ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <makesTen@plt>
  test   %rax,%rax
  je     L20
  lea    D2(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L20:
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string
name: retrieve_data
arguments: label: D31
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D47
type_guessed: string

tool: D26: Given two numbers, is one of them 10 or is there sum 10?


tool: D6: Enter two numbers : 

tool: D31: %d%d

tool: D2: True

tool: D47: False

assistant: ```c
int main() {
  int i, j;
  printf("Given two numbers, is one of them 10 or is there sum 10?\n");
  printf("Enter two numbers : ");
  scanf("%d%d", &i, &j);
  if (makesTen(i, j))
    printf("True");
  else
    printf("False");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <makesTen@plt>
  test   %rax,%rax
  je     L22
  lea    D46(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D30
datatype: string
name: read_data
arguments: data_label: D46
datatype: string
name: read_data
arguments: data_label: D7
datatype: string

tool: D3: Given two numbers, is one of them 10 or is there sum 10?


tool: D15: Enter two numbers : 

tool: D30: %d%d

tool: D46: True

tool: D7: False

assistant: ```c
int main() {
  int i, j;
  printf("Given two numbers, is one of them 10 or is there sum 10?\n");
  printf("Enter two numbers : ");
  scanf("%d%d", &i, &j);
  if (makesTen(i, j))
    printf("True");
  else
    printf("False");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_group_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L25
L12:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
L25:
  cmpq   $0x0,-0x10(%rbp)
  jne    L28
  mov    $0x0,%eax
  call   <getgrent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
L28:
  mov    $0x0,%eax
  call   <endgrent@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
gid_t get_group_by_name(const char *name) {
  struct group *grp;
  gid_t res = 0;
  while ((0 == res) && (NULL != (grp = getgrent()))) {
    if (0 == strcmp(name, grp->gr_name)) {
      res = grp->gr_gid;
    }
  }
  endgrent();
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_group_by_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L6:
  mov    $0x0,%eax
  call   <getgrent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    (%rbx),%rbx
  test   %rbx,%rbx
  je     L6
L8:
  mov    $0x0,%eax
  call   <endgrent@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
gid_t get_group_by_name(const char *name) {
  struct group *grp;
  gid_t res = 0;
  while ((0 == res) && (NULL != (grp = getgrent()))) {
    if (0 == strcmp(name, grp->gr_name)) {
      res = grp->gr_gid;
    }
  }
  endgrent();
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_group_by_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  call   <getgrent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L27
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L22
  xor    %eax,%eax
  call   <endgrent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  xor    %r12d,%r12d
  xor    %eax,%eax
  call   <endgrent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
gid_t get_group_by_name(const char *name) {
  struct group *grp;
  gid_t res = 0;
  while ((0 == res) && (NULL != (grp = getgrent()))) {
    if (0 == strcmp(name, grp->gr_name)) {
      res = grp->gr_gid;
    }
  }
  endgrent();
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_group_by_name>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <getgrent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L5
  xor    %eax,%eax
  call   <endgrent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %r12d,%r12d
  xor    %eax,%eax
  call   <endgrent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
gid_t get_group_by_name(const char *name) {
  struct group *grp;
  gid_t res = 0;
  while ((0 == res) && (NULL != (grp = getgrent()))) {
    if (0 == strcmp(name, grp->gr_name)) {
      res = grp->gr_gid;
    }
  }
  endgrent();
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DivisionCall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Division@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L9:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D5: %d

tool: D3: Division by zero is not allowed

assistant: ```c
void DivisionCall(int a, int b) {
  if (b != 0)
    printf("%d", Division(a, b));
  else
    puts("Division by zero is not allowed");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DivisionCall>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L13
  call   <Division@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L15:
  add    $0x8,%rsp
  ret
L13:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D5: %d

tool: D3: Division by zero is not allowed

assistant: ```c
void DivisionCall(int a, int b) {
  if (b != 0)
    printf("%d", Division(a, b));
  else
    puts("Division by zero is not allowed");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<DivisionCall>:
  endbr64
  test   %esi,%esi
  je     L9
  sub    $0x8,%rsp
  call   <Division@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1090 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  lea    D15(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string

tool: D3: %d

tool: D15: Division by zero is not allowed

assistant: ```c
void DivisionCall(int a, int b) {
  if (b != 0)
    printf("%d", Division(a, b));
  else
    puts("Division by zero is not allowed");
}
```
user: What is the c source code of the assembly code below:

```asm
<DivisionCall>:
  endbr64
  test   %esi,%esi
  je     L6
  sub    $0x8,%rsp
  call   <Division@plt>
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1090 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D14(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D14
data_type: string

tool: D11: %d

tool: D14: Division by zero is not allowed

assistant: ```c
void DivisionCall(int a, int b) {
  if (b != 0)
    printf("%d", Division(a, b));
  else
    puts("Division by zero is not allowed");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %rsi,-0x440(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %rcx,-0x450(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <get_pty@plt>
  mov    %eax,-0x42c(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    D33(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x42c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  cmpl   $0x0,-0x42c(%rbp)
  jns    L79
  mov    $0xffffffff,%eax
  jmp    L35
L79:
  movl   $0x50,-0x420(%rbp)
  movl   $0x19,-0x41c(%rbp)
  mov    -0x420(%rbp),%eax
  mov    %eax,-0x418(%rbp)
  mov    -0x41c(%rbp),%eax
  mov    %eax,-0x414(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x420(%rbp),%rdx
  mov    -0x42c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  call   <fork@plt>
  mov    %eax,-0x428(%rbp)
  cmpl   $0x0,-0x428(%rbp)
  jns    L48
  mov    $0xffffffff,%eax
  jmp    L35
L48:
  cmpl   $0x0,-0x428(%rbp)
  jne    L68
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,-0x424(%rbp)
  movl   $0x0,-0x430(%rbp)
  jmp    L75
L74:
  mov    -0x430(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0x430(%rbp)
L75:
  mov    -0x430(%rbp),%eax
  cmp    -0x424(%rbp),%eax
  jl     L74
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  lea    -0x410(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    $0x0,%edi
  call   <dup@plt>
  mov    $0x0,%edi
  call   <dup@plt>
  mov    $0x0,%eax
  call   <setsid@plt>
  mov    -0x440(%rbp),%rdx
  mov    -0x438(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execv@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L68:
  mov    -0x448(%rbp),%rax
  mov    -0x42c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x450(%rbp),%rax
  mov    -0x428(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int run_process(const char *path, char **argv, int *fd_ptr, int *pid_ptr) {
  int pty_fd, pid, i, nb_fds;
  char tty_name[1024];
  struct winsize ws;
  pty_fd = get_pty(tty_name, sizeof(tty_name));
  fcntl(pty_fd, F_SETFL, O_NONBLOCK);
  if (pty_fd < 0)
    return -1;
  ws.ws_col = 80;
  ws.ws_row = 25;
  ws.ws_xpixel = ws.ws_col;
  ws.ws_ypixel = ws.ws_row;
  ioctl(pty_fd, TIOCSWINSZ, &ws);
  pid = fork();
  if (pid < 0)
    return -1;
  if (pid == 0) {
    nb_fds = getdtablesize();
    for (i = 0; i < nb_fds; i++)
      close(i);
    open(tty_name, O_RDWR);
    dup(0);
    dup(0);
    setsid();
    execv(path, (char *const *)argv);
    exit(1);
  }
  *fd_ptr = pty_fd;
  *pid_ptr = pid;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<run_process>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    $0x400,%esi
  call   <get_pty@plt>
  mov    %eax,%ebp
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  call   <fcntl@plt>
  test   %ebp,%ebp
  js     L75
  movl   $0x50,0x10(%rsp)
  movl   $0x19,0x14(%rsp)
  movl   $0x50,0x18(%rsp)
  movl   $0x19,0x1c(%rsp)
  lea    0x10(%rsp),%rdx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  call   <ioctl@plt>
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L35
  je     L78
L28:
  mov    %ebp,(%r14)
  mov    %r12d,0x0(%r13)
  mov    $0x0,%eax
L76:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  mov    $0x0,%eax
  call   <getdtablesize@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L45
  mov    %r12d,%ebx
L48:
  mov    %ebx,%edi
  call   <close@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r15d
  jne    L48
L45:
  lea    0x20(%rsp),%rdi
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    $0x0,%edi
  call   <dup@plt>
  mov    $0x0,%edi
  call   <dup@plt>
  mov    $0x0,%eax
  call   <setsid@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  call   <execv@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
L75:
  mov    $0xffffffff,%eax
  jmp    L76
L35:
  mov    $0xffffffff,%eax
  jmp    L76
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int run_process(const char *path, char **argv, int *fd_ptr, int *pid_ptr) {
  int pty_fd, pid, i, nb_fds;
  char tty_name[1024];
  struct winsize ws;
  pty_fd = get_pty(tty_name, sizeof(tty_name));
  fcntl(pty_fd, F_SETFL, O_NONBLOCK);
  if (pty_fd < 0)
    return -1;
  ws.ws_col = 80;
  ws.ws_row = 25;
  ws.ws_xpixel = ws.ws_col;
  ws.ws_ypixel = ws.ws_row;
  ioctl(pty_fd, TIOCSWINSZ, &ws);
  pid = fork();
  if (pid < 0)
    return -1;
  if (pid == 0) {
    nb_fds = getdtablesize();
    for (i = 0; i < nb_fds; i++)
      close(i);
    open(tty_name, O_RDWR);
    dup(0);
    dup(0);
    setsid();
    execv(path, (char *const *)argv);
    exit(1);
  }
  *fd_ptr = pty_fd;
  *pid_ptr = pid;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<run_process>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x448,%rsp
  mov    %rdi,0x10(%rsp)
  lea    0x30(%rsp),%r15
  mov    %rsi,0x18(%rsp)
  mov    %r15,%rdi
  mov    $0x400,%esi
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x438(%rsp)
  xor    %eax,%eax
  call   <get_pty@plt>
  mov    %eax,%ebx
  mov    D37(%rip),%rax
  mov    %ebx,%edi
  mov    (%rax),%edx
  mov    D32(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  test   %ebx,%ebx
  js     L24
  movabs $0x1900000050,%rax
  lea    0x20(%rsp),%rdx
  mov    %ebx,%edi
  mov    %rax,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L24
  je     L21
L71:
  mov    0x8(%rsp),%rax
  mov    %ebx,0x0(%r13)
  mov    %ebp,(%rax)
  xor    %eax,%eax
L35:
  mov    0x438(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x448,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L21:
  xor    %eax,%eax
  call   <getdtablesize@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L69
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L46:
  mov    %r12d,%edi
  add    $0x1,%r12d
  call   <close@plt>
  cmp    %r12d,%r14d
  jne    L46
L69:
  mov    D29(%rip),%rax
  mov    %r15,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  xor    %edi,%edi
  call   <dup@plt>
  xor    %edi,%edi
  call   <dup@plt>
  xor    %eax,%eax
  call   <setsid@plt>
  mov    0x10(%rsp),%rdi
  mov    0x18(%rsp),%rsi
  call   <execv@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L71
L24:
  mov    $0xffffffff,%eax
  jmp    L35
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int run_process(const char *path, char **argv, int *fd_ptr, int *pid_ptr) {
  int pty_fd, pid, i, nb_fds;
  char tty_name[1024];
  struct winsize ws;
  pty_fd = get_pty(tty_name, sizeof(tty_name));
  fcntl(pty_fd, F_SETFL, O_NONBLOCK);
  if (pty_fd < 0)
    return -1;
  ws.ws_col = 80;
  ws.ws_row = 25;
  ws.ws_xpixel = ws.ws_col;
  ws.ws_ypixel = ws.ws_row;
  ioctl(pty_fd, TIOCSWINSZ, &ws);
  pid = fork();
  if (pid < 0)
    return -1;
  if (pid == 0) {
    nb_fds = getdtablesize();
    for (i = 0; i < nb_fds; i++)
      close(i);
    open(tty_name, O_RDWR);
    dup(0);
    dup(0);
    setsid();
    execv(path, (char *const *)argv);
    exit(1);
  }
  *fd_ptr = pty_fd;
  *pid_ptr = pid;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(501, &fixed_gamma, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(501, &fixed_gamma, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(501, &fixed_gamma, b, c);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<initialize_dobldobl_homotopy>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1f5,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int initialize_dobldobl_homotopy(int fixed_gamma) {
  int fail, *b;
  double *c;
  fail = _ada_use_c2phc(501, &fixed_gamma, b, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fill_first_3_handles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void fill_first_3_handles() {
  int tmp_pipe1[2];
  int tmp_pipe2[2];
  pipe(tmp_pipe1);
  pipe(tmp_pipe2);
  close(tmp_pipe2[1]);
}
```
user: What is the c source code of the assembly code below:

```asm
<fill_first_3_handles>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  lea    0x10(%rsp),%rdi
  call   <pipe@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill_first_3_handles() {
  int tmp_pipe1[2];
  int tmp_pipe2[2];
  pipe(tmp_pipe1);
  pipe(tmp_pipe2);
  close(tmp_pipe2[1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_first_3_handles>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  lea    0x10(%rsp),%rdi
  call   <pipe@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill_first_3_handles() {
  int tmp_pipe1[2];
  int tmp_pipe2[2];
  pipe(tmp_pipe1);
  pipe(tmp_pipe2);
  close(tmp_pipe2[1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fill_first_3_handles>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <pipe@plt>
  lea    0x10(%rsp),%rdi
  call   <pipe@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fill_first_3_handles() {
  int tmp_pipe1[2];
  int tmp_pipe2[2];
  pipe(tmp_pipe1);
  pipe(tmp_pipe2);
  close(tmp_pipe2[1]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitstream_write_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rcx
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void bitstream_write_uint32(char **b, uint32_t value) {
  memcpy(*b, &value, sizeof(uint32_t));
  *b += sizeof(uint32_t);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitstream_write_uint32>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    (%rdi),%rdi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void bitstream_write_uint32(char **b, uint32_t value) {
  memcpy(*b, &value, sizeof(uint32_t));
  *b += sizeof(uint32_t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitstream_write_uint32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void bitstream_write_uint32(char **b, uint32_t value) {
  memcpy(*b, &value, sizeof(uint32_t));
  *b += sizeof(uint32_t);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitstream_write_uint32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <memcpy@plt>
  addq   $0x4,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void bitstream_write_uint32(char **b, uint32_t value) {
  memcpy(*b, &value, sizeof(uint32_t));
  *b += sizeof(uint32_t);
}
```