ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_ternary>:
  endbr64
  push   %rbx
  mov    $0x33,%ecx
  mov    $0x33,%edx
  mov    $0x44,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x45,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x1a,%ecx
  mov    $0x1a,%edx
  mov    $0x46,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x11,%ecx
  mov    $0x11,%edx
  mov    $0x47,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x49,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x4a,%esi
  mov    %rbx,%rdi
  call   <fexpect@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c

assistant: ```c
void test_ternary() {
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 68, 51, (1 + 2) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 69, 52, (1 - 1) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 70, 26, (1 - 1) ? 51 : 52 / 2);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 71, 17, (1 - 0) ? 51 / 3 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 73, 52, 0 ?: 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 74, 3, (1 + 2) ?: 52);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_ternary>:
  endbr64
  push   %rbp
  mov    $0x33,%ecx
  mov    $0x33,%edx
  mov    $0x44,%esi
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x45,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x1a,%ecx
  mov    $0x1a,%edx
  mov    $0x46,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x11,%ecx
  mov    $0x11,%edx
  mov    $0x47,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x49,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  pop    %rbp
  mov    $0x3,%edx
  mov    $0x4a,%esi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c

assistant: ```c
void test_ternary() {
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 68, 51, (1 + 2) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 69, 52, (1 - 1) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 70, 26, (1 - 1) ? 51 : 52 / 2);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 71, 17, (1 - 0) ? 51 / 3 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 73, 52, 0 ?: 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 74, 3, (1 + 2) ?: 52);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_ternary>:
  endbr64
  push   %rbp
  mov    $0x33,%ecx
  mov    $0x33,%edx
  mov    $0x44,%esi
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x45,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x1a,%ecx
  mov    $0x1a,%edx
  mov    $0x46,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x11,%ecx
  mov    $0x11,%edx
  mov    $0x47,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x34,%ecx
  mov    $0x34,%edx
  mov    $0x49,%esi
  call   <fexpect@plt>
  mov    %rbp,%rdi
  mov    $0x3,%ecx
  pop    %rbp
  mov    $0x3,%edx
  mov    $0x4a,%esi
  jmp    1050 <fexpect@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c

assistant: ```c
void test_ternary() {
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 68, 51, (1 + 2) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 69, 52, (1 - 1) ? 51 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 70, 26, (1 - 1) ? 51 : 52 / 2);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 71, 17, (1 - 0) ? 51 / 3 : 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 73, 52, 0 ?: 52);
  ;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/arith.c", 74, 3, (1 + 2) ?: 52);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<random_ramp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <random_uniform@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <random_uniform@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmax@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double random_ramp(void) {
  double x1 = random_uniform();
  double x2 = random_uniform();
  double y = fmax(x1, x2);
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<random_ramp>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <random_uniform@plt>
  movq   %xmm0,%rbx
  mov    $0x0,%eax
  call   <random_uniform@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  call   <fmax@plt>
  pop    %rbx
  ret
```

assistant: ```c
double random_ramp(void) {
  double x1 = random_uniform();
  double x2 = random_uniform();
  double y = fmax(x1, x2);
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_ramp>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <random_uniform@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <random_uniform@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  jmp    1070 <fmax@plt>
```

assistant: ```c
double random_ramp(void) {
  double x1 = random_uniform();
  double x2 = random_uniform();
  double y = fmax(x1, x2);
  return y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<random_ramp>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <random_uniform@plt>
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <random_uniform@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  jmp    1070 <fmax@plt>
```

assistant: ```c
double random_ramp(void) {
  double x1 = random_uniform();
  double x2 = random_uniform();
  double y = fmax(x1, x2);
  return y;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x2,%eax
  cmp    $0x3,%eax
  jbe    L3
  mov    $0x6,%eax
  jmp    L2
L3:
  mov    $0x7,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int f(int i) {
  switch (i) {
  case -1:
    __attribute__((fallthrough));
  default:
    __attribute__((fallthrough));
  case 1:
    return 6;
  case 2 ... 4:
    __attribute__((fallthrough));
  case 5:
    return 7;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x2,%edi
  cmp    $0x4,%edi
  setb   %al
  movzbl %al,%eax
  add    $0x6,%eax
  ret
```

assistant: ```c
int f(int i) {
  switch (i) {
  case -1:
    __attribute__((fallthrough));
  default:
    __attribute__((fallthrough));
  case 1:
    return 6;
  case 2 ... 4:
    __attribute__((fallthrough));
  case 5:
    return 7;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x2,%edi
  xor    %eax,%eax
  cmp    $0x4,%edi
  setb   %al
  add    $0x6,%eax
  ret
```

assistant: ```c
int f(int i) {
  switch (i) {
  case -1:
    __attribute__((fallthrough));
  default:
    __attribute__((fallthrough));
  case 1:
    return 6;
  case 2 ... 4:
    __attribute__((fallthrough));
  case 5:
    return 7;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  sub    $0x2,%edi
  xor    %eax,%eax
  cmp    $0x4,%edi
  setb   %al
  add    $0x6,%eax
  ret
```

assistant: ```c
int f(int i) {
  switch (i) {
  case -1:
    __attribute__((fallthrough));
  default:
    __attribute__((fallthrough));
  case 1:
    return 6;
  case 2 ... 4:
    __attribute__((fallthrough));
  case 5:
    return 7;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_size_two_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  cmpq   $0x0,-0x10(%rbp)
  jne    L16
L21:
  mov    $0x1,%eax
  jmp    L13
L16:
  mov    -0x10(%rbp),%rax
  movq   $0x2,(%rax)
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int _size_two_bytes(struct MIDIMessageData *data, size_t *size) {
  if (data == NULL || size == NULL)
    return 1;
  *size = 2;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_size_two_bytes>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %rsi,%rsi
  je     L1
  movq   $0x2,(%rsi)
  mov    $0x0,%eax
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _size_two_bytes(struct MIDIMessageData *data, size_t *size) {
  if (data == NULL || size == NULL)
    return 1;
  *size = 2;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_size_two_bytes>:
  endbr64
  test   %rdi,%rdi
  je     L11
  test   %rsi,%rsi
  je     L11
  movq   $0x2,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _size_two_bytes(struct MIDIMessageData *data, size_t *size) {
  if (data == NULL || size == NULL)
    return 1;
  *size = 2;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_size_two_bytes>:
  endbr64
  test   %rdi,%rdi
  je     L11
  test   %rsi,%rsi
  je     L11
  movq   $0x2,(%rsi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _size_two_bytes(struct MIDIMessageData *data, size_t *size) {
  if (data == NULL || size == NULL)
    return 1;
  *size = 2;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6548,-0xe(%rbp)
  movw   $0x216f,-0xa(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L24:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L14:
  cmpl   $0x5,-0x14(%rbp)
  jle    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int main(void) {
  char word[] = {'H', 'e', 'l', 'l', 'o', '!'};
  int i;
  for (i = 0; i < 6; ++i) {
    printf("%c", word[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6548,0x2(%rsp)
  movw   $0x216f,0x6(%rsp)
  lea    0x2(%rsp),%rbx
  lea    0x8(%rsp),%rbp
L12:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char word[] = {'H', 'e', 'l', 'l', 'o', '!'};
  int i;
  for (i = 0; i < 6; ++i) {
    printf("%c", word[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x48,%edi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x216f,%eax
  lea    0x2(%rsp),%rbx
  movl   $0x6c6c6548,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  lea    0x8(%rsp),%rbp
  jmp    L24
  nopl   (%rax)
L5:
  movsbl (%rbx),%edi
L24:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char word[] = {'H', 'e', 'l', 'l', 'o', '!'};
  int i;
  for (i = 0; i < 6; ++i) {
    printf("%c", word[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x216f,%eax
  movl   $0x6c6c6548,0x2(%rsp)
  lea    0x2(%rsp),%rbx
  mov    %ax,0x6(%rsp)
  lea    0x8(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char word[] = {'H', 'e', 'l', 'l', 'o', '!'};
  int i;
  for (i = 0; i < 6; ++i) {
    printf("%c", word[i]);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<smileDsp_winHan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  jmp    L12
L7:
  movsd  -0x20(%rbp),%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  movsd  D28(%rip),%xmm2
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  D28(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D28(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L12:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  ja     L7
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
data_type: byte[8]
name: parse_data
arguments: label: D28
data_type: f64
name: parse_data
arguments: label: D19
data_type: f64

tool: {"D29": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D28: 1

tool: D19: 0.5

assistant: ```c
double *smileDsp_winHan(long _N) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = 0.5 * (1.0 - cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0)));
    x++;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<smileDsp_winHan>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  pxor   %xmm6,%xmm6
  cvtsi2sd %rbx,%xmm6
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  comisd %xmm7,%xmm6
  jbe    L4
  movq   %xmm6,%r14
  mov    %rax,%rbx
  subsd  D23(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
L15:
  movsd  D44(%rip),%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D23(%rip),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D38(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  movsd  D23(%rip),%xmm2
  addsd  (%rsp),%xmm2
  movsd  %xmm2,(%rsp)
  movq   %r14,%xmm5
  comisd %xmm2,%xmm5
  ja     L15
L4:
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
type: f64
name: unpack_data
arguments: tag: D44
type: byte[8]
name: unpack_data
arguments: tag: D38
type: f64

tool: D23: 1

tool: {"D44": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D38: 0.5

assistant: ```c
double *smileDsp_winHan(long _N) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = 0.5 * (1.0 - cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0)));
    x++;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<smileDsp_winHan>:
  endbr64
  push   %r14
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%edi
  sub    $0x10,%rsp
  call   <malloc@plt>
  pxor   %xmm5,%xmm5
  pxor   %xmm6,%xmm6
  cvtsi2sd %rbx,%xmm5
  mov    %rax,%r12
  comisd %xmm6,%xmm5
  jbe    L2
  movq   %xmm5,%r14
  subsd  D9(%rip),%xmm5
  pxor   %xmm1,%xmm1
  mov    %rax,%rbx
  movsd  %xmm5,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L8:
  movsd  D19(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm1,%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movsd  (%rsp),%xmm1
  addsd  D9(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  D9(%rip),%xmm0
  movq   %r14,%xmm4
  subsd  %xmm2,%xmm0
  mulsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  comisd %xmm1,%xmm4
  ja     L8
L2:
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: f64
name: parse_data
arguments: data_tag: D19
datatype: byte[8]
name: parse_data
arguments: data_tag: D10
datatype: f64

tool: D9: 1

tool: {"D19": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D10: 0.5

assistant: ```c
double *smileDsp_winHan(long _N) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = 0.5 * (1.0 - cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0)));
    x++;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<smileDsp_winHan>:
  endbr64
  push   %r14
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  shl    $0x3,%edi
  sub    $0x10,%rsp
  call   <malloc@plt>
  pxor   %xmm5,%xmm5
  pxor   %xmm6,%xmm6
  cvtsi2sd %rbx,%xmm5
  mov    %rax,%r12
  comisd %xmm6,%xmm5
  jbe    L11
  movq   %xmm5,%r14
  subsd  D29(%rip),%xmm5
  pxor   %xmm1,%xmm1
  mov    %rax,%rbx
  movsd  %xmm5,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  D19(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  add    $0x8,%rbx
  mulsd  %xmm1,%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movsd  (%rsp),%xmm1
  addsd  D29(%rip),%xmm1
  movapd %xmm0,%xmm2
  movsd  D29(%rip),%xmm0
  movq   %r14,%xmm4
  subsd  %xmm2,%xmm0
  mulsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  comisd %xmm1,%xmm4
  ja     L16
L11:
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D29
type_guessed: f64
name: retrieve_data
arguments: label: D19
type_guessed: byte[8]
name: retrieve_data
arguments: label: D9
type_guessed: f64

tool: D29: 1

tool: {"D19": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: D9: 0.5

assistant: ```c
double *smileDsp_winHan(long _N) {
  double i;
  double *ret = (double *)malloc(sizeof(double) * _N);
  double *x = ret;
  double NN = (double)_N;
  for (i = 0.0; i < NN; i += 1.0) {
    *x = 0.5 * (1.0 - cos((2.0 * 3.14159265358979323846264338327950288 * i) / (NN - 1.0)));
    x++;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  sub    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <nrerror@plt>
L19:
  addq   $0x8,-0x8(%rbp)
  mov    -0x60(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L3
L0:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L0
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: allocation failure in submatrix()

assistant: ```c
float **submatrix(a, oldrl, oldrh, oldcl, oldch, newrl, newcl)
float **a;
long newcl, newrl, oldch, oldcl, oldrh, oldrl;
{
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  float **m;
  m = (float **)malloc((unsigned int)((nrow + 1) * sizeof(float *)));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```