ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_bullet_indent>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    -0x2(%rdi),%r12d
  mov    $0x0,%ebx
  mov    $0x2d,%r13d
L0:
  cmp    %ebx,%r12d
  mov    $0x20,%edi
  cmove  %r13d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void do_bullet_indent(int indent) {
  int i;
  int n;
  n = indent - 2;
  for (i = 0; i < indent; i++)
    putchar((i == n) ? '-' : ' ');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_bullet_indent>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %r13
  mov    $0x2d,%r13d
  push   %r12
  lea    -0x2(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L17:
  cmp    %ebx,%r12d
  mov    $0x20,%edi
  cmove  %r13d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void do_bullet_indent(int indent) {
  int i;
  int n;
  n = indent - 2;
  for (i = 0; i < indent; i++)
    putchar((i == n) ? '-' : ' ');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_bullet_indent>:
  endbr64
  test   %edi,%edi
  jle    L36
  push   %r12
  lea    -0x2(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L15:
  cmp    %ebx,%r12d
  je     L23
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x2d,%edi
  lea    0x1(%r12),%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  ret
```

assistant: ```c
void do_bullet_indent(int indent) {
  int i;
  int n;
  n = indent - 2;
  for (i = 0; i < indent; i++)
    putchar((i == n) ? '-' : ' ');
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L35
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L20
  mov    $0x1,%eax
  jmp    L14
L20:
  mov    $0xffffffff,%eax
  jmp    L14
L35:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_int(void *v1, void *v2) {
  int a = *((int *)v1);
  int b = *((int *)v2);
  return (a == b) ? 0 : ((a > b) ? 1 : -1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp_int>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0x0,%eax
  cmp    %edx,%ecx
  je     L4
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L4:
  ret
```

assistant: ```c
int cmp_int(void *v1, void *v2) {
  int a = *((int *)v1);
  int b = *((int *)v2);
  return (a == b) ? 0 : ((a > b) ? 1 : -1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_int>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L2
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L2:
  ret
```

assistant: ```c
int cmp_int(void *v1, void *v2) {
  int a = *((int *)v1);
  int b = *((int *)v2);
  return (a == b) ? 0 : ((a > b) ? 1 : -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_int>:
  endbr64
  mov    (%rsi),%edx
  xor    %eax,%eax
  cmp    %edx,(%rdi)
  je     L2
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L2:
  ret
```

assistant: ```c
int cmp_int(void *v1, void *v2) {
  int a = *((int *)v1);
  int b = *((int *)v2);
  return (a == b) ? 0 : ((a > b) ? 1 : -1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  jmp    L23
L15:
  movslq %ebx,%rax
  movb   $0x2a,-0x40(%rbp,%rax,1)
  add    $0x1,%ebx
L23:
  cmp    $0x31,%ebx
  jle    L15
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void overflow() {
  register int i = 0;
  char foo[30];
  for (i = 0; i < 50; i++)
    foo[i] = 42;
}
```
user: What is the c source code of the assembly code below:

```asm
<overflow>:
  endbr64
  mov    $0x32,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  ret
```

assistant: ```c
void overflow() {
  register int i = 0;
  char foo[30];
  for (i = 0; i < 50; i++)
    foo[i] = 42;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<overflow>:
  endbr64
  ret
```

assistant: ```c
void overflow() {
  register int i = 0;
  char foo[30];
  for (i = 0; i < 50; i++)
    foo[i] = 42;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<overflow>:
  endbr64
  ret
```

assistant: ```c
void overflow() {
  register int i = 0;
  char foo[30];
  for (i = 0; i < 50; i++)
    foo[i] = 42;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0x3,-0x30(%rbp)
  movl   $0x4,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x5,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  lea    -0x34(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%r9
  mov    $0x5,%r8d
  mov    $0x6,%ecx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <maxNumber@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int returnSize = 0;
  int nums1[] = {3, 4, 6, 5};
  int nums2[] = {9, 1, 2, 5, 8, 3};
  maxNumber(nums1, 4, nums2, 6, 5, &returnSize);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x5,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x2,0x28(%rsp)
  movl   $0x5,0x2c(%rsp)
  movl   $0x8,0x30(%rsp)
  movl   $0x3,0x34(%rsp)
  lea    0x20(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%r9
  mov    $0x5,%r8d
  mov    $0x6,%ecx
  mov    $0x4,%esi
  call   <maxNumber@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int returnSize = 0;
  int nums1[] = {3, 4, 6, 5};
  int nums2[] = {9, 1, 2, 5, 8, 3};
  maxNumber(nums1, 4, nums2, 6, 5, &returnSize);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x5,%r8d
  mov    $0x6,%ecx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  movabs $0x400000003,%rax
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  lea    0xc(%rsp),%r9
  movabs $0x500000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000009,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x500000002,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x300000008,%rax
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x30(%rsp)
  call   <maxNumber@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int returnSize = 0;
  int nums1[] = {3, 4, 6, 5};
  int nums2[] = {9, 1, 2, 5, 8, 3};
  maxNumber(nums1, 4, nums2, 6, 5, &returnSize);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    $0x5,%r8d
  mov    $0x6,%ecx
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    D8(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D0(%rip),%xmm0
  lea    0xc(%rsp),%r9
  mov    $0x4,%esi
  movl   $0x0,0xc(%rsp)
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <maxNumber@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
type_guessed: byte[16]
name: read_data
arguments: data_tag: D8
type_guessed: byte[8]
name: read_data
arguments: data_tag: D0
type_guessed: byte[16]

tool: {"D26": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D8": [0x08,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D0": [0x09,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int returnSize = 0;
  int nums1[] = {3, 4, 6, 5};
  int nums2[] = {9, 1, 2, 5, 8, 3};
  maxNumber(nums1, 4, nums2, 6, 5, &returnSize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<readmbr_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <send_initial_clock@plt>
  mov    $0x0,%eax
  call   <send_reset@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L52
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  jmp    L22
L52:
  mov    $0x0,%eax
  call   <send_if_cond@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L37
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  jmp    L22
L37:
  mov    $0x0,%eax
  call   <send_read_ocr@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L54
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  jmp    L22
L54:
  mov    $0x0,%eax
  call   <sd_wait_ready@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L46
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  jmp    L22
L46:
  mov    $0x0,%eax
  call   <sd_set_blocklen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L83
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
  jmp    L22
L83:
  mov    $0x0,%eax
  call   <read_mbr@plt>
L22:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D41
type: string
name: extract_symbolic_data
arguments: data_label: D10
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D14: readmbr: failed to reset


tool: D20: readmbr: failed to send interface conditions


tool: D41: readmbr: failed to read OCR


tool: D10: readmbr: failed to wait for SD to become ready


tool: D12: readmbr: failed to set blocklen


assistant: ```c
void readmbr_handler(const char *buf) {
  int rc;
  send_initial_clock();
  rc = send_reset();
  if (rc) {
    printk("readmbr: failed to reset\n");
    return;
  }
  rc = send_if_cond();
  if (rc) {
    printk("readmbr: failed to send interface conditions\n");
    return;
  }
  rc = send_read_ocr();
  if (rc) {
    printk("readmbr: failed to read OCR\n");
    return;
  }
  rc = sd_wait_ready();
  if (rc) {
    printk("readmbr: failed to wait for SD to become ready\n");
    return;
  }
  rc = sd_set_blocklen();
  if (rc) {
    printk("readmbr: failed to set blocklen\n");
    return;
  }
  read_mbr();
}
```
user: What is the c source code of the assembly code below:

```asm
<readmbr_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <send_initial_clock@plt>
  mov    $0x0,%eax
  call   <send_reset@plt>
  test   %eax,%eax
  jne    L18
  mov    $0x0,%eax
  call   <send_if_cond@plt>
  test   %eax,%eax
  jne    L30
  mov    $0x0,%eax
  call   <send_read_ocr@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  call   <sd_wait_ready@plt>
  test   %eax,%eax
  jne    L58
  mov    $0x0,%eax
  call   <sd_set_blocklen@plt>
  test   %eax,%eax
  jne    L78
  mov    $0x0,%eax
  call   <read_mbr@plt>
  jmp    L70
L18:
  lea    D6(%rip),%rdi
  call   <printk@plt>
L70:
  add    $0x8,%rsp
  ret
L30:
  lea    D20(%rip),%rdi
  call   <printk@plt>
  jmp    L70
L3:
  lea    D43(%rip),%rdi
  call   <printk@plt>
  jmp    L70
L58:
  lea    D34(%rip),%rdi
  call   <printk@plt>
  jmp    L70
L78:
  lea    D33(%rip),%rdi
  call   <printk@plt>
  jmp    L70
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D43
data_type: string
name: disassemble_data
arguments: data_tag: D34
data_type: string
name: disassemble_data
arguments: data_tag: D33
data_type: string

tool: D6: readmbr: failed to reset


tool: D20: readmbr: failed to send interface conditions


tool: D43: readmbr: failed to read OCR


tool: D34: readmbr: failed to wait for SD to become ready


tool: D33: readmbr: failed to set blocklen


assistant: ```c
void readmbr_handler(const char *buf) {
  int rc;
  send_initial_clock();
  rc = send_reset();
  if (rc) {
    printk("readmbr: failed to reset\n");
    return;
  }
  rc = send_if_cond();
  if (rc) {
    printk("readmbr: failed to send interface conditions\n");
    return;
  }
  rc = send_read_ocr();
  if (rc) {
    printk("readmbr: failed to read OCR\n");
    return;
  }
  rc = sd_wait_ready();
  if (rc) {
    printk("readmbr: failed to wait for SD to become ready\n");
    return;
  }
  rc = sd_set_blocklen();
  if (rc) {
    printk("readmbr: failed to set blocklen\n");
    return;
  }
  read_mbr();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readmbr_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <send_initial_clock@plt>
  xor    %eax,%eax
  call   <send_reset@plt>
  test   %eax,%eax
  jne    L46
  xor    %eax,%eax
  call   <send_if_cond@plt>
  test   %eax,%eax
  jne    L32
  xor    %eax,%eax
  call   <send_read_ocr@plt>
  test   %eax,%eax
  jne    L44
  xor    %eax,%eax
  call   <sd_wait_ready@plt>
  test   %eax,%eax
  jne    L41
  xor    %eax,%eax
  call   <sd_set_blocklen@plt>
  test   %eax,%eax
  jne    L40
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <read_mbr@plt>
  nopl   0x0(%rax)
L32:
  lea    D13(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
  nopl   0x0(%rax,%rax,1)
L46:
  lea    D26(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L41:
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L44:
  lea    D27(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L40:
  lea    D34(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D34
data_type: string

tool: D13: readmbr: failed to send interface conditions


tool: D26: readmbr: failed to reset


tool: D7: readmbr: failed to wait for SD to become ready


tool: D27: readmbr: failed to read OCR


tool: D34: readmbr: failed to set blocklen


assistant: ```c
void readmbr_handler(const char *buf) {
  int rc;
  send_initial_clock();
  rc = send_reset();
  if (rc) {
    printk("readmbr: failed to reset\n");
    return;
  }
  rc = send_if_cond();
  if (rc) {
    printk("readmbr: failed to send interface conditions\n");
    return;
  }
  rc = send_read_ocr();
  if (rc) {
    printk("readmbr: failed to read OCR\n");
    return;
  }
  rc = sd_wait_ready();
  if (rc) {
    printk("readmbr: failed to wait for SD to become ready\n");
    return;
  }
  rc = sd_set_blocklen();
  if (rc) {
    printk("readmbr: failed to set blocklen\n");
    return;
  }
  read_mbr();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readmbr_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <send_initial_clock@plt>
  xor    %eax,%eax
  call   <send_reset@plt>
  test   %eax,%eax
  jne    L44
  xor    %eax,%eax
  call   <send_if_cond@plt>
  test   %eax,%eax
  jne    L29
  xor    %eax,%eax
  call   <send_read_ocr@plt>
  test   %eax,%eax
  jne    L15
  xor    %eax,%eax
  call   <sd_wait_ready@plt>
  test   %eax,%eax
  jne    L6
  xor    %eax,%eax
  call   <sd_set_blocklen@plt>
  test   %eax,%eax
  jne    L3
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10e0 <read_mbr@plt>
  nopl   0x0(%rax)
L29:
  lea    D23(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
  nopl   0x0(%rax,%rax,1)
L44:
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L6:
  lea    D26(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L15:
  lea    D29(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
L3:
  lea    D32(%rip),%rdi
  add    $0x8,%rsp
  jmp    1110 <printk@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: string
name: disassemble_data
arguments: data_label: D32
type_guessed: string

tool: D23: readmbr: failed to send interface conditions


tool: D2: readmbr: failed to reset


tool: D26: readmbr: failed to wait for SD to become ready


tool: D29: readmbr: failed to read OCR


tool: D32: readmbr: failed to set blocklen


assistant: ```c
void readmbr_handler(const char *buf) {
  int rc;
  send_initial_clock();
  rc = send_reset();
  if (rc) {
    printk("readmbr: failed to reset\n");
    return;
  }
  rc = send_if_cond();
  if (rc) {
    printk("readmbr: failed to send interface conditions\n");
    return;
  }
  rc = send_read_ocr();
  if (rc) {
    printk("readmbr: failed to read OCR\n");
    return;
  }
  rc = sd_wait_ready();
  if (rc) {
    printk("readmbr: failed to wait for SD to become ready\n");
    return;
  }
  rc = sd_set_blocklen();
  if (rc) {
    printk("readmbr: failed to set blocklen\n");
    return;
  }
  read_mbr();
}
```
user: Translate the below assembly code into C programming language:

```asm
<normpdf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <error@plt>
L0:
  movsd  D29(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x10(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm4
  mulsd  -0x18(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  mulsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D29
type: f64
name: unpack_data
arguments: data_tag: D7
type: byte[8]

tool: D8: Parameter sig is smaller than 0.

tool: D29: 0.3989422804014327

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

assistant: ```c
double normpdf(double x, double mu, double sig) {
  if (sig < 0)
    error("Parameter sig is smaller than 0.");
  return (0.3989422804014327 / sig) * exp(-0.5 * (x - mu) * (x - mu) / (sig) * (sig));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normpdf>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%r14
  movsd  %xmm2,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  ja     L16
L18:
  movq   %rbx,%xmm0
  movq   %r14,%xmm5
  subsd  %xmm5,%xmm0
  movapd %xmm0,%xmm1
  mulsd  D13(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm3
  divsd  %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  movsd  D11(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L16:
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: byte[8]
name: parse_data
arguments: label: D11
type_guessed: f64
name: parse_data
arguments: label: D14
type_guessed: string

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D11: 0.3989422804014327

tool: D14: Parameter sig is smaller than 0.

assistant: ```c
double normpdf(double x, double mu, double sig) {
  if (sig < 0)
    error("Parameter sig is smaller than 0.");
  return (0.3989422804014327 / sig) * exp(-0.5 * (x - mu) * (x - mu) / (sig) * (sig));
}
```
user: Translate the below assembly code into C programming language:

```asm
<normpdf>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x28,%rsp
  comisd %xmm2,%xmm3
  ja     L8
L12:
  subsd  %xmm1,%xmm0
  movsd  D25(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movsd  D0(%rip),%xmm0
  add    $0x28,%rsp
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <error@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type: byte[8]
name: disassemble_data
arguments: data_tag: D0
type: f64
name: disassemble_data
arguments: data_tag: D19
type: string

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D0: 0.3989422804014327

tool: D19: Parameter sig is smaller than 0.

assistant: ```c
double normpdf(double x, double mu, double sig) {
  if (sig < 0)
    error("Parameter sig is smaller than 0.");
  return (0.3989422804014327 / sig) * exp(-0.5 * (x - mu) * (x - mu) / (sig) * (sig));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<normpdf>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x28,%rsp
  comisd %xmm2,%xmm3
  ja     L13
L16:
  subsd  %xmm1,%xmm0
  movsd  D1(%rip),%xmm1
  movsd  %xmm2,0x8(%rsp)
  mulsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  movsd  D27(%rip),%xmm0
  add    $0x28,%rsp
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm0,0x8(%rsp)
  call   <error@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  jmp    L16
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: byte[8]
name: unpack_data
arguments: label: D27
type_guessed: f64
name: unpack_data
arguments: label: D11
type_guessed: string

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: D27: 0.3989422804014327

tool: D11: Parameter sig is smaller than 0.

assistant: ```c
double normpdf(double x, double mu, double sig) {
  if (sig < 0)
    error("Parameter sig is smaller than 0.");
  return (0.3989422804014327 / sig) * exp(-0.5 * (x - mu) * (x - mu) / (sig) * (sig));
}
```