ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  test   $0x10,%al
  je     L3
  test   $0x4,%al
  je     L1
  lea    0x0(,%rax,4),%rdx
L15:
  add    $0x1b18b848,%rdx
  mov    %rdx,(%rcx)
  ret
L1:
  add    %rax,%rax
  mov    %rax,%rdx
  mov    %al,%dh
  sar    $0x8,%ax
  mov    %al,%dl
  jmp    L15
L3:
  test   $0x8,%al
  je     L16
  lea    0x0(,%rax,4),%rdx
  jmp    L15
L16:
  mov    %rax,%rdx
  rol    $0x20,%rdx
  mov    %rax,%rsi
  shl    $0x8,%rsi
  shr    $0x38,%rsi
  shl    $0x20,%rsi
  movabs $0xffffff00ffffffff,%rdi
  and    %rdi,%rdx
  or     %rsi,%rdx
  movzbl %al,%eax
  shl    $0x10,%rax
  and    $0xffffffffff00ffff,%rdx
  or     %rax,%rdx
  jmp    L15
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned int copy12;
  unsigned int copy13;
  char copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
        }
      } else if ((state[0UL] >> 3UL) & 1UL) {
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        copy13 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy13;
      } else {
        state[0UL] += state[0UL];
        copy14 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 3UL) & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 4);
      *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy16;
    }
    output[0UL] = state[0UL] + 454604872UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  sub    $0x99f4bb,%rdx
  test   $0x10,%dl
  je     L0
  test   $0x4,%dl
  je     L10
L24:
  lea    0x0(,%rdx,4),%rax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
  nopl   (%rax)
L0:
  test   $0x8,%dl
  jne    L24
  movabs $0xffffff00ffffffff,%rdi
  mov    %rdx,%rsi
  mov    %rdx,%rax
  movzbl %dl,%edx
  shl    $0x8,%rsi
  rol    $0x20,%rax
  shr    $0x38,%rsi
  and    %rdi,%rax
  shl    $0x10,%rdx
  shl    $0x20,%rsi
  or     %rsi,%rax
  and    $0xffffffffff00ffff,%rax
  or     %rdx,%rax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
  nopl   (%rax)
L10:
  lea    (%rdx,%rdx,1),%rax
  mov    %eax,%edx
  rol    $0x8,%dx
  mov    %dx,%ax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned int copy12;
  unsigned int copy13;
  char copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
        }
      } else if ((state[0UL] >> 3UL) & 1UL) {
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        copy13 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy13;
      } else {
        state[0UL] += state[0UL];
        copy14 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 3UL) & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 4);
      *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy16;
    }
    output[0UL] = state[0UL] + 454604872UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rsi,%rcx
  sub    $0x99f4bb,%rax
  movq   %rax,%xmm1
  pshufd $0xe1,%xmm1,%xmm0
  test   $0x10,%al
  je     L7
  test   $0x4,%al
  je     L16
L19:
  shl    $0x2,%rax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
L7:
  test   $0x8,%al
  jne    L19
  mov    %rax,%rsi
  movq   %xmm0,%rdi
  movzbl %al,%eax
  movabs $0xffffff00ffffffff,%rdx
  shl    $0x8,%rsi
  and    %rdi,%rdx
  shl    $0x10,%rax
  shr    $0x38,%rsi
  shl    $0x20,%rsi
  or     %rsi,%rdx
  and    $0xffffffffff00ffff,%rdx
  or     %rdx,%rax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  add    %rax,%rax
  mov    %eax,%edx
  rol    $0x8,%dx
  mov    %dx,%ax
  add    $0x1b18b848,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned int copy12;
  unsigned int copy13;
  char copy14;
  unsigned int copy15;
  char copy16;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
        }
      } else if ((state[0UL] >> 3UL) & 1UL) {
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        copy13 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy13;
      } else {
        state[0UL] += state[0UL];
        copy14 = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy14;
        copy14 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
    } else if ((state[0UL] >> 3UL) & 1UL) {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    } else {
      copy15 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy15;
      copy16 = *((char *)(&state[0UL]) + 4);
      *((char *)(&state[0UL]) + 4) = *((char *)(&state[0UL]) + 2);
      *((char *)(&state[0UL]) + 2) = copy16;
    }
    output[0UL] = state[0UL] + 454604872UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L37
L27:
  addl   $0x1,-0x1c(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L27
  jmp    L32
L4:
  subl   $0x1,-0x20(%rbp)
L32:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L4
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L37
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x1c(%rbp)
L37:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L0
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  leave
  ret
```

assistant: ```c
int partition(int array[], int low, int high) {
  int pivot = array[(low + high) / 2];
  while (low <= high) {
    while (array[low] < pivot)
      low++;
    while (array[high] > pivot)
      high--;
    if (low <= high) {
      swap(array, low, high);
      high--;
      low++;
    }
  }
  return low - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%r13d
  lea    (%rsi,%rdx,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%rdi,%rax,4),%ebp
  jmp    L62
L11:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  sub    $0x1,%r13d
  add    $0x1,%r12d
  jmp    L62
L87:
  movslq %r13d,%rax
  cmp    (%rbx,%rax,4),%ebp
  jge    L11
L98:
  lea    -0x1(%r13),%eax
  cltq
L10:
  mov    %eax,%r13d
  sub    $0x1,%rax
  cmp    %ebp,0x4(%rbx,%rax,4)
  jg     L10
L18:
  cmp    %r12d,%r13d
  jge    L11
L62:
  cmp    %r13d,%r12d
  jg     L8
  movslq %r12d,%rdx
  lea    0x1(%r12),%eax
  cltq
  cmp    (%rbx,%rdx,4),%ebp
  jle    L87
L7:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmp    %ebp,-0x4(%rbx,%rax,4)
  jl     L7
  movslq %r13d,%rax
  cmp    (%rbx,%rax,4),%ebp
  jl     L98
  jmp    L18
L8:
  lea    -0x1(%r12),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int partition(int array[], int low, int high) {
  int pivot = array[(low + high) / 2];
  while (low <= high) {
    while (array[low] < pivot)
      low++;
    while (array[high] > pivot)
      high--;
    if (low <= high) {
      swap(array, low, high);
      high--;
      low++;
    }
  }
  return low - 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<partition>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  add    %esi,%edx
  mov    %edx,%eax
  push   %r12
  mov    %esi,%r12d
  shr    $0x1f,%eax
  push   %rbp
  add    %edx,%eax
  push   %rbx
  mov    %rdi,%rbx
  sar    %eax
  cltq
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%ebp
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    %r13d,%r12d
  jg     L24
L12:
  movslq %r13d,%rax
  movslq %r12d,%rdx
  mov    (%rbx,%rax,4),%ecx
  lea    0x1(%r12),%eax
  cltq
  cmp    (%rbx,%rdx,4),%ebp
  jle    L40
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmp    %ebp,-0x4(%rbx,%rax,4)
  jl     L25
  cmp    %ecx,%ebp
  jge    L20
L71:
  lea    -0x1(%r13),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %eax,%r13d
  sub    $0x1,%rax
  cmp    %ebp,0x4(%rbx,%rax,4)
  jg     L63
L20:
  cmp    %r12d,%r13d
  jl     L37
L50:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  sub    $0x1,%r13d
  call   <swap@plt>
  add    $0x1,%r12d
  cmp    %r13d,%r12d
  jle    L12
L24:
  add    $0x8,%rsp
  lea    -0x1(%r12),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L40:
  cmp    %ecx,%ebp
  jl     L71
  jmp    L50
```

assistant: ```c
int partition(int array[], int low, int high) {
  int pivot = array[(low + high) / 2];
  while (low <= high) {
    while (array[low] < pivot)
      low++;
    while (array[high] > pivot)
      high--;
    if (low <= high) {
      swap(array, low, high);
      high--;
      low++;
    }
  }
  return low - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<partition>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  add    %esi,%edx
  mov    %edx,%eax
  push   %r12
  mov    %esi,%r12d
  shr    $0x1f,%eax
  push   %rbp
  add    %edx,%eax
  push   %rbx
  mov    %rdi,%rbx
  sar    %eax
  cltq
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%ebp
  nopw   0x0(%rax,%rax,1)
L0:
  cmp    %r13d,%r12d
  jg     L37
L88:
  movslq %r13d,%rax
  movslq %r12d,%rdx
  mov    (%rbx,%rax,4),%ecx
  lea    0x1(%r12),%eax
  cltq
  cmp    (%rbx,%rdx,4),%ebp
  jle    L56
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %eax,%r12d
  add    $0x1,%rax
  cmp    %ebp,-0x4(%rbx,%rax,4)
  jl     L33
  cmp    %ecx,%ebp
  jge    L84
L50:
  lea    -0x1(%r13),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %eax,%r13d
  sub    $0x1,%rax
  cmp    %ebp,0x4(%rbx,%rax,4)
  jg     L48
L84:
  cmp    %r12d,%r13d
  jl     L0
L5:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  sub    $0x1,%r13d
  call   <swap@plt>
  add    $0x1,%r12d
  cmp    %r13d,%r12d
  jle    L88
L37:
  add    $0x8,%rsp
  lea    -0x1(%r12),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L56:
  cmp    %ecx,%ebp
  jl     L50
  jmp    L5
```

assistant: ```c
int partition(int array[], int low, int high) {
  int pivot = array[(low + high) / 2];
  while (low <= high) {
    while (array[low] < pivot)
      low++;
    while (array[high] > pivot)
      high--;
    if (low <= high) {
      swap(array, low, high);
      high--;
      low++;
    }
  }
  return low - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sum@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int n = __VERIFIER_nondet_int();
  int s = sum(n);
  __VERIFIER_assert(s >= 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edi
  call   <sum@plt>
  not    %eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = __VERIFIER_nondet_int();
  int s = sum(n);
  __VERIFIER_assert(s >= 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edi
  call   <sum@plt>
  not    %eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = __VERIFIER_nondet_int();
  int s = sum(n);
  __VERIFIER_assert(s >= 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%edi
  call   <sum@plt>
  not    %eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int n = __VERIFIER_nondet_int();
  int s = sum(n);
  __VERIFIER_assert(s >= 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <quit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void die(void) {
  quit();
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <quit@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(void) {
  quit();
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <quit@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(void) {
  quit();
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <quit@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(void) {
  quit();
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: Hello


assistant: ```c
void *list() {
  while (1) {
    printf("Hello\n");
    sleep(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<list>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rbx
L9:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string

tool: D0: Hello


assistant: ```c
void *list() {
  while (1) {
    printf("Hello\n");
    sleep(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: Hello


assistant: ```c
void *list() {
  while (1) {
    printf("Hello\n");
    sleep(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  nopl   0x0(%rax)
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: Hello


assistant: ```c
void *list() {
  while (1) {
    printf("Hello\n");
    sleep(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<urg_ticks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    D16(%rip),%rax
  test   %rax,%rax
  jne    L12
  mov    -0x18(%rbp),%rax
  mov    %rax,D27(%rip)
L12:
  mov    D27(%rip),%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
long urg_ticks(void) {
  long current_ticks = 0;
  static long first_ticks = 0;
  struct timeval tvp;
  gettimeofday(&tvp, NULL);
  long global_ticks = tvp.tv_sec * 1000 + tvp.tv_usec / 1000;
  if (first_ticks == 0) {
    first_ticks = global_ticks;
  }
  current_ticks = global_ticks - first_ticks;
  return current_ticks;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<urg_ticks>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  cltq
  cmpq   $0x0,D18(%rip)
  jne    L19
  mov    %rax,D24(%rip)
L19:
  sub    D24(%rip),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long urg_ticks(void) {
  long current_ticks = 0;
  static long first_ticks = 0;
  struct timeval tvp;
  gettimeofday(&tvp, NULL);
  long global_ticks = tvp.tv_sec * 1000 + tvp.tv_usec / 1000;
  if (first_ticks == 0) {
    first_ticks = global_ticks;
  }
  current_ticks = global_ticks - first_ticks;
  return current_ticks;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<urg_ticks>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%edx
  mov    D15(%rip),%r8
  mov    %rax,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  add    %edx,%eax
  cltq
  test   %r8,%r8
  je     L0
  sub    %r8,%rax
  mov    %rax,%r8
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %r8,%rax
  add    $0x18,%rsp
  ret
  nop
L0:
  mov    %rax,D9(%rip)
  jmp    L5
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long urg_ticks(void) {
  long current_ticks = 0;
  static long first_ticks = 0;
  struct timeval tvp;
  gettimeofday(&tvp, NULL);
  long global_ticks = tvp.tv_sec * 1000 + tvp.tv_usec / 1000;
  if (first_ticks == 0) {
    first_ticks = global_ticks;
  }
  current_ticks = global_ticks - first_ticks;
  return current_ticks;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<urg_ticks>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x3e8,(%rsp),%edx
  mov    D9(%rip),%r8
  mov    %rax,%rcx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x26,%rax
  sub    %ecx,%eax
  add    %edx,%eax
  cltq
  test   %r8,%r8
  je     L6
  sub    %r8,%rax
  mov    %rax,%r8
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    %r8,%rax
  add    $0x18,%rsp
  ret
  nop
L6:
  mov    %rax,D7(%rip)
  jmp    L4
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long urg_ticks(void) {
  long current_ticks = 0;
  static long first_ticks = 0;
  struct timeval tvp;
  gettimeofday(&tvp, NULL);
  long global_ticks = tvp.tv_sec * 1000 + tvp.tv_usec / 1000;
  if (first_ticks == 0) {
    first_ticks = global_ticks;
  }
  current_ticks = global_ticks - first_ticks;
  return current_ticks;
}
```