ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<Glob_Star>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  lea    0x38(%rsp),%r12
  lea    0x30(%rsp),%r13
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm2,%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  %xmm1,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x30(%rsp),%xmm2
  movsd  0x38(%rsp),%xmm9
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm9,0x18(%rsp)
  call   <sincos@plt>
  movsd  0x28(%rsp),%xmm3
  mov    %r13,%rsi
  mov    %r12,%rdi
  movsd  0x30(%rsp),%xmm4
  movsd  0x38(%rsp),%xmm5
  movapd %xmm3,%xmm0
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm5,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm2
  movsd  0x30(%rsp),%xmm1
  movsd  0x38(%rsp),%xmm6
  movapd %xmm5,%xmm10
  movsd  0x18(%rsp),%xmm9
  movsd  0x10(%rsp),%xmm4
  mulsd  %xmm2,%xmm10
  movapd %xmm1,%xmm11
  movq   D6(%rip),%xmm0
  mulsd  %xmm9,%xmm11
  movapd %xmm9,%xmm8
  mulsd  %xmm6,%xmm9
  xorpd  %xmm0,%xmm8
  xorpd  %xmm4,%xmm0
  mulsd  %xmm6,%xmm0
  movapd %xmm8,%xmm7
  mulsd  %xmm5,%xmm7
  mulsd  %xmm4,%xmm8
  movapd %xmm10,%xmm3
  mulsd  %xmm6,%xmm3
  mulsd  %xmm1,%xmm10
  addsd  %xmm11,%xmm3
  mulsd  0x8(%rbx),%xmm3
  movapd %xmm4,%xmm11
  mulsd  %xmm2,%xmm11
  subsd  %xmm10,%xmm9
  mulsd  (%rbx),%xmm11
  mulsd  0x10(%rbx),%xmm9
  addsd  %xmm11,%xmm3
  addsd  %xmm9,%xmm3
  movapd %xmm1,%xmm9
  mulsd  %xmm2,%xmm9
  mulsd  %xmm6,%xmm2
  movsd  %xmm3,0x0(%rbp)
  mulsd  (%rbx),%xmm8
  movapd %xmm7,%xmm3
  mulsd  %xmm6,%xmm3
  mulsd  %xmm1,%xmm7
  mulsd  %xmm4,%xmm1
  addsd  %xmm9,%xmm3
  mulsd  0x8(%rbx),%xmm3
  subsd  %xmm7,%xmm2
  mulsd  0x10(%rbx),%xmm2
  addsd  %xmm8,%xmm3
  addsd  %xmm2,%xmm3
  movsd  %xmm3,0x8(%rbp)
  mulsd  0x8(%rbx),%xmm0
  mulsd  (%rbx),%xmm5
  mulsd  0x10(%rbx),%xmm1
  addsd  %xmm5,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rbp)
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void Glob_Star(const double x[3], const double nu, const double eps, const double psi, double xsi[3]) {
  double cnu = cos(nu), snu = sin(nu);
  double ceps = cos(eps), seps = sin(eps);
  double cpsi = cos(psi), spsi = sin(psi);
  double rot[3][3];
  rot[0][0] = cpsi * ceps;
  rot[0][1] = cpsi * seps * snu + spsi * cnu;
  rot[0][2] = -cpsi * seps * cnu + spsi * snu;
  rot[1][0] = -spsi * ceps;
  rot[1][1] = -spsi * seps * snu + cpsi * cnu;
  rot[1][2] = spsi * seps * cnu + cpsi * snu;
  rot[2][0] = seps;
  rot[2][1] = -ceps * snu;
  rot[2][2] = ceps * cnu;
  xsi[0] = x[0] * rot[0][0] + x[1] * rot[0][1] + x[2] * rot[0][2];
  xsi[1] = x[0] * rot[1][0] + x[1] * rot[1][1] + x[2] * rot[1][2];
  xsi[2] = x[0] * rot[2][0] + x[1] * rot[2][1] + x[2] * rot[2][2];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_win>:
  endbr64
  mov    %esi,%edx
  lea    0x18(%rdi),%r10
  mov    %rdi,%r8
  jmp    L70
L41:
  add    $0x8,%r8
  cmp    %r10,%r8
  je     L27
L70:
  mov    (%r8),%rax
  lea    0xc(%rax),%r9
  mov    $0x0,%ecx
L112:
  cmp    %edx,(%rax)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  cmp    $0x3,%ecx
  je     L63
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L112
  jmp    L41
L74:
  add    $0x4,%rsi
  cmp    $0xc,%rsi
  je     L4
L88:
  mov    %rdi,%rax
  mov    $0x0,%ecx
L90:
  mov    (%rax),%r8
  cmp    %edx,(%r8,%rsi,1)
  sete   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%ecx
  cmp    $0x3,%ecx
  je     L92
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L90
  jmp    L74
L27:
  mov    $0x0,%esi
  jmp    L88
L4:
  mov    $0x0,%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
L103:
  mov    (%rdi,%rax,2),%r8
  cmp    %edx,(%r8,%rax,1)
  sete   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%ecx
  cmp    $0x3,%ecx
  je     L94
  add    $0x1,%esi
  add    $0x4,%rax
  cmp    $0x2,%esi
  jle    L103
  mov    $0x0,%r8d
  mov    $0x1,%eax
  mov    $0x0,%esi
  mov    $0x2,%r10d
L120:
  mov    0x8(%rdi,%rax,8),%rcx
  cmp    %edx,(%rcx,%r8,1)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%esi
  cmp    $0x3,%esi
  je     L132
  mov    %r10d,%ecx
  sub    %eax,%ecx
  cmp    $0x2,%ecx
  setle  %r9b
  mov    %eax,%ecx
  not    %ecx
  shr    $0x1f,%ecx
  sub    $0x1,%rax
  add    $0x4,%r8
  test   %cl,%r9b
  jne    L120
  mov    $0x0,%eax
  ret
L63:
  mov    $0x1,%eax
  ret
L92:
  mov    $0x1,%eax
  ret
L94:
  mov    $0x1,%eax
  ret
L132:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_win(int **board, int turn) {
  int i, j, k, free = 0, flag_turn = 0;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (i = 0, j = 0; (i < 3 && j < 3); i++, j++) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  flag_turn = 0;
  for (i = 2, j = 0; (i >= 0 && j < 3); i = i - 1, j = j + 1) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_win>:
  endbr64
  mov    %esi,%ecx
  lea    0x18(%rdi),%r10
  mov    %rdi,%r8
L99:
  mov    (%r8),%rax
  xor    %edx,%edx
  lea    0xc(%rax),%r9
L69:
  xor    %esi,%esi
  cmp    %ecx,(%rax)
  sete   %sil
  add    %esi,%edx
  cmp    $0x3,%edx
  je     L28
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L69
  add    $0x8,%r8
  cmp    %r10,%r8
  jne    L99
  xor    %esi,%esi
L71:
  mov    %rdi,%rax
  xor    %edx,%edx
L87:
  mov    (%rax),%r8
  cmp    %ecx,(%r8,%rsi,1)
  sete   %r8b
  movzbl %r8b,%r8d
  add    %r8d,%edx
  cmp    $0x3,%edx
  je     L28
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L87
  add    $0x4,%rsi
  cmp    $0xc,%rsi
  jne    L71
  xor    %eax,%eax
  xor    %edx,%edx
L90:
  mov    (%rdi,%rax,2),%rsi
  cmp    %ecx,(%rsi,%rax,1)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%edx
  cmp    $0x3,%edx
  je     L28
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L90
  mov    $0x1,%eax
  xor    %r8d,%r8d
  mov    $0x2,%r9d
  jmp    L88
L102:
  mov    %r9d,%edx
  sub    %eax,%edx
  cmp    $0x2,%edx
  mov    %eax,%edx
  not    %edx
  setle  %sil
  sub    $0x1,%rax
  shr    $0x1f,%edx
  test   %dl,%sil
  je     L107
L88:
  mov    %rax,%rsi
  mov    0x8(%rdi,%rax,8),%rdx
  neg    %rsi
  cmp    %ecx,0x4(%rdx,%rsi,4)
  jne    L7
  add    $0x1,%r8d
L7:
  cmp    $0x3,%r8d
  jne    L102
L28:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L107:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_win(int **board, int turn) {
  int i, j, k, free = 0, flag_turn = 0;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (i = 0, j = 0; (i < 3 && j < 3); i++, j++) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  flag_turn = 0;
  for (i = 2, j = 0; (i >= 0 && j < 3); i = i - 1, j = j + 1) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_win>:
  endbr64
  push   %rbp
  push   %rbx
  mov    (%rdi),%rax
  mov    (%rax),%ecx
  mov    0x4(%rax),%ebx
  cmp    %ecx,%esi
  je     L27
L55:
  mov    0x8(%rdi),%rdx
  mov    (%rdx),%r11d
  mov    0x4(%rdx),%r9d
  cmp    %r11d,%esi
  je     L45
L208:
  mov    0x10(%rdi),%rdi
  mov    (%rdi),%r10d
  mov    0x4(%rdi),%ebp
  cmp    %r10d,%esi
  je     L211
L200:
  cmp    %ecx,%esi
  je     L66
L329:
  cmp    %ebx,%esi
  je     L121
L261:
  mov    0x8(%rax),%eax
  mov    0x8(%rdx),%edx
  cmp    %eax,%esi
  je     L308
L185:
  cmp    %ecx,%esi
  je     L134
  xor    %r8d,%r8d
  cmp    %r9d,%esi
  je     L77
L206:
  cmp    %r10d,%esi
  je     L189
  xor    %r8d,%r8d
  cmp    %r9d,%esi
  je     L28
L69:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  cmp    %r11d,%esi
  jne    L329
  mov    $0x1,%r8d
  cmp    %esi,%r10d
  jne    L329
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L121:
  cmp    %r9d,%esi
  jne    L261
  mov    $0x1,%r8d
  cmp    %esi,%ebp
  jne    L261
  jmp    L69
  nopl   0x0(%rax)
L27:
  cmp    %ebx,%esi
  jne    L55
  mov    $0x1,%r8d
  cmp    %esi,0x8(%rax)
  jne    L55
  jmp    L69
  nopl   0x0(%rax)
L45:
  cmp    %r9d,%esi
  jne    L208
  mov    $0x1,%r8d
  cmp    %esi,0x8(%rdx)
  jne    L208
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L211:
  cmp    %esi,%ebp
  jne    L200
  mov    $0x1,%r8d
  cmp    0x8(%rdi),%esi
  jne    L200
  jmp    L69
  nopl   0x0(%rax)
L308:
  cmp    %edx,%esi
  jne    L185
  mov    $0x1,%r8d
  cmp    0x8(%rdi),%esi
  jne    L185
  jmp    L69
  nopl   0x0(%rax)
L134:
  cmp    %r9d,%esi
  jne    L206
  mov    $0x1,%r8d
L77:
  cmp    %esi,0x8(%rdi)
  jne    L206
  cmp    $0x1,%r8d
  je     L69
  jmp    L206
  nop
L189:
  xor    %r8d,%r8d
  cmp    %r9d,%esi
  jne    L69
  mov    $0x1,%r8d
L28:
  cmp    %eax,%esi
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_win(int **board, int turn) {
  int i, j, k, free = 0, flag_turn = 0;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (board[i][j] == turn)
        flag_turn += 1;
      if (flag_turn == 3)
        return 1;
    }
    flag_turn = 0;
  }
  for (i = 0, j = 0; (i < 3 && j < 3); i++, j++) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  flag_turn = 0;
  for (i = 2, j = 0; (i >= 0 && j < 3); i = i - 1, j = j + 1) {
    if (board[i][j] == turn) {
      flag_turn += 1;
    }
    if (flag_turn == 3) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<extreme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L30
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L28
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L23
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L23:
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x2c(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,D11(%rip)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,D19(%rip)
  lea    D11(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
double *extreme(double *x, int n) {
  int i;
  static double y[2];
  double min, max, sum1 = 0.;
  min = max = x[0];
  for (i = 0; i < n; ++i) {
    sum1 += x[i];
    if (min > x[i])
      min = x[i];
    if (max < x[i])
      max = x[i];
  }
  sum1 /= n;
  y[0] = max - sum1;
  y[1] = min - sum1;
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<extreme>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm3
  test   %esi,%esi
  jle    L0
  pxor   %xmm2,%xmm2
  add    $0x8,%rdi
  lea    -0x1(%rsi),%eax
  addsd  %xmm0,%xmm2
  lea    (%rdi,%rax,8),%rax
  jmp    L28
  nopl   (%rax)
L3:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm2
  minsd  %xmm3,%xmm4
  movapd %xmm4,%xmm3
L28:
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L3
L0:
  pxor   %xmm0,%xmm0
  lea    D14(%rip),%rax
  cvtsi2sd %esi,%xmm0
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  subsd  %xmm2,%xmm3
  movsd  %xmm1,D12(%rip)
  movsd  %xmm3,D12(%rip)
  ret
```

assistant: ```c
double *extreme(double *x, int n) {
  int i;
  static double y[2];
  double min, max, sum1 = 0.;
  min = max = x[0];
  for (i = 0; i < n; ++i) {
    sum1 += x[i];
    if (min > x[i])
      min = x[i];
    if (max < x[i])
      max = x[i];
  }
  sum1 /= n;
  y[0] = max - sum1;
  y[1] = min - sum1;
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<extreme>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm2,%xmm2
  movapd %xmm0,%xmm1
  unpcklpd %xmm1,%xmm1
  test   %esi,%esi
  jle    L21
  pxor   %xmm2,%xmm2
  lea    -0x1(%rsi),%eax
  movapd %xmm0,%xmm1
  add    $0x8,%rdi
  addsd  %xmm0,%xmm2
  lea    (%rdi,%rax,8),%rax
  movapd %xmm0,%xmm3
  jmp    L15
  nopl   (%rax)
L16:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm2
  minsd  %xmm3,%xmm4
  movapd %xmm4,%xmm3
L15:
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmp    %rax,%rdi
  jne    L16
  unpcklpd %xmm3,%xmm1
L21:
  pxor   %xmm0,%xmm0
  lea    D9(%rip),%rax
  cvtsi2sd %esi,%xmm0
  divsd  %xmm0,%xmm2
  unpcklpd %xmm2,%xmm2
  subpd  %xmm2,%xmm1
  movaps %xmm1,D13(%rip)
  ret
```

assistant: ```c
double *extreme(double *x, int n) {
  int i;
  static double y[2];
  double min, max, sum1 = 0.;
  min = max = x[0];
  for (i = 0; i < n; ++i) {
    sum1 += x[i];
    if (min > x[i])
      min = x[i];
    if (max < x[i])
      max = x[i];
  }
  sum1 /= n;
  y[0] = max - sum1;
  y[1] = min - sum1;
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rabin_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <rabin_rolling_checksum@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int rabin_checksum(char *buf, int len) {
  int i;
  unsigned int sum = 0;
  for (i = 0; i < len; ++i) {
    sum = rabin_rolling_checksum(sum, len, 0, buf[i]);
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rabin_checksum>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0x0,%edi
L19:
  movsbl (%rbx),%ecx
  mov    $0x0,%edx
  mov    %ebp,%esi
  call   <rabin_rolling_checksum@plt>
  mov    %eax,%edi
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0x0,%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned int rabin_checksum(char *buf, int len) {
  int i;
  unsigned int sum = 0;
  for (i = 0; i < len; ++i) {
    sum = rabin_rolling_checksum(sum, len, 0, buf[i]);
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rabin_checksum>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%ecx
  xor    %edx,%edx
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <rabin_rolling_checksum@plt>
  mov    %eax,%edi
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rabin_checksum(char *buf, int len) {
  int i;
  unsigned int sum = 0;
  for (i = 0; i < len; ++i) {
    sum = rabin_rolling_checksum(sum, len, 0, buf[i]);
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rabin_checksum>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%ecx
  xor    %edx,%edx
  mov    %ebp,%esi
  add    $0x1,%rbx
  call   <rabin_rolling_checksum@plt>
  mov    %eax,%edi
  cmp    %r12,%rbx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int rabin_checksum(char *buf, int len) {
  int i;
  unsigned int sum = 0;
  for (i = 0; i < len; ++i) {
    sum = rabin_rolling_checksum(sum, len, 0, buf[i]);
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<permutation_get_factoral>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L17:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x14(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int permutation_get_factoral(int N) {
  unsigned int factoral = 1;
  while (N)
    factoral *= N--;
  return factoral;
}
```
user: What is the c source code of the assembly code below:

```asm
<permutation_get_factoral>:
  endbr64
  test   %edi,%edi
  je     L6
  mov    $0x1,%eax
L13:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L13
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int permutation_get_factoral(int N) {
  unsigned int factoral = 1;
  while (N)
    factoral *= N--;
  return factoral;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permutation_get_factoral>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L6
  nopl   (%rax)
L13:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L13
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
unsigned int permutation_get_factoral(int N) {
  unsigned int factoral = 1;
  while (N)
    factoral *= N--;
  return factoral;
}
```
user: Translate the below assembly code into C programming language:

```asm
<permutation_get_factoral>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L1
  nopl   (%rax)
L0:
  imul   %edi,%eax
  sub    $0x1,%edi
  jne    L0
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
unsigned int permutation_get_factoral(int N) {
  unsigned int factoral = 1;
  while (N)
    factoral *= N--;
  return factoral;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L12:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L12
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double _mul(double *a, double *b, unsigned int length) {
  double ret = 0;
  for (unsigned int i = 0; i < length; i++)
    ret += a[i] * b[i];
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mul>:
  endbr64
  test   %edx,%edx
  je     L29
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L16:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
L24:
  movapd %xmm1,%xmm0
  ret
L29:
  pxor   %xmm1,%xmm1
  jmp    L24
```

assistant: ```c
double _mul(double *a, double *b, unsigned int length) {
  double ret = 0;
  for (unsigned int i = 0; i < length; i++)
    ret += a[i] * b[i];
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_mul>:
  endbr64
  test   %edx,%edx
  je     L13
  mov    %edx,%edx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
L12:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L12
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L13:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double _mul(double *a, double *b, unsigned int length) {
  double ret = 0;
  for (unsigned int i = 0; i < length; i++)
    ret += a[i] * b[i];
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_mul>:
  endbr64
  test   %edx,%edx
  je     L28
  cmp    $0x1,%edx
  je     L7
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L9:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L9
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L18
L49:
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L18:
  ret
  nopl   0x0(%rax)
L28:
  pxor   %xmm0,%xmm0
  ret
L7:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L49
```

assistant: ```c
double _mul(double *a, double *b, unsigned int length) {
  double ret = 0;
  for (unsigned int i = 0; i < length; i++)
    ret += a[i] * b[i];
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1,-0x8(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <getint@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L8
  movl   $0x1,-0x10(%rbp)
  jmp    L29
L10:
  mov    -0x10(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L8:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L9:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D26
type_infered: string
name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string

tool: D26: Introducir un numero positivo: 

tool: D14: Su factorial es: %lu


tool: D12: Valor invalido.

assistant: ```c
int main(void) {
  int numero, i;
  unsigned long int factorial = 1;
  numero = getint("Introducir un numero positivo: ");
  if (numero >= 0) {
    for (i = 1; i <= numero; i++) {
      factorial *= i;
    }
    printf("Su factorial es: %lu\n", factorial);
  } else {
    printf("Valor invalido.\n");
  }
}
```