ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<emit_call>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    $0x90,%edx
  mov    %eax,%esi
  mov    $0xb4,%edi
  call   <emit3@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    $0x90,%edx
  mov    %eax,%esi
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x10,%edx
  mov    $0xe0,%esi
  mov    $0xc1,%edi
  call   <emit3@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    $0x90,%edx
  mov    %eax,%esi
  mov    $0xb4,%edi
  call   <emit3@plt>
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    $0x90,%edx
  mov    %eax,%esi
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0x98,%esi
  mov    $0x48,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0xd0,%esi
  mov    $0xff,%edi
  call   <emit3@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_call(uint32_t addr) {
  emit3((0xb4), ((addr & 0xff000000) >> 24), 0x90);
  emit3((0xb0), ((addr & 0x00ff0000) >> 16), 0x90);
  emit3(0xc1, 0xe0, 0x10);
  emit3((0xb4), ((addr & 0x0000ff00) >> 8), 0x90);
  emit3((0xb0), ((addr & 0x000000ff)), 0x90);
  emit3((0x48), (0x98), 0x90);
  emit3((0xff), (0xd0), 0x90);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<emit_call>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  shr    $0x18,%esi
  mov    $0x90,%edx
  mov    $0xb4,%edi
  call   <emit3@plt>
  mov    %ebx,%esi
  sar    $0x10,%esi
  movzbl %sil,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x10,%edx
  mov    $0xe0,%esi
  mov    $0xc1,%edi
  call   <emit3@plt>
  movzbl %bh,%esi
  mov    $0x90,%edx
  mov    $0xb4,%edi
  call   <emit3@plt>
  movzbl %bl,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0x98,%esi
  mov    $0x48,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0xd0,%esi
  mov    $0xff,%edi
  call   <emit3@plt>
  pop    %rbx
  ret
```

assistant: ```c
void emit_call(uint32_t addr) {
  emit3((0xb4), ((addr & 0xff000000) >> 24), 0x90);
  emit3((0xb0), ((addr & 0x00ff0000) >> 16), 0x90);
  emit3(0xc1, 0xe0, 0x10);
  emit3((0xb4), ((addr & 0x0000ff00) >> 8), 0x90);
  emit3((0xb0), ((addr & 0x000000ff)), 0x90);
  emit3((0x48), (0x98), 0x90);
  emit3((0xff), (0xd0), 0x90);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_call>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  mov    $0x90,%edx
  shr    $0x18,%esi
  mov    $0xb4,%edi
  call   <emit3@plt>
  mov    %ebx,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  sar    $0x10,%esi
  movzbl %sil,%esi
  call   <emit3@plt>
  mov    $0x10,%edx
  mov    $0xe0,%esi
  mov    $0xc1,%edi
  call   <emit3@plt>
  movzbl %bh,%esi
  mov    $0x90,%edx
  mov    $0xb4,%edi
  call   <emit3@plt>
  movzbl %bl,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0x98,%esi
  mov    $0x48,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0xd0,%esi
  pop    %rbx
  mov    $0xff,%edi
  jmp    1050 <emit3@plt>
```

assistant: ```c
void emit_call(uint32_t addr) {
  emit3((0xb4), ((addr & 0xff000000) >> 24), 0x90);
  emit3((0xb0), ((addr & 0x00ff0000) >> 16), 0x90);
  emit3(0xc1, 0xe0, 0x10);
  emit3((0xb4), ((addr & 0x0000ff00) >> 8), 0x90);
  emit3((0xb0), ((addr & 0x000000ff)), 0x90);
  emit3((0x48), (0x98), 0x90);
  emit3((0xff), (0xd0), 0x90);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_call>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  mov    $0x90,%edx
  shr    $0x18,%esi
  mov    $0xb4,%edi
  call   <emit3@plt>
  mov    %ebx,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  sar    $0x10,%esi
  movzbl %sil,%esi
  call   <emit3@plt>
  mov    $0x10,%edx
  mov    $0xe0,%esi
  mov    $0xc1,%edi
  call   <emit3@plt>
  movzbl %bh,%esi
  mov    $0x90,%edx
  mov    $0xb4,%edi
  call   <emit3@plt>
  movzbl %bl,%esi
  mov    $0x90,%edx
  mov    $0xb0,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0x98,%esi
  mov    $0x48,%edi
  call   <emit3@plt>
  mov    $0x90,%edx
  mov    $0xd0,%esi
  pop    %rbx
  mov    $0xff,%edi
  jmp    1050 <emit3@plt>
```

assistant: ```c
void emit_call(uint32_t addr) {
  emit3((0xb4), ((addr & 0xff000000) >> 24), 0x90);
  emit3((0xb0), ((addr & 0x00ff0000) >> 16), 0x90);
  emit3(0xc1, 0xe0, 0x10);
  emit3((0xb4), ((addr & 0x0000ff00) >> 8), 0x90);
  emit3((0xb0), ((addr & 0x000000ff)), 0x90);
  emit3((0x48), (0x98), 0x90);
  emit3((0xff), (0xd0), 0x90);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fixup_vt1708S>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x28,%r8d
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1a,%esi
  mov    %rax,%rdi
  call   <fixup_via_mic_boost@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x28,%r8d
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <fixup_via_mic_boost@plt>
  nop
  leave
  ret
```

assistant: ```c
void fixup_vt1708S(struct xhda_codec *codec) {
  fixup_via_mic_boost(codec, 0x1a, 0, 3, 40);
  fixup_via_mic_boost(codec, 0x1e, 0, 3, 40);
}
```
user: What is the c source code of the assembly code below?

```asm
<fixup_vt1708S>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%r8d
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1a,%esi
  call   <fixup_via_mic_boost@plt>
  mov    $0x28,%r8d
  mov    $0x3,%ecx
  mov    $0x0,%edx
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <fixup_via_mic_boost@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fixup_vt1708S(struct xhda_codec *codec) {
  fixup_via_mic_boost(codec, 0x1a, 0, 3, 40);
  fixup_via_mic_boost(codec, 0x1e, 0, 3, 40);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fixup_vt1708S>:
  endbr64
  push   %rbp
  mov    $0x28,%r8d
  mov    %rdi,%rbp
  mov    $0x3,%ecx
  xor    %edx,%edx
  mov    $0x1a,%esi
  call   <fixup_via_mic_boost@plt>
  mov    %rbp,%rdi
  mov    $0x28,%r8d
  xor    %edx,%edx
  mov    $0x3,%ecx
  mov    $0x1e,%esi
  pop    %rbp
  jmp    1050 <fixup_via_mic_boost@plt>
```

assistant: ```c
void fixup_vt1708S(struct xhda_codec *codec) {
  fixup_via_mic_boost(codec, 0x1a, 0, 3, 40);
  fixup_via_mic_boost(codec, 0x1e, 0, 3, 40);
}
```
user: What is the c source code of the assembly code below?

```asm
<fixup_vt1708S>:
  endbr64
  push   %rbp
  mov    $0x28,%r8d
  mov    %rdi,%rbp
  mov    $0x3,%ecx
  xor    %edx,%edx
  mov    $0x1a,%esi
  call   <fixup_via_mic_boost@plt>
  mov    %rbp,%rdi
  mov    $0x28,%r8d
  xor    %edx,%edx
  mov    $0x3,%ecx
  mov    $0x1e,%esi
  pop    %rbp
  jmp    1050 <fixup_via_mic_boost@plt>
```

assistant: ```c
void fixup_vt1708S(struct xhda_codec *codec) {
  fixup_via_mic_boost(codec, 0x1a, 0, 3, 40);
  fixup_via_mic_boost(codec, 0x1e, 0, 3, 40);
}
```
user: What is the c source code of the assembly code below:

```asm
<next_triangle_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%rax
  lea    0x1(%rax),%rdx
  mov    D16(%rip),%rax
  add    %rdx,%rax
  mov    %rax,D58(%rip)
  mov    D15(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D58(%rip)
  mov    D58(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
long next_triangle_num(void) {
  static long last_index = 0;
  static long last_num = 0;
  last_num += last_index + 1;
  last_index++;
  return last_num;
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_triangle_num>:
  endbr64
  mov    D21(%rip),%rax
  add    $0x1,%rax
  mov    %rax,%rdx
  add    D37(%rip),%rdx
  mov    %rdx,D16(%rip)
  mov    %rax,D16(%rip)
  mov    %rdx,%rax
  ret
```

assistant: ```c
long next_triangle_num(void) {
  static long last_index = 0;
  static long last_num = 0;
  last_num += last_index + 1;
  last_index++;
  return last_num;
}
```
user: What is the c source code of the assembly code below:

```asm
<next_triangle_num>:
  endbr64
  mov    D0(%rip),%rax
  mov    D8(%rip),%r8
  add    $0x1,%rax
  add    %rax,%r8
  mov    %rax,D5(%rip)
  mov    %r8,D5(%rip)
  mov    %r8,%rax
  ret
```

assistant: ```c
long next_triangle_num(void) {
  static long last_index = 0;
  static long last_num = 0;
  last_num += last_index + 1;
  last_index++;
  return last_num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<next_triangle_num>:
  endbr64
  mov    D29(%rip),%rax
  mov    D37(%rip),%r8
  add    $0x1,%rax
  add    %rax,%r8
  mov    %rax,D6(%rip)
  mov    %r8,D6(%rip)
  mov    %r8,%rax
  ret
```

assistant: ```c
long next_triangle_num(void) {
  static long last_index = 0;
  static long last_num = 0;
  last_num += last_index + 1;
  last_index++;
  return last_num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_generic_api>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpl   $0xffffffff,-0x2c(%rbp)
  jne    L6
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L60
L6:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L60
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x28(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x2c(%rbp),%eax
  jmp    L88
L28:
  mov    -0x2c(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L55
L60:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L28
  jmp    L13
L55:
  nop
L13:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L51
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L94
L51:
  mov    $0xffffffff,%eax
  jmp    L88
L94:
  mov    -0x14(%rbp),%eax
L88:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int input_generic_api(char c[], int max_len) {
  int i = 0;
  if (max_len == -1)
    max_len = INT_MAX;
  else if (max_len == 1) {
    c[0] = getchar();
    return max_len;
  }
  while ((c[i++] = getchar()) != '\n')
    if (i > max_len - 1)
      break;
  c[i] = '\0';
  if (c[0] == 0 || c[0] == '\n')
    return -1;
  else
    return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<input_generic_api>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  cmp    $0xffffffff,%esi
  je     L48
  mov    %esi,%ebp
  cmp    $0x1,%esi
  je     L8
L51:
  mov    $0x1,%ebx
L1:
  mov    %ebx,%r13d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%r12,%rbx,1)
  cmp    %ebx,%ebp
  setle  %dl
  cmp    $0xa,%al
  sete   %al
  add    $0x1,%rbx
  or     %al,%dl
  je     L1
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  movzbl (%r12),%eax
  test   %al,%al
  je     L44
  cmp    $0xa,%al
  je     L44
L72:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    D3(%rip),%rax
  mov    (%rax),%ebp
  jmp    L51
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%r12)
  mov    %ebp,%r13d
  jmp    L72
L44:
  mov    $0xffffffff,%r13d
  jmp    L72
```

assistant: ```c
int input_generic_api(char c[], int max_len) {
  int i = 0;
  if (max_len == -1)
    max_len = INT_MAX;
  else if (max_len == 1) {
    c[0] = getchar();
    return max_len;
  }
  while ((c[i++] = getchar()) != '\n')
    if (i > max_len - 1)
      break;
  c[i] = '\0';
  if (c[0] == 0 || c[0] == '\n')
    return -1;
  else
    return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_generic_api>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L4
  mov    %esi,%ebp
  cmp    $0x1,%esi
  je     L7
L67:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L61:
  xor    %eax,%eax
  mov    %ebx,%r13d
  call   <getchar@plt>
  cmp    %ebx,%ebp
  setle  %dl
  cmp    $0xa,%al
  mov    %al,-0x1(%r12,%rbx,1)
  sete   %al
  add    $0x1,%rbx
  or     %al,%dl
  je     L61
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  movzbl (%r12),%eax
  test   %al,%al
  je     L31
  cmp    $0xa,%al
  je     L31
L1:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  mov    D8(%rip),%rax
  mov    (%rax),%ebp
  jmp    L67
L7:
  xor    %eax,%eax
  mov    $0x1,%r13d
  call   <getchar@plt>
  mov    %al,(%r12)
  jmp    L1
L31:
  mov    $0xffffffff,%r13d
  jmp    L1
```

assistant: ```c
int input_generic_api(char c[], int max_len) {
  int i = 0;
  if (max_len == -1)
    max_len = INT_MAX;
  else if (max_len == 1) {
    c[0] = getchar();
    return max_len;
  }
  while ((c[i++] = getchar()) != '\n')
    if (i > max_len - 1)
      break;
  c[i] = '\0';
  if (c[0] == 0 || c[0] == '\n')
    return -1;
  else
    return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<input_generic_api>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L53
  mov    %esi,%ebp
  cmp    $0x1,%esi
  je     L12
L27:
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  mov    %ebx,%r13d
  call   <getchar@plt>
  cmp    %ebx,%ebp
  setle  %dl
  cmp    $0xa,%al
  mov    %al,-0x1(%r12,%rbx,1)
  sete   %al
  add    $0x1,%rbx
  or     %al,%dl
  je     L29
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  movzbl (%r12),%eax
  test   %al,%al
  je     L75
  cmp    $0xa,%al
  je     L75
L10:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L53:
  mov    D3(%rip),%rax
  mov    (%rax),%ebp
  jmp    L27
L12:
  xor    %eax,%eax
  mov    $0x1,%r13d
  call   <getchar@plt>
  mov    %al,(%r12)
  jmp    L10
L75:
  mov    $0xffffffff,%r13d
  jmp    L10
```

assistant: ```c
int input_generic_api(char c[], int max_len) {
  int i = 0;
  if (max_len == -1)
    max_len = INT_MAX;
  else if (max_len == 1) {
    c[0] = getchar();
    return max_len;
  }
  while ((c[i++] = getchar()) != '\n')
    if (i > max_len - 1)
      break;
  c[i] = '\0';
  if (c[0] == 0 || c[0] == '\n')
    return -1;
  else
    return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <set_cursor_visibility@plt>
  mov    $0x0,%eax
  call   <prn_help_msg@plt>
  mov    $0x1,%edi
  call   <set_cursor_visibility@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  set_cursor_visibility(false);
  prn_help_msg();
  set_cursor_visibility(true);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <set_cursor_visibility@plt>
  mov    $0x0,%eax
  call   <prn_help_msg@plt>
  mov    $0x1,%edi
  call   <set_cursor_visibility@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  set_cursor_visibility(false);
  prn_help_msg();
  set_cursor_visibility(true);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <set_cursor_visibility@plt>
  xor    %eax,%eax
  call   <prn_help_msg@plt>
  mov    $0x1,%edi
  call   <set_cursor_visibility@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  set_cursor_visibility(false);
  prn_help_msg();
  set_cursor_visibility(true);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <set_cursor_visibility@plt>
  xor    %eax,%eax
  call   <prn_help_msg@plt>
  mov    $0x1,%edi
  call   <set_cursor_visibility@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  set_cursor_visibility(false);
  prn_help_msg();
  set_cursor_visibility(true);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ffs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L2
L11:
  movl   $0x1,-0x4(%rbp)
  jmp    L37
L23:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L23
  mov    -0x4(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int ffs(int mask) {
  int bit;
  if (mask == 0)
    return (0);
  for (bit = 1; !(mask & 1); bit++)
    mask >>= 1;
  return (bit);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ffs>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L17
  and    $0x1,%eax
  jne    L17
  mov    $0x1,%eax
L9:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L9
L17:
  ret
```

assistant: ```c
int ffs(int mask) {
  int bit;
  if (mask == 0)
    return (0);
  for (bit = 1; !(mask & 1); bit++)
    mask >>= 1;
  return (bit);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ffs>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L23
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L23
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L26:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L26
L23:
  ret
```

assistant: ```c
int ffs(int mask) {
  int bit;
  if (mask == 0)
    return (0);
  for (bit = 1; !(mask & 1); bit++)
    mask >>= 1;
  return (bit);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ffs>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L8
  mov    %edi,%eax
  and    $0x1,%eax
  jne    L8
  mov    $0x1,%eax
  cs nopw 0x0(%rax,%rax,1)
L10:
  sar    %edi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L10
L8:
  ret
```

assistant: ```c
int ffs(int mask) {
  int bit;
  if (mask == 0)
    return (0);
  for (bit = 1; !(mask & 1); bit++)
    mask >>= 1;
  return (bit);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <instance1@plt>
  mov    $0x0,%edi
  call   <instance2@plt>
  mov    $0x0,%edi
  call   <instance3@plt>
  mov    $0x0,%edi
  call   <instance4@plt>
  mov    $0x0,%edi
  call   <instance5@plt>
  mov    $0x0,%edi
  call   <instance6@plt>
  mov    $0x0,%edi
  call   <instance7@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  instance1(0);
__CPROVER_ASYNC_1:
  instance2(0);
__CPROVER_ASYNC_2:
  instance3(0);
__CPROVER_ASYNC_3:
  instance4(0);
__CPROVER_ASYNC_4:
  instance5(0);
__CPROVER_ASYNC_5:
  instance6(0);
__CPROVER_ASYNC_6:
  instance7(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <instance1@plt>
  mov    $0x0,%edi
  call   <instance2@plt>
  mov    $0x0,%edi
  call   <instance3@plt>
  mov    $0x0,%edi
  call   <instance4@plt>
  mov    $0x0,%edi
  call   <instance5@plt>
  mov    $0x0,%edi
  call   <instance6@plt>
  mov    $0x0,%edi
  call   <instance7@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  instance1(0);
__CPROVER_ASYNC_1:
  instance2(0);
__CPROVER_ASYNC_2:
  instance3(0);
__CPROVER_ASYNC_3:
  instance4(0);
__CPROVER_ASYNC_4:
  instance5(0);
__CPROVER_ASYNC_5:
  instance6(0);
__CPROVER_ASYNC_6:
  instance7(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <instance1@plt>
  xor    %edi,%edi
  call   <instance2@plt>
  xor    %edi,%edi
  call   <instance3@plt>
  xor    %edi,%edi
  call   <instance4@plt>
  xor    %edi,%edi
  call   <instance5@plt>
  xor    %edi,%edi
  call   <instance6@plt>
  xor    %edi,%edi
  call   <instance7@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  instance1(0);
__CPROVER_ASYNC_1:
  instance2(0);
__CPROVER_ASYNC_2:
  instance3(0);
__CPROVER_ASYNC_3:
  instance4(0);
__CPROVER_ASYNC_4:
  instance5(0);
__CPROVER_ASYNC_5:
  instance6(0);
__CPROVER_ASYNC_6:
  instance7(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <instance1@plt>
  xor    %edi,%edi
  call   <instance2@plt>
  xor    %edi,%edi
  call   <instance3@plt>
  xor    %edi,%edi
  call   <instance4@plt>
  xor    %edi,%edi
  call   <instance5@plt>
  xor    %edi,%edi
  call   <instance6@plt>
  xor    %edi,%edi
  call   <instance7@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_0:
  instance1(0);
__CPROVER_ASYNC_1:
  instance2(0);
__CPROVER_ASYNC_2:
  instance3(0);
__CPROVER_ASYNC_3:
  instance4(0);
__CPROVER_ASYNC_4:
  instance5(0);
__CPROVER_ASYNC_5:
  instance6(0);
__CPROVER_ASYNC_6:
  instance7(0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bubblesort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L69
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L69
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L34
L12:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L67
L45:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L75
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L75:
  addl   $0x1,-0x4(%rbp)
L67:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L45
  subl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L12
  jmp    L78
L69:
  nop
L78:
  leave
  ret
```

assistant: ```c
void bubblesort(int *array, int left, int right) {
  if (array == NULL || left >= right)
    return;
  int i, j;
  for (i = right; i != left; --i) {
    for (j = left + 1; j != i; ++j) {
      if (array[j - 1] > array[j])
        swap(&array[j - 1], &array[j]);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bubblesort>:
  endbr64
  test   %rdi,%rdi
  je     L68
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %edx,%r12d
  cmp    %edx,%esi
  jge    L25
  lea    0x1(%rsi),%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xfffffffe,%r15d
  sub    %esi,%r15d
  movslq %esi,%rax
  mov    %rax,0x18(%rsp)
  jmp    L73
L21:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L6
L15:
  lea    -0x4(%rbx),%rdi
  mov    (%rbx),%eax
  cmp    %eax,-0x4(%rbx)
  jle    L21
  mov    %rbx,%rsi
  call   <swap@plt>
  jmp    L21
L6:
  sub    $0x1,%r12d
  cmp    %r12d,%r13d
  je     L25
L73:
  cmp    %r12d,0xc(%rsp)
  je     L6
  lea    (%r15,%r12,1),%eax
  add    0x18(%rsp),%rax
  lea    0x8(%r14,%rax,4),%rbp
  mov    0x10(%rsp),%rbx
  jmp    L15
L25:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  ret
```

assistant: ```c
void bubblesort(int *array, int left, int right) {
  if (array == NULL || left >= right)
    return;
  int i, j;
  for (i = right; i != left; --i) {
    for (j = left + 1; j != i; ++j) {
      if (array[j - 1] > array[j])
        swap(&array[j - 1], &array[j]);
    }
  }
}
```