ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L12:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int n) {
  int ret = 0;
  int i = 0;
  for (i = 1; i <= n; ++i) {
    ret += i;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sum>:
  endbr64
  test   %edi,%edi
  jle    L25
  add    $0x1,%edi
  mov    $0x1,%eax
  mov    $0x0,%edx
L17:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L17
L16:
  mov    %edx,%eax
  ret
L25:
  mov    $0x0,%edx
  jmp    L16
```

assistant: ```c
int sum(int n) {
  int ret = 0;
  int i = 0;
  for (i = 1; i <= n; ++i) {
    ret += i;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  test   %edi,%edi
  jle    L19
  add    $0x1,%edi
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L6:
  add    %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L6
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sum(int n) {
  int ret = 0;
  int i = 0;
  for (i = 1; i <= n; ++i) {
    ret += i;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  jle    L107
  lea    -0x1(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L93
  mov    %edi,%ecx
  movdqa D13(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D7(%rip),%xmm3
  shr    $0x2,%ecx
  nopl   (%rax)
L6:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L6
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  lea    0x1(%rsi),%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L74
L100:
  lea    0x1(%rcx),%esi
  add    %ecx,%eax
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x2(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x6(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x7(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  lea    0x8(%rcx),%esi
  cmp    %esi,%edx
  jl     L113
  add    %esi,%eax
  add    $0x9,%ecx
  lea    (%rax,%rcx,1),%esi
  cmp    %ecx,%edx
  cmovge %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L107:
  xor    %eax,%eax
L113:
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  ret
L93:
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L100
```

tool_calls: name: read_data
arguments: data_label: D13
datatype: byte[16]
name: read_data
arguments: data_label: D7
datatype: byte[16]

tool: {"D13": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D7": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int sum(int n) {
  int ret = 0;
  int i = 0;
  for (i = 1; i <= n; ++i) {
    ret += i;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memoryIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0xffff,-0x8(%rbp)
  ja     L6
  mov    -0x8(%rbp),%rax
  jmp    L7
L6:
  mov    $0xffff,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
size_t memoryIndex(size_t p) {
  if (p < 0)
    return 0;
  else if (p < 65536)
    return p;
  else
    return 65536 - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<memoryIndex>:
  endbr64
  mov    $0xffff,%eax
  cmp    %rax,%rdi
  cmovbe %rdi,%rax
  ret
```

assistant: ```c
size_t memoryIndex(size_t p) {
  if (p < 0)
    return 0;
  else if (p < 65536)
    return p;
  else
    return 65536 - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memoryIndex>:
  endbr64
  mov    $0xffff,%eax
  cmp    %rax,%rdi
  cmovbe %rdi,%rax
  ret
```

assistant: ```c
size_t memoryIndex(size_t p) {
  if (p < 0)
    return 0;
  else if (p < 65536)
    return p;
  else
    return 65536 - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test1_f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0x14(%rbp)
  mov    $0x0,%eax
  call   <test1_f1@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L5
  movq   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x3,(%rax)
L5:
  cmpl   $0x2,-0x14(%rbp)
  jne    L17
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x3,(%rax)
L17:
  nop
  leave
  ret
```

assistant: ```c
void test1_f2() {
  int x = 1;
  x = test1_f1();
  if (x == 1) {
    int *p = 0;
    *p = 3;
  }
  if (x == 2) {
    int *p = 0;
    *p = 3;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test1_f2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test1_f1@plt>
  cmp    $0x1,%eax
  je     L23
  cmp    $0x2,%eax
  jne    L16
  movl   $0x3,0x0
  jmp    L16
L23:
  movl   $0x3,0x0
L16:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test1_f2() {
  int x = 1;
  x = test1_f1();
  if (x == 1) {
    int *p = 0;
    *p = 3;
  }
  if (x == 2) {
    int *p = 0;
    *p = 3;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test1_f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test1_f1@plt>
  cmp    $0x1,%eax
  je     L15
  cmp    $0x2,%eax
  jne    L11
L15:
  movl   $0x0,0x0
  ud2
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test1_f2() {
  int x = 1;
  x = test1_f1();
  if (x == 1) {
    int *p = 0;
    *p = 3;
  }
  if (x == 2) {
    int *p = 0;
    *p = 3;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test1_f2>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test1_f1@plt>
  cmp    $0x1,%eax
  je     L15
  cmp    $0x2,%eax
  jne    L11
L15:
  movl   $0x0,0x0
  ud2
  cs nopw 0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test1_f2() {
  int x = 1;
  x = test1_f1();
  if (x == 1) {
    int *p = 0;
    *p = 3;
  }
  if (x == 2) {
    int *p = 0;
    *p = 3;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dlmallocfork_save>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_footsize@plt>
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <_datasize@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x4(%rax),%ecx
  mov    -0x30(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  sub    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x30(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void dlmallocfork_save(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int TOP_FOOT_SIZE = _footsize(source, source_max);
  int i = 0;
  int datalen = _datasize(source, source_max);
  target[0] = (datalen >> 24) & 0xFF;
  target[1] = (datalen >> 16) & 0xFF;
  target[2] = (datalen >> 8) & 0xFF;
  target[3] = (datalen >> 0) & 0xFF;
  memcpy(&target[4], source, target_max - (4 + TOP_FOOT_SIZE));
  memcpy(&target[target_max - TOP_FOOT_SIZE], &source[source_max - (TOP_FOOT_SIZE - i)], TOP_FOOT_SIZE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dlmallocfork_save>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  call   <_footsize@plt>
  mov    %eax,%r13d
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <_datasize@plt>
  mov    %eax,%edx
  shr    $0x18,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rbp)
  movzbl %ah,%edx
  mov    %edx,0x8(%rbp)
  and    $0xff,%eax
  mov    %eax,0xc(%rbp)
  lea    0x4(%r13),%eax
  mov    %r12d,%edx
  sub    %eax,%edx
  lea    0x10(%rbp),%rdi
  mov    %r14,%rsi
  call   <memcpy@plt>
  sub    %r13d,%ebx
  movslq %ebx,%rbx
  lea    (%r14,%rbx,4),%rsi
  sub    %r13d,%r12d
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,4),%rdi
  mov    %r13d,%edx
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void dlmallocfork_save(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int TOP_FOOT_SIZE = _footsize(source, source_max);
  int i = 0;
  int datalen = _datasize(source, source_max);
  target[0] = (datalen >> 24) & 0xFF;
  target[1] = (datalen >> 16) & 0xFF;
  target[2] = (datalen >> 8) & 0xFF;
  target[3] = (datalen >> 0) & 0xFF;
  memcpy(&target[4], source, target_max - (4 + TOP_FOOT_SIZE));
  memcpy(&target[target_max - TOP_FOOT_SIZE], &source[source_max - (TOP_FOOT_SIZE - i)], TOP_FOOT_SIZE);
}
```
user: What is the c source code of the assembly code below?

```asm
<dlmallocfork_save>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_footsize@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <_datasize@plt>
  sub    %r13d,%ebx
  lea    0x10(%r12),%rdi
  mov    %r14,%rsi
  mov    %eax,%edx
  movslq %ebx,%rbx
  shr    $0x18,%edx
  mov    %edx,(%r12)
  mov    %eax,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%r12)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x8(%r12)
  mov    %ebp,%edx
  sub    %r13d,%ebp
  mov    %eax,0xc(%r12)
  lea    0x4(%r13),%eax
  movslq %ebp,%rbp
  sub    %eax,%edx
  call   <memcpy@plt>
  lea    (%r14,%rbx,4),%rsi
  lea    (%r12,%rbp,4),%rdi
  pop    %rbx
  mov    %r13d,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <memcpy@plt>
```

assistant: ```c
void dlmallocfork_save(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int TOP_FOOT_SIZE = _footsize(source, source_max);
  int i = 0;
  int datalen = _datasize(source, source_max);
  target[0] = (datalen >> 24) & 0xFF;
  target[1] = (datalen >> 16) & 0xFF;
  target[2] = (datalen >> 8) & 0xFF;
  target[3] = (datalen >> 0) & 0xFF;
  memcpy(&target[4], source, target_max - (4 + TOP_FOOT_SIZE));
  memcpy(&target[target_max - TOP_FOOT_SIZE], &source[source_max - (TOP_FOOT_SIZE - i)], TOP_FOOT_SIZE);
}
```
user: What is the c source code of the assembly code below?

```asm
<dlmallocfork_save>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_footsize@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <_datasize@plt>
  sub    %r12d,%ebx
  lea    0x10(%r13),%rdi
  mov    %r14,%rsi
  mov    %eax,%ecx
  mov    %eax,%edx
  movslq %ebx,%rbx
  shr    $0x18,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %dl,%edx
  movzbl %ah,%ecx
  movzbl %al,%eax
  movd   %eax,%xmm2
  movd   %edx,%xmm3
  movd   %ecx,%xmm1
  mov    %ebp,%edx
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  lea    0x4(%r12),%eax
  sub    %r12d,%ebp
  punpcklqdq %xmm1,%xmm0
  sub    %eax,%edx
  movslq %ebp,%rbp
  movups %xmm0,0x0(%r13)
  call   <memcpy@plt>
  lea    (%r14,%rbx,4),%rsi
  lea    0x0(%r13,%rbp,4),%rdi
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <memcpy@plt>
```

assistant: ```c
void dlmallocfork_save(void *_source, int source_max, void *_target, int target_max) {
  uint8_t *source = (uint8_t *)_source;
  uint8_t *target = (uint8_t *)_target;
  int TOP_FOOT_SIZE = _footsize(source, source_max);
  int i = 0;
  int datalen = _datasize(source, source_max);
  target[0] = (datalen >> 24) & 0xFF;
  target[1] = (datalen >> 16) & 0xFF;
  target[2] = (datalen >> 8) & 0xFF;
  target[3] = (datalen >> 0) & 0xFF;
  memcpy(&target[4], source, target_max - (4 + TOP_FOOT_SIZE));
  memcpy(&target[target_max - TOP_FOOT_SIZE], &source[source_max - (TOP_FOOT_SIZE - i)], TOP_FOOT_SIZE);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tp_serial_flush_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x24(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    $0xc350,%edi
  call   <usleep@plt>
  jmp    L19
L20:
  lea    -0x25(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x24(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
L19:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  cmp    $0x1,%eax
  je     L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void tp_serial_flush_input(int fd) {
  struct timeval tv;
  fd_set rfds;
  unsigned char junk;
  FD_ZERO(&rfds);
  FD_SET(fd, &rfds);
  tv.tv_sec = 0;
  tv.tv_usec = 0;
  usleep(50000);
  while (select(fd + 1, &rfds, NULL, NULL, &tv) == 1) {
    read(fd, &junk, 1);
    FD_ZERO(&rfds);
    FD_SET(fd, &rfds);
    tv.tv_sec = 0;
    tv.tv_usec = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<tp_serial_flush_input>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    $0xc350,%edi
  call   <usleep@plt>
  lea    0x10(%rsp),%r12
  jmp    L21
L26:
  lea    0xb(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebx,%edi
  call   <read@plt>
  lea    0xc(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <FD_SET@plt>
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
L21:
  lea    0xc(%rsp),%rsi
  lea    0x1(%rbx),%edi
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  call   <select@plt>
  cmp    $0x1,%eax
  je     L26
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tp_serial_flush_input(int fd) {
  struct timeval tv;
  fd_set rfds;
  unsigned char junk;
  FD_ZERO(&rfds);
  FD_SET(fd, &rfds);
  tv.tv_sec = 0;
  tv.tv_usec = 0;
  usleep(50000);
  while (select(fd + 1, &rfds, NULL, NULL, &tv) == 1) {
    read(fd, &junk, 1);
    FD_ZERO(&rfds);
    FD_SET(fd, &rfds);
    tv.tv_sec = 0;
    tv.tv_usec = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tp_serial_flush_input>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x1(%rbp),%r13d
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r12
  mov    %rbx,%rdi
  lea    0xb(%rsp),%r14
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    $0xc350,%edi
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <usleep@plt>
  jmp    L2
  nopl   (%rax)
L6:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
L2:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  cmp    $0x1,%eax
  je     L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tp_serial_flush_input(int fd) {
  struct timeval tv;
  fd_set rfds;
  unsigned char junk;
  FD_ZERO(&rfds);
  FD_SET(fd, &rfds);
  tv.tv_sec = 0;
  tv.tv_usec = 0;
  usleep(50000);
  while (select(fd + 1, &rfds, NULL, NULL, &tv) == 1) {
    read(fd, &junk, 1);
    FD_ZERO(&rfds);
    FD_SET(fd, &rfds);
    tv.tv_sec = 0;
    tv.tv_usec = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tp_serial_flush_input>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x1(%rbp),%r13d
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r12
  mov    %rbx,%rdi
  lea    0xb(%rsp),%r14
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  pxor   %xmm0,%xmm0
  mov    $0xc350,%edi
  movaps %xmm0,0x10(%rsp)
  call   <usleep@plt>
  jmp    L0
  nopl   0x0(%rax)
L24:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
L0:
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  cmp    $0x1,%eax
  je     L24
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tp_serial_flush_input(int fd) {
  struct timeval tv;
  fd_set rfds;
  unsigned char junk;
  FD_ZERO(&rfds);
  FD_SET(fd, &rfds);
  tv.tv_sec = 0;
  tv.tv_usec = 0;
  usleep(50000);
  while (select(fd + 1, &rfds, NULL, NULL, &tv) == 1) {
    read(fd, &junk, 1);
    FD_ZERO(&rfds);
    FD_SET(fd, &rfds);
    tv.tv_sec = 0;
    tv.tv_usec = 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fn1@plt>
  mov    -0x14(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
int *fn2(int i) {
  int *p = i;
  p = i;
  fn1(i);
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fn2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <fn1@plt>
  movslq %ebx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *fn2(int i) {
  int *p = i;
  p = i;
  fn1(i);
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn2>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <fn1@plt>
  movslq %ebx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *fn2(int i) {
  int *p = i;
  p = i;
  fn1(i);
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<fn2>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <fn1@plt>
  movslq %ebx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int *fn2(int i) {
  int *p = i;
  p = i;
  fn1(i);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<expand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L59:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L79
  cmpl   $0x0,-0xc(%rbp)
  je     L43
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jle    L53
L43:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L86
L53:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  add    $0x1,%eax
  mov    %al,-0xe(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xe(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L73
L72:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
L73:
  movsbl -0xd(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L72
  addl   $0x1,-0xc(%rbp)
  jmp    L86
L79:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L86:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L59
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void expand(char s[], char t[]) {
  int i, j, k;
  char b, e;
  k = 0;
  for (i = 0; i < strlen(s); i++) {
    if (s[i] == '-') {
      if (i == 0 || s[i - 1] > s[i + 1])
        t[k++] = s[i];
      else {
        b = s[i - 1] + 1;
        e = s[i + 1];
        for (j = b; j <= e; j++)
          t[k++] = j;
        i++;
      }
    } else
      t[k++] = s[i];
  }
  t[k] = '\0';
}
```