user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L105
  lea    0x1c(%rsp),%rax
  lea    0x20(%rsp),%rbx
  mov    %rax,(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L89:
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L73
  mov    %rbx,%r13
  xor    %r12d,%r12d
  xchg   %ax,%ax
L3:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    0x1c(%rsp),%edi
  cmp    %r12d,%edi
  jg     L3
  test   %edi,%edi
  jle    L73
  mov    %edi,%eax
  mov    %edi,%r11d
  lea    -0x1(%rdi),%r15d
  mov    %edi,%r14d
  shr    $0x2,%eax
  and    $0xfffffffc,%r11d
  xor    %esi,%esi
  xor    %r13d,%r13d
  lea    -0x1(%rax),%ecx
  xor    %r10d,%r10d
  shl    $0x4,%rcx
  add    0x8(%rsp),%rcx
  nopl   0x0(%rax,%rax,1)
L150:
  mov    (%rbx,%rsi,4),%edx
  movslq %esi,%r8
  cmp    $0x2,%r15d
  jbe    L182
  movd   %edx,%xmm3
  mov    %rbx,%rax
  pxor   %xmm0,%xmm0
  pshufd $0x0,%xmm3,%xmm2
L71:
  movdqa %xmm2,%xmm1
  add    $0x10,%rax
  pcmpeqd -0x10(%rax),%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L71
  movdqa %xmm0,%xmm1
  mov    %r11d,%eax
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%r9d
  cmp    %r11d,%edi
  je     L96
L33:
  movslq %eax,%r12
  cmp    0x20(%rsp,%r12,4),%edx
  jne    L144
  add    $0x1,%r9d
L144:
  lea    0x1(%rax),%r12d
  cmp    %r12d,%edi
  jle    L96
  movslq %r12d,%r12
  cmp    0x20(%rsp,%r12,4),%edx
  jne    L132
  add    $0x1,%r9d
L132:
  add    $0x2,%eax
  cmp    %eax,%edi
  jle    L96
  cltq
  cmp    0x20(%rsp,%rax,4),%edx
  jne    L96
  add    $0x1,%r9d
  nopl   (%rax)
L96:
  cmp    %r9d,%r10d
  jl     L85
  jne    L8
  movslq %r13d,%rax
  cmp    0x20(%rsp,%rax,4),%edx
  cmovl  %r8,%r13
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rsi
  cmp    %r14,%rsi
  jne    L150
L22:
  mov    0x20(%rsp,%r13,4),%esi
  mov    %r10d,%edx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L89
L105:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L116
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  movslq %r8d,%r13
  mov    %r9d,%r10d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L182:
  xor    %eax,%eax
  xor    %r9d,%r9d
  jmp    L33
L73:
  xor    %r13d,%r13d
  xor    %r10d,%r10d
  jmp    L22
L116:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string

tool: D2: %d

tool: D4: %d %d


assistant: ```c
int main() {
  int t, max, maxtemp, arr[100], n, i, j, pos;
  scanf("%d", &t);
  while (t--) {
    max = 0;
    pos = 0;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%d", &arr[i]);
    for (i = 0; i < n; i++) {
      maxtemp = 0;
      for (j = 0; j < n; j++) {
        if (arr[j] == arr[i])
          maxtemp++;
      }
      if (maxtemp > max) {
        max = maxtemp;
        pos = i;
      } else if (max == maxtemp) {
        if (arr[i] < arr[pos])
          pos = i;
      }
    }
    printf("%d %d\n", arr[pos], max);
  }
  return 0;
}
```