ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<printi>:
  endbr64
  push   %r14
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L31
  mov    %edx,%edi
  test   %ecx,%ecx
  setne  %dl
  cmp    $0xa,%edi
  sete   %al
  test   %al,%dl
  je     L129
  test   %esi,%esi
  js     L36
L129:
  xor    %ebx,%ebx
L19:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x27(%rsp)
  lea    0x27(%rsp),%r10
  lea    -0x3a(%rax),%r8d
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %eax,%esi
  mov    %r14,%r10
L58:
  xor    %edx,%edx
  mov    %esi,%eax
  lea    -0x1(%r10),%r14
  div    %edi
  cmp    $0x9,%edx
  lea    (%rdx,%r8,1),%ecx
  cmovle %edx,%ecx
  add    $0x30,%ecx
  mov    %cl,-0x1(%r10)
  cmp    %esi,%edi
  jbe    L73
  test   %ebx,%ebx
  jne    L105
L109:
  mov    %r9d,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <prints@plt>
  add    %ebx,%eax
L6:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  test   %r12d,%r12d
  je     L42
  test   $0x2,%r9b
  je     L42
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  mov    %r9d,0xc(%rsp)
  sub    $0x1,%r12d
  call   <printchar@plt>
  mov    0xc(%rsp),%r9d
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L42:
  movb   $0x2d,-0x1(%r14)
  xor    %ebx,%ebx
  lea    -0x2(%r10),%r14
  jmp    L109
  nopl   (%rax)
L31:
  mov    $0x30,%eax
  lea    0x1c(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r8d,%edx
  mov    %ax,0x1c(%rsp)
  call   <prints@plt>
  jmp    L6
  nop
L36:
  neg    %esi
  mov    $0x1,%ebx
  jmp    L19
L88:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else
      *--s = '-';
  }
  return pc + prints(out, s, width, pad);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printi>:
  endbr64
  push   %r13
  mov    %esi,%eax
  mov    %r9d,%r13d
  mov    %edx,%esi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x28(%rsp)
  xor    %edx,%edx
  test   %eax,%eax
  je     L120
  test   %ecx,%ecx
  setne  %cl
  cmp    $0xa,%esi
  sete   %dl
  test   %dl,%cl
  je     L134
  test   %eax,%eax
  js     L61
L134:
  mov    %eax,%ecx
  xor    %ebx,%ebx
L41:
  mov    0x60(%rsp),%eax
  movb   $0x0,0x27(%rsp)
  lea    0x27(%rsp),%r8
  lea    -0x3a(%rax),%r9d
  jmp    L111
  nop
L85:
  lea    0x30(%r9,%rdx,1),%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  ja     L58
L2:
  mov    %eax,%ecx
  mov    %rbp,%r8
L111:
  mov    %ecx,%eax
  xor    %edx,%edx
  lea    -0x1(%r8),%rbp
  div    %esi
  cmp    $0x9,%edx
  jg     L85
  add    $0x30,%edx
  mov    %dl,-0x1(%r8)
  cmp    %ecx,%esi
  jbe    L2
L58:
  test   %ebx,%ebx
  jne    L96
L126:
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <prints@plt>
  add    %ebx,%eax
L93:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L96:
  test   %r12d,%r12d
  je     L118
  test   $0x2,%r13b
  je     L118
  mov    $0x2d,%esi
  mov    %rdi,0x8(%rsp)
  sub    $0x1,%r12d
  call   <printchar@plt>
  mov    0x8(%rsp),%rdi
  jmp    L126
  nopl   (%rax)
L118:
  movb   $0x2d,-0x1(%rbp)
  xor    %ebx,%ebx
  lea    -0x2(%r8),%rbp
  jmp    L126
  nopl   0x0(%rax)
L120:
  mov    $0x30,%eax
  lea    0x1c(%rsp),%rsi
  mov    %r9d,%ecx
  mov    %r8d,%edx
  mov    %ax,0x1c(%rsp)
  call   <prints@plt>
  jmp    L93
  nopl   0x0(%rax)
L61:
  neg    %eax
  mov    $0x1,%ebx
  mov    %eax,%ecx
  jmp    L41
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int printi(char **out, int i, int b, int sg, int width, int pad, int letbase) {
  char print_buf[12];
  register char *s;
  register int t, neg = 0, pc = 0;
  register unsigned int u = i;
  if (i == 0) {
    print_buf[0] = '0';
    print_buf[1] = '\0';
    return prints(out, print_buf, width, pad);
  }
  if (sg && b == 10 && i < 0) {
    neg = 1;
    u = -i;
  }
  s = print_buf + 12 - 1;
  *s = '\0';
  while (u) {
    t = u % b;
    if (t >= 10)
      t += letbase - '0' - 10;
    *--s = t + '0';
    u /= b;
  }
  if (neg) {
    if (width && (pad & 2)) {
      printchar(out, '-');
      ++pc;
      --width;
    } else
      *--s = '-';
  }
  return pc + prints(out, s, width, pad);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EndVERBATIM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <PopIndent@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <TXTOUT@plt>
  mov    $0x0,%eax
  call   <RecursiveReturn@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: @end example


assistant: ```c
void EndVERBATIM() {
  PopIndent();
  TXTOUT("@end example\n");
  RecursiveReturn();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EndVERBATIM>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PopIndent@plt>
  lea    D8(%rip),%rdi
  call   <TXTOUT@plt>
  mov    $0x0,%eax
  call   <RecursiveReturn@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: @end example


assistant: ```c
void EndVERBATIM() {
  PopIndent();
  TXTOUT("@end example\n");
  RecursiveReturn();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EndVERBATIM>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PopIndent@plt>
  lea    D3(%rip),%rdi
  call   <TXTOUT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <RecursiveReturn@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: @end example


assistant: ```c
void EndVERBATIM() {
  PopIndent();
  TXTOUT("@end example\n");
  RecursiveReturn();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<EndVERBATIM>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PopIndent@plt>
  lea    D1(%rip),%rdi
  call   <TXTOUT@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <RecursiveReturn@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: @end example


assistant: ```c
void EndVERBATIM() {
  PopIndent();
  TXTOUT("@end example\n");
  RecursiveReturn();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Apresentacao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0xa,%al
  jne    L19
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D34
datatype: string
name: read_data
arguments: tag: D42
datatype: string
name: read_data
arguments: tag: D40
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D6
datatype: string

tool: D34: Bem-vindo ao Jogo da Velha:


tool: D42: O jogador comeca!!! 
Escolha se quer ser 'X' ou 'O'
Pronto p/comecar...

tool: D40: Aperte ENTER p/ iniciar...

tool: D18: %c

tool: D6: cls

assistant: ```c
void Apresentacao(void) {
  char enter;
  printf("Bem-vindo ao Jogo da Velha:\n");
  printf("O jogador comeca!!! \nEscolha se quer ser 'X' ou 'O'\nPronto p/comecar...");
  printf("Aperte ENTER p/ iniciar...");
  scanf("%c", &enter);
  if (enter == '\n') {
    system("cls");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Apresentacao>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0xa,0x7(%rsp)
  je     L26
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
L26:
  lea    D10(%rip),%rdi
  call   <system@plt>
  jmp    L2
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D31
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D12: Bem-vindo ao Jogo da Velha:


tool: D31: O jogador comeca!!! 
Escolha se quer ser 'X' ou 'O'
Pronto p/comecar...

tool: D2: Aperte ENTER p/ iniciar...

tool: D29: %c

tool: D10: cls

assistant: ```c
void Apresentacao(void) {
  char enter;
  printf("Bem-vindo ao Jogo da Velha:\n");
  printf("O jogador comeca!!! \nEscolha se quer ser 'X' ou 'O'\nPronto p/comecar...");
  printf("Aperte ENTER p/ iniciar...");
  scanf("%c", &enter);
  if (enter == '\n') {
    system("cls");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Apresentacao>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0xa,0x7(%rsp)
  je     L23
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L23:
  lea    D12(%rip),%rdi
  call   <system@plt>
  jmp    L27
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: string
name: disassemble_data
arguments: label: D30
type_infered: string
name: disassemble_data
arguments: label: D42
type_infered: string
name: disassemble_data
arguments: label: D31
type_infered: string
name: disassemble_data
arguments: label: D12
type_infered: string

tool: D10: Bem-vindo ao Jogo da Velha:


tool: D30: O jogador comeca!!! 
Escolha se quer ser 'X' ou 'O'
Pronto p/comecar...

tool: D42: Aperte ENTER p/ iniciar...

tool: D31: %c

tool: D12: cls

assistant: ```c
void Apresentacao(void) {
  char enter;
  printf("Bem-vindo ao Jogo da Velha:\n");
  printf("O jogador comeca!!! \nEscolha se quer ser 'X' ou 'O'\nPronto p/comecar...");
  printf("Aperte ENTER p/ iniciar...");
  scanf("%c", &enter);
  if (enter == '\n') {
    system("cls");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Apresentacao>:
  endbr64
  sub    $0x18,%rsp
  lea    D22(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0xa,0x7(%rsp)
  je     L13
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L13:
  lea    D37(%rip),%rdi
  call   <system@plt>
  jmp    L27
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D22
datatype: string
name: unpack_data
arguments: data_label: D39
datatype: string
name: unpack_data
arguments: data_label: D28
datatype: string
name: unpack_data
arguments: data_label: D44
datatype: string
name: unpack_data
arguments: data_label: D37
datatype: string

tool: D22: Bem-vindo ao Jogo da Velha:


tool: D39: O jogador comeca!!! 
Escolha se quer ser 'X' ou 'O'
Pronto p/comecar...

tool: D28: Aperte ENTER p/ iniciar...

tool: D44: %c

tool: D37: cls

assistant: ```c
void Apresentacao(void) {
  char enter;
  printf("Bem-vindo ao Jogo da Velha:\n");
  printf("O jogador comeca!!! \nEscolha se quer ser 'X' ou 'O'\nPronto p/comecar...");
  printf("Aperte ENTER p/ iniciar...");
  scanf("%c", &enter);
  if (enter == '\n') {
    system("cls");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<filelist_dir_name_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x228(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x214(%rbp)
  cmpl   $0x2,-0x214(%rbp)
  jle    L25
  mov    -0x214(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  je     L25
  mov    -0x214(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L25
  mov    -0x228(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x214(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movb   $0x0,-0x210(%rbp,%rax,1)
  mov    -0x230(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wfile_wild_match@plt>
  jmp    L9
L25:
  mov    -0x230(%rbp),%rdx
  mov    -0x228(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wfile_wild_match@plt>
  test   %eax,%eax
  jne    L69
  mov    $0x0,%eax
  jmp    L9
L69:
  mov    -0x214(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x228(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  sete   %al
  movzbl %al,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

assistant: ```c
int filelist_dir_name_match(char *pattern, char *dirname) {
  int len;
  len = strlen(pattern);
  if (len > 2 && wfile_eitherslash(pattern[len - 2]) && pattern[len - 1] == '*') {
    char tname[512];
    strcpy(tname, pattern);
    tname[len - 2] = '\0';
    return (wfile_wild_match(tname, dirname));
  }
  if (!wfile_wild_match(pattern, dirname))
    return (0);
  return (pattern[len - 1] == '*');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filelist_dir_name_match>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    $0x2,%eax
  jle    L44
  movslq %eax,%r13
  movsbl -0x2(%rbp,%r13,1),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  je     L44
  cmpb   $0x2a,-0x1(%rbp,%r13,1)
  je     L15
L44:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wfile_wild_match@plt>
  test   %eax,%eax
  je     L13
  movslq %ebx,%rbx
  cmpb   $0x2a,-0x1(%rbp,%rbx,1)
  sete   %al
  movzbl %al,%eax
L13:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %rsp,%r13
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  sub    $0x2,%ebx
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <wfile_wild_match@plt>
  jmp    L13
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelist_dir_name_match(char *pattern, char *dirname) {
  int len;
  len = strlen(pattern);
  if (len > 2 && wfile_eitherslash(pattern[len - 2]) && pattern[len - 1] == '*') {
    char tname[512];
    strcpy(tname, pattern);
    tname[len - 2] = '\0';
    return (wfile_wild_match(tname, dirname));
  }
  if (!wfile_wild_match(pattern, dirname))
    return (0);
  return (pattern[len - 1] == '*');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<filelist_dir_name_match>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movslq %eax,%rbx
  cmp    $0x2,%ebx
  jle    L43
  movslq %ebx,%r13
  movsbl -0x2(%rbp,%r13,1),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  jne    L44
L43:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wfile_wild_match@plt>
  test   %eax,%eax
  je     L23
  xor    %eax,%eax
  cmpb   $0x2a,-0x1(%rbp,%rbx,1)
  sete   %al
L23:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L44:
  cmpb   $0x2a,-0x1(%rbp,%r13,1)
  jne    L43
  mov    %rsp,%r13
  mov    %rbp,%rsi
  sub    $0x2,%ebx
  mov    %r13,%rdi
  movslq %ebx,%rbx
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <wfile_wild_match@plt>
  jmp    L23
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelist_dir_name_match(char *pattern, char *dirname) {
  int len;
  len = strlen(pattern);
  if (len > 2 && wfile_eitherslash(pattern[len - 2]) && pattern[len - 1] == '*') {
    char tname[512];
    strcpy(tname, pattern);
    tname[len - 2] = '\0';
    return (wfile_wild_match(tname, dirname));
  }
  if (!wfile_wild_match(pattern, dirname))
    return (0);
  return (pattern[len - 1] == '*');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filelist_dir_name_match>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movslq %eax,%rbx
  cmp    $0x2,%ebx
  jle    L23
  movslq %ebx,%r13
  movsbl -0x2(%rbp,%r13,1),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  jne    L57
L23:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wfile_wild_match@plt>
  test   %eax,%eax
  je     L49
  xor    %eax,%eax
  cmpb   $0x2a,-0x1(%rbp,%rbx,1)
  sete   %al
L49:
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L57:
  cmpb   $0x2a,-0x1(%rbp,%r13,1)
  jne    L23
  mov    %rsp,%r13
  mov    %rbp,%rsi
  sub    $0x2,%ebx
  mov    %r13,%rdi
  movslq %ebx,%rbx
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <wfile_wild_match@plt>
  jmp    L49
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filelist_dir_name_match(char *pattern, char *dirname) {
  int len;
  len = strlen(pattern);
  if (len > 2 && wfile_eitherslash(pattern[len - 2]) && pattern[len - 1] == '*') {
    char tname[512];
    strcpy(tname, pattern);
    tname[len - 2] = '\0';
    return (wfile_wild_match(tname, dirname));
  }
  if (!wfile_wild_match(pattern, dirname))
    return (0);
  return (pattern[len - 1] == '*');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<addOperators0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  jmp    L26
L14:
  mov    -0x20(%rbp),%eax
  cltq
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x28(%rbp),%rax
  push   -0x38(%rbp)
  lea    -0x18(%rbp),%rcx
  push   %rcx
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  push   -0x10(%rbp)
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <helper0@plt>
  add    $0x20,%rsp
  mov    -0x18(%rbp),%rax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
char **addOperators0(char *num, int target, int *returnSize) {
  char **arr = (char **)malloc(sizeof(char *));
  *returnSize = 0;
  int len = strlen(num);
  if (len == 0)
    return arr;
  char *stack = (char *)malloc(sizeof(char) * 2 * len);
  int top = -1;
  helper0(num, len, 0, target, 0, 0, stack, top, &arr, returnSize);
  return arr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<addOperators0>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rsp)
  movl   $0x0,(%r12)
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L25
  mov    (%rsp),%rax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  mov    %eax,%ebx
  lea    (%rax,%rax,1),%edi
  call   <malloc@plt>
  push   %r12
  lea    0x8(%rsp),%rdx
  push   %rdx
  push   $0xffffffffffffffff
  push   %rax
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %r13d,%ecx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <helper0@plt>
  mov    0x20(%rsp),%rax
  add    $0x20,%rsp
  jmp    L11
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **addOperators0(char *num, int target, int *returnSize) {
  char **arr = (char **)malloc(sizeof(char *));
  *returnSize = 0;
  int len = strlen(num);
  if (len == 0)
    return arr;
  char *stack = (char *)malloc(sizeof(char) * 2 * len);
  int top = -1;
  helper0(num, len, 0, target, 0, 0, stack, top, &arr, returnSize);
  return arr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addOperators0>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    $0x8,%edi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movl   $0x0,(%rbx)
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  call   <strlen@plt>
  test   %eax,%eax
  jne    L15
  mov    (%rsp),%rax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  lea    (%rax,%rax,1),%edi
  mov    %eax,%ebp
  call   <malloc@plt>
  push   %rbx
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    %r13d,%ecx
  mov    %ebp,%esi
  mov    %r12,%rdi
  lea    0x8(%rsp),%rdx
  push   %rdx
  xor    %edx,%edx
  push   $0xffffffffffffffff
  push   %rax
  call   <helper0@plt>
  mov    0x20(%rsp),%rax
  add    $0x20,%rsp
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char **addOperators0(char *num, int target, int *returnSize) {
  char **arr = (char **)malloc(sizeof(char *));
  *returnSize = 0;
  int len = strlen(num);
  if (len == 0)
    return arr;
  char *stack = (char *)malloc(sizeof(char) * 2 * len);
  int top = -1;
  helper0(num, len, 0, target, 0, 0, stack, top, &arr, returnSize);
  return arr;
}
```