user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<analise_fifo_m>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L172:
  cmp    %rcx,%rsp
  je     L34
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L172
L34:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L133
  orq    $0x0,-0x8(%rsp,%rdx,1)
L133:
  mov    %rsp,%r13
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L75:
  cmp    %rdx,%rsp
  je     L112
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L75
L112:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L114
  orq    $0x0,-0x8(%rsp,%rax,1)
L114:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L124
  mov    %r12d,%eax
  mov    %rax,-0x48(%rbp)
  mov    $0x0,%ebx
  jmp    L21
L42:
  add    $0x1,%rbx
  cmp    -0x48(%rbp),%rbx
  je     L98
L21:
  mov    (%r15,%rbx,4),%edi
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <quadro_ausente_fifo_m@plt>
  test   %eax,%eax
  je     L42
  mov    (%r15,%rbx,4),%eax
  mov    %eax,0x0(%r13,%rbx,4)
  jmp    L42
L98:
  mov    %r12d,%eax
L115:
  cltq
  shl    $0x2,%rax
  lea    (%r15,%rax,1),%rdx
  mov    (%rdx),%edi
  test   %edi,%edi
  jle    L152
  lea    0x4(%r15,%rax,1),%rbx
  mov    %rdx,%r15
  movl   $0x0,-0x48(%rbp)
  jmp    L32
L124:
  mov    $0x0,%eax
  jmp    L115
L62:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  add    $0x4,%r15
  test   %edi,%edi
  jle    L150
L32:
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    %r13,%rsi
  call   <quadro_ausente_fifo_m@plt>
  test   %eax,%eax
  je     L62
  addl   $0x1,-0x48(%rbp)
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <calc_posicao_fifo_m@plt>
  cltq
  mov    (%r15),%edx
  mov    %edx,0x0(%r13,%rax,4)
  jmp    L62
L152:
  movl   $0x0,-0x48(%rbp)
L150:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    -0x48(%rbp),%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int analise_fifo_m(int numero_de_quadros, int *referencias) {
  int vetor_quadros[numero_de_quadros], vetor_alloc[numero_de_quadros];
  int cont, cont_alloc;
  int page_fault;
  int qtd_page_fault = 0;
  for (cont = 0; cont < numero_de_quadros; cont++) {
    page_fault = quadro_ausente_fifo_m(referencias[cont], vetor_quadros, numero_de_quadros, vetor_alloc);
    if (page_fault) {
      vetor_quadros[cont] = referencias[cont];
    }
  }
  while (referencias[cont] > 0) {
    page_fault = quadro_ausente_fifo_m(referencias[cont], vetor_quadros, numero_de_quadros, vetor_alloc);
    if (page_fault) {
      qtd_page_fault++;
      cont_alloc = calc_posicao_fifo_m(vetor_alloc, numero_de_quadros);
      vetor_quadros[cont_alloc] = referencias[cont];
    };
    cont++;
  }
  return qtd_page_fault;
}
```