ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L15
  cmpl   $0x0,-0x4(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L41
L15:
  mov    $0x0,%eax
L41:
  mov    %eax,%edi
  call   <assume@plt>
L12:
  addl   $0x4,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L68
  cmpl   $0x0,-0x8(%rbp)
  js     L68
  mov    $0x1,%eax
  jmp    L18
L68:
  mov    $0x0,%eax
L18:
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L12
```

assistant: ```c
int main() {
  int x;
  int y;
  assume(x == y && y == 0);
  while (1) {
    x += 4;
    y++;
    assert(x == 4 * y && x >= 0);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  mov    $0x1,%edi
  call   <assume@plt>
  mov    $0x0,%r12d
  mov    %ebx,%ebp
L6:
  add    $0x4,%ebx
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %ebp,%r12d
  sete   %al
  and    %eax,%edi
  call   <assert@plt>
  jmp    L6
```

assistant: ```c
int main() {
  int x;
  int y;
  assume(x == y && y == 0);
  while (1) {
    x += 4;
    y++;
    assert(x == 4 * y && x >= 0);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,%ebp
  call   <assume@plt>
  nopl   0x0(%rax)
L6:
  add    $0x4,%ebx
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %r12d,%ebp
  sete   %al
  and    %eax,%edi
  call   <assert@plt>
  jmp    L6
```

assistant: ```c
int main() {
  int x;
  int y;
  assume(x == y && y == 0);
  while (1) {
    x += 4;
    y++;
    assert(x == 4 * y && x >= 0);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,%ebp
  call   <assume@plt>
  nopl   0x0(%rax)
L8:
  add    $0x4,%ebx
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %r12d,%ebp
  sete   %al
  and    %eax,%edi
  call   <assert@plt>
  jmp    L8
```

assistant: ```c
int main() {
  int x;
  int y;
  assume(x == y && y == 0);
  while (1) {
    x += 4;
    y++;
    assert(x == 4 * y && x >= 0);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %edi,-0x1b4(%rbp)
  mov    %esi,-0x1b8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a4(%rbp)
  jmp    L20
L10:
  mov    -0x1b8(%rbp),%edx
  mov    -0x1b4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
L20:
  cmpl   $0x14,-0x1a4(%rbp)
  jle    L10
  mov    -0x170(%rbp),%eax
  cmp    $0x17,%eax
  jne    L37
  movl   $0x3,-0x1b8(%rbp)
  jmp    L34
L37:
  movl   $0x1,-0x1b8(%rbp)
L34:
  movl   $0x0,-0x1a4(%rbp)
  jmp    L52
L56:
  mov    -0x1b8(%rbp),%edx
  mov    -0x1b4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
L52:
  cmpl   $0x14,-0x1a4(%rbp)
  jle    L56
  mov    -0x1b8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
int toto(int i, int b) {
  int j;
  int a[100];
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  if (a[12] == 23)
    b = 3;
  else
    b = 1;
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toto>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x54(%rsp),%rcx
  mov    %rax,%rdx
  add    %edi,%esi
L12:
  mov    %esi,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L12
  cmpl   $0x17,0x30(%rsp)
  sete   %sil
  movzbl %sil,%esi
  lea    0x1(%rsi,%rsi,1),%esi
  lea    (%rsi,%rdi,1),%edx
L15:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
  movslq %esi,%rsi
  mov    (%rsp,%rsi,4),%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x1a8,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto(int i, int b) {
  int j;
  int a[100];
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  if (a[12] == 23)
    b = 3;
  else
    b = 1;
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: Translate the below assembly code into C programming language:

```asm
<toto>:
  endbr64
  sub    $0x1a8,%rsp
  add    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x54(%rsp),%rcx
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %esi,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L4
  xor    %esi,%esi
  cmpl   $0x17,0x30(%rsp)
  sete   %sil
  lea    0x1(%rsi,%rsi,1),%esi
  lea    (%rsi,%rdi,1),%edx
  nopl   (%rax)
L29:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L29
  movslq %esi,%rsi
  mov    (%rsp,%rsi,4),%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x1a8,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto(int i, int b) {
  int j;
  int a[100];
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  if (a[12] == 23)
    b = 3;
  else
    b = 1;
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toto>:
  endbr64
  sub    $0x1a8,%rsp
  add    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  cmp    $0x17,%esi
  sete   %al
  lea    0x1(%rax,%rax,1),%eax
  add    %eax,%edi
  cltq
  movd   %edi,%xmm1
  pshufd $0x0,%xmm1,%xmm0
  movaps %xmm0,(%rsp)
  mov    (%rsp,%rax,4),%eax
  mov    0x198(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x1a8,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int toto(int i, int b) {
  int j;
  int a[100];
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  if (a[12] == 23)
    b = 3;
  else
    b = 1;
  for (j = 0; j <= 20; j++)
    a[j] = b + i;
  return a[b];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_splitfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_free@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_splitfree(char **split) {
  int i;
  i = 0;
  while (split[i]) {
    ft_free(split[i]);
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_splitfree>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  push   %rbx
  lea    0x8(%rax),%rbx
L8:
  call   <ft_free@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L8
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void ft_splitfree(char **split) {
  int i;
  i = 0;
  while (split[i]) {
    ft_free(split[i]);
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_splitfree>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L10:
  call   <ft_free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L10
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void ft_splitfree(char **split) {
  int i;
  i = 0;
  while (split[i]) {
    ft_free(split[i]);
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_splitfree>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L7
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L17:
  call   <ft_free@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L17
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void ft_splitfree(char **split) {
  int i;
  i = 0;
  while (split[i]) {
    ft_free(split[i]);
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_char_class>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L5
  addq   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L17
  addq   $0x1,-0x18(%rbp)
  jmp    L17
L94:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L18
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x2e,-0x1(%rbp)
  je     L33
  cmpb   $0x3a,-0x1(%rbp)
  je     L33
  cmpb   $0x3d,-0x1(%rbp)
  jne    L18
L33:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  jmp    L153
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  cmpb   $0xa,-0x2(%rbp)
  jne    L118
  mov    $0x0,%eax
  jmp    L120
L118:
  addq   $0x1,-0x18(%rbp)
L153:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L31
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jne    L31
L18:
  addq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L114
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L94
L114:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L135
  mov    -0x18(%rbp),%rax
  jmp    L120
L135:
  mov    $0x0,%eax
L120:
  pop    %rbp
  ret
```

assistant: ```c
const char *parse_char_class(const char *p) {
  char c, d;
  if (*p == '^')
    ++p;
  if (*p == ']')
    ++p;
  for (; *p != ']' && *p != '\n'; ++p)
    if (*p == '[' && ((d = p[1]) == '.' || d == ':' || d == '='))
      for (++p, c = *++p; *p != ']' || c != d; ++p)
        if ((c = *p) == '\n')
          return 0;
  return ((*p == ']') ? p : 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_char_class>:
  endbr64
  cmpb   $0x5e,(%rdi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movzbl (%rdi),%eax
  cmp    $0x5d,%al
  je     L163
  cmp    $0xa,%al
  je     L59
L108:
  movabs $0x2400400000000000,%r8
  jmp    L77
L163:
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  cmp    $0x5d,%al
  je     L89
  cmp    $0xa,%al
  je     L89
  mov    %rdx,%rdi
  jmp    L108
L154:
  mov    %ecx,%eax
L10:
  cmp    $0xa,%al
  je     L53
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %al,%sil
  jne    L154
  cmp    $0x5d,%cl
  jne    L154
  mov    %rdx,%rdi
L105:
  lea    0x1(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  cmp    $0x5d,%al
  je     L89
  cmp    $0xa,%al
  je     L89
  mov    %rdx,%rdi
L77:
  cmp    $0x5b,%al
  jne    L105
  movzbl 0x1(%rdi),%esi
  cmp    $0x3d,%sil
  ja     L105
  bt     %rsi,%r8
  jae    L105
  lea    0x2(%rdi),%rdx
  movzbl 0x2(%rdi),%eax
  cmp    %al,%sil
  jne    L10
  cmp    $0x5d,%al
  jne    L10
  mov    %rdx,%rdi
  jmp    L105
L89:
  cmp    $0x5d,%al
  mov    $0x0,%eax
  cmovne %rax,%rdx
  jmp    L84
L53:
  mov    $0x0,%edx
L84:
  mov    %rdx,%rax
  ret
L59:
  mov    $0x0,%edx
  jmp    L84
```

assistant: ```c
const char *parse_char_class(const char *p) {
  char c, d;
  if (*p == '^')
    ++p;
  if (*p == ']')
    ++p;
  for (; *p != ']' && *p != '\n'; ++p)
    if (*p == '[' && ((d = p[1]) == '.' || d == ':' || d == '='))
      for (++p, c = *++p; *p != ']' || c != d; ++p)
        if ((c = *p) == '\n')
          return 0;
  return ((*p == ']') ? p : 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_char_class>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x5e,%al
  jne    L104
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L104:
  cmp    $0x5d,%al
  je     L60
  cmp    $0xa,%al
  je     L76
L7:
  movabs $0xdbffbfffffffffff,%r8
  jmp    L70
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%rdi
  cmp    $0x5d,%cl
  je     L132
L24:
  cmp    $0xa,%cl
  je     L132
  mov    %ecx,%eax
L70:
  movzbl 0x1(%rdi),%ecx
  cmp    $0x5b,%al
  jne    L73
  cmp    $0x3d,%cl
  ja     L73
  bt     %rcx,%r8
  jb     L73
  movzbl 0x2(%rdi),%esi
  lea    0x2(%rdi),%rdx
  mov    %esi,%eax
  jmp    L129
  nop
L67:
  cmp    $0xa,%al
  je     L76
L114:
  add    $0x1,%rdx
  mov    %eax,%esi
  movzbl (%rdx),%eax
L129:
  cmp    $0x5d,%al
  jne    L67
  cmp    %cl,%sil
  jne    L114
  movzbl 0x1(%rdx),%ecx
  mov    %rdx,%rdi
  add    $0x1,%rdi
  cmp    $0x5d,%cl
  jne    L24
L132:
  xor    %eax,%eax
  cmp    $0x5d,%cl
  cmove  %rdi,%rax
  ret
L76:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  mov    %rdx,%rdi
  cmp    $0xa,%al
  je     L52
  cmp    $0x5d,%al
  jne    L7
L52:
  mov    %eax,%ecx
  jmp    L132
```

assistant: ```c
const char *parse_char_class(const char *p) {
  char c, d;
  if (*p == '^')
    ++p;
  if (*p == ']')
    ++p;
  for (; *p != ']' && *p != '\n'; ++p)
    if (*p == '[' && ((d = p[1]) == '.' || d == ':' || d == '='))
      for (++p, c = *++p; *p != ']' || c != d; ++p)
        if ((c = *p) == '\n')
          return 0;
  return ((*p == ']') ? p : 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_char_class>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x5e,%al
  jne    L8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L8:
  cmp    $0x5d,%al
  je     L3
  cmp    $0xa,%al
  je     L154
L158:
  movabs $0xdbffbfffffffffff,%r8
  jmp    L157
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rdi
  cmp    $0x5d,%cl
  je     L108
L150:
  cmp    $0xa,%cl
  je     L108
  mov    %ecx,%eax
L157:
  movzbl 0x1(%rdi),%ecx
  cmp    $0x5b,%al
  jne    L45
  cmp    $0x3d,%cl
  ja     L45
  bt     %rcx,%r8
  jb     L45
  movzbl 0x2(%rdi),%esi
  lea    0x2(%rdi),%rdx
  jmp    L48
  nopl   (%rax)
L12:
  cmp    $0xa,%al
  je     L154
L63:
  add    $0x1,%rdx
  mov    %eax,%esi
L48:
  movzbl (%rdx),%eax
  cmp    $0x5d,%al
  jne    L12
  cmp    %cl,%sil
  jne    L63
  movzbl 0x1(%rdx),%ecx
  mov    %rdx,%rdi
  add    $0x1,%rdi
  cmp    $0x5d,%cl
  jne    L150
L108:
  xor    %eax,%eax
  cmp    $0x5d,%cl
  cmove  %rdi,%rax
  ret
L154:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rdx
  mov    %rdx,%rdi
  cmp    $0xa,%al
  je     L112
  cmp    $0x5d,%al
  jne    L158
L112:
  mov    %eax,%ecx
  jmp    L108
```

assistant: ```c
const char *parse_char_class(const char *p) {
  char c, d;
  if (*p == '^')
    ++p;
  if (*p == ']')
    ++p;
  for (; *p != ']' && *p != '\n'; ++p)
    if (*p == '[' && ((d = p[1]) == '.' || d == ':' || d == '='))
      for (++p, c = *++p; *p != ']' || c != d; ++p)
        if ((c = *p) == '\n')
          return 0;
  return ((*p == ']') ? p : 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<util_add_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L55
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L40
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L67
L40:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lib_realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L2
L49:
  nop
  jmp    L2
L55:
  nop
  jmp    L2
L67:
  nop
L2:
  leave
  ret
```

assistant: ```c
void util_add_extension(char **name, const char *extension) {
  size_t name_len, ext_len;
  if (extension == NULL || *name == NULL)
    return;
  name_len = strlen(*name);
  ext_len = strlen(extension);
  if (ext_len == 0)
    return;
  if ((name_len > ext_len + 1) && (strcasecmp(&((*name)[name_len - ext_len]), extension) == 0))
    return;
  *name = lib_realloc(*name, name_len + ext_len + 2);
  (*name)[name_len] = '.';
  memcpy(&((*name)[name_len + 1]), extension, ext_len + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<util_add_extension>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    (%rdi),%r14
  test   %r14,%r14
  je     L35
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L35
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x1(%r12),%r15
  cmp    %rax,%r15
  jae    L9
  sub    %r12,%rax
  lea    (%r14,%rax,1),%rdi
  mov    %rbx,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L35
L9:
  lea    0x2(%r12,%r13,1),%rsi
  mov    0x0(%rbp),%rdi
  call   <lib_realloc@plt>
  mov    %rax,0x0(%rbp)
  movb   $0x2e,(%rax,%r13,1)
  mov    0x0(%rbp),%rax
  lea    0x1(%rax,%r13,1),%rdi
  mov    %r15,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  ret
```

assistant: ```c
void util_add_extension(char **name, const char *extension) {
  size_t name_len, ext_len;
  if (extension == NULL || *name == NULL)
    return;
  name_len = strlen(*name);
  ext_len = strlen(extension);
  if (ext_len == 0)
    return;
  if ((name_len > ext_len + 1) && (strcasecmp(&((*name)[name_len - ext_len]), extension) == 0))
    return;
  *name = lib_realloc(*name, name_len + ext_len + 2);
  (*name)[name_len] = '.';
  memcpy(&((*name)[name_len + 1]), extension, ext_len + 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<util_add_extension>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r14
  test   %r14,%r14
  je     L44
  mov    %rsi,%rbp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L44
  lea    0x1(%rax),%r15
  cmp    %r12,%r15
  jae    L40
  mov    %r12,%rax
  mov    %rbp,%rsi
  sub    %r13,%rax
  lea    (%r14,%rax,1),%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L44
  mov    (%rbx),%r14
L40:
  lea    0x2(%r12,%r13,1),%rsi
  mov    %r14,%rdi
  call   <lib_realloc@plt>
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x2e,(%rax,%r12,1)
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  lea    0x1(%rax,%r12,1),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <memcpy@plt>
  nopl   (%rax)
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L16:
  ret
```

assistant: ```c
void util_add_extension(char **name, const char *extension) {
  size_t name_len, ext_len;
  if (extension == NULL || *name == NULL)
    return;
  name_len = strlen(*name);
  ext_len = strlen(extension);
  if (ext_len == 0)
    return;
  if ((name_len > ext_len + 1) && (strcasecmp(&((*name)[name_len - ext_len]), extension) == 0))
    return;
  *name = lib_realloc(*name, name_len + ext_len + 2);
  (*name)[name_len] = '.';
  memcpy(&((*name)[name_len + 1]), extension, ext_len + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<util_add_extension>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r14
  test   %r14,%r14
  je     L16
  mov    %rsi,%rbp
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L16
  lea    0x1(%rax),%r15
  cmp    %r12,%r15
  jae    L25
  mov    %r12,%rax
  mov    %rbp,%rsi
  sub    %r13,%rax
  lea    (%r14,%rax,1),%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L16
  mov    (%rbx),%r14
L25:
  lea    0x2(%r12,%r13,1),%rsi
  mov    %r14,%rdi
  call   <lib_realloc@plt>
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  movb   $0x2e,(%rax,%r12,1)
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  lea    0x1(%rax,%r12,1),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <memcpy@plt>
  nopl   (%rax)
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L0:
  ret
```

assistant: ```c
void util_add_extension(char **name, const char *extension) {
  size_t name_len, ext_len;
  if (extension == NULL || *name == NULL)
    return;
  name_len = strlen(*name);
  ext_len = strlen(extension);
  if (ext_len == 0)
    return;
  if ((name_len > ext_len + 1) && (strcasecmp(&((*name)[name_len - ext_len]), extension) == 0))
    return;
  *name = lib_realloc(*name, name_len + ext_len + 2);
  (*name)[name_len] = '.';
  memcpy(&((*name)[name_len + 1]), extension, ext_len + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L25
L19:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D35
data_type: string
name: disassemble_data
arguments: label: D36
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string

tool: D9: Please enter your number: 

tool: D35: %d

tool: D36: Even.


tool: D26: Odd.


assistant: ```c
int main() {
  int a;
  printf("Please enter your number: ");
  scanf("%d", &a);
  if (a % 2 == 0) {
    printf("Even.\n");
  } else {
    printf("Odd.\n");
  }
  return 0;
}
```