ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<bit_entry_64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L104
  lea    -0x1(%rsi),%ebp
  xor    %r14d,%r14d
  cmp    $0x3f,%ebp
  jbe    L61
L35:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L104:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L61:
  mov    %rcx,%r13
  mov    %rdi,%rbx
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %ebp,%ecx
  test   %eax,%eax
  je     L35
  sub    $0x1,%eax
  mov    %rbx,%rdx
  lea    D4(%rip),%r8
  mov    $0x1,%r9d
  lea    0x1(%rbx,%rax,1),%rdi
  nopl   0x0(%rax)
L45:
  movzbl (%rdx),%eax
  lea    -0x7b(%rax),%esi
  and    $0xfd,%esi
  je     L93
  sub    $0x9,%eax
  cmp    $0x28,%al
  ja     L104
  movzbl %al,%eax
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  shl    %cl,%eax
  sub    $0x1,%ecx
  not    %eax
  and    %eax,(%r12)
  and    %eax,0x0(%r13)
  nopw   0x0(%rax,%rax,1)
L93:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L45
L10:
  xor    %r14d,%r14d
  cmp    $0xffffffff,%ecx
  sete   %r14b
  jmp    L35
  nopl   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x1,%ecx
  or     %eax,(%r12)
  or     %eax,0x0(%r13)
  cmp    %rdx,%rdi
  jne    L45
  jmp    L10
  nopl   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x1,%ecx
  mov    %eax,%esi
  not    %esi
  and    %esi,(%r12)
  or     %eax,0x0(%r13)
  cmp    %rdx,%rdi
  jne    L45
  jmp    L10
```

assistant: ```c
int bit_entry_64(const char *token, int bits, uint64_t *data, uint64_t *mask) {
  do {
    unsigned int count = 0;
    unsigned int index;
    int buf_index;
    if (token == NULL)
      return 0;
    if ((bits > 64) || (bits < 1))
      return 0;
    count = strlen(token);
    buf_index = bits - 1;
    for (index = 0; index < count; index++) {
      if ((token[index] == '{') || (token[index] == '}')) {
      } else if ((token[index] == ' ') || (token[index] == '\t')) {
      } else if (token[index] == '0') {
        *data &= ~(1 << buf_index);
        *mask |= (1 << buf_index);
        buf_index--;
      } else if (token[index] == '1') {
        *data |= (1 << buf_index);
        *mask |= (1 << buf_index);
        buf_index--;
      } else if ((token[index] == '-') || (token[index] == '*')) {
        *data &= ~(1 << buf_index);
        *mask &= ~(1 << buf_index);
        buf_index--;
      } else {
        return 0;
      };
    };
    if (buf_index != -1)
      return 0;
    return 1;
  } while (0);
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bit_entry_64>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L34
  lea    -0x1(%rsi),%ebp
  xor    %r14d,%r14d
  cmp    $0x3f,%ebp
  jbe    L59
L90:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L59:
  mov    %rcx,%r13
  mov    %rdi,%rbx
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %ebp,%ecx
  test   %eax,%eax
  je     L90
  sub    $0x1,%eax
  mov    %rbx,%rdx
  lea    D2(%rip),%r8
  mov    $0x1,%r9d
  lea    0x1(%rbx,%rax,1),%rdi
  nopl   0x0(%rax)
L53:
  movzbl (%rdx),%eax
  lea    -0x7b(%rax),%esi
  and    $0xfd,%esi
  je     L103
  sub    $0x9,%eax
  cmp    $0x28,%al
  ja     L34
  movzbl %al,%eax
  movslq (%r8,%rax,4),%rax
  add    %r8,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  shl    %cl,%eax
  sub    $0x1,%ecx
  not    %eax
  and    %eax,(%r12)
  and    %eax,0x0(%r13)
  nopw   0x0(%rax,%rax,1)
L103:
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L53
L77:
  xor    %r14d,%r14d
  cmp    $0xffffffff,%ecx
  sete   %r14b
  jmp    L90
  nopl   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x1,%ecx
  or     %eax,(%r12)
  or     %eax,0x0(%r13)
  cmp    %rdx,%rdi
  jne    L53
  jmp    L77
  nopl   0x0(%rax,%rax,1)
  mov    %r9d,%eax
  add    $0x1,%rdx
  shl    %cl,%eax
  sub    $0x1,%ecx
  mov    %eax,%esi
  not    %esi
  and    %esi,(%r12)
  or     %eax,0x0(%r13)
  cmp    %rdx,%rdi
  jne    L53
  jmp    L77
```

assistant: ```c
int bit_entry_64(const char *token, int bits, uint64_t *data, uint64_t *mask) {
  do {
    unsigned int count = 0;
    unsigned int index;
    int buf_index;
    if (token == NULL)
      return 0;
    if ((bits > 64) || (bits < 1))
      return 0;
    count = strlen(token);
    buf_index = bits - 1;
    for (index = 0; index < count; index++) {
      if ((token[index] == '{') || (token[index] == '}')) {
      } else if ((token[index] == ' ') || (token[index] == '\t')) {
      } else if (token[index] == '0') {
        *data &= ~(1 << buf_index);
        *mask |= (1 << buf_index);
        buf_index--;
      } else if (token[index] == '1') {
        *data |= (1 << buf_index);
        *mask |= (1 << buf_index);
        buf_index--;
      } else if ((token[index] == '-') || (token[index] == '*')) {
        *data &= ~(1 << buf_index);
        *mask &= ~(1 << buf_index);
        buf_index--;
      } else {
        return 0;
      };
    };
    if (buf_index != -1)
      return 0;
    return 1;
  } while (0);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numerical_suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L51
L54:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L20
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L20
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  nop
L1:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L49
L20:
  addq   $0x1,-0x18(%rbp)
L51:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jge    L54
L49:
  leave
  ret
```

assistant: ```c
char *numerical_suffix(char *name) {
  long i, len;
  len = strlen(name);
  i = 0;
  while (i < (len + 1)) {
    if ((name[i] == '.') && isdigit(name[i + 1])) {
      char *suffix = &name[i + 1];
      name = suffix;
      while (isdigit(*name++))
        ;
      *(name - 1) = 0;
      return suffix;
    } else
      i++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<numerical_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x1(%rbp),%rbx
  jmp    L39
L33:
  add    $0x1,%rbx
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    $0x1,%rax
  cmp    %rax,%r12
  jl     L14
L39:
  mov    %rbx,%r13
  cmpb   $0x2e,-0x1(%rbx)
  jne    L33
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L33
L45:
  mov    %rbx,%rbp
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L45
  movb   $0x0,0x0(%rbp)
L14:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *numerical_suffix(char *name) {
  long i, len;
  len = strlen(name);
  i = 0;
  while (i < (len + 1)) {
    if ((name[i] == '.') && isdigit(name[i + 1])) {
      char *suffix = &name[i + 1];
      name = suffix;
      while (isdigit(*name++))
        ;
      *(name - 1) = 0;
      return suffix;
    } else
      i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numerical_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rbp),%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  jmp    L5
  nop
L4:
  add    $0x1,%rbx
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    $0x1,%rax
  cmp    %rax,%r12
  jl     L13
L5:
  cmpb   $0x2e,-0x1(%rbx)
  mov    %rbx,%r13
  jne    L4
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L4
  nopl   0x0(%rax)
L7:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L7
  movb   $0x0,0x0(%rbp)
L13:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *numerical_suffix(char *name) {
  long i, len;
  len = strlen(name);
  i = 0;
  while (i < (len + 1)) {
    if ((name[i] == '.') && isdigit(name[i + 1])) {
      char *suffix = &name[i + 1];
      name = suffix;
      while (isdigit(*name++))
        ;
      *(name - 1) = 0;
      return suffix;
    } else
      i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<numerical_suffix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%rbp),%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%r12
  jmp    L48
  nop
L1:
  add    $0x1,%rbx
  mov    %rbx,%rax
  sub    %rbp,%rax
  sub    $0x1,%rax
  cmp    %r12,%rax
  jg     L28
L48:
  cmpb   $0x2e,-0x1(%rbx)
  mov    %rbx,%r13
  jne    L1
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L1
  nopl   0x0(%rax)
L39:
  mov    %rbx,%rbp
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  movb   $0x0,0x0(%rbp)
L28:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *numerical_suffix(char *name) {
  long i, len;
  len = strlen(name);
  i = 0;
  while (i < (len + 1)) {
    if ((name[i] == '.') && isdigit(name[i + 1])) {
      char *suffix = &name[i + 1];
      name = suffix;
      while (isdigit(*name++))
        ;
      *(name - 1) = 0;
      return suffix;
    } else
      i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getInfo>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    D17(%rip),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  test   %rbp,%rbp
  je     L23
  cmp    %r12d,%ebx
  jle    L14
L23:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %ebx,%edx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  jmp    L23
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D17: info { name=Lfo }

assistant: ```c
int getInfo(char *buf, int bufLen) {
  static const char *INFO = "info { name=Lfo }";
  int reqLen = strlen(INFO) + 1;
  if (buf != 0 && reqLen <= bufLen) {
    memcpy(buf, INFO, reqLen);
  }
  return reqLen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getInfo>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  test   %rbp,%rbp
  je     L13
  cmp    %ebx,%r12d
  jle    L4
L13:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L4:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: info { name=Lfo }

assistant: ```c
int getInfo(char *buf, int bufLen) {
  static const char *INFO = "info { name=Lfo }";
  int reqLen = strlen(INFO) + 1;
  if (buf != 0 && reqLen <= bufLen) {
    memcpy(buf, INFO, reqLen);
  }
  return reqLen;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getInfo>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  test   %rbp,%rbp
  je     L1
  cmp    %ebx,%r12d
  jle    L5
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L5:
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: info { name=Lfo }

assistant: ```c
int getInfo(char *buf, int bufLen) {
  static const char *INFO = "info { name=Lfo }";
  int reqLen = strlen(INFO) + 1;
  if (buf != 0 && reqLen <= bufLen) {
    memcpy(buf, INFO, reqLen);
  }
  return reqLen;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmatrix_eye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L42
L34:
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L44:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L15
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L58
L15:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L58:
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  addl   $0x1,-0x10(%rbp)
L42:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: f64

tool: D0: 1

assistant: ```c
void cmatrix_eye(double *m, int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      double val;
      if (i == j) {
        val = 1.0;
      } else {
        val = 0.0;
      }
      m[(((i)*n) + (j))] = val;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<cmatrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L41
  movslq %esi,%r8
  shl    $0x3,%r8
  mov    $0x0,%edx
  mov    %esi,%ecx
  movsd  D7(%rip),%xmm1
  pxor   %xmm2,%xmm2
  jmp    L16
L65:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L44
L8:
  movapd %xmm1,%xmm0
  cmp    %eax,%edx
  je     L65
  movapd %xmm2,%xmm0
  jmp    L65
L44:
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %edx,%esi
  je     L41
L16:
  mov    $0x0,%eax
  jmp    L8
L41:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type: f64

tool: D7: 1

assistant: ```c
void cmatrix_eye(double *m, int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      double val;
      if (i == j) {
        val = 1.0;
      } else {
        val = 0.0;
      }
      m[(((i)*n) + (j))] = val;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmatrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L37
  movslq %esi,%rcx
  movsd  D2(%rip),%xmm1
  xor    %edx,%edx
  pxor   %xmm2,%xmm2
  lea    0x0(,%rcx,8),%r8
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  movapd %xmm1,%xmm0
  cmp    %eax,%edx
  je     L38
  movapd %xmm2,%xmm0
L38:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L24
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %edx,%esi
  jne    L7
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: f64

tool: D2: 1

assistant: ```c
void cmatrix_eye(double *m, int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      double val;
      if (i == j) {
        val = 1.0;
      } else {
        val = 0.0;
      }
      m[(((i)*n) + (j))] = val;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmatrix_eye>:
  endbr64
  test   %esi,%esi
  jle    L27
  movslq %esi,%rcx
  movsd  D4(%rip),%xmm0
  xor    %edx,%edx
  lea    0x0(,%rcx,8),%r8
  nopl   (%rax)
L63:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %eax,%edx
  je     L33
  movq   $0x0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L36
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %edx,%esi
  jne    L63
L27:
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L36
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %edx,%esi
  jne    L63
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: f64

tool: D4: 1

assistant: ```c
void cmatrix_eye(double *m, int n) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      double val;
      if (i == j) {
        val = 1.0;
      } else {
        val = 0.0;
      }
      m[(((i)*n) + (j))] = val;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L7
  mov    -0x4(%rbp),%eax
  add    $0x20,%eax
  jmp    L2
L7:
  mov    -0x4(%rbp),%eax
L2:
  leave
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c))
    return c - ('A' - 'a');
  else
    return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tolower>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <isupper@plt>
  mov    %rax,%rdx
  lea    0x20(%rbx),%eax
  test   %rdx,%rdx
  cmovne %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c))
    return c - ('A' - 'a');
  else
    return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tolower>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <isupper@plt>
  mov    %rax,%r8
  lea    0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c))
    return c - ('A' - 'a');
  else
    return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tolower>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <isupper@plt>
  mov    %rax,%r8
  lea    0x20(%r12),%eax
  test   %r8,%r8
  cmovne %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int tolower(int c) {
  if (isupper(c))
    return c - ('A' - 'a');
  else
    return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strToUpper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  cmpb   $0x0,-0x1(%rbp)
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void strToUpper(char *str) {
  char c;
  do {
    c = *(str);
    *(str++) = toupper(c);
  } while (c != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strToUpper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
L8:
  movzbl (%rbx),%ebp
  movsbl %bpl,%edi
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  test   %bpl,%bpl
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strToUpper(char *str) {
  char c;
  do {
    c = *(str);
    *(str++) = toupper(c);
  } while (c != 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strToUpper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L2:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  mov    %edi,%ebp
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  test   %bpl,%bpl
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strToUpper(char *str) {
  char c;
  do {
    c = *(str);
    *(str++) = toupper(c);
  } while (c != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strToUpper>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L8:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  mov    %edi,%ebp
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  test   %bpl,%bpl
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void strToUpper(char *str) {
  char c;
  do {
    c = *(str);
    *(str++) = toupper(c);
  } while (c != 0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <heapifyUp@plt>
  nop
  leave
  ret
```

assistant: ```c
void add(int *pq, int *cap, int val) {
  pq[*cap] = val;
  *cap = *cap + 1;
  heapifyUp(pq, *cap - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  sub    $0x8,%rsp
  movslq (%rsi),%rax
  mov    %edx,(%rdi,%rax,4)
  mov    (%rsi),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%rsi)
  mov    %eax,%esi
  call   <heapifyUp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void add(int *pq, int *cap, int val) {
  pq[*cap] = val;
  *cap = *cap + 1;
  heapifyUp(pq, *cap - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add>:
  endbr64
  movslq (%rsi),%rax
  mov    %edx,(%rdi,%rax,4)
  mov    (%rsi),%r8d
  lea    0x1(%r8),%eax
  mov    %eax,(%rsi)
  mov    %r8d,%esi
  jmp    1050 <heapifyUp@plt>
```

assistant: ```c
void add(int *pq, int *cap, int val) {
  pq[*cap] = val;
  *cap = *cap + 1;
  heapifyUp(pq, *cap - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<add>:
  endbr64
  movslq (%rsi),%rax
  mov    %edx,(%rdi,%rax,4)
  mov    (%rsi),%r8d
  lea    0x1(%r8),%eax
  mov    %eax,(%rsi)
  mov    %r8d,%esi
  jmp    1050 <heapifyUp@plt>
```

assistant: ```c
void add(int *pq, int *cap, int val) {
  pq[*cap] = val;
  *cap = *cap + 1;
  heapifyUp(pq, *cap - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CompareContigPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L8
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L32
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L32
L8:
  mov    $0xffffffff,%eax
  jmp    L22
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L1
  mov    $0x0,%eax
  jmp    L22
L1:
  mov    $0x1,%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int CompareContigPos(int32_t contigOne, int32_t positionOne, int32_t contigTwo, int32_t positionTwo) {
  if (contigOne < contigTwo || (contigOne == contigTwo && positionOne < positionTwo)) {
    return -1;
  } else if (contigOne == contigTwo && positionOne == positionTwo) {
    return 0;
  } else {
    return 1;
  }
}
```