ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x17,(%rsp)
  movl   $0x2a,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x2e,0xc(%rsp)
  movl   $0x4e,0x10(%rsp)
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D38(%rip),%r12
L6:
  mov    0x0(%rbp),%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x5,%ebx
  jne    L6
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D38
datatype: string
name: extract_symbolic_data
arguments: data_tag: D3
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string
name: extract_symbolic_data
arguments: data_tag: D41
datatype: string

tool: D39: Elements 	 Address 	 Value 

tool: D38: %d 	 %p 	 %d 


tool: D3: Your array is : %p 


tool: D49: Your derefernced array is : %d 


tool: D41: Your derefernced array + 2 is : %d 


assistant: ```c
int main() {
  int arr[5] = {23, 42, 5, 46, 78};
  printf("Elements \t Address \t Value \n");
  for (int i = 0; i < 5; i++) {
    printf("%d \t %p \t %d \n", i, &arr[i], arr[i]);
  }
  printf("Your array is : %p \n", arr);
  printf("Your derefernced array is : %d \n", *arr);
  printf("Your derefernced array + 2 is : %d \n", *(arr + 2));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D34(%rip),%rdi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x2a00000017,%rax
  mov    %rsp,%r13
  movl   $0x4e,0x10(%rsp)
  mov    %r13,%rbp
  mov    %rax,(%rsp)
  movabs $0x2e00000005,%rax
  mov    %rax,0x8(%rsp)
  call   <puts@plt>
L8:
  mov    0x0(%rbp),%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L8
  mov    %r13,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D34
datatype: string
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D41
datatype: string
name: extract_symbolic_data
arguments: data_tag: D20
datatype: string

tool: D34: Elements 	 Address 	 Value 

tool: D8: %d 	 %p 	 %d 


tool: D11: Your array is : %p 


tool: D41: Your derefernced array is : %d 


tool: D20: Your derefernced array + 2 is : %d 


assistant: ```c
int main() {
  int arr[5] = {23, 42, 5, 46, 78};
  printf("Elements \t Address \t Value \n");
  for (int i = 0; i < 5; i++) {
    printf("%d \t %p \t %d \n", i, &arr[i], arr[i]);
  }
  printf("Your array is : %p \n", arr);
  printf("Your derefernced array is : %d \n", *arr);
  printf("Your derefernced array + 2 is : %d \n", *(arr + 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D34(%rip),%rdi
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movl   $0x4e,0x10(%rsp)
  movaps %xmm0,(%rsp)
  mov    %r13,%rbp
  call   <puts@plt>
L17:
  mov    0x0(%rbp),%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L17
  mov    %r13,%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%esi
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D34
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D11
data_type: byte[16]
name: parse_data
arguments: data_label: D52
data_type: string
name: parse_data
arguments: data_label: D42
data_type: string
name: parse_data
arguments: data_label: D43
data_type: string

tool: D34: Elements 	 Address 	 Value 

tool: D28: %d 	 %p 	 %d 


tool: {"D11": [0x17,0x00,0x00,0x00,0x2a,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x2e,0x00,0x00,0x00]}

tool: D52: Your array is : %p 


tool: D42: Your derefernced array is : %d 


tool: D43: Your derefernced array + 2 is : %d 


assistant: ```c
int main() {
  int arr[5] = {23, 42, 5, 46, 78};
  printf("Elements \t Address \t Value \n");
  for (int i = 0; i < 5; i++) {
    printf("%d \t %p \t %d \n", i, &arr[i], arr[i]);
  }
  printf("Your array is : %p \n", arr);
  printf("Your derefernced array is : %d \n", *arr);
  printf("Your derefernced array + 2 is : %d \n", *(arr + 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<msecs_to_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,0x4(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void msecs_to_timespec(int msecs, struct timespec *tmspec) {
  tmspec->tv_sec = msecs / 1000;
  tmspec->tv_nsec = (msecs % 1000) * 1000 * 1000;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msecs_to_timespec>:
  endbr64
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsi)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsi)
  ret
```

assistant: ```c
void msecs_to_timespec(int msecs, struct timespec *tmspec) {
  tmspec->tv_sec = msecs / 1000;
  tmspec->tv_nsec = (msecs % 1000) * 1000 * 1000;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msecs_to_timespec>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,(%rsi)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsi)
  ret
```

assistant: ```c
void msecs_to_timespec(int msecs, struct timespec *tmspec) {
  tmspec->tv_sec = msecs / 1000;
  tmspec->tv_nsec = (msecs % 1000) * 1000 * 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<msecs_to_timespec>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  sub    %edx,%edi
  imul   $0xf4240,%edi,%edi
  movd   %edi,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsi)
  ret
```

assistant: ```c
void msecs_to_timespec(int msecs, struct timespec *tmspec) {
  tmspec->tv_sec = msecs / 1000;
  tmspec->tv_nsec = (msecs % 1000) * 1000 * 1000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L70
  mov    -0x8(%rbp),%rax
  mov    $0x58,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L4
L70:
  mov    $0x0,%eax
  jmp    L53
L4:
  cmpq   $0x1,-0x10(%rbp)
  jbe    L92
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L92
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L92
  mov    $0x0,%eax
  jmp    L53
L92:
  cmpq   $0x2,-0x10(%rbp)
  jbe    L59
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L59
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L59
  mov    $0x0,%eax
  jmp    L53
L59:
  mov    $0x1,%eax
L53:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: -0

assistant: ```c
int is_decimal(const char *string, size_t length) {
  if (strchr(string, 'x') || strchr(string, 'X')) {
    return 0;
  }
  if (length > 1 && string[0] == '0' && string[1] != '.') {
    return 0;
  }
  if (length > 2 && !strncmp(string, "-0", 2) && string[2] != '.') {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_decimal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x78,%esi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L62
L74:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  mov    $0x58,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L74
  cmp    $0x1,%rbp
  jbe    L2
  cmpb   $0x30,(%rbx)
  je     L46
L2:
  mov    $0x1,%eax
  cmp    $0x2,%rbp
  jbe    L74
  mov    $0x2,%edx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L74
  cmpb   $0x2e,0x2(%rbx)
  sete   %al
  movzbl %al,%eax
  jmp    L74
L46:
  cmpb   $0x2e,0x1(%rbx)
  jne    L74
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D8: -0

assistant: ```c
int is_decimal(const char *string, size_t length) {
  if (strchr(string, 'x') || strchr(string, 'X')) {
    return 0;
  }
  if (length > 1 && string[0] == '0' && string[1] != '.') {
    return 0;
  }
  if (length > 2 && !strncmp(string, "-0", 2) && string[2] != '.') {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_decimal>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x78,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L67
L30:
  xor    %eax,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  mov    $0x58,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L30
  cmp    $0x1,%rbp
  jbe    L14
  cmpb   $0x30,(%rbx)
  je     L56
L36:
  cmp    $0x2,%rbp
  je     L14
  mov    $0x2,%edx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L14
  xor    %eax,%eax
  cmpb   $0x2e,0x2(%rbx)
  sete   %al
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L56:
  cmpb   $0x2e,0x1(%rbx)
  jne    L30
  jmp    L36
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: -0

assistant: ```c
int is_decimal(const char *string, size_t length) {
  if (strchr(string, 'x') || strchr(string, 'X')) {
    return 0;
  }
  if (length > 1 && string[0] == '0' && string[1] != '.') {
    return 0;
  }
  if (length > 2 && !strncmp(string, "-0", 2) && string[2] != '.') {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_decimal>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x78,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L50
L40:
  xor    %eax,%eax
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    $0x58,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L40
  cmp    $0x1,%rbp
  jbe    L42
  cmpb   $0x30,(%rbx)
  je     L5
L75:
  cmp    $0x2,%rbp
  je     L42
  mov    $0x2,%edx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L42
  xor    %eax,%eax
  cmpb   $0x2e,0x2(%rbx)
  sete   %al
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L42:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  cmpb   $0x2e,0x1(%rbx)
  jne    L40
  jmp    L75
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: -0

assistant: ```c
int is_decimal(const char *string, size_t length) {
  if (strchr(string, 'x') || strchr(string, 'X')) {
    return 0;
  }
  if (length > 1 && string[0] == '0' && string[1] != '.') {
    return 0;
  }
  if (length > 2 && !strncmp(string, "-0", 2) && string[2] != '.') {
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<fgets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L51
L33:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L0
  cmpl   $0x0,-0x8(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  mov    $0x0,%eax
  jmp    L42
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0x4(%rbp)
  jne    L18
  addl   $0x1,-0x8(%rbp)
  jmp    L50
L18:
  addl   $0x1,-0x8(%rbp)
L51:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L33
L50:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L42:
  leave
  ret
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  int i;
  for (i = 0; i < num - 1; i++) {
    int c = fgetc(stream);
    if (c == EOF) {
      if (i > 0)
        str[i] = '\0';
      return NULL;
    }
    str[i] = c;
    if (c == '\n') {
      i++;
      break;
    }
  }
  str[i] = '\0';
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fgets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  cmp    $0x1,%esi
  jle    L66
  mov    %rdx,%r13
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%r12d
  mov    $0x0,%ebx
L48:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L25
  mov    %al,0x0(%rbp)
  cmp    $0xa,%eax
  je     L51
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  jne    L48
  jmp    L0
L25:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jle    L56
  movslq %ebx,%rbx
  movb   $0x0,(%r14,%rbx,1)
  jmp    L56
L51:
  lea    0x1(%rbx),%r12d
L0:
  movslq %r12d,%r12
  movb   $0x0,(%r14,%r12,1)
  mov    %r14,%rax
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  mov    $0x0,%r12d
  jmp    L0
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  int i;
  for (i = 0; i < num - 1; i++) {
    int c = fgetc(stream);
    if (c == EOF) {
      if (i > 0)
        str[i] = '\0';
      return NULL;
    }
    str[i] = c;
    if (c == '\n') {
      i++;
      break;
    }
  }
  str[i] = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fgets>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L8
  mov    D5(%rip),%r12
  mov    %rdx,%rbp
  mov    %rdi,%r15
  xor    %r14d,%r14d
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %al,(%r15)
  add    $0x1,%r14d
  cmp    $0xa,%eax
  je     L60
  add    $0x1,%r15
  cmp    %r14d,%ebx
  je     L79
L55:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  jne    L20
  xor    %eax,%eax
  test   %r14d,%r14d
  je     L39
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  movslq %r14d,%r14
  lea    0x0(%r13,%r14,1),%rbx
L45:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L79:
  movslq %ebx,%rbx
  add    %r13,%rbx
  jmp    L45
L8:
  mov    %rdi,%rbx
  jmp    L45
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  int i;
  for (i = 0; i < num - 1; i++) {
    int c = fgetc(stream);
    if (c == EOF) {
      if (i > 0)
        str[i] = '\0';
      return NULL;
    }
    str[i] = c;
    if (c == '\n') {
      i++;
      break;
    }
  }
  str[i] = '\0';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fgets>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L9
  mov    D4(%rip),%r12
  mov    %rdx,%rbp
  mov    %rdi,%r15
  xor    %r14d,%r14d
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %al,(%r15)
  add    $0x1,%r14d
  cmp    $0xa,%eax
  je     L0
  add    $0x1,%r15
  cmp    %r14d,%ebx
  je     L64
L2:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r12)
  jne    L55
  xor    %eax,%eax
  test   %r14d,%r14d
  je     L21
  movslq %r14d,%r14
  movb   $0x0,0x0(%r13,%r14,1)
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movslq %r14d,%r14
  lea    0x0(%r13,%r14,1),%rbx
L12:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L64:
  movslq %ebx,%rbx
  add    %r13,%rbx
  jmp    L12
L9:
  mov    %rdi,%rbx
  jmp    L12
```

assistant: ```c
char *fgets(char *str, int num, FILE *stream) {
  int i;
  for (i = 0; i < num - 1; i++) {
    int c = fgetc(stream);
    if (c == EOF) {
      if (i > 0)
        str[i] = '\0';
      return NULL;
    }
    str[i] = c;
    if (c == '\n') {
      i++;
      break;
    }
  }
  str[i] = '\0';
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x150(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    $0x28,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsi,%rdx
  mov    %rdi,%rax
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  movl   $0x2,-0xec(%rbp)
  movl   $0xa,-0x158(%rbp)
  movss  D28(%rip),%xmm0
  movss  %xmm0,-0x7c(%rbp)
  movss  D10(%rip),%xmm0
  movss  %xmm0,0x788(%rbp)
  movl   $0x0,-0x158(%rbp)
  jmp    L30
L24:
  mov    -0x158(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0xec,%rax
  movl   $0x5,(%rax)
  addl   $0x1,-0x158(%rbp)
L30:
  cmpl   $0x2,-0x158(%rbp)
  jle    L24
  movl   $0x0,-0x154(%rbp)
  jmp    L49
L0:
  mov    -0x154(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rbp,%rax
  sub    $0xec,%rax
  movl   $0x5,(%rax)
  addl   $0x1,-0x154(%rbp)
L49:
  cmpl   $0x9,-0x154(%rbp)
  jle    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D28
type: byte[4]
name: unpack_data
arguments: data_tag: D10
type: byte[4]

tool: D5: vandah

tool: {"D28": [0x00,0x00,0xb5,0x42]}

tool: {"D10": [0x00,0x00,0xb3,0x42]}

assistant: ```c
int main() {
  struct student {
    char name[100];
    int roll;
    float marks;
  };
  struct student stu[] = {
      {"vandah", 12, 89.5f},
      {"edin", 15, 98.0f},
      {"david", 17, 90.0f},
  };
  stu[0].roll = 2;
  stu[-1].roll = 10;
  stu[1].marks = 90.5f;
  stu[20].marks = 89.5f;
  for (int i = 0; i < 3; ++i) {
    stu[i].roll = 5;
  }
  for (int i = 0; i < 10; ++i) {
    stu[i].roll = 5;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  struct student {
    char name[100];
    int roll;
    float marks;
  };
  struct student stu[] = {
      {"vandah", 12, 89.5f},
      {"edin", 15, 98.0f},
      {"david", 17, 90.0f},
  };
  stu[0].roll = 2;
  stu[-1].roll = 10;
  stu[1].marks = 90.5f;
  stu[20].marks = 89.5f;
  for (int i = 0; i < 3; ++i) {
    stu[i].roll = 5;
  }
  for (int i = 0; i < 10; ++i) {
    stu[i].roll = 5;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct student {
    char name[100];
    int roll;
    float marks;
  };
  struct student stu[] = {
      {"vandah", 12, 89.5f},
      {"edin", 15, 98.0f},
      {"david", 17, 90.0f},
  };
  stu[0].roll = 2;
  stu[-1].roll = 10;
  stu[1].marks = 90.5f;
  stu[20].marks = 89.5f;
  for (int i = 0; i < 3; ++i) {
    stu[i].roll = 5;
  }
  for (int i = 0; i < 10; ++i) {
    stu[i].roll = 5;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct student {
    char name[100];
    int roll;
    float marks;
  };
  struct student stu[] = {
      {"vandah", 12, 89.5f},
      {"edin", 15, 98.0f},
      {"david", 17, 90.0f},
  };
  stu[0].roll = 2;
  stu[-1].roll = 10;
  stu[1].marks = 90.5f;
  stu[20].marks = 89.5f;
  for (int i = 0; i < 3; ++i) {
    stu[i].roll = 5;
  }
  for (int i = 0; i < 10; ++i) {
    stu[i].roll = 5;
  }
  return 0;
}
```