ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<VerifyScanningOneInteger>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  mov    $0x200,%esi
  push   %r12
  mov    %rcx,%r12
  mov    %r8d,%ecx
  push   %rbp
  mov    %r12,%rdx
  mov    %rdi,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  mov    %r15,%rdi
  call   <trio_snprintf@plt>
  lea    0xc(%rsp),%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <trio_sscanf@plt>
  mov    0xc(%rsp),%r8d
  mov    %r14,%rdx
  mov    %r12,%rcx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <Verify@plt>
  mov    0x218(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x220,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int VerifyScanningOneInteger(const char *file, int line, const char *expected, const char *format, int original) {
  int number;
  char data[512];
  trio_snprintf(data, sizeof(data), format, original);
  trio_sscanf(data, format, &number);
  return Verify(file, line, expected, format, number);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u32_memswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  bswap  %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void u32_memswap(unsigned *arr, int length) {
  unsigned *end = arr + length;
  for (; arr < end; arr++) {
    *arr = __builtin_bswap32(*arr);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<u32_memswap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rdx
  cmp    %rdx,%rdi
  jae    L1
L9:
  mov    (%rdi),%eax
  bswap  %eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rdi,%rdx
  ja     L9
L1:
  ret
```

assistant: ```c
void u32_memswap(unsigned *arr, int length) {
  unsigned *end = arr + length;
  for (; arr < end; arr++) {
    *arr = __builtin_bswap32(*arr);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u32_memswap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rdx
  cmp    %rdx,%rdi
  jae    L16
L17:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  bswap  %eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rdx
  ja     L17
L16:
  ret
```

assistant: ```c
void u32_memswap(unsigned *arr, int length) {
  unsigned *end = arr + length;
  for (; arr < end; arr++) {
    *arr = __builtin_bswap32(*arr);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<u32_memswap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rdx
  cmp    %rdx,%rdi
  jae    L15
L12:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  bswap  %eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rdx
  ja     L12
L15:
  ret
```

assistant: ```c
void u32_memswap(unsigned *arr, int length) {
  unsigned *end = arr + length;
  for (; arr < end; arr++) {
    *arr = __builtin_bswap32(*arr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tms_get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x4,-0x24(%rbp)
  jle    L21
  movl   $0x4,-0x24(%rbp)
L21:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L24:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  jns    L24
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%ecx
  sub    $0x1,%ecx
  js     L7
  movslq %ecx,%rcx
  movslq (%rsi),%rax
  lea    (%rdi,%rax,4),%r8
  mov    $0x0,%eax
L29:
  shl    $0x8,%eax
  movzbl (%r8,%rcx,4),%edi
  or     %edi,%eax
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jns    L29
L2:
  add    %edx,(%rsi)
  ret
L7:
  mov    $0x0,%eax
  jmp    L2
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  mov    (%rsi),%r9d
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%ecx
  sub    $0x1,%ecx
  js     L19
  movslq %r9d,%rax
  movslq %ecx,%rcx
  lea    (%rdi,%rax,4),%r8
  xor    %eax,%eax
  nopl   0x0(%rax)
L11:
  movzbl (%r8,%rcx,4),%edi
  shl    $0x8,%eax
  sub    $0x1,%rcx
  or     %edi,%eax
  test   %ecx,%ecx
  jns    L11
  add    %r9d,%edx
  mov    %edx,(%rsi)
  ret
L19:
  add    %r9d,%edx
  xor    %eax,%eax
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tms_get_int>:
  endbr64
  mov    $0x4,%eax
  mov    %rdi,%rcx
  mov    (%rsi),%edi
  cmp    %eax,%edx
  cmovg  %eax,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  js     L11
  add    %edi,%eax
  lea    -0x2(%rdx),%r8d
  cltq
  movzbl (%rcx,%rax,4),%eax
  cmp    $0x1,%edx
  je     L34
  add    %edi,%r8d
  shl    $0x8,%eax
  lea    -0x3(%rdx),%r9d
  movslq %r8d,%r8
  movzbl (%rcx,%r8,4),%r8d
  or     %r8d,%eax
  cmp    $0x2,%edx
  je     L34
  lea    (%r9,%rdi,1),%r8d
  shl    $0x8,%eax
  movslq %r8d,%r8
  movzbl (%rcx,%r8,4),%r8d
  or     %r8d,%eax
  test   %r9d,%r9d
  je     L34
  movslq %edi,%r8
  shl    $0x8,%eax
  movzbl (%rcx,%r8,4),%ecx
  or     %ecx,%eax
L34:
  add    %edi,%edx
  mov    %edx,(%rsi)
  ret
  xchg   %ax,%ax
L11:
  add    %edi,%edx
  xor    %eax,%eax
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
int32_t tms_get_int(uint8_t *msg, int32_t *s, int32_t n) {
  int32_t i;
  int32_t b = 0;
  if (n > 4) {
    n = 4;
  }
  for (i = n - 1; i >= 0; i--) {
    b = (b << 8) | (msg[(*s) + i] & 0xFF);
  }
  (*s) += n;
  return (b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L44
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L43
L44:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
L43:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D37
type_guessed: string
name: read_data
arguments: label: D31
type_guessed: string
name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D37: Please input year number:

tool: D31: %d

tool: D15: %d is a leap year


tool: D12: %d is not a leap year


assistant: ```c
int main(void) {
  int year;
  printf("Please input year number:");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("%d is a leap year\n", year);
  else
    printf("%d is not a leap year\n", year);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L28
  mov    $0x64,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L2
L28:
  movslq %esi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%esi
  jne    L16
L2:
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string
name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string

tool: D8: Please input year number:

tool: D16: %d

tool: D29: %d is a leap year


tool: D39: %d is not a leap year


assistant: ```c
int main(void) {
  int year;
  printf("Please input year number:");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("%d is a leap year\n", year);
  else
    printf("%d is not a leap year\n", year);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L22
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
L0:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L0
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string

tool: D6: Please input year number:

tool: D14: %d

tool: D1: %d is a leap year


tool: D27: %d is not a leap year


assistant: ```c
int main(void) {
  int year;
  printf("Please input year number:");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("%d is a leap year\n", year);
  else
    printf("%d is not a leap year\n", year);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   $0x3,%sil
  jne    L15
  mov    %esi,%eax
  mov    $0x64,%ecx
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L15
L37:
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  imul   $0xc28f5c29,%esi,%eax
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L37
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L17
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D31
datatype: string
name: parse_data
arguments: label: D34
datatype: string
name: parse_data
arguments: label: D8
datatype: string

tool: D5: Please input year number:

tool: D31: %d

tool: D34: %d is a leap year


tool: D8: %d is not a leap year


assistant: ```c
int main(void) {
  int year;
  printf("Please input year number:");
  scanf("%d", &year);
  if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    printf("%d is a leap year\n", year);
  else
    printf("%d is not a leap year\n", year);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: %d


assistant: ```c
main() {
  int a;
  a = 0;
  a = printf("%d\n", a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: %d


assistant: ```c
main() {
  int a;
  a = 0;
  a = printf("%d\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: %d


assistant: ```c
main() {
  int a;
  a = 0;
  a = printf("%d\n", a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
main() {
  int a;
  a = 0;
  a = printf("%d\n", a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<esprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L13
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L13:
  movl   $0xffffffff,-0xc4(%rbp)
  mov    -0xe0(%rbp),%rdx
  mov    -0xc0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xbc(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0xb8(%rbp)
  cmpq   $0x0,-0xb8(%rbp)
  je     L11
  mov    -0xbc(%rbp),%edx
  mov    -0xe0(%rbp),%rcx
  mov    -0xb8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <__parseExtendedFormatString@plt>
  mov    -0xc0(%rbp),%edx
  mov    -0xb8(%rbp),%rcx
  mov    -0xd8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xc4(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L11:
  mov    -0xc0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int esprintf(char *buffer, const char *format, ...) {
  va_list arguments;
  int returnVal = -1, len;
  char *formBuf;
  va_start(arguments, format);
  if ((formBuf = (char *)(malloc(len = (strlen(format) + 1))))) {
    memcpy(formBuf, format, len);
    __parseExtendedFormatString(formBuf);
    returnVal = vsprintf(buffer, formBuf, arguments);
    free(formBuf);
  }
  va_end(arguments);
  return returnVal;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<esprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    $0x0,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  call   <__parseExtendedFormatString@plt>
  mov    $0x0,%edi
  mov    %edi,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L4:
  mov    $0x0,%edi
  call   <va_end@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0xffffffff,%ebp
  jmp    L4
```

assistant: ```c
int esprintf(char *buffer, const char *format, ...) {
  va_list arguments;
  int returnVal = -1, len;
  char *formBuf;
  va_start(arguments, format);
  if ((formBuf = (char *)(malloc(len = (strlen(format) + 1))))) {
    memcpy(formBuf, format, len);
    __parseExtendedFormatString(formBuf);
    returnVal = vsprintf(buffer, formBuf, arguments);
    free(formBuf);
  }
  va_end(arguments);
  return returnVal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<esprintf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %r14d,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <__parseExtendedFormatString@plt>
  mov    %r13,%rdi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L5:
  xor    %edi,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%r12d
  jmp    L5
```

assistant: ```c
int esprintf(char *buffer, const char *format, ...) {
  va_list arguments;
  int returnVal = -1, len;
  char *formBuf;
  va_start(arguments, format);
  if ((formBuf = (char *)(malloc(len = (strlen(format) + 1))))) {
    memcpy(formBuf, format, len);
    __parseExtendedFormatString(formBuf);
    returnVal = vsprintf(buffer, formBuf, arguments);
    free(formBuf);
  }
  va_end(arguments);
  return returnVal;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<esprintf>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %r14d,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rdi
  call   <__parseExtendedFormatString@plt>
  mov    %r13,%rdi
  xor    %edx,%edx
  mov    %rbp,%rsi
  call   <vsprintf@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L17:
  xor    %edi,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%r12d
  jmp    L17
```

assistant: ```c
int esprintf(char *buffer, const char *format, ...) {
  va_list arguments;
  int returnVal = -1, len;
  char *formBuf;
  va_start(arguments, format);
  if ((formBuf = (char *)(malloc(len = (strlen(format) + 1))))) {
    memcpy(formBuf, format, len);
    __parseExtendedFormatString(formBuf);
    returnVal = vsprintf(buffer, formBuf, arguments);
    free(formBuf);
  }
  va_end(arguments);
  return returnVal;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L25
L47:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L49
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xffffff80,%eax
  test   %eax,%eax
  jne    L47
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L49
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L47
L49:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <skip_space@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <skip_space@plt>
  cltq
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_param(cp)
char *cp;
{
  while (*cp && (!isascii(*cp) || (!isspace(*cp) && *cp != '='))) {
    cp++;
  }
  cp = skip_space(cp);
  if (*cp == '=') {
    cp = skip_space(cp + 1);
  }
  return (cp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_param>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  jne    L66
  jmp    L2
L25:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L2
L66:
  test   %bl,%bl
  js     L25
  movsbl %bl,%edi
  call   <isspace@plt>
  cmp    $0x3d,%bl
  je     L2
  test   %eax,%eax
  je     L25
L2:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <skip_space@plt>
  cltq
  cmpb   $0x3d,(%rax)
  je     L11
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    0x1(%rax),%rdi
  mov    $0x0,%eax
  call   <skip_space@plt>
  cltq
  jmp    L32
```

assistant: ```c
char *skip_param(cp)
char *cp;
{
  while (*cp && (!isascii(*cp) || (!isspace(*cp) && *cp != '='))) {
    cp++;
  }
  cp = skip_space(cp);
  if (*cp == '=') {
    cp = skip_space(cp + 1);
  }
  return (cp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_param>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L57
  nopl   0x0(%rax)
L58:
  test   %bl,%bl
  js     L40
  movsbl %bl,%edi
  call   <isspace@plt>
  cmp    $0x3d,%bl
  je     L57
  test   %eax,%eax
  jne    L57
L40:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  test   %bl,%bl
  jne    L58
L57:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <skip_space@plt>
  cltq
  cmpb   $0x3d,(%rax)
  je     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  lea    0x1(%rax),%rdi
  xor    %eax,%eax
  call   <skip_space@plt>
  add    $0x8,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *skip_param(cp)
char *cp;
{
  while (*cp && (!isascii(*cp) || (!isspace(*cp) && *cp != '='))) {
    cp++;
  }
  cp = skip_space(cp);
  if (*cp == '=') {
    cp = skip_space(cp + 1);
  }
  return (cp);
}
```