ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<lowercase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L8
  cmpl   $0x5a,-0x4(%rbp)
  jg     L8
  addl   $0x20,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lowercase(int c) {
  if (c >= 'A' && c <= 'Z') {
    c += 32;
  }
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lowercase>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%ecx
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int lowercase(int c) {
  if (c >= 'A' && c <= 'Z') {
    c += 32;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lowercase>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int lowercase(int c) {
  if (c >= 'A' && c <= 'Z') {
    c += 32;
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lowercase>:
  endbr64
  lea    -0x41(%rdi),%ecx
  mov    %edi,%eax
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int lowercase(int c) {
  if (c >= 'A' && c <= 'Z') {
    c += 32;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<syscon_read_dobldobl_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x14a,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_read_dobldobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(330, a, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<syscon_read_dobldobl_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x14a,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int syscon_read_dobldobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(330, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<syscon_read_dobldobl_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x14a,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int syscon_read_dobldobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(330, a, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<syscon_read_dobldobl_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x14a,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int syscon_read_dobldobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(330, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L11
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  seta   %al
  movzbl %al,%eax
  jmp    L3
L11:
  mov    $0xffffffff,%eax
L3:
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmp_cb(const void *a, const void *b) {
  uintptr_t va = *(uintptr_t *)a;
  uintptr_t vb = *(uintptr_t *)b;
  int res = va < vb ? -1 : va > vb ? 1 : 0;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmp_cb>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jb     L7
  seta   %al
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int cmp_cb(const void *a, const void *b) {
  uintptr_t va = *(uintptr_t *)a;
  uintptr_t vb = *(uintptr_t *)b;
  int res = va < vb ? -1 : va > vb ? 1 : 0;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cmp_cb>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_cb(const void *a, const void *b) {
  uintptr_t va = *(uintptr_t *)a;
  uintptr_t vb = *(uintptr_t *)b;
  int res = va < vb ? -1 : va > vb ? 1 : 0;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmp_cb>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_cb(const void *a, const void *b) {
  uintptr_t va = *(uintptr_t *)a;
  uintptr_t vb = *(uintptr_t *)b;
  int res = va < vb ? -1 : va > vb ? 1 : 0;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_temp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edi
  mov    -0x10(%rbp),%rsi
  mov    -0x1c(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r9
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %edi,%edx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: %.*s-%x%s

assistant: ```c
char *get_temp(char *base) {
  int salt = rand();
  char *temp = NULL;
  char *ext = strrchr(base, '.');
  asprintf(&temp, "%.*s-%x%s", (int)(ext - base), base, salt, ext);
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_temp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  movq   $0x0,(%rsp)
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  mov    %rax,%r9
  mov    %rsp,%rdi
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %eax,%edx
  sub    %ebx,%edx
  lea    D4(%rip),%rsi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: %.*s-%x%s

assistant: ```c
char *get_temp(char *base) {
  int salt = rand();
  char *temp = NULL;
  char *ext = strrchr(base, '.');
  asprintf(&temp, "%.*s-%x%s", (int)(ext - base), base, salt, ext);
  return temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_temp>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  movq   $0x0,(%rsp)
  mov    %eax,%ebp
  call   <strrchr@plt>
  mov    %rsp,%rdi
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %eax,%edx
  mov    %rax,%r9
  lea    D7(%rip),%rsi
  sub    %ebx,%edx
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: %.*s-%x%s

assistant: ```c
char *get_temp(char *base) {
  int salt = rand();
  char *temp = NULL;
  char *ext = strrchr(base, '.');
  asprintf(&temp, "%.*s-%x%s", (int)(ext - base), base, salt, ext);
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_temp>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  movq   $0x0,(%rsp)
  mov    %eax,%ebp
  call   <strrchr@plt>
  mov    %rsp,%rdi
  mov    %ebp,%r8d
  mov    %rbx,%rcx
  mov    %eax,%edx
  mov    %rax,%r9
  lea    D1(%rip),%rsi
  sub    %ebx,%edx
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %.*s-%x%s

assistant: ```c
char *get_temp(char *base) {
  int salt = rand();
  char *temp = NULL;
  char *ext = strrchr(base, '.');
  asprintf(&temp, "%.*s-%x%s", (int)(ext - base), base, salt, ext);
  return temp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jksengine_sha512_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <jksengine_digests_init@plt>
  leave
  ret
```

assistant: ```c
int jksengine_sha512_init(EVP_MD_CTX *ctx) {
  ;
  return (jksengine_digests_init(ctx, NID_sha512));
}
```
user: Translate the below assembly code into C programming language:

```asm
<jksengine_sha512_init>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <jksengine_digests_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int jksengine_sha512_init(EVP_MD_CTX *ctx) {
  ;
  return (jksengine_digests_init(ctx, NID_sha512));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jksengine_sha512_init>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <jksengine_digests_init@plt>
```

assistant: ```c
int jksengine_sha512_init(EVP_MD_CTX *ctx) {
  ;
  return (jksengine_digests_init(ctx, NID_sha512));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jksengine_sha512_init>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  jmp    1050 <jksengine_digests_init@plt>
```

assistant: ```c
int jksengine_sha512_init(EVP_MD_CTX *ctx) {
  ;
  return (jksengine_digests_init(ctx, NID_sha512));
}
```
user: Translate the below assembly code into C programming language:

```asm
<pages>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  jmp    L5
L1:
  mov    -0x8(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  add    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
unsigned pages(unsigned linesPerPage, unsigned totalLines) {
  if (totalLines % linesPerPage == 0)
    return totalLines / linesPerPage;
  else
    return (totalLines / linesPerPage) + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pages>:
  endbr64
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %edi
  test   %edx,%edx
  jne    L7
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %edi
  ret
L7:
  mov    %esi,%eax
  mov    $0x0,%edx
  div    %edi
  add    $0x1,%eax
  ret
```

assistant: ```c
unsigned pages(unsigned linesPerPage, unsigned totalLines) {
  if (totalLines % linesPerPage == 0)
    return totalLines / linesPerPage;
  else
    return (totalLines / linesPerPage) + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pages>:
  endbr64
  mov    %esi,%eax
  xor    %edx,%edx
  div    %edi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned pages(unsigned linesPerPage, unsigned totalLines) {
  if (totalLines % linesPerPage == 0)
    return totalLines / linesPerPage;
  else
    return (totalLines / linesPerPage) + 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pages>:
  endbr64
  mov    %esi,%eax
  xor    %edx,%edx
  div    %edi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned pages(unsigned linesPerPage, unsigned totalLines) {
  if (totalLines % linesPerPage == 0)
    return totalLines / linesPerPage;
  else
    return (totalLines / linesPerPage) + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ini__trim_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L5:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
L16:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ini__trim_right(char *str) {
  char *end = str + strlen(str) - 1;
  while (str < end && isspace(*end))
    *end-- = '\0';
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ini__trim_right>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jae    L13
L18:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L13
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L18
L13:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *ini__trim_right(char *str) {
  char *end = str + strlen(str) - 1;
  while (str < end && isspace(*end))
    *end-- = '\0';
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ini__trim_right>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L36
  jmp    L23
  nopl   0x0(%rax)
L16:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%r12
  je     L23
L36:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *ini__trim_right(char *str) {
  char *end = str + strlen(str) - 1;
  while (str < end && isspace(*end))
    *end-- = '\0';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ini__trim_right>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jb     L28
  jmp    L31
  nopl   0x0(%rax)
L9:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%r12
  je     L31
L28:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L9
L31:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *ini__trim_right(char *str) {
  char *end = str + strlen(str) - 1;
  while (str < end && isspace(*end))
    *end-- = '\0';
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L14
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L16
L14:
  mov    $0x14,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%eax
  jmp    L2
L16:
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: usage ./server port


assistant: ```c
char check_args(int ac, char *av, int *p) {
  if (ac < 2 || !(*p = atoi(av))) {
    write(2, "usage ./server port\n", 20);
    return (1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_args>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jle    L1
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  call   <atoi@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%edx
  test   %eax,%eax
  jne    L7
L1:
  mov    $0x14,%edx
  lea    D9(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%edx
L7:
  mov    %edx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: usage ./server port


assistant: ```c
char check_args(int ac, char *av, int *p) {
  if (ac < 2 || !(*p = atoi(av))) {
    write(2, "usage ./server port\n", 20);
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_args>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jle    L1
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  call   <atoi@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L1
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L1:
  mov    $0x14,%edx
  lea    D8(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: usage ./server port


assistant: ```c
char check_args(int ac, char *av, int *p) {
  if (ac < 2 || !(*p = atoi(av))) {
    write(2, "usage ./server port\n", 20);
    return (1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_args>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jle    L2
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  call   <atoi@plt>
  mov    %eax,(%rbx)
  test   %eax,%eax
  je     L2
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L2:
  mov    $0x14,%edx
  lea    D3(%rip),%rsi
  mov    $0x2,%edi
  call   <write@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string

tool: D3: usage ./server port


assistant: ```c
char check_args(int ac, char *av, int *p) {
  if (ac < 2 || !(*p = atoi(av))) {
    write(2, "usage ./server port\n", 20);
    return (1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %eax,%edi
  call   <pread@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void read_data(double *buf, long n, long o, char *p) {
  int fd;
  fd = open(p, O_RDONLY);
  assert(fd > 0);
  assert(pread(fd, buf, n * sizeof(double), o) == n * sizeof(double));
  close(fd);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%rdi
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  shl    $0x3,%rbx
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <pread@plt>
  cmp    %rbx,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <close@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void read_data(double *buf, long n, long o, char *p) {
  int fd;
  fd = open(p, O_RDONLY);
  assert(fd > 0);
  assert(pread(fd, buf, n * sizeof(double), o) == n * sizeof(double));
  close(fd);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read_data>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rcx,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebp
  setg   %dil
  shl    $0x3,%rbx
  call   <assert@plt>
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <pread@plt>
  xor    %edi,%edi
  cmp    %rbx,%rax
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <close@plt>
```

assistant: ```c
void read_data(double *buf, long n, long o, char *p) {
  int fd;
  fd = open(p, O_RDONLY);
  assert(fd > 0);
  assert(pread(fd, buf, n * sizeof(double), o) == n * sizeof(double));
  close(fd);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_data>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rcx,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  xor    %edi,%edi
  test   %eax,%eax
  mov    %eax,%ebp
  setg   %dil
  shl    $0x3,%rbx
  call   <assert@plt>
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <pread@plt>
  xor    %edi,%edi
  cmp    %rbx,%rax
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <close@plt>
```

assistant: ```c
void read_data(double *buf, long n, long o, char *p) {
  int fd;
  fd = open(p, O_RDONLY);
  assert(fd > 0);
  assert(pread(fd, buf, n * sizeof(double), o) == n * sizeof(double));
  close(fd);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L6:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <validptr@plt>
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  addq   $0x4,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0x63,-0x14(%rbp)
  jle    L6
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int *x;
  int *y;
  int i;
  y = (int *)malloc(100 * sizeof(int));
  x = y;
  i = 0;
  for (; i < 100; i++) {
    validptr(x);
    *x = 0;
    x++;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x190,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x190(%rax),%rbp
L0:
  mov    %rbx,%rdi
  call   <validptr@plt>
  movl   $0x0,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int *x;
  int *y;
  int i;
  y = (int *)malloc(100 * sizeof(int));
  x = y;
  i = 0;
  for (; i < 100; i++) {
    validptr(x);
    *x = 0;
    x++;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x190,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x190(%rax),%rbp
  xchg   %ax,%ax
L4:
  mov    %rbx,%rdi
  add    $0x4,%rbx
  call   <validptr@plt>
  movl   $0x0,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int *x;
  int *y;
  int i;
  y = (int *)malloc(100 * sizeof(int));
  x = y;
  i = 0;
  for (; i < 100; i++) {
    validptr(x);
    *x = 0;
    x++;
  }
  return;
}
```