ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<stamp_type_to_radar>:
  endbr64
  cmp    $0x80,%edi
  je     L56
  ja     L13
  mov    $0xffffffc5,%eax
  cmp    $0x60,%edi
  je     L8
  cmp    $0x70,%edi
  jne    L36
  mov    $0xffffffc6,%eax
  ret
L36:
  ret
L13:
  mov    $0xffffffc6,%eax
  cmp    $0x90,%edi
  je     L8
  cmp    $0x101,%edi
  jne    L42
  mov    $0xffffffff,%eax
L8:
  ret
L42:
  ret
L56:
  mov    $0xffffffc7,%eax
  ret
```

assistant: ```c
unsigned char stamp_type_to_radar(unsigned int t) {
  switch (t) {
  case 96:
    return 0xC5;
  case 112:
  case 144:
    return 0xC6;
  case 128:
    return 0xC7;
  case 257:
    return 0xff;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stamp_type_to_radar>:
  endbr64
  cmp    $0x80,%edi
  je     L32
  ja     L58
  mov    $0xffffffc5,%eax
  cmp    $0x60,%edi
  je     L19
  cmp    $0x70,%edi
  jne    L37
  mov    $0xffffffc6,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    $0xffffffc6,%eax
  cmp    $0x90,%edi
  je     L19
  cmp    $0x101,%edi
  jne    L31
  mov    $0xffffffff,%eax
L19:
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xffffffc7,%eax
  ret
L31:
  ret
L37:
  ret
```

assistant: ```c
unsigned char stamp_type_to_radar(unsigned int t) {
  switch (t) {
  case 96:
    return 0xC5;
  case 112:
  case 144:
    return 0xC6;
  case 128:
    return 0xC7;
  case 257:
    return 0xff;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stamp_type_to_radar>:
  endbr64
  cmp    $0x80,%edi
  je     L25
  ja     L22
  mov    $0xffffffc5,%eax
  cmp    $0x60,%edi
  je     L28
  cmp    $0x70,%edi
  jne    L11
  mov    $0xffffffc6,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0xffffffc6,%eax
  cmp    $0x90,%edi
  je     L28
  cmp    $0x101,%edi
  jne    L46
  mov    $0xffffffff,%eax
L28:
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0xffffffc7,%eax
  ret
L46:
  ret
L11:
  ret
```

assistant: ```c
unsigned char stamp_type_to_radar(unsigned int t) {
  switch (t) {
  case 96:
    return 0xC5;
  case 112:
  case 144:
    return 0xC6;
  case 128:
    return 0xC7;
  case 257:
    return 0xff;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <begin_game@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <count_onece_bits@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D13
type: string

tool: D7: %u%*c

tool: D13: %u -> %d

assistant: ```c
int main() {
  uint32_t inputNumber;
  scanf("%u%*c", &inputNumber);
  uint32_t resultNumber;
  resultNumber = begin_game(inputNumber);
  int onceCount = count_onece_bits(resultNumber);
  printf("%u -> %d", resultNumber, onceCount);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <begin_game@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <count_onece_bits@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D3
data_type: string

tool: D2: %u%*c

tool: D3: %u -> %d

assistant: ```c
int main() {
  uint32_t inputNumber;
  scanf("%u%*c", &inputNumber);
  uint32_t resultNumber;
  resultNumber = begin_game(inputNumber);
  int onceCount = count_onece_bits(resultNumber);
  printf("%u -> %d", resultNumber, onceCount);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <begin_game@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <count_onece_bits@plt>
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D19: %u%*c

tool: D17: %u -> %d

assistant: ```c
int main() {
  uint32_t inputNumber;
  scanf("%u%*c", &inputNumber);
  uint32_t resultNumber;
  resultNumber = begin_game(inputNumber);
  int onceCount = count_onece_bits(resultNumber);
  printf("%u -> %d", resultNumber, onceCount);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <begin_game@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <count_onece_bits@plt>
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D0: %u%*c

tool: D15: %u -> %d

assistant: ```c
int main() {
  uint32_t inputNumber;
  scanf("%u%*c", &inputNumber);
  uint32_t resultNumber;
  resultNumber = begin_game(inputNumber);
  int onceCount = count_onece_bits(resultNumber);
  printf("%u -> %d", resultNumber, onceCount);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  movabs $0xfffffffe2329b000,%r11
  lea    (%rsp,%r11,1),%r11
L34:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L34
  sub    $0x38,%rsp
  movabs $0xfffffffe2329afdc,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    %edi,(%rax)
  movabs $0xfffffffe2329afd0,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    %rsi,(%rax)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movabs $0xfffffffe2329afe4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  movl   $0x0,(%rax)
  jmp    L30
L22:
  movabs $0xfffffffe2329afe4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    (%rax),%eax
  add    %eax,%eax
  mov    %eax,%ecx
  movabs $0xfffffffe2329aff0,%rax
  lea    -0x10(%rax),%rax
  lea    (%rax,%rbp,1),%rdx
  movabs $0xfffffffe2329afe4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    (%rax),%eax
  mov    %rcx,(%rdx,%rax,8)
  movabs $0xfffffffe2329afe4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  movabs $0xfffffffe2329afe4,%rdx
  lea    -0x10(%rdx),%rcx
  lea    (%rcx,%rbp,1),%rdx
  mov    (%rdx),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
L30:
  movabs $0xfffffffe2329afe4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  cmpl   $0x3b9ac9ff,(%rax)
  jbe    L22
  movabs $0xfffffffe2329afe8,%rax
  lea    -0x10(%rax),%rax
  lea    (%rax,%rbp,1),%rbx
  movabs $0xfffffffe2329aff0,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    %rax,%rsi
  mov    $0x3b9aca00,%edi
  call   <add@plt>
  mov    %rax,(%rbx)
  movabs $0xfffffffe2329afe8,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  mov    (%rax),%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  movabs $0x1dcd65038,%r11
  add    %r11,%rsp
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: Sum of all elements was: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long elements[1000000000];
  for (unsigned int i = 0; i < 1000000000; ++i) {
    elements[i] = i << 1;
  }
  unsigned long sum = add(1000000000, elements);
  printf("Sum of all elements was: %lu\n", sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  movabs $0xfffffffe2329b000,%r11
  lea    (%rsp,%r11,1),%r11
L29:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L29
  sub    $0x18,%rsp
  movabs $0x1dcd65008,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,(%rsp,%rcx,1)
  xor    %eax,%eax
  movabs $0xfffffffe2329aff0,%rdx
  lea    0x8(%rcx),%rcx
  lea    (%rcx,%rdx,1),%rcx
  lea    (%rsp,%rcx,1),%rdx
L16:
  mov    %rax,(%rdx,%rax,4)
  add    $0x2,%rax
  cmp    $0x77359400,%rax
  jne    L16
  movabs $0xfffffffe2329aff0,%rsi
  movabs $0x1dcd65010,%rax
  lea    (%rax,%rsi,1),%rax
  lea    (%rsp,%rax,1),%rsi
  mov    $0x3b9aca00,%edi
  call   <add@plt>
  mov    %rax,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movabs $0x1dcd65008,%rdi
  mov    (%rsp,%rdi,1),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  movabs $0x1dcd65018,%r11
  add    %r11,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: Sum of all elements was: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long elements[1000000000];
  for (unsigned int i = 0; i < 1000000000; ++i) {
    elements[i] = i << 1;
  }
  unsigned long sum = add(1000000000, elements);
  printf("Sum of all elements was: %lu\n", sum);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  movabs $0xfffffffe2329b000,%r11
  add    %rsp,%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x18,%rsp
  movabs $0x1dcd65008,%rdx
  movabs $0xfffffffe2329aff0,%rsi
  movabs $0x1dcd65010,%rcx
  add    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,(%rsp,%rdx,1)
  xor    %eax,%eax
  lea    (%rsp,%rcx,1),%rsi
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rax,(%rsi,%rax,4)
  add    $0x2,%rax
  cmp    $0x77359400,%rax
  jne    L24
  mov    $0x3b9aca00,%edi
  call   <add@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  movabs $0x1dcd65008,%rdx
  mov    (%rsp,%rdx,1),%rax
  sub    %fs:0x28,%rax
  jne    L8
  movabs $0x1dcd65018,%r11
  xor    %eax,%eax
  add    %r11,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: Sum of all elements was: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long elements[1000000000];
  for (unsigned int i = 0; i < 1000000000; ++i) {
    elements[i] = i << 1;
  }
  unsigned long sum = add(1000000000, elements);
  printf("Sum of all elements was: %lu\n", sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  movabs $0xfffffffe2329b000,%r11
  add    %rsp,%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x18,%rsp
  movdqa D6(%rip),%xmm1
  movdqa D13(%rip),%xmm4
  pxor   %xmm2,%xmm2
  movabs $0x1dcd65008,%rcx
  add    $0x8,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rsp,%rcx,1)
  movabs $0xfffffffe2329aff0,%rax
  add    %rax,%rcx
  lea    (%rsp,%rcx,1),%rax
  movabs $0x1dcd65000,%rcx
  lea    (%rsp,%rcx,1),%rdx
  nopl   (%rax)
L25:
  movdqa %xmm1,%xmm0
  add    $0x20,%rax
  paddd  %xmm4,%xmm1
  pslld  $0x1,%xmm0
  movdqa %xmm0,%xmm3
  punpckhdq %xmm2,%xmm0
  punpckldq %xmm2,%xmm3
  movaps %xmm0,-0x10(%rax)
  movaps %xmm3,-0x20(%rax)
  cmp    %rax,%rdx
  jne    L25
  movabs $0xfffffffe2329aff0,%rsi
  mov    $0x3b9aca00,%edi
  movabs $0x1dcd65010,%rax
  add    %rsi,%rax
  lea    (%rsp,%rax,1),%rsi
  call   <add@plt>
  lea    D27(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  movabs $0x1dcd65008,%rdi
  mov    (%rsp,%rdi,1),%rax
  sub    %fs:0x28,%rax
  jne    L29
  movabs $0x1dcd65018,%r11
  xor    %eax,%eax
  add    %r11,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: byte[16]
name: read_data
arguments: data_label: D13
type_infered: byte[16]
name: read_data
arguments: data_label: D27
type_infered: string

tool: {"D6": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D13": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D27: Sum of all elements was: %lu


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long elements[1000000000];
  for (unsigned int i = 0; i < 1000000000; ++i) {
    elements[i] = i << 1;
  }
  unsigned long sum = add(1000000000, elements);
  printf("Sum of all elements was: %lu\n", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xilinxcorelib_a_3146741991_0543512595_p_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x4af8,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x6c(%rbp)
  cmpl   $0x1,-0x6c(%rbp)
  sete   %al
  mov    %al,-0x6e(%rbp)
  cmpb   $0x0,-0x6e(%rbp)
  jne    L7
  nop
  mov    -0x78(%rbp),%rax
  add    $0x7870,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movb   $0x2,(%rax)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast@plt>
L20:
  mov    -0x78(%rbp),%rax
  add    $0x6f00,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L22
L7:
  nop
  mov    -0x78(%rbp),%rax
  add    $0x1c30,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x6d(%rbp)
  mov    -0x78(%rbp),%rax
  add    $0x7870,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl -0x6d(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <xsi_driver_first_trans_fast@plt>
  jmp    L20
L22:
  leave
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_8(char *t0) {
  char *t1;
  char *t2;
  int t3;
  unsigned char t4;
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
LAB0:
  t1 = (t0 + 19192U);
  t2 = *((char **)t1);
  t3 = *((int *)t2);
  t4 = (t3 == 1);
  if (t4 != 0)
    goto LAB3;
LAB4:
LAB5:
  t11 = (t0 + 30832);
  t12 = (t11 + 56U);
  t13 = *((char **)t12);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  *((unsigned char *)t15) = (unsigned char)2;
  xsi_driver_first_trans_fast(t11);
LAB2:
  t16 = (t0 + 28416);
  *((int *)t16) = 1;
LAB1:
  return;
LAB3:
  t1 = (t0 + 7216U);
  t5 = *((char **)t1);
  t6 = *((unsigned char *)t5);
  t1 = (t0 + 30832);
  t7 = (t1 + 56U);
  t8 = *((char **)t7);
  t9 = (t8 + 56U);
  t10 = *((char **)t9);
  *((unsigned char *)t10) = t6;
  xsi_driver_first_trans_fast(t1);
  goto LAB2;
LAB6:
  goto LAB2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xilinxcorelib_a_3146741991_0543512595_p_8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    0x4af8(%rdi),%rax
  cmpl   $0x1,(%rax)
  je     L16
  mov    0x78a8(%rdi),%rax
  mov    0x38(%rax),%rax
  movb   $0x2,(%rax)
  lea    0x7870(%rdi),%rdi
  call   <xsi_driver_first_trans_fast@plt>
L17:
  movl   $0x1,0x6f00(%rbx)
  pop    %rbx
  ret
L16:
  mov    0x1c30(%rdi),%rax
  movzbl (%rax),%edx
  mov    0x78a8(%rdi),%rax
  mov    0x38(%rax),%rax
  mov    %dl,(%rax)
  lea    0x7870(%rdi),%rdi
  call   <xsi_driver_first_trans_fast@plt>
  jmp    L17
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_8(char *t0) {
  char *t1;
  char *t2;
  int t3;
  unsigned char t4;
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
LAB0:
  t1 = (t0 + 19192U);
  t2 = *((char **)t1);
  t3 = *((int *)t2);
  t4 = (t3 == 1);
  if (t4 != 0)
    goto LAB3;
LAB4:
LAB5:
  t11 = (t0 + 30832);
  t12 = (t11 + 56U);
  t13 = *((char **)t12);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  *((unsigned char *)t15) = (unsigned char)2;
  xsi_driver_first_trans_fast(t11);
LAB2:
  t16 = (t0 + 28416);
  *((int *)t16) = 1;
LAB1:
  return;
LAB3:
  t1 = (t0 + 7216U);
  t5 = *((char **)t1);
  t6 = *((unsigned char *)t5);
  t1 = (t0 + 30832);
  t7 = (t1 + 56U);
  t8 = *((char **)t7);
  t9 = (t8 + 56U);
  t10 = *((char **)t9);
  *((unsigned char *)t10) = t6;
  xsi_driver_first_trans_fast(t1);
  goto LAB2;
LAB6:
  goto LAB2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xilinxcorelib_a_3146741991_0543512595_p_8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  add    $0x7870,%rdi
  mov    0x78a8(%rbx),%rax
  mov    0x38(%rax),%rdx
  mov    0x4af8(%rbx),%rax
  cmpl   $0x1,(%rax)
  je     L4
  movb   $0x2,(%rdx)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f00(%rbx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    0x1c30(%rbx),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f00(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_8(char *t0) {
  char *t1;
  char *t2;
  int t3;
  unsigned char t4;
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
LAB0:
  t1 = (t0 + 19192U);
  t2 = *((char **)t1);
  t3 = *((int *)t2);
  t4 = (t3 == 1);
  if (t4 != 0)
    goto LAB3;
LAB4:
LAB5:
  t11 = (t0 + 30832);
  t12 = (t11 + 56U);
  t13 = *((char **)t12);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  *((unsigned char *)t15) = (unsigned char)2;
  xsi_driver_first_trans_fast(t11);
LAB2:
  t16 = (t0 + 28416);
  *((int *)t16) = 1;
LAB1:
  return;
LAB3:
  t1 = (t0 + 7216U);
  t5 = *((char **)t1);
  t6 = *((unsigned char *)t5);
  t1 = (t0 + 30832);
  t7 = (t1 + 56U);
  t8 = *((char **)t7);
  t9 = (t8 + 56U);
  t10 = *((char **)t9);
  *((unsigned char *)t10) = t6;
  xsi_driver_first_trans_fast(t1);
  goto LAB2;
LAB6:
  goto LAB2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xilinxcorelib_a_3146741991_0543512595_p_8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  add    $0x7870,%rdi
  mov    0x78a8(%rbx),%rax
  mov    0x38(%rax),%rdx
  mov    0x4af8(%rbx),%rax
  cmpl   $0x1,(%rax)
  je     L8
  movb   $0x2,(%rdx)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f00(%rbx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    0x1c30(%rbx),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  call   <xsi_driver_first_trans_fast@plt>
  movl   $0x1,0x6f00(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void xilinxcorelib_a_3146741991_0543512595_p_8(char *t0) {
  char *t1;
  char *t2;
  int t3;
  unsigned char t4;
  char *t5;
  unsigned char t6;
  char *t7;
  char *t8;
  char *t9;
  char *t10;
  char *t11;
  char *t12;
  char *t13;
  char *t14;
  char *t15;
  char *t16;
LAB0:
  t1 = (t0 + 19192U);
  t2 = *((char **)t1);
  t3 = *((int *)t2);
  t4 = (t3 == 1);
  if (t4 != 0)
    goto LAB3;
LAB4:
LAB5:
  t11 = (t0 + 30832);
  t12 = (t11 + 56U);
  t13 = *((char **)t12);
  t14 = (t13 + 56U);
  t15 = *((char **)t14);
  *((unsigned char *)t15) = (unsigned char)2;
  xsi_driver_first_trans_fast(t11);
LAB2:
  t16 = (t0 + 28416);
  *((int *)t16) = 1;
LAB1:
  return;
LAB3:
  t1 = (t0 + 7216U);
  t5 = *((char **)t1);
  t6 = *((unsigned char *)t5);
  t1 = (t0 + 30832);
  t7 = (t1 + 56U);
  t8 = *((char **)t7);
  t9 = (t8 + 56U);
  t10 = *((char **)t9);
  *((unsigned char *)t10) = t6;
  xsi_driver_first_trans_fast(t1);
  goto LAB2;
LAB6:
  goto LAB2;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__fprintf_chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __fprintf_chk(FILE *stream, int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stream, format, args);
  va_end(args);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__fprintf_chk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __fprintf_chk(FILE *stream, int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stream, format, args);
  va_end(args);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__fprintf_chk>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __fprintf_chk(FILE *stream, int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stream, format, args);
  va_end(args);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__fprintf_chk>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rdx,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __fprintf_chk(FILE *stream, int flags, const char *format, ...) {
  va_list args;
  int result;
  va_start(args, format);
  result = (*vfprintf)(stream, format, args);
  va_end(args);
  return result;
}
```