ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_argv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L2
  lea    -0x2(%rdi),%eax
  mov    %rdx,%r14
  mov    %rcx,%r15
  xor    %ebp,%ebp
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  jmp    L58
  nopl   0x0(%rax)
L4:
  mov    (%r15),%eax
  mov    %rbp,%rdi
  add    $0x8,%rbx
  lea    0x8(,%rax,8),%esi
  call   <realloc@plt>
  movslq (%r15),%r12
  mov    -0x8(%rbx),%rdi
  mov    %rax,%rbp
  lea    0x1(%r12),%eax
  mov    %eax,(%r15)
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%r12,8)
  cmp    %rbx,%r13
  je     L18
L58:
  mov    (%rbx),%rax
  cmpb   $0x2d,(%rax)
  jne    L4
  add    $0x8,%rbx
  movl   $0x1,(%r14)
  cmp    %rbx,%r13
  jne    L58
L18:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  xor    %ebp,%ebp
  jmp    L18
```

assistant: ```c
char **parse_argv(int argc, char *argv[], int *or_flag, int *search_words_cnt) {
  char **search_words = NULL;
  for (int i = 1; i < argc; i++) {
    if (argv[i][0] == '-') {
      *or_flag = 1;
      continue;
    } else {
      search_words = (char **)realloc(search_words, ((*search_words_cnt) + 1) * sizeof(char *));
      search_words[(*search_words_cnt)++] = strdup(argv[i]);
    }
  }
  return search_words;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d 

assistant: ```c
void print_array(int *l, int len) {
  int c;
  for (c = 0; c < len; c++) {
    printf("%d ", l[c]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D7(%rip),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L7
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: %d 

assistant: ```c
void print_array(int *l, int len) {
  int c;
  for (c = 0; c < len; c++) {
    printf("%d ", l[c]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string

tool: D7: %d 

assistant: ```c
void print_array(int *l, int len) {
  int c;
  for (c = 0; c < len; c++) {
    printf("%d ", l[c]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: %d 

assistant: ```c
void print_array(int *l, int len) {
  int c;
  for (c = 0; c < len; c++) {
    printf("%d ", l[c]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<fa_get_subband_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L10
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L19
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float fa_get_subband_power(float *X, int kmin, int kmax) {
  int k;
  float Px;
  Px = 0.0;
  for (k = kmin; k <= kmax; k++)
    Px += X[k] * X[k];
  return Px;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fa_get_subband_power>:
  endbr64
  cmp    %edx,%esi
  jg     L10
  movslq %esi,%rcx
  lea    (%rdi,%rcx,4),%rax
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm1,%xmm1
L3:
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
L29:
  movaps %xmm1,%xmm0
  ret
L10:
  pxor   %xmm1,%xmm1
  jmp    L29
```

assistant: ```c
float fa_get_subband_power(float *X, int kmin, int kmax) {
  int k;
  float Px;
  Px = 0.0;
  for (k = kmin; k <= kmax; k++)
    Px += X[k] * X[k];
  return Px;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fa_get_subband_power>:
  endbr64
  cmp    %edx,%esi
  jg     L4
  movslq %esi,%rcx
  sub    %esi,%edx
  pxor   %xmm1,%xmm1
  add    %rcx,%rdx
  lea    (%rdi,%rcx,4),%rax
  lea    0x4(%rdi,%rdx,4),%rdx
  nopl   (%rax)
L19:
  movss  (%rax),%xmm0
  add    $0x4,%rax
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L19
  movaps %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L4:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float fa_get_subband_power(float *X, int kmin, int kmax) {
  int k;
  float Px;
  Px = 0.0;
  for (k = kmin; k <= kmax; k++)
    Px += X[k] * X[k];
  return Px;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fa_get_subband_power>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  mov    %edx,%edi
  cmp    %edx,%esi
  jg     L41
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%r9d
  cmp    $0x2,%eax
  jbe    L57
  movslq %esi,%rax
  pxor   %xmm0,%xmm0
  lea    (%r8,%rax,4),%rdx
  mov    %r9d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L49
  nopl   (%rax)
L22:
  add    $0x10,%rax
L49:
  movups (%rdx),%xmm1
  mov    %rax,%rdx
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L22
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%ecx
  cmp    %eax,%r9d
  je     L25
L64:
  movslq %ecx,%rax
  movss  (%r8,%rax,4),%xmm1
  lea    0x0(,%rax,4),%rdx
  lea    0x1(%rcx),%eax
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%edi
  jl     L74
  movss  0x4(%r8,%rdx,1),%xmm1
  add    $0x2,%ecx
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %ecx,%edi
  jl     L74
  movss  0x8(%r8,%rdx,1),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L41:
  pxor   %xmm0,%xmm0
L74:
  ret
  nopl   (%rax)
L25:
  ret
L57:
  pxor   %xmm0,%xmm0
  jmp    L64
```

assistant: ```c
float fa_get_subband_power(float *X, int kmin, int kmax) {
  int k;
  float Px;
  Px = 0.0;
  for (k = kmin; k <= kmax; k++)
    Px += X[k] * X[k];
  return Px;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<utf8_to_latin1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L27
  mov    %eax,%r9d
  mov    %rbx,%rsi
  mov    $0x1,%ecx
  mov    $0x0,%edx
  jmp    L92
L72:
  mov    %ecx,%edi
  movb   $0x2e,(%rsi)
L60:
  add    $0x1,%edx
  add    $0x1,%ecx
  add    $0x1,%rsi
  cmp    %edx,%r9d
  jle    L156
L92:
  lea    -0x1(%rcx),%r10d
  movslq %edx,%rdi
  movzbl (%rbx,%rdi,1),%eax
  lea    -0x80(%rax),%r8d
  cmp    $0x3f,%r8b
  jbe    L72
  cmp    $0x1f,%al
  jbe    L72
  cmp    $0xdf,%al
  ja     L79
  mov    %eax,%r8d
  and    $0xffffffe0,%r8d
  cmp    $0xc0,%r8b
  je     L138
  mov    %ecx,%edi
  mov    %al,(%rsi)
  jmp    L60
L79:
  movslq %r10d,%r10
  movb   $0x0,(%rbx,%r10,1)
  jmp    L27
L138:
  add    $0x1,%edx
  cmp    %r9d,%edx
  je     L50
  mov    %eax,%r8d
  and    $0xfffffffc,%r8d
  cmp    $0xc0,%r8b
  jne    L96
  lea    0x1(%rbx,%rdi,1),%r8
  movzbl (%r8),%edi
  and    $0xffffffc0,%edi
  cmp    $0x80,%dil
  je     L106
  movslq %r10d,%r10
  movb   $0x0,(%rbx,%r10,1)
L27:
  pop    %rbx
  ret
L50:
  movslq %r10d,%r10
  movb   $0x0,(%rbx,%r10,1)
  jmp    L27
L96:
  mov    %ecx,%edi
  movb   $0x2e,(%rsi)
  jmp    L60
L106:
  shl    $0x6,%eax
  mov    %al,(%rsi)
  movzbl (%r8),%edi
  and    $0x3f,%edi
  add    %edi,%eax
  mov    %al,(%rsi)
  mov    %ecx,%edi
  jmp    L60
L156:
  cmp    %r9d,%edi
  jge    L27
  movslq %edi,%rdi
  movb   $0x0,(%rbx,%rdi,1)
  jmp    L27
```

assistant: ```c
void utf8_to_latin1(char *utf8_str) {
  int i, j, len;
  unsigned char *str;
  str = (unsigned char *)utf8_str;
  len = strlen(utf8_str);
  if (!len) {
    return;
  }
  j = 0;
  for (i = 0; i < len; i++) {
    if ((str[i] < 32) || ((str[i] > 127) && (str[i] < 192))) {
      str[j++] = '.';
      continue;
    }
    if (str[i] > 223) {
      str[j++] = 0;
      return;
    }
    if ((str[i] & 224) == 192) {
      if ((i + 1) == len) {
        str[j++] = 0;
        return;
      }
      if ((str[i] & 252) != 192) {
        str[j++] = '.';
        i++;
        continue;
      }
      if ((str[i + 1] & 192) != 128) {
        str[j++] = 0;
        return;
      }
      str[j] = str[i] << 6;
      str[j] += (str[i + 1] & 63);
      i++;
      j++;
      continue;
    }
    str[j++] = str[i];
  }
  if (j < len) {
    str[j] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<utf8_to_latin1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L85
  mov    %eax,%r9d
  mov    %rbx,%rcx
  mov    $0x1,%esi
  xor    %edx,%edx
  jmp    L112
  nopl   0x0(%rax)
L106:
  add    $0x1,%edx
  mov    %al,(%rcx)
  add    $0x1,%esi
  add    $0x1,%rcx
  cmp    %edx,%r9d
  jle    L41
L112:
  movslq %edx,%rdi
  movzbl (%rbx,%rdi,1),%eax
  lea    -0x80(%rax),%r8d
  cmp    $0x3f,%r8b
  jbe    L39
  cmp    $0x1f,%al
  jbe    L39
  cmp    $0xdf,%al
  ja     L67
  mov    %eax,%r8d
  movslq %esi,%r10
  and    $0xffffffe0,%r8d
  cmp    $0xc0,%r8b
  jne    L106
  add    $0x1,%edx
  cmp    %edx,%r9d
  je     L67
  mov    %eax,%r8d
  and    $0xfffffffc,%r8d
  cmp    $0xc0,%r8b
  je     L79
  mov    $0x2e,%eax
  jmp    L106
  nopw   0x0(%rax,%rax,1)
L39:
  movslq %esi,%r10
  mov    $0x2e,%eax
  jmp    L106
  nopw   0x0(%rax,%rax,1)
L79:
  lea    0x1(%rbx,%rdi,1),%r8
  movzbl (%r8),%edi
  and    $0xffffffc0,%edi
  cmp    $0x80,%dil
  je     L17
L67:
  movb   $0x0,(%rcx)
L85:
  pop    %rbx
  ret
  nop
L17:
  shl    $0x6,%eax
  mov    %al,(%rcx)
  movzbl (%r8),%edi
  and    $0x3f,%edi
  add    %edi,%eax
  jmp    L106
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    %r9d,%r10d
  jge    L85
  movb   $0x0,(%rbx,%r10,1)
  pop    %rbx
  ret
```

assistant: ```c
void utf8_to_latin1(char *utf8_str) {
  int i, j, len;
  unsigned char *str;
  str = (unsigned char *)utf8_str;
  len = strlen(utf8_str);
  if (!len) {
    return;
  }
  j = 0;
  for (i = 0; i < len; i++) {
    if ((str[i] < 32) || ((str[i] > 127) && (str[i] < 192))) {
      str[j++] = '.';
      continue;
    }
    if (str[i] > 223) {
      str[j++] = 0;
      return;
    }
    if ((str[i] & 224) == 192) {
      if ((i + 1) == len) {
        str[j++] = 0;
        return;
      }
      if ((str[i] & 252) != 192) {
        str[j++] = '.';
        i++;
        continue;
      }
      if ((str[i + 1] & 192) != 128) {
        str[j++] = 0;
        return;
      }
      str[j] = str[i] << 6;
      str[j] += (str[i + 1] & 63);
      i++;
      j++;
      continue;
    }
    str[j++] = str[i];
  }
  if (j < len) {
    str[j] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utf8_to_latin1>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L99
  mov    %eax,%r9d
  mov    %rbx,%rcx
  mov    $0x1,%esi
  xor    %edx,%edx
  jmp    L59
  nopl   0x0(%rax)
L32:
  add    $0x1,%edx
  mov    %al,(%rcx)
  add    $0x1,%esi
  add    $0x1,%rcx
  cmp    %edx,%r9d
  jle    L64
L59:
  movslq %edx,%rdi
  movzbl (%rbx,%rdi,1),%eax
  lea    -0x80(%rax),%r8d
  cmp    $0x3f,%r8b
  jbe    L137
  cmp    $0x1f,%al
  jbe    L137
  cmp    $0xdf,%al
  ja     L68
  mov    %eax,%r8d
  movslq %esi,%r10
  and    $0xffffffe0,%r8d
  cmp    $0xc0,%r8b
  jne    L32
  add    $0x1,%edx
  cmp    %edx,%r9d
  je     L68
  mov    %eax,%r8d
  and    $0xfffffffc,%r8d
  cmp    $0xc0,%r8b
  je     L72
  mov    $0x2e,%eax
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L137:
  movslq %esi,%r10
  mov    $0x2e,%eax
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L72:
  lea    0x1(%rbx,%rdi,1),%r8
  movzbl (%r8),%edi
  and    $0xffffffc0,%edi
  cmp    $0x80,%dil
  je     L29
L68:
  movb   $0x0,(%rcx)
L99:
  pop    %rbx
  ret
  nop
L29:
  shl    $0x6,%eax
  mov    %al,(%rcx)
  movzbl (%r8),%edi
  and    $0x3f,%edi
  add    %edi,%eax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L64:
  cmp    %r9d,%r10d
  jge    L99
  movb   $0x0,(%rbx,%r10,1)
  pop    %rbx
  ret
```

assistant: ```c
void utf8_to_latin1(char *utf8_str) {
  int i, j, len;
  unsigned char *str;
  str = (unsigned char *)utf8_str;
  len = strlen(utf8_str);
  if (!len) {
    return;
  }
  j = 0;
  for (i = 0; i < len; i++) {
    if ((str[i] < 32) || ((str[i] > 127) && (str[i] < 192))) {
      str[j++] = '.';
      continue;
    }
    if (str[i] > 223) {
      str[j++] = 0;
      return;
    }
    if ((str[i] & 224) == 192) {
      if ((i + 1) == len) {
        str[j++] = 0;
        return;
      }
      if ((str[i] & 252) != 192) {
        str[j++] = '.';
        i++;
        continue;
      }
      if ((str[i + 1] & 192) != 128) {
        str[j++] = 0;
        return;
      }
      str[j] = str[i] << 6;
      str[j] += (str[i + 1] & 63);
      i++;
      j++;
      continue;
    }
    str[j++] = str[i];
  }
  if (j < len) {
    str[j] = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: user ID = %d, group ID = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("user ID = %d, group ID = %d\n", getuid(), getgid());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: user ID = %d, group ID = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("user ID = %d, group ID = %d\n", getuid(), getgid());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: user ID = %d, group ID = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("user ID = %d, group ID = %d\n", getuid(), getgid());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: user ID = %d, group ID = %d


assistant: ```c
int main(int argc, char **argv) {
  printf("user ID = %d, group ID = %d\n", getuid(), getgid());
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x1a4(%rbp)
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <preenche@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <imprime@plt>
  mov    -0x1a4(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x1a0(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1a4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <imprime@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string

tool: D13: Vetor sem ordenar:


tool: D18: Vetor ordenado:


assistant: ```c
int main() {
  int vetor[100], tamanho = 100;
  preenche(tamanho, vetor);
  printf("Vetor sem ordenar:\n");
  imprime(tamanho, vetor);
  quick(vetor, 0, tamanho - 1);
  printf("Vetor ordenado:\n");
  imprime(tamanho, vetor);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    $0x64,%edi
  call   <preenche@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  mov    $0x63,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quick@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D14: Vetor sem ordenar:


tool: D3: Vetor ordenado:


assistant: ```c
int main() {
  int vetor[100], tamanho = 100;
  preenche(tamanho, vetor);
  printf("Vetor sem ordenar:\n");
  imprime(tamanho, vetor);
  quick(vetor, 0, tamanho - 1);
  printf("Vetor ordenado:\n");
  imprime(tamanho, vetor);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <preenche@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  xor    %esi,%esi
  mov    $0x63,%edx
  mov    %rbp,%rdi
  call   <quick@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D16: Vetor sem ordenar:


tool: D7: Vetor ordenado:


assistant: ```c
int main() {
  int vetor[100], tamanho = 100;
  preenche(tamanho, vetor);
  printf("Vetor sem ordenar:\n");
  imprime(tamanho, vetor);
  quick(vetor, 0, tamanho - 1);
  printf("Vetor ordenado:\n");
  imprime(tamanho, vetor);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%edi
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <preenche@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  xor    %esi,%esi
  mov    $0x63,%edx
  mov    %rbp,%rdi
  call   <quick@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    $0x64,%edi
  call   <imprime@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D1: Vetor sem ordenar:


tool: D19: Vetor ordenado:


assistant: ```c
int main() {
  int vetor[100], tamanho = 100;
  preenche(tamanho, vetor);
  printf("Vetor sem ordenar:\n");
  imprime(tamanho, vetor);
  quick(vetor, 0, tamanho - 1);
  printf("Vetor ordenado:\n");
  imprime(tamanho, vetor);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<devnum2devname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x74(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fmt_devname@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *devnum2devname(int num) {
  char name[100];
  fmt_devname(name, num);
  return strdup(name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<devnum2devname>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <fmt_devname@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x70,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *devnum2devname(int num) {
  char name[100];
  fmt_devname(name, num);
  return strdup(name);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<devnum2devname>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <fmt_devname@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x70,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *devnum2devname(int num) {
  char name[100];
  fmt_devname(name, num);
  return strdup(name);
}
```