ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<toDegrees>:
  endbr64
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: byte[8]

tool: {"D7": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
double toDegrees(double rads) {
  double convert = 360 / (2 * 3.1415926535897932384626433832795);
  return rads * convert;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toDegrees>:
  endbr64
  mulsd  D4(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: byte[8]

tool: {"D4": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
double toDegrees(double rads) {
  double convert = 360 / (2 * 3.1415926535897932384626433832795);
  return rads * convert;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_spin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %edi,-0x14(%rbp)
  movsd  %xmm2,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L64
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <mat_Dabs@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L21
  mov    $0x1,%eax
  jmp    L14
L21:
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <mat_Dabs@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L36
  mov    $0xffffffff,%eax
  jmp    L14
L36:
  mov    $0x0,%eax
  jmp    L14
L64:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <mat_Dabs@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L74
  mov    -0x14(%rbp),%eax
  jmp    L14
L74:
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int check_spin(const double spin_j, const double spin_k, const int sign, const double symprec) {
  if (sign == 0) {
    if (mat_Dabs(spin_j - spin_k) < symprec) {
      return 1;
    }
    if (mat_Dabs(spin_j + spin_k) < symprec) {
      return -1;
    }
    return 0;
  } else {
    if (mat_Dabs(spin_j - spin_k * sign) < symprec) {
      return sign;
    } else {
      return 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_spin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbp
  movsd  %xmm1,0x8(%rsp)
  movq   %xmm2,%r12
  test   %edi,%edi
  jne    L27
  subsd  %xmm1,%xmm0
  call   <mat_Dabs@plt>
  mov    $0x1,%eax
  movq   %r12,%xmm3
  comisd %xmm0,%xmm3
  ja     L0
  movq   %rbp,%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <mat_Dabs@plt>
  movq   %r12,%xmm6
  comisd %xmm0,%xmm6
  seta   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L0
L27:
  mov    %edi,%ebx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mulsd  0x8(%rsp),%xmm1
  subsd  %xmm1,%xmm0
  call   <mat_Dabs@plt>
  movq   %r12,%xmm5
  comisd %xmm0,%xmm5
  mov    $0x0,%eax
  cmova  %ebx,%eax
L0:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_spin(const double spin_j, const double spin_k, const int sign, const double symprec) {
  if (sign == 0) {
    if (mat_Dabs(spin_j - spin_k) < symprec) {
      return 1;
    }
    if (mat_Dabs(spin_j + spin_k) < symprec) {
      return -1;
    }
    return 0;
  } else {
    if (mat_Dabs(spin_j - spin_k * sign) < symprec) {
      return sign;
    } else {
      return 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_spin>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm3
  sub    $0x20,%rsp
  movsd  %xmm2,0x8(%rsp)
  test   %edi,%edi
  jne    L0
  movsd  %xmm0,0x18(%rsp)
  subsd  %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm4
  mov    $0x1,%eax
  comisd %xmm0,%xmm4
  jbe    L17
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm4
  xor    %eax,%eax
  comisd %xmm0,%xmm4
  seta   %al
  add    $0x20,%rsp
  neg    %eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  pxor   %xmm0,%xmm0
  mov    %edi,%ebx
  cvtsi2sd %edi,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm5
  xor    %eax,%eax
  comisd %xmm0,%xmm5
  cmova  %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int check_spin(const double spin_j, const double spin_k, const int sign, const double symprec) {
  if (sign == 0) {
    if (mat_Dabs(spin_j - spin_k) < symprec) {
      return 1;
    }
    if (mat_Dabs(spin_j + spin_k) < symprec) {
      return -1;
    }
    return 0;
  } else {
    if (mat_Dabs(spin_j - spin_k * sign) < symprec) {
      return sign;
    } else {
      return 0;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_spin>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm3
  sub    $0x20,%rsp
  movsd  %xmm2,0x8(%rsp)
  test   %edi,%edi
  jne    L1
  movsd  %xmm0,0x18(%rsp)
  subsd  %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm4
  mov    $0x1,%eax
  comisd %xmm0,%xmm4
  jbe    L15
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm4
  xor    %eax,%eax
  comisd %xmm0,%xmm4
  seta   %al
  add    $0x20,%rsp
  neg    %eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  pxor   %xmm0,%xmm0
  mov    %edi,%ebx
  cvtsi2sd %edi,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  call   <mat_Dabs@plt>
  movsd  0x8(%rsp),%xmm5
  xor    %eax,%eax
  comisd %xmm0,%xmm5
  cmova  %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
```

assistant: ```c
int check_spin(const double spin_j, const double spin_k, const int sign, const double symprec) {
  if (sign == 0) {
    if (mat_Dabs(spin_j - spin_k) < symprec) {
      return 1;
    }
    if (mat_Dabs(spin_j + spin_k) < symprec) {
      return -1;
    }
    return 0;
  } else {
    if (mat_Dabs(spin_j - spin_k * sign) < symprec) {
      return sign;
    } else {
      return 0;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void test(void) {
  char *buffer;
  struct tm timestruct;
  buffer = asctime(&timestruct);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <asctime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  char *buffer;
  struct tm timestruct;
  buffer = asctime(&timestruct);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <asctime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  char *buffer;
  struct tm timestruct;
  buffer = asctime(&timestruct);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <asctime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  char *buffer;
  struct tm timestruct;
  buffer = asctime(&timestruct);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intmsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x38(%rsp)
  mov    %rsi,%rbx
  mov    %rsi,0x18(%rsp)
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,0x30(%rsp)
  test   %rbx,%rbx
  je     L43
  mov    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x38(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    $0x1,%r12d
  mov    0x18(%rsp),%rax
  mov    %rax,0x28(%rsp)
L37:
  mov    0x28(%rsp),%rbp
  mov    0x8(%rsp),%r15
  mov    0x10(%rsp),%r13
L46:
  cmp    %rbp,%r12
  mov    %rbp,%rbx
  cmovbe %r12,%rbx
  sub    %rbx,%rbp
  cmp    %r12,%rbp
  mov    %r12,%r14
  cmovbe %rbp,%r14
  sub    %r14,%rbp
  lea    0x0(%r13,%rbx,4),%rdx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <intmerge@plt>
  add    %r14,%rbx
  shl    $0x2,%rbx
  add    %rbx,%r13
  add    %rbx,%r15
  test   %rbp,%rbp
  jne    L46
  addq   $0x1,0x20(%rsp)
  add    %r12,%r12
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  cmp    %r12,0x18(%rsp)
  jb     L32
  mov    %rax,0x10(%rsp)
  jmp    L37
L32:
  testb  $0x1,0x20(%rsp)
  je     L43
  mov    0x30(%rsp),%rcx
  mov    0x38(%rsp),%rsi
  mov    0x18(%rsp),%rax
L34:
  mov    -0x4(%rcx,%rax,4),%edx
  mov    %edx,-0x4(%rsi,%rax,4)
  sub    $0x1,%rax
  jne    L34
L43:
  mov    0x30(%rsp),%rdi
  call   <free@plt>
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void intmsort(int *arr_, size_t n) {
  int *arr = arr_;
  int *workarray = malloc(sizeof(int) * n);
  int *current_ = arr;
  int *work_ = workarray;
  int *swap, *first, *second, *cur, *work;
  size_t sub_array_size = 1;
  size_t counter = 0;
  size_t m, len1, len2;
  while (sub_array_size <= n) {
    m = n;
    cur = current_;
    work = work_;
    while (m) {
      first = cur;
      len1 = (m < sub_array_size) ? m : sub_array_size;
      m -= len1;
      second = cur + len1;
      len2 = (m < sub_array_size) ? m : sub_array_size;
      m -= len2;
      intmerge(first, len1, second, len2, work);
      cur += (len1 + len2);
      work += (len1 + len2);
    }
    swap = current_;
    current_ = work_;
    work_ = swap;
    counter++;
    sub_array_size *= 2;
  }
  if (counter % 2) {
    m = n;
    while (m) {
      arr[m - 1] = workarray[m - 1];
      m--;
    }
  }
  free(workarray);
}
```
user: What is the c source code of the assembly code below?

```asm
<intmsort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  lea    0x0(,%rsi,4),%edi
  mov    %rsi,0x10(%rsp)
  call   <malloc@plt>
  mov    %rax,0x20(%rsp)
  test   %rbx,%rbx
  je     L4
  mov    0x20(%rsp),%rax
  mov    $0x1,%r13d
  movq   $0x0,0x18(%rsp)
  mov    %rax,(%rsp)
  mov    0x28(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x10(%rsp),%r15
  mov    (%rsp),%r12
  mov    0x8(%rsp),%r14
  xchg   %ax,%ax
L41:
  cmp    %r15,%r13
  mov    %r15,%rbx
  mov    %r13,%rbp
  mov    %r12,%r8
  cmovbe %r13,%rbx
  mov    %r14,%rdi
  sub    %rbx,%r15
  lea    (%r14,%rbx,4),%rdx
  mov    %rbx,%rsi
  cmp    %r13,%r15
  cmovbe %r15,%rbp
  add    %rbp,%rbx
  mov    %rbp,%rcx
  sub    %rbp,%r15
  call   <intmerge@plt>
  shl    $0x2,%rbx
  add    %rbx,%r14
  add    %rbx,%r12
  test   %r15,%r15
  jne    L41
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rax
  add    %r13,%r13
  addq   $0x1,0x18(%rsp)
  mov    %rcx,(%rsp)
  cmp    %r13,0x10(%rsp)
  jb     L16
  mov    %rax,0x8(%rsp)
  jmp    L5
  nopl   (%rax)
L16:
  testb  $0x1,0x18(%rsp)
  jne    L61
L4:
  mov    0x20(%rsp),%rdi
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
L61:
  mov    0x20(%rsp),%rcx
  mov    0x28(%rsp),%rsi
  mov    0x10(%rsp),%rax
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    -0x4(%rcx,%rax,4),%edx
  mov    %edx,-0x4(%rsi,%rax,4)
  sub    $0x1,%rax
  jne    L26
  jmp    L4
```

assistant: ```c
void intmsort(int *arr_, size_t n) {
  int *arr = arr_;
  int *workarray = malloc(sizeof(int) * n);
  int *current_ = arr;
  int *work_ = workarray;
  int *swap, *first, *second, *cur, *work;
  size_t sub_array_size = 1;
  size_t counter = 0;
  size_t m, len1, len2;
  while (sub_array_size <= n) {
    m = n;
    cur = current_;
    work = work_;
    while (m) {
      first = cur;
      len1 = (m < sub_array_size) ? m : sub_array_size;
      m -= len1;
      second = cur + len1;
      len2 = (m < sub_array_size) ? m : sub_array_size;
      m -= len2;
      intmerge(first, len1, second, len2, work);
      cur += (len1 + len2);
      work += (len1 + len2);
    }
    swap = current_;
    current_ = work_;
    work_ = swap;
    counter++;
    sub_array_size *= 2;
  }
  if (counter % 2) {
    m = n;
    while (m) {
      arr[m - 1] = workarray[m - 1];
      m--;
    }
  }
  free(workarray);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uleq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rdx
  mov    %rsi,%rax
  jmp    L34
L14:
  mov    %ebx,%esi
  or     $0x20,%esi
  movzbl (%rax),%ecx
  or     $0x20,%ecx
  movsbl %cl,%ecx
  cmp    %ecx,%esi
  je     L21
  mov    $0x0,%eax
  jmp    L12
L21:
  add    $0x1,%rax
L34:
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movzbl (%rcx),%ecx
  movsbl %cl,%ebx
  test   %ebx,%ebx
  jne    L14
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uleq(c1, c2) register char *c1, *c2;
{
  register int c;
  while (c = *c1++)
    if ((c | 040) != (*c2 | 040))
      return (0);
    else
      c2++;
  return (*c2 == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uleq>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
L15:
  movzbl (%rsi),%edx
  or     $0x20,%edx
  or     $0x20,%eax
  cmp    %al,%dl
  jne    L28
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  jne    L15
L24:
  cmpb   $0x0,(%rsi)
  sete   %al
  movzbl %al,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uleq(c1, c2) register char *c1, *c2;
{
  register int c;
  while (c = *c1++)
    if ((c | 040) != (*c2 | 040))
      return (0);
    else
      c2++;
  return (*c2 == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uleq>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  jne    L5
  jmp    L6
  nopl   0x0(%rax)
L29:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  add    $0x1,%rsi
  test   %al,%al
  je     L6
L5:
  movzbl (%rsi),%edx
  or     $0x20,%eax
  or     $0x20,%edx
  cmp    %al,%dl
  je     L29
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  sete   %al
  ret
```

assistant: ```c
uleq(c1, c2) register char *c1, *c2;
{
  register int c;
  while (c = *c1++)
    if ((c | 040) != (*c2 | 040))
      return (0);
    else
      c2++;
  return (*c2 == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uleq>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  jne    L5
  jmp    L39
  nopl   0x0(%rax)
L2:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  add    $0x1,%rsi
  test   %al,%al
  je     L39
L5:
  movzbl (%rsi),%edx
  or     $0x20,%eax
  or     $0x20,%edx
  cmp    %al,%dl
  je     L2
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  sete   %al
  ret
```

assistant: ```c
uleq(c1, c2) register char *c1, *c2;
{
  register int c;
  while (c = *c1++)
    if ((c | 040) != (*c2 | 040))
      return (0);
    else
      c2++;
  return (*c2 == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printLogFileInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <output@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: LogFile


assistant: ```c
void printLogFileInfo(const char *cmd) {
  (void)cmd;
  output("LogFile\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printLogFileInfo>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <output@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: LogFile


assistant: ```c
void printLogFileInfo(const char *cmd) {
  (void)cmd;
  output("LogFile\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printLogFileInfo>:
  endbr64
  lea    D9(%rip),%rdi
  jmp    1050 <output@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: LogFile


assistant: ```c
void printLogFileInfo(const char *cmd) {
  (void)cmd;
  output("LogFile\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printLogFileInfo>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <output@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: LogFile


assistant: ```c
void printLogFileInfo(const char *cmd) {
  (void)cmd;
  output("LogFile\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ipv6_change_dsfield>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ntohs@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x4,%eax
  or     $0xf00f,%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void ipv6_change_dsfield(struct ipv6hdr *ipv6h, __u8 mask, __u8 value) {
  __u16 tmp;
  tmp = ntohs(*(__u16 *)ipv6h);
  tmp = (tmp & ((mask << 4) | 0xf00f)) | (value << 4);
  *(__u16 *)ipv6h = htons(tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ipv6_change_dsfield>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    (%rdi),%edi
  call   <ntohs@plt>
  shl    $0x4,%ebx
  or     $0xf00f,%ebx
  and    %eax,%ebx
  mov    %r12d,%edi
  shl    $0x4,%edi
  or     %ebx,%edi
  call   <htons@plt>
  mov    %eax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ipv6_change_dsfield(struct ipv6hdr *ipv6h, __u8 mask, __u8 value) {
  __u16 tmp;
  tmp = ntohs(*(__u16 *)ipv6h);
  tmp = (tmp & ((mask << 4) | 0xf00f)) | (value << 4);
  *(__u16 *)ipv6h = htons(tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ipv6_change_dsfield>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    (%rdi),%edi
  shl    $0x4,%ebx
  or     $0xf00f,%ebx
  call   <ntohs@plt>
  mov    %ebp,%edi
  and    %eax,%ebx
  shl    $0x4,%edi
  or     %ebx,%edi
  call   <htons@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,(%r12)
  pop    %r12
  ret
```

assistant: ```c
void ipv6_change_dsfield(struct ipv6hdr *ipv6h, __u8 mask, __u8 value) {
  __u16 tmp;
  tmp = ntohs(*(__u16 *)ipv6h);
  tmp = (tmp & ((mask << 4) | 0xf00f)) | (value << 4);
  *(__u16 *)ipv6h = htons(tmp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ipv6_change_dsfield>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    (%rdi),%edi
  shl    $0x4,%ebx
  or     $0xf00f,%ebx
  call   <ntohs@plt>
  mov    %ebp,%edi
  and    %eax,%ebx
  shl    $0x4,%edi
  or     %ebx,%edi
  call   <htons@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,(%r12)
  pop    %r12
  ret
```

assistant: ```c
void ipv6_change_dsfield(struct ipv6hdr *ipv6h, __u8 mask, __u8 value) {
  __u16 tmp;
  tmp = ntohs(*(__u16 *)ipv6h);
  tmp = (tmp & ((mask << 4) | 0xf00f)) | (value << 4);
  *(__u16 *)ipv6h = htons(tmp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D7: nomain!


assistant: ```c
int _start(void) {
  printf("nomain!\n");
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: nomain!


assistant: ```c
int _start(void) {
  printf("nomain!\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: nomain!


assistant: ```c
int _start(void) {
  printf("nomain!\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_start>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D8
data_type: string

tool: D8: nomain!


assistant: ```c
int _start(void) {
  printf("nomain!\n");
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  jmp    L32
L11:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  jmp    L22
L44:
  mov    -0x30(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L22:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L32:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *str2(const char *a, const char *b) {
  char *q, *p;
  p = q = malloc(strlen(a) + strlen(b) + 2);
  if (!q)
    return q;
  while (*a)
    *p++ = *a++;
  while (*b)
    *p++ = *b++;
  *p = '\0';
  return q;
}
```