ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_sockaddr>:
  endbr64
  push   %rbx
  mov    $0xc,%esi
  mov    %rdi,%rbx
  call   <bzero@plt>
  mov    D18(%rip),%rax
  mov    $0x1f98,%edi
  mov    D1(%rip),%rdx
  mov    (%rax),%eax
  movd   (%rdx),%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x4(%rbx)
  call   <htons@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void set_sockaddr(struct sockaddr_in *addr) {
  bzero((char *)addr, sizeof(struct sockaddr_in));
  addr->sin_family = AF_INET;
  addr->sin_addr.s_addr = INADDR_ANY;
  addr->sin_port = htons((8088));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clamp32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltd
  mov    $0x3f,%ecx
  mov    -0x4(%rbp),%eax
  sar    %cl,%eax
  cmp    %eax,%edx
  je     L0
  mov    $0x3f,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  xor    $0x7fffffff,%eax
  mov    %eax,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t clamp32(int64_t sample) {
  if ((sample >> 31) ^ (sample >> 63))
    sample = 0x7fffffff ^ (sample >> 63);
  return sample;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clamp32>:
  endbr64
  mov    %edi,%edx
  mov    $0x3f,%ecx
  sar    %cl,%edx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%eax
  xor    $0x7fffffff,%eax
  cmp    %edx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int32_t clamp32(int64_t sample) {
  if ((sample >> 31) ^ (sample >> 63))
    sample = 0x7fffffff ^ (sample >> 63);
  return sample;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clamp32>:
  endbr64
  mov    %edi,%edx
  mov    $0x3f,%ecx
  sar    %cl,%edx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%eax
  xor    $0x7fffffff,%eax
  cmp    %edx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int32_t clamp32(int64_t sample) {
  if ((sample >> 31) ^ (sample >> 63))
    sample = 0x7fffffff ^ (sample >> 63);
  return sample;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<clamp32>:
  endbr64
  mov    %edi,%edx
  mov    $0x3f,%ecx
  sar    %cl,%edx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%eax
  xor    $0x7fffffff,%eax
  cmp    %edx,%ecx
  cmove  %edi,%eax
  ret
```

assistant: ```c
int32_t clamp32(int64_t sample) {
  if ((sample >> 31) ^ (sample >> 63))
    sample = 0x7fffffff ^ (sample >> 63);
  return sample;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<example1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%eax
  cltq
  movl   $0x2a,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x2a,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void example1(void) {
  int top;
  int top2;
  int arr[10];
  arr[top] = 42;
  top2 = top;
  assert(arr[top2] == 42);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<example1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void example1(void) {
  int top;
  int top2;
  int arr[10];
  arr[top] = 42;
  top2 = top;
  assert(arr[top2] == 42);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<example1>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void example1(void) {
  int top;
  int top2;
  int arr[10];
  arr[top] = 42;
  top2 = top;
  assert(arr[top2] == 42);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<example1>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
void example1(void) {
  int top;
  int top2;
  int arr[10];
  arr[top] = 42;
  top2 = top;
  assert(arr[top2] == 42);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<url_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L42
  jmp    L140
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L127
L16:
  cmpl   $0x3,-0x14(%rbp)
  jle    L129
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%esi
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  lea    D0(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  addq   $0x3,-0x10(%rbp)
  subl   $0x3,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L140
L127:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x14(%rbp)
L140:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  cmpl   $0x1,-0x14(%rbp)
  jg     L12
  jmp    L42
L129:
  nop
L42:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
datatype: string

tool: D0: %%%2X

assistant: ```c
void url_encode(const char *s, char *t, int length) {
  if (s) {
    while (*s && length > 1) {
      if (*s <= 32 || *s == '%' || *s == '\\' || *s == '<' || *s == '>' || *s == '\'' || *s == '\"' || *s > 122) {
        if (length > 3) {
          snprintf(t, length, "%%%2X", *s);
          t += 3;
          length -= 3;
          s++;
        } else {
          break;
        }
      } else {
        *t++ = *s++;
        length--;
      }
    }
  }
  *t = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<url_encode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %rdi,%rdi
  je     L104
  mov    %edx,%ebx
  movzbl (%rdi),%ecx
  cmp    $0x1,%edx
  jle    L104
  test   %cl,%cl
  je     L104
  lea    0x1(%rdi),%rbp
  lea    D4(%rip),%r13
  movabs $0x400000014000021,%r14
  jmp    L46
L22:
  cmp    $0x7a,%cl
  jle    L98
L109:
  cmp    $0x3,%ebx
  jle    L104
  movsbl %cl,%ecx
  mov    %r13,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  add    $0x3,%r12
  sub    $0x3,%ebx
  mov    %rbp,%rax
L59:
  movzbl (%rax),%ecx
  add    $0x1,%rbp
  cmp    $0x1,%ebx
  jle    L104
  test   %cl,%cl
  je     L104
L46:
  cmp    $0x20,%cl
  jle    L109
  cmp    $0x25,%cl
  je     L109
  lea    -0x22(%rcx),%eax
  cmp    $0x3a,%al
  ja     L22
  bt     %rax,%r14
  jb     L109
L98:
  mov    %rbp,%rax
  mov    %cl,(%r12)
  sub    $0x1,%ebx
  lea    0x1(%r12),%r12
  jmp    L59
L104:
  movb   $0x0,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D4: %%%2X

assistant: ```c
void url_encode(const char *s, char *t, int length) {
  if (s) {
    while (*s && length > 1) {
      if (*s <= 32 || *s == '%' || *s == '\\' || *s == '<' || *s == '>' || *s == '\'' || *s == '\"' || *s > 122) {
        if (length > 3) {
          snprintf(t, length, "%%%2X", *s);
          t += 3;
          length -= 3;
          s++;
        } else {
          break;
        }
      } else {
        *t++ = *s++;
        length--;
      }
    }
  }
  *t = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<url_encode>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L22
  movsbl (%rdi),%ecx
  test   %cl,%cl
  je     L22
  mov    %edx,%ebx
  cmp    $0x1,%edx
  jle    L22
  lea    0x1(%rdi),%rbp
  lea    D0(%rip),%r12
  movabs $0x400000014000021,%r13
  jmp    L63
  nopl   (%rax)
L71:
  lea    -0x22(%rcx),%eax
  cmp    $0x3a,%al
  ja     L84
  bt     %rax,%r13
  jb     L39
L124:
  sub    $0x1,%ebx
  mov    %cl,(%r14)
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%ecx
  add    $0x1,%r14
  cmp    $0x1,%ebx
  jle    L22
  nopl   0x0(%rax)
L38:
  test   %cl,%cl
  je     L22
L63:
  cmp    $0x20,%cl
  jle    L39
  cmp    $0x25,%cl
  jne    L71
L39:
  cmp    $0x3,%ebx
  jle    L22
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %r12,%rdx
  sub    $0x3,%ebx
  call   <snprintf@plt>
  add    $0x3,%r14
  movsbl 0x0(%rbp),%ecx
  add    $0x1,%rbp
  cmp    $0x1,%ebx
  jg     L38
L22:
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r14)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L84:
  cmp    $0x7a,%cl
  jg     L39
  jmp    L124
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: %%%2X

assistant: ```c
void url_encode(const char *s, char *t, int length) {
  if (s) {
    while (*s && length > 1) {
      if (*s <= 32 || *s == '%' || *s == '\\' || *s == '<' || *s == '>' || *s == '\'' || *s == '\"' || *s > 122) {
        if (length > 3) {
          snprintf(t, length, "%%%2X", *s);
          t += 3;
          length -= 3;
          s++;
        } else {
          break;
        }
      } else {
        *t++ = *s++;
        length--;
      }
    }
  }
  *t = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<url_encode>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L20
  movsbl (%rdi),%ecx
  test   %cl,%cl
  je     L20
  mov    %edx,%ebx
  cmp    $0x1,%edx
  jle    L20
  lea    0x1(%rdi),%rbp
  lea    D2(%rip),%r12
  movabs $0x400000014000021,%r13
  jmp    L66
  nopl   (%rax)
L8:
  lea    -0x22(%rcx),%eax
  cmp    $0x3a,%al
  ja     L99
  bt     %rax,%r13
  jb     L5
L43:
  sub    $0x1,%ebx
  mov    %cl,(%r14)
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%ecx
  add    $0x1,%r14
  cmp    $0x1,%ebx
  jle    L20
  nopl   0x0(%rax)
L103:
  test   %cl,%cl
  je     L20
L66:
  cmp    $0x20,%cl
  jle    L5
  cmp    $0x25,%cl
  jne    L8
L5:
  cmp    $0x3,%ebx
  jle    L20
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %r12,%rdx
  sub    $0x3,%ebx
  call   <snprintf@plt>
  add    $0x3,%r14
  movsbl 0x0(%rbp),%ecx
  add    $0x1,%rbp
  cmp    $0x1,%ebx
  jg     L103
L20:
  pop    %rbx
  pop    %rbp
  movb   $0x0,(%r14)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L99:
  cmp    $0x7a,%cl
  jg     L5
  jmp    L43
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: %%%2X

assistant: ```c
void url_encode(const char *s, char *t, int length) {
  if (s) {
    while (*s && length > 1) {
      if (*s <= 32 || *s == '%' || *s == '\\' || *s == '<' || *s == '>' || *s == '\'' || *s == '\"' || *s > 122) {
        if (length > 3) {
          snprintf(t, length, "%%%2X", *s);
          t += 3;
          length -= 3;
          s++;
        } else {
          break;
        }
      } else {
        *t++ = *s++;
        length--;
      }
    }
  }
  *t = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L9
L24:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xff,%eax
  jg     L14
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: Memory allocation problem

assistant: ```c
int main(int argc, char **argv) {
  char *buf;
  buf = (char *)malloc(256);
  if (buf == NULL) {
    printf("Memory allocation problem");
    return 1;
  }
  if (strlen(argv[1]) < 256)
    strcpy(buf, argv[1]);
  free(buf);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x100,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  mov    0x8(%rbp),%rdi
  call   <strlen@plt>
  cmp    $0xff,%eax
  jle    L5
L28:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L9
L5:
  mov    0x8(%rbp),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L28
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string

tool: D6: Memory allocation problem

assistant: ```c
int main(int argc, char **argv) {
  char *buf;
  buf = (char *)malloc(256);
  if (buf == NULL) {
    printf("Memory allocation problem");
    return 1;
  }
  if (strlen(argv[1]) < 256)
    strcpy(buf, argv[1]);
  free(buf);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L5
  mov    0x8(%rbx),%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    $0xff,%eax
  jle    L15
L10:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L10
L5:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L31
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: Memory allocation problem

assistant: ```c
int main(int argc, char **argv) {
  char *buf;
  buf = (char *)malloc(256);
  if (buf == NULL) {
    printf("Memory allocation problem");
    return 1;
  }
  if (strlen(argv[1]) < 256)
    strcpy(buf, argv[1]);
  free(buf);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x100,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L32
  mov    0x8(%rbx),%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  cmp    $0xff,%eax
  jle    L25
L9:
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    0x8(%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L9
L32:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L26
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: Memory allocation problem

assistant: ```c
int main(int argc, char **argv) {
  char *buf;
  buf = (char *)malloc(256);
  if (buf == NULL) {
    printf("Memory allocation problem");
    return 1;
  }
  if (strlen(argv[1]) < 256)
    strcpy(buf, argv[1]);
  free(buf);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<posLongExtract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x80000000,%eax
  test   %rax,%rax
  je     L13
  movabs $0xffffffff7fffffff,%rax
  and    -0x8(%rbp),%rax
  neg    %rax
  jmp    L2
L13:
  mov    -0x8(%rbp),%rax
L2:
  pop    %rbp
  ret
```

assistant: ```c
long posLongExtract(unsigned char *inbuf) {
  long tmp;
  tmp = (long)((((inbuf[3]) << 24) & 0xFF000000) | (((inbuf[2]) << 16) & 0x00FF0000) | (((inbuf[1]) << 8) & 0x0000FF00) | ((inbuf[0]) & 0x000000FF));
  if (tmp & (1L << 31))
    return (-(tmp & ~(1L << 31)));
  else
    return (tmp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<posLongExtract>:
  endbr64
  movzbl 0x3(%rdi),%edx
  shl    $0x18,%edx
  movzbl 0x2(%rdi),%eax
  shl    $0x10,%eax
  or     %eax,%edx
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl (%rdi),%ecx
  or     %ecx,%eax
  or     %eax,%edx
  mov    %edx,%eax
  and    $0x7fffffff,%eax
  neg    %rax
  mov    %edx,%ecx
  test   %edx,%edx
  cmovns %rcx,%rax
  ret
```

assistant: ```c
long posLongExtract(unsigned char *inbuf) {
  long tmp;
  tmp = (long)((((inbuf[3]) << 24) & 0xFF000000) | (((inbuf[2]) << 16) & 0x00FF0000) | (((inbuf[1]) << 8) & 0x0000FF00) | ((inbuf[0]) & 0x000000FF));
  if (tmp & (1L << 31))
    return (-(tmp & ~(1L << 31)));
  else
    return (tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<posLongExtract>:
  endbr64
  mov    (%rdi),%eax
  mov    %rax,%rdx
  and    $0x7fffffff,%eax
  neg    %rax
  mov    %edx,%ecx
  test   %edx,%edx
  cmovns %rcx,%rax
  ret
```

assistant: ```c
long posLongExtract(unsigned char *inbuf) {
  long tmp;
  tmp = (long)((((inbuf[3]) << 24) & 0xFF000000) | (((inbuf[2]) << 16) & 0x00FF0000) | (((inbuf[1]) << 8) & 0x0000FF00) | ((inbuf[0]) & 0x000000FF));
  if (tmp & (1L << 31))
    return (-(tmp & ~(1L << 31)));
  else
    return (tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<posLongExtract>:
  endbr64
  mov    (%rdi),%eax
  mov    %rax,%rdx
  and    $0x7fffffff,%eax
  neg    %rax
  mov    %edx,%ecx
  test   %edx,%edx
  cmovns %rcx,%rax
  ret
```

assistant: ```c
long posLongExtract(unsigned char *inbuf) {
  long tmp;
  tmp = (long)((((inbuf[3]) << 24) & 0xFF000000) | (((inbuf[2]) << 16) & 0x00FF0000) | (((inbuf[1]) << 8) & 0x0000FF00) | ((inbuf[0]) & 0x000000FF));
  if (tmp & (1L << 31))
    return (-(tmp & ~(1L << 31)));
  else
    return (tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<assert_in_range_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <assert_in_range@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <assert_in_range@plt>
  nop
  leave
  ret
```

assistant: ```c
void assert_in_range_2(int m, int n) {
  assert_in_range(m);
  assert_in_range(n);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<assert_in_range_2>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <assert_in_range@plt>
  mov    %ebx,%edi
  call   <assert_in_range@plt>
  pop    %rbx
  ret
```

assistant: ```c
void assert_in_range_2(int m, int n) {
  assert_in_range(m);
  assert_in_range(n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<assert_in_range_2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <assert_in_range@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <assert_in_range@plt>
```

assistant: ```c
void assert_in_range_2(int m, int n) {
  assert_in_range(m);
  assert_in_range(n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<assert_in_range_2>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <assert_in_range@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1050 <assert_in_range@plt>
```

assistant: ```c
void assert_in_range_2(int m, int n) {
  assert_in_range(m);
  assert_in_range(n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<med3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  jns    L20
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  js     L87
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  jns    L36
  mov    -0x18(%rbp),%rax
  jmp    L59
L36:
  mov    -0x8(%rbp),%rax
  jmp    L59
L87:
  mov    -0x10(%rbp),%rax
  jmp    L59
L20:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  jg     L97
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  jns    L10
  mov    -0x8(%rbp),%rax
  jmp    L59
L10:
  mov    -0x18(%rbp),%rax
  jmp    L59
L97:
  mov    -0x10(%rbp),%rax
L59:
  leave
  ret
```

assistant: ```c
char *med3(a, b, c, cmp)
char *a, *b, *c;
int (*cmp)();
{ return cmp(a, b) < 0 ? (cmp(b, c) < 0 ? b : (cmp(a, c) < 0 ? c : a)) : (cmp(b, c) > 0 ? b : (cmp(a, c) < 0 ? a : c)); }
```
user: What would the C source look like for the assembly code provided here?

```asm
<med3>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    $0x0,%eax
  call   *%rcx
  test   %eax,%eax
  js     L43
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   *%rbp
  test   %eax,%eax
  jle    L19
L25:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   *%rbp
  test   %eax,%eax
  js     L25
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   *%rbp
  test   %eax,%eax
  mov    %r13,%rbx
  cmovs  %r12,%rbx
  jmp    L25
L19:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   *%rbp
  test   %eax,%eax
  mov    %r12,%rbx
  cmovs  %r13,%rbx
  jmp    L25
```

assistant: ```c
char *med3(a, b, c, cmp)
char *a, *b, *c;
int (*cmp)();
{ return cmp(a, b) < 0 ? (cmp(b, c) < 0 ? b : (cmp(a, c) < 0 ? c : a)) : (cmp(b, c) > 0 ? b : (cmp(a, c) < 0 ? a : c)); }
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<med3>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   *%rcx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  test   %eax,%eax
  mov    $0x0,%eax
  js     L5
  call   *%rbp
  test   %eax,%eax
  jle    L33
L27:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   *%rbp
  test   %eax,%eax
  js     L9
L23:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  call   *%rbp
  test   %eax,%eax
  js     L27
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   *%rbp
  test   %eax,%eax
  js     L23
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *med3(a, b, c, cmp)
char *a, *b, *c;
int (*cmp)();
{ return cmp(a, b) < 0 ? (cmp(b, c) < 0 ? b : (cmp(a, c) < 0 ? c : a)) : (cmp(b, c) > 0 ? b : (cmp(a, c) < 0 ? a : c)); }
```