ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_sym>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%rbp
  mov    %r13,%rdx
  mov    %rax,%rdi
  mov    %r12,%rcx
  lea    D20(%rip),%rsi
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <ask@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <free@plt>
  test   %r13d,%r13d
  jne    L35
  lea    0x8(%rsp),%rdx
  lea    D28(%rip),%rsi
  mov    %r14,%rdi
  call   <sscanf@plt>
  mov    %eax,%ecx
  mov    0x8(%rsp),%rax
  cmp    $0x1,%ecx
  jne    L44
L38:
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x1a8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  lea    0x90(%rsp),%rbp
  mov    %rax,%r8
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D13(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <show_warning@plt>
L35:
  xor    %eax,%eax
  jmp    L38
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D20
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D20: %s %s

tool: D28: %lx

tool: D13: Failed sscanf looking for '%s': %d 0x%lx

assistant: ```c
void *find_sym(char *type, char *name) {
  char *req;
  char ans[128];
  int i;
  void *addr = NULL;
  size_t len = 2;
  len += strlen(type);
  len += strlen(name);
  req = malloc(len);
  if (!req) {
    return NULL;
  }
  sprintf(req, "%s %s", type, name);
  i = ask(req, ans);
  free(req);
  if (i != 0)
    return NULL;
  i = sscanf(ans, "%lx", (long *)&addr);
  if (i != 1) {
    char message[256];
    sprintf(message, "Failed sscanf looking for '%s': %d 0x%lx", name, i, (long)addr);
    show_warning(message);
    return NULL;
  }
  return addr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<md_getgeo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int md_getgeo(struct block_device *bdev, struct hd_geometry *geo) {
  int a;
  return a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<md_getgeo>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int md_getgeo(struct block_device *bdev, struct hd_geometry *geo) {
  int a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<md_getgeo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int md_getgeo(struct block_device *bdev, struct hd_geometry *geo) {
  int a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<md_getgeo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int md_getgeo(struct block_device *bdev, struct hd_geometry *geo) {
  int a;
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<b64rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L99
  cmpl   $0x5a,-0x4(%rbp)
  jg     L99
  mov    -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L55
L99:
  cmpl   $0x60,-0x4(%rbp)
  jle    L71
  cmpl   $0x7a,-0x4(%rbp)
  jg     L71
  mov    -0x4(%rbp),%eax
  sub    $0x47,%eax
  jmp    L55
L71:
  cmpl   $0x2f,-0x4(%rbp)
  jle    L70
  cmpl   $0x39,-0x4(%rbp)
  jg     L70
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L55
L70:
  cmpl   $0x2b,-0x4(%rbp)
  jne    L3
  mov    $0x3e,%eax
  jmp    L55
L3:
  cmpl   $0x2f,-0x4(%rbp)
  jne    L98
  mov    $0x3f,%eax
  jmp    L55
L98:
  mov    $0x40,%eax
L55:
  pop    %rbp
  ret
```

assistant: ```c
int b64rev(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A';
  } else if (c >= 'a' && c <= 'z') {
    return c + 26 - 'a';
  } else if (c >= '0' && c <= '9') {
    return c + 52 - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 64;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<b64rev>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L13
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L16
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L11
  cmp    $0x2b,%edi
  je     L39
  cmp    $0x2f,%edi
  setne  %al
  movzbl %al,%eax
  add    $0x3f,%eax
  ret
L16:
  lea    -0x47(%rdi),%eax
  ret
L11:
  lea    0x4(%rdi),%eax
  ret
L39:
  mov    $0x3e,%eax
L13:
  ret
```

assistant: ```c
int b64rev(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A';
  } else if (c >= 'a' && c <= 'z') {
    return c + 26 - 'a';
  } else if (c >= '0' && c <= '9') {
    return c + 52 - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 64;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<b64rev>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L12
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L11
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L21
  cmp    $0x2b,%edi
  je     L16
  xor    %eax,%eax
  cmp    $0x2f,%edi
  setne  %al
  add    $0x3f,%eax
  ret
  nopl   (%rax)
L16:
  mov    $0x3e,%eax
L12:
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  lea    -0x47(%rdi),%eax
  ret
  nopl   0x0(%rax)
L21:
  lea    0x4(%rdi),%eax
  ret
```

assistant: ```c
int b64rev(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A';
  } else if (c >= 'a' && c <= 'z') {
    return c + 26 - 'a';
  } else if (c >= '0' && c <= '9') {
    return c + 52 - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 64;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<b64rev>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L30
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%eax
  jbe    L35
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L10
  cmp    $0x2b,%edi
  je     L19
  xor    %eax,%eax
  cmp    $0x2f,%edi
  setne  %al
  add    $0x3f,%eax
  ret
  nopl   (%rax)
L19:
  mov    $0x3e,%eax
L30:
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  lea    -0x47(%rdi),%eax
  ret
  nopl   0x0(%rax)
L10:
  lea    0x4(%rdi),%eax
  ret
```

assistant: ```c
int b64rev(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A';
  } else if (c >= 'a' && c <= 'z') {
    return c + 26 - 'a';
  } else if (c >= '0' && c <= '9') {
    return c + 52 - '0';
  } else if (c == '+') {
    return 62;
  } else if (c == '/') {
    return 63;
  } else {
    return 64;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f7(int x) {
#pragma omp declare simd simdlen(8) aligned(b : 8 * sizeof(int))
  extern int f8(int a, int *b, int c);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f7(int x) {
#pragma omp declare simd simdlen(8) aligned(b : 8 * sizeof(int))
  extern int f8(int a, int *b, int c);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f7(int x) {
#pragma omp declare simd simdlen(8) aligned(b : 8 * sizeof(int))
  extern int f8(int a, int *b, int c);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f7>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int f7(int x) {
#pragma omp declare simd simdlen(8) aligned(b : 8 * sizeof(int))
  extern int f8(int a, int *b, int c);
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<listupdate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L38
L15:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  movsd  D1(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x40(%rbp),%xmm0
  ja     L21
  jmp    L9
L21:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x14(%rbp)
L38:
  cmpl   $0x0,-0x14(%rbp)
  jg     L15
L9:
  mov    -0x30(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void listupdate(double **listval, int *listprop, int index, double val) {
  int list_length, list_orde, list_lengthmax;
  int i, listp;
  list_length = listprop[0];
  list_orde = listprop[1];
  list_lengthmax = listprop[2];
  listp = index;
  listval[list_orde - 1][index] = val;
  for (i = (list_orde - 1); i > 0; i--) {
    listp = (int)floor(((double)listp) / 2);
    if (val < listval[i - 1][listp]) {
      listval[i - 1][listp] = val;
    } else {
      break;
    }
  }
  listprop[0] = list_length;
  listprop[1] = list_orde;
  listprop[2] = list_lengthmax;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<listupdate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r13
  mov    (%rsi),%r15d
  mov    0x4(%rsi),%r14d
  mov    0x8(%rsi),%eax
  mov    %eax,0xc(%rsp)
  movslq %r14d,%rax
  movslq %edx,%rcx
  mov    -0x8(%rdi,%rax,8),%rax
  movsd  %xmm0,(%rax,%rcx,8)
  lea    -0x1(%r14),%ebx
  test   %ebx,%ebx
  jle    L12
  mov    %rdi,%r12
  movq   %xmm0,%rbp
  movslq %ebx,%rbx
L29:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D5(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,%edx
  cltq
  mov    -0x8(%r12,%rbx,8),%rcx
  lea    (%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  movq   %rbp,%xmm1
  comisd %xmm1,%xmm0
  jbe    L12
  mov    %rbp,(%rax)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L29
L12:
  mov    %r15d,0x0(%r13)
  mov    %r14d,0x4(%r13)
  mov    0xc(%rsp),%eax
  mov    %eax,0x8(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void listupdate(double **listval, int *listprop, int index, double val) {
  int list_length, list_orde, list_lengthmax;
  int i, listp;
  list_length = listprop[0];
  list_orde = listprop[1];
  list_lengthmax = listprop[2];
  listp = index;
  listval[list_orde - 1][index] = val;
  for (i = (list_orde - 1); i > 0; i--) {
    listp = (int)floor(((double)listp) / 2);
    if (val < listval[i - 1][listp]) {
      listval[i - 1][listp] = val;
    } else {
      break;
    }
  }
  listprop[0] = list_length;
  listprop[1] = list_orde;
  listprop[2] = list_lengthmax;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<listupdate>:
  endbr64
  push   %r14
  movslq %edx,%rcx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  movslq 0x4(%rsi),%rax
  mov    0x8(%rsi),%ebp
  mov    (%rsi),%r12
  mov    %rax,%r13
  mov    -0x8(%rdi,%rax,8),%rax
  sub    $0x1,%r13d
  movsd  %xmm0,(%rax,%rcx,8)
  test   %r13d,%r13d
  jle    L5
  mov    %rdi,%r14
  movapd %xmm0,%xmm1
  movslq %r13d,%r13
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L35:
  sub    $0x1,%r13
  movsd  %xmm1,(%rax)
  test   %r13d,%r13d
  jle    L5
L6:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,0x8(%rsp)
  cvtsi2sd %edx,%xmm0
  mulsd  D7(%rip),%xmm0
  call   <floor@plt>
  mov    -0x8(%r14,%r13,8),%rcx
  movsd  0x8(%rsp),%xmm1
  mov    %eax,%edx
  cltq
  lea    (%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  ja     L35
L5:
  mov    %r12,(%rbx)
  mov    %ebp,0x8(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void listupdate(double **listval, int *listprop, int index, double val) {
  int list_length, list_orde, list_lengthmax;
  int i, listp;
  list_length = listprop[0];
  list_orde = listprop[1];
  list_lengthmax = listprop[2];
  listp = index;
  listval[list_orde - 1][index] = val;
  for (i = (list_orde - 1); i > 0; i--) {
    listp = (int)floor(((double)listp) / 2);
    if (val < listval[i - 1][listp]) {
      listval[i - 1][listp] = val;
    } else {
      break;
    }
  }
  listprop[0] = list_length;
  listprop[1] = list_orde;
  listprop[2] = list_lengthmax;
}
```
user: What is the c source code of the assembly code below?

```asm
<listupdate>:
  endbr64
  push   %r13
  movslq %edx,%rcx
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rax
  mov    0x8(%rsi),%r12d
  mov    %rax,0x8(%rsp)
  movslq 0xc(%rsp),%rax
  mov    %rax,%rbx
  mov    -0x8(%rdi,%rax,8),%rax
  sub    $0x1,%ebx
  movsd  %xmm0,(%rax,%rcx,8)
  test   %ebx,%ebx
  jle    L32
  mov    %rdi,%r13
  movapd %xmm0,%xmm1
  movslq %ebx,%rbx
  jmp    L11
  nopl   (%rax)
L2:
  sub    $0x1,%rbx
  movsd  %xmm1,(%rax)
  test   %ebx,%ebx
  jle    L32
L11:
  pxor   %xmm0,%xmm0
  movsd  %xmm1,(%rsp)
  cvtsi2sd %edx,%xmm0
  mulsd  D6(%rip),%xmm0
  call   <floor@plt>
  mov    -0x8(%r13,%rbx,8),%rcx
  movsd  (%rsp),%xmm1
  mov    %eax,%edx
  cltq
  lea    (%rcx,%rax,8),%rax
  movsd  (%rax),%xmm0
  comisd %xmm1,%xmm0
  ja     L2
L32:
  mov    0x8(%rsp),%rax
  mov    %r12d,0x8(%rbp)
  mov    %rax,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void listupdate(double **listval, int *listprop, int index, double val) {
  int list_length, list_orde, list_lengthmax;
  int i, listp;
  list_length = listprop[0];
  list_orde = listprop[1];
  list_lengthmax = listprop[2];
  listp = index;
  listval[list_orde - 1][index] = val;
  for (i = (list_orde - 1); i > 0; i--) {
    listp = (int)floor(((double)listp) / 2);
    if (val < listval[i - 1][listp]) {
      listval[i - 1][listp] = val;
    } else {
      break;
    }
  }
  listprop[0] = list_length;
  listprop[1] = list_orde;
  listprop[2] = list_lengthmax;
}
```
user: Translate the below assembly code into C programming language:

```asm
<indexof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L4:
  movzbl -0x5(%rbp),%eax
  cmp    -0x1c(%rbp),%al
  jne    L19
  movsbl -0x5(%rbp),%eax
  jmp    L36
L19:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L4
  mov    $0xffffffff,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int indexof(char str[], char target) {
  int i = 0;
  char c;
  while ((c = str[i++]) != '\0')
    if (c == target)
      return c;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<indexof>:
  endbr64
L18:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  add    $0x1,%rdi
  cmp    %sil,%al
  jne    L18
  movsbl %al,%eax
  ret
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int indexof(char str[], char target) {
  int i = 0;
  char c;
  while ((c = str[i++]) != '\0')
    if (c == target)
      return c;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<indexof>:
  endbr64
  mov    %esi,%ecx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdi
  cmp    %cl,%dl
  je     L4
L15:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  mov    $0xffffffff,%eax
  ret
  nopl   (%rax)
L4:
  movsbl %sil,%eax
  ret
```

assistant: ```c
int indexof(char str[], char target) {
  int i = 0;
  char c;
  while ((c = str[i++]) != '\0')
    if (c == target)
      return c;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<indexof>:
  endbr64
  mov    %esi,%ecx
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
  cmp    %cl,%dl
  je     L12
L25:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L8
  mov    $0xffffffff,%eax
  ret
  nopl   (%rax)
L12:
  movsbl %sil,%eax
  ret
```

assistant: ```c
int indexof(char str[], char target) {
  int i = 0;
  char c;
  while ((c = str[i++]) != '\0')
    if (c == target)
      return c;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<mklower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L1
L18:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x18(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mklower(char *sx) {
  int len, k;
  len = strlen(sx);
  for (k = 0; k < len; ++k) {
    sx[k] = tolower(sx[k]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mklower>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L1:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mklower(char *sx) {
  int len, k;
  len = strlen(sx);
  for (k = 0; k < len; ++k) {
    sx[k] = tolower(sx[k]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mklower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L11:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L11
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mklower(char *sx) {
  int len, k;
  len = strlen(sx);
  for (k = 0; k < len; ++k) {
    sx[k] = tolower(sx[k]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mklower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L13
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  xchg   %ax,%ax
L14:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L14
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mklower(char *sx) {
  int len, k;
  len = strlen(sx);
  for (k = 0; k < len; ++k) {
    sx[k] = tolower(sx[k]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L17
L1:
  movq   $0x2,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <joseph@plt>
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D2
type: string

tool: D24: %d

tool: D12: %ld

tool: D2: %ld


assistant: ```c
int main() {
  long long t;
  scanf("%d", &t);
  while (t--) {
    long long n, k = 2;
    scanf("%ld", &n);
    printf("%ld\n", joseph(n, k) + 1);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L10
  lea    0x10(%rsp),%r12
  lea    D8(%rip),%rbp
  lea    D26(%rip),%rbx
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x2,%esi
  mov    0x10(%rsp),%rdi
  call   <joseph@plt>
  lea    0x1(%rax),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L14
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D26
type: string

tool: D16: %d

tool: D8: %ld

tool: D26: %ld


assistant: ```c
int main() {
  long long t;
  scanf("%d", &t);
  while (t--) {
    long long n, k = 2;
    scanf("%ld", &n);
    printf("%ld\n", joseph(n, k) + 1);
  }
  return 0;
}
```