ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<writeFLVScriptDataValueDouble>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L7
  movsd  %xmm0,0x8(%rsp)
  call   <writeFLVScriptDataString@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rax,%r12
L7:
  lea    0x17(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  movsd  %xmm0,0x8(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <fwrite@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <writeFLVDouble@plt>
  add    %rax,%rbx
  lea    (%rbx,%r12,1),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t writeFLVScriptDataValueDouble(FILE *fp, const char *name, double value) {
  size_t datasize = 0;
  char type;
  if (name != NULL)
    datasize += writeFLVScriptDataString(fp, name);
  type = 0;
  datasize += fwrite(&type, 1, 1, fp);
  datasize += writeFLVDouble(fp, value);
  return datasize;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_g7x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x45,-0x4(%rbp)
  jle    L3
  cmpl   $0x4a,-0x4(%rbp)
  je     L3
  cmpl   $0x4e,-0x4(%rbp)
  je     L3
  cmpl   $0x50,-0x4(%rbp)
  je     L3
  cmpl   $0x6f,-0x4(%rbp)
  jle    L28
L3:
  mov    $0x0,%eax
  jmp    L49
L28:
  mov    $0x1,%eax
L49:
  pop    %rbp
  ret
```

assistant: ```c
int is_g7x(int chipset) {
  if (chipset < 0x46 || chipset == 0x4a || chipset == 0x4e || chipset == 0x50 || chipset >= 0x70)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_g7x>:
  endbr64
  lea    -0x46(%rdi),%eax
  cmp    $0x29,%eax
  ja     L18
  mov    %edi,%eax
  and    $0xfffffffb,%eax
  cmp    $0x4a,%eax
  je     L18
  cmp    $0x50,%edi
  setne  %al
  movzbl %al,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_g7x(int chipset) {
  if (chipset < 0x46 || chipset == 0x4a || chipset == 0x4e || chipset == 0x50 || chipset >= 0x70)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_g7x>:
  endbr64
  lea    -0x46(%rdi),%eax
  cmp    $0x29,%eax
  ja     L4
  mov    %edi,%eax
  and    $0xfffffffb,%eax
  cmp    $0x4a,%eax
  je     L4
  xor    %eax,%eax
  cmp    $0x50,%edi
  setne  %al
  ret
  nop
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_g7x(int chipset) {
  if (chipset < 0x46 || chipset == 0x4a || chipset == 0x4e || chipset == 0x50 || chipset >= 0x70)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_g7x>:
  endbr64
  lea    -0x46(%rdi),%eax
  cmp    $0x29,%eax
  ja     L18
  mov    %edi,%eax
  and    $0xfffffffb,%eax
  cmp    $0x4a,%eax
  je     L18
  xor    %eax,%eax
  cmp    $0x50,%edi
  setne  %al
  ret
  nop
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_g7x(int chipset) {
  if (chipset < 0x46 || chipset == 0x4a || chipset == 0x4e || chipset == 0x50 || chipset >= 0x70)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<aligned_block_fill_shuffle16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L12:
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x14(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1c(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addq   $0x20,-0x8(%rbp)
L0:
  subl   $0x40,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void aligned_block_fill_shuffle16(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t data = *src;
  while ((size -= 64) >= 0) {
    dst[0 + 0] = data;
    dst[1 + 0] = data;
    dst[1 + 2] = data;
    dst[0 + 2] = data;
    dst[1 + 4] = data;
    dst[0 + 4] = data;
    dst[0 + 6] = data;
    dst[1 + 6] = data;
    dst += 8;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aligned_block_fill_shuffle16>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0x3f,%edx
  jle    L3
  sub    $0x40,%edx
  shr    $0x6,%edx
  add    $0x1,%edx
  mov    %edx,%edx
  shl    $0x5,%rdx
  add    %rdi,%rdx
L6:
  mov    %eax,(%rdi)
  mov    %eax,0x4(%rdi)
  mov    %eax,0xc(%rdi)
  mov    %eax,0x8(%rdi)
  mov    %eax,0x14(%rdi)
  mov    %eax,0x10(%rdi)
  mov    %eax,0x18(%rdi)
  mov    %eax,0x1c(%rdi)
  add    $0x20,%rdi
  cmp    %rdx,%rdi
  jne    L6
L3:
  ret
```

assistant: ```c
void aligned_block_fill_shuffle16(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t data = *src;
  while ((size -= 64) >= 0) {
    dst[0 + 0] = data;
    dst[1 + 0] = data;
    dst[1 + 2] = data;
    dst[0 + 2] = data;
    dst[1 + 4] = data;
    dst[0 + 4] = data;
    dst[0 + 6] = data;
    dst[1 + 6] = data;
    dst += 8;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aligned_block_fill_shuffle16>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0x3f,%edx
  jle    L1
  sub    $0x40,%edx
  shr    $0x6,%edx
  add    $0x1,%edx
  shl    $0x5,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %eax,(%rdi)
  add    $0x20,%rdi
  mov    %eax,-0x1c(%rdi)
  mov    %eax,-0x14(%rdi)
  mov    %eax,-0x18(%rdi)
  mov    %eax,-0xc(%rdi)
  mov    %eax,-0x10(%rdi)
  mov    %eax,-0x8(%rdi)
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jne    L18
L1:
  ret
```

assistant: ```c
void aligned_block_fill_shuffle16(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t data = *src;
  while ((size -= 64) >= 0) {
    dst[0 + 0] = data;
    dst[1 + 0] = data;
    dst[1 + 2] = data;
    dst[0 + 2] = data;
    dst[1 + 4] = data;
    dst[0 + 4] = data;
    dst[0 + 6] = data;
    dst[1 + 6] = data;
    dst += 8;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aligned_block_fill_shuffle16>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0x3f,%edx
  jle    L4
  sub    $0x40,%edx
  shr    $0x6,%edx
  add    $0x1,%edx
  shl    $0x5,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %eax,(%rdi)
  add    $0x20,%rdi
  mov    %eax,-0x1c(%rdi)
  mov    %eax,-0x14(%rdi)
  mov    %eax,-0x18(%rdi)
  mov    %eax,-0xc(%rdi)
  mov    %eax,-0x10(%rdi)
  mov    %eax,-0x8(%rdi)
  mov    %eax,-0x4(%rdi)
  cmp    %rdx,%rdi
  jne    L7
L4:
  ret
```

assistant: ```c
void aligned_block_fill_shuffle16(int64_t *__restrict dst_, int64_t *__restrict src, int size) {
  volatile int64_t *dst = dst_;
  int64_t data = *src;
  while ((size -= 64) >= 0) {
    dst[0 + 0] = data;
    dst[1 + 0] = data;
    dst[1 + 2] = data;
    dst[0 + 2] = data;
    dst[1 + 4] = data;
    dst[0 + 4] = data;
    dst[0 + 6] = data;
    dst[1 + 6] = data;
    dst += 8;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<av_stristart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L14
L36:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L36
L43:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  cmpq   $0x0,-0x28(%rbp)
  je     L46
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L46:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int av_stristart(const char *str, const char *pfx, const char **ptr) {
  while (*pfx && toupper((unsigned)*pfx) == toupper((unsigned)*str)) {
    pfx++;
    str++;
  }
  if (!*pfx && ptr)
    *ptr = str;
  return !*pfx;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<av_stristart>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  movzbl (%rsi),%edi
  test   %dil,%dil
  je     L3
L46:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  movsbl (%r12),%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L3
  add    $0x1,%rbp
  add    $0x1,%r12
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L46
L3:
  cmpb   $0x0,0x0(%rbp)
  jne    L5
  test   %r13,%r13
  je     L5
  mov    %r12,0x0(%r13)
L5:
  cmpb   $0x0,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int av_stristart(const char *str, const char *pfx, const char **ptr) {
  while (*pfx && toupper((unsigned)*pfx) == toupper((unsigned)*str)) {
    pfx++;
    str++;
  }
  if (!*pfx && ptr)
    *ptr = str;
  return !*pfx;
}
```
user: What is the c source code of the assembly code below?

```asm
<av_stristart>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  jne    L3
  jmp    L49
  nopl   0x0(%rax)
L30:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  add    $0x1,%rbp
  test   %dil,%dil
  je     L49
L3:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L30
  movzbl 0x0(%r13),%edi
L49:
  test   %dil,%dil
  sete   %al
  test   %r12,%r12
  je     L2
  test   %al,%al
  je     L2
  mov    %rbp,(%r12)
  cmpb   $0x0,0x0(%r13)
  sete   %al
L2:
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int av_stristart(const char *str, const char *pfx, const char **ptr) {
  while (*pfx && toupper((unsigned)*pfx) == toupper((unsigned)*str)) {
    pfx++;
    str++;
  }
  if (!*pfx && ptr)
    *ptr = str;
  return !*pfx;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<av_stristart>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  test   %dil,%dil
  jne    L18
  jmp    L23
  nopl   0x0(%rax)
L8:
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  add    $0x1,%rbp
  test   %dil,%dil
  je     L23
L18:
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L8
  movzbl 0x0(%r13),%edi
L23:
  test   %dil,%dil
  sete   %al
  test   %r12,%r12
  je     L43
  test   %al,%al
  je     L43
  mov    %rbp,(%r12)
  cmpb   $0x0,0x0(%r13)
  sete   %al
L43:
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int av_stristart(const char *str, const char *pfx, const char **ptr) {
  while (*pfx && toupper((unsigned)*pfx) == toupper((unsigned)*str)) {
    pfx++;
    str++;
  }
  if (!*pfx && ptr)
    *ptr = str;
  return !*pfx;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cuenta_palabras>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L7
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L32
  addl   $0x1,-0x4(%rbp)
L32:
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cuenta_palabras(char cadena[], int tam) {
  int i, p = 0;
  for (i = 0; i < tam; i++) {
    if (cadena[i] == 32)
      p++;
    if (cadena[i] == 59)
      p++;
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cuenta_palabras>:
  endbr64
  test   %esi,%esi
  jle    L37
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%ecx
  jmp    L2
L25:
  add    $0x1,%ecx
L33:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L32
L2:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L25
  cmp    $0x3b,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%ecx
  jmp    L33
L37:
  mov    $0x0,%ecx
L32:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int cuenta_palabras(char cadena[], int tam) {
  int i, p = 0;
  for (i = 0; i < tam; i++) {
    if (cadena[i] == 32)
      p++;
    if (cadena[i] == 59)
      p++;
  }
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<cuenta_palabras>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x1(%rdi,%rax,1),%rdx
  jmp    L2
  nopl   (%rax)
L46:
  cmp    $0x3b,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  cmp    %rdx,%rdi
  je     L28
L2:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L46
  add    $0x1,%rdi
  add    $0x1,%r8d
  cmp    %rdx,%rdi
  jne    L2
L28:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cuenta_palabras(char cadena[], int tam) {
  int i, p = 0;
  for (i = 0; i < tam; i++) {
    if (cadena[i] == 32)
      p++;
    if (cadena[i] == 59)
      p++;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cuenta_palabras>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x1(%rdi,%rax,1),%rdx
  jmp    L39
  nopl   (%rax)
L22:
  cmp    $0x3b,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  cmp    %rdi,%rdx
  je     L36
L39:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L22
  add    $0x1,%rdi
  add    $0x1,%r8d
  cmp    %rdi,%rdx
  jne    L39
L36:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int cuenta_palabras(char cadena[], int tam) {
  int i, p = 0;
  for (i = 0; i < tam; i++) {
    if (cadena[i] == 32)
      p++;
    if (cadena[i] == 59)
      p++;
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<alien>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  nop
L2:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  test   %rax,%rax
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void alien(char *p) {
  while (putchar(*(p += *(p + 1) - *p)))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alien>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L2:
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  sub    %edx,%eax
  cltq
  add    %rax,%rbx
  movsbl (%rbx),%edi
  call   <putchar@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void alien(char *p) {
  while (putchar(*(p += *(p + 1) - *p)))
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<alien>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  sub    %edx,%eax
  cltq
  add    %rax,%rbx
  movsbl (%rbx),%edi
  call   <putchar@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void alien(char *p) {
  while (putchar(*(p += *(p + 1) - *p)))
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<alien>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  movsbl 0x1(%rbx),%eax
  movsbl (%rbx),%edx
  sub    %edx,%eax
  cltq
  add    %rax,%rbx
  movsbl (%rbx),%edi
  call   <putchar@plt>
  test   %rax,%rax
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void alien(char *p) {
  while (putchar(*(p += *(p + 1) - *p)))
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<format_thousands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D24(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D41(%rip)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%edx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %edx,%ecx
  shr    $0x6,%ecx
  mov    D41(%rip),%edx
  movslq %edx,%rsi
  mov    %rsi,%rdx
  shl    $0x4,%rdx
  sub    %rsi,%rdx
  lea    D41(%rip),%rsi
  lea    (%rdx,%rsi,1),%rdi
  mov    %eax,%r8d
  lea    D43(%rip),%rax
  mov    %rax,%rdx
  mov    $0xf,%esi
  call   <snprintf@plt>
  mov    D41(%rip),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  lea    D41(%rip),%rdx
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D43
type_guessed: string

tool: D43: %d.%.3d

assistant: ```c
const char *format_thousands(unsigned int value) {
  static char buf[4][15];
  static int i = 0;
  i = (i + 1) % 4;
  snprintf(buf[i], 15, "%d.%.3d", value / 1000, value % 1000);
  return buf[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<format_thousands>:
  endbr64
  push   %rbx
  mov    %edi,%r8d
  mov    D9(%rip),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D28(%rip)
  mov    %edi,%ecx
  imul   $0x10624dd3,%rcx,%rcx
  shr    $0x26,%rcx
  imul   $0x3e8,%ecx,%edx
  cltq
  mov    %rax,%rdi
  shl    $0x4,%rdi
  sub    %rax,%rdi
  lea    D28(%rip),%rbx
  add    %rbx,%rdi
  sub    %edx,%r8d
  lea    D19(%rip),%rdx
  mov    $0xf,%esi
  call   <snprintf@plt>
  movslq D28(%rip),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type: string

tool: D19: %d.%.3d

assistant: ```c
const char *format_thousands(unsigned int value) {
  static char buf[4][15];
  static int i = 0;
  i = (i + 1) % 4;
  snprintf(buf[i], 15, "%d.%.3d", value / 1000, value % 1000);
  return buf[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<format_thousands>:
  endbr64
  mov    D41(%rip),%eax
  mov    %edi,%ecx
  push   %rbx
  lea    D38(%rip),%rbx
  mov    %rcx,%r8
  imul   $0x10624dd3,%rcx,%rcx
  mov    $0xf,%esi
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  shr    $0x26,%rcx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  imul   $0x3e8,%ecx,%edx
  mov    %eax,D7(%rip)
  cltq
  mov    %rax,%rdi
  shl    $0x4,%rdi
  sub    %edx,%r8d
  lea    D7(%rip),%rdx
  sub    %rax,%rdi
  add    %rbx,%rdi
  call   <snprintf@plt>
  movslq D7(%rip),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: %d.%.3d

assistant: ```c
const char *format_thousands(unsigned int value) {
  static char buf[4][15];
  static int i = 0;
  i = (i + 1) % 4;
  snprintf(buf[i], 15, "%d.%.3d", value / 1000, value % 1000);
  return buf[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<format_thousands>:
  endbr64
  mov    D30(%rip),%eax
  mov    %edi,%ecx
  push   %rbx
  lea    D43(%rip),%rbx
  mov    %rcx,%r8
  imul   $0x10624dd3,%rcx,%rcx
  mov    $0xf,%esi
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  shr    $0x26,%rcx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  imul   $0x3e8,%ecx,%edx
  mov    %eax,D9(%rip)
  cltq
  mov    %rax,%rdi
  shl    $0x4,%rdi
  sub    %edx,%r8d
  lea    D9(%rip),%rdx
  sub    %rax,%rdi
  add    %rbx,%rdi
  call   <snprintf@plt>
  movslq D9(%rip),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  add    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: %d.%.3d

assistant: ```c
const char *format_thousands(unsigned int value) {
  static char buf[4][15];
  static int i = 0;
  i = (i + 1) % 4;
  snprintf(buf[i], 15, "%d.%.3d", value / 1000, value % 1000);
  return buf[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<send_packet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <sigemptyset@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sigaddset@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <pthread_sigmask@plt>
  lea    -0x38(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write_all@plt>
  cmp    $0x8,%rax
  je     L30
  movl   $0xffffffff,-0xc(%rbp)
L30:
  cmpl   $0x0,-0xc(%rbp)
  jne    L36
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write_all@plt>
  mov    -0x38(%rbp),%rdx
  cmp    %rdx,%rax
  je     L36
  movl   $0xffffffff,-0xc(%rbp)
L36:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <pthread_sigmask@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
int send_packet(int fd, const char *buf, size_t len) {
  int ret = 0;
  sigset_t set, old;
  sigemptyset(&set);
  sigaddset(&set, SIGPIPE);
  pthread_sigmask(SIG_BLOCK, &set, &old);
  if (write_all(fd, &len, sizeof(len)) != sizeof(len))
    ret = -1;
  if (!ret && write_all(fd, buf, len) != len)
    ret = -1;
  pthread_sigmask(SIG_SETMASK, &old, NULL);
  return ret;
}
```