ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<get_latest_deadline>:
  endbr64
  push   %r12
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <get_default_deadline@plt>
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <get_license_deadline@plt>
  lea    0x50(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <ctime_r@plt>
  mov    %eax,%edi
  call   <strip_n@plt>
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,%r12d
  call   <ctime_r@plt>
  mov    %eax,%edi
  call   <strip_n@plt>
  mov    %r12d,%edx
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <dbg@plt>
  mov    0x8(%rsp),%rax
  mov    (%rsp),%rdx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0xa0,%rsp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: def_deadline = %s lic_deadline=%s


assistant: ```c
time_t get_latest_deadline(void) {
  time_t def_deadline = 0;
  time_t lic_deadline = 0;
  time_t deadline = 0;
  char timebuf1[64];
  char timebuf2[64];
  def_deadline = get_default_deadline();
  lic_deadline = get_license_deadline();
  dbg("def_deadline = %s lic_deadline=%s\n", strip_n(ctime_r(&def_deadline, timebuf1)), strip_n(ctime_r(&lic_deadline, timebuf2)));
  deadline = ((def_deadline) > (lic_deadline) ? (def_deadline) : (lic_deadline));
  return deadline;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_latest_deadline>:
  endbr64
  push   %r12
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <get_default_deadline@plt>
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <get_license_deadline@plt>
  lea    0x50(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <ctime_r@plt>
  mov    %eax,%edi
  call   <strip_n@plt>
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,%r12d
  call   <ctime_r@plt>
  mov    %eax,%edi
  call   <strip_n@plt>
  mov    %r12d,%edx
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <dbg@plt>
  mov    0x8(%rsp),%rax
  mov    (%rsp),%rdx
  cmp    %rdx,%rax
  cmovl  %rdx,%rax
  mov    0x98(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0xa0,%rsp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: def_deadline = %s lic_deadline=%s


assistant: ```c
time_t get_latest_deadline(void) {
  time_t def_deadline = 0;
  time_t lic_deadline = 0;
  time_t deadline = 0;
  char timebuf1[64];
  char timebuf2[64];
  def_deadline = get_default_deadline();
  lic_deadline = get_license_deadline();
  dbg("def_deadline = %s lic_deadline=%s\n", strip_n(ctime_r(&def_deadline, timebuf1)), strip_n(ctime_r(&lic_deadline, timebuf2)));
  deadline = ((def_deadline) > (lic_deadline) ? (def_deadline) : (lic_deadline));
  return deadline;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<floyd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x10(%rsp)
  test   %ecx,%ecx
  jle    L97
  mov    %rdi,%rax
  mov    %rdx,%r10
  lea    0xfa8(%rdi),%rbx
  mov    %rbx,-0x20(%rsp)
  add    $0x4,%r10
  lea    -0x1(%rcx),%ebx
  mov    %rbx,%rdx
  neg    %rdx
  lea    -0x8(,%rdx,4),%rdi
  mov    %rdi,-0x18(%rsp)
  imul   $0xfa8,%rbx,%rdx
  lea    0x1f50(%rsi,%rdx,1),%r15
  mov    $0xfffffffffffffffc,%r14
  add    $0xfa8,%rax
  mov    %rax,-0x8(%rsp)
  add    $0x2,%rbx
  jmp    L96
L78:
  cmp    %edx,%edi
  je     L105
L95:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L112
L56:
  mov    (%r8,%rax,4),%edi
  mov    (%r9),%esi
  mov    (%r11,%rax,4),%ecx
  lea    (%rsi,%rcx,1),%edx
  add    (%r10),%edx
  cmp    $0x989680,%esi
  setne  %sil
  cmp    $0x989680,%ecx
  setne  %cl
  test   %cl,%sil
  je     L78
  cmp    %edx,%edi
  jle    L78
  mov    %edx,(%r8,%rax,4)
  mov    0xfa8(%rbp),%edx
  mov    %edx,(%r12,%rax,4)
  jmp    L95
L105:
  mov    0xfa8(%rbp),%edi
  cmp    %edi,(%r12,%rax,4)
  jle    L95
  mov    %edx,(%r8,%rax,4)
  mov    0xfa8(%rbp),%edx
  mov    %edx,(%r12,%rax,4)
  jmp    L95
L112:
  add    $0xfa8,%rbp
  add    $0xfa8,%r13
  add    $0xfa8,%r9
  cmp    %r15,%r13
  je     L100
L40:
  lea    (%r9,%r14,1),%r8
  mov    %r13,%r12
  mov    $0x1,%eax
  jmp    L56
L100:
  addq   $0xfa8,-0x20(%rsp)
  add    $0x4,%r10
  sub    $0x4,%r14
  cmp    -0x18(%rsp),%r14
  je     L97
L96:
  mov    -0x20(%rsp),%r11
  mov    -0x10(%rsp),%rax
  mov    %rax,%rbp
  sub    %r14,%rbp
  lea    0xfa8(%rax),%r13
  mov    -0x8(%rsp),%r9
  sub    %r14,%r9
  jmp    L40
L97:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int (*path)[1002], int *ar, int n) {
  int i, j, k;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      for (j = 1; j <= n; j++) {
        if (dist[i][j] > dist[i][k] + dist[k][j] + ar[k] && dist[i][k] != 10000000 && dist[k][j] != 10000000) {
          dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
          path[i][j] = path[i][k];
        } else if (dist[i][j] == dist[i][k] + dist[k][j] + ar[k]) {
          if (path[i][j] > path[i][k]) {
            dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
            path[i][j] = path[i][k];
          }
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<floyd>:
  endbr64
  test   %ecx,%ecx
  jle    L36
  mov    %ecx,%eax
  mov    %rdx,%r9
  push   %r15
  sub    $0x1,%eax
  push   %r14
  mov    %rdi,%r14
  add    $0x4,%r9
  imul   $0xfa8,%rax,%rdx
  push   %r13
  lea    0x2(%rax),%r11
  add    $0xfa8,%r14
  push   %r12
  mov    %r14,%r10
  mov    $0xfffffffffffffffc,%r12
  push   %rbp
  push   %rbx
  lea    0x1f54(%rdi,%rdx,1),%r13
  mov    %rax,%rdx
  lea    0xfa8(%rsi),%rax
  neg    %rdx
  lea    -0x8(,%rdx,4),%r15
  mov    %rax,-0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L62:
  mov    -0x8(%rsp),%rbx
  mov    %r14,%rdi
  sub    %r12,%rdi
  sub    %r12,%rbx
  cs nopw 0x0(%rax,%rax,1)
L30:
  lea    (%rdi,%r12,1),%r8
  lea    (%rbx,%r12,1),%rbp
  mov    $0x1,%eax
  jmp    L42
  nop
L18:
  cmp    $0x989680,%ecx
  je     L103
  cmp    $0x989680,%esi
  je     L103
  mov    %edx,(%r8,%rax,4)
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp,%rax,4)
L103:
  add    $0x1,%rax
  cmp    %rax,%r11
  je     L32
L42:
  mov    (%rdi),%ecx
  mov    (%r10,%rax,4),%esi
  lea    (%rcx,%rsi,1),%edx
  add    (%r9),%edx
  cmp    %edx,(%r8,%rax,4)
  jg     L18
  jne    L103
  mov    (%rbx),%esi
  cmp    %esi,0x0(%rbp,%rax,4)
  jle    L103
  mov    %esi,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L42
  nopl   0x0(%rax)
L32:
  add    $0xfa8,%rdi
  add    $0xfa8,%rbx
  cmp    %r13,%rdi
  jne    L30
  sub    $0x4,%r12
  add    $0x4,%r13
  add    $0xfa8,%r10
  add    $0x4,%r9
  cmp    %r15,%r12
  jne    L62
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int (*path)[1002], int *ar, int n) {
  int i, j, k;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      for (j = 1; j <= n; j++) {
        if (dist[i][j] > dist[i][k] + dist[k][j] + ar[k] && dist[i][k] != 10000000 && dist[k][j] != 10000000) {
          dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
          path[i][j] = path[i][k];
        } else if (dist[i][j] == dist[i][k] + dist[k][j] + ar[k]) {
          if (path[i][j] > path[i][k]) {
            dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
            path[i][j] = path[i][k];
          }
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floyd>:
  endbr64
  test   %ecx,%ecx
  jle    L13
  mov    %ecx,%eax
  mov    %rdx,%r9
  push   %r15
  sub    $0x1,%eax
  push   %r14
  mov    %rdi,%r14
  add    $0x4,%r9
  imul   $0xfa8,%rax,%rdx
  push   %r13
  lea    0x2(%rax),%r11
  add    $0xfa8,%r14
  push   %r12
  mov    %r14,%r10
  mov    $0xfffffffffffffffc,%r12
  push   %rbp
  push   %rbx
  lea    0x1f54(%rdi,%rdx,1),%r13
  mov    %rax,%rdx
  lea    0xfa8(%rsi),%rax
  neg    %rdx
  lea    -0x8(,%rdx,4),%r15
  mov    %rax,-0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L94:
  mov    -0x8(%rsp),%rbx
  mov    %r14,%rdi
  sub    %r12,%rdi
  sub    %r12,%rbx
  cs nopw 0x0(%rax,%rax,1)
L87:
  lea    (%rdi,%r12,1),%r8
  lea    (%rbx,%r12,1),%rbp
  mov    $0x1,%eax
  jmp    L58
  nop
L67:
  cmp    $0x989680,%ecx
  je     L37
  cmp    $0x989680,%esi
  je     L37
  mov    %edx,(%r8,%rax,4)
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp,%rax,4)
L37:
  add    $0x1,%rax
  cmp    %rax,%r11
  je     L101
L58:
  mov    (%rdi),%ecx
  mov    (%r10,%rax,4),%esi
  lea    (%rcx,%rsi,1),%edx
  add    (%r9),%edx
  cmp    %edx,(%r8,%rax,4)
  jg     L67
  jne    L37
  mov    (%rbx),%esi
  cmp    %esi,0x0(%rbp,%rax,4)
  jle    L37
  mov    %esi,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L58
  nopl   0x0(%rax)
L101:
  add    $0xfa8,%rdi
  add    $0xfa8,%rbx
  cmp    %rdi,%r13
  jne    L87
  sub    $0x4,%r12
  add    $0x4,%r13
  add    $0xfa8,%r10
  add    $0x4,%r9
  cmp    %r15,%r12
  jne    L94
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  ret
```

assistant: ```c
void floyd(int (*dist)[1002], int (*path)[1002], int *ar, int n) {
  int i, j, k;
  for (k = 1; k <= n; k++) {
    for (i = 1; i <= n; i++) {
      for (j = 1; j <= n; j++) {
        if (dist[i][j] > dist[i][k] + dist[k][j] + ar[k] && dist[i][k] != 10000000 && dist[k][j] != 10000000) {
          dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
          path[i][j] = path[i][k];
        } else if (dist[i][j] == dist[i][k] + dist[k][j] + ar[k]) {
          if (path[i][j] > path[i][k]) {
            dist[i][j] = dist[i][k] + dist[k][j] + ar[k];
            path[i][j] = path[i][k];
          }
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<splitmix32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x21,%rax
  xor    -0x18(%rbp),%rax
  movabs $0x62a9d9ed799705f5,%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x1c,%rax
  xor    -0x8(%rbp),%rax
  movabs $0xcb24d0a5c88c35b3,%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x20,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int splitmix32(const unsigned long seed) {
  unsigned long result = (seed ^ (seed >> 33)) * 0x62a9d9ed799705f5ul;
  result = (result ^ (result >> 28)) * 0xcb24d0a5c88c35b3ul;
  return (unsigned int)(result >> 32);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<splitmix32>:
  endbr64
  mov    %rdi,%rdx
  shr    $0x21,%rdx
  xor    %rdi,%rdx
  movabs $0x62a9d9ed799705f5,%rax
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x1c,%rax
  xor    %rdx,%rax
  movabs $0xcb24d0a5c88c35b3,%rdx
  imul   %rdx,%rax
  shr    $0x20,%rax
  ret
```

assistant: ```c
unsigned int splitmix32(const unsigned long seed) {
  unsigned long result = (seed ^ (seed >> 33)) * 0x62a9d9ed799705f5ul;
  result = (result ^ (result >> 28)) * 0xcb24d0a5c88c35b3ul;
  return (unsigned int)(result >> 32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<splitmix32>:
  endbr64
  movabs $0x62a9d9ed799705f5,%rax
  mov    %rdi,%rdx
  shr    $0x21,%rdx
  xor    %rdi,%rdx
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x1c,%rax
  xor    %rdx,%rax
  movabs $0xcb24d0a5c88c35b3,%rdx
  imul   %rdx,%rax
  shr    $0x20,%rax
  ret
```

assistant: ```c
unsigned int splitmix32(const unsigned long seed) {
  unsigned long result = (seed ^ (seed >> 33)) * 0x62a9d9ed799705f5ul;
  result = (result ^ (result >> 28)) * 0xcb24d0a5c88c35b3ul;
  return (unsigned int)(result >> 32);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<splitmix32>:
  endbr64
  movabs $0x62a9d9ed799705f5,%rax
  mov    %rdi,%rdx
  shr    $0x21,%rdx
  xor    %rdi,%rdx
  imul   %rax,%rdx
  mov    %rdx,%rax
  shr    $0x1c,%rax
  xor    %rdx,%rax
  movabs $0xcb24d0a5c88c35b3,%rdx
  imul   %rdx,%rax
  shr    $0x20,%rax
  ret
```

assistant: ```c
unsigned int splitmix32(const unsigned long seed) {
  unsigned long result = (seed ^ (seed >> 33)) * 0x62a9d9ed799705f5ul;
  result = (result ^ (result >> 28)) * 0xcb24d0a5c88c35b3ul;
  return (unsigned int)(result >> 32);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lex_postag_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void lex_postag_delete(char *p) {
  if (p) {
    free(p);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lex_postag_delete>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
void lex_postag_delete(char *p) {
  if (p) {
    free(p);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lex_postag_delete>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void lex_postag_delete(char *p) {
  if (p) {
    free(p);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lex_postag_delete>:
  endbr64
  test   %rdi,%rdi
  je     L7
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L7:
  ret
```

assistant: ```c
void lex_postag_delete(char *p) {
  if (p) {
    free(p);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<varCharIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x7a,%eax
  je     L76
  cmp    $0x7a,%eax
  jg     L59
  cmp    $0x78,%eax
  je     L10
  cmp    $0x79,%eax
  je     L17
  jmp    L59
L10:
  mov    $0x0,%eax
  jmp    L43
L17:
  mov    $0x1,%eax
  jmp    L43
L76:
  mov    $0x2,%eax
  jmp    L43
L59:
  nop
  mov    $0x0,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int varCharIndex(char var) {
  switch (var) {
  case 'x':
    return 0;
  case 'y':
    return 1;
  case 'z':
    return 2;
  default:
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<varCharIndex>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x79,%dil
  je     L7
  cmp    $0x7a,%dil
  sete   %al
  movzbl %al,%eax
  add    %eax,%eax
L7:
  ret
```

assistant: ```c
int varCharIndex(char var) {
  switch (var) {
  case 'x':
    return 0;
  case 'y':
    return 1;
  case 'z':
    return 2;
  default:
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<varCharIndex>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x79,%dil
  je     L0
  xor    %eax,%eax
  cmp    $0x7a,%dil
  sete   %al
  add    %eax,%eax
L0:
  ret
```

assistant: ```c
int varCharIndex(char var) {
  switch (var) {
  case 'x':
    return 0;
  case 'y':
    return 1;
  case 'z':
    return 2;
  default:
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<varCharIndex>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x79,%dil
  je     L9
  xor    %eax,%eax
  cmp    $0x7a,%dil
  sete   %al
  add    %eax,%eax
L9:
  ret
```

assistant: ```c
int varCharIndex(char var) {
  switch (var) {
  case 'x':
    return 0;
  case 'y':
    return 1;
  case 'z':
    return 2;
  default:
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<clad_comparei>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L16
  mov    $0xffffffff,%eax
  jmp    L28
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L4
  mov    $0x1,%eax
  jmp    L28
L4:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int clad_comparei(int one, int two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clad_comparei>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    %esi,%edi
  jl     L7
  setg   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int clad_comparei(int one, int two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clad_comparei>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  mov    $0xffffffff,%edx
  setg   %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int clad_comparei(int one, int two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<clad_comparei>:
  endbr64
  xor    %eax,%eax
  cmp    %esi,%edi
  mov    $0xffffffff,%edx
  setg   %al
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int clad_comparei(int one, int two) {
  if (one < two)
    return -1;
  if (one > two)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L32
L33:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  movl   $0x1,-0x18(%rbp)
  jmp    L36
L44:
  cmpl   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L36
L11:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L36:
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L33
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <transfer@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string
name: extract_symbolic_data
arguments: label: D20
type_infered: string

tool: D3: \

tool: D20:  

assistant: ```c
int main(int argc, char *argv[]) {
  char *str1 = calloc((argc - 1), sizeof(argv) / 2);
  char *str2 = calloc((argc - 1), sizeof(argv) / 2);
  int token = 0;
  for (int i = 1; i < argc; i++) {
    if (strcmp(argv[i], "\\") == 0) {
      token = 1;
      continue;
    }
    if (token) {
      strcat(str2, argv[i]);
      strcat(str2, " ");
    } else {
      strcat(str1, argv[i]);
      strcat(str1, " ");
    }
  }
  puts(str1);
  transfer(str1, str2);
  free(str1);
  free(str2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r14
  lea    -0x1(%rdi),%ebx
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  cmp    $0x1,%ebp
  jle    L5
  lea    0x8(%r14),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r14,%rax,8),%r15
  movl   $0x0,0xc(%rsp)
  lea    D11(%rip),%r14
  jmp    L46
L33:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L17:
  add    $0x8,%rbx
  cmp    %r15,%rbx
  je     L5
L46:
  mov    %r14,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  cmpl   $0x0,0xc(%rsp)
  je     L33
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  lea    D5(%rip),%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
  jmp    L17
L34:
  movl   $0x1,0xc(%rsp)
  jmp    L17
L5:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <transfer@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D5
datatype: string

tool: D11: \

tool: D5:  

assistant: ```c
int main(int argc, char *argv[]) {
  char *str1 = calloc((argc - 1), sizeof(argv) / 2);
  char *str2 = calloc((argc - 1), sizeof(argv) / 2);
  int token = 0;
  for (int i = 1; i < argc; i++) {
    if (strcmp(argv[i], "\\") == 0) {
      token = 1;
      continue;
    }
    if (token) {
      strcat(str2, argv[i]);
      strcat(str2, " ");
    } else {
      strcat(str1, argv[i]);
      strcat(str1, " ");
    }
  }
  puts(str1);
  transfer(str1, str2);
  free(str1);
  free(str2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0x4,%esi
  push   %r12
  lea    -0x1(%rdi),%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %r12d,%edi
  sub    $0x18,%rsp
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %rax,%r12
  cmp    $0x1,%ebx
  jle    L11
  lea    -0x2(%rbx),%eax
  lea    0x8(%r13),%r14
  movl   $0x0,0xc(%rsp)
  lea    0x10(%r13,%rax,8),%r13
  lea    D18(%rip),%rbx
  lea    D16(%rip),%r15
  jmp    L54
  nopl   0x0(%rax)
L38:
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L31:
  add    $0x8,%r14
  cmp    %r13,%r14
  je     L11
L54:
  mov    (%r14),%rdi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  mov    0xc(%rsp),%eax
  mov    (%r14),%rsi
  test   %eax,%eax
  jne    L38
  mov    %rbp,%rdi
  add    $0x8,%r14
  call   <strcat@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  cmp    %r13,%r14
  jne    L54
L11:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <transfer@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L22:
  movl   $0x1,0xc(%rsp)
  jmp    L31
```

tool_calls: name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D18: \

tool: D16:  

assistant: ```c
int main(int argc, char *argv[]) {
  char *str1 = calloc((argc - 1), sizeof(argv) / 2);
  char *str2 = calloc((argc - 1), sizeof(argv) / 2);
  int token = 0;
  for (int i = 1; i < argc; i++) {
    if (strcmp(argv[i], "\\") == 0) {
      token = 1;
      continue;
    }
    if (token) {
      strcat(str2, argv[i]);
      strcat(str2, " ");
    } else {
      strcat(str1, argv[i]);
      strcat(str1, " ");
    }
  }
  puts(str1);
  transfer(str1, str2);
  free(str1);
  free(str2);
}
```