ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writeppm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %rcx,%rbx
  lea    D28(%rip),%rsi
  mov    $0x0,%eax
  call   <fopen@plt>
  mov    $0x1,%edx
  test   %eax,%eax
  jne    L3
L21:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  movslq %eax,%r12
  mov    %r12,%rcx
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  call   <fwrite@plt>
  mov    %r14d,%ecx
  mov    %ebp,%edx
  lea    D26(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  call   <fwrite@plt>
  test   %r14d,%r14d
  jle    L10
  lea    0x0(%rbp,%rbp,2),%r13d
  mov    %r13d,%r15d
  neg    %r15d
  movslq %r15d,%r15
  lea    -0x1(%r14),%eax
  imul   %r13d,%eax
  cltq
  add    %rax,%rbx
  mov    $0x0,%ebp
  movslq %r13d,%r13
L26:
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %rax,%r13
  jne    L32
  add    $0x1,%ebp
  add    %r15,%rbx
  cmp    %ebp,%r14d
  jne    L26
L10:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x0,%edx
  jmp    L21
L32:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fclose@plt>
  mov    $0x5,%edx
  jmp    L21
```

tool_calls: name: read_data
arguments: data_label: D28
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string

tool: D28: wb

tool: D14: P6


tool: D26: %d %d


tool: D33: 255


assistant: ```c
signed int writeppm(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 3 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "255\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeppm>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  lea    D18(%rip),%rsi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L37
L3:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L37:
  movslq %eax,%r12
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  lea    D14(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rdi
  lea    D0(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D24(%rip),%rdi
  call   <fwrite@plt>
  test   %r13d,%r13d
  jle    L13
  lea    0x0(%rbp,%rbp,2),%edx
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  imul   %edx,%eax
  mov    %edx,%r14d
  movslq %edx,%r15
  neg    %r14d
  movslq %r14d,%r14
  cltq
  add    %rax,%rbx
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L51:
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r13d
  je     L13
L53:
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %r15,%rax
  je     L51
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  mov    $0x5,%r8d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  xor    %r8d,%r8d
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D24
type_guessed: string

tool: D18: wb

tool: D14: P6


tool: D0: %d %d


tool: D24: 255


assistant: ```c
signed int writeppm(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 3 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "255\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeppm>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  lea    D32(%rip),%rsi
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L42
L20:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L42:
  movslq %eax,%r12
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r12,%rcx
  lea    D29(%rip),%rdi
  call   <fwrite@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12,%rdi
  lea    D33(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  call   <fwrite@plt>
  test   %r13d,%r13d
  jle    L24
  lea    0x0(%rbp,%rbp,2),%edx
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  imul   %edx,%eax
  mov    %edx,%r14d
  movslq %edx,%r15
  neg    %r14d
  movslq %r14d,%r14
  cltq
  add    %rax,%rbx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r13d
  je     L24
L16:
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
  cmp    %r15,%rax
  je     L15
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  mov    $0x5,%r8d
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <fclose@plt>
  xor    %r8d,%r8d
  jmp    L20
```

tool_calls: name: parse_data
arguments: label: D32
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D39
type: string

tool: D32: wb

tool: D29: P6


tool: D33: %d %d


tool: D39: 255


assistant: ```c
signed int writeppm(char *name, signed int xres, signed int yres, unsigned char *imgdata) {
  struct _IO_FILE$link40 *ofp;
  signed int y;
  signed int xbytes = 3 * xres;
  ofp = fopen(name, "wb");
  if (ofp == ((struct _IO_FILE$link40 *)((void *)0)))
    return 1;
  fprintf(ofp, "P6\n");
  fprintf(ofp, "%d %d\n", xres, yres);
  fprintf(ofp, "255\n");
  y = 0;
  while (!(y >= yres)) {
    unsigned long int return_value_fwrite$1;
    return_value_fwrite$1 = fwrite((const void *)&imgdata[(signed long int)(((yres - y) - 1) * xbytes)], (unsigned long int)1, (unsigned long int)xbytes, ofp);
    if (!(return_value_fwrite$1 == (unsigned long int)xbytes)) {
      fclose(ofp);
      return 5;
    }
    y = y + 1;
  }
  fclose(ofp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isvowel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jle    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x38,%al
  jle    L45
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x63,%al
  jne    L50
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jle    L50
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x38,%al
  jg     L50
L45:
  mov    $0x1,%eax
  jmp    L43
L50:
  mov    $0x0,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int isvowel(char *symbol) {
  if ((symbol[0] > '0' && symbol[0] < '9') || ((symbol[0] == 'c') && (symbol[1] > '0' && symbol[1] < '9'))) {
    return (1);
  } else
    return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isvowel>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x31(%rdx),%ecx
  mov    $0x1,%eax
  cmp    $0x7,%cl
  jbe    L11
  mov    $0x0,%eax
  cmp    $0x63,%dl
  jne    L11
  movzbl 0x1(%rdi),%eax
  sub    $0x31,%eax
  cmp    $0x7,%al
  setbe  %al
  movzbl %al,%eax
L11:
  ret
```

assistant: ```c
int isvowel(char *symbol) {
  if ((symbol[0] > '0' && symbol[0] < '9') || ((symbol[0] == 'c') && (symbol[1] > '0' && symbol[1] < '9'))) {
    return (1);
  } else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isvowel>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  lea    -0x31(%rdx),%ecx
  cmp    $0x7,%cl
  jbe    L1
  xor    %eax,%eax
  cmp    $0x63,%dl
  jne    L1
  movzbl 0x1(%rdi),%eax
  sub    $0x31,%eax
  cmp    $0x7,%al
  setbe  %al
  movzbl %al,%eax
L1:
  ret
```

assistant: ```c
int isvowel(char *symbol) {
  if ((symbol[0] > '0' && symbol[0] < '9') || ((symbol[0] == 'c') && (symbol[1] > '0' && symbol[1] < '9'))) {
    return (1);
  } else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isvowel>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  lea    -0x31(%rdx),%ecx
  cmp    $0x7,%cl
  jbe    L14
  xor    %eax,%eax
  cmp    $0x63,%dl
  jne    L14
  movzbl 0x1(%rdi),%eax
  sub    $0x31,%eax
  cmp    $0x7,%al
  setbe  %al
  movzbl %al,%eax
L14:
  ret
```

assistant: ```c
int isvowel(char *symbol) {
  if ((symbol[0] > '0' && symbol[0] < '9') || ((symbol[0] == 'c') && (symbol[1] > '0' && symbol[1] < '9'))) {
    return (1);
  } else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<discrete_world_position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L2:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L25:
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L2
L15:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void discrete_world_position(unsigned long long index, unsigned int nb_dimensions, unsigned int dimension_size[], unsigned int ret_pos[]) {
  unsigned int i = 0;
  while (index != 0 && i < nb_dimensions) {
    ret_pos[i] = index % dimension_size[i];
    index /= dimension_size[i];
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<discrete_world_position>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %esi,%r11d
  mov    %rdx,%rbx
  test   %esi,%esi
  je     L1
  mov    $0x0,%esi
L39:
  mov    %esi,%r9d
  lea    (%rbx,%r9,4),%r8
  mov    (%r8),%r10d
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %r10
  mov    %edx,(%rcx,%r9,4)
  mov    (%r8),%r8d
  mov    %rdi,%r9
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %r8
  mov    %rax,%rdi
  add    $0x1,%esi
  cmp    %r9,%r8
  ja     L1
  cmp    %esi,%r11d
  ja     L39
L1:
  pop    %rbx
  ret
L16:
  ret
```

assistant: ```c
void discrete_world_position(unsigned long long index, unsigned int nb_dimensions, unsigned int dimension_size[], unsigned int ret_pos[]) {
  unsigned int i = 0;
  while (index != 0 && i < nb_dimensions) {
    ret_pos[i] = index % dimension_size[i];
    index /= dimension_size[i];
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<discrete_world_position>:
  endbr64
  test   %rdi,%rdi
  je     L38
  mov    %esi,%r11d
  test   %esi,%esi
  je     L38
  push   %rbx
  xor    %esi,%esi
  mov    %rdx,%rbx
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %esi,%r9d
  mov    %rdi,%rax
  xor    %edx,%edx
  add    $0x1,%esi
  lea    (%rbx,%r9,4),%r8
  mov    (%r8),%r10d
  div    %r10
  mov    %rdi,%rax
  mov    %edx,(%rcx,%r9,4)
  mov    (%r8),%r8d
  xor    %edx,%edx
  mov    %rdi,%r9
  div    %r8
  mov    %rax,%rdi
  cmp    %r9,%r8
  ja     L28
  cmp    %esi,%r11d
  ja     L20
L28:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L38:
  ret
```

assistant: ```c
void discrete_world_position(unsigned long long index, unsigned int nb_dimensions, unsigned int dimension_size[], unsigned int ret_pos[]) {
  unsigned int i = 0;
  while (index != 0 && i < nb_dimensions) {
    ret_pos[i] = index % dimension_size[i];
    index /= dimension_size[i];
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<discrete_world_position>:
  endbr64
  test   %rdi,%rdi
  je     L16
  mov    %esi,%r11d
  test   %esi,%esi
  je     L16
  push   %rbx
  xor    %esi,%esi
  mov    %rdx,%rbx
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    %esi,%r9d
  mov    %rdi,%rax
  xor    %edx,%edx
  add    $0x1,%esi
  lea    (%rbx,%r9,4),%r8
  mov    (%r8),%r10d
  div    %r10
  mov    %rdi,%rax
  mov    %edx,(%rcx,%r9,4)
  mov    (%r8),%r8d
  xor    %edx,%edx
  mov    %rdi,%r9
  div    %r8
  mov    %rax,%rdi
  cmp    %r9,%r8
  ja     L21
  cmp    %esi,%r11d
  ja     L29
L21:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void discrete_world_position(unsigned long long index, unsigned int nb_dimensions, unsigned int dimension_size[], unsigned int ret_pos[]) {
  unsigned int i = 0;
  while (index != 0 && i < nb_dimensions) {
    ret_pos[i] = index % dimension_size[i];
    index /= dimension_size[i];
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decrypt_archive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,-0x7f(%rbp)
  movl   $0x43424139,-0x77(%rbp)
  movw   $0x4544,-0x73(%rbp)
  movb   $0x46,-0x71(%rbp)
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0xa,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x90(%rbp)
  mov    -0x98(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0xa,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x88(%rbp)
  mov    -0x98(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x7f(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <aescrypt@plt>
  mov    -0x88(%rbp),%rdi
  mov    -0x88(%rbp),%rsi
  mov    -0x90(%rbp),%rcx
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string

tool: D6: %s.zip

tool: D26: %s.tar

tool: D10: unzip %s; rm -f %s; tar xvf %s; rm -f %s

assistant: ```c
void decrypt_archive(char *user_name, char *pass) {
  char rand_key[15] = "123456789ABCDEF";
  char *zip_name, *tar_name, extract[100];
  zip_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.zip", user_name);
  tar_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.tar", user_name);
  aescrypt(1, user_name, zip_name, rand_key);
  sprintf(extract, "unzip %s; rm -f %s; tar xvf %s; rm -f %s", zip_name, zip_name, tar_name, tar_name);
}
```
user: What is the c source code of the assembly code below?

```asm
<decrypt_archive>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,0x1(%rsp)
  movl   $0x43424139,0x9(%rsp)
  movw   $0x4544,0xd(%rsp)
  movb   $0x46,0xf(%rsp)
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbp,%rdx
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x1(%rsp),%rcx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <aescrypt@plt>
  lea    0x10(%rsp),%rdi
  mov    %r12,%r9
  mov    %r12,%r8
  mov    %rbx,%rcx
  mov    %rbx,%rdx
  lea    D19(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D28
type_guessed: string
name: read_data
arguments: label: D19
type_guessed: string

tool: D10: %s.zip

tool: D28: %s.tar

tool: D19: unzip %s; rm -f %s; tar xvf %s; rm -f %s

assistant: ```c
void decrypt_archive(char *user_name, char *pass) {
  char rand_key[15] = "123456789ABCDEF";
  char *zip_name, *tar_name, extract[100];
  zip_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.zip", user_name);
  tar_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.tar", user_name);
  aescrypt(1, user_name, zip_name, rand_key);
  sprintf(extract, "unzip %s; rm -f %s; tar xvf %s; rm -f %s", zip_name, zip_name, tar_name, tar_name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decrypt_archive>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  movabs $0x3837363534333231,%rax
  movl   $0x43424139,0x9(%rsp)
  movb   $0x46,0xf(%rsp)
  mov    %rax,0x1(%rsp)
  mov    $0x4544,%eax
  mov    %ax,0xd(%rsp)
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdx
  lea    D9(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdx
  lea    D20(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <sprintf@plt>
  lea    0x1(%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <aescrypt@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rbx,%r9
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D25(%rip),%rsi
  mov    %r12,%rdx
  call   <sprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string

tool: D9: %s.zip

tool: D20: %s.tar

tool: D25: unzip %s; rm -f %s; tar xvf %s; rm -f %s

assistant: ```c
void decrypt_archive(char *user_name, char *pass) {
  char rand_key[15] = "123456789ABCDEF";
  char *zip_name, *tar_name, extract[100];
  zip_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.zip", user_name);
  tar_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.tar", user_name);
  aescrypt(1, user_name, zip_name, rand_key);
  sprintf(extract, "unzip %s; rm -f %s; tar xvf %s; rm -f %s", zip_name, zip_name, tar_name, tar_name);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<decrypt_archive>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  movabs $0x3837363534333231,%rax
  movl   $0x43424139,0x9(%rsp)
  movb   $0x46,0xf(%rsp)
  mov    %rax,0x1(%rsp)
  mov    $0x4544,%eax
  mov    %ax,0xd(%rsp)
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdx
  lea    D23(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xa(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rdx
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <sprintf@plt>
  lea    0x1(%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <aescrypt@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    %rbx,%r9
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D18(%rip),%rsi
  mov    %r12,%rdx
  call   <sprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string

tool: D23: %s.zip

tool: D6: %s.tar

tool: D18: unzip %s; rm -f %s; tar xvf %s; rm -f %s

assistant: ```c
void decrypt_archive(char *user_name, char *pass) {
  char rand_key[15] = "123456789ABCDEF";
  char *zip_name, *tar_name, extract[100];
  zip_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.zip", user_name);
  tar_name = (char *)malloc((strlen(user_name) + 10) * sizeof(char));
  sprintf(zip_name, "%s.tar", user_name);
  aescrypt(1, user_name, zip_name, rand_key);
  sprintf(extract, "unzip %s; rm -f %s; tar xvf %s; rm -f %s", zip_name, zip_name, tar_name, tar_name);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fprintf(FILE *__restrict fp, const char *__restrict fmt, ...) {
  int ret;
  va_list ap;
  va_start(ap, fmt);
  ret = vfprintf(fp, fmt, ap);
  va_end(ap);
  return (ret);
}
```