ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<panicf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x3f,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <panic@plt>
  nop
  leave
  ret
```

assistant: ```c
void panicf(const char *fmt, ...) {
  static char buf[64];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof buf - 1, fmt, ap);
  va_end(ap);
  panic(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<panicf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x3f,%esi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <panic@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void panicf(const char *fmt, ...) {
  static char buf[64];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof buf - 1, fmt, ap);
  va_end(ap);
  panic(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<panicf>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    $0x3f,%esi
  lea    D3(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <panic@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void panicf(const char *fmt, ...) {
  static char buf[64];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof buf - 1, fmt, ap);
  va_end(ap);
  panic(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<panicf>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    $0x3f,%esi
  lea    D9(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rdi
  call   <panic@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void panicf(const char *fmt, ...) {
  static char buf[64];
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof buf - 1, fmt, ap);
  va_end(ap);
  panic(buf);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%r13
  mov    $0x0,%ebx
  lea    D55(%rip),%r15
  lea    D87(%rip),%r14
L20:
  lea    0x1(%rbx),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rsi
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rbp
  lea    0x0(%rbp,%rbx,4),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  add    $0xa,%r13
  cmp    $0x5,%rbx
  jne    L20
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x32(%r12),%r13
  lea    D33(%rip),%rbx
L28:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp),%xmm0
  movsd  D44(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  add    $0xa,%r12
  cmp    %r13,%r12
  jne    L28
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D55
type: string
name: read_data
arguments: label: D87
type: string
name: read_data
arguments: label: D52
type: string
name: read_data
arguments: label: D17
type: string
name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D33
type: string
name: read_data
arguments: label: D44
type: f64
name: read_data
arguments: label: D13
type: string

tool: D55: 
Entre com o nome do funcionario %d: 

tool: D87: %s

tool: D52: 
Entre com o salario do funcionario %s: 

tool: D17: %f

tool: D28: 
Funcionario		Sal.Bruto	Sal.Liq

tool: D16: 
------------------------------------------

tool: D33: 
%s 			%.2f 		%.2f

tool: D44: 0.8

tool: D13: 
-------------------------------------------

assistant: ```c
int main() {
  char nome[5][10];
  float salario[5];
  int i;
  for (i = 0; i <= 4; i++) {
    printf("\nEntre com o nome do funcionario %d: ", i + 1);
    scanf("%s", nome[i]);
    printf("\nEntre com o salario do funcionario %s: ", nome[i]);
    scanf("%f", &salario[i]);
  }
  printf("\nFuncionario\t\tSal.Bruto\tSal.Liq");
  printf("\n------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s \t\t\t%.2f \t\t%.2f", nome[i], salario[i], salario[i] * 0.8);
  }
  printf("\n-------------------------------------------");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D66(%rip),%r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x30(%rsp),%r12
  mov    %rax,0x8(%rsp)
  mov    %r12,%rbx
L22:
  lea    0x1(%rbp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D53(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r13
  xor    %eax,%eax
  add    $0xa,%rbx
  lea    D27(%rip),%rdi
  lea    0x0(%r13,%rbp,4),%rsi
  add    $0x1,%rbp
  call   <scanf@plt>
  cmp    $0x5,%rbp
  jne    L22
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  lea    0x32(%r12),%rbp
  call   <printf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  lea    D0(%rip),%rbx
  call   <printf@plt>
L25:
  pxor   %xmm0,%xmm0
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  D87(%rip),%xmm1
  cvtss2sd 0x0(%r13),%xmm0
  add    $0xa,%r12
  add    $0x4,%r13
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L25
  xor    %eax,%eax
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D66
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D53
data_type: string
name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D49
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D87
data_type: f64
name: extract_symbolic_data
arguments: label: D74
data_type: string

tool: D66: 
Entre com o nome do funcionario %d: 

tool: D13: %s

tool: D53: 
Entre com o salario do funcionario %s: 

tool: D27: %f

tool: D49: 
Funcionario		Sal.Bruto	Sal.Liq

tool: D10: 
------------------------------------------

tool: D0: 
%s 			%.2f 		%.2f

tool: D87: 0.8

tool: D74: 
-------------------------------------------

assistant: ```c
int main() {
  char nome[5][10];
  float salario[5];
  int i;
  for (i = 0; i <= 4; i++) {
    printf("\nEntre com o nome do funcionario %d: ", i + 1);
    scanf("%s", nome[i]);
    printf("\nEntre com o salario do funcionario %s: ", nome[i]);
    scanf("%f", &salario[i]);
  }
  printf("\nFuncionario\t\tSal.Bruto\tSal.Liq");
  printf("\n------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s \t\t\t%.2f \t\t%.2f", nome[i], salario[i], salario[i] * 0.8);
  }
  printf("\n-------------------------------------------");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D23(%rip),%r15
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  lea    0x30(%rsp),%r12
  mov    %rax,0x8(%rsp)
  mov    %r12,%rbx
L18:
  lea    0x1(%rbp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r13
  xor    %eax,%eax
  add    $0xa,%rbx
  lea    D12(%rip),%rdi
  lea    0x0(%r13,%rbp,4),%rsi
  add    $0x1,%rbp
  call   <scanf@plt>
  cmp    $0x5,%rbp
  jne    L18
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  lea    0x32(%r12),%rbp
  call   <printf@plt>
  lea    D73(%rip),%rdi
  xor    %eax,%eax
  lea    D22(%rip),%rbx
  call   <printf@plt>
L19:
  pxor   %xmm0,%xmm0
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  D72(%rip),%xmm1
  cvtss2sd 0x0(%r13),%xmm0
  add    $0xa,%r12
  add    $0x4,%r13
  mulsd  %xmm0,%xmm1
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L19
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D23
type: string
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D73
type: string
name: unpack_data
arguments: tag: D22
type: string
name: unpack_data
arguments: tag: D72
type: f64
name: unpack_data
arguments: tag: D29
type: string

tool: D23: 
Entre com o nome do funcionario %d: 

tool: D31: %s

tool: D1: 
Entre com o salario do funcionario %s: 

tool: D12: %f

tool: D8: 
Funcionario		Sal.Bruto	Sal.Liq

tool: D73: 
------------------------------------------

tool: D22: 
%s 			%.2f 		%.2f

tool: D72: 0.8

tool: D29: 
-------------------------------------------

assistant: ```c
int main() {
  char nome[5][10];
  float salario[5];
  int i;
  for (i = 0; i <= 4; i++) {
    printf("\nEntre com o nome do funcionario %d: ", i + 1);
    scanf("%s", nome[i]);
    printf("\nEntre com o salario do funcionario %s: ", nome[i]);
    scanf("%f", &salario[i]);
  }
  printf("\nFuncionario\t\tSal.Bruto\tSal.Liq");
  printf("\n------------------------------------------");
  for (i = 0; i < 5; i++) {
    printf("\n%s \t\t\t%.2f \t\t%.2f", nome[i], salario[i], salario[i] * 0.8);
  }
  printf("\n-------------------------------------------");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<glPauseTransformFeedback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <next_glPauseTransformFeedback@plt>
  mov    $0x0,%eax
  call   <printGLError@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <debugPrint@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: glPauseTransformFeedback()


assistant: ```c
void glPauseTransformFeedback() {
  next_glPauseTransformFeedback();
  printGLError();
  debugPrint("glPauseTransformFeedback()\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<glPauseTransformFeedback>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <next_glPauseTransformFeedback@plt>
  mov    $0x0,%eax
  call   <printGLError@plt>
  lea    D8(%rip),%rdi
  call   <debugPrint@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: glPauseTransformFeedback()


assistant: ```c
void glPauseTransformFeedback() {
  next_glPauseTransformFeedback();
  printGLError();
  debugPrint("glPauseTransformFeedback()\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<glPauseTransformFeedback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <next_glPauseTransformFeedback@plt>
  xor    %eax,%eax
  call   <printGLError@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <debugPrint@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string

tool: D7: glPauseTransformFeedback()


assistant: ```c
void glPauseTransformFeedback() {
  next_glPauseTransformFeedback();
  printGLError();
  debugPrint("glPauseTransformFeedback()\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<glPauseTransformFeedback>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <next_glPauseTransformFeedback@plt>
  xor    %eax,%eax
  call   <printGLError@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <debugPrint@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: glPauseTransformFeedback()


assistant: ```c
void glPauseTransformFeedback() {
  next_glPauseTransformFeedback();
  printGLError();
  debugPrint("glPauseTransformFeedback()\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cimg2dimg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L11:
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L55
L21:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L21
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L11
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cimg2dimg(unsigned char *src, double *dst, int w, int h, int dp, double norm) {
  int i, j, k;
  int lw;
  lw = w * dp;
  for (j = 0; j < h; j++) {
    for (i = 0; i < w; i++) {
      for (k = 0; k < dp; k++)
        dst[j * lw + i * dp + k] = norm * src[j * lw + i * dp + k];
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<cimg2dimg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r14d
  imul   %r8d,%r14d
  test   %ecx,%ecx
  jle    L44
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %edx,%r10d
  mov    %ecx,%r13d
  mov    %r8d,%r9d
  movapd %xmm0,%xmm1
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    %r8d,%esi
  jmp    L74
L71:
  movslq %r8d,%rdx
  lea    (%rbx,%rdx,8),%rcx
  mov    $0x0,%eax
  add    %r11,%rdx
L15:
  movzbl (%rdx,%rax,1),%r15d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r15d,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L15
L22:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %edi,%r10d
  je     L72
L82:
  test   %r9d,%r9d
  jg     L71
  jmp    L22
L72:
  add    $0x1,%ebp
  add    %r14d,%r12d
  cmp    %ebp,%r13d
  je     L44
L74:
  test   %r10d,%r10d
  jle    L72
  mov    %r12d,%r8d
  mov    $0x0,%edi
  jmp    L82
L44:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cimg2dimg(unsigned char *src, double *dst, int w, int h, int dp, double norm) {
  int i, j, k;
  int lw;
  lw = w * dp;
  for (j = 0; j < h; j++) {
    for (i = 0; i < w; i++) {
      for (k = 0; k < dp; k++)
        dst[j * lw + i * dp + k] = norm * src[j * lw + i * dp + k];
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cimg2dimg>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  imul   %r8d,%r14d
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  jle    L1
  mov    %rsi,%rbx
  mov    %rdi,%r11
  mov    %edx,%r10d
  mov    %ecx,%r13d
  mov    %r8d,%r9d
  movapd %xmm0,%xmm1
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  lea    -0x1(%r8),%esi
  nopl   0x0(%rax)
L27:
  test   %r10d,%r10d
  jle    L4
  mov    %r12d,%r8d
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L37:
  test   %r9d,%r9d
  jle    L46
  movslq %r8d,%rdx
  xor    %eax,%eax
  lea    (%rbx,%rdx,8),%rcx
  add    %r11,%rdx
  nopl   0x0(%rax)
L32:
  movzbl (%rdx,%rax,1),%r15d
  pxor   %xmm0,%xmm0
  cvtsi2sd %r15d,%xmm0
  mov    %rax,%r15
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %r15,%rsi
  jne    L32
L46:
  add    $0x1,%edi
  add    %r9d,%r8d
  cmp    %edi,%r10d
  jne    L37
L4:
  add    $0x1,%ebp
  add    %r14d,%r12d
  cmp    %ebp,%r13d
  jne    L27
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cimg2dimg(unsigned char *src, double *dst, int w, int h, int dp, double norm) {
  int i, j, k;
  int lw;
  lw = w * dp;
  for (j = 0; j < h; j++) {
    for (i = 0; i < w; i++) {
      for (k = 0; k < dp; k++)
        dst[j * lw + i * dp + k] = norm * src[j * lw + i * dp + k];
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<process_internal_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  je     L56
  mov    -0x8(%rbp),%rax
  lea    D53(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L39
L56:
  mov    $0x1,%eax
  jmp    L131
L39:
  mov    -0x8(%rbp),%rax
  lea    D79(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  je     L50
  mov    -0x8(%rbp),%rax
  lea    D74(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L87
L50:
  mov    $0x2,%eax
  jmp    L131
L87:
  mov    -0x8(%rbp),%rax
  lea    D49(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L79
  mov    $0x3,%eax
  jmp    L131
L79:
  mov    -0x8(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L1
  mov    $0x4,%eax
  jmp    L131
L1:
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L85
  mov    $0x5,%eax
  jmp    L131
L85:
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L13
  mov    $0x6,%eax
  jmp    L131
L13:
  mov    $0x0,%eax
L131:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D53
type: string
name: unpack_data
arguments: tag: D79
type: string
name: unpack_data
arguments: tag: D74
type: string
name: unpack_data
arguments: tag: D49
type: string
name: unpack_data
arguments: tag: D21
type: string
name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D8
type: string

tool: D13: exit

tool: D53: quit

tool: D79: clear

tool: D74: cls

tool: D49: path

tool: D21: cd

tool: D17: fmount

tool: D8: fumount

assistant: ```c
int process_internal_command(char *cmd) {
  if (strstr(cmd, "exit") == cmd || strstr(cmd, "quit") == cmd) {
    return 1;
  }
  if (strstr(cmd, "clear") == cmd || strstr(cmd, "cls") == cmd) {
    return 2;
  }
  if (strstr(cmd, "path") == cmd) {
    return 3;
  }
  if (strstr(cmd, "cd") == cmd) {
    return 4;
  }
  if (strstr(cmd, "fmount") == cmd) {
    return 5;
  }
  if (strstr(cmd, "fumount") == cmd) {
    return 6;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<process_internal_command>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D34(%rip),%rsi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L34
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L123
  lea    D32(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L63
  lea    D77(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L93
  lea    D66(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L1
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L131
  lea    D20(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L101
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  mov    $0x0,%eax
  mov    $0x6,%edx
  cmove  %edx,%eax
L68:
  pop    %rbx
  ret
L34:
  mov    $0x1,%eax
  jmp    L68
L123:
  mov    $0x1,%eax
  jmp    L68
L63:
  mov    $0x2,%eax
  jmp    L68
L93:
  mov    $0x2,%eax
  jmp    L68
L1:
  mov    $0x3,%eax
  jmp    L68
L131:
  mov    $0x4,%eax
  jmp    L68
L101:
  mov    $0x5,%eax
  jmp    L68
```

tool_calls: name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D15
data_type: string
name: read_data
arguments: data_label: D32
data_type: string
name: read_data
arguments: data_label: D77
data_type: string
name: read_data
arguments: data_label: D66
data_type: string
name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D22
data_type: string

tool: D34: exit

tool: D15: quit

tool: D32: clear

tool: D77: cls

tool: D66: path

tool: D10: cd

tool: D20: fmount

tool: D22: fumount

assistant: ```c
int process_internal_command(char *cmd) {
  if (strstr(cmd, "exit") == cmd || strstr(cmd, "quit") == cmd) {
    return 1;
  }
  if (strstr(cmd, "clear") == cmd || strstr(cmd, "cls") == cmd) {
    return 2;
  }
  if (strstr(cmd, "path") == cmd) {
    return 3;
  }
  if (strstr(cmd, "cd") == cmd) {
    return 4;
  }
  if (strstr(cmd, "fmount") == cmd) {
    return 5;
  }
  if (strstr(cmd, "fumount") == cmd) {
    return 6;
  }
  return 0;
}
```