ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun2>:
  endbr64
  push   %r15
  lea    D73(%rip),%r15
  push   %r14
  lea    D79(%rip),%r14
  push   %r13
  lea    D66(%rip),%r13
  push   %r12
  lea    D64(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  lea    D48(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L11:
  test   %eax,%eax
  je     L23
  lea    D86(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L18
L34:
  mov    %r15,%rdi
  movl   $0xffffffff,0x14(%rsp)
  call   <system@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x1,%eax
  je     L68
  cmp    $0x2,%eax
  jne    L11
  xor    %eax,%eax
  call   <fun4@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jne    L34
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L23:
  call   <main@plt>
L68:
  xor    %eax,%eax
  call   <fun3@plt>
  jmp    L41
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D73
type: string
name: retrieve_data
arguments: data_tag: D79
type: string
name: retrieve_data
arguments: data_tag: D66
type: string
name: retrieve_data
arguments: data_tag: D64
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D48
type: string
name: retrieve_data
arguments: data_tag: D86
type: string
name: retrieve_data
arguments: data_tag: D65
type: string
name: retrieve_data
arguments: data_tag: D21
type: string

tool: D73: cls

tool: D79: Sub Menu


tool: D66: =========


tool: D64: 0-Exit to Main Menu


tool: D10: 1-Addition


tool: D48: 2-Subtraction


tool: D86: Error! you must choose (0 or 1 or 2)!


tool: D65: Choose your answer (0,1,2):  

tool: D21: %d

assistant: ```c
void fun2() {
  int ans1 = -1;
  do {
    ans1 = -1;
    system("cls");
    printf("Sub Menu\n");
    printf("=========\n");
    printf("0-Exit to Main Menu\n");
    printf("1-Addition\n");
    printf("2-Subtraction\n");
    printf("Choose your answer (0,1,2):  ");
    scanf("%d", &ans1);
    switch (ans1) {
    case 0:
      main();
    case 1:
      fun3();
      break;
    case 2:
      fun4();
      break;
    default:
      printf("Error! you must choose (0 or 1 or 2)!\n");
    }
  } while (ans1 != 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FDC_GetNopsToNextIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <FDD_CalculatePositionInTrack@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x1a00,%eax
  sub    -0x8(%rbp),%rax
  shl    $0x5,%rax
  leave
  ret
```

assistant: ```c
unsigned long FDC_GetNopsToNextIndex(void) {
  unsigned long PositionInTrack;
  PositionInTrack = FDD_CalculatePositionInTrack();
  return ((6656 - PositionInTrack) << 5);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<FDC_GetNopsToNextIndex>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <FDD_CalculatePositionInTrack@plt>
  mov    %rax,%rdx
  mov    $0x1a00,%eax
  sub    %rdx,%rax
  shl    $0x5,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long FDC_GetNopsToNextIndex(void) {
  unsigned long PositionInTrack;
  PositionInTrack = FDD_CalculatePositionInTrack();
  return ((6656 - PositionInTrack) << 5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<FDC_GetNopsToNextIndex>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <FDD_CalculatePositionInTrack@plt>
  add    $0x8,%rsp
  mov    %rax,%r8
  mov    $0x1a00,%eax
  sub    %r8,%rax
  shl    $0x5,%rax
  ret
```

assistant: ```c
unsigned long FDC_GetNopsToNextIndex(void) {
  unsigned long PositionInTrack;
  PositionInTrack = FDD_CalculatePositionInTrack();
  return ((6656 - PositionInTrack) << 5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FDC_GetNopsToNextIndex>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <FDD_CalculatePositionInTrack@plt>
  add    $0x8,%rsp
  mov    %rax,%r8
  mov    $0x1a00,%eax
  sub    %r8,%rax
  shl    $0x5,%rax
  ret
```

assistant: ```c
unsigned long FDC_GetNopsToNextIndex(void) {
  unsigned long PositionInTrack;
  PositionInTrack = FDD_CalculatePositionInTrack();
  return ((6656 - PositionInTrack) << 5);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ll2string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x60(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L29
L33:
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdx
  neg    %rdx
  cmovns %rdx,%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x1f,%rax
  mov    %rax,-0x48(%rbp)
L13:
  mov    -0x40(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x48(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x40(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L13
  cmpq   $0x0,-0x68(%rbp)
  jns    L51
  mov    -0x48(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  movb   $0x2d,(%rax)
L51:
  addq   $0x1,-0x48(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    $0x20,%eax
  sub    %rcx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x60(%rbp)
  jae    L56
  mov    -0x60(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
L56:
  mov    -0x38(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x58(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int ll2string(char *s, size_t len, long long value) {
  char buf[32], *p;
  unsigned long long v;
  size_t l;
  if (len == 0) {
    return 0;
  }
  v = (value < 0) ? -value : value;
  p = buf + 31;
  do {
    *p-- = '0' + (v % 10);
    v /= 10;
  } while (v);
  if (value < 0) {
    *p-- = '-';
  }
  p++;
  l = 32 - (p - buf);
  if (l + 1 > len) {
    l = len - 1;
  }
  memcpy(s, p, l);
  s[l] = '\0';
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ll2string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L21
  mov    %rdi,%rbx
  mov    %rsi,%r10
  mov    %rdx,%r11
  mov    %rdx,%rcx
  neg    %rcx
  cmovs  %rdx,%rcx
  lea    0x1f(%rsp),%rsi
  movabs $0xcccccccccccccccd,%r8
L40:
  mov    %rsi,%r9
  sub    $0x1,%rsi
  mov    %rcx,%rax
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rdi
  add    %rdi,%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  add    $0x30,%eax
  mov    %al,0x1(%rsi)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  ja     L40
  test   %r11,%r11
  js     L5
L26:
  add    $0x1,%rsi
  mov    %rsp,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  mov    $0x21,%ecx
  sub    %rax,%rcx
  mov    $0x20,%edx
  sub    %rax,%rdx
  lea    -0x1(%r10),%rax
  cmp    %r10,%rcx
  cmova  %rax,%rdx
  mov    %rdx,%rbp
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %ebp,%eax
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  movb   $0x2d,(%rsi)
  lea    -0x2(%r9),%rsi
  jmp    L26
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ll2string(char *s, size_t len, long long value) {
  char buf[32], *p;
  unsigned long long v;
  size_t l;
  if (len == 0) {
    return 0;
  }
  v = (value < 0) ? -value : value;
  p = buf + 31;
  do {
    *p-- = '0' + (v % 10);
    v /= 10;
  } while (v);
  if (value < 0) {
    *p-- = '-';
  }
  p++;
  l = 32 - (p - buf);
  if (l + 1 > len) {
    l = len - 1;
  }
  memcpy(s, p, l);
  s[l] = '\0';
  return l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ll2string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L43
  mov    %rdx,%rcx
  mov    %rdi,%rbx
  mov    %rsi,%r11
  mov    %rdx,%r10
  neg    %rcx
  lea    0x1f(%rsp),%rdi
  movabs $0xcccccccccccccccd,%r9
  cmovs  %rdx,%rcx
  nopl   (%rax)
L1:
  mov    %rcx,%rax
  mov    %rdi,%r8
  mul    %r9
  mov    %rcx,%rax
  lea    -0x1(%rdi),%rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,0x1(%rdi)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  ja     L1
  test   %r10,%r10
  js     L2
L10:
  mov    %rsp,%rdx
  mov    %r8,%rax
  mov    $0x21,%ecx
  mov    %r8,%rsi
  sub    %rdx,%rax
  mov    $0x20,%edx
  mov    %rbx,%rdi
  sub    %rax,%rcx
  sub    %rax,%rdx
  lea    -0x1(%r11),%rax
  cmp    %r11,%rcx
  cmova  %rax,%rdx
  mov    %rdx,%rbp
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %ebp,%eax
L43:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  movb   $0x2d,(%rdi)
  mov    %rdi,%r8
  jmp    L10
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ll2string(char *s, size_t len, long long value) {
  char buf[32], *p;
  unsigned long long v;
  size_t l;
  if (len == 0) {
    return 0;
  }
  v = (value < 0) ? -value : value;
  p = buf + 31;
  do {
    *p-- = '0' + (v % 10);
    v /= 10;
  } while (v);
  if (value < 0) {
    *p-- = '-';
  }
  p++;
  l = 32 - (p - buf);
  if (l + 1 > len) {
    l = len - 1;
  }
  memcpy(s, p, l);
  s[l] = '\0';
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ll2string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L5
  mov    %rdx,%rcx
  mov    %rdi,%rbx
  mov    %rsi,%r11
  mov    %rdx,%r10
  neg    %rcx
  lea    0x1f(%rsp),%rdi
  movabs $0xcccccccccccccccd,%r9
  cmovs  %rdx,%rcx
  nopl   (%rax)
L22:
  mov    %rcx,%rax
  mov    %rdi,%r8
  mul    %r9
  mov    %rcx,%rax
  lea    -0x1(%rdi),%rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  add    $0x30,%eax
  mov    %al,0x1(%rdi)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  cmp    $0x9,%rax
  ja     L22
  test   %r10,%r10
  js     L32
L16:
  mov    %rsp,%rdx
  mov    %r8,%rax
  mov    $0x21,%ecx
  mov    %r8,%rsi
  sub    %rdx,%rax
  mov    $0x20,%edx
  mov    %rbx,%rdi
  sub    %rax,%rcx
  sub    %rax,%rdx
  lea    -0x1(%r11),%rax
  cmp    %r11,%rcx
  cmova  %rax,%rdx
  mov    %rdx,%rbp
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %ebp,%eax
L5:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L32:
  movb   $0x2d,(%rdi)
  mov    %rdi,%r8
  jmp    L16
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ll2string(char *s, size_t len, long long value) {
  char buf[32], *p;
  unsigned long long v;
  size_t l;
  if (len == 0) {
    return 0;
  }
  v = (value < 0) ? -value : value;
  p = buf + 31;
  do {
    *p-- = '0' + (v % 10);
    v /= 10;
  } while (v);
  if (value < 0) {
    *p-- = '-';
  }
  p++;
  l = 32 - (p - buf);
  if (l + 1 > len) {
    l = len - 1;
  }
  memcpy(s, p, l);
  s[l] = '\0';
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ucs4_to_utf8_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L66
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x7f,%eax
  jg     L39
  addq   $0x1,-0x8(%rbp)
  jmp    L52
L39:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x7ff,%eax
  jg     L58
  addq   $0x2,-0x8(%rbp)
  jmp    L52
L58:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xffff,%eax
  jg     L51
  addq   $0x3,-0x8(%rbp)
  jmp    L52
L51:
  addq   $0x4,-0x8(%rbp)
L52:
  addq   $0x4,-0x18(%rbp)
L66:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t ucs4_to_utf8_size(const int *in) {
  size_t out_size = 1;
  while (*in) {
    if (*in <= 0x7f) {
      out_size++;
    } else if (*in <= 0x7ff) {
      out_size += 2;
    } else if (*in <= 0xffff) {
      out_size += 3;
    } else {
      out_size += 4;
    }
    ++in;
  }
  return out_size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ucs4_to_utf8_size>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L47
  mov    $0x1,%edx
  jmp    L57
L29:
  cmp    $0x7ff,%eax
  jg     L43
  add    $0x2,%rdx
L28:
  add    $0x4,%rdi
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L62
L57:
  cmp    $0x7f,%eax
  jg     L29
  add    $0x1,%rdx
  jmp    L28
L43:
  mov    %rdx,%rcx
  cmp    $0xffff,%eax
  setg   %dl
  movzbl %dl,%edx
  lea    0x3(%rdx,%rcx,1),%rdx
  jmp    L28
L47:
  mov    $0x1,%edx
L62:
  mov    %rdx,%rax
  ret
```

assistant: ```c
size_t ucs4_to_utf8_size(const int *in) {
  size_t out_size = 1;
  while (*in) {
    if (*in <= 0x7f) {
      out_size++;
    } else if (*in <= 0x7ff) {
      out_size += 2;
    } else if (*in <= 0xffff) {
      out_size += 3;
    } else {
      out_size += 4;
    }
    ++in;
  }
  return out_size;
}
```
user: What is the c source code of the assembly code below:

```asm
<ucs4_to_utf8_size>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L49
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L47:
  add    $0x1,%r8
L38:
  mov    0x4(%rdi),%eax
  add    $0x4,%rdi
  test   %eax,%eax
  je     L14
L49:
  cmp    $0x7f,%eax
  jle    L47
  cmp    $0x7ff,%eax
  jg     L50
  mov    0x4(%rdi),%eax
  add    $0x4,%rdi
  add    $0x2,%r8
  test   %eax,%eax
  jne    L49
L14:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L50:
  mov    %r8,%rdx
  xor    %r8d,%r8d
  cmp    $0xffff,%eax
  setg   %r8b
  lea    0x3(%r8,%rdx,1),%r8
  jmp    L38
```

assistant: ```c
size_t ucs4_to_utf8_size(const int *in) {
  size_t out_size = 1;
  while (*in) {
    if (*in <= 0x7f) {
      out_size++;
    } else if (*in <= 0x7ff) {
      out_size += 2;
    } else if (*in <= 0xffff) {
      out_size += 3;
    } else {
      out_size += 4;
    }
    ++in;
  }
  return out_size;
}
```
user: What is the c source code of the assembly code below:

```asm
<ucs4_to_utf8_size>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x1,%r8d
  test   %eax,%eax
  jne    L48
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L51:
  add    $0x1,%r8
L68:
  mov    0x4(%rdi),%eax
  add    $0x4,%rdi
  test   %eax,%eax
  je     L11
L48:
  cmp    $0x7f,%eax
  jle    L51
  cmp    $0x7ff,%eax
  jg     L46
  mov    0x4(%rdi),%eax
  add    $0x4,%rdi
  add    $0x2,%r8
  test   %eax,%eax
  jne    L48
L11:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %r8,%rdx
  xor    %r8d,%r8d
  cmp    $0xffff,%eax
  setg   %r8b
  lea    0x3(%r8,%rdx,1),%r8
  jmp    L68
```

assistant: ```c
size_t ucs4_to_utf8_size(const int *in) {
  size_t out_size = 1;
  while (*in) {
    if (*in <= 0x7f) {
      out_size++;
    } else if (*in <= 0x7ff) {
      out_size += 2;
    } else if (*in <= 0xffff) {
      out_size += 3;
    } else {
      out_size += 4;
    }
    ++in;
  }
  return out_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L5
L23:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L7
  addl   $0x1,-0x14(%rbp)
  jmp    L6
L7:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jne    L30
  addl   $0x1,-0x10(%rbp)
  jmp    L6
L30:
  addl   $0x1,-0xc(%rbp)
L6:
  addl   $0x1,-0x18(%rbp)
L5:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L23
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D9: %d

tool: D12: %d


assistant: ```c
int main() {
  int n = 1, i = 0, number, div, r1, r2;
  div = r1 = r2 = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &number);
    if (number % 3 == 0)
      div++;
    else if (number % 3 == 1)
      r1++;
    else
      r2++;
  }
  printf("%d\n", div);
  printf("%d\n", r1);
  printf("%d\n", r2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L6
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
  jmp    L36
L75:
  cmp    $0x1,%eax
  je     L43
  add    $0x1,%r13d
L21:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jle    L16
L36:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jne    L75
  add    $0x1,%ebp
  jmp    L21
L43:
  add    $0x1,%r14d
  jmp    L21
L6:
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  mov    $0x0,%ebp
L16:
  mov    %ebp,%esi
  lea    D22(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D22
datatype: string

tool: D5: %d

tool: D22: %d


assistant: ```c
int main() {
  int n = 1, i = 0, number, div, r1, r2;
  div = r1 = r2 = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &number);
    if (number % 3 == 0)
      div++;
    else if (number % 3 == 1)
      r1++;
    else
      r2++;
  }
  printf("%d\n", div);
  printf("%d\n", r1);
  printf("%d\n", r2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x1,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L23
  xor    %r15d,%r15d
  lea    0x4(%rsp),%r12
  jmp    L71
  nopl   0x0(%rax)
L13:
  add    $0x1,%ebp
L4:
  add    $0x1,%r15d
  cmp    %r15d,(%rsp)
  jle    L23
L71:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x55555556,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  je     L13
  cmp    $0x1,%eax
  je     L31
  add    $0x1,%r13d
  add    $0x1,%r15d
  cmp    %r15d,(%rsp)
  jg     L71
L23:
  mov    %ebp,%esi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L31:
  add    $0x1,%r14d
  jmp    L4
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D3
type: string

tool: D4: %d

tool: D3: %d


assistant: ```c
int main() {
  int n = 1, i = 0, number, div, r1, r2;
  div = r1 = r2 = 0;
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    scanf("%d", &number);
    if (number % 3 == 0)
      div++;
    else if (number % 3 == 1)
      r1++;
    else
      r2++;
  }
  printf("%d\n", div);
  printf("%d\n", r1);
  printf("%d\n", r2);
  return 0;
}
```