ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<asus_get_physToGpio>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

assistant: ```c
int *asus_get_physToGpio(int rev) {
  static int physToGpio_AP[64] = {-1, -1, -1, (4 + 248), -1, (5 + 248), -1, 17, (9 + 152), -1, (8 + 152), (12 + 152), (184), (14 + 152), -1, (15 + 152), (10 + 152), -1, (11 + 152), (9 + 248), -1, (8 + 248), (19 + 152), (6 + 248), (7 + 248), -1, (3 + 248), (17 + 216), (18 + 216), (13 + 152), -1, (16 + 152), (23 + 216), (22 + 216), -1, (1 + 184), (7 + 216), (8 + 216), (3 + 184), -1, (4 + 184), -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1};
  return physToGpio_AP;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<asus_get_physToGpio>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

assistant: ```c
int *asus_get_physToGpio(int rev) {
  static int physToGpio_AP[64] = {-1, -1, -1, (4 + 248), -1, (5 + 248), -1, 17, (9 + 152), -1, (8 + 152), (12 + 152), (184), (14 + 152), -1, (15 + 152), (10 + 152), -1, (11 + 152), (9 + 248), -1, (8 + 248), (19 + 152), (6 + 248), (7 + 248), -1, (3 + 248), (17 + 216), (18 + 216), (13 + 152), -1, (16 + 152), (23 + 216), (22 + 216), -1, (1 + 184), (7 + 216), (8 + 216), (3 + 184), -1, (4 + 184), -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1};
  return physToGpio_AP;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BIO_new_ssl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <BIO_f_ssl@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L38
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L42
  cmpl   $0x0,-0x1c(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_set_connect_state@plt>
  jmp    L46
L20:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <SSL_set_accept_state@plt>
L46:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_set_ssl@plt>
  mov    -0x10(%rbp),%rax
  jmp    L4
L38:
  nop
  jmp    L14
L42:
  nop
L14:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
BIO *BIO_new_ssl(SSL_CTX *ctx, int client) {
  BIO *ret;
  SSL *ssl;
  if ((ret = BIO_new(BIO_f_ssl())) == NULL)
    goto err;
  if ((ssl = SSL_new(ctx)) == NULL)
    goto err;
  if (client)
    SSL_set_connect_state(ssl);
  else
    SSL_set_accept_state(ssl);
  BIO_set_ssl(ret, ssl, BIO_CLOSE);
  return (ret);
err:
  BIO_free(ret);
  return (NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BIO_new_ssl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <BIO_f_ssl@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L49
  mov    %rbp,%rdi
  call   <SSL_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L49
  test   %r12d,%r12d
  je     L25
  mov    %rax,%rdi
  call   <SSL_set_connect_state@plt>
L26:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <BIO_set_ssl@plt>
L34:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %rax,%rdi
  call   <SSL_set_accept_state@plt>
  jmp    L26
L49:
  mov    %rbx,%rdi
  call   <BIO_free@plt>
  mov    $0x0,%ebx
  jmp    L34
```

assistant: ```c
BIO *BIO_new_ssl(SSL_CTX *ctx, int client) {
  BIO *ret;
  SSL *ssl;
  if ((ret = BIO_new(BIO_f_ssl())) == NULL)
    goto err;
  if ((ssl = SSL_new(ctx)) == NULL)
    goto err;
  if (client)
    SSL_set_connect_state(ssl);
  else
    SSL_set_accept_state(ssl);
  BIO_set_ssl(ret, ssl, BIO_CLOSE);
  return (ret);
err:
  BIO_free(ret);
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<BIO_new_ssl>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <BIO_f_ssl@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
  mov    %rbp,%rdi
  call   <SSL_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  test   %ebx,%ebx
  jne    L39
  call   <SSL_set_accept_state@plt>
L34:
  mov    D8(%rip),%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <BIO_set_ssl@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  call   <SSL_set_connect_state@plt>
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <BIO_free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
BIO *BIO_new_ssl(SSL_CTX *ctx, int client) {
  BIO *ret;
  SSL *ssl;
  if ((ret = BIO_new(BIO_f_ssl())) == NULL)
    goto err;
  if ((ssl = SSL_new(ctx)) == NULL)
    goto err;
  if (client)
    SSL_set_connect_state(ssl);
  else
    SSL_set_accept_state(ssl);
  BIO_set_ssl(ret, ssl, BIO_CLOSE);
  return (ret);
err:
  BIO_free(ret);
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BIO_new_ssl>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <BIO_f_ssl@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L23
  mov    %rbp,%rdi
  call   <SSL_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L23
  mov    %rax,%rdi
  test   %ebx,%ebx
  jne    L7
  call   <SSL_set_accept_state@plt>
L10:
  mov    D9(%rip),%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    (%rax),%edx
  call   <BIO_set_ssl@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  call   <SSL_set_connect_state@plt>
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <BIO_free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
BIO *BIO_new_ssl(SSL_CTX *ctx, int client) {
  BIO *ret;
  SSL *ssl;
  if ((ret = BIO_new(BIO_f_ssl())) == NULL)
    goto err;
  if ((ssl = SSL_new(ctx)) == NULL)
    goto err;
  if (client)
    SSL_set_connect_state(ssl);
  else
    SSL_set_accept_state(ssl);
  BIO_set_ssl(ret, ssl, BIO_CLOSE);
  return (ret);
err:
  BIO_free(ret);
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bench_madd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L36:
  cmp    %rax,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L32:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%r12
  mov    %rsp,%rax
L98:
  cmp    %rax,%rsp
  je     L80
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L98
L80:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%r13
  mov    %rsp,%rax
L22:
  cmp    %rax,%rsp
  je     L120
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L120:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%r14
  mov    %rsp,%rax
L77:
  cmp    %rax,%rsp
  je     L114
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L77
L114:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%r15
  movl   $0x28,-0x44(%rbp)
  jmp    L76
L128:
  subl   $0x1,-0x44(%rbp)
  je     L48
L76:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%esi
  mov    $0x100,%edx
  mov    %r12,%rdi
  call   <vector_set@plt>
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%esi
  mov    $0x100,%edx
  mov    %r13,%rdi
  call   <vector_set@plt>
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%esi
  mov    $0x100,%edx
  mov    %r14,%rdi
  call   <vector_set@plt>
  mov    $0x14,%ebx
L7:
  mov    $0x100,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <vector_madd_asm@plt>
  sub    $0x1,%ebx
  jne    L7
  jmp    L128
L48:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L94:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bench_madd() {
  const static unsigned int size = 256;
  int i, j;
  int a[size];
  int b[size];
  int c[size];
  int res[size];
  for (i = 0; i < 40; i++) {
    vector_set(a, random(), size);
    vector_set(b, random(), size);
    vector_set(c, random(), size);
    for (j = 0; j < 20; j++)
      vector_madd_asm(res, a, b, c, size);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bench_madd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L98
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L21
L98:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r12
  cmp    %rax,%rsp
  je     L85
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L7
L85:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r13
  cmp    %rax,%rsp
  je     L84
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L52
L84:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r14
  cmp    %rax,%rsp
  je     L15
L89:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L89
L15:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  movl   $0x28,-0x44(%rbp)
  mov    %rsp,%r15
  nopl   0x0(%rax)
L29:
  xor    %eax,%eax
  mov    $0x14,%ebx
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  xor    %eax,%eax
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  xor    %eax,%eax
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x100,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <vector_madd_asm@plt>
  sub    $0x1,%ebx
  jne    L1
  subl   $0x1,-0x44(%rbp)
  jne    L29
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L93:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bench_madd() {
  const static unsigned int size = 256;
  int i, j;
  int a[size];
  int b[size];
  int c[size];
  int res[size];
  for (i = 0; i < 40; i++) {
    vector_set(a, random(), size);
    vector_set(b, random(), size);
    vector_set(c, random(), size);
    for (j = 0; j < 20; j++)
      vector_madd_asm(res, a, b, c, size);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bench_madd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L41
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L22
L41:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r12
  cmp    %rax,%rsp
  je     L62
L69:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L69
L62:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r13
  cmp    %rax,%rsp
  je     L90
L61:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L61
L90:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%rax
  mov    %rsp,%r14
  cmp    %rax,%rsp
  je     L88
L82:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L82
L88:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  movl   $0x28,-0x44(%rbp)
  mov    %rsp,%r15
  nopl   0x0(%rax)
L106:
  xor    %eax,%eax
  mov    $0x14,%ebx
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  xor    %eax,%eax
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  xor    %eax,%eax
  call   <random@plt>
  mov    $0x100,%edx
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <vector_set@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x100,%r8d
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <vector_madd_asm@plt>
  sub    $0x1,%ebx
  jne    L0
  subl   $0x1,-0x44(%rbp)
  jne    L106
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bench_madd() {
  const static unsigned int size = 256;
  int i, j;
  int a[size];
  int b[size];
  int c[size];
  int res[size];
  for (i = 0; i < 40; i++) {
    vector_set(a, random(), size);
    vector_set(b, random(), size);
    vector_set(c, random(), size);
    for (j = 0; j < 20; j++)
      vector_madd_asm(res, a, b, c, size);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L38
L19:
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <WhiteSpace@plt>
  test   %eax,%eax
  jne    L16
  mov    -0x10(%rbp),%rax
  jmp    L28
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L19
  mov    -0x18(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
const char *str_rtrim(const char *start, const char *end) {
  const char *it, *prev;
  assert(start <= end);
  for (it = end; start != it; it = prev) {
    prev = it - 1;
    if (!(WhiteSpace(((unsigned char)(*prev)))))
      return it;
  }
  return start;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_rtrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  cmp    %rsi,%rdi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
L2:
  cmp    %r12,%rbx
  je     L16
  lea    -0x1(%rbx),%rbp
  movzbl -0x1(%rbx),%edi
  call   <WhiteSpace@plt>
  test   %eax,%eax
  je     L29
  mov    %rbp,%rbx
  jmp    L2
L29:
  mov    %rbx,%r12
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *str_rtrim(const char *start, const char *end) {
  const char *it, *prev;
  assert(start <= end);
  for (it = end; start != it; it = prev) {
    prev = it - 1;
    if (!(WhiteSpace(((unsigned char)(*prev)))))
      return it;
  }
  return start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_rtrim>:
  endbr64
  push   %r12
  cmp    %rsi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setbe  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  jmp    L25
L4:
  movzbl -0x1(%rbx),%edi
  lea    -0x1(%rbx),%rbp
  call   <WhiteSpace@plt>
  test   %eax,%eax
  je     L28
  mov    %rbp,%rbx
L25:
  cmp    %r12,%rbx
  jne    L4
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  mov    %rbx,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *str_rtrim(const char *start, const char *end) {
  const char *it, *prev;
  assert(start <= end);
  for (it = end; start != it; it = prev) {
    prev = it - 1;
    if (!(WhiteSpace(((unsigned char)(*prev)))))
      return it;
  }
  return start;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_rtrim>:
  endbr64
  push   %r12
  cmp    %rsi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setbe  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %rsi,%rbx
  call   <assert@plt>
  jmp    L3
L9:
  movzbl -0x1(%rbx),%edi
  lea    -0x1(%rbx),%rbp
  call   <WhiteSpace@plt>
  test   %eax,%eax
  je     L5
  mov    %rbp,%rbx
L3:
  cmp    %r12,%rbx
  jne    L9
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbx,%r12
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
const char *str_rtrim(const char *start, const char *end) {
  const char *it, *prev;
  assert(start <= end);
  for (it = end; start != it; it = prev) {
    prev = it - 1;
    if (!(WhiteSpace(((unsigned char)(*prev)))))
      return it;
  }
  return start;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eppInf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x48(%rbp),%xmm0
  mov    -0x40(%rbp),%rdi
  mov    -0x34(%rbp),%r8d
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <eplb@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L14
  mov    -0x10(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
void eppInf(double *x, double *c, int *iter_step, double *v, int n, double rho, double c0) {
  int i, steps;
  eplb(x, c, &steps, v, n, rho, c0);
  for (i = 0; i < n; i++) {
    x[i] = v[i] - x[i];
  }
  iter_step[0] = steps;
  iter_step[1] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eppInf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <eplb@plt>
  test   %r13d,%r13d
  jle    L21
  mov    %r13d,%r8d
  mov    $0x0,%eax
L15:
  movsd  0x0(%rbp,%rax,8),%xmm0
  subsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L15
L21:
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  movl   $0x0,0x4(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eppInf(double *x, double *c, int *iter_step, double *v, int n, double rho, double c0) {
  int i, steps;
  eplb(x, c, &steps, v, n, rho, c0);
  for (i = 0; i < n; i++) {
    x[i] = v[i] - x[i];
  }
  iter_step[0] = steps;
  iter_step[1] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eppInf>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8d,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <eplb@plt>
  test   %ebp,%ebp
  jle    L23
  movslq %ebp,%r8
  xor    %eax,%eax
  nopl   (%rax)
L26:
  movsd  (%r12,%rax,8),%xmm0
  subsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L26
L23:
  mov    0x4(%rsp),%eax
  movl   $0x0,0x4(%r13)
  mov    %eax,0x0(%r13)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eppInf(double *x, double *c, int *iter_step, double *v, int n, double rho, double c0) {
  int i, steps;
  eplb(x, c, &steps, v, n, rho, c0);
  for (i = 0; i < n; i++) {
    x[i] = v[i] - x[i];
  }
  iter_step[0] = steps;
  iter_step[1] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eppInf>:
  endbr64
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %r13d,%r8d
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <eplb@plt>
  test   %r13d,%r13d
  jle    L48
  lea    0x8(%rbp),%rax
  cmp    %rax,%rbx
  je     L25
  lea    -0x1(%r13),%eax
  cmp    $0x1,%eax
  jbe    L25
  mov    %r13d,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  nopl   (%rax)
L10:
  movupd 0x0(%rbp,%rax,1),%xmm0
  movupd (%rbx,%rax,1),%xmm2
  subpd  %xmm2,%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L10
  mov    %r13d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r13d
  je     L48
  lea    (%rbx,%rax,8),%rdx
  movsd  0x0(%rbp,%rax,8),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L48:
  movl   $0x0,0x4(%r12)
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L60:
  movsd  0x0(%rbp,%rax,8),%xmm0
  subsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L60
  jmp    L48
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void eppInf(double *x, double *c, int *iter_step, double *v, int n, double rho, double c0) {
  int i, steps;
  eplb(x, c, &steps, v, n, rho, c0);
  for (i = 0; i < n; i++) {
    x[i] = v[i] - x[i];
  }
  iter_step[0] = steps;
  iter_step[1] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int x) {
  int a;
  int b;
  return (a + b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int x) {
  int a;
  int b;
  return (a + b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int x) {
  int a;
  int b;
  return (a + b);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int x) {
  int a;
  int b;
  return (a + b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%edx
  mov    $0xab,%esi
  mov    $0x12345678,%edi
  call   <replace_byte@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%edx
  mov    $0xab,%esi
  mov    $0x12345678,%edi
  call   <replace_byte@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: A=%x, B=%x.


assistant: ```c
int main() {
  unsigned A, B;
  A = replace_byte(0x12345678, 0xAB, 2);
  B = replace_byte(0x12345678, 0xAB, 0);
  printf("A=%x, B=%x.\n", A, B);
  return 0;
}
```