ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<timeval_percentage_of>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  call   <tv_to_usec@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <tv_to_usec@plt>
  mov    %eax,%r8d
  imul   $0x2710,%ebx,%eax
  cltd
  idiv   %r8d
  cltq
  test   %rax,%rax
  js     L6
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
L4:
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %rbp,%xmm1
  mulsd  D8(%rip),%xmm1
  pop    %rbp
  pop    %r12
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
  jmp    L4
```

tool_calls: name: parse_data
arguments: label: D8
type: f64

tool: D8: 100

assistant: ```c
float timeval_percentage_of(const struct timeval *value, const struct timeval *from, unsigned int divider) {
  unsigned long long v;
  float p;
  v = (100 * 100 * tv_to_usec(value)) / tv_to_usec(from);
  p = (float)v / (100.0 * divider);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<AdmAccept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L5:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L5
L34:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *AdmAccept(char *pt) {
  while (*pt && (*pt != ' ' && *pt != '\t'))
    pt++;
  return pt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<AdmAccept>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L32
L11:
  cmp    $0x20,%dl
  je     L20
  cmp    $0x9,%dl
  je     L20
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L11
L20:
  ret
L32:
  ret
```

assistant: ```c
char *AdmAccept(char *pt) {
  while (*pt && (*pt != ' ' && *pt != '\t'))
    pt++;
  return pt;
}
```
user: What is the c source code of the assembly code below:

```asm
<AdmAccept>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L24
  xchg   %ax,%ax
L38:
  cmp    $0x20,%dl
  je     L18
  cmp    $0x9,%dl
  je     L18
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L38
L18:
  ret
L24:
  ret
```

assistant: ```c
char *AdmAccept(char *pt) {
  while (*pt && (*pt != ' ' && *pt != '\t'))
    pt++;
  return pt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<AdmAccept>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L10
  xchg   %ax,%ax
L37:
  cmp    $0x20,%dl
  je     L35
  cmp    $0x9,%dl
  je     L35
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L37
L35:
  ret
L10:
  ret
```

assistant: ```c
char *AdmAccept(char *pt) {
  while (*pt && (*pt != ' ' && *pt != '\t'))
    pt++;
  return pt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L72
L54:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L46
  cmpl   $0x0,-0x4(%rbp)
  je     L46
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L89
L46:
  cmpl   $0x0,-0x8(%rbp)
  je     L65
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L89
L65:
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L89
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L89:
  addl   $0x1,-0xc(%rbp)
L72:
  cmpl   $0x64,-0xc(%rbp)
  jle    L54
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D29
type: string
name: parse_data
arguments: label: D28
type: string

tool: D2: FizzBuzz

tool: D36: Fizz

tool: D29: Buzz

tool: D28: %d


assistant: ```c
int main(void) {
  int n, f, b;
  for (n = 0; n <= 100; f = !(n % 3), b = !(n % 5), (f && b) ? puts("FizzBuzz") : (f) ? puts("Fizz") : (b) ? puts("Buzz") : printf("%d\n", n), ++n)
    ;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D21(%rip),%r13
  lea    D32(%rip),%r12
  lea    D28(%rip),%r14
  lea    D9(%rip),%rbp
  jmp    L45
L63:
  mov    %rbp,%rdi
  call   <puts@plt>
L1:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L12
L45:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rdx
  shr    $0x20,%rdx
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%esi
  mov    %ebx,%edx
  sub    %esi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %ebx,%eax
  sub    %ecx,%eax
  mov    %edx,%edi
  or     %eax,%edi
  je     L63
  test   %edx,%edx
  je     L52
  test   %eax,%eax
  jne    L66
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L1
L52:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L1
L66:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L1
L12:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D21
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D28
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D21: %d


tool: D32: Buzz

tool: D28: Fizz

tool: D9: FizzBuzz

assistant: ```c
int main(void) {
  int n, f, b;
  for (n = 0; n <= 100; f = !(n % 3), b = !(n % 5), (f && b) ? puts("FizzBuzz") : (f) ? puts("Fizz") : (b) ? puts("Buzz") : printf("%d\n", n), ++n)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    $0xaaaaaaab,%ebp
  push   %rbx
  mov    $0xcccccccd,%ebx
  jmp    L54
  nopl   0x0(%rax)
L6:
  test   %edx,%edx
  je     L22
  test   %eax,%eax
  jne    L46
  mov    %r12,%rdi
  call   <puts@plt>
L4:
  add    $0x1,%r14d
  cmp    $0x65,%r14d
  je     L15
L54:
  mov    %r14d,%eax
  mov    %rax,%rdx
  imul   %rbx,%rax
  imul   %rbp,%rdx
  shr    $0x22,%rax
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%ecx
  mov    %r14d,%edx
  sub    %ecx,%edx
  lea    (%rax,%rax,4),%ecx
  mov    %r14d,%eax
  sub    %ecx,%eax
  mov    %edx,%esi
  or     %eax,%esi
  jne    L6
  lea    D39(%rip),%rdi
  add    $0x1,%r14d
  call   <puts@plt>
  cmp    $0x65,%r14d
  jne    L54
L15:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L4
  nopl   (%rax)
L22:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string
name: read_data
arguments: label: D22
type_guessed: string

tool: D14: %d


tool: D23: Buzz

tool: D39: FizzBuzz

tool: D22: Fizz

assistant: ```c
int main(void) {
  int n, f, b;
  for (n = 0; n <= 100; f = !(n % 3), b = !(n % 5), (f && b) ? puts("FizzBuzz") : (f) ? puts("Fizz") : (b) ? puts("Buzz") : printf("%d\n", n), ++n)
    ;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    $0xaaaaaaab,%ebp
  push   %rbx
  mov    $0xcccccccd,%ebx
  jmp    L63
  nopl   0x0(%rax)
L77:
  test   %edx,%edx
  je     L22
  test   %eax,%eax
  jne    L2
  mov    %r12,%rdi
  call   <puts@plt>
L1:
  add    $0x1,%r14d
  cmp    $0x65,%r14d
  je     L37
L63:
  mov    %r14d,%eax
  mov    %rax,%rdx
  imul   %rbx,%rax
  imul   %rbp,%rdx
  shr    $0x22,%rax
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,2),%ecx
  mov    %r14d,%edx
  sub    %ecx,%edx
  lea    (%rax,%rax,4),%ecx
  mov    %r14d,%eax
  sub    %ecx,%eax
  mov    %edx,%esi
  or     %eax,%esi
  jne    L77
  lea    D2(%rip),%rdi
  add    $0x1,%r14d
  call   <puts@plt>
  cmp    $0x65,%r14d
  jne    L63
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L1
  nopl   (%rax)
L22:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D2
type_infered: string
name: disassemble_data
arguments: tag: D32
type_infered: string

tool: D16: %d


tool: D18: Buzz

tool: D2: FizzBuzz

tool: D32: Fizz

assistant: ```c
int main(void) {
  int n, f, b;
  for (n = 0; n <= 100; f = !(n % 3), b = !(n % 5), (f && b) ? puts("FizzBuzz") : (f) ? puts("Fizz") : (b) ? puts("Buzz") : printf("%d\n", n), ++n)
    ;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printhex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  nop
  leave
  ret
```

assistant: ```c
void printhex(unsigned char c) {
  putch(hexchar(c >> 4));
  putch(hexchar(c));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printhex>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  movzbl %bl,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  pop    %rbx
  ret
```

assistant: ```c
void printhex(unsigned char c) {
  putch(hexchar(c >> 4));
  putch(hexchar(c));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printhex>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  movzbl %bl,%edi
  call   <hexchar@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1060 <putch@plt>
```

assistant: ```c
void printhex(unsigned char c) {
  putch(hexchar(c >> 4));
  putch(hexchar(c));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printhex>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <hexchar@plt>
  mov    %eax,%edi
  call   <putch@plt>
  movzbl %bl,%edi
  call   <hexchar@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1060 <putch@plt>
```

assistant: ```c
void printhex(unsigned char c) {
  putch(hexchar(c >> 4));
  putch(hexchar(c));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isValidID>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L16
  cmpl   $0x1f,-0x4(%rbp)
  jg     L16
  movl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool isValidID(char *pID) {
  bool isValid = false;
  int length = strlen(pID);
  if (0 <= length && 32 > length) {
    isValid = true;
  }
  return isValid;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValidID>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1f,%eax
  setbe  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool isValidID(char *pID) {
  bool isValid = false;
  int length = strlen(pID);
  if (0 <= length && 32 > length) {
    isValid = true;
  }
  return isValid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isValidID>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1f,%eax
  setbe  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool isValidID(char *pID) {
  bool isValid = false;
  int length = strlen(pID);
  if (0 <= length && 32 > length) {
    isValid = true;
  }
  return isValid;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isValidID>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1f,%eax
  setbe  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
bool isValidID(char *pID) {
  bool isValid = false;
  int length = strlen(pID);
  if (0 <= length && 32 > length) {
    isValid = true;
  }
  return isValid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lnp_hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  test   %edx,%edx
  je     L80
  mov    %rsi,%r12
  movl   $0x0,(%rsp)
  lea    D6(%rip),%r15
  jmp    L93
L119:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L117:
  mov    %ebx,%eax
  and    $0x7,%eax
  cmp    $0x7,%eax
  je     L22
L112:
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  je     L9
L58:
  cmp    %ebx,%ebp
  jbe    L119
  lea    0x1(%r12),%r13
  movzbl (%r12),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%r12
  jmp    L117
L22:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L112
L9:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebp,%eax
  sub    %rax,%r12
  mov    $0x0,%ebx
  jmp    L99
L30:
  call   <putchar@plt>
L98:
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  je     L108
L99:
  cmp    %ebx,%ebp
  jbe    L98
  movzbl (%r12,%rbx,1),%edi
  call   <isprint@plt>
  mov    $0x2e,%edi
  test   %rax,%rax
  je     L30
  movzbl (%r12,%rbx,1),%edi
  jmp    L30
L108:
  add    $0x10,%r12
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x10,(%rsp)
  mov    (%rsp),%eax
  cmp    %eax,0x4(%rsp)
  jbe    L80
L93:
  mov    0x4(%rsp),%ebp
  sub    (%rsp),%ebp
  mov    $0x10,%eax
  cmp    %eax,%ebp
  cmova  %eax,%ebp
  mov    0x8(%rsp),%rax
  test   %rax,%rax
  je     L52
  mov    %rax,%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L52:
  mov    (%rsp),%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D20(%rip),%r14
  jmp    L58
L80:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string

tool: D6:    

tool: D22: %s 

tool: D29: %04d 

tool: D20:  %d

assistant: ```c
void lnp_hexdump(char *prefix, void *data, unsigned length) {
  unsigned offset;
  unsigned char *dataptr = (unsigned char *)data;
  unsigned linesize, lineindex;
  for (offset = 0; offset < length; offset += 16) {
    linesize = (length - offset < 16) ? (length - offset) : 16;
    if (prefix)
      printf("%s ", prefix);
    printf("%04d ", offset);
    for (lineindex = 0; lineindex < 16; lineindex++) {
      if (lineindex < linesize)
        printf(" %d", *(dataptr++));
      else if (1)
        printf("   ");
      if ((lineindex % 8) == (8 - 1))
        printf(" ");
    }
    if (1) {
      printf(" ");
      dataptr -= linesize;
      for (lineindex = 0; lineindex < 16; lineindex++) {
        if (lineindex < linesize)
          printf("%c", (isprint(*dataptr)) ? (*dataptr) : '.');
        dataptr++;
      }
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %ax,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L89
  cmpw   $0x24,-0x18(%rbp)
  jbe    L62
L89:
  mov    $0xffffffff,%eax
  jmp    L42
L62:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L41:
  movzwl -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x9,-0x5(%rbp)
  jg     L21
  movzbl -0x5(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x5(%rbp)
  jmp    L84
L21:
  movzbl -0x5(%rbp),%eax
  add    $0x37,%eax
  mov    %al,-0x5(%rbp)
L84:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L87
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L41
  jmp    L32
L87:
  nop
L32:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jbe    L1
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strrev@plt>
  mov    -0x4(%rbp),%eax
  jmp    L42
L1:
  mov    $0xffffffff,%eax
L42:
  leave
  ret
```

assistant: ```c
int my_itoa(int number, unsigned short base, char *output, size_t max_len) {
  int length = 0;
  if (output == NULL || base > 36) {
    return -1;
  }
  for (length = 0; length < max_len; length++) {
    char digit = number % base;
    if (digit < 10) {
      digit += '0';
    } else {
      digit += ('A' - 10);
    }
    output[length] = digit;
    number = number / base;
    if (number == 0) {
      break;
    }
  }
  if (length < max_len) {
    my_strrev(output);
  } else {
    return -1;
  }
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_itoa>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L72
  mov    %rdx,%r9
  mov    %rcx,%r10
  cmp    $0x24,%si
  ja     L72
  test   %rcx,%rcx
  je     L49
  mov    $0x0,%ecx
  movzwl %si,%esi
L53:
  mov    %ecx,%ebx
  mov    %edi,%eax
  cltd
  idiv   %esi
  lea    0x30(%rdx),%r8d
  lea    0x37(%rdx),%eax
  cmp    $0x9,%dl
  cmovle %r8d,%eax
  mov    %al,(%r9,%rcx,1)
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  test   %eax,%eax
  je     L86
  add    $0x1,%rcx
  cmp    %rcx,%r10
  jne    L53
L49:
  mov    $0xffffffff,%ebx
  jmp    L67
L86:
  cmp    %r10,%rcx
  jae    L14
  mov    %r9,%rdi
  call   <my_strrev@plt>
L67:
  mov    %ebx,%eax
  pop    %rbx
  ret
L72:
  mov    $0xffffffff,%ebx
  jmp    L67
L14:
  mov    $0xffffffff,%ebx
  jmp    L67
```

assistant: ```c
int my_itoa(int number, unsigned short base, char *output, size_t max_len) {
  int length = 0;
  if (output == NULL || base > 36) {
    return -1;
  }
  for (length = 0; length < max_len; length++) {
    char digit = number % base;
    if (digit < 10) {
      digit += '0';
    } else {
      digit += ('A' - 10);
    }
    output[length] = digit;
    number = number / base;
    if (number == 0) {
      break;
    }
  }
  if (length < max_len) {
    my_strrev(output);
  } else {
    return -1;
  }
  return length;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<my_itoa>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L15
  cmp    $0x24,%si
  ja     L15
  test   %rcx,%rcx
  je     L15
  mov    %edi,%eax
  mov    %rdx,%r10
  movzwl %si,%esi
  xor    %edi,%edi
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  je     L15
L23:
  cltd
  mov    %edi,%r12d
  idiv   %esi
  lea    0x30(%rdx),%r9d
  lea    0x37(%rdx),%r8d
  cmp    $0x9,%edx
  cmovle %r9d,%r8d
  mov    %r8b,(%r10,%rdi,1)
  test   %eax,%eax
  jne    L34
  mov    %r10,%rdi
  call   <my_strrev@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  mov    $0xffffffff,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int my_itoa(int number, unsigned short base, char *output, size_t max_len) {
  int length = 0;
  if (output == NULL || base > 36) {
    return -1;
  }
  for (length = 0; length < max_len; length++) {
    char digit = number % base;
    if (digit < 10) {
      digit += '0';
    } else {
      digit += ('A' - 10);
    }
    output[length] = digit;
    number = number / base;
    if (number == 0) {
      break;
    }
  }
  if (length < max_len) {
    my_strrev(output);
  } else {
    return -1;
  }
  return length;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_itoa>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L28
  cmp    $0x24,%si
  ja     L28
  test   %rcx,%rcx
  je     L28
  mov    %edi,%eax
  mov    %rdx,%r10
  movzwl %si,%esi
  xor    %edi,%edi
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  je     L28
L2:
  cltd
  mov    %edi,%r12d
  idiv   %esi
  lea    0x30(%rdx),%r9d
  lea    0x37(%rdx),%r8d
  cmp    $0x9,%edx
  cmovle %r9d,%r8d
  mov    %r8b,(%r10,%rdi,1)
  test   %eax,%eax
  jne    L10
  mov    %r10,%rdi
  call   <my_strrev@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xffffffff,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int my_itoa(int number, unsigned short base, char *output, size_t max_len) {
  int length = 0;
  if (output == NULL || base > 36) {
    return -1;
  }
  for (length = 0; length < max_len; length++) {
    char digit = number % base;
    if (digit < 10) {
      digit += '0';
    } else {
      digit += ('A' - 10);
    }
    output[length] = digit;
    number = number / base;
    if (number == 0) {
      break;
    }
  }
  if (length < max_len) {
    my_strrev(output);
  } else {
    return -1;
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<generate_backup_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L19
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L6
L12:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  mov    -0x10(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rax
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D12
type: string

tool: D0: Error on generating backup file. Filename it's NULL!


tool: D24: Error on finding dot on filename


tool: D12: .bkp

assistant: ```c
char *generate_backup_name(char *filename) {
  char *aux_str;
  char *dot_pos;
  if (filename == NULL) {
    printf("Error on generating backup file. Filename it's NULL!\n");
    return NULL;
  }
  aux_str = malloc(strlen(filename) + 1);
  strcpy(aux_str, filename);
  dot_pos = strrchr(aux_str, '.');
  if (dot_pos != NULL) {
    *dot_pos = '\0';
  } else {
    printf("Error on finding dot on filename\n");
  }
  strcat(aux_str, ".bkp");
  return aux_str;
}
```