ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<comp128>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    $0x10,%edx
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x7,%ebx
  sub    $0x298,%rsp
  lea    0x40(%rsp),%rdi
  mov    %rsp,%rbp
  lea    0x80(%rsp),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x288(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
L4:
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <_comp128_compression@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_comp128_bitsfrombytes@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_comp128_permutation@plt>
  sub    $0x1,%ebx
  jne    L4
  mov    $0x10,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <_comp128_compression@plt>
  movdqa (%rsp),%xmm2
  mov    0x70(%rsp),%ecx
  movd   0x60(%rsp),%xmm4
  movd   0x50(%rsp),%xmm5
  movdqa %xmm2,%xmm0
  shufps $0x88,0x10(%rsp),%xmm0
  pslld  $0x4,%xmm0
  shufps $0xdd,0x10(%rsp),%xmm2
  por    %xmm2,%xmm0
  movd   0x58(%rsp),%xmm2
  movd   0x5c(%rsp),%xmm3
  mov    %ecx,%edx
  movups %xmm0,(%r15)
  movd   0x48(%rsp),%xmm0
  movd   0x64(%rsp),%xmm6
  sar    $0x2,%edx
  punpckldq %xmm4,%xmm2
  movd   0x54(%rsp),%xmm7
  movdqa 0x60(%rsp),%xmm1
  shl    $0x6,%ecx
  punpckldq %xmm5,%xmm0
  punpckldq %xmm6,%xmm3
  mov    0x6c(%rsp),%eax
  movl   $0x0,0x1c(%r14)
  punpcklqdq %xmm2,%xmm0
  movd   0x4c(%rsp),%xmm2
  pslld  $0x6,%xmm0
  shl    $0x2,%eax
  punpckldq %xmm7,%xmm2
  or     %eax,%edx
  punpcklqdq %xmm3,%xmm2
  pslld  $0x2,%xmm2
  por    %xmm2,%xmm0
  movdqa 0x50(%rsp),%xmm2
  shufps $0x88,%xmm1,%xmm2
  punpckhdq %xmm1,%xmm1
  psrad  $0x2,%xmm2
  movd   %xmm1,%eax
  por    %xmm2,%xmm0
  shl    $0x6,%eax
  movups %xmm0,(%r14)
  or     %edx,%eax
  mov    0x78(%rsp),%edx
  mov    %eax,0x10(%r14)
  mov    0x74(%rsp),%eax
  shl    $0x2,%eax
  or     %ecx,%eax
  mov    %edx,%ecx
  shl    $0x6,%edx
  sar    $0x2,%ecx
  or     %ecx,%eax
  mov    %eax,0x14(%r14)
  mov    0x7c(%rsp),%eax
  shl    $0x2,%eax
  or     %edx,%eax
  mov    %eax,0x18(%r14)
  mov    0x288(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x298,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void comp128(uint8_t *ki, uint8_t *rand, uint8_t *sres, uint8_t *kc) {
  int i;
  uint8_t x[32], bits[128];
  memcpy(&x[16], rand, 16);
  for (i = 0; i < 7; i++) {
    memcpy(x, ki, 16);
    _comp128_compression(x);
    _comp128_bitsfrombytes(x, bits);
    _comp128_permutation(x, bits);
  }
  memcpy(x, ki, 16);
  _comp128_compression(x);
  for (i = 0; i < 8; i += 2)
    sres[i >> 1] = x[i] << 4 | x[i + 1];
  for (i = 0; i < 12; i += 2)
    kc[i >> 1] = (x[i + 18] << 6) | (x[i + 19] << 2) | (x[i + 20] >> 2);
  kc[6] = (x[30] << 6) | (x[31] << 2);
  kc[7] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L16:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0xa,-0xd(%rbp)
  jne    L10
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L28
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L16
L28:
  leave
  ret
```

assistant: ```c
char *getStr() {
  int len = 1;
  char inp;
  char *output = malloc(sizeof(char));
  while (1) {
    inp = getchar();
    if (inp == '\n') {
      *(output + len - 1) = '\0';
      return output;
    } else {
      *(output + len - 1) = inp;
      len++;
      output = realloc(output, len);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getStr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%ebp
  jmp    L16
L6:
  mov    %al,(%rbx,%rbp,1)
  lea    0x2(%rbp),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  add    $0x1,%rbp
L16:
  lea    0x1(%rbp),%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L6
  movslq %r12d,%r12
  movb   $0x0,-0x1(%rbx,%r12,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getStr() {
  int len = 1;
  char inp;
  char *output = malloc(sizeof(char));
  while (1) {
    inp = getchar();
    if (inp == '\n') {
      *(output + len - 1) = '\0';
      return output;
    } else {
      *(output + len - 1) = inp;
      len++;
      output = realloc(output, len);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getStr>:
  endbr64
  push   %rbp
  mov    $0x1,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %al,(%rdx)
  mov    %rbp,%rdi
  lea    0x1(%rbx),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L14:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x0(%rbp,%rbx,1),%rdx
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L13
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getStr() {
  int len = 1;
  char inp;
  char *output = malloc(sizeof(char));
  while (1) {
    inp = getchar();
    if (inp == '\n') {
      *(output + len - 1) = '\0';
      return output;
    } else {
      *(output + len - 1) = inp;
      len++;
      output = realloc(output, len);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getStr>:
  endbr64
  push   %rbp
  mov    $0x1,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %al,(%rdx)
  mov    %rbp,%rdi
  lea    0x1(%rbx),%esi
  call   <realloc@plt>
  mov    %rax,%rbp
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    0x0(%rbp,%rbx,1),%rdx
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L13
  movb   $0x0,(%rdx)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *getStr() {
  int len = 1;
  char inp;
  char *output = malloc(sizeof(char));
  while (1) {
    inp = getchar();
    if (inp == '\n') {
      *(output + len - 1) = '\0';
      return output;
    } else {
      *(output + len - 1) = inp;
      len++;
      output = realloc(output, len);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<first_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3f,-0x110(%rbp)
  movl   $0x0,-0x10c(%rbp)
  movl   $0x3a,-0x108(%rbp)
  movl   $0x1,-0x104(%rbp)
  movl   $0x3b,-0x100(%rbp)
  movl   $0x2f,-0xfc(%rbp)
  movl   $0x35,-0xf8(%rbp)
  movl   $0x2,-0xf4(%rbp)
  movl   $0x3c,-0xf0(%rbp)
  movl   $0x27,-0xec(%rbp)
  movl   $0x30,-0xe8(%rbp)
  movl   $0x1b,-0xe4(%rbp)
  movl   $0x36,-0xe0(%rbp)
  movl   $0x21,-0xdc(%rbp)
  movl   $0x2a,-0xd8(%rbp)
  movl   $0x3,-0xd4(%rbp)
  movl   $0x3d,-0xd0(%rbp)
  movl   $0x33,-0xcc(%rbp)
  movl   $0x25,-0xc8(%rbp)
  movl   $0x28,-0xc4(%rbp)
  movl   $0x31,-0xc0(%rbp)
  movl   $0x12,-0xbc(%rbp)
  movl   $0x1c,-0xb8(%rbp)
  movl   $0x14,-0xb4(%rbp)
  movl   $0x37,-0xb0(%rbp)
  movl   $0x1e,-0xac(%rbp)
  movl   $0x22,-0xa8(%rbp)
  movl   $0xb,-0xa4(%rbp)
  movl   $0x2b,-0xa0(%rbp)
  movl   $0xe,-0x9c(%rbp)
  movl   $0x16,-0x98(%rbp)
  movl   $0x4,-0x94(%rbp)
  movl   $0x3e,-0x90(%rbp)
  movl   $0x39,-0x8c(%rbp)
  movl   $0x2e,-0x88(%rbp)
  movl   $0x34,-0x84(%rbp)
  movl   $0x26,-0x80(%rbp)
  movl   $0x1a,-0x7c(%rbp)
  movl   $0x20,-0x78(%rbp)
  movl   $0x29,-0x74(%rbp)
  movl   $0x32,-0x70(%rbp)
  movl   $0x24,-0x6c(%rbp)
  movl   $0x11,-0x68(%rbp)
  movl   $0x13,-0x64(%rbp)
  movl   $0x1d,-0x60(%rbp)
  movl   $0xa,-0x5c(%rbp)
  movl   $0xd,-0x58(%rbp)
  movl   $0x15,-0x54(%rbp)
  movl   $0x38,-0x50(%rbp)
  movl   $0x2d,-0x4c(%rbp)
  movl   $0x19,-0x48(%rbp)
  movl   $0x1f,-0x44(%rbp)
  movl   $0x23,-0x40(%rbp)
  movl   $0x10,-0x3c(%rbp)
  movl   $0x9,-0x38(%rbp)
  movl   $0xc,-0x34(%rbp)
  movl   $0x2c,-0x30(%rbp)
  movl   $0x18,-0x2c(%rbp)
  movl   $0xf,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0x17,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  mov    -0x118(%rbp),%rax
  neg    %rax
  and    -0x118(%rbp),%rax
  movabs $0x7edd5e59a4e28c2,%rdx
  imul   %rdx,%rax
  shr    $0x3a,%rax
  mov    -0x110(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int first_bit(unsigned long long b) {
  const int magic[64] = {63, 0, 58, 1, 59, 47, 53, 2, 60, 39, 48, 27, 54, 33, 42, 3, 61, 51, 37, 40, 49, 18, 28, 20, 55, 30, 34, 11, 43, 14, 22, 4, 62, 57, 46, 52, 38, 26, 32, 41, 50, 36, 17, 19, 29, 10, 13, 21, 56, 45, 25, 31, 35, 16, 9, 12, 44, 24, 15, 8, 23, 7, 6, 5};
  return magic[((b & (-b)) * 0x07EDD5E59A4E28C2ULL) >> 58];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<first_bit>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movl   $0x3f,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x3a,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x3b,0x10(%rsp)
  movl   $0x2f,0x14(%rsp)
  movl   $0x35,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0x3c,0x20(%rsp)
  movl   $0x27,0x24(%rsp)
  movl   $0x30,0x28(%rsp)
  movl   $0x1b,0x2c(%rsp)
  movl   $0x36,0x30(%rsp)
  movl   $0x21,0x34(%rsp)
  movl   $0x2a,0x38(%rsp)
  movl   $0x3,0x3c(%rsp)
  movl   $0x3d,0x40(%rsp)
  movl   $0x33,0x44(%rsp)
  movl   $0x25,0x48(%rsp)
  movl   $0x28,0x4c(%rsp)
  movl   $0x31,0x50(%rsp)
  movl   $0x12,0x54(%rsp)
  movl   $0x1c,0x58(%rsp)
  movl   $0x14,0x5c(%rsp)
  movl   $0x37,0x60(%rsp)
  movl   $0x1e,0x64(%rsp)
  movl   $0x22,0x68(%rsp)
  movl   $0xb,0x6c(%rsp)
  movl   $0x2b,0x70(%rsp)
  movl   $0xe,0x74(%rsp)
  movl   $0x16,0x78(%rsp)
  movl   $0x4,0x7c(%rsp)
  movl   $0x3e,0x80(%rsp)
  movl   $0x39,0x84(%rsp)
  movl   $0x2e,0x88(%rsp)
  movl   $0x34,0x8c(%rsp)
  movl   $0x26,0x90(%rsp)
  movl   $0x1a,0x94(%rsp)
  movl   $0x20,0x98(%rsp)
  movl   $0x29,0x9c(%rsp)
  movl   $0x32,0xa0(%rsp)
  movl   $0x24,0xa4(%rsp)
  movl   $0x11,0xa8(%rsp)
  movl   $0x13,0xac(%rsp)
  movl   $0x1d,0xb0(%rsp)
  movl   $0xa,0xb4(%rsp)
  movl   $0xd,0xb8(%rsp)
  movl   $0x15,0xbc(%rsp)
  movl   $0x38,0xc0(%rsp)
  movl   $0x2d,0xc4(%rsp)
  movl   $0x19,0xc8(%rsp)
  movl   $0x1f,0xcc(%rsp)
  movl   $0x23,0xd0(%rsp)
  movl   $0x10,0xd4(%rsp)
  movl   $0x9,0xd8(%rsp)
  movl   $0xc,0xdc(%rsp)
  movl   $0x2c,0xe0(%rsp)
  movl   $0x18,0xe4(%rsp)
  movl   $0xf,0xe8(%rsp)
  movl   $0x8,0xec(%rsp)
  movl   $0x17,0xf0(%rsp)
  movl   $0x7,0xf4(%rsp)
  movl   $0x6,0xf8(%rsp)
  movl   $0x5,0xfc(%rsp)
  mov    %rdi,%rax
  neg    %rax
  and    %rdi,%rax
  movabs $0x7edd5e59a4e28c2,%rdx
  imul   %rdx,%rax
  shr    $0x3a,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x118,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int first_bit(unsigned long long b) {
  const int magic[64] = {63, 0, 58, 1, 59, 47, 53, 2, 60, 39, 48, 27, 54, 33, 42, 3, 61, 51, 37, 40, 49, 18, 28, 20, 55, 30, 34, 11, 43, 14, 22, 4, 62, 57, 46, 52, 38, 26, 32, 41, 50, 36, 17, 19, 29, 10, 13, 21, 56, 45, 25, 31, 35, 16, 9, 12, 44, 24, 15, 8, 23, 7, 6, 5};
  return magic[((b & (-b)) * 0x07EDD5E59A4E28C2ULL) >> 58];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<first_bit>:
  endbr64
  sub    $0x118,%rsp
  movabs $0x7edd5e59a4e28c2,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x3f,(%rsp)
  movabs $0x10000003a,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2f0000003b,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000035,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x270000003c,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x1b00000030,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2100000036,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x30000002a,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x330000003d,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x2800000025,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x1200000031,%rax
  mov    %rax,0x50(%rsp)
  movabs $0x140000001c,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x1e00000037,%rax
  mov    %rax,0x60(%rsp)
  movabs $0xb00000022,%rax
  mov    %rax,0x68(%rsp)
  movabs $0xe0000002b,%rax
  mov    %rax,0x70(%rsp)
  movabs $0x400000016,%rax
  mov    %rax,0x78(%rsp)
  movabs $0x390000003e,%rax
  mov    %rax,0x80(%rsp)
  movabs $0x340000002e,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x1a00000026,%rax
  mov    %rax,0x90(%rsp)
  movabs $0x2900000020,%rax
  mov    %rax,0x98(%rsp)
  movabs $0x2400000032,%rax
  mov    %rax,0xa0(%rsp)
  movabs $0x1300000011,%rax
  mov    %rax,0xa8(%rsp)
  movabs $0xa0000001d,%rax
  mov    %rax,0xb0(%rsp)
  movabs $0x150000000d,%rax
  mov    %rax,0xb8(%rsp)
  movabs $0x2d00000038,%rax
  mov    %rax,0xc0(%rsp)
  movabs $0x1f00000019,%rax
  mov    %rax,0xc8(%rsp)
  movabs $0x1000000023,%rax
  mov    %rax,0xd0(%rsp)
  movabs $0xc00000009,%rax
  mov    %rax,0xd8(%rsp)
  movabs $0x180000002c,%rax
  mov    %rax,0xe0(%rsp)
  movabs $0x80000000f,%rax
  mov    %rax,0xe8(%rsp)
  movabs $0x700000017,%rax
  mov    %rax,0xf0(%rsp)
  movabs $0x500000006,%rax
  mov    %rax,0xf8(%rsp)
  mov    %rdi,%rax
  neg    %rax
  and    %rdi,%rax
  imul   %rdx,%rax
  shr    $0x3a,%rax
  mov    (%rsp,%rax,4),%eax
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x118,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int first_bit(unsigned long long b) {
  const int magic[64] = {63, 0, 58, 1, 59, 47, 53, 2, 60, 39, 48, 27, 54, 33, 42, 3, 61, 51, 37, 40, 49, 18, 28, 20, 55, 30, 34, 11, 43, 14, 22, 4, 62, 57, 46, 52, 38, 26, 32, 41, 50, 36, 17, 19, 29, 10, 13, 21, 56, 45, 25, 31, 35, 16, 9, 12, 44, 24, 15, 8, 23, 7, 6, 5};
  return magic[((b & (-b)) * 0x07EDD5E59A4E28C2ULL) >> 58];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delete_index_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <iv_header@plt>
  mov    %eax,%edi
  call   <safe_free@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void delete_index_vector(int32_t *v) {
  if (v != NULL) {
    safe_free(iv_header(v));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<delete_index_vector>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <iv_header@plt>
  mov    %eax,%edi
  call   <safe_free@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void delete_index_vector(int32_t *v) {
  if (v != NULL) {
    safe_free(iv_header(v));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delete_index_vector>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   <iv_header@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <safe_free@plt>
  nopl   (%rax)
L6:
  ret
```

assistant: ```c
void delete_index_vector(int32_t *v) {
  if (v != NULL) {
    safe_free(iv_header(v));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<delete_index_vector>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <iv_header@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <safe_free@plt>
  nopl   (%rax)
L9:
  ret
```

assistant: ```c
void delete_index_vector(int32_t *v) {
  if (v != NULL) {
    safe_free(iv_header(v));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thread_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execl@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread_func(void *arg) {
  char *exename = arg;
  execl(exename, exename, NULL);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *arg) {
  char *exename = arg;
  execl(exename, exename, NULL);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *arg) {
  char *exename = arg;
  execl(exename, exename, NULL);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thread_func>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_func(void *arg) {
  char *exename = arg;
  execl(exename, exename, NULL);
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<driveWithLogic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movss  %xmm1,-0x24(%rbp)
  movss  %xmm2,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xfffffff1,-0xc(%rbp)
  jl     L12
  cmpl   $0xf,-0xc(%rbp)
  jg     L12
  movl   $0x0,-0xc(%rbp)
L12:
  cmpl   $0xfffffff1,-0x8(%rbp)
  jl     L43
  cmpl   $0xf,-0x8(%rbp)
  jg     L43
  movl   $0x0,-0x8(%rbp)
L43:
  cmpl   $0xfffffff1,-0x4(%rbp)
  jl     L44
  cmpl   $0xf,-0x4(%rbp)
  jg     L44
  movl   $0x0,-0x4(%rbp)
L44:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <drive@plt>
  nop
  leave
  ret
```

assistant: ```c
void driveWithLogic(int speedForward, int speedTurn, int speedStrafe, float forwardMultiplier, float turnMultiplier, float strafeMultiplier) {
  int multipliedSpeedForward = speedForward;
  int multipliedSpeedTurn = speedTurn;
  int multipliedSpeedStrafe = speedStrafe;
  if (abs(multipliedSpeedForward) <= 15)
    multipliedSpeedForward = 0;
  if (abs(multipliedSpeedTurn) <= 15)
    multipliedSpeedTurn = 0;
  if (abs(multipliedSpeedStrafe) <= 15)
    multipliedSpeedStrafe = 0;
  drive(multipliedSpeedForward, multipliedSpeedTurn, multipliedSpeedStrafe);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<driveWithLogic>:
  endbr64
  sub    $0x8,%rsp
  lea    0xf(%rdi),%eax
  cmp    $0x1e,%eax
  mov    $0x0,%eax
  cmovbe %eax,%edi
  lea    0xf(%rsi),%eax
  cmp    $0x1e,%eax
  mov    $0x0,%eax
  cmovbe %eax,%esi
  lea    0xf(%rdx),%eax
  cmp    $0x1e,%eax
  mov    $0x0,%eax
  cmovbe %eax,%edx
  call   <drive@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void driveWithLogic(int speedForward, int speedTurn, int speedStrafe, float forwardMultiplier, float turnMultiplier, float strafeMultiplier) {
  int multipliedSpeedForward = speedForward;
  int multipliedSpeedTurn = speedTurn;
  int multipliedSpeedStrafe = speedStrafe;
  if (abs(multipliedSpeedForward) <= 15)
    multipliedSpeedForward = 0;
  if (abs(multipliedSpeedTurn) <= 15)
    multipliedSpeedTurn = 0;
  if (abs(multipliedSpeedStrafe) <= 15)
    multipliedSpeedStrafe = 0;
  drive(multipliedSpeedForward, multipliedSpeedTurn, multipliedSpeedStrafe);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<driveWithLogic>:
  endbr64
  lea    0xf(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x1e,%ecx
  lea    0xf(%rsi),%ecx
  cmovbe %eax,%edi
  cmp    $0x1e,%ecx
  lea    0xf(%rdx),%ecx
  cmovbe %eax,%esi
  cmp    $0x1e,%ecx
  cmovbe %eax,%edx
  jmp    1050 <drive@plt>
```

assistant: ```c
void driveWithLogic(int speedForward, int speedTurn, int speedStrafe, float forwardMultiplier, float turnMultiplier, float strafeMultiplier) {
  int multipliedSpeedForward = speedForward;
  int multipliedSpeedTurn = speedTurn;
  int multipliedSpeedStrafe = speedStrafe;
  if (abs(multipliedSpeedForward) <= 15)
    multipliedSpeedForward = 0;
  if (abs(multipliedSpeedTurn) <= 15)
    multipliedSpeedTurn = 0;
  if (abs(multipliedSpeedStrafe) <= 15)
    multipliedSpeedStrafe = 0;
  drive(multipliedSpeedForward, multipliedSpeedTurn, multipliedSpeedStrafe);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<driveWithLogic>:
  endbr64
  lea    0xf(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x1e,%ecx
  lea    0xf(%rsi),%ecx
  cmovbe %eax,%edi
  cmp    $0x1e,%ecx
  lea    0xf(%rdx),%ecx
  cmovbe %eax,%esi
  cmp    $0x1e,%ecx
  cmovbe %eax,%edx
  jmp    1050 <drive@plt>
```

assistant: ```c
void driveWithLogic(int speedForward, int speedTurn, int speedStrafe, float forwardMultiplier, float turnMultiplier, float strafeMultiplier) {
  int multipliedSpeedForward = speedForward;
  int multipliedSpeedTurn = speedTurn;
  int multipliedSpeedStrafe = speedStrafe;
  if (abs(multipliedSpeedForward) <= 15)
    multipliedSpeedForward = 0;
  if (abs(multipliedSpeedTurn) <= 15)
    multipliedSpeedTurn = 0;
  if (abs(multipliedSpeedStrafe) <= 15)
    multipliedSpeedStrafe = 0;
  drive(multipliedSpeedForward, multipliedSpeedTurn, multipliedSpeedStrafe);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gator_write_packed_int>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%eax
  test   $0xffffff80,%eax
  je     L16
  test   $0xffffc000,%eax
  je     L3
  test   $0xffe00000,%eax
  je     L2
  test   $0xf0000000,%eax
  jne    L32
  mov    %esi,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi)
  mov    %esi,%ecx
  shr    $0x7,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%ecx
  shr    $0xe,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x2(%rdi)
  shr    $0x15,%eax
  mov    %al,0x3(%rdi)
  mov    $0x4,%eax
  ret
L16:
  mov    %sil,(%rdx)
  mov    $0x1,%eax
  ret
L3:
  mov    %esi,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi)
  shr    $0x7,%eax
  mov    %al,0x1(%rdi)
  mov    $0x2,%eax
  ret
L2:
  mov    %esi,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi)
  mov    %esi,%ecx
  shr    $0x7,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x1(%rdi)
  shr    $0xe,%eax
  mov    %al,0x2(%rdi)
  mov    $0x3,%eax
  ret
L32:
  mov    %esi,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi)
  mov    %esi,%ecx
  shr    $0x7,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x1(%rdi)
  mov    %esi,%ecx
  shr    $0xe,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x2(%rdi)
  mov    %esi,%ecx
  shr    $0x15,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,0x3(%rdi)
  shr    $0x1c,%eax
  mov    %al,0x4(%rdi)
  mov    $0x5,%eax
  ret
```

assistant: ```c
int gator_write_packed_int(char *buffer, unsigned int x) {
  if ((x & 0xffffff80) == 0) {
    buffer[0] = x & 0x7f;
    return 1;
  } else if ((x & 0xffffc000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) & 0x7f;
    return 2;
  } else if ((x & 0xffe00000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) & 0x7f;
    return 3;
  } else if ((x & 0xf0000000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) & 0x7f;
    return 4;
  } else {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) | 0x80;
    buffer[4] = (x >> 28) & 0x0f;
    return 5;
  }
}
```