ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rach_max_trans_raw2val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x4,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x3,%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int rach_max_trans_raw2val(int raw) {
  const int tbl[4] = {1, 2, 4, 7};
  return tbl[raw & 3];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rach_max_trans_raw2val>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  and    $0x3,%edi
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rach_max_trans_raw2val(int raw) {
  const int tbl[4] = {1, 2, 4, 7};
  return tbl[raw & 3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rach_max_trans_raw2val>:
  endbr64
  sub    $0x28,%rsp
  and    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,(%rsp)
  movabs $0x700000004,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rach_max_trans_raw2val(int raw) {
  const int tbl[4] = {1, 2, 4, 7};
  return tbl[raw & 3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rach_max_trans_raw2val>:
  endbr64
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  and    $0x3,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: byte[16]

tool: {"D2": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int rach_max_trans_raw2val(int raw) {
  const int tbl[4] = {1, 2, 4, 7};
  return tbl[raw & 3];
}
```
user: What is the c source code of the assembly code below?

```asm
<cs_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0xf0,%rsp
  mov    %rdi,-0x80d8(%rbp)
  mov    %rsi,-0x80e0(%rbp)
  mov    %rdx,-0x80e8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    -0x80e8(%rbp),%rdx
  mov    -0x80c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x80c4(%rbp),%ecx
  mov    -0x80e8(%rbp),%rdx
  lea    -0x80c0(%rbp),%rax
  mov    $0x8000,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x80c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  movb   $0x0,-0xc1(%rbp)
  mov    -0x80e0(%rbp),%rdx
  lea    -0x80c0(%rbp),%rcx
  mov    -0x80d8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cs_strlcpy@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void cs_snprintf(char *dest, size_t size, const char *format, ...) {
  va_list argptr;
  char bigbuffer[0x8000];
  va_start(argptr, format);
  (void)vsnprintf(bigbuffer, sizeof(bigbuffer), format, argptr);
  va_end(argptr);
  bigbuffer[sizeof(bigbuffer) - 1] = '\0';
  cs_strlcpy(dest, bigbuffer, size);
}
```
user: What is the c source code of the assembly code below:

```asm
<cs_snprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %rsp,%r14
  mov    %r13d,%ecx
  mov    %rbx,%rdx
  mov    $0x8000,%esi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  movb   $0x0,0x7fff(%rsp)
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <cs_strlcpy@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x8010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cs_snprintf(char *dest, size_t size, const char *format, ...) {
  va_list argptr;
  char bigbuffer[0x8000];
  va_start(argptr, format);
  (void)vsnprintf(bigbuffer, sizeof(bigbuffer), format, argptr);
  va_end(argptr);
  bigbuffer[sizeof(bigbuffer) - 1] = '\0';
  cs_strlcpy(dest, bigbuffer, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cs_snprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x10,%rsp
  xor    %r14d,%r14d
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %r14d,%edi
  mov    %rsp,%r15
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x8000,%esi
  mov    %r14d,%ecx
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x7fff(%rsp)
  call   <cs_strlcpy@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x8010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cs_snprintf(char *dest, size_t size, const char *format, ...) {
  va_list argptr;
  char bigbuffer[0x8000];
  va_start(argptr, format);
  (void)vsnprintf(bigbuffer, sizeof(bigbuffer), format, argptr);
  va_end(argptr);
  bigbuffer[sizeof(bigbuffer) - 1] = '\0';
  cs_strlcpy(dest, bigbuffer, size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cs_snprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0x10,%rsp
  xor    %r14d,%r14d
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %r14d,%edi
  mov    %rsp,%r15
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x8000,%esi
  mov    %r14d,%ecx
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x7fff(%rsp)
  call   <cs_strlcpy@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x8010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cs_snprintf(char *dest, size_t size, const char *format, ...) {
  va_list argptr;
  char bigbuffer[0x8000];
  va_start(argptr, format);
  (void)vsnprintf(bigbuffer, sizeof(bigbuffer), format, argptr);
  va_end(argptr);
  bigbuffer[sizeof(bigbuffer) - 1] = '\0';
  cs_strlcpy(dest, bigbuffer, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<d2mce_utime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double d2mce_utime() {
  struct timeval now;
  gettimeofday(&now, 0);
  return now.tv_usec;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d2mce_utime>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double d2mce_utime() {
  struct timeval now;
  gettimeofday(&now, 0);
  return now.tv_usec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d2mce_utime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double d2mce_utime() {
  struct timeval now;
  gettimeofday(&now, 0);
  return now.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<d2mce_utime>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double d2mce_utime() {
  struct timeval now;
  gettimeofday(&now, 0);
  return now.tv_usec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shr    $0x3,%rax
  or     $0xffffffb5,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L15
L13:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%edx
  movzbl -0x9(%rbp),%eax
  shr    $0x3,%al
  movzbl %al,%eax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  xor    %edx,%eax
  mov    %al,-0x9(%rbp)
  addb   $0x2,-0xa(%rbp)
L15:
  cmpb   $0x0,-0xa(%rbp)
  je     L13
  movzbl -0x9(%rbp),%eax
  shl    $0x5,%eax
  xor    $0xffffffe0,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] ^= state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned char)5;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movb   $0xe0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] ^= state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned char)5;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RandomFunc>:
  endbr64
  movb   $0xe0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] ^= state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned char)5;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movb   $0xe0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned char)3;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[0UL] <<= ((state[0UL] >> (unsigned char)3) & (unsigned char)7) | 1UL;
      state[0UL] ^= state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] ^ 736209367UL) << (unsigned char)5;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L12
L0:
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L12:
  cmpl   $0x7,-0x34(%rbp)
  jle    L0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D32
data_type: string
name: disassemble_data
arguments: data_tag: D43
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string

tool: D17: vetor[%d]: 

tool: D32: %d

tool: D43: X: 

tool: D16: Y: 

tool: D20: Soma: %d

assistant: ```c
int main() {
  int vetor[8];
  int X, Y, i;
  for (i = 0; i < 8; i++) {
    printf("vetor[%d]: ", i);
    scanf("%d", &vetor[i]);
  }
  printf("X: ");
  scanf("%d", &X);
  printf("Y: ");
  scanf("%d", &Y);
  printf("Soma: %d", (vetor[X] + vetor[Y]));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r13
  lea    D30(%rip),%r12
L7:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x8,%ebx
  jne    L7
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D30(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  mov    0x10(%rsp,%rdx,4),%esi
  add    0x10(%rsp,%rax,4),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D48
data_type: string
name: parse_data
arguments: label: D43
data_type: string
name: parse_data
arguments: label: D18
data_type: string

tool: D2: vetor[%d]: 

tool: D30: %d

tool: D48: X: 

tool: D43: Y: 

tool: D18: Soma: %d

assistant: ```c
int main() {
  int vetor[8];
  int X, Y, i;
  for (i = 0; i < 8; i++) {
    printf("vetor[%d]: ", i);
    scanf("%d", &vetor[i]);
  }
  printf("X: ");
  scanf("%d", &X);
  printf("Y: ");
  scanf("%d", &Y);
  printf("Soma: %d", (vetor[X] + vetor[Y]));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x8,%ebx
  jne    L18
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  lea    D10(%rip),%rdi
  mov    0x10(%rsp,%rdx,4),%esi
  add    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D45
type: string
name: unpack_data
arguments: data_tag: D21
type: string
name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D10
type: string

tool: D45: vetor[%d]: 

tool: D21: %d

tool: D5: X: 

tool: D4: Y: 

tool: D10: Soma: %d

assistant: ```c
int main() {
  int vetor[8];
  int X, Y, i;
  for (i = 0; i < 8; i++) {
    printf("vetor[%d]: ", i);
    scanf("%d", &vetor[i]);
  }
  printf("X: ");
  scanf("%d", &X);
  printf("Y: ");
  scanf("%d", &Y);
  printf("Soma: %d", (vetor[X] + vetor[Y]));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x8,%ebx
  jne    L6
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x8(%rsp),%rax
  movslq 0xc(%rsp),%rdx
  lea    D6(%rip),%rdi
  mov    0x10(%rsp,%rdx,4),%esi
  add    0x10(%rsp,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D7: vetor[%d]: 

tool: D37: %d

tool: D39: X: 

tool: D16: Y: 

tool: D6: Soma: %d

assistant: ```c
int main() {
  int vetor[8];
  int X, Y, i;
  for (i = 0; i < 8; i++) {
    printf("vetor[%d]: ", i);
    scanf("%d", &vetor[i]);
  }
  printf("X: ");
  scanf("%d", &X);
  printf("Y: ");
  scanf("%d", &Y);
  printf("Soma: %d", (vetor[X] + vetor[Y]));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L12
L30:
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L15
L67:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L3
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L3:
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L67
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L50
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L30
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string

tool: D1: %d

tool: D13: %d 

assistant: ```c
int main() {
  int n, m;
  scanf("%d", &m);
  for (n = 1; n <= m; n++) {
    int fac, sum;
    for (sum = 0, fac = 1; fac < n; fac++)
      if (n % fac == 0)
        sum += fac;
    if (sum == n) {
      printf("%d ", n);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    $0x1,%edi
  lea    D0(%rip),%rbp
  cmpl   $0x0,0x4(%rsp)
  jg     L81
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    %eax,%ecx
L63:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  lea    0x1(%rcx),%eax
  cmp    %ecx,%edi
  jne    L26
L22:
  cmp    %ebx,%esi
  je     L73
L84:
  mov    %ebx,%edi
L81:
  lea    0x1(%rdi),%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L19
  cmp    $0x1,%ebx
  jle    L44
  mov    $0x0,%esi
  mov    $0x1,%ecx
  jmp    L63
L73:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L84
L44:
  mov    $0x0,%esi
  jmp    L22
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D1: %d

tool: D0: %d 

assistant: ```c
int main() {
  int n, m;
  scanf("%d", &m);
  for (n = 1; n <= m; n++) {
    int fac, sum;
    for (sum = 0, fac = 1; fac < n; fac++)
      if (n % fac == 0)
        sum += fac;
    if (sum == n) {
      printf("%d ", n);
    }
  }
  return 0;
}
```