ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kore_buf_appendf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <kore_buf_appendv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void kore_buf_appendf(struct kore_buf *buf, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_buf_appendv(buf, fmt, args);
  va_end(args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kore_buf_appendf>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <kore_buf_appendv@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void kore_buf_appendf(struct kore_buf *buf, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  kore_buf_appendv(buf, fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Mesh_System_RandomNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  jmp    L16
L8:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L16:
  movzbl -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dl,-0xc(%rbp)
  test   %al,%al
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void Mesh_System_RandomNumber(unsigned char *buffer, unsigned char length) {
  while (length--) {
    *buffer++ = (unsigned char)random();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Mesh_System_RandomNumber>:
  endbr64
  test   %sil,%sil
  je     L8
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  movzbl %al,%eax
  lea    0x1(%rdi,%rax,1),%rbp
L2:
  mov    $0x0,%eax
  call   <random@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  ret
```

assistant: ```c
void Mesh_System_RandomNumber(unsigned char *buffer, unsigned char length) {
  while (length--) {
    *buffer++ = (unsigned char)random();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Mesh_System_RandomNumber>:
  endbr64
  test   %sil,%sil
  je     L2
  push   %rbp
  movzbl %sil,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <random@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void Mesh_System_RandomNumber(unsigned char *buffer, unsigned char length) {
  while (length--) {
    *buffer++ = (unsigned char)random();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Mesh_System_RandomNumber>:
  endbr64
  test   %sil,%sil
  je     L9
  push   %rbp
  movzbl %sil,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <random@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void Mesh_System_RandomNumber(unsigned char *buffer, unsigned char length) {
  while (length--) {
    *buffer++ = (unsigned char)random();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<player_query>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    $0x0,%edi
  call   <player_line_query@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L26
L35:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L56
L37:
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addq   $0x1,-0x28(%rbp)
L56:
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L37
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L36
  mov    $0x1,%eax
  jmp    L26
L36:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool player_query(const char *accept) {
  char *answer;
  size_t answer_length;
  size_t character;
  answer = player_line_query(NULL);
  if (answer == NULL) {
    return false;
  }
  answer_length = strlen(answer);
  for (character = 0; character < answer_length; character++) {
    answer[character] = tolower(answer[character]);
  }
  if (strstr(answer, accept) != NULL) {
    return true;
  } else {
    return false;
  }
  free(answer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<player_query>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    $0x0,%edi
  call   <player_line_query@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L2
  mov    %r12,%rbx
  lea    (%r12,%rax,1),%rbp
L1:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    $0x0,%eax
  jmp    L16
```

assistant: ```c
bool player_query(const char *accept) {
  char *answer;
  size_t answer_length;
  size_t character;
  answer = player_line_query(NULL);
  if (answer == NULL) {
    return false;
  }
  answer_length = strlen(answer);
  for (character = 0; character < answer_length; character++) {
    answer[character] = tolower(answer[character]);
  }
  if (strstr(answer, accept) != NULL) {
    return true;
  } else {
    return false;
  }
  free(answer);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<player_query>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <player_line_query@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rbx
  lea    (%rax,%r12,1),%rbp
  nopl   0x0(%rax)
L11:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L11
L6:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool player_query(const char *accept) {
  char *answer;
  size_t answer_length;
  size_t character;
  answer = player_line_query(NULL);
  if (answer == NULL) {
    return false;
  }
  answer_length = strlen(answer);
  for (character = 0; character < answer_length; character++) {
    answer[character] = tolower(answer[character]);
  }
  if (strstr(answer, accept) != NULL) {
    return true;
  } else {
    return false;
  }
  free(answer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<player_query>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <player_line_query@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L4
  mov    %r12,%rbx
  lea    (%rax,%r12,1),%rbp
  nopl   0x0(%rax)
L10:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L10
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
bool player_query(const char *accept) {
  char *answer;
  size_t answer_length;
  size_t character;
  answer = player_line_query(NULL);
  if (answer == NULL) {
    return false;
  }
  answer_length = strlen(answer);
  for (character = 0; character < answer_length; character++) {
    answer[character] = tolower(answer[character]);
  }
  if (strstr(answer, accept) != NULL) {
    return true;
  } else {
    return false;
  }
  free(answer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x4e4d4c4b4a494847,%rax
  movabs $0x565554535251504f,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x5a595857,-0x10(%rbp)
  movb   $0x0,-0xc(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jle    L60
  movl   $0x0,-0x34(%rbp)
  negl   -0x44(%rbp)
  jmp    L86
L60:
  cmpl   $0x0,-0x44(%rbp)
  jne    L86
  mov    -0x50(%rbp),%rax
  add    $0xb,%rax
  movb   $0x0,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0xa,%rax
  movb   $0x30,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0xa,%rax
  jmp    L29
L86:
  mov    -0x48(%rbp),%eax
  cmp    $0x25,%eax
  jbe    L8
  movl   $0x25,-0x48(%rbp)
L8:
  mov    -0x50(%rbp),%rax
  add    $0xb,%rax
  movb   $0x0,(%rax)
  movl   $0xa,-0x3c(%rbp)
  jmp    L98
L49:
  mov    -0x38(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jle    L58
  mov    -0x38(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %edx,%ecx
  jmp    L7
L58:
  mov    -0x38(%rbp),%eax
  neg    %eax
  cltd
  idivl  -0x48(%rbp)
  mov    %edx,%ecx
L7:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  movzbl -0x30(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x38(%rbp),%eax
  cltd
  idivl  -0x48(%rbp)
  mov    %eax,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  je     L16
  subl   $0x1,-0x3c(%rbp)
L98:
  cmpl   $0x0,-0x3c(%rbp)
  jg     L49
  jmp    L128
L16:
  nop
L128:
  cmpl   $0x0,-0x34(%rbp)
  je     L75
  subl   $0x1,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L75:
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L97
  call   <__stack_chk_fail@plt>
L97:
  leave
  ret
```

assistant: ```c
char *itoa(int i, char *buff, int base) {
  char code[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int j;
  int val = i;
  int neg = 1;
  if (i > 0) {
    neg = 0;
    i = -i;
  } else if (i == 0) {
    buff[11] = '\0';
    buff[10] = '0';
    return &buff[10];
  }
  if (base > sizeof(code))
    base = sizeof(code);
  buff[11] = '\0';
  for (j = 10; j >= 1; j--) {
    buff[j] = code[val % base > 0 ? val % base : -val % base];
    val /= base;
    if (val == 0)
      break;
  }
  if (neg) {
    buff[--j] = '-';
  }
  return &buff[j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  sub    $0x38,%rsp
  mov    %edi,%ecx
  mov    %rsi,%r10
  mov    %edx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x4e4d4c4b4a494847,%rax
  movabs $0x565554535251504f,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x5a595857,0x20(%rsp)
  movb   $0x0,0x24(%rsp)
  mov    $0x0,%r11d
  test   %edi,%edi
  jle    L8
L62:
  mov    $0x25,%eax
  cmp    %eax,%esi
  cmova  %eax,%esi
  movb   $0x0,0xb(%r10)
  lea    0xa(%r10),%r9
  mov    $0xa,%r8d
  jmp    L39
L8:
  mov    $0x1,%r11d
  jne    L62
  movb   $0x0,0xb(%r10)
  movb   $0x30,0xa(%r10)
  lea    0xa(%r10),%rax
  jmp    L21
L82:
  movslq %edi,%rdi
  movzbl (%rsp,%rdi,1),%eax
  mov    %al,(%r9)
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  test   %eax,%eax
  je     L10
  sub    $0x1,%r9
  sub    $0x1,%r8d
  je     L10
L39:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%edi
  test   %edx,%edx
  jg     L82
  mov    %ecx,%eax
  neg    %eax
  cltd
  idiv   %esi
  mov    %edx,%edi
  jmp    L82
L10:
  test   %r11d,%r11d
  je     L70
  sub    $0x1,%r8d
  movslq %r8d,%rax
  movb   $0x2d,(%r10,%rax,1)
L70:
  movslq %r8d,%r8
  lea    (%r10,%r8,1),%rax
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x38,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *itoa(int i, char *buff, int base) {
  char code[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int j;
  int val = i;
  int neg = 1;
  if (i > 0) {
    neg = 0;
    i = -i;
  } else if (i == 0) {
    buff[11] = '\0';
    buff[10] = '0';
    return &buff[10];
  }
  if (base > sizeof(code))
    base = sizeof(code);
  buff[11] = '\0';
  for (j = 10; j >= 1; j--) {
    buff[j] = code[val % base > 0 ? val % base : -val % base];
    val /= base;
    if (val == 0)
      break;
  }
  if (neg) {
    buff[--j] = '-';
  }
  return &buff[j];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itoa>:
  endbr64
  sub    $0x38,%rsp
  movdqa D9(%rip),%xmm0
  mov    %rsi,%r9
  xor    %r11d,%r11d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edx,%esi
  movl   $0x5a595857,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D16(%rip),%xmm0
  movb   $0x0,0x24(%rsp)
  movaps %xmm0,0x10(%rsp)
  test   %edi,%edi
  jle    L55
L2:
  mov    $0x25,%eax
  movb   $0x0,0xb(%r9)
  mov    $0xa,%ecx
  cmp    %eax,%esi
  cmova  %eax,%esi
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %edi,%eax
  mov    %ecx,%r8d
  cltd
  idiv   %esi
  mov    %eax,%r10d
  test   %edx,%edx
  jg     L71
  mov    %edi,%eax
  neg    %eax
  cltd
  idiv   %esi
L71:
  movslq %edx,%rdx
  mov    %r10d,%edi
  movzbl (%rsp,%rdx,1),%eax
  mov    %al,(%r9,%rcx,1)
  test   %r10d,%r10d
  je     L8
  sub    $0x1,%rcx
  jne    L66
  xor    %r8d,%r8d
L8:
  test   %r11d,%r11d
  jne    L4
  movslq %r8d,%rax
  add    %r9,%rax
L26:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    -0x1(%r8),%eax
  cltq
  add    %r9,%rax
  movb   $0x2d,(%rax)
  jmp    L26
  xchg   %ax,%ax
L55:
  mov    $0x1,%r11d
  jne    L2
  mov    $0x30,%edx
  lea    0xa(%r9),%rax
  mov    %dx,0xa(%r9)
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D16
type: byte[16]

tool: {"D9": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

tool: {"D16": [0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56]}

assistant: ```c
char *itoa(int i, char *buff, int base) {
  char code[] = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int j;
  int val = i;
  int neg = 1;
  if (i > 0) {
    neg = 0;
    i = -i;
  } else if (i == 0) {
    buff[11] = '\0';
    buff[10] = '0';
    return &buff[10];
  }
  if (base > sizeof(code))
    base = sizeof(code);
  buff[11] = '\0';
  for (j = 10; j >= 1; j--) {
    buff[j] = code[val % base > 0 ? val % base : -val % base];
    val /= base;
    if (val == 0)
      break;
  }
  if (neg) {
    buff[--j] = '-';
  }
  return &buff[j];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  jmp    L77
L23:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x19999999,%eax
  ja     L0
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x19999999,%eax
  jne    L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x35,%al
  jle    L20
L0:
  mov    $0xffffffff,%eax
  jmp    L71
L20:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  lea    -0x30(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L77:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L81
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L23
L81:
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    $0xffffffff,%eax
  jmp    L71
L14:
  mov    $0x0,%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
int readparam(char *parameter, unsigned int *container) {
  int i = 0;
  *container = 0;
  while ((parameter[i] >= '0') && (parameter[i] <= '9')) {
    if ((*container > 429496729) || ((*container == 429496729) && (parameter[i] > '5')))
      return -1;
    *container = 10 * (*container) + (parameter[i] - '0');
    i++;
  }
  if (i == 0)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readparam>:
  endbr64
  movl   $0x0,(%rsi)
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%r8d
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x0,%r9d
  cmp    $0x9,%r8b
  jbe    L19
L23:
  cmp    $0x1,%r9d
  sbb    %eax,%eax
  ret
L39:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  mov    %edx,(%rsi)
  mov    %ecx,%r9d
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L23
  add    $0x1,%rcx
  cmp    $0x19999999,%edx
  ja     L48
L19:
  cmp    $0x35,%al
  jle    L39
  cmp    $0x19999999,%edx
  jne    L39
  mov    $0xffffffff,%eax
  ret
L48:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int readparam(char *parameter, unsigned int *container) {
  int i = 0;
  *container = 0;
  while ((parameter[i] >= '0') && (parameter[i] <= '9')) {
    if ((*container > 429496729) || ((*container == 429496729) && (parameter[i] > '5')))
      return -1;
    *container = 10 * (*container) + (parameter[i] - '0');
    i++;
  }
  if (i == 0)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<readparam>:
  endbr64
  movl   $0x0,(%rsi)
  movsbl (%rdi),%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L29
  xchg   %ax,%ax
L43:
  cmp    $0x35,%al
  jle    L39
  cmp    $0x19999999,%edx
  je     L29
L39:
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rax,%rdx,2),%edx
  mov    %edx,(%rsi)
  movsbl (%rdi,%rcx,1),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L21
  add    $0x1,%rcx
  cmp    $0x19999999,%edx
  jbe    L43
L29:
  mov    $0xffffffff,%eax
  ret
  nopl   (%rax)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readparam(char *parameter, unsigned int *container) {
  int i = 0;
  *container = 0;
  while ((parameter[i] >= '0') && (parameter[i] <= '9')) {
    if ((*container > 429496729) || ((*container == 429496729) && (parameter[i] > '5')))
      return -1;
    *container = 10 * (*container) + (parameter[i] - '0');
    i++;
  }
  if (i == 0)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<readparam>:
  endbr64
  movl   $0x0,(%rsi)
  movsbl (%rdi),%eax
  mov    $0x1,%ecx
  xor    %edx,%edx
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L24
  xchg   %ax,%ax
L13:
  cmp    $0x35,%al
  jle    L35
  cmp    $0x19999999,%edx
  je     L24
L35:
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rax,%rdx,2),%edx
  mov    %edx,(%rsi)
  movsbl (%rdi,%rcx,1),%eax
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  ja     L6
  add    $0x1,%rcx
  cmp    $0x19999999,%edx
  jbe    L13
L24:
  mov    $0xffffffff,%eax
  ret
  nopl   (%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readparam(char *parameter, unsigned int *container) {
  int i = 0;
  *container = 0;
  while ((parameter[i] >= '0') && (parameter[i] <= '9')) {
    if ((*container > 429496729) || ((*container == 429496729) && (parameter[i] > '5')))
      return -1;
    *container = 10 * (*container) + (parameter[i] - '0');
    i++;
  }
  if (i == 0)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<glmGenerateShadowMatrix4f>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %rdx,%rsi
  call   <glmDotProduct3f@plt>
  movaps %xmm0,%xmm2
  movss  (%r12),%xmm3
  mulss  0x0(%rbp),%xmm3
  movss  0x4(%r12),%xmm1
  mulss  0x4(%rbp),%xmm1
  addss  %xmm3,%xmm1
  movss  0x8(%r12),%xmm0
  mulss  0x8(%rbp),%xmm0
  addss  %xmm1,%xmm0
  subss  %xmm2,%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm3,%xmm1
  movss  %xmm1,(%rbx)
  movss  (%r12),%xmm3
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm3
  mulss  0x4(%rbp),%xmm3
  movss  %xmm3,0x10(%rbx)
  movss  (%r12),%xmm3
  xorps  %xmm1,%xmm3
  mulss  0x8(%rbp),%xmm3
  movss  %xmm3,0x20(%rbx)
  movaps %xmm2,%xmm3
  mulss  (%r12),%xmm3
  movss  %xmm3,0x30(%rbx)
  movss  0x4(%r12),%xmm3
  xorps  %xmm1,%xmm3
  mulss  0x0(%rbp),%xmm3
  movss  %xmm3,0x4(%rbx)
  movss  0x4(%r12),%xmm3
  mulss  0x4(%rbp),%xmm3
  movaps %xmm0,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x14(%rbx)
  movss  0x4(%r12),%xmm3
  xorps  %xmm1,%xmm3
  mulss  0x8(%rbp),%xmm3
  movss  %xmm3,0x24(%rbx)
  movaps %xmm2,%xmm3
  mulss  0x4(%r12),%xmm3
  movss  %xmm3,0x34(%rbx)
  movss  0x8(%r12),%xmm3
  xorps  %xmm1,%xmm3
  mulss  0x0(%rbp),%xmm3
  movss  %xmm3,0x8(%rbx)
  movss  0x8(%r12),%xmm3
  xorps  %xmm1,%xmm3
  mulss  0x4(%rbp),%xmm3
  movss  %xmm3,0x18(%rbx)
  movss  0x8(%r12),%xmm3
  mulss  0x8(%rbp),%xmm3
  movaps %xmm0,%xmm4
  subss  %xmm3,%xmm4
  movss  %xmm4,0x28(%rbx)
  movaps %xmm2,%xmm3
  mulss  0x8(%r12),%xmm3
  movss  %xmm3,0x38(%rbx)
  movss  0x0(%rbp),%xmm3
  xorps  %xmm1,%xmm3
  movss  %xmm3,0xc(%rbx)
  movss  0x4(%rbp),%xmm3
  xorps  %xmm1,%xmm3
  movss  %xmm3,0x1c(%rbx)
  movss  0x8(%rbp),%xmm3
  xorps  %xmm3,%xmm1
  movss  %xmm1,0x2c(%rbx)
  addss  %xmm2,%xmm0
  movss  %xmm0,0x3c(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x80]}

assistant: ```c
void glmGenerateShadowMatrix4f(float m[16], const float planeOrigin[3], const float planeNormal[3], const float light[3]) {
  float d = -glmDotProduct3f(planeOrigin, planeNormal);
  float p = light[0] * planeNormal[0] + light[1] * planeNormal[1] + light[2] * planeNormal[2] + d;
  m[0] = p - light[0] * planeNormal[0];
  m[4] = -light[0] * planeNormal[1];
  m[8] = -light[0] * planeNormal[2];
  m[12] = -light[0] * d;
  m[1] = -light[1] * planeNormal[0];
  m[5] = p - light[1] * planeNormal[1];
  m[9] = -light[1] * planeNormal[2];
  m[13] = -light[1] * d;
  m[2] = -light[2] * planeNormal[0];
  m[6] = -light[2] * planeNormal[1];
  m[10] = p - light[2] * planeNormal[2];
  m[14] = -light[2] * d;
  m[3] = -planeNormal[0];
  m[7] = -planeNormal[1];
  m[11] = -planeNormal[2];
  m[15] = p - d;
}
```