ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<show_usage>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rsi
  mov    %rdi,%rbp
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D100(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D72(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D40(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D96(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D94(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D89(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D98(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D49(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D81(%rip),%rsi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  lea    D99(%rip),%rsi
  pop    %rbp
  jmp    1050 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D100
type: string
name: parse_data
arguments: data_label: D72
type: string
name: parse_data
arguments: data_label: D40
type: string
name: parse_data
arguments: data_label: D96
type: string
name: parse_data
arguments: data_label: D94
type: string
name: parse_data
arguments: data_label: D89
type: string
name: parse_data
arguments: data_label: D98
type: string
name: parse_data
arguments: data_label: D49
type: string
name: parse_data
arguments: data_label: D81
type: string
name: parse_data
arguments: data_label: D99
type: string

tool: D7: Dump SuperCOSMOS binary 'source' file to stdout as text


tool: D100: USAGE:


tool: D72:    ssa-source-dump [OPTIONS] [FILE]


tool: D40: OPTIONS:


tool: D96:    -h  include columns header


tool: D94:    -r  include (one-based) record index


tool: D89:    minmag=float  minimal (bright) output magnitude


tool: D98:    maxmag=float  maximal (faint) output magnitude


tool: D49: If no input file is given then read plate file from stdin (to allow piped processing)


tool: D81: Examples:


tool: D99:  ssa-source-dump -h ssaSource000ra030.bin


assistant: ```c
void show_usage(FILE *output) {
  fprintf(output, "Dump SuperCOSMOS binary 'source' file to stdout as text\n");
  fprintf(output, "USAGE:\n");
  fprintf(output, "   ssa-source-dump [OPTIONS] [FILE]\n");
  fprintf(output, "OPTIONS:\n");
  fprintf(output, "   -h  include columns header\n");
  fprintf(output, "   -r  include (one-based) record index\n");
  fprintf(output, "   minmag=float  minimal (bright) output magnitude\n");
  fprintf(output, "   maxmag=float  maximal (faint) output magnitude\n");
  fprintf(output, "If no input file is given then read plate file from stdin (to allow piped processing)\n");
  fprintf(output, "Examples:\n");
  fprintf(output, " ssa-source-dump -h ssaSource000ra030.bin\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<celcon_write_mixed_cell_configuration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x51,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int celcon_write_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(81, a, b, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<celcon_write_mixed_cell_configuration>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x51,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int celcon_write_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(81, a, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<celcon_write_mixed_cell_configuration>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x51,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int celcon_write_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(81, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<celcon_write_mixed_cell_configuration>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x51,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int celcon_write_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(81, a, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_matches_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L28
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
L28:
  mov    $0x0,%eax
  jmp    L10
L22:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L10:
  leave
  ret
```

assistant: ```c
int string_matches_value(char *str, const char *value) {
  if (str == NULL || value == NULL)
    return 0;
  return strncmp(str, value, strlen(value)) == 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_matches_value>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L14
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int string_matches_value(char *str, const char *value) {
  if (str == NULL || value == NULL)
    return 0;
  return strncmp(str, value, strlen(value)) == 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_matches_value>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L19
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L19:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int string_matches_value(char *str, const char *value) {
  if (str == NULL || value == NULL)
    return 0;
  return strncmp(str, value, strlen(value)) == 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_matches_value>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L14
  mov    %rdi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int string_matches_value(char *str, const char *value) {
  if (str == NULL || value == NULL)
    return 0;
  return strncmp(str, value, strlen(value)) == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0xffffffec,%esi
  mov    $0xfffffff6,%edi
  call   <move@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <addstr@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: Hello, World!

assistant: ```c
int main(int argc, char *argv[]) {
  initscr();
  move(-10, -20);
  addstr("Hello, World!");
  getch();
  endwin();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0xffffffec,%esi
  mov    $0xfffffff6,%edi
  call   <move@plt>
  lea    D0(%rip),%rdi
  call   <addstr@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: Hello, World!

assistant: ```c
int main(int argc, char *argv[]) {
  initscr();
  move(-10, -20);
  addstr("Hello, World!");
  getch();
  endwin();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  mov    $0xffffffec,%esi
  mov    $0xfffffff6,%edi
  call   <move@plt>
  lea    D8(%rip),%rdi
  call   <addstr@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Hello, World!

assistant: ```c
int main(int argc, char *argv[]) {
  initscr();
  move(-10, -20);
  addstr("Hello, World!");
  getch();
  endwin();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  mov    $0xffffffec,%esi
  mov    $0xfffffff6,%edi
  call   <move@plt>
  lea    D4(%rip),%rdi
  call   <addstr@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: Hello, World!

assistant: ```c
int main(int argc, char *argv[]) {
  initscr();
  move(-10, -20);
  addstr("Hello, World!");
  getch();
  endwin();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printResults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x5f5e0ff,-0x3c(%rbp)
  jmp    L29
L23:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L15
  cmpl   $0x9,-0x44(%rbp)
  jg     L43
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x3c(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L43:
  addl   $0x1,-0x44(%rbp)
  mov    -0x3c(%rbp),%eax
  add    %eax,-0x40(%rbp)
L15:
  subl   $0x2,-0x3c(%rbp)
L29:
  cmpl   $0x1,-0x3c(%rbp)
  jg     L23
  addl   $0x2,-0x40(%rbp)
  addl   $0x1,-0x44(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <getTimeElapsed@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x9,-0x38(%rbp)
L20:
  cmpq   $0x0,-0x38(%rbp)
  je     L4
  lea    D0(%rip),%rax
  jmp    L1
L4:
  lea    D16(%rip),%rax
L1:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp,%rdx,4),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subq   $0x1,-0x38(%rbp)
  jmp    L20
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D58
type_infered: string
name: read_data
arguments: tag: D33
type_infered: string
name: read_data
arguments: tag: D69
type_infered: string
name: read_data
arguments: tag: D0
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string
name: read_data
arguments: tag: D63
type_infered: string

tool: D1: Execution time: %fs


tool: D58: Found %u primes.


tool: D33: Sum of primes = %lu


tool: D69: Top ten maximum primes: 

tool: D0: , 

tool: D16: 


tool: D63: %u%s

assistant: ```c
void printResults(struct timeval *begTime, uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printResults>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x5f5e0ff,%eax
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L45
L54:
  add    $0x1,%ebx
  add    %edx,%ebp
L23:
  sub    $0x2,%rax
  cmp    $0x1,%rax
  je     L22
L45:
  mov    %eax,%edx
  cmpl   $0x0,(%rsi,%rax,4)
  jne    L23
  cmp    $0x9,%ebx
  jg     L54
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
  jmp    L54
L22:
  call   <getTimeElapsed@plt>
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x9,%ebx
  lea    D59(%rip),%rdx
  lea    D8(%rip),%r13
  mov    %rdx,%r12
  lea    D29(%rip),%rbp
L31:
  mov    (%rsp,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L31
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D65
datatype: string
name: read_data
arguments: label: D17
datatype: string
name: read_data
arguments: label: D59
datatype: string
name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D29
datatype: string

tool: D26: Execution time: %fs


tool: D18: Found %u primes.


tool: D65: Sum of primes = %lu


tool: D17: Top ten maximum primes: 

tool: D59: , 

tool: D8: %u%s

tool: D29: 


assistant: ```c
void printResults(struct timeval *begTime, uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printResults>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    $0x5f5e0ff,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,4),%ecx
  mov    %eax,%edx
  test   %ecx,%ecx
  jne    L18
  cmp    $0x9,%ebx
  jg     L9
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
L9:
  add    $0x1,%ebx
  add    %edx,%ebp
L18:
  sub    $0x2,%rax
  cmp    $0x1,%rax
  jne    L6
  call   <getTimeElapsed@plt>
  lea    D23(%rip),%rdi
  mov    %rsp,%r14
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  mov    $0x9,%ebx
  call   <printf@plt>
  lea    D50(%rip),%rdx
  lea    D69(%rip),%r13
  mov    %rdx,%r12
  lea    D34(%rip),%rbp
  nopl   0x0(%rax)
L2:
  mov    (%r14,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
type: string
name: extract_symbolic_data
arguments: data_tag: D55
type: string
name: extract_symbolic_data
arguments: data_tag: D43
type: string
name: extract_symbolic_data
arguments: data_tag: D53
type: string
name: extract_symbolic_data
arguments: data_tag: D50
type: string
name: extract_symbolic_data
arguments: data_tag: D69
type: string
name: extract_symbolic_data
arguments: data_tag: D34
type: string

tool: D23: Execution time: %fs


tool: D55: Found %u primes.


tool: D43: Sum of primes = %lu


tool: D53: Top ten maximum primes: 

tool: D50: , 

tool: D69: %u%s

tool: D34: 


assistant: ```c
void printResults(struct timeval *begTime, uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printResults>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    $0x5f5e0ff,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rsi,%rax,4),%ecx
  mov    %eax,%edx
  test   %ecx,%ecx
  jne    L17
  cmp    $0x9,%ebx
  jg     L9
  movslq %ebx,%rcx
  mov    %eax,(%rsp,%rcx,4)
L9:
  add    $0x1,%ebx
  add    %edx,%ebp
L17:
  sub    $0x2,%rax
  cmp    $0x1,%rax
  jne    L11
  call   <getTimeElapsed@plt>
  lea    D55(%rip),%rdi
  mov    %rsp,%r14
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%esi
  xor    %eax,%eax
  lea    D53(%rip),%rdi
  call   <printf@plt>
  lea    0x2(%rbp),%esi
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  mov    $0x9,%ebx
  call   <printf@plt>
  lea    D38(%rip),%rdx
  lea    D39(%rip),%r13
  mov    %rdx,%r12
  lea    D4(%rip),%rbp
  nopl   0x0(%rax)
L39:
  mov    (%r14,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  mov    %rbp,%rdx
  cmovne %r12,%rdx
  jmp    L39
```

tool_calls: name: extract_symbolic_data
arguments: label: D55
type: string
name: extract_symbolic_data
arguments: label: D53
type: string
name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D38
type: string
name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D55: Execution time: %fs


tool: D53: Found %u primes.


tool: D30: Sum of primes = %lu


tool: D26: Top ten maximum primes: 

tool: D38: , 

tool: D39: %u%s

tool: D4: 


assistant: ```c
void printResults(struct timeval *begTime, uint8_t *isComposite) {
  uint32_t numOfPrimes = 0;
  uint64_t sumOfPrimes = 0;
  uint32_t maxPrimes[10];
  for (uint32_t i = 100000001 - 2; i > 1; i -= 2) {
    if (!isComposite[i]) {
      if (numOfPrimes < 10)
        maxPrimes[numOfPrimes] = i;
      numOfPrimes++;
      sumOfPrimes += i;
    }
  }
  sumOfPrimes += 2;
  numOfPrimes++;
  printf("Execution time: %fs\n", getTimeElapsed(begTime));
  printf("Found %u primes.\n", numOfPrimes);
  printf("Sum of primes = %lu\n", sumOfPrimes);
  printf("Top ten maximum primes: ");
  for (int8_t i = 9; i >= 0; i--)
    printf("%u%s", maxPrimes[i], i ? ", " : "\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L5:
  nop
L2:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <waiting@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  call   <forkall@plt>
  mov    $0x0,%eax
  call   <go@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  volatile int a = 0;
  while (waiting(&a) == 0)
    continue;
  (void)forkall();
  (void)go();
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L11:
  mov    %rbx,%rdi
  call   <waiting@plt>
  test   %rax,%rax
  je     L11
  mov    $0x0,%eax
  call   <forkall@plt>
  mov    $0x0,%eax
  call   <go@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  volatile int a = 0;
  while (waiting(&a) == 0)
    continue;
  (void)forkall();
  (void)go();
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L11:
  mov    %rbx,%rdi
  call   <waiting@plt>
  test   %rax,%rax
  je     L11
  xor    %eax,%eax
  call   <forkall@plt>
  xor    %eax,%eax
  call   <go@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  volatile int a = 0;
  while (waiting(&a) == 0)
    continue;
  (void)forkall();
  (void)go();
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L5:
  mov    %rbx,%rdi
  call   <waiting@plt>
  test   %rax,%rax
  je     L5
  xor    %eax,%eax
  call   <forkall@plt>
  xor    %eax,%eax
  call   <go@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  volatile int a = 0;
  while (waiting(&a) == 0)
    continue;
  (void)forkall();
  (void)go();
  return (0);
}
```