ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <upcase@plt>
  cmp    $0x40,%al
  jg     L10
  movsbl (%rbx),%ebp
  movsbl 0x1(%rbx),%edi
  sub    $0x30,%ebp
  shl    $0x4,%ebp
  call   <upcase@plt>
  cmp    $0x40,%al
  jg     L2
L18:
  movsbl 0x1(%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  lea    -0x30(%rbp,%rax,1),%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L10:
  movsbl (%rbx),%edi
  call   <upcase@plt>
  movsbl 0x1(%rbx),%edi
  movsbl %al,%ebp
  sub    $0x37,%ebp
  shl    $0x4,%ebp
  call   <upcase@plt>
  cmp    $0x40,%al
  jle    L18
L2:
  movsbl 0x1(%rbx),%edi
  call   <upcase@plt>
  add    $0x8,%rsp
  movsbl %al,%eax
  pop    %rbx
  lea    -0x37(%rbp,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hex2dec(char *chr) {
  int res = 0;
  int i;
  for (i = 0; i < 2; i++) {
    if (upcase(chr[i]) >= 'A') {
      res += (upcase(chr[i]) - 'A' + 10) << (4 * (1 - i));
    } else {
      res += (chr[i] - '0') << (4 * (1 - i));
    }
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <upcase@plt>
  cmp    $0x40,%al
  jg     L25
  movsbl (%rbx),%ebp
  movsbl 0x1(%rbx),%edi
  sub    $0x30,%ebp
  shl    $0x4,%ebp
  call   <upcase@plt>
  cmp    $0x40,%al
  jg     L11
L6:
  movsbl 0x1(%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  lea    -0x30(%rbp,%rax,1),%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L25:
  movsbl (%rbx),%edi
  call   <upcase@plt>
  movsbl 0x1(%rbx),%edi
  movsbl %al,%ebp
  sub    $0x37,%ebp
  shl    $0x4,%ebp
  call   <upcase@plt>
  cmp    $0x40,%al
  jle    L6
L11:
  movsbl 0x1(%rbx),%edi
  call   <upcase@plt>
  add    $0x8,%rsp
  movsbl %al,%eax
  pop    %rbx
  lea    -0x37(%rbp,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hex2dec(char *chr) {
  int res = 0;
  int i;
  for (i = 0; i < 2; i++) {
    if (upcase(chr[i]) >= 'A') {
      res += (upcase(chr[i]) - 'A' + 10) << (4 * (1 - i));
    } else {
      res += (chr[i] - '0') << (4 * (1 - i));
    }
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<simp3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %edx,%edi
  movslq %ecx,%rax
  lea    0x8(%r10,%rax,8),%r9
  movslq %r8d,%r12
  add    $0x1,%r12
  mov    (%r9),%rax
  movss  D17(%rip),%xmm2
  divss  (%rax,%r12,4),%xmm2
  test   %esi,%esi
  js     L121
  mov    %ecx,%ebp
  lea    0x0(,%r12,4),%r11
  mov    %esi,%ebx
  mov    $0x0,%esi
  mov    $0x0,%r13d
  jmp    L110
L97:
  mov    0x8(%r10,%rsi,8),%r14
  lea    (%r14,%rdx,1),%rcx
  mov    (%r9),%r15
  movss  (%r15,%rdx,1),%xmm1
  mulss  (%r14,%r11,1),%xmm1
  movss  (%rcx),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rcx)
L10:
  lea    0x1(%rax),%ecx
  add    $0x4,%rdx
  cmp    %edi,%eax
  je     L66
  mov    %ecx,%eax
L96:
  cmp    %eax,%r8d
  jne    L97
  jmp    L10
L66:
  lea    0x1(%rsi),%rax
  cmp    %rbx,%rsi
  je     L121
  mov    %rax,%rsi
L110:
  cmp    %esi,%ebp
  je     L66
  mov    %r11,%rax
  add    0x8(%r10,%rsi,8),%rax
  movaps %xmm2,%xmm0
  mulss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  test   %edi,%edi
  js     L66
  mov    $0x4,%edx
  mov    %r13d,%eax
  jmp    L96
L121:
  test   %edi,%edi
  js     L61
  mov    $0x4,%edx
  mov    $0x0,%eax
  movaps %xmm2,%xmm1
  xorps  D7(%rip),%xmm1
  jmp    L21
L105:
  lea    0x1(%rax),%ecx
  add    $0x4,%rdx
  cmp    %edi,%eax
  je     L61
  mov    %ecx,%eax
L21:
  cmp    %r8d,%eax
  je     L105
  mov    %rdx,%rcx
  add    (%r9),%rcx
  movaps %xmm1,%xmm0
  mulss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  jmp    L105
L61:
  mov    (%r9),%rax
  movss  %xmm2,(%rax,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: f32
name: parse_data
arguments: data_tag: D7
type_guessed: byte[16]

tool: D17: 1

tool: {"D7": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void simp3(float **a, int i1, int k1, int ip, int kp) {
  int kk, ii;
  float piv;
  piv = 1.0 / a[ip + 1][kp + 1];
  for (ii = 1; ii <= i1 + 1; ii++)
    if (ii - 1 != ip) {
      a[ii][kp + 1] *= piv;
      for (kk = 1; kk <= k1 + 1; kk++)
        if (kk - 1 != kp)
          a[ii][kk] -= a[ip + 1][kk] * a[ii][kp + 1];
    }
  for (kk = 1; kk <= k1 + 1; kk++)
    if (kk - 1 != kp)
      a[ip + 1][kk] *= -piv;
  a[ip + 1][kp + 1] = piv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simp3>:
  endbr64
  push   %r15
  movss  D2(%rip),%xmm2
  xor    %r9d,%r9d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  movslq %ecx,%rdx
  mov    0x8(%rbx,%rdx,8),%rcx
  mov    %rdx,%r11
  movslq %r8d,%rdx
  mov    %rdi,%r10
  lea    0x4(,%rdx,4),%r13
  lea    0x1(%rdi),%r12d
  lea    (%rcx,%r13,1),%r14
  divss  (%r14),%xmm2
  test   %ebp,%ebp
  js     L46
  nopw   0x0(%rax,%rax,1)
L11:
  cmp    %r9d,%r11d
  je     L37
  mov    0x8(%rbx,%r9,8),%rdx
  lea    (%rdx,%r13,1),%rsi
  movss  (%rsi),%xmm0
  mulss  %xmm2,%xmm0
  movss  %xmm0,(%rsi)
  test   %r12d,%r12d
  jle    L37
  xor    %eax,%eax
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %r15,%rax
L16:
  cmp    %eax,%r8d
  je     L18
  movss  0x4(%rcx,%rax,4),%xmm1
  mulss  (%rsi),%xmm1
  movss  0x4(%rdx,%rax,4),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx,%rax,4)
L18:
  lea    0x1(%rax),%r15
  cmp    %rdi,%rax
  jne    L79
L37:
  lea    0x1(%r9),%rax
  cmp    %rbp,%r9
  je     L46
  mov    %rax,%r9
  jmp    L11
  nopl   0x0(%rax)
L46:
  movaps %xmm2,%xmm1
  xor    %eax,%eax
  xorps  D9(%rip),%xmm1
  test   %r12d,%r12d
  jg     L98
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %rdx,%rax
L98:
  cmp    %eax,%r8d
  je     L107
  movss  0x4(%rcx,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rcx,%rax,4)
L107:
  lea    0x1(%rax),%rdx
  cmp    %rax,%r10
  jne    L33
L51:
  movss  %xmm2,(%r14)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: f32
name: retrieve_data
arguments: label: D9
type_infered: byte[16]

tool: D2: 1

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void simp3(float **a, int i1, int k1, int ip, int kp) {
  int kk, ii;
  float piv;
  piv = 1.0 / a[ip + 1][kp + 1];
  for (ii = 1; ii <= i1 + 1; ii++)
    if (ii - 1 != ip) {
      a[ii][kp + 1] *= piv;
      for (kk = 1; kk <= k1 + 1; kk++)
        if (kk - 1 != kp)
          a[ii][kk] -= a[ip + 1][kk] * a[ii][kp + 1];
    }
  for (kk = 1; kk <= k1 + 1; kk++)
    if (kk - 1 != kp)
      a[ip + 1][kk] *= -piv;
  a[ip + 1][kp + 1] = piv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<simp3>:
  endbr64
  movslq %ecx,%rax
  push   %r15
  mov    %esi,%r11d
  movss  D5(%rip),%xmm2
  push   %r14
  mov    %edx,%r10d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rax,%rbp
  push   %rbx
  mov    0x8(%rdi,%rax,8),%rcx
  movslq %r8d,%rax
  lea    0x4(,%rax,4),%r12
  lea    (%rcx,%r12,1),%r14
  divss  (%r14),%xmm2
  test   %r11d,%r11d
  js     L89
  mov    %rdi,%rbx
  lea    0x1(%r10),%r13d
  xor    %r9d,%r9d
  mov    %r10d,%edi
  nopl   (%rax)
L9:
  cmp    %r9d,%ebp
  je     L51
  mov    0x8(%rbx,%r9,8),%rdx
  lea    (%rdx,%r12,1),%rsi
  movss  (%rsi),%xmm0
  mulss  %xmm2,%xmm0
  movss  %xmm0,(%rsi)
  test   %r13d,%r13d
  jle    L51
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %r15,%rax
L67:
  cmp    %eax,%r8d
  je     L108
  movss  0x4(%rcx,%rax,4),%xmm1
  mulss  (%rsi),%xmm1
  movss  0x4(%rdx,%rax,4),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdx,%rax,4)
L108:
  lea    0x1(%rax),%r15
  cmp    %rax,%rdi
  jne    L54
L51:
  lea    0x1(%r9),%rax
  cmp    %r9,%r11
  je     L89
  mov    %rax,%r9
  jmp    L9
  nopl   0x0(%rax)
L89:
  test   %r10d,%r10d
  js     L110
  movaps %xmm2,%xmm1
  xor    %eax,%eax
  xorps  D9(%rip),%xmm1
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %rdx,%rax
L25:
  cmp    %eax,%r8d
  je     L40
  movss  0x4(%rcx,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rcx,%rax,4)
L40:
  lea    0x1(%rax),%rdx
  cmp    %r10,%rax
  jne    L42
L110:
  movss  %xmm2,(%r14)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: f32
name: read_data
arguments: data_tag: D9
data_type: byte[16]

tool: D5: 1

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void simp3(float **a, int i1, int k1, int ip, int kp) {
  int kk, ii;
  float piv;
  piv = 1.0 / a[ip + 1][kp + 1];
  for (ii = 1; ii <= i1 + 1; ii++)
    if (ii - 1 != ip) {
      a[ii][kp + 1] *= piv;
      for (kk = 1; kk <= k1 + 1; kk++)
        if (kk - 1 != kp)
          a[ii][kk] -= a[ip + 1][kk] * a[ii][kp + 1];
    }
  for (kk = 1; kk <= k1 + 1; kk++)
    if (kk - 1 != kp)
      a[ip + 1][kk] *= -piv;
  a[ip + 1][kp + 1] = piv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lcm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %ax,-0x4(%rbp)
  jmp    L9
L2:
  movzwl -0x4(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  movzwl -0x2(%rbp),%eax
  mov    %ax,-0x4(%rbp)
L9:
  movswl -0x6(%rbp),%eax
  movswl -0x4(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %ax,-0x2(%rbp)
  cmpw   $0x0,-0x2(%rbp)
  jne    L2
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  movswl -0x4(%rbp),%esi
  cltd
  idiv   %esi
  pop    %rbp
  ret
```

assistant: ```c
int lcm(int x, int y) {
  short a, b, c;
  a = x;
  b = y;
  while ((c = a % b) != 0) {
    a = b;
    b = c;
  }
  return (x * y / b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lcm>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
L9:
  movswl %r8w,%ecx
  cwtl
  cltd
  idiv   %ecx
  mov    %r8d,%eax
  mov    %edx,%r8d
  test   %dx,%dx
  jne    L9
  mov    %edi,%eax
  imul   %esi,%eax
  cltd
  idiv   %ecx
  ret
```

assistant: ```c
int lcm(int x, int y) {
  short a, b, c;
  a = x;
  b = y;
  while ((c = a % b) != 0) {
    a = b;
    b = c;
  }
  return (x * y / b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcm>:
  endbr64
  movswl %di,%eax
  mov    %esi,%r8d
  nopw   0x0(%rax,%rax,1)
L1:
  movswl %r8w,%ecx
  cltd
  idiv   %ecx
  movswl %r8w,%eax
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L1
  mov    %edi,%eax
  imul   %esi,%eax
  cltd
  idiv   %ecx
  ret
```

assistant: ```c
int lcm(int x, int y) {
  short a, b, c;
  a = x;
  b = y;
  while ((c = a % b) != 0) {
    a = b;
    b = c;
  }
  return (x * y / b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lcm>:
  endbr64
  movswl %di,%eax
  mov    %esi,%r8d
  nopw   0x0(%rax,%rax,1)
L4:
  movswl %r8w,%ecx
  cltd
  idiv   %ecx
  movswl %r8w,%eax
  mov    %edx,%r8d
  test   %edx,%edx
  jne    L4
  mov    %edi,%eax
  imul   %esi,%eax
  cltd
  idiv   %ecx
  ret
```

assistant: ```c
int lcm(int x, int y) {
  short a, b, c;
  a = x;
  b = y;
  while ((c = a % b) != 0) {
    a = b;
    b = c;
  }
  return (x * y / b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checkendianness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L4
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L4:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string

tool: D19:  Little Endian


tool: D1:  Big Endian


assistant: ```c
void checkendianness() {
  unsigned int a = 1;
  char *p = (char *)&a;
  if (*p == 1) {
    printf(" Little Endian\n");
  } else {
    printf(" Big Endian\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<checkendianness>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6:  Little Endian


assistant: ```c
void checkendianness() {
  unsigned int a = 1;
  char *p = (char *)&a;
  if (*p == 1) {
    printf(" Little Endian\n");
  } else {
    printf(" Big Endian\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<checkendianness>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: string

tool: D0:  Little Endian


assistant: ```c
void checkendianness() {
  unsigned int a = 1;
  char *p = (char *)&a;
  if (*p == 1) {
    printf(" Little Endian\n");
  } else {
    printf(" Big Endian\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checkendianness>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string

tool: D5:  Little Endian


assistant: ```c
void checkendianness() {
  unsigned int a = 1;
  char *p = (char *)&a;
  if (*p == 1) {
    printf(" Little Endian\n");
  } else {
    printf(" Big Endian\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  short a;
  int b = nondet_int();
  a = (short)b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  short a;
  int b = nondet_int();
  a = (short)b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  short a;
  int b = nondet_int();
  a = (short)b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  short a;
  int b = nondet_int();
  a = (short)b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
L1:
  movslq %ebx,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movslq %ebx,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    $0x0,%eax
  jmp    L14
L8:
  mov    %ebx,%eax
  lea    0x1(%rax),%ebx
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x1,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
eq(a, b) char *a, *b;
{
  register int i;
  i = 0;
l:
  if (a[i] != b[i])
    return (0);
  if (a[i++] == '\0')
    return (1);
  goto l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eq>:
  endbr64
  mov    $0x0,%eax
L3:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  jne    L15
  add    $0x1,%rax
  test   %dl,%dl
  jne    L3
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
```

assistant: ```c
eq(a, b) char *a, *b;
{
  register int i;
  i = 0;
l:
  if (a[i] != b[i])
    return (0);
  if (a[i++] == '\0')
    return (1);
  goto l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eq>:
  endbr64
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x1,%rax
  test   %dl,%dl
  je     L2
L26:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  je     L28
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
eq(a, b) char *a, *b;
{
  register int i;
  i = 0;
l:
  if (a[i] != b[i])
    return (0);
  if (a[i++] == '\0')
    return (1);
  goto l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eq>:
  endbr64
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L0:
  movzbl (%rdi,%rax,1),%edx
  cmp    (%rsi,%rax,1),%dl
  je     L20
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
eq(a, b) char *a, *b;
{
  register int i;
  i = 0;
l:
  if (a[i] != b[i])
    return (0);
  if (a[i++] == '\0')
    return (1);
  goto l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  jmp    L9
L1:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x79(%rbp)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x74(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x79(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x74(%rbp)
  subl   $0x1,-0x78(%rbp)
L9:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jg     L1
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main() {
  char bykva, dyma[100];
  int m, k = 0;
  gets(dyma);
  m = strlen(dyma) - 1;
  while (m > k) {
    bykva = dyma[k];
    dyma[k] = dyma[m];
    dyma[m] = bykva;
    k = k + 1, m = m - 1;
  }
  puts(dyma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L6
  mov    %rsp,%rcx
  movslq %eax,%rdx
  add    %rbx,%rdx
  mov    $0x0,%esi
L0:
  movzbl (%rcx),%edi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rcx)
  mov    %dil,-0x1(%rdx)
  add    $0x1,%esi
  add    $0x1,%rcx
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %esi,%edi
  sub    $0x1,%edi
  cmp    %edi,%esi
  jl     L0
L6:
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char bykva, dyma[100];
  int m, k = 0;
  gets(dyma);
  m = strlen(dyma) - 1;
  while (m > k) {
    bykva = dyma[k];
    dyma[k] = dyma[m];
    dyma[m] = bykva;
    k = k + 1, m = m - 1;
  }
  puts(dyma);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L16
  movslq %eax,%rdx
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  add    %rbp,%rdx
  nopl   0x0(%rax)
L18:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  add    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jl     L18
L16:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char bykva, dyma[100];
  int m, k = 0;
  gets(dyma);
  m = strlen(dyma) - 1;
  while (m > k) {
    bykva = dyma[k];
    dyma[k] = dyma[m];
    dyma[m] = bykva;
    k = k + 1, m = m - 1;
  }
  puts(dyma);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L18
  movslq %eax,%rdx
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  add    %rbp,%rdx
  nopl   0x0(%rax)
L23:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  add    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jl     L23
L18:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char bykva, dyma[100];
  int m, k = 0;
  gets(dyma);
  m = strlen(dyma) - 1;
  while (m > k) {
    bykva = dyma[k];
    dyma[k] = dyma[m];
    dyma[m] = bykva;
    k = k + 1, m = m - 1;
  }
  puts(dyma);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L7
  jmp    L29
L25:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <extract@plt>
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  jmp    L4
L7:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: unu
(c) 2013-2017 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013-2017 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L3
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L10:
  mov    (%rbx),%rdi
  call   <extract@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
L1:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    (%rsi),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: unu
(c) 2013-2017 charles childers

Try:
  %s filename


assistant: ```c
int main(int argc, char **argv) {
  int i = 1;
  if (argc > 1) {
    while (i < argc) {
      extract(argv[i++]);
    }
  } else
    printf("unu\n(c) 2013-2017 charles childers\n\nTry:\n  %s filename\n", argv[0]);
  return 0;
}
```