ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L0
L4:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
L0:
  cmpq   $0x0,-0x28(%rbp)
  jne    L4
  cmpq   $0x0,-0x28(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int read_all(int fd, char *buf, size_t count) {
  int bytes_read;
  while (count > 0) {
    bytes_read = read(fd, buf, count);
    assert(bytes_read > 0);
    buf += bytes_read;
    count -= bytes_read;
  }
  assert(count == 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L2
L15:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %rax,%rbp
  jne    L15
L2:
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_all(int fd, char *buf, size_t count) {
  int bytes_read;
  while (count > 0) {
    bytes_read = read(fd, buf, count);
    assert(bytes_read > 0);
    buf += bytes_read;
    count -= bytes_read;
  }
  assert(count == 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L13
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  nopl   0x0(%rax)
L12:
  mov    %r13,%rsi
  mov    %rbp,%rdx
  mov    %r12d,%edi
  call   <read@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebx
  setg   %dil
  call   <assert@plt>
  movslq %ebx,%rax
  add    %rax,%r13
  sub    %rax,%rbp
  jne    L12
L13:
  mov    $0x1,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_all(int fd, char *buf, size_t count) {
  int bytes_read;
  while (count > 0) {
    bytes_read = read(fd, buf, count);
    assert(bytes_read > 0);
    buf += bytes_read;
    count -= bytes_read;
  }
  assert(count == 0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L5
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  nopl   0x0(%rax)
L17:
  mov    %r13,%rsi
  mov    %rbp,%rdx
  mov    %r12d,%edi
  call   <read@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebx
  setg   %dil
  call   <assert@plt>
  movslq %ebx,%rax
  add    %rax,%r13
  sub    %rax,%rbp
  jne    L17
L5:
  mov    $0x1,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_all(int fd, char *buf, size_t count) {
  int bytes_read;
  while (count > 0) {
    bytes_read = read(fd, buf, count);
    assert(bytes_read > 0);
    buf += bytes_read;
    count -= bytes_read;
  }
  assert(count == 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<client_accept_s_expr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <socket_receive_file_to_buff@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *client_accept_s_expr(int fd) {
  char *expr;
  int filesize;
  expr = socket_receive_file_to_buff(fd, &filesize);
  expr[filesize] = '\0';
  return expr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<client_accept_s_expr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <socket_receive_file_to_buff@plt>
  movslq 0x4(%rsp),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *client_accept_s_expr(int fd) {
  char *expr;
  int filesize;
  expr = socket_receive_file_to_buff(fd, &filesize);
  expr[filesize] = '\0';
  return expr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<client_accept_s_expr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <socket_receive_file_to_buff@plt>
  movslq 0x4(%rsp),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *client_accept_s_expr(int fd) {
  char *expr;
  int filesize;
  expr = socket_receive_file_to_buff(fd, &filesize);
  expr[filesize] = '\0';
  return expr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<client_accept_s_expr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <socket_receive_file_to_buff@plt>
  movslq 0x4(%rsp),%rdx
  movb   $0x0,(%rax,%rdx,1)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *client_accept_s_expr(int fd) {
  char *expr;
  int filesize;
  expr = socket_receive_file_to_buff(fd, &filesize);
  expr[filesize] = '\0';
  return expr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<android_atomic_release_store>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <android_compiler_barrier@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
extern void android_atomic_release_store(int32_t value, volatile int32_t *ptr) {
  android_compiler_barrier();
  *ptr = value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<android_atomic_release_store>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <android_compiler_barrier@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern void android_atomic_release_store(int32_t value, volatile int32_t *ptr) {
  android_compiler_barrier();
  *ptr = value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<android_atomic_release_store>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <android_compiler_barrier@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern void android_atomic_release_store(int32_t value, volatile int32_t *ptr) {
  android_compiler_barrier();
  *ptr = value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<android_atomic_release_store>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <android_compiler_barrier@plt>
  mov    %ebp,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern void android_atomic_release_store(int32_t value, volatile int32_t *ptr) {
  android_compiler_barrier();
  *ptr = value;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<i2c_transact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L35
  cmpl   $0x0,-0x24(%rbp)
  jle    L35
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
L35:
  cmpl   $0x0,-0x4(%rbp)
  jle    L26
  cmpl   $0x0,-0x28(%rbp)
  jle    L26
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int i2c_transact(int fd, int chip_addr, uint8_t *buffer, int nw, int nr) {
  int err = ioctl(fd, I2C_SLAVE, chip_addr);
  if ((err == 0) && (nw > 0))
    err = write(fd, buffer, nw);
  if ((err > 0) && (nr > 0))
    err = read(fd, buffer, nr);
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<i2c_transact>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %r8d,%ebp
  mov    %esi,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  jne    L5
  test   %r13d,%r13d
  jg     L18
L5:
  test   %eax,%eax
  jle    L27
  test   %ebp,%ebp
  jg     L35
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  jmp    L5
L35:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <read@plt>
  jmp    L27
```

assistant: ```c
int i2c_transact(int fd, int chip_addr, uint8_t *buffer, int nw, int nr) {
  int err = ioctl(fd, I2C_SLAVE, chip_addr);
  if ((err == 0) && (nw > 0))
    err = write(fd, buffer, nw);
  if ((err > 0) && (nr > 0))
    err = read(fd, buffer, nr);
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2c_transact>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %esi,%edx
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  jne    L40
  test   %r14d,%r14d
  jg     L18
L40:
  test   %eax,%eax
  jle    L24
  test   %r12d,%r12d
  jg     L36
L24:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <read@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  jmp    L40
```

assistant: ```c
int i2c_transact(int fd, int chip_addr, uint8_t *buffer, int nw, int nr) {
  int err = ioctl(fd, I2C_SLAVE, chip_addr);
  if ((err == 0) && (nw > 0))
    err = write(fd, buffer, nw);
  if ((err > 0) && (nr > 0))
    err = read(fd, buffer, nr);
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<i2c_transact>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  mov    %esi,%edx
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  jne    L6
  test   %r14d,%r14d
  jg     L20
L6:
  test   %eax,%eax
  jle    L15
  test   %r12d,%r12d
  jg     L16
L15:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <read@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  jmp    L6
```

assistant: ```c
int i2c_transact(int fd, int chip_addr, uint8_t *buffer, int nw, int nr) {
  int err = ioctl(fd, I2C_SLAVE, chip_addr);
  if ((err == 0) && (nw > 0))
    err = write(fd, buffer, nw);
  if ((err > 0) && (nr > 0))
    err = read(fd, buffer, nr);
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L30
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L32
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L108
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L43
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L108
L43:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__memcpy@plt>
L108:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L106
  jmp    L57
L10:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L57:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L10
  jmp    L46
L69:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L106:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L69
  jmp    L46
L30:
  nop
L46:
  leave
  ret
```

assistant: ```c
bcopy(const void *s2, void *s1, int n) {
  const void *lasts;
  void *lastd;
  if (n == 0) {
    return;
  }
  lasts = s2 + (n - 1);
  lastd = s1 + (n - 1);
  if (((s1 < s2) || (s1 > lasts)) && ((lastd < s2) || (lastd > lasts)))
    __memcpy(s1, s2, n);
  if (s1 < s2)
    while (n--)
      *(char *)s1++ = *(char *)s2++;
  else
    while (n--)
      *(char *)lastd-- = *(char *)lasts--;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bcopy>:
  endbr64
  test   %edx,%edx
  je     L93
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  movslq %edx,%r13
  sub    $0x1,%r13
  lea    (%rdi,%r13,1),%r14
  add    %rsi,%r13
  cmp    %rsi,%rdi
  ja     L64
  cmp    %rsi,%r14
  jb     L64
L34:
  lea    -0x1(%rbx),%ecx
  not    %rcx
  mov    $0x0,%eax
L7:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,0x0(%r13,%rax,1)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L7
  jmp    L44
L64:
  cmp    %r13,%r12
  ja     L22
  cmp    %r13,%r14
  jb     L22
L13:
  cmp    %rbp,%r12
  jbe    L34
  mov    %ebx,%ebx
  mov    $0x0,%eax
L20:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L20
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <__memcpy@plt>
  jmp    L13
L93:
  ret
```

assistant: ```c
bcopy(const void *s2, void *s1, int n) {
  const void *lasts;
  void *lastd;
  if (n == 0) {
    return;
  }
  lasts = s2 + (n - 1);
  lastd = s1 + (n - 1);
  if (((s1 < s2) || (s1 > lasts)) && ((lastd < s2) || (lastd > lasts)))
    __memcpy(s1, s2, n);
  if (s1 < s2)
    while (n--)
      *(char *)s1++ = *(char *)s2++;
  else
    while (n--)
      *(char *)lastd-- = *(char *)lasts--;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bcopy>:
  endbr64
  test   %edx,%edx
  je     L75
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  sub    $0x1,%r13
  mov    %rdi,%r12
  push   %rbp
  lea    (%rdi,%r13,1),%r14
  mov    %rsi,%rbp
  add    %rsi,%r13
  push   %rbx
  sub    $0x10,%rsp
  cmp    %rsi,%rdi
  ja     L81
  cmp    %rsi,%r14
  jb     L81
L61:
  lea    -0x1(%rdx),%ecx
  xor    %eax,%eax
  not    %rcx
  xchg   %ax,%ax
L28:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,0x0(%r13,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  cmp    %r13,%r12
  ja     L59
  cmp    %r13,%r14
  jb     L59
L82:
  cmp    %rbp,%r12
  jbe    L61
  mov    %edx,%ebx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L75:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %edx,0xc(%rsp)
  call   <__memcpy@plt>
  mov    0xc(%rsp),%edx
  jmp    L82
```

assistant: ```c
bcopy(const void *s2, void *s1, int n) {
  const void *lasts;
  void *lastd;
  if (n == 0) {
    return;
  }
  lasts = s2 + (n - 1);
  lastd = s1 + (n - 1);
  if (((s1 < s2) || (s1 > lasts)) && ((lastd < s2) || (lastd > lasts)))
    __memcpy(s1, s2, n);
  if (s1 < s2)
    while (n--)
      *(char *)s1++ = *(char *)s2++;
  else
    while (n--)
      *(char *)lastd-- = *(char *)lasts--;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bcopy>:
  endbr64
  test   %edx,%edx
  je     L42
  push   %r14
  push   %r13
  movslq %edx,%r13
  sub    $0x1,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    (%rdi,%r13,1),%r14
  mov    %rdi,%rbp
  add    %rsi,%r13
  push   %rbx
  mov    %rsi,%rbx
  cmp    %rsi,%rdi
  ja     L88
  cmp    %rsi,%r14
  jb     L88
  lea    -0x1(%rdx),%ecx
L177:
  not    %rcx
  xor    %eax,%eax
  nopl   (%rax)
L174:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,0x0(%r13,%rax,1)
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L174
L156:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L88:
  cmp    %r13,%rbp
  ja     L62
  cmp    %r13,%r14
  jb     L62
L182:
  lea    -0x1(%r12),%ecx
  mov    %ecx,%esi
  cmp    %rbx,%rbp
  jbe    L177
  lea    0x1(%rbp),%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  cmp    $0xe,%rax
  jbe    L190
  cmp    $0x6,%ecx
  jbe    L190
  cmp    $0xe,%ecx
  jbe    L112
  mov    %r12d,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
L51:
  movdqu 0x0(%rbp,%rax,1),%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L51
  mov    %r12d,%eax
  mov    %ecx,%esi
  and    $0xfffffff0,%eax
  mov    %eax,%edx
  sub    %eax,%esi
  lea    0x0(%rbp,%rdx,1),%rdi
  add    %rbx,%rdx
  cmp    %eax,%r12d
  je     L156
L222:
  sub    %eax,%r12d
  lea    -0x1(%r12),%ecx
  cmp    $0x6,%ecx
  jbe    L132
  mov    0x0(%rbp,%rax,1),%rcx
  mov    %rcx,(%rbx,%rax,1)
  mov    %r12d,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%ecx
  sub    %eax,%esi
  add    %rcx,%rdi
  add    %rcx,%rdx
  cmp    %eax,%r12d
  je     L156
L132:
  movzbl (%rdi),%eax
  mov    %al,(%rdx)
  test   %esi,%esi
  je     L156
  movzbl 0x1(%rdi),%eax
  mov    %al,0x1(%rdx)
  cmp    $0x1,%esi
  je     L156
  movzbl 0x2(%rdi),%eax
  mov    %al,0x2(%rdx)
  cmp    $0x2,%esi
  je     L156
  movzbl 0x3(%rdi),%eax
  mov    %al,0x3(%rdx)
  cmp    $0x3,%esi
  je     L156
  movzbl 0x4(%rdi),%eax
  mov    %al,0x4(%rdx)
  cmp    $0x4,%esi
  je     L156
  movzbl 0x5(%rdi),%eax
  mov    %al,0x5(%rdx)
  cmp    $0x5,%esi
  je     L156
  movzbl 0x6(%rdi),%eax
  mov    %al,0x6(%rdx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L42:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__memcpy@plt>
  jmp    L182
  nopl   0x0(%rax,%rax,1)
L190:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L193:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdx
  jne    L193
  jmp    L156
L112:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  jmp    L222
```

assistant: ```c
bcopy(const void *s2, void *s1, int n) {
  const void *lasts;
  void *lastd;
  if (n == 0) {
    return;
  }
  lasts = s2 + (n - 1);
  lastd = s1 + (n - 1);
  if (((s1 < s2) || (s1 > lasts)) && ((lastd < s2) || (lastd > lasts)))
    __memcpy(s1, s2, n);
  if (s1 < s2)
    while (n--)
      *(char *)s1++ = *(char *)s2++;
  else
    while (n--)
      *(char *)lastd-- = *(char *)lasts--;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1f,-0xc(%rbp)
  jmp    L9
L18:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  lea    (%rdx,%rax,1),%esi
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %esi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L13
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L13:
  subl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0x0,-0xc(%rbp)
  jns    L18
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  int s;
  uint64_t ret_sq = 0;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int_sqrt>:
  endbr64
  mov    $0x0,%r9d
  mov    $0x1f,%eax
  mov    $0x0,%esi
  mov    $0x1,%r8d
  jmp    L5
L10:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  je     L17
L5:
  mov    %esi,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  lea    (%r9,%rdx,2),%edx
  lea    (%rax,%rax,1),%ecx
  mov    %r8,%r10
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L10
  mov    %r8,%r11
  mov    %eax,%ecx
  shl    %cl,%r11
  add    %r11d,%esi
  mov    %edx,%r9d
  jmp    L10
L17:
  mov    %esi,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  int s;
  uint64_t ret_sq = 0;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<int_sqrt>:
  endbr64
  xor    %r9d,%r9d
  mov    $0x1f,%eax
  xor    %r8d,%r8d
  mov    $0x1,%esi
  nopl   0x0(%rax)
L1:
  mov    %eax,%ecx
  mov    %r8d,%edx
  mov    %rsi,%r10
  shl    %cl,%edx
  lea    (%rax,%rax,1),%ecx
  lea    (%r9,%rdx,2),%edx
  shl    %cl,%r10
  add    %r10d,%edx
  cmp    %edi,%edx
  jg     L14
  mov    %rsi,%r11
  mov    %eax,%ecx
  mov    %edx,%r9d
  shl    %cl,%r11
  add    %r11d,%r8d
L14:
  sub    $0x1,%eax
  jae    L1
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint64_t int_sqrt(uint64_t a) {
  uint64_t ret = 0;
  int s;
  uint64_t ret_sq = 0;
  for (s = 31; s >= 0; s--) {
    uint64_t b = ret_sq + (1ULL << (s * 2)) + (ret << s) * 2;
    if (b <= a) {
      ret_sq = b;
      ret += 1ULL << s;
    }
  }
  return ret;
}
```