user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L91:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L91
  sub    $0xc70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c6c(%rbp),%rdx
  lea    -0x9c68(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x9c60(%rbp)
  jmp    L58
L64:
  movl   $0x0,-0x9c5c(%rbp)
  jmp    L97
L39:
  lea    -0x9c50(%rbp),%rcx
  mov    -0x9c5c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c60(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x9c5c(%rbp)
L97:
  mov    -0x9c6c(%rbp),%eax
  cmp    %eax,-0x9c5c(%rbp)
  jl     L39
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x9c60(%rbp)
L58:
  mov    -0x9c68(%rbp),%eax
  cmp    %eax,-0x9c60(%rbp)
  jl     L64
  mov    -0x9c6c(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <R_Sum@plt>
  mov    %eax,-0x9c64(%rbp)
  movl   $0x1,-0x9c58(%rbp)
  jmp    L81
L104:
  mov    -0x9c6c(%rbp),%edx
  mov    -0x9c58(%rbp),%eax
  lea    0x1(%rax),%ecx
  lea    -0x9c50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <R_Sum@plt>
  cmp    %eax,-0x9c64(%rbp)
  jge    L86
  mov    -0x9c6c(%rbp),%edx
  mov    -0x9c58(%rbp),%eax
  lea    0x1(%rax),%ecx
  lea    -0x9c50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <R_Sum@plt>
  mov    %eax,-0x9c64(%rbp)
L86:
  addl   $0x1,-0x9c58(%rbp)
L81:
  mov    -0x9c68(%rbp),%eax
  cmp    %eax,-0x9c58(%rbp)
  jl     L104
  movl   $0x1,-0x9c54(%rbp)
  jmp    L41
L84:
  mov    -0x9c6c(%rbp),%edx
  mov    -0x9c54(%rbp),%ecx
  lea    -0x9c50(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <R_Sum@plt>
  cmp    %eax,-0x9c64(%rbp)
  jne    L102
  mov    -0x9c54(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L102:
  addl   $0x1,-0x9c54(%rbp)
L41:
  mov    -0x9c68(%rbp),%eax
  cmp    %eax,-0x9c54(%rbp)
  jle    L84
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L106
  call   <__stack_chk_fail@plt>
L106:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D19
datatype: string
name: read_data
arguments: data_label: D0
datatype: string

tool: D20: %d %d


tool: D19: %d

tool: D0: %d 

assistant: ```c
int main() {
  int M[100][100], m, n, max, rmax;
  scanf("%d %d\n", &n, &m);
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      scanf("%d", &M[i][j]);
    }
    printf("\n");
  }
  max = R_Sum(M, 1, m);
  for (int i = 1; i < n; i++) {
    if (max < R_Sum(M, (i + 1), m)) {
      max = R_Sum(M, (i + 1), m);
    }
  }
  for (int i = 1; i <= n; i++) {
    if (max == R_Sum(M, i, m))
      printf("%d ", (i - 1));
  }
  return 0;
}
```