ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L9
  lea    D3(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xd7850430,%esi
  je     L11
L28:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L28
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D4
type_guessed: string
name: parse_data
arguments: data_label: D20
type_guessed: string

tool: D3: Call this program with %i arguments


tool: D4: %u


tool: D20: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3615818800U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cvt_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <XLookupString@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  je     L13
  mov    $0xffffffff,%eax
  jmp    L29
L13:
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int cvt_key(XKeyEvent *ev) {
  int n;
  char buf[4];
  n = XLookupString(ev, buf, 4, NULL, NULL);
  if (n != 1)
    return -1;
  return buf[0];
}
```
user: What is the c source code of the assembly code below?

```asm
<cvt_key>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x4,%edx
  call   <XLookupString@plt>
  cmp    $0x1,%eax
  jne    L14
  movsbl 0x4(%rsp),%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L4
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cvt_key(XKeyEvent *ev) {
  int n;
  char buf[4];
  n = XLookupString(ev, buf, 4, NULL, NULL);
  if (n != 1)
    return -1;
  return buf[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cvt_key>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <XLookupString@plt>
  cmp    $0x1,%eax
  jne    L4
  movsbl 0x4(%rsp),%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  jmp    L28
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cvt_key(XKeyEvent *ev) {
  int n;
  char buf[4];
  n = XLookupString(ev, buf, 4, NULL, NULL);
  if (n != 1)
    return -1;
  return buf[0];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cvt_key>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x4,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <XLookupString@plt>
  cmp    $0x1,%eax
  jne    L9
  movsbl 0x4(%rsp),%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  jmp    L1
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cvt_key(XKeyEvent *ev) {
  int n;
  char buf[4];
  n = XLookupString(ev, buf, 4, NULL, NULL);
  if (n != 1)
    return -1;
  return buf[0];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  char tmp;
  while (start < end) {
    tmp = str[start];
    str[start] = str[end];
    str[end] = tmp;
    start++;
    end--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L10
  movslq %esi,%rsi
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L2
L10:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  char tmp;
  while (start < end) {
    tmp = str[start];
    str[start] = str[end];
    str[end] = tmp;
    start++;
    end--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L14
  movslq %esi,%rsi
  xor    %eax,%eax
L18:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L18
L14:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  char tmp;
  while (start < end) {
    tmp = str[start];
    str[start] = str[end];
    str[end] = tmp;
    start++;
    end--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  xor    %eax,%eax
L17:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L17
L6:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  char tmp;
  while (start < end) {
    tmp = str[start];
    str[start] = str[end];
    str[end] = tmp;
    start++;
    end--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcc_current_sp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  unsigned int sp = 0;
  return sp;
}
```
user: What is the c source code of the assembly code below:

```asm
<gcc_current_sp>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  unsigned int sp = 0;
  return sp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcc_current_sp>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  unsigned int sp = 0;
  return sp;
}
```
user: What is the c source code of the assembly code below?

```asm
<gcc_current_sp>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int gcc_current_sp(void) {
  unsigned int sp = 0;
  return sp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stdf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <meanf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  subss  -0x4(%rbp),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0x4(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  D6(%rip),%xmm0
  divss  %xmm1,%xmm0
  mulss  -0x8(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float stdf(float *data, int numSamples) {
  int curSample;
  float m = meanf(data, numSamples);
  float std = 0;
  for (curSample = 0; curSample < numSamples; curSample++) {
    std += (data[curSample] - m) * (data[curSample] - m);
  }
  return sqrt(1 / (float)(numSamples - 1) * std);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stdf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <meanf@plt>
  test   %ebx,%ebx
  jle    L5
  mov    %rbp,%rax
  lea    -0x1(%rbx),%edx
  lea    0x4(%rbp,%rdx,4),%rdx
  pxor   %xmm2,%xmm2
L1:
  movss  (%rax),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm2
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L1
L26:
  sub    $0x1,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  movss  D4(%rip),%xmm0
  divss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%edi
  call   <sqrt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  pxor   %xmm2,%xmm2
  jmp    L26
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float stdf(float *data, int numSamples) {
  int curSample;
  float m = meanf(data, numSamples);
  float std = 0;
  for (curSample = 0; curSample < numSamples; curSample++) {
    std += (data[curSample] - m) * (data[curSample] - m);
  }
  return sqrt(1 / (float)(numSamples - 1) * std);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stdf>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <meanf@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  pxor   %xmm2,%xmm2
  mov    %rax,%rbp
  lea    0x4(%rbx,%rax,4),%rax
  nopw   0x0(%rax,%rax,1)
L23:
  movss  (%rdi),%xmm1
  add    $0x4,%rdi
  subss  %xmm0,%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm2
  cmp    %rdi,%rax
  jne    L23
L29:
  pxor   %xmm1,%xmm1
  movss  D3(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2ss %ebp,%xmm1
  pop    %rbx
  pop    %rbp
  divss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%edi
  jmp    1060 <sqrt@plt>
L0:
  pxor   %xmm2,%xmm2
  sub    $0x1,%ebp
  jmp    L29
```

tool_calls: name: parse_data
arguments: data_tag: D3
datatype: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float stdf(float *data, int numSamples) {
  int curSample;
  float m = meanf(data, numSamples);
  float std = 0;
  for (curSample = 0; curSample < numSamples; curSample++) {
    std += (data[curSample] - m) * (data[curSample] - m);
  }
  return sqrt(1 / (float)(numSamples - 1) * std);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stdf>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <meanf@plt>
  test   %ebx,%ebx
  jle    L35
  lea    -0x1(%rbx),%ecx
  movaps %xmm0,%xmm3
  cmp    $0x2,%ecx
  jbe    L66
  mov    %ebx,%edx
  movaps %xmm0,%xmm4
  pxor   %xmm2,%xmm2
  mov    %rbp,%rax
  shr    $0x2,%edx
  shufps $0x0,%xmm4,%xmm4
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rbp,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L67:
  movups (%rax),%xmm0
  add    $0x10,%rax
  subps  %xmm4,%xmm0
  mulps  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm2,%xmm1
  movaps %xmm0,%xmm2
  shufps $0x55,%xmm0,%xmm2
  addss  %xmm2,%xmm1
  movaps %xmm0,%xmm2
  unpckhps %xmm0,%xmm2
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  movaps %xmm1,%xmm2
  cmp    %rdx,%rax
  jne    L67
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L10
L77:
  movslq %eax,%rdx
  movss  0x0(%rbp,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rsi
  lea    0x1(%rax),%edx
  subss  %xmm3,%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm2
  cmp    %edx,%ebx
  jle    L10
  movss  0x4(%rbp,%rsi,1),%xmm0
  add    $0x2,%eax
  subss  %xmm3,%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm2
  cmp    %eax,%ebx
  jle    L10
  movss  0x8(%rbp,%rsi,1),%xmm0
  subss  %xmm3,%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm2
L10:
  pxor   %xmm1,%xmm1
  movss  D7(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2ss %ecx,%xmm1
  pop    %rbx
  pop    %rbp
  divss  %xmm1,%xmm0
  mulss  %xmm2,%xmm0
  cvttss2si %xmm0,%edi
  jmp    1060 <sqrt@plt>
  nopl   0x0(%rax)
L35:
  pxor   %xmm2,%xmm2
  lea    -0x1(%rbx),%ecx
  jmp    L10
L66:
  pxor   %xmm2,%xmm2
  xor    %eax,%eax
  jmp    L77
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float stdf(float *data, int numSamples) {
  int curSample;
  float m = meanf(data, numSamples);
  float std = 0;
  for (curSample = 0; curSample < numSamples; curSample++) {
    std += (data[curSample] - m) * (data[curSample] - m);
  }
  return sqrt(1 / (float)(numSamples - 1) * std);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort_docs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <hv_aloc_doc_matrix@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <hv_get_cos@plt>
  test   %rax,%rax
  je     L46
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <hv_get_name@plt>
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %s


assistant: ```c
void sort_docs(struct document **docs, int ndocs) {
  struct document **d = hv_aloc_doc_matrix(ndocs);
  int i;
  for (i = 0; i < ndocs; i++) {
    d[i] = docs[i];
  }
  bubble_sort(d, ndocs);
  for (i = 0; i < ndocs; i++) {
    if (hv_get_cos(d[i]) != 0) {
      printf("%s\n", hv_get_name(d[i]));
    }
  }
  free(d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort_docs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%edi
  call   <hv_aloc_doc_matrix@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L29
  mov    %r12d,%ecx
  mov    $0x0,%eax
L22:
  mov    (%rbx,%rax,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L22
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <bubble_sort@plt>
  mov    %rbp,%rbx
  mov    %r12d,%r12d
  lea    0x0(%rbp,%r12,8),%r12
  lea    D6(%rip),%r13
  jmp    L50
L3:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L18
L50:
  mov    (%rbx),%rdi
  call   <hv_get_cos@plt>
  test   %rax,%rax
  je     L3
  mov    (%rbx),%rdi
  call   <hv_get_name@plt>
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L3
L29:
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
L18:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: %s


assistant: ```c
void sort_docs(struct document **docs, int ndocs) {
  struct document **d = hv_aloc_doc_matrix(ndocs);
  int i;
  for (i = 0; i < ndocs; i++) {
    d[i] = docs[i];
  }
  bubble_sort(d, ndocs);
  for (i = 0; i < ndocs; i++) {
    if (hv_get_cos(d[i]) != 0) {
      printf("%s\n", hv_get_name(d[i]));
    }
  }
  free(d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_docs>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <hv_aloc_doc_matrix@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L33
  mov    %r13d,%edx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L17:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L17
  mov    %r13d,%esi
  mov    %r12,%rdi
  lea    (%r12,%rbx,8),%rbx
  mov    %r12,%rbp
  call   <bubble_sort@plt>
  lea    D1(%rip),%r13
  jmp    L60
  nopl   (%rax)
L12:
  add    $0x8,%rbp
  cmp    %rbx,%rbp
  je     L18
L60:
  mov    0x0(%rbp),%rdi
  call   <hv_get_cos@plt>
  test   %rax,%rax
  je     L12
  mov    0x0(%rbp),%rdi
  add    $0x8,%rbp
  call   <hv_get_name@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L60
L18:
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string

tool: D1: %s


assistant: ```c
void sort_docs(struct document **docs, int ndocs) {
  struct document **d = hv_aloc_doc_matrix(ndocs);
  int i;
  for (i = 0; i < ndocs; i++) {
    d[i] = docs[i];
  }
  bubble_sort(d, ndocs);
  for (i = 0; i < ndocs; i++) {
    if (hv_get_cos(d[i]) != 0) {
      printf("%s\n", hv_get_name(d[i]));
    }
  }
  free(d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sort_docs>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  sub    $0x8,%rsp
  call   <hv_aloc_doc_matrix@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L73
  lea    0x8(%rbx),%rax
  cmp    %rax,%rbp
  je     L97
  lea    -0x1(%r12),%eax
  cmp    $0x2,%eax
  jbe    L97
  mov    %r12d,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  nopl   (%rax)
L69:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,0x0(%rbp,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L69
  mov    %r12d,%eax
  mov    %r12d,%r13d
  and    $0xfffffffe,%eax
  test   $0x1,%r12b
  je     L96
  mov    (%rbx,%rax,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
L96:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  lea    0x0(%rbp,%r13,8),%r12
  mov    %rbp,%rbx
  call   <bubble_sort@plt>
  lea    D2(%rip),%r13
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L95:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L74
L60:
  mov    (%rbx),%rdi
  call   <hv_get_cos@plt>
  test   %rax,%rax
  je     L95
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <hv_get_name@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L60
L74:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <free@plt>
  nopl   0x0(%rax)
L97:
  mov    %r12d,%r13d
  xor    %eax,%eax
  nopl   (%rax)
L89:
  mov    (%rbx,%rax,8),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L89
  jmp    L96
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r12d,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  jmp    L74
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %s


assistant: ```c
void sort_docs(struct document **docs, int ndocs) {
  struct document **d = hv_aloc_doc_matrix(ndocs);
  int i;
  for (i = 0; i < ndocs; i++) {
    d[i] = docs[i];
  }
  bubble_sort(d, ndocs);
  for (i = 0; i < ndocs; i++) {
    if (hv_get_cos(d[i]) != 0) {
      printf("%s\n", hv_get_name(d[i]));
    }
  }
  free(d);
}
```