user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D126(%rip),%rdi
  lea    D20(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D124(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xb(%rsp),%rsi
  lea    D120(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D101(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0xb(%rsp),%eax
  cmp    $0x33,%al
  je     L0
  jg     L92
  cmp    $0x31,%al
  je     L41
  cmp    $0x32,%al
  jne    L72
  lea    D167(%rip),%rdi
  call   <puts@plt>
  lea    D135(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <modify_bit@plt>
  lea    D134(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L82
  add    $0x20,%rsp
  pop    %rbp
  ret
L92:
  cmp    $0x34,%al
  jne    L72
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <clear_bit@plt>
  jmp    L16
L0:
  lea    D49(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  lea    D132(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <isBitset@plt>
  lea    D115(%rip),%rdi
  test   %eax,%eax
  lea    D25(%rip),%rax
  cmove  %rax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L16
L72:
  lea    D160(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L16
L41:
  lea    D85(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <set_bit@plt>
  lea    D89(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L16
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D126
type_infered: string
name: disassemble_data
arguments: label: D20
type_infered: string
name: disassemble_data
arguments: label: D124
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D120
type_infered: string
name: disassemble_data
arguments: label: D41
type_infered: string
name: disassemble_data
arguments: label: D101
type_infered: string
name: disassemble_data
arguments: label: D167
type_infered: string
name: disassemble_data
arguments: label: D135
type_infered: string
name: disassemble_data
arguments: label: D134
type_infered: string
name: disassemble_data
arguments: label: D49
type_infered: string
name: disassemble_data
arguments: label: D132
type_infered: string
name: disassemble_data
arguments: label: D115
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string
name: disassemble_data
arguments: label: D160
type_infered: string
name: disassemble_data
arguments: label: D85
type_infered: string
name: disassemble_data
arguments: label: D89
type_infered: string

tool: D126: Enter the Number : 

tool: D20: %d

tool: D124: 
Enter your choice :

tool: D13: 1.set bit
2.Modify a bit
3.Is bit set
4.Clear bit

tool: D120:  %c

tool: D41: 
Enter the position :

tool: D101:  %d

tool: D167: Inside 2

tool: D135: 
Enter the new state :

tool: D134: After Modification : %d


tool: D49: inside 3

tool: D132: number %x 


tool: D115: SET


tool: D25: NOT SET


tool: D160: Invalid

tool: D85: Inside 1

tool: D89: After Modification : %d 


assistant: ```c
int main() {
  int number, pos;
  char ops;
  int state;
  printf("Enter the Number : ");
  scanf("%d", &number);
  printf("\nEnter your choice :");
  printf("1.set bit\n2.Modify a bit\n3.Is bit set\n4.Clear bit");
  scanf(" %c", &ops);
  printf("\nEnter the position :");
  scanf(" %d", &pos);
  switch (ops) {
  case '1':
    printf("Inside 1\n");
    printf("After Modification : %d \n", set_bit(number, pos));
    break;
  case '2':
    printf("Inside 2\n");
    printf("\nEnter the new state :");
    scanf("%d", &state);
    printf("After Modification : %d\n", modify_bit(number, pos, state));
    break;
  case '3':
    printf("inside 3\n");
    printf("number %x \n", number);
    printf((isBitset(number, pos)) ? "SET\n" : "NOT SET\n");
    break;
  case '4':
    return clear_bit(number, pos);
    break;
  default:
    printf("Invalid\n");
  }
  return 0;
}
```