ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x14,%edx
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D13: The old values: a = %d; b = %d.


tool: D6: The new values: a = %d; b = %d.


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("The old values: a = %d; b = %d.\n", a, b);
  swap(&a, &b);
  printf("The new values: a = %d; b = %d.\n", a, b);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x14,%edx
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  movl   $0xa,(%rsp)
  movl   $0x14,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <swap@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D1: The old values: a = %d; b = %d.


tool: D10: The new values: a = %d; b = %d.


assistant: ```c
int main() {
  int a = 10, b = 20;
  printf("The old values: a = %d; b = %d.\n", a, b);
  swap(&a, &b);
  printf("The new values: a = %d; b = %d.\n", a, b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AESReset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x84,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x84,%edx
  movslq %edx,%rdx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  nop
L0:
  mov    -0x4(%rbp),%eax
  add    $0x88,%eax
  cltq
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AESReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000084))) |= 0x00000002;
  while (((*((volatile uint32_t *)(ui32Base + 0x00000088))) & 0x00000001) == 0) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AESReset>:
  endbr64
  lea    0x84(%rdi),%eax
  cltq
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  add    $0x88,%edi
  movslq %edi,%rdx
L3:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L3
  ret
```

assistant: ```c
void AESReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000084))) |= 0x00000002;
  while (((*((volatile uint32_t *)(ui32Base + 0x00000088))) & 0x00000001) == 0) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AESReset>:
  endbr64
  lea    0x84(%rdi),%eax
  add    $0x88,%edi
  cltq
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  movslq %edi,%rdx
  nopl   0x0(%rax)
L2:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L2
  ret
```

assistant: ```c
void AESReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000084))) |= 0x00000002;
  while (((*((volatile uint32_t *)(ui32Base + 0x00000088))) & 0x00000001) == 0) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AESReset>:
  endbr64
  lea    0x84(%rdi),%eax
  add    $0x88,%edi
  cltq
  mov    (%rax),%edx
  or     $0x2,%edx
  mov    %edx,(%rax)
  movslq %edi,%rdx
  nopl   0x0(%rax)
L5:
  mov    (%rdx),%eax
  test   $0x1,%al
  je     L5
  ret
```

assistant: ```c
void AESReset(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000084))) |= 0x00000002;
  while (((*((volatile uint32_t *)(ui32Base + 0x00000088))) & 0x00000001) == 0) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ars_d_field_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%r8
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x18(%rbp),%rdi
  push   %rdi
  mov    %r8,%r9
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <ars_d_field_off@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L42
  mov    $0x0,%eax
  jmp    L7
L42:
  mov    -0x18(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L7
L6:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
char *ars_d_field_get(char *packet, char *layer, char *field, int skip) {
  int start, end, len;
  char *x;
  if (!ars_d_field_off(packet, layer, field, skip, NULL, &start, &end))
    return NULL;
  len = end - start + 1;
  if ((x = malloc(len + 1)) == NULL)
    return NULL;
  memcpy(x, packet + start, len);
  x[len] = '\0';
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ars_d_field_get>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  push   %rax
  lea    0x10(%rsp),%r9
  mov    $0x0,%r8d
  call   <ars_d_field_off@plt>
  add    $0x10,%rsp
  mov    $0x0,%ebx
  test   %eax,%eax
  je     L17
  mov    0x4(%rsp),%edi
  sub    (%rsp),%edi
  lea    0x1(%rdi),%r12d
  add    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
  movslq (%rsp),%rax
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  movb   $0x0,(%rbx,%r12,1)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ars_d_field_get(char *packet, char *layer, char *field, int skip) {
  int start, end, len;
  char *x;
  if (!ars_d_field_off(packet, layer, field, skip, NULL, &start, &end))
    return NULL;
  len = end - start + 1;
  if ((x = malloc(len + 1)) == NULL)
    return NULL;
  memcpy(x, packet + start, len);
  x[len] = '\0';
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<ars_d_field_get>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  push   %rax
  lea    0x10(%rsp),%r9
  call   <ars_d_field_off@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  je     L15
  mov    0x4(%rsp),%edi
  sub    (%rsp),%edi
  lea    0x1(%rdi),%ebp
  add    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  movslq (%rsp),%rax
  mov    %ebp,%edx
  mov    %r12,%rdi
  movslq %ebp,%rbp
  lea    (%rbx,%rax,1),%rsi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbp,1)
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ars_d_field_get(char *packet, char *layer, char *field, int skip) {
  int start, end, len;
  char *x;
  if (!ars_d_field_off(packet, layer, field, skip, NULL, &start, &end))
    return NULL;
  len = end - start + 1;
  if ((x = malloc(len + 1)) == NULL)
    return NULL;
  memcpy(x, packet + start, len);
  x[len] = '\0';
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ars_d_field_get>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x10(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rax
  push   %rax
  lea    0x10(%rsp),%r9
  call   <ars_d_field_off@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  je     L29
  mov    0x4(%rsp),%edi
  sub    (%rsp),%edi
  lea    0x1(%rdi),%ebp
  add    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L29
  movslq (%rsp),%rax
  mov    %ebp,%edx
  mov    %r12,%rdi
  movslq %ebp,%rbp
  lea    (%rbx,%rax,1),%rsi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbp,1)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ars_d_field_get(char *packet, char *layer, char *field, int skip) {
  int start, end, len;
  char *x;
  if (!ars_d_field_off(packet, layer, field, skip, NULL, &start, &end))
    return NULL;
  len = end - start + 1;
  if ((x = malloc(len + 1)) == NULL)
    return NULL;
  memcpy(x, packet + start, len);
  x[len] = '\0';
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L12
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hash_string(char *s) {
  unsigned char h = 0;
  for (; *s; s++)
    h ^= (unsigned char)(*s);
  return ((int)h);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L23
  mov    $0x0,%eax
L2:
  xor    %edx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
L0:
  movzbl %al,%eax
  ret
L23:
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
int hash_string(char *s) {
  unsigned char h = 0;
  for (; *s; s++)
    h ^= (unsigned char)(*s);
  return ((int)h);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L14
  xor    %eax,%eax
  nopl   (%rax)
L2:
  add    $0x1,%rdi
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L2
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash_string(char *s) {
  unsigned char h = 0;
  for (; *s; s++)
    h ^= (unsigned char)(*s);
  return ((int)h);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash_string>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  xor    %eax,%eax
  nopl   (%rax)
L0:
  add    $0x1,%rdi
  xor    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash_string(char *s) {
  unsigned char h = 0;
  for (; *s; s++)
    h ^= (unsigned char)(*s);
  return ((int)h);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D27
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D4: please enter two numbers:

tool: D27: %d%d

tool: D5: c=%d,d=%d,e=%d,p=%d,q=%d


assistant: ```c
int main(void) {
  int a, b, c, d, e, p, q;
  printf("please enter two numbers:\n");
  scanf("%d%d", &a, &b);
  c = a & b;
  d = b | a;
  e = a >> b;
  p = b ^ a;
  q = b << 3;
  printf("c=%d,d=%d,e=%d,p=%d,q=%d\n", c, d, e, p, q);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  mov    %r8d,%eax
  sar    %cl,%eax
  mov    %r8d,%edx
  or     %ecx,%edx
  mov    %r8d,%esi
  and    %ecx,%esi
  lea    0x0(,%rcx,8),%r9d
  xor    %ecx,%r8d
  mov    %eax,%ecx
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D6
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D15: please enter two numbers:

tool: D6: %d%d

tool: D7: c=%d,d=%d,e=%d,p=%d,q=%d


assistant: ```c
int main(void) {
  int a, b, c, d, e, p, q;
  printf("please enter two numbers:\n");
  scanf("%d%d", &a, &b);
  c = a & b;
  d = b | a;
  e = a >> b;
  p = b ^ a;
  q = b << 3;
  printf("c=%d,d=%d,e=%d,p=%d,q=%d\n", c, d, e, p, q);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  mov    %r8d,%r10d
  mov    %r8d,%edx
  mov    %r8d,%esi
  xor    %ecx,%r8d
  sar    %cl,%r10d
  or     %ecx,%edx
  lea    0x0(,%rcx,8),%r9d
  and    %ecx,%esi
  mov    %r10d,%ecx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
data_type: string
name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D14: please enter two numbers:

tool: D18: %d%d

tool: D8: c=%d,d=%d,e=%d,p=%d,q=%d


assistant: ```c
int main(void) {
  int a, b, c, d, e, p, q;
  printf("please enter two numbers:\n");
  scanf("%d%d", &a, &b);
  c = a & b;
  d = b | a;
  e = a >> b;
  p = b ^ a;
  q = b << 3;
  printf("c=%d,d=%d,e=%d,p=%d,q=%d\n", c, d, e, p, q);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8d
  mov    0x4(%rsp),%ecx
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  mov    %r8d,%r10d
  mov    %r8d,%edx
  mov    %r8d,%esi
  xor    %ecx,%r8d
  sar    %cl,%r10d
  or     %ecx,%edx
  lea    0x0(,%rcx,8),%r9d
  and    %ecx,%esi
  mov    %r10d,%ecx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D23
type_infered: string

tool: D17: please enter two numbers:

tool: D12: %d%d

tool: D23: c=%d,d=%d,e=%d,p=%d,q=%d


assistant: ```c
int main(void) {
  int a, b, c, d, e, p, q;
  printf("please enter two numbers:\n");
  scanf("%d%d", &a, &b);
  c = a & b;
  d = b | a;
  e = a >> b;
  p = b ^ a;
  q = b << 3;
  printf("c=%d,d=%d,e=%d,p=%d,q=%d\n", c, d, e, p, q);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psi_write_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L9
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <psi_crc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L9:
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  cmp    %eax,-0x14(%rbp)
  je     L4
  mov    $0x1,%eax
  jmp    L29
L4:
  mov    $0x0,%eax
L29:
  leave
  ret
```

assistant: ```c
int psi_write_crc(FILE *fp, const void *buf, unsigned cnt, unsigned long *crc) {
  if (crc != NULL) {
    *crc = psi_crc(*crc, buf, cnt);
  }
  if (fwrite(buf, 1, cnt, fp) != cnt) {
    return (1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<psi_write_crc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebx
  test   %rcx,%rcx
  je     L3
  mov    %rcx,%rbp
  mov    (%rcx),%rdi
  call   <psi_crc@plt>
  mov    %rax,0x0(%rbp)
L3:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int psi_write_crc(FILE *fp, const void *buf, unsigned cnt, unsigned long *crc) {
  if (crc != NULL) {
    *crc = psi_crc(*crc, buf, cnt);
  }
  if (fwrite(buf, 1, cnt, fp) != cnt) {
    return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<psi_write_crc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L4
  mov    (%rcx),%rdi
  mov    %rcx,%rbp
  call   <psi_crc@plt>
  mov    %rax,0x0(%rbp)
L4:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %ebx,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int psi_write_crc(FILE *fp, const void *buf, unsigned cnt, unsigned long *crc) {
  if (crc != NULL) {
    *crc = psi_crc(*crc, buf, cnt);
  }
  if (fwrite(buf, 1, cnt, fp) != cnt) {
    return (1);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<psi_write_crc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %rcx,%rcx
  je     L7
  mov    (%rcx),%rdi
  mov    %rcx,%rbp
  call   <psi_crc@plt>
  mov    %rax,0x0(%rbp)
L7:
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <fwrite@plt>
  cmp    %ebx,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int psi_write_crc(FILE *fp, const void *buf, unsigned cnt, unsigned long *crc) {
  if (crc != NULL) {
    *crc = psi_crc(*crc, buf, cnt);
  }
  if (fwrite(buf, 1, cnt, fp) != cnt) {
    return (1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_cos_kernel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x48(%rbp)
  movsd  D30(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D52(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D49(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D24(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D21(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D64(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D7(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x48(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D52
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D49
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D24
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D21
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D64
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D7
type_infered: f64

tool: D30: 0.9999999999992518

tool: {"D52": [0xd6,0xd1,0xf7,0xff,0xff,0xff,0xdf,0xbf]}

tool: D49: 0.041666666473384545

tool: {"D24": [0x9c,0x97,0x51,0x95,0x6b,0xc1,0x56,0xbf]}

tool: D21: 2.48010406484558e-05

tool: {"D64": [0x63,0x24,0xf3,0xf2,0xb4,0x78,0x92,0xbe]}

tool: D7: 1.9907856854e-09

assistant: ```c
double _cos_kernel(double x) {
  const double c1 = 0.99999999999925182;
  const double c2 = -0.49999999997024012;
  const double c3 = 0.041666666473384543;
  const double c4 = -0.001388888418000423;
  const double c5 = 0.0000248010406484558;
  const double c6 = -0.0000002752469638432;
  const double c7 = 0.0000000019907856854;
  double x2;
  x2 = x * x;
  return (c1 + x2 * (c2 + x2 * (c3 + x2 * (c4 + x2 * (c5 + x2 * (c6 + c7 * x2))))));
}
```