ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strjoin>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  or     %rsi,%r13
  je     L21
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L28
  test   %rdi,%rdi
  je     L4
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcat@plt>
L21:
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  pop    %rbp
  mov    %rsi,%rdi
  pop    %r12
  pop    %r13
  jmp    10d0 <strdup@plt>
  nopl   (%rax)
L28:
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <strdup@plt>
```

assistant: ```c
char *strjoin(const char *str1, const char *str2) {
  if (!str1 && !str2)
    return NULL;
  if (!str2)
    return strdup(str1);
  if (!str1)
    return strdup(str2);
  char *s = malloc(strlen(str1) + strlen(str2) + 1);
  strcpy(s, str1);
  strcat(s, str2);
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,-0x78(%rbp)
  movabs $0x6567656765676567,%rax
  movabs $0x65676567676567,%rdx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  movl   $0x73737361,(%rax)
  movw   $0x73,0x4(%rax)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D31
data_type: string

tool: D8: algelge

tool: D14: %lu


tool: 

assistant: ```c
int main(int argc, char **argv) {
  char *a = "algelge";
  char pre[100] = {"gegegegegeggege"};
  printf("%lu\n", strlen(a));
  a = "";
  printf("%lu\n", strlen(a));
  strcpy(pre, "assss");
  printf("%s\n", pre);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x6567656765676567,%rax
  movabs $0x65676567676567,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    $0x7,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  movl   $0x73737361,(%rsp)
  movw   $0x73,0x4(%rsp)
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: %lu


assistant: ```c
int main(int argc, char **argv) {
  char *a = "algelge";
  char pre[100] = {"gegegegegeggege"};
  printf("%lu\n", strlen(a));
  a = "";
  printf("%lu\n", strlen(a));
  strcpy(pre, "assss");
  printf("%s\n", pre);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    $0x7,%esi
  mov    %rbp,%rdi
  sub    $0x70,%rsp
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x73,%eax
  mov    %rsp,%rdi
  movl   $0x73737361,(%rsp)
  mov    %ax,0x4(%rsp)
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string
name: read_data
arguments: label: D11
type_infered: byte[16]

tool: D3: %lu


tool: {"D11": [0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x67,0x65,0x67,0x65,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  char *a = "algelge";
  char pre[100] = {"gegegegegeggege"};
  printf("%lu\n", strlen(a));
  a = "";
  printf("%lu\n", strlen(a));
  strcpy(pre, "assss");
  printf("%s\n", pre);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    $0x7,%esi
  mov    %rbp,%rdi
  sub    $0x70,%rsp
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <printf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x73,%eax
  mov    %rsp,%rdi
  movl   $0x73737361,(%rsp)
  mov    %ax,0x4(%rsp)
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D10
data_type: byte[16]

tool: D8: %lu


tool: {"D10": [0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x65,0x67,0x67,0x65,0x67,0x65,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  char *a = "algelge";
  char pre[100] = {"gegegegegeggege"};
  printf("%lu\n", strlen(a));
  a = "";
  printf("%lu\n", strlen(a));
  strcpy(pre, "assss");
  printf("%s\n", pre);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_uppercase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <convert_to_uppercase@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_uppercase(const char *const str) {
  char *upstr;
  upstr = strdup(str);
  convert_to_uppercase(upstr, 0, strlen(str));
  return upstr;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_uppercase>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strdup@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <convert_to_uppercase@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *get_uppercase(const char *const str) {
  char *upstr;
  upstr = strdup(str);
  convert_to_uppercase(upstr, 0, strlen(str));
  return upstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_uppercase>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <convert_to_uppercase@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_uppercase(const char *const str) {
  char *upstr;
  upstr = strdup(str);
  convert_to_uppercase(upstr, 0, strlen(str));
  return upstr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_uppercase>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <convert_to_uppercase@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_uppercase(const char *const str) {
  char *upstr;
  upstr = strdup(str);
  convert_to_uppercase(upstr, 0, strlen(str));
  return upstr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat44_ati>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L16
  cmpl   $0x3,-0x4(%rbp)
  jg     L16
  cmpl   $0x0,-0x8(%rbp)
  js     L16
  cmpl   $0x3,-0x8(%rbp)
  jle    L13
L16:
  mov    $0x3e,%r8d
  lea    D38(%rip),%rax
  mov    %rax,%rcx
  lea    D26(%rip),%rax
  mov    %rax,%rdx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <arghf@plt>
L13:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D38
datatype: string
name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D19
datatype: string

tool: D38: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h

tool: D26: mat44_ati

tool: D10: col >= 0 && col < 4 && row >= 0 && row < 4

tool: D19: ASSERT(%s) failed in %s() in %s:%d


assistant: ```c
int mat44_ati(int col, int row) {
  do {
    if (!(col >= 0 && col < 4 && row >= 0 && row < 4)) {
      arghf("ASSERT(%s) failed in %s() in %s:%d\n", "col >= 0 && col < 4 && row >= 0 && row < 4", __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h", 62);
    }
  } while (0);
  return row + col * 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat44_ati>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edi,%eax
  or     %esi,%eax
  cmp    $0x3,%eax
  jbe    L5
  mov    $0x3e,%r8d
  lea    D2(%rip),%rcx
  lea    D23(%rip),%rdx
  lea    D32(%rip),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <arghf@plt>
L5:
  lea    (%rbx,%rbp,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D27
type: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h

tool: D23: mat44_ati

tool: D32: col >= 0 && col < 4 && row >= 0 && row < 4

tool: D27: ASSERT(%s) failed in %s() in %s:%d


assistant: ```c
int mat44_ati(int col, int row) {
  do {
    if (!(col >= 0 && col < 4 && row >= 0 && row < 4)) {
      arghf("ASSERT(%s) failed in %s() in %s:%d\n", "col >= 0 && col < 4 && row >= 0 && row < 4", __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h", 62);
    }
  } while (0);
  return row + col * 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat44_ati>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %edi,%ebp
  push   %rbx
  or     %esi,%eax
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x3,%eax
  jbe    L2
  mov    $0x3e,%r8d
  lea    D36(%rip),%rcx
  xor    %eax,%eax
  lea    D17(%rip),%rdx
  lea    D38(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <arghf@plt>
L2:
  add    $0x8,%rsp
  lea    (%rbx,%rbp,4),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D36
type: string
name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D38
type: string
name: unpack_data
arguments: data_label: D4
type: string

tool: D36: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h

tool: D17: mat44_ati

tool: D38: col >= 0 && col < 4 && row >= 0 && row < 4

tool: D4: ASSERT(%s) failed in %s() in %s:%d


assistant: ```c
int mat44_ati(int col, int row) {
  do {
    if (!(col >= 0 && col < 4 && row >= 0 && row < 4)) {
      arghf("ASSERT(%s) failed in %s() in %s:%d\n", "col >= 0 && col < 4 && row >= 0 && row < 4", __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h", 62);
    }
  } while (0);
  return row + col * 4;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mat44_ati>:
  endbr64
  push   %rbp
  mov    %edi,%eax
  mov    %edi,%ebp
  push   %rbx
  or     %esi,%eax
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x3,%eax
  jbe    L1
  mov    $0x3e,%r8d
  lea    D37(%rip),%rcx
  xor    %eax,%eax
  lea    D31(%rip),%rdx
  lea    D10(%rip),%rsi
  lea    D36(%rip),%rdi
  call   <arghf@plt>
L1:
  add    $0x8,%rsp
  lea    (%rbx,%rbp,4),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
type: string
name: extract_symbolic_data
arguments: label: D31
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D36
type: string

tool: D37: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h

tool: D31: mat44_ati

tool: D10: col >= 0 && col < 4 && row >= 0 && row < 4

tool: D36: ASSERT(%s) failed in %s() in %s:%d


assistant: ```c
int mat44_ati(int col, int row) {
  do {
    if (!(col >= 0 && col < 4 && row >= 0 && row < 4)) {
      arghf("ASSERT(%s) failed in %s() in %s:%d\n", "col >= 0 && col < 4 && row >= 0 && row < 4", __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/sqaxomonophonen/cross-stub/refs/heads/master/m.h", 62);
    }
  } while (0);
  return row + col * 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <print_arguments@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  print_arguments(argc, argv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <print_arguments@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  print_arguments(argc, argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <print_arguments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  print_arguments(argc, argv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <print_arguments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  print_arguments(argc, argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<basic_hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x80,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <gethostname@plt>
  lea    D8(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *basic_hostname() {
  static char hname[128];
  (void)gethostname(hname, 128);
  return (hname);
}
```
user: Translate the below assembly code into C programming language:

```asm
<basic_hostname>:
  endbr64
  push   %rbx
  mov    $0x80,%esi
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <gethostname@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *basic_hostname() {
  static char hname[128];
  (void)gethostname(hname, 128);
  return (hname);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basic_hostname>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    $0x80,%esi
  mov    %r12,%rdi
  call   <gethostname@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *basic_hostname() {
  static char hname[128];
  (void)gethostname(hname, 128);
  return (hname);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<basic_hostname>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    $0x80,%esi
  mov    %r12,%rdi
  call   <gethostname@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *basic_hostname() {
  static char hname[128];
  (void)gethostname(hname, 128);
  return (hname);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_spi_speed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L27
  mov    -0x10(%rbp),%eax
  jmp    L13
L27:
  mov    -0xc(%rbp),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint32_t get_spi_speed(int fd) {
  uint32_t speed;
  int ret = ioctl(fd, SPI_IOC_RD_MAX_SPEED_HZ, &speed);
  if (ret >= 0) {
    return speed;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_spi_speed>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovns 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t get_spi_speed(int fd) {
  uint32_t speed;
  int ret = ioctl(fd, SPI_IOC_RD_MAX_SPEED_HZ, &speed);
  if (ret >= 0) {
    return speed;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_spi_speed>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovns 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t get_spi_speed(int fd) {
  uint32_t speed;
  int ret = ioctl(fd, SPI_IOC_RD_MAX_SPEED_HZ, &speed);
  if (ret >= 0) {
    return speed;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_spi_speed>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  cmovns 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t get_spi_speed(int fd) {
  uint32_t speed;
  int ret = ioctl(fd, SPI_IOC_RD_MAX_SPEED_HZ, &speed);
  if (ret >= 0) {
    return speed;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L0
L3:
  mov    -0x8(%rbp),%rax
  mov    $0x14,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strbuf_write@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x14,%eax
  mov    %eax,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    $0x14,%eax
  ja     L3
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strbuf_write@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7:                     

assistant: ```c
void print_spaces(struct strbuf *buf, int count) {
  static const char s[] = "                    ";
  while (count >= sizeof(s)) {
    strbuf_write(buf, s, sizeof(s) - 1);
    count -= sizeof(s) - 1;
  }
  strbuf_write(buf, s, count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_spaces>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%edx
  cmp    $0x14,%esi
  jbe    L6
  mov    %esi,%ebx
  lea    D7(%rip),%r12
L12:
  mov    $0x14,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strbuf_write@plt>
  sub    $0x14,%ebx
  cmp    $0x14,%ebx
  ja     L12
  mov    %ebx,%edx
L6:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strbuf_write@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D7:                     

assistant: ```c
void print_spaces(struct strbuf *buf, int count) {
  static const char s[] = "                    ";
  while (count >= sizeof(s)) {
    strbuf_write(buf, s, sizeof(s) - 1);
    count -= sizeof(s) - 1;
  }
  strbuf_write(buf, s, count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_spaces>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x14,%esi
  jbe    L9
  nopl   0x0(%rax)
L6:
  mov    $0x14,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  sub    $0x14,%ebx
  call   <strbuf_write@plt>
  cmp    $0x14,%ebx
  ja     L6
  mov    %ebx,%edx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <strbuf_write@plt>
  nopl   0x0(%rax)
L9:
  pop    %rbx
  mov    %esi,%edx
  mov    %rbp,%rdi
  mov    %r12,%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <strbuf_write@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0:                     

assistant: ```c
void print_spaces(struct strbuf *buf, int count) {
  static const char s[] = "                    ";
  while (count >= sizeof(s)) {
    strbuf_write(buf, s, sizeof(s) - 1);
    count -= sizeof(s) - 1;
  }
  strbuf_write(buf, s, count);
}
```