ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vec_norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vec_len@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L3
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L3
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  jmp    L9
L3:
  movss  D1(%rip),%xmm0
  divss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L54
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vec_norm(float *out, const float *in, int len) {
  float vlen = vec_len(in, len);
  if (vlen == 0.0f) {
    for (int i = 0; i < len; i++) {
      out[i] = 0.0f;
    }
    return;
  }
  vlen = 1.0f / vlen;
  for (int i = 0; i < len; i++) {
    out[i] = in[i] * vlen;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vec_norm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,%esi
  mov    %r12,%rdi
  call   <vec_len@plt>
  ucomiss D8(%rip),%xmm0
  jp     L65
  je     L30
L65:
  movss  D19(%rip),%xmm1
  divss  %xmm0,%xmm1
  test   %ebx,%ebx
  jle    L52
  mov    %ebx,%edx
  mov    $0x0,%eax
L21:
  movaps %xmm1,%xmm0
  mulss  (%r12,%rax,4),%xmm0
  movss  %xmm0,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L21
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  test   %ebx,%ebx
  jle    L52
  mov    %rbp,%rax
  lea    -0x1(%rbx),%edx
  lea    0x4(%rbp,%rdx,4),%rdx
L64:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L64
  jmp    L52
```

tool_calls: name: unpack_data
arguments: tag: D8
type: byte[4]
name: unpack_data
arguments: tag: D19
type: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x00]}

tool: {"D19": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vec_norm(float *out, const float *in, int len) {
  float vlen = vec_len(in, len);
  if (vlen == 0.0f) {
    for (int i = 0; i < len; i++) {
      out[i] = 0.0f;
    }
    return;
  }
  vlen = 1.0f / vlen;
  for (int i = 0; i < len; i++) {
    out[i] = in[i] * vlen;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vec_norm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %edx,%esi
  push   %rbx
  mov    %rbp,%rdi
  mov    %edx,%ebx
  call   <vec_len@plt>
  ucomiss D12(%rip),%xmm0
  jp     L20
  je     L37
L20:
  movss  D9(%rip),%xmm1
  divss  %xmm0,%xmm1
  test   %ebx,%ebx
  jle    L32
  movslq %ebx,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  movss  0x0(%rbp,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L3
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L37:
  test   %ebx,%ebx
  jle    L32
  movslq %ebx,%rdx
  mov    %r12,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  shl    $0x2,%rdx
  pop    %r12
  jmp    1060 <memset@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type: byte[4]
name: extract_symbolic_data
arguments: tag: D9
type: byte[4]

tool: {"D12": [0x00,0x00,0x00,0x00]}

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vec_norm(float *out, const float *in, int len) {
  float vlen = vec_len(in, len);
  if (vlen == 0.0f) {
    for (int i = 0; i < len; i++) {
      out[i] = 0.0f;
    }
    return;
  }
  vlen = 1.0f / vlen;
  for (int i = 0; i < len; i++) {
    out[i] = in[i] * vlen;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vec_norm>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vec_len@plt>
  ucomiss D3(%rip),%xmm0
  jp     L48
  je     L37
L48:
  movss  D15(%rip),%xmm1
  divss  %xmm0,%xmm1
  test   %ebp,%ebp
  jle    L56
  lea    0x4(%rbx),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L90
  cmp    $0x1,%ebp
  je     L90
  lea    -0x1(%rbp),%eax
  mov    %ebp,%ecx
  cmp    $0x2,%eax
  jbe    L106
  mov    %ebp,%edx
  movaps %xmm1,%xmm2
  xor    %eax,%eax
  shr    $0x2,%edx
  shufps $0x0,%xmm2,%xmm2
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L77:
  movups (%rbx,%rax,1),%xmm0
  mulps  %xmm2,%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L77
  mov    %ebp,%edx
  and    $0xfffffffc,%edx
  mov    %edx,%eax
  cmp    %edx,%ebp
  je     L56
  mov    %ebp,%ecx
  sub    %edx,%ecx
  cmp    $0x1,%ecx
  je     L57
L64:
  movq   (%rbx,%rdx,4),%xmm0
  movaps %xmm1,%xmm2
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm0
  movlps %xmm0,(%r12,%rdx,4)
  mov    %ecx,%edx
  and    $0xfffffffe,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L56
L57:
  cltq
  mulss  (%rbx,%rax,4),%xmm1
  movss  %xmm1,(%r12,%rax,4)
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  test   %ebp,%ebp
  jle    L56
  movslq %ebp,%rdx
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  shl    $0x2,%rdx
  xor    %esi,%esi
  pop    %r12
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L90:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L103:
  movss  (%rbx,%rax,4),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L103
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L106:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L64
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: byte[4]
name: unpack_data
arguments: data_label: D15
type: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x00]}

tool: {"D15": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vec_norm(float *out, const float *in, int len) {
  float vlen = vec_len(in, len);
  if (vlen == 0.0f) {
    for (int i = 0; i < len; i++) {
      out[i] = 0.0f;
    }
    return;
  }
  vlen = 1.0f / vlen;
  for (int i = 0; i < len; i++) {
    out[i] = in[i] * vlen;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <pinentry_init@plt>
  mov    $0x0,%eax
  call   <pinentry_emacs_init@plt>
  test   %eax,%eax
  jne    L0
  mov    $0x1,%eax
  jmp    L33
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <pinentry_parse_opts@plt>
  mov    $0x0,%eax
  call   <pinentry_loop@plt>
  test   %rax,%rax
  je     L30
  mov    $0x1,%eax
  jmp    L33
L30:
  mov    $0x0,%eax
L33:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: pinentry-emacs

assistant: ```c
int main(int argc, char *argv[]) {
  pinentry_init("pinentry-emacs");
  if (!pinentry_emacs_init())
    return 1;
  pinentry_parse_opts(argc, argv);
  if (pinentry_loop())
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    D3(%rip),%rdi
  call   <pinentry_init@plt>
  mov    $0x0,%eax
  call   <pinentry_emacs_init@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L3
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <pinentry_parse_opts@plt>
  mov    $0x0,%eax
  call   <pinentry_loop@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: pinentry-emacs

assistant: ```c
int main(int argc, char *argv[]) {
  pinentry_init("pinentry-emacs");
  if (!pinentry_emacs_init())
    return 1;
  pinentry_parse_opts(argc, argv);
  if (pinentry_loop())
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <pinentry_init@plt>
  xor    %eax,%eax
  call   <pinentry_emacs_init@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L0
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <pinentry_parse_opts@plt>
  xor    %eax,%eax
  call   <pinentry_loop@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string

tool: D6: pinentry-emacs

assistant: ```c
int main(int argc, char *argv[]) {
  pinentry_init("pinentry-emacs");
  if (!pinentry_emacs_init())
    return 1;
  pinentry_parse_opts(argc, argv);
  if (pinentry_loop())
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <pinentry_init@plt>
  xor    %eax,%eax
  call   <pinentry_emacs_init@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L3
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <pinentry_parse_opts@plt>
  xor    %eax,%eax
  call   <pinentry_loop@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: pinentry-emacs

assistant: ```c
int main(int argc, char *argv[]) {
  pinentry_init("pinentry-emacs");
  if (!pinentry_emacs_init())
    return 1;
  pinentry_parse_opts(argc, argv);
  if (pinentry_loop())
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qu2euLoopf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %rdx,-0xa8(%rbp)
  mov    %ecx,-0xac(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x4,-0x70(%rbp)
  movq   $0x3,-0x68(%rbp)
  movq   $0x0,-0x78(%rbp)
  jmp    L2
L5:
  mov    -0x78(%rbp),%rax
  imul   -0x70(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x78(%rbp),%rax
  imul   -0x68(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x80(%rbp)
  jmp    L13
L14:
  mov    -0x60(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    -0x80(%rbp),%rax
  movsd  %xmm0,-0x30(%rbp,%rax,8)
  addq   $0x1,-0x80(%rbp)
L13:
  mov    -0x80(%rbp),%rax
  cmp    -0x70(%rbp),%rax
  jb     L14
  mov    -0xac(%rbp),%edx
  lea    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <qu2eu@plt>
  mov    %eax,-0x84(%rbp)
  movq   $0x0,-0x80(%rbp)
  jmp    L48
L20:
  mov    -0x80(%rbp),%rax
  movsd  -0x50(%rbp,%rax,8),%xmm0
  mov    -0x58(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0xa0(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x80(%rbp)
L48:
  mov    -0x80(%rbp),%rax
  cmp    -0x68(%rbp),%rax
  jb     L20
  addq   $0x1,-0x78(%rbp)
L2:
  mov    -0x78(%rbp),%rax
  cmp    -0xa8(%rbp),%rax
  jb     L5
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int qu2euLoopf(float *qu, float *eu, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, qustep = 4, eustep = 3;
  double quFlt[4], euFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, quFlt, euFlt) firstprivate(qustep, eustep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * qustep;
    iOut = i * eustep;
    for (j = 0; j < qustep; j++) {
      quFlt[j] = (double)qu[iIn + j];
    }
    trash = qu2eu(quFlt, euFlt, p);
    for (j = 0; j < eustep; j++) {
      eu[iOut + j] = (float)euFlt[j];
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qu2euLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L25
  mov    %rdx,%r14
  mov    %ecx,%r15d
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  mov    $0x0,%r13d
  mov    %rsp,%r12
  jmp    L39
L34:
  add    $0x1,%r13
  add    $0xc,%rbp
  add    $0x10,%rbx
  cmp    %r13,%r14
  je     L25
L39:
  mov    $0x0,%eax
L6:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  movsd  %xmm0,0x20(%rsp,%rax,8)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L6
  lea    0x20(%rsp),%rdi
  mov    %r15d,%edx
  mov    %r12,%rsi
  call   <qu2eu@plt>
  mov    $0x0,%eax
L28:
  pxor   %xmm0,%xmm0
  cvtsd2ss (%r12,%rax,8),%xmm0
  movss  %xmm0,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L28
  jmp    L34
L25:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  mov    $0x1,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int qu2euLoopf(float *qu, float *eu, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, qustep = 4, eustep = 3;
  double quFlt[4], euFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, quFlt, euFlt) firstprivate(qustep, eustep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * qustep;
    iOut = i * eustep;
    for (j = 0; j < qustep; j++) {
      quFlt[j] = (double)qu[iIn + j];
    }
    trash = qu2eu(quFlt, euFlt, p);
    for (j = 0; j < eustep; j++) {
      eu[iOut + j] = (float)euFlt[j];
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qu2euLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L8
  mov    %ecx,%r12d
  mov    %rsi,%r13
  mov    %rdi,%rbx
  xor    %ebp,%ebp
  lea    0x30(%rsp),%r14
  lea    0x10(%rsp),%r15
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
L26:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%rax,4),%xmm0
  movsd  %xmm0,(%r14,%rax,8)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L26
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <qu2eu@plt>
  xor    %eax,%eax
L9:
  pxor   %xmm0,%xmm0
  cvtsd2ss (%r15,%rax,8),%xmm0
  movss  %xmm0,0x0(%r13,%rax,4)
  add    $0x1,%rax
  cmp    $0x3,%rax
  jne    L9
  add    $0x1,%rbp
  add    $0xc,%r13
  add    $0x10,%rbx
  cmp    %rbp,0x8(%rsp)
  jne    L24
L8:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x68,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int qu2euLoopf(float *qu, float *eu, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, qustep = 4, eustep = 3;
  double quFlt[4], euFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, quFlt, euFlt) firstprivate(qustep, eustep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * qustep;
    iOut = i * eustep;
    for (j = 0; j < qustep; j++) {
      quFlt[j] = (double)qu[iIn + j];
    }
    trash = qu2eu(quFlt, euFlt, p);
    for (j = 0; j < eustep; j++) {
      eu[iOut + j] = (float)euFlt[j];
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<qu2euLoopf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L4
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  lea    0x20(%rsp),%r15
  lea    0x40(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L5:
  movlps 0x8(%rbp),%xmm0
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  cvtps2pd 0x0(%rbp),%xmm1
  movaps %xmm0,(%rsp)
  add    $0x1,%r12
  add    $0x10,%rbp
  movaps %xmm1,0x40(%rsp)
  cvtps2pd %xmm0,%xmm1
  add    $0xc,%rbx
  movaps %xmm1,0x50(%rsp)
  call   <qu2eu@plt>
  cvtpd2ps 0x20(%rsp),%xmm1
  movlps %xmm1,-0xc(%rbx)
  pxor   %xmm1,%xmm1
  cvtsd2ss 0x30(%rsp),%xmm1
  movss  %xmm1,-0x4(%rbx)
  cmp    %r12,0x18(%rsp)
  movaps (%rsp),%xmm0
  jne    L5
L4:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x78,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int qu2euLoopf(float *qu, float *eu, unsigned long long n, int p) {
  int trash;
  unsigned long long j, i, iIn, iOut, qustep = 4, eustep = 3;
  double quFlt[4], euFlt[3];
#pragma omp parallel for default(shared) private(j, i, iIn, iOut, trash, quFlt, euFlt) firstprivate(qustep, eustep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * qustep;
    iOut = i * eustep;
    for (j = 0; j < qustep; j++) {
      quFlt[j] = (double)qu[iIn + j];
    }
    trash = qu2eu(quFlt, euFlt, p);
    for (j = 0; j < eustep; j++) {
      eu[iOut + j] = (float)euFlt[j];
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ip_hdr_csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x5,-0x1c(%rbp)
  jne    L8
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0xe,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x12,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L33
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L30:
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L30
L33:
  mov    -0x10(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x10(%rbp),%eax
  shr    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short ip_hdr_csum(unsigned int *ip, int len) {
  unsigned int sum = 0;
  int i;
  unsigned short *sp = (unsigned short *)ip;
  if (len == 5) {
    sum = sp[0] + sp[1] + sp[2] + sp[3] + sp[4] + sp[5] + sp[6] + sp[7] + sp[8] + sp[9];
  } else {
    for (i = 0; i < 2 * len; i++)
      sum += sp[i];
  }
  sum = (sum & 0xFFFF) + (sum >> 16);
  sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ip_hdr_csum>:
  endbr64
  cmp    $0x5,%esi
  je     L10
  add    %esi,%esi
  mov    $0x0,%edx
  test   %esi,%esi
  jle    L34
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x2(%rdi,%rdx,2),%rsi
  mov    $0x0,%edx
L20:
  movzwl (%rax),%ecx
  add    %ecx,%edx
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L20
L34:
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  add    %edx,%eax
  not    %eax
  ret
L10:
  movzwl (%rdi),%edx
  movzwl 0x2(%rdi),%eax
  add    %eax,%edx
  movzwl 0x4(%rdi),%eax
  add    %eax,%edx
  movzwl 0x6(%rdi),%eax
  add    %eax,%edx
  movzwl 0x8(%rdi),%eax
  add    %eax,%edx
  movzwl 0xa(%rdi),%eax
  add    %eax,%edx
  movzwl 0xc(%rdi),%eax
  add    %eax,%edx
  movzwl 0xe(%rdi),%eax
  add    %eax,%edx
  movzwl 0x10(%rdi),%eax
  add    %eax,%edx
  movzwl 0x12(%rdi),%eax
  add    %eax,%edx
  jmp    L34
```

assistant: ```c
unsigned short ip_hdr_csum(unsigned int *ip, int len) {
  unsigned int sum = 0;
  int i;
  unsigned short *sp = (unsigned short *)ip;
  if (len == 5) {
    sum = sp[0] + sp[1] + sp[2] + sp[3] + sp[4] + sp[5] + sp[6] + sp[7] + sp[8] + sp[9];
  } else {
    for (i = 0; i < 2 * len; i++)
      sum += sp[i];
  }
  sum = (sum & 0xFFFF) + (sum >> 16);
  sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ip_hdr_csum>:
  endbr64
  mov    %rdi,%rax
  cmp    $0x5,%esi
  je     L35
  add    %esi,%esi
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%edx
  lea    0x2(%rdi,%rdx,2),%rsi
  xor    %edx,%edx
  nopl   0x0(%rax)
L9:
  movzwl (%rax),%ecx
  add    $0x2,%rax
  add    %ecx,%edx
  cmp    %rax,%rsi
  jne    L9
L3:
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x10,%edx
  add    %edx,%eax
  not    %eax
  ret
L35:
  movzwl 0x2(%rdi),%ecx
  movzwl (%rdi),%edx
  movzwl 0x12(%rdi),%eax
  add    %ecx,%edx
  movzwl 0x4(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0x6(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0x8(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0xa(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0xc(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0xe(%rdi),%ecx
  add    %ecx,%edx
  movzwl 0x10(%rdi),%ecx
  add    %ecx,%edx
  add    %eax,%edx
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short ip_hdr_csum(unsigned int *ip, int len) {
  unsigned int sum = 0;
  int i;
  unsigned short *sp = (unsigned short *)ip;
  if (len == 5) {
    sum = sp[0] + sp[1] + sp[2] + sp[3] + sp[4] + sp[5] + sp[6] + sp[7] + sp[8] + sp[9];
  } else {
    for (i = 0; i < 2 * len; i++)
      sum += sp[i];
  }
  sum = (sum & 0xFFFF) + (sum >> 16);
  sum = (sum & 0xFFFF) + (sum >> 16);
  return ~sum;
}
```