ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_bank_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cpu_is_exynos5@plt>
  test   %rax,%rax
  je     L35
  mov    $0x0,%eax
  call   <proid_is_exynos5420@plt>
  test   %rax,%rax
  jne    L80
  mov    $0x0,%eax
  call   <proid_is_exynos5800@plt>
  test   %rax,%rax
  je     L4
L80:
  mov    $0x6,%eax
  jmp    L10
L4:
  mov    $0x8,%eax
  jmp    L10
L35:
  mov    $0x0,%eax
  call   <cpu_is_exynos4@plt>
  test   %rax,%rax
  je     L41
  mov    $0x0,%eax
  call   <proid_is_exynos4412@plt>
  test   %rax,%rax
  je     L50
  mov    $0x8,%eax
  jmp    L10
L50:
  mov    $0x4,%eax
  jmp    L10
L41:
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int get_bank_num(void) {
  if (cpu_is_exynos5()) {
    if (proid_is_exynos5420() || proid_is_exynos5800())
      return 6;
    else
      return 8;
  } else if (cpu_is_exynos4()) {
    if (proid_is_exynos4412())
      return 8;
    else
      return 4;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_bank_num>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cpu_is_exynos5@plt>
  test   %rax,%rax
  je     L22
  mov    $0x0,%eax
  call   <proid_is_exynos5420@plt>
  mov    %rax,%rdx
  mov    $0x6,%eax
  test   %rdx,%rdx
  jne    L49
  mov    $0x0,%eax
  call   <proid_is_exynos5800@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x2,%eax
  add    $0x6,%eax
  jmp    L49
L22:
  mov    $0x0,%eax
  call   <cpu_is_exynos4@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L30
L49:
  add    $0x8,%rsp
  ret
L30:
  call   <proid_is_exynos4412@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xfffffffc,%eax
  add    $0x8,%eax
  jmp    L49
```

assistant: ```c
unsigned int get_bank_num(void) {
  if (cpu_is_exynos5()) {
    if (proid_is_exynos5420() || proid_is_exynos5800())
      return 6;
    else
      return 8;
  } else if (cpu_is_exynos4()) {
    if (proid_is_exynos4412())
      return 8;
    else
      return 4;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_bank_num>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cpu_is_exynos5@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L16
  call   <proid_is_exynos5420@plt>
  test   %rax,%rax
  jne    L10
  call   <proid_is_exynos5800@plt>
  test   %rax,%rax
  je     L56
L10:
  mov    $0x6,%eax
L24:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  call   <cpu_is_exynos4@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L24
  call   <proid_is_exynos4412@plt>
  test   %rax,%rax
  jne    L56
  mov    $0x4,%eax
  jmp    L24
L56:
  mov    $0x8,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int get_bank_num(void) {
  if (cpu_is_exynos5()) {
    if (proid_is_exynos5420() || proid_is_exynos5800())
      return 6;
    else
      return 8;
  } else if (cpu_is_exynos4()) {
    if (proid_is_exynos4412())
      return 8;
    else
      return 4;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_bank_num>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cpu_is_exynos5@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L13
  call   <proid_is_exynos5420@plt>
  test   %rax,%rax
  jne    L47
  call   <proid_is_exynos5800@plt>
  test   %rax,%rax
  je     L24
L47:
  mov    $0x6,%eax
L22:
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  call   <cpu_is_exynos4@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L22
  call   <proid_is_exynos4412@plt>
  test   %rax,%rax
  jne    L24
  mov    $0x4,%eax
  jmp    L22
L24:
  mov    $0x8,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int get_bank_num(void) {
  if (cpu_is_exynos5()) {
    if (proid_is_exynos5420() || proid_is_exynos5800())
      return 6;
    else
      return 8;
  } else if (cpu_is_exynos4()) {
    if (proid_is_exynos4412())
      return 8;
    else
      return 4;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test9>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movabs $0x807060504030201,%rax
  movabs $0x100f0e0d0c0b0a09,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x7766554433221100,%rax
  movabs $0xffeeddccbbaa9988,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  mov    %rax,0x70(%rsp)
  mov    %rdx,0x78(%rsp)
  movabs $0xcb0f73a4c6a9501e,%rax
  movabs $0x33c17734fe4c2207,%rdx
  mov    %rax,0x80(%rsp)
  mov    %rdx,0x88(%rsp)
  movabs $0xb50de7fdfcb45b0e,%rax
  movabs $0x5dc78bbc1276cef3,%rdx
  mov    %rax,0x90(%rsp)
  mov    %rdx,0x98(%rsp)
  movabs $0x503e05d8f940d4c7,%rax
  movabs $0x188c161f9938cfd6,%rdx
  mov    %rax,0xa0(%rsp)
  mov    %rdx,0xa8(%rsp)
  movabs $0xf05165e01e89e1bf,%rax
  movabs $0x8279b2a2a88da259,%rdx
  mov    %rax,0xb0(%rsp)
  mov    %rdx,0xb8(%rsp)
  movabs $0xcd33d38bd428a629,%rax
  movabs $0xaa9f087e49cae199,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  lea    0x40(%rsp),%rcx
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x10(%rsp),%rax
  push   %rax
  push   $0x40
  lea    0x90(%rsp),%r9
  mov    $0x40,%r8d
  mov    $0x20,%edx
  call   <run_test@plt>
  add    $0x10,%rsp
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0xd8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test9() {
  unsigned long long mlen = 4 * 16;
  const unsigned long long clen = mlen;
  const unsigned long long hlen = 2 * 16;
  const unsigned char k[16] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
  const unsigned char h[2 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char m[4 * 16] = {0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff, 0x00, 0x11, 0x22, 0x33, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99, 0xaa, 0xbb, 0xcc, 0xdd, 0xee, 0xff};
  const unsigned char c[4 * 16] = {0x1e, 0x50, 0xa9, 0xc6, 0xa4, 0x73, 0x0f, 0xcb, 0x07, 0x22, 0x4c, 0xfe, 0x34, 0x77, 0xc1, 0x33, 0x0e, 0x5b, 0xb4, 0xfc, 0xfd, 0xe7, 0x0d, 0xb5, 0xf3, 0xce, 0x76, 0x12, 0xbc, 0x8b, 0xc7, 0x5d, 0xc7, 0xd4, 0x40, 0xf9, 0xd8, 0x05, 0x3e, 0x50, 0xd6, 0xcf, 0x38, 0x99, 0x1f, 0x16, 0x8c, 0x18, 0xbf, 0xe1, 0x89, 0x1e, 0xe0, 0x65, 0x51, 0xf0, 0x59, 0xa2, 0x8d, 0xa8, 0xa2, 0xb2, 0x79, 0x82};
  const unsigned char t[16] = {0x29, 0xa6, 0x28, 0xd4, 0x8b, 0xd3, 0x33, 0xcd, 0x99, 0xe1, 0xca, 0x49, 0x7e, 0x08, 0x9f, 0xaa};
  return run_test(k, h, hlen, m, mlen, c, clen, t);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pbit(unsigned int nbloque) {
  int i = nbloque % 8;
  return (i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pbit>:
  endbr64
  mov    %edi,%eax
  and    $0x7,%eax
  ret
```

assistant: ```c
int pbit(unsigned int nbloque) {
  int i = nbloque % 8;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pbit>:
  endbr64
  mov    %edi,%eax
  and    $0x7,%eax
  ret
```

assistant: ```c
int pbit(unsigned int nbloque) {
  int i = nbloque % 8;
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pbit>:
  endbr64
  mov    %edi,%eax
  and    $0x7,%eax
  ret
```

assistant: ```c
int pbit(unsigned int nbloque) {
  int i = nbloque % 8;
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: &d

assistant: ```c
int read(int *ip) {
  scanf("&d", ip);
  return *ip;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: &d

assistant: ```c
int read(int *ip) {
  scanf("&d", ip);
  return *ip;
}
```
user: What is the c source code of the assembly code below?

```asm
<read>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: &d

assistant: ```c
int read(int *ip) {
  scanf("&d", ip);
  return *ip;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
data_type: string

tool: D4: &d

assistant: ```c
int read(int *ip) {
  scanf("&d", ip);
  return *ip;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_str_mk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L0
L5:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_str_mk(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_str_mk>:
  endbr64
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  movzbl (%rsi),%ecx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L12
L2:
  add    $0x1,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L2
L12:
  ret
```

assistant: ```c
char *my_str_mk(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_str_mk>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L17
  nopl   0x0(%rax)
L8:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L8
L17:
  ret
```

assistant: ```c
char *my_str_mk(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_str_mk>:
  endbr64
  movzbl (%rsi),%ecx
  mov    %rdi,%rax
  lea    0x1(%rsi),%rdx
  mov    %cl,(%rdi)
  test   %cl,%cl
  je     L19
  nopl   0x0(%rax)
L8:
  movzbl (%rdx),%ecx
  add    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,(%rax)
  test   %cl,%cl
  jne    L8
L19:
  ret
```

assistant: ```c
char *my_str_mk(char *dst, const char *src) {
  while ((*dst = *src++))
    ++dst;
  return dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<testUtility>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x4,-0x14(%rbp)
  movw   $0xb,-0x12(%rbp)
  movw   $0x8,-0x10(%rbp)
  movw   $0xa,-0xe(%rbp)
  movw   $0x6,-0xc(%rbp)
  movw   $0x8,-0xa(%rbp)
  movl   $0x6,-0x18(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%ecx
  lea    -0x14(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <byteSwap@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L39
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  movzwl -0x14(%rbp,%rax,2),%eax
  cwtl
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L39:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x18(%rbp),%ecx
  lea    -0x14(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <byteSwap@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L18
L19:
  mov    -0x1c(%rbp),%eax
  cltq
  movzwl -0x14(%rbp,%rax,2),%eax
  cwtl
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L19
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
datatype: string
name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D25: 
Utilities

tool: D8: Byte swap

tool: D7: %d 

assistant: ```c
void testUtility() {
  int i, n;
  short int b[] = {4, 11, 8, 10, 6, 8};
  n = 6;
  printf("\nUtilities\n");
  printf("Byte swap\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<testUtility>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movw   $0x4,0xc(%rsp)
  movw   $0xb,0xe(%rsp)
  movw   $0x8,0x10(%rsp)
  movw   $0xa,0x12(%rsp)
  movw   $0x6,0x14(%rsp)
  movw   $0x8,0x16(%rsp)
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rbx
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <byteSwap@plt>
  mov    %rbx,%rbp
  lea    0x18(%rsp),%r12
  lea    D30(%rip),%r13
L8:
  movswl (%rbx),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%rbx
  cmp    %r12,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0xc(%rsp),%rdi
  mov    $0x2,%edx
  mov    $0x6,%esi
  call   <byteSwap@plt>
  lea    D30(%rip),%rbx
L0:
  movswl 0x0(%rbp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%rbp
  cmp    %r12,%rbp
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string
name: retrieve_data
arguments: tag: D33
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string

tool: D9: 
Utilities

tool: D33: Byte swap

tool: D30: %d 

assistant: ```c
void testUtility() {
  int i, n;
  short int b[] = {4, 11, 8, 10, 6, 8};
  n = 6;
  printf("\nUtilities\n");
  printf("Byte swap\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<testUtility>:
  endbr64
  push   %r14
  lea    D6(%rip),%rdi
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa0008000b0004,%rax
  lea    0xc(%rsp),%r14
  movl   $0x80006,0x14(%rsp)
  lea    0x18(%rsp),%r12
  mov    %r14,%rbx
  mov    %r14,%rbp
  mov    %rax,0xc(%rsp)
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %r14,%rdi
  call   <byteSwap@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  movswl 0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %r14,%rdi
  call   <byteSwap@plt>
  nopl   0x0(%rax,%rax,1)
L24:
  movswl (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L24
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D25
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D6: 
Utilities

tool: D25: %d 

tool: D13: Byte swap

assistant: ```c
void testUtility() {
  int i, n;
  short int b[] = {4, 11, 8, 10, 6, 8};
  n = 6;
  printf("\nUtilities\n");
  printf("Byte swap\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testUtility>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x8(%rsp),%r14
  movl   $0x80006,0x10(%rsp)
  mov    %r14,%rbx
  lea    0x14(%rsp),%r12
  mov    %r14,%rbp
  mov    %rax,0x8(%rsp)
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %r14,%rdi
  call   <byteSwap@plt>
  nopl   (%rax)
L25:
  movswl 0x0(%rbp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x2,%edx
  mov    $0x6,%esi
  mov    %r14,%rdi
  call   <byteSwap@plt>
  nopl   0x0(%rax,%rax,1)
L11:
  movswl (%rbx),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x2,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D8
type: byte[8]
name: read_data
arguments: tag: D24
type: string

tool: D13: 
Utilities

tool: D18: %d 

tool: {"D8": [0x04,0x00,0x0b,0x00,0x08,0x00,0x0a,0x00]}

tool: D24: Byte swap

assistant: ```c
void testUtility() {
  int i, n;
  short int b[] = {4, 11, 8, 10, 6, 8};
  n = 6;
  printf("\nUtilities\n");
  printf("Byte swap\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
  byteSwap(b, n, 2);
  for (i = 0; i < n; i++) {
    printf("%d ", b[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pool_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L1
L7:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L1:
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void pool_destroy(void **pool) {
  void *temp, *next;
  next = pool;
  while (next) {
    temp = next;
    next = *(void **)temp;
    free(temp);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pool_destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L16
L10:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L10
L16:
  pop    %rbx
  ret
```

assistant: ```c
void pool_destroy(void **pool) {
  void *temp, *next;
  next = pool;
  while (next) {
    temp = next;
    next = *(void **)temp;
    free(temp);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pool_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L12
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L8:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L8
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void pool_destroy(void **pool) {
  void *temp, *next;
  next = pool;
  while (next) {
    temp = next;
    next = *(void **)temp;
    free(temp);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pool_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L12
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L3:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L3
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
void pool_destroy(void **pool) {
  void *temp, *next;
  next = pool;
  while (next) {
    temp = next;
    next = *(void **)temp;
    free(temp);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<computeArea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x2c(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crossVectors@plt>
  movss  -0x2c(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x28(%rbp),%xmm2
  movss  -0x28(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movss  -0x24(%rbp),%xmm2
  movss  -0x24(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movd   %xmm0,%eax
  movss  D2(%rip),%xmm0
  movd   %eax,%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x40]}

assistant: ```c
float computeArea(const float v0[3], const float v1[3], const float v2[3]) {
  float res[3], v0v1[3], v0v2[3];
  v0v1[0] = v1[0] - v0[0];
  v0v1[1] = v1[1] - v0[1];
  v0v1[2] = v1[2] - v0[2];
  v0v2[0] = v2[0] - v0[0];
  v0v2[1] = v2[1] - v0[1];
  v0v2[2] = v2[2] - v0[2];
  crossVectors(v0v1, v0v2, res);
  return ((float)(sqrt(res[0] * res[0] + res[1] * res[1] + res[2] * res[2]) / 2.0f));
}
```