ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<cescape_char>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  cmp    $0x27,%dil
  jg     L78
  cmp    $0x6,%dil
  jle    L129
  lea    -0x7(%rdi),%eax
  cmp    $0x20,%al
  ja     L129
  lea    D2(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L78:
  cmp    $0x5c,%dil
  jne    L129
  mov    $0x5c5c,%ecx
  mov    $0x2,%eax
  mov    %cx,(%rsi)
L74:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L129:
  lea    -0x20(%rbx),%eax
  cmp    $0x5e,%al
  ja     L152
  mov    %bl,(%rsi)
  mov    $0x1,%eax
  jmp    L74
  nopl   0x0(%rax)
  mov    $0x615c,%eax
  mov    %ax,(%rsi)
  mov    $0x2,%eax
  jmp    L74
  nop
  mov    $0x625c,%ebx
  mov    $0x2,%eax
  mov    %bx,(%rsi)
  jmp    L74
  nop
  mov    $0x745c,%r8d
  mov    $0x2,%eax
  mov    %r8w,(%rsi)
  jmp    L74
  nopl   0x0(%rax)
  mov    $0x6e5c,%r10d
  mov    $0x2,%eax
  mov    %r10w,(%rsi)
  jmp    L74
  nopl   0x0(%rax)
  mov    $0x765c,%edi
  mov    $0x2,%eax
  mov    %di,(%rsi)
  jmp    L74
  nopw   0x0(%rax,%rax,1)
  mov    $0x665c,%r11d
  mov    $0x2,%eax
  mov    %r11w,(%rsi)
  jmp    L74
  nopl   0x0(%rax)
  mov    $0x725c,%r9d
  mov    $0x2,%eax
  mov    %r9w,(%rsi)
  jmp    L74
  nopl   0x0(%rax)
  mov    $0x225c,%edx
  mov    $0x2,%eax
  mov    %dx,(%rsi)
  jmp    L74
  nopw   0x0(%rax,%rax,1)
  mov    $0x275c,%eax
  mov    %ax,(%rsi)
  mov    $0x2,%eax
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L152:
  movb   $0x5c,(%rsi)
  mov    %ebx,%edi
  shr    $0x6,%dil
  mov    %rsi,0x8(%rsp)
  movzbl %dil,%edi
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edi
  shr    $0x3,%dil
  mov    %al,0x1(%rsi)
  movzbl %dil,%edi
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  movzbl %bl,%edi
  mov    %al,0x2(%rsi)
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  mov    %al,0x3(%rsi)
  mov    $0x4,%eax
  jmp    L74
```

assistant: ```c
int cescape_char(char c, char *buf) {
  char *buf_old = buf;
  switch (c) {
  case '\a':
    *(buf++) = '\\';
    *(buf++) = 'a';
    break;
  case '\b':
    *(buf++) = '\\';
    *(buf++) = 'b';
    break;
  case '\f':
    *(buf++) = '\\';
    *(buf++) = 'f';
    break;
  case '\n':
    *(buf++) = '\\';
    *(buf++) = 'n';
    break;
  case '\r':
    *(buf++) = '\\';
    *(buf++) = 'r';
    break;
  case '\t':
    *(buf++) = '\\';
    *(buf++) = 't';
    break;
  case '\v':
    *(buf++) = '\\';
    *(buf++) = 'v';
    break;
  case '\\':
    *(buf++) = '\\';
    *(buf++) = '\\';
    break;
  case '"':
    *(buf++) = '\\';
    *(buf++) = '"';
    break;
  case '\'':
    *(buf++) = '\\';
    *(buf++) = '\'';
    break;
  default:
    if ((c < ' ') || (c >= 127)) {
      *(buf++) = '\\';
      *(buf++) = octchar((unsigned char)c >> 6);
      *(buf++) = octchar((unsigned char)c >> 3);
      *(buf++) = octchar((unsigned char)c);
    } else
      *(buf++) = c;
    break;
  }
  return buf - buf_old;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cescape_char>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  cmp    $0x27,%dil
  jg     L72
  cmp    $0x6,%dil
  jle    L52
  lea    -0x7(%rdi),%eax
  cmp    $0x20,%al
  ja     L52
  lea    D7(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L72:
  cmp    $0x5c,%dil
  jne    L52
  mov    $0x5c5c,%ecx
  mov    $0x2,%eax
  mov    %cx,(%rsi)
L155:
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L52:
  lea    -0x20(%rbx),%eax
  cmp    $0x5e,%al
  ja     L79
  mov    %bl,(%rsi)
  mov    $0x1,%eax
  jmp    L155
  nopl   0x0(%rax)
  mov    $0x615c,%eax
  mov    %ax,(%rsi)
  mov    $0x2,%eax
  jmp    L155
  nop
  mov    $0x625c,%ebx
  mov    $0x2,%eax
  mov    %bx,(%rsi)
  jmp    L155
  nop
  mov    $0x745c,%r8d
  mov    $0x2,%eax
  mov    %r8w,(%rsi)
  jmp    L155
  nopl   0x0(%rax)
  mov    $0x6e5c,%r10d
  mov    $0x2,%eax
  mov    %r10w,(%rsi)
  jmp    L155
  nopl   0x0(%rax)
  mov    $0x765c,%edi
  mov    $0x2,%eax
  mov    %di,(%rsi)
  jmp    L155
  nopw   0x0(%rax,%rax,1)
  mov    $0x665c,%r11d
  mov    $0x2,%eax
  mov    %r11w,(%rsi)
  jmp    L155
  nopl   0x0(%rax)
  mov    $0x725c,%r9d
  mov    $0x2,%eax
  mov    %r9w,(%rsi)
  jmp    L155
  nopl   0x0(%rax)
  mov    $0x225c,%edx
  mov    $0x2,%eax
  mov    %dx,(%rsi)
  jmp    L155
  nopw   0x0(%rax,%rax,1)
  mov    $0x275c,%eax
  mov    %ax,(%rsi)
  mov    $0x2,%eax
  jmp    L155
  nopw   0x0(%rax,%rax,1)
L79:
  movb   $0x5c,(%rsi)
  mov    %ebx,%edi
  shr    $0x6,%dil
  mov    %rsi,0x8(%rsp)
  movzbl %dil,%edi
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edi
  shr    $0x3,%dil
  mov    %al,0x1(%rsi)
  movzbl %dil,%edi
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  movzbl %bl,%edi
  mov    %al,0x2(%rsi)
  call   <octchar@plt>
  mov    0x8(%rsp),%rsi
  mov    %al,0x3(%rsi)
  mov    $0x4,%eax
  jmp    L155
```

assistant: ```c
int cescape_char(char c, char *buf) {
  char *buf_old = buf;
  switch (c) {
  case '\a':
    *(buf++) = '\\';
    *(buf++) = 'a';
    break;
  case '\b':
    *(buf++) = '\\';
    *(buf++) = 'b';
    break;
  case '\f':
    *(buf++) = '\\';
    *(buf++) = 'f';
    break;
  case '\n':
    *(buf++) = '\\';
    *(buf++) = 'n';
    break;
  case '\r':
    *(buf++) = '\\';
    *(buf++) = 'r';
    break;
  case '\t':
    *(buf++) = '\\';
    *(buf++) = 't';
    break;
  case '\v':
    *(buf++) = '\\';
    *(buf++) = 'v';
    break;
  case '\\':
    *(buf++) = '\\';
    *(buf++) = '\\';
    break;
  case '"':
    *(buf++) = '\\';
    *(buf++) = '"';
    break;
  case '\'':
    *(buf++) = '\\';
    *(buf++) = '\'';
    break;
  default:
    if ((c < ' ') || (c >= 127)) {
      *(buf++) = '\\';
      *(buf++) = octchar((unsigned char)c >> 6);
      *(buf++) = octchar((unsigned char)c >> 3);
      *(buf++) = octchar((unsigned char)c);
    } else
      *(buf++) = c;
    break;
  }
  return buf - buf_old;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yas_bma250_set_selftest_stn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x32,%edi
  call   <yas_bma250_read_reg_byte@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xfffffffb,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  shl    $0x2,%eax
  and    $0x4,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x32,%edi
  call   <yas_bma250_write_reg_byte@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int yas_bma250_set_selftest_stn(unsigned char stn) {
  int ret = (0);
  int reg_data = 0;
  reg_data = yas_bma250_read_reg_byte(0x32);
  reg_data = ((reg_data & ~0x04) | ((stn << 2) & 0x04));
  ret = yas_bma250_write_reg_byte(0x32, reg_data);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yas_bma250_set_selftest_stn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x32,%edi
  call   <yas_bma250_read_reg_byte@plt>
  and    $0xfffffffb,%eax
  lea    0x0(,%rbx,4),%esi
  and    $0x4,%esi
  or     %eax,%esi
  mov    $0x32,%edi
  call   <yas_bma250_write_reg_byte@plt>
  pop    %rbx
  ret
```

assistant: ```c
int yas_bma250_set_selftest_stn(unsigned char stn) {
  int ret = (0);
  int reg_data = 0;
  reg_data = yas_bma250_read_reg_byte(0x32);
  reg_data = ((reg_data & ~0x04) | ((stn << 2) & 0x04));
  ret = yas_bma250_write_reg_byte(0x32, reg_data);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<yas_bma250_set_selftest_stn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x32,%edi
  call   <yas_bma250_read_reg_byte@plt>
  lea    0x0(,%rbx,4),%esi
  mov    $0x32,%edi
  pop    %rbx
  and    $0xfffffffb,%eax
  and    $0x4,%esi
  or     %eax,%esi
  jmp    1060 <yas_bma250_write_reg_byte@plt>
```

assistant: ```c
int yas_bma250_set_selftest_stn(unsigned char stn) {
  int ret = (0);
  int reg_data = 0;
  reg_data = yas_bma250_read_reg_byte(0x32);
  reg_data = ((reg_data & ~0x04) | ((stn << 2) & 0x04));
  ret = yas_bma250_write_reg_byte(0x32, reg_data);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movdqa D1(%rip),%xmm0
  movaps %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    $0xc,%eax
  jne    L37
  mov    -0x2c(%rbp),%eax
  cmp    $0xffffffde,%eax
  jne    L37
  mov    -0x28(%rbp),%eax
  cmp    $0xffffffc8,%eax
  jne    L37
  mov    -0x24(%rbp),%eax
  cmp    $0x4e,%eax
  je     L9
L37:
  call   <abort@plt>
L9:
  movdqa D12(%rip),%xmm0
  movaps %xmm0,-0x20(%rbp)
  movdqa -0x20(%rbp),%xmm0
  movaps %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cmp    $0xffffffeb,%eax
  jne    L34
  mov    -0x2c(%rbp),%eax
  cmp    $0xffffffd5,%eax
  jne    L34
  mov    -0x28(%rbp),%eax
  cmp    $0x41,%eax
  jne    L34
  mov    -0x24(%rbp),%eax
  cmp    $0x57,%eax
  je     L81
L34:
  call   <abort@plt>
L81:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: byte[16]
name: read_data
arguments: data_label: D12
type_infered: byte[16]

tool: {"D1": [0x0c,0x00,0x00,0x00,0xde,0xff,0xff,0xff,0xc8,0xff,0xff,0xff,0x4e,0x00,0x00,0x00]}

tool: {"D12": [0xeb,0xff,0xff,0xff,0xd5,0xff,0xff,0xff,0x41,0x00,0x00,0x00,0x57,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  __attribute__((vector_size(4 * sizeof(int)))) int vi = {12, -34, -56, 78};
#pragma acc parallel copy(vi)
  {
    if (vi[0] != 12 || vi[1] != -34 || vi[2] != -56 || vi[3] != 78)
      __builtin_abort();
    __attribute__((vector_size(4 * sizeof(int)))) int vi_ = {-21, -43, 65, 87};
    vi = vi_;
  }
  if (vi[0] != -21 || vi[1] != -43 || vi[2] != 65 || vi[3] != 87)
    __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  __attribute__((vector_size(4 * sizeof(int)))) int vi = {12, -34, -56, 78};
#pragma acc parallel copy(vi)
  {
    if (vi[0] != 12 || vi[1] != -34 || vi[2] != -56 || vi[3] != 78)
      __builtin_abort();
    __attribute__((vector_size(4 * sizeof(int)))) int vi_ = {-21, -43, 65, 87};
    vi = vi_;
  }
  if (vi[0] != -21 || vi[1] != -43 || vi[2] != 65 || vi[3] != 87)
    __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  __attribute__((vector_size(4 * sizeof(int)))) int vi = {12, -34, -56, 78};
#pragma acc parallel copy(vi)
  {
    if (vi[0] != 12 || vi[1] != -34 || vi[2] != -56 || vi[3] != 78)
      __builtin_abort();
    __attribute__((vector_size(4 * sizeof(int)))) int vi_ = {-21, -43, 65, 87};
    vi = vi_;
  }
  if (vi[0] != -21 || vi[1] != -43 || vi[2] != 65 || vi[3] != 87)
    __builtin_abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  __attribute__((vector_size(4 * sizeof(int)))) int vi = {12, -34, -56, 78};
#pragma acc parallel copy(vi)
  {
    if (vi[0] != 12 || vi[1] != -34 || vi[2] != -56 || vi[3] != 78)
      __builtin_abort();
    __attribute__((vector_size(4 * sizeof(int)))) int vi_ = {-21, -43, 65, 87};
    vi = vi_;
  }
  if (vi[0] != -21 || vi[1] != -43 || vi[2] != 65 || vi[3] != 87)
    __builtin_abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<make_subgeom>:
  endbr64
  cmp    $0x1,%edi
  je     L53
  cmp    $0x2,%edi
  je     L9
  jle    L34
  test   %ecx,%ecx
  jle    L34
  lea    0x1(%rcx),%r9d
  shl    $0x2,%r9
  mov    $0x4,%eax
L33:
  movslq (%r8,%rax,1),%rdi
  mov    (%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    (%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  movslq (%r8,%rax,1),%rdi
  mov    0x8(%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    0x8(%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  movslq (%r8,%rax,1),%rdi
  mov    0x10(%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    0x10(%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L33
L34:
  ret
L53:
  test   %ecx,%ecx
  jle    L34
  lea    0x1(%rcx),%r9d
  shl    $0x2,%r9
  mov    $0x4,%eax
L48:
  movslq (%r8,%rax,1),%rdi
  mov    (%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    (%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L48
  ret
L9:
  test   %ecx,%ecx
  jle    L34
  lea    0x1(%rcx),%r9d
  shl    $0x2,%r9
  mov    $0x4,%eax
L70:
  movslq (%r8,%rax,1),%rdi
  mov    (%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    (%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  movslq (%r8,%rax,1),%rdi
  mov    0x8(%rsi),%rcx
  movss  (%rcx,%rdi,4),%xmm0
  mov    0x8(%rdx),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L70
  ret
```

assistant: ```c
void make_subgeom(int igeom, float **coords, float **subcoords, int subnvtxs, int *loc2glob) {
  int i;
  if (igeom == 1) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
    }
  } else if (igeom == 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
    }
  } else if (igeom > 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
      subcoords[2][i] = coords[2][loc2glob[i]];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<make_subgeom>:
  endbr64
  cmp    $0x1,%edi
  je     L31
  cmp    $0x2,%edi
  je     L25
  jle    L27
  test   %ecx,%ecx
  jle    L27
  push   %rbx
  mov    (%rsi),%rbx
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  mov    0x8(%rsi),%r10
  mov    0x10(%rsi),%rdi
  mov    (%rdx),%r11
  mov    0x8(%rdx),%r9
  mov    0x10(%rdx),%rsi
  nop
L7:
  movslq (%r8,%rax,4),%rdx
  movss  (%rbx,%rdx,4),%xmm0
  movss  %xmm0,(%r11,%rax,4)
  movss  (%r10,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L7
  pop    %rbx
  ret
L25:
  test   %ecx,%ecx
  jle    L27
  mov    (%rsi),%r10
  mov    0x8(%rsi),%rdi
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  mov    (%rdx),%r9
  mov    0x8(%rdx),%rsi
  nopw   0x0(%rax,%rax,1)
L20:
  movslq (%r8,%rax,4),%rdx
  movss  (%r10,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L20
  ret
  nopl   0x0(%rax)
L31:
  test   %ecx,%ecx
  jle    L27
  mov    (%rsi),%rdi
  mov    (%rdx),%rsi
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L55:
  movslq (%r8,%rax,4),%rdx
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L55
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  ret
```

assistant: ```c
void make_subgeom(int igeom, float **coords, float **subcoords, int subnvtxs, int *loc2glob) {
  int i;
  if (igeom == 1) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
    }
  } else if (igeom == 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
    }
  } else if (igeom > 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
      subcoords[2][i] = coords[2][loc2glob[i]];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_subgeom>:
  endbr64
  cmp    $0x1,%edi
  je     L36
  cmp    $0x2,%edi
  je     L43
  jle    L79
  test   %ecx,%ecx
  jle    L79
  push   %rbx
  mov    (%rsi),%rbx
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  mov    0x8(%rsi),%r10
  mov    0x10(%rsi),%rdi
  mov    (%rdx),%r11
  mov    0x8(%rdx),%r9
  mov    0x10(%rdx),%rsi
  nop
L57:
  movslq (%r8,%rax,4),%rdx
  movss  (%rbx,%rdx,4),%xmm0
  movss  %xmm0,(%r11,%rax,4)
  movss  (%r10,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L57
  pop    %rbx
  ret
L43:
  test   %ecx,%ecx
  jle    L79
  mov    (%rsi),%r10
  mov    0x8(%rsi),%rdi
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  mov    (%rdx),%r9
  mov    0x8(%rdx),%rsi
  nopw   0x0(%rax,%rax,1)
L34:
  movslq (%r8,%rax,4),%rdx
  movss  (%r10,%rdx,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L34
  ret
  nopl   0x0(%rax)
L36:
  test   %ecx,%ecx
  jle    L79
  mov    (%rsi),%rdi
  mov    (%rdx),%rsi
  lea    0x1(%rcx),%ecx
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L28:
  movslq (%r8,%rax,4),%rdx
  movss  (%rdi,%rdx,4),%xmm0
  movss  %xmm0,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L28
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  ret
```

assistant: ```c
void make_subgeom(int igeom, float **coords, float **subcoords, int subnvtxs, int *loc2glob) {
  int i;
  if (igeom == 1) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
    }
  } else if (igeom == 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
    }
  } else if (igeom > 2) {
    for (i = 1; i <= subnvtxs; i++) {
      subcoords[0][i] = coords[0][loc2glob[i]];
      subcoords[1][i] = coords[1][loc2glob[i]];
      subcoords[2][i] = coords[2][loc2glob[i]];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<testb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  not    %eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int testb(void *s, unsigned int i) {
  unsigned char *v = s;
  v += i >> 3;
  return (*v & (1 << (7 - (i % 8)))) != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testb>:
  endbr64
  mov    %esi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  movzbl (%rdi,%rax,1),%eax
  not    %esi
  mov    %esi,%ecx
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int testb(void *s, unsigned int i) {
  unsigned char *v = s;
  v += i >> 3;
  return (*v & (1 << (7 - (i % 8)))) != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<testb>:
  endbr64
  mov    %esi,%eax
  not    %esi
  shr    $0x3,%eax
  mov    %esi,%ecx
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int testb(void *s, unsigned int i) {
  unsigned char *v = s;
  v += i >> 3;
  return (*v & (1 << (7 - (i % 8)))) != 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testb>:
  endbr64
  mov    %esi,%eax
  not    %esi
  shr    $0x3,%eax
  mov    %esi,%ecx
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int testb(void *s, unsigned int i) {
  unsigned char *v = s;
  v += i >> 3;
  return (*v & (1 << (7 - (i % 8)))) != 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x16,-0x30(%rbp)
  movl   $0x25,-0x2c(%rbp)
  movl   $0x56,-0x28(%rbp)
  movl   $0x36,-0x24(%rbp)
  movl   $0x20,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x63,-0x14(%rbp)
  movl   $0x22,-0x10(%rbp)
  movl   $0x9,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L12
L24:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L12:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: %d  

assistant: ```c
int main() {
  int a[] = {22, 37, 86, 54, 32, 1, 7, 99, 34};
  int n = 9;
  quickSort(a, n);
  for (int i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x16,(%rsp)
  movl   $0x25,0x4(%rsp)
  movl   $0x56,0x8(%rsp)
  movl   $0x36,0xc(%rsp)
  movl   $0x20,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x63,0x1c(%rsp)
  movl   $0x22,0x20(%rsp)
  mov    %rsp,%rbx
  mov    $0x9,%esi
  mov    %rbx,%rdi
  call   <quickSort@plt>
  lea    0x24(%rsp),%r12
  lea    D4(%rip),%rbp
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: %d  

assistant: ```c
int main() {
  int a[] = {22, 37, 86, 54, 32, 1, 7, 99, 34};
  int n = 9;
  quickSort(a, n);
  for (int i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x9,%esi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2500000016,%rax
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r12
  movl   $0x22,0x20(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x3600000056,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000020,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x6300000007,%rax
  mov    %rax,0x18(%rsp)
  call   <quickSort@plt>
  nopl   0x0(%rax)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: %d  

assistant: ```c
int main() {
  int a[] = {22, 37, 86, 54, 32, 1, 7, 99, 34};
  int n = 9;
  quickSort(a, n);
  for (int i = 0; i < n; i++) {
    printf("%d  ", a[i]);
  }
  printf("\n");
  return 0;
}
```