ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L16
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L19
L16:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: Underflow - 1


assistant: ```c
int pop(int *a, int **p) {
  if (*p <= a) {
    printf("Underflow - 1\n");
    return -1;
  }
  *p -= 1;
  int x = **p;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rdi,%rax
  jbe    L4
  lea    -0x4(%rax),%rdx
  mov    %rdx,(%rsi)
  mov    -0x4(%rax),%eax
  ret
L4:
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: Underflow - 1


assistant: ```c
int pop(int *a, int **p) {
  if (*p <= a) {
    printf("Underflow - 1\n");
    return -1;
  }
  *p -= 1;
  int x = **p;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pop>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rdi,%rax
  jbe    L7
  lea    -0x4(%rax),%rdx
  mov    -0x4(%rax),%eax
  mov    %rdx,(%rsi)
  ret
L7:
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: Underflow - 1


assistant: ```c
int pop(int *a, int **p) {
  if (*p <= a) {
    printf("Underflow - 1\n");
    return -1;
  }
  *p -= 1;
  int x = **p;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pop>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rdi,%rax
  jbe    L3
  lea    -0x4(%rax),%rdx
  mov    -0x4(%rax),%eax
  mov    %rdx,(%rsi)
  ret
L3:
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: Underflow - 1


assistant: ```c
int pop(int *a, int **p) {
  if (*p <= a) {
    printf("Underflow - 1\n");
    return -1;
  }
  *p -= 1;
  int x = **p;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ipixel_fmt_position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x90(%rbp)
  movl   $0xffffffff,-0x8c(%rbp)
  movl   $0xffffffff,-0x88(%rbp)
  movl   $0xffffffff,-0x84(%rbp)
  movl   $0xffffffff,-0x80(%rbp)
  movl   $0xffffffff,-0x7c(%rbp)
  movl   $0xffffffff,-0x78(%rbp)
  movl   $0xffffffff,-0x74(%rbp)
  movl   $0x1,-0x70(%rbp)
  movl   $0xffffffff,-0x6c(%rbp)
  movl   $0xffffffff,-0x68(%rbp)
  movl   $0xffffffff,-0x64(%rbp)
  movl   $0xffffffff,-0x60(%rbp)
  movl   $0xffffffff,-0x5c(%rbp)
  movl   $0xffffffff,-0x58(%rbp)
  movl   $0xffffffff,-0x54(%rbp)
  movl   $0x2,-0x50(%rbp)
  movl   $0xffffffff,-0x4c(%rbp)
  movl   $0xffffffff,-0x48(%rbp)
  movl   $0xffffffff,-0x44(%rbp)
  movl   $0xffffffff,-0x40(%rbp)
  movl   $0xffffffff,-0x3c(%rbp)
  movl   $0xffffffff,-0x38(%rbp)
  movl   $0xffffffff,-0x34(%rbp)
  movl   $0x3,-0x30(%rbp)
  movl   $0xffffffff,-0x2c(%rbp)
  movl   $0xffffffff,-0x28(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0xffffffff,-0x20(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int ipixel_fmt_position(int shift) {
  int table[] = {0, -1, -1, -1, -1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 2, -1, -1, -1, -1, -1, -1, -1, 3, -1, -1, -1, -1, -1, -1, -1, -1};
  return table[shift];
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipixel_fmt_position>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0xffffffff,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  movl   $0xffffffff,0x18(%rsp)
  movl   $0xffffffff,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0xffffffff,0x24(%rsp)
  movl   $0xffffffff,0x28(%rsp)
  movl   $0xffffffff,0x2c(%rsp)
  movl   $0xffffffff,0x30(%rsp)
  movl   $0xffffffff,0x34(%rsp)
  movl   $0xffffffff,0x38(%rsp)
  movl   $0xffffffff,0x3c(%rsp)
  movl   $0x2,0x40(%rsp)
  movl   $0xffffffff,0x44(%rsp)
  movl   $0xffffffff,0x48(%rsp)
  movl   $0xffffffff,0x4c(%rsp)
  movl   $0xffffffff,0x50(%rsp)
  movl   $0xffffffff,0x54(%rsp)
  movl   $0xffffffff,0x58(%rsp)
  movl   $0xffffffff,0x5c(%rsp)
  movl   $0x3,0x60(%rsp)
  movl   $0xffffffff,0x64(%rsp)
  movl   $0xffffffff,0x68(%rsp)
  movl   $0xffffffff,0x6c(%rsp)
  movl   $0xffffffff,0x70(%rsp)
  movl   $0xffffffff,0x74(%rsp)
  movl   $0xffffffff,0x78(%rsp)
  movl   $0xffffffff,0x7c(%rsp)
  movl   $0xffffffff,0x80(%rsp)
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x98,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipixel_fmt_position(int shift) {
  int table[] = {0, -1, -1, -1, -1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 2, -1, -1, -1, -1, -1, -1, -1, 3, -1, -1, -1, -1, -1, -1, -1, -1};
  return table[shift];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ipixel_fmt_position>:
  endbr64
  sub    $0x98,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0xffffffff00000000,%rax
  movq   $0xffffffffffffffff,0x8(%rsp)
  movq   $0xffffffffffffffff,0x10(%rsp)
  movq   $0xffffffffffffffff,0x18(%rsp)
  movq   $0xffffffffffffffff,0x28(%rsp)
  movq   $0xffffffffffffffff,0x30(%rsp)
  movq   $0xffffffffffffffff,0x38(%rsp)
  mov    %rax,(%rsp)
  add    $0x1,%rax
  mov    %rax,0x20(%rsp)
  add    $0x1,%rax
  mov    %rax,0x40(%rsp)
  add    $0x1,%rax
  movq   $0xffffffffffffffff,0x48(%rsp)
  movq   $0xffffffffffffffff,0x50(%rsp)
  movq   $0xffffffffffffffff,0x58(%rsp)
  mov    %rax,0x60(%rsp)
  movq   $0xffffffffffffffff,0x68(%rsp)
  movq   $0xffffffffffffffff,0x70(%rsp)
  movq   $0xffffffffffffffff,0x78(%rsp)
  movl   $0xffffffff,0x80(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipixel_fmt_position(int shift) {
  int table[] = {0, -1, -1, -1, -1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 2, -1, -1, -1, -1, -1, -1, -1, 3, -1, -1, -1, -1, -1, -1, -1, -1};
  return table[shift];
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipixel_fmt_position>:
  endbr64
  sub    $0x98,%rsp
  movdqa D36(%rip),%xmm1
  movslq %edi,%rdi
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x80(%rsp)
  movaps %xmm1,0x20(%rsp)
  movdqa D35(%rip),%xmm1
  movaps %xmm0,(%rsp)
  pcmpeqd %xmm0,%xmm0
  movaps %xmm1,0x40(%rsp)
  movdqa D29(%rip),%xmm1
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm1,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x98,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D36
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D26
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D35
type_guessed: byte[16]
name: retrieve_data
arguments: data_label: D29
type_guessed: byte[16]

tool: {"D36": [0x01,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: {"D26": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: {"D35": [0x02,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: {"D29": [0x03,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

assistant: ```c
int ipixel_fmt_position(int shift) {
  int table[] = {0, -1, -1, -1, -1, -1, -1, -1, 1, -1, -1, -1, -1, -1, -1, -1, 2, -1, -1, -1, -1, -1, -1, -1, 3, -1, -1, -1, -1, -1, -1, -1, -1};
  return table[shift];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x400,-0x8(%rbp)
  movl   $0x54713,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x2,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  and    $0x9,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D42
data_type: string

tool: D42: %u


assistant: ```c
int main() {
  unsigned int a = 1024;
  unsigned int b = 345875;
  printf("%u\n", a & 2);
  printf("%u\n", a & 31);
  printf("%u\n", b & 1);
  printf("%u\n", 2458 & 3);
  printf("%u\n", b & 9);
  printf("%u\n", 0xff & 4);
  printf("%u\n", b & 31);
  printf("%u\n", b & 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x13,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %u


assistant: ```c
int main() {
  unsigned int a = 1024;
  unsigned int b = 345875;
  printf("%u\n", a & 2);
  printf("%u\n", a & 31);
  printf("%u\n", b & 1);
  printf("%u\n", 2458 & 3);
  printf("%u\n", b & 9);
  printf("%u\n", 0xff & 4);
  printf("%u\n", b & 31);
  printf("%u\n", b & 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x13,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D8: %u


assistant: ```c
int main() {
  unsigned int a = 1024;
  unsigned int b = 345875;
  printf("%u\n", a & 2);
  printf("%u\n", a & 31);
  printf("%u\n", b & 1);
  printf("%u\n", 2458 & 3);
  printf("%u\n", b & 9);
  printf("%u\n", 0xff & 4);
  printf("%u\n", b & 31);
  printf("%u\n", b & 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x13,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D8: %u


assistant: ```c
int main() {
  unsigned int a = 1024;
  unsigned int b = 345875;
  printf("%u\n", a & 2);
  printf("%u\n", a & 31);
  printf("%u\n", b & 1);
  printf("%u\n", 2458 & 3);
  printf("%u\n", b & 9);
  printf("%u\n", 0xff & 4);
  printf("%u\n", b & 31);
  printf("%u\n", b & 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x10,-0x4(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void baz(int y) {
  if (y != 0x10)
    abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<baz>:
  endbr64
  cmp    $0x10,%edi
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void baz(int y) {
  if (y != 0x10)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<baz>:
  endbr64
  cmp    $0x10,%edi
  jne    L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void baz(int y) {
  if (y != 0x10)
    abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<baz>:
  endbr64
  cmp    $0x10,%edi
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void baz(int y) {
  if (y != 0x10)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x3039,%esi
  mov    $0x0,%edi
  call   <fmt_long@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  mov    $0x0,%edi
  call   <fmt_long@plt>
  cmp    $0x6,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x3039,%esi
  mov    %rax,%rdi
  call   <fmt_long@plt>
  cmp    $0x5,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movb   $0x0,-0x40b(%rbp)
  lea    -0x410(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_diff@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x410(%rbp),%rax
  mov    $0xffffcfc7,%esi
  mov    %rax,%rdi
  call   <fmt_long@plt>
  cmp    $0x6,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movb   $0x0,-0x40a(%rbp)
  lea    -0x410(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_diff@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D8: 12345

tool: D0: -12345

assistant: ```c
int main() {
  char buf[1024];
  assert(fmt_long(0, 12345) == 5);
  assert(fmt_long(0, -12345) == 6);
  assert(fmt_long(buf, 12345) == 5);
  buf[5] = 0;
  assert((!str_diff((buf), ("12345"))));
  assert(fmt_long(buf, -12345) == 6);
  buf[6] = 0;
  assert((!str_diff((buf), ("-12345"))));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x3039,%esi
  mov    $0x0,%edi
  call   <fmt_long@plt>
  cmp    $0x5,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  mov    $0x0,%edi
  call   <fmt_long@plt>
  cmp    $0x6,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rsp,%rbx
  mov    $0x3039,%esi
  mov    %rbx,%rdi
  call   <fmt_long@plt>
  cmp    $0x5,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movb   $0x0,0x5(%rsp)
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_diff@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  mov    %rbx,%rdi
  call   <fmt_long@plt>
  cmp    $0x6,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movb   $0x0,0x6(%rsp)
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <str_diff@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D0: 12345

tool: D6: -12345

assistant: ```c
int main() {
  char buf[1024];
  assert(fmt_long(0, 12345) == 5);
  assert(fmt_long(0, -12345) == 6);
  assert(fmt_long(buf, 12345) == 5);
  buf[5] = 0;
  assert((!str_diff((buf), ("12345"))));
  assert(fmt_long(buf, -12345) == 6);
  buf[6] = 0;
  assert((!str_diff((buf), ("-12345"))));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3039,%esi
  xor    %edi,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  xor    %edi,%edi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3039,%esi
  mov    %rbp,%rdi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x5(%rsp)
  call   <str_diff@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  mov    %rbp,%rdi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x6(%rsp)
  lea    D0(%rip),%rsi
  call   <str_diff@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D8: 12345

tool: D0: -12345

assistant: ```c
int main() {
  char buf[1024];
  assert(fmt_long(0, 12345) == 5);
  assert(fmt_long(0, -12345) == 6);
  assert(fmt_long(buf, 12345) == 5);
  buf[5] = 0;
  assert((!str_diff((buf), ("12345"))));
  assert(fmt_long(buf, -12345) == 6);
  buf[6] = 0;
  assert((!str_diff((buf), ("-12345"))));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3039,%esi
  xor    %edi,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  xor    %edi,%edi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x3039,%esi
  mov    %rbp,%rdi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x5(%rsp)
  call   <str_diff@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xffffcfc7,%esi
  mov    %rbp,%rdi
  call   <fmt_long@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x6(%rsp)
  lea    D4(%rip),%rsi
  call   <str_diff@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D4
datatype: string

tool: D7: 12345

tool: D4: -12345

assistant: ```c
int main() {
  char buf[1024];
  assert(fmt_long(0, 12345) == 5);
  assert(fmt_long(0, -12345) == 6);
  assert(fmt_long(buf, 12345) == 5);
  buf[5] = 0;
  assert((!str_diff((buf), ("12345"))));
  assert(fmt_long(buf, -12345) == 6);
  buf[6] = 0;
  assert((!str_diff((buf), ("-12345"))));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L23
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L10
L8:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L15
  mov    $0x0,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  const char *p1 = (const char *)s1;
  const char *p2 = (const char *)s2;
  size_t i;
  if (0)
    ;
  else
    for (i = 0; i < n; i++, p1++, p2++)
      if (*p1 != *p2)
        return (*p1 - *p2);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L5
  mov    $0x0,%eax
L2:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L4
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L2
  mov    $0x0,%eax
  ret
L4:
  movsbl %cl,%eax
  movsbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  const char *p1 = (const char *)s1;
  const char *p2 = (const char *)s2;
  size_t i;
  if (0)
    ;
  else
    for (i = 0; i < n; i++, p1++, p2++)
      if (*p1 != *p2)
        return (*p1 - *p2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcmp>:
  endbr64
  test   %rdx,%rdx
  je     L24
  xor    %eax,%eax
  jmp    L33
  nopl   (%rax)
L28:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L24
L33:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  je     L28
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
  xchg   %ax,%ax
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  const char *p1 = (const char *)s1;
  const char *p2 = (const char *)s2;
  size_t i;
  if (0)
    ;
  else
    for (i = 0; i < n; i++, p1++, p2++)
      if (*p1 != *p2)
        return (*p1 - *p2);
  return 0;
}
```