ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0xad8,%rsp
  lea    D15(%rip),%r13
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61ac8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  lea    0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %edx,%edx
  jle    L74
  mov    $0x1,%r12d
  lea    D49(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L53:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L33
  lea    0x20(%rsp),%rbx
  xor    %r14d,%r14d
  mov    %rbx,%r15
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    %r15,%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  add    $0x1,%r14d
  call   <scanf@plt>
  mov    0x18(%rsp),%ecx
  mov    D28(%rip),%rax
  add    $0x8,%r15
  movapd D28(%rip),%xmm2
  cmp    %r14d,%ecx
  movq   %rax,%xmm1
  jg     L94
  cmp    $0x1,%ecx
  jle    L33
  mov    $0x1,%esi
  lea    0x30(%rsp),%rdi
  nopl   (%rax)
L7:
  mov    %ecx,%eax
  mov    %esi,%r8d
  sub    $0x1,%ecx
  cmp    $0x1,%eax
  cmovg  %ecx,%r8d
  cmp    $0x2,%eax
  je     L4
  mov    %r8d,%edx
  mov    %rbx,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L61:
  movupd 0x8(%rax),%xmm0
  addpd  (%rax),%xmm0
  add    $0x10,%rax
  mulpd  %xmm2,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L61
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L45
L69:
  movslq %eax,%rdx
  add    $0x1,%eax
  cltq
  movsd  0x20(%rsp,%rax,8),%xmm0
  addsd  0x20(%rsp,%rdx,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x20(%rsp,%rdx,8)
L45:
  cmp    $0x1,%ecx
  jne    L7
  movl   $0x1,0x18(%rsp)
L33:
  movsd  0x20(%rsp),%xmm0
  mov    %r12d,%esi
  lea    D29(%rip),%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x1c(%rsp)
  jge    L53
L74:
  mov    0x61ac8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  add    $0x61ad8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  jmp    L69
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D49
type_guessed: string
name: unpack_data
arguments: data_tag: D28
type_guessed: byte[16]
name: unpack_data
arguments: data_tag: D29
type_guessed: string

tool: D15: %d

tool: D49: %lf

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D29: Case #%d: %.3lf


assistant: ```c
int main() {
  int n, t, i, j;
  double a[50005];
  scanf("%d", &t);
  for (j = 1; j <= t; j++) {
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%lf", &a[i]);
    while (n > 1) {
      for (i = 0; i < n - 1; i++) {
        a[i] = (a[i] + a[i + 1]) / 2;
      }
      n--;
    }
    printf("Case #%d: %.3lf\n", j, a[0]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pukeif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puke@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void pukeif(int ret, const char *message) {
  if (ret != 0) {
    puke(message);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pukeif>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
L2:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <puke@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pukeif(int ret, const char *message) {
  if (ret != 0) {
    puke(message);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pukeif>:
  endbr64
  test   %edi,%edi
  jne    L3
  ret
  nopl   0x0(%rax)
L3:
  mov    %rsi,%rdi
  jmp    1050 <puke@plt>
```

assistant: ```c
void pukeif(int ret, const char *message) {
  if (ret != 0) {
    puke(message);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pukeif>:
  endbr64
  test   %edi,%edi
  jne    L4
  ret
  nopl   0x0(%rax)
L4:
  mov    %rsi,%rdi
  jmp    1050 <puke@plt>
```

assistant: ```c
void pukeif(int ret, const char *message) {
  if (ret != 0) {
    puke(message);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<shellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L16
L65:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L35
L29:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L26:
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L47:
  cmpl   $0x0,-0x8(%rbp)
  js     L49
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L26
L49:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
L16:
  cmpl   $0x0,-0x10(%rbp)
  jg     L65
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: gap: %d, i: %d, j: %d, j+gap: %d


assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        printf("gap: %d, i: %d, j: %d, j+gap: %d\n", gap, i, j, j + gap);
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shellsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %esi,0x28(%rsp)
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  mov    %eax,%r13d
  lea    -0x1(%rsi),%eax
  mov    %eax,0x2c(%rsp)
  lea    D4(%rip),%r15
  cmp    $0x1,%esi
  jg     L0
L68:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    0x18(%rsp),%rsi
  lea    0x1(%rsi),%rax
  cmp    0x20(%rsp),%rsi
  je     L88
  mov    %rax,0x18(%rsp)
L57:
  mov    0xc(%rsp),%r14d
  mov    0x18(%rsp),%rax
  add    %eax,%r14d
  test   %eax,%eax
  js     L24
  mov    %rax,%rbx
L79:
  mov    %ebx,%ecx
  mov    0xc(%rsp),%eax
  lea    (%rax,%rbx,1),%r8d
  mov    (%r12,%rbx,4),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jle    L24
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,4),%eax
  mov    (%r12,%rbx,4),%edx
  mov    %edx,0x0(%rbp,%rbx,4)
  mov    %eax,(%r12,%rbx,4)
  add    0x10(%rsp),%rbx
  test   %ebx,%ebx
  jns    L79
  jmp    L24
L88:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %r13d,%eax
  sar    %eax
  cmp    $0x1,%r13d
  jle    L68
  mov    %eax,%r13d
L0:
  cmp    %r13d,0x28(%rsp)
  jle    L88
  mov    %r13d,0xc(%rsp)
  mov    0x2c(%rsp),%eax
  sub    %r13d,%eax
  mov    %rax,0x20(%rsp)
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%r12
  movq   $0x0,0x18(%rsp)
  mov    %r13d,%eax
  neg    %eax
  cltq
  mov    %rax,0x10(%rsp)
  jmp    L57
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: gap: %d, i: %d, j: %d, j+gap: %d


assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        printf("gap: %d, i: %d, j: %d, j+gap: %d\n", gap, i, j, j + gap);
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shellsort>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %esi,%r15d
  lea    -0x1(%rax),%esi
  mov    %esi,0x1c(%rsp)
  cmp    $0x1,%eax
  jle    L9
  nopl   0x0(%rax)
L31:
  cmp    %r15d,0x18(%rsp)
  jle    L38
  movq   $0x0,0x8(%rsp)
  mov    0x1c(%rsp),%eax
  mov    %r15d,%ebp
  neg    %ebp
  sub    %r15d,%eax
  mov    %rax,0x10(%rsp)
  movslq %r15d,%rax
  lea    (%r14,%rax,4),%r13
  movslq %ebp,%rax
  mov    %rax,(%rsp)
  mov    %r14,%rax
  mov    %r13,%r14
  mov    %rax,%r13
  nopl   0x0(%rax)
L72:
  mov    0x8(%rsp),%rbx
  lea    (%r15,%rbx,1),%ebp
  mov    %ebp,%eax
  mov    %r15d,%ebp
  mov    %eax,%r15d
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x0(%r13,%rbx,4),%eax
  mov    (%r14,%rbx,4),%edx
  mov    %edx,0x0(%r13,%rbx,4)
  mov    %eax,(%r14,%rbx,4)
  add    (%rsp),%rbx
  test   %ebx,%ebx
  js     L27
L67:
  mov    (%r14,%rbx,4),%eax
  mov    %ebx,%ecx
  lea    0x0(%rbp,%rbx,1),%r8d
  cmp    %eax,0x0(%r13,%rbx,4)
  jg     L74
L27:
  mov    0x8(%rsp),%rdi
  mov    %ebp,%r15d
  lea    0x1(%rdi),%rax
  cmp    0x10(%rsp),%rdi
  je     L54
  mov    %rax,0x8(%rsp)
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %r13,%r14
L38:
  sar    %r15d
  jne    L31
L9:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: gap: %d, i: %d, j: %d, j+gap: %d


assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        printf("gap: %d, i: %d, j: %d, j+gap: %d\n", gap, i, j, j + gap);
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shellsort>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x18(%rsp)
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %esi,%r15d
  lea    -0x1(%rax),%esi
  mov    %esi,0x1c(%rsp)
  cmp    $0x1,%eax
  jle    L55
  nopl   0x0(%rax)
L26:
  cmp    %r15d,0x18(%rsp)
  jle    L60
  movq   $0x0,0x8(%rsp)
  mov    0x1c(%rsp),%eax
  mov    %r15d,%ebp
  neg    %ebp
  mov    0x8(%rsp),%rbx
  sub    %r15d,%eax
  mov    %rax,0x10(%rsp)
  movslq %r15d,%rax
  lea    (%r14,%rax,4),%r13
  movslq %ebp,%rax
  mov    %rax,(%rsp)
  mov    %r14,%rax
  mov    %r13,%r14
  mov    %rax,%r13
  nopl   0x0(%rax)
L15:
  lea    (%r15,%rbx,1),%ebp
  mov    %ebp,%eax
  mov    %r15d,%ebp
  mov    %eax,%r15d
  jmp    L75
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x0(%r13,%rbx,4),%eax
  mov    (%r14,%rbx,4),%edx
  mov    %edx,0x0(%r13,%rbx,4)
  mov    %eax,(%r14,%rbx,4)
  add    (%rsp),%rbx
  test   %ebx,%ebx
  js     L65
L75:
  mov    (%r14,%rbx,4),%eax
  mov    %ebx,%ecx
  lea    0x0(%rbp,%rbx,1),%r8d
  cmp    %eax,0x0(%r13,%rbx,4)
  jg     L11
L65:
  mov    0x8(%rsp),%rdi
  mov    %ebp,%r15d
  lea    0x1(%rdi),%rax
  cmp    %rdi,0x10(%rsp)
  je     L45
  mov    %rax,0x8(%rsp)
  mov    %rax,%rbx
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %r13,%r14
L60:
  sar    %r15d
  jne    L26
L55:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: gap: %d, i: %d, j: %d, j+gap: %d


assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        printf("gap: %d, i: %d, j: %d, j+gap: %d\n", gap, i, j, j + gap);
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L33
L28:
  movl   $0x1,-0xc(%rbp)
  jmp    L48
L8:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L8
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string

tool: D20: %d

tool: D10: %d 

tool: D18: %d


assistant: ```c
int main() {
  int total;
  int counter = 0;
  scanf("%d", &total);
  for (int col = 1; col <= total; col++) {
    for (int row = 1; row < col; row++) {
      counter += 1;
      printf("%d ", counter);
    }
    counter += 1;
    printf("%d\n", counter);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  lea    D4(%rip),%r15
  lea    D5(%rip),%r12
  cmpl   $0x0,0x14(%rsp)
  jg     L2
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    %ebx,0xc(%rsp)
  lea    0x1(%rbp,%rbx,1),%ebp
  mov    %r13d,%ebx
L57:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L57
  mov    0xc(%rsp),%ebp
  add    %r13d,%ebp
L52:
  mov    %r14d,%ebx
L2:
  lea    0x1(%rbp),%r13d
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  lea    0x1(%rbx),%r14d
  cmp    %r14d,0x14(%rsp)
  jl     L29
  cmp    $0x1,%r14d
  jg     L39
  mov    %r13d,%ebp
  jmp    L52
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D19: %d

tool: D4: %d


tool: D5: %d 

assistant: ```c
int main() {
  int total;
  int counter = 0;
  scanf("%d", &total);
  for (int col = 1; col <= total; col++) {
    for (int row = 1; row < col; row++) {
      counter += 1;
      printf("%d ", counter);
    }
    counter += 1;
    printf("%d\n", counter);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  lea    D22(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  nop
L3:
  lea    0x1(%rbp),%ebx
  mov    %r14,%rdi
  mov    %r13d,%ebp
  add    $0x1,%r13d
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jl     L30
  add    %ebx,%ebp
  nopl   (%rax)
L5:
  add    $0x1,%ebx
  mov    %r12,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L5
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D29
type: string
name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D16
type: string

tool: D29: %d

tool: D22: %d


tool: D16: %d 

assistant: ```c
int main() {
  int total;
  int counter = 0;
  scanf("%d", &total);
  for (int col = 1; col <= total; col++) {
    for (int row = 1; row < col; row++) {
      counter += 1;
      printf("%d ", counter);
    }
    counter += 1;
    printf("%d\n", counter);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D26(%rip),%rdi
  lea    D2(%rip),%r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L27
  nop
L2:
  lea    0x1(%rbp),%ebx
  mov    %r14,%rdi
  mov    %r13d,%ebp
  add    $0x1,%r13d
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %r13d,0x4(%rsp)
  jl     L27
  add    %ebx,%ebp
  nopl   (%rax)
L34:
  add    $0x1,%ebx
  mov    %r12,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L34
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string
name: parse_data
arguments: data_tag: D25
datatype: string

tool: D26: %d

tool: D2: %d


tool: D25: %d 

assistant: ```c
int main() {
  int total;
  int counter = 0;
  scanf("%d", &total);
  for (int col = 1; col <= total; col++) {
    for (int row = 1; row < col; row++) {
      counter += 1;
      printf("%d ", counter);
    }
    counter += 1;
    printf("%d\n", counter);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x4,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <get_sha256@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D2: test

tool: D15: SHA256 from test: %s

assistant: ```c
int main() {
  unsigned char *test = NULL;
  test = get_sha256("test", 4);
  printf("SHA256 from test: %s", (char *)test);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D19(%rip),%rdi
  call   <get_sha256@plt>
  mov    %rax,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D15
type: string

tool: D19: test

tool: D15: SHA256 from test: %s

assistant: ```c
int main() {
  unsigned char *test = NULL;
  test = get_sha256("test", 4);
  printf("SHA256 from test: %s", (char *)test);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D3(%rip),%rdi
  call   <get_sha256@plt>
  lea    D17(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D3: test

tool: D17: SHA256 from test: %s

assistant: ```c
int main() {
  unsigned char *test = NULL;
  test = get_sha256("test", 4);
  printf("SHA256 from test: %s", (char *)test);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <get_sha256@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D6: test

tool: D14: SHA256 from test: %s

assistant: ```c
int main() {
  unsigned char *test = NULL;
  test = get_sha256("test", 4);
  printf("SHA256 from test: %s", (char *)test);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invalidFunctionArgBool_isalpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  leave
  ret
```

assistant: ```c
bool invalidFunctionArgBool_isalpha(bool b, int c) {
  (void)isalpha(b);
  return isalpha(c != 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invalidFunctionArgBool_isalpha>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  setne  %dil
  movzbl %dil,%edi
  call   <isalpha@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool invalidFunctionArgBool_isalpha(bool b, int c) {
  (void)isalpha(b);
  return isalpha(c != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<invalidFunctionArgBool_isalpha>:
  endbr64
  xor    %edi,%edi
  test   %esi,%esi
  setne  %dil
  jmp    1050 <isalpha@plt>
```

assistant: ```c
bool invalidFunctionArgBool_isalpha(bool b, int c) {
  (void)isalpha(b);
  return isalpha(c != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invalidFunctionArgBool_isalpha>:
  endbr64
  xor    %edi,%edi
  test   %esi,%esi
  setne  %dil
  jmp    1050 <isalpha@plt>
```

assistant: ```c
bool invalidFunctionArgBool_isalpha(bool b, int c) {
  (void)isalpha(b);
  return isalpha(c != 0);
}
```