ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UI_Cache_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MainMenu_Cache@plt>
  xor    %eax,%eax
  call   <InGame_Cache@plt>
  xor    %eax,%eax
  call   <ConfirmMenu_Cache@plt>
  xor    %eax,%eax
  call   <PlayerModel_Cache@plt>
  xor    %eax,%eax
  call   <PlayerSettings_Cache@plt>
  xor    %eax,%eax
  call   <Controls_Cache@plt>
  xor    %eax,%eax
  call   <Demos_Cache@plt>
  xor    %eax,%eax
  call   <UI_CinematicsMenu_Cache@plt>
  xor    %eax,%eax
  call   <Preferences_Cache@plt>
  xor    %eax,%eax
  call   <ServerInfo_Cache@plt>
  xor    %eax,%eax
  call   <SpecifyServer_Cache@plt>
  xor    %eax,%eax
  call   <ArenaServers_Cache@plt>
  xor    %eax,%eax
  call   <StartServer_Cache@plt>
  xor    %eax,%eax
  call   <ServerOptions_Cache@plt>
  xor    %eax,%eax
  call   <DriverInfo_Cache@plt>
  xor    %eax,%eax
  call   <GraphicsOptions_Cache@plt>
  xor    %eax,%eax
  call   <UI_DisplayOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SoundOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_NetworkOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPLevelMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPSkillMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPPostgameMenu_Cache@plt>
  xor    %eax,%eax
  call   <TeamMain_Cache@plt>
  xor    %eax,%eax
  call   <UI_AddBots_Cache@plt>
  xor    %eax,%eax
  call   <UI_RemoveBots_Cache@plt>
  xor    %eax,%eax
  call   <UI_SetupMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_BotSelectMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_CDKeyMenu_Cache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    13c0 <UI_ModsMenu_Cache@plt>
```

assistant: ```c
void UI_Cache_f(void) {
  MainMenu_Cache();
  InGame_Cache();
  ConfirmMenu_Cache();
  PlayerModel_Cache();
  PlayerSettings_Cache();
  Controls_Cache();
  Demos_Cache();
  UI_CinematicsMenu_Cache();
  Preferences_Cache();
  ServerInfo_Cache();
  SpecifyServer_Cache();
  ArenaServers_Cache();
  StartServer_Cache();
  ServerOptions_Cache();
  DriverInfo_Cache();
  GraphicsOptions_Cache();
  UI_DisplayOptionsMenu_Cache();
  UI_SoundOptionsMenu_Cache();
  UI_NetworkOptionsMenu_Cache();
  UI_SPLevelMenu_Cache();
  UI_SPSkillMenu_Cache();
  UI_SPPostgameMenu_Cache();
  TeamMain_Cache();
  UI_AddBots_Cache();
  UI_RemoveBots_Cache();
  UI_SetupMenu_Cache();
  UI_BotSelectMenu_Cache();
  UI_CDKeyMenu_Cache();
  UI_ModsMenu_Cache();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UI_Cache_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <MainMenu_Cache@plt>
  xor    %eax,%eax
  call   <InGame_Cache@plt>
  xor    %eax,%eax
  call   <ConfirmMenu_Cache@plt>
  xor    %eax,%eax
  call   <PlayerModel_Cache@plt>
  xor    %eax,%eax
  call   <PlayerSettings_Cache@plt>
  xor    %eax,%eax
  call   <Controls_Cache@plt>
  xor    %eax,%eax
  call   <Demos_Cache@plt>
  xor    %eax,%eax
  call   <UI_CinematicsMenu_Cache@plt>
  xor    %eax,%eax
  call   <Preferences_Cache@plt>
  xor    %eax,%eax
  call   <ServerInfo_Cache@plt>
  xor    %eax,%eax
  call   <SpecifyServer_Cache@plt>
  xor    %eax,%eax
  call   <ArenaServers_Cache@plt>
  xor    %eax,%eax
  call   <StartServer_Cache@plt>
  xor    %eax,%eax
  call   <ServerOptions_Cache@plt>
  xor    %eax,%eax
  call   <DriverInfo_Cache@plt>
  xor    %eax,%eax
  call   <GraphicsOptions_Cache@plt>
  xor    %eax,%eax
  call   <UI_DisplayOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SoundOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_NetworkOptionsMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPLevelMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPSkillMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_SPPostgameMenu_Cache@plt>
  xor    %eax,%eax
  call   <TeamMain_Cache@plt>
  xor    %eax,%eax
  call   <UI_AddBots_Cache@plt>
  xor    %eax,%eax
  call   <UI_RemoveBots_Cache@plt>
  xor    %eax,%eax
  call   <UI_SetupMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_BotSelectMenu_Cache@plt>
  xor    %eax,%eax
  call   <UI_CDKeyMenu_Cache@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    13c0 <UI_ModsMenu_Cache@plt>
```

assistant: ```c
void UI_Cache_f(void) {
  MainMenu_Cache();
  InGame_Cache();
  ConfirmMenu_Cache();
  PlayerModel_Cache();
  PlayerSettings_Cache();
  Controls_Cache();
  Demos_Cache();
  UI_CinematicsMenu_Cache();
  Preferences_Cache();
  ServerInfo_Cache();
  SpecifyServer_Cache();
  ArenaServers_Cache();
  StartServer_Cache();
  ServerOptions_Cache();
  DriverInfo_Cache();
  GraphicsOptions_Cache();
  UI_DisplayOptionsMenu_Cache();
  UI_SoundOptionsMenu_Cache();
  UI_NetworkOptionsMenu_Cache();
  UI_SPLevelMenu_Cache();
  UI_SPSkillMenu_Cache();
  UI_SPPostgameMenu_Cache();
  TeamMain_Cache();
  UI_AddBots_Cache();
  UI_RemoveBots_Cache();
  UI_SetupMenu_Cache();
  UI_BotSelectMenu_Cache();
  UI_CDKeyMenu_Cache();
  UI_ModsMenu_Cache();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x8,(%rax)
  mov    -0x1c(%rbp),%eax
  cmp    $0x8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a;
  unsigned long iptr = (unsigned long)&a;
  int *p = (int *)iptr;
  *p = 8;
  test_assert(a == 8);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a;
  unsigned long iptr = (unsigned long)&a;
  int *p = (int *)iptr;
  *p = 8;
  test_assert(a == 8);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a;
  unsigned long iptr = (unsigned long)&a;
  int *p = (int *)iptr;
  *p = 8;
  test_assert(a == 8);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <test_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int a;
  unsigned long iptr = (unsigned long)&a;
  int *p = (int *)iptr;
  *p = 8;
  test_assert(a == 8);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L42
L36:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L59
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L59:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L46
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L46:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L51
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L51:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  addl   $0x1,-0x4(%rbp)
L42:
  cmpl   $0x64,-0x4(%rbp)
  jle    L36
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
datatype: string
name: read_data
arguments: data_tag: D38
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D23: FizzBuzz

tool: D38: Fizz

tool: D24: Buzz

tool: D17: %i


assistant: ```c
int main() {
  for (int i = 1; i < 101; ++i) {
    if (i % 15 == 0)
      printf("%s\n", "FizzBuzz");
    else if (i % 3 == 0)
      printf("%s\n", "Fizz");
    else if (i % 5 == 0)
      printf("%s\n", "Buzz");
    else
      printf("%i\n", i);
  }
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D7(%rip),%r13
  lea    D28(%rip),%r12
  lea    D20(%rip),%r14
  lea    D30(%rip),%rbp
  jmp    L8
L47:
  mov    %rbp,%rdi
  call   <puts@plt>
L22:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L45
L8:
  movslq %ebx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x3,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %eax,%edx
  cmp    %edx,%ebx
  je     L47
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L2
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L15
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L22
L2:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L22
L15:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L45:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D20
datatype: string
name: parse_data
arguments: data_label: D30
datatype: string

tool: D7: %i


tool: D28: Buzz

tool: D20: Fizz

tool: D30: FizzBuzz

assistant: ```c
int main() {
  for (int i = 1; i < 101; ++i) {
    if (i % 15 == 0)
      printf("%s\n", "FizzBuzz");
    else if (i % 3 == 0)
      printf("%s\n", "Fizz");
    else if (i % 5 == 0)
      printf("%s\n", "Buzz");
    else
      printf("%i\n", i);
  }
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  lea    D31(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D30(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L9
  nop
L31:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L21
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L6
  mov    %r12,%rdi
  call   <puts@plt>
L64:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L66
L9:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L31
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L9
L66:
  xor    %eax,%eax
  call   <getchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L64
  xchg   %ax,%ax
L21:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L64
```

tool_calls: name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D28
type_guessed: string
name: retrieve_data
arguments: tag: D30
type_guessed: string

tool: D31: Fizz

tool: D8: %i


tool: D28: Buzz

tool: D30: FizzBuzz

assistant: ```c
int main() {
  for (int i = 1; i < 101; ++i) {
    if (i % 15 == 0)
      printf("%s\n", "FizzBuzz");
    else if (i % 3 == 0)
      printf("%s\n", "Fizz");
    else if (i % 5 == 0)
      printf("%s\n", "Buzz");
    else
      printf("%i\n", i);
  }
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L13
  nop
L76:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L0
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L18
  mov    %r12,%rdi
  call   <puts@plt>
L49:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L47
L13:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L76
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L13
L47:
  xor    %eax,%eax
  call   <getchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L18:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
  xchg   %ax,%ax
L0:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L49
```

tool_calls: name: disassemble_data
arguments: label: D7
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D38
type: string
name: disassemble_data
arguments: label: D11
type: string

tool: D7: Fizz

tool: D23: %i


tool: D38: Buzz

tool: D11: FizzBuzz

assistant: ```c
int main() {
  for (int i = 1; i < 101; ++i) {
    if (i % 15 == 0)
      printf("%s\n", "FizzBuzz");
    else if (i % 3 == 0)
      printf("%s\n", "Fizz");
    else if (i % 5 == 0)
      printf("%s\n", "Buzz");
    else
      printf("%i\n", i);
  }
  getchar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<decimal5_opt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L9
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int decimal5_opt(int *x) {
  int val = 0;
  int *xend = x + 4;
  do {
    val = (10 * val) + *x;
    x++;
  } while (x <= xend);
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<decimal5_opt>:
  endbr64
  lea    0x14(%rdi),%rcx
  mov    $0x0,%eax
L9:
  lea    (%rax,%rax,4),%edx
  mov    (%rdi),%eax
  lea    (%rax,%rdx,2),%eax
  add    $0x4,%rdi
  cmp    %rcx,%rdi
  jne    L9
  ret
```

assistant: ```c
int decimal5_opt(int *x) {
  int val = 0;
  int *xend = x + 4;
  do {
    val = (10 * val) + *x;
    x++;
  } while (x <= xend);
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decimal5_opt>:
  endbr64
  lea    0x14(%rdi),%rcx
  xor    %eax,%eax
L8:
  lea    (%rax,%rax,4),%edx
  mov    (%rdi),%eax
  add    $0x4,%rdi
  lea    (%rax,%rdx,2),%eax
  cmp    %rcx,%rdi
  jne    L8
  ret
```

assistant: ```c
int decimal5_opt(int *x) {
  int val = 0;
  int *xend = x + 4;
  do {
    val = (10 * val) + *x;
    x++;
  } while (x <= xend);
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<decimal5_opt>:
  endbr64
  mov    (%rdi),%eax
  lea    (%rax,%rax,4),%edx
  mov    0x4(%rdi),%eax
  lea    (%rax,%rdx,2),%eax
  lea    (%rax,%rax,4),%edx
  mov    0x8(%rdi),%eax
  lea    (%rax,%rdx,2),%eax
  lea    (%rax,%rax,4),%edx
  mov    0xc(%rdi),%eax
  lea    (%rax,%rdx,2),%eax
  lea    (%rax,%rax,4),%edx
  mov    0x10(%rdi),%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int decimal5_opt(int *x) {
  int val = 0;
  int *xend = x + 4;
  do {
    val = (10 * val) + *x;
    x++;
  } while (x <= xend);
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<buffer_reserve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <buffer_extendby@plt>
  test   %rax,%rax
  jns    L19
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L6
L19:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int buffer_reserve(struct buffer *buf, size_t reserve) {
  if (buffer_extendby(buf, reserve) < 0)
    return -errno;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buffer_reserve>:
  endbr64
  sub    $0x8,%rsp
  call   <buffer_extendby@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L10
L8:
  add    $0x8,%rsp
  ret
L10:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L8
```

assistant: ```c
int buffer_reserve(struct buffer *buf, size_t reserve) {
  if (buffer_extendby(buf, reserve) < 0)
    return -errno;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<buffer_reserve>:
  endbr64
  sub    $0x8,%rsp
  call   <buffer_extendby@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L9
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L9:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  neg    %eax
  ret
```

assistant: ```c
int buffer_reserve(struct buffer *buf, size_t reserve) {
  if (buffer_extendby(buf, reserve) < 0)
    return -errno;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<buffer_reserve>:
  endbr64
  sub    $0x8,%rsp
  call   <buffer_extendby@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L1
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L1:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  neg    %eax
  ret
```

assistant: ```c
int buffer_reserve(struct buffer *buf, size_t reserve) {
  if (buffer_extendby(buf, reserve) < 0)
    return -errno;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<neg_nums_in_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x24(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mat_to_arr@plt>
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L5
  addl   $0x1,-0x8(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jbe    L16
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int neg_nums_in_row(int *arr, int row, unsigned int rows, unsigned int columns) {
  int res = 0;
  for (unsigned int col = 1; col <= columns; col++)
    if (arr[mat_to_arr(row, col, columns)] < 0)
      res++;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<neg_nums_in_row>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %ecx,%ecx
  je     L13
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %ecx,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%r12d
L21:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <mat_to_arr@plt>
  cmpl   $0x80000000,0x0(%r13,%rax,4)
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jae    L21
L12:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0x0,%r12d
  jmp    L12
```

assistant: ```c
unsigned int neg_nums_in_row(int *arr, int row, unsigned int rows, unsigned int columns) {
  int res = 0;
  for (unsigned int col = 1; col <= columns; col++)
    if (arr[mat_to_arr(row, col, columns)] < 0)
      res++;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<neg_nums_in_row>:
  endbr64
  test   %ecx,%ecx
  je     L19
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    $0x1,%ebx
L15:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r14d,%edi
  call   <mat_to_arr@plt>
  cmpl   $0x80000000,0x0(%r13,%rax,4)
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jae    L15
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int neg_nums_in_row(int *arr, int row, unsigned int rows, unsigned int columns) {
  int res = 0;
  for (unsigned int col = 1; col <= columns; col++)
    if (arr[mat_to_arr(row, col, columns)] < 0)
      res++;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<neg_nums_in_row>:
  endbr64
  test   %ecx,%ecx
  je     L2
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    $0x1,%ebx
L12:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r14d,%edi
  call   <mat_to_arr@plt>
  cmpl   $0x80000000,0x0(%r13,%rax,4)
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jae    L12
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int neg_nums_in_row(int *arr, int row, unsigned int rows, unsigned int columns) {
  int res = 0;
  for (unsigned int col = 1; col <= columns; col++)
    if (arr[mat_to_arr(row, col, columns)] < 0)
      res++;
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<btff_perror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L2
L1:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    $0x1,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: 


assistant: ```c
void btff_perror(const char *s) {
  for (; *s; s++)
    write(2, s, 1);
  write(1, "\n", 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<btff_perror>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L16
L2:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L2
L16:
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: 


assistant: ```c
void btff_perror(const char *s) {
  for (; *s; s++)
    write(2, s, 1);
  write(1, "\n", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<btff_perror>:
  endbr64
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rdi,%rbx
  nopl   (%rax)
L17:
  mov    %rbx,%rsi
  mov    $0x1,%edx
  mov    $0x2,%edi
  add    $0x1,%rbx
  call   <write@plt>
  cmpb   $0x0,(%rbx)
  jne    L17
L14:
  mov    $0x1,%edx
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1050 <write@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: 


assistant: ```c
void btff_perror(const char *s) {
  for (; *s; s++)
    write(2, s, 1);
  write(1, "\n", 1);
}
```