ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_median_sorted_arrays>:
  endbr64
  lea    (%rsi,%rcx,1),%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    $0x10,%rsp
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L6
  mov    %eax,%r14d
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r12,%rcx
  shr    $0x1f,%r14d
  xor    %r9d,%r9d
  xor    %edx,%edx
  add    %eax,%r14d
  sar    %r14d
  push   %r14
  add    $0x1,%r14d
  call   <find_median_sorted_arrays_helper@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %r9d,%r9d
  mov    %r14d,(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <find_median_sorted_arrays_helper@plt>
  addsd  0x18(%rsp),%xmm0
  pop    %rax
  mulsd  D6(%rip),%xmm0
  pop    %rdx
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sar    %eax
  sub    $0x8,%rsp
  mov    %r12,%rcx
  mov    %ebx,%r8d
  add    $0x1,%eax
  xor    %r9d,%r9d
  xor    %edx,%edx
  push   %rax
  call   <find_median_sorted_arrays_helper@plt>
  pop    %rcx
  pop    %rsi
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double find_median_sorted_arrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int len;
  len = nums1_size + nums2_size;
  if (len % 2 == 1) {
    return find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2 + 1);
  } else {
    return (find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2) + find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2 + 1)) / 2.0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_median_sorted_arrays>:
  endbr64
  lea    (%rsi,%rcx,1),%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    $0x10,%rsp
  sub    %ecx,%edx
  cmp    $0x1,%edx
  je     L6
  mov    %eax,%r14d
  sub    $0x8,%rsp
  mov    %ebx,%r8d
  mov    %r12,%rcx
  shr    $0x1f,%r14d
  xor    %r9d,%r9d
  xor    %edx,%edx
  add    %eax,%r14d
  sar    %r14d
  push   %r14
  add    $0x1,%r14d
  call   <find_median_sorted_arrays_helper@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  xor    %edx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %r9d,%r9d
  mov    %r14d,(%rsp)
  movsd  %xmm0,0x18(%rsp)
  call   <find_median_sorted_arrays_helper@plt>
  addsd  0x18(%rsp),%xmm0
  pop    %rax
  mulsd  D1(%rip),%xmm0
  pop    %rdx
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sar    %eax
  sub    $0x8,%rsp
  mov    %r12,%rcx
  mov    %ebx,%r8d
  add    $0x1,%eax
  xor    %r9d,%r9d
  xor    %edx,%edx
  push   %rax
  call   <find_median_sorted_arrays_helper@plt>
  pop    %rcx
  pop    %rsi
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double find_median_sorted_arrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int len;
  len = nums1_size + nums2_size;
  if (len % 2 == 1) {
    return find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2 + 1);
  } else {
    return (find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2) + find_median_sorted_arrays_helper(nums1, nums1_size, 0, nums2, nums2_size, 0, len / 2 + 1)) / 2.0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stratParserError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <stratParserRemain@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: stratParserParse: invalid strategy string, before "%s"

assistant: ```c
int stratParserError(const char *const errstr) {
  SCOTCH_errorPrint("stratParserParse: invalid strategy string, before \"%s\"", stratParserRemain());
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stratParserError>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <stratParserRemain@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: stratParserParse: invalid strategy string, before "%s"

assistant: ```c
int stratParserError(const char *const errstr) {
  SCOTCH_errorPrint("stratParserParse: invalid strategy string, before \"%s\"", stratParserRemain());
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stratParserError>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stratParserRemain@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: stratParserParse: invalid strategy string, before "%s"

assistant: ```c
int stratParserError(const char *const errstr) {
  SCOTCH_errorPrint("stratParserParse: invalid strategy string, before \"%s\"", stratParserRemain());
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stratParserError>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <stratParserRemain@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <SCOTCH_errorPrint@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: stratParserParse: invalid strategy string, before "%s"

assistant: ```c
int stratParserError(const char *const errstr) {
  SCOTCH_errorPrint("stratParserParse: invalid strategy string, before \"%s\"", stratParserRemain());
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x58(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <print_user_inputs@plt>
  mov    -0x58(%rbp),%eax
  mov    %eax,%edi
  call   <set_motor_speed@plt>
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <set_moter_voltage@plt>
  mov    -0x5c(%rbp),%eax
  test   %eax,%eax
  jne    L22
  mov    $0x0,%eax
  call   <print_motor_detail_status@plt>
  jmp    L8
L22:
  mov    $0x0,%eax
  call   <print_motor_speed@plt>
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D27
type: string

tool: D17: %d

tool: D27: %s

assistant: ```c
int main(int argc, char **argv) {
  int usr_priority;
  int motor_params[2];
  char input_text[64];
  scanf("%d", &motor_params[0]);
  scanf("%d", &motor_params[1]);
  scanf("%d", &usr_priority);
  scanf("%s", input_text);
  print_user_inputs(input_text);
  set_motor_speed(motor_params[0]);
  set_moter_voltage(motor_params[1]);
  if (usr_priority == 0) {
    print_motor_detail_status();
  } else {
    print_motor_speed();
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <print_user_inputs@plt>
  mov    0x8(%rsp),%edi
  call   <set_motor_speed@plt>
  mov    0xc(%rsp),%edi
  call   <set_moter_voltage@plt>
  cmpl   $0x0,0x4(%rsp)
  jne    L26
  mov    $0x0,%eax
  call   <print_motor_detail_status@plt>
L22:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  ret
L26:
  mov    $0x0,%eax
  call   <print_motor_speed@plt>
  jmp    L22
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D4
datatype: string

tool: D6: %d

tool: D4: %s

assistant: ```c
int main(int argc, char **argv) {
  int usr_priority;
  int motor_params[2];
  char input_text[64];
  scanf("%d", &motor_params[0]);
  scanf("%d", &motor_params[1]);
  scanf("%d", &usr_priority);
  scanf("%s", input_text);
  print_user_inputs(input_text);
  set_motor_speed(motor_params[0]);
  set_moter_voltage(motor_params[1]);
  if (usr_priority == 0) {
    print_motor_detail_status();
  } else {
    print_motor_speed();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rbp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <print_user_inputs@plt>
  mov    0x8(%rsp),%edi
  call   <set_motor_speed@plt>
  mov    0xc(%rsp),%edi
  call   <set_moter_voltage@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  jne    L4
  call   <print_motor_detail_status@plt>
L10:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <print_motor_speed@plt>
  jmp    L10
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: D17: %d

tool: D13: %s

assistant: ```c
int main(int argc, char **argv) {
  int usr_priority;
  int motor_params[2];
  char input_text[64];
  scanf("%d", &motor_params[0]);
  scanf("%d", &motor_params[1]);
  scanf("%d", &usr_priority);
  scanf("%s", input_text);
  print_user_inputs(input_text);
  set_motor_speed(motor_params[0]);
  set_moter_voltage(motor_params[1]);
  if (usr_priority == 0) {
    print_motor_detail_status();
  } else {
    print_motor_speed();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0xc(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0x10(%rsp),%rbp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <print_user_inputs@plt>
  mov    0x8(%rsp),%edi
  call   <set_motor_speed@plt>
  mov    0xc(%rsp),%edi
  call   <set_moter_voltage@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  test   %edx,%edx
  jne    L15
  call   <print_motor_detail_status@plt>
L3:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  call   <print_motor_speed@plt>
  jmp    L3
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D15: %d

tool: D0: %s

assistant: ```c
int main(int argc, char **argv) {
  int usr_priority;
  int motor_params[2];
  char input_text[64];
  scanf("%d", &motor_params[0]);
  scanf("%d", &motor_params[1]);
  scanf("%d", &usr_priority);
  scanf("%s", input_text);
  print_user_inputs(input_text);
  set_motor_speed(motor_params[0]);
  set_moter_voltage(motor_params[1]);
  if (usr_priority == 0) {
    print_motor_detail_status();
  } else {
    print_motor_speed();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x2,-0x20(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D1
data_type: f64

tool: D17: 3.5

tool: D1: 5.5

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  array[0].a = 1;
  array[0].b = 3.5;
  array[1].a = 2;
  array[1].b = 5.5;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  array[0].a = 1;
  array[0].b = 3.5;
  array[1].a = 2;
  array[1].b = 5.5;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  array[0].a = 1;
  array[0].b = 3.5;
  array[1].a = 2;
  array[1].b = 5.5;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  struct my_struct {
    int a;
    double b;
  };
  struct my_struct array[2];
  array[0].a = 1;
  array[0].b = 3.5;
  array[1].a = 2;
  array[1].b = 5.5;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<printVET>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: %.3f  


assistant: ```c
void printVET(double vet[1000], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.3f  \n", vet[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printVET>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D9(%rip),%rbp
L2:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: %.3f  


assistant: ```c
void printVET(double vet[1000], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.3f  \n", vet[i]);
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printVET>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L0:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: %.3f  


assistant: ```c
void printVET(double vet[1000], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.3f  \n", vet[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printVET>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L6:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: %.3f  


assistant: ```c
void printVET(double vet[1000], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf("%.3f  \n", vet[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_assignment_expressions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  and    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    -0x8(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_assignment_expressions(int dest, int other) {
  __emit_expression_range(0, dest = other);
  __emit_expression_range(0, dest *= other);
  __emit_expression_range(0, dest /= other);
  __emit_expression_range(0, dest %= other);
  __emit_expression_range(0, dest += other);
  __emit_expression_range(0, dest -= other);
  __emit_expression_range(0, dest <<= other);
  __emit_expression_range(0, dest >>= other);
  __emit_expression_range(0, dest &= other);
  __emit_expression_range(0, dest ^= other);
  __emit_expression_range(0, dest |= other);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_assignment_expressions>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  imul   %ebx,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <__emit_expression_range@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test_assignment_expressions(int dest, int other) {
  __emit_expression_range(0, dest = other);
  __emit_expression_range(0, dest *= other);
  __emit_expression_range(0, dest /= other);
  __emit_expression_range(0, dest %= other);
  __emit_expression_range(0, dest += other);
  __emit_expression_range(0, dest -= other);
  __emit_expression_range(0, dest <<= other);
  __emit_expression_range(0, dest >>= other);
  __emit_expression_range(0, dest &= other);
  __emit_expression_range(0, dest ^= other);
  __emit_expression_range(0, dest |= other);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_assignment_expressions>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  mov    %esi,%ebp
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  imul   %ebp,%esi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <__emit_expression_range@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  pop    %rbp
  jmp    1050 <__emit_expression_range@plt>
```

assistant: ```c
void test_assignment_expressions(int dest, int other) {
  __emit_expression_range(0, dest = other);
  __emit_expression_range(0, dest *= other);
  __emit_expression_range(0, dest /= other);
  __emit_expression_range(0, dest %= other);
  __emit_expression_range(0, dest += other);
  __emit_expression_range(0, dest -= other);
  __emit_expression_range(0, dest <<= other);
  __emit_expression_range(0, dest >>= other);
  __emit_expression_range(0, dest &= other);
  __emit_expression_range(0, dest ^= other);
  __emit_expression_range(0, dest |= other);
}
```