ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<game>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <create_tab@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L33
  mov    $0x1,%eax
  jmp    L39
L33:
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <display@plt>
  test   %rax,%rax
  jne    L89
  cmpl   $0x0,-0x18(%rbp)
  jne    L89
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ia@plt>
  jmp    L23
L89:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <user@plt>
  cmp    $0x1,%eax
  jne    L23
  mov    $0x1,%eax
  jmp    L39
L23:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jg     L116
  mov    $0x2,%eax
  jmp    L149
L116:
  mov    $0x0,%eax
L149:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L20
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <display@plt>
  test   %rax,%rax
  jne    L106
  cmpl   $0x1,-0x18(%rbp)
  jg     L106
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ia@plt>
  jmp    L71
L106:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <user@plt>
  cmp    $0x1,%eax
  jne    L71
  mov    $0x1,%eax
  jmp    L39
L71:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
L20:
  cmpl   $0x0,-0xc(%rbp)
  je     L30
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_winner@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int game(int size, int mode) {
  unsigned char *rows;
  int winner;
  if ((rows = create_tab(size)) == NULL)
    return (1);
  winner = 0;
  while (winner == 0) {
    if (display(rows, size, 1, mode) == 0 && mode == 0)
      ia(rows, size);
    else if (user(rows, size) == 1)
      return (1);
    winner = (nb_alum(rows, size) < 1) * 2;
    if (winner == 0) {
      if (display(rows, size, 2, mode) == 0 && mode < 2)
        ia(rows, size);
      else if (user(rows, size) == 1)
        return (1);
      winner = (nb_alum(rows, size) < 1);
    }
  }
  print_winner(mode, winner);
  free(rows);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<game>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r12d
  call   <create_tab@plt>
  test   %rax,%rax
  je     L98
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    $0x2,%r13d
  jmp    L138
L33:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <user@plt>
  cmp    $0x1,%eax
  je     L0
L27:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <nb_alum@plt>
  mov    %r13d,%esi
  test   %eax,%eax
  jg     L73
L138:
  test   %esi,%esi
  jne    L137
  mov    %r12d,%ecx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <display@plt>
  test   %r12d,%r12d
  jne    L33
  test   %rax,%rax
  jne    L33
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <ia@plt>
  jmp    L27
L73:
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <display@plt>
  cmp    $0x1,%r12d
  jg     L21
  test   %rax,%rax
  je     L6
L21:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <user@plt>
  cmp    $0x1,%eax
  je     L0
L46:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  setle  %sil
  movzbl %sil,%esi
  jmp    L138
L6:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <ia@plt>
  jmp    L46
L137:
  mov    %r12d,%edi
  call   <print_winner@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L98:
  mov    $0x1,%eax
  jmp    L0
```

assistant: ```c
int game(int size, int mode) {
  unsigned char *rows;
  int winner;
  if ((rows = create_tab(size)) == NULL)
    return (1);
  winner = 0;
  while (winner == 0) {
    if (display(rows, size, 1, mode) == 0 && mode == 0)
      ia(rows, size);
    else if (user(rows, size) == 1)
      return (1);
    winner = (nb_alum(rows, size) < 1) * 2;
    if (winner == 0) {
      if (display(rows, size, 2, mode) == 0 && mode < 2)
        ia(rows, size);
      else if (user(rows, size) == 1)
        return (1);
      winner = (nb_alum(rows, size) < 1);
    }
  }
  print_winner(mode, winner);
  free(rows);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<game>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <create_tab@plt>
  test   %r12d,%r12d
  sete   %r13b
  mov    %rax,%rbp
  test   %rax,%rax
  je     L89
L33:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    $0x1,%edx
  call   <display@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L80
  test   %r13b,%r13b
  jne    L0
L80:
  call   <user@plt>
  cmp    $0x1,%eax
  je     L89
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jg     L109
L117:
  mov    $0x2,%esi
L10:
  mov    %r12d,%edi
  call   <print_winner@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  call   <ia@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jle    L117
L109:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    $0x2,%edx
  call   <display@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L96
  cmp    $0x1,%r12d
  jle    L16
L96:
  call   <user@plt>
  cmp    $0x1,%eax
  je     L89
L113:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jg     L33
  mov    $0x1,%esi
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L89:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <ia@plt>
  jmp    L113
```

assistant: ```c
int game(int size, int mode) {
  unsigned char *rows;
  int winner;
  if ((rows = create_tab(size)) == NULL)
    return (1);
  winner = 0;
  while (winner == 0) {
    if (display(rows, size, 1, mode) == 0 && mode == 0)
      ia(rows, size);
    else if (user(rows, size) == 1)
      return (1);
    winner = (nb_alum(rows, size) < 1) * 2;
    if (winner == 0) {
      if (display(rows, size, 2, mode) == 0 && mode < 2)
        ia(rows, size);
      else if (user(rows, size) == 1)
        return (1);
      winner = (nb_alum(rows, size) < 1);
    }
  }
  print_winner(mode, winner);
  free(rows);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<game>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <create_tab@plt>
  test   %r12d,%r12d
  sete   %r13b
  mov    %rax,%rbp
  test   %rax,%rax
  je     L76
L107:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    $0x1,%edx
  call   <display@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L20
  test   %r13b,%r13b
  jne    L1
L20:
  call   <user@plt>
  cmp    $0x1,%eax
  je     L76
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jg     L115
L80:
  mov    $0x2,%esi
L77:
  mov    %r12d,%edi
  call   <print_winner@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  call   <ia@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jle    L80
L115:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    $0x2,%edx
  call   <display@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  jne    L11
  cmp    $0x1,%r12d
  jle    L81
L11:
  call   <user@plt>
  cmp    $0x1,%eax
  je     L76
L61:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <nb_alum@plt>
  test   %eax,%eax
  jg     L107
  mov    $0x1,%esi
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L76:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  call   <ia@plt>
  jmp    L61
```

assistant: ```c
int game(int size, int mode) {
  unsigned char *rows;
  int winner;
  if ((rows = create_tab(size)) == NULL)
    return (1);
  winner = 0;
  while (winner == 0) {
    if (display(rows, size, 1, mode) == 0 && mode == 0)
      ia(rows, size);
    else if (user(rows, size) == 1)
      return (1);
    winner = (nb_alum(rows, size) < 1) * 2;
    if (winner == 0) {
      if (display(rows, size, 2, mode) == 0 && mode < 2)
        ia(rows, size);
      else if (user(rows, size) == 1)
        return (1);
      winner = (nb_alum(rows, size) < 1);
    }
  }
  print_winner(mode, winner);
  free(rows);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__ieee754_sqrtl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  lea    0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <_Qp_sqrt@plt>
  fldt   -0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
long double __ieee754_sqrtl(long double x) {
  long double ret;
  _Qp_sqrt(&ret, &x);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__ieee754_sqrtl>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x30(%rsp),%rsi
  call   <_Qp_sqrt@plt>
  fldt   (%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double __ieee754_sqrtl(long double x) {
  long double ret;
  _Qp_sqrt(&ret, &x);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ieee754_sqrtl>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x30(%rsp),%rsi
  call   <_Qp_sqrt@plt>
  fldt   (%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double __ieee754_sqrtl(long double x) {
  long double ret;
  _Qp_sqrt(&ret, &x);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ieee754_sqrtl>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x30(%rsp),%rsi
  call   <_Qp_sqrt@plt>
  fldt   (%rsp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  fstp   %st(0)
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long double __ieee754_sqrtl(long double x) {
  long double ret;
  _Qp_sqrt(&ret, &x);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<formula>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L2
  mov    $0x0,%eax
  jmp    L7
L2:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
formula(k) int k;
{
  if (k <= 0)
    return (0);
  return (((((((k * (k + 1)) / 2))))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<formula>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  jle    L2
  lea    0x1(%rdi),%edx
  imul   %edi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
L2:
  ret
```

assistant: ```c
formula(k) int k;
{
  if (k <= 0)
    return (0);
  return (((((((k * (k + 1)) / 2))))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<formula>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L4
  lea    0x1(%rdi),%eax
  imul   %edi,%eax
  sar    %eax
L4:
  ret
```

assistant: ```c
formula(k) int k;
{
  if (k <= 0)
    return (0);
  return (((((((k * (k + 1)) / 2))))));
}
```
user: What is the c source code of the assembly code below?

```asm
<formula>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L4
  lea    0x1(%rdi),%eax
  imul   %edi,%eax
  sar    %eax
L4:
  ret
```

assistant: ```c
formula(k) int k;
{
  if (k <= 0)
    return (0);
  return (((((((k * (k + 1)) / 2))))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<input_side_conv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L27:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x3,-0x4(%rbp)
  jle    L27
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x5,-0x8(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void input_side_conv(int *x, int *h, int *y) {
  int i, j;
  for (i = 0; i < (6); i++)
    for (j = 0; j < (4); j++)
      y[i + j] = y[i + j] + x[i] * h[j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<input_side_conv>:
  endbr64
  mov    $0x0,%r8d
  jmp    L21
L2:
  add    $0x1,%r8d
  add    $0x4,%rdx
  add    $0x4,%rdi
  cmp    $0x6,%r8d
  je     L10
L21:
  mov    $0x0,%eax
L25:
  mov    (%rdi),%ecx
  imul   (%rsi,%rax,1),%ecx
  add    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L25
  jmp    L2
L10:
  ret
```

assistant: ```c
void input_side_conv(int *x, int *h, int *y) {
  int i, j;
  for (i = 0; i < (6); i++)
    for (j = 0; j < (4); j++)
      y[i + j] = y[i + j] + x[i] * h[j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<input_side_conv>:
  endbr64
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
L1:
  mov    (%rdi),%ecx
  imul   (%rsi,%rax,1),%ecx
  add    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L1
  add    $0x1,%r8d
  add    $0x4,%rdx
  add    $0x4,%rdi
  cmp    $0x6,%r8d
  jne    L15
  ret
```

assistant: ```c
void input_side_conv(int *x, int *h, int *y) {
  int i, j;
  for (i = 0; i < (6); i++)
    for (j = 0; j < (4); j++)
      y[i + j] = y[i + j] + x[i] * h[j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<input_side_conv>:
  endbr64
  mov    %rdx,%rax
  mov    %rsi,%rcx
  mov    (%rsi),%edx
  imul   (%rdi),%edx
  add    %edx,(%rax)
  mov    (%rdi),%r8d
  imul   0x4(%rsi),%r8d
  add    0x4(%rax),%r8d
  mov    %r8d,0x4(%rax)
  mov    (%rdi),%esi
  imul   0x8(%rcx),%esi
  add    0x8(%rax),%esi
  mov    %esi,0x8(%rax)
  mov    0xc(%rcx),%edx
  imul   (%rdi),%edx
  add    0xc(%rax),%edx
  mov    %edx,0xc(%rax)
  mov    0x4(%rdi),%r9d
  imul   (%rcx),%r9d
  add    %r9d,%r8d
  mov    %r8d,0x4(%rax)
  mov    0x4(%rdi),%r8d
  imul   0x4(%rcx),%r8d
  add    %esi,%r8d
  mov    %r8d,0x8(%rax)
  mov    0x4(%rdi),%esi
  imul   0x8(%rcx),%esi
  add    %edx,%esi
  mov    %esi,0xc(%rax)
  mov    0x4(%rdi),%edx
  imul   0xc(%rcx),%edx
  add    0x10(%rax),%edx
  mov    %edx,0x10(%rax)
  mov    0x8(%rdi),%r9d
  imul   (%rcx),%r9d
  add    %r9d,%r8d
  mov    %r8d,0x8(%rax)
  mov    0x8(%rdi),%r8d
  imul   0x4(%rcx),%r8d
  add    %esi,%r8d
  mov    %r8d,0xc(%rax)
  mov    0x8(%rdi),%esi
  imul   0x8(%rcx),%esi
  add    %edx,%esi
  mov    %esi,0x10(%rax)
  mov    0x8(%rdi),%edx
  imul   0xc(%rcx),%edx
  add    0x14(%rax),%edx
  mov    %edx,0x14(%rax)
  mov    0xc(%rdi),%r9d
  imul   (%rcx),%r9d
  add    %r9d,%r8d
  mov    %r8d,0xc(%rax)
  mov    0xc(%rdi),%r8d
  imul   0x4(%rcx),%r8d
  add    %esi,%r8d
  mov    %r8d,0x10(%rax)
  mov    0xc(%rdi),%esi
  imul   0x8(%rcx),%esi
  add    %edx,%esi
  mov    %esi,0x14(%rax)
  mov    0xc(%rdi),%edx
  imul   0xc(%rcx),%edx
  add    0x18(%rax),%edx
  mov    %edx,0x18(%rax)
  mov    0x10(%rdi),%r9d
  imul   (%rcx),%r9d
  add    %r9d,%r8d
  mov    %r8d,0x10(%rax)
  mov    0x10(%rdi),%r8d
  imul   0x4(%rcx),%r8d
  add    %esi,%r8d
  mov    %r8d,0x14(%rax)
  mov    0x10(%rdi),%esi
  imul   0x8(%rcx),%esi
  add    %edx,%esi
  mov    %esi,0x18(%rax)
  mov    0x10(%rdi),%edx
  imul   0xc(%rcx),%edx
  add    0x1c(%rax),%edx
  mov    %edx,0x1c(%rax)
  mov    0x14(%rdi),%r9d
  imul   (%rcx),%r9d
  add    %r9d,%r8d
  mov    %r8d,0x14(%rax)
  mov    0x14(%rdi),%r8d
  imul   0x4(%rcx),%r8d
  add    %r8d,%esi
  mov    %esi,0x18(%rax)
  mov    0x14(%rdi),%esi
  imul   0x8(%rcx),%esi
  add    %esi,%edx
  mov    %edx,0x1c(%rax)
  mov    0x14(%rdi),%edx
  imul   0xc(%rcx),%edx
  add    %edx,0x20(%rax)
  ret
```

assistant: ```c
void input_side_conv(int *x, int *h, int *y) {
  int i, j;
  for (i = 0; i < (6); i++)
    for (j = 0; j < (4); j++)
      y[i + j] = y[i + j] + x[i] * h[j];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sig_pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: SIGPIPE caught


assistant: ```c
void sig_pipe(int signo) {
  printf("SIGPIPE caught\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sig_pipe>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: SIGPIPE caught


assistant: ```c
void sig_pipe(int signo) {
  printf("SIGPIPE caught\n");
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<sig_pipe>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: SIGPIPE caught


assistant: ```c
void sig_pipe(int signo) {
  printf("SIGPIPE caught\n");
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sig_pipe>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: SIGPIPE caught


assistant: ```c
void sig_pipe(int signo) {
  printf("SIGPIPE caught\n");
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func_ret_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x6,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func_ret_int(int a, int b, register int c) {
  int d;
  d = b - 6;
  return a + b + c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_ret_int>:
  endbr64
  add    %edi,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
int func_ret_int(int a, int b, register int c) {
  int d;
  d = b - 6;
  return a + b + c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<func_ret_int>:
  endbr64
  add    %edi,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
int func_ret_int(int a, int b, register int c) {
  int d;
  d = b - 6;
  return a + b + c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func_ret_int>:
  endbr64
  add    %edi,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
int func_ret_int(int a, int b, register int c) {
  int d;
  d = b - 6;
  return a + b + c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_pkt_tick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D12(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D6(%rip)
  mov    D6(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
u_int16_t get_pkt_tick() {
  static u_int16_t tick = 0;
  return ++tick;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_pkt_tick>:
  endbr64
  mov    D2(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D9(%rip)
  ret
```

assistant: ```c
u_int16_t get_pkt_tick() {
  static u_int16_t tick = 0;
  return ++tick;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_pkt_tick>:
  endbr64
  mov    D5(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D16(%rip)
  ret
```

assistant: ```c
u_int16_t get_pkt_tick() {
  static u_int16_t tick = 0;
  return ++tick;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_pkt_tick>:
  endbr64
  mov    D9(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D3(%rip)
  ret
```

assistant: ```c
u_int16_t get_pkt_tick() {
  static u_int16_t tick = 0;
  return ++tick;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L65
  mov    $0x0,%eax
  jmp    L9
L65:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L33
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L9
L33:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  je     L61
  subq   $0x1,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L65
  jmp    L18
L61:
  nop
L18:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t n) {
  if (n == 0)
    return (0);
  do {
    if (*str1 != *str2++)
      return (*(unsigned char *)str1 - *(unsigned char *)--str2);
    if (*str1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L34
  mov    $0x0,%eax
L29:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L10
  test   %cl,%cl
  je     L30
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L29
  mov    $0x0,%eax
  ret
L10:
  movzbl %cl,%eax
  movzbl %r8b,%r8d
  sub    %r8d,%eax
  ret
L30:
  mov    $0x0,%eax
L34:
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t n) {
  if (n == 0)
    return (0);
  do {
    if (*str1 != *str2++)
      return (*(unsigned char *)str1 - *(unsigned char *)--str2);
    if (*str1++ == 0)
      break;
  } while (--n != 0);
  return (0);
}
```