ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<test14>:
  endbr64
  ret
```

assistant: ```c
void test14() {
  typedef long long __m64 __attribute__((__vector_size__(8)));
  typedef short __v4hi __attribute__((__vector_size__(8)));
  __v4hi a;
  __m64 mask = (__m64)((__v4hi)a > (__v4hi)a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test14>:
  endbr64
  ret
```

assistant: ```c
void test14() {
  typedef long long __m64 __attribute__((__vector_size__(8)));
  typedef short __v4hi __attribute__((__vector_size__(8)));
  __v4hi a;
  __m64 mask = (__m64)((__v4hi)a > (__v4hi)a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test14>:
  endbr64
  ret
```

assistant: ```c
void test14() {
  typedef long long __m64 __attribute__((__vector_size__(8)));
  typedef short __v4hi __attribute__((__vector_size__(8)));
  __v4hi a;
  __m64 mask = (__m64)((__v4hi)a > (__v4hi)a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RemoveBlanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L16
L23:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L16:
  cmpl   $0x0,-0x4(%rbp)
  je     L25
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L23
L25:
  nop
  leave
  ret
```

assistant: ```c
void RemoveBlanks(char *p) {
  int l;
  l = strlen(p);
  while (l && p[l - 1] == ' ')
    p[--l] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RemoveBlanks>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L3
  mov    %eax,%ecx
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  lea    -0x2(%rbx,%rax,1),%rax
  lea    -0x1(%rcx),%ecx
  sub    %rcx,%rax
L19:
  cmpb   $0x20,(%rdx)
  jne    L3
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L19
L3:
  pop    %rbx
  ret
```

assistant: ```c
void RemoveBlanks(char *p) {
  int l;
  l = strlen(p);
  while (l && p[l - 1] == ' ')
    p[--l] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RemoveBlanks>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L7
  mov    %eax,%ecx
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  sub    $0x1,%ecx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L28:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L7
L26:
  cmpb   $0x20,(%rdx)
  je     L28
L7:
  pop    %rbx
  ret
```

assistant: ```c
void RemoveBlanks(char *p) {
  int l;
  l = strlen(p);
  while (l && p[l - 1] == ' ')
    p[--l] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RemoveBlanks>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L11
  mov    %eax,%ecx
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  sub    $0x1,%ecx
  lea    -0x2(%rbx,%rax,1),%rax
  sub    %rcx,%rax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L29:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %rax,%rdx
  je     L11
L3:
  cmpb   $0x20,(%rdx)
  je     L29
L11:
  pop    %rbx
  ret
```

assistant: ```c
void RemoveBlanks(char *p) {
  int l;
  l = strlen(p);
  while (l && p[l - 1] == ' ')
    p[--l] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  add    $0x1,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  add    $0x1,%rdx
  mov    %rdx,%rcx
  mov    $0x0,%ebx
  cltq
  lea    0x1(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L25:
  cmp    %rdx,%rsp
  je     L35
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L35:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movb   $0x78,0x1(%rax)
  mov    $0x0,%eax
  mov    %rsi,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void *p(int n) {
  struct f {
    char w;
    char x[n];
    char z[];
  } F;
  F.x[0] = 'x';
  return &F;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<p>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *p(int n) {
  struct f {
    char w;
    char x[n];
    char z[];
  } F;
  F.x[0] = 'x';
  return &F;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<p>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *p(int n) {
  struct f {
    char w;
    char x[n];
    char z[];
  } F;
  F.x[0] = 'x';
  return &F;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<p>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
void *p(int n) {
  struct f {
    char w;
    char x[n];
    char z[];
  } F;
  F.x[0] = 'x';
  return &F;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_get_argument_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L21
L60:
  mov    -0x8(%rbp),%rax
  movb   $0x22,(%rax)
  jmp    L20
L75:
  addl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L75
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L22
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x22,(%rax)
L22:
  mov    $0x1,%eax
  jmp    L32
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L36
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L36
  mov    $0x2,%eax
  jmp    L32
L36:
  mov    $0x1,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
char ft_get_argument_type(void *arg) {
  char *content;
  int i;
  content = (char *)arg;
  i = 0;
  if (content[0] == '"' || content[0] == '\'') {
    content[0] = '"';
    while (content[i])
      i++;
    if (content[i - 1] == '\'')
      content[i - 1] = '"';
    return (1);
  }
  if (content[0] >= '0' && content[0] <= '9')
    return (2);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_get_argument_type>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x22,%al
  je     L11
  cmp    $0x27,%al
  je     L11
  sub    $0x30,%eax
  cmp    $0xa,%al
  setb   %al
  add    $0x1,%eax
L37:
  ret
L11:
  movb   $0x22,(%rdi)
  mov    $0x1,%eax
L38:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L38
  lea    -0x1(%rdi,%rdx,1),%rdx
  mov    $0x1,%eax
  cmpb   $0x27,(%rdx)
  jne    L37
  movb   $0x22,(%rdx)
  ret
```

assistant: ```c
char ft_get_argument_type(void *arg) {
  char *content;
  int i;
  content = (char *)arg;
  i = 0;
  if (content[0] == '"' || content[0] == '\'') {
    content[0] = '"';
    while (content[i])
      i++;
    if (content[i - 1] == '\'')
      content[i - 1] = '"';
    return (1);
  }
  if (content[0] >= '0' && content[0] <= '9')
    return (2);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_get_argument_type>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x22,%al
  je     L28
  cmp    $0x27,%al
  je     L28
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L48
L46:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L28:
  movb   $0x22,(%rdi)
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L34
  lea    -0x1(%rdi,%rdx,1),%rax
  cmpb   $0x27,(%rax)
  jne    L46
  movb   $0x22,(%rax)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L48:
  mov    $0x2,%eax
  ret
```

assistant: ```c
char ft_get_argument_type(void *arg) {
  char *content;
  int i;
  content = (char *)arg;
  i = 0;
  if (content[0] == '"' || content[0] == '\'') {
    content[0] = '"';
    while (content[i])
      i++;
    if (content[i - 1] == '\'')
      content[i - 1] = '"';
    return (1);
  }
  if (content[0] >= '0' && content[0] <= '9')
    return (2);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_get_argument_type>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x22,%al
  je     L1
  cmp    $0x27,%al
  je     L1
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L14
L8:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L1:
  movb   $0x22,(%rdi)
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L19
  lea    -0x1(%rdi,%rdx,1),%rax
  cmpb   $0x27,(%rax)
  jne    L8
  movb   $0x22,(%rax)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L14:
  mov    $0x2,%eax
  ret
```

assistant: ```c
char ft_get_argument_type(void *arg) {
  char *content;
  int i;
  content = (char *)arg;
  i = 0;
  if (content[0] == '"' || content[0] == '\'') {
    content[0] = '"';
    while (content[i])
      i++;
    if (content[i - 1] == '\'')
      content[i - 1] = '"';
    return (1);
  }
  if (content[0] >= '0' && content[0] <= '9')
    return (2);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  cmpl   $0x0,-0x34(%rbp)
  js     L83
  mov    -0x34(%rbp),%edx
  cmp    -0x24(%rbp),%edx
  jge    L83
  cmpl   $0x0,-0x38(%rbp)
  js     L83
  mov    -0x38(%rbp),%edx
  cmp    -0x28(%rbp),%edx
  jge    L83
  mov    -0x34(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  imul   %rcx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rcx,%rdx,4),%edx
  test   %edx,%edx
  je     L33
L83:
  mov    $0x0,%eax
  jmp    L99
L33:
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  cltq
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%eax
  cltq
  movl   $0xffffffff,(%rdx,%rax,4)
  movl   $0x1,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  jmp    L57
L69:
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L40
L8:
  mov    -0x38(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%edi
  mov    -0x34(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <calculate>
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0xc(%rbp)
L40:
  cmpl   $0x1,-0xc(%rbp)
  jle    L8
  addl   $0x1,-0x10(%rbp)
L57:
  cmpl   $0x1,-0x10(%rbp)
  jle    L69
  mov    -0x14(%rbp),%eax
L99:
  leave
  ret
```

assistant: ```c
int calculate(int len, int wid, int map[len][wid], int row, int col) {
  if (row < 0 || row >= len || col < 0 || col >= wid || map[row][col] != 0)
    return 0;
  map[row][col] = -1;
  int size = 1;
  for (int i = -1; i <= 1; i++) {
    for (int j = -1; j <= 1; j++) {
      size += calculate(len, wid, map, row + i, col + j);
    }
  }
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %rdx,(%rsp)
  mov    %ecx,%edi
  or     %r8d,%edi
  js     L27
  mov    %esi,%r12d
  mov    %rdx,%rsi
  mov    %ecx,%eax
  mov    %r8d,%r13d
  cmp    %ecx,%r14d
  jle    L27
  mov    $0x0,%ebp
  cmp    %r8d,%r12d
  jle    L22
  movslq %r12d,%rdx
  movslq %ecx,%rcx
  imul   %rcx,%rdx
  lea    (%rsi,%rdx,4),%rcx
  movslq %r8d,%rdx
  cmpl   $0x0,(%rcx,%rdx,4)
  jne    L22
  movl   $0xffffffff,(%rcx,%rdx,4)
  lea    -0x1(%rax),%r15d
  add    $0x2,%eax
  mov    %eax,0xc(%rsp)
  mov    $0x1,%ebp
  lea    0x2(%r8),%eax
  mov    %eax,0x8(%rsp)
L20:
  lea    -0x1(%r13),%ebx
L51:
  mov    %ebx,%r8d
  mov    %r15d,%ecx
  mov    (%rsp),%rdx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <calculate>
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    0x8(%rsp),%ebx
  jne    L51
  add    $0x1,%r15d
  cmp    0xc(%rsp),%r15d
  jne    L20
  jmp    L22
L27:
  mov    $0x0,%ebp
L22:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int calculate(int len, int wid, int map[len][wid], int row, int col) {
  if (row < 0 || row >= len || col < 0 || col >= wid || map[row][col] != 0)
    return 0;
  map[row][col] = -1;
  int size = 1;
  for (int i = -1; i <= 1; i++) {
    for (int j = -1; j <= 1; j++) {
      size += calculate(len, wid, map, row + i, col + j);
    }
  }
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calculate>:
  endbr64
  push   %r15
  mov    %ecx,%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  or     %r8d,%eax
  js     L30
  mov    %rdx,%rbp
  mov    %edi,%r14d
  mov    %ecx,%edx
  cmp    %ecx,%edi
  jle    L30
  mov    %esi,%r13d
  xor    %r12d,%r12d
  cmp    %r8d,%esi
  jle    L63
  movslq %esi,%rax
  movslq %ecx,%rcx
  imul   %rcx,%rax
  movslq %r8d,%rcx
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax,%rcx,4),%esi
  test   %esi,%esi
  jne    L63
  movl   $0xffffffff,(%rax,%rcx,4)
  lea    0x2(%rdx),%eax
  lea    -0x1(%rdx),%r15d
  mov    $0x1,%r12d
  mov    %eax,0x8(%rsp)
  lea    -0x1(%r8),%eax
  mov    %eax,0xc(%rsp)
  lea    0x2(%r8),%eax
  mov    %eax,0x4(%rsp)
L23:
  mov    0xc(%rsp),%ebx
L43:
  mov    %ebx,%r8d
  mov    %r15d,%ecx
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r14d,%edi
  add    $0x1,%ebx
  call   <calculate>
  add    %eax,%r12d
  cmp    0x4(%rsp),%ebx
  jne    L43
  add    $0x1,%r15d
  cmp    0x8(%rsp),%r15d
  jne    L23
L63:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r12d,%r12d
  jmp    L63
```

assistant: ```c
int calculate(int len, int wid, int map[len][wid], int row, int col) {
  if (row < 0 || row >= len || col < 0 || col >= wid || map[row][col] != 0)
    return 0;
  map[row][col] = -1;
  int size = 1;
  for (int i = -1; i <= 1; i++) {
    for (int j = -1; j <= 1; j++) {
      size += calculate(len, wid, map, row + i, col + j);
    }
  }
  return size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<robPrintAscii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <space@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <space@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <space@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <space@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x3,-0x4(%rbp)
  jle    L15
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D31
datatype: string
name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D27:     -_-    


tool: D31:    [@_@]   


tool: D22:   /|   |\   


tool: D14:    d   b   


assistant: ```c
void robPrintAscii(void) {
  int i = 1;
  for (i; i < 4; i++) {
    space(i);
    printf("    -_-    \n");
    space(i);
    printf("   [@_@]   \n");
    space(i);
    printf("  /|   |\\   \n");
    space(i);
    printf("   d   b   \n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<robPrintAscii>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D39(%rip),%r14
  lea    D8(%rip),%r13
  lea    D18(%rip),%r12
  lea    D19(%rip),%rbp
L0:
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x4,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D39
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D19
type_guessed: string

tool: D39:     -_-    


tool: D8:    [@_@]   


tool: D18:   /|   |\   


tool: D19:    d   b   


assistant: ```c
void robPrintAscii(void) {
  int i = 1;
  for (i; i < 4; i++) {
    space(i);
    printf("    -_-    \n");
    space(i);
    printf("   [@_@]   \n");
    space(i);
    printf("  /|   |\\   \n");
    space(i);
    printf("   d   b   \n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<robPrintAscii>:
  endbr64
  push   %r14
  lea    D32(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
L5:
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <space@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D32:     -_-    


tool: D17:    [@_@]   


tool: D15:   /|   |\   


tool: D3:    d   b   


assistant: ```c
void robPrintAscii(void) {
  int i = 1;
  for (i; i < 4; i++) {
    space(i);
    printf("    -_-    \n");
    space(i);
    printf("   [@_@]   \n");
    space(i);
    printf("  /|   |\\   \n");
    space(i);
    printf("   d   b   \n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<robPrintAscii>:
  endbr64
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D38(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
L0:
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <space@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <space@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string

tool: D16:     -_-    


tool: D36:    [@_@]   


tool: D15:   /|   |\   


tool: D38:    d   b   


assistant: ```c
void robPrintAscii(void) {
  int i = 1;
  for (i; i < 4; i++) {
    space(i);
    printf("    -_-    \n");
    space(i);
    printf("   [@_@]   \n");
    space(i);
    printf("  /|   |\\   \n");
    space(i);
    printf("   d   b   \n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D149(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D203(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D149(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D193(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D197(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D192(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D192(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D217(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D192(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D192(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D192(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D196
datatype: string
name: extract_symbolic_data
arguments: data_label: D149
datatype: string
name: extract_symbolic_data
arguments: data_label: D203
datatype: string
name: extract_symbolic_data
arguments: data_label: D193
datatype: string
name: extract_symbolic_data
arguments: data_label: D197
datatype: string
name: extract_symbolic_data
arguments: data_label: D192
datatype: string
name: extract_symbolic_data
arguments: data_label: D217
datatype: string

tool: D39:   JJ     

tool: D196: %s 


tool: D149:  J       

tool: D203: J        

tool: D193:   JJJJJJJ

tool: 

tool: D192:         T

tool: D217: TTTTTTTTT

assistant: ```c
int main() {
  printf("%s \n", "  JJ     ");
  printf("%s \n", " J       ");
  printf("%s \n", "J        ");
  printf("%s \n", " J       ");
  printf("%s \n", "  JJJJJJJ");
  puts("");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "TTTTTTTTT");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  return 0;
}
```