ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<Julian>:
  endbr64
  cmp    $0x2,%esi
  jg     L48
  sub    $0x1,%edi
  add    $0xc,%esi
L48:
  cmp    $0x62e,%edi
  jg     L57
  sete   %dl
  cmp    $0xa,%esi
  jle    L18
  test   %dl,%dl
  je     L18
L57:
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rcx
  sar    $0x27,%rax
  sar    $0x25,%rcx
  sub    %ecx,%eax
  add    $0x2,%eax
L58:
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  cvtsi2sd %edi,%xmm1
  mulsd  D29(%rip),%xmm1
  cvttsd2si %xmm1,%rdx
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  mulsd  D32(%rip),%xmm1
  add    %edx,%eax
  cvttsd2si %xmm1,%rdx
  pxor   %xmm1,%xmm1
  add    %edx,%eax
  cvtsi2sd %eax,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D20(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    $0xa,%esi
  jne    L58
  test   %dl,%dl
  je     L58
  comisd D35(%rip),%xmm0
  jbe    L58
  jmp    L57
```

tool_calls: name: parse_data
arguments: label: D29
type_guessed: f64
name: parse_data
arguments: label: D32
type_guessed: f64
name: parse_data
arguments: label: D20
type_guessed: f64
name: parse_data
arguments: label: D35
type_guessed: byte[16]

tool: D29: 365.25

tool: D32: 30.6001

tool: D20: 1720994.5

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x2e,0x40,0x00,0x00,0x00,0x00,0x00,0xd4,0x76,0x40]}

assistant: ```c
double Julian(int year, int month, double day) {
  int a, b, c, e;
  if (month < 3) {
    year = year - 1;
    month = month + 12;
  }
  if (((year > 1582)) || ((year == 1582) && (month > 10)) || ((year == 1582) && (month == 10) && (day > 15))) {
    a = year / 100;
    b = 2 - a + a / 4;
  }
  c = (long)(365.25 * year);
  e = (long)(30.6001 * (month + 1));
  return b + c + e + day + 1720994.5;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sr_demangle_symbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L37
  mov    $0x0,%eax
  jmp    L35
L37:
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <__cxa_demangle@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L42
  mov    -0x14(%rbp),%eax
  cmp    $0xfffffffe,%eax
  je     L42
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <warn@plt>
L42:
  mov    -0x10(%rbp),%rax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D17
type: string

tool: D0: _Z

tool: D17: __cxa_demangle failed on symbol '%s' with status %d

assistant: ```c
char *sr_demangle_symbol(const char *sym) {
  if (0 != strncmp("_Z", sym, 2))
    return NULL;
  int status;
  char *demangled = __cxa_demangle(sym, NULL, 0, &status);
  if (status != 0 && status != -2)
    warn("__cxa_demangle failed on symbol '%s' with status %d", sym, status);
  return demangled;
}
```
user: What is the c source code of the assembly code below:

```asm
<sr_demangle_symbol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <strncmp@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  jne    L33
  lea    0x4(%rsp),%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <__cxa_demangle@plt>
  mov    %rax,%rbp
  mov    0x4(%rsp),%edx
  lea    0x2(%rdx),%eax
  test   $0xfffffffd,%eax
  jne    L12
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rbx,%rsi
  lea    D19(%rip),%rdi
  call   <warn@plt>
  jmp    L33
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D5: _Z

tool: D19: __cxa_demangle failed on symbol '%s' with status %d

assistant: ```c
char *sr_demangle_symbol(const char *sym) {
  if (0 != strncmp("_Z", sym, 2))
    return NULL;
  int status;
  char *demangled = __cxa_demangle(sym, NULL, 0, &status);
  if (status != 0 && status != -2)
    warn("__cxa_demangle failed on symbol '%s' with status %d", sym, status);
  return demangled;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sr_demangle_symbol>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x2,%edx
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L0
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0x4(%rsp),%rcx
  mov    %rbp,%rdi
  call   <__cxa_demangle@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%r12
  lea    0x2(%rdx),%eax
  and    $0xfffffffd,%eax
  jne    L30
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L30:
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <warn@plt>
  jmp    L0
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string
name: retrieve_data
arguments: data_label: D13
type_infered: string

tool: D4: _Z

tool: D13: __cxa_demangle failed on symbol '%s' with status %d

assistant: ```c
char *sr_demangle_symbol(const char *sym) {
  if (0 != strncmp("_Z", sym, 2))
    return NULL;
  int status;
  char *demangled = __cxa_demangle(sym, NULL, 0, &status);
  if (status != 0 && status != -2)
    warn("__cxa_demangle failed on symbol '%s' with status %d", sym, status);
  return demangled;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sr_demangle_symbol>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x2,%edx
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L30
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0x4(%rsp),%rcx
  mov    %rbp,%rdi
  call   <__cxa_demangle@plt>
  mov    0x4(%rsp),%edx
  mov    %rax,%r12
  lea    0x2(%rdx),%eax
  and    $0xfffffffd,%eax
  jne    L17
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L17:
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <warn@plt>
  jmp    L30
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type: string
name: read_data
arguments: data_label: D14
type: string

tool: D4: _Z

tool: D14: __cxa_demangle failed on symbol '%s' with status %d

assistant: ```c
char *sr_demangle_symbol(const char *sym) {
  if (0 != strncmp("_Z", sym, 2))
    return NULL;
  int status;
  char *demangled = __cxa_demangle(sym, NULL, 0, &status);
  if (status != 0 && status != -2)
    warn("__cxa_demangle failed on symbol '%s' with status %d", sym, status);
  return demangled;
}
```
user: What is the c source code of the assembly code below:

```asm
<getLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  jmp    L9
L11:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
L9:
  cmpb   $0xa,-0xd(%rbp)
  jne    L11
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getLine() {
  char c, *line = (char *)malloc(sizeof(char));
  int i = 0;
  c = getchar();
  while (c != '\n') {
    *(line + i++) = c;
    c = getchar();
    line = (char *)realloc(line, (i + 1) * sizeof(char));
  }
  *(line + i) = '\0';
  return line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L11
  mov    %eax,%ebp
  mov    $0x0,%r12d
L0:
  lea    0x1(%r12),%r13d
  mov    %bpl,(%rbx,%r12,1)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  lea    0x2(%r12),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  add    $0x1,%r12
  cmp    $0xa,%bpl
  jne    L0
L26:
  movslq %r13d,%r13
  movb   $0x0,(%rbx,%r13,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0x0,%r13d
  jmp    L26
```

assistant: ```c
char *getLine() {
  char c, *line = (char *)malloc(sizeof(char));
  int i = 0;
  c = getchar();
  while (c != '\n') {
    *(line + i++) = c;
    c = getchar();
    line = (char *)realloc(line, (i + 1) * sizeof(char));
  }
  *(line + i) = '\0';
  return line;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getLine>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L7
  mov    %eax,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %bl,0x0(%rbp,%r12,1)
  xor    %eax,%eax
  lea    0x1(%r12),%r13d
  call   <getchar@plt>
  lea    0x2(%r12),%esi
  mov    %rbp,%rdi
  add    $0x1,%r12
  mov    %eax,%ebx
  call   <realloc@plt>
  mov    %rax,%rbp
  cmp    $0xa,%bl
  jne    L18
  movslq %r13d,%r13
  add    %rax,%r13
L25:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  mov    %rbp,%r13
  jmp    L25
```

assistant: ```c
char *getLine() {
  char c, *line = (char *)malloc(sizeof(char));
  int i = 0;
  c = getchar();
  while (c != '\n') {
    *(line + i++) = c;
    c = getchar();
    line = (char *)realloc(line, (i + 1) * sizeof(char));
  }
  *(line + i) = '\0';
  return line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLine>:
  endbr64
  push   %r13
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L24
  mov    %eax,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %bl,0x0(%rbp,%r12,1)
  xor    %eax,%eax
  lea    0x1(%r12),%r13d
  call   <getchar@plt>
  lea    0x2(%r12),%esi
  mov    %rbp,%rdi
  add    $0x1,%r12
  mov    %eax,%ebx
  call   <realloc@plt>
  mov    %rax,%rbp
  cmp    $0xa,%bl
  jne    L2
  movslq %r13d,%r13
  add    %rax,%r13
L9:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L24:
  mov    %rbp,%r13
  jmp    L9
```

assistant: ```c
char *getLine() {
  char c, *line = (char *)malloc(sizeof(char));
  int i = 0;
  c = getchar();
  while (c != '\n') {
    *(line + i++) = c;
    c = getchar();
    line = (char *)realloc(line, (i + 1) * sizeof(char));
  }
  *(line + i) = '\0';
  return line;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int subr(int parm) {
  int keeping, busy;
  keeping = parm + parm;
  busy = keeping * keeping;
  return busy;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<subr>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int subr(int parm) {
  int keeping, busy;
  keeping = parm + parm;
  busy = keeping * keeping;
  return busy;
}
```
user: Translate the below assembly code into C programming language:

```asm
<subr>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int subr(int parm) {
  int keeping, busy;
  keeping = parm + parm;
  busy = keeping * keeping;
  return busy;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subr>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int subr(int parm) {
  int keeping, busy;
  keeping = parm + parm;
  busy = keeping * keeping;
  return busy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SHA1_Update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L1:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sha1_writebyte@plt>
L2:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void SHA1_Update(struct SHA1_CTX *s, const void *data, size_t len) {
  const uint8_t *bytes = data;
  for (; len--;)
    sha1_writebyte(s, *bytes++);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SHA1_Update>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%rbp
  test   %rdx,%rdx
  je     L14
L17:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  call   <sha1_writebyte@plt>
  sub    $0x1,%rbp
  cmp    $0xffffffffffffffff,%rbp
  jne    L17
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void SHA1_Update(struct SHA1_CTX *s, const void *data, size_t len) {
  const uint8_t *bytes = data;
  for (; len--;)
    sha1_writebyte(s, *bytes++);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SHA1_Update>:
  endbr64
  test   %rdx,%rdx
  je     L0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <sha1_writebyte@plt>
  sub    $0x1,%rbp
  jae    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
void SHA1_Update(struct SHA1_CTX *s, const void *data, size_t len) {
  const uint8_t *bytes = data;
  for (; len--;)
    sha1_writebyte(s, *bytes++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SHA1_Update>:
  endbr64
  test   %rdx,%rdx
  je     L8
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <sha1_writebyte@plt>
  sub    $0x1,%rbp
  jae    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void SHA1_Update(struct SHA1_CTX *s, const void *data, size_t len) {
  const uint8_t *bytes = data;
  for (; len--;)
    sha1_writebyte(s, *bytes++);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sudo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getpwnam@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L40
L30:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <setuid@plt>
  test   %rax,%rax
  je     L5
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x2,%eax
  jmp    L40
L5:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  test   %rax,%rax
  je     L21
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x3,%eax
  jmp    L40
L21:
  mov    $0x0,%eax
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string

tool: D29: %s does not exist


tool: D3: setuid

tool: D10: execvp

assistant: ```c
int sudo(char *user, char *cmd, char *argv[]) {
  struct passwd *pw = getpwnam(user);
  if (NULL == pw) {
    printf("%s does not exist\n", user);
    return 1;
  }
  if (0 != setuid(pw->pw_uid)) {
    perror("setuid");
    return 2;
  }
  if (0 != execvp(cmd, argv)) {
    perror("execvp");
    return 3;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sudo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L17
  mov    (%rax),%edi
  call   <setuid@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <execvp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L59
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L15
L18:
  lea    D21(%rip),%rdi
  call   <perror@plt>
  mov    $0x2,%eax
  jmp    L15
L59:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%eax
  jmp    L15
```

tool_calls: name: read_data
arguments: label: D8
data_type: string
name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D0
data_type: string

tool: D8: %s does not exist


tool: D21: setuid

tool: D0: execvp

assistant: ```c
int sudo(char *user, char *cmd, char *argv[]) {
  struct passwd *pw = getpwnam(user);
  if (NULL == pw) {
    printf("%s does not exist\n", user);
    return 1;
  }
  if (0 != setuid(pw->pw_uid)) {
    perror("setuid");
    return 2;
  }
  if (0 != execvp(cmd, argv)) {
    perror("execvp");
    return 3;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sudo>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L2
  mov    (%rax),%edi
  call   <setuid@plt>
  test   %rax,%rax
  jne    L25
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <execvp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L3
L32:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D10(%rip),%rdi
  call   <perror@plt>
  pop    %rbp
  mov    $0x2,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L3:
  lea    D28(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%eax
  jmp    L32
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string

tool: D11: %s does not exist


tool: D10: setuid

tool: D28: execvp

assistant: ```c
int sudo(char *user, char *cmd, char *argv[]) {
  struct passwd *pw = getpwnam(user);
  if (NULL == pw) {
    printf("%s does not exist\n", user);
    return 1;
  }
  if (0 != setuid(pw->pw_uid)) {
    perror("setuid");
    return 2;
  }
  if (0 != execvp(cmd, argv)) {
    perror("execvp");
    return 3;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sudo>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <getpwnam@plt>
  test   %rax,%rax
  je     L29
  mov    (%rax),%edi
  call   <setuid@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <execvp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L14
L7:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D14(%rip),%rdi
  call   <perror@plt>
  pop    %rbp
  mov    $0x2,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L14:
  lea    D22(%rip),%rdi
  call   <perror@plt>
  mov    $0x3,%eax
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D22
type_infered: string

tool: D24: %s does not exist


tool: D14: setuid

tool: D22: execvp

assistant: ```c
int sudo(char *user, char *cmd, char *argv[]) {
  struct passwd *pw = getpwnam(user);
  if (NULL == pw) {
    printf("%s does not exist\n", user);
    return 1;
  }
  if (0 != setuid(pw->pw_uid)) {
    perror("setuid");
    return 2;
  }
  if (0 != execvp(cmd, argv)) {
    perror("execvp");
    return 3;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L42
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x18(%rbp)
  jb     L1
L42:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  jmp    L51
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  xor    %rdx,%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L28
  jmp    L32
L46:
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L32:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L55
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L46
  jmp    L55
L100:
  subq   $0x8,-0x28(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
L55:
  cmpq   $0x7,-0x28(%rbp)
  ja     L100
  jmp    L28
L33:
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L28:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L33
L51:
  leave
  ret
```

assistant: ```c
void memmove(void *dest, const void *src, size_t size) {
  if (dest < src || src + size <= dest) {
    return memcpy(dest, src, size);
  }
  char *destc = (char *)dest;
  const char *srcc = (const char *)src;
  if ((uintptr_t)srcc % sizeof(size_t) == (uintptr_t)destc % sizeof(size_t)) {
    while ((uintptr_t)(destc + size) % sizeof(size_t) && size--) {
      destc[size] = srcc[size];
    }
    while (size >= sizeof(size_t)) {
      size -= sizeof(size_t);
      *(size_t *)(destc + size) = *(size_t *)(srcc + size);
    }
  }
  while (size--) {
    destc[size] = srcc[size];
  }
}
```