ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fputs(const char *s, FILE *stream) {
  int ret = 0;
  while (*s) {
    putc(*(s++), stream);
    ++ret;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L22
  mov    %rsi,%r12
  mov    $0x0,%ebp
L9:
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    %r12,%rsi
  call   <putc@plt>
  add    $0x1,%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L9
L4:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    $0x0,%ebp
  jmp    L4
```

assistant: ```c
int fputs(const char *s, FILE *stream) {
  int ret = 0;
  while (*s) {
    putc(*(s++), stream);
    ++ret;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L13:
  add    $0x1,%rbx
  mov    %rbp,%rsi
  add    $0x1,%r12d
  call   <putc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L13
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fputs(const char *s, FILE *stream) {
  int ret = 0;
  while (*s) {
    putc(*(s++), stream);
    ++ret;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputs>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L12:
  add    $0x1,%rbx
  mov    %rbp,%rsi
  add    $0x1,%r12d
  call   <putc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int fputs(const char *s, FILE *stream) {
  int ret = 0;
  while (*s) {
    putc(*(s++), stream);
    ++ret;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<_renormalize_transition_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  test   %esi,%esi
  jle    L92
  mov    %esi,%r12d
  mov    %rdx,%rbx
  movslq %esi,%rax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
  mov    %rdi,%r15
  mov    %rdi,%rbp
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    -0x1(%rsi),%r13d
L69:
  mov    %r12d,%edx
  mov    $0x0,%eax
L24:
  movsd  0x0(%rbp,%rax,8),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L24
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <_mixed_sort@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <_kahan_summation@plt>
  movsd  0x8(%rsp),%xmm3
  maxsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%r14d
  add    0x18(%rsp),%rbp
  cmp    %r14d,%r12d
  je     L95
  mov    %r14d,0x14(%rsp)
  jmp    L69
L19:
  movq   $0x0,(%rbx,%rbp,8)
L72:
  lea    0x1(%rax),%rdx
  cmp    %r13,%rax
  je     L90
  mov    %rdx,%rax
L85:
  movsd  (%r12,%rax,8),%xmm0
  divsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%r12,%rax,8)
  cmp    %ebp,%eax
  je     L19
  movsd  %xmm0,(%rbx,%rbp,8)
  jmp    L72
L90:
  mov    0x14(%rsp),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <_mixed_sort@plt>
  mov    %r14d,%esi
  mov    %rbx,%rdi
  call   <_kahan_summation@plt>
  movapd %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r15)
  lea    0x1(%rbp),%rax
  add    0x20(%rsp),%r15
  add    0x18(%rsp),%r12
  cmp    %r13,%rbp
  je     L92
  mov    %rax,%rbp
L75:
  mov    $0x0,%eax
  jmp    L85
L95:
  pxor   %xmm0,%xmm0
  comisd 0x8(%rsp),%xmm0
  jae    L92
  mov    0x18(%rsp),%rax
  add    $0x8,%rax
  mov    %rax,0x20(%rsp)
  mov    0x14(%rsp),%r13d
  mov    0x28(%rsp),%r12
  mov    $0x0,%ebp
  jmp    L75
L92:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: f64

tool: D1: 1

assistant: ```c
extern void _renormalize_transition_matrix(double *p, int n_conf_states, double *scratch_M) {
  int i, j;
  double sum, max_sum = 0.0;
  for (i = 0; i < n_conf_states; ++i) {
    for (j = 0; j < n_conf_states; ++j)
      scratch_M[j] = p[i * n_conf_states + j];
    _mixed_sort(scratch_M, 0, n_conf_states - 1);
    sum = _kahan_summation(scratch_M, n_conf_states);
    max_sum = (max_sum > sum) ? max_sum : sum;
  }
  if (0.0 >= max_sum)
    return;
  for (i = 0; i < n_conf_states; ++i) {
    for (j = 0; j < n_conf_states; ++j) {
      p[i * n_conf_states + j] /= max_sum;
      if (i == j)
        scratch_M[i] = 0.0;
      else
        scratch_M[i] = p[i * n_conf_states + j];
    }
    _mixed_sort(scratch_M, 0, n_conf_states - 1);
    p[i * n_conf_states + i] = 1.0 - _kahan_summation(scratch_M, n_conf_states);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_renormalize_transition_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  test   %esi,%esi
  jle    L2
  movslq %esi,%r13
  mov    %rdi,0x18(%rsp)
  mov    %esi,%r12d
  mov    %rdx,%r14
  lea    -0x1(%rsi),%r15d
  mov    %rdi,%rbx
  pxor   %xmm2,%xmm2
  xor    %ebp,%ebp
  lea    0x0(,%r13,8),%rax
  mov    %rax,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L75:
  movsd  (%rbx,%rax,8),%xmm0
  movsd  %xmm0,(%r14,%rax,8)
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L75
  mov    %r15d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  movsd  %xmm2,0x8(%rsp)
  call   <_mixed_sort@plt>
  mov    %r12d,%esi
  mov    %r14,%rdi
  add    $0x1,%ebp
  call   <_kahan_summation@plt>
  movsd  0x8(%rsp),%xmm2
  add    0x10(%rsp),%rbx
  maxsd  %xmm0,%xmm2
  cmp    %ebp,%r12d
  jne    L11
  pxor   %xmm3,%xmm3
  comisd %xmm2,%xmm3
  jae    L2
  mov    0x10(%rsp),%rax
  mov    0x28(%rsp),%r12
  xor    %ebx,%ebx
  add    $0x8,%rax
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax)
L72:
  xor    %eax,%eax
  jmp    L84
  nopl   0x0(%rax)
L20:
  movsd  %xmm0,(%r12,%rax,8)
  add    $0x1,%rax
  movsd  %xmm1,(%r14,%rbx,8)
  cmp    %r13,%rax
  je     L18
L84:
  movsd  (%r12,%rax,8),%xmm0
  divsd  %xmm2,%xmm0
  movapd %xmm0,%xmm1
  cmp    %eax,%ebx
  jne    L20
  pxor   %xmm1,%xmm1
  jmp    L20
  nopl   (%rax)
L18:
  xor    %esi,%esi
  mov    %r15d,%edx
  mov    %r14,%rdi
  movsd  %xmm2,0x8(%rsp)
  call   <_mixed_sort@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <_kahan_summation@plt>
  mov    0x18(%rsp),%rax
  mov    0x20(%rsp),%rcx
  movapd %xmm0,%xmm1
  add    0x10(%rsp),%r12
  movsd  0x8(%rsp),%xmm2
  movsd  D7(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    %rcx,%rax
  cmp    %r13,%rbx
  mov    %rax,0x18(%rsp)
  jne    L72
L2:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: f64

tool: D7: 1

assistant: ```c
extern void _renormalize_transition_matrix(double *p, int n_conf_states, double *scratch_M) {
  int i, j;
  double sum, max_sum = 0.0;
  for (i = 0; i < n_conf_states; ++i) {
    for (j = 0; j < n_conf_states; ++j)
      scratch_M[j] = p[i * n_conf_states + j];
    _mixed_sort(scratch_M, 0, n_conf_states - 1);
    sum = _kahan_summation(scratch_M, n_conf_states);
    max_sum = (max_sum > sum) ? max_sum : sum;
  }
  if (0.0 >= max_sum)
    return;
  for (i = 0; i < n_conf_states; ++i) {
    for (j = 0; j < n_conf_states; ++j) {
      p[i * n_conf_states + j] /= max_sum;
      if (i == j)
        scratch_M[i] = 0.0;
      else
        scratch_M[i] = p[i * n_conf_states + j];
    }
    _mixed_sort(scratch_M, 0, n_conf_states - 1);
    p[i * n_conf_states + i] = 1.0 - _kahan_summation(scratch_M, n_conf_states);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0xff,%r8d
  jg     L87
  mov    %esi,%r10d
  mov    %edx,%esi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  cmp    $0x1,%ecx
  jle    L87
  lea    -0x4(%r9),%eax
  test   $0xfffffffb,%eax
  je     L44
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L32
L44:
  cmp    %r9d,%ebp
  jl     L19
  lea    0x2(%rsi,%rbp,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  sub    %edx,%r9d
  test   %edx,%edx
  mov    %edx,%ebx
  cmovne %r9d,%ebx
  add    %ebx,%r13d
  test   %r10d,%r10d
  je     L24
  cmp    %r10d,%r13d
  jg     L77
L24:
  test   %rdi,%rdi
  je     L149
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebx
  je     L83
  test   %ebx,%ebx
  jg     L10
L51:
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  add    $0x8,%rax
  mov    0x30(%rsp),%rdx
  mov    %rax,(%rdx)
L149:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L83:
  mov    D17(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  jmp    L51
L10:
  mov    D4(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    0x8(%rax),%r14
  lea    -0x2(%rbx),%edx
  mov    %edx,0x4(%rax)
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movslq %ebx,%rbx
  lea    -0x8(%r14,%rbx,4),%rax
  jmp    L51
L87:
  mov    $0xffffffff,%r13d
  jmp    L149
L32:
  mov    $0xffffffff,%r13d
  jmp    L149
L19:
  mov    $0xffffffff,%r13d
  jmp    L149
L77:
  mov    $0xffffffff,%r13d
  jmp    L149
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len > 255) {
    return (-1);
  }
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0xff,%r8d
  jg     L54
  mov    %ecx,%r12d
  cmp    $0x1,%ecx
  jle    L54
  lea    -0x4(%r9),%eax
  mov    %esi,%r10d
  mov    %r8d,%ebx
  movslq %edx,%rsi
  and    $0xfffffffb,%eax
  je     L19
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L54
L19:
  cmp    %r9d,%ebx
  jl     L54
  lea    0x2(%rsi,%rbx,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rbp
  test   %ebp,%ebp
  je     L10
  sub    %ebp,%r9d
  movslq %r9d,%rbp
  add    %ebp,%r13d
L10:
  test   %r10d,%r10d
  je     L41
  cmp    %r13d,%r10d
  jl     L54
L41:
  test   %rdi,%rdi
  je     L109
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebp
  je     L61
  test   %ebp,%ebp
  jle    L77
  mov    D0(%rip),%rdx
  lea    0x8(%rax),%r14
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x2(%rbp),%edx
  mov    %edx,0x4(%rax)
  call   <memset@plt>
  lea    -0x8(%r14,%rbp,4),%rax
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L61:
  mov    D9(%rip),%rdx
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,-0x4(%rax)
L77:
  mov    0x30(%rsp),%rdx
  mov    %r12d,(%rax)
  add    $0x8,%rax
  mov    %ebx,-0x4(%rax)
  mov    %rax,(%rdx)
L109:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L54:
  mov    $0xffffffff,%r13d
  jmp    L109
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len > 255) {
    return (-1);
  }
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inet6_opt_append>:
  endbr64
  push   %r12
  movd   %ecx,%xmm0
  movd   %r8d,%xmm2
  push   %rbp
  punpckldq %xmm2,%xmm0
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0xff,%r8d
  jg     L76
  cmp    $0x1,%ecx
  jle    L76
  lea    -0x4(%r9),%eax
  mov    %esi,%r10d
  movslq %edx,%rsi
  and    $0xfffffffb,%eax
  je     L58
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L76
L58:
  cmp    %r9d,%r8d
  jl     L76
  lea    0x2(%rsi,%r8,1),%r12d
  mov    %r12d,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rbx
  test   %ebx,%ebx
  je     L20
  sub    %ebx,%r9d
  movslq %r9d,%rbx
  add    %ebx,%r12d
L20:
  test   %r10d,%r10d
  je     L38
  cmp    %r12d,%r10d
  jl     L76
L38:
  test   %rdi,%rdi
  je     L70
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebx
  je     L45
  test   %ebx,%ebx
  jle    L99
  mov    D4(%rip),%rcx
  lea    -0x2(%rbx),%edx
  lea    0x8(%rax),%rbp
  xor    %esi,%esi
  movd   %edx,%xmm3
  mov    %rbp,%rdi
  movq   %xmm0,0x8(%rsp)
  movd   (%rcx),%xmm1
  punpckldq %xmm3,%xmm1
  movq   %xmm1,(%rax)
  call   <memset@plt>
  movq   0x8(%rsp),%xmm0
  lea    -0x8(%rbp,%rbx,4),%rax
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L45:
  mov    D9(%rip),%rdx
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,-0x4(%rax)
L99:
  mov    0x30(%rsp),%rdx
  movq   %xmm0,(%rax)
  add    $0x8,%rax
  mov    %rax,(%rdx)
L70:
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L76:
  mov    $0xffffffff,%r12d
  jmp    L70
```

assistant: ```c
int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len > 255) {
    return (-1);
  }
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  movl   $0x5,-0x38(%rbp)
  movl   $0x7,-0x34(%rbp)
  movl   $0x2,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0xf,-0x20(%rbp)
  movl   $0x11,-0x1c(%rbp)
  movl   $0x22,-0x18(%rbp)
  movl   $0xc,-0x14(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <max_value@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: max value is %d


assistant: ```c
void main() {
  int a[3][4] = {{1, 3, 5, 7}, {2, 4, 6, 8}, {15, 17, 34, 12}};
  printf("max value is %d\n", max_value(a));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0xf,0x20(%rsp)
  movl   $0x11,0x24(%rsp)
  movl   $0x22,0x28(%rsp)
  movl   $0xc,0x2c(%rsp)
  mov    %rsp,%rdi
  call   <max_value@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: max value is %d


assistant: ```c
void main() {
  int a[3][4] = {{1, 3, 5, 7}, {2, 4, 6, 8}, {15, 17, 34, 12}};
  printf("max value is %d\n", max_value(a));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x110000000f,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xc00000022,%rax
  mov    %rax,0x28(%rsp)
  call   <max_value@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x48,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: max value is %d


assistant: ```c
void main() {
  int a[3][4] = {{1, 3, 5, 7}, {2, 4, 6, 8}, {15, 17, 34, 12}};
  printf("max value is %d\n", max_value(a));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  movdqa D39(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D13(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D37(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <max_value@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D39
type: byte[16]
name: unpack_data
arguments: tag: D13
type: byte[16]
name: unpack_data
arguments: tag: D37
type: byte[16]
name: unpack_data
arguments: tag: D11
type: string

tool: {"D39": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D13": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D37": [0x0f,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x22,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: D11: max value is %d


assistant: ```c
void main() {
  int a[3][4] = {{1, 3, 5, 7}, {2, 4, 6, 8}, {15, 17, 34, 12}};
  printf("max value is %d\n", max_value(a));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UpdateQuaternion>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  cvtss2sd %xmm0,%xmm0
  mulsd  D15(%rip),%xmm0
  call   <Vector3Scale@plt>
  movss  0xc(%rsp),%xmm0
  movaps %xmm0,%xmm1
  xorps  D0(%rip),%xmm1
  movss  0x4(%rbx),%xmm6
  movss  0x10(%rsp),%xmm5
  movss  0x8(%rbx),%xmm8
  movss  0x14(%rsp),%xmm4
  movss  0xc(%rbx),%xmm3
  movss  (%rbx),%xmm7
  movaps %xmm1,%xmm2
  mulss  %xmm6,%xmm2
  movaps %xmm5,%xmm9
  mulss  %xmm8,%xmm9
  subss  %xmm9,%xmm2
  movaps %xmm4,%xmm9
  mulss  %xmm3,%xmm9
  subss  %xmm9,%xmm2
  addss  %xmm7,%xmm2
  movss  %xmm2,(%rbx)
  movaps %xmm0,%xmm2
  mulss  %xmm7,%xmm2
  movaps %xmm5,%xmm9
  mulss  %xmm3,%xmm9
  subss  %xmm9,%xmm2
  movaps %xmm8,%xmm9
  mulss  %xmm4,%xmm9
  addss  %xmm9,%xmm2
  addss  %xmm6,%xmm2
  movss  %xmm2,0x4(%rbx)
  mulss  %xmm3,%xmm0
  movaps %xmm5,%xmm2
  mulss  %xmm7,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm6,%xmm2
  mulss  %xmm4,%xmm2
  subss  %xmm2,%xmm0
  addss  %xmm8,%xmm0
  movss  %xmm0,0x8(%rbx)
  mulss  %xmm8,%xmm1
  mulss  %xmm5,%xmm6
  addss  %xmm6,%xmm1
  mulss  %xmm7,%xmm4
  addss  %xmm4,%xmm1
  addss  %xmm3,%xmm1
  movss  %xmm1,0xc(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %rbx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
type: f64
name: parse_data
arguments: data_label: D0
type: byte[16]

tool: D15: 0.5

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float *UpdateQuaternion(float quat[4], const float angular_rate[3], float dt) {
  float dpqr[3];
  Vector3Scale(angular_rate, 0.5 * dt, dpqr);
  float d_quat[4];
  d_quat[0] = -dpqr[0] * quat[1] - dpqr[1] * quat[2] - dpqr[2] * quat[3];
  d_quat[1] = dpqr[0] * quat[0] - dpqr[1] * quat[3] + dpqr[2] * quat[2];
  d_quat[2] = dpqr[0] * quat[3] + dpqr[1] * quat[0] - dpqr[2] * quat[1];
  d_quat[3] = -dpqr[0] * quat[2] + dpqr[1] * quat[1] + dpqr[2] * quat[0];
  quat[0] += d_quat[0];
  quat[1] += d_quat[1];
  quat[2] += d_quat[2];
  quat[3] += d_quat[3];
  return quat;
}
```