ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6548,0x12(%rsp)
  movw   $0x6f,0x16(%rsp)
  movw   $0x6f79,0xf(%rsp)
  movb   $0x0,0x11(%rsp)
  lea    0xf(%rsp),%rsi
  lea    0x12(%rsp),%rbx
  mov    %rbx,%rdi
  call   <squeeze@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: %s


assistant: ```c
int main() {
  char s1[] = "Hello";
  char s2[] = "yo";
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6f79,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x12(%rsp),%rbp
  mov    $0x6f,%eax
  lea    0xf(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x6c6c6548,0x12(%rsp)
  mov    %ax,0x16(%rsp)
  mov    %dx,0xf(%rsp)
  movb   $0x0,0x11(%rsp)
  call   <squeeze@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: %s


assistant: ```c
int main() {
  char s1[] = "Hello";
  char s2[] = "yo";
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6f79,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x12(%rsp),%rbp
  mov    $0x6f,%eax
  lea    0xf(%rsp),%rsi
  mov    %rbp,%rdi
  movl   $0x6c6c6548,0x12(%rsp)
  mov    %ax,0x16(%rsp)
  mov    %dx,0xf(%rsp)
  movb   $0x0,0x11(%rsp)
  call   <squeeze@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: %s


assistant: ```c
int main() {
  char s1[] = "Hello";
  char s2[] = "yo";
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<convert_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  imul   %ebx,%eax
  add    %r12d,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L0
L6:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <my_getnbr_base@plt>
  mov    %eax,-0x1c(%rbp)
  jmp    L13
L19:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x1c(%rbp),%eax
  cltd
  idiv   %esi
  mov    %edx,%ecx
  mov    %ecx,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  cltd
  idiv   %ebx
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L13:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L19
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <rev_str@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
L0:
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *convert_base(char *nbr, char *ib, char *ob) {
  int i;
  int nb;
  char *res;
  i = 0;
  if ((res = malloc(strlen(nbr) + (strlen(ib) * strlen(ob)))) == NULL)
    return (NULL);
  nb = my_getnbr_base(nbr, ib);
  while (nb > 0) {
    res[i] = ob[nb % strlen(ob)];
    nb = nb / strlen(ob);
    i += 1;
  }
  res[i] = '\0';
  res = rev_str(res);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert_base>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  imul   %eax,%ebx
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L2
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <my_getnbr_base@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L6
  mov    $0x1,%ebp
L8:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%eax
  mov    %al,-0x1(%r13,%rbp,1)
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    %ebp,%edx
  add    $0x1,%rbp
  test   %eax,%eax
  jg     L8
L10:
  movslq %edx,%rdx
  movb   $0x0,0x0(%r13,%rdx,1)
  mov    %r13,%rdi
  call   <rev_str@plt>
  mov    %rax,%r13
L2:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
char *convert_base(char *nbr, char *ib, char *ob) {
  int i;
  int nb;
  char *res;
  i = 0;
  if ((res = malloc(strlen(nbr) + (strlen(ib) * strlen(ob)))) == NULL)
    return (NULL);
  nb = my_getnbr_base(nbr, ib);
  while (nb > 0) {
    res[i] = ob[nb % strlen(ob)];
    nb = nb / strlen(ob);
    i += 1;
  }
  res[i] = '\0';
  res = rev_str(res);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convert_base>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  imul   %eax,%ebx
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L6
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <my_getnbr_base@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L29
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L0:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%eax
  mov    %al,-0x1(%r13,%rbp,1)
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebx
  movslq %ebp,%rax
  add    $0x1,%rbp
  test   %ebx,%ebx
  jg     L0
  add    %r13,%rax
L15:
  movb   $0x0,(%rax)
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <rev_str@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %r13,%rax
  jmp    L15
```

assistant: ```c
char *convert_base(char *nbr, char *ib, char *ob) {
  int i;
  int nb;
  char *res;
  i = 0;
  if ((res = malloc(strlen(nbr) + (strlen(ib) * strlen(ob)))) == NULL)
    return (NULL);
  nb = my_getnbr_base(nbr, ib);
  while (nb > 0) {
    res[i] = ob[nb % strlen(ob)];
    nb = nb / strlen(ob);
    i += 1;
  }
  res[i] = '\0';
  res = rev_str(res);
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_base>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  imul   %eax,%ebx
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L12
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <my_getnbr_base@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L23
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L29:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  movslq %edx,%rdx
  movzbl (%r12,%rdx,1),%eax
  mov    %al,-0x1(%r13,%rbp,1)
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebx
  movslq %ebp,%rax
  add    $0x1,%rbp
  test   %ebx,%ebx
  jg     L29
  add    %r13,%rax
L36:
  movb   $0x0,(%rax)
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <rev_str@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r13,%rax
  jmp    L36
```

assistant: ```c
char *convert_base(char *nbr, char *ib, char *ob) {
  int i;
  int nb;
  char *res;
  i = 0;
  if ((res = malloc(strlen(nbr) + (strlen(ib) * strlen(ob)))) == NULL)
    return (NULL);
  nb = my_getnbr_base(nbr, ib);
  while (nb > 0) {
    res[i] = ob[nb % strlen(ob)];
    nb = nb / strlen(ob);
    i += 1;
  }
  res[i] = '\0';
  res = rev_str(res);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chat_client_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L10
  mov    $0xffffffff,%eax
  jmp    L7
L10:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int chat_client_write(int socket_fd, char buf[], int buflen) {
  int ret;
  if ((ret = write(socket_fd, buf, buflen)) != buflen)
    return -1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chat_client_write>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <write@plt>
  cmp    %eax,%ebx
  setne  %al
  movzbl %al,%eax
  neg    %eax
  pop    %rbx
  ret
```

assistant: ```c
int chat_client_write(int socket_fd, char buf[], int buflen) {
  int ret;
  if ((ret = write(socket_fd, buf, buflen)) != buflen)
    return -1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chat_client_write>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  call   <write@plt>
  cmp    %eax,%ebx
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int chat_client_write(int socket_fd, char buf[], int buflen) {
  int ret;
  if ((ret = write(socket_fd, buf, buflen)) != buflen)
    return -1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L7:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L57
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D12(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L11
  movl   $0x0,-0xc(%rbp)
  jmp    L57
L11:
  mov    $0xffffffff,%eax
  jmp    L54
L57:
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  jg     L7
  mov    -0x28(%rbp),%rax
L54:
  leave
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  ssize_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<writen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r14d
  test   %edx,%edx
  jle    L31
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r13d
  jmp    L48
L35:
  sub    %eax,%ebx
  cltq
  add    %rax,%rbp
  test   %ebx,%ebx
  jle    L31
L48:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L35
  mov    D8(%rip),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L33
  mov    %r13d,%eax
  jmp    L35
L33:
  mov    $0xffffffff,%r14d
L31:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  ssize_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L24
  nopl   (%rax)
L17:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L35
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L17
L24:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L35:
  mov    D7(%rip),%rax
  mov    D10(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L17
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  ssize_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L21
  nopl   (%rax)
L33:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L35
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L33
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L35:
  mov    D4(%rip),%rax
  mov    D0(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L33
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  ssize_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<btsl_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  bts    %eax,(%rdx)
  setb   %al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int btsl_mem(unsigned char *base, int bitno) {
  unsigned char res;
  __asm__ __volatile__("btsl\t%2, %0\n\t"
                       "setc\t%1"
                       : "=m"(*base), "=q"(res)
                       : "r"(bitno));
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<btsl_mem>:
  endbr64
  bts    %esi,(%rdi)
  setb   %sil
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int btsl_mem(unsigned char *base, int bitno) {
  unsigned char res;
  __asm__ __volatile__("btsl\t%2, %0\n\t"
                       "setc\t%1"
                       : "=m"(*base), "=q"(res)
                       : "r"(bitno));
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<btsl_mem>:
  endbr64
  bts    %esi,(%rdi)
  setb   %sil
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int btsl_mem(unsigned char *base, int bitno) {
  unsigned char res;
  __asm__ __volatile__("btsl\t%2, %0\n\t"
                       "setc\t%1"
                       : "=m"(*base), "=q"(res)
                       : "r"(bitno));
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<btsl_mem>:
  endbr64
  bts    %esi,(%rdi)
  setb   %sil
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int btsl_mem(unsigned char *base, int bitno) {
  unsigned char res;
  __asm__ __volatile__("btsl\t%2, %0\n\t"
                       "setc\t%1"
                       : "=m"(*base), "=q"(res)
                       : "r"(bitno));
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L16
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L19
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x1c(%rbp),%xmm1
  movss  -0x4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float mean(float *x, int n) {
  int j;
  float add;
  add = 0.0;
  for (j = 1; j <= n; j++)
    add += x[j];
  return (add / n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mean>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    0x4(%rdi),%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L19:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
L27:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
L14:
  pxor   %xmm0,%xmm0
  jmp    L27
```

assistant: ```c
float mean(float *x, int n) {
  int j;
  float add;
  add = 0.0;
  for (j = 1; j <= n; j++)
    add += x[j];
  return (add / n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mean>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi),%rax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rdx,4),%rdx
  nopl   0x0(%rax,%rax,1)
L6:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L6
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float mean(float *x, int n) {
  int j;
  float add;
  add = 0.0;
  for (j = 1; j <= n; j++)
    add += x[j];
  return (add / n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mean>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L48
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L5
  mov    %esi,%ecx
  lea    0x4(%rdi),%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x14(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L45:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L45
  mov    %esi,%ecx
  and    $0xfffffffc,%ecx
  lea    0x1(%rcx),%eax
  cmp    %ecx,%esi
  je     L22
L8:
  movslq %eax,%rcx
  addss  (%rdx,%rcx,4),%xmm0
  lea    0x0(,%rcx,4),%rdi
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jl     L22
  add    $0x2,%eax
  addss  0x4(%rdx,%rdi,1),%xmm0
  cmp    %eax,%esi
  jl     L22
  addss  0x8(%rdx,%rdi,1),%xmm0
L22:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  ret
L5:
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  jmp    L8
```

assistant: ```c
float mean(float *x, int n) {
  int j;
  float add;
  add = 0.0;
  for (j = 1; j <= n; j++)
    add += x[j];
  return (add / n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L20
L31:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L19
  cmpl   $0x0,-0x14(%rbp)
  je     L19
  subq   $0x1,-0x38(%rbp)
L20:
  cmpq   $0x0,-0x38(%rbp)
  jne    L31
L19:
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *ucs1 = (const unsigned char *)s1;
  const unsigned char *ucs2 = (const unsigned char *)s2;
  int d = 0;
  for (; n != 0; n--) {
    const int c1 = tolower(*ucs1++);
    const int c2 = tolower(*ucs2++);
    if (((d = c1 - c2) != 0) || (c2 == '\0')) {
      break;
    }
  }
  return d;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L17
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    (%rdi,%rdx,1),%r12
L21:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%r13d
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%edi
  call   <tolower@plt>
  sub    %eax,%r13d
  test   %eax,%eax
  je     L36
  test   %r13d,%r13d
  jne    L36
  cmp    %rbx,%r12
  jne    L21
L36:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    $0x0,%r13d
  jmp    L36
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *ucs1 = (const unsigned char *)s1;
  const unsigned char *ucs2 = (const unsigned char *)s2;
  int d = 0;
  for (; n != 0; n--) {
    const int c1 = tolower(*ucs1++);
    const int c2 = tolower(*ucs2++);
    if (((d = c1 - c2) != 0) || (c2 == '\0')) {
      break;
    }
  }
  return d;
}
```