ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_cmd_target>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <target_set_interactive@plt>
  test   %rax,%rax
  je     L1
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <msg_print@plt>
  nopl   0x0(%rax)
L1:
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <msg_print@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string

tool: D2: Target Selected.

tool: D17: Target Aborted.

assistant: ```c
void do_cmd_target(void) {
  if (target_set_interactive(0x01, -1, -1)) {
    msg_print("Target Selected.");
  } else {
    msg_print("Target Aborted.");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_cmd_target>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <target_set_interactive@plt>
  test   %rax,%rax
  je     L5
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <msg_print@plt>
  nopl   0x0(%rax)
L5:
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <msg_print@plt>
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D8
type: string

tool: D4: Target Selected.

tool: D8: Target Aborted.

assistant: ```c
void do_cmd_target(void) {
  if (target_set_interactive(0x01, -1, -1)) {
    msg_print("Target Selected.");
  } else {
    msg_print("Target Aborted.");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  js     L30
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  movl   $0x1,-0x18(%rbp)
  jmp    L1
L33:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L25:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  imul   -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
L45:
  cmpl   $0x0,-0x10(%rbp)
  jne    L25
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L57
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  addl   $0x1,-0x18(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D38
datatype: string
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D5
datatype: string

tool: D38: introduzca un numero entero positivo: 

tool: D4: %d

tool: D25: los numeros Armstrong hasta ese numero son : 

tool: D5: %d 

assistant: ```c
int main() {
  int num, r, sum, temp;
  int ent;
  printf("introduzca un numero entero positivo: ");
  scanf("%d", &ent);
  if (ent >= 0)
    printf("los numeros Armstrong hasta ese numero son : ");
  for (num = 1; num <= ent; num++) {
    temp = num;
    sum = 0;
    while (temp != 0) {
      r = temp % 10;
      temp = temp / 10;
      sum = sum + (r * r * r);
    }
    if (sum == num)
      printf("%d ", num);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jns    L85
L59:
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
  cmpl   $0x0,0x4(%rsp)
  jg     L13
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L85:
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L69:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L15
L13:
  mov    %ebx,%edx
  mov    $0x0,%edi
  test   %ebx,%ebx
  je     L69
L22:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %esi,%edx
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %eax,%edi
  test   %esi,%esi
  jne    L22
  cmp    %ebx,%edi
  jne    L14
  jmp    L69
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string

tool: D22: introduzca un numero entero positivo: 

tool: D5: %d

tool: D3: %d 

tool: D30: los numeros Armstrong hasta ese numero son : 

assistant: ```c
int main() {
  int num, r, sum, temp;
  int ent;
  printf("introduzca un numero entero positivo: ");
  scanf("%d", &ent);
  if (ent >= 0)
    printf("los numeros Armstrong hasta ese numero son : ");
  for (num = 1; num <= ent; num++) {
    temp = num;
    sum = 0;
    while (temp != 0) {
      r = temp % 10;
      temp = temp / 10;
      sum = sum + (r * r * r);
    }
    if (sum == num)
      printf("%d ", num);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  js     L39
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L39:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L23
  mov    $0x1,%ebp
  mov    $0xcccccccd,%ebx
  lea    D24(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L2:
  mov    %edx,%eax
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %eax,%edi
  test   %edx,%edx
  jne    L2
  cmp    %edi,%ebp
  je     L26
L6:
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jge    L52
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L26:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D24
type_guessed: string

tool: D12: introduzca un numero entero positivo: 

tool: D10: %d

tool: D25: los numeros Armstrong hasta ese numero son : 

tool: D24: %d 

assistant: ```c
int main() {
  int num, r, sum, temp;
  int ent;
  printf("introduzca un numero entero positivo: ");
  scanf("%d", &ent);
  if (ent >= 0)
    printf("los numeros Armstrong hasta ese numero son : ");
  for (num = 1; num <= ent; num++) {
    temp = num;
    sum = 0;
    while (temp != 0) {
      r = temp % 10;
      temp = temp / 10;
      sum = sum + (r * r * r);
    }
    if (sum == num)
      printf("%d ", num);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L47
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L47:
  mov    0x4(%rsp),%r8d
  mov    $0x1,%ebp
  mov    $0xcccccccd,%ebx
  lea    D38(%rip),%r12
  test   %r8d,%r8d
  jle    L25
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %ebp,%edx
  xor    %edi,%edi
  nopl   0x0(%rax)
L39:
  mov    %edx,%eax
  imul   %rbx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %eax,%edi
  test   %edx,%edx
  jne    L39
  cmp    %edi,%ebp
  je     L33
  add    $0x1,%ebp
  cmp    %r8d,%ebp
  jle    L67
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L33:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%r8d
  cmp    %r8d,%ebp
  jle    L67
  jmp    L25
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D38
type: string

tool: D0: introduzca un numero entero positivo: 

tool: D26: %d

tool: D6: los numeros Armstrong hasta ese numero son : 

tool: D38: %d 

assistant: ```c
int main() {
  int num, r, sum, temp;
  int ent;
  printf("introduzca un numero entero positivo: ");
  scanf("%d", &ent);
  if (ent >= 0)
    printf("los numeros Armstrong hasta ese numero son : ");
  for (num = 1; num <= ent; num++) {
    temp = num;
    sum = 0;
    while (temp != 0) {
      r = temp % 10;
      temp = temp / 10;
      sum = sum + (r * r * r);
    }
    if (sum == num)
      printf("%d ", num);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<JulianDay0FromGregorian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x76c,-0x14(%rbp)
  jle    L18
  cmpl   $0x833,-0x14(%rbp)
  jg     L18
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D38(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L2
L18:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  D18(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  add    %ecx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm1,%xmm0
L2:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: f64
name: extract_symbolic_data
arguments: tag: D38
type: f64
name: extract_symbolic_data
arguments: tag: D13
type: f64

tool: D18: 365.25

tool: D38: 1721409.5

tool: D13: 1721424.5

assistant: ```c
double JulianDay0FromGregorian(int year) {
  if (year >= 1901 && year <= 2099)
    return (1721409.5 + (int)(365.25 * (year - 1)));
  else {
    year--;
    int a = (int)(year / 100);
    return ((int)(365.25 * year) - a + (int)(a / 4) + 1721424.5);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<JulianDay0FromGregorian>:
  endbr64
  lea    -0x76d(%rdi),%eax
  cmp    $0xc6,%eax
  ja     L5
  sub    $0x1,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D39(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  D29(%rip),%xmm0
  ret
L5:
  sub    $0x1,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  mulsd  D39(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x25,%rsi
  mov    %rsi,%rcx
  sar    $0x1f,%edi
  sub    %edi,%ecx
  sub    %ecx,%edx
  sar    $0x27,%rax
  sub    %edi,%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  D21(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D39
type_infered: f64
name: read_data
arguments: data_label: D29
type_infered: f64
name: read_data
arguments: data_label: D21
type_infered: f64

tool: D39: 365.25

tool: D29: 1721409.5

tool: D21: 1721424.5

assistant: ```c
double JulianDay0FromGregorian(int year) {
  if (year >= 1901 && year <= 2099)
    return (1721409.5 + (int)(365.25 * (year - 1)));
  else {
    year--;
    int a = (int)(year / 100);
    return ((int)(365.25 * year) - a + (int)(a / 4) + 1721424.5);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<JulianDay0FromGregorian>:
  endbr64
  lea    -0x1(%rdi),%edx
  pxor   %xmm0,%xmm0
  sub    $0x76d,%edi
  cvtsi2sd %edx,%xmm0
  mulsd  D3(%rip),%xmm0
  cvttsd2si %xmm0,%ecx
  cmp    $0xc6,%edi
  ja     L0
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  addsd  D0(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movslq %edx,%rax
  sar    $0x1f,%edx
  pxor   %xmm0,%xmm0
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %edx,%eax
  sub    %edx,%esi
  sub    %esi,%ecx
  add    %eax,%ecx
  cvtsi2sd %ecx,%xmm0
  addsd  D14(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: f64
name: retrieve_data
arguments: data_label: D0
datatype: f64
name: retrieve_data
arguments: data_label: D14
datatype: f64

tool: D3: 365.25

tool: D0: 1721409.5

tool: D14: 1721424.5

assistant: ```c
double JulianDay0FromGregorian(int year) {
  if (year >= 1901 && year <= 2099)
    return (1721409.5 + (int)(365.25 * (year - 1)));
  else {
    year--;
    int a = (int)(year / 100);
    return ((int)(365.25 * year) - a + (int)(a / 4) + 1721424.5);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<JulianDay0FromGregorian>:
  endbr64
  lea    -0x1(%rdi),%edx
  pxor   %xmm0,%xmm0
  sub    $0x76d,%edi
  cvtsi2sd %edx,%xmm0
  mulsd  D21(%rip),%xmm0
  cvttsd2si %xmm0,%ecx
  cmp    $0xc6,%edi
  ja     L5
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  addsd  D13(%rip),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movslq %edx,%rax
  sar    $0x1f,%edx
  pxor   %xmm0,%xmm0
  imul   $0x51eb851f,%rax,%rax
  mov    %rax,%rsi
  sar    $0x27,%rax
  sar    $0x25,%rsi
  sub    %edx,%eax
  sub    %edx,%esi
  sub    %esi,%ecx
  add    %eax,%ecx
  cvtsi2sd %ecx,%xmm0
  addsd  D29(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: f64
name: parse_data
arguments: tag: D13
type_infered: f64
name: parse_data
arguments: tag: D29
type_infered: f64

tool: D21: 365.25

tool: D13: 1721409.5

tool: D29: 1721424.5

assistant: ```c
double JulianDay0FromGregorian(int year) {
  if (year >= 1901 && year <= 2099)
    return (1721409.5 + (int)(365.25 * (year - 1)));
  else {
    year--;
    int a = (int)(year / 100);
    return ((int)(365.25 * year) - a + (int)(a / 4) + 1721424.5);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vdev_utf8_unichar_to_encoded_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L47
  mov    $0x1,%eax
  jmp    L53
L47:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L36
  mov    $0x2,%eax
  jmp    L53
L36:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L68
  mov    $0x3,%eax
  jmp    L53
L68:
  cmpl   $0x1fffff,-0x4(%rbp)
  jg     L57
  mov    $0x4,%eax
  jmp    L53
L57:
  cmpl   $0x3ffffff,-0x4(%rbp)
  jg     L72
  mov    $0x5,%eax
  jmp    L53
L72:
  mov    $0x6,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int vdev_utf8_unichar_to_encoded_len(int unichar) {
  if (unichar < 0x80) {
    return 1;
  }
  if (unichar < 0x800) {
    return 2;
  }
  if (unichar < 0x10000) {
    return 3;
  }
  if (unichar < 0x200000) {
    return 4;
  }
  if (unichar < 0x4000000) {
    return 5;
  }
  return 6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vdev_utf8_unichar_to_encoded_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L39
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L39
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L39
  mov    $0x4,%eax
  cmp    $0x1fffff,%edi
  jle    L39
  cmp    $0x3ffffff,%edi
  setg   %al
  movzbl %al,%eax
  add    $0x5,%eax
L39:
  ret
```

assistant: ```c
int vdev_utf8_unichar_to_encoded_len(int unichar) {
  if (unichar < 0x80) {
    return 1;
  }
  if (unichar < 0x800) {
    return 2;
  }
  if (unichar < 0x10000) {
    return 3;
  }
  if (unichar < 0x200000) {
    return 4;
  }
  if (unichar < 0x4000000) {
    return 5;
  }
  return 6;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vdev_utf8_unichar_to_encoded_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L16
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L16
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L16
  mov    $0x4,%eax
  cmp    $0x1fffff,%edi
  jle    L16
  xor    %eax,%eax
  cmp    $0x3ffffff,%edi
  setg   %al
  add    $0x5,%eax
L16:
  ret
```

assistant: ```c
int vdev_utf8_unichar_to_encoded_len(int unichar) {
  if (unichar < 0x80) {
    return 1;
  }
  if (unichar < 0x800) {
    return 2;
  }
  if (unichar < 0x10000) {
    return 3;
  }
  if (unichar < 0x200000) {
    return 4;
  }
  if (unichar < 0x4000000) {
    return 5;
  }
  return 6;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vdev_utf8_unichar_to_encoded_len>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L36
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L36
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L36
  mov    $0x4,%eax
  cmp    $0x1fffff,%edi
  jle    L36
  xor    %eax,%eax
  cmp    $0x3ffffff,%edi
  setg   %al
  add    $0x5,%eax
L36:
  ret
```

assistant: ```c
int vdev_utf8_unichar_to_encoded_len(int unichar) {
  if (unichar < 0x80) {
    return 1;
  }
  if (unichar < 0x800) {
    return 2;
  }
  if (unichar < 0x10000) {
    return 3;
  }
  if (unichar < 0x200000) {
    return 4;
  }
  if (unichar < 0x4000000) {
    return 5;
  }
  return 6;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    -0x18(%rbp),%rax
  jmp    L10
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L42
L53:
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L54
  mov    -0x18(%rbp),%rax
  jmp    L10
L54:
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L53
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %r12,%rbx
  test   %rax,%rax
  je     L0
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbp
  ja     L38
  add    %rax,%r12
L10:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L0
  add    $0x1,%rbx
  mov    %r12,%rax
  sub    %rbx,%rax
  cmp    %rbp,%rax
  jae    L10
  mov    $0x0,%ebx
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    $0x0,%ebx
  jmp    L0
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L39
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r13
  cmp    %rax,%rbx
  jbe    L6
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L15
L6:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L27
L39:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L15:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strstr>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L43
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r13
  cmp    %rax,%rbx
  jbe    L40
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L24:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L13
L40:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L24
L43:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L13:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  if (!l2) {
    return (char *)s1;
  }
  l1 = strlen(s1);
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2)) {
      return (char *)s1;
    }
    s1++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<index_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <index_readroot@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <index_search__node@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *index_search(struct index_file *in, const char *key) {
  struct index_node_f *root;
  char *value;
  root = index_readroot(in);
  value = index_search__node(root, key, 0);
  return value;
}
```