ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  lea    0x4(%rdi),%r10
  nopl   0x0(%rax)
L30:
  test   %r9d,%r9d
  jle    L25
  lea    -0x1(%r9),%edx
  mov    %rdi,%rax
  xor    %r8d,%r8d
  mov    %rdx,%r9
  lea    (%r10,%rdx,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L27
  mov    %ecx,(%rax)
  mov    $0x1,%r8d
  mov    %edx,0x4(%rax)
L27:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L8
  test   %r8b,%r8b
  jne    L30
L25:
  ret
```

assistant: ```c
void bubbleSort(int arr[], int n) {
  _Bool swapped = 1;
  int j = 0;
  int tmp;
  int i;
  while (swapped) {
    swapped = 0;
    j++;
    for (i = 0; i < n - j; i++) {
      if (arr[i] > arr[i + 1]) {
        tmp = arr[i];
        arr[i] = arr[i + 1];
        arr[i + 1] = tmp;
        swapped = 1;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bubbleSort>:
  endbr64
  lea    -0x1(%rsi),%r9d
  lea    0x4(%rdi),%r10
  nopl   0x0(%rax)
L5:
  test   %r9d,%r9d
  jle    L30
  lea    -0x1(%r9),%eax
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  mov    %rax,%r9
  lea    (%r10,%rax,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L29:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L25
  movq   %xmm1,(%rdx)
  mov    $0x1,%r8d
L25:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L29
  test   %r8b,%r8b
  jne    L5
L30:
  ret
```

assistant: ```c
void bubbleSort(int arr[], int n) {
  _Bool swapped = 1;
  int j = 0;
  int tmp;
  int i;
  while (swapped) {
    swapped = 0;
    j++;
    for (i = 0; i < n - j; i++) {
      if (arr[i] > arr[i + 1]) {
        tmp = arr[i];
        arr[i] = arr[i + 1];
        arr[i + 1] = tmp;
        swapped = 1;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_to_nasm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0xd,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0xb,-0x10(%rbp)
  jmp    L13
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  lea    D11(%rip),%rdx
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  addq   $0x5,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L13:
  cmpq   $0x0,-0x20(%rbp)
  jne    L11
  mov    -0x10(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
data_type: string
name: parse_data
arguments: tag: D11
data_type: string
name: parse_data
arguments: tag: D15
data_type: string

tool: D13: payload db 

tool: D11: 0x%02x,

tool: D15: 0

assistant: ```c
char *str_to_nasm(char *bytes, size_t szBytes) {
  char *buffer, *backup;
  buffer = calloc(strlen("payload db ") + szBytes * 5 + 2, sizeof(*buffer));
  backup = buffer;
  strcpy(buffer, "payload db ");
  buffer += strlen("payload db ");
  while (szBytes) {
    snprintf(buffer, 6, "0x%02x,", *bytes & 0xff);
    buffer += 5;
    bytes++;
    szBytes--;
  }
  strcat(buffer, "0");
  return backup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_to_nasm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  lea    (%rsi,%rsi,4),%rax
  mov    %rax,0x8(%rsp)
  lea    0xd(%rax),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r14
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xb(%r14),%r15
  test   %r12,%r12
  je     L11
  add    %rbx,%r12
  mov    %r15,%rbp
  lea    D26(%rip),%r13
L14:
  movsbl (%rbx),%ecx
  mov    %r13,%rdx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  add    $0x5,%rbp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L14
  add    0x8(%rsp),%r15
L11:
  lea    D27(%rip),%rsi
  mov    %r15,%rdi
  call   <strcat@plt>
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string
name: unpack_data
arguments: tag: D27
datatype: string

tool: D0: payload db 

tool: D26: 0x%02x,

tool: D27: 0

assistant: ```c
char *str_to_nasm(char *bytes, size_t szBytes) {
  char *buffer, *backup;
  buffer = calloc(strlen("payload db ") + szBytes * 5 + 2, sizeof(*buffer));
  backup = buffer;
  strcpy(buffer, "payload db ");
  buffer += strlen("payload db ");
  while (szBytes) {
    snprintf(buffer, 6, "0x%02x,", *bytes & 0xff);
    buffer += 5;
    bytes++;
    szBytes--;
  }
  strcat(buffer, "0");
  return backup;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_to_nasm>:
  endbr64
  push   %r15
  lea    (%rsi,%rsi,4),%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  lea    0xd(%rax),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <calloc@plt>
  lea    D3(%rip),%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xb(%r13),%r14
  test   %rbp,%rbp
  je     L5
  add    %rbx,%rbp
  mov    %r14,%r15
  lea    D11(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L13:
  movsbl (%rbx),%ecx
  mov    %r15,%rdi
  mov    %r12,%rdx
  mov    $0x6,%esi
  add    $0x1,%rbx
  add    $0x5,%r15
  call   <snprintf@plt>
  cmp    %rbx,%rbp
  jne    L13
  add    0x8(%rsp),%r14
L5:
  mov    %r14,%rdi
  lea    D23(%rip),%rsi
  call   <strcat@plt>
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D11
type: string
name: read_data
arguments: tag: D23
type: string

tool: D3: payload db 

tool: D11: 0x%02x,

tool: D23: 0

assistant: ```c
char *str_to_nasm(char *bytes, size_t szBytes) {
  char *buffer, *backup;
  buffer = calloc(strlen("payload db ") + szBytes * 5 + 2, sizeof(*buffer));
  backup = buffer;
  strcpy(buffer, "payload db ");
  buffer += strlen("payload db ");
  while (szBytes) {
    snprintf(buffer, 6, "0x%02x,", *bytes & 0xff);
    buffer += 5;
    bytes++;
    szBytes--;
  }
  strcat(buffer, "0");
  return backup;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_to_nasm>:
  endbr64
  push   %r15
  lea    (%rsi,%rsi,4),%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  lea    0xd(%rax),%rdi
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  call   <calloc@plt>
  lea    D9(%rip),%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xb(%r13),%r14
  test   %rbp,%rbp
  je     L7
  add    %rbx,%rbp
  mov    %r14,%r15
  lea    D28(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl (%rbx),%ecx
  mov    %r15,%rdi
  mov    %r12,%rdx
  mov    $0x6,%esi
  add    $0x1,%rbx
  add    $0x5,%r15
  call   <snprintf@plt>
  cmp    %rbx,%rbp
  jne    L17
  add    0x8(%rsp),%r14
L7:
  mov    %r14,%rdi
  lea    D12(%rip),%rsi
  call   <strcat@plt>
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string
name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D12
data_type: string

tool: D9: payload db 

tool: D28: 0x%02x,

tool: D12: 0

assistant: ```c
char *str_to_nasm(char *bytes, size_t szBytes) {
  char *buffer, *backup;
  buffer = calloc(strlen("payload db ") + szBytes * 5 + 2, sizeof(*buffer));
  backup = buffer;
  strcpy(buffer, "payload db ");
  buffer += strlen("payload db ");
  while (szBytes) {
    snprintf(buffer, 6, "0x%02x,", *bytes & 0xff);
    buffer += 5;
    bytes++;
    szBytes--;
  }
  strcat(buffer, "0");
  return backup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mtgp32_temper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  xor    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  and    $0xf,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t mtgp32_temper(const uint32_t tmp_tbl[16], uint32_t r, uint32_t t) {
  t ^= t >> 16;
  t ^= t >> 8;
  r ^= tmp_tbl[t & 0x0f];
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mtgp32_temper>:
  endbr64
  mov    %edx,%ecx
  sar    $0x10,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x8,%edx
  xor    %ecx,%edx
  and    $0xf,%edx
  mov    %esi,%eax
  xor    (%rdi,%rdx,4),%eax
  ret
```

assistant: ```c
uint32_t mtgp32_temper(const uint32_t tmp_tbl[16], uint32_t r, uint32_t t) {
  t ^= t >> 16;
  t ^= t >> 8;
  r ^= tmp_tbl[t & 0x0f];
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mtgp32_temper>:
  endbr64
  mov    %edx,%ecx
  sar    $0x10,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x8,%edx
  xor    %ecx,%edx
  and    $0xf,%edx
  mov    (%rdi,%rdx,4),%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
uint32_t mtgp32_temper(const uint32_t tmp_tbl[16], uint32_t r, uint32_t t) {
  t ^= t >> 16;
  t ^= t >> 8;
  r ^= tmp_tbl[t & 0x0f];
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<mtgp32_temper>:
  endbr64
  mov    %edx,%ecx
  sar    $0x10,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x8,%edx
  xor    %ecx,%edx
  and    $0xf,%edx
  mov    (%rdi,%rdx,4),%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
uint32_t mtgp32_temper(const uint32_t tmp_tbl[16], uint32_t r, uint32_t t) {
  t ^= t >> 16;
  t ^= t >> 8;
  r ^= tmp_tbl[t & 0x0f];
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mm>:
  endbr64
  test   %r8d,%r8d
  jle    L35
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rdx,%rax
  mov    %ecx,%ebx
  mov    %r9d,%r12d
  mov    %rdx,%r10
  lea    -0x1(%r8),%edx
  lea    0x8(%rax,%rdx,8),%r13
  lea    -0x1(%r9),%eax
  lea    0x4(,%rax,4),%rbp
  lea    -0x5(%rcx),%eax
  lea    0x14(,%rax,4),%r9
  jmp    L30
L60:
  mov    %r10,%rdi
  mov    (%r10),%rax
  movl   $0x0,(%rax,%rdx,1)
  mov    %rdx,%rax
  add    (%r10),%rax
  mov    %r11,%r8
  mov    (%r11),%rcx
  mov    (%rsi),%r14
  movss  (%r14,%rdx,1),%xmm0
  mulss  (%rcx),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  mov    %rdx,%rax
  add    (%r10),%rax
  mov    (%r11),%rcx
  mov    0x8(%rsi),%r14
  movss  (%r14,%rdx,1),%xmm0
  mulss  0x4(%rcx),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  mov    %rdx,%rax
  add    (%r10),%rax
  mov    (%r11),%rcx
  mov    0x10(%rsi),%r14
  movss  (%r14,%rdx,1),%xmm0
  mulss  0x8(%rcx),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  mov    %rdx,%rax
  add    (%r10),%rax
  mov    (%r11),%rcx
  mov    0x18(%rsi),%r14
  movss  (%r14,%rdx,1),%xmm0
  mulss  0xc(%rcx),%xmm0
  addss  (%rax),%xmm0
  movss  %xmm0,(%rax)
  cmp    $0x4,%ebx
  jle    L28
  mov    $0x10,%eax
L53:
  mov    %rdx,%rcx
  add    (%rdi),%rcx
  mov    (%r8),%r14
  movss  (%r14,%rax,1),%xmm0
  mov    (%rsi,%rax,2),%r14
  mulss  (%r14,%rdx,1),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L53
L28:
  add    $0x4,%rdx
  cmp    %rbp,%rdx
  jne    L60
L51:
  add    $0x8,%r10
  add    $0x8,%r11
  cmp    %r13,%r10
  je     L1
L30:
  mov    $0x0,%edx
  test   %r12d,%r12d
  jg     L60
  jmp    L51
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int _t12;
  int _t11;
  int _t10;
  int _t9;
  int _t8;
  int _t7;
  int _t6;
  int _t5;
  int _t4;
  int _t3;
  int _t2;
  int _t1;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an - 1; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1) {
      C[t2][t4] = 0.0f;
      C[t2][t4] += (A[t2][0] * B[0][t4]);
      C[t2][t4] += (A[t2][1] * B[1][t4]);
      C[t2][t4] += (A[t2][2] * B[2][t4]);
      C[t2][t4] += (A[t2][3] * B[3][t4]);
      for (t6 = 4; t6 <= ambn - 1; t6 += 1)
        C[t2][t4] += (A[t2][t6] * B[t6][t4]);
    }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mm>:
  endbr64
  push   %r15
  movslq %r8d,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x10(%rsp)
  mov    %rdx,-0x8(%rsp)
  test   %eax,%eax
  jle    L12
  mov    %ecx,%r13d
  mov    %rax,-0x18(%rsp)
  lea    -0x1(%r9),%eax
  mov    %rsi,%r10
  mov    %r9d,%r15d
  xor    %r14d,%r14d
  pxor   %xmm2,%xmm2
  movslq %r13d,%r8
  lea    0x4(,%rax,4),%rcx
  nopw   0x0(%rax,%rax,1)
L36:
  test   %r15d,%r15d
  jle    L44
  mov    -0x10(%rsp),%rax
  mov    (%r10),%r12
  xor    %esi,%esi
  mov    0x8(%r10),%rbp
  mov    0x10(%r10),%rbx
  mov    (%rax,%r14,8),%rdi
  mov    -0x8(%rsp),%rax
  mov    0x18(%r10),%r11
  mov    (%rax,%r14,8),%rdx
  lea    (%rcx,%rdx,1),%r9
L5:
  movl   $0x0,(%rdx)
  movss  (%rdi),%xmm0
  mov    $0x4,%eax
  mulss  (%r12,%rsi,1),%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%rdi),%xmm1
  mulss  0x0(%rbp,%rsi,1),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  movss  0x8(%rdi),%xmm0
  mulss  (%rbx,%rsi,1),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0xc(%rdi),%xmm1
  mulss  (%r11,%rsi,1),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    $0x4,%r13d
  jle    L27
  mov    %rcx,-0x20(%rsp)
L51:
  mov    (%r10,%rax,8),%rcx
  movss  (%rcx,%rsi,1),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %r8,%rax
  jne    L51
  mov    -0x20(%rsp),%rcx
L27:
  add    $0x4,%rdx
  add    $0x4,%rsi
  cmp    %r9,%rdx
  jne    L5
L44:
  add    $0x1,%r14
  cmp    -0x18(%rsp),%r14
  jne    L36
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int _t12;
  int _t11;
  int _t10;
  int _t9;
  int _t8;
  int _t7;
  int _t6;
  int _t5;
  int _t4;
  int _t3;
  int _t2;
  int _t1;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an - 1; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1) {
      C[t2][t4] = 0.0f;
      C[t2][t4] += (A[t2][0] * B[0][t4]);
      C[t2][t4] += (A[t2][1] * B[1][t4]);
      C[t2][t4] += (A[t2][2] * B[2][t4]);
      C[t2][t4] += (A[t2][3] * B[3][t4]);
      for (t6 = 4; t6 <= ambn - 1; t6 += 1)
        C[t2][t4] += (A[t2][t6] * B[t6][t4]);
    }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x8(%rsp)
  test   %r8d,%r8d
  jle    L8
  mov    %r9d,%eax
  test   %eax,%eax
  jle    L8
  mov    %rsi,%r10
  mov    %ecx,%r11d
  movslq %r8d,%rsi
  xor    %r15d,%r15d
  mov    (%r10),%r14
  mov    0x8(%r10),%r13
  mov    %rsi,-0x10(%rsp)
  pxor   %xmm2,%xmm2
  mov    0x10(%r10),%rbp
  mov    0x18(%r10),%rbx
  movslq %r11d,%r8
  mov    %rdx,%rsi
  lea    0x0(,%rax,4),%rcx
  nopl   0x0(%rax)
L27:
  mov    -0x8(%rsp),%rax
  mov    (%rsi,%r15,8),%rdx
  xor    %edi,%edi
  mov    (%rax,%r15,8),%r9
  lea    (%rcx,%rdx,1),%r12
  nopl   0x0(%rax,%rax,1)
L29:
  movl   $0x0,(%rdx)
  movss  (%r9),%xmm0
  mov    $0x4,%eax
  mulss  (%r14,%rdi,1),%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rdx)
  movss  0x4(%r9),%xmm1
  mulss  0x0(%r13,%rdi,1),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  movss  0x8(%r9),%xmm0
  mulss  0x0(%rbp,%rdi,1),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdx)
  movss  0xc(%r9),%xmm1
  mulss  (%rbx,%rdi,1),%xmm1
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    $0x4,%r11d
  jle    L6
  mov    %rcx,-0x18(%rsp)
  nopl   (%rax)
L13:
  mov    (%r10,%rax,8),%rcx
  movss  (%rcx,%rdi,1),%xmm0
  mulss  (%r9,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rdx)
  cmp    %r8,%rax
  jne    L13
  mov    -0x18(%rsp),%rcx
L6:
  add    $0x4,%rdx
  add    $0x4,%rdi
  cmp    %rdx,%r12
  jne    L29
  add    $0x1,%r15
  cmp    %r15,-0x10(%rsp)
  jne    L27
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mm(float **A, float **B, float **C, int ambn, int an, int bm) {
  int t6;
  int t4;
  int t2;
  int _t12;
  int _t11;
  int _t10;
  int _t9;
  int _t8;
  int _t7;
  int _t6;
  int _t5;
  int _t4;
  int _t3;
  int _t2;
  int _t1;
  int i;
  int j;
  int n;
  for (t2 = 0; t2 <= an - 1; t2 += 1)
    for (t4 = 0; t4 <= bm - 1; t4 += 1) {
      C[t2][t4] = 0.0f;
      C[t2][t4] += (A[t2][0] * B[0][t4]);
      C[t2][t4] += (A[t2][1] * B[1][t4]);
      C[t2][t4] += (A[t2][2] * B[2][t4]);
      C[t2][t4] += (A[t2][3] * B[3][t4]);
      for (t6 = 4; t6 <= ambn - 1; t6 += 1)
        C[t2][t4] += (A[t2][t6] * B[t6][t4]);
    }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_variable_from_environment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <string_init_data@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <string_init@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dict_set@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <string_destroy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <string_destroy@plt>
  nop
  leave
  ret
```

assistant: ```c
void add_variable_from_environment(struct dict *macros, const char *str) {
  const char *at = strchr(str, '=');
  struct string *name;
  struct string *value;
  assert(at != NULL);
  name = string_init_data(str, (size_t)(at - str));
  value = string_init(at + 1);
  dict_set(macros, name, value);
  string_destroy(value);
  string_destroy(name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add_variable_from_environment>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x3d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rsi
  sub    %rbp,%rsi
  mov    %rbp,%rdi
  call   <string_init_data@plt>
  mov    %rax,%rbp
  lea    0x1(%rbx),%rdi
  call   <string_init@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <dict_set@plt>
  mov    %rbx,%rdi
  call   <string_destroy@plt>
  mov    %rbp,%rdi
  call   <string_destroy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void add_variable_from_environment(struct dict *macros, const char *str) {
  const char *at = strchr(str, '=');
  struct string *name;
  struct string *value;
  assert(at != NULL);
  name = string_init_data(str, (size_t)(at - str));
  value = string_init(at + 1);
  dict_set(macros, name, value);
  string_destroy(value);
  string_destroy(name);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<add_variable_from_environment>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x3d,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strchr@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  sub    %rbp,%rsi
  call   <string_init_data@plt>
  lea    0x1(%rbx),%rdi
  mov    %rax,%rbp
  call   <string_init@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  call   <dict_set@plt>
  mov    %r12,%rdi
  call   <string_destroy@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <string_destroy@plt>
```

assistant: ```c
void add_variable_from_environment(struct dict *macros, const char *str) {
  const char *at = strchr(str, '=');
  struct string *name;
  struct string *value;
  assert(at != NULL);
  name = string_init_data(str, (size_t)(at - str));
  value = string_init(at + 1);
  dict_set(macros, name, value);
  string_destroy(value);
  string_destroy(name);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findKth>:
  endbr64
  push   %rbx
  mov    %rdi,%r10
  mov    %rdx,%rdi
  mov    %ecx,%eax
  cmp    %ecx,%esi
  jg     L59
  test   %esi,%esi
  je     L63
  cmp    $0x1,%r8d
  je     L91
  mov    %r8d,%r9d
  shr    $0x1f,%r9d
  add    %r8d,%r9d
  sar    %r9d
  cmp    %esi,%r9d
  cmovg  %esi,%r9d
  sub    %r9d,%r8d
  movslq %r9d,%rdx
  shl    $0x2,%rdx
  mov    -0x4(%r10,%rdx,1),%ecx
  movslq %r8d,%r11
  shl    $0x2,%r11
  mov    -0x4(%rdi,%r11,1),%ebx
  cmp    %ebx,%ecx
  jl     L41
  jg     L55
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  jmp    L9
L59:
  mov    %esi,%ecx
  mov    %r10,%rdx
  mov    %eax,%esi
  call   <findKth>
  jmp    L9
L63:
  movslq %r8d,%r8
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rdx,%r8,4),%xmm0
L9:
  pop    %rbx
  ret
L91:
  mov    (%rdx),%eax
  mov    (%r10),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L9
L41:
  sub    %r9d,%esi
  add    %rdx,%r10
  mov    %eax,%ecx
  mov    %rdi,%rdx
  mov    %r10,%rdi
  call   <findKth>
  jmp    L9
L55:
  sub    %r8d,%eax
  mov    %eax,%ecx
  lea    (%rdi,%r11,1),%rdx
  mov    %r9d,%r8d
  mov    %r10,%rdi
  call   <findKth>
  jmp    L9
```

assistant: ```c
double findKth(int *a, int ma, int *b, int mb, int k) {
  if (ma > mb)
    return findKth(b, mb, a, ma, k);
  if (ma == 0)
    return b[k - 1];
  if (k == 1)
    return (a[0] < b[0]) ? a[0] : b[0];
  int pa = (ma < k / 2) ? ma : k / 2;
  int pb = k - pa;
  if (a[pa - 1] < b[pb - 1])
    return findKth(a + pa, ma - pa, b, mb, k - pa);
  else if (a[pa - 1] > b[pb - 1])
    return findKth(a, ma, b + pb, mb - pb, k - pb);
  else
    return a[pa - 1];
}
```