ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply189>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L80
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L16:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L76
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L76
  nopl   0x0(%rax)
L98:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L98
  cmp    -0x24(%rsp),%r11d
  je     L82
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L82
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L82
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L82:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L16
L80:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L85:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L85
  mov    -0x18(%rsp),%r8
  jmp    L82
```

assistant: ```c
void multiply189(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_c_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x1,%eax
  jmp    L6
L16:
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[], int type_len, int maxlen) {
  int i;
  for (i = 0; i < type_len; i++) {
    if (strncmp(t, types[i], maxlen) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_c_type>:
  endbr64
  test   %edx,%edx
  jle    L26
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %ecx,%r12d
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r13
L25:
  mov    %r12d,%edx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L38
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L25
  mov    $0x0,%eax
  jmp    L29
L26:
  mov    $0x0,%eax
  ret
L38:
  mov    $0x1,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[], int type_len, int maxlen) {
  int i;
  for (i = 0; i < type_len; i++) {
    if (strncmp(t, types[i], maxlen) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_c_type>:
  endbr64
  test   %edx,%edx
  jle    L39
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r13
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L26
  nopl   (%rax)
L21:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L8
L26:
  mov    (%rbx),%rsi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L21
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[], int type_len, int maxlen) {
  int i;
  for (i = 0; i < type_len; i++) {
    if (strncmp(t, types[i], maxlen) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_c_type>:
  endbr64
  test   %edx,%edx
  jle    L33
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r13
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L31
  nopl   (%rax)
L23:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L30
L31:
  mov    (%rbx),%rsi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L23
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[], int type_len, int maxlen) {
  int i;
  for (i = 0; i < type_len; i++) {
    if (strncmp(t, types[i], maxlen) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recstalta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    %r8d,-0x4c(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x48(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4c(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L40
L28:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L40:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L28
  mov    -0x4c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jge    L8
  movl   $0x0,-0x24(%rbp)
  jmp    L25
L26:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L25:
  mov    -0x24(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L26
  nop
L8:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: f64

tool: D7: 1

assistant: ```c
void recstalta(double *a, double *charfct, int ndat, int nsta, int nlta) {
  int i;
  double csta = 1. / ((double)nsta);
  double clta = 1. / ((double)nlta);
  double sta = 0.0;
  double lta = 0.0;
  for (i = 1; i < ndat; i++) {
    sta = csta * pow(a[i], 2) + (1 - csta) * sta;
    lta = clta * pow(a[i], 2) + (1 - clta) * lta;
    charfct[i] = sta / lta;
  }
  if (nlta < ndat)
    for (i = 0; i < nlta; i++)
      charfct[i] = 0.0;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recstalta>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%r15
  mov    %edx,%r14d
  mov    %r8d,%r13d
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  movsd  D1(%rip),%xmm0
  movapd %xmm0,%xmm7
  divsd  %xmm1,%xmm7
  movsd  %xmm7,0x10(%rsp)
  pxor   %xmm1,%xmm1
  cvtsi2sd %r8d,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rsp)
  cmp    $0x1,%edx
  jle    L17
  lea    0x8(%rdi),%rbx
  lea    0x8(%rsi),%rbp
  lea    -0x2(%rdx),%eax
  lea    0x10(%rdi,%rax,8),%r12
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  movsd  %xmm7,(%rsp)
L33:
  mov    $0x2,%edi
  movsd  (%rbx),%xmm0
  call   <pow@plt>
  movsd  D1(%rip),%xmm1
  movsd  0x10(%rsp),%xmm3
  subsd  %xmm3,%xmm1
  mulsd  (%rsp),%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsp)
  mov    $0x2,%edi
  movsd  (%rbx),%xmm0
  call   <pow@plt>
  movsd  D1(%rip),%xmm1
  movsd  0x18(%rsp),%xmm4
  subsd  %xmm4,%xmm1
  mulsd  0x8(%rsp),%xmm1
  mulsd  %xmm4,%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm1,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movsd  (%rsp),%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r12,%rbx
  jne    L33
L17:
  cmp    %r14d,%r13d
  jge    L35
  test   %r13d,%r13d
  jle    L35
  mov    %r15,%rax
  lea    -0x1(%r13),%edx
  lea    0x8(%r15,%rdx,8),%rdx
L21:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L21
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: f64

tool: D1: 1

assistant: ```c
void recstalta(double *a, double *charfct, int ndat, int nsta, int nlta) {
  int i;
  double csta = 1. / ((double)nsta);
  double clta = 1. / ((double)nlta);
  double sta = 0.0;
  double lta = 0.0;
  for (i = 1; i < ndat; i++) {
    sta = csta * pow(a[i], 2) + (1 - csta) * sta;
    lta = clta * pow(a[i], 2) + (1 - clta) * lta;
    charfct[i] = sta / lta;
  }
  if (nlta < ndat)
    for (i = 0; i < nlta; i++)
      charfct[i] = 0.0;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<recstalta>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  cvtsi2sd %ecx,%xmm0
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  D39(%rip),%xmm6
  movsd  D39(%rip),%xmm7
  divsd  %xmm0,%xmm6
  pxor   %xmm0,%xmm0
  cvtsi2sd %r8d,%xmm0
  divsd  %xmm0,%xmm7
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm7,0x18(%rsp)
  cmp    $0x1,%edx
  jle    L14
  lea    -0x2(%rdx),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rdi),%rbx
  lea    0x8(%rsi),%r15
  lea    0x10(%rdi,%rax,8),%rbp
  movsd  %xmm1,(%rsp)
  nopw   0x0(%rax,%rax,1)
L34:
  movsd  (%rbx),%xmm0
  mov    $0x2,%edi
  add    $0x8,%rbx
  add    $0x8,%r15
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm3
  mov    $0x2,%edi
  movsd  D39(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  (%rsp),%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsp)
  movsd  -0x8(%rbx),%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D39(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%rbx
  jne    L34
L14:
  cmp    %r13d,%r12d
  jge    L17
  test   %r12d,%r12d
  jle    L17
  add    $0x28,%rsp
  movslq %r12d,%rdx
  mov    %r14,%rdi
  xor    %esi,%esi
  pop    %rbx
  shl    $0x3,%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L17:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type_infered: f64

tool: D39: 1

assistant: ```c
void recstalta(double *a, double *charfct, int ndat, int nsta, int nlta) {
  int i;
  double csta = 1. / ((double)nsta);
  double clta = 1. / ((double)nlta);
  double sta = 0.0;
  double lta = 0.0;
  for (i = 1; i < ndat; i++) {
    sta = csta * pow(a[i], 2) + (1 - csta) * sta;
    lta = clta * pow(a[i], 2) + (1 - clta) * lta;
    charfct[i] = sta / lta;
  }
  if (nlta < ndat)
    for (i = 0; i < nlta; i++)
      charfct[i] = 0.0;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recstalta>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  cvtsi2sd %ecx,%xmm0
  mov    %rsi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  D9(%rip),%xmm6
  movsd  D9(%rip),%xmm7
  divsd  %xmm0,%xmm6
  pxor   %xmm0,%xmm0
  cvtsi2sd %r8d,%xmm0
  divsd  %xmm0,%xmm7
  movsd  %xmm6,0x10(%rsp)
  movsd  %xmm7,0x18(%rsp)
  cmp    $0x1,%edx
  jle    L20
  lea    -0x2(%rdx),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rdi),%rbx
  lea    0x8(%rsi),%r15
  lea    0x10(%rdi,%rax,8),%rbp
  movsd  %xmm1,(%rsp)
  nopw   0x0(%rax,%rax,1)
L3:
  movsd  (%rbx),%xmm0
  mov    $0x2,%edi
  add    $0x8,%rbx
  add    $0x8,%r15
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm3
  mov    $0x2,%edi
  movsd  D9(%rip),%xmm2
  mulsd  %xmm3,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  (%rsp),%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsp)
  movsd  -0x8(%rbx),%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D9(%rip),%xmm2
  movsd  0x8(%rsp),%xmm1
  subsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%rbx
  jne    L3
L20:
  cmp    %r13d,%r12d
  jge    L39
  test   %r12d,%r12d
  jle    L39
  add    $0x28,%rsp
  movslq %r12d,%rdx
  mov    %r14,%rdi
  xor    %esi,%esi
  pop    %rbx
  shl    $0x3,%rdx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <memset@plt>
  nopl   0x0(%rax)
L39:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: f64

tool: D9: 1

assistant: ```c
void recstalta(double *a, double *charfct, int ndat, int nsta, int nlta) {
  int i;
  double csta = 1. / ((double)nsta);
  double clta = 1. / ((double)nlta);
  double sta = 0.0;
  double lta = 0.0;
  for (i = 1; i < ndat; i++) {
    sta = csta * pow(a[i], 2) + (1 - csta) * sta;
    lta = clta * pow(a[i], 2) + (1 - clta) * lta;
    charfct[i] = sta / lta;
  }
  if (nlta < ndat)
    for (i = 0; i < nlta; i++)
      charfct[i] = 0.0;
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rle_compress_hdmv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %edx,0x14(%rsp)
  mov    %ecx,0x18(%rsp)
  movq   $0x0,(%rdi)
  movl   $0x0,(%r8)
  test   %ecx,%ecx
  jle    L8
  mov    %rsi,%r13
  mov    %ecx,%eax
  mov    %r8,%rbp
  mov    %edx,%ecx
  lea    0x0(,%rdx,4),%edi
  mov    %edi,0x1c(%rsp)
  imul   %edx,%eax
  mov    %eax,%edx
  lea    0xf(%rax),%eax
  test   %edx,%edx
  cmovns %edx,%eax
  sar    $0x4,%eax
  cltq
  mov    %rax,0x28(%rsp)
  movslq %ecx,%rax
  shl    $0x2,%rax
  mov    %rax,0x20(%rsp)
  lea    -0x2(%rcx),%eax
  lea    0x8(%rsi,%rax,4),%r12
  mov    $0x0,%edi
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  jmp    L9
L87:
  call   <write_rle_hdmv@plt>
  mov    %rax,%rdi
  addl   $0x1,0x0(%rbp)
  mov    (%rbx),%esi
  mov    $0x1,%edx
L101:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L71
L70:
  cmp    %esi,(%rbx)
  jne    L87
  add    $0x1,%edx
  jmp    L101
L71:
  test   %edx,%edx
  jne    L31
L95:
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <write_rle_hdmv@plt>
  mov    %rax,%rdi
  addl   $0x1,0x0(%rbp)
  mov    0x20(%rsp),%rax
  add    %rax,%r13
  add    $0x1,%r14d
  add    %rax,%r12
  cmp    %r14d,0x18(%rsp)
  je     L51
L9:
  mov    0x8(%rsp),%rax
  mov    (%rax),%rax
  mov    %rdi,%rbx
  sub    %rax,%rbx
  mov    %rbx,%rcx
  sar    $0x2,%rcx
  mov    %r15d,%edx
  sub    %ecx,%edx
  cmp    0x1c(%rsp),%edx
  jge    L6
  lea    (%r15,%r15,1),%rdx
  test   %r15,%r15
  cmove  0x28(%rsp),%rdx
  mov    %rdx,%r15
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    0x8(%rsp),%rcx
  mov    %rax,(%rcx)
  lea    (%rax,%rbx,1),%rdi
L6:
  mov    0x0(%r13),%esi
  cmpl   $0x1,0x14(%rsp)
  jle    L107
  lea    0x4(%r13),%rbx
  mov    $0x1,%edx
  jmp    L70
L107:
  mov    $0x1,%edx
L31:
  call   <write_rle_hdmv@plt>
  mov    %rax,%rdi
  addl   $0x1,0x0(%rbp)
  jmp    L95
L8:
  mov    $0x0,%edi
L51:
  mov    0x8(%rsp),%rcx
  mov    %rdi,%rax
  sub    (%rcx),%rax
  sar    $0x2,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
size_t rle_compress_hdmv(uint8_t **rle_data, const uint8_t *data, uint w, uint h, int *num_rle) {
  uint y;
  size_t rle_size = 0;
  uint8_t *rle = NULL;
  *rle_data = NULL;
  *num_rle = 0;
  for (y = 0; y < h; y++) {
    if ((ssize_t)(rle_size - (rle - *rle_data)) < w * 4) {
      size_t used = rle - *rle_data;
      rle_size = rle_size < 1 ? w * h / 16 : rle_size * 2;
      *rle_data = realloc(*rle_data, rle_size);
      rle = *rle_data + used;
    }
    uint color = *data;
    uint len = 1;
    uint x = 1;
    for (x = 1; x < w; x++) {
      if (data[x] == color) {
        len++;
      } else {
        rle = write_rle_hdmv(rle, color, len);
        (*num_rle)++;
        color = data[x];
        len = 1;
      }
    }
    if (len) {
      rle = write_rle_hdmv(rle, color, len);
      (*num_rle)++;
    }
    rle = write_rle_hdmv(rle, 0, 0);
    (*num_rle)++;
    data += w;
  }
  return rle - *rle_data;
}
```
user: What is the c source code of the assembly code below:

```asm
<t6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fn1@plt>
  test   %rax,%rax
  js     L28
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <fn2@plt>
  test   %rax,%rax
  js     L28
  mov    $0x2,%edi
  call   <fn3@plt>
  test   %rax,%rax
  jns    L21
L28:
  mov    $0xffffffff,%eax
  jmp    L11
L21:
  mov    $0x0,%eax
  call   <fn1@plt>
  mov    $0x15,%esi
  mov    $0x5c,%edi
  call   <fn2@plt>
  mov    $0x2a,%edi
  call   <fn3@plt>
  mov    $0x0,%edi
  call   <__builtin_fabsf@plt>
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int t6() {
  if (fn1() < 0 || fn2(2, 1) < 0 || fn3(2) < 0)
    return -1;
  fn1();
  fn2(92, 21);
  fn3(42);
  __builtin_fabsf(0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t6>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn1@plt>
  test   %rax,%rax
  js     L10
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <fn2@plt>
  test   %rax,%rax
  js     L54
  mov    $0x2,%edi
  call   <fn3@plt>
  test   %rax,%rax
  js     L9
  mov    $0x0,%eax
  call   <fn1@plt>
  mov    $0x15,%esi
  mov    $0x5c,%edi
  call   <fn2@plt>
  mov    $0x2a,%edi
  call   <fn3@plt>
  mov    $0x0,%edi
  call   <__builtin_fabsf@plt>
  mov    $0x0,%eax
L22:
  add    $0x8,%rsp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L22
L54:
  mov    $0xffffffff,%eax
  jmp    L22
L9:
  mov    $0xffffffff,%eax
  jmp    L22
```

assistant: ```c
int t6() {
  if (fn1() < 0 || fn2(2, 1) < 0 || fn3(2) < 0)
    return -1;
  fn1();
  fn2(92, 21);
  fn3(42);
  __builtin_fabsf(0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<t6>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn1@plt>
  test   %rax,%rax
  js     L20
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <fn2@plt>
  test   %rax,%rax
  js     L20
  mov    $0x2,%edi
  call   <fn3@plt>
  test   %rax,%rax
  js     L20
  xor    %eax,%eax
  call   <fn1@plt>
  mov    $0x15,%esi
  mov    $0x5c,%edi
  call   <fn2@plt>
  mov    $0x2a,%edi
  call   <fn3@plt>
  xor    %edi,%edi
  call   <__builtin_fabsf@plt>
  xor    %eax,%eax
L19:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L20:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int t6() {
  if (fn1() < 0 || fn2(2, 1) < 0 || fn3(2) < 0)
    return -1;
  fn1();
  fn2(92, 21);
  fn3(42);
  __builtin_fabsf(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<t6>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn1@plt>
  test   %rax,%rax
  js     L0
  mov    $0x1,%esi
  mov    $0x2,%edi
  call   <fn2@plt>
  test   %rax,%rax
  js     L0
  mov    $0x2,%edi
  call   <fn3@plt>
  test   %rax,%rax
  js     L0
  xor    %eax,%eax
  call   <fn1@plt>
  mov    $0x15,%esi
  mov    $0x5c,%edi
  call   <fn2@plt>
  mov    $0x2a,%edi
  call   <fn3@plt>
  xor    %edi,%edi
  call   <__builtin_fabsf@plt>
  xor    %eax,%eax
L32:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L0:
  mov    $0xffffffff,%eax
  jmp    L32
```

assistant: ```c
int t6() {
  if (fn1() < 0 || fn2(2, 1) < 0 || fn3(2) < 0)
    return -1;
  fn1();
  fn2(92, 21);
  fn3(42);
  __builtin_fabsf(0);
  return 0;
}
```