ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<pi>:
  endbr64
  test   %edi,%edi
  jle    L8
  lea    0x1(%rdi,%rdi,1),%edx
  mov    $0x1,%eax
  movsd  D6(%rip),%xmm1
  pxor   %xmm0,%xmm0
  movq   D13(%rip),%xmm4
L21:
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movapd %xmm1,%xmm2
  divsd  %xmm3,%xmm2
  xorpd  %xmm4,%xmm1
  addsd  %xmm2,%xmm0
  add    $0x2,%eax
  cmp    %edx,%eax
  jne    L21
L25:
  mulsd  D22(%rip),%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: f64
name: disassemble_data
arguments: data_tag: D13
type: f32[2]
name: disassemble_data
arguments: data_tag: D22
type: f32[2]

tool: D6: 1

tool: {"D13": [0.0,-0.0]}

tool: {"D22": [0.0,2.25]}

assistant: ```c
double pi(int amount) {
  int i = 0;
  double sum = 0.0;
  double sign = 1.0;
  for (; i < amount; ++i) {
    double item = sign / (2 * i + 1);
    sign = -sign;
    sum += item;
  }
  return 4 * sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pi>:
  endbr64
  test   %edi,%edi
  jle    L3
  movsd  D17(%rip),%xmm1
  lea    0x1(%rdi,%rdi,1),%edx
  mov    $0x1,%eax
  movq   D16(%rip),%xmm4
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L2:
  pxor   %xmm3,%xmm3
  movapd %xmm1,%xmm2
  xorpd  %xmm4,%xmm1
  cvtsi2sd %eax,%xmm3
  add    $0x2,%eax
  divsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L2
  mulsd  D20(%rip),%xmm0
  ret
L3:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
data_type: f64
name: disassemble_data
arguments: tag: D16
data_type: f32[2]
name: disassemble_data
arguments: tag: D20
data_type: f32[2]

tool: D17: 1

tool: {"D16": [0.0,-0.0]}

tool: {"D20": [0.0,2.25]}

assistant: ```c
double pi(int amount) {
  int i = 0;
  double sum = 0.0;
  double sign = 1.0;
  for (; i < amount; ++i) {
    double item = sign / (2 * i + 1);
    sign = -sign;
    sum += item;
  }
  return 4 * sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pi>:
  endbr64
  test   %edi,%edi
  jle    L19
  movsd  D26(%rip),%xmm1
  lea    0x1(%rdi,%rdi,1),%edx
  mov    $0x1,%eax
  movq   D18(%rip),%xmm4
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L5:
  pxor   %xmm3,%xmm3
  movapd %xmm1,%xmm2
  xorpd  %xmm4,%xmm1
  cvtsi2sd %eax,%xmm3
  add    $0x2,%eax
  divsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L5
  mulsd  D23(%rip),%xmm0
  ret
L19:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: f64
name: parse_data
arguments: label: D18
type_infered: f32[2]
name: parse_data
arguments: label: D23
type_infered: f32[2]

tool: D26: 1

tool: {"D18": [0.0,-0.0]}

tool: {"D23": [0.0,2.25]}

assistant: ```c
double pi(int amount) {
  int i = 0;
  double sum = 0.0;
  double sign = 1.0;
  for (; i < amount; ++i) {
    double item = sign / (2 * i + 1);
    sign = -sign;
    sum += item;
  }
  return 4 * sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<s_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,%eax
  mov    %al,-0xc(%rbp)
  jmp    L18
L26:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mls@plt>
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L24
  mov    -0x8(%rbp),%eax
  jmp    L36
L24:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <m_len@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L26
  mov    $0xffffffff,%eax
L36:
  leave
  ret
```

assistant: ```c
int s_index(int m, int p, char ch) {
  while (p < m_len(m))
    if (ch == (*(char *)mls((m), (p))))
      return p;
    else
      p++;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_index>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  jmp    L24
L32:
  add    $0x1,%ebx
L24:
  mov    %ebp,%edi
  call   <m_len@plt>
  cmp    %ebx,%eax
  jle    L1
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmp    %r12b,(%rax)
  jne    L32
  mov    %ebx,%eax
  jmp    L28
L1:
  mov    $0xffffffff,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int s_index(int m, int p, char ch) {
  while (p < m_len(m))
    if (ch == (*(char *)mls((m), (p))))
      return p;
    else
      p++;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<s_index>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L25
  nopl   0x0(%rax)
L0:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmp    %r12b,(%rax)
  je     L17
  add    $0x1,%ebx
L25:
  mov    %ebp,%edi
  call   <m_len@plt>
  cmp    %ebx,%eax
  jg     L0
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L17:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int s_index(int m, int p, char ch) {
  while (p < m_len(m))
    if (ch == (*(char *)mls((m), (p))))
      return p;
    else
      p++;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<s_index>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  jmp    L29
  nopl   0x0(%rax)
L27:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mls@plt>
  cmp    %r12b,(%rax)
  je     L24
  add    $0x1,%ebx
L29:
  mov    %ebp,%edi
  call   <m_len@plt>
  cmp    %ebx,%eax
  jg     L27
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L24:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int s_index(int m, int p, char ch) {
  while (p < m_len(m))
    if (ch == (*(char *)mls((m), (p))))
      return p;
    else
      p++;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6b,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  lea    -0x22(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] <= local1) {
        state[0UL] |= ((state[local1] + state[0UL]) & (unsigned char)31) << 3UL;
      } else {
        state[local1] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 381482377UL) + (unsigned char)85;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] <= local1) {
        state[0UL] |= ((state[local1] + state[0UL]) & (unsigned char)31) << 3UL;
      } else {
        state[local1] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 381482377UL) + (unsigned char)85;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] <= local1) {
        state[0UL] |= ((state[local1] + state[0UL]) & (unsigned char)31) << 3UL;
      } else {
        state[local1] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 381482377UL) + (unsigned char)85;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x73,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] > local1) {
        state[0UL] |= (((state[local1] >> ((state[local1] & (unsigned char)15) | 1UL)) | (state[local1] << (8 - ((state[local1] & (unsigned char)15) | 1UL)))) & (unsigned char)63) << 4UL;
      } else {
        state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      }
      if (state[0UL] <= local1) {
        state[0UL] |= ((state[local1] + state[0UL]) & (unsigned char)31) << 3UL;
      } else {
        state[local1] <<= ((state[0UL] >> (unsigned char)1) & (unsigned char)7) | 1UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 381482377UL) + (unsigned char)85;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sameNet6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L65
L52:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L62
  mov    $0x0,%eax
  jmp    L28
L62:
  addl   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L52
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xf,-0x8(%rbp)
  jg     L24
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  xor    %esi,%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L24
  mov    $0x0,%eax
  jmp    L28
L24:
  mov    $0x1,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int sameNet6(char *s, char *d, int cidr) {
  int b;
  int i;
  b = cidr / 8;
  i = 0;
  while (i < b) {
    if (s[i] != d[i])
      return 0;
    i++;
  }
  b = 8 - cidr % 8;
  if (i < 16 && ((s[i] >> b) & 0xff) != ((d[i] >> b) & 0xff))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sameNet6>:
  endbr64
  lea    0x7(%rdx),%ecx
  test   %edx,%edx
  cmovns %edx,%ecx
  sar    $0x3,%ecx
  cmp    $0x7,%edx
  jle    L19
  mov    $0x0,%eax
L7:
  movzbl (%rsi,%rax,1),%r9d
  cmp    %r9b,(%rdi,%rax,1)
  jne    L0
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L7
  mov    $0x1,%eax
  cmp    $0xf,%r8d
  jle    L47
  ret
L47:
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax),%ecx
L34:
  movslq %r8d,%r8
  movsbl (%rdi,%r8,1),%edx
  movsbl (%rsi,%r8,1),%eax
  xor    %edx,%eax
  sar    %cl,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
L19:
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax),%ecx
  mov    $0x0,%r8d
  jmp    L34
```

assistant: ```c
int sameNet6(char *s, char *d, int cidr) {
  int b;
  int i;
  b = cidr / 8;
  i = 0;
  while (i < b) {
    if (s[i] != d[i])
      return 0;
    i++;
  }
  b = 8 - cidr % 8;
  if (i < 16 && ((s[i] >> b) & 0xff) != ((d[i] >> b) & 0xff))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sameNet6>:
  endbr64
  test   %edx,%edx
  lea    0x7(%rdx),%ecx
  cmovns %edx,%ecx
  sar    $0x3,%ecx
  cmp    $0x7,%edx
  jle    L19
  xor    %eax,%eax
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L33:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %eax,%ecx
  jle    L31
L24:
  movzbl (%rsi,%rax,1),%r9d
  cmp    %r9b,(%rdi,%rax,1)
  je     L33
  xor    %eax,%eax
L18:
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0x1,%eax
  cmp    $0xf,%r8d
  jg     L18
  movslq %r8d,%r8
  and    $0x7,%edx
  mov    $0x8,%ecx
  sub    %edx,%ecx
  add    %r8,%rdi
  add    %r8,%rsi
L58:
  movsbl (%rdi),%edx
  movsbl (%rsi),%eax
  xor    %edx,%eax
  sar    %cl,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L19:
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax),%ecx
  jmp    L58
```

assistant: ```c
int sameNet6(char *s, char *d, int cidr) {
  int b;
  int i;
  b = cidr / 8;
  i = 0;
  while (i < b) {
    if (s[i] != d[i])
      return 0;
    i++;
  }
  b = 8 - cidr % 8;
  if (i < 16 && ((s[i] >> b) & 0xff) != ((d[i] >> b) & 0xff))
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sameNet6>:
  endbr64
  test   %edx,%edx
  lea    0x7(%rdx),%ecx
  cmovns %edx,%ecx
  sar    $0x3,%ecx
  cmp    $0x7,%edx
  jle    L32
  xor    %eax,%eax
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L20:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %eax,%ecx
  jle    L51
L53:
  movzbl (%rsi,%rax,1),%r9d
  cmp    %r9b,(%rdi,%rax,1)
  je     L20
  xor    %eax,%eax
L13:
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    $0x1,%eax
  cmp    $0xf,%r8d
  jg     L13
  movslq %r8d,%r8
  and    $0x7,%edx
  mov    $0x8,%ecx
  sub    %edx,%ecx
  add    %r8,%rdi
  add    %r8,%rsi
L25:
  movsbl (%rdi),%edx
  movsbl (%rsi),%eax
  xor    %edx,%eax
  sar    %cl,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L32:
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  add    %eax,%edx
  and    $0x7,%edx
  sub    %edx,%eax
  lea    0x8(%rax),%ecx
  jmp    L25
```

assistant: ```c
int sameNet6(char *s, char *d, int cidr) {
  int b;
  int i;
  b = cidr / 8;
  i = 0;
  while (i < b) {
    if (s[i] != d[i])
      return 0;
    i++;
  }
  b = 8 - cidr % 8;
  if (i < 16 && ((s[i] >> b) & 0xff) != ((d[i] >> b) & 0xff))
    return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rtpp_in_cksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L16
L31:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  add    %eax,-0x20(%rbp)
  subl   $0x2,-0x24(%rbp)
L16:
  cmpl   $0x1,-0x24(%rbp)
  jg     L31
  cmpl   $0x1,-0x24(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    %eax,-0x20(%rbp)
L6:
  mov    -0x20(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  not    %eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
uint16_t rtpp_in_cksum(void *addr, int len) {
  int nleft, sum;
  uint16_t *w;
  union {
    uint16_t us;
    uint16_t uc[2];
  } last;
  uint16_t answer;
  nleft = len;
  sum = 0;
  w = (uint16_t *)addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    last.uc[0] = *(uint8_t *)w;
    last.uc[1] = 0;
    sum += last.us;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rtpp_in_cksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  mov    $0x0,%eax
L25:
  add    $0x4,%rdi
  add    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L25
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%esi
L4:
  cmp    $0x1,%esi
  je     L3
L49:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L15:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L4
L3:
  add    (%rdx),%eax
  jmp    L49
```

assistant: ```c
uint16_t rtpp_in_cksum(void *addr, int len) {
  int nleft, sum;
  uint16_t *w;
  union {
    uint16_t us;
    uint16_t uc[2];
  } last;
  uint16_t answer;
  nleft = len;
  sum = 0;
  w = (uint16_t *)addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    last.uc[0] = *(uint8_t *)w;
    last.uc[1] = 0;
    sum += last.us;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtpp_in_cksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L21
  sub    $0x2,%esi
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%eax
  lea    (%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  add    $0x4,%rdi
  add    -0x4(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L1
  neg    %ecx
  lea    (%rsi,%rcx,2),%esi
L17:
  cmp    $0x1,%esi
  jne    L31
  add    (%rdx),%eax
L31:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax)
L21:
  mov    %rdi,%rdx
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
uint16_t rtpp_in_cksum(void *addr, int len) {
  int nleft, sum;
  uint16_t *w;
  union {
    uint16_t us;
    uint16_t uc[2];
  } last;
  uint16_t answer;
  nleft = len;
  sum = 0;
  w = (uint16_t *)addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    last.uc[0] = *(uint8_t *)w;
    last.uc[1] = 0;
    sum += last.us;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtpp_in_cksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0x5,%r10d
  jbe    L7
  mov    %rdi,%rax
  mov    %ecx,%edi
  pxor   %xmm0,%xmm0
  shr    $0x2,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
L24:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L24
  movdqa %xmm0,%xmm1
  mov    %ecx,%edi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edi
  paddd  %xmm1,%xmm0
  mov    %edi,%r8d
  movdqa %xmm0,%xmm1
  neg    %r8d
  psrldq $0x4,%xmm1
  lea    (%rsi,%r8,2),%esi
  mov    %edi,%r8d
  paddd  %xmm1,%xmm0
  lea    (%rdx,%r8,4),%r8
  movd   %xmm0,%eax
  cmp    %edi,%ecx
  je     L29
L2:
  lea    -0x2(%rsi),%edi
  add    (%r8),%eax
  cmp    $0x1,%edi
  jle    L29
  add    0x4(%r8),%eax
  cmp    $0x5,%esi
  jle    L29
  add    0x8(%r8),%eax
L29:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,4),%rdx
  lea    (%r10,%rcx,2),%esi
L45:
  cmp    $0x1,%esi
  jne    L11
  add    (%rdx),%eax
L11:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  jmp    L45
L7:
  mov    %rdi,%r8
  xor    %eax,%eax
  jmp    L2
```

assistant: ```c
uint16_t rtpp_in_cksum(void *addr, int len) {
  int nleft, sum;
  uint16_t *w;
  union {
    uint16_t us;
    uint16_t uc[2];
  } last;
  uint16_t answer;
  nleft = len;
  sum = 0;
  w = (uint16_t *)addr;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    last.uc[0] = *(uint8_t *)w;
    last.uc[1] = 0;
    sum += last.us;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  answer = ~sum;
  return (answer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x40(%rbp)
  movl   $0x25,-0x3c(%rbp)
  movl   $0x4f,-0x38(%rbp)
  movl   $0x80,-0x34(%rbp)
  movl   $0x391,-0x30(%rbp)
  movl   $0x2cb,-0x2c(%rbp)
  movl   $0xbd,-0x28(%rbp)
  movl   $0x356,-0x24(%rbp)
  movl   $0x2ad,-0x20(%rbp)
  movl   $0xc,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0xb,-0x44(%rbp)
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <radixSort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L26
L8:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L26:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_infered: string

tool: D8: %d 

assistant: ```c
int main() {
  int v[] = {5, 37, 79, 128, 913, 715, 189, 854, 685, 12, 0};
  int n = sizeof(v) / sizeof(v[0]);
  int i;
  radixSort(v, n);
  for (i = 0; i < n; ++i)
    printf("%d ", v[i]);
  printf("\n");
  return 0;
}
```