ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPrimo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L12
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L24
  addl   $0x1,-0x4(%rbp)
  jmp    L29
L24:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jg     L5
L29:
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int isPrimo(long n) {
  int i, counter = 0;
  for (i = 2; i < n; i++) {
    if (n % i == 0) {
      counter++;
      break;
    }
  }
  return (counter == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isPrimo>:
  endbr64
  cmp    $0x2,%rdi
  jle    L52
  test   $0x1,%dil
  je     L37
  mov    $0x3,%ecx
L21:
  mov    %rcx,%rsi
  cmp    %rcx,%rdi
  je     L50
  add    $0x1,%rcx
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L21
  mov    $0x1,%eax
  jmp    L64
L50:
  mov    $0x0,%eax
L64:
  xor    $0x1,%eax
  ret
L52:
  mov    $0x0,%eax
  jmp    L64
L37:
  mov    $0x1,%eax
  jmp    L64
```

assistant: ```c
int isPrimo(long n) {
  int i, counter = 0;
  for (i = 2; i < n; i++) {
    if (n % i == 0) {
      counter++;
      break;
    }
  }
  return (counter == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isPrimo>:
  endbr64
  cmp    $0x2,%rdi
  jle    L35
  test   $0x1,%dil
  je     L1
  mov    $0x3,%ecx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rdi,%rax
  add    $0x1,%rcx
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  je     L1
L25:
  mov    %rcx,%rsi
  cmp    %rcx,%rdi
  jne    L18
L35:
  mov    $0x1,%eax
  ret
  nop
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isPrimo(long n) {
  int i, counter = 0;
  for (i = 2; i < n; i++) {
    if (n % i == 0) {
      counter++;
      break;
    }
  }
  return (counter == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isPrimo>:
  endbr64
  cmp    $0x2,%rdi
  jle    L5
  test   $0x1,%dil
  je     L40
  mov    $0x3,%ecx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rdi,%rax
  add    $0x1,%rcx
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  je     L40
L19:
  mov    %rcx,%rsi
  cmp    %rcx,%rdi
  jne    L17
L5:
  mov    $0x1,%eax
  ret
  nop
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isPrimo(long n) {
  int i, counter = 0;
  for (i = 2; i < n; i++) {
    if (n % i == 0) {
      counter++;
      break;
    }
  }
  return (counter == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<callKaprekarFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L13:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isKarprekarNumber@plt>
  test   %rax,%rax
  je     L6
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L13
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D17: %d 

tool: D14: INVALID RANGE

assistant: ```c
void callKaprekarFunction(int p, int q) {
  int count = 0;
  for (int i = p; i <= q; i++) {
    if (isKarprekarNumber(i)) {
      count++;
      printf("%d ", i);
    }
  }
  if (count == 0) {
    printf("INVALID RANGE");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<callKaprekarFunction>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jg     L51
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%r12d
  lea    D13(%rip),%r13
  jmp    L7
L47:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L46
L7:
  mov    %ebx,%edi
  call   <isKarprekarNumber@plt>
  test   %rax,%rax
  je     L47
  add    $0x1,%r12d
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L46:
  test   %r12d,%r12d
  je     L51
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L50
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D13: %d 

tool: D15: INVALID RANGE

assistant: ```c
void callKaprekarFunction(int p, int q) {
  int count = 0;
  for (int i = p; i <= q; i++) {
    if (isKarprekarNumber(i)) {
      count++;
      printf("%d ", i);
    }
  }
  if (count == 0) {
    printf("INVALID RANGE");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<callKaprekarFunction>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jg     L28
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D6(%rip),%r13
  xor    %r12d,%r12d
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L4
L26:
  mov    %ebx,%edi
  call   <isKarprekarNumber@plt>
  test   %rax,%rax
  je     L52
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %ebx,%ebp
  jge    L26
L4:
  test   %r12d,%r12d
  je     L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D6: %d 

tool: D8: INVALID RANGE

assistant: ```c
void callKaprekarFunction(int p, int q) {
  int count = 0;
  for (int i = p; i <= q; i++) {
    if (isKarprekarNumber(i)) {
      count++;
      printf("%d ", i);
    }
  }
  if (count == 0) {
    printf("INVALID RANGE");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<callKaprekarFunction>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edi
  jg     L38
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D5(%rip),%r13
  xor    %r12d,%r12d
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L56:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L17
L50:
  mov    %ebx,%edi
  call   <isKarprekarNumber@plt>
  test   %rax,%rax
  je     L56
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %ebx,%ebp
  jge    L50
L17:
  test   %r12d,%r12d
  je     L38
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x8,%rsp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D13
type: string

tool: D5: %d 

tool: D13: INVALID RANGE

assistant: ```c
void callKaprekarFunction(int p, int q) {
  int count = 0;
  for (int i = p; i <= q; i++) {
    if (isKarprekarNumber(i)) {
      count++;
      printf("%d ", i);
    }
  }
  if (count == 0) {
    printf("INVALID RANGE");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ang_vec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dot_vec@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mod_vec@plt>
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <mod_vec@plt>
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <acos@plt>
  movq   %xmm0,%rax
  movsd  D11(%rip),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D0
type_guessed: f64

tool: D11: 3.1415026

tool: D0: 180

assistant: ```c
double ang_vec(struct vec *one, struct vec *two) {
  double dot;
  double cos_;
  dot = dot_vec(one, two);
  cos_ = (acos(dot / (mod_vec(one) * mod_vec(two))) / (3.1415026)) * 180.0;
  return cos_;
}
```
user: What is the c source code of the assembly code below?

```asm
<ang_vec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <dot_vec@plt>
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <mod_vec@plt>
  movq   %xmm0,%r12
  mov    %rbp,%rdi
  call   <mod_vec@plt>
  movq   %r12,%xmm1
  mulsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  call   <acos@plt>
  divsd  D14(%rip),%xmm0
  mulsd  D17(%rip),%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: f64

tool: D14: 3.1415026

tool: D17: 180

assistant: ```c
double ang_vec(struct vec *one, struct vec *two) {
  double dot;
  double cos_;
  dot = dot_vec(one, two);
  cos_ = (acos(dot / (mod_vec(one) * mod_vec(two))) / (3.1415026)) * 180.0;
  return cos_;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ang_vec>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  call   <dot_vec@plt>
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <mod_vec@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <mod_vec@plt>
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <acos@plt>
  divsd  D17(%rip),%xmm0
  mulsd  D6(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_infered: f64
name: disassemble_data
arguments: tag: D6
type_infered: f64

tool: D17: 3.1415026

tool: D6: 180

assistant: ```c
double ang_vec(struct vec *one, struct vec *two) {
  double dot;
  double cos_;
  dot = dot_vec(one, two);
  cos_ = (acos(dot / (mod_vec(one) * mod_vec(two))) / (3.1415026)) * 180.0;
  return cos_;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ang_vec>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  call   <dot_vec@plt>
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <mod_vec@plt>
  mov    %rbp,%rdi
  movsd  %xmm0,(%rsp)
  call   <mod_vec@plt>
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <acos@plt>
  divsd  D11(%rip),%xmm0
  mulsd  D1(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: f64
name: parse_data
arguments: tag: D1
type_infered: f64

tool: D11: 3.1415026

tool: D1: 180

assistant: ```c
double ang_vec(struct vec *one, struct vec *two) {
  double dot;
  double cos_;
  dot = dot_vec(one, two);
  cos_ = (acos(dot / (mod_vec(one) * mod_vec(two))) / (3.1415026)) * 180.0;
  return cos_;
}
```
user: Translate the below assembly code into C programming language:

```asm
<createErasePack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x7,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0xe,(%rax)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  cmpl   $0x0,-0x2c(%rbp)
  je     L14
  mov    $0x43,%ecx
  jmp    L18
L14:
  mov    $0x41,%ecx
L18:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %rdx,%rdi
  call   <checksum@plt>
  mov    %eax,(%rbx)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int createErasePack(uint8_t *pack, uint8_t tipe) {
  uint8_t ptr = 0;
  pack[ptr++] = 0x07;
  pack[ptr++] = 0x0E;
  pack[ptr++] = 1;
  pack[ptr++] = tipe ? 'C' : 'A';
  pack[ptr++] = checksum(&pack[2]);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<createErasePack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x7,(%rdi)
  movl   $0xe,0x4(%rdi)
  movl   $0x1,0x8(%rdi)
  cmp    $0x1,%esi
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
  add    $0x43,%eax
  mov    %eax,0xc(%rdi)
  lea    0x8(%rdi),%rdi
  call   <checksum@plt>
  mov    %eax,0x10(%rbx)
  mov    $0x5,%eax
  pop    %rbx
  ret
```

assistant: ```c
int createErasePack(uint8_t *pack, uint8_t tipe) {
  uint8_t ptr = 0;
  pack[ptr++] = 0x07;
  pack[ptr++] = 0x0E;
  pack[ptr++] = 1;
  pack[ptr++] = tipe ? 'C' : 'A';
  pack[ptr++] = checksum(&pack[2]);
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<createErasePack>:
  endbr64
  movabs $0xe00000007,%rax
  cmp    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rax,(%rdi)
  sbb    %eax,%eax
  lea    0x8(%rdi),%rdi
  and    $0xfffffffe,%eax
  movl   $0x1,(%rdi)
  add    $0x43,%eax
  mov    %eax,0x4(%rdi)
  call   <checksum@plt>
  mov    %eax,0x10(%rbx)
  mov    $0x5,%eax
  pop    %rbx
  ret
```

assistant: ```c
int createErasePack(uint8_t *pack, uint8_t tipe) {
  uint8_t ptr = 0;
  pack[ptr++] = 0x07;
  pack[ptr++] = 0x0E;
  pack[ptr++] = 1;
  pack[ptr++] = tipe ? 'C' : 'A';
  pack[ptr++] = checksum(&pack[2]);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<createErasePack>:
  endbr64
  mov    D2(%rip),%rax
  cmp    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x1,0x8(%rdi)
  lea    0x8(%rdi),%rdi
  mov    %rax,-0x8(%rdi)
  sbb    %eax,%eax
  and    $0xfffffffe,%eax
  add    $0x43,%eax
  mov    %eax,0x4(%rdi)
  call   <checksum@plt>
  mov    %eax,0x10(%rbx)
  mov    $0x5,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: byte[8]

tool: {"D2": [0x07,0x00,0x00,0x00,0x0e,0x00,0x00,0x00]}

assistant: ```c
int createErasePack(uint8_t *pack, uint8_t tipe) {
  uint8_t ptr = 0;
  pack[ptr++] = 0x07;
  pack[ptr++] = 0x0E;
  pack[ptr++] = 1;
  pack[ptr++] = tipe ? 'C' : 'A';
  pack[ptr++] = checksum(&pack[2]);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yesno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <input@plt>
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    $0x79,%al
  jne    L0
  mov    $0x1,%eax
  jmp    L19
L0:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
uint8_t yesno(void) {
  char b[2];
  input(b, 2);
  if (tolower(*b) == 'y')
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<yesno>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  mov    $0x2,%esi
  call   <input@plt>
  movsbl 0x6(%rsp),%edi
  call   <tolower@plt>
  cmp    $0x79,%al
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t yesno(void) {
  char b[2];
  input(b, 2);
  if (tolower(*b) == 'y')
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<yesno>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <input@plt>
  movsbl 0x6(%rsp),%edi
  call   <tolower@plt>
  cmp    $0x79,%al
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t yesno(void) {
  char b[2];
  input(b, 2);
  if (tolower(*b) == 'y')
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yesno>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%rdi
  call   <input@plt>
  movsbl 0x6(%rsp),%edi
  call   <tolower@plt>
  cmp    $0x79,%al
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t yesno(void) {
  char b[2];
  input(b, 2);
  if (tolower(*b) == 'y')
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L54
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L10
L54:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jne    L23
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L10
L23:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jns    L47
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  neg    %eax
  jmp    L32
L47:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L32:
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jns    L64
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  neg    %eax
  jmp    L77
L64:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L77:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pgcd@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D13: Nombre de parametres insuffisants

tool: D0: infini

tool: D9: %d

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  } else if (atoi(argv[2]) == 0) {
    printf("infini\n");
    return 1;
  } else {
    int a = (atoi(argv[1]) < 0 ? atoi(argv[1]) * -1 : atoi(argv[1]));
    int b = (atoi(argv[2]) < 0 ? atoi(argv[2]) * -1 : atoi(argv[2]));
    printf("%d", pgcd(a, b));
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L50
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  mov    %rsi,%rbx
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  jne    L18
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L32
L18:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  js     L23
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L0:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  test   %eax,%eax
  js     L76
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
L68:
  mov    %ebp,%edi
  call   <pgcd@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L32
L23:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%ebp
  jmp    L0
L76:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%esi
  jmp    L68
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D1: Nombre de parametres insuffisants

tool: D7: infini

tool: D14: %d

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  } else if (atoi(argv[2]) == 0) {
    printf("infini\n");
    return 1;
  } else {
    int a = (atoi(argv[1]) < 0 ? atoi(argv[1]) * -1 : atoi(argv[1]));
    int b = (atoi(argv[2]) < 0 ? atoi(argv[2]) * -1 : atoi(argv[2]));
    printf("%d", pgcd(a, b));
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L79
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L51:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L79:
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  call   <atoi@plt>
  test   %eax,%eax
  jne    L73
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L51
L73:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x8(%rbx),%rdi
  test   %eax,%eax
  js     L0
  call   <atoi@plt>
  mov    %eax,%ebp
L30:
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  test   %eax,%eax
  js     L32
  call   <atoi@plt>
  mov    %eax,%esi
L54:
  mov    %ebp,%edi
  call   <pgcd@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L51
L0:
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%ebp
  jmp    L30
L32:
  call   <atoi@plt>
  neg    %eax
  mov    %eax,%esi
  jmp    L54
```

tool_calls: name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D9
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D28: Nombre de parametres insuffisants

tool: D9: infini

tool: D14: %d

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3) {
    printf("Nombre de parametres insuffisants\n");
    return 1;
  } else if (atoi(argv[2]) == 0) {
    printf("infini\n");
    return 1;
  } else {
    int a = (atoi(argv[1]) < 0 ? atoi(argv[1]) * -1 : atoi(argv[1]));
    int b = (atoi(argv[2]) < 0 ? atoi(argv[2]) * -1 : atoi(argv[2]));
    printf("%d", pgcd(a, b));
    return 0;
  }
}
```