ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uniquePaths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0xf90,%rsp
  mov    %edi,-0x9f84(%rbp)
  mov    %esi,-0x9f88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9f70(%rbp),%rax
  mov    $0x9f64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0x9f6c(%rbp)
  movl   $0x1,-0x9f78(%rbp)
  jmp    L7
L12:
  movl   $0x1,-0x9f74(%rbp)
  jmp    L24
L47:
  mov    -0x9f78(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x9f74(%rbp),%eax
  movslq %eax,%rcx
  movslq %edx,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x9f70(%rbp,%rax,4),%ecx
  mov    -0x9f74(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rsi
  mov    -0x9f78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdi
  add    %rdi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    -0x9f70(%rbp,%rax,4),%eax
  add    %eax,%ecx
  mov    -0x9f74(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9f78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdi
  add    %rdi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  mov    %ecx,-0x9f70(%rbp,%rax,4)
  addl   $0x1,-0x9f74(%rbp)
L24:
  mov    -0x9f74(%rbp),%eax
  cmp    -0x9f88(%rbp),%eax
  jle    L47
  addl   $0x1,-0x9f78(%rbp)
L7:
  mov    -0x9f78(%rbp),%eax
  cmp    -0x9f84(%rbp),%eax
  jle    L12
  mov    -0x9f88(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9f84(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x9f70(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int uniquePaths(int m, int n) {
  int paths[(101)][(101)] = {0};
  int i, j;
  paths[0][1] = 1;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= n; j++) {
      paths[i][j] = paths[i - 1][j] + paths[i][j - 1];
    }
  }
  return paths[m][n];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uniquePaths>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0xf78,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x9f68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x9f64,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movl   $0x1,0x4(%rsp)
  test   %ebp,%ebp
  jle    L79
  lea    -0x1(%rbx),%esi
  lea    0x198(%rsp,%rsi,4),%rcx
  lea    -0x1(%rbp),%eax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rax
  add    %rsi,%rax
  lea    0x32c(%rsp,%rax,4),%rdi
  not    %rsi
  shl    $0x2,%rsi
  jmp    L78
L60:
  mov    (%rax),%edx
  add    -0x190(%rax),%edx
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L60
L14:
  add    $0x194,%rcx
  cmp    %rdi,%rcx
  je     L79
L78:
  lea    (%rsi,%rcx,1),%rax
  test   %ebx,%ebx
  jg     L60
  jmp    L14
L79:
  movslq %ebx,%rbx
  movslq %ebp,%rbp
  lea    0x0(%rbp,%rbp,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rax
  add    %rbx,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x9f68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x9f78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uniquePaths(int m, int n) {
  int paths[(101)][(101)] = {0};
  int i, j;
  paths[0][1] = 1;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= n; j++) {
      paths[i][j] = paths[i - 1][j] + paths[i][j - 1];
    }
  }
  return paths[m][n];
}
```
user: Translate the below assembly code into C programming language:

```asm
<uniquePaths>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L42:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L42
  sub    $0xf78,%rsp
  mov    $0x9f64,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x9f68(%rsp)
  xor    %eax,%eax
  movslq %edi,%rbp
  movslq %esi,%rbx
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  movl   $0x1,0x4(%rsp)
  test   %ebp,%ebp
  jle    L18
  lea    -0x1(%rbp),%r9d
  lea    -0x1(%rbx),%eax
  xor    %edi,%edi
  mov    $0xfffffffffffffe6c,%rsi
  imul   $0xfffffffffffffe6c,%r9,%r9
  lea    0x19c(%rsp,%rax,4),%r8
  lea    0x4(%rsp),%r10
  sub    $0x328,%r9
  nopl   (%rax)
L48:
  mov    %r10,%rax
  sub    %rsi,%rax
  test   %ebx,%ebx
  jle    L14
  nopw   0x0(%rax,%rax,1)
L33:
  lea    (%rax,%rsi,1),%rcx
  mov    -0x4(%rax),%edx
  add    $0x4,%rax
  add    (%rcx,%rdi,1),%edx
  mov    %edx,-0x4(%rax)
  cmp    %r8,%rax
  jne    L33
L14:
  sub    $0x194,%rsi
  add    $0x194,%rdi
  add    $0x194,%r8
  cmp    %r9,%rsi
  jne    L48
L18:
  lea    0x0(%rbp,%rbp,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rax
  add    %rbx,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x9f68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x9f78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uniquePaths(int m, int n) {
  int paths[(101)][(101)] = {0};
  int i, j;
  paths[0][1] = 1;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= n; j++) {
      paths[i][j] = paths[i - 1][j] + paths[i][j - 1];
    }
  }
  return paths[m][n];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uniquePaths>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0xf78,%rsp
  mov    $0x9f64,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x9f68(%rsp)
  xor    %eax,%eax
  movslq %edi,%rbx
  movslq %esi,%rbp
  mov    %rsp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  movl   $0x1,0x4(%rsp)
  test   %ebx,%ebx
  jle    L36
  test   %ebp,%ebp
  jle    L36
  lea    -0x1(%rbx),%r10d
  lea    -0x1(%rbp),%eax
  mov    $0x194,%esi
  xor    %edi,%edi
  imul   $0x194,%r10,%r10
  lea    0x4(%rsp),%r9
  lea    0x8(%rsp,%rax,4),%r8
  add    $0x328,%r10
  nopl   0x0(%rax)
L16:
  mov    0x190(%r9),%edx
  mov    %r9,%rax
  nopw   0x0(%rax,%rax,1)
L43:
  add    (%rax),%edx
  lea    (%rax,%rdi,1),%rcx
  add    $0x4,%rax
  mov    %edx,(%rcx,%rsi,1)
  cmp    %r8,%rax
  jne    L43
  add    $0x194,%rsi
  add    $0x194,%r9
  sub    $0x194,%rdi
  add    $0x194,%r8
  cmp    %r10,%rsi
  jne    L16
L36:
  lea    (%rbx,%rbx,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rbx,%rax,4),%rax
  add    %rbp,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x9f68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x9f78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int uniquePaths(int m, int n) {
  int paths[(101)][(101)] = {0};
  int i, j;
  paths[0][1] = 1;
  for (i = 1; i <= m; i++) {
    for (j = 1; j <= n; j++) {
      paths[i][j] = paths[i - 1][j] + paths[i][j - 1];
    }
  }
  return paths[m][n];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x150(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0xe0(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hideit@plt>
  lea    -0x150(%rbp),%rax
  mov    %rax,-0x158(%rbp)
  jmp    L2
L16:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x70(%rbp),%rcx
  mov    -0x158(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  addq   $0x1,-0x158(%rbp)
L2:
  lea    -0xe0(%rbp),%rdx
  mov    -0x158(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x158(%rbp)
  cmpq   $0x0,-0x158(%rbp)
  jne    L16
  lea    -0x150(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string

tool: D5: enter s1

tool: D19: enter s2

tool: D26: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char hide[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  hideit(hide, s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, hide, strlen(hide));
    ptr++;
  }
  printf("%s\n", s1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    0xe0(%rsp),%rdi
  mov    %rbp,%rsi
  call   <hideit@plt>
  mov    %rbx,%rdi
  jmp    L0
L18:
  lea    0xe0(%rsp),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  lea    0x1(%rbx),%rdi
L0:
  mov    %rbp,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L18
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D5: enter s1

tool: D2: enter s2

tool: D1: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char hide[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  hideit(hide, s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, hide, strlen(hide));
    ptr++;
  }
  printf("%s\n", s1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %rsp,%r13
  lea    0x70(%rsp),%r12
  lea    0xe0(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <hideit@plt>
  mov    %r13,%rdi
  jmp    L7
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <memmove@plt>
  lea    0x1(%rbx),%rdi
L7:
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L2
  mov    %r13,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x158,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string

tool: D12: enter s1

tool: D24: enter s2

tool: D22: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char hide[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  hideit(hide, s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, hide, strlen(hide));
    ptr++;
  }
  printf("%s\n", s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %rsp,%r13
  lea    0x70(%rsp),%r12
  lea    0xe0(%rsp),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <hideit@plt>
  mov    %r13,%rdi
  jmp    L2
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <memmove@plt>
  lea    0x1(%rbx),%rdi
L2:
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L7
  mov    %r13,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x158,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D12
datatype: string

tool: D16: enter s1

tool: D25: enter s2

tool: D12: %s


assistant: ```c
main() {
  char s1[100];
  char s2[100];
  char hide[100];
  char *ptr;
  puts("enter s1");
  gets(s1);
  puts("enter s2");
  gets(s2);
  hideit(hide, s2);
  ptr = s1;
  while (ptr = strstr(ptr, s2)) {
    memmove(ptr, hide, strlen(hide));
    ptr++;
  }
  printf("%s\n", s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L25
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <acceptnew@plt>
  jmp    L23
L25:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L43
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <swrite_sendfile@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  jne    L23
  mov    -0x20(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <shut@plt>
  jmp    L23
L43:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L23
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <sclose@plt>
L23:
  nop
  leave
  ret
```

assistant: ```c
void do_event(struct epoll_event *evp, int sockfd, int efd, int datafd, off_t datasz) {
  int connfd = -1;
  int done = 0;
  uint32_t events = evp->events;
  if (events & EPOLLIN) {
    acceptnew(sockfd, efd, evp);
  } else if (events & EPOLLOUT) {
    connfd = evp->data.fd;
    done = swrite_sendfile(connfd, datafd, datasz);
    if (done == 1) {
      shut(connfd, efd);
    }
  } else if (events & EPOLLHUP) {
    connfd = evp->data.fd;
    sclose(connfd);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_event>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %esi,%edi
  mov    %edx,%ebx
  mov    (%rax),%r9d
  mov    D15(%rip),%rdx
  mov    %r9d,%esi
  and    (%rdx),%esi
  jne    L3
  mov    D7(%rip),%rdx
  mov    %r9d,%edi
  and    (%rdx),%edi
  jne    L34
  mov    D8(%rip),%rdx
  and    (%rdx),%r9d
  je     L5
  mov    0x4(%rax),%edi
  call   <sclose@plt>
  jmp    L5
L3:
  mov    %rax,%rdx
  mov    %ebx,%esi
  call   <acceptnew@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L34:
  mov    0x4(%rax),%ebp
  mov    %r8d,%edx
  mov    %ecx,%esi
  mov    %ebp,%edi
  call   <swrite_sendfile@plt>
  cmp    $0x1,%eax
  jne    L5
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <shut@plt>
  jmp    L5
```

assistant: ```c
void do_event(struct epoll_event *evp, int sockfd, int efd, int datafd, off_t datasz) {
  int connfd = -1;
  int done = 0;
  uint32_t events = evp->events;
  if (events & EPOLLIN) {
    acceptnew(sockfd, efd, evp);
  } else if (events & EPOLLOUT) {
    connfd = evp->data.fd;
    done = swrite_sendfile(connfd, datafd, datasz);
    if (done == 1) {
      shut(connfd, efd);
    }
  } else if (events & EPOLLHUP) {
    connfd = evp->data.fd;
    sclose(connfd);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_event>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  mov    %esi,%edi
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  mov    (%r9),%eax
  mov    D14(%rip),%rdx
  mov    %eax,%esi
  and    (%rdx),%esi
  jne    L4
  mov    D3(%rip),%rdx
  mov    %eax,%edi
  and    (%rdx),%edi
  jne    L9
  mov    D19(%rip),%rdx
  and    (%rdx),%eax
  jne    L32
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x4(%r9),%r12d
  mov    %r8d,%edx
  mov    %ecx,%esi
  mov    %r12d,%edi
  call   <swrite_sendfile@plt>
  cmp    $0x1,%eax
  jne    L0
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <shut@plt>
  nop
L4:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r9,%rdx
  pop    %rbp
  pop    %r12
  jmp    1080 <acceptnew@plt>
  nopl   0x0(%rax)
L32:
  mov    0x4(%r9),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <sclose@plt>
```

assistant: ```c
void do_event(struct epoll_event *evp, int sockfd, int efd, int datafd, off_t datasz) {
  int connfd = -1;
  int done = 0;
  uint32_t events = evp->events;
  if (events & EPOLLIN) {
    acceptnew(sockfd, efd, evp);
  } else if (events & EPOLLOUT) {
    connfd = evp->data.fd;
    done = swrite_sendfile(connfd, datafd, datasz);
    if (done == 1) {
      shut(connfd, efd);
    }
  } else if (events & EPOLLHUP) {
    connfd = evp->data.fd;
    sclose(connfd);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_event>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  mov    %esi,%edi
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  mov    (%r9),%eax
  mov    D1(%rip),%rdx
  mov    %eax,%esi
  and    (%rdx),%esi
  jne    L36
  mov    D5(%rip),%rdx
  mov    %eax,%edi
  and    (%rdx),%edi
  jne    L29
  mov    D10(%rip),%rdx
  and    (%rdx),%eax
  jne    L9
L32:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x4(%r9),%r12d
  mov    %r8d,%edx
  mov    %ecx,%esi
  mov    %r12d,%edi
  call   <swrite_sendfile@plt>
  cmp    $0x1,%eax
  jne    L32
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <shut@plt>
  nop
L36:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r9,%rdx
  pop    %rbp
  pop    %r12
  jmp    1080 <acceptnew@plt>
  nopl   0x0(%rax)
L9:
  mov    0x4(%r9),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    10a0 <sclose@plt>
```

assistant: ```c
void do_event(struct epoll_event *evp, int sockfd, int efd, int datafd, off_t datasz) {
  int connfd = -1;
  int done = 0;
  uint32_t events = evp->events;
  if (events & EPOLLIN) {
    acceptnew(sockfd, efd, evp);
  } else if (events & EPOLLOUT) {
    connfd = evp->data.fd;
    done = swrite_sendfile(connfd, datafd, datasz);
    if (done == 1) {
      shut(connfd, efd);
    }
  } else if (events & EPOLLHUP) {
    connfd = evp->data.fd;
    sclose(connfd);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<data_rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x20(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L91
L18:
  mov    -0x24(%rbp),%eax
  cltq
  movl   $0xffffffff,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x24(%rbp)
L91:
  cmpl   $0x4,-0x24(%rbp)
  jle    L18
  movl   $0x1,-0x28(%rbp)
  jmp    L92
L49:
  movl   $0x0,-0x24(%rbp)
  jmp    L24
L54:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <data_vps@plt>
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x20(%rbp,%rdx,4),%edx
  cmp    %edx,%eax
  jle    L61
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <data_vps@plt>
  mov    -0x28(%rbp),%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  mov    -0x20(%rbp,%rdx,4),%edx
  cmp    %edx,%eax
  jge    L61
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <data_vps@plt>
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x20(%rbp,%rdx,4)
L61:
  addl   $0x1,-0x24(%rbp)
L24:
  cmpl   $0x3,-0x24(%rbp)
  jle    L54
  addl   $0x1,-0x28(%rbp)
L92:
  cmpl   $0x4,-0x28(%rbp)
  jle    L49
  movl   $0x1,-0x28(%rbp)
L76:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <data_vps@plt>
  mov    -0x28(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x20(%rbp,%rdx,4),%edx
  cmp    %edx,%eax
  jne    L19
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L108
  jmp    L17
L19:
  addl   $0x1,-0x28(%rbp)
  jmp    L76
L17:
  call   <__stack_chk_fail@plt>
L108:
  leave
  ret
```

assistant: ```c
int data_rank(int p) {
  int rank, i, maxes[5];
  maxes[0] = 100;
  for (i = 1; i < 5; i++)
    maxes[i] = -1;
  for (rank = 1; rank < 5; rank++) {
    for (i = 0; i < 4; i++) {
      if (data_vps(i) > maxes[rank] && data_vps(i) < maxes[rank - 1]) {
        maxes[rank] = data_vps(i);
      }
    }
  }
  for (rank = 1;; rank++)
    if (data_vps(p) == maxes[rank])
      return rank;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<data_rank>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  mov    %rsp,%rbp
  lea    0x10(%rsp),%r14
  jmp    L4
L62:
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  je     L44
L3:
  mov    %ebx,%edi
  call   <data_vps@plt>
  cmp    0x4(%rbp),%eax
  jle    L62
  mov    %ebx,%edi
  call   <data_vps@plt>
  cmp    0x0(%rbp),%eax
  jge    L62
  mov    %ebx,%edi
  call   <data_vps@plt>
  mov    %eax,0x4(%rbp)
  jmp    L62
L44:
  add    $0x4,%rbp
  cmp    %rbp,%r14
  je     L72
L4:
  mov    $0x0,%ebx
  jmp    L3
L72:
  mov    $0x1,%ebx
  mov    %rsp,%r12
L24:
  mov    %ebx,%ebp
  mov    %r13d,%edi
  call   <data_vps@plt>
  add    $0x1,%rbx
  cmp    -0x4(%r12,%rbx,4),%eax
  jne    L24
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %ebp,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int data_rank(int p) {
  int rank, i, maxes[5];
  maxes[0] = 100;
  for (i = 1; i < 5; i++)
    maxes[i] = -1;
  for (rank = 1; rank < 5; rank++) {
    for (i = 0; i < 4; i++) {
      if (data_vps(i) > maxes[rank] && data_vps(i) < maxes[rank - 1]) {
        maxes[rank] = data_vps(i);
      }
    }
  }
  for (rank = 1;; rank++)
    if (data_vps(p) == maxes[rank])
      return rank;
  return 0;
}
```