ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
  lea    D13(%rip),%rbp
  jmp    L20
L17:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xffff,%ebx
  je     L11
L20:
  mov    %ebx,%esi
  shr    $0xc,%esi
  and    $0x8,%esi
  mov    %ebx,%eax
  shr    $0x5,%eax
  and    $0x4,%eax
  or     %eax,%esi
  mov    %ebx,%eax
  shr    $0x3,%eax
  and    $0x2,%eax
  or     %eax,%esi
  mov    %ebx,%eax
  and    $0x1,%eax
  or     %eax,%esi
  add    $0x2,%esi
  mov    %ebx,%r13d
  mov    $0x1,%edx
L2:
  mov    %r13d,%ecx
  shr    %ecx
  mov    %r13d,%eax
  shr    $0x2,%eax
  xor    %ecx,%eax
  mov    %r13d,%edi
  shr    $0x8,%edi
  xor    %edi,%eax
  mov    %r13d,%edi
  shr    $0x9,%edi
  xor    %edi,%eax
  and    $0x1,%eax
  shl    $0xf,%eax
  or     %ecx,%eax
  and    $0x2008,%r13d
  mov    %eax,%ecx
  and    $0xfffffffe,%ecx
  or     $0x1,%eax
  cmp    $0x2008,%r13d
  cmovne %eax,%ecx
  mov    %ecx,%r13d
  add    $0x1,%edx
  cmp    %dl,%sil
  jne    L2
  jmp    L17
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string
name: retrieve_data
arguments: data_label: D13
type: string

tool: D7: %#06x 

tool: D13: %#06x


assistant: ```c
int main() {
  unsigned int input = 0x0000;
  while (input < 0xFFFF) {
    unsigned int seed = input;
    unsigned int seed_tmp = 0;
    unsigned char count = 0;
    unsigned char idx;
    unsigned char fib_tap = 0;
    count = ((seed >> 0xC & 0x8) | (seed >> 0x5 & 0x4) | (seed >> 0x3 & 0x2) | (seed & 0x1)) + 1;
    for (idx = 1; idx <= count; idx++) {
      fib_tap = ((seed >> 1) ^ (seed >> 2) ^ (seed >> 8) ^ (seed >> 9)) & 1;
      seed_tmp = ((seed >> 1) | (fib_tap << 0xF));
      if ((seed >> 0x3 & 1) && (seed >> 0xD & 1)) {
        seed = seed_tmp & ~1;
      } else {
        seed = seed_tmp | 1;
      }
    }
    printf("%#06x ", input);
    printf("%#06x\n", seed);
    input++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x8,%rsp
  nop
L1:
  mov    %r13d,%esi
  mov    %r13d,%eax
  mov    %r13d,%r12d
  mov    $0x1,%edx
  shr    $0xc,%esi
  shr    $0x5,%eax
  and    $0x4,%eax
  and    $0x8,%esi
  or     %eax,%esi
  mov    %r13d,%eax
  shr    $0x3,%eax
  and    $0x2,%eax
  or     %eax,%esi
  mov    %r13d,%eax
  and    $0x1,%eax
  or     %eax,%esi
  add    $0x2,%esi
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12d,%ecx
  mov    %r12d,%eax
  mov    %r12d,%edi
  shr    %ecx
  shr    $0x2,%eax
  xor    %ecx,%eax
  shr    $0x8,%edi
  xor    %edi,%eax
  mov    %r12d,%edi
  and    $0x2008,%r12d
  shr    $0x9,%edi
  xor    %edi,%eax
  and    $0x1,%eax
  shl    $0xf,%eax
  or     %ecx,%eax
  mov    %eax,%ecx
  or     $0x1,%eax
  and    $0xfffffffe,%ecx
  cmp    $0x2008,%r12d
  cmovne %eax,%ecx
  add    $0x1,%edx
  mov    %ecx,%r12d
  cmp    %sil,%dl
  jne    L15
  mov    %r13d,%esi
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    $0xffff,%r13d
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D8
type: string

tool: D3: %#06x 

tool: D8: %#06x


assistant: ```c
int main() {
  unsigned int input = 0x0000;
  while (input < 0xFFFF) {
    unsigned int seed = input;
    unsigned int seed_tmp = 0;
    unsigned char count = 0;
    unsigned char idx;
    unsigned char fib_tap = 0;
    count = ((seed >> 0xC & 0x8) | (seed >> 0x5 & 0x4) | (seed >> 0x3 & 0x2) | (seed & 0x1)) + 1;
    for (idx = 1; idx <= count; idx++) {
      fib_tap = ((seed >> 1) ^ (seed >> 2) ^ (seed >> 8) ^ (seed >> 9)) & 1;
      seed_tmp = ((seed >> 1) | (fib_tap << 0xF));
      if ((seed >> 0x3 & 1) && (seed >> 0xD & 1)) {
        seed = seed_tmp & ~1;
      } else {
        seed = seed_tmp | 1;
      }
    }
    printf("%#06x ", input);
    printf("%#06x\n", seed);
    input++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <ksft_print_header@plt>
  mov    $0x2,%edi
  call   <ksft_set_plan@plt>
  mov    $0x8,%edi
  call   <test_rename_attack@plt>
  mov    $0x10,%edi
  call   <test_rename_attack@plt>
  mov    $0x0,%eax
  call   <ksft_get_fail_cnt@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <ksft_get_error_cnt@plt>
  add    %rbx,%rax
  test   %rax,%rax
  jle    L19
  mov    $0x0,%eax
  call   <ksft_exit_fail@plt>
  jmp    L14
L19:
  mov    $0x0,%eax
  call   <ksft_exit_pass@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ksft_print_header();
  ksft_set_plan(2);
  test_rename_attack(0x08);
  test_rename_attack(0x10);
  if (ksft_get_fail_cnt() + ksft_get_error_cnt() > 0)
    ksft_exit_fail();
  else
    ksft_exit_pass();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <ksft_print_header@plt>
  mov    $0x2,%edi
  call   <ksft_set_plan@plt>
  mov    $0x8,%edi
  call   <test_rename_attack@plt>
  mov    $0x10,%edi
  call   <test_rename_attack@plt>
  mov    $0x0,%eax
  call   <ksft_get_fail_cnt@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <ksft_get_error_cnt@plt>
  add    %rax,%rbx
  test   %rbx,%rbx
  jle    L2
  mov    $0x0,%eax
  call   <ksft_exit_fail@plt>
L1:
  mov    $0x0,%eax
  pop    %rbx
  ret
L2:
  mov    $0x0,%eax
  call   <ksft_exit_pass@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  ksft_print_header();
  ksft_set_plan(2);
  test_rename_attack(0x08);
  test_rename_attack(0x10);
  if (ksft_get_fail_cnt() + ksft_get_error_cnt() > 0)
    ksft_exit_fail();
  else
    ksft_exit_pass();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <ksft_print_header@plt>
  mov    $0x2,%edi
  call   <ksft_set_plan@plt>
  mov    $0x8,%edi
  call   <test_rename_attack@plt>
  mov    $0x10,%edi
  call   <test_rename_attack@plt>
  xor    %eax,%eax
  call   <ksft_get_fail_cnt@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <ksft_get_error_cnt@plt>
  add    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  jle    L15
  call   <ksft_exit_fail@plt>
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  call   <ksft_exit_pass@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  ksft_print_header();
  ksft_set_plan(2);
  test_rename_attack(0x08);
  test_rename_attack(0x10);
  if (ksft_get_fail_cnt() + ksft_get_error_cnt() > 0)
    ksft_exit_fail();
  else
    ksft_exit_pass();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <ksft_print_header@plt>
  mov    $0x2,%edi
  call   <ksft_set_plan@plt>
  mov    $0x8,%edi
  call   <test_rename_attack@plt>
  mov    $0x10,%edi
  call   <test_rename_attack@plt>
  xor    %eax,%eax
  call   <ksft_get_fail_cnt@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <ksft_get_error_cnt@plt>
  add    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  jle    L0
  call   <ksft_exit_fail@plt>
L12:
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  call   <ksft_exit_pass@plt>
  jmp    L12
```

assistant: ```c
int main(int argc, char **argv) {
  ksft_print_header();
  ksft_set_plan(2);
  test_rename_attack(0x08);
  test_rename_attack(0x10);
  if (ksft_get_fail_cnt() + ksft_get_error_cnt() > 0)
    ksft_exit_fail();
  else
    ksft_exit_pass();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findMaxArr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L17:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L2:
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double findMaxArr(double *array, int num_elements) {
  int i = 0;
  double max = 0;
  for (i = 0; i < num_elements; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findMaxArr>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L8:
  movsd  (%rax),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L8
  ret
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double findMaxArr(double *array, int num_elements) {
  int i = 0;
  double max = 0;
  for (i = 0; i < num_elements; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<findMaxArr>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L3:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L3
  ret
  xchg   %ax,%ax
L10:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double findMaxArr(double *array, int num_elements) {
  int i = 0;
  double max = 0;
  for (i = 0; i < num_elements; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMaxArr>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L8:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L8
  ret
  xchg   %ax,%ax
L15:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double findMaxArr(double *array, int num_elements) {
  int i = 0;
  double max = 0;
  for (i = 0; i < num_elements; i++) {
    if (array[i] > max)
      max = array[i];
  }
  return max;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x28,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x28,%edx
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <lprintf@plt>
  sub    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  cmpl   $0x0,-0x34(%rbp)
  jle    L18
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <outstr@plt>
L18:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void printw(char *str) {
  int width = 40;
  char white[40];
  memset(white, '.', 40);
  width = width - lprintf(str);
  white[width + 1] = '\0';
  if (width > 0) {
    outstr(white);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printw>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x28,%edx
  mov    $0x2e,%esi
  call   <memset@plt>
  mov    %rbx,%rdi
  call   <lprintf@plt>
  mov    $0x29,%edx
  sub    %eax,%edx
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  cmp    $0x28,%eax
  jl     L2
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  mov    %rsp,%rdi
  call   <outstr@plt>
  jmp    L26
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printw(char *str) {
  int width = 40;
  char white[40];
  memset(white, '.', 40);
  width = width - lprintf(str);
  white[width + 1] = '\0';
  if (width > 0) {
    outstr(white);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printw>:
  endbr64
  push   %r12
  mov    $0x28,%edx
  mov    $0x2e,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    $0x29,%edx
  sub    %eax,%edx
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  cmp    $0x28,%eax
  jge    L10
  mov    %r12,%rdi
  call   <outstr@plt>
L10:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printw(char *str) {
  int width = 40;
  char white[40];
  memset(white, '.', 40);
  width = width - lprintf(str);
  white[width + 1] = '\0';
  if (width > 0) {
    outstr(white);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printw>:
  endbr64
  push   %r12
  mov    $0x28,%edx
  mov    $0x2e,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <lprintf@plt>
  mov    $0x29,%edx
  sub    %eax,%edx
  movslq %edx,%rdx
  movb   $0x0,(%rsp,%rdx,1)
  cmp    $0x28,%eax
  jge    L6
  mov    %r12,%rdi
  call   <outstr@plt>
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printw(char *str) {
  int width = 40;
  char white[40];
  memset(white, '.', 40);
  width = width - lprintf(str);
  white[width + 1] = '\0';
  if (width > 0) {
    outstr(white);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crop_ui16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L37
  mov    -0x10(%rbp),%rax
  jmp    L18
L37:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L21
  mov    -0x18(%rbp),%rax
  jmp    L18
L21:
  mov    -0x8(%rbp),%rax
L18:
  pop    %rbp
  ret
```

assistant: ```c
uint16_t crop_ui16(uint16_t val, uint16_t min, uint16_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crop_ui16>:
  endbr64
  cmp    %rdx,%rdi
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovge %rdx,%rax
  ret
```

assistant: ```c
uint16_t crop_ui16(uint16_t val, uint16_t min, uint16_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crop_ui16>:
  endbr64
  cmp    %rdx,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  cmovge %rdx,%rax
  ret
```

assistant: ```c
uint16_t crop_ui16(uint16_t val, uint16_t min, uint16_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crop_ui16>:
  endbr64
  cmp    %rdx,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  cmovge %rdx,%rax
  ret
```

assistant: ```c
uint16_t crop_ui16(uint16_t val, uint16_t min, uint16_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Trunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  cltd
  idivl  -0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double Trunc(double x, int n) {
  int power = pow(10, n);
  return floor(x * power) / power;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Trunc>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%r14
  mov    %edi,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %r14,%xmm1
  mulsd  %xmm1,%xmm0
  call   <floor@plt>
  cltd
  idiv   %ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double Trunc(double x, int n) {
  int power = pow(10, n);
  return floor(x * power) / power;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Trunc>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0xa,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double Trunc(double x, int n) {
  int power = pow(10, n);
  return floor(x * power) / power;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Trunc>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0xa,%edi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  mov    %eax,%ebx
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
```

assistant: ```c
double Trunc(double x, int n) {
  int power = pow(10, n);
  return floor(x * power) / power;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sumsm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L18:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L27:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L27
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumsm(int matrix[][100], int sc, int sr, int lc, int lr) {
  int i, j, sum = 0;
  for (i = sc; i <= lc; i++) {
    for (j = sr; j <= lr; j++)
      sum += matrix[i][j];
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumsm>:
  endbr64
  cmp    %ecx,%esi
  jg     L20
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %edx,%edi
  mov    %ecx,%eax
  mov    %r8d,%esi
  sub    %edx,%esi
  movslq %edx,%r11
  add    %rsi,%r11
  movslq %r9d,%rbx
  lea    (%rbx,%rbx,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x4,%rdx
  add    %r10,%rdx
  lea    0x4(%rdx,%r11,4),%rcx
  sub    %r9d,%eax
  add    %rbx,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r11,%rax,4),%rax
  lea    0x194(%r10,%rax,4),%r9
  mov    $0x0,%edx
  not    %rsi
  shl    $0x2,%rsi
  jmp    L37
L8:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L8
L0:
  add    $0x190,%rcx
  cmp    %r9,%rcx
  je     L6
L37:
  lea    (%rsi,%rcx,1),%rax
  cmp    %r8d,%edi
  jle    L8
  jmp    L0
L20:
  mov    $0x0,%edx
  mov    %edx,%eax
  ret
L6:
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sumsm(int matrix[][100], int sc, int sr, int lc, int lr) {
  int i, j, sum = 0;
  for (i = sc; i <= lc; i++) {
    for (j = sr; j <= lr; j++)
      sum += matrix[i][j];
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumsm>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%edi
  mov    %ecx,%eax
  mov    %edx,%esi
  cmp    %ecx,%edi
  jg     L24
  movslq %edi,%r11
  sub    %edi,%eax
  mov    %r8d,%ecx
  movslq %edx,%r10
  sub    %edx,%ecx
  add    %r11,%rax
  lea    (%r11,%r11,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rax,4),%rax
  add    %rcx,%r10
  not    %rcx
  shl    $0x4,%rdx
  lea    (%rax,%rax,4),%rax
  shl    $0x2,%rcx
  add    %r9,%rdx
  lea    (%r10,%rax,4),%rax
  lea    0x194(%r9,%rax,4),%rdi
  lea    0x4(%rdx,%r10,4),%rdx
  xor    %r9d,%r9d
  cs nopw 0x0(%rax,%rax,1)
L30:
  lea    (%rcx,%rdx,1),%rax
  cmp    %r8d,%esi
  jg     L5
  nopl   0x0(%rax)
L26:
  add    (%rax),%r9d
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L26
L5:
  add    $0x190,%rdx
  cmp    %rdi,%rdx
  jne    L30
  mov    %r9d,%eax
  ret
L24:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int sumsm(int matrix[][100], int sc, int sr, int lc, int lr) {
  int i, j, sum = 0;
  for (i = sc; i <= lc; i++) {
    for (j = sr; j <= lr; j++)
      sum += matrix[i][j];
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sumsm>:
  endbr64
  cmp    %ecx,%esi
  jg     L55
  mov    %esi,%eax
  mov    %edx,%r10d
  movslq %esi,%rdx
  push   %r15
  sub    %eax,%ecx
  push   %r14
  mov    %rdi,%r9
  movslq %r10d,%rdi
  lea    (%rcx,%rdx,1),%rax
  push   %r13
  lea    (%rdx,%rdx,4),%rsi
  push   %r12
  lea    (%rax,%rax,4),%rax
  lea    (%rsi,%rsi,4),%rsi
  push   %rbp
  mov    %r8d,%ebp
  lea    (%rax,%rax,4),%rax
  lea    (%rdi,%rsi,4),%rsi
  sub    %r10d,%ebp
  lea    (%rdi,%rax,4),%rax
  neg    %rdi
  push   %rbx
  lea    0x1(%rbp),%r12d
  lea    0x190(%r9,%rax,4),%r13
  shl    $0x2,%rdi
  mov    %r12d,%eax
  mov    %r12d,%r14d
  lea    (%r9,%rsi,4),%rsi
  shr    $0x2,%eax
  and    $0xfffffffc,%r14d
  sub    $0x1,%eax
  lea    (%r10,%r14,1),%r11d
  cmp    $0x2,%ebp
  cmovbe %r10d,%r11d
  xor    %r9d,%r9d
  lea    0x1(%r11),%r15d
  lea    0x2(%r11),%ebx
  movslq %r11d,%r11
  movslq %r15d,%rcx
  mov    %ebx,-0x1c(%rsp)
  movslq %ebx,%rbx
  mov    %rcx,-0x18(%rsp)
  mov    %rbx,-0x10(%rsp)
  lea    0x1(%rax),%rbx
  shl    $0x4,%rbx
  nopl   0x0(%rax)
L19:
  cmp    %r8d,%r10d
  jg     L76
  lea    (%rsi,%rdi,1),%rcx
  cmp    $0x2,%ebp
  jbe    L43
  lea    (%rbx,%rsi,1),%rdx
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L39:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L39
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%r9d
  cmp    %r14d,%r12d
  je     L76
L43:
  add    (%rcx,%r11,4),%r9d
  cmp    %r15d,%r8d
  jl     L76
  mov    -0x18(%rsp),%rax
  add    (%rcx,%rax,4),%r9d
  cmp    -0x1c(%rsp),%r8d
  jl     L76
  mov    -0x10(%rsp),%rax
  add    (%rcx,%rax,4),%r9d
L76:
  add    $0x190,%rsi
  cmp    %r13,%rsi
  jne    L19
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumsm(int matrix[][100], int sc, int sr, int lc, int lr) {
  int i, j, sum = 0;
  for (i = sc; i <= lc; i++) {
    for (j = sr; j <= lr; j++)
      sum += matrix[i][j];
  }
  return sum;
}
```