ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L20
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L34:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rbx,%rdi
  sub    $0x4,%rbx
  mov    -0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L0
  mov    %rbx,%rsi
  call   <swap@plt>
  cmp    %rbp,%rbx
  jne    L22
L0:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <print_arr@plt>
  cmp    %r12d,%r14d
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  ret
```

assistant: ```c
void insertion_sort(int *arr, int n) {
  int i;
  for (i = 1; i < n; ++i) {
    int j = i;
    while ((j > 0) && (arr[j] < arr[j - 1])) {
      swap(&arr[j], &arr[j - 1]);
      j--;
    }
    print_arr(arr, n);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    0x4(%rdi),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L12:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  sub    $0x4,%rbx
  mov    -0x4(%rdi),%eax
  cmp    %eax,(%rdi)
  jge    L22
  mov    %rbx,%rsi
  call   <swap@plt>
  cmp    %rbp,%rbx
  jne    L0
L22:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <print_arr@plt>
  cmp    %r12d,%r14d
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  ret
```

assistant: ```c
void insertion_sort(int *arr, int n) {
  int i;
  for (i = 1; i < n; ++i) {
    int j = i;
    while ((j > 0) && (arr[j] < arr[j - 1])) {
      swap(&arr[j], &arr[j - 1]);
      j--;
    }
    print_arr(arr, n);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  jmp    L43
L59:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L51
  mov    -0x4(%rbp),%eax
  jmp    L42
L51:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L40
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  jmp    L43
L40:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
L43:
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L59
  mov    $0xffffffff,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int bin_search(int a[], int reqV, int start, int end) {
  int middle;
  while (end >= start) {
    middle = (start + end) / 2;
    if (reqV == a[middle])
      return middle;
    if (reqV < a[middle])
      end = middle - 1;
    else
      start = middle + 1;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<bin_search>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L37
  mov    $0xffffffff,%r9d
  jmp    L11
L38:
  lea    0x1(%rax),%edx
L36:
  cmp    %ecx,%edx
  jg     L42
L37:
  lea    (%rdx,%rcx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  mov    %eax,%r9d
  movslq %eax,%rdi
  mov    (%r8,%rdi,4),%edi
  cmp    %esi,%edi
  je     L11
  jle    L38
  lea    -0x1(%rax),%ecx
  jmp    L36
L42:
  mov    $0xffffffff,%r9d
L11:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int bin_search(int a[], int reqV, int start, int end) {
  int middle;
  while (end >= start) {
    middle = (start + end) / 2;
    if (reqV == a[middle])
      return middle;
    if (reqV < a[middle])
      end = middle - 1;
    else
      start = middle + 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bin_search>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L0
  jmp    L10
  nopl   (%rax)
L33:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L10
L0:
  lea    (%rcx,%rdx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %esi,(%r8,%rdi,4)
  je     L11
  jg     L33
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L0
L10:
  mov    $0xffffffff,%r9d
L11:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int bin_search(int a[], int reqV, int start, int end) {
  int middle;
  while (end >= start) {
    middle = (start + end) / 2;
    if (reqV == a[middle])
      return middle;
    if (reqV < a[middle])
      end = middle - 1;
    else
      start = middle + 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bin_search>:
  endbr64
  nopl   0x0(%rax)
L30:
  cmp    %ecx,%edx
  jg     L24
L34:
  lea    (%rcx,%rdx,1),%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  movslq %eax,%r8
  cmp    %esi,(%rdi,%r8,4)
  je     L17
  jle    L1
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jge    L34
L24:
  mov    $0xffffffff,%eax
L17:
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x1(%rax),%edx
  jmp    L30
```

assistant: ```c
int bin_search(int a[], int reqV, int start, int end) {
  int middle;
  while (end >= start) {
    middle = (start + end) / 2;
    if (reqV == a[middle])
      return middle;
    if (reqV < a[middle])
      end = middle - 1;
    else
      start = middle + 1;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nCrModpLucas@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D37
datatype: string
name: read_data
arguments: label: D41
datatype: string
name: read_data
arguments: label: D52
datatype: string
name: read_data
arguments: label: D43
datatype: string
name: read_data
arguments: label: D63
datatype: string

tool: D37: Enter the value of n (in nCr) : 

tool: D41: %d

tool: D52: Enter the value of r (in nCr) : 

tool: D43: Enter the value of p: 

tool: D63: Value of nCr mod %d is %d 

assistant: ```c
int main() {
  int n, r, p;
  printf("Enter the value of n (in nCr) : ");
  scanf("%d", &n);
  printf("Enter the value of r (in nCr) : ");
  scanf("%d", &r);
  printf("Enter the value of p: ");
  scanf("%d", &p);
  printf("Value of nCr mod %d is %d ", p, nCrModpLucas(n, r, p));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <nCrModpLucas@plt>
  mov    %eax,%edx
  mov    0x14(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D31
type: string
name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D43
type: string
name: unpack_data
arguments: data_tag: D18
type: string

tool: D31: Enter the value of n (in nCr) : 

tool: D23: %d

tool: D11: Enter the value of r (in nCr) : 

tool: D43: Enter the value of p: 

tool: D18: Value of nCr mod %d is %d 

assistant: ```c
int main() {
  int n, r, p;
  printf("Enter the value of n (in nCr) : ");
  scanf("%d", &n);
  printf("Enter the value of r (in nCr) : ");
  scanf("%d", &r);
  printf("Enter the value of p: ");
  scanf("%d", &p);
  printf("Value of nCr mod %d is %d ", p, nCrModpLucas(n, r, p));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  lea    D23(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <nCrModpLucas@plt>
  mov    0x14(%rsp),%esi
  lea    D33(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D33
type_guessed: string

tool: D31: Enter the value of n (in nCr) : 

tool: D23: %d

tool: D15: Enter the value of r (in nCr) : 

tool: D2: Enter the value of p: 

tool: D33: Value of nCr mod %d is %d 

assistant: ```c
int main() {
  int n, r, p;
  printf("Enter the value of n (in nCr) : ");
  scanf("%d", &n);
  printf("Enter the value of r (in nCr) : ");
  scanf("%d", &r);
  printf("Enter the value of p: ");
  scanf("%d", &p);
  printf("Value of nCr mod %d is %d ", p, nCrModpLucas(n, r, p));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D23(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <nCrModpLucas@plt>
  mov    0x14(%rsp),%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string
name: unpack_data
arguments: data_label: D34
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D28: Enter the value of n (in nCr) : 

tool: D23: %d

tool: D34: Enter the value of r (in nCr) : 

tool: D19: Enter the value of p: 

tool: D6: Value of nCr mod %d is %d 

assistant: ```c
int main() {
  int n, r, p;
  printf("Enter the value of n (in nCr) : ");
  scanf("%d", &n);
  printf("Enter the value of r (in nCr) : ");
  scanf("%d", &r);
  printf("Enter the value of p: ");
  scanf("%d", &p);
  printf("Value of nCr mod %d is %d ", p, nCrModpLucas(n, r, p));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: string

tool: D8: %d

assistant: ```c
int main() {
  printf("%d", foo(5));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main() {
  printf("%d", foo(5));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <foo@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  printf("%d", foo(5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <foo@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  printf("%d", foo(5));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<libmesh_C_isnan_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  movss  -0x4(%rbp),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L3
  mov    $0x0,%eax
L3:
  movzbl %al,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: libmesh_C_isnan_float is deprecated and should not be used!


assistant: ```c
int libmesh_C_isnan_float(float a) {
  printf("libmesh_C_isnan_float is deprecated and should not be used!\n");
  return (a != a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<libmesh_C_isnan_float>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  lea    D6(%rip),%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm1
  ucomiss %xmm1,%xmm1
  setp   %al
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: libmesh_C_isnan_float is deprecated and should not be used!


assistant: ```c
int libmesh_C_isnan_float(float a) {
  printf("libmesh_C_isnan_float is deprecated and should not be used!\n");
  return (a != a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<libmesh_C_isnan_float>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  xor    %eax,%eax
  ucomiss %xmm0,%xmm0
  setp   %al
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: libmesh_C_isnan_float is deprecated and should not be used!


assistant: ```c
int libmesh_C_isnan_float(float a) {
  printf("libmesh_C_isnan_float is deprecated and should not be used!\n");
  return (a != a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libmesh_C_isnan_float>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  xor    %eax,%eax
  ucomiss %xmm0,%xmm0
  setp   %al
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: libmesh_C_isnan_float is deprecated and should not be used!


assistant: ```c
int libmesh_C_isnan_float(float a) {
  printf("libmesh_C_isnan_float is deprecated and should not be used!\n");
  return (a != a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<linear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L34
  mov    $0xffffffff,%eax
  jmp    L5
L34:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L0
  mov    -0xc(%rbp),%eax
  jmp    L5
L0:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <linear>
L5:
  leave
  ret
```

assistant: ```c
int linear(int a[], int s, int e, int num) {
  if (s > e)
    return -1;
  if (a[s] == num)
    return s;
  else
    linear(a, s + 1, e, num);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<linear>:
  endbr64
  mov    $0xffffffff,%eax
  cmp    %edx,%esi
  jg     L14
  movslq %esi,%r8
  mov    %esi,%eax
  cmp    %ecx,(%rdi,%r8,4)
  je     L14
  sub    $0x8,%rsp
  add    $0x1,%esi
  call   <linear>
  add    $0x8,%rsp
  ret
L14:
  ret
```

assistant: ```c
int linear(int a[], int s, int e, int num) {
  if (s > e)
    return -1;
  if (a[s] == num)
    return s;
  else
    linear(a, s + 1, e, num);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<linear>:
  endbr64
  cmp    %esi,%edx
  jl     L19
  movslq %esi,%rsi
  jmp    L35
  nopl   (%rax)
L17:
  add    $0x1,%rsi
  cmp    %esi,%edx
  jl     L19
L35:
  mov    %esi,%eax
  cmp    %ecx,(%rdi,%rsi,4)
  jne    L17
  ret
L19:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int linear(int a[], int s, int e, int num) {
  if (s > e)
    return -1;
  if (a[s] == num)
    return s;
  else
    linear(a, s + 1, e, num);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<linear>:
  endbr64
  cmp    %esi,%edx
  jl     L3
  movslq %esi,%rsi
  jmp    L15
  nopl   (%rax)
L25:
  add    $0x1,%rsi
  cmp    %esi,%edx
  jl     L3
L15:
  mov    %esi,%eax
  cmp    %ecx,(%rdi,%rsi,4)
  jne    L25
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int linear(int a[], int s, int e, int num) {
  if (s > e)
    return -1;
  if (a[s] == num)
    return s;
  else
    linear(a, s + 1, e, num);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L29:
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L15:
  mov    $0x0,%eax
  call   <random@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%ecx
  imul   -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L29
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <patch@plt>
  nop
  leave
  ret
```

assistant: ```c
void fill(int mwidth, int *m) {
  for (int i = 0; i < mwidth; i++) {
    for (int j = 0; j < mwidth; j++) {
      m[i * mwidth + j] = random() % 2;
    }
  }
  patch(mwidth, m);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fill>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L2
  movslq %edi,%r15
  shl    $0x2,%r15
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
  mov    $0x0,%r12d
  mov    %edi,%r14d
  neg    %r14
  shl    $0x2,%r14
L27:
  lea    (%r14,%rbp,1),%rbx
L28:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L28
  add    $0x1,%r12d
  add    %r15,%rbp
  cmp    %r12d,%r13d
  jne    L27
L2:
  mov    0x8(%rsp),%rsi
  mov    %r13d,%edi
  call   <patch@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void fill(int mwidth, int *m) {
  for (int i = 0; i < mwidth; i++) {
    for (int j = 0; j < mwidth; j++) {
      m[i * mwidth + j] = random() % 2;
    }
  }
  patch(mwidth, m);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fill>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L1
  lea    -0x1(%rdi),%eax
  movslq %edi,%r14
  mov    $0xfffffffffffffffc,%r13
  xor    %ebp,%ebp
  shl    $0x2,%rax
  shl    $0x2,%r14
  lea    0x4(%rsi,%rax,1),%rbx
  sub    %rax,%r13
  nopl   (%rax)
L8:
  lea    0x0(%r13,%rbx,1),%r15
  nopl   (%rax)
L2:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <random@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%r15)
  cmp    %rbx,%r15
  jne    L2
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r12d
  jne    L8
L1:
  mov    0x8(%rsp),%rsi
  add    $0x18,%rsp
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <patch@plt>
```

assistant: ```c
void fill(int mwidth, int *m) {
  for (int i = 0; i < mwidth; i++) {
    for (int j = 0; j < mwidth; j++) {
      m[i * mwidth + j] = random() % 2;
    }
  }
  patch(mwidth, m);
}
```
user: What is the c source code of the assembly code below:

```asm
<fill>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  test   %edi,%edi
  jle    L19
  lea    -0x1(%rdi),%eax
  movslq %edi,%r14
  mov    $0xfffffffffffffffc,%r13
  xor    %ebp,%ebp
  shl    $0x2,%rax
  shl    $0x2,%r14
  lea    0x4(%rsi,%rax,1),%rbx
  sub    %rax,%r13
  nopl   (%rax)
L24:
  lea    0x0(%r13,%rbx,1),%r15
  nopl   (%rax)
L20:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <random@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%r15)
  cmp    %rbx,%r15
  jne    L20
  add    $0x1,%ebp
  add    %r14,%rbx
  cmp    %ebp,%r12d
  jne    L24
L19:
  mov    0x8(%rsp),%rsi
  add    $0x18,%rsp
  mov    %r12d,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <patch@plt>
```

assistant: ```c
void fill(int mwidth, int *m) {
  for (int i = 0; i < mwidth; i++) {
    for (int j = 0; j < mwidth; j++) {
      m[i * mwidth + j] = random() % 2;
    }
  }
  patch(mwidth, m);
}
```