ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<szwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x5a455054474d4b00,%rax
  mov    %rax,0xf(%rsp)
  movb   $0x59,0x17(%rsp)
  test   %rdx,%rdx
  jne    L11
  test   %rcx,%rcx
  je     L11
  mov    %rcx,%rbx
L28:
  cmp    $0x270f,%rsi
  jbe    L134
  mov    $0x0,%eax
L87:
  add    $0x1,%rax
  mov    %rsi,%rdx
  shr    $0xa,%rsi
  cmp    $0x8,%rax
  ja     L59
  cmp    $0x9c3fff,%rdx
  ja     L87
L59:
  movzbl 0xf(%rsp,%rax,1),%ecx
  mov    %cl,0xe(%rsp)
  cmp    $0x9c3fff,%rdx
  jbe    L99
  movb   $0x3e,0x9(%rsp)
  movb   $0x39,0xd(%rsp)
  movb   $0x39,0xc(%rsp)
  movb   $0x39,0xb(%rsp)
  movb   $0x39,0xa(%rsp)
  mov    $0x0,%ecx
L93:
  add    $0x1,%rcx
  mov    $0x6,%r13d
  sub    %rcx,%r13
  lea    0x9(%rsp,%rcx,1),%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <memcpy@plt>
  cmpb   $0x0,0xe(%rsp)
  cmovne %rbp,%rbx
  test   %rbx,%rbx
  je     L48
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    (%r12,%r13,1),%rdi
  mov    %rax,%rdx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  add    %rbp,%r13
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  test   %rbx,%rbx
  je     L28
  test   %rbp,%rbp
  cmove  %rbx,%rbp
  jmp    L28
L67:
  mov    $0x4,%ecx
  movabs $0xcccccccccccccccd,%r8
L129:
  mov    %rsi,%rax
  mul    %r8
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rdi
  add    %rdi,%rdi
  mov    %rsi,%rax
  sub    %rdi,%rax
  add    $0x30,%eax
  mov    %al,0x9(%rsp,%rcx,1)
  mov    %rsi,%rax
  mov    %rdx,%rsi
  sub    $0x1,%rcx
  je     L93
  cmp    $0x9,%rax
  ja     L129
  jmp    L93
L134:
  movzbl 0xf(%rsp),%eax
  mov    %al,0xe(%rsp)
  mov    $0x0,%eax
L99:
  test   %rsi,%rsi
  jne    L67
  lea    -0x1(%rax),%rcx
  movb   $0x30,0x9(%rsp,%rax,1)
  jmp    L93
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t szwrite(char *out, size_t s, const char *suf, const char *sufs) {
  const char suffix[] = {0, 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'};
  char b[6];
  size_t i;
  if (suf == NULL && sufs != NULL)
    suf = sufs;
  else if (suf != NULL && sufs == NULL)
    sufs = suf;
  for (i = 0; i < sizeof(suffix) && s > 9999; i++, s /= 1024)
    ;
  b[5] = suffix[i];
  if (s > 9999) {
    b[0] = '>';
    b[1] = b[2] = b[3] = b[4] = '9';
    i = 0;
  } else if (s == 0)
    b[i--] = '0';
  else
    for (i = 4; i > 0 && s > 0; i--, s /= 10)
      b[i] = s % 10 + '0';
  i++;
  s = sizeof(b) - i;
  (void)memcpy(out, b + i, s);
  if (b[5])
    suf = sufs;
  if (suf != NULL) {
    i = strlen(suf);
    (void)memcpy(out + s, suf, i);
    s += i;
  }
  return (s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<szwrite>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x5a455054474d4b00,%rax
  movb   $0x59,0x17(%rsp)
  mov    %rax,0xf(%rsp)
  test   %rdx,%rdx
  jne    L125
  test   %rcx,%rcx
  je     L82
  mov    %rcx,%rbp
L85:
  cmp    $0x270f,%rdi
  jbe    L112
L75:
  xor    %eax,%eax
L7:
  add    $0x1,%rax
  shr    $0xa,%rdi
  cmp    $0x8,%rax
  ja     L110
  cmp    $0x270f,%rdi
  ja     L7
L110:
  movzbl 0xf(%rsp,%rax,1),%eax
  mov    %al,0xe(%rsp)
  cmp    $0x270f,%rdi
  jbe    L67
  movb   $0x39,0xd(%rsp)
  mov    $0x5,%r13d
  lea    0xa(%rsp),%rsi
  movl   $0x3939393e,0x9(%rsp)
L33:
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <memcpy@plt>
  cmpb   $0x0,0xe(%rsp)
  cmovne %rbx,%rbp
  test   %rbp,%rbp
  je     L14
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%r13,1),%rdi
  mov    %rbp,%rsi
  mov    %rax,%rbx
  mov    %rax,%rdx
  call   <memcpy@plt>
  add    %rbx,%r13
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x28,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L82:
  test   %rdx,%rdx
  je     L85
L125:
  test   %rbx,%rbx
  cmove  %rbp,%rbx
  cmp    $0x270f,%rdi
  ja     L75
L112:
  movb   $0x0,0xe(%rsp)
  test   %rdi,%rdi
  jne    L67
  movb   $0x30,0x9(%rsp)
  mov    $0x6,%r13d
  lea    0x9(%rsp),%rsi
  jmp    L33
  nopl   0x0(%rax)
L67:
  mov    $0x4,%ecx
  lea    0x9(%rsp),%rsi
  movabs $0xcccccccccccccccd,%r9
  jmp    L118
  cs nopw 0x0(%rax,%rax,1)
L149:
  cmp    $0x9,%rax
  jbe    L45
L118:
  mov    %rdi,%rax
  mul    %r9
  mov    %rdi,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r8
  add    %r8,%r8
  sub    %r8,%rax
  mov    %rcx,%r8
  add    $0x30,%eax
  mov    %al,(%rsi,%rcx,1)
  mov    %rdi,%rax
  mov    %rdx,%rdi
  sub    $0x1,%rcx
  jne    L149
L45:
  mov    $0x6,%r13d
  add    %r8,%rsi
  sub    %r8,%r13
  jmp    L33
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
size_t szwrite(char *out, size_t s, const char *suf, const char *sufs) {
  const char suffix[] = {0, 'K', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y'};
  char b[6];
  size_t i;
  if (suf == NULL && sufs != NULL)
    suf = sufs;
  else if (suf != NULL && sufs == NULL)
    sufs = suf;
  for (i = 0; i < sizeof(suffix) && s > 9999; i++, s /= 1024)
    ;
  b[5] = suffix[i];
  if (s > 9999) {
    b[0] = '>';
    b[1] = b[2] = b[3] = b[4] = '9';
    i = 0;
  } else if (s == 0)
    b[i--] = '0';
  else
    for (i = 4; i > 0 && s > 0; i--, s /= 10)
      b[i] = s % 10 + '0';
  i++;
  s = sizeof(b) - i;
  (void)memcpy(out, b + i, s);
  if (b[5])
    suf = sufs;
  if (suf != NULL) {
    i = strlen(suf);
    (void)memcpy(out + s, suf, i);
    s += i;
  }
  return (s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<T2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_infered: string
name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D9
type_infered: string

tool: D0: J


tool: D13: Q


tool: D9: K


assistant: ```c
void T2() {
  printf("J\n");
  printf("Q\n");
  printf("K\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<T2>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D22
data_type: string

tool: D7: J


tool: D15: Q


tool: D22: K


assistant: ```c
void T2() {
  printf("J\n");
  printf("Q\n");
  printf("K\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<T2>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string

tool: D20: J


tool: D7: Q


tool: D12: K


assistant: ```c
void T2() {
  printf("J\n");
  printf("Q\n");
  printf("K\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<T2>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D14
type_guessed: string

tool: D0: J


tool: D13: Q


tool: D14: K


assistant: ```c
void T2() {
  printf("J\n");
  printf("Q\n");
  printf("K\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x39,-0xa(%rbp)
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <fun@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void main() {
  char a[] = "123456789", *p, *q;
  fun(a);
  puts(a);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3837363534333231,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x39,0x16(%rsp)
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <fun@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char a[] = "123456789", *p, *q;
  fun(a);
  puts(a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3837363534333231,%rax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  mov    %rax,0xe(%rsp)
  mov    $0x39,%eax
  mov    %ax,0x16(%rsp)
  call   <fun@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char a[] = "123456789", *p, *q;
  fun(a);
  puts(a);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3837363534333231,%rax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  mov    %rax,0xe(%rsp)
  mov    $0x39,%eax
  mov    %ax,0x16(%rsp)
  call   <fun@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char a[] = "123456789", *p, *q;
  fun(a);
  puts(a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sed_emulator>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x838,%rsp
  mov    %rsi,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x2828(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  je     L79
  mov    $0x0,%ebx
L8:
  mov    0x18(%rsp),%rax
  mov    (%rax,%rbx,8),%rdi
  call   <strlen@plt>
  mov    %rax,0x20(%rsp,%rbx,8)
  add    $0x1,%rbx
  cmp    0x10(%rsp),%rbx
  jne    L8
L79:
  lea    0x2420(%rsp),%rbp
  lea    0x2020(%rsp),%r12
  jmp    L66
L34:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L63
L22:
  addq   $0x2,0x8(%rsp)
  mov    0x8(%rsp),%rax
  add    $0x10,%r15
  add    $0x10,%r13
  cmp    0x10(%rsp),%rax
  jb     L94
L18:
  mov    %r12,%rdi
  call   <puts@plt>
L66:
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L34
L63:
  cmpq   $0x0,0x10(%rsp)
  je     L18
  lea    0x20(%rsp),%r15
  mov    0x18(%rsp),%rax
  lea    0x8(%rax),%r13
  movq   $0x0,0x8(%rsp)
L94:
  mov    %r13,%r14
  mov    -0x8(%r13),%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L22
  lea    D8(%rip),%rsi
  mov    0x0(%r13),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L66
  movb   $0x0,(%rbx)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    (%r14),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    (%r15),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  mov    %rbp,%r12
  mov    %rax,%rbp
  jmp    L94
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: /DELETE/

assistant: ```c
void sed_emulator(int narg, char **patterns) {
  char buffer[1024];
  char buffer2[1024];
  size_t i, lengths[1024];
  char *b1 = buffer, *b2 = buffer2;
  for (i = 0; i < narg; i++)
    lengths[i] = strlen(patterns[i]);
  while (1) {
    if (gets(b1) == 0)
      exit(0);
    for (i = 0; i < narg; i += 2) {
      char *b3, *b4;
      while ((b3 = strstr(b1, patterns[i]))) {
        if (strcmp(patterns[i + 1], "/DELETE/") == 0)
          goto GO_ON;
        b3[0] = 0;
        strcpy(b2, b1);
        strcat(b2, patterns[i + 1]);
        strcat(b2, b3 + lengths[i]);
        b4 = b2;
        b2 = b1;
        b1 = b4;
      }
    }
    puts(b1);
  GO_ON:;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sed_emulator>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x838,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2828(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsi,%r12
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L78
  lea    0x20(%rsp),%rax
  xor    %ebx,%ebx
  mov    %rax,0x10(%rsp)
L84:
  mov    (%r12,%rbx,8),%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,(%rcx,%rbx,8)
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L84
L87:
  lea    0x8(%r12),%rax
  lea    0x2420(%rsp),%rbx
  mov    %rax,0x18(%rsp)
  lea    0x2020(%rsp),%rbp
  lea    D6(%rip),%r14
  xchg   %ax,%ax
L64:
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L17
L8:
  cmpq   $0x0,0x8(%rsp)
  je     L14
  movq   $0x0,(%rsp)
  mov    0x10(%rsp),%r13
  mov    0x18(%rsp),%r12
  jmp    L88
  nopl   0x0(%rax)
L42:
  mov    (%r12),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L64
  movb   $0x0,(%r15)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x0(%r13),%rsi
  mov    %rbx,%rdi
  add    %r15,%rsi
  call   <strcat@plt>
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
L88:
  mov    -0x8(%r12),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L42
  addq   $0x2,(%rsp)
  add    $0x10,%r13
  mov    (%rsp),%rax
  add    $0x10,%r12
  cmp    0x8(%rsp),%rax
  jb     L88
L14:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L8
L17:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L8
L78:
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  jmp    L87
```

tool_calls: name: read_data
arguments: tag: D6
type: string

tool: D6: /DELETE/

assistant: ```c
void sed_emulator(int narg, char **patterns) {
  char buffer[1024];
  char buffer2[1024];
  size_t i, lengths[1024];
  char *b1 = buffer, *b2 = buffer2;
  for (i = 0; i < narg; i++)
    lengths[i] = strlen(patterns[i]);
  while (1) {
    if (gets(b1) == 0)
      exit(0);
    for (i = 0; i < narg; i += 2) {
      char *b3, *b4;
      while ((b3 = strstr(b1, patterns[i]))) {
        if (strcmp(patterns[i + 1], "/DELETE/") == 0)
          goto GO_ON;
        b3[0] = 0;
        strcpy(b2, b1);
        strcat(b2, patterns[i + 1]);
        strcat(b2, b3 + lengths[i]);
        b4 = b2;
        b2 = b1;
        b1 = b4;
      }
    }
    puts(b1);
  GO_ON:;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sed_emulator>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x838,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2828(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsi,%r12
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L49
  lea    0x20(%rsp),%rax
  xor    %ebx,%ebx
  mov    %rax,0x10(%rsp)
L20:
  mov    (%r12,%rbx,8),%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,(%rcx,%rbx,8)
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L20
L37:
  lea    0x8(%r12),%rax
  lea    0x2420(%rsp),%rbx
  mov    %rax,0x18(%rsp)
  lea    0x2020(%rsp),%rbp
  lea    D4(%rip),%r14
  xchg   %ax,%ax
L48:
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L69
L5:
  cmpq   $0x0,0x8(%rsp)
  je     L47
  movq   $0x0,(%rsp)
  mov    0x10(%rsp),%r13
  mov    0x18(%rsp),%r12
  jmp    L109
  nopl   0x0(%rax)
L56:
  mov    (%r12),%rdi
  mov    %r14,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  movb   $0x0,(%r15)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    (%r12),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    0x0(%r13),%rsi
  mov    %rbx,%rdi
  add    %r15,%rsi
  call   <strcat@plt>
  mov    %rbp,%rax
  mov    %rbx,%rbp
  mov    %rax,%rbx
L109:
  mov    -0x8(%r12),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r15
  test   %rax,%rax
  jne    L56
  addq   $0x2,(%rsp)
  add    $0x10,%r13
  mov    (%rsp),%rax
  add    $0x10,%r12
  cmp    0x8(%rsp),%rax
  jb     L109
L47:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L5
L69:
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L5
L49:
  lea    0x20(%rsp),%rax
  mov    %rax,0x10(%rsp)
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: /DELETE/

assistant: ```c
void sed_emulator(int narg, char **patterns) {
  char buffer[1024];
  char buffer2[1024];
  size_t i, lengths[1024];
  char *b1 = buffer, *b2 = buffer2;
  for (i = 0; i < narg; i++)
    lengths[i] = strlen(patterns[i]);
  while (1) {
    if (gets(b1) == 0)
      exit(0);
    for (i = 0; i < narg; i += 2) {
      char *b3, *b4;
      while ((b3 = strstr(b1, patterns[i]))) {
        if (strcmp(patterns[i + 1], "/DELETE/") == 0)
          goto GO_ON;
        b3[0] = 0;
        strcpy(b2, b1);
        strcat(b2, patterns[i + 1]);
        strcat(b2, b3 + lengths[i]);
        b4 = b2;
        b2 = b1;
        b1 = b4;
      }
    }
    puts(b1);
  GO_ON:;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x186000(%rsp),%r11
L68:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L68
  sub    $0xa70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x186a70(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x0,-0x186a68(%rbp)
  jmp    L38
L71:
  mov    -0x186a68(%rbp),%rax
  movq   $0x0,-0xc3530(%rbp,%rax,8)
  lea    -0x186a60(%rbp),%rdx
  mov    -0x186a68(%rbp),%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addq   $0x1,-0x186a68(%rbp)
L38:
  mov    -0x186a70(%rbp),%rax
  cmp    %rax,-0x186a68(%rbp)
  jl     L71
  mov    -0x186a70(%rbp),%rax
  movq   $0x0,-0x186a60(%rbp,%rax,8)
  movq   $0x0,-0x186a68(%rbp)
  jmp    L60
L65:
  mov    -0x186a68(%rbp),%rax
  mov    -0x186a60(%rbp,%rax,8),%rdx
  mov    -0x186a68(%rbp),%rax
  add    $0x1,%rax
  mov    -0x186a60(%rbp,%rax,8),%rax
  add    %rax,%rdx
  mov    -0x186a68(%rbp),%rax
  mov    %rdx,-0xc3530(%rbp,%rax,8)
  addq   $0x1,-0x186a68(%rbp)
L60:
  mov    -0x186a70(%rbp),%rax
  cmp    %rax,-0x186a68(%rbp)
  jl     L65
  movq   $0x0,-0x186a68(%rbp)
  jmp    L21
L66:
  mov    -0x186a68(%rbp),%rax
  mov    -0xc3530(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x186a68(%rbp)
L21:
  mov    -0x186a70(%rbp),%rax
  cmp    %rax,-0x186a68(%rbp)
  jl     L66
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D20
data_type: string

tool: D3: %lld

tool: D20: %lld 

assistant: ```c
int main(void) {
  long long n, i, ar[100005], br[100005];
  scanf("%lld", &n);
  for (i = 0; i < n; i++) {
    br[i] = 0;
    scanf("%lld", &ar[i]);
  }
  ar[n] = 0;
  for (i = 0; i < n; i++) {
    br[i] = ar[i] + ar[i + 1];
  }
  for (i = 0; i < n; i++)
    printf("%lld ", br[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x186000(%rsp),%r11
L24:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L24
  sub    $0xa70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186a68(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L18
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D22(%rip),%r12
L21:
  movq   $0x0,0xc3540(%rsp,%rbx,8)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%rbx
  mov    0x8(%rsp),%rcx
  add    $0x8,%rbp
  cmp    %rbx,%rcx
  jg     L21
  movq   $0x0,0x10(%rsp,%rcx,8)
  test   %rcx,%rcx
  jle    L18
  lea    0xc3540(%rsp),%rax
  lea    0x18(%rsp),%rdx
  lea    (%rax,%rcx,8),%rsi
L5:
  mov    (%rdx),%rcx
  add    -0x8(%rdx),%rcx
  mov    %rcx,(%rax)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  jne    L5
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
L49:
  mov    0xc3540(%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jg     L49
L18:
  mov    0x186a68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x186a70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D22: %lld

tool: D14: %lld 

assistant: ```c
int main(void) {
  long long n, i, ar[100005], br[100005];
  scanf("%lld", &n);
  for (i = 0; i < n; i++) {
    br[i] = 0;
    scanf("%lld", &ar[i]);
  }
  ar[n] = 0;
  for (i = 0; i < n; i++) {
    br[i] = ar[i] + ar[i + 1];
  }
  for (i = 0; i < n; i++)
    printf("%lld ", br[i]);
  return 0;
}
```