ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  lea    D55(%rip),%r13
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x32,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L33:
  lea    (%rbx,%rbp,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
L65:
  lea    (%rbx,%rbp,1),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
L67:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L67
L43:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x79,%al
  je     L21
  cmp    $0x68,%al
  je     L26
  cmp    $0x6c,%al
  je     L33
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L26:
  lea    (%rbx,%rbp,1),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  jmp    L65
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    D51(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D55
datatype: string
name: unpack_data
arguments: data_label: D44
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string
name: unpack_data
arguments: data_label: D57
datatype: string
name: unpack_data
arguments: data_label: D51
datatype: string

tool: D1: Pick a integer from 1 to 100. I will try to guess 

tool: D55: Sorry, I understand only y, h, or l.

tool: D44: Well, then, is it %d?


tool: D10: it.
Respond with a y if my guess is right and with

tool: D23:  an l if it is lower and with a h if it is higher.

tool: D57: Uh...is your number %d?


tool: D51: I knew I could do it!

assistant: ```c
int main(void) {
  int a = 1, b = 100;
  char response;
  printf("Pick a integer from 1 to 100. I will try to guess ");
  printf("it.\nRespond with a y if my guess is right and with");
  printf(" an l if it is lower and with a h if it is higher.\n");
  printf("Uh...is your number %d?\n", (a + b) / 2);
  while ((response = getchar()) != 'y') {
    switch (response) {
    case 'l':
      a = (a + b) / 2;
      printf("Well, then, is it %d?\n", (a + b) / 2);
      break;
    case 'h':
      b = (a + b) / 2;
      printf("Well, then, is it %d?\n", (a + b) / 2);
      break;
    default:
      printf("Sorry, I understand only y, h, or l.\n");
    }
    while (getchar() != '\n')
      continue;
  }
  printf("I knew I could do it!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  lea    D31(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D50(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  mov    $0x32,%esi
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L53:
  lea    (%rbx,%rbp,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
L8:
  lea    (%rbx,%rbp,1),%eax
  mov    %r12,%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
L41:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L41
L69:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x79,%al
  je     L11
  cmp    $0x68,%al
  je     L57
  cmp    $0x6c,%al
  je     L53
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L57:
  lea    (%rbx,%rbp,1),%eax
  mov    %eax,%ebp
  shr    $0x1f,%ebp
  add    %eax,%ebp
  sar    %ebp
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L11:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D50
type_infered: string
name: parse_data
arguments: tag: D58
type_infered: string
name: parse_data
arguments: tag: D60
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string

tool: D21: Pick a integer from 1 to 100. I will try to guess 

tool: D31: Sorry, I understand only y, h, or l.

tool: D12: Well, then, is it %d?


tool: D50: it.
Respond with a y if my guess is right and with

tool: D58:  an l if it is lower and with a h if it is higher.

tool: D60: Uh...is your number %d?


tool: D39: I knew I could do it!

assistant: ```c
int main(void) {
  int a = 1, b = 100;
  char response;
  printf("Pick a integer from 1 to 100. I will try to guess ");
  printf("it.\nRespond with a y if my guess is right and with");
  printf(" an l if it is lower and with a h if it is higher.\n");
  printf("Uh...is your number %d?\n", (a + b) / 2);
  while ((response = getchar()) != 'y') {
    switch (response) {
    case 'l':
      a = (a + b) / 2;
      printf("Well, then, is it %d?\n", (a + b) / 2);
      break;
    case 'h':
      b = (a + b) / 2;
      printf("Well, then, is it %d?\n", (a + b) / 2);
      break;
    default:
      printf("Sorry, I understand only y, h, or l.\n");
    }
    while (getchar() != '\n')
      continue;
  }
  printf("I knew I could do it!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<turn_on_LED>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    %rax,%rdi
  call   <get_LED_flags@plt>
  movzbl -0x9(%rbp),%eax
  or     -0x14(%rbp),%al
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <set_LED_flags@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void turn_on_LED(char which_LED) {
  char flags = 0;
  get_LED_flags(&flags);
  flags |= which_LED;
  set_LED_flags(flags);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<turn_on_LED>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  call   <get_LED_flags@plt>
  mov    %ebx,%edi
  or     0x7(%rsp),%dil
  mov    %dil,0x7(%rsp)
  movsbl %dil,%edi
  call   <set_LED_flags@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void turn_on_LED(char which_LED) {
  char flags = 0;
  get_LED_flags(&flags);
  flags |= which_LED;
  set_LED_flags(flags);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<turn_on_LED>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  call   <get_LED_flags@plt>
  movzbl 0x7(%rsp),%edi
  or     %ebx,%edi
  mov    %dil,0x7(%rsp)
  movsbl %dil,%edi
  call   <set_LED_flags@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void turn_on_LED(char which_LED) {
  char flags = 0;
  get_LED_flags(&flags);
  flags |= which_LED;
  set_LED_flags(flags);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<turn_on_LED>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdi
  movb   $0x0,0x7(%rsp)
  call   <get_LED_flags@plt>
  movzbl 0x7(%rsp),%edi
  or     %ebx,%edi
  mov    %dil,0x7(%rsp)
  movsbl %dil,%edi
  call   <set_LED_flags@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void turn_on_LED(char which_LED) {
  char flags = 0;
  get_LED_flags(&flags);
  flags |= which_LED;
  set_LED_flags(flags);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculateSubgridError_ADR_tau>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x18(%rbp)
  mov    %r9,-0x20(%rbp)
  mov    %al,-0x10(%rbp)
  cmpb   $0x32,-0x10(%rbp)
  jne    L46
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  push   0x50(%rbp)
  push   0x48(%rbp)
  push   0x40(%rbp)
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  mov    0x10(%rbp),%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <calculateSubgridError_ADR_tau_2@plt>
  add    $0x40,%rsp
  jmp    L17
L46:
  cmpb   $0x31,-0x10(%rbp)
  jne    L29
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  push   0x50(%rbp)
  push   0x48(%rbp)
  push   0x40(%rbp)
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  mov    0x10(%rbp),%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <calculateSubgridError_ADR_tau_1@plt>
  add    $0x40,%rsp
  jmp    L17
L29:
  cmpb   $0x70,-0x10(%rbp)
  jne    L17
  mov    -0x20(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  push   0x50(%rbp)
  push   0x48(%rbp)
  push   0x40(%rbp)
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   0x28(%rbp)
  push   0x20(%rbp)
  push   0x18(%rbp)
  mov    0x10(%rbp),%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <calculateSubgridError_ADR_tau_p@plt>
  add    $0x40,%rsp
L17:
  nop
  leave
  ret
```

assistant: ```c
void calculateSubgridError_ADR_tau(int nElements_global, int nQuadraturePoints_element, int nSpace, char stabilization, double *elementDiameter, double *dmt, double *df, double *a, double *da, double *grad_phi, double *dphi, double *dr, double *pe, double *cfl, double *tau) {
  if (stabilization == '2')
    calculateSubgridError_ADR_tau_2(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == '1')
    calculateSubgridError_ADR_tau_1(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == 'p')
    calculateSubgridError_ADR_tau_p(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculateSubgridError_ADR_tau>:
  endbr64
  sub    $0x8,%rsp
  mov    %ecx,%eax
  mov    %r8,%rcx
  mov    %r9,%r8
  cmp    $0x32,%al
  je     L45
  cmp    $0x31,%al
  je     L13
  cmp    $0x70,%al
  je     L0
L55:
  add    $0x8,%rsp
  ret
L45:
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  mov    0x50(%rsp),%r9
  call   <calculateSubgridError_ADR_tau_2@plt>
  add    $0x40,%rsp
  jmp    L55
L13:
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  mov    0x50(%rsp),%r9
  call   <calculateSubgridError_ADR_tau_1@plt>
  add    $0x40,%rsp
  jmp    L55
L0:
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  mov    0x50(%rsp),%r9
  call   <calculateSubgridError_ADR_tau_p@plt>
  add    $0x40,%rsp
  jmp    L55
```

assistant: ```c
void calculateSubgridError_ADR_tau(int nElements_global, int nQuadraturePoints_element, int nSpace, char stabilization, double *elementDiameter, double *dmt, double *df, double *a, double *da, double *grad_phi, double *dphi, double *dr, double *pe, double *cfl, double *tau) {
  if (stabilization == '2')
    calculateSubgridError_ADR_tau_2(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == '1')
    calculateSubgridError_ADR_tau_1(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == 'p')
    calculateSubgridError_ADR_tau_p(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
}
```
user: What is the c source code of the assembly code below?

```asm
<calculateSubgridError_ADR_tau>:
  endbr64
  mov    %ecx,%eax
  push   %r15
  mov    %r8,%rcx
  mov    %r9,%r8
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r9
  mov    0x40(%rsp),%r10
  mov    0x48(%rsp),%r11
  mov    0x50(%rsp),%rbx
  mov    0x58(%rsp),%rbp
  mov    0x60(%rsp),%r12
  mov    0x68(%rsp),%r13
  mov    0x70(%rsp),%r14
  mov    0x78(%rsp),%r15
  cmp    $0x32,%al
  je     L0
  cmp    $0x31,%al
  je     L22
  cmp    $0x70,%al
  je     L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L0:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <calculateSubgridError_ADR_tau_2@plt>
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <calculateSubgridError_ADR_tau_1@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <calculateSubgridError_ADR_tau_p@plt>
```

assistant: ```c
void calculateSubgridError_ADR_tau(int nElements_global, int nQuadraturePoints_element, int nSpace, char stabilization, double *elementDiameter, double *dmt, double *df, double *a, double *da, double *grad_phi, double *dphi, double *dr, double *pe, double *cfl, double *tau) {
  if (stabilization == '2')
    calculateSubgridError_ADR_tau_2(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == '1')
    calculateSubgridError_ADR_tau_1(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == 'p')
    calculateSubgridError_ADR_tau_p(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calculateSubgridError_ADR_tau>:
  endbr64
  mov    %ecx,%eax
  push   %r15
  mov    %r8,%rcx
  mov    %r9,%r8
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r9
  mov    0x40(%rsp),%r10
  mov    0x48(%rsp),%r11
  mov    0x50(%rsp),%rbx
  mov    0x58(%rsp),%rbp
  mov    0x60(%rsp),%r12
  mov    0x68(%rsp),%r13
  mov    0x70(%rsp),%r14
  mov    0x78(%rsp),%r15
  cmp    $0x32,%al
  je     L29
  cmp    $0x31,%al
  je     L20
  cmp    $0x70,%al
  je     L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L29:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <calculateSubgridError_ADR_tau_2@plt>
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <calculateSubgridError_ADR_tau_1@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r15,0x70(%rsp)
  mov    %r14,0x68(%rsp)
  mov    %r13,0x60(%rsp)
  mov    %r12,0x58(%rsp)
  mov    %rbp,0x50(%rsp)
  mov    %rbx,0x48(%rsp)
  mov    %r11,0x40(%rsp)
  mov    %r10,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <calculateSubgridError_ADR_tau_p@plt>
```

assistant: ```c
void calculateSubgridError_ADR_tau(int nElements_global, int nQuadraturePoints_element, int nSpace, char stabilization, double *elementDiameter, double *dmt, double *df, double *a, double *da, double *grad_phi, double *dphi, double *dr, double *pe, double *cfl, double *tau) {
  if (stabilization == '2')
    calculateSubgridError_ADR_tau_2(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == '1')
    calculateSubgridError_ADR_tau_1(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
  else if (stabilization == 'p')
    calculateSubgridError_ADR_tau_p(nElements_global, nQuadraturePoints_element, nSpace, elementDiameter, dmt, df, a, da, grad_phi, dphi, dr, pe, cfl, tau);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uart_putx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  jne    L34
  mov    $0x30,%edi
  call   <uart_putc@plt>
  jmp    L30
L34:
  movb   $0x0,-0x11(%rbp)
  movl   $0x1e,-0x38(%rbp)
  jmp    L1
L14:
  mov    -0x48(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x9,-0x34(%rbp)
  ja     L43
  mov    -0x34(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  mov    %dl,-0x30(%rbp,%rax,1)
  jmp    L0
L43:
  mov    -0x34(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  mov    %dl,-0x30(%rbp,%rax,1)
L0:
  mov    -0x48(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,-0x48(%rbp)
  subl   $0x1,-0x38(%rbp)
L1:
  cmpq   $0x0,-0x48(%rbp)
  jne    L14
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%edx
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
L30:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
void uart_putx(unsigned long long x) {
  char tmp[32];
  unsigned int i;
  unsigned int j;
  if (x == 0) {
    uart_putc('0');
  } else {
    tmp[31] = 0;
    i = 30;
    while (x > 0) {
      j = x % 16;
      if (j < 10)
        tmp[i] = '0' + j;
      else
        tmp[i] = 'a' + j - 10;
      x /= 16;
      i--;
    }
    uart_puts(&(tmp[i + 1]));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_putx>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L34
  movb   $0x0,0x1f(%rsp)
  mov    $0x1e,%ecx
  jmp    L21
L34:
  mov    $0x30,%edi
  call   <uart_putc@plt>
  jmp    L14
L38:
  mov    %eax,%ecx
  mov    %rdx,%rdi
L21:
  mov    %edi,%edx
  and    $0xf,%edx
  lea    0x30(%rdx),%esi
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovbe %esi,%eax
  mov    %ecx,%edx
  mov    %al,(%rsp,%rdx,1)
  mov    %rdi,%rdx
  shr    $0x4,%rdx
  lea    -0x1(%rcx),%eax
  cmp    $0xf,%rdi
  ja     L38
  mov    %ecx,%ecx
  lea    (%rsp,%rcx,1),%rdi
  call   <uart_puts@plt>
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x38,%rsp
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uart_putx(unsigned long long x) {
  char tmp[32];
  unsigned int i;
  unsigned int j;
  if (x == 0) {
    uart_putc('0');
  } else {
    tmp[31] = 0;
    i = 30;
    while (x > 0) {
      j = x % 16;
      if (j < 10)
        tmp[i] = '0' + j;
      else
        tmp[i] = 'a' + j - 10;
      x /= 16;
      i--;
    }
    uart_puts(&(tmp[i + 1]));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_putx>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L15
  movb   $0x0,0x1f(%rsp)
  mov    $0x1e,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%ecx
  and    $0xf,%ecx
  cmp    $0x9,%ecx
  lea    0x30(%rcx),%esi
  lea    0x57(%rcx),%edx
  mov    %eax,%ecx
  cmovbe %esi,%edx
  sub    $0x1,%eax
  shr    $0x4,%rdi
  mov    %dl,(%rsp,%rcx,1)
  jne    L2
  lea    (%rsp,%rcx,1),%rdi
  call   <uart_puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L15:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x30,%edi
  add    $0x38,%rsp
  jmp    1070 <uart_putc@plt>
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uart_putx(unsigned long long x) {
  char tmp[32];
  unsigned int i;
  unsigned int j;
  if (x == 0) {
    uart_putc('0');
  } else {
    tmp[31] = 0;
    i = 30;
    while (x > 0) {
      j = x % 16;
      if (j < 10)
        tmp[i] = '0' + j;
      else
        tmp[i] = 'a' + j - 10;
      x /= 16;
      i--;
    }
    uart_puts(&(tmp[i + 1]));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_putx>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L23
  movb   $0x0,0x1f(%rsp)
  mov    $0x1e,%edx
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %edi,%eax
  mov    %edx,%ecx
  and    $0xf,%eax
  cmp    $0x9,%eax
  ja     L6
  add    $0x30,%eax
  sub    $0x1,%edx
  shr    $0x4,%rdi
  mov    %al,(%rsp,%rcx,1)
  jne    L53
L48:
  lea    (%rsp,%rcx,1),%rdi
  call   <uart_puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L6:
  add    $0x57,%eax
  sub    $0x1,%edx
  shr    $0x4,%rdi
  mov    %al,(%rsp,%rcx,1)
  jne    L53
  jmp    L48
  nopl   0x0(%rax)
L23:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  mov    $0x30,%edi
  add    $0x38,%rsp
  jmp    1070 <uart_putc@plt>
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uart_putx(unsigned long long x) {
  char tmp[32];
  unsigned int i;
  unsigned int j;
  if (x == 0) {
    uart_putc('0');
  } else {
    tmp[31] = 0;
    i = 30;
    while (x > 0) {
      j = x % 16;
      if (j < 10)
        tmp[i] = '0' + j;
      else
        tmp[i] = 'a' + j - 10;
      x /= 16;
      i--;
    }
    uart_puts(&(tmp[i + 1]));
  }
}
```