ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Hn>:
  endbr64
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm4
  mov    $0x1,%eax
  movsd  D5(%rip),%xmm3
  addsd  %xmm0,%xmm2
  jmp    L0
  nop
L14:
  movapd %xmm0,%xmm2
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm4,%xmm0
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm2,%xmm0
  add    $0x1,%eax
  mulsd  %xmm3,%xmm1
  movapd %xmm2,%xmm3
  subsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm0
  cmp    $0x64,%eax
  jne    L14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: f64

tool: D5: 1

assistant: ```c
double Hn(double x, int n) {
  double h[2] = {1, 2 * x};
  for (int k = 1; k < 100; k++) {
    double newvalue = 2 * (x * h[1] - k * h[0]);
    h[0] = h[1];
    h[1] = newvalue;
  }
  return h[1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ri_mem_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L8
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int ri_mem_free(void *ptr) {
  if (ptr == NULL) {
    return -1;
  }
  free(ptr);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ri_mem_free>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ri_mem_free(void *ptr) {
  if (ptr == NULL) {
    return -1;
  }
  free(ptr);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ri_mem_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ri_mem_free(void *ptr) {
  if (ptr == NULL) {
    return -1;
  }
  free(ptr);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ri_mem_free>:
  endbr64
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ri_mem_free(void *ptr) {
  if (ptr == NULL) {
    return -1;
  }
  free(ptr);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sInsert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x34(%rbp)
  jle    L1
  mov    -0x28(%rbp),%rax
  jmp    L8
L1:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x34(%rbp),%eax
  lea    0x1(%rax),%r12d
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x34(%rbp),%eax
  movslq %eax,%r13
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    0x0(%r13,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
L8:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *sInsert(char *d, const char *s, int p, int n) {
  if (p > strlen(d))
    return d;
  memmove(d + p + strlen(s), d + p, strlen(d) - p + 1);
  strncpy(d + p, s, strlen(s));
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sInsert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  call   <strlen@plt>
  cmp    %ebp,%eax
  jge    L0
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  movslq %ebp,%r14
  lea    (%rbx,%r14,1),%r13
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %ebp,%r15d
  lea    0x1(%r15),%edx
  movslq %eax,%rdi
  add    %r14,%rdi
  add    %rbx,%rdi
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  jmp    L1
```

assistant: ```c
char *sInsert(char *d, const char *s, int p, int n) {
  if (p > strlen(d))
    return d;
  memmove(d + p + strlen(s), d + p, strlen(d) - p + 1);
  strncpy(d + p, s, strlen(s));
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sInsert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L7
  mov    %r12,%rdi
  movslq %ebx,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    (%r12,%r15,1),%r14
  mov    %eax,%r13d
  call   <strlen@plt>
  sub    %ebx,%r13d
  mov    %r14,%rsi
  movslq %eax,%rdi
  lea    0x1(%r13),%edx
  add    %r15,%rdi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sInsert(char *d, const char *s, int p, int n) {
  if (p > strlen(d))
    return d;
  memmove(d + p + strlen(s), d + p, strlen(d) - p + 1);
  strncpy(d + p, s, strlen(s));
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sInsert>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L8
  mov    %r12,%rdi
  movslq %ebx,%r15
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    (%r12,%r15,1),%r14
  mov    %eax,%r13d
  call   <strlen@plt>
  sub    %ebx,%r13d
  mov    %r14,%rsi
  movslq %eax,%rdi
  lea    0x1(%r13),%edx
  add    %r15,%rdi
  add    %r12,%rdi
  call   <memmove@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %eax,%edx
  call   <strncpy@plt>
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *sInsert(char *d, const char *s, int p, int n) {
  if (p > strlen(d))
    return d;
  memmove(d + p + strlen(s), d + p, strlen(d) - p + 1);
  strncpy(d + p, s, strlen(s));
  return d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generateTrees>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L18
L1:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <generate@plt>
L18:
  leave
  ret
```

assistant: ```c
struct TreeNode **generateTrees(int n, int *returnSize) {
  *returnSize = 0;
  if (!n)
    return NULL;
  return generate(1, n, returnSize);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<generateTrees>:
  endbr64
  movl   $0x0,(%rsi)
  mov    $0x0,%eax
  test   %edi,%edi
  je     L4
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <generate@plt>
  add    $0x8,%rsp
  ret
L4:
  ret
```

assistant: ```c
struct TreeNode **generateTrees(int n, int *returnSize) {
  *returnSize = 0;
  if (!n)
    return NULL;
  return generate(1, n, returnSize);
}
```
user: Translate the below assembly code into C programming language:

```asm
<generateTrees>:
  endbr64
  movl   $0x0,(%rsi)
  mov    %rsi,%rdx
  test   %edi,%edi
  je     L0
  mov    %edi,%esi
  mov    $0x1,%edi
  jmp    1050 <generate@plt>
  nopl   (%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct TreeNode **generateTrees(int n, int *returnSize) {
  *returnSize = 0;
  if (!n)
    return NULL;
  return generate(1, n, returnSize);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<generateTrees>:
  endbr64
  movl   $0x0,(%rsi)
  mov    %rsi,%rdx
  test   %edi,%edi
  je     L1
  mov    %edi,%esi
  mov    $0x1,%edi
  jmp    1050 <generate@plt>
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct TreeNode **generateTrees(int n, int *returnSize) {
  *returnSize = 0;
  if (!n)
    return NULL;
  return generate(1, n, returnSize);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <someUserFunction@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    $0x2,%edi
  call   <setuid@plt>
  mov    $0x14,%edi
  call   <system@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L25
L7:
  cmpl   $0x1,-0x4(%rbp)
  jne    L25
  mov    $0x28,%edi
  call   <system@plt>
L25:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i = someUserFunction();
  if (i == 0) {
    setuid(2);
    i = system(20);
  } else if (i == 1) {
    system(40);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <someUserFunction@plt>
  test   %eax,%eax
  je     L14
  cmp    $0x1,%eax
  je     L5
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L14:
  mov    $0x2,%edi
  call   <setuid@plt>
  mov    $0x14,%edi
  call   <system@plt>
  jmp    L32
L5:
  mov    $0x28,%edi
  call   <system@plt>
  jmp    L32
```

assistant: ```c
main() {
  int i = someUserFunction();
  if (i == 0) {
    setuid(2);
    i = system(20);
  } else if (i == 1) {
    system(40);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <someUserFunction@plt>
  test   %eax,%eax
  je     L0
  cmp    $0x1,%eax
  je     L7
L34:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    $0x2,%edi
  call   <setuid@plt>
  mov    $0x14,%edi
  call   <system@plt>
  jmp    L34
L7:
  mov    $0x28,%edi
  call   <system@plt>
  jmp    L34
```

assistant: ```c
main() {
  int i = someUserFunction();
  if (i == 0) {
    setuid(2);
    i = system(20);
  } else if (i == 1) {
    system(40);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <someUserFunction@plt>
  test   %eax,%eax
  je     L28
  cmp    $0x1,%eax
  je     L36
L17:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L28:
  mov    $0x2,%edi
  call   <setuid@plt>
  mov    $0x14,%edi
  call   <system@plt>
  jmp    L17
L36:
  mov    $0x28,%edi
  call   <system@plt>
  jmp    L17
```

assistant: ```c
main() {
  int i = someUserFunction();
  if (i == 0) {
    setuid(2);
    i = system(20);
  } else if (i == 1) {
    system(40);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x9,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <selecao@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <imprimeVetor@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int v[5] = {8, 4, 6, 9, 1};
  selecao(v, 5);
  imprimeVetor(v, 5);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <selecao@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <imprimeVetor@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int v[5] = {8, 4, 6, 9, 1};
  selecao(v, 5);
  imprimeVetor(v, 5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000008,%rax
  mov    %rsp,%rbp
  movl   $0x1,0x10(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x900000006,%rax
  mov    %rax,0x8(%rsp)
  call   <selecao@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <imprimeVetor@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int v[5] = {8, 4, 6, 9, 1};
  selecao(v, 5);
  imprimeVetor(v, 5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x5,%esi
  sub    $0x20,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x1,0x10(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  call   <selecao@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <imprimeVetor@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: byte[16]

tool: {"D3": [0x08,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int v[5] = {8, 4, 6, 9, 1};
  selecao(v, 5);
  imprimeVetor(v, 5);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dilatation_lc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dilatation_ligne@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L19:
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L34:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x0(,%rax,8),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  lea    0x0(,%rdx,8),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L37:
  cmpl   $0x7,-0xc(%rbp)
  jle    L34
  addl   $0x1,-0x10(%rbp)
L10:
  cmpl   $0x7,-0x10(%rbp)
  jle    L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint8_t *dilatation_lc(uint8_t *bloc, uint8_t *out) {
  uint8_t *temp = malloc(32 * sizeof(uint8_t));
  temp = dilatation_ligne(bloc, temp);
  for (uint8_t i = 0; i < 8; i++) {
    for (uint8_t j = 0; j < 8; j++) {
      out[j + 8 * i] = temp[i / 2 * 8 + j];
    }
  }
  free(temp);
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dilatation_lc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dilatation_ligne@plt>
  mov    %rbx,%rsi
  mov    $0x0,%r8d
L7:
  mov    %r8d,%edx
  shr    $0x1f,%edx
  add    %r8d,%edx
  sar    %edx
  shl    $0x3,%edx
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rdi
  mov    $0x0,%edx
L16:
  mov    (%rdi,%rdx,1),%ecx
  mov    %ecx,(%rsi,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x20,%rdx
  jne    L16
  add    $0x1,%r8d
  add    $0x20,%rsi
  cmp    $0x8,%r8d
  jne    L7
  mov    %rax,%rdi
  call   <free@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *dilatation_lc(uint8_t *bloc, uint8_t *out) {
  uint8_t *temp = malloc(32 * sizeof(uint8_t));
  temp = dilatation_ligne(bloc, temp);
  for (uint8_t i = 0; i < 8; i++) {
    for (uint8_t j = 0; j < 8; j++) {
      out[j + 8 * i] = temp[i / 2 * 8 + j];
    }
  }
  free(temp);
  return out;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dilatation_lc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <dilatation_ligne@plt>
  mov    %r12,%rsi
  xor    %r8d,%r8d
  mov    %rax,%r9
  nop
L9:
  mov    %r8d,%edx
  sar    %edx
  shl    $0x3,%edx
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rdi
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  mov    (%rdi,%rdx,1),%ecx
  mov    %ecx,(%rsi,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x20,%rdx
  jne    L0
  add    $0x1,%r8d
  add    $0x20,%rsi
  cmp    $0x8,%r8d
  jne    L9
  mov    %r9,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint8_t *dilatation_lc(uint8_t *bloc, uint8_t *out) {
  uint8_t *temp = malloc(32 * sizeof(uint8_t));
  temp = dilatation_ligne(bloc, temp);
  for (uint8_t i = 0; i < 8; i++) {
    for (uint8_t j = 0; j < 8; j++) {
      out[j + 8 * i] = temp[i / 2 * 8 + j];
    }
  }
  free(temp);
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dilatation_lc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x80,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <dilatation_ligne@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  mov    %r12,%rax
  xchg   %ax,%ax
L3:
  mov    %esi,%edx
  add    $0x1,%esi
  add    $0x20,%rax
  sar    %edx
  shl    $0x3,%edx
  movslq %edx,%rcx
  add    $0x1,%edx
  mov    (%rdi,%rcx,4),%ecx
  movslq %edx,%rdx
  mov    %ecx,-0x20(%rax)
  lea    0x0(,%rdx,4),%rcx
  mov    (%rdi,%rdx,4),%edx
  mov    %edx,-0x1c(%rax)
  mov    0x4(%rdi,%rcx,1),%edx
  mov    %edx,-0x18(%rax)
  mov    0x8(%rdi,%rcx,1),%edx
  mov    %edx,-0x14(%rax)
  mov    0xc(%rdi,%rcx,1),%edx
  mov    %edx,-0x10(%rax)
  mov    0x10(%rdi,%rcx,1),%edx
  mov    %edx,-0xc(%rax)
  mov    0x14(%rdi,%rcx,1),%edx
  mov    %edx,-0x8(%rax)
  mov    0x18(%rdi,%rcx,1),%edx
  mov    %edx,-0x4(%rax)
  cmp    $0x8,%esi
  jne    L3
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint8_t *dilatation_lc(uint8_t *bloc, uint8_t *out) {
  uint8_t *temp = malloc(32 * sizeof(uint8_t));
  temp = dilatation_ligne(bloc, temp);
  for (uint8_t i = 0; i < 8; i++) {
    for (uint8_t j = 0; j < 8; j++) {
      out[j + 8 * i] = temp[i / 2 * 8 + j];
    }
  }
  free(temp);
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jle    L17
  addl   $0x1,-0x10(%rbp)
  jmp    L15
L17:
  mov    -0x28(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L15
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jle    L23
  addl   $0x1,-0x10(%rbp)
  jmp    L95
L23:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L95
  addl   $0x1,-0xc(%rbp)
L95:
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L65
  addl   $0x1,-0x10(%rbp)
  jmp    L61
L65:
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L61
  addl   $0x1,-0xc(%rbp)
L61:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D6: %d %d %d

tool: D8: %d %d

assistant: ```c
int main() {
  int a0;
  int a1;
  int a2;
  scanf("%d %d %d", &a0, &a1, &a2);
  int b0;
  int b1;
  int b2;
  scanf("%d %d %d", &b0, &b1, &b2);
  int score_a = 0;
  int score_b = 0;
  if (a0 > b0) {
    score_a++;
  } else if (a0 < b0) {
    score_b++;
  }
  if (a1 > b1) {
    score_a++;
  } else if (a1 < b1) {
    score_b++;
  }
  if (a2 > b2) {
    score_a++;
  } else if (a2 < b2) {
    score_b++;
  }
  printf("%d %d", score_a, score_b);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  jg     L75
  setl   %dl
  movzbl %dl,%edx
  mov    $0x0,%esi
L17:
  mov    0x4(%rsp),%ecx
  mov    0x10(%rsp),%eax
  cmp    %eax,%ecx
  jle    L11
  add    $0x1,%esi
L37:
  mov    0x8(%rsp),%ecx
  mov    0x14(%rsp),%eax
  cmp    %eax,%ecx
  jle    L16
  add    $0x1,%esi
L20:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L75:
  mov    $0x0,%edx
  mov    $0x1,%esi
  jmp    L17
L11:
  jge    L37
  add    $0x1,%edx
  jmp    L37
L16:
  jge    L20
  add    $0x1,%edx
  jmp    L20
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D8
datatype: string

tool: D6: %d %d %d

tool: D8: %d %d

assistant: ```c
int main() {
  int a0;
  int a1;
  int a2;
  scanf("%d %d %d", &a0, &a1, &a2);
  int b0;
  int b1;
  int b2;
  scanf("%d %d %d", &b0, &b1, &b2);
  int score_a = 0;
  int score_b = 0;
  if (a0 > b0) {
    score_a++;
  } else if (a0 < b0) {
    score_b++;
  }
  if (a1 > b1) {
    score_a++;
  } else if (a1 < b1) {
    score_b++;
  }
  if (a2 > b2) {
    score_a++;
  } else if (a2 < b2) {
    score_b++;
  }
  printf("%d %d", score_a, score_b);
  return 0;
}
```