ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<arithmetic_byte_add>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <assert@plt>
  test   %rbx,%rbx
  je     L1
  lea    0x0(%rbp,%r12,1),%esi
  xor    %eax,%eax
  mov    %sil,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  pop    %rbx
  mov    $0x2,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int arithmetic_byte_add(unsigned char a, unsigned char b, unsigned char *p_result) {
  assert(p_result);
  unsigned int err_code = 0;
  if (!p_result) {
    err_code = 2;
    goto end;
  }
  *p_result = (a + b);
end:
  return err_code;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arithmetic_byte_add>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  call   <assert@plt>
  test   %rbx,%rbx
  je     L9
  lea    0x0(%rbp,%r12,1),%esi
  xor    %eax,%eax
  mov    %sil,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  pop    %rbx
  mov    $0x2,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int arithmetic_byte_add(unsigned char a, unsigned char b, unsigned char *p_result) {
  assert(p_result);
  unsigned int err_code = 0;
  if (!p_result) {
    err_code = 2;
    goto end;
  }
  *p_result = (a + b);
end:
  return err_code;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vecadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x28(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vecadd(double *x, const double *y, double a, size_t n) {
  int k;
  for (k = 0; k < n; k++) {
    x[k] += a * y[k];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vecadd>:
  endbr64
  test   %rdx,%rdx
  je     L12
  shl    $0x3,%rdx
  mov    $0x0,%eax
L5:
  movapd %xmm0,%xmm1
  mulsd  (%rsi,%rax,1),%xmm1
  addsd  (%rdi,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L5
L12:
  ret
```

assistant: ```c
void vecadd(double *x, const double *y, double a, size_t n) {
  int k;
  for (k = 0; k < n; k++) {
    x[k] += a * y[k];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vecadd>:
  endbr64
  test   %rdx,%rdx
  je     L19
  shl    $0x3,%rdx
  xor    %eax,%eax
  nop
L14:
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rdi,%rax,1),%xmm1
  movsd  %xmm1,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rdx
  jne    L14
L19:
  ret
```

assistant: ```c
void vecadd(double *x, const double *y, double a, size_t n) {
  int k;
  for (k = 0; k < n; k++) {
    x[k] += a * y[k];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vecadd>:
  endbr64
  mov    %rdi,%rcx
  test   %rdx,%rdx
  je     L1
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L57
  cmp    $0x1,%rdx
  je     L57
  mov    %rdx,%rdi
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  shr    %rdi
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L58:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm3
  mulpd  %xmm2,%xmm1
  addpd  %xmm3,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L58
  mov    %rdx,%rdi
  and    $0xfffffffffffffffe,%rdi
  and    $0x1,%edx
  je     L1
  mulsd  (%rsi,%rdi,8),%xmm0
  lea    (%rcx,%rdi,8),%rax
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
  ret
  nopl   (%rax)
L57:
  shl    $0x3,%rdx
  xor    %eax,%eax
  xchg   %ax,%ax
L43:
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L43
L1:
  ret
```

assistant: ```c
void vecadd(double *x, const double *y, double a, size_t n) {
  int k;
  for (k = 0; k < n; k++) {
    x[k] += a * y[k];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<videoram_put_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  add    $0x13,%rax
  mov    %rax,-0x28(%rbp)
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
L23:
  mov    -0x38(%rbp),%rax
  and    $0xf,%eax
  mov    %al,-0x29(%rbp)
  mov    -0x38(%rbp),%rax
  shr    $0x4,%rax
  mov    %rax,-0x38(%rbp)
  cmpb   $0x9,-0x29(%rbp)
  jg     L7
  mov    $0x30,%edx
  jmp    L16
L7:
  mov    $0x37,%edx
L16:
  movzbl -0x29(%rbp),%eax
  add    %edx,%eax
  subq   $0x1,-0x28(%rbp)
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  cmpq   $0x0,-0x38(%rbp)
  jne    L23
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x78,(%rax)
  subq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movb   $0x30,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <videoram_put@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void videoram_put_hex(unsigned long v) {
  char s[2 + 2 * sizeof v + 1];
  char *p = &s[sizeof s];
  *--p = 0;
  do {
    char c = v % 16;
    v /= 16;
    *--p = c + (c < 10 ? '0' : 'A' - 10);
  } while (v > 0);
  *--p = 'x';
  *--p = '0';
  videoram_put(p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<videoram_put_hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x12(%rsp)
  lea    0x12(%rsp),%rdx
  mov    $0x30,%r9d
  mov    $0x37,%r8d
L12:
  mov    %edi,%eax
  and    $0xf,%eax
  mov    %rdi,%rcx
  shr    $0x4,%rdi
  cmp    $0xa,%al
  mov    %r8d,%esi
  cmovl  %r9d,%esi
  sub    $0x1,%rdx
  add    %esi,%eax
  mov    %al,(%rdx)
  cmp    $0xf,%rcx
  ja     L12
  movb   $0x78,-0x1(%rdx)
  movb   $0x30,-0x2(%rdx)
  lea    -0x2(%rdx),%rdi
  call   <videoram_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void videoram_put_hex(unsigned long v) {
  char s[2 + 2 * sizeof v + 1];
  char *p = &s[sizeof s];
  *--p = 0;
  do {
    char c = v % 16;
    v /= 16;
    *--p = c + (c < 10 ? '0' : 'A' - 10);
  } while (v > 0);
  *--p = 'x';
  *--p = '0';
  videoram_put(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<videoram_put_hex>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x30,%r9d
  mov    $0x37,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x12(%rsp)
  lea    0x12(%rsp),%rdx
  xchg   %ax,%ax
L17:
  mov    %edi,%eax
  mov    %rdi,%rcx
  mov    %r8d,%esi
  shr    $0x4,%rdi
  and    $0xf,%eax
  cmp    $0xa,%al
  cmovl  %r9d,%esi
  sub    $0x1,%rdx
  add    %esi,%eax
  mov    %al,(%rdx)
  cmp    $0xf,%rcx
  ja     L17
  movb   $0x78,-0x1(%rdx)
  lea    -0x2(%rdx),%rdi
  movb   $0x30,-0x2(%rdx)
  call   <videoram_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void videoram_put_hex(unsigned long v) {
  char s[2 + 2 * sizeof v + 1];
  char *p = &s[sizeof s];
  *--p = 0;
  do {
    char c = v % 16;
    v /= 16;
    *--p = c + (c < 10 ? '0' : 'A' - 10);
  } while (v > 0);
  *--p = 'x';
  *--p = '0';
  videoram_put(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<videoram_put_hex>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x12(%rsp),%rdx
  movb   $0x0,0x12(%rsp)
  jmp    L16
  nopl   0x0(%rax)
L31:
  add    $0x30,%eax
  mov    %al,(%rdx)
  cmp    $0xf,%rdi
  jbe    L25
L15:
  mov    %rcx,%rdi
L16:
  mov    %edi,%eax
  mov    %rdi,%rcx
  sub    $0x1,%rdx
  and    $0xf,%eax
  shr    $0x4,%rcx
  cmp    $0x9,%al
  jle    L31
  add    $0x37,%eax
  mov    %al,(%rdx)
  cmp    $0xf,%rdi
  ja     L15
L25:
  movb   $0x78,-0x1(%rdx)
  lea    -0x2(%rdx),%rdi
  movb   $0x30,-0x2(%rdx)
  call   <videoram_put@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x28,%rsp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void videoram_put_hex(unsigned long v) {
  char s[2 + 2 * sizeof v + 1];
  char *p = &s[sizeof s];
  *--p = 0;
  do {
    char c = v % 16;
    v /= 16;
    *--p = c + (c < 10 ? '0' : 'A' - 10);
  } while (v > 0);
  *--p = 'x';
  *--p = '0';
  videoram_put(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stw_le_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0x1c(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stw_le_p(void *ptr, int v) {
  uint8_t *p = ptr;
  p[0] = v;
  p[1] = v >> 8;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stw_le_p>:
  endbr64
  mov    %esi,(%rdi)
  sar    $0x8,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void stw_le_p(void *ptr, int v) {
  uint8_t *p = ptr;
  p[0] = v;
  p[1] = v >> 8;
}
```
user: What is the c source code of the assembly code below?

```asm
<stw_le_p>:
  endbr64
  mov    %esi,(%rdi)
  sar    $0x8,%esi
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void stw_le_p(void *ptr, int v) {
  uint8_t *p = ptr;
  p[0] = v;
  p[1] = v >> 8;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stw_le_p>:
  endbr64
  mov    %esi,%eax
  movd   %esi,%xmm0
  sar    $0x8,%eax
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi)
  ret
```

assistant: ```c
void stw_le_p(void *ptr, int v) {
  uint8_t *p = ptr;
  p[0] = v;
  p[1] = v >> 8;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_str_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L8:
  cmpl   $0x0,-0x4(%rbp)
  je     L48
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
L48:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <print_str@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x9,-0x4(%rbp)
  ja     L35
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
L35:
  cmpl   $0xa,-0x4(%rbp)
  jne    L53
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L53
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
L53:
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D21
data_type: string

tool: D4: {

tool: D19: , 

tool: D14: , ...

tool: D21: }

assistant: ```c
void print_str_array(char **strs) {
  unsigned i;
  print("{");
  for (i = 0; i < 10 && strs[i]; i++) {
    if (i > 0)
      print(", ");
    print_str(strs[i]);
  }
  if (i == 10 && strs[i - 1])
    print(", ...");
  print("}");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_str_array>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  lea    D15(%rip),%rdi
  call   <print@plt>
  mov    %r13,%rbx
  mov    $0x1,%ebp
  lea    D0(%rip),%r14
  jmp    L68
L27:
  mov    %r14,%rdi
  call   <print@plt>
  mov    (%r12),%rdi
  call   <print_str@plt>
  cmp    $0x9,%ebp
  ja     L55
L53:
  add    $0x8,%rbx
  add    $0x1,%ebp
L68:
  lea    -0x1(%rbp),%eax
  mov    %rbx,%r12
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L6
  test   %eax,%eax
  jne    L27
  call   <print_str@plt>
  jmp    L53
L6:
  mov    %eax,%ebp
L55:
  cmp    $0xa,%ebp
  je     L39
L3:
  lea    D30(%rip),%rdi
  call   <print@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  cmpq   $0x0,0x48(%r13)
  je     L3
  lea    D2(%rip),%rdi
  call   <print@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: tag: D15
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D15: {

tool: D0: , 

tool: D30: }

tool: D2: , ...

assistant: ```c
void print_str_array(char **strs) {
  unsigned i;
  print("{");
  for (i = 0; i < 10 && strs[i]; i++) {
    if (i > 0)
      print(", ");
    print_str(strs[i]);
  }
  if (i == 10 && strs[i - 1])
    print(", ...");
  print("}");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_str_array>:
  endbr64
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D32(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <print@plt>
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L42:
  call   <print_str@plt>
L6:
  add    $0x1,%rbx
L0:
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L12
  test   %rbx,%rbx
  je     L42
  mov    %r12,%rdi
  call   <print@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <print_str@plt>
  cmp    $0x9,%ebx
  jne    L6
  cmpq   $0x0,0x48(%rbp)
  je     L12
  lea    D26(%rip),%rdi
  call   <print@plt>
L12:
  pop    %rbx
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <print@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D35
data_type: string
name: unpack_data
arguments: data_tag: D32
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D35: , 

tool: D32: {

tool: D26: , ...

tool: D7: }

assistant: ```c
void print_str_array(char **strs) {
  unsigned i;
  print("{");
  for (i = 0; i < 10 && strs[i]; i++) {
    if (i > 0)
      print(", ");
    print_str(strs[i]);
  }
  if (i == 10 && strs[i - 1])
    print(", ...");
  print("}");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_str_array>:
  endbr64
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D33(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <print@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L23:
  call   <print_str@plt>
L27:
  add    $0x1,%rbx
L6:
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L43
  test   %rbx,%rbx
  je     L23
  mov    %r12,%rdi
  call   <print@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <print_str@plt>
  cmp    $0x9,%ebx
  jne    L27
  cmpq   $0x0,0x48(%rbp)
  je     L43
  lea    D27(%rip),%rdi
  call   <print@plt>
L43:
  pop    %rbx
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <print@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type: string
name: extract_symbolic_data
arguments: label: D33
type: string
name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D15
type: string

tool: D26: , 

tool: D33: {

tool: D27: , ...

tool: D15: }

assistant: ```c
void print_str_array(char **strs) {
  unsigned i;
  print("{");
  for (i = 0; i < 10 && strs[i]; i++) {
    if (i > 0)
      print(", ");
    print_str(strs[i]);
  }
  if (i == 10 && strs[i - 1])
    print(", ...");
  print("}");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L4:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L4
  sub    $0x50,%rsp
  movss  %xmm0,-0x8024(%rbp)
  movss  %xmm1,-0x8028(%rbp)
  movss  %xmm2,-0x802c(%rbp)
  mov    %rdi,-0x8038(%rbp)
  mov    %rsi,-0x8040(%rbp)
  mov    %edx,-0x8030(%rbp)
  movss  %xmm3,-0x8044(%rbp)
  movss  %xmm4,-0x8048(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x8024(%rbp),%xmm0
  movss  %xmm0,-0x8010(%rbp)
  movss  -0x8028(%rbp),%xmm0
  movss  %xmm0,-0x800c(%rbp)
  movl   $0x2,-0x8014(%rbp)
  jmp    L44
L25:
  mov    -0x8014(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movss  -0x8010(%rbp,%rax,4),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x8044(%rbp),%xmm1
  movss  -0x802c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  mov    -0x8014(%rbp),%eax
  sub    $0x2,%eax
  cltq
  movss  -0x8010(%rbp,%rax,4),%xmm1
  mulss  -0x8048(%rbp),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8014(%rbp),%eax
  cltq
  movss  %xmm0,-0x8010(%rbp,%rax,4)
  addl   $0x1,-0x8014(%rbp)
L44:
  mov    -0x8030(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x8014(%rbp)
  jl     L25
  mov    -0x8030(%rbp),%eax
  sub    $0x2,%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8010(%rbp,%rax,4)
  mov    -0x8030(%rbp),%eax
  sub    $0x1,%eax
  cltq
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8010(%rbp,%rax,4)
  mov    -0x8030(%rbp),%eax
  sub    $0x3,%eax
  mov    %eax,-0x8014(%rbp)
  jmp    L55
L15:
  mov    -0x8014(%rbp),%eax
  cltq
  movss  -0x8010(%rbp,%rax,4),%xmm0
  mov    -0x8014(%rbp),%eax
  add    $0x1,%eax
  cltq
  movss  -0x8010(%rbp,%rax,4),%xmm1
  mulss  -0x8044(%rbp),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8014(%rbp),%eax
  add    $0x2,%eax
  cltq
  movss  -0x8010(%rbp,%rax,4),%xmm1
  mulss  -0x8048(%rbp),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8014(%rbp),%eax
  cltq
  movss  %xmm0,-0x8010(%rbp,%rax,4)
  subl   $0x1,-0x8014(%rbp)
L55:
  cmpl   $0x0,-0x8014(%rbp)
  jns    L15
  movss  -0x8010(%rbp),%xmm0
  mov    -0x8038(%rbp),%rax
  movss  %xmm0,(%rax)
  movss  -0x800c(%rbp),%xmm0
  mov    -0x8040(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
void rep(float v1, float v2, float c, float *i1, float *i2, int n, float a1, float a2) {
  int i;
  float lb[8192];
  lb[0] = v1;
  lb[1] = v2;
  for (i = 2; i < n - 2; i++) {
    lb[i] = c - a1 * lb[i - 1] - a2 * lb[i - 2];
  }
  lb[n - 2] = 0.0;
  lb[n - 1] = 0.0;
  for (i = n - 3; i >= 0; i--) {
    lb[i] = lb[i] - a1 * lb[i + 1] - a2 * lb[i + 2];
  }
  *i1 = lb[0];
  *i2 = lb[1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rep>:
  endbr64
  lea    -0x8000(%rsp),%r11
L55:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L55
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  movss  %xmm0,(%rsp)
  movss  %xmm1,0x4(%rsp)
  lea    -0x2(%rdx),%esi
  cmp    $0x2,%esi
  jle    L30
  mov    %rsp,%rax
  lea    -0x5(%rdx),%edx
  lea    0x4(%rsp,%rdx,4),%rdx
L46:
  movaps %xmm3,%xmm1
  mulss  0x4(%rax),%xmm1
  movaps %xmm2,%xmm0
  subss  %xmm1,%xmm0
  movaps %xmm4,%xmm1
  mulss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,0x8(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L46
L30:
  movslq %esi,%rsi
  movl   $0x0,(%rsp,%rsi,4)
  lea    -0x1(%rcx),%eax
  cltq
  movl   $0x0,(%rsp,%rax,4)
  cmp    $0x2,%ecx
  jle    L28
  movslq %ecx,%rdx
  shl    $0x2,%rdx
  lea    (%rsp,%rdx,1),%rax
  lea    -0x4(%rsp,%rdx,1),%rdx
  lea    -0x3(%rcx),%ecx
  shl    $0x2,%rcx
  sub    %rcx,%rdx
L4:
  movaps %xmm3,%xmm1
  mulss  -0x8(%rax),%xmm1
  movss  -0xc(%rax),%xmm0
  subss  %xmm1,%xmm0
  movaps %xmm4,%xmm1
  mulss  -0x4(%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rax)
  sub    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
L28:
  movss  (%rsp),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsp),%xmm0
  movss  %xmm0,(%r8)
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x8018,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rep(float v1, float v2, float c, float *i1, float *i2, int n, float a1, float a2) {
  int i;
  float lb[8192];
  lb[0] = v1;
  lb[1] = v2;
  for (i = 2; i < n - 2; i++) {
    lb[i] = c - a1 * lb[i - 1] - a2 * lb[i - 2];
  }
  lb[n - 2] = 0.0;
  lb[n - 1] = 0.0;
  for (i = n - 3; i >= 0; i--) {
    lb[i] = lb[i] - a1 * lb[i + 1] - a2 * lb[i + 2];
  }
  *i1 = lb[0];
  *i2 = lb[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rep>:
  endbr64
  lea    -0x8000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rdx),%r8d
  mov    %rdi,%rcx
  movss  %xmm0,(%rsp)
  mov    %edx,%edi
  movss  %xmm1,0x4(%rsp)
  cmp    $0x2,%r8d
  jle    L20
  lea    0x8(%rsp),%rax
  lea    -0x5(%rdx),%edx
  lea    (%rax,%rdx,4),%rdx
  jmp    L13
  nopl   0x0(%rax)
L22:
  movss  -0x4(%rax),%xmm0
  add    $0x4,%rax
L13:
  mulss  %xmm3,%xmm1
  movaps %xmm2,%xmm5
  mulss  %xmm4,%xmm0
  subss  %xmm1,%xmm5
  subss  %xmm0,%xmm5
  movaps %xmm5,%xmm1
  movss  %xmm5,(%rax)
  cmp    %rdx,%rax
  jne    L22
L20:
  lea    -0x1(%rdi),%eax
  movslq %r8d,%r8
  cltq
  movl   $0x0,(%rsp,%r8,4)
  movl   $0x0,(%rsp,%rax,4)
  cmp    $0x2,%edi
  jle    L31
  movslq %edi,%rdx
  sub    $0x3,%edi
  pxor   %xmm1,%xmm1
  shl    $0x2,%rdx
  shl    $0x2,%rdi
  lea    (%rsp,%rdx,1),%rax
  lea    -0x4(%rsp,%rdx,1),%rdx
  sub    %rdi,%rdx
  jmp    L19
  nopl   0x0(%rax)
L33:
  movss  -0x4(%rax),%xmm1
L19:
  movss  -0x8(%rax),%xmm2
  movss  -0xc(%rax),%xmm0
  mulss  %xmm4,%xmm1
  sub    $0x4,%rax
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rax)
  cmp    %rdx,%rax
  jne    L33
L31:
  movss  (%rsp),%xmm0
  movss  %xmm0,(%rcx)
  movss  0x4(%rsp),%xmm0
  movss  %xmm0,(%rsi)
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x8018,%rsp
  ret
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rep(float v1, float v2, float c, float *i1, float *i2, int n, float a1, float a2) {
  int i;
  float lb[8192];
  lb[0] = v1;
  lb[1] = v2;
  for (i = 2; i < n - 2; i++) {
    lb[i] = c - a1 * lb[i - 1] - a2 * lb[i - 2];
  }
  lb[n - 2] = 0.0;
  lb[n - 1] = 0.0;
  for (i = n - 3; i >= 0; i--) {
    lb[i] = lb[i] - a1 * lb[i + 1] - a2 * lb[i + 2];
  }
  *i1 = lb[0];
  *i2 = lb[1];
}
```
user: What is the c source code of the assembly code below?

```asm
<logical_iterator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %ax,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movw   $0x0,-0x6(%rbp)
  jmp    L28
L0:
  cmpl   $0x0,-0x18(%rbp)
  je     L35
  movzwl -0x6(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  setne  %al
  jmp    L38
L35:
  movzwl -0x6(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %al
L38:
  test   %al,%al
  je     L9
  cmpl   $0x0,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L9:
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x6(%rbp)
L28:
  movzwl -0x6(%rbp),%eax
  cmp    -0x24(%rbp),%ax
  jb     L0
L14:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
bool logical_iterator(bool initial_result, bool condition_matcher, bool *boolean_list, unsigned short array_size) {
  unsigned short i;
  bool result = initial_result;
  for (i = 0u; i < array_size; i++) {
    if (condition_matcher ? boolean_list[i] : !boolean_list[i]) {
      result = !initial_result;
      break;
    }
  }
  return result;
}
```