ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sign>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L1
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L1:
  ret
```

assistant: ```c
int sign(const int x) {
  if (x == 0) {
    return 0;
  }
  return x > 0 ? 1 : -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<sign>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L6
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L6:
  ret
```

assistant: ```c
int sign(const int x) {
  if (x == 0) {
    return 0;
  }
  return x > 0 ? 1 : -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sign>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L1
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L1:
  ret
```

assistant: ```c
int sign(const int x) {
  if (x == 0) {
    return 0;
  }
  return x > 0 ? 1 : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sendToSock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L92
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <waitForWrite@plt>
  cmp    $0x1,%eax
  je     L72
  mov    $0xffffffff,%eax
  jmp    L61
L92:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <canWrite@plt>
  cmp    $0x1,%eax
  je     L72
  mov    $0xffffffff,%eax
  jmp    L61
L72:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L75
L37:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L31
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L31:
  nop
L75:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L37
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L94
  mov    $0x1,%eax
  jmp    L61
L94:
  mov    $0xffffffff,%eax
L61:
  leave
  ret
```

assistant: ```c
int sendToSock(int sockFd, char *buffer, int length, int isBlock) {
  if (isBlock) {
    if (waitForWrite(sockFd, NULL) != 1) {
      return -1;
    }
  } else {
    if (canWrite(sockFd) != 1) {
      return -1;
    }
  }
  int temp = 0;
  int sentSum = 0;
  while (sentSum < length) {
    temp = send(sockFd, buffer + sentSum, length - sentSum, 0);
    if (temp > 0) {
      sentSum += temp;
    }
    continue;
  }
  if (sentSum == length) {
    return 1;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sendToSock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  test   %ecx,%ecx
  je     L16
  mov    $0x0,%esi
  call   <waitForWrite@plt>
  mov    %eax,%edx
  mov    $0xffffffff,%eax
  cmp    $0x1,%edx
  jne    L17
L66:
  mov    $0x0,%r13d
  test   %ebx,%ebx
  jg     L34
L59:
  cmp    %r13d,%ebx
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <canWrite@plt>
  mov    %eax,%edx
  mov    $0xffffffff,%eax
  cmp    $0x1,%edx
  jne    L17
  jmp    L66
L34:
  mov    %ebx,%edx
  sub    %r13d,%edx
  movslq %r13d,%rsi
  add    %r12,%rsi
  mov    $0x0,%ecx
  mov    %ebp,%edi
  call   <send@plt>
  lea    0x0(%r13,%rax,1),%edx
  test   %eax,%eax
  cmovg  %edx,%r13d
  cmp    %r13d,%ebx
  jle    L59
  jmp    L34
```

assistant: ```c
int sendToSock(int sockFd, char *buffer, int length, int isBlock) {
  if (isBlock) {
    if (waitForWrite(sockFd, NULL) != 1) {
      return -1;
    }
  } else {
    if (canWrite(sockFd) != 1) {
      return -1;
    }
  }
  int temp = 0;
  int sentSum = 0;
  while (sentSum < length) {
    temp = send(sockFd, buffer + sentSum, length - sentSum, 0);
    if (temp > 0) {
      sentSum += temp;
    }
    continue;
  }
  if (sentSum == length) {
    return 1;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendToSock>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %ecx,%ecx
  je     L23
  xor    %esi,%esi
  call   <waitForWrite@plt>
  cmp    $0x1,%eax
  je     L28
L55:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L23:
  call   <canWrite@plt>
  cmp    $0x1,%eax
  jne    L55
L28:
  xor    %r13d,%r13d
  test   %ebx,%ebx
  jg     L32
L16:
  cmp    %r13d,%ebx
  jne    L55
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L32:
  movslq %r13d,%rsi
  mov    %ebx,%edx
  xor    %ecx,%ecx
  mov    %ebp,%edi
  sub    %r13d,%edx
  add    %r12,%rsi
  call   <send@plt>
  lea    0x0(%r13,%rax,1),%edx
  test   %eax,%eax
  cmovg  %edx,%r13d
  cmp    %ebx,%r13d
  jge    L16
  jmp    L32
```

assistant: ```c
int sendToSock(int sockFd, char *buffer, int length, int isBlock) {
  if (isBlock) {
    if (waitForWrite(sockFd, NULL) != 1) {
      return -1;
    }
  } else {
    if (canWrite(sockFd) != 1) {
      return -1;
    }
  }
  int temp = 0;
  int sentSum = 0;
  while (sentSum < length) {
    temp = send(sockFd, buffer + sentSum, length - sentSum, 0);
    if (temp > 0) {
      sentSum += temp;
    }
    continue;
  }
  if (sentSum == length) {
    return 1;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sendToSock>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  test   %ecx,%ecx
  je     L88
  xor    %esi,%esi
  call   <waitForWrite@plt>
  cmp    $0x1,%eax
  je     L31
L78:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L88:
  call   <canWrite@plt>
  cmp    $0x1,%eax
  jne    L78
L31:
  xor    %r13d,%r13d
  test   %ebx,%ebx
  jg     L53
L51:
  cmp    %r13d,%ebx
  jne    L78
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L53:
  xor    %r14d,%r14d
L96:
  mov    %ebx,%edx
  xor    %ecx,%ecx
  lea    (%r12,%r14,1),%rsi
  mov    %ebp,%edi
  sub    %r13d,%edx
  call   <send@plt>
  test   %eax,%eax
  jle    L22
  add    %eax,%r13d
  cmp    %r13d,%ebx
  jle    L51
  movslq %r13d,%r14
  jmp    L96
  cs nopw 0x0(%rax,%rax,1)
L22:
  cmp    %r13d,%ebx
  jle    L51
  jmp    L96
```

assistant: ```c
int sendToSock(int sockFd, char *buffer, int length, int isBlock) {
  if (isBlock) {
    if (waitForWrite(sockFd, NULL) != 1) {
      return -1;
    }
  } else {
    if (canWrite(sockFd) != 1) {
      return -1;
    }
  }
  int temp = 0;
  int sentSum = 0;
  while (sentSum < length) {
    temp = send(sockFd, buffer + sentSum, length - sentSum, 0);
    if (temp > 0) {
      sentSum += temp;
    }
    continue;
  }
  if (sentSum == length) {
    return 1;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sphere_func>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <vec3_norm@plt>
  pxor   %xmm7,%xmm7
  cvtsi2ss %eax,%xmm7
  movss  %xmm7,0x8(%rsp)
  movss  (%rbx),%xmm3
  ucomiss D3(%rip),%xmm3
  jp     L36
  jne    L36
  pxor   %xmm0,%xmm0
  ucomiss 0x4(%rbx),%xmm0
  jp     L36
  jne    L36
  ucomiss 0x8(%rbx),%xmm0
  jp     L36
  je     L73
L36:
  movss  0x0(%rbp),%xmm1
  movss  0x4(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  0x8(%rbp),%xmm4
  movaps %xmm2,%xmm6
  mulss  %xmm4,%xmm6
  movss  %xmm6,0xc(%rsp)
  mulss  %xmm4,%xmm0
  mulss  %xmm3,%xmm0
  movss  0x8(%rsp),%xmm5
  divss  %xmm5,%xmm0
  movss  %xmm0,0x1c(%rsp)
  mulss  %xmm4,%xmm1
  mulss  0x4(%rbx),%xmm1
  divss  %xmm5,%xmm1
  movss  %xmm1,0x20(%rsp)
  mulss  0x8(%rbx),%xmm2
  divss  %xmm5,%xmm2
  movss  %xmm2,0x24(%rsp)
  lea    0x1c(%rsp),%rdi
  mov    $0x0,%eax
  call   <vec3_norm@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  subss  0x8(%rsp),%xmm0
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L73:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd 0x8(%rbp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rbp),%xmm1
  mov    $0x3,%eax
  call   <max3@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L3
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x00]}

assistant: ```c
float sphere_func(const float p[3], const float s[3], float smoothness) {
  float d = vec3_norm(p);
  float r;
  if (p[0] == 0 && p[1] == 0 && p[2] == 0)
    return max3(s[0], s[1], s[2]);
  r = s[0] * s[1] * s[2] / vec3_norm(((float[]){s[1] * s[2] * p[0] / d, s[0] * s[2] * p[1] / d, s[0] * s[1] * p[2] / d}));
  return r - d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sphere_func>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <vec3_norm@plt>
  movss  (%rbx),%xmm6
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  cvtsi2ss %eax,%xmm4
  movss  0x4(%rbx),%xmm7
  movss  0x8(%rbx),%xmm8
  ucomiss %xmm0,%xmm6
  jp     L35
  jne    L35
  ucomiss %xmm0,%xmm7
  jp     L35
  jne    L35
  ucomiss %xmm0,%xmm8
  jp     L35
  je     L77
L35:
  movss  0x0(%rbp),%xmm1
  movss  0x8(%rbp),%xmm5
  lea    0x1c(%rsp),%rdi
  xor    %eax,%eax
  movss  0x4(%rbp),%xmm2
  movss  %xmm4,0x8(%rsp)
  movaps %xmm1,%xmm3
  mulss  %xmm2,%xmm3
  mulss  %xmm5,%xmm1
  mulss  %xmm5,%xmm2
  movaps %xmm3,%xmm0
  mulss  %xmm7,%xmm1
  mulss  %xmm6,%xmm2
  mulss  %xmm8,%xmm3
  mulss  %xmm5,%xmm0
  divss  %xmm4,%xmm1
  movss  %xmm0,0xc(%rsp)
  divss  %xmm4,%xmm2
  movss  %xmm1,0x20(%rsp)
  divss  %xmm4,%xmm3
  movss  %xmm2,0x1c(%rsp)
  movss  %xmm3,0x24(%rsp)
  call   <vec3_norm@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm4
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  subss  %xmm4,%xmm0
L59:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L77:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtss2sd 0x0(%rbp),%xmm0
  cvtss2sd 0x8(%rbp),%xmm2
  cvtss2sd 0x4(%rbp),%xmm1
  call   <max3@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L59
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float sphere_func(const float p[3], const float s[3], float smoothness) {
  float d = vec3_norm(p);
  float r;
  if (p[0] == 0 && p[1] == 0 && p[2] == 0)
    return max3(s[0], s[1], s[2]);
  r = s[0] * s[1] * s[2] / vec3_norm(((float[]){s[1] * s[2] * p[0] / d, s[0] * s[2] * p[1] / d, s[0] * s[1] * p[2] / d}));
  return r - d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sphere_func>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <vec3_norm@plt>
  movss  (%rbx),%xmm6
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  cvtsi2ss %eax,%xmm4
  movss  0x4(%rbx),%xmm8
  movss  0x8(%rbx),%xmm7
  ucomiss %xmm0,%xmm6
  jp     L49
  jne    L49
  ucomiss %xmm0,%xmm8
  jp     L49
  jne    L49
  ucomiss %xmm0,%xmm7
  jp     L49
  je     L1
L49:
  movss  0x0(%rbp),%xmm2
  movss  0x8(%rbp),%xmm5
  lea    0x18(%rsp),%rdi
  xor    %eax,%eax
  movss  0x4(%rbp),%xmm1
  movss  %xmm4,0x8(%rsp)
  movaps %xmm2,%xmm3
  mulss  %xmm1,%xmm3
  mulss  %xmm5,%xmm2
  mulss  %xmm5,%xmm1
  movaps %xmm3,%xmm0
  mulss  %xmm8,%xmm2
  mulss  %xmm6,%xmm1
  mulss  %xmm7,%xmm3
  mulss  %xmm5,%xmm0
  divss  %xmm4,%xmm2
  movss  %xmm0,0xc(%rsp)
  divss  %xmm4,%xmm1
  divss  %xmm4,%xmm3
  unpcklps %xmm2,%xmm1
  movlps %xmm1,0x18(%rsp)
  movss  %xmm3,0x20(%rsp)
  call   <vec3_norm@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm4
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  subss  %xmm4,%xmm0
L64:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtss2sd 0x0(%rbp),%xmm0
  cvtss2sd 0x8(%rbp),%xmm2
  cvtss2sd 0x4(%rbp),%xmm1
  call   <max3@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  jmp    L64
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float sphere_func(const float p[3], const float s[3], float smoothness) {
  float d = vec3_norm(p);
  float r;
  if (p[0] == 0 && p[1] == 0 && p[2] == 0)
    return max3(s[0], s[1], s[2]);
  r = s[0] * s[1] * s[2] / vec3_norm(((float[]){s[1] * s[2] * p[0] / d, s[0] * s[2] * p[1] / d, s[0] * s[1] * p[2] / d}));
  return r - d;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<determinant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  0x8(%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  0x10(%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  0x10(%rax),%xmm0
  mulsd  %xmm0,%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  0x10(%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  0x8(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  0x10(%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  0x8(%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  0x10(%rax),%xmm0
  mulsd  %xmm0,%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  0x8(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x18(%rbp),%rax
  movsd  0x8(%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x30,%rax
  movsd  0x10(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double determinant(matrix)
double matrix[3][3];
{
  double d1, d2;
  d1 = matrix[0][0] * matrix[1][1] * matrix[2][2] + matrix[0][1] * matrix[1][2] * matrix[2][0] + matrix[0][2] * matrix[1][0] * matrix[2][1];
  d2 = matrix[0][2] * matrix[1][1] * matrix[2][0] + matrix[0][0] * matrix[1][2] * matrix[2][1] + matrix[0][1] * matrix[1][0] * matrix[2][2];
  return (d1 - d2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<determinant>:
  endbr64
  movsd  (%rdi),%xmm3
  movsd  0x20(%rdi),%xmm1
  movsd  0x40(%rdi),%xmm5
  movsd  0x8(%rdi),%xmm2
  movsd  0x28(%rdi),%xmm8
  movsd  0x30(%rdi),%xmm9
  movsd  0x10(%rdi),%xmm10
  movsd  0x18(%rdi),%xmm6
  movsd  0x38(%rdi),%xmm7
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm5,%xmm0
  movapd %xmm2,%xmm4
  mulsd  %xmm8,%xmm4
  mulsd  %xmm9,%xmm4
  addsd  %xmm4,%xmm0
  movapd %xmm10,%xmm4
  mulsd  %xmm6,%xmm4
  mulsd  %xmm7,%xmm4
  addsd  %xmm4,%xmm0
  mulsd  %xmm10,%xmm1
  mulsd  %xmm9,%xmm1
  mulsd  %xmm8,%xmm3
  mulsd  %xmm7,%xmm3
  addsd  %xmm3,%xmm1
  mulsd  %xmm6,%xmm2
  mulsd  %xmm5,%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double determinant(matrix)
double matrix[3][3];
{
  double d1, d2;
  d1 = matrix[0][0] * matrix[1][1] * matrix[2][2] + matrix[0][1] * matrix[1][2] * matrix[2][0] + matrix[0][2] * matrix[1][0] * matrix[2][1];
  d2 = matrix[0][2] * matrix[1][1] * matrix[2][0] + matrix[0][0] * matrix[1][2] * matrix[2][1] + matrix[0][1] * matrix[1][0] * matrix[2][2];
  return (d1 - d2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<determinant>:
  endbr64
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm2
  movsd  0x20(%rdi),%xmm1
  movsd  0x28(%rdi),%xmm8
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm4
  movsd  0x40(%rdi),%xmm5
  movsd  0x30(%rdi),%xmm9
  mulsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm10
  movsd  0x18(%rdi),%xmm6
  mulsd  %xmm8,%xmm4
  movsd  0x38(%rdi),%xmm7
  mulsd  %xmm10,%xmm1
  mulsd  %xmm8,%xmm3
  mulsd  %xmm6,%xmm2
  mulsd  %xmm5,%xmm0
  mulsd  %xmm9,%xmm4
  mulsd  %xmm9,%xmm1
  mulsd  %xmm7,%xmm3
  mulsd  %xmm5,%xmm2
  addsd  %xmm4,%xmm0
  movapd %xmm10,%xmm4
  mulsd  %xmm6,%xmm4
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm7,%xmm4
  addsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double determinant(matrix)
double matrix[3][3];
{
  double d1, d2;
  d1 = matrix[0][0] * matrix[1][1] * matrix[2][2] + matrix[0][1] * matrix[1][2] * matrix[2][0] + matrix[0][2] * matrix[1][0] * matrix[2][1];
  d2 = matrix[0][2] * matrix[1][1] * matrix[2][0] + matrix[0][0] * matrix[1][2] * matrix[2][1] + matrix[0][1] * matrix[1][0] * matrix[2][2];
  return (d1 - d2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<determinant>:
  endbr64
  movsd  (%rdi),%xmm3
  movsd  0x8(%rdi),%xmm2
  movsd  0x20(%rdi),%xmm1
  movsd  0x28(%rdi),%xmm8
  movapd %xmm3,%xmm0
  movapd %xmm2,%xmm4
  movsd  0x40(%rdi),%xmm5
  movsd  0x30(%rdi),%xmm9
  mulsd  %xmm1,%xmm0
  movsd  0x10(%rdi),%xmm10
  movsd  0x18(%rdi),%xmm6
  mulsd  %xmm8,%xmm4
  movsd  0x38(%rdi),%xmm7
  mulsd  %xmm10,%xmm1
  mulsd  %xmm8,%xmm3
  mulsd  %xmm6,%xmm2
  mulsd  %xmm5,%xmm0
  mulsd  %xmm9,%xmm4
  mulsd  %xmm9,%xmm1
  mulsd  %xmm7,%xmm3
  mulsd  %xmm5,%xmm2
  addsd  %xmm4,%xmm0
  movapd %xmm10,%xmm4
  mulsd  %xmm6,%xmm4
  addsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm7,%xmm4
  addsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double determinant(matrix)
double matrix[3][3];
{
  double d1, d2;
  d1 = matrix[0][0] * matrix[1][1] * matrix[2][2] + matrix[0][1] * matrix[1][2] * matrix[2][0] + matrix[0][2] * matrix[1][0] * matrix[2][1];
  d2 = matrix[0][2] * matrix[1][1] * matrix[2][0] + matrix[0][0] * matrix[1][2] * matrix[2][1] + matrix[0][1] * matrix[1][0] * matrix[2][2];
  return (d1 - d2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L37:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L3
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L8
L3:
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L37
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const size_t nlen = strlen(needle);
  const size_t hlen = strlen(haystack);
  for (size_t i = 0; i < hlen; i++) {
    if (memcmp(haystack + i, needle, nlen) == 0) {
      return (char *)haystack + i;
    }
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L31
  mov    %rbp,%rbx
  add    %rax,%rbp
L32:
  mov    %rbx,%r14
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L19
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L32
  mov    $0x0,%r14d
L19:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  mov    $0x0,%r14d
  jmp    L19
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const size_t nlen = strlen(needle);
  const size_t hlen = strlen(haystack);
  for (size_t i = 0; i < hlen; i++) {
    if (memcmp(haystack + i, needle, nlen) == 0) {
      return (char *)haystack + i;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  test   %rax,%rax
  je     L32
  lea    (%rbx,%rax,1),%rbp
  jmp    L25
L36:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L32
L25:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r14
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L36
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const size_t nlen = strlen(needle);
  const size_t hlen = strlen(haystack);
  for (size_t i = 0; i < hlen; i++) {
    if (memcmp(haystack + i, needle, nlen) == 0) {
      return (char *)haystack + i;
    }
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  test   %rax,%rax
  je     L7
  lea    (%rbx,%rax,1),%rbp
  jmp    L31
L4:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L7
L31:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %rbx,%r14
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const size_t nlen = strlen(needle);
  const size_t hlen = strlen(haystack);
  for (size_t i = 0; i < hlen; i++) {
    if (memcmp(haystack + i, needle, nlen) == 0) {
      return (char *)haystack + i;
    }
  }
  return NULL;
}
```