ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sortFirst>:
  endbr64
  cmp    $0x1,%esi
  je     L49
  push   %rbp
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  push   %rbx
  lea    (%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L47
  xchg   %ax,%ax
L35:
  cmp    %rbp,%rbx
  je     L44
L47:
  mov    (%rbx),%edx
  mov    0x4(%rbx),%eax
  mov    %rbx,%rdi
  add    $0x4,%rbx
  cmp    %eax,%edx
  jle    L35
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%r8d
  cmp    %rbp,%rbx
  jne    L47
L44:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool sortFirst(int *array, int length) {
  bool swappedValues = false;
  int *cursor = array;
  while (--length) {
    if (*cursor > *(cursor + 1)) {
      swap(cursor, cursor + 1);
      swappedValues = true;
    }
    ++cursor;
  }
  return swappedValues;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sortFirst>:
  endbr64
  cmp    $0x1,%esi
  je     L24
  push   %rbp
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  push   %rbx
  lea    (%rdi,%rax,4),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L40
  xchg   %ax,%ax
L44:
  cmp    %rbp,%rbx
  je     L18
L40:
  mov    (%rbx),%edx
  mov    0x4(%rbx),%eax
  mov    %rbx,%rdi
  add    $0x4,%rbx
  cmp    %eax,%edx
  jle    L44
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    $0x1,%r8d
  cmp    %rbp,%rbx
  jne    L40
L18:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool sortFirst(int *array, int length) {
  bool swappedValues = false;
  int *cursor = array;
  while (--length) {
    if (*cursor > *(cursor + 1)) {
      swap(cursor, cursor + 1);
      swappedValues = true;
    }
    ++cursor;
  }
  return swappedValues;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L2
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L2:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strip@plt>
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  strip(argv[1]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L18
  mov    0x8(%rsi),%rdi
  call   <strip@plt>
  mov    $0x0,%eax
L1:
  add    $0x8,%rsp
  ret
L18:
  mov    (%rsi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  strip(argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L6
  mov    0x8(%rsi),%rdi
  call   <strip@plt>
  xor    %eax,%eax
L13:
  add    $0x8,%rsp
  ret
L6:
  mov    (%rsi),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L13
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string

tool: D4: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  strip(argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L10
  mov    0x8(%rsi),%rdi
  call   <strip@plt>
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  ret
L10:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  jmp    L14
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: Usage: %s filename


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("Usage: %s filename\n", argv[0]);
    return -1;
  }
  strip(argv[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc4(%rbp),%edx
  mov    -0xb4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void test(int a1, ...) {
  va_list va_arglist;
  va_start(va_arglist, a1);
  foo(va_arglist);
  va_end(va_arglist);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edi
  call   <foo@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test(int a1, ...) {
  va_list va_arglist;
  va_start(va_arglist, a1);
  foo(va_arglist);
  va_end(va_arglist);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <foo@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void test(int a1, ...) {
  va_list va_arglist;
  va_start(va_arglist, a1);
  foo(va_arglist);
  va_end(va_arglist);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  mov    %edi,%esi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edi
  call   <foo@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  ret
```

assistant: ```c
void test(int a1, ...) {
  va_list va_arglist;
  va_start(va_arglist, a1);
  foo(va_arglist);
  va_end(va_arglist);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_cmm_mark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_cmm_check_managed@plt>
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_cmm_push@plt>
  nop
  leave
  ret
```

assistant: ```c
void _cmm_mark(const void *p) {
  extern const bool cmm_debug_enabled;
  extern void _cmm_check_managed(const void *);
  extern void _cmm_push(const void *);
  if (cmm_debug_enabled)
    _cmm_check_managed(p);
  _cmm_push(p);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_cmm_mark>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    D0(%rip),%rax
  cmpl   $0x0,(%rax)
  jne    L6
L12:
  mov    %rbx,%rdi
  call   <_cmm_push@plt>
  pop    %rbx
  ret
L6:
  call   <_cmm_check_managed@plt>
  jmp    L12
```

assistant: ```c
void _cmm_mark(const void *p) {
  extern const bool cmm_debug_enabled;
  extern void _cmm_check_managed(const void *);
  extern void _cmm_push(const void *);
  if (cmm_debug_enabled)
    _cmm_check_managed(p);
  _cmm_push(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_cmm_mark>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L7
  jmp    1060 <_cmm_push@plt>
  cs nopw 0x0(%rax,%rax,1)
L7:
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <_cmm_check_managed@plt>
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  jmp    1060 <_cmm_push@plt>
```

assistant: ```c
void _cmm_mark(const void *p) {
  extern const bool cmm_debug_enabled;
  extern void _cmm_check_managed(const void *);
  extern void _cmm_push(const void *);
  if (cmm_debug_enabled)
    _cmm_check_managed(p);
  _cmm_push(p);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_cmm_mark>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L8
  jmp    1060 <_cmm_push@plt>
  cs nopw 0x0(%rax,%rax,1)
L8:
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <_cmm_check_managed@plt>
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  jmp    1060 <_cmm_push@plt>
```

assistant: ```c
void _cmm_mark(const void *p) {
  extern const bool cmm_debug_enabled;
  extern void _cmm_check_managed(const void *);
  extern void _cmm_push(const void *);
  if (cmm_debug_enabled)
    _cmm_check_managed(p);
  _cmm_push(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D10: 
 enter the values of a and b

tool: D6: %d%d 

tool: D8: %d %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  printf("\n enter the values of a and b");
  scanf("%d%d ", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d", a, b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: string
name: parse_data
arguments: data_label: D16
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string

tool: D25: 
 enter the values of a and b

tool: D16: %d%d 

tool: D23: %d %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  printf("\n enter the values of a and b");
  scanf("%d%d ", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d", a, b);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string

tool: D21: 
 enter the values of a and b

tool: D28: %d%d 

tool: D14: %d %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  printf("\n enter the values of a and b");
  scanf("%d%d ", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d", a, b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  mov    %edx,0x4(%rsp)
  mov    %esi,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D10
type: string

tool: D18: 
 enter the values of a and b

tool: D17: %d%d 

tool: D10: %d %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  printf("\n enter the values of a and b");
  scanf("%d%d ", &a, &b);
  a = a + b;
  b = a - b;
  a = a - b;
  printf("%d %d", a, b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%r8d
  mov    $0x4,%ecx
  mov    $0xa,%edx
  mov    $0x5,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1d,%esi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    D32(%rip),%rax
  movq   %rax,%xmm0
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D52
type_infered: string
name: retrieve_data
arguments: data_label: D49
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D45
type_infered: string
name: retrieve_data
arguments: data_label: D75
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: f64
name: retrieve_data
arguments: data_label: D60
type_infered: string
name: retrieve_data
arguments: data_label: D58
type_infered: string

tool: D52: Grade report for: Matthew Lozano

tool: D49: Assignment 01	

tool: D17: Test 01	Quiz 01	Worksheet 01

tool: D45: %d/5		%d/10	 %d/5	%d/10


tool: D75: Total points: %d/30


tool: D32: 96.67

tool: D60: Average: %.2f


tool: D58: Letter Grade: %c


assistant: ```c
int main() {
  printf("Grade report for: Matthew Lozano\n");
  printf("Assignment 01\t");
  printf("Test 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/5\t\t%d/10\t %d/5\t%d/10\n", 5, 10, 4, 10);
  printf("\n");
  printf("Total points: %d/30\n", 29);
  printf("Average: %.2f\n", 96.67);
  printf("Letter Grade: %c\n", 'A');
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%r8d
  mov    $0x4,%ecx
  mov    $0xa,%edx
  mov    $0x5,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1d,%esi
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D65(%rip),%xmm0
  lea    D44(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D50
type: string
name: disassemble_data
arguments: label: D9
type: string
name: disassemble_data
arguments: label: D37
type: string
name: disassemble_data
arguments: label: D53
type: string
name: disassemble_data
arguments: label: D58
type: string
name: disassemble_data
arguments: label: D65
type: f64
name: disassemble_data
arguments: label: D44
type: string
name: disassemble_data
arguments: label: D39
type: string

tool: D50: Grade report for: Matthew Lozano

tool: D9: Assignment 01	

tool: D37: Test 01	Quiz 01	Worksheet 01

tool: D53: %d/5		%d/10	 %d/5	%d/10


tool: D58: Total points: %d/30


tool: D65: 96.67

tool: D44: Average: %.2f


tool: D39: Letter Grade: %c


assistant: ```c
int main() {
  printf("Grade report for: Matthew Lozano\n");
  printf("Assignment 01\t");
  printf("Test 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/5\t\t%d/10\t %d/5\t%d/10\n", 5, 10, 4, 10);
  printf("\n");
  printf("Total points: %d/30\n", 29);
  printf("Average: %.2f\n", 96.67);
  printf("Letter Grade: %c\n", 'A');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D65(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%r8d
  mov    $0x4,%ecx
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0x5,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1d,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D19(%rip),%xmm0
  mov    $0x1,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D65
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string
name: parse_data
arguments: tag: D45
type_infered: string
name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: f64
name: parse_data
arguments: tag: D43
type_infered: string
name: parse_data
arguments: tag: D25
type_infered: string

tool: D65: Grade report for: Matthew Lozano

tool: D22: Assignment 01	

tool: D45: Test 01	Quiz 01	Worksheet 01

tool: D44: %d/5		%d/10	 %d/5	%d/10


tool: D3: Total points: %d/30


tool: D19: 96.67

tool: D43: Average: %.2f


tool: D25: Letter Grade: %c


assistant: ```c
int main() {
  printf("Grade report for: Matthew Lozano\n");
  printf("Assignment 01\t");
  printf("Test 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/5\t\t%d/10\t %d/5\t%d/10\n", 5, 10, 4, 10);
  printf("\n");
  printf("Total points: %d/30\n", 29);
  printf("Average: %.2f\n", 96.67);
  printf("Letter Grade: %c\n", 'A');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D51(%rip),%rdi
  call   <puts@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%r8d
  mov    $0x4,%ecx
  xor    %eax,%eax
  mov    $0xa,%edx
  mov    $0x5,%esi
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1d,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D3(%rip),%xmm0
  mov    $0x1,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D75(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D51
type: string
name: disassemble_data
arguments: label: D46
type: string
name: disassemble_data
arguments: label: D59
type: string
name: disassemble_data
arguments: label: D47
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D3
type: f64
name: disassemble_data
arguments: label: D30
type: string
name: disassemble_data
arguments: label: D75
type: string

tool: D51: Grade report for: Matthew Lozano

tool: D46: Assignment 01	

tool: D59: Test 01	Quiz 01	Worksheet 01

tool: D47: %d/5		%d/10	 %d/5	%d/10


tool: D12: Total points: %d/30


tool: D3: 96.67

tool: D30: Average: %.2f


tool: D75: Letter Grade: %c


assistant: ```c
int main() {
  printf("Grade report for: Matthew Lozano\n");
  printf("Assignment 01\t");
  printf("Test 01\tQuiz 01\tWorksheet 01\n");
  printf("%d/5\t\t%d/10\t %d/5\t%d/10\n", 5, 10, 4, 10);
  printf("\n");
  printf("Total points: %d/30\n", 29);
  printf("Average: %.2f\n", 96.67);
  printf("Letter Grade: %c\n", 'A');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <h@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int i(int x, int y) {
  int z;
  z = h(x);
  return z + y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<i>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <h@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int i(int x, int y) {
  int z;
  z = h(x);
  return z + y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<i>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <h@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int i(int x, int y) {
  int z;
  z = h(x);
  return z + y;
}
```
user: What is the c source code of the assembly code below?

```asm
<i>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <h@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int i(int x, int y) {
  int z;
  z = h(x);
  return z + y;
}
```