ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<h2o_hex_decode>:
  endbr64
  test   $0x1,%dl
  jne    L58
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    (%rsi,%rdx,1),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L55
  jmp    L6
  nopl   0x0(%rax)
L57:
  movsbl 0x1(%r13),%edi
  add    $0x2,%r13
  call   <decode_hex@plt>
  cmp    $0xffffffff,%eax
  je     L47
  shl    $0x4,%ebx
  add    $0x1,%rbp
  or     %eax,%ebx
  mov    %bl,-0x1(%rbp)
  cmp    %r13,%r12
  je     L6
L55:
  movsbl 0x0(%r13),%edi
  call   <decode_hex@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L57
L47:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int h2o_hex_decode(void *_dst, const char *src, size_t src_len) {
  unsigned char *dst = _dst;
  if (src_len % 2 != 0)
    return -1;
  for (; src_len != 0; src_len -= 2) {
    int hi, lo;
    if ((hi = decode_hex(*src++)) == -1 || (lo = decode_hex(*src++)) == -1)
      return -1;
    *dst++ = (hi << 4) | lo;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<h2o_hex_decode>:
  endbr64
  test   $0x1,%dl
  jne    L14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    (%rsi,%rdx,1),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jne    L51
  jmp    L23
  nopl   0x0(%rax)
L27:
  movsbl 0x1(%r13),%edi
  add    $0x2,%r13
  call   <decode_hex@plt>
  cmp    $0xffffffff,%eax
  je     L44
  shl    $0x4,%ebx
  add    $0x1,%rbp
  or     %eax,%ebx
  mov    %bl,-0x1(%rbp)
  cmp    %r13,%r12
  je     L23
L51:
  movsbl 0x0(%r13),%edi
  call   <decode_hex@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L27
L44:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L23:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int h2o_hex_decode(void *_dst, const char *src, size_t src_len) {
  unsigned char *dst = _dst;
  if (src_len % 2 != 0)
    return -1;
  for (; src_len != 0; src_len -= 2) {
    int hi, lo;
    if ((hi = decode_hex(*src++)) == -1 || (lo = decode_hex(*src++)) == -1)
      return -1;
    *dst++ = (hi << 4) | lo;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvtnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L38
L3:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L45
L12:
  addq   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x8(%rbp)
L45:
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L10:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  subq   $0x1,-0x18(%rbp)
  lea    D6(%rip),%rax
  movzbl (%rdx,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rax,-0x8(%rbp)
L25:
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
L38:
  pop    %rbp
  ret
```

assistant: ```c
void cvtnum(buf, num, base) char *buf;
unsigned long num;
int base;
{
  static char digits[] = "0123456789abcdef";
  unsigned long tmp;
  if (num == 0L) {
    buf[0] = '0';
    buf[1] = '\0';
    return;
  }
  for (tmp = num; tmp > 0; tmp /= base) {
    buf++;
  }
  *buf = '\0';
  for (tmp = num; tmp > 0; tmp /= base) {
    *--buf = digits[tmp % base];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cvtnum>:
  endbr64
  mov    %rsi,%rax
  movslq %edx,%rcx
  test   %rsi,%rsi
  je     L20
L5:
  add    $0x1,%rdi
  mov    %rax,%r8
  mov    $0x0,%edx
  div    %rcx
  cmp    %r8,%rcx
  jbe    L5
  movb   $0x0,(%rdi)
  lea    D3(%rip),%r8
L1:
  sub    $0x1,%rdi
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rcx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rdi)
  mov    %rsi,%rdx
  mov    %rax,%rsi
  cmp    %rdx,%rcx
  jbe    L1
  ret
L20:
  movb   $0x30,(%rdi)
  movb   $0x0,0x1(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: 0123456789abcdef

assistant: ```c
void cvtnum(buf, num, base) char *buf;
unsigned long num;
int base;
{
  static char digits[] = "0123456789abcdef";
  unsigned long tmp;
  if (num == 0L) {
    buf[0] = '0';
    buf[1] = '\0';
    return;
  }
  for (tmp = num; tmp > 0; tmp /= base) {
    buf++;
  }
  *buf = '\0';
  for (tmp = num; tmp > 0; tmp /= base) {
    *--buf = digits[tmp % base];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cvtnum>:
  endbr64
  movslq %edx,%rcx
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L12
  nop
L21:
  mov    %rax,%r8
  xor    %edx,%edx
  add    $0x1,%rdi
  div    %rcx
  cmp    %r8,%rcx
  jbe    L21
  movb   $0x0,(%rdi)
  lea    D2(%rip),%r8
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rsi,%rax
  xor    %edx,%edx
  sub    $0x1,%rdi
  div    %rcx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rdi)
  mov    %rsi,%rdx
  mov    %rax,%rsi
  cmp    %rdx,%rcx
  jbe    L23
  ret
  nop
L12:
  mov    $0x30,%eax
  mov    %ax,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: 0123456789abcdef

assistant: ```c
void cvtnum(buf, num, base) char *buf;
unsigned long num;
int base;
{
  static char digits[] = "0123456789abcdef";
  unsigned long tmp;
  if (num == 0L) {
    buf[0] = '0';
    buf[1] = '\0';
    return;
  }
  for (tmp = num; tmp > 0; tmp /= base) {
    buf++;
  }
  *buf = '\0';
  for (tmp = num; tmp > 0; tmp /= base) {
    *--buf = digits[tmp % base];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cvtnum>:
  endbr64
  movslq %edx,%rcx
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L7
  nop
L8:
  mov    %rax,%r8
  xor    %edx,%edx
  add    $0x1,%rdi
  div    %rcx
  cmp    %r8,%rcx
  jbe    L8
  movb   $0x0,(%rdi)
  lea    D9(%rip),%r8
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rsi,%rax
  xor    %edx,%edx
  sub    $0x1,%rdi
  div    %rcx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rdi)
  mov    %rsi,%rdx
  mov    %rax,%rsi
  cmp    %rdx,%rcx
  jbe    L22
  ret
  nop
L7:
  mov    $0x30,%eax
  mov    %ax,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: 0123456789abcdef

assistant: ```c
void cvtnum(buf, num, base) char *buf;
unsigned long num;
int base;
{
  static char digits[] = "0123456789abcdef";
  unsigned long tmp;
  if (num == 0L) {
    buf[0] = '0';
    buf[1] = '\0';
    return;
  }
  for (tmp = num; tmp > 0; tmp /= base) {
    buf++;
  }
  *buf = '\0';
  for (tmp = num; tmp > 0; tmp /= base) {
    *--buf = digits[tmp % base];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fs_nread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fs_open@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L15
L14:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fs_fnread@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fs_close@plt>
  mov    -0x8(%rbp),%rax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: r

assistant: ```c
char *fs_nread(const char *path, int len) {
  FILE *file = fs_open(path, "r");
  if (NULL == file)
    return NULL;
  char *buffer = fs_fnread(file, len);
  fs_close(file);
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fs_nread>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  lea    D3(%rip),%rsi
  call   <fs_open@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <fs_fnread@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <fs_close@plt>
L15:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    %rax,%rbp
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: r

assistant: ```c
char *fs_nread(const char *path, int len) {
  FILE *file = fs_open(path, "r");
  if (NULL == file)
    return NULL;
  char *buffer = fs_fnread(file, len);
  fs_close(file);
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fs_nread>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    D7(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fs_open@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <fs_fnread@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fs_close@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: r

assistant: ```c
char *fs_nread(const char *path, int len) {
  FILE *file = fs_open(path, "r");
  if (NULL == file)
    return NULL;
  char *buffer = fs_fnread(file, len);
  fs_close(file);
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fs_nread>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  lea    D6(%rip),%rsi
  push   %rbp
  sub    $0x8,%rsp
  call   <fs_open@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbp
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <fs_fnread@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <fs_close@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: r

assistant: ```c
char *fs_nread(const char *path, int len) {
  FILE *file = fs_open(path, "r");
  if (NULL == file)
    return NULL;
  char *buffer = fs_fnread(file, len);
  fs_close(file);
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<String_split>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rdx,0x8(%rsp)
  mov    %esi,%ebx
  movl   $0x0,(%rdx)
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x0,%r13d
  mov    $0xa,%r15d
  movsbl %bl,%eax
  mov    %eax,0x4(%rsp)
  jmp    L37
L20:
  lea    0x1(%r12,%rbx,1),%r12
  add    $0x1,%r13
L37:
  mov    %r13d,%ebp
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  sub    %r12,%rbx
  mov    %ebx,(%rsp)
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%rsp),%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,(%r14,%r13,8)
  lea    0x1(%r13),%ebp
  cmp    %ebp,%r15d
  jne    L20
  add    $0xa,%r15d
  lea    0x0(,%r15,8),%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L39
  mov    %rax,%r14
  jmp    L20
L39:
  cmpb   $0x0,(%r12)
  jne    L25
L49:
  lea    0x8(,%rbp,8),%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  cmove  %r14,%rax
  movslq %ebp,%rdx
  movq   $0x0,(%rax,%rdx,8)
  mov    0x8(%rsp),%rcx
  mov    %ebp,(%rcx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rax
  mov    %rbx,(%r14,%rax,8)
  add    $0x1,%ebp
  jmp    L49
```

assistant: ```c
char **String_split(const char *s, char sep, int *n) {
  *n = 0;
  const int rate = 10;
  char **out = (char **)malloc(sizeof(char *) * rate);
  int ctr = 0;
  int blocks = rate;
  char *where;
  while ((where = strchr(s, sep)) != NULL) {
    int size = where - s;
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size);
    token[size] = '\0';
    out[ctr] = token;
    ctr++;
    if (ctr == blocks) {
      blocks += rate;
      char **newOut = (char **)realloc(out, sizeof(char *) * blocks);
      if (newOut) {
        out = newOut;
      } else {
        blocks -= rate;
        break;
      }
    }
    s += size + 1;
  }
  if (s[0] != '\0') {
    int size = strlen(s);
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size + 1);
    out[ctr] = token;
    ctr++;
  }
  char **newOut = realloc(out, sizeof(char *) * (ctr + 1));
  if (newOut) {
    out = newOut;
  }
  out[ctr] = NULL;
  *n = ctr;
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<String_split>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x50,%edi
  push   %r14
  mov    %esi,%r14d
  push   %r13
  movsbl %r14b,%r14d
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movl   $0x0,(%rdx)
  mov    %rdx,0x18(%rsp)
  call   <malloc@plt>
  movl   $0xa,0x14(%rsp)
  mov    %rax,0x8(%rsp)
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L38:
  lea    0x1(%r15,%rbx,1),%r15
  add    $0x1,%r13
L19:
  mov    %r14d,%esi
  mov    %r15,%rdi
  lea    0x1(%r13),%ebp
  movslq %r13d,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L30
  sub    %r15,%rax
  lea    0x1(%rax),%edi
  mov    %rax,%rbx
  mov    %eax,0x10(%rsp)
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %r15,%rsi
  movslq %ebx,%rbx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,(%rax,%r13,8)
  cmp    %ebp,0x14(%rsp)
  jne    L38
  lea    0xb(%r13),%eax
  mov    0x8(%rsp),%rdi
  lea    0x0(,%rax,8),%esi
  mov    %eax,0x14(%rsp)
  call   <realloc@plt>
  test   %rax,%rax
  je     L50
  mov    %rax,0x8(%rsp)
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L50:
  movslq %ebp,%rbx
  nopl   0x0(%rax,%rax,1)
L30:
  cmpb   $0x0,(%r15)
  jne    L20
L45:
  mov    0x8(%rsp),%r14
  lea    0x8(,%rbx,8),%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  mov    0x18(%rsp),%rcx
  movslq %ebx,%rdx
  test   %rax,%rax
  cmove  %r14,%rax
  movq   $0x0,(%rax,%rdx,8)
  mov    %ebx,(%rcx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r15,%rdi
  lea    0x1(%rbx),%r13d
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax,%rbx,8)
  mov    %r13d,%ebx
  jmp    L45
```

assistant: ```c
char **String_split(const char *s, char sep, int *n) {
  *n = 0;
  const int rate = 10;
  char **out = (char **)malloc(sizeof(char *) * rate);
  int ctr = 0;
  int blocks = rate;
  char *where;
  while ((where = strchr(s, sep)) != NULL) {
    int size = where - s;
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size);
    token[size] = '\0';
    out[ctr] = token;
    ctr++;
    if (ctr == blocks) {
      blocks += rate;
      char **newOut = (char **)realloc(out, sizeof(char *) * blocks);
      if (newOut) {
        out = newOut;
      } else {
        blocks -= rate;
        break;
      }
    }
    s += size + 1;
  }
  if (s[0] != '\0') {
    int size = strlen(s);
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size + 1);
    out[ctr] = token;
    ctr++;
  }
  char **newOut = realloc(out, sizeof(char *) * (ctr + 1));
  if (newOut) {
    out = newOut;
  }
  out[ctr] = NULL;
  *n = ctr;
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<String_split>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    $0x50,%edi
  push   %r14
  mov    %esi,%r14d
  push   %r13
  movsbl %r14b,%r14d
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movl   $0x0,(%rdx)
  mov    %rdx,0x18(%rsp)
  call   <malloc@plt>
  movl   $0xa,0x14(%rsp)
  mov    %rax,0x8(%rsp)
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x1(%r15,%rbx,1),%r15
  add    $0x1,%r13
L20:
  mov    %r14d,%esi
  mov    %r15,%rdi
  lea    0x1(%r13),%ebp
  movslq %r13d,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  sub    %r15,%rax
  lea    0x1(%rax),%edi
  mov    %rax,%rbx
  mov    %eax,0x10(%rsp)
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %r15,%rsi
  movslq %ebx,%rbx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,(%rax,%r13,8)
  cmp    %ebp,0x14(%rsp)
  jne    L29
  mov    %rax,%rdi
  lea    0xb(%r13),%eax
  lea    0x0(,%rax,8),%esi
  mov    %eax,0x14(%rsp)
  call   <realloc@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,0x8(%rsp)
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L27:
  movslq %ebp,%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  cmpb   $0x0,(%r15)
  jne    L21
L41:
  mov    0x8(%rsp),%r14
  lea    0x8(,%rbx,8),%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  mov    0x18(%rsp),%rcx
  movslq %ebx,%rdx
  test   %rax,%rax
  cmove  %r14,%rax
  movq   $0x0,(%rax,%rdx,8)
  mov    %ebx,(%rcx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r15,%rdi
  lea    0x1(%rbx),%r13d
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strncpy@plt>
  mov    0x8(%rsp),%rax
  mov    %rbp,(%rax,%rbx,8)
  mov    %r13d,%ebx
  jmp    L41
```

assistant: ```c
char **String_split(const char *s, char sep, int *n) {
  *n = 0;
  const int rate = 10;
  char **out = (char **)malloc(sizeof(char *) * rate);
  int ctr = 0;
  int blocks = rate;
  char *where;
  while ((where = strchr(s, sep)) != NULL) {
    int size = where - s;
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size);
    token[size] = '\0';
    out[ctr] = token;
    ctr++;
    if (ctr == blocks) {
      blocks += rate;
      char **newOut = (char **)realloc(out, sizeof(char *) * blocks);
      if (newOut) {
        out = newOut;
      } else {
        blocks -= rate;
        break;
      }
    }
    s += size + 1;
  }
  if (s[0] != '\0') {
    int size = strlen(s);
    char *token = (char *)malloc(size + 1);
    strncpy(token, s, size + 1);
    out[ctr] = token;
    ctr++;
  }
  char **newOut = realloc(out, sizeof(char *) * (ctr + 1));
  if (newOut) {
    out = newOut;
  }
  out[ctr] = NULL;
  *n = ctr;
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %edi,-0x1c4(%rbp)
  mov    %rsi,-0x1d0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1b0(%rbp),%rcx
  lea    -0x1b4(%rbp),%rdx
  lea    -0x1b8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L35
L6:
  movl   $0x0,-0x1ac(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L77
L57:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a8(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1a8(%rbp)
L77:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jb     L57
  movl   $0x0,-0x1a4(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L11
L40:
  mov    -0x1b8(%rbp),%eax
  add    %eax,-0x1ac(%rbp)
  mov    -0x1a4(%rbp),%eax
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%edx
  mov    -0x1b8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1b8(%rbp)
  addl   $0x1,-0x1a4(%rbp)
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jne    L15
  movl   $0x0,-0x1a4(%rbp)
L15:
  addl   $0x1,-0x1a8(%rbp)
L11:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jb     L40
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1b0(%rbp),%rcx
  lea    -0x1b4(%rbp),%rdx
  lea    -0x1b8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L35:
  mov    -0x1b8(%rbp),%eax
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D36
type_infered: string

tool: D1: %u %u %u

tool: D27: %d

tool: D36: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int n, m, k, sum;
  unsigned int i, j;
  int pattern[100];
  scanf("%u %u %u", &n, &m, &k);
  while (n != 0) {
    sum = 0;
    for (i = 0; i < k; i++)
      scanf("%d", &pattern[i]);
    j = 0;
    for (i = 0; i < m; i++) {
      sum += n;
      n += pattern[j];
      j += 1;
      if (j == k)
        j = 0;
    }
    printf("%u\n", sum);
    scanf("%u %u %u", &n, &m, &k);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  lea    D3(%rip),%r12
  lea    0x10(%rsp),%rbp
  lea    D20(%rip),%r14
  lea    D1(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jne    L71
L76:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L86:
  mov    %ebx,%eax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  ja     L86
L1:
  mov    0x8(%rsp),%r9d
  test   %r9d,%r9d
  je     L68
  mov    0x4(%rsp),%ecx
  mov    $0x0,%eax
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%r10d
L64:
  add    %ecx,%edi
  mov    %eax,%r8d
  add    0x10(%rsp,%r8,4),%ecx
  add    $0x1,%eax
  cmp    %edx,%eax
  cmove  %r10d,%eax
  add    $0x1,%esi
  cmp    %r9d,%esi
  jne    L64
  mov    %ecx,0x4(%rsp)
L18:
  mov    %edi,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L76
L71:
  mov    0xc(%rsp),%edx
  mov    $0x0,%ebx
  test   %edx,%edx
  jne    L86
  jmp    L1
L68:
  mov    %r9d,%edi
  jmp    L18
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string

tool: D1: %u %u %u

tool: D3: %d

tool: D20: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int n, m, k, sum;
  unsigned int i, j;
  int pattern[100];
  scanf("%u %u %u", &n, &m, &k);
  while (n != 0) {
    sum = 0;
    for (i = 0; i < k; i++)
      scanf("%d", &pattern[i]);
    j = 0;
    for (i = 0; i < m; i++) {
      sum += n;
      n += pattern[j];
      j += 1;
      if (j == k)
        j = 0;
    }
    printf("%u\n", sum);
    scanf("%u %u %u", &n, &m, &k);
  }
  return 0;
}
```