ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x2,%esi
  push   %r13
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000002,%rax
  movl   $0xa,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%rbp
  mov    %rbx,%r13
  mov    %rax,(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x8(%rsp)
L13:
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L80
  mov    0x0(%r13),%esi
  jmp    L13
  nopl   0x0(%rax)
L80:
  lea    D1(%rip),%r14
  mov    %rbx,%r13
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x2,%esi
L23:
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L41
  mov    0x0(%r13),%esi
  jmp    L23
  xchg   %ax,%ax
L41:
  mov    %r14,%rdi
  mov    %rbx,%r13
  call   <puts@plt>
  mov    $0x2,%esi
L84:
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  je     L50
  mov    0x0(%r13),%esi
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x2,%esi
L42:
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L34
  mov    (%rbx),%esi
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L34:
  lea    D23(%rip),%rbp
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type_infered: string
name: disassemble_data
arguments: label: D1
type_infered: string
name: disassemble_data
arguments: label: D23
type_infered: string

tool: D27: %u

tool: 

tool: D23: %u


assistant: ```c
int main() {
  unsigned int values[5] = {2, 4, 6, 8, 10};
  unsigned int *vPtr;
  int i;
  for (i = 0; i < 5; i++) {
    printf("%u", values[i]);
  }
  puts("");
  vPtr = values;
  vPtr = &values[0];
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", *(vPtr + i));
  }
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", *(values + i));
  }
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", vPtr[i]);
  }
  puts("");
  printf("%u\n", values[4]);
  printf("%u\n", *(values + 4));
  printf("%u\n", vPtr[4]);
  printf("%u\n", *(vPtr + 4));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D37(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x14(%rsp),%rbp
  movaps %xmm0,(%rsp)
  mov    %rbx,%r13
L16:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L16
  lea    D7(%rip),%r14
  mov    %rbx,%r13
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  call   <puts@plt>
L48:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L48
  mov    %r14,%rdi
  mov    %rbx,%r13
  call   <puts@plt>
L25:
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L25
  mov    %r14,%rdi
  call   <puts@plt>
L7:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L7
  lea    D6(%rip),%rbp
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D37
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D2: %u

tool: {"D37": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: 

tool: D6: %u


assistant: ```c
int main() {
  unsigned int values[5] = {2, 4, 6, 8, 10};
  unsigned int *vPtr;
  int i;
  for (i = 0; i < 5; i++) {
    printf("%u", values[i]);
  }
  puts("");
  vPtr = values;
  vPtr = &values[0];
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", *(vPtr + i));
  }
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", *(values + i));
  }
  puts("");
  for (i = 0; i < 5; i++) {
    printf("%u", vPtr[i]);
  }
  puts("");
  printf("%u\n", values[4]);
  printf("%u\n", *(values + 4));
  printf("%u\n", vPtr[4]);
  printf("%u\n", *(vPtr + 4));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gdtInit@plt>
  mov    $0x0,%eax
  call   <idtInit@plt>
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <initTerm@plt>
  mov    $0x0,%eax
  call   <initExceptions@plt>
  mov    $0x0,%eax
  call   <initKeyboard@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <logSerial@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: Boot

assistant: ```c
void init() {
  gdtInit();
  idtInit();
  initTerm(0, 5);
  initExceptions();
  initKeyboard();
  logSerial("Boot");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gdtInit@plt>
  mov    $0x0,%eax
  call   <idtInit@plt>
  mov    $0x5,%esi
  mov    $0x0,%edi
  call   <initTerm@plt>
  mov    $0x0,%eax
  call   <initExceptions@plt>
  mov    $0x0,%eax
  call   <initKeyboard@plt>
  lea    D8(%rip),%rdi
  call   <logSerial@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: Boot

assistant: ```c
void init() {
  gdtInit();
  idtInit();
  initTerm(0, 5);
  initExceptions();
  initKeyboard();
  logSerial("Boot");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdtInit@plt>
  xor    %eax,%eax
  call   <idtInit@plt>
  xor    %edi,%edi
  mov    $0x5,%esi
  call   <initTerm@plt>
  xor    %eax,%eax
  call   <initExceptions@plt>
  xor    %eax,%eax
  call   <initKeyboard@plt>
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    10c0 <logSerial@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: Boot

assistant: ```c
void init() {
  gdtInit();
  idtInit();
  initTerm(0, 5);
  initExceptions();
  initKeyboard();
  logSerial("Boot");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gdtInit@plt>
  xor    %eax,%eax
  call   <idtInit@plt>
  xor    %edi,%edi
  mov    $0x5,%esi
  call   <initTerm@plt>
  xor    %eax,%eax
  call   <initExceptions@plt>
  xor    %eax,%eax
  call   <initKeyboard@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    10c0 <logSerial@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: Boot

assistant: ```c
void init() {
  gdtInit();
  idtInit();
  initTerm(0, 5);
  initExceptions();
  initKeyboard();
  logSerial("Boot");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_1970_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
time_t get_1970_ms() {
  struct timeval tv = {0};
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_1970_ms>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,0xc(%rsp),%eax
  mov    0x10(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_1970_ms() {
  struct timeval tv = {0};
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_1970_ms>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  call   <gettimeofday@plt>
  movslq 0x10(%rsp),%rdx
  imul   $0x3e8,0xc(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_1970_ms() {
  struct timeval tv = {0};
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_1970_ms>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  call   <gettimeofday@plt>
  movslq 0x10(%rsp),%rdx
  imul   $0x3e8,0xc(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
time_t get_1970_ms() {
  struct timeval tv = {0};
  gettimeofday(&tv, NULL);
  return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x87_fpu_exception_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  hlt
  nop
  pop    %rbp
  ret
```

assistant: ```c
void x87_fpu_exception_handler(struct exception_info *info) {
  asm volatile("" : : :);
  asm volatile("hlt");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<x87_fpu_exception_handler>:
  endbr64
  hlt
  ret
```

assistant: ```c
void x87_fpu_exception_handler(struct exception_info *info) {
  asm volatile("" : : :);
  asm volatile("hlt");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<x87_fpu_exception_handler>:
  endbr64
  hlt
  ret
```

assistant: ```c
void x87_fpu_exception_handler(struct exception_info *info) {
  asm volatile("" : : :);
  asm volatile("hlt");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<x87_fpu_exception_handler>:
  endbr64
  hlt
  ret
```

assistant: ```c
void x87_fpu_exception_handler(struct exception_info *info) {
  asm volatile("" : : :);
  asm volatile("hlt");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<litLatencyMes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %rdi,-0x168(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x15c(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x158(%rbp)
  cmpq   $0x0,-0x158(%rbp)
  jne    L82
  mov    $0x0,%eax
  jmp    L45
L65:
  mov    -0x158(%rbp),%rdx
  lea    -0x140(%rbp),%rax
  mov    $0x12d,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x140(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x150(%rbp)
  cmpq   $0x0,-0x150(%rbp)
  je     L1
  mov    -0x150(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x148(%rbp)
  cmpq   $0x0,-0x148(%rbp)
  je     L50
  mov    -0x148(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x150(%rbp),%rax
  add    %rax,%rdx
  lea    -0x140(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x140(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    -0x168(%rbp),%rdx
  mov    %eax,(%rdx)
  movl   $0x1,-0x15c(%rbp)
  jmp    L34
L82:
  nop
  mov    -0x158(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  je     L65
  jmp    L34
L1:
  nop
  jmp    L34
L50:
  nop
L34:
  mov    -0x158(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x15c(%rbp),%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D20
data_type: string
name: disassemble_data
arguments: label: D22
data_type: string

tool: D13: r

tool: D20: /tmp/wrekames.tmp

tool: D22: time=

assistant: ```c
int litLatencyMes(float *fLatency) {
  FILE *fFile;
  char ligne[300 + 1];
  char *pos, *pos2;
  int ok = 0;
  fFile = fopen("/tmp/wrekames.tmp", "r");
  if (!fFile) {
    return 0;
  }
  while (!feof(fFile)) {
    fgets(ligne, sizeof(ligne), fFile);
    pos = strstr(ligne, "time=");
    if (!pos)
      break;
    pos2 = strrchr(pos, ' ');
    if (!pos2)
      break;
    pos2[0] = '\0';
    strcpy(ligne, pos + strlen("time="));
    *fLatency = atof(ligne);
    ok = 1;
    break;
  }
  fclose(fFile);
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<litLatencyMes>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rsi
  lea    D23(%rip),%rdi
  call   <fopen@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L22
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <feof@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L24
  mov    $0x0,%ebp
L44:
  mov    %rbx,%rdi
  call   <fclose@plt>
L22:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %ebp,%eax
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %rsp,%r13
  mov    %rbx,%rdx
  mov    $0x12d,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  lea    D7(%rip),%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L44
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L44
  movb   $0x0,(%rax)
  lea    D7(%rip),%rdi
  call   <strlen@plt>
  cltq
  lea    0x0(%r13,%rax,1),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <atof@plt>
  movss  %xmm0,(%r12)
  mov    $0x1,%ebp
  jmp    L44
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D38
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D38: r

tool: D23: /tmp/wrekames.tmp

tool: D7: time=

assistant: ```c
int litLatencyMes(float *fLatency) {
  FILE *fFile;
  char ligne[300 + 1];
  char *pos, *pos2;
  int ok = 0;
  fFile = fopen("/tmp/wrekames.tmp", "r");
  if (!fFile) {
    return 0;
  }
  while (!feof(fFile)) {
    fgets(ligne, sizeof(ligne), fFile);
    pos = strstr(ligne, "time=");
    if (!pos)
      break;
    pos2 = strrchr(pos, ' ');
    if (!pos2)
      break;
    pos2[0] = '\0';
    strcpy(ligne, pos + strlen("time="));
    *fLatency = atof(ligne);
    ok = 1;
    break;
  }
  fclose(fFile);
  return ok;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<litLatencyMes>:
  endbr64
  push   %r14
  lea    D23(%rip),%rsi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L7
L32:
  xor    %r12d,%r12d
L48:
  mov    %rbp,%rdi
  call   <fclose@plt>
L12:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x140,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rsp,%r13
  mov    %rbp,%rdx
  mov    $0x12d,%esi
  mov    %r13,%rdi
  lea    D20(%rip),%r14
  call   <fgets@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L32
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L32
  movb   $0x0,(%rax)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  cltq
  lea    (%r12,%rax,1),%rsi
  mov    $0x1,%r12d
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <atof@plt>
  movss  %xmm0,(%rbx)
  jmp    L48
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string

tool: D23: r

tool: D0: /tmp/wrekames.tmp

tool: D20: time=

assistant: ```c
int litLatencyMes(float *fLatency) {
  FILE *fFile;
  char ligne[300 + 1];
  char *pos, *pos2;
  int ok = 0;
  fFile = fopen("/tmp/wrekames.tmp", "r");
  if (!fFile) {
    return 0;
  }
  while (!feof(fFile)) {
    fgets(ligne, sizeof(ligne), fFile);
    pos = strstr(ligne, "time=");
    if (!pos)
      break;
    pos2 = strrchr(pos, ' ');
    if (!pos2)
      break;
    pos2[0] = '\0';
    strcpy(ligne, pos + strlen("time="));
    *fLatency = atof(ligne);
    ok = 1;
    break;
  }
  fclose(fFile);
  return ok;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<litLatencyMes>:
  endbr64
  push   %r14
  lea    D18(%rip),%rsi
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <feof@plt>
  test   %eax,%eax
  je     L25
L2:
  xor    %r12d,%r12d
L38:
  mov    %rbp,%rdi
  call   <fclose@plt>
L17:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x140,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rsp,%r13
  mov    %rbp,%rdx
  mov    $0x12d,%esi
  mov    %r13,%rdi
  lea    D6(%rip),%r14
  call   <fgets@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  cltq
  lea    (%r12,%rax,1),%rsi
  mov    $0x1,%r12d
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <atof@plt>
  movss  %xmm0,(%rbx)
  jmp    L38
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D18: r

tool: D9: /tmp/wrekames.tmp

tool: D6: time=

assistant: ```c
int litLatencyMes(float *fLatency) {
  FILE *fFile;
  char ligne[300 + 1];
  char *pos, *pos2;
  int ok = 0;
  fFile = fopen("/tmp/wrekames.tmp", "r");
  if (!fFile) {
    return 0;
  }
  while (!feof(fFile)) {
    fgets(ligne, sizeof(ligne), fFile);
    pos = strstr(ligne, "time=");
    if (!pos)
      break;
    pos2 = strrchr(pos, ' ');
    if (!pos2)
      break;
    pos2[0] = '\0';
    strcpy(ligne, pos + strlen("time="));
    *fLatency = atof(ligne);
    ok = 1;
    break;
  }
  fclose(fFile);
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcCRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L19:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <CRCupdate@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L8:
  cmpl   $0xff,-0x8(%rbp)
  jle    L19
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <CRCupdate@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <CRCupdate@plt>
  mov    -0x4(%rbp),%eax
  not    %eax
  movzwl %ax,%eax
  leave
  ret
```

assistant: ```c
unsigned int calcCRC(unsigned char *buffer) {
  int j;
  unsigned int CRC;
  CRC = 0xFFFF;
  for (j = 0; j < 256; j++)
    CRC = CRCupdate(CRC, buffer[j]);
  CRCupdate(CRC, 0);
  CRCupdate(CRC, 0);
  return ((~CRC) & 0xffff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calcCRC>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    0x100(%rdi),%r12
  mov    $0xffff,%ebx
L7:
  movzbl 0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <CRCupdate@plt>
  mov    %eax,%ebx
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L7
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <CRCupdate@plt>
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <CRCupdate@plt>
  not    %ebx
  movzwl %bx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int calcCRC(unsigned char *buffer) {
  int j;
  unsigned int CRC;
  CRC = 0xFFFF;
  for (j = 0; j < 256; j++)
    CRC = CRCupdate(CRC, buffer[j]);
  CRCupdate(CRC, 0);
  CRCupdate(CRC, 0);
  return ((~CRC) & 0xffff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calcCRC>:
  endbr64
  push   %rbp
  lea    0x100(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xffff,%edi
  sub    $0x18,%rsp
  nopl   0x0(%rax)
L3:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  call   <CRCupdate@plt>
  mov    %eax,%edi
  cmp    %rbp,%rbx
  jne    L3
  xor    %esi,%esi
  mov    %eax,0xc(%rsp)
  call   <CRCupdate@plt>
  mov    0xc(%rsp),%edi
  xor    %esi,%esi
  call   <CRCupdate@plt>
  mov    0xc(%rsp),%edi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  not    %edi
  movzwl %di,%eax
  ret
```

assistant: ```c
unsigned int calcCRC(unsigned char *buffer) {
  int j;
  unsigned int CRC;
  CRC = 0xFFFF;
  for (j = 0; j < 256; j++)
    CRC = CRCupdate(CRC, buffer[j]);
  CRCupdate(CRC, 0);
  CRCupdate(CRC, 0);
  return ((~CRC) & 0xffff);
}
```