ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<expand>:
  endbr64
  mov    %rdi,%r10
  mov    %rsi,%rdi
  movzbl (%r10),%eax
  test   %al,%al
  je     L61
  mov    $0x1,%ecx
  xor    %edx,%edx
  xor    %r9d,%r9d
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L57:
  movslq %edx,%r8
  mov    %ecx,%r9d
  add    $0x1,%edx
  mov    %al,(%rdi,%r8,1)
  movzbl (%rsi),%eax
L11:
  lea    0x1(%r9),%ecx
  test   %al,%al
  je     L8
L39:
  movslq %ecx,%r8
  lea    (%r10,%r8,1),%rsi
  cmpb   $0x2d,(%rsi)
  jne    L57
  cmp    %al,0x1(%r10,%r8,1)
  jl     L57
  add    $0x2,%r9d
  movslq %r9d,%r8
  add    %r10,%r8
  movzbl (%r8),%ecx
  cmp    %al,%cl
  jle    L14
  add    $0x1,%edx
  mov    %eax,%ecx
  movslq %edx,%rsi
  nopl   (%rax)
L5:
  mov    %ecx,%eax
  add    $0x1,%ecx
  mov    %esi,%edx
  mov    %al,-0x1(%rdi,%rsi,1)
  movzbl (%r8),%eax
  add    $0x1,%rsi
  cmp    %cl,%al
  jg     L5
  lea    0x1(%r9),%ecx
  test   %al,%al
  jne    L39
  nop
L8:
  movslq %edx,%rdx
  add    %rdx,%rdi
L61:
  movb   $0x0,(%rdi)
  ret
L14:
  mov    %ecx,%eax
  jmp    L11
```

assistant: ```c
void expand(char s1[], char s2[]) {
  char c;
  int i, j;
  i = j = 0;
  while ((c = s1[i++]) != '\0')
    if (s1[i] == '-' && s1[i + 1] >= c) {
      i++;
      while (c < s1[i])
        s2[j++] = c++;
    } else
      s2[j++] = c;
  s2[j] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cs_ipvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L16
  cmpq   $0x0,-0x28(%rbp)
  jne    L35
L16:
  mov    $0x0,%eax
  jmp    L11
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  cmpq   $0x0,-0x20(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  jmp    L27
L14:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
L27:
  mov    -0x30(%rbp),%rcx
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  mov    $0x1,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int cs_ipvec(int n, const int *P, const double *b, double *x) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[P ? P[k] : k] = b[k];
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cs_ipvec>:
  endbr64
  test   %rcx,%rcx
  je     L41
  test   %rdx,%rdx
  je     L41
  test   %edi,%edi
  jle    L5
  mov    %edi,%edi
  mov    $0x0,%eax
  jmp    L45
L69:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%r8,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L10
L45:
  lea    0x0(,%rax,8),%r8
  test   %rsi,%rsi
  je     L69
  movslq (%rsi,%rax,4),%r8
  shl    $0x3,%r8
  jmp    L69
L10:
  mov    $0x1,%eax
  ret
L41:
  mov    $0x0,%eax
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cs_ipvec(int n, const int *P, const double *b, double *x) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[P ? P[k] : k] = b[k];
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cs_ipvec>:
  endbr64
  test   %rcx,%rcx
  je     L12
  test   %rdx,%rdx
  je     L12
  movslq %edi,%r8
  xor    %eax,%eax
  test   %edi,%edi
  jle    L28
  nopw   0x0(%rax,%rax,1)
L48:
  lea    0x0(,%rax,8),%rdi
  test   %rsi,%rsi
  je     L34
  movslq (%rsi,%rax,4),%rdi
  shl    $0x3,%rdi
L34:
  movsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  movsd  %xmm0,(%rcx,%rdi,1)
  cmp    %r8,%rax
  jne    L48
L28:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cs_ipvec(int n, const int *P, const double *b, double *x) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[P ? P[k] : k] = b[k];
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cs_ipvec>:
  endbr64
  mov    %rdx,%r8
  mov    %edi,%r9d
  mov    %rcx,%rdx
  test   %rcx,%rcx
  je     L17
  test   %r8,%r8
  je     L17
  test   %edi,%edi
  jle    L6
  movslq %edi,%rdi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L94
  nopl   (%rax)
L71:
  movsd  (%r8,%rax,8),%xmm0
  movslq (%rsi,%rax,4),%rcx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%rcx,8)
  cmp    %rdi,%rax
  jne    L71
L6:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  lea    -0x1(%r9),%eax
  cmp    $0x2,%eax
  jbe    L93
  lea    0x8(%r8),%rax
  cmp    %rax,%rcx
  je     L93
  mov    %r9d,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopl   (%rax)
L18:
  movupd (%r8,%rax,1),%xmm1
  movups %xmm1,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L18
  mov    %r9d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r9d
  je     L6
  movsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  mov    $0x1,%eax
  ret
L93:
  mov    %r9d,%eax
  xor    %ecx,%ecx
  nopl   (%rax)
L53:
  movsd  (%r8,%rcx,8),%xmm0
  movsd  %xmm0,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L53
  jmp    L6
```

assistant: ```c
int cs_ipvec(int n, const int *P, const double *b, double *x) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[P ? P[k] : k] = b[k];
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skiprand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
L3:
  cmpl   $0x0,-0x18(%rbp)
  je     L18
  mov    $0x0,%eax
  call   <random@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x18(%rbp)
  jmp    L3
L18:
  nop
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int skiprand(int seed, int n) {
  long tmp;
  {
    {
      while (1) {
      while_9_continue:;
        if (n) {
        } else {
          goto while_9_break;
        }
        {
          tmp = random();
          seed = (int)tmp;
          n = n - 1;
        }
      }
    while_9_break:;
    }
    return (seed);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<skiprand>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%eax
  test   %esi,%esi
  je     L4
L13:
  mov    $0x0,%eax
  call   <random@plt>
  sub    $0x1,%ebx
  jne    L13
L4:
  pop    %rbx
  ret
```

assistant: ```c
int skiprand(int seed, int n) {
  long tmp;
  {
    {
      while (1) {
      while_9_continue:;
        if (n) {
        } else {
          goto while_9_break;
        }
        {
          tmp = random();
          seed = (int)tmp;
          n = n - 1;
        }
      }
    while_9_break:;
    }
    return (seed);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skiprand>:
  endbr64
  test   %esi,%esi
  je     L17
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <random@plt>
  sub    $0x1,%ebx
  jne    L19
  pop    %rbx
  ret
  xchg   %ax,%ax
L17:
  mov    %edi,%eax
  ret
```

assistant: ```c
int skiprand(int seed, int n) {
  long tmp;
  {
    {
      while (1) {
      while_9_continue:;
        if (n) {
        } else {
          goto while_9_break;
        }
        {
          tmp = random();
          seed = (int)tmp;
          n = n - 1;
        }
      }
    while_9_break:;
    }
    return (seed);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skiprand>:
  endbr64
  test   %esi,%esi
  je     L18
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  call   <random@plt>
  sub    $0x1,%ebx
  jne    L9
  pop    %rbx
  ret
  xchg   %ax,%ax
L18:
  mov    %edi,%eax
  ret
```

assistant: ```c
int skiprand(int seed, int n) {
  long tmp;
  {
    {
      while (1) {
      while_9_continue:;
        if (n) {
        } else {
          goto while_9_break;
        }
        {
          tmp = random();
          seed = (int)tmp;
          n = n - 1;
        }
      }
    while_9_break:;
    }
    return (seed);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x100,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jns    L43
  mov    $0x80000000,%eax
  jmp    L35
L43:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L45
  mov    -0x4(%rbp),%eax
  jmp    L35
L45:
  shll   -0x4(%rbp)
  jmp    L43
L35:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int next_power(unsigned int size) {
  unsigned int i = 256;
  if (size >= 2147483648U)
    return 2147483648U;
  while (1) {
    if (i >= size)
      return i;
    i *= 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_power>:
  endbr64
  mov    $0x80000000,%eax
  test   %edi,%edi
  js     L2
  cmp    $0x100,%edi
  jbe    L28
  mov    $0x100,%eax
L24:
  add    %eax,%eax
  cmp    %eax,%edi
  ja     L24
  ret
L28:
  mov    $0x100,%eax
L2:
  ret
```

assistant: ```c
unsigned int next_power(unsigned int size) {
  unsigned int i = 256;
  if (size >= 2147483648U)
    return 2147483648U;
  while (1) {
    if (i >= size)
      return i;
    i *= 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<next_power>:
  endbr64
  mov    $0x80000000,%eax
  test   %edi,%edi
  js     L12
  mov    $0x100,%eax
  cmp    $0x100,%edi
  jbe    L12
  nopw   0x0(%rax,%rax,1)
L29:
  add    %eax,%eax
  cmp    %eax,%edi
  ja     L29
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
unsigned int next_power(unsigned int size) {
  unsigned int i = 256;
  if (size >= 2147483648U)
    return 2147483648U;
  while (1) {
    if (i >= size)
      return i;
    i *= 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<next_power>:
  endbr64
  mov    $0x80000000,%eax
  test   %edi,%edi
  js     L5
  mov    $0x100,%eax
  cmp    $0x100,%edi
  jbe    L5
  nopw   0x0(%rax,%rax,1)
L4:
  add    %eax,%eax
  cmp    %eax,%edi
  ja     L4
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
unsigned int next_power(unsigned int size) {
  unsigned int i = 256;
  if (size >= 2147483648U)
    return 2147483648U;
  while (1) {
    if (i >= size)
      return i;
    i *= 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<random_array2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L13
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  movl   $0x0,-0x18(%rbp)
  jmp    L5
L32:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L32
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int64_t *random_array2(int64_t size, int64_t shuffles) {
  assert(size != 0);
  srand(time(NULL));
  int64_t *arr = malloc(size * sizeof(int64_t));
  for (int64_t i = 0; i < size; i++) {
    arr[i] = i;
  }
  for (int64_t i = 0; i < shuffles; i++) {
    int64_t index1 = rand() % size;
    int64_t index2 = rand() % size;
    int64_t tmp = arr[index1];
    arr[index1] = arr[index2];
    arr[index2] = tmp;
  }
  return arr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<random_array2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  test   %edi,%edi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %ebx,%ebx
  jle    L0
  mov    %ebx,%edx
  mov    $0x0,%eax
L8:
  mov    %eax,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L0:
  test   %r12d,%r12d
  jle    L18
  mov    $0x0,%r13d
L14:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%r14d
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %r14d,%r14
  lea    0x0(%rbp,%r14,4),%rcx
  mov    (%rcx),%esi
  cltd
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jne    L14
L18:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int64_t *random_array2(int64_t size, int64_t shuffles) {
  assert(size != 0);
  srand(time(NULL));
  int64_t *arr = malloc(size * sizeof(int64_t));
  for (int64_t i = 0; i < size; i++) {
    arr[i] = i;
  }
  for (int64_t i = 0; i < shuffles; i++) {
    int64_t index1 = rand() % size;
    int64_t index2 = rand() % size;
    int64_t tmp = arr[index1];
    arr[index1] = arr[index2];
    arr[index2] = tmp;
  }
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<random_array2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  movslq %edi,%r12
  xor    %edi,%edi
  push   %rbp
  test   %r12d,%r12d
  mov    %esi,%ebp
  push   %rbx
  setne  %dil
  mov    %r12,%rbx
  call   <assert@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%r12,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L11
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %eax,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L27
L11:
  test   %ebp,%ebp
  jle    L19
  xor    %r14d,%r14d
  nopl   (%rax)
L30:
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r12
  call   <rand@plt>
  lea    0x0(%r13,%r12,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r14d,%ebp
  jne    L30
L19:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int64_t *random_array2(int64_t size, int64_t shuffles) {
  assert(size != 0);
  srand(time(NULL));
  int64_t *arr = malloc(size * sizeof(int64_t));
  for (int64_t i = 0; i < size; i++) {
    arr[i] = i;
  }
  for (int64_t i = 0; i < shuffles; i++) {
    int64_t index1 = rand() % size;
    int64_t index2 = rand() % size;
    int64_t tmp = arr[index1];
    arr[index1] = arr[index2];
    arr[index2] = tmp;
  }
  return arr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_array2>:
  endbr64
  push   %r14
  test   %edi,%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L46
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L57
  mov    %ebx,%edx
  movdqa D0(%rip),%xmm0
  movdqa D10(%rip),%xmm2
  mov    %r14,%rax
  shr    $0x2,%edx
  shl    $0x4,%rdx
  add    %r14,%rdx
  nopl   0x0(%rax,%rax,1)
L36:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L36
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L46
L31:
  movslq %eax,%rdx
  mov    %eax,(%r14,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L46
  add    $0x2,%eax
  mov    %edx,0x4(%r14,%rcx,1)
  cmp    %eax,%ebx
  jle    L46
  mov    %eax,0x8(%r14,%rcx,1)
L46:
  test   %ebp,%ebp
  jle    L54
  xor    %r13d,%r13d
  nopl   (%rax)
L62:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r12
  call   <rand@plt>
  lea    (%r14,%r12,4),%rcx
  cltd
  mov    (%rcx),%esi
  idiv   %ebx
  movslq %edx,%rdx
  lea    (%r14,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  cmp    %r13d,%ebp
  jne    L62
L54:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  xor    %eax,%eax
  jmp    L31
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: byte[16]
name: disassemble_data
arguments: tag: D10
type_infered: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D10": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int64_t *random_array2(int64_t size, int64_t shuffles) {
  assert(size != 0);
  srand(time(NULL));
  int64_t *arr = malloc(size * sizeof(int64_t));
  for (int64_t i = 0; i < size; i++) {
    arr[i] = i;
  }
  for (int64_t i = 0; i < shuffles; i++) {
    int64_t index1 = rand() % size;
    int64_t index2 = rand() % size;
    int64_t tmp = arr[index1];
    arr[index1] = arr[index2];
    arr[index2] = tmp;
  }
  return arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<WatchdogResetEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40000000,-0x4(%rbp)
  je     L12
  cmpl   $0x40001000,-0x4(%rbp)
  jne    L15
L12:
  mov    $0x1,%eax
  jmp    L18
L15:
  mov    $0x0,%eax
L18:
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x8,%edx
  movslq %edx,%rdx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<WatchdogResetEnable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x8,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x2,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WatchdogResetEnable>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  add    $0x8,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x2,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: What is the c source code of the assembly code below:

```asm
<WatchdogResetEnable>:
  endbr64
  mov    %edi,%eax
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  and    $0xef,%ah
  cmp    $0x40000000,%eax
  sete   %dil
  add    $0x8,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     $0x2,%eax
  mov    %eax,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ASSERT((ui32Base == 0x40000000) || (ui32Base == 0x40001000));
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<disp_example>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr2@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr2@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr2@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <my_putstr2@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D36
datatype: string

tool: D6: A valid file map begin with the correct number of rows of the 

tool: D14: map and each rows have the same length.
Each elements of the 

tool: D5: map are '.' or 'o'.
If any other caracters are found, the map 

tool: D36: is considered as wrong and is not executed.


assistant: ```c
void disp_example() {
  my_putstr2("A valid file map begin with the correct number of rows of the ");
  my_putstr2("map and each rows have the same length.\nEach elements of the ");
  my_putstr2("map are '.' or 'o'.\nIf any other caracters are found, the map ");
  my_putstr2("is considered as wrong and is not executed.\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<disp_example>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D33(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D36(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D30(%rip),%rdi
  call   <my_putstr2@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D33
datatype: string
name: parse_data
arguments: label: D36
datatype: string
name: parse_data
arguments: label: D30
datatype: string

tool: D17: A valid file map begin with the correct number of rows of the 

tool: D33: map and each rows have the same length.
Each elements of the 

tool: D36: map are '.' or 'o'.
If any other caracters are found, the map 

tool: D30: is considered as wrong and is not executed.


assistant: ```c
void disp_example() {
  my_putstr2("A valid file map begin with the correct number of rows of the ");
  my_putstr2("map and each rows have the same length.\nEach elements of the ");
  my_putstr2("map are '.' or 'o'.\nIf any other caracters are found, the map ");
  my_putstr2("is considered as wrong and is not executed.\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<disp_example>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D33(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D16(%rip),%rdi
  call   <my_putstr2@plt>
  lea    D34(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <my_putstr2@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D33
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D34
data_type: string

tool: D2: A valid file map begin with the correct number of rows of the 

tool: D33: map and each rows have the same length.
Each elements of the 

tool: D16: map are '.' or 'o'.
If any other caracters are found, the map 

tool: D34: is considered as wrong and is not executed.


assistant: ```c
void disp_example() {
  my_putstr2("A valid file map begin with the correct number of rows of the ");
  my_putstr2("map and each rows have the same length.\nEach elements of the ");
  my_putstr2("map are '.' or 'o'.\nIf any other caracters are found, the map ");
  my_putstr2("is considered as wrong and is not executed.\n");
}
```