ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp21>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L37
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L37
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
  jne    L37
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L37
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
L37:
  ret
```

assistant: ```c
int cmp21(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp21>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  jne    L36
  movsbl 0x2(%rdi),%eax
  movsbl 0x2(%rsi),%edx
  sub    %edx,%eax
  jne    L36
  movsbl 0x4(%rdi),%eax
  movsbl 0x4(%rsi),%edx
  sub    %edx,%eax
  jne    L36
  movsbl 0x1(%rdi),%eax
  movsbl 0x1(%rsi),%edx
  sub    %edx,%eax
  jne    L36
  movsbl 0x3(%rdi),%eax
  movsbl 0x3(%rsi),%edx
  sub    %edx,%eax
L36:
  ret
```

assistant: ```c
int cmp21(const void *a, const void *b) {
  const char *sa = a;
  const char *sb = b;
  int diff;
  if ((diff = sa[0] - sb[0]) != 0)
    return diff;
  if ((diff = sa[2] - sb[2]) != 0)
    return diff;
  if ((diff = sa[4] - sb[4]) != 0)
    return diff;
  if ((diff = sa[1] - sb[1]) != 0)
    return diff;
  if ((diff = sa[3] - sb[3]) != 0)
    return diff;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  movq   $0x80,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L21
  mov    -0x10(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L21:
  cmpq   $0x0,-0x28(%rbp)
  jne    L76
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0xffffffff,%eax
  jmp    L50
L76:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x30(%rbp)
L41:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x2c(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L74
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x30(%rbp)
  jle    L14
  mov    -0x30(%rbp),%eax
  jmp    L50
L14:
  mov    $0xffffffff,%eax
  jmp    L50
L74:
  mov    -0x30(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jne    L93
  shlq   -0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L107
  mov    $0xffffffff,%eax
  jmp    L50
L107:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L93:
  cmpl   $0xa,-0x2c(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x30(%rbp)
  jmp    L41
L30:
  nop
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%eax
L50:
  leave
  ret
```

assistant: ```c
ssize_t get_line(char **line, size_t *n, FILE *stream) {
  size_t const len_init = 128;
  char *buf = *line;
  size_t len = *n;
  if (!buf) {
    buf = malloc(sizeof(char) * len_init);
    len = len_init;
  }
  if (!buf) {
    *n = 0;
    return -1;
  }
  int ch;
  ssize_t i;
  char *ptr = buf;
  for (i = 0;; i++) {
    ch = fgetc(stream);
    if (ch == EOF) {
      *line = buf;
      *n = len;
      *ptr = 0;
      if (i > 0)
        return i;
      else
        return -1;
    }
    if (i == len) {
      char *new_buf = realloc(buf, len *= 2);
      if (!new_buf)
        return -1;
      ptr = new_buf + (ptr - buf);
      buf = new_buf;
    }
    if (ch == '\n')
      break;
    *ptr++ = ch;
  }
  *ptr = 0;
  *line = buf;
  *n = len;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,%r14
  mov    (%rdi),%r15
  mov    (%rsi),%r13
  test   %r15,%r15
  je     L52
L110:
  mov    %r15,%r12
  mov    $0x0,%ebp
  jmp    L107
L52:
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    $0x80,%r13d
  test   %rax,%rax
  jne    L110
  mov    0x10(%rsp),%rax
  movq   $0x0,(%rax)
  movl   $0xffffffff,0xc(%rsp)
  jmp    L20
L106:
  mov    0x18(%rsp),%rax
  mov    %r15,(%rax)
  mov    0x10(%rsp),%rax
  mov    %r13,(%rax)
  movb   $0x0,(%r12)
  cmpl   $0x0,0xc(%rsp)
  jle    L57
L20:
  mov    0xc(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L20
L129:
  add    $0x1,%rbp
  cmp    $0xa,%ebx
  je     L82
  mov    %bl,(%r12)
  lea    0x1(%r12),%r12
L107:
  mov    %ebp,0xc(%rsp)
  mov    %r14,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    D0(%rip),%rax
  cmp    %ebx,(%rax)
  je     L106
  cmp    %rbp,%r13
  jne    L129
  add    %r13,%r13
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L24
  sub    %r15,%r12
  add    %rax,%r12
  mov    %rax,%r15
  jmp    L129
L82:
  movb   $0x0,(%r12)
  mov    0x18(%rsp),%rax
  mov    %r15,(%rax)
  mov    0x10(%rsp),%rax
  mov    %r13,(%rax)
  jmp    L20
L24:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L20
```

assistant: ```c
ssize_t get_line(char **line, size_t *n, FILE *stream) {
  size_t const len_init = 128;
  char *buf = *line;
  size_t len = *n;
  if (!buf) {
    buf = malloc(sizeof(char) * len_init);
    len = len_init;
  }
  if (!buf) {
    *n = 0;
    return -1;
  }
  int ch;
  ssize_t i;
  char *ptr = buf;
  for (i = 0;; i++) {
    ch = fgetc(stream);
    if (ch == EOF) {
      *line = buf;
      *n = len;
      *ptr = 0;
      if (i > 0)
        return i;
      else
        return -1;
    }
    if (i == len) {
      char *new_buf = realloc(buf, len *= 2);
      if (!new_buf)
        return -1;
      ptr = new_buf + (ptr - buf);
      buf = new_buf;
    }
    if (ch == '\n')
      break;
    *ptr++ = ch;
  }
  *ptr = 0;
  *line = buf;
  *n = len;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdi),%r14
  mov    (%rsi),%rbx
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x10(%rsp)
  test   %r14,%r14
  je     L33
L60:
  mov    %r14,%r15
  xor    %r13d,%r13d
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L75:
  add    $0x1,%r13
  cmp    $0xa,%edx
  je     L90
L83:
  mov    %dl,(%r15)
  add    $0x1,%r15
L11:
  mov    %rbp,%rdi
  mov    %r13d,%r12d
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    D0(%rip),%rax
  cmp    %edx,(%rax)
  je     L8
  cmp    %r13,%rbx
  jne    L75
  add    %rbx,%rbx
  mov    %r14,%rdi
  mov    %edx,0xc(%rsp)
  mov    %rbx,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L80
  mov    %r15,%r8
  mov    0xc(%rsp),%edx
  add    $0x1,%r13
  sub    %r14,%r8
  mov    %rax,%r14
  lea    (%rax,%r8,1),%r15
  cmp    $0xa,%edx
  jne    L83
  nopw   0x0(%rax,%rax,1)
L90:
  mov    0x18(%rsp),%rax
  movb   $0x0,(%r15)
  mov    %r14,(%rax)
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  jmp    L85
  xchg   %ax,%ax
L8:
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  movb   $0x0,(%r15)
  test   %r13d,%r13d
  je     L80
L85:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L52
  mov    $0x80,%ebx
  jmp    L60
L80:
  mov    $0xffffffff,%r12d
  jmp    L85
L52:
  mov    0x10(%rsp),%rax
  mov    $0xffffffff,%r12d
  movq   $0x0,(%rax)
  jmp    L85
```

assistant: ```c
ssize_t get_line(char **line, size_t *n, FILE *stream) {
  size_t const len_init = 128;
  char *buf = *line;
  size_t len = *n;
  if (!buf) {
    buf = malloc(sizeof(char) * len_init);
    len = len_init;
  }
  if (!buf) {
    *n = 0;
    return -1;
  }
  int ch;
  ssize_t i;
  char *ptr = buf;
  for (i = 0;; i++) {
    ch = fgetc(stream);
    if (ch == EOF) {
      *line = buf;
      *n = len;
      *ptr = 0;
      if (i > 0)
        return i;
      else
        return -1;
    }
    if (i == len) {
      char *new_buf = realloc(buf, len *= 2);
      if (!new_buf)
        return -1;
      ptr = new_buf + (ptr - buf);
      buf = new_buf;
    }
    if (ch == '\n')
      break;
    *ptr++ = ch;
  }
  *ptr = 0;
  *line = buf;
  *n = len;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdi),%r14
  mov    (%rsi),%rbx
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x10(%rsp)
  test   %r14,%r14
  je     L78
L101:
  mov    %r14,%r15
  xor    %r13d,%r13d
  jmp    L59
  cs nopw 0x0(%rax,%rax,1)
L73:
  add    $0x1,%r13
  cmp    $0xa,%edx
  je     L28
L115:
  mov    %dl,(%r15)
  add    $0x1,%r15
L59:
  mov    %rbp,%rdi
  mov    %r13d,%r12d
  call   <fgetc@plt>
  mov    %eax,%edx
  mov    D0(%rip),%rax
  cmp    %edx,(%rax)
  je     L99
  cmp    %r13,%rbx
  jne    L73
  add    %rbx,%rbx
  mov    %r14,%rdi
  mov    %edx,0xc(%rsp)
  mov    %rbx,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L112
  mov    %r15,%r8
  mov    0xc(%rsp),%edx
  add    $0x1,%r13
  sub    %r14,%r8
  mov    %rax,%r14
  lea    (%rax,%r8,1),%r15
  cmp    $0xa,%edx
  jne    L115
  nopw   0x0(%rax,%rax,1)
L28:
  mov    0x18(%rsp),%rax
  movb   $0x0,(%r15)
  mov    %r14,(%rax)
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  jmp    L70
  xchg   %ax,%ax
L99:
  mov    0x18(%rsp),%rax
  mov    %r14,(%rax)
  mov    0x10(%rsp),%rax
  mov    %rbx,(%rax)
  movb   $0x0,(%r15)
  test   %r13d,%r13d
  je     L112
L70:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L78:
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L58
  mov    $0x80,%ebx
  jmp    L101
L112:
  mov    $0xffffffff,%r12d
  jmp    L70
L58:
  mov    0x10(%rsp),%rax
  mov    $0xffffffff,%r12d
  movq   $0x0,(%rax)
  jmp    L70
```

assistant: ```c
ssize_t get_line(char **line, size_t *n, FILE *stream) {
  size_t const len_init = 128;
  char *buf = *line;
  size_t len = *n;
  if (!buf) {
    buf = malloc(sizeof(char) * len_init);
    len = len_init;
  }
  if (!buf) {
    *n = 0;
    return -1;
  }
  int ch;
  ssize_t i;
  char *ptr = buf;
  for (i = 0;; i++) {
    ch = fgetc(stream);
    if (ch == EOF) {
      *line = buf;
      *n = len;
      *ptr = 0;
      if (i > 0)
        return i;
      else
        return -1;
    }
    if (i == len) {
      char *new_buf = realloc(buf, len *= 2);
      if (!new_buf)
        return -1;
      ptr = new_buf + (ptr - buf);
      buf = new_buf;
    }
    if (ch == '\n')
      break;
    *ptr++ = ch;
  }
  *ptr = 0;
  *line = buf;
  *n = len;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  shr    $0x3f,%rdi
  add    %rbp,%rdi
  sar    %rdi
  sub    $0x1,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  cmp    $0x3,%rbp
  jle    L178
  sub    $0x4,%rbp
  and    $0xfffffffffffffffe,%rbp
  lea    0x4(%rbp),%rcx
  mov    $0x2,%edx
L143:
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rdx,%rax
  sar    %rax
  movb   $0x1,-0x1(%rbx,%rax,1)
  add    $0x2,%rdx
  cmp    %rcx,%rdx
  jne    L143
L178:
  mov    $0x3,%ebp
  jmp    L41
L119:
  add    $0x2,%rbp
L41:
  pxor   %xmm0,%xmm0
  cvtsi2ssq 0x10(%rsp),%xmm0
  call   <sqrtf@plt>
  cmp    %rbp,%rax
  jle    L70
  mov    %rbp,%rsi
  lea    -0x1(%rbp),%rdx
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rdx,%rax
  sar    %rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  je     L119
  mov    %rbp,%rdx
  imul   %rbp,%rdx
  mov    0x10(%rsp),%rdi
  cmp    %rdi,%rdx
  jge    L119
  add    %rsi,%rsi
L96:
  lea    -0x1(%rdx),%rcx
  mov    %rcx,%rax
  shr    $0x3f,%rax
  add    %rcx,%rax
  sar    %rax
  movb   $0x0,-0x1(%rbx,%rax,1)
  add    %rsi,%rdx
  cmp    %rdi,%rdx
  jl     L96
  jmp    L119
L70:
  mov    0x10(%rsp),%r9
  mov    0x8(%rsp),%r10
  mov    $0x526d,%ebp
  mov    $0x0,%r8d
L93:
  lea    -0x2774(%rbp),%rdi
  lea    -0x2b5c(%rbp),%r11
  jmp    L48
L120:
  mov    %r8,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
L55:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L71:
  add    $0x64,%rax
  cmp    %rdi,%rax
  je     L176
L3:
  cmp    %rax,%r9
  jle    L120
  lea    -0x1(%rax),%rcx
  mov    %rcx,%rdx
  shr    $0x3f,%rdx
  add    %rcx,%rdx
  sar    %rdx
  cmpb   $0x0,-0x1(%rbx,%rdx,1)
  je     L71
  cmp    %rax,%r10
  setle  %dl
  movzbl %dl,%edx
  add    %rdx,%r8
  jmp    L71
L176:
  add    $0x3f2,%rdi
  add    $0x3f2,%r11
  cmp    %rbp,%rdi
  je     L54
L48:
  mov    %r11,%rax
  jmp    L3
L54:
  add    $0x4e22,%rbp
  cmp    $0x1d917,%rbp
  jne    L93
  jmp    L55
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D15
datatype: string

tool: D18: %ld %ld

tool: D15: %ld


assistant: ```c
int main() {
  long a, b, count = 0, i, j, n;
  scanf("%ld %ld", &a, &b);
  char *primes = malloc(b / 2 - 1);
  for (i = 3; i < b; i += 2)
    primes[(i - 1) / 2 - 1] = 1;
  for (i = 3; i < sqrtf((float)b); i += 2) {
    if (primes[(i - 1) / 2 - 1])
      for (j = i * i; j < b; j += i * 2)
        primes[(j - 1) / 2 - 1] = 0;
  }
  char k;
  for (i = 1; i < 10; i += 2)
    for (j = 0; j < 10; j++)
      for (k = 0; k < 10; k++) {
        n = i * 10001 + j * 1010 + k * 100;
        if (n >= b) {
          printf("%ld\n", count);
          return 0;
        }
        if (primes[(n - 1) / 2 - 1] && a <= n)
          count++;
      }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  shr    $0x3f,%rdi
  add    %rbp,%rdi
  sar    %rdi
  sub    $0x1,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  cmp    $0x3,%rbp
  jle    L42
  lea    -0x4(%rbp),%rcx
  mov    $0x2,%eax
  and    $0xfffffffffffffffe,%rcx
  add    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rax,%rdx
  add    $0x2,%rax
  sar    %rdx
  movb   $0x1,-0x1(%rbx,%rdx,1)
  cmp    %rcx,%rax
  jne    L23
L42:
  mov    $0x3,%r12d
  jmp    L57
  nopl   0x0(%rax)
L5:
  add    $0x2,%r12
L57:
  pxor   %xmm0,%xmm0
  cvtsi2ss %rbp,%xmm0
  call   <sqrtf@plt>
  cmp    %r12,%rax
  jle    L44
  lea    -0x1(%r12),%rax
  mov    0x10(%rsp),%rbp
  sar    %rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  je     L5
  mov    %r12,%rdx
  imul   %r12,%rdx
  cmp    %rbp,%rdx
  jge    L5
  lea    (%r12,%r12,1),%rsi
  nopl   0x0(%rax,%rax,1)
L16:
  lea    -0x1(%rdx),%rcx
  add    %rsi,%rdx
  mov    %rcx,%rax
  shr    $0x3f,%rax
  add    %rcx,%rax
  sar    %rax
  movb   $0x0,-0x1(%rbx,%rax,1)
  cmp    %rbp,%rdx
  jl     L16
  jmp    L5
L44:
  mov    0x10(%rsp),%rdi
  mov    0x8(%rsp),%r8
  mov    $0x526d,%r10d
  xor    %esi,%esi
L97:
  lea    -0x2774(%r10),%rcx
  lea    -0x2b5c(%r10),%r9
L46:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L55:
  cmp    %rax,%rdi
  jle    L7
  lea    -0x1(%rax),%rdx
  sar    %rdx
  cmpb   $0x0,-0x1(%rbx,%rdx,1)
  je     L74
  xor    %edx,%edx
  cmp    %rax,%r8
  setle  %dl
  add    %rdx,%rsi
L74:
  add    $0x64,%rax
  cmp    %rax,%rcx
  jne    L55
  add    $0x3f2,%rcx
  add    $0x3f2,%r9
  cmp    %r10,%rcx
  jne    L46
  add    $0x4e22,%r10
  cmp    $0x1d917,%r10
  je     L38
  jmp    L97
  nopl   0x0(%rax)
L7:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D11: %ld %ld

tool: D15: %ld


assistant: ```c
int main() {
  long a, b, count = 0, i, j, n;
  scanf("%ld %ld", &a, &b);
  char *primes = malloc(b / 2 - 1);
  for (i = 3; i < b; i += 2)
    primes[(i - 1) / 2 - 1] = 1;
  for (i = 3; i < sqrtf((float)b); i += 2) {
    if (primes[(i - 1) / 2 - 1])
      for (j = i * i; j < b; j += i * 2)
        primes[(j - 1) / 2 - 1] = 0;
  }
  char k;
  for (i = 1; i < 10; i += 2)
    for (j = 0; j < 10; j++)
      for (k = 0; k < 10; k++) {
        n = i * 10001 + j * 1010 + k * 100;
        if (n >= b) {
          printf("%ld\n", count);
          return 0;
        }
        if (primes[(n - 1) / 2 - 1] && a <= n)
          count++;
      }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L24
  cmpl   $0x2,-0x14(%rbp)
  jne    L94
L24:
  cmpl   $0x1,-0x14(%rbp)
  jne    L44
L94:
  mov    $0x0,%eax
  jmp    L14
L44:
  cmpl   $0x2,-0x14(%rbp)
  jne    L9
  mov    $0x1,%eax
  jmp    L14
L9:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L28
L58:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L86
  mov    $0x0,%eax
  jmp    L14
L86:
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L58
  mov    $0x1,%eax
L14:
  leave
  ret
```

assistant: ```c
int check_prime(int num) {
  if (num % 2 == 0 && num != 2 || num == 1)
    return 0;
  else if (num == 2)
    return 1;
  int j, k;
  k = sqrt(num);
  for (j = 3; j <= k; j++) {
    if (num % j == 0)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_prime>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   $0x1,%dil
  jne    L28
  mov    $0x0,%eax
  cmp    $0x2,%edi
  jne    L60
L28:
  mov    $0x0,%eax
  cmp    $0x1,%ebx
  je     L60
  mov    $0x1,%eax
  cmp    $0x2,%ebx
  je     L60
  mov    %ebx,%edi
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L7
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  je     L60
  mov    $0x3,%ecx
L20:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jl     L76
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L20
  jmp    L60
L76:
  mov    $0x1,%eax
L60:
  pop    %rbx
  ret
L7:
  mov    $0x1,%eax
  jmp    L60
```

assistant: ```c
int check_prime(int num) {
  if (num % 2 == 0 && num != 2 || num == 1)
    return 0;
  else if (num == 2)
    return 1;
  int j, k;
  k = sqrt(num);
  for (j = 3; j <= k; j++) {
    if (num % j == 0)
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L34
  test   $0x1,%dil
  je     L15
L34:
  cmp    $0x1,%r12d
  je     L15
  cmp    $0x2,%r12d
  je     L59
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L59
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L15
  mov    $0x3,%ecx
  jmp    L49
  nopl   0x0(%rax)
L33:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L15
L49:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L33
L59:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int check_prime(int num) {
  if (num % 2 == 0 && num != 2 || num == 1)
    return 0;
  else if (num == 2)
    return 1;
  int j, k;
  k = sqrt(num);
  for (j = 3; j <= k; j++) {
    if (num % j == 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_prime>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  cmp    $0x2,%edi
  je     L86
  test   $0x1,%dil
  je     L25
L86:
  cmp    $0x1,%r12d
  je     L25
  cmp    $0x2,%r12d
  je     L17
  mov    %r12d,%edi
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x2,%eax
  jle    L17
  imul   $0xaaaaaaab,%r12d,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L25
  mov    $0x3,%ecx
  jmp    L15
  nopl   0x0(%rax)
L77:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L25
L15:
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jge    L77
L17:
  mov    $0x1,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int check_prime(int num) {
  if (num % 2 == 0 && num != 2 || num == 1)
    return 0;
  else if (num == 2)
    return 1;
  int j, k;
  k = sqrt(num);
  for (j = 3; j <= k; j++) {
    if (num % j == 0)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <misra_5_2_func1@plt>
  cmp    $0x1,%eax
  jne    L35
  jmp    L10
L15:
  nop
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L48:
  mov    $0x0,%eax
  call   <misra_5_2_func3@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  cmpl   $0x9,-0x4(%rbp)
  jle    L48
  mov    $0x0,%eax
  call   <misra_5_2_func2@plt>
  test   %eax,%eax
  jne    L15
L35:
  nop
  leave
  ret
```

assistant: ```c
void foo(void) {
  int i;
  switch (misra_5_2_func1()) {
  case 1: {
    do {
      for (i = 0; i < 10; i++) {
        if (misra_5_2_func3()) {
          int misra_5_2_var_hides_var_1____31x;
          int misra_5_2_var_hides_var_1____31y;
        }
      }
    } while (misra_5_2_func2());
  }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <misra_5_2_func1@plt>
  cmp    $0x1,%eax
  je     L23
L14:
  pop    %rbx
  ret
L23:
  mov    $0xa,%ebx
L6:
  mov    $0x0,%eax
  call   <misra_5_2_func3@plt>
  sub    $0x1,%ebx
  jne    L6
  mov    $0x0,%eax
  call   <misra_5_2_func2@plt>
  test   %eax,%eax
  jne    L23
  jmp    L14
```

assistant: ```c
void foo(void) {
  int i;
  switch (misra_5_2_func1()) {
  case 1: {
    do {
      for (i = 0; i < 10; i++) {
        if (misra_5_2_func3()) {
          int misra_5_2_var_hides_var_1____31x;
          int misra_5_2_var_hides_var_1____31y;
        }
      }
    } while (misra_5_2_func2());
  }
  }
}
```