ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L49
  negl   -0x14(%rbp)
L49:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L39:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L39
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  subl   $0x1,-0x8(%rbp)
  jmp    L16
L42:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L16:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jg     L42
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itoa(int n, char s[], int w) {
  int i, j, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  j = w;
  do {
    s[i++] = n % 10 + '0';
    j--;
  } while ((n /= 10) > 0);
  if (sign < 0) {
    s[i++] = '-';
    j--;
  }
  while (j-- > 0)
    s[i++] = ' ';
  s[i] = '\0';
  reverse(s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<itoa>:
  endbr64
  push   %rbx
  mov    %edi,%r10d
  mov    %rsi,%r9
  mov    %edx,%r8d
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  mov    %rsi,%r11
  mov    $0x0,%edi
L9:
  mov    %edi,%ebx
  add    $0x1,%edi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%r11)
  mov    %r8d,%esi
  sub    $0x1,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  add    $0x1,%r11
  cmp    $0x9,%ecx
  jg     L9
  test   %r10d,%r10d
  js     L45
L11:
  lea    -0x1(%r8),%ecx
  test   %r8d,%r8d
  jle    L30
  movslq %edi,%rdx
  lea    (%r9,%rdx,1),%rax
  lea    0x1(%r9,%rdx,1),%rdx
  lea    -0x1(%r8),%esi
  add    %rsi,%rdx
L35:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L35
  lea    0x1(%rdi,%rcx,1),%edi
L30:
  movslq %edi,%rdi
  movb   $0x0,(%r9,%rdi,1)
  mov    %r9,%rdi
  call   <reverse@plt>
  pop    %rbx
  ret
L45:
  movslq %edi,%rdi
  movb   $0x2d,(%r9,%rdi,1)
  lea    -0x2(%rsi),%r8d
  lea    0x2(%rbx),%edi
  jmp    L11
```

assistant: ```c
void itoa(int n, char s[], int w) {
  int i, j, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  j = w;
  do {
    s[i++] = n % 10 + '0';
    j--;
  } while ((n /= 10) > 0);
  if (sign < 0) {
    s[i++] = '-';
    j--;
  }
  while (j-- > 0)
    s[i++] = ' ';
  s[i] = '\0';
  reverse(s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<itoa>:
  endbr64
  mov    %edi,%r9d
  mov    %edx,%edi
  push   %r12
  mov    %rsi,%r8
  mov    %r9d,%edx
  push   %rbp
  mov    $0xcccccccd,%r10d
  mov    %rsi,%rbp
  neg    %edx
  push   %rbx
  cmovs  %r9d,%edx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L18:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %ebx,%r11d
  imul   %r10,%rax
  add    $0x1,%ebx
  add    $0x1,%r8
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  mov    %edi,%esi
  sub    $0x1,%edi
  add    $0x30,%ecx
  mov    %cl,-0x1(%r8)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L18
  test   %r9d,%r9d
  jns    L24
  movslq %ebx,%rbx
  lea    -0x2(%rsi),%edi
  movb   $0x2d,0x0(%rbp,%rbx,1)
  lea    0x2(%r11),%ebx
L24:
  lea    -0x1(%rdi),%r12d
  test   %edi,%edi
  jle    L17
  movslq %ebx,%rdi
  mov    %r12d,%edx
  lea    0x1(%r12,%rbx,1),%ebx
  mov    $0x20,%esi
  add    $0x1,%rdx
  add    %rbp,%rdi
  call   <memset@plt>
L17:
  movslq %ebx,%rbx
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa(int n, char s[], int w) {
  int i, j, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  j = w;
  do {
    s[i++] = n % 10 + '0';
    j--;
  } while ((n /= 10) > 0);
  if (sign < 0) {
    s[i++] = '-';
    j--;
  }
  while (j-- > 0)
    s[i++] = ' ';
  s[i] = '\0';
  reverse(s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itoa>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  mov    %edi,%edx
  mov    %edi,%r8d
  neg    %edx
  push   %rbp
  mov    $0xcccccccd,%r9d
  mov    %rsi,%rbp
  cmovs  %edi,%edx
  push   %rbx
  mov    %rsi,%rdi
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %edx,%eax
  mov    %edx,%ecx
  mov    %ebx,%r10d
  imul   %r9,%rax
  add    $0x1,%ebx
  add    $0x1,%rdi
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  mov    %r12d,%esi
  sub    $0x1,%r12d
  add    $0x30,%ecx
  mov    %cl,-0x1(%rdi)
  mov    %edx,%ecx
  mov    %eax,%edx
  cmp    $0x9,%ecx
  jg     L12
  test   %r8d,%r8d
  jns    L28
  movslq %ebx,%rbx
  lea    -0x2(%rsi),%r12d
  movb   $0x2d,0x0(%rbp,%rbx,1)
  lea    0x2(%r10),%ebx
L28:
  test   %r12d,%r12d
  jle    L4
  movslq %ebx,%rdi
  movslq %r12d,%rdx
  mov    $0x20,%esi
  add    %r12d,%ebx
  add    %rbp,%rdi
  call   <memset@plt>
L4:
  movslq %ebx,%rbx
  mov    %rbp,%rdi
  movb   $0x0,0x0(%rbp,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <reverse@plt>
```

assistant: ```c
void itoa(int n, char s[], int w) {
  int i, j, sign;
  if ((sign = n) < 0)
    n = -n;
  i = 0;
  j = w;
  do {
    s[i++] = n % 10 + '0';
    j--;
  } while ((n /= 10) > 0);
  if (sign < 0) {
    s[i++] = '-';
    j--;
  }
  while (j-- > 0)
    s[i++] = ' ';
  s[i] = '\0';
  reverse(s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdr_u_int16_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L87
  cmp    $0x82,%eax
  jg     L48
  cmp    $0x80,%eax
  je     L46
  cmp    $0x81,%eax
  jne    L48
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rcx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  jmp    L2
L87:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rax),%rcx
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L31
  mov    $0x0,%eax
  jmp    L2
L31:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L2
L46:
  mov    $0x1,%eax
  jmp    L2
L48:
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
bool_t xdr_u_int16_t(XDR *xdrs, uint16_t *u_int16_p) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*u_int16_p;
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, (long *)&l)) {
      return (0);
    }
    *u_int16_p = (uint16_t)l;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdr_u_int16_t>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L43
  cmp    $0x82,%eax
  je     L20
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
L43:
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L8
L20:
  lea    0x4(%rsp),%rsi
  mov    0x8(%rdi),%rax
  call   *0x8(%rax)
  test   %eax,%eax
  je     L8
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L8
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int16_t(XDR *xdrs, uint16_t *u_int16_p) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*u_int16_p;
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, (long *)&l)) {
      return (0);
    }
    *u_int16_p = (uint16_t)l;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdr_u_int16_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L50
  cmp    $0x82,%eax
  je     L0
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x8(%rdi),%rax
  lea    0x4(%rsp),%rsi
  call   *0x8(%rax)
  test   %eax,%eax
  je     L12
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L12
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int16_t(XDR *xdrs, uint16_t *u_int16_p) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*u_int16_p;
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, (long *)&l)) {
      return (0);
    }
    *u_int16_p = (uint16_t)l;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xdr_u_int16_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L39
  cmp    $0x82,%eax
  je     L50
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%rsi),%eax
  lea    0x4(%rsp),%rsi
  mov    %eax,0x4(%rsp)
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L50:
  mov    0x8(%rdi),%rax
  lea    0x4(%rsp),%rsi
  call   *0x8(%rax)
  test   %eax,%eax
  je     L21
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L21
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_u_int16_t(XDR *xdrs, uint16_t *u_int16_p) {
  u_long l;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    l = (u_long)*u_int16_p;
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, (long *)&l));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, (long *)&l)) {
      return (0);
    }
    *u_int16_p = (uint16_t)l;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_escape_isDec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L76
L62:
  cmpb   $0x2f,-0xd(%rbp)
  jle    L92
  cmpb   $0x39,-0xd(%rbp)
  jle    L24
L92:
  cmpb   $0x40,-0xd(%rbp)
  jle    L3
  cmpb   $0x46,-0xd(%rbp)
  jle    L24
L3:
  cmpb   $0x60,-0xd(%rbp)
  jle    L19
  cmpb   $0x66,-0xd(%rbp)
  jle    L24
L19:
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L82
L24:
  movl   $0x0,-0xc(%rbp)
L76:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  je     L82
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L62
L82:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str_escape_isDec(char *ptr, unsigned int len) {
  char *temp = ptr;
  char c = '\0';
  int flag = -1;
  while ((c = *temp++) != '\0' && len-- > 0) {
    if ((c < '0' || c > '9') && (c < 'A' || c > 'F') && (c < 'a' || c > 'f')) {
      flag = -1;
      break;
    }
    flag = 0;
  }
  return flag;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_escape_isDec>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L37
  mov    %edx,%edx
  lea    0x2(%rdi,%rdx,1),%rsi
  jmp    L29
L26:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  je     L23
  cmp    %rcx,%rsi
  je     L5
L29:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L26
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L26
  mov    $0xffffffff,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L7:
  mov    $0xffffffff,%eax
  ret
L37:
  mov    $0xffffffff,%eax
  ret
L23:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int str_escape_isDec(char *ptr, unsigned int len) {
  char *temp = ptr;
  char c = '\0';
  int flag = -1;
  while ((c = *temp++) != '\0' && len-- > 0) {
    if ((c < '0' || c > '9') && (c < 'A' || c > 'F') && (c < 'a' || c > 'f')) {
      flag = -1;
      break;
    }
    flag = 0;
  }
  return flag;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_escape_isDec>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L1
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L1
  lea    0x2(%rdi,%rdx,1),%rsi
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L40
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L40
L1:
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L3
  cmp    %rsi,%rcx
  jne    L45
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_escape_isDec(char *ptr, unsigned int len) {
  char *temp = ptr;
  char c = '\0';
  int flag = -1;
  while ((c = *temp++) != '\0' && len-- > 0) {
    if ((c < '0' || c > '9') && (c < 'A' || c > 'F') && (c < 'a' || c > 'f')) {
      flag = -1;
      break;
    }
    flag = 0;
  }
  return flag;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_escape_isDec>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L45
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L45
  lea    0x2(%rdi,%rdx,1),%rsi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L58
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L58
L45:
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L16
  cmp    %rsi,%rcx
  jne    L18
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_escape_isDec(char *ptr, unsigned int len) {
  char *temp = ptr;
  char c = '\0';
  int flag = -1;
  while ((c = *temp++) != '\0' && len-- > 0) {
    if ((c < '0' || c > '9') && (c < 'A' || c > 'F') && (c < 'a' || c > 'f')) {
      flag = -1;
      break;
    }
    flag = 0;
  }
  return flag;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<findAllPlain>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
L137:
  mov    0x8(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x0,0x1c(%rsp)
  mov    $0x0,%r15d
  jmp    L149
L78:
  cmpl   $0x0,0x20(%rsp)
  jne    L130
  mov    $0x1,%eax
L30:
  mov    %eax,%ebp
  add    $0x1,%rax
  cmpl   $0x0,-0x4(%r13,%rax,4)
  je     L30
L130:
  add    $0x1,%ebp
  mov    %ebp,(%r14,%rbx,4)
  addl   $0x1,0x1c(%rsp)
L15:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L19
L103:
  mov    (%r14,%rbx,4),%ebp
  test   %ebp,%ebp
  jne    L15
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    0x8(%rsp),%rdi
  call   <checkspot@plt>
  cmp    $0x1,%eax
  je     L78
  jle    L15
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    0x8(%rsp),%rdi
  call   <checkElim@plt>
  test   %eax,%eax
  js     L15
  add    $0x1,%eax
  mov    %eax,(%r14,%rbx,4)
  addl   $0x1,0x1c(%rsp)
  jmp    L15
L19:
  add    $0x1,%r15d
  addq   $0x24,0x10(%rsp)
  cmp    $0x9,%r15d
  je     L75
L149:
  mov    0x10(%rsp),%r14
  mov    $0x0,%ebx
  jmp    L103
L75:
  cmpl   $0x0,0x1c(%rsp)
  jg     L137
  mov    0x8(%rsp),%rax
  lea    0x24(%rax),%rcx
  lea    0x168(%rax),%rsi
  mov    $0x0,%edx
L97:
  lea    -0x24(%rcx),%rax
L70:
  cmpl   $0x1,(%rax)
  adc    $0x0,%edx
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L70
  add    $0x24,%rcx
  cmp    %rcx,%rsi
  jne    L97
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %edx,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findAllPlain(int x[9][9]) {
  int possible_mask[9];
  int num_possible;
  int i, j, k;
  int num_found;
  int rounds = 0;
  do {
    num_found = 0;
    for (i = 0; i < 9; i++) {
      for (j = 0; j < 9; j++) {
        if (x[i][j] != 0)
          continue;
        num_possible = checkspot(x, i, j, possible_mask);
        if (num_possible == 1) {
          for (k = 0; possible_mask[k] == 0; k++)
            ;
          x[i][j] = k + 1;
          num_found++;
        } else if (num_possible > 1) {
          k = checkElim(x, i, j, possible_mask);
          if (k >= 0) {
            x[i][j] = k + 1;
            num_found++;
          }
        }
      }
    }
    rounds++;
  } while (num_found > 0);
  int num_empty = 0;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9; j++)
      if (x[i][j] == 0)
        num_empty++;
  return num_empty;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findAllPlain>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r15
  nopw   0x0(%rax,%rax,1)
L75:
  movl   $0x0,0xc(%rsp)
  mov    %rbp,%r14
  xor    %r12d,%r12d
  xchg   %ax,%ax
L79:
  xor    %ebx,%ebx
  jmp    L2
  nopl   0x0(%rax)
L115:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L16
L2:
  mov    (%r14,%rbx,4),%edi
  test   %edi,%edi
  jne    L115
  mov    %r15,%rcx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <checkspot@plt>
  cmp    $0x1,%eax
  je     L143
  jle    L115
  mov    %r15,%rcx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <checkElim@plt>
  test   %eax,%eax
  js     L115
L46:
  add    $0x1,%eax
L89:
  mov    %eax,(%r14,%rbx,4)
  add    $0x1,%rbx
  addl   $0x1,0xc(%rsp)
  cmp    $0x9,%rbx
  jne    L2
  nop
L16:
  add    $0x1,%r12d
  add    $0x24,%r14
  cmp    $0x9,%r12d
  jne    L79
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jne    L75
  lea    0x24(%rbp),%rdx
  add    $0x168,%rbp
  nopl   (%rax)
L99:
  lea    -0x24(%rdx),%rax
  nopl   0x0(%rax)
L68:
  cmpl   $0x1,(%rax)
  adcl   $0x0,0xc(%rsp)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L68
  add    $0x24,%rdx
  cmp    %rdx,%rbp
  jne    L99
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L128
  mov    0xc(%rsp),%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L143:
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  jne    L89
  mov    $0x1,%edx
  nopl   0x0(%rax)
L23:
  mov    %edx,%eax
  add    $0x1,%rdx
  mov    -0x4(%r15,%rdx,4),%ecx
  test   %ecx,%ecx
  je     L23
  jmp    L46
L128:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findAllPlain(int x[9][9]) {
  int possible_mask[9];
  int num_possible;
  int i, j, k;
  int num_found;
  int rounds = 0;
  do {
    num_found = 0;
    for (i = 0; i < 9; i++) {
      for (j = 0; j < 9; j++) {
        if (x[i][j] != 0)
          continue;
        num_possible = checkspot(x, i, j, possible_mask);
        if (num_possible == 1) {
          for (k = 0; possible_mask[k] == 0; k++)
            ;
          x[i][j] = k + 1;
          num_found++;
        } else if (num_possible > 1) {
          k = checkElim(x, i, j, possible_mask);
          if (k >= 0) {
            x[i][j] = k + 1;
            num_found++;
          }
        }
      }
    }
    rounds++;
  } while (num_found > 0);
  int num_empty = 0;
  for (i = 0; i < 9; i++)
    for (j = 0; j < 9; j++)
      if (x[i][j] == 0)
        num_empty++;
  return num_empty;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<load>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L4:
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L22:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x270f,-0xc(%rbp)
  jle    L22
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D22
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: D19: r

tool: D22: cannot open file


tool: D17: %lf,

assistant: ```c
void load(double N[10000], char path[]) {
  FILE *fp;
  int i;
  if ((fp = fopen(path, "r")) == NULL) {
    printf("cannot open file\n");
    return;
  }
  for (i = 0; i < 10000; i++) {
    fscanf(fp, "%lf,", &N[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<load>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %r12,%rbx
  add    $0x13880,%r12
  lea    D28(%rip),%r13
  test   %rax,%rax
  je     L28
L11:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L11
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D14
datatype: string

tool: D13: r

tool: D28: %lf,

tool: D14: cannot open file


assistant: ```c
void load(double N[10000], char path[]) {
  FILE *fp;
  int i;
  if ((fp = fopen(path, "r")) == NULL) {
    printf("cannot open file\n");
    return;
  }
  for (i = 0; i < 10000; i++) {
    fscanf(fp, "%lf,", &N[i]);
  }
}
```