ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%rdi
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jle    L55
  nopl   (%rax)
L52:
  mov    %r12,%rbx
  jmp    L54
  nopl   (%rax)
L4:
  movsbl (%rbx),%edi
  call   <number@plt>
  movsbl 0x1(%rbx),%edi
  mov    %rax,%rbp
  call   <number@plt>
  cmp    %rax,%rbp
  jle    L25
  movzbl (%rbx),%eax
  movzbl 0x1(%rbx),%edx
  mov    %al,0x1(%rbx)
  mov    %dl,(%rbx)
L25:
  add    $0x1,%rbx
L54:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  sub    %r13d,%eax
  sub    %r12d,%edx
  cmp    %edx,%eax
  jg     L4
  mov    %r12,%rdi
  add    $0x1,%r13d
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L52
L55:
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string

tool: D2: %s

tool: D7: 
%s

assistant: ```c
int main() {
  int i, k;
  char teste[14], teste1;
  scanf("%s", teste);
  for (i = 1; i < strlen(teste); i++) {
    for (k = 0; k < strlen(teste) - i; k++) {
      if (number(teste[k]) > number(teste[k + 1])) {
        teste1 = teste[k];
        teste[k] = teste[k + 1];
        teste[k + 1] = teste1;
      }
    }
  }
  printf("\n%s", teste);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gss>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %rdi,-0x48(%rbp)
  mov    $0x5,%edi
  call   <sqrt@plt>
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L14
L9:
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L30
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L14
L30:
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  movq   %rax,%xmm0
  call   *%rdx
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
L14:
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L9
  movsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D2": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x7a,0x3e]}

assistant: ```c
double gss(double a, double b, double (*f)(double)) {
  double r = (sqrt(5) - 1) / 2, eps = 1e-7;
  double x1 = b - r * (b - a), x2 = a + r * (b - a);
  double f1 = f(x1), f2 = f(x2);
  while (b - a > eps)
    if (f1 < f2) {
      b = x2;
      x2 = x1;
      f2 = f1;
      x1 = b - r * (b - a);
      f1 = f(x1);
    } else {
      a = x1;
      x1 = x2;
      f1 = f2;
      x2 = a + r * (b - a);
      f2 = f(x2);
    }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D173(%rip),%rax
  mov    %rax,%rdx
  lea    D101(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdx
  lea    D101(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D119(%rip),%rax
  mov    %rax,%rdx
  lea    D196(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D143(%rip),%rax
  mov    %rax,%rdx
  lea    D89(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D119(%rip),%rax
  mov    %rax,%rdx
  lea    D165(%rip),%rax
  mov    %rax,%rsi
  lea    D196(%rip),%rax
  mov    %rax,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D173
type_guessed: string
name: unpack_data
arguments: tag: D101
type_guessed: string
name: unpack_data
arguments: tag: D196
type_guessed: string
name: unpack_data
arguments: tag: D47
type_guessed: string
name: unpack_data
arguments: tag: D34
type_guessed: string
name: unpack_data
arguments: tag: D119
type_guessed: string
name: unpack_data
arguments: tag: D143
type_guessed: string
name: unpack_data
arguments: tag: D89
type_guessed: string
name: unpack_data
arguments: tag: D165
type_guessed: string

tool: D173: S

tool: D101: B

tool: D196: Billy!

tool: D47: > %s


tool: D34: Programming-

tool: D119: Steve!

tool: D143: -Steve!

tool: D89: !

tool: D165: Holla!

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("> %s\n", replace("Billy!", "B", "S"));
  printf("> %s\n", replace("Billy!", "B", "Programming-"));
  printf("> %s\n", replace("Billy!", "Billy!", "Steve!"));
  printf("> %s\n", replace("Billy!", "!", "-Steve!"));
  printf("> %s\n", replace("Billy!", "Holla!", "Steve!"));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D59(%rip),%rdx
  lea    D25(%rip),%r12
  mov    %r12,%rsi
  lea    D68(%rip),%rbx
  mov    %rbx,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  lea    D85(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D73(%rip),%r12
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdx
  lea    D80(%rip),%rsi
  mov    %rbx,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  lea    D63(%rip),%rsi
  mov    %rbx,%rdi
  call   <replace@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D59
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string
name: read_data
arguments: data_label: D68
type_infered: string
name: read_data
arguments: data_label: D85
type_infered: string
name: read_data
arguments: data_label: D66
type_infered: string
name: read_data
arguments: data_label: D73
type_infered: string
name: read_data
arguments: data_label: D84
type_infered: string
name: read_data
arguments: data_label: D80
type_infered: string
name: read_data
arguments: data_label: D63
type_infered: string

tool: D59: S

tool: D25: B

tool: D68: Billy!

tool: D85: > %s


tool: D66: Programming-

tool: D73: Steve!

tool: D84: -Steve!

tool: D80: !

tool: D63: Holla!

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("> %s\n", replace("Billy!", "B", "S"));
  printf("> %s\n", replace("Billy!", "B", "Programming-"));
  printf("> %s\n", replace("Billy!", "Billy!", "Steve!"));
  printf("> %s\n", replace("Billy!", "!", "-Steve!"));
  printf("> %s\n", replace("Billy!", "Holla!", "Steve!"));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D62(%rip),%r13
  lea    D44(%rip),%rdx
  push   %r12
  mov    %r13,%rsi
  lea    D65(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  mov    %rbp,%rdi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D73(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <replace@plt>
  lea    D16(%rip),%r13
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D42(%rip),%rdx
  mov    %rbp,%rdi
  lea    D80(%rip),%rsi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D14(%rip),%rsi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D62
datatype: string
name: parse_data
arguments: data_label: D44
datatype: string
name: parse_data
arguments: data_label: D65
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D73
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D42
datatype: string
name: parse_data
arguments: data_label: D80
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D62: B

tool: D44: S

tool: D65: > %s


tool: D2: Billy!

tool: D73: Programming-

tool: D16: Steve!

tool: D42: -Steve!

tool: D80: !

tool: D14: Holla!

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("> %s\n", replace("Billy!", "B", "S"));
  printf("> %s\n", replace("Billy!", "B", "Programming-"));
  printf("> %s\n", replace("Billy!", "Billy!", "Steve!"));
  printf("> %s\n", replace("Billy!", "!", "-Steve!"));
  printf("> %s\n", replace("Billy!", "Holla!", "Steve!"));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  lea    D65(%rip),%rdx
  push   %r12
  mov    %r13,%rsi
  lea    D61(%rip),%r12
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D47(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <replace@plt>
  lea    D11(%rip),%r13
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D80(%rip),%rdx
  mov    %rbp,%rdi
  lea    D44(%rip),%rsi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D55(%rip),%rsi
  call   <replace@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D65
type_infered: string
name: extract_symbolic_data
arguments: data_label: D61
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D47
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D80
type_infered: string
name: extract_symbolic_data
arguments: data_label: D44
type_infered: string
name: extract_symbolic_data
arguments: data_label: D55
type_infered: string

tool: D10: B

tool: D65: S

tool: D61: > %s


tool: D26: Billy!

tool: D47: Programming-

tool: D11: Steve!

tool: D80: -Steve!

tool: D44: !

tool: D55: Holla!

assistant: ```c
int main(int argc, char const *argv[]) {
  printf("> %s\n", replace("Billy!", "B", "S"));
  printf("> %s\n", replace("Billy!", "B", "Programming-"));
  printf("> %s\n", replace("Billy!", "Billy!", "Steve!"));
  printf("> %s\n", replace("Billy!", "!", "-Steve!"));
  printf("> %s\n", replace("Billy!", "Holla!", "Steve!"));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sdbm_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L3
L5:
  mov    %r12d,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  mov    %rbx,%rdx
  shl    $0x6,%rdx
  add    %rax,%rdx
  mov    %rbx,%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  sub    %rbx,%rax
  mov    %rax,%rbx
  add    $0x1,%r12d
L3:
  cmp    -0x1c(%rbp),%r12d
  jb     L5
  mov    %rbx,%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
unsigned long sdbm_hash(const char *str, unsigned int len) {
  register unsigned int i;
  register unsigned long hash = 0;
  for (i = 0; i < len; ++i) {
    hash = str[i] + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sdbm_hash>:
  endbr64
  test   %esi,%esi
  je     L17
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L0:
  imul   $0x1003f,%rax,%rax
  movsbq (%rdx),%rcx
  add    %rcx,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L0
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long sdbm_hash(const char *str, unsigned int len) {
  register unsigned int i;
  register unsigned long hash = 0;
  for (i = 0; i < len; ++i) {
    hash = str[i] + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<sdbm_hash>:
  endbr64
  test   %esi,%esi
  je     L2
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  imul   $0x1003f,%rax,%rax
  movsbq (%rdi),%rdx
  add    $0x1,%rdi
  add    %rdx,%rax
  cmp    %rdi,%rcx
  jne    L0
  ret
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long sdbm_hash(const char *str, unsigned int len) {
  register unsigned int i;
  register unsigned long hash = 0;
  for (i = 0; i < len; ++i) {
    hash = str[i] + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sdbm_hash>:
  endbr64
  test   %esi,%esi
  je     L11
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  imul   $0x1003f,%rax,%rax
  movsbq (%rdi),%rdx
  add    $0x1,%rdi
  add    %rdx,%rax
  cmp    %rdi,%rcx
  jne    L17
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long sdbm_hash(const char *str, unsigned int len) {
  register unsigned int i;
  register unsigned long hash = 0;
  for (i = 0; i < len; ++i) {
    hash = str[i] + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GrMapISO8859_9_Unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  movq   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0xd0,%eax
  cmp    $0x2e,%eax
  ja     L34
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D10(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x11e,%eax
  jmp    L16
  mov    $0x130,%eax
  jmp    L16
  mov    $0x15e,%eax
  jmp    L16
  mov    $0x11f,%eax
  jmp    L16
  mov    $0x131,%eax
  jmp    L16
  mov    $0x15f,%eax
  jmp    L16
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
L16:
  leave
  ret
```

assistant: ```c
unsigned long GrMapISO8859_9_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  switch ((unsigned char)*pcSrcChar) {
  case 0xD0: {
    return (0x11E);
  }
  case 0xDD: {
    return (0x130);
  }
  case 0xDE: {
    return (0x15E);
  }
  case 0xF0: {
    return (0x11F);
  }
  case 0xFD: {
    return (0x131);
  }
  case 0xFE: {
    return (0x15F);
  }
  default: {
    return ((unsigned long)(unsigned char)*pcSrcChar);
  }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GrMapISO8859_9_Unicode>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  lea    0x30(%rax),%edx
  cmp    $0x2e,%dl
  ja     L6
  movzbl %dl,%edx
  lea    D7(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x130,%eax
  jmp    L44
  mov    $0x15e,%eax
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  mov    $0x11f,%eax
  jmp    L44
  mov    $0x131,%eax
  jmp    L44
  mov    $0x15f,%eax
  jmp    L44
L6:
  movzbl %al,%eax
  jmp    L44
  mov    $0x11e,%eax
  jmp    L44
```

assistant: ```c
unsigned long GrMapISO8859_9_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  switch ((unsigned char)*pcSrcChar) {
  case 0xD0: {
    return (0x11E);
  }
  case 0xDD: {
    return (0x130);
  }
  case 0xDE: {
    return (0x15E);
  }
  case 0xF0: {
    return (0x11F);
  }
  case 0xFD: {
    return (0x131);
  }
  case 0xFE: {
    return (0x15F);
  }
  default: {
    return ((unsigned long)(unsigned char)*pcSrcChar);
  }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<GrMapISO8859_9_Unicode>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  lea    0x30(%rax),%edx
  cmp    $0x2e,%dl
  ja     L27
  lea    D7(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  mov    $0x15f,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x15e,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x11f,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x131,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  mov    $0x11e,%eax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
  mov    $0x130,%eax
  jmp    L27
```

assistant: ```c
unsigned long GrMapISO8859_9_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  switch ((unsigned char)*pcSrcChar) {
  case 0xD0: {
    return (0x11E);
  }
  case 0xDD: {
    return (0x130);
  }
  case 0xDE: {
    return (0x15E);
  }
  case 0xF0: {
    return (0x11F);
  }
  case 0xFD: {
    return (0x131);
  }
  case 0xFE: {
    return (0x15F);
  }
  default: {
    return ((unsigned long)(unsigned char)*pcSrcChar);
  }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GrMapISO8859_9_Unicode>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  movq   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  lea    0x30(%rax),%edx
  cmp    $0x2e,%dl
  ja     L23
  lea    D9(%rip),%rcx
  movzbl %dl,%edx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  mov    $0x15f,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x15e,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x11f,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  add    $0x8,%rsp
  mov    $0x131,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
  mov    $0x11e,%eax
  jmp    L23
  nopw   0x0(%rax,%rax,1)
  mov    $0x130,%eax
  jmp    L23
```

assistant: ```c
unsigned long GrMapISO8859_9_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  assert(pulSkip);
  assert(pcSrcChar);
  *pulSkip = 1;
  switch ((unsigned char)*pcSrcChar) {
  case 0xD0: {
    return (0x11E);
  }
  case 0xDD: {
    return (0x130);
  }
  case 0xDE: {
    return (0x15E);
  }
  case 0xF0: {
    return (0x11F);
  }
  case 0xFD: {
    return (0x131);
  }
  case 0xFE: {
    return (0x15F);
  }
  default: {
    return ((unsigned long)(unsigned char)*pcSrcChar);
  }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<truncstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L17
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L17:
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void truncstring(char *string) {
  int length;
  length = strlen(string);
  while (string[--length] == ' ')
    string[length] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<truncstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmpb   $0x20,(%rdx)
  jne    L12
  lea    -0x1(%rbx,%rax,1),%rax
L17:
  movb   $0x0,(%rdx)
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rax)
  je     L17
L12:
  pop    %rbx
  ret
```

assistant: ```c
void truncstring(char *string) {
  int length;
  length = strlen(string);
  while (string[--length] == ' ')
    string[length] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<truncstring>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmpb   $0x20,(%rdx)
  jne    L11
  lea    -0x1(%rbx,%rax,1),%rax
L19:
  movb   $0x0,(%rdx)
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmpb   $0x20,0x1(%rax)
  je     L19
L11:
  pop    %rbx
  ret
```

assistant: ```c
void truncstring(char *string) {
  int length;
  length = strlen(string);
  while (string[--length] == ' ')
    string[length] = '\0';
}
```