ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sys_writev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writev@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L8
  mov    D1(%rip),%rax
  mov    (%rax),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L8
  mov    $0x0,%eax
  call   <task_yield@plt>
  jmp    L12
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
ssize_t sys_writev(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t ret;
RETRY:
  ret = writev(fd, iov, iovcnt);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sys_writev>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L27
L10:
  mov    $0x0,%eax
  call   <task_yield@plt>
L27:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <writev@plt>
  cmp    $0xffffffff,%eax
  jne    L20
  mov    D0(%rip),%rcx
  mov    D11(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L10
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sys_writev(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t ret;
RETRY:
  ret = writev(fd, iov, iovcnt);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys_writev>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L0:
  mov    D3(%rip),%rdx
  mov    D19(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L28
  xor    %eax,%eax
  call   <task_yield@plt>
L14:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <writev@plt>
  cmp    $0xffffffff,%eax
  je     L0
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sys_writev(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t ret;
RETRY:
  ret = writev(fd, iov, iovcnt);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sys_writev>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L26:
  mov    D11(%rip),%rdx
  mov    D12(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  jne    L14
  xor    %eax,%eax
  call   <task_yield@plt>
L2:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <writev@plt>
  cmp    $0xffffffff,%eax
  je     L26
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
ssize_t sys_writev(int fd, const struct iovec *iov, int iovcnt) {
  ssize_t ret;
RETRY:
  ret = writev(fd, iov, iovcnt);
  if (ret == -1 && errno == EAGAIN) {
    task_yield();
    goto RETRY;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hlp_endianness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: LE


assistant: ```c
int hlp_endianness(void) {
  printf("LE\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hlp_endianness>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: LE


assistant: ```c
int hlp_endianness(void) {
  printf("LE\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hlp_endianness>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: LE


assistant: ```c
int hlp_endianness(void) {
  printf("LE\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<hlp_endianness>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: LE


assistant: ```c
int hlp_endianness(void) {
  printf("LE\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char **one, char **two) {
  char *tmp = *one;
  *one = *two;
  *two = tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char **one, char **two) {
  char *tmp = *one;
  *one = *two;
  *two = tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char **one, char **two) {
  char *tmp = *one;
  *one = *two;
  *two = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void swap(char **one, char **two) {
  char *tmp = *one;
  *one = *two;
  *two = tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x6,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int func1() {
  int i = 6;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func1>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int func1() {
  int i = 6;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func1>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int func1() {
  int i = 6;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<func1>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int func1() {
  int i = 6;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int add(int x, int y) {
  int aresult;
  aresult = (x + y);
  return aresult;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int x, int y) {
  int aresult;
  aresult = (x + y);
  return aresult;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int x, int y) {
  int aresult;
  aresult = (x + y);
  return aresult;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int add(int x, int y) {
  int aresult;
  aresult = (x + y);
  return aresult;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_insertion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L3
L14:
  mov    -0x10(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x2c(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L37
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jg     L35
L37:
  mov    -0xc(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void _insertion(void **ar, int (*cmp)(const void *, const void *), int low, int right, int gap) {
  int loc;
  for (loc = low + gap; loc <= right; loc += gap) {
    int i = loc - gap;
    void *value = ar[loc];
    while (i >= low && cmp(ar[i], value) > 0) {
      ar[i + gap] = ar[i];
      i -= gap;
    }
    ar[i + gap] = value;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_insertion>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,%r13d
  mov    %ecx,0x24(%rsp)
  mov    %r8d,0x4(%rsp)
  lea    (%rdx,%r8,1),%eax
  cmp    %ecx,%eax
  jg     L10
  mov    %rsi,%r15
  mov    %edx,0x20(%rsp)
  movslq %r8d,%r14
  lea    0x0(,%r14,8),%rax
  mov    %rax,0x28(%rsp)
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  mov    %r8d,%eax
  neg    %eax
  cltq
  shl    $0x3,%rax
  mov    %rax,0x8(%rsp)
  jmp    L0
L32:
  mov    0x4(%rsp),%edx
  add    %edx,%ebp
  movslq %ebp,%rbp
  mov    0x18(%rsp),%rax
  mov    %r12,(%rax,%rbp,8)
  add    %edx,0x20(%rsp)
  mov    0x20(%rsp),%eax
  mov    0x28(%rsp),%rsi
  add    %rsi,0x10(%rsp)
  add    %edx,%eax
  cmp    %eax,0x24(%rsp)
  jl     L10
L0:
  mov    0x20(%rsp),%eax
  mov    %eax,%ebp
  mov    0x10(%rsp),%rbx
  mov    (%rbx,%r14,8),%r12
  cmp    %eax,%r13d
  jg     L32
L57:
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   *%r15
  test   %eax,%eax
  jle    L32
  mov    (%rbx),%rax
  mov    %rax,(%rbx,%r14,8)
  sub    0x4(%rsp),%ebp
  add    0x8(%rsp),%rbx
  cmp    %ebp,%r13d
  jle    L57
  jmp    L32
L10:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void _insertion(void **ar, int (*cmp)(const void *, const void *), int low, int right, int gap) {
  int loc;
  for (loc = low + gap; loc <= right; loc += gap) {
    int i = loc - gap;
    void *value = ar[loc];
    while (i >= low && cmp(ar[i], value) > 0) {
      ar[i + gap] = ar[i];
      i -= gap;
    }
    ar[i + gap] = value;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_insertion>:
  endbr64
  push   %r15
  lea    (%rdx,%r8,1),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %ecx,0x2c(%rsp)
  cmp    %ecx,%eax
  jg     L21
  mov    %edx,%ebx
  movslq %r8d,%rdx
  mov    %eax,0x28(%rsp)
  mov    %r8d,%r12d
  lea    0x0(,%rdx,8),%rcx
  movslq %eax,%rdx
  mov    %rcx,0x20(%rsp)
  lea    (%rdi,%rdx,8),%rdx
  mov    %ebx,%ecx
  mov    %r8d,%ebx
  neg    %ebx
  mov    %rdx,0x18(%rsp)
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  xchg   %ax,%ax
L34:
  mov    0x18(%rsp),%r13
  mov    %ecx,%r14d
  mov    0x0(%r13),%rbp
  mov    %r13,%rax
  cmp    %ecx,0x4(%rsp)
  jg     L44
  mov    %r13,%r15
  sub    0x20(%rsp),%r15
  jmp    L29
  nop
L1:
  mov    (%r15),%rsi
  sub    %r12d,%r14d
  add    %rbx,%r15
  mov    %rsi,0x0(%r13)
  lea    (%rax,%rbx,1),%r13
  cmp    %r14d,0x4(%rsp)
  jg     L11
L29:
  mov    (%r15),%rdi
  mov    0x10(%rsp),%rax
  mov    %r15,0x8(%rsp)
  mov    %rbp,%rsi
  call   *%rax
  mov    %eax,%r9d
  mov    %r13,%rax
  test   %r9d,%r9d
  jg     L1
L44:
  mov    %rbp,(%rax)
  mov    0x28(%rsp),%eax
  mov    0x20(%rsp),%rcx
  add    %rcx,0x18(%rsp)
  mov    %eax,%ecx
  add    %r12d,%eax
  mov    %eax,0x28(%rsp)
  cmp    %eax,0x2c(%rsp)
  jge    L34
L21:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  mov    0x8(%rsp),%rax
  jmp    L44
```

assistant: ```c
void _insertion(void **ar, int (*cmp)(const void *, const void *), int low, int right, int gap) {
  int loc;
  for (loc = low + gap; loc <= right; loc += gap) {
    int i = loc - gap;
    void *value = ar[loc];
    while (i >= low && cmp(ar[i], value) > 0) {
      ar[i + gap] = ar[i];
      i -= gap;
    }
    ar[i + gap] = value;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_insertion>:
  endbr64
  push   %r15
  lea    (%rdx,%r8,1),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %ecx,0x2c(%rsp)
  cmp    %ecx,%eax
  jg     L31
  mov    %edx,%ebx
  movslq %r8d,%rdx
  mov    %eax,0x28(%rsp)
  mov    %r8d,%r12d
  lea    0x0(,%rdx,8),%rcx
  movslq %eax,%rdx
  mov    %rcx,0x20(%rsp)
  lea    (%rdi,%rdx,8),%rdx
  mov    %ebx,%ecx
  mov    %r8d,%ebx
  neg    %ebx
  mov    %rdx,0x18(%rsp)
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  xchg   %ax,%ax
L28:
  mov    0x18(%rsp),%r13
  mov    %ecx,%r14d
  mov    0x0(%r13),%rbp
  mov    %r13,%rax
  cmp    %ecx,0x4(%rsp)
  jg     L69
  mov    %r13,%r15
  sub    0x20(%rsp),%r15
  jmp    L52
  nop
L33:
  mov    (%r15),%rsi
  sub    %r12d,%r14d
  add    %rbx,%r15
  mov    %rsi,0x0(%r13)
  lea    (%rax,%rbx,1),%r13
  cmp    %r14d,0x4(%rsp)
  jg     L21
L52:
  mov    (%r15),%rdi
  mov    0x10(%rsp),%rax
  mov    %r15,0x8(%rsp)
  mov    %rbp,%rsi
  call   *%rax
  mov    %eax,%r9d
  mov    %r13,%rax
  test   %r9d,%r9d
  jg     L33
L69:
  mov    %rbp,(%rax)
  mov    0x28(%rsp),%eax
  mov    0x20(%rsp),%rcx
  add    %rcx,0x18(%rsp)
  mov    %eax,%ecx
  add    %r12d,%eax
  mov    %eax,0x28(%rsp)
  cmp    0x2c(%rsp),%eax
  jle    L28
L31:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    0x8(%rsp),%rax
  jmp    L69
```

assistant: ```c
void _insertion(void **ar, int (*cmp)(const void *, const void *), int low, int right, int gap) {
  int loc;
  for (loc = low + gap; loc <= right; loc += gap) {
    int i = loc - gap;
    void *value = ar[loc];
    while (i >= low && cmp(ar[i], value) > 0) {
      ar[i + gap] = ar[i];
      i -= gap;
    }
    ar[i + gap] = value;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6b,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  xor    $0x1f,%eax
  lea    0x73(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[0UL] * state[0UL] & (unsigned char)31) << 3UL;
        state[0UL] |= (state[local1] * state[local1] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] > local1) {
        state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      } else {
        state[0UL] = (state[local1] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[local1] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)));
        state[0UL] |= (state[local1] & (unsigned char)15) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] ^ 1073542431UL) + (unsigned char)115;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6b,%eax
  xor    $0x1f,%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[0UL] * state[0UL] & (unsigned char)31) << 3UL;
        state[0UL] |= (state[local1] * state[local1] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] > local1) {
        state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      } else {
        state[0UL] = (state[local1] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[local1] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)));
        state[0UL] |= (state[local1] & (unsigned char)15) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] ^ 1073542431UL) + (unsigned char)115;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6b,%eax
  xor    $0x1f,%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[0UL] * state[0UL] & (unsigned char)31) << 3UL;
        state[0UL] |= (state[local1] * state[local1] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] > local1) {
        state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      } else {
        state[0UL] = (state[local1] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[local1] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)));
        state[0UL] |= (state[local1] & (unsigned char)15) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] ^ 1073542431UL) + (unsigned char)115;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x6b,%eax
  xor    $0x1f,%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      } else {
        state[local1] |= (state[0UL] * state[0UL] & (unsigned char)31) << 3UL;
        state[0UL] |= (state[local1] * state[local1] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] > local1) {
        state[0UL] |= (state[0UL] & (unsigned char)7) << 2UL;
        state[0UL] |= ((state[0UL] + state[0UL]) & (unsigned char)15) << 2UL;
      } else {
        state[0UL] = (state[local1] << (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)) | (state[local1] >> (8 - (((state[0UL] >> (unsigned char)3) & (unsigned char)15) | 1UL)));
        state[0UL] |= (state[local1] & (unsigned char)15) << 3UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] ^ 1073542431UL) + (unsigned char)115;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L16:
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L16
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%edx
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string

tool: D4: Enter the number upto which the sum is to be calculated: 

tool: D15: %d

tool: D18: The sum is square of %d natural number is %d

assistant: ```c
int main() {
  int i, n, sum = 0, sq;
  printf("Enter the number upto which the sum is to be calculated: ");
  scanf("%d", &n);
  for (i = 0; i <= n; i++) {
    sq = i * i;
    sum = sum + sq;
  }
  printf("The sum is square of %d natural number is %d", n, sum);
  return 0;
}
```