ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0x4(%rsp)
  cmp    %edx,%esi
  jge    L113
  mov    %rdi,%r14
  mov    %esi,%r15d
  mov    %edx,%r12d
  lea    0x1(%rsi),%ebx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    (%rax),%r13d
  jmp    L14
L17:
  sub    $0x1,%r12d
L14:
  movslq %r12d,%rax
  lea    (%r14,%rax,4),%rsi
  cmp    %r13d,(%rsi)
  jg     L17
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rbp
  cmp    0x0(%rbp),%r13d
  jle    L43
  cmp    %r12d,%ebx
  jge    L43
  lea    0x4(%r14,%rax,1),%rax
L81:
  add    $0x1,%ebx
  mov    %rax,%rbp
  add    $0x4,%rax
  cmp    %r13d,0x0(%rbp)
  jge    L43
  cmp    %ebx,%r12d
  jg     L81
L43:
  cmp    %ebx,%r12d
  jle    L127
  mov    %rbp,%rdi
  call   <swap@plt>
  cmp    %r13d,0x0(%rbp)
  je     L140
  add    $0x1,%ebx
  jmp    L14
L140:
  sub    $0x1,%r12d
  jmp    L14
L127:
  mov    0x8(%rsp),%rdi
  call   <swap@plt>
  lea    -0x1(%rbx),%edx
  cmp    %r15d,%edx
  jg     L124
L90:
  lea    0x1(%r12),%esi
  cmp    0x4(%rsp),%esi
  jl     L42
L113:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L124:
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <quick_sort>
  jmp    L90
L42:
  mov    0x4(%rsp),%edx
  mov    %r14,%rdi
  call   <quick_sort>
  jmp    L113
```

assistant: ```c
void quick_sort(int a[], int left, int right) {
  int i = left + 1, j = right;
  int key = a[left];
  if (left >= right)
    return;
  while (1) {
    while (a[j] > key)
      j--;
    while (a[i] < key && i < j)
      i++;
    if (i >= j)
      break;
    swap(&a[i], &a[j]);
    if (a[i] == key)
      j--;
    else
      i++;
  }
  swap(&a[left], &a[j]);
  if (left < i - 1)
    quick_sort(a, left, i - 1);
  if (j + 1 < right)
    quick_sort(a, j + 1, right);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_sort>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x4(%rsp)
  mov    %eax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
L114:
  movslq 0x4(%rsp),%rax
  mov    %rax,%rcx
  lea    0x1(%rax),%ebx
  lea    (%r14,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    (%rax),%ebp
  cmp    0x10(%rsp),%ecx
  jge    L8
  mov    0x10(%rsp),%r12d
  mov    0x18(%rsp),%r13
  movslq %ebx,%r8
  nopw   0x0(%rax,%rax,1)
L64:
  lea    0x0(,%r8,4),%rax
  lea    (%r14,%r13,4),%rsi
  lea    (%r14,%rax,1),%r15
  mov    (%r15),%edi
  cmp    %ebp,(%rsi)
  jg     L109
  cmp    %edi,%ebp
  jle    L11
  cmp    %r12d,%ebx
  jge    L96
  lea    0x4(%r14,%rax,1),%rax
  jmp    L50
  nop
L86:
  add    $0x4,%rax
  cmp    %ebx,%r12d
  je     L107
L50:
  mov    %ebx,%r8d
  mov    %rax,%r15
  add    $0x1,%ebx
  cmp    %ebp,(%rax)
  jl     L86
L11:
  cmp    %r12d,%ebx
  jge    L96
  mov    %r15,%rdi
  call   <swap@plt>
  cmp    %ebp,(%r15)
  je     L27
  add    $0x1,%ebx
  movslq %ebx,%r8
  jmp    L64
L109:
  sub    $0x1,%r12d
  movslq %r12d,%r13
  jmp    L64
  nopl   0x0(%rax)
L27:
  sub    $0x1,%r12d
  movslq %ebx,%r8
  movslq %r12d,%r13
  jmp    L64
L96:
  lea    -0x1(%rbx),%r8d
L107:
  mov    0x8(%rsp),%rdi
  mov    %r8d,0x14(%rsp)
  call   <swap@plt>
  mov    0x14(%rsp),%r8d
  cmp    %r8d,0x4(%rsp)
  jl     L72
L9:
  lea    0x1(%r12),%eax
  mov    %eax,0x4(%rsp)
  cmp    0x10(%rsp),%eax
  jl     L114
L8:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  mov    0x4(%rsp),%esi
  mov    %r8d,%edx
  mov    %r14,%rdi
  call   <quick_sort>
  jmp    L9
```

assistant: ```c
void quick_sort(int a[], int left, int right) {
  int i = left + 1, j = right;
  int key = a[left];
  if (left >= right)
    return;
  while (1) {
    while (a[j] > key)
      j--;
    while (a[i] < key && i < j)
      i++;
    if (i >= j)
      break;
    swap(&a[i], &a[j]);
    if (a[i] == key)
      j--;
    else
      i++;
  }
  swap(&a[left], &a[j]);
  if (left < i - 1)
    quick_sort(a, left, i - 1);
  if (j + 1 < right)
    quick_sort(a, j + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quick_sort>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x4(%rsp)
  mov    %eax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
L130:
  movslq 0x4(%rsp),%rax
  mov    %rax,%rcx
  lea    0x1(%rax),%ebx
  lea    (%r14,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  mov    (%rax),%ebp
  cmp    0x10(%rsp),%ecx
  jge    L63
  mov    0x10(%rsp),%r12d
  mov    0x18(%rsp),%r13
  movslq %ebx,%r8
  nopw   0x0(%rax,%rax,1)
L131:
  lea    0x0(,%r8,4),%rax
  lea    (%r14,%r13,4),%rsi
  lea    (%r14,%rax,1),%r15
  mov    (%r15),%edi
  cmp    %ebp,(%rsi)
  jg     L115
  cmp    %edi,%ebp
  jle    L60
  cmp    %r12d,%ebx
  jge    L118
  lea    0x4(%r14,%rax,1),%rax
  jmp    L58
  nop
L146:
  add    $0x4,%rax
  cmp    %ebx,%r12d
  je     L49
L58:
  mov    %ebx,%r8d
  mov    %rax,%r15
  add    $0x1,%ebx
  cmp    %ebp,(%rax)
  jl     L146
L60:
  cmp    %r12d,%ebx
  jge    L118
  mov    %r15,%rdi
  call   <swap@plt>
  cmp    %ebp,(%r15)
  je     L121
  add    $0x1,%ebx
  movslq %ebx,%r8
  jmp    L131
L115:
  sub    $0x1,%r12d
  movslq %r12d,%r13
  jmp    L131
  nopl   0x0(%rax)
L121:
  sub    $0x1,%r12d
  movslq %ebx,%r8
  movslq %r12d,%r13
  jmp    L131
L118:
  lea    -0x1(%rbx),%r8d
L49:
  mov    0x8(%rsp),%rdi
  mov    %r8d,0x14(%rsp)
  call   <swap@plt>
  mov    0x14(%rsp),%r8d
  cmp    %r8d,0x4(%rsp)
  jl     L61
L89:
  lea    0x1(%r12),%eax
  mov    %eax,0x4(%rsp)
  cmp    0x10(%rsp),%eax
  jl     L130
L63:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  mov    0x4(%rsp),%esi
  mov    %r8d,%edx
  mov    %r14,%rdi
  call   <quick_sort>
  jmp    L89
```

assistant: ```c
void quick_sort(int a[], int left, int right) {
  int i = left + 1, j = right;
  int key = a[left];
  if (left >= right)
    return;
  while (1) {
    while (a[j] > key)
      j--;
    while (a[i] < key && i < j)
      i++;
    if (i >= j)
      break;
    swap(&a[i], &a[j]);
    if (a[i] == key)
      j--;
    else
      i++;
  }
  swap(&a[left], &a[j]);
  if (left < i - 1)
    quick_sort(a, left, i - 1);
  if (j + 1 < right)
    quick_sort(a, j + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  mov    $0x0,%eax
  jmp    L27
L24:
  mov    $0x1,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int g(int b) {
  if (b != 0) {
    b = b > 0 ? b : -b;
    if (b != 0)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<g>:
  endbr64
  test   %edi,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int g(int b) {
  if (b != 0) {
    b = b > 0 ? b : -b;
    if (b != 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  sete   %al
  ret
```

assistant: ```c
int g(int b) {
  if (b != 0) {
    b = b > 0 ? b : -b;
    if (b != 0)
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<g>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  sete   %al
  ret
```

assistant: ```c
int g(int b) {
  if (b != 0) {
    b = b > 0 ? b : -b;
    if (b != 0)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7274730973696854,%rax
  movabs $0x973616809676e69,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x726f770965766966,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x2e7364,-0x18(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <count_tabs@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D9: 
== test1 =====================================================

tool: D11: |%s|


tool: D13: Number of tabs is %i.


assistant: ```c
void test1(void) {
  char string[] = "This\tstring\thas\tfive\twords.";
  int tabs;
  printf("\n== test1 =====================================================\n");
  printf("|%s|\n", string);
  tabs = count_tabs(string);
  printf("Number of tabs is %i.\n", tabs);
}
```
user: What is the c source code of the assembly code below?

```asm
<test1>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x7274730973696854,%rax
  movabs $0x973616809676e69,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x726f770965766966,%rax
  mov    %rax,0x10(%rsp)
  movl   $0x2e7364,0x18(%rsp)
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <count_tabs@plt>
  mov    %eax,%esi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D20
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string

tool: D23: 
== test1 =====================================================

tool: D20: |%s|


tool: D27: Number of tabs is %i.


assistant: ```c
void test1(void) {
  char string[] = "This\tstring\thas\tfive\twords.";
  int tabs;
  printf("\n== test1 =====================================================\n");
  printf("|%s|\n", string);
  tabs = count_tabs(string);
  printf("Number of tabs is %i.\n", tabs);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test1>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x2e7364,0x18(%rsp)
  movabs $0x726f770965766966,%rax
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <count_tabs@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: byte[16]
name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D8
type_infered: string

tool: D34: 
== test1 =====================================================

tool: {"D17": [0x54,0x68,0x69,0x73,0x09,0x73,0x74,0x72,0x69,0x6e,0x67,0x09,0x68,0x61,0x73,0x09]}

tool: D14: |%s|


tool: D8: Number of tabs is %i.


assistant: ```c
void test1(void) {
  char string[] = "This\tstring\thas\tfive\twords.";
  int tabs;
  printf("\n== test1 =====================================================\n");
  printf("|%s|\n", string);
  tabs = count_tabs(string);
  printf("Number of tabs is %i.\n", tabs);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test1>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D24(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x2e7364,0x18(%rsp)
  movabs $0x726f770965766966,%rax
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <count_tabs@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
datatype: string
name: disassemble_data
arguments: tag: D24
datatype: byte[16]
name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D10: 
== test1 =====================================================

tool: {"D24": [0x54,0x68,0x69,0x73,0x09,0x73,0x74,0x72,0x69,0x6e,0x67,0x09,0x68,0x61,0x73,0x09]}

tool: D23: |%s|


tool: D11: Number of tabs is %i.


assistant: ```c
void test1(void) {
  char string[] = "This\tstring\thas\tfive\twords.";
  int tabs;
  printf("\n== test1 =====================================================\n");
  printf("|%s|\n", string);
  tabs = count_tabs(string);
  printf("Number of tabs is %i.\n", tabs);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L7:
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x2,-0xc(%rbp)
  jle    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x8(%rbp),%eax
  jmp    L39
L31:
  mov    $0x0,%eax
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4: %i,

assistant: ```c
int main() {
  int ret = 0;
  int i;
  for (i = 0; i < 3; i++) {
    int ret = 1;
    ret++;
    printf("%i,", ret);
  }
  printf("\n");
  if (ret == 0)
    return ret;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %i,

assistant: ```c
int main() {
  int ret = 0;
  int i;
  for (i = 0; i < 3; i++) {
    int ret = 1;
    ret++;
    printf("%i,", ret);
  }
  printf("\n");
  if (ret == 0)
    return ret;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x2,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: %i,

assistant: ```c
int main() {
  int ret = 0;
  int i;
  for (i = 0; i < 3; i++) {
    int ret = 1;
    ret++;
    printf("%i,", ret);
  }
  printf("\n");
  if (ret == 0)
    return ret;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0x2,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: %i,

assistant: ```c
int main() {
  int ret = 0;
  int i;
  for (i = 0; i < 3; i++) {
    int ret = 1;
    ret++;
    printf("%i,", ret);
  }
  printf("\n");
  if (ret == 0)
    return ret;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L85
L89:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L73
L19:
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x14(%rbp)
L73:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L19
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L85:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L89
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L88:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L52:
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L52
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L50:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L88
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D69
type_infered: string
name: disassemble_data
arguments: tag: D21
type_infered: string
name: disassemble_data
arguments: tag: D38
type_infered: string

tool: D12: Digite o tamanho:

tool: D8: %d

tool: D69: #

tool: D21: 


tool: D38: pause

assistant: ```c
int main() {
  printf("Digite o tamanho:");
  int tam;
  scanf("%d", &tam);
  for (int i = 0; i < tam; i++) {
    for (int k = tam; k > i; k--) {
      printf("#");
    }
    printf("\n");
  }
  for (int x = 0; x < tam; x++) {
    for (int z = 0; z <= x; z++) {
      printf("#");
    }
    printf("\n");
  }
  system("pause");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  mov    $0x0,%ebp
  lea    D13(%rip),%r12
  lea    D1(%rip),%r13
  test   %ebx,%ebx
  jg     L51
L117:
  lea    D4(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L111:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L111
L83:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%ebx
  cmp    %ebp,%ebx
  jle    L81
L51:
  cmp    %ebp,%ebx
  jg     L111
  jmp    L83
L81:
  test   %ebx,%ebx
  jle    L117
  mov    $0x0,%ebp
  lea    D13(%rip),%r12
  lea    D1(%rip),%r13
  jmp    L20
L108:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L108
L114:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L117
L20:
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jns    L108
  jmp    L114
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D12: Digite o tamanho:

tool: D3: %d

tool: D13: #

tool: D1: 


tool: D4: pause

assistant: ```c
int main() {
  printf("Digite o tamanho:");
  int tam;
  scanf("%d", &tam);
  for (int i = 0; i < tam; i++) {
    for (int k = tam; k > i; k--) {
      printf("#");
    }
    printf("\n");
  }
  for (int x = 0; x < tam; x++) {
    for (int z = 0; z <= x; z++) {
      printf("#");
    }
    printf("\n");
  }
  system("pause");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%rdi
  lea    D40(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D36(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L24
  nopl   0x0(%rax)
L59:
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L59
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r12d,%ebx
  jg     L59
  test   %ebx,%ebx
  jle    L24
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L44:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %r12d,%ebx
  jle    L64
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L44
L24:
  lea    D30(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_infered: string
name: retrieve_data
arguments: data_tag: D40
type_infered: string
name: retrieve_data
arguments: data_tag: D36
type_infered: string
name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D30
type_infered: string

tool: D25: Digite o tamanho:

tool: D40: 


tool: D36: #

tool: D44: %d

tool: D30: pause

assistant: ```c
int main() {
  printf("Digite o tamanho:");
  int tam;
  scanf("%d", &tam);
  for (int i = 0; i < tam; i++) {
    for (int k = tam; k > i; k--) {
      printf("#");
    }
    printf("\n");
  }
  for (int x = 0; x < tam; x++) {
    for (int z = 0; z <= x; z++) {
      printf("#");
    }
    printf("\n");
  }
  system("pause");
  return 0;
}
```