ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D80
type_infered: string
name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D82
type_infered: string
name: read_data
arguments: label: D71
type_infered: string
name: read_data
arguments: label: D72
type_infered: string

tool: D32: fibonacci of 0 is %llu


tool: D35: fibonacci of 1 is %llu


tool: D80: fibonacci of 2 is %llu


tool: D15: fibonacci of 3 is %llu


tool: D44: fibonacci of 4 is %llu


tool: D28: fibonacci of 5 is %llu


tool: D14: fibonacci of 6 is %llu


tool: D82: fibonacci of 10 is %llu


tool: D71: fibonacci of 20 is %llu


tool: D72: fibonacci of 30 is %llu


assistant: ```c
int main() {
  printf("fibonacci of 0 is %llu\n", fibonacci(0));
  printf("fibonacci of 1 is %llu\n", fibonacci(1));
  printf("fibonacci of 2 is %llu\n", fibonacci(2));
  printf("fibonacci of 3 is %llu\n", fibonacci(3));
  printf("fibonacci of 4 is %llu\n", fibonacci(4));
  printf("fibonacci of 5 is %llu\n", fibonacci(5));
  printf("fibonacci of 6 is %llu\n", fibonacci(6));
  printf("fibonacci of 10 is %llu\n", fibonacci(10));
  printf("fibonacci of 20 is %llu\n", fibonacci(20));
  printf("fibonacci of 30 is %llu\n", fibonacci(30));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D63(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D88(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D51(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <fibonacci@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D63
datatype: string
name: unpack_data
arguments: data_tag: D44
datatype: string
name: unpack_data
arguments: data_tag: D88
datatype: string
name: unpack_data
arguments: data_tag: D51
datatype: string
name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D72
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D63: fibonacci of 0 is %llu


tool: D44: fibonacci of 1 is %llu


tool: D88: fibonacci of 2 is %llu


tool: D51: fibonacci of 3 is %llu


tool: D23: fibonacci of 4 is %llu


tool: D0: fibonacci of 5 is %llu


tool: D72: fibonacci of 6 is %llu


tool: D17: fibonacci of 10 is %llu


tool: D5: fibonacci of 20 is %llu


tool: D9: fibonacci of 30 is %llu


assistant: ```c
int main() {
  printf("fibonacci of 0 is %llu\n", fibonacci(0));
  printf("fibonacci of 1 is %llu\n", fibonacci(1));
  printf("fibonacci of 2 is %llu\n", fibonacci(2));
  printf("fibonacci of 3 is %llu\n", fibonacci(3));
  printf("fibonacci of 4 is %llu\n", fibonacci(4));
  printf("fibonacci of 5 is %llu\n", fibonacci(5));
  printf("fibonacci of 6 is %llu\n", fibonacci(6));
  printf("fibonacci of 10 is %llu\n", fibonacci(10));
  printf("fibonacci of 20 is %llu\n", fibonacci(20));
  printf("fibonacci of 30 is %llu\n", fibonacci(30));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <fibonacci@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <fibonacci@plt>
  lea    D58(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <fibonacci@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <fibonacci@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <fibonacci@plt>
  lea    D52(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <fibonacci@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <fibonacci@plt>
  lea    D82(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <fibonacci@plt>
  lea    D62(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <fibonacci@plt>
  lea    D27(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <fibonacci@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
type_guessed: string
name: parse_data
arguments: tag: D58
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D82
type_guessed: string
name: parse_data
arguments: tag: D62
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string

tool: D15: fibonacci of 0 is %llu


tool: D58: fibonacci of 1 is %llu


tool: D6: fibonacci of 2 is %llu


tool: D1: fibonacci of 3 is %llu


tool: D52: fibonacci of 4 is %llu


tool: D22: fibonacci of 5 is %llu


tool: D82: fibonacci of 6 is %llu


tool: D62: fibonacci of 10 is %llu


tool: D27: fibonacci of 20 is %llu


tool: D20: fibonacci of 30 is %llu


assistant: ```c
int main() {
  printf("fibonacci of 0 is %llu\n", fibonacci(0));
  printf("fibonacci of 1 is %llu\n", fibonacci(1));
  printf("fibonacci of 2 is %llu\n", fibonacci(2));
  printf("fibonacci of 3 is %llu\n", fibonacci(3));
  printf("fibonacci of 4 is %llu\n", fibonacci(4));
  printf("fibonacci of 5 is %llu\n", fibonacci(5));
  printf("fibonacci of 6 is %llu\n", fibonacci(6));
  printf("fibonacci of 10 is %llu\n", fibonacci(10));
  printf("fibonacci of 20 is %llu\n", fibonacci(20));
  printf("fibonacci of 30 is %llu\n", fibonacci(30));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <fibonacci@plt>
  lea    D51(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <fibonacci@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <fibonacci@plt>
  lea    D91(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <fibonacci@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x4,%edi
  call   <fibonacci@plt>
  lea    D77(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x5,%edi
  call   <fibonacci@plt>
  lea    D60(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x6,%edi
  call   <fibonacci@plt>
  lea    D43(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <fibonacci@plt>
  lea    D36(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x14,%edi
  call   <fibonacci@plt>
  lea    D25(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x1e,%edi
  call   <fibonacci@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D51
type: string
name: disassemble_data
arguments: label: D32
type: string
name: disassemble_data
arguments: label: D91
type: string
name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D77
type: string
name: disassemble_data
arguments: label: D60
type: string
name: disassemble_data
arguments: label: D43
type: string
name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D12
type: string

tool: D51: fibonacci of 0 is %llu


tool: D32: fibonacci of 1 is %llu


tool: D91: fibonacci of 2 is %llu


tool: D17: fibonacci of 3 is %llu


tool: D77: fibonacci of 4 is %llu


tool: D60: fibonacci of 5 is %llu


tool: D43: fibonacci of 6 is %llu


tool: D36: fibonacci of 10 is %llu


tool: D25: fibonacci of 20 is %llu


tool: D12: fibonacci of 30 is %llu


assistant: ```c
int main() {
  printf("fibonacci of 0 is %llu\n", fibonacci(0));
  printf("fibonacci of 1 is %llu\n", fibonacci(1));
  printf("fibonacci of 2 is %llu\n", fibonacci(2));
  printf("fibonacci of 3 is %llu\n", fibonacci(3));
  printf("fibonacci of 4 is %llu\n", fibonacci(4));
  printf("fibonacci of 5 is %llu\n", fibonacci(5));
  printf("fibonacci of 6 is %llu\n", fibonacci(6));
  printf("fibonacci of 10 is %llu\n", fibonacci(10));
  printf("fibonacci of 20 is %llu\n", fibonacci(20));
  printf("fibonacci of 30 is %llu\n", fibonacci(30));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculate_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L6
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t calculate_sum(char *word) {
  uint32_t sum = 0;
  while (*word) {
    sum += *word;
    word++;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculate_sum>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  mov    $0x0,%edx
L7:
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L20:
  mov    %edx,%eax
  ret
L9:
  mov    %eax,%edx
  jmp    L20
```

assistant: ```c
uint32_t calculate_sum(char *word) {
  uint32_t sum = 0;
  while (*word) {
    sum += *word;
    word++;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculate_sum>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L5
  xchg   %ax,%ax
L1:
  add    $0x1,%rdi
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L1
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t calculate_sum(char *word) {
  uint32_t sum = 0;
  while (*word) {
    sum += *word;
    word++;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<calculate_sum>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L6
  xchg   %ax,%ax
L4:
  add    $0x1,%rdi
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t calculate_sum(char *word) {
  uint32_t sum = 0;
  while (*word) {
    sum += *word;
    word++;
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x4,-0x10(%rbp)
  jmp    L28
L25:
  mov    -0x10(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  mov    %dl,-0xc(%rbp,%rax,1)
  subl   $0x1,-0x10(%rbp)
L28:
  cmpl   $0x0,-0x10(%rbp)
  jns    L25
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %s


assistant: ```c
int main(int argc, char **argv) {
  char buf[4];
  int i;
  memset(buf, 0, sizeof(buf));
  for (i = sizeof(buf); i >= 0; i--) {
    buf[i] = '0' + i;
  }
  printf("%s\n", buf);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movb   $0x34,0x8(%rsp)
  movb   $0x33,0x7(%rsp)
  movb   $0x32,0x6(%rsp)
  movb   $0x31,0x5(%rsp)
  movb   $0x30,0x4(%rsp)
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %s


assistant: ```c
int main(int argc, char **argv) {
  char buf[4];
  int i;
  memset(buf, 0, sizeof(buf));
  for (i = sizeof(buf); i >= 0; i--) {
    buf[i] = '0' + i;
  }
  printf("%s\n", buf);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  movb   $0x34,0x8(%rsp)
  lea    D7(%rip),%rdi
  movl   $0x33323130,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: %s


assistant: ```c
int main(int argc, char **argv) {
  char buf[4];
  int i;
  memset(buf, 0, sizeof(buf));
  for (i = sizeof(buf); i >= 0; i--) {
    buf[i] = '0' + i;
  }
  printf("%s\n", buf);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  mov    $0x4,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  movl   $0x33323130,0x4(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: %s


assistant: ```c
int main(int argc, char **argv) {
  char buf[4];
  int i;
  memset(buf, 0, sizeof(buf));
  for (i = sizeof(buf); i >= 0; i--) {
    buf[i] = '0' + i;
  }
  printf("%s\n", buf);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L1
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L25
L1:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <kill@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L39
L37:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    $0x0,%eax
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D8
type: string
name: retrieve_data
arguments: data_label: D16
type: string

tool: D2: Wrong Number of Arguments

tool: D8: Successfully killed %d


tool: D16: %d : No such process


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    printf("Wrong Number of Arguments\n");
    return 0;
  }
  int pid = atoi(argv[2]);
  if (!kill(pid))
    printf("Successfully killed %d\n", pid);
  else
    printf("%d : No such process\n", pid);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x3,%edi
  je     L27
  lea    D26(%rip),%rdi
  call   <puts@plt>
L16:
  mov    $0x0,%eax
  pop    %rbx
  ret
L27:
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <kill@plt>
  test   %eax,%eax
  jne    L8
  mov    %ebx,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L8:
  mov    %ebx,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: read_data
arguments: label: D26
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string

tool: D26: Wrong Number of Arguments

tool: D17: Successfully killed %d


tool: D21: %d : No such process


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    printf("Wrong Number of Arguments\n");
    return 0;
  }
  int pid = atoi(argv[2]);
  if (!kill(pid))
    printf("Successfully killed %d\n", pid);
  else
    printf("%d : No such process\n", pid);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x3,%edi
  je     L16
  lea    D6(%rip),%rdi
  call   <puts@plt>
L12:
  xor    %eax,%eax
  pop    %rbp
  ret
L16:
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <kill@plt>
  mov    %ebp,%esi
  test   %eax,%eax
  jne    L29
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L29:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string

tool: D6: Wrong Number of Arguments

tool: D8: Successfully killed %d


tool: D14: %d : No such process


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    printf("Wrong Number of Arguments\n");
    return 0;
  }
  int pid = atoi(argv[2]);
  if (!kill(pid))
    printf("Successfully killed %d\n", pid);
  else
    printf("%d : No such process\n", pid);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x3,%edi
  je     L7
  lea    D1(%rip),%rdi
  call   <puts@plt>
L1:
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <kill@plt>
  mov    %ebp,%esi
  test   %eax,%eax
  jne    L34
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L34:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D1: Wrong Number of Arguments

tool: D20: Successfully killed %d


tool: D4: %d : No such process


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 3) {
    printf("Wrong Number of Arguments\n");
    return 0;
  }
  int pid = atoi(argv[2]);
  if (!kill(pid))
    printf("Successfully killed %d\n", pid);
  else
    printf("%d : No such process\n", pid);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s9_Compression>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L19:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <s9_encode@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  addq   $0x4,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x10(%rbp)
  jg     L19
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  sar    $0x2,%rax
  leave
  ret
```

assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned *tmp = output;
  while (left > 0) {
    ret = s9_encode(tmp, input, left);
    input += ret;
    left -= ret;
    tmp++;
  }
  return tmp - output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<s9_Compression>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  test   %edx,%edx
  jle    L7
  mov    %rdi,%r13
  mov    %edx,%ebx
  mov    %rsi,%rbp
L20:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <s9_encode@plt>
  movslq %eax,%rdx
  lea    0x0(%r13,%rdx,4),%r13
  sub    %eax,%ebx
  add    $0x4,%rbp
  test   %ebx,%ebx
  jg     L20
L2:
  mov    %rbp,%rax
  sub    %r12,%rax
  sar    $0x2,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %rsi,%rbp
  jmp    L2
```

assistant: ```c
int s9_Compression(unsigned int *input, unsigned int *output, int size) {
  int left = size;
  int ret;
  unsigned *tmp = output;
  while (left > 0) {
    ret = s9_encode(tmp, input, left);
    input += ret;
    left -= ret;
    tmp++;
  }
  return tmp - output;
}
```