ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_keygen_assist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0xff,%esi
  mov    %eax,%edi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp1 = _mm_xor_si128(temp1, temp2);
  return temp1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aes_keygen_assist>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    $0xff,%esi
  call   <_mm_shuffle_epi32@plt>
  mov    %eax,%r12d
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%ebp
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%ebp
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <_mm_slli_si128@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%edi
  mov    %r12d,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp1 = _mm_xor_si128(temp1, temp2);
  return temp1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_keygen_assist>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  mov    $0xff,%esi
  push   %rbp
  call   <_mm_shuffle_epi32@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %eax,%r13d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbp
  mov    %r13d,%esi
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp1 = _mm_xor_si128(temp1, temp2);
  return temp1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aes_keygen_assist>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  mov    $0xff,%esi
  push   %rbp
  call   <_mm_shuffle_epi32@plt>
  mov    %r12d,%edi
  mov    $0x4,%esi
  mov    %eax,%r13d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %eax,%r12d
  call   <_mm_slli_si128@plt>
  mov    %r12d,%edi
  mov    %eax,%esi
  call   <_mm_xor_si128@plt>
  pop    %rbp
  mov    %r13d,%esi
  pop    %r12
  mov    %eax,%edi
  pop    %r13
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i aes_keygen_assist(__m128i temp1, __m128i temp2) {
  __m128i temp3;
  temp2 = _mm_shuffle_epi32(temp2, 0xff);
  temp3 = _mm_slli_si128(temp1, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp3 = _mm_slli_si128(temp3, 0x4);
  temp1 = _mm_xor_si128(temp1, temp3);
  temp1 = _mm_xor_si128(temp1, temp2);
  return temp1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getuint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
unsigned int getuint(unsigned int x) {
  char *p1, *p2;
  unsigned int y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[3] = p1[0];
  p2[2] = p1[1];
  p2[1] = p1[2];
  p2[0] = p1[3];
  return (y);
}
```
user: What is the c source code of the assembly code below:

```asm
<getuint>:
  endbr64
  mov    %edi,%edx
  movzbl %dh,%ecx
  shl    $0x10,%ecx
  mov    %edi,%eax
  shl    $0x18,%eax
  or     %ecx,%eax
  mov    %edi,%ecx
  shl    $0x8,%ecx
  sar    $0x18,%ecx
  mov    %cl,%ah
  sar    $0x18,%edx
  mov    %dl,%al
  ret
```

assistant: ```c
unsigned int getuint(unsigned int x) {
  char *p1, *p2;
  unsigned int y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[3] = p1[0];
  p2[2] = p1[1];
  p2[1] = p1[2];
  p2[0] = p1[3];
  return (y);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getuint>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int getuint(unsigned int x) {
  char *p1, *p2;
  unsigned int y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[3] = p1[0];
  p2[2] = p1[1];
  p2[1] = p1[2];
  p2[0] = p1[3];
  return (y);
}
```
user: What is the c source code of the assembly code below?

```asm
<getuint>:
  endbr64
  mov    %edi,%eax
  bswap  %eax
  ret
```

assistant: ```c
unsigned int getuint(unsigned int x) {
  char *p1, *p2;
  unsigned int y;
  p1 = (char *)(&x);
  p2 = (char *)(&y);
  p2[3] = p1[0];
  p2[2] = p1[1];
  p2[1] = p1[2];
  p2[0] = p1[3];
  return (y);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L47
  cmpl   $0x3e8,-0x14(%rbp)
  jle    L19
L47:
  movl   $0x10,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L16
L27:
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int main() {
  int length = __VERIFIER_nondet_int();
  if (length < 1 || length > 1000)
    length = 16;
  int *arr = alloca(length * sizeof(int));
  if (arr == 0)
    return 0;
  arr[0] = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x3e8,%edx
  mov    $0x10,%edx
  cmovae %edx,%eax
  lea    0x0(,%rax,4),%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L13
  movl   $0x0,(%rax)
L13:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  leave
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int length = __VERIFIER_nondet_int();
  if (length < 1 || length > 1000)
    length = 16;
  int *arr = alloca(length * sizeof(int));
  if (arr == 0)
    return 0;
  arr[0] = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x3e8,%edx
  mov    $0x10,%edx
  cmovae %edx,%eax
  lea    0x0(,%rax,4),%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L7
  movl   $0x0,(%rax)
L7:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  leave
  xor    %eax,%eax
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int length = __VERIFIER_nondet_int();
  if (length < 1 || length > 1000)
    length = 16;
  int *arr = alloca(length * sizeof(int));
  if (arr == 0)
    return 0;
  arr[0] = 0;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  lea    -0x1(%rax),%edx
  cmp    $0x3e8,%edx
  mov    $0x10,%edx
  cmovae %edx,%eax
  lea    0x0(,%rax,4),%edi
  call   <alloca@plt>
  test   %rax,%rax
  je     L2
  movl   $0x0,(%rax)
L2:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  leave
  xor    %eax,%eax
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int length = __VERIFIER_nondet_int();
  if (length < 1 || length > 1000)
    length = 16;
  int *arr = alloca(length * sizeof(int));
  if (arr == 0)
    return 0;
  arr[0] = 0;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int hoge = 5;
  void *hoge_p;
  hoge_p = &hoge;
  printf("%d\n", *(int *)hoge_p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int hoge = 5;
  void *hoge_p;
  hoge_p = &hoge;
  printf("%d\n", *(int *)hoge_p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int hoge = 5;
  void *hoge_p;
  hoge_p = &hoge;
  printf("%d\n", *(int *)hoge_p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int hoge = 5;
  void *hoge_p;
  hoge_p = &hoge;
  printf("%d\n", *(int *)hoge_p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void reverse(char s[]) {
  int startChar = 0;
  int endChar = strlen(s) - 1;
  while (startChar < endChar) {
    int tmpChar = s[endChar];
    s[endChar] = s[startChar];
    s[startChar] = tmpChar;
    startChar++;
    endChar--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L5
  cltq
  mov    $0x0,%edx
L12:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L12
L5:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int startChar = 0;
  int endChar = strlen(s) - 1;
  while (startChar < endChar) {
    int tmpChar = s[endChar];
    s[endChar] = s[startChar];
    s[startChar] = tmpChar;
    startChar++;
    endChar--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L2
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L19:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rbx,%rax,1)
  sub    $0x1,%rax
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %eax,%edx
  jl     L19
L2:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int startChar = 0;
  int endChar = strlen(s) - 1;
  while (startChar < endChar) {
    int tmpChar = s[endChar];
    s[endChar] = s[startChar];
    s[startChar] = tmpChar;
    startChar++;
    endChar--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L3
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rbx,%rax,1)
  sub    $0x1,%rax
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L6
L3:
  pop    %rbx
  ret
```

assistant: ```c
void reverse(char s[]) {
  int startChar = 0;
  int endChar = strlen(s) - 1;
  while (startChar < endChar) {
    int tmpChar = s[endChar];
    s[endChar] = s[startChar];
    s[startChar] = tmpChar;
    startChar++;
    endChar--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<default_hash_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x6,%rax
  sub    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x11,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x9,%rax
  sub    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  sub    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xa,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0xf,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t default_hash_func(const void *key) {
  size_t a = *((size_t *)key);
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<default_hash_func>:
  endbr64
  mov    (%rdi),%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x11,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x9,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  xor    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xf,%rax
  xor    %rdx,%rax
  ret
```

assistant: ```c
size_t default_hash_func(const void *key) {
  size_t a = *((size_t *)key);
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<default_hash_func>:
  endbr64
  mov    (%rdi),%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x11,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x9,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  xor    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xf,%rax
  xor    %rdx,%rax
  ret
```

assistant: ```c
size_t default_hash_func(const void *key) {
  size_t a = *((size_t *)key);
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<default_hash_func>:
  endbr64
  mov    (%rdi),%rax
  mov    %rax,%rdx
  shl    $0x6,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x11,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x9,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  xor    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  xor    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xf,%rax
  xor    %rdx,%rax
  ret
```

assistant: ```c
size_t default_hash_func(const void *key) {
  size_t a = *((size_t *)key);
  a -= (a << 6);
  a ^= (a >> 17);
  a -= (a << 9);
  a ^= (a << 4);
  a -= (a << 3);
  a ^= (a << 10);
  a ^= (a >> 15);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<place_pivot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L22:
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%r8
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   *%r8
  test   %eax,%eax
  je     L9
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%r8
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   *%r8
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%r8
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   *%r8
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L9:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L22
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int place_pivot(void *array, int low, int high, int Compare(void *, int, int), void Swap(void *, int, int)) {
  int pivot = low;
  int switch_i;
  int i;
  for (switch_i = low + 1, i = low + 1; i <= high; i++) {
    if (Compare(array, i, pivot)) {
      Swap(array, i, switch_i);
      Swap(array, pivot, switch_i);
      pivot++;
      switch_i++;
    }
  }
  return pivot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<place_pivot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebp
  mov    %edx,0xc(%rsp)
  lea    0x1(%rsi),%r13d
  cmp    %edx,%r13d
  jg     L5
  mov    %rdi,%r12
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %r13d,%ebx
  jmp    L22
L8:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jl     L5
L22:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   *%r14
  test   %eax,%eax
  je     L8
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   *%r15
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   *%r15
  add    $0x1,%ebp
  add    $0x1,%r13d
  jmp    L8
L5:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int place_pivot(void *array, int low, int high, int Compare(void *, int, int), void Swap(void *, int, int)) {
  int pivot = low;
  int switch_i;
  int i;
  for (switch_i = low + 1, i = low + 1; i <= high; i++) {
    if (Compare(array, i, pivot)) {
      Swap(array, i, switch_i);
      Swap(array, pivot, switch_i);
      pivot++;
      switch_i++;
    }
  }
  return pivot;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<place_pivot>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  cmp    %edx,%r12d
  jg     L0
  mov    %rdi,%rbp
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    %r12d,%ebx
  xchg   %ax,%ax
L2:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   *%r14
  test   %eax,%eax
  je     L12
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   *%r15
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   *%r15
  add    $0x1,%r13d
  add    $0x1,%r12d
L12:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jge    L2
L0:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int place_pivot(void *array, int low, int high, int Compare(void *, int, int), void Swap(void *, int, int)) {
  int pivot = low;
  int switch_i;
  int i;
  for (switch_i = low + 1, i = low + 1; i <= high; i++) {
    if (Compare(array, i, pivot)) {
      Swap(array, i, switch_i);
      Swap(array, pivot, switch_i);
      pivot++;
      switch_i++;
    }
  }
  return pivot;
}
```