ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<sgn>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jae    L0
  xorpd  D1(%rip),%xmm0
L0:
  comisd %xmm2,%xmm1
  jb     L18
  ret
  nopl   (%rax)
L18:
  xorpd  D1(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: f32[4]

tool: {"D1": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double sgn(double a, double b) {
  double x = 0;
  x = (double)(a >= 0) ? a : -a;
  return (double)(b >= 0) ? x : -x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sgn>:
  endbr64
  pxor   %xmm2,%xmm2
  comisd %xmm2,%xmm0
  jae    L18
  xorpd  D11(%rip),%xmm0
L18:
  comisd %xmm2,%xmm1
  jb     L8
  ret
  nopl   (%rax)
L8:
  xorpd  D11(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: f32[4]

tool: {"D11": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double sgn(double a, double b) {
  double x = 0;
  x = (double)(a >= 0) ? a : -a;
  return (double)(b >= 0) ? x : -x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getppid_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x460,%rsp
  mov    %edi,-0x454(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x454(%rbp),%edx
  lea    -0x430(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x430(%rbp),%rax
  lea    D37(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x438(%rbp)
  cmpq   $0x0,-0x438(%rbp)
  jne    L40
  mov    $0xffffffff,%eax
  jmp    L26
L40:
  mov    -0x438(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x438(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L26
L1:
  mov    -0x438(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    -0x410(%rbp),%rax
  lea    D39(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x440(%rbp)
  movl   $0x0,-0x444(%rbp)
  jmp    L2
L22:
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x440(%rbp)
  addl   $0x1,-0x444(%rbp)
L2:
  cmpl   $0x2,-0x444(%rbp)
  jle    L22
  mov    -0x440(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D37
type: string
name: read_data
arguments: tag: D39
type: string

tool: D4: /proc/%d/stat

tool: D37: r

tool: D39:  

assistant: ```c
pid_t getppid_of(pid_t pid) {
  char statfile[20];
  char buffer[1024];
  sprintf(statfile, "/proc/%d/stat", pid);
  FILE *fd = fopen(statfile, "r");
  if (fd == NULL)
    return -1;
  if (fgets(buffer, sizeof(buffer), fd) == NULL) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  char *token = strtok(buffer, " ");
  int i;
  for (i = 0; i < 3; i++)
    token = strtok(NULL, " ");
  return atoi(token);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getppid_of>:
  endbr64
  push   %rbx
  sub    $0x430,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L32
  mov    %rax,%rbx
  lea    0x20(%rsp),%rdi
  mov    %rax,%rdx
  mov    $0x400,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L37
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    0x20(%rsp),%rdi
  lea    D20(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
L3:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x430,%rsp
  pop    %rbx
  ret
L37:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L3
L32:
  mov    $0xffffffff,%eax
  jmp    L3
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string

tool: D12: /proc/%d/stat

tool: D0: r

tool: D20:  

assistant: ```c
pid_t getppid_of(pid_t pid) {
  char statfile[20];
  char buffer[1024];
  sprintf(statfile, "/proc/%d/stat", pid);
  FILE *fd = fopen(statfile, "r");
  if (fd == NULL)
    return -1;
  if (fgets(buffer, sizeof(buffer), fd) == NULL) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  char *token = strtok(buffer, " ");
  int i;
  for (i = 0; i < 3; i++)
    token = strtok(NULL, " ");
  return atoi(token);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getppid_of>:
  endbr64
  push   %r12
  mov    %edi,%edx
  lea    D14(%rip),%rsi
  push   %rbp
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L12
  lea    0x20(%rsp),%r12
  mov    %rax,%rdx
  mov    $0x400,%esi
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L38
  call   <fclose@plt>
  lea    D7(%rip),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <atoi@plt>
L7:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x438,%rsp
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L7
L38:
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string

tool: D14: /proc/%d/stat

tool: D20: r

tool: D7:  

assistant: ```c
pid_t getppid_of(pid_t pid) {
  char statfile[20];
  char buffer[1024];
  sprintf(statfile, "/proc/%d/stat", pid);
  FILE *fd = fopen(statfile, "r");
  if (fd == NULL)
    return -1;
  if (fgets(buffer, sizeof(buffer), fd) == NULL) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  char *token = strtok(buffer, " ");
  int i;
  for (i = 0; i < 3; i++)
    token = strtok(NULL, " ");
  return atoi(token);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getppid_of>:
  endbr64
  push   %r12
  mov    %edi,%edx
  lea    D1(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x430,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L4
  lea    0x20(%rsp),%r12
  mov    %rax,%rdx
  mov    $0x400,%esi
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L6
  lea    D11(%rip),%rbp
  mov    $0x3,%ebx
  call   <fclose@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
L55:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  sub    $0x1,%ebx
  jne    L55
  mov    %rax,%rdi
  call   <atoi@plt>
L32:
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x430,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0xffffffff,%eax
  jmp    L32
L6:
  call   <fclose@plt>
  mov    $0xffffffff,%eax
  jmp    L32
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string

tool: D1: /proc/%d/stat

tool: D17: r

tool: D11:  

assistant: ```c
pid_t getppid_of(pid_t pid) {
  char statfile[20];
  char buffer[1024];
  sprintf(statfile, "/proc/%d/stat", pid);
  FILE *fd = fopen(statfile, "r");
  if (fd == NULL)
    return -1;
  if (fgets(buffer, sizeof(buffer), fd) == NULL) {
    fclose(fd);
    return -1;
  }
  fclose(fd);
  char *token = strtok(buffer, " ");
  int i;
  for (i = 0; i < 3; i++)
    token = strtok(NULL, " ");
  return atoi(token);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<makeEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %rdi,-0xf8(%rbp)
  mov    %esi,-0xfc(%rbp)
  mov    %rdx,-0x108(%rbp)
  mov    %ecx,-0x100(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0xe4(%rbp)
  movl   $0x0,-0xe8(%rbp)
  jmp    L39
L65:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xf8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shl    $0x2,%rax
  lea    -0x184(%rax),%rdx
  lea    -0xe0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xf8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shl    $0x2,%rax
  lea    -0x184(%rax),%rcx
  lea    -0xe0(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xe8(%rbp)
L39:
  mov    -0xe8(%rbp),%eax
  cmp    -0xfc(%rbp),%eax
  jl     L65
  movl   $0x0,-0xe8(%rbp)
  jmp    L34
L61:
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x108(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shl    $0x2,%rax
  lea    -0x184(%rax),%rdx
  lea    -0x70(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xe8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x108(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  shl    $0x2,%rax
  lea    -0x184(%rax),%rcx
  lea    -0x70(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xe8(%rbp)
L34:
  mov    -0xe8(%rbp),%eax
  cmp    -0x100(%rbp),%eax
  jl     L61
  movl   $0x0,-0xe8(%rbp)
  jmp    L42
L66:
  mov    -0xe8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0xe0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0xe8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    -0x70(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,-0xe4(%rbp)
  addl   $0x1,-0xe8(%rbp)
L42:
  cmpl   $0x19,-0xe8(%rbp)
  jle    L66
  mov    -0xe4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int a[26] = {0}, b[26] = {0}, i, r = 0;
  for (i = 0; i < n1; i++)
    *(a + *(s1 + i) - 'a') += 1;
  for (i = 0; i < n2; i++)
    *(b + *(s2 + i) - 'a') += 1;
  for (i = 0; i < 26; i++)
    r = r + abs(*(a + i) - *(b + i));
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<makeEqual>:
  endbr64
  sub    $0xe8,%rsp
  mov    %rdi,%r10
  mov    %rdx,%r9
  mov    %ecx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x70(%rsp),%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  test   %esi,%esi
  jle    L45
  mov    %r10,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%r10,%rdx,1),%rsi
  mov    %rsp,%rcx
L56:
  movsbq (%rax),%rdx
  addl   $0x1,-0x184(%rcx,%rdx,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L56
L45:
  test   %r8d,%r8d
  jle    L49
  mov    %r9,%rax
  lea    -0x1(%r8),%edx
  lea    0x1(%r9,%rdx,1),%rsi
  lea    0x70(%rsp),%rcx
L47:
  movsbq (%rax),%rdx
  addl   $0x1,-0x184(%rcx,%rdx,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L47
L49:
  mov    $0x0,%edx
  mov    $0x0,%esi
  lea    0x70(%rsp),%rdi
L5:
  mov    (%rsp,%rdx,1),%eax
  sub    (%rdx,%rdi,1),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  add    %eax,%esi
  add    $0x4,%rdx
  cmp    $0x68,%rdx
  jne    L5
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    %esi,%eax
  add    $0xe8,%rsp
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int a[26] = {0}, b[26] = {0}, i, r = 0;
  for (i = 0; i < n1; i++)
    *(a + *(s1 + i) - 'a') += 1;
  for (i = 0; i < n2; i++)
    *(b + *(s2 + i) - 'a') += 1;
  for (i = 0; i < 26; i++)
    r = r + abs(*(a + i) - *(b + i));
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<makeEqual>:
  endbr64
  sub    $0xe8,%rsp
  mov    %esi,%r11d
  mov    %rdi,%r8
  mov    %ecx,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xd,%ecx
  lea    0x70(%rsp),%r9
  mov    %rsi,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0xd,%ecx
  mov    %r9,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r11d,%r11d
  jle    L6
  lea    -0x1(%r11),%ecx
  mov    %r8,%rax
  lea    0x1(%r8,%rcx,1),%rdi
  nopw   0x0(%rax,%rax,1)
L9:
  movsbq (%rax),%rcx
  add    $0x1,%rax
  addl   $0x1,-0x184(%rsi,%rcx,4)
  cmp    %rax,%rdi
  jne    L9
  mov    (%rsp),%eax
  test   %r10d,%r10d
  jle    L16
L36:
  lea    -0x1(%r10),%ecx
  lea    0x1(%rdx,%rcx,1),%rdi
  cs nopw 0x0(%rax,%rax,1)
L72:
  movsbq (%rdx),%rcx
  add    $0x1,%rdx
  addl   $0x1,-0x184(%r9,%rcx,4)
  cmp    %rdx,%rdi
  jne    L72
  mov    0x70(%rsp),%ecx
L22:
  xor    %edx,%edx
  xor    %r8d,%r8d
  jmp    L63
  nopl   0x0(%rax)
L20:
  mov    (%rsi,%rdx,1),%eax
  mov    (%r9,%rdx,1),%ecx
L63:
  sub    %ecx,%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  add    $0x4,%rdx
  add    %eax,%r8d
  cmp    $0x68,%rdx
  jne    L20
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    %r8d,%eax
  add    $0xe8,%rsp
  ret
L6:
  xor    %eax,%eax
  test   %r10d,%r10d
  jg     L36
L16:
  xor    %ecx,%ecx
  jmp    L22
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int a[26] = {0}, b[26] = {0}, i, r = 0;
  for (i = 0; i < n1; i++)
    *(a + *(s1 + i) - 'a') += 1;
  for (i = 0; i < n2; i++)
    *(b + *(s2 + i) - 'a') += 1;
  for (i = 0; i < 26; i++)
    r = r + abs(*(a + i) - *(b + i));
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makeEqual>:
  endbr64
  sub    $0xe8,%rsp
  mov    %rdi,%r8
  mov    %esi,%r11d
  mov    %ecx,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    $0xd,%ecx
  lea    0x70(%rsp),%rsi
  mov    %r9,%rdi
  rep stos %rax,%es:(%rdi)
  mov    $0xd,%ecx
  mov    %rsi,%rdi
  rep stos %rax,%es:(%rdi)
  test   %r11d,%r11d
  jle    L38
  lea    -0x1(%r11),%ecx
  mov    %r8,%rax
  lea    0x1(%r8,%rcx,1),%rdi
  cs nopw 0x0(%rax,%rax,1)
L2:
  movsbq (%rax),%rcx
  add    $0x1,%rax
  addl   $0x1,-0x184(%r9,%rcx,4)
  cmp    %rax,%rdi
  jne    L2
L38:
  test   %r10d,%r10d
  jle    L28
  mov    %rdx,%rax
  lea    -0x1(%r10),%edx
  lea    0x1(%rax,%rdx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L30:
  movsbq (%rax),%rdx
  add    $0x1,%rax
  addl   $0x1,-0x184(%rsi,%rdx,4)
  cmp    %rcx,%rax
  jne    L30
L28:
  movdqa 0x10(%rsp),%xmm0
  mov    0x60(%rsp),%eax
  psubd  0x80(%rsp),%xmm0
  sub    0xd0(%rsp),%eax
  mov    %eax,%edx
  mov    0x64(%rsp),%ecx
  movdqa %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  movdqa (%rsp),%xmm0
  neg    %edx
  psrad  $0x1f,%xmm1
  psubd  0x70(%rsp),%xmm0
  cmovs  %eax,%edx
  sub    0xd4(%rsp),%ecx
  pxor   %xmm1,%xmm2
  psubd  %xmm1,%xmm2
  movdqa %xmm0,%xmm1
  psrad  $0x1f,%xmm1
  pxor   %xmm1,%xmm0
  psubd  %xmm1,%xmm0
  paddd  %xmm0,%xmm2
  movdqa 0x20(%rsp),%xmm0
  psubd  0x90(%rsp),%xmm0
  movdqa %xmm0,%xmm3
  movdqa %xmm0,%xmm1
  movdqa 0x30(%rsp),%xmm0
  psubd  0xa0(%rsp),%xmm0
  psrad  $0x1f,%xmm3
  pxor   %xmm3,%xmm1
  psubd  %xmm3,%xmm1
  movdqa %xmm0,%xmm3
  paddd  %xmm2,%xmm1
  psrad  $0x1f,%xmm3
  movdqa %xmm0,%xmm2
  movdqa 0x40(%rsp),%xmm0
  psubd  0xb0(%rsp),%xmm0
  pxor   %xmm3,%xmm2
  psubd  %xmm3,%xmm2
  movdqa %xmm0,%xmm3
  paddd  %xmm1,%xmm2
  movdqa %xmm0,%xmm1
  movdqa 0x50(%rsp),%xmm0
  psubd  0xc0(%rsp),%xmm0
  psrad  $0x1f,%xmm3
  pxor   %xmm3,%xmm1
  psubd  %xmm3,%xmm1
  paddd  %xmm2,%xmm1
  movdqa %xmm0,%xmm2
  psrad  $0x1f,%xmm2
  pxor   %xmm2,%xmm0
  psubd  %xmm2,%xmm0
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%edx
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  add    %edx,%eax
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0xe8,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int a[26] = {0}, b[26] = {0}, i, r = 0;
  for (i = 0; i < n1; i++)
    *(a + *(s1 + i) - 'a') += 1;
  for (i = 0; i < n2; i++)
    *(b + *(s2 + i) - 'a') += 1;
  for (i = 0; i < 26; i++)
    r = r + abs(*(a + i) - *(b + i));
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<binsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L41
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L53
  mov    -0x4(%rbp),%eax
  jmp    L12
L53:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jge    L36
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <binsearch>
  jmp    L12
L36:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <binsearch>
  jmp    L12
L41:
  mov    $0xffffffff,%eax
L12:
  leave
  ret
```

assistant: ```c
int binsearch(int arr[], int l, int r, int x) {
  if (r >= l) {
    int mid = l + (r - l) / 2;
    if (arr[mid] == x)
      return mid;
    if (arr[mid] > x)
      return binsearch(arr, l, mid - 1, x);
    return binsearch(arr, mid + 1, r, x);
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binsearch>:
  endbr64
  cmp    %esi,%edx
  jl     L29
  sub    $0x8,%rsp
  mov    %edx,%r8d
  sub    %esi,%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %ecx,%r8d
  je     L1
  jle    L7
  lea    -0x1(%rax),%edx
  call   <binsearch>
L1:
  add    $0x8,%rsp
  ret
L7:
  lea    0x1(%rax),%esi
  call   <binsearch>
  jmp    L1
L29:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int binsearch(int arr[], int l, int r, int x) {
  if (r >= l) {
    int mid = l + (r - l) / 2;
    if (arr[mid] == x)
      return mid;
    if (arr[mid] > x)
      return binsearch(arr, l, mid - 1, x);
    return binsearch(arr, mid + 1, r, x);
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binsearch>:
  endbr64
  cmp    %edx,%esi
  jle    L50
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L31:
  lea    -0x1(%rax),%edx
  cmp    %esi,%edx
  jl     L14
L50:
  mov    %edx,%eax
  sub    %esi,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  je     L11
  jg     L31
  lea    0x1(%rax),%esi
  cmp    %esi,%edx
  jge    L50
L14:
  mov    $0xffffffff,%eax
L11:
  ret
```

assistant: ```c
int binsearch(int arr[], int l, int r, int x) {
  if (r >= l) {
    int mid = l + (r - l) / 2;
    if (arr[mid] == x)
      return mid;
    if (arr[mid] > x)
      return binsearch(arr, l, mid - 1, x);
    return binsearch(arr, mid + 1, r, x);
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binsearch>:
  endbr64
  nopl   0x0(%rax)
L8:
  cmp    %edx,%esi
  jg     L25
L13:
  mov    %edx,%eax
  sub    %esi,%eax
  sar    %eax
  add    %esi,%eax
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  je     L32
  jle    L26
  lea    -0x1(%rax),%edx
  cmp    %esi,%edx
  jge    L13
L25:
  mov    $0xffffffff,%eax
L32:
  ret
  nopl   0x0(%rax)
L26:
  lea    0x1(%rax),%esi
  jmp    L8
```

assistant: ```c
int binsearch(int arr[], int l, int r, int x) {
  if (r >= l) {
    int mid = l + (r - l) / 2;
    if (arr[mid] == x)
      return mid;
    if (arr[mid] > x)
      return binsearch(arr, l, mid - 1, x);
    return binsearch(arr, mid + 1, r, x);
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__picotm_libc_get_current_dir_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
L30:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L23:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L28
  mov    -0x8(%rbp),%rax
  jmp    L35
L28:
  shlq   -0x20(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D28(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L30
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
char *__picotm_libc_get_current_dir_name() {
  size_t siz = PATH_MAX;
  char *buf = NULL;
  do {
    void *mem = malloc(siz);
    if (!mem) {
      free(buf);
    }
    buf = mem;
    char *cwd = getcwd(buf, siz);
    if (cwd) {
      return cwd;
    }
    siz *= 2;
  } while (errno == ERANGE);
  free(buf);
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<__picotm_libc_get_current_dir_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D17(%rip),%rax
  mov    (%rax),%r12
  mov    $0x0,%ebx
L32:
  mov    %rbx,%rbp
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L36
L35:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <getcwd@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L14
  add    %r12,%r12
  mov    D27(%rip),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L32
  mov    %rbx,%rdi
  call   <free@plt>
L14:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L35
```

assistant: ```c
char *__picotm_libc_get_current_dir_name() {
  size_t siz = PATH_MAX;
  char *buf = NULL;
  do {
    void *mem = malloc(siz);
    if (!mem) {
      free(buf);
    }
    buf = mem;
    char *cwd = getcwd(buf, siz);
    if (cwd) {
      return cwd;
    }
    siz *= 2;
  } while (errno == ERANGE);
  free(buf);
  return NULL;
}
```