ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_comb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L85
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L72:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L73:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L72
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <islast@plt>
  test   %eax,%eax
  jne    L29
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L29
L81:
  cmpl   $0x0,-0x18(%rbp)
  jle    L68
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L68
  addl   $0x1,-0x8(%rbp)
  jmp    L85
L68:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <ft_comb>
  addl   $0x1,-0x8(%rbp)
L85:
  cmpl   $0x9,-0x8(%rbp)
  jle    L81
  jmp    L25
L29:
  nop
L25:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D4
type: string

tool: D5: %d

tool: D4: , 

assistant: ```c
void ft_comb(int n, int nb[], int index) {
  int count;
  count = 0;
  if (index == n) {
    for (int i = 0; i < n; i++)
      printf("%d", nb[i]);
    if (!islast(n, nb))
      printf(", ");
    return;
  }
  while (count < 10) {
    if (index > 0 && nb[index - 1] >= count) {
      count++;
      continue;
    } else {
      nb[index] = count;
      ft_comb(n, nb, index + 1);
    }
    count++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_comb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r13
  cmp    %edi,%edx
  je     L39
  mov    %edx,%ebp
  movslq %edx,%r14
  shl    $0x2,%r14
  lea    -0x4(%rsi,%r14,1),%r12
  add    %rsi,%r14
  mov    $0x0,%ebx
  lea    0x1(%rdx),%eax
  mov    %eax,0xc(%rsp)
  jmp    L46
L39:
  test   %edi,%edi
  jle    L44
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
  lea    D0(%rip),%rbp
L47:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L47
L44:
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <islast@plt>
  test   %eax,%eax
  je     L97
L59:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L59
L52:
  lea    0x1(%rbx),%eax
L32:
  add    $0x1,%ebx
  cmp    $0x9,%eax
  jg     L59
L46:
  mov    %ebx,%eax
  test   %ebp,%ebp
  jle    L42
  cmp    %ebx,(%r12)
  jge    L52
L42:
  mov    %eax,(%r14)
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <ft_comb>
  lea    0x1(%rbx),%eax
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D0: %d

tool: D7: , 

assistant: ```c
void ft_comb(int n, int nb[], int index) {
  int count;
  count = 0;
  if (index == n) {
    for (int i = 0; i < n; i++)
      printf("%d", nb[i]);
    if (!islast(n, nb))
      printf(", ");
    return;
  }
  while (count < 10) {
    if (index > 0 && nb[index - 1] >= count) {
      count++;
      continue;
    } else {
      nb[index] = count;
      ft_comb(n, nb, index + 1);
    }
    count++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_comb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %edi,%edx
  je     L29
  movslq %edx,%rax
  mov    %edx,%ebp
  lea    0x1(%rdx),%r15d
  xor    %ebx,%ebx
  shl    $0x2,%rax
  lea    -0x4(%rsi,%rax,1),%r14
  add    %rsi,%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L49:
  test   %ebp,%ebp
  jle    L12
  cmp    %ebx,(%r14)
  jge    L8
L12:
  mov    0x8(%rsp),%rax
  mov    %r15d,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  mov    %ebx,(%rax)
  call   <ft_comb>
L8:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L49
L54:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L29:
  test   %edi,%edi
  jle    L53
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    D7(%rip),%rbp
  lea    0x4(%rsi,%rax,4),%r14
  xchg   %ax,%ax
L62:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L62
L53:
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <islast@plt>
  test   %eax,%eax
  jne    L54
  add    $0x18,%rsp
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string

tool: D7: %d

tool: D6: , 

assistant: ```c
void ft_comb(int n, int nb[], int index) {
  int count;
  count = 0;
  if (index == n) {
    for (int i = 0; i < n; i++)
      printf("%d", nb[i]);
    if (!islast(n, nb))
      printf(", ");
    return;
  }
  while (count < 10) {
    if (index > 0 && nb[index - 1] >= count) {
      count++;
      continue;
    } else {
      nb[index] = count;
      ft_comb(n, nb, index + 1);
    }
    count++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_comb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edi,%edx
  je     L48
  movslq %edx,%r12
  xor    %ebx,%ebx
  lea    0x1(%rdx),%r15d
  shl    $0x2,%r12
  lea    -0x4(%rsi,%r12,1),%r14
  add    %rsi,%r12
  test   %edx,%edx
  jle    L7
  nopl   0x0(%rax)
L33:
  cmp    %ebx,(%r14)
  jge    L49
  mov    %ebx,(%r12)
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <ft_comb>
L49:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L33
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L48:
  test   %edi,%edi
  jle    L40
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    D9(%rip),%r12
  lea    0x4(%rsi,%rax,4),%r14
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L44
L40:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <islast@plt>
  test   %eax,%eax
  jne    L67
  add    $0x8,%rsp
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
L7:
  mov    %r15d,%r14d
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %ebx,%eax
  mov    %r14d,%edx
  add    $0x1,%ebx
  mov    %rbp,%rsi
  mov    %eax,(%r12)
  mov    %r13d,%edi
  call   <ft_comb>
  cmp    $0xa,%ebx
  jne    L45
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D1
type: string

tool: D9: %d

tool: D1: , 

assistant: ```c
void ft_comb(int n, int nb[], int index) {
  int count;
  count = 0;
  if (index == n) {
    for (int i = 0; i < n; i++)
      printf("%d", nb[i]);
    if (!islast(n, nb))
      printf(", ");
    return;
  }
  while (count < 10) {
    if (index > 0 && nb[index - 1] >= count) {
      count++;
      continue;
    } else {
      nb[index] = count;
      ft_comb(n, nb, index + 1);
    }
    count++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Whitening@plt>
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DecryptionPrinceCore@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Whitening@plt>
  nop
  leave
  ret
```

assistant: ```c
void Decrypt(uint8_t *block, uint8_t *roundKeys) {
  Whitening(block, &roundKeys[8]);
  DecryptionPrinceCore(block, &roundKeys[16]);
  Whitening(block, roundKeys);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Decrypt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    0x20(%rsi),%rsi
  call   <Whitening@plt>
  lea    0x40(%rbp),%rsi
  mov    %rbx,%rdi
  call   <DecryptionPrinceCore@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <Whitening@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void Decrypt(uint8_t *block, uint8_t *roundKeys) {
  Whitening(block, &roundKeys[8]);
  DecryptionPrinceCore(block, &roundKeys[16]);
  Whitening(block, roundKeys);
}
```
user: What is the c source code of the assembly code below?

```asm
<Decrypt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    0x20(%rsi),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <Whitening@plt>
  lea    0x40(%r12),%rsi
  mov    %rbp,%rdi
  call   <DecryptionPrinceCore@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <Whitening@plt>
```

assistant: ```c
void Decrypt(uint8_t *block, uint8_t *roundKeys) {
  Whitening(block, &roundKeys[8]);
  DecryptionPrinceCore(block, &roundKeys[16]);
  Whitening(block, roundKeys);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Decrypt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    0x20(%rsi),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <Whitening@plt>
  lea    0x40(%r12),%rsi
  mov    %rbp,%rdi
  call   <DecryptionPrinceCore@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <Whitening@plt>
```

assistant: ```c
void Decrypt(uint8_t *block, uint8_t *roundKeys) {
  Whitening(block, &roundKeys[8]);
  DecryptionPrinceCore(block, &roundKeys[16]);
  Whitening(block, roundKeys);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void str_tolower(char *str) {
  char *c = str;
  while (*c) {
    *c = tolower(*c);
    c++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L18:
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L17:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *str) {
  char *c = str;
  while (*c) {
    *c = tolower(*c);
    c++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L19:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L14:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *str) {
  char *c = str;
  while (*c) {
    *c = tolower(*c);
    c++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<str_tolower>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L10
L18:
  call   <tolower@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L18
L10:
  pop    %rbx
  ret
```

assistant: ```c
void str_tolower(char *str) {
  char *c = str;
  while (*c) {
    *c = tolower(*c);
    c++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<intlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int intlen(int num) {
  int i = 0;
  while (num) {
    num /= 10;
    i++;
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<intlen>:
  endbr64
  test   %edi,%edi
  je     L7
  mov    $0x0,%edx
L19:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  add    $0x1,%edx
  test   %eax,%eax
  jne    L19
L18:
  mov    %edx,%eax
  ret
L7:
  mov    %edi,%edx
  jmp    L18
```

assistant: ```c
int intlen(int num) {
  int i = 0;
  while (num) {
    num /= 10;
    i++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<intlen>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L10
  nopl   0x0(%rax,%rax,1)
L0:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L0
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int intlen(int num) {
  int i = 0;
  while (num) {
    num /= 10;
    i++;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intlen>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L0
  nopl   0x0(%rax,%rax,1)
L4:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L4
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int intlen(int num) {
  int i = 0;
  while (num) {
    num /= 10;
    i++;
  }
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DecompressBlockBC2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %edx,-0x6c(%rbp)
  mov    %rcx,-0x78(%rbp)
  mov    %r8,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L9
L6:
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x5c(%rbp),%eax
  lea    0x0(,%rax,4),%ecx
  mov    %edx,%eax
  shl    $0x4,%eax
  add    %eax,%edx
  movslq %ecx,%rax
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x5c(%rbp),%eax
  shl    $0x2,%eax
  lea    0x1(%rax),%ecx
  mov    %edx,%eax
  shl    $0x4,%eax
  add    %eax,%edx
  movslq %ecx,%rax
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x5c(%rbp),%eax
  shl    $0x2,%eax
  lea    0x2(%rax),%ecx
  mov    %edx,%eax
  shl    $0x4,%eax
  add    %eax,%edx
  movslq %ecx,%rax
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
  sar    $0xc,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x5c(%rbp),%eax
  shl    $0x2,%eax
  lea    0x3(%rax),%ecx
  mov    %edx,%eax
  shl    $0x4,%eax
  add    %eax,%edx
  movslq %ecx,%rax
  mov    %edx,-0x50(%rbp,%rax,4)
  addq   $0x8,-0x78(%rbp)
  addl   $0x1,-0x5c(%rbp)
L9:
  cmpl   $0x3,-0x5c(%rbp)
  jle    L6
  mov    -0x64(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x68(%rbp),%eax
  imul   -0x6c(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x80(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  lea    -0x50(%rbp),%rcx
  mov    -0x6c(%rbp),%edx
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <DecompressBlockBC1Internal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void DecompressBlockBC2(uint32_t x, uint32_t y, uint32_t stride, const uint8_t *blockStorage, unsigned char *image) {
  int i;
  uint8_t alphaValues[16] = {0};
  for (i = 0; i < 4; ++i) {
    const uint16_t *alphaData = (const uint16_t *)(blockStorage);
    alphaValues[i * 4 + 0] = (((*alphaData) >> 0) & 0xF) * 17;
    alphaValues[i * 4 + 1] = (((*alphaData) >> 4) & 0xF) * 17;
    alphaValues[i * 4 + 2] = (((*alphaData) >> 8) & 0xF) * 17;
    alphaValues[i * 4 + 3] = (((*alphaData) >> 12) & 0xF) * 17;
    blockStorage += 2;
  }
  DecompressBlockBC1Internal(blockStorage, image + x * sizeof(uint32_t) + (y * stride), stride, alphaValues);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DecompressBlockBC2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%r11d
  mov    %esi,%r10d
  mov    %edx,%ebx
  mov    %rcx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  mov    %rsp,%rdx
  lea    0x40(%rsp),%rsi
  mov    %rcx,%r9
L6:
  mov    (%r9),%eax
  mov    %eax,%ebp
  and    $0xf,%ebp
  mov    %ebp,%ecx
  shl    $0x4,%ecx
  add    %ebp,%ecx
  mov    %ecx,(%rdx)
  mov    %eax,%ecx
  sar    $0x4,%ecx
  and    $0xf,%ecx
  mov    %ecx,%ebp
  shl    $0x4,%ebp
  add    %ebp,%ecx
  mov    %ecx,0x4(%rdx)
  mov    %eax,%ecx
  sar    $0x8,%ecx
  and    $0xf,%ecx
  mov    %ecx,%ebp
  shl    $0x4,%ebp
  add    %ebp,%ecx
  mov    %ecx,0x8(%rdx)
  sar    $0xc,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  add    %ecx,%eax
  mov    %eax,0xc(%rdx)
  add    $0x8,%r9
  add    $0x10,%rdx
  cmp    %rsi,%rdx
  jne    L6
  mov    %rsp,%rcx
  movslq %r11d,%r11
  imul   %ebx,%r10d
  movslq %r10d,%r10
  lea    (%r10,%r11,4),%rax
  lea    (%r8,%rax,1),%rsi
  add    $0x20,%rdi
  mov    %ebx,%edx
  call   <DecompressBlockBC1Internal@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DecompressBlockBC2(uint32_t x, uint32_t y, uint32_t stride, const uint8_t *blockStorage, unsigned char *image) {
  int i;
  uint8_t alphaValues[16] = {0};
  for (i = 0; i < 4; ++i) {
    const uint16_t *alphaData = (const uint16_t *)(blockStorage);
    alphaValues[i * 4 + 0] = (((*alphaData) >> 0) & 0xF) * 17;
    alphaValues[i * 4 + 1] = (((*alphaData) >> 4) & 0xF) * 17;
    alphaValues[i * 4 + 2] = (((*alphaData) >> 8) & 0xF) * 17;
    alphaValues[i * 4 + 3] = (((*alphaData) >> 12) & 0xF) * 17;
    blockStorage += 2;
  }
  DecompressBlockBC1Internal(blockStorage, image + x * sizeof(uint32_t) + (y * stride), stride, alphaValues);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<DecompressBlockBC2>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  movslq %edi,%r11
  mov    %esi,%r10d
  push   %r12
  mov    %rcx,%rdi
  mov    %edx,%r12d
  mov    %rcx,%r9
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movaps %xmm0,(%rsp)
  lea    0x40(%rsp),%rsi
  movaps %xmm0,0x10(%rsp)
  mov    %r13,%rdx
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
L16:
  mov    (%r9),%eax
  add    $0x10,%rdx
  add    $0x8,%r9
  mov    %eax,%ebx
  and    $0xf,%ebx
  mov    %ebx,%ecx
  shl    $0x4,%ecx
  add    %ebx,%ecx
  mov    %ecx,-0x10(%rdx)
  mov    %eax,%ecx
  sar    $0x4,%ecx
  and    $0xf,%ecx
  mov    %ecx,%ebx
  shl    $0x4,%ebx
  add    %ebx,%ecx
  mov    %ecx,-0xc(%rdx)
  mov    %eax,%ecx
  sar    $0xc,%eax
  sar    $0x8,%ecx
  and    $0xf,%eax
  and    $0xf,%ecx
  mov    %ecx,%ebx
  shl    $0x4,%ebx
  add    %ebx,%ecx
  mov    %ecx,-0x8(%rdx)
  mov    %eax,%ecx
  shl    $0x4,%ecx
  add    %ecx,%eax
  mov    %eax,-0x4(%rdx)
  cmp    %rdx,%rsi
  jne    L16
  imul   %r12d,%r10d
  add    $0x20,%rdi
  mov    %r13,%rcx
  mov    %r12d,%edx
  movslq %r10d,%r10
  lea    (%r10,%r11,4),%rax
  lea    (%r8,%rax,1),%rsi
  call   <DecompressBlockBC1Internal@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x50,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void DecompressBlockBC2(uint32_t x, uint32_t y, uint32_t stride, const uint8_t *blockStorage, unsigned char *image) {
  int i;
  uint8_t alphaValues[16] = {0};
  for (i = 0; i < 4; ++i) {
    const uint16_t *alphaData = (const uint16_t *)(blockStorage);
    alphaValues[i * 4 + 0] = (((*alphaData) >> 0) & 0xF) * 17;
    alphaValues[i * 4 + 1] = (((*alphaData) >> 4) & 0xF) * 17;
    alphaValues[i * 4 + 2] = (((*alphaData) >> 8) & 0xF) * 17;
    alphaValues[i * 4 + 3] = (((*alphaData) >> 12) & 0xF) * 17;
    blockStorage += 2;
  }
  DecompressBlockBC1Internal(blockStorage, image + x * sizeof(uint32_t) + (y * stride), stride, alphaValues);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x5,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  or     -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_bit(int nr, void *addr) {
  unsigned long mask = 1 << (nr & 0x1f);
  unsigned long *p = ((unsigned long *)addr) + (nr >> 5);
  *p |= mask;
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_bit>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%edx
  sar    $0x5,%edx
  movslq %edx,%rdx
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rax,(%rsi,%rdx,8)
  ret
```

assistant: ```c
void set_bit(int nr, void *addr) {
  unsigned long mask = 1 << (nr & 0x1f);
  unsigned long *p = ((unsigned long *)addr) + (nr >> 5);
  *p |= mask;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_bit>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  mov    $0x1,%eax
  sar    $0x5,%edx
  shl    %cl,%eax
  movslq %edx,%rdx
  cltq
  or     %rax,(%rsi,%rdx,8)
  ret
```

assistant: ```c
void set_bit(int nr, void *addr) {
  unsigned long mask = 1 << (nr & 0x1f);
  unsigned long *p = ((unsigned long *)addr) + (nr >> 5);
  *p |= mask;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_bit>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  mov    $0x1,%eax
  sar    $0x5,%edx
  shl    %cl,%eax
  movslq %edx,%rdx
  cltq
  or     %rax,(%rsi,%rdx,8)
  ret
```

assistant: ```c
void set_bit(int nr, void *addr) {
  unsigned long mask = 1 << (nr & 0x1f);
  unsigned long *p = ((unsigned long *)addr) + (nr >> 5);
  *p |= mask;
  return;
}
```