ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D38(%rip),%r15
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D59(%rip),%r13
  push   %r12
  push   %rbp
  lea    D28(%rip),%rbp
  push   %rbx
  lea    D46(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  lea    0x10(%rsp),%r12
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,(%rsp)
  jmp    L3
  nopl   (%rax)
L10:
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,0x8(%rsp)
L40:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L9
L3:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  jne    L10
  addl   $0x1,0xc(%rsp)
  jmp    L40
  nopl   (%rax)
L9:
  mov    0x8(%rsp),%ebx
  mov    0xc(%rsp),%ecx
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  lea    D25(%rip),%rdi
  mov    %ebx,%eax
  cvtsi2ss %ecx,%xmm0
  add    %ecx,%eax
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  movss  %xmm1,(%rsp)
  mulss  D27(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movss  (%rsp),%xmm1
  cvtsi2ss %ebx,%xmm0
  lea    D50(%rip),%rdi
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  mulss  D27(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D38
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D59
type: string
name: disassemble_data
arguments: label: D28
type: string
name: disassemble_data
arguments: label: D46
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D27
type: byte[4]
name: disassemble_data
arguments: label: D50
type: string

tool: D38: 1-Candidato 1 

tool: D12: 2-Candidato 2 

tool: D59: Escolha voto 

tool: D28: 
 Deseja continuar(1-s/0-n)

tool: D46: %d

tool: D25: 
Candidato 1 com %.2f%%

tool: {"D27": [0x00,0x00,0xc8,0x42]}

tool: D50: 
Candidato 2 com %.2f%% 


assistant: ```c
int main() {
  float perc1, perc2;
  int votos1 = 0, votos2 = 0, voto;
  int continuar;
  float total = 0.00;
  do {
    printf("1-Candidato 1 \n");
    printf("2-Candidato 2 \n");
    printf("Escolha voto \n");
    scanf("%d", &voto);
    if (voto == 1) {
      votos1++;
    }
    if (voto == 2) {
      votos2++;
    }
    printf("\n Deseja continuar(1-s/0-n)");
    scanf("%d", &continuar);
  } while (continuar == 1);
  total = votos1 + votos2;
  perc1 = (votos1 / total);
  perc2 = (votos2 / total);
  printf("\nCandidato 1 com %.2f%%", perc1 * 100);
  printf("\nCandidato 2 com %.2f%% \n", perc2 * 100);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<squareRoot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  D47(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D34(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x14(%rbp),%xmm0
  jbe    L24
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  D39(%rip),%xmm0
  jmp    L15
L24:
  jmp    L11
L39:
  movss  -0x14(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  D9(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
L11:
  movss  -0x8(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  subss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <absoluteValue@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm2
  comiss -0x4(%rbp),%xmm2
  jae    L39
  movss  -0x8(%rbp),%xmm0
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D47
data_type: byte[4]
name: unpack_data
arguments: data_tag: D34
data_type: f32
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D39
data_type: byte[4]
name: unpack_data
arguments: data_tag: D9
data_type: f32

tool: {"D47": [0xac,0xc5,0x27,0x37]}

tool: D34: 1

tool: D5: Negative argument to squareRoot.


tool: {"D39": [0x00,0x00,0x80,0xbf]}

tool: D9: 2

assistant: ```c
float squareRoot(float x) {
  const float episolon = .00001;
  float guess = 1.0;
  float absoluteValue(float x);
  if (x < 0) {
    printf("Negative argument to squareRoot.\n");
    return -1.0;
  }
  while (absoluteValue(guess * guess - x) >= episolon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<squareRoot>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm4
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  comiss %xmm4,%xmm0
  ja     L17
  movss  D8(%rip),%xmm5
  movss  %xmm5,0x8(%rsp)
  jmp    L25
L17:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  movss  D45(%rip),%xmm6
  movss  %xmm6,0x8(%rsp)
  jmp    L1
L26:
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm2
  divss  %xmm2,%xmm0
  addss  %xmm2,%xmm0
  mulss  D5(%rip),%xmm0
  movss  %xmm0,0x8(%rsp)
L25:
  movss  0x8(%rsp),%xmm1
  movaps %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  subss  0xc(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss D1(%rip),%xmm0
  jae    L26
L1:
  movss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: f32
name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D45
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D5
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D1
type_infered: byte[4]

tool: D8: 1

tool: D29: Negative argument to squareRoot.


tool: {"D45": [0x00,0x00,0x80,0xbf]}

tool: {"D5": [0x00,0x00,0x00,0x3f]}

tool: {"D1": [0xac,0xc5,0x27,0x37]}

assistant: ```c
float squareRoot(float x) {
  const float episolon = .00001;
  float guess = 1.0;
  float absoluteValue(float x);
  if (x < 0) {
    printf("Negative argument to squareRoot.\n");
    return -1.0;
  }
  while (absoluteValue(guess * guess - x) >= episolon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<squareRoot>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm3
  movss  D20(%rip),%xmm1
  movss  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comiss %xmm3,%xmm0
  jbe    L22
  jmp    L23
  nopl   0x0(%rax)
L4:
  movss  0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm1
  mulss  D19(%rip),%xmm1
L22:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm1,%xmm0
  subss  0x8(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss D12(%rip),%xmm0
  movss  0xc(%rsp),%xmm1
  jae    L4
  movaps %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L23:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  movss  D26(%rip),%xmm1
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
type: f32
name: read_data
arguments: data_label: D19
type: byte[4]
name: read_data
arguments: data_label: D12
type: byte[4]
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D26
type: byte[4]

tool: D20: 1

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: {"D12": [0xac,0xc5,0x27,0x37]}

tool: D23: Negative argument to squareRoot.


tool: {"D26": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float squareRoot(float x) {
  const float episolon = .00001;
  float guess = 1.0;
  float absoluteValue(float x);
  if (x < 0) {
    printf("Negative argument to squareRoot.\n");
    return -1.0;
  }
  while (absoluteValue(guess * guess - x) >= episolon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<squareRoot>:
  endbr64
  sub    $0x18,%rsp
  movaps %xmm0,%xmm3
  movss  D0(%rip),%xmm1
  movss  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comiss %xmm3,%xmm0
  jbe    L26
  jmp    L10
  nopl   0x0(%rax)
L21:
  movss  0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm1
  mulss  D37(%rip),%xmm1
L26:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm1,%xmm0
  subss  0x8(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss D41(%rip),%xmm0
  movss  0xc(%rsp),%xmm1
  jae    L21
  movaps %xmm1,%xmm0
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L10:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  movss  D34(%rip),%xmm1
  add    $0x18,%rsp
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: f32
name: disassemble_data
arguments: data_tag: D37
datatype: byte[4]
name: disassemble_data
arguments: data_tag: D41
datatype: byte[4]
name: disassemble_data
arguments: data_tag: D29
datatype: string
name: disassemble_data
arguments: data_tag: D34
datatype: byte[4]

tool: D0: 1

tool: {"D37": [0x00,0x00,0x00,0x3f]}

tool: {"D41": [0xac,0xc5,0x27,0x37]}

tool: D29: Negative argument to squareRoot.


tool: {"D34": [0x00,0x00,0x80,0xbf]}

assistant: ```c
float squareRoot(float x) {
  const float episolon = .00001;
  float guess = 1.0;
  float absoluteValue(float x);
  if (x < 0) {
    printf("Negative argument to squareRoot.\n");
    return -1.0;
  }
  while (absoluteValue(guess * guess - x) >= episolon)
    guess = (x / guess + guess) / 2.0;
  return guess;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <print_system_limits@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  print_system_limits();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_system_limits@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_system_limits();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_system_limits@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_system_limits();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_system_limits@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_system_limits();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  lea    0x0(,%rax,4),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    %edx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x64,%eax
  sub    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%eax
  sub    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  jmp    L0
L22:
  cmpl   $0x0,-0x4(%rbp)
  jne    L10
  addl   $0x2,-0xc(%rbp)
L10:
  cmpl   $0x1,-0x4(%rbp)
  jne    L32
  subl   $0x1,-0xc(%rbp)
L32:
  mov    $0x1,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  cmpl   $0x63,-0x8(%rbp)
  jle    L22
  cmpl   $0x32,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  cmpl   $0x64,-0xc(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int x = 0;
  int t = 0;
  int phase = 0;
  __ESBMC_assume(-3 * phase - t + 2 * x == 0);
  __ESBMC_assume(100 - phase - t >= 0);
  __ESBMC_assume(1 - phase >= 0);
  __ESBMC_assume(-phase + t >= 0);
  __ESBMC_assume(phase >= 0);
  while (t < 100) {
    if (phase == 0)
      x = x + 2;
    if (phase == 1)
      x = x - 1;
    phase = 1 - phase;
    t++;
  }
  __ESBMC_assume(-50 + x == 0);
  assert(x <= 100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x64,%edx
  mov    $0x0,%eax
  mov    $0x0,%ebx
  mov    $0x1,%ecx
  jmp    L23
L30:
  cmp    $0x1,%eax
  sete   %sil
  movzbl %sil,%esi
  sub    %esi,%ebx
L6:
  mov    %ecx,%edi
  sub    %eax,%edi
  mov    %edi,%eax
  sub    $0x1,%edx
  je     L32
L23:
  test   %eax,%eax
  jne    L30
  add    $0x2,%ebx
  jmp    L6
L32:
  cmp    $0x32,%ebx
  sete   %dil
  movzbl %dil,%edi
  call   <__ESBMC_assume@plt>
  cmp    $0x64,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  ret
```

assistant: ```c
void main() {
  int x = 0;
  int t = 0;
  int phase = 0;
  __ESBMC_assume(-3 * phase - t + 2 * x == 0);
  __ESBMC_assume(100 - phase - t >= 0);
  __ESBMC_assume(1 - phase >= 0);
  __ESBMC_assume(-phase + t >= 0);
  __ESBMC_assume(phase >= 0);
  while (t < 100) {
    if (phase == 0)
      x = x + 2;
    if (phase == 1)
      x = x - 1;
    phase = 1 - phase;
    t++;
  }
  __ESBMC_assume(-50 + x == 0);
  assert(x <= 100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  xor    %ebx,%ebx
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x64,%edx
  xor    %eax,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L9:
  lea    0x2(%rbx),%ecx
  mov    %esi,%edi
  sub    $0x1,%ebx
  test   %eax,%eax
  cmove  %ecx,%ebx
  sub    %eax,%edi
  mov    %edi,%eax
  sub    $0x1,%edx
  jne    L9
  xor    %edi,%edi
  cmp    $0x32,%ebx
  sete   %dil
  call   <__ESBMC_assume@plt>
  xor    %edi,%edi
  cmp    $0x64,%ebx
  pop    %rbx
  setle  %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
void main() {
  int x = 0;
  int t = 0;
  int phase = 0;
  __ESBMC_assume(-3 * phase - t + 2 * x == 0);
  __ESBMC_assume(100 - phase - t >= 0);
  __ESBMC_assume(1 - phase >= 0);
  __ESBMC_assume(-phase + t >= 0);
  __ESBMC_assume(phase >= 0);
  while (t < 100) {
    if (phase == 0)
      x = x + 2;
    if (phase == 1)
      x = x - 1;
    phase = 1 - phase;
    t++;
  }
  __ESBMC_assume(-50 + x == 0);
  assert(x <= 100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  xor    %ebx,%ebx
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x64,%edx
  xor    %eax,%eax
  mov    $0x1,%esi
  nopl   (%rax)
L1:
  lea    0x2(%rbx),%ecx
  mov    %esi,%edi
  sub    $0x1,%ebx
  test   %eax,%eax
  cmove  %ecx,%ebx
  sub    %eax,%edi
  mov    %edi,%eax
  sub    $0x1,%edx
  jne    L1
  xor    %edi,%edi
  cmp    $0x32,%ebx
  sete   %dil
  call   <__ESBMC_assume@plt>
  xor    %edi,%edi
  cmp    $0x64,%ebx
  pop    %rbx
  setle  %dil
  jmp    1060 <assert@plt>
```

assistant: ```c
void main() {
  int x = 0;
  int t = 0;
  int phase = 0;
  __ESBMC_assume(-3 * phase - t + 2 * x == 0);
  __ESBMC_assume(100 - phase - t >= 0);
  __ESBMC_assume(1 - phase >= 0);
  __ESBMC_assume(-phase + t >= 0);
  __ESBMC_assume(phase >= 0);
  while (t < 100) {
    if (phase == 0)
      x = x + 2;
    if (phase == 1)
      x = x - 1;
    phase = 1 - phase;
    t++;
  }
  __ESBMC_assume(-50 + x == 0);
  assert(x <= 100);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpl   $0x2,-0x2c(%rbp)
  jle    L86
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  add    $0x1,%eax
  cmp    %eax,-0x2c(%rbp)
  jle    L86
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L86
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    $0x64,%eax
  jg     L86
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L52
L53:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L52:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L53
  jmp    L1
L86:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L32
L63:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L32:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L63
L1:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: %d

assistant: ```c
int *readArgs(int *n, int argc, char *argv[]) {
  int loop;
  int *holds;
  if (argc > 2 && (argc >= atoi(argv[1]) + 2) && atoi(argv[1]) >= 3 && atoi(argv[1]) <= 100) {
    *n = atoi(argv[1]);
    if (1 == 0)
      printf("%d holds found in arguments!\n", *n);
    if (argc >= *n + 3)
      if (1 == 0)
        printf("Expected result: %d.\n", atoi(argv[argc - 1]));
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      holds[loop] = atoi(argv[loop + 2]);
    }
  } else {
    if (1 == 0)
      printf("#holds: ");
    scanf("%d", n);
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      if (1 == 0)
        printf("hold #%d height: ", loop + 1);
      scanf("%d", &holds[loop]);
    }
  }
  return holds;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readArgs>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  cmp    $0x2,%esi
  jle    L83
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    0x8(%rdx),%rdi
  call   <atoi@plt>
  add    $0x1,%eax
  cmp    %ebx,%eax
  jl     L6
L83:
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    (%r12),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  cmpl   $0x0,(%r12)
  jle    L30
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L42:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,(%r12)
  jg     L42
L30:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L83
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  cmp    $0x64,%eax
  jg     L83
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  cmpl   $0x0,(%r12)
  jle    L30
  mov    $0x0,%ebx
L9:
  mov    0x10(%rbp,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,(%r14,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,(%r12)
  jg     L9
  jmp    L30
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int *readArgs(int *n, int argc, char *argv[]) {
  int loop;
  int *holds;
  if (argc > 2 && (argc >= atoi(argv[1]) + 2) && atoi(argv[1]) >= 3 && atoi(argv[1]) <= 100) {
    *n = atoi(argv[1]);
    if (1 == 0)
      printf("%d holds found in arguments!\n", *n);
    if (argc >= *n + 3)
      if (1 == 0)
        printf("Expected result: %d.\n", atoi(argv[argc - 1]));
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      holds[loop] = atoi(argv[loop + 2]);
    }
  } else {
    if (1 == 0)
      printf("#holds: ");
    scanf("%d", n);
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      if (1 == 0)
        printf("hold #%d height: ", loop + 1);
      scanf("%d", &holds[loop]);
    }
  }
  return holds;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readArgs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%esi
  jle    L37
  mov    0x8(%rdx),%rdi
  mov    %esi,%ebx
  mov    %rdx,%r13
  call   <atoi@plt>
  add    $0x1,%eax
  cmp    %ebx,%eax
  jl     L85
L37:
  lea    D0(%rip),%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  jle    L57
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L69:
  lea    (%r12,%rbx,4),%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <scanf@plt>
  cmp    %ebx,0x0(%rbp)
  jg     L69
L57:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  mov    0x8(%r13),%rdi
  call   <atoi@plt>
  cmp    $0x2,%eax
  jle    L37
  mov    0x8(%r13),%rdi
  call   <atoi@plt>
  cmp    $0x64,%eax
  jg     L37
  mov    0x8(%r13),%rdi
  call   <atoi@plt>
  mov    %eax,0x0(%rbp)
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%edx
  mov    %rax,%r12
  test   %edx,%edx
  jle    L57
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L39:
  mov    0x10(%r13,%rbx,8),%rdi
  call   <atoi@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,0x0(%rbp)
  jg     L39
  jmp    L57
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
int *readArgs(int *n, int argc, char *argv[]) {
  int loop;
  int *holds;
  if (argc > 2 && (argc >= atoi(argv[1]) + 2) && atoi(argv[1]) >= 3 && atoi(argv[1]) <= 100) {
    *n = atoi(argv[1]);
    if (1 == 0)
      printf("%d holds found in arguments!\n", *n);
    if (argc >= *n + 3)
      if (1 == 0)
        printf("Expected result: %d.\n", atoi(argv[argc - 1]));
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      holds[loop] = atoi(argv[loop + 2]);
    }
  } else {
    if (1 == 0)
      printf("#holds: ");
    scanf("%d", n);
    holds = malloc(*n * sizeof(int));
    for (loop = 0; loop < *n; loop++) {
      if (1 == 0)
        printf("hold #%d height: ", loop + 1);
      scanf("%d", &holds[loop]);
    }
  }
  return holds;
}
```