ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<emptydir>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L28:
  mov    %rbp,%rdi
  call   <readdir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  mov    (%rax),%edi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D19
data_type: string

tool: D5: ..

tool: D19: .

assistant: ```c
int emptydir(DIR *dp) {
  struct dirent *entry;
  size_t files = 0;
  do {
    entry = readdir(dp);
    if (entry != NULL && strcmp(entry->d_name, ".") && strcmp(entry->d_name, ".."))
      files++;
  } while (entry != NULL && files == 0);
  return !files;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L4
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L51
L4:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L13
  jmp    L16
L92:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L92
  jmp    L96
L48:
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L48
L96:
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L39
L91:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L91
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
datatype: string
name: unpack_data
arguments: label: D20
datatype: string
name: unpack_data
arguments: label: D12
datatype: string

tool: D16: Please enter the two numbers

tool: D20: %d%d

tool: D12: The answer is %d


assistant: ```c
main() {
  int a, b, sm = 0;
  printf("Please enter the two numbers\n");
  scanf("%d%d", &a, &b);
  if ((a < 0) || (b < 0)) {
    if (a < 0) {
      while (a != 0) {
        sm += b;
        a++;
      }
    } else {
      while (b != 0) {
        sm += a;
        b++;
      }
    }
    printf("The answer is %d\n", (-1 * sm));
  } else {
    while (a != 0) {
      sm += b;
      a--;
    }
    printf("The answer is %d\n", sm);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  test   %esi,%esi
  js     L72
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L33
  mov    %esi,%eax
  test   %esi,%esi
  je     L56
L65:
  sub    $0x1,%eax
  jne    L65
  imul   %edx,%esi
  movl   $0x0,(%rsp)
L56:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L72:
  mov    0x4(%rsp),%edx
  mov    %esi,%eax
L88:
  add    $0x1,%eax
  jne    L88
  not    %esi
  imul   %edx,%esi
  add    %edx,%esi
  movl   $0x0,(%rsp)
  jmp    L9
L33:
  mov    %edx,%eax
L85:
  add    $0x1,%eax
  jne    L85
  not    %edx
  imul   %esi,%edx
  add    %edx,%esi
  movl   $0x0,0x4(%rsp)
L9:
  neg    %esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D20: Please enter the two numbers

tool: D25: %d%d

tool: D2: The answer is %d


assistant: ```c
main() {
  int a, b, sm = 0;
  printf("Please enter the two numbers\n");
  scanf("%d%d", &a, &b);
  if ((a < 0) || (b < 0)) {
    if (a < 0) {
      while (a != 0) {
        sm += b;
        a++;
      }
    } else {
      while (b != 0) {
        sm += a;
        b++;
      }
    }
    printf("The answer is %d\n", (-1 * sm));
  } else {
    while (a != 0) {
      sm += b;
      a--;
    }
    printf("The answer is %d\n", sm);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8d
  test   %r8d,%r8d
  js     L37
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L38
  test   %r8d,%r8d
  je     L29
  imul   %esi,%r8d
  movl   $0x0,(%rsp)
L29:
  mov    %r8d,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
  nopl   0x0(%rax)
L38:
  not    %esi
  movl   $0x0,0x4(%rsp)
  imul   %r8d,%esi
  add    %r8d,%esi
L20:
  neg    %esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  mov    0x4(%rsp),%eax
  not    %r8d
  movl   $0x0,(%rsp)
  imul   %eax,%r8d
  lea    (%r8,%rax,1),%esi
  jmp    L20
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D31
datatype: string

tool: D2: Please enter the two numbers

tool: D0: %d%d

tool: D31: The answer is %d


assistant: ```c
main() {
  int a, b, sm = 0;
  printf("Please enter the two numbers\n");
  scanf("%d%d", &a, &b);
  if ((a < 0) || (b < 0)) {
    if (a < 0) {
      while (a != 0) {
        sm += b;
        a++;
      }
    } else {
      while (b != 0) {
        sm += a;
        b++;
      }
    }
    printf("The answer is %d\n", (-1 * sm));
  } else {
    while (a != 0) {
      sm += b;
      a--;
    }
    printf("The answer is %d\n", sm);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r8d
  test   %r8d,%r8d
  js     L34
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  js     L29
  test   %r8d,%r8d
  je     L54
  imul   %esi,%r8d
  movl   $0x0,(%rsp)
L54:
  mov    %r8d,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L42
  nopl   0x0(%rax)
L29:
  not    %esi
  movl   $0x0,0x4(%rsp)
  imul   %r8d,%esi
  add    %r8d,%esi
L58:
  neg    %esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L34:
  mov    0x4(%rsp),%eax
  not    %r8d
  movl   $0x0,(%rsp)
  imul   %eax,%r8d
  lea    (%r8,%rax,1),%esi
  jmp    L58
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
datatype: string
name: parse_data
arguments: label: D39
datatype: string
name: parse_data
arguments: label: D32
datatype: string

tool: D33: Please enter the two numbers

tool: D39: %d%d

tool: D32: The answer is %d


assistant: ```c
main() {
  int a, b, sm = 0;
  printf("Please enter the two numbers\n");
  scanf("%d%d", &a, &b);
  if ((a < 0) || (b < 0)) {
    if (a < 0) {
      while (a != 0) {
        sm += b;
        a++;
      }
    } else {
      while (b != 0) {
        sm += a;
        b++;
      }
    }
    printf("The answer is %d\n", (-1 * sm));
  } else {
    while (a != 0) {
      sm += b;
      a--;
    }
    printf("The answer is %d\n", sm);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wisp_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <object_init@plt>
  mov    $0x0,%eax
  call   <symtab_init@plt>
  mov    $0x0,%eax
  call   <cons_init@plt>
  mov    $0x0,%eax
  call   <str_init@plt>
  mov    $0x0,%eax
  call   <lisp_init@plt>
  mov    $0x0,%eax
  call   <vector_init@plt>
  mov    $0x0,%eax
  call   <eval_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wisp_init() {
  object_init();
  symtab_init();
  cons_init();
  str_init();
  lisp_init();
  vector_init();
  eval_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wisp_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <object_init@plt>
  mov    $0x0,%eax
  call   <symtab_init@plt>
  mov    $0x0,%eax
  call   <cons_init@plt>
  mov    $0x0,%eax
  call   <str_init@plt>
  mov    $0x0,%eax
  call   <lisp_init@plt>
  mov    $0x0,%eax
  call   <vector_init@plt>
  mov    $0x0,%eax
  call   <eval_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wisp_init() {
  object_init();
  symtab_init();
  cons_init();
  str_init();
  lisp_init();
  vector_init();
  eval_init();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wisp_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <object_init@plt>
  xor    %eax,%eax
  call   <symtab_init@plt>
  xor    %eax,%eax
  call   <cons_init@plt>
  xor    %eax,%eax
  call   <str_init@plt>
  xor    %eax,%eax
  call   <lisp_init@plt>
  xor    %eax,%eax
  call   <vector_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <eval_init@plt>
```

assistant: ```c
void wisp_init() {
  object_init();
  symtab_init();
  cons_init();
  str_init();
  lisp_init();
  vector_init();
  eval_init();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rollDie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <genrand_int32@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  D9(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x18(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x4f]}

assistant: ```c
int rollDie(int min, int max) {
  int random_value;
  random_value = (int)(((float)genrand_int32() / (float)0xFFFFFFFF) * (max));
  return random_value + min;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rollDie>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <genrand_int32@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mulss  D8(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: byte[4]

tool: {"D8": [0x00,0x00,0x80,0x2f]}

assistant: ```c
int rollDie(int min, int max) {
  int random_value;
  random_value = (int)(((float)genrand_int32() / (float)0xFFFFFFFF) * (max));
  return random_value + min;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rollDie>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <genrand_int32@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm0
  mulss  D3(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2ss %ebp,%xmm1
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x2f]}

assistant: ```c
int rollDie(int min, int max) {
  int random_value;
  random_value = (int)(((float)genrand_int32() / (float)0xFFFFFFFF) * (max));
  return random_value + min;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rollDie>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <genrand_int32@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm0
  mulss  D6(%rip),%xmm0
  add    $0x8,%rsp
  cvtsi2ss %ebp,%xmm1
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x2f]}

assistant: ```c
int rollDie(int min, int max) {
  int random_value;
  random_value = (int)(((float)genrand_int32() / (float)0xFFFFFFFF) * (max));
  return random_value + min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<doFilter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L19
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L6
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
L6:
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x4,-0xc(%rbp)
  jle    L4
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int doFilter(int *valueList) {
  int total = 0;
  int biggest = valueList[0];
  int lowest = valueList[0];
  for (int i = 0; i < 5; i++) {
    total += valueList[i];
    if (valueList[i] > biggest) {
      biggest = valueList[i];
    }
    if (valueList[i] < lowest) {
      lowest = valueList[i];
    }
  }
  int filteredTotal = total - (biggest + lowest);
  int filterAverage = (filteredTotal / 3);
  return filterAverage;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<doFilter>:
  endbr64
  mov    (%rdi),%ecx
  mov    %rdi,%rdx
  add    $0x14,%rdi
  mov    %ecx,%esi
  mov    $0x0,%r8d
L9:
  mov    (%rdx),%eax
  add    %eax,%r8d
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  cmp    %eax,%esi
  cmovg  %eax,%esi
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L9
  add    %esi,%ecx
  sub    %ecx,%r8d
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%r8d
  sub    %r8d,%eax
  ret
```

assistant: ```c
int doFilter(int *valueList) {
  int total = 0;
  int biggest = valueList[0];
  int lowest = valueList[0];
  for (int i = 0; i < 5; i++) {
    total += valueList[i];
    if (valueList[i] > biggest) {
      biggest = valueList[i];
    }
    if (valueList[i] < lowest) {
      lowest = valueList[i];
    }
  }
  int filteredTotal = total - (biggest + lowest);
  int filterAverage = (filteredTotal / 3);
  return filterAverage;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<doFilter>:
  endbr64
  mov    (%rdi),%ecx
  lea    0x4(%rdi),%rsi
  xor    %r8d,%r8d
  add    $0x14,%rdi
  mov    %ecx,%eax
  mov    %ecx,%edx
L15:
  add    %eax,%r8d
  cmp    %eax,%ecx
  cmovl  %eax,%ecx
  cmp    %eax,%edx
  cmovg  %eax,%edx
  cmp    %rsi,%rdi
  je     L16
  mov    (%rsi),%eax
  add    $0x4,%rsi
  jmp    L15
  nop
L16:
  add    %ecx,%edx
  sub    %edx,%r8d
  movslq %r8d,%rax
  sar    $0x1f,%r8d
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int doFilter(int *valueList) {
  int total = 0;
  int biggest = valueList[0];
  int lowest = valueList[0];
  for (int i = 0; i < 5; i++) {
    total += valueList[i];
    if (valueList[i] > biggest) {
      biggest = valueList[i];
    }
    if (valueList[i] < lowest) {
      lowest = valueList[i];
    }
  }
  int filteredTotal = total - (biggest + lowest);
  int filterAverage = (filteredTotal / 3);
  return filterAverage;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<doFilter>:
  endbr64
  movd   (%rdi),%xmm5
  movdqu (%rdi),%xmm0
  mov    0x10(%rdi),%esi
  pshufd $0x0,%xmm5,%xmm2
  movdqa %xmm2,%xmm1
  movdqa %xmm2,%xmm4
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm1,%xmm3
  pand   %xmm1,%xmm4
  pandn  %xmm0,%xmm3
  por    %xmm4,%xmm3
  movdqa %xmm0,%xmm4
  pand   %xmm1,%xmm4
  pandn  %xmm2,%xmm1
  por    %xmm4,%xmm1
  movdqa %xmm1,%xmm4
  psrldq $0x8,%xmm4
  movdqa %xmm4,%xmm2
  pcmpgtd %xmm1,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm4,%xmm2
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm4
  psrldq $0x4,%xmm4
  movdqa %xmm4,%xmm2
  pcmpgtd %xmm1,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm4,%xmm2
  por    %xmm1,%xmm2
  movdqa %xmm3,%xmm1
  psrldq $0x8,%xmm1
  movd   %xmm2,%ecx
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm3,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm3,%xmm2
  por    %xmm1,%xmm2
  movdqa %xmm2,%xmm3
  psrldq $0x4,%xmm3
  movdqa %xmm3,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm3
  pandn  %xmm2,%xmm1
  por    %xmm3,%xmm1
  movd   %xmm1,%eax
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%edx
  add    %esi,%edx
  cmp    %eax,%esi
  cmovge %esi,%eax
  cmp    %ecx,%esi
  cmovg  %ecx,%esi
  add    %esi,%eax
  sub    %eax,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  ret
```

assistant: ```c
int doFilter(int *valueList) {
  int total = 0;
  int biggest = valueList[0];
  int lowest = valueList[0];
  for (int i = 0; i < 5; i++) {
    total += valueList[i];
    if (valueList[i] > biggest) {
      biggest = valueList[i];
    }
    if (valueList[i] < lowest) {
      lowest = valueList[i];
    }
  }
  int filteredTotal = total - (biggest + lowest);
  int filterAverage = (filteredTotal / 3);
  return filterAverage;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
L1:
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L5:
  cmpq   $0x0,-0x8(%rbp)
  jg     L1
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int64_t add_loop(int64_t x, int64_t y) {
  uint64_t ret = x;
  for (uint64_t i = y; i > 0; --i) {
    ret++;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_loop>:
  endbr64
  test   %rsi,%rsi
  jle    L16
  mov    %rsi,%rdx
L19:
  sub    $0x1,%rdx
  jne    L19
  lea    (%rdi,%rsi,1),%rax
  ret
L16:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int64_t add_loop(int64_t x, int64_t y) {
  uint64_t ret = x;
  for (uint64_t i = y; i > 0; --i) {
    ret++;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_loop>:
  endbr64
  test   %rsi,%rsi
  lea    (%rdi,%rsi,1),%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
int64_t add_loop(int64_t x, int64_t y) {
  uint64_t ret = x;
  for (uint64_t i = y; i > 0; --i) {
    ret++;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add_loop>:
  endbr64
  test   %rsi,%rsi
  lea    (%rdi,%rsi,1),%rax
  cmovle %rdi,%rax
  ret
```

assistant: ```c
int64_t add_loop(int64_t x, int64_t y) {
  uint64_t ret = x;
  for (uint64_t i = y; i > 0; --i) {
    ret++;
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string

tool: D1: 


assistant: ```c
void print_line(int fd, const char *str) {
  write(fd, str, strlen(str));
  write(fd, "\n", 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D9(%rip),%rsi
  mov    %ebx,%edi
  call   <write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D9: 


assistant: ```c
void print_line(int fd, const char *str) {
  write(fd, str, strlen(str));
  write(fd, "\n", 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_line>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    $0x1,%edx
  pop    %rbp
  lea    D1(%rip),%rsi
  pop    %r12
  jmp    1060 <write@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type: string

tool: D1: 


assistant: ```c
void print_line(int fd, const char *str) {
  write(fd, str, strlen(str));
  write(fd, "\n", 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_line>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    $0x1,%edx
  pop    %rbp
  lea    D0(%rip),%rsi
  pop    %r12
  jmp    1060 <write@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: 


assistant: ```c
void print_line(int fd, const char *str) {
  write(fd, str, strlen(str));
  write(fd, "\n", 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <struct_by_value_17_x@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct_by_value_17_x();
  exit(0);
}
```