ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<rotr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap_help;
  swap_help = *a;
  *a = *c;
  *c = *b;
  *b = swap_help;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotr>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi)
  mov    (%rsi),%ecx
  mov    %ecx,(%rdx)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap_help;
  swap_help = *a;
  *a = *c;
  *c = *b;
  *b = swap_help;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotr>:
  endbr64
  mov    (%rdx),%ecx
  mov    (%rdi),%eax
  mov    %ecx,(%rdi)
  mov    (%rsi),%ecx
  mov    %ecx,(%rdx)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap_help;
  swap_help = *a;
  *a = *c;
  *c = *b;
  *b = swap_help;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotr>:
  endbr64
  mov    (%rdx),%ecx
  mov    (%rdi),%eax
  mov    %ecx,(%rdi)
  mov    (%rsi),%ecx
  mov    %ecx,(%rdx)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap_help;
  swap_help = *a;
  *a = *c;
  *c = *b;
  *b = swap_help;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x19,-0x10(%rbp)
  movq   $0x1,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L17
L11:
  mov    -0x30(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  subq   $0x1,-0x28(%rbp)
L17:
  cmpq   $0x1,-0x28(%rbp)
  ja     L11
  movq   $0x0,-0x30(%rbp)
  movq   $0x19,-0x8(%rbp)
  movq   $0x1,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L2
L33:
  mov    -0x20(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  subq   $0x1,-0x18(%rbp)
L2:
  cmpq   $0x1,-0x18(%rbp)
  jg     L33
  movq   $0x0,-0x20(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned long long int nu;
  unsigned long long int resultu;
  unsigned long long int iu;
  signed long long int ns;
  signed long long int results;
  signed long long int is;
  nu = 25;
  resultu = 1;
  iu = nu;
  while (iu > 1) {
    resultu = resultu * iu;
    iu--;
  }
  resultu = 0;
  ns = 25;
  results = 1;
  is = ns;
  while (is > 1) {
    results = results * is;
    is--;
  }
  results = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x18,%eax
L19:
  sub    $0x1,%rax
  jne    L19
  mov    $0x18,%eax
L2:
  sub    $0x1,%rax
  jne    L2
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int nu;
  unsigned long long int resultu;
  unsigned long long int iu;
  signed long long int ns;
  signed long long int results;
  signed long long int is;
  nu = 25;
  resultu = 1;
  iu = nu;
  while (iu > 1) {
    resultu = resultu * iu;
    iu--;
  }
  resultu = 0;
  ns = 25;
  results = 1;
  is = ns;
  while (is > 1) {
    results = results * is;
    is--;
  }
  results = 0;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int nu;
  unsigned long long int resultu;
  unsigned long long int iu;
  signed long long int ns;
  signed long long int results;
  signed long long int is;
  nu = 25;
  resultu = 1;
  iu = nu;
  while (iu > 1) {
    resultu = resultu * iu;
    iu--;
  }
  resultu = 0;
  ns = 25;
  results = 1;
  is = ns;
  while (is > 1) {
    results = results * is;
    is--;
  }
  results = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int nu;
  unsigned long long int resultu;
  unsigned long long int iu;
  signed long long int ns;
  signed long long int results;
  signed long long int is;
  nu = 25;
  resultu = 1;
  iu = nu;
  while (iu > 1) {
    resultu = resultu * iu;
    iu--;
  }
  resultu = 0;
  ns = 25;
  results = 1;
  is = ns;
  while (is > 1) {
    results = results * is;
    is--;
  }
  results = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  jmp    L2
L6:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int gcd(unsigned int a, unsigned int b) {
  unsigned int tmp;
  tmp = a % b;
  while (tmp != 0) {
    a = b;
    b = tmp;
    tmp = a % b;
  }
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%ecx
  test   %edx,%edx
  je     L6
L5:
  mov    %ecx,%edi
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%ecx
  mov    %edi,%esi
  test   %edx,%edx
  jne    L5
L10:
  mov    %edi,%eax
  ret
L6:
  mov    %esi,%edi
  jmp    L10
```

assistant: ```c
unsigned int gcd(unsigned int a, unsigned int b) {
  unsigned int tmp;
  tmp = a % b;
  while (tmp != 0) {
    a = b;
    b = tmp;
    tmp = a % b;
  }
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  je     L4
  xchg   %ax,%ax
L9:
  mov    %edx,%r8d
  mov    %esi,%eax
  xor    %edx,%edx
  div    %r8d
  mov    %r8d,%esi
  test   %edx,%edx
  jne    L9
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L4:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int gcd(unsigned int a, unsigned int b) {
  unsigned int tmp;
  tmp = a % b;
  while (tmp != 0) {
    a = b;
    b = tmp;
    tmp = a % b;
  }
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  test   %edx,%edx
  je     L0
  xchg   %ax,%ax
L19:
  mov    %edx,%r8d
  mov    %esi,%eax
  xor    %edx,%edx
  div    %r8d
  mov    %r8d,%esi
  test   %edx,%edx
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L0:
  mov    %esi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int gcd(unsigned int a, unsigned int b) {
  unsigned int tmp;
  tmp = a % b;
  while (tmp != 0) {
    a = b;
    b = tmp;
    tmp = a % b;
  }
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<closeNonStdDescriptors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L12
  movq   $0x1000,-0x8(%rbp)
L12:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L23
L27:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jg     L27
  nop
  nop
  leave
  ret
```

assistant: ```c
void closeNonStdDescriptors(void) {
  long maxFd = sysconf(_SC_OPEN_MAX);
  if (maxFd < 0)
    maxFd = 4096;
  int fd;
  for (fd = STDERR_FILENO + 1; fd < maxFd; fd++)
    close(fd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<closeNonStdDescriptors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  test   %rax,%rax
  mov    $0x1000,%edx
  cmovs  %rdx,%rax
  mov    D2(%rip),%rdx
  mov    (%rdx),%r12d
  lea    0x1(%r12),%edx
  movslq %edx,%rdx
  cmp    %rdx,%rax
  jle    L15
  movslq %r12d,%rdx
  sub    %rdx,%rax
  lea    -0x1(%rax),%rbp
  mov    $0x0,%ebx
  add    $0x1,%r12d
L7:
  lea    (%r12,%rbx,1),%edi
  call   <close@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L7
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void closeNonStdDescriptors(void) {
  long maxFd = sysconf(_SC_OPEN_MAX);
  if (maxFd < 0)
    maxFd = 4096;
  int fd;
  for (fd = STDERR_FILENO + 1; fd < maxFd; fd++)
    close(fd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<closeNonStdDescriptors>:
  endbr64
  mov    D9(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x1000,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  mov    D8(%rip),%rdx
  movslq (%rdx),%rdx
  lea    0x1(%rdx),%r12d
  movslq %r12d,%rcx
  cmp    %rcx,%rax
  jle    L0
  sub    %rdx,%rax
  xor    %ebx,%ebx
  lea    -0x1(%rax),%rbp
  nopl   0x0(%rax)
L2:
  lea    (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <close@plt>
  cmp    %rbp,%rbx
  jne    L2
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void closeNonStdDescriptors(void) {
  long maxFd = sysconf(_SC_OPEN_MAX);
  if (maxFd < 0)
    maxFd = 4096;
  int fd;
  for (fd = STDERR_FILENO + 1; fd < maxFd; fd++)
    close(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<closeNonStdDescriptors>:
  endbr64
  mov    D16(%rip),%rax
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    $0x1000,%edx
  test   %rax,%rax
  cmovs  %rdx,%rax
  mov    D1(%rip),%rdx
  movslq (%rdx),%rdx
  lea    0x1(%rdx),%r12d
  movslq %r12d,%rcx
  cmp    %rcx,%rax
  jle    L17
  sub    %rdx,%rax
  xor    %ebx,%ebx
  lea    -0x1(%rax),%rbp
  nopl   0x0(%rax)
L19:
  lea    (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <close@plt>
  cmp    %rbp,%rbx
  jne    L19
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void closeNonStdDescriptors(void) {
  long maxFd = sysconf(_SC_OPEN_MAX);
  if (maxFd < 0)
    maxFd = 4096;
  int fd;
  for (fd = STDERR_FILENO + 1; fd < maxFd; fd++)
    close(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<slPairTwoColumnFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <lineFileOpen@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L1
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <cloneString@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <slPairAdd@plt>
L1:
  mov    -0x28(%rbp),%rax
  lea    -0x20(%rbp),%rcx
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <lineFileNextRow@plt>
  test   %rax,%rax
  jne    L9
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <lineFileClose@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <slReverse@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
struct slPair *slPairTwoColumnFile(char *fileName) {
  char *row[2];
  struct slPair *list = NULL;
  struct lineFile *lf = lineFileOpen(fileName, 1);
  while (lineFileNextRow(lf, row, (sizeof(row) / sizeof((row)[0]))))
    slPairAdd(&list, row[0], cloneString(row[1]));
  lineFileClose(&lf);
  slReverse(&list);
  return list;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<slPairTwoColumnFile>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    $0x1,%esi
  call   <lineFileOpen@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rbx
  jmp    L27
L8:
  mov    0x18(%rsp),%rdi
  call   <cloneString@plt>
  mov    %eax,%edx
  mov    %rsp,%rdi
  mov    0x10(%rsp),%rsi
  call   <slPairAdd@plt>
L27:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <lineFileNextRow@plt>
  test   %rax,%rax
  jne    L8
  lea    0x8(%rsp),%rdi
  call   <lineFileClose@plt>
  mov    %rsp,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x30,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slPair *slPairTwoColumnFile(char *fileName) {
  char *row[2];
  struct slPair *list = NULL;
  struct lineFile *lf = lineFileOpen(fileName, 1);
  while (lineFileNextRow(lf, row, (sizeof(row) / sizeof((row)[0]))))
    slPairAdd(&list, row[0], cloneString(row[1]));
  lineFileClose(&lf);
  slReverse(&list);
  return list;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<slPairTwoColumnFile>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rbx
  call   <lineFileOpen@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  jmp    L9
  xchg   %ax,%ax
L29:
  mov    0x18(%rsp),%rdi
  call   <cloneString@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <slPairAdd@plt>
  mov    0x8(%rsp),%rdi
L9:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  call   <lineFileNextRow@plt>
  test   %rax,%rax
  jne    L29
  lea    0x8(%rsp),%rdi
  call   <lineFileClose@plt>
  mov    %rbp,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slPair *slPairTwoColumnFile(char *fileName) {
  char *row[2];
  struct slPair *list = NULL;
  struct lineFile *lf = lineFileOpen(fileName, 1);
  while (lineFileNextRow(lf, row, (sizeof(row) / sizeof((row)[0]))))
    slPairAdd(&list, row[0], cloneString(row[1]));
  lineFileClose(&lf);
  slReverse(&list);
  return list;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slPairTwoColumnFile>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rbx
  call   <lineFileOpen@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  jmp    L20
  xchg   %ax,%ax
L23:
  mov    0x18(%rsp),%rdi
  call   <cloneString@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <slPairAdd@plt>
  mov    0x8(%rsp),%rdi
L20:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  call   <lineFileNextRow@plt>
  test   %rax,%rax
  jne    L23
  lea    0x8(%rsp),%rdi
  call   <lineFileClose@plt>
  mov    %rbp,%rdi
  call   <slReverse@plt>
  mov    (%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct slPair *slPairTwoColumnFile(char *fileName) {
  char *row[2];
  struct slPair *list = NULL;
  struct lineFile *lf = lineFileOpen(fileName, 1);
  while (lineFileNextRow(lf, row, (sizeof(row) / sizeof((row)[0]))))
    slPairAdd(&list, row[0], cloneString(row[1]));
  lineFileClose(&lf);
  slReverse(&list);
  return list;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L98:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L98
  sub    $0xc80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c74(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x9c60(%rbp)
  jmp    L2
L39:
  lea    -0x9c70(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x9c5c(%rbp)
  jmp    L0
L60:
  lea    -0x9c50(%rbp),%rdx
  mov    -0x9c5c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x9c5c(%rbp)
L0:
  mov    -0x9c70(%rbp),%eax
  cmp    %eax,-0x9c5c(%rbp)
  jl     L60
  lea    -0x9c6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x9c70(%rbp),%edx
  lea    -0x9c50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigma@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x9c58(%rbp)
  mov    -0x9c58(%rbp),%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x9c5c(%rbp)
  jmp    L65
L27:
  lea    -0x9c64(%rbp),%rdx
  lea    -0x9c68(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x9c68(%rbp),%eax
  test   %eax,%eax
  jns    L29
  mov    -0x9c68(%rbp),%eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L99
L29:
  mov    -0x9c68(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L99:
  mulsd  -0x9c58(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x9c5c(%rbp)
L65:
  mov    -0x9c6c(%rbp),%eax
  cmp    %eax,-0x9c5c(%rbp)
  jl     L27
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x9c60(%rbp)
L2:
  mov    -0x9c74(%rbp),%eax
  cmp    %eax,-0x9c60(%rbp)
  jl     L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L96
  call   <__stack_chk_fail@plt>
L96:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D30
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string
name: retrieve_data
arguments: tag: D66
type_guessed: string

tool: D30: %d

tool: D34: %.2f


tool: D66: %d %d

assistant: ```c
int main(void) {
  int T, N, Q, i, j, k, arr[10000], a, b;
  double s;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &N);
    for (j = 0; j < N; j++)
      scanf("%d", &arr[j]);
    scanf("%d", &Q);
    s = sigma(arr, N);
    printf("%.2f\n", s);
    for (j = 0; j < Q; j++) {
      scanf("%d %d", &a, &b);
      printf("%.2f\n", s * (a < 0 ? -a : a));
    }
    putchar('\n');
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L91:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L91
  sub    $0xc98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c88(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x2c(%rsp)
  jle    L23
  movl   $0x0,0x14(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    D39(%rip),%rbp
  lea    D25(%rip),%r12
  lea    D5(%rip),%r15
  jmp    L27
L3:
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L21:
  mulsd  0x8(%rsp),%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x34(%rsp)
  jle    L61
L70:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x38(%rsp),%eax
  test   %eax,%eax
  js     L3
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L21
L61:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x2c(%rsp)
  jle    L23
L27:
  mov    0x18(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0x30(%rsp)
  jle    L104
  lea    0x40(%rsp),%r13
  mov    $0x0,%ebx
L105:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r13
  cmp    %ebx,0x30(%rsp)
  jg     L105
L104:
  lea    0x34(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x40(%rsp),%rdi
  mov    0x30(%rsp),%esi
  call   <sigma@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  cmpl   $0x0,0x34(%rsp)
  jle    L61
  mov    $0x0,%ebx
  lea    0x3c(%rsp),%r14
  lea    0x38(%rsp),%r13
  jmp    L70
L23:
  mov    0x9c88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x9c98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D39
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D39: %d

tool: D25: %.2f


tool: D5: %d %d

assistant: ```c
int main(void) {
  int T, N, Q, i, j, k, arr[10000], a, b;
  double s;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &N);
    for (j = 0; j < N; j++)
      scanf("%d", &arr[j]);
    scanf("%d", &Q);
    s = sigma(arr, N);
    printf("%.2f\n", s);
    for (j = 0; j < Q; j++) {
      scanf("%d %d", &a, &b);
      printf("%.2f\n", s * (a < 0 ? -a : a));
    }
    putchar('\n');
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L85:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L85
  sub    $0xca8,%rsp
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c98(%rsp)
  xor    %eax,%eax
  lea    0x3c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x3c(%rsp),%ecx
  test   %ecx,%ecx
  jle    L19
  lea    0x40(%rsp),%rax
  movl   $0x0,0x14(%rsp)
  lea    D28(%rip),%r12
  mov    %rax,0x20(%rsp)
  lea    0x50(%rsp),%rax
  lea    D3(%rip),%r15
  mov    %rax,0x18(%rsp)
  lea    0x44(%rsp),%rax
  mov    %rax,0x28(%rsp)
  nopl   (%rax)
L76:
  mov    0x20(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x40(%rsp),%edx
  test   %edx,%edx
  jle    L53
  mov    0x18(%rsp),%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%r13
  cmp    %ebx,0x40(%rsp)
  jg     L79
L53:
  mov    0x28(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x40(%rsp),%esi
  mov    0x18(%rsp),%rdi
  call   <sigma@plt>
  mov    %r12,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  mov    0x44(%rsp),%eax
  test   %eax,%eax
  jle    L58
  xor    %ebx,%ebx
  lea    0x4c(%rsp),%r14
  lea    0x48(%rsp),%r13
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L95:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L80:
  mulsd  0x8(%rsp),%xmm0
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x44(%rsp)
  jle    L58
L66:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x48(%rsp),%eax
  test   %eax,%eax
  jns    L95
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L80
  nopl   0x0(%rax,%rax,1)
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    %eax,0x3c(%rsp)
  jg     L76
L19:
  mov    0x9c98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L84
  add    $0x9ca8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D3
type: string

tool: D19: %d

tool: D28: %.2f


tool: D3: %d %d

assistant: ```c
int main(void) {
  int T, N, Q, i, j, k, arr[10000], a, b;
  double s;
  scanf("%d", &T);
  for (i = 0; i < T; i++) {
    scanf("%d", &N);
    for (j = 0; j < N; j++)
      scanf("%d", &arr[j]);
    scanf("%d", &Q);
    s = sigma(arr, N);
    printf("%.2f\n", s);
    for (j = 0; j < Q; j++) {
      scanf("%d %d", &a, &b);
      printf("%.2f\n", s * (a < 0 ? -a : a));
    }
    putchar('\n');
  }
  return 0;
}
```