ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x1f4,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  lea    0xfa0(%rsp),%r12
  mov    %rbx,%rbp
L36:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L36
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rbp
  lea    D56(%rip),%r13
L23:
  mov    0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L23
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <merge_sort@plt>
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D56(%rip),%rbp
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L15
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D55
data_type: string
name: unpack_data
arguments: data_label: D56
data_type: string
name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D40
data_type: string

tool: D55: Original array: 
[

tool: D56: %d, 

tool: D15: ]

tool: D40: 
Sorted array: 
[

assistant: ```c
int main(int argc, char *argv[]) {
  int a[1000] = {0};
  srand(time(0));
  for (int i = 0; i < 1000; a[i] = rand() % 1000, i++) {
  }
  printf("Original array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  merge_sort(a, 1000);
  printf("\nSorted array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1f4,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%r12
  lea    0xfa0(%rsp),%rbp
  mov    %r12,%rbx
  mov    %r12,%r13
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L32:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L32
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  mov    %r12,%r13
  call   <printf@plt>
  lea    D33(%rip),%r14
  nopl   0x0(%rax)
L21:
  mov    0x0(%r13),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L21
  lea    D25(%rip),%r13
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  mov    $0x3e8,%esi
  call   <merge_sort@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L28:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L28
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D9: Original array: 
[

tool: D33: %d, 

tool: D25: ]

tool: D29: 
Sorted array: 
[

assistant: ```c
int main(int argc, char *argv[]) {
  int a[1000] = {0};
  srand(time(0));
  for (int i = 0; i < 1000; a[i] = rand() % 1000, i++) {
  }
  printf("Original array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  merge_sort(a, 1000);
  printf("\nSorted array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1f4,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%r12
  lea    0xfa0(%rsp),%rbp
  mov    %r12,%rbx
  mov    %r12,%r13
  rep stos %rax,%es:(%rdi)
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L26:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r13)
  cmp    %rbp,%r13
  jne    L26
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  mov    %r12,%r13
  call   <printf@plt>
  lea    D6(%rip),%r14
  nopl   0x0(%rax)
L38:
  mov    0x0(%r13),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L38
  lea    D38(%rip),%r13
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  mov    $0x3e8,%esi
  call   <merge_sort@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L29:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L29
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string
name: parse_data
arguments: data_label: D38
datatype: string
name: parse_data
arguments: data_label: D32
datatype: string

tool: D34: Original array: 
[

tool: D6: %d, 

tool: D38: ]

tool: D32: 
Sorted array: 
[

assistant: ```c
int main(int argc, char *argv[]) {
  int a[1000] = {0};
  srand(time(0));
  for (int i = 0; i < 1000; a[i] = rand() % 1000, i++) {
  }
  printf("Original array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  merge_sort(a, 1000);
  printf("\nSorted array: \n[");
  for (int i = 0; i < 1000; printf("%d, ", a[i++])) {
  }
  printf("\b\b]\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_array_opt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_inarray@plt>
  test   %rax,%rax
  jns    L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    %ecx,(%rdx)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L0:
  nop
  leave
  ret
```

assistant: ```c
void set_array_opt(const char *oarg, const char *arr[], int *size, int max) {
  if (str_inarray(oarg, arr, *size) < 0 && *size < max)
    arr[(*size)++] = oarg;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_array_opt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  mov    (%rdx),%edx
  call   <str_inarray@plt>
  test   %rax,%rax
  js     L22
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    (%rbx),%eax
  cmp    %r13d,%eax
  jge    L21
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  cltq
  mov    %r12,0x0(%rbp,%rax,8)
  jmp    L21
```

assistant: ```c
void set_array_opt(const char *oarg, const char *arr[], int *size, int max) {
  if (str_inarray(oarg, arr, *size) < 0 && *size < max)
    arr[(*size)++] = oarg;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<set_array_opt>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  call   <str_inarray@plt>
  test   %rax,%rax
  js     L2
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  movslq (%rbx),%rax
  cmp    %r13d,%eax
  jge    L5
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  mov    %r12,0x0(%rbp,%rax,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void set_array_opt(const char *oarg, const char *arr[], int *size, int max) {
  if (str_inarray(oarg, arr, *size) < 0 && *size < max)
    arr[(*size)++] = oarg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_array_opt>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  call   <str_inarray@plt>
  test   %rax,%rax
  js     L11
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  movslq (%rbx),%rax
  cmp    %r13d,%eax
  jge    L19
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  mov    %r12,0x0(%rbp,%rax,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void set_array_opt(const char *oarg, const char *arr[], int *size, int max) {
  if (str_inarray(oarg, arr, *size) < 0 && *size < max)
    arr[(*size)++] = oarg;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<scandbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <nxt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void scandbl(char **toks, double *f) {
  char *t = nxt(toks);
  double l = strtod(t, NULL);
  *f = l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scandbl>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <nxt@plt>
  mov    %rax,%rdi
  mov    $0x0,%esi
  call   <strtod@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void scandbl(char **toks, double *f) {
  char *t = nxt(toks);
  double l = strtod(t, NULL);
  *f = l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scandbl>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <nxt@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <strtod@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void scandbl(char **toks, double *f) {
  char *t = nxt(toks);
  double l = strtod(t, NULL);
  *f = l;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scandbl>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <nxt@plt>
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <strtod@plt>
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void scandbl(char **toks, double *f) {
  char *t = nxt(toks);
  double l = strtod(t, NULL);
  *f = l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<manipulateName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char manipulateName(char name[]) {
  char buf[20];
  strcpy(buf, name);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<manipulateName>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char manipulateName(char name[]) {
  char buf[20];
  strcpy(buf, name);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<manipulateName>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char manipulateName(char name[]) {
  char buf[20];
  strcpy(buf, name);
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<manipulateName>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char manipulateName(char name[]) {
  char buf[20];
  strcpy(buf, name);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest> [-I flags]


assistant: ```c
void usage(const char *program_name) {
  printf("USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest>"
         " [-I flags]\n",
         program_name);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest> [-I flags]


assistant: ```c
void usage(const char *program_name) {
  printf("USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest>"
         " [-I flags]\n",
         program_name);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest> [-I flags]


assistant: ```c
void usage(const char *program_name) {
  printf("USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest>"
         " [-I flags]\n",
         program_name);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest> [-I flags]


assistant: ```c
void usage(const char *program_name) {
  printf("USAGE: %s <path-to-cproto> <dut-source-file.c> <mockables.lst> <path-to-cutest>"
         " [-I flags]\n",
         program_name);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x7a1000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7a121c(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7a1218(%rbp)
  jmp    L83
L59:
  lea    -0x7a1210(%rbp),%rdx
  mov    -0x7a1218(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7a1218(%rbp)
L83:
  mov    -0x7a121c(%rbp),%eax
  cmp    %eax,-0x7a1218(%rbp)
  jl     L59
  movl   $0x0,-0x7a1214(%rbp)
  jmp    L36
L62:
  movl   $0x0,-0x7a1218(%rbp)
  jmp    L54
L0:
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    -0x7a1210(%rbp,%rax,4),%eax
  cmp    %eax,-0x7a1214(%rbp)
  jne    L51
  mov    -0x7a1214(%rbp),%eax
  cltq
  mov    -0x3d0910(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x7a1214(%rbp),%eax
  cltq
  mov    %edx,-0x3d0910(%rbp,%rax,4)
L51:
  addl   $0x1,-0x7a1218(%rbp)
L54:
  mov    -0x7a121c(%rbp),%eax
  cmp    %eax,-0x7a1218(%rbp)
  jl     L0
  mov    -0x7a1214(%rbp),%eax
  cltq
  mov    -0x3d0910(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x7a1214(%rbp)
L36:
  cmpl   $0x63,-0x7a1214(%rbp)
  jle    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D23
data_type: string

tool: D8: %d

tool: D23: %d 

assistant: ```c
int main() {
  int i, j, a[1000000], b[1000000], n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (j = 0; j < 100; j++) {
    for (i = 0; i < n; i++) {
      if (a[i] == j)
        b[j]++;
    }
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7a1000(%rsp),%r11
L101:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L101
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7a1218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L40
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L3
L40:
  lea    0x3d0910(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
  jmp    L51
L105:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L9
L6:
  cmp    %ebx,(%rax)
  jne    L105
  addl   $0x1,0x0(%rbp)
  jmp    L105
L9:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x64,%ebx
  je     L87
L51:
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L9
  lea    0x10(%rsp),%rax
  lea    -0x1(%rdx),%edx
  lea    0x14(%rsp,%rdx,4),%rdx
  jmp    L6
L87:
  mov    0x7a1218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    $0x0,%eax
  add    $0x7a1220,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D6: %d

tool: D16: %d 

assistant: ```c
int main() {
  int i, j, a[1000000], b[1000000], n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (j = 0; j < 100; j++) {
    for (i = 0; i < n; i++) {
      if (a[i] == j)
        b[j]++;
    }
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7a1000(%rsp),%r11
L10:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L10
  sub    $0x228,%rsp
  lea    D15(%rip),%r12
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x7a1218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L57
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
L45:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jg     L45
L57:
  lea    0x3d0910(%rsp),%r13
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r12
  lea    D2(%rip),%rbp
L63:
  mov    0x0(%r13),%esi
  test   %edx,%edx
  jle    L38
  sub    $0x1,%edx
  lea    0x10(%rsp),%rax
  lea    (%r12,%rdx,4),%rdx
  nopl   0x0(%rax)
L49:
  cmp    %ebx,(%rax)
  jne    L36
  add    $0x1,%esi
  mov    %esi,0x0(%r13)
L36:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L49
L38:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <printf@plt>
  cmp    $0x64,%ebx
  je     L76
  mov    0xc(%rsp),%edx
  jmp    L63
L76:
  mov    0x7a1218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x7a1228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string

tool: D15: %d

tool: D2: %d 

assistant: ```c
int main() {
  int i, j, a[1000000], b[1000000], n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (j = 0; j < 100; j++) {
    for (i = 0; i < n; i++) {
      if (a[i] == j)
        b[j]++;
    }
    printf("%d ", b[j]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7a1000(%rsp),%r11
L47:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L47
  sub    $0x228,%rsp
  lea    D3(%rip),%r12
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x7a1218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L37
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
L53:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jg     L53
L37:
  lea    0x3d0910(%rsp),%r13
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r12
  lea    D6(%rip),%rbp
L21:
  mov    0x0(%r13),%esi
  test   %edx,%edx
  jle    L9
  sub    $0x1,%edx
  lea    0x10(%rsp),%rax
  lea    (%r12,%rdx,4),%rdx
  nopl   0x0(%rax)
L85:
  cmp    %ebx,(%rax)
  jne    L59
  add    $0x1,%esi
  mov    %esi,0x0(%r13)
L59:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L85
L9:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <printf@plt>
  cmp    $0x64,%ebx
  je     L41
  mov    0xc(%rsp),%edx
  jmp    L21
L41:
  mov    0x7a1218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x7a1228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D6
type: string

tool: D3: %d

tool: D6: %d 

assistant: ```c
int main() {
  int i, j, a[1000000], b[1000000], n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (j = 0; j < 100; j++) {
    for (i = 0; i < n; i++) {
      if (a[i] == j)
        b[j]++;
    }
    printf("%d ", b[j]);
  }
  return 0;
}
```