ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <va_snprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void snprintf(char *str, int len, char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  va_snprintf(str, len, fmt, pvar);
  va_end(pvar);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <va_snprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void snprintf(char *str, int len, char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  va_snprintf(str, len, fmt, pvar);
  va_end(pvar);
}
```
user: What is the c source code of the assembly code below?

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <va_snprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void snprintf(char *str, int len, char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  va_snprintf(str, len, fmt, pvar);
  va_end(pvar);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <va_snprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void snprintf(char *str, int len, char *fmt, ...) {
  va_list pvar;
  va_start(pvar, fmt);
  va_snprintf(str, len, fmt, pvar);
  va_end(pvar);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SMS_GetPhoneNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x40(%rbp)
  jmp    L27
L33:
  cmpl   $0x1,-0x38(%rbp)
  jne    L61
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
L61:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L21
  addl   $0x1,-0x38(%rbp)
L21:
  addl   $0x1,-0x40(%rbp)
L27:
  mov    -0x40(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L33
  cmpl   $0x0,-0x38(%rbp)
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L47
L22:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x2c,%al
  jne    L30
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
L30:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x2(%rax),%edx
  lea    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    -0x50(%rbp),%rcx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int SMS_GetPhoneNum(char *msg, char *phone) {
  int len = strlen(msg);
  char tmp[32];
  int i, j = 0;
  int count = 0;
  memset(tmp, 0, 32);
  for (i = 0; i < len; i++) {
    if (count == 1)
      tmp[j++] = msg[i];
    if (msg[i] == ',')
      ++count;
  }
  if (count == 0)
    return -1;
  len = strlen(tmp);
  if (tmp[len - 1] == ',')
    tmp[len - 1] = '\0';
  memcpy(phone, tmp + 1, strlen(tmp) - 2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<SMS_GetPhoneNum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rsp,%rdi
  mov    $0x20,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L32
  mov    %rbx,%rdx
  lea    -0x1(%r12),%eax
  lea    (%rbx,%rax,1),%rsi
  mov    $0x0,%eax
  mov    $0x0,%r8d
  jmp    L78
L69:
  add    $0x1,%rdx
L78:
  mov    %rdx,%rdi
  cmpb   $0x2c,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    %rsi,%rdx
  je     L64
  cmp    $0x1,%eax
  jne    L69
  movslq %r8d,%rcx
  movzbl 0x1(%rdi),%edi
  mov    %dil,(%rsp,%rcx,1)
  lea    0x1(%r8),%r8d
  jmp    L69
L64:
  test   %eax,%eax
  je     L109
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  cmpb   $0x2c,(%rsp,%rdx,1)
  je     L20
L102:
  mov    %rsp,%rdi
  call   <strlen@plt>
  lea    -0x2(%rax),%edx
  lea    0x1(%rsp),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L96:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  movb   $0x0,(%rsp,%rdx,1)
  jmp    L102
L32:
  mov    $0xffffffff,%eax
  jmp    L96
L109:
  mov    $0xffffffff,%eax
  jmp    L96
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SMS_GetPhoneNum(char *msg, char *phone) {
  int len = strlen(msg);
  char tmp[32];
  int i, j = 0;
  int count = 0;
  memset(tmp, 0, 32);
  for (i = 0; i < len; i++) {
    if (count == 1)
      tmp[j++] = msg[i];
    if (msg[i] == ',')
      ++count;
  }
  if (count == 0)
    return -1;
  len = strlen(tmp);
  if (tmp[len - 1] == ',')
    tmp[len - 1] = '\0';
  memcpy(phone, tmp + 1, strlen(tmp) - 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SMS_GetPhoneNum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strlen@plt>
  xor    %esi,%esi
  mov    $0x20,%edx
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <memset@plt>
  test   %r13d,%r13d
  jle    L38
  lea    -0x1(%r13),%ecx
  mov    %rbx,%rdi
  xor    %eax,%eax
  xor    %esi,%esi
  add    %rbx,%rcx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L37:
  cmp    $0x1,%eax
  jne    L65
  movzbl 0x1(%rdi),%r8d
  movslq %esi,%rdx
  add    $0x1,%esi
  mov    %r8b,(%rsp,%rdx,1)
L65:
  add    $0x1,%rdi
L9:
  xor    %edx,%edx
  cmpb   $0x2c,(%rdi)
  sete   %dl
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L37
  test   %eax,%eax
  je     L38
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0x2c,(%rsp,%rax,1)
  jne    L18
  movb   $0x0,(%rsp,%rax,1)
L18:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rsp),%rsi
  mov    %rbp,%rdi
  lea    -0x2(%rax),%edx
  call   <memcpy@plt>
  xor    %eax,%eax
L57:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%eax
  jmp    L57
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SMS_GetPhoneNum(char *msg, char *phone) {
  int len = strlen(msg);
  char tmp[32];
  int i, j = 0;
  int count = 0;
  memset(tmp, 0, 32);
  for (i = 0; i < len; i++) {
    if (count == 1)
      tmp[j++] = msg[i];
    if (msg[i] == ',')
      ++count;
  }
  if (count == 0)
    return -1;
  len = strlen(tmp);
  if (tmp[len - 1] == ',')
    tmp[len - 1] = '\0';
  memcpy(phone, tmp + 1, strlen(tmp) - 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SMS_GetPhoneNum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <strlen@plt>
  xor    %esi,%esi
  mov    $0x20,%edx
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <memset@plt>
  test   %r13d,%r13d
  jle    L39
  lea    -0x1(%r13),%ecx
  mov    %rbx,%rdi
  xor    %eax,%eax
  xor    %esi,%esi
  add    %rbx,%rcx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L79:
  cmp    $0x1,%eax
  jne    L34
  movzbl 0x1(%rdi),%r8d
  movslq %esi,%rdx
  add    $0x1,%esi
  mov    %r8b,(%rsp,%rdx,1)
L34:
  add    $0x1,%rdi
L19:
  xor    %edx,%edx
  cmpb   $0x2c,(%rdi)
  sete   %dl
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L79
  test   %eax,%eax
  je     L39
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  cmpb   $0x2c,(%rsp,%rax,1)
  jne    L43
  movb   $0x0,(%rsp,%rax,1)
L43:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rsp),%rsi
  mov    %rbp,%rdi
  lea    -0x2(%rax),%edx
  call   <memcpy@plt>
  xor    %eax,%eax
L60:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffff,%eax
  jmp    L60
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int SMS_GetPhoneNum(char *msg, char *phone) {
  int len = strlen(msg);
  char tmp[32];
  int i, j = 0;
  int count = 0;
  memset(tmp, 0, 32);
  for (i = 0; i < len; i++) {
    if (count == 1)
      tmp[j++] = msg[i];
    if (msg[i] == ',')
      ++count;
  }
  if (count == 0)
    return -1;
  len = strlen(tmp);
  if (tmp[len - 1] == ',')
    tmp[len - 1] = '\0';
  memcpy(phone, tmp + 1, strlen(tmp) - 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: Hello World!


assistant: ```c
int main() {
  int i = 1;
  printf("Hello World!\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: Hello World!


assistant: ```c
int main() {
  int i = 1;
  printf("Hello World!\n");
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: Hello World!


assistant: ```c
int main() {
  int i = 1;
  printf("Hello World!\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: Hello World!


assistant: ```c
int main() {
  int i = 1;
  printf("Hello World!\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xxf2ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0xfa(%rax),%edx
  mov    -0x20(%rbp),%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %eax,-0x20(%rbp)
  shll   $0x2,-0x1c(%rbp)
  shll   $0x2,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L28
L20:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jle    L6
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7f,%al
  je     L6
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  movzbl (%rdx),%edx
  cltq
  lea    D15(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  jmp    L11
L6:
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    D15(%rip),%rdx
  movb   $0x20,(%rax,%rdx,1)
L11:
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L20
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltq
  lea    D15(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D15(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *xxf2ascii(float *x, int n1, int n2) {
  int i;
  char *p;
  static char result[250 + 1];
  n1--;
  p = (char *)x;
  n2 = (((250 + n1) < (n2)) ? (250 + n1) : (n2));
  n1 *= 4;
  n2 *= 4;
  for (i = n1; i < n2; i++) {
    if (p[i] >= 32 && p[i] <= 126)
      result[i - n1] = p[i];
    else
      result[i - n1] = ' ';
  }
  result[i - n1] = '\0';
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xxf2ascii>:
  endbr64
  lea    -0x1(%rsi),%r11d
  add    $0xf9,%esi
  cmp    %edx,%esi
  cmovle %esi,%edx
  mov    %edx,%r9d
  lea    0x0(,%r11,4),%r8d
  lea    0x0(,%rdx,4),%esi
  cmp    %edx,%r11d
  jge    L43
  mov    $0x0,%eax
  movslq %r8d,%rdx
  add    %rdx,%rdi
  lea    D16(%rip),%r10
  jmp    L51
L58:
  movslq %eax,%rdx
  movb   $0x20,(%r10,%rdx,1)
L24:
  add    $0x1,%rax
  lea    (%r8,%rax,1),%edx
  cmp    %edx,%esi
  jle    L57
L51:
  movzbl (%rdi,%rax,1),%edx
  lea    -0x20(%rdx),%ecx
  cmp    $0x5e,%cl
  ja     L58
  movslq %eax,%rcx
  mov    %dl,(%r10,%rcx,1)
  jmp    L24
L57:
  sub    %r8d,%esi
  sub    $0x1,%esi
  cmp    %r9d,%r11d
  mov    $0x0,%eax
  cmovge %eax,%esi
  lea    0x1(%r8,%rsi,1),%eax
L1:
  lea    D16(%rip),%rdx
  sub    %r8d,%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    %rdx,%rax
  ret
L43:
  mov    %r8d,%eax
  jmp    L1
```

assistant: ```c
char *xxf2ascii(float *x, int n1, int n2) {
  int i;
  char *p;
  static char result[250 + 1];
  n1--;
  p = (char *)x;
  n2 = (((250 + n1) < (n2)) ? (250 + n1) : (n2));
  n1 *= 4;
  n2 *= 4;
  for (i = n1; i < n2; i++) {
    if (p[i] >= 32 && p[i] <= 126)
      result[i - n1] = p[i];
    else
      result[i - n1] = ' ';
  }
  result[i - n1] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xxf2ascii>:
  endbr64
  lea    -0x1(%rsi),%r11d
  add    $0xf9,%esi
  mov    %rdi,%r8
  mov    %edx,%edi
  cmp    %edx,%esi
  push   %r12
  cmovle %esi,%edi
  push   %rbx
  cmp    %edi,%r11d
  jge    L11
  lea    0x0(,%r11,4),%ebx
  lea    D3(%rip),%r12
  mov    $0x20,%r10d
  movslq %ebx,%rax
  mov    %r12,%r9
  lea    0x0(,%rdi,4),%ecx
  sub    %rax,%r9
  nopl   (%rax)
L10:
  movzbl (%r8,%rax,1),%edx
  lea    -0x20(%rdx),%esi
  cmp    $0x5f,%sil
  cmovae %r10d,%edx
  mov    %dl,(%r9,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L10
  sub    %ebx,%ecx
  xor    %eax,%eax
  pop    %rbx
  sub    $0x1,%ecx
  cmp    %edi,%r11d
  cmovge %eax,%ecx
  mov    %r12,%rax
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movb   $0x0,(%r12,%rcx,1)
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %ecx,%ecx
  lea    D3(%rip),%r12
  pop    %rbx
  movslq %ecx,%rcx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rcx,1)
  pop    %r12
  ret
```

assistant: ```c
char *xxf2ascii(float *x, int n1, int n2) {
  int i;
  char *p;
  static char result[250 + 1];
  n1--;
  p = (char *)x;
  n2 = (((250 + n1) < (n2)) ? (250 + n1) : (n2));
  n1 *= 4;
  n2 *= 4;
  for (i = n1; i < n2; i++) {
    if (p[i] >= 32 && p[i] <= 126)
      result[i - n1] = p[i];
    else
      result[i - n1] = ' ';
  }
  result[i - n1] = '\0';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reservar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L14:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *reservar(int puntos) {
  float *array = malloc(puntos * sizeof(float));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 0.0;
  }
  return array;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reservar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L15
  mov    %rax,%rdx
  mov    %ebx,%ebx
  lea    (%rax,%rbx,4),%rcx
L4:
  movl   $0x0,(%rdx)
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L4
L15:
  pop    %rbx
  ret
```

assistant: ```c
float *reservar(int puntos) {
  float *array = malloc(puntos * sizeof(float));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 0.0;
  }
  return array;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<reservar>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x0(,%rbp,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L6
  lea    0x0(,%rbp,4),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L6:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float *reservar(int puntos) {
  float *array = malloc(puntos * sizeof(float));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 0.0;
  }
  return array;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reservar>:
  endbr64
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  lea    0x0(,%rbp,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L2
  lea    0x0(,%rbp,4),%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rax,%r8
L2:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
float *reservar(int puntos) {
  float *array = malloc(puntos * sizeof(float));
  int i;
  for (i = 0; i < puntos; i++) {
    array[i] = 0.0;
  }
  return array;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_domain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L27
  mov    $0x0,%eax
  jmp    L83
L27:
  movq   $0x1,-0x10(%rbp)
  jmp    L45
L24:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L31
  addq   $0x1,-0x8(%rbp)
  jmp    L41
L31:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L41
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L18
L41:
  addq   $0x1,-0x10(%rbp)
L45:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L24
  jmp    L81
L18:
  nop
L81:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L91
  cmpq   $0x0,-0x8(%rbp)
  jne    L65
L91:
  mov    $0x0,%eax
  jmp    L83
L65:
  mov    -0x10(%rbp),%rax
L83:
  leave
  ret
```

assistant: ```c
size_t check_domain(char *data, size_t size) {
  size_t i, np = 0;
  if (!isalnum(data[0]))
    return 0;
  for (i = 1; i < size - 1; ++i) {
    if (data[i] == '.')
      np++;
    else if (!isalnum(data[i]) && data[i] != '-')
      break;
  }
  if (!isalnum(data[i - 1]) || np == 0)
    return 0;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_domain>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movsbl (%rdi),%edi
  call   <isalnum@plt>
  mov    $0x0,%r12d
  test   %eax,%eax
  je     L17
  lea    -0x1(%rbx),%r12
  cmp    $0x1,%r12
  jbe    L51
  mov    $0x0,%r13d
  mov    $0x1,%ebx
  jmp    L89
L68:
  add    $0x1,%r13
L78:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L21
L89:
  movzbl 0x0(%rbp,%rbx,1),%edi
  cmp    $0x2e,%dil
  je     L68
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L78
  cmpb   $0x2d,0x0(%rbp,%rbx,1)
  je     L78
  mov    %rbx,%r12
L21:
  movsbl -0x1(%rbp,%r12,1),%edi
  call   <isalnum@plt>
  test   %r13,%r13
  je     L45
  test   %eax,%eax
  jne    L17
L45:
  mov    $0x0,%r12d
L17:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  movsbl 0x0(%rbp),%edi
  call   <isalnum@plt>
  mov    $0x0,%r12d
  jmp    L17
```

assistant: ```c
size_t check_domain(char *data, size_t size) {
  size_t i, np = 0;
  if (!isalnum(data[0]))
    return 0;
  for (i = 1; i < size - 1; ++i) {
    if (data[i] == '.')
      np++;
    else if (!isalnum(data[i]) && data[i] != '-')
      break;
  }
  if (!isalnum(data[i - 1]) || np == 0)
    return 0;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_domain>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  call   <isalnum@plt>
  test   %eax,%eax
  je     L98
  sub    $0x1,%r14
  cmp    $0x1,%r14
  jbe    L94
  lea    0x1(%r13),%rbx
  xor    %r12d,%r12d
  mov    $0x1,%ebp
  jmp    L54
  nopl   0x0(%rax)
L19:
  add    $0x1,%r12
L34:
  add    $0x1,%rbp
  add    $0x1,%rbx
  cmp    %r14,%rbp
  je     L58
L54:
  movsbl (%rbx),%edi
  mov    %rbx,%r15
  cmp    $0x2e,%dil
  je     L19
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L34
  cmpb   $0x2d,(%rbx)
  je     L34
  lea    -0x1(%r13,%rbp,1),%r15
  mov    %rbp,%r14
  nopl   0x0(%rax,%rax,1)
L58:
  movsbl (%r15),%edi
  call   <isalnum@plt>
  test   %r12,%r12
  je     L98
  test   %eax,%eax
  jne    L81
L98:
  xor    %r14d,%r14d
L81:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L94:
  movsbl 0x0(%r13),%edi
  call   <isalnum@plt>
  jmp    L98
```

assistant: ```c
size_t check_domain(char *data, size_t size) {
  size_t i, np = 0;
  if (!isalnum(data[0]))
    return 0;
  for (i = 1; i < size - 1; ++i) {
    if (data[i] == '.')
      np++;
    else if (!isalnum(data[i]) && data[i] != '-')
      break;
  }
  if (!isalnum(data[i - 1]) || np == 0)
    return 0;
  return i;
}
```