ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__expandBuffer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rax
  mov    (%rdx),%rsi
  cmp    %rax,%rsi
  jbe    L18
L36:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  add    %rsi,%rsi
  mov    %rsi,(%rdx)
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  jmp    L36
L5:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <_SocketError@plt>
  mov    %rbp,%rbx
  jmp    L36
```

assistant: ```c
char *__expandBuffer(char *buffer, size_t new_size, size_t *buff_size) {
  char *e;
  if (new_size >= *buff_size) {
    *buff_size = *buff_size * 2;
    e = realloc(buffer, *buff_size);
    if (e == NULL) {
      free(buffer);
      _SocketError();
      return NULL;
    } else {
      return e;
    }
  } else {
    return buffer;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__expandBuffer>:
  endbr64
  mov    %rsi,%r8
  mov    (%rdx),%rsi
  push   %r12
  mov    %rdi,%r12
  cmp    %r8,%rsi
  jbe    L11
L18:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    %rsi,%rsi
  mov    %rsi,(%rdx)
  call   <realloc@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  xor    %eax,%eax
  call   <_SocketError@plt>
  jmp    L18
```

assistant: ```c
char *__expandBuffer(char *buffer, size_t new_size, size_t *buff_size) {
  char *e;
  if (new_size >= *buff_size) {
    *buff_size = *buff_size * 2;
    e = realloc(buffer, *buff_size);
    if (e == NULL) {
      free(buffer);
      _SocketError();
      return NULL;
    } else {
      return e;
    }
  } else {
    return buffer;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__expandBuffer>:
  endbr64
  mov    %rsi,%r8
  mov    (%rdx),%rsi
  push   %r12
  mov    %rdi,%r12
  cmp    %r8,%rsi
  jbe    L2
L27:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  add    %rsi,%rsi
  mov    %rsi,(%rdx)
  call   <realloc@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L22:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  xor    %eax,%eax
  call   <_SocketError@plt>
  jmp    L27
```

assistant: ```c
char *__expandBuffer(char *buffer, size_t new_size, size_t *buff_size) {
  char *e;
  if (new_size >= *buff_size) {
    *buff_size = *buff_size * 2;
    e = realloc(buffer, *buff_size);
    if (e == NULL) {
      free(buffer);
      _SocketError();
      return NULL;
    } else {
      return e;
    }
  } else {
    return buffer;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<normalize>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x1c(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %edi,%edi
  jle    L101
  mov    %rdx,%r13
  mov    %r8,%r12
  mov    %r9,%rbx
  mov    %rdx,%rax
  xor    %r15d,%r15d
  nopw   0x0(%rax,%rax,1)
L92:
  movsd  (%rax),%xmm0
  mov    %rax,%rbp
  add    $0x1,%r15d
  call   <isnan@plt>
  mov    %rax,%r8
  lea    0x8(%rbp),%rax
  test   %r8,%r8
  jne    L92
  movsd  0x0(%rbp),%xmm0
  mov    0x1c(%rsp),%eax
  movsd  %xmm0,(%r12)
  cmp    %r15d,%eax
  jle    L20
  sub    %r15d,%eax
  movslq %r15d,%rcx
  movl   $0x1,0x10(%rsp)
  sub    $0x1,%eax
  lea    0x0(%r13,%rcx,8),%r14
  add    %rcx,%rax
  mov    %r14,%r15
  lea    0x8(%r13,%rax,8),%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax)
L21:
  movsd  (%r15),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L115
  movsd  (%r12),%xmm0
  addl   $0x1,0x10(%rsp)
  addsd  (%r15),%xmm0
  movsd  %xmm0,(%r12)
L115:
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L21
  pxor   %xmm2,%xmm2
  movsd  (%r12),%xmm1
  cvtsi2sdl 0x10(%rsp),%xmm2
  divsd  %xmm2,%xmm1
  movsd  %xmm2,0x10(%rsp)
  movsd  %xmm1,(%r12)
  movsd  0x0(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rbx)
  nopl   0x0(%rax,%rax,1)
L104:
  movsd  (%r14),%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  jne    L32
  movsd  (%r14),%xmm0
  subsd  (%r12),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  (%rbx),%xmm0
  movsd  %xmm0,(%rbx)
L32:
  add    $0x8,%r14
  cmp    (%rsp),%r14
  jne    L104
  movsd  (%rbx),%xmm0
  divsd  0x10(%rsp),%xmm0
L24:
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L86
  sqrtsd %xmm0,%xmm0
L110:
  mov    0x1c(%rsp),%eax
  movsd  %xmm0,(%rbx)
  lea    -0x1(%rax),%edx
  xor    %eax,%eax
  shl    $0x3,%rdx
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L102:
  movsd  (%rbx),%xmm0
  add    $0x8,%rax
L117:
  movsd  0x0(%r13,%rax,1),%xmm1
  subsd  (%r12),%xmm1
  mov    0x8(%rsp),%rsi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%r13,%rax,1)
  movsd  (%rsi,%rax,1),%xmm0
  divsd  (%rbx),%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  cmp    %rax,%rdx
  jne    L102
L101:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  subsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm0
  jmp    L24
L86:
  call   <sqrt@plt>
  jmp    L110
```

assistant: ```c
void normalize(int size, double *t, double *mag, double *sig, double *ave, double *stddev) {
  int i, i1, n;
  if (size > 0) {
    i = 0;
    while (isnan(mag[i]))
      i++;
    *ave = mag[i];
    n = 1;
    i1 = i;
    for (i = i + 1; i < size; i++)
      if (!isnan(mag[i])) {
        *ave += mag[i];
        n++;
      }
    *ave /= (double)n;
    *stddev = ((mag[i1] - *ave) * (mag[i1] - *ave));
    for (i = i1 + 1; i < size; i++)
      if (!isnan(mag[i]))
        *stddev += ((mag[i] - *ave) * (mag[i] - *ave));
    *stddev = sqrt((*stddev) / (double)n);
    for (i = 0; i < size; i++) {
      mag[i] = (mag[i] - *ave) / (*stddev);
      sig[i] = sig[i] / (*stddev);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<file_denied>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <chat_printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <file_cleanup@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %s

assistant: ```c
void file_denied(struct chat_data *buddy, char *txt) {
  chat_printf("%s", txt);
  file_cleanup(buddy);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<file_denied>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  call   <chat_printf@plt>
  mov    %rbx,%rdi
  call   <file_cleanup@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: %s

assistant: ```c
void file_denied(struct chat_data *buddy, char *txt) {
  chat_printf("%s", txt);
  file_cleanup(buddy);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_denied>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <chat_printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <file_cleanup@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %s

assistant: ```c
void file_denied(struct chat_data *buddy, char *txt) {
  chat_printf("%s", txt);
  file_cleanup(buddy);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<file_denied>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <chat_printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <file_cleanup@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: %s

assistant: ```c
void file_denied(struct chat_data *buddy, char *txt) {
  chat_printf("%s", txt);
  file_cleanup(buddy);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<has_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L19
  mov    $0x0,%eax
  jmp    L57
L19:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  jmp    L22
L44:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  cmp    %dl,%al
  je     L26
  mov    $0x0,%eax
  jmp    L57
L26:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L22:
  subl   $0x1,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L44
  mov    $0x1,%eax
L57:
  leave
  ret
```

assistant: ```c
int has_suffix(char *str, char *suffix) {
  int suffix_len = strlen(suffix);
  int str_len = strlen(str);
  if (suffix_len > str_len) {
    return 0;
  }
  str += str_len - suffix_len;
  while (--suffix_len >= 0) {
    if (tolower(*(unsigned char *)str) != *suffix) {
      return 0;
    }
    suffix += 1;
    str += 1;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<has_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%r12d
  jg     L25
  sub    %r12d,%eax
  movslq %eax,%rbx
  add    %r13,%rbx
  test   %r12d,%r12d
  jle    L58
  lea    -0x1(%r12),%eax
  lea    0x1(%rbx,%rax,1),%r12
L33:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  cmp    0x0(%rbp),%al
  jne    L28
  add    $0x1,%rbp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L33
  mov    $0x1,%edx
  jmp    L25
L58:
  mov    $0x1,%edx
  jmp    L25
L28:
  mov    $0x0,%edx
L25:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int has_suffix(char *str, char *suffix) {
  int suffix_len = strlen(suffix);
  int str_len = strlen(str);
  if (suffix_len > str_len) {
    return 0;
  }
  str += str_len - suffix_len;
  while (--suffix_len >= 0) {
    if (tolower(*(unsigned char *)str) != *suffix) {
      return 0;
    }
    suffix += 1;
    str += 1;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<has_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jg     L43
  sub    %r13d,%eax
  cltq
  add    %rax,%rbx
  lea    -0x1(%r13),%eax
  lea    0x1(%rbx,%rax,1),%r12
  test   %r13d,%r13d
  jg     L48
  jmp    L13
  nopl   0x0(%rax)
L19:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L13
L48:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  cmp    0x0(%rbp),%al
  je     L19
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int has_suffix(char *str, char *suffix) {
  int suffix_len = strlen(suffix);
  int str_len = strlen(str);
  if (suffix_len > str_len) {
    return 0;
  }
  str += str_len - suffix_len;
  while (--suffix_len >= 0) {
    if (tolower(*(unsigned char *)str) != *suffix) {
      return 0;
    }
    suffix += 1;
    str += 1;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<has_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jg     L43
  sub    %r13d,%eax
  cltq
  add    %rax,%rbx
  lea    -0x1(%r13),%eax
  lea    0x1(%rbx,%rax,1),%r12
  test   %r13d,%r13d
  jg     L22
  jmp    L23
  nopl   0x0(%rax)
L49:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbx
  je     L23
L22:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  cmp    0x0(%rbp),%al
  je     L49
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L23:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int has_suffix(char *str, char *suffix) {
  int suffix_len = strlen(suffix);
  int str_len = strlen(str);
  if (suffix_len > str_len) {
    return 0;
  }
  str += str_len - suffix_len;
  while (--suffix_len >= 0) {
    if (tolower(*(unsigned char *)str) != *suffix) {
      return 0;
    }
    suffix += 1;
    str += 1;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L25:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L10
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x8(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <printarray@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  call   <printarray@plt>
L10:
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L29
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L25
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D12
type_guessed: string

tool: D0: %d:


tool: D12: 	exchange(a[%d],a[%d])=(%d,%d)


assistant: ```c
void bubble_sort(int a[], int n) {
  int i;
  for (i = 0; i < n - 1; i++) {
    printf("%d:\n", i);
    int j;
    for (j = 0; j < n - 1 - i; j++) {
      if (a[j] > a[j + 1]) {
        printf("\texchange(a[%d],a[%d])=(%d,%d)\n", j, j + 1, a[j], a[j + 1]);
        printarray();
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
        printarray();
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    -0x1(%rsi),%r13d
  test   %r13d,%r13d
  jle    L72
  mov    %r13d,%r15d
  lea    D0(%rip),%r14
  jmp    L51
L74:
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %r12d,%ebp
  je     L40
L69:
  mov    (%rbx),%ecx
  mov    0x4(%rbx),%r8d
  cmp    %r8d,%ecx
  jle    L74
  lea    0x1(%rbp),%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <printarray@plt>
  mov    (%rbx),%eax
  mov    0x4(%rbx),%edx
  mov    %edx,(%rbx)
  mov    %eax,0x4(%rbx)
  mov    $0x0,%eax
  call   <printarray@plt>
  jmp    L74
L40:
  sub    $0x1,%r13d
  je     L72
L51:
  mov    %r15d,%esi
  sub    %r13d,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%r12d
  test   %r13d,%r13d
  jle    L40
  mov    0x8(%rsp),%rbx
  mov    $0x0,%ebp
  jmp    L69
L72:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string

tool: D0: 	exchange(a[%d],a[%d])=(%d,%d)


tool: D17: %d:


assistant: ```c
void bubble_sort(int a[], int n) {
  int i;
  for (i = 0; i < n - 1; i++) {
    printf("%d:\n", i);
    int j;
    for (j = 0; j < n - 1 - i; j++) {
      if (a[j] > a[j + 1]) {
        printf("\texchange(a[%d],a[%d])=(%d,%d)\n", j, j + 1, a[j], a[j + 1]);
        printarray();
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
        printarray();
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r13d,%r13d
  jle    L35
  mov    %r13d,%r14d
  lea    D3(%rip),%r15
  lea    D17(%rip),%r12
  nopl   (%rax)
L1:
  mov    %r13d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  sub    %r14d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rbx
  jmp    L34
  nopl   0x0(%rax)
L17:
  add    $0x4,%rbx
  cmp    %r14d,%ebp
  je     L52
L34:
  mov    (%rbx),%ecx
  mov    0x4(%rbx),%r8d
  mov    %ebp,%esi
  add    $0x1,%ebp
  cmp    %r8d,%ecx
  jle    L17
  mov    %ebp,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  xor    %eax,%eax
  call   <printarray@plt>
  mov    -0x4(%rbx),%eax
  mov    (%rbx),%edx
  mov    %eax,(%rbx)
  xor    %eax,%eax
  mov    %edx,-0x4(%rbx)
  call   <printarray@plt>
  cmp    %r14d,%ebp
  jne    L34
L52:
  sub    $0x1,%r14d
  jne    L1
L35:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string

tool: D3: %d:


tool: D17: 	exchange(a[%d],a[%d])=(%d,%d)


assistant: ```c
void bubble_sort(int a[], int n) {
  int i;
  for (i = 0; i < n - 1; i++) {
    printf("%d:\n", i);
    int j;
    for (j = 0; j < n - 1 - i; j++) {
      if (a[j] > a[j + 1]) {
        printf("\texchange(a[%d],a[%d])=(%d,%d)\n", j, j + 1, a[j], a[j + 1]);
        printarray();
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
        printarray();
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r13d,%r13d
  jle    L41
  mov    %r13d,%r14d
  lea    D11(%rip),%r15
  lea    D14(%rip),%r12
  nopl   0x0(%rax)
L29:
  mov    %r13d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  sub    %r14d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rbx
  jmp    L56
  nopl   0x0(%rax)
L16:
  add    $0x4,%rbx
  cmp    %r14d,%ebp
  je     L53
L56:
  mov    (%rbx),%ecx
  mov    0x4(%rbx),%r8d
  mov    %ebp,%esi
  add    $0x1,%ebp
  cmp    %r8d,%ecx
  jle    L16
  mov    %ebp,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <printarray@plt>
  rolq   $0x20,(%rbx)
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printarray@plt>
  cmp    %r14d,%ebp
  jne    L56
L53:
  sub    $0x1,%r14d
  jne    L29
L41:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D11: %d:


tool: D14: 	exchange(a[%d],a[%d])=(%d,%d)


assistant: ```c
void bubble_sort(int a[], int n) {
  int i;
  for (i = 0; i < n - 1; i++) {
    printf("%d:\n", i);
    int j;
    for (j = 0; j < n - 1 - i; j++) {
      if (a[j] > a[j + 1]) {
        printf("\texchange(a[%d],a[%d])=(%d,%d)\n", j, j + 1, a[j], a[j + 1]);
        printarray();
        int temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
        printarray();
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmd_mvwinnstr>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L112
  lea    0x10(%rsp),%rdx
  lea    D59(%rip),%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L21
  lea    0x4(%rsp),%rdx
  mov    0x8(%rbx),%rdi
  lea    D74(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L80
  lea    0x8(%rsp),%rdx
  mov    0x10(%rbx),%rdi
  lea    D74(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L18
  lea    0xc(%rsp),%rdx
  mov    0x18(%rbx),%rdi
  lea    D74(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L74
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L42
  mov    $0x2,%edi
  call   <report_count@plt>
  mov    0xc(%rsp),%r8d
  mov    %rbx,%rcx
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <mvwinnstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  mov    %rbx,%rdi
  call   <report_status@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  jmp    L112
L21:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D60(%rip),%rdi
  call   <report_error@plt>
L112:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  pop    %rbx
  ret
L80:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D60(%rip),%rdi
  call   <report_error@plt>
  jmp    L112
L18:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D60(%rip),%rdi
  call   <report_error@plt>
  jmp    L112
L74:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D60(%rip),%rdi
  call   <report_error@plt>
  jmp    L112
L42:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D56(%rip),%rdi
  call   <report_error@plt>
  jmp    L112
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D59
type: string
name: parse_data
arguments: data_label: D74
type: string
name: parse_data
arguments: data_label: D60
type: string
name: parse_data
arguments: data_label: D56
type: string

tool: D59: %p

tool: D74: %d

tool: D60: BAD ARGUMENT

tool: D56: MALLOC_FAILED

assistant: ```c
void cmd_mvwinnstr(int nargs, char **args) {
  int y, x, count;
  char *string;
  WINDOW *win;
  if (check_arg_count(nargs, 4) == 1)
    return;
  if (sscanf(args[0], "%p", &win) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[1], "%d", &y) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[2], "%d", &x) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if (sscanf(args[3], "%d", &count) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  if ((string = malloc(count + 1)) == NULL) {
    report_count(1);
    report_error("MALLOC_FAILED");
    return;
  }
  report_count(2);
  report_return(mvwinnstr(win, y, x, string, count));
  report_status(string);
  free(string);
}
```