ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_put_indirect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D6(%rip),%rdi
  call   <output_line@plt>
  test   $0x4,%bl
  je     L11
  lea    D7(%rip),%rdi
  call   <output_line@plt>
L1:
  pop    %rbx
  ret
L11:
  lea    D2(%rip),%rdi
  call   <output_line@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D7
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D6: puls x

tool: D7: stb ,x

tool: D2: std ,x

assistant: ```c
void gen_put_indirect(char typeobj) {
  output_line("puls x");
  if (typeobj & (1 << 2)) {
    output_line("stb ,x");
  } else {
    output_line("std ,x");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gen_put_indirect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D21(%rip),%rdi
  call   <output_line@plt>
  and    $0x4,%ebx
  je     L3
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
  nopl   (%rax)
L3:
  lea    D8(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
```

tool_calls: name: read_data
arguments: tag: D21
datatype: string
name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D8
datatype: string

tool: D21: puls x

tool: D5: stb ,x

tool: D8: std ,x

assistant: ```c
void gen_put_indirect(char typeobj) {
  output_line("puls x");
  if (typeobj & (1 << 2)) {
    output_line("stb ,x");
  } else {
    output_line("std ,x");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gen_put_indirect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D14(%rip),%rdi
  call   <output_line@plt>
  and    $0x4,%ebx
  je     L6
  lea    D26(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
  nopl   (%rax)
L6:
  lea    D15(%rip),%rdi
  pop    %rbx
  jmp    1050 <output_line@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D15
type: string

tool: D14: puls x

tool: D26: stb ,x

tool: D15: std ,x

assistant: ```c
void gen_put_indirect(char typeobj) {
  output_line("puls x");
  if (typeobj & (1 << 2)) {
    output_line("stb ,x");
  } else {
    output_line("std ,x");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BootComInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <BootComUartInit@plt>
  mov    $0x0,%eax
  call   <BootComCanInit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void BootComInit(void) {
  BootComUartInit();
  BootComCanInit();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BootComInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <BootComUartInit@plt>
  mov    $0x0,%eax
  call   <BootComCanInit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BootComInit(void) {
  BootComUartInit();
  BootComCanInit();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BootComInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BootComUartInit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <BootComCanInit@plt>
```

assistant: ```c
void BootComInit(void) {
  BootComUartInit();
  BootComCanInit();
}
```
user: What is the c source code of the assembly code below?

```asm
<BootComInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BootComUartInit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <BootComCanInit@plt>
```

assistant: ```c
void BootComInit(void) {
  BootComUartInit();
  BootComCanInit();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<reverse_sort_callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int reverse_sort_callback(const void *pa, const void *pb) {
  const char **a = (const char **)pa;
  const char **b = (const char **)pb;
  return strcmp(*b, *a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse_sort_callback>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rax
  mov    (%rdi),%rsi
  mov    (%rax),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int reverse_sort_callback(const void *pa, const void *pb) {
  const char **a = (const char **)pa;
  const char **b = (const char **)pb;
  return strcmp(*b, *a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_sort_callback>:
  endbr64
  mov    %rsi,%r8
  mov    (%rdi),%rsi
  mov    (%r8),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int reverse_sort_callback(const void *pa, const void *pb) {
  const char **a = (const char **)pa;
  const char **b = (const char **)pb;
  return strcmp(*b, *a);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<addr_to_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  shl    $0x2,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x4,%esi
  mov    %rcx,%rdi
  call   <ull_to_bytes@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x7,-0x4(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void addr_to_bytes(unsigned char *bytes, const uint32_t addr[8]) {
  int i;
  for (i = 0; i < 8; i++) {
    ull_to_bytes(bytes + i * 4, 4, addr[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<addr_to_bytes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L6:
  mov    0x0(%rbp,%rbx,1),%edx
  lea    (%r12,%rbx,1),%rdi
  mov    $0x4,%esi
  call   <ull_to_bytes@plt>
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void addr_to_bytes(unsigned char *bytes, const uint32_t addr[8]) {
  int i;
  for (i = 0; i < 8; i++) {
    ull_to_bytes(bytes + i * 4, 4, addr[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addr_to_bytes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L3:
  mov    0x0(%rbp,%rbx,1),%edx
  lea    (%r12,%rbx,1),%rdi
  mov    $0x4,%esi
  add    $0x4,%rbx
  call   <ull_to_bytes@plt>
  cmp    $0x20,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void addr_to_bytes(unsigned char *bytes, const uint32_t addr[8]) {
  int i;
  for (i = 0; i < 8; i++) {
    ull_to_bytes(bytes + i * 4, 4, addr[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<addr_to_bytes>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L1:
  mov    0x0(%rbp,%rbx,1),%edx
  lea    (%r12,%rbx,1),%rdi
  mov    $0x4,%esi
  add    $0x4,%rbx
  call   <ull_to_bytes@plt>
  cmp    $0x20,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void addr_to_bytes(unsigned char *bytes, const uint32_t addr[8]) {
  int i;
  for (i = 0; i < 8; i++) {
    ull_to_bytes(bytes + i * 4, 4, addr[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xstrdup(const char *s) {
  size_t len = strlen(s);
  char *r = xmalloc(len + 1);
  memcpy(r, s, len + 1);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<xstrdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12
  mov    %r12,%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *xstrdup(const char *s) {
  size_t len = strlen(s);
  char *r = xmalloc(len + 1);
  memcpy(r, s, len + 1);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<xstrdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <xmalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *xstrdup(const char *s) {
  size_t len = strlen(s);
  char *r = xmalloc(len + 1);
  memcpy(r, s, len + 1);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xstrdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13
  mov    %r13,%rdi
  call   <xmalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *xstrdup(const char *s) {
  size_t len = strlen(s);
  char *r = xmalloc(len + 1);
  memcpy(r, s, len + 1);
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: usage: lcs file_a file_b [ OPTIONS ]
	-o file3
	--size1 l
	--size2 l
	-s|--size l
	-d| --distance l


assistant: ```c
void usage() {
  printf("usage: lcs file_a file_b [ OPTIONS ]\n"
         "\t-o file3\n"
         "\t--size1 l\n"
         "\t--size2 l\n"
         "\t-s|--size l\n"
         "\t-d| --distance l\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: usage: lcs file_a file_b [ OPTIONS ]
	-o file3
	--size1 l
	--size2 l
	-s|--size l
	-d| --distance l


assistant: ```c
void usage() {
  printf("usage: lcs file_a file_b [ OPTIONS ]\n"
         "\t-o file3\n"
         "\t--size1 l\n"
         "\t--size2 l\n"
         "\t-s|--size l\n"
         "\t-d| --distance l\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: usage: lcs file_a file_b [ OPTIONS ]
	-o file3
	--size1 l
	--size2 l
	-s|--size l
	-d| --distance l


assistant: ```c
void usage() {
  printf("usage: lcs file_a file_b [ OPTIONS ]\n"
         "\t-o file3\n"
         "\t--size1 l\n"
         "\t--size2 l\n"
         "\t-s|--size l\n"
         "\t-d| --distance l\n");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string

tool: D1: usage: lcs file_a file_b [ OPTIONS ]
	-o file3
	--size1 l
	--size2 l
	-s|--size l
	-d| --distance l


assistant: ```c
void usage() {
  printf("usage: lcs file_a file_b [ OPTIONS ]\n"
         "\t-o file3\n"
         "\t--size1 l\n"
         "\t--size2 l\n"
         "\t-s|--size l\n"
         "\t-d| --distance l\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x5,-0x8(%rbp)
  jmp    L13
L18:
  mov    $0x0,%eax
  call   <foo@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x31,-0x8(%rbp)
  jle    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int sum = 0;
  for (i = 5; i < 50; i++) {
    sum += foo();
  }
  return sum / 10;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2d,%ebx
  mov    $0x0,%ebp
L1:
  mov    $0x0,%eax
  call   <foo@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L1
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebp
  sub    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int sum = 0;
  for (i = 5; i < 50; i++) {
    sum += foo();
  }
  return sum / 10;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2d,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <foo@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L9
  movslq %ebp,%rax
  add    $0x8,%rsp
  sar    $0x1f,%ebp
  imul   $0x66666667,%rax,%rax
  pop    %rbx
  sar    $0x22,%rax
  sub    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int sum = 0;
  for (i = 5; i < 50; i++) {
    sum += foo();
  }
  return sum / 10;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x2d,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  call   <foo@plt>
  add    %eax,%ebp
  sub    $0x1,%ebx
  jne    L8
  movslq %ebp,%rax
  add    $0x8,%rsp
  sar    $0x1f,%ebp
  imul   $0x66666667,%rax,%rax
  pop    %rbx
  sar    $0x22,%rax
  sub    %ebp,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 0;
  int sum = 0;
  for (i = 5; i < 50; i++) {
    sum += foo();
  }
  return sum / 10;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x24(%rbp)
  jne    L26
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <d_s@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <t_extract@plt>
  mov    %eax,-0x18(%rbp)
  jmp    L10
L26:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <t_extract@plt>
  mov    %eax,-0x18(%rbp)
L10:
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <t_conv@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type: string

tool: D3: %.1f


assistant: ```c
int main(int argc, char *argv[]) {
  char *temp_string;
  int temp_type;
  float temp;
  if (argc == 1) {
    temp_string = d_s(temp_string);
    temp_type = t_extract(temp_string, &temp);
  } else {
    temp_type = t_extract(argv[1], &temp);
  }
  printf("%.1f\n", t_conv(&temp, &temp_type));
  free(temp_string);
  return temp_type;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L19
  lea    0x4(%rsp),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <t_extract@plt>
L21:
  mov    %eax,(%rsp)
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  call   <t_conv@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  mov    $0x0,%ebx
  mov    %rbx,%rdi
  call   <d_s@plt>
  mov    %rax,%rbx
  lea    0x4(%rsp),%rsi
  mov    %rax,%rdi
  call   <t_extract@plt>
  jmp    L21
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %.1f


assistant: ```c
int main(int argc, char *argv[]) {
  char *temp_string;
  int temp_type;
  float temp;
  if (argc == 1) {
    temp_string = d_s(temp_string);
    temp_type = t_extract(temp_string, &temp);
  } else {
    temp_type = t_extract(argv[1], &temp);
  }
  printf("%.1f\n", t_conv(&temp, &temp_type));
  free(temp_string);
  return temp_type;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L29
  mov    0x8(%rsi),%rdi
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <t_extract@plt>
L7:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  mov    %eax,(%rsp)
  call   <t_conv@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L29:
  xor    %edi,%edi
  lea    0x4(%rsp),%r12
  call   <d_s@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <t_extract@plt>
  jmp    L7
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: %.1f


assistant: ```c
int main(int argc, char *argv[]) {
  char *temp_string;
  int temp_type;
  float temp;
  if (argc == 1) {
    temp_string = d_s(temp_string);
    temp_type = t_extract(temp_string, &temp);
  } else {
    temp_type = t_extract(argv[1], &temp);
  }
  printf("%.1f\n", t_conv(&temp, &temp_type));
  free(temp_string);
  return temp_type;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L19
  mov    0x8(%rsi),%rdi
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <t_extract@plt>
L9:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  mov    %eax,(%rsp)
  call   <t_conv@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L19:
  xor    %edi,%edi
  lea    0x4(%rsp),%r12
  call   <d_s@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <t_extract@plt>
  jmp    L9
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: %.1f


assistant: ```c
int main(int argc, char *argv[]) {
  char *temp_string;
  int temp_type;
  float temp;
  if (argc == 1) {
    temp_string = d_s(temp_string);
    temp_type = t_extract(temp_string, &temp);
  } else {
    temp_type = t_extract(argv[1], &temp);
  }
  printf("%.1f\n", t_conv(&temp, &temp_type));
  free(temp_string);
  return temp_type;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alg_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rax
  mov    0x8(%rax),%edx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <d2i_PBEPARAM@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <OBJ_obj2nid@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,%edi
  call   <ASN1_INTEGER_get@plt>
  mov    -0x38(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <PBEPARAM_free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int alg_get(X509_ALGOR *alg, int *pnid, int *piter, int *psaltlen) {
  PBEPARAM *pbe;
  const unsigned char *p;
  p = alg->parameter->value.sequence->data;
  pbe = d2i_PBEPARAM(NULL, &p, alg->parameter->value.sequence->length);
  *pnid = OBJ_obj2nid(alg->algorithm);
  *piter = ASN1_INTEGER_get(pbe->iter);
  *psaltlen = pbe->salt->length;
  PBEPARAM_free(pbe);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alg_get>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rdi),%rax
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  mov    %rdx,(%rsp)
  mov    (%rax),%rax
  mov    0x8(%rax),%edx
  mov    %rsp,%rsi
  mov    $0x0,%edi
  call   <d2i_PBEPARAM@plt>
  mov    %rax,%rbx
  mov    0x0(%rbp),%edi
  call   <OBJ_obj2nid@plt>
  mov    %eax,(%r14)
  mov    0x8(%rbx),%edi
  call   <ASN1_INTEGER_get@plt>
  mov    %eax,0x0(%r13)
  mov    (%rbx),%rax
  mov    (%rax),%eax
  mov    %eax,(%r12)
  mov    %rbx,%rdi
  call   <PBEPARAM_free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int alg_get(X509_ALGOR *alg, int *pnid, int *piter, int *psaltlen) {
  PBEPARAM *pbe;
  const unsigned char *p;
  p = alg->parameter->value.sequence->data;
  pbe = d2i_PBEPARAM(NULL, &p, alg->parameter->value.sequence->length);
  *pnid = OBJ_obj2nid(alg->algorithm);
  *piter = ASN1_INTEGER_get(pbe->iter);
  *psaltlen = pbe->salt->length;
  PBEPARAM_free(pbe);
  return 0;
}
```