ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<requestMemoryBlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void requestMemoryBlock(int blocksize_bytes, void **memory_pointer) {
  *memory_pointer = malloc(blocksize_bytes);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<requestMemoryBlock>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void requestMemoryBlock(int blocksize_bytes, void **memory_pointer) {
  *memory_pointer = malloc(blocksize_bytes);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<requestMemoryBlock>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void requestMemoryBlock(int blocksize_bytes, void **memory_pointer) {
  *memory_pointer = malloc(blocksize_bytes);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a - (-1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a - (-1));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a - (-1));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  *(&a - (-1));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<plugin_script_ptr2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D79(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,D90(%rip)
  mov    D90(%rip),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  lea    D90(%rip),%rax
  movb   $0x0,(%rdx,%rax,1)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    D90(%rip),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  lea    D90(%rip),%rax
  add    %rdx,%rax
  jmp    L8
L11:
  mov    -0x8(%rbp),%rax
  mov    D90(%rip),%edx
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shl    $0x5,%rcx
  lea    D90(%rip),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    %rax,%rcx
  lea    D74(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  call   <snprintf@plt>
  mov    D90(%rip),%eax
  cltq
  shl    $0x5,%rax
  mov    %rax,%rdx
  lea    D90(%rip),%rax
  add    %rdx,%rax
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D74
type: string

tool: D74: 0x%lx

assistant: ```c
const char *plugin_script_ptr2str(void *pointer) {
  static char str_pointer[32][32];
  static int index_pointer = 0;
  index_pointer = (index_pointer + 1) % 32;
  str_pointer[index_pointer][0] = '\0';
  if (!pointer)
    return str_pointer[index_pointer];
  snprintf(str_pointer[index_pointer], sizeof(str_pointer[index_pointer]), "0x%lx", (unsigned long)pointer);
  return str_pointer[index_pointer];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plugin_script_ptr2str>:
  endbr64
  mov    D41(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,D5(%rip)
  movslq %eax,%rdx
  shl    $0x5,%rdx
  lea    D5(%rip),%rsi
  movb   $0x0,(%rsi,%rdx,1)
  test   %rdi,%rdi
  je     L9
  push   %rbx
  mov    %rdi,%rcx
  cltq
  shl    $0x5,%rax
  lea    D5(%rip),%rbx
  lea    (%rax,%rbx,1),%rdi
  lea    D32(%rip),%rdx
  mov    $0x20,%esi
  call   <snprintf@plt>
  movslq D5(%rip),%rax
  shl    $0x5,%rax
  add    %rbx,%rax
  pop    %rbx
  ret
L9:
  mov    %rdx,%rax
  add    %rsi,%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D32
type_guessed: string

tool: D32: 0x%lx

assistant: ```c
const char *plugin_script_ptr2str(void *pointer) {
  static char str_pointer[32][32];
  static int index_pointer = 0;
  index_pointer = (index_pointer + 1) % 32;
  str_pointer[index_pointer][0] = '\0';
  if (!pointer)
    return str_pointer[index_pointer];
  snprintf(str_pointer[index_pointer], sizeof(str_pointer[index_pointer]), "0x%lx", (unsigned long)pointer);
  return str_pointer[index_pointer];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<plugin_script_ptr2str>:
  endbr64
  mov    D5(%rip),%eax
  push   %rbx
  lea    D45(%rip),%rbx
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,D14(%rip)
  cltq
  shl    $0x5,%rax
  add    %rbx,%rax
  movb   $0x0,(%rax)
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rcx
  lea    D14(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  movslq D14(%rip),%rax
  shl    $0x5,%rax
  add    %rbx,%rax
L8:
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
data_type: string

tool: D14: 0x%lx

assistant: ```c
const char *plugin_script_ptr2str(void *pointer) {
  static char str_pointer[32][32];
  static int index_pointer = 0;
  index_pointer = (index_pointer + 1) % 32;
  str_pointer[index_pointer][0] = '\0';
  if (!pointer)
    return str_pointer[index_pointer];
  snprintf(str_pointer[index_pointer], sizeof(str_pointer[index_pointer]), "0x%lx", (unsigned long)pointer);
  return str_pointer[index_pointer];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plugin_script_ptr2str>:
  endbr64
  mov    D8(%rip),%eax
  push   %rbx
  lea    D13(%rip),%rbx
  add    $0x1,%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,D45(%rip)
  cltq
  shl    $0x5,%rax
  add    %rbx,%rax
  movb   $0x0,(%rax)
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rcx
  lea    D45(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  movslq D45(%rip),%rax
  shl    $0x5,%rax
  add    %rbx,%rax
L8:
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D45
datatype: string

tool: D45: 0x%lx

assistant: ```c
const char *plugin_script_ptr2str(void *pointer) {
  static char str_pointer[32][32];
  static int index_pointer = 0;
  index_pointer = (index_pointer + 1) % 32;
  str_pointer[index_pointer][0] = '\0';
  if (!pointer)
    return str_pointer[index_pointer];
  snprintf(str_pointer[index_pointer], sizeof(str_pointer[index_pointer]), "0x%lx", (unsigned long)pointer);
  return str_pointer[index_pointer];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x40(%rbp)
  movl   $0x4,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  movl   $0x3,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0xc,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  movl   $0x3,-0x58(%rbp)
  movl   $0xfffffff7,-0x54(%rbp)
  movl   $0x4,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movl   $0x6,-0x48(%rbp)
  movl   $0xfffffff8,-0x44(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x68(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sum_rows@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sum_cols@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sum2d@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x4,%esi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <vla_sum2d@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x4,%esi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <vla_sum2d@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: Sum of all elements = %d


assistant: ```c
int main(void) {
  int junk[3][4] = {
      {2, 4, 6, 8},
      {3, 5, 7, 9},
      {12, 10, 8, 6},
  };
  int(*pt1)[4];
  pt1 = (int[][4]){{1, 2, 3, -9}, {4, 5, 6, -8}};
  sum_rows(junk, 3);
  sum_cols(junk, 3);
  printf("Sum of all elements = %d\n", sum2d(junk, 3));
  printf("Sum of all elements = %d\n", vla_sum2d(3, 4, junk));
  printf("Sum of all elements = %d\n", vla_sum2d(2, 4, pt1));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x20(%rsp)
  movl   $0x4,0x24(%rsp)
  movl   $0x6,0x28(%rsp)
  movl   $0x8,0x2c(%rsp)
  movl   $0x3,0x30(%rsp)
  movl   $0x5,0x34(%rsp)
  movl   $0x7,0x38(%rsp)
  movl   $0x9,0x3c(%rsp)
  movl   $0xc,0x40(%rsp)
  movl   $0xa,0x44(%rsp)
  movl   $0x8,0x48(%rsp)
  movl   $0x6,0x4c(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0xfffffff7,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0xfffffff8,0x1c(%rsp)
  lea    0x20(%rsp),%rbx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <sum_rows@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sum_cols@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sum2d@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    $0x4,%esi
  mov    $0x3,%edi
  mov    $0x0,%eax
  call   <vla_sum2d@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdx
  mov    $0x4,%esi
  mov    $0x2,%edi
  mov    $0x0,%eax
  call   <vla_sum2d@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: Sum of all elements = %d


assistant: ```c
int main(void) {
  int junk[3][4] = {
      {2, 4, 6, 8},
      {3, 5, 7, 9},
      {12, 10, 8, 6},
  };
  int(*pt1)[4];
  pt1 = (int[][4]){{1, 2, 3, -9}, {4, 5, 6, -8}};
  sum_rows(junk, 3);
  sum_cols(junk, 3);
  printf("Sum of all elements = %d\n", sum2d(junk, 3));
  printf("Sum of all elements = %d\n", vla_sum2d(3, 4, junk));
  printf("Sum of all elements = %d\n", vla_sum2d(2, 4, pt1));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x400000002,%rax
  lea    0x20(%rsp),%r12
  mov    %r12,%rdi
  mov    %rax,0x20(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000003,%rax
  mov    %rax,0x30(%rsp)
  movabs $0x900000007,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xa0000000c,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x600000008,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,(%rsp)
  movabs $0xfffffff700000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xfffffff800000006,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <sum_rows@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sum_cols@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    $0x4,%esi
  xor    %eax,%eax
  mov    $0x3,%edi
  call   <vla_sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x2,%edi
  call   <vla_sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: Sum of all elements = %d


assistant: ```c
int main(void) {
  int junk[3][4] = {
      {2, 4, 6, 8},
      {3, 5, 7, 9},
      {12, 10, 8, 6},
  };
  int(*pt1)[4];
  pt1 = (int[][4]){{1, 2, 3, -9}, {4, 5, 6, -8}};
  sum_rows(junk, 3);
  sum_cols(junk, 3);
  printf("Sum of all elements = %d\n", sum2d(junk, 3));
  printf("Sum of all elements = %d\n", vla_sum2d(3, 4, junk));
  printf("Sum of all elements = %d\n", vla_sum2d(2, 4, pt1));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%esi
  push   %rbp
  lea    D10(%rip),%rbp
  sub    $0x68,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  movaps %xmm0,0x20(%rsp)
  movdqa D30(%rip),%xmm0
  mov    %r12,%rdi
  movaps %xmm0,0x30(%rsp)
  movdqa D52(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D43(%rip),%xmm0
  movaps %xmm0,(%rsp)
  movdqa D19(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <sum_rows@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sum_cols@plt>
  mov    $0x3,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    $0x4,%esi
  xor    %eax,%eax
  mov    $0x3,%edi
  call   <vla_sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x2,%edi
  call   <vla_sum2d@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: byte[16]
name: unpack_data
arguments: tag: D30
type_guessed: byte[16]
name: unpack_data
arguments: tag: D52
type_guessed: byte[16]
name: unpack_data
arguments: tag: D43
type_guessed: byte[16]
name: unpack_data
arguments: tag: D19
type_guessed: byte[16]

tool: D10: Sum of all elements = %d


tool: {"D7": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D30": [0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D52": [0x0c,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D43": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0xf7,0xff,0xff,0xff]}

tool: {"D19": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0xf8,0xff,0xff,0xff]}

assistant: ```c
int main(void) {
  int junk[3][4] = {
      {2, 4, 6, 8},
      {3, 5, 7, 9},
      {12, 10, 8, 6},
  };
  int(*pt1)[4];
  pt1 = (int[][4]){{1, 2, 3, -9}, {4, 5, 6, -8}};
  sum_rows(junk, 3);
  sum_cols(junk, 3);
  printf("Sum of all elements = %d\n", sum2d(junk, 3));
  printf("Sum of all elements = %d\n", vla_sum2d(3, 4, junk));
  printf("Sum of all elements = %d\n", vla_sum2d(2, 4, pt1));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a4(%rbp)
  jmp    L28
L18:
  mov    -0x1a4(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x1a4(%rbp),%eax
  cltq
  movss  %xmm0,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
L28:
  cmpl   $0x63,-0x1a4(%rbp)
  jle    L18
  lea    -0x1a0(%rbp),%rax
  mov    $0x63,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <invertOrdem@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  float arr[100];
  int i;
  for (i = 0; i < 100; i++)
    arr[i] = i + 1;
  invertOrdem(arr, 0, 99);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
L14:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x65,%rax
  jne    L14
  mov    %rsp,%rdi
  mov    $0x63,%edx
  mov    $0x0,%esi
  call   <invertOrdem@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  float arr[100];
  int i;
  for (i = 0; i < 100; i++)
    arr[i] = i + 1;
  invertOrdem(arr, 0, 99);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    $0x1,%eax
  mov    %rsp,%rdi
  nopl   0x0(%rax)
L11:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x65,%rax
  jne    L11
  xor    %esi,%esi
  mov    $0x63,%edx
  call   <invertOrdem@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  float arr[100];
  int i;
  for (i = 0; i < 100; i++)
    arr[i] = i + 1;
  invertOrdem(arr, 0, 99);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x1a8,%rsp
  movdqa D1(%rip),%xmm1
  movdqa D15(%rip),%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movdqa D28(%rip),%xmm2
  lea    0x190(%rsp),%rdx
  mov    %rdi,%rax
  nopl   0x0(%rax)
L8:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cvtdq2ps %xmm0,%xmm0
  movaps %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L8
  xor    %esi,%esi
  mov    $0x63,%edx
  call   <invertOrdem@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x1a8,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: byte[16]
name: read_data
arguments: data_label: D15
data_type: byte[16]
name: read_data
arguments: data_label: D28
data_type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D15": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D28": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  float arr[100];
  int i;
  for (i = 0; i < 100; i++)
    arr[i] = i + 1;
  invertOrdem(arr, 0, 99);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L47
L96:
  movl   $0x0,-0x2728(%rbp)
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2724(%rbp)
  movl   $0x0,-0x2730(%rbp)
  jmp    L34
L39:
  mov    -0x2730(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L26
  mov    -0x2730(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x272c(%rbp)
  jmp    L72
L100:
  mov    -0x272c(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x272c(%rbp)
L72:
  mov    -0x272c(%rbp),%eax
  cmp    -0x2728(%rbp),%eax
  jge    L100
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    -0x2730(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x2728(%rbp)
L26:
  mov    -0x2724(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x2730(%rbp)
  jne    L41
  mov    -0x2730(%rbp),%eax
  mov    %eax,-0x272c(%rbp)
  jmp    L17
L2:
  mov    -0x272c(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  subl   $0x1,-0x272c(%rbp)
L17:
  mov    -0x272c(%rbp),%eax
  cmp    -0x2728(%rbp),%eax
  jge    L2
  mov    $0xa,%edi
  call   <putchar@plt>
L41:
  addl   $0x1,-0x2730(%rbp)
L34:
  mov    -0x2730(%rbp),%eax
  cmp    -0x2724(%rbp),%eax
  jl     L39
L47:
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L96
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

assistant: ```c
int main() {
  char s[10000];
  int i, j, a, l;
  while (gets(s)) {
    a = 0;
    l = strlen(s);
    for (i = 0; i < l; i++) {
      if (s[i] == ' ') {
        for (j = i - 1; j >= a; j--) {
          printf("%c", s[j]);
        }
        printf(" ");
        a = i + 1;
      }
      if (i == l - 1) {
        for (j = i; j >= a; j--)
          printf("%c", s[j]);
        printf("\n");
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
L114:
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L2
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L114
  mov    %eax,%eax
  mov    %rax,0x8(%rsp)
  mov    $0xffffffffffffffff,%r14
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L4
L38:
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%r13d
  add    $0x1,%r13d
L97:
  lea    -0x1(%r15),%eax
  cmp    %ebx,%eax
  je     L115
L78:
  add    $0x1,%rbx
  add    $0x1,%r14
  cmp    0x8(%rsp),%rbx
  je     L114
L4:
  mov    %ebx,0x4(%rsp)
  cmpb   $0x20,(%rbx,%r12,1)
  jne    L97
  cmp    %r14d,%r13d
  jg     L38
  mov    %r14,%rbp
L123:
  movsbl 0x0(%rbp,%r12,1),%edi
  call   <putchar@plt>
  sub    $0x1,%rbp
  cmp    %ebp,%r13d
  jle    L123
  jmp    L38
L115:
  cmp    %ebx,%r13d
  jg     L118
  mov    %rbx,%rbp
L94:
  movsbl 0x0(%rbp,%r12,1),%edi
  call   <putchar@plt>
  sub    $0x1,%rbp
  cmp    %ebp,%r13d
  jle    L94
L118:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L78
L2:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x2738,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char s[10000];
  int i, j, a, l;
  while (gets(s)) {
    a = 0;
    l = strlen(s);
    for (i = 0; i < l; i++) {
      if (s[i] == ' ') {
        for (j = i - 1; j >= a; j--) {
          printf("%c", s[j]);
        }
        printf(" ");
        a = i + 1;
      }
      if (i == l - 1) {
        for (j = i; j >= a; j--)
          printf("%c", s[j]);
        printf("\n");
      }
    }
  }
  return 0;
}
```