ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<isControlCharOrSlash>:
  endbr64
  cmp    $0x2f,%dil
  sete   %al
  cmp    $0x20,%dil
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
__attribute__((pure)) int isControlCharOrSlash(const char c) {
  if ((unsigned char)c < '!')
    return !0;
  if (c == '/')
    return !0;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ChgMark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <SubVertexList@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <AssignVertexMark@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <AddVertexList@plt>
  nop
  leave
  ret
```

assistant: ```c
void ChgMark(PDMCSchema, V, M) struct frvStruct *PDMCSchema;
struct Vertex *V;
struct Mark *M;
{
  SubVertexList(PDMCSchema, V);
  AssignVertexMark(V, M);
  AddVertexList(PDMCSchema, V);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ChgMark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <SubVertexList@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <AssignVertexMark@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <AddVertexList@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ChgMark(PDMCSchema, V, M) struct frvStruct *PDMCSchema;
struct Vertex *V;
struct Mark *M;
{
  SubVertexList(PDMCSchema, V);
  AssignVertexMark(V, M);
  AddVertexList(PDMCSchema, V);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ChgMark>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  call   <SubVertexList@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <AssignVertexMark@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1070 <AddVertexList@plt>
```

assistant: ```c
void ChgMark(PDMCSchema, V, M) struct frvStruct *PDMCSchema;
struct Vertex *V;
struct Mark *M;
{
  SubVertexList(PDMCSchema, V);
  AssignVertexMark(V, M);
  AddVertexList(PDMCSchema, V);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ChgMark>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  call   <SubVertexList@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <AssignVertexMark@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1070 <AddVertexList@plt>
```

assistant: ```c
void ChgMark(PDMCSchema, V, M) struct frvStruct *PDMCSchema;
struct Vertex *V;
struct Mark *M;
{
  SubVertexList(PDMCSchema, V);
  AssignVertexMark(V, M);
  AddVertexList(PDMCSchema, V);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<receiveMessage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x34(%rbp)
  jns    L42
  mov    $0xffffffff,%eax
  jmp    L43
L42:
  mov    -0x48(%rbp),%rax
  add    $0x64,%rax
  mov    %rax,-0x20(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x8,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  mov    -0x48(%rbp),%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  sub    %rdx,%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recvfromTimeOut@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  ja     L26
  mov    $0xffffffff,%eax
  jmp    L43
L26:
  mov    -0x38(%rbp),%edx
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x24(%rbp)
  nop
  mov    -0x24(%rbp),%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int receiveMessage(int sock, void *message, int maxLength, unsigned long timeout) {
  unsigned long val;
  long timeout_s;
  long timeout_us;
  int bytesReceived;
  if (sock < 0) {
    return -1;
  }
  val = timeout + 100;
  setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &val, sizeof(unsigned long));
  timeout_s = timeout / 1000;
  timeout_us = (timeout - (timeout_s * 1000)) * 1000;
  bytesReceived = 0;
  switch (recvfromTimeOut(sock, timeout_s, timeout_us)) {
  case 0:
  case -1:
    return -1;
    break;
  default:
    bytesReceived = recv(sock, message, maxLength, 0);
    break;
  }
  return bytesReceived;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<receiveMessage>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L28
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%rbx
  lea    0x64(%rcx),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rcx
  mov    $0x8,%r8d
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    %rbx,%rsi
  shr    $0x3,%rsi
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x4,%rdx
  mov    %rdx,%rsi
  imul   $0x3e8,%rdx,%rax
  sub    %rax,%rbx
  imul   $0x3e8,%rbx,%rdx
  mov    %ebp,%edi
  call   <recvfromTimeOut@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L13
  mov    $0x0,%ecx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L27
L13:
  mov    $0xffffffff,%eax
  jmp    L27
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int receiveMessage(int sock, void *message, int maxLength, unsigned long timeout) {
  unsigned long val;
  long timeout_s;
  long timeout_us;
  int bytesReceived;
  if (sock < 0) {
    return -1;
  }
  val = timeout + 100;
  setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &val, sizeof(unsigned long));
  timeout_s = timeout / 1000;
  timeout_us = (timeout - (timeout_s * 1000)) * 1000;
  bytesReceived = 0;
  switch (recvfromTimeOut(sock, timeout_s, timeout_us)) {
  case 0:
  case -1:
    return -1;
    break;
  default:
    bytesReceived = recv(sock, message, maxLength, 0);
    break;
  }
  return bytesReceived;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<receiveMessage>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L0
  lea    0x64(%rcx),%rax
  mov    %edx,%r13d
  mov    %rsi,%r12
  mov    %rcx,%rbx
  mov    %rax,(%rsp)
  mov    D4(%rip),%rax
  mov    %rsp,%rcx
  mov    %edi,%ebp
  mov    $0x8,%r8d
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  movabs $0x20c49ba5e353f7cf,%rdx
  shr    $0x3,%rsi
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x4,%rdx
  imul   $0x3e8,%rdx,%rax
  mov    %rdx,%rsi
  sub    %rax,%rbx
  imul   $0x3e8,%rbx,%rdx
  call   <recvfromTimeOut@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L0
  xor    %ecx,%ecx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%eax
  jmp    L11
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int receiveMessage(int sock, void *message, int maxLength, unsigned long timeout) {
  unsigned long val;
  long timeout_s;
  long timeout_us;
  int bytesReceived;
  if (sock < 0) {
    return -1;
  }
  val = timeout + 100;
  setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &val, sizeof(unsigned long));
  timeout_s = timeout / 1000;
  timeout_us = (timeout - (timeout_s * 1000)) * 1000;
  bytesReceived = 0;
  switch (recvfromTimeOut(sock, timeout_s, timeout_us)) {
  case 0:
  case -1:
    return -1;
    break;
  default:
    bytesReceived = recv(sock, message, maxLength, 0);
    break;
  }
  return bytesReceived;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<receiveMessage>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L6
  lea    0x64(%rcx),%rax
  mov    %edx,%r13d
  mov    %rsi,%r12
  mov    %rcx,%rbx
  mov    %rax,(%rsp)
  mov    D19(%rip),%rax
  mov    %rsp,%rcx
  mov    %edi,%ebp
  mov    $0x8,%r8d
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  movabs $0x20c49ba5e353f7cf,%rdx
  shr    $0x3,%rsi
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x4,%rdx
  imul   $0x3e8,%rdx,%rax
  mov    %rdx,%rsi
  sub    %rax,%rbx
  imul   $0x3e8,%rbx,%rdx
  call   <recvfromTimeOut@plt>
  add    $0x1,%eax
  cmp    $0x1,%eax
  jbe    L6
  xor    %ecx,%ecx
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
L30:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L6:
  mov    $0xffffffff,%eax
  jmp    L30
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int receiveMessage(int sock, void *message, int maxLength, unsigned long timeout) {
  unsigned long val;
  long timeout_s;
  long timeout_us;
  int bytesReceived;
  if (sock < 0) {
    return -1;
  }
  val = timeout + 100;
  setsockopt(sock, SOL_SOCKET, SO_RCVTIMEO, &val, sizeof(unsigned long));
  timeout_s = timeout / 1000;
  timeout_us = (timeout - (timeout_s * 1000)) * 1000;
  bytesReceived = 0;
  switch (recvfromTimeOut(sock, timeout_s, timeout_us)) {
  case 0:
  case -1:
    return -1;
    break;
  default:
    bytesReceived = recv(sock, message, maxLength, 0);
    break;
  }
  return bytesReceived;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<special>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  je     L19
  cmpl   $0x81,-0x4(%rbp)
  je     L9
  jmp    L28
L19:
  mov    $0x0,%eax
  call   <alphaup@plt>
  jmp    L28
L9:
  mov    $0x0,%eax
  call   <alphadown@plt>
  nop
L28:
  nop
  leave
  ret
```

assistant: ```c
void special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    alphaup();
    break;
  case GLUT_KEY_DOWN:
    alphadown();
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<special>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x80,%edi
  je     L37
  cmp    $0x81,%edi
  je     L23
L32:
  add    $0x8,%rsp
  ret
L37:
  mov    $0x0,%eax
  call   <alphaup@plt>
  jmp    L32
L23:
  mov    $0x0,%eax
  call   <alphadown@plt>
  jmp    L32
```

assistant: ```c
void special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    alphaup();
    break;
  case GLUT_KEY_DOWN:
    alphadown();
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<special>:
  endbr64
  cmp    $0x80,%edi
  je     L11
  cmp    $0x81,%edi
  jne    L0
  xor    %eax,%eax
  jmp    1060 <alphadown@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  jmp    1070 <alphaup@plt>
```

assistant: ```c
void special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    alphaup();
    break;
  case GLUT_KEY_DOWN:
    alphadown();
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<special>:
  endbr64
  cmp    $0x80,%edi
  je     L16
  cmp    $0x81,%edi
  jne    L0
  xor    %eax,%eax
  jmp    1060 <alphadown@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  jmp    1070 <alphaup@plt>
```

assistant: ```c
void special(int key, int x, int y) {
  switch (key) {
  case GLUT_KEY_UP:
    alphaup();
    break;
  case GLUT_KEY_DOWN:
    alphadown();
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_base64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    $0x22,%edx
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x17,%edx
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x17,%edx
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %eax,%ebx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x40(%rbp),%rax
  mov    $0x21,%r8d
  mov    %ebx,%ecx
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x40(%rbp),%rcx
  lea    -0x60(%rbp),%rax
  mov    $0x17,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base64_decode@plt>
  mov    %rax,-0x68(%rbp)
  mov    -0x70(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shr    $0x2,%rax
  mov    %eax,%r12d
  mov    -0x68(%rbp),%rax
  mov    %eax,%ebx
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x60(%rbp),%rax
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  add    $0x60,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D17
type: string
name: unpack_data
arguments: label: D25
type: string

tool: D20: Hello!12345612356..:-)

tool: D17: Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i


tool: D25: Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i


assistant: ```c
void test_base64(void) {
  char str1[((((23) * 4) / 3) + 3) + 1];
  char str2[23];
  memset(str1, 'x', sizeof(str1));
  memset(str2, 'x', sizeof(str2));
  size_t len_enc = base64_encode(str1, (unsigned char *)"Hello!12345612356..:-)", 23);
  printf("Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i\n", str1, (int)strlen(str1), (int)len_enc, ((((23) * 4) / 3) + 3));
  size_t len_dec = base64_decode((unsigned char *)str2, str1, 23);
  printf("Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i\n", str2, (int)strlen(str2), (int)len_dec, (int)((((len_enc)) * 3) / 4));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_base64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbx
  mov    $0x22,%edx
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rsp,%r12
  mov    $0x17,%edx
  mov    $0x78,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x17,%edx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <base64_encode@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    $0x21,%r8d
  mov    %ebp,%ecx
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <base64_decode@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rbp,2),%r8
  shr    $0x2,%r8
  mov    %ebx,%ecx
  mov    %eax,%edx
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D11: Hello!12345612356..:-)

tool: D13: Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i


tool: D10: Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i


assistant: ```c
void test_base64(void) {
  char str1[((((23) * 4) / 3) + 3) + 1];
  char str2[23];
  memset(str1, 'x', sizeof(str1));
  memset(str2, 'x', sizeof(str2));
  size_t len_enc = base64_encode(str1, (unsigned char *)"Hello!12345612356..:-)", 23);
  printf("Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i\n", str1, (int)strlen(str1), (int)len_enc, ((((23) * 4) / 3) + 3));
  size_t len_dec = base64_decode((unsigned char *)str2, str1, 23);
  printf("Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i\n", str2, (int)strlen(str2), (int)len_dec, (int)((((len_enc)) * 3) / 4));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_base64>:
  endbr64
  push   %r13
  mov    $0x22,%edx
  mov    $0x78,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %rsp,%r13
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x17,%edx
  mov    $0x78,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x17,%edx
  lea    D20(%rip),%rsi
  mov    %r12,%rdi
  call   <base64_encode@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    $0x21,%r8d
  mov    %ebp,%ecx
  mov    %r12,%rsi
  mov    %eax,%edx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <base64_decode@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x0(%rbp,%rbp,2),%r8
  mov    %ebx,%ecx
  mov    %r13,%rsi
  shr    $0x2,%r8
  mov    %eax,%edx
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string

tool: D20: Hello!12345612356..:-)

tool: D12: Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i


tool: D27: Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i


assistant: ```c
void test_base64(void) {
  char str1[((((23) * 4) / 3) + 3) + 1];
  char str2[23];
  memset(str1, 'x', sizeof(str1));
  memset(str2, 'x', sizeof(str2));
  size_t len_enc = base64_encode(str1, (unsigned char *)"Hello!12345612356..:-)", 23);
  printf("Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i\n", str1, (int)strlen(str1), (int)len_enc, ((((23) * 4) / 3) + 3));
  size_t len_dec = base64_decode((unsigned char *)str2, str1, 23);
  printf("Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i\n", str2, (int)strlen(str2), (int)len_dec, (int)((((len_enc)) * 3) / 4));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_base64>:
  endbr64
  push   %r13
  mov    $0x22,%edx
  mov    $0x78,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %rsp,%r13
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x17,%edx
  mov    $0x78,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x17,%edx
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <base64_encode@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    $0x21,%r8d
  mov    %ebp,%ecx
  mov    %r12,%rsi
  mov    %eax,%edx
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <base64_decode@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    0x0(%rbp,%rbp,2),%r8
  mov    %ebx,%ecx
  mov    %r13,%rsi
  shr    $0x2,%r8
  mov    %eax,%edx
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D11
type: string

tool: D4: Hello!12345612356..:-)

tool: D14: Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i


tool: D11: Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i


assistant: ```c
void test_base64(void) {
  char str1[((((23) * 4) / 3) + 3) + 1];
  char str2[23];
  memset(str1, 'x', sizeof(str1));
  memset(str2, 'x', sizeof(str2));
  size_t len_enc = base64_encode(str1, (unsigned char *)"Hello!12345612356..:-)", 23);
  printf("Encoded: %s strlen=%i len_enc=%i macro_encoded_size=%i\n", str1, (int)strlen(str1), (int)len_enc, ((((23) * 4) / 3) + 3));
  size_t len_dec = base64_decode((unsigned char *)str2, str1, 23);
  printf("Decoded: %s strlen=%i len_dec=%i macro_decode_size=%i\n", str2, (int)strlen(str2), (int)len_dec, (int)((((len_enc)) * 3) / 4));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Open_clientfd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open_clientfd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L24
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <unix_error@plt>
  jmp    L14
L24:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <dns_error@plt>
L14:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string

tool: D13: Open_clientfd Unix error

tool: D10: Open_clientfd DNS error

assistant: ```c
int Open_clientfd(char *hostname, int port) {
  int rc;
  if ((rc = open_clientfd(hostname, port)) < 0) {
    if (rc == -1)
      unix_error("Open_clientfd Unix error");
    else
      dns_error("Open_clientfd DNS error");
  }
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Open_clientfd>:
  endbr64
  push   %rbx
  call   <open_clientfd@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L25
L9:
  mov    %ebx,%eax
  pop    %rbx
  ret
L25:
  cmp    $0xffffffff,%eax
  je     L18
  lea    D2(%rip),%rdi
  call   <dns_error@plt>
  jmp    L9
L18:
  lea    D14(%rip),%rdi
  call   <unix_error@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D2: Open_clientfd DNS error

tool: D14: Open_clientfd Unix error

assistant: ```c
int Open_clientfd(char *hostname, int port) {
  int rc;
  if ((rc = open_clientfd(hostname, port)) < 0) {
    if (rc == -1)
      unix_error("Open_clientfd Unix error");
    else
      dns_error("Open_clientfd DNS error");
  }
  return rc;
}
```