ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_sleep1>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L2:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0xa,%edi
  call   <zcoroutine_sleep_millisecond@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: test_sleep1, 1s + 10ms 


assistant: ```c
void *test_sleep1(void *context) {
  while (1) {
    sleep(1);
    zcoroutine_sleep_millisecond(10);
    printf("test_sleep1, 1s + 10ms \n");
  }
  return context;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<eval_pol20_dy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  movsd  %xmm0,-0xd0(%rbp)
  movsd  %xmm1,-0xd8(%rbp)
  movsd  %xmm2,-0xe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0xb0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0xa8(%rbp)
  movsd  -0xd8(%rbp),%xmm0
  movsd  %xmm0,-0xa0(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x98(%rbp)
  movsd  -0xd0(%rbp),%xmm0
  movsd  %xmm0,-0x90(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x88(%rbp)
  movsd  -0xe0(%rbp),%xmm0
  movsd  %xmm0,-0x80(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  movsd  -0xd8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x70(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  movsd  -0xd0(%rbp),%xmm0
  mulsd  -0xe0(%rbp),%xmm0
  movsd  %xmm0,-0x60(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  movsd  -0xd0(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0xd8(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0xd0(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0xd8(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0xd8(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0xe0(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0xd8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0xe0(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0xb8(%rbp)
  movl   $0x0,-0xbc(%rbp)
  jmp    L1
L13:
  mov    -0xbc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xbc(%rbp),%eax
  cltq
  movsd  -0xb0(%rbp,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0xb8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0xb8(%rbp)
  addl   $0x1,-0xbc(%rbp)
L1:
  cmpl   $0x13,-0xbc(%rbp)
  jle    L13
  movsd  -0xb8(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: f32[2]

tool: {"D3": [0.0,2.125]}

assistant: ```c
double eval_pol20_dy(double c[20], double x, double y, double z) {
  double m[20] = {0, 0, y, 0, x, 0, z, 0, 2 * y, 0, x * z, 0, x * 2 * y, 0, x * x, 3 * y * y, z * z, 0, 2 * y * z, 0};
  double r = 0;
  for (int i = 0; i < 20; i++)
    r += c[i] * m[i];
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eval_pol20_dy>:
  endbr64
  sub    $0xb8,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movsd  %xmm0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movapd %xmm1,%xmm3
  addsd  %xmm1,%xmm3
  movsd  %xmm3,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movapd %xmm0,%xmm4
  mulsd  %xmm2,%xmm4
  movsd  %xmm4,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm4
  mulsd  %xmm1,%xmm4
  movsd  %xmm4,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,0x70(%rsp)
  movapd %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x78(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  mulsd  %xmm2,%xmm3
  movsd  %xmm3,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  pxor   %xmm1,%xmm1
  mov    %rsp,%rcx
L2:
  movsd  (%rdx,%rax,1),%xmm0
  mulsd  (%rax,%rcx,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    $0xa0,%rax
  jne    L2
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  movapd %xmm1,%xmm0
  add    $0xb8,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: f32[2]

tool: {"D7": [0.0,2.125]}

assistant: ```c
double eval_pol20_dy(double c[20], double x, double y, double z) {
  double m[20] = {0, 0, y, 0, x, 0, z, 0, 2 * y, 0, x * z, 0, x * 2 * y, 0, x * x, 3 * y * y, z * z, 0, 2 * y * z, 0};
  double r = 0;
  for (int i = 0; i < 20; i++)
    r += c[i] * m[i];
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eval_pol20_dy>:
  endbr64
  movapd %xmm0,%xmm4
  sub    $0xb8,%rsp
  movapd %xmm1,%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mulsd  %xmm2,%xmm4
  movsd  %xmm0,0x20(%rsp)
  addsd  %xmm1,%xmm3
  movsd  %xmm1,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movsd  %xmm3,0x40(%rsp)
  mulsd  %xmm2,%xmm3
  movq   $0x0,0x18(%rsp)
  movsd  %xmm4,0x50(%rsp)
  movapd %xmm0,%xmm4
  addsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm0
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x48(%rsp)
  mulsd  %xmm1,%xmm4
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x68(%rsp)
  movsd  %xmm0,0x70(%rsp)
  movsd  D8(%rip),%xmm0
  movq   $0x0,0x88(%rsp)
  mulsd  %xmm1,%xmm0
  movsd  %xmm2,0x30(%rsp)
  movq   $0x0,0x98(%rsp)
  movsd  %xmm4,0x60(%rsp)
  movsd  %xmm3,0x90(%rsp)
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x78(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x80(%rsp)
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
  jmp    L16
  nopl   (%rax)
L26:
  movsd  (%rsp,%rax,1),%xmm0
L16:
  mulsd  (%rdi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    $0xa0,%rax
  jne    L26
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  movapd %xmm1,%xmm0
  add    $0xb8,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: f32[2]

tool: {"D8": [0.0,2.125]}

assistant: ```c
double eval_pol20_dy(double c[20], double x, double y, double z) {
  double m[20] = {0, 0, y, 0, x, 0, z, 0, 2 * y, 0, x * z, 0, x * 2 * y, 0, x * x, 3 * y * y, z * z, 0, 2 * y * z, 0};
  double r = 0;
  for (int i = 0; i < 20; i++)
    r += c[i] * m[i];
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eval_pol20_dy>:
  endbr64
  movapd %xmm0,%xmm4
  sub    $0xb8,%rsp
  movupd (%rdi),%xmm5
  movapd %xmm1,%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mulsd  %xmm2,%xmm4
  movsd  %xmm0,0x20(%rsp)
  addsd  %xmm1,%xmm3
  movsd  %xmm1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm3,0x40(%rsp)
  mulsd  %xmm2,%xmm3
  movsd  %xmm4,0x50(%rsp)
  movapd %xmm0,%xmm4
  movq   $0x0,0x28(%rsp)
  addsd  %xmm0,%xmm4
  mulsd  %xmm0,%xmm0
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x58(%rsp)
  mulsd  %xmm1,%xmm4
  movq   $0x0,0x68(%rsp)
  movsd  %xmm0,0x70(%rsp)
  movsd  D6(%rip),%xmm0
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x98(%rsp)
  mulsd  %xmm1,%xmm0
  movsd  %xmm4,0x60(%rsp)
  movsd  %xmm3,0x90(%rsp)
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movsd  %xmm0,0x78(%rsp)
  movapd %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x80(%rsp)
  pxor   %xmm0,%xmm0
  mulpd  %xmm5,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movupd 0x10(%rdi),%xmm0
  mulpd  0x10(%rsp),%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  movupd 0x20(%rdi),%xmm0
  mulpd  0x20(%rsp),%xmm0
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movupd 0x30(%rdi),%xmm0
  mulpd  0x30(%rsp),%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  movupd 0x40(%rdi),%xmm0
  mulpd  0x40(%rsp),%xmm0
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movupd 0x50(%rdi),%xmm0
  mulpd  0x50(%rsp),%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  movupd 0x60(%rdi),%xmm0
  mulpd  0x60(%rsp),%xmm0
  addsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  unpckhpd %xmm0,%xmm0
  movapd %xmm0,%xmm1
  movupd 0x70(%rdi),%xmm0
  mulpd  0x70(%rsp),%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movupd 0x80(%rdi),%xmm1
  mulpd  0x80(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm0,%xmm1
  movupd 0x90(%rdi),%xmm0
  mulpd  0x90(%rsp),%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xb8,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type: f32[2]

tool: {"D6": [0.0,2.125]}

assistant: ```c
double eval_pol20_dy(double c[20], double x, double y, double z) {
  double m[20] = {0, 0, y, 0, x, 0, z, 0, 2 * y, 0, x * z, 0, x * 2 * y, 0, x * x, 3 * y * y, z * z, 0, 2 * y * z, 0};
  double r = 0;
  for (int i = 0; i < 20; i++)
    r += c[i] * m[i];
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<count_cs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
L60:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L83
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  jmp    L10
L83:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L63
  addl   $0x1,-0x4(%rbp)
  jmp    L79
L63:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7c,%al
  jne    L99
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L99
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L99
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L98
L99:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x25,%al
  jne    L98
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L98
  addl   $0x1,-0xc(%rbp)
L98:
  movl   $0x0,-0x4(%rbp)
L79:
  addl   $0x1,-0x10(%rbp)
  jmp    L60
L10:
  pop    %rbp
  ret
```

assistant: ```c
int count_cs(const char *expr) {
  int i;
  int n = 0;
  int max_n = 0;
  int anti_slash = 0;
  for (i = 0;; i++) {
    if (expr[i] == '\0')
      return (max_n > n ? max_n : n);
    if (expr[i] == '\\') {
      anti_slash++;
      continue;
    } else if (expr[i] == '|' && anti_slash % 2 == 0 && n > max_n) {
      max_n = n;
      n = 0;
    } else if (expr[i] == '%' && anti_slash % 2 == 0)
      n++;
    anti_slash = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_cs>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
  test   %dl,%dl
  je     L116
  add    $0x1,%rdi
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x0,%eax
  jmp    L27
L15:
  add    $0x1,%ecx
  jmp    L95
L43:
  test   $0x1,%cl
  jne    L40
  cmp    %esi,%eax
  jg     L91
L40:
  mov    $0x0,%ecx
L95:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L116
L27:
  cmp    $0x5c,%dl
  je     L15
  cmp    $0x7c,%dl
  je     L43
  cmp    $0x25,%dl
  je     L121
  mov    $0x0,%ecx
  jmp    L95
L121:
  and    $0x1,%ecx
  mov    $0x0,%ecx
  jne    L95
  add    $0x1,%eax
  jmp    L95
L91:
  mov    %eax,%esi
  mov    $0x0,%ecx
  mov    $0x0,%eax
  jmp    L95
L116:
  cmp    %esi,%eax
  cmovl  %esi,%eax
  ret
```

assistant: ```c
int count_cs(const char *expr) {
  int i;
  int n = 0;
  int max_n = 0;
  int anti_slash = 0;
  for (i = 0;; i++) {
    if (expr[i] == '\0')
      return (max_n > n ? max_n : n);
    if (expr[i] == '\\') {
      anti_slash++;
      continue;
    } else if (expr[i] == '|' && anti_slash % 2 == 0 && n > max_n) {
      max_n = n;
      n = 0;
    } else if (expr[i] == '%' && anti_slash % 2 == 0)
      n++;
    anti_slash = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_cs>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  add    $0x1,%rdi
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   (%rax)
L81:
  cmp    $0x5c,%dl
  je     L70
  cmp    $0x7c,%dl
  je     L21
  cmp    $0x25,%dl
  je     L48
L53:
  xor    %ecx,%ecx
L35:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L81
  cmp    %esi,%eax
  cmovl  %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  and    $0x1,%ecx
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x1,%edx
  adc    $0x0,%eax
  jmp    L35
  nop
L21:
  cmp    %esi,%eax
  jle    L53
  and    $0x1,%ecx
  jne    L53
  mov    %eax,%esi
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L35
  nopl   0x0(%rax)
L70:
  add    $0x1,%ecx
  jmp    L35
  nopl   (%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count_cs(const char *expr) {
  int i;
  int n = 0;
  int max_n = 0;
  int anti_slash = 0;
  for (i = 0;; i++) {
    if (expr[i] == '\0')
      return (max_n > n ? max_n : n);
    if (expr[i] == '\\') {
      anti_slash++;
      continue;
    } else if (expr[i] == '|' && anti_slash % 2 == 0 && n > max_n) {
      max_n = n;
      n = 0;
    } else if (expr[i] == '%' && anti_slash % 2 == 0)
      n++;
    anti_slash = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_cs>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L58
  add    $0x1,%rdi
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   (%rax)
L55:
  cmp    $0x5c,%dl
  je     L51
  cmp    $0x7c,%dl
  je     L0
  cmp    $0x25,%dl
  je     L99
L83:
  xor    %ecx,%ecx
L81:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L55
  cmp    %esi,%eax
  cmovl  %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L99:
  and    $0x1,%ecx
  mov    %ecx,%edx
  xor    %ecx,%ecx
  cmp    $0x1,%edx
  adc    $0x0,%eax
  jmp    L81
  nop
L0:
  cmp    %esi,%eax
  jle    L83
  and    $0x1,%ecx
  jne    L83
  mov    %eax,%esi
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L81
  nopl   0x0(%rax)
L51:
  add    $0x1,%ecx
  jmp    L81
  nopl   (%rax)
L58:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count_cs(const char *expr) {
  int i;
  int n = 0;
  int max_n = 0;
  int anti_slash = 0;
  for (i = 0;; i++) {
    if (expr[i] == '\0')
      return (max_n > n ? max_n : n);
    if (expr[i] == '\\') {
      anti_slash++;
      continue;
    } else if (expr[i] == '|' && anti_slash % 2 == 0 && n > max_n) {
      max_n = n;
      n = 0;
    } else if (expr[i] == '%' && anti_slash % 2 == 0)
      n++;
    anti_slash = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<doubles_mat44_rotate_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <doubles_mat44_identity@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x28,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x30,%rax
  movsd  -0x10(%rbp),%xmm0
  movq   D0(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x48,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x50,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
void doubles_mat44_rotate_x(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[1 * 4 + 1] = c;
  out[1 * 4 + 2] = -s;
  out[2 * 4 + 1] = s;
  out[2 * 4 + 2] = c;
}
```
user: What is the c source code of the assembly code below?

```asm
<doubles_mat44_rotate_x>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbp
  mov    %rdi,%rbx
  call   <doubles_mat44_identity@plt>
  movq   %rbp,%xmm0
  call   <sin@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movq   %xmm2,%r12
  movq   %rbp,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  %xmm0,0x28(%rbx)
  movq   %r12,%xmm1
  xorpd  D7(%rip),%xmm1
  movsd  %xmm1,0x30(%rbx)
  mov    %r12,0x48(%rbx)
  movsd  %xmm0,0x50(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_x(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[1 * 4 + 1] = c;
  out[1 * 4 + 2] = -s;
  out[2 * 4 + 1] = s;
  out[2 * 4 + 2] = c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<doubles_mat44_rotate_x>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  movsd  %xmm1,(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  movapd %xmm1,%xmm2
  xorpd  D7(%rip),%xmm2
  movsd  %xmm1,0x48(%rbx)
  movsd  %xmm2,0x30(%rbx)
  movsd  %xmm0,0x28(%rbx)
  movsd  %xmm0,0x50(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_x(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[1 * 4 + 1] = c;
  out[1 * 4 + 2] = -s;
  out[2 * 4 + 1] = s;
  out[2 * 4 + 2] = c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<doubles_mat44_rotate_x>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  call   <doubles_mat44_identity@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <sin@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  movsd  %xmm1,(%rsp)
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  movapd %xmm1,%xmm3
  xorpd  D9(%rip),%xmm3
  movapd %xmm0,%xmm2
  unpcklpd %xmm0,%xmm1
  unpcklpd %xmm3,%xmm2
  movups %xmm1,0x48(%rbx)
  movups %xmm2,0x28(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void doubles_mat44_rotate_x(double rad, double out[16]) {
  doubles_mat44_identity(out);
  double s = (double)sin(rad), c = (double)cos(rad);
  out[1 * 4 + 1] = c;
  out[1 * 4 + 2] = -s;
  out[2 * 4 + 1] = s;
  out[2 * 4 + 2] = c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L78:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <reads@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L95
  mov    D30(%rip),%rax
  mov    (%rax),%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L32
  jmp    L9
L32:
  mov    D30(%rip),%rax
  mov    (%rax),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L87
  mov    $0xffffffff,%eax
  jmp    L100
L87:
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L100
L95:
  cmpl   $0x0,-0x14(%rbp)
  je     L109
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L9:
  cmpq   $0x0,-0x10(%rbp)
  jne    L78
  jmp    L68
L29:
  nop
  jmp    L68
L109:
  nop
L68:
  mov    -0x38(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L100:
  leave
  ret
```

assistant: ```c
ssize_t readn(FILE *stream, void *buf, size_t n) {
  ssize_t ret;
  size_t nleft = n;
  char *buffer = (char *)buf;
  while (nleft > 0) {
    ret = reads(stream, buf, nleft);
    if (ret == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EBADF)
        return -1;
      if (nleft == n)
        return -1;
      else
        break;
    } else if (ret == 0)
      break;
    else {
      nleft -= ret;
      buffer += ret;
    }
  }
  return n - nleft;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readn>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L79
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  jmp    L65
L78:
  mov    D23(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D14(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L15
  mov    D17(%rip),%rcx
  cmp    %rdx,(%rcx)
  je     L25
  cmp    %rbx,%rbp
  je     L25
L32:
  mov    %ebp,%eax
  sub    %ebx,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  test   %rbx,%rbx
  je     L32
L65:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <reads@plt>
  cmp    $0xffffffff,%eax
  je     L78
  test   %eax,%eax
  je     L32
  cltq
  sub    %rax,%rbx
  jmp    L15
L79:
  mov    %rdx,%rbx
  jmp    L32
```

assistant: ```c
ssize_t readn(FILE *stream, void *buf, size_t n) {
  ssize_t ret;
  size_t nleft = n;
  char *buffer = (char *)buf;
  while (nleft > 0) {
    ret = reads(stream, buf, nleft);
    if (ret == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EBADF)
        return -1;
      if (nleft == n)
        return -1;
      else
        break;
    } else if (ret == 0)
      break;
    else {
      nleft -= ret;
      buffer += ret;
    }
  }
  return n - nleft;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readn>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L51
L42:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <reads@plt>
  cmp    $0xffffffff,%eax
  je     L47
  test   %eax,%eax
  je     L10
  cltq
  sub    %rax,%rbx
  jne    L42
L51:
  xor    %ebx,%ebx
  jmp    L10
  nopl   0x0(%rax)
L47:
  mov    D24(%rip),%rdx
  mov    D26(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    (%rcx),%rdx
  je     L42
  mov    D21(%rip),%rcx
  cmp    %rdx,(%rcx)
  je     L53
  cmp    %rbx,%rbp
  je     L53
L10:
  mov    %ebp,%eax
  sub    %ebx,%eax
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t readn(FILE *stream, void *buf, size_t n) {
  ssize_t ret;
  size_t nleft = n;
  char *buffer = (char *)buf;
  while (nleft > 0) {
    ret = reads(stream, buf, nleft);
    if (ret == -1) {
      if (errno == EINTR)
        continue;
      else if (errno == EBADF)
        return -1;
      if (nleft == n)
        return -1;
      else
        break;
    } else if (ret == 0)
      break;
    else {
      nleft -= ret;
      buffer += ret;
    }
  }
  return n - nleft;
}
```