ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %rsp,%r10
  jmp    L118
L4:
  lea    (%rdx,%rsi,1),%ecx
  mov    %ecx,(%rdi)
L117:
  add    $0x1,%rax
  add    $0x1,%edx
L50:
  lea    (%rsi,%rax,1),%ecx
  mov    %ecx,(%rdi,%rax,4)
  test   %eax,%eax
  je     L4
  cmp    $0x9,%edx
  jle    L117
  add    $0xa,%esi
  add    $0x28,%rdi
  cmp    %r8d,%esi
  je     L51
L10:
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L50
L51:
  add    $0x190,%r9
  cmp    $0xfa0,%r9
  je     L128
L118:
  lea    (%r9,%r10,1),%rdi
  mov    %r8d,%esi
  add    $0x64,%r8d
  jmp    L10
L100:
  cmp    %r8d,(%rsi)
  jne    L158
L7:
  add    $0x1,%rax
  add    $0x1,%edx
L99:
  test   %eax,%eax
  je     L100
  lea    (%rdi,%rdx,1),%ecx
  cmp    %ecx,(%rsi,%rax,4)
  jne    L32
  cmp    $0x9,%edx
  jle    L7
  add    $0x28,%rsi
  add    $0xa,%r9d
  add    $0xa,%r8d
  cmp    %r11d,%r8d
  je     L124
L71:
  mov    $0x1,%edx
  mov    $0x0,%eax
  lea    -0x1(%r9),%edi
  jmp    L99
L124:
  add    $0x64,%r11d
  add    $0x64,%ebp
  add    $0x190,%rbx
  cmp    $0xfa0,%rbx
  jne    L110
  mov    $0x0,%eax
  jmp    L139
L128:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x65,%r11d
L110:
  lea    (%rbx,%r10,1),%rsi
  lea    -0x64(%r11),%r8d
  mov    %ebp,%r9d
  jmp    L71
L158:
  mov    $0x1,%eax
  jmp    L139
L32:
  mov    $0x1,%eax
L139:
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L138
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L138:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[10][10][10];
  int i, j, k;
#pragma acc parallel loop gang private(j)
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
#pragma acc loop vector
      for (k = 0; k < 10; k++) {
        int tmp = j;
        a[i][tmp][k] = i * 100 + tmp * 10 + k;
        if (k == 0) {
          int tmp2 = j;
          a[i][tmp2][k]++;
        }
      }
    }
  }
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      for (k = 0; k < 10; k++) {
        if (k == 0) {
          if (a[i][j][k] != i * 100 + j * 10 + k + 1) {
            return 1;
          }
        } else {
          if (a[i][j][k] != i * 100 + j * 10 + k) {
            return 1;
          }
        }
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %r9d,%r9d
  xor    %esi,%esi
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
L71:
  lea    (%r10,%r9,1),%rcx
  lea    0x64(%rsi),%r8d
  nop
L144:
  xor    %eax,%eax
  lea    0x1(%rsi),%edi
  jmp    L107
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    $0x9,%rax
  je     L72
L33:
  add    $0x1,%rax
L107:
  lea    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,4)
  test   %rax,%rax
  jne    L22
  mov    %edi,(%rcx)
  jmp    L33
  nopl   0x0(%rax)
L72:
  add    $0xa,%esi
  add    $0x28,%rcx
  cmp    %r8d,%esi
  jne    L144
  add    $0x190,%r9
  cmp    $0xfa0,%r9
  jne    L71
  xor    %ebx,%ebx
  mov    $0x64,%r11d
L56:
  lea    -0x64(%r11),%r9d
  lea    (%r10,%rbx,1),%rsi
  lea    -0x63(%r11),%r8d
L126:
  mov    $0x1,%edx
  xor    %eax,%eax
  lea    -0x1(%r9),%edi
  jmp    L92
  nopl   (%rax)
L149:
  lea    (%rdi,%rdx,1),%ecx
  cmp    %ecx,(%rsi,%rax,4)
  jne    L143
  cmp    $0xa,%edx
  je     L67
L146:
  add    $0x1,%rax
  add    $0x1,%edx
L92:
  test   %rax,%rax
  jne    L149
  cmp    %r8d,(%rsi)
  je     L146
L143:
  mov    $0x1,%eax
L4:
  mov    0xfa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0xfb0,%rsp
  pop    %rbx
  ret
L67:
  add    $0xa,%r9d
  add    $0x28,%rsi
  add    $0xa,%r8d
  cmp    %r11d,%r9d
  jne    L126
  add    $0x190,%rbx
  lea    0x64(%r9),%r11d
  cmp    $0xfa0,%rbx
  jne    L56
  xor    %eax,%eax
  jmp    L4
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[10][10][10];
  int i, j, k;
#pragma acc parallel loop gang private(j)
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
#pragma acc loop vector
      for (k = 0; k < 10; k++) {
        int tmp = j;
        a[i][tmp][k] = i * 100 + tmp * 10 + k;
        if (k == 0) {
          int tmp2 = j;
          a[i][tmp2][k]++;
        }
      }
    }
  }
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      for (k = 0; k < 10; k++) {
        if (k == 0) {
          if (a[i][j][k] != i * 100 + j * 10 + k + 1) {
            return 1;
          }
        } else {
          if (a[i][j][k] != i * 100 + j * 10 + k) {
            return 1;
          }
        }
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<assert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L12:
  nop
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: List assert fail, quick exit


assistant: ```c
void assert(int value) {
  if (value)
    return;
  printf("List assert fail, quick exit\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<assert>:
  endbr64
  test   %edi,%edi
  je     L0
  ret
L0:
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: List assert fail, quick exit


assistant: ```c
void assert(int value) {
  if (value)
    return;
  printf("List assert fail, quick exit\n");
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assert>:
  endbr64
  test   %edi,%edi
  je     L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: List assert fail, quick exit


assistant: ```c
void assert(int value) {
  if (value)
    return;
  printf("List assert fail, quick exit\n");
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<assert>:
  endbr64
  test   %edi,%edi
  je     L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: List assert fail, quick exit


assistant: ```c
void assert(int value) {
  if (value)
    return;
  printf("List assert fail, quick exit\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RankOfElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L29
  addq   $0x1,-0x8(%rbp)
L29:
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L34
  mov    -0x28(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L53
  addq   $0x1,-0x8(%rbp)
L53:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L13
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t RankOfElement(const int *array, size_t length, size_t index) {
  size_t count = 0;
  for (int i = 0; i < index; i++) {
    if (array[i] <= array[index]) {
      count++;
    }
  }
  for (int i = index; i < length; i++) {
    if (array[i] < array[index]) {
      count++;
    }
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RankOfElement>:
  endbr64
  test   %rdx,%rdx
  je     L48
  mov    (%rdi,%rdx,4),%r10d
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%r9
  mov    $0x0,%eax
L46:
  cmp    %r10d,(%rcx)
  setle  %r8b
  movzbl %r8b,%r8d
  add    %r8,%rax
  add    $0x4,%rcx
  cmp    %r9,%rcx
  jne    L46
L13:
  movslq %edx,%rcx
  cmp    %rcx,%rsi
  jbe    L22
  mov    (%rdi,%rdx,4),%r8d
  lea    (%rdi,%rcx,4),%rdx
  lea    (%rdi,%rsi,4),%rsi
L24:
  cmp    %r8d,(%rdx)
  setl   %cl
  movzbl %cl,%ecx
  add    %rcx,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L24
L22:
  ret
L48:
  mov    %rdx,%rax
  jmp    L13
```

assistant: ```c
size_t RankOfElement(const int *array, size_t length, size_t index) {
  size_t count = 0;
  for (int i = 0; i < index; i++) {
    if (array[i] <= array[index]) {
      count++;
    }
  }
  for (int i = index; i < length; i++) {
    if (array[i] < array[index]) {
      count++;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RankOfElement>:
  endbr64
  test   %rdx,%rdx
  je     L9
  mov    (%rdi,%rdx,4),%r10d
  mov    %rdi,%rcx
  lea    (%rdi,%rdx,4),%r9
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  cmp    %r10d,(%rcx)
  setle  %r8b
  add    $0x4,%rcx
  add    %r8,%rax
  cmp    %r9,%rcx
  jne    L15
L22:
  movslq %edx,%rcx
  cmp    %rcx,%rsi
  jbe    L14
  mov    (%rdi,%rdx,4),%r8d
  lea    (%rdi,%rsi,4),%rsi
  lea    (%rdi,%rcx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L33:
  xor    %ecx,%ecx
  cmp    %r8d,(%rdx)
  setl   %cl
  add    $0x4,%rdx
  add    %rcx,%rax
  cmp    %rsi,%rdx
  jne    L33
L14:
  ret
  nopl   (%rax)
L9:
  xor    %eax,%eax
  jmp    L22
```

assistant: ```c
size_t RankOfElement(const int *array, size_t length, size_t index) {
  size_t count = 0;
  for (int i = 0; i < index; i++) {
    if (array[i] <= array[index]) {
      count++;
    }
  }
  for (int i = index; i < length; i++) {
    if (array[i] < array[index]) {
      count++;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L32:
  mov    -0xc(%rbp),%eax
  imul   -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L11
  mov    -0x8(%rbp),%rax
  jmp    L8
L11:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L32
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
void *lsearch(const void *key, void *base, int n, int elemSize, int (*cmpfn)(const void *, const void *)) {
  int i;
  for (i = 0; i < n; i++) {
    void *elemAddr = (char *)base + i * elemSize;
    if (cmpfn(key, elemAddr) == 0)
      return elemAddr;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  jle    L31
  mov    %rdi,%r14
  mov    %edx,%r13d
  mov    %r8,%r15
  movslq %ecx,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
L39:
  mov    %rbx,0x8(%rsp)
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   *%r15
  test   %eax,%eax
  je     L8
  add    $0x1,%ebp
  add    %r12,%rbx
  cmp    %ebp,%r13d
  jne    L39
  movq   $0x0,0x8(%rsp)
L8:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  movq   $0x0,0x8(%rsp)
  jmp    L8
```

assistant: ```c
void *lsearch(const void *key, void *base, int n, int elemSize, int (*cmpfn)(const void *, const void *)) {
  int i;
  for (i = 0; i < n; i++) {
    void *elemAddr = (char *)base + i * elemSize;
    if (cmpfn(key, elemAddr) == 0)
      return elemAddr;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<lsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  test   %edx,%edx
  jle    L40
  mov    %rdi,%r13
  mov    %r8,%r14
  movslq %ecx,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%r12d
  add    %rbp,%rbx
  cmp    %r12d,0xc(%rsp)
  je     L40
L10:
  mov    %rbx,%r15
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   *%r14
  test   %eax,%eax
  jne    L42
L23:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  xor    %r15d,%r15d
  jmp    L23
```

assistant: ```c
void *lsearch(const void *key, void *base, int n, int elemSize, int (*cmpfn)(const void *, const void *)) {
  int i;
  for (i = 0; i < n; i++) {
    void *elemAddr = (char *)base + i * elemSize;
    if (cmpfn(key, elemAddr) == 0)
      return elemAddr;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  test   %edx,%edx
  jle    L45
  mov    %rdi,%r13
  mov    %r8,%r14
  movslq %ecx,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12d
  add    %rbp,%rbx
  cmp    %r12d,0xc(%rsp)
  je     L45
L26:
  mov    %rbx,%r15
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   *%r14
  test   %eax,%eax
  jne    L10
L23:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  xor    %r15d,%r15d
  jmp    L23
```

assistant: ```c
void *lsearch(const void *key, void *base, int n, int elemSize, int (*cmpfn)(const void *, const void *)) {
  int i;
  for (i = 0; i < n; i++) {
    void *elemAddr = (char *)base + i * elemSize;
    if (cmpfn(key, elemAddr) == 0)
      return elemAddr;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x30,-0x4(%rbp)
  ja     L58
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D16(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D16(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x28,%eax
  jmp    L18
  mov    $0x27,%eax
  jmp    L18
  mov    $0x26,%eax
  jmp    L18
  mov    $0x25,%eax
  jmp    L18
  mov    $0x24,%eax
  jmp    L18
  mov    $0x23,%eax
  jmp    L18
  mov    $0x22,%eax
  jmp    L18
  mov    $0x21,%eax
  jmp    L18
  mov    $0x20,%eax
  jmp    L18
  mov    $0x1f,%eax
  jmp    L18
  mov    $0x1e,%eax
  jmp    L18
  mov    $0x1d,%eax
  jmp    L18
  mov    $0x1c,%eax
  jmp    L18
  mov    $0x1b,%eax
  jmp    L18
  mov    $0x1a,%eax
  jmp    L18
  mov    $0x19,%eax
  jmp    L18
  mov    $0x18,%eax
  jmp    L18
  mov    $0x17,%eax
  jmp    L18
  mov    $0x16,%eax
  jmp    L18
  mov    $0x15,%eax
  jmp    L18
  mov    $0x14,%eax
  jmp    L18
  mov    $0x13,%eax
  jmp    L18
  mov    $0x12,%eax
  jmp    L18
  mov    $0x11,%eax
  jmp    L18
  mov    $0x10,%eax
  jmp    L18
  mov    $0xf,%eax
  jmp    L18
  mov    $0xe,%eax
  jmp    L18
  mov    $0xd,%eax
  jmp    L18
  mov    $0xc,%eax
  jmp    L18
  mov    $0xb,%eax
  jmp    L18
  mov    $0xa,%eax
  jmp    L18
  mov    $0x9,%eax
  jmp    L18
  mov    $0x8,%eax
  jmp    L18
  mov    $0x7,%eax
  jmp    L18
  mov    $0x6,%eax
  jmp    L18
  mov    $0x5,%eax
  jmp    L18
L58:
  mov    $0xffffffff,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int value(int card) {
  switch (card) {
  case 22:
    return 40;
  case 21:
    return 39;
  case 20:
    return 38;
  case 9:
    return 37;
  case 8:
    return 36;
  case 19:
    return 35;
  case 35:
    return 34;
  case 34:
    return 33;
  case 48:
    return 32;
  case 47:
    return 31;
  case 7:
    return 30;
  case 33:
    return 29;
  case 18:
    return 28;
  case 6:
    return 27;
  case 46:
    return 26;
  case 32:
    return 25;
  case 45:
    return 24;
  case 17:
    return 23;
  case 31:
    return 22;
  case 5:
    return 21;
  case 44:
    return 20;
  case 4:
    return 19;
  case 30:
    return 18;
  case 43:
    return 17;
  case 15:
    return 16;
  case 3:
    return 15;
  case 29:
    return 14;
  case 16:
    return 13;
  case 14:
    return 12;
  case 2:
    return 11;
  case 1:
    return 10;
  case 28:
    return 9;
  case 27:
    return 8;
  case 42:
    return 7;
  case 41:
    return 6;
  case 40:
    return 5;
  default:
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<value>:
  endbr64
  cmp    $0x30,%edi
  ja     L5
  mov    %edi,%edi
  lea    D9(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x27,%eax
  ret
  mov    $0x26,%eax
  ret
  mov    $0x25,%eax
  ret
  mov    $0x24,%eax
  ret
  mov    $0x23,%eax
  ret
  mov    $0x22,%eax
  ret
  mov    $0x21,%eax
  ret
  mov    $0x20,%eax
  ret
  mov    $0x1f,%eax
  ret
  mov    $0x1e,%eax
  ret
  mov    $0x1d,%eax
  ret
  mov    $0x1c,%eax
  ret
  mov    $0x1b,%eax
  ret
  mov    $0x1a,%eax
  ret
  mov    $0x19,%eax
  ret
  mov    $0x18,%eax
  ret
  mov    $0x17,%eax
  ret
  mov    $0x16,%eax
  ret
  mov    $0x15,%eax
  ret
  mov    $0x14,%eax
  ret
  mov    $0x13,%eax
  ret
  mov    $0x12,%eax
  ret
  mov    $0x11,%eax
  ret
  mov    $0x10,%eax
  ret
  mov    $0xf,%eax
  ret
  mov    $0xe,%eax
  ret
  mov    $0xd,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0xb,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x7,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x5,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
  mov    $0x28,%eax
  ret
```

assistant: ```c
int value(int card) {
  switch (card) {
  case 22:
    return 40;
  case 21:
    return 39;
  case 20:
    return 38;
  case 9:
    return 37;
  case 8:
    return 36;
  case 19:
    return 35;
  case 35:
    return 34;
  case 34:
    return 33;
  case 48:
    return 32;
  case 47:
    return 31;
  case 7:
    return 30;
  case 33:
    return 29;
  case 18:
    return 28;
  case 6:
    return 27;
  case 46:
    return 26;
  case 32:
    return 25;
  case 45:
    return 24;
  case 17:
    return 23;
  case 31:
    return 22;
  case 5:
    return 21;
  case 44:
    return 20;
  case 4:
    return 19;
  case 30:
    return 18;
  case 43:
    return 17;
  case 15:
    return 16;
  case 3:
    return 15;
  case 29:
    return 14;
  case 16:
    return 13;
  case 14:
    return 12;
  case 2:
    return 11;
  case 1:
    return 10;
  case 28:
    return 9;
  case 27:
    return 8;
  case 42:
    return 7;
  case 41:
    return 6;
  case 40:
    return 5;
  default:
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<value>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x2f,%edi
  ja     L9
  lea    D4(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L9:
  ret
```

assistant: ```c
int value(int card) {
  switch (card) {
  case 22:
    return 40;
  case 21:
    return 39;
  case 20:
    return 38;
  case 9:
    return 37;
  case 8:
    return 36;
  case 19:
    return 35;
  case 35:
    return 34;
  case 34:
    return 33;
  case 48:
    return 32;
  case 47:
    return 31;
  case 7:
    return 30;
  case 33:
    return 29;
  case 18:
    return 28;
  case 6:
    return 27;
  case 46:
    return 26;
  case 32:
    return 25;
  case 45:
    return 24;
  case 17:
    return 23;
  case 31:
    return 22;
  case 5:
    return 21;
  case 44:
    return 20;
  case 4:
    return 19;
  case 30:
    return 18;
  case 43:
    return 17;
  case 15:
    return 16;
  case 3:
    return 15;
  case 29:
    return 14;
  case 16:
    return 13;
  case 14:
    return 12;
  case 2:
    return 11;
  case 1:
    return 10;
  case 28:
    return 9;
  case 27:
    return 8;
  case 42:
    return 7;
  case 41:
    return 6;
  case 40:
    return 5;
  default:
    return -1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<value>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x2f,%edi
  ja     L9
  lea    D3(%rip),%rax
  movsbl (%rax,%rdi,1),%eax
L9:
  ret
```

assistant: ```c
int value(int card) {
  switch (card) {
  case 22:
    return 40;
  case 21:
    return 39;
  case 20:
    return 38;
  case 9:
    return 37;
  case 8:
    return 36;
  case 19:
    return 35;
  case 35:
    return 34;
  case 34:
    return 33;
  case 48:
    return 32;
  case 47:
    return 31;
  case 7:
    return 30;
  case 33:
    return 29;
  case 18:
    return 28;
  case 6:
    return 27;
  case 46:
    return 26;
  case 32:
    return 25;
  case 45:
    return 24;
  case 17:
    return 23;
  case 31:
    return 22;
  case 5:
    return 21;
  case 44:
    return 20;
  case 4:
    return 19;
  case 30:
    return 18;
  case 43:
    return 17;
  case 15:
    return 16;
  case 3:
    return 15;
  case 29:
    return 14;
  case 16:
    return 13;
  case 14:
    return 12;
  case 2:
    return 11;
  case 1:
    return 10;
  case 28:
    return 9;
  case 27:
    return 8;
  case 42:
    return 7;
  case 41:
    return 6;
  case 40:
    return 5;
  default:
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x28(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0x80000000,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  neg    %eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  neg    %eax
  mov    %eax,-0x30(%rbp)
  movabs $0x8000000000000000,%rcx
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  and    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  neg    %rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  neg    %rax
  mov    %rax,-0x20(%rbp)
  mov    %rcx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  neg    %rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  and    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  neg    %rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  neg    %rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int e = 1, f = -1;
  volatile int i = (-0x7fffffff - 1);
  volatile int i2 = i & (((((((-i) + 1) - 1) + 1) - 1) + 1) - 1);
  i2 = -(i + e + f);
  i = -i;
  volatile long int li = (-0x7fffffffffffffffL - 1L);
  volatile long int li2 = li & (((((((-li) + 1) - 1) + 1) - 1) + 1) - 1);
  li2 = -(li + e + f);
  li = -li;
  volatile long long int lli = (-0x7fffffffffffffffLL - 1LL);
  volatile long long int lli2 = lli & (((((((-lli) + 1) - 1) + 1) - 1) + 1) - 1);
  lli2 = -(lli + e + f);
  lli = -lli;
  return 0;
}
```