ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<superPow>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%edx
  js     L16
  mov    %edi,%ebp
  mov    %rsi,%r13
  movslq %edx,%rbx
  mov    $0x1,%r12d
  nopl   0x0(%rax)
L14:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %ebp,%edi
  sub    $0x1,%rbx
  call   <helper@plt>
  mov    %ebp,%edi
  mov    $0xa,%esi
  imul   %r12d,%eax
  movslq %eax,%r12
  cltd
  imul   $0x6208cecb,%r12,%r12
  sar    $0x29,%r12
  sub    %edx,%r12d
  imul   $0x539,%r12d,%edx
  sub    %edx,%eax
  mov    %eax,%r12d
  call   <helper@plt>
  mov    %eax,%ebp
  test   %ebx,%ebx
  jns    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x8,%rsp
  mov    $0x1,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int superPow(int a, int *b, int bSize) {
  int res = 1;
  for (int i = bSize - 1; i >= 0; i--) {
    res = ((res * helper(a, b[i])) % 1337);
    a = helper(a, 10);
  }
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int g(const int *restrict a, int *b) {
  *b = 1;
  *a;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<g>:
  endbr64
  movl   $0x1,(%rsi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int g(const int *restrict a, int *b) {
  *b = 1;
  *a;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<g>:
  endbr64
  movl   $0x1,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int g(const int *restrict a, int *b) {
  *b = 1;
  *a;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<g>:
  endbr64
  movl   $0x1,(%rsi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int g(const int *restrict a, int *b) {
  *b = 1;
  *a;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1e,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_stack@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <cleanStack@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int **new_stack = NULL;
  push(new_stack, 10);
  push(new_stack, 20);
  push(new_stack, 30);
  push(new_stack, 40);
  push(new_stack, 50);
  push(new_stack, 60);
  print_stack(new_stack);
  pop(new_stack);
  pop(new_stack);
  cleanStack(new_stack);
  if (new_stack != NULL)
    free(new_stack);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x14,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x1e,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x28,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x32,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x3c,%esi
  mov    $0x0,%edi
  call   <push@plt>
  mov    $0x0,%edi
  call   <print_stack@plt>
  mov    $0x0,%edi
  call   <pop@plt>
  mov    $0x0,%edi
  call   <pop@plt>
  mov    $0x0,%edi
  call   <cleanStack@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int **new_stack = NULL;
  push(new_stack, 10);
  push(new_stack, 20);
  push(new_stack, 30);
  push(new_stack, 40);
  push(new_stack, 50);
  push(new_stack, 60);
  print_stack(new_stack);
  pop(new_stack);
  pop(new_stack);
  cleanStack(new_stack);
  if (new_stack != NULL)
    free(new_stack);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x14,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x1e,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x28,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x32,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x3c,%esi
  xor    %edi,%edi
  call   <push@plt>
  xor    %edi,%edi
  call   <print_stack@plt>
  xor    %edi,%edi
  call   <pop@plt>
  xor    %edi,%edi
  call   <pop@plt>
  xor    %edi,%edi
  call   <cleanStack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int **new_stack = NULL;
  push(new_stack, 10);
  push(new_stack, 20);
  push(new_stack, 30);
  push(new_stack, 40);
  push(new_stack, 50);
  push(new_stack, 60);
  print_stack(new_stack);
  pop(new_stack);
  pop(new_stack);
  cleanStack(new_stack);
  if (new_stack != NULL)
    free(new_stack);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x14,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x1e,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x28,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x32,%esi
  xor    %edi,%edi
  call   <push@plt>
  mov    $0x3c,%esi
  xor    %edi,%edi
  call   <push@plt>
  xor    %edi,%edi
  call   <print_stack@plt>
  xor    %edi,%edi
  call   <pop@plt>
  xor    %edi,%edi
  call   <pop@plt>
  xor    %edi,%edi
  call   <cleanStack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int **new_stack = NULL;
  push(new_stack, 10);
  push(new_stack, 20);
  push(new_stack, 30);
  push(new_stack, 40);
  push(new_stack, 50);
  push(new_stack, 60);
  print_stack(new_stack);
  pop(new_stack);
  pop(new_stack);
  cleanStack(new_stack);
  if (new_stack != NULL)
    free(new_stack);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ta_print_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <ta_print_spaces@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string

tool: D12:   %s

tool: D15: %s


assistant: ```c
void ta_print_help(const char *arg, const char *help, size_t maxlen) {
  size_t alen = strlen(arg);
  printf("  %s", arg);
  ta_print_spaces((maxlen - alen) + 3);
  printf("%s\n", help);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ta_print_help>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    0x3(%rbx),%rdi
  sub    %r13,%rdi
  call   <ta_print_spaces@plt>
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D19:   %s

tool: D6: %s


assistant: ```c
void ta_print_help(const char *arg, const char *help, size_t maxlen) {
  size_t alen = strlen(arg);
  printf("  %s", arg);
  ta_print_spaces((maxlen - alen) + 3);
  printf("%s\n", help);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ta_print_help>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  mov    %rax,%r13
  call   <printf@plt>
  lea    0x3(%rbx),%rdi
  sub    %r13,%rdi
  call   <ta_print_spaces@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  lea    D18(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D18
data_type: string

tool: D19:   %s

tool: D18: %s


assistant: ```c
void ta_print_help(const char *arg, const char *help, size_t maxlen) {
  size_t alen = strlen(arg);
  printf("  %s", arg);
  ta_print_spaces((maxlen - alen) + 3);
  printf("%s\n", help);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ta_print_help>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  mov    %rax,%r13
  call   <printf@plt>
  lea    0x3(%rbx),%rdi
  sub    %r13,%rdi
  call   <ta_print_spaces@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D0
type: string

tool: D2:   %s

tool: D0: %s


assistant: ```c
void ta_print_help(const char *arg, const char *help, size_t maxlen) {
  size_t alen = strlen(arg);
  printf("  %s", arg);
  ta_print_spaces((maxlen - alen) + 3);
  printf("%s\n", help);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_identifier>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L1
L33:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L1
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L34
L1:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L33
L34:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t read_identifier(const char *s, size_t pos, size_t len) {
  while (islower(s[pos]) || isdigit(s[pos]) || s[pos] == '_') {
    if (++pos >= len) {
      pos = len + 1;
      break;
    }
  }
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_identifier>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  jmp    L37
L34:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jae    L55
L37:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L34
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L34
  cmpb   $0x5f,0x0(%rbp,%rbx,1)
  je     L34
  mov    %rbx,%rax
  jmp    L10
L55:
  lea    0x1(%r12),%rax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t read_identifier(const char *s, size_t pos, size_t len) {
  while (islower(s[pos]) || isdigit(s[pos]) || s[pos] == '_') {
    if (++pos >= len) {
      pos = len + 1;
      break;
    }
  }
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_identifier>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jae    L43
L14:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L49
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L49
  cmpb   $0x5f,0x0(%rbp,%rbx,1)
  je     L49
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L43:
  lea    0x1(%r12),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t read_identifier(const char *s, size_t pos, size_t len) {
  while (islower(s[pos]) || isdigit(s[pos]) || s[pos] == '_') {
    if (++pos >= len) {
      pos = len + 1;
      break;
    }
  }
  return pos;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_identifier>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jae    L17
L8:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  jne    L4
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
  cmpb   $0x5f,0x0(%rbp,%rbx,1)
  je     L4
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L17:
  lea    0x1(%r12),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t read_identifier(const char *s, size_t pos, size_t len) {
  while (islower(s[pos]) || isdigit(s[pos]) || s[pos] == '_') {
    if (++pos >= len) {
      pos = len + 1;
      break;
    }
  }
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cs_pvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L45
  cmpq   $0x0,-0x20(%rbp)
  jne    L43
L45:
  mov    $0x0,%eax
  jmp    L61
L43:
  movl   $0x0,-0x4(%rbp)
  jmp    L62
L31:
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  jmp    L57
L4:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
L57:
  mov    -0x20(%rbp),%rdx
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L62:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L31
  mov    $0x1,%eax
L61:
  pop    %rbp
  ret
```

assistant: ```c
int cs_pvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[k] = b[p ? p[k] : k];
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cs_pvec>:
  endbr64
  test   %rdx,%rdx
  je     L62
  test   %rsi,%rsi
  je     L62
  test   %ecx,%ecx
  jle    L16
  mov    %ecx,%ecx
  mov    $0x0,%eax
  jmp    L53
L30:
  movsd  (%rsi,%r8,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L5
L53:
  lea    0x0(,%rax,8),%r8
  test   %rdi,%rdi
  je     L30
  movslq (%rdi,%rax,4),%r8
  shl    $0x3,%r8
  jmp    L30
L5:
  mov    $0x1,%eax
  ret
L62:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cs_pvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[k] = b[p ? p[k] : k];
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cs_pvec>:
  endbr64
  test   %rdx,%rdx
  je     L9
  test   %rsi,%rsi
  je     L9
  movslq %ecx,%r8
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L13
  nopw   0x0(%rax,%rax,1)
L38:
  lea    0x0(,%rax,8),%rcx
  test   %rdi,%rdi
  je     L1
  movslq (%rdi,%rax,4),%rcx
  shl    $0x3,%rcx
L1:
  movsd  (%rsi,%rcx,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L38
L13:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cs_pvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[k] = b[p ? p[k] : k];
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cs_pvec>:
  endbr64
  mov    %rsi,%r8
  test   %rdx,%rdx
  je     L81
  test   %rsi,%rsi
  je     L81
  test   %ecx,%ecx
  jle    L93
  movslq %ecx,%rsi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  nop
L53:
  movslq (%rdi,%rax,4),%rcx
  movsd  (%r8,%rcx,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L53
L93:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L81:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L61
  lea    0x8(%r8),%rax
  cmp    %rax,%rdx
  je     L61
  mov    %ecx,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  nopl   0x0(%rax,%rax,1)
L1:
  movupd (%r8,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L1
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L93
  movsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  mov    $0x1,%eax
  ret
L61:
  mov    %ecx,%ecx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L71:
  movsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L71
  jmp    L93
```

assistant: ```c
int cs_pvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[k] = b[p ? p[k] : k];
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_proc_self_stat_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jle    L215
  cmpq   $0x0,-0x28(%rbp)
  je     L215
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L133
L215:
  mov    $0x0,%eax
  jmp    L160
L133:
  cmpl   $0x1,-0x2c(%rbp)
  jne    L101
  mov    -0x28(%rbp),%rax
  jmp    L160
L101:
  cmpl   $0x2,-0x2c(%rbp)
  jne    L110
  mov    -0x28(%rbp),%rax
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  jmp    L160
L110:
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L145
L108:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L94
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L94:
  addq   $0x1,-0x10(%rbp)
L145:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L108
  cmpq   $0x0,-0x8(%rbp)
  jne    L200
  mov    $0x0,%eax
  jmp    L160
L200:
  addq   $0x1,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L201
L111:
  addq   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L129
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L111
L129:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L185
  jmp    L67
L199:
  addq   $0x1,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L201
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L199
L201:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  jmp    L106
L185:
  nop
L106:
  mov    -0x10(%rbp),%rax
L160:
  leave
  ret
```

assistant: ```c
const char *get_proc_self_stat_field(const char *buf, const int num) {
  const char *ptr = buf, *comm_end;
  int n;
  if (num < 1 || !buf || !*buf)
    return NULL;
  if (num == 1)
    return buf;
  if (num == 2)
    return strstr(buf, "(");
  comm_end = NULL;
  for (ptr = buf; *ptr; ptr++) {
    if (*ptr == ')')
      comm_end = ptr;
  }
  if (!comm_end)
    return NULL;
  comm_end++;
  n = num - 2;
  ptr = comm_end;
  while (*ptr) {
    while (*ptr && *ptr == ' ')
      ptr++;
    n--;
    if (n <= 0)
      break;
    while (*ptr && *ptr != ' ')
      ptr++;
  }
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_proc_self_stat_field>:
  endbr64
  test   %esi,%esi
  jle    L3
  test   %rdi,%rdi
  je     L3
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L129
  mov    %rdi,%rax
  cmp    $0x1,%esi
  je     L106
  mov    $0x0,%ecx
  cmp    $0x2,%esi
  je     L147
L130:
  cmp    $0x29,%dl
  cmove  %rdi,%rcx
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L130
  test   %rcx,%rcx
  je     L42
  lea    0x1(%rcx),%rax
  lea    -0x2(%rsi),%edx
  cmpb   $0x0,0x1(%rcx)
  jne    L25
  ret
L147:
  sub    $0x8,%rsp
  mov    $0x28,%esi
  call   <strchr@plt>
  add    $0x8,%rsp
  ret
L114:
  cmpb   $0x0,(%rax)
  je     L106
L25:
  cmpb   $0x20,(%rax)
  jne    L102
L135:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L135
L102:
  sub    $0x1,%edx
  test   %edx,%edx
  jle    L106
  testb  $0xdf,(%rax)
  je     L114
L16:
  add    $0x1,%rax
  testb  $0xdf,(%rax)
  jne    L16
  jmp    L114
L3:
  mov    $0x0,%eax
  ret
L129:
  mov    $0x0,%eax
  ret
L42:
  mov    %rcx,%rax
  ret
L106:
  ret
```

assistant: ```c
const char *get_proc_self_stat_field(const char *buf, const int num) {
  const char *ptr = buf, *comm_end;
  int n;
  if (num < 1 || !buf || !*buf)
    return NULL;
  if (num == 1)
    return buf;
  if (num == 2)
    return strstr(buf, "(");
  comm_end = NULL;
  for (ptr = buf; *ptr; ptr++) {
    if (*ptr == ')')
      comm_end = ptr;
  }
  if (!comm_end)
    return NULL;
  comm_end++;
  n = num - 2;
  ptr = comm_end;
  while (*ptr) {
    while (*ptr && *ptr == ' ')
      ptr++;
    n--;
    if (n <= 0)
      break;
    while (*ptr && *ptr != ' ')
      ptr++;
  }
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_proc_self_stat_field>:
  endbr64
  test   %esi,%esi
  jle    L81
  test   %rdi,%rdi
  je     L81
  movzbl (%rdi),%eax
  test   %al,%al
  je     L81
  cmp    $0x1,%esi
  je     L102
  xor    %edx,%edx
  cmp    $0x2,%esi
  je     L12
  nopl   0x0(%rax)
L125:
  cmp    $0x29,%al
  cmove  %rdi,%rdx
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L125
  test   %rdx,%rdx
  je     L81
  lea    0x1(%rdx),%rax
  movzbl 0x1(%rdx),%edx
  lea    -0x2(%rsi),%ecx
  test   %dl,%dl
  je     L31
  xchg   %ax,%ax
L78:
  cmp    $0x20,%dl
  jne    L41
  nopl   (%rax)
L0:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L0
L41:
  sub    $0x1,%ecx
  jne    L137
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L93:
  add    $0x1,%rax
L137:
  movzbl (%rax),%edx
  test   $0xdf,%dl
  jne    L93
  test   %dl,%dl
  jne    L78
L44:
  ret
  nopl   0x0(%rax)
L81:
  xor    %eax,%eax
  ret
L12:
  mov    $0x28,%esi
  jmp    1050 <strchr@plt>
L102:
  mov    %rdi,%rax
  ret
L31:
  ret
```

assistant: ```c
const char *get_proc_self_stat_field(const char *buf, const int num) {
  const char *ptr = buf, *comm_end;
  int n;
  if (num < 1 || !buf || !*buf)
    return NULL;
  if (num == 1)
    return buf;
  if (num == 2)
    return strstr(buf, "(");
  comm_end = NULL;
  for (ptr = buf; *ptr; ptr++) {
    if (*ptr == ')')
      comm_end = ptr;
  }
  if (!comm_end)
    return NULL;
  comm_end++;
  n = num - 2;
  ptr = comm_end;
  while (*ptr) {
    while (*ptr && *ptr == ' ')
      ptr++;
    n--;
    if (n <= 0)
      break;
    while (*ptr && *ptr != ' ')
      ptr++;
  }
  return ptr;
}
```