ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<Encrypt>:
  endbr64
  push   %r15
  lea    0xc(%rdi),%rax
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  lea    0x8(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbx,%rbp
  sub    $0x28,%rsp
  mov    0xcc(%rsi),%edi
  mov    %rsi,0x18(%rsp)
  mov    %rax,0x10(%rsp)
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x4(%r12)
  mov    0xc8(%rbx),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    0xc(%r12),%eax
  mov    %eax,0xc(%r12)
  mov    %eax,%edi
  lea    0xc0(%rbx),%rax
  mov    %rax,0x8(%rsp)
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0xc(%r12),%edi
L18:
  mov    0x8(%r12),%r15d
  add    $0x8,%rbp
  call   <F@plt>
  mov    -0x8(%rbp),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x4(%r12),%edi
  xor    %eax,%ebx
  xor    %r15d,%ebx
  mov    (%r12),%r15d
  mov    %ebx,0x8(%r12)
  call   <F@plt>
  mov    -0x4(%rbp),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x10(%rsp),%rdi
  mov    %r12,%rcx
  mov    %r14,%rdx
  xor    %eax,%ebx
  mov    %r13,%rsi
  xor    %r15d,%ebx
  mov    %ebx,(%r12)
  call   <RP@plt>
  cmp    %rbp,0x8(%rsp)
  jne    L1
  mov    0xc(%r12),%edi
  mov    0x8(%r12),%ebp
  call   <F@plt>
  mov    0x18(%rsp),%r14
  mov    %eax,%ebx
  mov    0xc0(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x4(%r12),%edi
  xor    %eax,%ebx
  xor    %ebp,%ebx
  mov    (%r12),%ebp
  mov    %ebx,0x8(%r12)
  call   <F@plt>
  mov    0xc4(%r14),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,%ebx
  xor    %ebp,%ebx
  mov    %ebx,(%r12)
  mov    0xd0(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0xc(%r12)
  mov    0xd4(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x4(%r12)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *x3 = (uint16_t *)block;
  uint16_t *x2 = x3 + 1;
  uint16_t *x1 = x3 + 2;
  uint16_t *x0 = x3 + 3;
  uint16_t *rk = (uint16_t *)roundKeys;
  *x2 ^= READ_ROUND_KEY_WORD(rk[51]);
  *x0 ^= READ_ROUND_KEY_WORD(rk[50]);
  for (i = 0; i < 25 - 1; ++i) {
    *x1 = *x1 ^ F(*x0) ^ READ_ROUND_KEY_WORD(rk[2 * i]);
    *x3 = *x3 ^ F(*x2) ^ READ_ROUND_KEY_WORD(rk[2 * i + 1]);
    RP(x0, x1, x2, x3);
  }
  *x1 = *x1 ^ F(*x0) ^ READ_ROUND_KEY_WORD(rk[2 * 25 - 2]);
  *x3 = *x3 ^ F(*x2) ^ READ_ROUND_KEY_WORD(rk[2 * 25 - 1]);
  *x0 ^= READ_ROUND_KEY_WORD(rk[52]);
  *x2 ^= READ_ROUND_KEY_WORD(rk[53]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Encrypt>:
  endbr64
  push   %r15
  lea    0xc(%rdi),%rax
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  lea    0x8(%rdi),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rbx,%rbp
  sub    $0x28,%rsp
  mov    0xcc(%rsi),%edi
  mov    %rsi,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x4(%r12)
  mov    0xc8(%rbx),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    0xc(%r12),%eax
  mov    %eax,0xc(%r12)
  mov    %eax,%edi
  lea    0xc0(%rbx),%rax
  mov    %rax,0x10(%rsp)
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    0xc(%r12),%edi
L4:
  mov    0x8(%r12),%r15d
  add    $0x8,%rbp
  call   <F@plt>
  mov    -0x8(%rbp),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x4(%r12),%edi
  xor    %eax,%ebx
  xor    %r15d,%ebx
  mov    (%r12),%r15d
  mov    %ebx,0x8(%r12)
  call   <F@plt>
  mov    -0x4(%rbp),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12,%rcx
  mov    %r14,%rdx
  xor    %eax,%ebx
  mov    %r13,%rsi
  xor    %r15d,%ebx
  mov    %ebx,(%r12)
  call   <RP@plt>
  cmp    %rbp,0x10(%rsp)
  jne    L12
  mov    0xc(%r12),%edi
  mov    0x8(%r12),%ebp
  call   <F@plt>
  mov    0x18(%rsp),%r14
  mov    %eax,%ebx
  mov    0xc0(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  mov    0x4(%r12),%edi
  xor    %eax,%ebx
  xor    %ebp,%ebx
  mov    (%r12),%ebp
  mov    %ebx,0x8(%r12)
  call   <F@plt>
  mov    0xc4(%r14),%edi
  mov    %eax,%ebx
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,%ebx
  xor    %ebp,%ebx
  mov    %ebx,(%r12)
  mov    0xd0(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0xc(%r12)
  mov    0xd4(%r14),%edi
  call   <READ_ROUND_KEY_WORD@plt>
  xor    %eax,0x4(%r12)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i;
  uint16_t *x3 = (uint16_t *)block;
  uint16_t *x2 = x3 + 1;
  uint16_t *x1 = x3 + 2;
  uint16_t *x0 = x3 + 3;
  uint16_t *rk = (uint16_t *)roundKeys;
  *x2 ^= READ_ROUND_KEY_WORD(rk[51]);
  *x0 ^= READ_ROUND_KEY_WORD(rk[50]);
  for (i = 0; i < 25 - 1; ++i) {
    *x1 = *x1 ^ F(*x0) ^ READ_ROUND_KEY_WORD(rk[2 * i]);
    *x3 = *x3 ^ F(*x2) ^ READ_ROUND_KEY_WORD(rk[2 * i + 1]);
    RP(x0, x1, x2, x3);
  }
  *x1 = *x1 ^ F(*x0) ^ READ_ROUND_KEY_WORD(rk[2 * 25 - 2]);
  *x3 = *x3 ^ F(*x2) ^ READ_ROUND_KEY_WORD(rk[2 * 25 - 1]);
  *x0 ^= READ_ROUND_KEY_WORD(rk[52]);
  *x2 ^= READ_ROUND_KEY_WORD(rk[53]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L16
L37:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L35:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x2,-0x14(%rbp)
  jle    L35
  addl   $0x1,-0x18(%rbp)
L16:
  cmpl   $0x6,-0x18(%rbp)
  jle    L37
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string

tool: D14: smskinv

tool: D16: # c::%s:len=%d


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smskinv", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D17(%rip),%r15
  jmp    L34
L0:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L35
L34:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0x989680,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L21:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L21
  jmp    L0
L35:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D9
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D17: smskinv

tool: D9: # c::%s:len=%d


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smskinv", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D27(%rip),%r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L3:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L11:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L11
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L3
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string

tool: D27: smskinv

tool: D7: # c::%s:len=%d


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smskinv", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D9(%rip),%r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L8:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0x989680,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L17:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L17
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L8
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D7
datatype: string

tool: D9: smskinv

tool: D4: # c::%s:len=%d


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 10000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smskinv", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_reserved>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L59:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L164
  cmpl   $0x0,-0x1c(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L175
L9:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L164
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    $0x5,%edx
  lea    D22(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L164
L175:
  mov    $0x1,%eax
  jmp    L160
L164:
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  cmp    $0x4,%eax
  jbe    L59
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L81:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L55
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jle    L55
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x34,%al
  jg     L55
  cmpl   $0x0,-0x1c(%rbp)
  je     L129
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L153
L129:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L55
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    $0x4,%edx
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L55
L153:
  mov    $0x1,%eax
  jmp    L160
L55:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L81
  mov    $0x0,%eax
L160:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type_guessed: string
name: retrieve_data
arguments: data_label: D18
type_guessed: string

tool: D22:      

tool: D18:     

assistant: ```c
int is_reserved(char *ans, int islong) {
  int i;
  static const char *dev3[] = {"CON", "AUX", "PRN", "NUL", "   "};
  static const char *dev4[] = {"COM", "LPT"};
  for (i = 0; i < sizeof(dev3) / sizeof(*dev3); i++)
    if (!strncasecmp(ans, dev3[i], 3) && ((islong && !ans[3]) || (!islong && !strncmp(ans + 3, "     ", 5))))
      return 1;
  for (i = 0; i < sizeof(dev4) / sizeof(*dev4); i++)
    if (!strncasecmp(ans, dev4[i], 3) && (ans[3] >= '1' && ans[3] <= '4') && ((islong && !ans[4]) || (!islong && !strncmp(ans + 4, "    ", 4))))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_reserved>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    D28(%rip),%rbx
  lea    0x28(%rbx),%r13
  lea    D30(%rip),%r14
  jmp    L162
L70:
  lea    0x3(%rbp),%rdi
  mov    $0x5,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L83
L114:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L24
L162:
  mov    $0x3,%edx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L114
  test   %r12d,%r12d
  je     L70
  cmpb   $0x0,0x3(%rbp)
  jne    L114
  mov    $0x1,%eax
  jmp    L28
L24:
  lea    D37(%rip),%rbx
  lea    0x10(%rbx),%r13
  lea    D13(%rip),%r14
  jmp    L91
L23:
  lea    0x4(%rbp),%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L109
L153:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L155
L91:
  mov    $0x3,%edx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L153
  movzbl 0x3(%rbp),%eax
  sub    $0x31,%eax
  cmp    $0x3,%al
  ja     L153
  test   %r12d,%r12d
  je     L23
  cmpb   $0x0,0x4(%rbp)
  jne    L153
  mov    $0x1,%eax
  jmp    L28
L155:
  mov    $0x0,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L83:
  mov    $0x1,%eax
  jmp    L28
L109:
  mov    $0x1,%eax
  jmp    L28
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D30:      

tool: D13:     

assistant: ```c
int is_reserved(char *ans, int islong) {
  int i;
  static const char *dev3[] = {"CON", "AUX", "PRN", "NUL", "   "};
  static const char *dev4[] = {"COM", "LPT"};
  for (i = 0; i < sizeof(dev3) / sizeof(*dev3); i++)
    if (!strncasecmp(ans, dev3[i], 3) && ((islong && !ans[3]) || (!islong && !strncmp(ans + 3, "     ", 5))))
      return 1;
  for (i = 0; i < sizeof(dev4) / sizeof(*dev4); i++)
    if (!strncasecmp(ans, dev4[i], 3) && (ans[3] >= '1' && ans[3] <= '4') && ((islong && !ans[4]) || (!islong && !strncmp(ans + 4, "    ", 4))))
      return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_reserved>:
  endbr64
  push   %r15
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D8(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D25(%rip),%rbx
  lea    0x28(%rbx),%r13
  sub    $0x8,%rsp
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L78:
  lea    0x3(%rbp),%rdi
  mov    $0x5,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L75
  nopl   (%rax)
L20:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L49
  mov    (%rbx),%rsi
L69:
  mov    $0x3,%edx
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L20
  test   %r12d,%r12d
  je     L78
  cmpb   $0x0,0x3(%rbp)
  jne    L20
L75:
  mov    $0x1,%eax
  jmp    L66
  nop
L49:
  mov    $0x2,%ebx
  lea    D10(%rip),%rsi
  lea    0x4(%rbp),%r15
  lea    D12(%rip),%r14
  lea    D19(%rip),%r13
L128:
  mov    $0x3,%edx
  mov    %rbp,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L81
  movzbl 0x3(%rbp),%eax
  sub    $0x31,%eax
  cmp    $0x3,%al
  ja     L81
  test   %r12d,%r12d
  jne    L95
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L75
  nopl   0x0(%rax,%rax,1)
L81:
  mov    %r13,%rsi
  cmp    $0x1,%ebx
  je     L83
  mov    $0x1,%ebx
  jmp    L128
  nopw   0x0(%rax,%rax,1)
L83:
  xor    %eax,%eax
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L95:
  cmpb   $0x0,0x4(%rbp)
  jne    L81
  jmp    L75
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D6:      

tool: D8: CON

tool: D10: COM

tool: D12:     

tool: D19: LPT

assistant: ```c
int is_reserved(char *ans, int islong) {
  int i;
  static const char *dev3[] = {"CON", "AUX", "PRN", "NUL", "   "};
  static const char *dev4[] = {"COM", "LPT"};
  for (i = 0; i < sizeof(dev3) / sizeof(*dev3); i++)
    if (!strncasecmp(ans, dev3[i], 3) && ((islong && !ans[3]) || (!islong && !strncmp(ans + 3, "     ", 5))))
      return 1;
  for (i = 0; i < sizeof(dev4) / sizeof(*dev4); i++)
    if (!strncasecmp(ans, dev4[i], 3) && (ans[3] >= '1' && ans[3] <= '4') && ((islong && !ans[4]) || (!islong && !strncmp(ans + 4, "    ", 4))))
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_reserved>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    0x28(%rbp),%r13
  mov    %rdi,%rbx
  test   %esi,%esi
  jne    L117
  lea    D26(%rip),%r14
L119:
  mov    0x0(%rbp),%rsi
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L135
  lea    0x3(%rbx),%rdi
  mov    $0x5,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L147
L135:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L119
L29:
  lea    D25(%rip),%rbp
  lea    D28(%rip),%r14
  lea    0x10(%rbp),%r13
L54:
  mov    0x0(%rbp),%rsi
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L103
  movzbl 0x3(%rbx),%eax
  sub    $0x31,%eax
  cmp    $0x3,%al
  ja     L103
  test   %r12d,%r12d
  jne    L33
  lea    0x4(%rbx),%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L147
  nop
L103:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L54
  xor    %eax,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L117:
  mov    0x0(%rbp),%rsi
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %eax,%eax
  jne    L5
  cmpb   $0x0,0x3(%rbx)
  je     L147
L5:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  jne    L117
  jmp    L29
  nopl   0x0(%rax)
L33:
  cmpb   $0x0,0x4(%rbx)
  jne    L103
L147:
  mov    $0x1,%eax
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: label: D26
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string

tool: D26:      

tool: D28:     

assistant: ```c
int is_reserved(char *ans, int islong) {
  int i;
  static const char *dev3[] = {"CON", "AUX", "PRN", "NUL", "   "};
  static const char *dev4[] = {"COM", "LPT"};
  for (i = 0; i < sizeof(dev3) / sizeof(*dev3); i++)
    if (!strncasecmp(ans, dev3[i], 3) && ((islong && !ans[3]) || (!islong && !strncmp(ans + 3, "     ", 5))))
      return 1;
  for (i = 0; i < sizeof(dev4) / sizeof(*dev4); i++)
    if (!strncasecmp(ans, dev4[i], 3) && (ans[3] >= '1' && ans[3] <= '4') && ((islong && !ans[4]) || (!islong && !strncmp(ans + 4, "    ", 4))))
      return 1;
  return 0;
}
```