ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mandoc_eos>:
  endbr64
  xor    %r9d,%r9d
  test   %rsi,%rsi
  je     L68
  movslq %esi,%rsi
  mov    %rdi,%r8
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  ja     L68
  push   %rbx
  mov    $0x1,%r10d
  movabs $0x1000000000000142,%rsi
  mov    $0x1,%r11d
L22:
  movzbl (%rax),%edi
  lea    -0x21(%rdi),%ecx
  cmp    $0x3c,%cl
  ja     L4
  mov    %r10,%rbx
  shl    %cl,%rbx
  test   %rsi,%rbx
  jne    L74
  test   $0x40002001,%ebx
  jne    L42
L4:
  test   %r9d,%r9d
  je     L83
  test   %edx,%edx
  jne    L80
L83:
  mov    %r9d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  test   %r9d,%r9d
  cmove  %r11d,%edx
L32:
  sub    $0x1,%rax
  cmp    %rax,%r8
  jbe    L22
  test   %edx,%edx
  sete   %al
  and    %eax,%r9d
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L80:
  call   <isalnum@plt>
  xor    %r9d,%r9d
  test   %eax,%eax
  setne  %r9b
  jmp    L83
L42:
  mov    $0x1,%r9d
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int mandoc_eos(const char *p, size_t sz, int enclosed) {
  const char *q;
  int found;
  if (0 == sz)
    return (0);
  found = 0;
  for (q = p + (int)sz - 1; q >= p; q--) {
    switch (*q) {
    case ('\"'):
    case ('\''):
    case (']'):
    case (')'):
      if (0 == found)
        enclosed = 1;
      break;
    case ('.'):
    case ('!'):
    case ('?'):
      found = 1;
      break;
    default:
      return (found && (!enclosed || isalnum((unsigned char)*q)));
    }
  }
  return (found && !enclosed);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mandoc_eos>:
  endbr64
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L18
  movslq %esi,%rsi
  mov    %rdi,%r8
  lea    -0x1(%rdi,%rsi,1),%rsi
  cmp    %rsi,%rdi
  ja     L18
  push   %rbx
  mov    $0x1,%r10d
  movabs $0x1000000000000142,%r9
  mov    $0x1,%r11d
L85:
  movzbl (%rsi),%edi
  lea    -0x21(%rdi),%ecx
  cmp    $0x3c,%cl
  ja     L57
  mov    %r10,%rbx
  shl    %cl,%rbx
  test   %r9,%rbx
  jne    L54
  test   $0x40002001,%ebx
  jne    L1
L57:
  test   %eax,%eax
  je     L5
  test   %edx,%edx
  jne    L67
L5:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  test   %eax,%eax
  mov    %eax,%ecx
  cmove  %r11d,%edx
L37:
  sub    $0x1,%rsi
  cmp    %rsi,%r8
  jbe    L85
  xor    %eax,%eax
  test   %edx,%edx
  pop    %rbx
  sete   %al
  and    %ecx,%eax
  ret
  nopl   0x0(%rax)
L67:
  call   <isalnum@plt>
  pop    %rbx
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%ecx
  mov    $0x1,%eax
  jmp    L37
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
int mandoc_eos(const char *p, size_t sz, int enclosed) {
  const char *q;
  int found;
  if (0 == sz)
    return (0);
  found = 0;
  for (q = p + (int)sz - 1; q >= p; q--) {
    switch (*q) {
    case ('\"'):
    case ('\''):
    case (']'):
    case (')'):
      if (0 == found)
        enclosed = 1;
      break;
    case ('.'):
    case ('!'):
    case ('?'):
      found = 1;
      break;
    default:
      return (found && (!enclosed || isalnum((unsigned char)*q)));
    }
  }
  return (found && !enclosed);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L13
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L37
L13:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_bin@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L37
L6:
  mov    $0x0,%eax
L37:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D29: Wrong input format.


tool: D12: Try 'eepdump input_file output_file'


tool: D5: Error reading input, aborting


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int i;
  if (argc < 3) {
    printf("Wrong input format.\n");
    printf("Try 'eepdump input_file output_file'\n");
    return 0;
  }
  ret = read_bin(argv[1], argv[2]);
  if (ret) {
    printf("Error reading input, aborting\n");
    return 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L1
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <read_bin@plt>
  test   %eax,%eax
  jne    L8
L34:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L1:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L8:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D11
data_type: string

tool: D4: Wrong input format.


tool: D1: Try 'eepdump input_file output_file'


tool: D11: Error reading input, aborting


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int i;
  if (argc < 3) {
    printf("Wrong input format.\n");
    printf("Try 'eepdump input_file output_file'\n");
    return 0;
  }
  ret = read_bin(argv[1], argv[2]);
  if (ret) {
    printf("Error reading input, aborting\n");
    return 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L20
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  call   <read_bin@plt>
  test   %eax,%eax
  jne    L16
L34:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L20:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L34
L16:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string
name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D18
datatype: string

tool: D2: Wrong input format.


tool: D12: Try 'eepdump input_file output_file'


tool: D18: Error reading input, aborting


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int i;
  if (argc < 3) {
    printf("Wrong input format.\n");
    printf("Try 'eepdump input_file output_file'\n");
    return 0;
  }
  ret = read_bin(argv[1], argv[2]);
  if (ret) {
    printf("Error reading input, aborting\n");
    return 0;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L15
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  call   <read_bin@plt>
  test   %eax,%eax
  jne    L14
L18:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L15:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L14:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string

tool: D14: Wrong input format.


tool: D25: Try 'eepdump input_file output_file'


tool: D3: Error reading input, aborting


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int i;
  if (argc < 3) {
    printf("Wrong input format.\n");
    printf("Try 'eepdump input_file output_file'\n");
    return 0;
  }
  ret = read_bin(argv[1], argv[2]);
  if (ret) {
    printf("Error reading input, aborting\n");
    return 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotatestringright>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  mov    D5(%rip),%rax
  movss  (%rax),%xmm1
  movss  -0x8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <round@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x0,-0xc(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void rotatestringright(char *string, int size) {
  float f = rand();
  int bit = round(f / RAND_MAX);
  for (int i = size; i > 0; i--) {
    string[i] = string[i - 1];
  }
  string[0] = (char)bit + 48;
  string[size + 1] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rotatestringright>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D1(%rip),%rax
  divss  (%rax),%xmm0
  call   <round@plt>
  test   %ebx,%ebx
  jle    L9
  movslq %ebx,%rcx
  lea    0x0(%rbp,%rcx,1),%rdx
  lea    -0x1(%rbp,%rcx,1),%rsi
  lea    -0x1(%rbx),%ecx
  sub    %rcx,%rsi
L15:
  movzbl -0x1(%rdx),%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L15
L9:
  add    $0x30,%eax
  mov    %al,0x0(%rbp)
  movslq %ebx,%rbx
  movb   $0x0,0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void rotatestringright(char *string, int size) {
  float f = rand();
  int bit = round(f / RAND_MAX);
  for (int i = size; i > 0; i--) {
    string[i] = string[i - 1];
  }
  string[0] = (char)bit + 48;
  string[size + 1] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rotatestringright>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  movslq %ebx,%r13
  sub    $0x8,%rsp
  call   <rand@plt>
  mov    D1(%rip),%rax
  divss  (%rax),%xmm0
  call   <round@plt>
  mov    %eax,%r12d
  test   %ebx,%ebx
  jle    L0
  sub    $0x1,%ebx
  lea    -0x1(%r13),%rsi
  lea    0x1(%rbp),%rdi
  mov    %r13,%rdx
  movslq %ebx,%rbx
  sub    %rbx,%rsi
  add    %rbp,%rsi
  call   <memmove@plt>
L0:
  add    $0x30,%r12d
  mov    %r12b,0x0(%rbp)
  movb   $0x0,0x1(%rbp,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotatestringright(char *string, int size) {
  float f = rand();
  int bit = round(f / RAND_MAX);
  for (int i = size; i > 0; i--) {
    string[i] = string[i - 1];
  }
  string[0] = (char)bit + 48;
  string[size + 1] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotatestringright>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  movslq %ebx,%r13
  sub    $0x8,%rsp
  call   <rand@plt>
  mov    D1(%rip),%rax
  divss  (%rax),%xmm0
  call   <round@plt>
  mov    %eax,%r12d
  test   %ebx,%ebx
  jle    L2
  sub    $0x1,%ebx
  lea    -0x1(%r13),%rsi
  lea    0x1(%rbp),%rdi
  mov    %r13,%rdx
  movslq %ebx,%rbx
  sub    %rbx,%rsi
  add    %rbp,%rsi
  call   <memmove@plt>
L2:
  add    $0x30,%r12d
  mov    %r12b,0x0(%rbp)
  movb   $0x0,0x1(%rbp,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotatestringright(char *string, int size) {
  float f = rand();
  int bit = round(f / RAND_MAX);
  for (int i = size; i > 0; i--) {
    string[i] = string[i - 1];
  }
  string[0] = (char)bit + 48;
  string[size + 1] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Flip01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L9
L13:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int Flip01(int x) {
  if (x == 0)
    return (1);
  else
    return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Flip01>:
  endbr64
  test   %edi,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Flip01(int x) {
  if (x == 0)
    return (1);
  else
    return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Flip01>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  sete   %al
  ret
```

assistant: ```c
int Flip01(int x) {
  if (x == 0)
    return (1);
  else
    return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Flip01>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  sete   %al
  ret
```

assistant: ```c
int Flip01(int x) {
  if (x == 0)
    return (1);
  else
    return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D56(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D41
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D31
type_guessed: string
name: disassemble_data
arguments: data_tag: D56
type_guessed: f64
name: disassemble_data
arguments: data_tag: D50
type_guessed: string

tool: D41: +-------*--------*--------*--------*-------+

tool: D26: Please input a round's radius:

tool: D31: %lf

tool: D56: 3.14159

tool: D50: The round's square is %lf


assistant: ```c
void square() {
  double round_r, s;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &round_r);
  s = 3.14159 * round_r * round_r;
  printf("The round's square is %lf\n", s);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<square>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm0
  mulsd  D8(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
type: string
name: parse_data
arguments: data_tag: D24
type: string
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D8
type: f64
name: parse_data
arguments: data_tag: D13
type: string

tool: D20: +-------*--------*--------*--------*-------+

tool: D24: Please input a round's radius:

tool: D2: %lf

tool: D8: 3.14159

tool: D13: The round's square is %lf


assistant: ```c
void square() {
  double round_r, s;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &round_r);
  s = 3.14159 * round_r * round_r;
  printf("The round's square is %lf\n", s);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<square>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  mov    $0x1,%eax
  movsd  D20(%rip),%xmm0
  lea    D34(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D26
datatype: string
name: disassemble_data
arguments: label: D20
datatype: f64
name: disassemble_data
arguments: label: D34
datatype: string

tool: D29: +-------*--------*--------*--------*-------+

tool: D0: Please input a round's radius:

tool: D26: %lf

tool: D20: 3.14159

tool: D34: The round's square is %lf


assistant: ```c
void square() {
  double round_r, s;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &round_r);
  s = 3.14159 * round_r * round_r;
  printf("The round's square is %lf\n", s);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<square>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  mov    $0x1,%eax
  movsd  D29(%rip),%xmm0
  lea    D39(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D29
datatype: f64
name: unpack_data
arguments: label: D39
datatype: string

tool: D5: +-------*--------*--------*--------*-------+

tool: D36: Please input a round's radius:

tool: D26: %lf

tool: D29: 3.14159

tool: D39: The round's square is %lf


assistant: ```c
void square() {
  double round_r, s;
  printf("+-------*--------*--------*--------*-------+\n");
  printf("Please input a round's radius:");
  scanf("%lf", &round_r);
  s = 3.14159 * round_r * round_r;
  printf("The round's square is %lf\n", s);
  printf("+-------*--------*--------*--------*-------+\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrix_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L4:
  mov    $0x0,%eax
  call   <drand48@plt>
  movq   %xmm0,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movq   %rax,%xmm0
  mulsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rdx)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void matrix_init(double *A, const int M, const int N, double val) {
  int i;
  for (i = 0; i < M * N; ++i) {
    A[i] = val * drand48();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  imul   %edx,%esi
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L17:
  mov    $0x0,%eax
  call   <drand48@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L17
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void matrix_init(double *A, const int M, const int N, double val) {
  int i;
  for (i = 0; i < M * N; ++i) {
    A[i] = val * drand48();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_init>:
  endbr64
  push   %rbp
  imul   %edx,%esi
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <drand48@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L11
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void matrix_init(double *A, const int M, const int N, double val) {
  int i;
  for (i = 0; i < M * N; ++i) {
    A[i] = val * drand48();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_init>:
  endbr64
  push   %rbp
  imul   %edx,%esi
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <drand48@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L18
L5:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void matrix_init(double *A, const int M, const int N, double val) {
  int i;
  for (i = 0; i < M * N; ++i) {
    A[i] = val * drand48();
  }
}
```