user: 这段汇编代码用C语言表示是什么样的:

```asm
<question_four>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L67
L43:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L43
L67:
  sub    $0x190,%rsp
  orq    $0x0,0x188(%rsp)
  lea    D18(%rip),%rdi
  lea    D15(%rip),%r14
  lea    D43(%rip),%r12
  lea    D37(%rip),%r15
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x64,%esi
  lea    -0x3c(%rbp),%r13
  mov    %rbx,%rdi
  call   <insere_lista_auto@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <mostra_lista@plt>
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L35:
  movslq -0x3c(%rbp),%rax
  lea    D2(%rip),%rdi
  mov    (%rbx,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%esi
  mov    %rbx,%rdi
  call   <primoAnterior@plt>
  mov    %eax,%esi
  test   %eax,%eax
  js     L81
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L59:
  mov    -0x3c(%rbp),%esi
  mov    $0x64,%edx
  mov    %rbx,%rdi
  call   <primoPosterior@plt>
  mov    %eax,%esi
  test   %eax,%eax
  js     L11
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L27:
  movslq -0x3c(%rbp),%rax
  mov    (%rbx,%rax,4),%edi
  call   <primo@plt>
  test   %rax,%rax
  jne    L71
L86:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    %r13,%rsi
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    (%rbx,%rax,4),%edi
  call   <primo@plt>
  test   %rax,%rax
  jne    L35
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L27
  nopl   0x0(%rax)
L11:
  lea    D88(%rip),%rdi
  call   <puts@plt>
  jmp    L27
  xchg   %ax,%ax
L81:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  jmp    L59
  nopl   0x0(%rax)
L71:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
type: string
name: disassemble_data
arguments: label: D15
type: string
name: disassemble_data
arguments: label: D43
type: string
name: disassemble_data
arguments: label: D37
type: string
name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D9
type: string
name: disassemble_data
arguments: label: D42
type: string
name: disassemble_data
arguments: label: D88
type: string
name: disassemble_data
arguments: label: D46
type: string

tool: D18: 
------------- Questao 4 -------------

tool: D15: Valor a procurar(indice): 

tool: D43: %d

tool: D37: O numero nao e primo

tool: D2: %d e primo


tool: D9: O proximo primo anterior esta na posicao: %d


tool: D42: O proximo primo posterior esta na posicao: %d


tool: D88: Nao existe um primo posterior

tool: D46: Nao existe um primo anterior

assistant: ```c
void question_four() {
  int n, tam_vetor = 100, vetor[tam_vetor], aux;
  printf("\n------------- Questao 4 -------------\n");
  insere_lista_auto(vetor, tam_vetor);
  mostra_lista(vetor, tam_vetor);
  do {
    printf("Valor a procurar(indice): ");
    scanf("%d", &n);
    if (primo(vetor[n])) {
      printf("%d e primo\n", vetor[n]);
      aux = primoAnterior(vetor, n);
      aux >= 0 ? printf("O proximo primo anterior esta na posicao: %d\n", aux) : printf("Nao existe um primo anterior\n");
      aux = primoPosterior(vetor, n, tam_vetor);
      aux >= 0 ? printf("O proximo primo posterior esta na posicao: %d\n", aux) : printf("Nao existe um primo posterior\n");
    } else
      printf("O numero nao e primo\n");
  } while (!primo(vetor[n]));
}
```