user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L54:
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfbc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfbc(%rbp),%eax
  cmp    $0x3e8,%eax
  jg     L54
  mov    -0xfc0(%rbp),%edx
  mov    -0xfbc(%rbp),%eax
  cmp    %eax,%edx
  jg     L54
L24:
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfc4(%rbp),%edx
  mov    -0xfc0(%rbp),%eax
  cmp    %eax,%edx
  jl     L24
  mov    -0xfc4(%rbp),%edx
  mov    -0xfbc(%rbp),%eax
  cmp    %eax,%edx
  jg     L24
  movl   $0x0,-0xfb4(%rbp)
  jmp    L2
L6:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfb4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xfb4(%rbp)
L2:
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L6
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xfb4(%rbp)
  jmp    L9
L83:
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%edx
  mov    -0xfb8(%rbp),%eax
  imul   %eax,%edx
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    %edx,-0xfb0(%rbp,%rax,4)
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xfb4(%rbp)
L9:
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L83
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D84
type: string
name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D81
type: string
name: retrieve_data
arguments: label: D42
type: string
name: retrieve_data
arguments: label: D57
type: string
name: retrieve_data
arguments: label: D82
type: string
name: retrieve_data
arguments: label: D45
type: string

tool: D84: 
 inseire n2 minore di 1000  

tool: D15: %d

tool: D81: 
 inserire n1 minore di n2  

tool: D42: 
 inserire il vettore dell'array  

tool: D57: 
 inserire un numero  

tool: D82: 
 inserire un numero intero  

tool: D45: %d  

assistant: ```c
main() {
  int vettore[1000];
  int K;
  int n1;
  int n2;
  int NUM;
  int x;
  do {
    printf("\n inseire n2 minore di 1000  ");
    scanf("%d", &n2);
    printf("\n inserire n1 minore di n2  ");
    scanf("%d", &n1);
  } while ((n2 > 1000) || (n1 > n2));
  do {
    printf("\n inserire il vettore dell'array  ");
    scanf("%d", &K);
  } while ((K < n1) || (K > n2));
  x = 0;
  while (x < K) {
    printf("\n inserire un numero  ");
    scanf("%d", &vettore[x]);
    x++;
  }
  printf("\n inserire un numero intero  ");
  scanf("%d", &NUM);
  x = 0;
  while (x < K) {
    vettore[x] = vettore[x] * NUM;
    printf("%d  ", vettore[x]);
    x++;
  }
}
```