ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  jne    L38
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D21(%rip),%rdi
  call   <printf@plt>
L32:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  mov    %eax,%ebx
  call   <fork@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L10:
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    %ebx,%edi
  call   <waitpid@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    %ebp,%edi
  call   <waitpid@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L32
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string

tool: D21: Soy el primer hijo (%d, hijo de %d)


tool: D10: Soy el segundo hijo (%d, hijo de %d)


tool: D5: Soy el padre (%d, hijo de %d)


assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid1, pid2;
  int status1, status2;
  if ((pid1 = fork()) == 0)
    printf("Soy el primer hijo (%d, hijo de %d)\n", getpid(), getppid());
  else {
    if ((pid2 = fork()) == 0) {
      printf("Soy el segundo hijo (%d, hijo de %d)\n", getpid(), getppid());
    } else {
      waitpid(pid1, &status1, 0);
      waitpid(pid2, &status2, 0);
      printf("Soy el padre (%d, hijo de %d)\n", getpid(), getppid());
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  jne    L23
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    %eax,%ebp
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L40
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L45
L40:
  mov    %rsp,%rsi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <waitpid@plt>
  lea    0x4(%rsp),%rsi
  xor    %edx,%edx
  mov    %r12d,%edi
  call   <waitpid@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L45
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D2
type: string

tool: D3: Soy el primer hijo (%d, hijo de %d)


tool: D9: Soy el segundo hijo (%d, hijo de %d)


tool: D2: Soy el padre (%d, hijo de %d)


assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid1, pid2;
  int status1, status2;
  if ((pid1 = fork()) == 0)
    printf("Soy el primer hijo (%d, hijo de %d)\n", getpid(), getppid());
  else {
    if ((pid2 = fork()) == 0) {
      printf("Soy el segundo hijo (%d, hijo de %d)\n", getpid(), getppid());
    } else {
      waitpid(pid1, &status1, 0);
      waitpid(pid2, &status2, 0);
      printf("Soy el padre (%d, hijo de %d)\n", getpid(), getppid());
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fork@plt>
  test   %eax,%eax
  jne    L17
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %eax,%ebp
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L40
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L48
L40:
  mov    %rsp,%rsi
  xor    %edx,%edx
  mov    %ebp,%edi
  call   <waitpid@plt>
  lea    0x4(%rsp),%rsi
  xor    %edx,%edx
  mov    %r12d,%edi
  call   <waitpid@plt>
  xor    %eax,%eax
  call   <getppid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L48
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D16: Soy el primer hijo (%d, hijo de %d)


tool: D9: Soy el segundo hijo (%d, hijo de %d)


tool: D3: Soy el padre (%d, hijo de %d)


assistant: ```c
int main(int argc, char *argv[]) {
  pid_t pid1, pid2;
  int status1, status2;
  if ((pid1 = fork()) == 0)
    printf("Soy el primer hijo (%d, hijo de %d)\n", getpid(), getppid());
  else {
    if ((pid2 = fork()) == 0) {
      printf("Soy el segundo hijo (%d, hijo de %d)\n", getpid(), getppid());
    } else {
      waitpid(pid1, &status1, 0);
      waitpid(pid2, &status2, 0);
      printf("Soy el padre (%d, hijo de %d)\n", getpid(), getppid());
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bmw_large_s0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <shiftr64@plt>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <shiftl64@plt>
  xor    %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <rotl64@plt>
  xor    %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    $0x1b,%esi
  mov    %eax,%edi
  call   <rotr64@plt>
  xor    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint64_t bmw_large_s0(uint64_t x) {
  uint64_t r;
  r = shiftr64(x, 1) ^ shiftl64(x, 3) ^ rotl64(x, 4) ^ rotr64(x, 64 - 37);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bmw_large_s0>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1,%esi
  call   <shiftr64@plt>
  mov    %eax,%ebx
  mov    $0x3,%esi
  mov    %ebp,%edi
  call   <shiftl64@plt>
  xor    %eax,%ebx
  mov    $0x4,%esi
  mov    %ebp,%edi
  call   <rotl64@plt>
  xor    %eax,%ebx
  mov    $0x1b,%esi
  mov    %ebp,%edi
  call   <rotr64@plt>
  xor    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t bmw_large_s0(uint64_t x) {
  uint64_t r;
  r = shiftr64(x, 1) ^ shiftl64(x, 3) ^ rotl64(x, 4) ^ rotr64(x, 64 - 37);
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bmw_large_s0>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <shiftr64@plt>
  mov    %ebp,%edi
  mov    $0x3,%esi
  mov    %eax,%ebx
  call   <shiftl64@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  xor    %eax,%ebx
  call   <rotl64@plt>
  mov    %ebp,%edi
  mov    $0x1b,%esi
  xor    %eax,%ebx
  call   <rotr64@plt>
  add    $0x8,%rsp
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t bmw_large_s0(uint64_t x) {
  uint64_t r;
  r = shiftr64(x, 1) ^ shiftl64(x, 3) ^ rotl64(x, 4) ^ rotr64(x, 64 - 37);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bmw_large_s0>:
  endbr64
  push   %rbp
  mov    $0x1,%esi
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <shiftr64@plt>
  mov    %ebp,%edi
  mov    $0x3,%esi
  mov    %eax,%ebx
  call   <shiftl64@plt>
  mov    %ebp,%edi
  mov    $0x4,%esi
  xor    %eax,%ebx
  call   <rotl64@plt>
  mov    %ebp,%edi
  mov    $0x1b,%esi
  xor    %eax,%ebx
  call   <rotr64@plt>
  add    $0x8,%rsp
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t bmw_large_s0(uint64_t x) {
  uint64_t r;
  r = shiftr64(x, 1) ^ shiftl64(x, 3) ^ rotl64(x, 4) ^ rotr64(x, 64 - 37);
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<work>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L13:
  mov    $0x0,%eax
  call   <a@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x2,-0x4(%rbp)
  jle    L13
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *work(void *arg) {
  for (int i = 0; i <= 2; i++) {
    a();
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<work>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *work(void *arg) {
  for (int i = 0; i <= 2; i++) {
    a();
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<work>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *work(void *arg) {
  for (int i = 0; i <= 2; i++) {
    a();
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<work>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *work(void *arg) {
  for (int i = 0; i <= 2; i++) {
    a();
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getSection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getSection(int i) {
  int ret = ((i - 1) / 1000) + 1;
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getSection>:
  endbr64
  sub    $0x1,%edi
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int getSection(int i) {
  int ret = ((i - 1) / 1000) + 1;
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getSection>:
  endbr64
  sub    $0x1,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edi,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int getSection(int i) {
  int ret = ((i - 1) / 1000) + 1;
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getSection>:
  endbr64
  sub    $0x1,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edi,%eax
  add    $0x1,%eax
  ret
```

assistant: ```c
int getSection(int i) {
  int ret = ((i - 1) / 1000) + 1;
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  mov    $0x0,%eax
  call   <simple_timer@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  simple_timer();
  cleanup_screen();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <setup_screen@plt>
  mov    $0x0,%eax
  call   <simple_timer@plt>
  mov    $0x0,%eax
  call   <cleanup_screen@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  simple_timer();
  cleanup_screen();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  xor    %eax,%eax
  call   <simple_timer@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  simple_timer();
  cleanup_screen();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <setup_screen@plt>
  xor    %eax,%eax
  call   <simple_timer@plt>
  xor    %eax,%eax
  call   <cleanup_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  setup_screen();
  simple_timer();
  cleanup_screen();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exppdf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L12
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L12:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L7
  pxor   %xmm0,%xmm0
  jmp    L20
L7:
  movsd  -0x10(%rbp),%xmm0
  movq   D3(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x10(%rbp),%xmm0
L20:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D3
type: f32[2]

tool: D16: Parameter lambda is smaller than 0.

tool: {"D3": [0.0,-0.0]}

assistant: ```c
double exppdf(double x, double lambda) {
  if (lambda < 0)
    error("Parameter lambda is smaller than 0.");
  if (x < 0)
    return 0.0;
  return lambda * exp(-lambda * x);
}
```
user: What is the c source code of the assembly code below:

```asm
<exppdf>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L2
L26:
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm3
  comisd %xmm3,%xmm0
  ja     L23
  movsd  (%rsp),%xmm0
  xorpd  D3(%rip),%xmm0
  mulsd  %xmm3,%xmm0
  call   <exp@plt>
  mulsd  (%rsp),%xmm0
L23:
  add    $0x18,%rsp
  ret
L2:
  lea    D15(%rip),%rdi
  call   <error@plt>
  jmp    L26
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: f32[4]
name: parse_data
arguments: tag: D15
type_guessed: string

tool: {"D3": [0.0,-0.0,0.0,0.0]}

tool: D15: Parameter lambda is smaller than 0.

assistant: ```c
double exppdf(double x, double lambda) {
  if (lambda < 0)
    error("Parameter lambda is smaller than 0.");
  if (x < 0)
    return 0.0;
  return lambda * exp(-lambda * x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<exppdf>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  ja     L27
L25:
  comisd %xmm2,%xmm0
  ja     L10
  movapd %xmm1,%xmm0
  xorpd  D15(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  mulsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm0
L10:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L27:
  lea    D2(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <error@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: f32[4]
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: {"D15": [0.0,-0.0,0.0,0.0]}

tool: D2: Parameter lambda is smaller than 0.

assistant: ```c
double exppdf(double x, double lambda) {
  if (lambda < 0)
    error("Parameter lambda is smaller than 0.");
  if (x < 0)
    return 0.0;
  return lambda * exp(-lambda * x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exppdf>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  ja     L19
L25:
  comisd %xmm2,%xmm0
  ja     L26
  movapd %xmm1,%xmm0
  xorpd  D6(%rip),%xmm0
  movsd  %xmm1,(%rsp)
  mulsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm0
L26:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L19:
  lea    D19(%rip),%rdi
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <error@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  jmp    L25
```

tool_calls: name: read_data
arguments: label: D6
datatype: f32[4]
name: read_data
arguments: label: D19
datatype: string

tool: {"D6": [0.0,-0.0,0.0,0.0]}

tool: D19: Parameter lambda is smaller than 0.

assistant: ```c
double exppdf(double x, double lambda) {
  if (lambda < 0)
    error("Parameter lambda is smaller than 0.");
  if (x < 0)
    return 0.0;
  return lambda * exp(-lambda * x);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdi
  lea    -0x1c(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x1c(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm3
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  -0x18(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x20(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  subss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0xc(%rbp),%xmm0
  jb     L0
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L40
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jne    L40
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L40:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L0:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D25
type: string
name: extract_symbolic_data
arguments: data_tag: D24
type: string

tool: D16: %f%f%f%f%f

tool: D9: Point is on the Circle.

tool: D25: Point is inside the Circle.

tool: D24: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1, a, b, c;
  scanf("%f%f%f%f%f", &x, &y, &r, &x1, &y1);
  a = (((x1 - x) * (x1 - x)) + ((y1 - y) * (y1 - y)));
  b = r * r;
  c = a - b;
  if (c <= 0) {
    if (c == 0) {
      printf("Point is on the Circle.");
    } else {
      printf("Point is inside the Circle.");
    }
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  subss  0x4(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  subss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  mulss  %xmm2,%xmm2
  subss  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  jb     L26
  ucomiss %xmm1,%xmm0
  jp     L19
  jne    L19
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L19:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L26:
  lea    D14(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D3
type_infered: string
name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D10: %f%f%f%f%f

tool: D3: Point is on the Circle.

tool: D25: Point is inside the Circle.

tool: D14: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1, a, b, c;
  scanf("%f%f%f%f%f", &x, &y, &r, &x1, &y1);
  a = (((x1 - x) * (x1 - x)) + ((y1 - y) * (y1 - y)));
  b = r * r;
  c = a - b;
  if (c <= 0) {
    if (c == 0) {
      printf("Point is on the Circle.");
    } else {
      printf("Point is inside the Circle.");
    }
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D27(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x14(%rsp),%r9
  lea    0x10(%rsp),%r8
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  subss  0x4(%rsp),%xmm0
  subss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  mulss  %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  subss  %xmm2,%xmm0
  comiss %xmm0,%xmm1
  jb     L33
  ucomiss %xmm1,%xmm0
  jp     L48
  jne    L48
  lea    D34(%rip),%rdi
  call   <printf@plt>
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L48:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L33:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D12
data_type: string

tool: D27: %f%f%f%f%f

tool: D34: Point is on the Circle.

tool: D26: Point is inside the Circle.

tool: D12: Point is outside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1, a, b, c;
  scanf("%f%f%f%f%f", &x, &y, &r, &x1, &y1);
  a = (((x1 - x) * (x1 - x)) + ((y1 - y) * (y1 - y)));
  b = r * r;
  c = a - b;
  if (c <= 0) {
    if (c == 0) {
      printf("Point is on the Circle.");
    } else {
      printf("Point is inside the Circle.");
    }
  } else {
    printf("Point is outside the Circle.");
  }
  return 0;
}
```