ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <getRandom@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: *(p + [%d]) : %d


assistant: ```c
int main() {
  int *p;
  int i;
  p = getRandom();
  for (i = 0; i < 10; i++) {
    printf("*(p + [%d]) : %d\n", i, *(p + i));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <getRandom@plt>
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5: *(p + [%d]) : %d


assistant: ```c
int main() {
  int *p;
  int i;
  p = getRandom();
  for (i = 0; i < 10; i++) {
    printf("*(p + [%d]) : %d\n", i, *(p + i));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strip_trailing_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L39
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jns    L20
  jmp    L30
L39:
  nop
L30:
  nop
  leave
  ret
```

assistant: ```c
void strip_trailing_chars(char *str, char char_to_strip) {
  for (int i = strlen(str) - 1; i >= 0; i--) {
    if (str[i] == char_to_strip) {
      str[i] = '\0';
    } else {
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strip_trailing_chars>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L10
  mov    %eax,%ecx
  movslq %edx,%rdx
  add    %rbp,%rdx
  cltq
  lea    -0x2(%rbp,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
L18:
  cmp    %bl,(%rdx)
  jne    L10
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L18
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strip_trailing_chars(char *str, char char_to_strip) {
  for (int i = strlen(str) - 1; i >= 0; i--) {
    if (str[i] == char_to_strip) {
      str[i] = '\0';
    } else {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strip_trailing_chars>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L6
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rax
  add    %rbp,%rdx
  sub    %rcx,%rax
  jmp    L22
  nop
L34:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L6
L22:
  cmp    %bl,(%rdx)
  je     L34
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strip_trailing_chars(char *str, char char_to_strip) {
  for (int i = strlen(str) - 1; i >= 0; i--) {
    if (str[i] == char_to_strip) {
      str[i] = '\0';
    } else {
      break;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strip_trailing_chars>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L17
  cltq
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  lea    -0x2(%rbp,%rax,1),%rax
  add    %rbp,%rdx
  sub    %rcx,%rax
  jmp    L11
  nop
L34:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L17
L11:
  cmp    %bl,(%rdx)
  je     L34
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strip_trailing_chars(char *str, char char_to_strip) {
  for (int i = strlen(str) - 1; i >= 0; i--) {
    if (str[i] == char_to_strip) {
      str[i] = '\0';
    } else {
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
#pragma nanos instrument declare(myEvent, "This is my event")
  sleep(1);
#pragma nanos instrument emit(myEvent, "1")
  sleep(1);
#pragma nanos instrument emit(myEvent, "2")
  sleep(1);
#pragma nanos instrument emit(myEvent, "3")
  sleep(1);
#pragma nanos instrument emit(myEvent, "4")
  sleep(1);
#pragma nanos instrument emit(myEvent, "5")
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
#pragma nanos instrument declare(myEvent, "This is my event")
  sleep(1);
#pragma nanos instrument emit(myEvent, "1")
  sleep(1);
#pragma nanos instrument emit(myEvent, "2")
  sleep(1);
#pragma nanos instrument emit(myEvent, "3")
  sleep(1);
#pragma nanos instrument emit(myEvent, "4")
  sleep(1);
#pragma nanos instrument emit(myEvent, "5")
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
#pragma nanos instrument declare(myEvent, "This is my event")
  sleep(1);
#pragma nanos instrument emit(myEvent, "1")
  sleep(1);
#pragma nanos instrument emit(myEvent, "2")
  sleep(1);
#pragma nanos instrument emit(myEvent, "3")
  sleep(1);
#pragma nanos instrument emit(myEvent, "4")
  sleep(1);
#pragma nanos instrument emit(myEvent, "5")
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
#pragma nanos instrument declare(myEvent, "This is my event")
  sleep(1);
#pragma nanos instrument emit(myEvent, "1")
  sleep(1);
#pragma nanos instrument emit(myEvent, "2")
  sleep(1);
#pragma nanos instrument emit(myEvent, "3")
  sleep(1);
#pragma nanos instrument emit(myEvent, "4")
  sleep(1);
#pragma nanos instrument emit(myEvent, "5")
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x34,%edi
  call   <f@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  struct A {
    int i, j;
  } x = {f(52), 3};
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%edi
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  struct A {
    int i, j;
  } x = {f(52), 3};
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%edi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  struct A {
    int i, j;
  } x = {f(52), 3};
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x34,%edi
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main(int argc, char *argv[]) {
  struct A {
    int i, j;
  } x = {f(52), 3};
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <remove_spaces@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  sete   %bl
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  sete   %al
  or     %ebx,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int is_char(char *tbd) {
  char *rmvd_tbd = remove_spaces(tbd);
  return (strlen(rmvd_tbd) == 1 | strlen(rmvd_tbd) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <remove_spaces@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  cmp    $0x1,%ebp
  sete   %al
  test   %edx,%edx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_char(char *tbd) {
  char *rmvd_tbd = remove_spaces(tbd);
  return (strlen(rmvd_tbd) == 1 | strlen(rmvd_tbd) == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <remove_spaces@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    $0x1,%ebx
  mov    %eax,%r8d
  sete   %al
  test   %r8d,%r8d
  sete   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_char(char *tbd) {
  char *rmvd_tbd = remove_spaces(tbd);
  return (strlen(rmvd_tbd) == 1 | strlen(rmvd_tbd) == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <remove_spaces@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    $0x1,%ebx
  mov    %eax,%r8d
  sete   %al
  test   %r8d,%r8d
  sete   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_char(char *tbd) {
  char *rmvd_tbd = remove_spaces(tbd);
  return (strlen(rmvd_tbd) == 1 | strlen(rmvd_tbd) == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2a,-0xc(%rbp)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Adresa: 0x%x	%d


assistant: ```c
int main() {
  int p = 42, *pi = (int *)malloc(10);
  for (int i = 0; 1; ++i) {
    printf("Adresa: 0x%x\t%d\n", pi + i, *(pi + i));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D1(%rip),%rbp
L3:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  jmp    L3
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: Adresa: 0x%x	%d


assistant: ```c
int main() {
  int p = 42, *pi = (int *)malloc(10);
  for (int i = 0; 1; ++i) {
    printf("Adresa: 0x%x\t%d\n", pi + i, *(pi + i));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: Adresa: 0x%x	%d


assistant: ```c
int main() {
  int p = 42, *pi = (int *)malloc(10);
  for (int i = 0; 1; ++i) {
    printf("Adresa: 0x%x\t%d\n", pi + i, *(pi + i));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L3:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: Adresa: 0x%x	%d


assistant: ```c
int main() {
  int p = 42, *pi = (int *)malloc(10);
  for (int i = 0; 1; ++i) {
    printf("Adresa: 0x%x\t%d\n", pi + i, *(pi + i));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ang_sort_comp_hook_longs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setle  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ang_sort_comp_hook_longs(const void *u, const void *v, int a, int b) {
  long *x = (long *)(u);
  (void)v;
  return (x[a] <= x[b]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ang_sort_comp_hook_longs>:
  endbr64
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,8),%rax
  cmp    %rax,(%rdi,%rdx,8)
  setle  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ang_sort_comp_hook_longs(const void *u, const void *v, int a, int b) {
  long *x = (long *)(u);
  (void)v;
  return (x[a] <= x[b]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ang_sort_comp_hook_longs>:
  endbr64
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,8),%rax
  cmp    %rax,(%rdi,%rdx,8)
  setle  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ang_sort_comp_hook_longs(const void *u, const void *v, int a, int b) {
  long *x = (long *)(u);
  (void)v;
  return (x[a] <= x[b]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ang_sort_comp_hook_longs>:
  endbr64
  movslq %edx,%rdx
  movslq %ecx,%rcx
  mov    (%rdi,%rcx,8),%rax
  cmp    %rax,(%rdi,%rdx,8)
  setle  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ang_sort_comp_hook_longs(const void *u, const void *v, int a, int b) {
  long *x = (long *)(u);
  (void)v;
  return (x[a] <= x[b]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_bit(void *_bits, int num) {
  uint32_t *bits = _bits;
  return (bits[num / 32] >> (num % 32)) & 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_bit>:
  endbr64
  mov    %esi,%ecx
  lea    0x1f(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x5,%eax
  cltq
  mov    (%rdi,%rax,4),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int get_bit(void *_bits, int num) {
  uint32_t *bits = _bits;
  return (bits[num / 32] >> (num % 32)) & 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_bit>:
  endbr64
  test   %esi,%esi
  lea    0x1f(%rsi),%eax
  mov    %esi,%ecx
  cmovns %esi,%eax
  sar    $0x5,%eax
  cltq
  mov    (%rdi,%rax,4),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int get_bit(void *_bits, int num) {
  uint32_t *bits = _bits;
  return (bits[num / 32] >> (num % 32)) & 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_bit>:
  endbr64
  test   %esi,%esi
  lea    0x1f(%rsi),%eax
  mov    %esi,%ecx
  cmovns %esi,%eax
  sar    $0x5,%eax
  cltq
  mov    (%rdi,%rax,4),%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int get_bit(void *_bits, int num) {
  uint32_t *bits = _bits;
  return (bits[num / 32] >> (num % 32)) & 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<equals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L15
  mov    $0x0,%eax
  jmp    L0
L15:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: FAIL: expected %d but was %d


assistant: ```c
int equals(int expected, int actual) {
  if (expected == actual) {
    return 0;
  }
  printf("FAIL: expected %d but was %d\n", expected, actual);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<equals>:
  endbr64
  mov    $0x0,%eax
  cmp    %esi,%edi
  je     L9
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L9:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: FAIL: expected %d but was %d


assistant: ```c
int equals(int expected, int actual) {
  if (expected == actual) {
    return 0;
  }
  printf("FAIL: expected %d but was %d\n", expected, actual);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<equals>:
  endbr64
  cmp    %esi,%edi
  je     L0
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: FAIL: expected %d but was %d


assistant: ```c
int equals(int expected, int actual) {
  if (expected == actual) {
    return 0;
  }
  printf("FAIL: expected %d but was %d\n", expected, actual);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<equals>:
  endbr64
  cmp    %esi,%edi
  je     L3
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: FAIL: expected %d but was %d


assistant: ```c
int equals(int expected, int actual) {
  if (expected == actual) {
    return 0;
  }
  printf("FAIL: expected %d but was %d\n", expected, actual);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smp_stack_elem_apption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int smp_stack_elem_apption(void *stk_elem, void *data) {
  *((int *)stk_elem) = *((int *)data);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smp_stack_elem_apption>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int smp_stack_elem_apption(void *stk_elem, void *data) {
  *((int *)stk_elem) = *((int *)data);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<smp_stack_elem_apption>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int smp_stack_elem_apption(void *stk_elem, void *data) {
  *((int *)stk_elem) = *((int *)data);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<smp_stack_elem_apption>:
  endbr64
  mov    (%rsi),%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int smp_stack_elem_apption(void *stk_elem, void *data) {
  *((int *)stk_elem) = *((int *)data);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xd8(%rbp)
  jmp    L14
L4:
  mov    -0xd8(%rbp),%eax
  cltq
  movb   $0x0,-0xd0(%rbp,%rax,1)
  addl   $0x1,-0xd8(%rbp)
L14:
  cmpl   $0xc7,-0xd8(%rbp)
  jle    L4
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <hash@plt>
  mov    %eax,-0xd4(%rbp)
  mov    -0xd4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D4
data_type: string

tool: D17: %s

tool: D4: %d

assistant: ```c
int main() {
  int result, zero;
  char arr[200];
  for (zero = 0; zero < 200; zero++)
    arr[zero] = '\0';
  scanf("%s", arr);
  result = hash(arr);
  printf("%d", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0xc8(%rsp),%rdx
L14:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <hash@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D16: %s

tool: D8: %d

assistant: ```c
int main() {
  int result, zero;
  char arr[200];
  for (zero = 0; zero < 200; zero++)
    arr[zero] = '\0';
  scanf("%s", arr);
  result = hash(arr);
  printf("%d", result);
  return 0;
}
```