ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_hashcode>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <assert@plt>
  movsbl 0x0(%rbp),%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %edi,%edi
  test   %ebx,%ebx
  setg   %dil
  xor    %eax,%eax
  call   <assert@plt>
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L29
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  shl    $0x4,%eax
  add    $0x1,%rbp
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L6
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L6:
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  jne    L12
  xor    %edx,%edx
  add    $0x8,%rsp
  div    %ebx
  pop    %rbx
  pop    %rbp
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int str_hashcode(const char *str, const int range) {
  register unsigned int h = 0;
  register unsigned int g;
  assert(str);
  assert(*str);
  assert(range > 0);
  while (*str) {
    h = (h << 4) + (*str++);
    if (g = h & 0xf0000000) {
      h = h ^ (g >> 24);
      h = h ^ g;
    }
  }
  return h % range;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_multiple_arg_token_next>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L54
  mov    $0x0,%eax
  jmp    L10
L54:
  mov    -0x18(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L30
L71:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L52
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
L30:
  cmpq   $0x0,-0x8(%rbp)
  jne    L71
  jmp    L76
L52:
  nop
L76:
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L45
L38:
  mov    $0x0,%eax
  jmp    L10
L45:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L10:
  leave
  ret
```

assistant: ```c
const char *get_multiple_arg_token_next(const char *arg) {
  const char *tok;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
    } else
      break;
  }
  if (!tok || strlen(tok) == 1)
    return 0;
  return tok + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_multiple_arg_token_next>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %rbx
  mov    $0x2c,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L47
L31:
  cmpb   $0x5c,-0x1(%rbx)
  jne    L44
  lea    0x1(%rbx),%rdi
  mov    $0x2c,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L31
L47:
  mov    $0x0,%eax
  jmp    L49
L39:
  mov    %rdi,%rax
  ret
L44:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    0x1(%rbx),%rax
  cmp    $0x1,%edx
  mov    $0x0,%edx
  cmove  %rdx,%rax
L49:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_multiple_arg_token_next(const char *arg) {
  const char *tok;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
    } else
      break;
  }
  if (!tok || strlen(tok) == 1)
    return 0;
  return tok + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_multiple_arg_token_next>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %rbx
  jmp    L45
  nopl   0x0(%rax)
L19:
  cmpb   $0x5c,-0x1(%rax)
  jne    L0
  lea    0x1(%rax),%rdi
L45:
  mov    $0x2c,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L19
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L1
  lea    0x1(%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *get_multiple_arg_token_next(const char *arg) {
  const char *tok;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
    } else
      break;
  }
  if (!tok || strlen(tok) == 1)
    return 0;
  return tok + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_multiple_arg_token_next>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %rbx
  jmp    L15
  nopl   0x0(%rax)
L19:
  cmpb   $0x5c,-0x1(%rax)
  jne    L25
  lea    0x1(%rax),%rdi
L15:
  mov    $0x2c,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L19
L29:
  xor    %eax,%eax
  pop    %rbx
  ret
L25:
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L29
  lea    0x1(%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *get_multiple_arg_token_next(const char *arg) {
  const char *tok;
  if (!arg)
    return 0;
  tok = strchr(arg, ',');
  while (tok) {
    if (*(tok - 1) == '\\') {
      tok = strchr(tok + 1, ',');
    } else
      break;
  }
  if (!tok || strlen(tok) == 1)
    return 0;
  return tok + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<a_times_sb_plus_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x1c(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L11
  nop
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int a_times_sb_plus_c(float *A, float sB, float *C, float *D, int32_t nI) {
  int status = 0;
#pragma omp simd
  for (int i = 0; i < nI; i++) {
    D[i] = C[i] + (A[i] * sB);
  }
BYE:
  return status;
}
```
user: What is the c source code of the assembly code below:

```asm
<a_times_sb_plus_c>:
  endbr64
  test   %ecx,%ecx
  jle    L5
  mov    %ecx,%ecx
  mov    $0x0,%eax
L11:
  movaps %xmm0,%xmm1
  mulss  (%rdi,%rax,4),%xmm1
  addss  (%rsi,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L11
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int a_times_sb_plus_c(float *A, float sB, float *C, float *D, int32_t nI) {
  int status = 0;
#pragma omp simd
  for (int i = 0; i < nI; i++) {
    D[i] = C[i] + (A[i] * sB);
  }
BYE:
  return status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<a_times_sb_plus_c>:
  endbr64
  test   %ecx,%ecx
  jle    L2
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L3:
  movss  (%rdi,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rsi,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L3
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int a_times_sb_plus_c(float *A, float sB, float *C, float *D, int32_t nI) {
  int status = 0;
#pragma omp simd
  for (int i = 0; i < nI; i++) {
    D[i] = C[i] + (A[i] * sB);
  }
BYE:
  return status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<a_times_sb_plus_c>:
  endbr64
  test   %ecx,%ecx
  jle    L46
  lea    0x4(%rdi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  seta   %r8b
  cmp    $0x1,%ecx
  setne  %al
  test   %al,%r8b
  je     L30
  lea    0x4(%rsi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L30
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r9d
  cmp    $0x2,%eax
  jbe    L95
  mov    %ecx,%r8d
  movaps %xmm0,%xmm2
  xor    %eax,%eax
  shr    $0x2,%r8d
  shufps $0x0,%xmm2,%xmm2
  shl    $0x4,%r8
  nopl   0x0(%rax)
L94:
  movups (%rdi,%rax,1),%xmm1
  movups (%rsi,%rax,1),%xmm3
  mulps  %xmm2,%xmm1
  addps  %xmm3,%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L94
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ecx
  je     L46
  sub    %r8d,%ecx
  mov    %ecx,%r9d
  cmp    $0x1,%ecx
  je     L83
L32:
  mov    %r8d,%ecx
  movaps %xmm0,%xmm2
  movq   (%rdi,%rcx,4),%xmm1
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm1
  movq   (%rsi,%rcx,4),%xmm2
  addps  %xmm2,%xmm1
  movlps %xmm1,(%rdx,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L46
L83:
  cltq
  mulss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
L46:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L30:
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L34:
  movss  (%rdi,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rsi,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L34
  xor    %eax,%eax
  ret
L95:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L32
```

assistant: ```c
int a_times_sb_plus_c(float *A, float sB, float *C, float *D, int32_t nI) {
  int status = 0;
#pragma omp simd
  for (int i = 0; i < nI; i++) {
    D[i] = C[i] + (A[i] * sB);
  }
BYE:
  return status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UrlGetFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x38(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L38
L6:
  movsbl -0x11(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  je     L49
  subq   $0x1,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L6
  jmp    L49
L4:
  nop
L49:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D2: ?#

assistant: ```c
size_t UrlGetFile(char *d, size_t sd, char const **ppurl) {
  char const *s;
  char *rd;
  char c;
  assert(d != NULL);
  assert(sd > 0);
  assert(ppurl != NULL);
  assert(*ppurl != NULL);
  rd = d;
  s = *ppurl;
  while (((c = *s) != 0) && (--sd)) {
    if (strchr("?#", c))
      break;
    *d++ = c;
    s++;
  }
  *d = '\0';
  *ppurl = s;
  return ((size_t)(d - rd));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UrlGetFile>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,0x8(%rsp)
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r13,%r13
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpq   $0x0,(%rbx)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  movzbl (%r12),%ebp
  test   %bpl,%bpl
  je     L30
  sub    $0x1,%r13
  je     L31
  mov    %r14,%rbx
  lea    D4(%rip),%r15
L7:
  movsbl %bpl,%esi
  mov    %r15,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L48
  add    $0x1,%rbx
  mov    %bpl,-0x1(%rbx)
  add    $0x1,%r12
  movzbl (%r12),%ebp
  test   %bpl,%bpl
  je     L48
  lea    (%r14,%r13,1),%rax
  cmp    %rax,%rbx
  jne    L7
L48:
  movb   $0x0,(%rbx)
  mov    0x8(%rsp),%rax
  mov    %r12,(%rax)
  mov    %rbx,%rax
  sub    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  mov    %r14,%rbx
  jmp    L48
L31:
  mov    %r14,%rbx
  jmp    L48
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string

tool: D4: ?#

assistant: ```c
size_t UrlGetFile(char *d, size_t sd, char const **ppurl) {
  char const *s;
  char *rd;
  char c;
  assert(d != NULL);
  assert(sd > 0);
  assert(ppurl != NULL);
  assert(*ppurl != NULL);
  rd = d;
  s = *ppurl;
  while (((c = *s) != 0) && (--sd)) {
    if (strchr("?#", c))
      break;
    *d++ = c;
    s++;
  }
  *d = '\0';
  *ppurl = s;
  return ((size_t)(d - rd));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UrlGetFile>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  mov    %rdi,0x8(%rsp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,(%r14)
  setne  %dil
  call   <assert@plt>
  mov    (%r14),%r15
  movzbl (%r15),%ebp
  test   %bpl,%bpl
  je     L12
  mov    %r12,%rax
  sub    $0x1,%rax
  je     L19
  lea    D9(%rip),%r13
  lea    (%rbx,%rax,1),%r12
  jmp    L63
  nopl   (%rax)
L31:
  add    $0x1,%r15
  mov    %bpl,(%rbx)
  add    $0x1,%rbx
  movzbl (%r15),%ebp
  test   %bpl,%bpl
  je     L73
  cmp    %r12,%rbx
  je     L73
L63:
  movsbl %bpl,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L31
L73:
  mov    %rbx,%rax
  sub    0x8(%rsp),%rax
L45:
  movb   $0x0,(%rbx)
  mov    %r15,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    0x8(%rsp),%rbx
  xor    %eax,%eax
  jmp    L45
L19:
  mov    0x8(%rsp),%rbx
  jmp    L45
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: ?#

assistant: ```c
size_t UrlGetFile(char *d, size_t sd, char const **ppurl) {
  char const *s;
  char *rd;
  char c;
  assert(d != NULL);
  assert(sd > 0);
  assert(ppurl != NULL);
  assert(*ppurl != NULL);
  rd = d;
  s = *ppurl;
  while (((c = *s) != 0) && (--sd)) {
    if (strchr("?#", c))
      break;
    *d++ = c;
    s++;
  }
  *d = '\0';
  *ppurl = s;
  return ((size_t)(d - rd));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UrlGetFile>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  mov    %rdi,0x8(%rsp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r14,%r14
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpq   $0x0,(%r14)
  setne  %dil
  call   <assert@plt>
  mov    (%r14),%r15
  movzbl (%r15),%ebp
  test   %bpl,%bpl
  je     L49
  mov    %r12,%rax
  sub    $0x1,%rax
  je     L65
  lea    D6(%rip),%r13
  lea    (%rbx,%rax,1),%r12
  jmp    L78
  nopl   (%rax)
L79:
  add    $0x1,%r15
  mov    %bpl,(%rbx)
  add    $0x1,%rbx
  movzbl (%r15),%ebp
  test   %bpl,%bpl
  je     L0
  cmp    %r12,%rbx
  je     L0
L78:
  movsbl %bpl,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L79
L0:
  mov    %rbx,%rax
  sub    0x8(%rsp),%rax
L50:
  movb   $0x0,(%rbx)
  mov    %r15,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  mov    0x8(%rsp),%rbx
  xor    %eax,%eax
  jmp    L50
L65:
  mov    0x8(%rsp),%rbx
  jmp    L50
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: ?#

assistant: ```c
size_t UrlGetFile(char *d, size_t sd, char const **ppurl) {
  char const *s;
  char *rd;
  char c;
  assert(d != NULL);
  assert(sd > 0);
  assert(ppurl != NULL);
  assert(*ppurl != NULL);
  rd = d;
  s = *ppurl;
  while (((c = *s) != 0) && (--sd)) {
    if (strchr("?#", c))
      break;
    *d++ = c;
    s++;
  }
  *d = '\0';
  *ppurl = s;
  return ((size_t)(d - rd));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D34(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L0
L17:
  movss  -0x4(%rbp),%xmm0
  movss  D57(%rip),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D39(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  -0x4(%rbp),%xmm0
  movss  D14(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L0:
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jae    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D34
type_guessed: byte[4]
name: read_data
arguments: tag: D57
type_guessed: byte[4]
name: read_data
arguments: tag: D39
type_guessed: byte[8]
name: read_data
arguments: tag: D50
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: byte[4]

tool: D16: Fahrenheit	Celsius


tool: {"D34": [0x00,0x00,0x96,0x43]}

tool: {"D57": [0x00,0x00,0x00,0x42]}

tool: {"D39": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D50: %3.0f		%6.1f


tool: {"D14": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr;
  printf("Fahrenheit\tCelsius\n\n");
  for (fahr = 300; fahr >= 0; fahr = (fahr - 20)) {
    printf("%3.0f\t\t%6.1f\n", fahr, (5.0) / (9.0) * (fahr - 32));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x10,%ebx
  movss  D19(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  lea    D0(%rip),%rbp
L1:
  movss  0xc(%rsp),%xmm2
  movaps %xmm2,%xmm1
  subss  D41(%rip),%xmm1
  cvtss2sd %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D25(%rip),%xmm1
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D22(%rip),%xmm2
  movss  %xmm2,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D19
data_type: byte[4]
name: read_data
arguments: data_label: D0
data_type: string
name: read_data
arguments: data_label: D41
data_type: byte[4]
name: read_data
arguments: data_label: D25
data_type: byte[8]
name: read_data
arguments: data_label: D22
data_type: byte[4]

tool: D10: Fahrenheit	Celsius


tool: {"D19": [0x00,0x00,0x96,0x43]}

tool: D0: %3.0f		%6.1f


tool: {"D41": [0x00,0x00,0x00,0x42]}

tool: {"D25": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D22": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr;
  printf("Fahrenheit\tCelsius\n\n");
  for (fahr = 300; fahr >= 0; fahr = (fahr - 20)) {
    printf("%3.0f\t\t%6.1f\n", fahr, (5.0) / (9.0) * (fahr - 32));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D57(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  movss  D59(%rip),%xmm2
  nopw   0x0(%rax,%rax,1)
L0:
  movaps %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  subss  D18(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D16(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D11(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D46
type: string
name: unpack_data
arguments: data_tag: D57
type: string
name: unpack_data
arguments: data_tag: D59
type: byte[4]
name: unpack_data
arguments: data_tag: D18
type: byte[4]
name: unpack_data
arguments: data_tag: D16
type: byte[8]
name: unpack_data
arguments: data_tag: D11
type: byte[4]

tool: D46: Fahrenheit	Celsius


tool: D57: %3.0f		%6.1f


tool: {"D59": [0x00,0x00,0x96,0x43]}

tool: {"D18": [0x00,0x00,0x00,0x42]}

tool: {"D16": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D11": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr;
  printf("Fahrenheit\tCelsius\n\n");
  for (fahr = 300; fahr >= 0; fahr = (fahr - 20)) {
    printf("%3.0f\t\t%6.1f\n", fahr, (5.0) / (9.0) * (fahr - 32));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D50(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  call   <puts@plt>
  movss  D3(%rip),%xmm2
  nopw   0x0(%rax,%rax,1)
L5:
  movaps %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  subss  D0(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D41(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D55(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D28
datatype: string
name: retrieve_data
arguments: label: D50
datatype: string
name: retrieve_data
arguments: label: D3
datatype: byte[4]
name: retrieve_data
arguments: label: D0
datatype: byte[4]
name: retrieve_data
arguments: label: D41
datatype: byte[8]
name: retrieve_data
arguments: label: D55
datatype: byte[4]

tool: D28: Fahrenheit	Celsius


tool: D50: %3.0f		%6.1f


tool: {"D3": [0x00,0x00,0x96,0x43]}

tool: {"D0": [0x00,0x00,0x00,0x42]}

tool: {"D41": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D55": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main() {
  float fahr;
  printf("Fahrenheit\tCelsius\n\n");
  for (fahr = 300; fahr >= 0; fahr = (fahr - 20)) {
    printf("%3.0f\t\t%6.1f\n", fahr, (5.0) / (9.0) * (fahr - 32));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L22
L33:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L48
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L29
L19:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
L22:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L33
  mov    -0xc(%rbp),%eax
L29:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: string

tool: D9: Error after reading %d bytes


assistant: ```c
int do_read(int s, unsigned char *buf, int len) {
  int total, slen, rlen;
  total = 0;
  rlen = len;
  while (total < len) {
    slen = read(s, buf, rlen);
    if (slen != rlen) {
      if (slen < 0) {
        printf("Error after reading %d bytes\n", total);
        return -1;
      }
      rlen -= slen;
      buf += slen;
    }
    total += slen;
  }
  return total;
}
```