ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ece391_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L5:
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ece391_strcpy(uint8_t *dst, const uint8_t *src) {
  while ('\0' != (*dst++ = *src++))
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ece391_strcpy>:
  endbr64
  mov    $0x0,%eax
L8:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  test   %edx,%edx
  jne    L8
  ret
```

assistant: ```c
void ece391_strcpy(uint8_t *dst, const uint8_t *src) {
  while ('\0' != (*dst++ = *src++))
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ece391_strcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  test   %edx,%edx
  jne    L6
  ret
```

assistant: ```c
void ece391_strcpy(uint8_t *dst, const uint8_t *src) {
  while ('\0' != (*dst++ = *src++))
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ece391_strcpy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,1)
  add    $0x4,%rax
  test   %edx,%edx
  jne    L5
  ret
```

assistant: ```c
void ece391_strcpy(uint8_t *dst, const uint8_t *src) {
  while ('\0' != (*dst++ = *src++))
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<computeSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double computeSum(double data[], int length) {
  double sum = 0.0;
  int i;
  for (i = 0; i < length; i++) {
    sum = sum + data[i];
  }
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<computeSum>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L5:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L5
  ret
L7:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double computeSum(double data[], int length) {
  double sum = 0.0;
  int i;
  for (i = 0; i < length; i++) {
    sum = sum + data[i];
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<computeSum>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L13:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double computeSum(double data[], int length) {
  double sum = 0.0;
  int i;
  for (i = 0; i < length; i++) {
    sum = sum + data[i];
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<computeSum>:
  endbr64
  test   %esi,%esi
  jle    L49
  cmp    $0x1,%esi
  je     L22
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L37:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L37
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L24
L5:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax)
L24:
  ret
  nopl   0x0(%rax)
L49:
  pxor   %xmm0,%xmm0
  ret
L22:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L5
```

assistant: ```c
double computeSum(double data[], int length) {
  double sum = 0.0;
  int i;
  for (i = 0; i < length; i++) {
    sum = sum + data[i];
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L0
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void str_tolower(char *s) {
  while (*s != '\0') {
    *s = tolower(*s);
    s++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L17:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L18:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *s) {
  while (*s != '\0') {
    *s = tolower(*s);
    s++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L1:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
L18:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *s) {
  while (*s != '\0') {
    *s = tolower(*s);
    s++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L11
L0:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L11:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *s) {
  while (*s != '\0') {
    *s = tolower(*s);
    s++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eatSlashSlashInPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movb   $0x0,-0x12(%rbp)
  jmp    L40
L31:
  cmpb   $0x2f,-0x11(%rbp)
  jne    L17
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jne    L17
  jmp    L40
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  movzbl -0x11(%rbp),%eax
  mov    %al,-0x12(%rbp)
L40:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L31
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void eatSlashSlashInPath(char *path) {
  char *s, *d;
  s = d = path;
  char c, lastC = 0;
  while ((c = *s++) != 0) {
    if (c == '/' && lastC == c)
      continue;
    *d++ = c;
    lastC = c;
  }
  *d = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<eatSlashSlashInPath>:
  endbr64
  lea    0x1(%rdi),%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  mov    $0x0,%esi
  jmp    L1
L11:
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rdi
L17:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  mov    %eax,%esi
  test   %cl,%cl
  je     L57
  mov    %ecx,%eax
L1:
  cmp    $0x2f,%al
  jne    L11
  cmp    %al,%sil
  jne    L11
  jmp    L17
L57:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void eatSlashSlashInPath(char *path) {
  char *s, *d;
  s = d = path;
  char c, lastC = 0;
  while ((c = *s++) != 0) {
    if (c == '/' && lastC == c)
      continue;
    *d++ = c;
    lastC = c;
  }
  *d = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eatSlashSlashInPath>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L20
  xor    %esi,%esi
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ecx,%eax
L39:
  cmp    $0x2f,%al
  jne    L14
  cmp    %al,%sil
  je     L44
L14:
  mov    %al,(%rdi)
  add    $0x1,%rdi
L44:
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  mov    %eax,%esi
  test   %cl,%cl
  jne    L27
L20:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void eatSlashSlashInPath(char *path) {
  char *s, *d;
  s = d = path;
  char c, lastC = 0;
  while ((c = *s++) != 0) {
    if (c == '/' && lastC == c)
      continue;
    *d++ = c;
    lastC = c;
  }
  *d = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eatSlashSlashInPath>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  test   %al,%al
  je     L19
  xor    %esi,%esi
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L56:
  cmp    %al,%sil
  jne    L33
  movzbl (%rdx),%ecx
  add    $0x1,%rdx
  test   %cl,%cl
  je     L19
L36:
  mov    %eax,%esi
  mov    %ecx,%eax
L62:
  cmp    $0x2f,%al
  je     L56
L33:
  add    $0x1,%rdx
  mov    %al,(%rdi)
  lea    0x1(%rdi),%rsi
  movzbl -0x1(%rdx),%ecx
  test   %cl,%cl
  je     L11
  mov    %rsi,%rdi
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%rsi
L11:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void eatSlashSlashInPath(char *path) {
  char *s, *d;
  s = d = path;
  char c, lastC = 0;
  while ((c = *s++) != 0) {
    if (c == '/' && lastC == c)
      continue;
    *d++ = c;
    lastC = c;
  }
  *d = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<IDCT1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x5,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L13:
  cmpl   $0x3f,-0x8(%rbp)
  jle    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void IDCT1(int *block) {
  int val = (((block[0]) >> (2 + 3)));
  int i;
  for (i = 0; i < 64; i++)
    block[i] = val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<IDCT1>:
  endbr64
  mov    (%rdi),%ecx
  sar    $0x5,%ecx
  mov    %rdi,%rax
  lea    0x100(%rdi),%rdx
L3:
  mov    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
  ret
```

assistant: ```c
void IDCT1(int *block) {
  int val = (((block[0]) >> (2 + 3)));
  int i;
  for (i = 0; i < 64; i++)
    block[i] = val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<IDCT1>:
  endbr64
  mov    (%rdi),%eax
  lea    0x100(%rdi),%rdx
  sar    $0x5,%eax
L6:
  mov    %eax,(%rdi)
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L6
  ret
```

assistant: ```c
void IDCT1(int *block) {
  int val = (((block[0]) >> (2 + 3)));
  int i;
  for (i = 0; i < 64; i++)
    block[i] = val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IDCT1>:
  endbr64
  mov    (%rdi),%eax
  sar    $0x5,%eax
  movd   %eax,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  movups %xmm0,(%rdi)
  movups %xmm0,0x10(%rdi)
  movups %xmm0,0x20(%rdi)
  movups %xmm0,0x30(%rdi)
  movups %xmm0,0x40(%rdi)
  movups %xmm0,0x50(%rdi)
  movups %xmm0,0x60(%rdi)
  movups %xmm0,0x70(%rdi)
  movups %xmm0,0x80(%rdi)
  movups %xmm0,0x90(%rdi)
  movups %xmm0,0xa0(%rdi)
  movups %xmm0,0xb0(%rdi)
  movups %xmm0,0xc0(%rdi)
  movups %xmm0,0xd0(%rdi)
  movups %xmm0,0xe0(%rdi)
  movups %xmm0,0xf0(%rdi)
  ret
```

assistant: ```c
void IDCT1(int *block) {
  int val = (((block[0]) >> (2 + 3)));
  int i;
  for (i = 0; i < 64; i++)
    block[i] = val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L18
L1:
  mov    $0x0,%eax
L18:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fannkuch@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Pfannkuchen(%d) = %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = (argc > 1) ? atoi(argv[1]) : 0;
  printf("Pfannkuchen(%d) = %ld\n", n, fannkuch(n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  cmp    $0x1,%edi
  jg     L12
L11:
  mov    %ebx,%edi
  call   <fannkuch@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string

tool: D8: Pfannkuchen(%d) = %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = (argc > 1) ? atoi(argv[1]) : 0;
  printf("Pfannkuchen(%d) = %ld\n", n, fannkuch(n));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  cmp    $0x1,%edi
  jle    L2
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L2:
  mov    %ebp,%edi
  call   <fannkuch@plt>
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Pfannkuchen(%d) = %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = (argc > 1) ? atoi(argv[1]) : 0;
  printf("Pfannkuchen(%d) = %ld\n", n, fannkuch(n));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  cmp    $0x1,%edi
  jle    L1
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
L1:
  mov    %ebp,%edi
  call   <fannkuch@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: Pfannkuchen(%d) = %ld


assistant: ```c
int main(int argc, char *argv[]) {
  int n = (argc > 1) ? atoi(argv[1]) : 0;
  printf("Pfannkuchen(%d) = %ld\n", n, fannkuch(n));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<byte_col_sjis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3f,-0x4(%rbp)
  jle    L14
  cmpl   $0x7e,-0x4(%rbp)
  jg     L14
  mov    -0x4(%rbp),%eax
  sub    $0x40,%eax
  jmp    L45
L14:
  cmpl   $0x7f,-0x4(%rbp)
  jle    L24
  cmpl   $0xfc,-0x4(%rbp)
  jg     L24
  mov    -0x4(%rbp),%eax
  sub    $0x41,%eax
  jmp    L45
L24:
  mov    $0xffffffff,%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int byte_col_sjis(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0x80 && byte < 0xfd)
    return byte - 0x41;
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_col_sjis>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L16
  lea    -0x80(%rdi),%eax
  cmp    $0x7c,%eax
  ja     L1
  lea    -0x41(%rdi),%eax
  ret
L1:
  mov    $0xffffffff,%eax
L16:
  ret
```

assistant: ```c
int byte_col_sjis(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0x80 && byte < 0xfd)
    return byte - 0x41;
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<byte_col_sjis>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L8
  lea    -0x80(%rdi),%eax
  cmp    $0x7c,%eax
  ja     L13
  lea    -0x41(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xffffffff,%eax
L8:
  ret
```

assistant: ```c
int byte_col_sjis(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0x80 && byte < 0xfd)
    return byte - 0x41;
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<byte_col_sjis>:
  endbr64
  lea    -0x40(%rdi),%eax
  cmp    $0x3e,%eax
  jbe    L16
  lea    -0x80(%rdi),%eax
  cmp    $0x7c,%eax
  ja     L6
  lea    -0x41(%rdi),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%eax
L16:
  ret
```

assistant: ```c
int byte_col_sjis(int byte) {
  if (byte >= 0x40 && byte < 0x7f)
    return byte - 0x40;
  else if (byte >= 0x80 && byte < 0xfd)
    return byte - 0x41;
  else
    return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getBitAt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getBitAt(unsigned int bitmap, unsigned int i) {
  int result = (bitmap >> i) & 1;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getBitAt>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int getBitAt(unsigned int bitmap, unsigned int i) {
  int result = (bitmap >> i) & 1;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getBitAt>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int getBitAt(unsigned int bitmap, unsigned int i) {
  int result = (bitmap >> i) & 1;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getBitAt>:
  endbr64
  mov    %esi,%ecx
  shr    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int getBitAt(unsigned int bitmap, unsigned int i) {
  int result = (bitmap >> i) & 1;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <lstat@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = lstat("/tmp/foo", &buf);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <lstat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = lstat("/tmp/foo", &buf);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = lstat("/tmp/foo", &buf);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: /tmp/foo

assistant: ```c
int main(void) {
  struct stat buf;
  int status;
  status = lstat("/tmp/foo", &buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<workEntry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
L7:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_lock@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_mutex_unlock@plt>
  cmpl   $0x0,-0x14(%rbp)
  jle    L20
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <print_prime_factors@plt>
  jmp    L7
L20:
  nop
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string

tool: D0: r

tool: D1: nombre premier.txt

tool: D11: %ju

assistant: ```c
void workEntry(pthread_mutex_t *mutex) {
  FILE *fichier = fopen("nombre premier.txt", "r");
  uint64_t lecture = 0;
  int fin;
  while (1) {
    pthread_mutex_lock(mutex);
    fin = fscanf(fichier, "%ju", &lecture);
    pthread_mutex_unlock(mutex);
    if (fin <= 0) {
      break;
    }
    print_prime_factors(lecture);
  }
  fclose(fichier);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<workEntry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  movl   $0x0,0x4(%rsp)
  lea    D29(%rip),%r13
  jmp    L4
L18:
  mov    0x4(%rsp),%edi
  call   <print_prime_factors@plt>
L4:
  mov    %rbp,%rdi
  call   <pthread_mutex_lock@plt>
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fscanf@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <pthread_mutex_unlock@plt>
  test   %ebx,%ebx
  jg     L18
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D29
type_infered: string

tool: D14: r

tool: D27: nombre premier.txt

tool: D29: %ju

assistant: ```c
void workEntry(pthread_mutex_t *mutex) {
  FILE *fichier = fopen("nombre premier.txt", "r");
  uint64_t lecture = 0;
  int fin;
  while (1) {
    pthread_mutex_lock(mutex);
    fin = fscanf(fichier, "%ju", &lecture);
    pthread_mutex_unlock(mutex);
    if (fin <= 0) {
      break;
    }
    print_prime_factors(lecture);
  }
  fclose(fichier);
}
```