ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<XmeXpmGetErrorString>:
  endbr64
  add    $0x4,%edi
  cmp    $0x5,%edi
  ja     L9
  lea    D63(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
  lea    D7(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D33(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D37(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D61(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D25(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D69(%rip),%rax
  ret
L9:
  lea    D49(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string
name: disassemble_data
arguments: data_label: D33
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D61
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D69
datatype: string
name: disassemble_data
arguments: data_label: D49
datatype: string

tool: D7: XpmSuccess

tool: D33: XpmColorError

tool: D37: XpmOpenFailed

tool: D61: XpmColorFailed

tool: D25: XpmNoMemory

tool: D69: XpmFileInvalid

tool: D49: Invalid XpmError

assistant: ```c
char *XmeXpmGetErrorString(errcode)
int errcode;
{
  switch (errcode) {
  case 1:
    return ("XpmColorError");
  case 0:
    return ("XpmSuccess");
  case -1:
    return ("XpmOpenFailed");
  case -2:
    return ("XpmFileInvalid");
  case -3:
    return ("XpmNoMemory");
  case -4:
    return ("XpmColorFailed");
  default:
    return ("Invalid XpmError");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<XmeXpmGetErrorString>:
  endbr64
  add    $0x4,%edi
  cmp    $0x5,%edi
  ja     L6
  lea    D21(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   (%rax)
  lea    D33(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D60(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D70(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D25(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D68(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D31(%rip),%rax
  ret
L6:
  lea    D10(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D33
datatype: string
name: read_data
arguments: data_tag: D60
datatype: string
name: read_data
arguments: data_tag: D70
datatype: string
name: read_data
arguments: data_tag: D25
datatype: string
name: read_data
arguments: data_tag: D68
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string

tool: D33: XpmSuccess

tool: D60: XpmColorError

tool: D70: XpmOpenFailed

tool: D25: XpmColorFailed

tool: D68: XpmNoMemory

tool: D31: XpmFileInvalid

tool: D10: Invalid XpmError

assistant: ```c
char *XmeXpmGetErrorString(errcode)
int errcode;
{
  switch (errcode) {
  case 1:
    return ("XpmColorError");
  case 0:
    return ("XpmSuccess");
  case -1:
    return ("XpmOpenFailed");
  case -2:
    return ("XpmFileInvalid");
  case -3:
    return ("XpmNoMemory");
  case -4:
    return ("XpmColorFailed");
  default:
    return ("Invalid XpmError");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<output_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bit_output@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0xf,-0x4(%rbp)
  jle    L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void output_all(struct gpio *gp) {
  int i;
  for (i = 0; i < 16; i++)
    bit_output(gp, i);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<output_all>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <bit_output@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_all(struct gpio *gp) {
  int i;
  for (i = 0; i < 16; i++)
    bit_output(gp, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_all>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <bit_output@plt>
  cmp    $0x10,%ebx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_all(struct gpio *gp) {
  int i;
  for (i = 0; i < 16; i++)
    bit_output(gp, i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_all>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nop
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <bit_output@plt>
  cmp    $0x10,%ebx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void output_all(struct gpio *gp) {
  int i;
  for (i = 0; i < 16; i++)
    bit_output(gp, i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L55
  mov    $0x1,%eax
  jmp    L9
L55:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  mov    $0x0,%eax
  jmp    L9
L19:
  movl   $0x3,-0x4(%rbp)
  jmp    L68
L48:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L9
L8:
  addl   $0x2,-0x4(%rbp)
L68:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L48
  mov    $0x1,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int isprime(int n) {
  int j;
  if (n == 2)
    return 1;
  if (n % 2 == 0)
    return 0;
  for (j = 3; j * j <= n; j += 2)
    if (n % j == 0)
      return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isprime>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L51
  mov    $0x0,%eax
  test   $0x1,%dil
  je     L51
  cmp    $0x8,%edi
  jle    L42
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  mov    %edi,%eax
  sub    %edx,%eax
  je     L51
  mov    $0x3,%ecx
L4:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L25
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L4
L51:
  ret
L25:
  mov    $0x1,%eax
  ret
L42:
  mov    $0x1,%eax
  jmp    L51
```

assistant: ```c
int isprime(int n) {
  int j;
  if (n == 2)
    return 1;
  if (n % 2 == 0)
    return 0;
  for (j = 3; j * j <= n; j += 2)
    if (n % j == 0)
      return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isprime>:
  endbr64
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L69
  xor    %edx,%edx
  test   $0x1,%dil
  je     L69
  cmp    $0x8,%edi
  jle    L50
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %edi,%edx
  sub    %eax,%edx
  je     L69
  mov    $0x3,%ecx
  jmp    L1
L35:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L69
L1:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L35
L50:
  mov    $0x1,%edx
L69:
  mov    %edx,%eax
  ret
```

assistant: ```c
int isprime(int n) {
  int j;
  if (n == 2)
    return 1;
  if (n % 2 == 0)
    return 0;
  for (j = 3; j * j <= n; j += 2)
    if (n % j == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isprime>:
  endbr64
  mov    $0x1,%edx
  cmp    $0x2,%edi
  je     L42
  xor    %edx,%edx
  test   $0x1,%dil
  je     L42
  cmp    $0x8,%edi
  jle    L2
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x55555556,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  mov    %edi,%edx
  sub    %eax,%edx
  je     L42
  mov    $0x3,%ecx
  jmp    L28
L51:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L42
L28:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L51
L2:
  mov    $0x1,%edx
L42:
  mov    %edx,%eax
  ret
```

assistant: ```c
int isprime(int n) {
  int j;
  if (n == 2)
    return 1;
  if (n % 2 == 0)
    return 0;
  for (j = 3; j * j <= n; j += 2)
    if (n % j == 0)
      return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exec_simple_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %rdi,-0x2028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x201c(%rbp)
  mov    -0x2028(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %eax,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strtok@plt>
  mov    %rax,-0x2018(%rbp)
  jmp    L3
L28:
  mov    -0x201c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x201c(%rbp)
  cltq
  mov    -0x2018(%rbp),%rdx
  mov    %rdx,-0x2010(%rbp,%rax,8)
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x2018(%rbp)
L3:
  cmpq   $0x0,-0x2018(%rbp)
  jne    L28
  mov    -0x201c(%rbp),%eax
  cltq
  movq   $0x0,-0x2010(%rbp,%rax,8)
  mov    -0x2010(%rbp),%rax
  lea    -0x2010(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string

tool: D19:  	

assistant: ```c
void exec_simple_command(const char *command) {
  char *av[1024];
  int ac = 0;
  char *token = strtok(strdup(command), " \t");
  while (token) {
    av[ac++] = token;
    token = strtok(0, " \t");
  }
  av[ac] = 0;
  execvp(av[0], av);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exec_simple_command>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %eax,%edi
  lea    D1(%rip),%rsi
  call   <strtok@plt>
  test   %rax,%rax
  je     L21
  mov    $0x1,%ebx
  lea    D1(%rip),%r12
L20:
  mov    %ebx,%ebp
  mov    %rax,-0x8(%rsp,%rbx,8)
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L20
L23:
  movslq %ebp,%rbp
  movq   $0x0,(%rsp,%rbp,8)
  mov    %rsp,%rsi
  mov    (%rsp),%rdi
  call   <execvp@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0x0,%ebp
  jmp    L23
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1:  	

assistant: ```c
void exec_simple_command(const char *command) {
  char *av[1024];
  int ac = 0;
  char *token = strtok(strdup(command), " \t");
  while (token) {
    av[ac++] = token;
    token = strtok(0, " \t");
  }
  av[ac] = 0;
  execvp(av[0], av);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<exec_simple_command>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D3(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strtok@plt>
  test   %rax,%rax
  je     L35
  mov    $0x1,%ebx
  mov    %rsp,%r13
  nopl   0x0(%rax)
L22:
  mov    %r12,%rsi
  xor    %edi,%edi
  mov    %rax,-0x8(%r13,%rbx,8)
  movslq %ebx,%rbp
  call   <strtok@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L22
L34:
  movq   $0x0,(%rsp,%rbp,8)
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <execvp@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  xor    %ebp,%ebp
  mov    %rsp,%r13
  jmp    L34
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3:  	

assistant: ```c
void exec_simple_command(const char *command) {
  char *av[1024];
  int ac = 0;
  char *token = strtok(strdup(command), " \t");
  while (token) {
    av[ac++] = token;
    token = strtok(0, " \t");
  }
  av[ac] = 0;
  execvp(av[0], av);
}
```
user: What is the c source code of the assembly code below:

```asm
<exec_simple_command>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  lea    D0(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <strtok@plt>
  test   %rax,%rax
  je     L22
  mov    $0x1,%ebx
  mov    %rsp,%r13
  nopl   0x0(%rax)
L9:
  mov    %r12,%rsi
  xor    %edi,%edi
  mov    %rax,-0x8(%r13,%rbx,8)
  movslq %ebx,%rbp
  call   <strtok@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  jne    L9
L8:
  movq   $0x0,(%rsp,%rbp,8)
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <execvp@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x2018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  xor    %ebp,%ebp
  mov    %rsp,%r13
  jmp    L8
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0:  	

assistant: ```c
void exec_simple_command(const char *command) {
  char *av[1024];
  int ac = 0;
  char *token = strtok(strdup(command), " \t");
  while (token) {
    av[ac++] = token;
    token = strtok(0, " \t");
  }
  av[ac] = 0;
  execvp(av[0], av);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mini_snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <mini_vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mini_snprintf(char *buffer, unsigned int buffer_len, const char *fmt, ...) {
  int ret;
  va_list va;
  va_start(va, fmt);
  ret = mini_vsnprintf(buffer, buffer_len, fmt, va);
  va_end(va);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mini_snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <mini_vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int mini_snprintf(char *buffer, unsigned int buffer_len, const char *fmt, ...) {
  int ret;
  va_list va;
  va_start(va, fmt);
  ret = mini_vsnprintf(buffer, buffer_len, fmt, va);
  va_end(va);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mini_snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mini_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mini_snprintf(char *buffer, unsigned int buffer_len, const char *fmt, ...) {
  int ret;
  va_list va;
  va_start(va, fmt);
  ret = mini_vsnprintf(buffer, buffer_len, fmt, va);
  va_end(va);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mini_snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <mini_vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mini_snprintf(char *buffer, unsigned int buffer_len, const char *fmt, ...) {
  int ret;
  va_list va;
  va_start(va, fmt);
  ret = mini_vsnprintf(buffer, buffer_len, fmt, va);
  va_end(va);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<popcount4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L39:
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L23:
  mov    -0x4(%rbp),%eax
  and    $0x1010101,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  shrl   -0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
L15:
  cmpl   $0x7,-0x10(%rbp)
  jle    L23
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x8,%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  ja     L39
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int popcount4(unsigned *lista, unsigned len) {
  int i, j, res = 0, val;
  unsigned x;
  for (i = 0; i < len; i++) {
    val = 0;
    x = lista[i];
    for (j = 0; j < 8; j++) {
      val += x & 0x01010101;
      x >>= 1;
    }
    val += (val >> 16);
    val += (val >> 8);
    res += val & 0xFF;
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<popcount4>:
  endbr64
  test   %esi,%esi
  je     L10
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  mov    $0x0,%edi
  mov    $0x0,%r9d
  jmp    L34
L48:
  mov    %ecx,%edx
  sar    $0x10,%edx
  add    %ecx,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  movzbl %al,%eax
  add    %eax,%edi
  add    $0x4,%r8
  cmp    %r10,%r8
  je     L9
L34:
  mov    (%r8),%edx
  mov    $0x8,%eax
  mov    %r9d,%ecx
L4:
  mov    %edx,%esi
  and    $0x1010101,%esi
  add    %esi,%ecx
  shr    %edx
  sub    $0x1,%eax
  jne    L4
  jmp    L48
L10:
  mov    $0x0,%edi
L9:
  mov    %edi,%eax
  ret
```

assistant: ```c
int popcount4(unsigned *lista, unsigned len) {
  int i, j, res = 0, val;
  unsigned x;
  for (i = 0; i < len; i++) {
    val = 0;
    x = lista[i];
    for (j = 0; j < 8; j++) {
      val += x & 0x01010101;
      x >>= 1;
    }
    val += (val >> 16);
    val += (val >> 8);
    res += val & 0xFF;
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<popcount4>:
  endbr64
  test   %esi,%esi
  je     L13
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%r9
  nopl   0x0(%rax,%rax,1)
L1:
  mov    (%rdi),%edx
  mov    $0x8,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L5:
  mov    %edx,%esi
  shr    %edx
  and    $0x1010101,%esi
  add    %esi,%ecx
  sub    $0x1,%eax
  jne    L5
  mov    %ecx,%edx
  add    $0x4,%rdi
  sar    $0x10,%edx
  add    %ecx,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  movzbl %al,%eax
  add    %eax,%r8d
  cmp    %rdi,%r9
  jne    L1
  mov    %r8d,%eax
  ret
L13:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int popcount4(unsigned *lista, unsigned len) {
  int i, j, res = 0, val;
  unsigned x;
  for (i = 0; i < len; i++) {
    val = 0;
    x = lista[i];
    for (j = 0; j < 8; j++) {
      val += x & 0x01010101;
      x >>= 1;
    }
    val += (val >> 16);
    val += (val >> 8);
    res += val & 0xFF;
  }
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  mov    %rax,%rdx
  je     L3
  shr    $0x10,%rdx
  mov    %rax,%rcx
  shr    $0x30,%rcx
  shl    $0x10,%rcx
  movabs $0xffffffff0000ffff,%rdi
  and    %rdi,%rax
  or     %rcx,%rax
  shl    $0x30,%rdx
  movabs $0xffffffffffff,%rcx
  and    %rcx,%rax
  or     %rax,%rdx
L3:
  add    $0x140a2d2a,%rdx
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  char copy12;
  char copy13;
  unsigned short copy15;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          copy11 = *((char *)(&state[local1]) + 7);
          *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
          copy11 = *((char *)(&state[local1]) + 6);
          *((char *)(&state[local1]) + 6) = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = copy11;
          state[0UL] -= state[local1];
        } else {
          copy12 = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy12;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 5);
          *((char *)(&state[0UL]) + 5) = copy12;
          copy13 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy13;
        }
      } else if (state[0UL] > local1) {
        copy15 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy15;
      } else {
        state[0UL] *= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 336211242UL;
  }
}
```