ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test_cut>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0x11,0x18(%rsp)
  movl   $0x11,0x1c(%rsp)
  movl   $0x14,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x9,%esi
  call   <cut_rec@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x16,%edx
  je     L14
L11:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x38,%rsp
  ret
L14:
  mov    %rsp,%rdi
  mov    $0x8,%edx
  mov    $0x9,%esi
  call   <cut_dyn@plt>
  cmp    $0x16,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L11
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_cut() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  return 22 == cut_rec(prices, 9, 8) && 22 == cut_dyn(prices, 9, 8);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_cut>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    $0x9,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%rbp
  movl   $0x14,0x20(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x800000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1100000011,%rax
  mov    %rax,0x18(%rsp)
  call   <cut_rec@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x16,%r8d
  je     L27
L3:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x30,%rsp
  pop    %rbp
  ret
L27:
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <cut_dyn@plt>
  cmp    $0x16,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_cut() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  return 22 == cut_rec(prices, 9, 8) && 22 == cut_dyn(prices, 9, 8);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_cut>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    $0x9,%esi
  sub    $0x30,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x14,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D15(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  call   <cut_rec@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x16,%r8d
  je     L16
L4:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbp
  ret
L16:
  mov    $0x8,%edx
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <cut_dyn@plt>
  cmp    $0x16,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L4
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: byte[16]
name: retrieve_data
arguments: label: D15
data_type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D15": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

assistant: ```c
int test_cut() {
  int prices[] = {0, 1, 5, 8, 9, 10, 17, 17, 20};
  return 22 == cut_rec(prices, 9, 8) && 22 == cut_dyn(prices, 9, 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<msg_blank_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <msgBlank@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void msg_blank_(int *const STATUS) {
  int status;
  status = *STATUS;
  msgBlank(&status);
  *STATUS = status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msg_blank_>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <msgBlank@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_blank_(int *const STATUS) {
  int status;
  status = *STATUS;
  msgBlank(&status);
  *STATUS = status;
}
```
user: What is the c source code of the assembly code below?

```asm
<msg_blank_>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <msgBlank@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_blank_(int *const STATUS) {
  int status;
  status = *STATUS;
  msgBlank(&status);
  *STATUS = status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<msg_blank_>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <msgBlank@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msg_blank_(int *const STATUS) {
  int status;
  status = *STATUS;
  msgBlank(&status);
  *STATUS = status;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<no_check_for_null_after_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x2a,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void no_check_for_null_after_malloc() {
  int *p;
  p = (int *)malloc(sizeof(int));
  *p = 42;
  free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<no_check_for_null_after_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movl   $0x2a,(%rax)
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void no_check_for_null_after_malloc() {
  int *p;
  p = (int *)malloc(sizeof(int));
  *p = 42;
  free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<no_check_for_null_after_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x2a,(%rax)
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

assistant: ```c
void no_check_for_null_after_malloc() {
  int *p;
  p = (int *)malloc(sizeof(int));
  *p = 42;
  free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<no_check_for_null_after_malloc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x2a,(%rax)
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1060 <free@plt>
```

assistant: ```c
void no_check_for_null_after_malloc() {
  int *p;
  p = (int *)malloc(sizeof(int));
  *p = 42;
  free(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x19(%rbp)
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  nop
  mov    $0xffffffff,%eax
  jmp    L36
L17:
  mov    -0x10(%rbp),%rdx
  lea    -0x19(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
L12:
  mov    -0x18(%rbp),%rdx
  lea    -0x19(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D46
type: string
name: read_data
arguments: data_label: D44
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D18
type: string
name: read_data
arguments: data_label: D35
type: string

tool: D46: r

tool: D44: /etc/passwd

tool: D23: rw

tool: D18: /dev/null

tool: D35: fopen

assistant: ```c
int main() {
  char rbuf = 0;
  FILE *pf = fopen("/etc/passwd", "r");
  FILE *pfnull = fopen("/dev/null", "rw");
  if (pf == NULL) {
    perror("fopen");
    goto err;
  }
  while (fread(&rbuf, 1, 1, pf) != 0) {
    fwrite(&rbuf, 1, 1, pfnull);
  }
  fclose(pf);
  return 0;
err:
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    D5(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    D12(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <fopen@plt>
  test   %rbp,%rbp
  je     L16
  mov    %rax,%r12
  lea    0x7(%rsp),%rbx
  jmp    L6
L16:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L22
L5:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L6:
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D1
type_infered: string

tool: D5: r

tool: D27: /etc/passwd

tool: D12: rw

tool: D14: /dev/null

tool: D1: fopen

assistant: ```c
int main() {
  char rbuf = 0;
  FILE *pf = fopen("/etc/passwd", "r");
  FILE *pfnull = fopen("/dev/null", "rw");
  if (pf == NULL) {
    perror("fopen");
    goto err;
  }
  while (fread(&rbuf, 1, 1, pf) != 0) {
    fwrite(&rbuf, 1, 1, pfnull);
  }
  fclose(pf);
  return 0;
err:
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D41(%rip),%rsi
  lea    D3(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <fopen@plt>
  lea    D45(%rip),%rsi
  lea    D36(%rip),%rdi
  mov    %rax,%rbp
  call   <fopen@plt>
  test   %rbp,%rbp
  je     L1
  mov    %rax,%r12
  lea    0x7(%rsp),%rbx
  jmp    L42
  nopl   0x0(%rax)
L18:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L42:
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D14(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%eax
  jmp    L23
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D41
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D45
datatype: string
name: read_data
arguments: tag: D36
datatype: string
name: read_data
arguments: tag: D14
datatype: string

tool: D41: r

tool: D3: /etc/passwd

tool: D45: rw

tool: D36: /dev/null

tool: D14: fopen

assistant: ```c
int main() {
  char rbuf = 0;
  FILE *pf = fopen("/etc/passwd", "r");
  FILE *pfnull = fopen("/dev/null", "rw");
  if (pf == NULL) {
    perror("fopen");
    goto err;
  }
  while (fread(&rbuf, 1, 1, pf) != 0) {
    fwrite(&rbuf, 1, 1, pfnull);
  }
  fclose(pf);
  return 0;
err:
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  lea    D0(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  call   <fopen@plt>
  lea    D30(%rip),%rsi
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  call   <fopen@plt>
  test   %rbp,%rbp
  je     L21
  mov    %rax,%r12
  lea    0x7(%rsp),%rbx
  jmp    L40
  nopl   0x0(%rax)
L31:
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L40:
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jne    L31
  mov    %rbp,%rdi
  call   <fclose@plt>
  xor    %eax,%eax
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  lea    D43(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%eax
  jmp    L46
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D30
type: string
name: unpack_data
arguments: label: D5
type: string
name: unpack_data
arguments: label: D43
type: string

tool: D7: r

tool: D0: /etc/passwd

tool: D30: rw

tool: D5: /dev/null

tool: D43: fopen

assistant: ```c
int main() {
  char rbuf = 0;
  FILE *pf = fopen("/etc/passwd", "r");
  FILE *pfnull = fopen("/dev/null", "rw");
  if (pf == NULL) {
    perror("fopen");
    goto err;
  }
  while (fread(&rbuf, 1, 1, pf) != 0) {
    fwrite(&rbuf, 1, 1, pfnull);
  }
  fclose(pf);
  return 0;
err:
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setVec3f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm2,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void setVec3f(float *out, float x, float y, float z) {
  out[0] = x;
  out[1] = y;
  out[2] = z;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setVec3f>:
  endbr64
  movss  %xmm0,(%rdi)
  movss  %xmm1,0x4(%rdi)
  movss  %xmm2,0x8(%rdi)
  ret
```

assistant: ```c
void setVec3f(float *out, float x, float y, float z) {
  out[0] = x;
  out[1] = y;
  out[2] = z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setVec3f>:
  endbr64
  movss  %xmm0,(%rdi)
  movss  %xmm1,0x4(%rdi)
  movss  %xmm2,0x8(%rdi)
  ret
```

assistant: ```c
void setVec3f(float *out, float x, float y, float z) {
  out[0] = x;
  out[1] = y;
  out[2] = z;
}
```
user: What is the c source code of the assembly code below?

```asm
<setVec3f>:
  endbr64
  unpcklps %xmm1,%xmm0
  movss  %xmm2,0x8(%rdi)
  movlps %xmm0,(%rdi)
  ret
```

assistant: ```c
void setVec3f(float *out, float x, float y, float z) {
  out[0] = x;
  out[1] = y;
  out[2] = z;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  mov    $0x0,%edi
  call   <eon@plt>
  mov    $0x1,%edi
  call   <_static@plt>
  mov    $0x1,%edi
  call   <on@plt>
  mov    $0x96,%edi
  call   <dim@plt>
  jmp    L19
L12:
  mov    $0x0,%edi
  call   <dim@plt>
  mov    $0x1,%edi
  call   <eon@plt>
  mov    $0x0,%edi
  call   <_static@plt>
  mov    $0x0,%edi
  call   <on@plt>
L19:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int power(int i) {
  if (i) {
    eon(0);
    _static(1);
    on(1);
    dim(150);
  } else {
    dim(0);
    eon(1);
    _static(0);
    on(0);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L17
  mov    $0x0,%edi
  call   <eon@plt>
  mov    $0x1,%edi
  call   <_static@plt>
  mov    $0x1,%edi
  call   <on@plt>
  mov    $0x96,%edi
  call   <dim@plt>
L3:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L17:
  mov    $0x0,%edi
  call   <dim@plt>
  mov    $0x1,%edi
  call   <eon@plt>
  mov    $0x0,%edi
  call   <_static@plt>
  mov    $0x0,%edi
  call   <on@plt>
  jmp    L3
```

assistant: ```c
int power(int i) {
  if (i) {
    eon(0);
    _static(1);
    on(1);
    dim(150);
  } else {
    dim(0);
    eon(1);
    _static(0);
    on(0);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<power>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  mov    $0x0,%edi
  je     L6
  call   <eon@plt>
  mov    $0x1,%edi
  call   <_static@plt>
  mov    $0x1,%edi
  call   <on@plt>
  mov    $0x96,%edi
  call   <dim@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  call   <dim@plt>
  mov    $0x1,%edi
  call   <eon@plt>
  xor    %edi,%edi
  call   <_static@plt>
  xor    %edi,%edi
  call   <on@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int power(int i) {
  if (i) {
    eon(0);
    _static(1);
    on(1);
    dim(150);
  } else {
    dim(0);
    eon(1);
    _static(0);
    on(0);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<power>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  mov    $0x0,%edi
  je     L6
  call   <eon@plt>
  mov    $0x1,%edi
  call   <_static@plt>
  mov    $0x1,%edi
  call   <on@plt>
  mov    $0x96,%edi
  call   <dim@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  call   <dim@plt>
  mov    $0x1,%edi
  call   <eon@plt>
  xor    %edi,%edi
  call   <_static@plt>
  xor    %edi,%edi
  call   <on@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int power(int i) {
  if (i) {
    eon(0);
    _static(1);
    on(1);
    dim(150);
  } else {
    dim(0);
    eon(1);
    _static(0);
    on(0);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f5(volatile int *a) {
  int b = a[3];
  int c = a[2];
  return b + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f5>:
  endbr64
  mov    0xc(%rdi),%eax
  mov    0x8(%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int f5(volatile int *a) {
  int b = a[3];
  int c = a[2];
  return b + c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f5>:
  endbr64
  mov    0xc(%rdi),%eax
  mov    0x8(%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int f5(volatile int *a) {
  int b = a[3];
  int c = a[2];
  return b + c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f5>:
  endbr64
  mov    0xc(%rdi),%eax
  mov    0x8(%rdi),%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int f5(volatile int *a) {
  int b = a[3];
  int c = a[2];
  return b + c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L7
L24:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L10
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L31
L10:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L31:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L7:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L24
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  int *x_ref = alloca(sizeof(int));
  int *y_ref = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *x_ref = x;
  *y_ref = y;
  *c = 0;
  while (!(*x_ref == *y_ref)) {
    if (*x_ref > *y_ref) {
      *y_ref = *y_ref + 1;
    } else {
      *x_ref = *x_ref + 1;
    }
    *c = *c + 1;
  }
  return *c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <alloca@plt>
  mov    %r14d,(%r12)
  mov    %r13d,(%rbx)
  movl   $0x0,(%rax)
  mov    (%r12),%ecx
  mov    (%rbx),%edx
  cmp    %edx,%ecx
  jne    L14
L20:
  mov    (%rax),%eax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L36:
  add    $0x1,%ecx
  mov    %ecx,(%r12)
L18:
  addl   $0x1,(%rax)
  mov    (%r12),%ecx
  mov    (%rbx),%edx
  cmp    %edx,%ecx
  je     L20
L14:
  cmp    %edx,%ecx
  jle    L36
  add    $0x1,%edx
  mov    %edx,(%rbx)
  jmp    L18
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_fun(int x, int y) {
  int *x_ref = alloca(sizeof(int));
  int *y_ref = alloca(sizeof(int));
  int *c = alloca(sizeof(int));
  *x_ref = x;
  *y_ref = y;
  *c = 0;
  while (!(*x_ref == *y_ref)) {
    if (*x_ref > *y_ref) {
      *y_ref = *y_ref + 1;
    } else {
      *x_ref = *x_ref + 1;
    }
    *c = *c + 1;
  }
  return *c;
}
```