ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpStringsWithEmbeddedNumbers>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  jmp    L23
L77:
  mov    %r12,%rdi
  call   <countLeadingNondigits@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <countLeadingNondigits@plt>
  mov    %eax,%ebp
  cmp    %eax,%ebx
  jne    L55
  test   %ebx,%ebx
  je     L13
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L11
  movslq %ebx,%rbx
  add    %rbx,%r12
  movslq %ebp,%rbp
  add    %rbp,%r13
L23:
  mov    %r12,%rdi
  call   <countLeadingDigits@plt>
  mov    %eax,%r14d
  mov    %r13,%rdi
  call   <countLeadingDigits@plt>
  mov    %eax,%ebp
  mov    %r14d,%eax
  or     %ebp,%eax
  js     L77
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <atoi@plt>
  sub    %eax,%ebx
  jne    L13
  movslq %r14d,%r14
  add    %r14,%r12
  movslq %ebp,%rbp
  add    %rbp,%r13
  jmp    L77
L55:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebx
L13:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    %eax,%ebx
  jmp    L13
```

assistant: ```c
int cmpStringsWithEmbeddedNumbers(const char *a, const char *b) {
  for (;;) {
    int aNum = countLeadingDigits(a);
    int bNum = countLeadingDigits(b);
    if (aNum >= 0 && bNum >= 0) {
      int diff = atoi(a) - atoi(b);
      if (diff != 0)
        return diff;
      a += aNum;
      b += bNum;
    }
    int aNonNum = countLeadingNondigits(a);
    int bNonNum = countLeadingNondigits(b);
    if (aNonNum != bNonNum)
      return strcmp(a, b);
    else if (aNonNum == 0)
      return 0;
    else {
      int diff = memcmp(a, b, aNonNum);
      if (diff != 0)
        return diff;
      a += aNonNum;
      b += bNonNum;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmpStringsWithEmbeddedNumbers>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L17
  nopl   0x0(%rax)
L9:
  test   %r12d,%r12d
  je     L20
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L44
  add    %r12,%r13
  add    %r12,%rbp
L17:
  mov    %r13,%rdi
  call   <countLeadingDigits@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <countLeadingDigits@plt>
  movslq %eax,%r14
  mov    %ebx,%eax
  or     %r14d,%eax
  js     L59
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  sub    %eax,%r12d
  jne    L20
  add    %rbx,%r13
  add    %r14,%rbp
L59:
  mov    %r13,%rdi
  call   <countLeadingNondigits@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <countLeadingNondigits@plt>
  cmp    %eax,%r12d
  je     L9
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strcmp@plt>
  nop
L44:
  mov    %eax,%r12d
L20:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int cmpStringsWithEmbeddedNumbers(const char *a, const char *b) {
  for (;;) {
    int aNum = countLeadingDigits(a);
    int bNum = countLeadingDigits(b);
    if (aNum >= 0 && bNum >= 0) {
      int diff = atoi(a) - atoi(b);
      if (diff != 0)
        return diff;
      a += aNum;
      b += bNum;
    }
    int aNonNum = countLeadingNondigits(a);
    int bNonNum = countLeadingNondigits(b);
    if (aNonNum != bNonNum)
      return strcmp(a, b);
    else if (aNonNum == 0)
      return 0;
    else {
      int diff = memcmp(a, b, aNonNum);
      if (diff != 0)
        return diff;
      a += aNonNum;
      b += bNonNum;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmpStringsWithEmbeddedNumbers>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  jmp    L23
  nopl   0x0(%rax)
L28:
  test   %r12d,%r12d
  je     L13
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L10
  add    %r12,%r13
  add    %r12,%rbp
L23:
  mov    %r13,%rdi
  call   <countLeadingDigits@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  call   <countLeadingDigits@plt>
  movslq %eax,%r14
  mov    %ebx,%eax
  or     %r14d,%eax
  js     L59
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  sub    %eax,%r12d
  jne    L13
  add    %rbx,%r13
  add    %r14,%rbp
L59:
  mov    %r13,%rdi
  call   <countLeadingNondigits@plt>
  mov    %rbp,%rdi
  movslq %eax,%r12
  call   <countLeadingNondigits@plt>
  cmp    %eax,%r12d
  je     L28
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strcmp@plt>
  nop
L10:
  mov    %eax,%r12d
L13:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int cmpStringsWithEmbeddedNumbers(const char *a, const char *b) {
  for (;;) {
    int aNum = countLeadingDigits(a);
    int bNum = countLeadingDigits(b);
    if (aNum >= 0 && bNum >= 0) {
      int diff = atoi(a) - atoi(b);
      if (diff != 0)
        return diff;
      a += aNum;
      b += bNum;
    }
    int aNonNum = countLeadingNondigits(a);
    int bNonNum = countLeadingNondigits(b);
    if (aNonNum != bNonNum)
      return strcmp(a, b);
    else if (aNonNum == 0)
      return 0;
    else {
      int diff = memcmp(a, b, aNonNum);
      if (diff != 0)
        return diff;
      a += aNonNum;
      b += bNonNum;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kth_largest_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  sub    -0x38(%rbp),%rax
  shr    %rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L20
L50:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L32
  addq   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L32:
  addq   $0x1,-0x10(%rbp)
L20:
  mov    -0x10(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jb     L50
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x30(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    %rax,-0x48(%rbp)
  jne    L24
  mov    -0x18(%rbp),%rax
  jmp    L14
L24:
  mov    -0x30(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    %rax,-0x48(%rbp)
  jae    L66
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <kth_largest_aux>
  jmp    L14
L66:
  mov    -0x48(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <kth_largest_aux>
L14:
  leave
  ret
```

assistant: ```c
ssize_t kth_largest_aux(int arr[], size_t arr_sz, size_t low, size_t high, size_t k) {
  size_t pi = low + (high - low) / 2;
  size_t i = low;
  swap(arr, i, pi);
  size_t j;
  for (j = i + 1; j < high; j++) {
    if (arr[j] < arr[low]) {
      i++;
      swap(arr, i, j);
    }
  }
  swap(arr, low, i);
  if (arr_sz - i == k) {
    return i;
  } else if (arr_sz - i > k) {
    return kth_largest_aux(arr, arr_sz, i + 1, high, k);
  } else {
    return kth_largest_aux(arr, arr_sz, low, i, k);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kth_largest_aux>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,(%rsp)
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,0x8(%rsp)
  mov    %rcx,%rdx
  sub    %r14,%rdx
  shr    %rdx
  add    %r14,%rdx
  mov    %r14,%rsi
  call   <swap@plt>
  lea    0x1(%r14),%rbx
  cmp    %rbx,%r13
  jbe    L65
  lea    0x0(%rbp,%r14,4),%r15
  mov    %r14,%r12
  jmp    L17
L40:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  jbe    L1
L17:
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L40
  add    $0x1,%r12
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L40
L65:
  mov    %r14,%r12
L1:
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    (%rsp),%rsi
  mov    %rsi,%rax
  sub    %r12,%rax
  mov    0x8(%rsp),%r8
  cmp    %r8,%rax
  je     L34
  jbe    L79
  lea    0x1(%r12),%rdx
  mov    %r13,%rcx
  mov    %rbp,%rdi
  call   <kth_largest_aux>
  mov    %rax,%r12
L34:
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    0x8(%rsp),%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <kth_largest_aux>
  mov    %rax,%r12
  jmp    L34
```

assistant: ```c
ssize_t kth_largest_aux(int arr[], size_t arr_sz, size_t low, size_t high, size_t k) {
  size_t pi = low + (high - low) / 2;
  size_t i = low;
  swap(arr, i, pi);
  size_t j;
  for (j = i + 1; j < high; j++) {
    if (arr[j] < arr[low]) {
      i++;
      swap(arr, i, j);
    }
  }
  swap(arr, low, i);
  if (arr_sz - i == k) {
    return i;
  } else if (arr_sz - i > k) {
    return kth_largest_aux(arr, arr_sz, i + 1, high, k);
  } else {
    return kth_largest_aux(arr, arr_sz, low, i, k);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<kth_largest_aux>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%rax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  xchg   %ax,%ax
L22:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  sub    %r12,%rdx
  shr    %rdx
  add    %r12,%rdx
  call   <swap@plt>
  mov    0x8(%rsp),%rax
  mov    %rax,%rbx
  cmp    %rax,%rbp
  jbe    L87
  lea    (%r15,%r12,4),%r13
  mov    %r12,%r14
  jmp    L32
  nopl   0x0(%rax)
L16:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L71
L32:
  mov    0x0(%r13),%eax
  cmp    %eax,(%r15,%rbx,4)
  jge    L16
  add    $0x1,%r14
  mov    %rbx,%rdx
  mov    %r15,%rdi
  add    $0x1,%rbx
  mov    %r14,%rsi
  call   <swap@plt>
  cmp    %rbx,%rbp
  ja     L32
L71:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  mov    0x10(%rsp),%rax
  sub    %r14,%rax
  cmp    0x18(%rsp),%rax
  je     L95
  jbe    L25
  lea    0x2(%r14),%rax
  lea    0x1(%r14),%r12
  mov    %rax,0x8(%rsp)
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rbp
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L95:
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %r12,%r14
  jmp    L71
```

assistant: ```c
ssize_t kth_largest_aux(int arr[], size_t arr_sz, size_t low, size_t high, size_t k) {
  size_t pi = low + (high - low) / 2;
  size_t i = low;
  swap(arr, i, pi);
  size_t j;
  for (j = i + 1; j < high; j++) {
    if (arr[j] < arr[low]) {
      i++;
      swap(arr, i, j);
    }
  }
  swap(arr, low, i);
  if (arr_sz - i == k) {
    return i;
  } else if (arr_sz - i > k) {
    return kth_largest_aux(arr, arr_sz, i + 1, high, k);
  } else {
    return kth_largest_aux(arr, arr_sz, low, i, k);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<kth_largest_aux>:
  endbr64
  push   %r15
  lea    0x1(%rdx),%rax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  xchg   %ax,%ax
L33:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  sub    %r12,%rdx
  shr    %rdx
  add    %r12,%rdx
  call   <swap@plt>
  mov    0x8(%rsp),%rax
  mov    %rax,%rbx
  cmp    %rax,%rbp
  jbe    L96
  lea    (%r15,%r12,4),%r13
  mov    %r12,%r14
  jmp    L81
  nopl   0x0(%rax)
L22:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L82
L81:
  mov    0x0(%r13),%eax
  cmp    %eax,(%r15,%rbx,4)
  jge    L22
  add    $0x1,%r14
  mov    %rbx,%rdx
  mov    %r15,%rdi
  add    $0x1,%rbx
  mov    %r14,%rsi
  call   <swap@plt>
  cmp    %rbx,%rbp
  ja     L81
L82:
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  mov    0x10(%rsp),%rax
  sub    %r14,%rax
  cmp    0x18(%rsp),%rax
  je     L59
  jbe    L76
  lea    0x2(%r14),%rax
  lea    0x1(%r14),%r12
  mov    %rax,0x8(%rsp)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %r14,%rbp
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L96:
  mov    %r12,%r14
  jmp    L82
```

assistant: ```c
ssize_t kth_largest_aux(int arr[], size_t arr_sz, size_t low, size_t high, size_t k) {
  size_t pi = low + (high - low) / 2;
  size_t i = low;
  swap(arr, i, pi);
  size_t j;
  for (j = i + 1; j < high; j++) {
    if (arr[j] < arr[low]) {
      i++;
      swap(arr, i, j);
    }
  }
  swap(arr, low, i);
  if (arr_sz - i == k) {
    return i;
  } else if (arr_sz - i > k) {
    return kth_largest_aux(arr, arr_sz, i + 1, high, k);
  } else {
    return kth_largest_aux(arr, arr_sz, low, i, k);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gcvt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  movq   %rcx,%xmm0
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %.*g

assistant: ```c
char *gcvt(double x, int n, char *b) {
  sprintf(b, "%.*g", n, x);
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcvt>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    %rsi,%rbx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: %.*g

assistant: ```c
char *gcvt(double x, int n, char *b) {
  sprintf(b, "%.*g", n, x);
  return b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcvt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%edx
  lea    D1(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: %.*g

assistant: ```c
char *gcvt(double x, int n, char *b) {
  sprintf(b, "%.*g", n, x);
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gcvt>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %edi,%edx
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: %.*g

assistant: ```c
char *gcvt(double x, int n, char *b) {
  sprintf(b, "%.*g", n, x);
  return b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_to_engineering_string@plt>
  mov    $0x0,%eax
  call   <test_to_engineering_string_unit@plt>
  mov    $0x0,%eax
  call   <test_from_engineering_string@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_to_engineering_string();
  test_to_engineering_string_unit();
  test_from_engineering_string();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_to_engineering_string@plt>
  mov    $0x0,%eax
  call   <test_to_engineering_string_unit@plt>
  mov    $0x0,%eax
  call   <test_from_engineering_string@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_to_engineering_string();
  test_to_engineering_string_unit();
  test_from_engineering_string();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_to_engineering_string@plt>
  xor    %eax,%eax
  call   <test_to_engineering_string_unit@plt>
  xor    %eax,%eax
  call   <test_from_engineering_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_to_engineering_string();
  test_to_engineering_string_unit();
  test_from_engineering_string();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_to_engineering_string@plt>
  xor    %eax,%eax
  call   <test_to_engineering_string_unit@plt>
  xor    %eax,%eax
  call   <test_from_engineering_string@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_to_engineering_string();
  test_to_engineering_string_unit();
  test_from_engineering_string();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<i24_to_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x800000,%eax
  test   %eax,%eax
  je     L6
  mov    -0x4(%rbp),%eax
  or     $0xff000000,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L17
L6:
  andl   $0xffffff,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
L17:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3e]}

assistant: ```c
void i24_to_double(unsigned char *i24, double *p) {
  int val = (i24[0]) | (i24[1] << 8) | (i24[2] << 16);
  if (val & 0x800000) {
    val |= 0xFF000000;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  } else {
    val &= 0xFFFFFF;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<i24_to_double>:
  endbr64
  movzbl 0x1(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl (%rdi),%edx
  or     %eax,%edx
  test   $0x800000,%eax
  je     L18
  or     $0xff000000,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D8(%rip),%xmm0
L19:
  movsd  %xmm0,(%rsi)
  ret
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D8(%rip),%xmm0
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3e]}

assistant: ```c
void i24_to_double(unsigned char *i24, double *p) {
  int val = (i24[0]) | (i24[1] << 8) | (i24[2] << 16);
  if (val & 0x800000) {
    val |= 0xFF000000;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  } else {
    val &= 0xFFFFFF;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<i24_to_double>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl (%rdi),%edx
  or     %eax,%edx
  test   $0x800000,%eax
  je     L4
  or     $0xff000000,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D14(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D14(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_infered: byte[8]

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3e]}

assistant: ```c
void i24_to_double(unsigned char *i24, double *p) {
  int val = (i24[0]) | (i24[1] << 8) | (i24[2] << 16);
  if (val & 0x800000) {
    val |= 0xFF000000;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  } else {
    val &= 0xFFFFFF;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i24_to_double>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl (%rdi),%edx
  or     %eax,%edx
  test   $0x800000,%eax
  je     L6
  or     $0xff000000,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D17(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  D17(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D17
type: byte[8]

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3e]}

assistant: ```c
void i24_to_double(unsigned char *i24, double *p) {
  int val = (i24[0]) | (i24[1] << 8) | (i24[2] << 16);
  if (val & 0x800000) {
    val |= 0xFF000000;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  } else {
    val &= 0xFFFFFF;
    *p = ((((double)val)) * (1.0 / (8388608.0)));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6e6f727720656874,%rax
  movabs $0x6e6f737265702067,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x726570,-0x24(%rbp)
  movb   $0x0,-0x25(%rbp)
  lea    -0x25(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <replaceString@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int main(void) {
  void replaceString(char source[], const char s1[], const char s2[]);
  char text1[] = "the wrong person";
  char text2[] = "per";
  char text3[] = "";
  replaceString(text1, text2, text3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x6e6f727720656874,%rax
  movabs $0x6e6f737265702067,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  movl   $0x726570,0xc(%rsp)
  movb   $0x0,0xb(%rsp)
  lea    0xb(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <replaceString@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  void replaceString(char source[], const char s1[], const char s2[]);
  char text1[] = "the wrong person";
  char text2[] = "per";
  char text3[] = "";
  replaceString(text1, text2, text3);
  return 0;
}
```