ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<dwt_deinterleave_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L35:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L35
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L30:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  sub    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  imul   -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dwt_deinterleave_z(int *a, int *b, int dn, int sn, int xy, int cas) {
  int i;
  for (i = 0; i < sn; i++) {
    b[i * xy] = a[2 * i + cas];
  }
  for (i = 0; i < dn; i++) {
    b[(sn + i) * xy] = a[(2 * i + 1 - cas)];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dwt_deinterleave_z>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rbx
  mov    %edx,%r11d
  mov    %ecx,%edi
  test   %ecx,%ecx
  jle    L28
  movslq %r9d,%rcx
  lea    (%r10,%rcx,4),%rax
  movslq %r8d,%rsi
  shl    $0x2,%rsi
  mov    %rbx,%rdx
  lea    -0x1(%rdi),%ebp
  lea    (%rcx,%rbp,2),%rcx
  lea    0x8(%r10,%rcx,4),%rbp
L9:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rbp,%rax
  jne    L9
L28:
  test   %r11d,%r11d
  jle    L37
  movslq %r9d,%r9
  mov    $0x1,%eax
  sub    %r9,%rax
  lea    (%r10,%rax,4),%rax
  movslq %r8d,%rsi
  shl    $0x2,%rsi
  imul   %r8d,%edi
  movslq %edi,%rdi
  lea    (%rbx,%rdi,4),%rdx
  lea    -0x1(%r11),%ecx
  add    %rcx,%rcx
  sub    %r9,%rcx
  lea    0xc(%r10,%rcx,4),%rdi
L21:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rdi,%rax
  jne    L21
L37:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void dwt_deinterleave_z(int *a, int *b, int dn, int sn, int xy, int cas) {
  int i;
  for (i = 0; i < sn; i++) {
    b[i * xy] = a[2 * i + cas];
  }
  for (i = 0; i < dn; i++) {
    b[(sn + i) * xy] = a[(2 * i + 1 - cas)];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dwt_deinterleave_z>:
  endbr64
  push   %rbp
  mov    %rdi,%r10
  mov    %edx,%r11d
  mov    %ecx,%edi
  push   %rbx
  mov    %rsi,%rbx
  test   %ecx,%ecx
  jle    L38
  movslq %r9d,%rcx
  lea    -0x1(%rdi),%ebp
  movslq %r8d,%rsi
  mov    %rbx,%rdx
  lea    (%r10,%rcx,4),%rax
  lea    (%rcx,%rbp,2),%rcx
  shl    $0x2,%rsi
  lea    0x8(%r10,%rcx,4),%rbp
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rax),%ecx
  add    $0x8,%rax
  mov    %ecx,(%rdx)
  add    %rsi,%rdx
  cmp    %rbp,%rax
  jne    L21
L38:
  test   %r11d,%r11d
  jle    L35
  imul   %r8d,%edi
  lea    -0x1(%r11),%ecx
  movslq %r9d,%r9
  mov    $0x1,%eax
  add    %rcx,%rcx
  sub    %r9,%rax
  movslq %r8d,%rsi
  sub    %r9,%rcx
  lea    (%r10,%rax,4),%rax
  shl    $0x2,%rsi
  movslq %edi,%rdi
  lea    (%rbx,%rdi,4),%rdx
  lea    0xc(%r10,%rcx,4),%rdi
  nopl   (%rax)
L27:
  mov    (%rax),%ecx
  add    $0x8,%rax
  mov    %ecx,(%rdx)
  add    %rsi,%rdx
  cmp    %rax,%rdi
  jne    L27
L35:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void dwt_deinterleave_z(int *a, int *b, int dn, int sn, int xy, int cas) {
  int i;
  for (i = 0; i < sn; i++) {
    b[i * xy] = a[2 * i + cas];
  }
  for (i = 0; i < dn; i++) {
    b[(sn + i) * xy] = a[(2 * i + 1 - cas)];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AL_initiateTone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  add    $0xa0,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <AL_writeRegister@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  and    $0x1c,%eax
  or     %edx,%eax
  or     $0x20,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0xb0,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <AL_writeRegister@plt>
  nop
  leave
  ret
```

assistant: ```c
void AL_initiateTone(int channel, int exponent, int mantissa) {
  AL_writeRegister((0XA0 + (channel)), (mantissa & 0XFF));
  AL_writeRegister((0XB0 + (channel)), (((mantissa >> 8) & 0X3) | ((exponent & 0X7) << 2) | 0X20));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<AL_initiateTone>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  movzbl %dl,%esi
  lea    0xa0(%rdi),%edi
  call   <AL_writeRegister@plt>
  sar    $0x8,%ebx
  mov    %ebx,%esi
  and    $0x3,%esi
  shl    $0x2,%r12d
  and    $0x1c,%r12d
  or     %r12d,%esi
  or     $0x20,%esi
  lea    0xb0(%rbp),%edi
  call   <AL_writeRegister@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void AL_initiateTone(int channel, int exponent, int mantissa) {
  AL_writeRegister((0XA0 + (channel)), (mantissa & 0XFF));
  AL_writeRegister((0XB0 + (channel)), (((mantissa >> 8) & 0X3) | ((exponent & 0X7) << 2) | 0X20));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AL_initiateTone>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    0xa0(%rdi),%edi
  push   %rbp
  mov    %esi,%ebp
  movzbl %dl,%esi
  push   %rbx
  mov    %edx,%ebx
  shl    $0x2,%ebp
  sar    $0x8,%ebx
  and    $0x1c,%ebp
  call   <AL_writeRegister@plt>
  mov    %ebx,%esi
  lea    0xb0(%r12),%edi
  pop    %rbx
  and    $0x3,%esi
  or     %ebp,%esi
  pop    %rbp
  pop    %r12
  or     $0x20,%esi
  jmp    1050 <AL_writeRegister@plt>
```

assistant: ```c
void AL_initiateTone(int channel, int exponent, int mantissa) {
  AL_writeRegister((0XA0 + (channel)), (mantissa & 0XFF));
  AL_writeRegister((0XB0 + (channel)), (((mantissa >> 8) & 0X3) | ((exponent & 0X7) << 2) | 0X20));
}
```
user: Translate the below assembly code into C programming language:

```asm
<AL_initiateTone>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  lea    0xa0(%rdi),%edi
  push   %rbp
  mov    %esi,%ebp
  movzbl %dl,%esi
  push   %rbx
  mov    %edx,%ebx
  shl    $0x2,%ebp
  sar    $0x8,%ebx
  and    $0x1c,%ebp
  call   <AL_writeRegister@plt>
  mov    %ebx,%esi
  lea    0xb0(%r12),%edi
  pop    %rbx
  and    $0x3,%esi
  or     %ebp,%esi
  pop    %rbp
  pop    %r12
  or     $0x20,%esi
  jmp    1050 <AL_writeRegister@plt>
```

assistant: ```c
void AL_initiateTone(int channel, int exponent, int mantissa) {
  AL_writeRegister((0XA0 + (channel)), (mantissa & 0XFF));
  AL_writeRegister((0XB0 + (channel)), (((mantissa >> 8) & 0X3) | ((exponent & 0X7) << 2) | 0X20));
}
```
user: What is the c source code of the assembly code below:

```asm
<UARTIntUnregister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <UARTIntNumberGet@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <IntUnregister@plt>
  nop
  leave
  ret
```

assistant: ```c
void UARTIntUnregister(unsigned long ulBase) {
  unsigned long ulInt;
  ;
  ulInt = UARTIntNumberGet(ulBase);
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTIntUnregister>:
  endbr64
  push   %rbx
  call   <UARTIntNumberGet@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbx,%rdi
  call   <IntUnregister@plt>
  pop    %rbx
  ret
```

assistant: ```c
void UARTIntUnregister(unsigned long ulBase) {
  unsigned long ulInt;
  ;
  ulInt = UARTIntNumberGet(ulBase);
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UARTIntUnregister>:
  endbr64
  push   %rbp
  call   <UARTIntNumberGet@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <IntUnregister@plt>
```

assistant: ```c
void UARTIntUnregister(unsigned long ulBase) {
  unsigned long ulInt;
  ;
  ulInt = UARTIntNumberGet(ulBase);
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UARTIntUnregister>:
  endbr64
  push   %rbp
  call   <UARTIntNumberGet@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <IntDisable@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <IntUnregister@plt>
```

assistant: ```c
void UARTIntUnregister(unsigned long ulBase) {
  unsigned long ulInt;
  ;
  ulInt = UARTIntNumberGet(ulBase);
  IntDisable(ulInt);
  IntUnregister(ulInt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ecdsa_get_wif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %esi,-0x9c(%rbp)
  mov    %rdx,-0xa8(%rbp)
  mov    %ecx,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x9c(%rbp),%eax
  mov    %eax,-0x90(%rbp)
  lea    -0x90(%rbp),%rax
  add    $0x4,%rax
  mov    -0x98(%rbp),%rcx
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x1,-0xc(%rbp)
  mov    -0xa0(%rbp),%ecx
  mov    -0xa8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <base58_encode_check@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x88,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void ecdsa_get_wif(const uint8_t *priv_key, uint8_t version, char *wif, int wifsize) {
  uint8_t data[34];
  data[0] = version;
  memcpy(data + 1, priv_key, 32);
  data[33] = 0x01;
  base58_encode_check(data, 34, wif, wifsize);
  memset((data), 0, (sizeof(data)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ecdsa_get_wif>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %rsp,%r12
  lea    0x4(%rsp),%rax
  mov    $0x20,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x1,0x84(%rsp)
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x22,%esi
  mov    %r12,%rdi
  call   <base58_encode_check@plt>
  mov    $0x88,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ecdsa_get_wif(const uint8_t *priv_key, uint8_t version, char *wif, int wifsize) {
  uint8_t data[34];
  data[0] = version;
  memcpy(data + 1, priv_key, 32);
  data[33] = 0x01;
  base58_encode_check(data, 34, wif, wifsize);
  memset((data), 0, (sizeof(data)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ecdsa_get_wif>:
  endbr64
  push   %r13
  mov    %rdi,%r8
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    $0x20,%edx
  push   %rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %esi,(%rsp)
  lea    0x4(%rsp),%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    $0x22,%esi
  mov    %rbp,%rdi
  movl   $0x1,0x84(%rsp)
  mov    %r13d,%ecx
  call   <base58_encode_check@plt>
  xor    %esi,%esi
  mov    $0x88,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ecdsa_get_wif(const uint8_t *priv_key, uint8_t version, char *wif, int wifsize) {
  uint8_t data[34];
  data[0] = version;
  memcpy(data + 1, priv_key, 32);
  data[33] = 0x01;
  base58_encode_check(data, 34, wif, wifsize);
  memset((data), 0, (sizeof(data)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ecdsa_get_wif>:
  endbr64
  push   %r13
  mov    %rdi,%r8
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  mov    $0x20,%edx
  push   %rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %esi,(%rsp)
  lea    0x4(%rsp),%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    $0x22,%esi
  mov    %rbp,%rdi
  movl   $0x1,0x84(%rsp)
  mov    %r13d,%ecx
  call   <base58_encode_check@plt>
  xor    %esi,%esi
  mov    $0x88,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ecdsa_get_wif(const uint8_t *priv_key, uint8_t version, char *wif, int wifsize) {
  uint8_t data[34];
  data[0] = version;
  memcpy(data + 1, priv_key, 32);
  data[33] = 0x01;
  base58_encode_check(data, 34, wif, wifsize);
  memset((data), 0, (sizeof(data)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<someFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int someFunc(int a, int b) {
  (void)a;
  (void)b;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<someFunc>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int someFunc(int a, int b) {
  (void)a;
  (void)b;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<someFunc>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int someFunc(int a, int b) {
  (void)a;
  (void)b;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<someFunc>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int someFunc(int a, int b) {
  (void)a;
  (void)b;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<APHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xaaaaaaaa,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L3:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L20
  mov    -0x8(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%edx
  shr    $0x3,%edx
  imul   %edx,%eax
  xor    %ecx,%eax
  jmp    L5
L20:
  mov    -0x8(%rbp),%eax
  shl    $0xb,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%eax
  shr    $0x5,%eax
  xor    %edx,%eax
  add    %ecx,%eax
  not    %eax
L5:
  xor    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L3
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int APHash(const char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<APHash>:
  endbr64
  test   %esi,%esi
  je     L20
  mov    %esi,%esi
  mov    $0x0,%edx
  mov    $0xaaaaaaaa,%ecx
  jmp    L12
L34:
  movsbl (%rdi,%rdx,1),%eax
  mov    %ecx,%r8d
  shr    $0x5,%r8d
  xor    %r8d,%eax
  mov    %ecx,%r8d
  shl    $0xb,%r8d
  add    %r8d,%eax
  not    %eax
L30:
  xor    %eax,%ecx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L38
L12:
  test   $0x1,%dl
  jne    L34
  movsbl (%rdi,%rdx,1),%eax
  mov    %ecx,%r8d
  shr    $0x3,%r8d
  imul   %r8d,%eax
  mov    %ecx,%r8d
  shl    $0x7,%r8d
  xor    %r8d,%eax
  jmp    L30
L20:
  mov    $0xaaaaaaaa,%ecx
L38:
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int APHash(const char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<APHash>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L11
  mov    %esi,%esi
  xor    %edx,%edx
  mov    $0xaaaaaaaa,%r8d
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L5:
  shr    $0x3,%edi
  add    $0x1,%rdx
  imul   %edi,%eax
  mov    %r8d,%edi
  shl    $0x7,%edi
  xor    %edi,%eax
  xor    %eax,%r8d
  cmp    %rsi,%rdx
  je     L44
L42:
  movsbl (%rcx,%rdx,1),%eax
  mov    %r8d,%edi
  test   $0x1,%dl
  je     L5
  shr    $0x5,%edi
  add    $0x1,%rdx
  xor    %edi,%eax
  mov    %r8d,%edi
  shl    $0xb,%edi
  add    %edi,%eax
  not    %eax
  xor    %eax,%r8d
  cmp    %rsi,%rdx
  jne    L42
L44:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L11:
  mov    $0xaaaaaaaa,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int APHash(const char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<APHash>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %esi,%esi
  xor    %edx,%edx
  mov    $0xaaaaaaaa,%eax
  nopl   0x0(%rax)
L25:
  movsbl (%rdi,%rdx,1),%ecx
  mov    %eax,%r8d
  test   $0x1,%dl
  jne    L28
  shr    $0x3,%r8d
  add    $0x1,%rdx
  imul   %r8d,%ecx
  mov    %eax,%r8d
  shl    $0x7,%r8d
  xor    %r8d,%ecx
  xor    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L25
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  shr    $0x5,%r8d
  add    $0x1,%rdx
  xor    %r8d,%ecx
  mov    %eax,%r8d
  shl    $0xb,%r8d
  add    %r8d,%ecx
  xor    %ecx,%eax
  not    %eax
  cmp    %rdx,%rsi
  jne    L25
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xaaaaaaaa,%eax
  ret
```

assistant: ```c
unsigned int APHash(const char *str, unsigned int len) {
  unsigned int hash = 0xAAAAAAAA;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash ^= ((i & 1) == 0) ? ((hash << 7) ^ (*str) * (hash >> 3)) : (~((hash << 11) + ((*str) ^ (hash >> 5))));
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<char_cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  cmpb   $0x0,-0x14(%rbp)
  je     L8
  movq   $0x25,D6(%rip)
  movq   $0x7,D11(%rip)
  mov    $0x0,%eax
  jmp    L15
L8:
  mov    D6(%rip),%rdx
  mov    D11(%rip),%rax
  imul   %rdx,%rax
  lea    0x2479(%rax),%rcx
  movabs $0x75fd684e9545f857,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xc,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0x22b7,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    D11(%rip),%rax
  mov    %rax,D8(%rip)
  mov    -0x8(%rbp),%rax
  mov    %rax,D8(%rip)
  mov    -0x8(%rbp),%rax
L15:
  pop    %rbp
  ret
```

assistant: ```c
long char_cipher(char st) {
  static long f, s;
  long r;
  if (st) {
    f = 37;
    s = 7;
    return (0L);
  }
  r = ((f * s) + 9337) % 8887;
  f = s;
  s = r;
  return (r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<char_cipher>:
  endbr64
  test   %dil,%dil
  jne    L9
  mov    D37(%rip),%rsi
  mov    %rsi,%rcx
  imul   D13(%rip),%rcx
  add    $0x2479,%rcx
  movabs $0x75fd684e9545f857,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xc,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x22b7,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rdx
L2:
  mov    %rsi,D22(%rip)
  mov    %rdx,D22(%rip)
  ret
L9:
  mov    $0x25,%esi
  mov    $0x7,%edx
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
long char_cipher(char st) {
  static long f, s;
  long r;
  if (st) {
    f = 37;
    s = 7;
    return (0L);
  }
  r = ((f * s) + 9337) % 8887;
  f = s;
  s = r;
  return (r);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<char_cipher>:
  endbr64
  test   %dil,%dil
  jne    L4
  mov    D34(%rip),%rsi
  mov    D20(%rip),%rcx
  movabs $0x75fd684e9545f857,%rdx
  imul   %rsi,%rcx
  mov    %rsi,D18(%rip)
  add    $0x2479,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sar    $0xc,%rax
  sub    %rdx,%rax
  imul   $0x22b7,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rdx
  mov    %rdx,D18(%rip)
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x25,%esi
  mov    $0x7,%edx
  xor    %eax,%eax
  mov    %rsi,D18(%rip)
  mov    %rdx,D18(%rip)
  ret
```

assistant: ```c
long char_cipher(char st) {
  static long f, s;
  long r;
  if (st) {
    f = 37;
    s = 7;
    return (0L);
  }
  r = ((f * s) + 9337) % 8887;
  f = s;
  s = r;
  return (r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<char_cipher>:
  endbr64
  test   %dil,%dil
  jne    L8
  mov    D18(%rip),%rsi
  mov    D16(%rip),%rcx
  movabs $0x75fd684e9545f857,%rdx
  imul   %rsi,%rcx
  mov    %rsi,D30(%rip)
  add    $0x2479,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sar    $0xc,%rax
  sub    %rdx,%rax
  imul   $0x22b7,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rdx
  mov    %rdx,D30(%rip)
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0x7,%edx
  mov    $0x25,%esi
  xor    %eax,%eax
  mov    %rdx,D30(%rip)
  mov    %rsi,D30(%rip)
  ret
```

assistant: ```c
long char_cipher(char st) {
  static long f, s;
  long r;
  if (st) {
    f = 37;
    s = 7;
    return (0L);
  }
  r = ((f * s) + 9337) % 8887;
  f = s;
  s = r;
  return (r);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rop3_38_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_38_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rop3_38_1_0>:
  endbr64
  mov    %esi,%eax
  or     (%rdi),%sil
  xor    %eax,%esi
  and    (%rdi),%al
  or     %eax,%esi
  mov    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_38_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T & S;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```