ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bitsum0>:
  endbr64
  movzbl %dil,%edi
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  nopl   (%rax)
L9:
  mov    %edi,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%r8b
  add    $0x1,%ecx
  cmp    $0x8,%ecx
  jne    L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char bitsum0(unsigned char byte) {
  unsigned char ret;
  unsigned char i;
  for (i = 0, ret = 0; i < 8; i++)
    if (!(byte & 0x01 << i))
      ret++;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitsum0>:
  endbr64
  movzbl %dil,%edx
  mov    %edi,%eax
  mov    %edx,%ecx
  xor    $0x1,%eax
  sar    %ecx
  and    $0x1,%eax
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %edx,%ecx
  adc    $0x0,%al
  sar    $0x2,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %edx,%ecx
  adc    $0x0,%al
  sar    $0x3,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %edx,%ecx
  adc    $0x0,%al
  sar    $0x4,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %edx,%ecx
  adc    $0x0,%al
  sar    $0x5,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  mov    %edx,%ecx
  adc    $0x0,%al
  sar    $0x6,%ecx
  and    $0x1,%ecx
  cmp    $0x1,%ecx
  adc    $0x0,%al
  sar    $0x7,%edx
  cmp    $0x1,%edx
  adc    $0x0,%al
  ret
```

assistant: ```c
unsigned char bitsum0(unsigned char byte) {
  unsigned char ret;
  unsigned char i;
  for (i = 0, ret = 0; i < 8; i++)
    if (!(byte & 0x01 << i))
      ret++;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<maxProfit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L13
  cmpl   $0x1,-0x1c(%rbp)
  jne    L61
L13:
  mov    $0x0,%eax
  jmp    L48
L61:
  movl   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L65
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L15
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L44
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L44:
  addl   $0x1,-0x8(%rbp)
L65:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0xc(%rbp),%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  if (!pricesSize || pricesSize == 1)
    return (0);
  int min, maxdiff, i, t;
  maxdiff = min = 0;
  for (i = 1; i < pricesSize; i++) {
    if (prices[i] < prices[min])
      min = i;
    t = prices[i] - prices[min];
    if (t > maxdiff)
      maxdiff = t;
  }
  return (maxdiff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maxProfit>:
  endbr64
  cmp    $0x1,%esi
  jle    L26
  mov    %esi,%esi
  mov    $0x1,%edx
  mov    $0x0,%r8d
  mov    $0x0,%ecx
L10:
  mov    (%rdi,%rdx,4),%eax
  movslq %ecx,%r9
  cmp    (%rdi,%r9,4),%eax
  cmovl  %edx,%ecx
  movslq %ecx,%r9
  sub    (%rdi,%r9,4),%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L10
L11:
  mov    %r8d,%eax
  ret
L26:
  mov    $0x0,%r8d
  jmp    L11
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  if (!pricesSize || pricesSize == 1)
    return (0);
  int min, maxdiff, i, t;
  maxdiff = min = 0;
  for (i = 1; i < pricesSize; i++) {
    if (prices[i] < prices[min])
      min = i;
    t = prices[i] - prices[min];
    if (t > maxdiff)
      maxdiff = t;
  }
  return (maxdiff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<maxProfit>:
  endbr64
  cmp    $0x1,%esi
  jle    L39
  lea    -0x2(%rsi),%eax
  mov    (%rdi),%ecx
  lea    0x4(%rdi),%rdx
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,4),%rsi
  jmp    L44
  nopl   0x0(%rax)
L0:
  sub    %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  je     L42
L44:
  mov    (%rdx),%eax
  cmp    %ecx,%eax
  jge    L0
  mov    %eax,%ecx
  xor    %eax,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L44
L42:
  mov    %r8d,%eax
  ret
L39:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  if (!pricesSize || pricesSize == 1)
    return (0);
  int min, maxdiff, i, t;
  maxdiff = min = 0;
  for (i = 1; i < pricesSize; i++) {
    if (prices[i] < prices[min])
      min = i;
    t = prices[i] - prices[min];
    if (t > maxdiff)
      maxdiff = t;
  }
  return (maxdiff);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<maxProfit>:
  endbr64
  cmp    $0x1,%esi
  jle    L37
  lea    -0x2(%rsi),%eax
  mov    (%rdi),%ecx
  lea    0x4(%rdi),%rdx
  xor    %r8d,%r8d
  lea    0x8(%rdi,%rax,4),%rsi
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rdx),%eax
  cmp    %ecx,%eax
  jl     L26
  sub    %ecx,%eax
  cmp    %eax,%r8d
  cmovl  %eax,%r8d
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L1
L21:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  je     L21
  mov    %eax,%ecx
  jmp    L1
  nopl   (%rax)
L37:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maxProfit(int *prices, int pricesSize) {
  if (!pricesSize || pricesSize == 1)
    return (0);
  int min, maxdiff, i, t;
  maxdiff = min = 0;
  for (i = 1; i < pricesSize; i++) {
    if (prices[i] < prices[min])
      min = i;
    t = prices[i] - prices[min];
    if (t > maxdiff)
      maxdiff = t;
  }
  return (maxdiff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<upperstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void upperstr(char *s) {
  for (; '\0' != *s; s++)
    *s = toupper(*s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<upperstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L10:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L10
L17:
  pop    %rbx
  ret
```

assistant: ```c
void upperstr(char *s) {
  for (; '\0' != *s; s++)
    *s = toupper(*s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<upperstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L1
L9:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L1:
  pop    %rbx
  ret
```

assistant: ```c
void upperstr(char *s) {
  for (; '\0' != *s; s++)
    *s = toupper(*s);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<upperstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L19:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L5:
  pop    %rbx
  ret
```

assistant: ```c
void upperstr(char *s) {
  for (; '\0' != *s; s++)
    *s = toupper(*s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movq   $0xa,-0x10(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L3
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void f3(int i) {
  unsigned long j;
  j = 10;
  i = -1;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f3(int i) {
  unsigned long j;
  j = 10;
  i = -1;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  mov    $0xffffffff,%esi
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f3(int i) {
  unsigned long j;
  j = 10;
  i = -1;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  mov    $0xffffffff,%esi
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <free@plt>
```

assistant: ```c
void f3(int i) {
  unsigned long j;
  j = 10;
  i = -1;
  if (i < 0) {
    void *ptr = calloc(j, i);
    free(ptr);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L115
  mov    -0x4(%rbp),%eax
  jmp    L38
L115:
  cmpl   $0x0,-0x4(%rbp)
  jne    L45
  mov    -0x8(%rbp),%eax
  jmp    L38
L45:
  cmpl   $0x0,-0x8(%rbp)
  jne    L76
  mov    -0x4(%rbp),%eax
  jmp    L38
L76:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L69
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L136
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
  jmp    L38
L136:
  mov    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    %eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
  add    %eax,%eax
  jmp    L38
L69:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L67
  mov    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
  jmp    L38
L67:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L1
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
  jmp    L38
L1:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <gcd>
L38:
  leave
  ret
```

assistant: ```c
int gcd(int u, int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if (~u & 1)
    if (v & 1)
      return gcd(u >> 1, v);
    else
      return gcd(u >> 1, v >> 1) << 1;
  if (~v & 1)
    return gcd(u, v >> 1);
  if (u > v)
    return gcd((u - v) >> 1, v);
  return gcd((v - u) >> 1, u);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  je     L73
  test   %edi,%edi
  je     L73
  mov    %edi,%eax
  test   %esi,%esi
  je     L73
  sub    $0x8,%rsp
  test   $0x1,%dil
  jne    L7
  test   $0x1,%sil
  je     L14
  sar    %edi
  call   <gcd>
  jmp    L105
L14:
  sar    %esi
  sar    %edi
  call   <gcd>
  add    %eax,%eax
  jmp    L105
L7:
  test   $0x1,%sil
  je     L5
  cmp    %esi,%edi
  jg     L11
  sub    %edi,%esi
  mov    %esi,%eax
  sar    %eax
  mov    %edi,%esi
  mov    %eax,%edi
  call   <gcd>
L105:
  add    $0x8,%rsp
  ret
L5:
  sar    %esi
  call   <gcd>
  jmp    L105
L11:
  sub    %esi,%edi
  sar    %edi
  call   <gcd>
  jmp    L105
L73:
  ret
```

assistant: ```c
int gcd(int u, int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if (~u & 1)
    if (v & 1)
      return gcd(u >> 1, v);
    else
      return gcd(u >> 1, v >> 1) << 1;
  if (~v & 1)
    return gcd(u, v >> 1);
  if (u > v)
    return gcd((u - v) >> 1, v);
  return gcd((v - u) >> 1, u);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  cmp    %esi,%edi
  jne    L105
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L61:
  sar    %edi
  test   %eax,%eax
  je     L92
L17:
  cmp    %edi,%esi
  je     L66
L105:
  test   %edi,%edi
  je     L66
L84:
  test   %esi,%esi
  je     L60
  mov    %esi,%eax
  and    $0x1,%eax
  test   $0x1,%dil
  je     L61
  test   %eax,%eax
  jne    L35
  sar    %esi
  cmp    %edi,%esi
  jne    L84
L66:
  mov    %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  cmp    %esi,%edi
  jle    L18
  sub    %esi,%edi
  sar    %edi
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %esi,%eax
  mov    %edi,%esi
  sub    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  jmp    L17
  nopl   0x0(%rax)
L60:
  mov    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L92:
  sub    $0x8,%rsp
  sar    %esi
  call   <gcd>
  add    $0x8,%rsp
  add    %eax,%eax
  ret
```

assistant: ```c
int gcd(int u, int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if (~u & 1)
    if (v & 1)
      return gcd(u >> 1, v);
    else
      return gcd(u >> 1, v >> 1) << 1;
  if (~v & 1)
    return gcd(u, v >> 1);
  if (u > v)
    return gcd((u - v) >> 1, v);
  return gcd((v - u) >> 1, u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  cmp    %esi,%edi
  jne    L161
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L190:
  sar    %edi
  test   %eax,%eax
  je     L45
L157:
  cmp    %edi,%esi
  je     L214
L161:
  test   %edi,%edi
  je     L214
L99:
  test   %esi,%esi
  je     L61
  mov    %esi,%eax
  and    $0x1,%eax
  test   $0x1,%dil
  je     L190
  test   %eax,%eax
  jne    L119
  sar    %esi
  cmp    %edi,%esi
  jne    L99
L214:
  mov    %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L119:
  cmp    %esi,%edi
  jle    L121
  sub    %esi,%edi
  sar    %edi
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L121:
  mov    %esi,%eax
  mov    %edi,%esi
  sub    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  jmp    L157
  nopl   0x0(%rax)
L61:
  mov    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  sar    %esi
  cmp    %edi,%esi
  jne    L74
  jmp    L170
L244:
  sar    %edi
  test   %eax,%eax
  je     L134
L247:
  cmp    %esi,%edi
  je     L170
L74:
  test   %edi,%edi
  je     L170
L0:
  test   %esi,%esi
  je     L2
  mov    %esi,%eax
  and    $0x1,%eax
  test   $0x1,%dil
  je     L244
  test   %eax,%eax
  jne    L115
  sar    %esi
  cmp    %edi,%esi
  jne    L0
L170:
  lea    (%rsi,%rsi,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L115:
  cmp    %esi,%edi
  jle    L196
  sub    %esi,%edi
  sar    %edi
  jmp    L247
  nopw   0x0(%rax,%rax,1)
L196:
  mov    %esi,%eax
  mov    %edi,%esi
  sub    %edi,%eax
  sar    %eax
  mov    %eax,%edi
  jmp    L247
L2:
  mov    %edi,%esi
  jmp    L170
L134:
  sub    $0x8,%rsp
  sar    %esi
  call   <gcd>
  add    $0x8,%rsp
  lea    (%rax,%rax,1),%esi
  lea    (%rsi,%rsi,1),%eax
  ret
```

assistant: ```c
int gcd(int u, int v) {
  if (u == v)
    return u;
  if (u == 0)
    return v;
  if (v == 0)
    return u;
  if (~u & 1)
    if (v & 1)
      return gcd(u >> 1, v);
    else
      return gcd(u >> 1, v >> 1) << 1;
  if (~v & 1)
    return gcd(u, v >> 1);
  if (u > v)
    return gcd((u - v) >> 1, v);
  return gcd((v - u) >> 1, u);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ConvertTempoToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x17(%rbp)
  movl   $0x0,-0xf(%rbp)
  movw   $0x0,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  movsd  -0x38(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  seta   %al
  xor    $0x1,%eax
  test   %al,%al
  jne    L104
  movsd  D1(%rip),%xmm0
  comisd -0x38(%rbp),%xmm0
  seta   %al
  xor    $0x1,%eax
  test   %al,%al
  je     L12
L104:
  mov    $0x0,%eax
  jmp    L74
L12:
  mov    -0x38(%rbp),%rdx
  lea    -0x17(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D6(%rip),%rdx
  mov    $0xe,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  test   %rax,%rax
  jns    L133
  mov    $0x0,%eax
  jmp    L74
L133:
  movl   $0x0,-0x24(%rbp)
  jmp    L40
L90:
  mov    -0x24(%rbp),%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  cmp    $0x2e,%al
  jne    L128
  mov    -0x24(%rbp),%eax
  movb   $0x2c,-0x17(%rbp,%rax,1)
L128:
  addl   $0x1,-0x24(%rbp)
L40:
  mov    -0x24(%rbp),%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L90
  movl   $0x0,-0x24(%rbp)
  jmp    L69
L65:
  mov    -0x24(%rbp),%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  cmp    $0x2c,%al
  jne    L86
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  test   %al,%al
  je     L86
  mov    -0x24(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  test   %al,%al
  je     L86
  mov    -0x24(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,%eax
  movb   $0x0,-0x17(%rbp,%rax,1)
L86:
  addl   $0x1,-0x24(%rbp)
L69:
  mov    -0x24(%rbp),%eax
  movzbl -0x17(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L65
  lea    -0x17(%rbp),%rax
  mov    %rax,%rdi
  call   <DuplicateString@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
L74:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L122
  call   <__stack_chk_fail@plt>
L122:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: f64
name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D1: 1000

tool: D6: %.6f

assistant: ```c
char *ConvertTempoToString(double tempo) {
  char string[15] = {0};
  char *temp = NULL;
  unsigned ctr = 0;
  if (!(tempo > 0.0) || !(tempo < 1000.0))
    return NULL;
  if (snprintf(string, sizeof(string) - 1, "%.6f", tempo) < 0)
    return NULL;
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if (string[ctr] == '.')
      string[ctr] = ',';
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if ((string[ctr] == ',') && (string[ctr + 1] != '\0') && (string[ctr + 2] != '\0'))
      string[ctr + 3] = '\0';
  temp = DuplicateString(string);
  return temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ConvertTempoToString>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x9(%rsp)
  movl   $0x0,0x11(%rsp)
  movw   $0x0,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  comisd D18(%rip),%xmm0
  jbe    L72
  movsd  D0(%rip),%xmm1
  mov    $0x0,%eax
  comisd %xmm0,%xmm1
  jbe    L3
  lea    0x9(%rsp),%rdi
  lea    D1(%rip),%rdx
  mov    $0xe,%esi
  call   <snprintf@plt>
  test   %rax,%rax
  js     L51
  movzbl 0x9(%rsp),%edx
  test   %dl,%dl
  je     L49
  lea    0x9(%rsp),%rax
  jmp    L69
L116:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L10
L69:
  cmp    $0x2e,%dl
  jne    L116
  movb   $0x2c,(%rax)
  jmp    L116
L10:
  movzbl 0x9(%rsp),%edx
  test   %dl,%dl
  je     L49
  lea    0xa(%rsp),%rax
  jmp    L179
L97:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L49
L77:
  add    $0x1,%rax
L179:
  cmp    $0x2c,%dl
  jne    L97
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L49
  cmpb   $0x0,0x1(%rax)
  je     L77
  movb   $0x0,0x2(%rax)
  jmp    L77
L49:
  lea    0x9(%rsp),%rdi
  call   <DuplicateString@plt>
L3:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x28,%rsp
  ret
L72:
  mov    $0x0,%eax
  jmp    L3
L51:
  mov    $0x0,%eax
  jmp    L3
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
data_type: f64[2]
name: extract_symbolic_data
arguments: label: D0
data_type: f64
name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: {"D18": [0.0,1000.0]}

tool: D0: 1000

tool: D1: %.6f

assistant: ```c
char *ConvertTempoToString(double tempo) {
  char string[15] = {0};
  char *temp = NULL;
  unsigned ctr = 0;
  if (!(tempo > 0.0) || !(tempo < 1000.0))
    return NULL;
  if (snprintf(string, sizeof(string) - 1, "%.6f", tempo) < 0)
    return NULL;
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if (string[ctr] == '.')
      string[ctr] = ',';
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if ((string[ctr] == ',') && (string[ctr + 1] != '\0') && (string[ctr + 2] != '\0'))
      string[ctr + 3] = '\0';
  temp = DuplicateString(string);
  return temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ConvertTempoToString>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  comisd D19(%rip),%xmm0
  movq   $0x0,0x9(%rsp)
  movl   $0x0,0x11(%rsp)
  mov    %ax,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  jbe    L104
  movsd  D9(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L104
  lea    0x9(%rsp),%rbp
  lea    D2(%rip),%rdx
  mov    $0xe,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  test   %rax,%rax
  js     L104
  movzbl 0x9(%rsp),%edx
  test   %dl,%dl
  je     L53
  mov    %rbp,%rax
L45:
  cmp    $0x2e,%dl
  jne    L135
  movb   $0x2c,(%rax)
L135:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L45
  movzbl 0x9(%rsp),%ecx
  test   %cl,%cl
  je     L53
  lea    0xa(%rsp),%rax
  jmp    L10
  nopl   0x0(%rax)
L28:
  test   %dl,%dl
  je     L53
L98:
  add    $0x1,%rax
  mov    %edx,%ecx
L10:
  movzbl (%rax),%edx
  cmp    $0x2c,%cl
  jne    L28
  test   %dl,%dl
  je     L53
  cmpb   $0x0,0x1(%rax)
  je     L98
  movb   $0x0,0x2(%rax)
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %rbp,%rdi
  call   <DuplicateString@plt>
L87:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbp
  ret
  xchg   %ax,%ax
L104:
  xor    %eax,%eax
  jmp    L87
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
data_type: f64[2]
name: disassemble_data
arguments: label: D9
data_type: f64
name: disassemble_data
arguments: label: D2
data_type: string

tool: {"D19": [0.0,1000.0]}

tool: D9: 1000

tool: D2: %.6f

assistant: ```c
char *ConvertTempoToString(double tempo) {
  char string[15] = {0};
  char *temp = NULL;
  unsigned ctr = 0;
  if (!(tempo > 0.0) || !(tempo < 1000.0))
    return NULL;
  if (snprintf(string, sizeof(string) - 1, "%.6f", tempo) < 0)
    return NULL;
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if (string[ctr] == '.')
      string[ctr] = ',';
  for (ctr = 0; string[ctr] != '\0'; ctr++)
    if ((string[ctr] == ',') && (string[ctr + 1] != '\0') && (string[ctr + 2] != '\0'))
      string[ctr + 3] = '\0';
  temp = DuplicateString(string);
  return temp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L45
L18:
  mov    -0x18(%rbp),%rax
  jmp    L22
L45:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L37:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L37
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L37
  mov    -0x8(%rbp),%rax
L22:
  pop    %rbp
  ret
```

assistant: ```c
char *_ltrim(char *pStr) {
  char *p;
  if ((pStr == (0)) || (*pStr == 0)) {
    return pStr;
  }
  p = pStr;
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ltrim>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L39
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L39
  cmp    $0x20,%dl
  je     L7
  cmp    $0x9,%dl
  jne    L39
L7:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L7
  cmp    $0x9,%dl
  je     L7
L39:
  ret
```

assistant: ```c
char *_ltrim(char *pStr) {
  char *p;
  if ((pStr == (0)) || (*pStr == 0)) {
    return pStr;
  }
  p = pStr;
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```