ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_response>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
L52:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x6e,%al
  je     L15
L26:
  jg     L44
  cmp    $0x4e,%al
  je     L15
  cmp    $0x59,%al
  jne    L52
L36:
  mov    $0x79,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L44:
  cmp    $0x79,%al
  je     L36
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x6e,%al
  jne    L26
L15:
  mov    $0x6e,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: %s (y/n)?

assistant: ```c
extern int get_response(char *question) {
  printf("%s (y/n)?", question);
  while (true) {
    char c = getchar();
    switch (c) {
    case 'y':
    case 'Y':
      putchar('y');
      return 0;
    case 'n':
    case 'N':
    case EOF:
      putchar('n');
      return 1;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_response>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
L19:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x6e,%al
  je     L25
L4:
  jg     L28
  cmp    $0x4e,%al
  je     L25
  cmp    $0x59,%al
  jne    L19
L52:
  mov    $0x79,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L28:
  cmp    $0x79,%al
  je     L52
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x6e,%al
  jne    L4
L25:
  mov    $0x6e,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: %s (y/n)?

assistant: ```c
extern int get_response(char *question) {
  printf("%s (y/n)?", question);
  while (true) {
    char c = getchar();
    switch (c) {
    case 'y':
    case 'Y':
      putchar('y');
      return 0;
    case 'n':
    case 'N':
    case EOF:
      putchar('n');
      return 1;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_mtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
L2:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: 


assistant: ```c
void get_mtime(int fd, struct stat *st, int do_write) {
  if (do_write)
    ASSERT(write(fd, "\n", 1) == 1);
  ASSERT(fstat(fd, st) == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_mtime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edx,%edx
  jne    L1
L19:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <fstat@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x1,%edx
  lea    D3(%rip),%rsi
  call   <write@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: 


assistant: ```c
void get_mtime(int fd, struct stat *st, int do_write) {
  if (do_write)
    ASSERT(write(fd, "\n", 1) == 1);
  ASSERT(fstat(fd, st) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_mtime>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L7
L9:
  mov    %ebp,%edi
  mov    %r12,%rsi
  call   <fstat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <ASSERT@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edx
  lea    D2(%rip),%rsi
  call   <write@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <ASSERT@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: 


assistant: ```c
void get_mtime(int fd, struct stat *st, int do_write) {
  if (do_write)
    ASSERT(write(fd, "\n", 1) == 1);
  ASSERT(fstat(fd, st) == 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_mtime>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L8
L13:
  mov    %ebp,%edi
  mov    %r12,%rsi
  call   <fstat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <ASSERT@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  call   <write@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <ASSERT@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: 


assistant: ```c
void get_mtime(int fd, struct stat *st, int do_write) {
  if (do_write)
    ASSERT(write(fd, "\n", 1) == 1);
  ASSERT(fstat(fd, st) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdimpl_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0xa,-0x8(%rbp)
  jne    L24
  cmpl   $0x0,-0x4(%rbp)
  jns    L24
  mov    -0x4(%rbp),%eax
  neg    %eax
  cltq
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <_xtoa@plt>
  jmp    L27
L24:
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <_xtoa@plt>
L27:
  leave
  ret
```

assistant: ```c
char *stdimpl_itoa(int v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<stdimpl_itoa>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xa,%edx
  jne    L24
  test   %edi,%edi
  jns    L24
  neg    %edi
  movslq %edi,%rdi
  mov    $0x1,%ecx
  call   <_xtoa@plt>
  jmp    L2
L24:
  movslq %edi,%rdi
  mov    $0x0,%ecx
  call   <_xtoa@plt>
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *stdimpl_itoa(int v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stdimpl_itoa>:
  endbr64
  cmp    $0xa,%edx
  jne    L15
  test   %edi,%edi
  jns    L15
  neg    %edi
  mov    $0x1,%ecx
  movslq %edi,%rdi
  jmp    1050 <_xtoa@plt>
  nopl   0x0(%rax)
L15:
  movslq %edi,%rdi
  xor    %ecx,%ecx
  jmp    1050 <_xtoa@plt>
```

assistant: ```c
char *stdimpl_itoa(int v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdimpl_itoa>:
  endbr64
  cmp    $0xa,%edx
  jne    L14
  test   %edi,%edi
  jns    L14
  neg    %edi
  mov    $0x1,%ecx
  movslq %edi,%rdi
  jmp    1050 <_xtoa@plt>
  nopl   0x0(%rax)
L14:
  movslq %edi,%rdi
  xor    %ecx,%ecx
  jmp    1050 <_xtoa@plt>
```

assistant: ```c
char *stdimpl_itoa(int v, char *string, int r) {
  if ((r == 10) && (v < 0)) {
    return _xtoa((unsigned long)(-v), string, r, 1);
  }
  return _xtoa((unsigned long)(v), string, r, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<handlemsg_worker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L2
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L34
L2:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <netd_sendmsg@plt>
L34:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1,%al
  jne    L33
  mov    $0xfffff830,%eax
  jmp    L22
L33:
  mov    $0x0,%eax
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: Got unexpected message from %d:%d: %s


assistant: ```c
int handlemsg_worker(int from, char *msg, int len, void **input) {
  int *in = (int *)input;
  if (from != in[0]) {
    printf("Got unexpected message from %d:%d: %s\n", from, len, msg);
  } else {
    netd_sendmsg(in[1], msg, len);
  }
  if (msg[0] == '\1')
    return -2000;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<handlemsg_worker>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    %edi,(%rcx)
  je     L10
  mov    %rsi,%rcx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
L12:
  cmpb   $0x1,(%rbx)
  mov    $0x0,%eax
  mov    $0xfffff830,%edx
  cmove  %edx,%eax
  pop    %rbx
  ret
L10:
  mov    0x4(%rcx),%edi
  call   <netd_sendmsg@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Got unexpected message from %d:%d: %s


assistant: ```c
int handlemsg_worker(int from, char *msg, int len, void **input) {
  int *in = (int *)input;
  if (from != in[0]) {
    printf("Got unexpected message from %d:%d: %s\n", from, len, msg);
  } else {
    netd_sendmsg(in[1], msg, len);
  }
  if (msg[0] == '\1')
    return -2000;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<handlemsg_worker>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    %edi,(%rcx)
  je     L4
  mov    %rsi,%rcx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0xfffff830,%edx
  cmpb   $0x1,(%rbx)
  cmove  %edx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  mov    0x4(%rcx),%edi
  call   <netd_sendmsg@plt>
  xor    %eax,%eax
  mov    $0xfffff830,%edx
  cmpb   $0x1,(%rbx)
  cmove  %edx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: Got unexpected message from %d:%d: %s


assistant: ```c
int handlemsg_worker(int from, char *msg, int len, void **input) {
  int *in = (int *)input;
  if (from != in[0]) {
    printf("Got unexpected message from %d:%d: %s\n", from, len, msg);
  } else {
    netd_sendmsg(in[1], msg, len);
  }
  if (msg[0] == '\1')
    return -2000;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<handlemsg_worker>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    %edi,(%rcx)
  je     L9
  mov    %rsi,%rcx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0xfffff830,%edx
  cmpb   $0x1,(%rbx)
  cmove  %edx,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L9:
  mov    0x4(%rcx),%edi
  call   <netd_sendmsg@plt>
  xor    %eax,%eax
  mov    $0xfffff830,%edx
  cmpb   $0x1,(%rbx)
  cmove  %edx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Got unexpected message from %d:%d: %s


assistant: ```c
int handlemsg_worker(int from, char *msg, int len, void **input) {
  int *in = (int *)input;
  if (from != in[0]) {
    printf("Got unexpected message from %d:%d: %s\n", from, len, msg);
  } else {
    netd_sendmsg(in[1], msg, len);
  }
  if (msg[0] == '\1')
    return -2000;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_Adjoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D60(%rip),%xmm0
  movsd  %xmm0,-0x1b0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x1a8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x1a0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x198(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x190(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x188(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x180(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x178(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x170(%rbp)
  movsd  D60(%rip),%xmm0
  movsd  %xmm0,-0x168(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x160(%rbp)
  movsd  D58(%rip),%xmm0
  movsd  %xmm0,-0x158(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x150(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x148(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x140(%rbp)
  movsd  D60(%rip),%xmm0
  movsd  %xmm0,-0x138(%rbp)
  lea    -0x130(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x24,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x130(%rbp),%rdx
  lea    -0x1b0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Adjoint@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x1b8(%rbp)
  jmp    L17
L28:
  movl   $0x0,-0x1b4(%rbp)
  jmp    L8
L1:
  mov    -0x1b4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1b8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  mov    -0x130(%rbp,%rax,8),%rax
  movq   %rax,%xmm0
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x1b4(%rbp)
L8:
  cmpl   $0x5,-0x1b4(%rbp)
  jle    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1b8(%rbp)
L17:
  cmpl   $0x5,-0x1b8(%rbp)
  jle    L28
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D60
type_infered: byte[8]
name: read_data
arguments: tag: D10
type_infered: byte[8]
name: read_data
arguments: tag: D58
type_infered: byte[8]
name: read_data
arguments: tag: D23
type_infered: string
name: read_data
arguments: tag: D48
type_infered: string

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D23: AdT:

tool: D48: %lf  

assistant: ```c
void test_Adjoint() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double AdT[6][6] = {{0}};
  Adjoint(T, AdT);
  int i;
  int j;
  printf("AdT:\n");
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      printf("%lf  ", AdT[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_Adjoint>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    D11(%rip),%rax
  mov    %rax,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movsd  %xmm0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  mov    D13(%rip),%rax
  mov    %rax,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movsd  %xmm0,0x78(%rsp)
  lea    0x80(%rsp),%rdi
  mov    $0x24,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    0x80(%rsp),%rbp
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <Adjoint@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  lea    0x1a0(%rsp),%r13
  lea    D20(%rip),%r12
L0:
  mov    $0x0,%ebx
L6:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x30,%rbp
  cmp    %r13,%rbp
  jne    L0
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D11
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D13
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D47
datatype: string
name: extract_symbolic_data
arguments: label: D20
datatype: string

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D47: AdT:

tool: D20: %lf  

assistant: ```c
void test_Adjoint() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double AdT[6][6] = {{0}};
  Adjoint(T, AdT);
  int i;
  int j;
  printf("AdT:\n");
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      printf("%lf  ", AdT[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_Adjoint>:
  endbr64
  push   %r13
  mov    $0x24,%ecx
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  movsd  D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  lea    0x80(%rsp),%rdi
  lea    0x80(%rsp),%rbp
  mov    %rbp,%rsi
  movsd  %xmm0,(%rsp)
  lea    0x1a0(%rsp),%r13
  mov    %rax,0x30(%rsp)
  mov    D42(%rip),%rax
  movsd  %xmm0,0x48(%rsp)
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  movsd  %xmm0,0x78(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  call   <Adjoint@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L6
  mov    $0xa,%edi
  add    $0x30,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L9
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D8
data_type: byte[8]
name: read_data
arguments: data_tag: D15
data_type: byte[8]
name: read_data
arguments: data_tag: D42
data_type: byte[8]
name: read_data
arguments: data_tag: D37
data_type: string

tool: D5: %lf  

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D37: AdT:

assistant: ```c
void test_Adjoint() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double AdT[6][6] = {{0}};
  Adjoint(T, AdT);
  int i;
  int j;
  printf("AdT:\n");
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      printf("%lf  ", AdT[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_Adjoint>:
  endbr64
  push   %r13
  mov    $0x24,%ecx
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  movq   D18(%rip),%xmm1
  movq   D59(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  movapd D30(%rip),%xmm2
  lea    0x80(%rsp),%rdi
  lea    0x80(%rsp),%rbp
  movaps %xmm1,0x30(%rsp)
  movapd D38(%rip),%xmm1
  mov    %rbp,%rsi
  lea    0x1a0(%rsp),%r13
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm1,0x40(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rdi
  movaps %xmm2,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm1,0x70(%rsp)
  call   <Adjoint@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L26:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x6,%rbx
  jne    L1
  mov    $0xa,%edi
  add    $0x30,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L26
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
datatype: string
name: extract_symbolic_data
arguments: tag: D18
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D59
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D30
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D38
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D19
datatype: string

tool: D31: %lf  

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D19: AdT:

assistant: ```c
void test_Adjoint() {
  double T[4][4] = {1, 0, 0, 0, 0, 0, -1, 0, 0, 1, 0, 3, 0, 0, 0, 1};
  double AdT[6][6] = {{0}};
  Adjoint(T, AdT);
  int i;
  int j;
  printf("AdT:\n");
  for (i = 0; i < 6; i++) {
    for (j = 0; j < 6; j++) {
      printf("%lf  ", AdT[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<comm_rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <i_crdy@plt>
  test   %rax,%rax
  je     L10
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  cltq
  shl    $0x3,%rax
  add    $0x100041,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L15
L10:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int comm_rec(int no, unsigned long *imessage, int tries) {
  if (i_crdy(no, tries)) {
    *imessage = *((unsigned long *)0x100041 + (no * 0x10));
    return 1;
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<comm_rec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%esi
  call   <i_crdy@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
  shl    $0x4,%ebx
  movslq %ebx,%rbx
  mov    0x100041(,%rbx,8),%rax
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int comm_rec(int no, unsigned long *imessage, int tries) {
  if (i_crdy(no, tries)) {
    *imessage = *((unsigned long *)0x100041 + (no * 0x10));
    return 1;
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<comm_rec>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <i_crdy@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L6
  shl    $0x4,%ebx
  movslq %ebx,%rbx
  mov    0x100041(,%rbx,8),%rax
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int comm_rec(int no, unsigned long *imessage, int tries) {
  if (i_crdy(no, tries)) {
    *imessage = *((unsigned long *)0x100041 + (no * 0x10));
    return 1;
  } else
    return 0;
}
```