ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nrf_set_mode_prx>:
  endbr64
  push   %r13
  mov    %rdi,%rdx
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <nrf_read_register@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L3
  movzbl 0x7(%rsp),%esi
  xor    %edi,%edi
  mov    %r13,%rdx
  or     $0x1,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  call   <nrf_write_register@plt>
  mov    $0x8c,%edi
  mov    %eax,%r12d
  call   <timer_wait_us@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nrf_set_mode_prx(char *retstatus) {
  char confreg = 0;
  int ret;
  ret = nrf_read_register(0x00, &confreg, retstatus);
  if (ret < 0)
    return ret;
  confreg |= 0x01;
  ret = nrf_write_register(0x00, confreg, retstatus);
  timer_wait_us(140);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nrf_set_mode_prx>:
  endbr64
  push   %r13
  mov    %rdi,%rdx
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <nrf_read_register@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L18
  movzbl 0x7(%rsp),%esi
  xor    %edi,%edi
  mov    %r13,%rdx
  or     $0x1,%esi
  mov    %sil,0x7(%rsp)
  movsbl %sil,%esi
  call   <nrf_write_register@plt>
  mov    $0x8c,%edi
  mov    %eax,%r12d
  call   <timer_wait_us@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nrf_set_mode_prx(char *retstatus) {
  char confreg = 0;
  int ret;
  ret = nrf_read_register(0x00, &confreg, retstatus);
  if (ret < 0)
    return ret;
  confreg |= 0x01;
  ret = nrf_write_register(0x00, confreg, retstatus);
  timer_wait_us(140);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_sub@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    $0xffffffff,%eax
  jmp    L6
L2:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int test_sub() {
  if (op_sub(3, 4) != (3 - 4))
    return (-1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_sub>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_sub@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test_sub() {
  if (op_sub(3, 4) != (3 - 4))
    return (-1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_sub>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_sub@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int test_sub() {
  if (op_sub(3, 4) != (3 - 4))
    return (-1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_sub>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <op_sub@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int test_sub() {
  if (op_sub(3, 4) != (3 - 4))
    return (-1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<land_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void land_test(void) {
  int i;
  i = 1 && 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<land_test>:
  endbr64
  ret
```

assistant: ```c
void land_test(void) {
  int i;
  i = 1 && 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<land_test>:
  endbr64
  ret
```

assistant: ```c
void land_test(void) {
  int i;
  i = 1 && 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<land_test>:
  endbr64
  ret
```

assistant: ```c
void land_test(void) {
  int i;
  i = 1 && 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__eshift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L77
L24:
  movw   $0x0,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L82
  negl   -0x1c(%rbp)
  jmp    L6
L12:
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  or     %ax,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshdn6@plt>
  subl   $0x10,-0x1c(%rbp)
L6:
  cmpl   $0xf,-0x1c(%rbp)
  jg     L12
  jmp    L38
L63:
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzbl %al,%edx
  movzwl -0xa(%rbp),%eax
  or     %edx,%eax
  mov    %ax,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshdn8@plt>
  subl   $0x8,-0x1c(%rbp)
L38:
  cmpl   $0x7,-0x1c(%rbp)
  jg     L63
  jmp    L152
L88:
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  or     %edx,%eax
  mov    %ax,-0xa(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshdn1@plt>
  subl   $0x1,-0x1c(%rbp)
L152:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L88
  jmp    L156
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshup6@plt>
  subl   $0x10,-0x1c(%rbp)
L82:
  cmpl   $0xf,-0x1c(%rbp)
  jg     L25
  jmp    L159
L60:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshup8@plt>
  subl   $0x8,-0x1c(%rbp)
L159:
  cmpl   $0x7,-0x1c(%rbp)
  jg     L60
  jmp    L100
L55:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__eshup1@plt>
  subl   $0x1,-0x1c(%rbp)
L100:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L55
L156:
  cmpw   $0x0,-0xa(%rbp)
  je     L21
  movw   $0x1,-0xa(%rbp)
L21:
  movzwl -0xa(%rbp),%eax
L77:
  leave
  ret
```

assistant: ```c
int __eshift(short unsigned int *x, int sc) {
  unsigned short lost;
  unsigned short *p;
  if (sc == 0)
    return (0);
  lost = 0;
  p = x + (6 + 3) - 1;
  if (sc < 0) {
    sc = -sc;
    while (sc >= 16) {
      lost |= *p;
      __eshdn6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      lost |= *p & 0xff;
      __eshdn8(x);
      sc -= 8;
    }
    while (sc > 0) {
      lost |= *p & 1;
      __eshdn1(x);
      sc -= 1;
    }
  } else {
    while (sc >= 16) {
      __eshup6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      __eshup8(x);
      sc -= 8;
    }
    while (sc > 0) {
      __eshup1(x);
      sc -= 1;
    }
  }
  if (lost)
    lost = 1;
  return ((int)lost);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__eshift>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%eax
  test   %esi,%esi
  je     L9
  mov    %rdi,%rbp
  mov    %esi,%ebx
  js     L24
  mov    %esi,%r12d
  cmp    $0xf,%esi
  jle    L159
L6:
  mov    %rbp,%rdi
  call   <__eshup6@plt>
  sub    $0x10,%r12d
  cmp    $0xf,%r12d
  jg     L6
  and    $0xf,%ebx
  cmp    $0x7,%ebx
  jle    L65
  mov    %rbp,%rdi
  call   <__eshup8@plt>
  lea    -0x8(%rbx),%r12d
  cmp    $0x7,%r12d
  jle    L69
  mov    %rbp,%rdi
  call   <__eshup8@plt>
L69:
  lea    -0x8(%rbx),%eax
  and    $0xfffffff8,%eax
  neg    %eax
  cmp    $0x7,%ebx
  mov    $0x0,%edx
  cmovle %edx,%eax
  lea    (%rax,%r12,1),%ebx
L65:
  test   %ebx,%ebx
  jle    L109
L48:
  mov    %rbp,%rdi
  call   <__eshup1@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L48
  mov    $0x0,%r13d
L186:
  cmp    $0x0,%r13w
  mov    $0x1,%eax
  cmovbe %r13d,%eax
  movzwl %ax,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %esi,%r12d
  neg    %r12d
  cmp    $0xfffffff1,%esi
  jge    L62
  mov    $0x0,%r13d
L180:
  or     0x10(%rbp),%r13w
  mov    %rbp,%rdi
  call   <__eshdn6@plt>
  sub    $0x10,%r12d
  cmp    $0xf,%r12d
  jg     L180
  mov    $0xfffffff0,%eax
  sub    %ebx,%eax
  mov    %eax,%r12d
  and    $0xfffffff0,%r12d
  neg    %r12d
  cmp    $0xfffffff1,%ebx
  mov    $0x0,%edx
  cmovge %edx,%r12d
  add    %eax,%r12d
  cmp    $0x7,%r12d
  jle    L40
L82:
  mov    %r12d,%ebx
L76:
  movzbl 0x10(%rbp),%eax
  or     %eax,%r13d
  mov    %rbp,%rdi
  call   <__eshdn8@plt>
  sub    $0x8,%ebx
  cmp    $0x7,%ebx
  jg     L76
  lea    -0x8(%r12),%edx
  mov    %edx,%eax
  and    $0xfffffff8,%eax
  neg    %eax
  cmp    $0x7,%r12d
  mov    $0x0,%ecx
  cmovle %ecx,%eax
  lea    (%rdx,%rax,1),%r12d
L40:
  test   %r12d,%r12d
  jle    L186
L181:
  movzwl 0x10(%rbp),%eax
  and    $0x1,%eax
  or     %eax,%r13d
  mov    %rbp,%rdi
  call   <__eshdn1@plt>
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jg     L181
  jmp    L186
L109:
  mov    $0x0,%r13d
  jmp    L186
L62:
  mov    $0x0,%r13d
  cmp    $0xfffffff9,%esi
  jge    L181
  mov    $0x0,%r13d
  jmp    L82
L159:
  cmp    $0x7,%esi
  jle    L48
  call   <__eshup8@plt>
  lea    -0x8(%rbx),%r12d
  jmp    L69
```

assistant: ```c
int __eshift(short unsigned int *x, int sc) {
  unsigned short lost;
  unsigned short *p;
  if (sc == 0)
    return (0);
  lost = 0;
  p = x + (6 + 3) - 1;
  if (sc < 0) {
    sc = -sc;
    while (sc >= 16) {
      lost |= *p;
      __eshdn6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      lost |= *p & 0xff;
      __eshdn8(x);
      sc -= 8;
    }
    while (sc > 0) {
      lost |= *p & 1;
      __eshdn1(x);
      sc -= 1;
    }
  } else {
    while (sc >= 16) {
      __eshup6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      __eshup8(x);
      sc -= 8;
    }
    while (sc > 0) {
      __eshup1(x);
      sc -= 1;
    }
  }
  if (lost)
    lost = 1;
  return ((int)lost);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__eshift>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L158
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%r12d
  js     L95
  cmp    $0xf,%esi
  jle    L89
  nopw   0x0(%rax,%rax,1)
L108:
  mov    %rbx,%rdi
  sub    $0x10,%r12d
  call   <__eshup6@plt>
  cmp    $0xf,%r12d
  jg     L108
  and    $0xf,%ebp
  cmp    $0x7,%ebp
  jg     L154
L128:
  test   %ebp,%ebp
  je     L64
  nopw   0x0(%rax,%rax,1)
L130:
  mov    %rbx,%rdi
  call   <__eshup1@plt>
  sub    $0x1,%ebp
  jne    L130
L64:
  xor    %eax,%eax
L158:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L95:
  neg    %r12d
  xor    %r13d,%r13d
  cmp    $0xfffffff1,%esi
  jge    L90
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %rbx,%rdi
  sub    $0x10,%r12d
  or     0x10(%rbx),%r13w
  call   <__eshdn6@plt>
  cmp    $0xf,%r12d
  jg     L54
  mov    $0xfffffff0,%r12d
  xor    %edx,%edx
  sub    %ebp,%r12d
  mov    %r12d,%eax
  and    $0xfffffff0,%eax
  neg    %eax
  cmp    $0xfffffff1,%ebp
  cmovge %edx,%eax
  add    %eax,%r12d
  cmp    $0x7,%r12d
  jg     L87
L50:
  test   %r12d,%r12d
  je     L159
  xchg   %ax,%ax
L42:
  movzwl 0x10(%rbx),%eax
  mov    %rbx,%rdi
  and    $0x1,%eax
  or     %eax,%r13d
  call   <__eshdn1@plt>
  sub    $0x1,%r12d
  jne    L42
L159:
  xor    %eax,%eax
  test   %r13w,%r13w
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L89:
  cmp    $0x7,%esi
  jle    L130
  nopl   0x0(%rax)
L154:
  mov    %rbx,%rdi
  sub    $0x8,%ebp
  call   <__eshup8@plt>
  jmp    L128
L90:
  cmp    $0xfffffff9,%esi
  jge    L42
  nopl   (%rax)
L87:
  movzbl 0x10(%rbx),%eax
  mov    %rbx,%rdi
  sub    $0x8,%r12d
  or     %eax,%r13d
  call   <__eshdn8@plt>
  jmp    L50
```

assistant: ```c
int __eshift(short unsigned int *x, int sc) {
  unsigned short lost;
  unsigned short *p;
  if (sc == 0)
    return (0);
  lost = 0;
  p = x + (6 + 3) - 1;
  if (sc < 0) {
    sc = -sc;
    while (sc >= 16) {
      lost |= *p;
      __eshdn6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      lost |= *p & 0xff;
      __eshdn8(x);
      sc -= 8;
    }
    while (sc > 0) {
      lost |= *p & 1;
      __eshdn1(x);
      sc -= 1;
    }
  } else {
    while (sc >= 16) {
      __eshup6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      __eshup8(x);
      sc -= 8;
    }
    while (sc > 0) {
      __eshup1(x);
      sc -= 1;
    }
  }
  if (lost)
    lost = 1;
  return ((int)lost);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__eshift>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L40
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%r12d
  js     L111
  cmp    $0xf,%esi
  jle    L52
  nopw   0x0(%rax,%rax,1)
L96:
  mov    %rbx,%rdi
  sub    $0x10,%r12d
  call   <__eshup6@plt>
  cmp    $0xf,%r12d
  jg     L96
  and    $0xf,%ebp
  cmp    $0x7,%ebp
  jg     L80
L141:
  test   %ebp,%ebp
  je     L44
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rbx,%rdi
  call   <__eshup1@plt>
  sub    $0x1,%ebp
  jne    L31
L44:
  xor    %eax,%eax
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L111:
  neg    %r12d
  xor    %r13d,%r13d
  cmp    $0xfffffff1,%esi
  jge    L155
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbx,%rdi
  sub    $0x10,%r12d
  or     0x10(%rbx),%r13w
  call   <__eshdn6@plt>
  cmp    $0xf,%r12d
  jg     L18
  mov    $0xfffffff0,%r12d
  xor    %edx,%edx
  sub    %ebp,%r12d
  mov    %r12d,%eax
  and    $0xfffffff0,%eax
  neg    %eax
  cmp    $0xfffffff1,%ebp
  cmovge %edx,%eax
  add    %eax,%r12d
  cmp    $0x7,%r12d
  jg     L23
L21:
  test   %r12d,%r12d
  je     L9
  xchg   %ax,%ax
L72:
  movzwl 0x10(%rbx),%eax
  mov    %rbx,%rdi
  and    $0x1,%eax
  or     %eax,%r13d
  call   <__eshdn1@plt>
  sub    $0x1,%r12d
  jne    L72
L9:
  xor    %eax,%eax
  test   %r13w,%r13w
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L52:
  cmp    $0x7,%esi
  jle    L31
  nopl   0x0(%rax)
L80:
  mov    %rbx,%rdi
  sub    $0x8,%ebp
  call   <__eshup8@plt>
  jmp    L141
L155:
  cmp    $0xfffffff9,%esi
  jge    L72
  nopl   (%rax)
L23:
  movzbl 0x10(%rbx),%eax
  mov    %rbx,%rdi
  sub    $0x8,%r12d
  or     %eax,%r13d
  call   <__eshdn8@plt>
  jmp    L21
```

assistant: ```c
int __eshift(short unsigned int *x, int sc) {
  unsigned short lost;
  unsigned short *p;
  if (sc == 0)
    return (0);
  lost = 0;
  p = x + (6 + 3) - 1;
  if (sc < 0) {
    sc = -sc;
    while (sc >= 16) {
      lost |= *p;
      __eshdn6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      lost |= *p & 0xff;
      __eshdn8(x);
      sc -= 8;
    }
    while (sc > 0) {
      lost |= *p & 1;
      __eshdn1(x);
      sc -= 1;
    }
  } else {
    while (sc >= 16) {
      __eshup6(x);
      sc -= 16;
    }
    while (sc >= 8) {
      __eshup8(x);
      sc -= 8;
    }
    while (sc > 0) {
      __eshup1(x);
      sc -= 1;
    }
  }
  if (lost)
    lost = 1;
  return ((int)lost);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binary_search_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L0
L42:
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L20
L69:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L71
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L20
L71:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L36
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L20
L36:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L69
  mov    -0x8(%rbp),%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int binary_search_left(int arr[], int first, int last, int value) {
  if (arr == NULL)
    return -1;
  int index = -1;
  while (first <= last) {
    int mid = first + ((last - first) >> 1);
    if (arr[mid] == value) {
      index = mid;
      last = mid - 1;
    } else if (arr[mid] > value)
      last = mid - 1;
    else
      first = mid + 1;
  }
  return index;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary_search_left>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L80
  cmp    %edx,%esi
  jg     L48
  mov    $0xffffffff,%r9d
  jmp    L82
L4:
  lea    -0x1(%rax),%edx
  mov    %eax,%r9d
L21:
  cmp    %edx,%esi
  jg     L42
L82:
  mov    %edx,%eax
  sub    %esi,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %ecx,%edi
  je     L4
  jle    L84
  lea    -0x1(%rax),%edx
  jmp    L21
L84:
  lea    0x1(%rax),%esi
  jmp    L21
L80:
  mov    $0xffffffff,%r9d
  jmp    L42
L48:
  mov    $0xffffffff,%r9d
L42:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int binary_search_left(int arr[], int first, int last, int value) {
  if (arr == NULL)
    return -1;
  int index = -1;
  while (first <= last) {
    int mid = first + ((last - first) >> 1);
    if (arr[mid] == value) {
      index = mid;
      last = mid - 1;
    } else if (arr[mid] > value)
      last = mid - 1;
    else
      first = mid + 1;
  }
  return index;
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search_left>:
  endbr64
  mov    $0xffffffff,%r9d
  test   %rdi,%rdi
  je     L61
  cmp    %edx,%esi
  jle    L11
  jmp    L61
  nopl   (%rax)
L37:
  jle    L6
  lea    -0x1(%rax),%edx
L12:
  cmp    %esi,%edx
  jl     L61
L11:
  mov    %edx,%eax
  sub    %esi,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  jne    L37
  lea    -0x1(%rax),%edx
  mov    %eax,%r9d
  cmp    %esi,%edx
  jge    L11
L61:
  mov    %r9d,%eax
  ret
L6:
  lea    0x1(%rax),%esi
  jmp    L12
```

assistant: ```c
int binary_search_left(int arr[], int first, int last, int value) {
  if (arr == NULL)
    return -1;
  int index = -1;
  while (first <= last) {
    int mid = first + ((last - first) >> 1);
    if (arr[mid] == value) {
      index = mid;
      last = mid - 1;
    } else if (arr[mid] > value)
      last = mid - 1;
    else
      first = mid + 1;
  }
  return index;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary_search_left>:
  endbr64
  mov    $0xffffffff,%r9d
  test   %rdi,%rdi
  je     L59
  nop
L6:
  cmp    %edx,%esi
  jg     L59
L61:
  mov    %edx,%eax
  sub    %esi,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%r8
  cmp    (%rdi,%r8,4),%ecx
  je     L38
  jge    L34
  lea    -0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L61
L59:
  mov    %r9d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  lea    -0x1(%rax),%edx
  mov    %eax,%r9d
  jmp    L6
L34:
  lea    0x1(%rax),%esi
  jmp    L6
```

assistant: ```c
int binary_search_left(int arr[], int first, int last, int value) {
  if (arr == NULL)
    return -1;
  int index = -1;
  while (first <= last) {
    int mid = first + ((last - first) >> 1);
    if (arr[mid] == value) {
      index = mid;
      last = mid - 1;
    } else if (arr[mid] > value)
      last = mid - 1;
    else
      first = mid + 1;
  }
  return index;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<http_500>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %edi,-0x2014(%rbp)
  mov    %rsi,-0x2020(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2010(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x2010(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x2010(%rbp),%rdx
  mov    -0x2014(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <send_msg@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: string

tool: D15: HTTP/1.0 500 INTERNAL SERVER ERROR


tool: D12: %sServer: xWebserver


assistant: ```c
void http_500(int fd, struct st_trx *wb_trx) {
  char buff[8192];
  sprintf(buff, "HTTP/1.0 500 INTERNAL SERVER ERROR\r\n");
  sprintf(buff, "%sServer: xWebserver\r\n", buff);
  send_msg(fd, buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<http_500>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movabs $0x302e312f50545448,%rax
  movabs $0x544e492030303520,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x4553204c414e5245,%rax
  movabs $0x5252452052455652,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0xa0d524f,0x20(%rsp)
  movb   $0x0,0x24(%rsp)
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <send_msg@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: string

tool: D7: %sServer: xWebserver


assistant: ```c
void http_500(int fd, struct st_trx *wb_trx) {
  char buff[8192];
  sprintf(buff, "HTTP/1.0 500 INTERNAL SERVER ERROR\r\n");
  sprintf(buff, "%sServer: xWebserver\r\n", buff);
  send_msg(fd, buff);
}
```
user: What is the c source code of the assembly code below:

```asm
<http_500>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  movdqa D26(%rip),%xmm0
  lea    D22(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movaps %xmm0,(%rsp)
  mov    %edi,%ebp
  movdqa D6(%rip),%xmm0
  mov    %r12,%rdi
  mov    %r12,%rdx
  movl   $0xa0d524f,0x20(%rsp)
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <send_msg@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x2018,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
datatype: byte[16]
name: parse_data
arguments: data_tag: D22
datatype: string
name: parse_data
arguments: data_tag: D6
datatype: byte[16]

tool: {"D26": [0x48,0x54,0x54,0x50,0x2f,0x31,0x2e,0x30,0x20,0x35,0x30,0x30,0x20,0x49,0x4e,0x54]}

tool: D22: %sServer: xWebserver


tool: {"D6": [0x45,0x52,0x4e,0x41,0x4c,0x20,0x53,0x45,0x52,0x56,0x45,0x52,0x20,0x45,0x52,0x52]}

assistant: ```c
void http_500(int fd, struct st_trx *wb_trx) {
  char buff[8192];
  sprintf(buff, "HTTP/1.0 500 INTERNAL SERVER ERROR\r\n");
  sprintf(buff, "%sServer: xWebserver\r\n", buff);
  send_msg(fd, buff);
}
```