ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<QuickSort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x978,%rsp
  mov    %rdi,%r10
  mov    %fs:0x28,%rax
  mov    %rax,0x968(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %esi,0x4b0(%rsp)
  mov    $0x0,%ebx
  jmp    L22
L150:
  movslq %ecx,%rax
  mov    (%r10,%rax,4),%edi
  jmp    L143
L128:
  cmp    %edx,%ecx
  jge    L177
  lea    0x1(%rcx),%r8d
  movslq %ecx,%rax
  mov    %esi,(%r10,%rax,4)
  mov    0x4(%r10,%rax,4),%esi
  cmp    %edx,%r8d
  jge    L112
  cmp    %esi,%edi
  jl     L112
  lea    0x2(%rcx),%eax
  cltq
L176:
  mov    %eax,%ecx
  mov    (%r10,%rax,4),%esi
  cmp    %eax,%edx
  setg   %r9b
  cmp    %edi,%esi
  setle  %r8b
  add    $0x1,%rax
  test   %r8b,%r9b
  jne    L176
L1:
  cmp    %edx,%ecx
  jge    L177
  sub    $0x1,%edx
  mov    %esi,(%r11)
  cmp    %ecx,%edx
  jle    L177
L143:
  movslq %edx,%rax
  lea    (%r10,%rax,4),%r11
  mov    (%r11),%esi
  cmp    %edx,%ecx
  jge    L128
  lea    -0x4(%r10,%rax,4),%rax
  cmp    %esi,%edi
  jg     L128
L165:
  sub    $0x1,%edx
  mov    %rax,%r11
  mov    (%rax),%esi
  sub    $0x4,%rax
  cmp    %ecx,%edx
  jle    L128
  cmp    %edi,%esi
  jge    L165
  jmp    L128
L112:
  mov    %r8d,%ecx
  jmp    L1
L177:
  movslq %ecx,%rax
  mov    %edi,(%r10,%rax,4)
  lea    0x1(%rbx),%esi
  lea    0x1(%rcx),%edx
  movslq %esi,%rax
  mov    %edx,(%rsp,%rax,4)
  mov    %ebp,0x4b0(%rsp,%rax,4)
  movslq %ebx,%rdi
  mov    %ecx,0x4b0(%rsp,%rdi,4)
  mov    0x4b0(%rsp,%rax,4),%eax
  mov    (%rsp,%rdi,4),%edi
  mov    %eax,%r9d
  sub    %edx,%r9d
  mov    %ecx,%r8d
  sub    %edi,%r8d
  cmp    %r8d,%r9d
  jle    L88
  movslq %esi,%r8
  mov    %edi,(%rsp,%r8,4)
  movslq %ebx,%rbx
  mov    %edx,(%rsp,%rbx,4)
  mov    %ecx,0x4b0(%rsp,%r8,4)
  mov    %eax,0x4b0(%rsp,%rbx,4)
  mov    %esi,%ebx
L72:
  test   %ebx,%ebx
  js     L168
L22:
  movslq %ebx,%rax
  mov    (%rsp,%rax,4),%ecx
  mov    0x4b0(%rsp,%rax,4),%ebp
  lea    -0x1(%rbp),%edx
  cmp    %edx,%ecx
  jl     L150
  sub    $0x1,%ebx
  jmp    L72
L88:
  mov    %esi,%ebx
  jmp    L72
L168:
  mov    0x968(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x978,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void QuickSort(int *arr, int elements) {
  int piv, beg[300], end[300], i = 0, L, R, swap;
  beg[0] = 0;
  end[0] = elements;
  while (i >= 0) {
    L = beg[i];
    R = end[i] - 1;
    if (L < R) {
      piv = arr[L];
      while (L < R) {
        while (arr[R] >= piv && L < R)
          R--;
        if (L < R)
          arr[L++] = arr[R];
        while (arr[L] <= piv && L < R)
          L++;
        if (L < R)
          arr[R--] = arr[L];
      }
      arr[L] = piv;
      beg[i + 1] = L + 1;
      end[i + 1] = end[i];
      end[i++] = L;
      if (end[i] - beg[i] > end[i - 1] - beg[i - 1]) {
        swap = beg[i];
        beg[i] = beg[i - 1];
        beg[i - 1] = swap;
        swap = end[i];
        end[i] = end[i - 1];
        end[i - 1] = swap;
      }
    } else {
      --i;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D25(%rip),%rbx
  jmp    L72
L35:
  add    $0x1,%rbx
L72:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L35
  sub    $0x1,%rbx
  jmp    L56
L42:
  sub    $0x1,%rbx
L56:
  lea    D25(%rip),%rax
  cmp    %rax,%rbx
  jb     L45
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  je     L42
  jmp    L45
L111:
  sub    $0x1,%rbx
L45:
  lea    D25(%rip),%rax
  cmp    %rax,%rbx
  jb     L117
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  jne    L111
  jmp    L117
L28:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
L117:
  lea    D25(%rip),%rax
  cmp    %rax,%rbx
  jb     L7
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  je     L28
L7:
  lea    D25(%rip),%rax
  cmp    %rax,%rbx
  jae    L65
  movb   $0x0,D25(%rip)
L65:
  lea    D25(%rip),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *dirname(path)
char *path;
{
  static char dn[256];
  register char *p;
  strcpy(dn, path);
  for (p = dn; *p; ++p)
    ;
  for (--p; (p >= dn) && (*p == '/'); --p)
    ;
  for (; (p >= dn) && (*p != '/'); --p)
    ;
  for (; (p >= dn) && (*p == '/'); --p)
    *p = '\0';
  if (p < dn)
    dn[0] = '\0';
  return (dn);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dirname>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <strcpy@plt>
  cmpb   $0x0,D4(%rip)
  je     L0
  lea    D4(%rip),%rdx
L4:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L4
  lea    D4(%rip),%rdx
  cmp    %rdx,%rax
  jb     L0
L53:
  cmpb   $0x2f,(%rax)
  jne    L27
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jae    L53
  jmp    L0
L27:
  lea    D4(%rip),%rdx
  cmp    %rdx,%rax
  jb     L0
L57:
  cmpb   $0x2f,(%rax)
  je     L45
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jae    L57
  jmp    L0
L45:
  lea    D4(%rip),%rdx
  cmp    %rdx,%rax
  jb     L0
L20:
  cmpb   $0x2f,(%rax)
  jne    L38
  movb   $0x0,(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jae    L20
L0:
  movb   $0x0,D4(%rip)
  jmp    L21
L38:
  lea    D4(%rip),%rdx
  cmp    %rdx,%rax
  jb     L0
L21:
  lea    D4(%rip),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *dirname(path)
char *path;
{
  static char dn[256];
  register char *p;
  strcpy(dn, path);
  for (p = dn; *p; ++p)
    ;
  for (--p; (p >= dn) && (*p == '/'); --p)
    ;
  for (; (p >= dn) && (*p != '/'); --p)
    ;
  for (; (p >= dn) && (*p == '/'); --p)
    *p = '\0';
  if (p < dn)
    dn[0] = '\0';
  return (dn);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dirname>:
  endbr64
  lea    D30(%rip),%r8
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <strcpy@plt>
  cmpb   $0x0,D30(%rip)
  mov    %rax,%r8
  je     L66
  mov    %rax,%rdx
  nopl   (%rax)
L100:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L100
  cmpb   $0x2f,(%rax)
  jne    L108
  nopl   0x0(%rax)
L64:
  sub    $0x1,%rax
  cmp    %r8,%rax
  jb     L66
  cmpb   $0x2f,(%rax)
  je     L64
L108:
  cmp    %r8,%rax
  jb     L66
  sub    $0x1,%rax
  lea    D16(%rip),%rcx
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %rax,%rdx
  cmp    %rcx,%rax
  je     L66
  sub    $0x1,%rax
  cmpb   $0x2f,0x1(%rax)
  jne    L76
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jb     L66
  xchg   %ax,%ax
L63:
  cmpb   $0x2f,(%rdx)
  jne    L8
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jae    L63
  nopl   0x0(%rax)
L66:
  movb   $0x0,D30(%rip)
L8:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *dirname(path)
char *path;
{
  static char dn[256];
  register char *p;
  strcpy(dn, path);
  for (p = dn; *p; ++p)
    ;
  for (--p; (p >= dn) && (*p == '/'); --p)
    ;
  for (; (p >= dn) && (*p != '/'); --p)
    ;
  for (; (p >= dn) && (*p == '/'); --p)
    *p = '\0';
  if (p < dn)
    dn[0] = '\0';
  return (dn);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dirname>:
  endbr64
  lea    D29(%rip),%r8
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <strcpy@plt>
  cmpb   $0x0,D29(%rip)
  mov    %rax,%r8
  je     L96
  mov    %rax,%rdx
  nopl   (%rax)
L43:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx)
  jne    L43
  cmpb   $0x2f,(%rax)
  jne    L56
  nopl   0x0(%rax)
L18:
  sub    $0x1,%rax
  cmp    %r8,%rax
  jb     L96
  cmpb   $0x2f,(%rax)
  je     L18
L56:
  cmp    %r8,%rax
  jb     L96
  sub    $0x1,%rax
  lea    D17(%rip),%rcx
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %rax,%rdx
  cmp    %rcx,%rax
  je     L96
  sub    $0x1,%rax
  cmpb   $0x2f,0x1(%rax)
  jne    L25
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jb     L96
  xchg   %ax,%ax
L77:
  cmpb   $0x2f,(%rdx)
  jne    L95
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  jae    L77
  nopl   0x0(%rax)
L96:
  movb   $0x0,D29(%rip)
L95:
  mov    %r8,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *dirname(path)
char *path;
{
  static char dn[256];
  register char *p;
  strcpy(dn, path);
  for (p = dn; *p; ++p)
    ;
  for (--p; (p >= dn) && (*p == '/'); --p)
    ;
  for (; (p >= dn) && (*p != '/'); --p)
    ;
  for (; (p >= dn) && (*p == '/'); --p)
    *p = '\0';
  if (p < dn)
    dn[0] = '\0';
  return (dn);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy1c_usmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x40(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    0x10(%rbp),%r8
  mov    %rax,%rdi
  call   <copy1c_usvector@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy1c_usmatrix(ushort **X, long nc, ushort **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    copy1c_usvector(X[i], nc, Y[i], ncl, nch);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy1c_usmatrix>:
  endbr64
  movslq %ecx,%rax
  cmp    %rax,%r8
  jl     L2
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %r8,%rbp
  mov    %r9,%r15
  mov    %rax,%rbx
L14:
  mov    (%r14,%rbx,8),%rdx
  mov    (%r12,%rbx,8),%rdi
  mov    0x40(%rsp),%r8
  mov    %r15,%rcx
  mov    %r13,%rsi
  call   <copy1c_usvector@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  ret
```

assistant: ```c
void copy1c_usmatrix(ushort **X, long nc, ushort **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    copy1c_usvector(X[i], nc, Y[i], ncl, nch);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy1c_usmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  mov    0x50(%rsp),%r14
  cmp    %rbx,%r8
  jl     L11
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %r9,%r13
L19:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rdi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <copy1c_usvector@plt>
  cmp    %rbx,0x8(%rsp)
  jge    L19
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy1c_usmatrix(ushort **X, long nc, ushort **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    copy1c_usvector(X[i], nc, Y[i], ncl, nch);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy1c_usmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  mov    0x50(%rsp),%r14
  cmp    %rbx,%r8
  jl     L15
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %r9,%r13
L16:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rdi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rsi
  add    $0x1,%rbx
  call   <copy1c_usvector@plt>
  cmp    %rbx,0x8(%rsp)
  jge    L16
L15:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void copy1c_usmatrix(ushort **X, long nc, ushort **Y, long nrl, long nrh, long ncl, long nch) {
  int i;
  for (i = nrl; i <= nrh; i++) {
    copy1c_usvector(X[i], nc, Y[i], ncl, nch);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rdx
  mov    %rsi,%rax
  jmp    L16
L3:
  test   %bl,%bl
  jne    L16
  mov    $0x1,%eax
  jmp    L29
L16:
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movzbl (%rcx),%ebx
  mov    %rax,%rcx
  lea    0x1(%rcx),%rax
  movzbl (%rcx),%ecx
  cmp    %cl,%bl
  je     L3
  test   %bl,%bl
  sete   %al
  movzbl %al,%eax
L29:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
prefix(s1, s2) register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return 1;
  return c == '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<prefix>:
  endbr64
  mov    $0x0,%eax
L10:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  jne    L12
  add    $0x1,%rax
  test   %dl,%dl
  jne    L10
  mov    $0x1,%eax
  ret
L12:
  test   %dl,%dl
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
prefix(s1, s2) register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return 1;
  return c == '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rax
  test   %dl,%dl
  je     L0
L21:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  je     L13
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
prefix(s1, s2) register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return 1;
  return c == '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prefix>:
  endbr64
  xor    %eax,%eax
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rax
  test   %dl,%dl
  je     L5
L15:
  movzbl (%rdi,%rax,1),%edx
  cmp    %dl,(%rsi,%rax,1)
  je     L27
  xor    %eax,%eax
  test   %dl,%dl
  sete   %al
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
prefix(s1, s2) register char *s1, *s2;
{
  register char c;
  while ((c = *s1++) == *s2++)
    if (c == '\0')
      return 1;
  return c == '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<solveMaze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0x0(,%rax,4),%rdi
  imul   %rax,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L77:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L77
L9:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L36
  orq    $0x0,-0x8(%rsp,%rax,1)
L36:
  mov    %rsp,%r12
  test   %ebx,%ebx
  jle    L54
  mov    %ebx,%eax
  lea    (%r12,%rax,4),%rdx
  mov    $0x0,%ecx
  mov    %ebx,%esi
  neg    %rsi
  shl    $0x2,%rsi
L20:
  lea    (%rsi,%rdx,1),%rax
L81:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L81
  add    $0x1,%ecx
  add    %rdi,%rdx
  cmp    %ecx,%ebx
  jne    L20
L54:
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %r9,%rsi
  mov    %ebx,%edi
  call   <mazeUtility@plt>
  test   %rax,%rax
  je     L25
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <printMaze@plt>
L4:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L25:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string

tool: D10: The solution for this maze exists


tool: D15: The solution maze wrt given maze is (follow the 1's):: 


tool: D2: There is no solution for the given maze


assistant: ```c
void solveMaze(int size, int maze[size][size]) {
  int i, j, sol[size][size];
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      sol[i][j] = 0;
  if (mazeUtility(size, maze, 0, 0, sol)) {
    printf("The solution for this maze exists\n");
    printf("The solution maze wrt given maze is (follow the 1's):: \n");
    printMaze(size, sol);
  } else
    printf("There is no solution for the given maze\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<solveMaze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  movslq %edi,%rbx
  mov    %rbx,%r12
  lea    0x0(,%rbx,4),%r13
  sub    $0x28,%rsp
  mov    %rsi,-0x48(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rbx,%rax
  imul   %rbx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L84
L13:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L13
L84:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L5
L59:
  mov    %rsp,%r15
  test   %r12d,%r12d
  jle    L31
  mov    %r15,%rdi
  shl    $0x2,%rbx
  xor    %r14d,%r14d
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %rbx,%rdx
  xor    %esi,%esi
  add    $0x1,%r14d
  call   <memset@plt>
  mov    %rax,%rdi
  add    %r13,%rdi
  cmp    %r14d,%r12d
  jne    L17
L31:
  mov    -0x48(%rbp),%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r15,%r8
  mov    %r12d,%edi
  call   <mazeUtility@plt>
  test   %rax,%rax
  je     L56
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r12d,%edi
  call   <printMaze@plt>
L67:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L56:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L5:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L59
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D28: The solution for this maze exists


tool: D6: The solution maze wrt given maze is (follow the 1's):: 


tool: D1: There is no solution for the given maze


assistant: ```c
void solveMaze(int size, int maze[size][size]) {
  int i, j, sol[size][size];
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      sol[i][j] = 0;
  if (mazeUtility(size, maze, 0, 0, sol)) {
    printf("The solution for this maze exists\n");
    printf("The solution maze wrt given maze is (follow the 1's):: \n");
    printMaze(size, sol);
  } else
    printf("There is no solution for the given maze\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<solveMaze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  movslq %edi,%rbx
  mov    %rbx,%r12
  lea    0x0(,%rbx,4),%r13
  sub    $0x28,%rsp
  mov    %rsi,-0x48(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rbx,%rax
  imul   %rbx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L30
L69:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L69
L30:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L14
L12:
  mov    %rsp,%r15
  test   %r12d,%r12d
  jle    L46
  mov    %r15,%rdi
  shl    $0x2,%rbx
  xor    %r14d,%r14d
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    %rbx,%rdx
  xor    %esi,%esi
  add    $0x1,%r14d
  call   <memset@plt>
  mov    %rax,%rdi
  add    %r13,%rdi
  cmp    %r14d,%r12d
  jne    L79
L46:
  mov    -0x48(%rbp),%rsi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %r15,%r8
  mov    %r12d,%edi
  call   <mazeUtility@plt>
  test   %rax,%rax
  je     L37
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %r12d,%edi
  call   <printMaze@plt>
L0:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L37:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L14:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L12
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D14
type: string

tool: D4: The solution for this maze exists


tool: D9: The solution maze wrt given maze is (follow the 1's):: 


tool: D14: There is no solution for the given maze


assistant: ```c
void solveMaze(int size, int maze[size][size]) {
  int i, j, sol[size][size];
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      sol[i][j] = 0;
  if (mazeUtility(size, maze, 0, 0, sol)) {
    printf("The solution for this maze exists\n");
    printf("The solution maze wrt given maze is (follow the 1's):: \n");
    printMaze(size, sol);
  } else
    printf("There is no solution for the given maze\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<setReverbMixFromMIDI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movzbl -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  D3(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%edx
  mov    -0x8(%rbp),%rax
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <setReverbMix@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: f32

tool: D3: 127

assistant: ```c
void setReverbMixFromMIDI(void *rev, unsigned char v) {
  struct b_reverb *r = (struct b_reverb *)rev;
  setReverbMix(r, (float)v / 127.0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<setReverbMixFromMIDI>:
  endbr64
  sub    $0x8,%rsp
  movzbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  divss  D5(%rip),%xmm0
  call   <setReverbMix@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: f32

tool: D5: 127

assistant: ```c
void setReverbMixFromMIDI(void *rev, unsigned char v) {
  struct b_reverb *r = (struct b_reverb *)rev;
  setReverbMix(r, (float)v / 127.0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setReverbMixFromMIDI>:
  endbr64
  movzbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  divss  D6(%rip),%xmm0
  jmp    1050 <setReverbMix@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: f32

tool: D6: 127

assistant: ```c
void setReverbMixFromMIDI(void *rev, unsigned char v) {
  struct b_reverb *r = (struct b_reverb *)rev;
  setReverbMix(r, (float)v / 127.0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setReverbMixFromMIDI>:
  endbr64
  movzbl %sil,%esi
  pxor   %xmm0,%xmm0
  cvtsi2ss %esi,%xmm0
  divss  D1(%rip),%xmm0
  jmp    1050 <setReverbMix@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_guessed: f32

tool: D1: 127

assistant: ```c
void setReverbMixFromMIDI(void *rev, unsigned char v) {
  struct b_reverb *r = (struct b_reverb *)rev;
  setReverbMix(r, (float)v / 127.0);
}
```