ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<pakowanie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L13:
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x3,-0x4(%rbp)
  jle    L13
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pakowanie(int tab[4]) {
  int pak = 0, i;
  for (i = 0; i < 4; i++)
    pak = (pak << 8) | (tab[i] & 255);
  return pak;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pakowanie>:
  endbr64
  lea    0x10(%rdi),%rcx
  mov    $0x0,%eax
L6:
  shl    $0x8,%eax
  movzbl (%rdi),%edx
  or     %edx,%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L6
  ret
```

assistant: ```c
int pakowanie(int tab[4]) {
  int pak = 0, i;
  for (i = 0; i < 4; i++)
    pak = (pak << 8) | (tab[i] & 255);
  return pak;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pakowanie>:
  endbr64
  lea    0x10(%rdi),%rcx
  xor    %eax,%eax
L3:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x4,%rdi
  or     %edx,%eax
  cmp    %rcx,%rdi
  jne    L3
  ret
```

assistant: ```c
int pakowanie(int tab[4]) {
  int pak = 0, i;
  for (i = 0; i < 4; i++)
    pak = (pak << 8) | (tab[i] & 255);
  return pak;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pakowanie>:
  endbr64
  mov    (%rdi),%eax
  movzbl 0x4(%rdi),%edx
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %edx,%eax
  movzbl 0x8(%rdi),%edx
  shl    $0x8,%eax
  or     %eax,%edx
  movzbl 0xc(%rdi),%eax
  shl    $0x8,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int pakowanie(int tab[4]) {
  int pak = 0, i;
  for (i = 0; i < 4; i++)
    pak = (pak << 8) | (tab[i] & 255);
  return pak;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3,%edi
  call   <lruCacheInit@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L11:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <lruCacheSet@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <lruCacheGet@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x4,-0x4(%rbp)
  jle    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L36:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <lruCacheGet@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x4,-0x4(%rbp)
  jle    L36
  mov    $0x0,%eax
  call   <lruCacheFree@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: %d


assistant: ```c
void main(void) {
  int i;
  lruCacheInit(3);
  for (i = 0; i < 5; i++) {
    lruCacheSet(i, i + 1);
    printf("%d\n", lruCacheGet(i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", lruCacheGet(i));
  }
  lruCacheFree();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x3,%edi
  call   <lruCacheInit@plt>
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
L5:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <lruCacheSet@plt>
  mov    %ebp,%edi
  call   <lruCacheGet@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D10(%rip),%rbp
L17:
  mov    %ebx,%edi
  call   <lruCacheGet@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L17
  mov    $0x0,%eax
  call   <lruCacheFree@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D10
type: string

tool: D10: %d


assistant: ```c
void main(void) {
  int i;
  lruCacheInit(3);
  for (i = 0; i < 5; i++) {
    lruCacheSet(i, i + 1);
    printf("%d\n", lruCacheGet(i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", lruCacheGet(i));
  }
  lruCacheFree();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <lruCacheInit@plt>
L1:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <lruCacheSet@plt>
  mov    %r12d,%edi
  call   <lruCacheGet@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L1
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L17:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <lruCacheGet@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L17
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10e0 <lruCacheFree@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d


assistant: ```c
void main(void) {
  int i;
  lruCacheInit(3);
  for (i = 0; i < 5; i++) {
    lruCacheSet(i, i + 1);
    printf("%d\n", lruCacheGet(i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", lruCacheGet(i));
  }
  lruCacheFree();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <lruCacheInit@plt>
L4:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <lruCacheSet@plt>
  mov    %r12d,%edi
  call   <lruCacheGet@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L4
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
L11:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <lruCacheGet@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L11
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10e0 <lruCacheFree@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
void main(void) {
  int i;
  lruCacheInit(3);
  for (i = 0; i < 5; i++) {
    lruCacheSet(i, i + 1);
    printf("%d\n", lruCacheGet(i));
  }
  printf("\n");
  for (i = 0; i < 5; i++) {
    printf("%d\n", lruCacheGet(i));
  }
  lruCacheFree();
}
```
user: What is the c source code of the assembly code below?

```asm
<reinitialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L27:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movq   $0x0,(%rdx,%rax,8)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  add    %rcx,%rax
  shl    $0x5,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,8),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rdx,(%rcx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x3,-0x4(%rbp)
  jle    L27
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x2,-0x8(%rbp)
  jle    L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reinitialize(unsigned long factors[3][100], unsigned long powers[3][100], unsigned long number_of_factors[3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    number_of_factors[i] = 0;
    for (j = 0; j < 4; j++)
      factors[i][j] = powers[i][j] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reinitialize>:
  endbr64
  lea    0x18(%rdx),%rax
L0:
  movq   $0x0,(%rdx)
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rsi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rsi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x18(%rdi)
  add    $0x8,%rdx
  add    $0x320,%rsi
  add    $0x320,%rdi
  cmp    %rdx,%rax
  jne    L0
  ret
```

assistant: ```c
void reinitialize(unsigned long factors[3][100], unsigned long powers[3][100], unsigned long number_of_factors[3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    number_of_factors[i] = 0;
    for (j = 0; j < 4; j++)
      factors[i][j] = powers[i][j] = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reinitialize>:
  endbr64
  lea    0x960(%rdi),%rcx
L24:
  lea    0x20(%rsi),%rax
  movq   $0x0,(%rdx)
  cmp    %rax,%rdi
  jae    L9
  lea    0x20(%rdi),%rax
  cmp    %rax,%rsi
  jb     L12
L9:
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rsi)
  movups %xmm0,0x10(%rsi)
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
L15:
  add    $0x320,%rdi
  add    $0x8,%rdx
  add    $0x320,%rsi
  cmp    %rcx,%rdi
  jne    L24
  ret
  xchg   %ax,%ax
L12:
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rsi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rsi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x18(%rdi)
  jmp    L15
```

assistant: ```c
void reinitialize(unsigned long factors[3][100], unsigned long powers[3][100], unsigned long number_of_factors[3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    number_of_factors[i] = 0;
    for (j = 0; j < 4; j++)
      factors[i][j] = powers[i][j] = 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<reinitialize>:
  endbr64
  movq   $0x0,(%rdx)
  movq   $0x0,(%rsi)
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rsi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rsi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x8(%rdx)
  movq   $0x0,0x320(%rsi)
  movq   $0x0,0x320(%rdi)
  movq   $0x0,0x328(%rsi)
  movq   $0x0,0x328(%rdi)
  movq   $0x0,0x330(%rsi)
  movq   $0x0,0x330(%rdi)
  movq   $0x0,0x338(%rsi)
  movq   $0x0,0x338(%rdi)
  movq   $0x0,0x10(%rdx)
  movq   $0x0,0x640(%rsi)
  movq   $0x0,0x640(%rdi)
  movq   $0x0,0x648(%rsi)
  movq   $0x0,0x648(%rdi)
  movq   $0x0,0x650(%rsi)
  movq   $0x0,0x650(%rdi)
  movq   $0x0,0x658(%rsi)
  movq   $0x0,0x658(%rdi)
  ret
```

assistant: ```c
void reinitialize(unsigned long factors[3][100], unsigned long powers[3][100], unsigned long number_of_factors[3]) {
  int i, j;
  for (i = 0; i < 3; i++) {
    number_of_factors[i] = 0;
    for (j = 0; j < 4; j++)
      factors[i][j] = powers[i][j] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<needs_replace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x60,-0x4(%rbp)
  jle    L78
  cmpb   $0x7a,-0x4(%rbp)
  jle    L99
L78:
  cmpb   $0x40,-0x4(%rbp)
  jle    L16
  cmpb   $0x7a,-0x4(%rbp)
  jle    L99
L16:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L40
  cmpb   $0x39,-0x4(%rbp)
  jle    L99
L40:
  cmpb   $0x2d,-0x4(%rbp)
  je     L99
  cmpb   $0x2e,-0x4(%rbp)
  je     L99
  cmpb   $0x5f,-0x4(%rbp)
  je     L99
  cmpb   $0x7e,-0x4(%rbp)
  jne    L94
L99:
  mov    $0x0,%eax
  jmp    L24
L94:
  mov    $0x1,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int needs_replace(char c) {
  if (('a' <= c && c <= 'z') || ('A' <= c && c <= 'z') || ('0' <= c && c <= '9') || (c == '-') || (c == '.') || (c == '_') || (c == '~')) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<needs_replace>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x39,%al
  jbe    L5
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L5
  lea    -0x2d(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0x1,%dl
  jbe    L26
  cmp    $0x7e,%dil
  setne  %al
  movzbl %al,%eax
  ret
L5:
  mov    $0x0,%eax
L26:
  ret
```

assistant: ```c
int needs_replace(char c) {
  if (('a' <= c && c <= 'z') || ('A' <= c && c <= 'z') || ('0' <= c && c <= '9') || (c == '-') || (c == '.') || (c == '_') || (c == '~')) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<needs_replace>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x39,%al
  jbe    L2
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L2
  lea    -0x2d(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x7e,%dil
  sete   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int needs_replace(char c) {
  if (('a' <= c && c <= 'z') || ('A' <= c && c <= 'z') || ('0' <= c && c <= '9') || (c == '-') || (c == '.') || (c == '_') || (c == '~')) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<needs_replace>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x39,%al
  jbe    L9
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L9
  lea    -0x2d(%rdi),%eax
  cmp    $0x1,%al
  setbe  %al
  cmp    $0x7e,%dil
  sete   %dl
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int needs_replace(char c) {
  if (('a' <= c && c <= 'z') || ('A' <= c && c <= 'z') || ('0' <= c && c <= '9') || (c == '-') || (c == '.') || (c == '_') || (c == '~')) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HistNormalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L28:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L50
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L50:
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x7fff,-0xc(%rbp)
  jle    L28
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L55
  jmp    L57
L55:
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L61:
  cmpl   $0x7fff,-0xc(%rbp)
  jle    L6
L57:
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: f32[2]

tool: {"D5": [0.0,-1.875]}

assistant: ```c
void HistNormalize(double *h16) {
  int i;
  double max = -1.0;
  for (i = 0; i < 32768; i++)
    if (h16[i] > max)
      max = h16[i];
  if (max > 0.0)
    for (i = 0; i < 32768; i++)
      h16[i] /= max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HistNormalize>:
  endbr64
  lea    0x40000(%rdi),%rdx
  mov    %rdi,%rax
  movsd  D0(%rip),%xmm0
L10:
  movsd  (%rax),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L10
  comisd D8(%rip),%xmm1
  jbe    L22
L11:
  movsd  (%rdi),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdi)
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L11
L22:
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: f32[2]
name: unpack_data
arguments: label: D8
type: f32

tool: {"D0": [0.0,-1.875]}

tool: D8: 0

assistant: ```c
void HistNormalize(double *h16) {
  int i;
  double max = -1.0;
  for (i = 0; i < 32768; i++)
    if (h16[i] > max)
      max = h16[i];
  if (max > 0.0)
    for (i = 0; i < 32768; i++)
      h16[i] /= max;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HistNormalize>:
  endbr64
  movsd  D6(%rip),%xmm0
  lea    0x40000(%rdi),%rdx
  mov    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L8:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L8
  comisd D15(%rip),%xmm1
  jbe    L0
  nop
L21:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rdx,%rdi
  jne    L21
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: f32[2]
name: retrieve_data
arguments: label: D15
type_guessed: f32

tool: {"D6": [0.0,-1.875]}

tool: D15: 0

assistant: ```c
void HistNormalize(double *h16) {
  int i;
  double max = -1.0;
  for (i = 0; i < 32768; i++)
    if (h16[i] > max)
      max = h16[i];
  if (max > 0.0)
    for (i = 0; i < 32768; i++)
      h16[i] /= max;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HistNormalize>:
  endbr64
  movsd  D17(%rip),%xmm0
  lea    0x40000(%rdi),%rdx
  mov    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L14:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L14
  comisd D1(%rip),%xmm0
  unpcklpd %xmm1,%xmm1
  jbe    L23
  nopl   0x0(%rax,%rax,1)
L28:
  movupd (%rdi),%xmm0
  add    $0x10,%rdi
  divpd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rdi)
  cmp    %rdx,%rdi
  jne    L28
L23:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: f32[2]
name: parse_data
arguments: data_tag: D1
datatype: f32

tool: {"D17": [0.0,-1.875]}

tool: D1: 0

assistant: ```c
void HistNormalize(double *h16) {
  int i;
  double max = -1.0;
  for (i = 0; i < 32768; i++)
    if (h16[i] > max)
      max = h16[i];
  if (max > 0.0)
    for (i = 0; i < 32768; i++)
      h16[i] /= max;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  lea    -0x1d(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_cli@plt>
  test   %eax,%eax
  jne    L21
  movl   $0x1,-0x1c(%rbp)
  jmp    L14
L21:
  movzbl -0x1d(%rbp),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <aligned_malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <unit_test@plt>
L14:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(int argv, char *argc[]) {
  int ret_val = 0;
  size_t alloc_size;
  unsigned char alignment;
  void *buf;
  if (!parse_cli(&alloc_size, &alignment, argv, argc)) {
    ret_val = 1;
    goto Exit;
  }
  buf = aligned_malloc(alloc_size, alignment);
  unit_test(buf, alloc_size);
Exit:
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <parse_cli@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L28
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  ret
L28:
  movzbl 0xf(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <aligned_malloc@plt>
  mov    %rax,%rdi
  mov    0x10(%rsp),%rsi
  call   <unit_test@plt>
  mov    $0x0,%eax
  jmp    L9
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argv, char *argc[]) {
  int ret_val = 0;
  size_t alloc_size;
  unsigned char alignment;
  void *buf;
  if (!parse_cli(&alloc_size, &alignment, argv, argc)) {
    ret_val = 1;
    goto Exit;
  }
  buf = aligned_malloc(alloc_size, alignment);
  unit_test(buf, alloc_size);
Exit:
  return ret_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <parse_cli@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L14
  movzbl 0xf(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <aligned_malloc@plt>
  mov    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <unit_test@plt>
  xor    %eax,%eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argv, char *argc[]) {
  int ret_val = 0;
  size_t alloc_size;
  unsigned char alignment;
  void *buf;
  if (!parse_cli(&alloc_size, &alignment, argv, argc)) {
    ret_val = 1;
    goto Exit;
  }
  buf = aligned_malloc(alloc_size, alignment);
  unit_test(buf, alloc_size);
Exit:
  return ret_val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,%edx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xf(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <parse_cli@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L1
  movzbl 0xf(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <aligned_malloc@plt>
  mov    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <unit_test@plt>
  xor    %eax,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argv, char *argc[]) {
  int ret_val = 0;
  size_t alloc_size;
  unsigned char alignment;
  void *buf;
  if (!parse_cli(&alloc_size, &alignment, argv, argc)) {
    ret_val = 1;
    goto Exit;
  }
  buf = aligned_malloc(alloc_size, alignment);
  unit_test(buf, alloc_size);
Exit:
  return ret_val;
}
```