user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D39(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  movq   $0x0,(%rsp)
  mov    %rax,0x8(%rsp)
L61:
  mov    0x8(%rsp),%rax
  mov    (%rsp),%rcx
  add    $0x1,%ebp
  xor    %r15d,%r15d
  mov    %rax,%r12
  lea    (%rax,%rcx,4),%rbx
L32:
  add    $0x1,%r15d
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r15d,%edx
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    $0x3,%r15d
  jne    L32
  addq   $0x3,(%rsp)
  cmp    $0x3,%ebp
  jne    L61
  lea    D47(%rip),%rdi
  lea    D46(%rip),%r13
  call   <puts@plt>
  mov    0x8(%rsp),%rbp
  lea    0x24(%rbp),%rbx
L28:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0xc,%rbp
  call   <printf@plt>
  mov    -0x8(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L28
  lea    D8(%rip),%rdi
  xor    %ebp,%ebp
  lea    D38(%rip),%r14
  call   <puts@plt>
L18:
  xor    %ebx,%ebx
L12:
  cmp    %ebx,%ebp
  je     L14
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L50:
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L12
  mov    $0xa,%edi
  add    $0x1,%ebp
  add    $0xc,%r12
  call   <putchar@plt>
  cmp    $0x3,%ebp
  jne    L18
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L50
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D47
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D46
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D38
type_guessed: string

tool: D39: Digite ELEMENTO da linha %d, coluna %d da matriz: 

tool: D11: %d

tool: D47: Matriz

tool: D46: %d	

tool: D8: 

Matriz menos a diagonal principal


tool: D38: -	

assistant: ```c
int main() {
  int lin, col, tab;
  int mat[3][3];
  for (lin = 0; lin < 3; lin++) {
    for (col = 0; col < 3; col++) {
      printf("Digite ELEMENTO da linha %d, coluna %d da matriz: ", lin + 1, col + 1);
      scanf("%d", &mat[lin][col]);
    }
  }
  printf("Matriz\n");
  for (lin = 0; lin < 3; lin++) {
    for (col = 0; col < 3; col++) {
      printf("%d\t", mat[lin][col]);
    }
    printf("\n");
  }
  printf("\n\nMatriz menos a diagonal principal\n\n");
  for (lin = 0; lin < 3; lin++) {
    for (col = 0; col < 3; col++) {
      if (lin != col)
        printf("%d\t", mat[lin][col]);
      else
        printf("-\t");
    }
    printf("\n");
  }
  return 0;
}
```