ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hc_fftw_to_half_mx>:
  endbr64
  mov    %rcx,%rax
  and    $0x1,%eax
  je     L44
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movq   $0x0,(%rsi)
  lea    0x1(%rcx),%r9
  mov    %r9,%r8
  sar    %r8
  cmp    $0x3,%r9
  jle    L42
  lea    -0x8(%rdx,%rcx,8),%rcx
L24:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  sub    $0x8,%rcx
  cmp    %r8,%rax
  jne    L24
  ret
L44:
  mov    %rcx,%r8
  sar    %r8
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movq   $0x0,(%rsi)
  cmp    $0x3,%rcx
  jle    L3
  lea    -0x8(%rdx,%rcx,8),%rcx
  mov    $0x1,%eax
L36:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  sub    $0x8,%rcx
  cmp    %rax,%r8
  jne    L36
L3:
  movsd  (%rdx,%r8,8),%xmm0
  movsd  %xmm0,(%rdi,%r8,8)
  movq   $0x0,(%rsi,%r8,8)
L42:
  ret
```

assistant: ```c
void hc_fftw_to_half_mx(register double *Xr, register double *Xi, register double *X, long N) {
  register long k;
  long Nover2 = N >> 1;
  if (N & 1) {
    Xr[0] = X[0];
    Xi[0] = 0.0;
    for (k = 1; k < ((N + 1) >> 1); ++k) {
      Xr[k] = X[k];
      Xi[k] = X[N - k];
    }
  } else {
    Xr[0] = X[0];
    Xi[0] = 0.0;
    for (k = 1; k < (Nover2); ++k) {
      Xr[k] = X[k];
      Xi[k] = X[N - k];
    }
    Xr[Nover2] = X[Nover2];
    Xi[Nover2] = 0.0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hc_fftw_to_half_mx>:
  endbr64
  mov    %rcx,%rax
  movsd  (%rdx),%xmm0
  and    $0x1,%eax
  je     L23
  lea    0x1(%rcx),%r9
  movsd  %xmm0,(%rdi)
  lea    -0x8(%rdx,%rcx,8),%rcx
  mov    %r9,%r8
  movq   $0x0,(%rsi)
  sar    %r8
  cmp    $0x3,%r9
  jle    L17
L4:
  movsd  (%rdx,%rax,8),%xmm0
  sub    $0x8,%rcx
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  0x8(%rcx),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
  nopl   0x0(%rax)
L23:
  mov    %rcx,%r8
  movsd  %xmm0,(%rdi)
  sar    %r8
  movq   $0x0,(%rsi)
  cmp    $0x3,%rcx
  jle    L27
  lea    -0x8(%rdx,%rcx,8),%rcx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L45:
  movsd  (%rdx,%rax,8),%xmm0
  sub    $0x8,%rcx
  movsd  %xmm0,(%rdi,%rax,8)
  movsd  0x8(%rcx),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L45
L27:
  movsd  (%rdx,%r8,8),%xmm0
  movsd  %xmm0,(%rdi,%r8,8)
  movq   $0x0,(%rsi,%r8,8)
  ret
```

assistant: ```c
void hc_fftw_to_half_mx(register double *Xr, register double *Xi, register double *X, long N) {
  register long k;
  long Nover2 = N >> 1;
  if (N & 1) {
    Xr[0] = X[0];
    Xi[0] = 0.0;
    for (k = 1; k < ((N + 1) >> 1); ++k) {
      Xr[k] = X[k];
      Xi[k] = X[N - k];
    }
  } else {
    Xr[0] = X[0];
    Xi[0] = 0.0;
    for (k = 1; k < (Nover2); ++k) {
      Xr[k] = X[k];
      Xi[k] = X[N - k];
    }
    Xr[Nover2] = X[Nover2];
    Xi[Nover2] = 0.0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<md_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L1
  cmpl   $0x0,-0x34(%rbp)
  jg     L69
L1:
  mov    $0x0,%eax
  jmp    L83
L69:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_get_data@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_next@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L94
  cmpq   $0x0,-0x8(%rbp)
  je     L94
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    %eax,-0x14(%rbp)
L94:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_get_init@plt>
  test   %rax,%rax
  je     L3
  cmpl   $0x0,-0x14(%rbp)
  jle    L3
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EVP_DigestUpdate@plt>
  test   %eax,%eax
  jne    L3
  mov    -0x28(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <BIO_clear_flags@plt>
  mov    $0x0,%eax
  jmp    L83
L3:
  cmpq   $0x0,-0x8(%rbp)
  je     L33
  mov    -0x28(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <BIO_clear_flags@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_copy_next_retry@plt>
L33:
  mov    -0x14(%rbp),%eax
L83:
  leave
  ret
```

assistant: ```c
int md_write(BIO *b, const char *in, int inl) {
  int ret = 0;
  EVP_MD_CTX *ctx;
  BIO *next;
  if ((in == NULL) || (inl <= 0))
    return 0;
  ctx = BIO_get_data(b);
  next = BIO_next(b);
  if ((ctx != NULL) && (next != NULL))
    ret = BIO_write(next, in, inl);
  if (BIO_get_init(b)) {
    if (ret > 0) {
      if (!EVP_DigestUpdate(ctx, (const unsigned char *)in, (unsigned int)ret)) {
        BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
        return 0;
      }
    }
  }
  if (next != NULL) {
    BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
    BIO_copy_next_retry(b);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<md_write>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L78
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r14d
  test   %edx,%edx
  jle    L78
  call   <BIO_get_data@plt>
  mov    %rax,%r13
  mov    %rbx,%rdi
  call   <BIO_next@plt>
  mov    %rax,%r12
  test   %r13,%r13
  je     L45
  test   %rax,%rax
  jne    L5
L45:
  mov    %rbx,%rdi
  call   <BIO_get_init@plt>
  test   %r12,%r12
  je     L26
  mov    $0x0,%r12d
L62:
  mov    $0xf,%esi
  mov    %rbx,%rdi
  call   <BIO_clear_flags@plt>
  mov    %rbx,%rdi
  call   <BIO_copy_next_retry@plt>
  jmp    L26
L5:
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <BIO_get_init@plt>
  test   %r12d,%r12d
  jle    L62
  test   %rax,%rax
  je     L62
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <EVP_DigestUpdate@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L62
  mov    $0xf,%esi
  mov    %rbx,%rdi
  call   <BIO_clear_flags@plt>
  mov    %ebp,%r12d
  jmp    L26
L78:
  mov    $0x0,%r12d
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int md_write(BIO *b, const char *in, int inl) {
  int ret = 0;
  EVP_MD_CTX *ctx;
  BIO *next;
  if ((in == NULL) || (inl <= 0))
    return 0;
  ctx = BIO_get_data(b);
  next = BIO_next(b);
  if ((ctx != NULL) && (next != NULL))
    ret = BIO_write(next, in, inl);
  if (BIO_get_init(b)) {
    if (ret > 0) {
      if (!EVP_DigestUpdate(ctx, (const unsigned char *)in, (unsigned int)ret)) {
        BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
        return 0;
      }
    }
  }
  if (next != NULL) {
    BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
    BIO_copy_next_retry(b);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<md_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  test   %rsi,%rsi
  je     L31
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L31
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <BIO_get_data@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <BIO_next@plt>
  mov    %rax,%r15
  test   %r14,%r14
  je     L44
  test   %rax,%rax
  jne    L41
L44:
  mov    %rbp,%rdi
  call   <BIO_get_init@plt>
  test   %r15,%r15
  jne    L62
L31:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13d,%eax
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L41:
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <BIO_get_init@plt>
  test   %rax,%rax
  je     L70
  test   %r13d,%r13d
  jle    L70
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <EVP_DigestUpdate@plt>
  test   %eax,%eax
  je     L67
L70:
  mov    %rbp,%rdi
  mov    $0xf,%esi
  call   <BIO_clear_flags@plt>
  mov    %rbp,%rdi
  call   <BIO_copy_next_retry@plt>
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  xor    %r13d,%r13d
  jmp    L70
  nopl   (%rax)
L67:
  mov    $0xf,%esi
  mov    %rbp,%rdi
  call   <BIO_clear_flags@plt>
  jmp    L31
```

assistant: ```c
int md_write(BIO *b, const char *in, int inl) {
  int ret = 0;
  EVP_MD_CTX *ctx;
  BIO *next;
  if ((in == NULL) || (inl <= 0))
    return 0;
  ctx = BIO_get_data(b);
  next = BIO_next(b);
  if ((ctx != NULL) && (next != NULL))
    ret = BIO_write(next, in, inl);
  if (BIO_get_init(b)) {
    if (ret > 0) {
      if (!EVP_DigestUpdate(ctx, (const unsigned char *)in, (unsigned int)ret)) {
        BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
        return 0;
      }
    }
  }
  if (next != NULL) {
    BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
    BIO_copy_next_retry(b);
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<md_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  test   %rsi,%rsi
  je     L3
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L3
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <BIO_get_data@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <BIO_next@plt>
  mov    %rax,%r15
  test   %r14,%r14
  je     L69
  test   %rax,%rax
  jne    L68
L69:
  mov    %rbp,%rdi
  call   <BIO_get_init@plt>
  test   %r15,%r15
  jne    L63
L3:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13d,%eax
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L68:
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <BIO_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <BIO_get_init@plt>
  test   %rax,%rax
  je     L7
  test   %r13d,%r13d
  jle    L7
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <EVP_DigestUpdate@plt>
  test   %eax,%eax
  je     L19
L7:
  mov    %rbp,%rdi
  mov    $0xf,%esi
  call   <BIO_clear_flags@plt>
  mov    %rbp,%rdi
  call   <BIO_copy_next_retry@plt>
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  xor    %r13d,%r13d
  jmp    L7
  nopl   (%rax)
L19:
  mov    $0xf,%esi
  mov    %rbp,%rdi
  call   <BIO_clear_flags@plt>
  jmp    L3
```

assistant: ```c
int md_write(BIO *b, const char *in, int inl) {
  int ret = 0;
  EVP_MD_CTX *ctx;
  BIO *next;
  if ((in == NULL) || (inl <= 0))
    return 0;
  ctx = BIO_get_data(b);
  next = BIO_next(b);
  if ((ctx != NULL) && (next != NULL))
    ret = BIO_write(next, in, inl);
  if (BIO_get_init(b)) {
    if (ret > 0) {
      if (!EVP_DigestUpdate(ctx, (const unsigned char *)in, (unsigned int)ret)) {
        BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
        return 0;
      }
    }
  }
  if (next != NULL) {
    BIO_clear_flags(b, ((0x01 | 0x02 | 0x04) | 0x08));
    BIO_copy_next_retry(b);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_servers_ports>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2000,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L37
L30:
  mov    -0x28(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  lea    -0x20(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L28
L10:
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x2c(%rbp)
  addl   $0x1,-0x24(%rbp)
L28:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x24(%rbp)
  jb     L10
  mov    -0x28(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x28(%rbp)
L37:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jb     L30
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string

tool: D10: :

assistant: ```c
int *get_servers_ports(char **servers_list, int servers_amount) {
  char *server_raw, *port_string;
  int server_port;
  int *servers_ports = malloc(1024 * sizeof(int *));
  unsigned int i, j;
  for (i = 0; i < servers_amount; i++) {
    server_raw = strdup(servers_list[i]);
    strsep(&server_raw, ":");
    port_string = strsep(&server_raw, ":");
    server_port = 0;
    for (j = 0; j < strlen(port_string); j++) {
      server_port = server_port * 10 + (port_string[j] - '0');
    }
    servers_ports[i] = server_port;
  }
  return servers_ports;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_servers_ports>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x2000,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  test   %ebx,%ebx
  je     L50
  lea    -0x1(%rbx),%eax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r13d
  lea    D9(%rip),%r14
  jmp    L46
L59:
  lea    0x0(%rbp,%rbp,4),%edx
  mov    %ebx,%eax
  movsbl (%r12,%rax,1),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%ebx
L27:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L59
  mov    (%rsp),%rax
  mov    %ebp,(%rax,%r13,4)
  lea    0x1(%r13),%rax
  cmp    0x8(%rsp),%r13
  je     L50
  mov    %rax,%r13
L46:
  mov    (%r15,%r13,8),%rdi
  call   <strdup@plt>
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strsep@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strsep@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L27
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    (%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: :

assistant: ```c
int *get_servers_ports(char **servers_list, int servers_amount) {
  char *server_raw, *port_string;
  int server_port;
  int *servers_ports = malloc(1024 * sizeof(int *));
  unsigned int i, j;
  for (i = 0; i < servers_amount; i++) {
    server_raw = strdup(servers_list[i]);
    strsep(&server_raw, ":");
    port_string = strsep(&server_raw, ":");
    server_port = 0;
    for (j = 0; j < strlen(port_string); j++) {
      server_port = server_port * 10 + (port_string[j] - '0');
    }
    servers_ports[i] = server_port;
  }
  return servers_ports;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_servers_ports>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x10(%rsp)
  mov    $0x2000,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r13d,%r13d
  je     L8
  mov    %r13d,%eax
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r12
  mov    %rax,0x18(%rsp)
  lea    D6(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    0x10(%rsp),%rax
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  mov    (%rax,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,0x20(%rsp)
  call   <strsep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strsep@plt>
  mov    %rax,%r15
  jmp    L23
  nopl   0x0(%rax)
L4:
  mov    %r14d,%eax
  lea    0x0(%r13,%r13,4),%ecx
  add    $0x1,%r14d
  movsbl (%r15,%rax,1),%eax
  lea    -0x30(%rax,%rcx,2),%r13d
L23:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  ja     L4
  mov    0x8(%rsp),%rax
  mov    %r13d,(%rax,%rbx,4)
  add    $0x1,%rbx
  cmp    0x18(%rsp),%rbx
  jne    L19
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    0x8(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: :

assistant: ```c
int *get_servers_ports(char **servers_list, int servers_amount) {
  char *server_raw, *port_string;
  int server_port;
  int *servers_ports = malloc(1024 * sizeof(int *));
  unsigned int i, j;
  for (i = 0; i < servers_amount; i++) {
    server_raw = strdup(servers_list[i]);
    strsep(&server_raw, ":");
    port_string = strsep(&server_raw, ":");
    server_port = 0;
    for (j = 0; j < strlen(port_string); j++) {
      server_port = server_port * 10 + (port_string[j] - '0');
    }
    servers_ports[i] = server_port;
  }
  return servers_ports;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_servers_ports>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x10(%rsp)
  mov    $0x2000,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r13d,%r13d
  je     L20
  mov    %r13d,%eax
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r12
  mov    %rax,0x18(%rsp)
  lea    D3(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x10(%rsp),%rax
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  mov    (%rax,%rbx,8),%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,0x20(%rsp)
  call   <strsep@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strsep@plt>
  mov    %rax,%r15
  jmp    L41
  nopl   0x0(%rax)
L10:
  mov    %r14d,%eax
  lea    0x0(%r13,%r13,4),%ecx
  add    $0x1,%r14d
  movsbl (%r15,%rax,1),%eax
  lea    -0x30(%rax,%rcx,2),%r13d
L41:
  mov    %r15,%rdi
  call   <strlen@plt>
  cmp    %r14d,%eax
  ja     L10
  mov    0x8(%rsp),%rax
  mov    %r13d,(%rax,%rbx,4)
  add    $0x1,%rbx
  cmp    0x18(%rsp),%rbx
  jne    L17
L20:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    0x8(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: :

assistant: ```c
int *get_servers_ports(char **servers_list, int servers_amount) {
  char *server_raw, *port_string;
  int server_port;
  int *servers_ports = malloc(1024 * sizeof(int *));
  unsigned int i, j;
  for (i = 0; i < servers_amount; i++) {
    server_raw = strdup(servers_list[i]);
    strsep(&server_raw, ":");
    port_string = strsep(&server_raw, ":");
    server_port = 0;
    for (j = 0; j < strlen(port_string); j++) {
      server_port = server_port * 10 + (port_string[j] - '0');
    }
    servers_ports[i] = server_port;
  }
  return servers_ports;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PicocParseInteractive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <PlatformPrintf@plt>
  mov    $0x1,%edi
  call   <PicocParseInteractiveNoStartPrompt@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: starting picoc v2.2


assistant: ```c
void PicocParseInteractive() {
  PlatformPrintf("starting picoc "
                 "v2.2"
                 "\n");
  PicocParseInteractiveNoStartPrompt(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<PicocParseInteractive>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <PlatformPrintf@plt>
  mov    $0x1,%edi
  call   <PicocParseInteractiveNoStartPrompt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: starting picoc v2.2


assistant: ```c
void PicocParseInteractive() {
  PlatformPrintf("starting picoc "
                 "v2.2"
                 "\n");
  PicocParseInteractiveNoStartPrompt(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PicocParseInteractive>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <PlatformPrintf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <PicocParseInteractiveNoStartPrompt@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: starting picoc v2.2


assistant: ```c
void PicocParseInteractive() {
  PlatformPrintf("starting picoc "
                 "v2.2"
                 "\n");
  PicocParseInteractiveNoStartPrompt(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PicocParseInteractive>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <PlatformPrintf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <PicocParseInteractiveNoStartPrompt@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: starting picoc v2.2


assistant: ```c
void PicocParseInteractive() {
  PlatformPrintf("starting picoc "
                 "v2.2"
                 "\n");
  PicocParseInteractiveNoStartPrompt(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <prompt@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  prompt();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prompt@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  prompt();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prompt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  prompt();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MeasurePattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L28
  addl   $0x1,-0x8(%rbp)
  jmp    L10
L24:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L24
  addl   $0x1,-0x4(%rbp)
  jmp    L20
L28:
  addl   $0x1,-0x4(%rbp)
L20:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%edx
  cmp    %edx,%eax
  ja     L18
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int MeasurePattern(char *myPattern) {
  int j = 0;
  int size = 0;
  while ((unsigned int)j < strlen(myPattern)) {
    if (myPattern[j] == '[') {
      j++;
      while (myPattern[j] != ']') {
        j++;
      }
      size++;
    } else {
      size++;
    }
    j++;
  }
  return size;
}
```