ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<integral_recur>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  movslq %esi,%rax
  mov    D7(%rip),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  sub    $0x1,%esi
  cmp    %edi,%esi
  jl     L12
  mov    %edi,%r12d
  movslq %esi,%rbx
L2:
  mov    0x8(%rbp,%rbx,8),%r13
  mov    $0x1,%edi
  call   <exp@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %r13,%xmm2
  addsd  %xmm2,%xmm0
  lea    0x1(%rbx),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x0(%rbp,%rbx,8)
  sub    $0x1,%rbx
  cmp    %ebx,%r12d
  jle    L2
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: byte[8]

tool: {"D7": [0x5e,0xb9,0xde,0x36,0x53,0x21,0x6e,0x3f]}

assistant: ```c
void integral_recur(int nmin, int nmax, double vals[]) {
  vals[nmax] = .003678;
  for (int n = nmax - 1; n >= nmin; n--) {
    vals[n] = (vals[n + 1] + 1 / (exp(1))) / (n + 1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<integral_recur>:
  endbr64
  mov    D6(%rip),%rcx
  movslq %esi,%rax
  sub    $0x1,%esi
  mov    %rcx,(%rdx,%rax,8)
  cmp    %edi,%esi
  jl     L16
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax)
L12:
  movsd  0x8(%r12,%rbx,8),%xmm2
  mov    $0x1,%edi
  movsd  %xmm2,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm0
  lea    0x1(%rbx),%eax
  cvtsi2sd %eax,%xmm1
  addsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  sub    $0x1,%rbx
  cmp    %ebx,%ebp
  jle    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: byte[8]

tool: {"D6": [0x5e,0xb9,0xde,0x36,0x53,0x21,0x6e,0x3f]}

assistant: ```c
void integral_recur(int nmin, int nmax, double vals[]) {
  vals[nmax] = .003678;
  for (int n = nmax - 1; n >= nmin; n--) {
    vals[n] = (vals[n + 1] + 1 / (exp(1))) / (n + 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<integral_recur>:
  endbr64
  mov    D9(%rip),%rcx
  movslq %esi,%rax
  sub    $0x1,%esi
  mov    %rcx,(%rdx,%rax,8)
  cmp    %edi,%esi
  jl     L10
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x10,%rsp
  nopl   0x0(%rax)
L13:
  movsd  0x8(%r12,%rbx,8),%xmm2
  mov    $0x1,%edi
  movsd  %xmm2,0x8(%rsp)
  call   <exp@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  cvtsi2sd %eax,%xmm0
  lea    0x1(%rbx),%eax
  cvtsi2sd %eax,%xmm1
  addsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12,%rbx,8)
  sub    $0x1,%rbx
  cmp    %ebx,%ebp
  jle    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: byte[8]

tool: {"D9": [0x5e,0xb9,0xde,0x36,0x53,0x21,0x6e,0x3f]}

assistant: ```c
void integral_recur(int nmin, int nmax, double vals[]) {
  vals[nmax] = .003678;
  for (int n = nmax - 1; n >= nmin; n--) {
    vals[n] = (vals[n + 1] + 1 / (exp(1))) / (n + 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  negl   -0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  lea    0x0(,%rax,4),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  sub    $0xcc,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x, y;
  x = rand();
  x *= -5;
  y = rand();
  y *= -3;
  return x * y - 204;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  imul   %eax,%ebx
  mov    %ebx,%eax
  shl    $0x4,%eax
  sub    %ebx,%eax
  sub    $0xcc,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x, y;
  x = rand();
  x *= -5;
  y = rand();
  y *= -3;
  return x * y - 204;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  imul   %eax,%ebx
  mov    %ebx,%eax
  shl    $0x4,%eax
  sub    %ebx,%eax
  pop    %rbx
  sub    $0xcc,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x, y;
  x = rand();
  x *= -5;
  y = rand();
  y *= -3;
  return x * y - 204;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  imul   %eax,%ebx
  mov    %ebx,%eax
  shl    $0x4,%eax
  sub    %ebx,%eax
  pop    %rbx
  sub    $0xcc,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int x, y;
  x = rand();
  x *= -5;
  y = rand();
  y *= -3;
  return x * y - 204;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  add    0xc(%rsp),%ebx
  add    0x14(%rsp),%ebx
  mov    %ebx,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movslq %ebx,%rsi
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rsi
  sar    $0x1f,%ebx
  sub    %ebx,%esi
  lea    D51(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  imul   0x14(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D31
datatype: string
name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D35
datatype: string
name: read_data
arguments: label: D51
datatype: string
name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D54
datatype: string
name: read_data
arguments: label: D66
datatype: string

tool: D31: Please, enter three integers: 

tool: D26: %d%d%d

tool: D35: Sum is %d


tool: D51: Average is %d


tool: D14: Product is %d


tool: D54: Smallest is %d


tool: D66: Largest is %d


assistant: ```c
int main(void) {
  int a;
  int b;
  int c;
  int sum;
  int avg;
  int prod;
  int small;
  int large;
  printf("Please, enter three integers: ");
  scanf("%d%d%d", &a, &b, &c);
  sum = a + b + c;
  printf("Sum is %d\n", sum);
  avg = sum / 3;
  printf("Average is %d\n", avg);
  prod = a * b * c;
  printf("Product is %d\n", prod);
  small = a;
  if (b < small)
    small = b;
  if (c < small)
    small = c;
  printf("Smallest is %d\n", small);
  large = a;
  if (b > large)
    large = b;
  if (c > large)
    large = c;
  printf("Largest is %d\n", large);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D69(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  add    0xc(%rsp),%ebx
  xor    %eax,%eax
  add    0x14(%rsp),%ebx
  lea    D68(%rip),%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  movslq %ebx,%rsi
  sar    $0x1f,%ebx
  xor    %eax,%eax
  imul   $0x55555556,%rsi,%rsi
  lea    D16(%rip),%rdi
  shr    $0x20,%rsi
  sub    %ebx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  xor    %eax,%eax
  imul   0x14(%rsp),%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  lea    D24(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  lea    D6(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D69
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D68
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D54
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D69: Please, enter three integers: 

tool: D17: %d%d%d

tool: D68: Sum is %d


tool: D16: Average is %d


tool: D54: Product is %d


tool: D24: Smallest is %d


tool: D6: Largest is %d


assistant: ```c
int main(void) {
  int a;
  int b;
  int c;
  int sum;
  int avg;
  int prod;
  int small;
  int large;
  printf("Please, enter three integers: ");
  scanf("%d%d%d", &a, &b, &c);
  sum = a + b + c;
  printf("Sum is %d\n", sum);
  avg = sum / 3;
  printf("Average is %d\n", avg);
  prod = a * b * c;
  printf("Product is %d\n", prod);
  small = a;
  if (b < small)
    small = b;
  if (c < small)
    small = c;
  printf("Smallest is %d\n", small);
  large = a;
  if (b > large)
    large = b;
  if (c > large)
    large = c;
  printf("Largest is %d\n", large);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D59(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  add    0xc(%rsp),%ebx
  xor    %eax,%eax
  add    0x14(%rsp),%ebx
  lea    D20(%rip),%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  movslq %ebx,%rsi
  sar    $0x1f,%ebx
  xor    %eax,%eax
  imul   $0x55555556,%rsi,%rsi
  lea    D60(%rip),%rdi
  shr    $0x20,%rsi
  sub    %ebx,%esi
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  xor    %eax,%eax
  imul   0x14(%rsp),%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  lea    D46(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%esi
  lea    D66(%rip),%rdi
  cmp    %eax,%esi
  cmovl  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D59
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D60
type_guessed: string
name: extract_symbolic_data
arguments: label: D34
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string
name: extract_symbolic_data
arguments: label: D66
type_guessed: string

tool: D59: Please, enter three integers: 

tool: D33: %d%d%d

tool: D20: Sum is %d


tool: D60: Average is %d


tool: D34: Product is %d


tool: D46: Smallest is %d


tool: D66: Largest is %d


assistant: ```c
int main(void) {
  int a;
  int b;
  int c;
  int sum;
  int avg;
  int prod;
  int small;
  int large;
  printf("Please, enter three integers: ");
  scanf("%d%d%d", &a, &b, &c);
  sum = a + b + c;
  printf("Sum is %d\n", sum);
  avg = sum / 3;
  printf("Average is %d\n", avg);
  prod = a * b * c;
  printf("Product is %d\n", prod);
  small = a;
  if (b < small)
    small = b;
  if (c < small)
    small = c;
  printf("Smallest is %d\n", small);
  large = a;
  if (b > large)
    large = b;
  if (c > large)
    large = c;
  printf("Largest is %d\n", large);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x6,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <printBorder@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L16:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L29:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L29
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L16
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <printBorder@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D27: A

tool: D10: B

tool: D2: A


assistant: ```c
int main() {
  int breite = 6;
  int hoehe = 3;
  printBorder(breite);
  for (int rowHeight = 0; rowHeight < hoehe; rowHeight++) {
    printf("A");
    for (int rowWidth = 0; rowWidth < breite; rowWidth++) {
      printf("B");
    }
    printf("A\n");
  }
  printBorder(breite);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x6,%edi
  call   <printBorder@plt>
  mov    $0x3,%r12d
  lea    D18(%rip),%r14
  lea    D27(%rip),%rbp
  lea    D16(%rip),%r13
L12:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x6,%ebx
L2:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L12
  mov    $0x6,%edi
  call   <printBorder@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
data_type: string
name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D16
data_type: string

tool: D18: A

tool: D27: B

tool: D16: A


assistant: ```c
int main() {
  int breite = 6;
  int hoehe = 3;
  printBorder(breite);
  for (int rowHeight = 0; rowHeight < hoehe; rowHeight++) {
    printf("A");
    for (int rowWidth = 0; rowWidth < breite; rowWidth++) {
      printf("B");
    }
    printf("A\n");
  }
  printBorder(breite);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6,%edi
  lea    D14(%rip),%r14
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  call   <printBorder@plt>
L8:
  mov    %r14,%rdi
  mov    $0x6,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L1:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L8
  mov    $0x6,%edi
  call   <printBorder@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D14: A

tool: D15: A


tool: D18: B

assistant: ```c
int main() {
  int breite = 6;
  int hoehe = 3;
  printBorder(breite);
  for (int rowHeight = 0; rowHeight < hoehe; rowHeight++) {
    printf("A");
    for (int rowWidth = 0; rowWidth < breite; rowWidth++) {
      printf("B");
    }
    printf("A\n");
  }
  printBorder(breite);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x6,%edi
  lea    D25(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  call   <printBorder@plt>
L11:
  mov    %r14,%rdi
  mov    $0x6,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L14:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L11
  mov    $0x6,%edi
  call   <printBorder@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D27
type_guessed: string

tool: D25: A

tool: D0: A


tool: D27: B

assistant: ```c
int main() {
  int breite = 6;
  int hoehe = 3;
  printBorder(breite);
  for (int rowHeight = 0; rowHeight < hoehe; rowHeight++) {
    printf("A");
    for (int rowWidth = 0; rowWidth < breite; rowWidth++) {
      printf("B");
    }
    printf("A\n");
  }
  printBorder(breite);
}
```
user: What is the c source code of the assembly code below?

```asm
<clip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int clip(int v, int minv, int maxv) {
  v = (v < minv) ? minv : v;
  v = (v > maxv) ? maxv : v;
  return v;
}
```
user: What is the c source code of the assembly code below?

```asm
<clip>:
  endbr64
  cmp    %esi,%edi
  cmovl  %esi,%edi
  cmp    %edx,%edi
  mov    %edx,%eax
  cmovle %edi,%eax
  ret
```

assistant: ```c
int clip(int v, int minv, int maxv) {
  v = (v < minv) ? minv : v;
  v = (v > maxv) ? maxv : v;
  return v;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clip>:
  endbr64
  cmp    %esi,%edi
  mov    %edx,%eax
  cmovl  %esi,%edi
  cmp    %edx,%edi
  cmovle %edi,%eax
  ret
```

assistant: ```c
int clip(int v, int minv, int maxv) {
  v = (v < minv) ? minv : v;
  v = (v > maxv) ? maxv : v;
  return v;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clip>:
  endbr64
  cmp    %esi,%edi
  mov    %edx,%eax
  cmovl  %esi,%edi
  cmp    %edx,%edi
  cmovle %edi,%eax
  ret
```

assistant: ```c
int clip(int v, int minv, int maxv) {
  v = (v < minv) ? minv : v;
  v = (v > maxv) ? maxv : v;
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L18
L32:
  cmpl   $0x2,-0x14(%rbp)
  jne    L23
  mov    $0x1,%eax
  jmp    L18
L23:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  add    %ebx,%eax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 1) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else {
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fib>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L18
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %eax,%ebp
  lea    -0x2(%rbx),%edi
  call   <fib>
  add    %ebp,%eax
  jmp    L19
L15:
  ret
```

assistant: ```c
int fib(int n) {
  if (n == 1) {
    return 0;
  } else if (n == 2) {
    return 1;
  } else {
    return fib(n - 1) + fib(n - 2);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x1024(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L19
L24:
  mov    -0x1014(%rbp),%edx
  lea    -0x1010(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
L19:
  lea    -0x1010(%rbp),%rcx
  mov    -0x1024(%rbp),%eax
  mov    $0x1000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x1014(%rbp)
  cmpl   $0x0,-0x1014(%rbp)
  jne    L24
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void copy(int fd) {
  char buf[4096];
  int c;
  while (c = read(fd, buf, sizeof(buf)))
    write(2, buf, c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L3
L25:
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
L3:
  mov    $0x1000,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L25
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void copy(int fd) {
  char buf[4096];
  int c;
  while (c = read(fd, buf, sizeof(buf)))
    write(2, buf, c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebp
  mov    %rsp,%rbx
  jmp    L17
L13:
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
L17:
  mov    $0x1000,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L13
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void copy(int fd) {
  char buf[4096];
  int c;
  while (c = read(fd, buf, sizeof(buf)))
    write(2, buf, c);
}
```