ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_indir>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip@plt>
  xor    %r8d,%r8d
  cmpb   $0x28,(%rax)
  jne    L36
  lea    0x1(%rax),%rdi
  cmp    %rbx,%rdi
  jae    L36
  mov    $0x1,%eax
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L43:
  cmp    $0x29,%dl
  sete   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  test   %eax,%eax
  jle    L50
L53:
  cmp    %rdi,%rbx
  jbe    L50
L33:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  cmp    $0x28,%dl
  jne    L43
  add    $0x1,%eax
  test   %eax,%eax
  jg     L53
  nopw   0x0(%rax,%rax,1)
L50:
  test   %eax,%eax
  sete   %bpl
  movzbl %bpl,%r8d
  cmp    %rdi,%rbx
  ja     L2
L36:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  call   <skip@plt>
  cmp    %rax,%rbx
  setbe  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  and    %ebp,%eax
  pop    %rbp
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_indir(char *p, char *q) {
  char c;
  int n;
  p = skip(p);
  if (*p++ != '(')
    return 0;
  n = 1;
  while (n > 0 && p < q) {
    c = *p++;
    if (c == '(')
      n++;
    else if (c == ')')
      n--;
  }
  if (p < q)
    p = skip(p);
  return n == 0 && p >= q;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_indir>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <skip@plt>
  xor    %r8d,%r8d
  cmpb   $0x28,(%rax)
  jne    L36
  lea    0x1(%rax),%rdi
  cmp    %rbx,%rdi
  jae    L36
  mov    $0x1,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    $0x29,%dl
  sete   %dl
  movzbl %dl,%edx
  sub    %edx,%eax
  cmp    %rdi,%rbx
  jbe    L20
L1:
  test   %eax,%eax
  jle    L20
L11:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  cmp    $0x28,%dl
  jne    L10
  add    $0x1,%eax
  cmp    %rdi,%rbx
  ja     L1
  nopl   0x0(%rax,%rax,1)
L20:
  test   %eax,%eax
  sete   %bpl
  movzbl %bpl,%r8d
  cmp    %rdi,%rbx
  ja     L56
L36:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L56:
  call   <skip@plt>
  cmp    %rax,%rbx
  setbe  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  and    %ebp,%eax
  pop    %rbp
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int check_indir(char *p, char *q) {
  char c;
  int n;
  p = skip(p);
  if (*p++ != '(')
    return 0;
  n = 1;
  while (n > 0 && p < q) {
    c = *p++;
    if (c == '(')
      n++;
    else if (c == ')')
      n--;
  }
  if (p < q)
    p = skip(p);
  return n == 0 && p >= q;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<roi_set_clean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x87,(%rax)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int roi_set_clean(unsigned char *buff) {
  buff[0] = (135);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<roi_set_clean>:
  endbr64
  movb   $0x87,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int roi_set_clean(unsigned char *buff) {
  buff[0] = (135);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<roi_set_clean>:
  endbr64
  movb   $0x87,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int roi_set_clean(unsigned char *buff) {
  buff[0] = (135);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<roi_set_clean>:
  endbr64
  movb   $0x87,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int roi_set_clean(unsigned char *buff) {
  buff[0] = (135);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ERI_Interpolate_Linear_Complex>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movq   %xmm0,%rbx
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %ecx,%r14d
  test   %ecx,%ecx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14d,%r14d
  jle    L49
  mov    %r13,%rdx
  mov    $0x0,%eax
L22:
  movq   %rbx,%xmm5
  comisd (%rdx),%xmm5
  jbe    L16
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%r14d
  jne    L22
  test   %r14d,%r14d
  jne    L32
L49:
  movsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%r12)
  movsd  0x8(%rbp),%xmm0
  jmp    L23
L16:
  test   %eax,%eax
  je     L49
  cmp    %eax,%r14d
  je     L32
  movslq %eax,%rcx
  movsd  -0x8(%r13,%rcx,8),%xmm1
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  movsd  -0x10(%rbp,%rdx,1),%xmm4
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  movsd  0x0(%r13,%rcx,8),%xmm3
  subsd  %xmm1,%xmm3
  movsd  0x0(%rbp,%rax,8),%xmm2
  subsd  %xmm4,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm4,%xmm1
  movsd  %xmm1,(%r12)
  movsd  -0x8(%rbp,%rdx,1),%xmm2
  movsd  0x8(%rbp,%rax,8),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
L23:
  movsd  %xmm0,0x8(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  lea    (%r14,%r14,1),%eax
  cltq
  shl    $0x3,%rax
  movsd  -0x10(%rbp,%rax,1),%xmm0
  movsd  %xmm0,(%r12)
  movsd  -0x8(%rbp,%rax,1),%xmm0
  jmp    L23
```

assistant: ```c
void ERI_Interpolate_Linear_Complex(double out[2], double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    out[0] = sy[0];
    out[1] = sy[1];
    return;
  }
  if (i == ns) {
    out[0] = sy[2 * ns - 2];
    out[1] = sy[2 * ns - 1];
    return;
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[2 * i - 2];
  y1 = sy[2 * i + 0];
  out[0] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
  y0 = sy[2 * i - 1];
  y1 = sy[2 * i + 1];
  out[1] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ERI_Interpolate_Linear_Complex>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  setg   %dil
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  xor    %edx,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  movsd  0x8(%rsp),%xmm0
  jg     L40
  jmp    L39
  nop
L33:
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%ebx
  je     L3
L40:
  movsd  0x0(%r13,%rdx,1),%xmm1
  comisd %xmm1,%xmm0
  ja     L33
  test   %eax,%eax
  je     L39
  add    %eax,%eax
  movsd  -0x8(%r13,%rdx,1),%xmm2
  cltq
  movsd  (%r12,%rax,8),%xmm3
  lea    0x0(,%rax,8),%rdx
  subsd  %xmm2,%xmm0
  movsd  -0x10(%r12,%rdx,1),%xmm4
  subsd  %xmm2,%xmm1
  subsd  %xmm4,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  addsd  %xmm4,%xmm2
  movsd  %xmm2,0x0(%rbp)
  movsd  -0x8(%r12,%rdx,1),%xmm3
  movsd  0x8(%r12,%rax,8),%xmm2
  subsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L39:
  movsd  (%r12),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%r12),%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    (%rbx,%rbx,1),%eax
  cltq
  shl    $0x3,%rax
  movsd  -0x10(%r12,%rax,1),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  -0x8(%r12,%rax,1),%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ERI_Interpolate_Linear_Complex(double out[2], double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    out[0] = sy[0];
    out[1] = sy[1];
    return;
  }
  if (i == ns) {
    out[0] = sy[2 * ns - 2];
    out[1] = sy[2 * ns - 1];
    return;
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[2 * i - 2];
  y1 = sy[2 * i + 0];
  out[0] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
  y0 = sy[2 * i - 1];
  y1 = sy[2 * i + 1];
  out[1] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ERI_Interpolate_Linear_Complex>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  test   %ecx,%ecx
  setg   %dil
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  xor    %edx,%edx
  xor    %eax,%eax
  test   %ebx,%ebx
  movsd  0x8(%rsp),%xmm0
  jg     L34
  jmp    L23
  nop
L45:
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%ebx
  je     L40
L34:
  movsd  0x0(%r13,%rdx,1),%xmm1
  comisd %xmm1,%xmm0
  ja     L45
  test   %eax,%eax
  je     L23
  add    %eax,%eax
  movsd  -0x8(%r13,%rdx,1),%xmm2
  cltq
  movsd  (%r12,%rax,8),%xmm3
  lea    0x0(,%rax,8),%rdx
  subsd  %xmm2,%xmm0
  movsd  -0x10(%r12,%rdx,1),%xmm4
  subsd  %xmm2,%xmm1
  subsd  %xmm4,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  addsd  %xmm4,%xmm2
  movsd  %xmm2,0x0(%rbp)
  movsd  -0x8(%r12,%rdx,1),%xmm3
  movsd  0x8(%r12,%rax,8),%xmm2
  subsd  %xmm3,%xmm2
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L23:
  movsd  (%r12),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%r12),%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  lea    (%rbx,%rbx,1),%eax
  cltq
  shl    $0x3,%rax
  movsd  -0x10(%r12,%rax,1),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  -0x8(%r12,%rax,1),%xmm0
  movsd  %xmm0,0x8(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ERI_Interpolate_Linear_Complex(double out[2], double x, const double *sx, const double *sy, int ns) {
  int i;
  double x0, x1, y0, y1;
  assert(0 < ns);
  for (i = 0; i < ns && sx[i] < x; i++)
    ;
  if (i == 0) {
    out[0] = sy[0];
    out[1] = sy[1];
    return;
  }
  if (i == ns) {
    out[0] = sy[2 * ns - 2];
    out[1] = sy[2 * ns - 1];
    return;
  }
  x0 = sx[i - 1];
  x1 = sx[i];
  y0 = sy[2 * i - 2];
  y1 = sy[2 * i + 0];
  out[0] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
  y0 = sy[2 * i - 1];
  y1 = sy[2 * i + 1];
  out[1] = y0 + (y1 - y0) * (x - x0) / (x1 - x0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fts_padjust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L12
L17:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  je     L50
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L50:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,0x10(%rax)
  mov    -0x10(%rbp),%rax
  mov    0x28(%rax),%rax
  mov    %rax,-0x10(%rbp)
L12:
  cmpq   $0x0,-0x10(%rbp)
  jne    L17
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L49
L33:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  je     L75
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L75:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,0x10(%rax)
  mov    -0x10(%rbp),%rax
  mov    0x28(%rax),%rax
  test   %rax,%rax
  je     L30
  mov    -0x10(%rbp),%rax
  mov    0x28(%rax),%rax
  jmp    L34
L30:
  mov    -0x10(%rbp),%rax
  mov    0x20(%rax),%rax
L34:
  mov    %rax,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fts_padjust(FTS *sp, FTSENT *head) {
  FTSENT *p;
  char *addr = sp->fts_path;
  for (p = sp->fts_child; p; p = p->fts_link) {
    if ((p)->fts_accpath != (p)->fts_name) {
      (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
    }
    (p)->fts_path = addr;
  };
  for (p = head; p->fts_level >= FTS_ROOTLEVEL;) {
    {
      if ((p)->fts_accpath != (p)->fts_name) {
        (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
      }
      (p)->fts_path = addr;
    };
    p = p->fts_link ? p->fts_link : p->fts_parent;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fts_padjust>:
  endbr64
  mov    (%rdi),%rcx
  mov    0x8(%rdi),%rax
  test   %rax,%rax
  jne    L6
L96:
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,0x18(%rsi)
  jl     L72
  mov    D0(%rip),%rdx
  jmp    L2
L98:
  sub    0x10(%rax),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
L7:
  mov    %rcx,0x10(%rax)
  mov    0x28(%rax),%rax
  test   %rax,%rax
  je     L96
L6:
  mov    (%rax),%rdx
  cmp    0x8(%rax),%rdx
  jne    L98
  jmp    L7
L80:
  mov    0x20(%rsi),%rsi
L21:
  mov    (%rdx),%rax
  cmp    %rax,0x18(%rsi)
  jl     L72
L2:
  mov    (%rsi),%rax
  cmp    0x8(%rsi),%rax
  je     L31
  sub    0x10(%rsi),%rax
  add    %rcx,%rax
  mov    %rax,(%rsi)
L31:
  mov    %rcx,0x10(%rsi)
  mov    0x28(%rsi),%rax
  test   %rax,%rax
  je     L80
  mov    %rax,%rsi
  jmp    L21
L72:
  ret
```

assistant: ```c
void fts_padjust(FTS *sp, FTSENT *head) {
  FTSENT *p;
  char *addr = sp->fts_path;
  for (p = sp->fts_child; p; p = p->fts_link) {
    if ((p)->fts_accpath != (p)->fts_name) {
      (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
    }
    (p)->fts_path = addr;
  };
  for (p = head; p->fts_level >= FTS_ROOTLEVEL;) {
    {
      if ((p)->fts_accpath != (p)->fts_name) {
        (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
      }
      (p)->fts_path = addr;
    };
    p = p->fts_link ? p->fts_link : p->fts_parent;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fts_padjust>:
  endbr64
  mov    0x8(%rdi),%rax
  mov    (%rdi),%rcx
  test   %rax,%rax
  je     L26
L43:
  mov    (%rax),%rdx
  cmp    0x8(%rax),%rdx
  je     L20
  sub    0x10(%rax),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
L20:
  mov    %rcx,0x10(%rax)
  mov    0x28(%rax),%rax
  test   %rax,%rax
  jne    L43
L26:
  mov    D4(%rip),%rax
  mov    (%rax),%rdx
L10:
  cmp    %rdx,0x18(%rsi)
  jl     L77
L39:
  mov    (%rsi),%rax
  cmp    0x8(%rsi),%rax
  je     L65
  sub    0x10(%rsi),%rax
  add    %rcx,%rax
  mov    %rax,(%rsi)
L65:
  mov    0x28(%rsi),%rax
  mov    %rcx,0x10(%rsi)
  test   %rax,%rax
  je     L48
  mov    %rax,%rsi
  cmp    %rdx,0x18(%rsi)
  jge    L39
L77:
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    0x20(%rsi),%rsi
  jmp    L10
```

assistant: ```c
void fts_padjust(FTS *sp, FTSENT *head) {
  FTSENT *p;
  char *addr = sp->fts_path;
  for (p = sp->fts_child; p; p = p->fts_link) {
    if ((p)->fts_accpath != (p)->fts_name) {
      (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
    }
    (p)->fts_path = addr;
  };
  for (p = head; p->fts_level >= FTS_ROOTLEVEL;) {
    {
      if ((p)->fts_accpath != (p)->fts_name) {
        (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
      }
      (p)->fts_path = addr;
    };
    p = p->fts_link ? p->fts_link : p->fts_parent;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fts_padjust>:
  endbr64
  mov    0x8(%rdi),%rax
  mov    (%rdi),%rcx
  test   %rax,%rax
  je     L10
L54:
  mov    (%rax),%rdx
  cmp    0x8(%rax),%rdx
  je     L16
  sub    0x10(%rax),%rdx
  mov    %rcx,0x10(%rax)
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    0x28(%rax),%rax
  test   %rax,%rax
  jne    L54
L10:
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  cmp    %rdx,0x18(%rsi)
  jge    L24
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    0x18(%rax),%rdx
  jg     L12
L74:
  mov    %rax,%rsi
L24:
  mov    (%rsi),%rax
  cmp    %rax,0x8(%rsi)
  je     L39
  sub    0x10(%rsi),%rax
  add    %rcx,%rax
  mov    %rax,(%rsi)
L39:
  mov    0x28(%rsi),%rax
  mov    %rcx,0x10(%rsi)
  test   %rax,%rax
  jne    L57
  mov    0x20(%rsi),%rax
  cmp    0x18(%rax),%rdx
  jle    L74
  ret
  nopl   0x0(%rax)
L16:
  mov    %rcx,0x10(%rax)
  mov    0x28(%rax),%rax
  test   %rax,%rax
  jne    L54
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  cmp    %rdx,0x18(%rsi)
  jge    L24
L12:
  ret
```

assistant: ```c
void fts_padjust(FTS *sp, FTSENT *head) {
  FTSENT *p;
  char *addr = sp->fts_path;
  for (p = sp->fts_child; p; p = p->fts_link) {
    if ((p)->fts_accpath != (p)->fts_name) {
      (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
    }
    (p)->fts_path = addr;
  };
  for (p = head; p->fts_level >= FTS_ROOTLEVEL;) {
    {
      if ((p)->fts_accpath != (p)->fts_name) {
        (p)->fts_accpath = (char *)addr + ((p)->fts_accpath - (p)->fts_path);
      }
      (p)->fts_path = addr;
    };
    p = p->fts_link ? p->fts_link : p->fts_parent;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  cmpl   $0x6,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: Number of counter: %d


assistant: ```c
int main() {
  int counter = 1;
  while (counter < 7)
    printf("Number of counter: %d\n", counter++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D5(%rip),%rbp
L0:
  mov    %ebx,%esi
  add    $0x1,%ebx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x7,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: Number of counter: %d


assistant: ```c
int main() {
  int counter = 1;
  while (counter < 7)
    printf("Number of counter: %d\n", counter++);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: Number of counter: %d


assistant: ```c
int main() {
  int counter = 1;
  while (counter < 7)
    printf("Number of counter: %d\n", counter++);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebx
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: Number of counter: %d


assistant: ```c
int main() {
  int counter = 1;
  while (counter < 7)
    printf("Number of counter: %d\n", counter++);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
L101:
  addl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L83
L38:
  mov    -0x28(%rbp),%eax
  cltq
  movb   $0x0,-0x1e(%rbp,%rax,1)
  addl   $0x1,-0x28(%rbp)
L83:
  cmpl   $0xa,-0x28(%rbp)
  jle    L38
  movl   $0x0,-0x28(%rbp)
  jmp    L69
L24:
  mov    -0x28(%rbp),%eax
  cltq
  movb   $0x0,-0x13(%rbp,%rax,1)
  addl   $0x1,-0x28(%rbp)
L69:
  cmpl   $0xa,-0x28(%rbp)
  jle    L24
  movl   $0x0,-0x28(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   %eax,%eax
  je     L12
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1e(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x13(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L43
L82:
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L62
  lea    -0x1e(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L61
L62:
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L61:
  addl   $0x1,-0x28(%rbp)
L43:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jl     L82
  jmp    L101
L12:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D1
type: string
name: parse_data
arguments: tag: D21
type: string
name: parse_data
arguments: tag: D7
type: string

tool: D18: %d

tool: D1: Teste %d


tool: D21: %s

tool: D7: %d %d

assistant: ```c
int main() {
  int a = 0, b = 0, n = 0, i = 0, teste = 0;
  char na[11], nb[11];
  while (1) {
    teste++;
    a = 0;
    b = 0;
    n = 0;
    i = 0;
    for (i; i < 11; i++)
      na[i] = '\0';
    i = 0;
    for (i; i < 11; i++)
      nb[i] = '\0';
    i = 0;
    scanf("%d", &n);
    if (n == 0)
      break;
    printf("Teste %d\n", teste);
    scanf("%s", na);
    scanf("%s", nb);
    for (i; i < n; i++) {
      a = 0;
      b = 0;
      scanf("%d %d", &a, &b);
      if ((a + b) % 2 == 0)
        printf("%s\n", na);
      else
        printf("%s\n", nb);
    }
  }
  return 0;
}
```