user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x38(%rsp),%rsi
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  call   <scanf@plt>
  cmpq   $0x0,0x38(%rsp)
  je     L21
  lea    0x58(%rsp),%rax
  lea    D7(%rip),%r12
  mov    %rax,0x28(%rsp)
  lea    0x50(%rsp),%rax
  lea    0x40(%rsp),%r15
  mov    %rax,0x8(%rsp)
  lea    0x60(%rsp),%rax
  lea    0x48(%rsp),%r14
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax)
L1:
  mov    0x28(%rsp),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x58(%rsp),%rdi
  call   <calculateFibo@plt>
  mov    %rax,%rbx
  mov    0x58(%rsp),%rax
  lea    0x1(%rax),%rdi
  call   <calculateFibo@plt>
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    %rax,%rdx
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x40(%rsp),%r8
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    0x48(%rsp),%rax
  lea    (%rbx,%r13,1),%rcx
  imul   %rbx,%r8
  mov    %rcx,0x18(%rsp)
  imul   %r13,%rax
  add    %rax,%r8
  mov    %rcx,%rax
  imul   0x50(%rsp),%rax
  add    %rax,%r8
  xor    %eax,%eax
  mov    %r8,0x10(%rsp)
  call   <scanf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x48(%rsp),%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  imul   0x40(%rsp),%rbx
  mov    0x18(%rsp),%rcx
  imul   %r13,%rdx
  mov    0x20(%rsp),%rsi
  imul   0x50(%rsp),%rcx
  add    %rdx,%rbx
  add    %rcx,%rbx
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <gcd@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  divq   0x60(%rsp)
  xor    %eax,%eax
  mov    %rdx,%rsi
  call   <printf@plt>
  subq   $0x1,0x38(%rsp)
  jne    L1
L21:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D22: %lu

tool: D7: %llu

tool: D10: Fibo Values: %llu %llu

assistant: ```c
int main() {
  unsigned long test = 0, a, b, c;
  unsigned long long N = 0, M = 0, num_1, num_2, GCD;
  unsigned long long fibo1, fib02;
  scanf("%lu", &test);
  while (test != 0) {
    scanf("%llu", &N);
    fibo1 = calculateFibo(N);
    fib02 = calculateFibo(N + 1);
    printf("Fibo Values: %llu %llu", fibo1, fib02);
    scanf("%lu", &a);
    scanf("%lu", &b);
    scanf("%lu", &c);
    num_1 = a * fibo1 + b * fib02 + c * (fib02 + fibo1);
    scanf("%lu", &a);
    scanf("%lu", &b);
    scanf("%lu", &c);
    num_2 = a * fibo1 + b * fib02 + c * (fib02 + fibo1);
    scanf("%llu", &M);
    GCD = gcd(num_1, num_2);
    printf("%llu", GCD % M);
    --test;
  }
}
```