ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<array_print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  lea    D9(%rip),%r12
  jmp    L21
L31:
  mov    -0x4(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  add    $0x1,%rbx
  cmp    $0x33,%rbx
  je     L32
L21:
  movslq %ebx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x3,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %eax,%edx
  cmp    %ebx,%edx
  je     L24
  jmp    L31
L32:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %8d

assistant: ```c
void array_print(int array[]) {
  int i;
  for (i = 0; i < 50; i += 1)
    if ((i + 1) % 15)
      if ((i + 1) % 15)
        printf("%8d", array[i]);
      else
        printf("%8d\n", array[i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_print>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L36
  nopl   0x0(%rax)
L19:
  add    $0x1,%rbx
  cmp    $0x33,%rbx
  je     L31
L36:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  jbe    L19
  mov    -0x4(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x33,%rbx
  jne    L36
L31:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: %8d

assistant: ```c
void array_print(int array[]) {
  int i;
  for (i = 0; i < 50; i += 1)
    if ((i + 1) % 15)
      if ((i + 1) % 15)
        printf("%8d", array[i]);
      else
        printf("%8d\n", array[i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_print>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L23
  nopl   0x0(%rax)
L18:
  add    $0x1,%rbx
  cmp    $0x33,%rbx
  je     L14
L23:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  jbe    L18
  mov    -0x4(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x33,%rbx
  jne    L23
L14:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %8d

assistant: ```c
void array_print(int array[]) {
  int i;
  for (i = 0; i < 50; i += 1)
    if ((i + 1) % 15)
      if ((i + 1) % 15)
        printf("%8d", array[i]);
      else
        printf("%8d\n", array[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<outer_test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <outer6@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <outer7@plt>
  mov    %rax,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void outer_test2(int x) {
  int *ip = outer6(x);
  int *ip2 = outer7(x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<outer_test2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <outer6@plt>
  mov    %ebx,%edi
  call   <outer7@plt>
  pop    %rbx
  ret
```

assistant: ```c
void outer_test2(int x) {
  int *ip = outer6(x);
  int *ip2 = outer7(x);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<outer_test2>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <outer6@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <outer7@plt>
```

assistant: ```c
void outer_test2(int x) {
  int *ip = outer6(x);
  int *ip2 = outer7(x);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<outer_test2>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <outer6@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <outer7@plt>
```

assistant: ```c
void outer_test2(int x) {
  int *ip = outer6(x);
  int *ip2 = outer7(x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<default_vd_score_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  cmpq   $0x0,-0x10(%rbp)
  jne    L5
L4:
  mov    $0x2,%eax
  jmp    L30
L5:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vd_cmp@plt>
  test   %rax,%rax
  jne    L23
  mov    $0x0,%eax
  jmp    L30
L23:
  mov    $0x3,%eax
L30:
  leave
  ret
```

assistant: ```c
int default_vd_score_func(void *a, void *b, size_t n) {
  if ((!a) || (!b)) {
    return 2;
  }
  if (vd_cmp(a, b, n) == 0) {
    return 0;
  }
  return 3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<default_vd_score_func>:
  endbr64
  test   %rdi,%rdi
  je     L8
  test   %rsi,%rsi
  je     L8
  sub    $0x8,%rsp
  call   <vd_cmp@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0x3,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int default_vd_score_func(void *a, void *b, size_t n) {
  if ((!a) || (!b)) {
    return 2;
  }
  if (vd_cmp(a, b, n) == 0) {
    return 0;
  }
  return 3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<default_vd_score_func>:
  endbr64
  test   %rdi,%rdi
  je     L15
  test   %rsi,%rsi
  je     L15
  sub    $0x8,%rsp
  call   <vd_cmp@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  and    $0x3,%eax
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int default_vd_score_func(void *a, void *b, size_t n) {
  if ((!a) || (!b)) {
    return 2;
  }
  if (vd_cmp(a, b, n) == 0) {
    return 0;
  }
  return 3;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<default_vd_score_func>:
  endbr64
  test   %rdi,%rdi
  je     L2
  test   %rsi,%rsi
  je     L2
  sub    $0x8,%rsp
  call   <vd_cmp@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  and    $0x3,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int default_vd_score_func(void *a, void *b, size_t n) {
  if ((!a) || (!b)) {
    return 2;
  }
  if (vd_cmp(a, b, n) == 0) {
    return 0;
  }
  return 3;
}
```
user: What is the c source code of the assembly code below:

```asm
<gettimeofday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gettimeofday(struct timeval *ptimeval, void *ptimezone) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gettimeofday>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int gettimeofday(struct timeval *ptimeval, void *ptimezone) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gettimeofday>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int gettimeofday(struct timeval *ptimeval, void *ptimezone) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gettimeofday>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int gettimeofday(struct timeval *ptimeval, void *ptimezone) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eraseTrailingSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L17
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L9
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  jns    L8
  jmp    L30
L9:
  nop
L30:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int eraseTrailingSpaces(char *s) {
  int len = strlen(s);
  int i;
  char c;
  int erased = 0;
  for (i = len - 1; i >= 0; --i) {
    c = s[i];
    if (isspace(c)) {
      s[i] = 0;
      ++erased;
    } else
      break;
  }
  return erased;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eraseTrailingSpaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  sub    $0x1,%eax
  js     L33
  cltq
  add    %rax,%rbx
  mov    $0x0,%ebp
L32:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rbx)
  add    $0x1,%ebp
  sub    $0x1,%rbx
  cmp    %ebp,%r12d
  jne    L32
  mov    %r12d,%ebp
L6:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%ebp
  jmp    L6
```

assistant: ```c
int eraseTrailingSpaces(char *s) {
  int len = strlen(s);
  int i;
  char c;
  int erased = 0;
  for (i = len - 1; i >= 0; --i) {
    c = s[i];
    if (isspace(c)) {
      s[i] = 0;
      ++erased;
    } else
      break;
  }
  return erased;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eraseTrailingSpaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  sub    $0x1,%eax
  js     L15
  cltq
  xor    %r12d,%r12d
  add    %rax,%rbx
  jmp    L47
  nopl   0x0(%rax)
L17:
  add    $0x1,%r12d
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L42
L47:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
L42:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  xor    %r12d,%r12d
  jmp    L42
```

assistant: ```c
int eraseTrailingSpaces(char *s) {
  int len = strlen(s);
  int i;
  char c;
  int erased = 0;
  for (i = len - 1; i >= 0; --i) {
    c = s[i];
    if (isspace(c)) {
      s[i] = 0;
      ++erased;
    } else
      break;
  }
  return erased;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eraseTrailingSpaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  sub    $0x1,%eax
  js     L32
  cltq
  xor    %r12d,%r12d
  add    %rax,%rbx
  jmp    L21
  nopl   0x0(%rax)
L8:
  add    $0x1,%r12d
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L26
L21:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  xor    %r12d,%r12d
  jmp    L26
```

assistant: ```c
int eraseTrailingSpaces(char *s) {
  int len = strlen(s);
  int i;
  char c;
  int erased = 0;
  for (i = len - 1; i >= 0; --i) {
    c = s[i];
    if (isspace(c)) {
      s[i] = 0;
      ++erased;
    } else
      break;
  }
  return erased;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    -0x2c(%rbp),%eax
  sub    %r13d,%eax
  lea    0x1(%rax),%r12d
  mov    $0x0,%ebx
  jmp    L6
L4:
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %r13d,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L15
  mov    $0x1,%eax
  jmp    L39
L15:
  add    $0x1,%ebx
  addq   $0x1,-0x28(%rbp)
L6:
  cmp    %r12d,%ebx
  jl     L4
  mov    $0x0,%eax
L39:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
match(ptr, len, str) char *ptr, *str;
{
  register i, lim, slen;
  slen = strlen(str);
  lim = len - slen + 1;
  for (i = 0; i < lim; ++i, ++ptr)
    if (!memcmp(ptr, str, slen))
      return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    %eax,%r12d
  js     L29
  mov    %eax,%r14d
  mov    $0x0,%ebp
L34:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L2
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jge    L34
  mov    $0x0,%eax
  jmp    L40
L29:
  mov    $0x0,%eax
  jmp    L40
L2:
  mov    $0x1,%eax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
match(ptr, len, str) char *ptr, *str;
{
  register i, lim, slen;
  slen = strlen(str);
  lim = len - slen + 1;
  for (i = 0; i < lim; ++i, ++ptr)
    if (!memcmp(ptr, str, slen))
      return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    %eax,%r12d
  js     L1
  mov    %eax,%r14d
  xor    %ebp,%ebp
  jmp    L10
  nopl   0x0(%rax)
L31:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jl     L1
L10:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L31
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
match(ptr, len, str) char *ptr, *str;
{
  register i, lim, slen;
  slen = strlen(str);
  lim = len - slen + 1;
  for (i = 0; i < lim; ++i, ++ptr)
    if (!memcmp(ptr, str, slen))
      return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<match>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <strlen@plt>
  sub    %eax,%r12d
  js     L8
  mov    %eax,%r14d
  xor    %ebp,%ebp
  jmp    L5
  nopl   0x0(%rax)
L16:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  jl     L8
L5:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L16
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
match(ptr, len, str) char *ptr, *str;
{
  register i, lim, slen;
  slen = strlen(str);
  lim = len - slen + 1;
  for (i = 0; i < lim; ++i, ++ptr)
    if (!memcmp(ptr, str, slen))
      return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reset_worker_signals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reset_worker_signals(void) {
  signal(SIGTERM, SIG_DFL);
  signal(SIGINT, SIG_DFL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<reset_worker_signals>:
  endbr64
  push   %rbx
  mov    D19(%rip),%rbx
  mov    (%rbx),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    (%rbx),%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  pop    %rbx
  ret
```

assistant: ```c
void reset_worker_signals(void) {
  signal(SIGTERM, SIG_DFL);
  signal(SIGINT, SIG_DFL);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reset_worker_signals>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rax
  mov    D7(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D14(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
```

assistant: ```c
void reset_worker_signals(void) {
  signal(SIGTERM, SIG_DFL);
  signal(SIGINT, SIG_DFL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reset_worker_signals>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rax
  mov    D25(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%esi
  call   <signal@plt>
  mov    D8(%rip),%rax
  mov    (%rbx),%esi
  pop    %rbx
  mov    (%rax),%edi
  jmp    1050 <signal@plt>
```

assistant: ```c
void reset_worker_signals(void) {
  signal(SIGTERM, SIG_DFL);
  signal(SIGINT, SIG_DFL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtrim_right_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L12
L4:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L12:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L7
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L7:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strtrim_right_end(char *beg, char *end) {
  while (end > beg && isspace((int)*--end)) {
    *end = '\0';
  }
  return end;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strtrim_right_end>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rax
  cmp    %rdi,%rsi
  jbe    L33
L14:
  sub    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L24
  movb   $0x0,(%rbx)
  cmp    %rbx,%rbp
  jne    L14
  mov    %rbp,%rax
  jmp    L33
L24:
  mov    %rbx,%rax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strtrim_right_end(char *beg, char *end) {
  while (end > beg && isspace((int)*--end)) {
    *end = '\0';
  }
  return end;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtrim_right_end>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rdi,%rsi
  ja     L29
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%rbx)
  cmp    %rbx,%rbp
  je     L10
L29:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
L31:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strtrim_right_end(char *beg, char *end) {
  while (end > beg && isspace((int)*--end)) {
    *end = '\0';
  }
  return end;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtrim_right_end>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rdi,%rsi
  ja     L23
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L9:
  movb   $0x0,(%rbx)
  cmp    %rbx,%rbp
  je     L6
L23:
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
L31:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strtrim_right_end(char *beg, char *end) {
  while (end > beg && isspace((int)*--end)) {
    *end = '\0';
  }
  return end;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movq   $0x8f,-0x30(%rbp)
  movq   $0xa5,-0x28(%rbp)
  movq   $0x11d,-0x20(%rbp)
  jmp    L38
L69:
  mov    -0x30(%rbp),%rax
  add    %rax,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x18(%rbp)
L15:
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  imul   -0x28(%rbp),%rax
  shr    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L72
  addq   $0x1,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L15
  jmp    L82
L72:
  nop
L82:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  imul   -0x20(%rbp),%rax
  shr    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L25
  addq   $0x1,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L82
  jmp    L80
L25:
  nop
L80:
  mov    -0x30(%rbp),%rcx
  mov    %rcx,%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L79
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L79:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L35
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L35
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L35:
  addq   $0x1,-0x30(%rbp)
L38:
  cmpq   $0x1869f,-0x30(%rbp)
  jbe    L69
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D2: %llu: %llu %llu %llu


tool: D12: %llu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long h, p, t;
  for (h = 143, p = 165, t = 285; h < 100000; ++h) {
    unsigned long long hex = h * (2 * h - 1);
    unsigned long long pen;
    unsigned long long tri;
    do {
      pen = p * (3 * p - 1) / 2;
      if (pen == hex)
        break;
      p++;
    } while (pen < hex);
    do {
      tri = t * (t + 1) / 2;
      if (tri == hex)
        break;
      t++;
    } while (tri < hex);
    if (h % 1000 == 0)
      printf("%llu: %llu %llu %llu\n", h, tri, pen, hex);
    if ((tri == pen) && (tri == hex)) {
      printf("%llu\n", hex);
    }
  }
  return 0;
}
```