ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<shell_quote_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L91
  mov    $0x2,%eax
  jmp    L25
L91:
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  jne    L82
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L25
L82:
  movb   $0x0,-0xb(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L52
L81:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  cmpb   $0x27,-0xa(%rbp)
  jne    L67
  mov    $0x22,%eax
  jmp    L73
L67:
  mov    $0x27,%eax
L73:
  mov    %al,-0x9(%rbp)
  movzbl -0xb(%rbp),%eax
  cmp    -0x9(%rbp),%al
  je     L39
  cmpb   $0x0,-0xb(%rbp)
  je     L27
  addq   $0x1,-0x8(%rbp)
L27:
  movzbl -0x9(%rbp),%eax
  mov    %al,-0xb(%rbp)
  addq   $0x1,-0x8(%rbp)
L39:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L52:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L81
  cmpb   $0x0,-0xb(%rbp)
  je     L37
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 	
 !"#$&'()*;<=>?[\]`{|}~

assistant: ```c
size_t shell_quote_length(const char *string) {
  if (string[0] == '\0')
    return 2;
  else if (strpbrk(string, "\t\n !\"#$&'()*;<=>?[\\]`{|}~") == NULL)
    return strlen(string);
  else {
    char qchar = '\0';
    size_t length = 0;
    for (; *string != '\0'; string++) {
      char c = *string;
      char q = (c == '\'' ? '"' : '\'');
      if (qchar != q) {
        if (qchar)
          length++;
        qchar = q;
        length++;
      }
      length++;
    }
    if (qchar)
      length++;
    return length;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shell_quote_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  mov    $0x2,%eax
  test   %bpl,%bpl
  je     L14
  mov    %rdi,%rbx
  lea    D0(%rip),%rsi
  call   <strpbrk@plt>
  mov    $0x0,%ecx
  mov    $0x0,%esi
  test   %rax,%rax
  jne    L24
  mov    %rbx,%rdi
  call   <strlen@plt>
  jmp    L14
L54:
  lea    0x1(%rdx),%rcx
  add    $0x1,%rbx
  movzbl (%rbx),%ebp
  test   %bpl,%bpl
  je     L44
  mov    %eax,%esi
L24:
  cmp    $0x27,%bpl
  setne  %al
  lea    0x22(%rax,%rax,4),%eax
  mov    %rcx,%rdx
  cmp    %sil,%al
  je     L54
  cmp    $0x1,%sil
  sbb    $0xfffffffffffffffe,%rdx
  jmp    L54
L44:
  lea    0x2(%rdx),%rax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D0: 	
 !"#$&'()*;<=>?[\]`{|}~

assistant: ```c
size_t shell_quote_length(const char *string) {
  if (string[0] == '\0')
    return 2;
  else if (strpbrk(string, "\t\n !\"#$&'()*;<=>?[\\]`{|}~") == NULL)
    return strlen(string);
  else {
    char qchar = '\0';
    size_t length = 0;
    for (; *string != '\0'; string++) {
      char c = *string;
      char q = (c == '\'' ? '"' : '\'');
      if (qchar != q) {
        if (qchar)
          length++;
        qchar = q;
        length++;
      }
      length++;
    }
    if (qchar)
      length++;
    return length;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<shell_quote_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L46
  lea    D8(%rip),%rsi
  mov    %rdi,%rbp
  call   <strpbrk@plt>
  xor    %ecx,%ecx
  xor    %esi,%esi
  test   %rax,%rax
  jne    L42
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %edx,%esi
L42:
  cmp    $0x27,%bl
  mov    %rcx,%rax
  setne  %dl
  lea    0x22(%rdx,%rdx,4),%edx
  cmp    %sil,%dl
  je     L1
  cmp    $0x1,%sil
  sbb    $0xfffffffffffffffe,%rax
L1:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  lea    0x1(%rax),%rcx
  test   %bl,%bl
  jne    L33
  add    $0x8,%rsp
  add    $0x2,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <strlen@plt>
  xchg   %ax,%ax
L46:
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: 	
 !"#$&'()*;<=>?[\]`{|}~

assistant: ```c
size_t shell_quote_length(const char *string) {
  if (string[0] == '\0')
    return 2;
  else if (strpbrk(string, "\t\n !\"#$&'()*;<=>?[\\]`{|}~") == NULL)
    return strlen(string);
  else {
    char qchar = '\0';
    size_t length = 0;
    for (; *string != '\0'; string++) {
      char c = *string;
      char q = (c == '\'' ? '"' : '\'');
      if (qchar != q) {
        if (qchar)
          length++;
        qchar = q;
        length++;
      }
      length++;
    }
    if (qchar)
      length++;
    return length;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<shell_quote_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L2
  lea    D5(%rip),%rsi
  mov    %rdi,%rbp
  call   <strpbrk@plt>
  xor    %ecx,%ecx
  xor    %esi,%esi
  test   %rax,%rax
  jne    L36
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %edx,%esi
L36:
  cmp    $0x27,%bl
  mov    %rcx,%rax
  setne  %dl
  lea    0x22(%rdx,%rdx,4),%edx
  cmp    %dl,%sil
  je     L25
  cmp    $0x1,%sil
  sbb    $0xfffffffffffffffe,%rax
L25:
  movzbl 0x1(%rbp),%ebx
  add    $0x1,%rbp
  lea    0x1(%rax),%rcx
  test   %bl,%bl
  jne    L17
  add    $0x8,%rsp
  add    $0x2,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <strlen@plt>
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  mov    $0x2,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D5: 	
 !"#$&'()*;<=>?[\]`{|}~

assistant: ```c
size_t shell_quote_length(const char *string) {
  if (string[0] == '\0')
    return 2;
  else if (strpbrk(string, "\t\n !\"#$&'()*;<=>?[\\]`{|}~") == NULL)
    return strlen(string);
  else {
    char qchar = '\0';
    size_t length = 0;
    for (; *string != '\0'; string++) {
      char c = *string;
      char q = (c == '\'' ? '"' : '\'');
      if (qchar != q) {
        if (qchar)
          length++;
        qchar = q;
        length++;
      }
      length++;
    }
    if (qchar)
      length++;
    return length;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_reverse_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L4:
  movb   $0x0,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x5,%eax
  and    $0x40,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  and    $0x20,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  and    $0x10,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    %eax
  and    $0x8,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x3,%eax
  and    $0x4,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sar    $0x5,%eax
  and    $0x2,%eax
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  add    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void array_reverse_bits(unsigned char data[], unsigned int size) {
  for (unsigned int i = 0; i < size; ++i) {
    unsigned char j = 0;
    j = (data[i] & 0x01) << 7;
    j += (data[i] & 0x02) << 5;
    j += (data[i] & 0x04) << 3;
    j += (data[i] & 0x08) << 1;
    j += (data[i] & 0x10) >> 1;
    j += (data[i] & 0x20) >> 3;
    j += (data[i] & 0x40) >> 5;
    j += (data[i] & 0x80) >> 7;
    data[i] = j;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<array_reverse_bits>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rdi
L4:
  movzbl (%rcx),%eax
  movzbl %al,%edx
  shr    $0x7,%al
  mov    %edx,%esi
  shl    $0x7,%esi
  add    %esi,%eax
  mov    %edx,%esi
  shl    $0x5,%esi
  and    $0x40,%esi
  add    %esi,%eax
  lea    0x0(,%rdx,8),%esi
  and    $0x20,%esi
  add    %esi,%eax
  lea    (%rdx,%rdx,1),%esi
  and    $0x10,%esi
  add    %esi,%eax
  mov    %edx,%esi
  sar    %esi
  and    $0x8,%esi
  add    %esi,%eax
  mov    %edx,%esi
  sar    $0x3,%esi
  and    $0x4,%esi
  add    %esi,%eax
  sar    $0x5,%edx
  and    $0x2,%edx
  add    %eax,%edx
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L4
L6:
  ret
```

assistant: ```c
void array_reverse_bits(unsigned char data[], unsigned int size) {
  for (unsigned int i = 0; i < size; ++i) {
    unsigned char j = 0;
    j = (data[i] & 0x01) << 7;
    j += (data[i] & 0x02) << 5;
    j += (data[i] & 0x04) << 3;
    j += (data[i] & 0x08) << 1;
    j += (data[i] & 0x10) >> 1;
    j += (data[i] & 0x20) >> 3;
    j += (data[i] & 0x40) >> 5;
    j += (data[i] & 0x80) >> 7;
    data[i] = j;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<array_reverse_bits>:
  endbr64
  test   %esi,%esi
  je     L5
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
L10:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%eax
  mov    %edx,%ecx
  shl    $0x7,%ecx
  shr    $0x7,%al
  add    %ecx,%eax
  mov    %edx,%ecx
  shl    $0x5,%ecx
  and    $0x40,%ecx
  add    %ecx,%eax
  lea    0x0(,%rdx,8),%ecx
  and    $0x20,%ecx
  add    %ecx,%eax
  lea    (%rdx,%rdx,1),%ecx
  and    $0x10,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  sar    %ecx
  and    $0x8,%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  sar    $0x5,%edx
  sar    $0x3,%ecx
  and    $0x2,%edx
  and    $0x4,%ecx
  add    %ecx,%eax
  add    %eax,%edx
  mov    %dl,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L10
L5:
  ret
```

assistant: ```c
void array_reverse_bits(unsigned char data[], unsigned int size) {
  for (unsigned int i = 0; i < size; ++i) {
    unsigned char j = 0;
    j = (data[i] & 0x01) << 7;
    j += (data[i] & 0x02) << 5;
    j += (data[i] & 0x04) << 3;
    j += (data[i] & 0x08) << 1;
    j += (data[i] & 0x10) >> 1;
    j += (data[i] & 0x20) >> 3;
    j += (data[i] & 0x40) >> 5;
    j += (data[i] & 0x80) >> 7;
    data[i] = j;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Nimsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x180,%rsp
  mov    %rdi,-0x168(%rbp)
  mov    %rsi,-0x170(%rbp)
  mov    %rdx,-0x178(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x150(%rbp),%rdx
  mov    -0x170(%rbp),%rcx
  mov    -0x168(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <trans@plt>
  mov    %eax,-0x15c(%rbp)
  lea    -0xb0(%rbp),%rdx
  mov    -0x178(%rbp),%rcx
  mov    -0x168(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <trans@plt>
  mov    %eax,-0x154(%rbp)
  mov    -0x15c(%rbp),%eax
  cmp    -0x154(%rbp),%eax
  jge    L28
  mov    -0x154(%rbp),%eax
  mov    %eax,-0x15c(%rbp)
L28:
  movl   $0x0,-0x158(%rbp)
  jmp    L37
L15:
  mov    -0x158(%rbp),%eax
  cltq
  mov    -0x150(%rbp,%rax,8),%rdx
  mov    -0x158(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,8),%rax
  add    %rdx,%rax
  cqto
  idivq  -0x168(%rbp)
  mov    -0x158(%rbp),%eax
  cltq
  mov    %rdx,-0x150(%rbp,%rax,8)
  addl   $0x1,-0x158(%rbp)
L37:
  cmpl   $0x13,-0x158(%rbp)
  jle    L15
  mov    -0x15c(%rbp),%edx
  lea    -0x150(%rbp),%rcx
  mov    -0x168(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vitrans@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
long Nimsum(long B, long x, long y) {
  long xf[20], yf[20];
  int xl, yl;
  int i;
  xl = trans(B, x, xf);
  yl = trans(B, y, yf);
  if (xl < yl) {
    xl = yl;
  }
  for (i = 0; i < 20; i++) {
    xf[i] = (xf[i] + yf[i]) % B;
  }
  return vitrans(B, xf, xl);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Nimsum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  call   <trans@plt>
  mov    %eax,%r13d
  lea    0xa0(%rsp),%r12
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <trans@plt>
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  mov    %rbx,%rcx
  mov    %r12,%rsi
  mov    %r12,%rdi
L11:
  mov    (%rsi),%rax
  add    (%rcx),%rax
  cqto
  idiv   %rbp
  mov    %rdx,(%rcx)
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rdi,%rcx
  jne    L11
  mov    %rsp,%rsi
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <vitrans@plt>
  mov    0x148(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Nimsum(long B, long x, long y) {
  long xf[20], yf[20];
  int xl, yl;
  int i;
  xl = trans(B, x, xf);
  yl = trans(B, y, yf);
  if (xl < yl) {
    xl = yl;
  }
  for (i = 0; i < 20; i++) {
    xf[i] = (xf[i] + yf[i]) % B;
  }
  return vitrans(B, xf, xl);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Nimsum>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0xa0(%rsp),%rbx
  mov    %r13,%rdx
  call   <trans@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <trans@plt>
  mov    %r13,%rcx
  mov    %rbx,%rsi
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  nopl   (%rax)
L19:
  mov    (%rsi),%rax
  add    (%rcx),%rax
  add    $0x8,%rcx
  add    $0x8,%rsi
  cqto
  idiv   %rbp
  mov    %rdx,-0x8(%rcx)
  cmp    %rbx,%rcx
  jne    L19
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <vitrans@plt>
  mov    0x148(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Nimsum(long B, long x, long y) {
  long xf[20], yf[20];
  int xl, yl;
  int i;
  xl = trans(B, x, xf);
  yl = trans(B, y, yf);
  if (xl < yl) {
    xl = yl;
  }
  for (i = 0; i < 20; i++) {
    xf[i] = (xf[i] + yf[i]) % B;
  }
  return vitrans(B, xf, xl);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Nimsum>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0xa0(%rsp),%rbx
  mov    %r13,%rdx
  call   <trans@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <trans@plt>
  mov    %r13,%rcx
  mov    %rbx,%rsi
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  nopl   (%rax)
L5:
  mov    (%rsi),%rax
  add    (%rcx),%rax
  add    $0x8,%rcx
  add    $0x8,%rsi
  cqto
  idiv   %rbp
  mov    %rdx,-0x8(%rcx)
  cmp    %rbx,%rcx
  jne    L5
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <vitrans@plt>
  mov    0x148(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long Nimsum(long B, long x, long y) {
  long xf[20], yf[20];
  int xl, yl;
  int i;
  xl = trans(B, x, xf);
  yl = trans(B, y, yf);
  if (xl < yl) {
    xl = yl;
  }
  for (i = 0; i < 20; i++) {
    xf[i] = (xf[i] + yf[i]) % B;
  }
  return vitrans(B, xf, xl);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RS232SetBaudRate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L19
L2:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <__rs232_set_baud@plt>
L19:
  leave
  ret
```

assistant: ```c
int RS232SetBaudRate(void *handle, int rate) {
  if (NULL == handle) {
    return -1;
  }
  return __rs232_set_baud(handle, rate);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RS232SetBaudRate>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <__rs232_set_baud@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int RS232SetBaudRate(void *handle, int rate) {
  if (NULL == handle) {
    return -1;
  }
  return __rs232_set_baud(handle, rate);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RS232SetBaudRate>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    1050 <__rs232_set_baud@plt>
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int RS232SetBaudRate(void *handle, int rate) {
  if (NULL == handle) {
    return -1;
  }
  return __rs232_set_baud(handle, rate);
}
```
user: Translate the below assembly code into C programming language:

```asm
<RS232SetBaudRate>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <__rs232_set_baud@plt>
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int RS232SetBaudRate(void *handle, int rate) {
  if (NULL == handle) {
    return -1;
  }
  return __rs232_set_baud(handle, rate);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getsample_constant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    %r9d,-0x1c(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  cmpl   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,D17(%rip)
L13:
  cmpl   $0x0,-0x18(%rbp)
  js     L22
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L22
  cmpl   $0x0,-0x1c(%rbp)
  js     L22
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L22
  cmpl   $0x0,0x10(%rbp)
  js     L22
  mov    0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L87
L22:
  movss  D17(%rip),%xmm0
  jmp    L34
L87:
  mov    -0x1c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
L34:
  pop    %rbp
  ret
```

assistant: ```c
float getsample_constant(float *x, int w, int h, int pd, int i, int j, int l) {
  static float value = 0;
  if (w == 0 && h == 0)
    value = *x;
  if (i < 0 || i >= w || j < 0 || j >= h || l < 0 || l >= pd)
    return value;
  return x[(i + j * w) * pd + l];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getsample_constant>:
  endbr64
  mov    %esi,%eax
  or     %edx,%esi
  jne    L23
  movss  (%rdi),%xmm0
  movss  %xmm0,D13(%rip)
L23:
  mov    %r9d,%esi
  or     0x8(%rsp),%esi
  or     %r8d,%esi
  js     L32
  cmp    %r8d,%eax
  jle    L32
  cmp    %r9d,%edx
  jle    L32
  cmp    %ecx,0x8(%rsp)
  jge    L32
  imul   %r9d,%eax
  add    %r8d,%eax
  imul   %ecx,%eax
  add    0x8(%rsp),%eax
  cltq
  movss  (%rdi,%rax,4),%xmm0
  ret
L32:
  movss  D13(%rip),%xmm0
  ret
```

assistant: ```c
float getsample_constant(float *x, int w, int h, int pd, int i, int j, int l) {
  static float value = 0;
  if (w == 0 && h == 0)
    value = *x;
  if (i < 0 || i >= w || j < 0 || j >= h || l < 0 || l >= pd)
    return value;
  return x[(i + j * w) * pd + l];
}
```
user: What is the c source code of the assembly code below?

```asm
<getsample_constant>:
  endbr64
  mov    %esi,%eax
  or     %edx,%esi
  jne    L1
  movss  (%rdi),%xmm0
  movss  %xmm0,D15(%rip)
L1:
  mov    0x8(%rsp),%esi
  or     %r9d,%esi
  or     %r8d,%esi
  js     L15
  cmp    %r8d,%eax
  jle    L15
  cmp    %r9d,%edx
  jle    L15
  cmp    %ecx,0x8(%rsp)
  jge    L15
  imul   %r9d,%eax
  add    %r8d,%eax
  imul   %ecx,%eax
  add    0x8(%rsp),%eax
  cltq
  movss  (%rdi,%rax,4),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movss  D15(%rip),%xmm0
  ret
```

assistant: ```c
float getsample_constant(float *x, int w, int h, int pd, int i, int j, int l) {
  static float value = 0;
  if (w == 0 && h == 0)
    value = *x;
  if (i < 0 || i >= w || j < 0 || j >= h || l < 0 || l >= pd)
    return value;
  return x[(i + j * w) * pd + l];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getsample_constant>:
  endbr64
  mov    %esi,%eax
  or     %edx,%esi
  jne    L22
  movss  (%rdi),%xmm0
  movss  %xmm0,D15(%rip)
L22:
  mov    0x8(%rsp),%esi
  or     %r9d,%esi
  or     %r8d,%esi
  js     L17
  cmp    %r8d,%eax
  jle    L17
  cmp    %r9d,%edx
  jle    L17
  cmp    %ecx,0x8(%rsp)
  jge    L17
  imul   %r9d,%eax
  add    %r8d,%eax
  imul   %ecx,%eax
  add    0x8(%rsp),%eax
  cltq
  movss  (%rdi,%rax,4),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movss  D15(%rip),%xmm0
  ret
```

assistant: ```c
float getsample_constant(float *x, int w, int h, int pd, int i, int j, int l) {
  static float value = 0;
  if (w == 0 && h == 0)
    value = *x;
  if (i < 0 || i >= w || j < 0 || j >= h || l < 0 || l >= pd)
    return value;
  return x[(i + j * w) * pd + l];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L11:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L19:
  cmpq   $0x0,-0x28(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *dest, int v, unsigned long len) {
  char *d = dest;
  for (; len; len--) {
    *(d++) = (char)v;
  }
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L1
  lea    (%rdi,%rdx,1),%rax
L15:
  add    $0x1,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rdi,%rax
  jne    L15
  ret
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int v, unsigned long len) {
  char *d = dest;
  for (; len; len--) {
    *(d++) = (char)v;
  }
  return d;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L6
  push   %rbx
  movsbl %sil,%esi
  mov    %rdx,%rbx
  call   <memset@plt>
  lea    (%rax,%rbx,1),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int v, unsigned long len) {
  char *d = dest;
  for (; len; len--) {
    *(d++) = (char)v;
  }
  return d;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L1
  push   %rbx
  movsbl %sil,%esi
  mov    %rdx,%rbx
  call   <memset@plt>
  lea    (%rax,%rbx,1),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *dest, int v, unsigned long len) {
  char *d = dest;
  for (; len; len--) {
    *(d++) = (char)v;
  }
  return d;
}
```