ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<insort_double>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  lea    0x8(%rdi),%r8
  mov    $0x1,%ecx
  jmp    L14
L15:
  movslq %edx,%rdx
  movsd  %xmm1,(%rdi,%rdx,8)
  add    $0x1,%ecx
  add    $0x8,%r8
  cmp    %ecx,%esi
  je     L11
L14:
  movsd  (%r8),%xmm1
  mov    %r8,%rax
  mov    %ecx,%edx
  test   %ecx,%ecx
  jle    L15
L58:
  movsd  -0x8(%rax),%xmm0
  comisd %xmm1,%xmm0
  jbe    L15
  movsd  %xmm0,(%rax)
  sub    $0x8,%rax
  sub    $0x1,%edx
  jne    L58
  jmp    L15
L11:
  ret
```

assistant: ```c
void insort_double(array, len) register double array[];
register int len;
{
  register int i, j;
  register double temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insort_double>:
  endbr64
  lea    0x8(%rdi),%rcx
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L29
  nopl   0x0(%rax,%rax,1)
L12:
  movsd  (%rcx),%xmm1
  mov    %rcx,%rax
  nop
L39:
  movsd  -0x8(%rax),%xmm0
  mov    %rax,%rdx
  comisd %xmm1,%xmm0
  jbe    L35
  movsd  %xmm0,(%rax)
  lea    -0x8(%rdx),%rax
  cmp    %rax,%rdi
  jne    L39
  mov    %rdi,%rdx
L35:
  add    $0x1,%r8d
  movsd  %xmm1,(%rdx)
  add    $0x8,%rcx
  cmp    %r8d,%esi
  jne    L12
L29:
  ret
```

assistant: ```c
void insort_double(array, len) register double array[];
register int len;
{
  register int i, j;
  register double temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<insort_double>:
  endbr64
  lea    0x8(%rdi),%rcx
  mov    $0x1,%r8d
  cmp    $0x1,%esi
  jle    L4
  nopl   0x0(%rax,%rax,1)
L34:
  movsd  (%rcx),%xmm1
  mov    %rcx,%rax
  nop
L18:
  movsd  -0x8(%rax),%xmm0
  mov    %rax,%rdx
  comisd %xmm1,%xmm0
  jbe    L29
  movsd  %xmm0,(%rax)
  lea    -0x8(%rdx),%rax
  cmp    %rdi,%rax
  jne    L18
  mov    %rdi,%rdx
L29:
  add    $0x1,%r8d
  movsd  %xmm1,(%rdx)
  add    $0x8,%rcx
  cmp    %r8d,%esi
  jne    L34
L4:
  ret
```

assistant: ```c
void insort_double(array, len) register double array[];
register int len;
{
  register int i, j;
  register double temp;
  for (i = 1; i < len; i++) {
    j = i;
    temp = array[j];
    while (j > 0 && ((array[j - 1]) > (temp))) {
      array[j] = array[j - 1];
      j--;
    }
    array[j] = temp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_full_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: string

tool: D4: ERROR READING FILE


assistant: ```c
void get_full_file(int file, char *return_string, int file_size) {
  int bytes_read;
  bytes_read = read(file, return_string, sizeof(char) * file_size);
  if (bytes_read < 0) {
    printf("ERROR READING FILE\n");
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_full_file>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L18
L8:
  add    $0x8,%rsp
  ret
L18:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: ERROR READING FILE


assistant: ```c
void get_full_file(int file, char *return_string, int file_size) {
  int bytes_read;
  bytes_read = read(file, return_string, sizeof(char) * file_size);
  if (bytes_read < 0) {
    printf("ERROR READING FILE\n");
    exit(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_full_file>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L3
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: ERROR READING FILE


assistant: ```c
void get_full_file(int file, char *return_string, int file_size) {
  int bytes_read;
  bytes_read = read(file, return_string, sizeof(char) * file_size);
  if (bytes_read < 0) {
    printf("ERROR READING FILE\n");
    exit(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_full_file>:
  endbr64
  sub    $0x8,%rsp
  call   <read@plt>
  test   %eax,%eax
  js     L3
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D7: ERROR READING FILE


assistant: ```c
void get_full_file(int file, char *return_string, int file_size) {
  int bytes_read;
  bytes_read = read(file, return_string, sizeof(char) * file_size);
  if (bytes_read < 0) {
    printf("ERROR READING FILE\n");
    exit(1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fd_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %edx,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%ecx
  mov    -0x130(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x114(%rbp)
  movb   $0x0,-0x11(%rbp)
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rcx
  mov    -0x124(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writen_ni@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int fd_vprintf(int fd, const char *format, va_list ap) {
  char buf[256];
  int len;
  len = vsnprintf(buf, sizeof(buf), format, ap);
  buf[sizeof(buf) - 1] = '\0';
  return writen_ni(fd, buf, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fd_vprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%ebx
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rsi,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%edx
  movb   $0x0,0xff(%rsp)
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <writen_ni@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_vprintf(int fd, const char *format, va_list ap) {
  char buf[256];
  int len;
  len = vsnprintf(buf, sizeof(buf), format, ap);
  buf[sizeof(buf) - 1] = '\0';
  return writen_ni(fd, buf, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fd_vprintf>:
  endbr64
  push   %r12
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0x0,0xff(%rsp)
  mov    %eax,%edx
  call   <writen_ni@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_vprintf(int fd, const char *format, va_list ap) {
  char buf[256];
  int len;
  len = vsnprintf(buf, sizeof(buf), format, ap);
  buf[sizeof(buf) - 1] = '\0';
  return writen_ni(fd, buf, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fd_vprintf>:
  endbr64
  push   %r12
  mov    %edx,%ecx
  mov    %rsi,%rdx
  mov    $0x100,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  movb   $0x0,0xff(%rsp)
  mov    %eax,%edx
  call   <writen_ni@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fd_vprintf(int fd, const char *format, va_list ap) {
  char buf[256];
  int len;
  len = vsnprintf(buf, sizeof(buf), format, ap);
  buf[sizeof(buf) - 1] = '\0';
  return writen_ni(fd, buf, len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L1:
  shlb   -0x5(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L28
  orb    $0x1,-0x5(%rbp)
L28:
  shrb   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x7,-0x4(%rbp)
  jle    L1
  movzbl -0x5(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char bitswap(unsigned char c) {
  unsigned char r = 0;
  int i;
  for (i = 0; i < 8; i++) {
    r <<= 1;
    if (c & 1)
      r |= 1;
    c >>= 1;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitswap>:
  endbr64
  mov    $0x8,%edx
  mov    $0x0,%eax
L4:
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x1,%dil
  cmovne %ecx,%eax
  shr    %dil
  sub    $0x1,%edx
  jne    L4
  ret
```

assistant: ```c
unsigned char bitswap(unsigned char c) {
  unsigned char r = 0;
  int i;
  for (i = 0; i < 8; i++) {
    r <<= 1;
    if (c & 1)
      r |= 1;
    c >>= 1;
  }
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitswap>:
  endbr64
  mov    $0x8,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x1,%dil
  cmovne %ecx,%eax
  shr    %dil
  sub    $0x1,%edx
  jne    L5
  ret
```

assistant: ```c
unsigned char bitswap(unsigned char c) {
  unsigned char r = 0;
  int i;
  for (i = 0; i < 8; i++) {
    r <<= 1;
    if (c & 1)
      r |= 1;
    c >>= 1;
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitswap>:
  endbr64
  mov    %edi,%eax
  and    $0x1,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x2,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x4,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x8,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x10,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x20,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   $0x40,%dil
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  or     $0x1,%ecx
  test   %dil,%dil
  cmovs  %ecx,%eax
  ret
```

assistant: ```c
unsigned char bitswap(unsigned char c) {
  unsigned char r = 0;
  int i;
  for (i = 0; i < 8; i++) {
    r <<= 1;
    if (c & 1)
      r |= 1;
    c >>= 1;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x2a,(%rax)
  mov    -0x14(%rbp),%eax
  cmp    $0x2a,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int a = 10;
  int *p = &a;
  *p = 42;
  assert(a == 42);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 10;
  int *p = &a;
  *p = 42;
  assert(a == 42);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 10;
  int *p = &a;
  *p = 42;
  assert(a == 42);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 10;
  int *p = &a;
  *p = 42;
  assert(a == 42);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x94(%rbp)
  jne    L5
  mov    -0xa0(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0xa0(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D19: Usage: %s argument


tool: D15: %s

assistant: ```c
int main(int argc, char *argv[]) {
  char buf[128];
  if (argc == 1) {
    printf("Usage: %s argument\n", argv[0]);
    exit(1);
  }
  strcpy(buf, argv[1]);
  printf("%s", buf);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L16
L24:
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  ret
L16:
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D6
type: string

tool: D3: %s

tool: D6: Usage: %s argument


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[128];
  if (argc == 1) {
    printf("Usage: %s argument\n", argv[0]);
    exit(1);
  }
  strcpy(buf, argv[1]);
  printf("%s", buf);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L27
L15:
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    (%rsi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type: string
name: read_data
arguments: label: D8
type: string

tool: D7: %s

tool: D8: Usage: %s argument


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[128];
  if (argc == 1) {
    printf("Usage: %s argument\n", argv[0]);
    exit(1);
  }
  strcpy(buf, argv[1]);
  printf("%s", buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L22
L13:
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    (%rsi),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L13
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D5
type: string

tool: D0: %s

tool: D5: Usage: %s argument


assistant: ```c
int main(int argc, char *argv[]) {
  char buf[128];
  if (argc == 1) {
    printf("Usage: %s argument\n", argv[0]);
    exit(1);
  }
  strcpy(buf, argv[1]);
  printf("%s", buf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wordvcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L33
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L37
L33:
  mov    $0xffffffff,%eax
  jmp    L39
L37:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    -0x4(%rbp),%eax
  jmp    L39
L13:
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    $0x0,%eax
L39:
  leave
  ret
```

assistant: ```c
int wordvcmp(char **wordv1, int wordc, char **wordv2) {
  int i;
  int back;
  for (i = 0; i < wordc; i++) {
    if (wordv1[i] == NULL || wordv2[i] == NULL)
      return (-1);
    if ((back = strcmp(wordv1[i], wordv2[i])) != 0)
      return (back);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wordvcmp>:
  endbr64
  test   %esi,%esi
  jle    L67
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L21:
  mov    (%r12,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L0
  mov    0x0(%r13,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L2
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L50
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L21
  jmp    L50
L67:
  mov    $0x0,%eax
  ret
L0:
  mov    $0xffffffff,%eax
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L50
```

assistant: ```c
int wordvcmp(char **wordv1, int wordc, char **wordv2) {
  int i;
  int back;
  for (i = 0; i < wordc; i++) {
    if (wordv1[i] == NULL || wordv2[i] == NULL)
      return (-1);
    if ((back = strcmp(wordv1[i], wordv2[i])) != 0)
      return (back);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wordvcmp>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nop
L12:
  mov    0x0(%r13,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L9
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L21
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L21
L8:
  mov    (%r12,%rbx,8),%rdi
  test   %rdi,%rdi
  jne    L12
L9:
  mov    $0xffffffff,%eax
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wordvcmp(char **wordv1, int wordc, char **wordv2) {
  int i;
  int back;
  for (i = 0; i < wordc; i++) {
    if (wordv1[i] == NULL || wordv2[i] == NULL)
      return (-1);
    if ((back = strcmp(wordv1[i], wordv2[i])) != 0)
      return (back);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wordvcmp>:
  endbr64
  test   %esi,%esi
  jle    L48
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L45
  nop
L49:
  mov    0x0(%r13,%rbx,8),%rsi
  test   %rsi,%rsi
  je     L54
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L28
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L28
L45:
  mov    (%r12,%rbx,8),%rdi
  test   %rdi,%rdi
  jne    L49
L54:
  mov    $0xffffffff,%eax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wordvcmp(char **wordv1, int wordc, char **wordv2) {
  int i;
  int back;
  for (i = 0; i < wordc; i++) {
    if (wordv1[i] == NULL || wordv2[i] == NULL)
      return (-1);
    if ((back = strcmp(wordv1[i], wordv2[i])) != 0)
      return (back);
  }
  return (0);
}
```