ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <f@plt>
  mov    %rbp,%rdi
  call   <k@plt>
  xor    %edx,%edx
  mov    %rsp,%rdi
  movabs $0x32206f6c6c6568,%rax
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <g@plt>
  xor    %edx,%edx
  lea    0x10(%rsp),%rdi
  movabs $0x33206f6c6c6568,%rax
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  call   <h@plt>
  lea    D1(%rip),%rdi
  call   <m@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D7: hello 1

tool: D1: hello 4

assistant: ```c
int main() {
  f("hello 1");
  k("hello 1");
  char hello2[16] = "hello 2";
  g(hello2);
  char hello3[16] = "hello 3";
  h(hello3);
  m("hello 4");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <f@plt>
  mov    %rbp,%rdi
  call   <k@plt>
  xor    %edx,%edx
  mov    %rsp,%rdi
  movabs $0x32206f6c6c6568,%rax
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <g@plt>
  xor    %edx,%edx
  lea    0x10(%rsp),%rdi
  movabs $0x33206f6c6c6568,%rax
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  call   <h@plt>
  lea    D10(%rip),%rdi
  call   <m@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D13
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D13: hello 1

tool: D10: hello 4

assistant: ```c
int main() {
  f("hello 1");
  k("hello 1");
  char hello2[16] = "hello 2";
  g(hello2);
  char hello3[16] = "hello 3";
  h(hello3);
  m("hello 4");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<randchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x60,-0x5(%rbp)
  jle    L4
  cmpb   $0x7a,-0x5(%rbp)
  jle    L12
  jmp    L4
L12:
  nop
  movzbl -0x5(%rbp),%eax
  leave
  ret
```

assistant: ```c
char randchar(void) {
  int r;
  char c;
  for (;;) {
    r = rand();
    c = (r >> 16) & 0xff;
    if ('a' <= c && c <= 'z')
      break;
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<randchar>:
  endbr64
  sub    $0x8,%rsp
L2:
  mov    $0x0,%eax
  call   <rand@plt>
  sar    $0x10,%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L2
  add    $0x8,%rsp
  ret
```

assistant: ```c
char randchar(void) {
  int r;
  char c;
  for (;;) {
    r = rand();
    c = (r >> 16) & 0xff;
    if ('a' <= c && c <= 'z')
      break;
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<randchar>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <rand@plt>
  sar    $0x10,%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L4
  add    $0x8,%rsp
  ret
```

assistant: ```c
char randchar(void) {
  int r;
  char c;
  for (;;) {
    r = rand();
    c = (r >> 16) & 0xff;
    if ('a' <= c && c <= 'z')
      break;
  }
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<randchar>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <rand@plt>
  sar    $0x10,%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L8
  add    $0x8,%rsp
  ret
```

assistant: ```c
char randchar(void) {
  int r;
  char c;
  for (;;) {
    r = rand();
    c = (r >> 16) & 0xff;
    if ('a' <= c && c <= 'z')
      break;
  }
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x40,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    D15(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
char *string_time(char *fmt) {
  static char s[64];
  time_t now = time(0);
  strftime(s, sizeof(s), fmt, localtime(&now));
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_time>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  mov    %rbx,%rdx
  mov    $0x40,%esi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_time(char *fmt) {
  static char s[64];
  time_t now = time(0);
  strftime(s, sizeof(s), fmt, localtime(&now));
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_time>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %r12,%rdx
  lea    D1(%rip),%r12
  mov    $0x40,%esi
  mov    %eax,%ecx
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_time(char *fmt) {
  static char s[64];
  time_t now = time(0);
  strftime(s, sizeof(s), fmt, localtime(&now));
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_time>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %r12,%rdx
  lea    D1(%rip),%r12
  mov    $0x40,%esi
  mov    %eax,%ecx
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *string_time(char *fmt) {
  static char s[64];
  time_t now = time(0);
  strftime(s, sizeof(s), fmt, localtime(&now));
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L95
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
L34:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L34
L95:
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L70
  lea    0xe0(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
L123:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L123
L70:
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%r10d
  sub    %esi,%r10d
  add    $0x1,%r10d
  js     L53
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D36(%rip),%r12
  jmp    L97
L101:
  lea    (%rbx,%rax,1),%edx
  cmp    %edx,%r8d
  setg   %cl
  cmp    %eax,%esi
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  je     L134
L69:
  mov    -0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,-0x4(%rbp,%rax,4)
  jne    L101
  add    $0x1,%r9d
  jmp    L101
L134:
  cmp    %r9d,%esi
  je     L119
  cmp    %ebx,%r10d
  je     L83
L139:
  lea    0x1(%rbx),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r10d
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jl     L53
  mov    %edx,%ebx
L97:
  lea    (%rsi,%rbx,1),%r8d
  mov    $0x1,%eax
  mov    $0x0,%r9d
  lea    0xe0(%rsp),%rdi
  test   %esi,%esi
  jg     L69
  jmp    L134
L119:
  lea    D59(%rip),%rdi
  call   <printf@plt>
L53:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L83:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L139
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D59
type_guessed: string

tool: D24: %d

tool: D36: NO

tool: D59: YES

assistant: ```c
int main() {
  int N1, N2, a[50], b[50], k, x, y;
  scanf("%d", &N1);
  for (int i = 0; i < N1; i++) {
    scanf("%d", &a[i]);
  }
  scanf("%d", &N2);
  for (int i = 0; i < N2; i++) {
    scanf("%d", &b[i]);
  }
  for (k = 0; k <= N1 - N2 + 1; k++) {
    int count = 0, x = k, y = 0;
    while ((x < k + N2) && (y <= N2 - 1)) {
      if (a[x] == b[y])
        count++;
      x++;
      y++;
    }
    if (count == N2) {
      printf("YES");
      break;
    } else if ((count != N2) && (k == N1 - N2 + 1))
      printf("NO");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L42
  nopl   (%rax)
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L14
L42:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  lea    0xe0(%rsp),%rbp
  xor    %ebx,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L43
  nop
L104:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L104
L43:
  mov    0x8(%rsp),%r11d
  mov    %r11d,%r10d
  sub    %esi,%r10d
  add    $0x1,%r10d
  js     L41
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D16(%rip),%r12
  nopl   (%rax)
L52:
  lea    (%rsi,%rbx,1),%r8d
  mov    $0x1,%eax
  xor    %r9d,%r9d
  lea    0xe0(%rsp),%rdi
  test   %esi,%esi
  jle    L114
  nopl   0x0(%rax,%rax,1)
L108:
  mov    -0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,-0x4(%rbp,%rax,4)
  jne    L136
  add    $0x1,%r9d
L136:
  lea    (%rbx,%rax,1),%edx
  cmp    %edx,%r8d
  setg   %cl
  cmp    %eax,%esi
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L108
L114:
  cmp    %r9d,%esi
  je     L131
  cmp    %ebx,%r10d
  je     L113
L34:
  mov    %r11d,%eax
  lea    0x1(%rbx),%edx
  add    $0x4,%rbp
  sub    %esi,%eax
  lea    0x1(%rax),%r10d
  cmp    %ebx,%eax
  jl     L41
  mov    %edx,%ebx
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L113:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%r11d
  jmp    L34
L131:
  lea    D4(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string
name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D4
data_type: string

tool: D14: %d

tool: D16: NO

tool: D4: YES

assistant: ```c
int main() {
  int N1, N2, a[50], b[50], k, x, y;
  scanf("%d", &N1);
  for (int i = 0; i < N1; i++) {
    scanf("%d", &a[i]);
  }
  scanf("%d", &N2);
  for (int i = 0; i < N2; i++) {
    scanf("%d", &b[i]);
  }
  for (k = 0; k <= N1 - N2 + 1; k++) {
    int count = 0, x = k, y = 0;
    while ((x < k + N2) && (y <= N2 - 1)) {
      if (a[x] == b[y])
        count++;
      x++;
      y++;
    }
    if (count == N2) {
      printf("YES");
      break;
    } else if ((count != N2) && (k == N1 - N2 + 1))
      printf("NO");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L124
  nopw   0x0(%rax,%rax,1)
L132:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L132
L124:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  lea    0xe0(%rsp),%rbp
  xor    %ebx,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L23
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  cmp    %ebx,%esi
  jg     L50
L23:
  mov    0x8(%rsp),%r10d
  mov    %r10d,%r12d
  sub    %esi,%r12d
  add    $0x1,%r12d
  js     L110
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D28(%rip),%r13
  nopl   (%rax)
L61:
  lea    (%rsi,%rbx,1),%r8d
  mov    $0x1,%eax
  xor    %r9d,%r9d
  lea    0xe0(%rsp),%rdi
  test   %esi,%esi
  jle    L49
  nopl   0x0(%rax,%rax,1)
L121:
  mov    -0x4(%rbp,%rax,4),%ecx
  cmp    %ecx,-0x4(%rdi,%rax,4)
  jne    L140
  add    $0x1,%r9d
L140:
  lea    (%rbx,%rax,1),%edx
  cmp    %edx,%r8d
  setg   %cl
  cmp    %eax,%esi
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L121
L49:
  cmp    %r9d,%esi
  je     L94
  cmp    %ebx,%r12d
  je     L53
  mov    %r10d,%eax
  lea    0x1(%rbx),%edx
  add    $0x4,%rbp
  sub    %esi,%eax
  lea    0x1(%rax),%r12d
  cmp    %ebx,%eax
  jl     L110
  mov    %edx,%ebx
  jmp    L61
L94:
  lea    D21(%rip),%rdi
  call   <printf@plt>
L110:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L53:
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  mov    0x8(%rsp),%r10d
  mov    0xc(%rsp),%esi
  lea    0x1(%r12),%edx
  mov    %r10d,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r12d
  cmp    %eax,%ebx
  jg     L110
  mov    %edx,%ebx
  jmp    L61
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D28
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string

tool: D24: %d

tool: D28: NO

tool: D21: YES

assistant: ```c
int main() {
  int N1, N2, a[50], b[50], k, x, y;
  scanf("%d", &N1);
  for (int i = 0; i < N1; i++) {
    scanf("%d", &a[i]);
  }
  scanf("%d", &N2);
  for (int i = 0; i < N2; i++) {
    scanf("%d", &b[i]);
  }
  for (k = 0; k <= N1 - N2 + 1; k++) {
    int count = 0, x = k, y = 0;
    while ((x < k + N2) && (y <= N2 - 1)) {
      if (a[x] == b[y])
        count++;
      x++;
      y++;
    }
    if (count == N2) {
      printf("YES");
      break;
    } else if ((count != N2) && (k == N1 - N2 + 1))
      printf("NO");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_lunation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x10(%rax),%r8d
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0xc(%rax),%edi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    0x8(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%esi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  cmpl   $0x3,-0x4(%rbp)
  jle    L2
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x4,%edx
  jne    L25
  mov    $0x2a,%edi
  call   <putchar@plt>
L25:
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0xfffffff8,%edx
  jne    L19
  mov    $0x2a,%edi
  call   <putchar@plt>
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D14
data_type: string

tool: D13: %+5.5d  

tool: D14: %4.4d/%2.2d/%2.2d %2.2d:%2.2d  

assistant: ```c
void print_lunation(int lunation, struct tm *event_date) {
  int i;
  printf("%+5.5d  ", lunation);
  for (i = 0; i <= 3; i++) {
    printf("%4.4d/%2.2d/%2.2d %2.2d:%2.2d  ", event_date[i].tm_year + 1900, event_date[i].tm_mon + 1, event_date[i].tm_mday, event_date[i].tm_hour, event_date[i].tm_min);
  }
  if (lunation % 12 == 4)
    printf("*");
  if (lunation % 12 == -8)
    printf("*");
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_lunation>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edi,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rbx
  add    $0x50,%r12
  lea    D17(%rip),%r13
L8:
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%eax
  lea    0x1(%rax),%edx
  mov    (%rbx),%eax
  lea    0x76c(%rax),%esi
  mov    0x10(%rbx),%r9d
  mov    0xc(%rbx),%r8d
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x14,%rbx
  cmp    %r12,%rbx
  jne    L8
  movslq %ebp,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  shl    $0x2,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  cmp    $0x4,%eax
  je     L45
  cmp    $0xfffffff8,%eax
  je     L28
L43:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L43
L28:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L43
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string

tool: D13: %+5.5d  

tool: D17: %4.4d/%2.2d/%2.2d %2.2d:%2.2d  

assistant: ```c
void print_lunation(int lunation, struct tm *event_date) {
  int i;
  printf("%+5.5d  ", lunation);
  for (i = 0; i <= 3; i++) {
    printf("%4.4d/%2.2d/%2.2d %2.2d:%2.2d  ", event_date[i].tm_year + 1900, event_date[i].tm_mon + 1, event_date[i].tm_mday, event_date[i].tm_hour, event_date[i].tm_min);
  }
  if (lunation % 12 == 4)
    printf("*");
  if (lunation % 12 == -8)
    printf("*");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_lunation>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  lea    0x50(%rbx),%r13
  sub    $0x8,%rsp
  call   <printf@plt>
L0:
  mov    0x4(%rbx),%eax
  mov    0x8(%rbx),%ecx
  mov    %r12,%rdi
  add    $0x14,%rbx
  mov    -0x4(%rbx),%r9d
  mov    -0x8(%rbx),%r8d
  lea    0x1(%rax),%edx
  mov    -0x14(%rbx),%eax
  lea    0x76c(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L0
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ebp
  mov    $0xffffffffffff7ff7,%rax
  add    $0xb,%ebp
  bt     %rbp,%rax
  jb     L9
  mov    $0x2a,%edi
  call   <putchar@plt>
L9:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D16: %4.4d/%2.2d/%2.2d %2.2d:%2.2d  

tool: D2: %+5.5d  

assistant: ```c
void print_lunation(int lunation, struct tm *event_date) {
  int i;
  printf("%+5.5d  ", lunation);
  for (i = 0; i <= 3; i++) {
    printf("%4.4d/%2.2d/%2.2d %2.2d:%2.2d  ", event_date[i].tm_year + 1900, event_date[i].tm_mon + 1, event_date[i].tm_mday, event_date[i].tm_hour, event_date[i].tm_min);
  }
  if (lunation % 12 == 4)
    printf("*");
  if (lunation % 12 == -8)
    printf("*");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_lunation>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  lea    0x50(%rbx),%r13
  sub    $0x8,%rsp
  call   <printf@plt>
L11:
  mov    0x4(%rbx),%eax
  mov    0x8(%rbx),%ecx
  mov    %r12,%rdi
  add    $0x14,%rbx
  mov    -0x4(%rbx),%r9d
  mov    -0x8(%rbx),%r8d
  lea    0x1(%rax),%edx
  mov    -0x14(%rbx),%eax
  lea    0x76c(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L11
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  shl    $0x2,%eax
  sub    %eax,%ebp
  mov    $0xffffffffffff7ff7,%rax
  add    $0xb,%ebp
  bt     %rbp,%rax
  jb     L12
  mov    $0x2a,%edi
  call   <putchar@plt>
L12:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D2
type: string

tool: D5: %4.4d/%2.2d/%2.2d %2.2d:%2.2d  

tool: D2: %+5.5d  

assistant: ```c
void print_lunation(int lunation, struct tm *event_date) {
  int i;
  printf("%+5.5d  ", lunation);
  for (i = 0; i <= 3; i++) {
    printf("%4.4d/%2.2d/%2.2d %2.2d:%2.2d  ", event_date[i].tm_year + 1900, event_date[i].tm_mon + 1, event_date[i].tm_mday, event_date[i].tm_hour, event_date[i].tm_min);
  }
  if (lunation % 12 == 4)
    printf("*");
  if (lunation % 12 == -8)
    printf("*");
  printf("\n");
}
```