ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<testjump>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  lea    D1(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <ol@plt>
  test   %ebx,%ebx
  je     L9
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <ot@plt>
L6:
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <printlabel@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1080 <nl@plt>
  nopl   0x0(%rax)
L9:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <ot@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string

tool: D1: cmpd	#0

tool: D3: lbne	

tool: D27: lbeq	

assistant: ```c
testjump(label, ft) int label;
int ft;
{
  ol("cmpd\t#0");
  if (ft)
    ot("lbne\t");
  else
    ot("lbeq\t");
  printlabel(label);
  nl();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D17: String %d


tool: D0: %d: %c:%d


assistant: ```c
void print_char(const unsigned char *foo, int length) {
  int x = 0;
  printf("String %d\n", length);
  for (x; x < length; x++) {
    printf("%d: %c:%d\n", x, foo[x], foo[x]);
  }
  putchar('\n');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L7
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D18(%rip),%r13
L17:
  movzbl (%r12,%rbx,1),%edx
  mov    %edx,%ecx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D18
datatype: string

tool: D8: String %d


tool: D18: %d: %c:%d


assistant: ```c
void print_char(const unsigned char *foo, int length) {
  int x = 0;
  printf("String %d\n", length);
  for (x; x < length; x++) {
    printf("%d: %c:%d\n", x, foo[x], foo[x]);
  }
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_char>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  lea    D17(%rip),%rdi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L13
  xor    %ebx,%ebx
  lea    D5(%rip),%r13
  nopl   0x0(%rax)
L12:
  movzbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
L13:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D17: String %d


tool: D5: %d: %c:%d


assistant: ```c
void print_char(const unsigned char *foo, int length) {
  int x = 0;
  printf("String %d\n", length);
  for (x; x < length; x++) {
    printf("%d: %c:%d\n", x, foo[x], foo[x]);
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_char>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  lea    D17(%rip),%rdi
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %ebp,%esi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L6
  xor    %ebx,%ebx
  lea    D0(%rip),%r13
  nopl   0x0(%rax)
L14:
  movzbl (%r12,%rbx,1),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  mov    %edx,%ecx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L14
L6:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D0
data_type: string

tool: D17: String %d


tool: D0: %d: %c:%d


assistant: ```c
void print_char(const unsigned char *foo, int length) {
  int x = 0;
  printf("String %d\n", length);
  for (x; x < length; x++) {
    printf("%d: %c:%d\n", x, foo[x], foo[x]);
  }
  putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TimerConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0xc,%rdx
  and    $0xfffffffffffffefe,%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  or     $0x2,%ah
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  or     $0x2,%ah
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TimerConfigure>:
  endbr64
  mov    %rsi,%rax
  mov    0xc(%rdi),%rdx
  and    $0xfffffffffffffefe,%rdx
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  movzbl %ah,%eax
  or     $0x2,%ah
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TimerConfigure>:
  endbr64
  mov    0xc(%rdi),%rdx
  mov    %rsi,%rax
  movzbl %ah,%eax
  and    $0xfffffffffffffefe,%rdx
  or     $0x2,%ah
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TimerConfigure>:
  endbr64
  mov    0xc(%rdi),%rdx
  mov    %rsi,%rax
  movzbl %ah,%eax
  and    $0xfffffffffffffefe,%rdx
  or     $0x2,%ah
  mov    %rdx,0xc(%rdi)
  mov    %rsi,%rdx
  shr    $0x18,%rdx
  mov    %rdx,(%rdi)
  movzbl %sil,%edx
  or     $0x2,%dh
  mov    %rdx,0x4(%rdi)
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerConfigure(unsigned long ulBase, unsigned long ulConfig) {
  ;

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x0000000C))) &= ~(0x00000001 | 0x00000100);
  (*((volatile unsigned long *)(ulBase + 0x00000000))) = ulConfig >> 24;
  (*((volatile unsigned long *)(ulBase + 0x00000004))) = (ulConfig & 255) | 0x00000200;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) = ((ulConfig >> 8) & 255) | 0x00000200;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<autohelperowl_attackpat186>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <countlib@plt>
  cmp    $0x4,%eax
  jg     L13
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <countlib@plt>
  cmp    $0x4,%eax
  jg     L13
  mov    $0x3,%eax
  sub    -0x24(%rbp),%eax
  mov    -0xc(%rbp),%r8d
  mov    -0x8(%rbp),%edi
  mov    -0xc(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  sub    $0x8,%rsp
  mov    -0x4(%rbp),%esi
  push   %rsi
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <play_break_through_n@plt>
  add    $0x10,%rsp
  cmp    $0x3,%eax
  jne    L13
  mov    $0x1,%eax
  jmp    L10
L13:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat186(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(-1, 0, move, transformation);
  b = offset(0, -1, move, transformation);
  c = offset(0, 1, move, transformation);
  return countlib(b) <= 4 && countlib(c) <= 4 && play_break_through_n((1 + 2 - (color)), 2, move, a, b, a, c) == 3;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<autohelperowl_attackpat186>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r14d
  mov    %esi,%ecx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <offset@plt>
  mov    %eax,%r13d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r12d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %r12d,%edi
  call   <countlib@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x4,%edx
  jle    L5
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  mov    %ebp,%edi
  call   <countlib@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x4,%edx
  jg     L18
  mov    $0x3,%edi
  sub    %r14d,%edi
  sub    $0x8,%rsp
  push   %rbp
  mov    %r13d,%r9d
  mov    %r12d,%r8d
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    $0x2,%esi
  call   <play_break_through_n@plt>
  add    $0x10,%rsp
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L18
```

assistant: ```c
int autohelperowl_attackpat186(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(-1, 0, move, transformation);
  b = offset(0, -1, move, transformation);
  c = offset(0, 1, move, transformation);
  return countlib(b) <= 4 && countlib(c) <= 4 && play_break_through_n((1 + 2 - (color)), 2, move, a, b, a, c) == 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<autohelperowl_attackpat186>:
  endbr64
  push   %r14
  mov    $0xffffffff,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbx
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %eax,%r14d
  call   <offset@plt>
  xor    %edi,%edi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%ebx
  mov    $0x1,%esi
  call   <offset@plt>
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <countlib@plt>
  cmp    $0x4,%eax
  jle    L19
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L19:
  mov    %r13d,%edi
  call   <countlib@plt>
  cmp    $0x4,%eax
  jg     L7
  sub    $0x8,%rsp
  mov    $0x3,%edi
  mov    %r14d,%ecx
  mov    %r12d,%edx
  push   %r13
  sub    %ebp,%edi
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    $0x2,%esi
  call   <play_break_through_n@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x3,%eax
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  pop    %r13
  movzbl %al,%eax
  pop    %r14
  ret
```

assistant: ```c
int autohelperowl_attackpat186(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(-1, 0, move, transformation);
  b = offset(0, -1, move, transformation);
  c = offset(0, 1, move, transformation);
  return countlib(b) <= 4 && countlib(c) <= 4 && play_break_through_n((1 + 2 - (color)), 2, move, a, b, a, c) == 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<autohelperowl_attackpat186>:
  endbr64
  push   %r14
  mov    $0xffffffff,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  xor    %esi,%esi
  push   %rbx
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %eax,%r14d
  call   <offset@plt>
  xor    %edi,%edi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %eax,%ebx
  mov    $0x1,%esi
  call   <offset@plt>
  mov    %ebx,%edi
  mov    %eax,%r13d
  call   <countlib@plt>
  cmp    $0x4,%eax
  jle    L0
L13:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L0:
  mov    %r13d,%edi
  call   <countlib@plt>
  cmp    $0x4,%eax
  jg     L13
  sub    $0x8,%rsp
  mov    $0x3,%edi
  mov    %r14d,%ecx
  mov    %r12d,%edx
  push   %r13
  sub    %ebp,%edi
  mov    %r14d,%r9d
  mov    %ebx,%r8d
  mov    $0x2,%esi
  call   <play_break_through_n@plt>
  pop    %rdx
  pop    %rcx
  cmp    $0x3,%eax
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  pop    %r13
  movzbl %al,%eax
  pop    %r14
  ret
```

assistant: ```c
int autohelperowl_attackpat186(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(-1, 0, move, transformation);
  b = offset(0, -1, move, transformation);
  c = offset(0, 1, move, transformation);
  return countlib(b) <= 4 && countlib(c) <= 4 && play_break_through_n((1 + 2 - (color)), 2, move, a, b, a, c) == 3;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sort_ivector_by_int_indices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <ivector@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L9
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L22
  movl   $0x1,-0x10(%rbp)
  jmp    L36
L33:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L33
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <free_ivector@plt>
  nop
  leave
  ret
```

assistant: ```c
void sort_ivector_by_int_indices(int n, int *v, int *indices) {
  int i;
  int curr_index;
  int *temp_v;
  temp_v = ivector(1, n);
  for (i = 1; i <= n; i++)
    temp_v[i] = v[i];
  for (i = 1; i <= n; i++) {
    curr_index = (int)indices[i];
    v[i] = temp_v[curr_index];
  }
  free_ivector(temp_v, 1, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort_ivector_by_int_indices>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <ivector@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L13
  lea    0x1(%r12),%eax
  mov    $0x1,%edx
L2:
  mov    (%rbx,%rdx,4),%ecx
  mov    %ecx,(%rdi,%rdx,4)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L2
  mov    $0x1,%edx
L26:
  movslq 0x0(%rbp,%rdx,4),%rcx
  mov    (%rdi,%rcx,4),%ecx
  mov    %ecx,(%rbx,%rdx,4)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L26
L13:
  mov    %r12d,%edx
  mov    $0x1,%esi
  call   <free_ivector@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort_ivector_by_int_indices(int n, int *v, int *indices) {
  int i;
  int curr_index;
  int *temp_v;
  temp_v = ivector(1, n);
  for (i = 1; i <= n; i++)
    temp_v[i] = v[i];
  for (i = 1; i <= n; i++) {
    curr_index = (int)indices[i];
    v[i] = temp_v[curr_index];
  }
  free_ivector(temp_v, 1, n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort_ivector_by_int_indices>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <ivector@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L7
  lea    0x1(%r12),%eax
  mov    $0x1,%ecx
  nop
L28:
  mov    (%rbx,%rcx,4),%esi
  mov    %esi,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L28
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L20:
  movslq 0x0(%rbp,%rcx,4),%rsi
  mov    (%rdi,%rsi,4),%esi
  mov    %esi,(%rbx,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L20
L7:
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  mov    $0x1,%esi
  pop    %r12
  jmp    1070 <free_ivector@plt>
```

assistant: ```c
void sort_ivector_by_int_indices(int n, int *v, int *indices) {
  int i;
  int curr_index;
  int *temp_v;
  temp_v = ivector(1, n);
  for (i = 1; i <= n; i++)
    temp_v[i] = v[i];
  for (i = 1; i <= n; i++) {
    curr_index = (int)indices[i];
    v[i] = temp_v[curr_index];
  }
  free_ivector(temp_v, 1, n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort_ivector_by_int_indices>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edi,%esi
  mov    $0x1,%edi
  call   <ivector@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L29
  sub    %rbx,%rax
  sub    $0x4,%rax
  cmp    $0x8,%rax
  jbe    L47
  lea    -0x1(%r12),%eax
  cmp    $0x2,%eax
  jbe    L47
  mov    %r12d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%edx
  mov    $0x4,%eax
  shl    $0x4,%rdx
  add    $0x14,%rdx
  xchg   %ax,%ax
L62:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L62
  mov    %r12d,%eax
  lea    0x1(%r12),%ecx
  and    $0xfffffffc,%eax
  lea    0x1(%rax),%edx
  cmp    %eax,%r12d
  je     L91
  movslq %edx,%rdx
  mov    (%rbx,%rdx,4),%r8d
  lea    0x0(,%rdx,4),%rsi
  mov    %r8d,(%rdi,%rdx,4)
  lea    0x2(%rax),%edx
  cmp    %edx,%r12d
  jl     L91
  mov    0x4(%rbx,%rsi,1),%edx
  add    $0x3,%eax
  mov    %edx,0x4(%rdi,%rsi,1)
  cmp    %eax,%r12d
  jl     L91
  mov    0x8(%rbx,%rsi,1),%eax
  mov    %eax,0x8(%rdi,%rsi,1)
L91:
  mov    %ecx,%ecx
  mov    $0x1,%eax
  nop
L2:
  movslq 0x0(%rbp,%rax,4),%rdx
  mov    (%rdi,%rdx,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L2
L29:
  pop    %rbx
  mov    %r12d,%edx
  pop    %rbp
  mov    $0x1,%esi
  pop    %r12
  jmp    1070 <free_ivector@plt>
  nopl   (%rax)
L47:
  lea    0x1(%r12),%esi
  mov    $0x1,%eax
  mov    %rsi,%rcx
  nopl   (%rax)
L54:
  mov    (%rbx,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L54
  jmp    L91
```

assistant: ```c
void sort_ivector_by_int_indices(int n, int *v, int *indices) {
  int i;
  int curr_index;
  int *temp_v;
  temp_v = ivector(1, n);
  for (i = 1; i <= n; i++)
    temp_v[i] = v[i];
  for (i = 1; i <= n; i++) {
    curr_index = (int)indices[i];
    v[i] = temp_v[curr_index];
  }
  free_ivector(temp_v, 1, n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <some_function@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  some_function();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <some_function@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  some_function();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <some_function@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  some_function();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <some_function@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  some_function();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L14:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L17:
  cmpl   $0x1,-0x14(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  while (n > 1) {
    result *= n--;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  cmp    $0x1,%edi
  jle    L18
  mov    $0x1,%eax
L4:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L4
  ret
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  while (n > 1) {
    result *= n--;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L19
  xchg   %ax,%ax
L0:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L0
  ret
  xchg   %ax,%ax
L19:
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  while (n > 1) {
    result *= n--;
  }
  return result;
}
```