user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  movl   $0x0,-0x5c(%rbp)
  movl   $0x0,-0x5c(%rbp)
  jmp    L34
L58:
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x60(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  addl   $0x1,-0x5c(%rbp)
L34:
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  lea    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  movl   $0x0,-0x5c(%rbp)
  jmp    L63
L19:
  mov    -0x5c(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x5c(%rbp)
L63:
  cmpl   $0xf,-0x5c(%rbp)
  jle    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <MD5@plt>
  movl   $0x0,-0x5c(%rbp)
  jmp    L44
L21:
  mov    -0x5c(%rbp),%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x5c(%rbp)
L44:
  cmpl   $0xf,-0x5c(%rbp)
  jle    L21
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D27
datatype: string
name: read_data
arguments: tag: D33
datatype: string

tool: D10: abcdefghijklmn

tool: D27: info [%s]


tool: D33: %02x

assistant: ```c
int main() {
  const char *info = "abcdefghijklmn";
  unsigned char szmd5[64] = {0};
  bzero(szmd5, sizeof(szmd5));
  printf("info [%s]\n", info);
  MD5_CTX c;
  MD5_Init(&c);
  int i = 0;
  for (i = 0; info[i] != '\0'; i++) {
    MD5_Update(&c, &info[i], 1);
  }
  MD5_Final(szmd5, &c);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  bzero(szmd5, sizeof(szmd5));
  MD5((const unsigned char *)info, strlen(info), szmd5);
  for (i = 0; i < 16; i++) {
    printf("%02x", szmd5[i]);
  }
  printf("\n");
  return 0;
}
```