ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%edi
  jmp    *%rax
```

assistant: ```c
int main(int argc, char *argv[]) {
  int thread_id = (int)(argv[1]);
  int (*component_main)(int) = (int (*)(int))(argv[2]);
  return component_main(thread_id);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<funcao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x14,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int funcao(int *x) {
  *x = 20;
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<funcao>:
  endbr64
  mov    %rdi,%rax
  movl   $0x14,(%rdi)
  ret
```

assistant: ```c
int funcao(int *x) {
  *x = 20;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<funcao>:
  endbr64
  movl   $0x14,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
int funcao(int *x) {
  *x = 20;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<funcao>:
  endbr64
  movl   $0x14,(%rdi)
  mov    %rdi,%rax
  ret
```

assistant: ```c
int funcao(int *x) {
  *x = 20;
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncpy0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L27
  cmpq   $0x0,-0x20(%rbp)
  jne    L11
L27:
  mov    $0x0,%eax
  jmp    L4
L11:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
char *strncpy0(char *strDest, const char *strSource, size_t count) {
  char *rval;
  if ((strDest == NULL) || (strSource == NULL) || (count < 0))
    return (NULL);
  rval = strncpy(strDest, strSource, count);
  strDest[count - 1] = 0;
  return (rval);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncpy0>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  test   %rsi,%rsi
  je     L25
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rbx,%rbp,1)
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x0,%eax
  jmp    L6
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strncpy0(char *strDest, const char *strSource, size_t count) {
  char *rval;
  if ((strDest == NULL) || (strSource == NULL) || (count < 0))
    return (NULL);
  rval = strncpy(strDest, strSource, count);
  strDest[count - 1] = 0;
  return (rval);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncpy0>:
  endbr64
  test   %rdi,%rdi
  je     L0
  test   %rsi,%rsi
  je     L0
  push   %rbx
  mov    %rdx,%rbx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rax,%rbx,1)
  pop    %rbx
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strncpy0(char *strDest, const char *strSource, size_t count) {
  char *rval;
  if ((strDest == NULL) || (strSource == NULL) || (count < 0))
    return (NULL);
  rval = strncpy(strDest, strSource, count);
  strDest[count - 1] = 0;
  return (rval);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncpy0>:
  endbr64
  test   %rdi,%rdi
  je     L17
  test   %rsi,%rsi
  je     L17
  push   %rbx
  mov    %rdx,%rbx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rax,%rbx,1)
  pop    %rbx
  ret
  xchg   %ax,%ax
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strncpy0(char *strDest, const char *strSource, size_t count) {
  char *rval;
  if ((strDest == NULL) || (strSource == NULL) || (count < 0))
    return (NULL);
  rval = strncpy(strDest, strSource, count);
  strDest[count - 1] = 0;
  return (rval);
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L23
L37:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D49(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D44(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   D12(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L35
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L35:
  addl   $0x1,-0x24(%rbp)
L23:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L37
L24:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  ucomisd -0x20(%rbp),%xmm0
  jnp    L46
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D49
datatype: f64
name: disassemble_data
arguments: data_label: D44
datatype: f64
name: disassemble_data
arguments: data_label: D12
datatype: qword
name: disassemble_data
arguments: data_label: D7
datatype: string

tool: D49: 1000

tool: D44: 500

tool: D12: 9223372036854775807

tool: D7: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = fabs(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L19:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D7(%rip),%xmm0
  subsd  D29(%rip),%xmm0
  andpd  D16(%rip),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L14
  sub    $0x1,%ebx
  jne    L19
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L4
L14:
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L4:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: f64
name: parse_data
arguments: data_tag: D29
type: f64
name: parse_data
arguments: data_tag: D16
type: qword[2]
name: parse_data
arguments: data_tag: D8
type: string

tool: D7: 1000

tool: D29: 500

tool: {"D16": [0x7fffffffffffffff,0x0000000000000000]}

tool: D8: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = fabs(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L27
  xchg   %ax,%ax
L22:
  sub    $0x1,%ebx
  je     L1
L27:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D11(%rip),%xmm0
  subsd  D21(%rip),%xmm0
  andpd  D23(%rip),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L22
  lea    D39(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type_guessed: f64
name: unpack_data
arguments: data_label: D21
type_guessed: f64
name: unpack_data
arguments: data_label: D23
type_guessed: qword[2]
name: unpack_data
arguments: data_label: D39
type_guessed: string

tool: D11: 1000

tool: D21: 500

tool: {"D23": [0x7fffffffffffffff,0x0000000000000000]}

tool: D39: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = fabs(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<benchmark>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x18,%rsp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L20
  xchg   %ax,%ax
L24:
  sub    $0x1,%ebx
  je     L3
L20:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D24(%rip),%xmm0
  subsd  D25(%rip),%xmm0
  andpd  D31(%rip),%xmm0
  ucomisd %xmm0,%xmm0
  jnp    L24
  lea    D33(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
datatype: f64
name: parse_data
arguments: tag: D25
datatype: f64
name: parse_data
arguments: tag: D31
datatype: qword[2]
name: parse_data
arguments: tag: D33
datatype: string

tool: D24: 1000

tool: D25: 500

tool: {"D31": [0x7fffffffffffffff,0x0000000000000000]}

tool: D33: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1000.0 * rand_double()) - 500.0;
    y = fabs(x);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cpu_gemm>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%r13d
  mov    %edx,%edi
  mov    %ecx,%r10d
  mov    0x48(%rsp),%rbx
  mov    0x50(%rsp),%r11d
  test   %edx,%edx
  jle    L117
  mov    $0x0,%esi
  mov    $0x0,%ecx
  lea    -0x1(%r10),%r14d
  lea    0x4(%rbx),%rbp
  jmp    L39
L120:
  movslq %esi,%rdx
  lea    (%rbx,%rdx,4),%rax
  add    %r14,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
L3:
  movaps %xmm1,%xmm2
  mulss  (%rax),%xmm2
  movss  %xmm2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
L76:
  add    $0x1,%ecx
  add    %r11d,%esi
  cmp    %ecx,%edi
  je     L117
L39:
  test   %r10d,%r10d
  jg     L120
  jmp    L76
L117:
  mov    %r12d,%eax
  or     %r13d,%eax
  je     L32
  test   %r12d,%r12d
  je     L45
  test   %r13d,%r13d
  je     L27
L45:
  test   %r12d,%r12d
  jne    L136
  test   %r13d,%r13d
  je     L136
  sub    $0x8,%rsp
  push   %r11
  push   %rbx
  mov    0x58(%rsp),%eax
  push   %rax
  push   0x58(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  mov    %r10d,%ecx
  mov    %edi,%edx
  mov    %r13d,%esi
  mov    $0x0,%edi
  call   <cpu_gemm_nt@plt>
  add    $0x30,%rsp
  jmp    L82
L32:
  sub    $0x8,%rsp
  push   %r11
  push   %rbx
  mov    0x58(%rsp),%eax
  push   %rax
  push   0x58(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  mov    %r10d,%ecx
  mov    %edi,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <cpu_gemm_nn@plt>
  add    $0x30,%rsp
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  sub    $0x8,%rsp
  push   %r11
  push   %rbx
  mov    0x58(%rsp),%eax
  push   %rax
  push   0x58(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  mov    %r10d,%ecx
  mov    %edi,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <cpu_gemm_tn@plt>
  add    $0x30,%rsp
  jmp    L82
L136:
  sub    $0x8,%rsp
  push   %r11
  push   %rbx
  mov    0x58(%rsp),%eax
  push   %rax
  push   0x58(%rsp)
  mov    0x58(%rsp),%eax
  push   %rax
  mov    %r10d,%ecx
  mov    %edi,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <cpu_gemm_tt@plt>
  add    $0x30,%rsp
  jmp    L82
```

assistant: ```c
void cpu_gemm(int TA, int TB, int M, int N, int K, float ALPHA, float *A, int lda, float *B, int ldb, float BETA, float *C, int ldc) {
  int i, j;
  for (i = 0; i < M; ++i) {
    for (j = 0; j < N; ++j) {
      C[i * ldc + j] *= BETA;
    }
  }
  if (!TA && !TB)
    cpu_gemm_nn(TA, TB, M, N, K, ALPHA, A, lda, B, ldb, BETA, C, ldc);
  else if (TA && !TB)
    cpu_gemm_tn(TA, TB, M, N, K, ALPHA, A, lda, B, ldb, BETA, C, ldc);
  else if (!TA && TB)
    cpu_gemm_nt(TA, TB, M, N, K, ALPHA, A, lda, B, ldb, BETA, C, ldc);
  else
    cpu_gemm_tt(TA, TB, M, N, K, ALPHA, A, lda, B, ldb, BETA, C, ldc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<charsToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <charToHex@plt>
  mov    %al,-0x2(%rbp)
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <charToHex@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
char charsToHex(char c1, char c2) {
  char hex1 = charToHex(c1);
  char hex2 = charToHex(c2);
  return (hex1 << 4) + hex2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<charsToHex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  movsbl %dil,%edi
  call   <charToHex@plt>
  mov    %eax,%ebx
  movsbl %bpl,%edi
  call   <charToHex@plt>
  shl    $0x4,%ebx
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char charsToHex(char c1, char c2) {
  char hex1 = charToHex(c1);
  char hex2 = charToHex(c2);
  return (hex1 << 4) + hex2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<charsToHex>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <charToHex@plt>
  movsbl %bpl,%edi
  mov    %eax,%ebx
  call   <charToHex@plt>
  shl    $0x4,%ebx
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char charsToHex(char c1, char c2) {
  char hex1 = charToHex(c1);
  char hex2 = charToHex(c2);
  return (hex1 << 4) + hex2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<charsToHex>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <charToHex@plt>
  movsbl %bpl,%edi
  mov    %eax,%ebx
  call   <charToHex@plt>
  shl    $0x4,%ebx
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char charsToHex(char c1, char c2) {
  char hex1 = charToHex(c1);
  char hex2 = charToHex(c2);
  return (hex1 << 4) + hex2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<component_enemy_blob_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <debug_warning@plt>
  jmp    L4
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <h_free@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: [component_enemy_blob_free] handle cannot be NULL

assistant: ```c
void component_enemy_blob_free(void *handle) {
  if (!handle) {
    debug_warning("[component_enemy_blob_free] handle cannot be NULL");
    return;
  }
  h_free(handle);
}
```
user: Translate the below assembly code into C programming language:

```asm
<component_enemy_blob_free>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  call   <h_free@plt>
L17:
  add    $0x8,%rsp
  ret
L8:
  lea    D7(%rip),%rdi
  call   <debug_warning@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: [component_enemy_blob_free] handle cannot be NULL

assistant: ```c
void component_enemy_blob_free(void *handle) {
  if (!handle) {
    debug_warning("[component_enemy_blob_free] handle cannot be NULL");
    return;
  }
  h_free(handle);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<component_enemy_blob_free>:
  endbr64
  test   %rdi,%rdi
  je     L9
  jmp    1070 <h_free@plt>
  xchg   %ax,%ax
L9:
  lea    D3(%rip),%rdi
  jmp    1060 <debug_warning@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: [component_enemy_blob_free] handle cannot be NULL

assistant: ```c
void component_enemy_blob_free(void *handle) {
  if (!handle) {
    debug_warning("[component_enemy_blob_free] handle cannot be NULL");
    return;
  }
  h_free(handle);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<component_enemy_blob_free>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1070 <h_free@plt>
  xchg   %ax,%ax
L0:
  lea    D6(%rip),%rdi
  jmp    1060 <debug_warning@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: [component_enemy_blob_free] handle cannot be NULL

assistant: ```c
void component_enemy_blob_free(void *handle) {
  if (!handle) {
    debug_warning("[component_enemy_blob_free] handle cannot be NULL");
    return;
  }
  h_free(handle);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ga_mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L22
L18:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L18
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  js     L21
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  jmp    L31
L21:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  addss  %xmm0,%xmm0
L31:
  movss  -0xc(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float ga_mean(float arr[], unsigned long n) {
  unsigned long i;
  float sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum / n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ga_mean>:
  endbr64
  test   %rsi,%rsi
  je     L43
  mov    %rdi,%rax
  lea    (%rdi,%rsi,4),%rdx
  pxor   %xmm0,%xmm0
L38:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L38
L8:
  test   %rsi,%rsi
  js     L32
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
L5:
  divss  %xmm1,%xmm0
  ret
L43:
  pxor   %xmm0,%xmm0
  jmp    L8
L32:
  mov    %rsi,%rax
  shr    %rax
  and    $0x1,%esi
  or     %rsi,%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  addss  %xmm1,%xmm1
  jmp    L5
```

assistant: ```c
float ga_mean(float arr[], unsigned long n) {
  unsigned long i;
  float sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum / n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ga_mean>:
  endbr64
  test   %rsi,%rsi
  je     L13
  lea    (%rdi,%rsi,4),%rax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L12:
  addss  (%rdi),%xmm0
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L12
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
```

assistant: ```c
float ga_mean(float arr[], unsigned long n) {
  unsigned long i;
  float sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum / n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ga_mean>:
  endbr64
  test   %rsi,%rsi
  je     L10
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L29
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
L31:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L31
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L1
L5:
  lea    0x1(%rax),%rcx
  addss  (%rdi,%rax,4),%xmm0
  lea    0x0(,%rax,4),%rdx
  cmp    %rcx,%rsi
  jbe    L1
  add    $0x2,%rax
  addss  0x4(%rdi,%rdx,1),%xmm0
  cmp    %rax,%rsi
  jbe    L1
  addss  0x8(%rdi,%rdx,1),%xmm0
L1:
  pxor   %xmm1,%xmm1
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rsi,%xmm1
  divss  %xmm1,%xmm0
  ret
L29:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
float ga_mean(float arr[], unsigned long n) {
  unsigned long i;
  float sum = 0.0;
  for (i = 0; i < n; i++) {
    sum += arr[i];
  }
  return sum / n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<norm_double_vec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double norm_double_vec(double *vec, int x) {
  int i;
  double norm_2 = 0.0;
  for (i = 0; i < x; i++) {
    norm_2 = norm_2 + (vec[i] * vec[i]);
  }
  return sqrt(norm_2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<norm_double_vec>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L27:
  movsd  (%rax),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L27
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L20
L11:
  sqrtsd %xmm0,%xmm0
  ret
L36:
  pxor   %xmm0,%xmm0
  jmp    L11
L20:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double norm_double_vec(double *vec, int x) {
  int i;
  double norm_2 = 0.0;
  for (i = 0; i < x; i++) {
    norm_2 = norm_2 + (vec[i] * vec[i]);
  }
  return sqrt(norm_2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<norm_double_vec>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi,%rax,8),%rax
  movapd %xmm2,%xmm0
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L16
  ucomisd %xmm0,%xmm2
  ja     L7
  sqrtsd %xmm0,%xmm0
  ret
L14:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L7:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm_double_vec(double *vec, int x) {
  int i;
  double norm_2 = 0.0;
  for (i = 0; i < x; i++) {
    norm_2 = norm_2 + (vec[i] * vec[i]);
  }
  return sqrt(norm_2);
}
```