ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<year_mjd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L6
  movl   $0xfffffffe,-0x1c(%rbp)
L6:
  lea    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    D15(%rip),%rax
  mov    %ecx,%esi
  movq   %rax,%xmm0
  mov    $0x1,%edi
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  lea    -0x10(%rbp),%rdx
  mov    D15(%rip),%rax
  mov    %ecx,%esi
  movq   %rax,%xmm0
  mov    $0x1,%edi
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x1c(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: f64

tool: D15: 1

assistant: ```c
void year_mjd(y, mjd) double y;
double *mjd;
{
  double e0, e1;
  int yf = floor(y);
  if (yf == -1)
    yf = -2;
  cal_mjd(1, 1.0, yf, &e0);
  cal_mjd(1, 1.0, yf + 1, &e1);
  *mjd = e0 + (y - yf) * (e1 - e0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<year_mjd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movapd %xmm0,%xmm2
  movsd  D12(%rip),%xmm1
  movapd %xmm0,%xmm4
  andpd  %xmm1,%xmm0
  movsd  D2(%rip),%xmm3
  ucomisd %xmm0,%xmm3
  jbe    L6
  cvttsd2si %xmm2,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm2
  cmpnlesd %xmm4,%xmm2
  movsd  D19(%rip),%xmm3
  andpd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  andnpd %xmm4,%xmm1
  movapd %xmm0,%xmm2
  orpd   %xmm1,%xmm2
L6:
  cvttsd2si %xmm2,%ebx
  cmp    $0xffffffff,%ebx
  mov    $0xfffffffe,%eax
  cmove  %eax,%ebx
  lea    0x18(%rsp),%rdx
  mov    %ebx,%esi
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x1,%edi
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  lea    0x20(%rsp),%rdx
  lea    0x1(%rbx),%esi
  mov    D19(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x1,%edi
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  movsd  0x18(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  0x20(%rsp),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: byte[8]
name: parse_data
arguments: tag: D2
data_type: byte[8]
name: parse_data
arguments: tag: D19
data_type: f64

tool: {"D12": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: D19: 1

assistant: ```c
void year_mjd(y, mjd) double y;
double *mjd;
{
  double e0, e1;
  int yf = floor(y);
  if (yf == -1)
    yf = -2;
  cal_mjd(1, 1.0, yf, &e0);
  cal_mjd(1, 1.0, yf + 1, &e1);
  *mjd = e0 + (y - yf) * (e1 - e0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<year_mjd>:
  endbr64
  push   %r12
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm4
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movsd  D8(%rip),%xmm3
  movsd  D5(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  andpd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm2
  movsd  D18(%rip),%xmm2
  jbe    L8
  cvttsd2si %xmm1,%rax
  pxor   %xmm0,%xmm0
  andnpd %xmm1,%xmm3
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm4
  cmpnlesd %xmm1,%xmm4
  andpd  %xmm2,%xmm4
  subsd  %xmm4,%xmm0
  movapd %xmm0,%xmm4
  orpd   %xmm3,%xmm4
L8:
  cvttsd2si %xmm4,%ebp
  mov    $0xfffffffe,%r12d
  cmp    $0xffffffff,%ebp
  je     L21
  mov    %ebp,%r12d
  add    $0x1,%ebp
L21:
  movapd %xmm2,%xmm0
  lea    0x18(%rsp),%rdx
  mov    %r12d,%esi
  mov    $0x1,%edi
  mov    $0x1,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <cal_mjd@plt>
  mov    D18(%rip),%rax
  lea    0x20(%rsp),%rdx
  mov    %ebp,%esi
  mov    $0x1,%edi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  cvtsi2sd %r12d,%xmm0
  subsd  %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D5
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D18
type_infered: f64

tool: {"D8": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: D18: 1

assistant: ```c
void year_mjd(y, mjd) double y;
double *mjd;
{
  double e0, e1;
  int yf = floor(y);
  if (yf == -1)
    yf = -2;
  cal_mjd(1, 1.0, yf, &e0);
  cal_mjd(1, 1.0, yf + 1, &e1);
  *mjd = e0 + (y - yf) * (e1 - e0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<year_mjd>:
  endbr64
  push   %r12
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm4
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  movsd  D5(%rip),%xmm3
  movsd  D4(%rip),%xmm2
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  andpd  %xmm3,%xmm0
  ucomisd %xmm0,%xmm2
  movsd  D10(%rip),%xmm2
  jbe    L16
  cvttsd2si %xmm1,%rax
  pxor   %xmm0,%xmm0
  andnpd %xmm1,%xmm3
  cvtsi2sd %rax,%xmm0
  movapd %xmm0,%xmm4
  cmpnlesd %xmm1,%xmm4
  andpd  %xmm2,%xmm4
  subsd  %xmm4,%xmm0
  movapd %xmm0,%xmm4
  orpd   %xmm3,%xmm4
L16:
  cvttsd2si %xmm4,%ebp
  mov    $0xfffffffe,%r12d
  cmp    $0xffffffff,%ebp
  je     L23
  mov    %ebp,%r12d
  add    $0x1,%ebp
L23:
  movapd %xmm2,%xmm0
  lea    0x18(%rsp),%rdx
  mov    %r12d,%esi
  mov    $0x1,%edi
  mov    $0x1,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <cal_mjd@plt>
  mov    D10(%rip),%rax
  lea    0x20(%rsp),%rdx
  mov    %ebp,%esi
  mov    $0x1,%edi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cal_mjd@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  cvtsi2sd %r12d,%xmm0
  subsd  %xmm0,%xmm1
  movsd  0x20(%rsp),%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: byte[8]
name: retrieve_data
arguments: tag: D4
type_infered: byte[8]
name: retrieve_data
arguments: tag: D10
type_infered: f64

tool: {"D5": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: D10: 1

assistant: ```c
void year_mjd(y, mjd) double y;
double *mjd;
{
  double e0, e1;
  int yf = floor(y);
  if (yf == -1)
    yf = -2;
  cal_mjd(1, 1.0, yf, &e0);
  cal_mjd(1, 1.0, yf + 1, &e1);
  *mjd = e0 + (y - yf) * (e1 - e0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kernel_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <sys_build_gdt@plt>
  mov    $0x0,%eax
  call   <sys_build_idt@plt>
  mov    $0x0,%eax
  call   <console_init@plt>
  mov    $0x0,%eax
  call   <sys_copy_multiboot@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kernel_init(void) {
  sys_build_gdt();
  sys_build_idt();
  console_init();
  sys_copy_multiboot();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kernel_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sys_build_gdt@plt>
  mov    $0x0,%eax
  call   <sys_build_idt@plt>
  mov    $0x0,%eax
  call   <console_init@plt>
  mov    $0x0,%eax
  call   <sys_copy_multiboot@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void kernel_init(void) {
  sys_build_gdt();
  sys_build_idt();
  console_init();
  sys_copy_multiboot();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kernel_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sys_build_gdt@plt>
  xor    %eax,%eax
  call   <sys_build_idt@plt>
  xor    %eax,%eax
  call   <console_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <sys_copy_multiboot@plt>
```

assistant: ```c
void kernel_init(void) {
  sys_build_gdt();
  sys_build_idt();
  console_init();
  sys_copy_multiboot();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <sys_build_gdt@plt>
  xor    %eax,%eax
  call   <sys_build_idt@plt>
  xor    %eax,%eax
  call   <console_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <sys_copy_multiboot@plt>
```

assistant: ```c
void kernel_init(void) {
  sys_build_gdt();
  sys_build_idt();
  console_init();
  sys_copy_multiboot();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <abort@plt>
L7:
  jmp    L7
```

assistant: ```c
void die(long e) {
  abort();
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  jmp    L6
```

assistant: ```c
void die(long e) {
  abort();
  for (;;)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
L4:
  jmp    L4
```

assistant: ```c
void die(long e) {
  abort();
  for (;;)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
L5:
  jmp    L5
```

assistant: ```c
void die(long e) {
  abort();
  for (;;)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_MIDI_ReadNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x4,-0x20(%rbp)
  jbe    L26
  movq   $0x4,-0x20(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L9:
  shlq   $0x8,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rax,-0x8(%rbp)
L19:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long _MIDI_ReadNumber(void *from, size_t size) {
  unsigned char *FromPtr;
  long value;
  if (size > 4) {
    size = 4;
  }
  FromPtr = (unsigned char *)from;
  value = 0;
  while (size--) {
    value <<= 8;
    value += *FromPtr++;
  }
  return (value);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_MIDI_ReadNumber>:
  endbr64
  mov    $0x4,%ecx
  cmp    %rcx,%rsi
  cmovbe %rsi,%rcx
  test   %rsi,%rsi
  je     L6
  add    %rdi,%rcx
  mov    $0x0,%eax
L8:
  shl    $0x8,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  add    %rdx,%rax
  cmp    %rdi,%rcx
  jne    L8
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
long _MIDI_ReadNumber(void *from, size_t size) {
  unsigned char *FromPtr;
  long value;
  if (size > 4) {
    size = 4;
  }
  FromPtr = (unsigned char *)from;
  value = 0;
  while (size--) {
    value <<= 8;
    value += *FromPtr++;
  }
  return (value);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_MIDI_ReadNumber>:
  endbr64
  mov    $0x4,%ecx
  cmp    %rcx,%rsi
  cmovbe %rsi,%rcx
  test   %rsi,%rsi
  je     L14
  add    %rdi,%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%rdi),%edx
  shl    $0x8,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  cmp    %rdi,%rcx
  jne    L11
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
long _MIDI_ReadNumber(void *from, size_t size) {
  unsigned char *FromPtr;
  long value;
  if (size > 4) {
    size = 4;
  }
  FromPtr = (unsigned char *)from;
  value = 0;
  while (size--) {
    value <<= 8;
    value += *FromPtr++;
  }
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_MIDI_ReadNumber>:
  endbr64
  mov    $0x4,%ecx
  cmp    %rcx,%rsi
  cmovbe %rsi,%rcx
  test   %rsi,%rsi
  je     L16
  add    %rdi,%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl (%rdi),%edx
  shl    $0x8,%rax
  add    $0x1,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L10
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
long _MIDI_ReadNumber(void *from, size_t size) {
  unsigned char *FromPtr;
  long value;
  if (size > 4) {
    size = 4;
  }
  FromPtr = (unsigned char *)from;
  value = 0;
  while (size--) {
    value <<= 8;
    value += *FromPtr++;
  }
  return (value);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<do_cmd_macro_aux_keymap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <flush@plt>
  mov    $0x0,%eax
  call   <inkey@plt>
  mov    -0x418(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x418(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ascii_to_text@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <Term_addstr@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void do_cmd_macro_aux_keymap(char *buf) {
  char tmp[1024];
  flush();
  buf[0] = inkey();
  buf[1] = '\0';
  ascii_to_text(tmp, buf);
  Term_addstr(-1, 1, tmp);
  flush();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_cmd_macro_aux_keymap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <flush@plt>
  mov    $0x0,%eax
  call   <inkey@plt>
  mov    %al,(%rbx)
  movb   $0x0,0x1(%rbx)
  mov    %rsp,%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <ascii_to_text@plt>
  mov    %rbp,%rdx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <Term_addstr@plt>
  mov    $0x0,%eax
  call   <flush@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_cmd_macro_aux_keymap(char *buf) {
  char tmp[1024];
  flush();
  buf[0] = inkey();
  buf[1] = '\0';
  ascii_to_text(tmp, buf);
  Term_addstr(-1, 1, tmp);
  flush();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_cmd_macro_aux_keymap>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <flush@plt>
  xor    %eax,%eax
  call   <inkey@plt>
  movb   $0x0,0x1(%rbp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %al,0x0(%rbp)
  call   <ascii_to_text@plt>
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <Term_addstr@plt>
  xor    %eax,%eax
  call   <flush@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x418,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_cmd_macro_aux_keymap(char *buf) {
  char tmp[1024];
  flush();
  buf[0] = inkey();
  buf[1] = '\0';
  ascii_to_text(tmp, buf);
  Term_addstr(-1, 1, tmp);
  flush();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_cmd_macro_aux_keymap>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <flush@plt>
  xor    %eax,%eax
  call   <inkey@plt>
  movb   $0x0,0x1(%rbp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %al,0x0(%rbp)
  call   <ascii_to_text@plt>
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    $0xffffffff,%edi
  call   <Term_addstr@plt>
  xor    %eax,%eax
  call   <flush@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x418,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void do_cmd_macro_aux_keymap(char *buf) {
  char tmp[1024];
  flush();
  buf[0] = inkey();
  buf[1] = '\0';
  ascii_to_text(tmp, buf);
  Term_addstr(-1, 1, tmp);
  flush();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D5(%rip),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  shl    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
double foo() {
  double ok2 = 4 * atan(1.0);
  return ok2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  call   <atan@plt>
  shl    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: f64

tool: D3: 1

assistant: ```c
double foo() {
  double ok2 = 4 * atan(1.0);
  return ok2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  movsd  D2(%rip),%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  shl    $0x2,%eax
  cvtsi2sd %eax,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: f64

tool: D2: 1

assistant: ```c
double foo() {
  double ok2 = 4 * atan(1.0);
  return ok2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  movsd  D6(%rip),%xmm0
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  shl    $0x2,%eax
  cvtsi2sd %eax,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: f64

tool: D6: 1

assistant: ```c
double foo() {
  double ok2 = 4 * atan(1.0);
  return ok2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HSMMCSDIsCmdComplete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  add    $0x230,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x1,%eax
  je     L27
  cmpl   $0x0,-0x18(%rbp)
  je     L27
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L2
L27:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int HSMMCSDIsCmdComplete(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x230)))) & (0x00000001u)) >> (0x00000000u);
    if ((1 == status) || (0 == retry)) {
      break;
    }
  } while (retry--);
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<HSMMCSDIsCmdComplete>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  lea    0x230(%rdi),%edx
  mov    0x230(%edi),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  test   %esi,%esi
  je     L23
  cmp    $0x1,%eax
  je     L23
L38:
  mov    (%rdx),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    $0x1,%esi
  je     L23
  cmp    $0x1,%eax
  jne    L38
L23:
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
unsigned int HSMMCSDIsCmdComplete(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x230)))) & (0x00000001u)) >> (0x00000000u);
    if ((1 == status) || (0 == retry)) {
      break;
    }
  } while (retry--);
  return status;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HSMMCSDIsCmdComplete>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    0x230(%edi),%eax
  lea    0x230(%rdi),%edx
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  test   %esi,%esi
  jne    L9
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L37:
  mov    (%rdx),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    $0x1,%esi
  je     L35
L9:
  cmp    $0x1,%eax
  jne    L37
L35:
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
unsigned int HSMMCSDIsCmdComplete(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x230)))) & (0x00000001u)) >> (0x00000000u);
    if ((1 == status) || (0 == retry)) {
      break;
    }
  } while (retry--);
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HSMMCSDIsCmdComplete>:
  endbr64
  movl   $0x0,-0x4(%rsp)
  mov    0x230(%edi),%eax
  lea    0x230(%rdi),%edx
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  test   %esi,%esi
  jne    L24
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L28:
  mov    (%rdx),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rsp)
  mov    -0x4(%rsp),%eax
  sub    $0x1,%esi
  je     L10
L24:
  cmp    $0x1,%eax
  jne    L28
L10:
  mov    -0x4(%rsp),%eax
  ret
```

assistant: ```c
unsigned int HSMMCSDIsCmdComplete(unsigned int baseAddr, unsigned int retry) {
  volatile unsigned int status = 0;
  do {
    status = ((*((volatile unsigned int *)(baseAddr + (0x230)))) & (0x00000001u)) >> (0x00000000u);
    if ((1 == status) || (0 == retry)) {
      break;
    }
  } while (retry--);
  return status;
}
```
user: Translate the below assembly code into C programming language:

```asm
<qnextline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <qnext@plt>
  cltq
  mov    %rax,-0x20(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *qnextline(q, s)
struct queue *q;
char *s;
{
  char ch;
  for (;;) {
    ch = *s;
    s = qnext(q, s);
    if (ch == '\n')
      return s;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<qnextline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L6:
  movzbl (%rsi),%ebx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <qnext@plt>
  movslq %eax,%rsi
  cmp    $0xa,%bl
  jne    L6
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *qnextline(q, s)
struct queue *q;
char *s;
{
  char ch;
  for (;;) {
    ch = *s;
    s = qnext(q, s);
    if (ch == '\n')
      return s;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qnextline>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L8:
  movzbl (%rsi),%ebx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <qnext@plt>
  movslq %eax,%rsi
  cmp    $0xa,%bl
  jne    L8
  add    $0x8,%rsp
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *qnextline(q, s)
struct queue *q;
char *s;
{
  char ch;
  for (;;) {
    ch = *s;
    s = qnext(q, s);
    if (ch == '\n')
      return s;
  }
}
```