ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseHexDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tolowercase@plt>
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L48
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L8
L48:
  cmpb   $0x60,-0x4(%rbp)
  jle    L6
  cmpb   $0x66,-0x4(%rbp)
  jg     L6
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L8
L6:
  mov    $0xffffffff,%eax
L8:
  leave
  ret
```

assistant: ```c
int8_t parseHexDigit(uint8_t digit) {
  digit = tolowercase(digit);
  if (isdigit(digit))
    return (int8_t)digit - '0';
  if ((digit >= 'a') && (digit <= 'f'))
    return (int8_t)digit + 0xA - 'a';
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseHexDigit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl %dil,%edi
  call   <tolowercase@plt>
  mov    %eax,%ebp
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L2
  sub    $0x61,%ebp
  sub    $0x57,%ebx
  cmp    $0x6,%bpl
  mov    $0xffffffff,%eax
  cmovb  %ebx,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    -0x30(%rbx),%eax
  jmp    L19
```

assistant: ```c
int8_t parseHexDigit(uint8_t digit) {
  digit = tolowercase(digit);
  if (isdigit(digit))
    return (int8_t)digit - '0';
  if ((digit >= 'a') && (digit <= 'f'))
    return (int8_t)digit + 0xA - 'a';
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parseHexDigit>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <tolowercase@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebx,%ebp
  mov    $0xffffffff,%eax
  sub    $0x57,%ebx
  sub    $0x61,%ebp
  cmp    $0x6,%bpl
  cmovb  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L5:
  add    $0x8,%rsp
  lea    -0x30(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int8_t parseHexDigit(uint8_t digit) {
  digit = tolowercase(digit);
  if (isdigit(digit))
    return (int8_t)digit - '0';
  if ((digit >= 'a') && (digit <= 'f'))
    return (int8_t)digit + 0xA - 'a';
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parseHexDigit>:
  endbr64
  push   %rbp
  movsbl %dil,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <tolowercase@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
  mov    %ebx,%ebp
  mov    $0xffffffff,%eax
  sub    $0x57,%ebx
  sub    $0x61,%ebp
  cmp    $0x6,%bpl
  cmovb  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L4:
  add    $0x8,%rsp
  lea    -0x30(%rbx),%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int8_t parseHexDigit(uint8_t digit) {
  digit = tolowercase(digit);
  if (isdigit(digit))
    return (int8_t)digit - '0';
  if ((digit >= 'a') && (digit <= 'f'))
    return (int8_t)digit + 0xA - 'a';
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<clz64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  bsr    -0x8(%rbp),%rax
  xor    $0x3f,%rax
  leave
  ret
```

assistant: ```c
uint32_t clz64(uint64_t x) {
  assert(x != 0);
  return __builtin_clzl(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  bsr    %rbx,%rax
  xor    $0x3f,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t clz64(uint64_t x) {
  assert(x != 0);
  return __builtin_clzl(x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  bsr    %rbx,%rax
  pop    %rbx
  xor    $0x3f,%eax
  ret
```

assistant: ```c
uint32_t clz64(uint64_t x) {
  assert(x != 0);
  return __builtin_clzl(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clz64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  bsr    %rbx,%rax
  pop    %rbx
  xor    $0x3f,%eax
  ret
```

assistant: ```c
uint32_t clz64(uint64_t x) {
  assert(x != 0);
  return __builtin_clzl(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Util_ZeroString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Util_Zero@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void Util_ZeroString(char *str) {
  if (str != ((void *)0)) {
    Util_Zero(str, strlen(str));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Util_ZeroString>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <Util_Zero@plt>
  pop    %rbx
  ret
L3:
  ret
```

assistant: ```c
void Util_ZeroString(char *str) {
  if (str != ((void *)0)) {
    Util_Zero(str, strlen(str));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Util_ZeroString>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  jmp    1060 <Util_Zero@plt>
L1:
  ret
```

assistant: ```c
void Util_ZeroString(char *str) {
  if (str != ((void *)0)) {
    Util_Zero(str, strlen(str));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Util_ZeroString>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  xor    %eax,%eax
  jmp    1060 <Util_Zero@plt>
L5:
  ret
```

assistant: ```c
void Util_ZeroString(char *str) {
  if (str != ((void *)0)) {
    Util_Zero(str, strlen(str));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x10(%rbp)
  movl   $0xff,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  union {
    uint8_t input[2];
    int16_t output;
  } u8_to_int16;
  u8_to_int16.input[0] = 10;
  u8_to_int16.input[1] = 255;
  printf("%d\n", u8_to_int16.output);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: %d


assistant: ```c
int main(int argc, char **argv) {
  union {
    uint8_t input[2];
    int16_t output;
  } u8_to_int16;
  u8_to_int16.input[0] = 10;
  u8_to_int16.input[1] = 255;
  printf("%d\n", u8_to_int16.output);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  union {
    uint8_t input[2];
    int16_t output;
  } u8_to_int16;
  u8_to_int16.input[0] = 10;
  u8_to_int16.input[1] = 255;
  printf("%d\n", u8_to_int16.output);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(int argc, char **argv) {
  union {
    uint8_t input[2];
    int16_t output;
  } u8_to_int16;
  u8_to_int16.input[0] = 10;
  u8_to_int16.input[1] = 255;
  printf("%d\n", u8_to_int16.output);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L36:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L7
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d	

assistant: ```c
void print_matrix(int **A, int M, int N) {
  int i, j;
  for (i = 0; i < M; i++) {
    for (j = 0; j < N; j++) {
      printf("%d\t", A[i][j]);
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L39
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r14d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r15
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%r13
  lea    D5(%rip),%r12
  jmp    L22
L6:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L6
L51:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L24
L22:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jg     L6
  jmp    L51
L24:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: %d	

assistant: ```c
void print_matrix(int **A, int M, int N) {
  int i, j;
  for (i = 0; i < M; i++) {
    for (j = 0; j < N; j++) {
      printf("%d\t", A[i][j]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L37
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  lea    0x8(%rdi,%rax,8),%r14
  lea    -0x1(%rdx),%eax
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x4(,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L28
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%r15),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L22
L28:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    %r14,%r15
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: %d	

assistant: ```c
void print_matrix(int **A, int M, int N) {
  int i, j;
  for (i = 0; i < M; i++) {
    for (j = 0; j < N; j++) {
      printf("%d\t", A[i][j]);
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L26
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  lea    0x8(%rdi,%rax,8),%r14
  lea    -0x1(%rdx),%eax
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x4(,%rax,4),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L34:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L20
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%r15),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L24
L20:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    %r14,%r15
  jne    L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: %d	

assistant: ```c
void print_matrix(int **A, int M, int N) {
  int i, j;
  for (i = 0; i < M; i++) {
    for (j = 0; j < N; j++) {
      printf("%d\t", A[i][j]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tanh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D13(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L1
  movsd  -0x18(%rbp),%xmm0
  movq   D9(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L1:
  movsd  -0x18(%rbp),%xmm0
  comisd D19(%rip),%xmm0
  jbe    L8
  movsd  -0x8(%rbp),%xmm0
  jmp    L29
L8:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sinh@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cosh@plt>
  movapd %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
L29:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_infered: f64
name: retrieve_data
arguments: data_tag: D9
type_infered: f32[2]
name: retrieve_data
arguments: data_tag: D1
type_infered: f32[2]
name: retrieve_data
arguments: data_tag: D19
type_infered: f64

tool: D13: 1

tool: {"D9": [0.0,-0.0]}

tool: {"D1": [0.0,-1.875]}

tool: D19: 21

assistant: ```c
double tanh(arg)
double arg;
{
  double sign;
  sign = 1.;
  if (arg < 0.) {
    arg = -arg;
    sign = -1.;
  }
  if (arg > 21.)
    return (sign);
  return (sign * sinh(arg) / cosh(arg));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tanh>:
  endbr64
  push   %r15
  push   %r14
  push   %rbx
  movq   %xmm0,%r14
  pxor   %xmm0,%xmm0
  movq   %r14,%xmm2
  mov    D5(%rip),%rbx
  comisd %xmm2,%xmm0
  ja     L22
L36:
  movq   %r14,%xmm3
  comisd D4(%rip),%xmm3
  jbe    L24
L5:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %r14
  pop    %r15
  ret
L22:
  xorpd  D36(%rip),%xmm2
  movq   %xmm2,%r14
  mov    D29(%rip),%rbx
  jmp    L36
L24:
  movq   %r14,%xmm0
  call   <sinh@plt>
  movq   %xmm0,%r15
  movq   %r14,%xmm0
  call   <cosh@plt>
  movq   %rbx,%xmm1
  movq   %r15,%xmm4
  mulsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rbx
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_guessed: f64
name: parse_data
arguments: data_tag: D4
type_guessed: f64[2]
name: parse_data
arguments: data_tag: D36
type_guessed: f32[4]
name: parse_data
arguments: data_tag: D29
type_guessed: f32[2]

tool: D5: 1

tool: {"D4": [21.0,0.0]}

tool: {"D36": [0.0,-0.0,0.0,0.0]}

tool: {"D29": [0.0,-1.875]}

assistant: ```c
double tanh(arg)
double arg;
{
  double sign;
  sign = 1.;
  if (arg < 0.) {
    arg = -arg;
    sign = -1.;
  }
  if (arg > 21.)
    return (sign);
  return (sign * sinh(arg) / cosh(arg));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tanh>:
  endbr64
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movsd  D35(%rip),%xmm2
  comisd %xmm1,%xmm0
  jbe    L6
  xorpd  D30(%rip),%xmm1
  movsd  D27(%rip),%xmm2
L6:
  comisd D31(%rip),%xmm1
  jbe    L17
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L17:
  sub    $0x28,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sinh@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <cosh@plt>
  movsd  0x18(%rsp),%xmm2
  mulsd  0x8(%rsp),%xmm2
  add    $0x28,%rsp
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D35
data_type: f64
name: read_data
arguments: tag: D30
data_type: f32[4]
name: read_data
arguments: tag: D27
data_type: f32[2]
name: read_data
arguments: tag: D31
data_type: f64[2]

tool: D35: 1

tool: {"D30": [0.0,-0.0,0.0,0.0]}

tool: {"D27": [0.0,-1.875]}

tool: {"D31": [21.0,0.0]}

assistant: ```c
double tanh(arg)
double arg;
{
  double sign;
  sign = 1.;
  if (arg < 0.) {
    arg = -arg;
    sign = -1.;
  }
  if (arg > 21.)
    return (sign);
  return (sign * sinh(arg) / cosh(arg));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tanh>:
  endbr64
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movsd  D35(%rip),%xmm2
  comisd %xmm1,%xmm0
  jbe    L8
  xorpd  D12(%rip),%xmm1
  movsd  D16(%rip),%xmm2
L8:
  comisd D38(%rip),%xmm1
  jbe    L12
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L12:
  sub    $0x28,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <sinh@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <cosh@plt>
  movsd  0x18(%rsp),%xmm2
  mulsd  0x8(%rsp),%xmm2
  add    $0x28,%rsp
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D35
data_type: f64
name: disassemble_data
arguments: data_label: D12
data_type: f32[4]
name: disassemble_data
arguments: data_label: D16
data_type: f32[2]
name: disassemble_data
arguments: data_label: D38
data_type: f64[2]

tool: D35: 1

tool: {"D12": [0.0,-0.0,0.0,0.0]}

tool: {"D16": [0.0,-1.875]}

tool: {"D38": [21.0,0.0]}

assistant: ```c
double tanh(arg)
double arg;
{
  double sign;
  sign = 1.;
  if (arg < 0.) {
    arg = -arg;
    sign = -1.;
  }
  if (arg > 21.)
    return (sign);
  return (sign * sinh(arg) / cosh(arg));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a_Hp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L7
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  D32(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D20(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movsd  D8(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  mulsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D47(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movq   %xmm2,%rax
  movsd  D42(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D24(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  jmp    L12
L7:
  pxor   %xmm0,%xmm0
L12:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D32
type_guessed: byte[8]
name: unpack_data
arguments: label: D20
type_guessed: f64
name: unpack_data
arguments: label: D8
type_guessed: byte[8]
name: unpack_data
arguments: label: D47
type_guessed: f64
name: unpack_data
arguments: label: D42
type_guessed: f64
name: unpack_data
arguments: label: D24
type_guessed: f64

tool: {"D32": [0x36,0x43,0x8c,0x79,0xf9,0x16,0xd7,0x3d]}

tool: D20: 1000

tool: {"D8": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0xbf]}

tool: D47: 1000000

tool: D42: 0.7

tool: D24: 1

assistant: ```c
double a_Hp(t)
double t;
{
  if (t > 0.0) {
    return (8.40e-11 / sqrt(t)) * pow(t / 1e3, -0.2) / (1.0 + pow(t / 1e6, 0.7));
  }
  return 0.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a_Hp>:
  endbr64
  comisd D16(%rip),%xmm0
  ja     L4
  pxor   %xmm0,%xmm0
  ret
L4:
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm4
  ucomisd %xmm4,%xmm0
  ja     L0
  movq   %rbx,%xmm3
  sqrtsd %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L8:
  movq   %rbx,%xmm0
  divsd  D30(%rip),%xmm0
  movsd  D48(%rip),%xmm1
  call   <pow@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  divsd  D36(%rip),%xmm0
  movsd  D62(%rip),%xmm1
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D11(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  movq   %r14,%xmm6
  mulsd  %xmm6,%xmm0
  addsd  D69(%rip),%xmm1
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L0:
  movq   %rbx,%xmm0
  call   <sqrt@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L8
```

tool_calls: name: parse_data
arguments: label: D16
data_type: f64[2]
name: parse_data
arguments: label: D30
data_type: f64
name: parse_data
arguments: label: D48
data_type: byte[8]
name: parse_data
arguments: label: D36
data_type: f64
name: parse_data
arguments: label: D62
data_type: f64
name: parse_data
arguments: label: D11
data_type: byte[8]
name: parse_data
arguments: label: D69
data_type: f64

tool: {"D16": [0.0,-0.2]}

tool: D30: 1000

tool: {"D48": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0xbf]}

tool: D36: 1000000

tool: D62: 0.7

tool: {"D11": [0x36,0x43,0x8c,0x79,0xf9,0x16,0xd7,0x3d]}

tool: D69: 1

assistant: ```c
double a_Hp(t)
double t;
{
  if (t > 0.0) {
    return (8.40e-11 / sqrt(t)) * pow(t / 1e3, -0.2) / (1.0 + pow(t / 1e6, 0.7));
  }
  return 0.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<a_Hp>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  ja     L21
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x28,%rsp
  ucomisd %xmm2,%xmm0
  ja     L27
  movapd %xmm2,%xmm3
  sqrtsd %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L28:
  movsd  D52(%rip),%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x18(%rsp)
  divsd  D32(%rip),%xmm0
  call   <pow@plt>
  movsd  D56(%rip),%xmm1
  movsd  0x18(%rsp),%xmm2
  divsd  D42(%rip),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  addsd  D16(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  divsd  %xmm1,%xmm0
  ret
L27:
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  jmp    L28
```

tool_calls: name: read_data
arguments: data_label: D52
type_infered: byte[8]
name: read_data
arguments: data_label: D32
type_infered: f64
name: read_data
arguments: data_label: D56
type_infered: f64
name: read_data
arguments: data_label: D42
type_infered: f64
name: read_data
arguments: data_label: D5
type_infered: byte[8]
name: read_data
arguments: data_label: D16
type_infered: f64

tool: {"D52": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0xbf]}

tool: D32: 1000

tool: D56: 0.7

tool: D42: 1000000

tool: {"D5": [0x36,0x43,0x8c,0x79,0xf9,0x16,0xd7,0x3d]}

tool: D16: 1

assistant: ```c
double a_Hp(t)
double t;
{
  if (t > 0.0) {
    return (8.40e-11 / sqrt(t)) * pow(t / 1e3, -0.2) / (1.0 + pow(t / 1e6, 0.7));
  }
  return 0.0;
}
```