ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_arrow_direction_new>:
  endbr64
  cmp    %edx,%edi
  je     L5
  cmp    %ecx,%esi
  je     L37
  cmp    %edx,%edi
  jge    L2
  mov    $0x7,%eax
  cmp    %ecx,%esi
  jg     L38
  mov    $0x0,%edx
  mov    $0x6,%eax
  cmovge %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
  cmp    %edx,%edi
  setle  %al
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  cmp    %ecx,%esi
  mov    $0x5,%edx
  setl   %al
  shl    $0x2,%eax
  cmp    %ecx,%esi
  cmovg  %edx,%eax
L38:
  ret
  nopl   (%rax)
L5:
  mov    $0x2,%eax
  cmp    %ecx,%esi
  jg     L38
  mov    $0x0,%edx
  mov    $0x3,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int get_arrow_direction_new(int y, int x, int ny, int nx) {
  int adjust = 0;
  if (y == ny) {
    if (x > nx)
      adjust = 2;
    else if (x < nx)
      adjust = 3;
  } else if (x == nx) {
    if (y > ny)
      adjust = 0;
    else
      adjust = 1;
  } else if (y < ny) {
    if (x > nx)
      adjust = 7;
    else if (x < nx)
      adjust = 6;
  } else {
    if (x > nx)
      adjust = 5;
    else if (x < nx)
      adjust = 4;
  }
  return (adjust);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_arrow_direction_new>:
  endbr64
  cmp    %edx,%edi
  je     L17
  cmp    %ecx,%esi
  je     L31
  cmp    %edx,%edi
  jge    L30
  mov    $0x7,%eax
  cmp    %ecx,%esi
  jg     L44
  mov    $0x0,%edx
  mov    $0x6,%eax
  cmovge %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
  cmp    %edx,%edi
  setle  %al
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  cmp    %ecx,%esi
  mov    $0x5,%edx
  setl   %al
  shl    $0x2,%eax
  cmp    %ecx,%esi
  cmovg  %edx,%eax
L44:
  ret
  nopl   (%rax)
L17:
  mov    $0x2,%eax
  cmp    %ecx,%esi
  jg     L44
  mov    $0x0,%edx
  mov    $0x3,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int get_arrow_direction_new(int y, int x, int ny, int nx) {
  int adjust = 0;
  if (y == ny) {
    if (x > nx)
      adjust = 2;
    else if (x < nx)
      adjust = 3;
  } else if (x == nx) {
    if (y > ny)
      adjust = 0;
    else
      adjust = 1;
  } else if (y < ny) {
    if (x > nx)
      adjust = 7;
    else if (x < nx)
      adjust = 6;
  } else {
    if (x > nx)
      adjust = 5;
    else if (x < nx)
      adjust = 4;
  }
  return (adjust);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int *p;
  p = 0;
  p[2] = 3;
  return p[2];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  movl   $0x3,0x8
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main(void) {
  int *p;
  p = 0;
  p[2] = 3;
  return p[2];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  movl   $0x3,0x8
  mov    0x8,%eax
  ud2
```

assistant: ```c
int main(void) {
  int *p;
  p = 0;
  p[2] = 3;
  return p[2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  movl   $0x3,0x8
  mov    0x8,%eax
  ud2
```

assistant: ```c
int main(void) {
  int *p;
  p = 0;
  p[2] = 3;
  return p[2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<soma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L19
L15:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <soma>
  add    %ebx,%eax
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int soma(int n, int *v) {
  if (n == 0)
    return 0;
  return v[n - 1] + soma(n - 1, v);
}
```
user: Translate the below assembly code into C programming language:

```asm
<soma>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L7
L10:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%edi
  call   <soma>
  movslq %ebx,%rbx
  add    -0x4(%rbp,%rbx,4),%eax
  mov    %eax,%ebx
  jmp    L10
```

assistant: ```c
int soma(int n, int *v) {
  if (n == 0)
    return 0;
  return v[n - 1] + soma(n - 1, v);
}
```
user: What is the c source code of the assembly code below?

```asm
<soma>:
  endbr64
  movslq %edi,%rax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L4
  xchg   %ax,%ax
L2:
  add    -0x4(%rsi,%rax,4),%r8d
  sub    $0x1,%rax
  test   %eax,%eax
  jne    L2
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int soma(int n, int *v) {
  if (n == 0)
    return 0;
  return v[n - 1] + soma(n - 1, v);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<soma>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  je     L21
  lea    -0x1(%rdi),%ecx
  mov    %edi,%r9d
  cmp    $0x2,%ecx
  jbe    L40
  movslq %edi,%rax
  shr    $0x2,%edi
  pxor   %xmm0,%xmm0
  lea    -0x10(%rsi,%rax,4),%rcx
  lea    -0x1(%rdi),%r8d
  lea    -0x10(%rcx),%rax
  shl    $0x4,%r8
  mov    %rax,%rdi
  sub    %r8,%rdi
  jmp    L16
L44:
  sub    $0x10,%rax
L16:
  movdqu (%rcx),%xmm1
  mov    %rax,%rcx
  pshufd $0x1b,%xmm1,%xmm1
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L44
  movdqa %xmm0,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  sub    %ecx,%edx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %ecx,%r9d
  je     L62
  lea    -0x1(%rdx),%ecx
L59:
  movslq %edx,%rdi
  add    -0x4(%rsi,%rdi,4),%eax
  test   %ecx,%ecx
  je     L62
  movslq %ecx,%rcx
  add    -0x4(%rsi,%rcx,4),%eax
  sub    $0x2,%edx
  je     L62
  movslq %edx,%rdx
  add    -0x4(%rsi,%rdx,4),%eax
L62:
  ret
  nopl   (%rax)
L21:
  xor    %eax,%eax
  ret
L40:
  xor    %eax,%eax
  jmp    L59
```

assistant: ```c
int soma(int n, int *v) {
  if (n == 0)
    return 0;
  return v[n - 1] + soma(n - 1, v);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string

tool: D16: %c

tool: D3: %d


assistant: ```c
int main() {
  unsigned char byte;
  scanf("%c", &byte);
  printf("%d\n", byte);
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D0
data_type: string

tool: D16: %c

tool: D0: %d


assistant: ```c
int main() {
  unsigned char byte;
  scanf("%c", &byte);
  printf("%d\n", byte);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: string
name: read_data
arguments: data_label: D16
type: string

tool: D6: %c

tool: D16: %d


assistant: ```c
int main() {
  unsigned char byte;
  scanf("%c", &byte);
  printf("%d\n", byte);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D13
data_type: string

tool: D8: %c

tool: D13: %d


assistant: ```c
int main() {
  unsigned char byte;
  scanf("%c", &byte);
  printf("%d\n", byte);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %rdx,-0xc8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xa8(%rbp)
  lea    -0xb0(%rbp),%rdx
  mov    -0xc8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtod@plt>
  mov    -0xb0(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  lea    D35(%rip),%rax
  mov    %rax,-0xa8(%rbp)
L48:
  cmpq   $0x0,-0xa8(%rbp)
  jne    L60
  movq   $0xa,-0xa0(%rbp)
  mov    -0xc8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L18
  mov    -0xc8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L61
  mov    -0xc8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L18
L61:
  addq   $0x2,-0xc8(%rbp)
  movq   $0x10,-0xa0(%rbp)
  jmp    L95
L18:
  mov    -0xc8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L95
  movq   $0x8,-0xa0(%rbp)
L95:
  mov    -0xa0(%rbp),%rdx
  lea    -0xb0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0xb0(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  lea    D47(%rip),%rax
  mov    %rax,-0xa8(%rbp)
  mov    -0x98(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D19(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,-0xc8(%rbp)
L60:
  cmpq   $0x0,-0xa8(%rbp)
  jne    L74
  lea    D49(%rip),%rax
  mov    %rax,-0xa8(%rbp)
L74:
  mov    -0xc8(%rbp),%rsi
  mov    -0xa8(%rbp),%rcx
  mov    -0xc0(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D35
datatype: string
name: unpack_data
arguments: data_label: D47
datatype: string
name: unpack_data
arguments: data_label: D19
datatype: string
name: unpack_data
arguments: data_label: D49
datatype: string
name: unpack_data
arguments: data_label: D9
datatype: string

tool: D35: n

tool: D47: l

tool: D19: %ld

tool: D49: s

tool: D9: %s:%s	%s	%s


assistant: ```c
void print_line(char *name, char *name2, char *val) {
  char *typename = NULL, *endptr, newval[128];
  (void)strtod(val, &endptr);
  if (*endptr == '\0')
    typename = "n";
  if (NULL == typename) {
    long foo, base = 10;
    if (val[0] == '0' && (val[1] == 'x' || val[1] == 'X')) {
      val += 2;
      base = 16;
    } else if (val[0] == '0') {
      base = 8;
    }
    foo = strtol(val, &endptr, base);
    if (*endptr == '\0') {
      typename = "l";
      snprintf(newval, sizeof(newval), "%ld", foo);
      val = newval;
    }
  }
  if (NULL == typename)
    typename = "s";
  printf("%s:%s\t%s\t%s\n", name, name2, typename, val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rdx,%rdi
  call   <strtod@plt>
  lea    D29(%rip),%rcx
  mov    0x8(%rsp),%rax
  cmpb   $0x0,(%rax)
  je     L47
  mov    $0xa,%edx
  cmpb   $0x30,(%rbx)
  je     L0
L13:
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strtol@plt>
  lea    D47(%rip),%rcx
  mov    0x8(%rsp),%rdx
  cmpb   $0x0,(%rdx)
  je     L40
L47:
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  movzbl 0x1(%rbx),%eax
  and    $0xffffffdf,%eax
  mov    $0x8,%edx
  cmp    $0x58,%al
  jne    L13
  add    $0x2,%rbx
  mov    $0x10,%edx
  jmp    L13
L40:
  lea    0x10(%rsp),%rbx
  mov    %rax,%rcx
  lea    D30(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D16(%rip),%rcx
  jmp    L47
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D47
type: string
name: extract_symbolic_data
arguments: label: D25
type: string
name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D29: n

tool: D47: s

tool: D25: %s:%s	%s	%s


tool: D30: %ld

tool: D16: l

assistant: ```c
void print_line(char *name, char *name2, char *val) {
  char *typename = NULL, *endptr, newval[128];
  (void)strtod(val, &endptr);
  if (*endptr == '\0')
    typename = "n";
  if (NULL == typename) {
    long foo, base = 10;
    if (val[0] == '0' && (val[1] == 'x' || val[1] == 'X')) {
      val += 2;
      base = 16;
    } else if (val[0] == '0') {
      base = 8;
    }
    foo = strtol(val, &endptr, base);
    if (*endptr == '\0') {
      typename = "l";
      snprintf(newval, sizeof(newval), "%ld", foo);
      val = newval;
    }
  }
  if (NULL == typename)
    typename = "s";
  printf("%s:%s\t%s\t%s\n", name, name2, typename, val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_line>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  mov    %r13,%rsi
  call   <strtod@plt>
  mov    0x8(%rsp),%rax
  lea    D20(%rip),%rcx
  cmpb   $0x0,(%rax)
  je     L9
  cmpb   $0x30,(%rbx)
  mov    $0xa,%edx
  je     L7
L16:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    0x8(%rsp),%rdx
  lea    D37(%rip),%rcx
  cmpb   $0x0,(%rdx)
  je     L21
L9:
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D44(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl 0x1(%rbx),%eax
  mov    $0x8,%edx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L16
  add    $0x2,%rbx
  mov    $0x10,%edx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x10(%rsp),%rbx
  mov    %rax,%rcx
  mov    $0x80,%esi
  lea    D9(%rip),%rdx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D35(%rip),%rcx
  jmp    L9
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D44
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D35
type_infered: string

tool: D20: n

tool: D37: s

tool: D44: %s:%s	%s	%s


tool: D9: %ld

tool: D35: l

assistant: ```c
void print_line(char *name, char *name2, char *val) {
  char *typename = NULL, *endptr, newval[128];
  (void)strtod(val, &endptr);
  if (*endptr == '\0')
    typename = "n";
  if (NULL == typename) {
    long foo, base = 10;
    if (val[0] == '0' && (val[1] == 'x' || val[1] == 'X')) {
      val += 2;
      base = 16;
    } else if (val[0] == '0') {
      base = 8;
    }
    foo = strtol(val, &endptr, base);
    if (*endptr == '\0') {
      typename = "l";
      snprintf(newval, sizeof(newval), "%ld", foo);
      val = newval;
    }
  }
  if (NULL == typename)
    typename = "s";
  printf("%s:%s\t%s\t%s\n", name, name2, typename, val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_line>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  mov    %r13,%rsi
  call   <strtod@plt>
  mov    0x8(%rsp),%rax
  lea    D28(%rip),%rcx
  cmpb   $0x0,(%rax)
  je     L15
  cmpb   $0x30,(%rbx)
  mov    $0xa,%edx
  je     L33
L43:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    0x8(%rsp),%rdx
  lea    D1(%rip),%rcx
  cmpb   $0x0,(%rdx)
  je     L13
L15:
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D9(%rip),%rdi
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  movzbl 0x1(%rbx),%eax
  mov    $0x8,%edx
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  jne    L43
  add    $0x2,%rbx
  mov    $0x10,%edx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L13:
  lea    0x10(%rsp),%rbx
  mov    %rax,%rcx
  mov    $0x80,%esi
  lea    D16(%rip),%rdx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    D49(%rip),%rcx
  jmp    L15
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D49
datatype: string

tool: D28: n

tool: D1: s

tool: D9: %s:%s	%s	%s


tool: D16: %ld

tool: D49: l

assistant: ```c
void print_line(char *name, char *name2, char *val) {
  char *typename = NULL, *endptr, newval[128];
  (void)strtod(val, &endptr);
  if (*endptr == '\0')
    typename = "n";
  if (NULL == typename) {
    long foo, base = 10;
    if (val[0] == '0' && (val[1] == 'x' || val[1] == 'X')) {
      val += 2;
      base = 16;
    } else if (val[0] == '0') {
      base = 8;
    }
    foo = strtol(val, &endptr, base);
    if (*endptr == '\0') {
      typename = "l";
      snprintf(newval, sizeof(newval), "%ld", foo);
      val = newval;
    }
  }
  if (NULL == typename)
    typename = "s";
  printf("%s:%s\t%s\t%s\n", name, name2, typename, val);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x3,%rax
  ja     L38
  je     L106
  cmp    $0x2,%rax
  jne    L52
  lea    0x1(%rsi),%rdx
  mov    0x4(%rdi,%rsi,4),%eax
  cmp    %eax,(%rdi,%rsi,4)
  jle    L52
  call   <swap@plt>
  jmp    L52
L38:
  mov    %rdx,%r12
  call   <partition@plt>
  mov    %rax,%r13
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <sort>
  lea    0x1(%r13),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <sort>
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L106:
  shl    $0x2,%rbx
  lea    (%rdi,%rbx,1),%rdi
  mov    (%rdi),%edx
  lea    0x4(%rbp,%rbx,1),%r8
  mov    (%r8),%eax
  lea    0x8(%rbp,%rbx,1),%rsi
  mov    (%rsi),%ecx
  cmp    %eax,%edx
  jle    L20
  cmp    %ecx,%eax
  jle    L141
  mov    %ecx,(%rdi)
  mov    %edx,(%rsi)
  jmp    L52
L141:
  cmp    %ecx,%edx
  jle    L13
  mov    %eax,(%rdi)
  mov    %ecx,(%r8)
  mov    %edx,(%rsi)
  jmp    L52
L13:
  mov    %eax,(%rdi)
  mov    %edx,(%r8)
  jmp    L52
L20:
  cmp    %ecx,%eax
  jle    L52
  cmp    %ecx,%edx
  jle    L23
  mov    %ecx,(%rdi)
  mov    %edx,(%r8)
  mov    %eax,(%rsi)
  jmp    L52
L23:
  mov    %ecx,(%r8)
  mov    %eax,(%rsi)
  jmp    L52
```

assistant: ```c
void sort(int a[], const size_t startIndex, const size_t endIndex) {
  const size_t len = endIndex - startIndex;
  if (len > 3) {
    const size_t pivot = partition(a, startIndex, endIndex);
    sort(a, startIndex, pivot);
    sort(a, pivot + 1, endIndex);
  } else if (len == 3) {
    const size_t x = startIndex, y = x + 1, z = y + 1;
    const int ax = a[x], ay = a[y], az = a[z];
    if (ax > ay) {
      if (ay > az) {
        a[x] = az;
        a[z] = ax;
      } else {
        if (ax > az) {
          a[x] = ay;
          a[y] = az;
          a[z] = ax;
        } else {
          a[x] = ay;
          a[y] = ax;
        }
      }
    } else {
      if (ay > az) {
        if (ax > az) {
          a[x] = az;
          a[y] = ax;
          a[z] = ay;
        } else {
          a[y] = az;
          a[z] = ay;
        }
      } else {
      }
    }
  } else if (len == 2) {
    const size_t x = startIndex;
    const size_t y = x + 1;
    if (a[x] > a[y]) {
      swap(a, x, y);
    }
  }
}
```