ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quickSortTest>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    $0x0,%eax
  call   <getSystemTime@plt>
  mov    %rax,%rbp
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSort@plt>
  mov    $0x0,%eax
  call   <getSystemTime@plt>
  sub    %rbp,%rax
  mov    %rax,%rdx
  lea    0x1(%rbx),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string

tool: D7: quickSort count %d use time: %ld 


assistant: ```c
void quickSortTest(int *arr, int start, int end) {
  long startTime = getSystemTime();
  quickSort(arr, start, end);
  printf("quickSort count %d use time: %ld \n", (end + 1), (getSystemTime() - startTime));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quickSortTest>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <getSystemTime@plt>
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <quickSort@plt>
  xor    %eax,%eax
  call   <getSystemTime@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%esi
  lea    D3(%rip),%rdi
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdx
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: quickSort count %d use time: %ld 


assistant: ```c
void quickSortTest(int *arr, int start, int end) {
  long startTime = getSystemTime();
  quickSort(arr, start, end);
  printf("quickSort count %d use time: %ld \n", (end + 1), (getSystemTime() - startTime));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quickSortTest>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <getSystemTime@plt>
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <quickSort@plt>
  xor    %eax,%eax
  call   <getSystemTime@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%esi
  lea    D3(%rip),%rdi
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdx
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string

tool: D3: quickSort count %d use time: %ld 


assistant: ```c
void quickSortTest(int *arr, int start, int end) {
  long startTime = getSystemTime();
  quickSort(arr, start, end);
  printf("quickSort count %d use time: %ld \n", (end + 1), (getSystemTime() - startTime));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ChangeToMilisec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L54
  mov    %r13,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r13,%rax,1),%r14
  mov    $0x0,%ebp
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  mov    $0x0,%r13d
  mov    $0x821,%r15d
  jmp    L21
L20:
  movslq %r13d,%rdx
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%r13d
  jmp    L106
L156:
  imul   $0x36ee80,%ebp,%eax
  mov    %eax,(%rsp)
L64:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    $0x0,%r13d
L106:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L83
L21:
  movzbl (%rbx),%eax
  lea    -0x68(%rax),%edx
  cmp    $0xb,%dl
  ja     L20
  bt     %rdx,%r15
  jae    L20
  cmp    $0x68,%al
  je     L156
  cmp    $0x6d,%al
  je     L107
  cmp    $0x73,%al
  jne    L64
  cmpb   $0x6d,-0x1(%rbx)
  je     L64
  imul   $0x3e8,%ebp,%eax
  mov    %eax,0x8(%rsp)
  jmp    L64
L107:
  cmpb   $0x73,0x1(%rbx)
  je     L144
  imul   $0xea60,%ebp,%eax
  mov    %eax,0x4(%rsp)
  jmp    L64
L144:
  mov    %ebp,0xc(%rsp)
  jmp    L64
L83:
  mov    %r12,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  js     L158
L97:
  mov    (%rsp),%ebp
  add    0x4(%rsp),%ebp
  add    0x8(%rsp),%ebp
  add    0xc(%rsp),%ebp
L158:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  mov    %rax,%rdi
  call   <free@plt>
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  jmp    L97
```

assistant: ```c
int ChangeToMilisec(char MsgRead[], int StringSize) {
  int i, Idx = 0, HourToMilisec = 0, MinToMilisec = 0, Milisec = 0, SecToMilisec = 0, Time = 0;
  char *Aux = malloc(StringSize * sizeof(char));
  for (i = 0; i < StringSize; i++) {
    if ((MsgRead[i] != 'h') & (MsgRead[i] != 'm') & (MsgRead[i] != 's')) {
      Aux[Idx] = MsgRead[i];
      Idx++;
    } else {
      if (MsgRead[i] == 'h') {
        HourToMilisec = Time * (3600000);
      } else if (MsgRead[i] == 'm') {
        if (MsgRead[i + 1] == 's')
          Milisec = Time;
        else
          MinToMilisec = Time * (60000);
      } else if (MsgRead[i] == 's') {
        if (MsgRead[i - 1] != 'm')
          SecToMilisec = Time * (1000);
      }
      memset(Aux, 0, strlen(Aux));
      Idx = 0;
    }
    Time = atoi(Aux);
  }
  free(Aux);
  if (Time >= 0)
    return (HourToMilisec + MinToMilisec + SecToMilisec + Milisec);
  else
    return Time;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ChangeToMilisec>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %esi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %ebx,%ebx
  jle    L18
  lea    -0x1(%rbx),%eax
  movl   $0x0,(%rsp)
  xor    %r8d,%r8d
  xor    %r13d,%r13d
  movl   $0x0,0xc(%rsp)
  lea    0x1(%r14,%rax,1),%rbp
  xor    %ebx,%ebx
  mov    $0xfffffffffffff7de,%r12
  movl   $0x0,0x4(%rsp)
  jmp    L42
  nopl   0x0(%rax)
L116:
  bt     %rdx,%r12
  jb     L89
  cmp    $0x68,%al
  je     L7
  cmp    $0x6d,%al
  je     L107
  cmpb   $0x6d,-0x1(%r14)
  je     L19
  imul   $0x3e8,%r8d,%eax
  mov    %eax,(%rsp)
L19:
  mov    %r15,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  call   <memset@plt>
L112:
  mov    %r15,%rdi
  add    $0x1,%r14
  call   <atoi@plt>
  mov    %eax,%r8d
  cmp    %r14,%rbp
  je     L143
L42:
  movzbl (%r14),%eax
  lea    -0x68(%rax),%edx
  cmp    $0xb,%dl
  jbe    L116
L89:
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%r15,%rdx,1)
  jmp    L112
  nopl   0x0(%rax)
L7:
  imul   $0x36ee80,%r8d,%r13d
  jmp    L19
  nopl   0x0(%rax)
L107:
  cmpb   $0x73,0x1(%r14)
  je     L125
  imul   $0xea60,%r8d,%eax
  mov    %eax,0x4(%rsp)
  jmp    L19
  nopl   0x0(%rax)
L143:
  mov    %r15,%rdi
  mov    %eax,0x8(%rsp)
  call   <free@plt>
  mov    0x8(%rsp),%r8d
  test   %r8d,%r8d
  js     L28
  mov    0xc(%rsp),%r8d
  add    0x4(%rsp),%r13d
  add    (%rsp),%r13d
  add    %r13d,%r8d
L28:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L125:
  mov    %r8d,0xc(%rsp)
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rax,%rdi
  call   <free@plt>
  xor    %r8d,%r8d
  jmp    L28
```

assistant: ```c
int ChangeToMilisec(char MsgRead[], int StringSize) {
  int i, Idx = 0, HourToMilisec = 0, MinToMilisec = 0, Milisec = 0, SecToMilisec = 0, Time = 0;
  char *Aux = malloc(StringSize * sizeof(char));
  for (i = 0; i < StringSize; i++) {
    if ((MsgRead[i] != 'h') & (MsgRead[i] != 'm') & (MsgRead[i] != 's')) {
      Aux[Idx] = MsgRead[i];
      Idx++;
    } else {
      if (MsgRead[i] == 'h') {
        HourToMilisec = Time * (3600000);
      } else if (MsgRead[i] == 'm') {
        if (MsgRead[i + 1] == 's')
          Milisec = Time;
        else
          MinToMilisec = Time * (60000);
      } else if (MsgRead[i] == 's') {
        if (MsgRead[i - 1] != 'm')
          SecToMilisec = Time * (1000);
      }
      memset(Aux, 0, strlen(Aux));
      Idx = 0;
    }
    Time = atoi(Aux);
  }
  free(Aux);
  if (Time >= 0)
    return (HourToMilisec + MinToMilisec + SecToMilisec + Milisec);
  else
    return Time;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ChangeToMilisec>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %esi,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %ebx,%ebx
  jle    L119
  lea    -0x1(%rbx),%eax
  movl   $0x0,(%rsp)
  xor    %r8d,%r8d
  xor    %r13d,%r13d
  movl   $0x0,0xc(%rsp)
  lea    0x1(%r14,%rax,1),%rbp
  xor    %ebx,%ebx
  mov    $0xfffffffffffff7de,%r12
  movl   $0x0,0x4(%rsp)
  jmp    L2
  nopl   0x0(%rax)
L114:
  bt     %rdx,%r12
  jb     L111
  cmp    $0x68,%al
  je     L6
  cmp    $0x6d,%al
  je     L113
  cmpb   $0x6d,-0x1(%r14)
  je     L144
  imul   $0x3e8,%r8d,%eax
  mov    %eax,(%rsp)
L144:
  mov    %r15,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %eax,%edx
  call   <memset@plt>
L20:
  mov    %r15,%rdi
  add    $0x1,%r14
  call   <atoi@plt>
  mov    %eax,%r8d
  cmp    %r14,%rbp
  je     L34
L2:
  movzbl (%r14),%eax
  lea    -0x68(%rax),%edx
  cmp    $0xb,%dl
  jbe    L114
L111:
  movslq %ebx,%rdx
  add    $0x1,%ebx
  mov    %al,(%r15,%rdx,1)
  jmp    L20
  nopl   0x0(%rax)
L6:
  imul   $0x36ee80,%r8d,%r13d
  jmp    L144
  nopl   0x0(%rax)
L113:
  cmpb   $0x73,0x1(%r14)
  je     L13
  imul   $0xea60,%r8d,%eax
  mov    %eax,0x4(%rsp)
  jmp    L144
  nopl   0x0(%rax)
L34:
  mov    %r15,%rdi
  mov    %eax,0x8(%rsp)
  call   <free@plt>
  mov    0x8(%rsp),%r8d
  test   %r8d,%r8d
  js     L67
  mov    0xc(%rsp),%r8d
  add    0x4(%rsp),%r13d
  add    (%rsp),%r13d
  add    %r13d,%r8d
L67:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L13:
  mov    %r8d,0xc(%rsp)
  jmp    L144
  nopw   0x0(%rax,%rax,1)
L119:
  mov    %rax,%rdi
  call   <free@plt>
  xor    %r8d,%r8d
  jmp    L67
```

assistant: ```c
int ChangeToMilisec(char MsgRead[], int StringSize) {
  int i, Idx = 0, HourToMilisec = 0, MinToMilisec = 0, Milisec = 0, SecToMilisec = 0, Time = 0;
  char *Aux = malloc(StringSize * sizeof(char));
  for (i = 0; i < StringSize; i++) {
    if ((MsgRead[i] != 'h') & (MsgRead[i] != 'm') & (MsgRead[i] != 's')) {
      Aux[Idx] = MsgRead[i];
      Idx++;
    } else {
      if (MsgRead[i] == 'h') {
        HourToMilisec = Time * (3600000);
      } else if (MsgRead[i] == 'm') {
        if (MsgRead[i + 1] == 's')
          Milisec = Time;
        else
          MinToMilisec = Time * (60000);
      } else if (MsgRead[i] == 's') {
        if (MsgRead[i - 1] != 'm')
          SecToMilisec = Time * (1000);
      }
      memset(Aux, 0, strlen(Aux));
      Idx = 0;
    }
    Time = atoi(Aux);
  }
  free(Aux);
  if (Time >= 0)
    return (HourToMilisec + MinToMilisec + SecToMilisec + Milisec);
  else
    return Time;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <arc4random@plt>
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <arc4random@plt>
  xor    %ebx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <recover_hi@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <recover_lo@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L28
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L14
L28:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L2
L14:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string

tool: D8: The real key is %016llx, the key candidates are %016llx, %016llx     

tool: D6: SUCCESS!

tool: D28: FAILURE!

assistant: ```c
int main() {
  uint64_t secret_key = (((uint64_t)arc4random()) << 32) ^ arc4random();
  uint64_t kk1 = recover_lo(secret_key, recover_hi(secret_key));
  uint64_t kk2 = kk1 ^ 0x8000000000000000ULL;
  printf("The real key is %016llx, the key candidates are %016llx, %016llx     ", secret_key, kk1, kk2);
  if ((kk1 == secret_key) || (kk2 == secret_key))
    printf("SUCCESS!\n");
  else
    printf("FAILURE!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <arc4random@plt>
  mov    $0x0,%eax
  call   <arc4random@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <recover_hi@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <recover_lo@plt>
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L9
  lea    D17(%rip),%rdi
  call   <puts@plt>
L15:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D28
datatype: string

tool: D13: The real key is %016llx, the key candidates are %016llx, %016llx     

tool: D17: SUCCESS!

tool: D28: FAILURE!

assistant: ```c
int main() {
  uint64_t secret_key = (((uint64_t)arc4random()) << 32) ^ arc4random();
  uint64_t kk1 = recover_lo(secret_key, recover_hi(secret_key));
  uint64_t kk2 = kk1 ^ 0x8000000000000000ULL;
  printf("The real key is %016llx, the key candidates are %016llx, %016llx     ", secret_key, kk1, kk2);
  if ((kk1 == secret_key) || (kk2 == secret_key))
    printf("SUCCESS!\n");
  else
    printf("FAILURE!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <arc4random@plt>
  xor    %eax,%eax
  call   <arc4random@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <recover_hi@plt>
  mov    %ebx,%edi
  mov    %eax,%esi
  call   <recover_lo@plt>
  mov    %ebx,%esi
  lea    D5(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L9
  lea    D9(%rip),%rdi
  call   <puts@plt>
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L17
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string

tool: D5: The real key is %016llx, the key candidates are %016llx, %016llx     

tool: D9: SUCCESS!

tool: D7: FAILURE!

assistant: ```c
int main() {
  uint64_t secret_key = (((uint64_t)arc4random()) << 32) ^ arc4random();
  uint64_t kk1 = recover_lo(secret_key, recover_hi(secret_key));
  uint64_t kk2 = kk1 ^ 0x8000000000000000ULL;
  printf("The real key is %016llx, the key candidates are %016llx, %016llx     ", secret_key, kk1, kk2);
  if ((kk1 == secret_key) || (kk2 == secret_key))
    printf("SUCCESS!\n");
  else
    printf("FAILURE!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <arc4random@plt>
  xor    %eax,%eax
  call   <arc4random@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <recover_hi@plt>
  mov    %ebx,%edi
  mov    %eax,%esi
  call   <recover_lo@plt>
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L2
  lea    D2(%rip),%rdi
  call   <puts@plt>
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D21
type: string

tool: D6: The real key is %016llx, the key candidates are %016llx, %016llx     

tool: D2: SUCCESS!

tool: D21: FAILURE!

assistant: ```c
int main() {
  uint64_t secret_key = (((uint64_t)arc4random()) << 32) ^ arc4random();
  uint64_t kk1 = recover_lo(secret_key, recover_hi(secret_key));
  uint64_t kk2 = kk1 ^ 0x8000000000000000ULL;
  printf("The real key is %016llx, the key candidates are %016llx, %016llx     ", secret_key, kk1, kk2);
  if ((kk1 == secret_key) || (kk2 == secret_key))
    printf("SUCCESS!\n");
  else
    printf("FAILURE!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L6
L31:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L3:
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L31
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D21
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D63
data_type: string

tool: D2: Inserire quanti numeri si vuole mettere:

tool: D21: %d

tool: D16: 
Inserisci primo numero:

tool: D23: 
Inserisci numero:

tool: D63: 
Il numero minimo e':%d

assistant: ```c
int main() {
  int n;
  int i;
  int num;
  int min;
  printf("Inserire quanti numeri si vuole mettere:");
  scanf("%d", &n);
  i = 1;
  printf("\nInserisci primo numero:");
  scanf("%d", &num);
  min = num;
  while (i < n) {
    printf("\nInserisci numero:");
    scanf("%d", &num);
    if (num < min) {
      min = num;
    }
    i++;
  }
  printf("\nIl numero minimo e':%d", min);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  cmpl   $0x1,(%rsp)
  jle    L21
  mov    $0x1,%ebp
  lea    D27(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D12(%rip),%r12
L4:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,(%rsp)
  jg     L4
L21:
  mov    %ebx,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D12
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D27
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D59
type_infered: string

tool: D6: Inserire quanti numeri si vuole mettere:

tool: D12: %d

tool: D11: 
Inserisci primo numero:

tool: D27: 
Inserisci numero:

tool: D59: 
Il numero minimo e':%d

assistant: ```c
int main() {
  int n;
  int i;
  int num;
  int min;
  printf("Inserire quanti numeri si vuole mettere:");
  scanf("%d", &n);
  i = 1;
  printf("\nInserisci primo numero:");
  scanf("%d", &num);
  min = num;
  while (i < n) {
    printf("\nInserisci numero:");
    scanf("%d", &num);
    if (num < min) {
      min = num;
    }
    i++;
  }
  printf("\nIl numero minimo e':%d", min);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%rdi
  push   %r13
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpl   $0x1,(%rsp)
  mov    0x4(%rsp),%ebp
  jle    L13
  mov    $0x1,%ebx
  lea    D8(%rip),%r14
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L0
L13:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
type_guessed: string
name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D20
type_guessed: string

tool: D23: Inserire quanti numeri si vuole mettere:

tool: D36: %d

tool: D29: 
Inserisci primo numero:

tool: D8: 
Inserisci numero:

tool: D20: 
Il numero minimo e':%d

assistant: ```c
int main() {
  int n;
  int i;
  int num;
  int min;
  printf("Inserire quanti numeri si vuole mettere:");
  scanf("%d", &n);
  i = 1;
  printf("\nInserisci primo numero:");
  scanf("%d", &num);
  min = num;
  while (i < n) {
    printf("\nInserisci numero:");
    scanf("%d", &num);
    if (num < min) {
      min = num;
    }
    i++;
  }
  printf("\nIl numero minimo e':%d", min);
}
```