ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_compare>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <string_length@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <string_length@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%r12d
  jne    L8
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L47
  xor    %eax,%eax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L47
L49:
  cmp    %dl,0x0(%rbp,%rax,1)
  je     L39
  xor    %eax,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L47:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int string_compare(char *s1, char *s2) {
  int length_s1 = string_length(s1);
  int length_s2 = string_length(s2);
  if (length_s1 != length_s2) {
    return 0;
  }
  while (*s1 != '\0') {
    if (*s1 != *s2) {
      return 0;
    }
    s1++;
    s2++;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<InitCTX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  mov    $0x0,%eax
  call   <SSLv2_client_method@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_CTX_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
SSL_CTX *InitCTX(void) {
  SSL_METHOD *method;
  SSL_CTX *ctx;
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
  method = SSLv2_client_method();
  ctx = SSL_CTX_new(method);
  if (ctx == NULL) {
    ERR_print_errors_fp(stderr);
    abort();
  }
  return ctx;
}
```
user: What is the c source code of the assembly code below?

```asm
<InitCTX>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  mov    $0x0,%eax
  call   <SSLv2_client_method@plt>
  mov    %rax,%rdi
  call   <SSL_CTX_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L10:
  mov    %rbx,%rax
  pop    %rbx
  ret
L7:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L10
```

assistant: ```c
SSL_CTX *InitCTX(void) {
  SSL_METHOD *method;
  SSL_CTX *ctx;
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
  method = SSLv2_client_method();
  ctx = SSL_CTX_new(method);
  if (ctx == NULL) {
    ERR_print_errors_fp(stderr);
    abort();
  }
  return ctx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InitCTX>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  xor    %eax,%eax
  call   <SSL_load_error_strings@plt>
  xor    %eax,%eax
  call   <SSLv2_client_method@plt>
  mov    %rax,%rdi
  call   <SSL_CTX_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
SSL_CTX *InitCTX(void) {
  SSL_METHOD *method;
  SSL_CTX *ctx;
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
  method = SSLv2_client_method();
  ctx = SSL_CTX_new(method);
  if (ctx == NULL) {
    ERR_print_errors_fp(stderr);
    abort();
  }
  return ctx;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<InitCTX>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  xor    %eax,%eax
  call   <SSL_load_error_strings@plt>
  xor    %eax,%eax
  call   <SSLv2_client_method@plt>
  mov    %rax,%rdi
  call   <SSL_CTX_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  call   <abort@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
SSL_CTX *InitCTX(void) {
  SSL_METHOD *method;
  SSL_CTX *ctx;
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
  method = SSLv2_client_method();
  ctx = SSL_CTX_new(method);
  if (ctx == NULL) {
    ERR_print_errors_fp(stderr);
    abort();
  }
  return ctx;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_all_ch_in_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x28(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L10:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L16
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L16:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _all_ch_in_string(char *buf, char ch, int **location) {
  int i = 0;
  int l = strlen(buf);
  *location = (int *)malloc(sizeof(int) * l);
  int n = 0;
  for (i = 0; i < l; i++) {
    if (buf[i] == ch) {
      (*location)[n] = i;
      n++;
    }
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_all_ch_in_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r13
  mov    %esi,%r12d
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %ebx,%ebx
  jle    L17
  mov    %ebx,%eax
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L43
L35:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L38
L43:
  cmp    %r12b,0x0(%rbp,%rdx,1)
  jne    L35
  movslq %ecx,%rdi
  mov    0x0(%r13),%rsi
  mov    %edx,(%rsi,%rdi,4)
  add    $0x1,%ecx
  jmp    L35
L17:
  mov    $0x0,%ecx
L38:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _all_ch_in_string(char *buf, char ch, int **location) {
  int i = 0;
  int l = strlen(buf);
  *location = (int *)malloc(sizeof(int) * l);
  int n = 0;
  for (i = 0; i < l; i++) {
    if (buf[i] == ch) {
      (*location)[n] = i;
      n++;
    }
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_all_ch_in_string>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %r12d,%r12d
  jle    L28
  mov    %rax,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L14
  movslq %eax,%rsi
  add    $0x1,%eax
  mov    %edx,(%rcx,%rsi,4)
L14:
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _all_ch_in_string(char *buf, char ch, int **location) {
  int i = 0;
  int l = strlen(buf);
  *location = (int *)malloc(sizeof(int) * l);
  int n = 0;
  for (i = 0; i < l; i++) {
    if (buf[i] == ch) {
      (*location)[n] = i;
      n++;
    }
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_all_ch_in_string>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%r12
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %r12d,%r12d
  jle    L7
  mov    %rax,%rcx
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %bpl,(%rbx,%rdx,1)
  jne    L27
  movslq %eax,%rsi
  add    $0x1,%eax
  mov    %edx,(%rcx,%rsi,4)
L27:
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _all_ch_in_string(char *buf, char ch, int **location) {
  int i = 0;
  int l = strlen(buf);
  *location = (int *)malloc(sizeof(int) * l);
  int n = 0;
  for (i = 0; i < l; i++) {
    if (buf[i] == ch) {
      (*location)[n] = i;
      n++;
    }
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L82
  negl   -0x14(%rbp)
L82:
  cmpl   $0x0,-0x18(%rbp)
  jns    L147
  negl   -0x18(%rbp)
L147:
  cmpl   $0x0,-0x14(%rbp)
  jne    L152
  mov    -0x18(%rbp),%eax
  jmp    L56
L152:
  cmpl   $0x0,-0x18(%rbp)
  jne    L59
  mov    -0x14(%rbp),%eax
  jmp    L56
L59:
  movl   $0x0,-0x8(%rbp)
  jmp    L116
L161:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L116:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L97
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L161
  jmp    L97
L68:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L36
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  jmp    L97
L36:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
  jmp    L97
L42:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L3
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  jmp    L97
L3:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x18(%rbp)
L97:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L68
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   -0x4(%rbp),%eax
L56:
  leave
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0) {
    return b;
  }
  if (b == 0) {
    return a;
  }
  int d = 0;
  while (a % 2 == 0 && b % 2 == 0) {
    a = a / 2;
    b = b / 2;
    d = d + 1;
  }
  while (a != b) {
    if (a % 2 == 0)
      a = a / 2;
    else if (b % 2 == 0)
      b = b / 2;
    else if (a > b)
      a = (a - b) / 2;
    else
      b = (b - a) / 2;
  }
  int g = a;
  return g * (int)pow(2, d);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gcd>:
  endbr64
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  test   %edi,%edi
  je     L105
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %esi,%esi
  je     L92
  mov    %edx,%eax
  or     %ebx,%eax
  test   $0x1,%al
  jne    L0
  mov    $0x0,%esi
L106:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    %eax,%ebx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %edx,%ecx
  sar    %ecx
  mov    %ecx,%edx
  add    $0x1,%esi
  or     %ecx,%eax
  test   $0x1,%al
  je     L106
L14:
  cmp    %edx,%ebx
  jne    L134
  mov    %edx,%ebx
L52:
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %ebx,%edx
  imul   %eax,%edx
L43:
  mov    %edx,%eax
  pop    %rbx
  ret
L0:
  mov    $0x0,%esi
  jmp    L14
L62:
  test   $0x1,%dl
  jne    L54
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
L112:
  cmp    %ebx,%edx
  je     L52
L134:
  test   $0x1,%bl
  jne    L62
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    %eax,%ebx
  jmp    L112
L54:
  cmp    %edx,%ebx
  jle    L16
  sub    %edx,%ebx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  sar    %ebx
  jmp    L112
L16:
  sub    %ebx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %eax,%edx
  sar    %edx
  jmp    L112
L92:
  mov    %ebx,%edx
  jmp    L43
L105:
  mov    %edx,%eax
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0) {
    return b;
  }
  if (b == 0) {
    return a;
  }
  int d = 0;
  while (a % 2 == 0 && b % 2 == 0) {
    a = a / 2;
    b = b / 2;
    d = d + 1;
  }
  while (a != b) {
    if (a % 2 == 0)
      a = a / 2;
    else if (b % 2 == 0)
      b = b / 2;
    else if (a > b)
      a = (a - b) / 2;
    else
      b = (b - a) / 2;
  }
  int g = a;
  return g * (int)pow(2, d);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %edi,%edi
  je     L115
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %esi,%esi
  je     L110
  mov    %eax,%edx
  xor    %esi,%esi
  or     %ebx,%edx
  and    $0x1,%edx
  jne    L16
  nopw   0x0(%rax,%rax,1)
L37:
  sar    %ebx
  sar    %eax
  add    $0x1,%esi
  mov    %ebx,%edx
  or     %eax,%edx
  and    $0x1,%edx
  je     L37
L16:
  cmp    %ebx,%eax
  je     L99
L68:
  test   $0x1,%bl
  jne    L24
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %edx,%ebx
  sar    %ebx
  cmp    %ebx,%eax
  jne    L68
L99:
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L110:
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L24:
  test   $0x1,%al
  jne    L77
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  jmp    L16
  nop
L77:
  cmp    %eax,%ebx
  jle    L34
  sub    %eax,%ebx
  sar    %ebx
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L34:
  sub    %ebx,%eax
  sar    %eax
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L115:
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0) {
    return b;
  }
  if (b == 0) {
    return a;
  }
  int d = 0;
  while (a % 2 == 0 && b % 2 == 0) {
    a = a / 2;
    b = b / 2;
    d = d + 1;
  }
  while (a != b) {
    if (a % 2 == 0)
      a = a / 2;
    else if (b % 2 == 0)
      b = b / 2;
    else if (a > b)
      a = (a - b) / 2;
    else
      b = (b - a) / 2;
  }
  int g = a;
  return g * (int)pow(2, d);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  test   %edi,%edi
  je     L29
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  cmovs  %edi,%ebx
  test   %esi,%esi
  je     L16
  mov    %eax,%edx
  xor    %esi,%esi
  or     %ebx,%edx
  and    $0x1,%edx
  jne    L113
  nopw   0x0(%rax,%rax,1)
L12:
  sar    %ebx
  sar    %eax
  add    $0x1,%esi
  mov    %ebx,%edx
  or     %eax,%edx
  and    $0x1,%edx
  je     L12
L113:
  cmp    %ebx,%eax
  jne    L125
  jmp    L111
  cs nopw 0x0(%rax,%rax,1)
L55:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %edx,%ebx
  sar    %ebx
L28:
  cmp    %eax,%ebx
  je     L111
L125:
  test   $0x1,%bl
  je     L55
  test   $0x1,%al
  jne    L57
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%ebx
  jne    L125
L111:
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %ebx,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L57:
  cmp    %ebx,%eax
  jge    L7
  sub    %eax,%ebx
  sar    %ebx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L7:
  sub    %ebx,%eax
  sar    %eax
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L29:
  ret
```

assistant: ```c
int gcd(int a, int b) {
  if (a < 0) {
    a = -a;
  }
  if (b < 0) {
    b = -b;
  }
  if (a == 0) {
    return b;
  }
  if (b == 0) {
    return a;
  }
  int d = 0;
  while (a % 2 == 0 && b % 2 == 0) {
    a = a / 2;
    b = b / 2;
    d = d + 1;
  }
  while (a != b) {
    if (a % 2 == 0)
      a = a / 2;
    else if (b % 2 == 0)
      b = b / 2;
    else if (a > b)
      a = (a - b) / 2;
    else
      b = (b - a) / 2;
  }
  int g = a;
  return g * (int)pow(2, d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x2,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <do_or_timeout@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main() {
  struct timespec max_wait;
  memset(&max_wait, 0, sizeof(max_wait));
  max_wait.tv_sec = 2;
  do_or_timeout(&max_wait);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movl   $0x2,0x4(%rsp)
  mov    %rbx,%rdi
  call   <do_or_timeout@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct timespec max_wait;
  memset(&max_wait, 0, sizeof(max_wait));
  max_wait.tv_sec = 2;
  do_or_timeout(&max_wait);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  movl   $0x2,0x4(%rsp)
  call   <do_or_timeout@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct timespec max_wait;
  memset(&max_wait, 0, sizeof(max_wait));
  max_wait.tv_sec = 2;
  do_or_timeout(&max_wait);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  movl   $0x2,0x4(%rsp)
  call   <do_or_timeout@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct timespec max_wait;
  memset(&max_wait, 0, sizeof(max_wait));
  max_wait.tv_sec = 2;
  do_or_timeout(&max_wait);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movw   $0x0,-0x1a(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x1a(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_scan@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  je     L1
  jmp    L64
L43:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L64:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L43
  movzwl -0x1a(%rbp),%eax
  test   %ax,%ax
  je     L35
  mov    -0x14(%rbp),%eax
  neg    %eax
  jmp    L24
L35:
  mov    -0x14(%rbp),%eax
  jmp    L24
L1:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  const char *pstr[1];
  int i;
  int n;
  short is_neg;
  pstr[0] = str;
  i = 0;
  n = 0;
  is_neg = 0;
  if ((i = ft_scan(&is_neg, pstr)) != -1) {
    while (ft_isdigit(str[i])) {
      n = 10 * n + (str[i] - 48);
      i++;
    }
    if (is_neg)
      return (-n);
    else
      return (n);
  } else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x10(%rsp)
  movw   $0x0,0xe(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  call   <ft_scan@plt>
  mov    $0x0,%ebp
  cmp    $0xffffffff,%eax
  je     L47
  cltq
  add    %rax,%rbx
  jmp    L8
L41:
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
L8:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L41
  cmpw   $0x0,0xe(%rsp)
  je     L47
  neg    %ebp
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %ebp,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  const char *pstr[1];
  int i;
  int n;
  short is_neg;
  pstr[0] = str;
  i = 0;
  n = 0;
  is_neg = 0;
  if ((i = ft_scan(&is_neg, pstr)) != -1) {
    while (ft_isdigit(str[i])) {
      n = 10 * n + (str[i] - 48);
      i++;
    }
    if (is_neg)
      return (-n);
    else
      return (n);
  } else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_atoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    %rdi,0x10(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  mov    %ax,0xe(%rsp)
  call   <ft_scan@plt>
  cmp    $0xffffffff,%eax
  je     L36
  cltq
  add    %rax,%rbx
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L48:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L22
  cmpw   $0x0,0xe(%rsp)
  jne    L0
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L0:
  neg    %r12d
  jmp    L36
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  const char *pstr[1];
  int i;
  int n;
  short is_neg;
  pstr[0] = str;
  i = 0;
  n = 0;
  is_neg = 0;
  if ((i = ft_scan(&is_neg, pstr)) != -1) {
    while (ft_isdigit(str[i])) {
      n = 10 * n + (str[i] - 48);
      i++;
    }
    if (is_neg)
      return (-n);
    else
      return (n);
  } else
    return (0);
}
```