ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<NRF24_SendPolling>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  jmp    L4
  nopl   0x0(%rax)
L28:
  mov    %eax,%r12d
  mov    0x8(%rsp),%eax
  test   $0x20,%al
  jne    L0
L4:
  mov    $0x7,%edi
  call   <NRF24_Read_Reg@plt>
  mov    $0x17,%edi
  mov    %eax,0x8(%rsp)
  call   <NRF24_Read_Reg@plt>
  mov    %eax,0xc(%rsp)
  mov    0x8(%rsp),%eax
  and    $0x10,%eax
  je     L28
  mov    $0xffffffff,%r12d
L0:
  xor    %eax,%eax
  call   <NRF24_CE_Disable@plt>
  mov    $0x20,%esi
  mov    $0x7,%edi
  call   <NRF24_Write_Reg@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int NRF24_SendPolling(void) {
  volatile uint8_t status, fifo_status;
  int ret;
  do {
    status = NRF24_Read_Reg(0x07);
    fifo_status = NRF24_Read_Reg(0x17);
    if (status & (1 << 4)) {
      ret = -1;
      break;
    }
    if (status & (1 << 5)) {
      ret = 0;
      break;
    }
  } while (1);
  NRF24_CE_Disable();
  NRF24_Write_Reg(0x07, (1 << 5));
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<NRF24_SendPolling>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  jmp    L2
  nopl   0x0(%rax)
L10:
  mov    %eax,%r12d
  mov    0x8(%rsp),%eax
  test   $0x20,%al
  jne    L8
L2:
  mov    $0x7,%edi
  call   <NRF24_Read_Reg@plt>
  mov    $0x17,%edi
  mov    %eax,0x8(%rsp)
  call   <NRF24_Read_Reg@plt>
  mov    %eax,0xc(%rsp)
  mov    0x8(%rsp),%eax
  and    $0x10,%eax
  je     L10
  mov    $0xffffffff,%r12d
L8:
  xor    %eax,%eax
  call   <NRF24_CE_Disable@plt>
  mov    $0x20,%esi
  mov    $0x7,%edi
  call   <NRF24_Write_Reg@plt>
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int NRF24_SendPolling(void) {
  volatile uint8_t status, fifo_status;
  int ret;
  do {
    status = NRF24_Read_Reg(0x07);
    fifo_status = NRF24_Read_Reg(0x17);
    if (status & (1 << 4)) {
      ret = -1;
      break;
    }
    if (status & (1 << 5)) {
      ret = 0;
      break;
    }
  } while (1);
  NRF24_CE_Disable();
  NRF24_Write_Reg(0x07, (1 << 5));
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libamg_str_next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    -0x8(%rbp),%rax
  jmp    L11
L10:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
char *libamg_str_next_token(char *str, char sep) {
  char *token = strchr(str, sep);
  if (!token)
    return token;
  token[0] = '\0';
  return ++token;
}
```
user: What is the c source code of the assembly code below?

```asm
<libamg_str_next_token>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
  add    $0x1,%rax
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *libamg_str_next_token(char *str, char sep) {
  char *token = strchr(str, sep);
  if (!token)
    return token;
  token[0] = '\0';
  return ++token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<libamg_str_next_token>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
  add    $0x1,%rax
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *libamg_str_next_token(char *str, char sep) {
  char *token = strchr(str, sep);
  if (!token)
    return token;
  token[0] = '\0';
  return ++token;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<libamg_str_next_token>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
  add    $0x1,%rax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *libamg_str_next_token(char *str, char sep) {
  char *token = strchr(str, sep);
  if (!token)
    return token;
  token[0] = '\0';
  return ++token;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iLog2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  jmp    L39
L20:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L30
  mov    -0x4(%rbp),%eax
  jmp    L28
L30:
  subl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x0,-0x4(%rbp)
  jne    L20
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int iLog2(int x) {
  int i;
  for (i = 32; i; i--) {
    if (x & (1 << (i - 1))) {
      return i;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<iLog2>:
  endbr64
  mov    $0x20,%eax
L18:
  mov    %eax,%edx
  sub    $0x1,%eax
  bt     %eax,%edi
  jb     L0
  test   %eax,%eax
  jne    L18
  mov    %eax,%edx
L0:
  mov    %edx,%eax
  ret
```

assistant: ```c
int iLog2(int x) {
  int i;
  for (i = 32; i; i--) {
    if (x & (1 << (i - 1))) {
      return i;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iLog2>:
  endbr64
  mov    $0x20,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L23:
  test   %eax,%eax
  je     L5
L8:
  mov    %eax,%r8d
  lea    -0x1(%rax),%eax
  bt     %eax,%edi
  jae    L23
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int iLog2(int x) {
  int i;
  for (i = 32; i; i--) {
    if (x & (1 << (i - 1))) {
      return i;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iLog2>:
  endbr64
  mov    $0x20,%eax
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L28:
  test   %eax,%eax
  je     L10
L27:
  mov    %eax,%r8d
  lea    -0x1(%rax),%eax
  bt     %eax,%edi
  jae    L28
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int iLog2(int x) {
  int i;
  for (i = 32; i; i--) {
    if (x & (1 << (i - 1))) {
      return i;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<angry_prof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L9:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <validity@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: %d %d

assistant: ```c
void angry_prof(int tick) {
  int n, k;
  int i;
  for (i = 0; i < tick; i++) {
    scanf("%d %d", &n, &k);
    validity(n, k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<angry_prof>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L27
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D8(%rip),%r12
L20:
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <validity@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L20
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: %d %d

assistant: ```c
void angry_prof(int tick) {
  int n, k;
  int i;
  for (i = 0; i < tick; i++) {
    scanf("%d %d", &n, &k);
    validity(n, k);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<angry_prof>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L15
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
  lea    D2(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <validity@plt>
  cmp    %ebx,%ebp
  jne    L10
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: %d %d

assistant: ```c
void angry_prof(int tick) {
  int n, k;
  int i;
  for (i = 0; i < tick; i++) {
    scanf("%d %d", &n, &k);
    validity(n, k);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<angry_prof>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L23
  mov    %edi,%ebp
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r14
  mov    %rsp,%r13
  lea    D6(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <validity@plt>
  cmp    %ebx,%ebp
  jne    L10
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string

tool: D6: %d %d

assistant: ```c
void angry_prof(int tick) {
  int n, k;
  int i;
  for (i = 0; i < tick; i++) {
    scanf("%d %d", &n, &k);
    validity(n, k);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L3:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void str_copy(char *t, char *s) {
  while (*t++ = *s++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_copy>:
  endbr64
  mov    $0x0,%eax
L3:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L3
  ret
```

assistant: ```c
void str_copy(char *t, char *s) {
  while (*t++ = *s++)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L4
  ret
```

assistant: ```c
void str_copy(char *t, char *s) {
  while (*t++ = *s++)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L0
  ret
```

assistant: ```c
void str_copy(char *t, char *s) {
  while (*t++ = *s++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_random_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  %xmm2,-0x38(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L27:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jae    L6
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm3,%xmm3
  cvtsi2sd %rax,%xmm3
  movsd  %xmm3,-0x38(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x38(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D6: w

tool: D3: %f %f 

assistant: ```c
void create_random_file(char *filename, int problem_size) {
  FILE *fp;
  fp = fopen(filename, "w");
  double tmp = 0, previous = 0;
  for (int i = 0; i < problem_size; i++) {
    while (tmp <= previous)
      tmp = (double)rand() / (double)rand();
    previous = tmp;
    fprintf(fp, "%f %f ", tmp, (double)rand() / (double)rand());
  }
  fclose(fp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<create_random_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  lea    D19(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  mov    D3(%rip),%rbx
  lea    D18(%rip),%r14
  test   %r13d,%r13d
  jg     L6
L42:
  mov    %r12,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %r15,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %rbx,%xmm2
  comisd %xmm0,%xmm2
  jae    L12
  movq   %xmm0,%rbx
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %r15,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  divsd  %xmm0,%xmm1
  movq   %rbx,%xmm0
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  je     L42
L6:
  movq   %rbx,%xmm3
  comisd %xmm3,%xmm3
  jae    L12
  jmp    L8
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: f64
name: read_data
arguments: label: D18
type_guessed: string

tool: D19: w

tool: D3: 0

tool: D18: %f %f 

assistant: ```c
void create_random_file(char *filename, int problem_size) {
  FILE *fp;
  fp = fopen(filename, "w");
  double tmp = 0, previous = 0;
  for (int i = 0; i < problem_size; i++) {
    while (tmp <= previous)
      tmp = (double)rand() / (double)rand();
    previous = tmp;
    fprintf(fp, "%f %f ", tmp, (double)rand() / (double)rand());
  }
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_random_file>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  lea    D17(%rip),%rsi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  call   <fopen@plt>
  pxor   %xmm4,%xmm4
  mov    %rax,%r12
  movsd  %xmm4,0x8(%rsp)
  test   %r13d,%r13d
  jle    L27
  xchg   %ax,%ax
L39:
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm3
  jb     L20
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %rbx,%xmm0
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  jae    L26
  movsd  %xmm0,0x8(%rsp)
L20:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    %r14,%rsi
  cvtsi2sd %rax,%xmm0
  mov    %r12,%rdi
  cvtsi2sd %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <fprintf@plt>
  cmp    %ebp,%r13d
  jne    L39
L27:
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <fclose@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D9: %f %f 

tool: D17: w

assistant: ```c
void create_random_file(char *filename, int problem_size) {
  FILE *fp;
  fp = fopen(filename, "w");
  double tmp = 0, previous = 0;
  for (int i = 0; i < problem_size; i++) {
    while (tmp <= previous)
      tmp = (double)rand() / (double)rand();
    previous = tmp;
    fprintf(fp, "%f %f ", tmp, (double)rand() / (double)rand());
  }
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_random_file>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  lea    D11(%rip),%rsi
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  call   <fopen@plt>
  pxor   %xmm5,%xmm5
  mov    %rax,%r12
  movsd  %xmm5,0x8(%rsp)
  test   %r13d,%r13d
  jle    L47
  movsd  0x8(%rsp),%xmm4
  comisd %xmm4,%xmm4
  jb     L12
  xchg   %ax,%ax
L79:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm3
  cvtsi2sd %rbx,%xmm0
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jae    L79
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebp
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %r14,%rsi
  cvtsi2sd %rax,%xmm2
  movsd  0x8(%rsp),%xmm0
  mov    %r12,%rdi
  cvtsi2sd %rbx,%xmm1
  divsd  %xmm2,%xmm1
  call   <fprintf@plt>
  cmp    %ebp,%r13d
  movsd  0x8(%rsp),%xmm0
  je     L47
L70:
  movsd  %xmm0,0x8(%rsp)
  movsd  0x8(%rsp),%xmm4
  comisd %xmm4,%xmm4
  jae    L79
L12:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    %r14,%rsi
  cvtsi2sd %rax,%xmm0
  mov    %r12,%rdi
  cvtsi2sd %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <fprintf@plt>
  cmp    %ebp,%r13d
  je     L47
  movsd  0x8(%rsp),%xmm0
  comisd %xmm0,%xmm0
  jae    L70
  nopl   (%rax)
L27:
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <rand@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  mov    %r14,%rsi
  cvtsi2sd %rax,%xmm0
  mov    %r12,%rdi
  cvtsi2sd %rbx,%xmm1
  divsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <fprintf@plt>
  cmp    %ebp,%r13d
  jg     L27
L47:
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <fclose@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D12: %f %f 

tool: D11: w

assistant: ```c
void create_random_file(char *filename, int problem_size) {
  FILE *fp;
  fp = fopen(filename, "w");
  double tmp = 0, previous = 0;
  for (int i = 0; i < problem_size; i++) {
    while (tmp <= previous)
      tmp = (double)rand() / (double)rand();
    previous = tmp;
    fprintf(fp, "%f %f ", tmp, (double)rand() / (double)rand());
  }
  fclose(fp);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<freeIntArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeIntArray(int **someArray, int rows) {
  int i;
  for (i = 0; i < rows; i++) {
    free(someArray[i]);
  }
  free(someArray);
}
```
user: What is the c source code of the assembly code below:

```asm
<freeIntArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L11
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L9:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L9
L11:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void freeIntArray(int **someArray, int rows) {
  int i;
  for (i = 0; i < rows; i++) {
    free(someArray[i]);
  }
  free(someArray);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<freeIntArray>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L16
L15:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeIntArray(int **someArray, int rows) {
  int i;
  for (i = 0; i < rows; i++) {
    free(someArray[i]);
  }
  free(someArray);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<freeIntArray>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L13
L19:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeIntArray(int **someArray, int rows) {
  int i;
  for (i = 0; i < rows; i++) {
    free(someArray[i]);
  }
  free(someArray);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<espera_envio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x24(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <select@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int espera_envio(int descriptor, int segundos) {
  struct timeval plazo = {segundos, 0L};
  fd_set fds;
  FD_ZERO(&fds);
  FD_SET(descriptor, &fds);
  return (select(descriptor + 1, (fd_set *)NULL, &fds, (fd_set *)NULL, &plazo));
}
```