ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L25
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D17(%rip),%r14
  jmp    L3
L58:
  sub    %edx,%eax
  cmp    %r13d,%eax
  jle    L37
  mov    %eax,%r13d
  mov    $0x2,%r15d
L37:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L38
L3:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebp,%edx
  add    0x10(%rsp),%edx
  mov    %edx,%ebp
  mov    %r12d,%eax
  add    0x14(%rsp),%eax
  mov    %eax,%r12d
  mov    %edx,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L58
  cmp    %r13d,%ecx
  jle    L37
  mov    %ecx,%r13d
  mov    $0x1,%r15d
  jmp    L37
L25:
  mov    $0x0,%r13d
L38:
  mov    %r13d,%edx
  mov    %r15d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D21: %d

tool: D17: %d %d

tool: D10: %d %d


assistant: ```c
int main() {
  int i, n, sum_a, sum_b, a, b, lead, max_lead = 0, winner;
  scanf("%d", &n);
  sum_a = 0;
  sum_b = 0;
  for (i = 0; i < n; i++) {
    scanf("%d %d", &a, &b);
    sum_a += a;
    sum_b += b;
    lead = sum_a - sum_b;
    if (lead > 0) {
      if (lead > max_lead) {
        max_lead = lead;
        winner = 1;
      }
    } else {
      if (-lead > max_lead) {
        max_lead = -lead;
        winner = 2;
      }
    }
  }
  printf("%d %d\n", winner, max_lead);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x8(%rsp)
  test   %eax,%eax
  jle    L29
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    0x24(%rsp),%r14
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r13
  lea    D11(%rip),%rbp
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L74:
  cmp    0x8(%rsp),%eax
  jle    L63
  mov    %eax,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
L63:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jle    L29
L23:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    0x20(%rsp),%ebx
  add    0x24(%rsp),%r12d
  mov    %ebx,%eax
  sub    %r12d,%eax
  test   %eax,%eax
  jg     L74
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    0x8(%rsp),%eax
  jle    L63
  mov    %eax,0x8(%rsp)
  add    $0x1,%r15d
  movl   $0x2,0xc(%rsp)
  cmp    %r15d,0x1c(%rsp)
  jg     L23
  nopl   0x0(%rax)
L29:
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D11
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D24: %d

tool: D11: %d %d

tool: D15: %d %d


assistant: ```c
int main() {
  int i, n, sum_a, sum_b, a, b, lead, max_lead = 0, winner;
  scanf("%d", &n);
  sum_a = 0;
  sum_b = 0;
  for (i = 0; i < n; i++) {
    scanf("%d %d", &a, &b);
    sum_a += a;
    sum_b += b;
    lead = sum_a - sum_b;
    if (lead > 0) {
      if (lead > max_lead) {
        max_lead = lead;
        winner = 1;
      }
    } else {
      if (-lead > max_lead) {
        max_lead = -lead;
        winner = 2;
      }
    }
  }
  printf("%d %d\n", winner, max_lead);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D21(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  movl   $0x0,0x8(%rsp)
  test   %eax,%eax
  jle    L75
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  lea    0x24(%rsp),%r14
  xor    %r15d,%r15d
  lea    0x20(%rsp),%r13
  lea    D10(%rip),%rbp
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    0x8(%rsp),%eax
  jle    L31
  mov    %eax,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
L31:
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jle    L75
L40:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    0x20(%rsp),%ebx
  add    0x24(%rsp),%r12d
  mov    %ebx,%eax
  sub    %r12d,%eax
  test   %eax,%eax
  jg     L21
  mov    %r12d,%eax
  sub    %ebx,%eax
  cmp    0x8(%rsp),%eax
  jle    L31
  mov    %eax,0x8(%rsp)
  add    $0x1,%r15d
  movl   $0x2,0xc(%rsp)
  cmp    %r15d,0x1c(%rsp)
  jg     L40
  nopl   0x0(%rax)
L75:
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D21: %d

tool: D10: %d %d

tool: D8: %d %d


assistant: ```c
int main() {
  int i, n, sum_a, sum_b, a, b, lead, max_lead = 0, winner;
  scanf("%d", &n);
  sum_a = 0;
  sum_b = 0;
  for (i = 0; i < n; i++) {
    scanf("%d %d", &a, &b);
    sum_a += a;
    sum_b += b;
    lead = sum_a - sum_b;
    if (lead > 0) {
      if (lead > max_lead) {
        max_lead = lead;
        winner = 1;
      }
    } else {
      if (-lead > max_lead) {
        max_lead = -lead;
        winner = 2;
      }
    }
  }
  printf("%d %d\n", winner, max_lead);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jle    L17
  cmpl   $0x4,-0x24(%rbp)
  jle    L25
L17:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L15
L25:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x4,-0x24(%rbp)
  jne    L22
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L22
  mov    $0x1,%eax
  jmp    L37
L22:
  mov    $0x0,%eax
L37:
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L31
  mov    $0x0,%eax
  call   <write_math@plt>
L31:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <write_rtti@plt>
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D7: Wrong number of args


tool: D13: rtti_only

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3 || argc > 4) {
    printf("Wrong number of args\n");
    return 1;
  }
  const char *src_file = argv[1];
  const char *dst_file = argv[2];
  int rtti_only = argc == 4 && !strcmp(argv[3], "rtti_only");
  if (!rtti_only)
    write_math();
  write_rtti(src_file, dst_file);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x3(%rdi),%eax
  cmp    $0x1,%eax
  ja     L30
  mov    0x8(%rsi),%rbx
  mov    0x10(%rsi),%rbp
  cmp    $0x4,%edi
  jne    L0
  mov    0x18(%rsi),%rdi
  lea    D18(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L24
L0:
  mov    $0x0,%eax
  call   <write_math@plt>
L24:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <write_rtti@plt>
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_label: D18
type_guessed: string
name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D18: rtti_only

tool: D9: Wrong number of args


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3 || argc > 4) {
    printf("Wrong number of args\n");
    return 1;
  }
  const char *src_file = argv[1];
  const char *dst_file = argv[2];
  int rtti_only = argc == 4 && !strcmp(argv[3], "rtti_only");
  if (!rtti_only)
    write_math();
  write_rtti(src_file, dst_file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    -0x3(%rdi),%eax
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%eax
  ja     L34
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  cmp    $0x4,%edi
  jne    L32
  mov    0x18(%rsi),%rdi
  lea    D11(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L6
L32:
  xor    %eax,%eax
  call   <write_math@plt>
L6:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <write_rtti@plt>
  xor    %eax,%eax
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L34:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: label: D11
type: string
name: read_data
arguments: label: D17
type: string

tool: D11: rtti_only

tool: D17: Wrong number of args


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3 || argc > 4) {
    printf("Wrong number of args\n");
    return 1;
  }
  const char *src_file = argv[1];
  const char *dst_file = argv[2];
  int rtti_only = argc == 4 && !strcmp(argv[3], "rtti_only");
  if (!rtti_only)
    write_math();
  write_rtti(src_file, dst_file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    -0x3(%rdi),%eax
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x1,%eax
  ja     L29
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%r12
  cmp    $0x4,%edi
  jne    L16
  mov    0x18(%rsi),%rdi
  lea    D14(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L24
L16:
  xor    %eax,%eax
  call   <write_math@plt>
L24:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <write_rtti@plt>
  xor    %eax,%eax
L19:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L29:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D14: rtti_only

tool: D3: Wrong number of args


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3 || argc > 4) {
    printf("Wrong number of args\n");
    return 1;
  }
  const char *src_file = argv[1];
  const char *dst_file = argv[2];
  int rtti_only = argc == 4 && !strcmp(argv[3], "rtti_only");
  if (!rtti_only)
    write_math();
  write_rtti(src_file, dst_file);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compress>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdi),%edx
  movslq %edx,%rax
  movsd  (%rsi,%rax,8),%xmm0
  mov    %edi,%eax
  sub    $0x2,%eax
  js     L61
  cltq
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm5
  jmp    L84
L19:
  movslq %edx,%r8
  movsd  %xmm1,(%rcx,%r8,8)
  lea    -0x1(%rdx),%edx
L89:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L61
L84:
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  ucomisd %xmm4,%xmm2
  jp     L19
  ucomisd %xmm5,%xmm2
  jne    L19
  movapd %xmm1,%xmm0
  jmp    L89
L61:
  add    $0x1,%edx
  cmp    %edx,%edi
  jle    L41
  movslq %edx,%rdx
  mov    $0x0,%eax
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm5
  jmp    L59
L105:
  movslq %eax,%rsi
  movsd  %xmm1,(%rcx,%rsi,8)
  lea    0x1(%rax),%eax
L4:
  add    $0x1,%rdx
  cmp    %edx,%edi
  jle    L64
L59:
  movsd  (%rcx,%rdx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm3
  subsd  %xmm2,%xmm3
  subsd  %xmm3,%xmm1
  ucomisd %xmm4,%xmm1
  jp     L105
  ucomisd %xmm5,%xmm1
  je     L4
  jmp    L105
L41:
  mov    $0x0,%eax
L64:
  movslq %eax,%rdx
  movsd  %xmm0,(%rcx,%rdx,8)
  add    $0x1,%eax
  ret
```

assistant: ```c
int compress(elen, e, h)
int elen;
double *e;
double *h;
{
  double Q, q;
  double Qnew;
  int eindex, hindex;
  double bvirt;
  double enow, hnow;
  int top, bottom;
  bottom = elen - 1;
  Q = e[bottom];
  for (eindex = elen - 2; eindex >= 0; eindex--) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = Qnew - Q;
    q = enow - bvirt;
    if (q != 0) {
      h[bottom--] = Qnew;
      Q = q;
    } else {
      Q = Qnew;
    }
  }
  top = 0;
  for (hindex = bottom + 1; hindex < elen; hindex++) {
    hnow = h[hindex];
    Qnew = (double)(hnow + Q);
    bvirt = Qnew - hnow;
    q = Q - bvirt;
    if (q != 0) {
      h[top++] = q;
    }
    Q = Qnew;
  }
  h[top] = Q;
  return top + 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compress>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdi),%edx
  movslq %edx,%rax
  movsd  (%rsi,%rax,8),%xmm0
  mov    %edi,%eax
  sub    $0x2,%eax
  js     L39
  cltq
  pxor   %xmm3,%xmm3
  jmp    L49
  nopl   (%rax)
L24:
  movslq %edx,%r8
  sub    $0x1,%rax
  sub    $0x1,%edx
  movsd  %xmm1,(%rcx,%r8,8)
  test   %eax,%eax
  js     L88
L49:
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm4
  subsd  %xmm4,%xmm2
  ucomisd %xmm3,%xmm2
  movapd %xmm2,%xmm0
  jp     L24
  jne    L24
  sub    $0x1,%rax
  movapd %xmm1,%xmm0
  test   %eax,%eax
  jns    L49
L88:
  add    $0x1,%edx
  cmp    %edx,%edi
  jle    L39
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L92:
  movsd  (%rcx,%rdx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm1
  ucomisd %xmm3,%xmm1
  jp     L50
  je     L85
L50:
  movslq %eax,%rsi
  add    $0x1,%eax
  movsd  %xmm1,(%rcx,%rsi,8)
L85:
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L92
  movslq %eax,%rdx
  add    $0x1,%eax
  lea    (%rcx,%rdx,8),%rcx
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  movsd  %xmm0,(%rcx)
  ret
```

assistant: ```c
int compress(elen, e, h)
int elen;
double *e;
double *h;
{
  double Q, q;
  double Qnew;
  int eindex, hindex;
  double bvirt;
  double enow, hnow;
  int top, bottom;
  bottom = elen - 1;
  Q = e[bottom];
  for (eindex = elen - 2; eindex >= 0; eindex--) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = Qnew - Q;
    q = enow - bvirt;
    if (q != 0) {
      h[bottom--] = Qnew;
      Q = q;
    } else {
      Q = Qnew;
    }
  }
  top = 0;
  for (hindex = bottom + 1; hindex < elen; hindex++) {
    hnow = h[hindex];
    Qnew = (double)(hnow + Q);
    bvirt = Qnew - hnow;
    q = Q - bvirt;
    if (q != 0) {
      h[top++] = q;
    }
    Q = Qnew;
  }
  h[top] = Q;
  return top + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compress>:
  endbr64
  mov    %rdx,%rcx
  lea    -0x1(%rdi),%edx
  movslq %edx,%rax
  movsd  (%rsi,%rax,8),%xmm0
  mov    %edi,%eax
  sub    $0x2,%eax
  js     L80
  cltq
  pxor   %xmm3,%xmm3
  nopl   0x0(%rax,%rax,1)
L38:
  movsd  (%rsi,%rax,8),%xmm2
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm4
  subsd  %xmm4,%xmm2
  ucomisd %xmm3,%xmm2
  movapd %xmm2,%xmm0
  jp     L68
  je     L13
L68:
  lea    -0x1(%rdx),%r8d
  sub    $0x1,%rax
  movslq %edx,%rdx
  movsd  %xmm1,(%rcx,%rdx,8)
  mov    %r8d,%edx
  test   %eax,%eax
  jns    L38
L8:
  add    $0x1,%edx
  cmp    %edx,%edi
  jle    L80
  movslq %edx,%rdx
  xor    %eax,%eax
L71:
  movsd  (%rcx,%rdx,8),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm2,%xmm0
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm4
  subsd  %xmm4,%xmm1
  ucomisd %xmm3,%xmm1
  jp     L50
  je     L48
L50:
  movslq %eax,%rsi
  add    $0x1,%eax
  movsd  %xmm1,(%rcx,%rsi,8)
L48:
  add    $0x1,%rdx
  cmp    %edx,%edi
  jg     L71
  movslq %eax,%rdx
  add    $0x1,%eax
  lea    (%rcx,%rdx,8),%rcx
  movsd  %xmm0,(%rcx)
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  sub    $0x1,%rax
  movapd %xmm1,%xmm0
  test   %eax,%eax
  jns    L38
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L80:
  mov    $0x1,%eax
  movsd  %xmm0,(%rcx)
  ret
```

assistant: ```c
int compress(elen, e, h)
int elen;
double *e;
double *h;
{
  double Q, q;
  double Qnew;
  int eindex, hindex;
  double bvirt;
  double enow, hnow;
  int top, bottom;
  bottom = elen - 1;
  Q = e[bottom];
  for (eindex = elen - 2; eindex >= 0; eindex--) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = Qnew - Q;
    q = enow - bvirt;
    if (q != 0) {
      h[bottom--] = Qnew;
      Q = q;
    } else {
      Q = Qnew;
    }
  }
  top = 0;
  for (hindex = bottom + 1; hindex < elen; hindex++) {
    hnow = h[hindex];
    Qnew = (double)(hnow + Q);
    bvirt = Qnew - hnow;
    q = Q - bvirt;
    if (q != 0) {
      h[top++] = q;
    }
    Q = Qnew;
  }
  h[top] = Q;
  return top + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<array2dNcFree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void array2dNcFree(double **array, int dim1) {
  int i;
  for (i = 0; i < dim1; i++) {
    free(array[i]);
  }
  free(array);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<array2dNcFree>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L0
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L19:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L19
L0:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void array2dNcFree(double **array, int dim1) {
  int i;
  for (i = 0; i < dim1; i++) {
    free(array[i]);
  }
  free(array);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<array2dNcFree>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L18
L7:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void array2dNcFree(double **array, int dim1) {
  int i;
  for (i = 0; i < dim1; i++) {
    free(array[i]);
  }
  free(array);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<array2dNcFree>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L14
L19:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void array2dNcFree(double **array, int dim1) {
  int i;
  for (i = 0; i < dim1; i++) {
    free(array[i]);
  }
  free(array);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L4
  mov    $0x1,%eax
  jmp    L5
L4:
  cmpl   $0x0,-0x8(%rbp)
  je     L15
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <helper>
  add    %eax,%eax
  jmp    L5
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <helper>
  add    %eax,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  add    %ecx,%eax
L5:
  leave
  ret
```

assistant: ```c
int helper(int n, int from_left) {
  if (n == 1)
    return 1;
  if (from_left)
    return 2 * helper(n / 2, 0);
  else
    return 2 * helper(n / 2, 1) - 1 + n % 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<helper>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  je     L11
  push   %rbx
  mov    %edi,%ebx
  test   %esi,%esi
  je     L17
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  mov    $0x0,%esi
  call   <helper>
  add    %eax,%eax
L1:
  pop    %rbx
  ret
L17:
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  mov    $0x1,%esi
  call   <helper>
  mov    %eax,%edx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %eax,%ebx
  and    $0x1,%ebx
  sub    %eax,%ebx
  lea    -0x1(%rbx,%rdx,2),%eax
  jmp    L1
L11:
  ret
```

assistant: ```c
int helper(int n, int from_left) {
  if (n == 1)
    return 1;
  if (from_left)
    return 2 * helper(n / 2, 0);
  else
    return 2 * helper(n / 2, 1) - 1 + n % 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<helper>:
  endbr64
  mov    %esi,%eax
  cmp    $0x1,%edi
  je     L0
  test   %esi,%esi
  je     L33
  mov    $0x2,%esi
  xor    %eax,%eax
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %edi,%edx
  mov    $0x2,%r9d
  mov    $0x1,%esi
  jmp    L11
  nop
L31:
  lea    (%r9,%r9,1),%esi
L57:
  mov    %edi,%edx
  lea    (%rsi,%rsi,1),%r9d
  shr    $0x1f,%edx
  add    %edi,%edx
  sar    %edx
  cmp    $0x1,%edx
  je     L4
L11:
  mov    %edx,%r8d
  mov    %edx,%edi
  shr    $0x1f,%r8d
  shr    $0x1f,%edi
  lea    (%rdx,%r8,1),%ecx
  add    %edx,%edi
  and    $0x1,%ecx
  sar    %edi
  sub    %r8d,%ecx
  sub    $0x1,%ecx
  imul   %esi,%ecx
  add    %ecx,%eax
  cmp    $0x1,%edi
  jne    L31
  add    %r9d,%eax
  ret
  nopl   0x0(%rax)
L4:
  add    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int helper(int n, int from_left) {
  if (n == 1)
    return 1;
  if (from_left)
    return 2 * helper(n / 2, 0);
  else
    return 2 * helper(n / 2, 1) - 1 + n % 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<helper>:
  endbr64
  mov    %esi,%eax
  cmp    $0x1,%edi
  je     L38
  test   %esi,%esi
  je     L28
  mov    $0x2,%esi
  xor    %eax,%eax
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %edi,%edx
  mov    $0x2,%r9d
  mov    $0x1,%esi
  jmp    L25
  nop
L23:
  lea    (%r9,%r9,1),%esi
L49:
  mov    %edi,%edx
  lea    (%rsi,%rsi,1),%r9d
  shr    $0x1f,%edx
  add    %edi,%edx
  sar    %edx
  cmp    $0x1,%edx
  je     L11
L25:
  mov    %edx,%r8d
  mov    %edx,%edi
  shr    $0x1f,%r8d
  shr    $0x1f,%edi
  lea    (%rdx,%r8,1),%ecx
  add    %edx,%edi
  and    $0x1,%ecx
  sar    %edi
  sub    %r8d,%ecx
  sub    $0x1,%ecx
  imul   %esi,%ecx
  add    %ecx,%eax
  cmp    $0x1,%edi
  jne    L23
  add    %r9d,%eax
  ret
  nopl   0x0(%rax)
L11:
  add    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int helper(int n, int from_left) {
  if (n == 1)
    return 1;
  if (from_left)
    return 2 * helper(n / 2, 0);
  else
    return 2 * helper(n / 2, 1) - 1 + n % 2;
}
```