user: 这段汇编代码用C语言表示是什么样的？

```asm
<handle_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x24(%rbp)
  jne    L38
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <trickled_getinfo@plt>
  cmp    $0xffffffff,%eax
  jne    L33
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L33:
  mov    -0xc(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x10(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D45(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x16,%ecx
  add    %ecx,%eax
  and    $0x3ff,%eax
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  lea    0x3ff(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0xa,%eax
  mov    %eax,%esi
  mov    -0xc(%rbp),%eax
  lea    0x3ff(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0xa,%eax
  movq   %rdx,%xmm0
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L4
  movl   $0x1,-0x14(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x18(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  divsd  %xmm2,%xmm0
  movapd %xmm0,%xmm1
  movsd  D45(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x16,%ecx
  add    %ecx,%eax
  and    $0x3ff,%eax
  sub    %ecx,%eax
  imul   $0x64,%eax,%eax
  lea    0x3ff(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0xa,%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  lea    0x3ff(%rax),%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  sar    $0xa,%eax
  movq   %rdx,%xmm0
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
L38:
  nop
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type: string
name: parse_data
arguments: data_label: D45
type: byte[8]
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D37
type: string

tool: D26: trickled_getinfo()

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D13: DOWNLOAD: %d.%d KB/s (utilization: %.1f%%)

tool: D37: UPLOAD: %d.%d KB/s (utilization: %.1f%%)

assistant: ```c
void handle_command(int cmd, int ac, char **av) {
  switch (cmd) {
  case 0: {
    uint32_t uplim, uprate, downlim, downrate;
    if (trickled_getinfo(&uplim, &uprate, &downlim, &downrate) == -1)
      err(1, "trickled_getinfo()");
    warnx("DOWNLOAD: %d.%d KB/s (utilization: %.1f%%)", downrate / 1024, (downrate % 1024) * 100 / 1024, ((1.0 * downrate) / (1.0 * downlim)) * 100);
    if (uprate == 0)
      uprate = 1;
    warnx("UPLOAD: %d.%d KB/s (utilization: %.1f%%)", uprate / 1024, (uprate % 1024) * 100 / 1024, ((1.0 * uprate) / (1.0 * uplim)) * 100);
  }
  default:
    break;
  }
}
```