ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fputc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <fwrite@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int fputc(int c, FILE *stream) {
  if (fwrite(&c, 1, 1, stream)) {
    return c;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fputc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rdi
  call   <fwrite@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne 0xc(%rsp),%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int fputc(int c, FILE *stream) {
  if (fwrite(&c, 1, 1, stream)) {
    return c;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<eal_bf_bkdrhash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x83,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L15:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L15
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int eal_bf_bkdrhash(const unsigned char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<eal_bf_bkdrhash>:
  endbr64
  test   %esi,%esi
  je     L3
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
L2:
  imul   $0x83,%eax,%eax
  movzbl (%rdi),%edx
  add    %edx,%eax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L2
  ret
L3:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bkdrhash(const unsigned char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eal_bf_bkdrhash>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L15:
  imul   $0x83,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L15
  ret
  nopl   (%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bkdrhash(const unsigned char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<eal_bf_bkdrhash>:
  endbr64
  test   %esi,%esi
  je     L11
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L15:
  imul   $0x83,%eax,%eax
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L15
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bkdrhash(const unsigned char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    $0x5f5e100,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L16
L7:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <get_value@plt>
  mov    %eax,(%rbx)
  addq   $0x1,-0x20(%rbp)
L16:
  cmpq   $0x5f5e0ff,-0x20(%rbp)
  jle    L7
  mov    -0x18(%rbp),%rax
  mov    $0x5f5e100,%esi
  mov    %rax,%rdi
  call   <crc8@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: 0x%02x


assistant: ```c
int main() {
  uint8_t *buf = malloc(100000000);
  long i;
  for (i = 0; i < 100000000; i++)
    buf[i] = get_value(i);
  uint8_t crc = crc8(buf, 100000000);
  free(buf);
  printf("0x%02x\n", crc);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5f5e100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
L0:
  mov    %rbx,%rdi
  call   <get_value@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x5f5e100,%rbx
  jne    L0
  mov    $0x5f5e100,%esi
  mov    %rbp,%rdi
  call   <crc8@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: 0x%02x


assistant: ```c
int main() {
  uint8_t *buf = malloc(100000000);
  long i;
  for (i = 0; i < 100000000; i++)
    buf[i] = get_value(i);
  uint8_t crc = crc8(buf, 100000000);
  free(buf);
  printf("0x%02x\n", crc);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5f5e100,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdi
  call   <get_value@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x5f5e100,%rbx
  jne    L0
  mov    $0x5f5e100,%esi
  mov    %rbp,%rdi
  call   <crc8@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: 0x%02x


assistant: ```c
int main() {
  uint8_t *buf = malloc(100000000);
  long i;
  for (i = 0; i < 100000000; i++)
    buf[i] = get_value(i);
  uint8_t crc = crc8(buf, 100000000);
  free(buf);
  printf("0x%02x\n", crc);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5f5e100,%edi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <malloc@plt>
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  call   <get_value@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x5f5e100,%rbx
  jne    L2
  mov    $0x5f5e100,%esi
  mov    %rbp,%rdi
  call   <crc8@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: 0x%02x


assistant: ```c
int main() {
  uint8_t *buf = malloc(100000000);
  long i;
  for (i = 0; i < 100000000; i++)
    buf[i] = get_value(i);
  uint8_t crc = crc8(buf, 100000000);
  free(buf);
  printf("0x%02x\n", crc);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffe,-0x20(%rbp)
  movl   $0xb,-0x1c(%rbp)
  movl   $0xfffffffc,-0x18(%rbp)
  movl   $0xd,-0x14(%rbp)
  movl   $0xfffffffb,-0x10(%rbp)
  movl   $0xfffffffe,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <MaxSubsequenceSumAlg2@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int A[] = {-2, 11, -4, 13, -5, -2};
  int maxSum;
  maxSum = MaxSubsequenceSumAlg2(A, 6);
  printf("%d\n", maxSum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffe,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0xfffffffc,0x8(%rsp)
  movl   $0xd,0xc(%rsp)
  movl   $0xfffffffb,0x10(%rsp)
  movl   $0xfffffffe,0x14(%rsp)
  mov    %rsp,%rdi
  mov    $0x6,%esi
  call   <MaxSubsequenceSumAlg2@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int A[] = {-2, 11, -4, 13, -5, -2};
  int maxSum;
  maxSum = MaxSubsequenceSumAlg2(A, 6);
  printf("%d\n", maxSum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xbfffffffe,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0xdfffffffc,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xfffffffefffffffb,%rax
  mov    %rax,0x10(%rsp)
  call   <MaxSubsequenceSumAlg2@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int A[] = {-2, 11, -4, 13, -5, -2};
  int maxSum;
  maxSum = MaxSubsequenceSumAlg2(A, 6);
  printf("%d\n", maxSum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <MaxSubsequenceSumAlg2@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: {"D7": [0xfe,0xff,0xff,0xff,0x0b,0x00,0x00,0x00,0xfc,0xff,0xff,0xff,0x0d,0x00,0x00,0x00]}

tool: {"D8": [0xfb,0xff,0xff,0xff,0xfe,0xff,0xff,0xff]}

tool: D4: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int A[] = {-2, 11, -4, 13, -5, -2};
  int maxSum;
  maxSum = MaxSubsequenceSumAlg2(A, 6);
  printf("%d\n", maxSum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_request_head>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %rsi,-0x2030(%rbp)
  mov    %rdx,-0x2038(%rbp)
  mov    %rcx,-0x2040(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x2010(%rbp)
  movq   $0x0,-0x2008(%rbp)
  lea    -0x2000(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3fe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x2028(%rbp),%rcx
  lea    -0x2010(%rbp),%rax
  mov    $0x1fff,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x2010(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x2018(%rbp)
  cmpq   $0x0,-0x2018(%rbp)
  jne    L72
  mov    $0xffffffff,%eax
  jmp    L29
L72:
  mov    -0x2018(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x2040(%rbp),%rsi
  mov    -0x2038(%rbp),%rcx
  mov    -0x2030(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  mov    %rsi,%r8
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L56
  mov    $0xffffffff,%eax
  jmp    L29
L56:
  mov    -0x2040(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x201c(%rbp)
  movl   $0x0,-0x2020(%rbp)
  jmp    L62
L77:
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L3
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L51
L3:
  mov    -0x2020(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2040(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L37
L51:
  addl   $0x1,-0x2020(%rbp)
L62:
  mov    -0x2020(%rbp),%eax
  cmp    -0x201c(%rbp),%eax
  jl     L77
L37:
  mov    $0x0,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: %[^ ] %[^ ] %[^ ]

assistant: ```c
int parse_request_head(char *buffer, char *method, char *url, char *protocol) {
  char tmp_buf[8192] = {0};
  char *end_of_line;
  memcpy(tmp_buf, buffer, 8192 - 1);
  end_of_line = strchr(tmp_buf, '\n');
  if (end_of_line == NULL)
    return -1;
  *end_of_line = '\0';
  if (sscanf(tmp_buf, "%[^ ] %[^ ] %[^ ]", method, url, protocol) != 3)
    return -1;
  int pro_len = strlen(protocol);
  for (int i = 0; i < pro_len; i++) {
    if (protocol[i] == '\r' || protocol[i] == '\n') {
      protocol[i] = '\0';
      break;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_request_head>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x3fe,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%r13
  mov    $0x1fff,%edx
  mov    %r8,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L41
  movb   $0x0,(%rax)
  mov    %rsp,%rdi
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L29
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L35
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
L27:
  mov    %rdx,%rcx
  movzbl (%rdx),%eax
  cmp    $0xd,%al
  je     L98
  cmp    $0xa,%al
  je     L98
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L27
  mov    $0x0,%eax
  jmp    L33
L98:
  movb   $0x0,(%rcx)
  mov    $0x0,%eax
L33:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    $0xffffffff,%eax
  jmp    L33
L29:
  mov    $0xffffffff,%eax
  jmp    L33
L35:
  mov    $0x0,%eax
  jmp    L33
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %[^ ] %[^ ] %[^ ]

assistant: ```c
int parse_request_head(char *buffer, char *method, char *url, char *protocol) {
  char tmp_buf[8192] = {0};
  char *end_of_line;
  memcpy(tmp_buf, buffer, 8192 - 1);
  end_of_line = strchr(tmp_buf, '\n');
  if (end_of_line == NULL)
    return -1;
  *end_of_line = '\0';
  if (sscanf(tmp_buf, "%[^ ] %[^ ] %[^ ]", method, url, protocol) != 3)
    return -1;
  int pro_len = strlen(protocol);
  for (int i = 0; i < pro_len; i++) {
    if (protocol[i] == '\r' || protocol[i] == '\n') {
      protocol[i] = '\0';
      break;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_request_head>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r9
  mov    %rsp,%rbp
  mov    %rcx,%rbx
  lea    0x10(%rsp),%rdi
  mov    $0x3fe,%ecx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %r9,%rsi
  mov    $0x1fff,%edx
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L6
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L70
  sub    $0x1,%eax
  mov    %rbx,%r8
  lea    0x1(%rbx,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%r8),%eax
  cmp    $0xd,%al
  je     L56
  cmp    $0xa,%al
  je     L56
  add    $0x1,%r8
  cmp    %rdx,%r8
  jne    L11
L70:
  xor    %eax,%eax
L58:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  movb   $0x0,(%r8)
  xor    %eax,%eax
  jmp    L58
L6:
  mov    $0xffffffff,%eax
  jmp    L58
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %[^ ] %[^ ] %[^ ]

assistant: ```c
int parse_request_head(char *buffer, char *method, char *url, char *protocol) {
  char tmp_buf[8192] = {0};
  char *end_of_line;
  memcpy(tmp_buf, buffer, 8192 - 1);
  end_of_line = strchr(tmp_buf, '\n');
  if (end_of_line == NULL)
    return -1;
  *end_of_line = '\0';
  if (sscanf(tmp_buf, "%[^ ] %[^ ] %[^ ]", method, url, protocol) != 3)
    return -1;
  int pro_len = strlen(protocol);
  for (int i = 0; i < pro_len; i++) {
    if (protocol[i] == '\r' || protocol[i] == '\n') {
      protocol[i] = '\0';
      break;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_request_head>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r9
  mov    %rsp,%rbp
  mov    %rcx,%rbx
  lea    0x10(%rsp),%rdi
  mov    $0x3fe,%ecx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %r9,%rsi
  mov    $0x1fff,%edx
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L51
  movb   $0x0,(%rax)
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  jne    L51
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L20
  sub    $0x1,%eax
  mov    %rbx,%r8
  lea    0x1(%rbx,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl (%r8),%eax
  cmp    $0xd,%al
  je     L76
  cmp    $0xa,%al
  je     L76
  add    $0x1,%r8
  cmp    %r8,%rdx
  jne    L30
L20:
  xor    %eax,%eax
L50:
  mov    0x2008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  movb   $0x0,(%r8)
  xor    %eax,%eax
  jmp    L50
L51:
  mov    $0xffffffff,%eax
  jmp    L50
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: %[^ ] %[^ ] %[^ ]

assistant: ```c
int parse_request_head(char *buffer, char *method, char *url, char *protocol) {
  char tmp_buf[8192] = {0};
  char *end_of_line;
  memcpy(tmp_buf, buffer, 8192 - 1);
  end_of_line = strchr(tmp_buf, '\n');
  if (end_of_line == NULL)
    return -1;
  *end_of_line = '\0';
  if (sscanf(tmp_buf, "%[^ ] %[^ ] %[^ ]", method, url, protocol) != 3)
    return -1;
  int pro_len = strlen(protocol);
  for (int i = 0; i < pro_len; i++) {
    if (protocol[i] == '\r' || protocol[i] == '\n') {
      protocol[i] = '\0';
      break;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_password>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_password(char *str) {
  int i = 0;
  while (str[i]) {
    printf("%c", str[i]);
    i++;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_password>:
  endbr64
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  lea    0x1(%rdi),%rbx
L19:
  movsbl %al,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L19
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void print_password(char *str) {
  int i = 0;
  while (str[i]) {
    printf("%c", str[i]);
    i++;
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_password>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L11
  push   %rbx
  lea    0x1(%rdi),%rbx
L0:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L0
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nop
L11:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print_password(char *str) {
  int i = 0;
  while (str[i]) {
    printf("%c", str[i]);
    i++;
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_password>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  push   %rbx
  lea    0x1(%rdi),%rbx
L16:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L16
  mov    $0xa,%edi
  pop    %rbx
  jmp    1050 <putchar@plt>
  nop
L5:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print_password(char *str) {
  int i = 0;
  while (str[i]) {
    printf("%c", str[i]);
    i++;
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<glabel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <output_string@plt>
  mov    $0x0,%eax
  call   <output_label_terminator@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  nop
  leave
  ret
```

assistant: ```c
glabel(lab) char *lab;
{
  output_string(lab);
  output_label_terminator();
  newline();
}
```
user: What is the c source code of the assembly code below?

```asm
<glabel>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <output_string@plt>
  mov    $0x0,%eax
  call   <output_label_terminator@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
glabel(lab) char *lab;
{
  output_string(lab);
  output_label_terminator();
  newline();
}
```