ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x38(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ebx,%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L103
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L103:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L80
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L80:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <check_realpath_step_by_step@plt>
  cmpl   $0x0,-0x4c(%rbp)
  jle    L81
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L96
  mov    D18(%rip),%rax
  mov    (%rax),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L42
  mov    $0xbe,%edi
  call   <e@plt>
  jmp    L42
L13:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  jne    L11
  mov    $0xc6,%edi
  call   <e@plt>
  jmp    L96
L11:
  mov    -0x4c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <check_realpath_recurse>
L96:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  jns    L71
  mov    $0xcd,%edi
  call   <e@plt>
L71:
  mov    %r12,%rsp
  jmp    L51
L42:
  nop
L81:
  mov    %r12,%rsp
L51:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOTDIR)
      (e(190));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(198));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(205));
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    D17(%rip),%rax
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L13:
  cmp    %rdx,%rsp
  je     L40
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L40:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L12
  orq    $0x0,-0x8(%rsp,%rax,1)
L12:
  mov    %rsp,%r14
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <check_realpath_step_by_step@plt>
  cmpl   $0x0,-0x44(%rbp)
  jle    L38
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    %rax,%r13
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x44(%rbp)
  test   %r13,%r13
  jne    L43
  mov    D19(%rip),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L130
L38:
  mov    %r15,%rsp
L41:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L130:
  mov    $0xbe,%edi
  call   <e@plt>
  jmp    L38
L21:
  mov    $0xc6,%edi
  call   <e@plt>
L43:
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L85
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  je     L21
  mov    -0x44(%rbp),%esi
  mov    %r14,%rdi
  call   <check_realpath_recurse>
  jmp    L43
L85:
  mov    %r13,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L0
L124:
  mov    %r15,%rsp
  jmp    L41
L0:
  mov    $0xcd,%edi
  call   <e@plt>
  jmp    L124
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOTDIR)
      (e(190));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(198));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(205));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L17
L11:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L87
L27:
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %edx,-0x44(%rbp)
  mov    %rsp,%r14
  call   <check_realpath_step_by_step@plt>
  mov    -0x44(%rbp),%edx
  test   %edx,%edx
  jle    L26
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    -0x44(%rbp),%edx
  mov    %rax,%r13
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x44(%rbp)
  test   %r13,%r13
  je     L21
L25:
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L0
L41:
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  je     L80
  mov    -0x44(%rbp),%esi
  mov    %r14,%rdi
  call   <check_realpath_recurse>
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L41
L0:
  mov    %r13,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L68
L26:
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  mov    $0xc6,%edi
  call   <e@plt>
  jmp    L25
  nopl   0x0(%rax)
L87:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L68:
  mov    $0xcd,%edi
  call   <e@plt>
  jmp    L26
  nopl   0x0(%rax)
L21:
  mov    D19(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L26
  mov    $0xbe,%edi
  call   <e@plt>
  jmp    L26
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOTDIR)
      (e(190));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(198));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(205));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_realpath_recurse>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  mov    %rsp,%rsi
  mov    %rsp,%r15
  mov    (%rax),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L142
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L38
L142:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L19
L114:
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %edx,-0x44(%rbp)
  mov    %rsp,%r14
  call   <check_realpath_step_by_step@plt>
  mov    -0x44(%rbp),%edx
  test   %edx,%edx
  jle    L120
  mov    %r12,%rdi
  call   <opendir@plt>
  mov    -0x44(%rbp),%edx
  mov    %rax,%r13
  lea    -0x1(%rdx),%eax
  mov    %eax,-0x44(%rbp)
  test   %r13,%r13
  je     L119
L34:
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L73
L15:
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <pathncat@plt>
  test   %eax,%eax
  je     L101
  mov    -0x44(%rbp),%esi
  mov    %r14,%rdi
  call   <check_realpath_recurse>
  mov    %r13,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L15
L73:
  mov    %r13,%rdi
  call   <closedir@plt>
  test   %rax,%rax
  js     L141
L120:
  mov    %r15,%rsp
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L101:
  mov    $0xc6,%edi
  call   <e@plt>
  jmp    L34
  nopl   0x0(%rax)
L19:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L114
  nopl   0x0(%rax,%rax,1)
L141:
  mov    $0xcd,%edi
  call   <e@plt>
  jmp    L120
  nopl   0x0(%rax)
L119:
  mov    D1(%rip),%rax
  mov    D28(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L120
  mov    $0xbe,%edi
  call   <e@plt>
  jmp    L120
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void check_realpath_recurse(const char *path, int depth) {
  DIR *dir;
  struct dirent *dirent;
  char pathsub[PATH_MAX + 1];
  check_realpath_step_by_step(path, 0);
  if (depth < 1)
    return;
  if (!(dir = opendir(path))) {
    if (errno != ENOTDIR)
      (e(190));
    return;
  }
  while (dirent = readdir(dir)) {
    if (!pathncat(pathsub, sizeof(pathsub), path, dirent->d_name)) {
      (e(198));
      continue;
    }
    check_realpath_recurse(pathsub, depth - 1);
  }
  if (closedir(dir) < 0)
    (e(205));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_USBNNackEvent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xe,%edi
  call   <USBNRead@plt>
  mov    %al,-0x1(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void _USBNNackEvent(void) {
  unsigned char event;
  event = USBNRead(0x0E);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_USBNNackEvent>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xe,%edi
  call   <USBNRead@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _USBNNackEvent(void) {
  unsigned char event;
  event = USBNRead(0x0E);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_USBNNackEvent>:
  endbr64
  mov    $0xe,%edi
  jmp    1050 <USBNRead@plt>
```

assistant: ```c
void _USBNNackEvent(void) {
  unsigned char event;
  event = USBNRead(0x0E);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_USBNNackEvent>:
  endbr64
  mov    $0xe,%edi
  jmp    1050 <USBNRead@plt>
```

assistant: ```c
void _USBNNackEvent(void) {
  unsigned char event;
  event = USBNRead(0x0E);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psmat4_assign_mat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat4_assign_mat2@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat2(struct mat4 *result, struct mat2 *m) {
  mat4_assign_mat2((float *)result, (float *)m);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<psmat4_assign_mat2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <mat4_assign_mat2@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat2(struct mat4 *result, struct mat2 *m) {
  mat4_assign_mat2((float *)result, (float *)m);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psmat4_assign_mat2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_assign_mat2@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat2(struct mat4 *result, struct mat2 *m) {
  mat4_assign_mat2((float *)result, (float *)m);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psmat4_assign_mat2>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <mat4_assign_mat2@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct mat4 *psmat4_assign_mat2(struct mat4 *result, struct mat2 *m) {
  mat4_assign_mat2((float *)result, (float *)m);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<retCeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  cmpl   $0x4,-0x30(%rbp)
  je     L100
  cmpl   $0x4,-0x30(%rbp)
  jg     L29
  cmpl   $0x3,-0x30(%rbp)
  je     L66
  cmpl   $0x3,-0x30(%rbp)
  jg     L29
  cmpl   $0x1,-0x30(%rbp)
  je     L72
  cmpl   $0x2,-0x30(%rbp)
  je     L3
  jmp    L29
L72:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L3:
  movl   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L29
L66:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L100:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  nop
L29:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L77
L19:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L45
L67:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  addl   $0x1,-0x14(%rbp)
L45:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L67
  addl   $0x1,-0x18(%rbp)
L77:
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void retCeros(int matriz[4][4], int dim, int cuadrante) {
  int i, j, col, fil, desdeFil, desdeCol;
  switch (cuadrante) {
  case 1:
    desdeFil = 0;
    desdeCol = 0;
    break;
  case 2:
    desdeFil = 0;
    desdeCol = (dim / 2);
    break;
  case 3:
    desdeFil = (dim / 2);
    desdeCol = 0;
    break;
  case 4:
    desdeFil = (dim / 2);
    desdeCol = (dim / 2);
    break;
  }
  fil = (dim / 2) + desdeFil;
  col = (dim / 2) + desdeCol;
  for (i = desdeFil; i < fil; i++) {
    for (j = desdeCol; j < col; j++) {
      matriz[i][j] = 0;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<retCeros>:
  endbr64
  cmp    $0x3,%edx
  je     L126
  jg     L69
  cmp    $0x1,%edx
  je     L19
  cmp    $0x2,%edx
  jne    L132
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  mov    $0x0,%ecx
  jmp    L132
L69:
  cmp    $0x4,%edx
  jne    L132
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  mov    %r8d,%ecx
  jmp    L132
L126:
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  add    %esi,%ecx
  sar    %ecx
  mov    $0x0,%r8d
  jmp    L132
L19:
  mov    $0x0,%r8d
  mov    $0x0,%ecx
L132:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  lea    (%rax,%r8,1),%edx
  lea    (%rax,%rcx,1),%esi
  cmp    %esi,%ecx
  jge    L85
  movslq %ecx,%rcx
  mov    %rcx,%rsi
  shl    $0x4,%rsi
  add    %rdi,%rsi
  lea    -0x1(%rax),%eax
  add    %rcx,%rax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rdi
  jmp    L59
L82:
  movl   $0x0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L82
L25:
  add    $0x10,%rsi
  cmp    %rdi,%rsi
  je     L85
L59:
  mov    %rsi,%rcx
  movslq %r8d,%rax
  cmp    %edx,%r8d
  jl     L82
  jmp    L25
L85:
  ret
```

assistant: ```c
void retCeros(int matriz[4][4], int dim, int cuadrante) {
  int i, j, col, fil, desdeFil, desdeCol;
  switch (cuadrante) {
  case 1:
    desdeFil = 0;
    desdeCol = 0;
    break;
  case 2:
    desdeFil = 0;
    desdeCol = (dim / 2);
    break;
  case 3:
    desdeFil = (dim / 2);
    desdeCol = 0;
    break;
  case 4:
    desdeFil = (dim / 2);
    desdeCol = (dim / 2);
    break;
  }
  fil = (dim / 2) + desdeFil;
  col = (dim / 2) + desdeCol;
  for (i = desdeFil; i < fil; i++) {
    for (j = desdeCol; j < col; j++) {
      matriz[i][j] = 0;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<retCeros>:
  endbr64
  mov    %esi,%eax
  push   %r13
  shr    $0x1f,%eax
  push   %r12
  push   %rbp
  lea    (%rax,%rsi,1),%ecx
  push   %rbx
  sar    %ecx
  mov    %ecx,%eax
  sub    $0x8,%rsp
  cmp    $0x3,%edx
  je     L68
  jg     L91
  cmp    $0x1,%edx
  je     L96
  cmp    $0x2,%edx
  jne    L90
  lea    (%rcx,%rcx,1),%ebp
  mov    %ecx,%ebx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    %eax,%edx
  jge    L80
  sub    $0x1,%eax
  movslq %edx,%r8
  movslq %ebx,%rsi
  sub    %edx,%eax
  lea    (%rsi,%r8,4),%rcx
  add    %r8,%rax
  lea    (%rdi,%rcx,4),%rcx
  lea    (%rsi,%rax,4),%rax
  lea    0x10(%rdi,%rax,4),%r12
  lea    -0x1(%rbp),%eax
  sub    %ebx,%eax
  lea    0x4(,%rax,4),%r13
L46:
  cmp    %ebp,%ebx
  jge    L69
  mov    %rcx,%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
L69:
  add    $0x10,%rcx
  cmp    %r12,%rcx
  jne    L46
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L91:
  cmp    $0x4,%edx
  jne    L90
  lea    (%rcx,%rcx,1),%ebp
  mov    %ecx,%ebx
  mov    %ecx,%edx
  mov    %ebp,%eax
  jmp    L22
L96:
  mov    %ecx,%ebp
  xor    %ebx,%ebx
  xor    %edx,%edx
  jmp    L22
L68:
  mov    %ecx,%ebp
  mov    %ecx,%edx
  add    %eax,%eax
  xor    %ebx,%ebx
  jmp    L22
L90:
  xor    %ebx,%ebx
  xor    %edx,%edx
  mov    %ecx,%eax
  lea    (%rbx,%rcx,1),%ebp
  jmp    L22
```

assistant: ```c
void retCeros(int matriz[4][4], int dim, int cuadrante) {
  int i, j, col, fil, desdeFil, desdeCol;
  switch (cuadrante) {
  case 1:
    desdeFil = 0;
    desdeCol = 0;
    break;
  case 2:
    desdeFil = 0;
    desdeCol = (dim / 2);
    break;
  case 3:
    desdeFil = (dim / 2);
    desdeCol = 0;
    break;
  case 4:
    desdeFil = (dim / 2);
    desdeCol = (dim / 2);
    break;
  }
  fil = (dim / 2) + desdeFil;
  col = (dim / 2) + desdeCol;
  for (i = desdeFil; i < fil; i++) {
    for (j = desdeCol; j < col; j++) {
      matriz[i][j] = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<retCeros>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rax,%rsi,1),%ecx
  sar    %ecx
  mov    %ecx,%eax
  cmp    $0x3,%edx
  je     L84
  jg     L105
  cmp    $0x1,%edx
  je     L83
  cmp    $0x2,%edx
  jne    L65
  lea    (%rcx,%rcx,1),%edx
  mov    %ecx,%esi
  xor    %r8d,%r8d
L96:
  cmp    %eax,%r8d
  jge    L102
L44:
  cmp    %edx,%esi
  jge    L102
  sub    $0x1,%eax
  push   %rbp
  movslq %r8d,%r10
  movslq %esi,%r9
  push   %rbx
  sub    %r8d,%eax
  sub    $0x1,%edx
  lea    (%r9,%r10,4),%rcx
  add    %r10,%rax
  sub    %esi,%edx
  lea    (%rdi,%rcx,4),%rcx
  lea    (%r9,%rax,4),%rax
  lea    0x4(,%rdx,4),%rbx
  sub    $0x8,%rsp
  lea    0x10(%rdi,%rax,4),%rbp
  nopl   0x0(%rax)
L7:
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
  add    $0x10,%rcx
  cmp    %rbp,%rcx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L105:
  cmp    $0x4,%edx
  jne    L65
  lea    (%rcx,%rcx,1),%edx
  mov    %ecx,%r8d
  mov    %ecx,%esi
  mov    %edx,%eax
  cmp    %eax,%r8d
  jl     L44
L102:
  ret
L83:
  mov    %ecx,%edx
  xor    %esi,%esi
  xor    %r8d,%r8d
  jmp    L96
L84:
  mov    %ecx,%edx
  mov    %ecx,%r8d
  add    %eax,%eax
  xor    %esi,%esi
  jmp    L96
L65:
  xor    %esi,%esi
  xor    %r8d,%r8d
  mov    %ecx,%eax
  lea    (%rsi,%rcx,1),%edx
  jmp    L96
```

assistant: ```c
void retCeros(int matriz[4][4], int dim, int cuadrante) {
  int i, j, col, fil, desdeFil, desdeCol;
  switch (cuadrante) {
  case 1:
    desdeFil = 0;
    desdeCol = 0;
    break;
  case 2:
    desdeFil = 0;
    desdeCol = (dim / 2);
    break;
  case 3:
    desdeFil = (dim / 2);
    desdeCol = 0;
    break;
  case 4:
    desdeFil = (dim / 2);
    desdeCol = (dim / 2);
    break;
  }
  fil = (dim / 2) + desdeFil;
  col = (dim / 2) + desdeCol;
  for (i = desdeFil; i < fil; i++) {
    for (j = desdeCol; j < col; j++) {
      matriz[i][j] = 0;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<errorFn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void errorFn(void) {
  {
  ERROR:
    __VERIFIER_error();
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<errorFn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void errorFn(void) {
  {
  ERROR:
    __VERIFIER_error();
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<errorFn>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__VERIFIER_error@plt>
```

assistant: ```c
void errorFn(void) {
  {
  ERROR:
    __VERIFIER_error();
    return;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<errorFn>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <__VERIFIER_error@plt>
```

assistant: ```c
void errorFn(void) {
  {
  ERROR:
    __VERIFIER_error();
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compareSubstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L10
  mov    $0x0,%eax
  jmp    L14
L10:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int compareSubstr(char *shortStr, char *longStr) {
  int i = 0;
  while (shortStr[i] != '\0') {
    if (shortStr[i] != longStr[i]) {
      return (0);
    }
    i++;
  }
  return (1);
}
```