ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<trim_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <after_blanks@plt>
  mov    %rax,-0x8(%rbp)
  nop
L41:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  subq   $0x1,-0x10(%rbp)
  jmp    L45
L37:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L45:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L13
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L22
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
  jmp    L8
L31:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x20,(%rax)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  subq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L63
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  leave
  ret
```

assistant: ```c
int trim_blanks(char *buffer) {
  if (*buffer != '\0') {
    char *d = buffer;
    char *s = after_blanks(d);
    while ((*d++ = *s++) != '\0') {
      ;
    }
    --d;
    while ((--d != buffer) && isspace(UCH(*d)))
      *d = '\0';
    for (s = d = buffer; (*d++ = *s++) != '\0';) {
      if (isspace(UCH(*s))) {
        *s = ' ';
        while (isspace(UCH(*s))) {
          *s++ = ' ';
        }
        --s;
      }
    }
  }
  return (int)strlen(buffer) - 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim_blanks>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  cmpb   $0x0,(%rdi)
  jne    L33
L87:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <after_blanks@plt>
  mov    %r12,%rdx
L21:
  add    $0x1,%rax
  mov    %rdx,%rbx
  add    $0x1,%rdx
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  jne    L21
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  je     L39
L109:
  movsbl (%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L109
  jmp    L39
L25:
  mov    %r12,%rbx
L39:
  lea    0x1(%rbx),%rbp
  mov    %rbp,%r13
  cmpb   $0x0,(%rbx)
  jne    L112
  jmp    L87
L27:
  movb   $0x20,0x1(%rbx)
  jmp    L35
L5:
  add    $0x1,%rbp
  movb   $0x20,-0x1(%rbp)
L35:
  movsbl 0x0(%rbp),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  lea    -0x1(%rbp),%rbx
L24:
  lea    0x1(%rbx),%rbp
  add    $0x1,%r13
  movzbl (%rbx),%eax
  mov    %al,-0x1(%r13)
  test   %al,%al
  je     L87
L112:
  movsbl 0x1(%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
  mov    %rbp,%rbx
  jmp    L24
```

assistant: ```c
int trim_blanks(char *buffer) {
  if (*buffer != '\0') {
    char *d = buffer;
    char *s = after_blanks(d);
    while ((*d++ = *s++) != '\0') {
      ;
    }
    --d;
    while ((--d != buffer) && isspace(UCH(*d)))
      *d = '\0';
    for (s = d = buffer; (*d++ = *s++) != '\0';) {
      if (isspace(UCH(*s))) {
        *s = ' ';
        while (isspace(UCH(*s))) {
          *s++ = ' ';
        }
        --s;
      }
    }
  }
  return (int)strlen(buffer) - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trim_blanks>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L91
L98:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  pop    %rbx
  sub    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L91:
  call   <after_blanks@plt>
  mov    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L111:
  movzbl (%rax),%ecx
  mov    %rdx,%rbx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  jne    L111
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L119
  xchg   %ax,%ax
L19:
  movsbl (%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L119
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L19
L119:
  lea    0x1(%rbp),%rbx
  cmpb   $0x0,0x0(%rbp)
  mov    %rbp,%r13
  mov    %rbx,%r12
  jne    L73
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %rbx,%r13
  add    $0x1,%rbx
L44:
  movzbl 0x0(%r13),%eax
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %al,%al
  je     L98
L73:
  movsbl 0x1(%r13),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L39
  movb   $0x20,0x1(%r13)
  jmp    L82
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x20,(%rbx)
  add    $0x1,%rbx
L82:
  movsbl (%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  lea    -0x1(%rbx),%r13
  jmp    L44
```

assistant: ```c
int trim_blanks(char *buffer) {
  if (*buffer != '\0') {
    char *d = buffer;
    char *s = after_blanks(d);
    while ((*d++ = *s++) != '\0') {
      ;
    }
    --d;
    while ((--d != buffer) && isspace(UCH(*d)))
      *d = '\0';
    for (s = d = buffer; (*d++ = *s++) != '\0';) {
      if (isspace(UCH(*s))) {
        *s = ' ';
        while (isspace(UCH(*s))) {
          *s++ = ' ';
        }
        --s;
      }
    }
  }
  return (int)strlen(buffer) - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trim_blanks>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L59
L75:
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    $0x8,%rsp
  pop    %rbx
  sub    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L59:
  call   <after_blanks@plt>
  mov    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L72:
  movzbl (%rax),%ecx
  mov    %rdx,%rbx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  test   %cl,%cl
  jne    L72
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L3
  xchg   %ax,%ax
L36:
  movsbl (%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L3
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L36
L3:
  lea    0x1(%rbp),%rbx
  cmpb   $0x0,0x0(%rbp)
  mov    %rbp,%r13
  mov    %rbx,%r12
  jne    L54
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rbx,%r13
  add    $0x1,%rbx
L20:
  movzbl 0x0(%r13),%eax
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %al,%al
  je     L75
L54:
  movsbl 0x1(%r13),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L31
  movb   $0x20,0x1(%r13)
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L109:
  movb   $0x20,(%rbx)
  add    $0x1,%rbx
L10:
  movsbl (%rbx),%edi
  call   <UCH@plt>
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L109
  lea    -0x1(%rbx),%r13
  jmp    L20
```

assistant: ```c
int trim_blanks(char *buffer) {
  if (*buffer != '\0') {
    char *d = buffer;
    char *s = after_blanks(d);
    while ((*d++ = *s++) != '\0') {
      ;
    }
    --d;
    while ((--d != buffer) && isspace(UCH(*d)))
      *d = '\0';
    for (s = d = buffer; (*d++ = *s++) != '\0';) {
      if (isspace(UCH(*s))) {
        *s = ' ';
        while (isspace(UCH(*s))) {
          *s++ = ' ';
        }
        --s;
      }
    }
  }
  return (int)strlen(buffer) - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<adjmin>:
  endbr64
  mov    $0x0,%eax
  test   %edx,%edx
  js     L62
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r13d
  cmp    $0x2b,%sil
  je     L144
  cmp    $0x2d,%sil
  je     L21
  mov    $0x0,%eax
  cmp    $0x3b,%edx
  jg     L12
  mov    %edx,(%r12)
  jmp    L37
L144:
  test   %edx,%edx
  jne    L96
L37:
  mov    $0x1,%eax
  test   %r13d,%r13d
  jne    L59
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L96:
  mov    %edx,%eax
  add    (%rdi),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    $0x0,%ecx
  mov    $0x2b,%esi
  call   <adjhour@plt>
  test   %eax,%eax
  je     L12
  movslq %ebx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x5,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3c,%eax,%eax
  sub    %eax,%ebx
  add    (%r12),%ebx
  lea    -0x3c(%rbx),%eax
  cmp    $0x3c,%ebx
  cmovge %eax,%ebx
  mov    %ebx,(%r12)
  jmp    L37
L21:
  test   %edx,%edx
  je     L37
  movslq %edx,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %ebx,%edx
  sar    $0x5,%edx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    $0x0,%ecx
  mov    $0x2d,%esi
  call   <adjhour@plt>
  test   %eax,%eax
  je     L12
  movslq %ebx,%r14
  imul   $0xffffffff88888889,%r14,%r14
  shr    $0x20,%r14
  add    %ebx,%r14d
  sar    $0x5,%r14d
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%r14d
  imul   $0x3c,%r14d,%eax
  sub    %eax,%ebx
  mov    %ebx,%r14d
  cmp    %ebx,(%r12)
  jl     L61
L55:
  sub    %r14d,(%r12)
  jmp    L37
L61:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x2d,%esi
  mov    %r12,%rdi
  call   <adjhour@plt>
  test   %eax,%eax
  je     L12
  sub    $0x3c,%r14d
  jmp    L55
L59:
  movsbl %bpl,%esi
  mov    %r12,%rdi
  call   <domktime@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L12
L62:
  ret
```

assistant: ```c
int adjmin(struct tm *t, char type, int val, int mk) {
  if (val < 0)
    return 0;
  switch (type) {
  case '+':
    if (val) {
      if (!adjhour(t, '+', (t->tm_min + val) / 60, 0))
        return 0;
      val %= 60;
      t->tm_min += val;
      if (t->tm_min > 59)
        t->tm_min -= 60;
    }
    break;
  case '-':
    if (val) {
      if (!adjhour(t, '-', val / 60, 0))
        return 0;
      val %= 60;
      if (val > t->tm_min) {
        if (!adjhour(t, '-', 1, 0))
          return 0;
        val -= 60;
      }
      t->tm_min -= val;
    }
    break;
  default:
    if (val > 59)
      return 0;
    t->tm_min = val;
  }
  return !mk || domktime(t, type) != -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<adjmin>:
  endbr64
  test   %edx,%edx
  js     L62
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  cmp    $0x2b,%sil
  je     L39
  cmp    $0x2d,%sil
  je     L78
  cmp    $0x3b,%edx
  jg     L111
  mov    %edx,(%rdi)
L25:
  mov    $0x1,%eax
  test   %ebp,%ebp
  jne    L121
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L78:
  test   %edx,%edx
  je     L25
  movslq %edx,%r13
  mov    %edx,%eax
  xor    %ecx,%ecx
  mov    $0x2d,%esi
  imul   $0xffffffff88888889,%r13,%r13
  sar    $0x1f,%eax
  mov    %rdi,0x8(%rsp)
  shr    $0x20,%r13
  add    %edx,%r13d
  sar    $0x5,%r13d
  sub    %eax,%r13d
  mov    %r13d,%edx
  call   <adjhour@plt>
  test   %eax,%eax
  je     L111
  imul   $0x3c,%r13d,%r13d
  mov    0x8(%rsp),%rdi
  mov    (%rdi),%eax
  sub    %r13d,%ebx
  cmp    %ebx,%eax
  jl     L15
L100:
  sub    %ebx,%eax
  mov    %eax,(%rdi)
  jmp    L25
  nopl   0x0(%rax)
L39:
  test   %edx,%edx
  je     L25
  mov    (%rdi),%eax
  xor    %ecx,%ecx
  mov    $0x2b,%esi
  mov    %rdi,0x8(%rsp)
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0x5,%edx
  sub    %eax,%edx
  call   <adjhour@plt>
  test   %eax,%eax
  je     L111
  movslq %ebx,%rax
  mov    %ebx,%edx
  mov    0x8(%rsp),%rdi
  imul   $0xffffffff88888889,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x5,%eax
  sub    %edx,%eax
  imul   $0x3c,%eax,%eax
  sub    %eax,%ebx
  add    (%rdi),%ebx
  lea    -0x3c(%rbx),%eax
  cmp    $0x3c,%ebx
  cmovge %eax,%ebx
  mov    %ebx,(%rdi)
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L111:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L121:
  movsbl %r12b,%esi
  call   <domktime@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x18,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L62:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0x2d,%esi
  call   <adjhour@plt>
  test   %eax,%eax
  je     L111
  mov    0x8(%rsp),%rdi
  sub    $0x3c,%ebx
  mov    (%rdi),%eax
  jmp    L100
```

assistant: ```c
int adjmin(struct tm *t, char type, int val, int mk) {
  if (val < 0)
    return 0;
  switch (type) {
  case '+':
    if (val) {
      if (!adjhour(t, '+', (t->tm_min + val) / 60, 0))
        return 0;
      val %= 60;
      t->tm_min += val;
      if (t->tm_min > 59)
        t->tm_min -= 60;
    }
    break;
  case '-':
    if (val) {
      if (!adjhour(t, '-', val / 60, 0))
        return 0;
      val %= 60;
      if (val > t->tm_min) {
        if (!adjhour(t, '-', 1, 0))
          return 0;
        val -= 60;
      }
      t->tm_min -= val;
    }
    break;
  default:
    if (val > 59)
      return 0;
    t->tm_min = val;
  }
  return !mk || domktime(t, type) != -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<adjmin>:
  endbr64
  test   %edx,%edx
  js     L117
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  cmp    $0x2b,%sil
  je     L67
  cmp    $0x2d,%sil
  je     L58
  cmp    $0x3b,%edx
  jg     L105
  mov    %edx,(%rdi)
L25:
  mov    $0x1,%eax
  test   %ebp,%ebp
  jne    L128
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  test   %edx,%edx
  je     L25
  movslq %edx,%r13
  mov    %edx,%eax
  xor    %ecx,%ecx
  mov    $0x2d,%esi
  imul   $0xffffffff88888889,%r13,%r13
  sar    $0x1f,%eax
  mov    %rdi,0x8(%rsp)
  shr    $0x20,%r13
  add    %edx,%r13d
  sar    $0x5,%r13d
  sub    %eax,%r13d
  mov    %r13d,%edx
  call   <adjhour@plt>
  test   %eax,%eax
  je     L105
  imul   $0x3c,%r13d,%r13d
  mov    0x8(%rsp),%rdi
  mov    (%rdi),%eax
  sub    %r13d,%ebx
  cmp    %ebx,%eax
  jl     L71
L133:
  sub    %ebx,%eax
  mov    %eax,(%rdi)
  jmp    L25
  nopl   0x0(%rax)
L67:
  test   %edx,%edx
  je     L25
  mov    (%rdi),%eax
  xor    %ecx,%ecx
  mov    $0x2b,%esi
  mov    %rdi,0x8(%rsp)
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0x5,%edx
  sub    %eax,%edx
  call   <adjhour@plt>
  test   %eax,%eax
  je     L105
  movslq %ebx,%rax
  mov    %ebx,%edx
  mov    0x8(%rsp),%rdi
  imul   $0xffffffff88888889,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x5,%eax
  sub    %edx,%eax
  imul   $0x3c,%eax,%eax
  sub    %eax,%ebx
  add    (%rdi),%ebx
  lea    -0x3c(%rbx),%eax
  cmp    $0x3c,%ebx
  cmovge %eax,%ebx
  mov    %ebx,(%rdi)
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L105:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L128:
  movsbl %r12b,%esi
  call   <domktime@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x18,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L117:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L71:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    $0x2d,%esi
  call   <adjhour@plt>
  test   %eax,%eax
  je     L105
  mov    0x8(%rsp),%rdi
  sub    $0x3c,%ebx
  mov    (%rdi),%eax
  jmp    L133
```

assistant: ```c
int adjmin(struct tm *t, char type, int val, int mk) {
  if (val < 0)
    return 0;
  switch (type) {
  case '+':
    if (val) {
      if (!adjhour(t, '+', (t->tm_min + val) / 60, 0))
        return 0;
      val %= 60;
      t->tm_min += val;
      if (t->tm_min > 59)
        t->tm_min -= 60;
    }
    break;
  case '-':
    if (val) {
      if (!adjhour(t, '-', val / 60, 0))
        return 0;
      val %= 60;
      if (val > t->tm_min) {
        if (!adjhour(t, '-', 1, 0))
          return 0;
        val -= 60;
      }
      t->tm_min -= val;
    }
    break;
  default:
    if (val > 59)
      return 0;
    t->tm_min = val;
  }
  return !mk || domktime(t, type) != -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rop3_244_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  not    %eax
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %eax,%edx
  movzbl -0x20(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x1c(%rbp),%al
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_244_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_244_1_1>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  movzbl (%rax),%ecx
  mov    %edx,%r8d
  or     %esi,%r8d
  mov    %ecx,%edx
  not    %edx
  and    %esi,%edx
  or     %edi,%edx
  mov    %r8d,%esi
  not    %esi
  and    %esi,%edx
  and    %r8d,%ecx
  or     %ecx,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void rop3_244_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rop3_244_1_1>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%r8d
  mov    %edx,%edi
  movzbl (%rax),%ecx
  or     %esi,%r8d
  mov    %ecx,%edx
  and    %r8d,%ecx
  not    %edx
  and    %esi,%edx
  mov    %r8d,%esi
  or     %edi,%edx
  not    %esi
  and    %esi,%edx
  or     %ecx,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void rop3_244_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_244_1_1>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%r8d
  mov    %edx,%edi
  movzbl (%rax),%ecx
  or     %esi,%r8d
  mov    %ecx,%edx
  and    %r8d,%ecx
  not    %edx
  and    %esi,%edx
  mov    %r8d,%esi
  or     %edi,%edx
  not    %esi
  and    %esi,%edx
  or     %ecx,%edx
  mov    %dl,(%rax)
  ret
```

assistant: ```c
void rop3_244_1_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T | stk2;
  *D = (stk1 & (~S) & (~T)) | (*D & S) | (*D & T);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IncopyOut3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L48
L47:
  cmpl   $0x20,-0x8(%rbp)
  jne    L23
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L10
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L10
L23:
  cmpl   $0xa,-0x8(%rbp)
  jne    L55
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L55:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
L10:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L48:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L47
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int IncopyOut3() {
  int ch;
  int n = 0;
  ch = getchar();
  while (ch != EOF) {
    if (ch == ' ') {
      n++;
      if (n <= 1)
        putchar(ch);
    } else if (ch == '\n') {
      putchar(ch);
      n = 0;
    } else {
      putchar(ch);
      n = 0;
    }
    ch = getchar();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IncopyOut3>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    (%rdx),%eax
  je     L76
  mov    $0x0,%ebx
  jmp    L50
L55:
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  jle    L66
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L76
L50:
  cmp    $0x20,%eax
  je     L55
  cmp    $0xa,%eax
  je     L40
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  jmp    L8
L66:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L8
L40:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  jmp    L8
L76:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int IncopyOut3() {
  int ch;
  int n = 0;
  ch = getchar();
  while (ch != EOF) {
    if (ch == ' ') {
      n++;
      if (n <= 1)
        putchar(ch);
    } else if (ch == '\n') {
      putchar(ch);
      n = 0;
    } else {
      putchar(ch);
      n = 0;
    }
    ch = getchar();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IncopyOut3>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    D9(%rip),%rbp
  cmp    0x0(%rbp),%eax
  je     L77
  xor    %ebx,%ebx
  jmp    L3
  nopl   0x0(%rax)
L9:
  cmp    $0xa,%eax
  je     L33
  mov    %eax,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  je     L77
L3:
  cmp    $0x20,%eax
  jne    L9
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  jne    L24
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L3
L77:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L33:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  jmp    L24
```

assistant: ```c
int IncopyOut3() {
  int ch;
  int n = 0;
  ch = getchar();
  while (ch != EOF) {
    if (ch == ' ') {
      n++;
      if (n <= 1)
        putchar(ch);
    } else if (ch == '\n') {
      putchar(ch);
      n = 0;
    } else {
      putchar(ch);
      n = 0;
    }
    ch = getchar();
  }
  return 0;
}
```