user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  movsd  D46(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x3dcccccd,0x24(%rsp)
  lea    0x40(%rsp),%rdi
  movabs $0x3e99999a3e4ccccd,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x3f0000003ecccccd,%rax
  mov    %rax,0x30(%rsp)
  mov    $0x1,%eax
  nopl   (%rax)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm2,%xmm0
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L5
  lea    0x20(%rsp),%rbp
  mov    %rsp,%rbx
  mov    $0x5,%ecx
  xor    %eax,%eax
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    $0x1,%r12d
  call   <toeplz@plt>
  lea    D33(%rip),%rdi
  lea    D6(%rip),%r15
  call   <puts@plt>
  lea    D4(%rip),%r14
  lea    D20(%rip),%r13
L27:
  pxor   %xmm0,%xmm0
  mov    %r12d,%edx
  mov    %r15,%rcx
  mov    %r14,%rsi
  cvtss2sd (%rbx,%r12,4),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    $0x6,%r12
  jne    L27
  lea    0x54(%rsp),%r15
  lea    D17(%rip),%rdi
  mov    $0x1,%r14d
  call   <puts@plt>
  lea    D42(%rip),%rdx
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  lea    D14(%rip),%r12
  call   <printf@plt>
  lea    0x14(%rsp),%r13
L17:
  mov    %rbx,%rax
  mov    %r15,%rdx
  pxor   %xmm0,%xmm0
L20:
  movss  (%rdx),%xmm1
  mulss  0x4(%rax),%xmm1
  add    $0x4,%rax
  sub    $0x4,%rdx
  addss  %xmm1,%xmm0
  cmp    %rax,%r13
  jne    L20
  pxor   %xmm1,%xmm1
  mov    %r12,%rdi
  cvtss2sd %xmm0,%xmm0
  add    $0x4,%r15
  cvtss2sd 0x0(%rbp,%r14,4),%xmm1
  mov    $0x2,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    $0x6,%r14
  jne    L17
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D46
type: f64
name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D20
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D46: 1

tool: D33: Solution vector:

tool: D6: ] =

tool: D4: x[

tool: D20: %7s%1d%s %13f


tool: D17: 
Test of solution:

tool: D42: original

tool: D8: mtrx*soln

tool: D34: %13s %12s


tool: D14: %12.4f %12.4f


assistant: ```c
int main(void) {
  int i, j;
  float sum, r[(2 * 5) + 1], x[5 + 1], y[5 + 1];
  for (i = 1; i <= 5; i++)
    y[i] = 0.1 * i;
  for (i = 1; i < (2 * 5); i++)
    r[i] = 1.0 / i;
  toeplz(r, x, y, 5);
  printf("Solution vector:\n");
  for (i = 1; i <= 5; i++)
    printf("%7s%1d%s %13f\n", "x[", i, "] =", x[i]);
  printf("\nTest of solution:\n");
  printf("%13s %12s\n", "mtrx*soln", "original");
  for (i = 1; i <= 5; i++) {
    sum = 0.0;
    for (j = 1; j <= 5; j++)
      sum += (r[5 + i - j] * x[j]);
    printf("%12.4f %12.4f\n", sum, y[i]);
  }
  return 0;
}
```