ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <square@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %f


assistant: ```c
int main() {
  int a = 13;
  double b = square(a);
  printf("%f\n", b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <square@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %f


assistant: ```c
int main() {
  int a = 13;
  double b = square(a);
  printf("%f\n", b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%edi
  call   <square@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %f


assistant: ```c
int main() {
  int a = 13;
  double b = square(a);
  printf("%f\n", b);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L20
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L57
L20:
  movl   $0x1bb,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jle    L28
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoull@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L28
  movl   $0x1bb,-0x4(%rbp)
L28:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <VMISSL_Init@plt>
  test   %rax,%rax
  je     L49
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L58
L49:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L58:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <VMISSL_CheckAlive@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <VMISSL_Release@plt>
  mov    $0x0,%eax
L57:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D27: %s servip [servport]


tool: D6: init failed

tool: D8: init ok

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("%s servip [servport]\n", argv[0]);
    return 0;
  }
  int port = 443;
  if (argc > 2) {
    port = strtoull(argv[2], NULL, 0);
    if (port < 1)
      port = 443;
  }
  if (VMISSL_Init(NULL, NULL) != 0) {
    printf("init failed\n");
  } else {
    printf("init ok\n");
  }
  VMISSL_CheckAlive(argv[1], port);
  VMISSL_Release(NULL, NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L48
  mov    $0x1bb,%ebp
  cmp    $0x2,%edi
  jg     L12
L41:
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <VMISSL_Init@plt>
  test   %rax,%rax
  je     L47
  lea    D16(%rip),%rdi
  call   <puts@plt>
L29:
  mov    0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <VMISSL_CheckAlive@plt>
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <VMISSL_Release@plt>
L25:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L12:
  mov    0x10(%rsi),%rdi
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtoull@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L41
  mov    $0x1bb,%ebp
  jmp    L41
L47:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: label: D16
data_type: string
name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D0
data_type: string

tool: D16: init failed

tool: D6: %s servip [servport]


tool: D0: init ok

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("%s servip [servport]\n", argv[0]);
    return 0;
  }
  int port = 443;
  if (argc > 2) {
    port = strtoull(argv[2], NULL, 0);
    if (port < 1)
      port = 443;
  }
  if (VMISSL_Init(NULL, NULL) != 0) {
    printf("init failed\n");
  } else {
    printf("init ok\n");
  }
  VMISSL_CheckAlive(argv[1], port);
  VMISSL_Release(NULL, NULL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L43
  cmp    $0x2,%edi
  jne    L23
L40:
  mov    $0x1bb,%ebp
L38:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <VMISSL_Init@plt>
  test   %rax,%rax
  jne    L54
  lea    D9(%rip),%rdi
  call   <puts@plt>
L11:
  mov    0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <VMISSL_CheckAlive@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <VMISSL_Release@plt>
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L54:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L11
L23:
  mov    0x10(%rsi),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L38
  jmp    L40
L43:
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D9: init ok

tool: D3: init failed

tool: D7: %s servip [servport]


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("%s servip [servport]\n", argv[0]);
    return 0;
  }
  int port = 443;
  if (argc > 2) {
    port = strtoull(argv[2], NULL, 0);
    if (port < 1)
      port = 443;
  }
  if (VMISSL_Init(NULL, NULL) != 0) {
    printf("init failed\n");
  } else {
    printf("init ok\n");
  }
  VMISSL_CheckAlive(argv[1], port);
  VMISSL_Release(NULL, NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L44
  cmp    $0x2,%edi
  jne    L29
L35:
  mov    $0x1bb,%ebp
L54:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <VMISSL_Init@plt>
  test   %rax,%rax
  jne    L69
  lea    D16(%rip),%rdi
  call   <puts@plt>
L6:
  mov    0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <VMISSL_CheckAlive@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <VMISSL_Release@plt>
L41:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L69:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L29:
  mov    0x10(%rsi),%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoull@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L54
  jmp    L35
L44:
  mov    (%rsi),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L41
```

tool_calls: name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string

tool: D16: init ok

tool: D13: init failed

tool: D20: %s servip [servport]


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("%s servip [servport]\n", argv[0]);
    return 0;
  }
  int port = 443;
  if (argc > 2) {
    port = strtoull(argv[2], NULL, 0);
    if (port < 1)
      port = 443;
  }
  if (VMISSL_Init(NULL, NULL) != 0) {
    printf("init failed\n");
  } else {
    printf("init ok\n");
  }
  VMISSL_CheckAlive(argv[1], port);
  VMISSL_Release(NULL, NULL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L8:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x17,%eax
  and    $0x1e0,%eax
  xor    %eax,-0x10(%rbp)
  andl   $0xfffffff,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  ja     L8
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int qhash(const char *id) {
  unsigned int h = 0;
  size_t len = strlen(id);
  for (int i = 0; i < len; i++) {
    h = (h << 4) + id[i];
    h ^= (h & 0xf0000000) >> 23;
    h &= 0x0fffffff;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qhash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L6
  mov    %rbx,%rcx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%eax
L27:
  shl    $0x4,%eax
  movsbl (%rcx),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x17,%eax
  and    $0x1e0,%eax
  xor    %edx,%eax
  and    $0xfffffff,%eax
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L27
L8:
  pop    %rbx
  ret
L6:
  mov    $0x0,%eax
  jmp    L8
```

assistant: ```c
unsigned int qhash(const char *id) {
  unsigned int h = 0;
  size_t len = strlen(id);
  for (int i = 0; i < len; i++) {
    h = (h << 4) + id[i];
    h ^= (h & 0xf0000000) >> 23;
    h &= 0x0fffffff;
  }
  return h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<qhash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L10
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rdi),%edx
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x17,%eax
  and    $0x1e0,%eax
  xor    %edx,%eax
  and    $0xfffffff,%eax
  cmp    %rdi,%rcx
  jne    L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int qhash(const char *id) {
  unsigned int h = 0;
  size_t len = strlen(id);
  for (int i = 0; i < len; i++) {
    h = (h << 4) + id[i];
    h ^= (h & 0xf0000000) >> 23;
    h &= 0x0fffffff;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qhash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L3
  lea    (%rbx,%rax,1),%rcx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  movsbl (%rdi),%edx
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x17,%eax
  and    $0x1e0,%eax
  xor    %edx,%eax
  and    $0xfffffff,%eax
  cmp    %rdi,%rcx
  jne    L17
  pop    %rbx
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int qhash(const char *id) {
  unsigned int h = 0;
  size_t len = strlen(id);
  for (int i = 0; i < len; i++) {
    h = (h << 4) + id[i];
    h ^= (h & 0xf0000000) >> 23;
    h &= 0x0fffffff;
  }
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L58
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L23
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <quickSort>
  jmp    L36
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L43
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <quickSort>
  jmp    L36
L43:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <quickSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <quickSort>
  jmp    L36
L58:
  nop
L36:
  leave
  ret
```

assistant: ```c
void quickSort(int lo, int hi, unsigned long *arr) {
  int k;
  if (lo >= hi)
    return;
  k = partition(arr, lo, hi);
  if (k == 0) {
    quickSort(k + 1, hi, arr);
  } else if (k == hi) {
    quickSort(lo, k - 1, arr);
  } else {
    quickSort(lo, k - 1, arr);
    quickSort(k + 1, hi, arr);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickSort>:
  endbr64
  cmp    %esi,%edi
  jl     L31
  ret
L31:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %esi,%edx
  mov    %edi,%esi
  mov    %r12,%rdi
  call   <partition@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L10
  cmp    %eax,%ebx
  je     L18
  lea    -0x1(%rax),%esi
  mov    %r12,%rdx
  mov    %ebp,%edi
  call   <quickSort>
  lea    0x1(%r13),%edi
  mov    %r12,%rdx
  mov    %ebx,%esi
  call   <quickSort>
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <quickSort>
  jmp    L47
L18:
  lea    -0x1(%rax),%esi
  mov    %r12,%rdx
  mov    %ebp,%edi
  call   <quickSort>
  jmp    L47
```

assistant: ```c
void quickSort(int lo, int hi, unsigned long *arr) {
  int k;
  if (lo >= hi)
    return;
  k = partition(arr, lo, hi);
  if (k == 0) {
    quickSort(k + 1, hi, arr);
  } else if (k == hi) {
    quickSort(lo, k - 1, arr);
  } else {
    quickSort(lo, k - 1, arr);
    quickSort(k + 1, hi, arr);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<davici_value_scanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <davici_value_vscanf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int davici_value_scanf(struct davici_response *res, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = davici_value_vscanf(res, fmt, args);
  va_end(args);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<davici_value_scanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <davici_value_vscanf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int davici_value_scanf(struct davici_response *res, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = davici_value_vscanf(res, fmt, args);
  va_end(args);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<davici_value_scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <davici_value_vscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int davici_value_scanf(struct davici_response *res, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = davici_value_vscanf(res, fmt, args);
  va_end(args);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<davici_value_scanf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <davici_value_vscanf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int davici_value_scanf(struct davici_response *res, const char *fmt, ...) {
  va_list args;
  int ret;
  va_start(args, fmt);
  ret = davici_value_vscanf(res, fmt, args);
  va_end(args);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L48
L37:
  mov    -0x7e4(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L48
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  mov    -0x7e8(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L48:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L37
  cmpl   $0x0,-0x7e8(%rbp)
  jle    L20
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D20: len for this line is %d


tool: D6: max so far is %d


tool: D8: The longest line was: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    printf("len for this line is %d\n", len);
    if (len > max) {
      max = len;
      printf("max so far is %d\n", max);
      copy(longest, line);
    }
  }
  if (max > 0) {
    printf("The longest line was: %s", longest);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  lea    D27(%rip),%r13
  mov    %rsp,%r12
  lea    D1(%rip),%r14
L6:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L31
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L6
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x3f0(%rsp),%rdi
  mov    %r12,%rsi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L6
L31:
  test   %ebp,%ebp
  jg     L58
L36:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  lea    0x3f0(%rsp),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string

tool: D27: len for this line is %d


tool: D1: max so far is %d


tool: D12: The longest line was: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    printf("len for this line is %d\n", len);
    if (len > max) {
      max = len;
      printf("max so far is %d\n", max);
      copy(longest, line);
    }
  }
  if (max > 0) {
    printf("The longest line was: %s", longest);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r14
  jmp    L25
  nopl   (%rax)
L23:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%ebp
  jl     L52
L25:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L23
  test   %ebp,%ebp
  jne    L28
L0:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <copy@plt>
  jmp    L25
L28:
  lea    0x3f0(%rsp),%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D13: max so far is %d


tool: D21: len for this line is %d


tool: D9: The longest line was: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getline(line, 1000)) > 0) {
    printf("len for this line is %d\n", len);
    if (len > max) {
      max = len;
      printf("max so far is %d\n", max);
      copy(longest, line);
    }
  }
  if (max > 0) {
    printf("The longest line was: %s", longest);
  }
  return 0;
}
```