ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<OS_StrIsNum>:
  endbr64
  test   %rdi,%rdi
  jne    L0
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L26:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L23
  add    $0x1,%rdi
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int OS_StrIsNum(char *str) {
  if (str == NULL)
    return (0);
  while (*str != '\0') {
    if (!((*str >= 48) && (*str <= 57)))
      return (0);
    str++;
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<OS_StrIsNum>:
  endbr64
  test   %rdi,%rdi
  jne    L36
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L26:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L8
  add    $0x1,%rdi
L36:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int OS_StrIsNum(char *str) {
  if (str == NULL)
    return (0);
  while (*str != '\0') {
    if (!((*str >= 48) && (*str <= 57)))
      return (0);
    str++;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string

tool: D24: 


tool: D21: %d 

assistant: ```c
void printArray(int *arr, int n) {
  printf("\n\n");
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printArray>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D23(%rip),%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L12
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D16(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
L12:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D16
type: string

tool: D23: 


tool: D16: %d 

assistant: ```c
void printArray(int *arr, int n) {
  printf("\n\n");
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printArray>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  lea    D9(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
L0:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D9
type_guessed: string

tool: D7: 


tool: D9: %d 

assistant: ```c
void printArray(int *arr, int n) {
  printf("\n\n");
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printArray>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L3
  lea    -0x1(%rbp),%eax
  lea    D13(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   (%rax)
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
L3:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D13
data_type: string

tool: D16: 


tool: D13: %d 

assistant: ```c
void printArray(int *arr, int n) {
  printf("\n\n");
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_to_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L31
L6:
  mov    $0x0,%eax
  jmp    L15
L31:
  mov    -0xc(%rbp),%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
data_type: string

tool: D9: %u

assistant: ```c
unsigned str_to_uint(const char *str) {
  unsigned n;
  if (!str || sscanf(str, "%u", &n) != 1)
    return 0;
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str_to_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  lea    0x4(%rsp),%rdx
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmove  0x4(%rsp),%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %u

assistant: ```c
unsigned str_to_uint(const char *str) {
  unsigned n;
  if (!str || sscanf(str, "%u", &n) != 1)
    return 0;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_to_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L34
  lea    0x4(%rsp),%rdx
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L9
L34:
  xor    %eax,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x4(%rsp),%eax
  jmp    L12
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %u

assistant: ```c
unsigned str_to_uint(const char *str) {
  unsigned n;
  if (!str || sscanf(str, "%u", &n) != 1)
    return 0;
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_to_uint>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L39
  lea    0x4(%rsp),%rdx
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L2
L39:
  xor    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x4(%rsp),%eax
  jmp    L13
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: %u

assistant: ```c
unsigned str_to_uint(const char *str) {
  unsigned n;
  if (!str || sscanf(str, "%u", &n) != 1)
    return 0;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mymemcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  je     L9
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L74
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L68:
  subq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L68
  jmp    L35
L74:
  movl   $0x0,-0x4(%rbp)
  jmp    L49
L56:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L49:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L56
  jmp    L35
L9:
  nop
L35:
  pop    %rbp
  ret
```

assistant: ```c
void mymemcpy(target, source, count) char *target;
char *source;
int count;
{
  int ii;
  if (target == source)
    return;
  if (target > source) {
    target += count;
    source += count;
    for (ii = 0; ii < count; ++ii) {
      --source;
      --target;
      *target = *source;
    }
  } else
    for (ii = 0; ii < count; ++ii)
      *target++ = *source++;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mymemcpy>:
  endbr64
  cmp    %rsi,%rdi
  je     L56
  ja     L8
  mov    %edx,%ecx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L57
L19:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L19
L56:
  ret
L57:
  ret
L8:
  movslq %edx,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  jle    L56
  lea    -0x1(%rdx),%eax
  mov    $0xfffffffffffffffe,%rcx
  sub    %rax,%rcx
  mov    $0xffffffffffffffff,%rax
L2:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L2
  ret
```

assistant: ```c
void mymemcpy(target, source, count) char *target;
char *source;
int count;
{
  int ii;
  if (target == source)
    return;
  if (target > source) {
    target += count;
    source += count;
    for (ii = 0; ii < count; ++ii) {
      --source;
      --target;
      *target = *source;
    }
  } else
    for (ii = 0; ii < count; ++ii)
      *target++ = *source++;
}
```
user: What is the c source code of the assembly code below:

```asm
<mymemcpy>:
  endbr64
  cmp    %rsi,%rdi
  je     L10
  jbe    L21
  movslq %edx,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  test   %edx,%edx
  jle    L10
  lea    -0x1(%rdx),%eax
  mov    $0xfffffffffffffffe,%rcx
  sub    %rax,%rcx
  mov    $0xffffffffffffffff,%rax
  nopl   0x0(%rax)
L48:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %rax,%rcx
  jne    L48
  ret
  nopl   0x0(%rax)
L21:
  movslq %edx,%rcx
  xor    %eax,%eax
  test   %edx,%edx
  jle    L24
  nopl   0x0(%rax)
L53:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L53
L10:
  ret
  nopl   0x0(%rax)
L24:
  ret
```

assistant: ```c
void mymemcpy(target, source, count) char *target;
char *source;
int count;
{
  int ii;
  if (target == source)
    return;
  if (target > source) {
    target += count;
    source += count;
    for (ii = 0; ii < count; ++ii) {
      --source;
      --target;
      *target = *source;
    }
  } else
    for (ii = 0; ii < count; ++ii)
      *target++ = *source++;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mymemcpy>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%r8
  cmp    %rsi,%rdi
  je     L170
  ja     L105
  test   %edx,%edx
  jle    L119
  lea    0x1(%r8),%r9
  mov    %edx,%esi
  lea    -0x1(%rdx),%ecx
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L8
  cmp    $0x6,%ecx
  jbe    L8
  cmp    $0xe,%ecx
  jbe    L7
  shr    $0x4,%esi
  xor    %ecx,%ecx
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L166:
  movdqu (%r8,%rcx,1),%xmm0
  movups %xmm0,(%rax,%rcx,1)
  add    $0x10,%rcx
  cmp    %rsi,%rcx
  jne    L166
  mov    %edx,%ecx
  and    $0xfffffff0,%ecx
  mov    %ecx,%edi
  lea    (%rax,%rdi,1),%r9
  lea    (%r8,%rdi,1),%r10
  cmp    %ecx,%edx
  je     L170
  mov    %edx,%esi
  sub    %ecx,%esi
  lea    -0x1(%rsi),%r11d
  cmp    $0x6,%r11d
  jbe    L42
L189:
  mov    (%r8,%rdi,1),%r8
  mov    %r8,(%rax,%rdi,1)
  mov    %esi,%eax
  and    $0xfffffff8,%eax
  mov    %eax,%edi
  add    %eax,%ecx
  add    %rdi,%r9
  add    %rdi,%r10
  cmp    %eax,%esi
  je     L170
L42:
  movzbl (%r10),%eax
  mov    %al,(%r9)
  lea    0x1(%rcx),%eax
  cmp    %eax,%edx
  jle    L170
  movzbl 0x1(%r10),%eax
  mov    %al,0x1(%r9)
  lea    0x2(%rcx),%eax
  cmp    %eax,%edx
  jle    L170
  movzbl 0x2(%r10),%eax
  mov    %al,0x2(%r9)
  lea    0x3(%rcx),%eax
  cmp    %eax,%edx
  jle    L170
  movzbl 0x3(%r10),%eax
  mov    %al,0x3(%r9)
  lea    0x4(%rcx),%eax
  cmp    %eax,%edx
  jle    L170
  movzbl 0x4(%r10),%eax
  mov    %al,0x4(%r9)
  lea    0x5(%rcx),%eax
  cmp    %eax,%edx
  jle    L170
  movzbl 0x5(%r10),%eax
  add    $0x6,%ecx
  mov    %al,0x5(%r9)
  cmp    %ecx,%edx
  jle    L170
  movzbl 0x6(%r10),%eax
  mov    %al,0x6(%r9)
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %edx,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L184:
  movzbl (%r8,%rcx,1),%esi
  mov    %sil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L184
L170:
  ret
  nopl   0x0(%rax,%rax,1)
L105:
  movslq %edx,%rcx
  lea    (%rdi,%rcx,1),%rdi
  add    %rsi,%rcx
  test   %edx,%edx
  jle    L170
  lea    -0x1(%rdx),%eax
  mov    $0xfffffffffffffffe,%rsi
  sub    %rax,%rsi
  mov    $0xffffffffffffffff,%rax
  nopw   0x0(%rax,%rax,1)
L103:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jne    L103
  ret
  nopl   0x0(%rax)
L119:
  ret
L7:
  mov    %r8,%r10
  mov    %rax,%r9
  xor    %ecx,%ecx
  xor    %edi,%edi
  jmp    L189
```

assistant: ```c
void mymemcpy(target, source, count) char *target;
char *source;
int count;
{
  int ii;
  if (target == source)
    return;
  if (target > source) {
    target += count;
    source += count;
    for (ii = 0; ii < count; ++ii) {
      --source;
      --target;
      *target = *source;
    }
  } else
    for (ii = 0; ii < count; ++ii)
      *target++ = *source++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncmp_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L9
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L15
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  jmp    L13
L15:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L13:
  leave
  ret
```

assistant: ```c
int strncmp_suffix(const char *str1, const char *str2, size_t n) {
  size_t len1 = strlen(str1);
  size_t len2 = strlen(str2);
  if (len1 > n)
    len1 = n;
  if (len2 <= len1)
    return strcmp(str1 + len1 - len2, str2);
  else
    return strcmp(str1, str2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r13,%rbx
  cmova  %r13,%rbx
  cmp    %rbx,%rax
  ja     L3
  sub    %rax,%rbx
  lea    (%r12,%rbx,1),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  jmp    L2
```

assistant: ```c
int strncmp_suffix(const char *str1, const char *str2, size_t n) {
  size_t len1 = strlen(str1);
  size_t len2 = strlen(str2);
  if (len1 > n)
    len1 = n;
  if (len2 <= len1)
    return strcmp(str1 + len1 - len2, str2);
  else
    return strcmp(str1, str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncmp_suffix>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %r13,%rbx
  cmova  %r13,%rbx
  cmp    %rbx,%rax
  ja     L1
  add    $0x8,%rsp
  sub    %rax,%rbx
  mov    %r12,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcmp@plt>
  nopl   (%rax)
L1:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcmp@plt>
```

assistant: ```c
int strncmp_suffix(const char *str1, const char *str2, size_t n) {
  size_t len1 = strlen(str1);
  size_t len2 = strlen(str2);
  if (len1 > n)
    len1 = n;
  if (len2 <= len1)
    return strcmp(str1 + len1 - len2, str2);
  else
    return strcmp(str1, str2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncmp_suffix>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %r13,%rbx
  cmova  %r13,%rbx
  cmp    %rbx,%rax
  ja     L3
  add    $0x8,%rsp
  sub    %rax,%rbx
  mov    %r12,%rsi
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcmp@plt>
  nopl   (%rax)
L3:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <strcmp@plt>
```

assistant: ```c
int strncmp_suffix(const char *str1, const char *str2, size_t n) {
  size_t len1 = strlen(str1);
  size_t len2 = strlen(str2);
  if (len1 > n)
    len1 = n;
  if (len2 <= len1)
    return strcmp(str1 + len1 - len2, str2);
  else
    return strcmp(str1, str2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_closure_dmg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <get_closure@plt>
  mov    -0x38(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <count_of_dim@plt>
  mov    %eax,%r13d
  mov    -0x38(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <count_of_dim@plt>
  mov    %eax,%r12d
  mov    -0x38(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <count_of_dim@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%ecx
  mov    -0x30(%rbp),%rax
  mov    $0x3,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <count_of_dim@plt>
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %r13d,%r9d
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rcx
  mov    $0xc,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L27
L25:
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  sub    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print_object_dmg@plt>
  addl   $0x1,-0x34(%rbp)
L27:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jb     L25
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  add    $0x38,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string
name: parse_data
arguments: label: D14
datatype: string

tool: D2: %u %u %u %u


tool: D14: 0 0 0
0 0 0


assistant: ```c
void print_closure_dmg(FILE *f, struct object *obj) {
  struct object **closure;
  unsigned closure_size;
  get_closure(obj, 0, &closure, &closure_size);
  fprintf(f, "%u %u %u %u\n", count_of_dim(closure, closure_size, 3), count_of_dim(closure, closure_size, 2), count_of_dim(closure, closure_size, 1), count_of_dim(closure, closure_size, 0));
  fprintf(f, "0 0 0\n0 0 0\n");
  for (unsigned i = 0; i < closure_size; ++i)
    print_object_dmg(f, closure[closure_size - i - 1]);
  free(closure);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_closure_dmg>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    $0x0,%esi
  call   <get_closure@plt>
  mov    $0x0,%edx
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <count_of_dim@plt>
  mov    %eax,%r13d
  mov    $0x1,%edx
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <count_of_dim@plt>
  mov    %eax,%r12d
  mov    $0x2,%edx
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <count_of_dim@plt>
  mov    %eax,%ebx
  mov    $0x3,%edx
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <count_of_dim@plt>
  mov    %eax,%edx
  mov    %r13d,%r9d
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbp,%rcx
  mov    $0xc,%edx
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <fwrite@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L4
  mov    $0x0,%ebx
L22:
  sub    %ebx,%eax
  lea    -0x1(%rax),%edx
  mov    0x10(%rsp),%rax
  mov    (%rax,%rdx,8),%rsi
  mov    %rbp,%rdi
  call   <print_object_dmg@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  ja     L22
L4:
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D5: %u %u %u %u


tool: D16: 0 0 0
0 0 0


assistant: ```c
void print_closure_dmg(FILE *f, struct object *obj) {
  struct object **closure;
  unsigned closure_size;
  get_closure(obj, 0, &closure, &closure_size);
  fprintf(f, "%u %u %u %u\n", count_of_dim(closure, closure_size, 3), count_of_dim(closure, closure_size, 2), count_of_dim(closure, closure_size, 1), count_of_dim(closure, closure_size, 0));
  fprintf(f, "0 0 0\n0 0 0\n");
  for (unsigned i = 0; i < closure_size; ++i)
    print_object_dmg(f, closure[closure_size - i - 1]);
  free(closure);
}
```