ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L15
L22:
  mov    %rsp,%rsi
  mov    0x8(%rbx),%rdi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%rsi
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L15:
  mov    %edi,%esi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D66
data_type: string
name: unpack_data
arguments: label: D30
data_type: string
name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D22
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D69
data_type: string

tool: D6: uid %d gid %d


tool: D66: blksize %d blocks %d


tool: D30: file[%s] size is %d the dev %d 


tool: D25: inode number %d


tool: D22: protection %d


tool: D18: number of hard links %d


tool: D69: the must most argc,the current argc is %d


assistant: ```c
int main(int argc, char **argv) {
  struct stat buf;
  if (argc < 2) {
    printf("the must most argc,the current argc is %d\n", argc);
    exit(1);
  }
  stat(argv[1], &buf);
  printf("uid %d gid %d\n", buf.st_uid, buf.st_gid);
  printf("blksize %d blocks %d\n", buf.st_blksize, buf.st_blocks);
  printf("file[%s] size is %d the dev %d \n", argv[1], buf.st_size, buf.st_dev);
  printf("inode number %d\n", buf.st_ino);
  printf("protection %d\n", buf.st_mode);
  printf("number of hard links %d\n", buf.st_nlink);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L24
L5:
  mov    0x8(%rbx),%rdi
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0x8(%rbx),%rsi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L24:
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D41
type_infered: string
name: read_data
arguments: data_label: D53
type_infered: string
name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D51
type_infered: string
name: read_data
arguments: data_label: D4
type_infered: string
name: read_data
arguments: data_label: D6
type_infered: string

tool: D41: uid %d gid %d


tool: D53: blksize %d blocks %d


tool: D45: file[%s] size is %d the dev %d 


tool: D33: inode number %d


tool: D51: protection %d


tool: D4: number of hard links %d


tool: D6: the must most argc,the current argc is %d


assistant: ```c
int main(int argc, char **argv) {
  struct stat buf;
  if (argc < 2) {
    printf("the must most argc,the current argc is %d\n", argc);
    exit(1);
  }
  stat(argv[1], &buf);
  printf("uid %d gid %d\n", buf.st_uid, buf.st_gid);
  printf("blksize %d blocks %d\n", buf.st_blksize, buf.st_blocks);
  printf("file[%s] size is %d the dev %d \n", argv[1], buf.st_size, buf.st_dev);
  printf("inode number %d\n", buf.st_ino);
  printf("protection %d\n", buf.st_mode);
  printf("number of hard links %d\n", buf.st_nlink);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L15
L5:
  mov    0x8(%rbx),%rdi
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0x8(%rbx),%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%esi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x1c(%rsp),%esi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%esi
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  mov    %edi,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D50
type: string
name: parse_data
arguments: label: D49
type: string
name: parse_data
arguments: label: D61
type: string
name: parse_data
arguments: label: D44
type: string
name: parse_data
arguments: label: D52
type: string
name: parse_data
arguments: label: D22
type: string

tool: D31: uid %d gid %d


tool: D50: blksize %d blocks %d


tool: D49: file[%s] size is %d the dev %d 


tool: D61: inode number %d


tool: D44: protection %d


tool: D52: number of hard links %d


tool: D22: the must most argc,the current argc is %d


assistant: ```c
int main(int argc, char **argv) {
  struct stat buf;
  if (argc < 2) {
    printf("the must most argc,the current argc is %d\n", argc);
    exit(1);
  }
  stat(argv[1], &buf);
  printf("uid %d gid %d\n", buf.st_uid, buf.st_gid);
  printf("blksize %d blocks %d\n", buf.st_blksize, buf.st_blocks);
  printf("file[%s] size is %d the dev %d \n", argv[1], buf.st_size, buf.st_dev);
  printf("inode number %d\n", buf.st_ino);
  printf("protection %d\n", buf.st_mode);
  printf("number of hard links %d\n", buf.st_nlink);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<part>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L59
L50:
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L50
  jmp    L20
L57:
  subl   $0x1,-0x20(%rbp)
L20:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L57
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L59
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L59:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L5
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int part(int a[], int l, int r) {
  int p;
  int tmp;
  p = a[(l + r) / 2];
  while (l <= r) {
    while (a[l] < p)
      l++;
    while (p < a[r])
      r--;
    if (l <= r) {
      tmp = a[l];
      a[l] = a[r];
      a[r] = tmp;
      l++;
      r--;
    }
  }
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<part>:
  endbr64
  mov    %rdi,%r11
  mov    %esi,%ecx
  lea    (%rsi,%rdx,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  jmp    L34
L54:
  mov    %r8d,(%r9)
  mov    %esi,(%r10)
  add    $0x1,%ecx
  sub    $0x1,%edx
  jmp    L34
L53:
  movslq %edx,%rax
  lea    (%r11,%rax,4),%r10
  mov    (%r10),%r8d
  cmp    %r8d,%edi
  jge    L54
L84:
  movslq %edx,%rax
  lea    -0x4(%r11,%rax,4),%rax
L61:
  sub    $0x1,%edx
  mov    %rax,%r10
  sub    $0x4,%rax
  mov    0x4(%rax),%r8d
  cmp    %edi,%r8d
  jg     L61
L91:
  cmp    %ecx,%edx
  jge    L54
L34:
  cmp    %edx,%ecx
  jg     L76
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%r11,%rax,1),%r9
  mov    (%r9),%esi
  lea    0x4(%r11,%rax,1),%rax
  cmp    %esi,%edi
  jle    L53
L64:
  add    $0x1,%ecx
  mov    %rax,%r9
  add    $0x4,%rax
  mov    -0x4(%rax),%esi
  cmp    %edi,%esi
  jl     L64
  movslq %edx,%rax
  lea    (%r11,%rax,4),%r10
  mov    (%r10),%r8d
  cmp    %r8d,%edi
  jl     L84
  jmp    L91
L76:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int part(int a[], int l, int r) {
  int p;
  int tmp;
  p = a[(l + r) / 2];
  while (l <= r) {
    while (a[l] < p)
      l++;
    while (p < a[r])
      r--;
    if (l <= r) {
      tmp = a[l];
      a[l] = a[r];
      a[r] = tmp;
      l++;
      r--;
    }
  }
  return l;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<part>:
  endbr64
  lea    (%rsi,%rdx,1),%ecx
  mov    %rdi,%r11
  mov    %esi,%r8d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  cmp    %edx,%esi
  jg     L31
  push   %rbx
L73:
  movslq %r8d,%rax
  movslq %edx,%rbx
  shl    $0x2,%rax
  lea    (%r11,%rbx,4),%r10
  lea    (%r11,%rax,1),%rcx
  mov    (%r10),%r9d
  lea    0x4(%r11,%rax,1),%rax
  mov    (%rcx),%esi
  cmp    %edi,%esi
  jge    L86
L46:
  mov    %rax,%rcx
  mov    (%rax),%esi
  lea    0x4(%rax),%rax
  add    $0x1,%r8d
  cmp    %edi,%esi
  jl     L46
  cmp    %r9d,%edi
  jge    L3
L88:
  lea    -0x4(%r11,%rbx,4),%rax
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %rax,%r10
  mov    (%rax),%r9d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%r9d
  jg     L55
L3:
  cmp    %r8d,%edx
  jge    L77
L28:
  cmp    %edx,%r8d
  jle    L73
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L86:
  cmp    %r9d,%edi
  jl     L88
L77:
  mov    %r9d,(%rcx)
  add    $0x1,%r8d
  sub    $0x1,%edx
  mov    %esi,(%r10)
  jmp    L28
L31:
  mov    %esi,%eax
  ret
```

assistant: ```c
int part(int a[], int l, int r) {
  int p;
  int tmp;
  p = a[(l + r) / 2];
  while (l <= r) {
    while (a[l] < p)
      l++;
    while (p < a[r])
      r--;
    if (l <= r) {
      tmp = a[l];
      a[l] = a[r];
      a[r] = tmp;
      l++;
      r--;
    }
  }
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<part>:
  endbr64
  lea    (%rsi,%rdx,1),%ecx
  mov    %rdi,%r11
  mov    %esi,%r8d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%edi
  cmp    %edx,%esi
  jg     L21
  push   %rbx
L4:
  movslq %r8d,%rax
  movslq %edx,%rbx
  shl    $0x2,%rax
  lea    (%r11,%rbx,4),%r10
  lea    (%r11,%rax,1),%rcx
  mov    (%r10),%r9d
  lea    0x4(%r11,%rax,1),%rax
  mov    (%rcx),%esi
  cmp    %edi,%esi
  jge    L7
L18:
  mov    %rax,%rcx
  mov    (%rax),%esi
  lea    0x4(%rax),%rax
  add    $0x1,%r8d
  cmp    %edi,%esi
  jl     L18
  cmp    %r9d,%edi
  jge    L28
L70:
  lea    -0x4(%r11,%rbx,4),%rax
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rax,%r10
  mov    (%rax),%r9d
  sub    $0x4,%rax
  sub    $0x1,%edx
  cmp    %edi,%r9d
  jg     L17
L28:
  cmp    %r8d,%edx
  jge    L77
L11:
  cmp    %edx,%r8d
  jle    L4
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L7:
  cmp    %r9d,%edi
  jl     L70
L77:
  mov    %r9d,(%rcx)
  add    $0x1,%r8d
  sub    $0x1,%edx
  mov    %esi,(%r10)
  jmp    L11
L21:
  mov    %esi,%eax
  ret
```

assistant: ```c
int part(int a[], int l, int r) {
  int p;
  int tmp;
  p = a[(l + r) / 2];
  while (l <= r) {
    while (a[l] < p)
      l++;
    while (p < a[r])
      r--;
    if (l <= r) {
      tmp = a[l];
      a[l] = a[r];
      a[r] = tmp;
      l++;
      r--;
    }
  }
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<partial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L75
L33:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L75:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L33
  movl   $0x1,-0x14(%rbp)
  jmp    L53
L79:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L16
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L16
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L53
L16:
  cmpl   $0x0,-0x10(%rbp)
  jne    L86
  addl   $0x1,-0x14(%rbp)
  jmp    L53
L86:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
L53:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L79
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *partial(char *needle, int n_len) {
  int *pi = (int *)malloc(sizeof(int) * n_len);
  int i = 0, j = 0, k = 0;
  for (i = 0; i < n_len; i++) {
    pi[i] = 0;
  }
  i = 1;
  while (i + j < n_len) {
    if (j < n_len && needle[i + j] == needle[j]) {
      j++;
      pi[i + j - 1] = j;
    } else {
      if (j == 0) {
        i++;
      } else {
        i += j - pi[j - 1];
        j = pi[j - 1];
      }
    }
  }
  return pi;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<partial>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %ebx,%ebx
  jle    L41
  mov    %ebx,%edx
  lea    (%rax,%rdx,4),%rdx
L99:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L99
L41:
  cmp    $0x1,%ebx
  jle    L48
  mov    $0x0,%eax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  jmp    L23
L91:
  test   %eax,%eax
  jne    L43
  add    $0x1,%ecx
L87:
  lea    (%rcx,%rax,1),%edx
  cmp    %ebx,%edx
  jge    L48
L23:
  cmp    %eax,%ebx
  jle    L91
  movslq %edx,%rdx
  movslq %eax,%rdi
  movzbl 0x0(%rbp,%rdi,1),%edi
  cmp    %dil,0x0(%rbp,%rdx,1)
  jne    L91
  add    $0x1,%eax
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rdx
  mov    %eax,-0x4(%rsi,%rdx,4)
  jmp    L87
L43:
  movslq %eax,%rdx
  mov    -0x4(%rsi,%rdx,4),%edx
  sub    %edx,%eax
  add    %eax,%ecx
  mov    %edx,%eax
  jmp    L87
L48:
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *partial(char *needle, int n_len) {
  int *pi = (int *)malloc(sizeof(int) * n_len);
  int i = 0, j = 0, k = 0;
  for (i = 0; i < n_len; i++) {
    pi[i] = 0;
  }
  i = 1;
  while (i + j < n_len) {
    if (j < n_len && needle[i + j] == needle[j]) {
      j++;
      pi[i + j - 1] = j;
    } else {
      if (j == 0) {
        i++;
      } else {
        i += j - pi[j - 1];
        j = pi[j - 1];
      }
    }
  }
  return pi;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<partial>:
  endbr64
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,4),%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L42
  lea    0x0(,%r12,4),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %r12,%rbx
  call   <memset@plt>
  mov    %rax,%r8
  cmp    $0x1,%r12d
  jle    L42
  xor    %eax,%eax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  jmp    L50
  nop
L51:
  add    $0x1,%ecx
  mov    %ecx,%edx
L6:
  cmp    %ebx,%edx
  jge    L42
L50:
  cmp    %eax,%ebx
  jle    L32
  movslq %eax,%rsi
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rsi,1),%edi
  cmp    %dil,0x0(%rbp,%rdx,1)
  je     L54
L32:
  test   %eax,%eax
  je     L51
  movslq %eax,%rdx
  mov    -0x4(%r8,%rdx,4),%esi
  sub    %esi,%eax
  add    %eax,%ecx
  mov    %esi,%eax
  lea    (%rsi,%rcx,1),%edx
  cmp    %ebx,%edx
  jl     L50
L42:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L54:
  add    $0x1,%eax
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rsi
  mov    %eax,-0x4(%r8,%rsi,4)
  jmp    L6
```

assistant: ```c
int *partial(char *needle, int n_len) {
  int *pi = (int *)malloc(sizeof(int) * n_len);
  int i = 0, j = 0, k = 0;
  for (i = 0; i < n_len; i++) {
    pi[i] = 0;
  }
  i = 1;
  while (i + j < n_len) {
    if (j < n_len && needle[i + j] == needle[j]) {
      j++;
      pi[i + j - 1] = j;
    } else {
      if (j == 0) {
        i++;
      } else {
        i += j - pi[j - 1];
        j = pi[j - 1];
      }
    }
  }
  return pi;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<partial>:
  endbr64
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%r12,4),%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L10
  lea    0x0(,%r12,4),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %r12,%rbx
  call   <memset@plt>
  mov    %rax,%r8
  cmp    $0x1,%r12d
  jle    L10
  xor    %eax,%eax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  jmp    L52
  nop
L53:
  add    $0x1,%ecx
  mov    %ecx,%edx
L68:
  cmp    %edx,%ebx
  jle    L10
L52:
  cmp    %eax,%ebx
  jle    L21
  movslq %eax,%rsi
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rsi,1),%edi
  cmp    %dil,0x0(%rbp,%rdx,1)
  je     L75
L21:
  test   %eax,%eax
  je     L53
  movslq %eax,%rdx
  mov    -0x4(%r8,%rdx,4),%esi
  sub    %esi,%eax
  add    %eax,%ecx
  mov    %esi,%eax
  lea    (%rsi,%rcx,1),%edx
  cmp    %edx,%ebx
  jg     L52
L10:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
L75:
  add    $0x1,%eax
  lea    (%rax,%rcx,1),%edx
  movslq %edx,%rsi
  mov    %eax,-0x4(%r8,%rsi,4)
  jmp    L68
```

assistant: ```c
int *partial(char *needle, int n_len) {
  int *pi = (int *)malloc(sizeof(int) * n_len);
  int i = 0, j = 0, k = 0;
  for (i = 0; i < n_len; i++) {
    pi[i] = 0;
  }
  i = 1;
  while (i + j < n_len) {
    if (j < n_len && needle[i + j] == needle[j]) {
      j++;
      pi[i + j - 1] = j;
    } else {
      if (j == 0) {
        i++;
      } else {
        i += j - pi[j - 1];
        j = pi[j - 1];
      }
    }
  }
  return pi;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<do_recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  mov    $0x1000,%edx
  mov    $0xba,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  call   <do_recurse>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
do_recurse() {
  char pg[4096];
  memset(pg, 0xba, sizeof(pg));
  do_recurse();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_recurse>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1000,%edx
  mov    $0xba,%esi
  call   <memset@plt>
  mov    $0x0,%eax
  call   <do_recurse>
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x1018,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
do_recurse() {
  char pg[4096];
  memset(pg, 0xba, sizeof(pg));
  do_recurse();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_recurse>:
  endbr64
  lea    -0x9000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    $0xba,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x9008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x1000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x2000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x3000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x4000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x5000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x6000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x7000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x8000(%rsp),%rdi
  call   <memset@plt>
  xor    %eax,%eax
  call   <do_recurse>
  mov    0x9008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x9018,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
do_recurse() {
  char pg[4096];
  memset(pg, 0xba, sizeof(pg));
  do_recurse();
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_recurse>:
  endbr64
  lea    -0x9000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    $0xba,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x9008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x1000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x2000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x3000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x4000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x5000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x6000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x7000(%rsp),%rdi
  call   <memset@plt>
  mov    $0x1000,%edx
  mov    $0xba,%esi
  lea    0x8000(%rsp),%rdi
  call   <memset@plt>
  xor    %eax,%eax
  call   <do_recurse>
  mov    0x9008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  xor    %eax,%eax
  add    $0x9018,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
do_recurse() {
  char pg[4096];
  memset(pg, 0xba, sizeof(pg));
  do_recurse();
}
```