ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vec_addf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vec_addf(float z[], const float x[], const float y[], int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] + y[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vec_addf>:
  endbr64
  test   %ecx,%ecx
  jle    L2
  mov    %ecx,%ecx
  mov    $0x0,%eax
L13:
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L13
L2:
  ret
```

assistant: ```c
void vec_addf(float z[], const float x[], const float y[], int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] + y[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vec_addf>:
  endbr64
  test   %ecx,%ecx
  jle    L6
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L10:
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L10
L6:
  ret
```

assistant: ```c
void vec_addf(float z[], const float x[], const float y[], int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] + y[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vec_addf>:
  endbr64
  test   %ecx,%ecx
  jle    L16
  lea    0x4(%rdx),%r8
  mov    %rdi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  seta   %r8b
  cmp    $0x1,%ecx
  setne  %al
  test   %al,%r8b
  je     L81
  lea    0x4(%rsi),%r8
  mov    %rdi,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L81
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r9d
  cmp    $0x2,%eax
  jbe    L27
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L62:
  movups (%rsi,%rax,1),%xmm0
  movups (%rdx,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L62
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ecx
  je     L16
  sub    %r8d,%ecx
  mov    %ecx,%r9d
  cmp    $0x1,%ecx
  je     L61
L84:
  mov    %r8d,%ecx
  movq   (%rsi,%rcx,4),%xmm0
  movq   (%rdx,%rcx,4),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdi,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L16
L61:
  cltq
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  ret
  nopl   (%rax)
L81:
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L55:
  movss  (%rsi,%rax,4),%xmm0
  addss  (%rdx,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L55
L16:
  ret
L27:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L84
```

assistant: ```c
void vec_addf(float z[], const float x[], const float y[], int n) {
  int i;
  for (i = 0; i < n; i++)
    z[i] = x[i] + y[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x61776c786e657462,%rax
  mov    %rax,-0x17(%rbp)
  movl   $0x62757a64,-0xf(%rbp)
  movw   $0x6d6e,-0xb(%rbp)
  movb   $0x77,-0x9(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L2
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x17(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L2:
  cmpl   $0xe,-0x1c(%rbp)
  jle    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x17(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <sort@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L43
L26:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x17(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L43:
  cmpl   $0xe,-0x1c(%rbp)
  jle    L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: string

tool: D10: %c 

assistant: ```c
int main() {
  char array[15] = "btenxlwadzubnmw";
  int i;
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  sort(array, 15);
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x61776c786e657462,%rax
  mov    %rax,0x9(%rsp)
  movl   $0x62757a64,0x11(%rsp)
  movw   $0x6d6e,0x15(%rsp)
  movb   $0x77,0x17(%rsp)
  lea    0x9(%rsp),%rbx
  lea    0x18(%rsp),%r12
  mov    %rbx,%rbp
  lea    D19(%rip),%r13
L2:
  movsbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x9(%rsp),%rdi
  mov    $0xf,%esi
  call   <sort@plt>
  lea    D19(%rip),%rbp
L23:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_guessed: string

tool: D19: %c 

assistant: ```c
int main() {
  char array[15] = "btenxlwadzubnmw";
  int i;
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  sort(array, 15);
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x62,%esi
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x61776c786e657462,%rax
  lea    0x9(%rsp),%r13
  movl   $0x62757a64,0x11(%rsp)
  lea    0xa(%rsp),%r14
  movb   $0x77,0x17(%rsp)
  mov    %r13,%rbx
  lea    0x18(%rsp),%rbp
  mov    %rax,0x9(%rsp)
  mov    $0x6d6e,%eax
  mov    %ax,0x15(%rsp)
  jmp    L26
  nopl   0x0(%rax)
L5:
  movsbl (%r14),%esi
  add    $0x1,%r14
L26:
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbp,%r14
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xf,%esi
  mov    %r13,%rdi
  call   <sort@plt>
  cs nopw 0x0(%rax,%rax,1)
L28:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: %c 

assistant: ```c
int main() {
  char array[15] = "btenxlwadzubnmw";
  int i;
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  sort(array, 15);
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x61776c786e657462,%rax
  movl   $0x62757a64,0x11(%rsp)
  lea    0x9(%rsp),%r14
  lea    0x18(%rsp),%r12
  movb   $0x77,0x17(%rsp)
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,0x9(%rsp)
  mov    $0x6d6e,%eax
  mov    %ax,0x15(%rsp)
  nopl   0x0(%rax,%rax,1)
L28:
  movsbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xf,%esi
  mov    %r14,%rdi
  call   <sort@plt>
  xchg   %ax,%ax
L27:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: %c 

assistant: ```c
int main() {
  char array[15] = "btenxlwadzubnmw";
  int i;
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  sort(array, 15);
  for (i = 0; i < 15; i++)
    printf("%c ", array[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<av_clip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L6
  mov    -0x8(%rbp),%eax
  jmp    L10
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L37
  mov    -0xc(%rbp),%eax
  jmp    L10
L37:
  mov    -0x4(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int av_clip(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<av_clip>:
  endbr64
  cmp    %edx,%edi
  cmovle %edi,%edx
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int av_clip(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<av_clip>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int av_clip(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<av_clip>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int av_clip(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chop_lvl2_domain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jg     L41
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jle    L33
L41:
  mov    -0x28(%rbp),%rax
  jmp    L60
L33:
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L68
L14:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L17
  addl   $0x1,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L67
L17:
  subl   $0x1,-0x18(%rbp)
L68:
  cmpl   $0x0,-0x18(%rbp)
  jns    L14
  jmp    L43
L67:
  nop
L43:
  cmpl   $0x0,-0x18(%rbp)
  jle    L45
  mov    -0x10(%rbp),%eax
  sub    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L45:
  mov    -0x28(%rbp),%rax
L60:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

assistant: ```c
char *chop_lvl2_domain(char *domname) {
  int i;
  int len, n;
  unsigned char unusedbuf[sizeof(struct in6_addr)];
  if (inet_pton(AF_INET, domname, (void *)unusedbuf) > 0 || inet_pton(AF_INET6, domname, (void *)unusedbuf) > 0)
    return domname;
  n = 0;
  len = strlen(domname);
  for (i = len; i >= 0; i--) {
    if (domname[i] == '.') {
      n++;
      if (n == 2)
        break;
    }
  }
  if (i > 0)
    memmove(domname, domname + i + 1, len - i - 1);
  return domname;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chop_lvl2_domain>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rdi,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jle    L81
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L81:
  lea    0x4(%rsp),%rdx
  mov    %rbx,%rsi
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jg     L64
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  js     L35
  movslq %eax,%rsi
  add    %rbx,%rsi
  mov    %eax,%ecx
  mov    $0x0,%edi
  jmp    L71
L105:
  sub    $0x1,%ecx
  sub    $0x1,%rsi
  cmp    $0xffffffff,%ecx
  je     L64
L71:
  cmpb   $0x2e,(%rsi)
  jne    L105
  add    $0x1,%edi
  cmp    $0x2,%edi
  jne    L105
L50:
  test   %ecx,%ecx
  jle    L64
  sub    %ecx,%eax
  lea    -0x1(%rax),%edx
  movslq %ecx,%rcx
  lea    0x1(%rbx,%rcx,1),%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  jmp    L64
L35:
  mov    %eax,%ecx
  jmp    L50
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *chop_lvl2_domain(char *domname) {
  int i;
  int len, n;
  unsigned char unusedbuf[sizeof(struct in6_addr)];
  if (inet_pton(AF_INET, domname, (void *)unusedbuf) > 0 || inet_pton(AF_INET6, domname, (void *)unusedbuf) > 0)
    return domname;
  n = 0;
  len = strlen(domname);
  for (i = len; i >= 0; i--) {
    if (domname[i] == '.') {
      n++;
      if (n == 2)
        break;
    }
  }
  if (i > 0)
    memmove(domname, domname + i + 1, len - i - 1);
  return domname;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chop_lvl2_domain>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jle    L68
L69:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L68:
  mov    D6(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jg     L69
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  js     L69
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L3
  nopl   0x0(%rax)
L96:
  sub    $0x1,%rcx
  cmp    $0xffffffff,%ecx
  je     L69
L3:
  cmpb   $0x2e,(%r12,%rcx,1)
  mov    %ecx,%esi
  jne    L96
  cmp    $0x1,%edx
  je     L42
  sub    $0x1,%rcx
  cmp    $0xffffffff,%ecx
  je     L69
  cmpb   $0x2e,(%r12,%rcx,1)
  mov    %ecx,%esi
  je     L42
  mov    $0x1,%edx
  jmp    L96
L42:
  test   %esi,%esi
  je     L69
  sub    %esi,%eax
  mov    %r12,%rdi
  lea    0x1(%r12,%rcx,1),%rsi
  lea    -0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L69
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *chop_lvl2_domain(char *domname) {
  int i;
  int len, n;
  unsigned char unusedbuf[sizeof(struct in6_addr)];
  if (inet_pton(AF_INET, domname, (void *)unusedbuf) > 0 || inet_pton(AF_INET6, domname, (void *)unusedbuf) > 0)
    return domname;
  n = 0;
  len = strlen(domname);
  for (i = len; i >= 0; i--) {
    if (domname[i] == '.') {
      n++;
      if (n == 2)
        break;
    }
  }
  if (i > 0)
    memmove(domname, domname + i + 1, len - i - 1);
  return domname;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chop_lvl2_domain>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jle    L34
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L34:
  mov    D10(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <inet_pton@plt>
  test   %rax,%rax
  jg     L88
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  js     L88
  movslq %eax,%rcx
  xor    %edx,%edx
  jmp    L118
  nopl   0x0(%rax)
L100:
  sub    $0x1,%rcx
  cmp    $0xffffffff,%ecx
  je     L88
L118:
  cmpb   $0x2e,(%r12,%rcx,1)
  mov    %ecx,%esi
  jne    L100
  cmp    $0x1,%edx
  je     L18
  sub    $0x1,%rcx
  cmp    $0xffffffff,%ecx
  je     L88
  cmpb   $0x2e,(%r12,%rcx,1)
  mov    %ecx,%esi
  je     L18
  mov    $0x1,%edx
  jmp    L100
L18:
  test   %esi,%esi
  je     L88
  sub    %esi,%eax
  mov    %r12,%rdi
  lea    0x1(%r12,%rcx,1),%rsi
  lea    -0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L88
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *chop_lvl2_domain(char *domname) {
  int i;
  int len, n;
  unsigned char unusedbuf[sizeof(struct in6_addr)];
  if (inet_pton(AF_INET, domname, (void *)unusedbuf) > 0 || inet_pton(AF_INET6, domname, (void *)unusedbuf) > 0)
    return domname;
  n = 0;
  len = strlen(domname);
  for (i = len; i >= 0; i--) {
    if (domname[i] == '.') {
      n++;
      if (n == 2)
        break;
    }
  }
  if (i > 0)
    memmove(domname, domname + i + 1, len - i - 1);
  return domname;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<translate_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x81,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    0x4(%rax),%eax
  jmp    L14
L2:
  nop
  mov    $0xffffffff,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int translate_event(const struct input_event *levt) {
  switch (levt->type) {
  case EV_KEY:
    return levt->code;
  case EV_REL:
  case EV_ABS:
  default:
    break;
    ;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<translate_event>:
  endbr64
  mov    $0xffffffff,%eax
  cmpl   $0x81,(%rdi)
  je     L4
L10:
  ret
L4:
  mov    0x4(%rdi),%eax
  jmp    L10
```

assistant: ```c
unsigned int translate_event(const struct input_event *levt) {
  switch (levt->type) {
  case EV_KEY:
    return levt->code;
  case EV_REL:
  case EV_ABS:
  default:
    break;
    ;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<translate_event>:
  endbr64
  cmpl   $0x81,(%rdi)
  mov    $0xffffffff,%eax
  je     L7
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x4(%rdi),%eax
  ret
```

assistant: ```c
unsigned int translate_event(const struct input_event *levt) {
  switch (levt->type) {
  case EV_KEY:
    return levt->code;
  case EV_REL:
  case EV_ABS:
  default:
    break;
    ;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<translate_event>:
  endbr64
  cmpl   $0x81,(%rdi)
  mov    $0xffffffff,%eax
  je     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    0x4(%rdi),%eax
  ret
```

assistant: ```c
unsigned int translate_event(const struct input_event *levt) {
  switch (levt->type) {
  case EV_KEY:
    return levt->code;
  case EV_REL:
  case EV_ABS:
  default:
    break;
    ;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oauth_url_unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L21
L58:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  jmp    L70
L65:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x31(%rbp)
  cmpb   $0x25,-0x31(%rbp)
  jne    L89
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L89
  mov    -0x48(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L89
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %al,-0x31(%rbp)
  addq   $0x2,-0x48(%rbp)
  subq   $0x2,-0x30(%rbp)
L89:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  add    %rax,%rdx
  movzbl -0x31(%rbp),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x48(%rbp)
L70:
  subq   $0x1,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L65
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x50(%rbp)
  je     L8
  mov    -0x50(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L8:
  mov    -0x20(%rbp),%rax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

assistant: ```c
char *oauth_url_unescape(const char *string, size_t *olen) {
  size_t alloc, strindex = 0;
  char *ns = NULL;
  unsigned char in;
  long hex;
  if (!string)
    return NULL;
  alloc = strlen(string) + 1;
  ns = (char *)malloc(alloc);
  while (--alloc > 0) {
    in = *string;
    if (('%' == in) && (isxdigit((int)((unsigned char)string[1]))) && (isxdigit((int)((unsigned char)string[2])))) {
      char hexstr[3];
      hexstr[0] = string[1];
      hexstr[1] = string[2];
      hexstr[2] = 0;
      hex = strtol(hexstr, NULL, 16);
      in = (unsigned char)hex;
      string += 2;
      alloc -= 2;
    }
    ns[strindex++] = in;
    string++;
  }
  ns[strindex] = 0;
  if (olen)
    *olen = strindex;
  return ns;
}
```