ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  imul   $0x66666667,%rax,%rcx
  mov    %rax,%rdx
  mov    %eax,%edi
  mov    %eax,%esi
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%edi
  sar    $0x21,%rcx
  shr    $0x20,%rax
  sub    %edi,%ecx
  add    %edx,%eax
  lea    (%rcx,%rcx,4),%ecx
  sar    $0x2,%eax
  sub    %ecx,%esi
  sub    %edi,%eax
  lea    0x0(,%rax,8),%ecx
  sub    %eax,%ecx
  sub    %ecx,%edx
  or     %edx,%esi
  je     L19
  lea    D24(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D1
datatype: string

tool: D11: %d

tool: D24: False.


tool: D1: True.


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n % 5 == 0 && n % 7 == 0) {
    printf("True.\n");
  } else {
    printf("False.\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<list_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__list_del_entry@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_add_tail@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_move(struct list_head *list, struct list_head *head) {
  __list_del_entry(list);
  list_add_tail(list, head);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_move>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <__list_del_entry@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <list_add_tail@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void list_move(struct list_head *list, struct list_head *head) {
  __list_del_entry(list);
  list_add_tail(list, head);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<list_move>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <__list_del_entry@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <list_add_tail@plt>
```

assistant: ```c
void list_move(struct list_head *list, struct list_head *head) {
  __list_del_entry(list);
  list_add_tail(list, head);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list_move>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <__list_del_entry@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <list_add_tail@plt>
```

assistant: ```c
void list_move(struct list_head *list, struct list_head *head) {
  __list_del_entry(list);
  list_add_tail(list, head);
}
```
user: What is the c source code of the assembly code below:

```asm
<u>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x30(%rbp)
  jge    L39
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L40
L39:
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L25
L7:
  movswl %bx,%eax
  add    %eax,%eax
  mov    %eax,%ebx
  mov    -0x2c(%rbp),%eax
  sar    $0x3,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  not    %eax
  and    $0x7,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x2c(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L13
  or     $0x1,%ebx
L13:
  mov    %r12d,%eax
  add    $0x1,%eax
  mov    %eax,%r12d
L25:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    %ax,%r12w
  jl     L7
  mov    %ebx,%eax
L40:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned short u(const unsigned char *buffer, int totbitoffset, int total_bits, int *code_bits) {
  long byteoffset;
  int bitoffset;
  register short val, i;
  if (*code_bits > total_bits) {
    *code_bits = 0;
    return 0;
  }
  val = 0;
  for (i = 0; i < (short)*code_bits; i++) {
    val <<= 1;
    byteoffset = totbitoffset >> 3;
    bitoffset = 7 - (totbitoffset & 0x07);
    totbitoffset++;
    if ((buffer[byteoffset] & (0x01 << bitoffset))) {
      val |= 1;
    }
  }
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<u>:
  endbr64
  mov    (%rcx),%eax
  cmp    %edx,%eax
  jg     L5
  test   %ax,%ax
  jle    L1
  sub    $0x1,%eax
  movzwl %ax,%eax
  lea    0x1(%rsi,%rax,1),%r8d
  mov    $0x0,%eax
L27:
  cwtl
  add    %eax,%eax
  mov    %esi,%edx
  sar    $0x3,%edx
  mov    %esi,%ecx
  not    %ecx
  and    $0x7,%ecx
  add    $0x1,%esi
  movslq %edx,%rdx
  movzbl (%rdi,%rdx,1),%edx
  sar    %cl,%edx
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x1,%dl
  cmovne %ecx,%eax
  cmp    %r8d,%esi
  jne    L27
  ret
L1:
  mov    $0x0,%eax
  ret
L5:
  movl   $0x0,(%rcx)
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned short u(const unsigned char *buffer, int totbitoffset, int total_bits, int *code_bits) {
  long byteoffset;
  int bitoffset;
  register short val, i;
  if (*code_bits > total_bits) {
    *code_bits = 0;
    return 0;
  }
  val = 0;
  for (i = 0; i < (short)*code_bits; i++) {
    val <<= 1;
    byteoffset = totbitoffset >> 3;
    bitoffset = 7 - (totbitoffset & 0x07);
    totbitoffset++;
    if ((buffer[byteoffset] & (0x01 << bitoffset))) {
      val |= 1;
    }
  }
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<u>:
  endbr64
  mov    (%rcx),%r9d
  mov    %rdi,%r8
  mov    %esi,%edi
  cmp    %edx,%r9d
  jg     L5
  test   %r9w,%r9w
  jle    L20
  sub    $0x1,%r9d
  lea    0x1(%rsi),%esi
  xor    %eax,%eax
  movzwl %r9w,%r9d
  add    %esi,%r9d
  jmp    L11
  nopl   0x0(%rax)
L22:
  add    $0x1,%esi
L11:
  mov    %edi,%edx
  not    %edi
  cwtl
  sar    $0x3,%edx
  mov    %edi,%ecx
  add    %eax,%eax
  mov    %esi,%edi
  movslq %edx,%rdx
  and    $0x7,%ecx
  movzbl (%r8,%rdx,1),%edx
  sar    %cl,%edx
  mov    %eax,%ecx
  or     $0x1,%ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
  cmp    %r9d,%esi
  jne    L22
  ret
  nop
L5:
  movl   $0x0,(%rcx)
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short u(const unsigned char *buffer, int totbitoffset, int total_bits, int *code_bits) {
  long byteoffset;
  int bitoffset;
  register short val, i;
  if (*code_bits > total_bits) {
    *code_bits = 0;
    return 0;
  }
  val = 0;
  for (i = 0; i < (short)*code_bits; i++) {
    val <<= 1;
    byteoffset = totbitoffset >> 3;
    bitoffset = 7 - (totbitoffset & 0x07);
    totbitoffset++;
    if ((buffer[byteoffset] & (0x01 << bitoffset))) {
      val |= 1;
    }
  }
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<u>:
  endbr64
  mov    (%rcx),%r9d
  mov    %rdi,%r8
  mov    %esi,%edi
  cmp    %edx,%r9d
  jg     L19
  test   %r9w,%r9w
  jle    L0
  sub    $0x1,%r9d
  lea    0x1(%rsi),%esi
  xor    %eax,%eax
  movzwl %r9w,%r9d
  add    %esi,%r9d
  jmp    L14
  nopl   0x0(%rax)
L20:
  add    $0x1,%esi
L14:
  mov    %edi,%edx
  not    %edi
  cwtl
  sar    $0x3,%edx
  mov    %edi,%ecx
  add    %eax,%eax
  mov    %esi,%edi
  movslq %edx,%rdx
  and    $0x7,%ecx
  movzbl (%r8,%rdx,1),%edx
  sar    %cl,%edx
  mov    %eax,%ecx
  or     $0x1,%ecx
  and    $0x1,%edx
  cmovne %ecx,%eax
  cmp    %esi,%r9d
  jne    L20
  ret
  nop
L19:
  movl   $0x0,(%rcx)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short u(const unsigned char *buffer, int totbitoffset, int total_bits, int *code_bits) {
  long byteoffset;
  int bitoffset;
  register short val, i;
  if (*code_bits > total_bits) {
    *code_bits = 0;
    return 0;
  }
  val = 0;
  for (i = 0; i < (short)*code_bits; i++) {
    val <<= 1;
    byteoffset = totbitoffset >> 3;
    bitoffset = 7 - (totbitoffset & 0x07);
    totbitoffset++;
    if ((buffer[byteoffset] & (0x01 << bitoffset))) {
      val |= 1;
    }
  }
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L19
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L19:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int *tableau, int gauche, int droite, int pivot) {
  int i, temp;
  for (i = gauche; i < droite; i++) {
    if (tableau[i] <= pivot) {
      temp = tableau[i];
      tableau[i] = tableau[gauche];
      tableau[gauche] = temp;
      ++gauche;
    }
  }
  return gauche;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L7
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rdi
  sub    $0x1,%edx
  sub    %eax,%edx
  add    %rsi,%rdx
  lea    0x4(%r8,%rdx,4),%r9
  jmp    L14
L30:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  je     L7
L14:
  mov    (%rdi),%edx
  cmp    %ecx,%edx
  jg     L30
  movslq %eax,%rsi
  lea    (%r8,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %r10d,(%rdi)
  mov    %edx,(%rsi)
  add    $0x1,%eax
  jmp    L30
L7:
  ret
```

assistant: ```c
int partition(int *tableau, int gauche, int droite, int pivot) {
  int i, temp;
  for (i = gauche; i < droite; i++) {
    if (tableau[i] <= pivot) {
      temp = tableau[i];
      tableau[i] = tableau[gauche];
      tableau[gauche] = temp;
      ++gauche;
    }
  }
  return gauche;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partition>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L2
  sub    $0x1,%edx
  movslq %esi,%rsi
  sub    %eax,%edx
  lea    (%rdi,%rsi,4),%rdi
  add    %rsi,%rdx
  lea    0x4(%r8,%rdx,4),%r9
  nopl   0x0(%rax)
L29:
  mov    (%rdi),%edx
  cmp    %ecx,%edx
  jg     L3
  movslq %eax,%rsi
  add    $0x1,%eax
  lea    (%r8,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %r10d,(%rdi)
  mov    %edx,(%rsi)
L3:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L29
L2:
  ret
```

assistant: ```c
int partition(int *tableau, int gauche, int droite, int pivot) {
  int i, temp;
  for (i = gauche; i < droite; i++) {
    if (tableau[i] <= pivot) {
      temp = tableau[i];
      tableau[i] = tableau[gauche];
      tableau[gauche] = temp;
      ++gauche;
    }
  }
  return gauche;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partition>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L9
  sub    $0x1,%edx
  movslq %esi,%rsi
  sub    %eax,%edx
  lea    (%rdi,%rsi,4),%rdi
  add    %rsi,%rdx
  lea    0x4(%r8,%rdx,4),%r9
  nopl   0x0(%rax)
L15:
  mov    (%rdi),%edx
  cmp    %ecx,%edx
  jg     L12
  movslq %eax,%rsi
  add    $0x1,%eax
  lea    (%r8,%rsi,4),%rsi
  mov    (%rsi),%r10d
  mov    %r10d,(%rdi)
  mov    %edx,(%rsi)
L12:
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L15
L9:
  ret
```

assistant: ```c
int partition(int *tableau, int gauche, int droite, int pivot) {
  int i, temp;
  for (i = gauche; i < droite; i++) {
    if (tableau[i] <= pivot) {
      temp = tableau[i];
      tableau[i] = tableau[gauche];
      tableau[gauche] = temp;
      ++gauche;
    }
  }
  return gauche;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0x98(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rax
  cmp    %rax,-0x98(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
data_type: string
name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D22: rs: %s


tool: D4: buf: %s


tool: D34: %d


tool: D2: %lu


assistant: ```c
int main() {
  char buf[128];
  char *rs = getcwd(buf, sizeof(buf));
  printf("rs: %s\n", rs);
  printf("buf: %s\n", buf);
  printf("%d\n", buf == rs);
  printf("%lu\n", strlen(rs));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <getcwd@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  sete   %sil
  movzbl %sil,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D9: rs: %s


tool: D30: buf: %s


tool: D7: %d


tool: D5: %lu


assistant: ```c
int main() {
  char buf[128];
  char *rs = getcwd(buf, sizeof(buf));
  printf("rs: %s\n", rs);
  printf("buf: %s\n", buf);
  printf("%d\n", buf == rs);
  printf("%lu\n", strlen(rs));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80,%esi
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <getcwd@plt>
  lea    D24(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  cmp    %rbx,%rbp
  lea    D25(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D35(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D29
type_infered: string
name: parse_data
arguments: data_tag: D25
type_infered: string
name: parse_data
arguments: data_tag: D35
type_infered: string

tool: D24: rs: %s


tool: D29: buf: %s


tool: D25: %d


tool: D35: %lu


assistant: ```c
int main() {
  char buf[128];
  char *rs = getcwd(buf, sizeof(buf));
  printf("rs: %s\n", rs);
  printf("buf: %s\n", buf);
  printf("%d\n", buf == rs);
  printf("%lu\n", strlen(rs));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x80,%esi
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <getcwd@plt>
  lea    D32(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  cmp    %rbx,%rbp
  lea    D25(%rip),%rdi
  sete   %sil
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D32
datatype: string
name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D25
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string

tool: D32: rs: %s


tool: D12: buf: %s


tool: D25: %d


tool: D27: %lu


assistant: ```c
int main() {
  char buf[128];
  char *rs = getcwd(buf, sizeof(buf));
  printf("rs: %s\n", rs);
  printf("buf: %s\n", buf);
  printf("%d\n", buf == rs);
  printf("%lu\n", strlen(rs));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getCreditCard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <InputHandler@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <checkNullity@plt>
  movl   $0x14,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L93
L98:
  cmpl   $0x4,-0x10(%rbp)
  je     L50
  cmpl   $0x9,-0x10(%rbp)
  je     L50
  cmpl   $0xe,-0x10(%rbp)
  jne    L32
L50:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L28
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L28
L32:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L28
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jne    L42
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L28
L42:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x4,%edi
  call   <exit@plt>
L28:
  addl   $0x1,-0x10(%rbp)
L93:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L98
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D37
datatype: string
name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string

tool: D2: Credit Card: 

tool: D37: Your credit card information is not in the correct format.


tool: D45: Example: 1234-1234-1234-1234


tool: D7: Your credit card contains invalid digits.


assistant: ```c
char *getCreditCard(void) {
  printf("Credit Card: ");
  char *card = InputHandler();
  checkNullity(card);
  int length = 20;
  for (int i = 0; i < length; i++) {
    if (i == 4 || i == 9 || i == 14) {
      if (card[i] != '-') {
        printf("Your credit card information is not in the correct format.\n");
        printf("Example: 1234-1234-1234-1234\n");
        free(card);
        exit(3);
      }
    } else {
      if (!isdigit(card[i])) {
        if (!(i == length - 1 && card[i] == '\n')) {
          printf("Your credit card contains invalid digits.\n");
          printf("Example: 1234-1234-1234-1234\n");
          free(card);
          exit(4);
        }
      }
    }
  }
  return card;
}
```
user: What is the c source code of the assembly code below:

```asm
<getCreditCard>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <InputHandler@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <checkNullity@plt>
  mov    $0x0,%ebx
  lea    D24(%rip),%r15
  lea    D2(%rip),%r13
  mov    $0x4210,%r12d
  lea    D32(%rip),%r14
  jmp    L5
L77:
  cmpb   $0x2d,0x0(%rbp,%rbx,1)
  jne    L95
L65:
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  je     L20
L5:
  cmp    $0xe,%ebx
  ja     L48
  bt     %rbx,%r12
  jb     L77
L48:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L65
  cmp    $0x13,%ebx
  je     L27
L85:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x4,%edi
  call   <exit@plt>
  jmp    L65
L95:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L65
L27:
  cmpb   $0xa,0x0(%rbp,%rbx,1)
  jne    L85
L20:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string
name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D32
type: string

tool: D37: Credit Card: 

tool: D24: Your credit card contains invalid digits.


tool: D2: Example: 1234-1234-1234-1234


tool: D32: Your credit card information is not in the correct format.


assistant: ```c
char *getCreditCard(void) {
  printf("Credit Card: ");
  char *card = InputHandler();
  checkNullity(card);
  int length = 20;
  for (int i = 0; i < length; i++) {
    if (i == 4 || i == 9 || i == 14) {
      if (card[i] != '-') {
        printf("Your credit card information is not in the correct format.\n");
        printf("Example: 1234-1234-1234-1234\n");
        free(card);
        exit(3);
      }
    } else {
      if (!isdigit(card[i])) {
        if (!(i == length - 1 && card[i] == '\n')) {
          printf("Your credit card contains invalid digits.\n");
          printf("Example: 1234-1234-1234-1234\n");
          free(card);
          exit(4);
        }
      }
    }
  }
  return card;
}
```