ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sqlite3OpcodeName>:
  endbr64
  movslq %edi,%rdi
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
const char *sqlite3OpcodeName(int i) {
  static const char *const azName[] = {
      "?", "Function", "Savepoint", "AutoCommit", "Transaction", "SorterNext", "PrevIfOpen", "NextIfOpen", "Prev", "Next", "AggStep", "Checkpoint", "JournalMode", "Vacuum", "VFilter", "VUpdate", "Goto", "Gosub", "Return", "Not", "InitCoroutine", "EndCoroutine", "Yield", "HaltIfNull", "Halt", "Integer", "Int64", "String", "Null", "SoftNull", "Blob", "Variable", "Move", "Copy", "SCopy", "ResultRow", "CollSeq", "AddImm", "MustBeInt", "RealAffinity", "Permutation", "Compare", "Jump", "Once", "If", "IfNot", "Column", "Affinity", "MakeRecord", "Count", "ReadCookie", "SetCookie", "OpenRead", "OpenWrite", "OpenAutoindex", "OpenEphemeral", "SorterOpen", "OpenPseudo", "Close", "SeekLT", "SeekLE", "SeekGE", "SeekGT", "Seek", "NoConflict", "NotFound", "Found", "NotExists", "Sequence", "NewRowid", "Insert", "Or", "And", "InsertInt", "Delete", "ResetCount", "IsNull", "NotNull", "Ne", "Eq", "Gt", "Le", "Lt", "Ge", "SorterCompare", "BitAnd", "BitOr", "ShiftLeft", "ShiftRight", "Add", "Subtract", "Multiply", "Divide", "Remainder", "Concat", "SorterData", "BitNot", "String8", "RowKey", "RowData", "Rowid", "NullRow", "Last", "SorterSort", "Sort", "Rewind", "SorterInsert", "IdxInsert", "IdxDelete", "IdxRowid", "IdxLE", "IdxGT", "IdxLT", "IdxGE", "Destroy", "Clear", "ResetSorter", "CreateIndex", "CreateTable", "ParseSchema", "LoadAnalysis", "DropTable", "DropIndex", "DropTrigger", "IntegrityCk", "RowSetAdd", "RowSetRead", "RowSetTest", "Program", "Param", "FkCounter", "FkIfZero", "MemMax", "Real", "IfPos", "IfNeg", "IfZero", "AggFinal", "IncrVacuum", "Expire", "TableLock", "VBegin", "VCreate", "ToText", "ToBlob", "ToNumeric", "ToInt", "ToReal", "VDestroy", "VOpen", "VColumn", "VNext", "VRename", "Pagecount", "MaxPgcnt", "Init", "Noop", "Explain",
  };
  return azName[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sqlite3OpcodeName>:
  endbr64
  movslq %edi,%rdi
  lea    D2(%rip),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
const char *sqlite3OpcodeName(int i) {
  static const char *const azName[] = {
      "?", "Function", "Savepoint", "AutoCommit", "Transaction", "SorterNext", "PrevIfOpen", "NextIfOpen", "Prev", "Next", "AggStep", "Checkpoint", "JournalMode", "Vacuum", "VFilter", "VUpdate", "Goto", "Gosub", "Return", "Not", "InitCoroutine", "EndCoroutine", "Yield", "HaltIfNull", "Halt", "Integer", "Int64", "String", "Null", "SoftNull", "Blob", "Variable", "Move", "Copy", "SCopy", "ResultRow", "CollSeq", "AddImm", "MustBeInt", "RealAffinity", "Permutation", "Compare", "Jump", "Once", "If", "IfNot", "Column", "Affinity", "MakeRecord", "Count", "ReadCookie", "SetCookie", "OpenRead", "OpenWrite", "OpenAutoindex", "OpenEphemeral", "SorterOpen", "OpenPseudo", "Close", "SeekLT", "SeekLE", "SeekGE", "SeekGT", "Seek", "NoConflict", "NotFound", "Found", "NotExists", "Sequence", "NewRowid", "Insert", "Or", "And", "InsertInt", "Delete", "ResetCount", "IsNull", "NotNull", "Ne", "Eq", "Gt", "Le", "Lt", "Ge", "SorterCompare", "BitAnd", "BitOr", "ShiftLeft", "ShiftRight", "Add", "Subtract", "Multiply", "Divide", "Remainder", "Concat", "SorterData", "BitNot", "String8", "RowKey", "RowData", "Rowid", "NullRow", "Last", "SorterSort", "Sort", "Rewind", "SorterInsert", "IdxInsert", "IdxDelete", "IdxRowid", "IdxLE", "IdxGT", "IdxLT", "IdxGE", "Destroy", "Clear", "ResetSorter", "CreateIndex", "CreateTable", "ParseSchema", "LoadAnalysis", "DropTable", "DropIndex", "DropTrigger", "IntegrityCk", "RowSetAdd", "RowSetRead", "RowSetTest", "Program", "Param", "FkCounter", "FkIfZero", "MemMax", "Real", "IfPos", "IfNeg", "IfZero", "AggFinal", "IncrVacuum", "Expire", "TableLock", "VBegin", "VCreate", "ToText", "ToBlob", "ToNumeric", "ToInt", "ToReal", "VDestroy", "VOpen", "VColumn", "VNext", "VRename", "Pagecount", "MaxPgcnt", "Init", "Noop", "Explain",
  };
  return azName[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fifaStreet2ecrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0xc153,-0x6(%rbp)
  movl   $0x10,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  mov    $0xfd4,%edx
  sub    %ecx,%edx
  imul   %edx,%eax
  add    %ax,-0x6(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0xfd3,-0x4(%rbp)
  jle    L7
  movzwl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short fifaStreet2ecrc(unsigned char *data) {
  unsigned short crc = 49491;
  int i;
  for (i = 0x00000010; i < 0xFD4; i++) {
    crc += data[i] * (0xFD4 - (i & ~0x3));
  }
  return crc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fifaStreet2ecrc>:
  endbr64
  mov    $0x10,%eax
  mov    $0xffffc153,%ecx
  mov    $0xfd4,%r8d
L5:
  mov    %eax,%edx
  and    $0xfffffffc,%edx
  mov    %r8d,%esi
  sub    %edx,%esi
  movzbl (%rdi,%rax,1),%edx
  imul   %esi,%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    $0xfd4,%rax
  jne    L5
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned short fifaStreet2ecrc(unsigned char *data) {
  unsigned short crc = 49491;
  int i;
  for (i = 0x00000010; i < 0xFD4; i++) {
    crc += data[i] * (0xFD4 - (i & ~0x3));
  }
  return crc;
}
```
user: What is the c source code of the assembly code below?

```asm
<fifaStreet2ecrc>:
  endbr64
  mov    $0x10,%eax
  mov    $0xffffc153,%r8d
  mov    $0xfd4,%esi
  nopl   0x0(%rax)
L9:
  mov    %eax,%edx
  mov    %esi,%ecx
  and    $0xfffffffc,%edx
  sub    %edx,%ecx
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  imul   %ecx,%edx
  add    %edx,%r8d
  cmp    $0xfd4,%rax
  jne    L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned short fifaStreet2ecrc(unsigned char *data) {
  unsigned short crc = 49491;
  int i;
  for (i = 0x00000010; i < 0xFD4; i++) {
    crc += data[i] * (0xFD4 - (i & ~0x3));
  }
  return crc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fifaStreet2ecrc>:
  endbr64
  movdqa D39(%rip),%xmm3
  lea    0x10(%rdi),%rax
  movdqa D37(%rip),%xmm10
  lea    0xfd0(%rdi),%rdx
  movdqa D52(%rip),%xmm6
  pxor   %xmm2,%xmm2
  pxor   %xmm4,%xmm4
  movdqa D22(%rip),%xmm9
  movdqa D14(%rip),%xmm5
  movdqa D42(%rip),%xmm7
  movdqa D44(%rip),%xmm8
  nopw   0x0(%rax,%rax,1)
L0:
  movdqa %xmm3,%xmm0
  movdqu (%rax),%xmm11
  add    $0x10,%rax
  paddd  %xmm10,%xmm3
  movdqa %xmm0,%xmm1
  movdqa %xmm0,%xmm13
  paddd  %xmm8,%xmm13
  paddd  %xmm9,%xmm1
  movdqa %xmm1,%xmm12
  punpcklwd %xmm13,%xmm1
  punpckhwd %xmm13,%xmm12
  movdqa %xmm1,%xmm13
  punpckhwd %xmm12,%xmm13
  punpcklwd %xmm12,%xmm1
  movdqa %xmm11,%xmm12
  punpcklwd %xmm13,%xmm1
  movdqa %xmm5,%xmm13
  punpckhbw %xmm4,%xmm12
  pand   %xmm6,%xmm1
  psubw  %xmm1,%xmm13
  movdqa %xmm13,%xmm1
  movdqa %xmm0,%xmm13
  paddd  %xmm7,%xmm13
  pmullw %xmm12,%xmm1
  movdqa %xmm0,%xmm12
  punpcklwd %xmm13,%xmm0
  punpckhwd %xmm13,%xmm12
  movdqa %xmm0,%xmm13
  punpcklwd %xmm12,%xmm0
  punpckhwd %xmm12,%xmm13
  movdqa %xmm5,%xmm12
  punpcklwd %xmm13,%xmm0
  pand   %xmm6,%xmm0
  psubw  %xmm0,%xmm12
  movdqa %xmm11,%xmm0
  punpcklbw %xmm4,%xmm0
  pmullw %xmm12,%xmm0
  paddw  %xmm1,%xmm0
  paddw  %xmm0,%xmm2
  cmp    %rax,%rdx
  jne    L0
  movdqa %xmm2,%xmm0
  movzbl 0xfd1(%rdi),%edx
  movzbl 0xfd0(%rdi),%eax
  psrldq $0x8,%xmm0
  paddw  %xmm0,%xmm2
  add    %edx,%eax
  movzbl 0xfd2(%rdi),%edx
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  add    %edx,%eax
  movzbl 0xfd3(%rdi),%edx
  paddw  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  add    %edx,%eax
  psrldq $0x2,%xmm0
  paddw  %xmm0,%xmm2
  pextrw $0x0,%xmm2,%edx
  lea    -0x3ead(%rdx,%rax,4),%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D39
type: byte[16]
name: read_data
arguments: tag: D37
type: byte[16]
name: read_data
arguments: tag: D52
type: byte[16]
name: read_data
arguments: tag: D22
type: byte[16]
name: read_data
arguments: tag: D14
type: byte[16]
name: read_data
arguments: tag: D42
type: byte[16]
name: read_data
arguments: tag: D44
type: byte[16]

tool: {"D39": [0x10,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x13,0x00,0x00,0x00]}

tool: {"D37": [0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: {"D52": [0xfc,0xff,0xfc,0xff,0xfc,0xff,0xfc,0xff,0xfc,0xff,0xfc,0xff,0xfc,0xff,0xfc,0xff]}

tool: {"D22": [0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D14": [0xd4,0x0f,0xd4,0x0f,0xd4,0x0f,0xd4,0x0f,0xd4,0x0f,0xd4,0x0f,0xd4,0x0f,0xd4,0x0f]}

tool: {"D42": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D44": [0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

assistant: ```c
unsigned short fifaStreet2ecrc(unsigned char *data) {
  unsigned short crc = 49491;
  int i;
  for (i = 0x00000010; i < 0xFD4; i++) {
    crc += data[i] * (0xFD4 - (i & ~0x3));
  }
  return crc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m68k_write_memory_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void m68k_write_memory_16(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<m68k_write_memory_16>:
  endbr64
  ret
```

assistant: ```c
void m68k_write_memory_16(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<m68k_write_memory_16>:
  endbr64
  ret
```

assistant: ```c
void m68k_write_memory_16(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<m68k_write_memory_16>:
  endbr64
  ret
```

assistant: ```c
void m68k_write_memory_16(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffe,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x16,-0x1c(%rbp)
  movl   $0x1b0,-0x18(%rbp)
  movl   $0x675ff,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x9,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <selection_sort@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L1
L19:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L1:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d 

assistant: ```c
int main(void) {
  int A[] = {-2, 12, 1, 3, 4, 22, 432, 423423, 3};
  int n = sizeof(A) / sizeof(int);
  selection_sort(A, n);
  for (int i = 0; i < n; i++)
    printf("%d ", A[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffe,(%rsp)
  movl   $0xc,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x16,0x14(%rsp)
  movl   $0x1b0,0x18(%rsp)
  movl   $0x675ff,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  mov    %rsp,%rbx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <selection_sort@plt>
  lea    0x24(%rsp),%r12
  lea    D8(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: %d 

assistant: ```c
int main(void) {
  int A[] = {-2, 12, 1, 3, 4, 22, 432, 423423, 3};
  int n = sizeof(A) / sizeof(int);
  selection_sort(A, n);
  for (int i = 0; i < n; i++)
    printf("%d ", A[i]);
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%esi
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xcfffffffe,%rax
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  movl   $0x3,0x20(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x300000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1600000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x675ff000001b0,%rax
  mov    %rax,0x18(%rsp)
  call   <selection_sort@plt>
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: %d 

assistant: ```c
int main(void) {
  int A[] = {-2, 12, 1, 3, 4, 22, 432, 423423, 3};
  int n = sizeof(A) / sizeof(int);
  selection_sort(A, n);
  for (int i = 0; i < n; i++)
    printf("%d ", A[i]);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%esi
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  movl   $0x3,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D28(%rip),%xmm0
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <selection_sort@plt>
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
type: string
name: read_data
arguments: label: D6
type: byte[16]
name: read_data
arguments: label: D28
type: byte[16]

tool: D26: %d 

tool: {"D6": [0xfe,0xff,0xff,0xff,0x0c,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D28": [0x04,0x00,0x00,0x00,0x16,0x00,0x00,0x00,0xb0,0x01,0x00,0x00,0xff,0x75,0x06,0x00]}

assistant: ```c
int main(void) {
  int A[] = {-2, 12, 1, 3, 4, 22, 432, 423423, 3};
  int n = sizeof(A) / sizeof(int);
  selection_sort(A, n);
  for (int i = 0; i < n; i++)
    printf("%d ", A[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8_to_string>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rcx
  test   $0x80,%al
  je     L20
  mov    %rsi,%rdx
  mov    %rsi,%rdi
  mov    %rsi,%r8
  shr    $0x10,%rdx
  shr    $0x8,%rdi
  and    $0x3f,%r8d
  mov    %rdx,%r9
  mov    %rdx,%rsi
  mov    %rdi,%rax
  and    $0x7f,%r9d
  and    $0xf,%esi
  and    $0x40,%edx
  mov    %rdi,%rdx
  cmove  %r9,%rsi
  mov    %rdi,%r9
  and    $0x1f,%edx
  and    $0x7f,%r9d
  test   $0x40,%dil
  cmove  %r9,%rdx
  and    $0x70000,%eax
  shl    $0xc,%rsi
  or     %r8,%rax
  or     %rsi,%rax
  shl    $0x6,%rdx
  or     %rdx,%rax
L20:
  cmp    $0x7f,%rax
  jbe    L24
  mov    %rax,%rsi
  lea    D9(%rip),%rdx
  mov    %rax,%rdi
  shr    $0x8,%rsi
  shr    $0xc,%rdi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%r9d
  mov    %rax,%rsi
  shr    $0x4,%rsi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%r8d
  mov    %rax,%rsi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%esi
  cmp    $0xfffe,%rax
  jbe    L13
  mov    %rax,%r10
  shr    $0x10,%rax
  and    $0xf,%edi
  mov    %r9b,0x7(%rcx)
  and    $0xf,%eax
  shr    $0x14,%r10
  movl   $0x3030555c,(%rcx)
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%r10,1),%r10d
  mov    %r8b,0x8(%rcx)
  mov    %sil,0x9(%rcx)
  mov    %al,0x5(%rcx)
  movzbl (%rdx,%rdi,1),%eax
  mov    %r10b,0x4(%rcx)
  mov    %al,0x6(%rcx)
  mov    $0xa,%eax
  movb   $0x0,0xa(%rcx)
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x755c,%eax
  mov    %r9b,0x3(%rcx)
  mov    %ax,(%rcx)
  movzbl (%rdx,%rdi,1),%eax
  mov    %r8b,0x4(%rcx)
  mov    %al,0x2(%rcx)
  mov    $0x6,%eax
  mov    %sil,0x5(%rcx)
  movb   $0x0,0x6(%rcx)
  ret
  nopl   (%rax)
L24:
  mov    %al,(%rcx)
  mov    $0x1,%eax
  movb   $0x0,0x1(%rcx)
  ret
```

assistant: ```c
int utf8_to_string(unsigned char buf[], unsigned long utf8) {
  unsigned long val = 0;
  static char hex[16] = "0123456789abcdef";
  if (utf8 & 0x80UL) {
    unsigned long x1, x2, x3, x4;
    x1 = (utf8 >> 24) & 0x7fUL;
    x2 = (utf8 >> 16) & 0x7fUL;
    x3 = (utf8 >> 8) & 0x7fUL;
    x4 = (utf8)&0x3fUL;
    x1 &= 0x07UL;
    if (x2 & 0x40UL)
      x2 &= 0x0fUL;
    if (x3 & 0x40UL)
      x3 &= 0x1fUL;
    val = x4 | (x3 << 6) | (x2 << 12) | (x1 << 16);
  } else
    val = utf8;
  if (val < 128) {
    buf[0] = val;
    buf[1] = 0;
    return 1;
  } else if (val < 0xffffUL) {
    buf[0] = '\\';
    buf[1] = 'u';
    buf[2] = hex[(size_t)(val >> 12)];
    buf[3] = hex[(size_t)((val >> 8) & 0xfU)];
    buf[4] = hex[(size_t)((val >> 4) & 0xfU)];
    buf[5] = hex[(size_t)(val & 0xfU)];
    buf[6] = 0;
    return 6;
  }
  buf[0] = '\\';
  buf[1] = 'U';
  buf[2] = '0';
  buf[3] = '0';
  buf[4] = hex[(size_t)(val >> 20)];
  buf[5] = hex[(size_t)((val >> 16) & 0xfU)];
  buf[6] = hex[(size_t)((val >> 12) & 0xfU)];
  buf[7] = hex[(size_t)((val >> 8) & 0xfU)];
  buf[8] = hex[(size_t)((val >> 4) & 0xfU)];
  buf[9] = hex[(size_t)(val & 0xfU)];
  buf[10] = 0;
  return 10;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8_to_string>:
  endbr64
  mov    %rsi,%rax
  mov    %rdi,%rcx
  test   $0x80,%al
  je     L22
  mov    %rsi,%rdx
  mov    %rsi,%rdi
  mov    %rsi,%r8
  shr    $0x10,%rdx
  shr    $0x8,%rdi
  and    $0x3f,%r8d
  mov    %rdx,%r9
  mov    %rdx,%rsi
  mov    %rdi,%rax
  and    $0x7f,%r9d
  and    $0xf,%esi
  and    $0x40,%edx
  mov    %rdi,%rdx
  cmove  %r9,%rsi
  mov    %rdi,%r9
  and    $0x1f,%edx
  and    $0x7f,%r9d
  test   $0x40,%dil
  cmove  %r9,%rdx
  and    $0x70000,%eax
  shl    $0xc,%rsi
  or     %r8,%rax
  or     %rsi,%rax
  shl    $0x6,%rdx
  or     %rdx,%rax
L22:
  cmp    $0x7f,%rax
  jbe    L0
  mov    %rax,%rsi
  lea    D5(%rip),%rdx
  mov    %rax,%rdi
  shr    $0x8,%rsi
  shr    $0xc,%rdi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%r9d
  mov    %rax,%rsi
  shr    $0x4,%rsi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%r8d
  mov    %rax,%rsi
  and    $0xf,%esi
  movzbl (%rdx,%rsi,1),%esi
  cmp    $0xfffe,%rax
  jbe    L18
  mov    %rax,%r10
  shr    $0x10,%rax
  and    $0xf,%edi
  mov    %r9b,0x7(%rcx)
  and    $0xf,%eax
  shr    $0x14,%r10
  movl   $0x3030555c,(%rcx)
  movzbl (%rdx,%rax,1),%eax
  movzbl (%rdx,%r10,1),%r10d
  mov    %r8b,0x8(%rcx)
  mov    %sil,0x9(%rcx)
  mov    %al,0x5(%rcx)
  movzbl (%rdx,%rdi,1),%eax
  mov    %r10b,0x4(%rcx)
  mov    %al,0x6(%rcx)
  mov    $0xa,%eax
  movb   $0x0,0xa(%rcx)
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x755c,%eax
  mov    %r9b,0x3(%rcx)
  mov    %ax,(%rcx)
  movzbl (%rdx,%rdi,1),%eax
  mov    %r8b,0x4(%rcx)
  mov    %al,0x2(%rcx)
  mov    $0x6,%eax
  mov    %sil,0x5(%rcx)
  movb   $0x0,0x6(%rcx)
  ret
  nopl   (%rax)
L0:
  mov    %al,(%rcx)
  mov    $0x1,%eax
  movb   $0x0,0x1(%rcx)
  ret
```

assistant: ```c
int utf8_to_string(unsigned char buf[], unsigned long utf8) {
  unsigned long val = 0;
  static char hex[16] = "0123456789abcdef";
  if (utf8 & 0x80UL) {
    unsigned long x1, x2, x3, x4;
    x1 = (utf8 >> 24) & 0x7fUL;
    x2 = (utf8 >> 16) & 0x7fUL;
    x3 = (utf8 >> 8) & 0x7fUL;
    x4 = (utf8)&0x3fUL;
    x1 &= 0x07UL;
    if (x2 & 0x40UL)
      x2 &= 0x0fUL;
    if (x3 & 0x40UL)
      x3 &= 0x1fUL;
    val = x4 | (x3 << 6) | (x2 << 12) | (x1 << 16);
  } else
    val = utf8;
  if (val < 128) {
    buf[0] = val;
    buf[1] = 0;
    return 1;
  } else if (val < 0xffffUL) {
    buf[0] = '\\';
    buf[1] = 'u';
    buf[2] = hex[(size_t)(val >> 12)];
    buf[3] = hex[(size_t)((val >> 8) & 0xfU)];
    buf[4] = hex[(size_t)((val >> 4) & 0xfU)];
    buf[5] = hex[(size_t)(val & 0xfU)];
    buf[6] = 0;
    return 6;
  }
  buf[0] = '\\';
  buf[1] = 'U';
  buf[2] = '0';
  buf[3] = '0';
  buf[4] = hex[(size_t)(val >> 20)];
  buf[5] = hex[(size_t)((val >> 16) & 0xfU)];
  buf[6] = hex[(size_t)((val >> 12) & 0xfU)];
  buf[7] = hex[(size_t)((val >> 8) & 0xfU)];
  buf[8] = hex[(size_t)((val >> 4) & 0xfU)];
  buf[9] = hex[(size_t)(val & 0xfU)];
  buf[10] = 0;
  return 10;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L39:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L3:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movzwl (%rdx,%rax,2),%eax
  movswl %ax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  movzwl (%rcx,%rax,2),%eax
  movswl %ax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x7,-0x8(%rbp)
  jle    L3
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x7,-0xc(%rbp)
  jle    L39
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short foo(short image[][16], short block[][8]) {
  int sad, diff = 0;
  int i, j;
  int tmp;
  for (i = 0; i < 8; i++) {
    sad = 0;
    for (j = 0; j < 8; j++) {
      tmp = image[i][j] - block[i][j];
      sad += (tmp < 0) ? -tmp : tmp;
    }
    diff += sad;
  }
  return diff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %rdi,%r11
  lea    0x100(%rdi),%rbx
  mov    $0x0,%eax
L3:
  mov    %r11,%r10
  mov    %rsi,%r9
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L18:
  movswl (%r10,%rcx,1),%edx
  movswl (%r9,%rcx,1),%edi
  sub    %edi,%edx
  mov    %edx,%edi
  neg    %edi
  cmovns %edi,%edx
  add    %edx,%r8d
  add    $0x2,%rcx
  cmp    $0x10,%rcx
  jne    L18
  add    %r8d,%eax
  add    $0x20,%r11
  add    $0x10,%rsi
  cmp    %rbx,%r11
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
short foo(short image[][16], short block[][8]) {
  int sad, diff = 0;
  int i, j;
  int tmp;
  for (i = 0; i < 8; i++) {
    sad = 0;
    for (j = 0; j < 8; j++) {
      tmp = image[i][j] - block[i][j];
      sad += (tmp < 0) ? -tmp : tmp;
    }
    diff += sad;
  }
  return diff;
}
```