ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_mvaddstr>:
  endbr64
  mov    %edi,%r9d
  test   %esi,%esi
  jns    L4
  mov    $0x1,%ecx
  mov    %esi,%edi
  mov    $0x1,%eax
  sub    %esi,%ecx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L18:
  lea    (%rdi,%rax,1),%esi
  movslq %eax,%r8
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L34
L13:
  cmpb   $0x0,-0x1(%rdx,%rax,1)
  jne    L18
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  ret
L34:
  add    %r8,%rdx
L4:
  sub    $0x8,%rsp
  mov    D34(%rip),%rax
  mov    %r9d,%edi
  mov    (%rax),%rcx
  sub    %esi,%ecx
  call   <mvaddnstr@plt>
  mov    %eax,%r8d
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%r8d
  je     L41
  mov    D26(%rip),%rax
  mov    (%rax),%eax
L41:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int my_mvaddstr(int y, int x, char *str) {
  int i = 0;
  for (; x < 0; ++x, ++i)
    if (str[i] == '\0')
      return ERR;
  if (mvaddnstr(y, x, &str[i], (int)COLS - x) == ERR)
    return ERR;
  return OK;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_mvaddstr>:
  endbr64
  mov    %edi,%r9d
  test   %esi,%esi
  jns    L13
  mov    $0x1,%ecx
  mov    %esi,%edi
  mov    $0x1,%eax
  sub    %esi,%ecx
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L2:
  lea    (%rdi,%rax,1),%esi
  movslq %eax,%r8
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L46
L35:
  cmpb   $0x0,-0x1(%rdx,%rax,1)
  jne    L2
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  ret
L46:
  add    %r8,%rdx
L13:
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    %r9d,%edi
  mov    (%rax),%rcx
  sub    %esi,%ecx
  call   <mvaddnstr@plt>
  mov    %eax,%r8d
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%r8d
  je     L25
  mov    D23(%rip),%rax
  mov    (%rax),%eax
L25:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int my_mvaddstr(int y, int x, char *str) {
  int i = 0;
  for (; x < 0; ++x, ++i)
    if (str[i] == '\0')
      return ERR;
  if (mvaddnstr(y, x, &str[i], (int)COLS - x) == ERR)
    return ERR;
  return OK;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gt_is_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L8
  mov    $0x1,%eax
  jmp    L4
L8:
  mov    $0x0,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
bool gt_is_little_endian(void) {
  int x = 1;
  if (*(char *)&x == 1)
    return true;
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gt_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool gt_is_little_endian(void) {
  int x = 1;
  if (*(char *)&x == 1)
    return true;
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gt_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool gt_is_little_endian(void) {
  int x = 1;
  if (*(char *)&x == 1)
    return true;
  return false;
}
```
user: What is the c source code of the assembly code below:

```asm
<gt_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool gt_is_little_endian(void) {
  int x = 1;
  if (*(char *)&x == 1)
    return true;
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<util_getLocalTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void util_getLocalTime(const char *fmt, char *buf, size_t len) {
  struct tm ltime;
  time_t t = time(NULL);
  localtime_r(&t, &ltime);
  strftime(buf, len, fmt, &ltime);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<util_getLocalTime>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  mov    %rsp,%r13
  lea    0x4(%rsp),%rdi
  mov    %r13,%rsi
  call   <localtime_r@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void util_getLocalTime(const char *fmt, char *buf, size_t len) {
  struct tm ltime;
  time_t t = time(NULL);
  localtime_r(&t, &ltime);
  strftime(buf, len, fmt, &ltime);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<util_getLocalTime>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %r14,%rsi
  mov    %eax,0x4(%rsp)
  call   <localtime_r@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void util_getLocalTime(const char *fmt, char *buf, size_t len) {
  struct tm ltime;
  time_t t = time(NULL);
  localtime_r(&t, &ltime);
  strftime(buf, len, fmt, &ltime);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_getLocalTime>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %r14,%rsi
  mov    %eax,0x4(%rsp)
  call   <localtime_r@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void util_getLocalTime(const char *fmt, char *buf, size_t len) {
  struct tm ltime;
  time_t t = time(NULL);
  localtime_r(&t, &ltime);
  strftime(buf, len, fmt, &ltime);
}
```
user: What is the c source code of the assembly code below?

```asm
<zmodem_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %esi,-0xb8(%rbp)
  mov    %rdx,-0xc0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  cmpl   $0x0,-0xb4(%rbp)
  je     L4
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void zmodem_error(int status, int errnum, const char *message, ...) {
  if (status)
    exit(status);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zmodem_error>:
  endbr64
  test   %edi,%edi
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void zmodem_error(int status, int errnum, const char *message, ...) {
  if (status)
    exit(status);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zmodem_error>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void zmodem_error(int status, int errnum, const char *message, ...) {
  if (status)
    exit(status);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zmodem_error>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void zmodem_error(int status, int errnum, const char *message, ...) {
  if (status)
    exit(status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<switchCol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L7:
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  movsd  (%rcx,%rax,8),%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  mov    -0xc(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void switchCol(double A[1000][1000], double sigma[1000], int index1, int index2, int n) {
  int i;
  double aux;
  for (i = 0; i < n; i++) {
    aux = A[i][index1];
    A[i][index1] = A[i][index2];
    A[i][index2] = aux;
  }
  aux = sigma[index1];
  sigma[index1] = sigma[index2];
  sigma[index2] = aux;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<switchCol>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%r9
  mov    %edx,%edi
  mov    %ecx,%esi
  test   %r8d,%r8d
  jle    L1
  movslq %edx,%r11
  lea    (%r10,%r11,8),%rax
  lea    -0x1(%r8),%edx
  imul   $0x3e8,%rdx,%rdx
  add    %r11,%rdx
  lea    0x1f40(%r10,%rdx,8),%rcx
  movslq %esi,%rdx
  sub    %r11,%rdx
L18:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rdx,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rdx,8)
  add    $0x1f40,%rax
  cmp    %rcx,%rax
  jne    L18
L1:
  movslq %edi,%rdi
  lea    (%r9,%rdi,8),%rdx
  movsd  (%rdx),%xmm0
  movslq %esi,%rsi
  lea    (%r9,%rsi,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
```

assistant: ```c
void switchCol(double A[1000][1000], double sigma[1000], int index1, int index2, int n) {
  int i;
  double aux;
  for (i = 0; i < n; i++) {
    aux = A[i][index1];
    A[i][index1] = A[i][index2];
    A[i][index2] = aux;
  }
  aux = sigma[index1];
  sigma[index1] = sigma[index2];
  sigma[index2] = aux;
}
```
user: Translate the below assembly code into C programming language:

```asm
<switchCol>:
  endbr64
  mov    %rsi,%r9
  movslq %edx,%rdx
  test   %r8d,%r8d
  jle    L27
  lea    -0x1(%r8),%esi
  movslq %ecx,%rcx
  lea    (%rdi,%rdx,8),%rax
  imul   $0x3e8,%rsi,%rsi
  add    %rdx,%rsi
  lea    0x1f40(%rdi,%rsi,8),%rdi
  mov    %rcx,%rsi
  sub    %rdx,%rsi
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rsi,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rsi,8)
  add    $0x1f40,%rax
  cmp    %rdi,%rax
  jne    L18
L24:
  lea    (%r9,%rdx,8),%rdx
  lea    (%r9,%rcx,8),%rax
  movsd  (%rdx),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
  xchg   %ax,%ax
L27:
  movslq %ecx,%rcx
  jmp    L24
```

assistant: ```c
void switchCol(double A[1000][1000], double sigma[1000], int index1, int index2, int n) {
  int i;
  double aux;
  for (i = 0; i < n; i++) {
    aux = A[i][index1];
    A[i][index1] = A[i][index2];
    A[i][index2] = aux;
  }
  aux = sigma[index1];
  sigma[index1] = sigma[index2];
  sigma[index2] = aux;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<switchCol>:
  endbr64
  mov    %rsi,%r9
  movslq %edx,%rdx
  test   %r8d,%r8d
  jle    L20
  lea    -0x1(%r8),%esi
  movslq %ecx,%rcx
  lea    (%rdi,%rdx,8),%rax
  imul   $0x3e8,%rsi,%rsi
  add    %rdx,%rsi
  lea    0x1f40(%rdi,%rsi,8),%rdi
  mov    %rcx,%rsi
  sub    %rdx,%rsi
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%rax),%xmm0
  movsd  (%rax,%rsi,8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rax,%rsi,8)
  add    $0x1f40,%rax
  cmp    %rdi,%rax
  jne    L18
L9:
  lea    (%r9,%rdx,8),%rdx
  lea    (%r9,%rcx,8),%rax
  movsd  (%rdx),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
  xchg   %ax,%ax
L20:
  movslq %ecx,%rcx
  jmp    L9
```

assistant: ```c
void switchCol(double A[1000][1000], double sigma[1000], int index1, int index2, int n) {
  int i;
  double aux;
  for (i = 0; i < n; i++) {
    aux = A[i][index1];
    A[i][index1] = A[i][index2];
    A[i][index2] = aux;
  }
  aux = sigma[index1];
  sigma[index1] = sigma[index2];
  sigma[index2] = aux;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<example_bad_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int example_bad_ptr(long i) {
  int *memory_at_address_i = (int *)i;
  return *memory_at_address_i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<example_bad_ptr>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int example_bad_ptr(long i) {
  int *memory_at_address_i = (int *)i;
  return *memory_at_address_i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<example_bad_ptr>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int example_bad_ptr(long i) {
  int *memory_at_address_i = (int *)i;
  return *memory_at_address_i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<example_bad_ptr>:
  endbr64
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int example_bad_ptr(long i) {
  int *memory_at_address_i = (int *)i;
  return *memory_at_address_i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmp_double_gt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L13
  mov    $0xffffffff,%eax
  jmp    L35
L13:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L36
  mov    $0x1,%eax
  jmp    L35
L36:
  mov    $0x0,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_double_gt(const void *a, const void *b) {
  double a_ = *(double *)a;
  double b_ = *(double *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp_double_gt>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L2
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L2:
  ret
```

assistant: ```c
int cmp_double_gt(const void *a, const void *b) {
  double a_ = *(double *)a;
  double b_ = *(double *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_double_gt>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L4
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L4:
  ret
```

assistant: ```c
int cmp_double_gt(const void *a, const void *b) {
  double a_ = *(double *)a;
  double b_ = *(double *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_double_gt>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm1,%xmm0
  ja     L1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
L1:
  ret
```

assistant: ```c
int cmp_double_gt(const void *a, const void *b) {
  double a_ = *(double *)a;
  double b_ = *(double *)b;
  if (a_ > b_)
    return -1;
  if (a_ < b_)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sockaddr_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sockaddr_len@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L9
L18:
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  leave
  ret
```

assistant: ```c
struct sockaddr *sockaddr_dup(struct sockaddr *addr) {
  socklen_t addrlen = sockaddr_len(addr);
  if (addrlen == 0)
    return NULL;
  void *dst = calloc(sizeof(struct sockaddr_storage), 1);
  return memcpy(dst, addr, addrlen);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sockaddr_dup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <sockaddr_len@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  test   %rbp,%rbp
  je     L4
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct sockaddr *sockaddr_dup(struct sockaddr *addr) {
  socklen_t addrlen = sockaddr_len(addr);
  if (addrlen == 0)
    return NULL;
  void *dst = calloc(sizeof(struct sockaddr_storage), 1);
  return memcpy(dst, addr, addrlen);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sockaddr_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <sockaddr_len@plt>
  test   %rax,%rax
  je     L0
  mov    $0x1,%esi
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
  nop
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct sockaddr *sockaddr_dup(struct sockaddr *addr) {
  socklen_t addrlen = sockaddr_len(addr);
  if (addrlen == 0)
    return NULL;
  void *dst = calloc(sizeof(struct sockaddr_storage), 1);
  return memcpy(dst, addr, addrlen);
}
```
user: What is the c source code of the assembly code below:

```asm
<sockaddr_dup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <sockaddr_len@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%esi
  mov    $0x4,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <memcpy@plt>
  nop
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct sockaddr *sockaddr_dup(struct sockaddr *addr) {
  socklen_t addrlen = sockaddr_len(addr);
  if (addrlen == 0)
    return NULL;
  void *dst = calloc(sizeof(struct sockaddr_storage), 1);
  return memcpy(dst, addr, addrlen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<solcon_append_multprec_solution_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L43:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L54:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L34
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L34:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L31
L29:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x30(%rbp),%rax
  mov    -0x40(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x40(%rbp)
L31:
  mov    -0x40(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L29
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1e8,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int solcon_append_multprec_solution_string(int nv, int nc, char *s) {
  int a[2], b[nc], fail, i;
  double *c;
  a[0] = nv;
  a[1] = nc;
  for (i = 0; i < nc; i++)
    b[i] = s[i];
  fail = _ada_use_c2phc(488, a, b, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_append_multprec_solution_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%r8d
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L25:
  cmp    %rdx,%rsp
  je     L41
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L25
L41:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L52
  orq    $0x0,-0x8(%rsp,%rax,1)
L52:
  mov    %rsp,%rdi
  mov    %r8d,-0x10(%rbp)
  mov    %esi,-0xc(%rbp)
  test   %esi,%esi
  jle    L0
  mov    %esi,%esi
  mov    $0x0,%eax
L38:
  movsbl (%rcx,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L38
L0:
  lea    -0x10(%rbp),%rsi
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x1e8,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  leave
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_append_multprec_solution_string(int nv, int nc, char *s) {
  int a[2], b[nc], fail, i;
  double *c;
  a[0] = nv;
  a[1] = nc;
  for (i = 0; i < nc; i++)
    b[i] = s[i];
  fail = _ada_use_c2phc(488, a, b, c);
  return fail;
}
```