ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D109(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L0
  comisd D26(%rip),%xmm0
  jbe    L62
L0:
  lea    D96(%rip),%rdi
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L62:
  lea    D102(%rip),%rdi
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  D100(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L78
  movsd  D94(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L20
  movsd  D76(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L40
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L78:
  lea    D65(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L20:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L40:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L33
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D109
type_guessed: string
name: parse_data
arguments: tag: D26
type_guessed: byte[16]
name: parse_data
arguments: tag: D96
type_guessed: string
name: parse_data
arguments: tag: D102
type_guessed: string
name: parse_data
arguments: tag: D100
type_guessed: byte[8]
name: parse_data
arguments: tag: D94
type_guessed: byte[8]
name: parse_data
arguments: tag: D76
type_guessed: byte[8]
name: parse_data
arguments: tag: D32
type_guessed: string
name: parse_data
arguments: tag: D65
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D64
type_guessed: string

tool: D109: %lf

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D96: Fora de intervalo


tool: D102: Intervalo 

tool: {"D100": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: {"D94": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: {"D76": [0x00,0x00,0x00,0x00,0x00,0xc0,0x52,0x40]}

tool: D32: (50,75]


tool: D65: [0,25]


tool: D13: (25,50]


tool: D64: (75,100]


assistant: ```c
int main() {
  double num;
  scanf("%lf", &num);
  if (num < 0 || num > 100) {
    printf("Fora de intervalo\n");
  } else {
    printf("Intervalo ");
    if (num <= 25) {
      printf("[0,25]\n");
    } else if (num <= 50) {
      printf("(25,50]\n");
    } else if (num <= 75) {
      printf("(50,75]\n");
    } else {
      printf("(75,100]\n");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D71(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L73
  comisd D92(%rip),%xmm0
  jbe    L93
L73:
  lea    D55(%rip),%rdi
  call   <printf@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L93:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  D86(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L23
  movsd  D61(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L13
  movsd  D89(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L7
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L23:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L13:
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D71
type: string
name: retrieve_data
arguments: tag: D92
type: byte[16]
name: retrieve_data
arguments: tag: D55
type: string
name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D86
type: byte[8]
name: retrieve_data
arguments: tag: D61
type: byte[8]
name: retrieve_data
arguments: tag: D89
type: byte[8]
name: retrieve_data
arguments: tag: D31
type: string
name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D78
type: string

tool: D71: %lf

tool: {"D92": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D55: Fora de intervalo


tool: D13: Intervalo 

tool: {"D86": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0xc0,0x52,0x40]}

tool: D31: (50,75]


tool: D33: [0,25]


tool: D6: (75,100]


tool: D78: (25,50]


assistant: ```c
int main() {
  double num;
  scanf("%lf", &num);
  if (num < 0 || num > 100) {
    printf("Fora de intervalo\n");
  } else {
    printf("Intervalo ");
    if (num <= 25) {
      printf("[0,25]\n");
    } else if (num <= 50) {
      printf("(25,50]\n");
    } else if (num <= 75) {
      printf("(50,75]\n");
    } else {
      printf("(75,100]\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L54
  comisd D56(%rip),%xmm0
  jbe    L82
L54:
  lea    D15(%rip),%rdi
  call   <printf@plt>
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L82:
  lea    D66(%rip),%rdi
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  movsd  D19(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L90
  movsd  D46(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L10
  movsd  D16(%rip),%xmm1
  comisd %xmm0,%xmm1
  jb     L33
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L90:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L33:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L10:
  lea    D78(%rip),%rdi
  call   <printf@plt>
  jmp    L77
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D56
datatype: byte[16]
name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D66
datatype: string
name: unpack_data
arguments: data_tag: D19
datatype: byte[8]
name: unpack_data
arguments: data_tag: D46
datatype: byte[8]
name: unpack_data
arguments: data_tag: D16
datatype: byte[8]
name: unpack_data
arguments: data_tag: D58
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D34
datatype: string
name: unpack_data
arguments: data_tag: D78
datatype: string

tool: D12: %lf

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: D15: Fora de intervalo


tool: D66: Intervalo 

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x39,0x40]}

tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0xc0,0x52,0x40]}

tool: D58: (50,75]


tool: D18: [0,25]


tool: D34: (75,100]


tool: D78: (25,50]


assistant: ```c
int main() {
  double num;
  scanf("%lf", &num);
  if (num < 0 || num > 100) {
    printf("Fora de intervalo\n");
  } else {
    printf("Intervalo ");
    if (num <= 25) {
      printf("[0,25]\n");
    } else if (num <= 50) {
      printf("(25,50]\n");
    } else if (num <= 75) {
      printf("(50,75]\n");
    } else {
      printf("(75,100]\n");
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hasher31>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L14:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L14
  mov    -0x8(%rbp),%rax
  and    $0x1fff,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hasher31(char *str) {
  unsigned long hash = 5381;
  int tmp = 0;
  while ((tmp = *str++)) {
    hash = ((hash << 5) + hash) + tmp;
  }
  return hash % (0x2000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hasher31>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L11
  mov    $0x1505,%eax
L7:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L7
L9:
  and    $0x1fff,%eax
  ret
L11:
  mov    $0x1505,%eax
  jmp    L9
```

assistant: ```c
unsigned long hasher31(char *str) {
  unsigned long hash = 5381;
  int tmp = 0;
  while ((tmp = *str++)) {
    hash = ((hash << 5) + hash) + tmp;
  }
  return hash % (0x2000);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hasher31>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L12
  nopl   (%rax)
L5:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L5
  and    $0x1fff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
unsigned long hasher31(char *str) {
  unsigned long hash = 5381;
  int tmp = 0;
  while ((tmp = *str++)) {
    hash = ((hash << 5) + hash) + tmp;
  }
  return hash % (0x2000);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hasher31>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L12
  nopl   (%rax)
L14:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L14
  and    $0x1fff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
unsigned long hasher31(char *str) {
  unsigned long hash = 5381;
  int tmp = 0;
  while ((tmp = *str++)) {
    hash = ((hash << 5) + hash) + tmp;
  }
  return hash % (0x2000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_addRange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L5
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
L5:
  cmpl   $0x0,-0x20(%rbp)
  jg     L15
  movl   $0x1,-0x20(%rbp)
L15:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _addRange(int channels[], int cmax, int ll, int rr) {
  int ii;
  if (rr > cmax)
    rr = cmax;
  if (ll < 1)
    ll = 1;
  for (ii = ll; ii <= rr; ++ii) {
    channels[ii] = 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_addRange>:
  endbr64
  cmp    %esi,%ecx
  cmovg  %esi,%ecx
  test   %edx,%edx
  mov    $0x1,%eax
  cmovle %eax,%edx
  cmp    %ecx,%edx
  jg     L0
  movslq %edx,%rsi
  lea    (%rdi,%rsi,4),%rax
  sub    %edx,%ecx
  add    %rsi,%rcx
  lea    0x4(%rdi,%rcx,4),%rdx
L5:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
L0:
  ret
```

assistant: ```c
void _addRange(int channels[], int cmax, int ll, int rr) {
  int ii;
  if (rr > cmax)
    rr = cmax;
  if (ll < 1)
    ll = 1;
  for (ii = ll; ii <= rr; ++ii) {
    channels[ii] = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_addRange>:
  endbr64
  cmp    %esi,%ecx
  mov    $0x1,%eax
  cmovg  %esi,%ecx
  test   %edx,%edx
  cmovle %eax,%edx
  cmp    %ecx,%edx
  jg     L1
  movslq %edx,%rsi
  sub    %edx,%ecx
  add    %rsi,%rcx
  lea    (%rdi,%rsi,4),%rax
  lea    0x4(%rdi,%rcx,4),%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
L1:
  ret
```

assistant: ```c
void _addRange(int channels[], int cmax, int ll, int rr) {
  int ii;
  if (rr > cmax)
    rr = cmax;
  if (ll < 1)
    ll = 1;
  for (ii = ll; ii <= rr; ++ii) {
    channels[ii] = 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_addRange>:
  endbr64
  cmp    %esi,%ecx
  mov    $0x1,%eax
  mov    %rdi,%r9
  cmovle %ecx,%esi
  test   %edx,%edx
  cmovle %eax,%edx
  mov    %esi,%r8d
  cmp    %esi,%edx
  jg     L1
  mov    %esi,%eax
  sub    %edx,%eax
  lea    0x1(%rax),%edi
  cmp    $0x2,%eax
  jbe    L28
  movslq %edx,%rax
  movdqa D1(%rip),%xmm0
  lea    (%r9,%rax,4),%rcx
  mov    %edi,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rcx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L24
  nopl   0x0(%rax)
L14:
  add    $0x10,%rax
L24:
  movups %xmm0,(%rcx)
  mov    %rax,%rcx
  cmp    %rsi,%rax
  jne    L14
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  add    %eax,%edx
  cmp    %eax,%edi
  je     L1
L28:
  movslq %edx,%rax
  movl   $0x1,(%r9,%rax,4)
  lea    0x0(,%rax,4),%rcx
  lea    0x1(%rdx),%eax
  cmp    %eax,%r8d
  jl     L1
  movl   $0x1,0x4(%r9,%rcx,1)
  add    $0x2,%edx
  cmp    %edx,%r8d
  jl     L1
  movl   $0x1,0x8(%r9,%rcx,1)
L1:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: byte[16]

tool: {"D1": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void _addRange(int channels[], int cmax, int ll, int rr) {
  int ii;
  if (rr > cmax)
    rr = cmax;
  if (ll < 1)
    ll = 1;
  for (ii = ll; ii <= rr; ++ii) {
    channels[ii] = 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<append_file_to_loc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r12
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%r12
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x2,%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %rax,%rdx
  mov    %rdx,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  mov    %rax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    %rax,%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ebx
  mov    $0x0,%edx
  div    %rbx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L18:
  cmp    %rdx,%rsp
  je     L37
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L18
L37:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L9
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L9:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x30(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x50(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %r12,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D9: /

assistant: ```c
char *append_file_to_loc(const char *location, const char *path) {
  char buf[strlen(location) + strlen(path) + 2];
  buf[0] = '\0';
  strcat(buf, location);
  strcat(buf, "/");
  strcat(buf, path);
  return strdup(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<append_file_to_loc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x11(%r13,%rax,1),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L24:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L24
L13:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L34
  orq    $0x0,-0x8(%rsp,%rax,1)
L34:
  movb   $0x0,(%rsp)
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  lea    D4(%rip),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: string

tool: D4: /

assistant: ```c
char *append_file_to_loc(const char *location, const char *path) {
  char buf[strlen(location) + strlen(path) + 2];
  buf[0] = '\0';
  strcat(buf, location);
  strcat(buf, "/");
  strcat(buf, path);
  return strdup(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<append_file_to_loc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x11(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L20
L48:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L48
L20:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L13
L26:
  mov    %r13,%rsi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp)
  call   <strcat@plt>
  lea    D4(%rip),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L26
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: /

assistant: ```c
char *append_file_to_loc(const char *location, const char *path) {
  char buf[strlen(location) + strlen(path) + 2];
  buf[0] = '\0';
  strcat(buf, location);
  strcat(buf, "/");
  strcat(buf, path);
  return strdup(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<append_file_to_loc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x11(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L5
L14:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L14
L5:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L32
L23:
  mov    %r13,%rsi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp)
  call   <strcat@plt>
  lea    D3(%rip),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L32:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L23
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: /

assistant: ```c
char *append_file_to_loc(const char *location, const char *path) {
  char buf[strlen(location) + strlen(path) + 2];
  buf[0] = '\0';
  strcat(buf, location);
  strcat(buf, "/");
  strcat(buf, path);
  return strdup(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <llenarListaPersonas@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <imprimir@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ordenarListaPersonasPorMatricula@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <imprimir@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: string

tool: D11: Sin ordenar:


tool: D17: Ordenada por matricula:


assistant: ```c
int main() {
  struct _persona *lista = NULL;
  llenarListaPersonas(&lista);
  printf("Sin ordenar:\n");
  imprimir(lista);
  ordenarListaPersonasPorMatricula(&lista);
  printf("Ordenada por matricula:\n");
  imprimir(lista);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <llenarListaPersonas@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <imprimir@plt>
  mov    %rbx,%rdi
  call   <ordenarListaPersonasPorMatricula@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <imprimir@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D11: Sin ordenar:


tool: D1: Ordenada por matricula:


assistant: ```c
int main() {
  struct _persona *lista = NULL;
  llenarListaPersonas(&lista);
  printf("Sin ordenar:\n");
  imprimir(lista);
  ordenarListaPersonasPorMatricula(&lista);
  printf("Ordenada por matricula:\n");
  imprimir(lista);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   <llenarListaPersonas@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <imprimir@plt>
  mov    %rbp,%rdi
  call   <ordenarListaPersonasPorMatricula@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <imprimir@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D12: Sin ordenar:


tool: D15: Ordenada por matricula:


assistant: ```c
int main() {
  struct _persona *lista = NULL;
  llenarListaPersonas(&lista);
  printf("Sin ordenar:\n");
  imprimir(lista);
  ordenarListaPersonasPorMatricula(&lista);
  printf("Ordenada por matricula:\n");
  imprimir(lista);
  return 0;
}
```