ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<nc_cal_chksum>:
  endbr64
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L14
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nop
L7:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L7
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L3:
  cmp    $0x1,%esi
  jne    L28
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
L28:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
unsigned short nc_cal_chksum(unsigned short *addr, int len) {
  int nleft = len;
  int sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nc_cal_chksum>:
  endbr64
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L71
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L13
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L74:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm3
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L74
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddd  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm0,%eax
  cmp    %r8d,%ecx
  je     L28
L62:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L28
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L28
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L28
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L28
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L28
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L28
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L28:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L115:
  cmp    $0x1,%esi
  jne    L108
  mov    (%rdx),%r10b
  movzwl %r10w,%edx
  add    %edx,%eax
L108:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  jmp    L115
L13:
  xor    %eax,%eax
  jmp    L62
```

assistant: ```c
unsigned short nc_cal_chksum(unsigned short *addr, int len) {
  int nleft = len;
  int sum = 0;
  unsigned short *w = addr;
  unsigned short answer = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&answer) = *(unsigned char *)w;
    sum += answer;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return answer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x10(%rax),%r9d
  mov    0xc(%rax),%edx
  shl    $0x2,%edx
  mov    %r9d,%r10d
  sar    $0xe,%r10d
  xor    %r10d,%edx
  shl    $0xd,%r9d
  xor    %r9d,%edx
  mov    0x14(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x28(%rax),%r9d
  mov    0x24(%rax),%edx
  shl    $0x2,%edx
  mov    %r9d,%r10d
  sar    $0xe,%r10d
  xor    %r10d,%edx
  add    %r9d,%r9d
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0xf,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x38(%rax),%edx
  shl    $0x3,%edx
  mov    0x3c(%rax),%r9d
  sar    $0xd,%r9d
  xor    %r9d,%edx
  xor    0x44(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x10(%rax),%r8d
  mov    0x14(%rax),%r9d
  mov    %r8d,%edx
  shl    $0xb,%edx
  mov    %r9d,%r10d
  sar    $0x5,%r10d
  xor    %r10d,%edx
  shl    $0xc,%r8d
  sar    $0x4,%r9d
  xor    %r9d,%r8d
  and    %r8d,%edx
  mov    0x24(%rax),%r8d
  shl    $0xb,%r8d
  mov    0x28(%rax),%r9d
  sar    $0x5,%r9d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x28(%rax),%r8d
  mov    0x3c(%rax),%edx
  shl    $0x8,%edx
  mov    0x40(%rax),%edi
  sar    $0x8,%edi
  xor    %edi,%edx
  xor    (%rsi),%edx
  mov    0x24(%rax),%edi
  shl    $0xf,%edi
  mov    %r8d,%r9d
  sar    %r9d
  xor    %r9d,%edi
  and    %r8d,%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x40(%rax),%esi
  mov    0x44(%rax),%edi
  mov    %esi,%edx
  shl    $0xe,%edx
  mov    %edi,%r8d
  sar    $0x2,%r8d
  xor    %r8d,%edx
  shl    $0xf,%esi
  sar    %edi
  xor    %edi,%esi
  and    %esi,%edx
  mov    0xc(%rax),%esi
  shl    $0x5,%esi
  mov    0x10(%rax),%eax
  sar    $0xb,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint16_t *state, uint16_t *t1, uint16_t *t2, uint16_t *t3, uint16_t *stream) {
  uint16_t x1, x2, x3, x4, x5;
  x1 = (state[3] << 2) ^ (state[4] >> 14);
  x4 = (state[4] << 13) ^ (state[5] >> 3);
  *t1 = x1 ^ x4;
  x1 = (state[9] << 2) ^ (state[10] >> 14);
  x4 = (state[10] << 1) ^ (state[11] >> 15);
  *t2 = x1 ^ x4;
  x1 = (state[14] << 3) ^ (state[15] >> 13);
  x4 = state[17];
  *t3 = x1 ^ x4;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x2 = (state[4] << 11) ^ (state[5] >> 5);
  x3 = (state[4] << 12) ^ (state[5] >> 4);
  x5 = (state[9] << 11) ^ (state[10] >> 5);
  *t1 ^= (x2 & x3) ^ x5;
  x2 = (state[9] << 15) ^ (state[10] >> 1);
  x3 = state[10];
  x5 = (state[15] << 8) ^ (state[16] >> 8);
  *t2 ^= (x2 & x3) ^ x5;
  x2 = (state[16] << 14) ^ (state[17] >> 2);
  x3 = (state[16] << 15) ^ (state[17] >> 1);
  x5 = (state[3] << 5) ^ (state[4] >> 11);
  *t3 ^= (x2 & x3) ^ x5;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x10(%rax),%r9d
  mov    0xc(%rax),%edx
  mov    %r9d,%r10d
  shl    $0x2,%edx
  sar    $0xe,%r10d
  shl    $0xd,%r9d
  xor    %r10d,%edx
  xor    %r9d,%edx
  mov    0x14(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x28(%rax),%r9d
  mov    0x24(%rax),%edx
  mov    %r9d,%r10d
  add    %r9d,%r9d
  sar    $0xe,%r10d
  shl    $0x2,%edx
  xor    %r10d,%edx
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0xf,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x38(%rax),%edx
  mov    0x3c(%rax),%r9d
  shl    $0x3,%edx
  sar    $0xd,%r9d
  xor    %r9d,%edx
  xor    0x44(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x10(%rax),%r8d
  mov    0x14(%rax),%r9d
  mov    %r8d,%edx
  shl    $0xc,%r8d
  mov    %r9d,%r10d
  shl    $0xb,%edx
  sar    $0x4,%r9d
  sar    $0x5,%r10d
  xor    %r9d,%r8d
  xor    %r10d,%edx
  mov    0x28(%rax),%r9d
  and    %r8d,%edx
  mov    0x24(%rax),%r8d
  sar    $0x5,%r9d
  shl    $0xb,%r8d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x3c(%rax),%edx
  mov    0x40(%rax),%edi
  mov    0x28(%rax),%r8d
  shl    $0x8,%edx
  sar    $0x8,%edi
  mov    %r8d,%r9d
  xor    %edi,%edx
  mov    0x24(%rax),%edi
  sar    %r9d
  xor    (%rsi),%edx
  shl    $0xf,%edi
  xor    %r9d,%edi
  and    %r8d,%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x40(%rax),%esi
  mov    0x44(%rax),%edi
  mov    %esi,%edx
  shl    $0xf,%esi
  mov    %edi,%r8d
  shl    $0xe,%edx
  sar    $0x2,%r8d
  sar    %edi
  xor    %edi,%esi
  xor    %r8d,%edx
  and    %esi,%edx
  mov    0xc(%rax),%esi
  mov    0x10(%rax),%eax
  shl    $0x5,%esi
  sar    $0xb,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint16_t *state, uint16_t *t1, uint16_t *t2, uint16_t *t3, uint16_t *stream) {
  uint16_t x1, x2, x3, x4, x5;
  x1 = (state[3] << 2) ^ (state[4] >> 14);
  x4 = (state[4] << 13) ^ (state[5] >> 3);
  *t1 = x1 ^ x4;
  x1 = (state[9] << 2) ^ (state[10] >> 14);
  x4 = (state[10] << 1) ^ (state[11] >> 15);
  *t2 = x1 ^ x4;
  x1 = (state[14] << 3) ^ (state[15] >> 13);
  x4 = state[17];
  *t3 = x1 ^ x4;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x2 = (state[4] << 11) ^ (state[5] >> 5);
  x3 = (state[4] << 12) ^ (state[5] >> 4);
  x5 = (state[9] << 11) ^ (state[10] >> 5);
  *t1 ^= (x2 & x3) ^ x5;
  x2 = (state[9] << 15) ^ (state[10] >> 1);
  x3 = state[10];
  x5 = (state[15] << 8) ^ (state[16] >> 8);
  *t2 ^= (x2 & x3) ^ x5;
  x2 = (state[16] << 14) ^ (state[17] >> 2);
  x3 = (state[16] << 15) ^ (state[17] >> 1);
  x5 = (state[3] << 5) ^ (state[4] >> 11);
  *t3 ^= (x2 & x3) ^ x5;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Update>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    0x10(%rax),%r9d
  mov    0xc(%rax),%edx
  mov    %r9d,%r10d
  shl    $0x2,%edx
  sar    $0xe,%r10d
  shl    $0xd,%r9d
  xor    %r10d,%edx
  xor    %r9d,%edx
  mov    0x14(%rax),%r9d
  sar    $0x3,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rdi)
  mov    0x28(%rax),%r9d
  mov    0x24(%rax),%edx
  mov    %r9d,%r10d
  add    %r9d,%r9d
  sar    $0xe,%r10d
  shl    $0x2,%edx
  xor    %r10d,%edx
  xor    %r9d,%edx
  mov    0x2c(%rax),%r9d
  sar    $0xf,%r9d
  xor    %r9d,%edx
  mov    %edx,(%rsi)
  mov    0x38(%rax),%edx
  mov    0x3c(%rax),%r9d
  shl    $0x3,%edx
  sar    $0xd,%r9d
  xor    %r9d,%edx
  xor    0x44(%rax),%edx
  mov    %edx,(%rcx)
  mov    (%r8),%r9d
  xor    (%rsi),%r9d
  xor    (%rdi),%r9d
  xor    %r9d,%edx
  mov    %edx,(%r8)
  mov    0x10(%rax),%r8d
  mov    0x14(%rax),%r9d
  mov    %r8d,%edx
  shl    $0xc,%r8d
  mov    %r9d,%r10d
  shl    $0xb,%edx
  sar    $0x4,%r9d
  sar    $0x5,%r10d
  xor    %r9d,%r8d
  xor    %r10d,%edx
  mov    0x28(%rax),%r9d
  and    %r8d,%edx
  mov    0x24(%rax),%r8d
  sar    $0x5,%r9d
  shl    $0xb,%r8d
  xor    %r9d,%r8d
  xor    (%rdi),%r8d
  xor    %r8d,%edx
  mov    %edx,(%rdi)
  mov    0x3c(%rax),%edx
  mov    0x40(%rax),%edi
  mov    0x28(%rax),%r8d
  shl    $0x8,%edx
  sar    $0x8,%edi
  mov    %r8d,%r9d
  xor    %edi,%edx
  mov    0x24(%rax),%edi
  sar    %r9d
  xor    (%rsi),%edx
  shl    $0xf,%edi
  xor    %r9d,%edi
  and    %r8d,%edi
  xor    %edi,%edx
  mov    %edx,(%rsi)
  mov    0x40(%rax),%esi
  mov    0x44(%rax),%edi
  mov    %esi,%edx
  shl    $0xf,%esi
  mov    %edi,%r8d
  shl    $0xe,%edx
  sar    $0x2,%r8d
  sar    %edi
  xor    %edi,%esi
  xor    %r8d,%edx
  and    %esi,%edx
  mov    0xc(%rax),%esi
  mov    0x10(%rax),%eax
  shl    $0x5,%esi
  sar    $0xb,%eax
  xor    %esi,%eax
  xor    (%rcx),%eax
  xor    %edx,%eax
  mov    %eax,(%rcx)
  ret
```

assistant: ```c
void Update(uint16_t *state, uint16_t *t1, uint16_t *t2, uint16_t *t3, uint16_t *stream) {
  uint16_t x1, x2, x3, x4, x5;
  x1 = (state[3] << 2) ^ (state[4] >> 14);
  x4 = (state[4] << 13) ^ (state[5] >> 3);
  *t1 = x1 ^ x4;
  x1 = (state[9] << 2) ^ (state[10] >> 14);
  x4 = (state[10] << 1) ^ (state[11] >> 15);
  *t2 = x1 ^ x4;
  x1 = (state[14] << 3) ^ (state[15] >> 13);
  x4 = state[17];
  *t3 = x1 ^ x4;
  *stream ^= *t1 ^ *t2 ^ *t3;
  x2 = (state[4] << 11) ^ (state[5] >> 5);
  x3 = (state[4] << 12) ^ (state[5] >> 4);
  x5 = (state[9] << 11) ^ (state[10] >> 5);
  *t1 ^= (x2 & x3) ^ x5;
  x2 = (state[9] << 15) ^ (state[10] >> 1);
  x3 = state[10];
  x5 = (state[15] << 8) ^ (state[16] >> 8);
  *t2 ^= (x2 & x3) ^ x5;
  x2 = (state[16] << 14) ^ (state[17] >> 2);
  x3 = (state[16] << 15) ^ (state[17] >> 1);
  x5 = (state[3] << 5) ^ (state[4] >> 11);
  *t3 ^= (x2 & x3) ^ x5;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <check@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D5
type: string

tool: D8: %d

tool: D5: %s

assistant: ```c
int main() {
  char *str;
  int n;
  str = (char *)malloc(n * sizeof(char));
  scanf("%d", &n);
  scanf("%s", str);
  check(str, n);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <check@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string

tool: D7: %d

tool: D9: %s

assistant: ```c
int main() {
  char *str;
  int n;
  str = (char *)malloc(n * sizeof(char));
  scanf("%d", &n);
  scanf("%s", str);
  check(str, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <check@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D4
datatype: string

tool: D12: %d

tool: D4: %s

assistant: ```c
int main() {
  char *str;
  int n;
  str = (char *)malloc(n * sizeof(char));
  scanf("%d", &n);
  scanf("%s", str);
  check(str, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <check@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D1
type: string

tool: D13: %d

tool: D1: %s

assistant: ```c
int main() {
  char *str;
  int n;
  str = (char *)malloc(n * sizeof(char));
  scanf("%d", &n);
  scanf("%s", str);
  check(str, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gpu_draw_range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0xa,%eax
  and    $0xffc00,%eax
  or     %edx,%eax
  or     $0xe3000000,%eax
  mov    %eax,%edi
  call   <gpu_send_control_gp0@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3ff,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  shl    $0xa,%eax
  and    $0xffc00,%eax
  or     %edx,%eax
  or     $0xe4000000,%eax
  mov    %eax,%edi
  call   <gpu_send_control_gp0@plt>
  nop
  leave
  ret
```

assistant: ```c
void gpu_draw_range(int x1, int y1, int x2, int y2) {
  gpu_send_control_gp0(0xE3000000 | (x1 & 0x3FF) | ((y1 & 0x3FF) << 10));
  gpu_send_control_gp0(0xE4000000 | (x2 & 0x3FF) | ((y2 & 0x3FF) << 10));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gpu_draw_range>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %ecx,%ebx
  shl    $0xa,%esi
  and    $0xffc00,%esi
  and    $0x3ff,%edi
  or     %edi,%esi
  or     $0xe3000000,%esi
  mov    %esi,%edi
  call   <gpu_send_control_gp0@plt>
  shl    $0xa,%ebx
  mov    %ebx,%edi
  and    $0xffc00,%edi
  and    $0x3ff,%ebp
  or     %ebp,%edi
  or     $0xe4000000,%edi
  call   <gpu_send_control_gp0@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void gpu_draw_range(int x1, int y1, int x2, int y2) {
  gpu_send_control_gp0(0xE3000000 | (x1 & 0x3FF) | ((y1 & 0x3FF) << 10));
  gpu_send_control_gp0(0xE4000000 | (x2 & 0x3FF) | ((y2 & 0x3FF) << 10));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gpu_draw_range>:
  endbr64
  shl    $0xa,%esi
  push   %rbp
  and    $0x3ff,%edi
  mov    %edx,%ebp
  push   %rbx
  and    $0xffc00,%esi
  mov    %ecx,%ebx
  and    $0x3ff,%ebp
  or     %edi,%esi
  shl    $0xa,%ebx
  or     $0xe3000000,%esi
  sub    $0x8,%rsp
  mov    %esi,%edi
  call   <gpu_send_control_gp0@plt>
  mov    %ebx,%edi
  add    $0x8,%rsp
  and    $0xffc00,%edi
  pop    %rbx
  or     %ebp,%edi
  pop    %rbp
  or     $0xe4000000,%edi
  jmp    1050 <gpu_send_control_gp0@plt>
```

assistant: ```c
void gpu_draw_range(int x1, int y1, int x2, int y2) {
  gpu_send_control_gp0(0xE3000000 | (x1 & 0x3FF) | ((y1 & 0x3FF) << 10));
  gpu_send_control_gp0(0xE4000000 | (x2 & 0x3FF) | ((y2 & 0x3FF) << 10));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gpu_draw_range>:
  endbr64
  shl    $0xa,%esi
  push   %rbp
  and    $0x3ff,%edi
  mov    %edx,%ebp
  push   %rbx
  and    $0xffc00,%esi
  mov    %ecx,%ebx
  and    $0x3ff,%ebp
  or     %edi,%esi
  shl    $0xa,%ebx
  or     $0xe3000000,%esi
  sub    $0x8,%rsp
  mov    %esi,%edi
  call   <gpu_send_control_gp0@plt>
  mov    %ebx,%edi
  add    $0x8,%rsp
  and    $0xffc00,%edi
  pop    %rbx
  or     %ebp,%edi
  pop    %rbp
  or     $0xe4000000,%edi
  jmp    1050 <gpu_send_control_gp0@plt>
```

assistant: ```c
void gpu_draw_range(int x1, int y1, int x2, int y2) {
  gpu_send_control_gp0(0xE3000000 | (x1 & 0x3FF) | ((y1 & 0x3FF) << 10));
  gpu_send_control_gp0(0xE4000000 | (x2 & 0x3FF) | ((y2 & 0x3FF) << 10));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str2sa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    $0xc,%esi
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inet_aton@plt>
  test   %eax,%eax
  jne    L15
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,D11(%rip)
L15:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,D11(%rip)
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,D64(%rip)
  cmpq   $0x0,-0x28(%rbp)
  je     L1
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L1:
  mov    D64(%rip),%rax
  mov    %rax,-0xc(%rbp)
  mov    D11(%rip),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%rax
  mov    -0x4(%rbp),%ecx
  mov    %rcx,%rdx
  leave
  ret
```

assistant: ```c
struct sockaddr_in str2sa(char *str, int port) {
  static struct sockaddr_in sa;
  bzero(&sa, sizeof(sa));
  str = strdup(str);
  if (!inet_aton(str, &sa.sin_addr)) {
    struct hostent *he;
    if ((he = gethostbyname(str)) != NULL) {
      sa.sin_addr = *(struct in_addr *)*(he->h_addr_list);
    }
  }
  sa.sin_port = htons(port);
  sa.sin_family = AF_INET;
  if (str != NULL) {
    free(str);
  }
  return sa;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str2sa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0xc,%esi
  lea    D33(%rip),%rdi
  call   <bzero@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <inet_aton@plt>
  test   %eax,%eax
  je     L2
L19:
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %eax,D53(%rip)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,D17(%rip)
  test   %rbx,%rbx
  je     L27
  mov    %rbx,%rdi
  call   <free@plt>
L27:
  mov    D4(%rip),%edx
  mov    D17(%rip),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rbx,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L19
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,D17(%rip)
  jmp    L19
```

assistant: ```c
struct sockaddr_in str2sa(char *str, int port) {
  static struct sockaddr_in sa;
  bzero(&sa, sizeof(sa));
  str = strdup(str);
  if (!inet_aton(str, &sa.sin_addr)) {
    struct hostent *he;
    if ((he = gethostbyname(str)) != NULL) {
      sa.sin_addr = *(struct in_addr *)*(he->h_addr_list);
    }
  }
  sa.sin_port = htons(port);
  sa.sin_family = AF_INET;
  if (str != NULL) {
    free(str);
  }
  return sa;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2sa>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    $0xc,%esi
  push   %rbp
  mov    %rdi,%rbp
  lea    D41(%rip),%rdi
  sub    $0x28,%rsp
  call   <bzero@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  lea    D32(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <inet_aton@plt>
  test   %eax,%eax
  je     L10
L5:
  mov    %r12d,%edi
  call   <htons@plt>
  mov    %eax,D66(%rip)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,D75(%rip)
  test   %rbp,%rbp
  je     L16
  mov    %rbp,%rdi
  call   <free@plt>
L16:
  mov    D32(%rip),%edx
  mov    D75(%rip),%rax
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L10:
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L5
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,D75(%rip)
  jmp    L5
```

assistant: ```c
struct sockaddr_in str2sa(char *str, int port) {
  static struct sockaddr_in sa;
  bzero(&sa, sizeof(sa));
  str = strdup(str);
  if (!inet_aton(str, &sa.sin_addr)) {
    struct hostent *he;
    if ((he = gethostbyname(str)) != NULL) {
      sa.sin_addr = *(struct in_addr *)*(he->h_addr_list);
    }
  }
  sa.sin_port = htons(port);
  sa.sin_family = AF_INET;
  if (str != NULL) {
    free(str);
  }
  return sa;
}
```