ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<vector3d_add>:
  endbr64
  lea    0x8(%rdx),%rax
  cmp    %rax,%rdi
  je     L19
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L19
  movupd (%rsi),%xmm0
  movupd (%rdx),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdi)
  movsd  0x10(%rsi),%xmm0
  addsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
  nopl   (%rax)
L19:
  movsd  (%rsi),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  addsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  addsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void vector3d_add(double u[3], double v[3], double w[3]) {
  int i;
  for (i = 0; i < 3; i++)
    u[i] = v[i] + w[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D9
data_type: string

tool: D0: r

tool: D8: haha

tool: D9: fopen haha

assistant: ```c
int main(void) {
  fopen("haha", "r");
  perror("fopen haha");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <fopen@plt>
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D29
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D9: r

tool: D29: haha

tool: D10: fopen haha

assistant: ```c
int main(void) {
  fopen("haha", "r");
  perror("fopen haha");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  lea    D4(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D2: r

tool: D13: haha

tool: D4: fopen haha

assistant: ```c
int main(void) {
  fopen("haha", "r");
  perror("fopen haha");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rsi
  lea    D28(%rip),%rdi
  call   <fopen@plt>
  lea    D9(%rip),%rdi
  call   <perror@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
data_type: string
name: read_data
arguments: data_tag: D28
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string

tool: D26: r

tool: D28: haha

tool: D9: fopen haha

assistant: ```c
int main(void) {
  fopen("haha", "r");
  perror("fopen haha");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stringParaInt@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D2:  %[^
]s

tool: D6:  %d...

assistant: ```c
int main() {
  int x = 0;
  char s[10];
  scanf(" %[^\n]s", s);
  stringParaInt(s, &x);
  printf(" %d...", x);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x8(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <stringParaInt@plt>
  mov    0x8(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D3
data_type: string

tool: D11:  %[^
]s

tool: D3:  %d...

assistant: ```c
int main() {
  int x = 0;
  char s[10];
  scanf(" %[^\n]s", s);
  stringParaInt(s, &x);
  printf(" %d...", x);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  movl   $0x0,0x8(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stringParaInt@plt>
  mov    0x8(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string

tool: D10:  %[^
]s

tool: D13:  %d...

assistant: ```c
int main() {
  int x = 0;
  char s[10];
  scanf(" %[^\n]s", s);
  stringParaInt(s, &x);
  printf(" %d...", x);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  movl   $0x0,0x8(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stringParaInt@plt>
  mov    0x8(%rsp),%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D5
type: string

tool: D9:  %[^
]s

tool: D5:  %d...

assistant: ```c
int main() {
  int x = 0;
  char s[10];
  scanf(" %[^\n]s", s);
  stringParaInt(s, &x);
  printf(" %d...", x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<update_mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int update_mac(unsigned char *buf, const char *mac) {
  memcpy(buf, mac, 6);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<update_mac>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  call   <memcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int update_mac(unsigned char *buf, const char *mac) {
  memcpy(buf, mac, 6);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<update_mac>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int update_mac(unsigned char *buf, const char *mac) {
  memcpy(buf, mac, 6);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<update_mac>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6,%edx
  call   <memcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int update_mac(unsigned char *buf, const char *mac) {
  memcpy(buf, mac, 6);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x10(%rbp)
  js     L6
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
data_type: string
name: read_data
arguments: data_label: D27
data_type: string
name: read_data
arguments: data_label: D28
data_type: string

tool: D21: ERROR: Line %d

tool: D27:  (Address: %d)

tool: D28:    %s


assistant: ```c
int error(char *msg, int lineNo, int instNo) {
  printf("ERROR: Line %d", lineNo);
  if (instNo >= 0)
    printf(" (Address: %d)", instNo);
  printf("   %s\n", msg);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%ebx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jns    L4
L13:
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %ebx,%esi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
```

tool_calls: name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D17: ERROR: Line %d

tool: D21:    %s


tool: D14:  (Address: %d)

assistant: ```c
int error(char *msg, int lineNo, int instNo) {
  printf("ERROR: Line %d", lineNo);
  if (instNo >= 0)
    printf(" (Address: %d)", instNo);
  printf("   %s\n", msg);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<error>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D18(%rip),%rdi
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  js     L7
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    %r12,%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D18: ERROR: Line %d

tool: D9:  (Address: %d)

tool: D16:    %s


assistant: ```c
int error(char *msg, int lineNo, int instNo) {
  printf("ERROR: Line %d", lineNo);
  if (instNo >= 0)
    printf(" (Address: %d)", instNo);
  printf("   %s\n", msg);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<error>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D14(%rip),%rdi
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  js     L5
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L5:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type: string
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D5
type: string

tool: D14: ERROR: Line %d

tool: D13:  (Address: %d)

tool: D5:    %s


assistant: ```c
int error(char *msg, int lineNo, int instNo) {
  printf("ERROR: Line %d", lineNo);
  if (instNo >= 0)
    printf(" (Address: %d)", instNo);
  printf("   %s\n", msg);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wordLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L5
L2:
  movq   $0x0,-0x8(%rbp)
  jmp    L28
L36:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L32
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
L32:
  mov    -0x8(%rbp),%rax
L5:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t wordLength(char *string) {
  if (string == NULL) {
    return 0;
  }
  uint8_t length = 0;
  while (string[length] != ' ' && string[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wordLength>:
  endbr64
  test   %rdi,%rdi
  je     L2
  testb  $0xdf,(%rdi)
  je     L6
  mov    $0x0,%eax
L23:
  add    $0x1,%rax
  testb  $0xdf,(%rdi,%rax,1)
  jne    L23
  ret
L2:
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint8_t wordLength(char *string) {
  if (string == NULL) {
    return 0;
  }
  uint8_t length = 0;
  while (string[length] != ' ' && string[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wordLength>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L16
  testb  $0xdf,(%rdi)
  je     L4
L20:
  add    $0x1,%rax
  testb  $0xdf,(%rdi,%rax,1)
  jne    L20
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
uint8_t wordLength(char *string) {
  if (string == NULL) {
    return 0;
  }
  uint8_t length = 0;
  while (string[length] != ' ' && string[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wordLength>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L2
  testb  $0xdf,(%rdi)
  je     L4
L10:
  add    $0x1,%rax
  testb  $0xdf,(%rdi,%rax,1)
  jne    L10
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
uint8_t wordLength(char *string) {
  if (string == NULL) {
    return 0;
  }
  uint8_t length = 0;
  while (string[length] != ' ' && string[length] != '\0') {
    length++;
  }
  return length;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<setenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movl   $0xff,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L4
  cmpq   $0x0,-0x10(%rbp)
  je     L4
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <putenv@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L4:
  mov    -0x20(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D9: %s=%s

assistant: ```c
int setenv(const char *key, const char *value, int overwrite) {
  int result = 255;
  char *current = getenv(key);
  if (overwrite && current) {
    int key_len = strlen(key);
    int val_len = strlen(value);
    int len = key_len + 1 + val_len + 1;
    char *buffer = malloc(len);
    memset(buffer, 0, len);
    sprintf(buffer, "%s=%s", key, value);
    result = putenv(buffer);
    free(buffer);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setenv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%ebp
  call   <getenv@plt>
  test   %ebp,%ebp
  je     L7
  test   %rax,%rax
  je     L7
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r12,%rcx
  mov    %rbx,%rdx
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <putenv@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L13
L7:
  mov    $0xff,%ebx
L13:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: %s=%s

assistant: ```c
int setenv(const char *key, const char *value, int overwrite) {
  int result = 255;
  char *current = getenv(key);
  if (overwrite && current) {
    int key_len = strlen(key);
    int val_len = strlen(value);
    int len = key_len + 1 + val_len + 1;
    char *buffer = malloc(len);
    memset(buffer, 0, len);
    sprintf(buffer, "%s=%s", key, value);
    result = putenv(buffer);
    free(buffer);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setenv>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <getenv@plt>
  test   %ebx,%ebx
  je     L15
  test   %rax,%rax
  je     L15
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <putenv@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L15:
  mov    $0xff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: %s=%s

assistant: ```c
int setenv(const char *key, const char *value, int overwrite) {
  int result = 255;
  char *current = getenv(key);
  if (overwrite && current) {
    int key_len = strlen(key);
    int val_len = strlen(value);
    int len = key_len + 1 + val_len + 1;
    char *buffer = malloc(len);
    memset(buffer, 0, len);
    sprintf(buffer, "%s=%s", key, value);
    result = putenv(buffer);
    free(buffer);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setenv>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <getenv@plt>
  test   %ebx,%ebx
  je     L3
  test   %rax,%rax
  je     L3
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <putenv@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L3:
  mov    $0xff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: %s=%s

assistant: ```c
int setenv(const char *key, const char *value, int overwrite) {
  int result = 255;
  char *current = getenv(key);
  if (overwrite && current) {
    int key_len = strlen(key);
    int val_len = strlen(value);
    int len = key_len + 1 + val_len + 1;
    char *buffer = malloc(len);
    memset(buffer, 0, len);
    sprintf(buffer, "%s=%s", key, value);
    result = putenv(buffer);
    free(buffer);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<line_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %edx,-0xc8(%rbp)
  mov    %rcx,-0xd8(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L23
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L23:
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <do_msg@plt>
  test   %rax,%rax
  je     L6
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xc8(%rbp),%esi
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <msg_primitive@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x1,-0xc4(%rbp)
  jle    L6
  mov    $0x0,%eax
  call   <record_error@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
void line_message(int severity, const char *fname, int line, const char *fmt, ...) {
  if (do_msg(severity)) {
    va_list ap;
    va_start(ap, fmt);
    msg_primitive(fname, line, fmt, ap);
    va_end(ap);
    if (severity >= 2)
      record_error();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<line_message>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %rcx,%rbp
  call   <do_msg@plt>
  test   %rax,%rax
  jne    L7
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    %rbp,%rsi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <msg_primitive@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  cmp    $0x1,%ebx
  jle    L6
  mov    $0x0,%eax
  call   <record_error@plt>
  jmp    L6
```

assistant: ```c
void line_message(int severity, const char *fname, int line, const char *fmt, ...) {
  if (do_msg(severity)) {
    va_list ap;
    va_start(ap, fmt);
    msg_primitive(fname, line, fmt, ap);
    va_end(ap);
    if (severity >= 2)
      record_error();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<line_message>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <do_msg@plt>
  test   %rax,%rax
  jne    L19
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r14d,%r14d
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  call   <msg_primitive@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  cmp    $0x1,%ebx
  jle    L0
  xor    %eax,%eax
  call   <record_error@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void line_message(int severity, const char *fname, int line, const char *fmt, ...) {
  if (do_msg(severity)) {
    va_list ap;
    va_start(ap, fmt);
    msg_primitive(fname, line, fmt, ap);
    va_end(ap);
    if (severity >= 2)
      record_error();
  }
}
```