ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_refine_buffer>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  mov    %rdi,%rax
  mov    %rdi,%rsi
  mov    $0x0,%r8d
  jmp    L18
L9:
  mov    %rsi,%rcx
  cmpb   $0xa,0x1(%rsi)
  je     L0
L75:
  mov    %r8d,%edx
L84:
  mov    %dl,(%rax)
  lea    0x1(%rcx),%rsi
  add    $0x1,%rax
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L23
L18:
  cmp    $0xa,%dl
  je     L20
  mov    %rsi,%rcx
  cmp    $0xd,%dl
  jne    L84
L20:
  cmp    $0xd,%dl
  je     L9
  mov    %rsi,%rcx
  cmpb   $0xd,0x1(%rsi)
  jne    L75
L0:
  lea    0x1(%rsi),%rcx
  jmp    L75
L7:
  mov    %rdi,%rax
L23:
  movb   $0x0,(%rax)
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
```

assistant: ```c
int str_refine_buffer(char *buf) {
  char *src = buf, *dest = buf;
  while (*src) {
    if (*src == 0x0A || *src == 0x0D) {
      if ((*src == 0x0D && *(src + 1) == 0x0A) || (*src == 0x0A && *(src + 1) == 0x0D))
        src++;
      *dest = '\0';
    } else
      *dest = *src;
    src++;
    dest++;
  }
  *dest = '\0';
  return dest - buf + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_refine_buffer>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  test   %al,%al
  je     L66
  mov    %rdi,%rsi
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %al,(%rdx)
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%rsi
  add    $0x1,%rdx
  test   %al,%al
  je     L28
L57:
  cmp    $0xa,%al
  je     L1
  mov    %rsi,%rcx
  cmp    $0xd,%al
  jne    L34
L1:
  movzbl 0x1(%rsi),%r8d
  cmp    $0xd,%al
  je     L42
  mov    %rsi,%rcx
  cmp    $0xd,%r8b
  je     L93
L69:
  xor    %eax,%eax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %rsi,%rcx
  cmp    $0xa,%r8b
  jne    L69
L93:
  lea    0x1(%rsi),%rcx
  xor    %eax,%eax
  jmp    L34
  nopl   0x0(%rax)
L28:
  mov    %rdx,%rax
  movb   $0x0,(%rdx)
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   (%rax)
L66:
  movb   $0x0,(%rdx)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int str_refine_buffer(char *buf) {
  char *src = buf, *dest = buf;
  while (*src) {
    if (*src == 0x0A || *src == 0x0D) {
      if ((*src == 0x0D && *(src + 1) == 0x0A) || (*src == 0x0A && *(src + 1) == 0x0D))
        src++;
      *dest = '\0';
    } else
      *dest = *src;
    src++;
    dest++;
  }
  *dest = '\0';
  return dest - buf + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_refine_buffer>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  test   %al,%al
  je     L77
  mov    %rdi,%rsi
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %al,(%rdx)
  movzbl 0x1(%rcx),%eax
  lea    0x1(%rcx),%rsi
  add    $0x1,%rdx
  test   %al,%al
  je     L81
L53:
  cmp    $0xa,%al
  je     L44
  mov    %rsi,%rcx
  cmp    $0xd,%al
  jne    L51
L44:
  movzbl 0x1(%rsi),%r8d
  cmp    $0xd,%al
  je     L65
  mov    %rsi,%rcx
  cmp    $0xd,%r8b
  je     L1
L6:
  xor    %eax,%eax
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %rsi,%rcx
  cmp    $0xa,%r8b
  jne    L6
L1:
  lea    0x1(%rsi),%rcx
  xor    %eax,%eax
  jmp    L51
  nopl   0x0(%rax)
L81:
  mov    %rdx,%rax
  movb   $0x0,(%rdx)
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   (%rax)
L77:
  movb   $0x0,(%rdx)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int str_refine_buffer(char *buf) {
  char *src = buf, *dest = buf;
  while (*src) {
    if (*src == 0x0A || *src == 0x0D) {
      if ((*src == 0x0D && *(src + 1) == 0x0A) || (*src == 0x0A && *(src + 1) == 0x0D))
        src++;
      *dest = '\0';
    } else
      *dest = *src;
    src++;
    dest++;
  }
  *dest = '\0';
  return dest - buf + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L11:
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x2,-0xc(%rbp)
  jle    L11
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D25
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D3: cosm1

tool: D25: # c::cephes::%s


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cosm1");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D27(%rip),%r13
  lea    D17(%rip),%r12
  lea    D13(%rip),%rbp
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L6
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string

tool: D27: cosm1

tool: D17: # c::cephes::%s


tool: D13: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cosm1");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D13(%rip),%r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D17
type: string
name: unpack_data
arguments: data_tag: D20
type: string

tool: D13: cosm1

tool: D17: # c::cephes::%s


tool: D20: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cosm1");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D9(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string

tool: D9: cosm1

tool: D0: # c::cephes::%s


tool: D27: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "cosm1");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_numconst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <bwx_DEBUG@plt>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  mov    $0x0,%eax
  jmp    L28
L57:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L45
  mov    $0x0,%eax
  jmp    L28
L45:
  nop
  addq   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0xffffffff,%eax
L28:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: is_numconst

assistant: ```c
int is_numconst(char *buffer) {
  char *p;
  bwx_DEBUG(__FUNCTION__);
  if (buffer[0] == '\0') {
    return 0;
  }
  p = buffer;
  while (*p != '\0') {
    switch (*p) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      break;
    default:
      return 0;
    }
    ++p;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_numconst>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <bwx_DEBUG@plt>
  movzbl (%rbx),%eax
  mov    $0x0,%edx
  test   %al,%al
  je     L18
L15:
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L1
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L15
  mov    $0xffffffff,%edx
  jmp    L18
L1:
  mov    $0x0,%edx
L18:
  mov    %edx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string

tool: D9: is_numconst

assistant: ```c
int is_numconst(char *buffer) {
  char *p;
  bwx_DEBUG(__FUNCTION__);
  if (buffer[0] == '\0') {
    return 0;
  }
  p = buffer;
  while (*p != '\0') {
    switch (*p) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      break;
    default:
      return 0;
    }
    ++p;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_numconst>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  call   <bwx_DEBUG@plt>
  movsbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L23
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L33
L23:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L36
  xor    %r8d,%r8d
L15:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L33:
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: is_numconst

assistant: ```c
int is_numconst(char *buffer) {
  char *p;
  bwx_DEBUG(__FUNCTION__);
  if (buffer[0] == '\0') {
    return 0;
  }
  p = buffer;
  while (*p != '\0') {
    switch (*p) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      break;
    default:
      return 0;
    }
    ++p;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_numconst>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  call   <bwx_DEBUG@plt>
  movsbl (%rbx),%eax
  xor    %r8d,%r8d
  test   %al,%al
  jne    L25
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L33:
  movsbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L17
L25:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L33
  xor    %r8d,%r8d
L20:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: is_numconst

assistant: ```c
int is_numconst(char *buffer) {
  char *p;
  bwx_DEBUG(__FUNCTION__);
  if (buffer[0] == '\0') {
    return 0;
  }
  p = buffer;
  while (*p != '\0') {
    switch (*p) {
    case '0':
    case '1':
    case '2':
    case '3':
    case '4':
    case '5':
    case '6':
    case '7':
    case '8':
    case '9':
      break;
    default:
      return 0;
    }
    ++p;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *f5(char *s) {
  s[0] = '-';
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f5>:
  endbr64
  mov    %rdi,%rax
  movb   $0x2d,(%rdi)
  ret
```

assistant: ```c
char *f5(char *s) {
  s[0] = '-';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f5>:
  endbr64
  movb   $0x2d,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *f5(char *s) {
  s[0] = '-';
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f5>:
  endbr64
  movb   $0x2d,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *f5(char *s) {
  s[0] = '-';
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<spechar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ch@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L129
L27:
  cmpb   $0x6e,-0x5(%rbp)
  jne    L30
  movb   $0xa,-0x5(%rbp)
  jmp    L155
L30:
  cmpb   $0x74,-0x5(%rbp)
  jne    L167
  movb   $0x9,-0x5(%rbp)
  jmp    L155
L167:
  cmpb   $0x72,-0x5(%rbp)
  jne    L13
  movb   $0xd,-0x5(%rbp)
  jmp    L155
L13:
  cmpb   $0x66,-0x5(%rbp)
  jne    L52
  movb   $0xc,-0x5(%rbp)
  jmp    L155
L52:
  cmpb   $0x62,-0x5(%rbp)
  jne    L100
  movb   $0x8,-0x5(%rbp)
  jmp    L155
L100:
  cmpb   $0x2f,-0x5(%rbp)
  jle    L155
  cmpb   $0x37,-0x5(%rbp)
  jg     L155
  movsbl -0x5(%rbp),%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gch@plt>
  mov    $0x0,%eax
  call   <ch@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x2f,-0x5(%rbp)
  jle    L116
  cmpb   $0x37,-0x5(%rbp)
  jle    L51
L116:
  mov    -0x4(%rbp),%eax
  jmp    L129
L51:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  movsbl -0x5(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gch@plt>
  mov    $0x0,%eax
  call   <ch@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x2f,-0x5(%rbp)
  jle    L82
  cmpb   $0x37,-0x5(%rbp)
  jle    L198
L82:
  mov    -0x4(%rbp),%eax
  jmp    L129
L198:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  movsbl -0x5(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gch@plt>
  mov    -0x4(%rbp),%eax
  jmp    L129
L155:
  mov    $0x0,%eax
  call   <gch@plt>
  movsbl -0x5(%rbp),%eax
L129:
  leave
  ret
```

assistant: ```c
spechar() {
  char c;
  c = ch();
  if (c == 0)
    return 0;
  else if (c == 'n')
    c = 10;
  else if (c == 't')
    c = 9;
  else if (c == 'r')
    c = 13;
  else if (c == 'f')
    c = 12;
  else if (c == 'b')
    c = 8;
  else if (c >= '0' && c <= '7') {
    int n = c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    return n;
  }
  gch();
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<spechar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ch@plt>
  mov    $0x0,%ebp
  test   %al,%al
  je     L103
  mov    %eax,%ebx
  cmp    $0x37,%al
  jle    L100
  lea    -0x62(%rbx),%eax
  cmp    $0x12,%al
  ja     L106
  lea    -0x62(%rbx),%eax
  cmp    $0x12,%al
  ja     L106
  movzbl %al,%eax
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L100:
  cmp    $0x2f,%al
  jg     L62
L106:
  mov    $0x0,%eax
  call   <gch@plt>
  movsbl %bl,%ebp
L103:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  mov    $0x9,%ebx
  jmp    L106
  mov    $0xc,%ebx
  jmp    L106
  mov    $0x8,%ebx
  jmp    L106
L62:
  movsbl %al,%ebp
  sub    $0x30,%ebp
  mov    $0x0,%eax
  call   <gch@plt>
  mov    $0x0,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L103
  movsbl %al,%eax
  lea    -0x30(%rax,%rbp,8),%ebp
  mov    $0x0,%eax
  call   <gch@plt>
  mov    $0x0,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L103
  movsbl %al,%eax
  lea    -0x30(%rax,%rbp,8),%ebp
  mov    $0x0,%eax
  call   <gch@plt>
  jmp    L103
  mov    $0xa,%ebx
  jmp    L106
  mov    $0xd,%ebx
  jmp    L106
```

assistant: ```c
spechar() {
  char c;
  c = ch();
  if (c == 0)
    return 0;
  else if (c == 'n')
    c = 10;
  else if (c == 't')
    c = 9;
  else if (c == 'r')
    c = 13;
  else if (c == 'f')
    c = 12;
  else if (c == 'b')
    c = 8;
  else if (c >= '0' && c <= '7') {
    int n = c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    return n;
  }
  gch();
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<spechar>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <ch@plt>
  test   %al,%al
  je     L111
  cmp    $0x37,%al
  jle    L10
  lea    -0x62(%rax),%edx
  cmp    $0x12,%dl
  ja     L11
  lea    D4(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
L10:
  cmp    $0x2f,%al
  jg     L97
L11:
  movsbl %al,%r12d
L86:
  xor    %eax,%eax
  call   <gch@plt>
L111:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
  mov    $0xa,%r12d
  jmp    L86
  nopl   0x0(%rax,%rax,1)
  mov    $0x8,%r12d
  jmp    L86
  nopl   0x0(%rax,%rax,1)
  mov    $0xc,%r12d
  jmp    L86
  nopl   0x0(%rax,%rax,1)
  mov    $0x9,%r12d
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L97:
  sub    $0x30,%eax
  movsbl %al,%r12d
  xor    %eax,%eax
  call   <gch@plt>
  xor    %eax,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L111
  movsbl %al,%eax
  lea    -0x30(%rax,%r12,8),%r12d
  xor    %eax,%eax
  call   <gch@plt>
  xor    %eax,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L111
  movsbl %al,%eax
  lea    -0x30(%rax,%r12,8),%r12d
  xor    %eax,%eax
  call   <gch@plt>
  jmp    L111
  nopl   0x0(%rax,%rax,1)
  mov    $0xd,%r12d
  jmp    L86
```

assistant: ```c
spechar() {
  char c;
  c = ch();
  if (c == 0)
    return 0;
  else if (c == 'n')
    c = 10;
  else if (c == 't')
    c = 9;
  else if (c == 'r')
    c = 13;
  else if (c == 'f')
    c = 12;
  else if (c == 'b')
    c = 8;
  else if (c >= '0' && c <= '7') {
    int n = c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    return n;
  }
  gch();
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spechar>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <ch@plt>
  test   %al,%al
  je     L19
  cmp    $0x37,%al
  jle    L118
  lea    -0x62(%rax),%edx
  cmp    $0x12,%dl
  ja     L14
  lea    D2(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
L118:
  cmp    $0x2f,%al
  jg     L21
L14:
  movsbl %al,%r12d
L88:
  xor    %eax,%eax
  call   <gch@plt>
L19:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
  mov    $0xa,%r12d
  jmp    L88
  nopl   0x0(%rax,%rax,1)
  mov    $0x8,%r12d
  jmp    L88
  nopl   0x0(%rax,%rax,1)
  mov    $0xc,%r12d
  jmp    L88
  nopl   0x0(%rax,%rax,1)
  mov    $0x9,%r12d
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x30,%eax
  movsbl %al,%r12d
  xor    %eax,%eax
  call   <gch@plt>
  xor    %eax,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L19
  movsbl %al,%eax
  lea    -0x30(%rax,%r12,8),%r12d
  xor    %eax,%eax
  call   <gch@plt>
  xor    %eax,%eax
  call   <ch@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x7,%dl
  ja     L19
  movsbl %al,%eax
  lea    -0x30(%rax,%r12,8),%r12d
  xor    %eax,%eax
  call   <gch@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
  mov    $0xd,%r12d
  jmp    L88
```

assistant: ```c
spechar() {
  char c;
  c = ch();
  if (c == 0)
    return 0;
  else if (c == 'n')
    c = 10;
  else if (c == 't')
    c = 9;
  else if (c == 'r')
    c = 13;
  else if (c == 'f')
    c = 12;
  else if (c == 'b')
    c = 8;
  else if (c >= '0' && c <= '7') {
    int n = c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    c = ch();
    if (c < '0' || c > '7')
      return n;
    n = (n << 3) + c - '0';
    gch();
    return n;
  }
  gch();
  return c;
}
```