ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  call   <fork@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jne    L30
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L28
L2:
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
L28:
  mov    -0x38(%rbp),%eax
  lea    -0x30(%rbp),%rcx
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L2
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L21
L30:
  mov    -0x38(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x34(%rbp),%eax
  mov    $0x20,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L21:
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: abc ola ola


assistant: ```c
int main(int argc, char **argv) {
  int pd[2];
  pipe(pd);
  int pid = fork();
  char buf[32];
  if (pid == 0) {
    close(pd[1]);
    while (read(pd[0], &buf, 32) > 0 && buf != 0) {
      write(1, &buf, 32);
    }
    close(pd[0]);
  } else {
    close(pd[0]);
    write(pd[1], "abc ola ola\n", 32);
    close(pd[1]);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L42
  mov    0xc(%rsp),%edi
  call   <close@plt>
  lea    0x10(%rsp),%rbx
  jmp    L46
L14:
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
L46:
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L14
  mov    0x8(%rsp),%edi
  call   <close@plt>
L35:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x1,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L42:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    $0x20,%edx
  lea    D5(%rip),%rsi
  mov    0xc(%rsp),%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  jmp    L35
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: abc ola ola


assistant: ```c
int main(int argc, char **argv) {
  int pd[2];
  pipe(pd);
  int pid = fork();
  char buf[32];
  if (pid == 0) {
    close(pd[1]);
    while (read(pd[0], &buf, 32) > 0 && buf != 0) {
      write(1, &buf, 32);
    }
    close(pd[0]);
  } else {
    close(pd[0]);
    write(pd[1], "abc ola ola\n", 32);
    close(pd[1]);
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L11
  mov    0xc(%rsp),%edi
  lea    0x10(%rsp),%rbx
  call   <close@plt>
  jmp    L39
  nopl   0x0(%rax)
L10:
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
L39:
  mov    0x8(%rsp),%edi
  mov    $0x20,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jg     L10
  mov    0x8(%rsp),%edi
  call   <close@plt>
L18:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
L11:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0xc(%rsp),%edi
  mov    $0x20,%edx
  xor    %eax,%eax
  lea    D5(%rip),%rsi
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  jmp    L18
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: abc ola ola


assistant: ```c
int main(int argc, char **argv) {
  int pd[2];
  pipe(pd);
  int pid = fork();
  char buf[32];
  if (pid == 0) {
    close(pd[1]);
    while (read(pd[0], &buf, 32) > 0 && buf != 0) {
      write(1, &buf, 32);
    }
    close(pd[0]);
  } else {
    close(pd[0]);
    write(pd[1], "abc ola ola\n", 32);
    close(pd[1]);
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L1
  mov    0xc(%rsp),%edi
  lea    0x10(%rsp),%rbx
  call   <close@plt>
  jmp    L20
  nopl   0x0(%rax)
L44:
  mov    $0x20,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
L20:
  mov    0x8(%rsp),%edi
  mov    $0x20,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  test   %rax,%rax
  jg     L44
  mov    0x8(%rsp),%edi
  call   <close@plt>
L40:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
L1:
  mov    0x8(%rsp),%edi
  call   <close@plt>
  mov    0xc(%rsp),%edi
  mov    $0x20,%edx
  xor    %eax,%eax
  lea    D4(%rip),%rsi
  call   <write@plt>
  mov    0xc(%rsp),%edi
  call   <close@plt>
  jmp    L40
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D4: abc ola ola


assistant: ```c
int main(int argc, char **argv) {
  int pd[2];
  pipe(pd);
  int pid = fork();
  char buf[32];
  if (pid == 0) {
    close(pd[1]);
    while (read(pd[0], &buf, 32) > 0 && buf != 0) {
      write(1, &buf, 32);
    }
    close(pd[0]);
  } else {
    close(pd[0]);
    write(pd[1], "abc ola ola\n", 32);
    close(pd[1]);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L27:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  js     L47
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L27
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L45
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L45:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_sort(int arr[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; ++i) {
    tmp = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tmp; --j) {
      arr[j + 1] = arr[j];
    }
    if (i != j)
      arr[j + 1] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L33
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r11d
  mov    $0x0,%r8d
  jmp    L41
L36:
  lea    0x1(%r10),%eax
  cmp    %eax,%edx
  je     L23
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
L23:
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r11,%r8
  je     L33
L41:
  mov    0x4(%r9),%esi
  mov    %r8d,%r10d
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L36
L77:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L36
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L77
  jmp    L36
L33:
  ret
```

assistant: ```c
void insertion_sort(int arr[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; ++i) {
    tmp = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tmp; --j) {
      arr[j + 1] = arr[j];
    }
    if (i != j)
      arr[j + 1] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertion_sort>:
  endbr64
  movslq %esi,%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L0
  nopw   0x0(%rax,%rax,1)
L44:
  mov    (%rdi,%r8,4),%ecx
  lea    -0x1(%r8),%rax
L1:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L16
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L1
  mov    %rdi,%rax
L54:
  mov    %ecx,(%rax)
L18:
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L44
L0:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    %r8d,%eax
  je     L18
  lea    0x1(%rax),%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  jmp    L54
```

assistant: ```c
void insertion_sort(int arr[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; ++i) {
    tmp = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tmp; --j) {
      arr[j + 1] = arr[j];
    }
    if (i != j)
      arr[j + 1] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<insertion_sort>:
  endbr64
  movslq %esi,%r9
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L15
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%rdi,%r8,4),%ecx
  lea    -0x1(%r8),%rax
L26:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L56
  mov    %edx,0x4(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L26
  mov    %rdi,%rax
L47:
  mov    %ecx,(%rax)
L13:
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L3
L15:
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  cmp    %r8d,%eax
  je     L13
  lea    0x1(%rax),%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  jmp    L47
```

assistant: ```c
void insertion_sort(int arr[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; ++i) {
    tmp = arr[i];
    for (j = i - 1; j >= 0 && arr[j] > tmp; --j) {
      arr[j + 1] = arr[j];
    }
    if (i != j)
      arr[j + 1] = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  lea    0x1(%rax),%rbx
  nop
L6:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L6
  sub    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strlen(s)
register char *s;
{
  register char *s0 = s + 1;
  while (*s++ != '\0')
    ;
  return (s - s0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
L0:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L0
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(s)
register char *s;
{
  register char *s0 = s + 1;
  while (*s++ != '\0')
    ;
  return (s - s0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L0
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(s)
register char *s;
{
  register char *s0 = s + 1;
  while (*s++ != '\0')
    ;
  return (s - s0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L1
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(s)
register char *s;
{
  register char *s0 = s + 1;
  while (*s++ != '\0')
    ;
  return (s - s0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mulby>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
L30:
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L3
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0xfffffff6,%eax,%eax
  add    %eax,-0x4(%rbp)
  subq   $0x1,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L30
L3:
  nop
  jmp    L9
L33:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   $0xfffffff6,%eax,%eax
  add    %eax,-0x4(%rbp)
  subq   $0x1,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
L9:
  cmpl   $0x0,-0x8(%rbp)
  jne    L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mulby(char *a, char *p, char *q, int b) {
  int n, c;
  n = 0;
  *p = 0;
  for (;;) {
    q--;
    if (q < a)
      break;
    c = *q - '0';
    c = (c << b) + n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
  while (n) {
    c = n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mulby>:
  endbr64
  mov    %rsi,%r9
  mov    %rdx,%r8
  movb   $0x0,(%rsi)
  lea    -0x1(%rdx),%rax
  cmp    %rax,%rdi
  ja     L12
  lea    -0x1(%rdi),%r10
  sub    %rdx,%r10
  mov    $0xffffffffffffffff,%rsi
  mov    $0x0,%eax
L29:
  movsbl (%r8,%rsi,1),%edx
  sub    $0x30,%edx
  shl    %cl,%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%eax
  imul   $0xfffffff6,%eax,%r11d
  lea    0x30(%r11,%rdx,1),%edx
  mov    %dl,(%r9,%rsi,1)
  sub    $0x1,%rsi
  cmp    %rsi,%r10
  jne    L29
  sub    %r8,%rdi
  add    %r9,%rdi
  test   %eax,%eax
  je     L25
L2:
  mov    %eax,%esi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  sub    $0x1,%rdi
  imul   $0xfffffff6,%edx,%ecx
  lea    0x30(%rcx,%rsi,1),%ecx
  mov    %cl,(%rdi)
  test   %edx,%edx
  jne    L2
  ret
L12:
  ret
L25:
  ret
```

assistant: ```c
void mulby(char *a, char *p, char *q, int b) {
  int n, c;
  n = 0;
  *p = 0;
  for (;;) {
    q--;
    if (q < a)
      break;
    c = *q - '0';
    c = (c << b) + n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
  while (n) {
    c = n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mulby>:
  endbr64
  lea    -0x1(%rdx),%rax
  movb   $0x0,(%rsi)
  mov    %rsi,%r9
  mov    %rdx,%r8
  cmp    %rax,%rdi
  ja     L19
  lea    -0x1(%rdi),%r10
  mov    $0xffffffffffffffff,%rsi
  xor    %eax,%eax
  sub    %rdx,%r10
  nopw   0x0(%rax,%rax,1)
L37:
  movsbl (%r8,%rsi,1),%edx
  sub    $0x30,%edx
  shl    %cl,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%r11d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r11d
  sar    $0x22,%rax
  sub    %r11d,%eax
  imul   $0xfffffff6,%eax,%r11d
  lea    0x30(%r11,%rdx,1),%edx
  mov    %dl,(%r9,%rsi,1)
  sub    $0x1,%rsi
  cmp    %rsi,%r10
  jne    L37
  sub    %r8,%rdi
  add    %r9,%rdi
  test   %eax,%eax
  je     L11
  nopl   0x0(%rax)
L5:
  cltq
  sub    $0x1,%rdi
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  imul   $0xfffffff6,%eax,%edx
  lea    0x30(%rdx,%rcx,1),%edx
  mov    %dl,(%rdi)
  test   %eax,%eax
  jne    L5
  ret
  nopl   0x0(%rax)
L19:
  ret
L11:
  ret
```

assistant: ```c
void mulby(char *a, char *p, char *q, int b) {
  int n, c;
  n = 0;
  *p = 0;
  for (;;) {
    q--;
    if (q < a)
      break;
    c = *q - '0';
    c = (c << b) + n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
  while (n) {
    c = n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<mulby>:
  endbr64
  lea    -0x1(%rdx),%rax
  movb   $0x0,(%rsi)
  mov    %rsi,%r9
  mov    %rdx,%r8
  cmp    %rax,%rdi
  ja     L21
  lea    -0x1(%rdi),%r10
  mov    $0xffffffffffffffff,%rsi
  xor    %eax,%eax
  sub    %rdx,%r10
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl (%r8,%rsi,1),%edx
  sub    $0x30,%edx
  shl    %cl,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%r11d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r11d
  sar    $0x22,%rax
  sub    %r11d,%eax
  imul   $0xfffffff6,%eax,%r11d
  lea    0x30(%r11,%rdx,1),%edx
  mov    %dl,(%r9,%rsi,1)
  sub    $0x1,%rsi
  cmp    %r10,%rsi
  jne    L1
  sub    %r8,%rdi
  add    %r9,%rdi
  test   %eax,%eax
  je     L17
  nopl   0x0(%rax)
L2:
  cltq
  sub    $0x1,%rdi
  mov    %rax,%rcx
  imul   $0x66666667,%rax,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  imul   $0xfffffff6,%eax,%edx
  lea    0x30(%rdx,%rcx,1),%edx
  mov    %dl,(%rdi)
  test   %eax,%eax
  jne    L2
  ret
  nopl   0x0(%rax)
L21:
  ret
L17:
  ret
```

assistant: ```c
void mulby(char *a, char *p, char *q, int b) {
  int n, c;
  n = 0;
  *p = 0;
  for (;;) {
    q--;
    if (q < a)
      break;
    c = *q - '0';
    c = (c << b) + n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
  while (n) {
    c = n;
    n = c / 10;
    c -= n * 10;
    p--;
    *p = c + '0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kbhit>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x0,D2(%rip)
  je     L24
L26:
  lea    0x4(%rsp),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  mov    %rbx,%rdx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%esi
  mov    D48(%rip),%rax
  mov    (%rax),%edi
  call   <setbuf@plt>
  movl   $0x1,D2(%rip)
  jmp    L26
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  static const int STDIN = 0;
  static bool initialized = false;
  if (!initialized) {
    struct termios term;
    tcgetattr(STDIN, &term);
    term.c_lflag &= ~ICANON;
    tcsetattr(STDIN, TCSANOW, &term);
    setbuf(stdin, NULL);
    initialized = true;
  }
  int bytesWaiting;
  ioctl(STDIN, FIONREAD, &bytesWaiting);
  return bytesWaiting;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kbhit>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D53(%rip),%eax
  lea    0x4(%rsp),%r12
  test   %eax,%eax
  je     L14
L13:
  mov    D52(%rip),%rax
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x10,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <tcgetattr@plt>
  mov    D40(%rip),%rax
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  mov    D54(%rip),%rax
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  mov    D35(%rip),%rax
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setbuf@plt>
  movl   $0x1,D53(%rip)
  jmp    L13
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  static const int STDIN = 0;
  static bool initialized = false;
  if (!initialized) {
    struct termios term;
    tcgetattr(STDIN, &term);
    term.c_lflag &= ~ICANON;
    tcsetattr(STDIN, TCSANOW, &term);
    setbuf(stdin, NULL);
    initialized = true;
  }
  int bytesWaiting;
  ioctl(STDIN, FIONREAD, &bytesWaiting);
  return bytesWaiting;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kbhit>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D44(%rip),%eax
  lea    0x4(%rsp),%r12
  test   %eax,%eax
  je     L2
L1:
  mov    D32(%rip),%rax
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <tcgetattr@plt>
  mov    D34(%rip),%rax
  mov    %r12,%rdx
  xor    %edi,%edi
  mov    (%rax),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <tcsetattr@plt>
  mov    D47(%rip),%rax
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setbuf@plt>
  movl   $0x1,D44(%rip)
  jmp    L1
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  static const int STDIN = 0;
  static bool initialized = false;
  if (!initialized) {
    struct termios term;
    tcgetattr(STDIN, &term);
    term.c_lflag &= ~ICANON;
    tcsetattr(STDIN, TCSANOW, &term);
    setbuf(stdin, NULL);
    initialized = true;
  }
  int bytesWaiting;
  ioctl(STDIN, FIONREAD, &bytesWaiting);
  return bytesWaiting;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<internal_random_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  leave
  ret
```

assistant: ```c
ssize_t internal_random_read(void *data, void *buffer, size_t nbytes) {
  int fd = (int)data;
  return read(fd, buffer, nbytes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<internal_random_read>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t internal_random_read(void *data, void *buffer, size_t nbytes) {
  int fd = (int)data;
  return read(fd, buffer, nbytes);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<internal_random_read>:
  endbr64
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t internal_random_read(void *data, void *buffer, size_t nbytes) {
  int fd = (int)data;
  return read(fd, buffer, nbytes);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<internal_random_read>:
  endbr64
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t internal_random_read(void *data, void *buffer, size_t nbytes) {
  int fd = (int)data;
  return read(fd, buffer, nbytes);
}
```