ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  movl   $0x2,0xc(%rax)
  cmpl   $0x2,0x10(%rax)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *r = malloc(5 * sizeof(int));
  r[3] = 2;
  assert(r[4] == 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  movl   $0x2,0xc(%rax)
  cmpl   $0x2,0x10(%rax)
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *r = malloc(5 * sizeof(int));
  r[3] = 2;
  assert(r[4] == 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x14,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  movl   $0x2,0xc(%rax)
  cmpl   $0x2,0x10(%rax)
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int *r = malloc(5 * sizeof(int));
  r[3] = 2;
  assert(r[4] == 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call2c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x8(%rbp)
  movapd %xmm1,%xmm0
  mov    %rdx,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    %ecx,%edx
  movapd %xmm3,%xmm1
  mov    %ax,-0x4(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movb   $0x61,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x30(%rbp)
  movw   $0x5,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x6,-0x8(%rbp)
  movss  D15(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movq   $0x7,-0x20(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type_infered: f32
name: retrieve_data
arguments: tag: D1
type_infered: f64

tool: D15: 0.1

tool: D1: 0.2

assistant: ```c
call2c(s, d1, i, f2, l, d2, c, f1) short s;
double d1;
int i;
float f2;
long l;
double d2;
char c;
float f1;
{
  c = 'a';
  f1 = 0.0;
  s = 5;
  d1 = 0.0;
  i = 6;
  f2 = 0.1;
  l = 7;
  d2 = 0.2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<call2c>:
  endbr64
  ret
```

assistant: ```c
call2c(s, d1, i, f2, l, d2, c, f1) short s;
double d1;
int i;
float f2;
long l;
double d2;
char c;
float f1;
{
  c = 'a';
  f1 = 0.0;
  s = 5;
  d1 = 0.0;
  i = 6;
  f2 = 0.1;
  l = 7;
  d2 = 0.2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<call2c>:
  endbr64
  ret
```

assistant: ```c
call2c(s, d1, i, f2, l, d2, c, f1) short s;
double d1;
int i;
float f2;
long l;
double d2;
char c;
float f1;
{
  c = 'a';
  f1 = 0.0;
  s = 5;
  d1 = 0.0;
  i = 6;
  f2 = 0.1;
  l = 7;
  d2 = 0.2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<call2c>:
  endbr64
  ret
```

assistant: ```c
call2c(s, d1, i, f2, l, d2, c, f1) short s;
double d1;
int i;
float f2;
long l;
double d2;
char c;
float f1;
{
  c = 'a';
  f1 = 0.0;
  s = 5;
  d1 = 0.0;
  i = 6;
  f2 = 0.1;
  l = 7;
  d2 = 0.2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isProbablySC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0xfff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xc,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L55:
  mov    -0x14(%rbp),%eax
  shl    $0xc,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L44
L15:
  mov    -0x14(%rbp),%eax
  shl    $0xc,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  je     L42
  mov    $0x0,%eax
  jmp    L26
L42:
  addl   $0x1,-0x10(%rbp)
L44:
  cmpl   $0xff,-0x10(%rbp)
  jle    L15
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L55
  mov    $0x1,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int isProbablySC(const uint8_t *image, uint32_t size) {
  uint32_t i, j;
  uint32_t banks = size / 4096;
  for (i = 0; i < banks; ++i) {
    uint8_t first = image[i * 4096];
    for (j = 0; j < 256; ++j) {
      if (image[i * 4096 + j] != first)
        return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<isProbablySC>:
  endbr64
  lea    0xfff(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0xc,%eax
  mov    %eax,%r8d
  cmp    $0xfff,%esi
  jle    L30
  lea    0x7f8(%rdi),%rdx
  mov    $0x0,%esi
L6:
  mov    -0x7f8(%rdx),%rcx
  lea    -0x7f8(%rdx),%rax
L38:
  cmp    %rdx,%rax
  je     L39
  add    $0x8,%rax
  cmp    %rcx,(%rax)
  je     L38
  mov    $0x0,%eax
  ret
L39:
  add    $0x1,%esi
  add    $0x8000,%rdx
  cmp    %esi,%r8d
  jg     L6
  mov    $0x1,%eax
  ret
L30:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isProbablySC(const uint8_t *image, uint32_t size) {
  uint32_t i, j;
  uint32_t banks = size / 4096;
  for (i = 0; i < banks; ++i) {
    uint8_t first = image[i * 4096];
    for (j = 0; j < 256; ++j) {
      if (image[i * 4096 + j] != first)
        return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isProbablySC>:
  endbr64
  test   %esi,%esi
  lea    0xfff(%rsi),%eax
  cmovns %esi,%eax
  sar    $0xc,%eax
  mov    %eax,%r8d
  cmp    $0xfff,%esi
  jle    L8
  lea    0x7f8(%rdi),%rdx
  xor    %esi,%esi
L16:
  mov    -0x7f8(%rdx),%rcx
  lea    -0x7f8(%rdx),%rax
  nopl   0x0(%rax)
L15:
  cmp    %rax,%rdx
  je     L25
  add    $0x8,%rax
  cmp    %rcx,(%rax)
  je     L15
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L25:
  add    $0x1,%esi
  add    $0x8000,%rdx
  cmp    %esi,%r8d
  jg     L16
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isProbablySC(const uint8_t *image, uint32_t size) {
  uint32_t i, j;
  uint32_t banks = size / 4096;
  for (i = 0; i < banks; ++i) {
    uint8_t first = image[i * 4096];
    for (j = 0; j < 256; ++j) {
      if (image[i * 4096 + j] != first)
        return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isProbablySC>:
  endbr64
  test   %esi,%esi
  lea    0xfff(%rsi),%eax
  cmovns %esi,%eax
  sar    $0xc,%eax
  mov    %eax,%r8d
  cmp    $0xfff,%esi
  jle    L29
  lea    0x7f8(%rdi),%rdx
  xor    %esi,%esi
L6:
  mov    -0x7f8(%rdx),%rcx
  lea    -0x7f8(%rdx),%rax
  nopl   0x0(%rax)
L26:
  cmp    %rax,%rdx
  je     L2
  add    $0x8,%rax
  cmp    %rcx,(%rax)
  je     L26
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  add    $0x1,%esi
  add    $0x8000,%rdx
  cmp    %esi,%r8d
  jg     L6
L29:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isProbablySC(const uint8_t *image, uint32_t size) {
  uint32_t i, j;
  uint32_t banks = size / 4096;
  for (i = 0; i < banks; ++i) {
    uint8_t first = image[i * 4096];
    for (j = 0; j < 256; ++j) {
      if (image[i * 4096 + j] != first)
        return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_ds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x8000,%eax
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  and    $0xfffc,%eax
  sub    $0x10000,%rax
  jmp    L1
L5:
  mov    -0x8(%rbp),%rax
  and    $0xfffc,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
long extract_ds(unsigned long insn, int *invalid) {
  if ((insn & 0x8000) != 0)
    return (insn & 0xfffc) - 0x10000;
  else
    return insn & 0xfffc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extract_ds>:
  endbr64
  mov    %rdi,%rdx
  and    $0xfffc,%edx
  sub    $0x10000,%rdx
  mov    %rdi,%rax
  and    $0xfffc,%eax
  test   $0x8000,%edi
  cmovne %rdx,%rax
  ret
```

assistant: ```c
long extract_ds(unsigned long insn, int *invalid) {
  if ((insn & 0x8000) != 0)
    return (insn & 0xfffc) - 0x10000;
  else
    return insn & 0xfffc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<extract_ds>:
  endbr64
  mov    %rdi,%rax
  and    $0xfffc,%eax
  test   $0x8000,%edi
  lea    -0x10000(%rax),%rdx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
long extract_ds(unsigned long insn, int *invalid) {
  if ((insn & 0x8000) != 0)
    return (insn & 0xfffc) - 0x10000;
  else
    return insn & 0xfffc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<extract_ds>:
  endbr64
  mov    %rdi,%rax
  and    $0xfffc,%eax
  test   $0x8000,%edi
  lea    -0x10000(%rax),%rdx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
long extract_ds(unsigned long insn, int *invalid) {
  if ((insn & 0x8000) != 0)
    return (insn & 0xfffc) - 0x10000;
  else
    return insn & 0xfffc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<plugin_script_build_function_and_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L10
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L99
L10:
  mov    $0x0,%eax
  jmp    L94
L99:
  cmpq   $0x0,-0x28(%rbp)
  je     L18
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L4
L18:
  mov    $0x0,%eax
L4:
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L116
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L38
L116:
  mov    $0x0,%eax
L38:
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L74
  mov    $0x0,%eax
  jmp    L94
L74:
  cmpq   $0x0,-0x28(%rbp)
  je     L69
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L70
L69:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L70:
  cmpq   $0x0,-0x30(%rbp)
  je     L67
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L92
L67:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L92:
  mov    -0x8(%rbp),%rax
L94:
  leave
  ret
```

assistant: ```c
char *plugin_script_build_function_and_data(const char *function, const char *data) {
  int length_function, length_data, length;
  char *result;
  if (!function || !function[0])
    return NULL;
  length_function = (function) ? strlen(function) : 0;
  length_data = (data) ? strlen(data) : 0;
  length = length_function + 1 + length_data + 1;
  result = malloc(length);
  if (!result)
    return NULL;
  if (function)
    memcpy(result, function, length_function + 1);
  else
    result[0] = '\0';
  if (data)
    memcpy(result + length_function + 1, data, length_data + 1);
  else
    result[length_function + 1] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plugin_script_build_function_and_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L49
  mov    %rsi,%r14
  mov    $0x0,%ebp
  cmpb   $0x0,(%rdi)
  je     L22
  call   <strlen@plt>
  mov    %eax,%r12d
  test   %r14,%r14
  je     L54
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x1(%r12),%r15d
  lea    0x2(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
  mov    %r15d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r13),%edx
  movslq %r12d,%r12
  lea    0x1(%rbp,%r12,1),%rdi
  mov    %r14,%rsi
  call   <memcpy@plt>
L22:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    %rdi,%rbp
  jmp    L22
L54:
  lea    0x1(%rax),%r13d
  lea    0x2(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L22
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  movb   $0x0,0x1(%rbp,%r12,1)
  jmp    L22
```

assistant: ```c
char *plugin_script_build_function_and_data(const char *function, const char *data) {
  int length_function, length_data, length;
  char *result;
  if (!function || !function[0])
    return NULL;
  length_function = (function) ? strlen(function) : 0;
  length_data = (data) ? strlen(data) : 0;
  length = length_function + 1 + length_data + 1;
  result = malloc(length);
  if (!result)
    return NULL;
  if (function)
    memcpy(result, function, length_function + 1);
  else
    result[0] = '\0';
  if (data)
    memcpy(result + length_function + 1, data, length_data + 1);
  else
    result[length_function + 1] = '\0';
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<plugin_script_build_function_and_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L61
  xor    %r12d,%r12d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L24
  mov    %rsi,%r13
  call   <strlen@plt>
  movslq %eax,%rbx
  test   %r13,%r13
  je     L26
  mov    %r13,%rdi
  lea    0x1(%rbx),%r15d
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r14),%edx
  lea    0x1(%r12,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  lea    0x2(%rbx),%edi
  lea    0x1(%rbx),%r13d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L24
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L61:
  xor    %r12d,%r12d
  jmp    L24
```

assistant: ```c
char *plugin_script_build_function_and_data(const char *function, const char *data) {
  int length_function, length_data, length;
  char *result;
  if (!function || !function[0])
    return NULL;
  length_function = (function) ? strlen(function) : 0;
  length_data = (data) ? strlen(data) : 0;
  length = length_function + 1 + length_data + 1;
  result = malloc(length);
  if (!result)
    return NULL;
  if (function)
    memcpy(result, function, length_function + 1);
  else
    result[0] = '\0';
  if (data)
    memcpy(result + length_function + 1, data, length_data + 1);
  else
    result[length_function + 1] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plugin_script_build_function_and_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L24
  xor    %r12d,%r12d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbp
  je     L4
  mov    %rsi,%r13
  call   <strlen@plt>
  movslq %eax,%rbx
  test   %r13,%r13
  je     L32
  mov    %r13,%rdi
  lea    0x1(%rbx),%r15d
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x1(%r14),%edx
  lea    0x1(%r12,%rbx,1),%rdi
  mov    %r13,%rsi
  call   <memcpy@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  lea    0x2(%rbx),%edi
  lea    0x1(%rbx),%r13d
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %r12d,%r12d
  jmp    L4
```

assistant: ```c
char *plugin_script_build_function_and_data(const char *function, const char *data) {
  int length_function, length_data, length;
  char *result;
  if (!function || !function[0])
    return NULL;
  length_function = (function) ? strlen(function) : 0;
  length_data = (data) ? strlen(data) : 0;
  length = length_function + 1 + length_data + 1;
  result = malloc(length);
  if (!result)
    return NULL;
  if (function)
    memcpy(result, function, length_function + 1);
  else
    result[0] = '\0';
  if (data)
    memcpy(result + length_function + 1, data, length_data + 1);
  else
    result[length_function + 1] = '\0';
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L25
L24:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L24
L18:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *skip_string(char *c) {
  while (*c && (*c != '"'))
    c++;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_string>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L34
  cmp    $0x22,%dl
  je     L34
L28:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L34
  cmp    $0x22,%dl
  jne    L28
L34:
  ret
```

assistant: ```c
char *skip_string(char *c) {
  while (*c && (*c != '"'))
    c++;
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L17
  jmp    L14
L11:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L14
L17:
  cmp    $0x22,%dl
  jne    L11
L14:
  ret
```

assistant: ```c
char *skip_string(char *c) {
  while (*c && (*c != '"'))
    c++;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skip_string>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L34
  jmp    L2
L23:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L2
L34:
  cmp    $0x22,%dl
  jne    L23
L2:
  ret
```

assistant: ```c
char *skip_string(char *c) {
  while (*c && (*c != '"'))
    c++;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffff0000,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x11,-0x34(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0x54,-0x2c(%rbp)
  movl   $0x13,-0x28(%rbp)
  movl   $0x6,-0x24(%rbp)
  movl   $0x16,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x23,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <heap_sort@plt>
  movl   $0x1,-0x44(%rbp)
  jmp    L8
L0:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L8:
  cmpl   $0xa,-0x44(%rbp)
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int i;
  int datas[11] = {-65536, 5, 3, 17, 10, 84, 19, 6, 22, 9, 35};
  heap_sort(datas, 10);
  for (i = 1; i < 11; ++i)
    printf("%d", datas[i]);
  printf("\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xffff0000,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x11,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x54,0x14(%rsp)
  movl   $0x13,0x18(%rsp)
  movl   $0x6,0x1c(%rsp)
  movl   $0x16,0x20(%rsp)
  movl   $0x9,0x24(%rsp)
  movl   $0x23,0x28(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <heap_sort@plt>
  lea    0x4(%rsp),%rbx
  lea    0x2c(%rsp),%r12
  lea    D2(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  int i;
  int datas[11] = {-65536, 5, 3, 17, 10, 84, 19, 6, 22, 9, 35};
  heap_sort(datas, 10);
  for (i = 1; i < 11; ++i)
    printf("%d", datas[i]);
  printf("\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x5ffff0000,%rax
  mov    %rsp,%rdi
  lea    0x4(%rsp),%rbx
  lea    0x2c(%rsp),%r12
  movl   $0x23,0x28(%rsp)
  mov    %rax,(%rsp)
  movabs $0x1100000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x540000000a,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x600000013,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000016,%rax
  mov    %rax,0x20(%rsp)
  call   <heap_sort@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: %d

assistant: ```c
int main() {
  int i;
  int datas[11] = {-65536, 5, 3, 17, 10, 84, 19, 6, 22, 9, 35};
  heap_sort(datas, 10);
  for (i = 1; i < 11; ++i)
    printf("%d", datas[i]);
  printf("\n");
  exit(0);
}
```