ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0x2,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  xor    %edi,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2,%esi
  mov    $0x2,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x17,%esi
  mov    $0x1,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x17,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%esi
  mov    $0x7,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x2ef,%esi
  mov    $0x21,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%esi
  mov    $0x46,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x46,%esi
  mov    $0xa,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5a,%esi
  mov    $0x46,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x46,%esi
  mov    $0x5a,%edi
  call   <gcd@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  assert(0 == gcd(0, 0));
  assert(2 == gcd(2, 0));
  assert(2 == gcd(0, 2));
  assert(2 == gcd(2, 2));
  assert(1 == gcd(1, 23));
  assert(1 == gcd(23, 1));
  assert(1 == gcd(7, 5));
  assert(1 == gcd(33, 751));
  assert(10 == gcd(70, 10));
  assert(10 == gcd(10, 70));
  assert(10 == gcd(70, 90));
  assert(10 == gcd(90, 70));
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1a,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: La edad del profe es: %d!


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("La edad del profe es: %d!\n", 26);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1a,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: La edad del profe es: %d!


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("La edad del profe es: %d!\n", 26);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1a,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: La edad del profe es: %d!


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("La edad del profe es: %d!\n", 26);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1a,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: La edad del profe es: %d!


assistant: ```c
int main(int argc, const char *argv[]) {
  printf("La edad del profe es: %d!\n", 26);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L18
L8:
  addq   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D4: Arg: %s


tool: D5: All Done

assistant: ```c
void printArgs(int _argc, char **_argv) {
  while (--_argc) {
    printf("Arg: %s\n", *++_argv);
  }
  printf("All Done\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<printArgs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  je     L8
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    (%rsi,%rax,8),%r12
  lea    D14(%rip),%rbp
L10:
  add    $0x8,%rbx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
L8:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D18
datatype: string

tool: D14: Arg: %s


tool: D18: All Done

assistant: ```c
void printArgs(int _argc, char **_argv) {
  while (--_argc) {
    printf("Arg: %s\n", *++_argv);
  }
  printf("All Done\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printArgs>:
  endbr64
  cmp    $0x1,%edi
  je     L13
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    (%rsi,%rax,8),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L7:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D11(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D23: Arg: %s


tool: D11: All Done

assistant: ```c
void printArgs(int _argc, char **_argv) {
  while (--_argc) {
    printf("Arg: %s\n", *++_argv);
  }
  printf("All Done\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<printArgs>:
  endbr64
  cmp    $0x1,%edi
  je     L17
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    (%rsi,%rax,8),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L4:
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  lea    D15(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  lea    D15(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D7: Arg: %s


tool: D15: All Done

assistant: ```c
void printArgs(int _argc, char **_argv) {
  while (--_argc) {
    printf("Arg: %s\n", *++_argv);
  }
  printf("All Done\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HTMLHead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D35
type_infered: string
name: unpack_data
arguments: data_tag: D44
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D45
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string

tool: D35: Content-Type: text/html;


tool: D44: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="fr" >
	<head>

tool: D4: Domotics motion detection

tool: D45: 		<title>%s</title>

tool: D27: 		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
	</head>
	<body>

assistant: ```c
void HTMLHead() {
  printf("Content-Type: text/html;\n\n");
  printf("<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Strict//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd\">\n<html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"fr\" >\n\t<head>");
  printf("\t\t<title>%s</title>", "Domotics motion detection");
  printf("\t\t<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />\n\t</head>\n\t<body>");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<HTMLHead>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rsi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D39
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D44
data_type: string
name: disassemble_data
arguments: label: D47
data_type: string

tool: D26: Content-Type: text/html;


tool: D39: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="fr" >
	<head>

tool: D10: Domotics motion detection

tool: D44: 		<title>%s</title>

tool: D47: 		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
	</head>
	<body>

assistant: ```c
void HTMLHead() {
  printf("Content-Type: text/html;\n\n");
  printf("<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Strict//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd\">\n<html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"fr\" >\n\t<head>");
  printf("\t\t<title>%s</title>", "Domotics motion detection");
  printf("\t\t<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />\n\t</head>\n\t<body>");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HTMLHead>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D49(%rip),%rdi
  lea    D40(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D39
type: string
name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D49
type: string
name: parse_data
arguments: label: D40
type: string
name: parse_data
arguments: label: D43
type: string

tool: D39: Content-Type: text/html;


tool: D15: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="fr" >
	<head>

tool: D49: 		<title>%s</title>

tool: D40: Domotics motion detection

tool: D43: 		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
	</head>
	<body>

assistant: ```c
void HTMLHead() {
  printf("Content-Type: text/html;\n\n");
  printf("<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Strict//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd\">\n<html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"fr\" >\n\t<head>");
  printf("\t\t<title>%s</title>", "Domotics motion detection");
  printf("\t\t<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />\n\t</head>\n\t<body>");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HTMLHead>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D30(%rip),%rdi
  lea    D49(%rip),%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D46
type_guessed: string
name: disassemble_data
arguments: tag: D30
type_guessed: string
name: disassemble_data
arguments: tag: D49
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D24: Content-Type: text/html;


tool: D46: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="fr" >
	<head>

tool: D30: 		<title>%s</title>

tool: D49: Domotics motion detection

tool: D26: 		<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
	</head>
	<body>

assistant: ```c
void HTMLHead() {
  printf("Content-Type: text/html;\n\n");
  printf("<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Strict//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd\">\n<html xmlns=\"http://www.w3.org/1999/xhtml\" xml:lang=\"fr\" >\n\t<head>");
  printf("\t\t<title>%s</title>", "Domotics motion detection");
  printf("\t\t<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />\n\t</head>\n\t<body>");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<real_lstat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lstat_nomap_nolog@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int real_lstat(const char *path, struct stat *statbuf) {
  int r;
  r = lstat_nomap_nolog(path, statbuf);
  return (r);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<real_lstat>:
  endbr64
  sub    $0x8,%rsp
  call   <lstat_nomap_nolog@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int real_lstat(const char *path, struct stat *statbuf) {
  int r;
  r = lstat_nomap_nolog(path, statbuf);
  return (r);
}
```
user: Translate the below assembly code into C programming language:

```asm
<real_lstat>:
  endbr64
  jmp    1050 <lstat_nomap_nolog@plt>
```

assistant: ```c
int real_lstat(const char *path, struct stat *statbuf) {
  int r;
  r = lstat_nomap_nolog(path, statbuf);
  return (r);
}
```
user: What is the c source code of the assembly code below?

```asm
<real_lstat>:
  endbr64
  jmp    1050 <lstat_nomap_nolog@plt>
```

assistant: ```c
int real_lstat(const char *path, struct stat *statbuf) {
  int r;
  r = lstat_nomap_nolog(path, statbuf);
  return (r);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  fldt   0xec5(%rip)        # 2010 <_fini+0xd70>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <sqrtl@plt>
  add    $0x10,%rsp
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x2,-0x38(%rbp)
  jmp    L31
L28:
  mov    -0x38(%rbp),%rax
  imul   %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x48(%rbp)
  fildll -0x48(%rbp)
  fldt   0xe92(%rip)        # 2020 <_fini+0xd80>
  fdivp  %st,%st(1)
  fld1
  fsubrp %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <sqrtl@plt>
  add    $0x10,%rsp
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  imul   %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  movq   $0xffffffffffffffff,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L62
L21:
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  sub    %rax,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L23:
  cmpq   $0x0,-0x18(%rbp)
  jg     L21
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L0
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  add    %rax,-0x30(%rbp)
L0:
  mov    -0x38(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  imul   %rax,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  sub    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  add    %rax,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  imul   %rax,%rax
  add    $0x1,%rax
  imul   %rdx,%rax
  shl    $0x2,%rax
  add    %rax,-0x18(%rbp)
  addq   $0x2,-0x28(%rbp)
L62:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jle    L23
  addq   $0x2,-0x38(%rbp)
L31:
  mov    -0x38(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L28
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: %lld


assistant: ```c
int main() {
  long long b, bmax = sqrtl(2 * 10000000000ll - 1), s = 0;
#pragma omp parallel for reduction(+ : s) schedule(dynamic)
  for (b = 2; b <= bmax; b += 2) {
    long long c, cmax, t, diff;
    cmax = sqrtl((((long double)10000000000ll) * 4 * 10000000000ll + 1) / (1 + b * b) - 1);
    t = 1 + b * b;
    diff = -1;
    for (c = b; c <= cmax; diff += (4 * c + 4) * (1 + b * b), c += 2) {
      while (diff > 0) {
        diff -= 2 * t + 1, t++;
      }
      if (diff == 0 && t % 2 == 0)
        s += t / 2;
      diff -= 4 * b * t + 4 * b * b, t += 2 * b;
    }
  }
  printf("%lld\n", s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  fldl   0xeb9(%rip)        # 2008 <_fini+0xda0>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <sqrtl@plt>
  add    $0x10,%rsp
  cmp    $0x1,%rax
  jle    L56
  mov    %rax,%r14
  mov    $0x0,%r13d
  mov    $0x2,%ebp
  jmp    L79
L17:
  mov    %rbp,%rdx
  imul   %rbx,%rdx
  add    %r12,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  add    %r8,%rbx
  add    %rcx,%rax
  add    $0x2,%rsi
  cmp    %rsi,%rdi
  jl     L91
  test   %rax,%rax
  jle    L43
  lea    0x1(%rbx,%rbx,1),%rdx
L22:
  sub    %rdx,%rax
  add    $0x1,%rbx
  add    $0x2,%rdx
  test   %rax,%rax
  jg     L22
L43:
  add    %r9,%rcx
L11:
  mov    %rbx,%rdx
  and    $0x1,%edx
  or     %rax,%rdx
  jne    L17
  mov    %rbx,%rdx
  shr    $0x3f,%rdx
  add    %rbx,%rdx
  sar    %rdx
  add    %rdx,%r13
  jmp    L17
L91:
  add    $0x2,%rbp
  cmp    %rbp,%r14
  jl     L51
L79:
  mov    %rbp,%r12
  imul   %rbp,%r12
  lea    0x1(%r12),%rbx
  mov    %rbx,(%rsp)
  fildll (%rsp)
  fdivrl 0xe15(%rip)        # 2010 <_fini+0xda8>
  fld1
  fsubrp %st,%st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <sqrtl@plt>
  mov    %rax,%rdi
  add    $0x10,%rsp
  cmp    %rbp,%rax
  jl     L91
  lea    0x0(%rbp,%rbp,1),%r8
  lea    0x0(,%rbx,8),%r9
  lea    0x1(%rbp),%rcx
  imul   %rbx,%rcx
  shl    $0x2,%rcx
  mov    %rbp,%rsi
  mov    $0xffffffffffffffff,%rax
  jmp    L11
L56:
  mov    $0x0,%r13d
L51:
  mov    %r13,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string

tool: D2: %lld


assistant: ```c
int main() {
  long long b, bmax = sqrtl(2 * 10000000000ll - 1), s = 0;
#pragma omp parallel for reduction(+ : s) schedule(dynamic)
  for (b = 2; b <= bmax; b += 2) {
    long long c, cmax, t, diff;
    cmax = sqrtl((((long double)10000000000ll) * 4 * 10000000000ll + 1) / (1 + b * b) - 1);
    t = 1 + b * b;
    diff = -1;
    for (c = b; c <= cmax; diff += (4 * c + 4) * (1 + b * b), c += 2) {
      while (diff > 0) {
        diff -= 2 * t + 1, t++;
      }
      if (diff == 0 && t % 2 == 0)
        s += t / 2;
      diff -= 4 * b * t + 4 * b * b, t += 2 * b;
    }
  }
  printf("%lld\n", s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  fldl   0xf72(%rip)        # 2008 <_fini+0xd9c>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <sqrtl@plt>
  pop    %rcx
  pop    %rsi
  cmp    $0x1,%rax
  jle    L33
  mov    %rax,%rbp
  xor    %r12d,%r12d
  mov    $0x2,%r13d
L32:
  mov    %r13,%r14
  sub    $0x10,%rsp
  imul   %r13,%r14
  lea    0x1(%r14),%rbx
  mov    %rbx,0x10(%rsp)
  fildll 0x10(%rsp)
  fdivrl 0xf32(%rip)        # 2010 <_fini+0xda4>
  fld1
  fsubrp %st,%st(1)
  fstpt  (%rsp)
  call   <sqrtl@plt>
  mov    %rax,%rdi
  pop    %rax
  pop    %rdx
  cmp    %r13,%rdi
  jl     L0
  lea    0x1(%r13),%rcx
  lea    0x0(%r13,%r13,1),%r8
  mov    %r13,%rsi
  mov    $0xffffffffffffffff,%rax
  imul   %rbx,%rcx
  lea    0x0(,%rbx,8),%r9
  shl    $0x2,%rcx
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %rbx,%r10
  mov    %rbx,%rdx
  sar    %rdx
  and    $0x1,%r10d
  add    %r12,%rdx
  or     %rax,%r10
  cmove  %rdx,%r12
  mov    %r13,%rdx
  add    $0x2,%rsi
  imul   %rbx,%rdx
  add    %r8,%rbx
  add    %r14,%rdx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  add    %rcx,%rax
  cmp    %rsi,%rdi
  jl     L0
  test   %rax,%rax
  jle    L68
  lea    0x1(%rbx,%rbx,1),%rdx
  nopl   0x0(%rax)
L50:
  sub    %rdx,%rax
  add    $0x1,%rbx
  add    $0x2,%rdx
  test   %rax,%rax
  jg     L50
L68:
  add    %r9,%rcx
  jmp    L56
  nopl   (%rax)
L0:
  add    $0x2,%r13
  cmp    %r13,%rbp
  jge    L32
L31:
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  xor    %r12d,%r12d
  jmp    L31
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type: string

tool: D7: %lld


assistant: ```c
int main() {
  long long b, bmax = sqrtl(2 * 10000000000ll - 1), s = 0;
#pragma omp parallel for reduction(+ : s) schedule(dynamic)
  for (b = 2; b <= bmax; b += 2) {
    long long c, cmax, t, diff;
    cmax = sqrtl((((long double)10000000000ll) * 4 * 10000000000ll + 1) / (1 + b * b) - 1);
    t = 1 + b * b;
    diff = -1;
    for (c = b; c <= cmax; diff += (4 * c + 4) * (1 + b * b), c += 2) {
      while (diff > 0) {
        diff -= 2 * t + 1, t++;
      }
      if (diff == 0 && t % 2 == 0)
        s += t / 2;
      diff -= 4 * b * t + 4 * b * b, t += 2 * b;
    }
  }
  printf("%lld\n", s);
}
```