ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<combine_halfedgeperm>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L94:
  mov    0x0(%rbp,%rax,1),%ecx
  test   %ecx,%ecx
  je     L60
  mov    (%r12,%rax,1),%edx
  test   %edx,%edx
  jne    L8
L60:
  add    $0x4,%rax
  cmp    $0x20,%rax
  jne    L94
  movabs $0x200000000,%rax
  xor    %ebx,%ebx
  lea    D1(%rip),%r14
  mov    %rax,0x4(%rsp)
  movabs $0x600000004,%rax
  mov    %rax,0xc(%rsp)
  movabs $0x300000001,%rax
  mov    %rax,0x24(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x2c(%rsp)
  jmp    L30
  nopl   (%rax)
L86:
  mov    (%rsp,%rax,4),%eax
  mov    %eax,0x0(%r13,%rbx,1)
L68:
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  je     L104
L30:
  movslq 0x0(%rbp,%rbx,1),%rax
  test   %eax,%eax
  jne    L86
  movslq (%r12,%rbx,1),%rax
  test   %eax,%eax
  je     L16
  mov    0x20(%rsp,%rax,4),%eax
  mov    %eax,0x0(%r13,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L30
L104:
  xor    %eax,%eax
L28:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L16:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <exit_w_error_message@plt>
  jmp    L68
  nopl   0x0(%rax)
L8:
  mov    $0x1,%eax
  jmp    L28
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: combine_halfedgeperm : invalid input

assistant: ```c
int combine_halfedgeperm(hep_array0_in, hep_array1_in, eperm_array_out)
int hep_array0_in[8], hep_array1_in[8];
int eperm_array_out[8];
{
  int trf_arr0[5], trf_arr1[5], ii;
  for (ii = 0; ii < 8; ii++)
    if (hep_array0_in[ii] && hep_array1_in[ii])
      return 1;
  trf_arr0[1] = 0;
  trf_arr0[2] = 2;
  trf_arr0[3] = 4;
  trf_arr0[4] = 6;
  trf_arr1[1] = 1;
  trf_arr1[2] = 3;
  trf_arr1[3] = 5;
  trf_arr1[4] = 7;
  for (ii = 0; ii < 8; ii++) {
    if (hep_array0_in[ii])
      eperm_array_out[ii] = trf_arr0[hep_array0_in[ii]];
    else if (hep_array1_in[ii])
      eperm_array_out[ii] = trf_arr1[hep_array1_in[ii]];
    else
      exit_w_error_message("combine_halfedgeperm : invalid input");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1b,-0x8(%rbp)
  je     L94
  mov    -0x8(%rbp),%eax
  jmp    L19
L94:
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x5b,-0x8(%rbp)
  je     L40
  mov    -0x8(%rbp),%eax
  or     $0x1,%ah
  jmp    L19
L40:
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L21
  mov    -0x8(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L85
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,-0x8(%rbp)
L85:
  cmpl   $0x7e,-0x8(%rbp)
  jne    L84
  mov    -0x4(%rbp),%eax
  or     $0x2,%ah
  jmp    L19
L84:
  mov    $0xffff,%eax
  jmp    L19
L21:
  mov    -0x8(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x3,%eax
  ja     L25
  mov    -0x8(%rbp),%eax
  or     $0x4,%ah
  jmp    L19
L25:
  mov    -0x8(%rbp),%eax
  or     $0x8,%ah
L19:
  leave
  ret
```

assistant: ```c
int get_key(void) {
  int c = get_byte();
  if (c != '\x1b')
    return c;
  c = get_byte();
  if (c != '[')
    return 0x100 | c;
  c = get_byte();
  if (isdigit(c)) {
    int accum = c - '0';
    c = get_byte();
    if (isdigit(c)) {
      accum = 10 * accum + c - '0';
      c = get_byte();
    }
    if (c == '~')
      return 0x200 | accum;
    return 0xFFFF;
  }
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
  case 'D':
    return 0x400 | c;
  }
  return 0x800 | c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_key>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_byte@plt>
  cmp    $0x1b,%eax
  je     L55
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  mov    $0x0,%eax
  call   <get_byte@plt>
  cmp    $0x5b,%eax
  je     L65
  or     $0x1,%ah
  jmp    L54
L65:
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  lea    -0x41(%rbx),%edx
  mov    %ebx,%eax
  or     $0x4,%ah
  or     $0x8,%bh
  cmp    $0x3,%edx
  cmova  %ebx,%eax
  jmp    L54
L39:
  sub    $0x30,%ebx
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L12
L53:
  or     $0x2,%bh
  cmp    $0x7e,%ebp
  mov    $0xffff,%eax
  cmove  %ebx,%eax
  jmp    L54
L12:
  lea    (%rbx,%rbx,4),%eax
  lea    -0x30(%rbp,%rax,2),%ebx
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    %eax,%ebp
  jmp    L53
```

assistant: ```c
int get_key(void) {
  int c = get_byte();
  if (c != '\x1b')
    return c;
  c = get_byte();
  if (c != '[')
    return 0x100 | c;
  c = get_byte();
  if (isdigit(c)) {
    int accum = c - '0';
    c = get_byte();
    if (isdigit(c)) {
      accum = 10 * accum + c - '0';
      c = get_byte();
    }
    if (c == '~')
      return 0x200 | accum;
    return 0xFFFF;
  }
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
  case 'D':
    return 0x400 | c;
  }
  return 0x800 | c;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_key>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <get_byte@plt>
  cmp    $0x1b,%eax
  je     L20
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  xor    %eax,%eax
  call   <get_byte@plt>
  cmp    $0x5b,%eax
  je     L56
  add    $0x8,%rsp
  or     $0x1,%ah
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  call   <get_byte@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L9
  lea    -0x41(%rbx),%edx
  mov    %ebx,%eax
  or     $0x8,%bh
  or     $0x4,%ah
  cmp    $0x3,%edx
  cmova  %ebx,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  sub    $0x30,%ebx
  call   <get_byte@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L67
L51:
  or     $0x2,%bh
  mov    $0xffff,%eax
  cmp    $0x7e,%ebp
  cmove  %ebx,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L67:
  lea    (%rbx,%rbx,4),%eax
  lea    -0x30(%rbp,%rax,2),%ebx
  xor    %eax,%eax
  call   <get_byte@plt>
  mov    %eax,%ebp
  jmp    L51
```

assistant: ```c
int get_key(void) {
  int c = get_byte();
  if (c != '\x1b')
    return c;
  c = get_byte();
  if (c != '[')
    return 0x100 | c;
  c = get_byte();
  if (isdigit(c)) {
    int accum = c - '0';
    c = get_byte();
    if (isdigit(c)) {
      accum = 10 * accum + c - '0';
      c = get_byte();
    }
    if (c == '~')
      return 0x200 | accum;
    return 0xFFFF;
  }
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
  case 'D':
    return 0x400 | c;
  }
  return 0x800 | c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_key>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <get_byte@plt>
  cmp    $0x1b,%eax
  je     L31
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L31:
  xor    %eax,%eax
  call   <get_byte@plt>
  cmp    $0x5b,%eax
  je     L54
  add    $0x8,%rsp
  or     $0x1,%ah
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  call   <get_byte@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L15
  lea    -0x41(%rbx),%edx
  mov    %ebx,%eax
  or     $0x8,%bh
  or     $0x4,%ah
  cmp    $0x3,%edx
  cmova  %ebx,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  sub    $0x30,%ebx
  call   <get_byte@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
L11:
  or     $0x2,%bh
  mov    $0xffff,%eax
  cmp    $0x7e,%ebp
  cmove  %ebx,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L51:
  lea    (%rbx,%rbx,4),%eax
  lea    -0x30(%rbp,%rax,2),%ebx
  xor    %eax,%eax
  call   <get_byte@plt>
  mov    %eax,%ebp
  jmp    L11
```

assistant: ```c
int get_key(void) {
  int c = get_byte();
  if (c != '\x1b')
    return c;
  c = get_byte();
  if (c != '[')
    return 0x100 | c;
  c = get_byte();
  if (isdigit(c)) {
    int accum = c - '0';
    c = get_byte();
    if (isdigit(c)) {
      accum = 10 * accum + c - '0';
      c = get_byte();
    }
    if (c == '~')
      return 0x200 | accum;
    return 0xFFFF;
  }
  switch (c) {
  case 'A':
  case 'B':
  case 'C':
  case 'D':
    return 0x400 | c;
  }
  return 0x800 | c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transfer_YUV422_to_YUVA8888>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L6
L2:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  movzbl 0x2(%rdx),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x10(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3,%rax
  movb   $0xff,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUV422_to_YUVA8888(unsigned char *(*output), unsigned char *input, int column) {
  if (!(column & 1))
    (*output)[0] = input[0];
  else
    (*output)[0] = input[2];
  (*output)[1] = input[1];
  (*output)[2] = input[3];
  (*output)[3] = 255;
  (*output) += 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transfer_YUV422_to_YUVA8888>:
  endbr64
  test   $0x1,%dl
  jne    L18
  mov    (%rdi),%rax
  movzbl (%rsi),%edx
  mov    %dl,(%rax)
L10:
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movb   $0xff,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
L18:
  mov    (%rdi),%rax
  movzbl 0x2(%rsi),%edx
  mov    %dl,(%rax)
  jmp    L10
```

assistant: ```c
void transfer_YUV422_to_YUVA8888(unsigned char *(*output), unsigned char *input, int column) {
  if (!(column & 1))
    (*output)[0] = input[0];
  else
    (*output)[0] = input[2];
  (*output)[1] = input[1];
  (*output)[2] = input[3];
  (*output)[3] = 255;
  (*output) += 4;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transfer_YUV422_to_YUVA8888>:
  endbr64
  and    $0x1,%edx
  mov    (%rdi),%rax
  jne    L2
  movzbl (%rsi),%edx
L15:
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movb   $0xff,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
  nopl   0x0(%rax)
L2:
  movzbl 0x2(%rsi),%edx
  jmp    L15
```

assistant: ```c
void transfer_YUV422_to_YUVA8888(unsigned char *(*output), unsigned char *input, int column) {
  if (!(column & 1))
    (*output)[0] = input[0];
  else
    (*output)[0] = input[2];
  (*output)[1] = input[1];
  (*output)[2] = input[3];
  (*output)[3] = 255;
  (*output) += 4;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<transfer_YUV422_to_YUVA8888>:
  endbr64
  and    $0x1,%edx
  mov    (%rdi),%rax
  jne    L18
  movzbl (%rsi),%edx
L0:
  mov    %dl,(%rax)
  mov    (%rdi),%rax
  movzbl 0x1(%rsi),%edx
  mov    %dl,0x1(%rax)
  mov    (%rdi),%rax
  movzbl 0x3(%rsi),%edx
  mov    %dl,0x2(%rax)
  mov    (%rdi),%rax
  movb   $0xff,0x3(%rax)
  addq   $0x4,(%rdi)
  ret
  nopl   0x0(%rax)
L18:
  movzbl 0x2(%rsi),%edx
  jmp    L0
```

assistant: ```c
void transfer_YUV422_to_YUVA8888(unsigned char *(*output), unsigned char *input, int column) {
  if (!(column & 1))
    (*output)[0] = input[0];
  else
    (*output)[0] = input[2];
  (*output)[1] = input[1];
  (*output)[2] = input[3];
  (*output)[3] = 255;
  (*output) += 4;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x811c9dc5,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L24
L3:
  mov    -0xc(%rbp),%eax
  imul   $0x1000193,%eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0xc(%rbp),%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash_func(const void *key) {
  const unsigned char *p = key;
  unsigned int h = 2166136261;
  if (!p)
    return 0;
  while (*p) {
    h = (h * 16777619) ^ *p;
    ++p;
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash_func>:
  endbr64
  test   %rdi,%rdi
  je     L11
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  mov    $0x811c9dc5,%eax
L22:
  imul   $0x1000193,%eax,%eax
  movzbl %dl,%edx
  xor    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L22
  ret
L11:
  mov    $0x0,%eax
  ret
L6:
  mov    $0x811c9dc5,%eax
  ret
```

assistant: ```c
unsigned int hash_func(const void *key) {
  const unsigned char *p = key;
  unsigned int h = 2166136261;
  if (!p)
    return 0;
  while (*p) {
    h = (h * 16777619) ^ *p;
    ++p;
  }
  return h;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_func>:
  endbr64
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%edx
  mov    $0x811c9dc5,%eax
  test   %dl,%dl
  je     L17
  nopl   (%rax)
L20:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L20
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
unsigned int hash_func(const void *key) {
  const unsigned char *p = key;
  unsigned int h = 2166136261;
  if (!p)
    return 0;
  while (*p) {
    h = (h * 16777619) ^ *p;
    ++p;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hash_func>:
  endbr64
  test   %rdi,%rdi
  je     L8
  movzbl (%rdi),%edx
  mov    $0x811c9dc5,%eax
  test   %dl,%dl
  je     L16
  nopl   (%rax)
L14:
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
unsigned int hash_func(const void *key) {
  const unsigned char *p = key;
  unsigned int h = 2166136261;
  if (!p)
    return 0;
  while (*p) {
    h = (h * 16777619) ^ *p;
    ++p;
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  mov    $0xefbeadde,%edx
  mov    $0x4,%esi
  mov    $0x98,%edi
  call   <write_i2c_message@plt>
  mov    $0x3e8,%edi
  call   <delay@plt>
  jmp    L6
```

assistant: ```c
int main() {
  while (1) {
    write_i2c_message(0x98, 4, 0xefbeadde);
    delay(1000);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0xefbeadde,%edx
  mov    $0x4,%esi
  mov    $0x98,%edi
  call   <write_i2c_message@plt>
  mov    $0x3e8,%edi
  call   <delay@plt>
  jmp    L9
```

assistant: ```c
int main() {
  while (1) {
    write_i2c_message(0x98, 4, 0xefbeadde);
    delay(1000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xefbeadde,%edx
  mov    $0x4,%esi
  mov    $0x98,%edi
  call   <write_i2c_message@plt>
  mov    $0x3e8,%edi
  call   <delay@plt>
  jmp    L8
```

assistant: ```c
int main() {
  while (1) {
    write_i2c_message(0x98, 4, 0xefbeadde);
    delay(1000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xefbeadde,%edx
  mov    $0x4,%esi
  mov    $0x98,%edi
  call   <write_i2c_message@plt>
  mov    $0x3e8,%edi
  call   <delay@plt>
  jmp    L1
```

assistant: ```c
int main() {
  while (1) {
    write_i2c_message(0x98, 4, 0xefbeadde);
    delay(1000);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<GetInputFileName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
L5:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: -i

assistant: ```c
char *GetInputFileName(int paramNumber, char *parameter[]) {
  int i = 0;
  do {
    i++;
  } while (strcmp(parameter[i], "-i"));
  char *inputFileName = malloc(strlen(parameter[i + 1]));
  inputFileName = parameter[i + 1];
  return inputFileName;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GetInputFileName>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    $0x1,%ebx
  lea    D1(%rip),%r12
L6:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  mov    %rbx,%rdx
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L6
  lea    0x8(%rbp,%rdx,8),%rbx
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: -i

assistant: ```c
char *GetInputFileName(int paramNumber, char *parameter[]) {
  int i = 0;
  do {
    i++;
  } while (strcmp(parameter[i], "-i"));
  char *inputFileName = malloc(strlen(parameter[i + 1]));
  inputFileName = parameter[i + 1];
  return inputFileName;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GetInputFileName>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  lea    0x0(%rbp,%rbx,8),%rbx
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: -i

assistant: ```c
char *GetInputFileName(int paramNumber, char *parameter[]) {
  int i = 0;
  do {
    i++;
  } while (strcmp(parameter[i], "-i"));
  char *inputFileName = malloc(strlen(parameter[i + 1]));
  inputFileName = parameter[i + 1];
  return inputFileName;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetInputFileName>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L0
  lea    0x0(%rbp,%rbx,8),%rbx
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  mov    (%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: -i

assistant: ```c
char *GetInputFileName(int paramNumber, char *parameter[]) {
  int i = 0;
  do {
    i++;
  } while (strcmp(parameter[i], "-i"));
  char *inputFileName = malloc(strlen(parameter[i + 1]));
  inputFileName = parameter[i + 1];
  return inputFileName;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kume_birlesimi_bul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L84:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L61:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L84
  movl   $0x0,-0x10(%rbp)
  jmp    L79
L71:
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L54
L75:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L2
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L2:
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L75
L21:
  cmpl   $0x1,-0x4(%rbp)
  jne    L15
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L15:
  addl   $0x1,-0x10(%rbp)
L79:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L71
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int kume_birlesimi_bul(int A[], int A_size, int B[], int B_size, int sonuc[]) {
  int i, j;
  int eleman_sayi = 0, state = 0;
  for (i = 0, j = 0; i < A_size; i++, j++) {
    sonuc[j] = A[i];
    eleman_sayi++;
  }
  for (i = 0; i < B_size; i++) {
    state = 1;
    for (j = 0; j < eleman_sayi; j++) {
      if (sonuc[j] == B[i]) {
        state = 0;
        break;
      }
    }
    if (state == 1) {
      sonuc[eleman_sayi] = B[i];
      eleman_sayi++;
    }
  }
  return eleman_sayi;
}
```