user: 这段汇编代码用C语言表示是什么样的?

```asm
<ParseDataLine>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  lea    0x1(%r13),%rsi
  mov    %rdx,%r12
  mov    $0x2,%edx
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    0x90(%rsp),%rcx
  mov    %r8,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%r8)
  movq   $0x0,(%rcx)
  call   <string_copy@plt>
  mov    %r12,%rdi
  lea    0x4(%r13),%rsi
  xor    %eax,%eax
  mov    $0x8,%edx
  xor    %r12d,%r12d
  call   <string_copy@plt>
  mov    %rbp,%rdi
  lea    0xe(%r13),%rsi
  xor    %eax,%eax
  mov    $0x8,%edx
  lea    0x39(%rsp),%rbp
  call   <string_copy@plt>
  lea    0x2a(%rsp),%rax
  lea    0x18(%r13),%rsi
  mov    $0xc,%edx
  mov    %rax,0x18(%rsp)
  mov    %rax,%r15
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <string_copy@plt>
  mov    %r15,%rbx
  nopl   0x0(%rax)
L47:
  movzbl (%r15),%r14d
  test   %r14b,%r14b
  je     L22
  movsbl %r14b,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L34
  movslq %r12d,%rax
  add    $0x1,%r12d
  mov    %r14b,0x39(%rsp,%rax,1)
L34:
  add    $0x1,%r15
  cmp    %rbp,%r15
  jne    L47
L22:
  mov    %rbp,%rdi
  movslq %r12d,%r12
  xor    %eax,%eax
  movb   $0x0,0x39(%rsp,%r12,1)
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rdi
  lea    0x27(%r13),%rsi
  cvtsi2sd %eax,%xmm0
  mov    (%rsp),%rax
  mov    $0x8,%edx
  movsd  %xmm0,(%rax)
  xor    %eax,%eax
  call   <string_copy@plt>
  mov    0x18(%rsp),%rdi
  lea    0x31(%r13),%rsi
  xor    %eax,%eax
  mov    $0xc,%edx
  xor    %r13d,%r13d
  call   <string_copy@plt>
  nopl   0x0(%rax,%rax,1)
L50:
  movzbl (%rbx),%r12d
  test   %r12b,%r12b
  je     L9
  movsbl %r12b,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L18
  movslq %r13d,%rax
  add    $0x1,%r13d
  mov    %r12b,0x39(%rsp,%rax,1)
L18:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L50
L9:
  movslq %r13d,%r13
  mov    %rbp,%rdi
  xor    %eax,%eax
  movb   $0x0,0x39(%rsp,%r13,1)
  call   <atof@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    0x10(%rsp),%rax
  movsd  %xmm0,(%rax)
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ParseDataLine(line, code, name1, name2, val1, name3, val2)
char *code, *line, *name1, *name2, *name3;
double *val1, *val2;
{
  int i, j;
  char valstr[15], NoBlank[15];
  *val1 = 0.0;
  *val2 = 0.0;
  string_copy(code, &line[1], 2);
  string_copy(name1, &line[4], 8);
  string_copy(name2, &line[14], 8);
  string_copy(valstr, &line[24], 12);
  j = 0;
  for (i = 0; i < 15 && valstr[i] != '\0'; i++)
    if (!isspace(valstr[i]))
      NoBlank[j++] = valstr[i];
  NoBlank[j] = '\0';
  *val1 = atof(NoBlank);
  string_copy(name3, &line[39], 8);
  string_copy(valstr, &line[49], 12);
  j = 0;
  for (i = 0; i < 15 && valstr[i] != '\0'; i++)
    if (!isspace(valstr[i]))
      NoBlank[j++] = valstr[i];
  NoBlank[j] = '\0';
  *val2 = atof(NoBlank);
  return 0;
}
```