ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copyImage2To32>:
  endbr64
  push   %r13
  lea    (%r8,%r8,1),%eax
  not    %r8d
  push   %r12
  lea    0x1f(%rdx,%rdx,1),%r12d
  sar    $0x5,%eax
  and    $0xf,%r8d
  sar    $0x5,%r12d
  push   %rbp
  shl    $0x2,%eax
  shl    $0x2,%r12d
  push   %rbx
  mov    %edx,%ebx
  movslq %r9d,%rdx
  movslq %r12d,%r12
  cltq
  mov    0x30(%rsp),%r13d
  shl    $0x5,%ebx
  imul   %r12,%rdx
  mov    0x38(%rsp),%r10
  sar    $0x3,%ebx
  add    %rdx,%rax
  mov    0x28(%rsp),%edx
  shl    $0x5,%edx
  sar    $0x3,%edx
  cmp    %r13d,%r9d
  jge    L13
  mov    %rdi,%r11
  movslq %edx,%rdx
  lea    (%r8,%r8,1),%ebp
  movslq %ebx,%rbx
  mov    %rsi,%r8
  lea    (%rsi,%rdx,1),%rdi
  add    %rax,%r11
  nop
L10:
  mov    %r11,%rsi
  mov    %r8,%rdx
  mov    %ebp,%ecx
  cmp    %rdi,%r8
  jae    L0
  nopl   (%rax)
L44:
  mov    (%rsi),%eax
  add    $0x4,%rdx
  shr    %cl,%eax
  and    $0x3,%eax
  mov    (%r10,%rax,4),%eax
  mov    %eax,-0x4(%rdx)
  sub    $0x2,%ecx
  jns    L8
  add    $0x4,%rsi
  mov    $0x1e,%ecx
L8:
  cmp    %rdx,%rdi
  ja     L44
L0:
  add    $0x1,%r9d
  add    %rbx,%r8
  add    %rbx,%rdi
  add    %r12,%r11
  cmp    %r9d,%r13d
  jne    L10
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copyImage2To32(int *fromImageData, int *toImageData, int width, int height, int affectedL, int affectedT, int affectedR, int affectedB, unsigned int *stColors) {
  long scanLine2, firstWord2, firstShift2;
  long scanLine32, firstWord32, lastWord32;
  int line;
  scanLine2 = ((((width) * (2) + 31) >> 5) << 2);
  firstWord2 = scanLine2 * affectedT + ((((affectedL) * (2)) >> 5) << 2);
  firstShift2 = 30 - ((affectedL & 15) * 2);
  scanLine32 = ((((width) * (32) + 31) >> 5) << 2);
  firstWord32 = 0;
  lastWord32 = ((((affectedR) * (32)) >> 5) << 2);
  for (line = affectedT; line < affectedB; line++) {
    register unsigned int *from = (unsigned int *)((long)fromImageData + firstWord2);
    register unsigned int *to = (unsigned int *)((long)toImageData + firstWord32);
    register unsigned int *limit = (unsigned int *)((long)toImageData + lastWord32);
    register int shift = firstShift2;
    while (to < limit) {
      *to = stColors[(*from >> shift) & 3];
      to++;
      shift -= 2;
      if (shift < 0) {
        shift = 30;
        from++;
      }
    }
    firstWord2 += scanLine2;
    firstWord32 += scanLine32;
    lastWord32 += scanLine32;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<max_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L7:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L14
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L14:
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_value(int a[], int n) {
  int j, max, x = 0;
  max = a[0];
  for (j = 0; j < n; j++) {
    if (max < a[j]) {
      max = a[j];
      x = j;
    }
  }
  return max;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max_value>:
  endbr64
  mov    (%rdi),%edx
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rsi
L4:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L4
L3:
  mov    %edx,%eax
  ret
```

assistant: ```c
int max_value(int a[], int n) {
  int j, max, x = 0;
  max = a[0];
  for (j = 0; j < n; j++) {
    if (max < a[j]) {
      max = a[j];
      x = j;
    }
  }
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max_value>:
  endbr64
  mov    (%rdi),%eax
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%edx
  add    $0x4,%rdi
  lea    (%rdi,%rdx,4),%rcx
  mov    %eax,%edx
  jmp    L2
  nopl   0x0(%rax)
L22:
  mov    (%rdi),%edx
  add    $0x4,%rdi
L2:
  cmp    %edx,%eax
  cmovl  %edx,%eax
  cmp    %rcx,%rdi
  jne    L22
L6:
  ret
```

assistant: ```c
int max_value(int a[], int n) {
  int j, max, x = 0;
  max = a[0];
  for (j = 0; j < n; j++) {
    if (max < a[j]) {
      max = a[j];
      x = j;
    }
  }
  return max;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<max_value>:
  endbr64
  mov    (%rdi),%eax
  mov    %esi,%edx
  test   %esi,%esi
  jle    L4
  lea    -0x1(%rsi),%ecx
  cmp    $0x2,%ecx
  jbe    L60
  mov    %esi,%ecx
  movd   %eax,%xmm3
  mov    %rdi,%rax
  shr    $0x2,%ecx
  pshufd $0x0,%xmm3,%xmm0
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L52:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm0,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  por    %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L52
  movdqa %xmm0,%xmm2
  mov    %edx,%ecx
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%ecx
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%dl
  je     L33
L54:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L4
  mov    0x4(%rdi,%r8,1),%esi
  cmp    %esi,%eax
  cmovl  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L4
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  ret
L60:
  xor    %ecx,%ecx
  jmp    L54
```

assistant: ```c
int max_value(int a[], int n) {
  int j, max, x = 0;
  max = a[0];
  for (j = 0; j < n; j++) {
    if (max < a[j]) {
      max = a[j];
      x = j;
    }
  }
  return max;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x10(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string
name: parse_data
arguments: label: D7
data_type: string

tool: D2: %d %d

tool: D7: score = %d


assistant: ```c
int main() {
  const int bonus = 10;
  int exam1;
  int exam2;
  int score;
  scanf("%d %d", &exam1, &exam2);
  score = (exam1 + exam2) / 2 + bonus;
  printf("score = %d\n", score);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  add    $0xa,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D6
data_type: string

tool: D13: %d %d

tool: D6: score = %d


assistant: ```c
int main() {
  const int bonus = 10;
  int exam1;
  int exam2;
  int score;
  scanf("%d %d", &exam1, &exam2);
  score = (exam1 + exam2) / 2 + bonus;
  printf("score = %d\n", score);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  add    $0xa,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D11: %d %d

tool: D4: score = %d


assistant: ```c
int main() {
  const int bonus = 10;
  int exam1;
  int exam2;
  int score;
  scanf("%d %d", &exam1, &exam2);
  score = (exam1 + exam2) / 2 + bonus;
  printf("score = %d\n", score);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  add    $0xa,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D13: %d %d

tool: D9: score = %d


assistant: ```c
int main() {
  const int bonus = 10;
  int exam1;
  int exam2;
  int score;
  scanf("%d %d", &exam1, &exam2);
  score = (exam1 + exam2) / 2 + bonus;
  printf("score = %d\n", score);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<valid_ebay_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L32
  mov    $0x0,%eax
  jmp    L10
L32:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x8,%rax
  setg   %al
  movzbl %al,%eax
L10:
  leave
  ret
```

assistant: ```c
int valid_ebay_number(char *ebay_number) {
  char *p;
  for (p = ebay_number; *p != '\0'; p++)
    if (!isdigit(*p))
      return 0;
  return (p - ebay_number >= 9);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<valid_ebay_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L38
  mov    %rbp,%rbx
L0:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  je     L35
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L32:
  sub    %rbp,%rbx
  cmp    $0x8,%rbx
  setg   %al
  movzbl %al,%eax
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %rbp,%rbx
  jmp    L32
```

assistant: ```c
int valid_ebay_number(char *ebay_number) {
  char *p;
  for (p = ebay_number; *p != '\0'; p++)
    if (!isdigit(*p))
      return 0;
  return (p - ebay_number >= 9);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<valid_ebay_number>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  mov    %rbp,%rbx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L48:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L33
L24:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L48
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L33:
  sub    %rbp,%rbx
  xor    %eax,%eax
  cmp    $0x8,%rbx
  setg   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  xor    %eax,%eax
  jmp    L34
```

assistant: ```c
int valid_ebay_number(char *ebay_number) {
  char *p;
  for (p = ebay_number; *p != '\0'; p++)
    if (!isdigit(*p))
      return 0;
  return (p - ebay_number >= 9);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<valid_ebay_number>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  mov    %rbp,%rbx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L20:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L7
L2:
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L20
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  sub    %rbp,%rbx
  xor    %eax,%eax
  cmp    $0x8,%rbx
  setg   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
int valid_ebay_number(char *ebay_number) {
  char *p;
  for (p = ebay_number; *p != '\0'; p++)
    if (!isdigit(*p))
      return 0;
  return (p - ebay_number >= 9);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <writen@plt>
  cmp    $0xffffffff,%eax
  jne    L12
  mov    $0xffffffff,%eax
  jmp    L1
L12:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int fputs(const char *str, FILE *stream) {
  if (-1 == writen(stream, str, strlen(str)))
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <writen@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fputs(const char *str, FILE *stream) {
  if (-1 == writen(stream, str, strlen(str)))
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fputs>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <writen@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int fputs(const char *str, FILE *stream) {
  if (-1 == writen(stream, str, strlen(str)))
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fputs>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <writen@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int fputs(const char *str, FILE *stream) {
  if (-1 == writen(stream, str, strlen(str)))
    return -1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  movslq %ebx,%rax
  imul   $0x74,%rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    0x1c(%rax),%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0x17,-0x20(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movslq %ebx,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    0x34(%rax),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x17,-0x1c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movslq %ebx,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    0x34(%rax),%eax
  cmp    $0x17,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void foo4(int n, int a[n][n]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  movslq %edi,%rbx
  imul   $0x74,%rbx,%rax
  cmpl   $0x17,0x1c(%rsi,%rax,1)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x0(,%rbx,8),%rax
  sub    %rbx,%rax
  lea    0x0(%rbp,%rax,4),%rbx
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo4(int n, int a[n][n]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo4>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  xor    %edi,%edi
  imul   $0x74,%rbx,%rax
  sub    $0x8,%rsp
  cmpl   $0x17,0x1c(%rsi,%rax,1)
  sete   %dil
  call   <assert@plt>
  lea    0x0(,%rbx,8),%rax
  xor    %edi,%edi
  sub    %rbx,%rax
  lea    0x0(%rbp,%rax,4),%rbx
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1050 <assert@plt>
```

assistant: ```c
void foo4(int n, int a[n][n]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo4>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  xor    %edi,%edi
  imul   $0x74,%rbx,%rax
  sub    $0x8,%rsp
  cmpl   $0x17,0x1c(%rsi,%rax,1)
  sete   %dil
  call   <assert@plt>
  lea    0x0(,%rbx,8),%rax
  xor    %edi,%edi
  sub    %rbx,%rax
  lea    0x0(%rbp,%rax,4),%rbx
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x17,0x34(%rbx)
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1050 <assert@plt>
```

assistant: ```c
void foo4(int n, int a[n][n]) {
  int x = (*(a + 29))[7];
  assert(x == 23);
  int y = (*(a + 7))[13];
  assert(y == 23);
  assert(a[7][13] == 23);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getRotationMatrixFromVectors>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <normalizeVector@plt>
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  mov    $0x0,%eax
  movl   $0x0,0xc(%rsp)
  pxor   %xmm3,%xmm3
  movaps %xmm3,%xmm0
L16:
  movss  (%r12,%rax,1),%xmm1
  movaps %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm0
  movss  (%rbx,%rax,1),%xmm2
  movaps %xmm2,%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm3
  mulss  %xmm2,%xmm1
  addss  0xc(%rsp),%xmm1
  movss  %xmm1,0xc(%rsp)
  add    $0x4,%rax
  cmp    $0xc,%rax
  jne    L16
  mulss  %xmm3,%xmm0
  call   <sqrt@plt>
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0x10(%rsp)
  movss  0x4(%r12),%xmm3
  movss  0x8(%rbx),%xmm4
  movss  0x8(%r12),%xmm1
  movss  0x4(%rbx),%xmm0
  movaps %xmm3,%xmm2
  mulss  %xmm4,%xmm2
  movaps %xmm1,%xmm5
  mulss  %xmm0,%xmm5
  subss  %xmm5,%xmm2
  movss  D1(%rip),%xmm5
  xorps  %xmm5,%xmm2
  movss  %xmm2,0x14(%rsp)
  movss  (%rbx),%xmm2
  movss  (%r12),%xmm6
  mulss  %xmm2,%xmm1
  mulss  %xmm6,%xmm4
  subss  %xmm4,%xmm1
  xorps  %xmm5,%xmm1
  movss  %xmm1,0x18(%rsp)
  mulss  %xmm6,%xmm0
  mulss  %xmm2,%xmm3
  subss  %xmm3,%xmm0
  xorps  %xmm5,%xmm0
  movss  %xmm0,0x1c(%rsp)
  lea    0x10(%rsp),%rbx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <normalizeVector@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <getRotationMatrixFromQuartenion@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
void getRotationMatrixFromVectors(float vin[3], float vout[3], float matrix[4][4]) {
  normalizeVector(vout, 3);
  float q[4] = {0, 0, 0, 0};
  float vin_length = 0;
  float vout_length = 0;
  float dotprod = 0;
  int i;
  for (i = 0; i < 3; i++) {
    vin_length += vin[i] * vin[i];
    vout_length += vout[i] * vout[i];
    dotprod += vin[i] * vout[i];
  }
  q[0] = sqrt(vin_length * vout_length) + dotprod;
  q[1] = -1 * (vin[1] * vout[2] - vin[2] * vout[1]);
  q[2] = -1 * (vin[2] * vout[0] - vin[0] * vout[2]);
  q[3] = -1 * (vin[0] * vout[1] - vin[1] * vout[0]);
  normalizeVector(q, 4);
  getRotationMatrixFromQuartenion(q, matrix);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getRotationMatrixFromVectors>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <normalizeVector@plt>
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movaps %xmm3,%xmm4
  movaps %xmm3,%xmm0
L18:
  movss  (%r12,%rax,1),%xmm1
  movaps %xmm1,%xmm2
  mulss  %xmm1,%xmm2
  addss  %xmm2,%xmm0
  movss  (%rbx,%rax,1),%xmm2
  add    $0x4,%rax
  mulss  %xmm2,%xmm1
  movaps %xmm2,%xmm5
  mulss  %xmm2,%xmm5
  addss  %xmm1,%xmm3
  addss  %xmm5,%xmm4
  cmp    $0xc,%rax
  jne    L18
  mulss  %xmm4,%xmm0
  movss  %xmm3,0xc(%rsp)
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm3
  movss  0x8(%rbx),%xmm4
  mov    $0x4,%esi
  movss  0x8(%r12),%xmm1
  movss  (%r12),%xmm6
  addss  %xmm3,%xmm0
  movss  0x4(%r12),%xmm3
  lea    0x10(%rsp),%r12
  movaps %xmm1,%xmm5
  mov    %r12,%rdi
  movaps %xmm3,%xmm2
  movss  %xmm0,0x10(%rsp)
  movss  0x4(%rbx),%xmm0
  mulss  %xmm4,%xmm2
  mulss  %xmm6,%xmm4
  mulss  %xmm0,%xmm5
  mulss  %xmm6,%xmm0
  subss  %xmm5,%xmm2
  movss  D5(%rip),%xmm5
  xorps  %xmm5,%xmm2
  movss  %xmm2,0x14(%rsp)
  movss  (%rbx),%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm3
  subss  %xmm4,%xmm1
  subss  %xmm3,%xmm0
  xorps  %xmm5,%xmm1
  xorps  %xmm5,%xmm0
  movss  %xmm1,0x18(%rsp)
  movss  %xmm0,0x1c(%rsp)
  call   <normalizeVector@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <getRotationMatrixFromQuartenion@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D5
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x80]}

assistant: ```c
void getRotationMatrixFromVectors(float vin[3], float vout[3], float matrix[4][4]) {
  normalizeVector(vout, 3);
  float q[4] = {0, 0, 0, 0};
  float vin_length = 0;
  float vout_length = 0;
  float dotprod = 0;
  int i;
  for (i = 0; i < 3; i++) {
    vin_length += vin[i] * vin[i];
    vout_length += vout[i] * vout[i];
    dotprod += vin[i] * vout[i];
  }
  q[0] = sqrt(vin_length * vout_length) + dotprod;
  q[1] = -1 * (vin[1] * vout[2] - vin[2] * vout[1]);
  q[2] = -1 * (vin[2] * vout[0] - vin[0] * vout[2]);
  q[3] = -1 * (vin[0] * vout[1] - vin[1] * vout[0]);
  normalizeVector(q, 4);
  getRotationMatrixFromQuartenion(q, matrix);
}
```