user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <getint@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L46
L8:
  mov    -0x38(%rbp),%eax
  cltq
  movl   $0x1,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
L46:
  cmpl   $0x9,-0x38(%rbp)
  jle    L8
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x3,-0x30(%rbp,%rax,4)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%esi
  mov    -0x34(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  lea    (%rsi,%rax,1),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%esi
  mov    -0x24(%rbp),%edx
  mov    -0x34(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %edx,%ecx
  imul   %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %ecx,%edx
  sub    %eax,%edx
  mov    -0x34(%rbp),%eax
  lea    (%rsi,%rax,1),%ecx
  movslq %edx,%rax
  mov    %ecx,-0x30(%rbp,%rax,4)
  movl   $0x0,-0x38(%rbp)
  jmp    L48
L0:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x38(%rbp)
L48:
  cmpl   $0x9,-0x38(%rbp)
  jle    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int s[10];
  int a;
  a = getint();
  a = a % 10;
  i = 0;
  while (i < 10) {
    s[i] = 1;
    i = i + 1;
  }
  s[3] = a;
  s[a] = 3;
  s[(s[(a + s[3]) % 10] * s[a]) % 10] = s[(s[a] + s[a * 2 % 10]) % 10] + a;
  i = 0;
  while (i < 10) {
    putint(s[i]);
    putchar(10);
    i = i + 1;
  }
  return 0;
}
```