user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  movl   $0x0,0x4(%rsp)
  lea    0x1a0(%rsp),%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L103
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r15
  lea    0x8(%rsp),%r14
  lea    D3(%rip),%r13
  lea    0x1a0(%rsp),%r12
  lea    0x10(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jle    L72
  mov    %eax,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
L72:
  mov    %edx,(%r12,%rbx,4)
  mov    0x4(%rsp),%edx
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%edx
  jg     L30
L103:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sort@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L55
  xor    %ebx,%ebx
  xor    %r13d,%r13d
  jmp    L27
  nopl   0x0(%rax)
L61:
  mov    0x4(%rsp),%ecx
  add    $0x1,%ebx
  cmp    %ecx,%ebx
  jge    L20
L27:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <find_conflicts@plt>
  test   %eax,%eax
  jne    L61
  movslq %ebx,%rax
  movslq %r13d,%rcx
  mov    0x10(%rsp,%rax,4),%esi
  mov    0x1a0(%rsp,%rax,4),%edx
  mov    %esi,0x330(%rsp,%rcx,4)
  mov    %edx,0x4c0(%rsp,%rcx,4)
  mov    0x4(%rsp),%ecx
  cmp    %edx,%esi
  jge    L53
  lea    0x0(%rbp,%rax,4),%rax
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L88:
  add    $0x4,%rax
  add    $0x1,%ebx
  cmp    (%rax),%edx
  jle    L53
L28:
  cmp    %ebx,%ecx
  jg     L88
L53:
  add    $0x1,%r13d
  cmp    %ecx,%ebx
  jl     L27
L20:
  xor    %eax,%eax
  mov    %r13d,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  test   %r13d,%r13d
  je     L43
  movslq %r13d,%r13
  xor    %ebx,%ebx
  lea    0x4c0(%rsp),%r14
  lea    0x330(%rsp),%r12
  lea    D6(%rip),%rbp
  nopl   0x0(%rax)
L106:
  mov    (%r14,%rbx,4),%edx
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L106
L43:
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  add    $0x668,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  xor    %esi,%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
L83:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D31
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D22: %d

tool: D3: %d%d

tool: D31: %d


tool: D6: %d %d


assistant: ```c
int main() {
  int list_1[100], list_2[100], flist_1[100], flist_2[100];
  int num_segs = 0, i, num1, num2;
  int fcounter = 0, fpointer = 0;
  int conflicts;
  scanf("%d", &num_segs);
  for (i = 0; i < num_segs; i++) {
    scanf("%d%d", &num1, &num2);
    if (num1 > num2) {
      list_1[i] = num2;
      list_2[i] = num1;
    } else {
      list_2[i] = num2;
      list_1[i] = num1;
    }
  }
  sort(list_1, list_2, num_segs);
  while (fpointer < num_segs) {
    int conflicts = find_conflicts(list_1, list_2, fpointer, num_segs);
    if (conflicts != 0) {
      fpointer++;
      continue;
    }
    flist_1[fcounter] = list_1[fpointer];
    flist_2[fcounter] = list_2[fpointer];
    while ((flist_2[fcounter] > list_1[fpointer]) && (fpointer < num_segs))
      fpointer++;
    fcounter++;
  }
  printf("%d\n", fcounter);
  for (i = 0; i < fcounter; i++)
    printf("%d %d\n", flist_1[i], flist_2[i]);
  return 0;
}
```