user: What would the C source look like for the assembly code provided here:

```asm
<div_factor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L105
L104:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L62
L76:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  sub    $0x30,%eax
  movsbl %al,%esi
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <subtract@plt>
  subl   $0x1,-0x20(%rbp)
L62:
  cmpl   $0x0,-0x20(%rbp)
  jns    L76
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L105
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L43
  mov    -0x14(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movl   $0x0,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
  jmp    L105
L43:
  cmpl   $0x0,-0x4(%rbp)
  jne    L105
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L37
L90:
  addl   $0x1,-0x20(%rbp)
L37:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    %eax,-0x8(%rbp)
  je     L90
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x2f,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L105
  mov    -0x14(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movl   $0x0,-0x14(%rbp)
  addl   $0x1,-0x1c(%rbp)
L105:
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L104
  mov    -0x14(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void div_factor(char *dividend, char *divisor, char *answer) {
  int i, d1_head;
  int d1_len = strlen(dividend) - 1;
  int d2_len = strlen(divisor) - 1;
  int d2_head = *(divisor) - '0';
  int j = 0;
  int head = 0;
  int total = 0;
  while (j < (d1_len - d2_len)) {
    for (i = d2_len; i >= 0; i--)
      subtract(dividend, *(divisor + i) - '0', head, i + j);
    d1_head = *(dividend + head) - '0';
    total++;
    if (d1_head < d2_head) {
      if (head == j) {
        *(answer + j) = total + '0';
        total = 0;
        j++;
      } else if (d1_head == 0) {
        head++;
        for (i = head; *(dividend + i) - '0' == d2_head; i++)
          ;
        if (*(dividend + i) - '0' < d2_head) {
          *(answer + j) = total + '0';
          total = 0;
          j++;
        }
      }
    }
  }
  *(answer + j) = total + '0';
  *(answer + j + 1) = '\0';
}
```