ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_open>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    D40(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L13
  mov    %rsp,%r13
  mov    %eax,%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <cfsetispeed@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <cfsetospeed@plt>
  mov    D112(%rip),%rdx
  mov    D87(%rip),%rax
  mov    %r12d,%edi
  mov    D193(%rip),%rcx
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D215(%rip),%rdx
  or     (%rdx),%eax
  mov    D64(%rip),%rdx
  not    %eax
  and    (%rsp),%eax
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D234(%rip),%rcx
  or     (%rcx),%edx
  or     %edx,%eax
  mov    D187(%rip),%rdx
  movd   %eax,%xmm0
  mov    D84(%rip),%rax
  mov    (%rax),%eax
  or     (%rdx),%eax
  mov    D225(%rip),%rdx
  or     (%rdx),%eax
  mov    D158(%rip),%rdx
  or     (%rdx),%eax
  mov    D71(%rip),%rdx
  or     (%rdx),%eax
  mov    D86(%rip),%rdx
  or     (%rdx),%eax
  mov    D239(%rip),%rdx
  or     (%rdx),%eax
  mov    D236(%rip),%rdx
  or     (%rdx),%eax
  mov    D203(%rip),%rdx
  or     (%rdx),%eax
  mov    D23(%rip),%rdx
  or     (%rdx),%eax
  mov    D66(%rip),%rdx
  mov    D34(%rip),%rcx
  or     (%rdx),%eax
  mov    D148(%rip),%rdx
  not    %eax
  and    0x4(%rsp),%eax
  mov    (%rdx),%edx
  or     (%rcx),%edx
  movd   %eax,%xmm3
  mov    D9(%rip),%rcx
  mov    D140(%rip),%rax
  punpckldq %xmm3,%xmm0
  or     (%rcx),%edx
  mov    D248(%rip),%rcx
  not    %edx
  and    0x8(%rsp),%edx
  mov    (%rax),%esi
  movd   %edx,%xmm1
  mov    D184(%rip),%rdx
  mov    (%rdx),%edx
  or     (%rcx),%edx
  mov    D10(%rip),%rcx
  or     (%rcx),%edx
  mov    D216(%rip),%rcx
  or     (%rcx),%edx
  mov    D1(%rip),%rcx
  or     (%rcx),%edx
  not    %edx
  and    0xc(%rsp),%edx
  movd   %edx,%xmm2
  mov    %r13,%rdx
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <tcsetattr@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int serial_open(char *port, int baud) {
  struct termios options;
  int fd;
  fd = open(port, O_RDWR);
  if (fd == -1) {
    return fd;
  }
  tcgetattr(fd, &options);
  cfsetispeed(&options, baud);
  cfsetospeed(&options, baud);
  options.c_cflag &= ~(PARENB | CSIZE | CSTOPB | CSIZE);
  options.c_cflag |= (CLOCAL | CREAD | CS8);
  options.c_iflag &= ~(ICRNL | INLCR | INPCK | IXON | IXOFF | IXANY | IGNBRK | BRKINT | PARMRK | ISTRIP | IGNCR);
  options.c_oflag &= ~(ONLCR | OCRNL | OPOST);
  options.c_lflag &= ~(ECHO | ECHONL | ICANON | ISIG | IEXTEN);
  tcsetattr(fd, TCSANOW, &options);
  return fd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chopcrlf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L11:
  cmpl   $0x1,-0x4(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void chopcrlf(str) char *str;
{
  int i;
  i = strlen(str);
  if (i >= 1 && str[i - 1] == '\n')
    str[i - 1] = 0;
  if (i >= 2 && str[i - 2] == '\r')
    str[i - 2] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chopcrlf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L53
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  cmpb   $0xa,(%rdx)
  je     L18
L53:
  cmp    $0x1,%eax
  jle    L17
  cltq
  lea    -0x2(%rbx,%rax,1),%rax
  cmpb   $0xd,(%rax)
  je     L34
L17:
  pop    %rbx
  ret
L18:
  movb   $0x0,(%rdx)
  jmp    L53
L34:
  movb   $0x0,(%rax)
  jmp    L17
```

assistant: ```c
void chopcrlf(str) char *str;
{
  int i;
  i = strlen(str);
  if (i >= 1 && str[i - 1] == '\n')
    str[i - 1] = 0;
  if (i >= 2 && str[i - 2] == '\r')
    str[i - 2] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<chopcrlf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rcx
  cmpb   $0xa,(%rcx)
  je     L36
L34:
  cmp    $0x1,%eax
  je     L2
  lea    -0x2(%rbx,%rdx,1),%rax
  cmpb   $0xd,(%rax)
  je     L29
L2:
  pop    %rbx
  ret
  nop
L29:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
  nopl   (%rax)
L36:
  movb   $0x0,(%rcx)
  jmp    L34
```

assistant: ```c
void chopcrlf(str) char *str;
{
  int i;
  i = strlen(str);
  if (i >= 1 && str[i - 1] == '\n')
    str[i - 1] = 0;
  if (i >= 2 && str[i - 2] == '\r')
    str[i - 2] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chopcrlf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L28
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rcx
  cmpb   $0xa,(%rcx)
  je     L35
L24:
  cmp    $0x1,%eax
  je     L28
  lea    -0x2(%rbx,%rdx,1),%rax
  cmpb   $0xd,(%rax)
  je     L38
L28:
  pop    %rbx
  ret
  nop
L38:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
  nopl   (%rax)
L35:
  movb   $0x0,(%rcx)
  jmp    L24
```

assistant: ```c
void chopcrlf(str) char *str;
{
  int i;
  i = strlen(str);
  if (i >= 1 && str[i - 1] == '\n')
    str[i - 1] = 0;
  if (i >= 2 && str[i - 2] == '\r')
    str[i - 2] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <alloca@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%eax
  cltq
  shr    $0x2,%rax
  mov    %eax,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L5
L9:
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    (%rax),%eax
  xor    %eax,%ebx
  addl   $0x1,-0x3c(%rbp)
L5:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  mov    -0x38(%rbp),%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%edx
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L11
  lea    -0x1c(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x4,%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  lea    -0x1c(%rbp),%rcx
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%ebx
L11:
  movslq %ebx,%rax
  imul   $0xffffffff80060049,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0xd,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3ffd,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int str_hash(char *s) {
  int *p;
  char *ss;
  int i, n, l;
  register int h = 0;
  char buf[sizeof(int)];
  l = strlen(s);
  ss = alloca(l + 1);
  strcpy(ss, s);
  n = l / sizeof(int);
  p = (int *)ss;
  for (i = 0; i < n; i++) {
    h ^= *p++;
  }
  n = l - n * sizeof(int);
  if (n != 0) {
    memset(buf, 0, sizeof(buf));
    strncpy(buf + n, (char *)p, 4 - n);
    p = (int *)buf;
    h ^= *p;
  }
  return h % 16381;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r14d
  lea    0x1(%rax),%edi
  call   <alloca@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movslq %r14d,%rax
  shr    $0x2,%rax
  test   %eax,%eax
  jle    L29
  lea    -0x1(%rax),%edx
  lea    0x4(%rbx,%rdx,4),%r13
  mov    $0x0,%r12d
L40:
  add    $0x4,%rbx
  xor    -0x4(%rbx),%r12d
  cmp    %r13,%rbx
  jne    L40
L5:
  shl    $0x2,%eax
  sub    %eax,%r14d
  jne    L15
L9:
  movslq %r12d,%rax
  imul   $0xffffffff80060049,%rax,%rax
  shr    $0x20,%rax
  add    %r12d,%eax
  sar    $0xd,%eax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3ffd,%eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L29:
  mov    %rbx,%r13
  mov    $0x0,%r12d
  jmp    L5
L15:
  lea    -0x2c(%rbp),%rbx
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  sub    %r14d,%edx
  movslq %r14d,%r14
  lea    (%rbx,%r14,1),%rdi
  mov    %r13,%rsi
  call   <strncpy@plt>
  xor    -0x2c(%rbp),%r12d
  jmp    L9
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_hash(char *s) {
  int *p;
  char *ss;
  int i, n, l;
  register int h = 0;
  char buf[sizeof(int)];
  l = strlen(s);
  ss = alloca(l + 1);
  strcpy(ss, s);
  n = l / sizeof(int);
  p = (int *)ss;
  for (i = 0; i < n; i++) {
    h ^= *p++;
  }
  n = l - n * sizeof(int);
  if (n != 0) {
    memset(buf, 0, sizeof(buf));
    strncpy(buf + n, (char *)p, 4 - n);
    p = (int *)buf;
    h ^= *p;
  }
  return h % 16381;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%r14d
  call   <alloca@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <strcpy@plt>
  movslq %r14d,%rax
  shr    $0x2,%rax
  test   %eax,%eax
  jle    L52
  lea    -0x1(%rax),%edx
  xor    %r12d,%r12d
  lea    0x4(%rbx,%rdx,4),%r13
  nopl   (%rax)
L12:
  add    $0x4,%rbx
  xor    -0x4(%rbx),%r12d
  cmp    %r13,%rbx
  jne    L12
L10:
  shl    $0x2,%eax
  sub    %eax,%r14d
  jne    L31
L35:
  movslq %r12d,%rax
  mov    %r12d,%edx
  imul   $0xffffffff80060049,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  add    %r12d,%eax
  sar    $0xd,%eax
  sub    %edx,%eax
  imul   $0x3ffd,%eax,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  lea    -0x2c(%rbp),%rbx
  mov    $0x4,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  sub    %r14d,%edx
  movslq %r14d,%r14
  lea    (%rbx,%r14,1),%rdi
  call   <strncpy@plt>
  xor    -0x2c(%rbp),%r12d
  jmp    L35
L52:
  mov    %rbx,%r13
  xor    %r12d,%r12d
  jmp    L10
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_hash(char *s) {
  int *p;
  char *ss;
  int i, n, l;
  register int h = 0;
  char buf[sizeof(int)];
  l = strlen(s);
  ss = alloca(l + 1);
  strcpy(ss, s);
  n = l / sizeof(int);
  p = (int *)ss;
  for (i = 0; i < n; i++) {
    h ^= *p++;
  }
  n = l - n * sizeof(int);
  if (n != 0) {
    memset(buf, 0, sizeof(buf));
    strncpy(buf + n, (char *)p, 4 - n);
    p = (int *)buf;
    h ^= *p;
  }
  return h % 16381;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  mov    %eax,%r12d
  call   <alloca@plt>
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <strcpy@plt>
  movslq %r12d,%rdx
  shr    $0x2,%rdx
  test   %edx,%edx
  jle    L13
  lea    -0x1(%rdx),%esi
  cmp    $0x2,%esi
  jbe    L31
  mov    %edx,%ecx
  mov    %r13,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%r13,%rcx,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L107:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rax,%rcx
  jne    L107
  movdqa %xmm0,%xmm1
  mov    %edx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  pxor   %xmm1,%xmm0
  mov    %eax,%ecx
  movdqa %xmm0,%xmm1
  lea    0x0(%r13,%rcx,4),%rcx
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%ebx
  cmp    %eax,%edx
  je     L100
L33:
  lea    0x1(%rax),%edi
  xor    (%rcx),%ebx
  cmp    %edi,%edx
  jle    L100
  add    $0x2,%eax
  xor    0x4(%rcx),%ebx
  cmp    %eax,%edx
  jle    L100
  xor    0x8(%rcx),%ebx
L100:
  lea    0x4(%r13,%rsi,4),%r13
L1:
  shl    $0x2,%edx
  sub    %edx,%r12d
  jne    L47
L83:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0xffffffff80060049,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0xd,%eax
  sub    %edx,%eax
  imul   $0x3ffd,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  lea    -0x2c(%rbp),%r14
  mov    $0x4,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  sub    %r12d,%edx
  movslq %r12d,%r12
  lea    (%r14,%r12,1),%rdi
  call   <strncpy@plt>
  xor    -0x2c(%rbp),%ebx
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %ebx,%ebx
  jmp    L1
L31:
  mov    %r13,%rcx
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L33
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_hash(char *s) {
  int *p;
  char *ss;
  int i, n, l;
  register int h = 0;
  char buf[sizeof(int)];
  l = strlen(s);
  ss = alloca(l + 1);
  strcpy(ss, s);
  n = l / sizeof(int);
  p = (int *)ss;
  for (i = 0; i < n; i++) {
    h ^= *p++;
  }
  n = l - n * sizeof(int);
  if (n != 0) {
    memset(buf, 0, sizeof(buf));
    strncpy(buf + n, (char *)p, 4 - n);
    p = (int *)buf;
    h ^= *p;
  }
  return h % 16381;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L55
L57:
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L41:
  mov    -0x8(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L3
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L58
L3:
  mov    $0x1,%edx
  jmp    L67
L58:
  mov    $0x0,%edx
L67:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L42:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L41
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L57
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void convert(int *src, int N) {
  int i, j;
  for (i = 0; i <= N - 1; i++)
    for (j = 0; j <= N - 1; j++)
      src[j * N + i] = src[i * N + j] || src[j * N + i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convert>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r8d
  movslq %esi,%rbp
  shl    $0x2,%rbp
  mov    %rdi,%r12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdi
  mov    $0x0,%r10d
  mov    %esi,%r11d
  neg    %r11
  shl    $0x2,%r11
  mov    $0x1,%r9d
  jmp    L43
L33:
  mov    %esi,(%rdx)
  add    $0x4,%rax
  add    %rbp,%rdx
  add    %r8d,%ecx
  cmp    %rdi,%rax
  je     L57
L52:
  mov    %r9d,%esi
  cmpl   $0x0,(%rax)
  jne    L33
  movslq %ecx,%rsi
  cmpl   $0x0,(%rbx,%rsi,4)
  setne  %sil
  movzbl %sil,%esi
  jmp    L33
L57:
  add    $0x1,%r10d
  add    %rbp,%rdi
  add    $0x4,%r12
  cmp    %r10d,%r8d
  je     L25
L43:
  lea    (%r11,%rdi,1),%rax
  mov    %r10d,%ecx
  mov    %r12,%rdx
  jmp    L52
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

assistant: ```c
void convert(int *src, int N) {
  int i, j;
  for (i = 0; i <= N - 1; i++)
    for (j = 0; j <= N - 1; j++)
      src[j * N + i] = src[i * N + j] || src[j * N + i];
}
```
user: What is the c source code of the assembly code below?

```asm
<convert>:
  endbr64
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rsi),%eax
  movslq %esi,%r9
  mov    $0xfffffffffffffffc,%r11
  xor    %r10d,%r10d
  shl    $0x2,%rax
  shl    $0x2,%r9
  lea    0x4(%rdi,%rax,1),%r8
  sub    %rax,%r11
  nopl   0x0(%rax,%rax,1)
L15:
  lea    (%r11,%r8,1),%rax
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L3:
  cmpl   $0x0,(%rax)
  mov    $0x1,%ecx
  jne    L10
  xor    %ecx,%ecx
  cmpl   $0x0,(%rdx)
  setne  %cl
L10:
  add    $0x4,%rax
  mov    %ecx,(%rdx)
  add    %r9,%rdx
  cmp    %r8,%rax
  jne    L3
  add    $0x1,%r10d
  add    %r9,%r8
  add    $0x4,%rdi
  cmp    %r10d,%esi
  jne    L15
L35:
  ret
```

assistant: ```c
void convert(int *src, int N) {
  int i, j;
  for (i = 0; i <= N - 1; i++)
    for (j = 0; j <= N - 1; j++)
      src[j * N + i] = src[i * N + j] || src[j * N + i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<convert>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  movslq %esi,%r8
  mov    $0xfffffffffffffffc,%r11
  xor    %r10d,%r10d
  shl    $0x2,%rax
  shl    $0x2,%r8
  lea    0x4(%rdi,%rax,1),%rcx
  sub    %rax,%r11
  nopl   0x0(%rax,%rax,1)
L9:
  lea    (%r11,%rcx,1),%rax
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rax),%r9d
  test   %r9d,%r9d
  jne    L32
  xor    %r9d,%r9d
  cmpl   $0x0,(%rdx)
  setne  %r9b
  add    $0x4,%rax
  mov    %r9d,(%rdx)
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L26
  add    $0x1,%r10d
  add    %r8,%rcx
  add    $0x4,%rdi
  cmp    %esi,%r10d
  jne    L9
L7:
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x4,%rax
  movl   $0x1,(%rdx)
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L26
  add    $0x1,%r10d
  add    %r8,%rcx
  add    $0x4,%rdi
  cmp    %esi,%r10d
  jne    L9
  jmp    L7
```

assistant: ```c
void convert(int *src, int N) {
  int i, j;
  for (i = 0; i <= N - 1; i++)
    for (j = 0; j <= N - 1; j++)
      src[j * N + i] = src[i * N + j] || src[j * N + i];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L27
L28:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L16
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L16:
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
L27:
  cmpq   $0x0,-0x28(%rbp)
  jne    L28
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: write

assistant: ```c
ssize_t xwrite(int fd, const void *buf, size_t count) {
  ssize_t r, r2;
  r2 = 0;
  while (count) {
    r = write(fd, buf, count);
    if (r < 0) {
      perror("write");
      exit(1);
    }
    count -= r;
    buf += r;
    r2 += r;
  }
  return r2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xwrite>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L48
  mov    %edi,%r14d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  lea    D7(%rip),%r15
  jmp    L5
L23:
  add    %rbx,%r12
  add    %rbx,%r13
  sub    %rbx,%rbp
  je     L37
L5:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <write@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jns    L23
  mov    %r15,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L23
L48:
  mov    $0x0,%r13d
L37:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: write

assistant: ```c
ssize_t xwrite(int fd, const void *buf, size_t count) {
  ssize_t r, r2;
  r2 = 0;
  while (count) {
    r = write(fd, buf, count);
    if (r < 0) {
      perror("write");
      exit(1);
    }
    count -= r;
    buf += r;
    r2 += r;
  }
  return r2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xwrite>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L44
  mov    %edi,%r13d
  mov    %rsi,%r15
  mov    %rdx,%rbp
  xor    %r12d,%r12d
  lea    D2(%rip),%r14
  jmp    L17
  nopl   0x0(%rax)
L43:
  add    %rbx,%r15
  add    %rbx,%r12
  sub    %rbx,%rbp
  je     L58
L17:
  mov    %rbp,%rdx
  mov    %r15,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jns    L43
  mov    %r14,%rdi
  add    %rbx,%r15
  add    %rbx,%r12
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  sub    %rbx,%rbp
  jne    L17
L58:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  xor    %r12d,%r12d
  jmp    L58
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: write

assistant: ```c
ssize_t xwrite(int fd, const void *buf, size_t count) {
  ssize_t r, r2;
  r2 = 0;
  while (count) {
    r = write(fd, buf, count);
    if (r < 0) {
      perror("write");
      exit(1);
    }
    count -= r;
    buf += r;
    r2 += r;
  }
  return r2;
}
```