ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_unrealize_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x7,%edx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L16
  lea    0x7(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x6,%edx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L34
  lea    0x6(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L6
L34:
  mov    $0x5,%edx
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L50
  lea    0x5(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L6
L50:
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D17
type_guessed: string
name: retrieve_data
arguments: data_tag: D22
type_guessed: string

tool: D15: struct 

tool: D6: union 

tool: D17: enum 

tool: D22: $

assistant: ```c
void _unrealize_name(char *target, const char *srcname) {
  if (strncmp(srcname, "struct ", 7) == 0) {
    strcpy(target, &srcname[7]);
  } else if (strncmp(srcname, "union ", 6) == 0) {
    strcpy(target, &srcname[6]);
  } else if (strncmp(srcname, "enum ", 5) == 0) {
    strcpy(target, &srcname[5]);
  } else {
    strcpy(target, "$");
    strcat(target, srcname);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_unrealize_name>:
  endbr64
  push   %r12
  mov    $0x7,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strncmp@plt>
  lea    0x7(%rbp),%rsi
  test   %rax,%rax
  je     L17
  mov    $0x6,%edx
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L24
  lea    0x6(%rbp),%rsi
L17:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D23(%rip),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <strncmp@plt>
  lea    0x5(%rbp),%rsi
  test   %rax,%rax
  je     L17
  mov    %r12,%rdi
  lea    D28(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <strcat@plt>
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D32
datatype: string
name: parse_data
arguments: label: D23
datatype: string
name: parse_data
arguments: label: D28
datatype: string

tool: D14: struct 

tool: D32: union 

tool: D23: enum 

tool: D28: $

assistant: ```c
void _unrealize_name(char *target, const char *srcname) {
  if (strncmp(srcname, "struct ", 7) == 0) {
    strcpy(target, &srcname[7]);
  } else if (strncmp(srcname, "union ", 6) == 0) {
    strcpy(target, &srcname[6]);
  } else if (strncmp(srcname, "enum ", 5) == 0) {
    strcpy(target, &srcname[5]);
  } else {
    strcpy(target, "$");
    strcat(target, srcname);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_unrealize_name>:
  endbr64
  push   %r12
  mov    $0x7,%edx
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D36(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strncmp@plt>
  lea    0x7(%rbp),%rsi
  test   %rax,%rax
  je     L28
  mov    $0x6,%edx
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L14
  lea    0x6(%rbp),%rsi
L28:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  lea    D26(%rip),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <strncmp@plt>
  lea    0x5(%rbp),%rsi
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  lea    D13(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <strcat@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D36
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D36: struct 

tool: D12: union 

tool: D26: enum 

tool: D13: $

assistant: ```c
void _unrealize_name(char *target, const char *srcname) {
  if (strncmp(srcname, "struct ", 7) == 0) {
    strcpy(target, &srcname[7]);
  } else if (strncmp(srcname, "union ", 6) == 0) {
    strcpy(target, &srcname[6]);
  } else if (strncmp(srcname, "enum ", 5) == 0) {
    strcpy(target, &srcname[5]);
  } else {
    strcpy(target, "$");
    strcat(target, srcname);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<containsForbiddenChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L41
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jbe    L14
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jbe    L35
L14:
  mov    $0x1,%eax
  jmp    L4
L35:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L41:
  cmpl   $0x0,-0xc(%rbp)
  jg     L32
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int containsForbiddenChars(const unsigned char *p, int len) {
  while (len > 0) {
    if (*p < ' ' || *p >= '\x7f')
      return 1;
    p++;
    len--;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<containsForbiddenChars>:
  endbr64
  test   %esi,%esi
  jle    L14
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rdx
L9:
  movzbl (%rdi),%eax
  sub    $0x20,%eax
  cmp    $0x5e,%al
  ja     L7
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L9
  mov    $0x0,%eax
  ret
L14:
  mov    $0x0,%eax
  ret
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int containsForbiddenChars(const unsigned char *p, int len) {
  while (len > 0) {
    if (*p < ' ' || *p >= '\x7f')
      return 1;
    p++;
    len--;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<containsForbiddenChars>:
  endbr64
  test   %esi,%esi
  jle    L37
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rdx
  jmp    L34
  nopl   0x0(%rax)
L31:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L37
L34:
  movzbl (%rdi),%eax
  sub    $0x20,%eax
  cmp    $0x5e,%al
  jbe    L31
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
int containsForbiddenChars(const unsigned char *p, int len) {
  while (len > 0) {
    if (*p < ' ' || *p >= '\x7f')
      return 1;
    p++;
    len--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<containsForbiddenChars>:
  endbr64
  test   %esi,%esi
  jle    L35
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rdx
  jmp    L38
  nopl   0x0(%rax)
L0:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L35
L38:
  movzbl (%rdi),%eax
  sub    $0x20,%eax
  cmp    $0x5e,%al
  jbe    L0
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int containsForbiddenChars(const unsigned char *p, int len) {
  while (len > 0) {
    if (*p < ' ' || *p >= '\x7f')
      return 1;
    p++;
    len--;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L81
  mov    $0x0,%eax
  jmp    L108
L81:
  cmpl   $0x3,-0x14(%rbp)
  jg     L37
  mov    $0x1,%eax
  jmp    L108
L37:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L19
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L4
L19:
  mov    $0x0,%eax
  jmp    L108
L4:
  movl   $0x5,-0x4(%rbp)
  jmp    L102
L69:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L45
  mov    -0x4(%rbp),%eax
  lea    0x2(%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
L45:
  mov    $0x0,%eax
  jmp    L108
L24:
  addl   $0x6,-0x4(%rbp)
L102:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L69
  mov    $0x1,%eax
L108:
  pop    %rbp
  ret
```

assistant: ```c
int isPrime(int number) {
  if (number <= 1)
    return 0;
  else if (number <= 3)
    return 1;
  else if (number % 2 == 0 || number % 3 == 0)
    return 0;
  int i = 5;
  while (i * i <= number) {
    if (number % i == 0 || number % (i + 2) == 0)
      return 0;
    i += 6;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L0
  mov    $0x1,%eax
  cmp    $0x3,%edi
  jle    L0
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L0
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L0
  cmp    $0x18,%edi
  jle    L81
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L0
  movslq %edi,%rax
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x2,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,8),%edx
  sub    %eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L0
  mov    $0x5,%esi
L62:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jg     L19
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  je     L0
  add    $0x8,%edi
  mov    %ecx,%eax
  cltd
  idiv   %edi
  mov    %edx,%eax
  test   %edx,%edx
  jne    L62
L0:
  ret
L19:
  mov    $0x1,%eax
  ret
L81:
  mov    $0x1,%eax
  jmp    L0
```

assistant: ```c
int isPrime(int number) {
  if (number <= 1)
    return 0;
  else if (number <= 3)
    return 1;
  else if (number % 2 == 0 || number % 3 == 0)
    return 0;
  int i = 5;
  while (i * i <= number) {
    if (number % i == 0 || number % (i + 2) == 0)
      return 0;
    i += 6;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L67
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L67
  xor    %edx,%edx
  test   $0x1,%dil
  je     L67
  movslq %edi,%rax
  mov    %edi,%esi
  imul   $0x55555556,%rax,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L67
  cmp    $0x18,%ecx
  jle    L45
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L67
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %esi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L67
  mov    $0x5,%esi
  jmp    L21
  nopl   (%rax)
L85:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L67
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L67
L21:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L85
L45:
  mov    $0x1,%edx
L67:
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int number) {
  if (number <= 1)
    return 0;
  else if (number <= 3)
    return 1;
  else if (number % 2 == 0 || number % 3 == 0)
    return 0;
  int i = 5;
  while (i * i <= number) {
    if (number % i == 0 || number % (i + 2) == 0)
      return 0;
    i += 6;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isPrime>:
  endbr64
  mov    %edi,%ecx
  xor    %edx,%edx
  cmp    $0x1,%edi
  jle    L49
  mov    $0x1,%edx
  cmp    $0x3,%edi
  jle    L49
  xor    %edx,%edx
  test   $0x1,%dil
  je     L49
  movslq %edi,%rax
  mov    %edi,%esi
  imul   $0x55555556,%rax,%rdx
  sar    $0x1f,%esi
  shr    $0x20,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,2),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L49
  cmp    $0x18,%ecx
  jle    L35
  imul   $0x66666667,%rax,%rdx
  sar    $0x21,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  mov    %ecx,%edx
  sub    %edi,%edx
  je     L49
  imul   $0xffffffff92492493,%rax,%rax
  shr    $0x20,%rax
  lea    (%rcx,%rax,1),%edx
  sar    $0x2,%edx
  sub    %esi,%edx
  lea    0x0(,%rdx,8),%eax
  sub    %edx,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  je     L49
  mov    $0x5,%esi
  jmp    L78
  nopl   (%rax)
L22:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L49
  mov    %ecx,%eax
  add    $0x8,%edi
  cltd
  idiv   %edi
  test   %edx,%edx
  je     L49
L78:
  mov    %esi,%edi
  add    $0x6,%esi
  mov    %esi,%eax
  imul   %esi,%eax
  cmp    %ecx,%eax
  jle    L22
L35:
  mov    $0x1,%edx
L49:
  mov    %edx,%eax
  ret
```

assistant: ```c
int isPrime(int number) {
  if (number <= 1)
    return 0;
  else if (number <= 3)
    return 1;
  else if (number % 2 == 0 || number % 3 == 0)
    return 0;
  int i = 5;
  while (i * i <= number) {
    if (number % i == 0 || number % (i + 2) == 0)
      return 0;
    i += 6;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<mat_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L15
L18:
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L31:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L4:
  mov    -0x2c(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mat_get@plt>
  movss  %xmm0,-0x30(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <mat_get@plt>
  mulss  -0x30(%rbp),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  mov    -0x2c(%rbp),%ecx
  mov    -0x4(%rbp),%edi
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x28(%rbp),%rax
  movd   %edi,%xmm0
  mov    %rax,%rdi
  call   <mat_set@plt>
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L31
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void mat_mult(const float *a, const float *b, float *r, int n) {
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++) {
      float sum = 0.0f;
      for (k = 0; k < n; k++) {
        sum += mat_get(a, i, k, n) * mat_get(b, k, j, n);
      }
      mat_set(r, i, j, sum, n);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mat_mult>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%ebp
  mov    $0x0,%r13d
  test   %ecx,%ecx
  jg     L33
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  lea    0x1(%r13),%eax
  cmp    0x4(%rsp),%r13d
  je     L27
  mov    %eax,%r13d
L33:
  mov    $0x0,%r12d
L19:
  pxor   %xmm3,%xmm3
  movss  %xmm3,(%rsp)
  mov    $0x0,%ebx
L6:
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <mat_get@plt>
  movss  %xmm0,0x4(%rsp)
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <mat_get@plt>
  mulss  0x4(%rsp),%xmm0
  addss  (%rsp),%xmm0
  movss  %xmm0,(%rsp)
  mov    %ebx,0x4(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L6
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    0x8(%rsp),%rdi
  call   <mat_set@plt>
  lea    0x1(%r12),%eax
  cmp    0x4(%rsp),%r12d
  je     L13
  mov    %eax,%r12d
  jmp    L19
```

assistant: ```c
void mat_mult(const float *a, const float *b, float *r, int n) {
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++) {
      float sum = 0.0f;
      for (k = 0; k < n; k++) {
        sum += mat_get(a, i, k, n) * mat_get(b, k, j, n);
      }
      mat_set(r, i, j, sum, n);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat_mult>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %ecx,%ecx
  jle    L27
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %ecx,%r15d
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L15:
  pxor   %xmm1,%xmm1
  xor    %ebx,%ebx
  xchg   %ax,%ax
L10:
  mov    %ebx,%edx
  mov    %r15d,%ecx
  mov    %ebp,%esi
  mov    %r14,%rdi
  movss  %xmm1,0x4(%rsp)
  call   <mat_get@plt>
  mov    %ebx,%esi
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  movss  %xmm0,(%rsp)
  call   <mat_get@plt>
  mulss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  mov    %ebx,%r8d
  add    $0x1,%ebx
  addss  %xmm0,%xmm1
  cmp    %ebx,%r15d
  jne    L10
  mov    0x8(%rsp),%rdi
  mov    %r15d,%ecx
  movaps %xmm1,%xmm0
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r8d,(%rsp)
  call   <mat_set@plt>
  mov    (%rsp),%r8d
  lea    0x1(%rbp),%eax
  cmp    %r8d,%ebp
  je     L39
  mov    %eax,%ebp
  jmp    L15
  nopl   (%rax)
L39:
  lea    0x1(%r12),%eax
  cmp    %ebp,%r12d
  je     L27
  mov    %eax,%r12d
  jmp    L16
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mat_mult(const float *a, const float *b, float *r, int n) {
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++) {
      float sum = 0.0f;
      for (k = 0; k < n; k++) {
        sum += mat_get(a, i, k, n) * mat_get(b, k, j, n);
      }
      mat_set(r, i, j, sum, n);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mat_mult>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %ecx,%ecx
  jle    L31
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %ecx,%r15d
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L8:
  pxor   %xmm1,%xmm1
  xor    %ebx,%ebx
  xchg   %ax,%ax
L19:
  mov    %ebx,%edx
  mov    %r15d,%ecx
  mov    %ebp,%esi
  mov    %r14,%rdi
  movss  %xmm1,0x4(%rsp)
  call   <mat_get@plt>
  mov    %ebx,%esi
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %r13,%rdi
  movss  %xmm0,(%rsp)
  call   <mat_get@plt>
  mulss  (%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  mov    %ebx,%r8d
  add    $0x1,%ebx
  addss  %xmm0,%xmm1
  cmp    %ebx,%r15d
  jne    L19
  mov    0x8(%rsp),%rdi
  mov    %r15d,%ecx
  movaps %xmm1,%xmm0
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r8d,(%rsp)
  call   <mat_set@plt>
  mov    (%rsp),%r8d
  lea    0x1(%rbp),%eax
  cmp    %r8d,%ebp
  je     L44
  mov    %eax,%ebp
  jmp    L8
  nopl   (%rax)
L44:
  lea    0x1(%r12),%eax
  cmp    %ebp,%r12d
  je     L31
  mov    %eax,%r12d
  jmp    L34
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mat_mult(const float *a, const float *b, float *r, int n) {
  int i, j, k;
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++) {
      float sum = 0.0f;
      for (k = 0; k < n; k++) {
        sum += mat_get(a, i, k, n) * mat_get(b, k, j, n);
      }
      mat_set(r, i, j, sum, n);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<IcsIsLittleEndianMachine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int IcsIsLittleEndianMachine(void) {
  int i = 1;
  char *cptr = (char *)&i;
  return (*cptr == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<IcsIsLittleEndianMachine>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IcsIsLittleEndianMachine(void) {
  int i = 1;
  char *cptr = (char *)&i;
  return (*cptr == 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<IcsIsLittleEndianMachine>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IcsIsLittleEndianMachine(void) {
  int i = 1;
  char *cptr = (char *)&i;
  return (*cptr == 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IcsIsLittleEndianMachine>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int IcsIsLittleEndianMachine(void) {
  int i = 1;
  char *cptr = (char *)&i;
  return (*cptr == 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pspnxController>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  D29(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L8
  movss  -0x4(%rbp),%xmm0
  movss  D29(%rip),%xmm1
  divss  %xmm1,%xmm0
  jmp    L10
L8:
  movss  -0x4(%rbp),%xmm0
  movss  D3(%rip),%xmm1
  divss  %xmm1,%xmm0
L10:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
datatype: byte[4]
name: retrieve_data
arguments: tag: D3
datatype: byte[4]

tool: {"D29": [0x00,0x00,0x00,0x43]}

tool: {"D3": [0x00,0x00,0xfe,0x42]}

assistant: ```c
float pspnxController(float input) {
  input = input - 128;
  if (input < 0)
    return input / 128;
  else
    return input / 127;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pspnxController>:
  endbr64
  subss  D26(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L1
  divss  D5(%rip),%xmm0
  ret
L1:
  mulss  D0(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D26
datatype: byte[4]
name: read_data
arguments: tag: D5
datatype: byte[4]
name: read_data
arguments: tag: D0
datatype: byte[4]

tool: {"D26": [0x00,0x00,0x00,0x43]}

tool: {"D5": [0x00,0x00,0xfe,0x42]}

tool: {"D0": [0x00,0x00,0x00,0x3c]}

assistant: ```c
float pspnxController(float input) {
  input = input - 128;
  if (input < 0)
    return input / 128;
  else
    return input / 127;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pspnxController>:
  endbr64
  subss  D4(%rip),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L4
  divss  D1(%rip),%xmm0
  ret
  xchg   %ax,%ax
L4:
  mulss  D9(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: byte[4]
name: unpack_data
arguments: tag: D1
type_infered: byte[4]
name: unpack_data
arguments: tag: D9
type_infered: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x43]}

tool: {"D1": [0x00,0x00,0xfe,0x42]}

tool: {"D9": [0x00,0x00,0x00,0x3c]}

assistant: ```c
float pspnxController(float input) {
  input = input - 128;
  if (input < 0)
    return input / 128;
  else
    return input / 127;
}
```