ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D44
type: string
name: unpack_data
arguments: label: D7
type: string
name: unpack_data
arguments: label: D49
type: string
name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D66
type: string

tool: D25: If two strings are idential, strcmp() will return 0.

tool: D44: For example, when you do a strcmp("dog", "dog"), the output will be: %d


tool: D7: 
If the string in the first parameter is less than the string in second parameter,

tool: D49:  strcmp() will return a value less than 0.

tool: D3: For example, when you do a strcmp("cat", "dog"), the output will be: %d


tool: D6: 
If the string in the first parameter is greater than the string in second parameter,

tool: D12:  strcmp() will return a value greater than 0.

tool: D66: For example, when you do a strcmp("dog", "cat"), the output will be: %d


assistant: ```c
int main(void) {
  printf("If two strings are idential, strcmp() will return 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"dog\"), the output will be: %d\n", strcmp("dog", "dog"));
  printf("\nIf the string in the first parameter is less than the string in second parameter,");
  printf(" strcmp() will return a value less than 0.\n");
  printf("For example, when you do a strcmp(\"cat\", \"dog\"), the output will be: %d\n", strcmp("cat", "dog"));
  printf("\nIf the string in the first parameter is greater than the string in second parameter,");
  printf(" strcmp() will return a value greater than 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"cat\"), the output will be: %d\n", strcmp("dog", "cat"));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D43(%rip),%rdi
  call   <puts@plt>
  xor    %esi,%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%esi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D43
type_guessed: string
name: read_data
arguments: tag: D55
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D53
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string
name: read_data
arguments: tag: D78
type_guessed: string
name: read_data
arguments: tag: D65
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D43: If two strings are idential, strcmp() will return 0.

tool: D55: For example, when you do a strcmp("dog", "dog"), the output will be: %d


tool: D1: 
If the string in the first parameter is less than the string in second parameter,

tool: D53:  strcmp() will return a value less than 0.

tool: D7: For example, when you do a strcmp("cat", "dog"), the output will be: %d


tool: D78: 
If the string in the first parameter is greater than the string in second parameter,

tool: D65:  strcmp() will return a value greater than 0.

tool: D16: For example, when you do a strcmp("dog", "cat"), the output will be: %d


assistant: ```c
int main(void) {
  printf("If two strings are idential, strcmp() will return 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"dog\"), the output will be: %d\n", strcmp("dog", "dog"));
  printf("\nIf the string in the first parameter is less than the string in second parameter,");
  printf(" strcmp() will return a value less than 0.\n");
  printf("For example, when you do a strcmp(\"cat\", \"dog\"), the output will be: %d\n", strcmp("cat", "dog"));
  printf("\nIf the string in the first parameter is greater than the string in second parameter,");
  printf(" strcmp() will return a value greater than 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"cat\"), the output will be: %d\n", strcmp("dog", "cat"));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %esi,%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D79(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%esi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D59
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D79
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D45
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string

tool: D0: If two strings are idential, strcmp() will return 0.

tool: D59: For example, when you do a strcmp("dog", "dog"), the output will be: %d


tool: D3: 
If the string in the first parameter is less than the string in second parameter,

tool: D79:  strcmp() will return a value less than 0.

tool: D48: For example, when you do a strcmp("cat", "dog"), the output will be: %d


tool: D33: 
If the string in the first parameter is greater than the string in second parameter,

tool: D45:  strcmp() will return a value greater than 0.

tool: D13: For example, when you do a strcmp("dog", "cat"), the output will be: %d


assistant: ```c
int main(void) {
  printf("If two strings are idential, strcmp() will return 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"dog\"), the output will be: %d\n", strcmp("dog", "dog"));
  printf("\nIf the string in the first parameter is less than the string in second parameter,");
  printf(" strcmp() will return a value less than 0.\n");
  printf("For example, when you do a strcmp(\"cat\", \"dog\"), the output will be: %d\n", strcmp("cat", "dog"));
  printf("\nIf the string in the first parameter is greater than the string in second parameter,");
  printf(" strcmp() will return a value greater than 0.\n");
  printf("For example, when you do a strcmp(\"dog\", \"cat\"), the output will be: %d\n", strcmp("dog", "cat"));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SerialDataAvail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  jne    L10
  mov    $0xffffffff,%eax
  jmp    L11
L10:
  mov    -0xc(%rbp),%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int SerialDataAvail(int fd) {
  int result;
  if (ioctl(fd, FIONREAD, &result) == -1)
    return -1;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SerialDataAvail>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    0x4(%rsp),%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SerialDataAvail(int fd) {
  int result;
  if (ioctl(fd, FIONREAD, &result) == -1)
    return -1;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SerialDataAvail>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    0x4(%rsp),%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SerialDataAvail(int fd) {
  int result;
  if (ioctl(fd, FIONREAD, &result) == -1)
    return -1;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<SerialDataAvail>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  cmp    $0xffffffff,%eax
  je     L17
  mov    0x4(%rsp),%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SerialDataAvail(int fd) {
  int result;
  if (ioctl(fd, FIONREAD, &result) == -1)
    return -1;
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rrotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  shll   %cl,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    %eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L2
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *rrotate(int *input, unsigned int bits, int n) {
  int lsb = 0;
  for (int i = 0; i < n; i++) {
    lsb = (input[i]) & 1;
    lsb <<= (bits - 1);
    input[i] = lsb | ((input[i]) >> 1);
  }
  return input;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rrotate>:
  endbr64
  mov    %rdi,%r9
  test   %edx,%edx
  jle    L2
  lea    -0x1(%rdx),%eax
  lea    0x4(%rdi,%rax,4),%r8
  lea    -0x1(%rsi),%ecx
L17:
  mov    (%rdi),%edx
  mov    %edx,%eax
  and    $0x1,%eax
  shl    %cl,%eax
  sar    %edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %r8,%rdi
  jne    L17
L2:
  mov    %r9,%rax
  ret
```

assistant: ```c
int *rrotate(int *input, unsigned int bits, int n) {
  int lsb = 0;
  for (int i = 0; i < n; i++) {
    lsb = (input[i]) & 1;
    lsb <<= (bits - 1);
    input[i] = lsb | ((input[i]) >> 1);
  }
  return input;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rrotate>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L7
  lea    -0x1(%rdx),%eax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rax,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  sar    %eax
  and    $0x1,%edx
  shl    %cl,%edx
  or     %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rsi
  jne    L18
L7:
  mov    %r8,%rax
  ret
```

assistant: ```c
int *rrotate(int *input, unsigned int bits, int n) {
  int lsb = 0;
  for (int i = 0; i < n; i++) {
    lsb = (input[i]) & 1;
    lsb <<= (bits - 1);
    input[i] = lsb | ((input[i]) >> 1);
  }
  return input;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rrotate>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L21
  lea    -0x1(%rdx),%eax
  lea    -0x1(%rsi),%ecx
  cmp    $0x2,%eax
  jbe    L27
  mov    %edx,%esi
  mov    %rdi,%rax
  movdqa D14(%rip),%xmm3
  shr    $0x2,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  movslq %ecx,%rdi
  movq   %rdi,%xmm2
  nopw   0x0(%rax,%rax,1)
L14:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  pand   %xmm3,%xmm0
  psrad  $0x1,%xmm1
  pslld  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L14
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  cmp    %esi,%edx
  je     L21
L30:
  sub    %esi,%edx
  cmp    $0x1,%edx
  je     L29
  movq   D14(%rip),%xmm0
  lea    (%r8,%rsi,4),%rsi
  movslq %ecx,%rdi
  movq   (%rsi),%xmm1
  movq   %rdi,%xmm4
  pand   %xmm1,%xmm0
  psrad  $0x1,%xmm1
  pslld  %xmm4,%xmm0
  por    %xmm1,%xmm0
  movq   %xmm0,(%rsi)
  mov    %edx,%esi
  and    $0xfffffffe,%esi
  add    %esi,%eax
  cmp    %esi,%edx
  je     L21
L29:
  cltq
  lea    (%r8,%rax,4),%rsi
  mov    (%rsi),%edx
  mov    %edx,%eax
  sar    %edx
  and    $0x1,%eax
  shl    %cl,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
L21:
  mov    %r8,%rax
  ret
L27:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
data_type: byte[16]

tool: {"D14": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int *rrotate(int *input, unsigned int bits, int n) {
  int lsb = 0;
  for (int i = 0; i < n; i++) {
    lsb = (input[i]) & 1;
    lsb <<= (bits - 1);
    input[i] = lsb | ((input[i]) >> 1);
  }
  return input;
}
```
user: What is the c source code of the assembly code below:

```asm
<filt_u_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x3e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  cmpq   $0x0,-0x10(%rbp)
  je     L15
  addq   $0x1,-0x18(%rbp)
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D21(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    %rax,-0x20(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x100,%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,%esi
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rcx
  lea    D20(%rip),%rax
  mov    %rax,%rdx
  call   <snprintf@plt>
  jmp    L23
L15:
  nop
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D22
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D20
type_guessed: string

tool: D22: Product:

tool: D41: Jul 27 14:50:37 

tool: D21: %s

tool: D20:  Find USB device: %s

assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  p3 = strstr(cur, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  p3 += strlen("Product:");
  snprintf(cur - 1, msg + 256 - cur, " Find USB device: %s", p3);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filt_u_message>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x3e,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  lea    D48(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rbp,%rbp
  je     L9
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  lea    D44(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    0x1(%rbp),%rcx
  lea    D42(%rip),%rdx
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D48(%rip),%rdi
  call   <strlen@plt>
  cltq
  lea    (%r12,%rax,1),%rcx
  movslq %r13d,%rax
  lea    -0x1(%rbx,%rax,1),%rdi
  lea    D5(%rip),%rdx
  mov    $0x100,%esi
  sub    %eax,%esi
  call   <snprintf@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D48
data_type: string
name: retrieve_data
arguments: data_tag: D44
data_type: string
name: retrieve_data
arguments: data_tag: D42
data_type: string
name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D48: Product:

tool: D44: Jul 27 14:50:37 

tool: D42: %s

tool: D5:  Find USB device: %s

assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  p3 = strstr(cur, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  p3 += strlen("Product:");
  snprintf(cur - 1, msg + 256 - cur, " Find USB device: %s", p3);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<filt_u_message>:
  endbr64
  push   %r14
  mov    $0x3e,%esi
  lea    D19(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rbp,%rbp
  je     L16
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
  lea    D6(%rip),%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%rcx
  lea    D20(%rip),%rdx
  mov    %rbx,%rdi
  movslq %eax,%r13
  mov    %r13d,%esi
  call   <snprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    $0x100,%esi
  lea    -0x1(%rbx,%r13,1),%rdi
  pop    %rbx
  cltq
  pop    %rbp
  lea    D9(%rip),%rdx
  sub    %r13d,%esi
  lea    (%r12,%rax,1),%rcx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <snprintf@plt>
  nop
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D20
data_type: string
name: read_data
arguments: tag: D9
data_type: string

tool: D19: Product:

tool: D6: Jul 27 14:50:37 

tool: D20: %s

tool: D9:  Find USB device: %s

assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  p3 = strstr(cur, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  p3 += strlen("Product:");
  snprintf(cur - 1, msg + 256 - cur, " Find USB device: %s", p3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<filt_u_message>:
  endbr64
  push   %r14
  mov    $0x3e,%esi
  lea    D30(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strchr@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rbp,%rbp
  je     L3
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  lea    D19(%rip),%rdi
  call   <strlen@plt>
  lea    0x1(%rbp),%rcx
  lea    D8(%rip),%rdx
  mov    %rbx,%rdi
  movslq %eax,%r13
  mov    %r13d,%esi
  call   <snprintf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    $0x100,%esi
  lea    -0x1(%rbx,%r13,1),%rdi
  pop    %rbx
  cltq
  pop    %rbp
  lea    D9(%rip),%rdx
  sub    %r13d,%esi
  lea    (%r12,%rax,1),%rcx
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <snprintf@plt>
  nop
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D30
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D30: Product:

tool: D19: Jul 27 14:50:37 

tool: D8: %s

tool: D9:  Find USB device: %s

assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  p3 = strstr(cur, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  p3 += strlen("Product:");
  snprintf(cur - 1, msg + 256 - cur, " Find USB device: %s", p3);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ResetIsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x400d20b4,%eax
  movq   $0xff,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetIsr(void) {
  (*((volatile unsigned long *)(0x400D20B4))) = 0xFF;
  __iar_program_start();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ResetIsr>:
  endbr64
  sub    $0x8,%rsp
  movq   $0xff,0x400d20b4
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ResetIsr(void) {
  (*((volatile unsigned long *)(0x400D20B4))) = 0xFF;
  __iar_program_start();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ResetIsr>:
  endbr64
  movq   $0xff,0x400d20b4
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetIsr(void) {
  (*((volatile unsigned long *)(0x400D20B4))) = 0xFF;
  __iar_program_start();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ResetIsr>:
  endbr64
  movq   $0xff,0x400d20b4
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetIsr(void) {
  (*((volatile unsigned long *)(0x400D20B4))) = 0xFF;
  __iar_program_start();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setObjAlt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  lea    -0x2c(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <getSexComponents@plt>
  mov    -0x28(%rbp),%ecx
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  lea    D7(%rip),%rdx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <setStandardProcedure@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: #:Sa%+02d*%02d#

assistant: ```c
int setObjAlt(double alt) {
  int d, m, s;
  char tempString[16];
  getSexComponents(alt, &d, &m, &s);
  snprintf(tempString, sizeof(tempString), "#:Sa%+02d*%02d#", d, m);
  return (setStandardProcedure(tempString));
}
```