user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    -0x3c(%rbp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    %rcx,-0x60(%rbp)
  imul   %rdx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L137:
  cmp    %rcx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L137
L18:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L217
  orq    $0x0,-0x8(%rsp,%rdx,1)
L217:
  mov    %rsp,-0x50(%rbp)
  test   %eax,%eax
  jle    L79
  mov    -0x60(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x48(%rbp)
  mov    $0x0,%r13d
  lea    D27(%rip),%r15
  lea    D10(%rip),%r14
  jmp    L190
L162:
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x3c(%rbp)
  jg     L162
L57:
  add    $0x1,%r13d
  mov    -0x3c(%rbp),%eax
  mov    -0x58(%rbp),%rdi
  add    %rdi,-0x48(%rbp)
  cmp    %r13d,%eax
  jle    L79
L190:
  mov    -0x50(%rbp),%rax
  mov    -0x48(%rbp),%rcx
  lea    (%rax,%rcx,4),%r12
  mov    $0x0,%ebx
  cmpl   $0x0,-0x3c(%rbp)
  jg     L162
  jmp    L57
L79:
  sub    $0x1,%eax
  mov    %eax,-0x58(%rbp)
  mov    -0x3c(%rbp),%r8d
  imul   %r8d,%r8d
  test   %r8d,%r8d
  jle    L100
  mov    -0x60(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  movl   $0x0,-0x48(%rbp)
  mov    $0x0,%r15d
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  mov    $0x0,%r14d
  jmp    L50
L125:
  add    $0x1,%r14d
L203:
  add    $0x1,%r15d
  cmp    -0x58(%rbp),%r15d
  je     L176
L157:
  lea    0x1(%r12),%eax
  and    $0x1,%eax
  or     -0x48(%rbp),%eax
  je     L188
L170:
  add    $0x1,%r13d
  mov    -0x3c(%rbp),%r8d
  imul   %r8d,%r8d
  cmp    %r13d,%r8d
  jle    L100
L50:
  movslq %ebx,%rax
  movslq %r14d,%rdx
  imul   -0x60(%rbp),%rdx
  add    %rdx,%rax
  mov    -0x50(%rbp),%rcx
  mov    (%rcx,%rax,4),%r9d
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %r14d,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  adc    $0x0,%ebx
  mov    %r12d,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%r12,%rdx,1),%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L125
  cmp    $0x2,%eax
  jne    L166
  sub    $0x1,%ebx
  jmp    L203
L166:
  cmp    $0x3,%eax
  jne    L203
  sub    $0x1,%r14d
  jmp    L203
L176:
  add    $0x1,%r12d
  movl   $0x0,-0x48(%rbp)
  mov    $0xffffffff,%r15d
  jmp    L157
L188:
  subl   $0x1,-0x58(%rbp)
  movl   $0x1,-0x48(%rbp)
  jmp    L170
L100:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L184
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L184:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D44
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string

tool: D44: Inserisci dimensione della matrice: 

tool: D10: %d

tool: D27: Inserisci numero [%d:%d]: 

tool: D22: 
[i=%d, k=%d; %d/%d]: %d

assistant: ```c
int main() {
  int i, k, j;
  int size;
  int direction, step, max_step;
  bool changed;
  printf("Inserisci dimensione della matrice: ");
  scanf("%d", &size);
  int matrix[size][size];
  for (i = 0; i < size; i++) {
    for (k = 0; k < size; k++) {
      printf("Inserisci numero [%d:%d]: ", i, k);
      scanf("%d", &matrix[i][k]);
    }
  }
  for (j = 0, i = 0, k = 0, direction = 0, step = 0, max_step = size - 1, changed = false; j < size * size; j++) {
    printf("\n[i=%d, k=%d; %d/%d]: %d", i, k, j, size * size, matrix[i][k]);
    if (direction % 4 == 0)
      k++;
    if (direction % 4 == 1)
      i++;
    if (direction % 4 == 2)
      k--;
    if (direction % 4 == 3)
      i--;
    step++;
    if (step == max_step)
      step = -1, direction++, changed = false;
    if ((direction + 1) % 2 == 0 && !changed)
      max_step--, changed = true;
  }
  printf("\n");
  return 0;
}
```