ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SKP_Silk_scale_vector32_Q16>:
  endbr64
  cmp    $0x7fff,%esi
  jg     L4
  test   %edx,%edx
  jle    L13
  lea    -0x1(%rdx),%eax
  movswl %si,%esi
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  movzwl %dx,%eax
  sar    $0x10,%edx
  imul   %esi,%eax
  imul   %esi,%edx
  sar    $0x10,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rcx
  jne    L17
L37:
  ret
L4:
  sub    $0x10000,%esi
  test   %edx,%edx
  jle    L37
  lea    -0x1(%rdx),%eax
  movswl %si,%esi
  lea    0x4(%rdi,%rax,4),%r8
  nopl   (%rax)
L31:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  movzwl %dx,%eax
  mov    %edx,%ecx
  imul   %esi,%eax
  sar    $0x10,%ecx
  imul   %esi,%ecx
  sar    $0x10,%eax
  add    %ecx,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%r8
  jne    L31
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
void SKP_Silk_scale_vector32_Q16(int *data1, int gain_Q16, const int dataSize) {
  int i;
  ;
  ;
  if (gain_Q16 > 0x7FFF) {
    gain_Q16 -= 65536;
    for (i = 0; i < dataSize; i++) {
      data1[i] = ((data1[i]) + ((((data1[i]) >> 16) * (int)((short)(gain_Q16))) + ((((data1[i]) & 0x0000FFFF) * (int)((short)(gain_Q16))) >> 16)));
    }
  } else {
    for (i = 0; i < dataSize; i++) {
      data1[i] = ((((data1[i]) >> 16) * (int)((short)(gain_Q16))) + ((((data1[i]) & 0x0000FFFF) * (int)((short)(gain_Q16))) >> 16));
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_EndianSwapUnsignedShort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %al,-0x2(%rbp)
  movzwl -0x14(%rbp),%eax
  shr    $0x8,%ax
  mov    %al,-0x1(%rbp)
  movzbl -0x2(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short _EndianSwapUnsignedShort(unsigned short s) {
  unsigned char b1, b2;
  b1 = s & 255;
  b2 = (s >> 8) & 255;
  return (b1 << 8) + b2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_EndianSwapUnsignedShort>:
  endbr64
  mov    %edi,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short _EndianSwapUnsignedShort(unsigned short s) {
  unsigned char b1, b2;
  b1 = s & 255;
  b2 = (s >> 8) & 255;
  return (b1 << 8) + b2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_EndianSwapUnsignedShort>:
  endbr64
  mov    %edi,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short _EndianSwapUnsignedShort(unsigned short s) {
  unsigned char b1, b2;
  b1 = s & 255;
  b2 = (s >> 8) & 255;
  return (b1 << 8) + b2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_EndianSwapUnsignedShort>:
  endbr64
  mov    %edi,%eax
  rol    $0x8,%ax
  ret
```

assistant: ```c
unsigned short _EndianSwapUnsignedShort(unsigned short s) {
  unsigned char b1, b2;
  b1 = s & 255;
  b2 = (s >> 8) & 255;
  return (b1 << 8) + b2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L59
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L30:
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L70
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L70:
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  jmp    L54
L59:
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L39:
  movl   $0x0,-0x4(%rbp)
  jmp    L89
L0:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L62
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L62:
  addl   $0x1,-0x4(%rbp)
L89:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L39
L54:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string

tool: D13: *(arreglo[0] + %i) = %i


tool: D17: arreglo_mult[%d][%d] = %d	

assistant: ```c
void print_values(int *valor, int n_rows, int n_cols) {
  int i, j;
  if (n_cols == 0) {
    for (i = 0; i < n_rows; i++) {
      if (i % 2 == 1) {
        printf("*(arreglo[0] + %i) = %i\n", i, *(valor + i));
      }
    }
  } else {
    for (i = 0; i < n_rows; i++) {
      for (j = 0; j < n_cols; j++) {
        if ((i * n_cols + j) % 2 == 1) {
          printf("arreglo_mult[%d][%d] = %d\t", i, j, *(valor + i * n_cols + j));
        }
      }
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_values>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %edx,%edx
  je     L121
  mov    %edx,%r14d
  test   %esi,%esi
  jle    L52
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  jmp    L111
L121:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L52
  mov    %eax,%ebp
  mov    $0x1,%ebx
  lea    D18(%rip),%r12
  jmp    L91
L2:
  add    $0x1,%rbx
L91:
  mov    %ebx,%esi
  cmp    %rbp,%rbx
  je     L52
  mov    %ebx,%edx
  shr    $0x1f,%edx
  lea    (%rdx,%rbx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L2
  mov    0x8(%rsp),%rax
  mov    (%rax,%rbx,4),%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L79:
  mov    (%r15,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r13d,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L85:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L117
L34:
  lea    0x0(%rbp,%rbx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L85
  jmp    L79
L117:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    %r14d,%ebp
  cmp    %r13d,0x4(%rsp)
  je     L52
L111:
  test   %r14d,%r14d
  jle    L117
  mov    %r14d,%r12d
  movslq %ebp,%rax
  mov    0x8(%rsp),%rdi
  lea    (%rdi,%rax,4),%r15
  mov    $0x0,%ebx
  jmp    L34
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D18: *(arreglo[0] + %i) = %i


tool: D16: arreglo_mult[%d][%d] = %d	

assistant: ```c
void print_values(int *valor, int n_rows, int n_cols) {
  int i, j;
  if (n_cols == 0) {
    for (i = 0; i < n_rows; i++) {
      if (i % 2 == 1) {
        printf("*(arreglo[0] + %i) = %i\n", i, *(valor + i));
      }
    }
  } else {
    for (i = 0; i < n_rows; i++) {
      for (j = 0; j < n_cols; j++) {
        if ((i * n_cols + j) % 2 == 1) {
          printf("arreglo_mult[%d][%d] = %d\t", i, j, *(valor + i * n_cols + j));
        }
      }
      printf("\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_values>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %edx,%edx
  je     L126
  test   %esi,%esi
  jle    L104
  mov    %edx,%ebp
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  nop
L25:
  test   %ebp,%ebp
  jle    L103
  mov    0x8(%rsp),%rdi
  movslq %r15d,%rax
  mov    %ebp,%r14d
  xor    %ebx,%ebx
  lea    (%rdi,%rax,4),%r13
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L128:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L103
L125:
  lea    (%r15,%rbx,1),%eax
  mov    %ebx,%edx
  test   $0x1,%al
  je     L128
  mov    0x0(%r13,%rbx,4),%ecx
  mov    %r12d,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L125
  nopw   0x0(%rax,%rax,1)
L103:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    %ebp,%r15d
  call   <putchar@plt>
  cmp    %r12d,0x4(%rsp)
  jne    L25
L104:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L126:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L104
  movslq %eax,%r12
  mov    $0x1,%ebx
  lea    D13(%rip),%rbp
  jmp    L119
  nopl   0x0(%rax)
L30:
  add    $0x1,%rbx
L119:
  mov    %ebx,%esi
  cmp    %r12,%rbx
  je     L104
  test   $0x1,%bl
  je     L30
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,4),%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D10: arreglo_mult[%d][%d] = %d	

tool: D13: *(arreglo[0] + %i) = %i


assistant: ```c
void print_values(int *valor, int n_rows, int n_cols) {
  int i, j;
  if (n_cols == 0) {
    for (i = 0; i < n_rows; i++) {
      if (i % 2 == 1) {
        printf("*(arreglo[0] + %i) = %i\n", i, *(valor + i));
      }
    }
  } else {
    for (i = 0; i < n_rows; i++) {
      for (j = 0; j < n_cols; j++) {
        if ((i * n_cols + j) % 2 == 1) {
          printf("arreglo_mult[%d][%d] = %d\t", i, j, *(valor + i * n_cols + j));
        }
      }
      printf("\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_values>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x4(%rsp)
  test   %edx,%edx
  je     L0
  test   %esi,%esi
  jle    L109
  mov    %edx,%ebp
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  nop
L93:
  test   %ebp,%ebp
  jle    L10
  mov    0x8(%rsp),%rdi
  movslq %r15d,%rax
  mov    %ebp,%r14d
  xor    %ebx,%ebx
  lea    (%rdi,%rax,4),%r13
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L96:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L10
L2:
  lea    (%r15,%rbx,1),%eax
  mov    %ebx,%edx
  test   $0x1,%al
  je     L96
  mov    0x0(%r13,%rbx,4),%ecx
  mov    %r12d,%esi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L2
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    %ebp,%r15d
  call   <putchar@plt>
  cmp    %r12d,0x4(%rsp)
  jne    L93
L109:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L0:
  cmp    $0x1,%esi
  jle    L109
  movslq %esi,%r12
  mov    $0x1,%ebx
  lea    D12(%rip),%rbp
  jmp    L126
  cs nopw 0x0(%rax,%rax,1)
L103:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L109
L126:
  mov    %ebx,%esi
  test   $0x1,%bl
  je     L103
  mov    0x8(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,4),%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L103
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string

tool: D0: arreglo_mult[%d][%d] = %d	

tool: D12: *(arreglo[0] + %i) = %i


assistant: ```c
void print_values(int *valor, int n_rows, int n_cols) {
  int i, j;
  if (n_cols == 0) {
    for (i = 0; i < n_rows; i++) {
      if (i % 2 == 1) {
        printf("*(arreglo[0] + %i) = %i\n", i, *(valor + i));
      }
    }
  } else {
    for (i = 0; i < n_rows; i++) {
      for (j = 0; j < n_cols; j++) {
        if ((i * n_cols + j) % 2 == 1) {
          printf("arreglo_mult[%d][%d] = %d\t", i, j, *(valor + i * n_cols + j));
        }
      }
      printf("\n");
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<build_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <insert_trie@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void build_index(char file[], char *f[], int len, struct trienode **root) {
  for (int i = 0; i < len; i++) {
    insert_trie(file, f[i], root);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<build_index>:
  endbr64
  test   %edx,%edx
  jle    L3
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rcx,%r12
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r13
L12:
  mov    %r12,%rdx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <insert_trie@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  ret
```

assistant: ```c
void build_index(char file[], char *f[], int len, struct trienode **root) {
  for (int i = 0; i < len; i++) {
    insert_trie(file, f[i], root);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<build_index>:
  endbr64
  test   %edx,%edx
  jle    L9
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r13
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <insert_trie@plt>
  cmp    %r13,%rbx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void build_index(char file[], char *f[], int len, struct trienode **root) {
  for (int i = 0; i < len; i++) {
    insert_trie(file, f[i], root);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<build_index>:
  endbr64
  test   %edx,%edx
  jle    L16
  push   %r13
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r13
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%rbx),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <insert_trie@plt>
  cmp    %r13,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void build_index(char file[], char *f[], int len, struct trienode **root) {
  for (int i = 0; i < len; i++) {
    insert_trie(file, f[i], root);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isDigit8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L34
  mov    $0x0,%eax
  jmp    L98
L34:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x32,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x34,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x35,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x36,%al
  je     L44
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jne    L41
L44:
  cmpq   $0x0,-0x20(%rbp)
  je     L110
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L110:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L98
L41:
  mov    $0x0,%eax
L98:
  pop    %rbp
  ret
```

assistant: ```c
int isDigit8(const char *c, int *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == '0' || *c == '1' || *c == '2' || *c == '3' || *c == '4' || *c == '5' || *c == '6' || *c == '7') {
    if (value != NULL)
      *value = *c - 48;
    c++;
    return c - start;
  } else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isDigit8>:
  endbr64
  test   %rdi,%rdi
  je     L20
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x7,%cl
  ja     L37
  mov    $0x1,%edx
  test   %rsi,%rsi
  je     L37
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,(%rsi)
L37:
  mov    %edx,%eax
  ret
L20:
  mov    $0x0,%edx
  jmp    L37
```

assistant: ```c
int isDigit8(const char *c, int *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == '0' || *c == '1' || *c == '2' || *c == '3' || *c == '4' || *c == '5' || *c == '6' || *c == '7') {
    if (value != NULL)
      *value = *c - 48;
    c++;
    return c - start;
  } else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isDigit8>:
  endbr64
  test   %rdi,%rdi
  je     L19
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x7,%al
  ja     L11
  mov    $0x1,%r8d
  test   %rsi,%rsi
  je     L11
  movsbl %al,%eax
  mov    %eax,(%rsi)
L11:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isDigit8(const char *c, int *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == '0' || *c == '1' || *c == '2' || *c == '3' || *c == '4' || *c == '5' || *c == '6' || *c == '7') {
    if (value != NULL)
      *value = *c - 48;
    c++;
    return c - start;
  } else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isDigit8>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x7,%al
  ja     L3
  mov    $0x1,%r8d
  test   %rsi,%rsi
  je     L3
  movsbl %al,%eax
  mov    %eax,(%rsi)
L3:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int isDigit8(const char *c, int *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == '0' || *c == '1' || *c == '2' || *c == '3' || *c == '4' || *c == '5' || *c == '6' || *c == '7') {
    if (value != NULL)
      *value = *c - 48;
    c++;
    return c - start;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D25: Martin

tool: D22: Alejandro

tool: D10: Noblia

assistant: ```c
int main() {
  const char *names[] = {"Martin", "Alejandro", "Noblia"};
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  const char *names[] = {"Martin", "Alejandro", "Noblia"};
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  const char *names[] = {"Martin", "Alejandro", "Noblia"};
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  const char *names[] = {"Martin", "Alejandro", "Noblia"};
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<move_clockwise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L5
  mov    -0x40(%rbp),%r8
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <move_even@plt>
  jmp    L45
L5:
  mov    0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L40
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <move_odd@plt>
L40:
  cmpl   $0x3,-0x4(%rbp)
  jne    L25
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <move_odd@plt>
L25:
  cmpl   $0x5,-0x4(%rbp)
  jne    L45
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x40(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <move_odd@plt>
L45:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int move_clockwise(int *A, int *len_a, int *B, int *len_b, int *C, int *len_c, int m) {
  if (m % 2 == 0) {
    move_even(A, len_a, B, len_b, C, len_c);
  } else {
    int r = m % 6;
    if (r == 1) {
      move_odd(A, len_a, B, len_b);
    }
    if (r == 3) {
      move_odd(B, len_b, C, len_c);
    }
    if (r == 5) {
      move_odd(C, len_c, A, len_a);
    }
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<move_clockwise>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  mov    %rdx,%r11
  mov    %rcx,%rbx
  mov    0x10(%rsp),%esi
  test   $0x1,%sil
  je     L6
  movslq %esi,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  add    %edx,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L58
  cmp    $0x3,%eax
  je     L31
  cmp    $0x5,%eax
  jne    L11
  mov    %r10,%rcx
  mov    %rdi,%rdx
  mov    %r9,%rsi
  mov    %r8,%rdi
  call   <move_odd@plt>
  jmp    L11
L6:
  mov    %r10,%rsi
  call   <move_even@plt>
L11:
  mov    $0x0,%eax
  pop    %rbx
  ret
L58:
  mov    %r11,%rdx
  mov    %r10,%rsi
  call   <move_odd@plt>
  jmp    L11
L31:
  mov    %r9,%rcx
  mov    %r8,%rdx
  mov    %rbx,%rsi
  mov    %r11,%rdi
  call   <move_odd@plt>
  jmp    L11
```

assistant: ```c
int move_clockwise(int *A, int *len_a, int *B, int *len_b, int *C, int *len_c, int m) {
  if (m % 2 == 0) {
    move_even(A, len_a, B, len_b, C, len_c);
  } else {
    int r = m % 6;
    if (r == 1) {
      move_odd(A, len_a, B, len_b);
    }
    if (r == 3) {
      move_odd(B, len_b, C, len_c);
    }
    if (r == 5) {
      move_odd(C, len_c, A, len_a);
    }
  }
  return (0);
}
```