ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %edi,-0x214(%rbp)
  mov    %rsi,-0x220(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L44
L3:
  lea    -0x200(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x204(%rbp)
  jmp    L19
L49:
  mov    -0x204(%rbp),%eax
  cltq
  movzbl -0x200(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L46
  mov    -0x204(%rbp),%eax
  cltq
  movzbl -0x200(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L46
  mov    -0x204(%rbp),%eax
  cltq
  movzbl -0x200(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L46:
  subl   $0x1,-0x204(%rbp)
L19:
  cmpl   $0x0,-0x204(%rbp)
  jns    L49
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L44:
  lea    -0x200(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_infered: string

tool: D1: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  char str[501];
  while (gets(str) != NULL) {
    for (i = strlen(str) - 1; i >= 0; i--)
      if (str[i] >= 'a' && str[i] <= 'z')
        putchar(str[i]);
    printf("\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rbp
  jmp    L59
L17:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L48
L79:
  movzbl (%rsp,%rbx,1),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  ja     L17
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L17
L48:
  mov    %rbp,%rdi
  call   <printf@plt>
L59:
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L39
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L48
  movslq %eax,%rbx
  jmp    L79
L39:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  char str[501];
  while (gets(str) != NULL) {
    for (i = strlen(str) - 1; i >= 0; i--)
      if (str[i] >= 'a' && str[i] <= 'z')
        putchar(str[i]);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L28
  nopl   0x0(%rax)
L71:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L26
  movslq %eax,%rbx
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L53:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L26
L48:
  movsbl (%r12,%rbx,1),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  ja     L53
  call   <putchar@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L48
L26:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L71
L28:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  char str[501];
  while (gets(str) != NULL) {
    for (i = strlen(str) - 1; i >= 0; i--)
      if (str[i] >= 'a' && str[i] <= 'z')
        putchar(str[i]);
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L6
  nopl   0x0(%rax)
L72:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L41
  movslq %eax,%rbx
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L50:
  sub    $0x1,%rbx
  test   %ebx,%ebx
  js     L41
L55:
  movsbl (%r12,%rbx,1),%edi
  lea    -0x61(%rdi),%eax
  cmp    $0x19,%al
  ja     L50
  call   <putchar@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L55
L41:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L72
L6:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int i;
  char str[501];
  while (gets(str) != NULL) {
    for (i = strlen(str) - 1; i >= 0; i--)
      if (str[i] >= 'a' && str[i] <= 'z')
        putchar(str[i]);
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L24:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  sarl   -0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L22
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L10
  mov    -0xc(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L44
L10:
  mov    -0xc(%rbp),%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x3e7,-0xc(%rbp)
  jle    L24
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string

tool: D7: 
%.3d: 

tool: D18: %d

assistant: ```c
int main(void) {
  int count, size, direction, to;
  for (count = 0; count < 1000; ++count) {
    size = count;
    printf("\n%.3d: ", count);
    do
      printf("%d", size % 2);
    while (size = size >> 1);
    if (count % 2)
      to = count - 2;
    else
      to = (count >> 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  lea    D1(%rip),%r13
  lea    D0(%rip),%rbp
L7:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%ebx
L19:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x1,%esi
  sub    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  sar    %ebx
  jne    L19
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L7
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string

tool: D1: 
%.3d: 

tool: D0: %d

assistant: ```c
int main(void) {
  int count, size, direction, to;
  for (count = 0; count < 1000; ++count) {
    size = count;
    printf("\n%.3d: ", count);
    do
      printf("%d", size % 2);
    while (size = size >> 1);
    if (count % 2)
      to = count - 2;
    else
      to = (count >> 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D13(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L18:
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %r12d,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  and    $0x1,%esi
  call   <printf@plt>
  sar    %ebx
  jne    L14
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L18
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string

tool: D1: 
%.3d: 

tool: D13: %d

assistant: ```c
int main(void) {
  int count, size, direction, to;
  for (count = 0; count < 1000; ++count) {
    size = count;
    printf("\n%.3d: ", count);
    do
      printf("%d", size % 2);
    while (size = size >> 1);
    if (count % 2)
      to = count - 2;
    else
      to = (count >> 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nop
L10:
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %r12d,%ebx
  call   <printf@plt>
  xchg   %ax,%ax
L14:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  and    $0x1,%esi
  call   <printf@plt>
  sar    %ebx
  jne    L14
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D2
type: string

tool: D16: 
%.3d: 

tool: D2: %d

assistant: ```c
int main(void) {
  int count, size, direction, to;
  for (count = 0; count < 1000; ++count) {
    size = count;
    printf("\n%.3d: ", count);
    do
      printf("%d", size % 2);
    while (size = size >> 1);
    if (count % 2)
      to = count - 2;
    else
      to = (count >> 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L17
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L17:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D8: 1001-1618-2903

tool: D3: %s

tool: D16: register succeed

tool: D19: register lose

assistant: ```c
void main() {
  char *ysn;
  char *sn;
  sn = "1001-1618-2903";
  scanf("%s", ysn);
  if (!strcmp(ysn, sn))
    printf("register succeed");
  else
    printf("register lose");
  getch();
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L13
  lea    D34(%rip),%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
L13:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D8: %s

tool: D29: 1001-1618-2903

tool: D34: register succeed

tool: D21: register lose

assistant: ```c
void main() {
  char *ysn;
  char *sn;
  sn = "1001-1618-2903";
  scanf("%s", ysn);
  if (!strcmp(ysn, sn))
    printf("register succeed");
  else
    printf("register lose");
  getch();
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  lea    D15(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L9
  lea    D30(%rip),%rdi
  call   <printf@plt>
L14:
  xor    %eax,%eax
  call   <getch@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    10d0 <exit@plt>
L9:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: tag: D15
datatype: string
name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D30
datatype: string
name: unpack_data
arguments: tag: D27
datatype: string

tool: D15: %s

tool: D20: 1001-1618-2903

tool: D30: register succeed

tool: D27: register lose

assistant: ```c
void main() {
  char *ysn;
  char *sn;
  sn = "1001-1618-2903";
  scanf("%s", ysn);
  if (!strcmp(ysn, sn))
    printf("register succeed");
  else
    printf("register lose");
  getch();
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  lea    D7(%rip),%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    D30(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L9
  lea    D6(%rip),%rdi
  call   <printf@plt>
L11:
  xor    %eax,%eax
  call   <getch@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    10d0 <exit@plt>
L9:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D30
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D7: %s

tool: D30: 1001-1618-2903

tool: D6: register succeed

tool: D3: register lose

assistant: ```c
void main() {
  char *ysn;
  char *sn;
  sn = "1001-1618-2903";
  scanf("%s", ysn);
  if (!strcmp(ysn, sn))
    printf("register succeed");
  else
    printf("register lose");
  getch();
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Combination>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  movl   $0x0,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L25
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L17
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jne    L13
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <Combination>
  jmp    L22
L17:
  nop
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string

tool: D6: posA=%d posB=%d


tool: D17: %d %d


assistant: ```c
void Combination(int *arr, int posA, int posB, int len) {
  if (posB >= len) {
    posB = 0;
    posA += 1;
  }
  if (posA >= posB) {
    posB = posA;
  }
  if (posA >= len) {
    return;
  }
  if (arr[posA] + arr[posB] == 4) {
    printf("posA=%d posB=%d\n", posA, posB);
  }
  printf("%d %d\n", posA, posB);
  Combination(arr, posA, posB + 1, len);
}
```
user: What is the c source code of the assembly code below:

```asm
<Combination>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %ecx,%r13d
  cmp    %ecx,%edx
  jl     L37
  add    $0x1,%ebp
  mov    $0x0,%edx
L37:
  cmp    %r13d,%ebp
  jge    L18
  cmp    %edx,%ebp
  mov    %edx,%ebx
  cmovge %ebp,%ebx
  movslq %ebp,%rdx
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%eax
  add    (%r12,%rdx,4),%eax
  cmp    $0x4,%eax
  je     L0
L6:
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x1(%rbx),%edx
  mov    %r13d,%ecx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <Combination>
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string
name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D6: %d %d


tool: D3: posA=%d posB=%d


assistant: ```c
void Combination(int *arr, int posA, int posB, int len) {
  if (posB >= len) {
    posB = 0;
    posA += 1;
  }
  if (posA >= posB) {
    posB = posA;
  }
  if (posA >= len) {
    return;
  }
  if (arr[posA] + arr[posB] == 4) {
    printf("posA=%d posB=%d\n", posA, posB);
  }
  printf("%d %d\n", posA, posB);
  Combination(arr, posA, posB + 1, len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Combination>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x1(%rbx),%edx
L24:
  cmp    %ebp,%edx
  jl     L12
  add    $0x1,%r15d
  xor    %edx,%edx
L12:
  cmp    %edx,%r15d
  mov    %edx,%ebx
  cmovge %r15d,%ebx
  cmp    %ebp,%r15d
  jge    L28
  movslq %r15d,%rdx
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%eax
  add    (%r12,%rdx,4),%eax
  cmp    $0x4,%eax
  jne    L15
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D18: posA=%d posB=%d


tool: D2: %d %d


assistant: ```c
void Combination(int *arr, int posA, int posB, int len) {
  if (posB >= len) {
    posB = 0;
    posA += 1;
  }
  if (posA >= posB) {
    posB = posA;
  }
  if (posA >= len) {
    return;
  }
  if (arr[posA] + arr[posB] == 4) {
    printf("posA=%d posB=%d\n", posA, posB);
  }
  printf("%d %d\n", posA, posB);
  Combination(arr, posA, posB + 1, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Combination>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x1(%rbx),%edx
L14:
  cmp    %ebp,%edx
  jl     L33
  add    $0x1,%r15d
  xor    %edx,%edx
L33:
  cmp    %edx,%r15d
  mov    %edx,%ebx
  cmovge %r15d,%ebx
  cmp    %ebp,%r15d
  jge    L31
  movslq %r15d,%rdx
  movslq %ebx,%rax
  mov    (%r12,%rax,4),%eax
  add    (%r12,%rdx,4),%eax
  cmp    $0x4,%eax
  jne    L13
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string

tool: D16: posA=%d posB=%d


tool: D18: %d %d


assistant: ```c
void Combination(int *arr, int posA, int posB, int len) {
  if (posB >= len) {
    posB = 0;
    posA += 1;
  }
  if (posA >= posB) {
    posB = posA;
  }
  if (posA >= len) {
    return;
  }
  if (arr[posA] + arr[posB] == 4) {
    printf("posA=%d posB=%d\n", posA, posB);
  }
  printf("%d %d\n", posA, posB);
  Combination(arr, posA, posB + 1, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movabs $0x7afdb142472c3516,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L29
L33:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%edx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  cmpl   $0x7,-0x14(%rbp)
  jne    L23
  movl   $0x0,-0x14(%rbp)
L23:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L33
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void encrypt(char *array, int array_size) {
  int i;
  int j = 0;
  char secret[8] = {22, 53, 44, 71, 66, 177, 253, 122};
  for (i = 0; i < array_size; i++) {
    array[i] ^= secret[j];
    if (j == 7)
      j = 0;
    j++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encrypt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x7afdb142472c3516,%rax
  mov    %rax,(%rsp)
  test   %esi,%esi
  jle    L15
  movzbl (%rsp),%eax
  xor    %al,(%rdi)
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  add    %rax,%rdi
  mov    $0x0,%eax
  mov    $0x0,%esi
  jmp    L6
L11:
  movslq %eax,%rcx
  movzbl (%rsp,%rcx,1),%ecx
  xor    %cl,0x1(%rdx)
  cmp    $0x7,%eax
  cmove  %esi,%eax
  add    $0x1,%rdx
L6:
  add    $0x1,%eax
  cmp    %rdi,%rdx
  jne    L11
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void encrypt(char *array, int array_size) {
  int i;
  int j = 0;
  char secret[8] = {22, 53, 44, 71, 66, 177, 253, 122};
  for (i = 0; i < array_size; i++) {
    array[i] ^= secret[j];
    if (j == 7)
      j = 0;
    j++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<encrypt>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x7afdb142472c3516,%rax
  mov    %rax,(%rsp)
  test   %esi,%esi
  jle    L35
  lea    -0x1(%rsi),%ecx
  mov    $0x16,%edx
  xor    %eax,%eax
  mov    $0x1,%esi
  add    %rdi,%rcx
  jmp    L30
  nopl   0x0(%rax)
L19:
  movslq %eax,%rdx
  add    $0x1,%rdi
  movzbl (%rsp,%rdx,1),%edx
L30:
  xor    %dl,(%rdi)
  lea    0x1(%rax),%edx
  cmp    $0x7,%eax
  mov    %edx,%eax
  cmove  %esi,%eax
  cmp    %rcx,%rdi
  jne    L19
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void encrypt(char *array, int array_size) {
  int i;
  int j = 0;
  char secret[8] = {22, 53, 44, 71, 66, 177, 253, 122};
  for (i = 0; i < array_size; i++) {
    array[i] ^= secret[j];
    if (j == 7)
      j = 0;
    j++;
  }
}
```