user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%rsi
  lea    D56(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D38(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x20(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  mov    0x20(%rsp),%ecx
  test   %ecx,%ecx
  jle    L12
  lea    0x24(%rsp),%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x18(%rsp)
  nopl   (%rax)
L6:
  mov    0x18(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x24(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x24(%rsp),%edx
  mov    %rax,0x10(%rsp)
  test   %edx,%edx
  jle    L83
  mov    %rax,%r13
  mov    %r12,%r15
  xor    %r14d,%r14d
  sub    %r12,%r13
L91:
  mov    %r15,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <fscanf@plt>
  lea    (%r15,%r13,1),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%r9d
  add    $0x4,%r15
  cmp    %r14d,%r9d
  jg     L91
  test   %r9d,%r9d
  jle    L83
  mov    %r12,%r10
  mov    $0x5f5e0ff,%r15d
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L53:
  lea    (%r10,%r13,1),%rsi
  mov    %r12,%rcx
  xor    %edx,%edx
  nopl   0x0(%rax)
L25:
  cmp    %edx,%edi
  je     L42
  mov    (%r10),%eax
  mov    (%rsi),%r8d
  sub    (%rcx),%eax
  sub    (%rcx,%r13,1),%r8d
  imul   %eax,%eax
  imul   %r8d,%r8d
  add    %r8d,%eax
  cmp    %eax,%r15d
  cmovg  %eax,%r15d
L42:
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edx,%r9d
  jne    L25
  add    $0x1,%edi
  add    $0x4,%r10
  cmp    %edi,%r9d
  jne    L53
L31:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  addl   $0x1,0xc(%rsp)
  pxor   %xmm0,%xmm0
  mov    0xc(%rsp),%r14d
  lea    D30(%rip),%rdi
  cvtsi2sd %r14d,%xmm0
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  lea    D54(%rip),%rdi
  cvtsi2sd %r15d,%xmm0
  mulsd  D41(%rip),%xmm0
  call   <printf@plt>
  cmp    0x20(%rsp),%r14d
  jl     L6
L12:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  mov    $0x5f5e0ff,%r15d
  jmp    L31
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D56
datatype: string
name: retrieve_data
arguments: tag: D38
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D54
datatype: string
name: retrieve_data
arguments: tag: D41
datatype: byte[8]

tool: D24: rt

tool: D56: squirrels.in

tool: D38:  %d

tool: D30: Campus #%d:


tool: D54: Maximum territory area = %.3f



tool: {"D41": [0x11,0x2d,0x44,0x54,0xfb,0x21,0xe9,0x3f]}

assistant: ```c
int main() {
  int c, t;
  int *x, *y;
  int testCase, i, j;
  int min;
  FILE *in = fopen("squirrels.in", "rt");
  fscanf(in, " %d", &c);
  for (testCase = 0; testCase < c; testCase++) {
    fscanf(in, " %d", &t);
    x = (int *)malloc(t * sizeof(int));
    y = (int *)malloc(t * sizeof(int));
    for (i = 0; i < t; i++) {
      fscanf(in, " %d", &(x[i]));
      fscanf(in, " %d", &(y[i]));
    }
    min = 99999999;
    for (i = 0; i < t; i++) {
      for (j = 0; j < t; j++) {
        if (i != j) {
          int dx = x[i] - x[j];
          int dy = y[i] - y[j];
          int distSq = dx * dx + dy * dy;
          if (min > distSq)
            min = distSq;
        }
      }
    }
    free(x);
    free(y);
    double answer = 3.14159265358979 / 4.0 * min;
    printf("Campus #%d:\n", testCase + 1);
    printf("Maximum territory area = %.3f\n\n", answer);
  }
  fclose(in);
  return 0;
}
```