ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<writePadding>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x8,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rsi
  mov    $0x10,%edi
  call   <fputc@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <fputc@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <fputc@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  sub    $0x1,%ebx
  jne    L1
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <fputc@plt>
```

assistant: ```c
void writePadding(FILE *out_file) {
  int i;
  for (i = 58; i < 66; ++i) {
    fputc(0x10, out_file);
    fputc(0x02, out_file);
    fputc(0x00, out_file);
    fputc(0x00, out_file);
    fputc(0x01, out_file);
    fputc(0x00, out_file);
    fputc(0x00, out_file);
    fputc(0x00, out_file);
  }
  fputc(0x30, out_file);
}
```
user: Translate the below assembly code into C programming language:

```asm
<shellsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printintarray@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L65
L7:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L37
L41:
  mov    -0xc(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L5
L52:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printintarray@plt>
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  js     L58
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L52
L58:
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
L65:
  cmpl   $0x0,-0x10(%rbp)
  jg     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  printintarray(v, n);
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
        printintarray(v, n);
      }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shellsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r14d
  call   <printintarray@plt>
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  mov    %eax,0x18(%rsp)
  lea    -0x1(%r14),%eax
  mov    %eax,0x1c(%rsp)
  cmp    $0x1,%r14d
  jg     L28
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  lea    0x1(%r15),%rax
  cmp    0x8(%rsp),%r15
  je     L51
  mov    %rax,%r15
L61:
  test   %r15d,%r15d
  js     L75
  movslq 0x14(%rsp),%r13
  mov    %r15,%rbx
L24:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    (%r12,%rbx,4),%eax
  cmp    %eax,%edx
  jle    L75
  mov    %eax,0x0(%rbp,%rbx,4)
  mov    %edx,(%r12,%rbx,4)
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <printintarray@plt>
  add    %r13,%rbx
  test   %ebx,%ebx
  jns    L24
  jmp    L75
L51:
  mov    0x18(%rsp),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    $0x1,%ecx
  jle    L6
  mov    %eax,0x18(%rsp)
L28:
  cmp    0x18(%rsp),%r14d
  jle    L51
  mov    0x1c(%rsp),%eax
  mov    0x18(%rsp),%ecx
  sub    %ecx,%eax
  mov    %rax,0x8(%rsp)
  movslq %ecx,%rax
  lea    0x0(%rbp,%rax,4),%r12
  mov    $0x0,%r15d
  neg    %ecx
  mov    %ecx,0x14(%rsp)
  jmp    L61
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  printintarray(v, n);
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
        printintarray(v, n);
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shellsort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%r14d
  shr    $0x1f,%r14d
  add    %ebp,%r14d
  sub    $0x18,%rsp
  sar    %r14d
  call   <printintarray@plt>
  lea    -0x1(%rbp),%eax
  mov    %r14d,0x8(%rsp)
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%ebp
  jle    L0
  nopw   0x0(%rax,%rax,1)
L38:
  cmp    0x8(%rsp),%ebp
  jle    L43
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%eax
  xor    %r12d,%r12d
  sub    %edx,%eax
  mov    %rax,(%rsp)
  movslq %edx,%rax
  neg    %edx
  lea    (%r15,%rax,4),%r14
  movslq %edx,%rbx
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r12,%r13
  jmp    L52
  nopl   (%rax)
L69:
  mov    %eax,(%r15,%r13,4)
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    %ecx,(%r14,%r13,4)
  add    %rbx,%r13
  call   <printintarray@plt>
  test   %r13d,%r13d
  js     L28
L52:
  mov    (%r15,%r13,4),%ecx
  mov    (%r14,%r13,4),%eax
  cmp    %eax,%ecx
  jg     L69
L28:
  lea    0x1(%r12),%rax
  cmp    (%rsp),%r12
  je     L43
  mov    %rax,%r12
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L43:
  sarl   0x8(%rsp)
  jne    L38
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  printintarray(v, n);
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
        printintarray(v, n);
      }
}
```
user: What is the c source code of the assembly code below?

```asm
<shellsort>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%r14d
  shr    $0x1f,%r14d
  add    %ebp,%r14d
  sub    $0x18,%rsp
  sar    %r14d
  call   <printintarray@plt>
  lea    -0x1(%rbp),%eax
  mov    %r14d,0x8(%rsp)
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%ebp
  jle    L55
  nopw   0x0(%rax,%rax,1)
L32:
  cmp    0x8(%rsp),%ebp
  jle    L30
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%eax
  xor    %r12d,%r12d
  sub    %edx,%eax
  mov    %rax,(%rsp)
  movslq %edx,%rax
  neg    %edx
  lea    (%r15,%rax,4),%r14
  movslq %edx,%rbx
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %r12,%r13
  jmp    L28
  nopl   (%rax)
L18:
  mov    %eax,(%r15,%r13,4)
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    %ecx,(%r14,%r13,4)
  add    %rbx,%r13
  call   <printintarray@plt>
  test   %r13d,%r13d
  js     L5
L28:
  mov    (%r15,%r13,4),%ecx
  mov    (%r14,%r13,4),%eax
  cmp    %eax,%ecx
  jg     L18
L5:
  lea    0x1(%r12),%rax
  cmp    %r12,(%rsp)
  je     L30
  mov    %rax,%r12
  jmp    L73
  cs nopw 0x0(%rax,%rax,1)
L30:
  sarl   0x8(%rsp)
  jne    L32
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shellsort(int v[], int n) {
  int gap, i, j, temp;
  printintarray(v, n);
  for (gap = n / 2; gap > 0; gap /= 2)
    for (i = gap; i < n; i++)
      for (j = i - gap; j >= 0 && v[j] > v[j + gap]; j -= gap) {
        temp = v[j];
        v[j] = v[j + gap];
        v[j + gap] = temp;
        printintarray(v, n);
      }
}
```
user: What is the c source code of the assembly code below:

```asm
<removeSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L17
L13:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L17:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void removeSubstring(char *s, const char *toremove) {
  while ((s = strstr(s, toremove)))
    memmove(s, s + strlen(toremove), 1 + strlen(s + strlen(toremove)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<removeSubstring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  jmp    L18
L2:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%edx
  movslq %eax,%rsi
  add    %rbx,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
L18:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void removeSubstring(char *s, const char *toremove) {
  while ((s = strstr(s, toremove)))
    memmove(s, s + strlen(toremove), 1 + strlen(s + strlen(toremove)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeSubstring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L18
L9:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  movslq %eax,%rsi
  add    %rbp,%rsi
  call   <memmove@plt>
L18:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void removeSubstring(char *s, const char *toremove) {
  while ((s = strstr(s, toremove)))
    memmove(s, s + strlen(toremove), 1 + strlen(s + strlen(toremove)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<removeSubstring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L6
L11:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  add    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rdi
  movslq %eax,%rsi
  add    %rbp,%rsi
  call   <memmove@plt>
L6:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void removeSubstring(char *s, const char *toremove) {
  while ((s = strstr(s, toremove)))
    memmove(s, s + strlen(toremove), 1 + strlen(s + strlen(toremove)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hwaddr_aton>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movb   $0x0,-0x9(%rbp)
  jmp    L79
L40:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L76
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  jne    L13
L76:
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D45(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L20
L13:
  cmpq   $0x0,-0x18(%rbp)
  jne    L118
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L118
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D45(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L20
L118:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L103
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
L103:
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  mov    D45(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L20
L38:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L44
  addq   $0x1,-0x28(%rbp)
L44:
  cmpq   $0x0,-0x20(%rbp)
  je     L89
  lea    -0xb(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L89:
  addq   $0x1,-0x18(%rbp)
L79:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    -0x18(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

assistant: ```c
size_t hwaddr_aton(unsigned char *buffer, const char *addr) {
  char c[3];
  const char *p = addr;
  unsigned char *bp = buffer;
  size_t len = 0;
  c[2] = '\0';
  while (*p) {
    c[0] = *p++;
    c[1] = *p++;
    if (isxdigit((unsigned char)c[0]) == 0 || isxdigit((unsigned char)c[1]) == 0) {
      errno = EINVAL;
      return 0;
    }
    if (len == 0 && *p == '\0') {
      errno = EINVAL;
      return 0;
    }
    if (!(*p == '\0' || (*p == ':' && *(p + 1) != '\0'))) {
      errno = EINVAL;
      return 0;
    }
    if (*p)
      p++;
    if (bp)
      *bp++ = (unsigned char)strtol(c, NULL, 16);
    len++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hwaddr_aton>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L105
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  lea    0x5(%rsp),%r13
  jmp    L143
L101:
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%ebp
L103:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L62:
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  jmp    L103
L68:
  movzbl 0x2(%rbx),%eax
  test   %al,%al
  jne    L104
  add    $0x2,%rbx
L8:
  test   %r12,%r12
  je     L34
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <strtol@plt>
  mov    %al,(%r12)
  lea    0x1(%r12),%r12
L34:
  add    $0x1,%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L103
L143:
  mov    %dil,0x5(%rsp)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x6(%rsp)
  movzbl %dil,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L101
  movzbl 0x6(%rsp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L101
  test   %rbp,%rbp
  jne    L68
  movzbl 0x2(%rbx),%eax
  test   %al,%al
  je     L62
L104:
  cmp    $0x3a,%al
  jne    L90
  cmpb   $0x0,0x3(%rbx)
  je     L90
  add    $0x3,%rbx
  jmp    L8
L90:
  mov    D34(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%ebp
  jmp    L103
L105:
  mov    $0x0,%ebp
  jmp    L103
L116:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t hwaddr_aton(unsigned char *buffer, const char *addr) {
  char c[3];
  const char *p = addr;
  unsigned char *bp = buffer;
  size_t len = 0;
  c[2] = '\0';
  while (*p) {
    c[0] = *p++;
    c[1] = *p++;
    if (isxdigit((unsigned char)c[0]) == 0 || isxdigit((unsigned char)c[1]) == 0) {
      errno = EINVAL;
      return 0;
    }
    if (len == 0 && *p == '\0') {
      errno = EINVAL;
      return 0;
    }
    if (!(*p == '\0' || (*p == ':' && *(p + 1) != '\0'))) {
      errno = EINVAL;
      return 0;
    }
    if (*p)
      p++;
    if (bp)
      *bp++ = (unsigned char)strtol(c, NULL, 16);
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hwaddr_aton>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rsi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  test   %dil,%dil
  je     L33
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  lea    0x5(%rsp),%r13
  jmp    L70
  nop
L11:
  test   %al,%al
  je     L4
L24:
  cmp    $0x3a,%al
  jne    L4
  cmpb   $0x0,0x3(%rbx)
  je     L4
  add    $0x3,%rbx
L74:
  test   %rbp,%rbp
  je     L84
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  add    $0x1,%rbp
  call   <strtol@plt>
  mov    %al,-0x1(%rbp)
L84:
  movzbl (%rbx),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L90
L70:
  movzbl 0x1(%rbx),%eax
  mov    %dil,0x5(%rsp)
  mov    %al,0x6(%rsp)
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L4
  movzbl 0x6(%rsp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L4
  movzbl 0x2(%rbx),%eax
  test   %r12,%r12
  je     L11
  test   %al,%al
  jne    L24
  add    $0x2,%rbx
  jmp    L74
  nopw   0x0(%rax,%rax,1)
L4:
  mov    D3(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
L90:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  xor    %r12d,%r12d
  jmp    L90
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t hwaddr_aton(unsigned char *buffer, const char *addr) {
  char c[3];
  const char *p = addr;
  unsigned char *bp = buffer;
  size_t len = 0;
  c[2] = '\0';
  while (*p) {
    c[0] = *p++;
    c[1] = *p++;
    if (isxdigit((unsigned char)c[0]) == 0 || isxdigit((unsigned char)c[1]) == 0) {
      errno = EINVAL;
      return 0;
    }
    if (len == 0 && *p == '\0') {
      errno = EINVAL;
      return 0;
    }
    if (!(*p == '\0' || (*p == ':' && *(p + 1) != '\0'))) {
      errno = EINVAL;
      return 0;
    }
    if (*p)
      p++;
    if (bp)
      *bp++ = (unsigned char)strtol(c, NULL, 16);
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hwaddr_aton>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rsi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x6(%rsp)
  test   %dil,%dil
  je     L16
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r13
  nopl   (%rax)
L18:
  xor    %eax,%eax
  mov    %dil,%al
  mov    0x1(%rbx),%ah
  mov    %ax,0x4(%rsp)
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L151
  movzbl 0x5(%rsp),%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L151
  movzbl 0x2(%rbx),%eax
  test   %r12,%r12
  jne    L84
  test   %al,%al
  je     L151
L71:
  cmp    $0x3a,%al
  jne    L151
  movzbl 0x3(%rbx),%edi
  test   %dil,%dil
  je     L151
  add    $0x3,%rbx
  test   %rbp,%rbp
  jne    L137
  add    $0x1,%r12
  jmp    L18
  nop
L84:
  test   %al,%al
  jne    L71
  add    $0x2,%rbx
  test   %rbp,%rbp
  je     L12
L137:
  mov    $0x10,%edx
  mov    %r13,%rdi
  xor    %esi,%esi
  add    $0x1,%r12
  call   <strtol@plt>
  lea    0x1(%rbp),%rdx
  mov    %al,0x0(%rbp)
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L146
  mov    %rdx,%rbp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L151:
  mov    D11(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
L146:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  add    $0x1,%r12
  jmp    L146
L16:
  xor    %r12d,%r12d
  jmp    L146
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t hwaddr_aton(unsigned char *buffer, const char *addr) {
  char c[3];
  const char *p = addr;
  unsigned char *bp = buffer;
  size_t len = 0;
  c[2] = '\0';
  while (*p) {
    c[0] = *p++;
    c[1] = *p++;
    if (isxdigit((unsigned char)c[0]) == 0 || isxdigit((unsigned char)c[1]) == 0) {
      errno = EINVAL;
      return 0;
    }
    if (len == 0 && *p == '\0') {
      errno = EINVAL;
      return 0;
    }
    if (!(*p == '\0' || (*p == ':' && *(p + 1) != '\0'))) {
      errno = EINVAL;
      return 0;
    }
    if (*p)
      p++;
    if (bp)
      *bp++ = (unsigned char)strtol(c, NULL, 16);
    len++;
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1a0,%rsp
  mov    %edi,-0x194(%rbp)
  mov    %rsi,-0x1a0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x180(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    $0x2d,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rdx
  mov    %rdi,%rax
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  lea    -0x180(%rbp),%rax
  mov    $0x12a,%edx
  mov    $0x5b,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,-0x184(%rbp)
  mov    -0x184(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D17: 

tool: D2: idx = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[] = {279, 284, 285, 287, 288, 296, 2, 8, 10, 11, 12, 13, 14, 19, 20, 22, 25, 26, 27, 28, 29, 33, 37, 39, 42, 43, 47, 48, 49, 50, 57, 62, 63, 66, 68, 69, 71, 73, 74, 77, 78, 79, 85, 89, 92, 94, 99, 111, 113, 117, 120, 122, 125, 134, 145, 152, 155, 157, 160, 161, 167, 168, 181, 182, 188, 189, 190, 194, 199, 201, 204, 208, 213, 220, 223, 225, 226, 227, 231, 237, 240, 242, 247, 254, 259, 260, 261, 264, 267, 271, 275};
  int idx = search(nums, sizeof(nums) / 4, 298);
  printf("idx = %d\n", idx);
  return 0;
}
```