ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bspline3>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%edi
  comisd D14(%rip),%xmm0
  jb     L0
  movapd %xmm0,%xmm3
  movsd  D48(%rip),%xmm0
  comisd %xmm3,%xmm0
  setae  %dil
  movzbl %dil,%edi
L0:
  call   <__CPROVER_assume@plt>
  movsd  0x8(%rsp),%xmm1
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  xorpd  D30(%rip),%xmm0
  divsd  D40(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%edi
  comisd D1(%rip),%xmm0
  jb     L9
  movsd  D0(%rip),%xmm0
  comisd %xmm2,%xmm0
  setae  %dil
  movzbl %dil,%edi
L9:
  lea    D24(%rip),%rsi
  call   <__CPROVER_assert@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
type: f64
name: parse_data
arguments: data_tag: D48
type: f64
name: parse_data
arguments: data_tag: D30
type: byte[16]
name: parse_data
arguments: data_tag: D40
type: f64
name: parse_data
arguments: data_tag: D1
type: byte[16]
name: parse_data
arguments: data_tag: D0
type: f64
name: parse_data
arguments: data_tag: D24
type: string

tool: D14: 0

tool: D48: 1

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D40: 6

tool: {"D1": [0xc3,0xf5,0x28,0x5c,0x8f,0xc2,0xc5,0xbf,0x9a,0x99,0x99,0x99,0x99,0x99,0xa9,0x3f]}

tool: D0: 0.05

tool: D24: postcondition

assistant: ```c
double bspline3(double u) {
  __CPROVER_assume(0.0 <= u && u <= 1.0);
  double res = (-((u * u) * u) / 6.0);
  __CPROVER_assert(-0.17 <= res && res <= 0.05, "postcondition");
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bspline3>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  comisd D33(%rip),%xmm0
  jb     L7
  movsd  D63(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L7:
  movsd  %xmm0,0x8(%rsp)
  call   <__CPROVER_assume@plt>
  movsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  xorpd  D31(%rip),%xmm0
  divsd  D23(%rip),%xmm0
  comisd D66(%rip),%xmm0
  jb     L2
  movsd  D34(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L2:
  lea    D15(%rip),%rsi
  movsd  %xmm0,0x8(%rsp)
  call   <__CPROVER_assert@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D33
datatype: f64
name: unpack_data
arguments: label: D63
datatype: f64
name: unpack_data
arguments: label: D31
datatype: byte[16]
name: unpack_data
arguments: label: D23
datatype: f64
name: unpack_data
arguments: label: D66
datatype: byte[16]
name: unpack_data
arguments: label: D34
datatype: f64
name: unpack_data
arguments: label: D15
datatype: string

tool: D33: 0

tool: D63: 1

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D23: 6

tool: {"D66": [0xc3,0xf5,0x28,0x5c,0x8f,0xc2,0xc5,0xbf,0x9a,0x99,0x99,0x99,0x99,0x99,0xa9,0x3f]}

tool: D34: 0.05

tool: D15: postcondition

assistant: ```c
double bspline3(double u) {
  __CPROVER_assume(0.0 <= u && u <= 1.0);
  double res = (-((u * u) * u) / 6.0);
  __CPROVER_assert(-0.17 <= res && res <= 0.05, "postcondition");
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bspline3>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  comisd D17(%rip),%xmm0
  jb     L15
  movsd  D41(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L15:
  movsd  %xmm0,0x8(%rsp)
  call   <__CPROVER_assume@plt>
  movsd  0x8(%rsp),%xmm0
  xor    %edi,%edi
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  xorpd  D10(%rip),%xmm0
  divsd  D28(%rip),%xmm0
  comisd D1(%rip),%xmm0
  jb     L0
  movsd  D69(%rip),%xmm1
  xor    %edi,%edi
  comisd %xmm0,%xmm1
  setae  %dil
L0:
  lea    D22(%rip),%rsi
  movsd  %xmm0,0x8(%rsp)
  call   <__CPROVER_assert@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_guessed: f64
name: parse_data
arguments: data_label: D41
type_guessed: f64
name: parse_data
arguments: data_label: D10
type_guessed: byte[16]
name: parse_data
arguments: data_label: D28
type_guessed: f64
name: parse_data
arguments: data_label: D1
type_guessed: byte[16]
name: parse_data
arguments: data_label: D69
type_guessed: f64
name: parse_data
arguments: data_label: D22
type_guessed: string

tool: D17: 0

tool: D41: 1

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D28: 6

tool: {"D1": [0xc3,0xf5,0x28,0x5c,0x8f,0xc2,0xc5,0xbf,0x9a,0x99,0x99,0x99,0x99,0x99,0xa9,0x3f]}

tool: D69: 0.05

tool: D22: postcondition

assistant: ```c
double bspline3(double u) {
  __CPROVER_assume(0.0 <= u && u <= 1.0);
  double res = (-((u * u) * u) / 6.0);
  __CPROVER_assert(-0.17 <= res && res <= 0.05, "postcondition");
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x989680,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L27
L4:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  je     L31
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  add    %eax,-0x10(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L4
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: string
name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D13: Enter a number in (01):

tool: D7: %d

tool: D20: Result:%d


tool: D9: pause

assistant: ```c
void main() {
  int number = 10000000, sum = 0, count = 0;
  printf("Enter a number in (01):");
  scanf("%d", &number);
  while (number != 0) {
    if (number % 10) {
      sum += (int)pow(2, count);
    }
    number /= 10;
    count++;
  }
  printf("Result:%d\n", sum);
  system("pause");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x989680,0x4(%rsp)
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L18
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L3
L6:
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  add    $0x1,%ebx
  test   %eax,%eax
  je     L8
L3:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  cmp    %edx,%eax
  je     L6
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  add    %eax,%ebp
  jmp    L6
L18:
  mov    %eax,%ebp
L8:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string

tool: D27: Enter a number in (01):

tool: D0: %d

tool: D1: Result:%d


tool: D36: pause

assistant: ```c
void main() {
  int number = 10000000, sum = 0, count = 0;
  printf("Enter a number in (01):");
  scanf("%d", &number);
  while (number != 0) {
    if (number % 10) {
      sum += (int)pow(2, count);
    }
    number /= 10;
    count++;
  }
  printf("Result:%d\n", sum);
  system("pause");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x989680,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  je     L2
  mov    %edx,%eax
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L16
  nop
L47:
  movslq %edx,%rax
  sar    $0x1f,%edx
  add    $0x1,%ebx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  mov    %eax,%edx
  test   %eax,%eax
  je     L44
L16:
  imul   $0xcccccccd,%eax,%eax
  add    $0x19999998,%eax
  ror    %eax
  cmp    $0x19999998,%eax
  jbe    L47
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    0x4(%rsp),%edx
  add    %eax,%ebp
  jmp    L47
L2:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L44:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D32
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D39
data_type: string

tool: D6: Enter a number in (01):

tool: D32: %d

tool: D2: Result:%d


tool: D39: pause

assistant: ```c
void main() {
  int number = 10000000, sum = 0, count = 0;
  printf("Enter a number in (01):");
  scanf("%d", &number);
  while (number != 0) {
    if (number % 10) {
      sum += (int)pow(2, count);
    }
    number /= 10;
    count++;
  }
  printf("Result:%d\n", sum);
  system("pause");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x989680,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  je     L51
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L15:
  imul   $0xcccccccd,%esi,%eax
  add    $0x19999998,%eax
  ror    %eax
  cmp    $0x19999998,%eax
  ja     L6
  movslq %esi,%rax
  mov    %esi,%edx
  add    $0x1,%ebx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,0x4(%rsp)
  mov    %eax,%esi
  test   %eax,%eax
  jne    L15
L40:
  mov    %ebp,%esi
L51:
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    %ebx,%esi
  mov    $0x2,%edi
  add    $0x1,%ebx
  call   <pow@plt>
  movslq 0x4(%rsp),%rsi
  add    %eax,%ebp
  mov    %rsi,%rax
  imul   $0x66666667,%rsi,%rsi
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jne    L15
  jmp    L40
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D37
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string

tool: D17: Enter a number in (01):

tool: D30: %d

tool: D37: Result:%d


tool: D6: pause

assistant: ```c
void main() {
  int number = 10000000, sum = 0, count = 0;
  printf("Enter a number in (01):");
  scanf("%d", &number);
  while (number != 0) {
    if (number % 10) {
      sum += (int)pow(2, count);
    }
    number /= 10;
    count++;
  }
  printf("Result:%d\n", sum);
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ppMem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdi
  mov    -0x18(%rbp),%rax
  add    %rdi,%rax
  mov    (%rax),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x4,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x18(%rbp),%rax
  movl   $0x121f1e1f,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movl   $0x3,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movl   $0xffffffff,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movl   $0x232f2e2f,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  movl   $0x242c2b2b,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movl   $0x252a2e2b,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1c,%rax
  movl   $0x262d2d2a,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x20,%rax
  movl   $0x3f343f3e,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  movl   $0x3e353d3c,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  movl   $0x363a3c3b,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2c,%rax
  movl   $0x3b373b3a,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movl   $0x454f4e45,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x34,%rax
  movl   $0x4e464d46,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x38,%rax
  movl   $0x474d474c,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x3c,%rax
  movl   $0x4a484a4c,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D3: MEM:

tool: D19: 0x%08x, 0x%08x, 0x%08x, 0x%08x


assistant: ```c
void ppMem(unsigned int *_mem, int _len) {
  int i;
  printf("MEM:\n");
  for (i = 0; i < _len; i = i + 4) {
    printf("0x%08x, 0x%08x, 0x%08x, 0x%08x\n", _mem[i], _mem[i + 1], _mem[i + 2], _mem[i + 3]);
  }
  _mem[0] = 0x121f1e1f;
  _mem[1] = 0;
  _mem[2] = 3;
  _mem[3] = -1;
  _mem[4] = 0x232f2e2f;
  _mem[5] = 0x242c2b2b;
  _mem[6] = 0x252a2e2b;
  _mem[7] = 0x262d2d2a;
  _mem[8] = 0x3f343f3e;
  _mem[9] = 0x3e353d3c;
  _mem[10] = 0x363a3c3b;
  _mem[11] = 0x3b373b3a;
  _mem[12] = 0x454f4e45;
  _mem[13] = 0x4e464d46;
  _mem[14] = 0x474d474c;
  _mem[15] = 0x4a484a4c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ppMem>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    D7(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L19
  mov    %rbp,%rbx
  sub    $0x1,%r12d
  shr    $0x2,%r12d
  mov    %r12d,%r12d
  shl    $0x4,%r12
  lea    0x10(%rbp,%r12,1),%r13
  lea    D16(%rip),%r12
L5:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rbx
  cmp    %r13,%rbx
  jne    L5
L19:
  movl   $0x121f1e1f,0x0(%rbp)
  movl   $0x0,0x4(%rbp)
  movl   $0x3,0x8(%rbp)
  movl   $0xffffffff,0xc(%rbp)
  movl   $0x232f2e2f,0x10(%rbp)
  movl   $0x242c2b2b,0x14(%rbp)
  movl   $0x252a2e2b,0x18(%rbp)
  movl   $0x262d2d2a,0x1c(%rbp)
  movl   $0x3f343f3e,0x20(%rbp)
  movl   $0x3e353d3c,0x24(%rbp)
  movl   $0x363a3c3b,0x28(%rbp)
  movl   $0x3b373b3a,0x2c(%rbp)
  movl   $0x454f4e45,0x30(%rbp)
  movl   $0x4e464d46,0x34(%rbp)
  movl   $0x474d474c,0x38(%rbp)
  movl   $0x4a484a4c,0x3c(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string

tool: D7: MEM:

tool: D16: 0x%08x, 0x%08x, 0x%08x, 0x%08x


assistant: ```c
void ppMem(unsigned int *_mem, int _len) {
  int i;
  printf("MEM:\n");
  for (i = 0; i < _len; i = i + 4) {
    printf("0x%08x, 0x%08x, 0x%08x, 0x%08x\n", _mem[i], _mem[i + 1], _mem[i + 2], _mem[i + 3]);
  }
  _mem[0] = 0x121f1e1f;
  _mem[1] = 0;
  _mem[2] = 3;
  _mem[3] = -1;
  _mem[4] = 0x232f2e2f;
  _mem[5] = 0x242c2b2b;
  _mem[6] = 0x252a2e2b;
  _mem[7] = 0x262d2d2a;
  _mem[8] = 0x3f343f3e;
  _mem[9] = 0x3e353d3c;
  _mem[10] = 0x363a3c3b;
  _mem[11] = 0x3b373b3a;
  _mem[12] = 0x454f4e45;
  _mem[13] = 0x4e464d46;
  _mem[14] = 0x474d474c;
  _mem[15] = 0x4a484a4c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ppMem>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L3
  sub    $0x1,%r12d
  mov    %rbp,%rbx
  shr    $0x2,%r12d
  shl    $0x4,%r12
  lea    0x10(%rbp,%r12,1),%r13
  lea    D8(%rip),%r12
L5:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  add    $0x10,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L5
L3:
  movabs $0xffffffff00000003,%rax
  movq   $0x121f1e1f,0x0(%rbp)
  mov    %rax,0x8(%rbp)
  movabs $0x242c2b2b232f2e2f,%rax
  mov    %rax,0x10(%rbp)
  movabs $0x262d2d2a252a2e2b,%rax
  mov    %rax,0x18(%rbp)
  movabs $0x3e353d3c3f343f3e,%rax
  mov    %rax,0x20(%rbp)
  movabs $0x3b373b3a363a3c3b,%rax
  mov    %rax,0x28(%rbp)
  movabs $0x4e464d46454f4e45,%rax
  mov    %rax,0x30(%rbp)
  movabs $0x4a484a4c474d474c,%rax
  mov    %rax,0x38(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D0: MEM:

tool: D8: 0x%08x, 0x%08x, 0x%08x, 0x%08x


assistant: ```c
void ppMem(unsigned int *_mem, int _len) {
  int i;
  printf("MEM:\n");
  for (i = 0; i < _len; i = i + 4) {
    printf("0x%08x, 0x%08x, 0x%08x, 0x%08x\n", _mem[i], _mem[i + 1], _mem[i + 2], _mem[i + 3]);
  }
  _mem[0] = 0x121f1e1f;
  _mem[1] = 0;
  _mem[2] = 3;
  _mem[3] = -1;
  _mem[4] = 0x232f2e2f;
  _mem[5] = 0x242c2b2b;
  _mem[6] = 0x252a2e2b;
  _mem[7] = 0x262d2d2a;
  _mem[8] = 0x3f343f3e;
  _mem[9] = 0x3e353d3c;
  _mem[10] = 0x363a3c3b;
  _mem[11] = 0x3b373b3a;
  _mem[12] = 0x454f4e45;
  _mem[13] = 0x4e464d46;
  _mem[14] = 0x474d474c;
  _mem[15] = 0x4a484a4c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ppMem>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D13(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L1
  sub    $0x1,%ebp
  mov    %r12,%rbx
  shr    $0x2,%ebp
  shl    $0x4,%rbp
  lea    0x10(%r12,%rbp,1),%r13
  lea    D3(%rip),%rbp
  nopl   0x0(%rax)
L12:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    0xc(%rbx),%r8d
  mov    (%rbx),%esi
  add    $0x10,%rbx
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L12
L1:
  movdqa D54(%rip),%xmm0
  movups %xmm0,(%r12)
  movdqa D58(%rip),%xmm0
  movups %xmm0,0x10(%r12)
  movdqa D35(%rip),%xmm0
  movups %xmm0,0x20(%r12)
  movdqa D23(%rip),%xmm0
  movups %xmm0,0x30(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D54
data_type: byte[16]
name: retrieve_data
arguments: data_label: D58
data_type: byte[16]
name: retrieve_data
arguments: data_label: D35
data_type: byte[16]
name: retrieve_data
arguments: data_label: D23
data_type: byte[16]

tool: D13: MEM:

tool: D3: 0x%08x, 0x%08x, 0x%08x, 0x%08x


tool: {"D54": [0x1f,0x1e,0x1f,0x12,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0xff,0xff,0xff,0xff]}

tool: {"D58": [0x2f,0x2e,0x2f,0x23,0x2b,0x2b,0x2c,0x24,0x2b,0x2e,0x2a,0x25,0x2a,0x2d,0x2d,0x26]}

tool: {"D35": [0x3e,0x3f,0x34,0x3f,0x3c,0x3d,0x35,0x3e,0x3b,0x3c,0x3a,0x36,0x3a,0x3b,0x37,0x3b]}

tool: {"D23": [0x45,0x4e,0x4f,0x45,0x46,0x4d,0x46,0x4e,0x4c,0x47,0x4d,0x47,0x4c,0x4a,0x48,0x4a]}

assistant: ```c
void ppMem(unsigned int *_mem, int _len) {
  int i;
  printf("MEM:\n");
  for (i = 0; i < _len; i = i + 4) {
    printf("0x%08x, 0x%08x, 0x%08x, 0x%08x\n", _mem[i], _mem[i + 1], _mem[i + 2], _mem[i + 3]);
  }
  _mem[0] = 0x121f1e1f;
  _mem[1] = 0;
  _mem[2] = 3;
  _mem[3] = -1;
  _mem[4] = 0x232f2e2f;
  _mem[5] = 0x242c2b2b;
  _mem[6] = 0x252a2e2b;
  _mem[7] = 0x262d2d2a;
  _mem[8] = 0x3f343f3e;
  _mem[9] = 0x3e353d3c;
  _mem[10] = 0x363a3c3b;
  _mem[11] = 0x3b373b3a;
  _mem[12] = 0x454f4e45;
  _mem[13] = 0x4e464d46;
  _mem[14] = 0x474d474c;
  _mem[15] = 0x4a484a4c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CrossProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mulss  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void CrossProduct(const float v1[3], const float v2[3], float result[3]) {
  result[0] = v1[1] * v2[2] - v2[1] * v1[2];
  result[1] = v2[0] * v1[2] - v1[0] * v2[2];
  result[2] = v1[0] * v2[1] - v2[0] * v1[1];
}
```