ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<FiveTimes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int FiveTimes(int a) {
  int t;
  t = (a << 2) + a;
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FiveTimes>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int FiveTimes(int a) {
  int t;
  t = (a << 2) + a;
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FiveTimes>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int FiveTimes(int a) {
  int t;
  t = (a << 2) + a;
  return t;
}
```
user: What is the c source code of the assembly code below:

```asm
<FiveTimes>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  ret
```

assistant: ```c
int FiveTimes(int a) {
  int t;
  t = (a << 2) + a;
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x1b1b1ac7(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] != local2 + local1) {
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 454761159UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2e8b115d,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] != local2 + local1) {
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 454761159UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2e8b115d,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] != local2 + local1) {
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 454761159UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x2e8b115d,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      local2 = 0UL;
      while (local2 < 0UL) {
        if (state[0UL] != local2 + local1) {
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 454761159UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L13
L0:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  xor    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D5
data_type: string

tool: D10: %lu


tool: D5: %lu %lu

assistant: ```c
int main() {
  unsigned long int a, b;
  while (scanf("%lu %lu", &a, &b) > 0) {
    printf("%lu\n", a ^ b);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D14(%rip),%rbx
  lea    D2(%rip),%r13
  jmp    L8
L24:
  mov    0x8(%rsp),%rsi
  xor    0x10(%rsp),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
L8:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L24
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D14: %lu %lu

tool: D2: %lu


assistant: ```c
int main() {
  unsigned long int a, b;
  while (scanf("%lu %lu", &a, &b) > 0) {
    printf("%lu\n", a ^ b);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    0x10(%rsp),%rsi
  call   <printf@plt>
L21:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D11: %lu


tool: D6: %lu %lu

assistant: ```c
int main() {
  unsigned long int a, b;
  while (scanf("%lu %lu", &a, &b) > 0) {
    printf("%lu\n", a ^ b);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  xor    0x10(%rsp),%rsi
  call   <printf@plt>
L16:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
type: string
name: read_data
arguments: label: D18
type: string

tool: D5: %lu


tool: D18: %lu %lu

assistant: ```c
int main() {
  unsigned long int a, b;
  while (scanf("%lu %lu", &a, &b) > 0) {
    printf("%lu\n", a ^ b);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<d2bei_clip_array>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    D25(%rip),%r13
  test   %ecx,%ecx
  jne    L51
  mov    D2(%rip),%r13
L51:
  lea    0x0(,%rbp,4),%eax
  cltq
  lea    (%rsi,%rax,1),%rbx
  sub    $0x1,%ebp
  js     L31
  movslq %ebp,%rbp
  jmp    L41
L71:
  movb   $0xff,0x3(%rbx)
  movb   $0xff,0x2(%rbx)
  movb   $0xff,0x1(%rbx)
  movb   $0x7f,(%rbx)
  jmp    L9
L67:
  call   <lrint@plt>
  mov    %eax,%edx
  sar    $0x18,%edx
  mov    %dl,(%rbx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x1(%rbx)
  movzbl %ah,%ecx
  mov    %cl,0x2(%rbx)
  mov    %al,0x3(%rbx)
L9:
  sub    $0x1,%rbp
  test   %ebp,%ebp
  js     L31
L41:
  sub    $0x4,%rbx
  movq   %r13,%xmm0
  mulsd  (%r12,%rbp,8),%xmm0
  comisd D3(%rip),%xmm0
  jae    L71
  movsd  D4(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L67
  movb   $0x0,0x3(%rbx)
  movb   $0x0,0x2(%rbx)
  movb   $0x0,0x1(%rbx)
  movb   $0x80,(%rbx)
  jmp    L9
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D2
type_guessed: f64
name: retrieve_data
arguments: tag: D3
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D4
type_guessed: byte[8]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x41]}

tool: D2: 1

tool: {"D3": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xc1]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xc1]}

assistant: ```c
void d2bei_clip_array(const double *src, int *dest, int count, int normalize) {
  unsigned char *ucptr;
  int value;
  double normfact, scaled_value;
  normfact = normalize ? (8.0 * 0x10000000) : 1.0;
  ucptr = ((unsigned char *)dest) + 4 * count;
  while (--count >= 0) {
    ucptr -= 4;
    scaled_value = src[count] * normfact;
    if (0 == 0 && scaled_value >= (1.0 * 0x7FFFFFFF)) {
      ucptr[3] = 0xFF;
      ucptr[2] = 0xFF;
      ucptr[1] = 0xFF;
      ucptr[0] = 0x7F;
      continue;
    };
    if (0 == 0 && scaled_value <= (-8.0 * 0x10000000)) {
      ucptr[3] = 0x00;
      ucptr[2] = 0x00;
      ucptr[1] = 0x00;
      ucptr[0] = 0x80;
      continue;
    };
    value = lrint(scaled_value);
    ucptr[0] = value >> 24;
    ucptr[1] = value >> 16;
    ucptr[2] = value >> 8;
    ucptr[3] = value;
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<d2bei_clip_array>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x10,%rsp
  movsd  D5(%rip),%xmm1
  test   %ecx,%ecx
  jne    L13
  movsd  D32(%rip),%xmm1
L13:
  lea    0x0(,%rbp,4),%eax
  cltq
  lea    (%rsi,%rax,1),%rbx
  sub    $0x1,%ebp
  js     L67
  movsd  D11(%rip),%xmm2
  movslq %ebp,%rbp
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L18:
  movb   $0x0,0x3(%rbx)
  movb   $0x0,0x2(%rbx)
  movb   $0x0,0x1(%rbx)
  movb   $0x80,(%rbx)
L32:
  sub    $0x1,%rbp
  test   %ebp,%ebp
  js     L67
L46:
  movsd  (%r12,%rbp,8),%xmm0
  sub    $0x4,%rbx
  mulsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jae    L21
  movsd  D3(%rip),%xmm3
  comisd %xmm0,%xmm3
  jae    L18
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%rbp
  call   <lrint@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %eax,%edx
  mov    %ah,0x2(%rbx)
  sar    $0x18,%edx
  mov    %al,0x3(%rbx)
  mov    %dl,(%rbx)
  mov    %eax,%edx
  mov    D11(%rip),%rax
  sar    $0x10,%edx
  mov    %dl,0x1(%rbx)
  movq   %rax,%xmm2
  test   %ebp,%ebp
  jns    L46
L67:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  movb   $0xff,0x3(%rbx)
  movb   $0xff,0x2(%rbx)
  movb   $0xff,0x1(%rbx)
  movb   $0x7f,(%rbx)
  jmp    L32
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D32
type_infered: f64
name: unpack_data
arguments: data_tag: D11
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D3
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x41]}

tool: D32: 1

tool: {"D11": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xc1]}

assistant: ```c
void d2bei_clip_array(const double *src, int *dest, int count, int normalize) {
  unsigned char *ucptr;
  int value;
  double normfact, scaled_value;
  normfact = normalize ? (8.0 * 0x10000000) : 1.0;
  ucptr = ((unsigned char *)dest) + 4 * count;
  while (--count >= 0) {
    ucptr -= 4;
    scaled_value = src[count] * normfact;
    if (0 == 0 && scaled_value >= (1.0 * 0x7FFFFFFF)) {
      ucptr[3] = 0xFF;
      ucptr[2] = 0xFF;
      ucptr[1] = 0xFF;
      ucptr[0] = 0x7F;
      continue;
    };
    if (0 == 0 && scaled_value <= (-8.0 * 0x10000000)) {
      ucptr[3] = 0x00;
      ucptr[2] = 0x00;
      ucptr[1] = 0x00;
      ucptr[0] = 0x80;
      continue;
    };
    value = lrint(scaled_value);
    ucptr[0] = value >> 24;
    ucptr[1] = value >> 16;
    ucptr[2] = value >> 8;
    ucptr[3] = value;
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<d2bei_clip_array>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x10,%rsp
  movsd  D14(%rip),%xmm1
  test   %ecx,%ecx
  jne    L25
  movsd  D30(%rip),%xmm1
L25:
  lea    0x0(,%rbp,4),%eax
  cltq
  lea    (%rsi,%rax,1),%rbx
  sub    $0x1,%ebp
  js     L15
  movsd  D34(%rip),%xmm2
  movslq %ebp,%rbp
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L58:
  movb   $0x0,0x3(%rbx)
  movb   $0x0,0x2(%rbx)
  movb   $0x0,0x1(%rbx)
  movb   $0x80,(%rbx)
L72:
  sub    $0x1,%rbp
  test   %ebp,%ebp
  js     L15
L7:
  movsd  (%r12,%rbp,8),%xmm0
  sub    $0x4,%rbx
  mulsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jae    L79
  movsd  D46(%rip),%xmm3
  comisd %xmm0,%xmm3
  jae    L58
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%rbp
  call   <lrint@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %eax,%edx
  mov    %ah,0x2(%rbx)
  sar    $0x18,%edx
  mov    %al,0x3(%rbx)
  mov    %dl,(%rbx)
  mov    %eax,%edx
  mov    D34(%rip),%rax
  sar    $0x10,%edx
  mov    %dl,0x1(%rbx)
  movq   %rax,%xmm2
  test   %ebp,%ebp
  jns    L7
L15:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L79:
  movb   $0xff,0x3(%rbx)
  movb   $0xff,0x2(%rbx)
  movb   $0xff,0x1(%rbx)
  movb   $0x7f,(%rbx)
  jmp    L72
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: byte[8]
name: parse_data
arguments: data_tag: D30
datatype: f64
name: parse_data
arguments: data_tag: D34
datatype: byte[8]
name: parse_data
arguments: data_tag: D46
datatype: byte[8]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x41]}

tool: D30: 1

tool: {"D34": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xc1]}

assistant: ```c
void d2bei_clip_array(const double *src, int *dest, int count, int normalize) {
  unsigned char *ucptr;
  int value;
  double normfact, scaled_value;
  normfact = normalize ? (8.0 * 0x10000000) : 1.0;
  ucptr = ((unsigned char *)dest) + 4 * count;
  while (--count >= 0) {
    ucptr -= 4;
    scaled_value = src[count] * normfact;
    if (0 == 0 && scaled_value >= (1.0 * 0x7FFFFFFF)) {
      ucptr[3] = 0xFF;
      ucptr[2] = 0xFF;
      ucptr[1] = 0xFF;
      ucptr[0] = 0x7F;
      continue;
    };
    if (0 == 0 && scaled_value <= (-8.0 * 0x10000000)) {
      ucptr[3] = 0x00;
      ucptr[2] = 0x00;
      ucptr[1] = 0x00;
      ucptr[0] = 0x80;
      continue;
    };
    value = lrint(scaled_value);
    ucptr[0] = value >> 24;
    ucptr[1] = value >> 16;
    ucptr[2] = value >> 8;
    ucptr[3] = value;
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<BTIC2D_TransIWHT_Stride8>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rax
  mov    %ecx,%r10d
  mov    (%rdi),%ecx
  movslq %edx,%r8
  lea    0x0(,%r8,4),%rdx
  add    %rdx,%rdi
  mov    (%rdi),%r9d
  add    %rdx,%rdi
  mov    (%rdi),%r11d
  add    %rdx,%rdi
  mov    (%rdi),%r12d
  add    %rdx,%rdi
  lea    (%rdi,%rdx,1),%r13
  lea    0x0(%r13,%rdx,1),%rsi
  mov    %ecx,%edx
  sar    %edx
  sub    (%rsi,%r8,4),%edx
  sub    %edx,%ecx
  mov    %r12d,%ebp
  sar    %ebp
  sub    (%rdi),%ebp
  mov    %r9d,%r8d
  sar    %r8d
  sub    (%rsi),%r8d
  sub    %r8d,%r9d
  mov    %r11d,%ebx
  sar    %ebx
  sub    0x0(%r13),%ebx
  mov    %ecx,%edi
  sar    %edi
  sub    %ebp,%r12d
  sub    %r12d,%edi
  mov    %edx,%esi
  sar    %esi
  sub    %ebp,%esi
  sub    %edi,%ecx
  sub    %esi,%edx
  mov    %r9d,%r12d
  sar    %r12d
  sub    %ebx,%r11d
  sub    %r11d,%r12d
  mov    %r8d,%ebp
  sar    %ebp
  sub    %ebx,%ebp
  mov    %ecx,%ebx
  sar    %ebx
  sub    %r12d,%r9d
  sub    %r9d,%ebx
  mov    %edx,%r11d
  sar    %r11d
  sub    %ebp,%r8d
  sub    %r8d,%r11d
  mov    %edi,%r9d
  sar    %r9d
  sub    %r12d,%r9d
  mov    %esi,%r8d
  sar    %r8d
  sub    %ebp,%r8d
  sub    %ebx,%ecx
  mov    %ecx,(%rax)
  movslq %r10d,%r10
  lea    0x0(,%r10,4),%rcx
  add    %rcx,%rax
  sub    %r11d,%edx
  mov    %edx,(%rax)
  add    %rcx,%rax
  sub    %r9d,%edi
  mov    %edi,(%rax)
  add    %rcx,%rax
  sub    %r8d,%esi
  mov    %esi,(%rax)
  add    %rcx,%rax
  mov    %ebx,(%rax)
  add    %rcx,%rax
  mov    %r11d,(%rax)
  add    %rcx,%rax
  mov    %r9d,(%rax)
  mov    %r8d,(%rax,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void BTIC2D_TransIWHT_Stride8(int *iblk, int *oblk, int istride, int ostride) {
  int ob0, ob1, ob2, ob3, ob4, ob5, ob6, ob7;
  int a0, a1, a2, a3, a4, a5, a6, a7;
  int b0, b1, b2, b3, b4, b5, b6, b7;
  int c0, c1, c2, c3, c4, c5, c6, c7;
  c0 = iblk[istride * 0];
  c4 = iblk[istride * 1];
  c6 = iblk[istride * 2];
  c2 = iblk[istride * 3];
  c3 = iblk[istride * 4];
  c7 = iblk[istride * 5];
  c5 = iblk[istride * 6];
  c1 = iblk[istride * 7];
  b1 = (c0 >> 1) - c1;
  b0 = c0 - b1;
  b3 = (c2 >> 1) - c3;
  b2 = c2 - b3;
  b5 = (c4 >> 1) - c5;
  b4 = c4 - b5;
  b7 = (c6 >> 1) - c7;
  b6 = c6 - b7;
  a2 = (b0 >> 1) - b2;
  a3 = (b1 >> 1) - b3;
  a0 = b0 - a2;
  a1 = b1 - a3;
  a6 = (b4 >> 1) - b6;
  a7 = (b5 >> 1) - b7;
  a4 = b4 - a6;
  a5 = b5 - a7;
  ob4 = (a0 >> 1) - a4;
  ob5 = (a1 >> 1) - a5;
  ob6 = (a2 >> 1) - a6;
  ob7 = (a3 >> 1) - a7;
  ob0 = a0 - ob4;
  ob1 = a1 - ob5;
  ob2 = a2 - ob6;
  ob3 = a3 - ob7;
  oblk[ostride * 0] = ob0;
  oblk[ostride * 1] = ob1;
  oblk[ostride * 2] = ob2;
  oblk[ostride * 3] = ob3;
  oblk[ostride * 4] = ob4;
  oblk[ostride * 5] = ob5;
  oblk[ostride * 6] = ob6;
  oblk[ostride * 7] = ob7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BTIC2D_TransIWHT_Stride8>:
  endbr64
  movslq %edx,%r8
  push   %r13
  movslq %ecx,%r10
  mov    %rsi,%rax
  lea    0x0(,%r8,4),%rdx
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%ecx
  add    %rdx,%rdi
  mov    (%rdi),%r9d
  add    %rdx,%rdi
  mov    (%rdi),%r11d
  add    %rdx,%rdi
  mov    (%rdi),%r12d
  add    %rdx,%rdi
  lea    (%rdi,%rdx,1),%r13
  mov    %r11d,%ebx
  lea    0x0(%r13,%rdx,1),%rsi
  mov    %ecx,%edx
  mov    %r12d,%ebp
  sar    %ebx
  sar    %edx
  sub    (%rsi,%r8,4),%edx
  mov    %r9d,%r8d
  sar    %ebp
  sub    %edx,%ecx
  sub    (%rdi),%ebp
  sar    %r8d
  sub    (%rsi),%r8d
  mov    %ecx,%edi
  mov    %edx,%esi
  sub    %r8d,%r9d
  sub    %ebp,%r12d
  sar    %edi
  sar    %esi
  sub    0x0(%r13),%ebx
  sub    %r12d,%edi
  sub    %ebp,%esi
  mov    %r9d,%r12d
  mov    %r8d,%ebp
  sub    %edi,%ecx
  sub    %ebx,%r11d
  sar    %r12d
  sub    %esi,%edx
  sar    %ebp
  sub    %r11d,%r12d
  mov    %edx,%r11d
  sub    %ebx,%ebp
  mov    %ecx,%ebx
  sub    %r12d,%r9d
  sar    %r11d
  sar    %ebx
  sub    %ebp,%r8d
  sub    %r9d,%ebx
  mov    %edi,%r9d
  sub    %r8d,%r11d
  mov    %esi,%r8d
  sar    %r9d
  sub    %ebx,%ecx
  sar    %r8d
  sub    %r11d,%edx
  mov    %ecx,(%rax)
  lea    0x0(,%r10,4),%rcx
  sub    %r12d,%r9d
  sub    %ebp,%r8d
  add    %rcx,%rax
  sub    %r9d,%edi
  sub    %r8d,%esi
  mov    %edx,(%rax)
  add    %rcx,%rax
  mov    %edi,(%rax)
  add    %rcx,%rax
  mov    %esi,(%rax)
  add    %rcx,%rax
  mov    %ebx,(%rax)
  add    %rcx,%rax
  mov    %r11d,(%rax)
  add    %rcx,%rax
  mov    %r9d,(%rax)
  mov    %r8d,(%rax,%r10,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void BTIC2D_TransIWHT_Stride8(int *iblk, int *oblk, int istride, int ostride) {
  int ob0, ob1, ob2, ob3, ob4, ob5, ob6, ob7;
  int a0, a1, a2, a3, a4, a5, a6, a7;
  int b0, b1, b2, b3, b4, b5, b6, b7;
  int c0, c1, c2, c3, c4, c5, c6, c7;
  c0 = iblk[istride * 0];
  c4 = iblk[istride * 1];
  c6 = iblk[istride * 2];
  c2 = iblk[istride * 3];
  c3 = iblk[istride * 4];
  c7 = iblk[istride * 5];
  c5 = iblk[istride * 6];
  c1 = iblk[istride * 7];
  b1 = (c0 >> 1) - c1;
  b0 = c0 - b1;
  b3 = (c2 >> 1) - c3;
  b2 = c2 - b3;
  b5 = (c4 >> 1) - c5;
  b4 = c4 - b5;
  b7 = (c6 >> 1) - c7;
  b6 = c6 - b7;
  a2 = (b0 >> 1) - b2;
  a3 = (b1 >> 1) - b3;
  a0 = b0 - a2;
  a1 = b1 - a3;
  a6 = (b4 >> 1) - b6;
  a7 = (b5 >> 1) - b7;
  a4 = b4 - a6;
  a5 = b5 - a7;
  ob4 = (a0 >> 1) - a4;
  ob5 = (a1 >> 1) - a5;
  ob6 = (a2 >> 1) - a6;
  ob7 = (a3 >> 1) - a7;
  ob0 = a0 - ob4;
  ob1 = a1 - ob5;
  ob2 = a2 - ob6;
  ob3 = a3 - ob7;
  oblk[ostride * 0] = ob0;
  oblk[ostride * 1] = ob1;
  oblk[ostride * 2] = ob2;
  oblk[ostride * 3] = ob3;
  oblk[ostride * 4] = ob4;
  oblk[ostride * 5] = ob5;
  oblk[ostride * 6] = ob6;
  oblk[ostride * 7] = ob7;
}
```