ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_len_word>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%ecx
  cmp    %sil,%al
  je     L42
  test   %al,%al
  je     L42
  mov    $0x1,%eax
  jmp    L22
  nopl   0x0(%rax)
L10:
  test   %dl,%dl
  je     L33
L22:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L10
L33:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_len_word(char const *s, char c) {
  int i;
  int len;
  i = 0;
  len = 0;
  while (s[i] != '\0' && s[i] != c) {
    i++;
    len++;
  }
  return (len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jb     L4
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <i2a>
  mov    %rax,-0x10(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x8(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  lea    D9(%rip),%rax
  movzbl (%rdx,%rax,1),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
char *i2a(unsigned i, char *a, unsigned r) {
  if (i / r > 0) {
    a = i2a(i / r, a, r);
  }
  *a = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[i % r];
  return a + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i2a>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edx,%ebp
  cmp    %edx,%edi
  jae    L13
L16:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ebp
  lea    D8(%rip),%rax
  movzbl (%rax,%rdx,1),%eax
  mov    %al,(%rsi)
  lea    0x1(%rsi),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %ebp
  mov    %eax,%edi
  mov    %ebp,%edx
  call   <i2a>
  mov    %rax,%rsi
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
char *i2a(unsigned i, char *a, unsigned r) {
  if (i / r > 0) {
    a = i2a(i / r, a, r);
  }
  *a = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[i % r];
  return a + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i2a>:
  endbr64
  push   %r13
  lea    D14(%rip),%rcx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%edi
  jae    L18
L8:
  mov    %ebp,%eax
  xor    %edx,%edx
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,(%rsi)
  add    $0x8,%rsp
  lea    0x1(%rsi),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ebx
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jae    L12
L22:
  mov    %r12d,%eax
  xor    %edx,%edx
  add    $0x1,%rsi
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  jmp    L8
  nopl   0x0(%rax)
L12:
  xor    %edx,%edx
  div    %ebx
  mov    %eax,%r13d
  cmp    %eax,%ebx
  jbe    L59
L14:
  mov    %r13d,%eax
  xor    %edx,%edx
  lea    D14(%rip),%rcx
  add    $0x1,%rsi
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  jmp    L22
  xchg   %ax,%ax
L59:
  xor    %edx,%edx
  div    %ebx
  mov    %ebx,%edx
  mov    %eax,%edi
  call   <i2a>
  mov    %rax,%rsi
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: D14: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
char *i2a(unsigned i, char *a, unsigned r) {
  if (i / r > 0) {
    a = i2a(i / r, a, r);
  }
  *a = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[i % r];
  return a + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<i2a>:
  endbr64
  push   %r13
  lea    D2(%rip),%rcx
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%edi
  jae    L42
L21:
  mov    %ebp,%eax
  xor    %edx,%edx
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,(%rsi)
  add    $0x8,%rsp
  lea    0x1(%rsi),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ebx
  mov    %eax,%r12d
  cmp    %ebx,%eax
  jae    L19
L17:
  mov    %r12d,%eax
  xor    %edx,%edx
  add    $0x1,%rsi
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  jmp    L21
  nopl   0x0(%rax)
L19:
  xor    %edx,%edx
  div    %ebx
  mov    %eax,%r13d
  cmp    %eax,%ebx
  jbe    L29
L26:
  mov    %r13d,%eax
  xor    %edx,%edx
  lea    D2(%rip),%rcx
  add    $0x1,%rsi
  div    %ebx
  movzbl (%rcx,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  jmp    L17
  xchg   %ax,%ax
L29:
  xor    %edx,%edx
  div    %ebx
  mov    %ebx,%edx
  mov    %eax,%edi
  call   <i2a>
  mov    %rax,%rsi
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: 0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
char *i2a(unsigned i, char *a, unsigned r) {
  if (i / r > 0) {
    a = i2a(i / r, a, r);
  }
  *a = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"[i % r];
  return a + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<answer_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char answer_1(int arg0) {
  unsigned int output = (1 << arg0);
  return output;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<answer_1>:
  endbr64
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char answer_1(int arg0) {
  unsigned int output = (1 << arg0);
  return output;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<answer_1>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char answer_1(int arg0) {
  unsigned int output = (1 << arg0);
  return output;
}
```
user: Translate the below assembly code into C programming language:

```asm
<answer_1>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
```

assistant: ```c
unsigned char answer_1(int arg0) {
  unsigned int output = (1 << arg0);
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %edx,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x84(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  mov    -0x80(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D2: %s

assistant: ```c
void printtime(FILE *stream, const char *format, time_t time) {
  char buf[100];
  strftime(buf, 100, format, localtime(&time));
  fprintf(stream, "%s", buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printtime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <localtime@plt>
  mov    %eax,%ecx
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    %r12,%rdx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: %s

assistant: ```c
void printtime(FILE *stream, const char *format, time_t time) {
  char buf[100];
  strftime(buf, 100, format, localtime(&time));
  fprintf(stream, "%s", buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printtime>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edx,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    %r13,%rdx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  sub    $0xffffffffffffff80,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %s

assistant: ```c
void printtime(FILE *stream, const char *format, time_t time) {
  char buf[100];
  strftime(buf, 100, format, localtime(&time));
  fprintf(stream, "%s", buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<printtime>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edx,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <localtime@plt>
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %r13,%rdi
  mov    %eax,%ecx
  call   <strftime@plt>
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  sub    $0xffffffffffffff80,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D4: %s

assistant: ```c
void printtime(FILE *stream, const char *format, time_t time) {
  char buf[100];
  strftime(buf, 100, format, localtime(&time));
  fprintf(stream, "%s", buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  lea    D48(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  call   <puts@plt>
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  imul   $0x59,0x8(%rsp),%edx
  lea    D17(%rip),%rdi
  mov    %ecx,%eax
  shl    $0x4,%eax
  sub    %ecx,%eax
  add    %eax,%edx
  mov    0x10(%rsp),%eax
  lea    (%rax,%rax,8),%eax
  lea    (%rax,%rax,8),%eax
  add    %eax,%edx
  mov    0x14(%rsp),%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x151d07eb,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x23,%rax
  sub    %ecx,%eax
  imul   $0x61,%eax,%eax
  sub    %edx,%eax
  lea    0x61(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D33
type: string
name: parse_data
arguments: data_tag: D48
type: string
name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D35
type: string
name: parse_data
arguments: data_tag: D47
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D33: Program for find the RIB key - programming by Lyes Belhadj

tool: D48: %d

tool: D20: 
Enter bank code: 

tool: D5: 
Enter guichet code: 

tool: D35: 
Enter the first part of number account (it's the five number of number account): 

tool: D47: 
Enter the second part of number account (it's the six fallowing number of number account): 

tool: D17: The key of RIB is: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int bank_code = 0, guichet_code = 0, account_num1 = 0, account_num2 = 0, key_rib = 0;
  printf("Program for find the RIB key - programming by Lyes Belhadj\n");
  printf("\nEnter bank code: ");
  scanf("%d", &bank_code);
  printf("\nEnter guichet code: ");
  scanf("%d", &guichet_code);
  printf("\nEnter the first part of number account (it's the five number of number account): ");
  scanf("%d", &account_num1);
  printf("\nEnter the second part of number account (it's the six fallowing number of number account): ");
  scanf("%d", &account_num2);
  key_rib = 97 - (89 * bank_code + 15 * guichet_code + 81 * account_num1 + 3 * account_num2) % 97;
  printf("The key of RIB is: %d", key_rib);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *chomp(char *str) {
  if (*str && str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = 0;
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<chomp>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L16
L20:
  mov    %rbx,%rax
  pop    %rbx
  ret
L16:
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  jne    L20
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L20
```

assistant: ```c
char *chomp(char *str) {
  if (*str && str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = 0;
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chomp>:
  endbr64
  push   %r12
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  jne    L12
L22:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  jne    L22
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  jmp    L22
```

assistant: ```c
char *chomp(char *str) {
  if (*str && str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = 0;
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chomp>:
  endbr64
  push   %r12
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  jne    L9
L27:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  jne    L27
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  jmp    L27
```

assistant: ```c
char *chomp(char *str) {
  if (*str && str[strlen(str) - 1] == '\n')
    str[strlen(str) - 1] = 0;
  return str;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L25:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <controlloNumeroPrimo@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L14
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  cmp    %edx,%eax
  jb     L25
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D47
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D21: Indica quanti numeri si desidera controllare: 

tool: D47: %s

tool: D3: %u

tool: D9: %u e' un numero primo!!


tool: D18: 
Sono stati scoperti: %u numeri primi

assistant: ```c
int main(void) {
  unsigned int controlloNumeroPrimo(unsigned int numeroDaControllare);
  unsigned int maxNumDaControllare;
  unsigned int numeroPrimo;
  unsigned int contatoreNumeri = 1;
  unsigned int quantiNumeriPrimi = 0;
  printf("%s", "Indica quanti numeri si desidera controllare: ");
  scanf("%u", &maxNumDaControllare);
  do {
    numeroPrimo = controlloNumeroPrimo(contatoreNumeri);
    if (numeroPrimo == 1) {
      printf("%u e' un numero primo!!\n", contatoreNumeri);
      quantiNumeriPrimi++;
    }
  } while (contatoreNumeri++ < maxNumDaControllare);
  printf("\nSono stati scoperti: %u numeri primi", quantiNumeriPrimi);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  lea    D45(%rip),%r12
  jmp    L32
L16:
  lea    0x1(%rbx),%eax
  cmp    %ebx,0x4(%rsp)
  jbe    L27
  mov    %eax,%ebx
L32:
  mov    %ebx,%edi
  call   <controlloNumeroPrimo@plt>
  cmp    $0x1,%eax
  jne    L16
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  jmp    L16
L27:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D43
type_guessed: string
name: disassemble_data
arguments: data_label: D49
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D45
type_guessed: string
name: disassemble_data
arguments: data_label: D15
type_guessed: string

tool: D43: Indica quanti numeri si desidera controllare: 

tool: D49: %s

tool: D11: %u

tool: D45: %u e' un numero primo!!


tool: D15: 
Sono stati scoperti: %u numeri primi

assistant: ```c
int main(void) {
  unsigned int controlloNumeroPrimo(unsigned int numeroDaControllare);
  unsigned int maxNumDaControllare;
  unsigned int numeroPrimo;
  unsigned int contatoreNumeri = 1;
  unsigned int quantiNumeriPrimi = 0;
  printf("%s", "Indica quanti numeri si desidera controllare: ");
  scanf("%u", &maxNumDaControllare);
  do {
    numeroPrimo = controlloNumeroPrimo(contatoreNumeri);
    if (numeroPrimo == 1) {
      printf("%u e' un numero primo!!\n", contatoreNumeri);
      quantiNumeriPrimi++;
    }
  } while (contatoreNumeri++ < maxNumDaControllare);
  printf("\nSono stati scoperti: %u numeri primi", quantiNumeriPrimi);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rsi
  lea    D47(%rip),%rdi
  push   %rbp
  lea    D36(%rip),%r12
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  jmp    L41
L36:
  lea    0x1(%rbx),%eax
  cmp    %ebx,0x4(%rsp)
  jbe    L14
L40:
  mov    %eax,%ebx
L41:
  mov    %ebx,%edi
  call   <controlloNumeroPrimo@plt>
  cmp    $0x1,%eax
  jne    L36
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  cmp    %ebx,0x4(%rsp)
  ja     L40
L14:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D44
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string

tool: D15: Indica quanti numeri si desidera controllare: 

tool: D47: %s

tool: D36: %u e' un numero primo!!


tool: D44: %u

tool: D23: 
Sono stati scoperti: %u numeri primi

assistant: ```c
int main(void) {
  unsigned int controlloNumeroPrimo(unsigned int numeroDaControllare);
  unsigned int maxNumDaControllare;
  unsigned int numeroPrimo;
  unsigned int contatoreNumeri = 1;
  unsigned int quantiNumeriPrimi = 0;
  printf("%s", "Indica quanti numeri si desidera controllare: ");
  scanf("%u", &maxNumDaControllare);
  do {
    numeroPrimo = controlloNumeroPrimo(contatoreNumeri);
    if (numeroPrimo == 1) {
      printf("%u e' un numero primo!!\n", contatoreNumeri);
      quantiNumeriPrimi++;
    }
  } while (contatoreNumeri++ < maxNumDaControllare);
  printf("\nSono stati scoperti: %u numeri primi", quantiNumeriPrimi);
  return 0;
}
```