ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<sig_alarm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <my_str@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: Attempt to contact server timed out.


assistant: ```c
void sig_alarm() {
  my_str("Attempt to contact server timed out.\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <my_str@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: Attempt to contact server timed out.


assistant: ```c
void sig_alarm() {
  my_str("Attempt to contact server timed out.\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <my_str@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: Attempt to contact server timed out.


assistant: ```c
void sig_alarm() {
  my_str("Attempt to contact server timed out.\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_alarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <my_str@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: Attempt to contact server timed out.


assistant: ```c
void sig_alarm() {
  my_str("Attempt to contact server timed out.\n");
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<netrom_inp_dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmpb   $0xff,(%rdi)
  je     L64
L62:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  mov    %rdi,%r13
  mov    %esi,%r14d
  lea    D18(%rip),%rsi
  mov    $0x7,%edi
  call   <lprintf@plt>
  lea    -0xa(%r14),%eax
  mov    %eax,0x1c(%rsp)
  cmp    $0x1,%eax
  jle    L62
  mov    $0x1,%ebx
  lea    0x2e(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x27(%rsp),%r15
  jmp    L35
L85:
  movzbl (%r12),%eax
  add    %eax,%ebp
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,1),%r12
  movzbl (%r12),%edx
  movzbl %dl,%ebx
  mov    %r14d,%ecx
  sub    %ebx,%ecx
  cmp    %ebp,%ecx
  jle    L60
  test   %dl,%dl
  je     L60
L76:
  cmpb   $0x0,0x1(%r13,%rax,1)
  jne    L85
  sub    $0x2,%ebx
  mov    $0x6,%edx
  cmp    %edx,%ebx
  cmovg  %edx,%ebx
  lea    0x2(%r13,%rax,1),%rsi
  mov    %ebx,%edx
  mov    %r15,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x27(%rsp,%rbx,1)
  jmp    L85
L60:
  lea    0x1(%rbp),%ebx
  mov    0x18(%rsp),%r9d
  mov    0x14(%rsp),%r8d
  mov    %r15,%rcx
  mov    0x8(%rsp),%rdx
  lea    D17(%rip),%rsi
  mov    $0x5,%edi
  mov    $0x0,%eax
  call   <lprintf@plt>
  cmp    0x1c(%rsp),%ebx
  jge    L62
L35:
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    0x8(%rsp),%rdi
  call   <pax25@plt>
  lea    0x7(%rbx),%eax
  cltq
  movzbl 0x0(%r13,%rax,1),%eax
  mov    %eax,0x14(%rsp)
  lea    0x8(%rbx),%eax
  cltq
  movzbl 0x0(%r13,%rax,1),%eax
  shl    $0x8,%eax
  lea    0xa(%rbx),%ebp
  add    $0x9,%ebx
  movslq %ebx,%rbx
  movzbl 0x0(%r13,%rbx,1),%edx
  add    %edx,%eax
  mov    %eax,0x18(%rsp)
  movb   $0x0,0x27(%rsp)
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,1),%r12
  movzbl (%r12),%edx
  movzbl %dl,%ebx
  mov    %r14d,%ecx
  sub    %ebx,%ecx
  cmp    %ecx,%ebp
  jge    L60
  test   %dl,%dl
  jne    L76
  jmp    L60
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D18: INP Route Information Frame:


tool: D17:         %12s  %-6s   %6u %6u


assistant: ```c
void netrom_inp_dump(unsigned char *data, int length) {
  char node[10];
  char alias[7];
  int hops;
  int tt;
  int alen;
  int i;
  if (data[0] == 0xff) {
    lprintf(7, "INP Route Information Frame:\n");
    i = 1;
    while (i < length - 10) {
      pax25(node, data + i);
      i += 7;
      hops = data[i++];
      tt = data[i++] * 256;
      tt += data[i++];
      alias[0] = 0;
      while (i < length - data[i] && data[i]) {
        if (data[i + 1] == 0x00) {
          alen = data[i] - 2;
          alen = alen < 7 ? alen : 6;
          memcpy(alias, data + i + 2, alen);
          alias[alen] = 0;
        }
        i += data[i];
      }
      i++;
      lprintf(5, "        %12s  %-6s   %6u %6u\n", node, alias, hops, tt);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<netrom_inp_dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  cmpb   $0xff,(%rdi)
  je     L99
L81:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L99:
  mov    %esi,%ebx
  mov    %rdi,%r14
  lea    D2(%rip),%rsi
  mov    $0x7,%edi
  call   <lprintf@plt>
  lea    -0xa(%rbx),%eax
  mov    %eax,0x1c(%rsp)
  cmp    $0x1,%eax
  jle    L81
  lea    0x2e(%rsp),%rax
  mov    $0x1,%r15d
  lea    0x27(%rsp),%r12
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rsp),%rdi
  movslq %r15d,%rsi
  lea    0xa(%r15),%r13d
  add    %r14,%rsi
  call   <pax25@plt>
  lea    0x7(%r15),%eax
  lea    0x9(%r15),%r11d
  movslq %r13d,%rsi
  cltq
  movslq %r11d,%r11
  mov    %ebx,%edi
  movb   $0x0,0x27(%rsp)
  movzbl (%r14,%rax,1),%eax
  movzbl (%r14,%r11,1),%ebp
  mov    %eax,0x14(%rsp)
  lea    0x8(%r15),%eax
  lea    (%r14,%rsi,1),%r15
  cltq
  movzbl (%r14,%rax,1),%eax
  shl    $0x8,%eax
  add    %ebp,%eax
  mov    %eax,0x18(%rsp)
  movzbl (%r15),%eax
  sub    %eax,%edi
  mov    %eax,%edx
  cmp    %edi,%r13d
  jl     L19
  jmp    L82
L71:
  add    %eax,%r13d
  mov    %ebx,%edi
  movslq %r13d,%rsi
  lea    (%r14,%rsi,1),%r15
  movzbl (%r15),%eax
  sub    %eax,%edi
  mov    %eax,%edx
  cmp    %r13d,%edi
  jle    L82
L19:
  test   %dl,%dl
  je     L82
  cmpb   $0x0,0x1(%r14,%rsi,1)
  jne    L71
  sub    $0x2,%eax
  mov    $0x6,%edx
  lea    0x2(%r14,%rsi,1),%rsi
  mov    %r12,%rdi
  cmp    %edx,%eax
  cmovle %eax,%edx
  mov    %edx,%ebp
  call   <memcpy@plt>
  movslq %ebp,%rdx
  movzbl (%r15),%eax
  movb   $0x0,0x27(%rsp,%rdx,1)
  jmp    L71
  nop
L82:
  mov    0x18(%rsp),%r9d
  mov    0x14(%rsp),%r8d
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    0x8(%rsp),%rdx
  lea    D14(%rip),%rsi
  mov    $0x5,%edi
  lea    0x1(%r13),%r15d
  call   <lprintf@plt>
  cmp    0x1c(%rsp),%r15d
  jl     L16
  jmp    L81
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D14
type_infered: string

tool: D2: INP Route Information Frame:


tool: D14:         %12s  %-6s   %6u %6u


assistant: ```c
void netrom_inp_dump(unsigned char *data, int length) {
  char node[10];
  char alias[7];
  int hops;
  int tt;
  int alen;
  int i;
  if (data[0] == 0xff) {
    lprintf(7, "INP Route Information Frame:\n");
    i = 1;
    while (i < length - 10) {
      pax25(node, data + i);
      i += 7;
      hops = data[i++];
      tt = data[i++] * 256;
      tt += data[i++];
      alias[0] = 0;
      while (i < length - data[i] && data[i]) {
        if (data[i + 1] == 0x00) {
          alen = data[i] - 2;
          alen = alen < 7 ? alen : 6;
          memcpy(alias, data + i + 2, alen);
          alias[alen] = 0;
        }
        i += data[i];
      }
      i++;
      lprintf(5, "        %12s  %-6s   %6u %6u\n", node, alias, hops, tt);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D26
type: string
name: unpack_data
arguments: tag: D20
type: string

tool: D10: Enter two LONG numbers:

tool: D26: %ld %ld

tool: D20: The result is: %ld

assistant: ```c
main() {
  long int a, b, c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  c = a * b;
  printf("The result is: %ld", c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  imul   0x10(%rsp),%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string

tool: D26: Enter two LONG numbers:

tool: D29: %ld %ld

tool: D14: The result is: %ld

assistant: ```c
main() {
  long int a, b, c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  c = a * b;
  printf("The result is: %ld", c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D29(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  imul   0x10(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type_guessed: string
name: unpack_data
arguments: data_tag: D21
type_guessed: string
name: unpack_data
arguments: data_tag: D4
type_guessed: string

tool: D29: Enter two LONG numbers:

tool: D21: %ld %ld

tool: D4: The result is: %ld

assistant: ```c
main() {
  long int a, b, c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  c = a * b;
  printf("The result is: %ld", c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  xor    %eax,%eax
  imul   0x10(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D29
type: string

tool: D22: Enter two LONG numbers:

tool: D25: %ld %ld

tool: D29: The result is: %ld

assistant: ```c
main() {
  long int a, b, c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  c = a * b;
  printf("The result is: %ld", c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x30303031,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <strindex@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string
name: disassemble_data
arguments: label: D34
type_guessed: string

tool: D0: %d

tool: D19: GEHO

tool: D34: HOGEHOGE

assistant: ```c
main() {
  int atoi(char *);
  char s[] = "1000";
  printf("%d", atoi(s));
  printf("%d", strindex("HOGEHOGE", "GEHO"));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x30303031,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x3(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rsi
  lea    D1(%rip),%rdi
  call   <strindex@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D1
type_infered: string

tool: D27: %d

tool: D13: GEHO

tool: D1: HOGEHOGE

assistant: ```c
main() {
  int atoi(char *);
  char s[] = "1000";
  printf("%d", atoi(s));
  printf("%d", strindex("HOGEHOGE", "GEHO"));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  movl   $0x30303031,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D12(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <strindex@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string
name: extract_symbolic_data
arguments: data_label: D15
type: string

tool: D3: %d

tool: D12: GEHO

tool: D15: HOGEHOGE

assistant: ```c
main() {
  int atoi(char *);
  char s[] = "1000";
  printf("%d", atoi(s));
  printf("%d", strindex("HOGEHOGE", "GEHO"));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rdi
  movl   $0x30303031,0x3(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D14(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <strindex@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D23
type_infered: string

tool: D2: %d

tool: D14: GEHO

tool: D23: HOGEHOGE

assistant: ```c
main() {
  int atoi(char *);
  char s[] = "1000";
  printf("%d", atoi(s));
  printf("%d", strindex("HOGEHOGE", "GEHO"));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quatgetconjugate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  D4(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  D4(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  D4(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quatgetconjugate(float *qout, const float *qin) {
  qout[0] = qin[0];
  qout[1] = -qin[1];
  qout[2] = -qin[2];
  qout[3] = -qin[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quatgetconjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  D7(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quatgetconjugate(float *qout, const float *qin) {
  qout[0] = qin[0];
  qout[1] = -qin[1];
  qout[2] = -qin[2];
  qout[3] = -qin[3];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quatgetconjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D9(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quatgetconjugate(float *qout, const float *qin) {
  qout[0] = qin[0];
  qout[1] = -qin[1];
  qout[2] = -qin[2];
  qout[3] = -qin[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<quatgetconjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D3(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x80]}

assistant: ```c
void quatgetconjugate(float *qout, const float *qin) {
  qout[0] = qin[0];
  qout[1] = -qin[1];
  qout[2] = -qin[2];
  qout[3] = -qin[3];
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    $0x0,%eax
  call   <stackInit@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <push@plt>
  jmp    L97
L0:
  call   <swap@plt>
  add    $0x1,%ebp
  sub    $0x1,%ebx
  jmp    L46
L167:
  mov    %ebx,%edx
  sub    %r14d,%edx
  mov    %r15d,%eax
  sub    %ebp,%eax
  cmp    %eax,%edx
  jle    L65
  cmp    %r14d,%ebx
  jg     L20
L21:
  cmp    %r15d,%ebp
  jl     L70
L97:
  mov    $0x0,%eax
  call   <isEmpty@plt>
  test   %eax,%eax
  jne    L176
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%r15d
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%r14d
  lea    (%r15,%rax,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    0x0(%r13,%rax,4),%r12d
  mov    %r15d,%ebx
  mov    %r14d,%ebp
  jmp    L46
L20:
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <push@plt>
  jmp    L21
L70:
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <push@plt>
  jmp    L97
L65:
  cmp    %r15d,%ebp
  jl     L127
L76:
  cmp    %r14d,%ebx
  jle    L97
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <push@plt>
  jmp    L97
L127:
  mov    %r15d,%esi
  mov    %ebp,%edi
  call   <push@plt>
  jmp    L76
L38:
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmp    (%rsi),%r12d
  jge    L0
L146:
  movslq %ebx,%rax
  lea    -0x4(%r13,%rax,4),%rax
L184:
  sub    $0x1,%ebx
  mov    %rax,%rsi
  sub    $0x4,%rax
  cmp    %r12d,0x4(%rax)
  jg     L184
L126:
  cmp    %ebp,%ebx
  jge    L0
L46:
  cmp    %ebx,%ebp
  jg     L167
  movslq %ebp,%rax
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rdi
  lea    0x4(%r13,%rax,1),%rax
  cmp    (%rdi),%r12d
  jle    L38
L25:
  add    $0x1,%ebp
  mov    %rax,%rdi
  add    $0x4,%rax
  cmp    %r12d,-0x4(%rax)
  jl     L25
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rsi
  cmp    (%rsi),%r12d
  jl     L146
  jmp    L126
L176:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(int *a, int l, int r) {
  stackInit();
  int i, j, v;
  int l0, r0;
  push(l, r);
  while (!isEmpty()) {
    r0 = j = pop();
    l0 = i = pop();
    v = a[(i + j) / 2];
    while (i <= j) {
      while (a[i] < v)
        i++;
      while (a[j] > v)
        j--;
      if (i <= j) {
        swap(a + i, a + j);
        i++;
        j--;
      }
    }
    if (j - l0 > r0 - i) {
      if (j > l0)
        push(l0, j);
      if (i < r0)
        push(i, r0);
    } else {
      if (i < r0)
        push(i, r0);
      if (j > l0)
        push(l0, j);
    }
  }
}
```