ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_palindrome_long>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  lea    D3(%rip),%rsi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <is_palindrome_str@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: %lu

assistant: ```c
size_t is_palindrome_long(long candidate) {
  char buffer[6 + 1];
  int str_length = sprintf(buffer, "%lu", candidate);
  return is_palindrome_str(buffer, str_length);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitcount2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L4:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x14(%rbp)
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitcount2(unsigned int x) {
  int b;
  for (b = 0; x; b++) {
    x &= x - 1;
  }
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitcount2>:
  endbr64
  test   %edi,%edi
  je     L11
  mov    $0x0,%edx
L14:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jne    L14
L15:
  mov    %edx,%eax
  ret
L11:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int bitcount2(unsigned int x) {
  int b;
  for (b = 0; x; b++) {
    x &= x - 1;
  }
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitcount2>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L14
  nopl   0x0(%rax,%rax,1)
L15:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L15
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount2(unsigned int x) {
  int b;
  for (b = 0; x; b++) {
    x &= x - 1;
  }
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitcount2>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L18
  nopl   0x0(%rax,%rax,1)
L13:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L13
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount2(unsigned int x) {
  int b;
  for (b = 0; x; b++) {
    x &= x - 1;
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_is_alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L2
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
L2:
  mov    $0x0,%eax
  jmp    L62
L41:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L54
  mov    $0x0,%eax
  jmp    L62
L54:
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L62:
  leave
  ret
```

assistant: ```c
int str_is_alpha(const char *s) {
  int i, len;
  if (!s || !*s) {
    return 0;
  }
  len = strlen((char *)s);
  for (i = 0; i < len; i++) {
    if (!isalpha((int)s[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_is_alpha>:
  endbr64
  test   %rdi,%rdi
  je     L25
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  jne    L13
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rbp
L33:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L23
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L33
  mov    $0x1,%eax
  jmp    L23
L25:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  jmp    L23
```

assistant: ```c
int str_is_alpha(const char *s) {
  int i, len;
  if (!s || !*s) {
    return 0;
  }
  len = strlen((char *)s);
  for (i = 0; i < len; i++) {
    if (!isalpha((int)s[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<str_is_alpha>:
  endbr64
  test   %rdi,%rdi
  je     L15
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L33
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  call   <strlen@plt>
  test   %eax,%eax
  jle    L20
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L20
L60:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L12
  jmp    L9
  nop
L20:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_is_alpha(const char *s) {
  int i, len;
  if (!s || !*s) {
    return 0;
  }
  len = strlen((char *)s);
  for (i = 0; i < len; i++) {
    if (!isalpha((int)s[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str_is_alpha>:
  endbr64
  test   %rdi,%rdi
  je     L34
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L61
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L61:
  call   <strlen@plt>
  test   %eax,%eax
  jle    L65
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L65
L62:
  movsbl (%rbx),%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L12
  jmp    L4
  nop
L65:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_is_alpha(const char *s) {
  int i, len;
  if (!s || !*s) {
    return 0;
  }
  len = strlen((char *)s);
  for (i = 0; i < len; i++) {
    if (!isalpha((int)s[i])) {
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x20100,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <b@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%edx
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  char c[4] = {0, 1, 2, 0};
  b(c);
  return c[0] + c[3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x20100,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <b@plt>
  movsbl 0x4(%rsp),%eax
  movsbl 0x7(%rsp),%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char c[4] = {0, 1, 2, 0};
  b(c);
  return c[0] + c[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x20100,0x4(%rsp)
  call   <b@plt>
  movsbl 0x4(%rsp),%eax
  movsbl 0x7(%rsp),%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char c[4] = {0, 1, 2, 0};
  b(c);
  return c[0] + c[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x20100,0x4(%rsp)
  call   <b@plt>
  movsbl 0x4(%rsp),%eax
  movsbl 0x7(%rsp),%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char c[4] = {0, 1, 2, 0};
  b(c);
  return c[0] + c[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<input_prime_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
L47:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L33
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L17
L33:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,-0x1c(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L49
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L1
L49:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L47
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string

tool: D16: input prime number: 

tool: D8: %d

assistant: ```c
int input_prime_number(int *prime_number, int range) {
  int value;
  do {
    printf("input prime number: ");
    scanf("%d", prime_number);
    value = (*prime_number);
    while ((*prime_number) != range && (*prime_number) != 0) {
      if ((*prime_number) > range) {
        (*prime_number) -= range;
      } else {
        range -= (*prime_number);
      }
    }
  } while ((*prime_number) != 1);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<input_prime_number>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D9(%rip),%r13
  lea    D13(%rip),%r12
  jmp    L14
L23:
  sub    %eax,%ebx
L87:
  mov    0x0(%rbp),%eax
  test   %eax,%eax
  je     L89
  cmp    %ebx,%eax
  je     L89
L55:
  cmp    %ebx,%eax
  jle    L23
  sub    %ebx,%eax
  mov    %eax,0x0(%rbp)
  jmp    L87
L73:
  mov    %edx,%eax
L89:
  cmp    $0x1,%eax
  je     L70
L14:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  je     L73
  cmp    %edx,%ebx
  je     L73
  mov    %edx,%eax
  jmp    L55
L70:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D13
type_guessed: string

tool: D9: input prime number: 

tool: D13: %d

assistant: ```c
int input_prime_number(int *prime_number, int range) {
  int value;
  do {
    printf("input prime number: ");
    scanf("%d", prime_number);
    value = (*prime_number);
    while ((*prime_number) != range && (*prime_number) != 0) {
      if ((*prime_number) > range) {
        (*prime_number) -= range;
      } else {
        range -= (*prime_number);
      }
    }
  } while ((*prime_number) != 1);
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<input_prime_number>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L74:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ebx
  jne    L40
  jmp    L60
  nopl   0x0(%rax)
L2:
  sub    %ebx,%eax
  mov    %eax,0x0(%rbp)
  cmp    %eax,%ebx
  je     L60
L40:
  test   %eax,%eax
  je     L74
  cmp    %eax,%ebx
  jl     L2
  sub    %eax,%ebx
  mov    0x0(%rbp),%eax
  cmp    %eax,%ebx
  jne    L40
L60:
  cmp    $0x1,%eax
  je     L31
  mov    %eax,%ebx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D13: input prime number: 

tool: D6: %d

assistant: ```c
int input_prime_number(int *prime_number, int range) {
  int value;
  do {
    printf("input prime number: ");
    scanf("%d", prime_number);
    value = (*prime_number);
    while ((*prime_number) != range && (*prime_number) != 0) {
      if ((*prime_number) > range) {
        (*prime_number) -= range;
      } else {
        range -= (*prime_number);
      }
    }
  } while ((*prime_number) != 1);
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<input_prime_number>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L71:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ebx
  je     L62
  nopw   0x0(%rax,%rax,1)
L56:
  test   %eax,%eax
  je     L71
  cmp    %eax,%ebx
  jge    L60
  sub    %ebx,%eax
  mov    %eax,0x0(%rbp)
  cmp    %ebx,%eax
  jne    L56
L62:
  cmp    $0x1,%ebx
  jne    L71
L59:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L60:
  sub    %eax,%ebx
  cmp    %eax,%ebx
  jne    L56
  cmp    $0x1,%ebx
  jne    L71
  jmp    L59
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D8: input prime number: 

tool: D10: %d

assistant: ```c
int input_prime_number(int *prime_number, int range) {
  int value;
  do {
    printf("input prime number: ");
    scanf("%d", prime_number);
    value = (*prime_number);
    while ((*prime_number) != range && (*prime_number) != 0) {
      if ((*prime_number) > range) {
        (*prime_number) -= range;
      } else {
        range -= (*prime_number);
      }
    }
  } while ((*prime_number) != 1);
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L26:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *retval = NULL;
  const char *cur;
  for (cur = s; *cur; cur++)
    if (*cur == c)
      retval = (char *)cur;
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  mov    $0x0,%edx
L21:
  movsbl %al,%eax
  cmp    %esi,%eax
  cmove  %rdi,%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L21
L12:
  mov    %rdx,%rax
  ret
L19:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *retval = NULL;
  const char *cur;
  for (cur = s; *cur; cur++)
    if (*cur == c)
      retval = (char *)cur;
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<strrchr>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L2
  xchg   %ax,%ax
L16:
  cmp    %esi,%eax
  cmove  %rdi,%r8
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L16
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *retval = NULL;
  const char *cur;
  for (cur = s; *cur; cur++)
    if (*cur == c)
      retval = (char *)cur;
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strrchr>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L8
  xchg   %ax,%ax
L5:
  cmp    %eax,%esi
  cmove  %rdi,%r8
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L5
L8:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  char *retval = NULL;
  const char *cur;
  for (cur = s; *cur; cur++)
    if (*cur == c)
      retval = (char *)cur;
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__finitef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7f800000,%eax
  cmp    $0x7f800000,%eax
  setne  %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int __finitef(float x) {
  union {
    u_int32_t lval;
    float fval;
  } z;
  z.fval = x;
  return ((z.lval & 0x7f800000) != 0x7f800000);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__finitef>:
  endbr64
  movd   %xmm0,%eax
  and    $0x7f800000,%eax
  cmp    $0x7f800000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __finitef(float x) {
  union {
    u_int32_t lval;
    float fval;
  } z;
  z.fval = x;
  return ((z.lval & 0x7f800000) != 0x7f800000);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__finitef>:
  endbr64
  movd   %xmm0,-0x4(%rsp)
  mov    $0x7f800000,%eax
  and    -0x4(%rsp),%eax
  cmp    $0x7f800000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __finitef(float x) {
  union {
    u_int32_t lval;
    float fval;
  } z;
  z.fval = x;
  return ((z.lval & 0x7f800000) != 0x7f800000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__finitef>:
  endbr64
  movd   %xmm0,-0x4(%rsp)
  mov    $0x7f800000,%eax
  and    -0x4(%rsp),%eax
  cmp    $0x7f800000,%eax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __finitef(float x) {
  union {
    u_int32_t lval;
    float fval;
  } z;
  z.fval = x;
  return ((z.lval & 0x7f800000) != 0x7f800000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L1:
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x2,-0xc(%rbp)
  jle    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D12: float64_get_high_word

tool: D0: # c::native::%s


tool: D25: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_get_high_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
  lea    D18(%rip),%r12
  lea    D26(%rip),%rbp
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: string
name: retrieve_data
arguments: tag: D18
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string

tool: D8: float64_get_high_word

tool: D18: # c::native::%s


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_get_high_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D7(%rip),%r13
  push   %r12
  lea    D29(%rip),%r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string

tool: D7: float64_get_high_word

tool: D29: # c::native::%s


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "float64_get_high_word");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```