ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D24
type_guessed: string
name: unpack_data
arguments: data_tag: D7
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string

tool: D24: Please enter 4 numbers separated by spaces > 

tool: D7: %d%d%d%d

tool: D10: %d is the smallest


assistant: ```c
int main() {
  int n1, n2, n3, n4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &n1, &n2, &n3, &n4);
  if (n1 <= n2)
    min = n1;
  else
    min = n2;
  if (min >= n3)
    min = n3;
  if (min >= n4)
    min = n4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  lea    D18(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%esi
  lea    D9(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D3: Please enter 4 numbers separated by spaces > 

tool: D18: %d%d%d%d

tool: D9: %d is the smallest


assistant: ```c
int main() {
  int n1, n2, n3, n4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &n1, &n2, &n3, &n4);
  if (n1 <= n2)
    min = n1;
  else
    min = n2;
  if (min >= n3)
    min = n3;
  if (min >= n4)
    min = n4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rcx
  lea    D11(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%esi
  lea    D25(%rip),%rdi
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x10(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  mov    0x14(%rsp),%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D25
datatype: string

tool: D17: Please enter 4 numbers separated by spaces > 

tool: D11: %d%d%d%d

tool: D25: %d is the smallest


assistant: ```c
int main() {
  int n1, n2, n3, n4, min;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &n1, &n2, &n3, &n4);
  if (n1 <= n2)
    min = n1;
  else
    min = n2;
  if (min >= n3)
    min = n3;
  if (min >= n4)
    min = n4;
  printf("%d is the smallest\n", min);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<GCD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L44
L12:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L35
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L35
  mov    -0x4(%rbp),%eax
  jmp    L41
L35:
  subl   $0x1,-0x4(%rbp)
L44:
  cmpl   $0x0,-0x4(%rbp)
  jg     L12
L41:
  leave
  ret
```

assistant: ```c
int GCD(int a, int b) {
  int i;
  for (i = min(a, b); i >= 1; i--) {
    if (a % i == 0 && b % i == 0)
      return i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GCD>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <min@plt>
  mov    %eax,%ecx
  test   %eax,%eax
  jg     L47
  jmp    L22
L10:
  sub    $0x1,%ecx
  je     L22
L47:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L10
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L10
L22:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int GCD(int a, int b) {
  int i;
  for (i = min(a, b); i >= 1; i--) {
    if (a % i == 0 && b % i == 0)
      return i;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GCD>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  sub    $0x8,%rsp
  call   <min@plt>
  test   %eax,%eax
  jle    L16
  mov    %eax,%r8d
  xchg   %ax,%ax
L35:
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L31
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L16
L31:
  sub    $0x1,%r8d
  jne    L35
L16:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int GCD(int a, int b) {
  int i;
  for (i = min(a, b); i >= 1; i--) {
    if (a % i == 0 && b % i == 0)
      return i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GCD>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  sub    $0x8,%rsp
  call   <min@plt>
  test   %eax,%eax
  jle    L31
  mov    %eax,%r8d
  xchg   %ax,%ax
L15:
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  jne    L8
  mov    %r13d,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L31
L8:
  sub    $0x1,%r8d
  jne    L15
L31:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int GCD(int a, int b) {
  int i;
  for (i = min(a, b); i >= 1; i--) {
    if (a % i == 0 && b % i == 0)
      return i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<highlight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L8
  mov    $0x5e,%edi
  call   <putchar@plt>
  jmp    L21
L8:
  mov    $0x20,%edi
  call   <putchar@plt>
L21:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %s

assistant: ```c
void highlight(char line[], int i[]) {
  int a;
  int len = strlen(line);
  printf("%s", line);
  for (a = 0; a < len; a++) {
    if (i[a] == 1)
      printf("^");
    else
      printf(" ");
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<highlight>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%rbp
  jmp    L44
L33:
  mov    $0x5e,%edi
  call   <putchar@plt>
L40:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L15
L44:
  cmpl   $0x1,(%rbx)
  je     L33
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L40
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %s

assistant: ```c
void highlight(char line[], int i[]) {
  int a;
  int len = strlen(line);
  printf("%s", line);
  for (a = 0; a < len; a++) {
    if (i[a] == 1)
      printf("^");
    else
      printf(" ");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<highlight>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L27
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0x20,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  je     L27
L6:
  cmpl   $0x1,(%rbx)
  jne    L33
  mov    $0x5e,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L6
L27:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: %s

assistant: ```c
void highlight(char line[], int i[]) {
  int a;
  int len = strlen(line);
  printf("%s", line);
  for (a = 0; a < len; a++) {
    if (i[a] == 1)
      printf("^");
    else
      printf(" ");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<highlight>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L0
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x20,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  je     L0
L18:
  cmpl   $0x1,(%rbx)
  jne    L4
  mov    $0x5e,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L18
L0:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: %s

assistant: ```c
void highlight(char line[], int i[]) {
  int a;
  int len = strlen(line);
  printf("%s", line);
  for (a = 0; a < len; a++) {
    if (i[a] == 1)
      printf("^");
    else
      printf(" ");
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_nbrchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L28
  addl   $0x1,-0x4(%rbp)
L28:
  addq   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_nbrchar(char const *str, char c) {
  int i;
  i = 0;
  while (*str) {
    if (*str == c)
      ++i;
    ++str;
  }
  return (i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_nbrchar>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  mov    $0x0,%edx
L0:
  cmp    %al,%sil
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
L13:
  mov    %edx,%eax
  ret
L1:
  mov    $0x0,%edx
  jmp    L13
```

assistant: ```c
int ft_nbrchar(char const *str, char c) {
  int i;
  i = 0;
  while (*str) {
    if (*str == c)
      ++i;
    ++str;
  }
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_nbrchar>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L2
  xchg   %ax,%ax
L12:
  cmp    %al,%sil
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_nbrchar(char const *str, char c) {
  int i;
  i = 0;
  while (*str) {
    if (*str == c)
      ++i;
    ++str;
  }
  return (i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_nbrchar>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L4
  xchg   %ax,%ax
L10:
  cmp    %sil,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_nbrchar(char const *str, char c) {
  int i;
  i = 0;
  while (*str) {
    if (*str == c)
      ++i;
    ++str;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlib_tok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlib_tok_r@plt>
  leave
  ret
```

assistant: ```c
char *strlib_tok(char *s, const char *sep) {
  static char *lasts;
  return (strlib_tok_r(s, sep, &lasts));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strlib_tok>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdx
  call   <strlib_tok_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *strlib_tok(char *s, const char *sep) {
  static char *lasts;
  return (strlib_tok_r(s, sep, &lasts));
}
```
user: What is the c source code of the assembly code below?

```asm
<strlib_tok>:
  endbr64
  lea    D1(%rip),%rdx
  jmp    1050 <strlib_tok_r@plt>
```

assistant: ```c
char *strlib_tok(char *s, const char *sep) {
  static char *lasts;
  return (strlib_tok_r(s, sep, &lasts));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlib_tok>:
  endbr64
  lea    D0(%rip),%rdx
  jmp    1050 <strlib_tok_r@plt>
```

assistant: ```c
char *strlib_tok(char *s, const char *sep) {
  static char *lasts;
  return (strlib_tok_r(s, sep, &lasts));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dinfo_get_dev_from_blockdev>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    $0x50,%edi
  call   <dinfo_malloc@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbp
  mov    %rbx,%rdx
  lea    D18(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x50,%edi
  call   <dinfo_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L22
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L68
  mov    $0x0,%ebp
  mov    $0x50,%r12d
  jmp    L67
L22:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L72
L17:
  add    $0x4f,%rbp
L67:
  lea    (%rbx,%rbp,1),%rdi
  mov    %r13,%rdx
  mov    $0x50,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L42
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L42
  lea    0x9e(%rbp),%eax
  cmp    %eax,%r12d
  jg     L17
  add    $0x4f,%r12d
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  jmp    L17
L42:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <dinfo_extract_dev@plt>
  neg    %rax
  sbb    %eax,%eax
L72:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L72
L68:
  mov    $0xffffffff,%eax
  jmp    L72
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D1
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D18: /sys/block/%s/dev

tool: D1: r

tool: D5: Error: Not enough memory to allocate readbuffer


assistant: ```c
int dinfo_get_dev_from_blockdev(char *blockdev, dev_t *dev) {
  FILE *dasddev;
  int offset = 0;
  char *devfile = NULL;
  char *readbuf = NULL;
  int readbuflen = 80;
  if ((devfile = dinfo_malloc(readbuflen)) == NULL)
    return -1;
  sprintf(devfile, "/sys/block/%s/dev", blockdev);
  if ((readbuf = dinfo_malloc(readbuflen)) == NULL) {
    printf("Error: Not enough memory to allocate readbuffer\n");
    return -1;
  }
  if ((dasddev = fopen(devfile, "r")) == NULL)
    return -1;
  while (fgets(readbuf + offset, 80, dasddev) && readbuf[strlen(readbuf) - 1] != '\n') {
    offset += 80 - 1;
    if (offset + 80 - 1 >= readbuflen) {
      readbuf = realloc(readbuf, readbuflen + 80 - 1);
      readbuflen += 80 - 1;
    }
  }
  fclose(dasddev);
  if (dinfo_extract_dev(dev, readbuf, readbuflen) != 0)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<dinfo_get_dev_from_blockdev>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x50,%edi
  push   %r12
  push   %rbp
  push   %rbx
  call   <dinfo_malloc@plt>
  test   %rax,%rax
  je     L62
  mov    %r13,%rdx
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  mov    $0x50,%edi
  call   <dinfo_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  lea    D28(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L62
  xor    %ebx,%ebx
  mov    $0x50,%r12d
  jmp    L67
  nopl   (%rax)
L79:
  add    $0x4f,%rbx
L67:
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    $0x50,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L13
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbp,%rax,1)
  je     L13
  lea    0x9e(%rbx),%eax
  cmp    %eax,%r12d
  jg     L79
  add    $0x4f,%r12d
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <dinfo_extract_dev@plt>
  neg    %rax
  sbb    %eax,%eax
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L62:
  mov    $0xffffffff,%eax
  jmp    L77
```

tool_calls: name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D15: /sys/block/%s/dev

tool: D28: r

tool: D6: Error: Not enough memory to allocate readbuffer


assistant: ```c
int dinfo_get_dev_from_blockdev(char *blockdev, dev_t *dev) {
  FILE *dasddev;
  int offset = 0;
  char *devfile = NULL;
  char *readbuf = NULL;
  int readbuflen = 80;
  if ((devfile = dinfo_malloc(readbuflen)) == NULL)
    return -1;
  sprintf(devfile, "/sys/block/%s/dev", blockdev);
  if ((readbuf = dinfo_malloc(readbuflen)) == NULL) {
    printf("Error: Not enough memory to allocate readbuffer\n");
    return -1;
  }
  if ((dasddev = fopen(devfile, "r")) == NULL)
    return -1;
  while (fgets(readbuf + offset, 80, dasddev) && readbuf[strlen(readbuf) - 1] != '\n') {
    offset += 80 - 1;
    if (offset + 80 - 1 >= readbuflen) {
      readbuf = realloc(readbuf, readbuflen + 80 - 1);
      readbuflen += 80 - 1;
    }
  }
  fclose(dasddev);
  if (dinfo_extract_dev(dev, readbuf, readbuflen) != 0)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<dinfo_get_dev_from_blockdev>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x50,%edi
  push   %r12
  push   %rbp
  push   %rbx
  call   <dinfo_malloc@plt>
  test   %rax,%rax
  je     L26
  mov    %r13,%rdx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  mov    $0x50,%edi
  call   <dinfo_malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L85
  lea    D27(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L26
  xor    %ebx,%ebx
  mov    $0x50,%r12d
  jmp    L51
  nopl   (%rax)
L55:
  add    $0x4f,%rbx
L51:
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r13,%rdx
  mov    $0x50,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L79
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbp,%rax,1)
  je     L79
  lea    0x9e(%rbx),%eax
  cmp    %eax,%r12d
  jg     L55
  add    $0x4f,%r12d
  mov    %rbp,%rdi
  mov    %r12d,%esi
  call   <realloc@plt>
  mov    %rax,%rbp
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L79:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <dinfo_extract_dev@plt>
  neg    %rax
  sbb    %eax,%eax
L66:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L85:
  lea    D18(%rip),%rdi
  call   <printf@plt>
L26:
  mov    $0xffffffff,%eax
  jmp    L66
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D27
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D9: /sys/block/%s/dev

tool: D27: r

tool: D18: Error: Not enough memory to allocate readbuffer


assistant: ```c
int dinfo_get_dev_from_blockdev(char *blockdev, dev_t *dev) {
  FILE *dasddev;
  int offset = 0;
  char *devfile = NULL;
  char *readbuf = NULL;
  int readbuflen = 80;
  if ((devfile = dinfo_malloc(readbuflen)) == NULL)
    return -1;
  sprintf(devfile, "/sys/block/%s/dev", blockdev);
  if ((readbuf = dinfo_malloc(readbuflen)) == NULL) {
    printf("Error: Not enough memory to allocate readbuffer\n");
    return -1;
  }
  if ((dasddev = fopen(devfile, "r")) == NULL)
    return -1;
  while (fgets(readbuf + offset, 80, dasddev) && readbuf[strlen(readbuf) - 1] != '\n') {
    offset += 80 - 1;
    if (offset + 80 - 1 >= readbuflen) {
      readbuf = realloc(readbuf, readbuflen + 80 - 1);
      readbuflen += 80 - 1;
    }
  }
  fclose(dasddev);
  if (dinfo_extract_dev(dev, readbuf, readbuflen) != 0)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<encryption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L8
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rot13@plt>
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L17
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %1000s

assistant: ```c
void encryption(char enc[1000]) {
  while (scanf("%1000s", enc)) {
    rot13(enc);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<encryption>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D9(%rip),%rbp
  jmp    L12
L9:
  mov    %rbx,%rdi
  call   <rot13@plt>
L12:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: %1000s

assistant: ```c
void encryption(char enc[1000]) {
  while (scanf("%1000s", enc)) {
    rot13(enc);
  }
}
```