ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<qstrgets>:
  endbr64
  test   %rdx,%rdx
  je     L64
  mov    (%rdx),%rax
  test   %rax,%rax
  je     L74
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L64
  sub    $0x1,%rsi
  je     L93
  lea    (%rax,%rsi,1),%r8
  mov    %rdi,%rsi
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L67:
  cmp    %rax,%r8
  je     L15
L19:
  cmp    $0xd,%cl
  je     L99
  cmp    $0xa,%cl
  je     L30
  mov    %cl,(%rsi)
  add    $0x1,%rsi
L99:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  jne    L67
L15:
  movb   $0x0,(%rsi)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
L74:
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%rax
  movb   $0x0,(%rsi)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
L93:
  mov    %rdi,%rsi
  jmp    L15
```

assistant: ```c
char *qstrgets(char *buf, size_t size, char **offset) {
  if (offset == NULL || *offset == NULL || **offset == '\0')
    return NULL;
  size_t i;
  char *from = *offset;
  char *to = buf;
  for (i = 0; *from != '\0' && i < (size - 1); i++, from++) {
    if (*from == '\r')
      continue;
    if (*from == '\n') {
      from++;
      break;
    }
    *to = *from;
    to++;
  }
  *to = '\0';
  *offset = from;
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qstrgets>:
  endbr64
  test   %rdx,%rdx
  je     L75
  mov    (%rdx),%rax
  test   %rax,%rax
  je     L84
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L75
  sub    $0x1,%rsi
  je     L7
  lea    (%rax,%rsi,1),%r8
  mov    %rdi,%rsi
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    %rax,%r8
  je     L64
L30:
  cmp    $0xd,%cl
  je     L13
  cmp    $0xa,%cl
  je     L42
  mov    %cl,(%rsi)
  add    $0x1,%rsi
L13:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  jne    L20
L64:
  movb   $0x0,(%rsi)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
L84:
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%rax
  movb   $0x0,(%rsi)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
L7:
  mov    %rdi,%rsi
  jmp    L64
```

assistant: ```c
char *qstrgets(char *buf, size_t size, char **offset) {
  if (offset == NULL || *offset == NULL || **offset == '\0')
    return NULL;
  size_t i;
  char *from = *offset;
  char *to = buf;
  for (i = 0; *from != '\0' && i < (size - 1); i++, from++) {
    if (*from == '\r')
      continue;
    if (*from == '\n') {
      from++;
      break;
    }
    *to = *from;
    to++;
  }
  *to = '\0';
  *offset = from;
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isVarNameRex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <isStringRex@plt>
  mov    %eax,-0x8(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  jne    L48
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L40:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <isNumRex@plt>
  test   %rax,%rax
  jne    L44
  movl   $0x1,-0x8(%rbp)
  jmp    L48
L44:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
L48:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int isVarNameRex(const char *text, int *strIndex, int *lenght) {
  int isString = isStringRex(text, strIndex, lenght);
  char ch = 0;
  int index = 0;
  if (isString == 1) {
    for (index = *strIndex; text[index] != '\0'; index++) {
      ch = text[index];
      if (isNumRex(ch) == 0) {
        isString = 1;
        break;
      } else {
        *strIndex = *strIndex + 1;
        *lenght = *lenght - 1;
        isString = 0;
      }
    }
  } else {
  }
  return isString;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isVarNameRex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <isStringRex@plt>
  mov    %eax,%r13d
  cmp    $0x1,%eax
  je     L14
L30:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  movslq (%rbx),%rax
  movzbl (%r12,%rax,1),%edi
  test   %dil,%dil
  je     L30
  lea    0x1(%r12,%rax,1),%r12
L4:
  movsbl %dil,%edi
  call   <isNumRex@plt>
  test   %rax,%rax
  je     L30
  addl   $0x1,(%rbx)
  subl   $0x1,0x0(%rbp)
  add    $0x1,%r12
  movzbl -0x1(%r12),%edi
  test   %dil,%dil
  jne    L4
  mov    $0x0,%r13d
  jmp    L30
```

assistant: ```c
int isVarNameRex(const char *text, int *strIndex, int *lenght) {
  int isString = isStringRex(text, strIndex, lenght);
  char ch = 0;
  int index = 0;
  if (isString == 1) {
    for (index = *strIndex; text[index] != '\0'; index++) {
      ch = text[index];
      if (isNumRex(ch) == 0) {
        isString = 1;
        break;
      } else {
        *strIndex = *strIndex + 1;
        *lenght = *lenght - 1;
        isString = 0;
      }
    }
  } else {
  }
  return isString;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isVarNameRex>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <isStringRex@plt>
  mov    %eax,%r13d
  cmp    $0x1,%eax
  je     L4
L14:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movslq (%rbx),%rdx
  movzbl (%r12,%rdx,1),%eax
  lea    0x1(%r12,%rdx,1),%r12
  test   %al,%al
  je     L14
  nopl   0x0(%rax)
L1:
  movsbl %al,%edi
  call   <isNumRex@plt>
  test   %rax,%rax
  je     L14
  add    $0x1,%r12
  addl   $0x1,(%rbx)
  subl   $0x1,0x0(%rbp)
  movzbl -0x1(%r12),%eax
  test   %al,%al
  jne    L1
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int isVarNameRex(const char *text, int *strIndex, int *lenght) {
  int isString = isStringRex(text, strIndex, lenght);
  char ch = 0;
  int index = 0;
  if (isString == 1) {
    for (index = *strIndex; text[index] != '\0'; index++) {
      ch = text[index];
      if (isNumRex(ch) == 0) {
        isString = 1;
        break;
      } else {
        *strIndex = *strIndex + 1;
        *lenght = *lenght - 1;
        isString = 0;
      }
    }
  } else {
  }
  return isString;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isVarNameRex>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <isStringRex@plt>
  mov    %eax,%r13d
  cmp    $0x1,%eax
  je     L14
L29:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  movslq (%rbx),%rdx
  movzbl (%r12,%rdx,1),%eax
  lea    0x1(%r12,%rdx,1),%r12
  test   %al,%al
  je     L29
  nopl   0x0(%rax)
L34:
  movsbl %al,%edi
  call   <isNumRex@plt>
  test   %rax,%rax
  je     L29
  add    $0x1,%r12
  addl   $0x1,(%rbx)
  subl   $0x1,0x0(%rbp)
  movzbl -0x1(%r12),%eax
  test   %al,%al
  jne    L34
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int isVarNameRex(const char *text, int *strIndex, int *lenght) {
  int isString = isStringRex(text, strIndex, lenght);
  char ch = 0;
  int index = 0;
  if (isString == 1) {
    for (index = *strIndex; text[index] != '\0'; index++) {
      ch = text[index];
      if (isNumRex(ch) == 0) {
        isString = 1;
        break;
      } else {
        *strIndex = *strIndex + 1;
        *lenght = *lenght - 1;
        isString = 0;
      }
    }
  } else {
  }
  return isString;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec2_squaredDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  movss  -0x4(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float vec2_squaredDistance(float *a, float *b) {
  float x = b[0] - a[0], y = b[1] - a[1];
  return x * x + y * y;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vec2_squaredDistance>:
  endbr64
  movss  (%rsi),%xmm0
  subss  (%rdi),%xmm0
  movss  0x4(%rsi),%xmm1
  subss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vec2_squaredDistance(float *a, float *b) {
  float x = b[0] - a[0], y = b[1] - a[1];
  return x * x + y * y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vec2_squaredDistance>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  subss  (%rdi),%xmm0
  subss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vec2_squaredDistance(float *a, float *b) {
  float x = b[0] - a[0], y = b[1] - a[1];
  return x * x + y * y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vec2_squaredDistance>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm1
  subss  (%rdi),%xmm0
  subss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
```

assistant: ```c
float vec2_squaredDistance(float *a, float *b) {
  float x = b[0] - a[0], y = b[1] - a[1];
  return x * x + y * y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mid_pred>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L56
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L50
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L69
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L50
L69:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L50
L56:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L50
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L45
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L50
L45:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((const)) int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L5
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
L5:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
__attribute__((const)) int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L5
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
  nopl   (%rax)
L5:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
__attribute__((const)) int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mid_pred>:
  endbr64
  mov    %esi,%eax
  cmp    %esi,%edi
  jle    L5
  cmp    %edx,%edi
  cmovg  %edx,%edi
  cmp    %edx,%esi
  cmovl  %edi,%eax
  ret
  nopl   (%rax)
L5:
  cmp    %edx,%edi
  cmovl  %edx,%edi
  cmp    %edx,%esi
  cmovg  %edi,%eax
  ret
```

assistant: ```c
__attribute__((const)) int mid_pred(int a, int b, int c) {
  if (a > b) {
    if (c > b) {
      if (c > a)
        b = a;
      else
        b = c;
    }
  } else {
    if (b > c) {
      if (c > a)
        b = c;
      else
        b = a;
    }
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_print_idle>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    D43(%rip),%rcx
  lea    D85(%rip),%rdx
  mov    $0x10,%esi
  call   <snprintf@plt>
  cmp    $0x10,%eax
  jg     L2
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L9
  mov    (%rbx),%rcx
  sub    0x8(%rsp),%rcx
  cmp    $0x1517f,%rcx
  ja     L51
  cmp    $0xe0f,%rcx
  ja     L18
  movabs $0x8888888888888889,%rsi
  mov    %rcx,%rax
  mul    %rsi
  mov    %rdx,%rsi
  shr    $0x5,%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L2:
  lea    D89(%rip),%rsi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  lea    D89(%rip),%rsi
  lea    D64(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L51:
  movabs $0xc22e450672894ab7,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x10,%rdx
  mov    %rdx,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L18:
  mov    %rcx,%rsi
  shr    $0x4,%rsi
  movabs $0x91a2b3c4d5e6f81,%rdx
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rsi
  imul   $0xe10,%rdx,%rax
  sub    %rax,%rcx
  movabs $0x8888888888888889,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x5,%rdx
  lea    D87(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D43
datatype: string
name: disassemble_data
arguments: data_label: D85
datatype: string
name: disassemble_data
arguments: data_label: D34
datatype: string
name: disassemble_data
arguments: data_label: D89
datatype: string
name: disassemble_data
arguments: data_label: D64
datatype: string
name: disassemble_data
arguments: data_label: D46
datatype: string
name: disassemble_data
arguments: data_label: D87
datatype: string

tool: D43: /dev/

tool: D85: %s%s

tool: D34: %02lum%02lu 

tool: D89: ?

tool: D64: %5s 

tool: D46: %4lud 

tool: D87: %02lu:%02lu 

assistant: ```c
int _print_idle(struct timeval *tv, char *device) {
  char dev[16];
  struct stat st;
  unsigned long idle;
  if (snprintf(dev, sizeof(dev), "%s%s", "/dev/", device) > (int)sizeof(dev))
    return printf("%5s ", "?");
  if (lstat(dev, &st) != 0)
    return printf("%5s ", "?");
  idle = tv->tv_sec - st.st_atime;
  if (idle / 3600 >= 24)
    return printf("%4lud ", idle / 3600 / 24);
  else if (idle / 60 >= 60)
    return printf("%02lu:%02lu ", idle / 3600, idle % 3600 / 60);
  return printf("%02lum%02lu ", idle / 60, idle % 60);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_print_idle>:
  endbr64
  push   %rbp
  mov    %rsi,%r8
  lea    D63(%rip),%rcx
  lea    D18(%rip),%rdx
  push   %rbx
  mov    $0x10,%esi
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    $0x10,%eax
  jg     L53
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L53
  mov    (%rbx),%rcx
  sub    0x8(%rsp),%rcx
  cmp    $0x1517f,%rcx
  ja     L27
  cmp    $0xe0f,%rcx
  ja     L21
  mov    %rcx,%rax
  lea    D2(%rip),%rdi
  movabs $0x8888888888888889,%rsi
  mul    %rsi
  mov    %rdx,%rsi
  shr    $0x5,%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  xor    %eax,%eax
  mov    %rcx,%rdx
  call   <printf@plt>
L6:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L53:
  lea    D30(%rip),%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
  nop
L27:
  mov    %rcx,%rax
  lea    D15(%rip),%rdi
  movabs $0xc22e450672894ab7,%rdx
  mul    %rdx
  xor    %eax,%eax
  shr    $0x10,%rdx
  mov    %rdx,%rsi
  call   <printf@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %rcx,%rsi
  lea    D53(%rip),%rdi
  movabs $0x91a2b3c4d5e6f81,%rdx
  shr    $0x4,%rsi
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  imul   $0xe10,%rdx,%rax
  mov    %rdx,%rsi
  movabs $0x8888888888888889,%rdx
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  shr    $0x5,%rdx
  call   <printf@plt>
  jmp    L6
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D63
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string
name: read_data
arguments: data_tag: D53
data_type: string

tool: D63: /dev/

tool: D18: %s%s

tool: D2: %02lum%02lu 

tool: D30: ?

tool: D3: %5s 

tool: D15: %4lud 

tool: D53: %02lu:%02lu 

assistant: ```c
int _print_idle(struct timeval *tv, char *device) {
  char dev[16];
  struct stat st;
  unsigned long idle;
  if (snprintf(dev, sizeof(dev), "%s%s", "/dev/", device) > (int)sizeof(dev))
    return printf("%5s ", "?");
  if (lstat(dev, &st) != 0)
    return printf("%5s ", "?");
  idle = tv->tv_sec - st.st_atime;
  if (idle / 3600 >= 24)
    return printf("%4lud ", idle / 3600 / 24);
  else if (idle / 60 >= 60)
    return printf("%02lu:%02lu ", idle / 3600, idle % 3600 / 60);
  return printf("%02lum%02lu ", idle / 60, idle % 60);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_print_idle>:
  endbr64
  push   %rbp
  mov    %rsi,%r8
  lea    D15(%rip),%rcx
  lea    D54(%rip),%rdx
  push   %rbx
  mov    $0x10,%esi
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cmp    $0x10,%eax
  jg     L4
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <lstat@plt>
  test   %rax,%rax
  jne    L4
  mov    (%rbx),%rcx
  sub    0x8(%rsp),%rcx
  cmp    $0x1517f,%rcx
  ja     L35
  cmp    $0xe0f,%rcx
  ja     L10
  mov    %rcx,%rax
  lea    D42(%rip),%rdi
  movabs $0x8888888888888889,%rsi
  mul    %rsi
  mov    %rdx,%rsi
  shr    $0x5,%rsi
  mov    %rsi,%rax
  shl    $0x4,%rax
  sub    %rsi,%rax
  shl    $0x2,%rax
  sub    %rax,%rcx
  xor    %eax,%eax
  mov    %rcx,%rdx
  call   <printf@plt>
L68:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L4:
  lea    D64(%rip),%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L68
  nop
L35:
  mov    %rcx,%rax
  lea    D13(%rip),%rdi
  movabs $0xc22e450672894ab7,%rdx
  mul    %rdx
  xor    %eax,%eax
  shr    $0x10,%rdx
  mov    %rdx,%rsi
  call   <printf@plt>
  jmp    L68
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rcx,%rsi
  lea    D41(%rip),%rdi
  movabs $0x91a2b3c4d5e6f81,%rdx
  shr    $0x4,%rsi
  mov    %rsi,%rax
  mul    %rdx
  shr    $0x3,%rdx
  imul   $0xe10,%rdx,%rax
  mov    %rdx,%rsi
  movabs $0x8888888888888889,%rdx
  sub    %rax,%rcx
  mov    %rcx,%rax
  mul    %rdx
  xor    %eax,%eax
  shr    $0x5,%rdx
  call   <printf@plt>
  jmp    L68
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type: string
name: extract_symbolic_data
arguments: label: D54
type: string
name: extract_symbolic_data
arguments: label: D42
type: string
name: extract_symbolic_data
arguments: label: D64
type: string
name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D41
type: string

tool: D15: /dev/

tool: D54: %s%s

tool: D42: %02lum%02lu 

tool: D64: ?

tool: D24: %5s 

tool: D13: %4lud 

tool: D41: %02lu:%02lu 

assistant: ```c
int _print_idle(struct timeval *tv, char *device) {
  char dev[16];
  struct stat st;
  unsigned long idle;
  if (snprintf(dev, sizeof(dev), "%s%s", "/dev/", device) > (int)sizeof(dev))
    return printf("%5s ", "?");
  if (lstat(dev, &st) != 0)
    return printf("%5s ", "?");
  idle = tv->tv_sec - st.st_atime;
  if (idle / 3600 >= 24)
    return printf("%4lud ", idle / 3600 / 24);
  else if (idle / 60 >= 60)
    return printf("%02lu:%02lu ", idle / 3600, idle % 3600 / 60);
  return printf("%02lum%02lu ", idle / 60, idle % 60);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_week_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  jg     L45
  jmp    L44
L28:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_wday@plt>
  cmp    %eax,-0x20(%rbp)
  sete   %al
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  subl   $0x7,-0x18(%rbp)
L44:
  cmpl   $0x7,-0x18(%rbp)
  jg     L28
  jmp    L30
L45:
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0xa,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L24
  movl   $0x34,-0x4(%rbp)
  jmp    L30
L24:
  cmpl   $0x34,-0x4(%rbp)
  jle    L30
  movl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _week_num(int year, int yday, int wday, int first) {
  int result = 0;
  if (first <= (0 + 1)) {
    while (yday > (6 + 1)) {
      result += (_wday(year, yday) == first) ? 1 : 0;
      yday -= (6 + 1);
    }
  } else {
    result = ((yday - wday) + 10) / 7;
    if (result < 1) {
      result = 52;
    } else if (result > 52) {
      result = 1;
    }
  }
  return result;
}
```