ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getUserInput@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D32(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L29
L17:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <checkPalindrome@plt>
  test   %rax,%rax
  je     L4
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L4:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
L29:
  cmpq   $0x0,-0x10(%rbp)
  jne    L17
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D67
data_type: string
name: retrieve_data
arguments: data_label: D32
data_type: string
name: retrieve_data
arguments: data_label: D39
data_type: string
name: retrieve_data
arguments: data_label: D26
data_type: string
name: retrieve_data
arguments: data_label: D57
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D67: Please input your words/sentences to be checked for palindromes.
Separate each entity with a comma.



tool: D32: ,

tool: D39: 

Palindromes:
-------------------


tool: D26: 	palindrome



tool: D57: 	not a palindrome



tool: D8: 

-------------------


assistant: ```c
int main() {
  char *str = NULL;
  printf("Please input your words/sentences to be checked for palindromes.\n"
         "Separate each entity with a comma.\n\n");
  str = getUserInput(str);
  char *part;
  part = strtok(str, ",");
  printf("\n\nPalindromes:\n-------------------\n");
  while (part != NULL) {
    printf(part);
    if (checkPalindrome(str))
      printf("\tpalindrome\n\n");
    else
      printf("\tnot a palindrome\n\n");
    part = strtok(NULL, ",");
  }
  printf("\n\n-------------------\n");
  free(str);
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <getUserInput@plt>
  mov    %rax,%rbp
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  test   %rbx,%rbx
  je     L40
  lea    D17(%rip),%r14
  lea    D69(%rip),%r13
  lea    D0(%rip),%r12
  jmp    L35
L8:
  mov    %r14,%rdi
  call   <printf@plt>
L43:
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L40
L35:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <checkPalindrome@plt>
  test   %rax,%rax
  je     L8
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L43
L40:
  lea    D66(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D49
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D69
data_type: string
name: parse_data
arguments: label: D66
data_type: string

tool: D49: Please input your words/sentences to be checked for palindromes.
Separate each entity with a comma.



tool: D0: ,

tool: D13: 

Palindromes:
-------------------


tool: D17: 	not a palindrome



tool: D69: 	palindrome



tool: D66: 

-------------------


assistant: ```c
int main() {
  char *str = NULL;
  printf("Please input your words/sentences to be checked for palindromes.\n"
         "Separate each entity with a comma.\n\n");
  str = getUserInput(str);
  char *part;
  part = strtok(str, ",");
  printf("\n\nPalindromes:\n-------------------\n");
  while (part != NULL) {
    printf(part);
    if (checkPalindrome(str))
      printf("\tpalindrome\n\n");
    else
      printf("\tnot a palindrome\n\n");
    part = strtok(NULL, ",");
  }
  printf("\n\n-------------------\n");
  free(str);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  call   <printf@plt>
  xor    %edi,%edi
  call   <getUserInput@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  lea    D24(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  test   %rbp,%rbp
  je     L11
  lea    D2(%rip),%r14
  lea    D20(%rip),%r13
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %r13,%rdi
  call   <printf@plt>
L19:
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L11
L13:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <checkPalindrome@plt>
  test   %rax,%rax
  jne    L45
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L19
  nopl   0x0(%rax)
L11:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string

tool: D10: Please input your words/sentences to be checked for palindromes.
Separate each entity with a comma.



tool: D3: ,

tool: D24: 

Palindromes:
-------------------


tool: D2: 	not a palindrome



tool: D20: 	palindrome



tool: D15: 

-------------------


assistant: ```c
int main() {
  char *str = NULL;
  printf("Please input your words/sentences to be checked for palindromes.\n"
         "Separate each entity with a comma.\n\n");
  str = getUserInput(str);
  char *part;
  part = strtok(str, ",");
  printf("\n\nPalindromes:\n-------------------\n");
  while (part != NULL) {
    printf(part);
    if (checkPalindrome(str))
      printf("\tpalindrome\n\n");
    else
      printf("\tnot a palindrome\n\n");
    part = strtok(NULL, ",");
  }
  printf("\n\n-------------------\n");
  free(str);
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  call   <printf@plt>
  xor    %edi,%edi
  call   <getUserInput@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  lea    D43(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  test   %rbp,%rbp
  je     L19
  lea    D16(%rip),%r14
  lea    D23(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <checkPalindrome@plt>
  mov    %r13,%rdi
  test   %rax,%rax
  jne    L12
  mov    %r14,%rdi
L12:
  call   <printf@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L17
L19:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D45
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D43
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D23
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D45: Please input your words/sentences to be checked for palindromes.
Separate each entity with a comma.



tool: D19: ,

tool: D43: 

Palindromes:
-------------------


tool: D16: 	not a palindrome



tool: D23: 	palindrome



tool: D2: 

-------------------


assistant: ```c
int main() {
  char *str = NULL;
  printf("Please input your words/sentences to be checked for palindromes.\n"
         "Separate each entity with a comma.\n\n");
  str = getUserInput(str);
  char *part;
  part = strtok(str, ",");
  printf("\n\nPalindromes:\n-------------------\n");
  while (part != NULL) {
    printf(part);
    if (checkPalindrome(str))
      printf("\tpalindrome\n\n");
    else
      printf("\tnot a palindrome\n\n");
    part = strtok(NULL, ",");
  }
  printf("\n\n-------------------\n");
  free(str);
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<alock_string2lower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L16
L17:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x20(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void alock_string2lower(char *string) {
  const size_t s = strlen(string);
  size_t i;
  for (i = 0; i < s; i++)
    string[i] = tolower(string[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alock_string2lower>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  je     L8
  mov    %rbp,%rbx
  add    %rax,%rbp
L16:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L16
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void alock_string2lower(char *string) {
  const size_t s = strlen(string);
  size_t i;
  for (i = 0; i < s; i++)
    string[i] = tolower(string[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alock_string2lower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L11
  lea    (%rbx,%rax,1),%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L10
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void alock_string2lower(char *string) {
  const size_t s = strlen(string);
  size_t i;
  for (i = 0; i < s; i++)
    string[i] = tolower(string[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alock_string2lower>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L11
  lea    (%rbx,%rax,1),%rbp
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L9
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void alock_string2lower(char *string) {
  const size_t s = strlen(string);
  size_t i;
  for (i = 0; i < s; i++)
    string[i] = tolower(string[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bar@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int r = 0;
  r += foo(r);
  r += 1;
  r += bar(r);
  r += 2;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <foo@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <bar@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int r = 0;
  r += foo(r);
  r += 1;
  r += bar(r);
  r += 2;
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <foo@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <bar@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int r = 0;
  r += foo(r);
  r += 1;
  r += bar(r);
  r += 2;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <foo@plt>
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <bar@plt>
  lea    0x2(%rbx,%rax,1),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int r = 0;
  r += foo(r);
  r += 1;
  r += bar(r);
  r += 2;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bin_search_recursive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L33
  mov    -0x4(%rbp),%eax
  jmp    L0
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L14
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <bin_search_recursive>
  mov    %eax,-0x8(%rbp)
  jmp    L34
L14:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bin_search_recursive>
  mov    %eax,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
L0:
  leave
  ret
```

assistant: ```c
int bin_search_recursive(int *array, int v, int l, int r) {
  int m;
  int ret;
  m = l + (r - l) / 2;
  assert(l <= r);
  if (v == array[m])
    return m;
  if (v > array[m])
    ret = bin_search_recursive(array, v, m + 1, r);
  else
    ret = bin_search_recursive(array, v, l, m - 1);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin_search_recursive>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,%r13d
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  add    %edx,%ebx
  cmp    %edx,%ecx
  setge  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebx,%rax
  mov    (%r14,%rax,4),%eax
  cmp    %r12d,%eax
  je     L20
  jge    L18
  lea    0x1(%rbx),%edx
  mov    %r13d,%ecx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <bin_search_recursive>
  mov    %eax,%ebx
L20:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  lea    -0x1(%rbx),%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <bin_search_recursive>
  mov    %eax,%ebx
  jmp    L20
```

assistant: ```c
int bin_search_recursive(int *array, int v, int l, int r) {
  int m;
  int ret;
  m = l + (r - l) / 2;
  assert(l <= r);
  if (v == array[m])
    return m;
  if (v > array[m])
    ret = bin_search_recursive(array, v, m + 1, r);
  else
    ret = bin_search_recursive(array, v, l, m - 1);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bin_search_recursive>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r14d,%eax
  xor    %edi,%edi
  sub    %r13d,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  add    %r13d,%r12d
  cmp    %r13d,%r14d
  setge  %dil
  call   <assert@plt>
  movslq %r12d,%rax
  cmp    %ebx,0x0(%rbp,%rax,4)
  je     L30
  jge    L35
  lea    0x1(%r12),%r13d
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L35:
  lea    -0x1(%r12),%r14d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L30:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_search_recursive(int *array, int v, int l, int r) {
  int m;
  int ret;
  m = l + (r - l) / 2;
  assert(l <= r);
  if (v == array[m])
    return m;
  if (v > array[m])
    ret = bin_search_recursive(array, v, m + 1, r);
  else
    ret = bin_search_recursive(array, v, l, m - 1);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin_search_recursive>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r14d,%eax
  xor    %edi,%edi
  sub    %r13d,%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  add    %r13d,%r12d
  cmp    %r13d,%r14d
  setge  %dil
  call   <assert@plt>
  movslq %r12d,%rax
  cmp    %ebx,0x0(%rbp,%rax,4)
  je     L27
  jge    L26
  lea    0x1(%r12),%r13d
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L26:
  lea    -0x1(%r12),%r14d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bin_search_recursive(int *array, int v, int l, int r) {
  int m;
  int ret;
  m = l + (r - l) / 2;
  assert(l <= r);
  if (v == array[m])
    return m;
  if (v > array[m])
    ret = bin_search_recursive(array, v, m + 1, r);
  else
    ret = bin_search_recursive(array, v, l, m - 1);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <CRYPTO_set_mem_debug_functions@plt>
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  call   <abort@plt>
L11:
  mov    $0x0,%eax
  call   <BN_CTX_new@plt>
  mov    %rax,-0x58(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x50(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x48(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x40(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x38(%rbp)
  jmp    L30
L3:
  movabs $0x646e616d65642049,%rax
  movabs $0x61756e616d206120,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6e756f636572206c,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x2174,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  mov    $0x1b,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <RAND_seed@plt>
L30:
  mov    $0x0,%eax
  call   <RAND_status@plt>
  test   %eax,%eax
  je     L3
  mov    -0x58(%rbp),%rdi
  mov    -0x40(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x50(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <do_mul_exp@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: I demand a manual recount!

assistant: ```c
int main(int argc, char **argv) {
  BN_CTX *ctx;
  BIGNUM *a, *b, *c, *r;
  if (!CRYPTO_set_mem_debug_functions(0, 0, 0, 0, 0))
    abort();
  ctx = BN_CTX_new();
  a = BN_new();
  b = BN_new();
  c = BN_new();
  r = BN_new();
  while (!RAND_status()) {
    const char str[] = "I demand a manual recount!";
    RAND_seed("I demand a manual recount!", sizeof str);
  };
  do_mul_exp(r, a, b, c, ctx);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <CRYPTO_set_mem_debug_functions@plt>
  test   %eax,%eax
  je     L36
L26:
  mov    $0x0,%eax
  call   <BN_CTX_new@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,%r13
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,%r14
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,%rbp
  lea    D5(%rip),%rbx
  jmp    L13
L36:
  call   <abort@plt>
  jmp    L26
L19:
  mov    $0x1b,%esi
  mov    %rbx,%rdi
  call   <RAND_seed@plt>
L13:
  mov    $0x0,%eax
  call   <RAND_status@plt>
  test   %eax,%eax
  je     L19
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <do_mul_exp@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: I demand a manual recount!

assistant: ```c
int main(int argc, char **argv) {
  BN_CTX *ctx;
  BIGNUM *a, *b, *c, *r;
  if (!CRYPTO_set_mem_debug_functions(0, 0, 0, 0, 0))
    abort();
  ctx = BN_CTX_new();
  a = BN_new();
  b = BN_new();
  c = BN_new();
  r = BN_new();
  while (!RAND_status()) {
    const char str[] = "I demand a manual recount!";
    RAND_seed("I demand a manual recount!", sizeof str);
  };
  do_mul_exp(r, a, b, c, ctx);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %r14
  xor    %esi,%esi
  xor    %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <CRYPTO_set_mem_debug_functions@plt>
  test   %eax,%eax
  je     L13
L32:
  xor    %eax,%eax
  lea    D6(%rip),%rbx
  call   <BN_CTX_new@plt>
  mov    %rax,%r15
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%r13
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%r14
  xor    %eax,%eax
  call   <BN_new@plt>
  mov    %rax,%rbp
  jmp    L12
  nopl   0x0(%rax)
L25:
  mov    $0x1b,%esi
  mov    %rbx,%rdi
  call   <RAND_seed@plt>
L12:
  xor    %eax,%eax
  call   <RAND_status@plt>
  test   %eax,%eax
  je     L25
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <do_mul_exp@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <abort@plt>
  jmp    L32
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: I demand a manual recount!

assistant: ```c
int main(int argc, char **argv) {
  BN_CTX *ctx;
  BIGNUM *a, *b, *c, *r;
  if (!CRYPTO_set_mem_debug_functions(0, 0, 0, 0, 0))
    abort();
  ctx = BN_CTX_new();
  a = BN_new();
  b = BN_new();
  c = BN_new();
  r = BN_new();
  while (!RAND_status()) {
    const char str[] = "I demand a manual recount!";
    RAND_seed("I demand a manual recount!", sizeof str);
  };
  do_mul_exp(r, a, b, c, ctx);
  return 0;
}
```