ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_oct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L13
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <oct_to_val@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L18
  jmp    L23
L13:
  mov    $0xffffffff,%eax
  jmp    L43
L23:
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%ebx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <oct_to_val@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L18:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L0
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%ebx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <oct_to_val@plt>
  or     %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
L43:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int parse_oct(char **input) {
  int rval = 0;
  if (is_oct_digit(**input)) {
    rval = oct_to_val(**input);
    (*input)++;
  } else {
    return -1;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  return rval & 0xFF;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_oct>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L18
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  mov    %eax,%ebp
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl 0x1(%rax),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L47
L37:
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L14
L36:
  movzbl %bpl,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L47:
  shl    $0x3,%ebp
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  or     %eax,%ebp
  addq   $0x1,(%rbx)
  jmp    L37
L14:
  shl    $0x3,%ebp
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  or     %eax,%ebp
  addq   $0x1,(%rbx)
  jmp    L36
L18:
  mov    $0xffffffff,%eax
  jmp    L20
```

assistant: ```c
int parse_oct(char **input) {
  int rval = 0;
  if (is_oct_digit(**input)) {
    rval = oct_to_val(**input);
    (*input)++;
  } else {
    return -1;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  return rval & 0xFF;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_oct>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L45
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  mov    (%rbx),%rdx
  mov    %eax,%ebp
  lea    0x1(%rdx),%rax
  mov    %rax,(%rbx)
  movsbl 0x1(%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L21
  mov    (%rbx),%rdx
  movsbl (%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L35
L14:
  movzbl %bpl,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L21:
  mov    (%rbx),%rax
  shl    $0x3,%ebp
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  or     %eax,%ebp
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L14
L35:
  mov    (%rbx),%rax
  shl    $0x3,%ebp
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  addq   $0x1,(%rbx)
  or     %eax,%ebp
  jmp    L14
  nopl   (%rax)
L45:
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int parse_oct(char **input) {
  int rval = 0;
  if (is_oct_digit(**input)) {
    rval = oct_to_val(**input);
    (*input)++;
  } else {
    return -1;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  return rval & 0xFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_oct>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  movsbl (%rax),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L33
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  mov    (%rbx),%rdx
  mov    %eax,%ebp
  lea    0x1(%rdx),%rax
  mov    %rax,(%rbx)
  movsbl 0x1(%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L40
  mov    (%rbx),%rdx
  movsbl (%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  jne    L27
L6:
  movzbl %bpl,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L40:
  mov    (%rbx),%rax
  shl    $0x3,%ebp
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  or     %eax,%ebp
  mov    (%rbx),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movsbl (%rdx),%edi
  call   <is_oct_digit@plt>
  test   %rax,%rax
  je     L6
L27:
  mov    (%rbx),%rax
  shl    $0x3,%ebp
  movsbl (%rax),%edi
  call   <oct_to_val@plt>
  addq   $0x1,(%rbx)
  or     %eax,%ebp
  jmp    L6
  nopl   (%rax)
L33:
  mov    $0xffffffff,%eax
  jmp    L43
```

assistant: ```c
int parse_oct(char **input) {
  int rval = 0;
  if (is_oct_digit(**input)) {
    rval = oct_to_val(**input);
    (*input)++;
  } else {
    return -1;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  if (is_oct_digit(**input)) {
    rval = (rval << 3) | oct_to_val(**input);
    (*input)++;
  }
  return rval & 0xFF;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L18
L38:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jle    L27
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L38
L27:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L29
  mov    -0x14(%rbp),%eax
  jmp    L37
L29:
  mov    -0x18(%rbp),%eax
L37:
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D8
type: string

tool: D13: %d %d

tool: D8: %d %d


assistant: ```c
int main() {
  int a, b;
  int ans_diff = 0, ans_same = 0;
  scanf("%d %d", &a, &b);
  while (a > 0 && b > 0) {
    a--;
    b--;
    ans_diff++;
  }
  ans_same = a == 0 ? b : a;
  ans_same /= 2;
  printf("%d %d\n", ans_diff, ans_same);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L73
  mov    0x4(%rsp),%edx
  mov    $0x0,%edi
  mov    $0x0,%r8d
  mov    $0x0,%esi
  mov    $0x1,%ecx
L16:
  test   %edx,%edx
  jle    L80
  sub    $0x1,%edx
  add    $0x1,%esi
  mov    %ecx,%r8d
  mov    %ecx,%edi
  sub    $0x1,%eax
  je     L28
  mov    %eax,%ebx
  jmp    L16
L28:
  mov    %edx,0x4(%rsp)
  movl   $0x0,(%rsp)
L6:
  mov    0x4(%rsp),%eax
L34:
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L80:
  test   %dil,%dil
  je     L90
  mov    %edx,0x4(%rsp)
L90:
  test   %r8b,%r8b
  je     L53
  mov    %ebx,(%rsp)
L53:
  test   %eax,%eax
  jne    L34
  jmp    L6
L73:
  mov    $0x0,%esi
  jmp    L53
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D3: %d %d

tool: D5: %d %d


assistant: ```c
int main() {
  int a, b;
  int ans_diff = 0, ans_same = 0;
  scanf("%d %d", &a, &b);
  while (a > 0 && b > 0) {
    a--;
    b--;
    ans_diff++;
  }
  ans_same = a == 0 ? b : a;
  ans_same /= 2;
  printf("%d %d\n", ans_diff, ans_same);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L8
  mov    0x4(%rsp),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  jmp    L15
  xchg   %ax,%ax
L2:
  sub    $0x1,%edx
  add    $0x1,%esi
  mov    $0x1,%ecx
  sub    $0x1,%eax
  je     L7
  mov    %eax,%ebx
L15:
  test   %edx,%edx
  jg     L2
  test   %cl,%cl
  je     L42
  mov    %edx,0x4(%rsp)
  mov    %ebx,(%rsp)
L42:
  mov    %eax,%edx
  lea    D10(%rip),%rdi
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L7:
  mov    %edx,0x4(%rsp)
  mov    %esi,%eax
  movl   $0x0,(%rsp)
L82:
  mov    %eax,%esi
  mov    0x4(%rsp),%eax
  jmp    L42
L8:
  je     L82
  xor    %esi,%esi
  jmp    L42
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string

tool: D18: %d %d

tool: D10: %d %d


assistant: ```c
int main() {
  int a, b;
  int ans_diff = 0, ans_same = 0;
  scanf("%d %d", &a, &b);
  while (a > 0 && b > 0) {
    a--;
    b--;
    ans_diff++;
  }
  ans_same = a == 0 ? b : a;
  ans_same /= 2;
  printf("%d %d\n", ans_diff, ans_same);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L80
  mov    0x4(%rsp),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  jmp    L65
  xchg   %ax,%ax
L82:
  sub    $0x1,%edx
  add    $0x1,%esi
  mov    $0x1,%ecx
  sub    $0x1,%eax
  je     L38
  mov    %eax,%ebx
L65:
  test   %edx,%edx
  jg     L82
  test   %cl,%cl
  je     L27
  mov    %edx,0x4(%rsp)
  mov    %ebx,(%rsp)
L27:
  mov    %eax,%edx
  lea    D15(%rip),%rdi
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L38:
  mov    %edx,0x4(%rsp)
  mov    %esi,%eax
  movl   $0x0,(%rsp)
L68:
  mov    %eax,%esi
  mov    0x4(%rsp),%eax
  jmp    L27
L80:
  je     L68
  xor    %esi,%esi
  jmp    L27
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D8: %d %d

tool: D15: %d %d


assistant: ```c
int main() {
  int a, b;
  int ans_diff = 0, ans_same = 0;
  scanf("%d %d", &a, &b);
  while (a > 0 && b > 0) {
    a--;
    b--;
    ans_diff++;
  }
  ans_same = a == 0 ? b : a;
  ans_same /= 2;
  printf("%d %d\n", ans_diff, ans_same);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<ivector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *ivector(int n) {
  int *vec = (int *)malloc(sizeof(int) * n);
  assert(vec);
  memset(vec, 0, n * sizeof(int));
  return vec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ivector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x0(,%rdi,4),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *ivector(int n) {
  int *vec = (int *)malloc(sizeof(int) * n);
  assert(vec);
  memset(vec, 0, n * sizeof(int));
  return vec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ivector>:
  endbr64
  push   %r13
  lea    0x0(,%rdi,4),%r13d
  push   %r12
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *ivector(int n) {
  int *vec = (int *)malloc(sizeof(int) * n);
  assert(vec);
  memset(vec, 0, n * sizeof(int));
  return vec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ivector>:
  endbr64
  push   %r13
  lea    0x0(,%rdi,4),%r13d
  push   %r12
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *ivector(int n) {
  int *vec = (int *)malloc(sizeof(int) * n);
  assert(vec);
  memset(vec, 0, n * sizeof(int));
  return vec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x3f,%rax
  shr    $0x6,%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L11
  cmpl   $0x20,-0x1c(%rbp)
  jbe    L0
L11:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  mov    -0x1c(%rbp),%eax
  neg    %eax
  and    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    $0xffffffffffffffff,%rsi
  mov    %edx,%ecx
  shr    %cl,%rsi
  mov    %rsi,%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void bitmap_fill(unsigned long *dst, unsigned int nbits) {
  unsigned int nlongs = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  if (!(__builtin_constant_p(nbits) && (nbits) <= 32)) {
    unsigned int len = (nlongs - 1) * sizeof(unsigned long);
    memset(dst, 0xff, len);
  }
  dst[nlongs - 1] = (~0UL >> (-(nbits) & (32 - 1)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitmap_fill>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %esi,%ebp
  add    $0x3f,%rbp
  shr    $0x6,%rbp
  mov    %esi,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L1
  test   %rax,%rax
  jne    L3
L1:
  lea    -0x8(,%rbp,8),%edx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L3:
  lea    -0x1(%rbp),%edx
  mov    %ebx,%ecx
  neg    %ecx
  and    $0x1f,%ecx
  mov    $0xffffffffffffffff,%rax
  shr    %cl,%rax
  mov    %rax,(%r12,%rdx,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bitmap_fill(unsigned long *dst, unsigned int nbits) {
  unsigned int nlongs = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  if (!(__builtin_constant_p(nbits) && (nbits) <= 32)) {
    unsigned int len = (nlongs - 1) * sizeof(unsigned long);
    memset(dst, 0xff, len);
  }
  dst[nlongs - 1] = (~0UL >> (-(nbits) & (32 - 1)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_fill>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %rbp,%rbx
  add    $0x3f,%rbp
  shr    $0x6,%rbp
  sub    $0x1,%ebp
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L6
  test   %rax,%rax
  je     L6
L16:
  mov    %ebx,%ecx
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  neg    %ecx
  and    $0x1f,%ecx
  shr    %cl,%rax
  mov    %rax,(%r12,%rbp,8)
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    0x0(,%rbp,8),%edx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  jmp    L16
```

assistant: ```c
void bitmap_fill(unsigned long *dst, unsigned int nbits) {
  unsigned int nlongs = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  if (!(__builtin_constant_p(nbits) && (nbits) <= 32)) {
    unsigned int len = (nlongs - 1) * sizeof(unsigned long);
    memset(dst, 0xff, len);
  }
  dst[nlongs - 1] = (~0UL >> (-(nbits) & (32 - 1)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_fill>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %rbp,%rbx
  add    $0x3f,%rbp
  shr    $0x6,%rbp
  sub    $0x1,%ebp
  call   <__builtin_constant_p@plt>
  cmp    $0x20,%ebx
  ja     L7
  test   %rax,%rax
  je     L7
L10:
  mov    %ebx,%ecx
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  neg    %ecx
  and    $0x1f,%ecx
  shr    %cl,%rax
  mov    %rax,(%r12,%rbp,8)
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    0x0(,%rbp,8),%edx
  mov    $0xff,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  jmp    L10
```

assistant: ```c
void bitmap_fill(unsigned long *dst, unsigned int nbits) {
  unsigned int nlongs = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  if (!(__builtin_constant_p(nbits) && (nbits) <= 32)) {
    unsigned int len = (nlongs - 1) * sizeof(unsigned long);
    memset(dst, 0xff, len);
  }
  dst[nlongs - 1] = (~0UL >> (-(nbits) & (32 - 1)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matchclass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  sub    $0x61,%eax
  cmp    $0x16,%eax
  ja     L98
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D10(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <iscntrl@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ispunct@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L66
L98:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  jmp    L76
L66:
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L28
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  jmp    L76
L28:
  mov    -0x4(%rbp),%eax
L76:
  leave
  ret
```

assistant: ```c
int matchclass(int c, int cl) {
  int res;
  switch (tolower((unsigned char)cl)) {
  case 'a':
    res = isalpha((unsigned char)c);
    break;
  case 'c':
    res = iscntrl((unsigned char)c);
    break;
  case 'd':
    res = isdigit((unsigned char)c);
    break;
  case 'l':
    res = islower((unsigned char)c);
    break;
  case 'p':
    res = ispunct((unsigned char)c);
    break;
  case 's':
    res = isspace((unsigned char)c);
    break;
  case 'u':
    res = isupper((unsigned char)c);
    break;
  case 'w':
    res = isalnum((unsigned char)c);
    break;
  default:
    return (cl == c);
  }
  return (islower((unsigned char)cl) ? res : !res);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matchclass>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  movzbl %sil,%ebp
  mov    %ebp,%edi
  call   <tolower@plt>
  sub    $0x61,%eax
  cmp    $0x16,%eax
  ja     L49
  mov    %eax,%eax
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  movzbl %bl,%edi
  call   <isalpha@plt>
  mov    %eax,%ebx
L42:
  mov    %ebp,%edi
  call   <islower@plt>
  test   %eax,%eax
  jne    L92
  test   %ebx,%ebx
  sete   %bl
  movzbl %bl,%ebx
L92:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  movzbl %bl,%edi
  call   <iscntrl@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <isdigit@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <islower@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <ispunct@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <isspace@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <isupper@plt>
  mov    %eax,%ebx
  jmp    L42
  movzbl %bl,%edi
  call   <isalnum@plt>
  mov    %eax,%ebx
  jmp    L42
L49:
  cmp    %ebx,%r12d
  sete   %bl
  movzbl %bl,%ebx
  jmp    L92
```

assistant: ```c
int matchclass(int c, int cl) {
  int res;
  switch (tolower((unsigned char)cl)) {
  case 'a':
    res = isalpha((unsigned char)c);
    break;
  case 'c':
    res = iscntrl((unsigned char)c);
    break;
  case 'd':
    res = isdigit((unsigned char)c);
    break;
  case 'l':
    res = islower((unsigned char)c);
    break;
  case 'p':
    res = ispunct((unsigned char)c);
    break;
  case 's':
    res = isspace((unsigned char)c);
    break;
  case 'u':
    res = isupper((unsigned char)c);
    break;
  case 'w':
    res = isalnum((unsigned char)c);
    break;
  default:
    return (cl == c);
  }
  return (islower((unsigned char)cl) ? res : !res);
}
```