ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  je     L16
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    (%rbx),%rsi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L72:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  test   $0x1,%al
  je     L70
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L70
  test   %ebx,%ebx
  jns    L20
  mov    %ebx,%ebp
  neg    %ebp
  cmp    $0xffffffff,%ebx
  jge    L5
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D4(%rip),%r14
  jmp    L21
L70:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L72
L124:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jge    L69
L21:
  test   $0x1,%bl
  je     L124
  mov    $0x5,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L124
  mov    %ebx,%edi
  call   <findNdigits@plt>
  mov    %eax,%r15d
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%r15d
  jle    L124
  mov    %ebx,%r13d
  mov    %r15d,%r12d
  jmp    L124
L5:
  mov    $0x0,%r13d
  mov    $0x0,%r12d
L69:
  mov    %r13d,%edx
  mov    %r12d,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L72
L20:
  mov    %ebx,%edi
  call   <findNdigits@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L72
```

tool_calls: name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string
name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string

tool: D20: ERROR: invalid or missing argument

tool: D34: USAGE: %s n


tool: D4: %6d: %d


tool: D21: ERROR: Invalid argument.  n must not be divisible by 2 or 5.

tool: D18: max ndigits = %d for n = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n, i, maxdigits, maxdigitsi, ndigits;
  if (argc != 2) {
    printf("ERROR: invalid or missing argument\n");
    printf("USAGE: %s n\n", argv[0]);
    return (1);
  }
  n = atoi(argv[1]);
  if (n % 2 == 0 || n % 5 == 0) {
    printf("ERROR: Invalid argument.  n must not be divisible by 2 or 5.\n");
    return (1);
  }
  if (n < 0) {
    maxdigits = 0;
    maxdigitsi = 0;
    for (i = 1; i < -n; i++) {
      if (i % 2 != 0 && i % 5 != 0) {
        ndigits = findNdigits(i);
        printf("%6d: %d\n", i, ndigits);
        if (maxdigits < ndigits) {
          maxdigits = ndigits;
          maxdigitsi = i;
        }
      }
    }
    printf("max ndigits = %d for n = %d\n", maxdigits, maxdigitsi);
  } else {
    ndigits = findNdigits(n);
    printf("%6d: %d\n", n, ndigits);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L121
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    (%r12),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L121:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   $0x1,%al
  je     L129
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L129
  test   %r12d,%r12d
  jns    L77
  mov    %r12d,%ebx
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  neg    %ebx
  add    $0x1,%r12d
  je     L114
  mov    $0x1,%r12d
  lea    D11(%rip),%r13
  jmp    L96
  nopl   0x0(%rax)
L83:
  add    $0x1,%r12d
  cmp    %ebx,%r12d
  jge    L114
L96:
  test   $0x1,%r12b
  je     L83
  mov    %r12d,%eax
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L83
  mov    %r12d,%edi
  call   <findNdigits@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %eax,%ebp
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r14d,%ebp
  jle    L83
  mov    %r12d,%r15d
  mov    %ebp,%r14d
  jmp    L83
L129:
  lea    D57(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L56
L77:
  mov    %r12d,%edi
  call   <findNdigits@plt>
  mov    %r12d,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L56
L114:
  mov    %r15d,%edx
  mov    %r14d,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L56
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D57
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D5: ERROR: invalid or missing argument

tool: D10: USAGE: %s n


tool: D11: %6d: %d


tool: D57: ERROR: Invalid argument.  n must not be divisible by 2 or 5.

tool: D13: max ndigits = %d for n = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n, i, maxdigits, maxdigitsi, ndigits;
  if (argc != 2) {
    printf("ERROR: invalid or missing argument\n");
    printf("USAGE: %s n\n", argv[0]);
    return (1);
  }
  n = atoi(argv[1]);
  if (n % 2 == 0 || n % 5 == 0) {
    printf("ERROR: Invalid argument.  n must not be divisible by 2 or 5.\n");
    return (1);
  }
  if (n < 0) {
    maxdigits = 0;
    maxdigitsi = 0;
    for (i = 1; i < -n; i++) {
      if (i % 2 != 0 && i % 5 != 0) {
        ndigits = findNdigits(i);
        printf("%6d: %d\n", i, ndigits);
        if (maxdigits < ndigits) {
          maxdigits = ndigits;
          maxdigitsi = i;
        }
      }
    }
    printf("max ndigits = %d for n = %d\n", maxdigits, maxdigitsi);
  } else {
    ndigits = findNdigits(n);
    printf("%6d: %d\n", n, ndigits);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L30
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    (%r12),%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L63:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  test   $0x1,%al
  je     L22
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
  test   %r12d,%r12d
  jns    L35
  mov    %r12d,%ebx
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  neg    %ebx
  add    $0x1,%r12d
  je     L24
  mov    $0x1,%r12d
  lea    D16(%rip),%r13
  jmp    L91
  nopl   0x0(%rax)
L42:
  add    $0x1,%r12d
  cmp    %ebx,%r12d
  jge    L24
L91:
  test   $0x1,%r12b
  je     L42
  mov    %r12d,%eax
  mov    $0x5,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L42
  mov    %r12d,%edi
  call   <findNdigits@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %eax,%ebp
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r14d,%ebp
  jle    L42
  mov    %r12d,%r15d
  mov    %ebp,%r14d
  jmp    L42
L22:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L63
L35:
  mov    %r12d,%edi
  call   <findNdigits@plt>
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L63
L24:
  mov    %r15d,%edx
  mov    %r14d,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L63
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D43
type: string
name: read_data
arguments: tag: D16
type: string
name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D12
type: string

tool: D18: ERROR: invalid or missing argument

tool: D43: USAGE: %s n


tool: D16: %6d: %d


tool: D14: ERROR: Invalid argument.  n must not be divisible by 2 or 5.

tool: D12: max ndigits = %d for n = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int n, i, maxdigits, maxdigitsi, ndigits;
  if (argc != 2) {
    printf("ERROR: invalid or missing argument\n");
    printf("USAGE: %s n\n", argv[0]);
    return (1);
  }
  n = atoi(argv[1]);
  if (n % 2 == 0 || n % 5 == 0) {
    printf("ERROR: Invalid argument.  n must not be divisible by 2 or 5.\n");
    return (1);
  }
  if (n < 0) {
    maxdigits = 0;
    maxdigitsi = 0;
    for (i = 1; i < -n; i++) {
      if (i % 2 != 0 && i % 5 != 0) {
        ndigits = findNdigits(i);
        printf("%6d: %d\n", i, ndigits);
        if (maxdigits < ndigits) {
          maxdigits = ndigits;
          maxdigitsi = i;
        }
      }
    }
    printf("max ndigits = %d for n = %d\n", maxdigits, maxdigitsi);
  } else {
    ndigits = findNdigits(n);
    printf("%6d: %d\n", n, ndigits);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cell2row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L4
  cmpl   $0x9,-0xc(%rbp)
  jg     L4
  cmpl   $0x0,-0x4(%rbp)
  js     L4
  cmpl   $0x8,-0x4(%rbp)
  jg     L4
  cmpl   $0x0,-0x8(%rbp)
  js     L4
  cmpl   $0x8,-0x8(%rbp)
  jg     L4
  mov    $0x1,%eax
  jmp    L18
L4:
  mov    $0x0,%eax
L18:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  lea    0x0(,%rax,8),%edx
  lea    (%rax,%rdx,1),%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  leave
  ret
```

assistant: ```c
int cell2row(int r, int c, int val) {
  assert(val > 0 && val < 10 && r >= 0 && r < 9 && c >= 0 && c < 9);
  return r * 9 * 9 + c * 9 + val - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cell2row>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  lea    -0x1(%rdx),%eax
  mov    $0x0,%edi
  cmp    $0x8,%eax
  ja     L9
  cmp    $0x8,%ebp
  setbe  %al
  cmp    $0x8,%esi
  setbe  %dil
  movzbl %dil,%edi
  and    %eax,%edi
L9:
  call   <assert@plt>
  lea    0x0(%rbp,%rbp,8),%eax
  lea    (%rax,%rax,8),%eax
  lea    (%rbx,%rbx,8),%edx
  add    %edx,%eax
  lea    -0x1(%r12,%rax,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cell2row(int r, int c, int val) {
  assert(val > 0 && val < 10 && r >= 0 && r < 9 && c >= 0 && c < 9);
  return r * 9 * 9 + c * 9 + val - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cell2row>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x8,%eax
  ja     L8
  cmp    $0x8,%ebp
  setbe  %al
  xor    %edi,%edi
  cmp    $0x8,%esi
  setbe  %dil
  and    %eax,%edi
L8:
  call   <assert@plt>
  lea    0x0(%rbp,%rbp,8),%eax
  lea    (%rbx,%rbx,8),%edx
  pop    %rbx
  lea    (%rax,%rax,8),%eax
  pop    %rbp
  add    %edx,%eax
  lea    -0x1(%r12,%rax,1),%eax
  pop    %r12
  ret
```

assistant: ```c
int cell2row(int r, int c, int val) {
  assert(val > 0 && val < 10 && r >= 0 && r < 9 && c >= 0 && c < 9);
  return r * 9 * 9 + c * 9 + val - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cell2row>:
  endbr64
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x8,%eax
  ja     L1
  cmp    $0x8,%ebp
  setbe  %al
  xor    %edi,%edi
  cmp    $0x8,%esi
  setbe  %dil
  and    %eax,%edi
L1:
  call   <assert@plt>
  lea    0x0(%rbp,%rbp,8),%eax
  lea    (%rbx,%rbx,8),%edx
  pop    %rbx
  lea    (%rax,%rax,8),%eax
  pop    %rbp
  add    %edx,%eax
  lea    -0x1(%r12,%rax,1),%eax
  pop    %r12
  ret
```

assistant: ```c
int cell2row(int r, int c, int val) {
  assert(val > 0 && val < 10 && r >= 0 && r < 9 && c >= 0 && c < 9);
  return r * 9 * 9 + c * 9 + val - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x17,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x10,%eax
  and    $0x7f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: 	Sched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int status;
  unsigned int queued;
  unsigned int next;
  unsigned int prior;
  status = atoi(argv[1]);
  queued = ((status >> 31) & 0x00000001);
  next = ((status >> 23) & 0x000000FF);
  prior = ((status >> 16) & 0x0000007F);
  printf("\tSched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)\n", queued, next, prior);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  shr    $0x10,%ecx
  and    $0x7f,%ecx
  mov    %eax,%edx
  shr    $0x17,%edx
  movzbl %dl,%edx
  shr    $0x1f,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: 	Sched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int status;
  unsigned int queued;
  unsigned int next;
  unsigned int prior;
  status = atoi(argv[1]);
  queued = ((status >> 31) & 0x00000001);
  next = ((status >> 23) & 0x000000FF);
  prior = ((status >> 16) & 0x0000007F);
  printf("\tSched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)\n", queued, next, prior);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%ecx
  mov    %eax,%edx
  shr    $0x1f,%eax
  shr    $0x10,%ecx
  shr    $0x17,%edx
  mov    %eax,%esi
  and    $0x7f,%ecx
  movzbl %dl,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string

tool: D7: 	Sched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int status;
  unsigned int queued;
  unsigned int next;
  unsigned int prior;
  status = atoi(argv[1]);
  queued = ((status >> 31) & 0x00000001);
  next = ((status >> 23) & 0x000000FF);
  prior = ((status >> 16) & 0x0000007F);
  printf("\tSched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)\n", queued, next, prior);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%ecx
  mov    %eax,%edx
  shr    $0x1f,%eax
  shr    $0x10,%ecx
  shr    $0x17,%edx
  mov    %eax,%esi
  and    $0x7f,%ecx
  movzbl %dl,%edx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_guessed: string

tool: D6: 	Sched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int status;
  unsigned int queued;
  unsigned int next;
  unsigned int prior;
  status = atoi(argv[1]);
  queued = ((status >> 31) & 0x00000001);
  next = ((status >> 23) & 0x000000FF);
  prior = ((status >> 16) & 0x0000007F);
  printf("\tSched - (QUE=0x%2.2x) (NXT=0x%2.2x) (PRI=0x%2.2x)\n", queued, next, prior);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stringRelease>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void stringRelease(char *src) {
  if (src)
    free((void *)src);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stringRelease>:
  endbr64
  test   %rdi,%rdi
  je     L4
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
void stringRelease(char *src) {
  if (src)
    free((void *)src);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stringRelease>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void stringRelease(char *src) {
  if (src)
    free((void *)src);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stringRelease>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void stringRelease(char *src) {
  if (src)
    free((void *)src);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L4:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int my_strlen(const char *s) {
  int size_t = 0;
  while (s[size_t] != '\0') {
    size_t++;
  }
  return (size_t);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x1,%eax
L23:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L23
L18:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L18
```

assistant: ```c
int my_strlen(const char *s) {
  int size_t = 0;
  while (s[size_t] != '\0') {
    size_t++;
  }
  return (size_t);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  mov    $0x1,%eax
  xchg   %ax,%ax
L5:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int my_strlen(const char *s) {
  int size_t = 0;
  while (s[size_t] != '\0') {
    size_t++;
  }
  return (size_t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    $0x1,%eax
  xchg   %ax,%ax
L17:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L17
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int my_strlen(const char *s) {
  int size_t = 0;
  while (s[size_t] != '\0') {
    size_t++;
  }
  return (size_t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CompareSquare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mul@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CompareSquare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init@plt>
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mpz_cmp@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CompareSquare>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <mpz_clear@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CompareSquare>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <mpz_clear@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<uint32ToInt8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t uint32ToInt8(uint32_t x) {
  int8_t y = x;
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uint32ToInt8>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int8_t uint32ToInt8(uint32_t x) {
  int8_t y = x;
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uint32ToInt8>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int8_t uint32ToInt8(uint32_t x) {
  int8_t y = x;
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uint32ToInt8>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int8_t uint32ToInt8(uint32_t x) {
  int8_t y = x;
  return y;
}
```