user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D24(%rip),%rbp
  jmp    L39
L50:
  mov    $0xa,%edi
  call   <putchar@plt>
L39:
  add    $0x1,%ebx
  cmp    $0x32,%ebx
  je     L34
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  jne    L39
  jmp    L50
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    $0x3b4,%ebx
L67:
  mov    $0x0,%eax
  call   <genrand@plt>
  sub    $0x1,%ebx
  jne    L67
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3e8,%ebx
L72:
  mov    $0x0,%eax
  call   <genrand@plt>
  add    $0x1,%ebx
  cmp    $0x1387,%ebx
  jne    L72
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D57(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1388,%ebx
L87:
  mov    $0x0,%eax
  call   <genrand@plt>
  add    $0x1,%ebx
  cmp    $0x270f,%ebx
  jne    L87
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2710,%ebx
L82:
  mov    $0x0,%eax
  call   <genrand@plt>
  add    $0x1,%ebx
  cmp    $0x4e1f,%ebx
  jne    L82
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4e20,%ebx
L8:
  mov    $0x0,%eax
  call   <genrand@plt>
  add    $0x1,%ebx
  cmp    $0x752f,%ebx
  jne    L8
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
datatype: string
name: retrieve_data
arguments: label: D59
datatype: string
name: retrieve_data
arguments: label: D57
datatype: string
name: retrieve_data
arguments: label: D41
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string

tool: D24: %12lu 

tool: D59:  1000: %08lx


tool: D57:  5000: %08lx


tool: D41: 10000: %08lx


tool: D9: 20000: %08lx


tool: D10: 30000: %08lx


assistant: ```c
int main() {
  int j;
  for (j = 0; j < 50; j++) {
    printf("%12lu ", genrand());
    if (j % 5 == 4)
      printf("\n");
  }
  printf("\n");
  genrand();
  for (++j; j < 999; j++) {
    genrand();
  }
  printf(" 1000: %08lx\n", genrand());
  for (++j; j < 4999; j++) {
    genrand();
  }
  printf(" 5000: %08lx\n", genrand());
  for (++j; j < 9999; j++) {
    genrand();
  }
  printf("10000: %08lx\n", genrand());
  for (++j; j < 19999; j++) {
    genrand();
  }
  printf("20000: %08lx\n", genrand());
  for (++j; j < 29999; j++) {
    genrand();
  }
  printf("30000: %08lx\n", genrand());
  return (0);
}
```