ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: Usage: %s serial|parallel num_tasks


assistant: ```c
void *print_usage(int argc, char *argv[]) {
  printf("Usage: %s serial|parallel num_tasks\n", argv[0]);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: Usage: %s serial|parallel num_tasks


assistant: ```c
void *print_usage(int argc, char *argv[]) {
  printf("Usage: %s serial|parallel num_tasks\n", argv[0]);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Usage: %s serial|parallel num_tasks


assistant: ```c
void *print_usage(int argc, char *argv[]) {
  printf("Usage: %s serial|parallel num_tasks\n", argv[0]);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Usage: %s serial|parallel num_tasks


assistant: ```c
void *print_usage(int argc, char *argv[]) {
  printf("Usage: %s serial|parallel num_tasks\n", argv[0]);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CodecGenerateInitialVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L17
L28:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x4f7a09cd,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0xe,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   $0xffff31da,%eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  imul   $0x9ef4,%eax,%edx
  mov    -0x24(%rbp),%eax
  imul   $0xfffff131,%eax,%eax
  add    %edx,%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jns    L10
  mov    -0x28(%rbp),%eax
  add    $0x7fffff07,%eax
  mov    %eax,-0x28(%rbp)
L10:
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x28(%rbp),%edx
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x28(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%eax
  add    $0x1,%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x28(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%eax
  add    $0x2,%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  mov    -0x28(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%eax
  add    $0x3,%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x2c(%rbp)
L17:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L28
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <CodecGetMD5Binary@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void CodecGenerateInitialVector(int seed, unsigned char iv[16]) {
  unsigned char initkey[16];
  int j, q;
  int z = seed + 1;
  for (j = 0; j < 4; j++) {
    q = z / 52774;
    z = 40692 * (z - 52774 * q) - 3791 * q;
    if (z < 0)
      z += 2147483399L;
    initkey[4 * j + 0] = 0xff & z;
    initkey[4 * j + 1] = 0xff & (z >> 8);
    initkey[4 * j + 2] = 0xff & (z >> 16);
    initkey[4 * j + 3] = 0xff & (z >> 24);
  }
  CodecGetMD5Binary((unsigned char *)initkey, 16, iv);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CodecGenerateInitialVector>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdi),%eax
  mov    %rsp,%rcx
  lea    0x10(%rsp),%rdi
L17:
  movslq %eax,%rdx
  imul   $0x4f7a09cd,%rdx,%rdx
  sar    $0x2e,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0xffff31da,%edx,%esi
  add    %esi,%eax
  imul   $0x9ef4,%eax,%eax
  imul   $0xfffff131,%edx,%edx
  add    %edx,%eax
  lea    0x7fffff07(%rax),%edx
  cmovs  %edx,%eax
  mov    %al,(%rcx)
  movzbl %ah,%edx
  mov    %dl,0x1(%rcx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rcx)
  mov    %eax,%edx
  shr    $0x18,%edx
  mov    %dl,0x3(%rcx)
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L17
  mov    %rsp,%rdi
  mov    %r8,%rdx
  mov    $0x10,%esi
  call   <CodecGetMD5Binary@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CodecGenerateInitialVector(int seed, unsigned char iv[16]) {
  unsigned char initkey[16];
  int j, q;
  int z = seed + 1;
  for (j = 0; j < 4; j++) {
    q = z / 52774;
    z = 40692 * (z - 52774 * q) - 3791 * q;
    if (z < 0)
      z += 2147483399L;
    initkey[4 * j + 0] = 0xff & z;
    initkey[4 * j + 1] = 0xff & (z >> 8);
    initkey[4 * j + 2] = 0xff & (z >> 16);
    initkey[4 * j + 3] = 0xff & (z >> 24);
  }
  CodecGetMD5Binary((unsigned char *)initkey, 16, iv);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CodecGenerateInitialVector>:
  endbr64
  push   %rbx
  lea    0x1(%rdi),%edx
  mov    %rsi,%r8
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%r9
  mov    %rdi,%rcx
L16:
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x4f7a09cd,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x2e,%rax
  sub    %esi,%eax
  imul   $0xffff31da,%eax,%esi
  imul   $0xfffff131,%eax,%eax
  add    %esi,%edx
  imul   $0x9ef4,%edx,%edx
  add    %eax,%edx
  mov    %edx,%eax
  jns    L6
  lea    0x7fffff07(%rdx),%eax
  mov    %eax,%edx
L6:
  mov    %edx,%esi
  shr    $0x18,%eax
  mov    %dl,(%rcx)
  add    $0x4,%rcx
  sar    $0x10,%esi
  mov    %dh,-0x3(%rcx)
  mov    %sil,-0x2(%rcx)
  mov    %al,-0x1(%rcx)
  cmp    %rcx,%r9
  jne    L16
  mov    %r8,%rdx
  mov    $0x10,%esi
  call   <CodecGetMD5Binary@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CodecGenerateInitialVector(int seed, unsigned char iv[16]) {
  unsigned char initkey[16];
  int j, q;
  int z = seed + 1;
  for (j = 0; j < 4; j++) {
    q = z / 52774;
    z = 40692 * (z - 52774 * q) - 3791 * q;
    if (z < 0)
      z += 2147483399L;
    initkey[4 * j + 0] = 0xff & z;
    initkey[4 * j + 1] = 0xff & (z >> 8);
    initkey[4 * j + 2] = 0xff & (z >> 16);
    initkey[4 * j + 3] = 0xff & (z >> 24);
  }
  CodecGetMD5Binary((unsigned char *)initkey, 16, iv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CodecGenerateInitialVector>:
  endbr64
  push   %rbx
  add    $0x1,%edi
  mov    %rsi,%r8
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x4f7a09cd,%rax,%rax
  sar    $0x2e,%rax
  sub    %edx,%eax
  imul   $0xffff31da,%eax,%edx
  imul   $0xfffff131,%eax,%eax
  add    %edi,%edx
  imul   $0x9ef4,%edx,%edx
  add    %edx,%eax
  lea    0x7fffff07(%rax),%ecx
  cmovns %eax,%ecx
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x4f7a09cd,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x2e,%rax
  sub    %edx,%eax
  imul   $0xffff31da,%eax,%edx
  imul   $0xfffff131,%eax,%eax
  add    %ecx,%edx
  imul   $0x9ef4,%edx,%edx
  add    %edx,%eax
  lea    0x7fffff07(%rax),%ebx
  cmovns %eax,%ebx
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x4f7a09cd,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x2e,%rax
  sub    %edx,%eax
  imul   $0xffff31da,%eax,%edx
  imul   $0xfffff131,%eax,%eax
  add    %ebx,%edx
  imul   $0x9ef4,%edx,%edx
  add    %edx,%eax
  lea    0x7fffff07(%rax),%edx
  cmovs  %edx,%eax
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x4f7a09cd,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x2e,%rdx
  sub    %esi,%edx
  imul   $0xffff31da,%edx,%esi
  imul   $0xfffff131,%edx,%edx
  add    %eax,%esi
  imul   $0x9ef4,%esi,%esi
  lea    (%rdx,%rsi,1),%r10d
  lea    0x7fffff07(%r10),%esi
  test   %r10d,%r10d
  mov    %esi,%edi
  cmovns %r10d,%edi
  xor    %r9d,%r9d
  mov    %cl,%r9b
  mov    %r9d,%edx
  mov    %ch,%dh
  xor    %cx,%cx
  movzwl %dx,%r9d
  mov    %edi,%edx
  or     %r9d,%ecx
  movd   %ecx,%xmm0
  xor    %ecx,%ecx
  mov    %bl,%cl
  mov    %bh,%ch
  movzwl %cx,%r9d
  mov    %ebx,%ecx
  xor    %ebx,%ebx
  mov    %al,%bl
  xor    %cx,%cx
  mov    %ah,%bh
  xor    %ax,%ax
  or     %r9d,%ecx
  movzwl %bx,%ebx
  movd   %ecx,%xmm3
  or     %ebx,%eax
  xor    %ebx,%ebx
  punpckldq %xmm3,%xmm0
  mov    %dil,%bl
  and    $0xff0000,%edi
  movd   %eax,%xmm1
  test   %r10d,%r10d
  cmovns %r10d,%esi
  mov    %dh,%bh
  mov    %r8,%rdx
  movzwl %bx,%ebx
  and    $0xff000000,%esi
  or     %edi,%ebx
  mov    %rsp,%rdi
  or     %esi,%ebx
  mov    $0x10,%esi
  movd   %ebx,%xmm2
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <CodecGetMD5Binary@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CodecGenerateInitialVector(int seed, unsigned char iv[16]) {
  unsigned char initkey[16];
  int j, q;
  int z = seed + 1;
  for (j = 0; j < 4; j++) {
    q = z / 52774;
    z = 40692 * (z - 52774 * q) - 3791 * q;
    if (z < 0)
      z += 2147483399L;
    initkey[4 * j + 0] = 0xff & z;
    initkey[4 * j + 1] = 0xff & (z >> 8);
    initkey[4 * j + 2] = 0xff & (z >> 16);
    initkey[4 * j + 3] = 0xff & (z >> 24);
  }
  CodecGetMD5Binary((unsigned char *)initkey, 16, iv);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    $0x1,%r13d
  jmp    L47
L55:
  mov    -0x28(%rbp),%r12
  mov    -0x30(%rbp),%rbx
  jmp    L29
L118:
  movzbl (%rbx),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <isKanji@plt>
  test   %eax,%eax
  je     L17
  movzbl (%r12),%edx
  movzbl (%rbx),%eax
  cmp    %al,%dl
  jne    L22
  add    $0x1,%r12
  add    $0x1,%rbx
L17:
  movzbl (%r12),%edx
  movzbl (%rbx),%eax
  cmp    %al,%dl
  jne    L115
  add    $0x1,%r12
  add    $0x1,%rbx
L29:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L118
  jmp    L31
L22:
  nop
  jmp    L31
L115:
  nop
L31:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L8
  mov    %r13d,%eax
  jmp    L42
L8:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <isKanji@plt>
  test   %eax,%eax
  je     L74
  addq   $0x1,-0x28(%rbp)
L74:
  addq   $0x1,-0x28(%rbp)
  add    $0x1,%r13d
L47:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L55
  mov    $0x0,%eax
L42:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
Index(s, t) char *s, *t;
{
  register char *u, *v;
  register int i;
  for (i = 1; *s; s++, i++) {
    for (u = s, v = t; *v; u++, v++) {
      if (isKanji(*v)) {
        if (*u != *v)
          break;
        u++;
        v++;
      }
      if (*u != *v)
        break;
    }
    if (*v == '\0')
      return i;
    if (isKanji(*s))
      s++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Index>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    $0x1,%r14d
  cmpb   $0x0,(%rdi)
  jne    L97
  mov    $0x0,%r14d
  jmp    L38
L30:
  mov    %rbp,%rax
L49:
  movzbl (%rax),%edx
  cmp    %dl,(%rbx)
  jne    L79
  add    $0x1,%rbx
  lea    0x1(%rax),%rbp
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L38
L8:
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <isKanji@plt>
  test   %eax,%eax
  je     L30
  movzbl 0x0(%rbp),%eax
  cmp    %al,(%rbx)
  jne    L21
  add    $0x1,%rbx
  lea    0x1(%rbp),%rax
  jmp    L49
L21:
  mov    %rbp,%rax
L79:
  cmpb   $0x0,(%rax)
  je     L38
  movsbl (%r12),%edi
  mov    $0x0,%eax
  call   <isKanji@plt>
  cmp    $0x1,%eax
  mov    %r12,%rax
  sbb    $0xffffffffffffffff,%rax
  lea    0x1(%rax),%r12
  add    $0x1,%r14d
  cmpb   $0x0,0x1(%rax)
  je     L68
L97:
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L38
  mov    %r13,%rbp
  mov    %r12,%rbx
  jmp    L8
L68:
  mov    $0x0,%r14d
L38:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
Index(s, t) char *s, *t;
{
  register char *u, *v;
  register int i;
  for (i = 1; *s; s++, i++) {
    for (u = s, v = t; *v; u++, v++) {
      if (isKanji(*v)) {
        if (*u != *v)
          break;
        u++;
        v++;
      }
      if (*u != *v)
        break;
    }
    if (*v == '\0')
      return i;
    if (isKanji(*s))
      s++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Index>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L0
  nopl   (%rax)
L77:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L47
  mov    %r12,%r14
  mov    %rbp,%rbx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L69:
  movzbl (%r14),%edx
  cmp    %dl,(%rbx)
  jne    L88
  add    $0x1,%rbx
  lea    0x1(%r14),%rax
  movzbl (%rax),%edx
  cmp    %dl,(%rbx)
  jne    L88
L78:
  movsbl 0x1(%rax),%edi
  add    $0x1,%rbx
  lea    0x1(%rax),%r14
  test   %dil,%dil
  je     L47
L34:
  xor    %eax,%eax
  call   <isKanji@plt>
  test   %eax,%eax
  jne    L69
  mov    %r14,%rax
  movzbl (%rax),%edx
  cmp    %dl,(%rbx)
  je     L78
L88:
  test   %dl,%dl
  je     L47
  movsbl 0x0(%rbp),%edi
  xor    %eax,%eax
  call   <isKanji@plt>
  cmp    $0x1,%eax
  mov    %rbp,%rax
  sbb    $0xffffffffffffffff,%rax
  add    $0x1,%r13d
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rbp
  jne    L77
L0:
  xor    %r13d,%r13d
L47:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
Index(s, t) char *s, *t;
{
  register char *u, *v;
  register int i;
  for (i = 1; *s; s++, i++) {
    for (u = s, v = t; *v; u++, v++) {
      if (isKanji(*v)) {
        if (*u != *v)
          break;
        u++;
        v++;
      }
      if (*u != *v)
        break;
    }
    if (*v == '\0')
      return i;
    if (isKanji(*s))
      s++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Index>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L54
  nopl   (%rax)
L1:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L3
  mov    %r12,%r14
  mov    %rbp,%rbx
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%r14),%edx
  cmp    %dl,(%rbx)
  jne    L14
  add    $0x1,%rbx
  lea    0x1(%r14),%rax
  movzbl (%rax),%edx
  cmp    %dl,(%rbx)
  jne    L14
L66:
  movsbl 0x1(%rax),%edi
  add    $0x1,%rbx
  lea    0x1(%rax),%r14
  test   %dil,%dil
  je     L3
L5:
  xor    %eax,%eax
  call   <isKanji@plt>
  test   %eax,%eax
  jne    L2
  mov    %r14,%rax
  movzbl (%rax),%edx
  cmp    %dl,(%rbx)
  je     L66
L14:
  test   %dl,%dl
  je     L3
  movsbl 0x0(%rbp),%edi
  xor    %eax,%eax
  call   <isKanji@plt>
  cmp    $0x1,%eax
  mov    %rbp,%rax
  sbb    $0xffffffffffffffff,%rax
  add    $0x1,%r13d
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rbp
  jne    L1
L54:
  xor    %r13d,%r13d
L3:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
Index(s, t) char *s, *t;
{
  register char *u, *v;
  register int i;
  for (i = 1; *s; s++, i++) {
    for (u = s, v = t; *v; u++, v++) {
      if (isKanji(*v)) {
        if (*u != *v)
          break;
        u++;
        v++;
      }
      if (*u != *v)
        break;
    }
    if (*v == '\0')
      return i;
    if (isKanji(*s))
      s++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multimod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L13
L10:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D9(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L10
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: qword

tool: D9: 9223372036854775807

assistant: ```c
double multimod(double sol[], int DIM) {
  double s, p, t;
  int i;
  s = p = fabs(sol[0]);
  for (i = 1; i < DIM; i++) {
    t = fabs(sol[i]);
    s += t;
    p *= t;
  }
  return s + p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multimod>:
  endbr64
  movsd  (%rdi),%xmm0
  andpd  D4(%rip),%xmm0
  cmp    $0x1,%esi
  jle    L0
  lea    0x8(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x10(%rdi,%rdx,8),%rdx
  movapd %xmm0,%xmm2
  movq   D4(%rip),%xmm3
L20:
  movsd  (%rax),%xmm1
  andpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L20
L3:
  addsd  %xmm2,%xmm0
  ret
L0:
  movapd %xmm0,%xmm2
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: qword[2]

tool: {"D4": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double multimod(double sol[], int DIM) {
  double s, p, t;
  int i;
  s = p = fabs(sol[0]);
  for (i = 1; i < DIM; i++) {
    t = fabs(sol[i]);
    s += t;
    p *= t;
  }
  return s + p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multimod>:
  endbr64
  movsd  (%rdi),%xmm0
  movq   D9(%rip),%xmm3
  andpd  %xmm3,%xmm0
  cmp    $0x1,%esi
  jle    L4
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  movapd %xmm0,%xmm2
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L10:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  andpd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L10
  addsd  %xmm2,%xmm0
  ret
  xchg   %ax,%ax
L4:
  movapd %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: qword

tool: D9: 9223372036854775807

assistant: ```c
double multimod(double sol[], int DIM) {
  double s, p, t;
  int i;
  s = p = fabs(sol[0]);
  for (i = 1; i < DIM; i++) {
    t = fabs(sol[i]);
    s += t;
    p *= t;
  }
  return s + p;
}
```
user: What is the c source code of the assembly code below?

```asm
<multimod>:
  endbr64
  movsd  (%rdi),%xmm0
  movq   D8(%rip),%xmm3
  andpd  %xmm3,%xmm0
  cmp    $0x1,%esi
  jle    L1
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  movapd %xmm0,%xmm2
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L19:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  andpd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L19
  addsd  %xmm2,%xmm0
  ret
  xchg   %ax,%ax
L1:
  movapd %xmm0,%xmm2
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: qword

tool: D8: 9223372036854775807

assistant: ```c
double multimod(double sol[], int DIM) {
  double s, p, t;
  int i;
  s = p = fabs(sol[0]);
  for (i = 1; i < DIM; i++) {
    t = fabs(sol[i]);
    s += t;
    p *= t;
  }
  return s + p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calc_stream_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L73
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x6f,%eax
  je     L74
  cmp    $0x6f,%eax
  jg     L6
  cmp    $0x63,%eax
  je     L21
  cmp    $0x69,%eax
  jne    L6
  addq   $0x4,-0x8(%rbp)
  jmp    L6
L21:
  addq   $0x1,-0x8(%rbp)
  jmp    L6
L74:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <calc_stream_size>
  add    %rax,-0x8(%rbp)
  nop
L6:
  addq   $0x1,-0x18(%rbp)
L73:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: iiiic

assistant: ```c
size_t calc_stream_size(const char *type) {
  size_t size = 0;
  for (; *type != 0; type++) {
    switch (*type) {
    case 'i':
      size += 4;
      break;
    case 'c':
      size += 1;
      break;
    case 'o':
      size += calc_stream_size("iiiic");
      break;
    default:
      size += 0;
    }
  }
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_stream_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  mov    $0x0,%ebp
  test   %al,%al
  je     L65
  mov    %rdi,%rbx
  lea    D5(%rip),%r12
  jmp    L54
L25:
  cmp    $0x63,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
L38:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L65
L54:
  cmp    $0x69,%al
  je     L20
  cmp    $0x6f,%al
  jne    L25
  mov    %r12,%rdi
  call   <calc_stream_size>
  add    %rax,%rbp
  jmp    L38
L20:
  add    $0x4,%rbp
  jmp    L38
L65:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: iiiic

assistant: ```c
size_t calc_stream_size(const char *type) {
  size_t size = 0;
  for (; *type != 0; type++) {
    switch (*type) {
    case 'i':
      size += 4;
      break;
    case 'c':
      size += 1;
      break;
    case 'o':
      size += calc_stream_size("iiiic");
      break;
    default:
      size += 0;
    }
  }
  return size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_stream_size>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L37
  mov    %rdi,%rbx
  lea    D9(%rip),%rbp
L38:
  cmp    $0x69,%al
  je     L41
  cmp    $0x6f,%al
  je     L36
  cmp    $0x63,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%r12
L42:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L38
L37:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rdi
  call   <calc_stream_size>
  add    %rax,%r12
  jmp    L42
  nopl   (%rax)
L41:
  add    $0x4,%r12
  jmp    L42
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: iiiic

assistant: ```c
size_t calc_stream_size(const char *type) {
  size_t size = 0;
  for (; *type != 0; type++) {
    switch (*type) {
    case 'i':
      size += 4;
      break;
    case 'c':
      size += 1;
      break;
    case 'o':
      size += calc_stream_size("iiiic");
      break;
    default:
      size += 0;
    }
  }
  return size;
}
```