ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x38(%rbp)
  movss  D5(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movl   $0x3,-0x34(%rbp)
  movsd  D29(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x3,-0x30(%rbp)
  fldt   0xe90(%rip)        # 2020 <_fini+0xe58>
  fstpt  -0x20(%rbp)
  mov    -0x30(%rbp),%ecx
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: byte[4]
name: extract_symbolic_data
arguments: label: D29
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: {"D5": [0x00,0x00,0x20,0x41]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D8: quo: %d, %d, %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int quof, quo, quol;
  float rf = remquof(100.0f, 30.0f, &quof);
  double r = remquo(100.0, 30.0, &quo);
  long double rl = remquol(100.0l, 30.0l, &quol);
  printf("quo: %d, %d, %d.\n", quof, quo, quol);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: quo: %d, %d, %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int quof, quo, quol;
  float rf = remquof(100.0f, 30.0f, &quof);
  double r = remquo(100.0, 30.0, &quo);
  long double rl = remquol(100.0l, 30.0l, &quol);
  printf("quo: %d, %d, %d.\n", quof, quo, quol);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: quo: %d, %d, %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int quof, quo, quol;
  float rf = remquof(100.0f, 30.0f, &quof);
  double r = remquo(100.0, 30.0, &quo);
  long double rl = remquol(100.0l, 30.0l, &quol);
  printf("quo: %d, %d, %d.\n", quof, quo, quol);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0x3,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: quo: %d, %d, %d.


assistant: ```c
int main(int argc, char *argv[]) {
  int quof, quo, quol;
  float rf = remquof(100.0f, 30.0f, &quof);
  double r = remquo(100.0, 30.0, &quo);
  long double rl = remquol(100.0l, 30.0l, &quol);
  printf("quo: %d, %d, %d.\n", quof, quo, quol);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<list_constructor_head>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L19:
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <list_push@plt>
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
struct list *list_constructor_head(int n) {
  struct list *head = NULL;
  int i = 0;
  for (i = 0; i < n; i++) {
    list_push(i, &head);
  }
  return head;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_constructor_head>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  jle    L5
  mov    %edi,%ebp
  mov    $0x0,%ebx
  mov    %rsp,%r12
L17:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <list_push@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L17
L5:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct list *list_constructor_head(int n) {
  struct list *head = NULL;
  int i = 0;
  for (i = 0; i < n; i++) {
    list_push(i, &head);
  }
  return head;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list_constructor_head>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  jle    L33
  mov    %edi,%ebp
  xor    %ebx,%ebx
  mov    %rsp,%r12
  nop
L30:
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <list_push@plt>
  cmp    %ebx,%ebp
  jne    L30
  mov    (%rsp),%rax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L33:
  xor    %eax,%eax
  jmp    L5
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct list *list_constructor_head(int n) {
  struct list *head = NULL;
  int i = 0;
  for (i = 0; i < n; i++) {
    list_push(i, &head);
  }
  return head;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<list_constructor_head>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  test   %edi,%edi
  jle    L8
  mov    %edi,%ebp
  xor    %ebx,%ebx
  mov    %rsp,%r12
  nop
L12:
  mov    %ebx,%edi
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <list_push@plt>
  cmp    %ebx,%ebp
  jne    L12
  mov    (%rsp),%rax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  jmp    L15
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct list *list_constructor_head(int n) {
  struct list *head = NULL;
  int i = 0;
  for (i = 0; i < n; i++) {
    list_push(i, &head);
  }
  return head;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<def_hashfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L4:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int def_hashfunc(void *key) {
  unsigned int hash = 0;
  unsigned char *k = (unsigned char *)key;
  while (*k)
    hash += *k++;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<def_hashfunc>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  mov    $0x0,%edx
L21:
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
L4:
  mov    %edx,%eax
  ret
L1:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
unsigned int def_hashfunc(void *key) {
  unsigned int hash = 0;
  unsigned char *k = (unsigned char *)key;
  while (*k)
    hash += *k++;
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<def_hashfunc>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L17
  xchg   %ax,%ax
L18:
  add    $0x1,%rdi
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int def_hashfunc(void *key) {
  unsigned int hash = 0;
  unsigned char *k = (unsigned char *)key;
  while (*k)
    hash += *k++;
  return hash;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<def_hashfunc>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L1
  xchg   %ax,%ax
L9:
  add    $0x1,%rdi
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L9
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int def_hashfunc(void *key) {
  unsigned int hash = 0;
  unsigned char *k = (unsigned char *)key;
  while (*k)
    hash += *k++;
  return hash;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<load_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L10
L0:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L0
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *load_input(FILE *stream) {
  int c;
  int n = 0;
  char *input = NULL;
  while ((c = getc(stream)) != EOF) {
    input = realloc(input, ++n);
    input[n - 1] = c;
  }
  input = realloc(input, n + 1);
  input[n] = 0;
  return input;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<load_input>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L2
L1:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    %bl,(%rax,%r12,1)
  mov    %r13,%r12
L2:
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  lea    0x1(%r12),%r13
  mov    D6(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L1
  lea    0x1(%r12),%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  movslq %r12d,%r14
  movb   $0x0,(%rax,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *load_input(FILE *stream) {
  int c;
  int n = 0;
  char *input = NULL;
  while ((c = getc(stream)) != EOF) {
    input = realloc(input, ++n);
    input[n - 1] = c;
  }
  input = realloc(input, n + 1);
  input[n] = 0;
  return input;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<load_input>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%r14
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L2:
  call   <realloc@plt>
  mov    %bl,(%rax,%rbp,1)
  mov    %rax,%r15
  add    $0x1,%rbp
L15:
  mov    %r13,%rdi
  movslq %ebp,%r12
  call   <getc@plt>
  lea    0x1(%rbp),%esi
  mov    %r15,%rdi
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  jne    L2
  call   <realloc@plt>
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *load_input(FILE *stream) {
  int c;
  int n = 0;
  char *input = NULL;
  while ((c = getc(stream)) != EOF) {
    input = realloc(input, ++n);
    input[n - 1] = c;
  }
  input = realloc(input, n + 1);
  input[n] = 0;
  return input;
}
```
user: What is the c source code of the assembly code below:

```asm
<load_input>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%r14
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L1:
  call   <realloc@plt>
  mov    %bl,(%rax,%rbp,1)
  mov    %rax,%r15
  add    $0x1,%rbp
L18:
  mov    %r13,%rdi
  movslq %ebp,%r12
  call   <getc@plt>
  lea    0x1(%rbp),%esi
  mov    %r15,%rdi
  mov    %eax,%ebx
  cmp    %eax,(%r14)
  jne    L1
  call   <realloc@plt>
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *load_input(FILE *stream) {
  int c;
  int n = 0;
  char *input = NULL;
  while ((c = getc(stream)) != EOF) {
    input = realloc(input, ++n);
    input[n - 1] = c;
  }
  input = realloc(input, n + 1);
  input[n] = 0;
  return input;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getnetbyaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x1,%edi
  call   <setnetent@plt>
  jmp    L5
L9:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L15
L5:
  mov    $0x0,%eax
  call   <getnetent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  jmp    L29
L15:
  nop
L29:
  mov    $0x0,%eax
  call   <endnetent@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct netent *getnetbyaddr(uint32_t net, int type) {
  struct netent *ne;
  setnetent(1);
  while ((ne = getnetent()) != NULL) {
    if ((ne->n_net == net) && (ne->n_addrtype == type)) {
      break;
    }
  }
  endnetent();
  return ne;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getnetbyaddr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x1,%edi
  call   <setnetent@plt>
L5:
  mov    $0x0,%eax
  call   <getnetent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  cmp    %rbp,(%rbx)
  jne    L5
  cmp    %r12d,0x8(%rbx)
  jne    L5
L8:
  mov    $0x0,%eax
  call   <endnetent@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct netent *getnetbyaddr(uint32_t net, int type) {
  struct netent *ne;
  setnetent(1);
  while ((ne = getnetent()) != NULL) {
    if ((ne->n_net == net) && (ne->n_addrtype == type)) {
      break;
    }
  }
  endnetent();
  return ne;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getnetbyaddr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <setnetent@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <getnetent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L23
  cmp    %rbx,(%r12)
  jne    L8
  cmp    %ebp,0x8(%r12)
  jne    L8
L23:
  xor    %eax,%eax
  call   <endnetent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct netent *getnetbyaddr(uint32_t net, int type) {
  struct netent *ne;
  setnetent(1);
  while ((ne = getnetent()) != NULL) {
    if ((ne->n_net == net) && (ne->n_addrtype == type)) {
      break;
    }
  }
  endnetent();
  return ne;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getnetbyaddr>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <setnetent@plt>
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  call   <getnetent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L22
  cmp    %rbx,(%r12)
  jne    L21
  cmp    %ebp,0x8(%r12)
  jne    L21
L22:
  xor    %eax,%eax
  call   <endnetent@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct netent *getnetbyaddr(uint32_t net, int type) {
  struct netent *ne;
  setnetent(1);
  while ((ne = getnetent()) != NULL) {
    if ((ne->n_net == net) && (ne->n_addrtype == type)) {
      break;
    }
  }
  endnetent();
  return ne;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<transpose_psdmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L17:
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L27:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L27
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose_psdmatrix(double **m, int dim) {
  double temp;
  int row, col;
  for (row = 0; row < dim; row++) {
    for (col = 0; col < row; col++) {
      temp = m[row][col];
      m[row][col] = m[col][row];
      m[col][row] = temp;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<transpose_psdmatrix>:
  endbr64
  test   %esi,%esi
  jle    L49
  lea    0x8(%rdi),%r9
  mov    $0x8,%edx
  mov    $0x0,%r10d
  jmp    L39
L26:
  mov    $0x0,%eax
L40:
  mov    %rax,%rcx
  add    (%r9),%rcx
  movsd  (%rcx),%xmm0
  mov    (%rdi,%rax,1),%r8
  movsd  (%r8,%rdx,1),%xmm1
  movsd  %xmm1,(%rcx)
  mov    (%rdi,%rax,1),%rcx
  movsd  %xmm0,(%rcx,%rdx,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L40
L1:
  add    $0x8,%r9
  add    $0x8,%rdx
L39:
  add    $0x1,%r10d
  cmp    %r10d,%esi
  je     L49
  test   %r10d,%r10d
  jg     L26
  jmp    L1
L49:
  ret
```

assistant: ```c
void transpose_psdmatrix(double **m, int dim) {
  double temp;
  int row, col;
  for (row = 0; row < dim; row++) {
    for (col = 0; col < row; col++) {
      temp = m[row][col];
      m[row][col] = m[col][row];
      m[col][row] = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transpose_psdmatrix>:
  endbr64
  mov    $0x8,%ecx
  xor    %r9d,%r9d
  test   %esi,%esi
  jle    L14
  add    $0x1,%r9d
  cmp    %r9d,%esi
  je     L4
  nopl   0x0(%rax)
L18:
  mov    (%rdi,%rcx,1),%r8
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    (%rdi,%rax,1),%rdx
  movsd  (%r8,%rax,1),%xmm0
  add    %rcx,%rdx
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%r8,%rax,1)
  add    $0x8,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rcx
  jne    L30
  add    $0x1,%r9d
  add    $0x8,%rcx
  cmp    %r9d,%esi
  jne    L18
L4:
  ret
L14:
  ret
```

assistant: ```c
void transpose_psdmatrix(double **m, int dim) {
  double temp;
  int row, col;
  for (row = 0; row < dim; row++) {
    for (col = 0; col < row; col++) {
      temp = m[row][col];
      m[row][col] = m[col][row];
      m[col][row] = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transpose_psdmatrix>:
  endbr64
  mov    $0x8,%ecx
  mov    $0x1,%r9d
  cmp    $0x1,%esi
  jle    L6
  nopl   0x0(%rax)
L26:
  mov    (%rdi,%rcx,1),%r8
  xor    %eax,%eax
  xchg   %ax,%ax
L9:
  mov    (%rdi,%rax,1),%rdx
  movsd  (%r8,%rax,1),%xmm0
  add    %rcx,%rdx
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%r8,%rax,1)
  add    $0x8,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rcx,%rax
  jne    L9
  add    $0x1,%r9d
  add    $0x8,%rcx
  cmp    %r9d,%esi
  jne    L26
  ret
L6:
  ret
```

assistant: ```c
void transpose_psdmatrix(double **m, int dim) {
  double temp;
  int row, col;
  for (row = 0; row < dim; row++) {
    for (col = 0; col < row; col++) {
      temp = m[row][col];
      m[row][col] = m[col][row];
      m[col][row] = temp;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<writecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  andl   $0xffff,-0x14(%rbp)
  movl   $0x3,-0x4(%rbp)
  jmp    L42
L3:
  movb   $0xff,-0x5(%rbp)
  jmp    L54
L4:
  mov    -0x14(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L43
  mov    $0x0,%eax
  call   <lp@plt>
  jmp    L1
L43:
  mov    $0x0,%eax
  call   <sp@plt>
L1:
  shll   -0x14(%rbp)
  movzbl -0x5(%rbp),%eax
  shr    %al
  mov    %al,-0x5(%rbp)
L54:
  cmpb   $0x0,-0x5(%rbp)
  jne    L4
  mov    $0x0,%eax
  call   <lp@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L42:
  cmpl   $0x0,-0x4(%rbp)
  jne    L3
  mov    $0x0,%eax
  call   <lp@plt>
  nop
  leave
  ret
```

assistant: ```c
void writecs(unsigned int cs) {
  unsigned char i = 0;
  int j = 0;
  cs &= 0xffff;
  for (j = 0x3; j; j /= 2) {
    for (i = 0xff; i; i /= 2) {
      if (cs & 0x8000)
        lp();
      else
        sp();
      cs *= 2;
    }
    lp();
  }
  lp();
}
```
user: What is the c source code of the assembly code below?

```asm
<writecs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzwl %di,%ebx
  mov    $0x2,%r12d
  jmp    L5
L8:
  mov    $0x0,%eax
  call   <sp@plt>
L22:
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L59
L58:
  test   $0x80,%bh
  je     L8
  mov    $0x0,%eax
  call   <lp@plt>
  jmp    L22
L59:
  mov    $0x0,%eax
  call   <lp@plt>
  sub    $0x1,%r12d
  je     L1
L5:
  mov    $0x8,%ebp
  jmp    L58
L1:
  mov    $0x0,%eax
  call   <lp@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void writecs(unsigned int cs) {
  unsigned char i = 0;
  int j = 0;
  cs &= 0xffff;
  for (j = 0x3; j; j /= 2) {
    for (i = 0xff; i; i /= 2) {
      if (cs & 0x8000)
        lp();
      else
        sp();
      cs *= 2;
    }
    lp();
  }
  lp();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<writecs>:
  endbr64
  push   %r12
  mov    $0x2,%r12d
  push   %rbp
  push   %rbx
  movzwl %di,%ebx
L59:
  mov    $0x8,%ebp
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L5:
  call   <lp@plt>
  add    %ebx,%ebx
  sub    $0x1,%ebp
  je     L38
L16:
  xor    %eax,%eax
  test   $0x80,%bh
  jne    L5
  call   <sp@plt>
  add    %ebx,%ebx
  sub    $0x1,%ebp
  jne    L16
L38:
  xor    %eax,%eax
  call   <lp@plt>
  cmp    $0x1,%r12d
  je     L40
  mov    $0x1,%r12d
  jmp    L59
  nopl   0x0(%rax)
L40:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1060 <lp@plt>
```

assistant: ```c
void writecs(unsigned int cs) {
  unsigned char i = 0;
  int j = 0;
  cs &= 0xffff;
  for (j = 0x3; j; j /= 2) {
    for (i = 0xff; i; i /= 2) {
      if (cs & 0x8000)
        lp();
      else
        sp();
      cs *= 2;
    }
    lp();
  }
  lp();
}
```