ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<excellent>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x14(%rdi),%r13
  mov    $0x0,%r14d
  jmp    L75
L25:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L43
L44:
  movss  (%rbx),%xmm0
  movd   %r12d,%xmm1
  addss  %xmm0,%xmm1
  movd   %xmm1,%r12d
  comiss D46(%rip),%xmm0
  sbb    $0xffffffff,%ebp
  cmp    $0x4,%ebp
  jle    L25
  mov    %r15d,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L43:
  movd   %r12d,%xmm0
  divss  D29(%rip),%xmm0
  comiss D3(%rip),%xmm0
  jae    L53
L22:
  add    $0x1,%r14
  add    $0x14,%r13
  cmp    $0x4,%r14
  je     L58
L75:
  mov    %r14d,%r15d
  lea    -0x14(%r13),%rbx
  mov    D12(%rip),%r12d
  mov    $0x0,%ebp
  jmp    L44
L53:
  mov    %r15d,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D46
data_type: byte[4]
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D29
data_type: byte[4]
name: disassemble_data
arguments: label: D3
data_type: byte[4]
name: disassemble_data
arguments: label: D12
data_type: byte[4]
name: disassemble_data
arguments: label: D36
data_type: string

tool: {"D46": [0x00,0x00,0xaa,0x42]}

tool: D14: da yu ba shi wu student %d
 

tool: {"D29": [0x00,0x00,0xa0,0x40]}

tool: {"D3": [0x00,0x00,0xb4,0x42]}

tool: {"D12": [0x00,0x00,0x00,0x00]}

tool: D36: da yu jiu shi student %d


assistant: ```c
void excellent(float (*b)[5]) {
  int n[27] = {0}, x[27] = {0};
  int i, j = 0, k, h = 0, f = 0;
  float w;
  for (i = 0; i < 4; i++) {
    h = 0, f = 0;
    w = 0;
    for (k = 0; k < 5; k++) {
      w = w + *(*(b + i) + k);
      if (*(*(b + i) + k) >= 85)
        h++;
      if (h >= 5)
        printf("da yu ba shi wu student %d\n ", i);
    }
    if ((w / 5) >= 90)
      printf("da yu jiu shi student %d\n", i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<excellent>:
  endbr64
  push   %r15
  lea    0x14(%rdi),%r15
  push   %r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
L49:
  mov    %r12d,%r14d
  lea    -0x14(%r15),%rbx
  pxor   %xmm1,%xmm1
  xor    %ebp,%ebp
L25:
  movss  (%rbx),%xmm0
  comiss D13(%rip),%xmm0
  addss  %xmm0,%xmm1
  sbb    $0xffffffff,%ebp
  cmp    $0x4,%ebp
  jg     L16
L26:
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L25
  divss  D24(%rip),%xmm1
  comiss D21(%rip),%xmm1
  jae    L14
L0:
  add    $0x1,%r12
  add    $0x14,%r15
  cmp    $0x4,%r12
  jne    L49
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r14d,%esi
  mov    %r13,%rdi
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  jmp    L26
  nopl   0x0(%rax)
L14:
  mov    %r14d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: byte[4]
name: parse_data
arguments: data_tag: D24
data_type: byte[4]
name: parse_data
arguments: data_tag: D21
data_type: byte[4]
name: parse_data
arguments: data_tag: D8
data_type: string

tool: D15: da yu ba shi wu student %d
 

tool: {"D13": [0x00,0x00,0xaa,0x42]}

tool: {"D24": [0x00,0x00,0xa0,0x40]}

tool: {"D21": [0x00,0x00,0xb4,0x42]}

tool: D8: da yu jiu shi student %d


assistant: ```c
void excellent(float (*b)[5]) {
  int n[27] = {0}, x[27] = {0};
  int i, j = 0, k, h = 0, f = 0;
  float w;
  for (i = 0; i < 4; i++) {
    h = 0, f = 0;
    w = 0;
    for (k = 0; k < 5; k++) {
      w = w + *(*(b + i) + k);
      if (*(*(b + i) + k) >= 85)
        h++;
      if (h >= 5)
        printf("da yu ba shi wu student %d\n ", i);
    }
    if ((w / 5) >= 90)
      printf("da yu jiu shi student %d\n", i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<excellent>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D55(%rip),%rbp
  push   %rbx
  lea    D60(%rip),%rbx
  sub    $0x18,%rsp
L40:
  movss  (%r12),%xmm1
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  movss  0x10(%r12),%xmm2
  comiss D54(%rip),%xmm1
  addss  %xmm1,%xmm0
  movss  0x4(%r12),%xmm1
  setae  %al
  comiss D54(%rip),%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%r12),%xmm1
  sbb    $0xffffffff,%eax
  comiss D54(%rip),%xmm1
  addss  %xmm1,%xmm0
  movss  0xc(%r12),%xmm1
  sbb    $0xffffffff,%eax
  comiss D54(%rip),%xmm1
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  jb     L32
  comiss D54(%rip),%xmm2
  jb     L32
  cmp    $0x3,%eax
  jne    L32
  mov    %r13d,%esi
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
L32:
  divss  D78(%rip),%xmm0
  comiss D66(%rip),%xmm0
  jae    L23
L39:
  add    $0x1,%r13d
  add    $0x14,%r12
  cmp    $0x4,%r13d
  jne    L40
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L39
```

tool_calls: name: read_data
arguments: tag: D55
type: string
name: read_data
arguments: tag: D60
type: string
name: read_data
arguments: tag: D54
type: byte[4]
name: read_data
arguments: tag: D78
type: byte[4]
name: read_data
arguments: tag: D66
type: byte[4]

tool: D55: da yu ba shi wu student %d
 

tool: D60: da yu jiu shi student %d


tool: {"D54": [0x00,0x00,0xaa,0x42]}

tool: {"D78": [0x00,0x00,0xa0,0x40]}

tool: {"D66": [0x00,0x00,0xb4,0x42]}

assistant: ```c
void excellent(float (*b)[5]) {
  int n[27] = {0}, x[27] = {0};
  int i, j = 0, k, h = 0, f = 0;
  float w;
  for (i = 0; i < 4; i++) {
    h = 0, f = 0;
    w = 0;
    for (k = 0; k < 5; k++) {
      w = w + *(*(b + i) + k);
      if (*(*(b + i) + k) >= 85)
        h++;
      if (h >= 5)
        printf("da yu ba shi wu student %d\n ", i);
    }
    if ((w / 5) >= 90)
      printf("da yu jiu shi student %d\n", i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D99(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D68
type: string
name: disassemble_data
arguments: data_tag: D14
type: string
name: disassemble_data
arguments: data_tag: D92
type: string
name: disassemble_data
arguments: data_tag: D29
type: string
name: disassemble_data
arguments: data_tag: D9
type: string
name: disassemble_data
arguments: data_tag: D71
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D99
type: string
name: disassemble_data
arguments: data_tag: D21
type: string

tool: D68: mudwalk version 0.11 pat@snarg.com


tool: D14: usage: mudwalk <directions>


tool: D92: 


tool: D29: for example this command:


tool: D9: >mudwalk 3n2s5u


tool: D71: should return the following output:


tool: D12: nnnssuuuuu


tool: D99: >mudwalk -r 3n2s5u will reverse the output:


tool: D21: >reversed dddddnnsss


assistant: ```c
print_usage() {
  printf("mudwalk version 0.11 pat@snarg.com\n");
  printf("usage: mudwalk <directions>\n");
  printf("\n");
  printf("for example this command:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("\n");
  printf("should return the following output:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("nnnssuuuuu\n");
  printf(">mudwalk -r 3n2s5u will reverse the output:\n");
  printf(">reversed dddddnnsss\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D80(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D71(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D89(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D80
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D41
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D71
type_infered: string
name: parse_data
arguments: tag: D54
type_infered: string
name: parse_data
arguments: tag: D77
type_infered: string
name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D89
type_infered: string

tool: D80: mudwalk version 0.11 pat@snarg.com


tool: D23: usage: mudwalk <directions>


tool: D41: 


tool: D9: for example this command:


tool: D71: >mudwalk 3n2s5u


tool: D54: should return the following output:


tool: D77: nnnssuuuuu


tool: D15: >mudwalk -r 3n2s5u will reverse the output:


tool: D89: >reversed dddddnnsss


assistant: ```c
print_usage() {
  printf("mudwalk version 0.11 pat@snarg.com\n");
  printf("usage: mudwalk <directions>\n");
  printf("\n");
  printf("for example this command:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("\n");
  printf("should return the following output:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("nnnssuuuuu\n");
  printf(">mudwalk -r 3n2s5u will reverse the output:\n");
  printf(">reversed dddddnnsss\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_usage>:
  endbr64
  push   %r12
  lea    D53(%rip),%rdi
  lea    D45(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D88(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D56(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D53
datatype: string
name: read_data
arguments: tag: D45
datatype: string
name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D88
datatype: string
name: read_data
arguments: tag: D57
datatype: string
name: read_data
arguments: tag: D42
datatype: string
name: read_data
arguments: tag: D9
datatype: string
name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D56
datatype: string

tool: D53: mudwalk version 0.11 pat@snarg.com


tool: D45: 


tool: D5: >mudwalk 3n2s5u


tool: D88: usage: mudwalk <directions>


tool: D57: for example this command:


tool: D42: should return the following output:


tool: D9: nnnssuuuuu


tool: D14: >mudwalk -r 3n2s5u will reverse the output:


tool: D56: >reversed dddddnnsss


assistant: ```c
print_usage() {
  printf("mudwalk version 0.11 pat@snarg.com\n");
  printf("usage: mudwalk <directions>\n");
  printf("\n");
  printf("for example this command:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("\n");
  printf("should return the following output:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("nnnssuuuuu\n");
  printf(">mudwalk -r 3n2s5u will reverse the output:\n");
  printf(">reversed dddddnnsss\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_usage>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  lea    D22(%rip),%r12
  push   %rbp
  lea    D33(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D81(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D21(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D36
type: string
name: disassemble_data
arguments: tag: D31
type: string
name: disassemble_data
arguments: tag: D81
type: string
name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D42
type: string
name: disassemble_data
arguments: tag: D21
type: string

tool: D14: mudwalk version 0.11 pat@snarg.com


tool: D22: 


tool: D33: >mudwalk 3n2s5u


tool: D36: usage: mudwalk <directions>


tool: D31: for example this command:


tool: D81: should return the following output:


tool: D6: nnnssuuuuu


tool: D42: >mudwalk -r 3n2s5u will reverse the output:


tool: D21: >reversed dddddnnsss


assistant: ```c
print_usage() {
  printf("mudwalk version 0.11 pat@snarg.com\n");
  printf("usage: mudwalk <directions>\n");
  printf("\n");
  printf("for example this command:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("\n");
  printf("should return the following output:\n");
  printf(">mudwalk 3n2s5u\n");
  printf("nnnssuuuuu\n");
  printf(">mudwalk -r 3n2s5u will reverse the output:\n");
  printf(">reversed dddddnnsss\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getMedian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L5
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  jmp    L1
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int getMedian(int arr[], int n) {
  if (n % 2 == 0)
    return (arr[n / 2 - 1] + arr[n / 2]) / 2;
  else
    return arr[n / 2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getMedian>:
  endbr64
  test   $0x1,%sil
  jne    L2
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edx
  add    -0x4(%rdi,%rax,4),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  ret
L2:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%eax
  ret
```

assistant: ```c
int getMedian(int arr[], int n) {
  if (n % 2 == 0)
    return (arr[n / 2 - 1] + arr[n / 2]) / 2;
  else
    return arr[n / 2];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getMedian>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  and    $0x1,%esi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    (%rdi,%rax,4),%eax
  jne    L9
  add    -0x4(%rdi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L9:
  ret
```

assistant: ```c
int getMedian(int arr[], int n) {
  if (n % 2 == 0)
    return (arr[n / 2 - 1] + arr[n / 2]) / 2;
  else
    return arr[n / 2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMedian>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  and    $0x1,%esi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    (%rdi,%rax,4),%eax
  jne    L2
  add    -0x4(%rdi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L2:
  ret
```

assistant: ```c
int getMedian(int arr[], int n) {
  if (n % 2 == 0)
    return (arr[n / 2 - 1] + arr[n / 2]) / 2;
  else
    return arr[n / 2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gvpriw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
long gvpriw(long index) {
  extern long *iwork;
  return *(iwork + index);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gvpriw>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
long gvpriw(long index) {
  extern long *iwork;
  return *(iwork + index);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gvpriw>:
  endbr64
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
long gvpriw(long index) {
  extern long *iwork;
  return *(iwork + index);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gvpriw>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  mov    (%rax,%rdi,8),%rax
  ret
```

assistant: ```c
long gvpriw(long index) {
  extern long *iwork;
  return *(iwork + index);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetOctOrDec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L201
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L166
L201:
  addq   $0x1,-0x8(%rbp)
  jmp    L166
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L209
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jg     L209
  addq   $0x1,-0x8(%rbp)
L166:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
L209:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L155
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L155
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
  jmp    L64
L155:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L35
L53:
  addq   $0x1,-0x8(%rbp)
  jmp    L35
L115:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x38,%al
  je     L224
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jne    L174
L224:
  movl   $0x1,-0xc(%rbp)
  jmp    L238
L174:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L225
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L225
L238:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L115
L225:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x44,%al
  jne    L193
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L193
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L16
L193:
  cmpl   $0x0,-0xc(%rbp)
  je     L133
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L133
L16:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
  jmp    L64
L133:
  mov    $0x1,%eax
L64:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string
name: parse_data
arguments: tag: D6
datatype: string

tool: D3: %o

tool: D6: %d

assistant: ```c
int GetOctOrDec(const char *s, int *Value) {
  const char *ss;
  int has_8_or_9 = 0;
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss < '0' || *ss > '7')
      break;
  if (!*ss && ss != s) {
    sscanf(s, "%o", Value);
    return (0);
  }
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss == '8' || *ss == '9')
      has_8_or_9 = 1;
    else if (*ss < '0' || *ss > '9')
      break;
  if ((*ss == 'D' && ss[1] == 0 && ss != s) || (has_8_or_9 && ss[0] == 0)) {
    sscanf(s, "%d", Value);
    return (0);
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetOctOrDec>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r10
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  mov    %rdi,%rcx
  adc    $0x0,%rcx
  movzbl (%rcx),%eax
  mov    %rcx,%r8
  mov    %eax,%edi
  test   %al,%al
  je     L55
L35:
  lea    -0x30(%rdi),%r9d
  cmp    $0x7,%r9b
  ja     L13
  add    $0x1,%r8
  movzbl (%r8),%edi
  test   %dil,%dil
  jne    L35
L13:
  cmp    %r8,%r10
  je     L50
  test   %dil,%dil
  je     L105
L50:
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  jmp    L167
L55:
  mov    $0x0,%r8d
  cmp    %rcx,%r10
  jne    L105
L153:
  mov    $0x0,%eax
L22:
  test   %al,%al
  jne    L149
  test   %r8d,%r8d
  jne    L155
L149:
  mov    $0x1,%eax
L21:
  add    $0x8,%rsp
  ret
L105:
  mov    %rsi,%rdx
  lea    D8(%rip),%rsi
  mov    %r10,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
  jmp    L21
L95:
  mov    %r9d,%r8d
L99:
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  test   %al,%al
  je     L153
L167:
  lea    -0x38(%rax),%edi
  cmp    $0x1,%dil
  jbe    L95
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  jbe    L99
  cmp    $0x44,%al
  jne    L22
  cmpb   $0x0,0x1(%rcx)
  jne    L116
  cmp    %rcx,%r10
  jne    L155
L116:
  mov    $0x1,%eax
  jmp    L21
L155:
  mov    %rsi,%rdx
  lea    D5(%rip),%rsi
  mov    %r10,%rdi
  call   <sscanf@plt>
  mov    $0x0,%eax
  jmp    L21
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D8: %o

tool: D5: %d

assistant: ```c
int GetOctOrDec(const char *s, int *Value) {
  const char *ss;
  int has_8_or_9 = 0;
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss < '0' || *ss > '7')
      break;
  if (!*ss && ss != s) {
    sscanf(s, "%o", Value);
    return (0);
  }
  ss = s;
  if (*ss == '+' || *ss == '-')
    ss++;
  for (; *ss; ss++)
    if (*ss == '8' || *ss == '9')
      has_8_or_9 = 1;
    else if (*ss < '0' || *ss > '9')
      break;
  if ((*ss == 'D' && ss[1] == 0 && ss != s) || (has_8_or_9 && ss[0] == 0)) {
    sscanf(s, "%d", Value);
    return (0);
  }
  return (1);
}
```