user: 这段汇编代码用C语言表示是什么样的?

```asm
<solve_LatLonAlt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  mov    %rdi,-0x50(%rbp)
  mov    %rsi,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  movl   $0x64,-0x2c(%rbp)
  movsd  D40(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D3(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  mov    -0x40(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <atan2@plt>
  addsd  %xmm0,%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  D31(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movq   %xmm0,%rax
  mov    -0x50(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x60(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  jmp    L25
L29:
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  D31(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  subsd  -0x8(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm1
  movapd %xmm1,%xmm2
  addsd  -0x8(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D31(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x18(%rbp),%xmm1
  movsd  -0x48(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movq   %xmm0,%rax
  mov    -0x50(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x60(%rbp),%rax
  movsd  (%rax),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L30
  subl   $0x1,-0x2c(%rbp)
L25:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L29
  jmp    L2
L30:
  nop
L2:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D40
type_guessed: f64
name: unpack_data
arguments: data_tag: D3
type_guessed: f64
name: unpack_data
arguments: data_tag: D31
type_guessed: f64

tool: D40: 6378137

tool: D3: 0.00669437999014132

tool: D31: 1

assistant: ```c
void solve_LatLonAlt(double x_n, double y_n, double z_n, double *lat, double *lon, double *alt) {
  int iterations = 100;
  const double a = (6378137.0);
  const double e2 = (0.00669437999014132);
  const double p = sqrt(x_n * x_n + y_n * y_n);
  *lon = 2.0 * atan2(y_n, x_n + p);
  *lat = atan(z_n / (p * (1.0 - e2)));
  *alt = 0.0;
  while (iterations > 0) {
    double tmp = *alt;
    double N = a / sqrt(1.0 - e2 * pow(sin(*lat), 2));
    *alt = p / cos(*lat) - N;
    *lat = atan(z_n / (p * (1.0 - e2 * N / (N + *alt))));
    if (fabs(*alt - tmp) < 1e-3)
      break;
    iterations--;
  }
}
```