ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L18
  movzbl %al,%eax
  lea    D24(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D36(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L16
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L16
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L18:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D39
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D50
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D36
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D48
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D23
type_infered: string

tool: D39: 
Enter a martial code: 

tool: D50: %c

tool: D36: 
Individual is married. 


tool: D29: 
Individual is single. 


tool: D20: 
Individual is divorced. 


tool: D48: 
Individual is widowed. 


tool: D23: 
An invalid code was entered. 


assistant: ```c
int main() {
  char marcode;
  printf("\nEnter a martial code: ");
  scanf("%c", &marcode);
  switch (marcode) {
  case 'm':
  case 'M':
    printf("\nIndividual is married. \n");
    break;
  case 's':
  case 'S':
    printf("\nIndividual is single. \n");
    break;
  case 'd':
  case 'D':
    printf("\nIndividual is divorced. \n");
    break;
  case 'w':
  case 'W':
    printf("\nIndividual is widowed. \n");
    break;
  default:
    printf("\nAn invalid code was entered. \n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D54(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L5
  lea    D14(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L5:
  lea    D30(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L19
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L19
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L19
  lea    D47(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D54
type_infered: string
name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string
name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D44
type_infered: string
name: extract_symbolic_data
arguments: tag: D47
type_infered: string

tool: D7: 
Enter a martial code: 

tool: D54: %c

tool: D30: 
An invalid code was entered. 


tool: D18: 
Individual is widowed. 


tool: D21: 
Individual is single. 


tool: D44: 
Individual is married. 


tool: D47: 
Individual is divorced. 


assistant: ```c
int main() {
  char marcode;
  printf("\nEnter a martial code: ");
  scanf("%c", &marcode);
  switch (marcode) {
  case 'm':
  case 'M':
    printf("\nIndividual is married. \n");
    break;
  case 's':
  case 'S':
    printf("\nIndividual is single. \n");
    break;
  case 'd':
  case 'D':
    printf("\nIndividual is divorced. \n");
    break;
  case 'w':
  case 'W':
    printf("\nIndividual is widowed. \n");
    break;
  default:
    printf("\nAn invalid code was entered. \n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D66(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x44,%eax
  cmp    $0x33,%al
  ja     L32
  lea    D60(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L32:
  lea    D29(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L14
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D66
type_infered: string
name: retrieve_data
arguments: data_tag: D13
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D52
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D1
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D66: 
Enter a martial code: 

tool: D13: %c

tool: D29: 
An invalid code was entered. 


tool: D52: 
Individual is widowed. 


tool: D18: 
Individual is single. 


tool: D1: 
Individual is married. 


tool: D23: 
Individual is divorced. 


assistant: ```c
int main() {
  char marcode;
  printf("\nEnter a martial code: ");
  scanf("%c", &marcode);
  switch (marcode) {
  case 'm':
  case 'M':
    printf("\nIndividual is married. \n");
    break;
  case 's':
  case 'S':
    printf("\nIndividual is single. \n");
    break;
  case 'd':
  case 'D':
    printf("\nIndividual is divorced. \n");
    break;
  case 'w':
  case 'W':
    printf("\nIndividual is widowed. \n");
    break;
  default:
    printf("\nAn invalid code was entered. \n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lengthAckermannSequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L22
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L17
L22:
  sarl   -0x14(%rbp)
L17:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L26
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lengthAckermannSequence(int n) {
  int count = 0;
  do {
    if (n & 1) {
      n = 3 * n + 1;
    } else {
      n >>= 1;
    }
    count++;
  } while (n > 1);
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lengthAckermannSequence>:
  endbr64
  mov    $0x0,%eax
  jmp    L32
L3:
  lea    0x1(%rdi,%rdi,2),%edi
L39:
  add    $0x1,%eax
  cmp    $0x1,%edi
  jle    L14
L32:
  test   $0x1,%dil
  jne    L3
  sar    %edi
  jmp    L39
L14:
  ret
```

assistant: ```c
int lengthAckermannSequence(int n) {
  int count = 0;
  do {
    if (n & 1) {
      n = 3 * n + 1;
    } else {
      n >>= 1;
    }
    count++;
  } while (n > 1);
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<lengthAckermannSequence>:
  endbr64
  xor    %eax,%eax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L2:
  lea    0x1(%rdi,%rdi,2),%edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jle    L27
L6:
  test   $0x1,%dil
  jne    L2
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jg     L6
L27:
  ret
```

assistant: ```c
int lengthAckermannSequence(int n) {
  int count = 0;
  do {
    if (n & 1) {
      n = 3 * n + 1;
    } else {
      n >>= 1;
    }
    count++;
  } while (n > 1);
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lengthAckermannSequence>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L20:
  test   $0x1,%dil
  je     L8
  lea    0x1(%rdi,%rdi,2),%edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jg     L20
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  sar    %edi
  add    $0x1,%eax
  cmp    $0x1,%edi
  jg     L20
  ret
```

assistant: ```c
int lengthAckermannSequence(int n) {
  int count = 0;
  do {
    if (n & 1) {
      n = 3 * n + 1;
    } else {
      n >>= 1;
    }
    count++;
  } while (n > 1);
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tste@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <tste_vol@plt>
  cmp    %rax,%rbx
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
main() {
  if (tste() != tste_vol())
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <tste@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <tste_vol@plt>
  cmp    %rax,%rbx
  jne    L17
L18:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L18
```

assistant: ```c
main() {
  if (tste() != tste_vol())
    abort();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <tste@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <tste_vol@plt>
  cmp    %rax,%rbx
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  if (tste() != tste_vol())
    abort();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <tste@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <tste_vol@plt>
  cmp    %rax,%rbx
  je     L6
  xor    %eax,%eax
  call   <abort@plt>
L6:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  if (tste() != tste_vol())
    abort();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_count_ip@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L19
L12:
  mov    D37(%rip),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D26(%rip)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L12
  mov    D26(%rip),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <sml_printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
datatype: string

tool: D26: n = %d : sigma n = %d


assistant: ```c
main(int argc, char **argv) {
  static int count = 0;
  int loops = 0;
  int idx;
  loops = get_count_ip();
  for (idx = 1; idx <= loops; idx++) {
    count += idx;
  }
  sml_printf("n = %d : sigma n = %d\n", loops, count);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_count_ip@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jle    L7
  mov    D26(%rip),%ecx
  lea    0x1(%rax),%edi
  mov    $0x1,%edx
L10:
  add    %edx,%ecx
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L10
  mov    %ecx,D14(%rip)
L7:
  mov    D14(%rip),%edx
  lea    D14(%rip),%rdi
  call   <sml_printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type: string

tool: D14: n = %d : sigma n = %d


assistant: ```c
main(int argc, char **argv) {
  static int count = 0;
  int loops = 0;
  int idx;
  loops = get_count_ip();
  for (idx = 1; idx <= loops; idx++) {
    count += idx;
  }
  sml_printf("n = %d : sigma n = %d\n", loops, count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_count_ip@plt>
  mov    D20(%rip),%r8d
  mov    $0x1,%edx
  mov    %eax,%esi
  lea    0x1(%rax),%ecx
  test   %eax,%eax
  jle    L15
  nopl   0x0(%rax)
L0:
  add    %edx,%r8d
  add    $0x1,%edx
  cmp    %edx,%ecx
  jne    L0
  mov    %r8d,D0(%rip)
L15:
  mov    %r8d,%edx
  lea    D0(%rip),%rdi
  call   <sml_printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: n = %d : sigma n = %d


assistant: ```c
main(int argc, char **argv) {
  static int count = 0;
  int loops = 0;
  int idx;
  loops = get_count_ip();
  for (idx = 1; idx <= loops; idx++) {
    count += idx;
  }
  sml_printf("n = %d : sigma n = %d\n", loops, count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_count_ip@plt>
  mov    D28(%rip),%edx
  mov    %eax,%esi
  test   %eax,%eax
  jle    L2
  lea    -0x1(%rax),%eax
  cmp    $0x9,%eax
  jbe    L76
  mov    %esi,%ecx
  movdqa D10(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D11(%rip),%xmm3
  shr    $0x2,%ecx
  cs nopw 0x0(%rax,%rax,1)
L119:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%ecx
  jne    L119
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %eax,%edx
  lea    0x1(%rcx),%eax
  cmp    %ecx,%esi
  je     L9
L47:
  lea    0x1(%rax),%ecx
  add    %eax,%edx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x2(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x3(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x4(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x5(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x6(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x7(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    %ecx,%edx
  lea    0x8(%rax),%ecx
  cmp    %ecx,%esi
  jl     L9
  add    $0x9,%eax
  add    %ecx,%edx
  cmp    %eax,%esi
  jl     L9
  add    %eax,%edx
L9:
  mov    %edx,D36(%rip)
L2:
  lea    D36(%rip),%rdi
  call   <sml_printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L76:
  mov    $0x1,%eax
  jmp    L47
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: byte[16]
name: parse_data
arguments: data_label: D11
datatype: byte[16]
name: parse_data
arguments: data_label: D36
datatype: string

tool: {"D10": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D36: n = %d : sigma n = %d


assistant: ```c
main(int argc, char **argv) {
  static int count = 0;
  int loops = 0;
  int idx;
  loops = get_count_ip();
  for (idx = 1; idx <= loops; idx++) {
    count += idx;
  }
  sml_printf("n = %d : sigma n = %d\n", loops, count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmp_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L66
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L82
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
L82:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
  mov    $0x0,%eax
  jmp    L56
L49:
  mov    $0xffffffff,%eax
  jmp    L56
L77:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L5
  mov    $0x1,%eax
  jmp    L56
L5:
  addl   $0x1,-0x4(%rbp)
L66:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
L56:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_name(const char *lname, const char *dname, int nlen) {
  int i;
  for (i = 0; i < nlen; i++) {
    if (lname[i] == '/' || lname[i] == 0) {
      if (dname[i] == 0)
        return 0;
      return -1;
    }
    if (lname[i] != dname[i])
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmp_name>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
L26:
  movzbl (%rdi,%rax,1),%ecx
  cmp    $0x2f,%cl
  je     L9
  test   %cl,%cl
  je     L9
  cmp    (%rsi,%rax,1),%cl
  jne    L37
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  mov    $0x0,%eax
  ret
L9:
  movzbl (%rsi,%rax,1),%eax
  neg    %al
  sbb    %eax,%eax
  ret
L14:
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cmp_name(const char *lname, const char *dname, int nlen) {
  int i;
  for (i = 0; i < nlen; i++) {
    if (lname[i] == '/' || lname[i] == 0) {
      if (dname[i] == 0)
        return 0;
      return -1;
    }
    if (lname[i] != dname[i])
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmp_name>:
  endbr64
  test   %edx,%edx
  jle    L45
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L56
  nop
L29:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L45
L56:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    $0x2f,%cl
  je     L18
  test   %cl,%cl
  je     L18
  cmp    %r8b,%cl
  je     L29
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  neg    %r8b
  sbb    %eax,%eax
  ret
```

assistant: ```c
int cmp_name(const char *lname, const char *dname, int nlen) {
  int i;
  for (i = 0; i < nlen; i++) {
    if (lname[i] == '/' || lname[i] == 0) {
      if (dname[i] == 0)
        return 0;
      return -1;
    }
    if (lname[i] != dname[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_name>:
  endbr64
  test   %edx,%edx
  jle    L18
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L53
  nop
L35:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L18
L53:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%r8d
  cmp    $0x2f,%cl
  je     L21
  test   %cl,%cl
  je     L21
  cmp    %r8b,%cl
  je     L35
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  neg    %r8b
  sbb    %eax,%eax
  ret
```

assistant: ```c
int cmp_name(const char *lname, const char *dname, int nlen) {
  int i;
  for (i = 0; i < nlen; i++) {
    if (lname[i] == '/' || lname[i] == 0) {
      if (dname[i] == 0)
        return 0;
      return -1;
    }
    if (lname[i] != dname[i])
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x250,%rsp
  mov    %edi,-0x234(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x240(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x240(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x224(%rbp)
  mov    -0x224(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x220(%rbp)
  mov    -0x220(%rbp),%rdx
  mov    -0x224(%rbp),%esi
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <read_data_double@plt>
  movl   $0x0,-0x228(%rbp)
  jmp    L16
L29:
  mov    -0x228(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x220(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,-0x248(%rbp)
  fldl   -0x248(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <zscore2pvalue@plt>
  add    $0x10,%rsp
  mov    %eax,%edi
  call   <log10@plt>
  neg    %rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x218(%rbp)
  mov    -0x218(%rbp),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x228(%rbp)
L16:
  mov    -0x228(%rbp),%eax
  cmp    -0x224(%rbp),%eax
  jl     L29
  mov    -0x220(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %G


assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  int N, i;
  double *data;
  double pvalue;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  data = (double *)malloc(N * sizeof(double));
  read_data_double(input_file, N, 1, data);
  for (i = 0; i < N; i++) {
    pvalue = (double)(-log10(zscore2pvalue((long double)data[i])));
    printf("%G\n", pvalue);
  }
  free(data);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rsi
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %rax,%rbp
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <read_data_double@plt>
  test   %ebp,%ebp
  jle    L11
  mov    %r13,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r13,%rax,8),%r12
  lea    D5(%rip),%rbp
L9:
  fldl   (%rbx)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <zscore2pvalue@plt>
  mov    %eax,%edi
  call   <log10@plt>
  neg    %rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  add    $0x10,%rsp
  cmp    %r12,%rbx
  jne    L9
L11:
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %G


assistant: ```c
int main(int argc, char *argv[]) {
  char input_file[512];
  int N, i;
  double *data;
  double pvalue;
  strcpy(input_file, argv[1]);
  N = (int)atoi(argv[2]);
  data = (double *)malloc(N * sizeof(double));
  read_data_double(input_file, N, 1, data);
  for (i = 0; i < N; i++) {
    pvalue = (double)(-log10(zscore2pvalue((long double)data[i])));
    printf("%G\n", pvalue);
  }
  free(data);
  return 0;
}
```