ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D51(%rip),%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L38
  lea    0x10(%rsp),%r12
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D60(%rip),%r14
  lea    D51(%rip),%r13
L69:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    %ebx,%ecx
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L69
  test   %ecx,%ecx
  jle    L38
  movslq %ecx,%rax
  lea    0x10(%rsp,%rax,4),%rdx
  mov    %ecx,%eax
L48:
  mov    (%r12),%esi
  mov    (%rdx),%edi
  mov    %edi,(%r12)
  mov    %esi,(%rdx)
  sub    $0x1,%eax
  add    $0x4,%r12
  sub    $0x4,%rdx
  mov    %ecx,%esi
  sub    %eax,%esi
  cmp    %esi,%eax
  jg     L48
L38:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0xc(%rsp)
  je     L43
  mov    $0x0,%ebx
  lea    D40(%rip),%rbp
L60:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  movslq 0xc(%rsp),%rax
  cmp    %rbx,%rax
  ja     L60
L43:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D39
type: string
name: parse_data
arguments: data_label: D51
type: string
name: parse_data
arguments: data_label: D49
type: string
name: parse_data
arguments: data_label: D60
type: string
name: parse_data
arguments: data_label: D45
type: string
name: parse_data
arguments: data_label: D40
type: string

tool: D39: How many number would you like to input? 
> 

tool: D51: %d

tool: D49: Enter the number: 

tool: D60: > 

tool: D45: The reserved number is: 

tool: D40: >> %d


assistant: ```c
int main(void) {
  int input[5], i, tmp, count, j;
  printf("How many number would you like to input? \n> ");
  scanf("%d", &count);
  printf("Enter the number: \n");
  for (i = 0; i < count; i++) {
    printf("> ");
    scanf("%d", &input[i]);
  }
  j = i - 1;
  i = 0;
  while (i < j) {
    tmp = input[i];
    input[i] = input[j];
    input[j] = tmp;
    i++;
    j--;
  }
  printf("The reserved number is: \n");
  for (size_t i = 0; i < count; i++) {
    printf(">> %d\n", input[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D26(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D56(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L4
  lea    0x10(%rsp),%r13
  xor    %ebx,%ebx
  lea    D9(%rip),%r14
  mov    %r13,%r15
  mov    %r13,%rbp
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    %ebx,%eax
  lea    0x1(%rbx),%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L29
  test   %eax,%eax
  je     L4
  movslq %eax,%rdx
  lea    0x0(%r13,%rdx,4),%rcx
  mov    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%r15),%esi
  mov    (%rcx),%edi
  sub    $0x1,%edx
  add    $0x4,%r15
  sub    $0x4,%rcx
  mov    %edi,-0x4(%r15)
  mov    %esi,0x4(%rcx)
  mov    %eax,%esi
  sub    %edx,%esi
  cmp    %esi,%edx
  jg     L23
L4:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L58
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r13
  lea    D20(%rip),%rbp
  nopl   0x0(%rax)
L10:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movslq 0xc(%rsp),%rax
  cmp    %rbx,%rax
  ja     L10
L58:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D26
data_type: string
name: retrieve_data
arguments: tag: D56
data_type: string
name: retrieve_data
arguments: tag: D50
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D43
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string

tool: D26: How many number would you like to input? 
> 

tool: D56: %d

tool: D50: Enter the number: 

tool: D9: > 

tool: D43: The reserved number is: 

tool: D20: >> %d


assistant: ```c
int main(void) {
  int input[5], i, tmp, count, j;
  printf("How many number would you like to input? \n> ");
  scanf("%d", &count);
  printf("Enter the number: \n");
  for (i = 0; i < count; i++) {
    printf("> ");
    scanf("%d", &input[i]);
  }
  j = i - 1;
  i = 0;
  while (i < j) {
    tmp = input[i];
    input[i] = input[j];
    input[j] = tmp;
    i++;
    j--;
  }
  printf("The reserved number is: \n");
  for (size_t i = 0; i < count; i++) {
    printf(">> %d\n", input[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<saveMenu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <save@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string

tool: D0: 	enter money>

tool: D48: %lf

tool: D15: ===========================

tool: D14: save %lf successful!


assistant: ```c
void saveMenu() {
  printf("\tenter money>");
  double money = 0;
  scanf("%lf", &money);
  save(money);
  printf("===========================\n");
  printf("save %lf successful!\n", money);
  printf("===========================\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<saveMenu>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  call   <save@plt>
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  movsd  (%rsp),%xmm0
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type: string
name: parse_data
arguments: tag: D32
type: string
name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D14
type: string

tool: D6: 	enter money>

tool: D32: %lf

tool: D26: ===========================

tool: D14: save %lf successful!


assistant: ```c
void saveMenu() {
  printf("\tenter money>");
  double money = 0;
  scanf("%lf", &money);
  save(money);
  printf("===========================\n");
  printf("save %lf successful!\n", money);
  printf("===========================\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<saveMenu>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D19(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D31(%rip),%rdi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  call   <save@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D31
type: string
name: retrieve_data
arguments: data_tag: D16
type: string

tool: D5: 	enter money>

tool: D19: ===========================

tool: D31: %lf

tool: D16: save %lf successful!


assistant: ```c
void saveMenu() {
  printf("\tenter money>");
  double money = 0;
  scanf("%lf", &money);
  save(money);
  printf("===========================\n");
  printf("save %lf successful!\n", money);
  printf("===========================\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<saveMenu>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  lea    D16(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D37(%rip),%rdi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  call   <save@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string
name: read_data
arguments: data_label: D37
type_guessed: string
name: read_data
arguments: data_label: D5
type_guessed: string

tool: D21: 	enter money>

tool: D16: ===========================

tool: D37: %lf

tool: D5: save %lf successful!


assistant: ```c
void saveMenu() {
  printf("\tenter money>");
  double money = 0;
  scanf("%lf", &money);
  save(money);
  printf("===========================\n");
  printf("save %lf successful!\n", money);
  printf("===========================\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L29
L22:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L29:
  cmpl   $0x7,-0x34(%rbp)
  jle    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int main(void) {
  int i;
  int a[8];
  memset(a, 1, sizeof(a));
  for (i = 0; i < 8; ++i) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0x20(%rsp),%r12
  lea    D0(%rip),%rbp
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L13
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main(void) {
  int i;
  int a[8];
  memset(a, 1, sizeof(a));
  for (i = 0; i < 8; ++i) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x20,%edx
  mov    $0x1,%esi
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rdi
  call   <memset@plt>
  nopl   (%rax)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int i;
  int a[8];
  memset(a, 1, sizeof(a));
  for (i = 0; i < 8; ++i) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x20,%edx
  mov    $0x1,%esi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x20(%rsp),%r12
  mov    %rbx,%rdi
  call   <memset@plt>
  nopl   (%rax)
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D8: %d


assistant: ```c
int main(void) {
  int i;
  int a[8];
  memset(a, 1, sizeof(a));
  for (i = 0; i < 8; ++i) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_sort_integer_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L4
L17:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L49:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L9
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x1,-0xc(%rbp)
L9:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L49
L4:
  cmpl   $0x1,-0xc(%rbp)
  je     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_sort_integer_table(int *tab, int size) {
  int i;
  int flag;
  int tmp;
  flag = 1;
  while (flag == 1) {
    flag = 0;
    i = 0;
    while (i < size - 1) {
      if (tab[i] > tab[i + 1]) {
        tmp = tab[i];
        tab[i] = tab[i + 1];
        tab[i + 1] = tmp;
        flag = 1;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_sort_integer_table>:
  endbr64
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  jmp    L39
L23:
  cmp    $0x1,%ecx
  jne    L29
L39:
  mov    %r8d,%ecx
L4:
  cmp    $0x1,%esi
  jle    L23
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  jle    L4
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  mov    %r9d,%ecx
  jmp    L4
L29:
  ret
```

assistant: ```c
void ft_sort_integer_table(int *tab, int size) {
  int i;
  int flag;
  int tmp;
  flag = 1;
  while (flag == 1) {
    flag = 0;
    i = 0;
    while (i < size - 1) {
      if (tab[i] > tab[i + 1]) {
        tmp = tab[i];
        tab[i] = tab[i + 1];
        tab[i + 1] = tmp;
        flag = 1;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_sort_integer_table>:
  endbr64
  xor    %r8d,%r8d
  cmp    $0x1,%esi
  setg   %r8b
  xor    %ecx,%ecx
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  jg     L52
L54:
  cmp    $0x1,%esi
  jg     L15
  cmp    $0x1,%ecx
  jne    L31
L30:
  mov    %r8d,%ecx
  jmp    L54
L52:
  mov    %edx,(%rdi)
  mov    %eax,0x4(%rdi)
  jmp    L30
L31:
  ret
```

assistant: ```c
void ft_sort_integer_table(int *tab, int size) {
  int i;
  int flag;
  int tmp;
  flag = 1;
  while (flag == 1) {
    flag = 0;
    i = 0;
    while (i < size - 1) {
      if (tab[i] > tab[i + 1]) {
        tmp = tab[i];
        tab[i] = tab[i + 1];
        tab[i + 1] = tmp;
        flag = 1;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_sort_integer_table>:
  endbr64
  xor    %ecx,%ecx
  cmp    $0x1,%esi
  setg   %cl
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L21
  nopl   0x0(%rax,%rax,1)
L24:
  mov    0x4(%rdi),%eax
  mov    (%rdi),%edx
  nopl   (%rax)
L13:
  cmp    %eax,%edx
  jle    L13
  movd   %eax,%xmm0
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
L8:
  mov    %ecx,%eax
  cmp    $0x1,%esi
  jg     L24
L21:
  cmp    $0x1,%eax
  je     L8
  ret
```

assistant: ```c
void ft_sort_integer_table(int *tab, int size) {
  int i;
  int flag;
  int tmp;
  flag = 1;
  while (flag == 1) {
    flag = 0;
    i = 0;
    while (i < size - 1) {
      if (tab[i] > tab[i + 1]) {
        tmp = tab[i];
        tab[i] = tab[i + 1];
        tab[i + 1] = tmp;
        flag = 1;
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <dicebag_init@plt>
  mov    $0x64,%edi
  call   <dicebag_roll@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xc8,%esi
  mov    $0x64,%edi
  call   <dicebag_range@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffff9c,%esi
  mov    $0xffffff38,%edi
  call   <dicebag_range@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <dicebag_dice@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <dicebag_best@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D26
datatype: string
name: retrieve_data
arguments: data_tag: D30
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string
name: retrieve_data
arguments: data_tag: D15
datatype: string

tool: D26: roll( 100 ) -> %d


tool: D30: range( 100, 200 ) -> %d


tool: D4: range( -200, -100 ) -> %d


tool: D34: dice( 10, 10 ) -> %d


tool: D15: best( 10, 20, 10 ) -> %d


assistant: ```c
int main(int argc, char **argv) {
  int n;
  dicebag_init();
  n = dicebag_roll(100);
  printf("roll( 100 ) -> %d\n", n);
  n = dicebag_range(100, 200);
  printf("range( 100, 200 ) -> %d\n", n);
  n = dicebag_range(-200, -100);
  printf("range( -200, -100 ) -> %d\n", n);
  n = dicebag_dice(10, 10);
  printf("dice( 10, 10 ) -> %d\n", n);
  n = dicebag_best(10, 20, 10);
  printf("best( 10, 20, 10 ) -> %d\n", n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dicebag_init@plt>
  mov    $0x64,%edi
  call   <dicebag_roll@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xc8,%esi
  mov    $0x64,%edi
  call   <dicebag_range@plt>
  mov    %eax,%esi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffff9c,%esi
  mov    $0xffffff38,%edi
  call   <dicebag_range@plt>
  mov    %eax,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <dicebag_dice@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    $0x14,%esi
  mov    $0xa,%edi
  call   <dicebag_best@plt>
  mov    %eax,%esi
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D49
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D47
type_infered: string

tool: D8: roll( 100 ) -> %d


tool: D49: range( 100, 200 ) -> %d


tool: D39: range( -200, -100 ) -> %d


tool: D28: dice( 10, 10 ) -> %d


tool: D47: best( 10, 20, 10 ) -> %d


assistant: ```c
int main(int argc, char **argv) {
  int n;
  dicebag_init();
  n = dicebag_roll(100);
  printf("roll( 100 ) -> %d\n", n);
  n = dicebag_range(100, 200);
  printf("range( 100, 200 ) -> %d\n", n);
  n = dicebag_range(-200, -100);
  printf("range( -200, -100 ) -> %d\n", n);
  n = dicebag_dice(10, 10);
  printf("dice( 10, 10 ) -> %d\n", n);
  n = dicebag_best(10, 20, 10);
  printf("best( 10, 20, 10 ) -> %d\n", n);
  return 0;
}
```