ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_number_of_digits>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  test   %edx,%edx
  jle    L14
  mov    $0x0,%ecx
L3:
  add    $0x1,%rcx
  mov    %edx,%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  cmp    $0x9,%esi
  jg     L3
L9:
  mov    %rcx,%rax
  ret
L14:
  mov    $0x0,%ecx
  jmp    L9
```

assistant: ```c
size_t get_number_of_digits(int64_t value) {
  size_t result = 0U;
  value = (value < 0) ? (-value) : (value);
  while (value > 0) {
    result++;
    value /= 10;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_number_of_digits>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L16
  mov    $0xcccccccd,%edx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %eax,%eax
  add    $0x1,%r8
  imul   %rdx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L3
L16:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t get_number_of_digits(int64_t value) {
  size_t result = 0U;
  value = (value < 0) ? (-value) : (value);
  while (value > 0) {
    result++;
    value /= 10;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_number_of_digits>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L0
  mov    $0xcccccccd,%edx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %eax,%eax
  add    $0x1,%r8
  imul   %rdx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L11
L0:
  mov    %r8,%rax
  ret
```

assistant: ```c
size_t get_number_of_digits(int64_t value) {
  size_t result = 0U;
  value = (value < 0) ? (-value) : (value);
  while (value > 0) {
    result++;
    value /= 10;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L42
L61:
  movq   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L67
L70:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L86
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L67:
  cmpq   $0x0,-0x20(%rbp)
  je     L97
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
  jmp    L97
L86:
  nop
L97:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x18(%rbp),%rax
  jmp    L73
L7:
  addq   $0x1,-0x18(%rbp)
L42:
  cmpq   $0x0,-0x18(%rbp)
  je     L82
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L61
L82:
  mov    $0x0,%eax
L73:
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  size_t i;
  const char *t = ct;
  for (; cs && *cs; cs++) {
    for (i = 0, ct = t; ct && *ct; ct++, i++)
      if (*(cs + i) != *ct)
        break;
    if (!*ct)
      return ((char *)cs);
  }
  return (NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strstr>:
  endbr64
  jmp    L3
L29:
  add    $0x1,%rax
L18:
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L24
  cmp    %dl,(%rdi,%rax,1)
  je     L29
  add    $0x1,%rdi
L3:
  cmpb   $0x0,(%rdi)
  je     L11
  mov    $0x0,%eax
  jmp    L18
L11:
  mov    $0x0,%edi
L24:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  size_t i;
  const char *t = ct;
  for (; cs && *cs; cs++) {
    for (i = 0, ct = t; ct && *ct; ct++, i++)
      if (*(cs + i) != *ct)
        break;
    if (!*ct)
      return ((char *)cs);
  }
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r8
  je     L52
  movzbl (%rsi),%edi
  nop
L26:
  test   %dil,%dil
  je     L6
  mov    %r8,%rcx
  mov    %rsi,%rax
  mov    %edi,%edx
  jmp    L50
  nop
L19:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  test   %dl,%dl
  je     L6
L50:
  cmp    %dl,(%rcx)
  je     L19
  cmpb   $0x0,(%rax)
  je     L6
  add    $0x1,%r8
  cmpb   $0x0,(%r8)
  jne    L26
L52:
  xor    %r8d,%r8d
L6:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  size_t i;
  const char *t = ct;
  for (; cs && *cs; cs++) {
    for (i = 0, ct = t; ct && *ct; ct++, i++)
      if (*(cs + i) != *ct)
        break;
    if (!*ct)
      return ((char *)cs);
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r8
  je     L60
  movzbl (%rsi),%edi
  nop
L30:
  test   %dil,%dil
  je     L44
  mov    %r8,%rcx
  mov    %rsi,%rax
  mov    %edi,%edx
  jmp    L57
  nop
L38:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  test   %dl,%dl
  je     L44
L57:
  cmp    %dl,(%rcx)
  je     L38
  cmpb   $0x0,(%rax)
  je     L44
  add    $0x1,%r8
  cmpb   $0x0,(%r8)
  jne    L30
L60:
  xor    %r8d,%r8d
L44:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strstr(const char *cs, const char *ct) {
  size_t i;
  const char *t = ct;
  for (; cs && *cs; cs++) {
    for (i = 0, ct = t; ct && *ct; ct++, i++)
      if (*(cs + i) != *ct)
        break;
    if (!*ct)
      return ((char *)cs);
  }
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dsLock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getReadLock@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getWriteLock@plt>
  mov    %eax,-0x4(%rbp)
  movzbl -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L5
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L12
L5:
  movzbl -0x1c(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L13
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L12
L13:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int dsLock(void *mem, unsigned char operations) {
  int rsemid, wsemid;
  rsemid = getReadLock(mem);
  wsemid = getWriteLock(mem);
  if (operations & (1 << 0)) {
    if (semaphoreReserve(rsemid) == -1)
      return -1;
  }
  if (operations & (1 << 1)) {
    if (semaphoreReserve(wsemid) == -1)
      return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dsLock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <getReadLock@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <getWriteLock@plt>
  mov    %eax,%ebx
  test   $0x1,%bpl
  jne    L16
L45:
  mov    $0x0,%eax
  test   $0x2,%bpl
  jne    L30
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %r12d,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  jne    L45
  jmp    L0
L30:
  mov    %ebx,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
  jmp    L0
```

assistant: ```c
int dsLock(void *mem, unsigned char operations) {
  int rsemid, wsemid;
  rsemid = getReadLock(mem);
  wsemid = getWriteLock(mem);
  if (operations & (1 << 0)) {
    if (semaphoreReserve(rsemid) == -1)
      return -1;
  }
  if (operations & (1 << 1)) {
    if (semaphoreReserve(wsemid) == -1)
      return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dsLock>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <getReadLock@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <getWriteLock@plt>
  mov    %eax,%ebp
  test   $0x1,%bl
  jne    L33
  and    $0x2,%ebx
  jne    L17
L14:
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    %r12d,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  je     L11
  and    $0x2,%ebx
  je     L14
L17:
  mov    %ebp,%edi
  call   <semaphoreReserve@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0xffffffff,%eax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int dsLock(void *mem, unsigned char operations) {
  int rsemid, wsemid;
  rsemid = getReadLock(mem);
  wsemid = getWriteLock(mem);
  if (operations & (1 << 0)) {
    if (semaphoreReserve(rsemid) == -1)
      return -1;
  }
  if (operations & (1 << 1)) {
    if (semaphoreReserve(wsemid) == -1)
      return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dsLock>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  call   <getReadLock@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <getWriteLock@plt>
  mov    %eax,%ebp
  test   $0x1,%bl
  jne    L20
  and    $0x2,%ebx
  jne    L32
L19:
  xor    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    %r12d,%edi
  call   <semaphoreReserve@plt>
  cmp    $0xffffffff,%eax
  je     L37
  and    $0x2,%ebx
  je     L19
L32:
  mov    %ebp,%edi
  call   <semaphoreReserve@plt>
  pop    %rbx
  pop    %rbp
  cmp    $0xffffffff,%eax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int dsLock(void *mem, unsigned char operations) {
  int rsemid, wsemid;
  rsemid = getReadLock(mem);
  wsemid = getWriteLock(mem);
  if (operations & (1 << 0)) {
    if (semaphoreReserve(rsemid) == -1)
      return -1;
  }
  if (operations & (1 << 1)) {
    if (semaphoreReserve(wsemid) == -1)
      return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D60(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L53
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D21(%rip),%r12
L19:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L19
L53:
  lea    D41(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%ebx
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  test   %ebx,%ebx
  js     L51
  mov    0xc(%rsp),%esi
  mov    $0x0,%ebp
  jmp    L89
L107:
  je     L11
  lea    -0x1(%rdx),%ebx
L17:
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebx,%ebp
  jg     L51
L89:
  movslq %edx,%rax
  mov    0x10(%rsp,%rax,4),%eax
  cmp    %esi,%eax
  jge    L107
  lea    0x1(%rdx),%ebp
  jmp    L17
L11:
  add    $0x1,%edx
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jg     L51
L48:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  mov    0xc(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L48
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D60
datatype: string
name: retrieve_data
arguments: tag: D41
datatype: string
name: retrieve_data
arguments: tag: D47
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string

tool: D24: Enter number of elements

tool: D21: %d

tool: D60: Enter %d integers


tool: D41: Enter value to find

tool: D47: %d found at location %d.


tool: D1: Not found! %d is not present in the list.


assistant: ```c
main() {
  int c, first, last, middle, n, search, array[100];
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter value to find\n");
  scanf("%d", &search);
  first = 0;
  last = n - 1;
  middle = (first + last) / 2;
  while (first <= last) {
    if (array[middle] < search)
      first = middle + 1;
    else if (array[middle] == search) {
      printf("%d found at location %d.\n", search, middle + 1);
      break;
    } else
      last = middle - 1;
    middle = (first + last) / 2;
  }
  if (first > last)
    printf("Not found! %d is not present in the list.\n", search);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D32(%rip),%rdi
  lea    D56(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L70
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L16
L70:
  lea    D17(%rip),%rdi
  xor    %ebp,%ebp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  lea    -0x1(%rax),%ebx
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  test   %ebx,%ebx
  jns    L97
  jmp    L9
  nopl   (%rax)
L14:
  lea    0x1(%rdx),%ebp
L24:
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebx,%ebp
  jg     L9
L97:
  movslq %edx,%rax
  cmp    %esi,0x10(%rsp,%rax,4)
  jl     L14
  je     L74
  lea    -0x1(%rdx),%ebx
  jmp    L24
  nopl   0x0(%rax)
L74:
  add    $0x1,%edx
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jge    L38
  mov    0xc(%rsp),%esi
  nopl   0x0(%rax)
L9:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L38:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D32
type_infered: string
name: disassemble_data
arguments: label: D56
type_infered: string
name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D58
type_infered: string
name: disassemble_data
arguments: label: D23
type_infered: string

tool: D32: Enter number of elements

tool: D56: %d

tool: D34: Enter %d integers


tool: D17: Enter value to find

tool: D58: %d found at location %d.


tool: D23: Not found! %d is not present in the list.


assistant: ```c
main() {
  int c, first, last, middle, n, search, array[100];
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter value to find\n");
  scanf("%d", &search);
  first = 0;
  last = n - 1;
  middle = (first + last) / 2;
  while (first <= last) {
    if (array[middle] < search)
      first = middle + 1;
    else if (array[middle] == search) {
      printf("%d found at location %d.\n", search, middle + 1);
      break;
    } else
      last = middle - 1;
    middle = (first + last) / 2;
  }
  if (first > last)
    printf("Not found! %d is not present in the list.\n", search);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  lea    D33(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  lea    D55(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L18
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L40
L18:
  lea    D45(%rip),%rdi
  xor    %ebp,%ebp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%esi
  lea    -0x1(%rax),%ebx
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  test   %ebx,%ebx
  jns    L5
  jmp    L15
  nopl   (%rax)
L54:
  lea    0x1(%rdx),%ebp
L84:
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebx,%ebp
  jg     L15
L5:
  movslq %edx,%rax
  cmp    %esi,0x10(%rsp,%rax,4)
  jl     L54
  je     L26
  lea    -0x1(%rdx),%ebx
  jmp    L84
  nopl   0x0(%rax)
L26:
  add    $0x1,%edx
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jge    L86
  mov    0xc(%rsp),%esi
  nopl   0x0(%rax)
L15:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L86:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D33
datatype: string
name: disassemble_data
arguments: data_label: D55
datatype: string
name: disassemble_data
arguments: data_label: D45
datatype: string
name: disassemble_data
arguments: data_label: D30
datatype: string
name: disassemble_data
arguments: data_label: D12
datatype: string

tool: D15: Enter number of elements

tool: D33: %d

tool: D55: Enter %d integers


tool: D45: Enter value to find

tool: D30: %d found at location %d.


tool: D12: Not found! %d is not present in the list.


assistant: ```c
main() {
  int c, first, last, middle, n, search, array[100];
  printf("Enter number of elements\n");
  scanf("%d", &n);
  printf("Enter %d integers\n", n);
  for (c = 0; c < n; c++)
    scanf("%d", &array[c]);
  printf("Enter value to find\n");
  scanf("%d", &search);
  first = 0;
  last = n - 1;
  middle = (first + last) / 2;
  while (first <= last) {
    if (array[middle] < search)
      first = middle + 1;
    else if (array[middle] == search) {
      printf("%d found at location %d.\n", search, middle + 1);
      break;
    } else
      last = middle - 1;
    middle = (first + last) / 2;
  }
  if (first > last)
    printf("Not found! %d is not present in the list.\n", search);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L4:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x288df0cb,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hash(char *str) {
  int i, ans = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++) {
    ans += str[i] * (i + 1);
  }
  ans = ans % 101;
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L6
  lea    0x1(%rax),%esi
  mov    $0x1,%eax
  mov    $0x0,%ecx
L20:
  movsbl -0x1(%rbx,%rax,1),%edx
  imul   %eax,%edx
  add    %edx,%ecx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L20
L26:
  movslq %ecx,%rax
  imul   $0x288df0cb,%rax,%rax
  sar    $0x24,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  pop    %rbx
  ret
L6:
  mov    $0x0,%ecx
  jmp    L26
```

assistant: ```c
int hash(char *str) {
  int i, ans = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++) {
    ans += str[i] * (i + 1);
  }
  ans = ans % 101;
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  lea    0x1(%rax),%esi
  xor    %ecx,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl -0x1(%rbx,%rax,1),%edx
  imul   %eax,%edx
  add    $0x1,%rax
  add    %edx,%ecx
  cmp    %rax,%rsi
  jne    L2
  movslq %ecx,%rax
  mov    %ecx,%edx
  pop    %rbx
  imul   $0x288df0cb,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x24,%rax
  sub    %edx,%eax
  imul   $0x65,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int hash(char *str) {
  int i, ans = 0;
  int length = strlen(str);
  for (i = 0; i < length; i++) {
    ans += str[i] * (i + 1);
  }
  ans = ans % 101;
  return ans;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<solcon_replace_standard_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x23,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int solcon_replace_standard_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(35, &k, b, sol);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_replace_standard_solution>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x23,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_replace_standard_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(35, &k, b, sol);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<solcon_replace_standard_solution>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x10(%rsp)
  mov    $0x23,%edi
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_replace_standard_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(35, &k, b, sol);
  return fail;
}
```