ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printIncSeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L39
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArr@plt>
  jmp    L6
L39:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L56
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  jmp    L18
L56:
  mov    $0x1,%eax
L18:
  mov    %eax,-0x4(%rbp)
  jmp    L35
L27:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <printIncSeq>
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L27
L6:
  leave
  ret
```

assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    return;
  }
  for (int i = len > 0 ? arr[len - 1] + 1 : 1; i <= n; i++) {
    arr[len] = i;
    printIncSeq(n, m, len + 1, arr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printIncSeq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  mov    %rcx,%r12
  cmp    %esi,%edx
  je     L0
  mov    %edi,%ebp
  mov    $0x1,%ebx
  test   %edx,%edx
  jle    L17
  movslq %edx,%rax
  mov    -0x4(%rcx,%rax,4),%ebx
  add    $0x1,%ebx
L17:
  cmp    %ebp,%ebx
  jg     L31
  movslq %edx,%rax
  lea    (%r12,%rax,4),%r14
  lea    0x1(%rdx),%r15d
L14:
  mov    %ebx,(%r14)
  mov    %r12,%rcx
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <printIncSeq>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L14
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    %rcx,%rdi
  call   <printArr@plt>
  jmp    L31
```

assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    return;
  }
  for (int i = len > 0 ? arr[len - 1] + 1 : 1; i <= n; i++) {
    arr[len] = i;
    printIncSeq(n, m, len + 1, arr);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<printIncSeq>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%edx
  je     L14
  mov    %edi,%r12d
  mov    %esi,%r15d
  mov    $0x1,%ebx
  test   %edx,%edx
  jle    L5
  movslq %edx,%rax
  mov    -0x4(%rcx,%rax,4),%ebx
  add    $0x1,%ebx
L5:
  cmp    %r12d,%ebx
  jg     L36
  movslq %edx,%rax
  lea    0x1(%rdx),%ebp
  lea    0x0(%r13,%rax,4),%r14
L20:
  mov    %ebx,(%r14)
  mov    %r13,%rcx
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <printIncSeq>
  cmp    %ebx,%r12d
  jge    L20
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  add    $0x8,%rsp
  mov    %edx,%esi
  mov    %rcx,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printArr@plt>
```

assistant: ```c
void printIncSeq(int n, int m, int len, int arr[]) {
  if (len == m) {
    printArr(arr, m);
    return;
  }
  for (int i = len > 0 ? arr[len - 1] + 1 : 1; i <= n; i++) {
    arr[len] = i;
    printIncSeq(n, m, len + 1, arr);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<procstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pushstr@plt>
  nop
  leave
  ret
```

assistant: ```c
void procstr(char *cmd) {
  cmd++;
  if (cmd[strlen(cmd) - 1] == '"')
    cmd[strlen(cmd) - 1] = '\0';
  pushstr(cmd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<procstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x1(%rdi),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,(%rbx,%rax,1)
  je     L1
L10:
  mov    %rbp,%rdi
  call   <pushstr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,(%rbx,%rax,1)
  jmp    L10
```

assistant: ```c
void procstr(char *cmd) {
  cmd++;
  if (cmd[strlen(cmd) - 1] == '"')
    cmd[strlen(cmd) - 1] = '\0';
  pushstr(cmd);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<procstr>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmpb   $0x22,(%rbx,%rax,1)
  je     L3
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <pushstr@plt>
  nop
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  movb   $0x0,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <pushstr@plt>
```

assistant: ```c
void procstr(char *cmd) {
  cmd++;
  if (cmd[strlen(cmd) - 1] == '"')
    cmd[strlen(cmd) - 1] = '\0';
  pushstr(cmd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<procstr>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmpb   $0x22,(%rbx,%rax,1)
  je     L5
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <pushstr@plt>
  nop
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  cltq
  movb   $0x0,(%rbx,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <pushstr@plt>
```

assistant: ```c
void procstr(char *cmd) {
  cmd++;
  if (cmd[strlen(cmd) - 1] == '"')
    cmd[strlen(cmd) - 1] = '\0';
  pushstr(cmd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_isalnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L6
  cmpl   $0x5a,-0x4(%rbp)
  jle    L15
L6:
  cmpl   $0x60,-0x4(%rbp)
  jle    L12
  cmpl   $0x7a,-0x4(%rbp)
  jle    L15
L12:
  cmpl   $0x2f,-0x4(%rbp)
  jle    L61
  cmpl   $0x39,-0x4(%rbp)
  jg     L61
L15:
  mov    $0x1,%eax
  jmp    L17
L61:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isalnum(int c) {
  if ((c >= 65 && c <= 90) || (c >= 97 && c <= 122) || (c >= '0' && c <= '9'))
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_isalnum>:
  endbr64
  mov    %edi,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  mov    $0x1,%edx
  cmp    $0x19,%eax
  jbe    L9
  sub    $0x30,%edi
  cmp    $0x9,%edi
  setbe  %dl
  movzbl %dl,%edx
L9:
  mov    %edx,%eax
  ret
```

assistant: ```c
int ft_isalnum(int c) {
  if ((c >= 65 && c <= 90) || (c >= 97 && c <= 122) || (c >= '0' && c <= '9'))
    return (1);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isalnum>:
  endbr64
  mov    %edi,%eax
  mov    $0x1,%r8d
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  jbe    L6
  sub    $0x30,%edi
  xor    %r8d,%r8d
  cmp    $0x9,%edi
  setbe  %r8b
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_isalnum(int c) {
  if ((c >= 65 && c <= 90) || (c >= 97 && c <= 122) || (c >= '0' && c <= '9'))
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_isalnum>:
  endbr64
  mov    %edi,%eax
  mov    $0x1,%r8d
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%eax
  jbe    L6
  sub    $0x30,%edi
  xor    %r8d,%r8d
  cmp    $0x9,%edi
  setbe  %r8b
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_isalnum(int c) {
  if ((c >= 65 && c <= 90) || (c >= 97 && c <= 122) || (c >= '0' && c <= '9'))
    return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D10
type_guessed: string

tool: D11: in func before swap a = %d; b = %d;


tool: D10: in func after swap a = %d; b = %d;


assistant: ```c
void swap(int a, int b) {
  int temp = 0;
  printf("in func before swap a = %d; b = %d;\n", a, b);
  temp = a;
  a = b;
  b = temp;
  printf("in func after swap a = %d; b = %d;\n", a, b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string

tool: D14: in func before swap a = %d; b = %d;


tool: D16: in func after swap a = %d; b = %d;


assistant: ```c
void swap(int a, int b) {
  int temp = 0;
  printf("in func before swap a = %d; b = %d;\n", a, b);
  temp = a;
  a = b;
  b = temp;
  printf("in func after swap a = %d; b = %d;\n", a, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string

tool: D0: in func before swap a = %d; b = %d;


tool: D11: in func after swap a = %d; b = %d;


assistant: ```c
void swap(int a, int b) {
  int temp = 0;
  printf("in func before swap a = %d; b = %d;\n", a, b);
  temp = a;
  a = b;
  b = temp;
  printf("in func after swap a = %d; b = %d;\n", a, b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string
name: disassemble_data
arguments: label: D5
type: string

tool: D9: in func before swap a = %d; b = %d;


tool: D5: in func after swap a = %d; b = %d;


assistant: ```c
void swap(int a, int b) {
  int temp = 0;
  printf("in func before swap a = %d; b = %d;\n", a, b);
  temp = a;
  a = b;
  b = temp;
  printf("in func after swap a = %d; b = %d;\n", a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mymkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1fd,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mkdir@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mymkdir(dirname) const char *dirname;
{
  int ret = 0;
  ret = mkdir(dirname, 0775);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mymkdir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1fd,%esi
  mov    $0x0,%eax
  call   <mkdir@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int mymkdir(dirname) const char *dirname;
{
  int ret = 0;
  ret = mkdir(dirname, 0775);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mymkdir>:
  endbr64
  mov    $0x1fd,%esi
  xor    %eax,%eax
  jmp    1050 <mkdir@plt>
```

assistant: ```c
int mymkdir(dirname) const char *dirname;
{
  int ret = 0;
  ret = mkdir(dirname, 0775);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mymkdir>:
  endbr64
  mov    $0x1fd,%esi
  xor    %eax,%eax
  jmp    1050 <mkdir@plt>
```

assistant: ```c
int mymkdir(dirname) const char *dirname;
{
  int ret = 0;
  ret = mkdir(dirname, 0775);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UI_ProportionalSizeScale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L14
  movss  D13(%rip),%xmm0
  jmp    L37
L14:
  mov    -0x4(%rbp),%eax
  and    $0x20000,%eax
  test   %eax,%eax
  je     L17
  movss  D21(%rip),%xmm0
  jmp    L37
L17:
  movss  D10(%rip),%xmm0
L37:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: f32
name: unpack_data
arguments: data_label: D21
data_type: f32
name: unpack_data
arguments: data_label: D10
data_type: byte[4]

tool: D13: 0.75

tool: D21: 0.4

tool: {"D10": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  if (style & 0x00020000) {
    return 0.4;
  }
  return 1.0f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<UI_ProportionalSizeScale>:
  endbr64
  movss  D9(%rip),%xmm0
  test   $0x10,%dil
  jne    L2
  movss  D20(%rip),%xmm0
  test   $0x20000,%edi
  jne    L25
L2:
  ret
L25:
  movss  D14(%rip),%xmm0
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: f32
name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: f32

tool: D9: 0.75

tool: {"D20": [0x00,0x00,0x80,0x3f]}

tool: D14: 0.4

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  if (style & 0x00020000) {
    return 0.4;
  }
  return 1.0f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UI_ProportionalSizeScale>:
  endbr64
  movss  D10(%rip),%xmm0
  test   $0x10,%dil
  jne    L14
  and    $0x20000,%edi
  movss  D24(%rip),%xmm0
  jne    L16
L14:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movss  D1(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type: f32
name: parse_data
arguments: tag: D24
type: byte[4]
name: parse_data
arguments: tag: D1
type: f32

tool: D10: 0.75

tool: {"D24": [0x00,0x00,0x80,0x3f]}

tool: D1: 0.4

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  if (style & 0x00020000) {
    return 0.4;
  }
  return 1.0f;
}
```
user: What is the c source code of the assembly code below:

```asm
<UI_ProportionalSizeScale>:
  endbr64
  movss  D3(%rip),%xmm0
  test   $0x10,%dil
  jne    L2
  and    $0x20000,%edi
  movss  D16(%rip),%xmm0
  jne    L15
L2:
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movss  D8(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: f32
name: parse_data
arguments: tag: D16
type_guessed: byte[4]
name: parse_data
arguments: tag: D8
type_guessed: f32

tool: D3: 0.75

tool: {"D16": [0x00,0x00,0x80,0x3f]}

tool: D8: 0.4

assistant: ```c
float UI_ProportionalSizeScale(int style) {
  if (style & 0x00000010) {
    return 0.75;
  }
  if (style & 0x00020000) {
    return 0.4;
  }
  return 1.0f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x10,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t ts(int32_t track, int32_t sector) {
  int sectors_per_track = 16;
  return ((track * sectors_per_track) + sector) * 256;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ts>:
  endbr64
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%eax
  shl    $0x8,%eax
  ret
```

assistant: ```c
uint32_t ts(int32_t track, int32_t sector) {
  int sectors_per_track = 16;
  return ((track * sectors_per_track) + sector) * 256;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ts>:
  endbr64
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%eax
  shl    $0x8,%eax
  ret
```

assistant: ```c
uint32_t ts(int32_t track, int32_t sector) {
  int sectors_per_track = 16;
  return ((track * sectors_per_track) + sector) * 256;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ts>:
  endbr64
  shl    $0x4,%edi
  lea    (%rdi,%rsi,1),%eax
  shl    $0x8,%eax
  ret
```

assistant: ```c
uint32_t ts(int32_t track, int32_t sector) {
  int sectors_per_track = 16;
  return ((track * sectors_per_track) + sector) * 256;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<counter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  jle    L37
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x6,%eax
  jg     L37
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L14
L37:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xa,%eax
  jne    L14
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L14:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int counter(int *val, int *count) {
  if ((*val > 2) && (*val < 7)) {
    *count = *count + 1;
  } else if (*val == 10) {
    *count = *count - 1;
  }
  return *count;
}
```
user: What is the c source code of the assembly code below?

```asm
<counter>:
  endbr64
  mov    (%rdi),%eax
  lea    -0x3(%rax),%edx
  cmp    $0x3,%edx
  ja     L20
  addl   $0x1,(%rsi)
L15:
  mov    (%rsi),%eax
  ret
L20:
  cmp    $0xa,%eax
  jne    L15
  subl   $0x1,(%rsi)
  jmp    L15
```

assistant: ```c
int counter(int *val, int *count) {
  if ((*val > 2) && (*val < 7)) {
    *count = *count + 1;
  } else if (*val == 10) {
    *count = *count - 1;
  }
  return *count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<counter>:
  endbr64
  mov    (%rdi),%edx
  mov    (%rsi),%eax
  lea    -0x3(%rdx),%ecx
  cmp    $0x3,%ecx
  ja     L16
  add    $0x1,%eax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  cmp    $0xa,%edx
  je     L1
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
int counter(int *val, int *count) {
  if ((*val > 2) && (*val < 7)) {
    *count = *count + 1;
  } else if (*val == 10) {
    *count = *count - 1;
  }
  return *count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<counter>:
  endbr64
  mov    (%rdi),%edx
  mov    (%rsi),%eax
  lea    -0x3(%rdx),%ecx
  cmp    $0x3,%ecx
  ja     L18
  add    $0x1,%eax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  cmp    $0xa,%edx
  je     L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
int counter(int *val, int *count) {
  if ((*val > 2) && (*val < 7)) {
    *count = *count + 1;
  } else if (*val == 10) {
    *count = *count - 1;
  }
  return *count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fc8180_set_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x5(%rbp)
  mov    $0x5c490,%eax
  mov    $0x0,%edx
  divl   -0x20(%rbp)
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    $0xd1b71759,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0xd,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x4,%edx
  jbe    L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  add    $0x1,%eax
  mov    %al,-0x5(%rbp)
  jmp    L5
L7:
  mov    -0x4(%rbp),%eax
  mov    $0xffffffcd,%edx
  mul    %dl
  shr    $0x8,%ax
  shr    $0x3,%al
  mov    %al,-0x5(%rbp)
L5:
  movzbl -0x5(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int fc8180_set_filter(void *handle, unsigned int ref_clock, unsigned int filter_bw) {
  unsigned int div_cal = 0;
  unsigned char div = 0;
  div_cal = (378000 / filter_bw) * ref_clock / 10000;
  if ((div_cal % 10) >= 5)
    div = (unsigned char)(div_cal / 10) + 1;
  else
    div = (unsigned char)div_cal / 10;
  return div;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fc8180_set_filter>:
  endbr64
  mov    %edx,%ecx
  mov    $0x5c490,%eax
  mov    $0x0,%edx
  div    %ecx
  imul   %esi,%eax
  mov    $0xd1b71759,%edx
  imul   %rdx,%rax
  shr    $0x2d,%rax
  mov    %eax,%edx
  mov    $0xcccccccd,%ecx
  imul   %rcx,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %eax,%ecx
  sub    %edx,%ecx
  cmp    $0x4,%ecx
  jbe    L10
  mov    %eax,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  add    $0x1,%eax
L17:
  movzbl %al,%eax
  ret
L10:
  mov    $0xffffffcd,%edx
  mul    %dl
  shr    $0xb,%ax
  jmp    L17
```

assistant: ```c
unsigned int fc8180_set_filter(void *handle, unsigned int ref_clock, unsigned int filter_bw) {
  unsigned int div_cal = 0;
  unsigned char div = 0;
  div_cal = (378000 / filter_bw) * ref_clock / 10000;
  if ((div_cal % 10) >= 5)
    div = (unsigned char)(div_cal / 10) + 1;
  else
    div = (unsigned char)div_cal / 10;
  return div;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fc8180_set_filter>:
  endbr64
  mov    %edx,%r8d
  mov    $0x5c490,%eax
  xor    %edx,%edx
  mov    $0xcccccccd,%ecx
  div    %r8d
  mov    $0xd1b71759,%edx
  imul   %esi,%eax
  imul   %rdx,%rax
  shr    $0x2d,%rax
  mov    %eax,%edx
  mov    %eax,%esi
  imul   %rcx,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%esi
  cmp    $0x4,%esi
  jbe    L0
  lea    0x1(%rdx),%eax
  movzbl %al,%eax
  ret
  nopl   (%rax)
L0:
  mov    $0xffffffcd,%edx
  mul    %dl
  shr    $0xb,%ax
  movzbl %al,%eax
  ret
```

assistant: ```c
unsigned int fc8180_set_filter(void *handle, unsigned int ref_clock, unsigned int filter_bw) {
  unsigned int div_cal = 0;
  unsigned char div = 0;
  div_cal = (378000 / filter_bw) * ref_clock / 10000;
  if ((div_cal % 10) >= 5)
    div = (unsigned char)(div_cal / 10) + 1;
  else
    div = (unsigned char)div_cal / 10;
  return div;
}
```