ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<uart_init_boot_phase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa0210320,%eax
  movl   $0x100000,(%rax)
  mov    $0xa00c0058,%eax
  movl   $0x16c,(%rax)
  mov    $0xa00c0008,%eax
  movl   $0x1,(%rax)
  mov    $0xa00c0014,%eax
  movl   $0x901,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_init_boot_phase(void) {
  *(volatile uint32_t *)0xA0210320 = 0x100000;
  *(volatile uint32_t *)0xA00C0058 = 0x016C;
  *(volatile uint32_t *)0xA00C0008 = 0x0001;
  *(volatile uint32_t *)0xA00C0014 = 0x901;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_init_boot_phase>:
  endbr64
  mov    $0xa0210320,%eax
  movl   $0x100000,(%rax)
  lea    -0x1502c8(%rax),%rax
  movl   $0x16c,(%rax)
  lea    -0x50(%rax),%rax
  movl   $0x1,(%rax)
  lea    0xc(%rax),%rax
  movl   $0x901,(%rax)
  ret
```

assistant: ```c
void uart_init_boot_phase(void) {
  *(volatile uint32_t *)0xA0210320 = 0x100000;
  *(volatile uint32_t *)0xA00C0058 = 0x016C;
  *(volatile uint32_t *)0xA00C0008 = 0x0001;
  *(volatile uint32_t *)0xA00C0014 = 0x901;
}
```
user: What is the c source code of the assembly code below:

```asm
<uart_init_boot_phase>:
  endbr64
  mov    $0xa0210320,%eax
  movl   $0x100000,(%rax)
  movl   $0x16c,-0x1502c8(%rax)
  movl   $0x1,-0x150318(%rax)
  movl   $0x901,-0x15030c(%rax)
  ret
```

assistant: ```c
void uart_init_boot_phase(void) {
  *(volatile uint32_t *)0xA0210320 = 0x100000;
  *(volatile uint32_t *)0xA00C0058 = 0x016C;
  *(volatile uint32_t *)0xA00C0008 = 0x0001;
  *(volatile uint32_t *)0xA00C0014 = 0x901;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_init_boot_phase>:
  endbr64
  mov    $0xa0210320,%eax
  movl   $0x100000,(%rax)
  movl   $0x16c,-0x1502c8(%rax)
  movl   $0x1,-0x150318(%rax)
  movl   $0x901,-0x15030c(%rax)
  ret
```

assistant: ```c
void uart_init_boot_phase(void) {
  *(volatile uint32_t *)0xA0210320 = 0x100000;
  *(volatile uint32_t *)0xA00C0058 = 0x016C;
  *(volatile uint32_t *)0xA00C0008 = 0x0001;
  *(volatile uint32_t *)0xA00C0014 = 0x901;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x50(%rbp)
  movl   $0x3,-0x4c(%rbp)
  movl   $0x6,-0x48(%rbp)
  movl   $0x2,-0x44(%rbp)
  movl   $0x7,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x8,-0x54(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x5c(%rbp)
  jmp    L8
L25:
  mov    -0x5c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x5c(%rbp)
L8:
  mov    -0x5c(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L25
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x2,%esi
  mov    $0x4,%edi
  call   <union_sets@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x58(%rbp)
  jmp    L14
L33:
  mov    -0x58(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x58(%rbp)
L14:
  mov    -0x58(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D34
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D0: Parent array before union: 

tool: D34: %d 

tool: D25: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rbp
  lea    D34(%rip),%r13
L22:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rdx
  mov    $0x2,%esi
  mov    $0x4,%edi
  call   <union_sets@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D34(%rip),%rbp
L21:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type: string
name: unpack_data
arguments: label: D34
type: string
name: unpack_data
arguments: label: D33
type: string

tool: D13: Parent array before union: 

tool: D34: %d 

tool: D33: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%r14
  lea    0x20(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000005,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  call   <puts@plt>
L21:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x4,%edi
  mov    %r14,%rdx
  mov    $0x2,%esi
  call   <union_sets@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L0:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type: string
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D3
type: string

tool: D18: Parent array before union: 

tool: D11: %d 

tool: D3: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D40(%rip),%rdi
  push   %r13
  lea    D41(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x20(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D8(%rip),%xmm0
  mov    %r14,%rbx
  mov    %r14,%rbp
  movaps %xmm0,0x10(%rsp)
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x4,%edi
  mov    %r14,%rdx
  mov    $0x2,%esi
  call   <union_sets@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L5:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
type_infered: string
name: unpack_data
arguments: data_label: D41
type_infered: string
name: unpack_data
arguments: data_label: D18
type_infered: byte[16]
name: unpack_data
arguments: data_label: D8
type_infered: byte[16]
name: unpack_data
arguments: data_label: D24
type_infered: string

tool: D40: Parent array before union: 

tool: D41: %d 

tool: {"D18": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D8": [0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: D24: Parent array after union: 

assistant: ```c
int main(int argc, char const *argv[]) {
  int a[] = {1, 3, 6, 2, 7, 5, 0, 4};
  int a_length = sizeof(a) / sizeof(a[0]);
  int parent_array[] = {1, 1, 1, 2, 5, 5, 5, 5};
  printf("%s\n", "Parent array before union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  union_sets(4, 2, parent_array);
  printf("%s\n", "Parent array after union: ");
  for (int i = 0; i < a_length; i++) {
    printf("%d ", parent_array[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_both>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L46:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L35
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L44
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L46
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_both(int row_ones[], int pos[], int count) {
  int i, j;
  for (i = 0; i < count; i++) {
    int temp = row_ones[i];
    int p = i;
    for (j = i + 1; j < count; j++) {
      if (temp < row_ones[j]) {
        temp = row_ones[j];
        p = j;
      }
    }
    temp = row_ones[i];
    row_ones[i] = row_ones[p];
    row_ones[p] = temp;
    temp = pos[i];
    pos[i] = pos[p];
    pos[p] = temp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_both>:
  endbr64
  test   %edx,%edx
  jle    L25
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %edx,%r8d
  lea    -0x1(%rdx),%r12d
  mov    %r12d,%ebp
  mov    $0x0,%r9d
  jmp    L2
L37:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jle    L59
L60:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L37
  mov    %eax,%esi
  mov    %edx,%ecx
  jmp    L37
L11:
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%rdx
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi,%rbp,4)
  mov    %r11d,(%rdx)
  lea    (%r10,%rbp,4),%rdx
  mov    (%rdx),%ecx
  add    %rax,%r10
  mov    (%r10),%eax
  mov    %eax,(%rdx)
  mov    %ecx,(%r10)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  movslq %esi,%rsi
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r9,4)
  mov    %r11d,(%rax)
  mov    (%r10,%r9,4),%eax
  add    %r10,%rsi
  mov    (%rsi),%edx
  mov    %edx,(%r10,%r9,4)
  mov    %eax,(%rsi)
  mov    %rbx,%r9
L2:
  mov    %r9d,%esi
  mov    (%rdi,%r9,4),%r11d
  cmp    %rbp,%r9
  je     L11
  lea    0x1(%r9),%rbx
  mov    %rbx,%rax
  mov    %r11d,%ecx
  jmp    L60
L25:
  ret
```

assistant: ```c
void sort_both(int row_ones[], int pos[], int count) {
  int i, j;
  for (i = 0; i < count; i++) {
    int temp = row_ones[i];
    int p = i;
    for (j = i + 1; j < count; j++) {
      if (temp < row_ones[j]) {
        temp = row_ones[j];
        p = j;
      }
    }
    temp = row_ones[i];
    row_ones[i] = row_ones[p];
    row_ones[p] = temp;
    temp = pos[i];
    pos[i] = pos[p];
    pos[p] = temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort_both>:
  endbr64
  test   %edx,%edx
  jle    L25
  push   %rbp
  xor    %r9d,%r9d
  lea    -0x1(%rdx),%ebp
  mov    %rsi,%r10
  push   %rbx
  mov    (%rdi,%r9,4),%r11d
  mov    %edx,%r8d
  movslq %r9d,%rsi
  cmp    %r9,%rbp
  je     L14
  nopw   0x0(%rax,%rax,1)
L1:
  lea    0x1(%r9),%rbx
  mov    %r11d,%ecx
  mov    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L33:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jle    L34
  movslq %eax,%rsi
  mov    %edx,%ecx
L34:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L33
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  add    %r10,%rsi
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r9,4)
  mov    %r11d,(%rax)
  mov    (%rsi),%edx
  mov    (%r10,%r9,4),%eax
  mov    %edx,(%r10,%r9,4)
  mov    %rbx,%r9
  mov    %eax,(%rsi)
  movslq %r9d,%rsi
  mov    (%rdi,%r9,4),%r11d
  cmp    %r9,%rbp
  jne    L1
L14:
  pop    %rbx
  pop    %rbp
  ret
L25:
  ret
```

assistant: ```c
void sort_both(int row_ones[], int pos[], int count) {
  int i, j;
  for (i = 0; i < count; i++) {
    int temp = row_ones[i];
    int p = i;
    for (j = i + 1; j < count; j++) {
      if (temp < row_ones[j]) {
        temp = row_ones[j];
        p = j;
      }
    }
    temp = row_ones[i];
    row_ones[i] = row_ones[p];
    row_ones[p] = temp;
    temp = pos[i];
    pos[i] = pos[p];
    pos[p] = temp;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_both>:
  endbr64
  test   %edx,%edx
  jle    L15
  push   %rbp
  mov    %edx,%r8d
  push   %rbx
  mov    (%rdi),%ebx
  cmp    $0x1,%edx
  je     L9
  mov    %rsi,%r11
  lea    -0x1(%rdx),%ebp
  xor    %r9d,%r9d
  nopl   (%rax)
L21:
  movslq %r9d,%rsi
  mov    %r9,%r10
  add    $0x1,%r9
  mov    %ebx,%ecx
  mov    %r9,%rax
  nop
L16:
  mov    (%rdi,%rax,4),%edx
  cmp    %edx,%ecx
  jge    L5
  movslq %eax,%rsi
  mov    %edx,%ecx
L5:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L16
  shl    $0x2,%rsi
  lea    (%rdi,%rsi,1),%rax
  add    %r11,%rsi
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r10,4)
  mov    %ebx,(%rax)
  mov    (%r11,%r10,4),%eax
  mov    (%rsi),%edx
  mov    %edx,(%r11,%r10,4)
  mov    %eax,(%rsi)
  mov    0x4(%rdi,%r10,4),%ebx
  cmp    %rbp,%r9
  jne    L21
L9:
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
void sort_both(int row_ones[], int pos[], int count) {
  int i, j;
  for (i = 0; i < count; i++) {
    int temp = row_ones[i];
    int p = i;
    for (j = i + 1; j < count; j++) {
      if (temp < row_ones[j]) {
        temp = row_ones[j];
        p = j;
      }
    }
    temp = row_ones[i];
    row_ones[i] = row_ones[p];
    row_ones[p] = temp;
    temp = pos[i];
    pos[i] = pos[p];
    pos[p] = temp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Pipe2Buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xa000,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <xmalloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L67:
  mov    -0xc(%rbp),%eax
  add    $0x1000,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L68
  addl   $0xa000,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L68:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L50
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L12
L50:
  cmpl   $0x0,-0x4(%rbp)
  jne    L22
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L60
L22:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L60
L12:
  jmp    L67
L60:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int Pipe2Buf(int fd, char **buf) {
  int got;
  int clen = 0;
  int blen = 0;
  blen = 4096 * 10;
  *buf = xmalloc(blen);
  while (1) {
    if ((clen + 4096) >= blen) {
      blen += 4096 * 10;
      *buf = xrealloc(*buf, blen);
    }
    got = read(fd, *buf + clen, 4096);
    if (got > 0) {
      clen += got;
      continue;
    } else if (got == 0) {
      blen = clen + 1;
      *buf = xrealloc(*buf, blen);
      *(*buf + clen) = '\0';
      break;
    } else {
      xfree(*buf);
      blen = -1;
      break;
    }
  }
  return blen;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Pipe2Buf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0xa000,%edi
  call   <xmalloc@plt>
  mov    %rax,(%rbx)
  mov    $0x0,%ebp
  mov    $0xa000,%r14d
L32:
  movslq %ebp,%r13
  mov    %r13,%rsi
  add    (%rbx),%rsi
  mov    $0x1000,%edx
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L4
  jne    L16
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    (%rbx),%rdi
  call   <xrealloc@plt>
  mov    %rax,(%rbx)
  movb   $0x0,(%rax,%r13,1)
L28:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  add    %eax,%ebp
  lea    0x1000(%rbp),%eax
  cmp    %r14d,%eax
  jl     L32
  add    $0xa000,%r14d
  mov    %r14d,%esi
  mov    (%rbx),%rdi
  call   <xrealloc@plt>
  mov    %rax,(%rbx)
  jmp    L32
L16:
  mov    (%rbx),%rdi
  call   <xfree@plt>
  mov    $0xffffffff,%ebp
  jmp    L28
```

assistant: ```c
int Pipe2Buf(int fd, char **buf) {
  int got;
  int clen = 0;
  int blen = 0;
  blen = 4096 * 10;
  *buf = xmalloc(blen);
  while (1) {
    if ((clen + 4096) >= blen) {
      blen += 4096 * 10;
      *buf = xrealloc(*buf, blen);
    }
    got = read(fd, *buf + clen, 4096);
    if (got > 0) {
      clen += got;
      continue;
    } else if (got == 0) {
      blen = clen + 1;
      *buf = xrealloc(*buf, blen);
      *(*buf + clen) = '\0';
      break;
    } else {
      xfree(*buf);
      blen = -1;
      break;
    }
  }
  return blen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Pipe2Buf>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    $0xa000,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xa000,%edi
  push   %rbx
  mov    %rsi,%rbx
  call   <xmalloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
L3:
  movslq %r14d,%r13
  mov    $0x1000,%edx
  lea    (%rdi,%r13,1),%rsi
  mov    %ebp,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L49
  mov    (%rbx),%rdi
  jne    L25
  add    $0x1,%r14d
  mov    %r14d,%esi
  call   <xrealloc@plt>
  mov    %rax,(%rbx)
  movb   $0x0,(%rax,%r13,1)
L47:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L49:
  add    %eax,%r14d
  mov    (%rbx),%rdi
  lea    0x1000(%r14),%eax
  cmp    %r12d,%eax
  jl     L3
  add    $0xa000,%r12d
  mov    %r12d,%esi
  call   <xrealloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  jmp    L3
  nopl   0x0(%rax)
L25:
  call   <xfree@plt>
  mov    $0xffffffff,%r14d
  jmp    L47
```

assistant: ```c
int Pipe2Buf(int fd, char **buf) {
  int got;
  int clen = 0;
  int blen = 0;
  blen = 4096 * 10;
  *buf = xmalloc(blen);
  while (1) {
    if ((clen + 4096) >= blen) {
      blen += 4096 * 10;
      *buf = xrealloc(*buf, blen);
    }
    got = read(fd, *buf + clen, 4096);
    if (got > 0) {
      clen += got;
      continue;
    } else if (got == 0) {
      blen = clen + 1;
      *buf = xrealloc(*buf, blen);
      *(*buf + clen) = '\0';
      break;
    } else {
      xfree(*buf);
      blen = -1;
      break;
    }
  }
  return blen;
}
```