ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_entry>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <read@plt>
  test   %eax,%eax
  js     L1
  mov    $0x0,%eax
L11:
  add    $0x8,%rsp
  ret
L1:
  mov    %eax,%edx
  lea    D14(%rip),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D14: read_entry

tool: D10: ERROR: %s: read returned %i


assistant: ```c
int read_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = read(fd, buf, len);
  if (ret < 0) {
    printf("ERROR: %s: read returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_entry>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read@plt>
  test   %eax,%eax
  js     L11
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  ret
L11:
  mov    %eax,%edx
  lea    D10(%rip),%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D10: read_entry

tool: D2: ERROR: %s: read returned %i


assistant: ```c
int read_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = read(fd, buf, len);
  if (ret < 0) {
    printf("ERROR: %s: read returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_entry>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <read@plt>
  test   %eax,%eax
  js     L9
  xor    %eax,%eax
L8:
  add    $0x8,%rsp
  ret
L9:
  mov    %eax,%edx
  lea    D4(%rip),%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D4: read_entry

tool: D11: ERROR: %s: read returned %i


assistant: ```c
int read_entry(int fd, char *buf, int len) {
  int ret;
  do {
  } while (0);
  ret = read(fd, buf, len);
  if (ret < 0) {
    printf("ERROR: %s: read returned %i\n", __func__, ret);
    return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_c_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L28:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x1,%eax
  jmp    L34
L32:
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L28
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[]) {
  int type_len = sizeof(types) / sizeof(char *);
  int i;
  for (i = 0; i < type_len; i++) {
    if (strcmp(t, types[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_c_type>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[]) {
  int type_len = sizeof(types) / sizeof(char *);
  int i;
  for (i = 0; i < type_len; i++) {
    if (strcmp(t, types[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_c_type>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[]) {
  int type_len = sizeof(types) / sizeof(char *);
  int i;
  for (i = 0; i < type_len; i++) {
    if (strcmp(t, types[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_c_type>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_c_type(char *t, char *types[]) {
  int type_len = sizeof(types) / sizeof(char *);
  int i;
  for (i = 0; i < type_len; i++) {
    if (strcmp(t, types[i]) == 0) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  jmp    L21
L5:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  addq   $0x1,-0x10(%rbp)
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  jmp    L32
L0:
  mov    -0x8(%rbp),%rax
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x6e,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x75,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x6c,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x6c,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  call   <print_buff_add@plt>
L32:
  nop
  leave
  ret
```

assistant: ```c
void print_string(struct printing_state *ps, const char *c) {
  if (c) {
    while (*c) {
      print_buff_add(ps, *c);
      c++;
    }
  } else {
    print_buff_add(ps, '(');
    print_buff_add(ps, 'n');
    print_buff_add(ps, 'u');
    print_buff_add(ps, 'l');
    print_buff_add(ps, 'l');
    print_buff_add(ps, ')');
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rsi,%rsi
  je     L0
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L15
L36:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L36
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x28,%esi
  call   <print_buff_add@plt>
  mov    $0x6e,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  mov    $0x75,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  mov    $0x6c,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  mov    $0x6c,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  mov    $0x29,%esi
  mov    %rbp,%rdi
  call   <print_buff_add@plt>
  jmp    L15
```

assistant: ```c
void print_string(struct printing_state *ps, const char *c) {
  if (c) {
    while (*c) {
      print_buff_add(ps, *c);
      c++;
    }
  } else {
    print_buff_add(ps, '(');
    print_buff_add(ps, 'n');
    print_buff_add(ps, 'u');
    print_buff_add(ps, 'l');
    print_buff_add(ps, 'l');
    print_buff_add(ps, ')');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L2
  mov    %rsi,%rbx
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L24
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <print_buff_add@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L4
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x28,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6e,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x75,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6c,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6c,%esi
  call   <print_buff_add@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x29,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <print_buff_add@plt>
```

assistant: ```c
void print_string(struct printing_state *ps, const char *c) {
  if (c) {
    while (*c) {
      print_buff_add(ps, *c);
      c++;
    }
  } else {
    print_buff_add(ps, '(');
    print_buff_add(ps, 'n');
    print_buff_add(ps, 'u');
    print_buff_add(ps, 'l');
    print_buff_add(ps, 'l');
    print_buff_add(ps, ')');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L8
  mov    %rsi,%rbx
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L20
  nopl   (%rax)
L9:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <print_buff_add@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L9
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x28,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6e,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x75,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6c,%esi
  call   <print_buff_add@plt>
  mov    %rbp,%rdi
  mov    $0x6c,%esi
  call   <print_buff_add@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  mov    $0x29,%esi
  pop    %rbx
  pop    %rbp
  jmp    1050 <print_buff_add@plt>
```

assistant: ```c
void print_string(struct printing_state *ps, const char *c) {
  if (c) {
    while (*c) {
      print_buff_add(ps, *c);
      c++;
    }
  } else {
    print_buff_add(ps, '(');
    print_buff_add(ps, 'n');
    print_buff_add(ps, 'u');
    print_buff_add(ps, 'l');
    print_buff_add(ps, 'l');
    print_buff_add(ps, ')');
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strnEql>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L10
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L18
L15:
  mov    $0x1,%eax
  jmp    L34
L18:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L47
  mov    $0x0,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int strnEql(const char *s, const char *t, int n) {
  for (; *s == *t; s++, t++)
    if (*s == '\0' || --n <= 0)
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strnEql>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    (%rsi),%cl
  jne    L21
  mov    $0x1,%eax
L16:
  test   %cl,%cl
  je     L4
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L14
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  je     L16
  mov    $0x0,%eax
  ret
L21:
  mov    $0x0,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strnEql(const char *s, const char *t, int n) {
  for (; *s == *t; s++, t++)
    if (*s == '\0' || --n <= 0)
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<strnEql>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    (%rsi),%cl
  jne    L49
  mov    $0x1,%eax
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L4
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L49
L33:
  test   %cl,%cl
  jne    L39
L4:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strnEql(const char *s, const char *t, int n) {
  for (; *s == *t; s++, t++)
    if (*s == '\0' || --n <= 0)
      return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnEql>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    (%rsi),%cl
  jne    L2
  mov    $0x1,%eax
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L46
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%cl
  jne    L2
L44:
  test   %cl,%cl
  jne    L5
L46:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strnEql(const char *s, const char *t, int n) {
  for (; *s == *t; s++, t++)
    if (*s == '\0' || --n <= 0)
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmp_llu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jae    L6
  mov    $0xffffffff,%eax
  jmp    L18
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jbe    L22
  mov    $0x1,%eax
  jmp    L18
L22:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_llu(const void *a, const void *b) {
  if (*(unsigned long long *)a < *(unsigned long long *)b)
    return -1;
  if (*(unsigned long long *)a > *(unsigned long long *)b)
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmp_llu>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jb     L0
  seta   %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int cmp_llu(const void *a, const void *b) {
  if (*(unsigned long long *)a < *(unsigned long long *)b)
    return -1;
  if (*(unsigned long long *)a > *(unsigned long long *)b)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp_llu>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_llu(const void *a, const void *b) {
  if (*(unsigned long long *)a < *(unsigned long long *)b)
    return -1;
  if (*(unsigned long long *)a > *(unsigned long long *)b)
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp_llu>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int cmp_llu(const void *a, const void *b) {
  if (*(unsigned long long *)a < *(unsigned long long *)b)
    return -1;
  if (*(unsigned long long *)a > *(unsigned long long *)b)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<updateZXedge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L5
L17:
  mov    -0x14(%rbp),%r8d
  mov    -0x38(%rbp),%rcx
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0x30(%rbp),%edi
  push   %rdi
  mov    %r8d,%r9d
  mov    0x10(%rbp),%r8d
  mov    %eax,%edi
  call   <count@plt>
  add    $0x10,%rsp
  mov    %al,-0x16(%rbp)
  mov    -0x28(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  imul   %edx,%eax
  imul   0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  add    $0x2,%eax
  imul   -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%edx
  movzbl -0x16(%rbp),%eax
  mov    -0x28(%rbp),%ecx
  lea    0x2(%rcx),%esi
  mov    -0x2c(%rbp),%ecx
  add    $0x2,%ecx
  imul   %esi,%ecx
  mov    %ecx,%esi
  imul   0x10(%rbp),%esi
  mov    -0x2c(%rbp),%ecx
  add    $0x2,%ecx
  imul   -0x14(%rbp),%ecx
  add    %ecx,%esi
  mov    -0x30(%rbp),%ecx
  add    %esi,%ecx
  movslq %ecx,%rsi
  mov    -0x40(%rbp),%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <transition@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void updateZXedge(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int x, int rank) {
  int y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    c = count(Ix, Iy, Iz, data, x, y, z);
    old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
    newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<updateZXedge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,(%rsp)
  mov    %edx,0x4(%rsp)
  cmp    $0x2,%esi
  jle    L14
  mov    %esi,%r12d
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %r9d,%r14d
  lea    0x2(%rdx),%eax
  movslq %eax,%rcx
  mov    %rcx,0x8(%rsp)
  lea    0x2(%rsi),%ebx
  imul   %eax,%ebx
  imul   0x50(%rsp),%ebx
  movslq %ebx,%rbx
  add    %eax,%eax
  cltq
  movslq %r9d,%rdx
  add    %rdx,%rax
  add    %rax,%rbx
  mov    $0x2,%ebp
L9:
  sub    $0x8,%rsp
  push   %r14
  mov    %ebp,%r9d
  mov    0x60(%rsp),%r8d
  mov    %r13,%rcx
  mov    0x14(%rsp),%edx
  mov    %r12d,%esi
  mov    0x10(%rsp),%edi
  call   <count@plt>
  movzbl 0x0(%r13,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    %al,(%r15,%rbx,1)
  add    $0x1,%ebp
  add    0x18(%rsp),%rbx
  add    $0x10,%rsp
  cmp    %ebp,%r12d
  jne    L9
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZXedge(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int x, int rank) {
  int y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    c = count(Ix, Iy, Iz, data, x, y, z);
    old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
    newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<updateZXedge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L18
  lea    0x2(%rdx),%eax
  lea    0x2(%rsi),%ebx
  mov    %edx,%r13d
  mov    %edi,%r14d
  imul   %eax,%ebx
  movslq %eax,%rdx
  add    %eax,%eax
  mov    %esi,%r15d
  imul   0x60(%rsp),%ebx
  mov    %rdx,0x18(%rsp)
  cltq
  movslq %r9d,%rdx
  add    %rdx,%rax
  mov    %rcx,%rbp
  mov    $0x2,%r12d
  movslq %ebx,%rbx
  add    %rax,%rbx
  nopl   (%rax)
L11:
  sub    $0x8,%rsp
  mov    %r12d,%r9d
  mov    %rbp,%rcx
  mov    %r13d,%edx
  mov    0x1c(%rsp),%eax
  mov    %r15d,%esi
  mov    %r14d,%edi
  add    $0x1,%r12d
  push   %rax
  mov    0x70(%rsp),%r8d
  call   <count@plt>
  movzbl 0x0(%rbp,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    0x18(%rsp),%rcx
  mov    %al,(%rcx,%rbx,1)
  add    0x28(%rsp),%rbx
  pop    %rax
  pop    %rdx
  cmp    %r12d,%r15d
  jne    L11
L18:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZXedge(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int x, int rank) {
  int y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    c = count(Ix, Iy, Iz, data, x, y, z);
    old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
    newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<updateZXedge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %r9d,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L6
  lea    0x2(%rdx),%eax
  lea    0x2(%rsi),%ebx
  mov    %edx,%r13d
  mov    %edi,%r14d
  imul   %eax,%ebx
  movslq %eax,%rdx
  add    %eax,%eax
  mov    %esi,%r15d
  imul   0x60(%rsp),%ebx
  mov    %rdx,0x18(%rsp)
  cltq
  movslq %r9d,%rdx
  add    %rdx,%rax
  mov    %rcx,%rbp
  mov    $0x2,%r12d
  movslq %ebx,%rbx
  add    %rax,%rbx
  nopl   (%rax)
L10:
  sub    $0x8,%rsp
  mov    %r12d,%r9d
  mov    %rbp,%rcx
  mov    %r13d,%edx
  mov    0x1c(%rsp),%eax
  mov    %r15d,%esi
  mov    %r14d,%edi
  add    $0x1,%r12d
  push   %rax
  mov    0x70(%rsp),%r8d
  call   <count@plt>
  movzbl 0x0(%rbp,%rbx,1),%esi
  movzbl %al,%edi
  call   <transition@plt>
  mov    0x18(%rsp),%rcx
  mov    %al,(%rcx,%rbx,1)
  add    0x28(%rsp),%rbx
  pop    %rax
  pop    %rdx
  cmp    %r12d,%r15d
  jne    L10
L6:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void updateZXedge(int Ix, int Iy, int Iz, unsigned char *data, unsigned char *newData, int z, int x, int rank) {
  int y;
  unsigned char c, old;
  for (y = 2; y < Iy; y++) {
    c = count(Ix, Iy, Iz, data, x, y, z);
    old = data[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z];
    newData[(Iy + 2) * (Iz + 2) * x + (Iz + 2) * y + z] = transition(c, old);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rp_decode_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x2c,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rp_decode_uint64@plt>
  test   %eax,%eax
  jne    L9
  mov    $0x0,%eax
  jmp    L23
L9:
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rp_decode_uint32@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x0,%eax
  jmp    L23
L12:
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int rp_decode_mem(const char *in, uint64_t *addr, size_t *len) {
  uint32_t val;
  assert(in != NULL);
  assert(addr != NULL);
  assert(len != 0);
  if (!rp_decode_uint64(&in, addr, ','))
    return 0;
  if (!rp_decode_uint32(&in, &val, '\0'))
    return 0;
  *len = val;
  return (!0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rp_decode_mem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x2c,%edx
  mov    %rbx,%rsi
  call   <rp_decode_uint64@plt>
  test   %eax,%eax
  jne    L5
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x0,%edx
  call   <rp_decode_uint32@plt>
  test   %eax,%eax
  je     L25
  mov    0x10(%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L25
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rp_decode_mem(const char *in, uint64_t *addr, size_t *len) {
  uint32_t val;
  assert(in != NULL);
  assert(addr != NULL);
  assert(len != 0);
  if (!rp_decode_uint64(&in, addr, ','))
    return 0;
  if (!rp_decode_uint32(&in, &val, '\0'))
    return 0;
  *len = val;
  return (!0);
}
```