user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rdx
  xor    %eax,%eax
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  jle    L80
  lea    0x10(%rsp),%r12
  xor    %r14d,%r14d
  lea    D25(%rip),%r13
  mov    %r12,%r15
  cs nopw 0x0(%rax,%rax,1)
L60:
  mov    0xc(%rsp),%ecx
  mov    %r15,%rbp
  xor    %ebx,%ebx
  test   %ecx,%ecx
  jle    L34
  nopl   (%rax)
L94:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L94
L34:
  mov    0x8(%rsp),%eax
  add    $0x1,%r14
  add    $0x28,%r15
  cmp    %r14d,%eax
  jg     L60
  test   %eax,%eax
  jle    L80
  mov    0xc(%rsp),%r8d
  sub    $0x1,%eax
  lea    0x1a0(%rsp),%rdi
  lea    0x1a4(%rsp,%rax,4),%r9
  lea    -0x1(%r8),%edx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x1c8(%rsp,%rdx,8),%rsi
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rdi,%rax
  mov    %r12,%rdx
  test   %r8d,%r8d
  jle    L104
  nopl   0x0(%rax,%rax,1)
L95:
  mov    (%rdx),%ecx
  add    $0x28,%rax
  add    $0x4,%rdx
  mov    %ecx,-0x28(%rax)
  cmp    %rsi,%rax
  jne    L95
L104:
  add    $0x4,%rdi
  add    $0x28,%r12
  add    $0x4,%rsi
  cmp    %r9,%rdi
  jne    L29
L80:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L119
  lea    0x1a0(%rsp),%rbp
  xor    %r13d,%r13d
  lea    D12(%rip),%r12
  nopl   0x0(%rax)
L63:
  mov    0x8(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jle    L84
  nopw   0x0(%rax,%rax,1)
L118:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L118
L84:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x28,%rbp
  call   <putchar@plt>
  cmp    %r13d,0xc(%rsp)
  jg     L63
L119:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  add    $0x348,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D50
type: string
name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D25
type: string
name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D12
type: string

tool: D4: Enter the number of rows and columns of matrix

tool: D50: %d%d

tool: D6: Enter the elements of matrix

tool: D25: %d

tool: D17: Transposed Matrix :-

tool: D12: %d	

assistant: ```c
int main() {
  int m, n, c, d, matrix[10][10], transpose[10][10];
  printf("Enter the number of rows and columns of matrix\n");
  scanf("%d%d", &m, &n);
  printf("Enter the elements of matrix\n");
  for (c = 0; c < m; c++)
    for (d = 0; d < n; d++)
      scanf("%d", &matrix[c][d]);
  for (c = 0; c < m; c++)
    for (d = 0; d < n; d++)
      transpose[d][c] = matrix[c][d];
  printf("Transposed Matrix :-\n");
  for (c = 0; c < n; c++) {
    for (d = 0; d < m; d++)
      printf("%d\t", transpose[c][d]);
    printf("\n");
  }
  return 0;
}
```