ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<iTlvSerachTemplate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_iTlvCheckTlvObj@plt>
  test   %eax,%eax
  js     L53
  cmp    %r13d,%eax
  jg     L53
  testb  $0x20,(%rbx)
  je     L199
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <iTlvValue@plt>
  mov    %eax,%ebx
  mov    $0xffffd8ec,%eax
  test   %ebx,%ebx
  jg     L134
  jmp    L82
L62:
  test   %ebx,%ebx
  jle    L206
  call   <_iTlvCheckTlvObj@plt>
  test   %eax,%eax
  js     L126
  cmp    %ebx,%eax
  jg     L126
  test   %ebp,%ebp
  jle    L203
  sub    $0x1,%ebp
  movslq %eax,%rdx
  add    %rdx,(%rsp)
  sub    %eax,%ebx
  test   %ebx,%ebx
  jle    L121
L134:
  mov    (%rsp),%rdi
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  jbe    L62
  test   %ebx,%ebx
  jle    L62
L149:
  add    $0x1,%rdi
  mov    %rdi,(%rsp)
  sub    $0x1,%ebx
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  jbe    L62
  test   %ebx,%ebx
  jg     L149
  jmp    L62
L203:
  mov    (%rsp),%rdx
  mov    %rdx,(%r12)
  jmp    L82
L53:
  mov    $0xffffd8ee,%eax
  jmp    L82
L199:
  mov    $0xffffd8ee,%eax
  jmp    L82
L206:
  mov    $0xffffd8ec,%eax
L82:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L156
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L126:
  mov    $0xffffd8ee,%eax
  jmp    L82
L121:
  mov    $0xffffd8ec,%eax
  jmp    L82
L156:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iTlvSerachTemplate(unsigned char *psTemplate, int iTemplateLen, int iIndex, unsigned char **ppsTlvObj) {
  int iDataLen;
  unsigned char *psData;
  int iRet;
  iRet = _iTlvCheckTlvObj(psTemplate);
  if (iRet < 0 || iRet > iTemplateLen)
    return (-10002);
  if (((psTemplate[0] & 0x20) != 0x20))
    return (-10002);
  iDataLen = iTlvValue(psTemplate, &psData);
  while (iDataLen > 0) {
    while ((*psData == 0x00 || *psData == 0xff) && (iDataLen > 0)) {
      psData++;
      iDataLen--;
    }
    if (iDataLen <= 0)
      break;
    iRet = _iTlvCheckTlvObj(psData);
    if (iRet < 0 || iRet > iDataLen)
      return (-10002);
    if (iIndex <= 0) {
      *ppsTlvObj = psData;
      return (iRet);
    }
    iIndex--;
    psData += iRet;
    iDataLen -= iRet;
  }
  return (-10004);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iTlvSerachTemplate>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_iTlvCheckTlvObj@plt>
  test   %eax,%eax
  js     L29
  cmp    %ebx,%eax
  jg     L29
  testb  $0x20,0x0(%r13)
  je     L29
  mov    %r13,%rdi
  mov    %rsp,%rsi
  call   <iTlvValue@plt>
  mov    (%rsp),%rdi
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L138
  xchg   %ax,%ax
L99:
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  ja     L4
  jmp    L95
  nopl   0x0(%rax)
L65:
  test   %ebx,%ebx
  je     L138
L4:
  add    $0x1,%rdi
  sub    $0x1,%ebx
  mov    %rdi,(%rsp)
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  ja     L65
  test   %ebx,%ebx
  je     L138
L95:
  call   <_iTlvCheckTlvObj@plt>
  cmp    %ebx,%eax
  ja     L29
  mov    (%rsp),%rdi
  test   %r12d,%r12d
  jle    L102
  movslq %eax,%rdx
  sub    %eax,%ebx
  sub    $0x1,%r12d
  add    %rdx,%rdi
  mov    %rdi,(%rsp)
  test   %ebx,%ebx
  jg     L99
  nopl   0x0(%rax,%rax,1)
L138:
  mov    $0xffffd8ec,%eax
L146:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L111
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    $0xffffd8ee,%eax
  jmp    L146
L102:
  mov    %rdi,0x0(%rbp)
  jmp    L146
L111:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iTlvSerachTemplate(unsigned char *psTemplate, int iTemplateLen, int iIndex, unsigned char **ppsTlvObj) {
  int iDataLen;
  unsigned char *psData;
  int iRet;
  iRet = _iTlvCheckTlvObj(psTemplate);
  if (iRet < 0 || iRet > iTemplateLen)
    return (-10002);
  if (((psTemplate[0] & 0x20) != 0x20))
    return (-10002);
  iDataLen = iTlvValue(psTemplate, &psData);
  while (iDataLen > 0) {
    while ((*psData == 0x00 || *psData == 0xff) && (iDataLen > 0)) {
      psData++;
      iDataLen--;
    }
    if (iDataLen <= 0)
      break;
    iRet = _iTlvCheckTlvObj(psData);
    if (iRet < 0 || iRet > iDataLen)
      return (-10002);
    if (iIndex <= 0) {
      *ppsTlvObj = psData;
      return (iRet);
    }
    iIndex--;
    psData += iRet;
    iDataLen -= iRet;
  }
  return (-10004);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iTlvSerachTemplate>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_iTlvCheckTlvObj@plt>
  test   %eax,%eax
  js     L17
  cmp    %ebx,%eax
  jg     L17
  testb  $0x20,0x0(%r13)
  je     L17
  mov    %r13,%rdi
  mov    %rsp,%rsi
  call   <iTlvValue@plt>
  mov    (%rsp),%rdi
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L79
  xchg   %ax,%ax
L85:
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  ja     L98
  jmp    L130
  nopl   0x0(%rax)
L73:
  test   %ebx,%ebx
  je     L79
L98:
  add    $0x1,%rdi
  sub    $0x1,%ebx
  mov    %rdi,(%rsp)
  movzbl (%rdi),%eax
  sub    $0x1,%eax
  cmp    $0xfd,%al
  ja     L73
  test   %ebx,%ebx
  je     L79
L130:
  call   <_iTlvCheckTlvObj@plt>
  cmp    %ebx,%eax
  ja     L17
  mov    (%rsp),%rdi
  test   %r12d,%r12d
  jle    L127
  movslq %eax,%rdx
  sub    %eax,%ebx
  sub    $0x1,%r12d
  add    %rdx,%rdi
  mov    %rdi,(%rsp)
  test   %ebx,%ebx
  jg     L85
  nopl   0x0(%rax,%rax,1)
L79:
  mov    $0xffffd8ec,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    $0xffffd8ee,%eax
  jmp    L2
L127:
  mov    %rdi,0x0(%rbp)
  jmp    L2
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int iTlvSerachTemplate(unsigned char *psTemplate, int iTemplateLen, int iIndex, unsigned char **ppsTlvObj) {
  int iDataLen;
  unsigned char *psData;
  int iRet;
  iRet = _iTlvCheckTlvObj(psTemplate);
  if (iRet < 0 || iRet > iTemplateLen)
    return (-10002);
  if (((psTemplate[0] & 0x20) != 0x20))
    return (-10002);
  iDataLen = iTlvValue(psTemplate, &psData);
  while (iDataLen > 0) {
    while ((*psData == 0x00 || *psData == 0xff) && (iDataLen > 0)) {
      psData++;
      iDataLen--;
    }
    if (iDataLen <= 0)
      break;
    iRet = _iTlvCheckTlvObj(psData);
    if (iRet < 0 || iRet > iDataLen)
      return (-10002);
    if (iIndex <= 0) {
      *ppsTlvObj = psData;
      return (iRet);
    }
    iIndex--;
    psData += iRet;
    iDataLen -= iRet;
  }
  return (-10004);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<squareRoot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  D11(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L14
L19:
  movss  -0x14(%rbp),%xmm0
  divss  -0x4(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  movss  D23(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  subss  -0x14(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <absoluteValue@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm2
  comiss -0x18(%rbp),%xmm2
  jae    L19
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: f32
name: disassemble_data
arguments: data_tag: D23
type_infered: f32
name: disassemble_data
arguments: data_tag: D22
type_infered: string

tool: D11: 1

tool: D23: 2

tool: D22: %.3f


assistant: ```c
float squareRoot(float x, float epsilon) {
  float guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon) {
    guess = (x / guess + guess) / 2.0;
    printf("%.3f\n", guess);
  }
  return guess;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<squareRoot>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  movss  D2(%rip),%xmm6
  movss  %xmm6,0x4(%rsp)
  lea    D12(%rip),%rbx
  jmp    L13
L17:
  movss  0x8(%rsp),%xmm0
  movss  0x4(%rsp),%xmm3
  divss  %xmm3,%xmm0
  addss  %xmm3,%xmm0
  mulss  D11(%rip),%xmm0
  movss  %xmm0,0x4(%rsp)
  mov    %rbx,%rdi
  call   <printf@plt>
L13:
  movss  0x4(%rsp),%xmm2
  movaps %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  0x8(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss 0xc(%rsp),%xmm0
  jae    L17
  movss  0x4(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: f32
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D11
data_type: byte[4]

tool: D2: 1

tool: D12: %.3f


tool: {"D11": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float squareRoot(float x, float epsilon) {
  float guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon) {
    guess = (x / guess + guess) / 2.0;
    printf("%.3f\n", guess);
  }
  return guess;
}
```
user: What is the c source code of the assembly code below?

```asm
<squareRoot>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  D24(%rip),%xmm1
  movss  %xmm0,0x4(%rsp)
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L15:
  movss  0x4(%rsp),%xmm0
  mov    %rbx,%rdi
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm1
  mulss  D29(%rip),%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
L19:
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  mulss  %xmm1,%xmm0
  subss  0x4(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss 0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  jae    L15
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: f32
name: extract_symbolic_data
arguments: tag: D29
type_infered: byte[4]

tool: D3: %.3f


tool: D24: 1

tool: {"D29": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float squareRoot(float x, float epsilon) {
  float guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon) {
    guess = (x / guess + guess) / 2.0;
    printf("%.3f\n", guess);
  }
  return guess;
}
```
user: Translate the below assembly code into C programming language:

```asm
<squareRoot>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  D10(%rip),%xmm1
  movss  %xmm0,0x4(%rsp)
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L2:
  movss  0x4(%rsp),%xmm0
  mov    %rbx,%rdi
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm1
  mulss  D26(%rip),%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
L11:
  movaps %xmm1,%xmm0
  movss  %xmm1,0x8(%rsp)
  mulss  %xmm1,%xmm0
  subss  0x4(%rsp),%xmm0
  call   <absoluteValue@plt>
  comiss 0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  jae    L2
  add    $0x10,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: f32
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: byte[4]

tool: D8: %.3f


tool: D10: 1

tool: {"D26": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float squareRoot(float x, float epsilon) {
  float guess = 1.0;
  while (absoluteValue(guess * guess - x) >= epsilon) {
    guess = (x / guess + guess) / 2.0;
    printf("%.3f\n", guess);
  }
  return guess;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<searcher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L14
  mov    $0x1,%eax
  jmp    L11
L14:
  mov    $0x2,%eax
L11:
  leave
  ret
```

assistant: ```c
int searcher(char *url, char *sub) {
  if (strstr(url, sub) != NULL) {
    return 1;
  } else {
    return 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<searcher>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  adc    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int searcher(char *url, char *sub) {
  if (strstr(url, sub) != NULL) {
    return 1;
  } else {
    return 2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<searcher>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  adc    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int searcher(char *url, char *sub) {
  if (strstr(url, sub) != NULL) {
    return 1;
  } else {
    return 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<searcher>:
  endbr64
  sub    $0x8,%rsp
  call   <strstr@plt>
  cmp    $0x1,%rax
  mov    $0x1,%eax
  adc    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int searcher(char *url, char *sub) {
  if (strstr(url, sub) != NULL) {
    return 1;
  } else {
    return 2;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x7372657665722061,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x676e697274732065,%rax
  movabs $0x656c706d61786520,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x2e,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <reverseWords@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char str[] = "This is a reverse string example.";
  reverseWords(str);
  printf("%s\n", str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x2073692073696854,%rax
  movabs $0x7372657665722061,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x676e697274732065,%rax
  movabs $0x656c706d61786520,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x2e,0x20(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <reverseWords@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char str[] = "This is a reverse string example.";
  reverseWords(str);
  printf("%s\n", str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x2e,%eax
  movaps %xmm0,(%rsp)
  movdqa D27(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <reverseWords@plt>
  mov    %rbp,%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: byte[16]
name: unpack_data
arguments: label: D27
type_infered: byte[16]
name: unpack_data
arguments: label: D29
type_infered: string

tool: {"D6": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x72,0x65,0x76,0x65,0x72,0x73]}

tool: {"D27": [0x65,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x65,0x78,0x61,0x6d,0x70,0x6c,0x65]}

tool: D29: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char str[] = "This is a reverse string example.";
  reverseWords(str);
  printf("%s\n", str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  movdqa D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x2e,%eax
  movaps %xmm0,(%rsp)
  movdqa D14(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <reverseWords@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
type_infered: byte[16]
name: parse_data
arguments: data_label: D14
type_infered: byte[16]
name: parse_data
arguments: data_label: D21
type_infered: string

tool: {"D27": [0x54,0x68,0x69,0x73,0x20,0x69,0x73,0x20,0x61,0x20,0x72,0x65,0x76,0x65,0x72,0x73]}

tool: {"D14": [0x65,0x20,0x73,0x74,0x72,0x69,0x6e,0x67,0x20,0x65,0x78,0x61,0x6d,0x70,0x6c,0x65]}

tool: D21: %s


assistant: ```c
int main(int argc, char *argv[]) {
  char str[] = "This is a reverse string example.";
  reverseWords(str);
  printf("%s\n", str);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *realloc(void *ptr, size_t size) {
  void *p = malloc(size);
  if (ptr)
    memcpy(p, ptr, size);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<realloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L0
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L0:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *realloc(void *ptr, size_t size) {
  void *p = malloc(size);
  if (ptr)
    memcpy(p, ptr, size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L8
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *realloc(void *ptr, size_t size) {
  void *p = malloc(size);
  if (ptr)
    memcpy(p, ptr, size);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<realloc>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L9
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *realloc(void *ptr, size_t size) {
  void *p = malloc(size);
  if (ptr)
    memcpy(p, ptr, size);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PatternCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L61
L34:
  mov    -0x20(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L67
  movl   $0x1,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%edx
  lea    (%rax,%rdx,1),%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jae    L67
L40:
  mov    -0x18(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L25
  movl   $0x1,-0x14(%rbp)
  jmp    L12
L25:
  movl   $0x0,-0x14(%rbp)
  jmp    L67
L12:
  addl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x1c(%rbp)
  jb     L40
L67:
  cmpl   $0x0,-0x14(%rbp)
  je     L35
  addl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
L35:
  addl   $0x1,-0x20(%rbp)
L61:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x20(%rbp)
  jb     L34
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int PatternCount(char text[], char pattern[]) {
  unsigned int count = 0;
  unsigned int i, j, z, flag = 0;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == pattern[0]) {
      j = 1;
      z = i + 1;
      if (z + strlen(pattern) < strlen(text))
        do {
          if (text[z] == pattern[j])
            flag = 1;
          else {
            flag = 0;
            break;
          }
          j++;
          z++;
        } while (j < strlen(pattern));
    }
    if (flag) {
      count++;
      flag = 0;
    }
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PatternCount>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L45
L23:
  add    $0x1,%r14d
L69:
  add    $0x1,%ebx
L45:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jbe    L3
  mov    %ebx,%eax
  movzbl (%r12),%ecx
  cmp    %cl,0x0(%rbp,%rax,1)
  jne    L69
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %eax,%r13d
  jae    L69
  mov    $0x1,%r13d
L1:
  lea    (%rbx,%r13,1),%eax
  mov    %r13d,%edx
  movzbl (%r12,%rdx,1),%esi
  cmp    %sil,0x0(%rbp,%rax,1)
  jne    L69
  add    $0x1,%r13d
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  ja     L1
  jmp    L23
L3:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int PatternCount(char text[], char pattern[]) {
  unsigned int count = 0;
  unsigned int i, j, z, flag = 0;
  for (i = 0; i < strlen(text); i++) {
    if (text[i] == pattern[0]) {
      j = 1;
      z = i + 1;
      if (z + strlen(pattern) < strlen(text))
        do {
          if (text[z] == pattern[j])
            flag = 1;
          else {
            flag = 0;
            break;
          }
          j++;
          z++;
        } while (j < strlen(pattern));
    }
    if (flag) {
      count++;
      flag = 0;
    }
  }
  return count;
}
```