ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_id>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  je     L39
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  sar    $0x6,%edx
  and    $0x3,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,%edx
  and    $0x1f,%eax
  shr    $0x5,%edx
  and    $0x1,%edx
  mov    %edx,(%rbx)
  cmp    $0x1f,%eax
  je     L28
  cltq
  mov    %rax,(%r14)
  mov    $0x1,%eax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L82:
  mov    0x4(%rsp),%edx
  shl    $0x7,%rbx
  add    $0x1,%rbp
  mov    %edx,%eax
  and    $0x7f,%al
  cltq
  or     %rax,%rbx
  and    $0x80,%edx
  je     L20
L32:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  jne    L82
L39:
  mov    $0xffffffff,%eax
  jmp    L35
  nopl   0x0(%rax)
L20:
  cmp    $0x8,%rbp
  ja     L11
  mov    %rbx,(%r14)
  lea    0x1(%rbp),%eax
  jmp    L35
L11:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  jmp    L39
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_id(struct ber *b, unsigned long *tag, int *class, int *cstruct) {
  u_char u;
  size_t i = 0;
  unsigned long t = 0;
  if (ber_getc(b, &u) == -1)
    return -1;
  *class = (u >> 6) & 0x3;
  *cstruct = (u & 0x20) == 0x20;
  if ((u & 0x1f) != 0x1f) {
    *tag = u & 0x1f;
    return 1;
  }
  do {
    if (ber_getc(b, &u) == -1)
      return -1;
    t = (t << 7) | (u & ~0x80);
    i++;
  } while (u & 0x80);
  if (i > sizeof(unsigned long)) {
    errno = ERANGE;
    return -1;
  }
  *tag = t;
  return i + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_id>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  je     L50
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  sar    $0x6,%edx
  and    $0x3,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,%edx
  and    $0x1f,%eax
  shr    $0x5,%edx
  and    $0x1,%edx
  mov    %edx,(%rbx)
  cmp    $0x1f,%eax
  je     L10
  cltq
  mov    %rax,(%r14)
  mov    $0x1,%eax
L47:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  jmp    L80
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    0x4(%rsp),%edx
  shl    $0x7,%rbx
  add    $0x1,%rbp
  mov    %edx,%eax
  and    $0x7f,%al
  cltq
  or     %rax,%rbx
  and    $0x80,%edx
  je     L44
L80:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  jne    L19
L50:
  mov    $0xffffffff,%eax
  jmp    L47
  nopl   0x0(%rax)
L44:
  cmp    $0x8,%rbp
  ja     L77
  mov    %rbx,(%r14)
  lea    0x1(%rbp),%eax
  jmp    L47
L77:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  jmp    L50
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_id(struct ber *b, unsigned long *tag, int *class, int *cstruct) {
  u_char u;
  size_t i = 0;
  unsigned long t = 0;
  if (ber_getc(b, &u) == -1)
    return -1;
  *class = (u >> 6) & 0x3;
  *cstruct = (u & 0x20) == 0x20;
  if ((u & 0x1f) != 0x1f) {
    *tag = u & 0x1f;
    return 1;
  }
  do {
    if (ber_getc(b, &u) == -1)
      return -1;
    t = (t << 7) | (u & ~0x80);
    i++;
  } while (u & 0x80);
  if (i > sizeof(unsigned long)) {
    errno = ERANGE;
    return -1;
  }
  *tag = t;
  return i + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x18,-0xc(%rbp)
  movl   $0x2d,-0x8(%rbp)
  movl   $0xffffff0f,-0x4(%rbp)
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0xffffff0e,-0x4(%rbp)
  setl   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x18,-0xc(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  int a, b, c;
  a = 24;
  b = 45;
  c = -241;
  printf("%d\n", 2 < 3);
  printf("%d\n", 2 < 2);
  printf("%d\n", a < b);
  printf("%d\n", b < a);
  printf("%d\n", c < a);
  printf("%d\n", c < b);
  printf("%d\n", b < c);
  printf("%d\n", a < c);
  printf("%d\n", c < -242);
  printf("%d\n", a < 25);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  int a, b, c;
  a = 24;
  b = 45;
  c = -241;
  printf("%d\n", 2 < 3);
  printf("%d\n", 2 < 2);
  printf("%d\n", a < b);
  printf("%d\n", b < a);
  printf("%d\n", c < a);
  printf("%d\n", c < b);
  printf("%d\n", b < c);
  printf("%d\n", a < c);
  printf("%d\n", c < -242);
  printf("%d\n", a < 25);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main() {
  int a, b, c;
  a = 24;
  b = 45;
  c = -241;
  printf("%d\n", 2 < 3);
  printf("%d\n", 2 < 2);
  printf("%d\n", a < b);
  printf("%d\n", b < a);
  printf("%d\n", c < a);
  printf("%d\n", c < b);
  printf("%d\n", b < c);
  printf("%d\n", a < c);
  printf("%d\n", c < -242);
  printf("%d\n", a < 25);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int a, b, c;
  a = 24;
  b = 45;
  c = -241;
  printf("%d\n", 2 < 3);
  printf("%d\n", 2 < 2);
  printf("%d\n", a < b);
  printf("%d\n", b < a);
  printf("%d\n", c < a);
  printf("%d\n", c < b);
  printf("%d\n", b < c);
  printf("%d\n", a < c);
  printf("%d\n", c < -242);
  printf("%d\n", a < 25);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EVP_CIPHER_CTX_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_CIPHER_CTX_cleanup@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void EVP_CIPHER_CTX_free(EVP_CIPHER_CTX *ctx) {
  if (ctx) {
    EVP_CIPHER_CTX_cleanup(ctx);
    free(ctx);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EVP_CIPHER_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  call   <EVP_CIPHER_CTX_cleanup@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void EVP_CIPHER_CTX_free(EVP_CIPHER_CTX *ctx) {
  if (ctx) {
    EVP_CIPHER_CTX_cleanup(ctx);
    free(ctx);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<EVP_CIPHER_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L7
  push   %rbp
  mov    %rdi,%rbp
  call   <EVP_CIPHER_CTX_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void EVP_CIPHER_CTX_free(EVP_CIPHER_CTX *ctx) {
  if (ctx) {
    EVP_CIPHER_CTX_cleanup(ctx);
    free(ctx);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<EVP_CIPHER_CTX_free>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbp
  mov    %rdi,%rbp
  call   <EVP_CIPHER_CTX_cleanup@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void EVP_CIPHER_CTX_free(EVP_CIPHER_CTX *ctx) {
  if (ctx) {
    EVP_CIPHER_CTX_cleanup(ctx);
    free(ctx);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tmpnam_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L57
L53:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <___path_search@plt>
  test   %rax,%rax
  je     L33
  mov    $0x0,%eax
  jmp    L57
L33:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <__gen_tempname@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  jmp    L57
L11:
  mov    -0x8(%rbp),%rax
L57:
  leave
  ret
```

assistant: ```c
char *tmpnam_r(char *s) {
  if (s == NULL)
    return NULL;
  if (___path_search(s, L_tmpnam, NULL, NULL))
    return NULL;
  if (__gen_tempname(s, 3, 0, 0, 0))
    return NULL;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tmpnam_r>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L14
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <___path_search@plt>
  test   %rax,%rax
  jne    L25
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <__gen_tempname@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%rbx
L14:
  mov    %rbx,%rax
  pop    %rbx
  ret
L25:
  mov    $0x0,%ebx
  jmp    L14
```

assistant: ```c
char *tmpnam_r(char *s) {
  if (s == NULL)
    return NULL;
  if (___path_search(s, L_tmpnam, NULL, NULL))
    return NULL;
  if (__gen_tempname(s, 3, 0, 0, 0))
    return NULL;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tmpnam_r>:
  endbr64
  test   %rdi,%rdi
  je     L12
  mov    D9(%rip),%rax
  push   %rbx
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rdi,%rbx
  mov    (%rax),%esi
  call   <___path_search@plt>
  test   %rax,%rax
  jne    L20
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <__gen_tempname@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L20
  pop    %rbx
  ret
  nopl   (%rax)
L20:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *tmpnam_r(char *s) {
  if (s == NULL)
    return NULL;
  if (___path_search(s, L_tmpnam, NULL, NULL))
    return NULL;
  if (__gen_tempname(s, 3, 0, 0, 0))
    return NULL;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tmpnam_r>:
  endbr64
  test   %rdi,%rdi
  je     L10
  mov    D2(%rip),%rax
  push   %rbx
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rdi,%rbx
  mov    (%rax),%esi
  call   <___path_search@plt>
  test   %rax,%rax
  jne    L18
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <__gen_tempname@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  jne    L18
  pop    %rbx
  ret
  nopl   (%rax)
L18:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *tmpnam_r(char *s) {
  if (s == NULL)
    return NULL;
  if (___path_search(s, L_tmpnam, NULL, NULL))
    return NULL;
  if (__gen_tempname(s, 3, 0, 0, 0))
    return NULL;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<add_quats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vcopy@plt>
  mov    -0x60(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  lea    -0x50(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <vscale@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vcopy@plt>
  mov    -0x58(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  lea    -0x40(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <vscale@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  mov    -0x60(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vcross@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x40(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vadd@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vadd@plt>
  mov    -0x58(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm1
  mov    -0x60(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  movss  %xmm1,-0x6c(%rbp)
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vdot@plt>
  movaps %xmm0,%xmm1
  movss  -0x6c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x20(%rbp),%xmm0
  mov    -0x68(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x68(%rbp),%rax
  add    $0x4,%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x68(%rbp),%rax
  add    $0x8,%rax
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x68(%rbp),%rax
  add    $0xc,%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    D16(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D31(%rip)
  mov    D31(%rip),%eax
  cmp    $0x61,%eax
  jle    L5
  movl   $0x0,D31(%rip)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <normalize_quat@plt>
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void add_quats(const float q1[4], const float q2[4], float dest[4]) {
  static int count = 0;
  float t1[4], t2[4], t3[4];
  float tf[4];
  vcopy(q1, t1);
  vscale(t1, q2[3]);
  vcopy(q2, t2);
  vscale(t2, q1[3]);
  vcross(q2, q1, t3);
  vadd(t1, t2, tf);
  vadd(t3, tf, tf);
  tf[3] = q1[3] * q2[3] - vdot(q1, q2);
  dest[0] = tf[0];
  dest[1] = tf[1];
  dest[2] = tf[2];
  dest[3] = tf[3];
  if (++count > 97) {
    count = 0;
    normalize_quat(dest);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<add_quats>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  call   <vcopy@plt>
  movss  0xc(%rbp),%xmm0
  mov    %r14,%rdi
  call   <vscale@plt>
  lea    0x20(%rsp),%r15
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <vcopy@plt>
  movss  0xc(%rbx),%xmm0
  mov    %r15,%rdi
  call   <vscale@plt>
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vcross@plt>
  lea    0x40(%rsp),%r13
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <vadd@plt>
  mov    %r13,%rdx
  mov    %r13,%rsi
  mov    0x8(%rsp),%rdi
  call   <vadd@plt>
  movss  0xc(%rbx),%xmm0
  mulss  0xc(%rbp),%xmm0
  movd   %xmm0,%r13d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vdot@plt>
  movaps %xmm0,%xmm1
  movd   %r13d,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4c(%rsp)
  movss  0x40(%rsp),%xmm1
  movss  %xmm1,(%r12)
  movss  0x44(%rsp),%xmm1
  movss  %xmm1,0x4(%r12)
  movss  0x48(%rsp),%xmm1
  movss  %xmm1,0x8(%r12)
  movss  %xmm0,0xc(%r12)
  mov    D8(%rip),%eax
  add    $0x1,%eax
  cmp    $0x61,%eax
  jg     L4
  mov    %eax,D23(%rip)
L11:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  movl   $0x0,D23(%rip)
  mov    %r12,%rdi
  call   <normalize_quat@plt>
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_quats(const float q1[4], const float q2[4], float dest[4]) {
  static int count = 0;
  float t1[4], t2[4], t3[4];
  float tf[4];
  vcopy(q1, t1);
  vscale(t1, q2[3]);
  vcopy(q2, t2);
  vscale(t2, q1[3]);
  vcross(q2, q1, t3);
  vadd(t1, t2, tf);
  vadd(t3, tf, tf);
  tf[3] = q1[3] * q2[3] - vdot(q1, q2);
  dest[0] = tf[0];
  dest[1] = tf[1];
  dest[2] = tf[2];
  dest[3] = tf[3];
  if (++count > 97) {
    count = 0;
    normalize_quat(dest);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_quats>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  lea    0x20(%rsp),%rbx
  mov    %r15,%rsi
  lea    0x40(%rsp),%r14
  call   <vcopy@plt>
  movss  0xc(%r12),%xmm0
  mov    %r15,%rdi
  call   <vscale@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vcopy@plt>
  movss  0xc(%rbp),%xmm0
  mov    %rbx,%rdi
  call   <vscale@plt>
  lea    0x30(%rsp),%r8
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %r8,%rdx
  mov    %r8,0x8(%rsp)
  call   <vcross@plt>
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <vadd@plt>
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  mov    %r14,%rsi
  call   <vadd@plt>
  movss  0xc(%rbp),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  0xc(%r12),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <vdot@plt>
  mov    0x40(%rsp),%rax
  movss  0x8(%rsp),%xmm1
  mov    %rax,0x0(%r13)
  subss  %xmm0,%xmm1
  mov    D11(%rip),%eax
  movss  0x48(%rsp),%xmm0
  add    $0x1,%eax
  movss  %xmm1,0x4c(%rsp)
  movss  %xmm0,0x8(%r13)
  movss  %xmm1,0xc(%r13)
  cmp    $0x61,%eax
  jg     L24
  mov    %eax,D22(%rip)
L18:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L24:
  movl   $0x0,D22(%rip)
  mov    %r13,%rdi
  call   <normalize_quat@plt>
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_quats(const float q1[4], const float q2[4], float dest[4]) {
  static int count = 0;
  float t1[4], t2[4], t3[4];
  float tf[4];
  vcopy(q1, t1);
  vscale(t1, q2[3]);
  vcopy(q2, t2);
  vscale(t2, q1[3]);
  vcross(q2, q1, t3);
  vadd(t1, t2, tf);
  vadd(t3, tf, tf);
  tf[3] = q1[3] * q2[3] - vdot(q1, q2);
  dest[0] = tf[0];
  dest[1] = tf[1];
  dest[2] = tf[2];
  dest[3] = tf[3];
  if (++count > 97) {
    count = 0;
    normalize_quat(dest);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add_quats>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  lea    0x20(%rsp),%rbx
  mov    %r15,%rsi
  lea    0x40(%rsp),%r14
  call   <vcopy@plt>
  movss  0xc(%r12),%xmm0
  mov    %r15,%rdi
  call   <vscale@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vcopy@plt>
  movss  0xc(%rbp),%xmm0
  mov    %rbx,%rdi
  call   <vscale@plt>
  lea    0x30(%rsp),%r8
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %r8,%rdx
  mov    %r8,0x8(%rsp)
  call   <vcross@plt>
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <vadd@plt>
  mov    0x8(%rsp),%rdi
  mov    %r14,%rdx
  mov    %r14,%rsi
  call   <vadd@plt>
  movss  0xc(%rbp),%xmm0
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  0xc(%r12),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  call   <vdot@plt>
  movss  0x8(%rsp),%xmm1
  movss  0x44(%rsp),%xmm2
  mov    D4(%rip),%eax
  subss  %xmm0,%xmm1
  add    $0x1,%eax
  movaps %xmm1,%xmm0
  movss  %xmm1,0x4c(%rsp)
  movss  0x48(%rsp),%xmm1
  unpcklps %xmm0,%xmm1
  movss  0x40(%rsp),%xmm0
  unpcklps %xmm2,%xmm0
  movlhps %xmm1,%xmm0
  movups %xmm0,0x0(%r13)
  cmp    $0x61,%eax
  jg     L8
  mov    %eax,D21(%rip)
L15:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  movl   $0x0,D21(%rip)
  mov    %r13,%rdi
  call   <normalize_quat@plt>
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_quats(const float q1[4], const float q2[4], float dest[4]) {
  static int count = 0;
  float t1[4], t2[4], t3[4];
  float tf[4];
  vcopy(q1, t1);
  vscale(t1, q2[3]);
  vcopy(q2, t2);
  vscale(t2, q1[3]);
  vcross(q2, q1, t3);
  vadd(t1, t2, tf);
  vadd(t3, tf, tf);
  tf[3] = q1[3] * q2[3] - vdot(q1, q2);
  dest[0] = tf[0];
  dest[1] = tf[1];
  dest[2] = tf[2];
  dest[3] = tf[3];
  if (++count > 97) {
    count = 0;
    normalize_quat(dest);
  }
}
```