ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calc_vc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movapd %xmm1,%xmm0
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %ecx,%eax
  neg    %eax
  movsd  0x8(%rsp),%xmm6
  ucomisd D14(%rip),%xmm6
  cmovbe %eax,%r13d
  call   <sqrt@plt>
  movsd  (%rbx),%xmm2
  movsd  0x8(%rbx),%xmm1
  movsd  0x10(%rbx),%xmm4
  movapd %xmm2,%xmm3
  mulsd  %xmm2,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  movapd %xmm4,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm0,%xmm3
  movsd  D5(%rip),%xmm0
  subsd  %xmm3,%xmm0
  imul   %r13d,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  mulsd  0x8(%rbp),%xmm1
  movsd  0x8(%rsp),%xmm6
  movapd %xmm6,%xmm5
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm1
  mulsd  0x10(%rbp),%xmm4
  addsd  %xmm4,%xmm1
  subsd  %xmm1,%xmm3
  mulsd  %xmm0,%xmm6
  movapd %xmm6,%xmm1
  divsd  %xmm3,%xmm1
  subsd  %xmm1,%xmm2
  movsd  %xmm2,(%r12)
  movapd %xmm0,%xmm2
  mulsd  0x8(%rbp),%xmm2
  divsd  %xmm3,%xmm2
  movsd  0x8(%rbx),%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%r12)
  mulsd  0x10(%rbp),%xmm0
  divsd  %xmm3,%xmm0
  movsd  0x10(%rbx),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%r12)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: f64
name: extract_symbolic_data
arguments: label: D5
data_type: f64

tool: D14: 0

tool: D5: 1

assistant: ```c
void calc_vc(double Bx, double *Ka, double *Bc, double enth, double *vc, int LR) {
  int sgn = Bx > 0 ? LR : -LR;
  double eta = sgn * sqrt(enth);
  double K2 = Ka[0] * Ka[0] + Ka[1] * Ka[1] + Ka[2] * Ka[2];
  double KB = Ka[0] * Bx + Ka[1] * Bc[1] + Ka[2] * Bc[2];
  vc[0] = Ka[0] - Bx * (1.0 - K2) / (eta - KB);
  vc[1] = Ka[1] - Bc[1] * (1.0 - K2) / (eta - KB);
  vc[2] = Ka[2] - Bc[2] * (1.0 - K2) / (eta - KB);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_vc>:
  endbr64
  push   %r13
  mov    %ecx,%eax
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  push   %r12
  neg    %eax
  mov    %ecx,%r12d
  mov    %rdx,%r13
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  ucomisd D12(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  cmovbe %eax,%r12d
  call   <sqrt@plt>
  movsd  (%rbx),%xmm3
  movsd  0x8(%rbx),%xmm1
  movsd  0x10(%rbx),%xmm5
  movsd  0x8(%rsp),%xmm2
  imul   %r12d,%eax
  movapd %xmm3,%xmm4
  movapd %xmm1,%xmm0
  movapd %xmm3,%xmm6
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  0x8(%rbp),%xmm1
  mulsd  %xmm2,%xmm6
  addsd  %xmm0,%xmm4
  movapd %xmm5,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  0x10(%rbp),%xmm5
  addsd  %xmm6,%xmm1
  addsd  %xmm0,%xmm4
  movsd  D19(%rip),%xmm0
  addsd  %xmm5,%xmm1
  subsd  %xmm4,%xmm0
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  mulsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm4
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm3
  movsd  %xmm3,0x0(%r13)
  movsd  0x8(%rbp),%xmm2
  movsd  0x8(%rbx),%xmm1
  mulsd  %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%r13)
  mulsd  0x10(%rbp),%xmm0
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: f64
name: parse_data
arguments: data_label: D19
datatype: f64

tool: D12: 0

tool: D19: 1

assistant: ```c
void calc_vc(double Bx, double *Ka, double *Bc, double enth, double *vc, int LR) {
  int sgn = Bx > 0 ? LR : -LR;
  double eta = sgn * sqrt(enth);
  double K2 = Ka[0] * Ka[0] + Ka[1] * Ka[1] + Ka[2] * Ka[2];
  double KB = Ka[0] * Bx + Ka[1] * Bc[1] + Ka[2] * Bc[2];
  vc[0] = Ka[0] - Bx * (1.0 - K2) / (eta - KB);
  vc[1] = Ka[1] - Bc[1] * (1.0 - K2) / (eta - KB);
  vc[2] = Ka[2] - Bc[2] * (1.0 - K2) / (eta - KB);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calc_vc>:
  endbr64
  push   %r13
  mov    %ecx,%eax
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm0
  push   %r12
  neg    %eax
  mov    %ecx,%r12d
  mov    %rdx,%r13
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  ucomisd D3(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  cmovbe %eax,%r12d
  call   <sqrt@plt>
  movsd  (%rbx),%xmm3
  movsd  0x8(%rbx),%xmm1
  movsd  0x10(%rbx),%xmm5
  movsd  0x8(%rsp),%xmm2
  imul   %r12d,%eax
  movapd %xmm3,%xmm4
  movapd %xmm1,%xmm0
  movapd %xmm3,%xmm6
  mulsd  %xmm1,%xmm0
  mulsd  %xmm3,%xmm4
  mulsd  0x8(%rbp),%xmm1
  mulsd  %xmm2,%xmm6
  addsd  %xmm0,%xmm4
  movapd %xmm5,%xmm0
  mulsd  %xmm5,%xmm0
  mulsd  0x10(%rbp),%xmm5
  addsd  %xmm6,%xmm1
  addsd  %xmm0,%xmm4
  movsd  D17(%rip),%xmm0
  addsd  %xmm5,%xmm1
  subsd  %xmm4,%xmm0
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  mulsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm4
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm3
  movsd  %xmm3,0x0(%r13)
  movsd  0x8(%rbp),%xmm2
  movsd  0x8(%rbx),%xmm1
  mulsd  %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%r13)
  mulsd  0x10(%rbp),%xmm0
  movsd  0x10(%rbx),%xmm1
  divsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%r13)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: f64
name: parse_data
arguments: tag: D17
datatype: f64

tool: D3: 0

tool: D17: 1

assistant: ```c
void calc_vc(double Bx, double *Ka, double *Bc, double enth, double *vc, int LR) {
  int sgn = Bx > 0 ? LR : -LR;
  double eta = sgn * sqrt(enth);
  double K2 = Ka[0] * Ka[0] + Ka[1] * Ka[1] + Ka[2] * Ka[2];
  double KB = Ka[0] * Bx + Ka[1] * Bc[1] + Ka[2] * Bc[2];
  vc[0] = Ka[0] - Bx * (1.0 - K2) / (eta - KB);
  vc[1] = Ka[1] - Bc[1] * (1.0 - K2) / (eta - KB);
  vc[2] = Ka[2] - Bc[2] * (1.0 - K2) / (eta - KB);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_striteri>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L9
  cmpq   $0x0,-0x20(%rbp)
  je     L9
  jmp    L15
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   *%rdx
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  jmp    L36
L9:
  nop
L36:
  leave
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    (*f)(i, &s[i]);
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L22
  cmpb   $0x0,(%rdi)
  je     L22
  mov    $0x0,%ebp
L17:
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   *%r12
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    (*f)(i, &s[i]);
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L1
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L1
  xor    %ebp,%ebp
  nop
L13:
  mov    %rbx,%rsi
  add    $0x1,%rbx
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   *%r12
  cmpb   $0x0,(%rbx)
  jne    L13
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    (*f)(i, &s[i]);
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_striteri>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L4
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L4
  xor    %ebp,%ebp
  nop
L22:
  mov    %rbx,%rsi
  add    $0x1,%rbx
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   *%r12
  cmpb   $0x0,(%rbx)
  jne    L22
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  ret
```

assistant: ```c
void ft_striteri(char *s, void (*f)(unsigned int, char *)) {
  int i;
  i = 0;
  if (!s || !f)
    return;
  while (s[i]) {
    (*f)(i, &s[i]);
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nullpo_info_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xe0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edi
  mov    -0xe0(%rbp),%rcx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <nullpo_info_core@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void nullpo_info_f(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  nullpo_info_core(file, line, func, fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nullpo_info_f>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%r14
  mov    %rcx,%rbx
  mov    %rcx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %r14,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <nullpo_info_core@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void nullpo_info_f(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  nullpo_info_core(file, line, func, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nullpo_info_f>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %esi,%r14d
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <nullpo_info_core@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void nullpo_info_f(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  nullpo_info_core(file, line, func, fmt, ap);
  va_end(ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nullpo_info_f>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %esi,%r14d
  mov    %rcx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%r8d
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <nullpo_info_core@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void nullpo_info_f(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  nullpo_info_core(file, line, func, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  call   <f2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  f1();
  f2();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f1@plt>
  mov    $0x0,%eax
  call   <f2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  f1();
  f2();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  call   <f2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  f1();
  f2();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f1@plt>
  xor    %eax,%eax
  call   <f2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  f1();
  f2();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<echo_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <term_set_raw_mode@plt>
L15:
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  cmpl   $0x1,-0x24(%rbp)
  jne    L15
  movzbl -0x20(%rbp),%eax
  cmp    $0xa,%al
  je     L21
  movzbl -0x20(%rbp),%eax
  cmp    $0xd,%al
  je     L21
  jmp    L15
L21:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: echo_read()


assistant: ```c
void echo_read(void) {
  int ret;
  char buf[16];
  printf("echo_read()\n");
  term_set_raw_mode();
  while (1) {
    ret = read(0, buf, sizeof(buf));
    write(1, buf, ret);
    if (ret == 1 && (buf[0] == '\n' || buf[0] == '\r'))
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<echo_read>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <term_set_raw_mode@plt>
  mov    %rsp,%rbp
L38:
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  cmp    $0x1,%ebx
  jne    L38
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L12
  cmp    $0xd,%al
  jne    L38
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: echo_read()


assistant: ```c
void echo_read(void) {
  int ret;
  char buf[16];
  printf("echo_read()\n");
  term_set_raw_mode();
  while (1) {
    ret = read(0, buf, sizeof(buf));
    write(1, buf, ret);
    if (ret == 1 && (buf[0] == '\n' || buf[0] == '\r'))
      break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<echo_read>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  xor    %eax,%eax
  call   <term_set_raw_mode@plt>
L35:
  xor    %edi,%edi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%ebx
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0x1,%ebx
  jne    L35
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L20
  cmp    $0xd,%al
  jne    L35
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string

tool: D4: echo_read()


assistant: ```c
void echo_read(void) {
  int ret;
  char buf[16];
  printf("echo_read()\n");
  term_set_raw_mode();
  while (1) {
    ret = read(0, buf, sizeof(buf));
    write(1, buf, ret);
    if (ret == 1 && (buf[0] == '\n' || buf[0] == '\r'))
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<echo_read>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  xor    %eax,%eax
  call   <term_set_raw_mode@plt>
L10:
  xor    %edi,%edi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <read@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%ebx
  mov    %eax,%edx
  call   <write@plt>
  cmp    $0x1,%ebx
  jne    L10
  movzbl (%rsp),%eax
  cmp    $0xa,%al
  je     L27
  cmp    $0xd,%al
  jne    L10
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: echo_read()


assistant: ```c
void echo_read(void) {
  int ret;
  char buf[16];
  printf("echo_read()\n");
  term_set_raw_mode();
  while (1) {
    ret = read(0, buf, sizeof(buf));
    write(1, buf, ret);
    if (ret == 1 && (buf[0] == '\n' || buf[0] == '\r'))
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x6c(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x64(%rbp)
  jmp    L10
L45:
  lea    -0x30(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x64(%rbp)
L10:
  mov    -0x6c(%rbp),%eax
  cmp    %eax,-0x64(%rbp)
  jle    L45
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x64(%rbp)
  jmp    L16
L1:
  lea    -0x60(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x64(%rbp)
L16:
  mov    -0x6c(%rbp),%eax
  cmp    %eax,-0x64(%rbp)
  jle    L1
  mov    -0x68(%rbp),%esi
  mov    -0x6c(%rbp),%eax
  lea    -0x30(%rbp),%rcx
  lea    -0x60(%rbp),%rdx
  mov    %eax,%edi
  call   <Knapsack@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D42
type: string
name: read_data
arguments: data_tag: D64
type: string
name: read_data
arguments: data_tag: D22
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D42: Enter the no of objects :


tool: D64: %d

tool: D22: Enter the total weight :


tool: D30: Enter the weights


tool: D16: Enter the profits


assistant: ```c
int main(int argc, char *argv[]) {
  int no, wt, pt[10] = {0}, weight[10] = {0};
  int i;
  printf("Enter the no of objects :\n");
  scanf("%d", &no);
  printf("Enter the total weight :\n");
  scanf("%d", &wt);
  printf("Enter the weights\n");
  for (i = 1; i <= no; i++)
    scanf("%d", &weight[i]);
  printf("Enter the profits\n");
  for (i = 1; i <= no; i++)
    scanf("%d", &pt[i]);
  Knapsack(no, wt, pt, weight);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D69(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L32
  lea    0x44(%rsp),%rbp
  mov    $0x1,%ebx
  lea    D20(%rip),%r12
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jge    L25
L32:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%edi
  test   %edi,%edi
  jle    L6
  lea    0x14(%rsp),%rbp
  mov    $0x1,%ebx
  lea    D20(%rip),%r12
L37:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%edi
  add    $0x4,%rbp
  cmp    %ebx,%edi
  jge    L37
L6:
  lea    0x40(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    0xc(%rsp),%esi
  call   <Knapsack@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D61
datatype: string
name: unpack_data
arguments: data_tag: D20
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string
name: unpack_data
arguments: data_tag: D69
datatype: string
name: unpack_data
arguments: data_tag: D30
datatype: string

tool: D61: Enter the no of objects :


tool: D20: %d

tool: D10: Enter the total weight :


tool: D69: Enter the weights


tool: D30: Enter the profits


assistant: ```c
int main(int argc, char *argv[]) {
  int no, wt, pt[10] = {0}, weight[10] = {0};
  int i;
  printf("Enter the no of objects :\n");
  scanf("%d", &no);
  printf("Enter the total weight :\n");
  scanf("%d", &wt);
  printf("Enter the weights\n");
  for (i = 1; i <= no; i++)
    scanf("%d", &weight[i]);
  printf("Enter the profits\n");
  for (i = 1; i <= no; i++)
    scanf("%d", &pt[i]);
  Knapsack(no, wt, pt, weight);
  return (0);
}
```