ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D15(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2710,%ebx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r15
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x41(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x50(%rsp),%rdi
  mov    %r14,%rsi
  lea    0x1(%rax),%ebp
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  movslq %ebp,%rbp
  nopl   0x0(%rax)
L9:
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <crypto_sign_ecdsa256sha512@plt>
  sub    $0x1,%ebx
  jne    L9
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
data_type: string
name: read_data
arguments: data_label: D3
data_type: string

tool: D15: Hello World!

tool: D3: 10000 signatures completed


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  printf("10000 signatures completed\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2710,%ebx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r15
  call   <strdup@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x41(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x50(%rsp),%rdi
  mov    %r14,%rsi
  lea    0x1(%rax),%ebp
  call   <crypto_sign_keypair_ecdsa256sha512@plt>
  movslq %ebp,%rbp
  nopl   0x0(%rax)
L13:
  mov    %r14,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <crypto_sign_ecdsa256sha512@plt>
  sub    $0x1,%ebx
  jne    L13
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D13
type: string

tool: D10: Hello World!

tool: D13: 10000 signatures completed


assistant: ```c
int main() {
  unsigned char sk[64];
  unsigned char pk[64];
  unsigned char *m = strdup("Hello World!");
  unsigned char *sm = malloc(strlen(m) + 65);
  unsigned long long smlen;
  unsigned long long mlen = strlen(m) + 1;
  crypto_sign_keypair_ecdsa256sha512(pk, sk);
  for (int i = 0; i < 10000; i++)
    crypto_sign_ecdsa256sha512(sm, &smlen, m, mlen, sk);
  printf("10000 signatures completed\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CStrings__extract_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L75
L39:
  subl   $0x1,-0x38(%rbp)
  jmp    L20
L27:
  addl   $0x1,-0x18(%rbp)
L20:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <Characters__is_space_or_tab@plt>
  test   %rax,%rax
  jne    L27
  movl   $0x0,-0x14(%rbp)
  jmp    L59
L19:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L70
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x14(%rbp)
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <Characters__tolower@plt>
  mov    %al,(%rbx)
L70:
  addl   $0x1,-0x18(%rbp)
L59:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L109
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <Characters__is_space_or_tab@plt>
  test   %rax,%rax
  je     L19
L109:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L77
L75:
  cmpl   $0x0,-0x38(%rbp)
  jg     L39
  jmp    L50
L77:
  nop
L50:
  cmpl   $0x0,-0x38(%rbp)
  jle    L78
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
L78:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void CStrings__extract_word(char *fword, char *line, int size, int word) {
  int i = 0;
  fword[0] = 0;
  while (word > 0) {
    word--;
    while (Characters__is_space_or_tab(line[i]))
      i++;
    int j = 0;
    while ((line[i]) && (!Characters__is_space_or_tab(line[i]))) {
      if (j < size - 1)
        fword[j++] = Characters__tolower(line[i]);
      i++;
    }
    fword[j] = 0;
    if (line[i] == 0)
      break;
  }
  if (word > 0)
    fword[0] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<CStrings__extract_word>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x18(%rsp)
  mov    %ecx,0x14(%rsp)
  movb   $0x0,(%rdi)
  mov    $0x0,%r12d
  lea    -0x1(%rdx),%r14d
  jmp    L19
L38:
  add    $0x1,%r12d
  mov    %rbx,%r13
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  je     L97
L94:
  movsbl %dil,%edi
  call   <Characters__is_space_or_tab@plt>
  test   %rax,%rax
  jne    L97
  cmp    %ebp,%r14d
  jle    L38
  lea    0x1(%rbp),%r15d
  movslq %ebp,%rbp
  add    0x8(%rsp),%rbp
  movsbl 0x0(%r13),%edi
  call   <Characters__tolower@plt>
  mov    %al,0x0(%rbp)
  mov    %r15d,%ebp
  jmp    L38
L8:
  mov    %ebp,%r12d
  mov    $0x0,%ebp
L97:
  movslq %ebp,%rbp
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax,%rbp,1)
  cmpb   $0x0,0x0(%r13)
  je     L109
L19:
  cmpl   $0x0,0x14(%rsp)
  jle    L92
  subl   $0x1,0x14(%rsp)
  movslq %r12d,%rax
  add    0x18(%rsp),%rax
  mov    %rax,%rbx
  sub    %eax,%r12d
L48:
  lea    (%r12,%rbx,1),%ebp
  mov    %rbx,%r13
  movsbl (%rbx),%edi
  call   <Characters__is_space_or_tab@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L48
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L8
  movslq %ebp,%rax
  mov    0x18(%rsp),%rdx
  lea    0x1(%rdx,%rax,1),%rbx
  mov    %ebp,%r12d
  mov    $0x0,%ebp
  jmp    L94
L109:
  cmpl   $0x0,0x14(%rsp)
  jle    L92
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
L92:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CStrings__extract_word(char *fword, char *line, int size, int word) {
  int i = 0;
  fword[0] = 0;
  while (word > 0) {
    word--;
    while (Characters__is_space_or_tab(line[i]))
      i++;
    int j = 0;
    while ((line[i]) && (!Characters__is_space_or_tab(line[i]))) {
      if (j < size - 1)
        fword[j++] = Characters__tolower(line[i]);
      i++;
    }
    fword[j] = 0;
    if (line[i] == 0)
      break;
  }
  if (word > 0)
    fword[0] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CStrings__extract_word>:
  endbr64
  push   %r15
  lea    -0x1(%rdx),%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  movb   $0x0,(%rdi)
  mov    %rsi,0x18(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %eax,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L62
  subl   $0x1,0x14(%rsp)
  movslq %ebx,%rax
  add    0x18(%rsp),%rax
  sub    %eax,%ebx
  nopl   0x0(%rax,%rax,1)
L89:
  movsbl (%rax),%edi
  mov    %rax,%r15
  lea    (%rbx,%rax,1),%ebp
  call   <Characters__is_space_or_tab@plt>
  mov    %rax,%r8
  lea    0x1(%r15),%rax
  test   %r8,%r8
  jne    L89
  movsbl (%r15),%edi
  mov    %r13,%rsi
  mov    %ebp,%ebx
  test   %dil,%dil
  je     L36
  mov    0x18(%rsp),%rdx
  movslq %ebp,%rax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  lea    0x1(%rdx,%rax,1),%r14
  jmp    L25
  nopl   0x0(%rax)
L70:
  mov    %r14,%r15
  movsbl (%r14),%edi
  lea    0x1(%r14),%r14
  add    $0x1,%ebx
  test   %dil,%dil
  je     L82
L25:
  call   <Characters__is_space_or_tab@plt>
  lea    0x0(%r13,%r12,1),%rsi
  test   %rax,%rax
  jne    L36
  cmp    %ebp,0x10(%rsp)
  jle    L70
  movsbl (%r15),%edi
  mov    %rsi,0x8(%rsp)
  add    $0x1,%ebp
  movslq %ebp,%r12
  call   <Characters__tolower@plt>
  mov    0x8(%rsp),%rsi
  mov    %al,(%rsi)
  jmp    L70
  nopl   (%rax)
L82:
  lea    0x0(%r13,%r12,1),%rsi
L36:
  movb   $0x0,(%rsi)
  cmpb   $0x0,(%r15)
  jne    L24
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L62
  movb   $0x0,0x0(%r13)
L62:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void CStrings__extract_word(char *fword, char *line, int size, int word) {
  int i = 0;
  fword[0] = 0;
  while (word > 0) {
    word--;
    while (Characters__is_space_or_tab(line[i]))
      i++;
    int j = 0;
    while ((line[i]) && (!Characters__is_space_or_tab(line[i]))) {
      if (j < size - 1)
        fword[j++] = Characters__tolower(line[i]);
      i++;
    }
    fword[j] = 0;
    if (line[i] == 0)
      break;
  }
  if (word > 0)
    fword[0] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CStrings__extract_word>:
  endbr64
  push   %r15
  lea    -0x1(%rdx),%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  movb   $0x0,(%rdi)
  mov    %rsi,0x18(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %eax,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L16:
  mov    0x14(%rsp),%edx
  test   %edx,%edx
  jle    L39
  subl   $0x1,0x14(%rsp)
  movslq %ebx,%rax
  add    0x18(%rsp),%rax
  sub    %eax,%ebx
  nopl   0x0(%rax,%rax,1)
L83:
  movsbl (%rax),%edi
  mov    %rax,%r15
  lea    (%rbx,%rax,1),%ebp
  call   <Characters__is_space_or_tab@plt>
  mov    %rax,%r8
  lea    0x1(%r15),%rax
  test   %r8,%r8
  jne    L83
  movsbl (%r15),%edi
  mov    %r13,%rsi
  mov    %ebp,%ebx
  test   %dil,%dil
  je     L84
  mov    0x18(%rsp),%rdx
  movslq %ebp,%rax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  lea    0x1(%rdx,%rax,1),%r14
  nopw   0x0(%rax,%rax,1)
L57:
  call   <Characters__is_space_or_tab@plt>
  lea    0x0(%r13,%r12,1),%rsi
  test   %rax,%rax
  jne    L84
  cmp    %ebp,0x10(%rsp)
  jg     L67
  mov    %r14,%r15
  movsbl (%r14),%edi
  add    $0x1,%r14
  add    $0x1,%ebx
  test   %dil,%dil
  jne    L57
L47:
  lea    0x0(%r13,%r12,1),%rsi
L84:
  movb   $0x0,(%rsi)
  cmpb   $0x0,(%r15)
  jne    L16
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L39
  movb   $0x0,0x0(%r13)
L39:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L67:
  movsbl (%r15),%edi
  mov    %rsi,0x8(%rsp)
  mov    %r14,%r15
  lea    0x1(%r14),%r14
  add    $0x1,%ebp
  add    $0x1,%ebx
  call   <Characters__tolower@plt>
  mov    0x8(%rsp),%rsi
  movslq %ebp,%r12
  mov    %al,(%rsi)
  movsbl -0x1(%r14),%edi
  test   %dil,%dil
  jne    L57
  jmp    L47
```

assistant: ```c
void CStrings__extract_word(char *fword, char *line, int size, int word) {
  int i = 0;
  fword[0] = 0;
  while (word > 0) {
    word--;
    while (Characters__is_space_or_tab(line[i]))
      i++;
    int j = 0;
    while ((line[i]) && (!Characters__is_space_or_tab(line[i]))) {
      if (j < size - 1)
        fword[j++] = Characters__tolower(line[i]);
      i++;
    }
    fword[j] = 0;
    if (line[i] == 0)
      break;
  }
  if (word > 0)
    fword[0] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__netif_subqueue_stopped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <netif_queue_stopped@plt>
  leave
  ret
```

assistant: ```c
int __netif_subqueue_stopped(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  return netif_queue_stopped(dev);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__netif_subqueue_stopped>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbx,%rdi
  call   <netif_queue_stopped@plt>
  pop    %rbx
  ret
```

assistant: ```c
int __netif_subqueue_stopped(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  return netif_queue_stopped(dev);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__netif_subqueue_stopped>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <netif_queue_stopped@plt>
```

assistant: ```c
int __netif_subqueue_stopped(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  return netif_queue_stopped(dev);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__netif_subqueue_stopped>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edi
  call   <WARN_ON@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <netif_queue_stopped@plt>
```

assistant: ```c
int __netif_subqueue_stopped(struct net_device *dev, int fifo_no) {
  WARN_ON(1);
  return netif_queue_stopped(dev);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L43:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L30
L75:
  mov    -0x18(%rbp),%eax
  cmp    $0x4,%eax
  jle    L43
  mov    -0x18(%rbp),%eax
  cmp    $0xa,%eax
  jg     L43
  jmp    L103
L30:
  nop
L103:
  mov    -0x18(%rbp),%eax
  cmp    $0x5,%eax
  jle    L74
  mov    -0x18(%rbp),%eax
  cmp    $0xa,%eax
  jg     L74
  mov    -0x18(%rbp),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
  jmp    L36
L74:
  addl   $0x1,-0xc(%rbp)
L36:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L75
  cmpl   $0x0,-0x10(%rbp)
  jne    L108
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L108:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L9:
  cmpl   $0x0,-0xc(%rbp)
  je     L104
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L104:
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D43
datatype: string
name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D62
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string
name: parse_data
arguments: data_label: D58
datatype: string

tool: D18: vnesi ocena od 5 do 10 : 

tool: D43: %d

tool: D34: Nema polozeni ispiti

tool: D62: Prosekot e %4.2f


tool: D3: Padnal na %d ispiti


tool: D58: Ne padnal na ispit

assistant: ```c
int main() {
  int ocena, suma = 0, broceni = 0, padnal = 0;
  while (scanf("%d", &ocena) == 1) {
    while (ocena < 5 || ocena > 10) {
      printf("vnesi ocena od 5 do 10 : ");
      if (scanf("%d", &ocena) != 1)
        break;
    }
    if (ocena >= 6 && ocena <= 10) {
      suma += ocena;
      broceni++;
    } else
      padnal++;
  }
  if (broceni == 0)
    printf("Nema polozeni ispiti");
  else
    printf("Prosekot e %4.2f\n", (float)suma / broceni);
  if (padnal != 0)
    printf("Padnal na %d ispiti\n", padnal);
  else
    printf("Ne padnal na ispit\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  mov    $0x0,%r15d
  lea    0x4(%rsp),%rbp
  lea    D37(%rip),%rbx
  lea    D15(%rip),%r12
  jmp    L104
L23:
  mov    0x4(%rsp),%eax
  lea    -0x6(%rax),%edx
  cmp    $0x4,%edx
  ja     L28
  add    %eax,%r15d
  add    $0x1,%r14d
L104:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L44
L100:
  mov    0x4(%rsp),%eax
  sub    $0x5,%eax
  cmp    $0x5,%eax
  jbe    L23
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L100
  jmp    L23
L28:
  add    $0x1,%r13d
  jmp    L104
L44:
  test   %r14d,%r14d
  jne    L81
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L99:
  test   %r13d,%r13d
  je     L84
  mov    %r13d,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  pxor   %xmm0,%xmm0
  cvtsi2ss %r15d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r14d,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D52(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L99
L84:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L15
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D42
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D52
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D37: %d

tool: D15: vnesi ocena od 5 do 10 : 

tool: D42: Nema polozeni ispiti

tool: D25: Padnal na %d ispiti


tool: D52: Prosekot e %4.2f


tool: D3: Ne padnal na ispit

assistant: ```c
int main() {
  int ocena, suma = 0, broceni = 0, padnal = 0;
  while (scanf("%d", &ocena) == 1) {
    while (ocena < 5 || ocena > 10) {
      printf("vnesi ocena od 5 do 10 : ");
      if (scanf("%d", &ocena) != 1)
        break;
    }
    if (ocena >= 6 && ocena <= 10) {
      suma += ocena;
      broceni++;
    } else
      padnal++;
  }
  if (broceni == 0)
    printf("Nema polozeni ispiti");
  else
    printf("Prosekot e %4.2f\n", (float)suma / broceni);
  if (padnal != 0)
    printf("Padnal na %d ispiti\n", padnal);
  else
    printf("Ne padnal na ispit\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D40(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  xchg   %ax,%ax
L70:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L84
  jmp    L116
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L31
L84:
  mov    0x4(%rsp),%eax
  lea    -0x5(%rax),%edx
  cmp    $0x5,%edx
  ja     L3
L49:
  lea    -0x6(%rax),%edx
  cmp    $0x4,%edx
  ja     L21
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    %eax,%r15d
  add    $0x1,%r14d
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L84
L116:
  test   %r14d,%r14d
  jne    L4
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L18:
  test   %r13d,%r13d
  je     L8
  mov    %r13d,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L21:
  add    $0x1,%r13d
  jmp    L70
  nopl   0x0(%rax)
L31:
  mov    0x4(%rsp),%eax
  jmp    L49
L4:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  cvtsi2ss %r15d,%xmm0
  lea    D34(%rip),%rdi
  cvtsi2ss %r14d,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L18
L8:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  jmp    L25
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D40
data_type: string
name: unpack_data
arguments: data_tag: D53
data_type: string
name: unpack_data
arguments: data_tag: D56
data_type: string
name: unpack_data
arguments: data_tag: D34
data_type: string
name: unpack_data
arguments: data_tag: D41
data_type: string

tool: D22: vnesi ocena od 5 do 10 : 

tool: D40: %d

tool: D53: Nema polozeni ispiti

tool: D56: Padnal na %d ispiti


tool: D34: Prosekot e %4.2f


tool: D41: Ne padnal na ispit

assistant: ```c
int main() {
  int ocena, suma = 0, broceni = 0, padnal = 0;
  while (scanf("%d", &ocena) == 1) {
    while (ocena < 5 || ocena > 10) {
      printf("vnesi ocena od 5 do 10 : ");
      if (scanf("%d", &ocena) != 1)
        break;
    }
    if (ocena >= 6 && ocena <= 10) {
      suma += ocena;
      broceni++;
    } else
      padnal++;
  }
  if (broceni == 0)
    printf("Nema polozeni ispiti");
  else
    printf("Prosekot e %4.2f\n", (float)suma / broceni);
  if (padnal != 0)
    printf("Padnal na %d ispiti\n", padnal);
  else
    printf("Ne padnal na ispit\n");
  return 0;
}
```