ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort_desc>:
  endbr64
  test   %esi,%esi
  jle    L55
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  jmp    L26
L54:
  mov    (%rdi,%r8,4),%eax
  movslq %edx,%rdx
  mov    %eax,(%rdi,%rdx,4)
L47:
  add    $0x1,%r8
  add    $0x1,%r9
L26:
  mov    %r8d,%edx
  cmp    %r9d,%esi
  jle    L55
  mov    %r9,%rax
L53:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovg  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L53
  cmp    %r8d,%edx
  jne    L54
  jmp    L47
L55:
  ret
```

assistant: ```c
void sort_desc(int vec[], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    int imin = i;
    for (j = i + 1; j < n; j++) {
      if (vec[j] > vec[imin])
        imin = j;
    }
    if (imin != i) {
      int temp = vec[i];
      vec[imin] = temp;
      vec[i] = vec[imin];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort_desc>:
  endbr64
  test   %esi,%esi
  jle    L12
  mov    $0x1,%r8d
  xor    %r9d,%r9d
  mov    %r9d,%edx
  mov    %r8d,%r10d
  cmp    %esi,%r8d
  jge    L12
  nopl   0x0(%rax)
L52:
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovg  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L13
  cmp    %r9d,%edx
  je     L46
  mov    (%rdi,%r9,4),%eax
  movslq %edx,%rdx
  mov    %eax,(%rdi,%rdx,4)
  cmp    %esi,%r10d
  jge    L12
L46:
  add    $0x1,%r9
  add    $0x1,%r8
  mov    %r9d,%edx
  mov    %r8d,%r10d
  cmp    %esi,%r8d
  jl     L52
L12:
  ret
```

assistant: ```c
void sort_desc(int vec[], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    int imin = i;
    for (j = i + 1; j < n; j++) {
      if (vec[j] > vec[imin])
        imin = j;
    }
    if (imin != i) {
      int temp = vec[i];
      vec[imin] = temp;
      vec[i] = vec[imin];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort_desc>:
  endbr64
  test   %esi,%esi
  jle    L87
  push   %r12
  push   %rbp
  lea    0x4(%rdi),%rbp
  push   %rbx
  xor    %ebx,%ebx
  lea    0x1(%rbx),%r11d
  cmp    %r11d,%esi
  jle    L17
  nopl   0x0(%rax,%rax,1)
L75:
  mov    -0x4(%rbp),%r12d
  mov    %rbp,%rax
  mov    %ebx,%r10d
  mov    %r11d,%edx
  mov    %r12d,%r8d
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L86:
  movslq %r10d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rdi,%rcx,4),%r9
  cmp    %edx,%esi
  je     L84
L88:
  mov    (%rax),%ecx
  mov    %rax,%r9
  cmp    %r8d,%ecx
  jle    L86
  mov    %edx,%r10d
  add    $0x1,%edx
  mov    %ecx,%r8d
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L88
L84:
  cmp    %ebx,%r10d
  je     L61
  mov    %r12d,(%r9)
  cmp    %r11d,%esi
  jle    L17
L61:
  mov    %r11d,%ebx
  add    $0x4,%rbp
  lea    0x1(%rbx),%r11d
  cmp    %r11d,%esi
  jg     L75
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L87:
  ret
```

assistant: ```c
void sort_desc(int vec[], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    int imin = i;
    for (j = i + 1; j < n; j++) {
      if (vec[j] > vec[imin])
        imin = j;
    }
    if (imin != i) {
      int temp = vec[i];
      vec[imin] = temp;
      vec[i] = vec[imin];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__msort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfe0,%rsp
  mov    %rdi,-0xfc8(%rbp)
  mov    %rsi,-0xfd0(%rbp)
  mov    %edx,-0xfd4(%rbp)
  mov    %ecx,-0xfd8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xfd4(%rbp),%eax
  cmp    -0xfd8(%rbp),%eax
  jne    L6
  mov    -0xfd4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xfc8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xfd4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0xfd0(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L4
L6:
  mov    -0xfd4(%rbp),%edx
  mov    -0xfd8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xfb4(%rbp)
  mov    -0xfb4(%rbp),%ecx
  mov    -0xfd4(%rbp),%edx
  lea    -0xfb0(%rbp),%rsi
  mov    -0xfc8(%rbp),%rax
  mov    %rax,%rdi
  call   <__msort>
  mov    -0xfb4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0xfd8(%rbp),%edx
  lea    -0xfb0(%rbp),%rsi
  mov    -0xfc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <__msort>
  mov    -0xfd8(%rbp),%edi
  mov    -0xfb4(%rbp),%ecx
  mov    -0xfd4(%rbp),%edx
  mov    -0xfd0(%rbp),%rsi
  lea    -0xfb0(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <__merge@plt>
L4:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void __msort(int origin[], int swap[], int start, int end) {
  int m;
  int temp[1000 + 1];
  if (start == end) {
    swap[start] = origin[start];
    return;
  }
  m = (start + end) / 2;
  __msort(origin, temp, start, m);
  __msort(origin, temp, m + 1, end);
  __merge(temp, swap, start, m, end);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__msort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%edx
  je     L19
  mov    %ecx,%ebp
  lea    (%rdx,%rcx,1),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %rsp,%r15
  mov    %r12d,%ecx
  mov    %r15,%rsi
  call   <__msort>
  lea    0x1(%r12),%edx
  mov    %ebp,%ecx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <__msort>
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <__merge@plt>
L13:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  movslq %edx,%rbx
  mov    (%rdi,%rbx,4),%eax
  mov    %eax,(%rsi,%rbx,4)
  jmp    L13
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __msort(int origin[], int swap[], int start, int end) {
  int m;
  int temp[1000 + 1];
  if (start == end) {
    swap[start] = origin[start];
    return;
  }
  m = (start + end) / 2;
  __msort(origin, temp, start, m);
  __msort(origin, temp, m + 1, end);
  __merge(temp, swap, start, m, end);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__msort>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  cmp    %ecx,%r12d
  je     L10
  lea    (%r12,%rcx,1),%eax
  mov    %rsp,%rbp
  mov    %ecx,%ebx
  mov    %r12d,%edx
  mov    %eax,%r13d
  mov    %rbp,%rsi
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%ecx
  call   <__msort>
  lea    0x1(%r13),%edx
  mov    %ebx,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <__msort>
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <__merge@plt>
L25:
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L10:
  mov    (%rdi,%r12,4),%eax
  mov    %eax,(%rsi,%r12,4)
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __msort(int origin[], int swap[], int start, int end) {
  int m;
  int temp[1000 + 1];
  if (start == end) {
    swap[start] = origin[start];
    return;
  }
  m = (start + end) / 2;
  __msort(origin, temp, start, m);
  __msort(origin, temp, m + 1, end);
  __merge(temp, swap, start, m, end);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <convert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  convert(argv[1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <convert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  convert(argv[1]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <convert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  convert(argv[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <convert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  convert(argv[1]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sectors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x7ff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xb,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x15,%edx
  add    %edx,%eax
  and    $0x7ff,%eax
  sub    %edx,%eax
  test   %eax,%eax
  jle    L3
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sectors(int nbytes) {
  int nsectors = nbytes / 2048;
  if (nbytes % 2048 > 0)
    nsectors += 1;
  return nsectors;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sectors>:
  endbr64
  lea    0x7ff(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0xb,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x15,%edx
  add    %edx,%edi
  and    $0x7ff,%edi
  sub    %edx,%edi
  test   %edi,%edi
  setg   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int sectors(int nbytes) {
  int nsectors = nbytes / 2048;
  if (nbytes % 2048 > 0)
    nsectors += 1;
  return nsectors;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sectors>:
  endbr64
  test   %edi,%edi
  lea    0x7ff(%rdi),%eax
  mov    %edi,%edx
  cmovns %edi,%eax
  sar    $0x1f,%edx
  shr    $0x15,%edx
  add    %edx,%edi
  sar    $0xb,%eax
  and    $0x7ff,%edi
  sub    %edx,%edi
  xor    %edx,%edx
  test   %edi,%edi
  setg   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int sectors(int nbytes) {
  int nsectors = nbytes / 2048;
  if (nbytes % 2048 > 0)
    nsectors += 1;
  return nsectors;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sectors>:
  endbr64
  test   %edi,%edi
  lea    0x7ff(%rdi),%eax
  mov    %edi,%edx
  cmovns %edi,%eax
  sar    $0x1f,%edx
  shr    $0x15,%edx
  add    %edx,%edi
  sar    $0xb,%eax
  and    $0x7ff,%edi
  sub    %edx,%edi
  xor    %edx,%edx
  test   %edi,%edi
  setg   %dl
  add    %edx,%eax
  ret
```

assistant: ```c
int sectors(int nbytes) {
  int nsectors = nbytes / 2048;
  if (nbytes % 2048 > 0)
    nsectors += 1;
  return nsectors;
}
```
user: Translate the below assembly code into C programming language:

```asm
<idct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <idct_M128ASM_scalar@plt>
  nop
  leave
  ret
```

assistant: ```c
void idct(short *block) {
  {
    idct_M128ASM_scalar(block);
    return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<idct>:
  endbr64
  sub    $0x8,%rsp
  call   <idct_M128ASM_scalar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void idct(short *block) {
  {
    idct_M128ASM_scalar(block);
    return;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<idct>:
  endbr64
  jmp    1050 <idct_M128ASM_scalar@plt>
```

assistant: ```c
void idct(short *block) {
  {
    idct_M128ASM_scalar(block);
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<idct>:
  endbr64
  jmp    1050 <idct_M128ASM_scalar@plt>
```

assistant: ```c
void idct(short *block) {
  {
    idct_M128ASM_scalar(block);
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<kernel_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  mov    %rax,-0x8(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <intern@plt>
  mov    %eax,%esi
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <toi_funcall@plt>
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D10: stdout

tool: D16: puts

assistant: ```c
unsigned long int kernel_puts(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("puts"), 1, arg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kernel_puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D7(%rip),%rdi
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  mov    %rax,%rbx
  lea    D12(%rip),%rdi
  call   <intern@plt>
  mov    %eax,%esi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <toi_funcall@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string
name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D7: stdout

tool: D12: puts

assistant: ```c
unsigned long int kernel_puts(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("puts"), 1, arg);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kernel_puts>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rbp
  call   <intern@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1090 <toi_funcall@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D5: stdout

tool: D6: puts

assistant: ```c
unsigned long int kernel_puts(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("puts"), 1, arg);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kernel_puts>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <intern@plt>
  mov    %eax,%edi
  call   <get_variable@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rbp
  call   <intern@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    %eax,%esi
  pop    %rbp
  mov    $0x1,%edx
  pop    %r12
  jmp    1090 <toi_funcall@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D13: stdout

tool: D7: puts

assistant: ```c
unsigned long int kernel_puts(unsigned long int recv, unsigned long int arg) {
  unsigned long int out;
  out = get_variable(intern("stdout"));
  return toi_funcall(out, intern("puts"), 1, arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,-0x3c(%rbp)
  jmp    L20
L25:
  subq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x28(%rbp)
L20:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  mov    -0x28(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L35
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L25
L35:
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jle    L38
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L53
L38:
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L53:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findPalindrome(char *s, char *b, char *f, char **l, char **r, int len) {
  int t;
  while (*f && f >= s && *b == *f) {
    b--;
    f++;
  }
  t = f - b - 1;
  if (t > len) {
    *l = b + 1;
    *r = f - 1;
  } else
    t = len;
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findPalindrome>:
  endbr64
  mov    %rdi,%r10
  mov    %r9d,%eax
  movzbl (%rdx),%edi
  cmp    %r10,%rdx
  jb     L5
  test   %dil,%dil
  je     L5
L17:
  cmp    %dil,(%rsi)
  jne    L5
  sub    $0x1,%rsi
  add    $0x1,%rdx
  movzbl (%rdx),%edi
  cmp    %rdx,%r10
  ja     L5
  test   %dil,%dil
  jne    L17
L5:
  mov    %rdx,%rdi
  sub    %rsi,%rdi
  sub    $0x1,%edi
  cmp    %eax,%edi
  jle    L51
  add    $0x1,%rsi
  mov    %rsi,(%rcx)
  sub    $0x1,%rdx
  mov    %rdx,(%r8)
  mov    %edi,%eax
L51:
  ret
```

assistant: ```c
int findPalindrome(char *s, char *b, char *f, char **l, char **r, int len) {
  int t;
  while (*f && f >= s && *b == *f) {
    b--;
    f++;
  }
  t = f - b - 1;
  if (t > len) {
    *l = b + 1;
    *r = f - 1;
  } else
    t = len;
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findPalindrome>:
  endbr64
  movzbl (%rdx),%eax
  cmp    %rdi,%rdx
  jae    L57
  jmp    L7
  xchg   %ax,%ax
L6:
  cmp    %al,(%rsi)
  jne    L7
  add    $0x1,%rdx
  sub    $0x1,%rsi
  movzbl (%rdx),%eax
  cmp    %rdx,%rdi
  ja     L7
L57:
  test   %al,%al
  jne    L6
L7:
  mov    %rdx,%rax
  sub    %rsi,%rax
  sub    $0x1,%eax
  cmp    %r9d,%eax
  jle    L56
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %rsi,(%rcx)
  mov    %rdx,(%r8)
  ret
  nopl   (%rax)
L56:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int findPalindrome(char *s, char *b, char *f, char **l, char **r, int len) {
  int t;
  while (*f && f >= s && *b == *f) {
    b--;
    f++;
  }
  t = f - b - 1;
  if (t > len) {
    *l = b + 1;
    *r = f - 1;
  } else
    t = len;
  return t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<findPalindrome>:
  endbr64
  movzbl (%rdx),%eax
  cmp    %rdi,%rdx
  jae    L37
  jmp    L57
  xchg   %ax,%ax
L44:
  cmp    %al,(%rsi)
  jne    L57
  add    $0x1,%rdx
  sub    $0x1,%rsi
  movzbl (%rdx),%eax
  cmp    %rdx,%rdi
  ja     L57
L37:
  test   %al,%al
  jne    L44
L57:
  mov    %rdx,%rax
  sub    %rsi,%rax
  sub    $0x1,%eax
  cmp    %r9d,%eax
  jle    L51
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %rsi,(%rcx)
  mov    %rdx,(%r8)
  ret
  nopl   (%rax)
L51:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int findPalindrome(char *s, char *b, char *f, char **l, char **r, int len) {
  int t;
  while (*f && f >= s && *b == *f) {
    b--;
    f++;
  }
  t = f - b - 1;
  if (t > len) {
    *l = b + 1;
    *r = f - 1;
  } else
    t = len;
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getnext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  jmp    L24
L39:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L24:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L39
L14:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    $0x0,%eax
  jmp    L46
L4:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
L46:
  pop    %rbp
  ret
```

assistant: ```c
const char *getnext(char *out, const char *s, char delim) {
  while (*s && *s != delim)
    *out++ = *s++;
  *out = 0;
  if (!*s)
    return NULL;
  return ++s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getnext>:
  endbr64
  mov    %edx,%ecx
  movzbl (%rsi),%eax
  cmp    %dl,%al
  je     L29
  test   %al,%al
  je     L29
L18:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  cmp    %cl,%al
  je     L29
  test   %al,%al
  jne    L18
L29:
  movb   $0x0,(%rdi)
  lea    0x1(%rsi),%rax
  cmpb   $0x0,(%rsi)
  mov    $0x0,%edx
  cmove  %rdx,%rax
  ret
```

assistant: ```c
const char *getnext(char *out, const char *s, char delim) {
  while (*s && *s != delim)
    *out++ = *s++;
  *out = 0;
  if (!*s)
    return NULL;
  return ++s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getnext>:
  endbr64
  movzbl (%rsi),%eax
  mov    %edx,%ecx
  cmp    %dl,%al
  je     L30
  test   %al,%al
  jne    L3
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    %cl,%al
  je     L30
L3:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L2
L30:
  xor    %edx,%edx
  movb   $0x0,(%rdi)
  lea    0x1(%rsi),%rax
  cmpb   $0x0,(%rsi)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
const char *getnext(char *out, const char *s, char delim) {
  while (*s && *s != delim)
    *out++ = *s++;
  *out = 0;
  if (!*s)
    return NULL;
  return ++s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getnext>:
  endbr64
  movzbl (%rsi),%eax
  mov    %edx,%ecx
  cmp    %dl,%al
  je     L39
  test   %al,%al
  jne    L32
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L48:
  cmp    %cl,%al
  je     L39
L32:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L48
L39:
  xor    %edx,%edx
  movb   $0x0,(%rdi)
  lea    0x1(%rsi),%rax
  cmpb   $0x0,(%rsi)
  cmove  %rdx,%rax
  ret
```

assistant: ```c
const char *getnext(char *out, const char *s, char delim) {
  while (*s && *s != delim)
    *out++ = *s++;
  *out = 0;
  if (!*s)
    return NULL;
  return ++s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  bsr    %eax,%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bsr(int i) {
  int r, t;
  asm("bsr %1,%0\n\t" : "=&q"(r), "=&q"(t) : "1"(i) : "cc");
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bsr>:
  endbr64
  bsr    %edi,%eax
  ret
```

assistant: ```c
int bsr(int i) {
  int r, t;
  asm("bsr %1,%0\n\t" : "=&q"(r), "=&q"(t) : "1"(i) : "cc");
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bsr>:
  endbr64
  bsr    %edi,%eax
  ret
```

assistant: ```c
int bsr(int i) {
  int r, t;
  asm("bsr %1,%0\n\t" : "=&q"(r), "=&q"(t) : "1"(i) : "cc");
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsr>:
  endbr64
  bsr    %edi,%eax
  ret
```

assistant: ```c
int bsr(int i) {
  int r, t;
  asm("bsr %1,%0\n\t" : "=&q"(r), "=&q"(t) : "1"(i) : "cc");
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nj_tree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fast_nj_tree@plt>
  nop
  leave
  ret
```

assistant: ```c
void nj_tree(char **tree_description, FILE *tree) {
  void fast_nj_tree(char **tree_description, FILE *tree);
  fast_nj_tree(tree_description, tree);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nj_tree>:
  endbr64
  sub    $0x8,%rsp
  call   <fast_nj_tree@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nj_tree(char **tree_description, FILE *tree) {
  void fast_nj_tree(char **tree_description, FILE *tree);
  fast_nj_tree(tree_description, tree);
}
```