ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <fmod@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: fmod(2, 7) = [%lf]


assistant: ```c
int main() {
  printf("fmod(2, 7) = [%lf]\n", fmod(2, 7));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zf_readw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    $0x218,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x21a,%edi
  call   <inw@plt>
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned short zf_readw(unsigned char port) {
  unsigned short tmp;
  {
    outb(port, 536U);
    tmp = inw(538U);
    return (tmp);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zf_readw>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  mov    $0x218,%esi
  call   <outb@plt>
  mov    $0x21a,%edi
  call   <inw@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned short zf_readw(unsigned char port) {
  unsigned short tmp;
  {
    outb(port, 536U);
    tmp = inw(538U);
    return (tmp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zf_readw>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  mov    $0x218,%esi
  call   <outb@plt>
  mov    $0x21a,%edi
  add    $0x8,%rsp
  jmp    1060 <inw@plt>
```

assistant: ```c
unsigned short zf_readw(unsigned char port) {
  unsigned short tmp;
  {
    outb(port, 536U);
    tmp = inw(538U);
    return (tmp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zf_readw>:
  endbr64
  sub    $0x8,%rsp
  movzbl %dil,%edi
  mov    $0x218,%esi
  call   <outb@plt>
  mov    $0x21a,%edi
  add    $0x8,%rsp
  jmp    1060 <inw@plt>
```

assistant: ```c
unsigned short zf_readw(unsigned char port) {
  unsigned short tmp;
  {
    outb(port, 536U);
    tmp = inw(538U);
    return (tmp);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x6,%edi
  call   <sortuj@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L7
L12:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L7:
  cmpl   $0x2,-0x18(%rbp)
  jle    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string

tool: D1: %d 

assistant: ```c
int main(void) {
  int tablica[3], i;
  sortuj(6, 3, 4, tablica);
  for (i = 0; i < 3; i++) {
    printf("%d ", tablica[i]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x6,%edi
  call   <sortuj@plt>
  mov    0xc(%rsp),%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
int main(void) {
  int tablica[3], i;
  sortuj(6, 3, 4, tablica);
  for (i = 0; i < 3; i++) {
    printf("%d ", tablica[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x6,%edi
  lea    D9(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  call   <sortuj@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %d 

assistant: ```c
int main(void) {
  int tablica[3], i;
  sortuj(6, 3, 4, tablica);
  for (i = 0; i < 3; i++) {
    printf("%d ", tablica[i]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    $0x6,%edi
  lea    D7(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  call   <sortuj@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string

tool: D7: %d 

assistant: ```c
int main(void) {
  int tablica[3], i;
  sortuj(6, 3, 4, tablica);
  for (i = 0; i < 3; i++) {
    printf("%d ", tablica[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  movl   $0xedb88320,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  shr    %eax
  mov    %eax,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x6,%eax
  xor    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  shr    $0x6,%eax
  xor    -0x28(%rbp),%eax
  shr    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  jmp    L11
L13:
  mov    -0x40(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  shl    $0x1f,%eax
  sar    $0x1f,%eax
  and    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x1e,%eax
  sar    $0x1f,%eax
  and    -0x10(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x1d,%eax
  sar    $0x1f,%eax
  and    -0x14(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x1c,%eax
  sar    $0x1f,%eax
  and    -0x18(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x1b,%eax
  sar    $0x1f,%eax
  and    -0x1c(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x1a,%eax
  sar    $0x1f,%eax
  and    -0x20(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x19,%eax
  sar    $0x1f,%eax
  and    -0x24(%rbp),%eax
  xor    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x18,%eax
  sar    $0x1f,%eax
  and    -0x28(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x2c(%rbp),%eax
  shr    $0x8,%eax
  xor    -0x4(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L11:
  mov    -0x38(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  test   %eax,%eax
  jne    L13
  mov    -0x2c(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int crc32(unsigned int start, unsigned char *data, unsigned int count) {
  int crc;
  unsigned int byte, c;
  const unsigned int g0 = 0xEDB88320, g1 = g0 >> 1, g2 = g0 >> 2, g3 = g0 >> 3, g4 = g0 >> 4, g5 = g0 >> 5, g6 = (g0 >> 6) ^ g0, g7 = ((g0 >> 6) ^ g0) >> 1;
  crc = start;
  while (count--) {
    byte = *data++;
    crc = crc ^ byte;
    c = ((crc << 31 >> 31) & g7) ^ ((crc << 30 >> 31) & g6) ^ ((crc << 29 >> 31) & g5) ^ ((crc << 28 >> 31) & g4) ^ ((crc << 27 >> 31) & g3) ^ ((crc << 26 >> 31) & g2) ^ ((crc << 25 >> 31) & g1) ^ ((crc << 24 >> 31) & g0);
    crc = ((unsigned)crc >> 8) ^ c;
  }
  return ~crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crc32>:
  endbr64
  mov    %rsi,%rcx
  mov    %edi,%eax
  lea    -0x1(%rdx),%esi
  test   %edx,%edx
  je     L18
  mov    %esi,%esi
  lea    0x1(%rcx,%rsi,1),%rsi
L8:
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0x1f,%edx
  sar    $0x1f,%edx
  and    $0x77073096,%edx
  mov    %eax,%edi
  shl    $0x1e,%edi
  sar    $0x1f,%edi
  and    $0xee0e612c,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shr    $0x8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1d,%edi
  sar    $0x1f,%edi
  and    $0x76dc419,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1c,%edi
  sar    $0x1f,%edi
  and    $0xedb8832,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1b,%edi
  sar    $0x1f,%edi
  and    $0x1db71064,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1a,%edi
  sar    $0x1f,%edi
  and    $0x3b6e20c8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x19,%edi
  sar    $0x1f,%edi
  and    $0x76dc4190,%edi
  xor    %edi,%edx
  shl    $0x18,%eax
  sar    $0x1f,%eax
  and    $0xedb88320,%eax
  xor    %edx,%eax
  cmp    %rcx,%rsi
  jne    L8
L18:
  not    %eax
  ret
```

assistant: ```c
unsigned int crc32(unsigned int start, unsigned char *data, unsigned int count) {
  int crc;
  unsigned int byte, c;
  const unsigned int g0 = 0xEDB88320, g1 = g0 >> 1, g2 = g0 >> 2, g3 = g0 >> 3, g4 = g0 >> 4, g5 = g0 >> 5, g6 = (g0 >> 6) ^ g0, g7 = ((g0 >> 6) ^ g0) >> 1;
  crc = start;
  while (count--) {
    byte = *data++;
    crc = crc ^ byte;
    c = ((crc << 31 >> 31) & g7) ^ ((crc << 30 >> 31) & g6) ^ ((crc << 29 >> 31) & g5) ^ ((crc << 28 >> 31) & g4) ^ ((crc << 27 >> 31) & g3) ^ ((crc << 26 >> 31) & g2) ^ ((crc << 25 >> 31) & g1) ^ ((crc << 24 >> 31) & g0);
    crc = ((unsigned)crc >> 8) ^ c;
  }
  return ~crc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crc32>:
  endbr64
  mov    %rsi,%rcx
  mov    %edi,%eax
  test   %edx,%edx
  je     L6
  mov    %edx,%edx
  lea    (%rsi,%rdx,1),%rsi
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  xor    %edx,%eax
  mov    %eax,%edx
  mov    %eax,%edi
  shl    $0x1f,%edx
  shl    $0x1e,%edi
  sar    $0x1f,%edx
  sar    $0x1f,%edi
  and    $0xee0e612c,%edi
  and    $0x77073096,%edx
  xor    %edi,%edx
  mov    %eax,%edi
  shr    $0x8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1d,%edi
  sar    $0x1f,%edi
  and    $0x76dc419,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1c,%edi
  sar    $0x1f,%edi
  and    $0xedb8832,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1b,%edi
  sar    $0x1f,%edi
  and    $0x1db71064,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1a,%edi
  sar    $0x1f,%edi
  and    $0x3b6e20c8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x18,%eax
  shl    $0x19,%edi
  sar    $0x1f,%edi
  and    $0x76dc4190,%edi
  xor    %edi,%edx
  sar    $0x1f,%eax
  and    $0xedb88320,%eax
  xor    %edx,%eax
  cmp    %rsi,%rcx
  jne    L8
L6:
  not    %eax
  ret
```

assistant: ```c
unsigned int crc32(unsigned int start, unsigned char *data, unsigned int count) {
  int crc;
  unsigned int byte, c;
  const unsigned int g0 = 0xEDB88320, g1 = g0 >> 1, g2 = g0 >> 2, g3 = g0 >> 3, g4 = g0 >> 4, g5 = g0 >> 5, g6 = (g0 >> 6) ^ g0, g7 = ((g0 >> 6) ^ g0) >> 1;
  crc = start;
  while (count--) {
    byte = *data++;
    crc = crc ^ byte;
    c = ((crc << 31 >> 31) & g7) ^ ((crc << 30 >> 31) & g6) ^ ((crc << 29 >> 31) & g5) ^ ((crc << 28 >> 31) & g4) ^ ((crc << 27 >> 31) & g3) ^ ((crc << 26 >> 31) & g2) ^ ((crc << 25 >> 31) & g1) ^ ((crc << 24 >> 31) & g0);
    crc = ((unsigned)crc >> 8) ^ c;
  }
  return ~crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crc32>:
  endbr64
  mov    %rsi,%rcx
  mov    %edi,%eax
  test   %edx,%edx
  je     L2
  mov    %edx,%edx
  lea    (%rsi,%rdx,1),%rsi
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  xor    %edx,%eax
  mov    %eax,%edx
  mov    %eax,%edi
  shl    $0x1f,%edx
  shl    $0x1e,%edi
  sar    $0x1f,%edx
  sar    $0x1f,%edi
  and    $0xee0e612c,%edi
  and    $0x77073096,%edx
  xor    %edi,%edx
  mov    %eax,%edi
  shr    $0x8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1d,%edi
  sar    $0x1f,%edi
  and    $0x76dc419,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1c,%edi
  sar    $0x1f,%edi
  and    $0xedb8832,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1b,%edi
  sar    $0x1f,%edi
  and    $0x1db71064,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x1a,%edi
  sar    $0x1f,%edi
  and    $0x3b6e20c8,%edi
  xor    %edi,%edx
  mov    %eax,%edi
  shl    $0x18,%eax
  shl    $0x19,%edi
  sar    $0x1f,%edi
  and    $0x76dc4190,%edi
  xor    %edi,%edx
  sar    $0x1f,%eax
  and    $0xedb88320,%eax
  xor    %edx,%eax
  cmp    %rsi,%rcx
  jne    L16
L2:
  not    %eax
  ret
```

assistant: ```c
unsigned int crc32(unsigned int start, unsigned char *data, unsigned int count) {
  int crc;
  unsigned int byte, c;
  const unsigned int g0 = 0xEDB88320, g1 = g0 >> 1, g2 = g0 >> 2, g3 = g0 >> 3, g4 = g0 >> 4, g5 = g0 >> 5, g6 = (g0 >> 6) ^ g0, g7 = ((g0 >> 6) ^ g0) >> 1;
  crc = start;
  while (count--) {
    byte = *data++;
    crc = crc ^ byte;
    c = ((crc << 31 >> 31) & g7) ^ ((crc << 30 >> 31) & g6) ^ ((crc << 29 >> 31) & g5) ^ ((crc << 28 >> 31) & g4) ^ ((crc << 27 >> 31) & g3) ^ ((crc << 26 >> 31) & g2) ^ ((crc << 25 >> 31) & g1) ^ ((crc << 24 >> 31) & g0);
    crc = ((unsigned)crc >> 8) ^ c;
  }
  return ~crc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fons__blurRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L52
L47:
  movl   $0x0,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L20
L32:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  sub    -0x4(%rbp),%eax
  imul   -0x28(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  add    %eax,-0x8(%rbp)
L20:
  mov    -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L32
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x24(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  sub    -0x4(%rbp),%eax
  imul   -0x28(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L4:
  cmpl   $0x0,-0x8(%rbp)
  jns    L44
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fons__blurRows(unsigned char *dst, int w, int h, int dstStride, int alpha) {
  int x, y;
  for (x = 0; x < w; x++) {
    int z = 0;
    for (y = dstStride; y < h * dstStride; y += dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[(h - 1) * dstStride] = 0;
    z = 0;
    for (y = (h - 2) * dstStride; y >= 0; y -= dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[0] = 0;
    dst++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fons__blurRows>:
  endbr64
  test   %esi,%esi
  jle    L55
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebp
  mov    %ecx,%r9d
  imul   %edx,%r9d
  lea    -0x1(%rdx),%r12d
  imul   %ecx,%r12d
  movslq %r12d,%r12
  lea    -0x2(%rdx),%r11d
  imul   %ecx,%r11d
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rbx
  movslq %ecx,%rsi
  mov    %ecx,%r10d
  neg    %r10d
  movslq %r10d,%r10
  jmp    L78
L37:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %rsi,%rdx
  cmp    %edx,%r9d
  jg     L37
L61:
  movb   $0x0,(%rdi,%r12,1)
  test   %r11d,%r11d
  js     L63
  movslq %r11d,%rdx
  mov    $0x0,%ecx
L33:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %r10,%rdx
  test   %edx,%edx
  jns    L33
L63:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rbx,%rdi
  je     L0
L78:
  mov    %rsi,%rdx
  mov    $0x0,%ecx
  cmp    %r9d,%ebp
  jl     L37
  jmp    L61
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  ret
```

assistant: ```c
void fons__blurRows(unsigned char *dst, int w, int h, int dstStride, int alpha) {
  int x, y;
  for (x = 0; x < w; x++) {
    int z = 0;
    for (y = dstStride; y < h * dstStride; y += dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[(h - 1) * dstStride] = 0;
    z = 0;
    for (y = (h - 2) * dstStride; y >= 0; y -= dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[0] = 0;
    dst++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fons__blurRows>:
  endbr64
  movslq %esi,%rax
  test   %eax,%eax
  jle    L24
  lea    -0x1(%rdx),%r11d
  mov    %ecx,%r9d
  mov    %ecx,%r10d
  push   %r12
  imul   %ecx,%r11d
  neg    %r10d
  push   %rbp
  movslq %ecx,%rsi
  imul   %edx,%r9d
  push   %rbx
  mov    %ecx,%ebp
  lea    (%rdi,%rax,1),%rbx
  movslq %r10d,%r10
  movslq %r11d,%r12
  sub    %ecx,%r11d
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  cmp    %r9d,%ebp
  jge    L0
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %rsi,%rdx
  cmp    %edx,%r9d
  jg     L5
L0:
  movb   $0x0,(%rdi,%r12,1)
  movslq %r11d,%rdx
  xor    %ecx,%ecx
  test   %r11d,%r11d
  js     L48
  nopl   0x0(%rax)
L59:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %r10,%rdx
  test   %edx,%edx
  jns    L59
L48:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rbx,%rdi
  jne    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  ret
```

assistant: ```c
void fons__blurRows(unsigned char *dst, int w, int h, int dstStride, int alpha) {
  int x, y;
  for (x = 0; x < w; x++) {
    int z = 0;
    for (y = dstStride; y < h * dstStride; y += dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[(h - 1) * dstStride] = 0;
    z = 0;
    for (y = (h - 2) * dstStride; y >= 0; y -= dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[0] = 0;
    dst++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fons__blurRows>:
  endbr64
  movslq %esi,%rax
  test   %eax,%eax
  jle    L51
  lea    -0x1(%rdx),%r11d
  mov    %ecx,%r9d
  mov    %ecx,%r10d
  push   %r12
  imul   %ecx,%r11d
  neg    %r10d
  push   %rbp
  movslq %ecx,%rsi
  imul   %edx,%r9d
  push   %rbx
  mov    %ecx,%ebp
  lea    (%rdi,%rax,1),%rbx
  movslq %r10d,%r10
  movslq %r11d,%r12
  sub    %ecx,%r11d
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  cmp    %r9d,%ebp
  jge    L12
  nopw   0x0(%rax,%rax,1)
L31:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %rsi,%rdx
  cmp    %edx,%r9d
  jg     L31
L12:
  movb   $0x0,(%rdi,%r12,1)
  movslq %r11d,%rdx
  xor    %ecx,%ecx
  test   %r11d,%r11d
  js     L23
  nopl   0x0(%rax)
L46:
  movzbl (%rdi,%rdx,1),%eax
  shl    $0x7,%eax
  sub    %ecx,%eax
  imul   %r8d,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  mov    %ecx,%eax
  sar    $0x7,%eax
  mov    %al,(%rdi,%rdx,1)
  add    %r10,%rdx
  test   %edx,%edx
  jns    L46
L23:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  cmp    %rbx,%rdi
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  ret
```

assistant: ```c
void fons__blurRows(unsigned char *dst, int w, int h, int dstStride, int alpha) {
  int x, y;
  for (x = 0; x < w; x++) {
    int z = 0;
    for (y = dstStride; y < h * dstStride; y += dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[(h - 1) * dstStride] = 0;
    z = 0;
    for (y = (h - 2) * dstStride; y >= 0; y -= dstStride) {
      z += (alpha * (((int)(dst[y]) << 7) - z)) >> 16;
      dst[y] = (unsigned char)(z >> 7);
    }
    dst[0] = 0;
    dst++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<trailer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <outstr@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D9: ; --- End of Compilation ---


assistant: ```c
void trailer(void) {
  nl();
  outstr("; --- End of Compilation ---\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<trailer>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D9(%rip),%rdi
  call   <outstr@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: ; --- End of Compilation ---


assistant: ```c
void trailer(void) {
  nl();
  outstr("; --- End of Compilation ---\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trailer>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nl@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <outstr@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: ; --- End of Compilation ---


assistant: ```c
void trailer(void) {
  nl();
  outstr("; --- End of Compilation ---\n");
}
```