ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getBoolean>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L1
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D2(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L1:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: Yes

assistant: ```c
int getBoolean(char *value) {
  if (value != NULL && strncmp(value, "Yes", 3) == 0) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getBoolean>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D1(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: Yes

assistant: ```c
int getBoolean(char *value) {
  if (value != NULL && strncmp(value, "Yes", 3) == 0) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getBoolean>:
  endbr64
  test   %rdi,%rdi
  je     L2
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D6(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: Yes

assistant: ```c
int getBoolean(char *value) {
  if (value != NULL && strncmp(value, "Yes", 3) == 0) {
    return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tooManyDetect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L9:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <maxDifference@plt>
  cmp    %eax,-0x28(%rbp)
  jg     L5
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L12
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
L12:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int tooManyDetect(int *arrCount, int *arrTooMany, int size, int maxDiff, int id) {
  int i;
  for (i = 0; i < size; i++) {
    if (maxDifference(arrCount, i, size) >= maxDiff)
      arrTooMany[i] = 1;
    else
      arrTooMany[i] = -1;
  }
  return arrTooMany[id];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tooManyDetect>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%r12
  mov    %r8d,0xc(%rsp)
  test   %edx,%edx
  jle    L5
  mov    %rdi,%r13
  mov    %edx,%ebp
  mov    %ecx,%r14d
  mov    %edx,%r15d
  mov    $0x0,%ebx
L12:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <maxDifference@plt>
  cmp    %r14d,%eax
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L12
L5:
  movslq 0xc(%rsp),%rax
  mov    (%r12,%rax,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int tooManyDetect(int *arrCount, int *arrTooMany, int size, int maxDiff, int id) {
  int i;
  for (i = 0; i < size; i++) {
    if (maxDifference(arrCount, i, size) >= maxDiff)
      arrTooMany[i] = 1;
    else
      arrTooMany[i] = -1;
  }
  return arrTooMany[id];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tooManyDetect>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  test   %r14d,%r14d
  jle    L16
  mov    %rdi,%r13
  mov    %r14,%r15
  mov    %ecx,%r12d
  xor    %ebx,%ebx
  nopl   (%rax)
L18:
  mov    %ebx,%esi
  mov    %r15d,%edx
  mov    %r13,%rdi
  call   <maxDifference@plt>
  cmp    %r12d,%eax
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L18
L16:
  movslq 0xc(%rsp),%r15
  mov    0x0(%rbp,%r15,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int tooManyDetect(int *arrCount, int *arrTooMany, int size, int maxDiff, int id) {
  int i;
  for (i = 0; i < size; i++) {
    if (maxDifference(arrCount, i, size) >= maxDiff)
      arrTooMany[i] = 1;
    else
      arrTooMany[i] = -1;
  }
  return arrTooMany[id];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tooManyDetect>:
  endbr64
  push   %r15
  push   %r14
  movslq %edx,%r14
  push   %r13
  mov    %r14,%r15
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %r8d,0xc(%rsp)
  test   %r14d,%r14d
  jle    L31
  nopl   (%rax)
L11:
  mov    %r15d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <maxDifference@plt>
  cmp    %r12d,%eax
  jge    L15
  movl   $0xffffffff,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L11
L31:
  movslq 0xc(%rsp),%r15
  mov    0x0(%rbp,%r15,4),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L15:
  movl   $0x1,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L11
  jmp    L31
```

assistant: ```c
int tooManyDetect(int *arrCount, int *arrTooMany, int size, int maxDiff, int id) {
  int i;
  for (i = 0; i < size; i++) {
    if (maxDifference(arrCount, i, size) >= maxDiff)
      arrTooMany[i] = 1;
    else
      arrTooMany[i] = -1;
  }
  return arrTooMany[id];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<addexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x65,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x190,-0x1c(%rbp)
  jle    L18
  mov    $0x0,%eax
  jmp    L30
L18:
  cmpl   $0x9,-0x1c(%rbp)
  jg     L27
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L27:
  cmpl   $0x63,-0x1c(%rbp)
  jle    L25
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L25:
  cmpl   $0x9,-0x1c(%rbp)
  jle    L22
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x1c(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int addexp(char *buf, int e, int sign) {
  int n = 0;
  buf[n++] = 'e';
  buf[n++] = (char)sign;
  if (e > 400)
    return 0;
  if (e < 10)
    buf[n++] = '0';
  if (e >= 100)
    buf[n++] = (char)(e / 100 + '0'), e -= 100 * (e / 100);
  if (e >= 10)
    buf[n++] = (char)(e / 10 + '0'), e -= 10 * (e / 10);
  buf[n++] = (char)(e + '0');
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addexp>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  movb   $0x65,(%rdi)
  mov    %dl,0x1(%rdi)
  mov    $0x0,%esi
  cmp    $0x190,%eax
  jg     L51
  cmp    $0x9,%eax
  jg     L54
  movb   $0x30,0x2(%rdi)
  mov    $0x3,%edx
L30:
  lea    0x1(%rdx),%esi
  movslq %edx,%rdx
  add    $0x30,%eax
  mov    %al,(%rcx,%rdx,1)
L51:
  mov    %esi,%eax
  ret
L55:
  mov    $0x3,%edx
  jmp    L30
L54:
  cmp    $0x63,%eax
  jle    L47
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    0x30(%rdx),%esi
  mov    %sil,0x2(%rcx)
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  cmp    $0x9,%eax
  jle    L55
  mov    $0x3,%esi
L23:
  lea    0x1(%rsi),%edx
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%esi
  lea    0x30(%rsi),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    (%rsi,%rsi,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  jmp    L30
L47:
  mov    $0x2,%esi
  jmp    L23
```

assistant: ```c
int addexp(char *buf, int e, int sign) {
  int n = 0;
  buf[n++] = 'e';
  buf[n++] = (char)sign;
  if (e > 400)
    return 0;
  if (e < 10)
    buf[n++] = '0';
  if (e >= 100)
    buf[n++] = (char)(e / 100 + '0'), e -= 100 * (e / 100);
  if (e >= 10)
    buf[n++] = (char)(e / 10 + '0'), e -= 10 * (e / 10);
  buf[n++] = (char)(e + '0');
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<addexp>:
  endbr64
  movb   $0x65,(%rdi)
  mov    %rdi,%rcx
  mov    %esi,%eax
  xor    %r8d,%r8d
  mov    %dl,0x1(%rdi)
  cmp    $0x190,%esi
  jg     L51
  cmp    $0x9,%esi
  jle    L1
  cmp    $0x63,%esi
  jle    L63
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  sub    %esi,%edx
  lea    0x30(%rdx),%esi
  imul   $0x64,%edx,%edx
  mov    %sil,0x2(%rcx)
  sub    %edx,%eax
  cmp    $0x9,%eax
  jle    L11
  mov    $0x4,%esi
  mov    $0x5,%r8d
  mov    $0x3,%edi
L65:
  mov    %eax,%edx
  mov    $0xcccccccd,%r9d
  imul   %r9,%rdx
  shr    $0x23,%rdx
  lea    0x30(%rdx),%r9d
  lea    (%rdx,%rdx,4),%edx
  mov    %r9b,(%rcx,%rdi,1)
  add    %edx,%edx
  sub    %edx,%eax
L20:
  add    $0x30,%eax
  mov    %al,(%rcx,%rsi,1)
L51:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  movb   $0x30,0x2(%rdi)
  mov    $0x4,%r8d
  mov    $0x3,%esi
  jmp    L20
L63:
  mov    $0x3,%esi
  mov    $0x4,%r8d
  mov    $0x2,%edi
  jmp    L65
L11:
  mov    $0x4,%r8d
  mov    $0x3,%esi
  jmp    L20
```

assistant: ```c
int addexp(char *buf, int e, int sign) {
  int n = 0;
  buf[n++] = 'e';
  buf[n++] = (char)sign;
  if (e > 400)
    return 0;
  if (e < 10)
    buf[n++] = '0';
  if (e >= 100)
    buf[n++] = (char)(e / 100 + '0'), e -= 100 * (e / 100);
  if (e >= 10)
    buf[n++] = (char)(e / 10 + '0'), e -= 10 * (e / 10);
  buf[n++] = (char)(e + '0');
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<addexp>:
  endbr64
  movb   $0x65,(%rdi)
  mov    %rdi,%rcx
  mov    %esi,%eax
  xor    %r8d,%r8d
  mov    %dl,0x1(%rdi)
  cmp    $0x190,%esi
  jg     L49
  cmp    $0x9,%esi
  jle    L8
  cmp    $0x63,%esi
  jle    L31
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  sub    %esi,%edx
  lea    0x30(%rdx),%esi
  imul   $0x64,%edx,%edx
  mov    %sil,0x2(%rcx)
  sub    %edx,%eax
  cmp    $0x9,%eax
  jle    L68
  mov    $0x4,%esi
  mov    $0x5,%r8d
  mov    $0x3,%edi
L7:
  mov    %eax,%edx
  mov    $0xcccccccd,%r9d
  imul   %r9,%rdx
  shr    $0x23,%rdx
  lea    0x30(%rdx),%r9d
  lea    (%rdx,%rdx,4),%edx
  mov    %r9b,(%rcx,%rdi,1)
  add    %edx,%edx
  sub    %edx,%eax
L54:
  add    $0x30,%eax
  mov    %al,(%rcx,%rsi,1)
L49:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movb   $0x30,0x2(%rdi)
  mov    $0x4,%r8d
  mov    $0x3,%esi
  jmp    L54
L31:
  mov    $0x3,%esi
  mov    $0x4,%r8d
  mov    $0x2,%edi
  jmp    L7
L68:
  mov    $0x4,%r8d
  mov    $0x3,%esi
  jmp    L54
```

assistant: ```c
int addexp(char *buf, int e, int sign) {
  int n = 0;
  buf[n++] = 'e';
  buf[n++] = (char)sign;
  if (e > 400)
    return 0;
  if (e < 10)
    buf[n++] = '0';
  if (e >= 100)
    buf[n++] = (char)(e / 100 + '0'), e -= 100 * (e / 100);
  if (e >= 10)
    buf[n++] = (char)(e / 10 + '0'), e -= 10 * (e / 10);
  buf[n++] = (char)(e + '0');
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<closeHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L19:
  cmpl   $0x4,-0x8(%rbp)
  je     L40
  cmpl   $0x5,-0x8(%rbp)
  je     L40
  cmpl   $0x6,-0x8(%rbp)
  jne    L28
L40:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L28:
  addl   $0x1,-0x8(%rbp)
L20:
  cmpl   $0x8,-0x8(%rbp)
  jle    L19
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x4d4873ed,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x35,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int closeHash(char ID[]) {
  int square = 0, i, w = 0;
  for (i = 0; i < 9; i++) {
    if (i == 4 || i == 5 || i == 6) {
      square = square + (ID[i] - 48);
      square *= 10;
    }
  }
  square /= 10;
  square = square * square;
  square = square % 53;
  return square;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<closeHash>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%ecx
L32:
  lea    -0x5(%rax),%edx
  cmp    $0x2,%edx
  jbe    L36
  cmp    $0x8,%eax
  jg     L6
L18:
  add    $0x1,%eax
  add    $0x1,%rdi
  jmp    L32
L36:
  movsbl (%rdi),%edx
  lea    -0x30(%rcx,%rdx,1),%ecx
  imul   $0xa,%ecx,%ecx
  jmp    L18
L6:
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   %edx,%edx
  movslq %edx,%rax
  imul   $0x4d4873ed,%rax,%rax
  sar    $0x24,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x35,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int closeHash(char ID[]) {
  int square = 0, i, w = 0;
  for (i = 0; i < 9; i++) {
    if (i == 4 || i == 5 || i == 6) {
      square = square + (ID[i] - 48);
      square *= 10;
    }
  }
  square /= 10;
  square = square * square;
  square = square % 53;
  return square;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<closeHash>:
  endbr64
  mov    $0x1,%eax
  xor    %ecx,%ecx
  jmp    L15
  nopl   (%rax)
L24:
  add    $0x1,%rax
L15:
  lea    -0x5(%rax),%edx
  cmp    $0x2,%edx
  jbe    L37
  cmp    $0x9,%rax
  jne    L24
  movslq %ecx,%rdx
  sar    $0x1f,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  imul   %edx,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4d4873ed,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x35,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L37:
  movsbl -0x1(%rdi,%rax,1),%edx
  lea    -0x30(%rcx,%rdx,1),%ecx
  imul   $0xa,%ecx,%ecx
  jmp    L24
```

assistant: ```c
int closeHash(char ID[]) {
  int square = 0, i, w = 0;
  for (i = 0; i < 9; i++) {
    if (i == 4 || i == 5 || i == 6) {
      square = square + (ID[i] - 48);
      square *= 10;
    }
  }
  square /= 10;
  square = square * square;
  square = square % 53;
  return square;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<closeHash>:
  endbr64
  movsbl 0x4(%rdi),%eax
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x5(%rdi),%eax
  lea    -0x30(%rax,%rdx,2),%eax
  lea    (%rax,%rax,4),%edx
  movsbl 0x6(%rdi),%eax
  lea    -0x30(%rax,%rdx,2),%edx
  imul   %edx,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x4d4873ed,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x24,%rax
  sub    %ecx,%eax
  imul   $0x35,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int closeHash(char ID[]) {
  int square = 0, i, w = 0;
  for (i = 0; i < 9; i++) {
    if (i == 4 || i == 5 || i == 6) {
      square = square + (ID[i] - 48);
      square *= 10;
    }
  }
  square /= 10;
  square = square * square;
  square = square % 53;
  return square;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kore_color_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <kore_color_vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void kore_color_printf(int color, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_color_vprintf(color, fmt, args);
  va_end(args);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kore_color_printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <kore_color_vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void kore_color_printf(int color, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_color_vprintf(color, fmt, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kore_color_printf>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <kore_color_vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void kore_color_printf(int color, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_color_vprintf(color, fmt, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kore_color_printf>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <kore_color_vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void kore_color_printf(int color, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_color_vprintf(color, fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SysCtlLDOConfigSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400fe160,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SysCtlLDOConfigSet(unsigned long ulConfig) {

  ;
  (*((volatile unsigned long *)(0x400FE160))) = ulConfig;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SysCtlLDOConfigSet>:
  endbr64
  mov    %rdi,0x400fe160
  ret
```

assistant: ```c
void SysCtlLDOConfigSet(unsigned long ulConfig) {

  ;
  (*((volatile unsigned long *)(0x400FE160))) = ulConfig;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SysCtlLDOConfigSet>:
  endbr64
  mov    %rdi,0x400fe160
  ret
```

assistant: ```c
void SysCtlLDOConfigSet(unsigned long ulConfig) {

  ;
  (*((volatile unsigned long *)(0x400FE160))) = ulConfig;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SysCtlLDOConfigSet>:
  endbr64
  mov    %rdi,0x400fe160
  ret
```

assistant: ```c
void SysCtlLDOConfigSet(unsigned long ulConfig) {

  ;
  (*((volatile unsigned long *)(0x400FE160))) = ulConfig;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<descale_and_clamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x4(%rbp),%eax
  mov    $0xff,%edi
  mov    $0x0,%r8d
  mov    %esi,%ecx
  add    %edx,%eax
  sar    %cl,%eax
  sub    $0xffffff80,%eax
  cmovl  %r8d,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char descale_and_clamp(int x, int shift) {
  __asm__("add %3,%1\n"
          "\tsar %2,%1\n"
          "\tsub $-128,%1\n"
          "\tcmovl %5,%1\n"
          "\tcmpl %4,%1\n"
          "\tcmovg %4,%1\n"
          : "=r"(x)
          : "0"(x), "Ic"((unsigned char)shift), "ir"(1U << (shift - 1)), "r"(0xff), "r"(0));
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<descale_and_clamp>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%edx
  mov    %edi,%eax
  mov    $0xff,%edi
  mov    $0x0,%r8d
  mov    %esi,%ecx
  add    %edx,%eax
  sar    %cl,%eax
  sub    $0xffffff80,%eax
  cmovl  %r8d,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  ret
```

assistant: ```c
unsigned char descale_and_clamp(int x, int shift) {
  __asm__("add %3,%1\n"
          "\tsar %2,%1\n"
          "\tsub $-128,%1\n"
          "\tcmovl %5,%1\n"
          "\tcmpl %4,%1\n"
          "\tcmovg %4,%1\n"
          : "=r"(x)
          : "0"(x), "Ic"((unsigned char)shift), "ir"(1U << (shift - 1)), "r"(0xff), "r"(0));
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<descale_and_clamp>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  shl    %cl,%eax
  mov    %esi,%ecx
  mov    %eax,%edx
  mov    %edi,%eax
  mov    $0xff,%edi
  add    %edx,%eax
  sar    %cl,%eax
  sub    $0xffffff80,%eax
  cmovl  %r8d,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  ret
```

assistant: ```c
unsigned char descale_and_clamp(int x, int shift) {
  __asm__("add %3,%1\n"
          "\tsar %2,%1\n"
          "\tsub $-128,%1\n"
          "\tcmovl %5,%1\n"
          "\tcmpl %4,%1\n"
          "\tcmovg %4,%1\n"
          : "=r"(x)
          : "0"(x), "Ic"((unsigned char)shift), "ir"(1U << (shift - 1)), "r"(0xff), "r"(0));
  return x;
}
```