ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasestr_spec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L129
  cmpq   $0x0,-0x30(%rbp)
  je     L129
  mov    $0x1,%eax
  jmp    L44
L129:
  mov    $0x0,%eax
L44:
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L11
L18:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L40
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L114
L113:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L110
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L114:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L75
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L113
  jmp    L75
L110:
  nop
L75:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    -0x20(%rbp),%rax
  jmp    L9
L40:
  addq   $0x1,-0x28(%rbp)
L11:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strcasestr_spec(char *str1, const char *str2) {
  char *temp1 = NULL;
  const char *temp2 = NULL;
  (assert((str1 != NULL) && (str2 != NULL)));
  while (*str1 != '\0') {
    if (tolower(*str1) == tolower(*str2)) {
      for (temp1 = str1, temp2 = str2; ((*temp1 != '\0') && (*temp2 != '\0')); temp1++, temp2++) {
        if (tolower(*temp1) != tolower(*temp2))
          break;
      }
      if ((*temp2) == '\0')
        return temp1;
    }
    str1++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcasestr_spec>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L55
  mov    $0x0,%ebp
  jmp    L30
L49:
  cmpb   $0x0,(%rbx)
  je     L30
L21:
  add    $0x1,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L41
L55:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  movsbl 0x0(%r13),%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L21
  movzbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%rbp
  test   %dil,%dil
  je     L49
L34:
  cmpb   $0x0,(%rbx)
  je     L30
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%r14
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %rax,%r14
  jne    L49
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L34
  jmp    L49
L41:
  mov    $0x0,%ebp
L30:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strcasestr_spec(char *str1, const char *str2) {
  char *temp1 = NULL;
  const char *temp2 = NULL;
  (assert((str1 != NULL) && (str2 != NULL)));
  while (*str1 != '\0') {
    if (tolower(*str1) == tolower(*str2)) {
      for (temp1 = str1, temp2 = str2; ((*temp1 != '\0') && (*temp2 != '\0')); temp1++, temp2++) {
        if (tolower(*temp1) != tolower(*temp2))
          break;
      }
      if ((*temp2) == '\0')
        return temp1;
    }
    str1++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcasestr_spec>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  setne  %al
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  push   %rbx
  and    %eax,%edi
  call   <assert@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L48
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L58:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L30
L48:
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L58
  movsbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%r14
  test   %dil,%dil
  jne    L91
  jmp    L73
  nopl   0x0(%rax)
L88:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L73
  movsbl 0x1(%r14),%edi
  add    $0x1,%r14
  add    $0x1,%rbx
  test   %dil,%dil
  je     L73
L91:
  cmpb   $0x0,(%rbx)
  jne    L88
L32:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  cmpb   $0x0,(%rbx)
  je     L32
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L48
L30:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strcasestr_spec(char *str1, const char *str2) {
  char *temp1 = NULL;
  const char *temp2 = NULL;
  (assert((str1 != NULL) && (str2 != NULL)));
  while (*str1 != '\0') {
    if (tolower(*str1) == tolower(*str2)) {
      for (temp1 = str1, temp2 = str2; ((*temp1 != '\0') && (*temp2 != '\0')); temp1++, temp2++) {
        if (tolower(*temp1) != tolower(*temp2))
          break;
      }
      if ((*temp2) == '\0')
        return temp1;
    }
    str1++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasestr_spec>:
  endbr64
  test   %rdi,%rdi
  push   %r14
  setne  %al
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  test   %rsi,%rsi
  push   %rbp
  setne  %dil
  push   %rbx
  and    %eax,%edi
  call   <assert@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L0
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L76:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L15
L0:
  call   <tolower@plt>
  movsbl 0x0(%r13),%edi
  mov    %rax,%rbx
  call   <tolower@plt>
  cmp    %rax,%rbx
  jne    L76
  movsbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%r14
  test   %dil,%dil
  jne    L26
  jmp    L20
  nopl   0x0(%rax)
L57:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L20
  movsbl 0x1(%r14),%edi
  add    $0x1,%r14
  add    $0x1,%rbx
  test   %dil,%dil
  je     L20
L26:
  cmpb   $0x0,(%rbx)
  jne    L57
L7:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  cmpb   $0x0,(%rbx)
  je     L7
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L0
L15:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strcasestr_spec(char *str1, const char *str2) {
  char *temp1 = NULL;
  const char *temp2 = NULL;
  (assert((str1 != NULL) && (str2 != NULL)));
  while (*str1 != '\0') {
    if (tolower(*str1) == tolower(*str2)) {
      for (temp1 = str1, temp2 = str2; ((*temp1 != '\0') && (*temp2 != '\0')); temp1++, temp2++) {
        if (tolower(*temp1) != tolower(*temp2))
          break;
      }
      if ((*temp2) == '\0')
        return temp1;
    }
    str1++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTBusy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__byte@plt>
  and    $0x40,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
bool UARTBusy(uint32_t ui32Base) {
  ;
  return ((__byte((int *)(ui32Base + 0x4), 0) & 0x40) ? false : true);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTBusy>:
  endbr64
  sub    $0x8,%rsp
  add    $0x4,%rdi
  mov    $0x0,%esi
  call   <__byte@plt>
  test   $0x40,%al
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool UARTBusy(uint32_t ui32Base) {
  ;
  return ((__byte((int *)(ui32Base + 0x4), 0) & 0x40) ? false : true);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTBusy>:
  endbr64
  sub    $0x8,%rsp
  add    $0x4,%rdi
  xor    %esi,%esi
  call   <__byte@plt>
  test   $0x40,%al
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool UARTBusy(uint32_t ui32Base) {
  ;
  return ((__byte((int *)(ui32Base + 0x4), 0) & 0x40) ? false : true);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UARTBusy>:
  endbr64
  sub    $0x8,%rsp
  add    $0x4,%rdi
  xor    %esi,%esi
  call   <__byte@plt>
  test   $0x40,%al
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool UARTBusy(uint32_t ui32Base) {
  ;
  return ((__byte((int *)(ui32Base + 0x4), 0) & 0x40) ? false : true);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L0:
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int check_error(int fb, char str[]) {
  if (fb < 0)
    perror(str);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_error>:
  endbr64
  test   %edi,%edi
  js     L2
  mov    $0xffffffff,%eax
  ret
L2:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int check_error(int fb, char str[]) {
  if (fb < 0)
    perror(str);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_error>:
  endbr64
  test   %edi,%edi
  js     L4
  mov    $0xffffffff,%eax
  ret
  xchg   %ax,%ax
L4:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int check_error(int fb, char str[]) {
  if (fb < 0)
    perror(str);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_error>:
  endbr64
  test   %edi,%edi
  js     L9
  mov    $0xffffffff,%eax
  ret
  xchg   %ax,%ax
L9:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int check_error(int fb, char str[]) {
  if (fb < 0)
    perror(str);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cleanUp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x13fff,-0x4(%rbp)
  jle    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void cleanUp(char *base[]) {
  int i;
  for (i = 0; i < 81920; i++) {
    free(base[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cleanUp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0xa0000(%rdi),%rbp
L0:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cleanUp(char *base[]) {
  int i;
  for (i = 0; i < 81920; i++) {
    free(base[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cleanUp>:
  endbr64
  push   %rbp
  lea    0xa0000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cleanUp(char *base[]) {
  int i;
  for (i = 0; i < 81920; i++) {
    free(base[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cleanUp>:
  endbr64
  push   %rbp
  lea    0xa0000(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void cleanUp(char *base[]) {
  int i;
  for (i = 0; i < 81920; i++) {
    free(base[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hooks_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hooks_write(struct bufferevent *ev, void *arg) {
  arg = NULL;
  ev = NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hooks_write>:
  endbr64
  ret
```

assistant: ```c
void hooks_write(struct bufferevent *ev, void *arg) {
  arg = NULL;
  ev = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hooks_write>:
  endbr64
  ret
```

assistant: ```c
void hooks_write(struct bufferevent *ev, void *arg) {
  arg = NULL;
  ev = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hooks_write>:
  endbr64
  ret
```

assistant: ```c
void hooks_write(struct bufferevent *ev, void *arg) {
  arg = NULL;
  ev = NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L29
  mov    $0x1,%eax
  jmp    L0
L29:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    $0xffffffff,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int find(int *a, int size, int x) {
  for (int i = 0; i < size; i++) {
    if (a[i] == x) {
      return 1;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rcx
L28:
  cmp    %edx,(%rax)
  je     L19
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
  mov    $0xffffffff,%eax
  ret
L16:
  mov    $0xffffffff,%eax
  ret
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int find(int *a, int size, int x) {
  for (int i = 0; i < size; i++) {
    if (a[i] == x) {
      return 1;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L33:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L16
L29:
  cmp    %edx,(%rdi)
  jne    L33
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find(int *a, int size, int x) {
  for (int i = 0; i < size; i++) {
    if (a[i] == x) {
      return 1;
    }
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find>:
  endbr64
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L31
L34:
  cmp    %edx,(%rdi)
  jne    L36
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int find(int *a, int size, int x) {
  for (int i = 0; i < size; i++) {
    if (a[i] == x) {
      return 1;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calc_1root>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movq   D9(%rip),%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double calc_1root(double a, double b) {
  double root1;
  root1 = -b / (2 * a);
  return root1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<calc_1root>:
  endbr64
  xorpd  D2(%rip),%xmm1
  addsd  %xmm0,%xmm0
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double calc_1root(double a, double b) {
  double root1;
  root1 = -b / (2 * a);
  return root1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_1root>:
  endbr64
  addsd  %xmm0,%xmm0
  xorpd  D6(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: byte[16]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double calc_1root(double a, double b) {
  double root1;
  root1 = -b / (2 * a);
  return root1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_1root>:
  endbr64
  addsd  %xmm0,%xmm0
  xorpd  D7(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double calc_1root(double a, double b) {
  double root1;
  root1 = -b / (2 * a);
  return root1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x13(%rbp),%rdx
  lea    -0x1e(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1e(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movzbl -0x1e(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cmp    $0x17,%eax
  seta   %dl
  test   %dl,%dl
  jne    L3
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,%rdx
  and    $0x104111,%edx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L46
  and    $0x800000,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L61
  jmp    L3
L46:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,-0x1e(%rbp,%rax,1)
  jmp    L3
L61:
  mov    -0x28(%rbp),%rax
  sub    $0x2,%rax
  movzbl -0x1e(%rbp,%rax,1),%eax
  cmp    $0x65,%al
  jne    L52
  mov    -0x28(%rbp),%rax
  sub    $0x2,%rax
  movb   $0x0,-0x1e(%rbp,%rax,1)
L52:
  nop
L3:
  lea    -0x13(%rbp),%rdx
  lea    -0x1e(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D12: %s %s

tool: D5: ex

tool: D7: %s%s%s


assistant: ```c
int main() {
  char first[11], second[11];
  scanf("%s %s", first, second);
  size_t f_len = strlen(first);
  switch (first[f_len - 1]) {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
    first[f_len - 1] = 0;
    break;
  case 'x':
    if (first[f_len - 2] == 'e')
      first[f_len - 2] = 0;
    break;
  }
  printf("%s%s%s\n", first, "ex", second);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rdx
  lea    0x2(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rsi
  movzbl 0x2(%rsp,%rsi,1),%ebx
  lea    -0x61(%rbx),%ecx
  cmp    $0x17,%cl
  ja     L64
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x104111,%edx
  jne    L10
  cmp    $0x17,%cl
  je     L40
L64:
  lea    0xd(%rsp),%rcx
  lea    0x2(%rsp),%rsi
  lea    D8(%rip),%rdx
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  movb   $0x0,0x2(%rsp,%rsi,1)
  jmp    L64
L40:
  cmpb   $0x65,(%rsp,%rax,1)
  jne    L64
  movb   $0x0,(%rsp,%rax,1)
  jmp    L64
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: string

tool: D27: %s %s

tool: D8: ex

tool: D24: %s%s%s


assistant: ```c
int main() {
  char first[11], second[11];
  scanf("%s %s", first, second);
  size_t f_len = strlen(first);
  switch (first[f_len - 1]) {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
    first[f_len - 1] = 0;
    break;
  case 'x':
    if (first[f_len - 2] == 'e')
      first[f_len - 2] = 0;
    break;
  }
  printf("%s%s%s\n", first, "ex", second);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  lea    0xd(%rsp),%r12
  mov    %rbp,%rsi
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rsi
  movzbl 0x2(%rsp,%rsi,1),%ecx
  sub    $0x61,%ecx
  cmp    $0x17,%cl
  ja     L59
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x104111,%edx
  jne    L52
  cmp    $0x17,%cl
  je     L67
L59:
  mov    %r12,%rcx
  lea    D12(%rip),%rdx
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L52:
  movb   $0x0,0x2(%rsp,%rsi,1)
  jmp    L59
L67:
  cmpb   $0x65,(%rsp,%rax,1)
  jne    L59
  movb   $0x0,(%rsp,%rax,1)
  jmp    L59
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D0: %s %s

tool: D12: ex

tool: D11: %s%s%s


assistant: ```c
int main() {
  char first[11], second[11];
  scanf("%s %s", first, second);
  size_t f_len = strlen(first);
  switch (first[f_len - 1]) {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
    first[f_len - 1] = 0;
    break;
  case 'x':
    if (first[f_len - 2] == 'e')
      first[f_len - 2] = 0;
    break;
  }
  printf("%s%s%s\n", first, "ex", second);
  return 0;
}
```