ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<at_tok_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L25
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  add    $0x1,%rax
  mov    %rax,(%rbx)
  mov    $0x0,%eax
L39:
  pop    %rbx
  ret
L34:
  movq   $0x0,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L39
L25:
  mov    $0xffffffff,%eax
  jmp    L39
```

assistant: ```c
int at_tok_char(char **p_cur) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, '(');
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<at_tok_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L15
  add    $0x1,%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  movq   $0x0,(%rbx)
L8:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int at_tok_char(char **p_cur) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, '(');
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<at_tok_char>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  mov    $0x28,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  add    $0x1,%rax
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
L12:
  movq   $0x0,(%rbx)
L8:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int at_tok_char(char **p_cur) {
  if (*p_cur == NULL) {
    return -1;
  }
  *p_cur = strchr(*p_cur, '(');
  if (*p_cur == NULL) {
    return -1;
  }
  (*p_cur)++;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memrchr32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x28(%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%rax
  add    %ecx,%eax
  lea    (%rdx,%rax,1),%r13d
  jmp    L71
L22:
  mov    (%rbx),%eax
  xor    %r13d,%eax
  mov    %eax,%r12d
  mov    %r12d,%eax
  lea    -0x1010101(%rax),%edx
  mov    %r12d,%eax
  not    %eax
  and    %edx,%eax
  and    $0x80808080,%eax
  test   %eax,%eax
  jne    L39
  subq   $0x4,-0x30(%rbp)
  sub    $0x4,%rbx
L71:
  cmpq   $0x3,-0x30(%rbp)
  ja     L22
  jmp    L58
L39:
  nop
  jmp    L58
L61:
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  add    %rbx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L58
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  add    %rbx,%rax
  jmp    L14
L58:
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  test   %rax,%rax
  jne    L61
  mov    $0x0,%eax
L14:
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void *memrchr32(const void *s, uint8_t c, size_t n) {
  register const uint32_t *ip;
  register const uint8_t *p;
  register uint32_t mask;
  register uint32_t x;
  ip = (const uint32_t *)((const uint8_t *)s + n - 1 - sizeof(uint32_t));
  mask = ((((uint32_t)c) << 24) + (((uint32_t)c) << 16) + ((((uint32_t)c) << 8) + ((uint32_t)c)));
  while (n >= sizeof(uint32_t)) {
    x = *ip ^ mask;
    if ((x - 0x01010101U) & ~x & 0x80808080U)
      break;
    n -= sizeof(uint32_t);
    ip--;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (p[n] == c)
      return ((void *)(p + n));
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memrchr32>:
  endbr64
  lea    -0x28(%rdi,%rdx,8),%rdi
  imul   $0x1010101,%esi,%r8d
  cmp    $0x3,%rdx
  jbe    L25
L48:
  mov    %r8d,%eax
  xor    (%rdi),%eax
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  jne    L25
  sub    $0x4,%rdx
  sub    $0x4,%rdi
  cmp    $0x3,%rdx
  ja     L48
L25:
  lea    -0x8(%rdi,%rdx,8),%rax
L47:
  test   %rdx,%rdx
  je     L11
  mov    %rax,%rcx
  sub    $0x1,%rdx
  sub    $0x8,%rax
  cmp    %rsi,(%rcx)
  jne    L47
  jmp    L31
L11:
  mov    $0x0,%ecx
L31:
  mov    %rcx,%rax
  ret
```

assistant: ```c
void *memrchr32(const void *s, uint8_t c, size_t n) {
  register const uint32_t *ip;
  register const uint8_t *p;
  register uint32_t mask;
  register uint32_t x;
  ip = (const uint32_t *)((const uint8_t *)s + n - 1 - sizeof(uint32_t));
  mask = ((((uint32_t)c) << 24) + (((uint32_t)c) << 16) + ((((uint32_t)c) << 8) + ((uint32_t)c)));
  while (n >= sizeof(uint32_t)) {
    x = *ip ^ mask;
    if ((x - 0x01010101U) & ~x & 0x80808080U)
      break;
    n -= sizeof(uint32_t);
    ip--;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (p[n] == c)
      return ((void *)(p + n));
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memrchr32>:
  endbr64
  imul   $0x1010101,%esi,%r8d
  lea    -0x28(%rdi,%rdx,8),%rdi
  cmp    $0x3,%rdx
  ja     L2
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L37:
  sub    $0x4,%rdx
  sub    $0x4,%rdi
  cmp    $0x3,%rdx
  jbe    L15
L2:
  mov    (%rdi),%eax
  xor    %r8d,%eax
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  je     L37
L15:
  lea    -0x8(%rdi,%rdx,8),%rax
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rax,%r8
  sub    $0x1,%rdx
  sub    $0x8,%rax
  cmp    %rsi,(%r8)
  je     L55
L58:
  test   %rdx,%rdx
  jne    L56
  xor    %r8d,%r8d
L55:
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memrchr32(const void *s, uint8_t c, size_t n) {
  register const uint32_t *ip;
  register const uint8_t *p;
  register uint32_t mask;
  register uint32_t x;
  ip = (const uint32_t *)((const uint8_t *)s + n - 1 - sizeof(uint32_t));
  mask = ((((uint32_t)c) << 24) + (((uint32_t)c) << 16) + ((((uint32_t)c) << 8) + ((uint32_t)c)));
  while (n >= sizeof(uint32_t)) {
    x = *ip ^ mask;
    if ((x - 0x01010101U) & ~x & 0x80808080U)
      break;
    n -= sizeof(uint32_t);
    ip--;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (p[n] == c)
      return ((void *)(p + n));
  }
  return (NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memrchr32>:
  endbr64
  imul   $0x1010101,%esi,%r8d
  lea    -0x28(%rdi,%rdx,8),%rdi
  cmp    $0x3,%rdx
  ja     L24
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x4,%rdx
  sub    $0x4,%rdi
  cmp    $0x3,%rdx
  jbe    L3
L24:
  mov    (%rdi),%eax
  xor    %r8d,%eax
  lea    -0x1010101(%rax),%ecx
  not    %eax
  and    %ecx,%eax
  test   $0x80808080,%eax
  je     L6
L3:
  lea    -0x8(%rdi,%rdx,8),%rax
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rax,%r8
  sub    $0x1,%rdx
  sub    $0x8,%rax
  cmp    %rsi,(%r8)
  je     L64
L30:
  test   %rdx,%rdx
  jne    L40
  xor    %r8d,%r8d
L64:
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memrchr32(const void *s, uint8_t c, size_t n) {
  register const uint32_t *ip;
  register const uint8_t *p;
  register uint32_t mask;
  register uint32_t x;
  ip = (const uint32_t *)((const uint8_t *)s + n - 1 - sizeof(uint32_t));
  mask = ((((uint32_t)c) << 24) + (((uint32_t)c) << 16) + ((((uint32_t)c) << 8) + ((uint32_t)c)));
  while (n >= sizeof(uint32_t)) {
    x = *ip ^ mask;
    if ((x - 0x01010101U) & ~x & 0x80808080U)
      break;
    n -= sizeof(uint32_t);
    ip--;
  }
  p = (const uint8_t *)ip;
  while (n--) {
    if (p[n] == c)
      return ((void *)(p + n));
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<a_cas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  lock cmpxchg %edx,(%rcx)
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int a_cas(volatile int *p, int t, int s) {
  __asm__("lock ; cmpxchg %3, %1" : "=a"(t), "=m"(*p) : "a"(t), "r"(s) : "memory");
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<a_cas>:
  endbr64
  mov    %esi,%eax
  lock cmpxchg %edx,(%rdi)
  ret
```

assistant: ```c
int a_cas(volatile int *p, int t, int s) {
  __asm__("lock ; cmpxchg %3, %1" : "=a"(t), "=m"(*p) : "a"(t), "r"(s) : "memory");
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<a_cas>:
  endbr64
  mov    %esi,%eax
  lock cmpxchg %edx,(%rdi)
  ret
```

assistant: ```c
int a_cas(volatile int *p, int t, int s) {
  __asm__("lock ; cmpxchg %3, %1" : "=a"(t), "=m"(*p) : "a"(t), "r"(s) : "memory");
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xd8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <mat_vsnprintf@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int mat_snprintf(char *str, size_t count, const char *fmt, ...) {
  size_t ret;
  va_list ap;
  va_start(ap, fmt);
  ret = mat_vsnprintf(str, count, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mat_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mat_vsnprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mat_snprintf(char *str, size_t count, const char *fmt, ...) {
  size_t ret;
  va_list ap;
  va_start(ap, fmt);
  ret = mat_vsnprintf(str, count, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mat_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mat_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mat_snprintf(char *str, size_t count, const char *fmt, ...) {
  size_t ret;
  va_list ap;
  va_start(ap, fmt);
  ret = mat_vsnprintf(str, count, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat_snprintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <mat_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %rax,%rbx
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mat_snprintf(char *str, size_t count, const char *fmt, ...) {
  size_t ret;
  va_list ap;
  va_start(ap, fmt);
  ret = mat_vsnprintf(str, count, fmt, ap);
  va_end(ap);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_zero() {
#pragma omp sections
  {}
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_zero>:
  endbr64
  ret
```

assistant: ```c
void test_zero() {
#pragma omp sections
  {}
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_zero>:
  endbr64
  ret
```

assistant: ```c
void test_zero() {
#pragma omp sections
  {}
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_zero>:
  endbr64
  ret
```

assistant: ```c
void test_zero() {
#pragma omp sections
  {}
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yas_lis331dlh_read_reg_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x14(%rbp),%eax
  lea    -0xd(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <yas_lis331dlh_read_reg@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L6
  movzbl -0xd(%rbp),%eax
  movzbl %al,%eax
  jmp    L12
L6:
  mov    $0x0,%eax
L12:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int yas_lis331dlh_read_reg_byte(unsigned char adr) {
  unsigned char buf;
  int err;
  err = yas_lis331dlh_read_reg(adr, &buf, 1);
  if (err == 0) {
    return buf;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<yas_lis331dlh_read_reg_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movzbl %dil,%edi
  mov    $0x1,%edx
  call   <yas_lis331dlh_read_reg@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L14
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L14:
  movzbl 0x7(%rsp),%eax
  jmp    L4
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yas_lis331dlh_read_reg_byte(unsigned char adr) {
  unsigned char buf;
  int err;
  err = yas_lis331dlh_read_reg(adr, &buf, 1);
  if (err == 0) {
    return buf;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yas_lis331dlh_read_reg_byte>:
  endbr64
  sub    $0x18,%rsp
  movzbl %dil,%edi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <yas_lis331dlh_read_reg@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L19
  movzbl 0x7(%rsp),%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yas_lis331dlh_read_reg_byte(unsigned char adr) {
  unsigned char buf;
  int err;
  err = yas_lis331dlh_read_reg(adr, &buf, 1);
  if (err == 0) {
    return buf;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yas_lis331dlh_read_reg_byte>:
  endbr64
  sub    $0x18,%rsp
  movzbl %dil,%edi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <yas_lis331dlh_read_reg@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L19
  movzbl 0x7(%rsp),%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int yas_lis331dlh_read_reg_byte(unsigned char adr) {
  unsigned char buf;
  int err;
  err = yas_lis331dlh_read_reg(adr, &buf, 1);
  if (err == 0) {
    return buf;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setup_DPT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    $0x0,%edi
  call   <HD_RW@plt>
  movb   $0x80,-0x52(%rbp)
  movb   $0x2e,-0x4e(%rbp)
  lea    -0x210(%rbp),%rax
  add    $0x1c6,%rax
  movq   $0x1,(%rax)
  lea    -0x210(%rbp),%rax
  add    $0x1ca,%rax
  movq   $0x400000,(%rax)
  movb   $0x2f,-0x3e(%rbp)
  lea    -0x210(%rbp),%rax
  add    $0x1d6,%rax
  movq   $0x400001,(%rax)
  lea    -0x210(%rbp),%rax
  add    $0x1da,%rax
  movq   $0x200000,(%rax)
  movb   $0x55,-0x12(%rbp)
  movb   $0xaa,-0x11(%rbp)
  lea    -0x210(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x30,%esi
  mov    $0x0,%edi
  call   <HD_RW@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void setup_DPT(void) {
  unsigned char sect[512];
  HD_RW(0, 0x20, 1, sect);
  sect[0x1be] = 0x80;
  sect[0x1be + 0x04] = 0x2e;
  *(unsigned long *)&sect[0x1be + 0x08] = 1;
  *(unsigned long *)&sect[0x1be + 0x0c] = 1024 * 2 * 1024 * 2;
  sect[0x1ce + 0x04] = 0x2f;
  *(unsigned long *)&sect[0x1ce + 0x08] = 1024 * 2 * 1024 * 2 + 1;
  *(unsigned long *)&sect[0x1ce + 0x0c] = 1024 * 1024 * 2;
  sect[0x1fe] = 0x55;
  sect[0x1ff] = 0xaa;
  HD_RW(0, 0x30, 1, sect);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setup_DPT>:
  endbr64
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x20,%esi
  mov    $0x0,%edi
  call   <HD_RW@plt>
  movb   $0x80,0x1be(%rsp)
  movb   $0x2e,0x1c2(%rsp)
  movq   $0x1,0x1c6(%rsp)
  movq   $0x400000,0x1ca(%rsp)
  movb   $0x2f,0x1d2(%rsp)
  movq   $0x400001,0x1d6(%rsp)
  movq   $0x200000,0x1da(%rsp)
  movb   $0x55,0x1fe(%rsp)
  movb   $0xaa,0x1ff(%rsp)
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x30,%esi
  mov    $0x0,%edi
  call   <HD_RW@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x210,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setup_DPT(void) {
  unsigned char sect[512];
  HD_RW(0, 0x20, 1, sect);
  sect[0x1be] = 0x80;
  sect[0x1be + 0x04] = 0x2e;
  *(unsigned long *)&sect[0x1be + 0x08] = 1;
  *(unsigned long *)&sect[0x1be + 0x0c] = 1024 * 2 * 1024 * 2;
  sect[0x1ce + 0x04] = 0x2f;
  *(unsigned long *)&sect[0x1ce + 0x08] = 1024 * 2 * 1024 * 2 + 1;
  *(unsigned long *)&sect[0x1ce + 0x0c] = 1024 * 1024 * 2;
  sect[0x1fe] = 0x55;
  sect[0x1ff] = 0xaa;
  HD_RW(0, 0x30, 1, sect);
}
```
user: Translate the below assembly code into C programming language:

```asm
<setup_DPT>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    $0x20,%esi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rcx
  call   <HD_RW@plt>
  mov    $0xffffaa55,%eax
  xor    %edi,%edi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x30,%esi
  movq   $0x1,0x1c6(%rsp)
  movq   $0x400001,0x1d6(%rsp)
  movb   $0x80,0x1be(%rsp)
  movb   $0x2e,0x1c2(%rsp)
  movq   $0x400000,0x1ca(%rsp)
  movb   $0x2f,0x1d2(%rsp)
  movq   $0x200000,0x1da(%rsp)
  mov    %ax,0x1fe(%rsp)
  call   <HD_RW@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x210,%rsp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setup_DPT(void) {
  unsigned char sect[512];
  HD_RW(0, 0x20, 1, sect);
  sect[0x1be] = 0x80;
  sect[0x1be + 0x04] = 0x2e;
  *(unsigned long *)&sect[0x1be + 0x08] = 1;
  *(unsigned long *)&sect[0x1be + 0x0c] = 1024 * 2 * 1024 * 2;
  sect[0x1ce + 0x04] = 0x2f;
  *(unsigned long *)&sect[0x1ce + 0x08] = 1024 * 2 * 1024 * 2 + 1;
  *(unsigned long *)&sect[0x1ce + 0x0c] = 1024 * 1024 * 2;
  sect[0x1fe] = 0x55;
  sect[0x1ff] = 0xaa;
  HD_RW(0, 0x30, 1, sect);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setup_DPT>:
  endbr64
  push   %r12
  xor    %edi,%edi
  mov    $0x1,%edx
  mov    $0x20,%esi
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rcx
  call   <HD_RW@plt>
  mov    $0xffffaa55,%eax
  xor    %edi,%edi
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    $0x30,%esi
  movq   $0x1,0x1c6(%rsp)
  movq   $0x400001,0x1d6(%rsp)
  movb   $0x80,0x1be(%rsp)
  movb   $0x2e,0x1c2(%rsp)
  movq   $0x400000,0x1ca(%rsp)
  movb   $0x2f,0x1d2(%rsp)
  movq   $0x200000,0x1da(%rsp)
  mov    %ax,0x1fe(%rsp)
  call   <HD_RW@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x210,%rsp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setup_DPT(void) {
  unsigned char sect[512];
  HD_RW(0, 0x20, 1, sect);
  sect[0x1be] = 0x80;
  sect[0x1be + 0x04] = 0x2e;
  *(unsigned long *)&sect[0x1be + 0x08] = 1;
  *(unsigned long *)&sect[0x1be + 0x0c] = 1024 * 2 * 1024 * 2;
  sect[0x1ce + 0x04] = 0x2f;
  *(unsigned long *)&sect[0x1ce + 0x08] = 1024 * 2 * 1024 * 2 + 1;
  *(unsigned long *)&sect[0x1ce + 0x0c] = 1024 * 1024 * 2;
  sect[0x1fe] = 0x55;
  sect[0x1ff] = 0xaa;
  HD_RW(0, 0x30, 1, sect);
}
```