ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<RD_ReadBool>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L17
L9:
  mov    $0x1,%eax
  pop    %rbp
  ret
L17:
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  call   <strcasecmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D12
type_guessed: string

tool: D22: true

tool: D24: yes

tool: D12: on

assistant: ```c
unsigned RD_ReadBool(const char *val) {
  if ((strcasecmp(val, "true") == 0) || (strcasecmp(val, "yes") == 0) || (strcasecmp(val, "on") == 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RD_ReadBool>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L19
L4:
  mov    $0x1,%eax
  pop    %rbp
  ret
L19:
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  call   <strcasecmp@plt>
  pop    %rbp
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D0
type: string

tool: D17: true

tool: D1: yes

tool: D0: on

assistant: ```c
unsigned RD_ReadBool(const char *val) {
  if ((strcasecmp(val, "true") == 0) || (strcasecmp(val, "yes") == 0) || (strcasecmp(val, "on") == 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<i2c_tiny_usb_get_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <i2c_tiny_usb_read@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: Functionality = %lx


assistant: ```c
void i2c_tiny_usb_get_func(void) {
  unsigned long func;
  if (i2c_tiny_usb_read(1, &func, sizeof(func)) == 0)
    printf("Functionality = %lx\n", func);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i2c_tiny_usb_get_func>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    $0x1,%edi
  call   <i2c_tiny_usb_read@plt>
  test   %rax,%rax
  je     L29
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L29:
  mov    (%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D7
type: string

tool: D7: Functionality = %lx


assistant: ```c
void i2c_tiny_usb_get_func(void) {
  unsigned long func;
  if (i2c_tiny_usb_read(1, &func, sizeof(func)) == 0)
    printf("Functionality = %lx\n", func);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2c_tiny_usb_get_func>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <i2c_tiny_usb_read@plt>
  test   %rax,%rax
  je     L22
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L22:
  mov    (%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: Functionality = %lx


assistant: ```c
void i2c_tiny_usb_get_func(void) {
  unsigned long func;
  if (i2c_tiny_usb_read(1, &func, sizeof(func)) == 0)
    printf("Functionality = %lx\n", func);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<i2c_tiny_usb_get_func>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x8,%edx
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <i2c_tiny_usb_read@plt>
  test   %rax,%rax
  je     L22
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L22:
  mov    (%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string

tool: D3: Functionality = %lx


assistant: ```c
void i2c_tiny_usb_get_func(void) {
  unsigned long func;
  if (i2c_tiny_usb_read(1, &func, sizeof(func)) == 0)
    printf("Functionality = %lx\n", func);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<linked_list_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <linked_list_out@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <linked_list_insert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <linked_list_out@plt>
  nop
  leave
  ret
```

assistant: ```c
void linked_list_add(struct linked_list_t *list, void *data) {
  linked_list_out(list);
  linked_list_insert(list, data);
  linked_list_out(list);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<linked_list_add>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <linked_list_out@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <linked_list_insert@plt>
  mov    %rbx,%rdi
  call   <linked_list_out@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void linked_list_add(struct linked_list_t *list, void *data) {
  linked_list_out(list);
  linked_list_insert(list, data);
  linked_list_out(list);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<linked_list_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <linked_list_out@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <linked_list_insert@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <linked_list_out@plt>
```

assistant: ```c
void linked_list_add(struct linked_list_t *list, void *data) {
  linked_list_out(list);
  linked_list_insert(list, data);
  linked_list_out(list);
}
```
user: What is the c source code of the assembly code below?

```asm
<linked_list_add>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <linked_list_out@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <linked_list_insert@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <linked_list_out@plt>
```

assistant: ```c
void linked_list_add(struct linked_list_t *list, void *data) {
  linked_list_out(list);
  linked_list_insert(list, data);
  linked_list_out(list);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<destroyMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void destroyMatrix(int **mat, int n) {
  int i;
  for (i = 0; i < n; i++)
    free(mat[i]);
  free(mat);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<destroyMatrix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L16:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L16
L4:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void destroyMatrix(int **mat, int n) {
  int i;
  for (i = 0; i < n; i++)
    free(mat[i]);
  free(mat);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<destroyMatrix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L13
L1:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void destroyMatrix(int **mat, int n) {
  int i;
  for (i = 0; i < n; i++)
    free(mat[i]);
  free(mat);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<destroyMatrix>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L1
L3:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void destroyMatrix(int **mat, int n) {
  int i;
  for (i = 0; i < n; i++)
    free(mat[i]);
  free(mat);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L55:
  cmpl   $0xa,-0x4(%rbp)
  je     L84
  jmp    L38
L84:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L129
  cmpl   $0x80,-0x4(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L39
L37:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cmp    $0xfe,%eax
  jle    L129
  mov    $0x1,%eax
  jmp    L39
L129:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L37
  cmpl   $0x80,-0x4(%rbp)
  jne    L97
  mov    $0x1,%eax
  jmp    L39
L97:
  mov    $0x0,%eax
  jmp    L39
L38:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  jne    L55
  mov    $0x1,%eax
L39:
  leave
  ret
```

assistant: ```c
int main(void) {
  int ch;
  int counter = 0;
  while ((ch = getchar()) != EOF) {
    if (ch != '\n')
      continue;
    ch = getchar();
    switch (ch) {
    case EOF:
      return 0;
    case '\n':
      while ((ch = getchar()) == '\n')
        if (counter++ >= 255)
          return 1;
      if (ch == EOF)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
L68:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x80,%eax
  je     L53
  cmp    $0xa,%eax
  jne    L68
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L29
  cmp    $0x80,%eax
  jne    L68
  mov    $0x0,%eax
L46:
  pop    %rbx
  ret
L29:
  mov    $0x100,%ebx
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L1
  sub    $0x1,%ebx
  jne    L3
  mov    $0x1,%eax
  jmp    L46
L1:
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L46
L53:
  mov    $0x1,%eax
  jmp    L46
```

assistant: ```c
int main(void) {
  int ch;
  int counter = 0;
  while ((ch = getchar()) != EOF) {
    if (ch != '\n')
      continue;
    ch = getchar();
    switch (ch) {
    case EOF:
      return 0;
    case '\n':
      while ((ch = getchar()) == '\n')
        if (counter++ >= 255)
          return 1;
      if (ch == EOF)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
L68:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x80,%eax
  je     L17
  cmp    $0xa,%eax
  jne    L68
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L65
  cmp    $0x80,%eax
  jne    L68
  xor    %eax,%eax
  pop    %rbx
  ret
L65:
  mov    $0x100,%ebx
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
L10:
  sub    $0x1,%ebx
  je     L17
L42:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L10
  cmp    $0x80,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L17:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int ch;
  int counter = 0;
  while ((ch = getchar()) != EOF) {
    if (ch != '\n')
      continue;
    ch = getchar();
    switch (ch) {
    case EOF:
      return 0;
    case '\n':
      while ((ch = getchar()) == '\n')
        if (counter++ >= 255)
          return 1;
      if (ch == EOF)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x80,%eax
  je     L63
  cmp    $0xa,%eax
  jne    L2
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L69
  cmp    $0x80,%eax
  jne    L2
  xor    %eax,%eax
  pop    %rbx
  ret
L69:
  mov    $0x100,%ebx
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L17:
  sub    $0x1,%ebx
  je     L63
L48:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  je     L17
  cmp    $0x80,%eax
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L63:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int ch;
  int counter = 0;
  while ((ch = getchar()) != EOF) {
    if (ch != '\n')
      continue;
    ch = getchar();
    switch (ch) {
    case EOF:
      return 0;
    case '\n':
      while ((ch = getchar()) == '\n')
        if (counter++ >= 255)
          return 1;
      if (ch == EOF)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fmt_convert_s32_to_s24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L2:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  sar    $0x8,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fmt_convert_s32_to_s24(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] >> 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fmt_convert_s32_to_s24>:
  endbr64
  test   %edx,%edx
  jle    L8
  mov    %edx,%edx
  mov    $0x0,%eax
L6:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L8:
  ret
```

assistant: ```c
void fmt_convert_s32_to_s24(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] >> 8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmt_convert_s32_to_s24>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L5:
  mov    (%rsi,%rax,4),%ecx
  sar    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
L14:
  ret
```

assistant: ```c
void fmt_convert_s32_to_s24(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] >> 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmt_convert_s32_to_s24>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L44
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L35
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L35
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L33:
  movdqu (%rsi,%rax,1),%xmm0
  psrad  $0x8,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L33
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L44
  mov    %eax,%r8d
  mov    (%rsi,%r8,4),%r9d
  lea    0x0(,%r8,4),%rdi
  sar    $0x8,%r9d
  mov    %r9d,(%rcx,%r8,4)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%edx
  jle    L44
  mov    0x4(%rsi,%rdi,1),%r8d
  add    $0x2,%eax
  sar    $0x8,%r8d
  mov    %r8d,0x4(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L44
  mov    0x8(%rsi,%rdi,1),%eax
  sar    $0x8,%eax
  mov    %eax,0x8(%rcx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L30:
  mov    (%rsi,%rax,4),%edi
  sar    $0x8,%edi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L30
L44:
  ret
```

assistant: ```c
void fmt_convert_s32_to_s24(void *dest_v, void *src_v, int n) {
  int32_t *dest = dest_v;
  int32_t *src = src_v;
  int i;
  for (i = 0; i < n; i++)
    dest[i] = (src[i] >> 8);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SKP_Silk_resample_3_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7c0,%rsp
  mov    %rdi,-0x7a8(%rbp)
  mov    %rsi,-0x7b0(%rbp)
  mov    %rdx,-0x7b8(%rbp)
  mov    %ecx,-0x7bc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L26
L13:
  mov    -0x7bc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x50,%edi
  call   <SKP_min_int@plt>
  mov    %eax,-0x798(%rbp)
  mov    -0x798(%rbp),%eax
  movswl %ax,%edx
  mov    -0x798(%rbp),%eax
  cwtl
  shl    $0xf,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x794(%rbp)
  mov    -0x798(%rbp),%ecx
  mov    -0x7b8(%rbp),%rdx
  mov    -0x7b0(%rbp),%rsi
  lea    -0x790(%rbp),%rax
  mov    %rax,%rdi
  call   <SKP_Silk_resample_3_1@plt>
  mov    -0x7b0(%rbp),%rax
  lea    0x1c(%rax),%rsi
  mov    -0x794(%rbp),%edi
  lea    -0x5b0(%rbp),%rcx
  mov    -0x7a8(%rbp),%rdx
  lea    -0x790(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <SKP_Silk_resample_1_2_coarse@plt>
  mov    -0x798(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x7b8(%rbp)
  mov    -0x794(%rbp),%eax
  cltq
  add    %rax,%rax
  add    %rax,-0x7a8(%rbp)
  mov    -0x798(%rbp),%eax
  sub    %eax,-0x7bc(%rbp)
L26:
  cmpl   $0x0,-0x7bc(%rbp)
  jg     L13
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void SKP_Silk_resample_3_2(short *out, int *S, const short *in, int inLen) {
  int LSubFrameIn, LSubFrameOut;
  short outH[3 * 80];
  int scratch[(9 * 80) / 2];
  ;
  while (inLen > 0) {
    LSubFrameIn = SKP_min_int(80, inLen);
    LSubFrameOut = ((((98304) >> 16) * (int)((short)(LSubFrameIn))) + ((((98304) & 0x0000FFFF) * (int)((short)(LSubFrameIn))) >> 16));
    SKP_Silk_resample_3_1(outH, &S[0], in, LSubFrameIn);
    SKP_Silk_resample_1_2_coarse(outH, &S[7], out, scratch, LSubFrameOut);
    in += LSubFrameIn;
    out += LSubFrameOut;
    inLen -= LSubFrameIn;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SKP_Silk_resample_3_2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x798(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L29
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %ecx,%r12d
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
L19:
  mov    %r12d,%esi
  mov    $0x50,%edi
  call   <SKP_min_int@plt>
  mov    %eax,%ebx
  cwtl
  mov    %eax,%ebp
  sar    %ebp
  add    %eax,%ebp
  mov    %ebx,%ecx
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <SKP_Silk_resample_3_1@plt>
  lea    0x1f0(%rsp),%rcx
  lea    0x1c(%r15),%rsi
  mov    %ebp,%r8d
  mov    %r13,%rdx
  mov    0x8(%rsp),%rdi
  call   <SKP_Silk_resample_1_2_coarse@plt>
  movslq %ebx,%rax
  lea    (%r14,%rax,2),%r14
  movslq %ebp,%rbp
  lea    0x0(%r13,%rbp,2),%r13
  sub    %ebx,%r12d
  test   %r12d,%r12d
  jg     L19
L29:
  mov    0x798(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x7a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SKP_Silk_resample_3_2(short *out, int *S, const short *in, int inLen) {
  int LSubFrameIn, LSubFrameOut;
  short outH[3 * 80];
  int scratch[(9 * 80) / 2];
  ;
  while (inLen > 0) {
    LSubFrameIn = SKP_min_int(80, inLen);
    LSubFrameOut = ((((98304) >> 16) * (int)((short)(LSubFrameIn))) + ((((98304) & 0x0000FFFF) * (int)((short)(LSubFrameIn))) >> 16));
    SKP_Silk_resample_3_1(outH, &S[0], in, LSubFrameIn);
    SKP_Silk_resample_1_2_coarse(outH, &S[7], out, scratch, LSubFrameOut);
    in += LSubFrameIn;
    out += LSubFrameOut;
    inLen -= LSubFrameIn;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SKP_Silk_resample_3_2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7b8,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x7a8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsi),%rax
  mov    %rax,0x8(%rsp)
  lea    0x200(%rsp),%rax
  mov    %rax,0x18(%rsp)
  test   %ecx,%ecx
  jle    L19
  mov    %rdi,%r12
  mov    %rdx,%rbp
  lea    0x20(%rsp),%r13
  mov    %ecx,%r15d
  nopl   (%rax)
L25:
  mov    %r15d,%esi
  mov    $0x50,%edi
  call   <SKP_min_int@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %r13,%rdi
  mov    %eax,%r14d
  cwtl
  mov    %eax,%ebx
  mov    %r14d,%ecx
  sub    %r14d,%r15d
  sar    %ebx
  add    %eax,%ebx
  call   <SKP_Silk_resample_3_1@plt>
  mov    0x18(%rsp),%rcx
  mov    %ebx,%r8d
  mov    %r12,%rdx
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  movslq %ebx,%rbx
  lea    (%r12,%rbx,2),%r12
  call   <SKP_Silk_resample_1_2_coarse@plt>
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,2),%rbp
  test   %r15d,%r15d
  jg     L25
L19:
  mov    0x7a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x7b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SKP_Silk_resample_3_2(short *out, int *S, const short *in, int inLen) {
  int LSubFrameIn, LSubFrameOut;
  short outH[3 * 80];
  int scratch[(9 * 80) / 2];
  ;
  while (inLen > 0) {
    LSubFrameIn = SKP_min_int(80, inLen);
    LSubFrameOut = ((((98304) >> 16) * (int)((short)(LSubFrameIn))) + ((((98304) & 0x0000FFFF) * (int)((short)(LSubFrameIn))) >> 16));
    SKP_Silk_resample_3_1(outH, &S[0], in, LSubFrameIn);
    SKP_Silk_resample_1_2_coarse(outH, &S[7], out, scratch, LSubFrameOut);
    in += LSubFrameIn;
    out += LSubFrameOut;
    inLen -= LSubFrameIn;
  }
}
```