ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: >>> free 0x%8.8X


assistant: ```c
void my_free(void *p) {
  printf(">>> free 0x%8.8X\n", p);
  free(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  jne    L27
  lea    0x8(%rsi),%rbx
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r13
  lea    D3(%rip),%r12
L33:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  add    $0x8,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L33
  movzbl 0x6(%rsp),%ebp
  movzbl 0x4(%rsp),%ebx
  shl    $0x8,%ebx
  and    $0x7f00,%ebx
  movzbl 0x5(%rsp),%eax
  or     %eax,%ebx
  mov    %ebp,%eax
  shr    $0x5,%al
  shl    $0xf,%eax
  and    $0x18000,%eax
  or     %eax,%ebx
  movzbl 0x7(%rsp),%r12d
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%r9d
  shr    $0x4,%r9b
  mov    %r12d,%r8d
  shr    $0x5,%r8b
  mov    %r12d,%ecx
  shr    $0x6,%cl
  movzbl %cl,%ecx
  mov    %ebp,%edx
  shr    $0x4,%dl
  and    $0x1,%edx
  mov    %ebp,%esi
  and    $0xf,%esi
  sub    $0x8,%rsp
  and    $0xf,%r12d
  push   %r12
  and    $0x1,%r9d
  and    $0x1,%r8d
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  imul   $0xf424,%ebx,%esi
  sub    $0x2273948,%esi
  mov    %esi,%edx
  imul   $0x10624dd3,%rdx,%rcx
  shr    $0x26,%rcx
  mov    %ecx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ecx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x32,%rdx
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L22
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D38
data_type: string
name: unpack_data
arguments: label: D40
data_type: string
name: unpack_data
arguments: label: D16
data_type: string

tool: D3: %hhx

tool: D18: div: %d


tool: D38: r=%d pe=%d c=%d re=%d rts=%d p=%d


tool: D40: freq: %d Hz (%d.%03dMHz)


tool: D16: usage: showfreq xx xx xx xx

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buffer[4];
  unsigned int i, div, r, pe, c, re, rts, p;
  if (argc != 5) {
    printf("usage: showfreq xx xx xx xx\n");
    return 0;
  }
  for (i = 0; i < 4; i++)
    sscanf(argv[i + 1], "%hhx", buffer + i);
  div = buffer[1] | ((buffer[0] & 0x7F) << 8) | (((buffer[2] >> 5) & 3) << 15);
  r = buffer[2] & 15;
  pe = (buffer[2] >> 4) & 1;
  c = buffer[3] >> 6;
  re = !!(buffer[3] & 32);
  rts = !!(buffer[3] & 16);
  p = buffer[3] & 15;
  printf("div: %d\n", div);
  printf("r=%d pe=%d c=%d re=%d rts=%d p=%d\n", r, pe, c, re, rts, p);
  div *= 62500;
  div -= 36125000;
  div /= 1;
  printf("freq: %d Hz (%d.%03dMHz)\n", div, div / (1000 * 1000), (div / 1000) % 1000);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  jne    L28
  lea    0x8(%rsi),%rbx
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r13
  lea    D25(%rip),%r12
L29:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  add    $0x1,%rbp
  add    $0x8,%rbx
  call   <sscanf@plt>
  cmp    %r13,%rbp
  jne    L29
  movzbl 0x4(%rsp),%ebx
  movzbl 0x6(%rsp),%r12d
  lea    D5(%rip),%rdi
  movzbl 0x5(%rsp),%eax
  movzbl 0x7(%rsp),%ebp
  shl    $0x8,%ebx
  and    $0x7f00,%ebx
  or     %eax,%ebx
  mov    %r12d,%eax
  shr    $0x5,%al
  shl    $0xf,%eax
  and    $0x18000,%eax
  or     %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  sub    $0x8,%rsp
  mov    %ebp,%r9d
  mov    %ebp,%r8d
  mov    %ebp,%ecx
  and    $0xf,%ebp
  mov    %r12d,%edx
  shr    $0x4,%r9b
  push   %rbp
  shr    $0x5,%r8b
  shr    $0x6,%cl
  mov    %r12d,%esi
  shr    $0x4,%dl
  movzbl %cl,%ecx
  and    $0xf,%esi
  and    $0x1,%r9d
  and    $0x1,%edx
  and    $0x1,%r8d
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xf424,%ebx,%esi
  lea    D31(%rip),%rdi
  lea    -0x2273948(%rsi),%edx
  imul   $0x10624dd3,%rdx,%rcx
  mov    %rdx,%rsi
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x26,%rcx
  mov    %ecx,%eax
  shr    $0x32,%rdx
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rax
  pop    %rdx
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L38
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D43
datatype: string
name: retrieve_data
arguments: data_tag: D31
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D25: %hhx

tool: D5: div: %d


tool: D43: r=%d pe=%d c=%d re=%d rts=%d p=%d


tool: D31: freq: %d Hz (%d.%03dMHz)


tool: D19: usage: showfreq xx xx xx xx

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buffer[4];
  unsigned int i, div, r, pe, c, re, rts, p;
  if (argc != 5) {
    printf("usage: showfreq xx xx xx xx\n");
    return 0;
  }
  for (i = 0; i < 4; i++)
    sscanf(argv[i + 1], "%hhx", buffer + i);
  div = buffer[1] | ((buffer[0] & 0x7F) << 8) | (((buffer[2] >> 5) & 3) << 15);
  r = buffer[2] & 15;
  pe = (buffer[2] >> 4) & 1;
  c = buffer[3] >> 6;
  re = !!(buffer[3] & 32);
  rts = !!(buffer[3] & 16);
  p = buffer[3] & 15;
  printf("div: %d\n", div);
  printf("r=%d pe=%d c=%d re=%d rts=%d p=%d\n", r, pe, c, re, rts, p);
  div *= 62500;
  div -= 36125000;
  div /= 1;
  printf("freq: %d Hz (%d.%03dMHz)\n", div, div / (1000 * 1000), (div / 1000) % 1000);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x5,%edi
  jne    L34
  lea    0x8(%rsi),%rbx
  lea    0x4(%rsp),%rbp
  lea    0x8(%rsp),%r13
  lea    D39(%rip),%r12
L39:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  add    $0x1,%rbp
  add    $0x8,%rbx
  call   <sscanf@plt>
  cmp    %r13,%rbp
  jne    L39
  movzbl 0x4(%rsp),%ebx
  movzbl 0x6(%rsp),%r12d
  lea    D8(%rip),%rdi
  movzbl 0x5(%rsp),%eax
  movzbl 0x7(%rsp),%ebp
  shl    $0x8,%ebx
  and    $0x7f00,%ebx
  or     %eax,%ebx
  mov    %r12d,%eax
  shr    $0x5,%al
  shl    $0xf,%eax
  and    $0x18000,%eax
  or     %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  sub    $0x8,%rsp
  mov    %ebp,%r9d
  mov    %ebp,%r8d
  mov    %ebp,%ecx
  and    $0xf,%ebp
  mov    %r12d,%edx
  shr    $0x4,%r9b
  push   %rbp
  shr    $0x5,%r8b
  shr    $0x6,%cl
  mov    %r12d,%esi
  shr    $0x4,%dl
  movzbl %cl,%ecx
  and    $0xf,%esi
  and    $0x1,%r9d
  and    $0x1,%edx
  and    $0x1,%r8d
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  imul   $0xf424,%ebx,%esi
  lea    D17(%rip),%rdi
  lea    -0x2273948(%rsi),%edx
  imul   $0x10624dd3,%rdx,%rcx
  mov    %rdx,%rsi
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x26,%rcx
  mov    %ecx,%eax
  shr    $0x32,%rdx
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%eax
  sub    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rax
  pop    %rdx
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D39
data_type: string
name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D20
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D49
data_type: string

tool: D39: %hhx

tool: D8: div: %d


tool: D20: r=%d pe=%d c=%d re=%d rts=%d p=%d


tool: D17: freq: %d Hz (%d.%03dMHz)


tool: D49: usage: showfreq xx xx xx xx

assistant: ```c
int main(int argc, char **argv) {
  unsigned char buffer[4];
  unsigned int i, div, r, pe, c, re, rts, p;
  if (argc != 5) {
    printf("usage: showfreq xx xx xx xx\n");
    return 0;
  }
  for (i = 0; i < 4; i++)
    sscanf(argv[i + 1], "%hhx", buffer + i);
  div = buffer[1] | ((buffer[0] & 0x7F) << 8) | (((buffer[2] >> 5) & 3) << 15);
  r = buffer[2] & 15;
  pe = (buffer[2] >> 4) & 1;
  c = buffer[3] >> 6;
  re = !!(buffer[3] & 32);
  rts = !!(buffer[3] & 16);
  p = buffer[3] & 15;
  printf("div: %d\n", div);
  printf("r=%d pe=%d c=%d re=%d rts=%d p=%d\n", r, pe, c, re, rts, p);
  div *= 62500;
  div -= 36125000;
  div /= 1;
  printf("freq: %d Hz (%d.%03dMHz)\n", div, div / (1000 * 1000), (div / 1000) % 1000);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  test   %al,%al
  js     L17
  mov    -0x8(%rbp),%rax
  test   %al,%al
  jne    L6
L17:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L29
L6:
  mov    $0x0,%edi
  call   <exit@plt>
  nop
L29:
  nop
  leave
  ret
```

assistant: ```c
void f(long i) {
  if ((signed char)i < 0 || (signed char)i == 0)
    abort();
  else
    exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  test   %dil,%dil
  jle    L5
  mov    $0x0,%edi
  call   <exit@plt>
L13:
  add    $0x8,%rsp
  ret
L5:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L13
```

assistant: ```c
void f(long i) {
  if ((signed char)i < 0 || (signed char)i == 0)
    abort();
  else
    exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  test   %dil,%dil
  jle    L5
  xor    %edi,%edi
  jmp    1070 <exit@plt>
L5:
  xor    %eax,%eax
  jmp    1060 <abort@plt>
```

assistant: ```c
void f(long i) {
  if ((signed char)i < 0 || (signed char)i == 0)
    abort();
  else
    exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  test   %dil,%dil
  jle    L2
  xor    %edi,%edi
  jmp    1070 <exit@plt>
L2:
  xor    %eax,%eax
  jmp    1060 <abort@plt>
```

assistant: ```c
void f(long i) {
  if ((signed char)i < 0 || (signed char)i == 0)
    abort();
  else
    exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<saturate_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_rx_sat@plt>
  leave
  ret
```

assistant: ```c
int saturate_add(int arg1, int arg2) {
  arg1 += arg2;
  return __builtin_rx_sat(arg1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<saturate_add>:
  endbr64
  sub    $0x8,%rsp
  add    %esi,%edi
  call   <__builtin_rx_sat@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int saturate_add(int arg1, int arg2) {
  arg1 += arg2;
  return __builtin_rx_sat(arg1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<saturate_add>:
  endbr64
  add    %esi,%edi
  jmp    1050 <__builtin_rx_sat@plt>
```

assistant: ```c
int saturate_add(int arg1, int arg2) {
  arg1 += arg2;
  return __builtin_rx_sat(arg1);
}
```
user: What is the c source code of the assembly code below?

```asm
<saturate_add>:
  endbr64
  add    %esi,%edi
  jmp    1050 <__builtin_rx_sat@plt>
```

assistant: ```c
int saturate_add(int arg1, int arg2) {
  arg1 += arg2;
  return __builtin_rx_sat(arg1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_99_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_99_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_99_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  not    %eax
  or     $0xff,%al
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_99_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xrop3_99_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %esi,%eax
  or     %edi,%edx
  not    %eax
  or     $0xff,%al
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_99_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_99_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  mov    %edi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %esi,%eax
  or     %edi,%edx
  not    %eax
  or     $0xff,%al
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_99_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %#08x %8zu %-80s


assistant: ```c
int list(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  printf("%#08x %8zu %-80s\n", typeflag, sb->st_size, fpath);
  (void)ftwbuf;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<list>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  mov    %edx,%esi
  mov    (%rax),%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: %#08x %8zu %-80s


assistant: ```c
int list(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  printf("%#08x %8zu %-80s\n", typeflag, sb->st_size, fpath);
  (void)ftwbuf;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<list>:
  endbr64
  mov    %rsi,%r8
  sub    $0x8,%rsp
  mov    %edx,%esi
  mov    %rdi,%rcx
  mov    (%r8),%edx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %#08x %8zu %-80s


assistant: ```c
int list(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  printf("%#08x %8zu %-80s\n", typeflag, sb->st_size, fpath);
  (void)ftwbuf;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list>:
  endbr64
  mov    %rsi,%r8
  sub    $0x8,%rsp
  mov    %edx,%esi
  mov    %rdi,%rcx
  mov    (%r8),%edx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: %#08x %8zu %-80s


assistant: ```c
int list(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  printf("%#08x %8zu %-80s\n", typeflag, sb->st_size, fpath);
  (void)ftwbuf;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L59:
  addl   $0x1,-0x8(%rbp)
L21:
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  jmp    L28
L31:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L28:
  cmpq   $0x0,-0x20(%rbp)
  je     L22
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L31
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strcat(char *__restrict s1, const char *__restrict s2) {
  int count1;
  int count2;
  count1 = 0;
  count2 = 0;
  while (s1 && s1[count1])
    count1++;
  while (s2 && s2[count2] != 0x0a)
    s1[count1++] = s2[count2++];
  s1[count1] = 0x0a;
  return (s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strcat>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L23
L33:
  mov    %edx,%r8d
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L33
L36:
  test   %rsi,%rsi
  je     L30
  movslq %r8d,%r8
  mov    %r8,%rdx
  sub    %r8,%rsi
  jmp    L21
L23:
  mov    $0x0,%r8d
  jmp    L36
L16:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
L21:
  mov    %edx,%r8d
  movzbl (%rsi,%rdx,1),%ecx
  cmp    $0xa,%cl
  jne    L16
L30:
  movslq %r8d,%r8
  movb   $0xa,(%rax,%r8,1)
  ret
```

assistant: ```c
char *ft_strcat(char *__restrict s1, const char *__restrict s2) {
  int count1;
  int count2;
  count1 = 0;
  count2 = 0;
  while (s1 && s1[count1])
    count1++;
  while (s2 && s2[count2] != 0x0a)
    s1[count1++] = s2[count2++];
  s1[count1] = 0x0a;
  return (s1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strcat>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L58
  mov    %rdi,%rcx
  xor    %edx,%edx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%edx
L20:
  mov    %rcx,%r8
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L14
L61:
  test   %rsi,%rsi
  je     L23
  movslq %edx,%rdx
  add    %rax,%rdx
  jmp    L5
  nopl   (%rax)
L30:
  mov    %cl,(%rdx)
  add    $0x1,%rdx
L5:
  movzbl (%rsi),%ecx
  mov    %rdx,%r8
  add    $0x1,%rsi
  cmp    $0xa,%cl
  jne    L30
L23:
  movb   $0xa,(%r8)
  ret
L58:
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L61
```

assistant: ```c
char *ft_strcat(char *__restrict s1, const char *__restrict s2) {
  int count1;
  int count2;
  count1 = 0;
  count2 = 0;
  while (s1 && s1[count1])
    count1++;
  while (s2 && s2[count2] != 0x0a)
    s1[count1++] = s2[count2++];
  s1[count1] = 0x0a;
  return (s1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strcat>:
  endbr64
  mov    %rdi,%rax
  test   %rdi,%rdi
  je     L19
  cmpb   $0x0,(%rdi)
  je     L68
  lea    0x1(%rdi),%rdx
  neg    %edi
  nopw   0x0(%rax,%rax,1)
L11:
  lea    (%rdi,%rdx,1),%r8d
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L11
L6:
  test   %rsi,%rsi
  je     L37
  movzbl (%rsi),%edx
  movslq %r8d,%r8
  lea    (%rax,%r8,1),%rcx
  cmp    $0xa,%dl
  je     L37
  lea    0x1(%rax,%r8,1),%r8
  add    $0x1,%rsi
  sub    %rcx,%r8
  nopl   0x0(%rax)
L77:
  mov    %dl,(%rcx)
  movzbl (%rsi),%edx
  add    %r8,%rcx
  add    $0x1,%rsi
  cmp    $0xa,%dl
  jne    L77
L37:
  movb   $0xa,(%rcx)
  ret
L19:
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  jmp    L6
L68:
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  jmp    L6
```

assistant: ```c
char *ft_strcat(char *__restrict s1, const char *__restrict s2) {
  int count1;
  int count2;
  count1 = 0;
  count2 = 0;
  while (s1 && s1[count1])
    count1++;
  while (s2 && s2[count2] != 0x0a)
    s1[count1++] = s2[count2++];
  s1[count1] = 0x0a;
  return (s1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<internal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <prerror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D9: Internal programming error: %s


assistant: ```c
void internal_error(const char *message) {
  prerror("Internal programming error: %s\n", message);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<internal_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <prerror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type: string

tool: D8: Internal programming error: %s


assistant: ```c
void internal_error(const char *message) {
  prerror("Internal programming error: %s\n", message);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<internal_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <prerror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D3: Internal programming error: %s


assistant: ```c
void internal_error(const char *message) {
  prerror("Internal programming error: %s\n", message);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<internal_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <prerror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: Internal programming error: %s


assistant: ```c
void internal_error(const char *message) {
  prerror("Internal programming error: %s\n", message);
  exit(1);
}
```