ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D28(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  lea    D22(%rip),%rdi
  mulss  0x14(%rsp),%xmm0
  mov    $0x1,%eax
  divss  D4(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D46
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D22
type: string
name: read_data
arguments: data_tag: D4
type: byte[4]

tool: D46: Enter Principal: 

tool: D28: %f

tool: D26: Enter Rate: 

tool: D25: Enter Time: 

tool: D22: Simple Interest is: %0.2f

tool: {"D4": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  float p, r, t;
  printf("Enter Principal: ");
  scanf("%f", &p);
  printf("Enter Rate: ");
  scanf("%f", &r);
  printf("Enter Time: ");
  scanf("%f", &t);
  printf("Simple Interest is: %0.2f", (p * r * t) / 100);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  lea    D9(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  lea    D54(%rip),%rdi
  mulss  0x14(%rsp),%xmm0
  mov    $0x1,%eax
  divss  D12(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string
name: parse_data
arguments: data_tag: D54
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: byte[4]

tool: D28: Enter Principal: 

tool: D9: %f

tool: D17: Enter Rate: 

tool: D18: Enter Time: 

tool: D54: Simple Interest is: %0.2f

tool: {"D12": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  float p, r, t;
  printf("Enter Principal: ");
  scanf("%f", &p);
  printf("Enter Rate: ");
  scanf("%f", &r);
  printf("Enter Time: ");
  scanf("%f", &t);
  printf("Simple Interest is: %0.2f", (p * r * t) / 100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spectral_median>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L127:
  cmp    %rcx,%rsp
  je     L137
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L127
L137:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L138
  orq    $0x0,-0x8(%rsp,%rax,1)
L138:
  mov    %rsp,%r12
  shl    $0x2,%edx
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  jle    L139
  lea    0x1(%rbx),%edi
  mov    %r12,%rdx
  mov    $0x1,%esi
  lea    0x4(%r12),%r8
  jmp    L16
L115:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L123
L88:
  movss  0x4(%rax),%xmm1
  movss  (%rdx),%xmm0
  comiss %xmm1,%xmm0
  jbe    L115
  movss  %xmm1,(%rdx)
  movss  %xmm0,0x4(%rax)
  jmp    L115
L123:
  add    $0x1,%rsi
  add    $0x4,%rdx
  cmp    %rdi,%rsi
  je     L139
L16:
  cmp    %esi,%ebx
  jl     L123
  mov    %ebx,%eax
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r8,%rax,4),%rcx
  mov    %rdx,%rax
  jmp    L88
L139:
  test   $0x1,%bl
  jne    L118
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cltq
  movss  (%r12,%rdx,4),%xmm0
  addss  (%r12,%rax,4),%xmm0
  mulss  D9(%rip),%xmm0
L69:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L118:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  cltq
  movss  (%r12,%rax,4),%xmm0
  jmp    L69
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float spectral_median(float *x, int n) {
  float temp;
  int i, j;
  float tmp[n + 1];
  memcpy(tmp, x, sizeof(float) * (n + 1));
  for (i = 0; i < n; i++) {
    for (j = i + 1; j <= n; j++) {
      if (tmp[j] < tmp[i]) {
        temp = tmp[i];
        tmp[i] = tmp[j];
        tmp[j] = temp;
      }
    }
  }
  if (n % 2 == 0) {
    return ((tmp[n / 2] + tmp[n / 2 - 1]) / 2.f);
  } else {
    return tmp[n / 2];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<spectral_median>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %r12d,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L37
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L37:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L60
L13:
  mov    %rsp,%r13
  mov    %rdi,%rsi
  lea    0x0(,%r12,4),%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edi
  mov    %r13,%rdx
  mov    $0x1,%esi
  lea    0x4(%r13),%r8
  test   %ebx,%ebx
  jle    L100
  nopl   0x0(%rax)
L96:
  cmp    %esi,%ebx
  jl     L83
  mov    %ebx,%eax
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r8,%rax,4),%rcx
  mov    %rdx,%rax
  nopl   0x0(%rax)
L75:
  movss  0x4(%rax),%xmm1
  movss  (%rdx),%xmm0
  comiss %xmm1,%xmm0
  jbe    L58
  movss  %xmm1,(%rdx)
  movss  %xmm0,0x4(%rax)
L58:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L75
L83:
  add    $0x1,%rsi
  add    $0x4,%rdx
  cmp    %rdi,%rsi
  jne    L96
L100:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  and    $0x1,%ebx
  movslq %eax,%rdx
  movss  0x0(%r13,%rdx,4),%xmm0
  jne    L35
  sub    $0x1,%eax
  cltq
  addss  0x0(%r13,%rax,4),%xmm0
  mulss  D2(%rip),%xmm0
L35:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L60:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L13
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float spectral_median(float *x, int n) {
  float temp;
  int i, j;
  float tmp[n + 1];
  memcpy(tmp, x, sizeof(float) * (n + 1));
  for (i = 0; i < n; i++) {
    for (j = i + 1; j <= n; j++) {
      if (tmp[j] < tmp[i]) {
        temp = tmp[i];
        tmp[i] = tmp[j];
        tmp[j] = temp;
      }
    }
  }
  if (n % 2 == 0) {
    return ((tmp[n / 2] + tmp[n / 2 - 1]) / 2.f);
  } else {
    return tmp[n / 2];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<spectral_median>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %r12d,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L33
L12:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L12
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L93
L97:
  mov    %rsp,%r13
  mov    %rdi,%rsi
  lea    0x0(,%r12,4),%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edi
  mov    %r13,%rdx
  mov    $0x1,%esi
  lea    0x4(%r13),%r8
  test   %ebx,%ebx
  jle    L56
  nopl   0x0(%rax)
L16:
  cmp    %esi,%ebx
  jl     L84
  mov    %ebx,%eax
  sub    %esi,%eax
  lea    -0x1(%rsi,%rax,1),%rax
  lea    (%r8,%rax,4),%rcx
  mov    %rdx,%rax
  nopl   0x0(%rax)
L89:
  movss  0x4(%rax),%xmm1
  movss  (%rdx),%xmm0
  comiss %xmm1,%xmm0
  jbe    L35
  movss  %xmm1,(%rdx)
  movss  %xmm0,0x4(%rax)
L35:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L89
L84:
  add    $0x1,%rsi
  add    $0x4,%rdx
  cmp    %rdi,%rsi
  jne    L16
L56:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  and    $0x1,%ebx
  movslq %eax,%rdx
  movss  0x0(%r13,%rdx,4),%xmm0
  jne    L80
  sub    $0x1,%eax
  cltq
  addss  0x0(%r13,%rax,4),%xmm0
  mulss  D7(%rip),%xmm0
L80:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L93:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L97
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float spectral_median(float *x, int n) {
  float temp;
  int i, j;
  float tmp[n + 1];
  memcpy(tmp, x, sizeof(float) * (n + 1));
  for (i = 0; i < n; i++) {
    for (j = i + 1; j <= n; j++) {
      if (tmp[j] < tmp[i]) {
        temp = tmp[i];
        tmp[i] = tmp[j];
        tmp[j] = temp;
      }
    }
  }
  if (n % 2 == 0) {
    return ((tmp[n / 2] + tmp[n / 2 - 1]) / 2.f);
  } else {
    return tmp[n / 2];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <prepare_for_exit@plt>
  mov    $0x0,%eax
  call   <free_memory@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void signal_handler(const int sig) {
  prepare_for_exit();
  free_memory();
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<signal_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prepare_for_exit@plt>
  mov    $0x0,%eax
  call   <free_memory@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void signal_handler(const int sig) {
  prepare_for_exit();
  free_memory();
  exit(EXIT_FAILURE);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<signal_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prepare_for_exit@plt>
  xor    %eax,%eax
  call   <free_memory@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

assistant: ```c
void signal_handler(const int sig) {
  prepare_for_exit();
  free_memory();
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<signal_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prepare_for_exit@plt>
  xor    %eax,%eax
  call   <free_memory@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

assistant: ```c
void signal_handler(const int sig) {
  prepare_for_exit();
  free_memory();
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<confirm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <isStringEmpty@plt>
  test   %rax,%rax
  je     L15
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L3
L15:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D0: CONFIRM:

tool: D1: CONFIRM: %s


assistant: ```c
void confirm(const char *str) {
  if (isStringEmpty(str)) {
    printf("CONFIRM:\n");
    return;
  }
  printf("CONFIRM: %s\n", str + sizeof(int32_t));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<confirm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <isStringEmpty@plt>
  test   %rax,%rax
  jne    L5
  lea    0x4(%rbx),%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  pop    %rbx
  ret
L5:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D16: CONFIRM: %s


tool: D9: CONFIRM:

assistant: ```c
void confirm(const char *str) {
  if (isStringEmpty(str)) {
    printf("CONFIRM:\n");
    return;
  }
  printf("CONFIRM: %s\n", str + sizeof(int32_t));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<confirm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <isStringEmpty@plt>
  test   %rax,%rax
  jne    L6
  lea    0x4(%rbx),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <printf@plt>
  nopl   (%rax)
L6:
  lea    D14(%rip),%rdi
  pop    %rbx
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D10: CONFIRM: %s


tool: D14: CONFIRM:

assistant: ```c
void confirm(const char *str) {
  if (isStringEmpty(str)) {
    printf("CONFIRM:\n");
    return;
  }
  printf("CONFIRM: %s\n", str + sizeof(int32_t));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<confirm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <isStringEmpty@plt>
  test   %rax,%rax
  jne    L0
  lea    0x4(%rbx),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <printf@plt>
  nopl   (%rax)
L0:
  lea    D3(%rip),%rdi
  pop    %rbx
  jmp    1070 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string

tool: D6: CONFIRM: %s


tool: D3: CONFIRM:

assistant: ```c
void confirm(const char *str) {
  if (isStringEmpty(str)) {
    printf("CONFIRM:\n");
    return;
  }
  printf("CONFIRM: %s\n", str + sizeof(int32_t));
}
```
user: What is the c source code of the assembly code below?

```asm
<set_high_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_high_bit(char *buf, size_t bytes) {
  size_t i;
  for (i = 0; i < bytes; ++i)
    buf[i] |= 0x80;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_high_bit>:
  endbr64
  test   %rsi,%rsi
  je     L7
  mov    %rdi,%rax
  add    %rsi,%rdi
L18:
  orb    $0x80,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L7:
  ret
```

assistant: ```c
void set_high_bit(char *buf, size_t bytes) {
  size_t i;
  for (i = 0; i < bytes; ++i)
    buf[i] |= 0x80;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_high_bit>:
  endbr64
  test   %rsi,%rsi
  je     L1
  add    %rdi,%rsi
  nopl   0x0(%rax)
L18:
  orb    $0x80,(%rdi)
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L18
L1:
  ret
```

assistant: ```c
void set_high_bit(char *buf, size_t bytes) {
  size_t i;
  for (i = 0; i < bytes; ++i)
    buf[i] |= 0x80;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_high_bit>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  test   %rsi,%rsi
  je     L53
  lea    -0x1(%rsi),%rax
  cmp    $0xe,%rax
  jbe    L46
  and    $0xfffffffffffffff0,%rsi
  movdqa D2(%rip),%xmm1
  mov    %rdi,%rax
  add    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L127:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  por    %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rsi,%rax
  jne    L127
  mov    %rcx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%cl
  je     L87
L105:
  mov    %rcx,%rsi
  sub    %rax,%rsi
  lea    -0x1(%rsi),%rdi
  cmp    $0x6,%rdi
  jbe    L22
  movq   D2(%rip),%xmm1
  lea    (%rdx,%rax,1),%rdi
  movq   (%rdi),%xmm0
  por    %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  mov    %rsi,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rax
  cmp    %rdi,%rsi
  je     L53
L22:
  lea    0x1(%rax),%rsi
  orb    $0x80,(%rdx,%rax,1)
  cmp    %rcx,%rsi
  jae    L53
  orb    $0x80,(%rdx,%rsi,1)
  lea    0x2(%rax),%rsi
  cmp    %rsi,%rcx
  jbe    L53
  orb    $0x80,(%rdx,%rsi,1)
  lea    0x3(%rax),%rsi
  cmp    %rsi,%rcx
  jbe    L53
  orb    $0x80,(%rdx,%rsi,1)
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rcx
  jbe    L53
  orb    $0x80,(%rdx,%rsi,1)
  lea    0x5(%rax),%rsi
  cmp    %rsi,%rcx
  jbe    L53
  add    $0x6,%rax
  orb    $0x80,(%rdx,%rsi,1)
  cmp    %rax,%rcx
  jbe    L53
  orb    $0x80,(%rdx,%rax,1)
L53:
  ret
L46:
  xor    %eax,%eax
  jmp    L105
L87:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[16]

tool: {"D2": [0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80,0x80]}

assistant: ```c
void set_high_bit(char *buf, size_t bytes) {
  size_t i;
  for (i = 0; i < bytes; ++i)
    buf[i] |= 0x80;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrWildcardTest>:
  endbr64
  mov    %rdi,%rcx
  movzbl (%rsi),%edx
  cmp    $0x3f,%dl
  jbe    L112
  mov    $0x1,%eax
L92:
  movabs $0x8000040000000001,%r9
  jmp    L158
L112:
  mov    $0x1,%eax
  movabs $0x8000040000000001,%rdi
  bt     %rdx,%rdi
  jae    L92
  mov    $0x0,%edi
  mov    $0x0,%eax
L25:
  test   %dl,%dl
  je     L214
  movslq %edi,%r9
  movzbl (%rsi,%r9,1),%edx
  cmp    $0x3f,%dl
  je     L77
  cmp    $0x2a,%dl
  jne    L95
L77:
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rsi,%r9,1),%rax
  mov    $0x0,%esi
  mov    $0x0,%r8d
L48:
  cmp    $0x3f,%dl
  je     L224
  mov    $0x2710,%esi
L41:
  mov    %rax,%rbx
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x3f,%dl
  je     L48
  cmp    $0x2a,%dl
  je     L48
  test   %r8d,%r8d
  jle    L226
  lea    0x1(%rdi),%eax
  cltq
  lea    -0x1(%r8),%edx
  lea    0x2(%r9,%rdx,1),%rdx
L4:
  mov    %eax,%edi
  cmpb   $0x0,-0x1(%rcx,%rax,1)
  je     L211
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L226:
  sub    %r8d,%esi
  test   %esi,%esi
  jle    L43
  movslq %edi,%rdi
  lea    (%rcx,%rdi,1),%rbp
  lea    0x1(%rcx,%rdi,1),%r12
  lea    -0x1(%rsi),%eax
  add    %rax,%r12
L135:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <StrWildcardTest>
  test   %eax,%eax
  jne    L70
  cmpb   $0x0,0x0(%rbp)
  je     L111
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L135
  jmp    L111
L95:
  mov    $0x0,%eax
  ret
L214:
  cmpb   $0x0,(%rcx,%rax,1)
  sete   %al
  movzbl %al,%eax
  ret
L224:
  add    $0x1,%r8d
  add    $0x1,%esi
  jmp    L41
L26:
  mov    $0x0,%eax
  ret
L211:
  mov    $0x0,%eax
L111:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    $0x0,%eax
  jmp    L111
L70:
  mov    $0x1,%eax
  jmp    L111
L156:
  add    $0x1,%rax
L158:
  cmp    %dl,-0x1(%rcx,%rax,1)
  jne    L26
  mov    %eax,%edi
  movzbl (%rsi,%rax,1),%edx
  cmp    $0x3f,%dl
  ja     L156
  lea    0x1(%rax),%r8
  bt     %rdx,%r9
  jb     L25
  mov    %r8,%rax
  jmp    L158
```

assistant: ```c
int StrWildcardTest(const char *test, const char *wildcard) {
  int i = 0, j, k, mineat = 0, maxeat = 0;
  while ((wildcard[i] != '\0') && (wildcard[i] != '?') && (wildcard[i] != '*'))
    if (test[i] != wildcard[i]) {
      return 0;
    } else {
      i++;
    }
  if (wildcard[i] == '\0')
    return (test[i] == '\0');
  j = i;
  while ((wildcard[j] == '?') || (wildcard[j] == '*')) {
    if (wildcard[j] == '?') {
      mineat++;
      maxeat++;
    } else {
      maxeat = 10000;
    }
    j++;
  }
  for (k = 0; k < mineat; k++)
    if (test[i++] == '\0')
      return 0;
  for (k = 0; k < maxeat - mineat; k++) {
    if (StrWildcardTest(test + i, wildcard + j))
      return 1;
    if (test[i++] == '\0')
      return 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<StrWildcardTest>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L238
  cmp    $0x3f,%al
  je     L238
  xor    %edx,%edx
  jmp    L132
  nopl   0x0(%rax,%rax,1)
L110:
  cmp    %al,(%rdi,%rdx,1)
  jne    L12
  add    $0x1,%rdx
  add    $0x1,%ecx
  movzbl (%rsi,%rdx,1),%eax
  test   %al,%al
  je     L18
  cmp    $0x3f,%al
  je     L208
L132:
  mov    %edx,%ecx
  cmp    $0x2a,%al
  jne    L110
L30:
  movslq %ecx,%rcx
  movzbl (%rsi,%rcx,1),%edx
  cmp    $0x3f,%dl
  je     L166
  cmp    $0x2a,%dl
  jne    L12
L166:
  lea    0x1(%rcx),%rax
  push   %r12
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  push   %rbp
  add    %rax,%rsi
  push   %rbx
  jmp    L159
  nopw   0x0(%rax,%rax,1)
L179:
  cmp    $0x2a,%dl
  jne    L214
L159:
  cmp    $0x3f,%dl
  je     L56
  mov    $0x2710,%r8d
L206:
  movzbl (%rsi),%edx
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rsi
  cmp    $0x3f,%dl
  jne    L179
L56:
  add    $0x1,%r9d
  add    $0x1,%r8d
  jmp    L206
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L214:
  test   %r9d,%r9d
  je     L188
  lea    -0x1(%r9),%edx
  lea    0x2(%rdx,%rcx,1),%rdx
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L93:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L48
L86:
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  movslq %eax,%rcx
  jne    L93
L147:
  xor    %eax,%eax
L113:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L238:
  xor    %ecx,%ecx
  xor    %edx,%edx
  xchg   %ax,%ax
L208:
  test   %al,%al
  jne    L30
L18:
  xor    %eax,%eax
  cmpb   $0x0,(%rdi,%rdx,1)
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  sub    %r9d,%r8d
  test   %r8d,%r8d
  jle    L147
L188:
  lea    0x1(%rdi,%rcx,1),%r12
  lea    -0x1(%r8),%eax
  lea    (%rdi,%rcx,1),%rbp
  add    %rax,%r12
  jmp    L196
  nopw   0x0(%rax,%rax,1)
L245:
  cmpb   $0x0,0x0(%rbp)
  je     L113
  add    $0x1,%rbp
  cmp    %rbp,%r12
  je     L113
L196:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <StrWildcardTest>
  test   %eax,%eax
  je     L245
  mov    $0x1,%eax
  jmp    L113
```

assistant: ```c
int StrWildcardTest(const char *test, const char *wildcard) {
  int i = 0, j, k, mineat = 0, maxeat = 0;
  while ((wildcard[i] != '\0') && (wildcard[i] != '?') && (wildcard[i] != '*'))
    if (test[i] != wildcard[i]) {
      return 0;
    } else {
      i++;
    }
  if (wildcard[i] == '\0')
    return (test[i] == '\0');
  j = i;
  while ((wildcard[j] == '?') || (wildcard[j] == '*')) {
    if (wildcard[j] == '?') {
      mineat++;
      maxeat++;
    } else {
      maxeat = 10000;
    }
    j++;
  }
  for (k = 0; k < mineat; k++)
    if (test[i++] == '\0')
      return 0;
  for (k = 0; k < maxeat - mineat; k++) {
    if (StrWildcardTest(test + i, wildcard + j))
      return 1;
    if (test[i++] == '\0')
      return 0;
  }
  return 0;
}
```