user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x54(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x54(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rdx
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L23
L121:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L121
L23:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L4
L99:
  mov    %rsp,%rbx
  test   %edx,%edx
  jle    L80
  xor    %r12d,%r12d
  lea    -0x40(%rbp),%r8
  lea    -0x48(%rbp),%r15
  lea    -0x4c(%rbp),%r14
  lea    -0x50(%rbp),%r13
  nopl   0x0(%rax)
L77:
  mov    %r14,%rdx
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    %r15,%rcx
  mov    %r13,%rsi
  mov    %r8,-0x68(%rbp)
  call   <scanf@plt>
  mov    -0x50(%rbp),%edx
  mov    -0x4c(%rbp),%eax
  mov    D10(%rip),%rdi
  mov    -0x68(%rbp),%r8
  cmp    %eax,%edx
  movq   %rdi,%xmm1
  jg     L57
  movsd  -0x48(%rbp),%xmm3
  movsd  -0x40(%rbp),%xmm2
  mov    $0x1,%ecx
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x1,%ecx
  cmp    $0x65,%ecx
  je     L67
L76:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    %esi,%edx
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  add    %esi,%eax
  cmp    %eax,%edx
  jle    L37
L67:
  mov    %edx,-0x50(%rbp)
  mov    %eax,-0x4c(%rbp)
L33:
  mov    -0x54(%rbp),%eax
  mov    %cl,(%rbx,%r12,1)
  add    $0x1,%r12
  cmp    %r12d,%eax
  jg     L77
  test   %eax,%eax
  jle    L80
  xor    %r12d,%r12d
  lea    D43(%rip),%r14
  lea    D31(%rip),%r13
  jmp    L139
  nopl   0x0(%rax)
L150:
  mov    %r13,%rdi
  add    $0x1,%r12
  call   <puts@plt>
  cmp    %r12d,-0x54(%rbp)
  jle    L80
L139:
  movsbl (%rbx,%r12,1),%esi
  cmp    $0x64,%sil
  jg     L150
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x54(%rbp)
  jg     L139
L80:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L57:
  xor    %ecx,%ecx
  jmp    L33
L4:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L99
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D34
type_infered: string
name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D43
type_infered: string
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string

tool: D34: %d

tool: D0: %d %d %lf %lf

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D43: %d anos.


tool: D31: Mais de 1 seculo.

assistant: ```c
int main() {
  int testsQtt;
  int aPopulation, bPopulation;
  double aPercentualGrowing, bPercentualGrowing;
  scanf("%d", &testsQtt);
  char results[testsQtt];
  int i, years;
  for (i = 0; i < testsQtt; i++) {
    scanf("%d %d %lf %lf", &aPopulation, &bPopulation, &aPercentualGrowing, &bPercentualGrowing);
    years = 0;
    while (aPopulation <= bPopulation) {
      years++;
      if (years > 100) {
        break;
      }
      aPopulation += (int)(aPopulation * aPercentualGrowing / 100);
      bPopulation += (int)(bPopulation * bPercentualGrowing / 100);
    }
    results[i] = years;
  }
  for (i = 0; i < testsQtt; i++) {
    if (results[i] > 100) {
      printf("Mais de 1 seculo.\n");
    } else {
      printf("%d anos.\n", results[i]);
    }
  }
  return 0;
}
```