ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<unlock_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,%edi
  call   <unlock_fd@plt>
  leave
  ret
```

assistant: ```c
int unlock_file(FILE *f) {
  assert(f);
  return unlock_fd(fileno(f));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unlock_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <fileno@plt>
  mov    %eax,%edi
  call   <unlock_fd@plt>
  pop    %rbx
  ret
```

assistant: ```c
int unlock_file(FILE *f) {
  assert(f);
  return unlock_fd(fileno(f));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unlock_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fileno@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1090 <unlock_fd@plt>
```

assistant: ```c
int unlock_file(FILE *f) {
  assert(f);
  return unlock_fd(fileno(f));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<unlock_file>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fileno@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1090 <unlock_fd@plt>
```

assistant: ```c
int unlock_file(FILE *f) {
  assert(f);
  return unlock_fd(fileno(f));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<meanarray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float meanarray(int *array, int b) {
  int total = 0;
  for (int i = 0; i < b; ++i) {
    total += array[i];
  }
  return (double)total / b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<meanarray>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L26:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L26
L29:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L24:
  mov    $0x0,%edx
  jmp    L29
```

assistant: ```c
float meanarray(int *array, int b) {
  int total = 0;
  for (int i = 0; i < b; ++i) {
    total += array[i];
  }
  return (double)total / b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<meanarray>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  jne    L5
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

assistant: ```c
float meanarray(int *array, int b) {
  int total = 0;
  for (int i = 0; i < b; ++i) {
    total += array[i];
  }
  return (double)total / b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<meanarray>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L58
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L30:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L30
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L26
L39:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L26
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L26
  add    0x8(%rdx,%r8,1),%eax
L26:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L11:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
L58:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
float meanarray(int *array, int b) {
  int total = 0;
  for (int i = 0; i < b; ++i) {
    total += array[i];
  }
  return (double)total / b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strupr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strupr(str)
char *str;
{
  char *ptr = str;
  while (*ptr) {
    *ptr = toupper(*ptr);
    ptr++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strupr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L13
  mov    %rbp,%rbx
L4:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L4
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strupr(str)
char *str;
{
  char *ptr = str;
  while (*ptr) {
    *ptr = toupper(*ptr);
    ptr++;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
  mov    %r12,%rbx
  nopl   0x0(%rax)
L5:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strupr(str)
char *str;
{
  char *ptr = str;
  while (*ptr) {
    *ptr = toupper(*ptr);
    ptr++;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
  mov    %r12,%rbx
  nopl   0x0(%rax)
L18:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strupr(str)
char *str;
{
  char *ptr = str;
  while (*ptr) {
    *ptr = toupper(*ptr);
    ptr++;
  }
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L24
  mov    -0x8(%rbp),%rax
  jmp    L33
L24:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  const char *ptr = str;
  while (*ptr) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr++;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
L10:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L9
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  const char *ptr = str;
  while (*ptr) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    %esi,%edx
  je     L21
  add    $0x1,%rdi
L26:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  const char *ptr = str;
  while (*ptr) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<strchr>:
  endbr64
  jmp    L20
  cs nopw 0x0(%rax,%rax,1)
L3:
  cmp    %esi,%edx
  je     L22
  add    $0x1,%rdi
L20:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  const char *ptr = str;
  while (*ptr) {
    if (*ptr == c) {
      return (char *)ptr;
    }
    ptr++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clear_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x48,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x50,%rax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x58,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x60,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x68,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x70,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x78,%rax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void clear_matrix(double *matrix) {
  matrix[0] = 1;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = 1;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = 1;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = 0;
  matrix[15] = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_matrix>:
  endbr64
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,(%rdi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  movsd  %xmm0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x40(%rdi)
  movq   $0x0,0x48(%rdi)
  movsd  %xmm0,0x50(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  movsd  %xmm0,0x78(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void clear_matrix(double *matrix) {
  matrix[0] = 1;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = 1;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = 1;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = 0;
  matrix[15] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clear_matrix>:
  endbr64
  movsd  D8(%rip),%xmm0
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x40(%rdi)
  movq   $0x0,0x48(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  movsd  %xmm0,(%rdi)
  movsd  %xmm0,0x28(%rdi)
  movsd  %xmm0,0x50(%rdi)
  movsd  %xmm0,0x78(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void clear_matrix(double *matrix) {
  matrix[0] = 1;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = 1;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = 1;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = 0;
  matrix[15] = 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<clear_matrix>:
  endbr64
  movq   D1(%rip),%xmm2
  movapd D2(%rip),%xmm1
  pxor   %xmm0,%xmm0
  movups %xmm0,0x10(%rdi)
  movups %xmm2,(%rdi)
  movups %xmm1,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm2,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  movups %xmm1,0x70(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D2
type_guessed: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void clear_matrix(double *matrix) {
  matrix[0] = 1;
  matrix[1] = 0;
  matrix[2] = 0;
  matrix[3] = 0;
  matrix[4] = 0;
  matrix[5] = 1;
  matrix[6] = 0;
  matrix[7] = 0;
  matrix[8] = 0;
  matrix[9] = 0;
  matrix[10] = 1;
  matrix[11] = 0;
  matrix[12] = 0;
  matrix[13] = 0;
  matrix[14] = 0;
  matrix[15] = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L19:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L13
  mov    $0x1,%eax
  jmp    L17
L13:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int compare(const char *s1, const char *s2, int b) {
  int i;
  for (i = 0; i < b; ++i) {
    if (*s1++ != *s2++)
      return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
L21:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L22
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
  mov    $0x0,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int compare(const char *s1, const char *s2, int b) {
  int i;
  for (i = 0; i < b; ++i) {
    if (*s1++ != *s2++)
      return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L24
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L12
  nop
L10:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L24
L12:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L10
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int compare(const char *s1, const char *s2, int b) {
  int i;
  for (i = 0; i < b; ++i) {
    if (*s1++ != *s2++)
      return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare>:
  endbr64
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L10
  nop
L1:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L9
L10:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L1
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int compare(const char *s1, const char *s2, int b) {
  int i;
  for (i = 0; i < b; ++i) {
    if (*s1++ != *s2++)
      return (1);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clone_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imatrix@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <memcpy_imatrix@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **clone_imatrix(int **const m, const size_t nrow, const size_t ncol) {
  int **m2 = imatrix(nrow, ncol);
  memcpy_imatrix(m2, m, nrow, ncol);
  return m2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clone_imatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdx,%rsi
  mov    %rbp,%rdi
  call   <imatrix@plt>
  mov    %rax,%rbx
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy_imatrix@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **clone_imatrix(int **const m, const size_t nrow, const size_t ncol) {
  int **m2 = imatrix(nrow, ncol);
  memcpy_imatrix(m2, m, nrow, ncol);
  return m2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clone_imatrix>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <imatrix@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy_imatrix@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int **clone_imatrix(int **const m, const size_t nrow, const size_t ncol) {
  int **m2 = imatrix(nrow, ncol);
  memcpy_imatrix(m2, m, nrow, ncol);
  return m2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_char_code_common>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,0x8(%rsp)
  mov    (%rdi),%rbx
  movsbl (%rbx),%r13d
  movsbl 0x1(%rbx),%r15d
  mov    %r15d,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L181
  add    $0x1,%rbx
L162:
  mov    $0x0,%r15d
  test   %rbp,%rbp
  je     L41
  cmpb   $0x7e,(%rbx)
  je     L112
L41:
  cmp    $0x20,%r12b
  je     L37
  test   %r12b,%r12b
  je     L74
  cmp    %r12b,(%rbx)
  jne    L206
  add    $0x1,%rbx
L74:
  mov    %r13d,%eax
  or     %r15d,%eax
  js     L190
  mov    %rbx,(%r14)
L190:
  test   %rbp,%rbp
  je     L141
  mov    %r15d,0x0(%rbp)
L141:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L181:
  add    $0x2,%rbx
  mov    %r13d,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L129
  mov    $0xffffffff,%r13d
  jmp    L162
L129:
  mov    %r15d,%esi
  mov    %r13d,%edi
  call   <two_char_as_hex@plt>
  mov    %eax,%r13d
  mov    0x8(%rsp),%eax
  or     %r13d,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r13d
  jmp    L162
L112:
  movsbl 0x1(%rbx),%r15d
  movsbl 0x2(%rbx),%eax
  mov    %eax,0xc(%rsp)
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L17
  add    $0x2,%rbx
  jmp    L41
L17:
  add    $0x3,%rbx
  mov    %r15d,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L91
  mov    $0xffffffff,%r15d
  jmp    L41
L91:
  mov    0xc(%rsp),%esi
  mov    %r15d,%edi
  call   <two_char_as_hex@plt>
  mov    %eax,%r15d
  mov    0x8(%rsp),%eax
  or     %r15d,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r15d
  jmp    L41
L37:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L182
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L11
L182:
  mov    %rbx,%rdi
  call   <skip_whitespace@plt>
  mov    %rax,%rbx
  jmp    L74
L11:
  mov    %eax,%r13d
  jmp    L74
L206:
  mov    $0xffffffff,%r13d
  jmp    L190
```

assistant: ```c
int parse_char_code_common(char **_s, int *comp, char terminator, int zeroOk) {
  char *s = *_s;
  int cc, cc2;
  char follower;
  cc = *(s++);
  follower = *s;
  if (isxdigit(follower)) {
    s++;
    if (isxdigit(cc))
      cc = two_char_as_hex(cc, follower);
    else
      cc = -1;
    if ((!zeroOk) && (cc == 0))
      cc = -1;
  }
  cc2 = 0;
  if ((comp != NULL) && (*s != '~'))
    ;
  else if ((comp != NULL) && (*s == '~')) {
    s++;
    cc2 = *(s++);
    follower = *s;
    if (isxdigit(follower)) {
      s++;
      if (isxdigit(cc2))
        cc2 = two_char_as_hex(cc2, follower);
      else
        cc2 = -1;
      if ((!zeroOk) && (cc2 == 0))
        cc2 = -1;
    }
  }
  if (terminator == ' ') {
    if ((*s != 0) && (!isspace(*s)))
      cc = 0;
    else
      s = skip_whitespace(s);
  } else if (terminator != 0) {
    if (*s != terminator)
      cc = -1;
    else
      s++;
  }
  if ((cc >= 0) && (cc2 >= 0))
    *_s = s;
  if (comp != NULL)
    *comp = cc2;
  return cc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SniffPcap_Close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L4:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int SniffPcap_Close(FILE *fp) {
  if (fp) {
    fflush(NULL);
    fclose(fp);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SniffPcap_Close>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <fflush@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int SniffPcap_Close(FILE *fp) {
  if (fp) {
    fflush(NULL);
    fclose(fp);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SniffPcap_Close>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int SniffPcap_Close(FILE *fp) {
  if (fp) {
    fflush(NULL);
    fclose(fp);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<SniffPcap_Close>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int SniffPcap_Close(FILE *fp) {
  if (fp) {
    fflush(NULL);
    fclose(fp);
  }
  return 0;
}
```