ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L26
  mov    $0x1,%eax
L0:
  test   %dl,%dl
  je     L22
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  je     L0
  mov    $0x1,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while ((*a) == (*b)) {
    if (*a == 0)
      return 0;
    a++;
    b++;
  };
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L35
  mov    $0x1,%eax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L35
L3:
  test   %dl,%dl
  jne    L19
  xor    %eax,%eax
  ret
  nopl   (%rax)
L35:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while ((*a) == (*b)) {
    if (*a == 0)
      return 0;
    a++;
    b++;
  };
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L28
  mov    $0x1,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L28
L35:
  test   %dl,%dl
  jne    L38
  xor    %eax,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmp(const char *a, const char *b) {
  while ((*a) == (*b)) {
    if (*a == 0)
      return 0;
    a++;
    b++;
  };
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1e,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x4d,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L0:
  movl   $0x64,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cmp    $0x20,%eax
  jle    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string

tool: D32: x in outer block: %d


tool: D6: x in inner block: %d


tool: D26: x in while loop: %d


assistant: ```c
int main() {
  int x = 30;
  printf("x in outer block: %d\n", x);
  {
    int x = 77;
    printf("x in inner block: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  while (x++ < 33) {
    int x = 100;
    x++;
    printf("x in while loop: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1e,%esi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x1e,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x65,%esi
  lea    D27(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x65,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x65,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x22,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D27
type: string

tool: D12: x in outer block: %d


tool: D26: x in inner block: %d


tool: D27: x in while loop: %d


assistant: ```c
int main() {
  int x = 30;
  printf("x in outer block: %d\n", x);
  {
    int x = 77;
    printf("x in inner block: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  while (x++ < 33) {
    int x = 100;
    x++;
    printf("x in while loop: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1e,%esi
  lea    D6(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x4d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1e,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x22,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string

tool: D6: x in while loop: %d


tool: D1: x in outer block: %d


tool: D25: x in inner block: %d


assistant: ```c
int main() {
  int x = 30;
  printf("x in outer block: %d\n", x);
  {
    int x = 77;
    printf("x in inner block: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  while (x++ < 33) {
    int x = 100;
    x++;
    printf("x in while loop: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1e,%esi
  lea    D1(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x4d,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1e,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x65,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x22,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D25
data_type: string
name: parse_data
arguments: label: D28
data_type: string

tool: D1: x in while loop: %d


tool: D25: x in outer block: %d


tool: D28: x in inner block: %d


assistant: ```c
int main() {
  int x = 30;
  printf("x in outer block: %d\n", x);
  {
    int x = 77;
    printf("x in inner block: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  while (x++ < 33) {
    int x = 100;
    x++;
    printf("x in while loop: %d\n", x);
  }
  printf("x in outer block: %d\n", x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<IcsFGetStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L67:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  cmpl   $0xd,-0x4(%rbp)
  jne    L108
  cmpb   $0xa,-0x20(%rbp)
  jne    L108
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  movsbl -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  je     L108
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L108
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movl   $0xd,-0x4(%rbp)
L108:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    %al,-0x20(%rbp)
  je     L18
L41:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L67
  jmp    L87
L64:
  nop
  jmp    L87
L18:
  nop
L87:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x8(%rbp)
  je     L106
  mov    -0x18(%rbp),%rax
  jmp    L84
L106:
  mov    $0x0,%eax
L84:
  leave
  ret
```

assistant: ```c
char *IcsFGetStr(char *line, int n, FILE *fi, char sep) {
  int ii = 0;
  int ch;
  while (ii < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[ii] = (char)ch;
    ii++;
    if ((char)ch == sep)
      break;
  }
  line[ii] = '\0';
  if (ii != 0) {
    return line;
  } else
    return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IcsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%r15d
  jmp    L58
L44:
  mov    %al,(%r14,%rbx,1)
  mov    0xc(%rsp),%ebp
  add    $0x1,%ebp
  cmp    %r12b,%al
  je     L88
L66:
  add    $0x1,%rbx
L58:
  mov    %ebx,0xc(%rsp)
  mov    %ebx,%ebp
  cmp    %ebx,%r15d
  jle    L88
  mov    %r13,%rdi
  call   <getc@plt>
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L88
  cmp    $0xd,%eax
  jne    L44
  cmp    $0xa,%r12b
  jne    L44
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L70
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L44
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,(%r14,%rbx,1)
  jmp    L66
L70:
  movslq %ebp,%rax
  movb   $0xa,(%r14,%rax,1)
  add    $0x1,%ebp
L88:
  movslq %ebp,%rax
  movb   $0x0,(%r14,%rax,1)
  test   %ebp,%ebp
  mov    $0x0,%eax
  cmove  %rax,%r14
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *IcsFGetStr(char *line, int n, FILE *fi, char sep) {
  int ii = 0;
  int ch;
  while (ii < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[ii] = (char)ch;
    ii++;
    if ((char)ch == sep)
      break;
  }
  line[ii] = '\0';
  if (ii != 0) {
    return line;
  } else
    return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<IcsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r14d,%r14d
  jle    L101
  mov    D8(%rip),%r15
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L56:
  cmp    $0xa,%r12b
  jne    L7
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L94
  cmp    %eax,(%r15)
  je     L7
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,0x0(%rbp)
  nopw   0x0(%rax,%rax,1)
L107:
  add    $0x1,%rbp
  cmp    %ebx,%r14d
  je     L104
L102:
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    %eax,(%r15)
  je     L24
  add    $0x1,%ebx
  cmp    $0xd,%eax
  je     L56
L7:
  mov    %al,0x0(%rbp)
  cmp    %r12b,%al
  jne    L107
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L59:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L24:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  test   %ebx,%ebx
  jne    L61
L110:
  xor    %eax,%eax
L61:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0xa,0x0(%rbp)
  movb   $0x0,(%rax,%rbx,1)
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L104:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r14
  movb   $0x0,(%rax,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  jmp    L110
```

assistant: ```c
char *IcsFGetStr(char *line, int n, FILE *fi, char sep) {
  int ii = 0;
  int ch;
  while (ii < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[ii] = (char)ch;
    ii++;
    if ((char)ch == sep)
      break;
  }
  line[ii] = '\0';
  if (ii != 0) {
    return line;
  } else
    return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IcsFGetStr>:
  endbr64
  push   %r15
  push   %r14
  lea    -0x1(%rsi),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %r14d,%r14d
  jle    L41
  mov    D7(%rip),%r15
  mov    %rdx,%r13
  mov    %ecx,%r12d
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L91:
  cmp    $0xa,%r12b
  jne    L114
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  je     L68
  cmp    %eax,(%r15)
  je     L114
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movb   $0xd,0x0(%rbp)
  nopw   0x0(%rax,%rax,1)
L93:
  add    $0x1,%rbp
  cmp    %ebx,%r14d
  je     L99
L89:
  mov    %r13,%rdi
  call   <getc@plt>
  cmp    %eax,(%r15)
  je     L83
  add    $0x1,%ebx
  cmp    $0xd,%eax
  je     L91
L114:
  mov    %al,0x0(%rbp)
  cmp    %r12b,%al
  jne    L93
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
L78:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L83:
  movb   $0x0,0x0(%rbp)
  mov    0x8(%rsp),%rax
  test   %ebx,%ebx
  jne    L109
L49:
  xor    %eax,%eax
L109:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  mov    0x8(%rsp),%rax
  movslq %ebx,%rbx
  movb   $0xa,0x0(%rbp)
  movb   $0x0,(%rax,%rbx,1)
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L99:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r14
  movb   $0x0,(%rax,%r14,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  movb   $0x0,(%rdi)
  jmp    L49
```

assistant: ```c
char *IcsFGetStr(char *line, int n, FILE *fi, char sep) {
  int ii = 0;
  int ch;
  while (ii < n - 1) {
    ch = getc(fi);
    if (ch == EOF)
      break;
    if (ch == '\r' && sep == '\n') {
      ch = getc(fi);
      if (ch != sep && ch != EOF) {
        ungetc(ch, fi);
        ch = '\r';
      }
    }
    line[ii] = (char)ch;
    ii++;
    if ((char)ch == sep)
      break;
  }
  line[ii] = '\0';
  if (ii != 0) {
    return line;
  } else
    return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
  cmpl   $0x0,-0x4(%rbp)
  jg     L3
  mov    $0x0,%eax
  jmp    L18
L3:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int main(int n) {
  for (int n = 0; n < 1; n++) {
    int n;
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int n) {
  for (int n = 0; n < 1; n++) {
    int n;
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int n) {
  for (int n = 0; n < 1; n++) {
    int n;
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int n) {
  for (int n = 0; n < 1; n++) {
    int n;
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <get_symmetric_letter@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %c


assistant: ```c
int main() {
  char input_letter = getchar();
  printf("%c\n", get_symmetric_letter(input_letter));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <get_symmetric_letter@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: %c


assistant: ```c
int main() {
  char input_letter = getchar();
  printf("%c\n", get_symmetric_letter(input_letter));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <get_symmetric_letter@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: %c


assistant: ```c
int main() {
  char input_letter = getchar();
  printf("%c\n", get_symmetric_letter(input_letter));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <get_symmetric_letter@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: %c


assistant: ```c
int main() {
  char input_letter = getchar();
  printf("%c\n", get_symmetric_letter(input_letter));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isr_memfault>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L5:
  jmp    L5
```

assistant: ```c
void isr_memfault(void) {
  while (1)
    ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isr_memfault>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
void isr_memfault(void) {
  while (1)
    ;
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isr_memfault>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void isr_memfault(void) {
  while (1)
    ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isr_memfault>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void isr_memfault(void) {
  while (1)
    ;
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x8(%rbp)
  movl   $0x10030,-0x4(%rbp)
  shll   -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 0x10030;
  a <<= 1;
  b >>= a;
  return a + b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x4a,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 0x10030;
  a <<= 1;
  b >>= a;
  return a + b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x4a,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 0x10030;
  a <<= 1;
  b >>= a;
  return a + b;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x4a,%eax
  ret
```

assistant: ```c
int main(void) {
  int a = 5;
  int b = 0x10030;
  a <<= 1;
  b >>= a;
  return a + b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initGlut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <glutInitDisplayMode@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <glutDisplayFunc@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <glutKeyboardFunc@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <glutSpecialFunc@plt>
  nop
  leave
  ret
```

assistant: ```c
void initGlut(void (*cbDisplay)(void), void (*cbKeyboard)(unsigned char ucKey, int iX, int iY), void (*cbKeyboardSpecial)(int iKey, int iX, int iY)) {
  glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB | GLUT_DEPTH);
  glutDisplayFunc(cbDisplay);
  glutKeyboardFunc(cbKeyboard);
  glutSpecialFunc(cbKeyboardSpecial);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initGlut>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  mov    D12(%rip),%rax
  or     (%rax),%edi
  mov    D9(%rip),%rax
  or     (%rax),%edi
  call   <glutInitDisplayMode@plt>
  mov    %r12,%rdi
  call   <glutDisplayFunc@plt>
  mov    %rbp,%rdi
  call   <glutKeyboardFunc@plt>
  mov    %rbx,%rdi
  call   <glutSpecialFunc@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void initGlut(void (*cbDisplay)(void), void (*cbKeyboard)(unsigned char ucKey, int iX, int iY), void (*cbKeyboardSpecial)(int iKey, int iX, int iY)) {
  glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB | GLUT_DEPTH);
  glutDisplayFunc(cbDisplay);
  glutKeyboardFunc(cbKeyboard);
  glutSpecialFunc(cbKeyboardSpecial);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<initGlut>:
  endbr64
  mov    D18(%rip),%rax
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    (%rax),%edi
  mov    %rdx,%rbp
  mov    D21(%rip),%rax
  or     (%rax),%edi
  mov    D11(%rip),%rax
  or     (%rax),%edi
  call   <glutInitDisplayMode@plt>
  mov    %r13,%rdi
  call   <glutDisplayFunc@plt>
  mov    %r12,%rdi
  call   <glutKeyboardFunc@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <glutSpecialFunc@plt>
```

assistant: ```c
void initGlut(void (*cbDisplay)(void), void (*cbKeyboard)(unsigned char ucKey, int iX, int iY), void (*cbKeyboardSpecial)(int iKey, int iX, int iY)) {
  glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB | GLUT_DEPTH);
  glutDisplayFunc(cbDisplay);
  glutKeyboardFunc(cbKeyboard);
  glutSpecialFunc(cbKeyboardSpecial);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<initGlut>:
  endbr64
  mov    D19(%rip),%rax
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    (%rax),%edi
  mov    %rdx,%rbp
  mov    D3(%rip),%rax
  or     (%rax),%edi
  mov    D24(%rip),%rax
  or     (%rax),%edi
  call   <glutInitDisplayMode@plt>
  mov    %r13,%rdi
  call   <glutDisplayFunc@plt>
  mov    %r12,%rdi
  call   <glutKeyboardFunc@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <glutSpecialFunc@plt>
```

assistant: ```c
void initGlut(void (*cbDisplay)(void), void (*cbKeyboard)(unsigned char ucKey, int iX, int iY), void (*cbKeyboardSpecial)(int iKey, int iX, int iY)) {
  glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB | GLUT_DEPTH);
  glutDisplayFunc(cbDisplay);
  glutKeyboardFunc(cbKeyboard);
  glutSpecialFunc(cbKeyboardSpecial);
}
```