ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_http_ipv4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L16
  lea    D5(%rip),%rdi
  lea    D14(%rip),%r12
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send_msg@plt>
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7d0,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L4:
  mov    $0x7d0,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv_msg@plt>
  test   %eax,%eax
  jg     L22
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    D9(%rip),%rdi
  call   <err_msg@plt>
  jmp    L45
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D5: Connect success

tool: D14: %s

tool: D9: connect()

assistant: ```c
void get_http_ipv4(const u_int *fd, struct sockaddr_in *saddr4, char *buff) {
  u_int nrecv;
  u_int trx_fd = *fd;
  struct sockaddr_in addr4;
  memcpy(&addr4, saddr4, sizeof(*saddr4));
  if (connect(trx_fd, (struct sockaddr *)&addr4, sizeof(addr4)) == -1)
    err_msg("connect()");
  else {
    printf("Connect success\n");
    send_msg(trx_fd, buff);
    while ((nrecv = recv_msg(trx_fd, buff, 2000)) > 0) {
      printf("%s", buff);
      memset(buff, 0, 2000);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<get_http_ipv4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <connect@plt>
  cmp    $0xffffffff,%eax
  je     L39
  lea    D4(%rip),%rdi
  lea    D14(%rip),%r12
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <send_msg@plt>
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7d0,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L17:
  mov    $0x7d0,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv_msg@plt>
  test   %eax,%eax
  jg     L45
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  lea    D16(%rip),%rdi
  call   <err_msg@plt>
  jmp    L16
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D4: Connect success

tool: D14: %s

tool: D16: connect()

assistant: ```c
void get_http_ipv4(const u_int *fd, struct sockaddr_in *saddr4, char *buff) {
  u_int nrecv;
  u_int trx_fd = *fd;
  struct sockaddr_in addr4;
  memcpy(&addr4, saddr4, sizeof(*saddr4));
  if (connect(trx_fd, (struct sockaddr *)&addr4, sizeof(addr4)) == -1)
    err_msg("connect()");
  else {
    printf("Connect success\n");
    send_msg(trx_fd, buff);
    while ((nrecv = recv_msg(trx_fd, buff, 2000)) > 0) {
      printf("%s", buff);
      memset(buff, 0, 2000);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_combs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L35
L38:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  cmp    %eax,-0x4(%rbp)
  jg     L38
  movl   $0x2,-0x4(%rbp)
  jmp    L15
L11:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L11
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int num_combs(int n, int k) {
  int combs = 1;
  int i;
  for (i = n; i > max(k, n - k); i--) {
    combs *= i;
  }
  for (i = 2; i <= min(k, n - k); i++) {
    combs /= i;
  }
  return combs;
}
```
user: What is the c source code of the assembly code below:

```asm
<num_combs>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edi,%ebp
  mov    $0x1,%ebx
  sub    %esi,%r12d
  jmp    L33
L0:
  imul   %ebp,%ebx
  sub    $0x1,%ebp
L33:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <max@plt>
  cmp    %ebp,%eax
  jl     L0
  mov    $0x2,%ebp
  jmp    L11
L5:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%ebx
  add    $0x1,%ebp
L11:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <min@plt>
  cmp    %ebp,%eax
  jge    L5
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_combs(int n, int k) {
  int combs = 1;
  int i;
  for (i = n; i > max(k, n - k); i--) {
    combs *= i;
  }
  for (i = 2; i <= min(k, n - k); i++) {
    combs /= i;
  }
  return combs;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<num_combs>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    %esi,%r13d
  mov    $0x1,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L20
L25:
  imul   %ebx,%r12d
  sub    $0x1,%ebx
L20:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <max@plt>
  cmp    %ebx,%eax
  jl     L25
  mov    $0x2,%ebx
  jmp    L8
  nopl   0x0(%rax)
L1:
  cltd
  idiv   %ebx
  add    $0x1,%ebx
  mov    %eax,%r12d
L8:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <min@plt>
  cmp    %ebx,%eax
  mov    %r12d,%eax
  jge    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_combs(int n, int k) {
  int combs = 1;
  int i;
  for (i = n; i > max(k, n - k); i--) {
    combs *= i;
  }
  for (i = 2; i <= min(k, n - k); i++) {
    combs /= i;
  }
  return combs;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_combs>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    %esi,%r13d
  mov    $0x1,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L34
L39:
  imul   %ebx,%r12d
  sub    $0x1,%ebx
L34:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <max@plt>
  cmp    %ebx,%eax
  jl     L39
  mov    $0x2,%ebx
  jmp    L6
  nopl   0x0(%rax)
L11:
  cltd
  idiv   %ebx
  add    $0x1,%ebx
  mov    %eax,%r12d
L6:
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <min@plt>
  cmp    %ebx,%eax
  mov    %r12d,%eax
  jge    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_combs(int n, int k) {
  int combs = 1;
  int i;
  for (i = n; i > max(k, n - k); i--) {
    combs *= i;
  }
  for (i = 2; i <= min(k, n - k); i++) {
    combs /= i;
  }
  return combs;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printAll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x9,-0x4(%rbp)
  jle    L21
  cmpl   $0xa,-0x4(%rbp)
  jne    L19
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L19:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D0: array=[%d] = %d


tool: D9: 


assistant: ```c
void printAll(int array[]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("array=[%d] = %d\n", i, array[i]);
  }
  if (i == 10)
    printf("\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printAll>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L8:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L8
  lea    D5(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D5
data_type: string

tool: D4: array=[%d] = %d


tool: D5: 


assistant: ```c
void printAll(int array[]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("array=[%d] = %d\n", i, array[i]);
  }
  if (i == 10)
    printf("\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printAll>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L8
  pop    %rbx
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D15
data_type: string

tool: D1: array=[%d] = %d


tool: D15: 


assistant: ```c
void printAll(int array[]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("array=[%d] = %d\n", i, array[i]);
  }
  if (i == 10)
    printf("\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printAll>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L8
  pop    %rbx
  lea    D14(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string

tool: D13: array=[%d] = %d


tool: D14: 


assistant: ```c
void printAll(int array[]) {
  int i;
  for (i = 0; i < 10; i++) {
    printf("array=[%d] = %d\n", i, array[i]);
  }
  if (i == 10)
    printf("\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L36
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L36
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L48
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <heapify>
L48:
  nop
  leave
  ret
```

assistant: ```c
void heapify(int arr[], int n, int i) {
  int largest = i;
  int l = 2 * i + 1;
  int r = 2 * i + 2;
  if (l < n && arr[l] > arr[largest])
    largest = l;
  if (r < n && arr[r] > arr[largest])
    largest = r;
  if (largest != i) {
    int t = arr[i];
    arr[i] = arr[largest];
    arr[largest] = t;
    heapify(arr, n, largest);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heapify>:
  endbr64
  mov    %edx,%eax
  lea    (%rdx,%rdx,1),%edx
  lea    0x1(%rdx),%ecx
  add    $0x2,%edx
  cmp    %esi,%ecx
  jge    L35
  movslq %ecx,%r8
  movslq %eax,%r9
  mov    (%rdi,%r9,4),%r10d
  cmp    %r10d,(%rdi,%r8,4)
  jle    L35
  cmp    %esi,%edx
  jge    L3
  movslq %edx,%r9
  mov    (%rdi,%r8,4),%r11d
  cmp    %r11d,(%rdi,%r9,4)
  cmovle %ecx,%edx
  jmp    L54
L3:
  mov    %ecx,%edx
  jmp    L54
L35:
  cmp    %esi,%edx
  jge    L15
  movslq %edx,%rcx
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r11d
  cmp    %r11d,(%rdi,%rcx,4)
  jle    L14
L54:
  cmp    %eax,%edx
  je     L15
  sub    $0x8,%rsp
  cltq
  lea    (%rdi,%rax,4),%rcx
  mov    (%rcx),%r8d
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%r9d
  mov    %r9d,(%rcx)
  mov    %r8d,(%rax)
  call   <heapify>
  add    $0x8,%rsp
  ret
L14:
  ret
L15:
  ret
```

assistant: ```c
void heapify(int arr[], int n, int i) {
  int largest = i;
  int l = 2 * i + 1;
  int r = 2 * i + 2;
  if (l < n && arr[l] > arr[largest])
    largest = l;
  if (r < n && arr[r] > arr[largest])
    largest = r;
  if (largest != i) {
    int t = arr[i];
    arr[i] = arr[largest];
    arr[largest] = t;
    heapify(arr, n, largest);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<heapify>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%r8d
  jmp    L17
  nopl   0x0(%rax)
L36:
  movslq %edx,%rsi
  movslq %edi,%r9
  mov    (%rcx,%rsi,4),%r11d
  cmp    %r11d,(%rcx,%r9,4)
  jle    L59
  cmp    %r8d,%eax
  jl     L2
  mov    %edi,%eax
L48:
  cmp    %edx,%eax
  je     L32
  movslq %eax,%rdx
  lea    (%rcx,%rsi,4),%rsi
  lea    (%rcx,%rdx,4),%rdx
  mov    (%rsi),%edi
  mov    (%rdx),%r9d
  mov    %r9d,(%rsi)
  mov    %edi,(%rdx)
  mov    %eax,%edx
L17:
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%edi
  add    $0x2,%eax
  cmp    %r8d,%edi
  jl     L36
L59:
  cmp    %r8d,%eax
  jge    L32
  movslq %edx,%rsi
  movslq %eax,%rdi
  mov    (%rcx,%rsi,4),%r10d
  cmp    %r10d,(%rcx,%rdi,4)
  jg     L48
L32:
  ret
L2:
  movslq %eax,%r10
  mov    (%rcx,%r9,4),%r11d
  cmp    %r11d,(%rcx,%r10,4)
  cmovle %edi,%eax
  jmp    L48
```

assistant: ```c
void heapify(int arr[], int n, int i) {
  int largest = i;
  int l = 2 * i + 1;
  int r = 2 * i + 2;
  if (l < n && arr[l] > arr[largest])
    largest = l;
  if (r < n && arr[r] > arr[largest])
    largest = r;
  if (largest != i) {
    int t = arr[i];
    arr[i] = arr[largest];
    arr[largest] = t;
    heapify(arr, n, largest);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<heapify>:
  endbr64
  mov    %esi,%r9d
  jmp    L60
  nopl   0x0(%rax)
L66:
  movslq %ecx,%r10
  movslq %edx,%r11
  lea    (%rdi,%r10,4),%rsi
  mov    (%rsi),%r8d
  cmp    (%rdi,%r11,4),%r8d
  jle    L52
  cmp    %r9d,%eax
  jl     L15
L17:
  cmp    %edx,%ecx
  je     L69
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %r8d,(%rax)
  mov    %edx,(%rsi)
  mov    %ecx,%edx
L60:
  lea    (%rdx,%rdx,1),%eax
  lea    0x1(%rax),%ecx
  add    $0x2,%eax
  cmp    %r9d,%ecx
  jl     L66
L52:
  cmp    %r9d,%eax
  jge    L69
  mov    %edx,%ecx
  movslq %edx,%r10
L15:
  movslq %eax,%rsi
  lea    (%rdi,%r10,4),%r10
  lea    (%rdi,%rsi,4),%rsi
  mov    (%r10),%r11d
  mov    (%rsi),%r8d
  cmp    %r11d,%r8d
  jg     L82
  mov    %r11d,%r8d
  mov    %r10,%rsi
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L82:
  mov    %eax,%ecx
  jmp    L17
  nopl   0x0(%rax)
L69:
  ret
```

assistant: ```c
void heapify(int arr[], int n, int i) {
  int largest = i;
  int l = 2 * i + 1;
  int r = 2 * i + 2;
  if (l < n && arr[l] > arr[largest])
    largest = l;
  if (r < n && arr[r] > arr[largest])
    largest = r;
  if (largest != i) {
    int t = arr[i];
    arr[i] = arr[largest];
    arr[largest] = t;
    heapify(arr, n, largest);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_bitremap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bitmap_weight@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bitmap_pos_to_ord@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L6
  cmpl   $0x0,-0x8(%rbp)
  jne    L29
L6:
  mov    -0x14(%rbp),%eax
  jmp    L22
L29:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bitmap_ord_to_pos@plt>
L22:
  leave
  ret
```

assistant: ```c
int bitmap_bitremap(int oldbit, const unsigned long *old, const unsigned long *new, int bits) {
  int w = bitmap_weight(new, bits);
  int n = bitmap_pos_to_ord(old, oldbit, bits);
  if (n < 0 || w == 0)
    return oldbit;
  else
    return bitmap_ord_to_pos(new, n % w, bits);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_bitremap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %ecx,%esi
  mov    %rdx,%rdi
  call   <bitmap_weight@plt>
  mov    %eax,%r13d
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <bitmap_pos_to_ord@plt>
  test   %eax,%eax
  js     L17
  test   %r13d,%r13d
  jne    L16
L17:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  cltd
  idiv   %r13d
  mov    %edx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <bitmap_ord_to_pos@plt>
  mov    %eax,%ebx
  jmp    L17
```

assistant: ```c
int bitmap_bitremap(int oldbit, const unsigned long *old, const unsigned long *new, int bits) {
  int w = bitmap_weight(new, bits);
  int n = bitmap_pos_to_ord(old, oldbit, bits);
  if (n < 0 || w == 0)
    return oldbit;
  else
    return bitmap_ord_to_pos(new, n % w, bits);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitmap_bitremap>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %ecx,%esi
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <bitmap_weight@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <bitmap_pos_to_ord@plt>
  test   %eax,%eax
  js     L14
  test   %ebx,%ebx
  jne    L7
L14:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  cltd
  mov    %rbp,%rdi
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %edx,%esi
  mov    %r12d,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <bitmap_ord_to_pos@plt>
```

assistant: ```c
int bitmap_bitremap(int oldbit, const unsigned long *old, const unsigned long *new, int bits) {
  int w = bitmap_weight(new, bits);
  int n = bitmap_pos_to_ord(old, oldbit, bits);
  if (n < 0 || w == 0)
    return oldbit;
  else
    return bitmap_ord_to_pos(new, n % w, bits);
}
```
user: What is the c source code of the assembly code below?

```asm
<bitmap_bitremap>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %ecx,%esi
  push   %r13
  mov    %edi,%r13d
  mov    %rdx,%rdi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <bitmap_weight@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <bitmap_pos_to_ord@plt>
  test   %eax,%eax
  js     L3
  test   %ebx,%ebx
  jne    L13
L3:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  cltd
  mov    %rbp,%rdi
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %edx,%esi
  mov    %r12d,%edx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <bitmap_ord_to_pos@plt>
```

assistant: ```c
int bitmap_bitremap(int oldbit, const unsigned long *old, const unsigned long *new, int bits) {
  int w = bitmap_weight(new, bits);
  int n = bitmap_pos_to_ord(old, oldbit, bits);
  if (n < 0 || w == 0)
    return oldbit;
  else
    return bitmap_ord_to_pos(new, n % w, bits);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gmtime_r@plt>
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = gmtime_r(&time, &timestruct);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <gmtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = gmtime_r(&time, &timestruct);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <gmtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = gmtime_r(&time, &timestruct);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <gmtime_r@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  time_t time;
  struct tm *timestruct_pointer;
  struct tm timestruct;
  timestruct_pointer = gmtime_r(&time, &timestruct);
}
```