ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<thetag>:
  endbr64
  movsd  D11(%rip),%xmm1
  pxor   %xmm2,%xmm2
  mov    %rdi,%rcx
  addsd  %xmm0,%xmm1
  mulsd  D69(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  movapd %xmm0,%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  D37(%rip),%xmm2
  lea    0x50(%rax),%edx
  cmp    $0xa,%eax
  cmovl  %edx,%eax
  lea    -0x45(%rax),%edx
  subsd  %xmm2,%xmm1
  cmp    $0x45,%eax
  jg     L7
  mov    %eax,%esi
  sub    $0x48,%esi
  cmovns %esi,%edx
L7:
  sub    $0x46,%eax
  sar    $0x2,%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm0
  cvtsi2sd %edx,%xmm2
  mulsd  D25(%rip),%xmm0
  addsd  D17(%rip),%xmm0
  addsd  %xmm2,%xmm0
  movsd  D26(%rip),%xmm2
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  mulsd  D28(%rip),%xmm0
  addsd  D59(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L19
  ret
  nopl   0x0(%rax)
L19:
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: byte[8]
name: retrieve_data
arguments: label: D69
type_guessed: byte[8]
name: retrieve_data
arguments: label: D37
type_guessed: f64
name: retrieve_data
arguments: label: D25
type_guessed: f64
name: retrieve_data
arguments: label: D17
type_guessed: f64
name: retrieve_data
arguments: label: D26
type_guessed: f64
name: retrieve_data
arguments: label: D28
type_guessed: f64
name: retrieve_data
arguments: label: D59
type_guessed: f64

tool: {"D11": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x8a,0x3e]}

tool: {"D69": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D37: 1000

tool: D25: 365

tool: D17: 7305

tool: D26: 6.283185307179586

tool: D28: 6.3003880987

tool: D59: 1.72944494

assistant: ```c
double thetag(double EP, double *DS50) {
  int JY, N, I;
  double YR, D, THETA, TEMP, THETAG;
  YR = (EP + 2.0E-7) * 1.0E-3;
  JY = (int)YR;
  YR = JY;
  D = EP - YR * 1.0E3;
  if (JY < 10)
    JY += 80;
  N = (JY - 69) / 4;
  if (JY < 70)
    N = (JY - 72) / 4;
  *DS50 = 7305.0 + 365.0 * (JY - 70) + N + D;
  THETA = 1.72944494 + 6.3003880987 * *DS50;
  TEMP = THETA / (6.2831853071795864770);
  I = (int)TEMP;
  TEMP = I;
  THETAG = THETA - TEMP * (6.2831853071795864770);
  if (THETAG < 0.0)
    THETAG += (6.2831853071795864770);
  return THETAG;
}
```
user: What is the c source code of the assembly code below:

```asm
<cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <file_destroy_all@plt>
  mov    $0x0,%eax
  call   <dir_destroy_all@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cleanup(void) {
  file_destroy_all();
  dir_destroy_all();
}
```
user: Translate the below assembly code into C programming language:

```asm
<cleanup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <file_destroy_all@plt>
  mov    $0x0,%eax
  call   <dir_destroy_all@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cleanup(void) {
  file_destroy_all();
  dir_destroy_all();
}
```
user: What is the c source code of the assembly code below?

```asm
<cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <file_destroy_all@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <dir_destroy_all@plt>
```

assistant: ```c
void cleanup(void) {
  file_destroy_all();
  dir_destroy_all();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <file_destroy_all@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <dir_destroy_all@plt>
```

assistant: ```c
void cleanup(void) {
  file_destroy_all();
  dir_destroy_all();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TestAesOfb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <TestVectors@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  movl   $0x0,-0x8(%rbp)
L6:
  mov    $0x0,%eax
  call   <TestLargeVector@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L28
  movl   $0x0,-0x8(%rbp)
L28:
  mov    $0x0,%eax
  call   <TestStreamConsistency@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  movl   $0x0,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool TestAesOfb(void) {
  bool totalSuccess = true;
  bool success;
  success = TestVectors();
  if (!success) {
    totalSuccess = false;
  }
  success = TestLargeVector();
  if (!success) {
    totalSuccess = false;
  }
  success = TestStreamConsistency();
  if (!success) {
    totalSuccess = false;
  }
  return totalSuccess;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TestAesOfb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <TestVectors@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <TestLargeVector@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L4
  test   %ebp,%ebp
  setne  %bl
  movzbl %bl,%ebx
L4:
  mov    $0x0,%eax
  call   <TestStreamConsistency@plt>
  test   %eax,%eax
  cmove  %eax,%ebx
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool TestAesOfb(void) {
  bool totalSuccess = true;
  bool success;
  success = TestVectors();
  if (!success) {
    totalSuccess = false;
  }
  success = TestLargeVector();
  if (!success) {
    totalSuccess = false;
  }
  success = TestStreamConsistency();
  if (!success) {
    totalSuccess = false;
  }
  return totalSuccess;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TestAesOfb>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <TestVectors@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <TestLargeVector@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L7
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L7:
  xor    %eax,%eax
  call   <TestStreamConsistency@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %eax,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
bool TestAesOfb(void) {
  bool totalSuccess = true;
  bool success;
  success = TestVectors();
  if (!success) {
    totalSuccess = false;
  }
  success = TestLargeVector();
  if (!success) {
    totalSuccess = false;
  }
  success = TestStreamConsistency();
  if (!success) {
    totalSuccess = false;
  }
  return totalSuccess;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TestAesOfb>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <TestVectors@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <TestLargeVector@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L9:
  xor    %eax,%eax
  call   <TestStreamConsistency@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %eax,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
bool TestAesOfb(void) {
  bool totalSuccess = true;
  bool success;
  success = TestVectors();
  if (!success) {
    totalSuccess = false;
  }
  success = TestLargeVector();
  if (!success) {
    totalSuccess = false;
  }
  success = TestStreamConsistency();
  if (!success) {
    totalSuccess = false;
  }
  return totalSuccess;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <do_guest@plt>
  leave
  ret
```

assistant: ```c
int do_start(char *username) {
  static char path[] = "/etc"
                       "/"
                       "ponyguests"
                       "/ponyguests-make-guest";
  return do_guest(path, username);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<do_start>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <do_guest@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int do_start(char *username) {
  static char path[] = "/etc"
                       "/"
                       "ponyguests"
                       "/ponyguests-make-guest";
  return do_guest(path, username);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_start>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <do_guest@plt>
```

assistant: ```c
int do_start(char *username) {
  static char path[] = "/etc"
                       "/"
                       "ponyguests"
                       "/ponyguests-make-guest";
  return do_guest(path, username);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_start>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <do_guest@plt>
```

assistant: ```c
int do_start(char *username) {
  static char path[] = "/etc"
                       "/"
                       "ponyguests"
                       "/ponyguests-make-guest";
  return do_guest(path, username);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L21
L19:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  lea    -0x9(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L21:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x9(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L19
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  while (read(STDIN_FILENO, &c, 1) != 0) {
    write(STDOUT_FILENO, &c, 1);
  }
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L17
L27:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <write@plt>
L17:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L27
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  while (read(STDIN_FILENO, &c, 1) != 0) {
    write(STDOUT_FILENO, &c, 1);
  }
  return EXIT_SUCCESS;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D0(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L3:
  mov    D26(%rip),%rax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    (%rax),%edi
  call   <write@plt>
L19:
  mov    0x0(%rbp),%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L3
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  while (read(STDIN_FILENO, &c, 1) != 0) {
    write(STDOUT_FILENO, &c, 1);
  }
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D11(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L3:
  mov    D8(%rip),%rax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    (%rax),%edi
  call   <write@plt>
L11:
  mov    0x0(%rbp),%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jne    L3
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  while (read(STDIN_FILENO, &c, 1) != 0) {
    write(STDOUT_FILENO, &c, 1);
  }
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string

tool: D25: printf:
	x + y = [%d]


tool: D9: x + y

tool: D10: PrintExpr:
	%s = [%d]


assistant: ```c
void print_test(int x, int y) {
  printf("printf:\n\tx + y = [%d]\n", x + y);
  (printf("PrintExpr:\n\t%s = [%d]\n", "x + y", (x + y)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_test>:
  endbr64
  push   %rbx
  lea    (%rdi,%rsi,1),%ebx
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  lea    D24(%rip),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string

tool: D5: printf:
	x + y = [%d]


tool: D24: x + y

tool: D27: PrintExpr:
	%s = [%d]


assistant: ```c
void print_test(int x, int y) {
  printf("printf:\n\tx + y = [%d]\n", x + y);
  (printf("PrintExpr:\n\t%s = [%d]\n", "x + y", (x + y)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_test>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12d
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string

tool: D6: printf:
	x + y = [%d]


tool: D9: x + y

tool: D16: PrintExpr:
	%s = [%d]


assistant: ```c
void print_test(int x, int y) {
  printf("printf:\n\tx + y = [%d]\n", x + y);
  (printf("PrintExpr:\n\t%s = [%d]\n", "x + y", (x + y)));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_test>:
  endbr64
  push   %r12
  lea    (%rdi,%rsi,1),%r12d
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  lea    D11(%rip),%rsi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string
name: parse_data
arguments: data_tag: D20
type_guessed: string

tool: D0: printf:
	x + y = [%d]


tool: D11: x + y

tool: D20: PrintExpr:
	%s = [%d]


assistant: ```c
void print_test(int x, int y) {
  printf("printf:\n\tx + y = [%d]\n", x + y);
  (printf("PrintExpr:\n\t%s = [%d]\n", "x + y", (x + y)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<selectionSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L32
L35:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L30
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L30:
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void selectionSort(int *a, int n) {
  int i, j = 0;
  int imin;
  int tmp;
  while (j < n) {
    imin = j;
    for (i = j; i < n; i++) {
      if (a[i] < a[imin]) {
        imin = i;
      }
    }
    tmp = a[j];
    a[j] = a[imin];
    a[imin] = tmp;
    j++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<selectionSort>:
  endbr64
  test   %esi,%esi
  jle    L1
  mov    %esi,%r9d
  mov    $0x0,%r8d
  jmp    L54
L59:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L59
L55:
  mov    (%rdi,%r8,4),%ecx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r8,4)
  mov    %ecx,(%rax)
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L1
L54:
  mov    %r8d,%edx
  mov    %r8,%rax
  cmp    %r8d,%esi
  jg     L59
  jmp    L55
L1:
  ret
```

assistant: ```c
void selectionSort(int *a, int n) {
  int i, j = 0;
  int imin;
  int tmp;
  while (j < n) {
    imin = j;
    for (i = j; i < n; i++) {
      if (a[i] < a[imin]) {
        imin = i;
      }
    }
    tmp = a[j];
    a[j] = a[imin];
    a[imin] = tmp;
    j++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<selectionSort>:
  endbr64
  test   %esi,%esi
  jle    L50
  push   %rbp
  xor    %r11d,%r11d
  push   %rbx
  mov    %rdi,%rbx
L29:
  mov    (%rdi),%ebp
  mov    %rdi,%rdx
  mov    %r11d,%r10d
  mov    %r11d,%eax
  mov    %ebp,%ecx
  mov    %ebp,%r8d
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %r10d,%rcx
  add    $0x1,%eax
  add    $0x4,%rdx
  lea    (%rbx,%rcx,4),%r9
  cmp    %eax,%esi
  jle    L0
L39:
  mov    (%rdx),%ecx
L21:
  cmp    %ecx,%r8d
  jle    L8
  mov    %eax,%r10d
  add    $0x1,%eax
  mov    %rdx,%r9
  mov    %ecx,%r8d
  add    $0x4,%rdx
  cmp    %eax,%esi
  jg     L39
L0:
  add    $0x1,%r11d
  mov    %r8d,(%rdi)
  add    $0x4,%rdi
  mov    %ebp,(%r9)
  cmp    %r11d,%esi
  jne    L29
  pop    %rbx
  pop    %rbp
  ret
L50:
  ret
```

assistant: ```c
void selectionSort(int *a, int n) {
  int i, j = 0;
  int imin;
  int tmp;
  while (j < n) {
    imin = j;
    for (i = j; i < n; i++) {
      if (a[i] < a[imin]) {
        imin = i;
      }
    }
    tmp = a[j];
    a[j] = a[imin];
    a[imin] = tmp;
    j++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<selectionSort>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %rbp
  xor    %r11d,%r11d
  push   %rbx
  mov    %rdi,%rbx
L2:
  mov    (%rdi),%ebp
  mov    %rdi,%rax
  mov    %r11d,%r10d
  mov    %r11d,%edx
  mov    %ebp,%r8d
  jmp    L22
L48:
  movslq %r10d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rbx,%rcx,4),%r9
  cmp    %edx,%esi
  jle    L26
L22:
  mov    (%rax),%ecx
  mov    %rax,%r9
  cmp    %ecx,%r8d
  jle    L48
  mov    %edx,%r10d
  add    $0x1,%edx
  mov    %ecx,%r8d
  add    $0x4,%rax
  cmp    %edx,%esi
  jg     L22
L26:
  add    $0x1,%r11d
  mov    %r8d,(%rdi)
  add    $0x4,%rdi
  mov    %ebp,(%r9)
  cmp    %r11d,%esi
  jne    L2
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
void selectionSort(int *a, int n) {
  int i, j = 0;
  int imin;
  int tmp;
  while (j < n) {
    imin = j;
    for (i = j; i < n; i++) {
      if (a[i] < a[imin]) {
        imin = i;
      }
    }
    tmp = a[j];
    a[j] = a[imin];
    a[imin] = tmp;
    j++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rj485_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L26:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <rj485_getc@plt>
  mov    %al,(%rbx)
L3:
  mov    $0x0,%eax
  call   <rj_readstat@plt>
  and    $0x4,%eax
  test   %eax,%eax
  je     L12
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L26
L12:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rj485_read(unsigned char *buf, int maxlen) {
  int i = 0;
  while ((rj_readstat() & 0x04) && (i < maxlen)) {
    buf[i++] = rj485_getc();
  }
  buf[i] = 0;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rj485_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L21:
  mov    %ebx,%r13d
  mov    $0x0,%eax
  call   <rj_readstat@plt>
  test   $0x4,%al
  je     L2
  cmp    %ebx,%r12d
  jle    L2
  mov    $0x0,%eax
  call   <rj485_getc@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L21
L2:
  movslq %r13d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rj485_read(unsigned char *buf, int maxlen) {
  int i = 0;
  while ((rj_readstat() & 0x04) && (i < maxlen)) {
    buf[i++] = rj485_getc();
  }
  buf[i] = 0;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rj485_read>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L7:
  cmp    %ebp,%r12d
  jge    L14
  xor    %eax,%eax
  add    $0x1,%r12d
  add    $0x1,%rbx
  call   <rj485_getc@plt>
  mov    %al,-0x1(%rbx)
L17:
  xor    %eax,%eax
  call   <rj_readstat@plt>
  test   $0x4,%al
  jne    L7
L14:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rj485_read(unsigned char *buf, int maxlen) {
  int i = 0;
  while ((rj_readstat() & 0x04) && (i < maxlen)) {
    buf[i++] = rj485_getc();
  }
  buf[i] = 0;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rj485_read>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L5:
  cmp    %ebp,%r12d
  jge    L20
  xor    %eax,%eax
  add    $0x1,%r12d
  add    $0x1,%rbx
  call   <rj485_getc@plt>
  mov    %al,-0x1(%rbx)
L18:
  xor    %eax,%eax
  call   <rj_readstat@plt>
  test   $0x4,%al
  jne    L5
L20:
  movb   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int rj485_read(unsigned char *buf, int maxlen) {
  int i = 0;
  while ((rj_readstat() & 0x04) && (i < maxlen)) {
    buf[i++] = rj485_getc();
  }
  buf[i] = 0;
  return i;
}
```