ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<vtune_norm_to_high>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xff,0x10(%rsp)
  test   %rdx,%rdx
  je     L39
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%r13
  lea    -0x14(%rdx),%r15
  lea    0x10(%rsp),%r14
L78:
  sub    $0x1,%rbx
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <write_vcocap@plt>
  test   %eax,%eax
  jne    L6
  mov    %r14,%rcx
  mov    $0x19,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <get_vtune@plt>
  test   %eax,%eax
  jne    L6
  cmpq   $0x2,0x10(%rsp)
  je     L85
  cmp    %r15,%rbx
  je     L12
  test   %rbx,%rbx
  jne    L78
L39:
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L6
L85:
  mov    0x8(%rsp),%rcx
  mov    %rbx,(%rcx)
  jmp    L6
L12:
  mov    $0xffffffff,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtune_norm_to_high(struct bladerf *dev, uint8_t base, uint8_t vcocap, uint8_t vcocap_reg_state, uint8_t *vtune_high_limit) {
  int status;
  unsigned int i;
  uint8_t vtune = 0xff;
  for (i = 0; i < 20; i++) {
    if (vcocap == 0) {
      *vtune_high_limit = 0;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
    vcocap--;
    status = write_vcocap(dev, base, vcocap, vcocap_reg_state);
    if (status != 0) {
      return status;
    }
    status = get_vtune(dev, base, 25, &vtune);
    if (status != 0) {
      return status;
    }
    if (vtune == 0x02) {
      *vtune_high_limit = vcocap;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
  }
  do {
    do {
    } while (0);
  } while (0);
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vtune_norm_to_high>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  lea    -0x14(%rdx),%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xff,0x10(%rsp)
  nopl   (%rax)
L78:
  test   %r15,%r15
  je     L17
  sub    $0x1,%r15
  mov    %r12,%rcx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  call   <write_vcocap@plt>
  test   %eax,%eax
  jne    L60
  mov    %r13,%rcx
  mov    $0x19,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <get_vtune@plt>
  test   %eax,%eax
  jne    L60
  cmpq   $0x2,0x10(%rsp)
  je     L27
  cmp    %r14,%r15
  jne    L78
  mov    $0xffffffff,%eax
L60:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L17:
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax)
  xor    %eax,%eax
  jmp    L60
L27:
  mov    0x8(%rsp),%rbx
  mov    %r15,(%rbx)
  jmp    L60
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtune_norm_to_high(struct bladerf *dev, uint8_t base, uint8_t vcocap, uint8_t vcocap_reg_state, uint8_t *vtune_high_limit) {
  int status;
  unsigned int i;
  uint8_t vtune = 0xff;
  for (i = 0; i < 20; i++) {
    if (vcocap == 0) {
      *vtune_high_limit = 0;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
    vcocap--;
    status = write_vcocap(dev, base, vcocap, vcocap_reg_state);
    if (status != 0) {
      return status;
    }
    status = get_vtune(dev, base, 25, &vtune);
    if (status != 0) {
      return status;
    }
    if (vtune == 0x02) {
      *vtune_high_limit = vcocap;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
  }
  do {
    do {
    } while (0);
  } while (0);
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vtune_norm_to_high>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  lea    -0x14(%rdx),%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xff,0x10(%rsp)
  nopl   (%rax)
L31:
  test   %r15,%r15
  je     L35
  sub    $0x1,%r15
  mov    %r12,%rcx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r15,%rdx
  call   <write_vcocap@plt>
  test   %eax,%eax
  jne    L27
  mov    %r13,%rcx
  mov    $0x19,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <get_vtune@plt>
  test   %eax,%eax
  jne    L27
  cmpq   $0x2,0x10(%rsp)
  je     L0
  cmp    %r14,%r15
  jne    L31
  mov    $0xffffffff,%eax
L27:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L35:
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax)
  xor    %eax,%eax
  jmp    L27
L0:
  mov    0x8(%rsp),%rbx
  mov    %r15,(%rbx)
  jmp    L27
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vtune_norm_to_high(struct bladerf *dev, uint8_t base, uint8_t vcocap, uint8_t vcocap_reg_state, uint8_t *vtune_high_limit) {
  int status;
  unsigned int i;
  uint8_t vtune = 0xff;
  for (i = 0; i < 20; i++) {
    if (vcocap == 0) {
      *vtune_high_limit = 0;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
    vcocap--;
    status = write_vcocap(dev, base, vcocap, vcocap_reg_state);
    if (status != 0) {
      return status;
    }
    status = get_vtune(dev, base, 25, &vtune);
    if (status != 0) {
      return status;
    }
    if (vtune == 0x02) {
      *vtune_high_limit = vcocap;
      do {
        do {
        } while (0);
      } while (0);
      return 0;
    }
  }
  do {
    do {
    } while (0);
  } while (0);
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  push   0x18(%rbp)
  push   0x10(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <fminl@plt>
  add    $0x20,%rsp
  mov    %rax,%rdx
  fldt   0x10(%rbp)
  fnstcw -0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  or     $0xc,%ah
  mov    %ax,-0x4(%rbp)
  fldcw  -0x4(%rbp)
  fistpll -0x10(%rbp)
  fldcw  -0x2(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  leave
  ret
```

assistant: ```c
void foo(long double xl) {
  do {
    if ((long)fminl(xl, xl) != (long)xl)
      return;
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <fminl@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void foo(long double xl) {
  do {
    if ((long)fminl(xl, xl) != (long)xl)
      return;
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <fminl@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void foo(long double xl) {
  do {
    if ((long)fminl(xl, xl) != (long)xl)
      return;
  } while (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  push   0x28(%rsp)
  push   0x28(%rsp)
  call   <fminl@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
void foo(long double xl) {
  do {
    if ((long)fminl(xl, xl) != (long)xl)
      return;
  } while (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Controller_updateSubjectCriteria>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <SubjectModel_getSubjectRange@plt>
  mov    %eax,%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x120(%rbp),%rcx
  mov    -0x118(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SubjectModel_modifySubject@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void Controller_updateSubjectCriteria(char subjectName[], char subjectCriteria[]) {
  char subjectRange[256];
  strcpy(subjectRange, SubjectModel_getSubjectRange(subjectName));
  SubjectModel_modifySubject(subjectName, subjectCriteria, subjectRange);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Controller_updateSubjectCriteria>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <SubjectModel_getSubjectRange@plt>
  mov    %eax,%esi
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <SubjectModel_modifySubject@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Controller_updateSubjectCriteria(char subjectName[], char subjectCriteria[]) {
  char subjectRange[256];
  strcpy(subjectRange, SubjectModel_getSubjectRange(subjectName));
  SubjectModel_modifySubject(subjectName, subjectCriteria, subjectRange);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Controller_updateSubjectCriteria>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <SubjectModel_getSubjectRange@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SubjectModel_modifySubject@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Controller_updateSubjectCriteria(char subjectName[], char subjectCriteria[]) {
  char subjectRange[256];
  strcpy(subjectRange, SubjectModel_getSubjectRange(subjectName));
  SubjectModel_modifySubject(subjectName, subjectCriteria, subjectRange);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Controller_updateSubjectCriteria>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <SubjectModel_getSubjectRange@plt>
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <SubjectModel_modifySubject@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Controller_updateSubjectCriteria(char subjectName[], char subjectCriteria[]) {
  char subjectRange[256];
  strcpy(subjectRange, SubjectModel_getSubjectRange(subjectName));
  SubjectModel_modifySubject(subjectName, subjectCriteria, subjectRange);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TimerITRxExternalClockConfigure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x8,%rdx
  or     -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TimerITRxExternalClockConfigure(unsigned long ulBase, unsigned long ulInputTriggerSource) {

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) |= ulInputTriggerSource;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TimerITRxExternalClockConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerITRxExternalClockConfigure(unsigned long ulBase, unsigned long ulInputTriggerSource) {

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) |= ulInputTriggerSource;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TimerITRxExternalClockConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerITRxExternalClockConfigure(unsigned long ulBase, unsigned long ulInputTriggerSource) {

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) |= ulInputTriggerSource;
}
```
user: What is the c source code of the assembly code below?

```asm
<TimerITRxExternalClockConfigure>:
  endbr64
  mov    0x8(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x8(%rdi)
  ret
```

assistant: ```c
void TimerITRxExternalClockConfigure(unsigned long ulBase, unsigned long ulInputTriggerSource) {

  ;

  ;
  (*((volatile unsigned long *)(ulBase + 0x00000008))) |= ulInputTriggerSource;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x7,0x14(%rsp)
  movl   $0x23,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <sigemptyset@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <sigaddset@plt>
  mov    $0x20,%edi
  call   <epoll_create@plt>
  mov    %eax,%ebx
  mov    $0xffffffff,%edi
  call   <epoll_create@plt>
  lea    0xc(%rsp),%r12
  mov    D9(%rip),%rbp
  mov    %r12,%rcx
  mov    $0xd,%edx
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <epoll_ctl@plt>
  mov    %r12,%rcx
  mov    $0xd,%edx
  mov    0x0(%rbp),%esi
  mov    $0xffffffff,%edi
  call   <epoll_ctl@plt>
  mov    %r12,%rcx
  mov    $0xd,%edx
  mov    $0xffffffff,%esi
  mov    %ebx,%edi
  call   <epoll_ctl@plt>
  mov    %r12,%rcx
  mov    $0xffffffff,%edx
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <epoll_ctl@plt>
  mov    $0xffffffffffffffff,%rcx
  mov    $0xd,%edx
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <epoll_ctl@plt>
  lea    0x20(%rsp),%rbp
  mov    $0x0,%ecx
  mov    $0x11,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <epoll_wait@plt>
  mov    $0x0,%ecx
  mov    $0x11,%edx
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  call   <epoll_wait@plt>
  mov    $0x0,%ecx
  mov    $0x11,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    %ebx,%edi
  call   <epoll_wait@plt>
  mov    $0x0,%ecx
  mov    $0xffffffff,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <epoll_wait@plt>
  mov    $0xffffffff,%ecx
  mov    $0x11,%edx
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  call   <epoll_wait@plt>
  mov    %ebx,%edi
  call   <close@plt>
  lea    0x14(%rsp),%rbx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <poll@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <poll@plt>
  mov    $0x0,%edx
  mov    $0xffffffff,%esi
  mov    %rbx,%rdi
  call   <poll@plt>
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <poll@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct epoll_event ev, events[17];
  struct pollfd pfd = {7, 0x23, 0};
  int fd;
  struct timespec tim = {.tv_sec = 0, .tv_nsec = 200000000};
  sigset_t sigs;
  sigemptyset(&sigs);
  sigaddset(&sigs, SIGUSR2);
  fd = epoll_create(32);
  epoll_create(-1);
  epoll_ctl(fd, EPOLL_CTL_ADD, 13, &ev);
  epoll_ctl(-1, EPOLL_CTL_ADD, 13, &ev);
  epoll_ctl(fd, -1, 13, &ev);
  epoll_ctl(fd, EPOLL_CTL_ADD, -1, &ev);
  epoll_ctl(fd, EPOLL_CTL_ADD, 13, (struct epoll_event *)-1);
  epoll_wait(fd, events, 17, 0);
  epoll_wait(-1, events, 17, 0);
  epoll_wait(fd, (struct epoll_event *)-1, 17, 0);
  epoll_wait(fd, events, -1, 0);
  epoll_wait(-1, events, 17, -1);
  close(fd);
  poll(&pfd, 1, 0);
  poll((struct pollfd *)-1, 1, 0);
  poll(&pfd, -1, 0);
  poll(NULL, 1, -1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x2300000007,%rax
  lea    0x10(%rsp),%rbp
  movl   $0x0,0x1c(%rsp)
  lea    0xc(%rsp),%r13
  mov    %rbp,%rdi
  mov    %rax,0x14(%rsp)
  call   <sigemptyset@plt>
  mov    D11(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    $0x20,%edi
  call   <epoll_create@plt>
  mov    $0xffffffff,%edi
  mov    %eax,%ebp
  call   <epoll_create@plt>
  mov    %ebp,%edi
  mov    %r13,%rcx
  mov    $0xd,%edx
  mov    D2(%rip),%r12
  mov    (%r12),%esi
  call   <epoll_ctl@plt>
  mov    (%r12),%esi
  mov    %r13,%rcx
  mov    $0xd,%edx
  mov    $0xffffffff,%edi
  call   <epoll_ctl@plt>
  mov    %ebp,%edi
  mov    %r13,%rcx
  mov    $0xd,%edx
  mov    $0xffffffff,%esi
  call   <epoll_ctl@plt>
  mov    (%r12),%esi
  mov    %ebp,%edi
  mov    %r13,%rcx
  mov    $0xffffffff,%edx
  call   <epoll_ctl@plt>
  mov    (%r12),%esi
  mov    %ebp,%edi
  lea    0x20(%rsp),%r12
  mov    $0xffffffffffffffff,%rcx
  mov    $0xd,%edx
  call   <epoll_ctl@plt>
  xor    %ecx,%ecx
  mov    %ebp,%edi
  mov    $0x11,%edx
  mov    %r12,%rsi
  call   <epoll_wait@plt>
  xor    %ecx,%ecx
  mov    $0x11,%edx
  mov    %r12,%rsi
  mov    $0xffffffff,%edi
  call   <epoll_wait@plt>
  xor    %ecx,%ecx
  mov    %ebp,%edi
  mov    $0x11,%edx
  mov    $0xffffffffffffffff,%rsi
  call   <epoll_wait@plt>
  xor    %ecx,%ecx
  mov    %ebp,%edi
  mov    $0xffffffff,%edx
  mov    %r12,%rsi
  call   <epoll_wait@plt>
  mov    $0xffffffff,%ecx
  mov    $0x11,%edx
  mov    %r12,%rsi
  mov    $0xffffffff,%edi
  call   <epoll_wait@plt>
  mov    %ebp,%edi
  lea    0x14(%rsp),%rbp
  call   <close@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <poll@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0xffffffffffffffff,%rdi
  call   <poll@plt>
  xor    %edx,%edx
  mov    $0xffffffff,%esi
  mov    %rbp,%rdi
  call   <poll@plt>
  xor    %edi,%edi
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  call   <poll@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct epoll_event ev, events[17];
  struct pollfd pfd = {7, 0x23, 0};
  int fd;
  struct timespec tim = {.tv_sec = 0, .tv_nsec = 200000000};
  sigset_t sigs;
  sigemptyset(&sigs);
  sigaddset(&sigs, SIGUSR2);
  fd = epoll_create(32);
  epoll_create(-1);
  epoll_ctl(fd, EPOLL_CTL_ADD, 13, &ev);
  epoll_ctl(-1, EPOLL_CTL_ADD, 13, &ev);
  epoll_ctl(fd, -1, 13, &ev);
  epoll_ctl(fd, EPOLL_CTL_ADD, -1, &ev);
  epoll_ctl(fd, EPOLL_CTL_ADD, 13, (struct epoll_event *)-1);
  epoll_wait(fd, events, 17, 0);
  epoll_wait(-1, events, 17, 0);
  epoll_wait(fd, (struct epoll_event *)-1, 17, 0);
  epoll_wait(fd, events, -1, 0);
  epoll_wait(-1, events, 17, -1);
  close(fd);
  poll(&pfd, 1, 0);
  poll((struct pollfd *)-1, 1, 0);
  poll(&pfd, -1, 0);
  poll(NULL, 1, -1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wild_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  nop
  leave
  ret
```

assistant: ```c
void wild_open(void) {
  int fd;
  fd = open((const char *)0x4, O_RDONLY);
  close(fd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wild_open>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    $0x4,%edi
  call   <open@plt>
  mov    %eax,%edi
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wild_open(void) {
  int fd;
  fd = open((const char *)0x4, O_RDONLY);
  close(fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wild_open>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    $0x4,%edi
  mov    (%rax),%esi
  call   <open@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <close@plt>
```

assistant: ```c
void wild_open(void) {
  int fd;
  fd = open((const char *)0x4, O_RDONLY);
  close(fd);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wild_open>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    $0x4,%edi
  mov    (%rax),%esi
  call   <open@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <close@plt>
```

assistant: ```c
void wild_open(void) {
  int fd;
  fd = open((const char *)0x4, O_RDONLY);
  close(fd);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L12:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s != '\0') {
    s++;
    n++;
  }
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x0,%eax
L11:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L11
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s != '\0') {
    s++;
    n++;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L9
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s != '\0') {
    s++;
    n++;
  }
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L18
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t n = 0;
  while (*s != '\0') {
    s++;
    n++;
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pipe(int filedes[2] __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<pipe>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2] __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pipe>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2] __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pipe>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pipe(int filedes[2] __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```