ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<customPrint>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %rsp,%r12
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x3ff,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %s


assistant: ```c
int customPrint(const char *msg, ...) {
  va_list fmtargs;
  char buffer[1024];
  va_start(fmtargs, msg);
  vsnprintf(buffer, sizeof(buffer) - 1, msg, fmtargs);
  va_end(fmtargs);
  return printf("%s\n", buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<customPrint>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x3ff,%esi
  mov    %ebp,%ecx
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: string

tool: D6: %s


assistant: ```c
int customPrint(const char *msg, ...) {
  va_list fmtargs;
  char buffer[1024];
  va_start(fmtargs, msg);
  vsnprintf(buffer, sizeof(buffer) - 1, msg, fmtargs);
  va_end(fmtargs);
  return printf("%s\n", buffer);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<customPrint>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    $0x3ff,%esi
  mov    %ebp,%ecx
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x410,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: %s


assistant: ```c
int customPrint(const char *msg, ...) {
  va_list fmtargs;
  char buffer[1024];
  va_start(fmtargs, msg);
  vsnprintf(buffer, sizeof(buffer) - 1, msg, fmtargs);
  va_end(fmtargs);
  return printf("%s\n", buffer);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: Kernel PANIC


assistant: ```c
int panic(void) {
  printf("Kernel PANIC\n");
  assert(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<panic>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: Kernel PANIC


assistant: ```c
int panic(void) {
  printf("Kernel PANIC\n");
  assert(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<panic>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: Kernel PANIC


assistant: ```c
int panic(void) {
  printf("Kernel PANIC\n");
  assert(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<panic>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: Kernel PANIC


assistant: ```c
int panic(void) {
  printf("Kernel PANIC\n");
  assert(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  lea    0x2bc(%rax),%esi
  mov    $0xe4e1c0,%eax
  cltd
  mov    %esi,0xc(%rsp)
  idiv   %esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x3a98,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  nopl   (%rax)
L15:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%r15
  imul   $0xffffffff86fc9297,%rdx,%rdx
  mov    %r15d,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  add    %r15d,%edx
  sar    $0x9,%edx
  sub    %eax,%edx
  xor    %eax,%eax
  imul   $0x3cb,%edx,%edx
  sub    %edx,%r15d
  call   <rand@plt>
  add    $0x1e,%r15d
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x460a5cc9,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sub    %ecx,%edx
  imul   $0x3a7b,%edx,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%r13d
  mov    %r15d,%eax
  imul   %r13d,%eax
  cmp    %ebx,%eax
  jg     L15
  mov    %r15d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  cmp    %ebp,0xc(%rsp)
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D15: 

tool: D11: %d

assistant: ```c
int main() {
  int X;
  int Y;
  int n;
  int i;
  int maxPieceArea;
  int minSide = 30;
  srand(time(NULL));
  X = 1000 + rand() % 1;
  Y = 15000 + rand() % 1;
  n = 700 + rand() % 101;
  maxPieceArea = X * Y / n;
  printf("%d", n);
  printf("\r\n");
  printf("%d", X);
  printf(" ");
  printf("%d", Y);
  printf("\r\n");
  for (i = 0; i < n; i++) {
    int a = minSide + rand() % (X - minSide + 1);
    int b = minSide + rand() % (Y - minSide + 1);
    while (a * b > maxPieceArea) {
      a = minSide + rand() % (X - minSide + 1);
      b = minSide + rand() % (Y - minSide + 1);
    }
    printf("%d", a);
    printf(" ");
    printf("%d", b);
    printf("\r\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x288df0cb,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x24,%rdx
  sub    %ecx,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  lea    0x2bc(%rax),%esi
  mov    $0xe4e1c0,%eax
  cltd
  mov    %esi,0xc(%rsp)
  idiv   %esi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x3a98,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  nopl   (%rax)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%r15
  imul   $0xffffffff86fc9297,%rdx,%rdx
  mov    %r15d,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  add    %r15d,%edx
  sar    $0x9,%edx
  sub    %eax,%edx
  xor    %eax,%eax
  imul   $0x3cb,%edx,%edx
  sub    %edx,%r15d
  call   <rand@plt>
  add    $0x1e,%r15d
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x460a5cc9,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2c,%rdx
  sub    %ecx,%edx
  imul   $0x3a7b,%edx,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%r13d
  mov    %r15d,%eax
  imul   %r13d,%eax
  cmp    %ebx,%eax
  jg     L16
  mov    %r15d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  cmp    %ebp,0xc(%rsp)
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D2
datatype: string

tool: D18: 

tool: D2: %d

assistant: ```c
int main() {
  int X;
  int Y;
  int n;
  int i;
  int maxPieceArea;
  int minSide = 30;
  srand(time(NULL));
  X = 1000 + rand() % 1;
  Y = 15000 + rand() % 1;
  n = 700 + rand() % 101;
  maxPieceArea = X * Y / n;
  printf("%d", n);
  printf("\r\n");
  printf("%d", X);
  printf(" ");
  printf("%d", Y);
  printf("\r\n");
  for (i = 0; i < n; i++) {
    int a = minSide + rand() % (X - minSide + 1);
    int b = minSide + rand() % (Y - minSide + 1);
    while (a * b > maxPieceArea) {
      a = minSide + rand() % (X - minSide + 1);
      b = minSide + rand() % (Y - minSide + 1);
    }
    printf("%d", a);
    printf(" ");
    printf("%d", b);
    printf("\r\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D12
datatype: string

tool: D15: Warning : This program will work only on Valleyview

tool: D7: Usage: %s [addr] [val]


tool: D12: 	 addr : in 0xXXXX format

assistant: ```c
void usage(char *cmdname) {
  printf("Warning : This program will work only on Valleyview\n");
  printf("Usage: %s [addr] [val]\n", cmdname);
  printf("\t addr : in 0xXXXX format\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type: string
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D2
type: string

tool: D18: Warning : This program will work only on Valleyview

tool: D11: Usage: %s [addr] [val]


tool: D2: 	 addr : in 0xXXXX format

assistant: ```c
void usage(char *cmdname) {
  printf("Warning : This program will work only on Valleyview\n");
  printf("Usage: %s [addr] [val]\n", cmdname);
  printf("\t addr : in 0xXXXX format\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D9: Warning : This program will work only on Valleyview

tool: D0: Usage: %s [addr] [val]


tool: D1: 	 addr : in 0xXXXX format

assistant: ```c
void usage(char *cmdname) {
  printf("Warning : This program will work only on Valleyview\n");
  printf("Usage: %s [addr] [val]\n", cmdname);
  printf("\t addr : in 0xXXXX format\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D24(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D1
data_type: string
name: parse_data
arguments: tag: D24
data_type: string

tool: D12: Warning : This program will work only on Valleyview

tool: D1: Usage: %s [addr] [val]


tool: D24: 	 addr : in 0xXXXX format

assistant: ```c
void usage(char *cmdname) {
  printf("Warning : This program will work only on Valleyview\n");
  printf("Usage: %s [addr] [val]\n", cmdname);
  printf("\t addr : in 0xXXXX format\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  xor    %edi,%edi
  xor    %eax,%eax
  mov    %r12,%rdx
  lea    D48(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D51(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D3(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D16(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D77(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D50(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D21(%rip),%rsi
  call   <eprintf@plt>
  mov    %r12,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D14(%rip),%rsi
  call   <eprintf@plt>
  xor    %edi,%edi
  mov    %r12,%rdx
  xor    %eax,%eax
  lea    D53(%rip),%rsi
  call   <eprintf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type: string
name: unpack_data
arguments: tag: D48
type: string
name: unpack_data
arguments: tag: D51
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D77
type: string
name: unpack_data
arguments: tag: D50
type: string
name: unpack_data
arguments: tag: D21
type: string
name: unpack_data
arguments: tag: D14
type: string
name: unpack_data
arguments: tag: D53
type: string

tool: D17: usage

tool: D48: %s: usage: charade [options] [command [arg ...]]


tool: D51: %s: Options:


tool: D3: %s:   -c          Generate C-shell commands on stdout.


tool: D16: %s:   -s          Generate Bourne shell commands on stdout.


tool: D77: %s:   -k          Kill the current agent.


tool: D50: %s:   -d          Don't fork.


tool: D21: %s:   -v [-v ...] More trace output.


tool: D14: %s:   -a socket   Bind agent socket to given name.


tool: D53: %s:   --copyright Print out copyright message & licence.


assistant: ```c
void usage(void) {
  eprintf(0,
          "%s: "
          "usage: charade [options] [command [arg ...]]\n",
          __func__);
  eprintf(0,
          "%s: "
          "Options:\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -c          Generate C-shell commands on stdout.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -s          Generate Bourne shell commands on stdout.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -k          Kill the current agent.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -d          Don't fork.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -v [-v ...] More trace output.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  -a socket   Bind agent socket to given name.\n",
          __func__);
  eprintf(0,
          "%s: "
          "  --copyright Print out copyright message & licence.\n",
          __func__);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_triple_quote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L79
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L77
L79:
  mov    $0x0,%eax
  jmp    L50
L77:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
L11:
  mov    $0x0,%eax
  jmp    L50
L72:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L87
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L87
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L87
  mov    $0x1,%eax
  jmp    L50
L87:
  mov    $0x0,%eax
L50:
  pop    %rbp
  ret
```

assistant: ```c
int is_triple_quote(char **s) {
  if (!s || !*s)
    return 0;
  if (**s == '\0' || *(*s + 1) == '\0' || *(*s + 2) == '\0')
    return 0;
  return ((*s)[0] == '"' && (*s)[1] == '"' && (*s)[2] == '"');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_triple_quote>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L14
  movzbl (%rdx),%ecx
  mov    $0x0,%eax
  test   %cl,%cl
  je     L12
  movzbl 0x1(%rdx),%esi
  test   %sil,%sil
  je     L12
  cmpb   $0x22,0x2(%rdx)
  jne    L12
  cmp    $0x22,%sil
  sete   %dl
  cmp    $0x22,%cl
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x0,%eax
L12:
  ret
```

assistant: ```c
int is_triple_quote(char **s) {
  if (!s || !*s)
    return 0;
  if (**s == '\0' || *(*s + 1) == '\0' || *(*s + 2) == '\0')
    return 0;
  return ((*s)[0] == '"' && (*s)[1] == '"' && (*s)[2] == '"');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_triple_quote>:
  endbr64
  test   %rdi,%rdi
  je     L12
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L12
  movzbl (%rdx),%ecx
  xor    %eax,%eax
  test   %cl,%cl
  je     L11
  movzbl 0x1(%rdx),%esi
  test   %sil,%sil
  je     L11
  cmpb   $0x22,0x2(%rdx)
  jne    L11
  cmp    $0x22,%cl
  sete   %dl
  xor    %eax,%eax
  cmp    $0x22,%sil
  sete   %al
  and    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
L11:
  ret
```

assistant: ```c
int is_triple_quote(char **s) {
  if (!s || !*s)
    return 0;
  if (**s == '\0' || *(*s + 1) == '\0' || *(*s + 2) == '\0')
    return 0;
  return ((*s)[0] == '"' && (*s)[1] == '"' && (*s)[2] == '"');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_triple_quote>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    (%rdi),%rdx
  test   %rdx,%rdx
  je     L4
  movzbl (%rdx),%ecx
  xor    %eax,%eax
  test   %cl,%cl
  je     L17
  movzbl 0x1(%rdx),%esi
  test   %sil,%sil
  je     L17
  cmpb   $0x22,0x2(%rdx)
  jne    L17
  cmp    $0x22,%cl
  sete   %dl
  xor    %eax,%eax
  cmp    $0x22,%sil
  sete   %al
  and    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
L17:
  ret
```

assistant: ```c
int is_triple_quote(char **s) {
  if (!s || !*s)
    return 0;
  if (**s == '\0' || *(*s + 1) == '\0' || *(*s + 2) == '\0')
    return 0;
  return ((*s)[0] == '"' && (*s)[1] == '"' && (*s)[2] == '"');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertAtEnd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8d,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertAtEnd(int **queue, int queueRowSize, int maxRowSize, int currHeight, int currCount) {
  queue[queueRowSize + 1][0] = currHeight;
  queue[queueRowSize + 1][1] = currCount;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insertAtEnd>:
  endbr64
  movslq %esi,%rsi
  lea    0x8(%rdi,%rsi,8),%rax
  mov    (%rax),%rdx
  mov    %ecx,(%rdx)
  mov    (%rax),%rax
  mov    %r8d,0x4(%rax)
  ret
```

assistant: ```c
void insertAtEnd(int **queue, int queueRowSize, int maxRowSize, int currHeight, int currCount) {
  queue[queueRowSize + 1][0] = currHeight;
  queue[queueRowSize + 1][1] = currCount;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insertAtEnd>:
  endbr64
  movslq %esi,%rsi
  mov    0x8(%rdi,%rsi,8),%rax
  mov    %ecx,(%rax)
  mov    %r8d,0x4(%rax)
  ret
```

assistant: ```c
void insertAtEnd(int **queue, int queueRowSize, int maxRowSize, int currHeight, int currCount) {
  queue[queueRowSize + 1][0] = currHeight;
  queue[queueRowSize + 1][1] = currCount;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<insertAtEnd>:
  endbr64
  movslq %esi,%rsi
  movd   %ecx,%xmm0
  movd   %r8d,%xmm1
  mov    0x8(%rdi,%rsi,8),%rax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rax)
  ret
```

assistant: ```c
void insertAtEnd(int **queue, int queueRowSize, int maxRowSize, int currHeight, int currCount) {
  queue[queueRowSize + 1][0] = currHeight;
  queue[queueRowSize + 1][1] = currCount;
  return;
}
```