user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Floyd>:
  endbr64
  sub    $0x58,%rsp
  movdqu 0x30(%rdi),%xmm0
  movdqu (%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movdqu 0x10(%rdi),%xmm2
  movdqu 0x20(%rdi),%xmm3
  mov    %rsp,%r9
  movaps %xmm0,0x30(%rsp)
  pshufd $0xff,%xmm0,%xmm0
  mov    %r9,%rdx
  mov    %r9,%rax
  movaps %xmm1,(%rsp)
  movd   %xmm0,%esi
  lea    0x40(%rsp),%r8
  movaps %xmm2,0x10(%rsp)
  movaps %xmm3,0x20(%rsp)
L62:
  mov    (%rdx),%ecx
  mov    (%rax),%edi
  add    %ecx,%edi
  cmp    %edi,(%rsp)
  jle    L144
  mov    %edi,(%rsp)
  mov    (%rdx),%ecx
L144:
  mov    0x4(%rax),%edi
  add    %ecx,%edi
  cmp    %edi,0x4(%rsp)
  jle    L128
  mov    %edi,0x4(%rsp)
  mov    (%rdx),%ecx
L128:
  mov    0x8(%rax),%edi
  add    %ecx,%edi
  cmp    0x8(%rsp),%edi
  jge    L75
  mov    %edi,0x8(%rsp)
  mov    (%rdx),%ecx
L75:
  add    0xc(%rax),%ecx
  cmp    0xc(%rsp),%ecx
  jge    L102
  mov    %ecx,0xc(%rsp)
L102:
  mov    0x10(%rdx),%ecx
  mov    (%rax),%edi
  add    %ecx,%edi
  cmp    %edi,0x10(%rsp)
  jle    L95
  mov    %edi,0x10(%rsp)
  mov    0x10(%rdx),%ecx
L95:
  mov    0x4(%rax),%edi
  add    %ecx,%edi
  cmp    0x14(%rsp),%edi
  jge    L176
  mov    %edi,0x14(%rsp)
  mov    0x10(%rdx),%ecx
L176:
  mov    0x8(%rax),%edi
  add    %ecx,%edi
  cmp    0x18(%rsp),%edi
  jge    L66
  mov    %edi,0x18(%rsp)
  mov    0x10(%rdx),%ecx
L66:
  add    0xc(%rax),%ecx
  cmp    0x1c(%rsp),%ecx
  jge    L96
  mov    %ecx,0x1c(%rsp)
L96:
  mov    0x20(%rdx),%ecx
  mov    (%rax),%edi
  add    %ecx,%edi
  cmp    0x20(%rsp),%edi
  jge    L38
  mov    %edi,0x20(%rsp)
  mov    0x20(%rdx),%ecx
L38:
  mov    0x4(%rax),%edi
  add    %ecx,%edi
  cmp    0x24(%rsp),%edi
  jge    L16
  mov    %edi,0x24(%rsp)
  mov    0x20(%rdx),%ecx
L16:
  mov    0x8(%rax),%edi
  add    %ecx,%edi
  cmp    0x28(%rsp),%edi
  jge    L136
  mov    %edi,0x28(%rsp)
  mov    0x20(%rdx),%ecx
L136:
  add    0xc(%rax),%ecx
  cmp    0x2c(%rsp),%ecx
  jge    L69
  mov    %ecx,0x2c(%rsp)
L69:
  mov    0x30(%rdx),%ecx
  mov    (%rax),%edi
  add    %ecx,%edi
  cmp    0x30(%rsp),%edi
  jge    L135
  mov    %edi,0x30(%rsp)
  mov    0x30(%rdx),%ecx
L135:
  mov    0x4(%rax),%edi
  add    %ecx,%edi
  cmp    0x34(%rsp),%edi
  jge    L99
  mov    %edi,0x34(%rsp)
  mov    0x30(%rdx),%ecx
L99:
  mov    0x8(%rax),%edi
  add    %ecx,%edi
  cmp    0x38(%rsp),%edi
  jge    L23
  mov    %edi,0x38(%rsp)
  mov    0x30(%rdx),%ecx
L23:
  add    0xc(%rax),%ecx
  cmp    %ecx,%esi
  jle    L116
  mov    %ecx,0x3c(%rsp)
  mov    %ecx,%esi
L116:
  add    $0x10,%rax
  add    $0x4,%rdx
  cmp    %r8,%rax
  jne    L62
  mov    %r9,%rdi
  call   <PrintTheSolution@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  add    $0x58,%rsp
  ret
L124:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void Floyd(int graph[][4]) {
  int distance[4][4], i, j, k;
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++)
      distance[i][j] = graph[i][j];
  for (k = 0; k < 4; k++) {
    for (i = 0; i < 4; i++) {
      for (j = 0; j < 4; j++) {
        if (distance[i][k] + distance[k][j] < distance[i][j])
          distance[i][j] = distance[i][k] + distance[k][j];
      }
    }
  }
  PrintTheSolution(distance);
}
```