ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<crc32init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    %rdx,(%rax)
  jmp    L7
L8:
  nop
L7:
  pop    %rbp
  ret
```

assistant: ```c
void crc32init(unsigned long *crcvar) {
  if (!crcvar)
    return;
  *crcvar = 0xffffffffl;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crc32init>:
  endbr64
  test   %rdi,%rdi
  je     L1
  mov    $0xffffffff,%eax
  mov    %rax,(%rdi)
L1:
  ret
```

assistant: ```c
void crc32init(unsigned long *crcvar) {
  if (!crcvar)
    return;
  *crcvar = 0xffffffffl;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc32init>:
  endbr64
  test   %rdi,%rdi
  je     L0
  mov    $0xffffffff,%eax
  mov    %rax,(%rdi)
L0:
  ret
```

assistant: ```c
void crc32init(unsigned long *crcvar) {
  if (!crcvar)
    return;
  *crcvar = 0xffffffffl;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<crc32init>:
  endbr64
  test   %rdi,%rdi
  je     L2
  mov    $0xffffffff,%eax
  mov    %rax,(%rdi)
L2:
  ret
```

assistant: ```c
void crc32init(unsigned long *crcvar) {
  if (!crcvar)
    return;
  *crcvar = 0xffffffffl;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    D48(%rip),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L20
  mov    D48(%rip),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    %eax,D54(%rip)
  mov    D54(%rip),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    D54(%rip),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,D2(%rip)
  jmp    L13
L9:
  mov    $0x0,%eax
  call   <random@plt>
  mov    D2(%rip),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x7f218557,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x9,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x407,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    D54(%rip),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L9
L20:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L21:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  sub    $0x401fa,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L46
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x7f218557,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x9,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x407,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
L46:
  mov    D2(%rip),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x7f218557,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x9,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x407,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
int hash(char *s) {
  static int *coef = NULL;
  static int max_len = 0;
  int len = strlen(s);
  int i, h;
  if (len > max_len) {
    i = max_len;
    max_len = 2 * len;
    coef = (int *)realloc(coef, max_len * sizeof(int));
    for (; i < max_len; i++)
      coef[i] = random() % (1031);
  }
  h = 0;
  for (i = 0; i < len; i++) {
    if (h >= MAXINT - ((1031) - 1) * 255)
      h = h % (1031);
    h += coef[i] * s[i];
  }
  return (h % (1031));
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    D16(%rip),%r12d
  cmp    %eax,%r12d
  jl     L73
L62:
  test   %ebp,%ebp
  jle    L30
  mov    D40(%rip),%rax
  mov    (%rax),%esi
  sub    $0x401fa,%esi
  mov    D20(%rip),%rdi
  mov    %ebp,%ebp
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L22
L73:
  lea    (%rax,%rax,1),%esi
  mov    %esi,D68(%rip)
  shl    $0x2,%esi
  mov    D20(%rip),%rdi
  call   <realloc@plt>
  mov    %rax,D68(%rip)
  cmp    D68(%rip),%r12d
  jge    L62
  movslq %r12d,%r13
  shl    $0x2,%r13
L3:
  mov    $0x0,%eax
  call   <random@plt>
  movslq %eax,%rdx
  imul   $0x7f218557,%rdx,%rdx
  sar    $0x29,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x407,%edx,%edx
  sub    %edx,%eax
  mov    D68(%rip),%rdx
  mov    %eax,(%rdx,%r13,1)
  add    $0x1,%r12d
  add    $0x4,%r13
  cmp    %r12d,D68(%rip)
  jg     L3
  jmp    L62
L14:
  movsbl (%rbx,%rax,1),%ecx
  imul   (%rdi,%rax,4),%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L67
L22:
  cmp    %edx,%esi
  jg     L14
  movslq %edx,%rcx
  imul   $0x7f218557,%rcx,%rcx
  sar    $0x29,%rcx
  mov    %edx,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%ecx
  imul   $0x407,%ecx,%ecx
  sub    %ecx,%edx
  jmp    L14
L30:
  mov    $0x0,%edx
L67:
  movslq %edx,%rax
  imul   $0x7f218557,%rax,%rax
  sar    $0x29,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x407,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hash(char *s) {
  static int *coef = NULL;
  static int max_len = 0;
  int len = strlen(s);
  int i, h;
  if (len > max_len) {
    i = max_len;
    max_len = 2 * len;
    coef = (int *)realloc(coef, max_len * sizeof(int));
    for (; i < max_len; i++)
      coef[i] = random() % (1031);
  }
  h = 0;
  for (i = 0; i < len; i++) {
    if (h >= MAXINT - ((1031) - 1) * 255)
      h = h % (1031);
    h += coef[i] * s[i];
  }
  return (h % (1031));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    D86(%rip),%r12d
  movslq %eax,%rbp
  cmp    %ebp,%r12d
  jl     L33
L14:
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L3
  mov    D54(%rip),%rax
  mov    D36(%rip),%rdi
  xor    %edx,%edx
  mov    (%rax),%esi
  xor    %eax,%eax
  sub    $0x401fa,%esi
  nopl   0x0(%rax)
L24:
  cmp    %edx,%esi
  jg     L38
  movslq %edx,%rcx
  mov    %edx,%r8d
  imul   $0x7f218557,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x29,%rcx
  sub    %r8d,%ecx
  imul   $0x407,%ecx,%ecx
  sub    %ecx,%edx
L38:
  movsbl (%rbx,%rax,1),%ecx
  imul   (%rdi,%rax,4),%ecx
  add    $0x1,%rax
  add    %ecx,%edx
  cmp    %rax,%rbp
  jne    L24
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x7f218557,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x29,%rax
  sub    %ecx,%eax
  imul   $0x407,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  mov    D36(%rip),%rdi
  lea    0x0(%rbp,%rbp,1),%eax
  lea    0x0(,%rbp,8),%esi
  mov    %eax,D45(%rip)
  call   <realloc@plt>
  cmp    D45(%rip),%r12d
  mov    %rax,D45(%rip)
  jge    L14
  movslq %r12d,%r13
  shl    $0x2,%r13
L10:
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x7f218557,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x29,%rdx
  sub    %ecx,%edx
  imul   $0x407,%edx,%edx
  sub    %edx,%eax
  mov    D45(%rip),%rdx
  mov    %eax,(%rdx,%r13,1)
  add    $0x4,%r13
  cmp    %r12d,D45(%rip)
  jg     L10
  jmp    L14
```

assistant: ```c
int hash(char *s) {
  static int *coef = NULL;
  static int max_len = 0;
  int len = strlen(s);
  int i, h;
  if (len > max_len) {
    i = max_len;
    max_len = 2 * len;
    coef = (int *)realloc(coef, max_len * sizeof(int));
    for (; i < max_len; i++)
      coef[i] = random() % (1031);
  }
  h = 0;
  for (i = 0; i < len; i++) {
    if (h >= MAXINT - ((1031) - 1) * 255)
      h = h % (1031);
    h += coef[i] * s[i];
  }
  return (h % (1031));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    D82(%rip),%r12d
  movslq %eax,%rbp
  cmp    %ebp,%r12d
  jl     L60
L7:
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L19
  mov    D28(%rip),%rax
  mov    D72(%rip),%rdi
  xor    %edx,%edx
  mov    (%rax),%esi
  xor    %eax,%eax
  sub    $0x401fa,%esi
  nopl   0x0(%rax)
L8:
  cmp    %edx,%esi
  jg     L37
  movslq %edx,%rcx
  mov    %edx,%r8d
  imul   $0x7f218557,%rcx,%rcx
  sar    $0x1f,%r8d
  sar    $0x29,%rcx
  sub    %r8d,%ecx
  imul   $0x407,%ecx,%ecx
  sub    %ecx,%edx
L37:
  movsbl (%rbx,%rax,1),%ecx
  imul   (%rdi,%rax,4),%ecx
  add    $0x1,%rax
  add    %ecx,%edx
  cmp    %rax,%rbp
  jne    L8
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x7f218557,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x29,%rax
  sub    %ecx,%eax
  imul   $0x407,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L60:
  mov    D72(%rip),%rdi
  lea    0x0(%rbp,%rbp,1),%eax
  lea    0x0(,%rbp,8),%esi
  mov    %eax,D14(%rip)
  call   <realloc@plt>
  cmp    D14(%rip),%r12d
  mov    %rax,D14(%rip)
  jge    L7
  movslq %r12d,%r13
  shl    $0x2,%r13
L0:
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <random@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x7f218557,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x29,%rdx
  sub    %ecx,%edx
  imul   $0x407,%edx,%edx
  sub    %edx,%eax
  mov    D14(%rip),%rdx
  mov    %eax,(%rdx,%r13,1)
  add    $0x4,%r13
  cmp    %r12d,D14(%rip)
  jg     L0
  jmp    L7
```

assistant: ```c
int hash(char *s) {
  static int *coef = NULL;
  static int max_len = 0;
  int len = strlen(s);
  int i, h;
  if (len > max_len) {
    i = max_len;
    max_len = 2 * len;
    coef = (int *)realloc(coef, max_len * sizeof(int));
    for (; i < max_len; i++)
      coef[i] = random() % (1031);
  }
  h = 0;
  for (i = 0; i < len; i++) {
    if (h >= MAXINT - ((1031) - 1) * 255)
      h = h % (1031);
    h += coef[i] * s[i];
  }
  return (h % (1031));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_collapse>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x10,%r13d
  jmp    L59
L7:
  sub    $0x1,%r13d
  je     L37
L59:
  mov    $0x10,%r12d
L21:
  mov    $0x10,%ebp
L4:
  mov    $0x10,%ebx
L50:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L50
  sub    $0x1,%ebp
  jne    L4
  sub    $0x1,%r12d
  jne    L21
  jmp    L7
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L37:
  mov    $0x10,%r12d
L33:
  mov    $0x10,%ebp
  nop
L10:
  mov    $0x10,%ebx
  nopl   (%rax)
L18:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L18
  sub    $0x1,%ebp
  jne    L10
  sub    $0x1,%r12d
  jne    L33
  sub    $0x1,%r13d
  jne    L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_collapse>:
  endbr64
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
L17:
  mov    $0x10,%r12d
L14:
  mov    $0x10,%ebp
  nop
L34:
  mov    $0x10,%ebx
  nopl   (%rax)
L1:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L1
  sub    $0x1,%ebp
  jne    L34
  sub    $0x1,%r12d
  jne    L14
  sub    $0x1,%r13d
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void test_collapse() {
  int i;
#pragma omp target teams distribute parallel for collapse
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4, , 4)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(4)
  for (int i1 = 0; i1 < 16; ++i1)
    for (int i2 = 0; i2 < 16; ++i2)
      for (int i3 = 0; i3 < 16; ++i3)
        for (int i4 = 0; i4 < 16; ++i4)
          foo();
#pragma omp target teams distribute parallel for collapse(4, 8)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2.5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(foo())
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(-5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(5 - 5)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp target teams distribute parallel for collapse(2) firstprivate(i)
  for (i = 0; i < 16; ++i)
    for (int j = 0; j < 16; ++j)
#pragma omp parallel for reduction(+ : i, j)
      for (int k = 0; k < 16; ++k)
        i += j;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split_cfg_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x23,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L39:
  mov    -0x18(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L42
L8:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    $0x0,%eax
  jmp    L42
L37:
  mov    $0xffffffff,%eax
L42:
  leave
  ret
```

assistant: ```c
int split_cfg_line(char *line, char **name, char **value) {
  char *p = NULL;
  if ((p = strchr(line, '#')) != NULL) {
    *p = '\0';
  }
  if ((p = strchr(line, '=')) == NULL) {
    return -1;
  }
  *value = rtrim(ltrim(p + 1));
  *p = '\0';
  *name = rtrim(ltrim(line));
  return (strlen(*name) != 0) ? 0 : -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split_cfg_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    $0x23,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
L7:
  mov    $0x3d,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L18
  lea    0x1(%rax),%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rax,0x0(%r13)
  movb   $0x0,0x0(%rbp)
  mov    %rbx,%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rax,(%r12)
  cmpb   $0x1,(%rax)
  sbb    %eax,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int split_cfg_line(char *line, char **name, char **value) {
  char *p = NULL;
  if ((p = strchr(line, '#')) != NULL) {
    *p = '\0';
  }
  if ((p = strchr(line, '=')) == NULL) {
    return -1;
  }
  *value = rtrim(ltrim(p + 1));
  *p = '\0';
  *name = rtrim(ltrim(line));
  return (strlen(*name) != 0) ? 0 : -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<split_cfg_line>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x23,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
  movb   $0x0,(%rax)
L21:
  mov    $0x3d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
  lea    0x1(%rax),%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  movb   $0x0,(%rbx)
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rax,(%r12)
  cmpb   $0x1,(%rax)
  sbb    %eax,%eax
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L26
```

assistant: ```c
int split_cfg_line(char *line, char **name, char **value) {
  char *p = NULL;
  if ((p = strchr(line, '#')) != NULL) {
    *p = '\0';
  }
  if ((p = strchr(line, '=')) == NULL) {
    return -1;
  }
  *value = rtrim(ltrim(p + 1));
  *p = '\0';
  *name = rtrim(ltrim(line));
  return (strlen(*name) != 0) ? 0 : -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<split_cfg_line>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x23,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  movb   $0x0,(%rax)
L17:
  mov    $0x3d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
  lea    0x1(%rax),%rdi
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  movb   $0x0,(%rbx)
  call   <ltrim@plt>
  mov    %eax,%edi
  call   <rtrim@plt>
  mov    %rax,(%r12)
  cmpb   $0x1,(%rax)
  sbb    %eax,%eax
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int split_cfg_line(char *line, char **name, char **value) {
  char *p = NULL;
  if ((p = strchr(line, '#')) != NULL) {
    *p = '\0';
  }
  if ((p = strchr(line, '=')) == NULL) {
    return -1;
  }
  *value = rtrim(ltrim(p + 1));
  *p = '\0';
  *name = rtrim(ltrim(line));
  return (strlen(*name) != 0) ? 0 : -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x68(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getgroups@plt>
  mov    %eax,-0x64(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void test(void) {
  gid_t grouplist[20];
  int gidsetsize;
  int result;
  gidsetsize = 20;
  result = getgroups(gidsetsize, grouplist);
}
```