ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_inside>:
  endbr64
  test   %edx,%edx
  jle    L30
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L30
L8:
  cmp    %esi,(%rdi)
  jne    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_inside(int *v, int f, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (v[i] == f)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_inside>:
  endbr64
  test   %edx,%edx
  jle    L32
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L32
L16:
  cmp    %esi,(%rdi)
  jne    L11
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_inside(int *v, int f, int n) {
  int i;
  for (i = 0; i < n; i++) {
    if (v[i] == f)
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long read32(unsigned long reg1) {
  unsigned long *reg;
  signed long val;
  reg = (unsigned long *)reg1;
  val = (long)*(reg);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read32>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long read32(unsigned long reg1) {
  unsigned long *reg;
  signed long val;
  reg = (unsigned long *)reg1;
  val = (long)*(reg);
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read32>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long read32(unsigned long reg1) {
  unsigned long *reg;
  signed long val;
  reg = (unsigned long *)reg1;
  val = (long)*(reg);
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read32>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
long read32(unsigned long reg1) {
  unsigned long *reg;
  signed long val;
  reg = (unsigned long *)reg1;
  val = (long)*(reg);
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pickreciprocal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %rdi,-0xfc8(%rbp)
  mov    %esi,-0xfcc(%rbp)
  mov    %edx,-0xfd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xfb8(%rbp)
  cmpl   $0x1,-0xfcc(%rbp)
  jne    L85
  mov    $0x0,%eax
  jmp    L19
L85:
  mov    -0xfcc(%rbp),%edx
  mov    -0xfc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pickzero@plt>
  mov    %eax,-0xfb4(%rbp)
  cmpl   $0xffffffff,-0xfb4(%rbp)
  je     L48
  mov    -0xfb4(%rbp),%eax
  jmp    L19
L48:
  movl   $0x0,-0xfbc(%rbp)
  jmp    L44
L49:
  mov    -0xfbc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xfc8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0xfb8(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xfb8(%rbp)
  addl   $0x1,-0xfbc(%rbp)
L44:
  mov    -0xfbc(%rbp),%eax
  cmp    -0xfcc(%rbp),%eax
  jl     L49
  movl   $0x0,-0xfbc(%rbp)
  jmp    L71
L33:
  mov    -0xfbc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xfc8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xfb8(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfbc(%rbp)
L71:
  mov    -0xfbc(%rbp),%eax
  cmp    -0xfcc(%rbp),%eax
  jl     L33
  mov    -0xfcc(%rbp),%edx
  lea    -0xfb0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <pickweight@plt>
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int pickreciprocal(int *numbreak, int clausesize, int tofix) {
  int i;
  int weight[1000];
  int tochange;
  int totalproduct = 1;
  if (clausesize == 1)
    return (0);
  if ((tochange = pickzero(numbreak, clausesize)) != -1)
    return (tochange);
  for (i = 0; i < clausesize; i++)
    totalproduct *= numbreak[i];
  for (i = 0; i < clausesize; i++)
    weight[i] = (totalproduct / numbreak[i]);
  return (pickweight(weight, clausesize));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pickreciprocal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L51
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <pickzero@plt>
  cmp    $0xffffffff,%eax
  jne    L51
  test   %ebp,%ebp
  jle    L14
  mov    %rbx,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%rbx,%rdx,4),%rdx
  mov    $0x1,%esi
L58:
  imul   (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L58
  mov    %ebp,%edi
  mov    $0x0,%ecx
L31:
  mov    %esi,%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,(%rsp,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L31
L14:
  mov    %rsp,%rdi
  mov    %ebp,%esi
  call   <pickweight@plt>
L51:
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pickreciprocal(int *numbreak, int clausesize, int tofix) {
  int i;
  int weight[1000];
  int tochange;
  int totalproduct = 1;
  if (clausesize == 1)
    return (0);
  if ((tochange = pickzero(numbreak, clausesize)) != -1)
    return (tochange);
  for (i = 0; i < clausesize; i++)
    totalproduct *= numbreak[i];
  for (i = 0; i < clausesize; i++)
    weight[i] = (totalproduct / numbreak[i]);
  return (pickweight(weight, clausesize));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pickreciprocal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L43
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <pickzero@plt>
  cmp    $0xffffffff,%eax
  jne    L43
  mov    %rsp,%rdi
  test   %ebp,%ebp
  jle    L27
  lea    -0x1(%rbp),%edx
  mov    %rbx,%rax
  mov    $0x1,%esi
  lea    0x4(%rbx,%rdx,4),%rdx
  nopl   0x0(%rax,%rax,1)
L10:
  imul   (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L10
  mov    %ebp,%r8d
  xor    %ecx,%ecx
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L15:
  mov    %esi,%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L15
L27:
  mov    %ebp,%esi
  call   <pickweight@plt>
L43:
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pickreciprocal(int *numbreak, int clausesize, int tofix) {
  int i;
  int weight[1000];
  int tochange;
  int totalproduct = 1;
  if (clausesize == 1)
    return (0);
  if ((tochange = pickzero(numbreak, clausesize)) != -1)
    return (tochange);
  for (i = 0; i < clausesize; i++)
    totalproduct *= numbreak[i];
  for (i = 0; i < clausesize; i++)
    weight[i] = (totalproduct / numbreak[i]);
  return (pickweight(weight, clausesize));
}
```
user: What is the c source code of the assembly code below:

```asm
<pickreciprocal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L76
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <pickzero@plt>
  cmp    $0xffffffff,%eax
  jne    L76
  mov    %rsp,%rdi
  test   %ebp,%ebp
  jle    L13
  lea    -0x1(%rbp),%eax
  cmp    $0x1a,%eax
  jbe    L47
  mov    %ebp,%edx
  movdqa D3(%rip),%xmm1
  mov    %rbx,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbx,%rdx,1),%rdx
  nop
L40:
  movdqu (%rax),%xmm2
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L40
  movdqa %xmm1,%xmm0
  mov    %ebp,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  movdqa %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  pmuludq %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%bpl
  je     L60
L99:
  cltq
  nopl   0x0(%rax)
L90:
  imul   (%rbx,%rax,4),%esi
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L90
L60:
  mov    %ebp,%r8d
  xor    %ecx,%ecx
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L32:
  mov    %esi,%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L32
L13:
  mov    %ebp,%esi
  call   <pickweight@plt>
L76:
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  mov    $0x1,%esi
  xor    %eax,%eax
  jmp    L99
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int pickreciprocal(int *numbreak, int clausesize, int tofix) {
  int i;
  int weight[1000];
  int tochange;
  int totalproduct = 1;
  if (clausesize == 1)
    return (0);
  if ((tochange = pickzero(numbreak, clausesize)) != -1)
    return (tochange);
  for (i = 0; i < clausesize; i++)
    totalproduct *= numbreak[i];
  for (i = 0; i < clausesize; i++)
    weight[i] = (totalproduct / numbreak[i]);
  return (pickweight(weight, clausesize));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x40(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x38(%rbp)
  movl   $0x9,-0x44(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L5
L13:
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%rax
  lea    D66(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x48(%rbp)
L5:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L13
  lea    -0x30(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%rax
  lea    D70(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D65
type: string
name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D68
type: string
name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D66
type: string
name: retrieve_data
arguments: data_tag: D70
type: string

tool: D17: r

tool: D65: task.in

tool: D28: w

tool: D68: task.out

tool: D16: %d

tool: D66: %d 

tool: D70: %d


assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int array[10];
  int last = 10 - 1;
  for (int i = 0; i < last; i++) {
    fscanf(in, "%d", &array[i]);
    fprintf(out, "%d ", array[i]);
  }
  fscanf(in, "%d", &array[last]);
  fprintf(out, "%d\n", array[last]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  lea    D47(%rip),%rsi
  lea    D41(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rsp,%rbx
  lea    0x24(%rsp),%r15
  lea    D25(%rip),%r14
  lea    D26(%rip),%r13
L14:
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fscanf@plt>
  mov    (%rbx),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L14
  lea    0x24(%rsp),%rdx
  lea    D25(%rip),%rsi
  mov    %r12,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%edx
  lea    D76(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type_infered: string
name: unpack_data
arguments: data_tag: D0
type_infered: string
name: unpack_data
arguments: data_tag: D47
type_infered: string
name: unpack_data
arguments: data_tag: D41
type_infered: string
name: unpack_data
arguments: data_tag: D25
type_infered: string
name: unpack_data
arguments: data_tag: D26
type_infered: string
name: unpack_data
arguments: data_tag: D76
type_infered: string

tool: D22: r

tool: D0: task.in

tool: D47: w

tool: D41: task.out

tool: D25: %d

tool: D26: %d 

tool: D76: %d


assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int array[10];
  int last = 10 - 1;
  for (int i = 0; i < last; i++) {
    fscanf(in, "%d", &array[i]);
    fprintf(out, "%d ", array[i]);
  }
  fscanf(in, "%d", &array[last]);
  fprintf(out, "%d\n", array[last]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D66(%rip),%rsi
  lea    D8(%rip),%rdi
  push   %r14
  lea    D55(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%r15
  call   <fopen@plt>
  lea    D61(%rip),%rsi
  lea    D1(%rip),%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L18:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <fscanf@plt>
  mov    -0x4(%r12),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  cmp    %r15,%r12
  jne    L18
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%edx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D66
type_infered: string
name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D55
type_infered: string
name: retrieve_data
arguments: tag: D29
type_infered: string
name: retrieve_data
arguments: tag: D61
type_infered: string
name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string

tool: D66: r

tool: D8: task.in

tool: D55: %d

tool: D29: %d 

tool: D61: w

tool: D1: task.out

tool: D27: %d


assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int array[10];
  int last = 10 - 1;
  for (int i = 0; i < last; i++) {
    fscanf(in, "%d", &array[i]);
    fprintf(out, "%d ", array[i]);
  }
  fscanf(in, "%d", &array[last]);
  fprintf(out, "%d\n", array[last]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D40(%rip),%rsi
  lea    D44(%rip),%rdi
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x24(%rsp),%r15
  call   <fopen@plt>
  lea    D36(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax)
L9:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <fscanf@plt>
  mov    -0x4(%r12),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  cmp    %r15,%r12
  jne    L9
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fscanf@plt>
  mov    0x24(%rsp),%edx
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D40
datatype: string
name: retrieve_data
arguments: data_tag: D44
datatype: string
name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string
name: retrieve_data
arguments: data_tag: D36
datatype: string
name: retrieve_data
arguments: data_tag: D35
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string

tool: D40: r

tool: D44: task.in

tool: D10: %d

tool: D33: %d 

tool: D36: w

tool: D35: task.out

tool: D22: %d


assistant: ```c
int main() {
  FILE *in = fopen("task.in", "r");
  FILE *out = fopen("task.out", "w");
  int array[10];
  int last = 10 - 1;
  for (int i = 0; i < last; i++) {
    fscanf(in, "%d", &array[i]);
    fprintf(out, "%d ", array[i]);
  }
  fscanf(in, "%d", &array[last]);
  fprintf(out, "%d\n", array[last]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ln_get_solar_sdiam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ln_get_earth_solar_dist@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: f64

tool: D2: 959.63

assistant: ```c
double ln_get_solar_sdiam(double JD) {
  double So = 959.63;
  double dist;
  dist = ln_get_earth_solar_dist(JD);
  return So / dist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ln_get_solar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_earth_solar_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  divsd  %xmm1,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: f64

tool: D6: 959.63

assistant: ```c
double ln_get_solar_sdiam(double JD) {
  double So = 959.63;
  double dist;
  dist = ln_get_earth_solar_dist(JD);
  return So / dist;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ln_get_solar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_earth_solar_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D8(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: f64

tool: D8: 959.63

assistant: ```c
double ln_get_solar_sdiam(double JD) {
  double So = 959.63;
  double dist;
  dist = ln_get_earth_solar_dist(JD);
  return So / dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ln_get_solar_sdiam>:
  endbr64
  sub    $0x8,%rsp
  call   <ln_get_earth_solar_dist@plt>
  movapd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  add    $0x8,%rsp
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: f64

tool: D1: 959.63

assistant: ```c
double ln_get_solar_sdiam(double JD) {
  double So = 959.63;
  double dist;
  dist = ln_get_earth_solar_dist(JD);
  return So / dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dealtab>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L62
  mov    %esi,%r13d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L117
L2:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rax,%rbx,1),%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax,%rbx,1),%r14d
  movslq %r14d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %r14d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  mov    $0x14,%ecx
  lea    -0x14(%rcx,%rax,4),%r15d
  lea    D38(%rip),%rcx
  mov    %r15d,%edx
  mov    %r14d,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r15d,%r14d
  jg     L30
  movslq %ebp,%rax
  movzbl (%r12,%rbx,1),%edx
  mov    %dl,0x10(%rsp,%rax,1)
  lea    0x1(%rbp),%ebp
L14:
  cmp    %r13d,%ebp
  jge    L109
  add    $0x1,%rbx
  movzbl (%r12,%rbx,1),%eax
  test   %al,%al
  je     L6
L117:
  mov    %ebx,0xc(%rsp)
  cmp    $0x9,%al
  je     L2
  movslq %ebp,%rdx
  mov    %al,0x10(%rsp,%rdx,1)
  lea    0x1(%rbp),%ebp
  jmp    L14
L30:
  lea    D38(%rip),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L14
  movslq %ebp,%rdx
  lea    0x10(%rsp,%rdx,1),%rax
  lea    0x11(%rsp,%rdx,1),%rdx
  mov    %r14d,%ecx
  sub    0xc(%rsp),%ecx
  lea    -0x1(%rcx),%ecx
  add    %rcx,%rdx
L118:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L118
  sub    0xc(%rsp),%ebp
  add    %r14d,%ebp
  jmp    L14
L62:
  mov    $0x0,%ebp
L6:
  movslq %ebp,%rbp
  movb   $0x0,0x10(%rsp,%rbp,1)
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L46:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L87
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L109:
  mov    $0xffffffff,%eax
  jmp    L46
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D38
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string

tool: D38: dealtab

tool: D27: nextstop=%d, nextcol=%d: %s


tool: D15: get any: %s


assistant: ```c
int dealtab(char line[], int limit) {
  int i, j, k, nextstop, nextcol;
  char tmp[256];
  for (i = j = 0; line[i] != '\0'; i++) {
    if (line[i] == '\t') {
      nextstop = i + 8 - i % 8;
      nextcol = nextstop + (20 - nextstop % 20) - 20;
      printf("nextstop=%d, nextcol=%d: %s\n", nextstop, nextcol, __func__);
      if (nextstop > nextcol) {
        printf("get any: %s\n", __func__);
        for (k = i; k < nextstop; k++) {
          tmp[j++] = ' ';
        }
      } else {
        tmp[j++] = line[i];
      }
    } else {
      tmp[j++] = line[i];
    }
    if (j >= limit) {
      return -1;
    }
  }
  tmp[j] = '\0';
  strcpy(line, tmp);
  return 0;
}
```