ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<number_to_letters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  cmpl   $0x4766,-0x14(%rbp)
  jle    L6
  mov    -0x20(%rbp),%rax
  movl   $0x3f3f3f,(%rax)
  jmp    L28
L6:
  cmpl   $0x2be,-0x14(%rbp)
  jle    L36
  mov    -0x14(%rbp),%eax
  sub    $0x1b,%eax
  movslq %eax,%rdx
  imul   $0x60f25deb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x8,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D11(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  lea    -0x1b(%rax),%edx
  movslq %edx,%rax
  imul   $0x60f25deb,%rax,%rax
  shr    $0x20,%rax
  sar    $0x8,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x2a4,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1b,%eax
  mov    %eax,-0x14(%rbp)
L36:
  cmpl   $0x1a,-0x14(%rbp)
  jle    L30
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D11(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x1a,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D11(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
L28:
  pop    %rbp
  ret
```

assistant: ```c
number_to_letters(decimal, letters) int decimal;
char letters[];
{
  static char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int index = 0;
  letters[0] = '\0';
  if (decimal > 18278) {
    strcpy(letters, "???");
    return;
  }
  if (decimal > 702) {
    letters[index++] = alphabet[(decimal - 26 - 1) / 676 - 1];
    decimal = (decimal - 26 - 1) % 676 + 26 + 1;
  }
  if (decimal > 26) {
    letters[index++] = alphabet[(decimal - 1) / 26 - 1];
    decimal = (decimal - 1) % 26 + 1;
  }
  letters[index++] = alphabet[decimal - 1];
  letters[index++] = '\0';
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<number_to_letters>:
  endbr64
  mov    %rsi,%rax
  movb   $0x0,(%rsi)
  cmp    $0x4766,%edi
  jg     L7
  cmp    $0x2be,%edi
  jle    L5
  sub    $0x1b,%edi
  movslq %edi,%rdx
  imul   $0x60f25deb,%rdx,%rdx
  sar    $0x28,%rdx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    -0x1(%rdx),%ecx
  movslq %ecx,%rcx
  lea    D25(%rip),%rsi
  movzbl (%rsi,%rcx,1),%ecx
  mov    %cl,(%rax)
  imul   $0x2a4,%edx,%edx
  sub    %edx,%edi
  add    $0x1b,%edi
  mov    $0x1,%ecx
L19:
  sub    $0x1,%edi
  lea    0x1(%rcx),%edx
  movslq %ecx,%rsi
  movslq %edi,%rcx
  imul   $0x4ec4ec4f,%rcx,%rcx
  sar    $0x23,%rcx
  mov    %edi,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%ecx
  lea    -0x1(%rcx),%r8d
  movslq %r8d,%r8
  lea    D25(%rip),%r9
  movzbl (%r9,%r8,1),%r8d
  mov    %r8b,(%rax,%rsi,1)
  imul   $0x1a,%ecx,%ecx
  sub    %ecx,%edi
  add    $0x1,%edi
  jmp    L42
L7:
  movl   $0x3f3f3f,(%rsi)
  ret
L5:
  cmp    $0x1a,%edi
  jg     L29
  mov    $0x0,%edx
L42:
  movslq %edx,%rcx
  sub    $0x1,%edi
  movslq %edi,%rdi
  lea    D25(%rip),%rsi
  movzbl (%rsi,%rdi,1),%esi
  mov    %sil,(%rax,%rcx,1)
  add    $0x1,%edx
  movslq %edx,%rdx
  movb   $0x0,(%rax,%rdx,1)
  ret
L29:
  mov    $0x0,%ecx
  jmp    L19
```

tool_calls: name: parse_data
arguments: tag: D25
type: string

tool: D25: ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
number_to_letters(decimal, letters) int decimal;
char letters[];
{
  static char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int index = 0;
  letters[0] = '\0';
  if (decimal > 18278) {
    strcpy(letters, "???");
    return;
  }
  if (decimal > 702) {
    letters[index++] = alphabet[(decimal - 26 - 1) / 676 - 1];
    decimal = (decimal - 26 - 1) % 676 + 26 + 1;
  }
  if (decimal > 26) {
    letters[index++] = alphabet[(decimal - 1) / 26 - 1];
    decimal = (decimal - 1) % 26 + 1;
  }
  letters[index++] = alphabet[decimal - 1];
  letters[index++] = '\0';
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<number_to_letters>:
  endbr64
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  cmp    $0x4766,%edi
  jg     L13
  cmp    $0x2be,%edi
  jg     L25
  lea    -0x1(%rdi),%r9d
  mov    %r9d,%ecx
  cmp    $0x1a,%edi
  jg     L19
  lea    D16(%rip),%r8
  movslq %ecx,%rdx
  mov    $0x1,%r10d
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rax,%r10,1)
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  lea    -0x1b(%rdi),%edx
  lea    D16(%rip),%r8
  mov    $0x3,%r10d
  mov    $0x1,%r11d
  mov    %rdx,%rdi
  imul   $0x60f25deb,%rdx,%rdx
  shr    $0x28,%rdx
  lea    -0x1(%rdx),%ecx
  imul   $0x2a4,%edx,%edx
  movslq %ecx,%rcx
  movzbl (%r8,%rcx,1),%ecx
  sub    %edx,%edi
  mov    %cl,(%rsi)
  mov    $0x2,%esi
  lea    0x1a(%rdi),%r9d
L0:
  mov    %r9d,%edx
  add    %rax,%rsi
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x23,%rdx
  lea    -0x1(%rdx),%ecx
  movslq %ecx,%rcx
  imul   $0x1a,%edx,%edx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rax,%r11,1)
  mov    %r9d,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rax,%r10,1)
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  movl   $0x3f3f3f,(%rsi)
  ret
L19:
  mov    $0x2,%r10d
  mov    $0x1,%esi
  xor    %r11d,%r11d
  lea    D16(%rip),%r8
  jmp    L0
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string

tool: D16: ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
number_to_letters(decimal, letters) int decimal;
char letters[];
{
  static char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int index = 0;
  letters[0] = '\0';
  if (decimal > 18278) {
    strcpy(letters, "???");
    return;
  }
  if (decimal > 702) {
    letters[index++] = alphabet[(decimal - 26 - 1) / 676 - 1];
    decimal = (decimal - 26 - 1) % 676 + 26 + 1;
  }
  if (decimal > 26) {
    letters[index++] = alphabet[(decimal - 1) / 26 - 1];
    decimal = (decimal - 1) % 26 + 1;
  }
  letters[index++] = alphabet[decimal - 1];
  letters[index++] = '\0';
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<number_to_letters>:
  endbr64
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  cmp    $0x4766,%edi
  jg     L9
  cmp    $0x2be,%edi
  jg     L2
  lea    -0x1(%rdi),%r9d
  mov    %r9d,%ecx
  cmp    $0x1a,%edi
  jg     L30
  lea    D14(%rip),%r8
  movslq %ecx,%rdx
  mov    $0x1,%r10d
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rax,%r10,1)
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    -0x1b(%rdi),%edx
  lea    D14(%rip),%r8
  mov    $0x3,%r10d
  mov    $0x1,%r11d
  mov    %rdx,%rdi
  imul   $0x60f25deb,%rdx,%rdx
  shr    $0x28,%rdx
  lea    -0x1(%rdx),%ecx
  imul   $0x2a4,%edx,%edx
  movslq %ecx,%rcx
  movzbl (%r8,%rcx,1),%ecx
  sub    %edx,%edi
  mov    %cl,(%rsi)
  mov    $0x2,%esi
  lea    0x1a(%rdi),%r9d
L22:
  mov    %r9d,%edx
  add    %rax,%rsi
  imul   $0x4ec4ec4f,%rdx,%rdx
  shr    $0x23,%rdx
  lea    -0x1(%rdx),%ecx
  movslq %ecx,%rcx
  imul   $0x1a,%edx,%edx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rax,%r11,1)
  mov    %r9d,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rdx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rax,%r10,1)
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movl   $0x3f3f3f,(%rsi)
  ret
L30:
  mov    $0x2,%r10d
  mov    $0x1,%esi
  xor    %r11d,%r11d
  lea    D14(%rip),%r8
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type: string

tool: D14: ABCDEFGHIJKLMNOPQRSTUVWXYZ

assistant: ```c
number_to_letters(decimal, letters) int decimal;
char letters[];
{
  static char alphabet[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
  int index = 0;
  letters[0] = '\0';
  if (decimal > 18278) {
    strcpy(letters, "???");
    return;
  }
  if (decimal > 702) {
    letters[index++] = alphabet[(decimal - 26 - 1) / 676 - 1];
    decimal = (decimal - 26 - 1) % 676 + 26 + 1;
  }
  if (decimal > 26) {
    letters[index++] = alphabet[(decimal - 1) / 26 - 1];
    decimal = (decimal - 1) % 26 + 1;
  }
  letters[index++] = alphabet[decimal - 1];
  letters[index++] = '\0';
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<base64_encode>:
  endbr64
  push   %rbx
  mov    %esi,%r8d
  mov    %rdx,%r10
  test   %esi,%esi
  jle    L37
  mov    %rdi,%r9
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  lea    D3(%rip),%rsi
  jmp    L86
L70:
  mov    %edi,%ecx
  mov    %r11d,%edi
  mov    %r11d,%ebx
L78:
  shl    $0x10,%eax
  add    %ebx,%eax
  shl    $0x8,%edi
  add    %edi,%eax
  mov    %eax,%edi
  shr    $0x12,%edi
  mov    %edi,%edi
  movzbl (%rsi,%rdi,1),%edi
  mov    %dil,(%rdx)
  mov    %eax,%edi
  shr    $0xc,%edi
  and    $0x3f,%edi
  movzbl (%rsi,%rdi,1),%edi
  mov    %dil,0x1(%rdx)
  mov    %eax,%edi
  shr    $0x6,%edi
  and    $0x3f,%edi
  movzbl (%rsi,%rdi,1),%edi
  mov    %dil,0x2(%rdx)
  and    $0x3f,%eax
  movzbl (%rsi,%rax,1),%eax
  mov    %al,0x3(%rdx)
  add    $0x4,%rdx
  cmp    %r8d,%ecx
  jge    L37
L86:
  lea    0x1(%rcx),%edi
  movslq %ecx,%rax
  movzbl (%r9,%rax,1),%eax
  cmp    %edi,%r8d
  jle    L70
  lea    0x2(%rcx),%ebx
  movslq %edi,%rdi
  movzbl (%r9,%rdi,1),%edi
  cmp    %ebx,%r8d
  jle    L30
  add    $0x3,%ecx
  movslq %ebx,%rbx
  movzbl (%r9,%rbx,1),%ebx
  jmp    L78
L30:
  mov    %ebx,%ecx
  mov    %r11d,%ebx
  jmp    L78
L37:
  add    $0x2,%r8d
  movslq %r8d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  lea    (%rax,%rax,2),%eax
  sub    %eax,%r8d
  cmp    $0x2,%r8d
  jge    L61
  movslq %ecx,%rdx
  lea    (%r10,%rdx,1),%rax
  lea    -0x1(%r10,%rdx,1),%rdx
  mov    $0x1,%esi
  sub    %r8d,%esi
  sub    %rsi,%rdx
L74:
  movb   $0x3d,-0x1(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L74
L61:
  movslq %ecx,%rcx
  movb   $0x0,(%r10,%rcx,1)
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D3: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void base64_encode(const unsigned char *in_bytes, int length, char *out_bytes) {
  static const char *encoding_table = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                                      "abcdefghijklmnopqrstuvwxyz"
                                      "0123456789+/";
  for (int i = 0, j = 0; i < length;) {
    unsigned int c0 = i < length ? in_bytes[i++] : 0;
    unsigned int c1 = i < length ? in_bytes[i++] : 0;
    unsigned int c2 = i < length ? in_bytes[i++] : 0;
    unsigned int triple = (c0 << 0x10) + (c1 << 0x08) + c2;
    out_bytes[j++] = encoding_table[(triple >> 3 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 2 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 1 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 0 * 6) & 0x3F];
  }
  int encoded_length = 4 * ((length + 2) / 3);
  int remaining_bytes = (3 - ((length + 2) % 3)) - 1;
  for (int i = 0; i < remaining_bytes; i++)
    out_bytes[encoded_length - 1 - i] = '=';
  out_bytes[encoded_length] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<base64_encode>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %rdx,%r10
  xor    %ecx,%ecx
  lea    D3(%rip),%rdi
  test   %esi,%esi
  jg     L5
  jmp    L18
  nop
L85:
  movslq %esi,%rsi
  lea    0x2(%rcx),%r11d
  movzbl (%r8,%rsi,1),%esi
  shl    $0x8,%esi
  cmp    %r11d,%r9d
  jle    L46
  movslq %r11d,%r11
  add    $0x3,%ecx
  movzbl (%r8,%r11,1),%r11d
L7:
  shl    $0x10,%eax
  add    $0x4,%rdx
  add    %esi,%eax
  lea    (%rax,%r11,1),%esi
  mov    %eax,%r11d
  shr    $0xc,%eax
  and    $0x3f,%eax
  shr    $0x12,%r11d
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdi,%r11,1),%r11d
  mov    %al,-0x3(%rdx)
  mov    %esi,%eax
  and    $0x3f,%esi
  shr    $0x6,%eax
  mov    %r11b,-0x4(%rdx)
  and    $0x3f,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,-0x2(%rdx)
  movzbl (%rdi,%rsi,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    %r9d,%ecx
  jge    L18
L5:
  movslq %ecx,%rax
  lea    0x1(%rcx),%esi
  movzbl (%r8,%rax,1),%eax
  cmp    %esi,%r9d
  jg     L85
  mov    %esi,%ecx
  xor    %r11d,%r11d
  xor    %esi,%esi
  jmp    L7
  nopl   0x0(%rax)
L18:
  add    $0x2,%r9d
  movslq %r9d,%rax
  mov    %r9d,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  lea    (%rax,%rax,2),%eax
  sub    %eax,%r9d
  cmp    $0x2,%r9d
  je     L77
  mov    $0x1,%eax
  lea    -0x1(%rcx),%edx
  sub    %r9d,%eax
  movslq %edx,%rdx
  lea    0x1(%rax),%rsi
  sub    %rax,%rdx
  add    %r10,%rdx
  mov    %esi,%edi
  test   %esi,%esi
  je     L77
  xor    %eax,%eax
L8:
  mov    %eax,%esi
  add    $0x1,%eax
  movb   $0x3d,(%rdx,%rsi,1)
  cmp    %edi,%eax
  jb     L8
L77:
  movslq %ecx,%rcx
  movb   $0x0,(%r10,%rcx,1)
  ret
L46:
  mov    %r11d,%ecx
  xor    %r11d,%r11d
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D3
data_type: string

tool: D3: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void base64_encode(const unsigned char *in_bytes, int length, char *out_bytes) {
  static const char *encoding_table = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                                      "abcdefghijklmnopqrstuvwxyz"
                                      "0123456789+/";
  for (int i = 0, j = 0; i < length;) {
    unsigned int c0 = i < length ? in_bytes[i++] : 0;
    unsigned int c1 = i < length ? in_bytes[i++] : 0;
    unsigned int c2 = i < length ? in_bytes[i++] : 0;
    unsigned int triple = (c0 << 0x10) + (c1 << 0x08) + c2;
    out_bytes[j++] = encoding_table[(triple >> 3 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 2 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 1 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 0 * 6) & 0x3F];
  }
  int encoded_length = 4 * ((length + 2) / 3);
  int remaining_bytes = (3 - ((length + 2) % 3)) - 1;
  for (int i = 0; i < remaining_bytes; i++)
    out_bytes[encoded_length - 1 - i] = '=';
  out_bytes[encoded_length] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<base64_encode>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  mov    %rdx,%r10
  xor    %ecx,%ecx
  lea    D6(%rip),%rdi
  test   %esi,%esi
  jg     L98
  jmp    L38
  nop
L73:
  movslq %esi,%rsi
  lea    0x2(%rcx),%r11d
  movzbl (%r8,%rsi,1),%esi
  shl    $0x8,%esi
  cmp    %r11d,%r9d
  jle    L52
  movslq %r11d,%r11
  add    $0x3,%ecx
  movzbl (%r8,%r11,1),%r11d
L12:
  shl    $0x10,%eax
  add    $0x4,%rdx
  add    %esi,%eax
  lea    (%rax,%r11,1),%esi
  mov    %eax,%r11d
  shr    $0xc,%eax
  and    $0x3f,%eax
  shr    $0x12,%r11d
  movzbl (%rdi,%rax,1),%eax
  movzbl (%rdi,%r11,1),%r11d
  mov    %al,-0x3(%rdx)
  mov    %esi,%eax
  and    $0x3f,%esi
  shr    $0x6,%eax
  mov    %r11b,-0x4(%rdx)
  and    $0x3f,%eax
  movzbl (%rdi,%rax,1),%eax
  mov    %al,-0x2(%rdx)
  movzbl (%rdi,%rsi,1),%eax
  mov    %al,-0x1(%rdx)
  cmp    %r9d,%ecx
  jge    L38
L98:
  movslq %ecx,%rax
  lea    0x1(%rcx),%esi
  movzbl (%r8,%rax,1),%eax
  cmp    %esi,%r9d
  jg     L73
  mov    %esi,%ecx
  xor    %r11d,%r11d
  xor    %esi,%esi
  jmp    L12
  nopl   0x0(%rax)
L38:
  add    $0x2,%r9d
  movslq %r9d,%rax
  mov    %r9d,%edx
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    0x0(,%rax,4),%ecx
  lea    (%rax,%rax,2),%eax
  sub    %eax,%r9d
  cmp    $0x2,%r9d
  je     L57
  mov    $0x1,%eax
  lea    -0x1(%rcx),%edx
  sub    %r9d,%eax
  movslq %edx,%rdx
  lea    0x1(%rax),%rsi
  sub    %rax,%rdx
  add    %r10,%rdx
  mov    %esi,%edi
  test   %esi,%esi
  je     L57
  xor    %eax,%eax
L48:
  mov    %eax,%esi
  add    $0x1,%eax
  movb   $0x3d,(%rdx,%rsi,1)
  cmp    %edi,%eax
  jb     L48
L57:
  movslq %ecx,%rcx
  movb   $0x0,(%r10,%rcx,1)
  ret
L52:
  mov    %r11d,%ecx
  xor    %r11d,%r11d
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/

assistant: ```c
void base64_encode(const unsigned char *in_bytes, int length, char *out_bytes) {
  static const char *encoding_table = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
                                      "abcdefghijklmnopqrstuvwxyz"
                                      "0123456789+/";
  for (int i = 0, j = 0; i < length;) {
    unsigned int c0 = i < length ? in_bytes[i++] : 0;
    unsigned int c1 = i < length ? in_bytes[i++] : 0;
    unsigned int c2 = i < length ? in_bytes[i++] : 0;
    unsigned int triple = (c0 << 0x10) + (c1 << 0x08) + c2;
    out_bytes[j++] = encoding_table[(triple >> 3 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 2 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 1 * 6) & 0x3F];
    out_bytes[j++] = encoding_table[(triple >> 0 * 6) & 0x3F];
  }
  int encoded_length = 4 * ((length + 2) / 3);
  int remaining_bytes = (3 - ((length + 2) % 3)) - 1;
  for (int i = 0; i < remaining_bytes; i++)
    out_bytes[encoded_length - 1 - i] = '=';
  out_bytes[encoded_length] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xc,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x7ed55d16,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x13,%eax
  xor    -0x4(%rbp),%eax
  xor    $0xc761c23c,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    $0x165667b1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x2c5d9b94(%rax),%edx
  mov    -0x4(%rbp),%eax
  shl    $0x9,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x28fb93b,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  xor    -0x4(%rbp),%eax
  xor    $0xb55a4f09,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(unsigned int a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%eax
  mov    %eax,%edx
  shr    $0x13,%edx
  xor    %eax,%edx
  xor    $0xc761c23c,%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  add    %edx,%eax
  lea    0x165667b1(%rax),%edx
  shl    $0x9,%edx
  sub    $0x160733e3,%eax
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
unsigned int hash(unsigned int a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%eax
  mov    %eax,%edx
  shr    $0x13,%edx
  xor    %eax,%edx
  xor    $0xc761c23c,%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  add    %edx,%eax
  lea    0x165667b1(%rax),%edx
  sub    $0x160733e3,%eax
  shl    $0x9,%edx
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
unsigned int hash(unsigned int a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash>:
  endbr64
  mov    %edi,%eax
  shl    $0xc,%eax
  lea    0x7ed55d16(%rax,%rdi,1),%eax
  mov    %eax,%edx
  shr    $0x13,%edx
  xor    %eax,%edx
  xor    $0xc761c23c,%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  add    %edx,%eax
  lea    0x165667b1(%rax),%edx
  sub    $0x160733e3,%eax
  shl    $0x9,%edx
  xor    %edx,%eax
  lea    -0x28fb93b(%rax,%rax,8),%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  xor    %edx,%eax
  xor    $0xb55a4f09,%eax
  ret
```

assistant: ```c
unsigned int hash(unsigned int a) {
  a = (a + 0x7ed55d16) + (a << 12);
  a = (a ^ 0xc761c23c) ^ (a >> 19);
  a = (a + 0x165667b1) + (a << 5);
  a = (a + 0xd3a2646c) ^ (a << 9);
  a = (a + 0xfd7046c5) + (a << 3);
  a = (a ^ 0xb55a4f09) ^ (a >> 16);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<starbar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L9:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x28,-0x4(%rbp)
  jle    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void starbar(void) {
  int count;
  for (count = 1; count <= 40; count++)
    putchar('*');
  putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<starbar>:
  endbr64
  push   %rbx
  mov    $0x28,%ebx
L3:
  mov    $0x2a,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void starbar(void) {
  int count;
  for (count = 1; count <= 40; count++)
    putchar('*');
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<starbar>:
  endbr64
  push   %rbx
  mov    $0x28,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x2a,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
void starbar(void) {
  int count;
  for (count = 1; count <= 40; count++)
    putchar('*');
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<starbar>:
  endbr64
  push   %rbx
  mov    $0x28,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x2a,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L7
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
```

assistant: ```c
void starbar(void) {
  int count;
  for (count = 1; count <= 40; count++)
    putchar('*');
  putchar('\n');
}
```