ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x2cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  nop
  movzwl -0xa(%rbp),%eax
  add    $0x537d,%ax
  lea    (%rax,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << (unsigned short)1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0xb0(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << (unsigned short)1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0xb0(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < (unsigned short)0) {
      local2 = 0UL;
      while (local2 < (unsigned short)0) {
        state[0UL] |= (((state[local2] << (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)) | (state[local2] >> (16 - (((state[0UL] >> (unsigned short)1) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
        state[0UL] |= ((state[local2] ^ state[local1]) & (unsigned short)31) << 4UL;
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 255873917UL) << (unsigned short)1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<readmstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <readmsg@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <readstring@plt>
  mov    %eax,-0x4(%rbp)
L9:
  cmpl   $0x1,-0x4(%rbp)
  jne    L15
  mov    $0x0,%eax
  call   <readmend@plt>
  mov    %eax,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int readmstr(int msg, char **buf) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readstring(buf);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<readmstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L2
L19:
  pop    %rbx
  ret
L2:
  mov    %rbx,%rdi
  call   <readstring@plt>
  cmp    $0x1,%eax
  jne    L19
  mov    $0x0,%eax
  call   <readmend@plt>
  jmp    L19
```

assistant: ```c
int readmstr(int msg, char **buf) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readstring(buf);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readmstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L14
L10:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rdi
  call   <readstring@plt>
  cmp    $0x1,%eax
  jne    L10
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <readmend@plt>
```

assistant: ```c
int readmstr(int msg, char **buf) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readstring(buf);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readmstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <readmsg@plt>
  cmp    $0x1,%eax
  je     L11
L15:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  mov    %rbp,%rdi
  call   <readstring@plt>
  cmp    $0x1,%eax
  jne    L15
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <readmend@plt>
```

assistant: ```c
int readmstr(int msg, char **buf) {
  int x;
  x = readmsg(msg);
  if (x == (1))
    x = readstring(buf);
  if (x == (1))
    x = readmend();
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PSG_setTone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movq   $0xc00011,-0x8(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x5,%eax
  and    $0x60,%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  and    $0xf,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  movzwl -0x18(%rbp),%eax
  shr    $0x4,%ax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PSG_setTone(unsigned char channel, unsigned short value) {
  volatile unsigned char *pb;
  pb = (unsigned char *)0xC00011;
  *pb = 0x80 | ((channel & 3) << 5) | (value & 0xF);
  *pb = (value >> 4) & 0x3F;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PSG_setTone>:
  endbr64
  shl    $0x5,%edi
  and    $0x60,%edi
  mov    %esi,%eax
  and    $0xf,%eax
  or     %eax,%edi
  or     $0xffffff80,%edi
  mov    %dil,0xc00011
  shr    $0x4,%si
  and    $0x3f,%esi
  mov    %sil,0xc00011
  ret
```

assistant: ```c
void PSG_setTone(unsigned char channel, unsigned short value) {
  volatile unsigned char *pb;
  pb = (unsigned char *)0xC00011;
  *pb = 0x80 | ((channel & 3) << 5) | (value & 0xF);
  *pb = (value >> 4) & 0x3F;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PSG_setTone>:
  endbr64
  mov    %esi,%eax
  shl    $0x5,%edi
  and    $0x60,%edi
  and    $0xf,%eax
  shr    $0x4,%si
  or     %eax,%edi
  and    $0x3f,%esi
  or     $0xffffff80,%edi
  mov    %dil,0xc00011
  mov    %sil,0xc00011
  ret
```

assistant: ```c
void PSG_setTone(unsigned char channel, unsigned short value) {
  volatile unsigned char *pb;
  pb = (unsigned char *)0xC00011;
  *pb = 0x80 | ((channel & 3) << 5) | (value & 0xF);
  *pb = (value >> 4) & 0x3F;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<PSG_setTone>:
  endbr64
  mov    %esi,%eax
  shl    $0x5,%edi
  and    $0x60,%edi
  and    $0xf,%eax
  shr    $0x4,%si
  or     %eax,%edi
  and    $0x3f,%esi
  or     $0xffffff80,%edi
  mov    %dil,0xc00011
  mov    %sil,0xc00011
  ret
```

assistant: ```c
void PSG_setTone(unsigned char channel, unsigned short value) {
  volatile unsigned char *pb;
  pb = (unsigned char *)0xC00011;
  *pb = 0x80 | ((channel & 3) << 5) | (value & 0xF);
  *pb = (value >> 4) & 0x3F;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L24
L1:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L24:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D18:  %d

tool: D9: %d^2 = %d


assistant: ```c
int main() {
  int N = 0, i = 2;
  scanf(" %d", &N);
  while (i <= N) {
    printf("%d^2 = %d\n", i, i * i);
    i += 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L7
  mov    $0x2,%ebx
  lea    D17(%rip),%rbp
L2:
  mov    %ebx,%edx
  imul   %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L2
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D13:  %d

tool: D17: %d^2 = %d


assistant: ```c
int main() {
  int N = 0, i = 2;
  scanf(" %d", &N);
  while (i <= N) {
    printf("%d^2 = %d\n", i, i * i);
    i += 2;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L12
  mov    $0x2,%ebx
  lea    D10(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   %ebx,%edx
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L8
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D10
type: string

tool: D16:  %d

tool: D10: %d^2 = %d


assistant: ```c
int main() {
  int N = 0, i = 2;
  scanf(" %d", &N);
  while (i <= N) {
    printf("%d^2 = %d\n", i, i * i);
    i += 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  cmpl   $0x1,0x4(%rsp)
  jle    L23
  mov    $0x2,%ebx
  lea    D8(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  imul   %ebx,%edx
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L18
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D2:  %d

tool: D8: %d^2 = %d


assistant: ```c
int main() {
  int N = 0, i = 2;
  scanf(" %d", &N);
  while (i <= N) {
    printf("%d^2 = %d\n", i, i * i);
    i += 2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sigterm_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <shutdown_routine@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void sigterm_handler(int sig) {
  if (sig == SIGTERM)
    shutdown_routine();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sigterm_handler>:
  endbr64
  mov    D7(%rip),%rax
  cmp    %edi,(%rax)
  je     L6
  ret
L6:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <shutdown_routine@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sigterm_handler(int sig) {
  if (sig == SIGTERM)
    shutdown_routine();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sigterm_handler>:
  endbr64
  mov    D3(%rip),%rax
  cmp    %edi,(%rax)
  je     L0
  ret
L0:
  xor    %eax,%eax
  jmp    1050 <shutdown_routine@plt>
```

assistant: ```c
void sigterm_handler(int sig) {
  if (sig == SIGTERM)
    shutdown_routine();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sigterm_handler>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %edi,(%rax)
  je     L5
  ret
L5:
  xor    %eax,%eax
  jmp    1050 <shutdown_routine@plt>
```

assistant: ```c
void sigterm_handler(int sig) {
  if (sig == SIGTERM)
    shutdown_routine();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <lock_demo@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  lock_demo();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <lock_demo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lock_demo();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lock_demo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lock_demo();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <lock_demo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  lock_demo();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pcshft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  -0x14(%rbp),%xmm1
  movss  D9(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L0
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movss  -0x8(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  movss  -0x14(%rbp),%xmm0
  movaps %xmm0,%xmm1
  addss  -0x18(%rbp),%xmm1
  movss  D0(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L54
L58:
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L34
L56:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mulss  -0x4(%rbp),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  subl   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L56
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L58
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: f32
name: unpack_data
arguments: tag: D0
type_guessed: f32

tool: D9: 2

tool: D0: 0.5

assistant: ```c
void pcshft(float a, float b, float d[], int n) {
  int k, j;
  float fac, cnst;
  cnst = 2.0 / (b - a);
  fac = cnst;
  for (j = 1; j < n; j++) {
    d[j] *= fac;
    fac *= cnst;
  }
  cnst = 0.5 * (a + b);
  for (j = 0; j <= n - 2; j++)
    for (k = n - 2; k >= j; k--)
      d[k] -= cnst * d[k + 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pcshft>:
  endbr64
  mov    %rdi,%r9
  movaps %xmm1,%xmm2
  subss  %xmm0,%xmm2
  movss  D11(%rip),%xmm4
  divss  %xmm2,%xmm4
  cmp    $0x1,%esi
  jle    L41
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rdx
  movaps %xmm4,%xmm2
L36:
  movaps %xmm2,%xmm3
  mulss  (%rax),%xmm3
  movss  %xmm3,(%rax)
  mulss  %xmm4,%xmm2
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L36
  addss  %xmm0,%xmm1
  mulss  D16(%rip),%xmm1
  lea    -0x1(%rsi),%edi
  lea    -0x2(%rsi),%r8d
  movslq %r8d,%rax
  lea    (%r9,%rax,4),%r10
  movslq %esi,%rax
  mov    $0x0,%ecx
  mov    %r8d,%esi
  lea    -0xc(%r9,%rax,4),%r9
L40:
  cmp    %ecx,%esi
  jl     L45
  mov    %r8d,%eax
  sub    %ecx,%eax
  shl    $0x2,%rax
  mov    %r9,%rdx
  sub    %rax,%rdx
  mov    %r10,%rax
L9:
  movaps %xmm1,%xmm2
  mulss  0x4(%rax),%xmm2
  movss  (%rax),%xmm0
  subss  %xmm2,%xmm0
  movss  %xmm0,(%rax)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
L45:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jg     L40
  ret
L41:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: f32
name: unpack_data
arguments: data_label: D16
type: f32

tool: D11: 2

tool: D16: 0.5

assistant: ```c
void pcshft(float a, float b, float d[], int n) {
  int k, j;
  float fac, cnst;
  cnst = 2.0 / (b - a);
  fac = cnst;
  for (j = 1; j < n; j++) {
    d[j] *= fac;
    fac *= cnst;
  }
  cnst = 0.5 * (a + b);
  for (j = 0; j <= n - 2; j++)
    for (k = n - 2; k >= j; k--)
      d[k] -= cnst * d[k + 1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pcshft>:
  endbr64
  movaps %xmm1,%xmm2
  lea    -0x1(%rsi),%r8d
  addss  %xmm0,%xmm1
  mov    %rdi,%r10
  subss  %xmm0,%xmm2
  movss  D15(%rip),%xmm3
  mulss  D5(%rip),%xmm1
  divss  %xmm2,%xmm3
  cmp    $0x1,%esi
  jle    L4
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  movaps %xmm3,%xmm0
  mov    %rdx,%rdi
  lea    0x8(%r10,%rdx,4),%rdx
  nopl   (%rax)
L29:
  movss  (%rax),%xmm2
  add    $0x4,%rax
  mulss  %xmm0,%xmm2
  mulss  %xmm3,%xmm0
  movss  %xmm2,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L29
L12:
  movslq %edi,%rax
  movslq %esi,%rsi
  xor    %ecx,%ecx
  lea    (%r10,%rax,4),%r9
  lea    -0xc(%r10,%rsi,4),%rsi
  nopl   0x0(%rax,%rax,1)
L46:
  cmp    %edi,%ecx
  jg     L23
  mov    %edi,%eax
  mov    %rsi,%rdx
  sub    %ecx,%eax
  shl    $0x2,%rax
  sub    %rax,%rdx
  mov    %r9,%rax
  nopl   (%rax)
L24:
  movss  0x4(%rax),%xmm2
  movss  (%rax),%xmm0
  sub    $0x4,%rax
  mulss  %xmm1,%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,0x4(%rax)
  cmp    %rax,%rdx
  jne    L24
L23:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jl     L46
  ret
L4:
  test   %r8d,%r8d
  jg     L8
  ret
L8:
  lea    -0x2(%rsi),%edi
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: f32
name: extract_symbolic_data
arguments: data_label: D5
type_infered: f32

tool: D15: 2

tool: D5: 0.5

assistant: ```c
void pcshft(float a, float b, float d[], int n) {
  int k, j;
  float fac, cnst;
  cnst = 2.0 / (b - a);
  fac = cnst;
  for (j = 1; j < n; j++) {
    d[j] *= fac;
    fac *= cnst;
  }
  cnst = 0.5 * (a + b);
  for (j = 0; j <= n - 2; j++)
    for (k = n - 2; k >= j; k--)
      d[k] -= cnst * d[k + 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pcshft>:
  endbr64
  movaps %xmm1,%xmm2
  movss  D12(%rip),%xmm3
  addss  %xmm0,%xmm1
  mov    %rdi,%rdx
  subss  %xmm0,%xmm2
  mulss  D11(%rip),%xmm1
  divss  %xmm2,%xmm3
  cmp    $0x1,%esi
  jle    L8
  lea    -0x2(%rsi),%ecx
  lea    0x4(%rdi),%rax
  movaps %xmm3,%xmm0
  mov    %rcx,%rdi
  lea    0x8(%rdx,%rcx,4),%rcx
  nopl   (%rax)
L15:
  movss  (%rax),%xmm2
  add    $0x4,%rax
  mulss  %xmm0,%xmm2
  mulss  %xmm3,%xmm0
  movss  %xmm2,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L15
  movslq %esi,%rsi
  xor    %ecx,%ecx
  lea    (%rdx,%rsi,4),%r8
  movslq %edi,%rsi
  cs nopw 0x0(%rax,%rax,1)
L5:
  movss  -0x4(%r8),%xmm0
  mov    %rsi,%rax
  nopl   0x0(%rax)
L6:
  movaps %xmm0,%xmm2
  movss  (%rdx,%rax,4),%xmm0
  mulss  %xmm1,%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  sub    $0x1,%rax
  cmp    %eax,%ecx
  jle    L6
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jle    L5
  ret
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: f32
name: retrieve_data
arguments: label: D11
type_infered: f32

tool: D12: 2

tool: D11: 0.5

assistant: ```c
void pcshft(float a, float b, float d[], int n) {
  int k, j;
  float fac, cnst;
  cnst = 2.0 / (b - a);
  fac = cnst;
  for (j = 1; j < n; j++) {
    d[j] *= fac;
    fac *= cnst;
  }
  cnst = 0.5 * (a + b);
  for (j = 0; j <= n - 2; j++)
    for (k = n - 2; k >= j; k--)
      d[k] -= cnst * d[k + 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: string

tool: D2:  %d

assistant: ```c
void print(int a[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", a[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D2(%rip),%rbp
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L8
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2:  %d

assistant: ```c
void print(int a[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", a[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8:  %d

assistant: ```c
void print(int a[], int n) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", a[i]);
  printf("\n");
}
```