ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L6
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  nop
  leave
  ret
```

assistant: ```c
void str_trim(char *line) {
  int len = strlen(line) - 1;
  if (line[len] == '\n' || line[len] == '\r') {
    line[len] = '\0';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L6
  cmp    $0xd,%al
  jne    L3
L6:
  movb   $0x0,(%rbx)
L3:
  pop    %rbx
  ret
```

assistant: ```c
void str_trim(char *line) {
  int len = strlen(line) - 1;
  if (line[len] == '\n' || line[len] == '\r') {
    line[len] = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L17
  cmp    $0xd,%al
  je     L17
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void str_trim(char *line) {
  int len = strlen(line) - 1;
  if (line[len] == '\n' || line[len] == '\r') {
    line[len] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L2
  cmp    $0xd,%al
  je     L2
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void str_trim(char *line) {
  int len = strlen(line) - 1;
  if (line[len] == '\n' || line[len] == '\r') {
    line[len] = '\0';
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x6,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %i %i


assistant: ```c
void main(void) {
  int n = 6, m = 3;
  n *= m + 1;
  printf("%i %i\n", m, n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x18,%edx
  mov    $0x3,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: %i %i


assistant: ```c
void main(void) {
  int n = 6, m = 3;
  n *= m + 1;
  printf("%i %i\n", m, n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x18,%edx
  mov    $0x3,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: %i %i


assistant: ```c
void main(void) {
  int n = 6, m = 3;
  n *= m + 1;
  printf("%i %i\n", m, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x18,%edx
  mov    $0x3,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string

tool: D9: %i %i


assistant: ```c
void main(void) {
  int n = 6, m = 3;
  n *= m + 1;
  printf("%i %i\n", m, n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ClearEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  sub    $0x1,%rax
  lea    (%r12,%rax,1),%rbx
  jmp    L3
L11:
  mov    %rbx,%rax
  lea    -0x1(%rax),%rbx
  movb   $0x0,(%rax)
L3:
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jle    L11
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *ClearEnd(register char *cp) {
  register char *end = cp + strlen(cp) - 1;
  while (*end < 33)
    *end-- = 0;
  return (cp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ClearEnd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jg     L8
L5:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmpb   $0x20,(%rax)
  jle    L5
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *ClearEnd(register char *cp) {
  register char *end = cp + strlen(cp) - 1;
  while (*end < 33)
    *end-- = 0;
  return (cp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ClearEnd>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jg     L14
  nopw   0x0(%rax,%rax,1)
L4:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmpb   $0x20,(%rax)
  jle    L4
L14:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ClearEnd(register char *cp) {
  register char *end = cp + strlen(cp) - 1;
  while (*end < 33)
    *end-- = 0;
  return (cp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ClearEnd>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rax
  cmpb   $0x20,(%rax)
  jg     L2
  nopw   0x0(%rax,%rax,1)
L1:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  cmpb   $0x20,(%rax)
  jle    L1
L2:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ClearEnd(register char *cp) {
  register char *end = cp + strlen(cp) - 1;
  while (*end < 33)
    *end-- = 0;
  return (cp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test5_stack_overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x90909090,-0xc(%rbp)
  movl   $0x91919191,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x14(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x45,(%rax)
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jbe    L4
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void test5_stack_overflow(void) {
  int a, b, i;
  a = 0x90909090;
  b = 0x91919191;
  for (i = 0; i <= sizeof(b); i++)
    *(((unsigned char *)(&b)) + i) = 'E';
}
```
user: What is the c source code of the assembly code below:

```asm
<test5_stack_overflow>:
  endbr64
  ret
```

assistant: ```c
void test5_stack_overflow(void) {
  int a, b, i;
  a = 0x90909090;
  b = 0x91919191;
  for (i = 0; i <= sizeof(b); i++)
    *(((unsigned char *)(&b)) + i) = 'E';
}
```
user: Translate the below assembly code into C programming language:

```asm
<test5_stack_overflow>:
  endbr64
  ret
```

assistant: ```c
void test5_stack_overflow(void) {
  int a, b, i;
  a = 0x90909090;
  b = 0x91919191;
  for (i = 0; i <= sizeof(b); i++)
    *(((unsigned char *)(&b)) + i) = 'E';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test5_stack_overflow>:
  endbr64
  ret
```

assistant: ```c
void test5_stack_overflow(void) {
  int a, b, i;
  a = 0x90909090;
  b = 0x91919191;
  for (i = 0; i <= sizeof(b); i++)
    *(((unsigned char *)(&b)) + i) = 'E';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x6b,-0x1(%rbp)
L3:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpb   $0x6b,-0x1(%rbp)
  je     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %c

assistant: ```c
void main() {
  char ch = 'k';
  do {
    ch = getch();
    printf("%c", ch);
  } while (ch == 'k');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D5(%rip),%rbp
L8:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  movsbl %al,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x6b,%bl
  je     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: %c

assistant: ```c
void main() {
  char ch = 'k';
  do {
    ch = getch();
    printf("%c", ch);
  } while (ch == 'k');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  mov    %esi,%ebx
  call   <printf@plt>
  cmp    $0x6b,%bl
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: %c

assistant: ```c
void main() {
  char ch = 'k';
  do {
    ch = getch();
    printf("%c", ch);
  } while (ch == 'k');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %rbp,%rdi
  movsbl %al,%esi
  mov    %esi,%ebx
  call   <printf@plt>
  cmp    $0x6b,%bl
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: %c

assistant: ```c
void main() {
  char ch = 'k';
  do {
    ch = getch();
    printf("%c", ch);
  } while (ch == 'k');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<random16_min_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <random16_max@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint16_t random16_min_max(uint16_t min, uint16_t lim) {
  uint16_t delta = lim - min;
  uint16_t r = random16_max(delta) + min;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random16_min_max>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    %rdi,%rsi
  mov    %rsi,%rdi
  call   <random16_max@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint16_t random16_min_max(uint16_t min, uint16_t lim) {
  uint16_t delta = lim - min;
  uint16_t r = random16_max(delta) + min;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random16_min_max>:
  endbr64
  push   %rbx
  sub    %rdi,%rsi
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <random16_max@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint16_t random16_min_max(uint16_t min, uint16_t lim) {
  uint16_t delta = lim - min;
  uint16_t r = random16_max(delta) + min;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<random16_min_max>:
  endbr64
  push   %rbx
  sub    %rdi,%rsi
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <random16_max@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint16_t random16_min_max(uint16_t min, uint16_t lim) {
  uint16_t delta = lim - min;
  uint16_t r = random16_max(delta) + min;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memory_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L48:
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x2c(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L48
  mov    -0x2c(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L20
L38:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  subl   $0x1,-0x14(%rbp)
L20:
  cmpl   $0x0,-0x14(%rbp)
  jns    L38
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memory_zero(void *ptr, uint32_t len) {
  uint32_t *ptr32 = ptr;
  uint8_t *ptr8;
  int i;
  for (i = 0; i < len / 4; i++)
    *ptr32++ = 0;
  if (len % 4) {
    ptr8 = (uint8_t *)ptr32;
    for (i = len % 4; i >= 0; i--)
      ptr8[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memory_zero>:
  endbr64
  mov    %rdi,%rdx
  lea    0x3(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  cmp    $0x3,%esi
  jle    L17
  mov    $0x0,%eax
L47:
  movl   $0x0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L47
  lea    -0x1(%rcx),%eax
  lea    0x4(,%rax,4),%rax
  cmp    $0x3,%esi
  mov    $0x4,%ecx
  cmovle %rcx,%rax
  add    %rax,%rdx
  test   $0x3,%sil
  jne    L14
  ret
L17:
  test   $0x3,%sil
  je     L52
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rsi,%rax,1),%ecx
  and    $0x3,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  jns    L41
L52:
  ret
L14:
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  lea    (%rsi,%rcx,1),%eax
  and    $0x3,%eax
  sub    %ecx,%eax
L41:
  cltq
L48:
  movq   $0x0,(%rdx,%rax,8)
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L48
  ret
```

assistant: ```c
void memory_zero(void *ptr, uint32_t len) {
  uint32_t *ptr32 = ptr;
  uint8_t *ptr8;
  int i;
  for (i = 0; i < len / 4; i++)
    *ptr32++ = 0;
  if (len % 4) {
    ptr8 = (uint8_t *)ptr32;
    for (i = len % 4; i >= 0; i--)
      ptr8[i] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memory_zero>:
  endbr64
  push   %rbp
  lea    0x3(%rsi),%eax
  mov    %rdi,%rcx
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  cmp    $0x3,%esi
  jle    L38
  sub    $0x1,%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rbp
  mov    %rbp,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbp,%rcx
  and    $0x3,%ebx
  jne    L58
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  test   $0x3,%sil
  je     L27
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  js     L27
  nopw   0x0(%rax,%rax,1)
L58:
  movslq %ebx,%rbx
  lea    0x8(%rcx),%rsi
  movq   $0x0,(%rcx)
  xor    %edi,%edi
  lea    0x8(,%rbx,8),%rax
  and    $0xfffffffffffffff8,%rsi
  mov    %eax,%edx
  movq   $0x0,-0x8(%rcx,%rdx,1)
  sub    %rsi,%rcx
  add    %ecx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L27
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L20:
  mov    %edx,%ecx
  add    $0x8,%edx
  mov    %rdi,(%rsi,%rcx,1)
  cmp    %eax,%edx
  jb     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void memory_zero(void *ptr, uint32_t len) {
  uint32_t *ptr32 = ptr;
  uint8_t *ptr8;
  int i;
  for (i = 0; i < len / 4; i++)
    *ptr32++ = 0;
  if (len % 4) {
    ptr8 = (uint8_t *)ptr32;
    for (i = len % 4; i >= 0; i--)
      ptr8[i] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memory_zero>:
  endbr64
  push   %rbp
  lea    0x3(%rsi),%eax
  mov    %rdi,%rcx
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x2,%eax
  cmp    $0x3,%esi
  jle    L16
  sub    $0x1,%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rbp
  mov    %rbp,%rdx
  call   <memset@plt>
  mov    %rax,%rcx
  add    %rbp,%rcx
  and    $0x3,%ebx
  jne    L57
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  test   $0x3,%sil
  je     L56
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  js     L56
  nopw   0x0(%rax,%rax,1)
L57:
  movslq %ebx,%rbx
  lea    0x8(%rcx),%rsi
  movq   $0x0,(%rcx)
  xor    %edi,%edi
  lea    0x8(,%rbx,8),%rax
  and    $0xfffffffffffffff8,%rsi
  mov    %eax,%edx
  movq   $0x0,-0x8(%rcx,%rdx,1)
  sub    %rsi,%rcx
  add    %ecx,%eax
  and    $0xfffffff8,%eax
  cmp    $0x8,%eax
  jb     L56
  and    $0xfffffff8,%eax
  xor    %edx,%edx
L48:
  mov    %edx,%ecx
  add    $0x8,%edx
  mov    %rdi,(%rsi,%rcx,1)
  cmp    %eax,%edx
  jb     L48
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void memory_zero(void *ptr, uint32_t len) {
  uint32_t *ptr32 = ptr;
  uint8_t *ptr8;
  int i;
  for (i = 0; i < len / 4; i++)
    *ptr32++ = 0;
  if (len % 4) {
    ptr8 = (uint8_t *)ptr32;
    for (i = len % 4; i >= 0; i--)
      ptr8[i] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InitRockStripes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void InitRockStripes(char **type_of_rock, double **topography) {
  if ((0) > 3) {
    int y;
    for (y = 0; y < 2 * (200); y++) {
      int x;
      for (x = 0; x < (0) - 3; x++) {
        type_of_rock[x][y] = 'f';
        topography[x][y] = (30.0);
      }
    }
    set_rock_blocks(type_of_rock + (0) - 3, topography + (0) - 3, (50) - ((0) - 3), 2 * (200), (9));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InitRockStripes>:
  endbr64
  ret
```

assistant: ```c
void InitRockStripes(char **type_of_rock, double **topography) {
  if ((0) > 3) {
    int y;
    for (y = 0; y < 2 * (200); y++) {
      int x;
      for (x = 0; x < (0) - 3; x++) {
        type_of_rock[x][y] = 'f';
        topography[x][y] = (30.0);
      }
    }
    set_rock_blocks(type_of_rock + (0) - 3, topography + (0) - 3, (50) - ((0) - 3), 2 * (200), (9));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<InitRockStripes>:
  endbr64
  ret
```

assistant: ```c
void InitRockStripes(char **type_of_rock, double **topography) {
  if ((0) > 3) {
    int y;
    for (y = 0; y < 2 * (200); y++) {
      int x;
      for (x = 0; x < (0) - 3; x++) {
        type_of_rock[x][y] = 'f';
        topography[x][y] = (30.0);
      }
    }
    set_rock_blocks(type_of_rock + (0) - 3, topography + (0) - 3, (50) - ((0) - 3), 2 * (200), (9));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L2
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <outputcar@plt>
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void output(char *s) {
  while (*s) {
    outputcar(*s++);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L4:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <outputcar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L4
L19:
  pop    %rbx
  ret
```

assistant: ```c
void output(char *s) {
  while (*s) {
    outputcar(*s++);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<output>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L1:
  call   <outputcar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L10:
  pop    %rbx
  ret
```

assistant: ```c
void output(char *s) {
  while (*s) {
    outputcar(*s++);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<output>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L9:
  call   <outputcar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L9
L14:
  pop    %rbx
  ret
```

assistant: ```c
void output(char *s) {
  while (*s) {
    outputcar(*s++);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vectors_scalar_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float vectors_scalar_product(const float u[3], const float v[3]) {
  float scp = (u[0] * v[0] + u[1] * v[1] + u[2] * v[2]);
  return scp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vectors_scalar_product>:
  endbr64
  movss  (%rdi),%xmm0
  mulss  (%rsi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vectors_scalar_product(const float u[3], const float v[3]) {
  float scp = (u[0] * v[0] + u[1] * v[1] + u[2] * v[2]);
  return scp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vectors_scalar_product>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vectors_scalar_product(const float u[3], const float v[3]) {
  float scp = (u[0] * v[0] + u[1] * v[1] + u[2] * v[2]);
  return scp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vectors_scalar_product>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  mulss  (%rsi),%xmm0
  mulss  0x4(%rsi),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  0x8(%rsi),%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vectors_scalar_product(const float u[3], const float v[3]) {
  float scp = (u[0] * v[0] + u[1] * v[1] + u[2] * v[2]);
  return scp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ms2ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ms2ns(uint64_t msec) {
  uint64_t const ns = msec * 1000000;
  return ns;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ms2ns>:
  endbr64
  imul   $0xf4240,%edi,%eax
  ret
```

assistant: ```c
uint64_t ms2ns(uint64_t msec) {
  uint64_t const ns = msec * 1000000;
  return ns;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ms2ns>:
  endbr64
  imul   $0xf4240,%edi,%eax
  ret
```

assistant: ```c
uint64_t ms2ns(uint64_t msec) {
  uint64_t const ns = msec * 1000000;
  return ns;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ms2ns>:
  endbr64
  imul   $0xf4240,%edi,%eax
  ret
```

assistant: ```c
uint64_t ms2ns(uint64_t msec) {
  uint64_t const ns = msec * 1000000;
  return ns;
}
```