ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cb_compile_c>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movabs $0x646f632f706d742f,%rcx
  movabs $0x6f635f626d6f6265,%rbx
  mov    %rcx,(%rsp)
  mov    %rbx,0x8(%rsp)
  movabs $0x6f6974616c69706d,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x632e6e,0x18(%rsp)
  lea    0x400(%rsp),%r14
  mov    %rcx,0x400(%rsp)
  mov    %rbx,0x408(%rsp)
  mov    %rax,0x410(%rsp)
  movl   $0x69622e6e,0x418(%rsp)
  movw   $0x6e,0x41c(%rsp)
  lea    D3(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  lea    D24(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    0x800(%rsp),%rbx
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  test   %eax,%eax
  setne  %al
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0xc10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D3: w

tool: D24: %s


tool: D11: %s %s -o %s

assistant: ```c
int cb_compile_c(const char *cmd, const char *code) {
  char srcpath[1024];
  sprintf(srcpath, "/tmp/codebomb_compilation.c");
  char binpath[1024];
  sprintf(binpath, "/tmp/codebomb_compilation.bin");
  FILE *f = fopen(srcpath, "w");
  fprintf(f, "%s\n", code);
  fclose(f);
  char cmdline[1024];
  sprintf(cmdline, "%s %s -o %s", cmd, srcpath, binpath);
  int e = system(cmdline);
  return (e != 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cb_compile_c>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D34(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  movdqa D30(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  movabs $0x6f6974616c69706d,%rax
  movl   $0x632e6e,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %r14,%rdi
  lea    0x400(%rsp),%rbx
  mov    %rax,0x410(%rsp)
  mov    $0x6e,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x400(%rsp)
  movl   $0x69622e6e,0x418(%rsp)
  mov    %ax,0x41c(%rsp)
  call   <fopen@plt>
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    0x800(%rsp),%rbp
  call   <fclose@plt>
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  test   %eax,%eax
  setne  %al
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0xc10,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D34
type: string
name: parse_data
arguments: data_label: D30
type: byte[16]
name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D32
type: string

tool: D34: w

tool: {"D30": [0x2f,0x74,0x6d,0x70,0x2f,0x63,0x6f,0x64,0x65,0x62,0x6f,0x6d,0x62,0x5f,0x63,0x6f]}

tool: D4: %s


tool: D32: %s %s -o %s

assistant: ```c
int cb_compile_c(const char *cmd, const char *code) {
  char srcpath[1024];
  sprintf(srcpath, "/tmp/codebomb_compilation.c");
  char binpath[1024];
  sprintf(binpath, "/tmp/codebomb_compilation.bin");
  FILE *f = fopen(srcpath, "w");
  fprintf(f, "%s\n", code);
  fclose(f);
  char cmdline[1024];
  sprintf(cmdline, "%s %s -o %s", cmd, srcpath, binpath);
  int e = system(cmdline);
  return (e != 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cb_compile_c>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  lea    D21(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0xc10,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xc08(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  movabs $0x6f6974616c69706d,%rax
  movl   $0x632e6e,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %r14,%rdi
  lea    0x400(%rsp),%rbx
  mov    %rax,0x410(%rsp)
  mov    $0x6e,%eax
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x400(%rsp)
  movl   $0x69622e6e,0x418(%rsp)
  mov    %ax,0x41c(%rsp)
  call   <fopen@plt>
  mov    %r13,%rdx
  lea    D26(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    0x800(%rsp),%rbp
  call   <fclose@plt>
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  test   %eax,%eax
  setne  %al
  mov    0xc08(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xc10,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type: string
name: retrieve_data
arguments: label: D8
type: byte[16]
name: retrieve_data
arguments: label: D26
type: string
name: retrieve_data
arguments: label: D6
type: string

tool: D21: w

tool: {"D8": [0x2f,0x74,0x6d,0x70,0x2f,0x63,0x6f,0x64,0x65,0x62,0x6f,0x6d,0x62,0x5f,0x63,0x6f]}

tool: D26: %s


tool: D6: %s %s -o %s

assistant: ```c
int cb_compile_c(const char *cmd, const char *code) {
  char srcpath[1024];
  sprintf(srcpath, "/tmp/codebomb_compilation.c");
  char binpath[1024];
  sprintf(binpath, "/tmp/codebomb_compilation.bin");
  FILE *f = fopen(srcpath, "w");
  fprintf(f, "%s\n", code);
  fclose(f);
  char cmdline[1024];
  sprintf(cmdline, "%s %s -o %s", cmd, srcpath, binpath);
  int e = system(cmdline);
  return (e != 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L22
  mov    $0x1,%eax
  jmp    L38
L22:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L24
  mov    $0xffffffff,%eax
  jmp    L38
L24:
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  if (*(int *)a > *(int *)b)
    return 1;
  else if (*(int *)a < *(int *)b)
    return -1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,%ecx
  jg     L3
  setl   %al
  movzbl %al,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  if (*(int *)a > *(int *)b)
    return 1;
  else if (*(int *)a < *(int *)b)
    return -1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<compare>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L3
  setl   %al
  movzbl %al,%eax
  neg    %eax
L3:
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  if (*(int *)a > *(int *)b)
    return 1;
  else if (*(int *)a < *(int *)b)
    return -1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare>:
  endbr64
  mov    (%rsi),%edx
  mov    $0x1,%eax
  cmp    %edx,(%rdi)
  jg     L9
  setl   %al
  movzbl %al,%eax
  neg    %eax
L9:
  ret
```

assistant: ```c
int compare(const void *a, const void *b) {
  if (*(int *)a > *(int *)b)
    return 1;
  else if (*(int *)a < *(int *)b)
    return -1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <safe_malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <safe_malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L32
L25:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x28(%rbp)
L32:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x28(%rbp)
  jle    L25
  movl   $0x0,-0x28(%rbp)
  jmp    L27
L14:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x28(%rbp)
L27:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x28(%rbp)
  jle    L14
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i, ret;
  char *cp1, *cp2;
  cp1 = safe_malloc(strlen(s1) + 1);
  cp2 = safe_malloc(strlen(s2) + 1);
  for (i = 0; i < strlen(s1) + 1; i++)
    cp1[i] = tolower(s1[i]);
  for (i = 0; i < strlen(s2) + 1; i++)
    cp2[i] = tolower(s2[i]);
  ret = strcmp(cp1, cp2);
  free(cp1);
  free(cp2);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasecmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rax,%r14
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rax,%r13
  mov    $0x0,%ebx
  jmp    L25
L13:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L13
  mov    $0x0,%ebx
  jmp    L30
L15:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L15
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebx
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i, ret;
  char *cp1, *cp2;
  cp1 = safe_malloc(strlen(s1) + 1);
  cp2 = safe_malloc(strlen(s2) + 1);
  for (i = 0; i < strlen(s1) + 1; i++)
    cp1[i] = tolower(s1[i]);
  for (i = 0; i < strlen(s2) + 1; i++)
    cp2[i] = tolower(s2[i]);
  ret = strcmp(cp1, cp2);
  free(cp1);
  free(cp2);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rax,%r13
  jmp    L11
  nopl   0x0(%rax)
L38:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L38
  xor    %ebx,%ebx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L37:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L27
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i, ret;
  char *cp1, *cp2;
  cp1 = safe_malloc(strlen(s1) + 1);
  cp2 = safe_malloc(strlen(s2) + 1);
  for (i = 0; i < strlen(s1) + 1; i++)
    cp1[i] = tolower(s1[i]);
  for (i = 0; i < strlen(s2) + 1; i++)
    cp2[i] = tolower(s2[i]);
  ret = strcmp(cp1, cp2);
  free(cp1);
  free(cp2);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcasecmp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  mov    %rax,%r13
  jmp    L11
  nopl   0x0(%rax)
L21:
  movsbl (%r12,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L21
  xor    %ebx,%ebx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L23:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <tolower@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jge    L23
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  int i, ret;
  char *cp1, *cp2;
  cp1 = safe_malloc(strlen(s1) + 1);
  cp2 = safe_malloc(strlen(s2) + 1);
  for (i = 0; i < strlen(s1) + 1; i++)
    cp1[i] = tolower(s1[i]);
  for (i = 0; i < strlen(s2) + 1; i++)
    cp2[i] = tolower(s2[i]);
  ret = strcmp(cp1, cp2);
  free(cp1);
  free(cp2);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L8
  nop
L2:
  jmp    L2
L8:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *p;
  int *q;
  p = malloc(4);
  q = malloc(4);
  if (p != q) {
  ERROR:
    goto ERROR;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  cmp    %rax,%rbx
  je     L15
L2:
  jmp    L2
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *p;
  int *q;
  p = malloc(4);
  q = malloc(4);
  if (p != q) {
  ERROR:
    goto ERROR;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  cmp    %rax,%rbx
  je     L2
L4:
  jmp    L4
L2:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *p;
  int *q;
  p = malloc(4);
  q = malloc(4);
  if (p != q) {
  ERROR:
    goto ERROR;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  cmp    %rax,%rbx
  je     L16
L3:
  jmp    L3
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *p;
  int *q;
  p = malloc(4);
  q = malloc(4);
  if (p != q) {
  ERROR:
    goto ERROR;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<svd_dscal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jle    L38
  cmpq   $0x0,-0x30(%rbp)
  je     L38
  cmpq   $0x0,-0x30(%rbp)
  jns    L47
  mov    $0x1,%eax
  sub    -0x18(%rbp),%rax
  imul   -0x30(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x28(%rbp)
L47:
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L18:
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x28(%rbp)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L18
  jmp    L6
L38:
  nop
L6:
  pop    %rbp
  ret
```

assistant: ```c
void svd_dscal(long n, double da, double *dx, long incx) {
  long i;
  if (n <= 0 || incx == 0)
    return;
  if (incx < 0)
    dx += (-n + 1) * incx;
  for (i = 0; i < n; i++) {
    *dx *= da;
    dx += incx;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<svd_dscal>:
  endbr64
  test   %rdi,%rdi
  jle    L34
  test   %rdx,%rdx
  je     L34
  js     L5
L29:
  shl    $0x3,%rdx
  mov    $0x0,%eax
L21:
  movapd %xmm0,%xmm1
  mulsd  (%rsi),%xmm1
  movsd  %xmm1,(%rsi)
  add    %rdx,%rsi
  add    $0x1,%rax
  cmp    %rax,%rdi
  jg     L21
L34:
  ret
L5:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  lea    (%rsi,%rax,8),%rsi
  jmp    L29
```

assistant: ```c
void svd_dscal(long n, double da, double *dx, long incx) {
  long i;
  if (n <= 0 || incx == 0)
    return;
  if (incx < 0)
    dx += (-n + 1) * incx;
  for (i = 0; i < n; i++) {
    *dx *= da;
    dx += incx;
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<svd_dscal>:
  endbr64
  test   %rdi,%rdi
  jle    L18
  test   %rdx,%rdx
  je     L18
  js     L27
L6:
  shl    $0x3,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  (%rsi),%xmm1
  add    $0x1,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  add    %rdx,%rsi
  cmp    %rax,%rdi
  jg     L3
L18:
  ret
  nopl   0x0(%rax)
L27:
  mov    $0x1,%eax
  sub    %rdi,%rax
  imul   %rdx,%rax
  lea    (%rsi,%rax,8),%rsi
  jmp    L6
```

assistant: ```c
void svd_dscal(long n, double da, double *dx, long incx) {
  long i;
  if (n <= 0 || incx == 0)
    return;
  if (incx < 0)
    dx += (-n + 1) * incx;
  for (i = 0; i < n; i++) {
    *dx *= da;
    dx += incx;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<svd_dscal>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  jle    L0
  test   %rdx,%rdx
  je     L0
  js     L56
  lea    0x0(,%rdx,8),%rdi
  cmp    $0x1,%rdx
  jne    L33
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  movsd  (%rsi),%xmm1
  add    $0x1,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  add    %rdi,%rsi
  cmp    %rax,%rcx
  jg     L17
L0:
  ret
  nopl   0x0(%rax)
L56:
  mov    $0x1,%eax
  sub    %rdi,%rax
  lea    0x0(,%rdx,8),%rdi
  imul   %rdx,%rax
  lea    (%rsi,%rax,8),%rsi
L33:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  movsd  (%rsi),%xmm1
  add    $0x1,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  add    %rdi,%rsi
  cmp    %rax,%rcx
  jg     L22
  ret
```

assistant: ```c
void svd_dscal(long n, double da, double *dx, long incx) {
  long i;
  if (n <= 0 || incx == 0)
    return;
  if (incx < 0)
    dx += (-n + 1) * incx;
  for (i = 0; i < n; i++) {
    *dx *= da;
    dx += incx;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <converte@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D29
type: string

tool: D25: Quantos segundos? 

tool: D13: %d

tool: D29: %d:%02d:%02d


assistant: ```c
int main() {
  int n, tempo[3];
  printf("Quantos segundos? ");
  scanf("%d", &n);
  converte(n, tempo);
  printf("%d:%02d:%02d\n", tempo[2], tempo[1], tempo[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    0x8(%rsp),%edi
  call   <converte@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string
name: unpack_data
arguments: tag: D14
type_guessed: string

tool: D26: Quantos segundos? 

tool: D22: %d

tool: D14: %d:%02d:%02d


assistant: ```c
int main() {
  int n, tempo[3];
  printf("Quantos segundos? ");
  scanf("%d", &n);
  converte(n, tempo);
  printf("%d:%02d:%02d\n", tempo[2], tempo[1], tempo[0]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  lea    0xc(%rsp),%rsi
  call   <converte@plt>
  mov    0xc(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %eax,%eax
  mov    0x14(%rsp),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D26: Quantos segundos? 

tool: D22: %d

tool: D10: %d:%02d:%02d


assistant: ```c
int main() {
  int n, tempo[3];
  printf("Quantos segundos? ");
  scanf("%d", &n);
  converte(n, tempo);
  printf("%d:%02d:%02d\n", tempo[2], tempo[1], tempo[0]);
  return 0;
}
```