user: 这段汇编代码用C语言表示是什么样的?

```asm
<symmetric>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%r10d
  test   %r10d,%r10d
  jle    L13
  lea    0x10(%rsp),%r12
  mov    %r12,%r15
  mov    $0x0,%r14d
  lea    D59(%rip),%r13
  jmp    L68
L41:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L41
L87:
  mov    0x8(%rsp),%r10d
  add    $0x1,%r14
  add    $0x28,%r15
  cmp    %r14d,%r10d
  jle    L124
L68:
  mov    %r15,%rbp
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L41
  jmp    L87
L124:
  test   %r10d,%r10d
  jle    L13
  mov    0xc(%rsp),%ebx
  lea    0x1a0(%rsp),%rdi
  lea    -0x1(%rbx),%eax
  lea    (%rax,%rax,4),%rax
  lea    0x1c8(%rsp,%rax,8),%rsi
  lea    -0x1(%r10),%r8d
  lea    0x1a4(%rsp,%r8,4),%rbp
  mov    %rdi,%r9
  mov    %r12,%r11
  jmp    L141
L172:
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rdx
  add    $0x28,%rax
  cmp    %rsi,%rax
  jne    L172
L46:
  add    $0x28,%r11
  add    $0x4,%r9
  add    $0x4,%rsi
  cmp    %rbp,%r9
  je     L49
L141:
  mov    %r9,%rax
  mov    %r11,%rdx
  test   %ebx,%ebx
  jg     L172
  jmp    L46
L90:
  mov    %rcx,%rax
L79:
  mov    %eax,%edx
  mov    (%rdi,%rax,4),%ebx
  cmp    %ebx,(%r12,%rax,4)
  jne    L40
  lea    0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    %r8,%rax
  jne    L90
L40:
  cmp    %edx,%r10d
  jne    L37
  add    $0x1,%esi
  add    $0x28,%r12
  add    $0x28,%rdi
  cmp    %esi,%r10d
  je     L198
L104:
  mov    %r9,%rax
  jmp    L79
L49:
  mov    $0x0,%esi
  mov    $0x0,%r9d
  cmp    %ebx,%r10d
  je     L104
L145:
  lea    D0(%rip),%rdi
  call   <printf@plt>
L69:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L179
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  cmp    %r10d,0xc(%rsp)
  jne    L145
  mov    $0x0,%esi
L37:
  cmp    %esi,%r10d
  jne    L69
L198:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L179:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D30
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D59
type: string
name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D50
type: string

tool: D5: Enter the number of rows and columns of matrix


tool: D30: %d%d

tool: D16: Enter the elements of matrix


tool: D59: %d

tool: D0: Not a symmetric matrix.


tool: D50: Symmetric matrix.


assistant: ```c
void symmetric() {
  int m, n, c, d, matrix[10][10], transpose[10][10];
  printf("Enter the number of rows and columns of matrix\n");
  scanf("%d%d", &m, &n);
  printf("Enter the elements of matrix\n");
  for (c = 0; c < m; c++)
    for (d = 0; d < n; d++)
      scanf("%d", &matrix[c][d]);
  for (c = 0; c < m; c++) {
    for (d = 0; d < n; d++) {
      transpose[d][c] = matrix[c][d];
    }
  }
  if (m == n) {
    for (c = 0; c < m; c++) {
      for (d = 0; d < m; d++) {
        if (matrix[c][d] != transpose[c][d])
          break;
      }
      if (d != m)
        break;
    }
    if (c == m)
      printf("Symmetric matrix.\n");
  } else
    printf("Not a symmetric matrix.\n");
}
```