ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<debug_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <debug_flag@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L13
L14:
  nop
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D16: INFOCRAWLER_DEBUG

tool: D1:  	


assistant: ```c
void debug_init() {
  char *s = NULL;
  char *t = NULL;
  char *u = NULL;
  s = getenv("INFOCRAWLER_DEBUG");
  if (s == (char *)0)
    return;
  t = strdup(s);
  u = strtok(t, " \t\n");
  do {
    debug_flag(u);
  } while ((u = strtok((char *)0, " \t\n")));
  free(t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<debug_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rbp
  lea    D12(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  lea    D12(%rip),%rbx
L6:
  call   <debug_flag@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L6
  mov    %rbp,%rdi
  call   <free@plt>
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string

tool: D1: INFOCRAWLER_DEBUG

tool: D12:  	


assistant: ```c
void debug_init() {
  char *s = NULL;
  char *t = NULL;
  char *u = NULL;
  s = getenv("INFOCRAWLER_DEBUG");
  if (s == (char *)0)
    return;
  t = strdup(s);
  u = strtok(t, " \t\n");
  do {
    debug_flag(u);
  } while ((u = strtok((char *)0, " \t\n")));
  free(t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<debug_init>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L13
  mov    %rax,%rdi
  lea    D19(%rip),%rbx
  call   <strdup@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  nopl   0x0(%rax,%rax,1)
L19:
  call   <debug_flag@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <free@plt>
  nopl   (%rax)
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string

tool: D9: INFOCRAWLER_DEBUG

tool: D19:  	


assistant: ```c
void debug_init() {
  char *s = NULL;
  char *t = NULL;
  char *u = NULL;
  s = getenv("INFOCRAWLER_DEBUG");
  if (s == (char *)0)
    return;
  t = strdup(s);
  u = strtok(t, " \t\n");
  do {
    debug_flag(u);
  } while ((u = strtok((char *)0, " \t\n")));
  free(t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_init>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  lea    D8(%rip),%rbx
  call   <strdup@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strtok@plt>
  mov    %rax,%rdi
  nopl   0x0(%rax,%rax,1)
L11:
  call   <debug_flag@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <free@plt>
  nopl   (%rax)
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string
name: unpack_data
arguments: label: D8
type_infered: string

tool: D9: INFOCRAWLER_DEBUG

tool: D8:  	


assistant: ```c
void debug_init() {
  char *s = NULL;
  char *t = NULL;
  char *u = NULL;
  s = getenv("INFOCRAWLER_DEBUG");
  if (s == (char *)0)
    return;
  t = strdup(s);
  u = strtok(t, " \t\n");
  do {
    debug_flag(u);
  } while ((u = strtok((char *)0, " \t\n")));
  free(t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xdab,%eax
  jle    L4
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L24
L4:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D29: %d

tool: D11: YES

tool: D9: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num >= 3500)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0xdab,0x4(%rsp)
  jle    L17
  lea    D29(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L17:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D16
type: string

tool: D12: %d

tool: D29: YES

tool: D16: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num >= 3500)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0xdab,0x4(%rsp)
  jle    L25
  lea    D26(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L25:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
type: string
name: read_data
arguments: data_label: D26
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D21: %d

tool: D26: YES

tool: D7: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num >= 3500)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cmpl   $0xdab,0x4(%rsp)
  jle    L27
  lea    D28(%rip),%rdi
  call   <printf@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L27:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D8: %d

tool: D28: YES

tool: D9: NO

assistant: ```c
int main() {
  int num;
  scanf("%d", &num);
  if (num >= 3500)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<diminuto_string_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L11
L0:
  mov    -0x18(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
const char *diminuto_string_basename(const char *argvzero) {
  const char *basename;
  return ((basename = strrchr(argvzero, '/')) == (char *)0) ? argvzero : basename + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<diminuto_string_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *diminuto_string_basename(const char *argvzero) {
  const char *basename;
  return ((basename = strrchr(argvzero, '/')) == (char *)0) ? argvzero : basename + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<diminuto_string_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *diminuto_string_basename(const char *argvzero) {
  const char *basename;
  return ((basename = strrchr(argvzero, '/')) == (char *)0) ? argvzero : basename + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diminuto_string_basename>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *diminuto_string_basename(const char *argvzero) {
  const char *basename;
  return ((basename = strrchr(argvzero, '/')) == (char *)0) ? argvzero : basename + 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L48:
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    $0x40,%eax
  jmp    L56
L11:
  mov    $0x2e,%eax
L56:
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L48
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_bitmap(unsigned char **pixels, int w, int h) {
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      putchar(pixels[y][x] ? '@' : '.');
    }
    putchar('\n');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L50
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r13d
  mov    %rdi,%rbp
  lea    -0x1(%rdx),%eax
  lea    0x8(%rdi,%rax,8),%r14
  mov    %esi,%r12d
  jmp    L28
L30:
  mov    0x0(%rbp),%rax
  cmpb   $0x1,(%rax,%rbx,1)
  sbb    %edi,%edi
  and    $0xffffffee,%edi
  add    $0x40,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L30
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L55
L28:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L30
  jmp    L12
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  ret
```

assistant: ```c
void print_bitmap(unsigned char **pixels, int w, int h) {
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      putchar(pixels[y][x] ? '@' : '.');
    }
    putchar('\n');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L34
  push   %r14
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r14
  push   %r13
  lea    0x8(%rdi,%rax,8),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L21:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L1
  nop
L17:
  mov    (%r14),%rax
  cmpb   $0x1,(%rax,%rbx,1)
  sbb    %edi,%edi
  add    $0x1,%rbx
  and    $0xffffffee,%edi
  add    $0x40,%edi
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L17
L1:
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r13,%r14
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  ret
```

assistant: ```c
void print_bitmap(unsigned char **pixels, int w, int h) {
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      putchar(pixels[y][x] ? '@' : '.');
    }
    putchar('\n');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_bitmap>:
  endbr64
  test   %edx,%edx
  jle    L5
  push   %r14
  lea    -0x1(%rdx),%eax
  push   %r13
  lea    0x8(%rdi,%rax,8),%r14
  mov    %esi,%r13d
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  nopl   0x0(%rax)
L43:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L67
  nop
L13:
  mov    0x0(%rbp),%rax
  cmpb   $0x0,(%rax,%rbx,1)
  je     L64
  mov    $0x40,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r12,%rbx
  jne    L13
L67:
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L43
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L64:
  mov    $0x2e,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L13
  jmp    L67
L5:
  ret
```

assistant: ```c
void print_bitmap(unsigned char **pixels, int w, int h) {
  int x, y;
  for (y = 0; y < h; y++) {
    for (x = 0; x < w; x++) {
      putchar(pixels[y][x] ? '@' : '.');
    }
    putchar('\n');
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__kern_isrvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movzbl -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __kern_isrvec(unsigned char __intno, void (*__israddr)(void)) {
  void (**ivec)(void) = 0x0000;
  *(ivec + __intno) = __israddr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__kern_isrvec>:
  endbr64
  movzbl %dil,%edi
  mov    %rsi,0x0(,%rdi,8)
  ret
```

assistant: ```c
void __kern_isrvec(unsigned char __intno, void (*__israddr)(void)) {
  void (**ivec)(void) = 0x0000;
  *(ivec + __intno) = __israddr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__kern_isrvec>:
  endbr64
  movzbl %dil,%edi
  mov    %rsi,0x0(,%rdi,8)
  ret
```

assistant: ```c
void __kern_isrvec(unsigned char __intno, void (*__israddr)(void)) {
  void (**ivec)(void) = 0x0000;
  *(ivec + __intno) = __israddr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__kern_isrvec>:
  endbr64
  movzbl %dil,%edi
  mov    %rsi,0x0(,%rdi,8)
  ret
```

assistant: ```c
void __kern_isrvec(unsigned char __intno, void (*__israddr)(void)) {
  void (**ivec)(void) = 0x0000;
  *(ivec + __intno) = __israddr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ic_string_contents_steal_and_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L26
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ic_string_contents_steal@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L26
L24:
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <ic_string_destroy@plt>
  test   %eax,%eax
  jne    L31
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L26
L31:
  mov    -0x8(%rbp),%rax
L26:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string

tool: D10: ic_string_contents_steal_and_destroy: null string passed in

tool: D14: ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed

tool: D11: ic_string_contents_steal: call to ic_string_destroy failed

assistant: ```c
char *ic_string_contents_steal_and_destroy(struct ic_string *string) {
  char *ch = 0;
  if (!string) {
    puts("ic_string_contents_steal_and_destroy: null string passed in");
    return 0;
  }
  ch = ic_string_contents_steal(string);
  if (!ch) {
    puts("ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed");
    return 0;
  }
  if (!ic_string_destroy(string, 1)) {
    puts("ic_string_contents_steal: call to ic_string_destroy failed");
    return 0;
  }
  return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ic_string_contents_steal_and_destroy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L55
  call   <ic_string_contents_steal@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L44
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <ic_string_destroy@plt>
  test   %eax,%eax
  je     L51
L59:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rbp
  jmp    L59
L44:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L59
L51:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  jmp    L59
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string

tool: D28: ic_string_contents_steal_and_destroy: null string passed in

tool: D25: ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed

tool: D21: ic_string_contents_steal: call to ic_string_destroy failed

assistant: ```c
char *ic_string_contents_steal_and_destroy(struct ic_string *string) {
  char *ch = 0;
  if (!string) {
    puts("ic_string_contents_steal_and_destroy: null string passed in");
    return 0;
  }
  ch = ic_string_contents_steal(string);
  if (!ch) {
    puts("ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed");
    return 0;
  }
  if (!ic_string_destroy(string, 1)) {
    puts("ic_string_contents_steal: call to ic_string_destroy failed");
    return 0;
  }
  return ch;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ic_string_contents_steal_and_destroy>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L20
  mov    %rdi,%rbp
  call   <ic_string_contents_steal@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L29
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <ic_string_destroy@plt>
  test   %eax,%eax
  je     L21
L34:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  lea    D11(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L34
  nopl   0x0(%rax)
L21:
  lea    D9(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L34
  nopl   0x0(%rax)
L29:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L34
```

tool_calls: name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D25
type_infered: string

tool: D11: ic_string_contents_steal_and_destroy: null string passed in

tool: D9: ic_string_contents_steal: call to ic_string_destroy failed

tool: D25: ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed

assistant: ```c
char *ic_string_contents_steal_and_destroy(struct ic_string *string) {
  char *ch = 0;
  if (!string) {
    puts("ic_string_contents_steal_and_destroy: null string passed in");
    return 0;
  }
  ch = ic_string_contents_steal(string);
  if (!ch) {
    puts("ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed");
    return 0;
  }
  if (!ic_string_destroy(string, 1)) {
    puts("ic_string_contents_steal: call to ic_string_destroy failed");
    return 0;
  }
  return ch;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ic_string_contents_steal_and_destroy>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L57
  mov    %rdi,%rbp
  call   <ic_string_contents_steal@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L59
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <ic_string_destroy@plt>
  test   %eax,%eax
  je     L32
L38:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L57:
  lea    D20(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L38
  nopl   0x0(%rax)
L32:
  lea    D24(%rip),%rdi
  xor    %r12d,%r12d
  call   <puts@plt>
  jmp    L38
  nopl   0x0(%rax)
L59:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D20: ic_string_contents_steal_and_destroy: null string passed in

tool: D24: ic_string_contents_steal: call to ic_string_destroy failed

tool: D3: ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed

assistant: ```c
char *ic_string_contents_steal_and_destroy(struct ic_string *string) {
  char *ch = 0;
  if (!string) {
    puts("ic_string_contents_steal_and_destroy: null string passed in");
    return 0;
  }
  ch = ic_string_contents_steal(string);
  if (!ch) {
    puts("ic_string_contents_steal_and_destroy: call to ic_string_contents_steal failed");
    return 0;
  }
  if (!ic_string_destroy(string, 1)) {
    puts("ic_string_contents_steal: call to ic_string_destroy failed");
    return 0;
  }
  return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SOS_Warning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: Warning: 

assistant: ```c
void SOS_Warning(const char *warntext_ptr, ...) {
  va_list arg_ptr;
  printf("Warning: ");
  va_start(arg_ptr, warntext_ptr);
  vprintf(warntext_ptr, arg_ptr);
  va_end(arg_ptr);
}
```