ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L25
  xor    %eax,%eax
  jmp    L4
  nopl   (%rax)
L43:
  jne    L22
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L25
L4:
  mov    (%rsi,%rax,8),%rcx
  cmp    %rcx,(%rdi,%rax,8)
  jge    L43
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  const uint8_t *ap = a;
  const uint8_t *bp = b;
  while (n--) {
    if (*ap < *bp)
      return -1;
    if (*ap != *bp)
      return 1;
    ap++;
    bp++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L13
  xor    %eax,%eax
  jmp    L25
  nopl   (%rax)
L5:
  jne    L12
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L13
L25:
  mov    (%rsi,%rax,8),%rcx
  cmp    %rcx,(%rdi,%rax,8)
  jge    L5
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int memcmp(const void *a, const void *b, size_t n) {
  const uint8_t *ap = a;
  const uint8_t *bp = b;
  while (n--) {
    if (*ap < *bp)
      return -1;
    if (*ap != *bp)
      return 1;
    ap++;
    bp++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L35
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  jmp    L37
L35:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
L37:
  mov    %rax,-0x10(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jle    L16
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%rax
  jmp    L15
L16:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
L15:
  mov    %rax,-0x8(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  jle    L18
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  jmp    L8
L18:
  mov    $0x5,%eax
L8:
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ncmp@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  char *s = argc >= 2 ? argv[1] : argv[0];
  char *t = argc >= 3 ? argv[2] : argv[0];
  int n = argc >= 4 ? atol(argv[3]) : 5;
  printf("%d\n", ncmp(s, t, n));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L9
  mov    0x8(%rsi),%rbx
  cmp    $0x2,%edi
  jle    L0
  mov    0x10(%rsi),%rbp
  mov    $0x5,%edx
  cmp    $0x3,%edi
  jle    L31
  mov    0x18(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%edx
  jmp    L31
L9:
  mov    (%rsi),%rbx
L0:
  mov    (%rsi),%rbp
  mov    $0x5,%edx
L31:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <ncmp@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  char *s = argc >= 2 ? argv[1] : argv[0];
  char *t = argc >= 3 ? argv[2] : argv[0];
  int n = argc >= 4 ? atol(argv[3]) : 5;
  printf("%d\n", ncmp(s, t, n));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L18
  mov    0x8(%rsi),%r12
  cmp    $0x2,%edi
  je     L22
  mov    0x10(%rsi),%rbp
  cmp    $0x3,%edi
  je     L42
  mov    0x18(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%edx
  jmp    L39
L18:
  mov    (%rsi),%rbp
  mov    %rbp,%r12
L42:
  mov    $0x5,%edx
L39:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ncmp@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    (%rsi),%rbp
  jmp    L42
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: %d


assistant: ```c
int main(int argc, char **argv) {
  char *s = argc >= 2 ? argv[1] : argv[0];
  char *t = argc >= 3 ? argv[2] : argv[0];
  int n = argc >= 4 ? atol(argv[3]) : 5;
  printf("%d\n", ncmp(s, t, n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L40
  mov    0x8(%rsi),%r12
  cmp    $0x2,%edi
  je     L47
  mov    0x10(%rsi),%rbp
  cmp    $0x3,%edi
  je     L32
  mov    0x18(%rsi),%rdi
  call   <atol@plt>
  mov    %eax,%edx
  jmp    L48
L40:
  mov    (%rsi),%rbp
  mov    %rbp,%r12
L32:
  mov    $0x5,%edx
L48:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ncmp@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    (%rsi),%rbp
  jmp    L32
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  char *s = argc >= 2 ? argv[1] : argv[0];
  char *t = argc >= 3 ? argv[2] : argv[0];
  int n = argc >= 4 ? atol(argv[3]) : 5;
  printf("%d\n", ncmp(s, t, n));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D76(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D62(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x6d,%al
  je     L44
  cmp    $0x66,%al
  jne    L130
  mov    0x10(%rsp),%eax
  cmp    $0x3e,%eax
  jle    L182
  cmpl   $0x9,0x14(%rsp)
  jg     L176
L135:
  cmpl   $0xe,0x14(%rsp)
  jg     L104
L26:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L44:
  mov    0x10(%rsp),%eax
  cmp    $0x40,%eax
  jle    L66
  cmpl   $0x9,0x14(%rsp)
  jg     L31
L76:
  cmpl   $0xe,0x14(%rsp)
  jg     L168
L70:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L31:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L66:
  cmp    $0x3e,%eax
  jle    L70
  jmp    L76
L168:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L176:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L182:
  cmp    $0x3c,%eax
  jle    L26
  jmp    L135
L104:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L180
L130:
  lea    D40(%rip),%rdi
  call   <printf@plt>
L180:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x20,%rsp
  pop    %rbx
  ret
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D51
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D32
datatype: string
name: unpack_data
arguments: data_tag: D76
datatype: string
name: unpack_data
arguments: data_tag: D62
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D40
datatype: string

tool: D51: Informe seu sexo('m' ou 'f'): 

tool: D1: %c

tool: D32: Informe sua idade: 

tool: D76: %d

tool: D62: Informe o tempo de contribuicao: 

tool: D11: Nao pode aposentar!


tool: D5: Pode aposentar!


tool: D40: Reveja os parametros informados.


assistant: ```c
void main() {
  int idd, contrib;
  char sexo;
  printf("Informe seu sexo('m' ou 'f'): ");
  scanf("%c", &sexo);
  printf("Informe sua idade: ");
  scanf("%d", &idd);
  printf("Informe o tempo de contribuicao: ");
  scanf("%d", &contrib);
  if (sexo == 'm') {
    if (idd >= 65 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 63 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else if (sexo == 'f') {
    if (idd >= 63 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 61 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else {
    printf("Reveja os parametros informados.\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D43(%rip),%rdi
  lea    D4(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x6d,%al
  je     L105
  cmp    $0x66,%al
  jne    L117
  mov    0x10(%rsp),%eax
  cmp    $0x3e,%eax
  jle    L6
L49:
  cmpl   $0x9,0x14(%rsp)
  jg     L13
L69:
  cmpl   $0xe,0x14(%rsp)
  jg     L13
L43:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L117:
  lea    D25(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  pop    %rbp
  ret
L105:
  mov    0x10(%rsp),%eax
  cmp    $0x40,%eax
  jg     L49
  cmp    $0x3e,%eax
  jle    L43
  jmp    L69
L13:
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L6:
  cmp    $0x3c,%eax
  jle    L43
  jmp    L69
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D43
data_type: string
name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D34
data_type: string
name: unpack_data
arguments: label: D59
data_type: string
name: unpack_data
arguments: label: D15
data_type: string
name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D60
data_type: string

tool: D43: Informe seu sexo('m' ou 'f'): 

tool: D4: %d

tool: D14: %c

tool: D34: Informe sua idade: 

tool: D59: Informe o tempo de contribuicao: 

tool: D15: Nao pode aposentar!


tool: D25: Reveja os parametros informados.


tool: D60: Pode aposentar!


assistant: ```c
void main() {
  int idd, contrib;
  char sexo;
  printf("Informe seu sexo('m' ou 'f'): ");
  scanf("%c", &sexo);
  printf("Informe sua idade: ");
  scanf("%d", &idd);
  printf("Informe o tempo de contribuicao: ");
  scanf("%d", &contrib);
  if (sexo == 'm') {
    if (idd >= 65 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 63 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else if (sexo == 'f') {
    if (idd >= 63 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 61 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else {
    printf("Reveja os parametros informados.\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  lea    D45(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xf(%rsp),%eax
  cmp    $0x6d,%al
  je     L94
  cmp    $0x66,%al
  jne    L1
  mov    0x10(%rsp),%eax
  cmp    $0x3e,%eax
  jle    L35
L81:
  cmpl   $0x9,0x14(%rsp)
  jg     L128
L48:
  cmpl   $0xe,0x14(%rsp)
  jg     L128
L17:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  jmp    L108
L1:
  lea    D24(%rip),%rdi
  call   <printf@plt>
L108:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x20,%rsp
  pop    %rbp
  ret
L94:
  mov    0x10(%rsp),%eax
  cmp    $0x40,%eax
  jg     L81
  cmp    $0x3e,%eax
  jle    L17
  jmp    L48
L128:
  lea    D67(%rip),%rdi
  call   <printf@plt>
  jmp    L108
L35:
  cmp    $0x3c,%eax
  jle    L17
  jmp    L48
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D45
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D66
type_guessed: string
name: retrieve_data
arguments: data_tag: D73
type_guessed: string
name: retrieve_data
arguments: data_tag: D49
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D67
type_guessed: string

tool: D25: Informe seu sexo('m' ou 'f'): 

tool: D45: %d

tool: D14: %c

tool: D66: Informe sua idade: 

tool: D73: Informe o tempo de contribuicao: 

tool: D49: Nao pode aposentar!


tool: D24: Reveja os parametros informados.


tool: D67: Pode aposentar!


assistant: ```c
void main() {
  int idd, contrib;
  char sexo;
  printf("Informe seu sexo('m' ou 'f'): ");
  scanf("%c", &sexo);
  printf("Informe sua idade: ");
  scanf("%d", &idd);
  printf("Informe o tempo de contribuicao: ");
  scanf("%d", &contrib);
  if (sexo == 'm') {
    if (idd >= 65 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 63 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else if (sexo == 'f') {
    if (idd >= 63 && contrib >= 10) {
      printf("Pode aposentar!\n");
    } else if (idd >= 61 && contrib >= 15) {
      printf("Pode aposentar!\n");
    } else {
      printf("Nao pode aposentar!\n");
    }
  } else {
    printf("Reveja os parametros informados.\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_three>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L24:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_three(int x, int y) {
#pragma omp parallel for simd collapse(1)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_three>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jg     L6
  ret
L43:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L43
L11:
  add    $0x1,%edx
  cmp    %edx,%edi
  je     L37
L6:
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L43
  jmp    L11
L37:
  ret
```

assistant: ```c
void test_three(int x, int y) {
#pragma omp parallel for simd collapse(1)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_three>:
  endbr64
  ret
```

assistant: ```c
void test_three(int x, int y) {
#pragma omp parallel for simd collapse(1)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_three>:
  endbr64
  ret
```

assistant: ```c
void test_three(int x, int y) {
#pragma omp parallel for simd collapse(1)
  for (int i = 0; i < x; i++)
    for (int i = 0; i < y; i++)
      ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L17
  mov    $0xffffffff,%eax
  jmp    L11
L17:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  setg   %al
  movzbl %al,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int compare(const void *x, const void *y) {
  int *low = (int *)x;
  int *high = (int *)y;
  if (*low < *high) {
    return -1;
  } else {
    return *low > *high ? 1 : 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L7
  setg   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int compare(const void *x, const void *y) {
  int *low = (int *)x;
  int *high = (int *)y;
  if (*low < *high) {
    return -1;
  } else {
    return *low > *high ? 1 : 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compare>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compare(const void *x, const void *y) {
  int *low = (int *)x;
  int *high = (int *)y;
  if (*low < *high) {
    return -1;
  } else {
    return *low > *high ? 1 : 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<compare>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int compare(const void *x, const void *y) {
  int *low = (int *)x;
  int *high = (int *)y;
  if (*low < *high) {
    return -1;
  } else {
    return *low > *high ? 1 : 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vectorSumElements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L1:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L1
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double vectorSumElements(double *values, unsigned int dim) {
  double result = 0.0;
  unsigned int i = 0;
  for (i = 0; i < dim; i++) {
    result = result + values[i];
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vectorSumElements>:
  endbr64
  test   %esi,%esi
  je     L9
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L19:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
  ret
L9:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double vectorSumElements(double *values, unsigned int dim) {
  double result = 0.0;
  unsigned int i = 0;
  for (i = 0; i < dim; i++) {
    result = result + values[i];
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vectorSumElements>:
  endbr64
  test   %esi,%esi
  je     L0
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L12:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L12
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double vectorSumElements(double *values, unsigned int dim) {
  double result = 0.0;
  unsigned int i = 0;
  for (i = 0; i < dim; i++) {
    result = result + values[i];
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vectorSumElements>:
  endbr64
  test   %esi,%esi
  je     L45
  cmp    $0x1,%esi
  je     L13
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L5:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L5
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L31
L32:
  addsd  (%rdi,%rax,8),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  ret
  nopl   0x0(%rax)
L45:
  pxor   %xmm0,%xmm0
  ret
L13:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L32
```

assistant: ```c
double vectorSumElements(double *values, unsigned int dim) {
  double result = 0.0;
  unsigned int i = 0;
  for (i = 0; i < dim; i++) {
    result = result + values[i];
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L69
L58:
  movl   $0x2,-0x4(%rbp)
  jmp    L49
L52:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L45
  addl   $0x1,-0x4(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L52
  jmp    L67
L45:
  nop
L67:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L16
  addl   $0x1,-0x8(%rbp)
L16:
  addl   $0x1,-0xc(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L58
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void primes(int n) {
  int i = 3, count, c;
  for (count = 2; count <= n;) {
    for (c = 2; c <= i - 1; c++) {
      if (i % c == 0)
        break;
    }
    if (c == i) {
      count++;
    }
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<primes>:
  endbr64
  mov    $0x2,%r8d
  mov    $0x3,%esi
  cmp    $0x1,%edi
  jg     L66
  ret
L28:
  jne    L2
L16:
  add    $0x1,%r8d
L2:
  add    $0x1,%esi
  cmp    %edi,%r8d
  jg     L0
L66:
  cmp    $0x2,%esi
  jle    L28
  test   $0x1,%sil
  je     L2
  mov    $0x2,%ecx
L13:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L16
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L13
  jmp    L2
L0:
  ret
```

assistant: ```c
void primes(int n) {
  int i = 3, count, c;
  for (count = 2; count <= n;) {
    for (c = 2; c <= i - 1; c++) {
      if (i % c == 0)
        break;
    }
    if (c == i) {
      count++;
    }
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<primes>:
  endbr64
  ret
```

assistant: ```c
void primes(int n) {
  int i = 3, count, c;
  for (count = 2; count <= n;) {
    for (c = 2; c <= i - 1; c++) {
      if (i % c == 0)
        break;
    }
    if (c == i) {
      count++;
    }
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<primes>:
  endbr64
  ret
```

assistant: ```c
void primes(int n) {
  int i = 3, count, c;
  for (count = 2; count <= n;) {
    for (c = 2; c <= i - 1; c++) {
      if (i % c == 0)
        break;
    }
    if (c == i) {
      count++;
    }
    i++;
  }
}
```