ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0x4,-0x3c(%rbp)
  movl   $0x6,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  lea    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x4,%ecx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <merge@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L18
L25:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L18:
  cmpl   $0x8,-0x44(%rbp)
  jle    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %d 

assistant: ```c
int main(void) {
  int arr1[9] = {1, 3, 5, 7, 9};
  int arr2[4] = {2, 4, 6, 8};
  merge(arr1, 5, arr2, 4);
  for (int i = 0; i < 9; i++) {
    printf("%d ", arr1[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  mov    %rsp,%rdx
  lea    0x10(%rsp),%rbx
  mov    $0x4,%ecx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <merge@plt>
  lea    0x34(%rsp),%r12
  lea    D7(%rip),%rbp
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: %d 

assistant: ```c
int main(void) {
  int arr1[9] = {1, 3, 5, 7, 9};
  int arr2[4] = {2, 4, 6, 8};
  merge(arr1, 5, arr2, 4);
  for (int i = 0; i < 9; i++) {
    printf("%d ", arr1[i]);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%ecx
  mov    $0x5,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000001,%rax
  lea    0x10(%rsp),%rbx
  mov    %rsp,%rdx
  lea    0x34(%rsp),%r12
  mov    %rbx,%rdi
  movl   $0x0,0x30(%rsp)
  movq   $0x9,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000002,%rax
  mov    %rax,(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x8(%rsp)
  call   <merge@plt>
  nopl   (%rax)
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d 

assistant: ```c
int main(void) {
  int arr1[9] = {1, 3, 5, 7, 9};
  int arr2[4] = {2, 4, 6, 8};
  merge(arr1, 5, arr2, 4);
  for (int i = 0; i < 9; i++) {
    printf("%d ", arr1[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0x4,%ecx
  mov    $0x5,%esi
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x20(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rsp,%rdx
  movdqa D27(%rip),%xmm0
  mov    %rbx,%rdi
  movl   $0x0,0x30(%rsp)
  lea    0x34(%rsp),%r12
  movl   $0x9,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D13(%rip),%xmm0
  movaps %xmm0,(%rsp)
  call   <merge@plt>
  nopl   0x0(%rax)
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D27
data_type: byte[16]
name: parse_data
arguments: data_label: D13
data_type: byte[16]

tool: D10: %d 

tool: {"D27": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D13": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int arr1[9] = {1, 3, 5, 7, 9};
  int arr2[4] = {2, 4, 6, 8};
  merge(arr1, 5, arr2, 4);
  for (int i = 0; i < 9; i++) {
    printf("%d ", arr1[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CopyNextPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L61
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L35
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L61
L35:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  lea    0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  add    $0x1,%ebx
L61:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L72
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L9
L72:
  test   %ebx,%ebx
  jle    L40
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L24:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L75
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L75:
  mov    %ebx,%eax
  jmp    L6
L40:
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int CopyNextPath(to, from)
char *to, **from;
{
  register int n = 0;
  while ((**from != '\0') && (**from != ':')) {
    if (**from == ' ')
      (*from)++;
    else {
      *to++ = *(*from)++;
      n++;
    };
  };
  if (n > 0) {
    *to-- = '\0';
    if (**from == ':')
      (*from)++;
    if (*to == '/')
      *to = '\0';
    return (n);
  };
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CopyNextPath>:
  endbr64
  mov    (%rsi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L98
  cmp    $0x3a,%dl
  je     L98
  mov    $0x0,%ecx
  jmp    L58
L111:
  add    $0x1,%rax
  mov    %rax,(%rsi)
L60:
  mov    (%rsi),%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L108
  cmp    $0x3a,%dl
  je     L108
L58:
  cmp    $0x20,%dl
  je     L111
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsi)
  movzbl (%rax),%eax
  mov    %al,(%rdi)
  add    $0x1,%ecx
  lea    0x1(%rdi),%rdi
  jmp    L60
L108:
  test   %ecx,%ecx
  jg     L80
  mov    $0x0,%ecx
L33:
  mov    %ecx,%eax
  ret
L80:
  movb   $0x0,(%rdi)
  mov    (%rsi),%rax
  cmpb   $0x3a,(%rax)
  je     L116
L34:
  cmpb   $0x2f,-0x1(%rdi)
  jne    L33
  movb   $0x0,-0x1(%rdi)
  jmp    L33
L116:
  add    $0x1,%rax
  mov    %rax,(%rsi)
  jmp    L34
L98:
  mov    $0x0,%ecx
  jmp    L33
```

assistant: ```c
int CopyNextPath(to, from)
char *to, **from;
{
  register int n = 0;
  while ((**from != '\0') && (**from != ':')) {
    if (**from == ' ')
      (*from)++;
    else {
      *to++ = *(*from)++;
      n++;
    };
  };
  if (n > 0) {
    *to-- = '\0';
    if (**from == ':')
      (*from)++;
    if (*to == '/')
      *to = '\0';
    return (n);
  };
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CopyNextPath>:
  endbr64
  mov    (%rsi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L19
  xor    %r8d,%r8d
  cmp    $0x3a,%al
  jne    L33
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L50:
  movzbl (%rdx),%eax
  add    $0x1,%r8d
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  mov    (%rsi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L24
L38:
  cmp    $0x3a,%al
  je     L24
L33:
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  cmp    $0x20,%al
  jne    L50
  mov    %rcx,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L38
  nopl   0x0(%rax)
L24:
  test   %r8d,%r8d
  jne    L10
L19:
  xor    %r8d,%r8d
L41:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L10:
  movb   $0x0,(%rdi)
  mov    (%rsi),%rax
  cmpb   $0x3a,(%rax)
  jne    L14
  add    $0x1,%rax
  mov    %rax,(%rsi)
L14:
  cmpb   $0x2f,-0x1(%rdi)
  jne    L41
  movb   $0x0,-0x1(%rdi)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CopyNextPath(to, from)
char *to, **from;
{
  register int n = 0;
  while ((**from != '\0') && (**from != ':')) {
    if (**from == ' ')
      (*from)++;
    else {
      *to++ = *(*from)++;
      n++;
    };
  };
  if (n > 0) {
    *to-- = '\0';
    if (**from == ':')
      (*from)++;
    if (*to == '/')
      *to = '\0';
    return (n);
  };
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CopyNextPath>:
  endbr64
  mov    (%rsi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L97
  xor    %r8d,%r8d
  cmp    $0x3a,%al
  je     L97
L110:
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  cmp    $0x20,%al
  je     L109
L49:
  movzbl (%rdx),%eax
  lea    0x1(%rdi),%rcx
  add    $0x1,%r8d
  mov    %al,(%rdi)
  mov    (%rsi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L43
  cmp    $0x3a,%al
  je     L43
  mov    %rcx,%rdi
  lea    0x1(%rdx),%rcx
  mov    %rcx,(%rsi)
  cmp    $0x20,%al
  jne    L49
L109:
  movzbl 0x1(%rdx),%eax
  cmp    $0x3a,%al
  je     L89
  test   %al,%al
  je     L89
  mov    %rcx,%rdx
  jmp    L110
  nopw   0x0(%rax,%rax,1)
L89:
  test   %r8d,%r8d
  jne    L85
L97:
  xor    %r8d,%r8d
L26:
  mov    %r8d,%eax
  ret
L85:
  mov    %rdi,%rcx
  nop
L43:
  movb   $0x0,(%rcx)
  mov    (%rsi),%rax
  cmpb   $0x3a,(%rax)
  jne    L112
  add    $0x1,%rax
  mov    %rax,(%rsi)
L112:
  cmpb   $0x2f,-0x1(%rcx)
  jne    L26
  movb   $0x0,-0x1(%rcx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
int CopyNextPath(to, from)
char *to, **from;
{
  register int n = 0;
  while ((**from != '\0') && (**from != ':')) {
    if (**from == ' ')
      (*from)++;
    else {
      *to++ = *(*from)++;
      n++;
    };
  };
  if (n > 0) {
    *to-- = '\0';
    if (**from == ':')
      (*from)++;
    if (*to == '/')
      *to = '\0';
    return (n);
  };
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<regPrintVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  movsd  %xmm0,-0x88(%rbp)
  mov    %rdi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x78(%rbp)
  mov    -0x88(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x60(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x70(%rbp)
  cmpq   $0x0,-0x70(%rbp)
  je     L26
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x78(%rbp)
  jmp    L37
L26:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x78(%rbp)
L37:
  lea    -0x60(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x68(%rbp)
  cmpq   $0x0,-0x68(%rbp)
  je     L4
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,-0x78(%rbp)
  jle    L4
  jmp    L98
L89:
  mov    -0x78(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x78(%rbp)
  movb   $0x0,-0x60(%rbp,%rax,1)
L98:
  cmpq   $0x0,-0x78(%rbp)
  jle    L70
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L89
L70:
  cmpq   $0x0,-0x78(%rbp)
  jle    L4
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L4
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  lea    -0x60(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x70(%rbp)
  je     L13
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,-0x78(%rbp)
  jge    L13
  mov    -0x70(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L13:
  mov    -0x90(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D4: %g

tool: D1: eE

assistant: ```c
char *regPrintVal(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<regPrintVal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D14(%rip),%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L58
  mov    %rsp,%rdi
  mov    %rax,%rbx
  sub    %rdi,%rbx
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L54
  cmp    %rax,%rbp
  ja     L116
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L1:
  mov    %rsp,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  cmp    %rbx,%rax
  jle    L42
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L42
L58:
  mov    %rsp,%r13
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    $0x2e,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L19
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  sub    %r13,%rax
  cmp    %rax,%rbx
  jle    L155
L116:
  mov    %rsp,%rax
  lea    0x1(%rsp),%rdx
  test   %rbx,%rbx
  jle    L177
L176:
  cmpb   $0x30,(%rbx,%rax,1)
  jne    L119
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  jne    L176
L177:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L42
  jmp    L1
L119:
  test   %rbx,%rbx
  jle    L177
  cmpb   $0x2e,(%rsp,%rbx,1)
  jne    L177
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L177
L54:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L42:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  mov    %r12,%rax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L42
L155:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L42
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D14
type_infered: string

tool: D15: %g

tool: D14: eE

assistant: ```c
char *regPrintVal(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<regPrintVal>:
  endbr64
  push   %r13
  lea    D8(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L115
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
  mov    %r13,%rbx
  sub    %rbp,%rbx
  cmp    %rax,%r13
  jbe    L74
  test   %rbx,%rbx
  jle    L70
L77:
  lea    0x1(%rsp),%rdx
  jmp    L73
  nop
L65:
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  je     L104
L73:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x30,%al
  je     L65
  cmp    $0x2e,%al
  je     L39
L104:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %r13,%r13
  je     L140
L15:
  mov    %r13,%rax
  sub    %rbp,%rax
  cmp    %rbx,%rax
  jle    L140
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L140
  nopl   0x0(%rax,%rax,1)
L115:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L74
  sub    $0x1,%ebx
  sub    %rbp,%rax
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  jle    L74
  test   %rbx,%rbx
  jg     L77
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L140:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x68,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L39:
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L104
L70:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L15
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D8: %g

tool: D6: eE

assistant: ```c
char *regPrintVal(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<regPrintVal>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L5
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L15
  mov    %r13,%rbx
  sub    %rbp,%rbx
  cmp    %rax,%r13
  jbe    L15
  test   %rbx,%rbx
  jle    L31
L153:
  lea    0x1(%rsp),%rdx
  jmp    L3
  nop
L63:
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  je     L10
L3:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x30,%al
  je     L63
  cmp    $0x2e,%al
  je     L73
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %r13,%r13
  je     L93
L104:
  mov    %r13,%rax
  sub    %rbp,%rax
  cmp    %rbx,%rax
  jle    L93
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L93
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L15
  sub    $0x1,%ebx
  sub    %rbp,%rax
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  jle    L15
  test   %rbx,%rbx
  jg     L153
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L93:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  add    $0x68,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L73:
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L10
L31:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L104
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D19
type_infered: string

tool: D4: %g

tool: D19: eE

assistant: ```c
char *regPrintVal(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<equi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jle    L48
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L30:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L8
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L30
L48:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: %d 

assistant: ```c
int equi(int A[], int N) {
  int a = -1;
  int i;
  int sum = 0;
  int lsum = 0, rsum = 0;
  if (N > 0) {
    for (i = 0; i < N; i++) {
      sum += A[i];
    }
    for (i = 0; i < N; i++) {
      lsum = sum - rsum - A[i];
      if (lsum == rsum) {
        printf("%d ", i);
        a = i;
      }
      rsum += A[i];
    }
  }
  return a;
}
```