user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x7c(%rbp)
  mov    -0x84(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L146:
  addq   $0x8,-0x90(%rbp)
  mov    -0x90(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x2f,%eax
  je     L108
  cmp    $0x2f,%eax
  jg     L24
  cmp    $0x2d,%eax
  je     L49
  cmp    $0x2d,%eax
  jg     L24
  cmp    $0x2a,%eax
  je     L82
  cmp    $0x2b,%eax
  jne    L24
  mov    $0x0,%eax
  call   <pop@plt>
  movsd  %xmm0,-0x98(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movapd %xmm0,%xmm1
  addsd  -0x98(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L107
L82:
  mov    $0x0,%eax
  call   <pop@plt>
  movsd  %xmm0,-0x98(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movapd %xmm0,%xmm2
  mulsd  -0x98(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L107
L49:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x78(%rbp)
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm3
  subsd  -0x78(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L107
L108:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x78(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x78(%rbp),%xmm0
  jp     L37
  pxor   %xmm0,%xmm0
  ucomisd -0x78(%rbp),%xmm0
  je     L73
L37:
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm4
  divsd  -0x78(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  jmp    L107
L73:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L107
L24:
  mov    -0x90(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <push@plt>
  nop
L107:
  addl   $0x1,-0x7c(%rbp)
L48:
  mov    -0x7c(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jl     L146
  mov    $0x0,%eax
  call   <pop@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L90
  call   <__stack_chk_fail@plt>
L90:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string

tool: D8: total commod line arguments:%d


tool: D10: error: zero divisor

tool: D27: 	%.8g


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  double op2;
  char s[100];
  i = 1;
  printf("total commod line arguments:%d\n", argc);
  while (i < argc) {
    switch (*(*++argv)) {
    case '+':
      push(pop() + pop());
      break;
    case '*':
      push(pop() * pop());
      break;
    case '-':
      op2 = pop();
      push(pop() - op2);
      break;
    case '/':
      op2 = pop();
      if (op2 != 0.0)
        push(pop() / op2);
      else
        printf("error: zero divisor\n");
      break;
    default:
      push(atof(*argv));
      break;
    }
    i++;
  }
  printf("\t%.8g\n", pop());
  return 0;
}
```