ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x8(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x5,-0x8(%rbp)
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D45
data_type: string
name: parse_data
arguments: data_label: D33
data_type: string

tool: D45: n=%d, x=%d


tool: D33: Press any key to end...

assistant: ```c
main() {
  int n, x;
  n = 5;
  x = n++;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = ++n;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = n--;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = --n;
  printf("n=%d, x=%d\n", n, x);
  printf("Press any key to end...");
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%edx
  mov    $0x6,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string

tool: D4: n=%d, x=%d


tool: D15: Press any key to end...

assistant: ```c
main() {
  int n, x;
  n = 5;
  x = n++;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = ++n;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = n--;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = --n;
  printf("n=%d, x=%d\n", n, x);
  printf("Press any key to end...");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D16: n=%d, x=%d


tool: D5: Press any key to end...

assistant: ```c
main() {
  int n, x;
  n = 5;
  x = n++;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = ++n;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = n--;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = --n;
  printf("n=%d, x=%d\n", n, x);
  printf("Press any key to end...");
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x6,%edx
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    $0x4,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string

tool: D3: n=%d, x=%d


tool: D14: Press any key to end...

assistant: ```c
main() {
  int n, x;
  n = 5;
  x = n++;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = ++n;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = n--;
  printf("n=%d, x=%d\n", n, x);
  n = 5;
  x = --n;
  printf("n=%d, x=%d\n", n, x);
  printf("Press any key to end...");
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <execve@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type_guessed: string

tool: D11: /bin/sh

assistant: ```c
int main() {
  char *cmd[] = {"/bin/sh", (char *)0};
  execve("/bin/sh", cmd, NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <execve@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: /bin/sh

assistant: ```c
int main() {
  char *cmd[] = {"/bin/sh", (char *)0};
  execve("/bin/sh", cmd, NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <execve@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: /bin/sh

assistant: ```c
int main() {
  char *cmd[] = {"/bin/sh", (char *)0};
  execve("/bin/sh", cmd, NULL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D5(%rip),%rdi
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    %rdi,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <execve@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: /bin/sh

assistant: ```c
int main() {
  char *cmd[] = {"/bin/sh", (char *)0};
  execve("/bin/sh", cmd, NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strftime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L27
L13:
  cmpq   $0x0,-0x18(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  jmp    L6
L9:
  lea    D5(%rip),%rax
L6:
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x3e8,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L55
  lea    D6(%rip),%rax
  jmp    L27
L55:
  mov    $0x0,%eax
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %A %B %d %I:%M:%S %p %Y %Z

assistant: ```c
char *my_strftime(const char *format, struct tm *tmp) {
  static char buf[1000];
  size_t s;
  if (tmp == NULL) {
    return NULL;
  }
  s = strftime(buf, 1000, (format != NULL) ? format : "%A %B %d %I:%M:%S %p %Y %Z", tmp);
  return (s == 0) ? NULL : buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_strftime>:
  endbr64
  mov    %rsi,%rcx
  test   %rsi,%rsi
  je     L5
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  test   %rdi,%rdi
  lea    D21(%rip),%rax
  cmove  %rax,%rdx
  mov    $0x3e8,%esi
  lea    D7(%rip),%rdi
  call   <strftime@plt>
  test   %rax,%rax
  lea    D7(%rip),%rcx
  mov    $0x0,%eax
  cmovne %rcx,%rax
  add    $0x8,%rsp
  ret
L5:
  mov    %rsi,%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
datatype: string

tool: D21: %A %B %d %I:%M:%S %p %Y %Z

assistant: ```c
char *my_strftime(const char *format, struct tm *tmp) {
  static char buf[1000];
  size_t s;
  if (tmp == NULL) {
    return NULL;
  }
  s = strftime(buf, 1000, (format != NULL) ? format : "%A %B %d %I:%M:%S %p %Y %Z", tmp);
  return (s == 0) ? NULL : buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strftime>:
  endbr64
  test   %rsi,%rsi
  je     L3
  test   %rdi,%rdi
  push   %rbx
  mov    %rdi,%rdx
  lea    D8(%rip),%rax
  lea    D14(%rip),%rbx
  cmove  %rax,%rdx
  mov    %rsi,%rcx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L5
  pop    %rbx
  ret
  nop
L5:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: %A %B %d %I:%M:%S %p %Y %Z

assistant: ```c
char *my_strftime(const char *format, struct tm *tmp) {
  static char buf[1000];
  size_t s;
  if (tmp == NULL) {
    return NULL;
  }
  s = strftime(buf, 1000, (format != NULL) ? format : "%A %B %d %I:%M:%S %p %Y %Z", tmp);
  return (s == 0) ? NULL : buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_strftime>:
  endbr64
  test   %rsi,%rsi
  je     L9
  test   %rdi,%rdi
  push   %rbx
  mov    %rdi,%rdx
  lea    D10(%rip),%rax
  lea    D12(%rip),%rbx
  cmove  %rax,%rdx
  mov    %rsi,%rcx
  mov    $0x3e8,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L8
  pop    %rbx
  ret
  nop
L8:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D10: %A %B %d %I:%M:%S %p %Y %Z

assistant: ```c
char *my_strftime(const char *format, struct tm *tmp) {
  static char buf[1000];
  size_t s;
  if (tmp == NULL) {
    return NULL;
  }
  s = strftime(buf, 1000, (format != NULL) ? format : "%A %B %d %I:%M:%S %p %Y %Z", tmp);
  return (s == 0) ? NULL : buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Copy_Frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x40(%rbp)
  je     L19
  movl   $0x2,-0x4(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jne    L37
  mov    -0x34(%rbp),%eax
  add    %eax,-0xc(%rbp)
  jmp    L37
L19:
  movl   $0x1,-0x4(%rbp)
L37:
  movl   $0x0,-0x14(%rbp)
  jmp    L35
L8:
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L45:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L45
  mov    -0x34(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x14(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Copy_Frame(src, dst, width, height, parity, field_mode) unsigned char *src;
unsigned char *dst;
int width;
int height;
int parity;
int field_mode;
{
  int row, col;
  int s, d;
  int incr;
  s = d = 0;
  if (field_mode) {
    incr = 2;
    if (parity == 0)
      s += width;
  } else {
    incr = 1;
  }
  for (row = 0; row < height; row += incr) {
    for (col = 0; col < width; col++) {
      dst[d + col] = src[s + col];
    }
    d += (width * incr);
    s += (width * incr);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Copy_Frame>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rax
  mov    %edx,%r11d
  mov    %ecx,%ebx
  mov    $0x1,%ebp
  test   %r9d,%r9d
  je     L7
  test   %r8d,%r8d
  mov    $0x0,%r9d
  cmove  %edx,%r9d
  mov    $0x2,%ebp
L7:
  test   %ebx,%ebx
  jle    L69
  mov    %ebp,%r10d
  imul   %r11d,%r10d
  movslq %r10d,%r10
  movslq %r9d,%r9
  lea    (%rdi,%r9,1),%rsi
  mov    %rax,%rcx
  mov    $0x0,%r8d
  mov    %r11d,%edi
  jmp    L65
L59:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L59
L20:
  add    %ebp,%r8d
  add    %r10,%rsi
  add    %r10,%rcx
  cmp    %r8d,%ebx
  jle    L69
L65:
  mov    $0x0,%eax
  test   %r11d,%r11d
  jg     L59
  jmp    L20
L69:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Copy_Frame(src, dst, width, height, parity, field_mode) unsigned char *src;
unsigned char *dst;
int width;
int height;
int parity;
int field_mode;
{
  int row, col;
  int s, d;
  int incr;
  s = d = 0;
  if (field_mode) {
    incr = 2;
    if (parity == 0)
      s += width;
  } else {
    incr = 1;
  }
  for (row = 0; row < height; row += incr) {
    for (col = 0; col < width; col++) {
      dst[d + col] = src[s + col];
    }
    d += (width * incr);
    s += (width * incr);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Copy_Frame>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %edx,%r11d
  mov    $0x1,%ebp
  push   %rbx
  mov    %ecx,%ebx
  test   %r9d,%r9d
  je     L48
  xor    %r9d,%r9d
  test   %r8d,%r8d
  mov    $0x2,%ebp
  cmove  %edx,%r9d
L48:
  test   %ebx,%ebx
  jle    L5
  mov    %ebp,%r10d
  movslq %r9d,%r9
  mov    %rax,%rcx
  xor    %r8d,%r8d
  imul   %r11d,%r10d
  lea    (%rdi,%r9,1),%rsi
  lea    -0x1(%r11),%edi
  movslq %r10d,%r10
  cs nopw 0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  test   %r11d,%r11d
  jle    L18
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L8
L18:
  add    %ebp,%r8d
  add    %r10,%rsi
  add    %r10,%rcx
  cmp    %r8d,%ebx
  jg     L22
L5:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Copy_Frame(src, dst, width, height, parity, field_mode) unsigned char *src;
unsigned char *dst;
int width;
int height;
int parity;
int field_mode;
{
  int row, col;
  int s, d;
  int incr;
  s = d = 0;
  if (field_mode) {
    incr = 2;
    if (parity == 0)
      s += width;
  } else {
    incr = 1;
  }
  for (row = 0; row < height; row += incr) {
    for (col = 0; col < width; col++) {
      dst[d + col] = src[s + col];
    }
    d += (width * incr);
    s += (width * incr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rfft1pt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movss  0x4(%rax),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x10(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rfft1pt(float *ioptr) {
  float f0r, f0i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rfft1pt>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  movaps %xmm0,%xmm2
  addss  %xmm1,%xmm2
  movss  %xmm2,(%rdi)
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  ret
```

assistant: ```c
void rfft1pt(float *ioptr) {
  float f0r, f0i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rfft1pt>:
  endbr64
  movss  (%rdi),%xmm0
  movss  0x4(%rdi),%xmm1
  movaps %xmm0,%xmm2
  subss  %xmm1,%xmm0
  addss  %xmm1,%xmm2
  movss  %xmm0,0x4(%rdi)
  movss  %xmm2,(%rdi)
  ret
```

assistant: ```c
void rfft1pt(float *ioptr) {
  float f0r, f0i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rfft1pt>:
  endbr64
  movq   (%rdi),%xmm1
  movaps %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  shufps $0xe0,%xmm0,%xmm0
  movaps %xmm0,%xmm2
  subps  %xmm1,%xmm0
  addps  %xmm1,%xmm2
  movss  %xmm2,%xmm0
  movlps %xmm0,(%rdi)
  ret
```

assistant: ```c
void rfft1pt(float *ioptr) {
  float f0r, f0i;
  float t0r, t0i;
  f0r = ioptr[0];
  f0i = ioptr[1];
  t0r = f0r + f0i;
  t0i = f0r - f0i;
  ioptr[0] = t0r;
  ioptr[1] = t0i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SkipLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  jmp    L16
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x4(%rbp)
L16:
  cmpb   $0xa,-0x4(%rbp)
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void SkipLine(char c) {
  while (c != '\n')
    c = getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SkipLine>:
  endbr64
  cmp    $0xa,%dil
  je     L6
  sub    $0x8,%rsp
L16:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L16
  add    $0x8,%rsp
  ret
L6:
  ret
```

assistant: ```c
void SkipLine(char c) {
  while (c != '\n')
    c = getchar();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SkipLine>:
  endbr64
  cmp    $0xa,%dil
  je     L1
  sub    $0x8,%rsp
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  add    $0x8,%rsp
  ret
L1:
  ret
```

assistant: ```c
void SkipLine(char c) {
  while (c != '\n')
    c = getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SkipLine>:
  endbr64
  cmp    $0xa,%dil
  je     L11
  sub    $0x8,%rsp
  xchg   %ax,%ax
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L15
  add    $0x8,%rsp
  ret
L11:
  ret
```

assistant: ```c
void SkipLine(char c) {
  while (c != '\n')
    c = getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<atoi_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L78
L49:
  addl   $0x1,-0xc(%rbp)
L78:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L59
  mov    $0xffffffff,%eax
  jmp    L28
L59:
  mov    $0x1,%eax
L28:
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L56
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L74
L56:
  addl   $0x1,-0xc(%rbp)
L74:
  movl   $0x0,-0x8(%rbp)
  jmp    L43
L51:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int atoi_2(char s[]) {
  int i = 0;
  int n = 0;
  int sign = 0;
  for (i = 0; isspace(s[i]); ++i)
    ;
  sign = (s[i] == '-') ? (-1) : 1;
  if (s[i] == '+' || s[i] == '-')
    ++i;
  for (n = 0; isdigit(s[i]); ++i)
    n = n * 10 + (s[i] - '0');
  return sign * n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoi_2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L7
L43:
  add    $0x1,%ebp
L7:
  mov    %rbx,%r12
  movsbl (%rbx),%edi
  call   <isspace@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L43
  movzbl (%r12),%eax
  cmp    $0x2d,%al
  je     L34
  sub    $0x2b,%eax
  mov    $0x1,%r12d
  test   $0xfd,%al
  je     L49
L51:
  movslq %ebp,%rbx
  add    %r13,%rbx
  mov    $0x0,%ebp
  jmp    L19
L34:
  mov    $0xffffffff,%r12d
L49:
  add    $0x1,%ebp
  jmp    L51
L47:
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
L19:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L47
  mov    %ebp,%eax
  imul   %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int atoi_2(char s[]) {
  int i = 0;
  int n = 0;
  int sign = 0;
  for (i = 0; isspace(s[i]); ++i)
    ;
  sign = (s[i] == '-') ? (-1) : 1;
  if (s[i] == '+' || s[i] == '-')
    ++i;
  for (n = 0; isdigit(s[i]); ++i)
    n = n * 10 + (s[i] - '0');
  return sign * n;
}
```