user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x40(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x40(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L31
L292:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L292
L31:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L120
L149:
  mov    %rsp,%r12
  test   %ecx,%ecx
  jle    L191
  movl   $0x0,-0x44(%rbp)
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  lea    -0x3c(%rbp),%r14
  nopl   0x0(%rax)
L234:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  mov    -0x3c(%rbp),%edx
  test   %esi,%esi
  jle    L85
  mov    %esi,%ecx
  mov    %r12,%rax
  lea    (%r12,%rcx,4),%rcx
  cs nopw 0x0(%rax,%rax,1)
L70:
  cmp    %edx,(%rax)
  jne    L268
  movl   $0x0,(%rax)
L268:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L70
L85:
  mov    %edx,(%r12,%r15,4)
  and    $0x1,%edx
  jne    L224
  addl   $0x1,-0x44(%rbp)
L162:
  add    $0x1,%r15
  cmp    %r15d,%esi
  jg     L234
  test   %esi,%esi
  jle    L153
  lea    -0x1(%rsi),%eax
  cmp    $0x3,%eax
  jbe    L81
  mov    %esi,%edx
  pxor   %xmm3,%xmm3
  movdqa D3(%rip),%xmm6
  mov    %r12,%rax
  shr    $0x2,%edx
  movdqa %xmm3,%xmm2
  movdqa %xmm3,%xmm5
  shl    $0x4,%rdx
  add    %r12,%rdx
  nopl   0x0(%rax)
L186:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm0
  pand   %xmm6,%xmm0
  pcmpeqd %xmm5,%xmm0
  movdqa %xmm0,%xmm4
  pandn  %xmm1,%xmm0
  pand   %xmm1,%xmm4
  paddd  %xmm0,%xmm3
  paddd  %xmm4,%xmm2
  cmp    %rax,%rdx
  jne    L186
  movdqa %xmm3,%xmm0
  mov    %esi,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm3
  movdqa %xmm3,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm3
  movdqa %xmm2,%xmm0
  psrldq $0x8,%xmm0
  movd   %xmm3,%ecx
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%r9d
  test   $0x3,%sil
  je     L188
L242:
  movslq %eax,%rdx
  lea    (%r12,%rdx,4),%rdx
  mov    (%rdx),%edi
  test   $0x1,%dil
  jne    L168
  add    %edi,%r9d
L96:
  lea    0x1(%rax),%edi
  cmp    %esi,%edi
  jge    L188
  mov    0x4(%rdx),%edi
  test   $0x1,%dil
  jne    L264
  add    %edi,%r9d
L259:
  lea    0x2(%rax),%edi
  cmp    %esi,%edi
  jge    L188
  mov    0x8(%rdx),%edi
  test   $0x1,%dil
  jne    L142
  add    %edi,%r9d
L209:
  add    $0x3,%eax
  cmp    %eax,%esi
  jle    L188
  mov    0xc(%rdx),%eax
  test   $0x1,%al
  je     L83
  add    %eax,%ecx
L188:
  cmp    %ecx,%r9d
  jle    L132
  mov    -0x44(%rbp),%esi
  mov    %r9d,%ecx
  mov    %r13d,%edx
  lea    D38(%rip),%rdi
  call   <printf@plt>
L281:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L160
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L224:
  add    $0x1,%r13d
  jmp    L162
L191:
  movl   $0x0,-0x44(%rbp)
  xor    %r13d,%r13d
L153:
  xor    %ecx,%ecx
L132:
  mov    -0x44(%rbp),%esi
  mov    %r13d,%edx
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L281
L168:
  add    %edi,%ecx
  jmp    L96
L264:
  add    %edi,%ecx
  jmp    L259
L142:
  add    %edi,%ecx
  jmp    L209
L83:
  add    %eax,%r9d
  jmp    L188
L120:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L149
L81:
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  xor    %eax,%eax
  jmp    L242
L160:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D3
datatype: byte[16]
name: read_data
arguments: data_tag: D38
datatype: string

tool: D9: %d

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D38: %d
%d
%d


assistant: ```c
int main(int argc, char const *argv[]) {
  int a, b, i, j, fj = 0, fm = 0, sj = 0, sm = 0;
  scanf("%d", &a);
  int f[a];
  for (i = 0; i < a; ++i) {
    scanf("%d", &b);
    for (j = 0; j < a; ++j) {
      if (f[j] == b) {
        f[j] = 0;
      }
    }
    f[i] = b;
    if (b % 2 == 0) {
      fj++;
    } else {
      fm++;
    }
  }
  for (i = 0; i < a; ++i) {
    if (f[i] % 2 == 0) {
      sj += f[i];
    } else {
      sm += f[i];
    }
  }
  sj > sm ? printf("%d\n%d\n%d\n", fj, fm, sj) : printf("%d\n%d\n%d\n", fj, fm, sm);
  return 0;
}
```