ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %s [EAL options] -- -p PORTMASK -P  [--config (port,queue,lcore)[,(port,queue,lcore]]  -p PORTMASK: hexadecimal bitmask of ports to configure
  -P : enable promiscuous mode
  --config (port,queue,lcore): rx queues configuration
  --no-numa: optional, disable numa awareness
 which max packet len is PKTLEN in decimal (64-9600)
  --hash-entry-num: specify the hash entry number in hexadecimal to be setup


assistant: ```c
void print_usage(const char *prgname) {
  printf("%s [EAL options] -- -p PORTMASK -P"
         "  [--config (port,queue,lcore)[,(port,queue,lcore]]"
         "  -p PORTMASK: hexadecimal bitmask of ports to configure\n"
         "  -P : enable promiscuous mode\n"
         "  --config (port,queue,lcore): rx queues configuration\n"
         "  --no-numa: optional, disable numa awareness\n"
         " which max packet len is PKTLEN in decimal (64-9600)\n"
         "  --hash-entry-num: specify the hash entry number in hexadecimal to be setup\n",
         prgname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<om_sysfs_swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <om_sysfs_path@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L14
L1:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <om_sysfs_writefile@plt>
  test   %rax,%rax
  je     L12
  mov    $0x0,%eax
  jmp    L14
L12:
  mov    -0x8(%rbp),%rax
L14:
  leave
  ret
```

assistant: ```c
const char *om_sysfs_swap(const char *name, const char *val) {
  const char *path = om_sysfs_path(name);
  const char *res = NULL;
  if (path == NULL)
    return NULL;
  res = om_sysfs_readfile(path);
  if (om_sysfs_writefile(path, val) != 0)
    return NULL;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<om_sysfs_swap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  call   <om_sysfs_path@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <om_sysfs_writefile@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%rbp
L18:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rax,%rbp
  jmp    L18
```

assistant: ```c
const char *om_sysfs_swap(const char *name, const char *val) {
  const char *path = om_sysfs_path(name);
  const char *res = NULL;
  if (path == NULL)
    return NULL;
  res = om_sysfs_readfile(path);
  if (om_sysfs_writefile(path, val) != 0)
    return NULL;
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<om_sysfs_swap>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <om_sysfs_path@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <om_sysfs_writefile@plt>
  test   %rax,%rax
  jne    L2
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
const char *om_sysfs_swap(const char *name, const char *val) {
  const char *path = om_sysfs_path(name);
  const char *res = NULL;
  if (path == NULL)
    return NULL;
  res = om_sysfs_readfile(path);
  if (om_sysfs_writefile(path, val) != 0)
    return NULL;
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<om_sysfs_swap>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  call   <om_sysfs_path@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <om_sysfs_readfile@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <om_sysfs_writefile@plt>
  test   %rax,%rax
  jne    L18
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  xor    %r13d,%r13d
  pop    %rbp
  pop    %r12
  mov    %r13,%rax
  pop    %r13
  ret
```

assistant: ```c
const char *om_sysfs_swap(const char *name, const char *val) {
  const char *path = om_sysfs_path(name);
  const char *res = NULL;
  if (path == NULL)
    return NULL;
  res = om_sysfs_readfile(path);
  if (om_sysfs_writefile(path, val) != 0)
    return NULL;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_uint16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_uint16(uint16_t *x) {
  char n = ((char *)x)[0];
  ((char *)x)[0] = ((char *)x)[1];
  ((char *)x)[1] = n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap_uint16>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  mov    %dl,(%rdi)
  mov    %al,0x1(%rdi)
  ret
```

assistant: ```c
void swap_uint16(uint16_t *x) {
  char n = ((char *)x)[0];
  ((char *)x)[0] = ((char *)x)[1];
  ((char *)x)[1] = n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_uint16>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void swap_uint16(uint16_t *x) {
  char n = ((char *)x)[0];
  ((char *)x)[0] = ((char *)x)[1];
  ((char *)x)[1] = n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap_uint16>:
  endbr64
  rolw   $0x8,(%rdi)
  ret
```

assistant: ```c
void swap_uint16(uint16_t *x) {
  char n = ((char *)x)[0];
  ((char *)x)[0] = ((char *)x)[1];
  ((char *)x)[1] = n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skipEverything>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L74
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L40
L74:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <skipString@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L69
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isIdentifierFirstCharacter@plt>
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  jmp    L51
L13:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  jmp    L67
L69:
  nop
L67:
  mov    -0x8(%rbp),%rax
L51:
  leave
  ret
```

assistant: ```c
const char *skipEverything(const char *cp) {
  for (; *cp; cp++) {
    if (*cp == '"' || *cp == '\'') {
      cp = skipString(cp);
      if (!*cp)
        break;
    }
    if (isIdentifierFirstCharacter((int)*cp))
      return cp;
  }
  return cp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipEverything>:
  endbr64
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L25
  mov    %rdi,%rbx
  jmp    L44
L77:
  call   <skipString@plt>
  mov    %rax,%rbx
  cmpb   $0x0,(%rax)
  je     L44
L61:
  movsbl (%rbx),%edi
  call   <isIdentifierFirstCharacter@plt>
  test   %rax,%rax
  jne    L44
  lea    0x1(%rbx),%rdi
  movzbl 0x1(%rbx),%eax
  test   %al,%al
  je     L17
L25:
  cmp    $0x22,%al
  je     L77
  mov    %rdi,%rbx
  cmp    $0x27,%al
  jne    L61
  jmp    L77
L17:
  mov    %rdi,%rbx
L44:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *skipEverything(const char *cp) {
  for (; *cp; cp++) {
    if (*cp == '"' || *cp == '\'') {
      cp = skipString(cp);
      if (!*cp)
        break;
    }
    if (isIdentifierFirstCharacter((int)*cp))
      return cp;
  }
  return cp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skipEverything>:
  endbr64
  push   %r12
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  jne    L56
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L47:
  movsbl (%r8),%edi
  mov    %r8,%r12
L69:
  call   <isIdentifierFirstCharacter@plt>
  test   %rax,%rax
  jne    L26
  movzbl 0x1(%r12),%eax
  lea    0x1(%r12),%r8
  test   %al,%al
  je     L63
L56:
  cmp    $0x22,%al
  je     L1
  cmp    $0x27,%al
  jne    L47
L1:
  mov    %r8,%rdi
  call   <skipString@plt>
  movsbl (%rax),%edi
  mov    %rax,%r12
  test   %dil,%dil
  jne    L69
L26:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L63:
  mov    %r8,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skipEverything(const char *cp) {
  for (; *cp; cp++) {
    if (*cp == '"' || *cp == '\'') {
      cp = skipString(cp);
      if (!*cp)
        break;
    }
    if (isIdentifierFirstCharacter((int)*cp))
      return cp;
  }
  return cp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipEverything>:
  endbr64
  push   %r12
  mov    %rdi,%r8
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L20
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L58:
  call   <isIdentifierFirstCharacter@plt>
  test   %rax,%rax
  jne    L2
  movsbl 0x1(%r12),%edi
  lea    0x1(%r12),%r8
  test   %dil,%dil
  je     L8
L20:
  cmp    $0x22,%dil
  je     L37
  mov    %r8,%r12
  cmp    $0x27,%dil
  jne    L58
L37:
  mov    %r8,%rdi
  call   <skipString@plt>
  movsbl (%rax),%edi
  mov    %rax,%r12
  test   %dil,%dil
  jne    L58
L2:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r8,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *skipEverything(const char *cp) {
  for (; *cp; cp++) {
    if (*cp == '"' || *cp == '\'') {
      cp = skipString(cp);
      if (!*cp)
        break;
    }
    if (isIdentifierFirstCharacter((int)*cp))
      return cp;
  }
  return cp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<header_get_field>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <my_stristr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *header_get_field(char *header, char *field) {
  char *t = my_stristr(header, field);
  if (!t && (strncasecmp(header, field + 1, strlen(field) - 1) == 0))
    t = header;
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<header_get_field>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <my_stristr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L19
L8:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rdx
  lea    0x1(%rbp),%rsi
  mov    %r12,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  cmove  %r12,%rbx
  jmp    L8
```

assistant: ```c
char *header_get_field(char *header, char *field) {
  char *t = my_stristr(header, field);
  if (!t && (strncasecmp(header, field + 1, strlen(field) - 1) == 0))
    t = header;
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<header_get_field>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <my_stristr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  lea    -0x1(%rax),%rdx
  call   <strncasecmp@plt>
  pop    %rbx
  test   %rax,%rax
  cmove  %rbp,%r12
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *header_get_field(char *header, char *field) {
  char *t = my_stristr(header, field);
  if (!t && (strncasecmp(header, field + 1, strlen(field) - 1) == 0))
    t = header;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<header_get_field>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <my_stristr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rdi
  lea    -0x1(%rax),%rdx
  call   <strncasecmp@plt>
  pop    %rbx
  test   %rax,%rax
  cmove  %rbp,%r12
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *header_get_field(char *header, char *field) {
  char *t = my_stristr(header, field);
  if (!t && (strncasecmp(header, field + 1, strlen(field) - 1) == 0))
    t = header;
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cris_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L64
L63:
  shlq   -0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L64:
  mov    -0x18(%rbp),%rax
  and    $0xffffffff80000000,%rax
  test   %rax,%rax
  je     L63
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L137
L104:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xffffffff80000000,%rax
  test   %rax,%rax
  jne    L94
  jmp    L26
L113:
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  shlq   -0x18(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xffffffff80000000,%rax
  test   %rax,%rax
  jne    L48
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L65
L26:
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L113
  jmp    L35
L48:
  nop
  jmp    L35
L65:
  nop
L35:
  subq   $0x1,-0x8(%rbp)
L137:
  cmpq   $0x2,-0x8(%rbp)
  ja     L104
  jmp    L39
L94:
  nop
  jmp    L39
L23:
  mov    -0x30(%rbp),%rax
  sub    %rax,-0x28(%rbp)
L39:
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L23
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long cris_mod(unsigned long m, unsigned long p) {
  unsigned long i, t, inc;
  i = p;
  t = 0;
  while (!(i & (1 << 31))) {
    i <<= 1;
    t++;
  }
  t--;
  for (inc = t; inc > 2; inc--) {
    i = p << inc;
    if (i & (1 << 31))
      break;
    while (m >= i) {
      m -= i;
      i <<= 1;
      if (i & (1 << 31))
        break;
      if (i < p)
        break;
    }
  }
  while (m >= p)
    m -= p;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cris_mod>:
  endbr64
  mov    %rsi,%rax
  and    $0xffffffff80000000,%rax
  jne    L80
  mov    %rsi,%rdx
L102:
  add    %rdx,%rdx
  mov    %rax,%rcx
  add    $0x1,%rax
  test   $0xffffffff80000000,%rdx
  je     L102
  cmp    $0x2,%rcx
  jbe    L113
L124:
  mov    %rsi,%rax
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  je     L100
L113:
  cmp    %rdi,%rsi
  ja     L81
L84:
  sub    %rsi,%rdi
  cmp    %rdi,%rsi
  jbe    L84
L81:
  mov    %rdi,%rax
  ret
L80:
  mov    $0xffffffffffffffff,%rcx
  jmp    L124
L78:
  sub    $0x1,%rcx
  cmp    $0x2,%rcx
  jbe    L113
  mov    %rsi,%rax
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  jne    L113
L100:
  cmp    %rax,%rdi
  jb     L78
  sub    %rax,%rdi
  add    %rax,%rax
  test   $0xffffffff80000000,%rax
  jne    L78
  cmp    %rax,%rsi
  jbe    L100
  jmp    L78
```

assistant: ```c
unsigned long cris_mod(unsigned long m, unsigned long p) {
  unsigned long i, t, inc;
  i = p;
  t = 0;
  while (!(i & (1 << 31))) {
    i <<= 1;
    t++;
  }
  t--;
  for (inc = t; inc > 2; inc--) {
    i = p << inc;
    if (i & (1 << 31))
      break;
    while (m >= i) {
      m -= i;
      i <<= 1;
      if (i & (1 << 31))
        break;
      if (i < p)
        break;
    }
  }
  while (m >= p)
    m -= p;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cris_mod>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  and    $0xffffffff80000000,%rcx
  jne    L120
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L60:
  add    %rax,%rax
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  test   $0xffffffff80000000,%rax
  je     L60
  cmp    $0x2,%rdx
  jbe    L18
  mov    %edx,%ecx
L99:
  mov    %rsi,%rax
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  je     L17
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L97:
  sub    %rax,%r8
  add    %rax,%rax
  test   $0xffffffff80000000,%rax
  jne    L12
  cmp    %rax,%rsi
  ja     L12
L17:
  cmp    %rax,%r8
  jae    L97
L12:
  sub    $0x1,%rdx
  cmp    $0x2,%rdx
  je     L18
  mov    %rsi,%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  je     L17
  cmp    %r8,%rsi
  ja     L91
  nopw   0x0(%rax,%rax,1)
L62:
  sub    %rsi,%r8
L18:
  cmp    %r8,%rsi
  jbe    L62
L91:
  mov    %r8,%rax
  ret
L120:
  mov    $0xffffffff,%ecx
  mov    $0xffffffffffffffff,%rdx
  jmp    L99
```

assistant: ```c
unsigned long cris_mod(unsigned long m, unsigned long p) {
  unsigned long i, t, inc;
  i = p;
  t = 0;
  while (!(i & (1 << 31))) {
    i <<= 1;
    t++;
  }
  t--;
  for (inc = t; inc > 2; inc--) {
    i = p << inc;
    if (i & (1 << 31))
      break;
    while (m >= i) {
      m -= i;
      i <<= 1;
      if (i & (1 << 31))
        break;
      if (i < p)
        break;
    }
  }
  while (m >= p)
    m -= p;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cris_mod>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  and    $0xffffffff80000000,%rcx
  jne    L20
  mov    %rsi,%rax
  nopw   0x0(%rax,%rax,1)
L78:
  add    %rax,%rax
  mov    %rcx,%rdx
  lea    0x1(%rcx),%rcx
  test   $0xffffffff80000000,%rax
  je     L78
  cmp    $0x2,%rdx
  jbe    L115
  mov    %edx,%ecx
L42:
  mov    %rsi,%rax
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  je     L18
  jmp    L115
  nopw   0x0(%rax,%rax,1)
L103:
  sub    %rax,%r8
  add    %rax,%rax
  test   $0xffffffff80000000,%rax
  jne    L60
  cmp    %rax,%rsi
  ja     L60
L18:
  cmp    %rax,%r8
  jae    L103
L60:
  sub    $0x1,%rdx
  cmp    $0x2,%rdx
  je     L115
  mov    %rsi,%rax
  mov    %edx,%ecx
  shl    %cl,%rax
  test   $0xffffffff80000000,%rax
  je     L18
  cmp    %r8,%rsi
  ja     L17
  nopw   0x0(%rax,%rax,1)
L104:
  sub    %rsi,%r8
L115:
  cmp    %r8,%rsi
  jbe    L104
L17:
  mov    %r8,%rax
  ret
L20:
  mov    $0xffffffff,%ecx
  mov    $0xffffffffffffffff,%rdx
  jmp    L42
```

assistant: ```c
unsigned long cris_mod(unsigned long m, unsigned long p) {
  unsigned long i, t, inc;
  i = p;
  t = 0;
  while (!(i & (1 << 31))) {
    i <<= 1;
    t++;
  }
  t--;
  for (inc = t; inc > 2; inc--) {
    i = p << inc;
    if (i & (1 << 31))
      break;
    while (m >= i) {
      m -= i;
      i <<= 1;
      if (i & (1 << 31))
        break;
      if (i < p)
        break;
    }
  }
  while (m >= p)
    m -= p;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L36
L38:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    $0xffffffff,%eax
  jmp    L37
L7:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L36:
  cmpl   $0x0,-0x8(%rbp)
  jne    L38
  mov    -0x18(%rbp),%eax
L37:
  leave
  ret
```

assistant: ```c
int write_all(int fd, const char *buf, int len) {
  int left = len;
  int written;
  while (left) {
    written = write(fd, buf, left);
    if (written < 0) {
      return -1;
    }
    left -= written;
    buf += written;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<write_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  je     L17
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L10:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  js     L16
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L10
  jmp    L17
L16:
  mov    $0xffffffff,%r13d
L17:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_all(int fd, const char *buf, int len) {
  int left = len;
  int written;
  while (left) {
    written = write(fd, buf, left);
    if (written < 0) {
      return -1;
    }
    left -= written;
    buf += written;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_all>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L28
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L9
  nop
L35:
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L28
L9:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L35
  mov    $0xffffffff,%r13d
L28:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_all(int fd, const char *buf, int len) {
  int left = len;
  int written;
  while (left) {
    written = write(fd, buf, left);
    if (written < 0) {
      return -1;
    }
    left -= written;
    buf += written;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_all>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L18
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L12
  nop
L35:
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L18
L12:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L35
  mov    $0xffffffff,%r13d
L18:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_all(int fd, const char *buf, int len) {
  int left = len;
  int written;
  while (left) {
    written = write(fd, buf, left);
    if (written < 0) {
      return -1;
    }
    left -= written;
    buf += written;
  }
  return len;
}
```