ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lit_en_tetes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1,%r12d
  lea    D18(%rip),%r13
  xor    %r14d,%r14d
  lea    D3(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsp,%rbx
  jmp    L52
L35:
  xor    %r12d,%r12d
L52:
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <my_fgets@plt>
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L49
  cmp    $0xd,%al
  je     L49
  mov    $0xb,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L35
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  cmovne %r14d,%r12d
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L49:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x1018,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D18: Connection:

tool: D3: close

assistant: ```c
int lit_en_tetes(FILE *stream) {
  char buf[4096];
  int keepalive = 1;
  while (1) {
    my_fgets(buf, sizeof(buf), stream);
    if (buf[0] == '\n' || buf[0] == '\r')
      break;
    if (!strncasecmp(buf, "Connection:", 11) || strstr(buf, "close"))
      keepalive = 0;
  }
  return keepalive;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lit_en_tetes>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1,%r12d
  lea    D19(%rip),%r13
  xor    %r14d,%r14d
  lea    D3(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsp,%rbx
  jmp    L27
L13:
  xor    %r12d,%r12d
L27:
  mov    %rbp,%rdx
  mov    $0x1000,%esi
  mov    %rbx,%rdi
  call   <my_fgets@plt>
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L48
  cmp    $0xd,%al
  je     L48
  mov    $0xb,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  je     L13
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  cmovne %r14d,%r12d
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L48:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x1018,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
datatype: string
name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D19: Connection:

tool: D3: close

assistant: ```c
int lit_en_tetes(FILE *stream) {
  char buf[4096];
  int keepalive = 1;
  while (1) {
    my_fgets(buf, sizeof(buf), stream);
    if (buf[0] == '\n' || buf[0] == '\r')
      break;
    if (!strncasecmp(buf, "Connection:", 11) || strstr(buf, "close"))
      keepalive = 0;
  }
  return keepalive;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <found@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  found();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <found@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  found();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <found@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  found();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f11_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  subl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <clang_analyzer_warnIfReached@plt>
  nop
  leave
  ret
```

assistant: ```c
void f11_3(void) {
  int x;
  --x;
  clang_analyzer_warnIfReached();
}
```
user: Translate the below assembly code into C programming language:

```asm
<f11_3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clang_analyzer_warnIfReached@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f11_3(void) {
  int x;
  --x;
  clang_analyzer_warnIfReached();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f11_3>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <clang_analyzer_warnIfReached@plt>
```

assistant: ```c
void f11_3(void) {
  int x;
  --x;
  clang_analyzer_warnIfReached();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f11_3>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <clang_analyzer_warnIfReached@plt>
```

assistant: ```c
void f11_3(void) {
  int x;
  --x;
  clang_analyzer_warnIfReached();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <caml_startup@plt>
  lea    D3(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <solve_equation@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <solve_equation@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <solve_equation@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D3:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO2

tool: D6:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO

tool: D1: solution : %s


assistant: ```c
int main(int argc, char **argv) {
  caml_startup(argv);
  char *eq = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO2";
  char *eq2 = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO";
  char *result = solve_equation(eq);
  char *result2 = solve_equation(eq2);
  printf("solution : %s\n", result);
  printf("solution : %s\n", result2);
  free(result2);
  result2 = solve_equation(eq);
  printf("solution : %s\n", result2);
  free(result);
  free(result2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <caml_startup@plt>
  lea    D27(%rip),%r13
  mov    %r13,%rdi
  call   <solve_equation@plt>
  mov    %rax,%rbp
  lea    D17(%rip),%rdi
  call   <solve_equation@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  lea    D28(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <solve_equation@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D28
data_type: string

tool: D27:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO2

tool: D17:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO

tool: D28: solution : %s


assistant: ```c
int main(int argc, char **argv) {
  caml_startup(argv);
  char *eq = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO2";
  char *eq2 = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO";
  char *result = solve_equation(eq);
  char *result2 = solve_equation(eq2);
  printf("solution : %s\n", result);
  printf("solution : %s\n", result2);
  free(result2);
  result2 = solve_equation(eq);
  printf("solution : %s\n", result2);
  free(result);
  free(result2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%rdi
  lea    D5(%rip),%r14
  push   %r13
  lea    D20(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <caml_startup@plt>
  mov    %r14,%rdi
  call   <solve_equation@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%r12
  call   <solve_equation@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <solve_equation@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D20
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D5:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO2

tool: D20: solution : %s


tool: D0:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO

assistant: ```c
int main(int argc, char **argv) {
  caml_startup(argv);
  char *eq = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO2";
  char *eq2 = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO";
  char *result = solve_equation(eq);
  char *result2 = solve_equation(eq2);
  printf("solution : %s\n", result);
  printf("solution : %s\n", result2);
  free(result2);
  result2 = solve_equation(eq);
  printf("solution : %s\n", result2);
  free(result);
  free(result2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    %rsi,%rdi
  lea    D16(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <caml_startup@plt>
  mov    %r14,%rdi
  call   <solve_equation@plt>
  lea    D25(%rip),%rdi
  mov    %rax,%r12
  call   <solve_equation@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <solve_equation@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
data_type: string
name: unpack_data
arguments: data_tag: D21
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string

tool: D16:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO2

tool: D21: solution : %s


tool: D25:  a CH3(CH2)3COOH + b O2 -> c H2O + d CO

assistant: ```c
int main(int argc, char **argv) {
  caml_startup(argv);
  char *eq = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO2";
  char *eq2 = " a CH3(CH2)3COOH + b O2 -> c H2O + d CO";
  char *result = solve_equation(eq);
  char *result2 = solve_equation(eq2);
  printf("solution : %s\n", result);
  printf("solution : %s\n", result2);
  free(result2);
  result2 = solve_equation(eq);
  printf("solution : %s\n", result2);
  free(result);
  free(result2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x1a8(%rbp)
  jmp    L39
L27:
  lea    -0x1ac(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1a0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x1a4(%rbp)
  jmp    L7
L24:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a4(%rbp)
L7:
  mov    -0x1ac(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L24
  mov    -0x1ac(%rbp),%edx
  lea    -0x1a0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <max_trip@plt>
  mov    %eax,%edx
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1a8(%rbp)
L39:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jle    L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D33
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D33: %d

tool: D28: Case #%d: %d


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    int N;
    scanf("%d", &N);
    int W[100] = {};
    for (int i = 0; i < N; i++) {
      scanf("%d", &W[i]);
    }
    printf("Case #%d: %d\n", caseIndex, max_trip(W, N));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L4
  mov    $0x1,%r13d
  lea    0xc(%rsp),%r15
  lea    D17(%rip),%r12
  lea    D20(%rip),%r14
L48:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x32,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L34
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
L27:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L27
L34:
  lea    0x10(%rsp),%rdi
  call   <max_trip@plt>
  mov    %eax,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  cmp    %r13d,0x8(%rsp)
  jge    L48
L4:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string

tool: D17: %d

tool: D20: Case #%d: %d


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    int N;
    scanf("%d", &N);
    int W[100] = {};
    for (int i = 0; i < N; i++) {
      scanf("%d", &W[i]);
    }
    printf("Case #%d: %d\n", caseIndex, max_trip(W, N));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L31
  mov    $0x1,%ebp
  lea    0xc(%rsp),%r15
  lea    0x10(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  test   %esi,%esi
  jle    L34
  mov    %r12,%r14
  xor    %r13d,%r13d
  xchg   %ax,%ax
L32:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %r13d,%esi
  jg     L32
L34:
  mov    %r12,%rdi
  call   <max_trip@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  add    $0x1,%ebp
  mov    %eax,%edx
  call   <printf@plt>
  cmp    %ebp,0x8(%rsp)
  jge    L20
L31:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D9: %d

tool: D2: Case #%d: %d


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    int N;
    scanf("%d", &N);
    int W[100] = {};
    for (int i = 0; i < N; i++) {
      scanf("%d", &W[i]);
    }
    printf("Case #%d: %d\n", caseIndex, max_trip(W, N));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x1,%ebp
  lea    0xc(%rsp),%r15
  lea    0x10(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  test   %esi,%esi
  jle    L49
  mov    %r12,%r14
  xor    %r13d,%r13d
  xchg   %ax,%ax
L23:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %r13d,%esi
  jg     L23
L49:
  mov    %r12,%rdi
  call   <max_trip@plt>
  mov    %ebp,%esi
  lea    D12(%rip),%rdi
  add    $0x1,%ebp
  mov    %eax,%edx
  call   <printf@plt>
  cmp    %ebp,0x8(%rsp)
  jge    L3
L20:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D4: %d

tool: D12: Case #%d: %d


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    int N;
    scanf("%d", &N);
    int W[100] = {};
    for (int i = 0; i < N; i++) {
      scanf("%d", &W[i]);
    }
    printf("Case #%d: %d\n", caseIndex, max_trip(W, N));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<small_mmu_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L0:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <small_mmu_write@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <small_mmu_write@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <small_mmu_write@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0xf,-0x4(%rbp)
  jbe    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void small_mmu_reset(struct hw_device *dev) {
  unsigned int page;
  for (page = 0; page < 16; page++) {
    small_mmu_write(dev, 0, page);
    small_mmu_write(dev, 6, page);
    small_mmu_write(dev, 7, 0x3);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<small_mmu_reset>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L4:
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  mov    %ebx,%edx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  mov    $0x3,%edx
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void small_mmu_reset(struct hw_device *dev) {
  unsigned int page;
  for (page = 0; page < 16; page++) {
    small_mmu_write(dev, 0, page);
    small_mmu_write(dev, 6, page);
    small_mmu_write(dev, 7, 0x3);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<small_mmu_reset>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L3:
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  mov    %ebx,%edx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  add    $0x1,%ebx
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x7,%esi
  call   <small_mmu_write@plt>
  cmp    $0x10,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void small_mmu_reset(struct hw_device *dev) {
  unsigned int page;
  for (page = 0; page < 16; page++) {
    small_mmu_write(dev, 0, page);
    small_mmu_write(dev, 6, page);
    small_mmu_write(dev, 7, 0x3);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<small_mmu_reset>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L7:
  mov    %ebx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  mov    %ebx,%edx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <small_mmu_write@plt>
  add    $0x1,%ebx
  mov    $0x3,%edx
  mov    %rbp,%rdi
  mov    $0x7,%esi
  call   <small_mmu_write@plt>
  cmp    $0x10,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void small_mmu_reset(struct hw_device *dev) {
  unsigned int page;
  for (page = 0; page < 16; page++) {
    small_mmu_write(dev, 0, page);
    small_mmu_write(dev, 6, page);
    small_mmu_write(dev, 7, 0x3);
  }
}
```