user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D30(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x50(%rsp),%rbp
  mov    %r12,%rsi
  lea    0x90(%rsp),%r14
  call   <scanf@plt>
  lea    0xf(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D42(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  call   <index@plt>
  test   %eax,%eax
  je     L93
  jmp    L96
  nop
L56:
  movzbl 0x0(%rbp,%r15,1),%eax
L77:
  mov    %al,(%r14,%r15,1)
  add    $0x1,%r15
L93:
  mov    %r12,%rdi
  mov    %r15d,%r13d
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    %r15d,%ebx
  jle    L71
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jg     L56
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %eax,%r13d
  movslq %r13d,%r13
  movzbl 0x10(%rsp,%r13,1),%eax
  jmp    L77
L96:
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <index@plt>
  test   %eax,%eax
  jg     L65
  jmp    L121
  nopl   0x0(%rax)
L27:
  movzbl (%r12,%rbx,1),%eax
  mov    %al,(%r14,%rbx,1)
  add    $0x1,%rbx
L65:
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  call   <index@plt>
  cmp    %ebx,%eax
  jg     L27
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  mov    %rbp,%r15
  call   <index@plt>
  movslq %eax,%r13
  sub    %r13,%r15
  jmp    L92
  cs nopw 0x0(%rax,%rax,1)
L61:
  movzbl (%r15,%r13,1),%eax
  mov    %al,(%r14,%r13,1)
  add    $0x1,%r13
L92:
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  call   <index@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    %r13d,%ebx
  jg     L61
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  call   <index@plt>
  movsbl 0xf(%rsp),%esi
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <index@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  lea    0x0(%r13,%rax,1),%edx
  movslq %edx,%r13
  sub    %r13,%rbx
  lea    (%r12,%rbx,1),%r15
  jmp    L119
  nopl   0x0(%rax)
L94:
  movzbl (%r15,%r13,1),%eax
  mov    %al,(%r14,%r13,1)
  add    $0x1,%r13
L119:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  add    %eax,%ebx
  cmp    %r13d,%ebx
  jg     L94
L71:
  mov    %r14,%rsi
  lea    D42(%rip),%rdi
  call   <printf@plt>
L31:
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L121:
  mov    %r12,%rsi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D30
datatype: string
name: unpack_data
arguments: data_tag: D37
datatype: string
name: unpack_data
arguments: data_tag: D42
datatype: string

tool: D30: %s


tool: D37: %c


tool: D42: %s

assistant: ```c
int main() {
  char s1[50], s2[50], c1;
  scanf("%s\n", s1);
  scanf("%c\n", &c1);
  scanf("%s", s2);
  char s3[100];
  int i, j;
  if ((index(s1, c1)) == 0) {
    for (i = 0; i < (strlen(s1) + strlen(s2)); i++) {
      if (i < strlen(s2))
        s3[i] = s2[i];
      else
        s3[i] = s1[(i - strlen(s2))];
    }
    printf("%s", s3);
  } else if (index(s1, c1) > 0) {
    for (j = 0; j < index(s1, c1); j++) {
      s3[j] = s1[j];
    }
    int k = 0;
    for (j = index(s1, c1); j < (index(s1, c1) + strlen(s2)); j++) {
      s3[j] = s2[k];
      k++;
    }
    int l = index(s1, c1);
    for (j = (index(s1, c1) + strlen(s2)); j < (strlen(s1) + strlen(s2)); j++) {
      s3[j] = s1[l];
      l++;
    }
    printf("%s", s3);
  } else {
    printf("%s", s1);
  }
  return 0;
}
```