strbtok>:
  endbr64
  movl   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L16
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  je     L11
  mov    %rdx,%rdi
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L11
  mov    0x0(%rbp),%r10
  cmpb   $0x0,(%r10)
  je     L60
  mov    (%r12),%esi
  mov    %r10,%rcx
  xor    %r8d,%r8d
  jmp    L9
  nopl   0x0(%rax)
L24:
  xor    %r8d,%r8d
  cmp    %dil,(%rbx)
  sete   %r8b
  add    $0x1,%rcx
  mov    %rcx,0x0(%rbp)
  cmpb   $0x0,(%rcx)
  je     L32
L9:
  mov    %esi,%r9d
  mov    %r8d,%edx
  add    $0x1,%esi
  mov    %esi,(%r12)
  movzbl (%rcx),%edi
  cmp    (%rbx,%rdx,1),%dil
  jne    L24
  lea    0x1(%r8),%edx
  cmp    %edx,%eax
  je     L88
  add    $0x1,%rcx
  mov    %edx,%r8d
  mov    %rcx,0x0(%rbp)
  cmpb   $0x0,(%rcx)
  jne    L9
L32:
  cmp    %eax,%r8d
  je     L89
L60:
  movl   $0x0,(%r12)
L89:
  pop    %rbx
  mov    %r10,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %r10d,%r10d
  pop    %rbx
  pop    %rbp
  mov    %r10,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  sub    %r8d,%r9d
  add    $0x1,%rcx
  mov    %r10,%rax
  mov    %r9d,(%r12)
  mov    %rcx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *tu_strbtok(char **str, unsigned int *match_length, const char *delimiter) {
  char *start_ptr;
  unsigned int cur_delimiter, delimiter_length;
  *match_length = 0;
  if (str == NULL || *str == NULL)
    return NULL;
  delimiter_length = strlen(delimiter);
  if (delimiter_length == 0)
    return NULL;
  start_ptr = *str;
  cur_delimiter = 0;
  while (**str) {
    (*match_length)++;
    if (**str == *(delimiter + cur_delimiter)) {
      cur_delimiter++;
      if (cur_delimiter == delimiter_length) {
        (*match_length) -= delimiter_length;
        (*str)++;
        break;
      }
    } else {
      if (**str == *delimiter)
        cur_delimiter = 1;
      else
        cur_delimiter = 0;
    }
    (*str)++;
  }
  if (cur_delimiter != delimiter_length)
    *match_length = 0;
  return start_ptr;
}
```