ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmp_long_asc>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int cmp_long_asc(const void *x, const void *y) {
  if (*(long *)x < *(long *)y) {
    return -1;
  } else if (*(long *)x > *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmp_long_asc>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int cmp_long_asc(const void *x, const void *y) {
  if (*(long *)x < *(long *)y) {
    return -1;
  } else if (*(long *)x > *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void fatal(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal(char *msg) {
  perror(msg);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fatal(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fatal(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int i) {
  switch (i) {
#pragma acc parallel
    { case 0:; }
  }
  switch (i) {
#pragma acc kernels
    { case 0:; }
  }
  switch (i) {
#pragma acc data
    { case 0:; }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int i) {
  switch (i) {
#pragma acc parallel
    { case 0:; }
  }
  switch (i) {
#pragma acc kernels
    { case 0:; }
  }
  switch (i) {
#pragma acc data
    { case 0:; }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int i) {
  switch (i) {
#pragma acc parallel
    { case 0:; }
  }
  switch (i) {
#pragma acc kernels
    { case 0:; }
  }
  switch (i) {
#pragma acc data
    { case 0:; }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(int i) {
  switch (i) {
#pragma acc parallel
    { case 0:; }
  }
  switch (i) {
#pragma acc kernels
    { case 0:; }
  }
  switch (i) {
#pragma acc data
    { case 0:; }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_731>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_731(void *pnt) {
  unsigned char *p = (unsigned char *)pnt;
  return ((unsigned int)p[0]) + ((unsigned int)p[1] << 8) + ((unsigned int)p[2] << 16) + ((unsigned int)p[3] << 24);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_731>:
  endbr64
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int get_731(void *pnt) {
  unsigned char *p = (unsigned char *)pnt;
  return ((unsigned int)p[0]) + ((unsigned int)p[1] << 8) + ((unsigned int)p[2] << 16) + ((unsigned int)p[3] << 24);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_731>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int get_731(void *pnt) {
  unsigned char *p = (unsigned char *)pnt;
  return ((unsigned int)p[0]) + ((unsigned int)p[1] << 8) + ((unsigned int)p[2] << 16) + ((unsigned int)p[3] << 24);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_731>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int get_731(void *pnt) {
  unsigned char *p = (unsigned char *)pnt;
  return ((unsigned int)p[0]) + ((unsigned int)p[1] << 8) + ((unsigned int)p[2] << 16) + ((unsigned int)p[3] << 24);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<badch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L45
  cmpq   $0x23,-0x30(%rbp)
  ja     L13
L45:
  lea    D5(%rip),%rax
  jmp    L48
L13:
  mov    -0x28(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0xfffffffc,%eax
  sub    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  movsbl -0xe(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L25
  movzbl -0xe(%rbp),%eax
  mov    %al,-0xd(%rbp)
  movb   $0x0,-0xc(%rbp)
  jmp    L38
L25:
  movb   $0x5c,-0xd(%rbp)
  movsbl -0xe(%rbp),%eax
  sar    $0x6,%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,-0xc(%rbp)
  movsbl -0xe(%rbp),%eax
  sar    $0x3,%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,-0xb(%rbp)
  movzbl -0xe(%rbp),%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
L38:
  lea    -0xd(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
  lea    D24(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x28(%rbp),%rax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: D5: unknown character in input

tool: D28: unknown character (`

tool: D24: ') in input

assistant: ```c
const char *badch(const char *src, int errcode, char *errp, size_t errlen) {
  static const char pre[] = "unknown character (`";
  static const char suf[] = "') in input";
  char buf[5];
  struct sizecheck {
    char bigenough[40 - (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf))];
  };
  char ch;
  if (errp == NULL || errlen < (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf)))
    return "unknown character in input";
  strcpy(errp, pre);
  ch = *(src + ((-4) - (errcode)));
  if (isprint(ch)) {
    buf[0] = ch;
    buf[1] = '\0';
  } else {
    buf[0] = '\\';
    buf[1] = ((ch & 0700) >> 6) + '0';
    buf[2] = ((ch & 0070) >> 3) + '0';
    buf[3] = ((ch & 0007) >> 0) + '0';
    buf[4] = '\0';
  }
  strcat(errp, buf);
  strcat(errp, suf);
  return (const char *)errp;
}
```
user: What is the c source code of the assembly code below:

```asm
<badch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L15
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  cmp    $0x23,%rcx
  jbe    L15
  lea    D3(%rip),%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    $0xfffffffc,%eax
  sub    %r12d,%eax
  cltq
  movzbl 0x0(%rbp,%rax,1),%r12d
  movsbl %r12b,%ebp
  mov    %ebp,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L49
  mov    %r12b,0x3(%rsp)
  movb   $0x0,0x4(%rsp)
L1:
  lea    0x3(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  jmp    L41
L49:
  movb   $0x5c,0x3(%rsp)
  mov    %ebp,%eax
  sar    $0x6,%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,0x4(%rsp)
  sar    $0x3,%ebp
  and    $0x7,%ebp
  add    $0x30,%ebp
  mov    %bpl,0x5(%rsp)
  and    $0x7,%r12d
  add    $0x30,%r12d
  mov    %r12b,0x6(%rsp)
  movb   $0x0,0x7(%rsp)
  jmp    L1
L15:
  lea    D28(%rip),%rax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string

tool: D3: unknown character (`

tool: D14: ') in input

tool: D28: unknown character in input

assistant: ```c
const char *badch(const char *src, int errcode, char *errp, size_t errlen) {
  static const char pre[] = "unknown character (`";
  static const char suf[] = "') in input";
  char buf[5];
  struct sizecheck {
    char bigenough[40 - (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf))];
  };
  char ch;
  if (errp == NULL || errlen < (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf)))
    return "unknown character in input";
  strcpy(errp, pre);
  ch = *(src + ((-4) - (errcode)));
  if (isprint(ch)) {
    buf[0] = ch;
    buf[1] = '\0';
  } else {
    buf[0] = '\\';
    buf[1] = ((ch & 0700) >> 6) + '0';
    buf[2] = ((ch & 0070) >> 3) + '0';
    buf[3] = ((ch & 0007) >> 0) + '0';
    buf[4] = '\0';
  }
  strcat(errp, buf);
  strcat(errp, suf);
  return (const char *)errp;
}
```
user: What is the c source code of the assembly code below?

```asm
<badch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L35
  cmp    $0x23,%rcx
  jbe    L35
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rdi
  mov    %rdx,%rbx
  lea    D14(%rip),%rsi
  call   <strcpy@plt>
  mov    $0xfffffffc,%eax
  sub    %ebp,%eax
  cltq
  movsbl (%r12,%rax,1),%ebp
  mov    %ebp,%edi
  mov    %ebp,%r12d
  call   <isprint@plt>
  test   %rax,%rax
  je     L17
  mov    %bpl,0x3(%rsp)
  movb   $0x0,0x4(%rsp)
L29:
  lea    0x3(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L35:
  lea    D8(%rip),%rax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %ebp,%eax
  sar    $0x3,%ebp
  and    $0x7,%r12d
  movb   $0x5c,0x3(%rsp)
  sar    $0x6,%eax
  and    $0x7,%ebp
  add    $0x30,%r12d
  movb   $0x0,0x7(%rsp)
  and    $0x7,%eax
  add    $0x30,%ebp
  mov    %r12b,0x6(%rsp)
  add    $0x30,%eax
  mov    %bpl,0x5(%rsp)
  mov    %al,0x4(%rsp)
  jmp    L29
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D24
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D14: unknown character (`

tool: D24: ') in input

tool: D8: unknown character in input

assistant: ```c
const char *badch(const char *src, int errcode, char *errp, size_t errlen) {
  static const char pre[] = "unknown character (`";
  static const char suf[] = "') in input";
  char buf[5];
  struct sizecheck {
    char bigenough[40 - (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf))];
  };
  char ch;
  if (errp == NULL || errlen < (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf)))
    return "unknown character in input";
  strcpy(errp, pre);
  ch = *(src + ((-4) - (errcode)));
  if (isprint(ch)) {
    buf[0] = ch;
    buf[1] = '\0';
  } else {
    buf[0] = '\\';
    buf[1] = ((ch & 0700) >> 6) + '0';
    buf[2] = ((ch & 0070) >> 3) + '0';
    buf[3] = ((ch & 0007) >> 0) + '0';
    buf[4] = '\0';
  }
  strcat(errp, buf);
  strcat(errp, suf);
  return (const char *)errp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<badch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L17
  cmp    $0x23,%rcx
  jbe    L17
  mov    %esi,%ebp
  mov    %rdi,%r12
  lea    D21(%rip),%rsi
  mov    %rdx,%rdi
  mov    %rdx,%rbx
  call   <strcpy@plt>
  mov    $0xfffffffc,%eax
  sub    %ebp,%eax
  cltq
  movsbl (%r12,%rax,1),%r12d
  mov    %r12d,%edi
  mov    %r12d,%ebp
  call   <isprint@plt>
  xor    %edx,%edx
  test   %rax,%rax
  jne    L20
  mov    %r12d,%edx
  sar    $0x3,%r12d
  and    $0x7,%ebp
  xor    %ecx,%ecx
  and    $0x7,%r12d
  lea    0x30(%rbp),%eax
  sar    $0x6,%edx
  movb   $0x0,0x6(%rsp)
  add    $0x30,%r12d
  and    $0x7,%edx
  mov    $0x5c,%ebp
  mov    %r12b,%cl
  add    $0x30,%edx
  mov    %al,%ch
  mov    %cx,0x4(%rsp)
L20:
  xor    %eax,%eax
  lea    0x2(%rsp),%rsi
  mov    %rbx,%rdi
  mov    %bpl,%al
  mov    %dl,%ah
  mov    %ax,0x2(%rsp)
  call   <strcat@plt>
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L17:
  lea    D11(%rip),%rax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D21: unknown character (`

tool: D22: ') in input

tool: D11: unknown character in input

assistant: ```c
const char *badch(const char *src, int errcode, char *errp, size_t errlen) {
  static const char pre[] = "unknown character (`";
  static const char suf[] = "') in input";
  char buf[5];
  struct sizecheck {
    char bigenough[40 - (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf))];
  };
  char ch;
  if (errp == NULL || errlen < (sizeof(pre) - 1 + sizeof(buf) - 1 + sizeof(suf)))
    return "unknown character in input";
  strcpy(errp, pre);
  ch = *(src + ((-4) - (errcode)));
  if (isprint(ch)) {
    buf[0] = ch;
    buf[1] = '\0';
  } else {
    buf[0] = '\\';
    buf[1] = ((ch & 0700) >> 6) + '0';
    buf[2] = ((ch & 0070) >> 3) + '0';
    buf[3] = ((ch & 0007) >> 0) + '0';
    buf[4] = '\0';
  }
  strcat(errp, buf);
  strcat(errp, suf);
  return (const char *)errp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<blasDSCAL>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%rdi
  test   %ecx,%ecx
  jle    L5
  cmp    $0x1,%edx
  je     L40
  mov    $0x0,%eax
  test   %edx,%edx
  js     L24
L51:
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rsi
  cltq
  lea    (%rdi,%rax,8),%rax
  mov    $0x0,%edx
L87:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x1,%edx
  add    %rsi,%rax
  cmp    %edx,%ecx
  jne    L87
L5:
  ret
L40:
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L52
  mov    %rsi,%rax
  lea    -0x1(%rdx),%esi
  lea    0x8(%rdi,%rsi,8),%rsi
L23:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L23
L52:
  cmp    %edx,%ecx
  jle    L5
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%rax
L60:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x8(%rax),%xmm1
  movsd  %xmm1,0x8(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x10(%rax),%xmm1
  movsd  %xmm1,0x10(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x18(%rax),%xmm1
  movsd  %xmm1,0x18(%rax)
  movapd %xmm0,%xmm1
  mulsd  0x20(%rax),%xmm1
  movsd  %xmm1,0x20(%rax)
  add    $0x5,%edx
  add    $0x28,%rax
  cmp    %edx,%ecx
  jg     L60
  ret
L24:
  mov    $0x1,%eax
  sub    %ecx,%eax
  imul   %edx,%eax
  jmp    L51
```

assistant: ```c
void blasDSCAL(int n, double sa, double x[], int incx) {
  int i, ix, m;
  if (n <= 0) {
  } else if (incx == 1) {
    m = n % 5;
    for (i = 0; i < m; i++) {
      x[i] = sa * x[i];
    }
    for (i = m; i < n; i = i + 5) {
      x[i] = sa * x[i];
      x[i + 1] = sa * x[i + 1];
      x[i + 2] = sa * x[i + 2];
      x[i + 3] = sa * x[i + 3];
      x[i + 4] = sa * x[i + 4];
    }
  } else {
    if (0 <= incx) {
      ix = 0;
    } else {
      ix = (-n + 1) * incx;
    }
    for (i = 0; i < n; i++) {
      x[ix] = sa * x[ix];
      ix = ix + incx;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<blasDSCAL>:
  endbr64
  mov    %edi,%ecx
  mov    %rsi,%rdi
  test   %ecx,%ecx
  jle    L33
  cmp    $0x1,%edx
  je     L62
  xor    %eax,%eax
  test   %edx,%edx
  jns    L8
  mov    $0x1,%eax
  sub    %ecx,%eax
  imul   %edx,%eax
L8:
  movslq %edx,%rdx
  cltq
  lea    0x0(,%rdx,8),%rsi
  lea    (%rdi,%rax,8),%rax
  xor    %edx,%edx
  nopl   (%rax)
L70:
  movsd  (%rax),%xmm1
  add    $0x1,%edx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
  add    %rsi,%rax
  cmp    %edx,%ecx
  jne    L70
L33:
  ret
  nop
L62:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x21,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L79
  mov    %rsi,%rax
  lea    -0x1(%rdx),%esi
  lea    0x8(%rdi,%rsi,8),%rsi
L43:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L43
  cmp    %edx,%ecx
  jle    L33
L79:
  movslq %edx,%rax
  lea    (%rdi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L30:
  movsd  (%rax),%xmm1
  add    $0x5,%edx
  add    $0x28,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x28(%rax)
  movsd  -0x20(%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rax)
  movsd  -0x18(%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x18(%rax)
  movsd  -0x10(%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rax)
  movsd  -0x8(%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %edx,%ecx
  jg     L30
  ret
```

assistant: ```c
void blasDSCAL(int n, double sa, double x[], int incx) {
  int i, ix, m;
  if (n <= 0) {
  } else if (incx == 1) {
    m = n % 5;
    for (i = 0; i < m; i++) {
      x[i] = sa * x[i];
    }
    for (i = m; i < n; i = i + 5) {
      x[i] = sa * x[i];
      x[i + 1] = sa * x[i + 1];
      x[i + 2] = sa * x[i + 2];
      x[i + 3] = sa * x[i + 3];
      x[i + 4] = sa * x[i + 4];
    }
  } else {
    if (0 <= incx) {
      ix = 0;
    } else {
      ix = (-n + 1) * incx;
    }
    for (i = 0; i < n; i++) {
      x[ix] = sa * x[ix];
      ix = ix + incx;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pkey_get_eckey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L10
L49:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_get1_EC_KEY@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_free@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L10
L29:
  cmpq   $0x0,-0x20(%rbp)
  je     L20
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <EC_KEY_free@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L20:
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
EC_KEY *pkey_get_eckey(EVP_PKEY *key, EC_KEY **eckey) {
  EC_KEY *dtmp;
  if (!key)
    return NULL;
  dtmp = EVP_PKEY_get1_EC_KEY(key);
  EVP_PKEY_free(key);
  if (!dtmp)
    return NULL;
  if (eckey) {
    EC_KEY_free(*eckey);
    *eckey = dtmp;
  }
  return dtmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pkey_get_eckey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L19
  mov    %rsi,%r12
  call   <EVP_PKEY_get1_EC_KEY@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <EVP_PKEY_free@plt>
  test   %rbp,%rbp
  je     L0
  test   %r12,%r12
  je     L0
  mov    (%r12),%rdi
  call   <EC_KEY_free@plt>
  mov    %rbp,(%r12)
L0:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rdi,%rbp
  jmp    L0
```

assistant: ```c
EC_KEY *pkey_get_eckey(EVP_PKEY *key, EC_KEY **eckey) {
  EC_KEY *dtmp;
  if (!key)
    return NULL;
  dtmp = EVP_PKEY_get1_EC_KEY(key);
  EVP_PKEY_free(key);
  if (!dtmp)
    return NULL;
  if (eckey) {
    EC_KEY_free(*eckey);
    *eckey = dtmp;
  }
  return dtmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pkey_get_eckey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L4
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <EVP_PKEY_get1_EC_KEY@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_PKEY_free@plt>
  test   %r12,%r12
  je     L4
  test   %rbx,%rbx
  je     L6
  mov    (%rbx),%rdi
  call   <EC_KEY_free@plt>
  mov    %r12,(%rbx)
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
EC_KEY *pkey_get_eckey(EVP_PKEY *key, EC_KEY **eckey) {
  EC_KEY *dtmp;
  if (!key)
    return NULL;
  dtmp = EVP_PKEY_get1_EC_KEY(key);
  EVP_PKEY_free(key);
  if (!dtmp)
    return NULL;
  if (eckey) {
    EC_KEY_free(*eckey);
    *eckey = dtmp;
  }
  return dtmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pkey_get_eckey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L18
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <EVP_PKEY_get1_EC_KEY@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_PKEY_free@plt>
  test   %r12,%r12
  je     L18
  test   %rbx,%rbx
  je     L27
  mov    (%rbx),%rdi
  call   <EC_KEY_free@plt>
  mov    %r12,(%rbx)
L27:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
EC_KEY *pkey_get_eckey(EVP_PKEY *key, EC_KEY **eckey) {
  EC_KEY *dtmp;
  if (!key)
    return NULL;
  dtmp = EVP_PKEY_get1_EC_KEY(key);
  EVP_PKEY_free(key);
  if (!dtmp)
    return NULL;
  if (eckey) {
    EC_KEY_free(*eckey);
    *eckey = dtmp;
  }
  return dtmp;
}
```