ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wcrossprod>:
  endbr64
  push   %r15
  movslq %r9d,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x8(%rsp)
  test   %eax,%eax
  jle    L58
  mov    %r8d,%r14d
  mov    %rdi,%rbx
  mov    %rax,-0x18(%rsp)
  mov    %rsi,%rbp
  lea    0x0(,%rax,8),%r8
  movl   $0x0,-0x1c(%rsp)
  mov    %rdx,%r12
  xor    %r13d,%r13d
  lea    (%rdi,%r8,1),%r15
  movslq 0x38(%rsp),%rdi
  shl    $0x3,%rdi
  lea    (%rsi,%rdi,1),%rax
  mov    %rax,-0x10(%rsp)
  lea    -0x2(%r14),%eax
  lea    0x10(%rdx,%rax,8),%r9
  mov    0x38(%rsp),%eax
  sub    $0x1,%eax
  mov    %rax,-0x28(%rsp)
  nopl   (%rax)
L35:
  mov    0x38(%rsp),%eax
  test   %eax,%eax
  jle    L16
  movslq -0x1c(%rsp),%rax
  mov    -0x8(%rsp),%rsi
  xor    %r10d,%r10d
  mov    -0x10(%rsp),%r11
  lea    (%rsi,%rax,8),%rsi
  nopw   0x0(%rax,%rax,1)
L7:
  movsd  (%rbx,%r13,8),%xmm1
  mulsd  0x0(%rbp,%r10,8),%xmm1
  mov    %r11,%rcx
  mov    %r15,%rdx
  mulsd  (%r12),%xmm1
  lea    0x8(%r12),%rax
  movsd  %xmm1,(%rsi)
  cmp    $0x1,%r14d
  jle    L63
L66:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    %r8,%rdx
  mulsd  -0x8(%rax),%xmm0
  add    %rdi,%rcx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%r9
  jne    L66
L63:
  lea    0x1(%r10),%rax
  add    $0x8,%rsi
  add    $0x8,%r11
  cmp    -0x28(%rsp),%r10
  je     L16
  mov    %rax,%r10
  jmp    L7
  nopl   0x0(%rax)
L16:
  mov    0x38(%rsp),%esi
  add    $0x1,%r13
  add    %esi,-0x1c(%rsp)
  add    $0x8,%r15
  cmp    -0x18(%rsp),%r13
  jne    L35
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void wcrossprod(const double *x, const double *y, const double *w, double *z, const int m, const int n, const int p) {
  int i, j, k, ip;
  const double *restrict xr = x, *restrict yr = y, *restrict wr = w;
  double *restrict zr = z;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      k = 0;
      ip = i * p;
      zr[ip + j] = xr[i] * yr[j] * wr[k];
      for (k = 1; k < m; k++)
        zr[ip + j] += xr[k * n + i] * yr[k * p + j] * wr[k];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wcrossprod>:
  endbr64
  push   %r15
  movslq %r9d,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq 0x38(%rsp),%r15
  mov    %rcx,-0x10(%rsp)
  mov    %r8d,-0x24(%rsp)
  test   %eax,%eax
  jle    L13
  test   %r15d,%r15d
  jle    L13
  mov    %rsi,%rbp
  mov    %r8d,%esi
  mov    %rdi,%rbx
  mov    %rax,-0x8(%rsp)
  lea    0x0(,%rax,8),%r8
  mov    %rdx,%r12
  xor    %r13d,%r13d
  movq   $0x0,-0x20(%rsp)
  lea    (%rdi,%r8,1),%r14
  lea    0x0(,%r15,8),%rdi
  lea    0x0(%rbp,%rdi,1),%rax
  mov    %rax,-0x18(%rsp)
  lea    -0x2(%rsi),%eax
  lea    0x10(%rdx,%rax,8),%r9
  nopl   0x0(%rax)
L28:
  mov    -0x10(%rsp),%rax
  mov    -0x20(%rsp),%rsi
  xor    %r10d,%r10d
  mov    -0x18(%rsp),%r11
  lea    (%rax,%rsi,8),%rsi
  xchg   %ax,%ax
L23:
  cmpl   $0x1,-0x24(%rsp)
  lea    0x8(%r12),%rax
  mov    %r11,%rcx
  mov    %r14,%rdx
  movsd  (%rbx,%r13,8),%xmm1
  mulsd  0x0(%rbp,%r10,8),%xmm1
  mulsd  (%r12),%xmm1
  movsd  %xmm1,(%rsi)
  jle    L48
  nopl   0x0(%rax)
L9:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    %r8,%rdx
  mulsd  -0x8(%rax),%xmm0
  add    %rdi,%rcx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%r9
  jne    L9
L48:
  add    $0x1,%r10
  add    $0x8,%rsi
  add    $0x8,%r11
  cmp    %r10,%r15
  jne    L23
  add    %r15,-0x20(%rsp)
  add    $0x1,%r13
  add    $0x8,%r14
  cmp    %r13,-0x8(%rsp)
  jne    L28
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void wcrossprod(const double *x, const double *y, const double *w, double *z, const int m, const int n, const int p) {
  int i, j, k, ip;
  const double *restrict xr = x, *restrict yr = y, *restrict wr = w;
  double *restrict zr = z;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++) {
      k = 0;
      ip = i * p;
      zr[ip + j] = xr[i] * yr[j] * wr[k];
      for (k = 1; k < m; k++)
        zr[ip + j] += xr[k * n + i] * yr[k * p + j] * wr[k];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shortestPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L113
L7:
  movl   $0x0,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L38
L70:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L15
  addl   $0x1,-0x18(%rbp)
L38:
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L70
  jmp    L66
L15:
  nop
L66:
  mov    -0xc(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jge    L30
  addl   $0x1,-0x1c(%rbp)
L113:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L7
  jmp    L36
L30:
  nop
L36:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L45
  mov    -0x28(%rbp),%rax
  jmp    L79
L45:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  jmp    L52
L25:
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x14(%rbp)
L52:
  cmpl   $0x0,-0x14(%rbp)
  jns    L25
  mov    -0x8(%rbp),%rax
L79:
  leave
  ret
```

assistant: ```c
char *shortestPalindrome(char *s) {
  int maxOut = strlen(s) - 1;
  int i = 0;
  int j = 0, maxIn = 0;
  int minLeft = 0;
  for (; i < maxOut; i++) {
    for (j = 0, maxIn = maxOut - i; j < maxIn - j; j++) {
      if (s[j] != s[maxIn - j])
        break;
    }
    if (j >= maxIn - j)
      break;
  }
  minLeft = i;
  if (minLeft == 0)
    return s;
  char *strRet = (char *)malloc(minLeft + maxOut + 1);
  strcpy(strRet + minLeft, s);
  for (; minLeft >= 0; minLeft--)
    strRet[minLeft] = s[maxOut - minLeft];
  return strRet;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shortestPalindrome>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ebp
  test   %ebp,%ebp
  jle    L26
  mov    %eax,%r13d
  mov    %ebp,%edi
  mov    %ebp,%ecx
  mov    $0x0,%r12d
  mov    $0x0,%eax
  jmp    L49
L7:
  cmp    %eax,%ecx
  jle    L15
  add    $0x1,%r12d
  cmp    %r12d,%ebp
  jle    L15
  mov    %ebp,%ecx
  sub    %r12d,%ecx
  test   %ecx,%ecx
  jle    L15
  mov    %ecx,%edi
  mov    $0x0,%eax
L49:
  movslq %eax,%rdx
  movslq %ecx,%rsi
  movzbl (%rbx,%rsi,1),%esi
  cmp    %sil,(%rbx,%rdx,1)
  jne    L7
  add    $0x1,%eax
  mov    %edi,%ecx
  sub    %eax,%ecx
  cmp    %eax,%ecx
  jg     L49
L15:
  test   %r12d,%r12d
  je     L26
  lea    0x1(%r12,%rbp,1),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  movslq %r12d,%r15
  lea    (%rax,%r15,1),%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  test   %r12d,%r12d
  js     L13
  movslq %ebp,%rax
  sub    %r15,%rax
  add    %rbx,%rax
  movslq %r13d,%r13
  lea    (%rbx,%r13,1),%rsi
  sub    %r15,%rsi
  mov    %r12d,%r12d
  add    %r12,%rsi
  add    %r14,%r13
  lea    -0x1(%rbx,%r13,1),%rdi
L50:
  movzbl (%rax),%ecx
  mov    %rdi,%rdx
  sub    %rax,%rdx
  mov    %cl,(%rdx)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L50
  mov    %r14,%rbx
L26:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  mov    %r14,%rbx
  jmp    L26
```

assistant: ```c
char *shortestPalindrome(char *s) {
  int maxOut = strlen(s) - 1;
  int i = 0;
  int j = 0, maxIn = 0;
  int minLeft = 0;
  for (; i < maxOut; i++) {
    for (j = 0, maxIn = maxOut - i; j < maxIn - j; j++) {
      if (s[j] != s[maxIn - j])
        break;
    }
    if (j >= maxIn - j)
      break;
  }
  minLeft = i;
  if (minLeft == 0)
    return s;
  char *strRet = (char *)malloc(minLeft + maxOut + 1);
  strcpy(strRet + minLeft, s);
  for (; minLeft >= 0; minLeft--)
    strRet[minLeft] = s[maxOut - minLeft];
  return strRet;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shortestPalindrome>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%r13
  lea    -0x1(%r13),%ebx
  test   %ebx,%ebx
  jle    L14
  mov    %ebx,%esi
  mov    %ebx,%eax
  xor    %ebp,%ebp
  xor    %edx,%edx
  jmp    L42
  nopl   (%rax)
L78:
  add    $0x1,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    %edx,%eax
  jle    L74
L42:
  cltq
  movslq %edx,%rcx
  movzbl (%r12,%rax,1),%eax
  cmp    %al,(%r12,%rcx,1)
  je     L78
  add    $0x1,%ebp
  mov    %ebx,%eax
  sub    %ebp,%eax
  cmp    %ebp,%ebx
  jle    L65
  test   %eax,%eax
  jle    L65
  mov    %eax,%esi
  xor    %edx,%edx
  jmp    L42
L74:
  test   %ebp,%ebp
  je     L14
  nopl   0x0(%rax)
L65:
  lea    0x1(%rbp,%rbx,1),%edi
  movslq %ebp,%rbp
  call   <malloc@plt>
  mov    %r12,%rsi
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%r14
  call   <strcpy@plt>
  movslq %ebx,%rax
  lea    (%r12,%r14,1),%rdx
  lea    (%r12,%r13,1),%rdi
  sub    %rbp,%rax
  lea    -0x1(%r13,%rdx,1),%rsi
  add    %r12,%rax
  nopl   0x0(%rax)
L15:
  movzbl (%rax),%ecx
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    $0x1,%rax
  mov    %cl,(%rdx)
  cmp    %rdi,%rax
  jne    L15
  mov    %r14,%r12
L14:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *shortestPalindrome(char *s) {
  int maxOut = strlen(s) - 1;
  int i = 0;
  int j = 0, maxIn = 0;
  int minLeft = 0;
  for (; i < maxOut; i++) {
    for (j = 0, maxIn = maxOut - i; j < maxIn - j; j++) {
      if (s[j] != s[maxIn - j])
        break;
    }
    if (j >= maxIn - j)
      break;
  }
  minLeft = i;
  if (minLeft == 0)
    return s;
  char *strRet = (char *)malloc(minLeft + maxOut + 1);
  strcpy(strRet + minLeft, s);
  for (; minLeft >= 0; minLeft--)
    strRet[minLeft] = s[maxOut - minLeft];
  return strRet;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shortestPalindrome>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%r13
  lea    -0x1(%r13),%ebx
  test   %ebx,%ebx
  jle    L75
  mov    %ebx,%esi
  mov    %ebx,%eax
  xor    %ebp,%ebp
  xor    %edx,%edx
  jmp    L9
  nopl   (%rax)
L41:
  add    $0x1,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    %edx,%eax
  jle    L0
L9:
  cltq
  movslq %edx,%rcx
  movzbl (%r12,%rax,1),%eax
  cmp    %al,(%r12,%rcx,1)
  je     L41
  add    $0x1,%ebp
  mov    %ebx,%eax
  sub    %ebp,%eax
  cmp    %ebp,%ebx
  jle    L8
  test   %eax,%eax
  jle    L8
  mov    %eax,%esi
  xor    %edx,%edx
  jmp    L9
L0:
  test   %ebp,%ebp
  je     L75
  nopl   0x0(%rax)
L8:
  lea    0x1(%rbp,%rbx,1),%edi
  movslq %ebp,%rbp
  call   <malloc@plt>
  mov    %r12,%rsi
  lea    (%rax,%rbp,1),%rdi
  mov    %rax,%r14
  call   <strcpy@plt>
  movslq %ebx,%rax
  lea    (%r12,%r14,1),%rdx
  lea    (%r12,%r13,1),%rdi
  sub    %rbp,%rax
  lea    -0x1(%r13,%rdx,1),%rsi
  add    %r12,%rax
  nopl   0x0(%rax)
L50:
  movzbl (%rax),%ecx
  mov    %rsi,%rdx
  sub    %rax,%rdx
  add    $0x1,%rax
  mov    %cl,(%rdx)
  cmp    %rax,%rdi
  jne    L50
  mov    %r14,%r12
L75:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *shortestPalindrome(char *s) {
  int maxOut = strlen(s) - 1;
  int i = 0;
  int j = 0, maxIn = 0;
  int minLeft = 0;
  for (; i < maxOut; i++) {
    for (j = 0, maxIn = maxOut - i; j < maxIn - j; j++) {
      if (s[j] != s[maxIn - j])
        break;
    }
    if (j >= maxIn - j)
      break;
  }
  minLeft = i;
  if (minLeft == 0)
    return s;
  char *strRet = (char *)malloc(minLeft + maxOut + 1);
  strcpy(strRet + minLeft, s);
  for (; minLeft >= 0; minLeft--)
    strRet[minLeft] = s[maxOut - minLeft];
  return strRet;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int rotr(int *a, int *b, int *c) {
  int d;
  d = *c;
  *c = *b;
  *b = *a;
  *a = d;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rotr>:
  endbr64
  mov    (%rdx),%eax
  mov    (%rsi),%ecx
  mov    %ecx,(%rdx)
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rotr(int *a, int *b, int *c) {
  int d;
  d = *c;
  *c = *b;
  *b = *a;
  *a = d;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotr>:
  endbr64
  mov    (%rsi),%ecx
  mov    (%rdx),%eax
  mov    %ecx,(%rdx)
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotr(int *a, int *b, int *c) {
  int d;
  d = *c;
  *c = *b;
  *b = *a;
  *a = d;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rotr>:
  endbr64
  mov    (%rsi),%ecx
  mov    (%rdx),%eax
  mov    %ecx,(%rdx)
  mov    (%rdi),%edx
  mov    %edx,(%rsi)
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int rotr(int *a, int *b, int *c) {
  int d;
  d = *c;
  *c = *b;
  *b = *a;
  *a = d;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x90(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x1,-0x88(%rbp)
  movl   $0x1,-0x84(%rbp)
  movl   $0x1,-0x80(%rbp)
  movl   $0x1,-0x7c(%rbp)
  movl   $0x1,-0x78(%rbp)
  movl   $0x1,-0x74(%rbp)
  movl   $0x1,-0x70(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x1,-0x5c(%rbp)
  movl   $0x1,-0x58(%rbp)
  movl   $0x1,-0x54(%rbp)
  movl   $0x1,-0x50(%rbp)
  movl   $0x1,-0x4c(%rbp)
  movl   $0x1,-0x48(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  lea    -0x30(%rbp),%rcx
  lea    -0x60(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <matrix_multiply@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int a[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int b[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int mat[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  matrix_multiply(3, a, b, mat);
  print(3, mat);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x1,0x34(%rsp)
  movl   $0x1,0x38(%rsp)
  movl   $0x1,0x3c(%rsp)
  movl   $0x1,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x1,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x1,0x60(%rsp)
  movl   $0x1,0x64(%rsp)
  movl   $0x1,0x68(%rsp)
  movl   $0x1,0x6c(%rsp)
  movl   $0x1,0x70(%rsp)
  movl   $0x1,0x74(%rsp)
  movl   $0x1,0x78(%rsp)
  movl   $0x1,0x7c(%rsp)
  movl   $0x1,0x80(%rsp)
  lea    0x60(%rsp),%rbx
  lea    0x30(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %rbx,%rcx
  mov    $0x3,%edi
  call   <matrix_multiply@plt>
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <print@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int b[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int mat[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  matrix_multiply(3, a, b, mat);
  print(3, mat);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x100000001,%rax
  lea    0x60(%rsp),%rbp
  mov    %rsp,%rsi
  lea    0x30(%rsp),%rdx
  mov    %rbp,%rcx
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x1,0x80(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  mov    %rax,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  mov    %rax,0x60(%rsp)
  mov    %rax,0x68(%rsp)
  mov    %rax,0x70(%rsp)
  mov    %rax,0x78(%rsp)
  call   <matrix_multiply@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <print@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int b[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int mat[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  matrix_multiply(3, a, b, mat);
  print(3, mat);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edi
  sub    $0x90,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rbp
  mov    %rsp,%rsi
  lea    0x30(%rsp),%rdx
  mov    %rbp,%rcx
  movaps %xmm0,(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x1,0x80(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <matrix_multiply@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <print@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int b[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  int mat[3][3] = {{1, 1, 1}, {1, 1, 1}, {1, 1, 1}};
  matrix_multiply(3, a, b, mat);
  print(3, mat);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f91>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x64,-0x4(%rbp)
  jle    L26
  mov    -0x4(%rbp),%eax
  sub    $0xa,%eax
  jmp    L2
L26:
  cmpl   $0x65,-0x4(%rbp)
  jg     L2
  mov    -0x4(%rbp),%eax
  add    $0xb,%eax
  mov    %eax,%edi
  call   <f91>
  mov    %eax,%edi
  call   <f91>
L2:
  leave
  ret
```

assistant: ```c
int f91(int num) {
  if (num >= 101)
    return num - 10;
  else if (num <= 101)
    f91(f91(num + 11));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f91>:
  endbr64
  cmp    $0x64,%edi
  jg     L2
  sub    $0x8,%rsp
  add    $0xb,%edi
  call   <f91>
  mov    %eax,%edi
  call   <f91>
  add    $0x8,%rsp
  ret
L2:
  lea    -0xa(%rdi),%eax
  ret
```

assistant: ```c
int f91(int num) {
  if (num >= 101)
    return num - 10;
  else if (num <= 101)
    f91(f91(num + 11));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f91>:
  endbr64
  mov    %edi,%eax
  cmp    $0x64,%edi
  jg     L64
L393:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L139
L137:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L76
L255:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L377
L337:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L109
L257:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L374
L13:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L357
L299:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L229
L291:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jg     L294
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L126:
  lea    0xb(%rax),%edi
  call   <f91>
  cmp    $0x64,%eax
  jle    L126
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L403
L412:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L126
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L412
L403:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L324
L85:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L412
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L85
L324:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L65
L348:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L85
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L348
L65:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L33
L371:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L348
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L371
L33:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L402
L399:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L371
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L399
L402:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L343
L247:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L399
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L247
L343:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L124
L359:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L247
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L359
L124:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jg     L193
L233:
  add    $0xb,%eax
  cmp    $0x64,%eax
  jle    L359
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L233
L193:
  sub    $0xa,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L294:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L291
L229:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L299
L357:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L13
L374:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L257
L109:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L337
L377:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L255
L76:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L137
L139:
  sub    $0xa,%eax
  cmp    $0x64,%eax
  jle    L393
L64:
  sub    $0xa,%eax
  ret
```

assistant: ```c
int f91(int num) {
  if (num >= 101)
    return num - 10;
  else if (num <= 101)
    f91(f91(num + 11));
}
```