ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<birthdayGift>:
  endbr64
  push   %r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    -0x1(%rsi),%eax
  mov    %eax,(%rsp)
  test   %esi,%esi
  je     L0
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebx
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L10
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%esi
L0:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D7
datatype: byte[8]
name: unpack_data
arguments: label: D8
datatype: string

tool: D29: %d

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D8: %.1f

assistant: ```c
int birthdayGift(void) {
  int numSteps;
  scanf("%d", &numSteps);
  int sum = 0;
  while (numSteps--) {
    int input;
    scanf("%d", &input);
    sum += input;
  }
  printf("%.1f", sum / 2.0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<birthdayGift>:
  endbr64
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    -0x1(%rsi),%eax
  mov    %eax,(%rsp)
  test   %esi,%esi
  je     L3
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  add    0x4(%rsp),%ebx
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L16
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  D4(%rip),%xmm0
  cvttsd2si %xmm0,%esi
L3:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: byte[8]
name: retrieve_data
arguments: data_tag: D28
type_guessed: string

tool: D18: %d

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D28: %.1f

assistant: ```c
int birthdayGift(void) {
  int numSteps;
  scanf("%d", &numSteps);
  int sum = 0;
  while (numSteps--) {
    int input;
    scanf("%d", &input);
    sum += input;
  }
  printf("%.1f", sum / 2.0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SshEncodeBuffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L18
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movb   $0x0,(%rax)
  movl   $0x5,-0x4(%rbp)
  jmp    L16
L18:
  movl   $0x4,-0x4(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int SshEncodeBuffer(unsigned char *pEncoding, int bufferLen, unsigned char *pBuffer) {
  int adjustedLen = bufferLen, index;
  if (*pBuffer & 0x80) {
    adjustedLen++;
    pEncoding[4] = 0;
    index = 5;
  } else {
    index = 4;
  }
  pEncoding[0] = (unsigned char)(adjustedLen >> 24);
  pEncoding[1] = (unsigned char)(adjustedLen >> 16);
  pEncoding[2] = (unsigned char)(adjustedLen >> 8);
  pEncoding[3] = (unsigned char)(adjustedLen);
  memcpy(&pEncoding[index], pBuffer, bufferLen);
  return index + bufferLen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SshEncodeBuffer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %rdx,%rsi
  mov    %ebx,%eax
  mov    $0x4,%ebp
  cmpb   $0x0,(%rdx)
  js     L2
L4:
  mov    %eax,%edx
  sar    $0x18,%edx
  mov    %dl,(%rdi)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x1(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rdi)
  mov    %al,0x3(%rdi)
  movslq %ebp,%rax
  add    %rax,%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x0(%rbp,%rbx,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    0x1(%rbx),%eax
  movb   $0x0,0x4(%rdi)
  mov    $0x5,%ebp
  jmp    L4
```

assistant: ```c
int SshEncodeBuffer(unsigned char *pEncoding, int bufferLen, unsigned char *pBuffer) {
  int adjustedLen = bufferLen, index;
  if (*pBuffer & 0x80) {
    adjustedLen++;
    pEncoding[4] = 0;
    index = 5;
  } else {
    index = 4;
  }
  pEncoding[0] = (unsigned char)(adjustedLen >> 24);
  pEncoding[1] = (unsigned char)(adjustedLen >> 16);
  pEncoding[2] = (unsigned char)(adjustedLen >> 8);
  pEncoding[3] = (unsigned char)(adjustedLen);
  memcpy(&pEncoding[index], pBuffer, bufferLen);
  return index + bufferLen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SshEncodeBuffer>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdx)
  js     L3
  mov    %ebx,%eax
  mov    $0x4,%edx
  mov    $0x4,%ebp
L17:
  bswap  %eax
  mov    %eax,(%rdi)
  add    %rdx,%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  movb   $0x0,0x4(%rdi)
  lea    0x1(%rbx),%eax
  mov    $0x5,%edx
  mov    $0x5,%ebp
  jmp    L17
```

assistant: ```c
int SshEncodeBuffer(unsigned char *pEncoding, int bufferLen, unsigned char *pBuffer) {
  int adjustedLen = bufferLen, index;
  if (*pBuffer & 0x80) {
    adjustedLen++;
    pEncoding[4] = 0;
    index = 5;
  } else {
    index = 4;
  }
  pEncoding[0] = (unsigned char)(adjustedLen >> 24);
  pEncoding[1] = (unsigned char)(adjustedLen >> 16);
  pEncoding[2] = (unsigned char)(adjustedLen >> 8);
  pEncoding[3] = (unsigned char)(adjustedLen);
  memcpy(&pEncoding[index], pBuffer, bufferLen);
  return index + bufferLen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SshEncodeBuffer>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdx)
  js     L9
  mov    %ebx,%eax
  mov    $0x4,%edx
  mov    $0x4,%ebp
L0:
  bswap  %eax
  mov    %eax,(%rdi)
  add    %rdx,%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  movb   $0x0,0x4(%rdi)
  lea    0x1(%rbx),%eax
  mov    $0x5,%edx
  mov    $0x5,%ebp
  jmp    L0
```

assistant: ```c
int SshEncodeBuffer(unsigned char *pEncoding, int bufferLen, unsigned char *pBuffer) {
  int adjustedLen = bufferLen, index;
  if (*pBuffer & 0x80) {
    adjustedLen++;
    pEncoding[4] = 0;
    index = 5;
  } else {
    index = 4;
  }
  pEncoding[0] = (unsigned char)(adjustedLen >> 24);
  pEncoding[1] = (unsigned char)(adjustedLen >> 16);
  pEncoding[2] = (unsigned char)(adjustedLen >> 8);
  pEncoding[3] = (unsigned char)(adjustedLen);
  memcpy(&pEncoding[index], pBuffer, bufferLen);
  return index + bufferLen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bounds_okay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L12
  cmpl   $0x0,-0x8(%rbp)
  js     L12
  cmpl   $0x31f,-0x4(%rbp)
  jg     L12
  cmpl   $0x257,-0x8(%rbp)
  jg     L12
  mov    $0x1,%eax
  jmp    L13
L12:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int bounds_okay(int x, int y) {
  if (x >= 0)
    if (y >= 0)
      if (x < 800)
        if (y < 600)
          return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bounds_okay>:
  endbr64
  cmp    $0x31f,%edi
  setbe  %dl
  cmp    $0x257,%esi
  setbe  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int bounds_okay(int x, int y) {
  if (x >= 0)
    if (y >= 0)
      if (x < 800)
        if (y < 600)
          return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bounds_okay>:
  endbr64
  cmp    $0x31f,%edi
  setbe  %dl
  xor    %eax,%eax
  cmp    $0x257,%esi
  setbe  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int bounds_okay(int x, int y) {
  if (x >= 0)
    if (y >= 0)
      if (x < 800)
        if (y < 600)
          return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bounds_okay>:
  endbr64
  cmp    $0x31f,%edi
  setbe  %dl
  xor    %eax,%eax
  cmp    $0x257,%esi
  setbe  %al
  and    %edx,%eax
  ret
```

assistant: ```c
int bounds_okay(int x, int y) {
  if (x >= 0)
    if (y >= 0)
      if (x < 800)
        if (y < 600)
          return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hidpp_set_unaligned_le_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0xc(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hidpp_set_unaligned_le_u16(uint8_t *buf, uint16_t value) {
  buf[0] = value & 0xFF;
  buf[1] = value >> 8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hidpp_set_unaligned_le_u16>:
  endbr64
  movzbl %sil,%eax
  mov    %eax,(%rdi)
  sar    $0x8,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void hidpp_set_unaligned_le_u16(uint8_t *buf, uint16_t value) {
  buf[0] = value & 0xFF;
  buf[1] = value >> 8;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hidpp_set_unaligned_le_u16>:
  endbr64
  movzbl %sil,%eax
  sar    $0x8,%esi
  mov    %eax,(%rdi)
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void hidpp_set_unaligned_le_u16(uint8_t *buf, uint16_t value) {
  buf[0] = value & 0xFF;
  buf[1] = value >> 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hidpp_set_unaligned_le_u16>:
  endbr64
  movzbl %sil,%eax
  sar    $0x8,%esi
  movd   %eax,%xmm0
  movd   %esi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

assistant: ```c
void hidpp_set_unaligned_le_u16(uint8_t *buf, uint16_t value) {
  buf[0] = value & 0xFF;
  buf[1] = value >> 8;
}
```
user: What is the c source code of the assembly code below?

```asm
<write_out_padding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %edx,-0x834(%rbp)
  mov    %rcx,-0x840(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x800,-0x818(%rbp)
  mov    -0x818(%rbp),%rdx
  mov    -0x834(%rbp),%ecx
  lea    -0x810(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L2
L30:
  mov    -0x830(%rbp),%rax
  cmp    -0x818(%rbp),%rax
  jae    L35
  mov    -0x830(%rbp),%rax
  mov    %rax,-0x818(%rbp)
L35:
  mov    -0x840(%rbp),%rcx
  mov    -0x818(%rbp),%rdx
  lea    -0x810(%rbp),%rsi
  mov    -0x828(%rbp),%rax
  mov    %rax,%rdi
  call   <write_out_data@plt>
  test   %rax,%rax
  je     L12
  mov    $0xffffffff,%eax
  jmp    L21
L12:
  mov    -0x818(%rbp),%rax
  sub    %rax,-0x830(%rbp)
L2:
  cmpq   $0x0,-0x830(%rbp)
  jne    L30
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int write_out_padding(FILE *outfile, size_t len, uint8_t padc, struct csum_state *css) {
  uint8_t buf[512];
  size_t buflen = sizeof(buf);
  memset(buf, padc, buflen);
  while (len > 0) {
    if (len < buflen)
      buflen = len;
    if (write_out_data(outfile, buf, buflen, css))
      return -1;
    len -= buflen;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_out_padding>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%esi
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x800,%edx
  call   <memset@plt>
  test   %rbp,%rbp
  je     L9
  mov    $0x800,%ebx
  mov    %rsp,%r14
L1:
  cmp    %rbp,%rbx
  cmova  %rbp,%rbx
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <write_out_data@plt>
  test   %rax,%rax
  jne    L11
  sub    %rbx,%rbp
  jne    L1
  jmp    L58
L9:
  mov    $0x0,%eax
  jmp    L58
L11:
  mov    $0xffffffff,%eax
L58:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_out_padding(FILE *outfile, size_t len, uint8_t padc, struct csum_state *css) {
  uint8_t buf[512];
  size_t buflen = sizeof(buf);
  memset(buf, padc, buflen);
  while (len > 0) {
    if (len < buflen)
      buflen = len;
    if (write_out_data(outfile, buf, buflen, css))
      return -1;
    len -= buflen;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_out_padding>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  mov    $0x800,%edx
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memset@plt>
  test   %rbp,%rbp
  je     L22
  mov    $0x800,%ebx
  jmp    L56
  nopl   (%rax)
L18:
  sub    %rbx,%rbp
  je     L22
L56:
  cmp    %rbp,%rbx
  mov    %r13,%rcx
  mov    %r14,%rsi
  mov    %r12,%rdi
  cmova  %rbp,%rbx
  mov    %rbx,%rdx
  call   <write_out_data@plt>
  test   %rax,%rax
  je     L18
  mov    $0xffffffff,%eax
  jmp    L53
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
L53:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_out_padding(FILE *outfile, size_t len, uint8_t padc, struct csum_state *css) {
  uint8_t buf[512];
  size_t buflen = sizeof(buf);
  memset(buf, padc, buflen);
  while (len > 0) {
    if (len < buflen)
      buflen = len;
    if (write_out_data(outfile, buf, buflen, css))
      return -1;
    len -= buflen;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_out_padding>:
  endbr64
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  mov    $0x800,%edx
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <memset@plt>
  test   %rbp,%rbp
  je     L55
  mov    $0x800,%ebx
  jmp    L18
  nopl   (%rax)
L47:
  sub    %rbx,%rbp
  je     L55
L18:
  cmp    %rbp,%rbx
  mov    %r13,%rcx
  mov    %r14,%rsi
  mov    %r12,%rdi
  cmova  %rbp,%rbx
  mov    %rbx,%rdx
  call   <write_out_data@plt>
  test   %rax,%rax
  je     L47
  mov    $0xffffffff,%eax
  jmp    L40
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
L40:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L51
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_out_padding(FILE *outfile, size_t len, uint8_t padc, struct csum_state *css) {
  uint8_t buf[512];
  size_t buflen = sizeof(buf);
  memset(buf, padc, buflen);
  while (len > 0) {
    if (len < buflen)
      buflen = len;
    if (write_out_data(outfile, buf, buflen, css))
      return -1;
    len -= buflen;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  lea    -0xc(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    $0x0,%eax
  call   <clearStdinBuf@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int getInput() {
  int cmd = -1;
  char cmdBuf[4];
  fgets(cmdBuf, 2, stdin);
  clearStdinBuf();
  cmd = (int)cmdBuf[0];
  return cmd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getInput>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0x2,%esi
  call   <fgets@plt>
  mov    $0x0,%eax
  call   <clearStdinBuf@plt>
  movsbl 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput() {
  int cmd = -1;
  char cmdBuf[4];
  fgets(cmdBuf, 2, stdin);
  clearStdinBuf();
  cmd = (int)cmdBuf[0];
  return cmd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getInput>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  xor    %eax,%eax
  call   <clearStdinBuf@plt>
  movsbl 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput() {
  int cmd = -1;
  char cmdBuf[4];
  fgets(cmdBuf, 2, stdin);
  clearStdinBuf();
  cmd = (int)cmdBuf[0];
  return cmd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getInput>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x4(%rsp),%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  xor    %eax,%eax
  call   <clearStdinBuf@plt>
  movsbl 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getInput() {
  int cmd = -1;
  char cmdBuf[4];
  fgets(cmdBuf, 2, stdin);
  clearStdinBuf();
  cmd = (int)cmdBuf[0];
  return cmd;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<longshr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  nop
  cmpl   $0x0,-0x20(%rbp)
  jle    L54
  cmpl   $0x7,-0x20(%rbp)
  jg     L45
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  cltq
  mov    %rax,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    $0x8,%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  or     -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  subq   $0x1,-0x8(%rbp)
  jmp    L34
L45:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L29
L20:
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subq   $0x1,-0x8(%rbp)
L29:
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  subl   $0x8,-0x20(%rbp)
  jmp    L23
L54:
  nop
L23:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void longshr(uint8_t num[], uint8_t len, uint8_t bits) {
  int8_t i;
  uint8_t temp;
  while (bits > 0) {
    if (bits < 8) {
      num[len - 1] >>= bits;
      for (i = len - 2; i >= 0; i--) {
        temp = num[i] << (8 - bits);
        num[i] >>= bits;
        num[i + 1] |= temp;
      }
      bits = 0;
    } else {
      for (i = len - 1; i > 0; i--)
        num[i] = num[i - 1];
      num[0] = 0;
      bits -= 8;
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<longshr>:
  endbr64
  test   %edx,%edx
  jle    L37
  cmp    $0x7,%edx
  jg     L26
  movslq %esi,%rax
  mov    %edx,%ecx
  sarl   %cl,-0x4(%rdi,%rax,4)
  sub    $0x2,%esi
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  mov    $0x8,%r8d
  sub    %edx,%r8d
L42:
  mov    (%rax),%esi
  mov    %esi,%edi
  mov    %edx,%ecx
  sar    %cl,%edi
  mov    %edi,(%rax)
  mov    %r8d,%ecx
  shl    %cl,%esi
  or     %esi,0x4(%rax)
  sub    $0x4,%rax
  jmp    L42
L26:
  sub    $0x1,%esi
  movslq %esi,%rax
  test   %rax,%rax
  je     L28
L8:
  mov    -0x4(%rdi,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  sub    $0x1,%rax
  jne    L8
L28:
  movl   $0x0,(%rdi)
L37:
  ret
```

assistant: ```c
void longshr(uint8_t num[], uint8_t len, uint8_t bits) {
  int8_t i;
  uint8_t temp;
  while (bits > 0) {
    if (bits < 8) {
      num[len - 1] >>= bits;
      for (i = len - 2; i >= 0; i--) {
        temp = num[i] << (8 - bits);
        num[i] >>= bits;
        num[i + 1] |= temp;
      }
      bits = 0;
    } else {
      for (i = len - 1; i > 0; i--)
        num[i] = num[i - 1];
      num[0] = 0;
      bits -= 8;
      break;
    }
  }
}
```