ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Complain>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Complain(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Complain>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Complain(char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vfprintf(stderr, fmt, args);
  va_end(args);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<multiply90>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L0
L11:
  movl   $0x0,-0x3c(%rbp)
  jmp    L20
L31:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L20:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L31
  addl   $0x1,-0x40(%rbp)
L0:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L11
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply90(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply90>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L9:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L0:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L0
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  ret
```

assistant: ```c
void multiply90(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply90>:
  endbr64
  test   %edi,%edi
  jle    L14
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L26
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L7
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
void multiply90(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<multiply90>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L21
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L50:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L45
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L45
  nopl   0x0(%rax)
L33:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L33
  cmp    -0x24(%rsp),%r11d
  je     L12
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L12
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L12
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L12:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L50
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L52:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L52
  mov    -0x18(%rsp),%r8
  jmp    L12
```

assistant: ```c
void multiply90(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L33:
  mov    $0x0,%eax
  call   <play_game@plt>
  test   %rax,%rax
  je     L20
  addl   $0x1,-0x10(%rbp)
  jmp    L32
L20:
  addl   $0x1,-0xc(%rbp)
L32:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x11(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x11(%rbp),%eax
  cmp    $0x6e,%al
  je     L36
  nop
  jmp    L33
L36:
  nop
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D12
datatype: string

tool: D28: Play again? 

tool: D6: %c

tool: D12: Wins:  %d  Losses:  %d


assistant: ```c
int main(void) {
  int wins = 0, losses = 0;
  char play_again;
  srand((unsigned)time(NULL));
  for (;;) {
    if (play_game())
      wins++;
    else
      losses++;
    printf("Play again? ");
    scanf("%c", &play_again);
    if (play_again == 'n')
      break;
    else
      continue;
  }
  printf("Wins:  %d  Losses:  %d\n", wins, losses);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D21(%rip),%r14
  lea    0x7(%rsp),%r13
  lea    D20(%rip),%r12
L25:
  mov    $0x0,%eax
  call   <play_game@plt>
  test   %rax,%rax
  je     L23
  add    $0x1,%ebx
L13:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpb   $0x6e,0x7(%rsp)
  jne    L25
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  add    $0x1,%ebp
  jmp    L13
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string
name: extract_symbolic_data
arguments: tag: D18
type: string

tool: D21: Play again? 

tool: D20: %c

tool: D18: Wins:  %d  Losses:  %d


assistant: ```c
int main(void) {
  int wins = 0, losses = 0;
  char play_again;
  srand((unsigned)time(NULL));
  for (;;) {
    if (play_game())
      wins++;
    else
      losses++;
    printf("Play again? ");
    scanf("%c", &play_again);
    if (play_again == 'n')
      break;
    else
      continue;
  }
  printf("Wins:  %d  Losses:  %d\n", wins, losses);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D18(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L13:
  xor    %eax,%eax
  call   <play_game@plt>
  test   %rax,%rax
  je     L3
  add    $0x1,%ebp
L1:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x6e,0x7(%rsp)
  jne    L13
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D23(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r12d
  jmp    L1
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D18: Play again? 

tool: D28: %c

tool: D23: Wins:  %d  Losses:  %d


assistant: ```c
int main(void) {
  int wins = 0, losses = 0;
  char play_again;
  srand((unsigned)time(NULL));
  for (;;) {
    if (play_game())
      wins++;
    else
      losses++;
    printf("Play again? ");
    scanf("%c", &play_again);
    if (play_again == 'n')
      break;
    else
      continue;
  }
  printf("Wins:  %d  Losses:  %d\n", wins, losses);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  lea    D4(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%r13
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L6:
  xor    %eax,%eax
  call   <play_game@plt>
  test   %rax,%rax
  je     L18
  add    $0x1,%ebp
L16:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x6e,0x7(%rsp)
  jne    L6
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D14(%rip),%rdi
  mov    %ebp,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12d
  jmp    L16
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D14
type_infered: string

tool: D4: Play again? 

tool: D25: %c

tool: D14: Wins:  %d  Losses:  %d


assistant: ```c
int main(void) {
  int wins = 0, losses = 0;
  char play_again;
  srand((unsigned)time(NULL));
  for (;;) {
    if (play_game())
      wins++;
    else
      losses++;
    printf("Play again? ");
    scanf("%c", &play_again);
    if (play_again == 'n')
      break;
    else
      continue;
  }
  printf("Wins:  %d  Losses:  %d\n", wins, losses);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0xa,-0x4(%rbp)
  jmp    L10
L0:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x0,-0x4(%rbp)
  jg     L0
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: !10 = %d


assistant: ```c
int main() {
  int fact, i, n, m;
  fact = 1;
  for (n = 10; n > 0; n--) {
    fact = fact * n;
  }
  printf("!10 = %d\n", fact);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%eax
  mov    $0x1,%esi
L0:
  imul   %eax,%esi
  sub    $0x1,%eax
  jne    L0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: !10 = %d


assistant: ```c
int main() {
  int fact, i, n, m;
  fact = 1;
  for (n = 10; n > 0; n--) {
    fact = fact * n;
  }
  printf("!10 = %d\n", fact);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%eax
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L7:
  imul   %eax,%esi
  sub    $0x1,%eax
  jne    L7
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: !10 = %d


assistant: ```c
int main() {
  int fact, i, n, m;
  fact = 1;
  for (n = 10; n > 0; n--) {
    fact = fact * n;
  }
  printf("!10 = %d\n", fact);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x375f00,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
datatype: string

tool: D1: !10 = %d


assistant: ```c
int main() {
  int fact, i, n, m;
  fact = 1;
  for (n = 10; n > 0; n--) {
    fact = fact * n;
  }
  printf("!10 = %d\n", fact);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x20(%rbp)
  movl   $0xc8,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  movsbl %al,%eax
  mov    $0x64,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    -0x1c(%rbp),%eax
  movsbl %al,%eax
  mov    $0xc8,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    -0x18(%rbp),%eax
  movsbl %al,%eax
  mov    $0x64,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    -0x14(%rbp),%eax
  movsbl %al,%eax
  mov    $0xc8,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  mov    -0x10(%rbp),%eax
  movsbl %al,%eax
  mov    $0xc8,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  movl   $0x64,-0x28(%rbp)
  movl   $0xc8,-0x24(%rbp)
  movzbl -0x28(%rbp),%eax
  movsbl %al,%eax
  mov    $0x64,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  movzbl -0x24(%rbp),%eax
  movsbl %al,%eax
  mov    $0xc8,%esi
  mov    %eax,%edi
  call   <expecti@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void test() {
  struct incomplete;
  struct s {
    int a;
    int b;
    int array[3];
  } d;
  d.a = 100;
  d.b = 200;
  d.array[0] = d.a;
  d.array[1] = d.b;
  d.array[2] = d.array[1];
  expecti(d.a, 100);
  expecti(d.b, 200);
  expecti(d.array[0], 100);
  expecti(d.array[1], 200);
  expecti(d.array[2], 200);
  struct {
    union {
      struct {
        int x;
        int y;
      };
      struct {
        char data[8];
      };
    };
  } a;
  a.x = 100;
  a.y = 200;
  expecti(a.data[0], 100);
  expecti(a.data[4], 200);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test() {
  struct incomplete;
  struct s {
    int a;
    int b;
    int array[3];
  } d;
  d.a = 100;
  d.b = 200;
  d.array[0] = d.a;
  d.array[1] = d.b;
  d.array[2] = d.array[1];
  expecti(d.a, 100);
  expecti(d.b, 200);
  expecti(d.array[0], 100);
  expecti(d.array[1], 200);
  expecti(d.array[2], 200);
  struct {
    union {
      struct {
        int x;
        int y;
      };
      struct {
        char data[8];
      };
    };
  } a;
  a.x = 100;
  a.y = 200;
  expecti(a.data[0], 100);
  expecti(a.data[4], 200);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  add    $0x8,%rsp
  jmp    1050 <expecti@plt>
```

assistant: ```c
void test() {
  struct incomplete;
  struct s {
    int a;
    int b;
    int array[3];
  } d;
  d.a = 100;
  d.b = 200;
  d.array[0] = d.a;
  d.array[1] = d.b;
  d.array[2] = d.array[1];
  expecti(d.a, 100);
  expecti(d.b, 200);
  expecti(d.array[0], 100);
  expecti(d.array[1], 200);
  expecti(d.array[2], 200);
  struct {
    union {
      struct {
        int x;
        int y;
      };
      struct {
        char data[8];
      };
    };
  } a;
  a.x = 100;
  a.y = 200;
  expecti(a.data[0], 100);
  expecti(a.data[4], 200);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  call   <expecti@plt>
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <expecti@plt>
  mov    $0xc8,%esi
  mov    $0xffffffc8,%edi
  add    $0x8,%rsp
  jmp    1050 <expecti@plt>
```

assistant: ```c
void test() {
  struct incomplete;
  struct s {
    int a;
    int b;
    int array[3];
  } d;
  d.a = 100;
  d.b = 200;
  d.array[0] = d.a;
  d.array[1] = d.b;
  d.array[2] = d.array[1];
  expecti(d.a, 100);
  expecti(d.b, 200);
  expecti(d.array[0], 100);
  expecti(d.array[1], 200);
  expecti(d.array[2], 200);
  struct {
    union {
      struct {
        int x;
        int y;
      };
      struct {
        char data[8];
      };
    };
  } a;
  a.x = 100;
  a.y = 200;
  expecti(a.data[0], 100);
  expecti(a.data[4], 200);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string

tool: D2: PyCharlockHolmes


assistant: ```c
int main() {
  printf("PyCharlockHolmes\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: PyCharlockHolmes


assistant: ```c
int main() {
  printf("PyCharlockHolmes\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: PyCharlockHolmes


assistant: ```c
int main() {
  printf("PyCharlockHolmes\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: PyCharlockHolmes


assistant: ```c
int main() {
  printf("PyCharlockHolmes\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<qt_internal_get_env_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x59,%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <check_info@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <qt_internal_envstr@plt>
  leave
  ret
```

assistant: ```c
const char __attribute__((visibility("hidden"))) * qt_internal_get_env_str(const char *envariable, const char *dflt) {
  assert(strlen(envariable) < 90);
  check_info();
  return qt_internal_envstr(envariable, dflt);
}
```