ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_initgroups>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    %rsp,%rcx
  mov    (%rax),%esi
  lea    0x1(%rsi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L31
L36:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L36
L31:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L47
L5:
  lea    0x3(%rsp),%r12
  mov    %r12,%rax
  and    $0xfffffffffffffffc,%r12
  shr    $0x2,%rax
  lea    0x4(%r12),%rdx
  mov    %r8d,0x0(,%rax,4)
  call   <getGroups@plt>
  cmp    $0xffffffff,%eax
  je     L18
  lea    0x1(%rax),%edi
  mov    %r12,%rsi
  call   <setgroups@plt>
L18:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  mov    -0x8(%rbp),%r12
  leave
  ret
  cs nopw 0x0(%rax,%rax,1)
L47:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L5
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _initgroups(const char *user, gid_t group) {
  gid_t suppGroups[(NGROUPS_MAX + 1)];
  int nGroups;
  suppGroups[0] = group;
  if ((nGroups = getGroups(user, (NGROUPS_MAX + 1) - 1, &suppGroups[1])) == -1) {
    return -1;
  }
  return setgroups(nGroups + 1, suppGroups);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_initgroups>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    D3(%rip),%rax
  mov    %rsp,%rcx
  mov    (%rax),%esi
  lea    0x1(%rsi),%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L25
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L42
L25:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L4
L18:
  lea    0x3(%rsp),%r12
  mov    %r12,%rax
  and    $0xfffffffffffffffc,%r12
  shr    $0x2,%rax
  lea    0x4(%r12),%rdx
  mov    %r8d,0x0(,%rax,4)
  call   <getGroups@plt>
  cmp    $0xffffffff,%eax
  je     L56
  lea    0x1(%rax),%edi
  mov    %r12,%rsi
  call   <setgroups@plt>
L56:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  mov    -0x8(%rbp),%r12
  leave
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L18
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _initgroups(const char *user, gid_t group) {
  gid_t suppGroups[(NGROUPS_MAX + 1)];
  int nGroups;
  suppGroups[0] = group;
  if ((nGroups = getGroups(user, (NGROUPS_MAX + 1) - 1, &suppGroups[1])) == -1) {
    return -1;
  }
  return setgroups(nGroups + 1, suppGroups);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1c8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1c0(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x1b0(%rbp)
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x1a8(%rbp)
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  lea    -0x1a0(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1a8(%rbp),%rax
  mov    $0x63,%esi
  mov    %rax,%rdi
  call   <read_element@plt>
  mov    -0x1b8(%rbp),%rax
  movl   $0x11,(%rax)
  mov    -0x1b8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1b0(%rbp),%rax
  movl   $0x11,(%rax)
  mov    -0x1b0(%rbp),%rax
  mov    %rax,%rdi
  call   <free_anything@plt>
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_anything@plt>
  mov    -0x1c8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_anything@plt>
  mov    -0x1c0(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free_anything(never_free);
  free_anything(array2);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rsp,%r15
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %r15,%rdi
  call   <read_element@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free@plt>
  movl   $0x11,0x0(%rbp)
  mov    %rbp,%rdi
  call   <free_anything@plt>
  mov    %rbx,%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free_anything@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free_anything(never_free);
  free_anything(array2);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free_anything@plt>
  mov    %rbp,%rdi
  call   <free_anything@plt>
  mov    %r15,%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free_anything(never_free);
  free_anything(array2);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r15
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    $0x190,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbx,%rdi
  call   <read_element@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  mov    $0x63,%esi
  mov    %rbp,%rdi
  call   <read_element@plt>
  movl   $0x11,0x0(%r13)
  mov    %r13,%rdi
  call   <free@plt>
  movl   $0x11,(%r12)
  mov    %r12,%rdi
  call   <free_anything@plt>
  mov    %rbp,%rdi
  call   <free_anything@plt>
  mov    %r15,%rdi
  call   <free_anything@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1a8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int *never_allocated = malloc(sizeof(int));
  int *free_twice = malloc(sizeof(int));
  int *use_after_free = malloc(sizeof(int));
  int *never_free = malloc(sizeof(int));
  int array1[100];
  int *array2 = malloc(100 * sizeof(int));
  read_element(array1, 0);
  read_element(array1, 99);
  read_element(array2, 0);
  read_element(array2, 99);
  *use_after_free = 17;
  free(use_after_free);
  *never_free = 17;
  free_anything(never_free);
  free_anything(array2);
  free_anything(never_allocated);
  free(free_twice);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L16
L15:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const unsigned char *p;
  p = s;
  while (n-- > 0) {
    if (*p++ == c)
      return ((void *)(p - 1));
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memchr>:
  endbr64
  add    %rdi,%rdx
L11:
  cmp    %rdx,%rdi
  je     L21
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  cmp    %esi,%eax
  je     L8
  mov    %rcx,%rdi
  jmp    L11
L21:
  mov    $0x0,%eax
  ret
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const unsigned char *p;
  p = s;
  while (n-- > 0) {
    if (*p++ == c)
      return ((void *)(p - 1));
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memchr>:
  endbr64
  add    %rdi,%rdx
  jmp    L0
  nopl   0x0(%rax)
L11:
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  cmp    %esi,%eax
  je     L22
  mov    %rcx,%rdi
L0:
  cmp    %rdx,%rdi
  jne    L11
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const unsigned char *p;
  p = s;
  while (n-- > 0) {
    if (*p++ == c)
      return ((void *)(p - 1));
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memchr>:
  endbr64
  add    %rdi,%rdx
  jmp    L22
  nopl   0x0(%rax)
L14:
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  cmp    %esi,%eax
  je     L5
  mov    %rcx,%rdi
L22:
  cmp    %rdi,%rdx
  jne    L14
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memchr(const void *s, int c, size_t n) {
  const unsigned char *p;
  p = s;
  while (n-- > 0) {
    if (*p++ == c)
      return ((void *)(p - 1));
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<agregarPersona>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  cmpq   $0x0,-0x20(%rbp)
  je     L21
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L41:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  mov    $0x1,%eax
  jmp    L17
L4:
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x1869f,-0x4(%rbp)
  jle    L41
L21:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int agregarPersona(struct Persona **personas, struct Persona *nuevo) {
  int i;
  if (personas != NULL && nuevo != NULL) {
    for (i = 0; i < 100000; i++) {
      if (personas[i] == NULL) {
        personas[i] = nuevo;
        return 1;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<agregarPersona>:
  endbr64
  test   %rdi,%rdi
  je     L37
  test   %rsi,%rsi
  je     L37
  mov    %rdi,%rax
  add    $0xc3500,%rdi
L38:
  cmpq   $0x0,(%rax)
  je     L0
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L38
  mov    $0x0,%eax
  ret
L0:
  mov    %rsi,(%rax)
  mov    $0x1,%eax
  ret
L37:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int agregarPersona(struct Persona **personas, struct Persona *nuevo) {
  int i;
  if (personas != NULL && nuevo != NULL) {
    for (i = 0; i < 100000; i++) {
      if (personas[i] == NULL) {
        personas[i] = nuevo;
        return 1;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<agregarPersona>:
  endbr64
  test   %rdi,%rdi
  je     L22
  test   %rsi,%rsi
  je     L22
  lea    0xc3500(%rdi),%rax
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L22
L2:
  cmpq   $0x0,(%rdi)
  jne    L17
  mov    %rsi,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int agregarPersona(struct Persona **personas, struct Persona *nuevo) {
  int i;
  if (personas != NULL && nuevo != NULL) {
    for (i = 0; i < 100000; i++) {
      if (personas[i] == NULL) {
        personas[i] = nuevo;
        return 1;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<agregarPersona>:
  endbr64
  test   %rdi,%rdi
  je     L6
  test   %rsi,%rsi
  je     L6
  lea    0xc3500(%rdi),%rax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L6
L48:
  cmpq   $0x0,(%rdi)
  jne    L20
  mov    %rsi,(%rdi)
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int agregarPersona(struct Persona **personas, struct Persona *nuevo) {
  int i;
  if (personas != NULL && nuevo != NULL) {
    for (i = 0; i < 100000; i++) {
      if (personas[i] == NULL) {
        personas[i] = nuevo;
        return 1;
      }
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_lcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L72
  cmpq   $0x0,-0x28(%rbp)
  jne    L36
L72:
  mov    $0x0,%eax
  jmp    L49
L36:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jbe    L57
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  jmp    L49
L57:
  movq   $0x0,-0x18(%rbp)
  jmp    L29
L75:
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,%rdx
  jb     L75
L55:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L49:
  leave
  ret
```

assistant: ```c
size_t str_lcat(char *dst, const char *src, size_t size) {
  if (size == 0 || !dst) {
    return (0);
  } else {
    const size_t dst_len = strlen(dst);
    const size_t src_len = strlen(src);
    if (dst_len > size) {
      return (size + src_len);
    } else {
      size_t j = 0;
      for (; src[j] != '\0' && dst_len + j < size - 1; j++) {
        dst[dst_len + j] = src[j];
        j++;
      }
      dst[dst_len + j] = '\0';
      return (dst_len + src_len);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_lcat>:
  endbr64
  test   %rdx,%rdx
  je     L67
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  je     L49
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdx
  cmp    %r12,%rbx
  jb     L17
  movzbl 0x0(%rbp),%ecx
  test   %cl,%cl
  je     L46
  sub    $0x1,%rbx
  mov    $0x0,%edx
  lea    0x0(%r13,%r12,1),%rdi
  cmp    %rbx,%r12
  jae    L75
L11:
  mov    %cl,(%rdi,%rdx,1)
  add    $0x2,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  je     L75
  lea    (%r12,%rdx,1),%rsi
  cmp    %rbx,%rsi
  jb     L11
L75:
  add    %r12,%r13
  movb   $0x0,0x0(%r13,%rdx,1)
  lea    (%r12,%rax,1),%rdx
L17:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  mov    $0x0,%edx
  jmp    L75
L49:
  mov    $0x0,%edx
  jmp    L17
L67:
  mov    $0x0,%edx
  mov    %rdx,%rax
  ret
```

assistant: ```c
size_t str_lcat(char *dst, const char *src, size_t size) {
  if (size == 0 || !dst) {
    return (0);
  } else {
    const size_t dst_len = strlen(dst);
    const size_t src_len = strlen(src);
    if (dst_len > size) {
      return (size + src_len);
    } else {
      size_t j = 0;
      for (; src[j] != '\0' && dst_len + j < size - 1; j++) {
        dst[dst_len + j] = src[j];
        j++;
      }
      dst[dst_len + j] = '\0';
      return (dst_len + src_len);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_lcat>:
  endbr64
  test   %rdx,%rdx
  je     L5
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L34
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r8
  cmp    %r13,%rbx
  jb     L17
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L70
  mov    %r12,%rsi
  sub    $0x1,%rbx
  mov    %r13,%rcx
  sub    %r13,%rsi
  cmp    %rbx,%r13
  jb     L35
  jmp    L22
  nopl   0x0(%rax)
L49:
  cmp    %rbx,%rcx
  jae    L22
L35:
  mov    %dil,0x0(%rbp,%rcx,1)
  movzbl 0x2(%rsi,%rcx,1),%edi
  add    $0x2,%rcx
  test   %dil,%dil
  jne    L49
L22:
  movb   $0x0,0x0(%rbp,%rcx,1)
  lea    0x0(%r13,%rax,1),%r8
L17:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
L70:
  mov    %r13,%rcx
  jmp    L22
```

assistant: ```c
size_t str_lcat(char *dst, const char *src, size_t size) {
  if (size == 0 || !dst) {
    return (0);
  } else {
    const size_t dst_len = strlen(dst);
    const size_t src_len = strlen(src);
    if (dst_len > size) {
      return (size + src_len);
    } else {
      size_t j = 0;
      for (; src[j] != '\0' && dst_len + j < size - 1; j++) {
        dst[dst_len + j] = src[j];
        j++;
      }
      dst[dst_len + j] = '\0';
      return (dst_len + src_len);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_lcat>:
  endbr64
  test   %rdx,%rdx
  je     L59
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L35
  mov    %rsi,%r12
  mov    %rdx,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%r8
  cmp    %r13,%rbx
  jb     L50
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L53
  mov    %r12,%rsi
  sub    $0x1,%rbx
  mov    %r13,%rcx
  sub    %r13,%rsi
  cmp    %rbx,%r13
  jb     L13
  jmp    L73
  nopl   0x0(%rax)
L77:
  cmp    %rbx,%rcx
  jae    L73
L13:
  mov    %dil,0x0(%rbp,%rcx,1)
  movzbl 0x2(%rsi,%rcx,1),%edi
  add    $0x2,%rcx
  test   %dil,%dil
  jne    L77
L73:
  movb   $0x0,0x0(%rbp,%rcx,1)
  lea    0x0(%r13,%rax,1),%r8
L50:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L59:
  xor    %eax,%eax
  ret
L53:
  mov    %r13,%rcx
  jmp    L73
```

assistant: ```c
size_t str_lcat(char *dst, const char *src, size_t size) {
  if (size == 0 || !dst) {
    return (0);
  } else {
    const size_t dst_len = strlen(dst);
    const size_t src_len = strlen(src);
    if (dst_len > size) {
      return (size + src_len);
    } else {
      size_t j = 0;
      for (; src[j] != '\0' && dst_len + j < size - 1; j++) {
        dst[dst_len + j] = src[j];
        j++;
      }
      dst[dst_len + j] = '\0';
      return (dst_len + src_len);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jp     L16
  pxor   %xmm0,%xmm0
  ucomisd -0x10(%rbp),%xmm0
  jne    L16
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <bounce@plt>
L16:
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: division by zero

assistant: ```c
double divide(double dividend, double divisor) {
  if (divisor == 0.0)
    bounce("division by zero");
  return (dividend / divisor);
}
```