ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc34(%rbp)
  lea    -0xbc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L18
L15:
  mov    -0xc34(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc34(%rbp),%eax
  cltq
  movzbl -0xbc0(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  addl   $0x1,-0xc34(%rbp)
L18:
  mov    -0xc34(%rbp),%eax
  cltq
  movzbl -0xbc0(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D16: %[^
]s

tool: D19: %d

assistant: ```c
int main() {
  char sentence[3000];
  int counter = 0;
  int alphabet[26];
  scanf("%[^\n]s", sentence);
  while (sentence[counter] != '\0') {
    printf("%d", counter);
    if (sentence[counter] >= 'a' && sentence[counter] <= 'z') {
    }
    counter++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xbc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L20
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
L28:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rsp,%rbx,1)
  jne    L28
L20:
  mov    0xbb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0xbc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string

tool: D6: %[^
]s

tool: D17: %d

assistant: ```c
int main() {
  char sentence[3000];
  int counter = 0;
  int alphabet[26];
  scanf("%[^\n]s", sentence);
  while (sentence[counter] != '\0') {
    printf("%d", counter);
    if (sentence[counter] >= 'a' && sentence[counter] <= 'z') {
    }
    counter++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xbc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L0
  xor    %ebx,%ebx
  lea    D7(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L2
L0:
  mov    0xbb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0xbc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D6: %[^
]s

tool: D7: %d

assistant: ```c
int main() {
  char sentence[3000];
  int counter = 0;
  int alphabet[26];
  scanf("%[^\n]s", sentence);
  while (sentence[counter] != '\0') {
    printf("%d", counter);
    if (sentence[counter] >= 'a' && sentence[counter] <= 'z') {
    }
    counter++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xbc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L0
  xor    %ebx,%ebx
  lea    D4(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmpb   $0x0,0x0(%rbp,%rbx,1)
  jne    L15
L0:
  mov    0xbb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xbc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string

tool: D7: %[^
]s

tool: D4: %d

assistant: ```c
int main() {
  char sentence[3000];
  int counter = 0;
  int alphabet[26];
  scanf("%[^\n]s", sentence);
  while (sentence[counter] != '\0') {
    printf("%d", counter);
    if (sentence[counter] >= 'a' && sentence[counter] <= 'z') {
    }
    counter++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<side_ripples>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %esi,0x1c(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x1a1d232b23262b31,%rax
  movabs $0x710192310151d26,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  lea    0x0(,%rdi,4),%eax
  mov    %eax,0x18(%rsp)
  test   %eax,%eax
  jle    L39
  movl   $0x0,0x14(%rsp)
  jmp    L13
L4:
  mov    0x1c(%rsp),%edi
  call   <delay_ms@plt>
  addl   $0x4,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cmp    0x18(%rsp),%eax
  jge    L39
L13:
  mov    $0x0,%edi
  call   <fill@plt>
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x7,%r15d
  mov    $0x0,%r14d
L44:
  mov    $0x0,%ebp
L51:
  mov    0x8(%rsp),%rax
  movzbl 0x14(%rsp),%edi
  add    (%rax,%rbp,4),%dil
  movzbl %dil,%edi
  call   <totty_sin@plt>
  add    $0xc4,%eax
  movslq %eax,%rbx
  imul   $0x5397829d,%rbx,%rbx
  sar    $0x24,%rbx
  sar    $0x1f,%eax
  sub    %eax,%ebx
  movzbl %bl,%ebx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  mov    %ebp,0x10(%rsp)
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <setvoxel@plt>
  mov    $0x7,%r13d
  sub    %ebp,%r13d
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r15d,%edi
  call   <setvoxel@plt>
  mov    $0x7,%r12d
  sub    %ebx,%r12d
  mov    0x10(%rsp),%ebx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <setvoxel@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <setvoxel@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <setvoxel@plt>
  add    $0x1,%rbp
  cmp    $0x4,%rbp
  jne    L51
  add    $0x1,%r14d
  addq   $0x1,0x8(%rsp)
  sub    $0x1,%r15d
  cmp    $0x4,%r14d
  jne    L44
  jmp    L4
L39:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void side_ripples(int iterations, int delay) {
  unsigned char sqrt_LUT[] = {49, 43, 38, 35, 43, 35, 29, 26, 38, 29, 21, 16, 35, 25, 16, 7};
  unsigned char x, y, height, distance;
  int i;
  for (i = 0; i < iterations * 4; i += 4) {
    fill(0x00);
    for (x = 0; x < 4; x++)
      for (y = 0; y < 4; y++) {
        distance = sqrt_LUT[x + y * 4];
        height = (196 + totty_sin(distance + i)) / 49;
        setvoxel(x, height, y);
        setvoxel(7 - x, height, y);
        setvoxel(x, height, 7 - y);
        setvoxel(7 - x, height, 7 - y);
        setvoxel(x, 7 - height, y);
        setvoxel(7 - x, 7 - height, y);
        setvoxel(x, 7 - height, 7 - y);
        setvoxel(7 - x, 7 - height, 7 - y);
      }
    delay_ms(delay);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply378>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L27
L9:
  movl   $0x0,-0x3c(%rbp)
  jmp    L11
L32:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L11:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L32
  addl   $0x1,-0x40(%rbp)
L27:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L9
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply378(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply378>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L0:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L12:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L12
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  ret
```

assistant: ```c
void multiply378(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply378>:
  endbr64
  test   %edi,%edi
  jle    L26
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L16
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L29
  pop    %rbx
  ret
L26:
  ret
```

assistant: ```c
void multiply378(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<multiply378>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L38
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L62:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L86
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L86
  nopl   0x0(%rax)
L91:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L91
  cmp    -0x24(%rsp),%r11d
  je     L8
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L8:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L62
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L86:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L64:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L64
  mov    -0x18(%rsp),%r8
  jmp    L8
```

assistant: ```c
void multiply378(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L38
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jg     L23
L38:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  mov    -0xc(%rbp),%eax
  cmp    $0x31,%eax
  jg     L24
L23:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L25
L24:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D27
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D8
type_guessed: string

tool: D3: Informe um numero inteiro qualquer: 

tool: D27: %d

tool: D9: Sim.


tool: D8: Nao.

assistant: ```c
void main() {
  int num;
  printf("Informe um numero inteiro qualquer: ");
  scanf("%d", &num);
  if (((num % 2 == 0) && (num > 10)) || ((num % 2 != 0) && (num < 50))) {
    printf("Sim.\n");
  } else {
    printf("Nao.");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  and    $0x1,%edx
  cmp    $0xa,%eax
  jle    L33
  test   %edx,%edx
  je     L57
L33:
  cmp    $0x31,%eax
  jg     L49
  test   %edx,%edx
  je     L49
L57:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x18,%rsp
  ret
L49:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L51
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D29
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string

tool: D29: Informe um numero inteiro qualquer: 

tool: D23: %d

tool: D5: Sim.


tool: D30: Nao.

assistant: ```c
void main() {
  int num;
  printf("Informe um numero inteiro qualquer: ");
  scanf("%d", &num);
  if (((num % 2 == 0) && (num > 10)) || ((num % 2 != 0) && (num < 50))) {
    printf("Sim.\n");
  } else {
    printf("Nao.");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D30(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  jne    L42
  cmp    $0xa,%eax
  jle    L5
L21:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L42:
  cmp    $0x31,%eax
  jle    L21
L5:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string
name: extract_symbolic_data
arguments: tag: D21
data_type: string

tool: D30: Informe um numero inteiro qualquer: 

tool: D2: %d

tool: D15: Sim.


tool: D21: Nao.

assistant: ```c
void main() {
  int num;
  printf("Informe um numero inteiro qualquer: ");
  scanf("%d", &num);
  if (((num % 2 == 0) && (num > 10)) || ((num % 2 != 0) && (num < 50))) {
    printf("Sim.\n");
  } else {
    printf("Nao.");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   $0x1,%al
  jne    L9
  cmp    $0xa,%eax
  jle    L48
L22:
  lea    D27(%rip),%rdi
  call   <printf@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  ret
L9:
  cmp    $0x31,%eax
  jle    L22
L48:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D26
datatype: string
name: retrieve_data
arguments: tag: D27
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: D16: Informe um numero inteiro qualquer: 

tool: D26: %d

tool: D27: Sim.


tool: D2: Nao.

assistant: ```c
void main() {
  int num;
  printf("Informe um numero inteiro qualquer: ");
  scanf("%d", &num);
  if (((num % 2 == 0) && (num > 10)) || ((num % 2 != 0) && (num < 50))) {
    printf("Sim.\n");
  } else {
    printf("Nao.");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L5
L41:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L23
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jae    L7
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L55
L7:
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L55
L23:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L55:
  addb   $0x2,-0xa(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L41
  movzbl -0x9(%rbp),%eax
  lea    0x7d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
        } else {
          state[local1] = state[0UL] + state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x45(%rax),%edx
  movzbl 0x1(%rdi),%edi
  test   %dil,%dil
  je     L18
  mov    $0x0,%eax
  mov    $0x0,%r8d
L5:
  lea    (%rdx,%rdx,1),%ecx
  cmp    %dl,%al
  cmovb  %r8d,%ecx
  mov    %ecx,%edx
  add    $0x2,%eax
  cmp    %dil,%al
  jb     L5
L18:
  add    $0x7d,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
        } else {
          state[local1] = state[0UL] + state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  lea    0x45(%rax),%edx
  test   %dil,%dil
  je     L0
  xor    %eax,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    %dl,%al
  lea    (%rdx,%rdx,1),%ecx
  cmovb  %r8d,%ecx
  add    $0x2,%eax
  mov    %ecx,%edx
  cmp    %dil,%al
  jb     L12
L0:
  add    $0x7d,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          state[local1] -= state[0UL];
        } else {
          state[local1] = state[0UL] + state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 255873917UL;
  }
}
```