ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D49(%rip),%rbp
  sub    $0x40,%rsp
  movdqa D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <optimalStrategyOfGame@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x4,%esi
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <optimalStrategyOfGame@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x6,%esi
  movdqa D6(%rip),%xmm0
  mov    D8(%rip),%rax
  movaps %xmm0,0x20(%rsp)
  mov    %rax,0x30(%rsp)
  call   <optimalStrategyOfGame@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D49
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D10
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D6
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D8
type_guessed: byte[8]

tool: D49: %d


tool: {"D27": [0x08,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D10": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D6": [0x14,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D8": [0x02,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int arr1[] = {8, 15, 3, 7};
  int n = sizeof(arr1) / sizeof(arr1[0]);
  printf("%d\n", optimalStrategyOfGame(arr1, n));
  int arr2[] = {2, 2, 2, 2};
  n = sizeof(arr2) / sizeof(arr2[0]);
  printf("%d\n", optimalStrategyOfGame(arr2, n));
  int arr3[] = {20, 30, 2, 2, 2, 10};
  n = sizeof(arr3) / sizeof(arr3[0]);
  printf("%d\n", optimalStrategyOfGame(arr3, n));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0xff,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: 
%d%c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n%d%c", i, c);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L0:
  movsbl %bl,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: 
%d%c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n%d%c", i, c);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl %bl,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: 
%d%c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n%d%c", i, c);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl %bl,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: 
%d%c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n%d%c", i, c);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x6c(%rbp)
  movl   $0x0,-0x64(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L23
L47:
  mov    -0x68(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L58
  mov    -0x68(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x64(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x64(%rbp)
L58:
  addl   $0x1,-0x68(%rbp)
L23:
  cmpl   $0x28,-0x68(%rbp)
  jle    L47
  movl   $0x0,-0x68(%rbp)
  jmp    L1
L0:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  add    %eax,-0x6c(%rbp)
  addl   $0x1,-0x68(%rbp)
L1:
  cmpl   $0x14,-0x68(%rbp)
  jle    L0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x6c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string
name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D0: ----------

tool: D28: %d 

tool: D11: 
----------

tool: D5: Total: %d

assistant: ```c
void main() {
  int nums[21];
  int total = 0;
  int i;
  int i2 = 0;
  printf("----------\n");
  for (i = 0; i < 41; i += 1) {
    if (((i + 1) % 2) == 1) {
      nums[i2] = i + 1;
      i2 += 1;
    }
  }
  for (i = 0; i < 21; i += 1) {
    printf("%d ", nums[i]);
    total += nums[i];
  }
  printf("\n----------\n");
  printf("Total: %d", total);
  printf("\n----------");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L42
L21:
  cmp    $0x29,%edx
  je     L39
L42:
  add    $0x1,%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  cmp    $0x1,%eax
  jne    L21
  movslq %esi,%rax
  mov    %edx,(%rsp,%rax,4)
  add    $0x1,%esi
  jmp    L21
L39:
  mov    %rsp,%rbx
  lea    0x54(%rsp),%r14
  mov    $0x0,%r12d
  lea    D9(%rip),%r13
L9:
  mov    (%rbx),%ebp
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %ebp,%r12d
  add    $0x4,%rbx
  cmp    %rbx,%r14
  jne    L9
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D39
data_type: string
name: unpack_data
arguments: tag: D9
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D1
data_type: string

tool: D39: ----------

tool: D9: %d 

tool: D26: 
----------

tool: D1: Total: %d

assistant: ```c
void main() {
  int nums[21];
  int total = 0;
  int i;
  int i2 = 0;
  printf("----------\n");
  for (i = 0; i < 41; i += 1) {
    if (((i + 1) % 2) == 1) {
      nums[i2] = i + 1;
      i2 += 1;
    }
  }
  for (i = 0; i < 21; i += 1) {
    printf("%d ", nums[i]);
    total += nums[i];
  }
  printf("\n----------\n");
  printf("Total: %d", total);
  printf("\n----------");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %edx,%edx
  xor    %eax,%eax
L26:
  add    $0x1,%eax
  test   $0x1,%al
  je     L25
  movslq %edx,%rcx
  add    $0x1,%edx
  mov    %eax,(%rsp,%rcx,4)
L25:
  cmp    $0x29,%eax
  jne    L26
  mov    %rsp,%rbx
  lea    0x54(%rsp),%r14
  xor    %r12d,%r12d
  lea    D9(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L34:
  mov    (%rbx),%ebp
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  mov    %ebp,%esi
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L34
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x60,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <printf@plt>
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D17
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D29: ----------

tool: D9: %d 

tool: D17: 
----------

tool: D15: Total: %d

assistant: ```c
void main() {
  int nums[21];
  int total = 0;
  int i;
  int i2 = 0;
  printf("----------\n");
  for (i = 0; i < 41; i += 1) {
    if (((i + 1) % 2) == 1) {
      nums[i2] = i + 1;
      i2 += 1;
    }
  }
  for (i = 0; i < 21; i += 1) {
    printf("%d ", nums[i]);
    total += nums[i];
  }
  printf("\n----------\n");
  printf("Total: %d", total);
  printf("\n----------");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %edx,%edx
  xor    %eax,%eax
L17:
  add    $0x1,%eax
  test   $0x1,%al
  je     L23
  movslq %edx,%rcx
  add    $0x1,%edx
  mov    %eax,(%rsp,%rcx,4)
L23:
  cmp    $0x29,%eax
  jne    L17
  mov    %rsp,%rbx
  lea    0x54(%rsp),%r14
  xor    %r12d,%r12d
  lea    D33(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%ebp
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  mov    %ebp,%esi
  add    %ebp,%r12d
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L13
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x60,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <printf@plt>
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: string
name: parse_data
arguments: data_label: D33
type_guessed: string
name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D22: ----------

tool: D33: %d 

tool: D0: 
----------

tool: D6: Total: %d

assistant: ```c
void main() {
  int nums[21];
  int total = 0;
  int i;
  int i2 = 0;
  printf("----------\n");
  for (i = 0; i < 41; i += 1) {
    if (((i + 1) % 2) == 1) {
      nums[i2] = i + 1;
      i2 += 1;
    }
  }
  for (i = 0; i < 21; i += 1) {
    printf("%d ", nums[i]);
    total += nums[i];
  }
  printf("\n----------\n");
  printf("Total: %d", total);
  printf("\n----------");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D18(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L9
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bar@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L28
L9:
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string

tool: D18: a

tool: D1: b

assistant: ```c
main() {
  char *p = "a", *q = "b";
  if (p)
    if (bar(p, q))
      return 0;
  abort();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <bar@plt>
  test   %rax,%rax
  je     L19
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L19:
  call   <abort@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: tag: D10
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D10: b

tool: D15: a

assistant: ```c
main() {
  char *p = "a", *q = "b";
  if (p)
    if (bar(p, q))
      return 0;
  abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <bar@plt>
  test   %rax,%rax
  jne    L3
  call   <abort@plt>
L3:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string

tool: D15: b

tool: D7: a

assistant: ```c
main() {
  char *p = "a", *q = "b";
  if (p)
    if (bar(p, q))
      return 0;
  abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <bar@plt>
  test   %rax,%rax
  jne    L9
  call   <abort@plt>
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: string
name: unpack_data
arguments: label: D9
type_guessed: string

tool: D19: b

tool: D9: a

assistant: ```c
main() {
  char *p = "a", *q = "b";
  if (p)
    if (bar(p, q))
      return 0;
  abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L79:
  cmp    %rdx,%rsp
  je     L33
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L79
L33:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L35
  orq    $0x0,-0x8(%rsp,%rax,1)
L35:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L91
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,4),%r15
L65:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D39(%rip),%xmm0
  subss  D10(%rip),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %r15,%rbx
  jne    L65
L91:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L11
  mov    $0x0,%ebx
L70:
  mov    $0x1,%edx
  mov    %r14,%rsi
  movss  D4(%rip),%xmm0
  mov    %r12d,%edi
  call   <stdlib_strided_dsapxsum@plt>
  ucomisd %xmm0,%xmm0
  jp     L34
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L70
L11:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L21:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L34:
  lea    D26(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L21
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D10
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D4
type_guessed: byte[4]
name: retrieve_data
arguments: data_tag: D26
type_guessed: string

tool: {"D39": [0x00,0x40,0x9c,0x46]}

tool: {"D10": [0x00,0x40,0x1c,0x46]}

tool: {"D4": [0x00,0x00,0xa0,0x40]}

tool: D26: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsapxsum(len, 5.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L116
L63:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L63
L116:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L61
L117:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L119
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D5(%rip),%xmm0
  subss  D30(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L25
L119:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L104
  xor    %r14d,%r14d
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L104
L74:
  movss  D9(%rip),%xmm0
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dsapxsum@plt>
  ucomisd %xmm0,%xmm0
  jnp    L8
  lea    D10(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L102:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L104:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L102
  cs nopw 0x0(%rax,%rax,1)
L61:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L117
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: byte[4]
name: unpack_data
arguments: data_label: D30
type_infered: byte[4]
name: unpack_data
arguments: data_label: D9
type_infered: byte[4]
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: {"D5": [0x00,0x40,0x9c,0x46]}

tool: {"D30": [0x00,0x40,0x1c,0x46]}

tool: {"D9": [0x00,0x00,0xa0,0x40]}

tool: D10: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsapxsum(len, 5.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L78
L84:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L84
L78:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L77
L34:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L81
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,4),%r14
  nopl   0x0(%rax)
L50:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand_float@plt>
  mulss  D20(%rip),%xmm0
  subss  D15(%rip),%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %r14,%r15
  jne    L50
L81:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L15
  xor    %r14d,%r14d
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L107:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L15
L52:
  movss  D27(%rip),%xmm0
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dsapxsum@plt>
  ucomisd %xmm0,%xmm0
  jnp    L107
  lea    D18(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L119:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L119
  cs nopw 0x0(%rax,%rax,1)
L77:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L34
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: byte[4]
name: parse_data
arguments: data_tag: D15
data_type: byte[4]
name: parse_data
arguments: data_tag: D27
data_type: byte[4]
name: parse_data
arguments: data_tag: D18
data_type: string

tool: {"D20": [0x00,0x40,0x9c,0x46]}

tool: {"D15": [0x00,0x40,0x1c,0x46]}

tool: {"D27": [0x00,0x00,0xa0,0x40]}

tool: D18: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_float() * 20000.0f) - 10000.0f;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dsapxsum(len, 5.0f, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```