ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L39:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%edx
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L46:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L39
  cmpl   $0x0,-0x20(%rbp)
  je     L43
  jmp    L26
L2:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L26:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  xor    $0xffff,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L43:
  nop
  leave
  ret
```

assistant: ```c
void checksum(const void *buffer, int bytes, uint32_t *total, int finalize) {
  const uint16_t *ptr;
  int words;
  ptr = (uint16_t *)buffer;
  words = (bytes + 1) / 2;
  while (words--)
    *total += ntohs(*ptr++);
  if (finalize) {
    while (*total & 0xffff0000)
      *total = (*total >> 16) + (*total & 0xffff);
    *total = *total ^ 0xffff;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<checksum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    %ecx,%r13d
  add    $0x1,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  je     L5
  mov    %rdi,%rbx
  lea    -0x1(%rax),%eax
  lea    0x4(%rdi,%rax,4),%r12
L25:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%edi
  call   <ntohs@plt>
  add    %eax,0x0(%rbp)
  cmp    %r12,%rbx
  jne    L25
L5:
  test   %r13d,%r13d
  je     L1
  mov    0x0(%rbp),%eax
  test   $0xffff0000,%eax
  je     L46
L22:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %edx,%eax
  test   $0xffff0000,%eax
  jne    L22
L46:
  xor    $0xffff,%eax
  mov    %eax,0x0(%rbp)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void checksum(const void *buffer, int bytes, uint32_t *total, int finalize) {
  const uint16_t *ptr;
  int words;
  ptr = (uint16_t *)buffer;
  words = (bytes + 1) / 2;
  while (words--)
    *total += ntohs(*ptr++);
  if (finalize) {
    while (*total & 0xffff0000)
      *total = (*total >> 16) + (*total & 0xffff);
    *total = *total ^ 0xffff;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<checksum>:
  endbr64
  add    $0x1,%esi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%eax
  push   %rbp
  shr    $0x1f,%eax
  mov    %rdx,%rbp
  push   %rbx
  add    %esi,%eax
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  sar    %eax
  mov    %eax,%edx
  lea    (%rdi,%rdx,4),%r12
  je     L2
  nopl   0x0(%rax,%rax,1)
L32:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <ntohs@plt>
  add    %eax,0x0(%rbp)
  cmp    %r12,%rbx
  jne    L32
L2:
  test   %r13d,%r13d
  je     L30
  mov    0x0(%rbp),%eax
  test   $0xffff0000,%eax
  je     L10
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  test   $0xffff0000,%eax
  jne    L27
L10:
  xor    $0xffff,%eax
  mov    %eax,0x0(%rbp)
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void checksum(const void *buffer, int bytes, uint32_t *total, int finalize) {
  const uint16_t *ptr;
  int words;
  ptr = (uint16_t *)buffer;
  words = (bytes + 1) / 2;
  while (words--)
    *total += ntohs(*ptr++);
  if (finalize) {
    while (*total & 0xffff0000)
      *total = (*total >> 16) + (*total & 0xffff);
    *total = *total ^ 0xffff;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  add    $0x1,%esi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %esi,%eax
  push   %rbp
  shr    $0x1f,%eax
  mov    %rdx,%rbp
  push   %rbx
  add    %esi,%eax
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  sar    %eax
  mov    %eax,%edx
  lea    (%rdi,%rdx,4),%r12
  je     L23
  nopl   0x0(%rax,%rax,1)
L0:
  mov    (%rbx),%edi
  add    $0x4,%rbx
  call   <ntohs@plt>
  add    %eax,0x0(%rbp)
  cmp    %r12,%rbx
  jne    L0
L23:
  test   %r13d,%r13d
  je     L11
  mov    0x0(%rbp),%eax
  test   $0xffff0000,%eax
  je     L21
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  test   $0xffff0000,%eax
  jne    L29
L21:
  xor    $0xffff,%eax
  mov    %eax,0x0(%rbp)
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void checksum(const void *buffer, int bytes, uint32_t *total, int finalize) {
  const uint16_t *ptr;
  int words;
  ptr = (uint16_t *)buffer;
  words = (bytes + 1) / 2;
  while (words--)
    *total += ntohs(*ptr++);
  if (finalize) {
    while (*total & 0xffff0000)
      *total = (*total >> 16) + (*total & 0xffff);
    *total = *total ^ 0xffff;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<constant_expr_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string

tool: D37: constant_expr:

tool: D26: %d


assistant: ```c
void constant_expr_test() {
  int a;
  printf("constant_expr:\n");
  a = 3;
  printf("%d\n", a * 16);
  printf("%d\n", a * 1);
  printf("%d\n", a + 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<constant_expr_test>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x30,%esi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D0: constant_expr:

tool: D16: %d


assistant: ```c
void constant_expr_test() {
  int a;
  printf("constant_expr:\n");
  a = 3;
  printf("%d\n", a * 16);
  printf("%d\n", a * 1);
  printf("%d\n", a + 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<constant_expr_test>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  lea    D15(%rip),%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x30,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D15
datatype: string

tool: D16: constant_expr:

tool: D15: %d


assistant: ```c
void constant_expr_test() {
  int a;
  printf("constant_expr:\n");
  a = 3;
  printf("%d\n", a * 16);
  printf("%d\n", a * 1);
  printf("%d\n", a + 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<constant_expr_test>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  lea    D18(%rip),%rbp
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x30,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%esi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D18
type_guessed: string

tool: D16: constant_expr:

tool: D18: %d


assistant: ```c
void constant_expr_test() {
  int a;
  printf("constant_expr:\n");
  a = 3;
  printf("%d\n", a * 16);
  printf("%d\n", a * 1);
  printf("%d\n", a + 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrixMultiplication>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L39:
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L59:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L59
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L25
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixMultiplication(double **ma, double **mb, double **resultm, int dimension) {
  int i, j, k;
  for (i = 0; i < dimension; i++) {
    for (j = 0; j < dimension; j++) {
      resultm[i][j] = 0;
      for (k = 0; k < dimension; k++) {
        resultm[i][j] += mb[i][k] * ma[k][j];
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixMultiplication>:
  endbr64
  test   %ecx,%ecx
  jle    L38
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%r10
  mov    %ecx,%eax
  mov    %rdx,%r11
  lea    -0x1(%rcx),%ecx
  lea    0x8(%rdx,%rcx,8),%rbx
  mov    %eax,%eax
  lea    0x0(,%rax,8),%r8
L30:
  mov    $0x0,%ecx
L16:
  mov    %r11,%rbp
  mov    (%r11),%rax
  movq   $0x0,(%rax,%rcx,1)
  mov    $0x0,%eax
L29:
  mov    %rcx,%rdx
  add    0x0(%rbp),%rdx
  mov    (%r10),%rdi
  mov    (%r9,%rax,1),%rsi
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rcx,1),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L29
  add    $0x8,%rcx
  cmp    %r8,%rcx
  jne    L16
  add    $0x8,%r11
  add    $0x8,%r10
  cmp    %rbx,%r11
  jne    L30
  pop    %rbx
  pop    %rbp
  ret
L38:
  ret
```

assistant: ```c
void matrixMultiplication(double **ma, double **mb, double **resultm, int dimension) {
  int i, j, k;
  for (i = 0; i < dimension; i++) {
    for (j = 0; j < dimension; j++) {
      resultm[i][j] = 0;
      for (k = 0; k < dimension; k++) {
        resultm[i][j] += mb[i][k] * ma[k][j];
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrixMultiplication>:
  endbr64
  mov    %rdi,%r9
  movslq %ecx,%rdi
  test   %edi,%edi
  jle    L0
  push   %rbp
  lea    0x0(,%rdi,8),%r10
  mov    %rdx,%rbp
  xor    %r11d,%r11d
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rsi,%rbx
  nopl   (%rax)
L21:
  mov    (%rbx,%r11,8),%r8
  mov    0x0(%rbp,%r11,8),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L4:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L26:
  mov    (%r9,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rdi,%rax
  jne    L26
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rcx,%r10
  jne    L4
  add    $0x1,%r11
  cmp    %rdi,%r11
  jne    L21
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
void matrixMultiplication(double **ma, double **mb, double **resultm, int dimension) {
  int i, j, k;
  for (i = 0; i < dimension; i++) {
    for (j = 0; j < dimension; j++) {
      resultm[i][j] = 0;
      for (k = 0; k < dimension; k++) {
        resultm[i][j] += mb[i][k] * ma[k][j];
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matrixMultiplication>:
  endbr64
  mov    %rdi,%r9
  movslq %ecx,%rdi
  test   %edi,%edi
  jle    L19
  push   %rbp
  lea    0x0(,%rdi,8),%r10
  mov    %rdx,%rbp
  xor    %r11d,%r11d
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rsi,%rbx
  nopl   (%rax)
L20:
  mov    (%rbx,%r11,8),%r8
  mov    0x0(%rbp,%r11,8),%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L13:
  movq   $0x0,(%rsi)
  xor    %eax,%eax
  movapd %xmm2,%xmm1
  nopl   (%rax)
L34:
  mov    (%r9,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mulsd  (%r8,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%rdi
  jne    L34
  add    $0x8,%rcx
  add    $0x8,%rsi
  cmp    %rcx,%r10
  jne    L13
  add    $0x1,%r11
  cmp    %r11,%rdi
  jne    L20
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void matrixMultiplication(double **ma, double **mb, double **resultm, int dimension) {
  int i, j, k;
  for (i = 0; i < dimension; i++) {
    for (j = 0; j < dimension; j++) {
      resultm[i][j] = 0;
      for (k = 0; k < dimension; k++) {
        resultm[i][j] += mb[i][k] * ma[k][j];
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prompt_player>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <input_line@plt>
  movzbl (%rbx),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L235
  test   %al,%al
  je     L235
  lea    0x1(%rbx),%rbp
L47:
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <shftstr@plt>
  movzbl (%rbx),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L235
  test   %al,%al
  jne    L47
L235:
  cmpb   $0x0,(%rbx)
  je     L97
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  sub    $0x21,%eax
  cmp    $0x59,%al
  jbe    L68
  movb   $0x0,(%rdx)
  cmpb   $0x0,(%rbx)
  jne    L27
L97:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L68:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L97
  mov    %rbx,%rbp
  jmp    L104
L161:
  movb   $0x20,0x0(%rbp)
  mov    %rbp,%rdx
  test   %r12d,%r12d
  jne    L126
L139:
  lea    0x1(%rdx),%rbp
  movzbl 0x1(%rdx),%eax
  test   %al,%al
  je     L175
L104:
  sub    $0x21,%eax
  mov    %rbp,%rdx
  cmp    $0x59,%al
  jbe    L139
  movzbl 0x1(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L101
  test   %al,%al
  je     L101
  mov    $0x0,%r12d
L224:
  mov    %r12d,%esi
  add    $0x1,%r12d
  add    $0x1,%rbp
  movzbl 0x1(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L161
  test   %al,%al
  jne    L224
  jmp    L161
L126:
  not    %esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <shftstr@plt>
  movslq %r12d,%r12
  mov    %rbp,%rdx
  sub    %r12,%rdx
  jmp    L139
L175:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L48
  jmp    L97
L124:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L97
L48:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L124
  and    $0xffffffdf,%eax
  mov    %al,(%rbx)
  jmp    L124
L101:
  movb   $0x20,0x0(%rbp)
  mov    %rbp,%rdx
  jmp    L139
```

assistant: ```c
prompt_player(command) char *command;
{
  char *pos;
  int len;
  input_line(command);
  while ((*command != '\0') && (((*command) < '!') || ((*command) > 'z')))
    shftstr(command + 1, -1);
  while ((*command != '\0') && (((*(command + strlen(command) - 1)) < '!') || ((*(command + strlen(command) - 1)) > 'z')))
    *(command + strlen(command) - 1) = '\0';
  for (pos = command; *pos != '\0'; ++pos) {
    if ((((*pos) < '!') || ((*pos) > 'z'))) {
      len = 0;
      while ((*(pos + 1) != '\0') && (((*(pos + 1)) < '!') || ((*(pos + 1)) > 'z'))) {
        ++len;
        ++pos;
      }
      *pos = ' ';
      if (len) {
        shftstr(pos, -len);
        pos -= len;
      }
    }
  }
  for (pos = command; *pos != '\0'; ++pos)
    if ((*pos >= 'a') && (*pos <= 'z'))
      *pos &= 0xdf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prompt_player>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <input_line@plt>
  movzbl 0x0(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L3
  test   %al,%al
  je     L70
  lea    0x1(%rbp),%rbx
  jmp    L198
  nopl   0x0(%rax,%rax,1)
L87:
  test   %al,%al
  je     L70
L198:
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <shftstr@plt>
  movzbl 0x0(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  ja     L87
L3:
  test   %al,%al
  je     L70
  nopl   0x0(%rax,%rax,1)
L194:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rdx
  movzbl (%rdx),%eax
  sub    $0x21,%eax
  cmp    $0x59,%al
  jbe    L73
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  jne    L194
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L73:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L70
  mov    %rbp,%rbx
  jmp    L123
  nopl   (%rax)
L143:
  add    $0x1,%rbx
  test   %al,%al
  je     L15
L123:
  lea    -0x21(%rax),%edx
  movzbl 0x1(%rbx),%eax
  cmp    $0x59,%dl
  jbe    L143
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L173
  test   %al,%al
  je     L173
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L181:
  movzbl 0x2(%rbx),%eax
  mov    %r12d,%esi
  add    $0x1,%rbx
  add    $0x1,%r12d
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L131
  test   %al,%al
  jne    L181
L131:
  movb   $0x20,(%rbx)
  movslq %r12d,%r12
  mov    %rbx,%rdi
  not    %esi
  xor    %eax,%eax
  sub    %r12,%rbx
  call   <shftstr@plt>
  movzbl 0x1(%rbx),%eax
  jmp    L143
  xchg   %ax,%ax
L189:
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L118
  and    $0xffffffdf,%eax
  mov    %al,0x0(%rbp)
L118:
  add    $0x1,%rbp
L15:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L189
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L173:
  movb   $0x20,(%rbx)
  jmp    L143
```

assistant: ```c
prompt_player(command) char *command;
{
  char *pos;
  int len;
  input_line(command);
  while ((*command != '\0') && (((*command) < '!') || ((*command) > 'z')))
    shftstr(command + 1, -1);
  while ((*command != '\0') && (((*(command + strlen(command) - 1)) < '!') || ((*(command + strlen(command) - 1)) > 'z')))
    *(command + strlen(command) - 1) = '\0';
  for (pos = command; *pos != '\0'; ++pos) {
    if ((((*pos) < '!') || ((*pos) > 'z'))) {
      len = 0;
      while ((*(pos + 1) != '\0') && (((*(pos + 1)) < '!') || ((*(pos + 1)) > 'z'))) {
        ++len;
        ++pos;
      }
      *pos = ' ';
      if (len) {
        shftstr(pos, -len);
        pos -= len;
      }
    }
  }
  for (pos = command; *pos != '\0'; ++pos)
    if ((*pos >= 'a') && (*pos <= 'z'))
      *pos &= 0xdf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prompt_player>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <input_line@plt>
  movzbl 0x0(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L197
  test   %al,%al
  je     L229
  lea    0x1(%rbp),%rbx
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L124:
  test   %al,%al
  je     L229
L68:
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <shftstr@plt>
  movzbl 0x0(%rbp),%eax
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  ja     L124
L197:
  test   %al,%al
  je     L229
  nopl   0x0(%rax,%rax,1)
L188:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rbp,%rax,1),%rdx
  movzbl (%rdx),%eax
  sub    $0x21,%eax
  cmp    $0x59,%al
  jbe    L2
  movb   $0x0,(%rdx)
  cmpb   $0x0,0x0(%rbp)
  jne    L188
L229:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L229
  mov    %rbp,%rbx
  jmp    L71
  nopl   (%rax)
L69:
  add    $0x1,%rbx
  test   %al,%al
  je     L32
L71:
  lea    -0x21(%rax),%edx
  movzbl 0x1(%rbx),%eax
  cmp    $0x59,%dl
  jbe    L69
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L104
  test   %al,%al
  je     L104
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl 0x2(%rbx),%eax
  mov    %r12d,%esi
  add    $0x1,%rbx
  add    $0x1,%r12d
  lea    -0x21(%rax),%edx
  cmp    $0x59,%dl
  jbe    L66
  test   %al,%al
  jne    L12
L66:
  movb   $0x20,(%rbx)
  movslq %r12d,%r12
  mov    %rbx,%rdi
  not    %esi
  sub    %r12,%rbx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <shftstr@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L71
  nopl   0x0(%rax,%rax,1)
L32:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L229
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L204
L76:
  and    $0xffffffdf,%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L229
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  jbe    L76
L204:
  add    $0x1,%rbp
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L104:
  movb   $0x20,(%rbx)
  jmp    L69
```

assistant: ```c
prompt_player(command) char *command;
{
  char *pos;
  int len;
  input_line(command);
  while ((*command != '\0') && (((*command) < '!') || ((*command) > 'z')))
    shftstr(command + 1, -1);
  while ((*command != '\0') && (((*(command + strlen(command) - 1)) < '!') || ((*(command + strlen(command) - 1)) > 'z')))
    *(command + strlen(command) - 1) = '\0';
  for (pos = command; *pos != '\0'; ++pos) {
    if ((((*pos) < '!') || ((*pos) > 'z'))) {
      len = 0;
      while ((*(pos + 1) != '\0') && (((*(pos + 1)) < '!') || ((*(pos + 1)) > 'z'))) {
        ++len;
        ++pos;
      }
      *pos = ' ';
      if (len) {
        shftstr(pos, -len);
        pos -= len;
      }
    }
  }
  for (pos = command; *pos != '\0'; ++pos)
    if ((*pos >= 'a') && (*pos <= 'z'))
      *pos &= 0xdf;
}
```
user: What is the c source code of the assembly code below:

```asm
<LSR_absx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x0,%eax
  call   <LSR_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LSR_absx(void) {
  c64_memAbsoluteAddrX();
  LSR_();
}
```
user: What is the c source code of the assembly code below:

```asm
<LSR_absx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x0,%eax
  call   <LSR_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LSR_absx(void) {
  c64_memAbsoluteAddrX();
  LSR_();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<LSR_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memAbsoluteAddrX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <LSR_@plt>
```

assistant: ```c
void LSR_absx(void) {
  c64_memAbsoluteAddrX();
  LSR_();
}
```
user: What is the c source code of the assembly code below?

```asm
<LSR_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memAbsoluteAddrX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <LSR_@plt>
```

assistant: ```c
void LSR_absx(void) {
  c64_memAbsoluteAddrX();
  LSR_();
}
```