ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_erase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L7
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <erase@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L10
L7:
  nop
L10:
  leave
  ret
```

assistant: ```c
void cmd_erase(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(erase());
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmd_erase>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L2
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    $0x0,%eax
  call   <erase@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_erase(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(erase());
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_erase>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <erase@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_erase(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(erase());
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmd_erase>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L5
  mov    $0x1,%edi
  call   <report_count@plt>
  xor    %eax,%eax
  call   <erase@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cmd_erase(int nargs, char **args) {
  if (check_arg_count(nargs, 0) == 1)
    return;
  report_count(1);
  report_return(erase());
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x61,-0x1(%rbp)
  movb   $0x6b,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: character: %c

assistant: ```c
int main(int argc, char *argv[]) {
  char character = 'a';
  character = 'k';
  printf("character: %c", character);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6b,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D8: character: %c

assistant: ```c
int main(int argc, char *argv[]) {
  char character = 'a';
  character = 'k';
  printf("character: %c", character);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6b,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: character: %c

assistant: ```c
int main(int argc, char *argv[]) {
  char character = 'a';
  character = 'k';
  printf("character: %c", character);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6b,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: character: %c

assistant: ```c
int main(int argc, char *argv[]) {
  char character = 'a';
  character = 'k';
  printf("character: %c", character);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_screen() {
  initscr();
  noecho();
  cbreak();
  refresh();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_screen>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    $0x0,%eax
  call   <cbreak@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_screen() {
  initscr();
  noecho();
  cbreak();
  refresh();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_screen>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <refresh@plt>
```

assistant: ```c
void init_screen() {
  initscr();
  noecho();
  cbreak();
  refresh();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_screen>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initscr@plt>
  xor    %eax,%eax
  call   <noecho@plt>
  xor    %eax,%eax
  call   <cbreak@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <refresh@plt>
```

assistant: ```c
void init_screen() {
  initscr();
  noecho();
  cbreak();
  refresh();
}
```
user: Translate the below assembly code into C programming language:

```asm
<dependsOnValueOfPtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L37
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L37:
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L30
L29:
  nop
L30:
  leave
  ret
```

assistant: ```c
void dependsOnValueOfPtr(int *g, unsigned f) {
  int *p;
  if (f) {
    p = g;
  } else {
    p = malloc(12);
  }
  if (p != g)
    free(p);
  else
    return;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dependsOnValueOfPtr>:
  endbr64
  test   %esi,%esi
  je     L8
  ret
L8:
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %rbx,%rax
  je     L7
  call   <free@plt>
L7:
  pop    %rbx
  ret
```

assistant: ```c
void dependsOnValueOfPtr(int *g, unsigned f) {
  int *p;
  if (f) {
    p = g;
  } else {
    p = malloc(12);
  }
  if (p != g)
    free(p);
  else
    return;
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dependsOnValueOfPtr>:
  endbr64
  test   %esi,%esi
  je     L12
  ret
  nopl   0x0(%rax)
L12:
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %rbx,%rax
  je     L3
  pop    %rbx
  jmp    1060 <free@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
void dependsOnValueOfPtr(int *g, unsigned f) {
  int *p;
  if (f) {
    p = g;
  } else {
    p = malloc(12);
  }
  if (p != g)
    free(p);
  else
    return;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dependsOnValueOfPtr>:
  endbr64
  test   %esi,%esi
  je     L6
  ret
  nopl   0x0(%rax)
L6:
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    %rbx,%rax
  je     L3
  pop    %rbx
  jmp    1060 <free@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
void dependsOnValueOfPtr(int *g, unsigned f) {
  int *p;
  if (f) {
    p = g;
  } else {
    p = malloc(12);
  }
  if (p != g)
    free(p);
  else
    return;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L38
  movl   $0x0,-0x14(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L0
  negl   -0x24(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L0:
  mov    -0x24(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L3
L38:
  cmpl   $0x0,-0x24(%rbp)
  jns    L42
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    $0x30,%eax
  sub    %edx,%eax
  mov    %eax,%ebx
  jmp    L15
L42:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  mov    %eax,%ebx
L15:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <itoa>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %bl,(%rax)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int itoa(int n, char s[]) {
  int i;
  if (!(n / 10)) {
    i = 0;
    if (n < 0) {
      n = -n;
      s[i++] = '-';
    }
    s[i++] = n + '0';
  } else {
    s[i = itoa(n / 10, s)] = (n < 0 ? -(n % 10) : n % 10) + '0';
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%edx
  mov    %rsi,%rbx
  lea    0x9(%rdi),%eax
  cmp    $0x12,%eax
  ja     L7
  mov    $0x0,%ecx
  test   %edi,%edi
  js     L56
L21:
  lea    0x1(%rcx),%eax
  movslq %ecx,%rcx
  add    $0x30,%edx
  mov    %dl,(%rbx,%rcx,1)
L42:
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L56:
  neg    %edx
  movb   $0x2d,(%rsi)
  mov    $0x1,%ecx
  jmp    L21
L7:
  test   %edi,%edi
  js     L4
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edi,%ebp
  sub    %eax,%ebp
  add    $0x30,%ebp
L32:
  movslq %edx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%edx
  sub    %edx,%edi
  mov    %rbx,%rsi
  call   <itoa>
  movslq %eax,%rdx
  mov    %bpl,(%rbx,%rdx,1)
  add    $0x1,%eax
  jmp    L42
L4:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ebp
  add    %ebp,%ebp
  sub    %edi,%ebp
  add    $0x30,%ebp
  jmp    L32
```

assistant: ```c
int itoa(int n, char s[]) {
  int i;
  if (!(n / 10)) {
    i = 0;
    if (n < 0) {
      n = -n;
      s[i++] = '-';
    }
    s[i++] = n + '0';
  } else {
    s[i = itoa(n / 10, s)] = (n < 0 ? -(n % 10) : n % 10) + '0';
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  push   %rbp
  lea    0x9(%rdi),%eax
  mov    %edi,%edx
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x12,%eax
  ja     L15
  test   %edi,%edi
  js     L23
  mov    $0x1,%ecx
  mov    $0x1,%eax
L29:
  add    $0x30,%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L15:
  movslq %edi,%rdi
  mov    %edx,%eax
  imul   $0x66666667,%rdi,%rdi
  sar    $0x1f,%eax
  sar    $0x22,%rdi
  sub    %eax,%edi
  mov    %edx,%eax
  lea    (%rdi,%rdi,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    $0x30,%ecx
  sub    %eax,%ecx
  add    $0x30,%eax
  test   %edx,%edx
  cmovns %eax,%ecx
  mov    %ecx,%ebp
  call   <itoa>
  movslq %eax,%rdx
  add    $0x1,%eax
  movslq %eax,%rcx
  mov    %bpl,(%rbx,%rdx,1)
  movb   $0x0,(%rbx,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  movb   $0x2d,(%rbx)
  lea    0x1(%rsi),%rsi
  neg    %edx
  mov    $0x2,%ecx
  mov    $0x2,%eax
  jmp    L29
```

assistant: ```c
int itoa(int n, char s[]) {
  int i;
  if (!(n / 10)) {
    i = 0;
    if (n < 0) {
      n = -n;
      s[i++] = '-';
    }
    s[i++] = n + '0';
  } else {
    s[i = itoa(n / 10, s)] = (n < 0 ? -(n % 10) : n % 10) + '0';
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_vx_vy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <print_ophead@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  and    $0xf,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: V%X, V%X


assistant: ```c
void print_vx_vy(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, V%X\n", (op & 0x0F00) >> 8, (op & 0x00F0) >> 4);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_vx_vy>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  mov    %ebx,%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  sar    $0x8,%ebx
  mov    %ebx,%esi
  and    $0xf,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: V%X, V%X


assistant: ```c
void print_vx_vy(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, V%X\n", (op & 0x0F00) >> 8, (op & 0x00F0) >> 4);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_vx_vy>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  mov    %ebx,%edx
  sar    $0x8,%ebx
  lea    D6(%rip),%rdi
  mov    %ebx,%esi
  sar    $0x4,%edx
  pop    %rbx
  and    $0xf,%edx
  and    $0xf,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: V%X, V%X


assistant: ```c
void print_vx_vy(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, V%X\n", (op & 0x0F00) >> 8, (op & 0x00F0) >> 4);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_vx_vy>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <print_ophead@plt>
  mov    %ebx,%edx
  sar    $0x8,%ebx
  lea    D6(%rip),%rdi
  mov    %ebx,%esi
  sar    $0x4,%edx
  pop    %rbx
  and    $0xf,%edx
  and    $0xf,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: V%X, V%X


assistant: ```c
void print_vx_vy(uint16_t op, const char *name, int index) {
  print_ophead(op, name, index);
  printf("V%X, V%X\n", (op & 0x0F00) >> 8, (op & 0x00F0) >> 4);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<file_type>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbx
  mov    %rdi,%rbx
  lea    D11(%rip),%rsi
  call   <strcmp@plt>
  mov    $0x2,%edx
  test   %rax,%rax
  je     L148
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jle    L62
  movslq %eax,%rdx
  cmpb   $0x2e,-0x2(%rbx,%rdx,1)
  je     L124
L62:
  mov    $0x0,%edx
  cmp    $0x4,%eax
  jle    L148
  cltq
  cmpb   $0x2e,-0x4(%rbx,%rax,1)
  je     L139
L148:
  mov    %edx,%eax
  pop    %rbx
  ret
L124:
  movzbl -0x1(%rbx,%rdx,1),%edx
  and    $0xffffffdf,%edx
  cmp    $0x43,%dl
  je     L78
  cmp    $0x48,%dl
  jne    L62
L78:
  mov    $0x1,%edx
  jmp    L148
L139:
  lea    -0x3(%rbx,%rax,1),%rbx
  lea    D68(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x2,%edx
  test   %rax,%rax
  je     L148
  lea    D35(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x2,%edx
  test   %rax,%rax
  je     L148
  lea    D59(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x3,%edx
  test   %rax,%rax
  je     L148
  lea    D58(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x3,%edx
  test   %rax,%rax
  je     L148
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    $0x4,%edx
  test   %rax,%rax
  je     L148
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  shl    $0x2,%edx
  jmp    L148
L15:
  mov    $0x2,%edx
  mov    %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: string
name: retrieve_data
arguments: tag: D68
type: string
name: retrieve_data
arguments: tag: D35
type: string
name: retrieve_data
arguments: tag: D59
type: string
name: retrieve_data
arguments: tag: D58
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D47
type: string

tool: D11: -

tool: D68: txt

tool: D35: TXT

tool: D59: fnt

tool: D58: FNT

tool: D25: bmp

tool: D47: BMP

assistant: ```c
int file_type(const char *c) {
  int n;
  if (c == NULL || strcmp(c, "-") == 0)
    return 2;
  n = (int)strlen(c);
  if (n >= 3 && c[n - 2] == '.' && (c[n - 1] == 'c' || c[n - 1] == 'C' || c[n - 1] == 'h' || c[n - 1] == 'H'))
    return 1;
  if (n < 5 || c[n - 4] != '.')
    return 0;
  if (strcmp(c + n - 3, "txt") == 0 || strcmp(c + n - 3, "TXT") == 0)
    return 2;
  if (strcmp(c + n - 3, "fnt") == 0 || strcmp(c + n - 3, "FNT") == 0)
    return 3;
  if (strcmp(c + n - 3, "bmp") == 0 || strcmp(c + n - 3, "BMP") == 0)
    return 4;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_type>:
  endbr64
  test   %rdi,%rdi
  je     L145
  push   %rbp
  lea    D27(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x2,%eax
  jle    L114
  movslq %eax,%rdx
  cmpb   $0x2e,-0x2(%rbx,%rdx,1)
  je     L33
L41:
  xor    %r8d,%r8d
  cmp    $0x4,%eax
  jle    L114
  cmpb   $0x2e,-0x4(%rbx,%rdx,1)
  je     L89
L114:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L82:
  add    $0x8,%rsp
  mov    $0x2,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L89:
  lea    -0x3(%rbx,%rdx,1),%rbp
  lea    D64(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  lea    D63(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L82
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L101
  lea    D53(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L101
  lea    D50(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    $0x4,%r8d
  test   %rax,%rax
  je     L114
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
  shl    $0x2,%r8d
  jmp    L114
  nopl   0x0(%rax)
L33:
  movzbl -0x1(%rbx,%rdx,1),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x43,%cl
  je     L19
  cmp    $0x48,%cl
  jne    L41
L19:
  mov    $0x1,%r8d
  jmp    L114
  nopl   0x0(%rax)
L145:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L101:
  mov    $0x3,%r8d
  jmp    L114
```

tool_calls: name: read_data
arguments: label: D27
data_type: string
name: read_data
arguments: label: D64
data_type: string
name: read_data
arguments: label: D63
data_type: string
name: read_data
arguments: label: D23
data_type: string
name: read_data
arguments: label: D53
data_type: string
name: read_data
arguments: label: D50
data_type: string
name: read_data
arguments: label: D39
data_type: string

tool: D27: -

tool: D64: txt

tool: D63: TXT

tool: D23: fnt

tool: D53: FNT

tool: D50: bmp

tool: D39: BMP

assistant: ```c
int file_type(const char *c) {
  int n;
  if (c == NULL || strcmp(c, "-") == 0)
    return 2;
  n = (int)strlen(c);
  if (n >= 3 && c[n - 2] == '.' && (c[n - 1] == 'c' || c[n - 1] == 'C' || c[n - 1] == 'h' || c[n - 1] == 'H'))
    return 1;
  if (n < 5 || c[n - 4] != '.')
    return 0;
  if (strcmp(c + n - 3, "txt") == 0 || strcmp(c + n - 3, "TXT") == 0)
    return 2;
  if (strcmp(c + n - 3, "fnt") == 0 || strcmp(c + n - 3, "FNT") == 0)
    return 3;
  if (strcmp(c + n - 3, "bmp") == 0 || strcmp(c + n - 3, "BMP") == 0)
    return 4;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_type>:
  endbr64
  test   %rdi,%rdi
  je     L35
  push   %rbp
  lea    D48(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L126
  mov    %rbx,%rdi
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    $0x2,%eax
  jle    L12
  movslq %eax,%rdx
  cmpb   $0x2e,-0x2(%rbx,%rdx,1)
  je     L71
L132:
  xor    %r8d,%r8d
  cmp    $0x4,%eax
  jle    L12
  cmpb   $0x2e,-0x4(%rbx,%rdx,1)
  je     L109
L12:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L126:
  add    $0x8,%rsp
  mov    $0x2,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L109:
  lea    -0x3(%rbx,%rdx,1),%rbp
  lea    D58(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L126
  lea    D39(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L126
  lea    D51(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L77
  lea    D33(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L77
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    $0x4,%r8d
  test   %rax,%rax
  je     L12
  lea    D57(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
  shl    $0x2,%r8d
  jmp    L12
  nopl   0x0(%rax)
L71:
  movzbl -0x1(%rbx,%rdx,1),%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x43,%cl
  je     L101
  cmp    $0x48,%cl
  jne    L132
L101:
  mov    $0x1,%r8d
  jmp    L12
  nopl   0x0(%rax)
L35:
  mov    $0x2,%eax
  ret
  xchg   %ax,%ax
L77:
  mov    $0x3,%r8d
  jmp    L12
```

tool_calls: name: parse_data
arguments: data_label: D48
type: string
name: parse_data
arguments: data_label: D58
type: string
name: parse_data
arguments: data_label: D39
type: string
name: parse_data
arguments: data_label: D51
type: string
name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D37
type: string
name: parse_data
arguments: data_label: D57
type: string

tool: D48: -

tool: D58: txt

tool: D39: TXT

tool: D51: fnt

tool: D33: FNT

tool: D37: bmp

tool: D57: BMP

assistant: ```c
int file_type(const char *c) {
  int n;
  if (c == NULL || strcmp(c, "-") == 0)
    return 2;
  n = (int)strlen(c);
  if (n >= 3 && c[n - 2] == '.' && (c[n - 1] == 'c' || c[n - 1] == 'C' || c[n - 1] == 'h' || c[n - 1] == 'H'))
    return 1;
  if (n < 5 || c[n - 4] != '.')
    return 0;
  if (strcmp(c + n - 3, "txt") == 0 || strcmp(c + n - 3, "TXT") == 0)
    return 2;
  if (strcmp(c + n - 3, "fnt") == 0 || strcmp(c + n - 3, "FNT") == 0)
    return 3;
  if (strcmp(c + n - 3, "bmp") == 0 || strcmp(c + n - 3, "BMP") == 0)
    return 4;
  return 0;
}
```