ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rbp
  call   <tty_raw_mode@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  xor    %edi,%edi
  mov    $0x1,%edx
  call   <read@plt>
  movsbl 0x7(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(int argc, char **argv) {
  tty_raw_mode();
  while (1) {
    char ch;
    read(0, &ch, 1);
    printf("%d\n", ch);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys_setrlimit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <syscall2@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int sys_setrlimit(int resource, rlim_t limit) {
  const struct rlimit buf = {
      .rlim_cur = limit,
      .rlim_max = limit,
  };
  return syscall2(SYS_setrlimit, resource, (uintptr_t)&buf);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sys_setrlimit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdx
  mov    %edi,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <syscall2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_setrlimit(int resource, rlim_t limit) {
  const struct rlimit buf = {
      .rlim_cur = limit,
      .rlim_max = limit,
  };
  return syscall2(SYS_setrlimit, resource, (uintptr_t)&buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys_setrlimit>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %esi,(%rsp)
  mov    %rsp,%rdx
  mov    %esi,0x4(%rsp)
  mov    %edi,%esi
  mov    (%rax),%edi
  call   <syscall2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_setrlimit(int resource, rlim_t limit) {
  const struct rlimit buf = {
      .rlim_cur = limit,
      .rlim_max = limit,
  };
  return syscall2(SYS_setrlimit, resource, (uintptr_t)&buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sys_setrlimit>:
  endbr64
  sub    $0x18,%rsp
  movd   %esi,%xmm1
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  pshufd $0xe0,%xmm1,%xmm0
  mov    %rsp,%rdx
  movq   %xmm0,(%rsp)
  mov    (%rax),%edi
  call   <syscall2@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sys_setrlimit(int resource, rlim_t limit) {
  const struct rlimit buf = {
      .rlim_cur = limit,
      .rlim_max = limit,
  };
  return syscall2(SYS_setrlimit, resource, (uintptr_t)&buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  movw   $0x7a73,0x6(%rsp)
  movabs $0x7774706d6a676461,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x7875716e6b686562,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x7976726f6c696663,%rax
  mov    %rax,0x18(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  mov    %rbx,%rcx
  lea    -0x1(%rax),%eax
  lea    0x21(%rsp,%rax,1),%r10
  mov    $0x0,%esi
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r8
  lea    0x18(%rsp),%r9
  lea    0x6(%rsp),%r11
  jmp    L51
L45:
  mov    $0x0,%eax
  jmp    L22
L145:
  add    $0x1,%esi
L101:
  add    $0x1,%rax
  cmp    $0x8,%rax
  je     L98
L22:
  cmp    (%rax,%rdi,1),%dl
  je     L145
  cmp    (%rax,%r8,1),%dl
  je     L35
  cmp    (%rax,%r9,1),%dl
  je     L36
  cmp    (%rax,%r11,1),%dl
  jne    L101
  add    $0x4,%esi
  jmp    L101
L35:
  add    $0x2,%esi
  jmp    L101
L36:
  add    $0x3,%esi
  jmp    L101
L98:
  add    $0x1,%rcx
  cmp    %r10,%rcx
  je     L71
L51:
  movzbl (%rcx),%edx
  cmp    $0x20,%dl
  jne    L45
  add    $0x1,%esi
  jmp    L98
L11:
  mov    $0x0,%esi
L71:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  ret
L118:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D8: %[^
]s

tool: D10: %d

assistant: ```c
int main() {
  char four_click[] = {'s', 'z'};
  char one_click[] = {'a', 'd', 'g', 'j', 'm', 'p', 't', 'w'};
  char two_click[] = {'b', 'e', 'h', 'k', 'n', 'q', 'u', 'x'};
  char three_click[] = {'c', 'f', 'i', 'l', 'o', 'r', 'v', 'y'};
  char space[] = {' '};
  char text[160];
  int i = 0, k = 0, how_many_clicks = 0;
  scanf("%[^\n]s", &text);
  int l = strlen(text);
  for (i = 0; i < l; i++) {
    if (text[i] == space[0])
      how_many_clicks++;
    else {
      for (k = 0; k < 8; k++) {
        if (text[i] == one_click[k])
          how_many_clicks++;
        else if (text[i] == two_click[k])
          how_many_clicks = how_many_clicks + 2;
        else if (text[i] == three_click[k])
          how_many_clicks = how_many_clicks + 3;
        else if (text[i] == four_click[k])
          how_many_clicks = how_many_clicks + 4;
      }
    }
  }
  printf("%d", how_many_clicks);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D11(%rip),%rdi
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    $0x7a73,%eax
  lea    0x20(%rsp),%rbx
  mov    %ax,0x6(%rsp)
  mov    %rbx,%rsi
  movabs $0x7774706d6a676461,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x7875716e6b686562,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x7976726f6c696663,%rax
  mov    %rax,0x18(%rsp)
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L45
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x10(%rsp),%r8
  xor    %esi,%esi
  lea    0x21(%rsp,%rax,1),%r10
  lea    0x18(%rsp),%r9
  lea    0x6(%rsp),%r11
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L99:
  add    $0x1,%esi
L135:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  je     L89
L51:
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L99
  xor    %eax,%eax
  mov    $0x61,%ecx
  jmp    L90
  nopl   (%rax)
L66:
  cmp    (%rax,%r8,1),%dl
  je     L76
  cmp    (%rax,%r9,1),%dl
  je     L93
  cmp    (%rax,%r11,1),%dl
  jne    L16
  add    $0x4,%esi
  nopl   (%rax)
L16:
  add    $0x1,%rax
  cmp    $0x8,%rax
  je     L135
  movzbl 0x8(%rsp,%rax,1),%ecx
L90:
  cmp    %cl,%dl
  jne    L66
  add    $0x1,%esi
  jmp    L16
L76:
  add    $0x2,%esi
  jmp    L16
  nopl   (%rax)
L93:
  add    $0x3,%esi
  jmp    L16
L45:
  xor    %esi,%esi
  nop
L89:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D6
type: string

tool: D11: %[^
]s

tool: D6: %d

assistant: ```c
int main() {
  char four_click[] = {'s', 'z'};
  char one_click[] = {'a', 'd', 'g', 'j', 'm', 'p', 't', 'w'};
  char two_click[] = {'b', 'e', 'h', 'k', 'n', 'q', 'u', 'x'};
  char three_click[] = {'c', 'f', 'i', 'l', 'o', 'r', 'v', 'y'};
  char space[] = {' '};
  char text[160];
  int i = 0, k = 0, how_many_clicks = 0;
  scanf("%[^\n]s", &text);
  int l = strlen(text);
  for (i = 0; i < l; i++) {
    if (text[i] == space[0])
      how_many_clicks++;
    else {
      for (k = 0; k < 8; k++) {
        if (text[i] == one_click[k])
          how_many_clicks++;
        else if (text[i] == two_click[k])
          how_many_clicks = how_many_clicks + 2;
        else if (text[i] == three_click[k])
          how_many_clicks = how_many_clicks + 3;
        else if (text[i] == four_click[k])
          how_many_clicks = how_many_clicks + 4;
      }
    }
  }
  printf("%d", how_many_clicks);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  jmp    L13
L19:
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <fahrenheit_to_celsius@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x8(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
L13:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jae    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: %3.0f %6.1f


assistant: ```c
int main(int argc, char const *argv[]) {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahrenheit_to_celsius(fahr);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x10,%ebp
  mov    D11(%rip),%ebx
  lea    D18(%rip),%r12
L5:
  movd   %ebx,%xmm0
  call   <fahrenheit_to_celsius@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  mov    %r12,%rdi
  call   <printf@plt>
  movd   %ebx,%xmm2
  addss  D10(%rip),%xmm2
  movd   %xmm2,%ebx
  sub    $0x1,%ebp
  jne    L5
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: byte[4]
name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: byte[4]

tool: {"D11": [0x00,0x00,0x00,0x00]}

tool: D18: %3.0f %6.1f


tool: {"D10": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(int argc, char const *argv[]) {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahrenheit_to_celsius(fahr);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm2,%xmm2
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <fahrenheit_to_celsius@plt>
  movss  0xc(%rsp),%xmm2
  mov    %rbp,%rdi
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D11(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string
name: unpack_data
arguments: data_label: D11
datatype: byte[4]

tool: D1: %3.0f %6.1f


tool: {"D11": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(int argc, char const *argv[]) {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahrenheit_to_celsius(fahr);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm2,%xmm2
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  movaps %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <fahrenheit_to_celsius@plt>
  movss  0xc(%rsp),%xmm2
  mov    %rbp,%rdi
  movaps %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D6(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D6
type_guessed: byte[4]

tool: D3: %3.0f %6.1f


tool: {"D6": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(int argc, char const *argv[]) {
  float fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahrenheit_to_celsius(fahr);
    printf("%3.0f %6.1f\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itex2MML_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <itex2MML_setup@plt>
  mov    $0x0,%eax
  call   <itex2MML_restart@plt>
  mov    $0x0,%edi
  call   <itex2MML_yyparse@plt>
  leave
  ret
```

assistant: ```c
int itex2MML_filter(const char *buffer, unsigned long length) {
  itex2MML_setup(buffer, length);
  itex2MML_restart();
  return itex2MML_yyparse(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itex2MML_filter>:
  endbr64
  sub    $0x8,%rsp
  call   <itex2MML_setup@plt>
  mov    $0x0,%eax
  call   <itex2MML_restart@plt>
  mov    $0x0,%edi
  call   <itex2MML_yyparse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int itex2MML_filter(const char *buffer, unsigned long length) {
  itex2MML_setup(buffer, length);
  itex2MML_restart();
  return itex2MML_yyparse(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<itex2MML_filter>:
  endbr64
  sub    $0x8,%rsp
  call   <itex2MML_setup@plt>
  xor    %eax,%eax
  call   <itex2MML_restart@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <itex2MML_yyparse@plt>
```

assistant: ```c
int itex2MML_filter(const char *buffer, unsigned long length) {
  itex2MML_setup(buffer, length);
  itex2MML_restart();
  return itex2MML_yyparse(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itex2MML_filter>:
  endbr64
  sub    $0x8,%rsp
  call   <itex2MML_setup@plt>
  xor    %eax,%eax
  call   <itex2MML_restart@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1090 <itex2MML_yyparse@plt>
```

assistant: ```c
int itex2MML_filter(const char *buffer, unsigned long length) {
  itex2MML_setup(buffer, length);
  itex2MML_restart();
  return itex2MML_yyparse(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sha1_verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdi
  mov    -0x40(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <sha1_do_hmac@plt>
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x20(%rbp),%rax
  mov    $0x14,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int sha1_verify(void *handle, unsigned char *blk, int len, unsigned long seq) {
  unsigned char correct[20];
  sha1_do_hmac(handle, blk, len, seq, correct);
  return !memcmp(correct, blk + len, 20);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sha1_verify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%r8
  call   <sha1_do_hmac@plt>
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rsi
  mov    $0x14,%edx
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sha1_verify(void *handle, unsigned char *blk, int len, unsigned long seq) {
  unsigned char correct[20];
  sha1_do_hmac(handle, blk, len, seq, correct);
  return !memcmp(correct, blk + len, 20);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sha1_verify>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%r8
  call   <sha1_do_hmac@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    $0x14,%edx
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sha1_verify(void *handle, unsigned char *blk, int len, unsigned long seq) {
  unsigned char correct[20];
  sha1_do_hmac(handle, blk, len, seq, correct);
  return !memcmp(correct, blk + len, 20);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sha1_verify>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%r8
  call   <sha1_do_hmac@plt>
  lea    (%rbx,%rbp,1),%rsi
  mov    $0x14,%edx
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sha1_verify(void *handle, unsigned char *blk, int len, unsigned long seq) {
  unsigned char correct[20];
  sha1_do_hmac(handle, blk, len, seq, correct);
  return !memcmp(correct, blk + len, 20);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<downhi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r10
  mov    %ecx,%r11d
  mov    %esi,%r13d
  shr    $0x1f,%r13d
  add    %esi,%r13d
  sar    %r13d
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  lea    -0x1(%rax,%rax,1),%ecx
  lea    -0x1(%r11),%edx
  lea    -0x1(%rax),%ebp
  cmp    %edx,%ecx
  cmovl  %eax,%ebp
  cmp    %r13d,%ebp
  jge    L14
  movslq %ebp,%rax
  lea    (%r8,%rax,8),%rbx
  lea    0x1(%rbp,%rbp,1),%r9d
  lea    0x1(%r13,%r13,1),%r12d
  lea    -0x1(%r11),%eax
  shl    $0x3,%rax
  mov    %rdi,%r14
  sub    %rax,%r14
  jmp    L128
L87:
  mov    %r10,%rdx
  movslq %r9d,%rax
  lea    (%rdi,%rax,8),%rax
  lea    -0x1(%r9),%ecx
  movslq %ecx,%rcx
  lea    (%r14,%rcx,8),%rcx
  pxor   %xmm1,%xmm1
L42:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rdx
  sub    $0x8,%rax
  cmp    %rcx,%rax
  jne    L42
L49:
  movsd  %xmm1,(%rbx)
  add    $0x8,%rbx
  add    $0x2,%r9d
  cmp    %r12d,%r9d
  je     L14
L128:
  pxor   %xmm1,%xmm1
  test   %r11d,%r11d
  jg     L87
  jmp    L49
L14:
  cmp    %r13d,%ebp
  cmovg  %r13d,%ebp
  test   %ebp,%ebp
  jle    L32
  mov    %r8,%rbx
  lea    0x1(%rbp,%rbp,1),%ebp
  lea    -0x1(%r11),%eax
  lea    0x8(%r10,%rax,8),%r9
  mov    $0x1,%r8d
  jmp    L61
L64:
  lea    (%rax,%rsi,1),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  movslq %eax,%rcx
  movsd  (%rdi,%rcx,8),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  sub    $0x1,%eax
  add    $0x8,%rdx
  cmp    %r9,%rdx
  jne    L64
L10:
  movsd  %xmm1,(%rbx)
  add    $0x8,%rbx
  add    $0x2,%r8d
  cmp    %ebp,%r8d
  je     L32
L61:
  mov    %r8d,%eax
  test   %r11d,%r11d
  jle    L39
  mov    %r10,%rdx
  pxor   %xmm1,%xmm1
  jmp    L64
L39:
  pxor   %xmm1,%xmm1
  jmp    L10
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void downhi(x, n, hpf, m, y) double x[], hpf[], y[];
int n, m;
{
  int n2, mlo, i, h, j;
  double s;
  n2 = n / 2;
  mlo = m / 2 - 1;
  if (2 * mlo + 1 - (m - 1) < 0)
    mlo++;
  for (i = mlo; i < n2; i++) {
    s = 0.;
    for (h = 0; h < m; h++)
      s += hpf[h] * x[2 * i + 1 - h];
    y[i] = s;
  }
  if (mlo > n2)
    mlo = n2;
  for (i = 0; i < mlo; i++) {
    s = 0.;
    j = 2 * i + 1;
    for (h = 0; h < m; h++) {
      if (j < 0)
        j += n;
      s += hpf[h] * x[j];
      --j;
    }
    y[i] = s;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<downhi>:
  endbr64
  mov    %ecx,%eax
  push   %r15
  mov    %rdx,%r10
  mov    %esi,%r9d
  shr    $0x1f,%eax
  push   %r14
  lea    -0x1(%rcx),%r14d
  mov    %ecx,%r11d
  push   %r13
  add    %ecx,%eax
  mov    %esi,%r13d
  sar    %eax
  shr    $0x1f,%r13d
  push   %r12
  add    %esi,%r13d
  lea    -0x1(%rax,%rax,1),%edx
  push   %rbp
  lea    -0x1(%rax),%ebp
  sar    %r13d
  cmp    %r14d,%edx
  push   %rbx
  mov    %r8,%rbx
  cmovl  %eax,%ebp
  cmp    %r13d,%ebp
  jge    L39
  movslq %ebp,%rax
  lea    0x1(%rbp,%rbp,1),%esi
  lea    0x1(%r13,%r13,1),%r12d
  mov    %rdi,%r15
  lea    (%r8,%rax,8),%r8
  mov    %r14d,%eax
  pxor   %xmm2,%xmm2
  shl    $0x3,%rax
  sub    %rax,%r15
  nopw   0x0(%rax,%rax,1)
L21:
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L37
  lea    -0x1(%rsi),%ecx
  movslq %esi,%rax
  movapd %xmm2,%xmm1
  mov    %r10,%rdx
  movslq %ecx,%rcx
  lea    (%rdi,%rax,8),%rax
  lea    (%r15,%rcx,8),%rcx
  nopl   0x0(%rax)
L30:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  sub    $0x8,%rax
  add    $0x8,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L30
L37:
  add    $0x2,%esi
  movsd  %xmm1,(%r8)
  add    $0x8,%r8
  cmp    %r12d,%esi
  jne    L21
L39:
  cmp    %r13d,%ebp
  cmovg  %r13d,%ebp
  test   %ebp,%ebp
  jle    L76
  lea    0x1(%rbp,%rbp,1),%ebp
  lea    (%r10,%r14,8),%rsi
  mov    $0x1,%r8d
  pxor   %xmm2,%xmm2
  nop
L45:
  mov    %r8d,%eax
  mov    %r10,%rdx
  movapd %xmm2,%xmm1
  test   %r11d,%r11d
  jg     L86
  jmp    L74
  nopl   0x0(%rax)
L29:
  test   %eax,%eax
  lea    (%rax,%r9,1),%ecx
  cmovs  %ecx,%eax
  add    $0x8,%rdx
L86:
  movslq %eax,%rcx
  sub    $0x1,%eax
  movsd  (%rdi,%rcx,8),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rdx,%rsi
  jne    L29
L74:
  add    $0x2,%r8d
  movsd  %xmm1,(%rbx)
  add    $0x8,%rbx
  cmp    %r8d,%ebp
  jne    L45
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void downhi(x, n, hpf, m, y) double x[], hpf[], y[];
int n, m;
{
  int n2, mlo, i, h, j;
  double s;
  n2 = n / 2;
  mlo = m / 2 - 1;
  if (2 * mlo + 1 - (m - 1) < 0)
    mlo++;
  for (i = mlo; i < n2; i++) {
    s = 0.;
    for (h = 0; h < m; h++)
      s += hpf[h] * x[2 * i + 1 - h];
    y[i] = s;
  }
  if (mlo > n2)
    mlo = n2;
  for (i = 0; i < mlo; i++) {
    s = 0.;
    j = 2 * i + 1;
    for (h = 0; h < m; h++) {
      if (j < 0)
        j += n;
      s += hpf[h] * x[j];
      --j;
    }
    y[i] = s;
  }
}
```