user: 这段汇编代码用C语言表示是什么样的?

```asm
<itostr>:
  endbr64
  cmp    $0x1e,%esi
  jle    L175
  movb   $0x0,D57(%rip)
L75:
  lea    D57(%rip),%rax
  ret
L175:
  mov    %esi,%r8d
  mov    %edx,%r9d
  mov    %ecx,%r10d
  test   %edi,%edi
  je     L61
  push   %rbx
  mov    %edx,%ecx
  cmp    $0x2,%edx
  je     L48
  cmp    $0x3,%edx
  mov    $0xa,%ecx
  mov    $0x10,%eax
  cmove  %eax,%ecx
L48:
  test   %r8b,%r8b
  jle    L55
  movsbl %r8b,%r11d
  lea    -0x1(%r11),%esi
  sub    $0x2,%r11d
  lea    -0x1(%r8),%eax
  movzbl %al,%eax
  sub    %eax,%r11d
  lea    D57(%rip),%rbx
  jmp    L218
L219:
  cmp    $0x9,%dl
  jle    L37
  movslq %esi,%rax
  add    $0x37,%edx
  mov    %dl,(%rbx,%rax,1)
L210:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  sub    $0x1,%esi
  cmp    %r11d,%esi
  je     L55
L218:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x3,%r9d
  je     L219
  cmp    $0x1,%r9d
  je     L9
  movslq %esi,%rax
  add    $0x30,%edx
  mov    %dl,(%rbx,%rax,1)
  jmp    L210
L37:
  movslq %esi,%rax
  add    $0x30,%edx
  mov    %dl,(%rbx,%rax,1)
  jmp    L210
L9:
  test   %edi,%edi
  jne    L26
  test   %r10d,%r10d
  je     L26
  movslq %esi,%rax
  movb   $0x20,(%rbx,%rax,1)
  jmp    L210
L26:
  movslq %esi,%rax
  add    $0x30,%edx
  mov    %dl,(%rbx,%rax,1)
  jmp    L210
L55:
  movslq %r8d,%r8
  lea    D57(%rip),%rax
  movb   $0x0,(%rax,%r8,1)
  lea    D57(%rip),%rax
  pop    %rbx
  ret
L61:
  cmp    $0x1,%edx
  jne    L181
  test   %ecx,%ecx
  je     L181
  test   %esi,%esi
  jle    L148
  mov    $0x0,%eax
  lea    D57(%rip),%rcx
L177:
  movzbl %al,%edx
  movb   $0x20,(%rcx,%rdx,1)
  add    $0x1,%eax
  movsbl %al,%edx
  cmp    %r8d,%edx
  jl     L177
L148:
  lea    D57(%rip),%rdx
  lea    -0x1(%r8),%eax
  cltq
  movb   $0x30,(%rdx,%rax,1)
  movslq %r8d,%r8
  movb   $0x0,(%rdx,%r8,1)
  jmp    L75
L181:
  mov    $0x0,%eax
  lea    D57(%rip),%rcx
  test   %r8d,%r8d
  jle    L10
L124:
  movzbl %al,%edx
  movb   $0x30,(%rcx,%rdx,1)
  add    $0x1,%eax
  movsbl %al,%edx
  cmp    %r8d,%edx
  jl     L124
L10:
  movzbl %al,%eax
  lea    D57(%rip),%rdx
  movb   $0x0,(%rdx,%rax,1)
  jmp    L75
```

assistant: ```c
char *itostr(u_int iNumber, u_char cDigits, u_char cMode, u_char cDec_mode) {
  static char cBuffer[31];
  char c, cMod;
  u_int iDivisor = 10;
  if (cDigits > 30) {
    cBuffer[0] = '\0';
  } else {
    if (iNumber) {
      switch (cMode) {
      case 2:
        iDivisor = 2;
        break;
      case 1:
        iDivisor = 10;
        break;
      case 3:
        iDivisor = 16;
        break;
      }
      for (c = cDigits; c > 0; c--) {
        cMod = iNumber % iDivisor;
        if (cMode == 3) {
          if (cMod > 9)
            cBuffer[c - 1] = cMod + 55;
          else
            cBuffer[c - 1] = cMod + 48;
        } else {
          if (cMode == 1) {
            if ((!iNumber) && (cDec_mode))
              cBuffer[c - 1] = ' ';
            else
              cBuffer[c - 1] = cMod + 48;
          } else
            cBuffer[c - 1] = cMod + 48;
        }
        iNumber /= iDivisor;
      }
      cBuffer[cDigits] = '\0';
    } else {
      if ((cMode == 1) && (cDec_mode)) {
        for (c = 0; c < cDigits; c++)
          cBuffer[(unsigned char)c] = ' ';
        cBuffer[cDigits - 1] = '0';
        cBuffer[cDigits] = '\0';
      } else {
        for (c = 0; c < cDigits; c++)
          cBuffer[(unsigned char)c] = '0';
        cBuffer[(unsigned char)c] = '\0';
      }
    }
  }
  return (cBuffer);
}
```