user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x16,%edx
  push   %r13
  lea    D64(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rsi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x2400000016,%rax
  movl   $0x2,0x10(%rsp)
  mov    %rsp,%rbp
  mov    %r12,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x170000001b,%rax
  mov    %rax,0x8(%rsp)
  lea    D53(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D91(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D23(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D45(%rip),%rax
  mov    %rax,0x40(%rsp)
L50:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x14,%rbx
  je     L0
  mov    0x0(%rbp,%rbx,1),%edx
  mov    0x20(%rsp,%rbx,2),%rsi
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D111(%rip),%r13
  xor    %ebx,%ebx
  lea    D34(%rip),%r14
  mov    %r13,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rsi
  mov    $0x16,%edx
  jmp    L37
  xchg   %ax,%ax
L75:
  mov    0x0(%rbp,%rbx,1),%edx
  mov    0x20(%rsp,%rbx,2),%rsi
L37:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x18,%rbx
  jne    L75
  mov    %r13,%rdi
  xor    %ebx,%ebx
  lea    D66(%rip),%r14
  call   <puts@plt>
  lea    D2(%rip),%rsi
  mov    $0x16,%edx
  jmp    L52
  nopl   0x0(%rax)
L55:
  mov    0x0(%rbp,%rbx,1),%edx
  mov    0x20(%rsp,%rbx,2),%rsi
L52:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x14,%rbx
  jne    L55
  mov    %r13,%rdi
  mov    %rbp,%rbx
  lea    D104(%rip),%r13
  call   <puts@plt>
  mov    $0x16,%edx
  jmp    L87
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%edx
L87:
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %rbx,%rax
  sub    %rbp,%rax
  cmp    $0x10,%rax
  jle    L15
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D64
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string
name: extract_symbolic_data
arguments: tag: D53
datatype: string
name: extract_symbolic_data
arguments: tag: D91
datatype: string
name: extract_symbolic_data
arguments: tag: D23
datatype: string
name: extract_symbolic_data
arguments: tag: D45
datatype: string
name: extract_symbolic_data
arguments: tag: D111
datatype: string
name: extract_symbolic_data
arguments: tag: D34
datatype: string
name: extract_symbolic_data
arguments: tag: D66
datatype: string
name: extract_symbolic_data
arguments: tag: D104
datatype: string

tool: D64: %s is %d years old


tool: D2: Alan

tool: D53: Frank

tool: D91: Mary

tool: D23: John

tool: D45: Lisa

tool: D111: ---

tool: D34: %s is %d years alive


tool: D66: %s has lived %d years


tool: D104: %s's age is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int ages[] = {22, 36, 27, 23, 2};
  char *names[] = {"Alan", "Frank", "Mary", "John", "Lisa"};
  int count = sizeof(ages) / sizeof(int);
  int i = 0;
  for (; i < count; i++) {
    printf("%s is %d years old\n", names[i], ages[i]);
  }
  printf("---\n");
  int *cur_age = ages;
  char **cur_name = names;
  for (i = 0; i < count + 1; i++) {
    printf("%s is %d years alive\n", *(cur_name + i), *(cur_age + i));
  }
  printf("---\n");
  for (i = -1; i++, i < count;) {
    printf("%s has lived %d years\n", cur_name[i], cur_age[i]);
  }
  printf("---\n");
  for (cur_age = ages, cur_name = names; (cur_age - ages) < count; cur_age++) {
    printf("%s's age is %d\n", *cur_name, *cur_age);
  }
  return 0;
}
```