ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xa,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  ja     L83
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D21(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D21(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D155(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
  mov    -0x4(%rbp),%eax
  sub    $0x3,%eax
  cmp    $0x5,%eax
  ja     L30
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D65(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D65(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D155(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
  lea    D141(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
  lea    D122(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L133
L30:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L133:
  jmp    L37
  lea    D141(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
  lea    D122(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L37
L83:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L37:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D155
type_guessed: string
name: retrieve_data
arguments: tag: D33
type_guessed: string
name: retrieve_data
arguments: tag: D50
type_guessed: string
name: retrieve_data
arguments: tag: D141
type_guessed: string
name: retrieve_data
arguments: tag: D122
type_guessed: string
name: retrieve_data
arguments: tag: D29
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D155: Two!


tool: D33: Three!


tool: D50: Four!


tool: D141: Five!


tool: D122: Six!


tool: D29: Seven!


tool: D7: Other!


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10 - argc;
  switch (argc) {
  case 2:
    printf("Two!\n");
    break;
  case 3:
    printf("Three!\n");
    break;
  case 4:
    switch (n) {
    case 10 - 2:
      printf("Two!\n");
      break;
    case 10 - 3:
      printf("Three!\n");
      break;
    case 10 - 4:
      printf("Four!\n");
      break;
    case 10 - 5:
      printf("Five!\n");
      break;
    case 10 - 6:
      printf("Six!\n");
      break;
    case 10 - 7:
      printf("Seven!\n");
      break;
    default:
      printf("Other!\n");
      break;
    }
    break;
  case 5:
    printf("Five!\n");
    break;
  case 6:
    printf("Six!\n");
    break;
  case 7:
    printf("Seven!\n");
    break;
  default:
    printf("Other!\n");
    break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x7,%edi
  ja     L35
  mov    %edi,%edi
  lea    D13(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D64(%rip),%rdi
  call   <printf@plt>
L39:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
  lea    D71(%rip),%rdi
  call   <printf@plt>
  jmp    L39
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L39
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L39
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L39
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L35:
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L39
```

tool_calls: name: unpack_data
arguments: data_tag: D64
datatype: string
name: unpack_data
arguments: data_tag: D71
datatype: string
name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D69
datatype: string

tool: D64: Two!


tool: D71: Three!


tool: D25: Four!


tool: D19: Five!


tool: D17: Six!


tool: D0: Seven!


tool: D69: Other!


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10 - argc;
  switch (argc) {
  case 2:
    printf("Two!\n");
    break;
  case 3:
    printf("Three!\n");
    break;
  case 4:
    switch (n) {
    case 10 - 2:
      printf("Two!\n");
      break;
    case 10 - 3:
      printf("Three!\n");
      break;
    case 10 - 4:
      printf("Four!\n");
      break;
    case 10 - 5:
      printf("Five!\n");
      break;
    case 10 - 6:
      printf("Six!\n");
      break;
    case 10 - 7:
      printf("Seven!\n");
      break;
    default:
      printf("Other!\n");
      break;
    }
    break;
  case 5:
    printf("Five!\n");
    break;
  case 6:
    printf("Six!\n");
    break;
  case 7:
    printf("Seven!\n");
    break;
  default:
    printf("Other!\n");
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x7,%edi
  ja     L14
  lea    D56(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D26(%rip),%rdi
  call   <printf@plt>
L46:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  lea    D37(%rip),%rdi
  call   <printf@plt>
  jmp    L46
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L46
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L46
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L14:
  lea    D73(%rip),%rdi
  call   <printf@plt>
  jmp    L46
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L46
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string
name: parse_data
arguments: label: D53
type_infered: string
name: parse_data
arguments: label: D75
type_infered: string
name: parse_data
arguments: label: D70
type_infered: string
name: parse_data
arguments: label: D73
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D26: Seven!


tool: D37: Two!


tool: D53: Three!


tool: D75: Five!


tool: D70: Six!


tool: D73: Other!


tool: D4: Four!


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10 - argc;
  switch (argc) {
  case 2:
    printf("Two!\n");
    break;
  case 3:
    printf("Three!\n");
    break;
  case 4:
    switch (n) {
    case 10 - 2:
      printf("Two!\n");
      break;
    case 10 - 3:
      printf("Three!\n");
      break;
    case 10 - 4:
      printf("Four!\n");
      break;
    case 10 - 5:
      printf("Five!\n");
      break;
    case 10 - 6:
      printf("Six!\n");
      break;
    case 10 - 7:
      printf("Seven!\n");
      break;
    default:
      printf("Other!\n");
      break;
    }
    break;
  case 5:
    printf("Five!\n");
    break;
  case 6:
    printf("Six!\n");
    break;
  case 7:
    printf("Seven!\n");
    break;
  default:
    printf("Other!\n");
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x7,%edi
  ja     L27
  lea    D37(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D33(%rip),%rdi
  call   <printf@plt>
L43:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  lea    D73(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D55(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D76(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L27:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L43
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L43
```

tool_calls: name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D73
type_guessed: string
name: disassemble_data
arguments: tag: D43
type_guessed: string
name: disassemble_data
arguments: tag: D55
type_guessed: string
name: disassemble_data
arguments: tag: D76
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D56
type_guessed: string

tool: D33: Seven!


tool: D73: Two!


tool: D43: Three!


tool: D55: Five!


tool: D76: Six!


tool: D15: Other!


tool: D56: Four!


assistant: ```c
int main(int argc, char *argv[]) {
  int n = 10 - argc;
  switch (argc) {
  case 2:
    printf("Two!\n");
    break;
  case 3:
    printf("Three!\n");
    break;
  case 4:
    switch (n) {
    case 10 - 2:
      printf("Two!\n");
      break;
    case 10 - 3:
      printf("Three!\n");
      break;
    case 10 - 4:
      printf("Four!\n");
      break;
    case 10 - 5:
      printf("Five!\n");
      break;
    case 10 - 6:
      printf("Six!\n");
      break;
    case 10 - 7:
      printf("Seven!\n");
      break;
    default:
      printf("Other!\n");
      break;
    }
    break;
  case 5:
    printf("Five!\n");
    break;
  case 6:
    printf("Six!\n");
    break;
  case 7:
    printf("Seven!\n");
    break;
  default:
    printf("Other!\n");
    break;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<map_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  neg    %eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    D28(%rip),%rax
  mov    (%rax),%ecx
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  or     %eax,%esi
  mov    -0x4(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %edi,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t map_mem(int fd, void **va, off_t pa, size_t length) {
  off_t pa_aligned = pa & ~(sysconf(_SC_PAGE_SIZE) - 1);
  length = pa - pa_aligned + length;
  *va = mmap(NULL, length, PROT_READ | PROT_WRITE, MAP_SHARED, fd, pa_aligned);
  return length;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<map_mem>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    D39(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  neg    %eax
  mov    %eax,%r9d
  and    %ebx,%r9d
  sub    %r9d,%ebx
  movslq %ebx,%rbx
  add    %r13,%rbx
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  or     (%rax),%edx
  mov    %r12d,%r8d
  mov    D24(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <mmap@plt>
  mov    %rax,0x0(%rbp)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map_mem(int fd, void **va, off_t pa, size_t length) {
  off_t pa_aligned = pa & ~(sysconf(_SC_PAGE_SIZE) - 1);
  length = pa - pa_aligned + length;
  *va = mmap(NULL, length, PROT_READ | PROT_WRITE, MAP_SHARED, fd, pa_aligned);
  return length;
}
```
user: What is the c source code of the assembly code below:

```asm
<map_mem>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %r13d,%r8d
  xor    %edi,%edi
  neg    %eax
  mov    %eax,%r9d
  mov    D8(%rip),%rax
  and    %r12d,%r9d
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  sub    %r9d,%r12d
  movslq %r12d,%r12
  or     (%rax),%edx
  mov    D16(%rip),%rax
  add    %rbp,%r12
  mov    %r12,%rsi
  mov    (%rax),%ecx
  call   <mmap@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map_mem(int fd, void **va, off_t pa, size_t length) {
  off_t pa_aligned = pa & ~(sysconf(_SC_PAGE_SIZE) - 1);
  length = pa - pa_aligned + length;
  *va = mmap(NULL, length, PROT_READ | PROT_WRITE, MAP_SHARED, fd, pa_aligned);
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<map_mem>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    D38(%rip),%rax
  mov    (%rax),%edi
  call   <sysconf@plt>
  mov    %r13d,%r8d
  xor    %edi,%edi
  neg    %eax
  mov    %eax,%r9d
  mov    D10(%rip),%rax
  and    %r12d,%r9d
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  sub    %r9d,%r12d
  movslq %r12d,%r12
  or     (%rax),%edx
  mov    D19(%rip),%rax
  add    %rbp,%r12
  mov    %r12,%rsi
  mov    (%rax),%ecx
  call   <mmap@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t map_mem(int fd, void **va, off_t pa, size_t length) {
  off_t pa_aligned = pa & ~(sysconf(_SC_PAGE_SIZE) - 1);
  length = pa - pa_aligned + length;
  *va = mmap(NULL, length, PROT_READ | PROT_WRITE, MAP_SHARED, fd, pa_aligned);
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x11(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    $0x1,%eax
  jmp    L29
L23:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int foo(void) {
  char *p;
  {
    char a = 0;
    p = &a;
  }
  if (*p)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int foo(void) {
  char *p;
  {
    char a = 0;
    p = &a;
  }
  if (*p)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo(void) {
  char *p;
  {
    char a = 0;
    p = &a;
  }
  if (*p)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo(void) {
  char *p;
  {
    char a = 0;
    p = &a;
  }
  if (*p)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bpf_obj_get_next_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sys_bpf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  mov    -0x10(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L13:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int bpf_obj_get_next_id(__u32 start_id, __u32 *next_id, int cmd) {
  union bpf_attr attr;
  int err;
  memset(&attr, 0, sizeof(attr));
  attr.start_id = start_id;
  err = sys_bpf(cmd, &attr, sizeof(attr));
  if (!err)
    *next_id = attr.next_id;
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bpf_obj_get_next_id>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %ebp,0x4(%rsp)
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <sys_bpf@plt>
  test   %eax,%eax
  jne    L4
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get_next_id(__u32 start_id, __u32 *next_id, int cmd) {
  union bpf_attr attr;
  int err;
  memset(&attr, 0, sizeof(attr));
  attr.start_id = start_id;
  err = sys_bpf(cmd, &attr, sizeof(attr));
  if (!err)
    *next_id = attr.next_id;
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bpf_obj_get_next_id>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edx,%ebp
  mov    $0x4,%edx
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %ebx,0x4(%rsp)
  call   <sys_bpf@plt>
  test   %eax,%eax
  jne    L11
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get_next_id(__u32 start_id, __u32 *next_id, int cmd) {
  union bpf_attr attr;
  int err;
  memset(&attr, 0, sizeof(attr));
  attr.start_id = start_id;
  err = sys_bpf(cmd, &attr, sizeof(attr));
  if (!err)
    *next_id = attr.next_id;
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bpf_obj_get_next_id>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edx,%ebp
  mov    $0x4,%edx
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %ebx,0x4(%rsp)
  call   <sys_bpf@plt>
  test   %eax,%eax
  jne    L3
  mov    0x4(%rsp),%edx
  mov    %edx,(%r12)
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_obj_get_next_id(__u32 start_id, __u32 *next_id, int cmd) {
  union bpf_attr attr;
  int err;
  memset(&attr, 0, sizeof(attr));
  attr.start_id = start_id;
  err = sys_bpf(cmd, &attr, sizeof(attr));
  if (!err)
    *next_id = attr.next_id;
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L96
L16:
  addl   $0x1,-0xc(%rbp)
L96:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xc,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xb,%al
  je     L16
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L7
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L64
L7:
  addl   $0x1,-0xc(%rbp)
L64:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L37
  movl   $0x1,-0x8(%rbp)
  jmp    L37
L140:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L43
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L140
L43:
  cmpl   $0x1,-0x8(%rbp)
  jne    L77
  mov    -0x4(%rbp),%eax
  neg    %eax
  jmp    L70
L77:
  mov    -0x4(%rbp),%eax
L70:
  pop    %rbp
  ret
```

assistant: ```c
int ft_atoi(char *str) {
  int i;
  int negative;
  int nb;
  nb = 0;
  i = 0;
  negative = 0;
  while (str[i] == ' ' || str[i] == '\n' || str[i] == '\t' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-' || str[i] == '+')
    i++;
  if (str[i] == '-')
    negative = 1;
  while (str[i] >= 48 && str[i] <= 57) {
    nb = nb * 10;
    nb = nb + (str[i] - '0');
    i++;
  }
  if (negative == 1)
    return (-nb);
  else
    return (nb);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_atoi>:
  endbr64
  movzbl (%rdi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x4,%al
  jbe    L49
  cmp    $0x20,%dl
  jne    L68
L49:
  mov    $0x1,%eax
L79:
  mov    %eax,%esi
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x4,%cl
  jbe    L79
  cmp    $0x20,%dl
  je     L79
L30:
  sub    $0x2b,%edx
  and    $0xfffffffd,%edx
  cmp    $0x1,%dl
  adc    $0x0,%esi
  movslq %esi,%rsi
  movzbl (%rdi,%rsi,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L78
  lea    0x1(%rdi,%rsi,1),%rcx
  mov    $0x0,%edx
L0:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L0
L36:
  mov    %edx,%eax
  ret
L68:
  mov    $0x0,%esi
  jmp    L30
L78:
  mov    $0x0,%edx
  jmp    L36
```

assistant: ```c
int ft_atoi(char *str) {
  int i;
  int negative;
  int nb;
  nb = 0;
  i = 0;
  negative = 0;
  while (str[i] == ' ' || str[i] == '\n' || str[i] == '\t' || str[i] == '\f' || str[i] == '\r' || str[i] == '\v')
    i++;
  if (str[i] == '-' || str[i] == '+')
    i++;
  if (str[i] == '-')
    negative = 1;
  while (str[i] >= 48 && str[i] <= 57) {
    nb = nb * 10;
    nb = nb + (str[i] - '0');
    i++;
  }
  if (negative == 1)
    return (-nb);
  else
    return (nb);
}
```