ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<perform_call>:
  endbr64
  cmp    $0xffffffff,%esi
  jne    L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D8(%rip),%rdi
  jmp    1050 <native_error@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: Wrong number of generated inputs for {TEST_OBJECT_NAME}

assistant: ```c
void perform_call(double *args, int num_args) {
  const int NUM_ARGS = -1;
  if (num_args != NUM_ARGS) {
    native_error("Wrong number of generated inputs for {TEST_OBJECT_NAME}");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<perform_call>:
  endbr64
  cmp    $0xffffffff,%esi
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D4(%rip),%rdi
  jmp    1050 <native_error@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: Wrong number of generated inputs for {TEST_OBJECT_NAME}

assistant: ```c
void perform_call(double *args, int num_args) {
  const int NUM_ARGS = -1;
  if (num_args != NUM_ARGS) {
    native_error("Wrong number of generated inputs for {TEST_OBJECT_NAME}");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<removeArgFromArgv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L4:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jb     L4
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeArgFromArgv(size_t index, int *argc, char **argv) {
  size_t i;
  for (i = index; i < *argc - 1; i++) {
    argv[i] = argv[i + 1];
  }
  argv[--(*argc)] = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeArgFromArgv>:
  endbr64
  mov    (%rsi),%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  cmp    %rcx,%rdi
  jae    L17
L11:
  add    $0x1,%rdi
  mov    (%rdx,%rdi,8),%rax
  mov    %rax,-0x8(%rdx,%rdi,8)
  mov    (%rsi),%eax
  sub    $0x1,%eax
  movslq %eax,%rcx
  cmp    %rcx,%rdi
  jb     L11
L17:
  mov    %eax,(%rsi)
  movq   $0x0,(%rdx,%rcx,8)
  ret
```

assistant: ```c
void removeArgFromArgv(size_t index, int *argc, char **argv) {
  size_t i;
  for (i = index; i < *argc - 1; i++) {
    argv[i] = argv[i + 1];
  }
  argv[--(*argc)] = NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<removeArgFromArgv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  lea    -0x1(%rax),%r12d
  movslq %r12d,%r13
  cmp    %r13,%rdi
  jae    L1
  mov    %r13,%rdx
  lea    0x0(,%rdi,8),%rax
  sub    %rdi,%rdx
  lea    0x8(%rbx,%rax,1),%rsi
  lea    (%rbx,%rax,1),%rdi
  shl    $0x3,%rdx
  call   <memmove@plt>
L1:
  mov    %r12d,0x0(%rbp)
  movq   $0x0,(%rbx,%r13,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void removeArgFromArgv(size_t index, int *argc, char **argv) {
  size_t i;
  for (i = index; i < *argc - 1; i++) {
    argv[i] = argv[i + 1];
  }
  argv[--(*argc)] = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<removeArgFromArgv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  lea    -0x1(%rax),%r12d
  movslq %r12d,%r13
  cmp    %r13,%rdi
  jae    L2
  mov    %r13,%rdx
  lea    0x0(,%rdi,8),%rax
  sub    %rdi,%rdx
  lea    0x8(%rbx,%rax,1),%rsi
  lea    (%rbx,%rax,1),%rdi
  shl    $0x3,%rdx
  call   <memmove@plt>
L2:
  mov    %r12d,0x0(%rbp)
  movq   $0x0,(%rbx,%r13,8)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void removeArgFromArgv(size_t index, int *argc, char **argv) {
  size_t i;
  for (i = index; i < *argc - 1; i++) {
    argv[i] = argv[i + 1];
  }
  argv[--(*argc)] = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<index_of_nearest_point>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltd
  idivl  -0x30(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x34(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_distance@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  je     L18
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x34(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_distance@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L41
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L41
L18:
  nop
L41:
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L2
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int index_of_nearest_point(const double *const *data, int I, int t, int n) {
  int J = (I + 1) % t;
  double minimum = get_distance(data[I], data[J], n);
  for (int i = 0; i < t; i++) {
    if (i == I)
      continue;
    double distance = get_distance(data[I], data[i], n);
    if (distance < minimum) {
      minimum = distance;
      J = i;
    }
  }
  return J;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<index_of_nearest_point>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %ecx,0xc(%rsp)
  lea    0x1(%rsi),%eax
  cltd
  idiv   %ebp
  mov    %edx,%r13d
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%r15
  movslq %edx,%rdx
  mov    (%rdi,%rdx,8),%rsi
  mov    %ecx,%edx
  mov    (%r15),%rdi
  call   <get_distance@plt>
  movsd  %xmm0,(%rsp)
  test   %ebp,%ebp
  jle    L23
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  jmp    L34
L10:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L23
L34:
  mov    %ebx,0x8(%rsp)
  cmp    %ebx,%r12d
  je     L10
  mov    (%r14,%rbx,8),%rsi
  mov    0xc(%rsp),%edx
  mov    (%r15),%rdi
  call   <get_distance@plt>
  movsd  (%rsp),%xmm1
  comisd %xmm0,%xmm1
  minsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsp)
  cmova  0x8(%rsp),%r13d
  jmp    L10
L23:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int index_of_nearest_point(const double *const *data, int I, int t, int n) {
  int J = (I + 1) % t;
  double minimum = get_distance(data[I], data[J], n);
  for (int i = 0; i < t; i++) {
    if (i == I)
      continue;
    double distance = get_distance(data[I], data[i], n);
    if (distance < minimum) {
      minimum = distance;
      J = i;
    }
  }
  return J;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<index_of_nearest_point>:
  endbr64
  lea    0x1(%rsi),%eax
  push   %r15
  push   %r14
  movslq %edx,%r14
  cltd
  idiv   %r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rax
  mov    %ecx,%r12d
  sub    $0x18,%rsp
  mov    %rdi,%r13
  lea    (%rdi,%rax,8),%rcx
  mov    %esi,%ebp
  mov    %rcx,0x8(%rsp)
  movslq %edx,%rax
  mov    %edx,%r15d
  mov    %r12d,%edx
  mov    (%rdi,%rax,8),%rsi
  mov    (%rcx),%rdi
  call   <get_distance@plt>
  test   %r14d,%r14d
  jle    L25
  movapd %xmm0,%xmm1
  xor    %ebx,%ebx
L18:
  cmp    %ebx,%ebp
  je     L15
  mov    0x8(%rsp),%rax
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12d,%edx
  movsd  %xmm1,(%rsp)
  mov    (%rax),%rdi
  call   <get_distance@plt>
  movsd  (%rsp),%xmm1
  comisd %xmm0,%xmm1
  minsd  %xmm1,%xmm0
  cmova  %ebx,%r15d
  movapd %xmm0,%xmm1
L15:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L18
L25:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int index_of_nearest_point(const double *const *data, int I, int t, int n) {
  int J = (I + 1) % t;
  double minimum = get_distance(data[I], data[J], n);
  for (int i = 0; i < t; i++) {
    if (i == I)
      continue;
    double distance = get_distance(data[I], data[i], n);
    if (distance < minimum) {
      minimum = distance;
      J = i;
    }
  }
  return J;
}
```
user: Translate the below assembly code into C programming language:

```asm
<index_of_nearest_point>:
  endbr64
  lea    0x1(%rsi),%eax
  push   %r15
  push   %r14
  movslq %edx,%r14
  cltd
  idiv   %r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rax
  mov    %ecx,%r12d
  sub    $0x18,%rsp
  mov    %rdi,%r13
  lea    (%rdi,%rax,8),%rcx
  mov    %esi,%ebp
  mov    %rcx,0x8(%rsp)
  movslq %edx,%rax
  mov    %edx,%r15d
  mov    %r12d,%edx
  mov    (%rdi,%rax,8),%rsi
  mov    (%rcx),%rdi
  call   <get_distance@plt>
  test   %r14d,%r14d
  jle    L29
  movapd %xmm0,%xmm1
  xor    %ebx,%ebx
L27:
  cmp    %ebx,%ebp
  je     L17
  mov    0x8(%rsp),%rax
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12d,%edx
  movsd  %xmm1,(%rsp)
  mov    (%rax),%rdi
  call   <get_distance@plt>
  movsd  (%rsp),%xmm1
  comisd %xmm0,%xmm1
  minsd  %xmm1,%xmm0
  cmova  %ebx,%r15d
  movapd %xmm0,%xmm1
L17:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L27
L29:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int index_of_nearest_point(const double *const *data, int I, int t, int n) {
  int J = (I + 1) % t;
  double minimum = get_distance(data[I], data[J], n);
  for (int i = 0; i < t; i++) {
    if (i == I)
      continue;
    double distance = get_distance(data[I], data[i], n);
    if (distance < minimum) {
      minimum = distance;
      J = i;
    }
  }
  return J;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  cmpl   $0x2,-0x64(%rbp)
  je     L67
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L46
L67:
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  lea    -0x3b(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x39(%rbp)
  movl   $0x8,-0x5c(%rbp)
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x58(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L80:
  cmp    %rdx,%rsp
  je     L60
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L80
L60:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L95
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L95:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x50(%rbp)
  movl   $0x1,-0x60(%rbp)
  jmp    L33
L84:
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x50(%rbp),%rcx
  lea    -0x3b(%rbp),%rdx
  mov    -0x60(%rbp),%esi
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <crack@plt>
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x48(%rbp)
  je     L10
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L46
L10:
  addl   $0x1,-0x60(%rbp)
L33:
  mov    -0x60(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jle    L84
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsp
  mov    $0x0,%eax
  jmp    L41
L46:
  mov    %rbx,%rsp
L41:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D1: Not enough arguments

tool: D14: No solution found.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Not enough arguments\n");
    return 1;
  }
  char salt[3];
  strncpy(salt, argv[1], 2);
  salt[2] = '\0';
  int keySize = 8;
  char buf[keySize];
  for (int length = 1; length <= keySize; length++) {
    char *key = crack(argv[1], length, salt, buf, 0);
    if (key != NULL) {
      printf("%s\n", key);
      return 0;
    }
  }
  printf("No solution found.");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%r13
  cmp    $0x2,%edi
  je     L15
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L0:
  mov    %r13,%rsp
L41:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L15:
  mov    %rsi,%r14
  mov    0x8(%rsi),%rsi
  lea    -0x2b(%rbp),%rdi
  mov    $0x2,%edx
  call   <strncpy@plt>
  movb   $0x0,-0x29(%rbp)
  mov    $0x1,%ebx
  lea    -0x33(%rbp),%r12
L45:
  lea    -0x2b(%rbp),%rdx
  mov    0x8(%r14),%rdi
  mov    $0x0,%r8d
  mov    %r12,%rcx
  mov    %ebx,%esi
  call   <crack@plt>
  test   %rax,%rax
  jne    L42
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L45
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsp
  mov    $0x0,%eax
  jmp    L41
L42:
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L0
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D9: Not enough arguments

tool: D4: No solution found.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Not enough arguments\n");
    return 1;
  }
  char salt[3];
  strncpy(salt, argv[1], 2);
  salt[2] = '\0';
  int keySize = 8;
  char buf[keySize];
  for (int length = 1; length <= keySize; length++) {
    char *key = crack(argv[1], length, salt, buf, 0);
    if (key != NULL) {
      printf("%s\n", key);
      return 0;
    }
  }
  printf("No solution found.");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%r13
  cmp    $0x2,%edi
  je     L55
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L46:
  mov    %r13,%rsp
L6:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L55:
  lea    -0x3b(%rbp),%rax
  mov    %rsi,%r14
  mov    0x8(%rsi),%rsi
  mov    $0x2,%edx
  mov    %rax,%rdi
  mov    %rax,%r15
  lea    -0x43(%rbp),%r12
  mov    $0x1,%ebx
  call   <strncpy@plt>
  movb   $0x0,-0x39(%rbp)
  nopw   0x0(%rax,%rax,1)
L50:
  mov    0x8(%r14),%rdi
  xor    %r8d,%r8d
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %ebx,%esi
  call   <crack@plt>
  test   %rax,%rax
  jne    L48
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L50
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r13,%rsp
  jmp    L6
L48:
  mov    %rax,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L46
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D4: Not enough arguments

tool: D1: No solution found.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Not enough arguments\n");
    return 1;
  }
  char salt[3];
  strncpy(salt, argv[1], 2);
  salt[2] = '\0';
  int keySize = 8;
  char buf[keySize];
  for (int length = 1; length <= keySize; length++) {
    char *key = crack(argv[1], length, salt, buf, 0);
    if (key != NULL) {
      printf("%s\n", key);
      return 0;
    }
  }
  printf("No solution found.");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%r13
  cmp    $0x2,%edi
  je     L26
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L48:
  mov    %r13,%rsp
L10:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L26:
  lea    -0x3b(%rbp),%rax
  mov    %rsi,%r14
  mov    0x8(%rsi),%rsi
  mov    $0x2,%edx
  mov    %rax,%rdi
  mov    %rax,%r15
  lea    -0x43(%rbp),%r12
  mov    $0x1,%ebx
  call   <strncpy@plt>
  movb   $0x0,-0x39(%rbp)
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x8(%r14),%rdi
  xor    %r8d,%r8d
  mov    %r12,%rcx
  mov    %r15,%rdx
  mov    %ebx,%esi
  call   <crack@plt>
  test   %rax,%rax
  jne    L15
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L21
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r13,%rsp
  jmp    L10
L15:
  mov    %rax,%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L48
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D0
type: string

tool: D9: Not enough arguments

tool: D0: No solution found.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Not enough arguments\n");
    return 1;
  }
  char salt[3];
  strncpy(salt, argv[1], 2);
  salt[2] = '\0';
  int keySize = 8;
  char buf[keySize];
  for (int length = 1; length <= keySize; length++) {
    char *key = crack(argv[1], length, salt, buf, 0);
    if (key != NULL) {
      printf("%s\n", key);
      return 0;
    }
  }
  printf("No solution found.");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L18
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
L18:
  leave
  ret
```

assistant: ```c
void *_xmalloc(size_t len) {
  if (len == 0)
    return NULL;
  return malloc(len);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_xmalloc>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
L5:
  ret
```

assistant: ```c
void *_xmalloc(size_t len) {
  if (len == 0)
    return NULL;
  return malloc(len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_xmalloc>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <malloc@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *_xmalloc(size_t len) {
  if (len == 0)
    return NULL;
  return malloc(len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_xmalloc>:
  endbr64
  test   %rdi,%rdi
  je     L0
  jmp    1050 <malloc@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *_xmalloc(size_t len) {
  if (len == 0)
    return NULL;
  return malloc(len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TX_MEMCPY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pmemobj_tx_add_range_direct@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  leave
  ret
```

assistant: ```c
void *TX_MEMCPY(void *dest, const void *src, size_t num) {
  pmemobj_tx_add_range_direct(dest, num);
  return memcpy(dest, src, num);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TX_MEMCPY>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <pmemobj_tx_add_range_direct@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *TX_MEMCPY(void *dest, const void *src, size_t num) {
  pmemobj_tx_add_range_direct(dest, num);
  return memcpy(dest, src, num);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TX_MEMCPY>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pmemobj_tx_add_range_direct@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *TX_MEMCPY(void *dest, const void *src, size_t num) {
  pmemobj_tx_add_range_direct(dest, num);
  return memcpy(dest, src, num);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TX_MEMCPY>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <pmemobj_tx_add_range_direct@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <memcpy@plt>
```

assistant: ```c
void *TX_MEMCPY(void *dest, const void *src, size_t num) {
  pmemobj_tx_add_range_direct(dest, num);
  return memcpy(dest, src, num);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<voronoi_F1S>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movss  %xmm0,-0x54(%rbp)
  movss  %xmm1,-0x58(%rbp)
  movss  %xmm2,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rsi
  lea    -0x50(%rbp),%rdi
  movss  -0x5c(%rbp),%xmm1
  movss  -0x58(%rbp),%xmm0
  mov    -0x54(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <voronoi@plt>
  movss  -0x50(%rbp),%xmm0
  addss  %xmm0,%xmm0
  movss  D3(%rip),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float voronoi_F1S(float x, float y, float z) {
  float da[4], pa[12];
  voronoi(x, y, z, da, pa, 1, 0);
  return (2.0f * da[0] - 1.0f);
}
```