ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transpose_matrix_vector_mult>:
  endbr64
  test   %r8d,%r8d
  jle    L28
  mov    %ecx,%eax
  push   %r15
  mov    %ecx,%r11d
  movapd %xmm0,%xmm4
  shr    %eax
  push   %r14
  pxor   %xmm5,%xmm5
  unpcklpd %xmm4,%xmm4
  push   %r13
  sub    $0x1,%eax
  movslq %r8d,%r13
  push   %r12
  mov    %r13,%r10
  shl    $0x4,%rax
  mov    %r11d,%r12d
  push   %rbp
  shl    $0x4,%r10
  mov    %rdx,%rbp
  lea    0x0(,%r13,8),%r9
  push   %rbx
  lea    0x10(%rsi,%rax,1),%rcx
  mov    %rdi,%rbx
  and    $0xfffffffe,%r12d
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %edx,%r15d
  movapd %xmm5,%xmm2
  test   %r11d,%r11d
  jle    L42
  cmp    $0x1,%r11d
  je     L69
  mov    %rsi,%r14
  mov    %rbx,%rax
  movapd %xmm5,%xmm2
L27:
  movsd  (%rax),%xmm1
  movupd (%r14),%xmm6
  add    $0x10,%r14
  movhpd (%rax,%r9,1),%xmm1
  add    %r10,%rax
  mulpd  %xmm6,%xmm1
  mulpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm2
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %r14,%rcx
  jne    L27
  movslq %r12d,%r14
  cmp    %r11d,%r12d
  je     L42
L65:
  mov    %r8d,%eax
  imul   %r14d,%eax
  add    %r15d,%eax
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%rsi,%r14,8),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm2
L42:
  movsd  %xmm2,0x0(%rbp,%rdx,8)
  add    $0x1,%rdx
  add    $0x8,%rbx
  cmp    %r13,%rdx
  jne    L46
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  xor    %r14d,%r14d
  movapd %xmm5,%xmm2
  jmp    L65
L28:
  ret
```

assistant: ```c
void transpose_matrix_vector_mult(const double *mat, const double *vec, double *c, int rows, int cols, double weight) {
  for (int i = 0; i < cols; i++) {
    double res = 0.0;
    for (int j = 0; j < rows; j++)
      res += (mat[j * cols + i] * vec[j] * weight);
    c[i] = res;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  jmp    L29
L13:
  lea    -0x1c(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L29
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  lea    -0x1c(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L29:
  lea    -0x1c(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <getlin@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jg     L13
  cmpl   $0x0,-0x24(%rbp)
  jle    L12
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D15: %d, %s

tool: D9: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[10];
  char longest[10];
  max = 0;
  while ((len = getlin(line, 10)) > 0) {
    printf("%d, %s", len, line);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  lea    D7(%rip),%r12
L12:
  lea    0x4(%rsp),%rdi
  mov    $0xa,%esi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L5
  lea    0x4(%rsp),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L12
  lea    0x4(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L12
L5:
  test   %ebp,%ebp
  jg     L31
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  lea    0xe(%rsp),%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string

tool: D7: %d, %s

tool: D9: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[10];
  char longest[10];
  max = 0;
  while ((len = getlin(line, 10)) > 0) {
    printf("%d, %s", len, line);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L24
  nop
L23:
  xor    %eax,%eax
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L10
L24:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L23
  test   %r12d,%r12d
  jne    L58
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  lea    0xe(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <copy@plt>
  jmp    L24
L58:
  lea    0xe(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D4: %d, %s

tool: D14: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[10];
  char longest[10];
  max = 0;
  while ((len = getlin(line, 10)) > 0) {
    printf("%d, %s", len, line);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L52
  nop
L64:
  xor    %eax,%eax
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L29
L52:
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L64
  test   %r12d,%r12d
  jne    L2
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L29:
  lea    0xe(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <copy@plt>
  jmp    L52
L2:
  lea    0xe(%rsp),%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D2: %d, %s

tool: D15: %s

assistant: ```c
main() {
  int len;
  int max;
  char line[10];
  char longest[10];
  max = 0;
  while ((len = getlin(line, 10)) > 0) {
    printf("%d, %s", len, line);
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extractline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
  jmp    L89
L16:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L89:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L61
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L16
L61:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L67
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L6
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L31
L6:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L31
L67:
  addq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L76
L34:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L96
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L34
L96:
  mov    -0x8(%rbp),%rax
L31:
  pop    %rbp
  ret
```

assistant: ```c
char *extractline(char *option, int *start, int *end) {
  *start = 0;
  *end = -1;
  while (*option >= '0' && *option <= '9') {
    *start += (*start) * 10 + ((*option) - '0');
    option++;
  }
  if (*option != ',') {
    if (*start == 0) {
      *start = 1;
      return option;
    }
    *end = *start;
    return option;
  }
  option++;
  *end = 0;
  while (*option >= '0' && *option <= '9') {
    *end += (*end) * 10 + ((*option) - '0');
    option++;
  }
  return option;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<extractline>:
  endbr64
  mov    %rdi,%rcx
  mov    %rdx,%r8
  movl   $0x0,(%rsi)
  movl   $0xffffffff,(%rdx)
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L49
L64:
  mov    (%rsi),%edx
  lea    (%rdx,%rdx,4),%edi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdi,2),%eax
  add    %edx,%eax
  mov    %eax,(%rsi)
  add    $0x1,%rcx
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L64
L49:
  cmp    $0x2c,%al
  je     L72
  mov    (%rsi),%eax
  test   %eax,%eax
  jne    L24
  movl   $0x1,(%rsi)
  mov    %rcx,%rsi
L15:
  mov    %rsi,%rax
  ret
L24:
  mov    %eax,(%r8)
  mov    %rcx,%rsi
  jmp    L15
L72:
  lea    0x1(%rcx),%rsi
  movl   $0x0,(%r8)
  movzbl 0x1(%rcx),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L15
L14:
  mov    (%r8),%edx
  lea    (%rdx,%rdx,4),%ecx
  movsbl %al,%eax
  lea    -0x30(%rax,%rcx,2),%eax
  add    %edx,%eax
  mov    %eax,(%r8)
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L14
  jmp    L15
```

assistant: ```c
char *extractline(char *option, int *start, int *end) {
  *start = 0;
  *end = -1;
  while (*option >= '0' && *option <= '9') {
    *start += (*start) * 10 + ((*option) - '0');
    option++;
  }
  if (*option != ',') {
    if (*start == 0) {
      *start = 1;
      return option;
    }
    *end = *start;
    return option;
  }
  option++;
  *end = 0;
  while (*option >= '0' && *option <= '9') {
    *end += (*end) * 10 + ((*option) - '0');
    option++;
  }
  return option;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<extractline>:
  endbr64
  movl   $0x0,(%rsi)
  mov    %rdx,%r9
  mov    %rdi,%rcx
  movl   $0xffffffff,(%rdx)
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L10
  mov    (%rsi),%edx
  nopl   0x0(%rax,%rax,1)
L3:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%edi
  add    $0x1,%rcx
  movsbl %al,%eax
  lea    (%rax,%rdi,2),%eax
  add    %eax,%edx
  mov    %edx,(%rsi)
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  jbe    L3
L10:
  cmp    $0x2c,%al
  je     L22
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L48
  mov    %eax,(%r9)
  mov    %rcx,%r8
L7:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L48:
  mov    %rcx,%r8
  movl   $0x1,(%rsi)
  mov    %r8,%rax
  ret
  nopl   (%rax)
L22:
  movl   $0x0,(%r9)
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%r8
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L7
  xor    %edx,%edx
  nopl   0x0(%rax)
L14:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%ecx
  add    $0x1,%r8
  movsbl %al,%eax
  lea    (%rax,%rcx,2),%eax
  add    %eax,%edx
  mov    %edx,(%r9)
  movzbl (%r8),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L14
  mov    %r8,%rax
  ret
```

assistant: ```c
char *extractline(char *option, int *start, int *end) {
  *start = 0;
  *end = -1;
  while (*option >= '0' && *option <= '9') {
    *start += (*start) * 10 + ((*option) - '0');
    option++;
  }
  if (*option != ',') {
    if (*start == 0) {
      *start = 1;
      return option;
    }
    *end = *start;
    return option;
  }
  option++;
  *end = 0;
  while (*option >= '0' && *option <= '9') {
    *end += (*end) * 10 + ((*option) - '0');
    option++;
  }
  return option;
}
```
user: What is the c source code of the assembly code below:

```asm
<extractline>:
  endbr64
  movl   $0x0,(%rsi)
  mov    %rdx,%r9
  mov    %rdi,%rcx
  movl   $0xffffffff,(%rdx)
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L22
  mov    (%rsi),%edx
  nopl   0x0(%rax,%rax,1)
L38:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%edi
  add    $0x1,%rcx
  movsbl %al,%eax
  lea    (%rax,%rdi,2),%eax
  add    %eax,%edx
  mov    %edx,(%rsi)
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  jbe    L38
L22:
  cmp    $0x2c,%al
  je     L36
  mov    (%rsi),%eax
  test   %eax,%eax
  je     L56
  mov    %eax,(%r9)
  mov    %rcx,%r8
L1:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L56:
  mov    %rcx,%r8
  movl   $0x1,(%rsi)
  mov    %r8,%rax
  ret
  nopl   (%rax)
L36:
  movl   $0x0,(%r9)
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%r8
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L1
  xor    %edx,%edx
  nopl   0x0(%rax)
L53:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%ecx
  add    $0x1,%r8
  movsbl %al,%eax
  lea    (%rax,%rcx,2),%eax
  add    %eax,%edx
  mov    %edx,(%r9)
  movzbl (%r8),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L53
  mov    %r8,%rax
  ret
```

assistant: ```c
char *extractline(char *option, int *start, int *end) {
  *start = 0;
  *end = -1;
  while (*option >= '0' && *option <= '9') {
    *start += (*start) * 10 + ((*option) - '0');
    option++;
  }
  if (*option != ',') {
    if (*start == 0) {
      *start = 1;
      return option;
    }
    *end = *start;
    return option;
  }
  option++;
  *end = 0;
  while (*option >= '0' && *option <= '9') {
    *end += (*end) * 10 + ((*option) - '0');
    option++;
  }
  return option;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L21
L19:
  addl   $0x1,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x64,-0x18(%rbp)
  jle    L21
  movl   $0x0,-0x18(%rbp)
L21:
  cmpl   $0x0,-0x14(%rbp)
  je     L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D3
datatype: f64

tool: D8: spin: Pid %ld


tool: D3: 3.14159256

assistant: ```c
int main(int argc, char *argv[]) {
  int i, j = 0;
  double pi;
  pid_t pid;
  pid = getpid();
  printf("spin: Pid %ld\n", (long)pid);
  i = 0;
  while (0 == j) {
    i++;
    pi = i / 3.14159256;
    if (i > 100)
      i = 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L3:
  mov    $0x65,%eax
L12:
  sub    $0x1,%eax
  jne    L12
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: spin: Pid %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j = 0;
  double pi;
  pid_t pid;
  pid = getpid();
  printf("spin: Pid %ld\n", (long)pid);
  i = 0;
  while (0 == j) {
    i++;
    pi = i / 3.14159256;
    if (i > 100)
      i = 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D2(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
L6:
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: spin: Pid %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j = 0;
  double pi;
  pid_t pid;
  pid = getpid();
  printf("spin: Pid %ld\n", (long)pid);
  i = 0;
  while (0 == j) {
    i++;
    pi = i / 3.14159256;
    if (i > 100)
      i = 0;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
L1:
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: spin: Pid %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int i, j = 0;
  double pi;
  pid_t pid;
  pid = getpid();
  printf("spin: Pid %ld\n", (long)pid);
  i = 0;
  while (0 == j) {
    i++;
    pi = i / 3.14159256;
    if (i > 100)
      i = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<evil_chroot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <real_chroot@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int evil_chroot(const char *path) {
  int ret = 0;
  ret = real_chroot(path);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<evil_chroot>:
  endbr64
  sub    $0x8,%rsp
  call   <real_chroot@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int evil_chroot(const char *path) {
  int ret = 0;
  ret = real_chroot(path);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evil_chroot>:
  endbr64
  jmp    1050 <real_chroot@plt>
```

assistant: ```c
int evil_chroot(const char *path) {
  int ret = 0;
  ret = real_chroot(path);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<evil_chroot>:
  endbr64
  jmp    1050 <real_chroot@plt>
```

assistant: ```c
int evil_chroot(const char *path) {
  int ret = 0;
  ret = real_chroot(path);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reap_exited_processes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
L7:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L15
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L15
  jmp    L7
L15:
  nop
  leave
  ret
```

assistant: ```c
void reap_exited_processes(int sig_number) {
  pid_t process_id;
  while (1) {
    process_id = waitpid(-1, NULL, WNOHANG);
    if ((0 == process_id) || (-1 == process_id)) {
      break;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reap_exited_processes>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
L6:
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  ja     L6
  pop    %rbx
  ret
```

assistant: ```c
void reap_exited_processes(int sig_number) {
  pid_t process_id;
  while (1) {
    process_id = waitpid(-1, NULL, WNOHANG);
    if ((0 == process_id) || (-1 == process_id)) {
      break;
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reap_exited_processes>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  ja     L7
  pop    %rbx
  ret
```

assistant: ```c
void reap_exited_processes(int sig_number) {
  pid_t process_id;
  while (1) {
    process_id = waitpid(-1, NULL, WNOHANG);
    if ((0 == process_id) || (-1 == process_id)) {
      break;
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<reap_exited_processes>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
  nopl   0x0(%rax)
L3:
  mov    (%rbx),%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <waitpid@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  ja     L3
  pop    %rbx
  ret
```

assistant: ```c
void reap_exited_processes(int sig_number) {
  pid_t process_id;
  while (1) {
    process_id = waitpid(-1, NULL, WNOHANG);
    if ((0 == process_id) || (-1 == process_id)) {
      break;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_tape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x10000(%rsp),%r11
L22:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L22
  sub    $0x40,%rsp
  mov    %edi,-0x10034(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x10034(%rbp),%eax
  mov    %eax,%edi
  call   <tell_tape@plt>
  mov    %eax,-0x10024(%rbp)
  lea    -0x10010(%rbp),%rcx
  mov    -0x10034(%rbp),%eax
  mov    $0xffff,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x10020(%rbp)
  cmpl   $0xffffffff,-0x10020(%rbp)
  jne    L7
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D32(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L54
  mov    $0x0,%eax
  jmp    L53
L54:
  mov    $0x1,%eax
  jmp    L53
L7:
  mov    -0x10034(%rbp),%eax
  mov    %eax,%edi
  call   <tell_tape@plt>
  cmp    %eax,-0x10024(%rbp)
  je     L12
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10014(%rbp)
  mov    -0x10024(%rbp),%eax
  mov    %eax,-0x10018(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10018(%rbp),%rdx
  mov    -0x10034(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x1001c(%rbp)
L12:
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int read_tape(int fd) {
  struct mtop mtop;
  int block_number, rc, n_read;
  char buffer[65535];
  block_number = tell_tape(fd);
  n_read = read(fd, buffer, sizeof(buffer));
  if (n_read == -1) {
    if (errno == ENOSPC)
      return 0;
    else
      return 1;
  }
  if (block_number != tell_tape(fd)) {
    mtop.mt_op = MTSEEK;
    mtop.mt_count = block_number;
    rc = ioctl(fd, MTIOCTOP, &mtop);
  }
  return 0;
}
```