ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Hash32Len5to12>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    (%rsi,%rsi,4),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <read32@plt>
  lea    -0x4(%rbp,%rbx,1),%rdi
  mov    %rax,%r14
  call   <read32@plt>
  mov    %rax,%r13
  mov    %rbx,%rax
  shr    %rax
  and    $0x4,%eax
  lea    0x0(%rbp,%rax,1),%rdi
  call   <read32@plt>
  lea    (%rbx,%r14,1),%edi
  mov    %r12d,%esi
  mov    %rax,%rbp
  call   <mur@plt>
  lea    (%r12,%r13,1),%edi
  mov    %eax,%esi
  call   <mur@plt>
  lea    0x9(%rbp),%edi
  mov    %eax,%esi
  call   <mur@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fmix@plt>
```

assistant: ```c
uint32_t Hash32Len5to12(const char *s, size_t len) {
  uint32_t a = len, b = len * 5, c = 9, d = b;
  a += read32(s);
  b += read32(s + len - 4);
  c += read32(s + ((len >> 1) & 4));
  return fmix(mur(c, mur(b, mur(a, d))));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Hash32Len5to12>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    (%rsi,%rsi,4),%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <read32@plt>
  lea    -0x4(%rbp,%rbx,1),%rdi
  mov    %rax,%r14
  call   <read32@plt>
  mov    %rax,%r13
  mov    %rbx,%rax
  shr    %rax
  and    $0x4,%eax
  lea    0x0(%rbp,%rax,1),%rdi
  call   <read32@plt>
  lea    (%rbx,%r14,1),%edi
  mov    %r12d,%esi
  mov    %rax,%rbp
  call   <mur@plt>
  lea    (%r12,%r13,1),%edi
  mov    %eax,%esi
  call   <mur@plt>
  lea    0x9(%rbp),%edi
  mov    %eax,%esi
  call   <mur@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <fmix@plt>
```

assistant: ```c
uint32_t Hash32Len5to12(const char *s, size_t len) {
  uint32_t a = len, b = len * 5, c = 9, d = b;
  a += read32(s);
  b += read32(s + len - 4);
  c += read32(s + ((len >> 1) & 4));
  return fmix(mur(c, mur(b, mur(a, d))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <get_percent@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  get_percent(atoi(argv[1]));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <get_percent@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  get_percent(atoi(argv[1]));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <get_percent@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  get_percent(atoi(argv[1]));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  call   <get_percent@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  get_percent(atoi(argv[1]));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<token_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L17
L3:
  nop
L17:
  leave
  ret
```

assistant: ```c
void token_destroy(struct token *t) {
  if (t == NULL)
    return;
  free(t);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<token_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L0:
  ret
```

assistant: ```c
void token_destroy(struct token *t) {
  if (t == NULL)
    return;
  free(t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<token_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
void token_destroy(struct token *t) {
  if (t == NULL)
    return;
  free(t);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<token_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void token_destroy(struct token *t) {
  if (t == NULL)
    return;
  free(t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ControlNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0xa,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L29
L7:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  add    %eax,-0x38(%rbp)
  addl   $0x1,-0x34(%rbp)
L29:
  cmpl   $0x9,-0x34(%rbp)
  jle    L7
  mov    -0x38(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,-0x38(%rbp)
  cmpl   $0x9,-0x38(%rbp)
  jg     L41
  mov    -0x38(%rbp),%eax
  jmp    L2
L41:
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int ControlNum(const char *id) {
  int digitWeight[10] = {2, 4, 8, 5, 10, 9, 7, 3, 6}, sum = 0, i;
  for (i = 0; i < 10; i++)
    sum += (id[i] - '0') * digitWeight[i];
  sum %= 11;
  return (sum < 10) ? sum : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ControlNum>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x24(%rsp)
  movl   $0x2,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0xa,0x10(%rsp)
  movl   $0x9,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x6,0x20(%rsp)
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    %rsp,%rsi
L4:
  movsbl (%rdi,%rdx,1),%eax
  sub    $0x30,%eax
  imul   (%rsi,%rdx,4),%eax
  add    %eax,%ecx
  add    $0x1,%rdx
  cmp    $0xa,%rdx
  jne    L4
  movslq %ecx,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  cmp    $0xa,%eax
  mov    $0x0,%edx
  cmovge %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x38,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ControlNum(const char *id) {
  int digitWeight[10] = {2, 4, 8, 5, 10, 9, 7, 3, 6}, sum = 0, i;
  for (i = 0; i < 10; i++)
    sum += (id[i] - '0') * digitWeight[i];
  sum %= 11;
  return (sum < 10) ? sum : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ControlNum>:
  endbr64
  sub    $0x38,%rsp
  xor    %edx,%edx
  mov    $0x2,%esi
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x4(%rsp)
  movabs $0x500000008,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x90000000a,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x300000007,%rax
  mov    %rax,0x18(%rsp)
  movq   $0x6,0x20(%rsp)
  jmp    L18
  nopl   0x0(%rax)
L13:
  mov    (%rsp,%rdx,4),%esi
L18:
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  imul   %esi,%eax
  add    %eax,%ecx
  cmp    $0xa,%rdx
  jne    L13
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  xor    %edx,%edx
  cmp    $0xa,%eax
  cmove  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x38,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ControlNum(const char *id) {
  int digitWeight[10] = {2, 4, 8, 5, 10, 9, 7, 3, 6}, sum = 0, i;
  for (i = 0; i < 10; i++)
    sum += (id[i] - '0') * digitWeight[i];
  sum %= 11;
  return (sum < 10) ? sum : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ControlNum>:
  endbr64
  movsbl 0x1(%rdi),%edx
  movsbl (%rdi),%ecx
  movsbl 0x8(%rdi),%eax
  lea    -0xc0(,%rdx,4),%edx
  lea    -0x60(%rdx,%rcx,2),%edx
  movsbl 0x2(%rdi),%ecx
  lea    -0x90(%rax,%rax,2),%eax
  lea    -0x180(%rdx,%rcx,8),%ecx
  movsbl 0x3(%rdi),%edx
  lea    -0xf0(%rdx,%rdx,4),%edx
  add    %ecx,%edx
  movsbl 0x4(%rdi),%ecx
  lea    -0xf0(%rcx,%rcx,4),%ecx
  lea    (%rdx,%rcx,2),%esi
  movsbl 0x5(%rdi),%edx
  lea    -0x1b0(%rdx,%rdx,8),%ecx
  movsbl 0x6(%rdi),%edx
  add    %esi,%ecx
  sub    $0x30,%edx
  lea    (%rcx,%rdx,8),%ecx
  sub    %edx,%ecx
  movsbl 0x7(%rdi),%edx
  lea    -0x90(%rdx,%rdx,2),%edx
  add    %ecx,%edx
  lea    (%rdx,%rax,2),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  mov    %edx,%eax
  xor    %edx,%edx
  sub    %ecx,%eax
  cmp    $0xa,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int ControlNum(const char *id) {
  int digitWeight[10] = {2, 4, 8, 5, 10, 9, 7, 3, 6}, sum = 0, i;
  for (i = 0; i < 10; i++)
    sum += (id[i] - '0') * digitWeight[i];
  sum %= 11;
  return (sum < 10) ? sum : 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<int_size_is_at_least_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x80000000,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_size_is_at_least_32(void) {
  int t = 0x80000000;
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_size_is_at_least_32>:
  endbr64
  mov    $0x80000000,%eax
  ret
```

assistant: ```c
int int_size_is_at_least_32(void) {
  int t = 0x80000000;
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_size_is_at_least_32>:
  endbr64
  mov    $0x80000000,%eax
  ret
```

assistant: ```c
int int_size_is_at_least_32(void) {
  int t = 0x80000000;
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0xff,-0x4(%rbp)
  jle    L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: %c - %d 


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 255; i++) {
    printf("%c - %d \n", i, i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L6:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %c - %d 


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 255; i++) {
    printf("%c - %d \n", i, i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: %c - %d 


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 255; i++) {
    printf("%c - %d \n", i, i);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: %c - %d 


assistant: ```c
int main() {
  int i;
  for (i = 0; i <= 255; i++) {
    printf("%c - %d \n", i, i);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    -0x38(%rbp),%rax
  cltq
  and    $0x3,%eax
  test   %rax,%rax
  jne    L76
  mov    -0x40(%rbp),%rax
  cltq
  and    $0x3,%eax
  test   %rax,%rax
  jne    L76
  mov    -0x44(%rbp),%eax
  cltq
  and    $0x3,%eax
  test   %rax,%rax
  jne    L76
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L30
L58:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x24(%rbp)
L30:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x44(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L58
  jmp    L69
L76:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L14
L16:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x24(%rbp)
L14:
  mov    -0x24(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L16
L69:
  mov    -0x38(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *destination, const void *source, uint64_t length) {
  uint64_t i;
  if ((uint64_t)destination % sizeof(uint32_t) == 0 && (uint64_t)source % sizeof(uint32_t) == 0 && length % sizeof(uint32_t) == 0) {
    uint32_t *d = (uint32_t *)destination;
    const uint32_t *s = (const uint32_t *)source;
    for (i = 0; i < length / sizeof(uint32_t); i++)
      d[i] = s[i];
  } else {
    uint8_t *d = (uint8_t *)destination;
    const uint8_t *s = (const uint8_t *)source;
    for (i = 0; i < length; i++)
      d[i] = s[i];
  }
  return destination;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  or     %rsi,%rcx
  and    $0x3,%ecx
  je     L13
L33:
  mov    %edx,%edi
  mov    $0x0,%ecx
  test   %edx,%edx
  jle    L39
L12:
  mov    (%rsi,%rcx,4),%edx
  mov    %edx,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L12
L59:
  ret
L39:
  ret
L13:
  test   $0x3,%dl
  jne    L33
  movslq %edx,%rdx
  mov    %rdx,%rdi
  shr    $0x2,%rdi
  cmp    $0x3,%rdx
  jbe    L59
L53:
  mov    (%rsi,%rcx,4),%edx
  mov    %edx,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jb     L53
  ret
```

assistant: ```c
void *memcpy(void *destination, const void *source, uint64_t length) {
  uint64_t i;
  if ((uint64_t)destination % sizeof(uint32_t) == 0 && (uint64_t)source % sizeof(uint32_t) == 0 && length % sizeof(uint32_t) == 0) {
    uint32_t *d = (uint32_t *)destination;
    const uint32_t *s = (const uint32_t *)source;
    for (i = 0; i < length / sizeof(uint32_t); i++)
      d[i] = s[i];
  } else {
    uint8_t *d = (uint8_t *)destination;
    const uint8_t *s = (const uint8_t *)source;
    for (i = 0; i < length; i++)
      d[i] = s[i];
  }
  return destination;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  or     %rsi,%rax
  and    $0x3,%eax
  je     L46
L33:
  movslq %edx,%rcx
  xor    %eax,%eax
  test   %edx,%edx
  jle    L21
  nopl   0x0(%rax,%rax,1)
L50:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L50
L21:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L46:
  test   $0x3,%dl
  jne    L33
  movslq %edx,%rdx
  shr    $0x2,%rdx
  je     L21
  shl    $0x2,%rdx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L9
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memcpy(void *destination, const void *source, uint64_t length) {
  uint64_t i;
  if ((uint64_t)destination % sizeof(uint32_t) == 0 && (uint64_t)source % sizeof(uint32_t) == 0 && length % sizeof(uint32_t) == 0) {
    uint32_t *d = (uint32_t *)destination;
    const uint32_t *s = (const uint32_t *)source;
    for (i = 0; i < length / sizeof(uint32_t); i++)
      d[i] = s[i];
  } else {
    uint8_t *d = (uint8_t *)destination;
    const uint8_t *s = (const uint8_t *)source;
    for (i = 0; i < length; i++)
      d[i] = s[i];
  }
  return destination;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  mov    %rsi,%rcx
  or     %rsi,%rax
  and    $0x3,%eax
  je     L169
L121:
  test   %edx,%edx
  jle    L196
  lea    0x4(%rcx),%rsi
  mov    %r8,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L84
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L84
  mov    %edx,%esi
  xor    %eax,%eax
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L96:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L96
  mov    %edx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dl
  je     L196
  mov    %eax,%edi
  mov    (%rcx,%rdi,4),%r9d
  lea    0x0(,%rdi,4),%rsi
  mov    %r9d,(%r8,%rdi,4)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L196
  mov    0x4(%rcx,%rsi,1),%edi
  add    $0x2,%eax
  mov    %edi,0x4(%r8,%rsi,1)
  cmp    %eax,%edx
  jle    L196
  mov    0x8(%rcx,%rsi,1),%eax
  mov    %eax,0x8(%r8,%rsi,1)
L196:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L169:
  test   $0x3,%dl
  jne    L121
  movslq %edx,%rdx
  mov    %rdx,%rsi
  shr    $0x2,%rsi
  je     L196
  lea    0x4(%rcx),%r9
  sub    %r9,%rdi
  cmp    $0x8,%rdi
  jbe    L60
  lea    -0x1(%rsi),%rdi
  cmp    $0x2,%rdi
  jbe    L60
  mov    %rdx,%rdi
  and    $0xfffffffffffffff0,%rdx
  shr    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L174:
  movdqu (%rcx,%rax,1),%xmm1
  movups %xmm1,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L174
  lea    0x0(,%rdi,4),%rax
  cmp    %rax,%rsi
  je     L196
  shl    $0x4,%rdi
  mov    (%rcx,%rdi,1),%edx
  mov    %edx,(%r8,%rdi,1)
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    %rdx,%rsi
  jbe    L196
  mov    (%rcx,%rdx,4),%r9d
  add    $0x2,%eax
  lea    0x0(,%rdx,4),%rdi
  cltq
  mov    %r9d,(%r8,%rdx,4)
  cmp    %rax,%rsi
  jbe    L196
  mov    0x4(%rcx,%rdi,1),%eax
  mov    %eax,0x4(%r8,%rdi,1)
  jmp    L196
  cs nopw 0x0(%rax,%rax,1)
L84:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L145:
  mov    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L145
  mov    %r8,%rax
  ret
L60:
  shl    $0x2,%rsi
L44:
  mov    (%rcx,%rax,1),%edx
  mov    %edx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L44
  jmp    L196
```

assistant: ```c
void *memcpy(void *destination, const void *source, uint64_t length) {
  uint64_t i;
  if ((uint64_t)destination % sizeof(uint32_t) == 0 && (uint64_t)source % sizeof(uint32_t) == 0 && length % sizeof(uint32_t) == 0) {
    uint32_t *d = (uint32_t *)destination;
    const uint32_t *s = (const uint32_t *)source;
    for (i = 0; i < length / sizeof(uint32_t); i++)
      d[i] = s[i];
  } else {
    uint8_t *d = (uint8_t *)destination;
    const uint8_t *s = (const uint8_t *)source;
    for (i = 0; i < length; i++)
      d[i] = s[i];
  }
  return destination;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x2a,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: %d

assistant: ```c
int main(int argc, char **argv) {
  printf("%d", 42);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1: %d

assistant: ```c
int main(int argc, char **argv) {
  printf("%d", 42);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: %d

assistant: ```c
int main(int argc, char **argv) {
  printf("%d", 42);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2a,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main(int argc, char **argv) {
  printf("%d", 42);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L4:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  imul   $0x1388,%rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  imul   $0x1388,%rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x1387,-0x4(%rbp)
  jle    L15
  addl   $0x1,-0x8(%rbp)
L31:
  cmpl   $0x1387,-0x8(%rbp)
  jle    L4
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  static int x[5000][5000];
  for (int i = 0; i < 5000; i++) {
    for (int j = 0; j < 5000; j++) {
      x[j][i]++;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  lea    D9(%rip),%rcx
  lea    0x5f5e100(%rcx),%rdx
  add    $0x5f62f20,%rcx
L1:
  lea    -0x5f5e100(%rdx),%rax
L3:
  addl   $0x1,(%rax)
  add    $0x4e20,%rax
  cmp    %rdx,%rax
  jne    L3
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L1
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  static int x[5000][5000];
  for (int i = 0; i < 5000; i++) {
    for (int j = 0; j < 5000; j++) {
      x[j][i]++;
    }
  }
  return 0;
}
```