ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<isotropicBuildF32>:
  endbr64
  mov    (%rcx),%r11d
  mov    0x4(%rcx),%eax
  mov    %rdx,%r8
  test   %r11d,%r11d
  jle    L76
  test   %eax,%eax
  jle    L76
  mov    %eax,%r9d
  movslq %eax,%r10
  movss  D2(%rip),%xmm3
  xor    %ecx,%ecx
  lea    0x0(,%r9,4),%rdx
  neg    %r9
  shl    $0x2,%r10
  pxor   %xmm2,%xmm2
  shl    $0x2,%r9
  nopl   (%rax)
L98:
  lea    (%r9,%rdx,1),%rax
  jmp    L99
  xchg   %ax,%ax
L2:
  addss  %xmm1,%xmm0
  mulss  %xmm3,%xmm0
L95:
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  je     L0
L99:
  movss  (%rsi,%rax,1),%xmm1
  movss  (%rdi,%rax,1),%xmm0
  ucomiss %xmm2,%xmm1
  jp     L24
  je     L95
L24:
  ucomiss %xmm2,%xmm0
  jp     L2
  jne    L2
  movaps %xmm1,%xmm0
  movss  %xmm0,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L99
L0:
  add    $0x1,%ecx
  add    %r10,%rdx
  cmp    %ecx,%r11d
  jne    L98
L76:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void isotropicBuildF32(float *data1, float *data2, float *newdata, int *dims) {
  int i, j, index;
  int ydim = dims[0];
  int xdim = dims[1];
  for (j = 0; j < ydim; j++)
    for (i = 0; i < xdim; i++) {
      index = (j * xdim) + (i);
      if (data2[index] == 0.0)
        newdata[index] = data1[index];
      else if (data1[index] == 0.0)
        newdata[index] = data2[index];
      else
        newdata[index] = (data1[index] + data2[index]) / 2;
    }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L35
L31:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  jmp    L42
L18:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L42:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_ltrim(char *dest, const char *src) {
  size_t n = 0;
  while (src[n] != '\0' && isspace((unsigned char)src[n])) {
    ++n;
  }
  while (src[n] != '\0') {
    *dest = src[n];
    ++dest;
    ++n;
  }
  *dest = '\0';
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_ltrim>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  movzbl (%rsi),%edi
  mov    $0x0,%ebp
  test   %dil,%dil
  je     L46
L5:
  movzbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L9
  add    $0x1,%rbp
  movzbl (%r12,%rbp,1),%edi
  test   %dil,%dil
  jne    L5
L46:
  mov    %rbx,%rax
  jmp    L53
L9:
  movzbl (%r12,%rbp,1),%edx
  test   %dl,%dl
  je     L32
  lea    0x1(%r12,%rbp,1),%rcx
  mov    %rbx,%rax
L21:
  mov    %dl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L21
L53:
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    %rbx,%rax
  jmp    L53
```

assistant: ```c
char *str_ltrim(char *dest, const char *src) {
  size_t n = 0;
  while (src[n] != '\0' && isspace((unsigned char)src[n])) {
    ++n;
  }
  while (src[n] != '\0') {
    *dest = src[n];
    ++dest;
    ++n;
  }
  *dest = '\0';
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_ltrim>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rsi),%edi
  test   %dil,%dil
  jne    L27
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rbp
  movzbl (%r12,%rbp,1),%edi
  test   %dil,%dil
  je     L13
L27:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
  movzbl (%r12,%rbp,1),%edx
  test   %dl,%dl
  je     L13
  lea    0x1(%r12,%rbp,1),%rcx
  mov    %rbx,%rax
  nopl   0x0(%rax)
L15:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L15
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbx,%rax
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_ltrim(char *dest, const char *src) {
  size_t n = 0;
  while (src[n] != '\0' && isspace((unsigned char)src[n])) {
    ++n;
  }
  while (src[n] != '\0') {
    *dest = src[n];
    ++dest;
    ++n;
  }
  *dest = '\0';
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_ltrim>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rsi),%edi
  test   %dil,%dil
  jne    L57
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbp
  movzbl (%r12,%rbp,1),%edi
  test   %dil,%dil
  je     L4
L57:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L1
  movzbl (%r12,%rbp,1),%edx
  test   %dl,%dl
  je     L4
  lea    0x1(%r12,%rbp,1),%rcx
  mov    %rbx,%rax
  nopl   0x0(%rax)
L32:
  add    $0x1,%rcx
  mov    %dl,(%rax)
  add    $0x1,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L32
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rax
  movb   $0x0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_ltrim(char *dest, const char *src) {
  size_t n = 0;
  while (src[n] != '\0' && isspace((unsigned char)src[n])) {
    ++n;
  }
  while (src[n] != '\0') {
    *dest = src[n];
    ++dest;
    ++n;
  }
  *dest = '\0';
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1ac(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1a4(%rbp)
  jmp    L8
L63:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1a4(%rbp)
L8:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L63
  movl   $0x0,-0x1a4(%rbp)
  jmp    L39
L60:
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <count_digits@plt>
  and    $0x1,%eax
  test   %eax,%eax
  jne    L18
  addl   $0x1,-0x1ac(%rbp)
  jmp    L55
L18:
  addl   $0x1,-0x1a8(%rbp)
L55:
  addl   $0x1,-0x1a4(%rbp)
L39:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a4(%rbp)
  jl     L60
  mov    -0x1ac(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1a8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D7
datatype: string

tool: D10: %d

tool: D2: Even digits numbers count: %d


tool: D7: Odd digits numbers count: %d


assistant: ```c
int main() {
  int evenNum = 0, oddNum = 0, i, n, a[100];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    if ((count_digits(a[i])) % 2 == 0)
      evenNum++;
    else
      oddNum++;
  }
  printf("Even digits numbers count: %d\n", evenNum);
  printf("Odd digits numbers count: %d\n", oddNum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L74
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D32(%rip),%r12
L59:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L59
  test   %eax,%eax
  jle    L29
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L4
L22:
  add    $0x1,%ebp
L5:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L10
L4:
  mov    0x10(%rsp,%rbx,4),%edi
  call   <count_digits@plt>
  test   $0x1,%al
  jne    L22
  add    $0x1,%r12d
  jmp    L5
L74:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L10:
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L10
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D32
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D32: %d

tool: D7: Even digits numbers count: %d


tool: D23: Odd digits numbers count: %d


assistant: ```c
int main() {
  int evenNum = 0, oddNum = 0, i, n, a[100];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    if ((count_digits(a[i])) % 2 == 0)
      evenNum++;
    else
      oddNum++;
  }
  printf("Even digits numbers count: %d\n", evenNum);
  printf("Odd digits numbers count: %d\n", oddNum);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    %r12,%rbp
  test   %eax,%eax
  jle    L71
  xchg   %ax,%ax
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L15
  test   %eax,%eax
  jle    L71
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r13d
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L54
L27:
  mov    (%r12,%rbx,4),%edi
  call   <count_digits@plt>
  test   $0x1,%al
  je     L35
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L27
L54:
  mov    %r13d,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  jmp    L54
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D19
type: string

tool: D13: %d

tool: D26: Even digits numbers count: %d


tool: D19: Odd digits numbers count: %d


assistant: ```c
int main() {
  int evenNum = 0, oddNum = 0, i, n, a[100];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    if ((count_digits(a[i])) % 2 == 0)
      evenNum++;
    else
      oddNum++;
  }
  printf("Even digits numbers count: %d\n", evenNum);
  printf("Odd digits numbers count: %d\n", oddNum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    %r12,%rbp
  test   %eax,%eax
  jle    L46
  xchg   %ax,%ax
L44:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L44
  test   %eax,%eax
  jle    L46
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r13d
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L63
L23:
  mov    (%r12,%rbx,4),%edi
  call   <count_digits@plt>
  test   $0x1,%al
  je     L18
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L23
L63:
  mov    %r13d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x1b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  jmp    L63
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D24
datatype: string

tool: D21: %d

tool: D5: Even digits numbers count: %d


tool: D24: Odd digits numbers count: %d


assistant: ```c
int main() {
  int evenNum = 0, oddNum = 0, i, n, a[100];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    if ((count_digits(a[i])) % 2 == 0)
      evenNum++;
    else
      oddNum++;
  }
  printf("Even digits numbers count: %d\n", evenNum);
  printf("Odd digits numbers count: %d\n", oddNum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x14(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L31
  movl   $0x1,-0x18(%rbp)
L31:
  cmpl   $0x0,-0x18(%rbp)
  je     L39
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L39:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D19
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D12
datatype: string

tool: D14: Enter the 10 digit Coupon Number:


tool: D19: 9876543210

tool: D3: Congrats, You have won a jackpot.


tool: D12: You are not the lucky winner. Better luck next time


assistant: ```c
int main(void) {
  char coupon_number[12];
  int jackpot_won = 0;
  printf("Enter the 10 digit Coupon Number:\n");
  gets(coupon_number);
  if (strcmp(coupon_number, "9876543210") == 0) {
    jackpot_won = 1;
  }
  if (jackpot_won) {
    printf("Congrats, You have won a jackpot.\n");
  } else {
    printf("You are not the lucky winner. Better luck next time\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  lea    D2(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D21
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D28
type_infered: string

tool: D9: Enter the 10 digit Coupon Number:


tool: D21: 9876543210

tool: D2: You are not the lucky winner. Better luck next time


tool: D28: Congrats, You have won a jackpot.


assistant: ```c
int main(void) {
  char coupon_number[12];
  int jackpot_won = 0;
  printf("Enter the 10 digit Coupon Number:\n");
  gets(coupon_number);
  if (strcmp(coupon_number, "9876543210") == 0) {
    jackpot_won = 1;
  }
  if (jackpot_won) {
    printf("Congrats, You have won a jackpot.\n");
  } else {
    printf("You are not the lucky winner. Better luck next time\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L12
  lea    D30(%rip),%rdi
  call   <printf@plt>
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L12:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L25
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
data_type: string
name: retrieve_data
arguments: tag: D4
data_type: string
name: retrieve_data
arguments: tag: D30
data_type: string
name: retrieve_data
arguments: tag: D26
data_type: string

tool: D20: Enter the 10 digit Coupon Number:


tool: D4: 9876543210

tool: D30: You are not the lucky winner. Better luck next time


tool: D26: Congrats, You have won a jackpot.


assistant: ```c
int main(void) {
  char coupon_number[12];
  int jackpot_won = 0;
  printf("Enter the 10 digit Coupon Number:\n");
  gets(coupon_number);
  if (strcmp(coupon_number, "9876543210") == 0) {
    jackpot_won = 1;
  }
  if (jackpot_won) {
    printf("Congrats, You have won a jackpot.\n");
  } else {
    printf("You are not the lucky winner. Better luck next time\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L23
  lea    D3(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
data_type: string
name: retrieve_data
arguments: tag: D26
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D9
data_type: string

tool: D27: Enter the 10 digit Coupon Number:


tool: D26: 9876543210

tool: D3: You are not the lucky winner. Better luck next time


tool: D9: Congrats, You have won a jackpot.


assistant: ```c
int main(void) {
  char coupon_number[12];
  int jackpot_won = 0;
  printf("Enter the 10 digit Coupon Number:\n");
  gets(coupon_number);
  if (strcmp(coupon_number, "9876543210") == 0) {
    jackpot_won = 1;
  }
  if (jackpot_won) {
    printf("Congrats, You have won a jackpot.\n");
  } else {
    printf("You are not the lucky winner. Better luck next time\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ireverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L13
L29:
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
L13:
  cmpl   $0x0,-0x34(%rbp)
  jne    L29
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int ireverse(int value) {
  char str[12] = {'\0'};
  char *ptr = str;
  int tmp;
  while (value) {
    tmp = value % 10;
    *ptr++ = tmp + '0';
    value /= 10;
  }
  return atoi(str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ireverse>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  test   %edi,%edi
  je     L27
  lea    0xc(%rsp),%rcx
L14:
  add    $0x1,%rcx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rcx)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L14
L27:
  lea    0xc(%rsp),%rdi
  call   <atoi@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ireverse(int value) {
  char str[12] = {'\0'};
  char *ptr = str;
  int tmp;
  while (value) {
    tmp = value % 10;
    *ptr++ = tmp + '0';
    value /= 10;
  }
  return atoi(str);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ireverse>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r8
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    %r8,%rcx
  test   %edi,%edi
  je     L2
  nopl   (%rax)
L13:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%rcx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rcx)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L13
L2:
  mov    %r8,%rdi
  call   <atoi@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ireverse(int value) {
  char str[12] = {'\0'};
  char *ptr = str;
  int tmp;
  while (value) {
    tmp = value % 10;
    *ptr++ = tmp + '0';
    value /= 10;
  }
  return atoi(str);
}
```