ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movabs $0x3837363534333231,%rax
  mov    %rax,-0x2b(%rbp)
  movw   $0x4139,-0x23(%rbp)
  movb   $0x0,-0x21(%rbp)
L3:
  lea    -0x2b(%rbp),%rax
  mov    %rax,%rdi
  call   <is_magic@plt>
  test   %rax,%rax
  je     L43
  lea    -0x2b(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <get_representation@plt>
  mov    %rax,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L43
  lea    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L43
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L43:
  lea    -0x2b(%rbp),%rax
  mov    %rax,%rdi
  call   <next_permutation@plt>
  test   %rax,%rax
  jne    L3
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: %s


assistant: ```c
int main(void) {
  char representation[16 + 1] = "";
  char digits[] = "123456789A";
  do {
    if (is_magic(digits)) {
      char *r_ptr = get_representation(digits, 16);
      if (r_ptr && strcmp(r_ptr, representation) > 0)
        strcpy(representation, r_ptr);
    }
  } while (next_permutation(digits));
  printf("%s\n", representation);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  movabs $0x3837363534333231,%rax
  mov    %rax,0x5(%rsp)
  movw   $0x4139,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0x5(%rsp),%rbx
  jmp    L44
L27:
  mov    %rbx,%rdi
  call   <next_permutation@plt>
  test   %rax,%rax
  je     L23
L44:
  mov    %rbx,%rdi
  call   <is_magic@plt>
  test   %rax,%rax
  je     L27
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <get_representation@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  lea    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L27
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  jmp    L27
L23:
  lea    0x10(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s


assistant: ```c
int main(void) {
  char representation[16 + 1] = "";
  char digits[] = "123456789A";
  do {
    if (is_magic(digits)) {
      char *r_ptr = get_representation(digits, 16);
      if (r_ptr && strcmp(r_ptr, representation) > 0)
        strcpy(representation, r_ptr);
    }
  } while (next_permutation(digits));
  printf("%s\n", representation);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbx
  movb   $0x0,0x20(%rsp)
  movabs $0x3837363534333231,%rax
  mov    %rax,0x5(%rsp)
  mov    $0x4139,%eax
  lea    0x10(%rsp),%r12
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x10(%rsp)
  jmp    L53
  nopl   0x0(%rax)
L49:
  mov    %rbx,%rdi
  call   <next_permutation@plt>
  test   %rax,%rax
  je     L67
L53:
  mov    %rbx,%rdi
  call   <is_magic@plt>
  test   %rax,%rax
  je     L49
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <get_representation@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L49
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L49
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L49
  nopl   0x0(%rax)
L67:
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D4: %s


assistant: ```c
int main(void) {
  char representation[16 + 1] = "";
  char digits[] = "123456789A";
  do {
    if (is_magic(digits)) {
      char *r_ptr = get_representation(digits, 16);
      if (r_ptr && strcmp(r_ptr, representation) > 0)
        strcpy(representation, r_ptr);
    }
  } while (next_permutation(digits));
  printf("%s\n", representation);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbx
  movb   $0x0,0x20(%rsp)
  movabs $0x3837363534333231,%rax
  mov    %rax,0x5(%rsp)
  mov    $0x4139,%eax
  lea    0x10(%rsp),%r12
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x10(%rsp)
  jmp    L25
  nopl   0x0(%rax)
L65:
  mov    %rbx,%rdi
  call   <next_permutation@plt>
  test   %rax,%rax
  je     L43
L25:
  mov    %rbx,%rdi
  call   <is_magic@plt>
  test   %rax,%rax
  je     L65
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <get_representation@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L65
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L65
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L65
  nopl   0x0(%rax)
L43:
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %s


assistant: ```c
int main(void) {
  char representation[16 + 1] = "";
  char digits[] = "123456789A";
  do {
    if (is_magic(digits)) {
      char *r_ptr = get_representation(digits, 16);
      if (r_ptr && strcmp(r_ptr, representation) > 0)
        strcpy(representation, r_ptr);
    }
  } while (next_permutation(digits));
  printf("%s\n", representation);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x2c(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L4
L10:
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  sub    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  add    %rax,-0x10(%rbp)
L4:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L10
  mov    -0x30(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D4: %d%d

tool: D16: %lld%lld%lld

tool: D5: %lld

assistant: ```c
int main() {
  int n, m;
  long long int count = 0;
  scanf("%d%d", &n, &m);
  while (m--) {
    long long int a, b, k;
    scanf("%lld%lld%lld", &a, &b, &k);
    count = count + (b - a + 1) * k;
  }
  printf("%lld", (count / n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L37
  mov    $0x0,%ebx
  lea    D15(%rip),%rbp
L35:
  lea    0x20(%rsp),%rcx
  lea    0x18(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rdx
  sub    0x10(%rsp),%rdx
  add    $0x1,%rdx
  imul   0x20(%rsp),%rdx
  add    %rdx,%rbx
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L35
L9:
  movslq 0x8(%rsp),%rcx
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    $0x0,%ebx
  jmp    L9
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D9
type: string

tool: D16: %d%d

tool: D15: %lld%lld%lld

tool: D9: %lld

assistant: ```c
int main() {
  int n, m;
  long long int count = 0;
  scanf("%d%d", &n, &m);
  while (m--) {
    long long int a, b, k;
    scanf("%lld%lld%lld", &a, &b, &k);
    count = count + (b - a + 1) * k;
  }
  printf("%lld", (count / n));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L7
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D22(%rip),%rbp
  nopl   (%rax)
L23:
  mov    %r13,%rdx
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rdx
  sub    0x10(%rsp),%rdx
  add    $0x1,%rdx
  imul   0x20(%rsp),%rdx
  mov    0xc(%rsp),%eax
  add    %rdx,%rbx
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L23
L7:
  mov    %rbx,%rax
  movslq 0x8(%rsp),%rcx
  lea    D27(%rip),%rdi
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string

tool: D4: %d%d

tool: D22: %lld%lld%lld

tool: D27: %lld

assistant: ```c
int main() {
  int n, m;
  long long int count = 0;
  scanf("%d%d", &n, &m);
  while (m--) {
    long long int a, b, k;
    scanf("%lld%lld%lld", &a, &b, &k);
    count = count + (b - a + 1) * k;
  }
  printf("%lld", (count / n));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L8
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D12(%rip),%rbp
  nopl   (%rax)
L16:
  mov    %r13,%rdx
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x18(%rsp),%rdx
  sub    0x10(%rsp),%rdx
  add    $0x1,%rdx
  imul   0x20(%rsp),%rdx
  mov    0xc(%rsp),%eax
  add    %rdx,%rbx
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L16
L8:
  mov    %rbx,%rax
  movslq 0x8(%rsp),%rcx
  lea    D20(%rip),%rdi
  cqto
  idiv   %rcx
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D13: %d%d

tool: D12: %lld%lld%lld

tool: D20: %lld

assistant: ```c
int main() {
  int n, m;
  long long int count = 0;
  scanf("%d%d", &n, &m);
  while (m--) {
    long long int a, b, k;
    scanf("%lld%lld%lld", &a, &b, &k);
    count = count + (b - a + 1) * k;
  }
  printf("%lld", (count / n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_floats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L0
L61:
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <read_word@plt>
  mov    %rax,-0x48(%rbp)
  lea    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <to_float@plt>
  test   %rax,%rax
  je     L58
  mov    $0xffffffff,%eax
  jmp    L86
L58:
  cmpq   $0x0,-0x48(%rbp)
  je     L85
  addl   $0x1,-0x34(%rbp)
L0:
  mov    -0x34(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jb     L61
  jmp    L16
L65:
  nop
  jmp    L16
L85:
  nop
L16:
  mov    -0x34(%rbp),%eax
L86:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int read_floats(const char *str, float *buf, unsigned int size) {
  unsigned int w;
  for (w = 0; w < size; w++) {
    char word[32];
    str = read_word(word, (sizeof(word) / sizeof(*word)), str);
    if (strlen(word) == 0)
      break;
    if (to_float(word, &buf[w]))
      return -1;
    if (str == NULL)
      break;
  }
  return w;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_floats>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L25
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %rsp,%r13
L48:
  mov    %rbx,%rdx
  mov    $0x20,%esi
  mov    %r13,%rdi
  call   <read_word@plt>
  mov    %rax,%rbx
  cmpb   $0x0,(%rsp)
  je     L60
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <to_float@plt>
  test   %rax,%rax
  jne    L9
  test   %rbx,%rbx
  je     L60
  add    $0x1,%r12d
  add    $0x4,%rbp
  cmp    %r12d,%r14d
  jne    L48
  jmp    L25
L9:
  mov    $0xffffffff,%eax
  jmp    L27
L60:
  mov    %r12d,%r14d
L25:
  mov    %r14d,%eax
L27:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L62
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_floats(const char *str, float *buf, unsigned int size) {
  unsigned int w;
  for (w = 0; w < size; w++) {
    char word[32];
    str = read_word(word, (sizeof(word) / sizeof(*word)), str);
    if (strlen(word) == 0)
      break;
    if (to_float(word, &buf[w]))
      return -1;
    if (str == NULL)
      break;
  }
  return w;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_floats>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L93
  mov    %rdi,%r12
  mov    %edx,%r14d
  mov    %rsi,%rbx
  xor    %ebp,%ebp
  mov    %rsp,%r13
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <to_float@plt>
  test   %rax,%rax
  jne    L91
  test   %r12,%r12
  je     L4
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r14d
  je     L16
L57:
  mov    %r12,%rdx
  mov    $0x20,%esi
  mov    %r13,%rdi
  call   <read_word@plt>
  cmpb   $0x0,(%rsp)
  mov    %rax,%r12
  jne    L26
L4:
  mov    %ebp,%eax
L39:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L91:
  mov    $0xffffffff,%eax
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r14d,%eax
  jmp    L39
L93:
  xor    %eax,%eax
  jmp    L39
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_floats(const char *str, float *buf, unsigned int size) {
  unsigned int w;
  for (w = 0; w < size; w++) {
    char word[32];
    str = read_word(word, (sizeof(word) / sizeof(*word)), str);
    if (strlen(word) == 0)
      break;
    if (to_float(word, &buf[w]))
      return -1;
    if (str == NULL)
      break;
  }
  return w;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_floats>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L90
  mov    %rdi,%r12
  mov    %edx,%r14d
  mov    %rsi,%rbx
  xor    %ebp,%ebp
  mov    %rsp,%r13
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <to_float@plt>
  test   %rax,%rax
  jne    L99
  test   %r12,%r12
  je     L31
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,%r14d
  je     L53
L21:
  mov    %r12,%rdx
  mov    $0x20,%esi
  mov    %r13,%rdi
  call   <read_word@plt>
  cmpb   $0x0,(%rsp)
  mov    %rax,%r12
  jne    L8
L31:
  mov    %ebp,%eax
L39:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L99:
  mov    $0xffffffff,%eax
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %r14d,%eax
  jmp    L39
L90:
  xor    %eax,%eax
  jmp    L39
L74:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_floats(const char *str, float *buf, unsigned int size) {
  unsigned int w;
  for (w = 0; w < size; w++) {
    char word[32];
    str = read_word(word, (sizeof(word) / sizeof(*word)), str);
    if (strlen(word) == 0)
      break;
    if (to_float(word, &buf[w]))
      return -1;
    if (str == NULL)
      break;
  }
  return w;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_real_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <initialize_string@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realpath@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_real_path(char *variable, const char *stipulated_path) {
  initialize_string(variable);
  realpath(stipulated_path, variable);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<set_real_path>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <initialize_string@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <realpath@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_real_path(char *variable, const char *stipulated_path) {
  initialize_string(variable);
  realpath(stipulated_path, variable);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set_real_path>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <initialize_string@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <realpath@plt>
```

assistant: ```c
void set_real_path(char *variable, const char *stipulated_path) {
  initialize_string(variable);
  realpath(stipulated_path, variable);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_real_path>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <initialize_string@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <realpath@plt>
```

assistant: ```c
void set_real_path(char *variable, const char *stipulated_path) {
  initialize_string(variable);
  realpath(stipulated_path, variable);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_128_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_128_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_128_0_1>:
  endbr64
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_128_0_1>:
  endbr64
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xrop3_128_0_1>:
  endbr64
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_128_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T & S;
  stk1 = D & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```