ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<pack_char_compact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  or     %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L17
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int pack_char_compact(char str[]) {
  int val = str[0];
  for (int i = 0; i < strlen(str); i++)
    val = (val << CHAR_BIT) | str[i];
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pack_char_compact>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movsbl (%rdi),%ebx
  mov    $0x0,%ebp
  jmp    L19
L6:
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  shl    %cl,%ebx
  movsbl (%r12,%rbp,1),%eax
  or     %eax,%ebx
  add    $0x1,%rbp
L19:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jg     L6
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int pack_char_compact(char str[]) {
  int val = str[0];
  for (int i = 0; i < strlen(str); i++)
    val = (val << CHAR_BIT) | str[i];
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_char_compact>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  movsbl (%rdi),%r12d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L15:
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  shl    %cl,%r12d
  or     %eax,%r12d
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L15
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int pack_char_compact(char str[]) {
  int val = str[0];
  for (int i = 0; i < strlen(str); i++)
    val = (val << CHAR_BIT) | str[i];
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pack_char_compact>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  movsbl (%rdi),%r12d
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L1:
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  shl    %cl,%r12d
  or     %eax,%r12d
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int pack_char_compact(char str[]) {
  int val = str[0];
  for (int i = 0; i < strlen(str); i++)
    val = (val << CHAR_BIT) | str[i];
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<charactatime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setbuf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L13
L2:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <putc@plt>
L13:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void charactatime(char *buf) {
  char *ptr;
  int ch;
  setbuf(stdout, NULL);
  for (ptr = buf; ch = *buf++;) {
    putc(ch, stdout);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<charactatime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%esi
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <setbuf@plt>
  movsbl 0x0(%rbp),%edi
  test   %edi,%edi
  je     L12
  lea    0x1(%rbp),%rbx
  mov    D18(%rip),%rbp
L3:
  mov    0x0(%rbp),%esi
  call   <putc@plt>
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  test   %edi,%edi
  jne    L3
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void charactatime(char *buf) {
  char *ptr;
  int ch;
  setbuf(stdout, NULL);
  for (ptr = buf; ch = *buf++;) {
    putc(ch, stdout);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<charactatime>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    D9(%rip),%rbp
  push   %rbx
  mov    0x0(%rbp),%edi
  call   <setbuf@plt>
  movsbl (%r12),%edi
  test   %edi,%edi
  je     L12
  lea    0x1(%r12),%rbx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x0(%rbp),%esi
  add    $0x1,%rbx
  call   <putc@plt>
  movsbl -0x1(%rbx),%edi
  test   %edi,%edi
  jne    L13
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void charactatime(char *buf) {
  char *ptr;
  int ch;
  setbuf(stdout, NULL);
  for (ptr = buf; ch = *buf++;) {
    putc(ch, stdout);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<charactatime>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    D5(%rip),%rbp
  push   %rbx
  mov    0x0(%rbp),%edi
  call   <setbuf@plt>
  movsbl (%r12),%edi
  test   %edi,%edi
  je     L18
  lea    0x1(%r12),%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp),%esi
  add    $0x1,%rbx
  call   <putc@plt>
  movsbl -0x1(%rbx),%edi
  test   %edi,%edi
  jne    L2
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void charactatime(char *buf) {
  char *ptr;
  int ch;
  setbuf(stdout, NULL);
  for (ptr = buf; ch = *buf++;) {
    putc(ch, stdout);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x726f776f6c6c6568,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x646c,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L19
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void f3(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size < 0)
    memmove(dest, src, size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x726f776f6c6c6568,%rax
  mov    %rax,(%rsp)
  movl   $0x646c,0x8(%rsp)
  test   %edi,%edi
  js     L23
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  ret
L23:
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
  jmp    L3
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f3(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size < 0)
    memmove(dest, src, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f776f6c6c6568,%rax
  movl   $0x646c,0x8(%rsp)
  mov    %rax,(%rsp)
  test   %edi,%edi
  js     L16
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L16:
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
  jmp    L15
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f3(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size < 0)
    memmove(dest, src, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f3>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x726f776f6c6c6568,%rax
  movl   $0x646c,0x8(%rsp)
  mov    %rax,(%rsp)
  test   %edi,%edi
  js     L25
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  ret
  nopl   (%rax)
L25:
  mov    %edi,%edx
  mov    %rsp,%rsi
  lea    0xc(%rsp),%rdi
  call   <memmove@plt>
  jmp    L29
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f3(int size) {
  char src[12] = "helloworld";
  char dest[12];
  if (size < 0)
    memmove(dest, src, size);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sched_get_priority_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0xff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sched_get_priority_max(int policy) {
  (void)policy;
  return 255;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sched_get_priority_max>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
int sched_get_priority_max(int policy) {
  (void)policy;
  return 255;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sched_get_priority_max>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
int sched_get_priority_max(int policy) {
  (void)policy;
  return 255;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sched_get_priority_max>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
int sched_get_priority_max(int policy) {
  (void)policy;
  return 255;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x3039,-0x38(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <itoa@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: integer = %d string = %s


assistant: ```c
int main(void) {
  long number = 12345;
  char string[25];
  itoa(number, string, 2);
  printf("integer = %d string = %s\n", number, string);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    $0x3039,%edi
  call   <itoa@plt>
  mov    %rbx,%rdx
  mov    $0x3039,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: integer = %d string = %s


assistant: ```c
int main(void) {
  long number = 12345;
  char string[25];
  itoa(number, string, 2);
  printf("integer = %d string = %s\n", number, string);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    $0x3039,%edi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <itoa@plt>
  mov    %r12,%rdx
  mov    $0x3039,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: integer = %d string = %s


assistant: ```c
int main(void) {
  long number = 12345;
  char string[25];
  itoa(number, string, 2);
  printf("integer = %d string = %s\n", number, string);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  mov    $0x3039,%edi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <itoa@plt>
  mov    %r12,%rdx
  mov    $0x3039,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: integer = %d string = %s


assistant: ```c
int main(void) {
  long number = 12345;
  char string[25];
  itoa(number, string, 2);
  printf("integer = %d string = %s\n", number, string);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rta_addattr_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edi
  call   <RTA_LENGTH@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <RTA_ALIGN@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <RTA_ALIGN@plt>
  add    %ebx,%eax
  cmp    %eax,-0x2c(%rbp)
  jge    L12
  mov    $0xffffffff,%eax
  jmp    L1
L12:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <RTA_ALIGN@plt>
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%edx
  mov    %edx,0x4(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <RTA_DATA@plt>
  mov    %eax,%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <NLMSG_ALIGN@plt>
  mov    %eax,%ebx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <RTA_ALIGN@plt>
  lea    (%rbx,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rta_addattr_len(struct rtattr *rta, int maxlen, int type, const void *data, int alen) {
  struct rtattr *subrta;
  int len = RTA_LENGTH(alen);
  if ((RTA_ALIGN(rta->rta_len) + RTA_ALIGN(len)) > maxlen) {
    return -1;
  }
  subrta = (struct rtattr *)(((void *)rta) + RTA_ALIGN(rta->rta_len));
  subrta->rta_type = type;
  subrta->rta_len = len;
  memcpy(RTA_DATA(subrta), data, alen);
  rta->rta_len = NLMSG_ALIGN(rta->rta_len) + RTA_ALIGN(len);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rta_addattr_len>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %edx,%r15d
  mov    %rcx,%r14
  mov    %r8d,%r12d
  mov    %r8d,%edi
  call   <RTA_LENGTH@plt>
  mov    %eax,%ebp
  mov    (%rbx),%edi
  call   <RTA_ALIGN@plt>
  mov    %eax,0xc(%rsp)
  mov    %ebp,%edi
  call   <RTA_ALIGN@plt>
  add    0xc(%rsp),%eax
  cmp    %r13d,%eax
  jg     L11
  mov    (%rbx),%edi
  call   <RTA_ALIGN@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  mov    %r15d,0x4(%rdi)
  mov    %ebp,(%rdi)
  call   <RTA_DATA@plt>
  mov    %eax,%edi
  mov    %r12d,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <RTA_ALIGN@plt>
  add    %eax,%r12d
  mov    %r12d,(%rbx)
  mov    $0x0,%eax
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int rta_addattr_len(struct rtattr *rta, int maxlen, int type, const void *data, int alen) {
  struct rtattr *subrta;
  int len = RTA_LENGTH(alen);
  if ((RTA_ALIGN(rta->rta_len) + RTA_ALIGN(len)) > maxlen) {
    return -1;
  }
  subrta = (struct rtattr *)(((void *)rta) + RTA_ALIGN(rta->rta_len));
  subrta->rta_type = type;
  subrta->rta_len = len;
  memcpy(RTA_DATA(subrta), data, alen);
  rta->rta_len = NLMSG_ALIGN(rta->rta_len) + RTA_ALIGN(len);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<rta_addattr_len>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r8d,%edi
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <RTA_LENGTH@plt>
  mov    (%rbx),%edi
  mov    %eax,%ebp
  call   <RTA_ALIGN@plt>
  mov    %ebp,%edi
  mov    %eax,%r14d
  call   <RTA_ALIGN@plt>
  add    %eax,%r14d
  cmp    0xc(%rsp),%r14d
  jg     L1
  mov    (%rbx),%edi
  call   <RTA_ALIGN@plt>
  movslq %eax,%rdi
  add    %rbx,%rdi
  mov    %r13d,0x4(%rdi)
  mov    %ebp,(%rdi)
  call   <RTA_DATA@plt>
  mov    %r12,%rsi
  mov    %r15d,%edx
  mov    %eax,%edi
  call   <memcpy@plt>
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <RTA_ALIGN@plt>
  add    %eax,%r12d
  xor    %eax,%eax
  mov    %r12d,(%rbx)
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int rta_addattr_len(struct rtattr *rta, int maxlen, int type, const void *data, int alen) {
  struct rtattr *subrta;
  int len = RTA_LENGTH(alen);
  if ((RTA_ALIGN(rta->rta_len) + RTA_ALIGN(len)) > maxlen) {
    return -1;
  }
  subrta = (struct rtattr *)(((void *)rta) + RTA_ALIGN(rta->rta_len));
  subrta->rta_type = type;
  subrta->rta_len = len;
  memcpy(RTA_DATA(subrta), data, alen);
  rta->rta_len = NLMSG_ALIGN(rta->rta_len) + RTA_ALIGN(len);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rta_addattr_len>:
  endbr64
  push   %r15
  mov    %r8d,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r8d,%edi
  sub    $0x18,%rsp
  call   <RTA_LENGTH@plt>
  movd   %r13d,%xmm1
  mov    (%rbx),%edi
  movd   %eax,%xmm0
  mov    %eax,%ebp
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  call   <RTA_ALIGN@plt>
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <RTA_ALIGN@plt>
  add    %eax,%r13d
  cmp    %r14d,%r13d
  jg     L18
  mov    (%rbx),%edi
  call   <RTA_ALIGN@plt>
  movslq %eax,%rdi
  mov    0x8(%rsp),%rax
  add    %rbx,%rdi
  mov    %rax,(%rdi)
  call   <RTA_DATA@plt>
  mov    %r12,%rsi
  mov    %r15d,%edx
  mov    %eax,%edi
  call   <memcpy@plt>
  mov    (%rbx),%edi
  call   <NLMSG_ALIGN@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <RTA_ALIGN@plt>
  add    %eax,%r12d
  xor    %eax,%eax
  mov    %r12d,(%rbx)
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int rta_addattr_len(struct rtattr *rta, int maxlen, int type, const void *data, int alen) {
  struct rtattr *subrta;
  int len = RTA_LENGTH(alen);
  if ((RTA_ALIGN(rta->rta_len) + RTA_ALIGN(len)) > maxlen) {
    return -1;
  }
  subrta = (struct rtattr *)(((void *)rta) + RTA_ALIGN(rta->rta_len));
  subrta->rta_type = type;
  subrta->rta_len = len;
  memcpy(RTA_DATA(subrta), data, alen);
  rta->rta_len = NLMSG_ALIGN(rta->rta_len) + RTA_ALIGN(len);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_getenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  jne    L42
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  je     L47
L42:
  mov    $0x0,%eax
  jmp    L39
L47:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <prctl@plt>
  test   %rax,%rax
  jne    L41
  mov    $0x0,%eax
  jmp    L39
L41:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__secure_getenv@plt>
L39:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *safe_getenv(const char *arg) {
  if ((getuid() != geteuid()) || (getgid() != getegid())) {
    return NULL;
  }
  if (prctl(PR_GET_DUMPABLE, 0, 0, 0, 0) == 0) {
    return NULL;
  }
  return __secure_getenv(arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<safe_getenv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rbx
  jne    L11
  call   <getgid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rbx
  jne    L11
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <prctl@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L11
  mov    %rbp,%rdi
  call   <__secure_getenv@plt>
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *safe_getenv(const char *arg) {
  if ((getuid() != geteuid()) || (getgid() != getegid())) {
    return NULL;
  }
  if (prctl(PR_GET_DUMPABLE, 0, 0, 0, 0) == 0) {
    return NULL;
  }
  return __secure_getenv(arg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<safe_getenv>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  jne    L7
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  jne    L7
  mov    D8(%rip),%rax
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <prctl@plt>
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10f0 <__secure_getenv@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *safe_getenv(const char *arg) {
  if ((getuid() != geteuid()) || (getgid() != getegid())) {
    return NULL;
  }
  if (prctl(PR_GET_DUMPABLE, 0, 0, 0, 0) == 0) {
    return NULL;
  }
  return __secure_getenv(arg);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<safe_getenv>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getuid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  jne    L14
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  jne    L14
  mov    D9(%rip),%rax
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <prctl@plt>
  test   %rax,%rax
  je     L14
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10f0 <__secure_getenv@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *safe_getenv(const char *arg) {
  if ((getuid() != geteuid()) || (getgid() != getegid())) {
    return NULL;
  }
  if (prctl(PR_GET_DUMPABLE, 0, 0, 0, 0) == 0) {
    return NULL;
  }
  return __secure_getenv(arg);
}
```