user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<editDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,-0x50(%rbp)
  mov    %eax,%r15d
  call   <strlen@plt>
  movslq %eax,%rbx
  cmp    %ebx,%r15d
  jge    L90
  mov    %r13,%rax
  mov    %ebx,-0x50(%rbp)
  mov    %r12,%r13
  movslq %r15d,%rbx
  mov    %rax,%r12
L90:
  lea    0x1(%rbx),%esi
  mov    %rsp,%rcx
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rdx
  mov    %rdx,%rdi
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rax
  sub    %rdi,%rcx
  cmp    %rcx,%rsp
  je     L59
L58:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L58
L59:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L231
L244:
  mov    %rsp,%r15
  test   %ebx,%ebx
  js     L24
  cmp    $0x2,%ebx
  jle    L85
  mov    %esi,%ecx
  movdqa D0(%rip),%xmm0
  movdqa D16(%rip),%xmm2
  mov    %r15,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%r15,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L202:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L202
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  and    $0x3,%esi
  je     L24
L171:
  movslq %eax,%rcx
  lea    0x1(%rax),%esi
  lea    (%r15,%rcx,4),%rcx
  mov    %eax,(%rcx)
  cmp    %esi,%ebx
  jl     L24
  add    $0x2,%eax
  mov    %esi,0x4(%rcx)
  cmp    %eax,%ebx
  jl     L24
  mov    %eax,0x8(%rcx)
L24:
  mov    %rdx,%rax
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L240
L29:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L29
L240:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L44
L149:
  mov    -0x50(%rbp),%eax
  mov    %rsp,%r14
  test   %eax,%eax
  jle    L188
  xor    %eax,%eax
  test   %ebx,%ebx
  mov    %r13,-0x48(%rbp)
  cmovns %rbx,%rax
  movl   $0x1,-0x4c(%rbp)
  lea    0x4(,%rax,4),%rax
  mov    %rax,-0x58(%rbp)
  nopl   0x0(%rax,%rax,1)
L249:
  mov    -0x4c(%rbp),%eax
  mov    %eax,(%r14)
  test   %ebx,%ebx
  jle    L39
  mov    $0x1,%r13d
L23:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
L254:
  mov    -0x4(%r15,%r13,4),%edi
  cmp    -0x1(%r12,%r13,1),%al
  je     L118
  mov    -0x4(%r14,%r13,4),%edx
  mov    (%r15,%r13,4),%esi
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,(%r14,%r13,4)
  add    $0x1,%r13
  cmp    %r13d,%ebx
  jge    L23
L15:
  mov    -0x58(%rbp),%r13
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    %r13,%rdx
  call   <memcpy@plt>
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
L50:
  addl   $0x1,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  addq   $0x1,-0x48(%rbp)
  cmp    %eax,-0x50(%rbp)
  jge    L249
L188:
  mov    (%r15,%rbx,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L255
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L118:
  mov    %edi,(%r14,%r13,4)
  add    $0x1,%r13
  cmp    %r13d,%ebx
  jge    L254
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L39:
  jne    L50
  jmp    L15
  nopl   0x0(%rax)
L44:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L149
L231:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L244
L85:
  xor    %eax,%eax
  jmp    L171
L255:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: byte[16]
name: unpack_data
arguments: label: D16
type_infered: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D16": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int editDistance(char a[], char b[]) {
  int aLength = strlen(a), bLength = strlen(b);
  int i, j;
  if (aLength < bLength) {
    char *tempPointer = a;
    a = b;
    b = tempPointer;
    int temp = aLength;
    aLength = bLength;
    bLength = temp;
  }
  int prev[bLength + 1];
  for (j = 0; j <= bLength; ++j) {
    prev[j] = j;
  }
  int curr[bLength + 1];
  for (i = 1; i <= aLength; ++i) {
    curr[0] = i;
    for (j = 1; j <= bLength; ++j) {
      if (a[i - 1] == b[j - 1]) {
        curr[j] = prev[j - 1];
      } else {
        curr[j] = 1 + min(prev[j - 1], prev[j], curr[j - 1]);
      }
    }
    for (j = 0; j <= bLength; ++j) {
      prev[j] = curr[j];
      curr[j] = 0;
    }
  }
  return prev[bLength];
}
```