ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hex_to_char_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  addq   $0x2,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: %2hhx

assistant: ```c
void hex_to_char_array(unsigned char *hex, unsigned char *buffer, int buff_size) {
  int i;
  for (i = 0; i < buff_size; i++) {
    sscanf(hex, "%2hhx", &buffer[i]);
    hex += 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex_to_char_array>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%edx
  lea    (%rdi,%rdx,2),%r13
  lea    D7(%rip),%r12
L4:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  add    $0x2,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %2hhx

assistant: ```c
void hex_to_char_array(unsigned char *hex, unsigned char *buffer, int buff_size) {
  int i;
  for (i = 0; i < buff_size; i++) {
    sscanf(hex, "%2hhx", &buffer[i]);
    hex += 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hex_to_char_array>:
  endbr64
  test   %edx,%edx
  jle    L12
  push   %r13
  movslq %edx,%rdx
  push   %r12
  lea    (%rdi,%rdx,2),%r13
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  call   <sscanf@plt>
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %2hhx

assistant: ```c
void hex_to_char_array(unsigned char *hex, unsigned char *buffer, int buff_size) {
  int i;
  for (i = 0; i < buff_size; i++) {
    sscanf(hex, "%2hhx", &buffer[i]);
    hex += 2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hex_to_char_array>:
  endbr64
  test   %edx,%edx
  jle    L1
  push   %r13
  movslq %edx,%rdx
  push   %r12
  lea    (%rdi,%rdx,2),%r13
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  add    $0x2,%rbx
  call   <sscanf@plt>
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %2hhx

assistant: ```c
void hex_to_char_array(unsigned char *hex, unsigned char *buffer, int buff_size) {
  int i;
  for (i = 0; i < buff_size; i++) {
    sscanf(hex, "%2hhx", &buffer[i]);
    hex += 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<UARTConfigGetExpClk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x24,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x28,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x2,%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rcx
  shl    $0x6,%rcx
  mov    -0x8(%rbp),%rdx
  lea    (%rdx,%rcx,1),%rsi
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2c,%rax
  mov    (%rax),%rax
  and    $0xee,%eax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTConfigGetExpClk(unsigned long ulBase, unsigned long ulUARTClk, unsigned long *pulBaud, unsigned long *pulConfig) {
  unsigned long ulInt, ulFrac;
  ;
  ulInt = (*((volatile unsigned long *)(ulBase + 0x00000024)));
  ulFrac = (*((volatile unsigned long *)(ulBase + 0x00000028)));
  *pulBaud = (ulUARTClk * 4) / ((64 * ulInt) + ulFrac);
  *pulConfig = ((*((volatile unsigned long *)(ulBase + 0x0000002C))) & (0x00000080 | 0x00000060 | 0x00000008 | 0x00000004 | 0x00000002));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<UARTConfigGetExpClk>:
  endbr64
  mov    %rdx,%r9
  mov    %rcx,%r8
  mov    0x24(%rdi),%rcx
  mov    0x28(%rdi),%rdx
  lea    0x0(,%rsi,4),%rax
  shl    $0x6,%rcx
  add    %rdx,%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,(%r9)
  mov    0x2c(%rdi),%rax
  and    $0xee,%eax
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void UARTConfigGetExpClk(unsigned long ulBase, unsigned long ulUARTClk, unsigned long *pulBaud, unsigned long *pulConfig) {
  unsigned long ulInt, ulFrac;
  ;
  ulInt = (*((volatile unsigned long *)(ulBase + 0x00000024)));
  ulFrac = (*((volatile unsigned long *)(ulBase + 0x00000028)));
  *pulBaud = (ulUARTClk * 4) / ((64 * ulInt) + ulFrac);
  *pulConfig = ((*((volatile unsigned long *)(ulBase + 0x0000002C))) & (0x00000080 | 0x00000060 | 0x00000008 | 0x00000004 | 0x00000002));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UARTConfigGetExpClk>:
  endbr64
  mov    %rcx,%r8
  mov    0x24(%rdi),%rcx
  mov    %rdx,%r9
  mov    0x28(%rdi),%rdx
  lea    0x0(,%rsi,4),%rax
  shl    $0x6,%rcx
  add    %rdx,%rcx
  xor    %edx,%edx
  div    %rcx
  mov    %rax,(%r9)
  mov    0x2c(%rdi),%rax
  and    $0xee,%eax
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void UARTConfigGetExpClk(unsigned long ulBase, unsigned long ulUARTClk, unsigned long *pulBaud, unsigned long *pulConfig) {
  unsigned long ulInt, ulFrac;
  ;
  ulInt = (*((volatile unsigned long *)(ulBase + 0x00000024)));
  ulFrac = (*((volatile unsigned long *)(ulBase + 0x00000028)));
  *pulBaud = (ulUARTClk * 4) / ((64 * ulInt) + ulFrac);
  *pulConfig = ((*((volatile unsigned long *)(ulBase + 0x0000002C))) & (0x00000080 | 0x00000060 | 0x00000008 | 0x00000004 | 0x00000002));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<UARTConfigGetExpClk>:
  endbr64
  mov    %rcx,%r8
  mov    0x24(%rdi),%rcx
  mov    %rdx,%r9
  mov    0x28(%rdi),%rdx
  lea    0x0(,%rsi,4),%rax
  shl    $0x6,%rcx
  add    %rdx,%rcx
  xor    %edx,%edx
  div    %rcx
  mov    %rax,(%r9)
  mov    0x2c(%rdi),%rax
  and    $0xee,%eax
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void UARTConfigGetExpClk(unsigned long ulBase, unsigned long ulUARTClk, unsigned long *pulBaud, unsigned long *pulConfig) {
  unsigned long ulInt, ulFrac;
  ;
  ulInt = (*((volatile unsigned long *)(ulBase + 0x00000024)));
  ulFrac = (*((volatile unsigned long *)(ulBase + 0x00000028)));
  *pulBaud = (ulUARTClk * 4) / ((64 * ulInt) + ulFrac);
  *pulConfig = ((*((volatile unsigned long *)(ulBase + 0x0000002C))) & (0x00000080 | 0x00000060 | 0x00000008 | 0x00000004 | 0x00000002));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<separator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L9
  mov    $0x1,%eax
  jmp    L6
L9:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int separator(char ch) {
  if (!isalnum(ch))
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<separator>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int separator(char ch) {
  if (!isalnum(ch))
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<separator>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int separator(char ch) {
  if (!isalnum(ch))
    return (1);
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<separator>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int separator(char ch) {
  if (!isalnum(ch))
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x41,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  cmp    $0x41,%eax
  je     L47
  cmp    $0x42,%eax
  je     L60
  jmp    L31
L47:
  movzbl -0x1(%rbp),%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    %dl,-0x1(%rbp)
  movsbl %al,%eax
  cmp    $0x41,%eax
  je     L33
  cmp    $0x42,%eax
  je     L68
  jmp    L60
L33:
  mov    $0x41,%edi
  call   <putchar@plt>
  jmp    L60
L68:
  mov    $0x42,%edi
  call   <putchar@plt>
  nop
L60:
  mov    $0x41,%edi
  call   <putchar@plt>
  nop
L31:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  char c = 65;
  switch (c) {
  case 65:
    switch (c++) {
    case 65:
      putchar('A');
      break;
    case 66:
      putchar('B');
      break;
    }
  case 'B':
    putchar('A');
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <putchar@plt>
  mov    $0x41,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char c = 65;
  switch (c) {
  case 65:
    switch (c++) {
    case 65:
      putchar('A');
      break;
    case 66:
      putchar('B');
      break;
    }
  case 'B':
    putchar('A');
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <putchar@plt>
  mov    $0x41,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char c = 65;
  switch (c) {
  case 65:
    switch (c++) {
    case 65:
      putchar('A');
      break;
    case 66:
      putchar('B');
      break;
    }
  case 'B':
    putchar('A');
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <putchar@plt>
  mov    $0x41,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  char c = 65;
  switch (c) {
  case 65:
    switch (c++) {
    case 65:
      putchar('A');
      break;
    case 66:
      putchar('B');
      break;
    }
  case 'B':
    putchar('A');
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ne_test_gncm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xd8(%rbp)
  jmp    L64
L7:
  mov    -0xd8(%rbp),%ecx
  lea    -0xc0(%rbp),%rdx
  lea    -0xd0(%rbp),%rsi
  mov    -0xe4(%rbp),%eax
  mov    %ecx,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <ne_get_cmap_params@plt>
  mov    %eax,-0xd4(%rbp)
  cmpl   $0x0,-0xd4(%rbp)
  jns    L143
  mov    -0xd4(%rbp),%eax
  jmp    L93
L143:
  movl   $0x0,-0xe0(%rbp)
  jmp    L75
L99:
  mov    -0xe0(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%esi
  mov    -0xd8(%rbp),%edi
  lea    -0x60(%rbp),%rcx
  lea    -0xb0(%rbp),%rdx
  mov    -0xe4(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <ne_get_node_cmap@plt>
  mov    %eax,-0xd4(%rbp)
  cmpl   $0x0,-0xd4(%rbp)
  jns    L138
  mov    -0xd4(%rbp),%eax
  jmp    L93
L138:
  movl   $0x0,-0xdc(%rbp)
  jmp    L71
L140:
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  mov    -0xdc(%rbp),%edx
  add    $0x1,%edx
  add    %edx,%edx
  cmp    %edx,%eax
  je     L132
  mov    $0xffffffff,%eax
  jmp    L93
L132:
  mov    -0xdc(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%edx
  mov    -0xdc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  je     L54
  mov    $0xffffffff,%eax
  jmp    L93
L54:
  addl   $0x1,-0xdc(%rbp)
L71:
  cmpl   $0x13,-0xdc(%rbp)
  jle    L140
  addl   $0x1,-0xe0(%rbp)
L75:
  cmpl   $0x3,-0xe0(%rbp)
  jle    L99
  addl   $0x1,-0xd8(%rbp)
L64:
  cmpl   $0x9,-0xd8(%rbp)
  jle    L7
  mov    $0x0,%eax
L93:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L128
  call   <__stack_chk_fail@plt>
L128:
  leave
  ret
```

assistant: ```c
int ne_test_gncm(int fileid) {
  int i, j, iproc, error;
  int node_map_ids[4], node_map_cnts[4];
  int node_ids[20], proc_ids[20];
  for (iproc = 0; iproc < 10; iproc++) {
    error = ne_get_cmap_params(fileid, node_map_ids, node_map_cnts, NULL, NULL, iproc);
    if (error < 0)
      return error;
    for (i = 0; i < 4; i++) {
      error = ne_get_node_cmap(fileid, node_map_ids[i], node_ids, proc_ids, iproc);
      if (error < 0)
        return error;
      for (j = 0; j < 20; j++) {
        if (node_ids[j] != 2 * (j + 1))
          return -1;
        if (proc_ids[j] != 3 * (j + 1))
          return -1;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ne_test_gncm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  lea    0x10(%rsp),%r14
L16:
  mov    %rsp,%rsi
  mov    %r12d,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %r14,%rdx
  mov    %ebp,%edi
  call   <ne_get_cmap_params@plt>
  test   %eax,%eax
  js     L19
  mov    %rsp,%r13
  lea    0x70(%rsp),%rbx
L52:
  lea    0x20(%rsp),%rdx
  mov    %r12d,%r8d
  mov    %rbx,%rcx
  mov    0x0(%r13),%esi
  mov    %ebp,%edi
  call   <ne_get_node_cmap@plt>
  test   %eax,%eax
  js     L19
  mov    $0x1,%eax
  lea    0x20(%rsp),%rcx
L1:
  lea    (%rax,%rax,1),%edx
  cmp    %edx,-0x4(%rcx,%rax,4)
  jne    L83
  lea    (%rax,%rax,2),%edx
  cmp    %edx,-0x4(%rbx,%rax,4)
  jne    L67
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L1
  add    $0x4,%r13
  cmp    %r14,%r13
  jne    L52
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L16
  mov    $0x0,%eax
  jmp    L19
L83:
  mov    $0xffffffff,%eax
L19:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L67:
  mov    $0xffffffff,%eax
  jmp    L19
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_gncm(int fileid) {
  int i, j, iproc, error;
  int node_map_ids[4], node_map_cnts[4];
  int node_ids[20], proc_ids[20];
  for (iproc = 0; iproc < 10; iproc++) {
    error = ne_get_cmap_params(fileid, node_map_ids, node_map_cnts, NULL, NULL, iproc);
    if (error < 0)
      return error;
    for (i = 0; i < 4; i++) {
      error = ne_get_node_cmap(fileid, node_map_ids[i], node_ids, proc_ids, iproc);
      if (error < 0)
        return error;
      for (j = 0; j < 20; j++) {
        if (node_ids[j] != 2 * (j + 1))
          return -1;
        if (proc_ids[j] != 3 * (j + 1))
          return -1;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ne_test_gncm>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0x80(%rsp),%rbx
L17:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r14d,%r9d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <ne_get_cmap_params@plt>
  test   %eax,%eax
  js     L68
  mov    %rbp,%r15
  lea    0x30(%rsp),%r9
L82:
  mov    (%r15),%esi
  mov    %r14d,%r8d
  mov    %rbx,%rcx
  mov    %r9,%rdx
  mov    %r13d,%edi
  mov    %r9,0x8(%rsp)
  call   <ne_get_node_cmap@plt>
  test   %eax,%eax
  js     L68
  mov    0x8(%rsp),%r9
  mov    $0x1,%eax
  nopl   0x0(%rax)
L58:
  lea    (%rax,%rax,1),%edx
  cmp    %edx,-0x4(%r9,%rax,4)
  jne    L20
  add    %eax,%edx
  cmp    %edx,-0x4(%rbx,%rax,4)
  jne    L20
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L58
  add    $0x4,%r15
  cmp    %r12,%r15
  jne    L82
  add    $0x1,%r14d
  cmp    $0xa,%r14d
  jne    L17
  xor    %eax,%eax
  nopl   0x0(%rax)
L68:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  mov    $0xffffffff,%eax
  jmp    L68
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_gncm(int fileid) {
  int i, j, iproc, error;
  int node_map_ids[4], node_map_cnts[4];
  int node_ids[20], proc_ids[20];
  for (iproc = 0; iproc < 10; iproc++) {
    error = ne_get_cmap_params(fileid, node_map_ids, node_map_cnts, NULL, NULL, iproc);
    if (error < 0)
      return error;
    for (i = 0; i < 4; i++) {
      error = ne_get_node_cmap(fileid, node_map_ids[i], node_ids, proc_ids, iproc);
      if (error < 0)
        return error;
      for (j = 0; j < 20; j++) {
        if (node_ids[j] != 2 * (j + 1))
          return -1;
        if (proc_ids[j] != 3 * (j + 1))
          return -1;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ne_test_gncm>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  lea    0x10(%rsp),%rbp
  lea    0x80(%rsp),%rbx
L42:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r14d,%r9d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <ne_get_cmap_params@plt>
  test   %eax,%eax
  js     L33
  mov    %rbp,%r15
  lea    0x30(%rsp),%r9
L37:
  mov    (%r15),%esi
  mov    %r14d,%r8d
  mov    %rbx,%rcx
  mov    %r9,%rdx
  mov    %r13d,%edi
  mov    %r9,0x8(%rsp)
  call   <ne_get_node_cmap@plt>
  test   %eax,%eax
  js     L33
  mov    0x8(%rsp),%r9
  mov    $0x1,%eax
  nopl   0x0(%rax)
L80:
  lea    (%rax,%rax,1),%edx
  cmp    %edx,-0x4(%r9,%rax,4)
  jne    L61
  add    %eax,%edx
  cmp    %edx,-0x4(%rbx,%rax,4)
  jne    L61
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L80
  add    $0x4,%r15
  cmp    %r12,%r15
  jne    L37
  add    $0x1,%r14d
  cmp    $0xa,%r14d
  jne    L42
  xor    %eax,%eax
  nopl   0x0(%rax)
L33:
  mov    0xd8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L64
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L61:
  mov    $0xffffffff,%eax
  jmp    L33
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_gncm(int fileid) {
  int i, j, iproc, error;
  int node_map_ids[4], node_map_cnts[4];
  int node_ids[20], proc_ids[20];
  for (iproc = 0; iproc < 10; iproc++) {
    error = ne_get_cmap_params(fileid, node_map_ids, node_map_cnts, NULL, NULL, iproc);
    if (error < 0)
      return error;
    for (i = 0; i < 4; i++) {
      error = ne_get_node_cmap(fileid, node_map_ids[i], node_ids, proc_ids, iproc);
      if (error < 0)
        return error;
      for (j = 0; j < 20; j++) {
        if (node_ids[j] != 2 * (j + 1))
          return -1;
        if (proc_ids[j] != 3 * (j + 1))
          return -1;
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allocate_contiguous_vframe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0xc,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0xfff,%eax
  test   %eax,%eax
  je     L12
  addl   $0x1,-0x20(%rbp)
L12:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <get_next_available_virtual_frame@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L16
L22:
  mov    -0x1c(%rbp),%eax
  shl    $0xc,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <allocate_frame@plt>
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <map_page@plt>
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  ja     L22
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void *allocate_contiguous_vframe(unsigned int size) {
  unsigned int num_of_frames = (size / 0x1000);
  if (size % 0x1000) {
    num_of_frames++;
  }
  void *vframe = get_next_available_virtual_frame(num_of_frames);
  for (int i = 0; i < num_of_frames; i++) {
    map_page(allocate_frame(), vframe + 0x1000 * i, 2);
  }
  return vframe;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<allocate_contiguous_vframe>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  shr    $0xc,%r12d
  test   $0xfff,%edi
  je     L16
  add    $0x1,%r12d
  mov    %r12d,%edi
  call   <get_next_available_virtual_frame@plt>
  mov    %rax,%r13
L24:
  mov    %r13,%rbp
  mov    $0x0,%ebx
L23:
  mov    $0x0,%eax
  call   <allocate_frame@plt>
  mov    %eax,%edi
  mov    $0x2,%edx
  mov    %rbp,%rsi
  call   <map_page@plt>
  add    $0x1,%ebx
  add    $0x1000,%rbp
  cmp    %ebx,%r12d
  ja     L23
L34:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    %edi,%ebx
  mov    %r12d,%edi
  call   <get_next_available_virtual_frame@plt>
  mov    %rax,%r13
  cmp    $0xfff,%ebx
  ja     L24
  jmp    L34
```

assistant: ```c
void *allocate_contiguous_vframe(unsigned int size) {
  unsigned int num_of_frames = (size / 0x1000);
  if (size % 0x1000) {
    num_of_frames++;
  }
  void *vframe = get_next_available_virtual_frame(num_of_frames);
  for (int i = 0; i < num_of_frames; i++) {
    map_page(allocate_frame(), vframe + 0x1000 * i, 2);
  }
  return vframe;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocate_contiguous_vframe>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  shr    $0xc,%r12d
  push   %rbx
  sub    $0x8,%rsp
  and    $0xfff,%edi
  je     L16
  add    $0x1,%r12d
  mov    %r12d,%edi
  call   <get_next_available_virtual_frame@plt>
  mov    %rax,%r13
L4:
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <allocate_frame@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edx
  add    $0x1000,%rbp
  mov    %eax,%edi
  call   <map_page@plt>
  cmp    %ebx,%r12d
  ja     L5
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r12d,%edi
  call   <get_next_available_virtual_frame@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jne    L4
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *allocate_contiguous_vframe(unsigned int size) {
  unsigned int num_of_frames = (size / 0x1000);
  if (size % 0x1000) {
    num_of_frames++;
  }
  void *vframe = get_next_available_virtual_frame(num_of_frames);
  for (int i = 0; i < num_of_frames; i++) {
    map_page(allocate_frame(), vframe + 0x1000 * i, 2);
  }
  return vframe;
}
```