ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sincospi>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <__ocml_sincospi_f64@plt>
  movsd  %xmm0,0x0(%rbp)
  movsd  (%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sincospi(double x, double *sptr, double *cptr) {
  double tmp;
  *sptr = __ocml_sincospi_f64(x, (__attribute__((address_space(5))) double *)&tmp);
  *cptr = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  movl   $0x3,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <missingNumber@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main() {
  int arr[] = {0, 1, 3};
  int len = sizeof arr / sizeof arr[0];
  printf("%d\n", missingNumber(arr, len));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x3,%esi
  call   <missingNumber@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d


assistant: ```c
int main() {
  int arr[] = {0, 1, 3};
  int len = sizeof arr / sizeof arr[0];
  printf("%d\n", missingNumber(arr, len));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x3,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <missingNumber@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  int arr[] = {0, 1, 3};
  int len = sizeof arr / sizeof arr[0];
  printf("%d\n", missingNumber(arr, len));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x3,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <missingNumber@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: byte[8]
name: retrieve_data
arguments: tag: D12
datatype: string

tool: {"D2": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D12: %d


assistant: ```c
int main() {
  int arr[] = {0, 1, 3};
  int len = sizeof arr / sizeof arr[0];
  printf("%d\n", missingNumber(arr, len));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: POSIX timing not implemented on this machine.

assistant: ```c
int main(int argc, char **argv) {
  printf("POSIX timing not implemented on this machine.");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: POSIX timing not implemented on this machine.

assistant: ```c
int main(int argc, char **argv) {
  printf("POSIX timing not implemented on this machine.");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: POSIX timing not implemented on this machine.

assistant: ```c
int main(int argc, char **argv) {
  printf("POSIX timing not implemented on this machine.");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: POSIX timing not implemented on this machine.

assistant: ```c
int main(int argc, char **argv) {
  printf("POSIX timing not implemented on this machine.");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<create_sheet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
char *create_sheet(int *size) {
  char *sheet;
  sheet = (char *)malloc(*size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<create_sheet>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *create_sheet(int *size) {
  char *sheet;
  sheet = (char *)malloc(*size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_sheet>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
char *create_sheet(int *size) {
  char *sheet;
  sheet = (char *)malloc(*size);
}
```
user: What is the c source code of the assembly code below?

```asm
<create_sheet>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
char *create_sheet(int *size) {
  char *sheet;
  sheet = (char *)malloc(*size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%r8
  lea    -0x1c(%rbp),%rdi
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x14(%rbp),%rsi
  push   %rsi
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  add    $0x10,%rsp
  movss  -0x28(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x24(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L3
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L34
L3:
  movss  -0x18(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x24(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  -0x28(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x20(%rbp),%xmm3
  movss  -0x24(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  -0x28(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x18(%rbp),%xmm2
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  -0x28(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x20(%rbp),%xmm3
  movss  -0x24(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L6
L34:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D8
data_type: string
name: unpack_data
arguments: data_tag: D33
data_type: string
name: unpack_data
arguments: data_tag: D35
data_type: string

tool: D28: Enter The Value of A B C D M N: 

tool: D8: %f %f %f %f %f %f

tool: D33: X1= %.2f X2= %.2f 


tool: D35: ad - cb is 0... can't proceed!! 

assistant: ```c
int main() {
  float x1, x2, a, b, c, d, m, n;
  printf("Enter The Value of A B C D M N: ");
  scanf("%f %f %f %f %f %f", &a, &b, &c, &d, &m, &n);
  if ((a * d - c * b) != 0) {
    x1 = (m * d - b * n) / (a * d - c * b);
    x2 = (n * a - m * c) / (a * d - c * b);
    printf("X1= %.2f X2= %.2f \n", x1, x2);
  } else
    printf("ad - cb is 0... can't proceed!! ");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rcx
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  sub    $0x8,%rsp
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x1c(%rsp),%xmm0
  movss  0x18(%rsp),%xmm4
  movss  0x14(%rsp),%xmm3
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movaps %xmm4,%xmm5
  mulss  %xmm3,%xmm5
  subss  %xmm5,%xmm2
  add    $0x10,%rsp
  ucomiss D21(%rip),%xmm2
  jp     L38
  jne    L38
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L38:
  movss  0x10(%rsp),%xmm6
  movss  0x14(%rsp),%xmm5
  mulss  %xmm5,%xmm1
  mulss  %xmm6,%xmm4
  subss  %xmm4,%xmm1
  divss  %xmm2,%xmm1
  mulss  %xmm6,%xmm0
  mulss  %xmm5,%xmm3
  subss  %xmm3,%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D40(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: byte[4]
name: retrieve_data
arguments: tag: D29
datatype: string
name: retrieve_data
arguments: tag: D40
datatype: string

tool: D20: Enter The Value of A B C D M N: 

tool: D7: %f %f %f %f %f %f

tool: {"D21": [0x00,0x00,0x00,0x00]}

tool: D29: ad - cb is 0... can't proceed!! 

tool: D40: X1= %.2f X2= %.2f 


assistant: ```c
int main() {
  float x1, x2, a, b, c, d, m, n;
  printf("Enter The Value of A B C D M N: ");
  scanf("%f %f %f %f %f %f", &a, &b, &c, &d, &m, &n);
  if ((a * d - c * b) != 0) {
    x1 = (m * d - b * n) / (a * d - c * b);
    x2 = (n * a - m * c) / (a * d - c * b);
    printf("X1= %.2f X2= %.2f \n", x1, x2);
  } else
    printf("ad - cb is 0... can't proceed!! ");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rcx
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm4
  movss  0x1c(%rsp),%xmm0
  movss  0x14(%rsp),%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm4,%xmm5
  pop    %rax
  pop    %rdx
  mulss  %xmm0,%xmm2
  mulss  %xmm3,%xmm5
  subss  %xmm5,%xmm2
  ucomiss D29(%rip),%xmm2
  jp     L24
  jne    L24
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L24:
  movss  0x10(%rsp),%xmm6
  movss  0x14(%rsp),%xmm5
  mov    $0x2,%eax
  lea    D24(%rip),%rdi
  mulss  %xmm5,%xmm1
  mulss  %xmm6,%xmm4
  mulss  %xmm6,%xmm0
  mulss  %xmm5,%xmm3
  subss  %xmm4,%xmm1
  subss  %xmm3,%xmm0
  divss  %xmm2,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L15
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: byte[4]
name: parse_data
arguments: tag: D25
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string

tool: D2: Enter The Value of A B C D M N: 

tool: D0: %f %f %f %f %f %f

tool: {"D29": [0x00,0x00,0x00,0x00]}

tool: D25: ad - cb is 0... can't proceed!! 

tool: D24: X1= %.2f X2= %.2f 


assistant: ```c
int main() {
  float x1, x2, a, b, c, d, m, n;
  printf("Enter The Value of A B C D M N: ");
  scanf("%f %f %f %f %f %f", &a, &b, &c, &d, &m, &n);
  if ((a * d - c * b) != 0) {
    x1 = (m * d - b * n) / (a * d - c * b);
    x2 = (n * a - m * c) / (a * d - c * b);
    printf("X1= %.2f X2= %.2f \n", x1, x2);
  } else
    printf("ad - cb is 0... can't proceed!! ");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rcx
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  lea    0x1c(%rsp),%rax
  push   %rax
  lea    0x20(%rsp),%r9
  lea    0x1c(%rsp),%r8
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  movss  0x18(%rsp),%xmm4
  movss  0x1c(%rsp),%xmm0
  movss  0x14(%rsp),%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm4,%xmm5
  pop    %rax
  pop    %rdx
  mulss  %xmm0,%xmm2
  mulss  %xmm3,%xmm5
  subss  %xmm5,%xmm2
  ucomiss D42(%rip),%xmm2
  jp     L28
  jne    L28
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L28:
  movss  0x10(%rsp),%xmm6
  movss  0x14(%rsp),%xmm5
  mov    $0x2,%eax
  lea    D7(%rip),%rdi
  mulss  %xmm5,%xmm1
  mulss  %xmm6,%xmm4
  mulss  %xmm6,%xmm0
  mulss  %xmm5,%xmm3
  subss  %xmm4,%xmm1
  subss  %xmm3,%xmm0
  divss  %xmm2,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L15
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D20
data_type: string
name: unpack_data
arguments: tag: D42
data_type: byte[4]
name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string

tool: D26: Enter The Value of A B C D M N: 

tool: D20: %f %f %f %f %f %f

tool: {"D42": [0x00,0x00,0x00,0x00]}

tool: D18: ad - cb is 0... can't proceed!! 

tool: D7: X1= %.2f X2= %.2f 


assistant: ```c
int main() {
  float x1, x2, a, b, c, d, m, n;
  printf("Enter The Value of A B C D M N: ");
  scanf("%f %f %f %f %f %f", &a, &b, &c, &d, &m, &n);
  if ((a * d - c * b) != 0) {
    x1 = (m * d - b * n) / (a * d - c * b);
    x2 = (n * a - m * c) / (a * d - c * b);
    printf("X1= %.2f X2= %.2f \n", x1, x2);
  } else
    printf("ad - cb is 0... can't proceed!! ");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DWSwap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    -0x20(%rbp),%rbx
  mov    $0x0,%r13d
  jmp    L19
L14:
  movzbl (%rbx),%r12d
  movzbl 0x2(%rbx),%eax
  mov    %al,(%rbx)
  lea    0x2(%rbx),%rax
  mov    %r12b,(%rax)
  movzbl 0x1(%rbx),%r12d
  lea    0x1(%rbx),%rax
  movzbl 0x3(%rbx),%edx
  mov    %dl,(%rax)
  lea    0x3(%rbx),%rax
  mov    %r12b,(%rax)
  add    $0x1,%r13d
  add    $0x4,%rbx
L19:
  mov    -0x24(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  cmp    %eax,%r13d
  jl     L14
  nop
  nop
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void DWSwap(void *Field, int Cnt) {
  register unsigned char *Run = (unsigned char *)Field, Swap;
  register int z;
  for (z = 0; z < Cnt / 4; z++, Run += 4) {
    Swap = Run[0];
    Run[0] = Run[2];
    Run[2] = Swap;
    Swap = Run[1];
    Run[1] = Run[3];
    Run[3] = Swap;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DWSwap>:
  endbr64
  lea    0x3(%rsi),%r8d
  test   %esi,%esi
  cmovns %esi,%r8d
  sar    $0x2,%r8d
  cmp    $0x3,%esi
  jle    L14
  mov    $0x0,%eax
L0:
  movzbl (%rdi),%edx
  movzbl 0x2(%rdi),%ecx
  mov    %cl,(%rdi)
  mov    %dl,0x2(%rdi)
  movzbl 0x1(%rdi),%edx
  movzbl 0x3(%rdi),%ecx
  mov    %cl,0x1(%rdi)
  mov    %dl,0x3(%rdi)
  add    $0x1,%eax
  add    $0x4,%rdi
  cmp    %r8d,%eax
  jl     L0
L14:
  ret
```

assistant: ```c
void DWSwap(void *Field, int Cnt) {
  register unsigned char *Run = (unsigned char *)Field, Swap;
  register int z;
  for (z = 0; z < Cnt / 4; z++, Run += 4) {
    Swap = Run[0];
    Run[0] = Run[2];
    Run[2] = Swap;
    Swap = Run[1];
    Run[1] = Run[3];
    Run[3] = Swap;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<DWSwap>:
  endbr64
  test   %esi,%esi
  lea    0x3(%rsi),%r8d
  cmovns %esi,%r8d
  sar    $0x2,%r8d
  cmp    $0x3,%esi
  jle    L7
  xor    %eax,%eax
  nopl   0x0(%rax)
L9:
  movzbl (%rdi),%edx
  movzbl 0x2(%rdi),%ecx
  add    $0x1,%eax
  add    $0x4,%rdi
  mov    %cl,-0x4(%rdi)
  movzbl -0x1(%rdi),%ecx
  mov    %dl,-0x2(%rdi)
  movzbl -0x3(%rdi),%edx
  mov    %cl,-0x3(%rdi)
  mov    %dl,-0x1(%rdi)
  cmp    %r8d,%eax
  jl     L9
L7:
  ret
```

assistant: ```c
void DWSwap(void *Field, int Cnt) {
  register unsigned char *Run = (unsigned char *)Field, Swap;
  register int z;
  for (z = 0; z < Cnt / 4; z++, Run += 4) {
    Swap = Run[0];
    Run[0] = Run[2];
    Run[2] = Swap;
    Swap = Run[1];
    Run[1] = Run[3];
    Run[3] = Swap;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_kbd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <device_info@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <kbd_map_read@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <kbd_map_print@plt>
  jmp    L3
L9:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <kbd_print_bits@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void show_kbd(int fd, unsigned int protocol_version) {
  struct kbd_map *map;
  device_info(fd);
  map = kbd_map_read(fd, protocol_version);
  if (map)
    kbd_map_print(stdout, map, 0);
  else
    kbd_print_bits(fd);
}
```
user: What is the c source code of the assembly code below?

```asm
<show_kbd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <device_info@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <kbd_map_read@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    $0x0,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <kbd_map_print@plt>
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %ebx,%edi
  call   <kbd_print_bits@plt>
  jmp    L14
```

assistant: ```c
void show_kbd(int fd, unsigned int protocol_version) {
  struct kbd_map *map;
  device_info(fd);
  map = kbd_map_read(fd, protocol_version);
  if (map)
    kbd_map_print(stdout, map, 0);
  else
    kbd_print_bits(fd);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<show_kbd>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <device_info@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <kbd_map_read@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rsi
  mov    D1(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1090 <kbd_map_print@plt>
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <kbd_print_bits@plt>
```

assistant: ```c
void show_kbd(int fd, unsigned int protocol_version) {
  struct kbd_map *map;
  device_info(fd);
  map = kbd_map_read(fd, protocol_version);
  if (map)
    kbd_map_print(stdout, map, 0);
  else
    kbd_print_bits(fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<show_kbd>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <device_info@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <kbd_map_read@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    D6(%rip),%rax
  xor    %edx,%edx
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1090 <kbd_map_print@plt>
  xchg   %ax,%ax
L0:
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1080 <kbd_print_bits@plt>
```

assistant: ```c
void show_kbd(int fd, unsigned int protocol_version) {
  struct kbd_map *map;
  device_info(fd);
  map = kbd_map_read(fd, protocol_version);
  if (map)
    kbd_map_print(stdout, map, 0);
  else
    kbd_print_bits(fd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getppid@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D32
type: string
name: parse_data
arguments: data_label: D28
type: string

tool: D1: pid   = %u


tool: D22: ppid  = %u


tool: D15: uid   = %u


tool: D33: euid  = %u


tool: D32: gid   = %u


tool: D28: egid  = %u


assistant: ```c
int main(void) {
  printf("pid   = %u\n", getpid());
  printf("ppid  = %u\n", getppid());
  printf("uid   = %u\n", getuid());
  printf("euid  = %u\n", geteuid());
  printf("gid   = %u\n", getgid());
  printf("egid  = %u\n", getegid());
  sleep(10);
  return 0;
}
```