ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binarySearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L49
L41:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L36
  mov    -0x4(%rbp),%eax
  jmp    L0
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L13
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L49
L13:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L41
L0:
  pop    %rbp
  ret
```

assistant: ```c
int binarySearch(int *a, int n, int k) {
  int beg = 0, end = n - 1;
  int mid;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == k) {
      return mid;
    } else if (a[mid] < k) {
      beg = mid + 1;
    } else {
      end = mid - 1;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<binarySearch>:
  endbr64
  sub    $0x1,%esi
  js     L45
  mov    $0x0,%r8d
  jmp    L8
L39:
  lea    -0x1(%rax),%esi
L55:
  cmp    %esi,%r8d
  jg     L45
L8:
  lea    (%r8,%rsi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %edx,%ecx
  je     L45
  jge    L39
  lea    0x1(%rax),%r8d
  jmp    L55
L45:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int binarySearch(int *a, int n, int k) {
  int beg = 0, end = n - 1;
  int mid;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == k) {
      return mid;
    } else if (a[mid] < k) {
      beg = mid + 1;
    } else {
      end = mid - 1;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binarySearch>:
  endbr64
  sub    $0x1,%esi
  js     L8
  xor    %ecx,%ecx
  jmp    L18
  nopl   (%rax)
L30:
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jl     L8
L18:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L8
  jl     L30
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L18
L8:
  ret
```

assistant: ```c
int binarySearch(int *a, int n, int k) {
  int beg = 0, end = n - 1;
  int mid;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == k) {
      return mid;
    } else if (a[mid] < k) {
      beg = mid + 1;
    } else {
      end = mid - 1;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<binarySearch>:
  endbr64
  sub    $0x1,%esi
  js     L29
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  lea    (%rcx,%rsi,1),%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %edx,(%rdi,%r8,4)
  je     L29
  jge    L23
  lea    0x1(%rax),%ecx
  cmp    %esi,%ecx
  jle    L2
L29:
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  lea    -0x1(%rax),%esi
  cmp    %ecx,%esi
  jge    L2
  ret
```

assistant: ```c
int binarySearch(int *a, int n, int k) {
  int beg = 0, end = n - 1;
  int mid;
  while (beg <= end) {
    mid = (beg + end) / 2;
    if (a[mid] == k) {
      return mid;
    } else if (a[mid] < k) {
      beg = mid + 1;
    } else {
      end = mid - 1;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__progname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  addq   $0x1,-0x8(%rbp)
  jmp    L1
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *__progname(char *nargv0) {
  char *tmp = strrchr(nargv0, '/');
  if (tmp)
    tmp++;
  else
    tmp = nargv0;
  return (tmp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__progname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *__progname(char *nargv0) {
  char *tmp = strrchr(nargv0, '/');
  if (tmp)
    tmp++;
  else
    tmp = nargv0;
  return (tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__progname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *__progname(char *nargv0) {
  char *tmp = strrchr(nargv0, '/');
  if (tmp)
    tmp++;
  else
    tmp = nargv0;
  return (tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__progname>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *__progname(char *nargv0) {
  char *tmp = strrchr(nargv0, '/');
  if (tmp)
    tmp++;
  else
    tmp = nargv0;
  return (tmp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<eb_unesc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    $0x64,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L36
L21:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa9,%al
  jne    L71
  movl   $0x1,-0x74(%rbp)
  jmp    L94
L71:
  cmpl   $0x1,-0x74(%rbp)
  jne    L69
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L80
  mov    -0x7c(%rbp),%eax
  cltq
  movb   $0xaa,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x7c(%rbp)
  jmp    L68
L80:
  mov    -0x7c(%rbp),%eax
  cltq
  movb   $0xa9,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x7c(%rbp)
L68:
  movl   $0x0,-0x74(%rbp)
  jmp    L94
L69:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x7c(%rbp)
L94:
  addl   $0x1,-0x78(%rbp)
L36:
  mov    -0x90(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x78(%rbp)
  jl     L21
  mov    -0x88(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L66
L60:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rax,%rdx
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x78(%rbp)
L66:
  mov    -0x78(%rbp),%eax
  cmp    -0x7c(%rbp),%eax
  jl     L60
  mov    -0x90(%rbp),%rax
  mov    -0x7c(%rbp),%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

assistant: ```c
void eb_unesc(unsigned char *buf, int *buflen) {
  unsigned char tmp[100];
  int tmplen, i, found;
  memset(tmp, '\0', sizeof(tmp));
  i = 0;
  tmplen = 0;
  found = 0;
  while (i < *buflen) {
    if (buf[i] == 0xA9) {
      found = 1;
    } else if (found == 1) {
      if (buf[i] == 0x01) {
        tmp[tmplen] = 0xAA;
        tmplen++;
      } else {
        tmp[tmplen] = 0xA9;
        tmplen++;
      }
      found = 0;
    } else {
      tmp[tmplen] = buf[i];
      tmplen++;
    }
    i++;
  }
  memset(buf, '\0', sizeof(buf));
  for (i = 0; i < tmplen; i++)
    buf[i] = tmp[i];
  *buflen = tmplen;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<eb_unesc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x64,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    (%r12),%edx
  test   %edx,%edx
  jle    L74
  mov    %rbp,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rbp,%rdx,1),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%ebx
  mov    $0x1,%r8d
  mov    $0x0,%r9d
  jmp    L11
L124:
  cmp    $0x1,%dl
  je     L120
  movslq %ebx,%rdx
  movb   $0xa9,(%rsp,%rdx,1)
  add    $0x1,%ebx
  mov    %r9d,%ecx
  jmp    L63
L120:
  movslq %ebx,%rdx
  movb   $0xaa,(%rsp,%rdx,1)
  add    $0x1,%ebx
  mov    %r9d,%ecx
  jmp    L63
L13:
  mov    %r8d,%ecx
L63:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L0
L11:
  movzbl (%rax),%edx
  cmp    $0xa9,%dl
  je     L13
  cmp    $0x1,%ecx
  je     L124
  movslq %ebx,%rdi
  mov    %dl,(%rsp,%rdi,1)
  add    $0x1,%ebx
  jmp    L63
L0:
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  jle    L111
  mov    %ebx,%ecx
  mov    $0x0,%eax
L109:
  movzbl (%rsp,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L109
L111:
  mov    %ebx,(%r12)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L74:
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x0,%ebx
  jmp    L111
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eb_unesc(unsigned char *buf, int *buflen) {
  unsigned char tmp[100];
  int tmplen, i, found;
  memset(tmp, '\0', sizeof(tmp));
  i = 0;
  tmplen = 0;
  found = 0;
  while (i < *buflen) {
    if (buf[i] == 0xA9) {
      found = 1;
    } else if (found == 1) {
      if (buf[i] == 0x01) {
        tmp[tmplen] = 0xAA;
        tmplen++;
      } else {
        tmp[tmplen] = 0xA9;
        tmplen++;
      }
      found = 0;
    } else {
      tmp[tmplen] = buf[i];
      tmplen++;
    }
    i++;
  }
  memset(buf, '\0', sizeof(buf));
  for (i = 0; i < tmplen; i++)
    buf[i] = tmp[i];
  *buflen = tmplen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eb_unesc>:
  endbr64
  push   %r13
  mov    $0x64,%edx
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  jle    L13
  sub    $0x1,%edx
  mov    %r13,%rax
  xor    %ecx,%ecx
  xor    %ebx,%ebx
  lea    0x1(%r13,%rdx,1),%rdi
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L107:
  lea    0x1(%rbx),%esi
  cmp    $0x1,%ecx
  je     L38
  mov    %dl,(%rsp,%rbx,1)
  movslq %esi,%rbx
L88:
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L67
L7:
  movzbl (%rax),%edx
  cmp    $0xa9,%dl
  jne    L107
  add    $0x1,%rax
  mov    $0x1,%ecx
  cmp    %rax,%rdi
  jne    L7
L67:
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L96
  movslq %ebx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
L96:
  mov    %ebx,0x0(%rbp)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L38:
  cmp    $0x1,%dl
  je     L66
  movb   $0xa9,(%rsp,%rbx,1)
  xor    %ecx,%ecx
  movslq %esi,%rbx
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L66:
  movb   $0xaa,(%rsp,%rbx,1)
  xor    %ecx,%ecx
  movslq %esi,%rbx
  jmp    L88
  xchg   %ax,%ax
L13:
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %ebx,%ebx
  call   <memset@plt>
  jmp    L96
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eb_unesc(unsigned char *buf, int *buflen) {
  unsigned char tmp[100];
  int tmplen, i, found;
  memset(tmp, '\0', sizeof(tmp));
  i = 0;
  tmplen = 0;
  found = 0;
  while (i < *buflen) {
    if (buf[i] == 0xA9) {
      found = 1;
    } else if (found == 1) {
      if (buf[i] == 0x01) {
        tmp[tmplen] = 0xAA;
        tmplen++;
      } else {
        tmp[tmplen] = 0xA9;
        tmplen++;
      }
      found = 0;
    } else {
      tmp[tmplen] = buf[i];
      tmplen++;
    }
    i++;
  }
  memset(buf, '\0', sizeof(buf));
  for (i = 0; i < tmplen; i++)
    buf[i] = tmp[i];
  *buflen = tmplen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eb_unesc>:
  endbr64
  push   %r13
  mov    $0x64,%edx
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  jle    L27
  sub    $0x1,%edx
  mov    %r13,%rax
  xor    %ecx,%ecx
  xor    %ebx,%ebx
  lea    0x1(%r13,%rdx,1),%rdi
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L17:
  lea    0x1(%rbx),%esi
  cmp    $0x1,%ecx
  je     L113
  mov    %dl,(%rsp,%rbx,1)
  movslq %esi,%rbx
L97:
  add    $0x1,%rax
  cmp    %rax,%rdi
  je     L108
L56:
  movzbl (%rax),%edx
  cmp    $0xa9,%dl
  jne    L17
  add    $0x1,%rax
  mov    $0x1,%ecx
  cmp    %rax,%rdi
  jne    L56
L108:
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L15
  movslq %ebx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
L15:
  mov    %ebx,0x0(%rbp)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L113:
  cmp    $0x1,%dl
  je     L80
  movb   $0xa9,(%rsp,%rbx,1)
  xor    %ecx,%ecx
  movslq %esi,%rbx
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L80:
  movb   $0xaa,(%rsp,%rbx,1)
  xor    %ecx,%ecx
  movslq %esi,%rbx
  jmp    L97
  xchg   %ax,%ax
L27:
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %ebx,%ebx
  call   <memset@plt>
  jmp    L15
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eb_unesc(unsigned char *buf, int *buflen) {
  unsigned char tmp[100];
  int tmplen, i, found;
  memset(tmp, '\0', sizeof(tmp));
  i = 0;
  tmplen = 0;
  found = 0;
  while (i < *buflen) {
    if (buf[i] == 0xA9) {
      found = 1;
    } else if (found == 1) {
      if (buf[i] == 0x01) {
        tmp[tmplen] = 0xAA;
        tmplen++;
      } else {
        tmp[tmplen] = 0xA9;
        tmplen++;
      }
      found = 0;
    } else {
      tmp[tmplen] = buf[i];
      tmplen++;
    }
    i++;
  }
  memset(buf, '\0', sizeof(buf));
  for (i = 0; i < tmplen; i++)
    buf[i] = tmp[i];
  *buflen = tmplen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fails>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fails(void *data) {
  errno = ECANCELED;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fails>:
  endbr64
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fails(void *data) {
  errno = ECANCELED;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fails>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fails(void *data) {
  errno = ECANCELED;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fails>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fails(void *data) {
  errno = ECANCELED;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix_scale_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  movss  %xmm0,-0x5c(%rbp)
  movss  %xmm1,-0x60(%rbp)
  movss  %xmm2,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x64(%rbp),%xmm1
  movss  -0x60(%rbp),%xmm0
  mov    -0x5c(%rbp),%edx
  lea    -0x50(%rbp),%rax
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <matrix_get_scale@plt>
  mov    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matrix_multiply_ext@plt>
  mov    -0x70(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
float *matrix_scale_ext(const float matrix[4 * 4], const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_scale(matrix_tmp, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix_scale_ext>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <matrix_get_scale@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    %rbx,%rax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_scale_ext(const float matrix[4 * 4], const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_scale(matrix_tmp, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<matrix_scale_ext>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <matrix_get_scale@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_scale_ext(const float matrix[4 * 4], const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_scale(matrix_tmp, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix_scale_ext>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <matrix_get_scale@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <matrix_multiply_ext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float *matrix_scale_ext(const float matrix[4 * 4], const float x, const float y, const float z, float matrix_out[4 * 4]) {
  float matrix_tmp[4 * 4];
  matrix_get_scale(matrix_tmp, x, y, z);
  matrix_multiply_ext(matrix, matrix_tmp, matrix_out);
  return matrix_out;
}
```
user: What is the c source code of the assembly code below?

```asm
<utf8_strwidth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L20
L23:
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <utf8_tounicode@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <utf8_width@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  subl   $0x1,-0x2c(%rbp)
L20:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L23
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int utf8_strwidth(const char *str, int charlen) {
  int width = 0;
  while (charlen) {
    int c;
    int l = utf8_tounicode(str, &c);
    width += utf8_width(c);
    str += l;
    charlen--;
  }
  return width;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utf8_strwidth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L22
  mov    %rdi,%r12
  mov    $0x0,%r13d
  lea    0x4(%rsp),%r14
L18:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <utf8_tounicode@plt>
  mov    %eax,%ebx
  mov    0x4(%rsp),%edi
  call   <utf8_width@plt>
  add    %eax,%r13d
  movslq %ebx,%rbx
  add    %rbx,%r12
  sub    $0x1,%ebp
  jne    L18
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %r13d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    %esi,%r13d
  jmp    L12
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_strwidth(const char *str, int charlen) {
  int width = 0;
  while (charlen) {
    int c;
    int l = utf8_tounicode(str, &c);
    width += utf8_width(c);
    str += l;
    charlen--;
  }
  return width;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utf8_strwidth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L32
  mov    %rdi,%r14
  mov    %esi,%ebp
  lea    0x4(%rsp),%r13
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L0:
  mov    %r14,%rdi
  mov    %r13,%rsi
  call   <utf8_tounicode@plt>
  mov    0x4(%rsp),%edi
  movslq %eax,%rbx
  call   <utf8_width@plt>
  add    %rbx,%r14
  add    %eax,%r12d
  sub    $0x1,%ebp
  jne    L0
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %r12d,%r12d
  jmp    L4
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int utf8_strwidth(const char *str, int charlen) {
  int width = 0;
  while (charlen) {
    int c;
    int l = utf8_tounicode(str, &c);
    width += utf8_width(c);
    str += l;
    charlen--;
  }
  return width;
}
```