ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    D21(%rip),%r12
  lea    0xc(%rsp),%rbp
  lea    D26(%rip),%rbx
L10:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x4e,%eax
  ja     L10
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <leVETOR@plt>
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <quadradoVETOR@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x160,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string

tool: D21: Introduza o n de inteiros a ler: 

tool: D26: %d

tool: D2: %d


assistant: ```c
int main() {
  int vetor[80], n = 0;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  leVETOR(vetor, n);
  quadradoVETOR(vetor, n);
  printf("%d\n", vetor[n - 1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  nopl   (%rax)
L0:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x4e,%eax
  ja     L0
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <leVETOR@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <quadradoVETOR@plt>
  mov    0xc(%rsp),%eax
  lea    D3(%rip),%rdi
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D25: Introduza o n de inteiros a ler: 

tool: D2: %d

tool: D3: %d


assistant: ```c
int main() {
  int vetor[80], n = 0;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  leVETOR(vetor, n);
  quadradoVETOR(vetor, n);
  printf("%d\n", vetor[n - 1]);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x158(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  nopl   (%rax)
L17:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  lea    -0x1(%rsi),%eax
  cmp    $0x4e,%eax
  ja     L17
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <leVETOR@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <quadradoVETOR@plt>
  mov    0xc(%rsp),%eax
  lea    D24(%rip),%rdi
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x158(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x160,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D24
datatype: string

tool: D29: Introduza o n de inteiros a ler: 

tool: D19: %d

tool: D24: %d


assistant: ```c
int main() {
  int vetor[80], n = 0;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  leVETOR(vetor, n);
  quadradoVETOR(vetor, n);
  printf("%d\n", vetor[n - 1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<string_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L35
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L19
L35:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L26:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  mov    -0x10(%rbp),%eax
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: string_count: length of s == 0


assistant: ```c
int string_count(char *str, char *s) {
  char *ptr;
  int num, len;
  if ((len = strlen(s)) == 0) {
    printf("string_count: length of s == 0\n");
    return 0;
  }
  ptr = str;
  for (num = 0; (ptr = strstr(ptr, s)) != NULL; num++)
    ptr += len;
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_count>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    $0x0,%ebp
  movslq %eax,%r13
  test   %eax,%eax
  jne    L15
  mov    %eax,%r14d
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r14d,%ebp
  jmp    L7
L13:
  lea    (%rax,%r13,1),%rbx
  add    $0x1,%ebp
L15:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L13
L7:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: string_count: length of s == 0


assistant: ```c
int string_count(char *str, char *s) {
  char *ptr;
  int num, len;
  if ((len = strlen(s)) == 0) {
    printf("string_count: length of s == 0\n");
    return 0;
  }
  ptr = str;
  for (num = 0; (ptr = strstr(ptr, s)) != NULL; num++)
    ptr += len;
  return num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_count>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%r13
  test   %eax,%eax
  jne    L9
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L1:
  lea    (%rax,%r13,1),%rbp
  add    $0x1,%r12d
L9:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: string_count: length of s == 0


assistant: ```c
int string_count(char *str, char *s) {
  char *ptr;
  int num, len;
  if ((len = strlen(s)) == 0) {
    printf("string_count: length of s == 0\n");
    return 0;
  }
  ptr = str;
  for (num = 0; (ptr = strstr(ptr, s)) != NULL; num++)
    ptr += len;
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_count>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%r13
  test   %eax,%eax
  jne    L20
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L3:
  lea    (%rax,%r13,1),%rbp
  add    $0x1,%r12d
L20:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: string_count: length of s == 0


assistant: ```c
int string_count(char *str, char *s) {
  char *ptr;
  int num, len;
  if ((len = strlen(s)) == 0) {
    printf("string_count: length of s == 0\n");
    return 0;
  }
  ptr = str;
  for (num = 0; (ptr = strstr(ptr, s)) != NULL; num++)
    ptr += len;
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_balance_after_removal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x50(%rbp)
  movl   $0x37,-0x30(%rbp)
  movl   $0x21,-0x2c(%rbp)
  movl   $0x52,-0x28(%rbp)
  movl   $0x2f,-0x24(%rbp)
  movl   $0x1b,-0x20(%rbp)
  movl   $0x56,-0x1c(%rbp)
  movl   $0x45,-0x18(%rbp)
  movl   $0x19,-0x14(%rbp)
  movl   $0x3b,-0x10(%rbp)
  movq   $0x0,-0x48(%rbp)
  jmp    L5
L36:
  mov    -0x48(%rbp),%rax
  mov    -0x30(%rbp,%rax,4),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  addq   $0x1,-0x48(%rbp)
L5:
  cmpq   $0x8,-0x48(%rbp)
  jbe    L36
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <test_tree_properties@plt>
  movl   $0x37,-0x38(%rbp)
  movl   $0x1b,-0x34(%rbp)
  movq   $0x0,-0x40(%rbp)
  jmp    L23
L15:
  mov    -0x40(%rbp),%rax
  mov    -0x38(%rbp,%rax,4),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <remove_node@plt>
  addq   $0x1,-0x40(%rbp)
L23:
  cmpq   $0x1,-0x40(%rbp)
  jbe    L15
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <test_tree_properties@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <free_tree@plt>
  movq   $0x0,-0x50(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
void test_balance_after_removal() {
  struct Node *root = NULL;
  int items[] = {55, 33, 82, 47, 27, 86, 69, 25, 59};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {55, 27};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_balance_after_removal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x37,0x10(%rsp)
  movl   $0x21,0x14(%rsp)
  movl   $0x52,0x18(%rsp)
  movl   $0x2f,0x1c(%rsp)
  movl   $0x1b,0x20(%rsp)
  movl   $0x56,0x24(%rsp)
  movl   $0x45,0x28(%rsp)
  movl   $0x19,0x2c(%rsp)
  movl   $0x3b,0x30(%rsp)
  lea    0x10(%rsp),%rbx
  lea    0x34(%rsp),%r12
  lea    0x8(%rsp),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <insert@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L7
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  lea    0x8(%rsp),%rbx
  mov    $0x37,%esi
  mov    %rbx,%rdi
  call   <remove_node@plt>
  mov    $0x1b,%esi
  mov    %rbx,%rdi
  call   <remove_node@plt>
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_balance_after_removal() {
  struct Node *root = NULL;
  int items[] = {55, 33, 82, 47, 27, 86, 69, 25, 59};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {55, 27};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_balance_after_removal>:
  endbr64
  push   %r12
  mov    $0x37,%esi
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbx
  lea    0x34(%rsp),%r12
  movabs $0x5200000021,%rax
  mov    %rax,0x14(%rsp)
  lea    0x8(%rsp),%rbp
  movabs $0x1b0000002f,%rax
  mov    %rax,0x1c(%rsp)
  movabs $0x4500000056,%rax
  mov    %rax,0x24(%rsp)
  movabs $0x3b00000019,%rax
  movq   $0x0,0x8(%rsp)
  mov    %rax,0x2c(%rsp)
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L18:
  mov    %rbp,%rdi
  call   <insert@plt>
  cmp    %rbx,%r12
  jne    L7
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    $0x37,%esi
  mov    %rbp,%rdi
  call   <remove_node@plt>
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  call   <remove_node@plt>
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_balance_after_removal() {
  struct Node *root = NULL;
  int items[] = {55, 33, 82, 47, 27, 86, 69, 25, 59};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {55, 27};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_balance_after_removal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0x34(%rsp),%r12
  movq   $0x0,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D11(%rip),%xmm0
  lea    0x8(%rsp),%rbp
  movl   $0x3b,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <insert@plt>
  cmp    %rbx,%r12
  jne    L17
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    $0x37,%esi
  mov    %rbp,%rdi
  call   <remove_node@plt>
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  call   <remove_node@plt>
  mov    0x8(%rsp),%rdi
  call   <test_tree_properties@plt>
  mov    0x8(%rsp),%rdi
  call   <free_tree@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D11
type_guessed: byte[16]

tool: {"D6": [0x37,0x00,0x00,0x00,0x21,0x00,0x00,0x00,0x52,0x00,0x00,0x00,0x2f,0x00,0x00,0x00]}

tool: {"D11": [0x1b,0x00,0x00,0x00,0x56,0x00,0x00,0x00,0x45,0x00,0x00,0x00,0x19,0x00,0x00,0x00]}

assistant: ```c
void test_balance_after_removal() {
  struct Node *root = NULL;
  int items[] = {55, 33, 82, 47, 27, 86, 69, 25, 59};
  for (size_t i = 0; i < sizeof(items) / sizeof(items[0]); i++) {
    insert(&root, items[i]);
  };
  test_tree_properties(root);
  int removable[] = {55, 27};
  for (size_t i = 0; i < sizeof(removable) / sizeof(removable[0]); i++) {
    remove_node(&root, removable[i]);
  };
  test_tree_properties(root);
  free_tree(root);
  root = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_value_from_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L78
  mov    $0xfffffffd,%eax
  jmp    L21
L78:
  movl   $0xffffffff,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L16
L48:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L62
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x50(%rbp),%rdx
  sub    $0x1,%rdx
  cmp    %rdx,%rax
  jbe    L52
  movl   $0xfffffffe,-0x24(%rbp)
  jmp    L17
L52:
  mov    -0x8(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L17
L62:
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x20(%rbp)
L16:
  cmpq   $0x0,-0x20(%rbp)
  jne    L48
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x24(%rbp),%eax
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: &,


assistant: ```c
int get_value_from_response(const char *buf, const char *key, char *retbuf, size_t retbuflen) {
  int ret;
  char *tokens, *kv_pair;
  size_t keylen = strlen(key);
  tokens = strdup(buf);
  if (tokens == NULL)
    return -3;
  ret = -1;
  kv_pair = strtok(tokens, "&,\r\n");
  for (; kv_pair != NULL; kv_pair = strtok(NULL, "&,\r\n")) {
    if (strncmp(key, kv_pair, keylen) == 0) {
      char *val = &kv_pair[keylen];
      if (strlen(val) > retbuflen - 1) {
        ret = -2;
      } else {
        strcpy(retbuf, val);
        ret = 1;
      }
      break;
    }
  }
  free(tokens);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_value_from_response>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%r15
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strdup@plt>
  test   %rax,%rax
  je     L33
  mov    %rax,%r14
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  lea    D4(%rip),%r13
L38:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L40
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L38
  mov    $0xffffffff,%ebp
L22:
  mov    %r14,%rdi
  call   <free@plt>
L12:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  add    %r12,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%r15
  mov    $0xfffffffe,%ebp
  cmp    %r15,%rax
  ja     L22
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <strcpy@plt>
  mov    $0x1,%ebp
  jmp    L22
L14:
  mov    $0xffffffff,%ebp
  jmp    L22
L33:
  mov    $0xfffffffd,%ebp
  jmp    L12
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: &,


assistant: ```c
int get_value_from_response(const char *buf, const char *key, char *retbuf, size_t retbuflen) {
  int ret;
  char *tokens, *kv_pair;
  size_t keylen = strlen(key);
  tokens = strdup(buf);
  if (tokens == NULL)
    return -3;
  ret = -1;
  kv_pair = strtok(tokens, "&,\r\n");
  for (; kv_pair != NULL; kv_pair = strtok(NULL, "&,\r\n")) {
    if (strncmp(key, kv_pair, keylen) == 0) {
      char *val = &kv_pair[keylen];
      if (strlen(val) > retbuflen - 1) {
        ret = -2;
      } else {
        strcpy(retbuf, val);
        ret = 1;
      }
      break;
    }
  }
  free(tokens);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_value_from_response>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strdup@plt>
  test   %rax,%rax
  je     L35
  lea    D3(%rip),%r12
  mov    %rax,%rdi
  mov    %rax,%r13
  mov    %r12,%rsi
  call   <strtok@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L77
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L73
L77:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L75
  add    %r15,%rbp
  sub    $0x1,%r14
  mov    $0xfffffffe,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r14,%rax
  ja     L55
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  mov    $0x1,%r12d
  call   <strcpy@plt>
  jmp    L55
  nopl   0x0(%rax)
L73:
  mov    $0xffffffff,%r12d
L55:
  mov    %r13,%rdi
  call   <free@plt>
L50:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  mov    $0xfffffffd,%r12d
  jmp    L50
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: string

tool: D3: &,


assistant: ```c
int get_value_from_response(const char *buf, const char *key, char *retbuf, size_t retbuflen) {
  int ret;
  char *tokens, *kv_pair;
  size_t keylen = strlen(key);
  tokens = strdup(buf);
  if (tokens == NULL)
    return -3;
  ret = -1;
  kv_pair = strtok(tokens, "&,\r\n");
  for (; kv_pair != NULL; kv_pair = strtok(NULL, "&,\r\n")) {
    if (strncmp(key, kv_pair, keylen) == 0) {
      char *val = &kv_pair[keylen];
      if (strlen(val) > retbuflen - 1) {
        ret = -2;
      } else {
        strcpy(retbuf, val);
        ret = 1;
      }
      break;
    }
  }
  free(tokens);
  return ret;
}
```