ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<strstr>:
  endbr64
  movzbl (%rsi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L22
  cmpb   $0x0,(%rdi)
  je     L41
  nopl   (%rax)
L5:
  movzbl (%rdi),%edx
  mov    %r8d,%ecx
  mov    $0x1,%eax
  test   %dl,%dl
  jne    L1
  jmp    L71
  nopl   0x0(%rax)
L67:
  test   %cl,%cl
  je     L7
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  test   %dl,%dl
  je     L78
L1:
  cmp    %cl,%dl
  je     L67
L78:
  test   %cl,%cl
  je     L7
L71:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L5
L41:
  xor    %eax,%eax
L22:
  ret
  nopl   0x0(%rax)
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strstr(const char *str, const char *subString) {
  char *cp, *s1, *s2;
  if (NULL == str) {
    return NULL;
  }
  if (subString == 0 || *subString == '\0') {
    return (char *)str;
  }
  for (cp = (char *)str; *cp; cp++) {
    s1 = cp;
    s2 = (char *)subString;
    while (*s1 && *s2 && (*s1 == *s2)) {
      s1++;
      s2++;
    }
    if (*s2 == '\0') {
      return cp;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x7c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L13
L32:
  addl   $0x1,-0x78(%rbp)
L13:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L32
  mov    -0x7c(%rbp),%eax
  cltd
  idivl  -0x78(%rbp)
  mov    %edx,%eax
  mov    %eax,-0x7c(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L33
L21:
  mov    -0x7c(%rbp),%edx
  mov    -0x74(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x78(%rbp)
  jle    L59
  mov    -0x78(%rbp),%eax
  sub    -0x74(%rbp),%eax
  mov    %eax,%edx
  mov    -0x7c(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L59:
  mov    -0x7c(%rbp),%edx
  mov    -0x74(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x78(%rbp)
  mov    -0x78(%rbp),%eax
  sub    %edx,%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L53:
  addl   $0x1,-0x74(%rbp)
L33:
  mov    -0x74(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jl     L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: string

tool: D22: %s

tool: D4: %d

tool: D20: %c

assistant: ```c
int main() {
  int n, count = 0, i, s, s1;
  char str[100];
  scanf("%s", str);
  scanf("%d", &n);
  count = 0;
  while (str[count] != '\0')
    count++;
  n = n % count;
  for (int i = 0; i < count; i++) {
    if (i + n < count)
      printf("%c", str[count - i + n]);
    else
      printf("%c", str[count - (i + n) % count]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpb   $0x0,0x10(%rsp)
  je     L66
  lea    0x11(%rsp),%rax
  mov    $0x0,%ebx
L4:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L4
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %edx,0xc(%rsp)
  test   %ebx,%ebx
  jle    L66
  mov    $0x0,%ebp
  lea    D26(%rip),%r13
  jmp    L61
L54:
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
L68:
  lea    0x1(%rbp),%eax
  cmp    %ebp,%r12d
  jle    L66
  mov    %eax,%ebp
L61:
  mov    0xc(%rsp),%edx
  lea    (%rdx,%rbp,1),%eax
  cmp    %ebx,%eax
  jge    L54
  mov    %ebx,%eax
  sub    %ebp,%eax
  add    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L68
L66:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D22
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string

tool: D29: %s

tool: D22: %d

tool: D26: %c

assistant: ```c
int main() {
  int n, count = 0, i, s, s1;
  char str[100];
  scanf("%s", str);
  scanf("%d", &n);
  count = 0;
  while (str[count] != '\0')
    count++;
  n = n % count;
  for (int i = 0; i < count; i++) {
    if (i + n < count)
      printf("%c", str[count - i + n]);
    else
      printf("%c", str[count - (i + n) % count]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,0x10(%rsp)
  je     L45
  lea    0x11(%rsp),%rax
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x1,%rax
  mov    %ebx,%r12d
  add    $0x1,%ebx
  cmpb   $0x0,-0x1(%rax)
  jne    L2
  mov    0xc(%rsp),%eax
  lea    0x1(%r12),%r14d
  xor    %ebp,%ebp
  lea    D11(%rip),%r13
  cltd
  idiv   %ebx
  mov    %edx,0xc(%rsp)
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r14d,%eax
  mov    %r13,%rdi
  sub    %ebp,%eax
  add    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  call   <printf@plt>
  lea    0x1(%rbp),%eax
  cmp    %ebp,%r12d
  je     L37
L42:
  mov    0xc(%rsp),%edx
  mov    %eax,%ebp
L56:
  lea    (%rdx,%rbp,1),%eax
  cmp    %ebx,%eax
  jl     L18
  cltd
  mov    %r13,%rdi
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  call   <printf@plt>
  lea    0x1(%rbp),%eax
  cmp    %ebp,%r12d
  jne    L42
L37:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  ud2
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D6: %s

tool: D22: %d

tool: D11: %c

assistant: ```c
int main() {
  int n, count = 0, i, s, s1;
  char str[100];
  scanf("%s", str);
  scanf("%d", &n);
  count = 0;
  while (str[count] != '\0')
    count++;
  n = n % count;
  for (int i = 0; i < count; i++) {
    if (i + n < count)
      printf("%c", str[count - i + n]);
    else
      printf("%c", str[count - (i + n) % count]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  lea    D22(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,0x10(%rsp)
  je     L50
  lea    0x11(%rsp),%rax
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    $0x1,%rax
  mov    %ebx,%r12d
  add    $0x1,%ebx
  cmpb   $0x0,-0x1(%rax)
  jne    L24
  mov    0xc(%rsp),%eax
  lea    0x1(%r12),%r14d
  xor    %ebp,%ebp
  lea    D8(%rip),%r13
  cltd
  idiv   %ebx
  mov    %edx,0xc(%rsp)
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %r14d,%eax
  mov    %r13,%rdi
  sub    %ebp,%eax
  add    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  call   <printf@plt>
  lea    0x1(%rbp),%eax
  cmp    %ebp,%r12d
  je     L2
L38:
  mov    0xc(%rsp),%edx
  mov    %eax,%ebp
L41:
  lea    (%rdx,%rbp,1),%eax
  cmp    %ebx,%eax
  jl     L48
  cltd
  mov    %r13,%rdi
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  cltq
  movsbl 0x10(%rsp,%rax,1),%esi
  call   <printf@plt>
  lea    0x1(%rbp),%eax
  cmp    %ebp,%r12d
  jne    L38
L2:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  ud2
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: D22: %s

tool: D12: %d

tool: D8: %c

assistant: ```c
int main() {
  int n, count = 0, i, s, s1;
  char str[100];
  scanf("%s", str);
  scanf("%d", &n);
  count = 0;
  while (str[count] != '\0')
    count++;
  n = n % count;
  for (int i = 0; i < count; i++) {
    if (i + n < count)
      printf("%c", str[count - i + n]);
    else
      printf("%c", str[count - (i + n) % count]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crypto_box_nistp256aes256gcm_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x60(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crypto_box_nistp256aes256gcm_beforenm@plt>
  lea    -0x30(%rbp),%rdi
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <crypto_box_nistp256aes256gcm_open_afternm@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int crypto_box_nistp256aes256gcm_open(unsigned char *m, unsigned char *c, unsigned long long clen, unsigned char *n, unsigned char *pk, unsigned char *sk) {
  unsigned char k[32];
  crypto_box_nistp256aes256gcm_beforenm(k, pk, sk);
  return crypto_box_nistp256aes256gcm_open_afternm(m, c, clen, n, k);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crypto_box_nistp256aes256gcm_open>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%rsi
  mov    %r9,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <crypto_box_nistp256aes256gcm_beforenm@plt>
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <crypto_box_nistp256aes256gcm_open_afternm@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_box_nistp256aes256gcm_open(unsigned char *m, unsigned char *c, unsigned long long clen, unsigned char *n, unsigned char *pk, unsigned char *sk) {
  unsigned char k[32];
  crypto_box_nistp256aes256gcm_beforenm(k, pk, sk);
  return crypto_box_nistp256aes256gcm_open_afternm(m, c, clen, n, k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypto_box_nistp256aes256gcm_open>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r9,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    %r8,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <crypto_box_nistp256aes256gcm_beforenm@plt>
  mov    %r13,%rdx
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_box_nistp256aes256gcm_open_afternm@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_box_nistp256aes256gcm_open(unsigned char *m, unsigned char *c, unsigned long long clen, unsigned char *n, unsigned char *pk, unsigned char *sk) {
  unsigned char k[32];
  crypto_box_nistp256aes256gcm_beforenm(k, pk, sk);
  return crypto_box_nistp256aes256gcm_open_afternm(m, c, clen, n, k);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<crypto_box_nistp256aes256gcm_open>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %r9,%rdx
  push   %r12
  mov    %rsi,%r12
  mov    %r8,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <crypto_box_nistp256aes256gcm_beforenm@plt>
  mov    %r13,%rdx
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <crypto_box_nistp256aes256gcm_open_afternm@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int crypto_box_nistp256aes256gcm_open(unsigned char *m, unsigned char *c, unsigned long long clen, unsigned char *n, unsigned char *pk, unsigned char *sk) {
  unsigned char k[32];
  crypto_box_nistp256aes256gcm_beforenm(k, pk, sk);
  return crypto_box_nistp256aes256gcm_open_afternm(m, c, clen, n, k);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L2:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L5:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string

tool: D12: null	

tool: D7: %.02f	

assistant: ```c
void printFloat(void *i) {
  if (i == NULL)
    printf("null\t");
  else
    printf("%.02f\t", *((float *)i));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printFloat>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L3
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi),%xmm0
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L8:
  add    $0x8,%rsp
  ret
L3:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: data_tag: D11
datatype: string
name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D11: %.02f	

tool: D2: null	

assistant: ```c
void printFloat(void *i) {
  if (i == NULL)
    printf("null\t");
  else
    printf("%.02f\t", *((float *)i));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printFloat>:
  endbr64
  test   %rdi,%rdi
  je     L6
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd (%rdi),%xmm0
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D0
type: string

tool: D1: %.02f	

tool: D0: null	

assistant: ```c
void printFloat(void *i) {
  if (i == NULL)
    printf("null\t");
  else
    printf("%.02f\t", *((float *)i));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printFloat>:
  endbr64
  test   %rdi,%rdi
  je     L1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd (%rdi),%xmm0
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string

tool: D13: %.02f	

tool: D18: null	

assistant: ```c
void printFloat(void *i) {
  if (i == NULL)
    printf("null\t");
  else
    printf("%.02f\t", *((float *)i));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bb_perror_msg_and_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bb_vperror_msg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void bb_perror_msg_and_die(const char *s, ...) {
  va_list p;
  va_start(p, s);
  bb_vperror_msg(s, p);
  va_end(p);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bb_perror_msg_and_die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <bb_vperror_msg@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bb_perror_msg_and_die(const char *s, ...) {
  va_list p;
  va_start(p, s);
  bb_vperror_msg(s, p);
  va_end(p);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bb_perror_msg_and_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <bb_vperror_msg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bb_perror_msg_and_die(const char *s, ...) {
  va_list p;
  va_start(p, s);
  bb_vperror_msg(s, p);
  va_end(p);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bb_perror_msg_and_die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <bb_vperror_msg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bb_perror_msg_and_die(const char *s, ...) {
  va_list p;
  va_start(p, s);
  bb_vperror_msg(s, p);
  va_end(p);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<shm_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <fb_flock@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void shm_unlock(int fd) {
  fb_flock(fd, 8);
  close(fd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<shm_unlock>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x8,%esi
  call   <fb_flock@plt>
  mov    %ebx,%edi
  call   <close@plt>
  pop    %rbx
  ret
```

assistant: ```c
void shm_unlock(int fd) {
  fb_flock(fd, 8);
  close(fd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shm_unlock>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    %edi,%ebp
  call   <fb_flock@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <close@plt>
```

assistant: ```c
void shm_unlock(int fd) {
  fb_flock(fd, 8);
  close(fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shm_unlock>:
  endbr64
  push   %rbp
  mov    $0x8,%esi
  mov    %edi,%ebp
  call   <fb_flock@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <close@plt>
```

assistant: ```c
void shm_unlock(int fd) {
  fb_flock(fd, 8);
  close(fd);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  jmp    L37
L20:
  subl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L37:
  cmpl   $0x0,-0xc(%rbp)
  js     L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jge    L0
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L20
L0:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void getPalindrome(char *str, int left, int right, int *start, int *end) {
  while (left >= 0 && right <= strlen(str) - 1 && str[left] == str[right]) {
    left--;
    right++;
  }
  *start = left + 1;
  *end = right - 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getPalindrome>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  test   %esi,%esi
  js     L8
  mov    %rdi,%r12
  movslq %esi,%rbp
  movslq %edx,%rbx
L6:
  mov    %ebx,%r15d
  mov    %ebx,%r14d
  mov    %ebp,0xc(%rsp)
  mov    %ebp,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L8
  movzbl (%r12,%rbx,1),%eax
  cmp    %al,(%r12,%rbp,1)
  jne    L8
  mov    0xc(%rsp),%r13d
  sub    $0x1,%r13d
  lea    0x1(%r15),%r14d
  sub    $0x1,%rbp
  add    $0x1,%rbx
  test   %ebp,%ebp
  jns    L6
L8:
  add    $0x1,%r13d
  mov    0x10(%rsp),%rax
  mov    %r13d,(%rax)
  sub    $0x1,%r14d
  mov    0x18(%rsp),%rax
  mov    %r14d,(%rax)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getPalindrome(char *str, int left, int right, int *start, int *end) {
  while (left >= 0 && right <= strlen(str) - 1 && str[left] == str[right]) {
    left--;
    right++;
  }
  *start = left + 1;
  *end = right - 1;
}
```