ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CmdCounter>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <getBraceParam@plt>
  lea    D37(%rip),%rsi
  mov    $0x4,%edi
  mov    %rax,%rdx
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <diagnostics@plt>
  lea    -0x2(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L85
  cmp    $0x1,%ebx
  je     L43
L54:
  mov    %rbp,%rdi
  call   <free@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L85:
  xor    %eax,%eax
  call   <getBraceParam@plt>
  mov    $0x7b,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L93
  mov    $0x7d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L93
  movb   $0x0,(%rax)
  add    $0x1,%r13
  mov    $0x4,%edi
  xor    %eax,%eax
  mov    %r13,%rdx
  lea    D23(%rip),%rsi
  call   <diagnostics@plt>
  mov    %r13,%rdi
  call   <getCounter@plt>
  mov    %eax,0x4(%rsp)
L106:
  mov    %r12,%rdi
  call   <free@plt>
  cmp    $0x3,%ebx
  je     L102
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <setCounter@plt>
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L93:
  lea    0x4(%rsp),%rdx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L106
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <diagnostics@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <setCounter@plt>
  jmp    L54
  nop
L102:
  mov    %rbp,%rdi
  call   <getCounter@plt>
  add    0x4(%rsp),%eax
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <setCounter@plt>
  jmp    L54
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D37: Entering CmdCounter(), <%s>

tool: D23: CmdCounter() processing \value{%s}

tool: D2: %d

tool: D0: 
Bad parameter in set/addcounter{%s}{%s}

assistant: ```c
void CmdCounter(int code) {
  char *s, *s2, *s3, *s4;
  int num;
  s = getBraceParam();
  diagnostics(4, "Entering CmdCounter(), <%s>", s);
  if (code == 3 || code == 2) {
    s2 = getBraceParam();
    if ((s3 = strchr(s2, '{')) && (s4 = strchr(s2, '}'))) {
      s3++;
      *s4 = '\0';
      diagnostics(4, "CmdCounter() processing \\value{%s}", s3);
      num = getCounter(s3);
    } else if (sscanf(s2, "%d", &num) != 1) {
      diagnostics(1, "\nBad parameter in set/addcounter{%s}{%s}", s, s2);
      free(s2);
      free(s);
      return;
    }
    free(s2);
    if (code == 3)
      setCounter(s, getCounter(s) + num);
    else
      setCounter(s, num);
  } else if (code == 1)
    setCounter(s, 0);
  free(s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L32:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  je     L58
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L32
L58:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L58
  mov    -0x14(%rbp),%eax
  cmp    $0x7,%eax
  jg     L58
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L64
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%eax
  or     %edx,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L50
L64:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
data_type: string

tool: D21: %d

assistant: ```c
int main() {
  int p, n, v;
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v != 0 && v != 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  if (v == 1) {
    printf("%d", n | (1 << p));
  } else {
    printf("%d", n ^ (1 << p));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rbx
L36:
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  ja     L36
  lea    D15(%rip),%rbx
L43:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    $0x7,%ecx
  ja     L43
  cmpl   $0x1,0x14(%rsp)
  je     L7
  mov    $0x1,%esi
  shl    %cl,%esi
  xor    0x10(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  mov    $0x1,%esi
  shl    %cl,%esi
  or     0x10(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D15: %d

assistant: ```c
int main() {
  int p, n, v;
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v != 0 && v != 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  if (v == 1) {
    printf("%d", n | (1 << p));
  } else {
    printf("%d", n ^ (1 << p));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rbx
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  ja     L14
  lea    0xc(%rsp),%rbx
  nop
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    $0x7,%ecx
  ja     L15
  mov    $0x1,%esi
  mov    0x10(%rsp),%eax
  shl    %cl,%esi
  cmpl   $0x1,0x14(%rsp)
  je     L13
  xor    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  or     %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L0
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  int p, n, v;
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v != 0 && v != 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  if (v == 1) {
    printf("%d", n | (1 << p));
  } else {
    printf("%d", n ^ (1 << p));
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x14(%rsp),%rbx
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  ja     L21
  lea    0xc(%rsp),%rbx
  nop
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    $0x7,%ecx
  ja     L13
  mov    $0x1,%esi
  mov    0x10(%rsp),%eax
  shl    %cl,%esi
  cmpl   $0x1,0x14(%rsp)
  je     L12
  xor    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  or     %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L27
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %d

assistant: ```c
int main() {
  int p, n, v;
  scanf("%d", &n);
  do {
    scanf("%d", &v);
  } while (v != 0 && v != 1);
  do {
    scanf("%d", &p);
  } while (p < 0 || p > 7);
  if (v == 1) {
    printf("%d", n | (1 << p));
  } else {
    printf("%d", n ^ (1 << p));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%r12
  mov    %r12,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    %r12,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D37(%rip),%r14
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%ebx
  lea    D17(%rip),%r13
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%r14d
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <my_strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <my_strlen@plt>
  lea    0x2(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <my_strcpy@plt>
  mov    %r13,%rdi
  call   <my_strlen@plt>
  cltq
  movb   $0x20,(%rbx,%rax,1)
  mov    %r13,%rdi
  call   <my_strlen@plt>
  cltq
  lea    0x1(%rbx,%rax,1),%rdi
  mov    %r12,%rsi
  call   <my_strcpy@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <my_strlen@plt>
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L9:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L13:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L6
  orq    $0x0,-0x8(%rsp,%rax,1)
L6:
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <my_strcpy@plt>
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D34
type: string
name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D37
type: string
name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D1
type: string

tool: D34: slack

tool: D14: my_strlen(): %s is %d characters long.


tool: D37: short

tool: D17: super long

tool: D1: my_strcmp(): after: %d, before: %d, and equal: %d


assistant: ```c
int main() {
  char *s1 = "slack";
  int len = my_strlen(s1);
  printf("my_strlen(): %s is %d characters long.\n", s1, len);
  char *s2 = "short";
  char *s3 = "super long";
  char *s4 = "slack";
  int cmp1 = my_strcmp(s1, s2);
  int cmp2 = my_strcmp(s2, s3);
  int cmp3 = my_strcmp(s1, s4);
  printf("my_strcmp(): after: %d, before: %d, and equal: %d\n", cmp1, cmp2, cmp3);
  char *s5 = (char *)malloc(my_strlen(s3) + my_strlen(s1) + 2);
  my_strcpy(s5, s3);
  s5[my_strlen(s3)] = ' ';
  my_strcpy(s5 + my_strlen(s3) + 1, s1);
  printf("%s\n", s5);
  char s6[my_strlen(s5)];
  my_strcpy(s6, s5);
  printf("%s\n", s6);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wHashVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L10:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0xc(%rbp),%eax
  and    $0x3ff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int wHashVal(char *str) {
  unsigned int h;
  unsigned char *p;
  h = 0;
  for (p = (unsigned char *)str; *p != '\0'; p++) {
    h = 31 * h + *p;
  }
  return h % 1024;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wHashVal>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L20
  mov    $0x0,%eax
L0:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  movzbl %dl,%edx
  lea    (%rdx,%rcx,1),%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L0
L3:
  and    $0x3ff,%eax
  ret
L20:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
unsigned int wHashVal(char *str) {
  unsigned int h;
  unsigned char *p;
  h = 0;
  for (p = (unsigned char *)str; *p != '\0'; p++) {
    h = 31 * h + *p;
  }
  return h % 1024;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wHashVal>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L6
  nopl   (%rax)
L5:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  sub    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L5
  and    $0x3ff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
unsigned int wHashVal(char *str) {
  unsigned int h;
  unsigned char *p;
  h = 0;
  for (p = (unsigned char *)str; *p != '\0'; p++) {
    h = 31 * h + *p;
  }
  return h % 1024;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wHashVal>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L17
  nopl   (%rax)
L12:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  sub    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  and    $0x3ff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
unsigned int wHashVal(char *str) {
  unsigned int h;
  unsigned char *p;
  h = 0;
  for (p = (unsigned char *)str; *p != '\0'; p++) {
    h = 31 * h + *p;
  }
  return h % 1024;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<findMedianSortedArrays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r10
  mov    %esi,%edi
  mov    %rdx,%r11
  mov    %ecx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    (%rsi,%rcx,1),%ebx
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L20:
  cmp    %rdx,%rsp
  je     L130
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L20
L130:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L8
  orq    $0x0,-0x8(%rsp,%rax,1)
L8:
  mov    %rsp,%r9
  test   %edi,%edi
  jg     L70
  test   %r8d,%r8d
  jle    L114
L70:
  mov    $0x0,%eax
  mov    $0x0,%esi
L120:
  cmp    %esi,%edi
  jg     L154
  lea    0x1(%rax),%ecx
  lea    (%rcx,%rsi,1),%edx
  movslq %edx,%rdx
  cltq
  mov    (%r11,%rax,4),%eax
  mov    %eax,(%r9,%rdx,4)
  mov    %ecx,%eax
L134:
  cmp    %edi,%esi
  jl     L120
  cmp    %r8d,%eax
  jl     L120
L114:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L85
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cltq
  mov    (%r9,%rax,4),%eax
  add    (%r9,%rdx,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D7(%rip),%xmm0
L146:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  mov    -0x8(%rbp),%rbx
  leave
  ret
L154:
  cmp    %eax,%r8d
  jg     L121
  lea    0x1(%rsi),%ecx
  lea    (%rcx,%rax,1),%edx
  movslq %edx,%rdx
  movslq %esi,%rsi
  mov    (%r10,%rsi,4),%esi
  mov    %esi,(%r9,%rdx,4)
  mov    %ecx,%esi
  jmp    L134
L121:
  movslq %esi,%rdx
  mov    (%r10,%rdx,4),%ecx
  movslq %eax,%rdx
  mov    (%r11,%rdx,4),%edx
  cmp    %edx,%ecx
  jge    L14
  add    $0x1,%esi
L41:
  lea    (%rsi,%rax,1),%edx
  movslq %edx,%rdx
  mov    %ecx,(%r9,%rdx,4)
  jmp    L134
L14:
  add    $0x1,%eax
  mov    %edx,%ecx
  jmp    L41
L85:
  sub    $0x1,%ebx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  cltq
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%r9,%rax,4),%xmm0
  jmp    L146
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1Size, int *nums2, int nums2Size) {
  int c1, c2;
  c1 = c2 = 0;
  int sumSize = nums1Size + nums2Size;
  int sArray[sumSize];
  while (c1 < nums1Size || c2 < nums2Size) {
    if (c1 >= nums1Size) {
      sArray[c1 + c2] = nums2[c2++];
    } else if (c2 >= nums2Size) {
      sArray[c1 + c2] = nums1[c1++];
    } else {
      sArray[c1 + c2] = nums1[c1] < nums2[c2] ? nums1[c1++] : nums2[c2++];
    }
  }
  if (1 == sumSize % 2)
    return (double)sArray[(sumSize - 1) / 2];
  else
    return (double)(sArray[(sumSize / 2) - 1] + sArray[sumSize / 2]) / 2;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %rbp
  mov    %rdi,%r11
  mov    %rdx,%r10
  mov    %ecx,%edi
  mov    %rsp,%rbp
  push   %rbx
  lea    (%rsi,%rcx,1),%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movslq %ebx,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L85:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L85
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L22
  mov    %rsp,%r9
  test   %edi,%edi
  jg     L172
L15:
  test   %esi,%esi
  jle    L127
L172:
  xor    %eax,%eax
  xor    %edx,%edx
L73:
  cmp    %edx,%esi
  jg     L168
  lea    0x1(%rax),%r8d
  cltq
  mov    (%r10,%rax,4),%eax
  lea    (%r8,%rdx,1),%ecx
  movslq %ecx,%rcx
  mov    %eax,(%r9,%rcx,4)
  mov    %r8d,%eax
L96:
  cmp    %esi,%edx
  jl     L73
  cmp    %edi,%eax
  jl     L73
L127:
  mov    %ebx,%edx
  shr    $0x1f,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L80
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  lea    -0x1(%rax),%edx
  cltq
  movslq %edx,%rdx
  mov    (%r9,%rax,4),%eax
  add    (%r9,%rdx,4),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D4(%rip),%xmm0
L54:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   0x0(%rax)
L168:
  movslq %edx,%rcx
  mov    (%r11,%rcx,4),%ecx
  cmp    %eax,%edi
  jg     L136
  add    $0x1,%edx
  lea    (%rdx,%rax,1),%r8d
  movslq %r8d,%r8
  mov    %ecx,(%r9,%r8,4)
  jmp    L96
  nopl   0x0(%rax,%rax,1)
L136:
  movslq %eax,%r8
  mov    (%r10,%r8,4),%r8d
  cmp    %ecx,%r8d
  jle    L77
  add    $0x1,%edx
L101:
  lea    (%rdx,%rax,1),%r8d
  movslq %r8d,%r8
  mov    %ecx,(%r9,%r8,4)
  jmp    L96
  nop
L77:
  add    $0x1,%eax
  mov    %r8d,%ecx
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L80:
  sub    $0x1,%ebx
  pxor   %xmm0,%xmm0
  sar    %ebx
  movslq %ebx,%rax
  cvtsi2sdl (%r9,%rax,4),%xmm0
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L22:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%r9
  test   %edi,%edi
  jle    L15
  jmp    L172
L110:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1Size, int *nums2, int nums2Size) {
  int c1, c2;
  c1 = c2 = 0;
  int sumSize = nums1Size + nums2Size;
  int sArray[sumSize];
  while (c1 < nums1Size || c2 < nums2Size) {
    if (c1 >= nums1Size) {
      sArray[c1 + c2] = nums2[c2++];
    } else if (c2 >= nums2Size) {
      sArray[c1 + c2] = nums1[c1++];
    } else {
      sArray[c1 + c2] = nums1[c1] < nums2[c2] ? nums1[c1++] : nums2[c2++];
    }
  }
  if (1 == sumSize % 2)
    return (double)sArray[(sumSize - 1) / 2];
  else
    return (double)(sArray[(sumSize / 2) - 1] + sArray[sumSize / 2]) / 2;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findMedianSortedArrays>:
  endbr64
  push   %rbp
  lea    (%rsi,%rcx,1),%r10d
  mov    %rdx,%r9
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movslq %r10d,%rax
  mov    %rsp,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rdi,%rsp
  je     L87
L67:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L67
L87:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L65
  mov    %rsp,%r8
  test   %ecx,%ecx
  jg     L46
L129:
  test   %esi,%esi
  jle    L64
L46:
  xor    %edx,%edx
  xor    %eax,%eax
L100:
  cmp    %eax,%esi
  jg     L106
  lea    0x1(%rdx),%edi
  movslq %edx,%r11
  mov    (%r9,%r11,4),%r11d
  lea    (%rdi,%rax,1),%esi
  movslq %esi,%rsi
  mov    %r11d,(%r8,%rsi,4)
  cmp    %edi,%ecx
  jg     1060 <findMedianSortedArrays.cold>
  jmp    L64
  nopl   0x0(%rax)
L106:
  movslq %eax,%rdi
  mov    (%rbx,%rdi,4),%edi
  cmp    %edx,%ecx
  jg     L4
  add    $0x1,%eax
  lea    (%rax,%rdx,1),%r11d
  movslq %r11d,%r11
  mov    %edi,(%r8,%r11,4)
L75:
  cmp    %edx,%ecx
  jg     L100
  cmp    %esi,%eax
  jl     L100
L64:
  mov    %r10d,%edx
  shr    $0x1f,%edx
  lea    (%r10,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L70
  mov    %r10d,%eax
  pxor   %xmm0,%xmm0
  shr    $0x1f,%eax
  add    %r10d,%eax
  sar    %eax
  lea    -0x1(%rax),%edx
  cltq
  movslq %edx,%rdx
  mov    (%r8,%rax,4),%eax
  add    (%r8,%rdx,4),%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
L111:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   0x0(%rax)
L4:
  movslq %edx,%r11
  mov    (%r9,%r11,4),%r11d
  cmp    %edi,%r11d
  jle    L171
  add    $0x1,%eax
L117:
  lea    (%rax,%rdx,1),%r11d
  movslq %r11d,%r11
  mov    %edi,(%r8,%r11,4)
  jmp    L75
  nopl   0x0(%rax)
L171:
  add    $0x1,%edx
  mov    %r11d,%edi
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L70:
  sub    $0x1,%r10d
  pxor   %xmm0,%xmm0
  sar    %r10d
  movslq %r10d,%rax
  cvtsi2sdl (%r8,%rax,4),%xmm0
  jmp    L111
  cs nopw 0x0(%rax,%rax,1)
L65:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  mov    %rsp,%r8
  test   %ecx,%ecx
  jle    L129
  jmp    L46
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1Size, int *nums2, int nums2Size) {
  int c1, c2;
  c1 = c2 = 0;
  int sumSize = nums1Size + nums2Size;
  int sArray[sumSize];
  while (c1 < nums1Size || c2 < nums2Size) {
    if (c1 >= nums1Size) {
      sArray[c1 + c2] = nums2[c2++];
    } else if (c2 >= nums2Size) {
      sArray[c1 + c2] = nums1[c1++];
    } else {
      sArray[c1 + c2] = nums1[c1] < nums2[c2] ? nums1[c1++] : nums2[c2++];
    }
  }
  if (1 == sumSize % 2)
    return (double)sArray[(sumSize - 1) / 2];
  else
    return (double)(sArray[(sumSize / 2) - 1] + sArray[sumSize / 2]) / 2;
  return 0;
}
```