ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L37
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    D10(%rip),%r13
L53:
  lea    0x10(%rsp),%rbx
  lea    (%rbx,%rbp,4),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rbx,%rbp,4),%edi
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  call   <nr_cifre@plt>
  add    %eax,%r12d
  mov    0x4(%rsp),%eax
  add    $0x1,%rbp
  cmp    %ebp,%eax
  jg     L53
  test   %eax,%eax
  jle    L55
  mov    $0x0,%ebp
  lea    D52(%rip),%r13
L18:
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    (%rbx),%edi
  call   <nr_cifre@plt>
  mov    %eax,%edx
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    0x4(%rsp),%ebp
  jl     L18
L55:
  mov    %r12d,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  mov    $0x0,%r12d
  jmp    L55
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D44
type_infered: string
name: retrieve_data
arguments: tag: D37
type_infered: string
name: retrieve_data
arguments: tag: D32
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string
name: retrieve_data
arguments: tag: D52
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string

tool: D44: Interval de cautare: 

tool: D37: %d %d

tool: D32: Nr de componente in sir: 

tool: D10: %d

tool: D52: 
Numarul %d are %d cifre in interval.


tool: D40: 
Numarul de cifre in interval este: %d 


assistant: ```c
int main() {
  int n, a, b, s = 0, v[100], i;
  printf("Interval de cautare: ");
  scanf("%d %d", &a, &b);
  printf("Nr de componente in sir: ");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v[i]);
    s += nr_cifre(v[i], a, b);
  }
  for (i = 0; i < n; i++) {
    printf("\nNumarul %d are %d cifre in interval.\n", i + 1, nr_cifre(v[i], a, b));
  }
  printf("\nNumarul de cifre in interval este: %d \n", s);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D42(%rip),%rdi
  lea    D23(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L53:
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x0(%r13,%rbx,4),%edi
  mov    0xc(%rsp),%edx
  add    $0x1,%rbx
  mov    0x8(%rsp),%esi
  call   <nr_cifre@plt>
  add    %eax,%r12d
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L53
  test   %eax,%eax
  jle    L3
  xor    %ebx,%ebx
  lea    D40(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L47:
  mov    0x0(%rbp),%edi
  mov    0xc(%rsp),%edx
  add    $0x1,%ebx
  add    $0x4,%rbp
  mov    0x8(%rsp),%esi
  call   <nr_cifre@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L47
L3:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  xor    %r12d,%r12d
  jmp    L3
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D42
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D50
type_guessed: string
name: unpack_data
arguments: data_tag: D37
type_guessed: string
name: unpack_data
arguments: data_tag: D40
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string

tool: D42: Interval de cautare: 

tool: D23: %d

tool: D50: %d %d

tool: D37: Nr de componente in sir: 

tool: D40: 
Numarul %d are %d cifre in interval.


tool: D19: 
Numarul de cifre in interval este: %d 


assistant: ```c
int main() {
  int n, a, b, s = 0, v[100], i;
  printf("Interval de cautare: ");
  scanf("%d %d", &a, &b);
  printf("Nr de componente in sir: ");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v[i]);
    s += nr_cifre(v[i], a, b);
  }
  for (i = 0; i < n; i++) {
    printf("\nNumarul %d are %d cifre in interval.\n", i + 1, nr_cifre(v[i], a, b));
  }
  printf("\nNumarul de cifre in interval este: %d \n", s);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%rdi
  lea    D45(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L59
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L12:
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r13,%rbp
  call   <scanf@plt>
  mov    0x0(%r13,%rbx,4),%edi
  mov    0xc(%rsp),%edx
  add    $0x1,%rbx
  mov    0x8(%rsp),%esi
  call   <nr_cifre@plt>
  add    %eax,%r12d
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L12
  test   %eax,%eax
  jle    L43
  xor    %ebx,%ebx
  lea    D17(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L48:
  mov    0x0(%rbp),%edi
  mov    0xc(%rsp),%edx
  add    $0x1,%ebx
  add    $0x4,%rbp
  mov    0x8(%rsp),%esi
  call   <nr_cifre@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0x4(%rsp),%ebx
  jl     L48
L43:
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  xor    %r12d,%r12d
  jmp    L43
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D45
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string
name: parse_data
arguments: data_tag: D34
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string

tool: D19: Interval de cautare: 

tool: D45: %d

tool: D11: %d %d

tool: D34: Nr de componente in sir: 

tool: D17: 
Numarul %d are %d cifre in interval.


tool: D4: 
Numarul de cifre in interval este: %d 


assistant: ```c
int main() {
  int n, a, b, s = 0, v[100], i;
  printf("Interval de cautare: ");
  scanf("%d %d", &a, &b);
  printf("Nr de componente in sir: ");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &v[i]);
    s += nr_cifre(v[i], a, b);
  }
  for (i = 0; i < n; i++) {
    printf("\nNumarul %d are %d cifre in interval.\n", i + 1, nr_cifre(v[i], a, b));
  }
  printf("\nNumarul de cifre in interval este: %d \n", s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_text_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
L17:
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L46
  mov    -0x14(%rbp),%eax
  jmp    L55
L46:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L37
  addq   $0x1,-0x8(%rbp)
  jmp    L31
L37:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L31:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    -0x30(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  je     L17
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
L55:
  leave
  ret
```

assistant: ```c
int _text_read(fd, buf, nbytes)
int fd;
char *buf;
int nbytes;
{
  char *to, *from;
  int r;
  do {
    r = read(fd, buf, nbytes);
    if (r <= 0)
      return r;
    to = from = buf;
    do {
      if (*from == '\r')
        from++;
      else
        *to++ = *from++;
    } while (--r);
  } while (buf == to);
  return (to - buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_text_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %edx,%ebp
  lea    0x2(%rsi),%r13
  jmp    L40
L6:
  mov    %cl,(%rax)
  lea    0x1(%rax),%rax
L68:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L23
L67:
  movzbl -0x1(%rdx),%ecx
  cmp    $0xd,%cl
  jne    L6
  jmp    L68
L23:
  cmp    %rbx,%rax
  jne    L63
L40:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  mov    $0x0,%eax
  call   <read@plt>
  test   %eax,%eax
  jle    L44
  lea    0x1(%rbx),%rdx
  lea    -0x1(%rax),%esi
  add    %r13,%rsi
  mov    %rbx,%rax
  jmp    L67
L63:
  sub    %ebx,%eax
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _text_read(fd, buf, nbytes)
int fd;
char *buf;
int nbytes;
{
  char *to, *from;
  int r;
  do {
    r = read(fd, buf, nbytes);
    if (r <= 0)
      return r;
    to = from = buf;
    do {
      if (*from == '\r')
        from++;
      else
        *to++ = *from++;
    } while (--r);
  } while (buf == to);
  return (to - buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_text_read>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  nop
L23:
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L31
  cltq
  mov    %r12,%rdx
  mov    %r12,%rdi
  add    %r12,%rax
  nopl   (%rax)
L20:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  cmp    $0xd,%cl
  je     L21
  mov    %cl,(%rdi)
  add    $0x1,%rdi
L21:
  cmp    %rax,%rdx
  jne    L20
  cmp    %r12,%rdi
  je     L23
  mov    %edi,%eax
  sub    %r12d,%eax
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _text_read(fd, buf, nbytes)
int fd;
char *buf;
int nbytes;
{
  char *to, *from;
  int r;
  do {
    r = read(fd, buf, nbytes);
    if (r <= 0)
      return r;
    to = from = buf;
    do {
      if (*from == '\r')
        from++;
      else
        *to++ = *from++;
    } while (--r);
  } while (buf == to);
  return (to - buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_text_read>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  nop
L35:
  xor    %eax,%eax
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L33
  cltq
  mov    %r12,%rdx
  mov    %r12,%rdi
  add    %r12,%rax
  nopl   (%rax)
L22:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  cmp    $0xd,%cl
  je     L10
  mov    %cl,(%rdi)
  add    $0x1,%rdi
L10:
  cmp    %rdx,%rax
  jne    L22
  cmp    %r12,%rdi
  je     L35
  mov    %edi,%eax
  sub    %r12d,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _text_read(fd, buf, nbytes)
int fd;
char *buf;
int nbytes;
{
  char *to, *from;
  int r;
  do {
    r = read(fd, buf, nbytes);
    if (r <= 0)
      return r;
    to = from = buf;
    do {
      if (*from == '\r')
        from++;
      else
        *to++ = *from++;
    } while (--r);
  } while (buf == to);
  return (to - buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <funTemF2C@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  funTemF2C();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <funTemF2C@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  funTemF2C();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <funTemF2C@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  funTemF2C();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <funTemF2C@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  funTemF2C();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<drawSix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0xa(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x5,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x5,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  mov    -0x8(%rbp),%eax
  lea    0xa(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x3,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  mov    -0x8(%rbp),%eax
  lea    0xa(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  mov    -0x8(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4f,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  nop
  leave
  ret
```

assistant: ```c
void drawSix(int y, int x) {
  mvaddch(y + 5, x + 10, 'O');
  mvaddch(y + 5, x + 2, 'O');
  mvaddch(y + 3, x + 10, 'O');
  mvaddch(y + 3, x + 2, 'O');
  mvaddch(y + 1, x + 10, 'O');
  mvaddch(y + 1, x + 2, 'O');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<drawSix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    0xa(%rsi),%r12d
  lea    0x5(%rdi),%r13d
  mov    $0x4f,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <mvaddch@plt>
  add    $0x2,%ebp
  mov    $0x4f,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <mvaddch@plt>
  lea    0x3(%rbx),%r13d
  mov    $0x4f,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <mvaddch@plt>
  mov    $0x4f,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <mvaddch@plt>
  add    $0x1,%ebx
  mov    $0x4f,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mvaddch@plt>
  mov    $0x4f,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mvaddch@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void drawSix(int y, int x) {
  mvaddch(y + 5, x + 10, 'O');
  mvaddch(y + 5, x + 2, 'O');
  mvaddch(y + 3, x + 10, 'O');
  mvaddch(y + 3, x + 2, 'O');
  mvaddch(y + 1, x + 10, 'O');
  mvaddch(y + 1, x + 2, 'O');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<drawSix>:
  endbr64
  push   %r13
  lea    0xa(%rsi),%r13d
  mov    $0x4f,%edx
  push   %r12
  lea    0x5(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %r13d,%esi
  push   %rbx
  add    $0x2,%ebp
  mov    %edi,%ebx
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <mvaddch@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x4f,%edx
  call   <mvaddch@plt>
  lea    0x3(%rbx),%r12d
  mov    %r13d,%esi
  mov    $0x4f,%edx
  mov    %r12d,%edi
  call   <mvaddch@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x4f,%edx
  call   <mvaddch@plt>
  lea    0x1(%rbx),%r12d
  mov    %r13d,%esi
  mov    $0x4f,%edx
  mov    %r12d,%edi
  call   <mvaddch@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbx
  mov    $0x4f,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <mvaddch@plt>
```

assistant: ```c
void drawSix(int y, int x) {
  mvaddch(y + 5, x + 10, 'O');
  mvaddch(y + 5, x + 2, 'O');
  mvaddch(y + 3, x + 10, 'O');
  mvaddch(y + 3, x + 2, 'O');
  mvaddch(y + 1, x + 10, 'O');
  mvaddch(y + 1, x + 2, 'O');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drawSix>:
  endbr64
  push   %r13
  lea    0xa(%rsi),%r13d
  mov    $0x4f,%edx
  push   %r12
  lea    0x5(%rdi),%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %r13d,%esi
  push   %rbx
  add    $0x2,%ebp
  mov    %edi,%ebx
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <mvaddch@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x4f,%edx
  call   <mvaddch@plt>
  lea    0x3(%rbx),%r12d
  mov    %r13d,%esi
  mov    $0x4f,%edx
  mov    %r12d,%edi
  call   <mvaddch@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    $0x4f,%edx
  call   <mvaddch@plt>
  lea    0x1(%rbx),%r12d
  mov    %r13d,%esi
  mov    $0x4f,%edx
  mov    %r12d,%edi
  call   <mvaddch@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbx
  mov    $0x4f,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <mvaddch@plt>
```

assistant: ```c
void drawSix(int y, int x) {
  mvaddch(y + 5, x + 10, 'O');
  mvaddch(y + 5, x + 2, 'O');
  mvaddch(y + 3, x + 10, 'O');
  mvaddch(y + 3, x + 2, 'O');
  mvaddch(y + 1, x + 10, 'O');
  mvaddch(y + 1, x + 2, 'O');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DE_MONTH_NAME>:
  endbr64
  add    $0x1,%edi
  mov    %rsi,%r8
  cmp    $0xc,%edi
  ja     L6
  lea    D121(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  lea    D100(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D76(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D40(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D124(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D2(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D32(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D108(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D73(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D45(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D77(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D131(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nop
  lea    D30(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
L6:
  lea    D31(%rip),%rsi
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D100
type_guessed: string
name: extract_symbolic_data
arguments: label: D76
type_guessed: string
name: extract_symbolic_data
arguments: label: D40
type_guessed: string
name: extract_symbolic_data
arguments: label: D124
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D108
type_guessed: string
name: extract_symbolic_data
arguments: label: D73
type_guessed: string
name: extract_symbolic_data
arguments: label: D45
type_guessed: string
name: extract_symbolic_data
arguments: label: D77
type_guessed: string
name: extract_symbolic_data
arguments: label: D131
type_guessed: string
name: extract_symbolic_data
arguments: label: D30
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string

tool: D100: Dec

tool: D76: Jan

tool: D40: Feb

tool: D124: Mar

tool: D2: Apr

tool: D32: May

tool: D108: Jun

tool: D73: Jul

tool: D45: Aug

tool: D77: Sep

tool: D131: Oct

tool: D30: Nov

tool: D31: Err

assistant: ```c
void DE_MONTH_NAME(int month, char *monthStr) {
  switch (month + 1) {
  case 1:
    strcpy(monthStr, "Jan");
    break;
  case 2:
    strcpy(monthStr, "Feb");
    break;
  case 3:
    strcpy(monthStr, "Mar");
    break;
  case 4:
    strcpy(monthStr, "Apr");
    break;
  case 5:
    strcpy(monthStr, "May");
    break;
  case 6:
    strcpy(monthStr, "Jun");
    break;
  case 7:
    strcpy(monthStr, "Jul");
    break;
  case 8:
    strcpy(monthStr, "Aug");
    break;
  case 9:
    strcpy(monthStr, "Sep");
    break;
  case 10:
    strcpy(monthStr, "Oct");
    break;
  case 11:
    strcpy(monthStr, "Nov");
    break;
  case 12:
    strcpy(monthStr, "Dec");
    break;
  default:
    strcpy(monthStr, "Err");
    break;
  }
}
```