ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitmap_full>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %esi,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L29
  cmp    $0x40,%ebp
  jg     L29
  mov    (%r12),%rsi
  mov    %rsi,%rax
  not    %rax
  and    $0x3f,%ebp
  je     L18
  mov    $0xffffffffffffffff,%rax
  mov    %ebp,%ecx
  shl    %cl,%rax
  or     %rsi,%rax
  not    %rax
L18:
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <__bitmap_full@plt>
```

assistant: ```c
int bitmap_full(const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= ((int)((sizeof(long) * 8)))))
    return !(~(*src) & (((nbits) % ((int)((sizeof(long) * 8)))) ? (1UL << ((nbits) % ((int)((sizeof(long) * 8))))) - 1 : ~0UL));
  else
    return __bitmap_full(src, nbits);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_column_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string

tool: D1:   

tool: D12: %s	

assistant: ```c
int print_column_callback(void *data, int n_columns, char **col_values, char **col_names) {
  int i;
  printf("  ");
  for (i = 0; i < n_columns; i++) {
    printf("%s\t", col_values[i]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_column_callback>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L19
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D15(%rip),%rbp
L16:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L16
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
type: string
name: retrieve_data
arguments: label: D15
type: string

tool: D19:   

tool: D15: %s	

assistant: ```c
int print_column_callback(void *data, int n_columns, char **col_values, char **col_names) {
  int i;
  printf("  ");
  for (i = 0; i < n_columns; i++) {
    printf("%s\t", col_values[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_column_callback>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L2
  lea    -0x1(%rbp),%eax
  lea    D8(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  xchg   %ax,%ax
L7:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D10:   

tool: D8: %s	

assistant: ```c
int print_column_callback(void *data, int n_columns, char **col_values, char **col_names) {
  int i;
  printf("  ");
  for (i = 0; i < n_columns; i++) {
    printf("%s\t", col_values[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_column_callback>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L3
  lea    -0x1(%rbp),%eax
  lea    D5(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  xchg   %ax,%ax
L5:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D16:   

tool: D5: %s	

assistant: ```c
int print_column_callback(void *data, int n_columns, char **col_values, char **col_names) {
  int i;
  printf("  ");
  for (i = 0; i < n_columns; i++) {
    printf("%s\t", col_values[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert2to8>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xf6a35c09,0x4(%rsp)
  lea    D10(%rip),%rdi
  mov    $0x0,%esi
  jmp    L26
L24:
  add    $0x1,%esi
  add    $0x4,%rdi
  cmp    $0x100,%esi
  je     L8
L26:
  mov    $0x0,%eax
L11:
  lea    (%rax,%rax,1),%ecx
  mov    %esi,%r10d
  sar    %cl,%r10d
  mov    %r10d,%ecx
  and    $0x3,%ecx
  movzbl 0x4(%rsp,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L11
  jmp    L24
L8:
  test   %edx,%edx
  jle    L64
  mov    %r9,%rax
  mov    %r8,%rcx
  lea    -0x1(%rdx),%edx
  lea    0x1(%r9,%rdx,1),%rdi
  lea    D10(%rip),%rdx
L35:
  movzbl (%rax),%esi
  movzbl (%rdx,%rsi,4),%esi
  mov    %sil,(%rcx)
  movzbl (%rax),%esi
  movzbl 0x1(%rdx,%rsi,4),%esi
  mov    %sil,0x1(%rcx)
  movzbl (%rax),%esi
  movzbl 0x2(%rdx,%rsi,4),%esi
  mov    %sil,0x2(%rcx)
  movzbl (%rax),%esi
  movzbl 0x3(%rdx,%rsi,4),%esi
  mov    %sil,0x3(%rcx)
  add    $0x1,%rax
  add    $0x4,%rcx
  cmp    %rdi,%rax
  jne    L35
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert2to8(unsigned char *dest, const unsigned char *src, int bytes) {
  const unsigned char levels[4] = {9, 92, 163, 246};
  static int first = 1;
  static unsigned char lut2to8[256][4];
  int i, o;
  if (first) {
    for (i = 0; i < 256; ++i) {
      int j;
      for (j = 0; j < 4; ++j) {
        int k;
        k = (i >> (2 * j)) & 0x3;
        lut2to8[i][j] = levels[k];
      }
    }
  }
  o = 0;
  for (i = 0; i < bytes; ++i) {
    dest[o++] = lut2to8[src[i]][0];
    dest[o++] = lut2to8[src[i]][1];
    dest[o++] = lut2to8[src[i]][2];
    dest[o++] = lut2to8[src[i]][3];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<convert2to8>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%r8
  mov    %edx,%r9d
  mov    $0x9,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %r8,%rdx
  movl   $0xf6a35c09,0x4(%rsp)
  jmp    L19
  nopl   0x0(%rax)
L30:
  mov    %eax,%ecx
  and    $0x3,%ecx
  movzbl 0x4(%rsp,%rcx,1),%ecx
L19:
  mov    %cl,(%rdx)
  mov    %eax,%ecx
  add    $0x4,%rdx
  sar    $0x2,%ecx
  and    $0x3,%ecx
  movzbl 0x4(%rsp,%rcx,1),%ecx
  mov    %cl,-0x3(%rdx)
  mov    %eax,%ecx
  sar    $0x4,%ecx
  and    $0x3,%ecx
  movzbl 0x4(%rsp,%rcx,1),%ecx
  mov    %cl,-0x2(%rdx)
  mov    %eax,%ecx
  add    $0x1,%eax
  sar    $0x6,%ecx
  movslq %ecx,%rcx
  movzbl 0x4(%rsp,%rcx,1),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    $0x100,%eax
  jne    L30
  lea    -0x1(%r9),%eax
  lea    0x1(%rsi,%rax,1),%rdx
  test   %r9d,%r9d
  jle    L32
L23:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  add    $0x4,%rdi
  movzbl (%r8,%rax,4),%eax
  mov    %al,-0x4(%rdi)
  movzbl -0x1(%rsi),%eax
  movzbl 0x1(%r8,%rax,4),%eax
  mov    %al,-0x3(%rdi)
  movzbl -0x1(%rsi),%eax
  movzbl 0x2(%r8,%rax,4),%eax
  mov    %al,-0x2(%rdi)
  movzbl -0x1(%rsi),%eax
  movzbl 0x3(%r8,%rax,4),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdx
  jne    L23
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert2to8(unsigned char *dest, const unsigned char *src, int bytes) {
  const unsigned char levels[4] = {9, 92, 163, 246};
  static int first = 1;
  static unsigned char lut2to8[256][4];
  int i, o;
  if (first) {
    for (i = 0; i < 256; ++i) {
      int j;
      for (j = 0; j < 4; ++j) {
        int k;
        k = (i >> (2 * j)) & 0x3;
        lut2to8[i][j] = levels[k];
      }
    }
  }
  o = 0;
  for (i = 0; i < bytes; ++i) {
    dest[o++] = lut2to8[src[i]][0];
    dest[o++] = lut2to8[src[i]][1];
    dest[o++] = lut2to8[src[i]][2];
    dest[o++] = lut2to8[src[i]][3];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert2to8>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %edx,%r10d
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xf6a35c09,0x4(%rsp)
  mov    $0x1,%edx
  lea    D10(%rip),%rdi
  movl   $0x9090909,D10(%rip)
  nop
L13:
  mov    %rdx,%rcx
  xor    %eax,%eax
  and    $0x3,%ecx
  mov    0x4(%rsp,%rcx,1),%al
  mov    %edx,%ecx
  sar    $0x2,%ecx
  and    $0x3,%ecx
  mov    0x4(%rsp,%rcx,1),%ah
  mov    %edx,%ecx
  sar    $0x4,%ecx
  and    $0x3,%ecx
  movzwl %ax,%eax
  movzbl 0x4(%rsp,%rcx,1),%esi
  mov    %edx,%ecx
  sar    $0x6,%ecx
  movslq %ecx,%rcx
  shl    $0x10,%esi
  movzbl 0x4(%rsp,%rcx,1),%ecx
  or     %esi,%eax
  shl    $0x18,%ecx
  or     %ecx,%eax
  mov    %eax,(%rdi,%rdx,4)
  add    $0x1,%rdx
  cmp    $0x100,%rdx
  jne    L13
  test   %r10d,%r10d
  jle    L10
  lea    -0x1(%r10),%eax
  lea    0x1(%r9,%rax,1),%rdx
  nopl   (%rax)
L19:
  movzbl (%r9),%eax
  add    $0x1,%r9
  add    $0x4,%r8
  movzbl (%rdi,%rax,4),%eax
  mov    %al,-0x4(%r8)
  movzbl -0x1(%r9),%eax
  movzbl 0x1(%rdi,%rax,4),%eax
  mov    %al,-0x3(%r8)
  movzbl -0x1(%r9),%eax
  movzbl 0x2(%rdi,%rax,4),%eax
  mov    %al,-0x2(%r8)
  movzbl -0x1(%r9),%eax
  movzbl 0x3(%rdi,%rax,4),%eax
  mov    %al,-0x1(%r8)
  cmp    %rdx,%r9
  jne    L19
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void convert2to8(unsigned char *dest, const unsigned char *src, int bytes) {
  const unsigned char levels[4] = {9, 92, 163, 246};
  static int first = 1;
  static unsigned char lut2to8[256][4];
  int i, o;
  if (first) {
    for (i = 0; i < 256; ++i) {
      int j;
      for (j = 0; j < 4; ++j) {
        int k;
        k = (i >> (2 * j)) & 0x3;
        lut2to8[i][j] = levels[k];
      }
    }
  }
  o = 0;
  for (i = 0; i < bytes; ++i) {
    dest[o++] = lut2to8[src[i]][0];
    dest[o++] = lut2to8[src[i]][1];
    dest[o++] = lut2to8[src[i]][2];
    dest[o++] = lut2to8[src[i]][3];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getPressentVoltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x2a,%esi
  mov    %eax,%edi
  call   <dxl_read_byte@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <PrintErrorCode@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getPressentVoltage(int Id) {
  int CurrentVolt;
  CurrentVolt = dxl_read_byte(Id, 42) / 10;
  PrintErrorCode();
  return CurrentVolt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPressentVoltage>:
  endbr64
  push   %rbx
  mov    $0x2a,%esi
  call   <dxl_read_byte@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <PrintErrorCode@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getPressentVoltage(int Id) {
  int CurrentVolt;
  CurrentVolt = dxl_read_byte(Id, 42) / 10;
  PrintErrorCode();
  return CurrentVolt;
}
```
user: What is the c source code of the assembly code below:

```asm
<getPressentVoltage>:
  endbr64
  push   %rbx
  mov    $0x2a,%esi
  call   <dxl_read_byte@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <PrintErrorCode@plt>
  movslq %ebx,%rax
  sar    $0x1f,%ebx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getPressentVoltage(int Id) {
  int CurrentVolt;
  CurrentVolt = dxl_read_byte(Id, 42) / 10;
  PrintErrorCode();
  return CurrentVolt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getPressentVoltage>:
  endbr64
  push   %rbx
  mov    $0x2a,%esi
  call   <dxl_read_byte@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <PrintErrorCode@plt>
  movslq %ebx,%rax
  sar    $0x1f,%ebx
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getPressentVoltage(int Id) {
  int CurrentVolt;
  CurrentVolt = dxl_read_byte(Id, 42) / 10;
  PrintErrorCode();
  return CurrentVolt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%esi
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: toes is %d, twice toes is %d, toes squared is %d.


assistant: ```c
int main(void) {
  int toes;
  toes = 10;
  printf("toes is %d, twice toes is %d, toes squared is %d.\n", toes, toes * 2, toes * toes);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: toes is %d, twice toes is %d, toes squared is %d.


assistant: ```c
int main(void) {
  int toes;
  toes = 10;
  printf("toes is %d, twice toes is %d, toes squared is %d.\n", toes, toes * 2, toes * toes);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: toes is %d, twice toes is %d, toes squared is %d.


assistant: ```c
int main(void) {
  int toes;
  toes = 10;
  printf("toes is %d, twice toes is %d, toes squared is %d.\n", toes, toes * 2, toes * toes);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x14,%edx
  mov    $0xa,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: toes is %d, twice toes is %d, toes squared is %d.


assistant: ```c
int main(void) {
  int toes;
  toes = 10;
  printf("toes is %d, twice toes is %d, toes squared is %d.\n", toes, toes * 2, toes * toes);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hskip_lws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L6:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hskip_lws(const char *hdr) {
  int i;
  for (i = 0; *hdr == ' ' || *hdr == '\t' || *hdr == '\r' || *hdr == '\n'; ++hdr)
    ++i;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hskip_lws>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x0,%esi
  cmp    $0x20,%al
  ja     L42
  movabs $0x100002600,%rdx
  bt     %rax,%rdx
  jae    L18
  mov    %rdi,%rax
  mov    $0x1,%ecx
  sub    %edi,%ecx
  mov    %rdx,%rdi
  jmp    L55
L51:
  bt     %rdx,%rdi
  jae    L42
L55:
  lea    (%rcx,%rax,1),%esi
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jbe    L51
L42:
  mov    %esi,%eax
  ret
L18:
  mov    $0x0,%esi
  jmp    L42
```

assistant: ```c
int hskip_lws(const char *hdr) {
  int i;
  for (i = 0; *hdr == ' ' || *hdr == '\t' || *hdr == '\r' || *hdr == '\n'; ++hdr)
    ++i;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hskip_lws>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0x20,%al
  ja     L27
  movabs $0xfffffffeffffd9ff,%rcx
  bt     %rax,%rcx
  jb     L27
  mov    $0x1,%edx
  sub    %edi,%edx
  nopl   (%rax)
L16:
  lea    (%rdx,%rdi,1),%r8d
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  ja     L27
  bt     %rax,%rcx
  jae    L16
L27:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hskip_lws(const char *hdr) {
  int i;
  for (i = 0; *hdr == ' ' || *hdr == '\t' || *hdr == '\r' || *hdr == '\n'; ++hdr)
    ++i;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hskip_lws>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    $0x20,%al
  ja     L39
  movabs $0xfffffffeffffd9ff,%rcx
  bt     %rax,%rcx
  jb     L39
  mov    $0x1,%edx
  sub    %edi,%edx
  nopl   (%rax)
L10:
  lea    (%rdx,%rdi,1),%r8d
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  ja     L39
  bt     %rax,%rcx
  jae    L10
L39:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int hskip_lws(const char *hdr) {
  int i;
  for (i = 0; *hdr == ' ' || *hdr == '\t' || *hdr == '\r' || *hdr == '\n'; ++hdr)
    ++i;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_minfloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movss  %xmm0,-0x64(%rbp)
  mov    %rdi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x64(%rbp),%xmm0
  cvttss2si %xmm0,%edx
  lea    -0x50(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,-0x58(%rbp)
  movl   $0x8,-0x5c(%rbp)
  jmp    L31
L36:
  pxor   %xmm1,%xmm1
  cvtss2sd -0x64(%rbp),%xmm1
  movq   %xmm1,%rcx
  mov    -0x5c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  movq   %rcx,%xmm0
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <sprintf@plt>
  mov    %eax,-0x54(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  ucomiss -0x64(%rbp),%xmm0
  jp     L73
  ucomiss -0x64(%rbp),%xmm0
  je     L70
  jmp    L73
L70:
  mov    -0x54(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jge    L74
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x58(%rbp)
  lea    -0x30(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L74:
  subl   $0x1,-0x5c(%rbp)
L31:
  cmpl   $0x0,-0x5c(%rbp)
  jg     L36
  jmp    L38
L73:
  nop
L38:
  mov    -0x70(%rbp),%rdx
  mov    -0x58(%rbp),%esi
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D8: %#.9g

tool: D3: %#.*g

assistant: ```c
void print_minfloat(float f, FILE *out) {
  int i;
  int bestlen;
  char best[32];
  bestlen = sprintf(best, "%#.9g", f);
  for (i = 8; i > 0; i--) {
    char buf[sizeof(best)];
    int len = sprintf(buf, "%#.*g", i, f);
    if (f == (float)strtod(buf, 0)) {
      if (len < bestlen) {
        bestlen = len;
        memcpy(best, buf, sizeof(buf));
      }
    } else {
      break;
    }
  }
  fwrite(best, bestlen, 1, out);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_minfloat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  cvttss2si %xmm0,%edx
  lea    0x20(%rsp),%rdi
  lea    D3(%rip),%rsi
  call   <sprintf@plt>
  mov    %eax,%r13d
  mov    $0x8,%ebp
  pxor   %xmm2,%xmm2
  cvtss2sd 0xc(%rsp),%xmm2
  movsd  %xmm2,0x10(%rsp)
  lea    0x40(%rsp),%r12
  lea    D2(%rip),%r14
  lea    0x20(%rsp),%r15
  jmp    L58
L14:
  sub    $0x1,%ebp
  je     L68
L58:
  movsd  0x10(%rsp),%xmm0
  mov    %ebp,%edx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <sprintf@plt>
  mov    %eax,%ebx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtod@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  0xc(%rsp),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L68
  jne    L68
  cmp    %r13d,%ebx
  jge    L14
  mov    $0x20,%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %ebx,%r13d
  jmp    L14
L68:
  lea    0x20(%rsp),%rdi
  mov    0x18(%rsp),%rcx
  mov    $0x1,%edx
  mov    %r13d,%esi
  call   <fwrite@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D3: %#.9g

tool: D2: %#.*g

assistant: ```c
void print_minfloat(float f, FILE *out) {
  int i;
  int bestlen;
  char best[32];
  bestlen = sprintf(best, "%#.9g", f);
  for (i = 8; i > 0; i--) {
    char buf[sizeof(best)];
    int len = sprintf(buf, "%#.*g", i, f);
    if (f == (float)strtod(buf, 0)) {
      if (len < bestlen) {
        bestlen = len;
        memcpy(best, buf, sizeof(buf));
      }
    } else {
      break;
    }
  }
  fwrite(best, bestlen, 1, out);
}
```