ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bufferLineToDouble>:
  endbr64
  movzbl (%rdi),%r8d
  cmp    $0x31,%r8b
  je     L111
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0xa,%r8b
  je     L17
  test   %r8b,%r8b
  je     L17
  lea    0x1(%rdi),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L94:
  movzbl (%rdx),%ecx
  movslq %eax,%rsi
  add    $0x1,%rdx
  add    $0x1,%eax
  cmp    $0xa,%cl
  je     L100
  test   %cl,%cl
  jne    L94
L100:
  cmp    $0x30,%r8b
  jne    L53
  cmp    $0x1,%eax
  je     L80
L53:
  lea    -0x1(%rsi),%r13d
  cmp    $0x1,%esi
  jle    L13
  lea    (%rdi,%rsi,1),%rbp
  xor    %r14d,%r14d
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L77:
  movsbl 0x0(%rbp),%edi
  sub    $0x1,%rbp
  call   <charToInt@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  mov    %eax,%r12d
  call   <fastPower10@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14d,%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%r14d
  cmp    %r13d,%ebx
  jne    L77
  pxor   %xmm1,%xmm1
  cvtsi2sd %r14d,%xmm1
L65:
  mov    %r13d,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <fastPower10@plt>
  movsd  0x8(%rsp),%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
L103:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L111:
  movsd  D8(%rip),%xmm0
  ret
L80:
  pxor   %xmm0,%xmm0
  jmp    L103
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0xfffffffe,%r13d
  pxor   %xmm1,%xmm1
  jmp    L65
L13:
  pxor   %xmm1,%xmm1
  jmp    L65
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: f64

tool: D8: 1

assistant: ```c
double bufferLineToDouble(const char *buffer) {
  if (buffer[0] == '1')
    return 1.0;
  int len, p, value;
  len = p = value = 0;
  while (buffer[len] != '\n' && buffer[len] != '\0') {
    len++;
  }
  if (len == 1 && buffer[0] == '0')
    return 0.0;
  for (int i = len - 1; i >= 2; i--) {
    value += charToInt(buffer[i]) * fastPower10(p);
    p++;
  }
  double valueDouble = (double)value / fastPower10(len - 2);
  return valueDouble;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Decomment>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r10
  movzbl (%rdi),%eax
  test   %al,%al
  je     L163
  mov    $0x0,%esi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x0,%edi
  mov    $0x0,%r11d
  jmp    L88
L51:
  movzbl 0x1(%r9,%rdi,1),%edi
  test   %esi,%esi
  sete   %r8b
  cmp    $0x2f,%dil
  jne    L130
  test   %r8b,%r8b
  jne    L160
L130:
  cmp    $0x2a,%dil
  jne    L80
  test   %r8b,%r8b
  je     L80
  add    $0x4,%ecx
  movslq %ecx,%rax
  jmp    L153
L160:
  movslq %ecx,%rax
  cmpb   $0xa,(%r9,%rax,1)
  je     L183
  add    $0x1,%ecx
  movslq %ecx,%rax
L201:
  mov    %eax,%ecx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%r9,%rax,1)
  jne    L201
L183:
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  mov    %edx,%r8d
  mov    $0x0,%esi
  jmp    L82
L81:
  add    $0x1,%rax
L153:
  mov    %eax,%ecx
  cmpb   $0x2a,-0x2(%r9,%rax,1)
  jne    L81
  cmpb   $0x2f,-0x1(%r9,%rax,1)
  jne    L81
  mov    %edx,%r8d
  mov    $0x0,%esi
  jmp    L142
L124:
  cmp    $0x22,%al
  jne    L80
  test   %esi,%esi
  je     L166
  cmp    $0x4,%esi
  cmove  %r11d,%esi
L80:
  add    $0x1,%ecx
  lea    0x1(%rdx),%r8d
  movslq %edx,%rdx
  mov    %al,(%r10,%rdx,1)
L142:
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L76
L82:
  mov    %r8d,%edx
L88:
  cmp    $0x2f,%al
  je     L51
  cmp    $0x27,%al
  jne    L124
  test   %esi,%esi
  je     L106
  cmp    $0x3,%esi
  cmove  %r11d,%esi
  jmp    L80
L166:
  mov    $0x4,%esi
  jmp    L80
L163:
  mov    $0x0,%r8d
L76:
  movslq %r8d,%r8
  movb   $0x0,(%r10,%r8,1)
  ret
L106:
  mov    $0x3,%esi
  jmp    L80
```

assistant: ```c
void Decomment(char s[], char d[]) {
  int i, j, state;
  i = j = 0;
  state = 0;
  while (s[i] != '\0') {
    if (s[i] == '/' && s[i + 1] == '/' && state == 0) {
      for (; s[i] != '\n'; i++) {
      }
      continue;
    }
    if (s[i] == '/' && s[i + 1] == '*' && state == 0) {
      for (i += 4; s[i - 2] != '*' || s[i - 1] != '/'; i++) {
      }
      continue;
    }
    if (s[i] == '\'') {
      if (state == 0) {
        state = 3;
      } else if (state == 3) {
        state = 0;
      }
    }
    if (s[i] == '"') {
      if (state == 0) {
        state = 4;
      } else if (state == 4) {
        state = 0;
      }
    }
    d[j++] = s[i++];
  }
  d[j] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Decomment>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L210
  xor    %r10d,%r10d
  xor    %edx,%edx
  xor    %edi,%edi
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  jmp    L209
L138:
  cmp    $0x27,%al
  je     L67
  cmp    $0x22,%al
  jne    L45
  test   %r10d,%r10d
  jne    L145
  mov    $0x4,%r10d
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%edi
  mov    %al,(%rsi,%rdx,1)
  lea    0x1(%rdx),%r9d
  movslq %edi,%rcx
  movzbl (%r8,%rcx,1),%eax
  test   %al,%al
  je     L36
L169:
  movslq %r9d,%rdx
L209:
  cmp    $0x2f,%al
  jne    L138
  movzbl 0x1(%r8,%rcx,1),%ecx
  cmp    $0x2f,%cl
  jne    L44
  test   %r10d,%r10d
  je     L196
L44:
  cmp    $0x2a,%cl
  jne    L45
  test   %r10d,%r10d
  jne    L45
  add    $0x4,%edi
  movslq %edi,%rcx
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rcx
L32:
  cmpb   $0x2a,-0x2(%r8,%rcx,1)
  mov    %ecx,%edi
  jne    L38
  cmpb   $0x2f,-0x1(%r8,%rcx,1)
  jne    L38
  movzbl (%r8,%rcx,1),%eax
  mov    %edx,%r9d
  test   %al,%al
  jne    L169
  nopw   0x0(%rax,%rax,1)
L36:
  movslq %r9d,%r9
  add    %r9,%rsi
L210:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  test   %r10d,%r10d
  jne    L171
  mov    $0x3,%r10d
  jmp    L45
L171:
  cmp    $0x3,%r10d
  cmove  %r11d,%r10d
  jmp    L45
  nopl   (%rax)
L145:
  cmp    $0x4,%r10d
  cmove  %r11d,%r10d
  jmp    L45
  nopl   (%rax)
L196:
  movslq %edi,%rcx
  cmpb   $0xa,(%r8,%rcx,1)
  je     L52
  add    $0x1,%edi
  movslq %edi,%rax
L89:
  mov    %eax,%edi
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%r8,%rax,1)
  jne    L89
L52:
  mov    %edx,%r9d
  mov    $0xa,%eax
  xor    %r10d,%r10d
  jmp    L169
```

assistant: ```c
void Decomment(char s[], char d[]) {
  int i, j, state;
  i = j = 0;
  state = 0;
  while (s[i] != '\0') {
    if (s[i] == '/' && s[i + 1] == '/' && state == 0) {
      for (; s[i] != '\n'; i++) {
      }
      continue;
    }
    if (s[i] == '/' && s[i + 1] == '*' && state == 0) {
      for (i += 4; s[i - 2] != '*' || s[i - 1] != '/'; i++) {
      }
      continue;
    }
    if (s[i] == '\'') {
      if (state == 0) {
        state = 3;
      } else if (state == 3) {
        state = 0;
      }
    }
    if (s[i] == '"') {
      if (state == 0) {
        state = 4;
      } else if (state == 4) {
        state = 0;
      }
    }
    d[j++] = s[i++];
  }
  d[j] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Decomment>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  test   %al,%al
  je     L205
  xor    %r10d,%r10d
  xor    %edx,%edx
  xor    %edi,%edi
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  jmp    L60
L81:
  cmp    $0x27,%al
  je     L135
  cmp    $0x22,%al
  jne    L43
  test   %r10d,%r10d
  jne    L91
  mov    $0x4,%r10d
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%edi
  mov    %al,(%rsi,%rdx,1)
  lea    0x1(%rdx),%r9d
  movslq %edi,%rcx
  movzbl (%r8,%rcx,1),%eax
  test   %al,%al
  je     L179
L203:
  movslq %r9d,%rdx
L60:
  cmp    $0x2f,%al
  jne    L81
  movzbl 0x1(%r8,%rcx,1),%ecx
  cmp    $0x2f,%cl
  jne    L89
  test   %r10d,%r10d
  je     L159
L89:
  cmp    $0x2a,%cl
  jne    L43
  test   %r10d,%r10d
  jne    L43
  add    $0x4,%edi
  movslq %edi,%rcx
  jmp    L100
  nopl   0x0(%rax,%rax,1)
L129:
  add    $0x1,%rcx
L100:
  cmpb   $0x2a,-0x2(%r8,%rcx,1)
  mov    %ecx,%edi
  jne    L129
  cmpb   $0x2f,-0x1(%r8,%rcx,1)
  jne    L129
  movzbl (%r8,%rcx,1),%eax
  mov    %edx,%r9d
  test   %al,%al
  jne    L203
  nopw   0x0(%rax,%rax,1)
L179:
  movslq %r9d,%r9
  add    %r9,%rsi
L205:
  movb   $0x0,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L135:
  test   %r10d,%r10d
  jne    L195
  mov    $0x3,%r10d
  jmp    L43
L195:
  cmp    $0x3,%r10d
  cmove  %r11d,%r10d
  jmp    L43
  nopl   (%rax)
L91:
  cmp    $0x4,%r10d
  cmove  %r11d,%r10d
  jmp    L43
  nopl   (%rax)
L159:
  movslq %edi,%rcx
  cmpb   $0xa,(%r8,%rcx,1)
  je     L39
  add    $0x1,%edi
  movslq %edi,%rax
L79:
  mov    %eax,%edi
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%r8,%rax,1)
  jne    L79
L39:
  mov    %edx,%r9d
  mov    $0xa,%eax
  xor    %r10d,%r10d
  jmp    L203
```

assistant: ```c
void Decomment(char s[], char d[]) {
  int i, j, state;
  i = j = 0;
  state = 0;
  while (s[i] != '\0') {
    if (s[i] == '/' && s[i + 1] == '/' && state == 0) {
      for (; s[i] != '\n'; i++) {
      }
      continue;
    }
    if (s[i] == '/' && s[i + 1] == '*' && state == 0) {
      for (i += 4; s[i - 2] != '*' || s[i - 1] != '/'; i++) {
      }
      continue;
    }
    if (s[i] == '\'') {
      if (state == 0) {
        state = 3;
      } else if (state == 3) {
        state = 0;
      }
    }
    if (s[i] == '"') {
      if (state == 0) {
        state = 4;
      } else if (state == 4) {
        state = 0;
      }
    }
    d[j++] = s[i++];
  }
  d[j] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  long double a;
  typedef long double my_long_double;
  my_long_double d;
  long double e;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  long double a;
  typedef long double my_long_double;
  my_long_double d;
  long double e;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  long double a;
  typedef long double my_long_double;
  my_long_double d;
  long double e;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  long double a;
  typedef long double my_long_double;
  my_long_double d;
  long double e;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scorearray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L2:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <scoreletter@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int scorearray(char *input) {
  int score = 0;
  int i = 0;
  while (input[i] != '\0')
    score += scoreletter(input[i++]);
  return score;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<scorearray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  lea    0x1(%rdi),%rbx
  mov    $0x0,%ebp
L6:
  movsbl %al,%edi
  call   <scoreletter@plt>
  add    %eax,%ebp
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L6
L27:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    $0x0,%ebp
  jmp    L27
```

assistant: ```c
int scorearray(char *input) {
  int score = 0;
  int i = 0;
  while (input[i] != '\0')
    score += scoreletter(input[i++]);
  return score;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scorearray>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  lea    0x1(%rdi),%rbx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L18:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <scoreletter@plt>
  add    %eax,%r12d
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L18
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int scorearray(char *input) {
  int score = 0;
  int i = 0;
  while (input[i] != '\0')
    score += scoreletter(input[i++]);
  return score;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scorearray>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  lea    0x1(%rdi),%rbx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L9:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <scoreletter@plt>
  add    %eax,%r12d
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L9
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int scorearray(char *input) {
  int score = 0;
  int i = 0;
  while (input[i] != '\0')
    score += scoreletter(input[i++]);
  return score;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x64,%edi
  call   <generateRandomNumber@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D15
type: string

tool: D12: Random number in [1,100]

tool: D15: %d


assistant: ```c
int main() {
  int c, n;
  printf("Random number in [1,100]\n");
  printf("%d\n", generateRandomNumber(100));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%edi
  call   <generateRandomNumber@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string

tool: D4: Random number in [1,100]

tool: D19: %d


assistant: ```c
int main() {
  int c, n;
  printf("Random number in [1,100]\n");
  printf("%d\n", generateRandomNumber(100));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%edi
  call   <generateRandomNumber@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D11
type: string

tool: D17: Random number in [1,100]

tool: D11: %d


assistant: ```c
int main() {
  int c, n;
  printf("Random number in [1,100]\n");
  printf("%d\n", generateRandomNumber(100));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%edi
  call   <generateRandomNumber@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D2
data_type: string

tool: D0: Random number in [1,100]

tool: D2: %d


assistant: ```c
int main() {
  int c, n;
  printf("Random number in [1,100]\n");
  printf("%d\n", generateRandomNumber(100));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_lineno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x18(%rbp)
  mov    D8(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D36(%rip)
  mov    %eax,%edx
  mov    -0x18(%rbp),%esi
  lea    -0x13(%rbp),%rax
  mov    %edx,%ecx
  lea    D36(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  cmp    %eax,-0x18(%rbp)
  jg     L1
  mov    -0x18(%rbp),%eax
  cltq
  movb   $0x0,-0x13(%rbp,%rax,1)
L1:
  lea    -0x13(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  test   %rax,%rax
  je     L14
  mov    $0x0,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <sh_error@plt>
L14:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D36
type_guessed: string
name: extract_symbolic_data
arguments: label: D29
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string

tool: D36: %u

tool: D29: LINENO

tool: D28: setenv

assistant: ```c
void _lineno(void) {
  static unsigned int i = 1;
  char lineno[11];
  const int len = sizeof(lineno) - 1;
  if (snprintf(lineno, len, "%u", i++) >= len)
    lineno[len] = '\0';
  if (setenv("LINENO", lineno, 1) != 0)
    sh_error("setenv", 0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_lineno>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D43(%rip),%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,D6(%rip)
  lea    0xd(%rsp),%rdi
  lea    D6(%rip),%rdx
  mov    $0xa,%esi
  call   <snprintf@plt>
  cmp    $0x9,%eax
  jle    L27
  movb   $0x0,0x17(%rsp)
L27:
  lea    0xd(%rsp),%rsi
  mov    $0x1,%edx
  lea    D5(%rip),%rdi
  call   <setenv@plt>
  test   %rax,%rax
  jne    L23
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  ret
L23:
  mov    $0x0,%esi
  lea    D11(%rip),%rdi
  call   <sh_error@plt>
  jmp    L22
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D6: %u

tool: D5: LINENO

tool: D11: setenv

assistant: ```c
void _lineno(void) {
  static unsigned int i = 1;
  char lineno[11];
  const int len = sizeof(lineno) - 1;
  if (snprintf(lineno, len, "%u", i++) >= len)
    lineno[len] = '\0';
  if (setenv("LINENO", lineno, 1) != 0)
    sh_error("setenv", 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_lineno>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdx
  mov    $0xa,%esi
  sub    $0x20,%rsp
  mov    D20(%rip),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbp
  lea    0x1(%rcx),%eax
  mov    %rbp,%rdi
  mov    %eax,D25(%rip)
  call   <snprintf@plt>
  cmp    $0x9,%eax
  jle    L17
  movb   $0x0,0x17(%rsp)
L17:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  lea    D25(%rip),%rdi
  call   <setenv@plt>
  test   %rax,%rax
  jne    L6
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  call   <sh_error@plt>
  jmp    L7
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D25
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D34: %u

tool: D25: LINENO

tool: D11: setenv

assistant: ```c
void _lineno(void) {
  static unsigned int i = 1;
  char lineno[11];
  const int len = sizeof(lineno) - 1;
  if (snprintf(lineno, len, "%u", i++) >= len)
    lineno[len] = '\0';
  if (setenv("LINENO", lineno, 1) != 0)
    sh_error("setenv", 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_lineno>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdx
  mov    $0xa,%esi
  sub    $0x20,%rsp
  mov    D6(%rip),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbp
  lea    0x1(%rcx),%eax
  mov    %rbp,%rdi
  mov    %eax,D46(%rip)
  call   <snprintf@plt>
  cmp    $0x9,%eax
  jle    L26
  movb   $0x0,0x17(%rsp)
L26:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  lea    D46(%rip),%rdi
  call   <setenv@plt>
  test   %rax,%rax
  jne    L39
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %esi,%esi
  lea    D36(%rip),%rdi
  call   <sh_error@plt>
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D46
type: string
name: read_data
arguments: tag: D36
type: string

tool: D21: %u

tool: D46: LINENO

tool: D36: setenv

assistant: ```c
void _lineno(void) {
  static unsigned int i = 1;
  char lineno[11];
  const int len = sizeof(lineno) - 1;
  if (snprintf(lineno, len, "%u", i++) >= len)
    lineno[len] = '\0';
  if (setenv("LINENO", lineno, 1) != 0)
    sh_error("setenv", 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_support>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L4:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D23
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string
name: retrieve_data
arguments: data_label: D10
data_type: string

tool: D23: [ YES |    ]

tool: D7: [     | NO ]

tool: D10: 	%-60s	%s


assistant: ```c
void print_support(uint64_t supported, char *feature, char *feature_type) {
  if (supported) {
    printf("[ YES |    ]");
  } else {
    printf("[     | NO ]");
  }
  printf("\t%-60s\t%s\n", feature, feature_type);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_support>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L0
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D23
type_infered: string

tool: D16: [ YES |    ]

tool: D4: 	%-60s	%s


tool: D23: [     | NO ]

assistant: ```c
void print_support(uint64_t supported, char *feature, char *feature_type) {
  if (supported) {
    printf("[ YES |    ]");
  } else {
    printf("[     | NO ]");
  }
  printf("\t%-60s\t%s\n", feature, feature_type);
}
```