user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%r13
  cltd
  imul   $0x68db8bad,%r13,%r13
  sar    $0x2c,%r13
  sub    %edx,%r13d
  imul   $0x2710,%r13d,%edx
  sub    %edx,%eax
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <rand@plt>
  lea    0x1(%r13),%ebx
  lea    D14(%rip),%rdi
  movslq %eax,%r14
  cltd
  mov    %ebx,%esi
  imul   $0x68db8bad,%r14,%r14
  sar    $0x2c,%r14
  sub    %edx,%r14d
  imul   $0x2710,%r14d,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%r15d
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r15d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  je     L23
  xor    %r12d,%r12d
  xchg   %ax,%ax
L26:
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ebx
  and    $0x1,%ebx
  sub    %edx,%ebx
  cmp    $0xffffffff,%ebx
  je     L48
L31:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  lea    0x61(%rax),%edi
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L48
  mov    $0x1,%ebp
  jmp    L31
  nop
L48:
  mov    $0x20,%edi
  xor    %ebp,%ebp
  call   <putchar@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ebx
  and    $0x1,%ebx
  sub    %edx,%ebx
  cmp    $0xffffffff,%ebx
  je     L1
L67:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x4ec4ec4f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  imul   $0x1a,%edx,%edx
  sub    %edx,%eax
  lea    0x61(%rax),%edi
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jle    L1
  mov    $0x1,%ebp
  jmp    L67
  nopl   0x0(%rax)
L1:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%r12),%rax
  cmp    %r12,%r13
  je     L23
  mov    %rax,%r12
  jmp    L26
  nopl   0x0(%rax)
L23:
  test   %r15d,%r15d
  jne    L39
L117:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    $0x1a,%ebx
L54:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  lea    0x61(%rdx),%edi
  call   <putchar@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r14d
  jae    L54
  jmp    L117
```

tool_calls: name: disassemble_data
arguments: tag: D14
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string

tool: D14: %d 

tool: D6: %d


assistant: ```c
int main() {
  int i, j, c, len, num, temp, t, res, q;
  srand(time(NULL));
  int r;
  t = rand() % 10000 + 1;
  q = rand() % 10000 + 1;
  printf("%d ", t);
  printf("%d\n", q);
  while (t--) {
    len = rand() % 2 + 1;
    for (i = 0; i < len; i++) {
      r = rand() % 26;
      printf("%c", 'a' + r);
    }
    printf(" ");
    len = rand() % 2 + 1;
    for (i = 0; i < len; i++) {
      r = rand() % 26;
      printf("%c", 'a' + r);
    }
    printf("\n");
  }
  while (q--) {
    len = 1;
    for (i = 0; i < len; i++) {
      r = rand() % 26;
      printf("%c", 'a' + r);
    }
    printf("\n");
  }
  return 0;
}
```