ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__detect_PLATFORM_ENV_OS_VER_DETAIL>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <uname@plt>
  test   %rax,%rax
  js     L2
  mov    0x8(%rsp),%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%r8
  lea    D22(%rip),%rsi
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <sscanf@plt>
  test   %rax,%rax
  jle    L2
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  lea    D17(%rip),%rdi
  shl    $0x8,%eax
  shl    $0x10,%esi
  or     %eax,%esi
  xor    %eax,%eax
  or     0x14(%rsp),%esi
  call   <printf@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L2:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D13
type: string

tool: D22: %d.%d.%d

tool: D17: 0x%x

tool: D13: TT_ENV_OS_VER_UNKNOWN

assistant: ```c
int __detect_PLATFORM_ENV_OS_VER_DETAIL() {
  struct utsname name;
  int v, v1, v2, v3;
  if (uname(&name) < 0) {
    printf("TT_ENV_OS_VER_UNKNOWN");
    return 0;
  }
  v1 = v2 = v3 = 0;
  if (sscanf(name.release, "%d.%d.%d", &v1, &v2, &v3) <= 0) {
    printf("TT_ENV_OS_VER_UNKNOWN");
    return 0;
  }
  v = (v1) << 16 | (v2) << 8 | (v3);
  printf("0x%x", v);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__detect_PLATFORM_ENV_OS_VER_DETAIL>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <uname@plt>
  test   %rax,%rax
  js     L21
  mov    0x8(%rsp),%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  movl   $0x0,0x14(%rsp)
  lea    0x14(%rsp),%r8
  lea    D4(%rip),%rsi
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  call   <sscanf@plt>
  test   %rax,%rax
  jle    L21
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%eax
  lea    D26(%rip),%rdi
  shl    $0x8,%eax
  shl    $0x10,%esi
  or     %eax,%esi
  xor    %eax,%eax
  or     0x14(%rsp),%esi
  call   <printf@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L21:
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L22
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D25
type: string

tool: D4: %d.%d.%d

tool: D26: 0x%x

tool: D25: TT_ENV_OS_VER_UNKNOWN

assistant: ```c
int __detect_PLATFORM_ENV_OS_VER_DETAIL() {
  struct utsname name;
  int v, v1, v2, v3;
  if (uname(&name) < 0) {
    printf("TT_ENV_OS_VER_UNKNOWN");
    return 0;
  }
  v1 = v2 = v3 = 0;
  if (sscanf(name.release, "%d.%d.%d", &v1, &v2, &v3) <= 0) {
    printf("TT_ENV_OS_VER_UNKNOWN");
    return 0;
  }
  v = (v1) << 16 | (v2) << 8 | (v3);
  printf("0x%x", v);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<all_bat_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_bat_comments@plt>
  mov    $0x0,%eax
  call   <test_bat_comment_entities@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void all_bat_tests() {
  test_bat_comments();
  test_bat_comment_entities();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<all_bat_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_bat_comments@plt>
  mov    $0x0,%eax
  call   <test_bat_comment_entities@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void all_bat_tests() {
  test_bat_comments();
  test_bat_comment_entities();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<all_bat_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_bat_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <test_bat_comment_entities@plt>
```

assistant: ```c
void all_bat_tests() {
  test_bat_comments();
  test_bat_comment_entities();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<all_bat_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_bat_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <test_bat_comment_entities@plt>
```

assistant: ```c
void all_bat_tests() {
  test_bat_comments();
  test_bat_comment_entities();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x6c(%rbp)
  jmp    L71
L28:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    -0x6c(%rbp),%eax
  cltq
  mov    %edx,-0x60(%rbp,%rax,4)
  addl   $0x1,-0x6c(%rbp)
L71:
  cmpl   $0x13,-0x6c(%rbp)
  jle    L28
  movl   $0x14,-0x64(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L98
L18:
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x68(%rbp)
  jne    L29
  lea    D22(%rip),%rax
  jmp    L2
L29:
  lea    D54(%rip),%rax
L2:
  mov    -0x68(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x60(%rbp,%rdx,4),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L98:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L18
  mov    -0x64(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L14
L12:
  mov    -0x64(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x68(%rbp)
  jne    L8
  lea    D22(%rip),%rax
  jmp    L87
L8:
  lea    D54(%rip),%rax
L87:
  mov    -0x68(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x60(%rbp,%rdx,4),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x68(%rbp)
L14:
  mov    -0x68(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D54
type: string
name: unpack_data
arguments: tag: D79
type: string
name: unpack_data
arguments: tag: D5
type: string

tool: D19: The pre-sorted numbers are...

tool: D22: 


tool: D54:  

tool: D79: %d%s

tool: D5: The post-sorted numbers are...

assistant: ```c
int main() {
  int a[20];
  for (int i = 1; i < 20; ++i) {
    a[i] = rand() % 1000 + 1;
  }
  int n = sizeof a / sizeof a[0];
  int i;
  printf("The pre-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  bubble_sort(a, n);
  printf("The post-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x50(%rsp),%rbp
L23:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L23
  lea    D82(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D79(%rip),%r12
  lea    D43(%rip),%rbp
L38:
  mov    -0x4(%rsp,%rbx,4),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L38
  cltq
  mov    (%rsp,%rax,4),%esi
  lea    D42(%rip),%rdx
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  mov    $0x14,%esi
  call   <bubble_sort@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D79(%rip),%r12
  lea    D43(%rip),%rbp
L24:
  mov    -0x4(%rsp,%rbx,4),%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L24
  cltq
  mov    (%rsp,%rax,4),%esi
  lea    D42(%rip),%rdx
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D82
data_type: string
name: disassemble_data
arguments: data_label: D79
data_type: string
name: disassemble_data
arguments: data_label: D43
data_type: string
name: disassemble_data
arguments: data_label: D42
data_type: string
name: disassemble_data
arguments: data_label: D51
data_type: string

tool: D82: The pre-sorted numbers are...

tool: D79:  

tool: D43: %d%s

tool: D42: 


tool: D51: The post-sorted numbers are...

assistant: ```c
int main() {
  int a[20];
  for (int i = 1; i < 20; ++i) {
    a[i] = rand() % 1000 + 1;
  }
  int n = sizeof a / sizeof a[0];
  int i;
  printf("The pre-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  bubble_sort(a, n);
  printf("The post-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x50(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L4
  lea    D12(%rip),%rdi
  mov    $0x1,%ebx
  mov    %rsp,%r12
  call   <puts@plt>
  lea    D45(%rip),%r13
  lea    D32(%rip),%rbp
  nopl   (%rax)
L25:
  mov    -0x4(%r12,%rbx,4),%esi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L25
  mov    (%rsp,%rax,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D30(%rip),%r14
  mov    %r14,%rdx
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <bubble_sort@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L27:
  mov    -0x4(%r12,%rbx,4),%esi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L27
  mov    (%rsp,%rax,4),%esi
  mov    %r14,%rdx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D45
datatype: string
name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D30
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D12: The pre-sorted numbers are...

tool: D45:  

tool: D32: %d%s

tool: D30: 


tool: D3: The post-sorted numbers are...

assistant: ```c
int main() {
  int a[20];
  for (int i = 1; i < 20; ++i) {
    a[i] = rand() % 1000 + 1;
  }
  int n = sizeof a / sizeof a[0];
  int i;
  printf("The pre-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  bubble_sort(a, n);
  printf("The post-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    0x50(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L3
  lea    D32(%rip),%rdi
  mov    $0x1,%ebx
  mov    %rsp,%r12
  call   <puts@plt>
  lea    D24(%rip),%r13
  lea    D38(%rip),%rbp
  nopl   (%rax)
L2:
  mov    -0x4(%r12,%rbx,4),%esi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L2
  mov    (%rsp,%rax,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D30(%rip),%r14
  mov    %r14,%rdx
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  call   <bubble_sort@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L39:
  mov    -0x4(%r12,%rbx,4),%esi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq %ebx,%rax
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L39
  mov    (%rsp,%rax,4),%esi
  mov    %r14,%rdx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D32
type_infered: string
name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D37
type_infered: string

tool: D32: The pre-sorted numbers are...

tool: D24:  

tool: D38: %d%s

tool: D30: 


tool: D37: The post-sorted numbers are...

assistant: ```c
int main() {
  int a[20];
  for (int i = 1; i < 20; ++i) {
    a[i] = rand() % 1000 + 1;
  }
  int n = sizeof a / sizeof a[0];
  int i;
  printf("The pre-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  bubble_sort(a, n);
  printf("The post-sorted numbers are...\n");
  for (i = 0; i < n; i++) {
    printf("%d%s", a[i], i == n - 1 ? "\n" : " ");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <new_sequence@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L40
L19:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <slist_insert@plt>
  cmp    $0xffffffff,%eax
  jne    L15
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  addl   $0x1,-0x24(%rbp)
L40:
  cmpl   $0x63,-0x24(%rbp)
  jle    L19
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <slist_length@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x64,-0x18(%rbp)
  je     L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <print_list@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <slist_destroy@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <destroy_seq@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D3
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D14
type: string

tool: D16: [!] failed to insert %d


tool: D3: [!] expected a length of 100, actual is %lu


tool: D8: [+] list length matches expected value

tool: D14: [+] insert complete

assistant: ```c
void test_insert(void) {
  size_t length = 0;
  int **seq = new_sequence(0, 100);
  int i;
  struct slist_node *head = NULL;
  for (i = 0; i < 100; i++) {
    if (-1 == slist_insert(&head, seq[i], sizeof(int))) {
      printf("[!] failed to insert %d\n", *seq[i]);
    }
  }
  length = slist_length(head);
  if (length != 100) {
    printf("[!] expected a length of 100, actual is %lu\n", (long unsigned)length);
  }
  printf("[+] list length matches expected value\n");
  print_list(head);
  slist_destroy(&head);
  destroy_seq(seq, 100);
  printf("[+] insert complete\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_insert>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <new_sequence@plt>
  mov    %rax,%r13
  movq   $0x0,(%rsp)
  mov    %rax,%rbx
  lea    0x320(%rax),%rbp
  lea    D3(%rip),%r12
  jmp    L23
L37:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L60
L23:
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    (%rbx),%rsi
  call   <slist_insert@plt>
  cmp    $0xffffffff,%eax
  jne    L37
  mov    (%rbx),%rax
  mov    (%rax),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L60:
  mov    (%rsp),%rdi
  call   <slist_length@plt>
  cmp    $0x64,%rax
  jne    L40
L15:
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rdi
  call   <print_list@plt>
  mov    %rsp,%rdi
  call   <slist_destroy@plt>
  mov    $0x64,%esi
  mov    %r13,%rdi
  call   <destroy_seq@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  mov    %rax,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D37
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D3: [!] failed to insert %d


tool: D37: [+] list length matches expected value

tool: D19: [+] insert complete

tool: D13: [!] expected a length of 100, actual is %lu


assistant: ```c
void test_insert(void) {
  size_t length = 0;
  int **seq = new_sequence(0, 100);
  int i;
  struct slist_node *head = NULL;
  for (i = 0; i < 100; i++) {
    if (-1 == slist_insert(&head, seq[i], sizeof(int))) {
      printf("[!] failed to insert %d\n", *seq[i]);
    }
  }
  length = slist_length(head);
  if (length != 100) {
    printf("[!] expected a length of 100, actual is %lu\n", (long unsigned)length);
  }
  printf("[+] list length matches expected value\n");
  print_list(head);
  slist_destroy(&head);
  destroy_seq(seq, 100);
  printf("[+] insert complete\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_insert>:
  endbr64
  push   %r14
  mov    $0x64,%esi
  xor    %edi,%edi
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <new_sequence@plt>
  movq   $0x0,(%rsp)
  mov    %rax,%r14
  mov    %rax,%rbx
  lea    0x320(%rax),%r12
  jmp    L33
  nopl   (%rax)
L37:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L41
L33:
  mov    (%rbx),%rsi
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <slist_insert@plt>
  cmp    $0xffffffff,%eax
  jne    L37
  mov    (%rbx),%rax
  mov    %r13,%rdi
  add    $0x8,%rbx
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L33
L41:
  mov    (%rsp),%rdi
  call   <slist_length@plt>
  mov    %rax,%rsi
  cmp    $0x64,%rax
  je     L14
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    (%rsp),%rdi
  call   <print_list@plt>
  mov    %rbp,%rdi
  call   <slist_destroy@plt>
  mov    %r14,%rdi
  mov    $0x64,%esi
  call   <destroy_seq@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D9
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string

tool: D10: [!] failed to insert %d


tool: D9: [!] expected a length of 100, actual is %lu


tool: D18: [+] list length matches expected value

tool: D19: [+] insert complete

assistant: ```c
void test_insert(void) {
  size_t length = 0;
  int **seq = new_sequence(0, 100);
  int i;
  struct slist_node *head = NULL;
  for (i = 0; i < 100; i++) {
    if (-1 == slist_insert(&head, seq[i], sizeof(int))) {
      printf("[!] failed to insert %d\n", *seq[i]);
    }
  }
  length = slist_length(head);
  if (length != 100) {
    printf("[!] expected a length of 100, actual is %lu\n", (long unsigned)length);
  }
  printf("[+] list length matches expected value\n");
  print_list(head);
  slist_destroy(&head);
  destroy_seq(seq, 100);
  printf("[+] insert complete\n");
}
```