ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<menu_load_flags>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <read_entire_file@plt>
  mov    0x4(%rsp),%ecx
  test   %rax,%rax
  je     L28
  test   %ecx,%ecx
  je     L28
  mov    %rax,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0xffffffffffffffff,%rdi
  jg     L111
  jmp    L90
  nopl   0x0(%rax)
L19:
  cmp    $0xa,%al
  je     L101
L17:
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jle    L90
L111:
  lea    0x0(%rbp,%rbx,1),%rdx
  mov    %ebx,%esi
  movzbl (%rdx),%eax
  cmp    $0x5c,%al
  jne    L19
  mov    %ebx,%r12d
  add    $0x1,%rbx
  cmp    %ebx,%ecx
  jg     L111
L90:
  mov    %rbp,%rdi
  call   <__mem_free@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L115
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L101:
  lea    -0x2(%r12),%eax
  cmp    %edi,%eax
  jle    L100
  sub    $0x2,%esi
  cmp    %r12d,%esi
  jg     L68
L100:
  movslq %ebx,%rdi
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L68:
  movslq %r12d,%rax
  movb   $0x0,(%rdx)
  movb   $0x0,0x0(%rbp,%rax,1)
  movsbl 0x1(%rbp,%rdi,1),%edx
  lea    0x1(%rbp,%rax,1),%rsi
  lea    0x3(%rbp,%rdi,1),%rdi
  sub    $0x30,%edx
  call   <menu_set_flags@plt>
  mov    0x4(%rsp),%ecx
  movslq %ebx,%rdi
  jmp    L17
L115:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void menu_load_flags(char *filename) {
  int size = 0;
  char *buf = (char *)read_entire_file(filename, &size);
  if (!size)
    return;
  if (!buf)
    return;
  int prev = -1;
  int sep = 0;
  for (int i = 0; i < size; i++) {
    if (buf[i] == '\\')
      sep = i;
    else if (buf[i] == '\n') {
      if (prev < sep - 2 && sep < i - 2) {
        buf[i] = 0;
        buf[sep] = 0;
        char *menu_name = &buf[prev + 3];
        char *entry_name = &buf[sep + 1];
        int flags = buf[prev + 1] - '0';
        menu_set_flags(menu_name, entry_name, flags);
      }
      prev = i;
    }
  }
  __mem_free(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <reverse_array@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L21
L25:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L21:
  cmpl   $0x4,-0x24(%rbp)
  jle    L25
  mov    $0x876543ff,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D15: %d


tool: D8: %x


assistant: ```c
int main(void) {
  int nums[5] = {1, 2, 3, 4, 5};
  reverse_array(nums, 5);
  int i = 0;
  for (; i < 5; ++i) {
    printf("%d\n", nums[i]);
  }
  printf("%x\n", 0x87654321 | 0xFF);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <reverse_array@plt>
  lea    0x14(%rsp),%r12
  lea    D1(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    $0x876543ff,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string

tool: D1: %d


tool: D15: %x


assistant: ```c
int main(void) {
  int nums[5] = {1, 2, 3, 4, 5};
  reverse_array(nums, 5);
  int i = 0;
  for (; i < 5; ++i) {
    printf("%d\n", nums[i]);
  }
  printf("%x\n", 0x87654321 | 0xFF);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  movl   $0x5,0x10(%rsp)
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  call   <reverse_array@plt>
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  mov    $0x876543ff,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string

tool: D19: %d


tool: D13: %x


assistant: ```c
int main(void) {
  int nums[5] = {1, 2, 3, 4, 5};
  reverse_array(nums, 5);
  int i = 0;
  for (; i < 5; ++i) {
    printf("%d\n", nums[i]);
  }
  printf("%x\n", 0x87654321 | 0xFF);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%esi
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  movl   $0x5,0x10(%rsp)
  mov    %rbx,%rdi
  movaps %xmm0,(%rsp)
  call   <reverse_array@plt>
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0x876543ff,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: byte[16]
name: disassemble_data
arguments: label: D16
type_guessed: string

tool: D12: %d


tool: {"D8": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D16: %x


assistant: ```c
int main(void) {
  int nums[5] = {1, 2, 3, 4, 5};
  reverse_array(nums, 5);
  int i = 0;
  for (; i < 5; ++i) {
    printf("%d\n", nums[i]);
  }
  printf("%x\n", 0x87654321 | 0xFF);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_mem_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L46
  mov    $0x0,%eax
  jmp    L48
L46:
  cmpq   $0x0,-0x18(%rbp)
  je     L88
  cmpq   $0x0,-0x20(%rbp)
  jne    L39
L88:
  mov    $0x2,%eax
  jmp    L48
L39:
  movq   $0x0,-0x8(%rbp)
  jmp    L89
L34:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L11
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L48
L11:
  addq   $0x1,-0x8(%rbp)
L89:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L34
  mov    $0x0,%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
int find_mem_diff(const char *a, const char *b, size_t n, size_t *offset) {
  size_t i;
  if (a == b)
    return 0;
  if (!a || !b)
    return 2;
  for (i = 0; i < n; i++)
    if (a[i] != b[i]) {
      *offset = i;
      return 1;
    }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_mem_diff>:
  endbr64
  cmp    %rsi,%rdi
  je     L42
  test   %rdi,%rdi
  je     L13
  test   %rsi,%rsi
  je     L13
  test   %rdx,%rdx
  je     L25
  mov    $0x0,%eax
L12:
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  jne    L29
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
  mov    $0x0,%eax
  ret
L29:
  mov    %rax,(%rcx)
  mov    $0x1,%eax
  ret
L42:
  mov    $0x0,%eax
  ret
L13:
  mov    $0x2,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int find_mem_diff(const char *a, const char *b, size_t n, size_t *offset) {
  size_t i;
  if (a == b)
    return 0;
  if (!a || !b)
    return 2;
  for (i = 0; i < n; i++)
    if (a[i] != b[i]) {
      *offset = i;
      return 1;
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_mem_diff>:
  endbr64
  cmp    %rsi,%rdi
  je     L36
  test   %rdi,%rdi
  je     L42
  test   %rsi,%rsi
  je     L42
  test   %rdx,%rdx
  je     L36
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax)
L30:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L36
L29:
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  je     L30
  mov    %rax,(%rcx)
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L36:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int find_mem_diff(const char *a, const char *b, size_t n, size_t *offset) {
  size_t i;
  if (a == b)
    return 0;
  if (!a || !b)
    return 2;
  for (i = 0; i < n; i++)
    if (a[i] != b[i]) {
      *offset = i;
      return 1;
    }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_mem_diff>:
  endbr64
  cmp    %rsi,%rdi
  je     L29
  test   %rdi,%rdi
  je     L56
  test   %rsi,%rsi
  je     L56
  test   %rdx,%rdx
  je     L29
  xor    %eax,%eax
  jmp    L68
  nopl   0x0(%rax)
L3:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L29
L68:
  movzbl (%rsi,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  je     L3
  mov    %rax,(%rcx)
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L29:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int find_mem_diff(const char *a, const char *b, size_t n, size_t *offset) {
  size_t i;
  if (a == b)
    return 0;
  if (!a || !b)
    return 2;
  for (i = 0; i < n; i++)
    if (a[i] != b[i]) {
      *offset = i;
      return 1;
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_add_num_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <test_add_num_num@plt>
  test   %rax,%rax
  je     L3
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L18
L3:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D25
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string

tool: D17: Add:


tool: D35: Success


tool: D25: Failed


tool: D22: 


assistant: ```c
void check_add_num_num(unsigned int number_of_tests, unsigned int seed) {
  printf("Add:\n");
  if (test_add_num_num(number_of_tests, seed)) {
    printf("Success\n");
  } else {
    printf("Failed\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_add_num_num>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <test_add_num_num@plt>
  test   %rax,%rax
  je     L19
  lea    D23(%rip),%rdi
  call   <printf@plt>
L10:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string
name: read_data
arguments: data_tag: D18
type_guessed: string

tool: D0: Add:


tool: D23: Success


tool: D3: 


tool: D18: Failed


assistant: ```c
void check_add_num_num(unsigned int number_of_tests, unsigned int seed) {
  printf("Add:\n");
  if (test_add_num_num(number_of_tests, seed)) {
    printf("Success\n");
  } else {
    printf("Failed\n");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_add_num_num>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D28(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <test_add_num_num@plt>
  test   %rax,%rax
  je     L4
  lea    D12(%rip),%rdi
  call   <printf@plt>
L2:
  add    $0x8,%rsp
  lea    D35(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D35
data_type: string
name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D28: Add:


tool: D12: Success


tool: D35: 


tool: D8: Failed


assistant: ```c
void check_add_num_num(unsigned int number_of_tests, unsigned int seed) {
  printf("Add:\n");
  if (test_add_num_num(number_of_tests, seed)) {
    printf("Success\n");
  } else {
    printf("Failed\n");
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_add_num_num>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <test_add_num_num@plt>
  test   %rax,%rax
  je     L9
  lea    D37(%rip),%rdi
  call   <printf@plt>
L10:
  add    $0x8,%rsp
  lea    D30(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string

tool: D9: Add:


tool: D37: Success


tool: D30: 


tool: D13: Failed


assistant: ```c
void check_add_num_num(unsigned int number_of_tests, unsigned int seed) {
  printf("Add:\n");
  if (test_add_num_num(number_of_tests, seed)) {
    printf("Success\n");
  } else {
    printf("Failed\n");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_tcp_uncork>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void set_tcp_uncork(int fd) {
  int state = 0;
  setsockopt(fd, IPPROTO_TCP, TCP_CORK, &state, sizeof(state));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_tcp_uncork>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    $0x4,%r8d
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_tcp_uncork(int fd) {
  int state = 0;
  setsockopt(fd, IPPROTO_TCP, TCP_CORK, &state, sizeof(state));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_tcp_uncork>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_tcp_uncork(int fd) {
  int state = 0;
  setsockopt(fd, IPPROTO_TCP, TCP_CORK, &state, sizeof(state));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_tcp_uncork>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void set_tcp_uncork(int fd) {
  int state = 0;
  setsockopt(fd, IPPROTO_TCP, TCP_CORK, &state, sizeof(state));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L2:
  cmpb   $0x2e,-0x5(%rbp)
  jne    L43
  addl   $0x1,-0x4(%rbp)
  mov    $0x21,%edi
  call   <putchar@plt>
  jmp    L37
L43:
  cmpb   $0x21,-0x5(%rbp)
  jne    L31
  addl   $0x1,-0x4(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L37
L31:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L37:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  cmpb   $0x23,-0x5(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D18: !!

tool: D8: 
%d replaces.


assistant: ```c
int main(void) {
  char ch;
  int i = 0;
  while ((ch = getchar()) != '#') {
    if (ch == '.') {
      i++;
      putchar('!');
    } else if (ch == '!') {
      i++;
      printf("!!");
    } else
      putchar(ch);
  }
  printf("\n%d replaces.\n", i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D3(%rip),%rbp
  jmp    L58
L52:
  add    $0x1,%ebx
  mov    $0x21,%edi
  call   <putchar@plt>
  jmp    L58
L8:
  add    $0x1,%ebx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L58:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L0
  cmp    $0x2e,%al
  je     L52
  cmp    $0x21,%al
  je     L8
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L58
L0:
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string

tool: D3: !!

tool: D16: 
%d replaces.


assistant: ```c
int main(void) {
  char ch;
  int i = 0;
  while ((ch = getchar()) != '#') {
    if (ch == '.') {
      i++;
      putchar('!');
    } else if (ch == '!') {
      i++;
      printf("!!");
    } else
      putchar(ch);
  }
  printf("\n%d replaces.\n", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x8,%rsp
L9:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L13
L28:
  cmp    $0x2e,%al
  je     L40
  cmp    $0x21,%al
  je     L14
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  jne    L28
L13:
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L40:
  mov    $0x21,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D19: !!

tool: D11: 
%d replaces.


assistant: ```c
int main(void) {
  char ch;
  int i = 0;
  while ((ch = getchar()) != '#') {
    if (ch == '.') {
      i++;
      putchar('!');
    } else if (ch == '!') {
      i++;
      printf("!!");
    } else
      putchar(ch);
  }
  printf("\n%d replaces.\n", i);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D0(%rip),%rbx
  sub    $0x8,%rsp
L53:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  je     L12
L32:
  cmp    $0x2e,%al
  je     L27
  cmp    $0x21,%al
  je     L8
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x23,%al
  jne    L32
L12:
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x21,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  jmp    L53
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D14
datatype: string

tool: D0: !!

tool: D14: 
%d replaces.


assistant: ```c
int main(void) {
  char ch;
  int i = 0;
  while ((ch = getchar()) != '#') {
    if (ch == '.') {
      i++;
      putchar('!');
    } else if (ch == '!') {
      i++;
      printf("!!");
    } else
      putchar(ch);
  }
  printf("\n%d replaces.\n", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_ucmath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  lea    0x5(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edx
  lea    D27(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string
name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D27: do_ucmath

tool: D26: %s: X before: %u


tool: D6: %s: X after: %u


assistant: ```c
void do_ucmath(unsigned char *x) {
  printf("%s: X before: %u\n", __func__, *x);
  *x += 5;
  printf("%s: X after: %u\n", __func__, *x);
}
```