ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<print_plot_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  cmp    $0xfff,%edi
  jg     L100
  cmp    $0xfff,%esi
  jg     L18
  mov    $0x800,%eax
  cmp    %eax,%esi
  cmovge %esi,%eax
  mov    %eax,%ebp
  mov    %rsp,%r12
  mov    $0x6e,%esi
  mov    %r12,%rdi
  call   <bzero@plt>
  mov    $0x800,%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  lea    -0x800(%rbx),%esi
  mov    %r12,%rdx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  cltq
  lea    0x1(%rsp,%rax,1),%rcx
  mov    %r12,%rax
L36:
  movb   $0x2a,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L36
  sub    $0x800,%ebp
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x23,%rax
  sar    $0x1f,%ebp
  sub    %ebp,%eax
  cltq
  cmpb   $0x2a,(%rsp,%rax,1)
  je     L95
  movb   $0x7c,(%rsp,%rax,1)
  test   %rax,%rax
  je     L114
  add    %rax,%r12
  jmp    L82
L100:
  lea    -0x800(%rdi),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L18:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L73
L95:
  movb   $0x2b,(%rsp,%rax,1)
L114:
  mov    %rsp,%rdx
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L73:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  add    $0x1,%rdx
  cmp    %r12,%rdx
  je     L114
L82:
  cmpb   $0x0,(%rdx)
  jne    L15
  movb   $0x20,(%rdx)
  jmp    L15
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string

tool: D26: %5d: value is out of range


tool: D5: %5d: baseline is out of range


tool: D12: %5d: %s


assistant: ```c
void print_plot_str(uint16_t value, uint16_t baseline) {
  char str[110];
  int32_t idx, i;
  if (value > 4095) {
    printf("%5d: value is out of range\n", value - 2048);
    return;
  }
  if (baseline > 4095) {
    printf("%5d: baseline is out of range\n", baseline);
    return;
  }
  if (value < 2048) {
    value = 2048;
  }
  if (baseline < 2048) {
    baseline = 2048;
  }
  bzero(str, sizeof(str));
  idx = (value - 2048) / 20;
  for (i = 0; i <= idx; i++) {
    str[i] = '*';
  }
  idx = (baseline - 2048) / 20;
  if (str[idx] == '*') {
    str[idx] = '+';
  } else {
    str[idx] = '|';
    for (i = 0; i < idx; i++) {
      if (str[i] == '\0') {
        str[i] = ' ';
      }
    }
  }
  printf("%5d: %s\n", value - 2048, str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fnEncryption@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  fnEncryption();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fnEncryption@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fnEncryption();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fnEncryption@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fnEncryption();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fnEncryption@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fnEncryption();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<computarOperacao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L20
L56:
  movq   $0x0,-0x10(%rbp)
  jmp    L78
L69:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    $0xb,%eax
  sub    -0x10(%rbp),%rax
  movsd  (%rdx,%rax,8),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L78:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L69
  addq   $0x1,-0x18(%rbp)
L20:
  cmpq   $0x5,-0x18(%rbp)
  jbe    L56
  movq   $0x6,-0x18(%rbp)
  jmp    L32
L111:
  movq   $0x0,-0x10(%rbp)
  jmp    L58
L82:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    $0xb,%eax
  sub    -0x10(%rbp),%rax
  movsd  (%rdx,%rax,8),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L58:
  mov    $0xb,%eax
  sub    -0x18(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L82
  addq   $0x1,-0x18(%rbp)
L32:
  cmpq   $0xb,-0x18(%rbp)
  jbe    L111
  cmpb   $0x53,-0x24(%rbp)
  jne    L94
  movsd  -0x20(%rbp),%xmm1
  jmp    L30
L94:
  mov    -0x8(%rbp),%rax
  test   %rax,%rax
  js     L17
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L112
L17:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L112:
  movsd  -0x20(%rbp),%xmm1
  divsd  %xmm0,%xmm1
L30:
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double computarOperacao(char operacao, double matriz[][12]) {
  double soma = 0;
  size_t i, j, posicoesSomadas = 0;
  for (i = 0; i < 12 / 2; i++) {
    for (j = 0; j < i; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  for (i = 12 / 2; i < 12; i++) {
    for (j = 0; j < 12 - i - 1; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  if (operacao == 'S') {
    return soma;
  } else {
    return soma / posicoesSomadas;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<computarOperacao>:
  endbr64
  mov    %edi,%r11d
  mov    %rsi,%r10
  mov    %rsi,%rdi
  mov    %rsi,%rdx
  mov    $0x1,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  pxor   %xmm0,%xmm0
  jmp    L97
L42:
  add    $0x1,%rcx
  add    $0x1,%r8
  add    $0x60,%rdi
  add    $0x58,%rdx
L97:
  mov    %rdi,%rax
  test   %rcx,%rcx
  je     L42
L16:
  addsd  0x58(%rax),%xmm0
  sub    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
  add    %rcx,%rsi
  cmp    $0x5,%r8
  jbe    L42
  mov    $0x6,%ecx
  mov    $0x5,%r9d
  mov    $0x0,%edx
  mov    $0xb,%r8d
  jmp    L87
L53:
  mov    $0x0,%edx
L87:
  lea    (%rcx,%rcx,2),%rax
  shl    $0x5,%rax
  add    %r10,%rax
  mov    %r8,%rdi
  sub    %rdx,%rdi
  addsd  (%rax,%rdi,8),%xmm0
  add    $0x1,%rsi
  add    $0x1,%rdx
  cmp    %rdx,%r9
  ja     L87
  add    $0x1,%rcx
  cmp    $0xb,%rcx
  ja     L15
  mov    %r8,%r9
  sub    %rcx,%r9
  jne    L53
L15:
  cmp    $0x53,%r11b
  je     L69
  test   %rsi,%rsi
  js     L96
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
L12:
  divsd  %xmm1,%xmm0
L69:
  ret
L96:
  mov    %rsi,%rax
  shr    %rax
  and    $0x1,%esi
  or     %rsi,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L12
```

assistant: ```c
double computarOperacao(char operacao, double matriz[][12]) {
  double soma = 0;
  size_t i, j, posicoesSomadas = 0;
  for (i = 0; i < 12 / 2; i++) {
    for (j = 0; j < i; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  for (i = 12 / 2; i < 12; i++) {
    for (j = 0; j < 12 - i - 1; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  if (operacao == 'S') {
    return soma;
  } else {
    return soma / posicoesSomadas;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<computarOperacao>:
  endbr64
  mov    %edi,%r11d
  mov    %rsi,%r10
  mov    %rsi,%r8
  mov    %rsi,%rdx
  xor    %edi,%edi
  xor    %esi,%esi
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax,%rax,1)
L63:
  lea    0x1(%rdi),%rcx
  mov    %r8,%rax
  test   %rdi,%rdi
  je     L106
  nopl   0x0(%rax)
L99:
  addsd  0x58(%rax),%xmm0
  sub    $0x8,%rax
  cmp    %rax,%rdx
  jne    L99
  add    %rdi,%rsi
  cmp    $0x6,%rcx
  je     L34
L106:
  add    $0x60,%r8
  add    $0x58,%rdx
  mov    %rcx,%rdi
  jmp    L63
  nopl   0x0(%rax)
L34:
  mov    $0x5,%r9d
  xor    %edx,%edx
  mov    $0xb,%r8d
  cs nopw 0x0(%rax,%rax,1)
L103:
  lea    (%rcx,%rcx,2),%rax
  mov    %r8,%rdi
  add    $0x1,%rsi
  shl    $0x5,%rax
  sub    %rdx,%rdi
  add    $0x1,%rdx
  add    %r10,%rax
  addsd  (%rax,%rdi,8),%xmm0
  cmp    %r9,%rdx
  jb     L103
  add    $0x1,%rcx
  cmp    $0xc,%rcx
  je     L56
  mov    %r8,%r9
  sub    %rcx,%r9
  je     L56
  xor    %edx,%edx
  jmp    L103
  nopl   0x0(%rax)
L56:
  cmp    $0x53,%r11b
  je     L62
  test   %rsi,%rsi
  js     L46
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
L18:
  divsd  %xmm1,%xmm0
L62:
  ret
L46:
  mov    %rsi,%rax
  and    $0x1,%esi
  pxor   %xmm1,%xmm1
  shr    %rax
  or     %rsi,%rax
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L18
```

assistant: ```c
double computarOperacao(char operacao, double matriz[][12]) {
  double soma = 0;
  size_t i, j, posicoesSomadas = 0;
  for (i = 0; i < 12 / 2; i++) {
    for (j = 0; j < i; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  for (i = 12 / 2; i < 12; i++) {
    for (j = 0; j < 12 - i - 1; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  if (operacao == 'S') {
    return soma;
  } else {
    return soma / posicoesSomadas;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<computarOperacao>:
  endbr64
  pxor   %xmm0,%xmm0
  addsd  0xb8(%rsi),%xmm0
  mov    %edi,%ecx
  xor    %edx,%edx
  addsd  0x118(%rsi),%xmm0
  addsd  0x110(%rsi),%xmm0
  mov    $0x6,%edi
  mov    $0x5,%r11d
  addsd  0x178(%rsi),%xmm0
  addsd  0x170(%rsi),%xmm0
  mov    $0xf,%r8d
  mov    $0xb,%r10d
  addsd  0x168(%rsi),%xmm0
  addsd  0x1d8(%rsi),%xmm0
  addsd  0x1d0(%rsi),%xmm0
  addsd  0x1c8(%rsi),%xmm0
  addsd  0x1c0(%rsi),%xmm0
  addsd  0x238(%rsi),%xmm0
  addsd  0x230(%rsi),%xmm0
  addsd  0x228(%rsi),%xmm0
  addsd  0x220(%rsi),%xmm0
  addsd  0x218(%rsi),%xmm0
  nopl   0x0(%rax,%rax,1)
L26:
  lea    (%rdi,%rdi,2),%rax
  mov    %r10,%r9
  add    $0x1,%r8
  shl    $0x5,%rax
  sub    %rdx,%r9
  add    $0x1,%rdx
  add    %rsi,%rax
  addsd  (%rax,%r9,8),%xmm0
  cmp    %r11,%rdx
  jb     L26
  add    $0x1,%rdi
  cmp    $0xc,%rdi
  je     L65
  mov    %r10,%r11
  sub    %rdi,%r11
  je     L65
  xor    %edx,%edx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L65:
  cmp    $0x53,%cl
  je     L15
  test   %r8,%r8
  js     L18
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8,%xmm1
L34:
  divsd  %xmm1,%xmm0
L15:
  ret
L18:
  mov    %r8,%rax
  and    $0x1,%r8d
  pxor   %xmm1,%xmm1
  shr    %rax
  or     %r8,%rax
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L34
```

assistant: ```c
double computarOperacao(char operacao, double matriz[][12]) {
  double soma = 0;
  size_t i, j, posicoesSomadas = 0;
  for (i = 0; i < 12 / 2; i++) {
    for (j = 0; j < i; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  for (i = 12 / 2; i < 12; i++) {
    for (j = 0; j < 12 - i - 1; j++) {
      soma += matriz[i][12 - j - 1];
      posicoesSomadas++;
    }
  }
  if (operacao == 'S') {
    return soma;
  } else {
    return soma / posicoesSomadas;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x1,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
L7:
  mov    -0x28(%rbp),%rax
  and    $0x1,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  shr    %rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long binary(unsigned long number) {
  unsigned long module, i = 1, total = 0;
  do {
    module = number % 2;
    total += i * module;
    number /= 2;
    i *= 10;
  } while (number > 0);
  return total;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binary>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x1,%eax
L2:
  mov    %rdi,%rdx
  and    $0x1,%edx
  imul   %rax,%rdx
  add    %rdx,%rcx
  mov    %rdi,%rdx
  shr    %rdi
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  cmp    $0x1,%rdx
  ja     L2
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long binary(unsigned long number) {
  unsigned long module, i = 1, total = 0;
  do {
    module = number % 2;
    total += i * module;
    number /= 2;
    i *= 10;
  } while (number > 0);
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binary>:
  endbr64
  xor    %r8d,%r8d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L4:
  mov    %rdi,%rdx
  and    $0x1,%edx
  imul   %rax,%rdx
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  add    %rdx,%r8
  mov    %rdi,%rdx
  shr    %rdi
  cmp    $0x1,%rdx
  ja     L4
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long binary(unsigned long number) {
  unsigned long module, i = 1, total = 0;
  do {
    module = number % 2;
    total += i * module;
    number /= 2;
    i *= 10;
  } while (number > 0);
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<binary>:
  endbr64
  xor    %r8d,%r8d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rdx
  and    $0x1,%edx
  imul   %rax,%rdx
  lea    (%rax,%rax,4),%rax
  add    %rax,%rax
  add    %rdx,%r8
  mov    %rdi,%rdx
  shr    %rdi
  cmp    $0x1,%rdx
  ja     L1
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long binary(unsigned long number) {
  unsigned long module, i = 1, total = 0;
  do {
    module = number % 2;
    total += i * module;
    number /= 2;
    i *= 10;
  } while (number > 0);
  return total;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x10,%edi
  lea    D18(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x10,%ecx
  mov    $0x4,%edx
  mov    $0x8,%esi
  mov    %rax,%rbx
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  mov    $0x1,%edx
  xor    %esi,%esi
  lea    D52(%rip),%rbp
  movl   $0x1,(%rax)
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  movl   $0x2,0x4(%rax)
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%rax
  mov    %rbp,%rdi
  mov    0x4(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%esi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D39
type: string
name: read_data
arguments: tag: D52
type: string
name: read_data
arguments: tag: D20
type: string
name: read_data
arguments: tag: D76
type: string
name: read_data
arguments: tag: D28
type: string
name: read_data
arguments: tag: D69
type: string

tool: D18: Copying b[%d][%d]


tool: D12: sizeof(*b)=%ld sizeof(**b)=%ld total size %ld


tool: D39: %ld


tool: D52: %d 

tool: D20: Printing Two Dimensional array with %d rows and %d columns


tool: D76: %d


tool: D28: Must print 1 if you have machine which is Little Endian

tool: D69: size of struct t %ld


assistant: ```c
int main() {
  unsigned int x = 1;
  double y;
  struct t {
    char c;
  };
  int a[3][4] = {{0, 1, 2, 3}, {4, 5, 6, 7}, {8, 9, 10, 11}};
  int rows = 1;
  int columns = 2;
  int start = 1;
  int i, j;
  int **b = NULL;
  b = malloc(sizeof(*b) * rows + (rows * columns * sizeof(**b)));
  printf("sizeof(*b)=%ld sizeof(**b)=%ld total size %ld\n", sizeof(*b), sizeof(**b), (sizeof(*b) * rows + (rows * columns * sizeof(**b))));
  printf("%ld\n", (char *)(&y + 1) - (char *)(&y));
  getchar();
  for (i = 0; i < rows; i++) {
    for (j = 0; j < columns; j++) {
      printf("Copying b[%d][%d]\n", i, j);
      b[i][j] = start++;
    }
    start += 10;
  }
  printf("Printing Two Dimensional array with %d rows and %d columns\n", rows, columns);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < columns; j++) {
      printf("%d ", b[i][j]);
    }
    printf("\n");
    start += 10;
  }
  printf("%d\n", (int)(((char *)&x)[0]));
  printf("Must print 1 if you have machine which is Little Endian\n");
  printf("size of struct t %ld\n", sizeof(struct t));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mem_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L3
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L55:
  mov    -0x18(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L55
  jmp    L10
L3:
  mov    -0x24(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x2,%rax
  add    %rax,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L58:
  subq   $0x4,-0x18(%rbp)
  subq   $0x4,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L58
  nop
L10:
  pop    %rbp
  ret
```

assistant: ```c
void mem_copy(int *source, int *destination, unsigned int length) {
  int i;
  if (source < destination) {
    for (i = 0; i < length; i++) {
      *(destination++) = *(source++);
    }
  } else {
    source += length;
    destination += length;
    for (i = 0; i < length; i++) {
      *(--destination) = *(--source);
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mem_copy>:
  endbr64
  cmp    %rsi,%rdi
  jae    L5
  test   %edx,%edx
  je     L47
  mov    %edx,%edx
  mov    $0x0,%eax
L46:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L46
  ret
L5:
  mov    %edx,%eax
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L47
  lea    -0x1(%rdx),%eax
  neg    %rax
  lea    -0x8(,%rax,4),%rcx
  mov    $0xfffffffffffffffc,%rax
L13:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  sub    $0x4,%rax
  cmp    %rax,%rcx
  jne    L13
L47:
  ret
```

assistant: ```c
void mem_copy(int *source, int *destination, unsigned int length) {
  int i;
  if (source < destination) {
    for (i = 0; i < length; i++) {
      *(destination++) = *(source++);
    }
  } else {
    source += length;
    destination += length;
    for (i = 0; i < length; i++) {
      *(--destination) = *(--source);
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_copy>:
  endbr64
  cmp    %rsi,%rdi
  jae    L28
  test   %edx,%edx
  je     L42
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L31:
  mov    (%rdi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L31
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %edx,%eax
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  je     L42
  lea    -0x1(%rdx),%eax
  neg    %rax
  lea    -0x8(,%rax,4),%rcx
  mov    $0xfffffffffffffffc,%rax
  nopl   (%rax)
L26:
  mov    (%rdi,%rax,1),%edx
  mov    %edx,(%rsi,%rax,1)
  sub    $0x4,%rax
  cmp    %rax,%rcx
  jne    L26
L42:
  ret
```

assistant: ```c
void mem_copy(int *source, int *destination, unsigned int length) {
  int i;
  if (source < destination) {
    for (i = 0; i < length; i++) {
      *(destination++) = *(source++);
    }
  } else {
    source += length;
    destination += length;
    for (i = 0; i < length; i++) {
      *(--destination) = *(--source);
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mem_copy>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%rax
  mov    %edx,%esi
  cmp    %rcx,%rdi
  jae    L154
  test   %esi,%esi
  je     L53
  lea    0x4(%rdi),%rdi
  mov    %rcx,%rdx
  sub    %rdi,%rdx
  cmp    $0x8,%rdx
  jbe    L132
  lea    -0x1(%rsi),%edx
  cmp    $0x2,%edx
  jbe    L132
  mov    %esi,%edi
  xor    %edx,%edx
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L135:
  movdqu (%rax,%rdx,1),%xmm0
  movups %xmm0,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L135
  mov    %esi,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%edx
  shl    $0x2,%rdx
  add    %rdx,%rax
  add    %rcx,%rdx
  cmp    %edi,%esi
  je     L53
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  lea    0x1(%rdi),%ecx
  cmp    %ecx,%esi
  jbe    L53
  mov    0x4(%rax),%ecx
  add    $0x2,%edi
  mov    %ecx,0x4(%rdx)
  cmp    %edi,%esi
  jbe    L53
  mov    0x8(%rax),%eax
  mov    %eax,0x8(%rdx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L84:
  neg    %r10
  mov    $0xfffffffffffffffc,%rax
  lea    -0x8(,%r10,4),%rcx
  nopw   0x0(%rax,%rax,1)
L88:
  mov    (%r8,%rax,1),%edx
  mov    %edx,(%r9,%rax,1)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L88
L53:
  ret
  nopw   0x0(%rax,%rax,1)
L154:
  mov    %esi,%edx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%r8
  lea    (%rcx,%rdx,1),%r9
  test   %esi,%esi
  je     L53
  mov    %rcx,%rdi
  lea    -0x1(%rsi),%r10d
  sub    %rax,%rdi
  add    $0xc,%rdi
  cmp    $0x8,%rdi
  jbe    L84
  cmp    $0x2,%r10d
  jbe    L84
  mov    %esi,%edi
  sub    $0x10,%rdx
  shr    $0x2,%edi
  add    %rdx,%rax
  add    %rdx,%rcx
  xor    %edx,%edx
  neg    %rdi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L151:
  movdqu (%rax,%rdx,1),%xmm1
  movups %xmm1,(%rcx,%rdx,1)
  sub    $0x10,%rdx
  cmp    %rdx,%rdi
  jne    L151
  mov    %esi,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%eax
  neg    %rax
  shl    $0x2,%rax
  cmp    %edx,%esi
  je     L53
  sub    $0x4,%rax
  add    %rax,%r8
  add    %r9,%rax
  mov    (%r8),%ecx
  mov    %ecx,(%rax)
  lea    0x1(%rdx),%ecx
  cmp    %ecx,%esi
  jbe    L53
  mov    -0x4(%r8),%ecx
  add    $0x2,%edx
  mov    %ecx,-0x4(%rax)
  cmp    %edx,%esi
  jbe    L53
  mov    -0x8(%r8),%edx
  mov    %edx,-0x8(%rax)
  ret
L132:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L127:
  mov    (%rax,%rdx,4),%edi
  mov    %edi,(%rcx,%rdx,4)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L127
  ret
```

assistant: ```c
void mem_copy(int *source, int *destination, unsigned int length) {
  int i;
  if (source < destination) {
    for (i = 0; i < length; i++) {
      *(destination++) = *(source++);
    }
  } else {
    source += length;
    destination += length;
    for (i = 0; i < length; i++) {
      *(--destination) = *(--source);
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stringtrim_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L4
L12:
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
L2:
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
const char *stringtrim_l(const char *string) {
  if (!string)
    return NULL;
  while (*string && isspace(*string))
    string++;
  return string;
}
```