ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gator_write_packed_int>:
  endbr64
  test   $0xffffff80,%esi
  je     L8
  mov    %esi,%ecx
  mov    %esi,%eax
  or     $0xffffff80,%ecx
  shr    $0x7,%eax
  test   $0xffffc000,%esi
  je     L1
  mov    %esi,%edx
  or     $0xffffff80,%eax
  shr    $0xe,%edx
  test   $0xffe00000,%esi
  je     L10
  or     $0xffffff80,%edx
  mov    %esi,%r8d
  mov    %cl,(%rdi)
  mov    %al,0x1(%rdi)
  shr    $0x15,%r8d
  mov    %dl,0x2(%rdi)
  test   $0xf0000000,%esi
  jne    L3
  mov    %r8b,0x3(%rdi)
  mov    $0x4,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %sil,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L3:
  or     $0xffffff80,%r8d
  shr    $0x1c,%esi
  mov    $0x5,%eax
  mov    %r8b,0x3(%rdi)
  mov    %sil,0x4(%rdi)
  ret
  nopl   (%rax)
L10:
  mov    %al,0x1(%rdi)
  mov    $0x3,%eax
  mov    %cl,(%rdi)
  mov    %dl,0x2(%rdi)
  ret
  xchg   %ax,%ax
L1:
  mov    %al,0x1(%rdi)
  mov    $0x2,%eax
  mov    %cl,(%rdi)
  ret
```

assistant: ```c
int gator_write_packed_int(char *buffer, unsigned int x) {
  if ((x & 0xffffff80) == 0) {
    buffer[0] = x & 0x7f;
    return 1;
  } else if ((x & 0xffffc000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) & 0x7f;
    return 2;
  } else if ((x & 0xffe00000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) & 0x7f;
    return 3;
  } else if ((x & 0xf0000000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) & 0x7f;
    return 4;
  } else {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) | 0x80;
    buffer[4] = (x >> 28) & 0x0f;
    return 5;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gator_write_packed_int>:
  endbr64
  test   $0xffffff80,%esi
  je     L0
  mov    %esi,%ecx
  mov    %esi,%eax
  or     $0xffffff80,%ecx
  shr    $0x7,%eax
  test   $0xffffc000,%esi
  je     L39
  mov    %esi,%edx
  or     $0xffffff80,%eax
  shr    $0xe,%edx
  test   $0xffe00000,%esi
  je     L38
  or     $0xffffff80,%edx
  mov    %esi,%r8d
  mov    %cl,(%rdi)
  mov    %al,0x1(%rdi)
  shr    $0x15,%r8d
  mov    %dl,0x2(%rdi)
  test   $0xf0000000,%esi
  jne    L10
  mov    %r8b,0x3(%rdi)
  mov    $0x4,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %sil,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L10:
  or     $0xffffff80,%r8d
  shr    $0x1c,%esi
  mov    $0x5,%eax
  mov    %r8b,0x3(%rdi)
  mov    %sil,0x4(%rdi)
  ret
  nopl   (%rax)
L38:
  mov    %al,0x1(%rdi)
  mov    $0x3,%eax
  mov    %cl,(%rdi)
  mov    %dl,0x2(%rdi)
  ret
  xchg   %ax,%ax
L39:
  mov    %al,0x1(%rdi)
  mov    $0x2,%eax
  mov    %cl,(%rdi)
  ret
```

assistant: ```c
int gator_write_packed_int(char *buffer, unsigned int x) {
  if ((x & 0xffffff80) == 0) {
    buffer[0] = x & 0x7f;
    return 1;
  } else if ((x & 0xffffc000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) & 0x7f;
    return 2;
  } else if ((x & 0xffe00000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) & 0x7f;
    return 3;
  } else if ((x & 0xf0000000) == 0) {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) & 0x7f;
    return 4;
  } else {
    buffer[0] = x | 0x80;
    buffer[1] = (x >> 7) | 0x80;
    buffer[2] = (x >> 14) | 0x80;
    buffer[3] = (x >> 21) | 0x80;
    buffer[4] = (x >> 28) & 0x0f;
    return 5;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<variation_recover>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  movw   $0x0,-0x14(%rbp)
  mov    -0x70(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L87
  mov    -0x68(%rbp),%rax
  jmp    L33
L87:
  movq   $0x0,-0x50(%rbp)
  jmp    L86
L26:
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L83
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L83
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x48(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,-0x30(%rbp,%rax,1)
L83:
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L82
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L82
  mov    -0x70(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x51(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x51(%rbp),%eax
  mov    %al,(%rdx)
  movq   $0x0,-0x48(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x1e,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L82:
  addq   $0x1,-0x50(%rbp)
L86:
  mov    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,-0x50(%rbp)
  jb     L26
  mov    -0x68(%rbp),%rax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

assistant: ```c
char *variation_recover(char *base_temp, char *_cor) {
  size_t i = 0, j = 0, len = 0, next = 0;
  char NUM[30] = {'\0'}, _base;
  if (_cor[0] == '\n') {
    return base_temp;
  } else {
    for (i = 0; i < strlen(_cor); i++) {
      if (_cor[i] >= '0' && _cor[i] <= '9')
        NUM[j++] = _cor[i];
      if (_cor[i] >= 'A' && _cor[i] <= 'Z') {
        _base = _cor[i];
        len = atoi(NUM);
        next = len + next;
        base_temp[next] = _base;
        j = 0;
        memset(NUM, '\0', 30);
      }
    }
    return base_temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<variation_recover>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movw   $0x0,0x2c(%rsp)
  cmpb   $0xa,(%rsi)
  je     L65
  mov    %rsi,%r12
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r15
  jmp    L1
L66:
  lea    -0x41(%rbp),%eax
  cmp    $0x19,%al
  ja     L28
  mov    %r15,%rdi
  call   <atoi@plt>
  add    %rax,%r14
  mov    0x8(%rsp),%rax
  mov    %bpl,(%rax,%r14,1)
  mov    $0x1e,%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    $0x0,%r13d
L28:
  add    $0x1,%rbx
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L65
  movzbl (%r12,%rbx,1),%ebp
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%al
  ja     L66
  mov    %bpl,0x10(%rsp,%r13,1)
  lea    0x1(%r13),%r13
  jmp    L28
L65:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    0x8(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *variation_recover(char *base_temp, char *_cor) {
  size_t i = 0, j = 0, len = 0, next = 0;
  char NUM[30] = {'\0'}, _base;
  if (_cor[0] == '\n') {
    return base_temp;
  } else {
    for (i = 0; i < strlen(_cor); i++) {
      if (_cor[i] >= '0' && _cor[i] <= '9')
        NUM[j++] = _cor[i];
      if (_cor[i] >= 'A' && _cor[i] <= 'Z') {
        _base = _cor[i];
        len = atoi(NUM);
        next = len + next;
        base_temp[next] = _base;
        j = 0;
        memset(NUM, '\0', 30);
      }
    }
    return base_temp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<variation_recover>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  cmpb   $0xa,(%rsi)
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    %ax,0x2c(%rsp)
  je     L7
  mov    %rsi,%r14
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r15
  jmp    L33
  nop
L5:
  mov    %bpl,0x10(%rsp,%r12,1)
  add    $0x1,%r12
L2:
  add    $0x1,%rbx
L33:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L7
  movzbl (%r14,%rbx,1),%ebp
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%al
  jbe    L5
  lea    -0x41(%rbp),%eax
  cmp    $0x19,%al
  ja     L2
  mov    %r15,%rdi
  xor    %r12d,%r12d
  call   <atoi@plt>
  mov    $0x1e,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  add    %rax,%r13
  mov    0x8(%rsp),%rax
  mov    %bpl,(%rax,%r13,1)
  call   <memset@plt>
  jmp    L2
  nopl   (%rax)
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    0x8(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *variation_recover(char *base_temp, char *_cor) {
  size_t i = 0, j = 0, len = 0, next = 0;
  char NUM[30] = {'\0'}, _base;
  if (_cor[0] == '\n') {
    return base_temp;
  } else {
    for (i = 0; i < strlen(_cor); i++) {
      if (_cor[i] >= '0' && _cor[i] <= '9')
        NUM[j++] = _cor[i];
      if (_cor[i] >= 'A' && _cor[i] <= 'Z') {
        _base = _cor[i];
        len = atoi(NUM);
        next = len + next;
        base_temp[next] = _base;
        j = 0;
        memset(NUM, '\0', 30);
      }
    }
    return base_temp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<variation_recover>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  cmpb   $0xa,(%rsi)
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  mov    %ax,0x2c(%rsp)
  je     L7
  mov    %rsi,%r14
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r15
  jmp    L25
  nop
L67:
  mov    %bpl,0x10(%rsp,%r12,1)
  add    $0x1,%r12
L46:
  add    $0x1,%rbx
L25:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L7
  movzbl (%r14,%rbx,1),%ebp
  lea    -0x30(%rbp),%eax
  cmp    $0x9,%al
  jbe    L67
  lea    -0x41(%rbp),%eax
  cmp    $0x19,%al
  ja     L46
  mov    %r15,%rdi
  xor    %r12d,%r12d
  call   <atoi@plt>
  mov    $0x1e,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  add    %rax,%r13
  mov    0x8(%rsp),%rax
  mov    %bpl,(%rax,%r13,1)
  call   <memset@plt>
  jmp    L46
  nopl   (%rax)
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    0x8(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *variation_recover(char *base_temp, char *_cor) {
  size_t i = 0, j = 0, len = 0, next = 0;
  char NUM[30] = {'\0'}, _base;
  if (_cor[0] == '\n') {
    return base_temp;
  } else {
    for (i = 0; i < strlen(_cor); i++) {
      if (_cor[i] >= '0' && _cor[i] <= '9')
        NUM[j++] = _cor[i];
      if (_cor[i] >= 'A' && _cor[i] <= 'Z') {
        _base = _cor[i];
        len = atoi(NUM);
        next = len + next;
        base_temp[next] = _base;
        j = 0;
        memset(NUM, '\0', 30);
      }
    }
    return base_temp;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D52(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D70(%rip),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  lea    -0x30(%rbp),%rdx
  mov    %rax,%rsi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  lea    -0x30(%rbp),%rdx
  add    $0x8,%rdx
  mov    %rax,%rsi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  lea    -0x30(%rbp),%rdx
  add    $0x10,%rdx
  mov    %rax,%rsi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <in_array@plt>
  test   %rax,%rax
  je     L5
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L5:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D52
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D70
type_infered: string
name: unpack_data
arguments: tag: D84
type_infered: string
name: unpack_data
arguments: tag: D73
type_infered: string
name: unpack_data
arguments: tag: D76
type_infered: string

tool: D52: aaa

tool: D1: bbb

tool: D70: ccc

tool: D84: %s, addr:%lu


tool: D73: sizeof(const char*)=%u


tool: D76: ccc in array

assistant: ```c
int main() {
  const char *test_array[] = {"aaa", "bbb", "ccc", NULL};
  printf("%s, addr:%lu\n", test_array[0], &test_array[0]);
  printf("%s, addr:%lu\n", test_array[1], &test_array[1]);
  printf("%s, addr:%lu\n", test_array[2], &test_array[2]);
  printf("sizeof(const char*)=%u\n", sizeof(const char *));
  if (in_array("ccc", test_array)) {
    printf("ccc in array\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rsi
  mov    %rsi,(%rsp)
  lea    D41(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D59(%rip),%rbp
  mov    %rbp,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rsp,%r12
  mov    %r12,%rdx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rdx
  mov    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdx
  mov    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <in_array@plt>
  test   %rax,%rax
  jne    L20
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D41
type_guessed: string
name: unpack_data
arguments: data_tag: D59
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D40
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string

tool: D1: aaa

tool: D41: bbb

tool: D59: ccc

tool: D5: %s, addr:%lu


tool: D40: sizeof(const char*)=%u


tool: D15: ccc in array

assistant: ```c
int main() {
  const char *test_array[] = {"aaa", "bbb", "ccc", NULL};
  printf("%s, addr:%lu\n", test_array[0], &test_array[0]);
  printf("%s, addr:%lu\n", test_array[1], &test_array[1]);
  printf("%s, addr:%lu\n", test_array[2], &test_array[2]);
  printf("sizeof(const char*)=%u\n", sizeof(const char *));
  if (in_array("ccc", test_array)) {
    printf("ccc in array\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D57(%rip),%rsi
  push   %r12
  lea    D37(%rip),%r12
  push   %rbp
  lea    D32(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    D39(%rip),%rax
  mov    %rsi,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r12,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <in_array@plt>
  test   %rax,%rax
  jne    L10
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D57
type_guessed: string
name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D32
type_guessed: string
name: retrieve_data
arguments: label: D39
type_guessed: string
name: retrieve_data
arguments: label: D50
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string

tool: D57: aaa

tool: D37: ccc

tool: D32: %s, addr:%lu


tool: D39: bbb

tool: D50: sizeof(const char*)=%u


tool: D18: ccc in array

assistant: ```c
int main() {
  const char *test_array[] = {"aaa", "bbb", "ccc", NULL};
  printf("%s, addr:%lu\n", test_array[0], &test_array[0]);
  printf("%s, addr:%lu\n", test_array[1], &test_array[1]);
  printf("%s, addr:%lu\n", test_array[2], &test_array[2]);
  printf("sizeof(const char*)=%u\n", sizeof(const char *));
  if (in_array("ccc", test_array)) {
    printf("ccc in array\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rsi
  push   %r12
  movq   %rsi,%xmm0
  lea    D38(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rsp,%r13
  mov    %r12,0x10(%rsp)
  movq   %rax,%xmm1
  mov    %r13,%rdx
  xor    %eax,%eax
  movq   $0x0,0x18(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <in_array@plt>
  test   %rax,%rax
  jne    L11
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D22
datatype: string

tool: D8: aaa

tool: D38: ccc

tool: D4: %s, addr:%lu


tool: D0: bbb

tool: D33: sizeof(const char*)=%u


tool: D22: ccc in array

assistant: ```c
int main() {
  const char *test_array[] = {"aaa", "bbb", "ccc", NULL};
  printf("%s, addr:%lu\n", test_array[0], &test_array[0]);
  printf("%s, addr:%lu\n", test_array[1], &test_array[1]);
  printf("%s, addr:%lu\n", test_array[2], &test_array[2]);
  printf("sizeof(const char*)=%u\n", sizeof(const char *));
  if (in_array("ccc", test_array)) {
    printf("ccc in array\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<spy_mach_read_variant_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L7
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L15
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  addl   $0x7,-0xc(%rbp)
L11:
  cmpl   $0x1c,-0xc(%rbp)
  jle    L33
L15:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t spy_mach_read_variant_4(unsigned char *b, uint32_t *value) {
  uint32_t res = 0, shift;
  unsigned char *p = b;
  for (shift = 0; shift <= 28; shift += 7) {
    if (!(*p & (1 << 7))) {
      res |= (*p << shift);
      *value = res;
      break;
    } else {
      res |= ((*p & ((1 << 7) - 1)) << shift);
    }
    p++;
  }
  return p - b + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<spy_mach_read_variant_4>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L21:
  movzbl (%rax),%edx
  test   %dl,%dl
  jns    L2
  and    $0x7f,%edx
  shl    %cl,%edx
  or     %edx,%r8d
  add    $0x1,%rax
  add    $0x7,%ecx
  cmp    $0x23,%ecx
  jne    L21
L28:
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
L2:
  movzbl %dl,%edx
  shl    %cl,%edx
  or     %r8d,%edx
  mov    %edx,(%rsi)
  jmp    L28
```

assistant: ```c
uint32_t spy_mach_read_variant_4(unsigned char *b, uint32_t *value) {
  uint32_t res = 0, shift;
  unsigned char *p = b;
  for (shift = 0; shift <= 28; shift += 7) {
    if (!(*p & (1 << 7))) {
      res |= (*p << shift);
      *value = res;
      break;
    } else {
      res |= ((*p & ((1 << 7) - 1)) << shift);
    }
    p++;
  }
  return p - b + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spy_mach_read_variant_4>:
  endbr64
  mov    %rdi,%rax
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L1:
  movzbl (%rax),%edx
  test   %dl,%dl
  jns    L6
  and    $0x7f,%edx
  add    $0x1,%rax
  shl    %cl,%edx
  add    $0x7,%ecx
  or     %edx,%r8d
  cmp    $0x23,%ecx
  jne    L1
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  xchg   %ax,%ax
L6:
  shl    %cl,%edx
  sub    %rdi,%rax
  or     %r8d,%edx
  add    $0x1,%eax
  mov    %edx,(%rsi)
  ret
```

assistant: ```c
uint32_t spy_mach_read_variant_4(unsigned char *b, uint32_t *value) {
  uint32_t res = 0, shift;
  unsigned char *p = b;
  for (shift = 0; shift <= 28; shift += 7) {
    if (!(*p & (1 << 7))) {
      res |= (*p << shift);
      *value = res;
      break;
    } else {
      res |= ((*p & ((1 << 7) - 1)) << shift);
    }
    p++;
  }
  return p - b + 1;
}
```