ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  D24(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0xffffff6a,-0xc(%rbp)
  movb   $0x61,-0x11(%rbp)
  movss  -0x10(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm2,%xmm2
  cvtsi2ssl -0x8(%rbp),%xmm2
  movd   %xmm2,%edx
  movss  -0x10(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  movsd  D59(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  movss  D26(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
datatype: f32
name: extract_symbolic_data
arguments: data_tag: D50
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D61
datatype: string
name: extract_symbolic_data
arguments: data_tag: D59
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D24: 123.125

tool: D50: %f assigned to an int produces %i


tool: D6: %i assigned to an float produces %f


tool: D61: %i divided by 100 produces %f


tool: D59: 100

tool: D0: %i divided by 100.0 produces %f


tool: {"D26": [0x00,0x00,0xc8,0x42]}

tool: D17: (float) %i divided by 100 produces %f


assistant: ```c
int main(void) {
  float f1 = 123.125, f2;
  int i1, i2 = -150;
  char c = 'a';
  i1 = f1;
  printf("%f assigned to an int produces %i\n", f1, i1);
  f1 = i2;
  printf("%i assigned to an float produces %f\n", i2, f1);
  f1 = i2 / 100;
  printf("%i divided by 100 produces %f\n", i2, f1);
  f2 = i2 / 100.0;
  printf("%i divided by 100.0 produces %f\n", i2, f2);
  f2 = (float)i2 / 100;
  printf("(float) %i divided by 100 produces %f\n", i2, f2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D5(%rip),%xmm0
  mov    $0x7b,%esi
  lea    D83(%rip),%rdi
  call   <printf@plt>
  movss  D11(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D85(%rip),%rdi
  call   <printf@plt>
  movss  D43(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  movss  D63(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D68(%rip),%rdi
  call   <printf@plt>
  movss  D63(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D78(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D83
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D85
datatype: string
name: extract_symbolic_data
arguments: label: D43
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D44
datatype: string
name: extract_symbolic_data
arguments: label: D63
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D68
datatype: string
name: extract_symbolic_data
arguments: label: D78
datatype: string

tool: {"D5": [0x00,0x00,0xf6,0x42]}

tool: D83: %f assigned to an int produces %i


tool: {"D11": [0x00,0x00,0x16,0xc3]}

tool: D85: %i assigned to an float produces %f


tool: {"D43": [0x00,0x00,0x80,0xbf]}

tool: D44: %i divided by 100 produces %f


tool: {"D63": [0x00,0x00,0xc0,0xbf]}

tool: D68: %i divided by 100.0 produces %f


tool: D78: (float) %i divided by 100 produces %f


assistant: ```c
int main(void) {
  float f1 = 123.125, f2;
  int i1, i2 = -150;
  char c = 'a';
  i1 = f1;
  printf("%f assigned to an int produces %i\n", f1, i1);
  f1 = i2;
  printf("%i assigned to an float produces %f\n", i2, f1);
  f1 = i2 / 100;
  printf("%i divided by 100 produces %f\n", i2, f1);
  f2 = i2 / 100.0;
  printf("%i divided by 100.0 produces %f\n", i2, f2);
  f2 = (float)i2 / 100;
  printf("(float) %i divided by 100 produces %f\n", i2, f2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7b,%esi
  movss  D48(%rip),%xmm0
  lea    D98(%rip),%rdi
  call   <printf@plt>
  movss  D89(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  movss  D27(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movss  D20(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D92(%rip),%rdi
  call   <printf@plt>
  movss  D20(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D99(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D48
data_type: byte[4]
name: read_data
arguments: data_tag: D98
data_type: string
name: read_data
arguments: data_tag: D89
data_type: byte[4]
name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D27
data_type: byte[4]
name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D20
data_type: byte[4]
name: read_data
arguments: data_tag: D92
data_type: string
name: read_data
arguments: data_tag: D99
data_type: string

tool: {"D48": [0x00,0x00,0xf6,0x42]}

tool: D98: %f assigned to an int produces %i


tool: {"D89": [0x00,0x00,0x16,0xc3]}

tool: D19: %i assigned to an float produces %f


tool: {"D27": [0x00,0x00,0x80,0xbf]}

tool: D10: %i divided by 100 produces %f


tool: {"D20": [0x00,0x00,0xc0,0xbf]}

tool: D92: %i divided by 100.0 produces %f


tool: D99: (float) %i divided by 100 produces %f


assistant: ```c
int main(void) {
  float f1 = 123.125, f2;
  int i1, i2 = -150;
  char c = 'a';
  i1 = f1;
  printf("%f assigned to an int produces %i\n", f1, i1);
  f1 = i2;
  printf("%i assigned to an float produces %f\n", i2, f1);
  f1 = i2 / 100;
  printf("%i divided by 100 produces %f\n", i2, f1);
  f2 = i2 / 100.0;
  printf("%i divided by 100.0 produces %f\n", i2, f2);
  f2 = (float)i2 / 100;
  printf("(float) %i divided by 100 produces %f\n", i2, f2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7b,%esi
  movss  D77(%rip),%xmm0
  lea    D36(%rip),%rdi
  call   <printf@plt>
  movss  D0(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  movss  D98(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  movss  D69(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D88(%rip),%rdi
  call   <printf@plt>
  movss  D69(%rip),%xmm0
  mov    $0xffffff6a,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D77
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D0
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D50
type_guessed: string
name: retrieve_data
arguments: data_label: D98
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D69
type_guessed: byte[4]
name: retrieve_data
arguments: data_label: D88
type_guessed: string
name: retrieve_data
arguments: data_label: D37
type_guessed: string

tool: {"D77": [0x00,0x00,0xf6,0x42]}

tool: D36: %f assigned to an int produces %i


tool: {"D0": [0x00,0x00,0x16,0xc3]}

tool: D50: %i assigned to an float produces %f


tool: {"D98": [0x00,0x00,0x80,0xbf]}

tool: D29: %i divided by 100 produces %f


tool: {"D69": [0x00,0x00,0xc0,0xbf]}

tool: D88: %i divided by 100.0 produces %f


tool: D37: (float) %i divided by 100 produces %f


assistant: ```c
int main(void) {
  float f1 = 123.125, f2;
  int i1, i2 = -150;
  char c = 'a';
  i1 = f1;
  printf("%f assigned to an int produces %i\n", f1, i1);
  f1 = i2;
  printf("%i assigned to an float produces %f\n", i2, f1);
  f1 = i2 / 100;
  printf("%i divided by 100 produces %f\n", i2, f1);
  f2 = i2 / 100.0;
  printf("%i divided by 100.0 produces %f\n", i2, f2);
  f2 = (float)i2 / 100;
  printf("(float) %i divided by 100 produces %f\n", i2, f2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  leave
  ret
```

assistant: ```c
int hashVal(char *string, int size) {
  int total = 0;
  int loop = strlen(string);
  int hash;
  for (int i = 0; i < loop; i++)
    total += string[i];
  hash = total % size;
  return abs(hash);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hashVal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L28:
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L28
L19:
  cltd
  idiv   %ebp
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
int hashVal(char *string, int size) {
  int total = 0;
  int loop = strlen(string);
  int hash;
  for (int i = 0; i < loop; i++)
    total += string[i];
  hash = total % size;
  return abs(hash);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashVal>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L3
  cltd
  idiv   %ebp
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int hashVal(char *string, int size) {
  int total = 0;
  int loop = strlen(string);
  int hash;
  for (int i = 0; i < loop; i++)
    total += string[i];
  hash = total % size;
  return abs(hash);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ctrlunmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L45:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5e,%eax
  jne    L19
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7e,%al
  jne    L38
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x5e,(%rax)
  jmp    L42
L38:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x40(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L42:
  addl   $0x1,-0x4(%rbp)
  jmp    L15
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
  nop
L15:
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ctrlunmask(char *p, char *o, int n) {
  int i, k = 0;
  for (i = 0; i < n; i++) {
    switch (p[i]) {
    case '^':
      if (p[++i] == '~') {
        *o++ = '^';
      } else {
        *o++ = p[i] - '@';
      }
      k++;
      break;
    default:
      *o++ = p[i];
      k++;
      break;
    }
  }
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ctrlunmask>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L22
  add    $0x1,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  jmp    L40
L44:
  mov    %cl,-0x1(%rsi)
  add    $0x1,%eax
  add    $0x1,%rsi
  add    $0x1,%edi
  cmp    %eax,%edx
  jle    L26
L40:
  movslq %eax,%rcx
  movzbl (%r8,%rcx,1),%ecx
  mov    %edi,%r9d
  cmp    $0x5e,%cl
  jne    L44
  add    $0x1,%eax
  movslq %eax,%r9
  movzbl (%r8,%r9,1),%r9d
  lea    -0x40(%r9),%r10d
  cmp    $0x7e,%r9b
  cmovne %r10d,%ecx
  mov    %edi,%r9d
  jmp    L44
L22:
  mov    $0x0,%r9d
L26:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ctrlunmask(char *p, char *o, int n) {
  int i, k = 0;
  for (i = 0; i < n; i++) {
    switch (p[i]) {
    case '^':
      if (p[++i] == '~') {
        *o++ = '^';
      } else {
        *o++ = p[i] - '@';
      }
      k++;
      break;
    default:
      *o++ = p[i];
      k++;
      break;
    }
  }
  return k;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ctrlunmask>:
  endbr64
  test   %edx,%edx
  jle    L1
  mov    $0x1,%r8d
  xor    %eax,%eax
  sub    %esi,%r8d
  nopl   0x0(%rax,%rax,1)
L2:
  movslq %eax,%rcx
  lea    (%r8,%rsi,1),%r9d
  movzbl (%rdi,%rcx,1),%ecx
  cmp    $0x5e,%cl
  jne    L24
  add    $0x1,%eax
  movslq %eax,%r10
  movzbl (%rdi,%r10,1),%r10d
  lea    -0x40(%r10),%r11d
  cmp    $0x7e,%r10b
  cmovne %r11d,%ecx
L24:
  add    $0x1,%eax
  mov    %cl,(%rsi)
  add    $0x1,%rsi
  cmp    %eax,%edx
  jg     L2
  mov    %r9d,%eax
  ret
L1:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ctrlunmask(char *p, char *o, int n) {
  int i, k = 0;
  for (i = 0; i < n; i++) {
    switch (p[i]) {
    case '^':
      if (p[++i] == '~') {
        *o++ = '^';
      } else {
        *o++ = p[i] - '@';
      }
      k++;
      break;
    default:
      *o++ = p[i];
      k++;
      break;
    }
  }
  return k;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ctrlunmask>:
  endbr64
  test   %edx,%edx
  jle    L4
  mov    $0x1,%r8d
  xor    %eax,%eax
  sub    %esi,%r8d
  nopl   0x0(%rax,%rax,1)
L16:
  movslq %eax,%rcx
  lea    (%r8,%rsi,1),%r9d
  movzbl (%rdi,%rcx,1),%ecx
  cmp    $0x5e,%cl
  jne    L0
  add    $0x1,%eax
  movslq %eax,%r10
  movzbl (%rdi,%r10,1),%r10d
  lea    -0x40(%r10),%r11d
  cmp    $0x7e,%r10b
  cmovne %r11d,%ecx
L0:
  add    $0x1,%eax
  mov    %cl,(%rsi)
  add    $0x1,%rsi
  cmp    %eax,%edx
  jg     L16
  mov    %r9d,%eax
  ret
L4:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ctrlunmask(char *p, char *o, int n) {
  int i, k = 0;
  for (i = 0; i < n; i++) {
    switch (p[i]) {
    case '^':
      if (p[++i] == '~') {
        *o++ = '^';
      } else {
        *o++ = p[i] - '@';
      }
      k++;
      break;
    default:
      *o++ = p[i];
      k++;
      break;
    }
  }
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7d29287b29285b28,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x295d,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <BemFormada@plt>
  test   %rax,%rax
  je     L22
  lea    D32(%rip),%rax
  jmp    L8
L22:
  lea    D13(%rip),%rax
L8:
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D32
datatype: string
name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D27
datatype: string
name: unpack_data
arguments: label: D23
datatype: string

tool: D32: Bem formada

tool: D13: Mal formada

tool: D27: %s


tool: D23: pause

assistant: ```c
int main(void) {
  char expr[10] = "([(){()}])";
  printf("%s\n", BemFormada(expr) ? "Bem formada" : "Mal formada");
  system("pause");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x7d29287b29285b28,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x295d,0x16(%rsp)
  lea    0xe(%rsp),%rdi
  call   <BemFormada@plt>
  test   %rax,%rax
  lea    D14(%rip),%rsi
  lea    D4(%rip),%rax
  cmove  %rax,%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D14: Bem formada

tool: D4: Mal formada

tool: D28: %s


tool: D19: pause

assistant: ```c
int main(void) {
  char expr[10] = "([(){()}])";
  printf("%s\n", BemFormada(expr) ? "Bem formada" : "Mal formada");
  system("pause");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x7d29287b29285b28,%rax
  lea    0xe(%rsp),%rdi
  mov    %rax,0xe(%rsp)
  mov    $0x295d,%eax
  mov    %ax,0x16(%rsp)
  call   <BemFormada@plt>
  lea    D6(%rip),%rsi
  lea    D34(%rip),%rdi
  test   %rax,%rax
  lea    D36(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string

tool: D6: Bem formada

tool: D34: %s


tool: D36: Mal formada

tool: D15: pause

assistant: ```c
int main(void) {
  char expr[10] = "([(){()}])";
  printf("%s\n", BemFormada(expr) ? "Bem formada" : "Mal formada");
  system("pause");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x7d29287b29285b28,%rax
  lea    0xe(%rsp),%rdi
  mov    %rax,0xe(%rsp)
  mov    $0x295d,%eax
  mov    %ax,0x16(%rsp)
  call   <BemFormada@plt>
  lea    D2(%rip),%rsi
  lea    D3(%rip),%rdi
  test   %rax,%rax
  lea    D29(%rip),%rax
  cmove  %rax,%rsi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <system@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D29
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string

tool: D2: Bem formada

tool: D3: %s


tool: D29: Mal formada

tool: D30: pause

assistant: ```c
int main(void) {
  char expr[10] = "([(){()}])";
  printf("%s\n", BemFormada(expr) ? "Bem formada" : "Mal formada");
  system("pause");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_uint64_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L120
  cmp    $0x82,%eax
  jg     L127
  cmp    $0x80,%eax
  je     L70
  cmp    $0x81,%eax
  jne    L127
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rax),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  je     L91
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rax),%rcx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  je     L91
  mov    $0x1,%eax
  jmp    L3
L91:
  mov    $0x0,%eax
  jmp    L3
L120:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  je     L17
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rcx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L98
L17:
  mov    $0x0,%eax
  jmp    L3
L98:
  mov    -0x10(%rbp),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L3
L70:
  mov    $0x1,%eax
  jmp    L3
L127:
  mov    $0x0,%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
bool_t xdr_uint64_t(XDR *xdrs, uint64_t *uip) {
  uint32_t t1;
  uint32_t t2;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    t1 = (uint32_t)((*uip) >> 32);
    t2 = (uint32_t)(*uip);
    return ((*(xdrs)->x_ops->x_putint32)(xdrs, (int32_t *)&t1) && (*(xdrs)->x_ops->x_putint32)(xdrs, (int32_t *)&t2));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getint32)(xdrs, (int32_t *)&t1) || !(*(xdrs)->x_ops->x_getint32)(xdrs, (int32_t *)&t2))
      return 0;
    *uip = ((uint64_t)t1) << 32;
    *uip |= t2;
    return 1;
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```