ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L8:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  cmpq   $0x0,-0x28(%rbp)
  jne    L8
  jmp    L26
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L26:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strncpy(char *dst, const char *src, size_t n) {
  char *save;
  save = dst;
  while (*src != '\0' && n > 0) {
    *(dst++) = *(src++);
    n--;
  }
  while (n-- > 0)
    *(dst++) = '\0';
  return (save);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_strncpy>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%r8d
  test   %rdx,%rdx
  je     L16
  test   %r8b,%r8b
  je     L16
  mov    %rdi,%rcx
L10:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  movzbl (%rsi),%r8d
  sub    $0x1,%rdx
  je     L12
  test   %r8b,%r8b
  jne    L10
L12:
  test   %rdx,%rdx
  je     L33
  add    %rcx,%rdx
L8:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L8
L33:
  ret
L16:
  mov    %rax,%rcx
  jmp    L12
```

assistant: ```c
char *ft_strncpy(char *dst, const char *src, size_t n) {
  char *save;
  save = dst;
  while (*src != '\0' && n > 0) {
    *(dst++) = *(src++);
    n--;
  }
  while (n-- > 0)
    *(dst++) = '\0';
  return (save);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L48
  test   %rdx,%rdx
  jne    L19
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L44:
  test   %rdx,%rdx
  je     L23
L19:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  sub    $0x1,%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L44
L48:
  test   %rdx,%rdx
  je     L23
  xor    %esi,%esi
  call   <memset@plt>
L23:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ft_strncpy(char *dst, const char *src, size_t n) {
  char *save;
  save = dst;
  while (*src != '\0' && n > 0) {
    *(dst++) = *(src++);
    n--;
  }
  while (n-- > 0)
    *(dst++) = '\0';
  return (save);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strncpy>:
  endbr64
  push   %r12
  movzbl (%rsi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L20
  test   %rdx,%rdx
  jne    L58
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L31:
  test   %rdx,%rdx
  je     L30
L58:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  sub    $0x1,%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L31
L20:
  test   %rdx,%rdx
  je     L30
  xor    %esi,%esi
  call   <memset@plt>
L30:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ft_strncpy(char *dst, const char *src, size_t n) {
  char *save;
  save = dst;
  while (*src != '\0' && n > 0) {
    *(dst++) = *(src++);
    n--;
  }
  while (n-- > 0)
    *(dst++) = '\0';
  return (save);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<w9968cf_smbus_write_nack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x13,%esi
  mov    %rax,%rdi
  call   <w9968cf_write_sb@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x12,%esi
  mov    %rax,%rdi
  call   <w9968cf_write_sb@plt>
  nop
  leave
  ret
```

assistant: ```c
void w9968cf_smbus_write_nack(struct sd *sd) {
  w9968cf_write_sb(sd, 0x0013);
  w9968cf_write_sb(sd, 0x0012);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<w9968cf_smbus_write_nack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x13,%esi
  call   <w9968cf_write_sb@plt>
  mov    $0x12,%esi
  mov    %rbx,%rdi
  call   <w9968cf_write_sb@plt>
  pop    %rbx
  ret
```

assistant: ```c
void w9968cf_smbus_write_nack(struct sd *sd) {
  w9968cf_write_sb(sd, 0x0013);
  w9968cf_write_sb(sd, 0x0012);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<w9968cf_smbus_write_nack>:
  endbr64
  push   %rbp
  mov    $0x13,%esi
  mov    %rdi,%rbp
  call   <w9968cf_write_sb@plt>
  mov    %rbp,%rdi
  mov    $0x12,%esi
  pop    %rbp
  jmp    1050 <w9968cf_write_sb@plt>
```

assistant: ```c
void w9968cf_smbus_write_nack(struct sd *sd) {
  w9968cf_write_sb(sd, 0x0013);
  w9968cf_write_sb(sd, 0x0012);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<w9968cf_smbus_write_nack>:
  endbr64
  push   %rbp
  mov    $0x13,%esi
  mov    %rdi,%rbp
  call   <w9968cf_write_sb@plt>
  mov    %rbp,%rdi
  mov    $0x12,%esi
  pop    %rbp
  jmp    1050 <w9968cf_write_sb@plt>
```

assistant: ```c
void w9968cf_smbus_write_nack(struct sd *sd) {
  w9968cf_write_sb(sd, 0x0013);
  w9968cf_write_sb(sd, 0x0012);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtsp_digest_auth_get_username>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L25
L28:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  lea    D12(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rtsp_get_header@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L33
  mov    $0x0,%eax
  jmp    L25
L33:
  mov    -0x8(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rtsp_digest_get_sub_value@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D12: Authorization

tool: D11: username

assistant: ```c
char *rtsp_digest_auth_get_username(struct rtsp_client *c) {
  const char *p;
  if (c == NULL)
    return NULL;
  p = rtsp_get_header(c, "Authorization", 0);
  if (p == NULL)
    return NULL;
  return rtsp_digest_get_sub_value(p, "username");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtsp_digest_auth_get_username>:
  endbr64
  test   %rdi,%rdi
  je     L11
  sub    $0x8,%rsp
  mov    $0x0,%edx
  lea    D15(%rip),%rsi
  call   <rtsp_get_header@plt>
  test   %rax,%rax
  je     L8
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <rtsp_digest_get_sub_value@plt>
L8:
  add    $0x8,%rsp
  ret
L11:
  mov    %rdi,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: string
name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D15: Authorization

tool: D9: username

assistant: ```c
char *rtsp_digest_auth_get_username(struct rtsp_client *c) {
  const char *p;
  if (c == NULL)
    return NULL;
  p = rtsp_get_header(c, "Authorization", 0);
  if (p == NULL)
    return NULL;
  return rtsp_digest_get_sub_value(p, "username");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rtsp_digest_auth_get_username>:
  endbr64
  test   %rdi,%rdi
  je     L14
  sub    $0x8,%rsp
  xor    %edx,%edx
  lea    D7(%rip),%rsi
  call   <rtsp_get_header@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L8
  lea    D10(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <rtsp_digest_get_sub_value@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L14:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D10
data_type: string

tool: D7: Authorization

tool: D10: username

assistant: ```c
char *rtsp_digest_auth_get_username(struct rtsp_client *c) {
  const char *p;
  if (c == NULL)
    return NULL;
  p = rtsp_get_header(c, "Authorization", 0);
  if (p == NULL)
    return NULL;
  return rtsp_digest_get_sub_value(p, "username");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rtsp_digest_auth_get_username>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  xor    %edx,%edx
  lea    D11(%rip),%rsi
  call   <rtsp_get_header@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L9
  lea    D14(%rip),%rsi
  add    $0x8,%rsp
  jmp    1070 <rtsp_digest_get_sub_value@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nop
L6:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D14
type_infered: string

tool: D11: Authorization

tool: D14: username

assistant: ```c
char *rtsp_digest_auth_get_username(struct rtsp_client *c) {
  const char *p;
  if (c == NULL)
    return NULL;
  p = rtsp_get_header(c, "Authorization", 0);
  if (p == NULL)
    return NULL;
  return rtsp_digest_get_sub_value(p, "username");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addq   $0x8,-0x18(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void free_tab(char **tab) {
  int idx;
  for (idx = 0; tab[idx]; tab++)
    free(tab[idx]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<free_tab>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
L13:
  call   <free@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L13
L4:
  pop    %rbx
  ret
```

assistant: ```c
void free_tab(char **tab) {
  int idx;
  for (idx = 0; tab[idx]; tab++)
    free(tab[idx]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<free_tab>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L15
L4:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L4
L15:
  pop    %rbx
  ret
```

assistant: ```c
void free_tab(char **tab) {
  int idx;
  for (idx = 0; tab[idx]; tab++)
    free(tab[idx]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_tab>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L1
L2:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L2
L1:
  pop    %rbx
  ret
```

assistant: ```c
void free_tab(char **tab) {
  int idx;
  for (idx = 0; tab[idx]; tab++)
    free(tab[idx]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pid>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x8,%eax
  and    $0x1f00,%eax
  or     0x4(%rdi),%eax
  ret
```

assistant: ```c
uint16_t get_pid(uint8_t *pid) {
  uint16_t pp = 0;
  pp = (pid[0] & 0x1F) << 8;
  pp |= pid[1];
  return pp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_pid>:
  endbr64
  mov    (%rdi),%eax
  shl    $0x8,%eax
  and    $0x1f00,%eax
  or     0x4(%rdi),%eax
  ret
```

assistant: ```c
uint16_t get_pid(uint8_t *pid) {
  uint16_t pp = 0;
  pp = (pid[0] & 0x1F) << 8;
  pp |= pid[1];
  return pp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <tty_mode@plt>
  mov    $0x0,%eax
  call   <set_timeout_mode@plt>
  mov    $0x0,%eax
  call   <set_cr_noecho_mode@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <get_response@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x1,%edi
  call   <tty_mode@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: D7: Do you want another transaction

assistant: ```c
int main(void) {
  tty_mode(0);
  set_timeout_mode();
  set_cr_noecho_mode();
  int response = get_response("Do you want another transaction");
  tty_mode(1);
  return response;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <tty_mode@plt>
  mov    $0x0,%eax
  call   <set_timeout_mode@plt>
  mov    $0x0,%eax
  call   <set_cr_noecho_mode@plt>
  lea    D1(%rip),%rdi
  call   <get_response@plt>
  mov    %eax,%ebx
  mov    $0x1,%edi
  call   <tty_mode@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: Do you want another transaction

assistant: ```c
int main(void) {
  tty_mode(0);
  set_timeout_mode();
  set_cr_noecho_mode();
  int response = get_response("Do you want another transaction");
  tty_mode(1);
  return response;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  call   <tty_mode@plt>
  xor    %eax,%eax
  call   <set_timeout_mode@plt>
  xor    %eax,%eax
  call   <set_cr_noecho_mode@plt>
  lea    D8(%rip),%rdi
  call   <get_response@plt>
  mov    $0x1,%edi
  mov    %eax,%r12d
  call   <tty_mode@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: Do you want another transaction

assistant: ```c
int main(void) {
  tty_mode(0);
  set_timeout_mode();
  set_cr_noecho_mode();
  int response = get_response("Do you want another transaction");
  tty_mode(1);
  return response;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  call   <tty_mode@plt>
  xor    %eax,%eax
  call   <set_timeout_mode@plt>
  xor    %eax,%eax
  call   <set_cr_noecho_mode@plt>
  lea    D9(%rip),%rdi
  call   <get_response@plt>
  mov    $0x1,%edi
  mov    %eax,%r12d
  call   <tty_mode@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: Do you want another transaction

assistant: ```c
int main(void) {
  tty_mode(0);
  set_timeout_mode();
  set_cr_noecho_mode();
  int response = get_response("Do you want another transaction");
  tty_mode(1);
  return response;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L23
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L23:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D30
type: string

tool: D28: Enter a number: 

tool: D19: %d

tool: D0: Prime


tool: D30: Not prime


assistant: ```c
int main(void) {
  int n;
  printf("Enter a number: ");
  scanf("%d", &n);
  if (is_prime(n)) {
    printf("Prime\n");
  } else {
    printf("Not prime\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L26
  lea    D18(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D31
type_infered: string

tool: D4: Enter a number: 

tool: D8: %d

tool: D18: Prime


tool: D31: Not prime


assistant: ```c
int main(void) {
  int n;
  printf("Enter a number: ");
  scanf("%d", &n);
  if (is_prime(n)) {
    printf("Prime\n");
  } else {
    printf("Not prime\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L22
  lea    D32(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D39
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string
name: extract_symbolic_data
arguments: label: D26
type_infered: string

tool: D13: Enter a number: 

tool: D39: %d

tool: D32: Prime


tool: D26: Not prime


assistant: ```c
int main(void) {
  int n;
  printf("Enter a number: ");
  scanf("%d", &n);
  if (is_prime(n)) {
    printf("Prime\n");
  } else {
    printf("Not prime\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D36(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L4
  lea    D3(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D36
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D3
type_infered: string
name: read_data
arguments: data_tag: D27
type_infered: string

tool: D36: Enter a number: 

tool: D15: %d

tool: D3: Prime


tool: D27: Not prime


assistant: ```c
int main(void) {
  int n;
  printf("Enter a number: ");
  scanf("%d", &n);
  if (is_prime(n)) {
    printf("Prime\n");
  } else {
    printf("Not prime\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<update_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D22
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string

tool: D7: sudo apt-get update

tool: D22: sudo apt-get upgrade

tool: D11: updated system


assistant: ```c
int update_system() {
  system("sudo apt-get update");
  system("sudo apt-get upgrade");
  printf("updated system\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<update_system>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <system@plt>
  lea    D29(%rip),%rdi
  call   <system@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D29
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D12: sudo apt-get update

tool: D29: sudo apt-get upgrade

tool: D3: updated system


assistant: ```c
int update_system() {
  system("sudo apt-get update");
  system("sudo apt-get upgrade");
  printf("updated system\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_system>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <system@plt>
  lea    D20(%rip),%rdi
  call   <system@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string

tool: D1: sudo apt-get update

tool: D20: sudo apt-get upgrade

tool: D28: updated system


assistant: ```c
int update_system() {
  system("sudo apt-get update");
  system("sudo apt-get upgrade");
  printf("updated system\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<update_system>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <system@plt>
  lea    D10(%rip),%rdi
  call   <system@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string

tool: D7: sudo apt-get update

tool: D10: sudo apt-get upgrade

tool: D13: updated system


assistant: ```c
int update_system() {
  system("sudo apt-get update");
  system("sudo apt-get upgrade");
  printf("updated system\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intcelcon_type_of_mixture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2e9,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int intcelcon_type_of_mixture(int *r, int *mix) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(745, r, mix, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intcelcon_type_of_mixture>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rsi
  mov    $0x2e9,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int intcelcon_type_of_mixture(int *r, int *mix) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(745, r, mix, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<intcelcon_type_of_mixture>:
  endbr64
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    $0x2e9,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int intcelcon_type_of_mixture(int *r, int *mix) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(745, r, mix, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<intcelcon_type_of_mixture>:
  endbr64
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  mov    $0x2e9,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int intcelcon_type_of_mixture(int *r, int *mix) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(745, r, mix, c, 0);
  return fail;
}
```