user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %edx,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L9:
  cmp    %rdx,%rsp
  je     L93
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L93:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L30
L45:
  mov    -0x40(%rbp),%rax
  mov    -0x5c(%rbp),%edx
  movslq %edx,%rdx
  movl   $0x1,(%rax,%rdx,4)
  addl   $0x1,-0x5c(%rbp)
L30:
  mov    -0x5c(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L45
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  jmp    L26
L52:
  mov    $0x0,%eax
  call   <rnd@plt>
  cltd
  idivl  -0x50(%rbp)
  mov    %edx,%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  mov    (%rax,%rdx,4),%eax
  test   %eax,%eax
  je     L52
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movl   $0x0,(%rax,%rdx,4)
  nop
  subl   $0x1,-0x58(%rbp)
L26:
  cmpl   $0x0,-0x58(%rbp)
  jg     L52
  movl   $0x0,-0x54(%rbp)
  jmp    L90
L13:
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x70(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x70(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  test   %eax,%eax
  jne    L111
  mov    -0x70(%rbp),%rax
  movb   $0x20,(%rax)
  addq   $0x1,-0x70(%rbp)
L111:
  addl   $0x1,-0x54(%rbp)
L90:
  mov    -0x54(%rbp),%eax
  cmp    -0x50(%rbp),%eax
  jl     L13
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x70(%rbp),%rax
  mov    %dl,(%rax)
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void split(const char *s, char *result, int n) {
  int l = strlen(s) - 1;
  int space_holders[l];
  for (int i = 0; i < l; i++) {
    space_holders[i] = (!0);
  }
  for (int spaces = n; spaces > 0; spaces--) {
    do {
      unsigned int r = rnd() % l;
      if (space_holders[r]) {
        space_holders[r] = 0;
        break;
      }
    } while ((!0));
  }
  for (int i = 0; i < l; i++) {
    *result = s[i];
    result++;
    if (!space_holders[i]) {
      *result = ' ';
      result++;
    }
  }
  *result = s[l];
}
```