user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  lea    -0x3c(%rbp),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%eax
  mov    %rbx,-0x68(%rbp)
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  je     L39
L50:
  mov    -0x68(%rbp),%rsi
  mov    %r12,%rdi
  mov    %rsp,-0x58(%rbp)
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0x0(,%rax,4),%r15
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L7
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L3
L7:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L5
  orq    $0x0,-0x8(%rsp,%rdx,1)
L5:
  lea    0x3(%rsp),%r13
  mov    %r13,%rax
  and    $0xfffffffffffffffc,%r13
  shr    $0x2,%rax
  mov    %r13,-0x50(%rbp)
  mov    %rax,-0x60(%rbp)
  test   %ecx,%ecx
  jle    L91
  shr    $0x2,%r15
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  mov    %r15,-0x48(%rbp)
  nopl   0x0(%rax)
L37:
  mov    -0x50(%rbp),%rax
  xor    %r13d,%r13d
  lea    (%rax,%r14,4),%r15
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r15,%rsi
  mov    %r12,%rdi
  add    $0x1,%r13d
  add    $0x4,%r15
  call   <scanf@plt>
  cmp    %ebx,%r13d
  jle    L49
  mov    -0x3c(%rbp),%r8d
  add    $0x1,%ebx
  add    -0x48(%rbp),%r14
  cmp    %ebx,%r8d
  jg     L37
  sub    $0x1,%r8d
  js     L91
  mov    -0x48(%rbp),%rbx
  movslq %r8d,%rdi
  mov    -0x50(%rbp),%r13
  lea    -0x1(%rdi),%r10
  mov    %rbx,%r11
  mov    %r10,%r9
  neg    %r11
  shl    $0x2,%r11
  mov    %r11,%rax
  imul   %r10,%rax
  sub    %rax,%r13
  nopl   0x0(%rax)
L12:
  sub    %r9,%rdi
  mov    %r13,%rax
  xor    %ecx,%ecx
  imul   %rbx,%rdi
  nopl   0x0(%rax)
L67:
  mov    (%rax,%rdi,4),%edx
  mov    0x4(%rax,%rdi,4),%esi
  add    $0x1,%ecx
  cmp    %esi,%edx
  cmovl  %esi,%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r8d,%ecx
  jle    L67
  sub    $0x1,%r8d
  add    %r11,%r13
  mov    %r10,%rdi
  sub    $0x1,%r9
  cmp    $0xffffffff,%r8d
  je     L91
  sub    $0x1,%r10
  jmp    L12
  nopl   0x0(%rax)
L91:
  mov    -0x60(%rbp),%rax
  lea    D13(%rip),%rdi
  mov    0x0(,%rax,4),%esi
  call   <printf@plt>
  mov    -0x40(%rbp),%eax
  mov    -0x58(%rbp),%rsp
  lea    -0x1(%rax),%edx
  mov    %edx,-0x40(%rbp)
  test   %eax,%eax
  jne    L50
L39:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D13
datatype: string

tool: D4: %d

tool: D13: %d


assistant: ```c
int main(void) {
  int T, N, i, j, max_path = 0;
  scanf("%d", &T);
  while (T--) {
    scanf("%d", &N);
    int arr[N][N];
    i = 0;
    for (i = 0; i < N; i++) {
      for (j = 0; j <= i; j++) {
        scanf("%d", &arr[i][j]);
      }
    }
    for (i = N - 1; i >= 0; i--) {
      for (j = 0; j <= i; j++) {
        arr[i - 1][j] += arr[i][j] >= arr[i][j + 1] ? arr[i][j] : arr[i][j + 1];
      }
    }
    printf("%d\n", arr[0][0]);
  }
  return 0;
}
```