ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  lea    D9(%rip),%rdi
  call   <h@plt>
  mov    $0x2,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <foo@plt>
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L7
  add    $0x8,%rsp
  ret
L7:
  xor    %edi,%edi
  pop    %rax
  jmp    1090 <do_something@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: toto

assistant: ```c
void main(int x) {
  foo(1);
  h("toto");
  foo(2);
  foo(foo(2));
  if (foo(3)) {
    int foo;
    do_something(foo);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  lea    D6(%rip),%rdi
  call   <h@plt>
  mov    $0x2,%edi
  call   <foo@plt>
  mov    $0x2,%edi
  call   <foo@plt>
  mov    %eax,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  test   %eax,%eax
  jne    L0
  add    $0x8,%rsp
  ret
L0:
  xor    %edi,%edi
  pop    %rax
  jmp    1090 <do_something@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: toto

assistant: ```c
void main(int x) {
  foo(1);
  h("toto");
  foo(2);
  foo(foo(2));
  if (foo(3)) {
    int foo;
    do_something(foo);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IL_re_search_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x24(%rbp)
  mov    -0x24(%rbp),%r9d
  mov    -0x18(%rbp),%r8d
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    0x20(%rbp),%edi
  push   %rdi
  push   0x18(%rbp)
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <byte_re_search_2@plt>
  add    $0x20,%rsp
  leave
  ret
```

assistant: ```c
int IL_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int startpos;
int range;
struct re_registers *regs;
int stop;
{ return byte_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop); }
```
user: What is the c source code of the assembly code below:

```asm
<IL_re_search_2>:
  endbr64
  sub    $0x10,%rsp
  mov    0x28(%rsp),%eax
  push   %rax
  push   0x28(%rsp)
  mov    0x28(%rsp),%eax
  push   %rax
  mov    $0x0,%eax
  call   <byte_re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int IL_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int startpos;
int range;
struct re_registers *regs;
int stop;
{ return byte_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop); }
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<IL_re_search_2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <byte_re_search_2@plt>
```

assistant: ```c
int IL_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int startpos;
int range;
struct re_registers *regs;
int stop;
{ return byte_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop); }
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IL_re_search_2>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <byte_re_search_2@plt>
```

assistant: ```c
int IL_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop)
struct re_pattern_buffer *bufp;
const char *string1, *string2;
int size1, size2;
int startpos;
int range;
struct re_registers *regs;
int stop;
{ return byte_re_search_2(bufp, string1, size1, string2, size2, startpos, range, regs, stop); }
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<s_move_elems>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  mov    -0x28(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rcx
  imul   -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x10(%rbp),%rdx
  imul   -0x30(%rbp),%rdx
  mov    %rdx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memmove@plt>
L10:
  nop
  leave
  ret
```

assistant: ```c
void s_move_elems(void *t, size_t t_off, const void *s, size_t s_off, size_t n, size_t e_size) {
  if (t && s)
    memmove((char *)t + t_off * e_size, (const char *)s + s_off * e_size, n * e_size);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<s_move_elems>:
  endbr64
  test   %rdi,%rdi
  je     L7
  mov    %rsi,%rax
  test   %rdx,%rdx
  jne    L11
L7:
  ret
L11:
  sub    $0x8,%rsp
  imul   %r9,%r8
  imul   %r9,%rcx
  lea    (%rdx,%rcx,1),%rsi
  imul   %rax,%r9
  add    %r9,%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void s_move_elems(void *t, size_t t_off, const void *s, size_t s_off, size_t n, size_t e_size) {
  if (t && s)
    memmove((char *)t + t_off * e_size, (const char *)s + s_off * e_size, n * e_size);
}
```
user: What is the c source code of the assembly code below?

```asm
<s_move_elems>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L13
  test   %rdx,%rdx
  jne    L8
L13:
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  imul   %r9,%r8
  imul   %r9,%rcx
  imul   %rax,%r9
  lea    (%rdx,%rcx,1),%rsi
  mov    %r8,%rdx
  add    %r9,%rdi
  jmp    1050 <memmove@plt>
```

assistant: ```c
void s_move_elems(void *t, size_t t_off, const void *s, size_t s_off, size_t n, size_t e_size) {
  if (t && s)
    memmove((char *)t + t_off * e_size, (const char *)s + s_off * e_size, n * e_size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<s_move_elems>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L16
  test   %rdx,%rdx
  jne    L10
L16:
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  imul   %r9,%r8
  imul   %r9,%rcx
  imul   %rax,%r9
  lea    (%rdx,%rcx,1),%rsi
  mov    %r8,%rdx
  add    %r9,%rdi
  jmp    1050 <memmove@plt>
```

assistant: ```c
void s_move_elems(void *t, size_t t_off, const void *s, size_t s_off, size_t n, size_t e_size) {
  if (t && s)
    memmove((char *)t + t_off * e_size, (const char *)s + s_off * e_size, n * e_size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<root>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movsd  %xmm0,-0x48(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L78
L34:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  movsd  %xmm2,-0x50(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rbx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %rbx,%xmm1
  divsd  %xmm0,%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x50(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   D5(%rip),%xmm1
  andpd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L5
  movl   $0x1,-0x18(%rbp)
L5:
  addl   $0x1,-0x14(%rbp)
L78:
  cmpl   $0x0,-0x18(%rbp)
  jne    L57
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L34
L57:
  cmpl   $0x0,-0x14(%rbp)
  jne    L47
  mov    -0x40(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L7
L47:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
L7:
  cmpl   $0x0,-0x18(%rbp)
  je     L43
  mov    $0x0,%eax
  jmp    L21
L43:
  mov    $0xffffffff,%eax
L21:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: qword

tool: D5: 9223372036854775807

assistant: ```c
int root(double (*f)(double), double (*g)(double), double *x, int *n, double delta) {
  int satisfied, i;
  i = 0;
  satisfied = 0;
  while (!satisfied && i + 1 < *n) {
    x[i + 1] = x[i] - (f(x[i]) / g(x[i]));
    if (fabs(x[i + 1] - x[i]) < delta)
      satisfied = 1;
    i += 1;
  }
  if (i == 0)
    *n = 1;
  else
    *n = i + 1;
  if (satisfied)
    return 0;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<root>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %rcx,%r14
  movsd  %xmm0,0x18(%rsp)
  mov    %rdx,%rbx
  mov    $0x0,%eax
L29:
  lea    0x1(%rax),%r12d
  cmp    (%r14),%r12d
  jge    L21
  mov    %rbx,%r13
  movsd  (%rbx),%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   *%r15
  movsd  %xmm0,0x10(%rsp)
  movsd  (%rbx),%xmm0
  call   *%rbp
  movsd  0x10(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rbx)
  add    $0x8,%rbx
  subsd  0x0(%r13),%xmm0
  andpd  D7(%rip),%xmm0
  movsd  0x18(%rsp),%xmm3
  comisd %xmm0,%xmm3
  ja     L3
  mov    %r12d,%eax
  jmp    L29
L21:
  mov    %eax,%r12d
  mov    $0x0,%eax
  jmp    L28
L3:
  mov    $0x1,%eax
L28:
  add    $0x1,%r12d
  mov    %r12d,(%r14)
  sub    $0x1,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: qword[2]

tool: {"D7": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int root(double (*f)(double), double (*g)(double), double *x, int *n, double delta) {
  int satisfied, i;
  i = 0;
  satisfied = 0;
  while (!satisfied && i + 1 < *n) {
    x[i + 1] = x[i] - (f(x[i]) / g(x[i]));
    if (fabs(x[i + 1] - x[i]) < delta)
      satisfied = 1;
    i += 1;
  }
  if (i == 0)
    *n = 1;
  else
    *n = i + 1;
  if (satisfied)
    return 0;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<root>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  lea    0x1(%rax),%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  cmp    (%rbx),%r14d
  jge    L39
  nop
L12:
  movsd  0x0(%r13),%xmm1
  mov    %r13,%r15
  add    $0x8,%r13
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   *%r12
  movsd  %xmm0,0x8(%rsp)
  movsd  -0x8(%r13),%xmm0
  call   *%rbp
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x0(%r13)
  subsd  (%r15),%xmm1
  andpd  D7(%rip),%xmm1
  comisd %xmm1,%xmm4
  ja     L24
  mov    %r14d,%eax
  lea    0x1(%rax),%r14d
  cmp    (%rbx),%r14d
  jl     L12
L39:
  test   %eax,%eax
  jne    L48
  mov    $0xffffffff,%eax
  mov    $0x1,%r14d
L9:
  mov    %r14d,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
L55:
  add    $0x1,%r14d
  jmp    L9
L48:
  mov    %eax,%r14d
  or     $0xffffffff,%eax
  jmp    L55
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: qword[2]

tool: {"D7": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int root(double (*f)(double), double (*g)(double), double *x, int *n, double delta) {
  int satisfied, i;
  i = 0;
  satisfied = 0;
  while (!satisfied && i + 1 < *n) {
    x[i + 1] = x[i] - (f(x[i]) / g(x[i]));
    if (fabs(x[i + 1] - x[i]) < delta)
      satisfied = 1;
    i += 1;
  }
  if (i == 0)
    *n = 1;
  else
    *n = i + 1;
  if (satisfied)
    return 0;
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<root>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  lea    0x1(%rax),%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  cmp    (%rbx),%r14d
  jge    L0
  nop
L34:
  movsd  0x0(%r13),%xmm1
  mov    %r13,%r15
  add    $0x8,%r13
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   *%r12
  movsd  %xmm0,0x8(%rsp)
  movsd  -0x8(%r13),%xmm0
  call   *%rbp
  movsd  0x8(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x0(%r13)
  subsd  (%r15),%xmm1
  andpd  D0(%rip),%xmm1
  comisd %xmm1,%xmm4
  ja     L31
  mov    %r14d,%eax
  lea    0x1(%rax),%r14d
  cmp    (%rbx),%r14d
  jl     L34
L0:
  test   %eax,%eax
  jne    L49
  mov    $0xffffffff,%eax
  mov    $0x1,%r14d
L12:
  mov    %r14d,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
L5:
  add    $0x1,%r14d
  jmp    L12
L49:
  mov    %eax,%r14d
  or     $0xffffffff,%eax
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: qword[2]

tool: {"D0": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int root(double (*f)(double), double (*g)(double), double *x, int *n, double delta) {
  int satisfied, i;
  i = 0;
  satisfied = 0;
  while (!satisfied && i + 1 < *n) {
    x[i + 1] = x[i] - (f(x[i]) / g(x[i]));
    if (fabs(x[i + 1] - x[i]) < delta)
      satisfied = 1;
    i += 1;
  }
  if (i == 0)
    *n = 1;
  else
    *n = i + 1;
  if (satisfied)
    return 0;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x2c(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x20(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x1e(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x1c(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x1a(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x18(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x16(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x12(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0xe(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0xc(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0xa(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x8(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x2c(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rcx)
  mov    %rdx,0x8(%rcx)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x10(%rcx)
  mov    %rdx,0x18(%rcx)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__v16hi foo_6(short c) {
  __v16hi v1 = {c, c, c, c, c, c, c, c, c, c, c, c, c, c, c, c};
  return v1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo_6>:
  endbr64
  mov    %rdi,%rax
  mov    %si,(%rdi)
  mov    %si,0x2(%rdi)
  mov    %si,0x4(%rdi)
  mov    %si,0x6(%rdi)
  mov    %si,0x8(%rdi)
  mov    %si,0xa(%rdi)
  mov    %si,0xc(%rdi)
  mov    %si,0xe(%rdi)
  mov    %si,0x10(%rdi)
  mov    %si,0x12(%rdi)
  mov    %si,0x14(%rdi)
  mov    %si,0x16(%rdi)
  mov    %si,0x18(%rdi)
  mov    %si,0x1a(%rdi)
  mov    %si,0x1c(%rdi)
  mov    %si,0x1e(%rdi)
  ret
```

assistant: ```c
__v16hi foo_6(short c) {
  __v16hi v1 = {c, c, c, c, c, c, c, c, c, c, c, c, c, c, c, c};
  return v1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo_6>:
  endbr64
  mov    %si,(%rdi)
  mov    %rdi,%rax
  mov    %si,0x2(%rdi)
  mov    %si,0x4(%rdi)
  mov    %si,0x6(%rdi)
  mov    %si,0x8(%rdi)
  mov    %si,0xa(%rdi)
  mov    %si,0xc(%rdi)
  mov    %si,0xe(%rdi)
  mov    %si,0x10(%rdi)
  mov    %si,0x12(%rdi)
  mov    %si,0x14(%rdi)
  mov    %si,0x16(%rdi)
  mov    %si,0x18(%rdi)
  mov    %si,0x1a(%rdi)
  mov    %si,0x1c(%rdi)
  mov    %si,0x1e(%rdi)
  ret
```

assistant: ```c
__v16hi foo_6(short c) {
  __v16hi v1 = {c, c, c, c, c, c, c, c, c, c, c, c, c, c, c, c};
  return v1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo_6>:
  endbr64
  movd   %esi,%xmm0
  mov    %rdi,%rax
  punpcklwd %xmm0,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
__v16hi foo_6(short c) {
  __v16hi v1 = {c, c, c, c, c, c, c, c, c, c, c, c, c, c, c, c};
  return v1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Isleap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L34
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L39
L34:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xfa0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L1
L39:
  mov    $0x1,%eax
  jmp    L7
L1:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int Isleap(int year) {
  if (((year % 4) == 0 && (year % 100) != 0) || ((year % 400 == 0) && (year % 4000) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Isleap>:
  endbr64
  mov    %edi,%eax
  test   $0x3,%al
  jne    L25
  movslq %edi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  mov    $0x1,%ecx
  cmp    %edx,%edi
  jne    L21
L25:
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x190,%edx,%edx
  mov    $0x0,%ecx
  cmp    %edx,%eax
  jne    L21
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x28,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xfa0,%edx,%edx
  cmp    %edx,%eax
  setne  %cl
  movzbl %cl,%ecx
L21:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int Isleap(int year) {
  if (((year % 4) == 0 && (year % 100) != 0) || ((year % 400 == 0) && (year % 4000) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Isleap>:
  endbr64
  test   $0x3,%dil
  jne    L19
  imul   $0xc28f5c29,%edi,%eax
  mov    $0x1,%r8d
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  ja     L2
L19:
  imul   $0xc28f5c29,%edi,%eax
  xor    %r8d,%r8d
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  ja     L2
  imul   $0x26e978d5,%edi,%edi
  xor    %r8d,%r8d
  add    $0x10624c0,%edi
  ror    $0x5,%edi
  cmp    $0x10624c,%edi
  seta   %r8b
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Isleap(int year) {
  if (((year % 4) == 0 && (year % 100) != 0) || ((year % 400 == 0) && (year % 4000) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Isleap>:
  endbr64
  test   $0x3,%dil
  jne    L9
  imul   $0xc28f5c29,%edi,%eax
  mov    $0x1,%r8d
  add    $0x51eb850,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  ja     L16
L9:
  imul   $0xc28f5c29,%edi,%eax
  xor    %r8d,%r8d
  add    $0x51eb850,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  ja     L16
  imul   $0x26e978d5,%edi,%edi
  xor    %r8d,%r8d
  add    $0x10624c0,%edi
  ror    $0x5,%edi
  cmp    $0x10624c,%edi
  seta   %r8b
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Isleap(int year) {
  if (((year % 4) == 0 && (year % 100) != 0) || ((year % 400 == 0) && (year % 4000) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x28(%rbp),%r8
  mov    -0x40(%rbp),%rdi
  mov    -0x38(%rbp),%rcx
  mov    0x18(%rbp),%rdx
  mov    0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x30(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <enc@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  int res = enc(c, k, npub, ad, adlen, m, mlen);
  *clen = mlen + (long long)(const int)32 / 8;
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %rcx,%rbx
  mov    %r8,%rcx
  mov    %r9,%r8
  push   %rbx
  mov    %rdx,%r9
  mov    0x38(%rsp),%rdx
  mov    0x40(%rsp),%rsi
  call   <enc@plt>
  add    $0x4,%rbx
  mov    %rbx,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  int res = enc(c, k, npub, ad, adlen, m, mlen);
  *clen = mlen + (long long)(const int)32 / 8;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    %rdx,%r9
  sub    $0x10,%rsp
  push   %rbx
  mov    0x38(%rsp),%rdx
  add    $0x4,%rbx
  mov    0x40(%rsp),%rsi
  call   <enc@plt>
  mov    %rbx,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  int res = enc(c, k, npub, ad, adlen, m, mlen);
  *clen = mlen + (long long)(const int)32 / 8;
  return res;
}
```