ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movq   $0x0,0xc0(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xc8,%eax
  jg     L13
  mov    %rbp,%rdi
  call   <hash@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D17
type: string

tool: D18: %s

tool: D17: 
 %ld

assistant: ```c
int main() {
  char word[200] = {0};
  do {
    scanf("%s", word);
  } while (strlen(word) > 200);
  printf("\n %ld", hash(word));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movq   $0x0,0xc0(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  nopl   0x0(%rax)
L12:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0xc8,%eax
  jg     L12
  mov    %rbp,%rdi
  call   <hash@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string

tool: D11: %s

tool: D12: 
 %ld

assistant: ```c
int main() {
  char word[200] = {0};
  do {
    scanf("%s", word);
  } while (strlen(word) > 200);
  printf("\n %ld", hash(word));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blinky>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L9:
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x32,%edi
  call   <delay_ms@plt>
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x5dc,%edi
  call   <delay_ms@plt>
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x1e,%edi
  call   <delay_ms@plt>
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x1b58,%edi
  call   <delay_ms@plt>
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x2,-0x4(%rbp)
  jle    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void blinky() {
  int a;
  fill(0x00);
  delay_ms(2000);
  for (a = 0; a < 3; a++) {
    fill(0xff);
    delay_ms(50);
    fill(0x00);
    delay_ms(1500);
    fill(0xff);
    delay_ms(30);
    fill(0x00);
    delay_ms(7000);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<blinky>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
  mov    $0x3,%ebx
L5:
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x32,%edi
  call   <delay_ms@plt>
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x5dc,%edi
  call   <delay_ms@plt>
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x1e,%edi
  call   <delay_ms@plt>
  mov    $0x0,%edi
  call   <fill@plt>
  mov    $0x1b58,%edi
  call   <delay_ms@plt>
  sub    $0x1,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void blinky() {
  int a;
  fill(0x00);
  delay_ms(2000);
  for (a = 0; a < 3; a++) {
    fill(0xff);
    delay_ms(50);
    fill(0x00);
    delay_ms(1500);
    fill(0xff);
    delay_ms(30);
    fill(0x00);
    delay_ms(7000);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<blinky>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  mov    $0x3,%ebx
  call   <fill@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
L8:
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x32,%edi
  call   <delay_ms@plt>
  xor    %edi,%edi
  call   <fill@plt>
  mov    $0x5dc,%edi
  call   <delay_ms@plt>
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x1e,%edi
  call   <delay_ms@plt>
  xor    %edi,%edi
  call   <fill@plt>
  mov    $0x1b58,%edi
  call   <delay_ms@plt>
  sub    $0x1,%ebx
  jne    L8
  pop    %rbx
  ret
```

assistant: ```c
void blinky() {
  int a;
  fill(0x00);
  delay_ms(2000);
  for (a = 0; a < 3; a++) {
    fill(0xff);
    delay_ms(50);
    fill(0x00);
    delay_ms(1500);
    fill(0xff);
    delay_ms(30);
    fill(0x00);
    delay_ms(7000);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blinky>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  mov    $0x3,%ebx
  call   <fill@plt>
  mov    $0x7d0,%edi
  call   <delay_ms@plt>
L0:
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x32,%edi
  call   <delay_ms@plt>
  xor    %edi,%edi
  call   <fill@plt>
  mov    $0x5dc,%edi
  call   <delay_ms@plt>
  mov    $0xff,%edi
  call   <fill@plt>
  mov    $0x1e,%edi
  call   <delay_ms@plt>
  xor    %edi,%edi
  call   <fill@plt>
  mov    $0x1b58,%edi
  call   <delay_ms@plt>
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void blinky() {
  int a;
  fill(0x00);
  delay_ms(2000);
  for (a = 0; a < 3; a++) {
    fill(0xff);
    delay_ms(50);
    fill(0x00);
    delay_ms(1500);
    fill(0xff);
    delay_ms(30);
    fill(0x00);
    delay_ms(7000);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<moving_median>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  cmp    $0x4,%ax
  jg     L6
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  movswq %ax,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  add    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  mov    %cx,(%rdx,%rax,1)
  mov    -0x18(%rbp),%eax
  jmp    L48
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movzwl (%rdx,%rax,1),%eax
  cmp    $0x4,%ax
  je     L22
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L30:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L3:
  cmpl   $0x3,-0x8(%rbp)
  jle    L30
  jmp    L25
L22:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    D16(%rip),%rax
  movw   $0x6,(%rdx,%rax,1)
L25:
  mov    -0x20(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L60
L55:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    D29(%rip),%rdx
  mov    %eax,(%rcx,%rdx,1)
  addl   $0x1,-0x4(%rbp)
L60:
  cmpl   $0x4,-0x4(%rbp)
  jle    L55
  lea    D29(%rip),%rax
  mov    %rax,%rcx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <selection_algorithm@plt>
L48:
  leave
  ret
```

assistant: ```c
int moving_median(int sensor, int current, int *values) {
  static short count[10] = {0};
  static int dupArray[5] = {0};
  if (count[sensor] < 5) {
    values[count[sensor]] = current;
    count[sensor]++;
    return current;
  } else {
    if (count[sensor] != 5 - 1) {
      for (int i = 0; i < (5 - 1); i++) {
        values[i] = values[i + 1];
      }
    } else {
      count[sensor] = 5 + 1;
    }
    values[5 - 1] = current;
    for (int i = 0; i < 5; i++) {
      dupArray[i] = values[i];
    }
    return selection_algorithm(0, 5 - 1, 3, dupArray);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<moving_median>:
  endbr64
  mov    %esi,%eax
  movslq %edi,%rsi
  lea    D11(%rip),%rcx
  movzwl (%rcx,%rsi,2),%ecx
  cmp    $0x4,%cx
  jg     L10
  movswq %cx,%rsi
  mov    %eax,(%rdx,%rsi,4)
  movslq %edi,%rdi
  add    $0x1,%ecx
  lea    D11(%rip),%rdx
  mov    %cx,(%rdx,%rdi,2)
  ret
L10:
  sub    $0x8,%rsp
  mov    0x4(%rdx),%ecx
  mov    %ecx,(%rdx)
  mov    0x8(%rdx),%ecx
  mov    %ecx,0x4(%rdx)
  mov    0xc(%rdx),%ecx
  mov    %ecx,0x8(%rdx)
  mov    0x10(%rdx),%ecx
  mov    %ecx,0xc(%rdx)
  mov    %eax,0x10(%rdx)
  mov    $0x0,%eax
  lea    D20(%rip),%rsi
L13:
  mov    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    $0x14,%rax
  jne    L13
  lea    D20(%rip),%rcx
  mov    $0x3,%edx
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <selection_algorithm@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int moving_median(int sensor, int current, int *values) {
  static short count[10] = {0};
  static int dupArray[5] = {0};
  if (count[sensor] < 5) {
    values[count[sensor]] = current;
    count[sensor]++;
    return current;
  } else {
    if (count[sensor] != 5 - 1) {
      for (int i = 0; i < (5 - 1); i++) {
        values[i] = values[i + 1];
      }
    } else {
      count[sensor] = 5 + 1;
    }
    values[5 - 1] = current;
    for (int i = 0; i < 5; i++) {
      dupArray[i] = values[i];
    }
    return selection_algorithm(0, 5 - 1, 3, dupArray);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<moving_median>:
  endbr64
  mov    %esi,%eax
  movslq %edi,%rdi
  lea    D45(%rip),%rsi
  movzwl (%rsi,%rdi,2),%ecx
  cmp    $0x4,%cx
  jle    L9
  mov    0x4(%rdx),%r8d
  mov    0x8(%rdx),%edi
  mov    0xc(%rdx),%esi
  mov    0x10(%rdx),%ecx
  mov    %eax,0x10(%rdx)
  mov    %r8d,(%rdx)
  mov    %edi,0x4(%rdx)
  mov    %esi,0x8(%rdx)
  mov    %ecx,0xc(%rdx)
  mov    $0x3,%edx
  mov    %edi,D59(%rip)
  xor    %edi,%edi
  mov    %esi,D37(%rip)
  mov    $0x4,%esi
  mov    %ecx,D30(%rip)
  lea    D66(%rip),%rcx
  mov    %r8d,D31(%rip)
  mov    %eax,D31(%rip)
  jmp    1050 <selection_algorithm@plt>
  nopl   (%rax)
L9:
  movswq %cx,%r8
  add    $0x1,%ecx
  mov    %eax,(%rdx,%r8,4)
  mov    %cx,(%rsi,%rdi,2)
  ret
```

assistant: ```c
int moving_median(int sensor, int current, int *values) {
  static short count[10] = {0};
  static int dupArray[5] = {0};
  if (count[sensor] < 5) {
    values[count[sensor]] = current;
    count[sensor]++;
    return current;
  } else {
    if (count[sensor] != 5 - 1) {
      for (int i = 0; i < (5 - 1); i++) {
        values[i] = values[i + 1];
      }
    } else {
      count[sensor] = 5 + 1;
    }
    values[5 - 1] = current;
    for (int i = 0; i < 5; i++) {
      dupArray[i] = values[i];
    }
    return selection_algorithm(0, 5 - 1, 3, dupArray);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<moving_median>:
  endbr64
  mov    %esi,%eax
  movslq %edi,%rdi
  lea    D26(%rip),%rsi
  movzwl (%rsi,%rdi,2),%ecx
  cmp    $0x4,%cx
  jle    L5
  movdqu 0x4(%rdx),%xmm0
  mov    %eax,0x10(%rdx)
  lea    D0(%rip),%rcx
  xor    %edi,%edi
  mov    $0x4,%esi
  movups %xmm0,(%rdx)
  mov    $0x3,%edx
  mov    %eax,D29(%rip)
  movaps %xmm0,D35(%rip)
  jmp    1050 <selection_algorithm@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  movswq %cx,%r8
  add    $0x1,%ecx
  mov    %eax,(%rdx,%r8,4)
  mov    %cx,(%rsi,%rdi,2)
  ret
```

assistant: ```c
int moving_median(int sensor, int current, int *values) {
  static short count[10] = {0};
  static int dupArray[5] = {0};
  if (count[sensor] < 5) {
    values[count[sensor]] = current;
    count[sensor]++;
    return current;
  } else {
    if (count[sensor] != 5 - 1) {
      for (int i = 0; i < (5 - 1); i++) {
        values[i] = values[i + 1];
      }
    } else {
      count[sensor] = 5 + 1;
    }
    values[5 - 1] = current;
    for (int i = 0; i < 5; i++) {
      dupArray[i] = values[i];
    }
    return selection_algorithm(0, 5 - 1, 3, dupArray);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<STC31xx_StopPowerSavingMode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <STC31xx_ReadByte8@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xfffffffe,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <STC31xx_WriteByte8@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  jmp    L19
L9:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int STC31xx_StopPowerSavingMode(void) {
  int res;
  res = STC31xx_ReadByte8(0x00);
  res = STC31xx_WriteByte8(0x00, (res & ~0x01));
  if (res != 0)
    return (res);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<STC31xx_StopPowerSavingMode>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <STC31xx_ReadByte8@plt>
  and    $0xfffffffe,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <STC31xx_WriteByte8@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int STC31xx_StopPowerSavingMode(void) {
  int res;
  res = STC31xx_ReadByte8(0x00);
  res = STC31xx_WriteByte8(0x00, (res & ~0x01));
  if (res != 0)
    return (res);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<STC31xx_StopPowerSavingMode>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <STC31xx_ReadByte8@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  and    $0xfffffffe,%eax
  mov    %eax,%esi
  jmp    1060 <STC31xx_WriteByte8@plt>
```

assistant: ```c
int STC31xx_StopPowerSavingMode(void) {
  int res;
  res = STC31xx_ReadByte8(0x00);
  res = STC31xx_WriteByte8(0x00, (res & ~0x01));
  if (res != 0)
    return (res);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<STC31xx_StopPowerSavingMode>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <STC31xx_ReadByte8@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  and    $0xfffffffe,%eax
  mov    %eax,%esi
  jmp    1060 <STC31xx_WriteByte8@plt>
```

assistant: ```c
int STC31xx_StopPowerSavingMode(void) {
  int res;
  res = STC31xx_ReadByte8(0x00);
  res = STC31xx_WriteByte8(0x00, (res & ~0x01));
  if (res != 0)
    return (res);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dontwarn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dontwarn2(unsigned int U) {
  if (U <= 4294967295) {
  }
  if (U <= (2147483647 * 2U + 1U)) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dontwarn2>:
  endbr64
  ret
```

assistant: ```c
void dontwarn2(unsigned int U) {
  if (U <= 4294967295) {
  }
  if (U <= (2147483647 * 2U + 1U)) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dontwarn2>:
  endbr64
  ret
```

assistant: ```c
void dontwarn2(unsigned int U) {
  if (U <= 4294967295) {
  }
  if (U <= (2147483647 * 2U + 1U)) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dontwarn2>:
  endbr64
  ret
```

assistant: ```c
void dontwarn2(unsigned int U) {
  if (U <= 4294967295) {
  }
  if (U <= (2147483647 * 2U + 1U)) {
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x28,%ebx
  test   %edi,%edi
  je     L78
  mov    0x8(%rsi),%rdi
  test   %rdi,%rdi
  je     L78
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,%rbx
L78:
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %eax,%eax
  jne    L23
  mov    %rbx,%rdi
  call   <fibo_ite@plt>
  mov    %eax,%esi
  test   %rbx,%rbx
  js     L89
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
L59:
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L54
  pxor   %xmm0,%xmm0
  cvtsi2sdq 0x10(%rsp),%xmm0
  movsd  D1(%rip),%xmm2
  divsd  %xmm2,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq 0x18(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdq 0x8(%rsp),%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    %ebx,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L23:
  lea    D20(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%ebx
  jmp    L8
L89:
  mov    %rbx,%rax
  shr    %rax
  and    $0x1,%ebx
  or     %rbx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L59
L54:
  lea    D16(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%ebx
  jmp    L8
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D1
datatype: f64
name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D20
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D7: fibo_ite %lu: %lf


tool: D1: 1000000

tool: D24: %lf elapsed


tool: D20: start gettime error


tool: D16: end gettime error


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int ret = 0;
  struct timeval start, end;
  double s, e;
  unsigned long int n;
  if (argc != 0 && argv[1])
    n = strtoul(argv[1], NULL, 0);
  else
    n = 40;
  ret = gettimeofday(&start, NULL);
  if (ret != 0) {
    perror("start gettime error\n");
    return 1;
  }
  printf("fibo_ite %lu: %lf\n", n, fibo_ite(n));
  ret = gettimeofday(&end, NULL);
  if (ret != 0) {
    perror("end gettime error\n");
    return 1;
  }
  s = (double)start.tv_sec + (double)start.tv_usec / 1000000.0;
  e = (double)end.tv_sec + (double)end.tv_usec / 1000000.0;
  printf("%lf elapsed\n", e - s);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  mov    $0x28,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L58
  mov    0x8(%rsi),%rdi
  test   %rdi,%rdi
  je     L58
  xor    %edx,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %rax,%rbx
L58:
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  test   %eax,%eax
  jne    L61
  mov    %rbx,%rdi
  call   <fibo_ite@plt>
  mov    %eax,%esi
  test   %rbx,%rbx
  js     L17
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
L59:
  lea    D49(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L45
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  movsd  D23(%rip),%xmm2
  lea    D18(%rip),%rdi
  cvtsi2sdq 0x10(%rsp),%xmm0
  mov    $0x1,%eax
  cvtsi2sdq 0x18(%rsp),%xmm1
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rsp),%xmm1
  divsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdq 0x8(%rsp),%xmm2
  addsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  call   <printf@plt>
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L17:
  mov    %rbx,%rax
  and    $0x1,%ebx
  pxor   %xmm0,%xmm0
  shr    %rax
  or     %rbx,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L59
L61:
  lea    D5(%rip),%rdi
  mov    $0x1,%r12d
  call   <perror@plt>
  jmp    L0
L45:
  lea    D26(%rip),%rdi
  mov    $0x1,%r12d
  call   <perror@plt>
  jmp    L0
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D49
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: f64
name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D5
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string

tool: D49: fibo_ite %lu: %lf


tool: D23: 1000000

tool: D18: %lf elapsed


tool: D5: start gettime error


tool: D26: end gettime error


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  int ret = 0;
  struct timeval start, end;
  double s, e;
  unsigned long int n;
  if (argc != 0 && argv[1])
    n = strtoul(argv[1], NULL, 0);
  else
    n = 40;
  ret = gettimeofday(&start, NULL);
  if (ret != 0) {
    perror("start gettime error\n");
    return 1;
  }
  printf("fibo_ite %lu: %lf\n", n, fibo_ite(n));
  ret = gettimeofday(&end, NULL);
  if (ret != 0) {
    perror("end gettime error\n");
    return 1;
  }
  s = (double)start.tv_sec + (double)start.tv_usec / 1000000.0;
  e = (double)end.tv_sec + (double)end.tv_usec / 1000000.0;
  printf("%lf elapsed\n", e - s);
  return 0;
}
```