user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D59(%rip),%rdi
  lea    D79(%rip),%rbp
  call   <puts@plt>
  mov    $0xfffe1dc0,%r8d
  mov    $0xfffe1dc0,%ecx
  xor    %eax,%eax
  mov    $0x1e240,%edx
  mov    $0x1e240,%esi
  lea    D148(%rip),%rdi
  call   <printf@plt>
  movsd  D62(%rip),%xmm0
  mov    $0x1,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  movsd  D158(%rip),%xmm0
  mov    $0x1,%eax
  lea    D69(%rip),%rdi
  call   <printf@plt>
  movsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  movsd  D35(%rip),%xmm1
  mov    %rbp,%rdi
  movsd  D6(%rip),%xmm0
  mov    $0x4,%eax
  movapd %xmm1,%xmm3
  movapd %xmm0,%xmm2
  call   <printf@plt>
  movsd  D98(%rip),%xmm0
  mov    %rbp,%rdi
  movsd  D12(%rip),%xmm1
  mov    $0x4,%eax
  lea    D49(%rip),%rbp
  movapd %xmm0,%xmm3
  movapd %xmm1,%xmm2
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%r8d
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x6,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  lea    D132(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x4,%r8d
  xor    %eax,%eax
  mov    $0xfffffffe,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D59
datatype: string
name: read_data
arguments: tag: D79
datatype: string
name: read_data
arguments: tag: D148
datatype: string
name: read_data
arguments: tag: D62
datatype: f64
name: read_data
arguments: tag: D27
datatype: string
name: read_data
arguments: tag: D158
datatype: f64
name: read_data
arguments: tag: D69
datatype: string
name: read_data
arguments: tag: D8
datatype: byte[8]
name: read_data
arguments: tag: D45
datatype: string
name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D35
datatype: byte[8]
name: read_data
arguments: tag: D6
datatype: byte[8]
name: read_data
arguments: tag: D98
datatype: byte[8]
name: read_data
arguments: tag: D12
datatype: byte[8]
name: read_data
arguments: tag: D49
datatype: string
name: read_data
arguments: tag: D48
datatype: string
name: read_data
arguments: tag: D132
datatype: string

tool: D59: 

Question 8


tool: D79: %f, %f, %f, %f


tool: D148: *%20.10d*
*%-20.10d*
*%.10d*
*%-20d*


tool: D62: 83.162

tool: D27: %.4f


tool: D158: 30.253

tool: D69: %12.5e


tool: {"D8": [0xc3,0x72,0x42,0xa7,0xf2,0xbd,0xb0,0x3e]}

tool: D45: %-6.2g


tool: D5: 

Question 9


tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D98": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0xc0]}

tool: D49: %d %d %d %d


tool: D48: 

Question 10


tool: D132: 

Question 11


assistant: ```c
int main(void) {
  printf("\n\nQuestion 8\n\n");
  printf("*%20.10d*\n*%-20.10d*\n*%.10d*\n*%-20d*\n", 123456, 123456, -123456, -123456);
  printf("%.4f\n", 83.162);
  printf("%12.5e\n", 30.253);
  printf("%-6.2g\n", .0000009979);
  printf("\n\nQuestion 9\n\n");
  float a, b, c, d;
  a = 13 % 4;
  b = -13 % 4;
  c = 13 % -4;
  d = -13 % -4;
  printf("%f, %f, %f, %f\n", a, b, c, d);
  a = 13 / 4;
  b = -13 / 4;
  c = 13 / -4;
  d = -13 / -4;
  printf("%f, %f, %f, %f\n", a, b, c, d);
  printf("\n\nQuestion 10\n\n");
  int i = 1, j = 2;
  int k = 3, m = 4;
  i %= j++ % (k += --m);
  printf("%d %d %d %d\n", i++, ++j, k--, --m);
  printf("\n\nQuestion 11\n\n");
  i = 1, j = 2;
  k = 3, m = 4;
  i *= j / -(k -= ++m);
  printf("%d %d %d %d\n", i++, ++j, k--, --m);
}
```