ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hex_dump>:
  endbr64
  test   %ecx,%ecx
  jle    L63
  push   %r15
  lea    -0x1(%rcx),%eax
  mov    $0x1,%r15d
  push   %r14
  lea    0x1(%rdx,%rax,1),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L1
  nopl   0x0(%rax)
L39:
  add    $0x1,%rbx
  add    $0x1,%r15d
  cmp    %r14,%rbx
  je     L40
L1:
  cmp    $0x1,%r15d
  je     L29
L15:
  movzbl (%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %r15d,%ebp
  jne    L39
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r14,%rbx
  je     L9
L29:
  mov    %r13,%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%r15d
  call   <printf@plt>
  jmp    L15
  nopl   0x0(%rax)
L40:
  cmp    $0x1,%r15d
  jne    L23
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L23:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L63:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D19: %2.2X 

tool: D7: %s

assistant: ```c
void hex_dump(char *pref, int width, unsigned char *buf, int len) {
  register int i, n;
  for (i = 0, n = 1; i < len; i++, n++) {
    if (n == 1)
      printf("%s", pref);
    printf("%2.2X ", buf[i]);
    if (n == width) {
      printf("\n");
      n = 0;
    }
  }
  if (i && n != 1)
    printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Cyc_Absyn_attribute_case_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x14,%eax
  ja     L6
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D6(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L41
  mov    $0x1,%eax
  jmp    L41
  mov    $0x2,%eax
  jmp    L41
  mov    $0x3,%eax
  jmp    L41
  mov    $0x4,%eax
  jmp    L41
  mov    $0x5,%eax
  jmp    L41
  mov    $0x6,%eax
  jmp    L41
  mov    $0x7,%eax
  jmp    L41
  mov    $0x8,%eax
  jmp    L41
  mov    $0x9,%eax
  jmp    L41
  mov    $0xa,%eax
  jmp    L41
  mov    $0xb,%eax
  jmp    L41
  mov    $0xc,%eax
  jmp    L41
  mov    $0xd,%eax
  jmp    L41
  mov    $0xe,%eax
  jmp    L41
  mov    $0xf,%eax
  jmp    L41
  mov    $0x10,%eax
  jmp    L41
  mov    $0x11,%eax
  jmp    L41
  mov    $0x12,%eax
  jmp    L41
  mov    $0x13,%eax
  jmp    L41
  mov    $0x14,%eax
  jmp    L41
L6:
  mov    $0x15,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int Cyc_Absyn_attribute_case_number(void *att) {
  void *_tmp25D = att;
  switch (*((int *)_tmp25D)) {
  case 0U:
  _LL1:
  _LL2:
    return 0;
  case 1U:
  _LL3:
  _LL4:
    return 1;
  case 2U:
  _LL5:
  _LL6:
    return 2;
  case 3U:
  _LL7:
  _LL8:
    return 3;
  case 4U:
  _LL9:
  _LLA:
    return 4;
  case 5U:
  _LLB:
  _LLC:
    return 5;
  case 6U:
  _LLD:
  _LLE:
    return 6;
  case 7U:
  _LLF:
  _LL10:
    return 7;
  case 8U:
  _LL11:
  _LL12:
    return 8;
  case 9U:
  _LL13:
  _LL14:
    return 9;
  case 10U:
  _LL15:
  _LL16:
    return 10;
  case 11U:
  _LL17:
  _LL18:
    return 11;
  case 12U:
  _LL19:
  _LL1A:
    return 12;
  case 13U:
  _LL1B:
  _LL1C:
    return 13;
  case 14U:
  _LL1D:
  _LL1E:
    return 14;
  case 15U:
  _LL1F:
  _LL20:
    return 15;
  case 16U:
  _LL21:
  _LL22:
    return 16;
  case 17U:
  _LL23:
  _LL24:
    return 17;
  case 18U:
  _LL25:
  _LL26:
    return 18;
  case 19U:
  _LL27:
  _LL28:
    return 19;
  case 20U:
  _LL29:
  _LL2A:
    return 20;
  default:
  _LL2B:
  _LL2C:
    return 21;
  }
_LL0:;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cyc_Absyn_attribute_case_number>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x15,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  ret
```

assistant: ```c
int Cyc_Absyn_attribute_case_number(void *att) {
  void *_tmp25D = att;
  switch (*((int *)_tmp25D)) {
  case 0U:
  _LL1:
  _LL2:
    return 0;
  case 1U:
  _LL3:
  _LL4:
    return 1;
  case 2U:
  _LL5:
  _LL6:
    return 2;
  case 3U:
  _LL7:
  _LL8:
    return 3;
  case 4U:
  _LL9:
  _LLA:
    return 4;
  case 5U:
  _LLB:
  _LLC:
    return 5;
  case 6U:
  _LLD:
  _LLE:
    return 6;
  case 7U:
  _LLF:
  _LL10:
    return 7;
  case 8U:
  _LL11:
  _LL12:
    return 8;
  case 9U:
  _LL13:
  _LL14:
    return 9;
  case 10U:
  _LL15:
  _LL16:
    return 10;
  case 11U:
  _LL17:
  _LL18:
    return 11;
  case 12U:
  _LL19:
  _LL1A:
    return 12;
  case 13U:
  _LL1B:
  _LL1C:
    return 13;
  case 14U:
  _LL1D:
  _LL1E:
    return 14;
  case 15U:
  _LL1F:
  _LL20:
    return 15;
  case 16U:
  _LL21:
  _LL22:
    return 16;
  case 17U:
  _LL23:
  _LL24:
    return 17;
  case 18U:
  _LL25:
  _LL26:
    return 18;
  case 19U:
  _LL27:
  _LL28:
    return 19;
  case 20U:
  _LL29:
  _LL2A:
    return 20;
  default:
  _LL2B:
  _LL2C:
    return 21;
  }
_LL0:;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Cyc_Absyn_attribute_case_number>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x15,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  ret
```

assistant: ```c
int Cyc_Absyn_attribute_case_number(void *att) {
  void *_tmp25D = att;
  switch (*((int *)_tmp25D)) {
  case 0U:
  _LL1:
  _LL2:
    return 0;
  case 1U:
  _LL3:
  _LL4:
    return 1;
  case 2U:
  _LL5:
  _LL6:
    return 2;
  case 3U:
  _LL7:
  _LL8:
    return 3;
  case 4U:
  _LL9:
  _LLA:
    return 4;
  case 5U:
  _LLB:
  _LLC:
    return 5;
  case 6U:
  _LLD:
  _LLE:
    return 6;
  case 7U:
  _LLF:
  _LL10:
    return 7;
  case 8U:
  _LL11:
  _LL12:
    return 8;
  case 9U:
  _LL13:
  _LL14:
    return 9;
  case 10U:
  _LL15:
  _LL16:
    return 10;
  case 11U:
  _LL17:
  _LL18:
    return 11;
  case 12U:
  _LL19:
  _LL1A:
    return 12;
  case 13U:
  _LL1B:
  _LL1C:
    return 13;
  case 14U:
  _LL1D:
  _LL1E:
    return 14;
  case 15U:
  _LL1F:
  _LL20:
    return 15;
  case 16U:
  _LL21:
  _LL22:
    return 16;
  case 17U:
  _LL23:
  _LL24:
    return 17;
  case 18U:
  _LL25:
  _LL26:
    return 18;
  case 19U:
  _LL27:
  _LL28:
    return 19;
  case 20U:
  _LL29:
  _LL2A:
    return 20;
  default:
  _LL2B:
  _LL2C:
    return 21;
  }
_LL0:;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Cyc_Absyn_attribute_case_number>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x15,%edx
  cmp    %edx,%eax
  cmova  %edx,%eax
  ret
```

assistant: ```c
int Cyc_Absyn_attribute_case_number(void *att) {
  void *_tmp25D = att;
  switch (*((int *)_tmp25D)) {
  case 0U:
  _LL1:
  _LL2:
    return 0;
  case 1U:
  _LL3:
  _LL4:
    return 1;
  case 2U:
  _LL5:
  _LL6:
    return 2;
  case 3U:
  _LL7:
  _LL8:
    return 3;
  case 4U:
  _LL9:
  _LLA:
    return 4;
  case 5U:
  _LLB:
  _LLC:
    return 5;
  case 6U:
  _LLD:
  _LLE:
    return 6;
  case 7U:
  _LLF:
  _LL10:
    return 7;
  case 8U:
  _LL11:
  _LL12:
    return 8;
  case 9U:
  _LL13:
  _LL14:
    return 9;
  case 10U:
  _LL15:
  _LL16:
    return 10;
  case 11U:
  _LL17:
  _LL18:
    return 11;
  case 12U:
  _LL19:
  _LL1A:
    return 12;
  case 13U:
  _LL1B:
  _LL1C:
    return 13;
  case 14U:
  _LL1D:
  _LL1E:
    return 14;
  case 15U:
  _LL1F:
  _LL20:
    return 15;
  case 16U:
  _LL21:
  _LL22:
    return 16;
  case 17U:
  _LL23:
  _LL24:
    return 17;
  case 18U:
  _LL25:
  _LL26:
    return 18;
  case 19U:
  _LL27:
  _LL28:
    return 19;
  case 20U:
  _LL29:
  _LL2A:
    return 20;
  default:
  _LL2B:
  _LL2C:
    return 21;
  }
_LL0:;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<resample_post_gamma>:
  endbr64
  push   %r15
  lea    0x1(%rcx),%eax
  push   %r14
  mov    %edi,%r14d
  lea    0x0(,%rax,8),%edi
  movslq %eax,%r15
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %r9,%rbx
  sub    $0x28,%rsp
  mov    %r8,0x18(%rsp)
  mov    0x60(%rsp),%r8
  mov    %ecx,0x14(%rsp)
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    0x14(%rsp),%ecx
  mov    0x8(%rsp),%r8
  mov    %rax,%rbp
  test   %ecx,%ecx
  jle    L20
  movslq %ecx,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  shl    $0x3,%rdx
  call   <memset@plt>
  mov    0x8(%rsp),%r8
L20:
  pxor   %xmm0,%xmm0
  pxor   %xmm3,%xmm3
  lea    -0x8(%rbp,%r15,8),%rcx
  cvtsi2sdl 0x14(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rcx)
  test   %r14d,%r14d
  jle    L8
  movslq %r14d,%rax
  movsd  D8(%rip),%xmm2
  xor    %r11d,%r11d
  mov    %rax,0x8(%rsp)
L65:
  movslq (%r12,%r11,4),%r14
  test   %r14d,%r14d
  jle    L6
  mov    0x0(%r13,%r11,8),%r15
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L52:
  movslq (%r15,%r10,4),%rsi
  test   %esi,%esi
  jle    L67
  mov    (%r8,%r11,8),%rax
  mov    (%rax,%r10,8),%r9
  mov    (%rbx,%r11,8),%rax
  mov    (%rax,%r10,8),%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L38:
  cmpl   $0x2,(%r9,%rax,4)
  movsd  (%rcx),%xmm1
  movapd %xmm2,%xmm0
  je     L33
  movapd %xmm3,%xmm0
L33:
  movslq (%rdi,%rax,4),%rdx
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  lea    -0x8(%rbp,%rdx,8),%rdx
  movsd  %xmm1,(%rcx)
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L38
L67:
  add    $0x1,%r10
  cmp    %r10,%r14
  jne    L52
L6:
  add    $0x1,%r11
  cmp    %r11,0x8(%rsp)
  jne    L65
L8:
  mov    0x18(%rsp),%rdi
  mov    0x14(%rsp),%edx
  mov    %rbp,%rsi
  call   <sample_Delta@plt>
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <free@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: f64

tool: D8: 1

assistant: ```c
void resample_post_gamma(int D, int **M, int *N, int V, double *post_gamma, int ***w, int ***s) {
  int k_8;
  double *tmpSP4;
  int d_2;
  int n_74;
  int m_290;
  int dvv_loop_var_1;
  tmpSP4 = (double *)malloc(sizeof(double) * (1 + ((V) + (1)) - (1)));
  for (k_8 = 2; k_8 <= 2; k_8++) {
    for (dvv_loop_var_1 = 1; dvv_loop_var_1 <= V; dvv_loop_var_1++) {
      tmpSP4[dvv_loop_var_1 - 1] = 0.0;
    }
    tmpSP4[(V) + (1) - 1] = (0.0) * (((1) + (V)) - (1));
    for (d_2 = 1; d_2 <= D; d_2++) {
      for (n_74 = 1; n_74 <= N[d_2 - 1]; n_74++) {
        for (m_290 = 1; m_290 <= M[d_2 - 1][n_74 - 1]; m_290++) {
          tmpSP4[(V) + (1) - 1] += (1.0) * ((((k_8) == (s[d_2 - 1][n_74 - 1][m_290 - 1])) ? 1 : 0));
          tmpSP4[w[d_2 - 1][n_74 - 1][m_290 - 1] - 1] += (1.0) * ((((k_8) == (s[d_2 - 1][n_74 - 1][m_290 - 1])) ? 1 : 0));
        }
      }
    }
    sample_Delta(post_gamma, tmpSP4, V);
  }
  free(tmpSP4);
}
```
user: What is the c source code of the assembly code below?

```asm
<setns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int setns(int fd, int nstype) {
  errno = ENOSYS;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setns>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setns(int fd, int nstype) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setns>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setns(int fd, int nstype) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setns>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setns(int fd, int nstype) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<serial_wait_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <serial_getc@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L5
  cmpb   $0xa,-0x1(%rbp)
  je     L5
  cmpb   $0xd,-0x1(%rbp)
  jne    L17
L5:
  nop
  leave
  ret
```

assistant: ```c
void serial_wait_line(int fd) {
  unsigned char c = 0;
  do {
    c = serial_getc(fd);
  } while (c != 0 && c != '\n' && c != '\r');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_wait_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x2401,%ebp
L8:
  mov    %ebx,%edi
  call   <serial_getc@plt>
  cmp    $0xd,%al
  ja     L8
  bt     %rax,%rbp
  jae    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void serial_wait_line(int fd) {
  unsigned char c = 0;
  do {
    c = serial_getc(fd);
  } while (c != 0 && c != '\n' && c != '\r');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<serial_wait_line>:
  endbr64
  push   %rbp
  mov    $0xffffffffffffdbfe,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%edi
  call   <serial_getc@plt>
  cmp    $0xd,%al
  ja     L7
  bt     %rax,%rbp
  jb     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void serial_wait_line(int fd) {
  unsigned char c = 0;
  do {
    c = serial_getc(fd);
  } while (c != 0 && c != '\n' && c != '\r');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<serial_wait_line>:
  endbr64
  push   %rbp
  mov    $0xffffffffffffdbfe,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  call   <serial_getc@plt>
  cmp    $0xd,%al
  ja     L9
  bt     %rax,%rbp
  jb     L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void serial_wait_line(int fd) {
  unsigned char c = 0;
  do {
    c = serial_getc(fd);
  } while (c != 0 && c != '\n' && c != '\r');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_image_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jg     L17
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int free_image_array(the_array, length)
short **the_array;
long length;
{
  int i;
  for (i = 0; i < length; i++)
    free(the_array[i]);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_image_array>:
  endbr64
  test   %rsi,%rsi
  jle    L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,8),%rbp
L19:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L19
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int free_image_array(the_array, length)
short **the_array;
long length;
{
  int i;
  for (i = 0; i < length; i++)
    free(the_array[i]);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_image_array>:
  endbr64
  test   %rsi,%rsi
  jle    L17
  push   %rbp
  lea    (%rdi,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int free_image_array(the_array, length)
short **the_array;
long length;
{
  int i;
  for (i = 0; i < length; i++)
    free(the_array[i]);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<free_image_array>:
  endbr64
  test   %rsi,%rsi
  jle    L17
  push   %rbp
  lea    (%rdi,%rsi,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L15
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int free_image_array(the_array, length)
short **the_array;
long length;
{
  int i;
  for (i = 0; i < length; i++)
    free(the_array[i]);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L11
L42:
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L41
  mov    -0x14(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L35
L41:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L35:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D19
type_infered: string

tool: D15: %d %d %d

tool: D19: %d


assistant: ```c
int main() {
  int n, i, j;
  int cont = 0;
  int aux = 0;
  scanf("%d %d %d", &n, &i, &j);
  while (cont < n) {
    if (aux % i == 0 || aux % j == 0) {
      printf("%d\n", aux);
      cont++;
    }
    aux++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L8
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D15(%rip),%r12
  jmp    L51
L27:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
L55:
  add    $0x1,%ebx
  cmp    %ebp,0xc(%rsp)
  jle    L8
L51:
  mov    %ebx,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L27
  mov    %ebx,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L55
  jmp    L27
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D5: %d %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n, i, j;
  int cont = 0;
  int aux = 0;
  scanf("%d %d %d", &n, &i, &j);
  while (cont < n) {
    if (aux % i == 0 || aux % j == 0) {
      printf("%d\n", aux);
      cont++;
    }
    aux++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    D18(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12d,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L45
  mov    %r12d,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L37
L45:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
L37:
  add    $0x1,%r12d
  cmp    %ebx,0xc(%rsp)
  jg     L1
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D18
data_type: string

tool: D1: %d %d %d

tool: D18: %d


assistant: ```c
int main() {
  int n, i, j;
  int cont = 0;
  int aux = 0;
  scanf("%d %d %d", &n, &i, &j);
  while (cont < n) {
    if (aux % i == 0 || aux % j == 0) {
      printf("%d\n", aux);
      cont++;
    }
    aux++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L35
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r12d,%eax
  cltd
  idivl  0x10(%rsp)
  test   %edx,%edx
  je     L3
  mov    %r12d,%eax
  cltd
  idivl  0x14(%rsp)
  test   %edx,%edx
  jne    L9
L3:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0xc(%rsp),%ecx
L9:
  add    $0x1,%r12d
  cmp    %ecx,%ebx
  jl     L20
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D14: %d %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n, i, j;
  int cont = 0;
  int aux = 0;
  scanf("%d %d %d", &n, &i, &j);
  while (cont < n) {
    if (aux % i == 0 || aux % j == 0) {
      printf("%d\n", aux);
      cont++;
    }
    aux++;
  }
  return 0;
}
```