ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<passCrypt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x2e2e2e2e2e243124,%rax
  mov    %rax,0x1c(%rsp)
  movl   $0x2e2e2e,0x24(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rbp
  mov    %rax,(%rsp)
  mov    $0x0,%eax
  call   <getpid@plt>
  shr    $0xe,%rbp
  and    $0x30000,%ebp
  xor    %rax,%rbp
  mov    %rbp,0x8(%rsp)
  mov    $0x0,%edx
  lea    0x1f(%rsp),%rdi
  lea    D7(%rip),%rsi
L9:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  movslq %eax,%r8
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  add    %ecx,%ecx
  mov    (%rsp,%r8,8),%rax
  shr    %cl,%rax
  and    $0x3f,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x8,%rdx
  jne    L9
  lea    0x1c(%rsp),%rsi
  mov    %rbx,%rdi
  call   <crypt@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *passCrypt(char *in) {
  unsigned long seed[2];
  char salt[] = "$1$........";
  const char *seedchars = "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++)
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  return crypt(in, salt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<passCrypt>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x2e2e2e2e2e243124,%rax
  movl   $0x2e2e2e,0x24(%rsp)
  mov    %rax,0x1c(%rsp)
  call   <time@plt>
  mov    %rax,(%rsp)
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  lea    0x1f(%rsp),%rsi
  xor    %edx,%edx
  mov    $0xcccccccd,%edi
  mov    %rax,%r8
  mov    %rbx,%rax
  shr    $0xe,%rax
  and    $0x30000,%eax
  xor    %r8,%rax
  lea    D4(%rip),%r8
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  jmp    L9
  nopl   (%rax)
L7:
  mov    %edx,%eax
  mov    %rax,%rcx
  imul   %rdi,%rcx
  shr    $0x22,%rcx
  mov    (%rsp,%rcx,8),%rbx
L9:
  imul   %rdi,%rax
  add    $0x1,%rsi
  shr    $0x22,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  add    $0x1,%edx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  add    %ecx,%ecx
  shr    %cl,%rbx
  and    $0x3f,%ebx
  movzbl (%r8,%rbx,1),%eax
  mov    %al,-0x1(%rsi)
  cmp    $0x8,%edx
  jne    L7
  lea    0x1c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <crypt@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *passCrypt(char *in) {
  unsigned long seed[2];
  char salt[] = "$1$........";
  const char *seedchars = "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++)
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  return crypt(in, salt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<passCrypt>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2e2e2e2e2e243124,%rax
  movl   $0x2e2e2e,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <time@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %rbx,%rdi
  mov    %rbx,%rcx
  mov    %rbx,%rsi
  shr    $0xe,%rdi
  mov    %rbx,%r8
  mov    %rbx,%r9
  shr    $0x18,%rbx
  and    $0x30000,%edi
  and    $0x3f,%ebx
  shr    $0x12,%r9
  and    $0x3f,%ecx
  shr    $0xc,%r8
  xor    %rax,%rdi
  and    $0x3f,%eax
  and    $0x3f,%r9d
  mov    %rdi,%r11
  shr    $0xc,%rdi
  mov    %rax,%r10
  and    $0x3f,%r8d
  lea    D8(%rip),%rdx
  shr    $0x6,%r11
  and    $0x3f,%edi
  shr    $0x6,%rsi
  movzbl (%rdx,%rdi,1),%eax
  and    $0x3f,%r11d
  and    $0x3f,%esi
  movzbl (%rdx,%r11,1),%edi
  movzbl (%rdx,%rsi,1),%esi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r10,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%rbx,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r9,1),%edi
  shl    $0x8,%rax
  or     %rdi,%rax
  movzbl (%rdx,%r8,1),%edi
  movzbl (%rdx,%rcx,1),%edx
  shl    $0x8,%rax
  or     %rdi,%rax
  mov    %rbp,%rdi
  shl    $0x8,%rax
  or     %rsi,%rax
  lea    0x8(%rsp),%rsi
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,0xb(%rsp)
  call   <crypt@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: ./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz

assistant: ```c
char *passCrypt(char *in) {
  unsigned long seed[2];
  char salt[] = "$1$........";
  const char *seedchars = "./0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
  int i;
  seed[0] = time(NULL);
  seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
  for (i = 0; i < 8; i++)
    salt[3 + i] = seedchars[(seed[i / 5] >> (i % 5) * 6) & 0x3f];
  return crypt(in, salt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jenkins_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xa,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x6,%rax
  xor    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L24
L19:
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0xb,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xf,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long jenkins_hash(void *string, unsigned long length) {
  unsigned char *p;
  unsigned long acc = 0;
  p = (unsigned char *)string;
  unsigned long hash = 0;
  while (*p != '\0' && acc < length) {
    hash += *p;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    ++p;
    ++acc;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jenkins_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L8
  test   %al,%al
  je     L8
  mov    $0x0,%edx
  mov    $0x0,%ecx
L6:
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x6,%rdx
  xor    %rax,%rdx
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  cmp    %rcx,%rsi
  jbe    L0
  test   %al,%al
  jne    L6
L0:
  lea    (%rdx,%rdx,8),%rax
  mov    %rax,%rdx
  shr    $0xb,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0xf,%rax
  add    %rdx,%rax
  ret
L8:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
unsigned long jenkins_hash(void *string, unsigned long length) {
  unsigned char *p;
  unsigned long acc = 0;
  p = (unsigned char *)string;
  unsigned long hash = 0;
  while (*p != '\0' && acc < length) {
    hash += *p;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    ++p;
    ++acc;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<jenkins_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L22
  test   %al,%al
  je     L22
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L21:
  test   %al,%al
  je     L45
L18:
  add    %rdx,%rax
  add    $0x1,%rcx
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x6,%rdx
  xor    %rax,%rdx
  movzbl (%rdi,%rcx,1),%eax
  cmp    %rcx,%rsi
  ja     L21
L45:
  lea    (%rdx,%rdx,8),%rax
  mov    %rax,%rdx
  shr    $0xb,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0xf,%rax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long jenkins_hash(void *string, unsigned long length) {
  unsigned char *p;
  unsigned long acc = 0;
  p = (unsigned char *)string;
  unsigned long hash = 0;
  while (*p != '\0' && acc < length) {
    hash += *p;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    ++p;
    ++acc;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jenkins_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L40
  test   %al,%al
  je     L40
  xor    %edx,%edx
  xor    %ecx,%ecx
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L4:
  test   %al,%al
  je     L31
L19:
  add    %rdx,%rax
  add    $0x1,%rcx
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x6,%rdx
  xor    %rax,%rdx
  movzbl (%rdi,%rcx,1),%eax
  cmp    %rcx,%rsi
  ja     L4
L31:
  lea    (%rdx,%rdx,8),%rax
  mov    %rax,%rdx
  shr    $0xb,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0xf,%rax
  add    %rdx,%rax
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long jenkins_hash(void *string, unsigned long length) {
  unsigned char *p;
  unsigned long acc = 0;
  p = (unsigned char *)string;
  unsigned long hash = 0;
  while (*p != '\0' && acc < length) {
    hash += *p;
    hash += (hash << 10);
    hash ^= (hash >> 6);
    ++p;
    ++acc;
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L3:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L37
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L37:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L3
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_min(int *array, int size) {
  int low = 0;
  int high = size - 1;
  int mid;
  while (low < high) {
    mid = ((high + low) / 2);
    if (array[mid] < array[high]) {
      high = mid - 1;
    } else {
      low = mid + 1;
    }
  }
  return low;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L27
  mov    $0x0,%ecx
  jmp    L40
L47:
  lea    0x1(%rax),%ecx
L29:
  cmp    %ecx,%esi
  jle    L11
L40:
  lea    (%rcx,%rsi,1),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  movslq %eax,%r8
  movslq %esi,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,(%rdi,%r8,4)
  jge    L47
  lea    -0x1(%rax),%esi
  jmp    L29
L27:
  mov    $0x0,%ecx
L11:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int find_min(int *array, int size) {
  int low = 0;
  int high = size - 1;
  int mid;
  while (low < high) {
    mid = ((high + low) / 2);
    if (array[mid] < array[high]) {
      high = mid - 1;
    } else {
      low = mid + 1;
    }
  }
  return low;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  xor    %r8d,%r8d
  test   %esi,%esi
  jg     L17
  jmp    L36
L5:
  lea    -0x1(%rax),%esi
  cmp    %esi,%r8d
  jge    L36
L17:
  lea    (%r8,%rsi,1),%eax
  movslq %esi,%rdx
  sar    %eax
  mov    (%rdi,%rdx,4),%edx
  movslq %eax,%rcx
  cmp    %edx,(%rdi,%rcx,4)
  jl     L5
  lea    0x1(%rax),%r8d
  cmp    %esi,%r8d
  jl     L17
L36:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_min(int *array, int size) {
  int low = 0;
  int high = size - 1;
  int mid;
  while (low < high) {
    mid = ((high + low) / 2);
    if (array[mid] < array[high]) {
      high = mid - 1;
    } else {
      low = mid + 1;
    }
  }
  return low;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  xor    %r8d,%r8d
  test   %esi,%esi
  jg     L19
  jmp    L41
L22:
  lea    -0x1(%rax),%esi
  cmp    %r8d,%esi
  jle    L41
L19:
  movslq %esi,%rcx
L21:
  lea    (%rsi,%r8,1),%eax
  sar    %eax
  movslq %eax,%rdx
  mov    (%rdi,%rdx,4),%edx
  cmp    %edx,(%rdi,%rcx,4)
  jg     L22
  lea    0x1(%rax),%r8d
  cmp    %esi,%r8d
  jl     L21
L41:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_min(int *array, int size) {
  int low = 0;
  int high = size - 1;
  int mid;
  while (low < high) {
    mid = ((high + low) / 2);
    if (array[mid] < array[high]) {
      high = mid - 1;
    } else {
      low = mid + 1;
    }
  }
  return low;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<extractQuery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x323225,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %al,-0x1b(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ax,-0x1a(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2b,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <chrrpl@plt>
  test   %rax,%rax
  jne    L17
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L22
L17:
  movsbw -0x1b(%rbp),%dx
  movzwl -0x1a(%rbp),%eax
  add    %eax,%edx
  movsbw -0x1b(%rbp),%ax
  add    %edx,%eax
  add    $0x1,%eax
  cwtl
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbq -0x1b(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  movsbq -0x1b(%rbp),%rdx
  movswq -0x1a(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  movswl -0x1a(%rbp),%edx
  movsbl -0x1b(%rbp),%eax
  add    %eax,%edx
  movsbl -0x1b(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
char *extractQuery(char *str) {
  const char d[] = "%22";
  char dl = strlen(d);
  short len = strlen(str);
  char *q;
  if (chrrpl(str, ' ', '+') == 0)
    return strdup(str);
  q = malloc(len + dl + dl + 1);
  strcpy(q, d);
  strcpy(q + dl, str);
  strcpy(q + dl + len, d);
  q[len + dl + dl] = '\0';
  return q;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<extractQuery>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x323225,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    $0x2b,%edx
  mov    $0x20,%esi
  mov    %r13,%rdi
  call   <chrrpl@plt>
  test   %rax,%rax
  je     L9
  movsbw %r12b,%di
  lea    0x1(%rbp,%rdi,2),%edi
  movswl %di,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%r14
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movsbq %r12b,%r15
  lea    (%rbx,%r15,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  movswq %bp,%rdi
  add    %r15,%rdi
  add    %rbx,%rdi
  mov    %r14,%rsi
  call   <strcpy@plt>
  movsbl %r12b,%r12d
  movswl %bp,%ebp
  lea    0x0(%rbp,%r12,2),%eax
  cltq
  movb   $0x0,(%rbx,%rax,1)
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  jmp    L23
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractQuery(char *str) {
  const char d[] = "%22";
  char dl = strlen(d);
  short len = strlen(str);
  char *q;
  if (chrrpl(str, ' ', '+') == 0)
    return strdup(str);
  q = malloc(len + dl + dl + 1);
  strcpy(q, d);
  strcpy(q + dl, str);
  strcpy(q + dl + len, d);
  q[len + dl + dl] = '\0';
  return q;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<extractQuery>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  movl   $0x323225,0x4(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    $0x2b,%edx
  mov    $0x20,%esi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <chrrpl@plt>
  test   %rax,%rax
  je     L20
  movsbw %bpl,%di
  movsbq %bpl,%r15
  movsbl %bpl,%ebp
  lea    0x1(%rbx,%rdi,2),%edi
  movswl %di,%edi
  call   <malloc@plt>
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x0(%r13,%r15,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  movswq %bx,%rdi
  mov    %r14,%rsi
  movswl %bx,%ebx
  add    %r15,%rdi
  add    %r13,%rdi
  call   <strcpy@plt>
  lea    (%rbx,%rbp,2),%eax
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <strdup@plt>
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractQuery(char *str) {
  const char d[] = "%22";
  char dl = strlen(d);
  short len = strlen(str);
  char *q;
  if (chrrpl(str, ' ', '+') == 0)
    return strdup(str);
  q = malloc(len + dl + dl + 1);
  strcpy(q, d);
  strcpy(q + dl, str);
  strcpy(q + dl + len, d);
  q[len + dl + dl] = '\0';
  return q;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<extractQuery>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  movl   $0x323225,0x4(%rsp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    $0x2b,%edx
  mov    $0x20,%esi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <chrrpl@plt>
  test   %rax,%rax
  je     L29
  movsbw %bpl,%di
  movsbq %bpl,%r15
  movsbl %bpl,%ebp
  lea    0x1(%rbx,%rdi,2),%edi
  movswl %di,%edi
  call   <malloc@plt>
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0x0(%r13,%r15,1),%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  movswq %bx,%rdi
  mov    %r14,%rsi
  movswl %bx,%ebx
  add    %r15,%rdi
  add    %r13,%rdi
  call   <strcpy@plt>
  lea    (%rbx,%rbp,2),%eax
  cltq
  movb   $0x0,0x0(%r13,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10f0 <strdup@plt>
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *extractQuery(char *str) {
  const char d[] = "%22";
  char dl = strlen(d);
  short len = strlen(str);
  char *q;
  if (chrrpl(str, ' ', '+') == 0)
    return strdup(str);
  q = malloc(len + dl + dl + 1);
  strcpy(q, d);
  strcpy(q + dl, str);
  strcpy(q + dl + len, d);
  q[len + dl + dl] = '\0';
  return q;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_inpchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  cmpb   $0x0,-0x9(%rbp)
  je     L3
  movsbl -0x9(%rbp),%eax
  jmp    L13
L3:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int _inpchar(void **inp) {
  char result;
  char *buf = (char *)(*inp);
  result = *(buf++);
  *inp = (void *)buf;
  return ((result == '\0') ? EOF : result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_inpchar>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  test   %al,%al
  je     L9
  movsbl %al,%eax
  ret
L9:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int _inpchar(void **inp) {
  char result;
  char *buf = (char *)(*inp);
  result = *(buf++);
  *inp = (void *)buf;
  return ((result == '\0') ? EOF : result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_inpchar>:
  endbr64
  mov    (%rdi),%rdx
  movsbl (%rdx),%eax
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  test   %al,%al
  jne    L4
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L4:
  ret
```

assistant: ```c
int _inpchar(void **inp) {
  char result;
  char *buf = (char *)(*inp);
  result = *(buf++);
  *inp = (void *)buf;
  return ((result == '\0') ? EOF : result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_inpchar>:
  endbr64
  mov    (%rdi),%rdx
  movsbl (%rdx),%eax
  add    $0x1,%rdx
  mov    %rdx,(%rdi)
  test   %al,%al
  jne    L5
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L5:
  ret
```

assistant: ```c
int _inpchar(void **inp) {
  char result;
  char *buf = (char *)(*inp);
  result = *(buf++);
  *inp = (void *)buf;
  return ((result == '\0') ? EOF : result);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tableinit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <softclip_table_init@plt>
  mov    $0x0,%eax
  call   <rnd_table_init@plt>
  mov    $0x0,%eax
  call   <init_noise_samples@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tableinit(void) {
  softclip_table_init();
  rnd_table_init();
  init_noise_samples();
}
```
user: What is the c source code of the assembly code below:

```asm
<tableinit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <softclip_table_init@plt>
  mov    $0x0,%eax
  call   <rnd_table_init@plt>
  mov    $0x0,%eax
  call   <init_noise_samples@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void tableinit(void) {
  softclip_table_init();
  rnd_table_init();
  init_noise_samples();
}
```