ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<COMPARE2>:
  endbr64
  push   %r12
  cmp    %esi,%edi
  mov    %esi,%r10d
  push   %rbp
  mov    %esi,%ebp
  cmovbe %edi,%ebp
  push   %rbx
  test   %ebp,%ebp
  je     L51
  mov    %rdx,%r11
  mov    %r8d,%eax
  xor    %edx,%edx
  mov    %rcx,%rbx
  div    %edi
  mov    %r9d,%eax
  movsbl (%r11,%rdx,1),%r12d
  xor    %edx,%edx
  div    %esi
  movsbl (%rcx,%rdx,1),%edx
  cmp    %edx,%r12d
  jne    L61
  cmp    $0x1,%ebp
  je     L46
  xor    %ecx,%ecx
  jmp    L24
  nopl   0x0(%rax)
L48:
  add    $0x3,%esi
  cmp    %esi,%ebp
  jb     L46
L24:
  mov    %ecx,%esi
  add    $0x1,%ecx
  xor    %edx,%edx
  lea    (%r8,%rcx,1),%eax
  div    %edi
  lea    (%r9,%rcx,1),%eax
  movsbl (%r11,%rdx,1),%r12d
  xor    %edx,%edx
  div    %r10d
  movsbl (%rbx,%rdx,1),%edx
  cmp    %edx,%r12d
  je     L48
  lea    0x2(%rsi),%eax
L23:
  mov    %eax,%ecx
  pop    %rbx
  pop    %rbp
  neg    %ecx
  cmp    %edx,%r12d
  pop    %r12
  cmovge %ecx,%eax
  ret
  nopl   (%rax)
L51:
  cmp    %edi,%esi
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  or     $0x1,%eax
  ret
  nopl   0x0(%rax)
L46:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L61:
  mov    $0x1,%eax
  jmp    L23
```

assistant: ```c
int COMPARE2(unsigned int nA, unsigned int nB, const char *const a, const char *const b, unsigned int i, unsigned int j) {
  unsigned int k, s = ((nA) > (nB) ? (nB) : (nA));
  if (s == 0) {
    return (nB < nA) ? -1 : 1;
  }
  for (k = 0;; k++) {
    int A = (int)a[(i + k) % nA];
    int B = (int)b[(j + k) % nB];
    if (A == B) {
      if (k + 2 > s)
        return 0;
    } else if (A < B) {
      return (int)(k + 1u);
    } else {
      return -(int)(k + 1u);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<COMPARE2>:
  endbr64
  push   %r12
  cmp    %esi,%edi
  mov    %esi,%r10d
  push   %rbp
  mov    %esi,%ebp
  cmovbe %edi,%ebp
  push   %rbx
  test   %ebp,%ebp
  je     L0
  mov    %rdx,%r11
  mov    %r8d,%eax
  xor    %edx,%edx
  mov    %rcx,%rbx
  div    %edi
  mov    %r9d,%eax
  movsbl (%r11,%rdx,1),%r12d
  xor    %edx,%edx
  div    %esi
  movsbl (%rcx,%rdx,1),%edx
  cmp    %edx,%r12d
  jne    L26
  cmp    $0x1,%ebp
  je     L12
  xor    %ecx,%ecx
  jmp    L41
  nopl   0x0(%rax)
L65:
  add    $0x3,%esi
  cmp    %esi,%ebp
  jb     L12
L41:
  mov    %ecx,%esi
  add    $0x1,%ecx
  xor    %edx,%edx
  lea    (%r8,%rcx,1),%eax
  div    %edi
  lea    (%r9,%rcx,1),%eax
  movsbl (%r11,%rdx,1),%r12d
  xor    %edx,%edx
  div    %r10d
  movsbl (%rbx,%rdx,1),%edx
  cmp    %edx,%r12d
  je     L65
  lea    0x2(%rsi),%eax
L56:
  mov    %eax,%ecx
  pop    %rbx
  pop    %rbp
  neg    %ecx
  cmp    %edx,%r12d
  pop    %r12
  cmovge %ecx,%eax
  ret
  nopl   (%rax)
L0:
  cmp    %edi,%esi
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  or     $0x1,%eax
  ret
  nopl   0x0(%rax)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    $0x1,%eax
  jmp    L56
```

assistant: ```c
int COMPARE2(unsigned int nA, unsigned int nB, const char *const a, const char *const b, unsigned int i, unsigned int j) {
  unsigned int k, s = ((nA) > (nB) ? (nB) : (nA));
  if (s == 0) {
    return (nB < nA) ? -1 : 1;
  }
  for (k = 0;; k++) {
    int A = (int)a[(i + k) % nA];
    int B = (int)b[(j + k) % nB];
    if (A == B) {
      if (k + 2 > s)
        return 0;
    } else if (A < B) {
      return (int)(k + 1u);
    } else {
      return -(int)(k + 1u);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<expecti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L6
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D22
data_type: string
name: read_data
arguments: label: D29
data_type: string

tool: D19:  [ERROR]

tool: D22:     Expected: %d


tool: D29:     Result:   %d


assistant: ```c
void expecti(int a, int b) {
  if (a != b) {
    printf(" [ERROR]\n");
    printf("    Expected: %d\n", b);
    printf("    Result:   %d\n", a);
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<expecti>:
  endbr64
  cmp    %esi,%edi
  jne    L3
  ret
L3:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string

tool: D6:  [ERROR]

tool: D8:     Expected: %d


tool: D18:     Result:   %d


assistant: ```c
void expecti(int a, int b) {
  if (a != b) {
    printf(" [ERROR]\n");
    printf("    Expected: %d\n", b);
    printf("    Result:   %d\n", a);
    exit(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expecti>:
  endbr64
  cmp    %esi,%edi
  jne    L5
  ret
  nopl   0x0(%rax)
L5:
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string

tool: D3:  [ERROR]

tool: D29:     Expected: %d


tool: D16:     Result:   %d


assistant: ```c
void expecti(int a, int b) {
  if (a != b) {
    printf(" [ERROR]\n");
    printf("    Expected: %d\n", b);
    printf("    Result:   %d\n", a);
    exit(1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<expecti>:
  endbr64
  cmp    %esi,%edi
  jne    L1
  ret
  nopl   0x0(%rax)
L1:
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D23(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D23:  [ERROR]

tool: D27:     Expected: %d


tool: D7:     Result:   %d


assistant: ```c
void expecti(int a, int b) {
  if (a != b) {
    printf(" [ERROR]\n");
    printf("    Expected: %d\n", b);
    printf("    Result:   %d\n", a);
    exit(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_simulation_completed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D18
type: string

tool: D7: The simulation completed

tool: D18: -------------------------

assistant: ```c
void print_simulation_completed(void) {
  puts("The simulation completed");
  puts("-------------------------");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_simulation_completed>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string

tool: D7: The simulation completed

tool: D14: -------------------------

assistant: ```c
void print_simulation_completed(void) {
  puts("The simulation completed");
  puts("-------------------------");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_simulation_completed>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D2: The simulation completed

tool: D3: -------------------------

assistant: ```c
void print_simulation_completed(void) {
  puts("The simulation completed");
  puts("-------------------------");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_simulation_completed>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D6: The simulation completed

tool: D8: -------------------------

assistant: ```c
void print_simulation_completed(void) {
  puts("The simulation completed");
  puts("-------------------------");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<console_printlogadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void console_printlogadd(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stderr, fmt, arglist);
  va_end(arglist);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<console_printlogadd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void console_printlogadd(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stderr, fmt, arglist);
  va_end(arglist);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<console_printlogadd>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void console_printlogadd(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stderr, fmt, arglist);
  va_end(arglist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<console_printlogadd>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void console_printlogadd(char *fmt, ...) {
  va_list arglist;
  va_start(arglist, fmt);
  vfprintf(stderr, fmt, arglist);
  va_end(arglist);
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_write_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
L25:
  mov    -0x44(%rbp),%eax
  cltq
  and    $0x7f,%eax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  sarl   $0x7,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  je     L3
  mov    -0x40(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    (%rax),%rdx
  or     $0x80,%dl
  mov    %rdx,(%rax)
  jmp    L25
L3:
  lea    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  sub    %rdx,%rax
  sar    $0x3,%rax
  add    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void do_write_number(uint32_t num) {
  u_char buf[5], *b = buf;
  size_t sz;
  do {
    *b = (u_char)(num & 0x7f);
  } while ((num >>= 7) && (*(b++) |= 0x80));
  sz = b - buf + 1;
  do_write(buf, sz);
}
```
user: What is the c source code of the assembly code below:

```asm
<do_write_number>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  and    $0x7f,%eax
  mov    %edi,%edx
  and    $0x7f,%edx
  mov    %rdx,(%rsp)
  sar    $0x7,%edi
  je     L39
  mov    %rsp,%rsi
L9:
  add    $0x8,%rsi
  or     $0x80,%al
  cltq
  mov    %rax,-0x8(%rsi)
  mov    %edi,%eax
  and    $0x7f,%eax
  mov    %edi,%edx
  and    $0x7f,%edx
  mov    %rdx,(%rsi)
  sar    $0x7,%edi
  jne    L9
L4:
  mov    %rsp,%rdi
  sub    %rdi,%rsi
  sar    $0x3,%rsi
  add    $0x1,%rsi
  call   <do_write@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x38,%rsp
  ret
L39:
  mov    %rsp,%rsi
  jmp    L4
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_write_number(uint32_t num) {
  u_char buf[5], *b = buf;
  size_t sz;
  do {
    *b = (u_char)(num & 0x7f);
  } while ((num >>= 7) && (*(b++) |= 0x80));
  sz = b - buf + 1;
  do_write(buf, sz);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_write_number>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    %edi,%eax
  and    $0x7f,%edx
  mov    %rdx,(%rsp)
  and    $0x7f,%eax
  sar    $0x7,%edi
  je     L6
  mov    %rsp,%r8
  mov    %r8,%rsi
  nop
L28:
  or     $0x80,%al
  add    $0x8,%rsi
  mov    %edi,%edx
  cltq
  and    $0x7f,%edx
  mov    %rax,-0x8(%rsi)
  mov    %edi,%eax
  and    $0x7f,%eax
  sar    $0x7,%edi
  mov    %rdx,(%rsi)
  jne    L28
  sub    %r8,%rsi
  sar    $0x3,%rsi
  add    $0x1,%rsi
L17:
  mov    %r8,%rdi
  call   <do_write@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x38,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    $0x1,%esi
  mov    %rsp,%r8
  jmp    L17
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_write_number(uint32_t num) {
  u_char buf[5], *b = buf;
  size_t sz;
  do {
    *b = (u_char)(num & 0x7f);
  } while ((num >>= 7) && (*(b++) |= 0x80));
  sz = b - buf + 1;
  do_write(buf, sz);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<do_write_number>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    %edi,%eax
  and    $0x7f,%edx
  mov    %rdx,(%rsp)
  and    $0x7f,%eax
  sar    $0x7,%edi
  je     L12
  mov    %rsp,%r8
  mov    %r8,%rsi
  nop
L27:
  or     $0x80,%al
  mov    %edi,%edx
  add    $0x8,%rsi
  cltq
  and    $0x7f,%edx
  movq   %rax,%xmm0
  movq   %rdx,%xmm1
  mov    %edi,%eax
  and    $0x7f,%eax
  punpcklqdq %xmm1,%xmm0
  sar    $0x7,%edi
  movups %xmm0,-0x8(%rsi)
  jne    L27
  sub    %r8,%rsi
  sar    $0x3,%rsi
  add    $0x1,%rsi
L13:
  mov    %r8,%rdi
  call   <do_write@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L12:
  mov    $0x1,%esi
  mov    %rsp,%r8
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_write_number(uint32_t num) {
  u_char buf[5], *b = buf;
  size_t sz;
  do {
    *b = (u_char)(num & 0x7f);
  } while ((num >>= 7) && (*(b++) |= 0x80));
  sz = b - buf + 1;
  do_write(buf, sz);
}
```
user: Translate the below assembly code into C programming language:

```asm
<laplacian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L52
L28:
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x100(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__builtin_prefetch@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L59
L58:
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <kernel@plt>
  addl   $0x4,-0x4(%rbp)
L59:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0x3,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L58
  jmp    L53
L22:
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <kernel_sequential@plt>
  addl   $0x1,-0x4(%rbp)
L53:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L22
  addl   $0x1,-0x8(%rbp)
L52:
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void laplacian(double *v1, double *v2, int dim_m, int dim_n) {
#pragma omp parallel for schedule(static)
  for (int j = 1; j < dim_n - 1; ++j) {
    __builtin_prefetch((void *)v2 + j * dim_n + 256, 0, 1);
    int i;
    for (i = 1; i < dim_m - 1 - (dim_m - 1) % 4; i = i + 4) {
      kernel(v1 + j * dim_n + i, v2 + j * dim_n + i, dim_n);
    }
    for (; i < dim_m - 1; ++i) {
      kernel_sequential(v1 + j * dim_n + i, v2 + j * dim_n + i, dim_n);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<laplacian>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %edx,0x40(%rsp)
  cmp    $0x2,%ecx
  jle    L25
  mov    %rdi,%r13
  mov    %ecx,%r12d
  lea    -0x1(%rdx),%ecx
  mov    %ecx,0x1c(%rsp)
  mov    %ecx,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rcx,%rdx,1),%eax
  and    $0x3,%eax
  sub    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%eax
  mov    %ecx,0x30(%rsp)
  movslq %r12d,%rcx
  mov    %rcx,0x20(%rsp)
  lea    0x0(,%rcx,8),%rdi
  mov    %rdi,0x28(%rsp)
  add    $0x8,%rdi
  mov    %rdi,0x8(%rsp)
  lea    -0x1(%r12),%edi
  mov    %edi,0x34(%rsp)
  sub    $0x2,%eax
  mov    %eax,%edx
  shr    $0x2,%edx
  mov    %edx,%edx
  lea    0x0(,%rdx,4),%rdi
  mov    %rdi,0x48(%rsp)
  and    $0xfffffffc,%eax
  add    $0x5,%eax
  mov    %eax,0x44(%rsp)
  mov    %rcx,(%rsp)
  mov    $0x1,%r14d
  lea    0x100(%rsi),%rax
  mov    %rax,0x38(%rsp)
L1:
  mov    0x38(%rsp),%rdi
  mov    (%rsp),%r15
  add    %r15,%rdi
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <__builtin_prefetch@plt>
  cmpl   $0x1,0x30(%rsp)
  jle    L9
  mov    0x8(%rsp),%rax
  lea    (%rax,%r13,1),%rbx
  mov    0x10(%rsp),%rbp
  add    %rax,%rbp
  mov    0x48(%rsp),%rax
  add    %r15,%rax
  lea    0x28(%r13,%rax,8),%r15
L20:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <kernel@plt>
  add    $0x20,%rbx
  add    $0x20,%rbp
  cmp    %r15,%rbx
  jne    L20
  mov    0x44(%rsp),%ecx
L22:
  cmp    %ecx,0x1c(%rsp)
  jle    L44
  movslq %ecx,%rdx
  add    (%rsp),%rdx
  lea    0x0(,%rdx,8),%rbp
  lea    0x0(%r13,%rbp,1),%rbx
  add    0x10(%rsp),%rbp
  mov    0x40(%rsp),%eax
  sub    $0x2,%eax
  sub    %ecx,%eax
  add    %rdx,%rax
  lea    0x8(%r13,%rax,8),%r15
L67:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <kernel_sequential@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbx
  jne    L67
L44:
  add    $0x1,%r14d
  mov    0x20(%rsp),%rcx
  add    %rcx,(%rsp)
  mov    0x28(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  cmp    0x34(%rsp),%r14d
  jne    L1
L25:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    $0x1,%ecx
  jmp    L22
```

assistant: ```c
void laplacian(double *v1, double *v2, int dim_m, int dim_n) {
#pragma omp parallel for schedule(static)
  for (int j = 1; j < dim_n - 1; ++j) {
    __builtin_prefetch((void *)v2 + j * dim_n + 256, 0, 1);
    int i;
    for (i = 1; i < dim_m - 1 - (dim_m - 1) % 4; i = i + 4) {
      kernel(v1 + j * dim_n + i, v2 + j * dim_n + i, dim_n);
    }
    for (; i < dim_m - 1; ++i) {
      kernel_sequential(v1 + j * dim_n + i, v2 + j * dim_n + i, dim_n);
    }
  }
}
```