ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ands_si_test2>:
  endbr64
  movzbl %dil,%ecx
  add    %edx,%edi
  lea    (%rcx,%rsi,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0xff;
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ands_si_test2>:
  endbr64
  movzbl %dil,%ecx
  add    %edx,%edi
  lea    (%rcx,%rsi,1),%eax
  add    %edx,%eax
  test   %ecx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int ands_si_test2(int a, int b, int c) {
  int d = a & 0xff;
  if (d == 0)
    return a + c;
  else
    return b + d + c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gostcfbencrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  jmp    L19
L7:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gostcrypt@plt>
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    (%rdx),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%edx
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L19:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void gostcfbencrypt(uint32_t const *in, uint32_t *out, int len, uint32_t iv[2], uint32_t const key[8]) {
  while (len--) {
    gostcrypt(iv, iv, key);
    iv[0] = *out++ ^= iv[0];
    iv[1] = *out++ ^= iv[1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gostcfbencrypt>:
  endbr64
  test   %edx,%edx
  je     L10
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  mov    %r8,%r12
  mov    %edx,%edx
  lea    (%rsi,%rdx,8),%r13
L16:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <gostcrypt@plt>
  mov    (%rbx),%eax
  xor    0x0(%rbp),%eax
  mov    %eax,(%rbx)
  mov    %eax,0x0(%rbp)
  add    $0x8,%rbx
  mov    -0x4(%rbx),%eax
  xor    0x4(%rbp),%eax
  mov    %eax,-0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmp    %rbx,%r13
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  ret
```

assistant: ```c
void gostcfbencrypt(uint32_t const *in, uint32_t *out, int len, uint32_t iv[2], uint32_t const key[8]) {
  while (len--) {
    gostcrypt(iv, iv, key);
    iv[0] = *out++ ^= iv[0];
    iv[1] = *out++ ^= iv[1];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gostcfbencrypt>:
  endbr64
  test   %edx,%edx
  je     L17
  push   %r13
  mov    %edx,%edx
  push   %r12
  lea    (%rsi,%rdx,8),%r13
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <gostcrypt@plt>
  mov    -0x8(%rbx),%eax
  xor    0x0(%rbp),%eax
  mov    %eax,-0x8(%rbx)
  mov    %eax,0x0(%rbp)
  mov    -0x4(%rbx),%eax
  xor    0x4(%rbp),%eax
  mov    %eax,-0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmp    %rbx,%r13
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void gostcfbencrypt(uint32_t const *in, uint32_t *out, int len, uint32_t iv[2], uint32_t const key[8]) {
  while (len--) {
    gostcrypt(iv, iv, key);
    iv[0] = *out++ ^= iv[0];
    iv[1] = *out++ ^= iv[1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gostcfbencrypt>:
  endbr64
  test   %edx,%edx
  je     L17
  push   %r13
  mov    %edx,%edx
  push   %r12
  lea    (%rsi,%rdx,8),%r13
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <gostcrypt@plt>
  mov    -0x8(%rbx),%eax
  xor    0x0(%rbp),%eax
  mov    %eax,-0x8(%rbx)
  mov    %eax,0x0(%rbp)
  mov    -0x4(%rbx),%eax
  xor    0x4(%rbp),%eax
  mov    %eax,-0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmp    %rbx,%r13
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void gostcfbencrypt(uint32_t const *in, uint32_t *out, int len, uint32_t iv[2], uint32_t const key[8]) {
  while (len--) {
    gostcrypt(iv, iv, key);
    iv[0] = *out++ ^= iv[0];
    iv[1] = *out++ ^= iv[1];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__require_allocated_array@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__get_array_length@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L28
  mov    $0x0,%eax
  jmp    L10
L28:
  cmpl   $0x0,-0x8(%rbp)
  js     L11
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
L11:
  jmp    L11
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L10:
  leave
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int size;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  __require_allocated_array(s);
  size = __get_array_length(s);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size)
    while (1)
      ;
  return (char *)s + offset;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <__require_allocated_array@plt>
  mov    %rbx,%rdi
  call   <__get_array_length@plt>
  test   %r12d,%r12d
  jne    L23
  test   %ebp,%ebp
  js     L20
  cmp    %eax,%ebp
  setge  %dl
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rax
  test   %dl,%dl
  jne    L20
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  jmp    L20
L23:
  mov    $0x0,%eax
  jmp    L14
```

assistant: ```c
char *strchr(const char *s, int c) {
  int size;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  __require_allocated_array(s);
  size = __get_array_length(s);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size)
    while (1)
      ;
  return (char *)s + offset;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strchr>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rbx,%rdi
  movslq %eax,%rbp
  call   <__require_allocated_array@plt>
  mov    %rbx,%rdi
  call   <__get_array_length@plt>
  test   %r12d,%r12d
  jne    L29
  test   %ebp,%ebp
  js     L10
  cmp    %eax,%ebp
  lea    (%rbx,%rbp,1),%rax
  setge  %dl
  test   %dl,%dl
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  jmp    L10
  nopl   0x0(%rax)
L29:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int size;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  __require_allocated_array(s);
  size = __get_array_length(s);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size)
    while (1)
      ;
  return (char *)s + offset;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strchr>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rbx,%rdi
  movslq %eax,%rbp
  call   <__require_allocated_array@plt>
  mov    %rbx,%rdi
  call   <__get_array_length@plt>
  test   %r12d,%r12d
  jne    L23
  test   %ebp,%ebp
  js     L2
  cmp    %eax,%ebp
  lea    (%rbx,%rbp,1),%rax
  setge  %dl
  test   %dl,%dl
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  jmp    L2
  nopl   0x0(%rax)
L23:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  int size;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  __require_allocated_array(s);
  size = __get_array_length(s);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size)
    while (1)
      ;
  return (char *)s + offset;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  jmp    L43
L17:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L1
  mov    $0x1,%eax
  jmp    L18
L1:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  addq   $0x8,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L1
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int find_char(char **strings, int value) {
  assert(strings != NULL);
  while (*strings != NULL) {
    while (**strings != '\0') {
      if (*(*strings)++ == value)
        return 1;
    }
    strings++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<find_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  cmpq   $0x0,(%rbx)
  je     L11
L19:
  mov    (%rbx),%rax
  cmpb   $0x0,(%rax)
  je     L44
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rax),%eax
  cmp    %ebp,%eax
  jne    L19
  mov    $0x1,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  add    $0x8,%rbx
  cmpq   $0x0,(%rbx)
  jne    L19
  mov    $0x0,%eax
  jmp    L11
```

assistant: ```c
int find_char(char **strings, int value) {
  assert(strings != NULL);
  while (*strings != NULL) {
    while (**strings != '\0') {
      if (*(*strings)++ == value)
        return 1;
    }
    strings++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_char>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L24
  jmp    L12
  nopl   0x0(%rax)
L5:
  add    $0x1,%rax
  mov    %rax,(%rbx)
  movsbl -0x1(%rax),%edx
  cmp    %ebp,%edx
  je     L13
L24:
  cmpb   $0x0,(%rax)
  jne    L5
  mov    0x8(%rbx),%rax
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L24
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int find_char(char **strings, int value) {
  assert(strings != NULL);
  while (*strings != NULL) {
    while (**strings != '\0') {
      if (*(*strings)++ == value)
        return 1;
    }
    strings++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<find_char>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L49
  jmp    L0
  nopl   0x0(%rax)
L34:
  add    $0x1,%rax
  mov    %rax,(%rbx)
  movsbl -0x1(%rax),%edx
  cmp    %ebp,%edx
  je     L25
L49:
  cmpb   $0x0,(%rax)
  jne    L34
  mov    0x8(%rbx),%rax
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L49
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int find_char(char **strings, int value) {
  assert(strings != NULL);
  while (*strings != NULL) {
    while (**strings != '\0') {
      if (*(*strings)++ == value)
        return 1;
    }
    strings++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<intto6bitsigned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  and    $0x1f,%eax
  mov    %al,-0x1(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L13
  movzbl -0x1(%rbp),%eax
  xor    $0x3f,%eax
  add    $0x1,%eax
  jmp    L19
L13:
  movzbl -0x1(%rbp),%eax
L19:
  leave
  ret
```

assistant: ```c
char intto6bitsigned(int x) {
  char ax5 = ((char)abs(x)) & 0x1f;
  if (x < 0) {
    return ((ax5 ^ 0x3f) + 1);
  } else {
    return (ax5);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intto6bitsigned>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <abs@plt>
  mov    %rax,%rcx
  and    $0x1f,%eax
  xor    $0x3f,%eax
  lea    0x1(%rax),%edx
  and    $0x1f,%ecx
  test   %ebx,%ebx
  mov    %edx,%eax
  cmovns %ecx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char intto6bitsigned(int x) {
  char ax5 = ((char)abs(x)) & 0x1f;
  if (x < 0) {
    return ((ax5 ^ 0x3f) + 1);
  } else {
    return (ax5);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intto6bitsigned>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <abs@plt>
  and    $0x1f,%eax
  mov    %eax,%edx
  xor    $0x3f,%edx
  add    $0x1,%edx
  test   %ebx,%ebx
  pop    %rbx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
char intto6bitsigned(int x) {
  char ax5 = ((char)abs(x)) & 0x1f;
  if (x < 0) {
    return ((ax5 ^ 0x3f) + 1);
  } else {
    return (ax5);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<intto6bitsigned>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <abs@plt>
  and    $0x1f,%eax
  mov    %eax,%edx
  xor    $0x3f,%edx
  add    $0x1,%edx
  test   %ebx,%ebx
  pop    %rbx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
char intto6bitsigned(int x) {
  char ax5 = ((char)abs(x)) & 0x1f;
  if (x < 0) {
    return ((ax5 ^ 0x3f) + 1);
  } else {
    return (ax5);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<builtin_pwd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %esi,-0x11c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x11c(%rbp)
  je     L15
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L9
L15:
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L9:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: usage: pwd

assistant: ```c
void builtin_pwd(char *c_argv[], int c_argc) {
  if (c_argc != 0) {
    printf("usage: pwd\n");
  } else {
    char cwd[256];
    getcwd(cwd, sizeof(cwd));
    printf("%s\n", cwd);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<builtin_pwd>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L8
  lea    D0(%rip),%rdi
  call   <puts@plt>
L27:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x110,%rsp
  pop    %rbx
  ret
L8:
  mov    %rsp,%rbx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <getcwd@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L27
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: usage: pwd

assistant: ```c
void builtin_pwd(char *c_argv[], int c_argc) {
  if (c_argc != 0) {
    printf("usage: pwd\n");
  } else {
    char cwd[256];
    getcwd(cwd, sizeof(cwd));
    printf("%s\n", cwd);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<builtin_pwd>:
  endbr64
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L0
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x110,%rsp
  lea    D6(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rsp,%rbp
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <getcwd@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x110,%rsp
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: usage: pwd

assistant: ```c
void builtin_pwd(char *c_argv[], int c_argc) {
  if (c_argc != 0) {
    printf("usage: pwd\n");
  } else {
    char cwd[256];
    getcwd(cwd, sizeof(cwd));
    printf("%s\n", cwd);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<builtin_pwd>:
  endbr64
  push   %rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L29
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  lea    D4(%rip),%rdi
  pop    %rbp
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rsp,%rbp
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <getcwd@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: string

tool: D4: usage: pwd

assistant: ```c
void builtin_pwd(char *c_argv[], int c_argc) {
  if (c_argc != 0) {
    printf("usage: pwd\n");
  } else {
    char cwd[256];
    getcwd(cwd, sizeof(cwd));
    printf("%s\n", cwd);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SKP_Silk_k2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %edx,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x58(%rbp)
  jmp    L10
L3:
  movl   $0x0,-0x54(%rbp)
  jmp    L60
L0:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x54(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x54(%rbp)
L60:
  mov    -0x54(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jl     L0
  movl   $0x0,-0x54(%rbp)
  jmp    L53
L28:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x58(%rbp),%eax
  sub    -0x54(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  add    %eax,%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x58(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rsi
  mov    -0x70(%rbp),%rax
  add    %rsi,%rax
  movzwl (%rax),%eax
  cwtl
  mov    %edx,%esi
  imul   %eax,%esi
  mov    -0x58(%rbp),%eax
  sub    -0x54(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  add    %eax,%eax
  movzwl %ax,%edx
  mov    -0x58(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdi
  mov    -0x70(%rbp),%rax
  add    %rdi,%rax
  movzwl (%rax),%eax
  cwtl
  imul   %edx,%eax
  sar    $0x10,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x68(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x54(%rbp)
L53:
  mov    -0x54(%rbp),%eax
  cmp    -0x58(%rbp),%eax
  jl     L28
  mov    -0x58(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  shl    $0x9,%eax
  mov    %eax,%edx
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x68(%rbp),%rax
  add    %rcx,%rax
  neg    %edx
  mov    %edx,(%rax)
  addl   $0x1,-0x58(%rbp)
L10:
  mov    -0x58(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L3
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void SKP_Silk_k2a(int *A_Q24, const short *rc_Q15, const int order) {
  int k, n;
  int Atmp[16];
  for (k = 0; k < order; k++) {
    for (n = 0; n < k; n++) {
      Atmp[n] = A_Q24[n];
    }
    for (n = 0; n < k; n++) {
      A_Q24[n] = ((A_Q24[n]) + ((((((Atmp[k - n - 1]) << (1))) >> 16) * (int)((short)(rc_Q15[k]))) + ((((((Atmp[k - n - 1]) << (1))) & 0x0000FFFF) * (int)((short)(rc_Q15[k]))) >> 16)));
    }
    A_Q24[k] = -(((int)rc_Q15[k]) << (9));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<SKP_Silk_k2a>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L20
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    -0x4(%rsp),%rbx
  mov    %edx,%ebp
  mov    $0xffffffff,%r11d
  mov    $0x0,%r10d
  lea    0x4(%r8),%r12
  jmp    L48
L70:
  mov    (%r8,%rax,4),%edx
  mov    %edx,(%rsp,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L70
  mov    %r8,%rcx
  lea    (%r12,%rsi,4),%r9
  mov    %rbx,%rsi
L67:
  mov    (%rsi),%eax
  add    %eax,%eax
  movswl (%rdi),%r13d
  movzwl %ax,%edx
  imul   %r13d,%edx
  sar    $0x10,%edx
  sar    $0x10,%eax
  imul   %r13d,%eax
  add    %edx,%eax
  add    %eax,(%rcx)
  add    $0x4,%rcx
  sub    $0x4,%rsi
  cmp    %r9,%rcx
  jne    L67
L10:
  movswl (%rdi),%eax
  shl    $0x9,%eax
  neg    %eax
  mov    %eax,(%r8,%r10,4)
  add    $0x1,%r10
  add    $0x2,%rdi
  add    $0x4,%rbx
  add    $0x1,%r11d
  cmp    %rbp,%r10
  je     L20
L48:
  mov    %r11d,%esi
  mov    $0x0,%eax
  test   %r10d,%r10d
  jg     L70
  jmp    L10
L20:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void SKP_Silk_k2a(int *A_Q24, const short *rc_Q15, const int order) {
  int k, n;
  int Atmp[16];
  for (k = 0; k < order; k++) {
    for (n = 0; n < k; n++) {
      Atmp[n] = A_Q24[n];
    }
    for (n = 0; n < k; n++) {
      A_Q24[n] = ((A_Q24[n]) + ((((((Atmp[k - n - 1]) << (1))) >> 16) * (int)((short)(rc_Q15[k]))) + ((((((Atmp[k - n - 1]) << (1))) & 0x0000FFFF) * (int)((short)(rc_Q15[k]))) >> 16)));
    }
    A_Q24[k] = -(((int)rc_Q15[k]) << (9));
  }
}
```