ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fconf_readkv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L34
  mov    $0xffffffff,%eax
  jmp    L47
L34:
  mov    -0x18(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L40
  mov    $0xfffffffe,%eax
  jmp    L47
L40:
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <trim@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
  mov    $0xfffffffd,%eax
  jmp    L47
L41:
  mov    $0x0,%eax
L47:
  leave
  ret
```

assistant: ```c
int fconf_readkv(char *line, char **key, char **value) {
  *key = NULL;
  *value = NULL;
  size_t lenofline = strlen(line);
  if (lenofline == 0) {
    return -1;
  }
  char *loc = strchr(line, '=');
  if (!loc) {
    return -2;
  }
  *key = line;
  *value = loc + 1;
  *loc = '\0';
  *key = trim(*key);
  *value = trim(*value);
  if (strchr(*key, ' ')) {
    return -3;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fconf_readkv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  call   <strlen@plt>
  test   %rax,%rax
  je     L16
  mov    $0x3d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  mov    %r12,(%rbx)
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    (%rbx),%rdi
  call   <trim@plt>
  mov    %rax,(%rbx)
  mov    0x0(%rbp),%rdi
  call   <trim@plt>
  mov    %rax,0x0(%rbp)
  mov    $0x20,%esi
  mov    (%rbx),%rdi
  call   <strchr@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L9
L8:
  mov    $0xfffffffe,%eax
  jmp    L9
```

assistant: ```c
int fconf_readkv(char *line, char **key, char **value) {
  *key = NULL;
  *value = NULL;
  size_t lenofline = strlen(line);
  if (lenofline == 0) {
    return -1;
  }
  char *loc = strchr(line, '=');
  if (!loc) {
    return -2;
  }
  *key = line;
  *value = loc + 1;
  *loc = '\0';
  *key = trim(*key);
  *value = trim(*value);
  if (strchr(*key, ' ')) {
    return -3;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fconf_readkv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    $0x3d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  lea    0x1(%rax),%rdx
  mov    %r12,(%rbx)
  mov    %rdx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    (%rbx),%rdi
  call   <trim@plt>
  mov    %rax,(%rbx)
  mov    0x0(%rbp),%rdi
  call   <trim@plt>
  mov    $0x20,%esi
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdi
  call   <strchr@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
  jmp    L1
L19:
  mov    $0xfffffffe,%eax
  jmp    L1
```

assistant: ```c
int fconf_readkv(char *line, char **key, char **value) {
  *key = NULL;
  *value = NULL;
  size_t lenofline = strlen(line);
  if (lenofline == 0) {
    return -1;
  }
  char *loc = strchr(line, '=');
  if (!loc) {
    return -2;
  }
  *key = line;
  *value = loc + 1;
  *loc = '\0';
  *key = trim(*key);
  *value = trim(*value);
  if (strchr(*key, ' ')) {
    return -3;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fconf_readkv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdx)
  call   <strlen@plt>
  test   %rax,%rax
  je     L25
  mov    $0x3d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
  lea    0x1(%rax),%rdx
  mov    %r12,(%rbx)
  mov    %rdx,0x0(%rbp)
  movb   $0x0,(%rax)
  mov    (%rbx),%rdi
  call   <trim@plt>
  mov    %rax,(%rbx)
  mov    0x0(%rbp),%rdi
  call   <trim@plt>
  mov    $0x20,%esi
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdi
  call   <strchr@plt>
  neg    %rax
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffff,%eax
  jmp    L18
L16:
  mov    $0xfffffffe,%eax
  jmp    L18
```

assistant: ```c
int fconf_readkv(char *line, char **key, char **value) {
  *key = NULL;
  *value = NULL;
  size_t lenofline = strlen(line);
  if (lenofline == 0) {
    return -1;
  }
  char *loc = strchr(line, '=');
  if (!loc) {
    return -2;
  }
  *key = line;
  *value = loc + 1;
  *loc = '\0';
  *key = trim(*key);
  *value = trim(*value);
  if (strchr(*key, ' ')) {
    return -3;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L18
  movl   $0x1,-0x4(%rbp)
  negl   -0x14(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L30
L20:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L30:
  cmpl   $0x0,-0x14(%rbp)
  jne    L20
  cmpl   $0x1,-0x4(%rbp)
  jne    L34
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L34:
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  jmp    L31
L36:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L31:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jne    L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void itoa(int i, char *str, int c) {
  int d = c;
  int flag = 0;
  if (i < 0) {
    flag = 1;
    i *= -1;
  }
  str[c--] = '\0';
  while (i != 0) {
    str[c--] = i % 10 + '0';
    i /= 10;
  }
  if (flag == 1) {
    str[c--] = '-';
  }
  d -= c;
  while (d--) {
    str[i++] = str[i + c + 1];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itoa>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%r8
  mov    %edx,%r9d
  test   %edi,%edi
  js     L42
  lea    -0x1(%rdx),%edi
  movslq %edx,%rax
  movb   $0x0,(%rsi,%rax,1)
  je     L46
  mov    $0x0,%r10d
L8:
  lea    -0x1(%rdi),%edx
  movslq %edx,%rdx
L31:
  mov    %edx,%edi
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,0x1(%r8,%rdx,1)
  mov    %eax,%ecx
  sub    $0x1,%rdx
  test   %eax,%eax
  jne    L31
  cmp    $0x1,%r10d
  je     L41
L46:
  sub    %edi,%r9d
  je     L54
  mov    %r8,%rax
  lea    -0x1(%r9),%edx
  lea    0x1(%r8,%rdx,1),%rcx
  movslq %edi,%rdi
L15:
  movzbl 0x1(%rax,%rdi,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L15
L54:
  ret
L42:
  neg    %ecx
  lea    -0x1(%rdx),%edi
  movslq %edx,%rax
  movb   $0x0,(%rsi,%rax,1)
  mov    $0x1,%r10d
  jmp    L8
L41:
  movslq %edi,%rax
  movb   $0x2d,(%r8,%rax,1)
  lea    -0x1(%rdi),%edi
  jmp    L46
```

assistant: ```c
void itoa(int i, char *str, int c) {
  int d = c;
  int flag = 0;
  if (i < 0) {
    flag = 1;
    i *= -1;
  }
  str[c--] = '\0';
  while (i != 0) {
    str[c--] = i % 10 + '0';
    i /= 10;
  }
  if (flag == 1) {
    str[c--] = '-';
  }
  d -= c;
  while (d--) {
    str[i++] = str[i + c + 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<itoa>:
  endbr64
  movslq %edx,%rdx
  mov    %rsi,%rcx
  mov    %edi,%eax
  mov    %rdx,%r10
  lea    -0x1(%rdx),%esi
  add    %rcx,%rdx
  test   %eax,%eax
  js     L83
  movb   $0x0,(%rdx)
  mov    $0x0,%r11d
  je     L35
L25:
  movslq %esi,%r8
  push   %rbx
  mov    $0xcccccccd,%ebx
  add    %rcx,%r8
  nopl   0x0(%rax)
L87:
  mov    %eax,%edx
  mov    %esi,%r9d
  sub    $0x1,%r8
  sub    $0x1,%esi
  imul   %rbx,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  sub    %edi,%eax
  add    $0x30,%eax
  mov    %al,0x1(%r8)
  mov    %edx,%eax
  test   %edx,%edx
  jne    L87
  cmp    $0x1,%r11d
  je     L15
  sub    %esi,%r10d
  lea    -0x1(%r10),%eax
L88:
  test   %r10d,%r10d
  je     L45
  lea    0x1(%rcx,%rax,1),%rdi
  mov    %rcx,%rdx
  movslq %esi,%rax
  nopl   (%rax)
L30:
  movzbl 0x1(%rdx,%rax,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L30
L45:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  movb   $0x0,(%rdx)
  neg    %eax
  mov    $0x1,%r11d
  jmp    L25
  nopl   (%rax)
L15:
  sub    $0x2,%r9d
  movslq %esi,%rax
  sub    %r9d,%r10d
  movb   $0x2d,(%rcx,%rax,1)
  mov    %r9d,%esi
  lea    -0x1(%r10),%eax
  jmp    L88
L35:
  lea    0x1(%rcx,%rax,1),%rdi
  mov    %rcx,%rdx
  movslq %esi,%rax
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl 0x1(%rdx,%rax,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L16
  ret
```

assistant: ```c
void itoa(int i, char *str, int c) {
  int d = c;
  int flag = 0;
  if (i < 0) {
    flag = 1;
    i *= -1;
  }
  str[c--] = '\0';
  while (i != 0) {
    str[c--] = i % 10 + '0';
    i /= 10;
  }
  if (flag == 1) {
    str[c--] = '-';
  }
  d -= c;
  while (d--) {
    str[i++] = str[i + c + 1];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  mov    $0x28,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: add(40,2) = %u


assistant: ```c
int main() {
  printf("add(40,2) = %u\n", add(40, 2));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x28,%edi
  call   <add@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: add(40,2) = %u


assistant: ```c
int main() {
  printf("add(40,2) = %u\n", add(40, 2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x28,%edi
  call   <add@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: add(40,2) = %u


assistant: ```c
int main() {
  printf("add(40,2) = %u\n", add(40, 2));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x28,%edi
  call   <add@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: add(40,2) = %u


assistant: ```c
int main() {
  printf("add(40,2) = %u\n", add(40, 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x58,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc4(%rbp),%eax
  imul   %eax,%eax
  mov    -0xc4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xb4(%rbp)
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int f(int y, ...) {
  int f = y * y * y;
  return f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %edi,%eax
  ret
```

assistant: ```c
int f(int y, ...) {
  int f = y * y * y;
  return f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %edi,%eax
  ret
```

assistant: ```c
int f(int y, ...) {
  int f = y * y * y;
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  mov    %edi,%eax
  imul   %edi,%eax
  imul   %edi,%eax
  ret
```

assistant: ```c
int f(int y, ...) {
  int f = y * y * y;
  return f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_div_df_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__builtin_vsx_xstdivdp_fg@plt>
  test   %rax,%rax
  je     L5
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movl   $0x1,(%rax)
L5:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *test_div_df_3(double a, double b, int *p) {
  if (__builtin_vsx_xstdivdp_fg(a, b))
    *p++ = 1;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_div_df_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <__builtin_vsx_xstdivdp_fg@plt>
  test   %rax,%rax
  je     L7
  movl   $0x1,(%rbx)
  lea    0x4(%rbx),%rbx
L7:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *test_div_df_3(double a, double b, int *p) {
  if (__builtin_vsx_xstdivdp_fg(a, b))
    *p++ = 1;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_div_df_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L2
  movl   $0x1,(%rbx)
  add    $0x4,%rax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int *test_div_df_3(double a, double b, int *p) {
  if (__builtin_vsx_xstdivdp_fg(a, b))
    *p++ = 1;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_div_df_3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <__builtin_vsx_xstdivdp_fg@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L2
  movl   $0x1,(%rbx)
  add    $0x4,%rax
L2:
  pop    %rbx
  ret
```

assistant: ```c
int *test_div_df_3(double a, double b, int *p) {
  if (__builtin_vsx_xstdivdp_fg(a, b))
    *p++ = 1;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isfluid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xc,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  and    -0x14(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int isfluid(int flag) {
  int ret = pow(2, 12);
  return ((flag & (3 * ret)) == ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isfluid>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xc,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    (%rax,%rax,2),%edi
  and    %ebx,%edi
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isfluid(int flag) {
  int ret = pow(2, 12);
  return ((flag & (3 * ret)) == ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isfluid>:
  endbr64
  push   %rbx
  mov    $0xc,%esi
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <pow@plt>
  lea    (%rax,%rax,2),%edi
  and    %ebx,%edi
  pop    %rbx
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isfluid(int flag) {
  int ret = pow(2, 12);
  return ((flag & (3 * ret)) == ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isfluid>:
  endbr64
  push   %rbx
  mov    $0xc,%esi
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <pow@plt>
  lea    (%rax,%rax,2),%edi
  and    %ebx,%edi
  pop    %rbx
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isfluid(int flag) {
  int ret = pow(2, 12);
  return ((flag & (3 * ret)) == ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L35:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L38
  mov    -0x4(%rbp),%eax
  jmp    L23
L38:
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0xf,-0x4(%rbp)
  jle    L35
  mov    $0xffffffff,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int get_index(int *table, int number) {
  int i;
  for (i = 0; i < 16; i++)
    if (table[i] == number)
      return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_index>:
  endbr64
  mov    $0x0,%eax
L17:
  mov    %eax,%edx
  cmp    %esi,(%rdi,%rax,4)
  je     L8
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L17
  mov    $0xffffffff,%edx
L8:
  mov    %edx,%eax
  ret
```

assistant: ```c
int get_index(int *table, int number) {
  int i;
  for (i = 0; i < 16; i++)
    if (table[i] == number)
      return i;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_index>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %eax,%r8d
  cmp    %esi,(%rdi,%rax,4)
  je     L16
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L2
  mov    $0xffffffff,%r8d
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_index(int *table, int number) {
  int i;
  for (i = 0; i < 16; i++)
    if (table[i] == number)
      return i;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_index>:
  endbr64
  cmp    (%rdi),%esi
  je     L71
  cmp    0x4(%rdi),%esi
  je     L6
  cmp    0x8(%rdi),%esi
  je     L74
  cmp    0xc(%rdi),%esi
  je     L110
  cmp    0x10(%rdi),%esi
  je     L15
  cmp    0x14(%rdi),%esi
  je     L4
  cmp    0x18(%rdi),%esi
  je     L5
  cmp    0x1c(%rdi),%esi
  je     L80
  cmp    0x20(%rdi),%esi
  je     L72
  cmp    0x24(%rdi),%esi
  je     L90
  cmp    0x28(%rdi),%esi
  je     L129
  cmp    0x2c(%rdi),%esi
  je     L143
  cmp    0x30(%rdi),%esi
  je     L41
  cmp    0x34(%rdi),%esi
  je     L128
  cmp    0x38(%rdi),%esi
  je     L136
  cmp    %esi,0x3c(%rdi)
  mov    $0xf,%edx
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
L71:
  xor    %eax,%eax
  ret
L6:
  mov    $0x1,%eax
  ret
L41:
  mov    $0xc,%eax
  ret
L74:
  mov    $0x2,%eax
  ret
L110:
  mov    $0x3,%eax
  ret
L15:
  mov    $0x4,%eax
  ret
L4:
  mov    $0x5,%eax
  ret
L5:
  mov    $0x6,%eax
  ret
L80:
  mov    $0x7,%eax
  ret
L72:
  mov    $0x8,%eax
  ret
L90:
  mov    $0x9,%eax
  ret
L129:
  mov    $0xa,%eax
  ret
L143:
  mov    $0xb,%eax
  ret
L128:
  mov    $0xd,%eax
  ret
L136:
  mov    $0xe,%eax
  ret
```

assistant: ```c
int get_index(int *table, int number) {
  int i;
  for (i = 0; i < 16; i++)
    if (table[i] == number)
      return i;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<elf_exchange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L15:
  addl   $0x1,-0x8(%rbp)
  sarl   -0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  or     $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int elf_exchange(int n) {
  int b = 0;
  int t = n;
  while (t != 0) {
    b++;
    t >>= 1;
  }
  n = n ^ (0x1 << (b - 1));
  n = (n << 1) | 0x1;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<elf_exchange>:
  endbr64
  test   %edi,%edi
  je     L10
  mov    %edi,%edx
  mov    $0x0,%ecx
L3:
  add    $0x1,%ecx
  sar    %edx
  jne    L3
L6:
  sub    $0x1,%ecx
  btc    %ecx,%edi
  lea    0x1(%rdi,%rdi,1),%eax
  ret
L10:
  mov    %edi,%ecx
  jmp    L6
```

assistant: ```c
int elf_exchange(int n) {
  int b = 0;
  int t = n;
  while (t != 0) {
    b++;
    t >>= 1;
  }
  n = n ^ (0x1 << (b - 1));
  n = (n << 1) | 0x1;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<elf_exchange>:
  endbr64
  test   %edi,%edi
  je     L0
  mov    %edi,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax)
L14:
  mov    %edx,%eax
  add    $0x1,%edx
  sar    %ecx
  jne    L14
  btc    %eax,%edi
  lea    0x1(%rdi,%rdi,1),%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  btc    %eax,%edi
  lea    0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int elf_exchange(int n) {
  int b = 0;
  int t = n;
  while (t != 0) {
    b++;
    t >>= 1;
  }
  n = n ^ (0x1 << (b - 1));
  n = (n << 1) | 0x1;
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<elf_exchange>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    %edi,%ecx
  xor    %edx,%edx
  nopl   0x0(%rax)
L15:
  mov    %edx,%eax
  add    $0x1,%edx
  sar    %ecx
  jne    L15
  btc    %eax,%edi
  lea    0x1(%rdi,%rdi,1),%eax
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%eax
  btc    %eax,%edi
  lea    0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int elf_exchange(int n) {
  int b = 0;
  int t = n;
  while (t != 0) {
    b++;
    t >>= 1;
  }
  n = n ^ (0x1 << (b - 1));
  n = (n << 1) | 0x1;
  return n;
}
```