user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  lea    D89(%rip),%rbp
  sub    $0x10,%rsp
  movss  D69(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  movss  %xmm0,(%rsp)
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D73(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm2
  comiss %xmm2,%xmm1
  jbe    L68
  subss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
L84:
  lea    D28(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm1
  pxor   %xmm2,%xmm2
  ucomiss %xmm2,%xmm1
  jp     L43
  je     L86
L43:
  movss  0x4(%rsp),%xmm0
  ucomiss %xmm2,%xmm0
  jp     L99
  jne    L99
L86:
  lea    D19(%rip),%rdi
  call   <puts@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L68:
  subss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  jmp    L84
L99:
  comiss %xmm0,%xmm1
  jbe    L36
  divss  %xmm0,%xmm1
  lea    D55(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  jmp    L27
L36:
  divss  %xmm1,%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L27
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string
name: retrieve_data
arguments: label: D89
datatype: string
name: retrieve_data
arguments: label: D69
datatype: byte[4]
name: retrieve_data
arguments: label: D73
datatype: string
name: retrieve_data
arguments: label: D58
datatype: string
name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string
name: retrieve_data
arguments: label: D55
datatype: string

tool: D0: Please provide a number for the first float: 

tool: D89:  %f

tool: {"D69": [0x5c,0xff,0x79,0xc4]}

tool: D73: Please provide a number for the second float: 

tool: D58: The number for the sum of the two floats is %.2f



tool: D28: The number for the difference of the two float is %.2f



tool: D4: The number for the product of the two float is %.2f



tool: D19: 
You cannot any number divide by zero because it produces a non-real result. Any zero dived by any integer is equal to zero.


tool: D55: The number for the quotient of the two float is %.2f



assistant: ```c
int main() {
  float a1, a2, intSum, intDiff, intProd, intQuot, intMod;
  a1 = a2 = intSum = intDiff = intProd = intQuot = intMod = -999.99;
  printf("Please provide a number for the first float: \n");
  scanf(" %f", &a1);
  printf("Please provide a number for the second float: \n");
  scanf(" %f", &a2);
  intSum = a1 + a2;
  printf("The number for the sum of the two floats is %.2f\n\n", intSum);
  if (a1 > a2) {
    intDiff = a1 - a2;
  } else {
    intDiff = a2 - a1;
  }
  printf("The number for the difference of the two float is %.2f\n\n", intDiff);
  intProd = a1 * a2;
  printf("The number for the product of the two float is %.2f\n\n", intProd);
  if (a1 == 0 || a2 == 0) {
    printf("\nYou cannot any number divide by zero because it produces a non-real result. Any zero dived by any integer is equal to zero.\n\n");
  } else if (a1 > a2) {
    intQuot = a1 / a2;
    printf("The number for the quotient of the two float is %.2f\n\n", intQuot);
  } else {
    intQuot = a2 / a1;
    printf("The number for the quotient of the two float is %.2f\n\n", intQuot);
  }
  return 0;
}
```