ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inMandelbrot>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D3(%rip),%xmm6
  movapd %xmm2,%xmm4
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L21:
  movapd %xmm4,%xmm3
  movapd %xmm2,%xmm5
  sub    $0x1,%edi
  mulsd  %xmm2,%xmm5
  mulsd  %xmm4,%xmm3
  addsd  %xmm4,%xmm4
  mulsd  %xmm4,%xmm2
  subsd  %xmm5,%xmm3
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm3
  movapd %xmm2,%xmm5
  movapd %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm4
  comisd %xmm6,%xmm4
  ja     L20
  movapd %xmm3,%xmm4
L19:
  test   %edi,%edi
  jg     L21
  mov    $0x1,%eax
  ret
  nop
L20:
  xor    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: f32[2]

tool: {"D3": [0.0,2.25]}

assistant: ```c
int inMandelbrot(double x0, double y0, int n) {
  double x = 0.0;
  double y = 0.0;
  double xtemp;
  while (n > 0) {
    xtemp = x * x - y * y + x0;
    y = 2 * x * y + y0;
    x = xtemp;
    n -= 1;
    if (x * x + y * y > 4) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
L19:
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int print_lines(FILE *fp, char **lines) {
  char *line;
  while ((line = *lines++))
    fputs(line, fp);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_lines>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x8(%rsi),%rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L2
L6:
  mov    %rbp,%rsi
  call   <fputs@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L6
L2:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int print_lines(FILE *fp, char **lines) {
  char *line;
  while ((line = *lines++))
    fputs(line, fp);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_lines>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L8
  lea    0x8(%rsi),%rbx
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <fputs@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L14
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int print_lines(FILE *fp, char **lines) {
  char *line;
  while ((line = *lines++))
    fputs(line, fp);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_lines>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L9
  lea    0x8(%rsi),%rbx
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rsi
  add    $0x8,%rbx
  call   <fputs@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L13
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int print_lines(FILE *fp, char **lines) {
  char *line;
  while ((line = *lines++))
    fputs(line, fp);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<st103_ep_clear_dtog_rx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <st103_get_epreg@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x4000,%eax
  test   %eax,%eax
  je     L8
  andl   $0x8f8f,-0x4(%rbp)
  orl    $0xc080,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <st103_set_epreg@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void st103_ep_clear_dtog_rx(uint8_t ep_num) {
  uint16_t value = st103_get_epreg(ep_num);
  if ((value & (0x4000))) {
    value &= ((0x8000) | (0x0800) | (0x0600) | (0x0100) | (0x0080) | (0x000F));
    value |= (0x8000) | (0x0080) | (0x4000);
    st103_set_epreg(ep_num, value);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<st103_ep_clear_dtog_rx>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <st103_get_epreg@plt>
  test   $0x40,%ah
  jne    L4
L16:
  pop    %rbx
  ret
L4:
  and    $0x8f8f,%eax
  or     $0xc080,%eax
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <st103_set_epreg@plt>
  jmp    L16
```

assistant: ```c
void st103_ep_clear_dtog_rx(uint8_t ep_num) {
  uint16_t value = st103_get_epreg(ep_num);
  if ((value & (0x4000))) {
    value &= ((0x8000) | (0x0800) | (0x0600) | (0x0100) | (0x0080) | (0x000F));
    value |= (0x8000) | (0x0080) | (0x4000);
    st103_set_epreg(ep_num, value);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<st103_ep_clear_dtog_rx>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <st103_get_epreg@plt>
  test   $0x40,%ah
  jne    L8
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  and    $0x8f8f,%eax
  mov    %ebp,%edi
  pop    %rbp
  or     $0xc080,%eax
  mov    %eax,%esi
  jmp    1070 <st103_set_epreg@plt>
```

assistant: ```c
void st103_ep_clear_dtog_rx(uint8_t ep_num) {
  uint16_t value = st103_get_epreg(ep_num);
  if ((value & (0x4000))) {
    value &= ((0x8000) | (0x0800) | (0x0600) | (0x0100) | (0x0080) | (0x000F));
    value |= (0x8000) | (0x0080) | (0x4000);
    st103_set_epreg(ep_num, value);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st103_ep_clear_dtog_rx>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <st103_get_epreg@plt>
  test   $0x40,%ah
  jne    L5
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  and    $0x8f8f,%eax
  mov    %ebp,%edi
  pop    %rbp
  or     $0xc080,%eax
  mov    %eax,%esi
  jmp    1070 <st103_set_epreg@plt>
```

assistant: ```c
void st103_ep_clear_dtog_rx(uint8_t ep_num) {
  uint16_t value = st103_get_epreg(ep_num);
  if ((value & (0x4000))) {
    value &= ((0x8000) | (0x0800) | (0x0600) | (0x0100) | (0x0080) | (0x000F));
    value |= (0x8000) | (0x0080) | (0x4000);
    st103_set_epreg(ep_num, value);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L53
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  jmp    L42
L53:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L17
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L42
L17:
  movq   $0x1,-0x10(%rbp)
  jmp    L30
L44:
  mov    -0x10(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x20(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L44
  mov    -0x8(%rbp),%rax
L42:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: string

tool: D15: Allocation error

assistant: ```c
void **alloc_image(uint32_t lines, uint32_t columns, size_t bytes_per_element) {
  void **image;
  image = calloc(lines, sizeof(void *));
  if (image == NULL) {
    perror("Allocation error");
    return NULL;
  }
  *image = calloc(lines * columns, bytes_per_element);
  if (*image == NULL) {
    perror("Allocation error");
    free(image);
    return NULL;
  }
  for (uint32_t i = 1; i < lines; i++)
    image[i] = image[i - 1] + columns * bytes_per_element;
  return image;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alloc_image>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r14
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L21
  mov    %r12,%rdi
  imul   %rbx,%rdi
  mov    %r14,%rsi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L38
  cmp    $0x1,%r12
  jbe    L49
  imul   %r14,%rbx
  mov    %rbx,%rcx
  mov    %rbp,%rax
  lea    -0x8(%rbp,%r12,8),%rsi
L57:
  mov    %rcx,%rdx
  add    (%rax),%rdx
  mov    %rdx,0x8(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L57
L49:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  jmp    L49
L38:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rbp
  jmp    L49
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: Allocation error

assistant: ```c
void **alloc_image(uint32_t lines, uint32_t columns, size_t bytes_per_element) {
  void **image;
  image = calloc(lines, sizeof(void *));
  if (image == NULL) {
    perror("Allocation error");
    return NULL;
  }
  *image = calloc(lines * columns, bytes_per_element);
  if (*image == NULL) {
    perror("Allocation error");
    free(image);
    return NULL;
  }
  for (uint32_t i = 1; i < lines; i++)
    image[i] = image[i - 1] + columns * bytes_per_element;
  return image;
}
```
user: What is the c source code of the assembly code below:

```asm
<alloc_image>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L61
  mov    %r13,%rdi
  mov    %rbp,%rsi
  imul   %rbx,%rdi
  call   <calloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L43
  cmp    $0x1,%r13
  jbe    L54
  imul   %rbp,%rbx
  lea    0x8(%r12),%rdx
  lea    -0x8(%r12,%r13,8),%rsi
  mov    %rbx,%rcx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x8,%rdx
L38:
  add    %rcx,%rax
  mov    %rax,(%rdx)
  cmp    %rsi,%rdx
  jne    L24
L54:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  lea    D14(%rip),%rdi
  call   <perror@plt>
  jmp    L54
L43:
  lea    D14(%rip),%rdi
  call   <perror@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L54
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D14: Allocation error

assistant: ```c
void **alloc_image(uint32_t lines, uint32_t columns, size_t bytes_per_element) {
  void **image;
  image = calloc(lines, sizeof(void *));
  if (image == NULL) {
    perror("Allocation error");
    return NULL;
  }
  *image = calloc(lines * columns, bytes_per_element);
  if (*image == NULL) {
    perror("Allocation error");
    free(image);
    return NULL;
  }
  for (uint32_t i = 1; i < lines; i++)
    image[i] = image[i - 1] + columns * bytes_per_element;
  return image;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_image>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x8,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L21
  mov    %r13,%rdi
  mov    %rbp,%rsi
  imul   %rbx,%rdi
  call   <calloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L45
  cmp    $0x1,%r13
  jbe    L43
  imul   %rbp,%rbx
  lea    0x8(%r12),%rdx
  lea    (%r12,%r13,8),%rsi
  mov    %rbx,%rcx
  nopw   0x0(%rax,%rax,1)
L37:
  add    %rcx,%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rsi,%rdx
  jne    L37
L43:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  lea    D13(%rip),%rdi
  call   <perror@plt>
  jmp    L43
L45:
  lea    D13(%rip),%rdi
  call   <perror@plt>
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L43
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string

tool: D13: Allocation error

assistant: ```c
void **alloc_image(uint32_t lines, uint32_t columns, size_t bytes_per_element) {
  void **image;
  image = calloc(lines, sizeof(void *));
  if (image == NULL) {
    perror("Allocation error");
    return NULL;
  }
  *image = calloc(lines * columns, bytes_per_element);
  if (*image == NULL) {
    perror("Allocation error");
    free(image);
    return NULL;
  }
  for (uint32_t i = 1; i < lines; i++)
    image[i] = image[i - 1] + columns * bytes_per_element;
  return image;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L10
L61:
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
  subq   $0x1,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L31:
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  subq   $0x1,-0x20(%rbp)
  jmp    L22
L64:
  subl   $0x1,-0x4(%rbp)
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L64
  cmpl   $0x0,-0x4(%rbp)
  je     L68
  mov    $0x1,%eax
  jmp    L3
L68:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  int i;
  for (; *s != '\0'; s++)
    ;
  s--;
  for (i = 0; *t != '\0'; t++, i++)
    ;
  t--;
  for (; *s == *t; s--, t--)
    i--;
  if (i)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strend>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L15
L43:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L43
L15:
  cmpb   $0x0,(%rsi)
  je     L16
  mov    $0x0,%edx
L42:
  add    $0x1,%rsi
  add    $0x1,%edx
  cmpb   $0x0,(%rsi)
  jne    L42
L6:
  movzbl -0x1(%rsi),%eax
  cmp    %al,-0x1(%rdi)
  jne    L17
  mov    $0xfffffffffffffffe,%rax
  lea    0x1(%rdx),%r8d
L68:
  lea    (%r8,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  sub    $0x1,%rax
  cmp    0x1(%rsi,%rax,1),%cl
  je     L68
L17:
  test   %edx,%edx
  setne  %al
  movzbl %al,%eax
  ret
L16:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int strend(char *s, char *t) {
  int i;
  for (; *s != '\0'; s++)
    ;
  s--;
  for (i = 0; *t != '\0'; t++, i++)
    ;
  t--;
  for (; *s == *t; s--, t--)
    i--;
  if (i)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strend>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L31
  nopl   0x0(%rax)
L37:
  mov    %rdi,%rcx
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L37
  cmpb   $0x0,(%rsi)
  je     L34
L45:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %rsi,%r8
  add    $0x1,%rsi
  add    $0x1,%edx
  cmpb   $0x0,(%rsi)
  jne    L73
  movzbl -0x1(%rdi),%eax
  cmp    %al,-0x1(%rsi)
  jne    L1
L52:
  mov    $0xffffffffffffffff,%rax
  nopw   0x0(%rax,%rax,1)
L66:
  movzbl (%rcx,%rax,1),%esi
  lea    (%rdx,%rax,1),%edi
  sub    $0x1,%rax
  cmp    0x1(%r8,%rax,1),%sil
  je     L66
  xor    %eax,%eax
  test   %edi,%edi
  setne  %al
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  cmpb   $0x0,(%rsi)
  lea    -0x1(%rdi),%rcx
  jne    L45
  nopl   0x0(%rax)
L34:
  movzbl -0x1(%rdi),%eax
  lea    -0x1(%rsi),%r8
  xor    %edx,%edx
  cmp    %al,-0x1(%rsi)
  je     L52
L1:
  mov    %edx,%edi
  xor    %eax,%eax
  test   %edi,%edi
  setne  %al
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  int i;
  for (; *s != '\0'; s++)
    ;
  s--;
  for (i = 0; *t != '\0'; t++, i++)
    ;
  t--;
  for (; *s == *t; s--, t--)
    i--;
  if (i)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strend>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rcx
  add    $0x1,%rdi
  mov    %eax,%r9d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
  movzbl (%rsi),%eax
  test   %al,%al
  je     L41
L79:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %rsi,%rdi
  add    $0x1,%rsi
  mov    %eax,%r8d
  add    $0x1,%edx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L47
  cmp    %r8b,%r9b
  jne    L51
L53:
  mov    $0xffffffffffffffff,%rax
L29:
  movzbl (%rcx,%rax,1),%esi
  lea    (%rdx,%rax,1),%r8d
  sub    $0x1,%rax
  cmp    0x1(%rdi,%rax,1),%sil
  je     L29
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  ret
  nopl   0x0(%rax)
L7:
  movzbl (%rsi),%eax
  movzbl -0x1(%rdi),%r9d
  lea    -0x1(%rdi),%rcx
  test   %al,%al
  jne    L79
L41:
  movzbl -0x1(%rsi),%r8d
  lea    -0x1(%rsi),%rdi
  xor    %edx,%edx
  cmp    %r8b,%r9b
  je     L53
L51:
  mov    %edx,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  int i;
  for (; *s != '\0'; s++)
    ;
  s--;
  for (i = 0; *t != '\0'; t++, i++)
    ;
  t--;
  for (; *s == *t; s--, t--)
    i--;
  if (i)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  mov    $0xffffffff,%eax
  jmp    L24
L6:
  cmpl   $0x1,-0x4(%rbp)
  jg     L22
  mov    $0x1,%eax
  jmp    L24
L22:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial>
  imul   -0x4(%rbp),%eax
L24:
  leave
  ret
```

assistant: ```c
int factorial(int n) {
  if (n < 0)
    return (-1);
  else if (n <= 1)
    return (1);
  return (n * factorial(n - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  test   %edi,%edi
  js     L17
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L7
  lea    -0x1(%rdi),%edi
  call   <factorial>
  imul   %ebx,%eax
L7:
  pop    %rbx
  ret
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  if (n < 0)
    return (-1);
  else if (n <= 1)
    return (1);
  return (n * factorial(n - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  test   %edi,%edi
  js     L13
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L2
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L25
  ret
L13:
  mov    $0xffffffff,%eax
  ret
L2:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n < 0)
    return (-1);
  else if (n <= 1)
    return (1);
  return (n * factorial(n - 1));
}
```
user: What is the c source code of the assembly code below?

```asm
<factorial>:
  endbr64
  test   %edi,%edi
  js     L26
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L27
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L2
  ret
L26:
  mov    $0xffffffff,%eax
  ret
L27:
  ret
```

assistant: ```c
int factorial(int n) {
  if (n < 0)
    return (-1);
  else if (n <= 1)
    return (1);
  return (n * factorial(n - 1));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  mov    $0x0,%esi
  mov    $0x32,%r8d
  mov    $0x0,%r9d
  movabs $0x2c3ce1ec00,%r12
  movabs $0xd79435e50d79436,%rbp
  movabs $0x438558d400,%rbx
  movabs $0x469ee58469ee5847,%r11
L9:
  movsbl %dil,%edi
  sub    $0x41,%edi
  mov    %r9d,%ecx
  imul   %r9d,%ecx
  mov    %edi,%eax
  shl    %cl,%eax
  movslq %eax,%rcx
  lea    (%r8,%r8,2),%rax
  shl    $0x3,%rax
  sub    %r8,%rax
  xor    %rax,%rcx
  add    %r12,%rcx
  mov    %rcx,%rax
  imul   %rbp
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rdx,%rax,2),%rax
  sub    %rax,%rcx
  mov    %rcx,%r8
  lea    (%rsi,%rsi,2),%rax
  shl    $0x3,%rax
  sub    %rsi,%rax
  add    %rbx,%rax
  movslq %edi,%rdi
  imul   %r9,%rdi
  add    %rax,%rdi
  mov    %rdi,%rax
  imul   %r11
  sar    $0x3,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    0x0(,%rsi,8),%rax
  sub    %rsi,%rax
  lea    (%rsi,%rax,4),%rax
  mov    %rdi,%rsi
  sub    %rax,%rsi
  add    $0x1,%r9
  movzbl (%r10,%r9,1),%edi
  test   %dil,%dil
  jne    L9
  lea    D3(%rip),%rax
  mov    (%rax,%rsi,8),%rcx
  cmp    %rsi,%rcx
  je     L13
  movabs $0x2e90edd000,%rax
  add    %rax,%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x3,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x32,%r8d
L13:
  movabs $0x2e90edd000,%rax
  lea    (%r8,%rax,1),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x3,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rdx
  shl    $0x2,%rdx
  mov    %ecx,%eax
  sub    %edx,%eax
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: 

assistant: ```c
int hashString(char *str) {
  static const long long precalculated_table[31] = {0, 4, 2, 16, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 19, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30};
  long long i, ret = 50, sub = 0;
  for (i = 0; str[i] != 0; i++) {
    ret = (190000000000LL + ((ret * 23) ^ ((str[i] - 'A') << i * i))) % 19;
    sub = (290000000000LL + sub * 23 + (str[i] - 'A') * i) % 29;
  }
  return (int)((200000000000LL + (sub != precalculated_table[sub] ? precalculated_table[sub] : ret)) % 20LL);
}
```