ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%r13
  lea    D6(%rip),%r14
  lea    D44(%rip),%rbp
  jmp    L99
L58:
  add    $0x1,%ebx
  cmp    %ecx,%ebx
  jg     L15
L127:
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L58
  cmp    %ecx,%ebx
  jg     L58
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x4(%rsp)
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L58
  cmp    %ebx,%ecx
  jge    L12
  jmp    L58
L15:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L65
  lea    0x1(%rax),%esi
  mov    $0x1,%ebx
  mov    $0x2,%ecx
L30:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%ebx
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L30
L135:
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L99:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  je     L53
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%ecx
  mov    $0x2,%ebx
  cmp    $0x1,%eax
  jg     L127
  jmp    L15
L65:
  mov    $0x1,%ebx
  jmp    L135
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D44
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string

tool: D5: %d

tool: D6: %d = 

tool: D44: %d * 

tool: D11: %d


tool: D18: With %d marbles, %d different rectangles can be constructed.


assistant: ```c
int main() {
  int n, m;
  int i, j, count;
  while (1) {
    scanf("%d", &n);
    if (n == 0)
      break;
    m = n;
    printf("%d = ", n);
    count = 1;
    i = 2;
    j = sqrt(n);
    while (i <= j) {
      while (n % i == 0 && i <= j) {
        printf("%d * ", i);
        n /= i;
        j = sqrt(n);
      }
      i++;
    }
    j = sqrt(m);
    for (i = 2; i <= j; i++) {
      if (m % i == 0)
        count++;
    }
    printf("%d\n", n);
    printf("With %d marbles, %d different rectangles can be constructed.\n", m, count);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D39(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    D41(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L1:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  je     L109
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0x2,%r14d
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L91
L93:
  mov    %edi,%eax
  cltd
  idiv   %r14d
  test   %edx,%edx
  jne    L58
  cmp    %esi,%r14d
  jle    L118
  jmp    L58
  nopl   0x0(%rax)
L115:
  cmp    %r14d,%esi
  jl     L58
L118:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %r14d
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  mov    %edi,%eax
  cltd
  idiv   %r14d
  test   %edx,%edx
  je     L115
L58:
  add    $0x1,%r14d
  cmp    %esi,%r14d
  jle    L93
L91:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L110
  lea    0x1(%rax),%esi
  mov    $0x1,%r14d
  mov    $0x2,%ecx
  nopl   0x0(%rax)
L35:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r14d
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L35
L8:
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%edx
  mov    %r12d,%esi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L109:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L110:
  mov    $0x1,%r14d
  jmp    L8
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D41
data_type: string
name: parse_data
arguments: label: D24
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D39: %d = 

tool: D5: %d

tool: D41: %d * 

tool: D24: %d


tool: D8: With %d marbles, %d different rectangles can be constructed.


assistant: ```c
int main() {
  int n, m;
  int i, j, count;
  while (1) {
    scanf("%d", &n);
    if (n == 0)
      break;
    m = n;
    printf("%d = ", n);
    count = 1;
    i = 2;
    j = sqrt(n);
    while (i <= j) {
      while (n % i == 0 && i <= j) {
        printf("%d * ", i);
        n /= i;
        j = sqrt(n);
      }
      i++;
    }
    j = sqrt(m);
    for (i = 2; i <= j; i++) {
      if (m % i == 0)
        count++;
    }
    printf("%d\n", n);
    printf("With %d marbles, %d different rectangles can be constructed.\n", m, count);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D25(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  lea    D42(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  nopl   0x0(%rax)
L9:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  je     L118
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <sqrt@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L92
  mov    0x4(%rsp),%edi
  mov    $0x2,%r14d
L78:
  mov    %edi,%eax
  cltd
  idiv   %r14d
  test   %edx,%edx
  jne    L36
  cmp    %esi,%r14d
  jle    L2
  jmp    L36
  nopl   0x0(%rax)
L30:
  cmp    %r14d,%esi
  jl     L36
L2:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %r14d
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  call   <sqrt@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  mov    %edi,%eax
  cltd
  idiv   %r14d
  test   %edx,%edx
  je     L30
L36:
  add    $0x1,%r14d
  cmp    %esi,%r14d
  jle    L78
L92:
  mov    %r12d,%edi
  call   <sqrt@plt>
  cmp    $0x1,%eax
  jle    L124
  lea    0x1(%rax),%esi
  mov    $0x1,%r14d
  mov    $0x2,%ecx
  nopl   0x0(%rax)
L126:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%r14d
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L126
L1:
  mov    0x4(%rsp),%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%edx
  mov    %r12d,%esi
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L118:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L124:
  mov    $0x1,%r14d
  jmp    L1
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D42
datatype: string
name: parse_data
arguments: tag: D43
datatype: string
name: parse_data
arguments: tag: D8
datatype: string

tool: D25: %d = 

tool: D45: %d

tool: D42: %d * 

tool: D43: %d


tool: D8: With %d marbles, %d different rectangles can be constructed.


assistant: ```c
int main() {
  int n, m;
  int i, j, count;
  while (1) {
    scanf("%d", &n);
    if (n == 0)
      break;
    m = n;
    printf("%d = ", n);
    count = 1;
    i = 2;
    j = sqrt(n);
    while (i <= j) {
      while (n % i == 0 && i <= j) {
        printf("%d * ", i);
        n /= i;
        j = sqrt(n);
      }
      i++;
    }
    j = sqrt(m);
    for (i = 2; i <= j; i++) {
      if (m % i == 0)
        count++;
    }
    printf("%d\n", n);
    printf("With %d marbles, %d different rectangles can be constructed.\n", m, count);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<remem_t_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: Erreur d'allocation de memoire'


assistant: ```c
int *remem_t_int(int *p, int i) {
  int *aux;
  aux = (int *)realloc(p, i * sizeof(int));
  if (aux == NULL) {
    printf("Erreur d'allocation de memoire'\n");
    exit(-1);
  }
  p = aux;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remem_t_int>:
  endbr64
  push   %rbx
  shl    $0x2,%esi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
L3:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: Erreur d'allocation de memoire'


assistant: ```c
int *remem_t_int(int *p, int i) {
  int *aux;
  aux = (int *)realloc(p, i * sizeof(int));
  if (aux == NULL) {
    printf("Erreur d'allocation de memoire'\n");
    exit(-1);
  }
  p = aux;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<remem_t_int>:
  endbr64
  push   %r12
  shl    $0x2,%esi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: Erreur d'allocation de memoire'


assistant: ```c
int *remem_t_int(int *p, int i) {
  int *aux;
  aux = (int *)realloc(p, i * sizeof(int));
  if (aux == NULL) {
    printf("Erreur d'allocation de memoire'\n");
    exit(-1);
  }
  p = aux;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remem_t_int>:
  endbr64
  push   %r12
  shl    $0x2,%esi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: Erreur d'allocation de memoire'


assistant: ```c
int *remem_t_int(int *p, int i) {
  int *aux;
  aux = (int *)realloc(p, i * sizeof(int));
  if (aux == NULL) {
    printf("Erreur d'allocation de memoire'\n");
    exit(-1);
  }
  p = aux;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cpuid_num_perfevtsel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0xc(%rbp)
  lea    -0x10(%rbp),%rdi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0xc(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <cpuid@plt>
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int cpuid_num_perfevtsel(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((15)) - ((8)) + 1)) - 1) << ((8)))) >> (8));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cpuid_num_perfevtsel>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0xa,%edi
  call   <cpuid@plt>
  movzbl 0x9(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_num_perfevtsel(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((15)) - ((8)) + 1)) - 1) << ((8)))) >> (8));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cpuid_num_perfevtsel>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  movzbl 0x9(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_num_perfevtsel(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((15)) - ((8)) + 1)) - 1) << ((8)))) >> (8));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cpuid_num_perfevtsel>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xa,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <cpuid@plt>
  movzbl 0x9(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cpuid_num_perfevtsel(void) {
  uint64_t rax, rbx, rcx, rdx;
  int leaf = 10;
  cpuid(leaf, &rax, &rbx, &rcx, &rdx);
  return (((uint64_t)(rax) & ((((uint64_t)1 << (((15)) - ((8)) + 1)) - 1) << ((8)))) >> (8));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L3
  mov    $0x0,%eax
  jmp    L1
L3:
  mov    -0x4(%rbp),%eax
L1:
  leave
  ret
```

assistant: ```c
int is(const char *x, char *s) {
  int i = strlen(x);
  if (strncmp(x, s, i))
    return 0;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int is(const char *x, char *s) {
  int i = strlen(x);
  if (strncmp(x, s, i))
    return 0;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is(const char *x, char *s) {
  int i = strlen(x);
  if (strncmp(x, s, i))
    return 0;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  mov    %eax,%r12d
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is(const char *x, char *s) {
  int i = strlen(x);
  if (strncmp(x, s, i))
    return 0;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<GrOffScreen4BPPLineDrawV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  add    %edx,%eax
  add    $0x6,%eax
  cltq
  add    $0x30,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  jmp    L47
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xfffffff0,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x20(%rbp)
L47:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L36
  jmp    L39
L2:
  shll   $0x4,-0x28(%rbp)
  jmp    L34
L57:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x20(%rbp)
L34:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L57
L39:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GrOffScreen4BPPLineDrawV(void *pvDisplayData, int lX, int lY1, int lY2, unsigned int ulValue) {
  unsigned char *pucData;
  int lBytesPerRow;
  ;
  pucData = (unsigned char *)pvDisplayData;
  lBytesPerRow = (*(unsigned short *)(pucData + 1) + 1) / 2;
  pucData += (lBytesPerRow * lY1) + (lX / 2) + 6 + (16 * 3);
  if (lX & 1) {
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0xf0) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  } else {
    ulValue <<= 4;
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0x0f) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GrOffScreen4BPPLineDrawV>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %ecx,%edi
  movzwl 0x1(%r10),%esi
  add    $0x1,%esi
  sar    %esi
  mov    %esi,%eax
  imul   %edx,%eax
  mov    %r9d,%ecx
  shr    $0x1f,%ecx
  add    %r9d,%ecx
  sar    %ecx
  add    %ecx,%eax
  cltq
  lea    0x36(%r10,%rax,1),%rax
  test   $0x1,%r9b
  je     L29
  cmp    %edi,%edx
  jg     L37
  add    $0x1,%edi
  movslq %esi,%rsi
L28:
  movzbl (%rax),%ecx
  and    $0xfffffff0,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rsi,%rax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L28
  ret
L29:
  shl    $0x4,%r8d
  cmp    %edi,%edx
  jg     L37
  add    $0x1,%edi
  movslq %esi,%rsi
L42:
  movzbl (%rax),%ecx
  and    $0xf,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rsi,%rax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L42
L37:
  ret
```

assistant: ```c
void GrOffScreen4BPPLineDrawV(void *pvDisplayData, int lX, int lY1, int lY2, unsigned int ulValue) {
  unsigned char *pucData;
  int lBytesPerRow;
  ;
  pucData = (unsigned char *)pvDisplayData;
  lBytesPerRow = (*(unsigned short *)(pucData + 1) + 1) / 2;
  pucData += (lBytesPerRow * lY1) + (lX / 2) + 6 + (16 * 3);
  if (lX & 1) {
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0xf0) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  } else {
    ulValue <<= 4;
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0x0f) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GrOffScreen4BPPLineDrawV>:
  endbr64
  mov    %rdi,%r10
  movzwl 0x1(%rdi),%edi
  mov    %esi,%r9d
  mov    %ecx,%esi
  mov    %r9d,%ecx
  add    $0x1,%edi
  shr    $0x1f,%ecx
  sar    %edi
  add    %r9d,%ecx
  mov    %edi,%eax
  sar    %ecx
  imul   %edx,%eax
  add    %ecx,%eax
  and    $0x1,%r9d
  cltq
  lea    0x36(%r10,%rax,1),%rax
  je     L12
  movslq %edi,%rdi
  lea    0x1(%rsi),%r9d
  cmp    %esi,%edx
  jg     L40
  nop
L41:
  movzbl (%rax),%ecx
  add    $0x1,%edx
  and    $0xfffffff0,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rdi,%rax
  cmp    %r9d,%edx
  jne    L41
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  shl    $0x4,%r8d
  cmp    %esi,%edx
  jg     L40
  movslq %edi,%rdi
  add    $0x1,%esi
  xchg   %ax,%ax
L7:
  movzbl (%rax),%ecx
  add    $0x1,%edx
  and    $0xf,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rdi,%rax
  cmp    %edx,%esi
  jne    L7
L40:
  ret
```

assistant: ```c
void GrOffScreen4BPPLineDrawV(void *pvDisplayData, int lX, int lY1, int lY2, unsigned int ulValue) {
  unsigned char *pucData;
  int lBytesPerRow;
  ;
  pucData = (unsigned char *)pvDisplayData;
  lBytesPerRow = (*(unsigned short *)(pucData + 1) + 1) / 2;
  pucData += (lBytesPerRow * lY1) + (lX / 2) + 6 + (16 * 3);
  if (lX & 1) {
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0xf0) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  } else {
    ulValue <<= 4;
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0x0f) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GrOffScreen4BPPLineDrawV>:
  endbr64
  mov    %rdi,%r10
  movzwl 0x1(%rdi),%edi
  mov    %esi,%r9d
  mov    %ecx,%esi
  mov    %r9d,%ecx
  add    $0x1,%edi
  shr    $0x1f,%ecx
  sar    %edi
  add    %r9d,%ecx
  mov    %edi,%eax
  sar    %ecx
  imul   %edx,%eax
  add    %ecx,%eax
  and    $0x1,%r9d
  cltq
  lea    0x36(%r10,%rax,1),%rax
  je     L11
  movslq %edi,%rdi
  lea    0x1(%rsi),%r9d
  cmp    %esi,%edx
  jg     L24
  nop
L23:
  movzbl (%rax),%ecx
  add    $0x1,%edx
  and    $0xfffffff0,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rdi,%rax
  cmp    %r9d,%edx
  jne    L23
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  shl    $0x4,%r8d
  cmp    %esi,%edx
  jg     L24
  movslq %edi,%rdi
  add    $0x1,%esi
  xchg   %ax,%ax
L15:
  movzbl (%rax),%ecx
  add    $0x1,%edx
  and    $0xf,%ecx
  or     %r8d,%ecx
  mov    %cl,(%rax)
  add    %rdi,%rax
  cmp    %esi,%edx
  jne    L15
L24:
  ret
```

assistant: ```c
void GrOffScreen4BPPLineDrawV(void *pvDisplayData, int lX, int lY1, int lY2, unsigned int ulValue) {
  unsigned char *pucData;
  int lBytesPerRow;
  ;
  pucData = (unsigned char *)pvDisplayData;
  lBytesPerRow = (*(unsigned short *)(pucData + 1) + 1) / 2;
  pucData += (lBytesPerRow * lY1) + (lX / 2) + 6 + (16 * 3);
  if (lX & 1) {
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0xf0) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  } else {
    ulValue <<= 4;
    while (lY1 <= lY2) {
      *pucData = (*pucData & 0x0f) | ulValue;
      pucData += lBytesPerRow;
      lY1++;
    }
  }
}
```