ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<AddEdge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%edx
  imul   $0x2a,%edx,%r15d
  test   %r15d,%r15d
  jle    L25
  sar    %ecx
  imul   $0x54,%edx,%ebp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %ecx,0xc(%rsp)
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  movslq %ebx,%rax
  mov    0x8(%r12,%rax,4),%esi
  xor    %r13d,%esi
  mov    %esi,%eax
  test   $0xfffffffe,%eax
  je     L23
  add    $0x2,%ebx
  cmp    %ebx,%r15d
  jg     L7
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  or     %ebx,%eax
  mov    %ebp,%esi
  mov    %edx,0x8(%rsp)
  cltq
  lea    (%r14,%rax,4),%rdi
  call   <__sync_fetch_and_add@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  cltq
  mov    %ecx,(%r14,%rax,4)
  movl   $0x0,0x4(%r14,%rax,4)
  imul   $0x1862,%ebx,%eax
  sar    $0x12,%eax
  add    $0x1,%eax
  imul   $0x2a,%eax,%ebx
  cmp    %eax,%edx
  jg     L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void AddEdge(uint32_t *pu32TargetNodes, uint32_t *pu32Header, uint64_t u32Node, uint32_t u32Edge) {
  uint32_t u32NumSols42 = pu32TargetNodes[0] * 42;
  uint32_t i = 0;
  while (i < u32NumSols42) {
    uint32_t u32Xor = u32Node ^ pu32TargetNodes[i + 2];
    if ((u32Xor & -2) == 0) {
      uint32_t u32WrPtr = __sync_fetch_and_add(&(pu32Header[i | u32Xor]), u32NumSols42 * 2);
      pu32Header[u32WrPtr] = u32Edge >> 1;
      pu32Header[u32WrPtr + 1] = 0;
      i *= 6242;
      i >>= 18;
      i += 1;
      i *= 42;
      continue;
    }
    i += 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<hide_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %rcx,-0x90(%rbp)
  mov    %r8,-0x98(%rbp)
  mov    %r9,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  movl   $0x0,-0x64(%rbp)
  jmp    L5
L14:
  mov    -0x64(%rbp),%eax
  imul   0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    0x18(%rbp),%edi
  mov    -0x64(%rbp),%edx
  mov    -0x80(%rbp),%rsi
  mov    -0x78(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x88(%rbp)
  mov    %edi,%r9d
  mov    0x10(%rbp),%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <hide_pixels@plt>
  add    $0x10,%rsp
  addl   $0x1,-0x64(%rbp)
L5:
  mov    -0x64(%rbp),%eax
  cltq
  cmp    %rax,-0x90(%rbp)
  jg     L14
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int hide_image(cover_image, message_image, mlength, mwidth, clength, cwidth, lsb, n)
int lsb, n;
long clength, cwidth, mlength, mwidth;
short **cover_image, **message_image;
{
  char response[80];
  int h_counter = 0;
  for (h_counter = 0; h_counter < mwidth; h_counter++) {
    hide_pixels(cover_image, message_image, h_counter, h_counter * n, lsb, n, mlength);
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hide_image>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    0x58(%rsp),%r12d
  test   %rcx,%rcx
  jle    L10
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %rcx,%r13
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L18:
  sub    $0x8,%rsp
  push   %r15
  mov    %r12d,%r9d
  mov    0x60(%rsp),%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    0x18(%rsp),%rdi
  mov    $0x0,%eax
  call   <hide_pixels@plt>
  add    $0x1,%rbx
  add    %r12d,%ebp
  add    $0x10,%rsp
  cmp    %r13,%rbx
  jne    L18
L10:
  mov    $0x1,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int hide_image(cover_image, message_image, mlength, mwidth, clength, cwidth, lsb, n)
int lsb, n;
long clength, cwidth, mlength, mwidth;
short **cover_image, **message_image;
{
  char response[80];
  int h_counter = 0;
  for (h_counter = 0; h_counter < mwidth; h_counter++) {
    hide_pixels(cover_image, message_image, h_counter, h_counter * n, lsb, n, mlength);
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hide_image>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r15d
  mov    0x58(%rsp),%r14d
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %rcx,%rcx
  jle    L2
  mov    %rdi,%r12
  mov    %rsi,%r13
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r14d,%r9d
  push   0x8(%rsp)
  mov    %r15d,%r8d
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    %r14d,%ebp
  call   <hide_pixels@plt>
  pop    %rax
  pop    %rdx
  cmp    0x8(%rsp),%rbx
  jne    L4
L2:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int hide_image(cover_image, message_image, mlength, mwidth, clength, cwidth, lsb, n)
int lsb, n;
long clength, cwidth, mlength, mwidth;
short **cover_image, **message_image;
{
  char response[80];
  int h_counter = 0;
  for (h_counter = 0; h_counter < mwidth; h_counter++) {
    hide_pixels(cover_image, message_image, h_counter, h_counter * n, lsb, n, mlength);
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hide_image>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x50(%rsp),%r15d
  mov    0x58(%rsp),%r14d
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  test   %rcx,%rcx
  jle    L8
  mov    %rdi,%r12
  mov    %rsi,%r13
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L11:
  sub    $0x8,%rsp
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r14d,%r9d
  push   0x8(%rsp)
  mov    %r15d,%r8d
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    %r14d,%ebp
  call   <hide_pixels@plt>
  pop    %rax
  pop    %rdx
  cmp    0x8(%rsp),%rbx
  jne    L11
L8:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int hide_image(cover_image, message_image, mlength, mwidth, clength, cwidth, lsb, n)
int lsb, n;
long clength, cwidth, mlength, mwidth;
short **cover_image, **message_image;
{
  char response[80];
  int h_counter = 0;
  for (h_counter = 0; h_counter < mwidth; h_counter++) {
    hide_pixels(cover_image, message_image, h_counter, h_counter * n, lsb, n, mlength);
  }
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L25:
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x3,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x3(%rax),%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x10(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L25
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L3:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L24:
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L3
  mov    -0xc(%rbp),%eax
  lea    -0x2b2feb28(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] - 724560680UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%r8d
  test   %r8d,%r8d
  je     L9
  mov    $0x0,%edx
  lea    0x4(%rsp),%r9
L18:
  mov    %edx,%eax
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %dil,(%rax)
  mov    %cl,0x3(%rax)
  add    $0x2,%edx
  cmp    %r8d,%edx
  jb     L18
  shll   0x4(%rsp)
L9:
  mov    0x4(%rsp),%eax
  sub    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] - 724560680UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  test   %r8d,%r8d
  je     L26
  xor    %edx,%edx
  lea    0x4(%rsp),%r9
  nopl   0x0(%rax)
L25:
  mov    %edx,%eax
  add    $0x2,%edx
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %cl,0x3(%rax)
  mov    %dil,(%rax)
  cmp    %r8d,%edx
  jb     L25
  mov    0x4(%rsp),%eax
  add    %eax,%eax
L26:
  sub    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] - 724560680UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  mov    %eax,0x4(%rsp)
  test   %r8d,%r8d
  je     L2
  xor    %edx,%edx
  lea    0x4(%rsp),%r9
  nopl   0x0(%rax)
L29:
  mov    %edx,%eax
  add    $0x2,%edx
  lea    (%r9,%rax,4),%rax
  movzbl (%rax),%ecx
  movzbl 0x3(%rax),%edi
  mov    %cl,0x3(%rax)
  mov    %dil,(%rax)
  cmp    %r8d,%edx
  jb     L29
  mov    0x4(%rsp),%eax
  add    %eax,%eax
L2:
  sub    $0x2b2feb28,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] + state[0UL];
      local1++;
    }
    output[0UL] = state[0UL] - 724560680UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fls64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x20,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fls@plt>
  add    $0x20,%eax
  jmp    L4
L3:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fls@plt>
L4:
  leave
  ret
```

assistant: ```c
int fls64(__u64 x) {
  __u32 h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fls64>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  jne    L6
  call   <fls@plt>
L2:
  add    $0x8,%rsp
  ret
L6:
  mov    %eax,%edi
  call   <fls@plt>
  add    $0x20,%eax
  jmp    L2
```

assistant: ```c
int fls64(__u64 x) {
  __u32 h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: What is the c source code of the assembly code below:

```asm
<fls64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x20,%ecx
  sar    %cl,%r8d
  test   %r8d,%r8d
  jne    L7
  jmp    1050 <fls@plt>
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  mov    %r8d,%edi
  call   <fls@plt>
  add    $0x8,%rsp
  add    $0x20,%eax
  ret
```

assistant: ```c
int fls64(__u64 x) {
  __u32 h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fls64>:
  endbr64
  mov    %edi,%r8d
  mov    $0x20,%ecx
  sar    %cl,%r8d
  test   %r8d,%r8d
  jne    L9
  jmp    1050 <fls@plt>
  nopl   0x0(%rax)
L9:
  sub    $0x8,%rsp
  mov    %r8d,%edi
  call   <fls@plt>
  add    $0x8,%rsp
  add    $0x20,%eax
  ret
```

assistant: ```c
int fls64(__u64 x) {
  __u32 h = x >> 32;
  if (h)
    return fls(h) + 32;
  return fls(x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L50
L92:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L50:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L92
  movl   $0x0,-0x1c(%rbp)
  jmp    L106
L103:
  movl   $0x0,-0x18(%rbp)
  jmp    L97
L42:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L57
L12:
  nop
L57:
  addl   $0x1,-0x18(%rbp)
L97:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L42
  addl   $0x1,-0x1c(%rbp)
L106:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L103
  movl   $0x0,-0x18(%rbp)
  jmp    L80
L66:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L80:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L66
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string

tool: D12: %d

tool: D16: %d 

assistant: ```c
int main() {
  int *arr, n, i, j;
  scanf("%d", &n);
  arr = (int *)malloc(sizeof(int) * n);
  for (i = 0; i < n; i++) {
    scanf("%d", arr + i);
  }
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
      } else {
        continue;
      }
    }
  }
  for (j = 0; j < n; j++) {
    printf("%d ", *(arr + j));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L47
  mov    %rax,%rbx
  mov    %rax,%r12
  mov    $0x0,%ebp
  lea    D3(%rip),%r13
L103:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  mov    0x4(%rsp),%eax
  add    $0x4,%r12
  cmp    %ebp,%eax
  jg     L103
  mov    $0x0,%r8d
  cmp    $0x1,%eax
  jg     L37
L84:
  cmpl   $0x0,0x4(%rsp)
  jle    L47
  mov    $0x0,%ebp
  lea    D27(%rip),%r12
L64:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,0x4(%rsp)
  jg     L64
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %esi,(%rdi)
  mov    %edx,(%rax)
L97:
  add    $0x1,%ecx
  mov    0x4(%rsp),%edi
  lea    -0x1(%rdi),%edx
  cmp    %ecx,%edx
  jle    L44
L17:
  mov    %rax,%rdi
  mov    (%rax),%edx
  add    $0x4,%rax
  mov    (%rax),%esi
  cmp    %esi,%edx
  jg     L0
  jmp    L97
L44:
  add    $0x1,%r8d
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r8d,%eax
  jle    L84
L37:
  mov    %rbx,%rax
  mov    $0x0,%ecx
  cmpl   $0x1,0x4(%rsp)
  jg     L17
  jmp    L44
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D27
type_guessed: string

tool: D3: %d

tool: D27: %d 

assistant: ```c
int main() {
  int *arr, n, i, j;
  scanf("%d", &n);
  arr = (int *)malloc(sizeof(int) * n);
  for (i = 0; i < n; i++) {
    scanf("%d", arr + i);
  }
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
      } else {
        continue;
      }
    }
  }
  for (j = 0; j < n; j++) {
    printf("%d ", *(arr + j));
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L16
  mov    %rax,%rbx
  mov    %rax,%r12
  xor    %ebp,%ebp
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    %ebp,%edi
  jg     L54
  cmp    $0x1,%edi
  jle    L91
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rax
  xor    %edx,%edx
  nopl   (%rax)
L26:
  mov    (%rax),%ecx
  mov    %rax,%r8
  mov    0x4(%rax),%esi
  add    $0x4,%rax
  cmp    %esi,%ecx
  jle    L24
  mov    %esi,(%r8)
  mov    %ecx,(%rax)
  mov    0x4(%rsp),%edi
L24:
  add    $0x1,%edx
  lea    -0x1(%rdi),%ecx
  cmp    %edx,%ecx
  jg     L26
  add    $0x1,%r9d
  cmp    %r9d,%ecx
  jle    L91
  cmp    $0x1,%edi
  jg     L5
L91:
  xor    %ebp,%ebp
  lea    D12(%rip),%r12
  test   %edi,%edi
  jle    L16
  xchg   %ax,%ax
L61:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L61
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D13: %d

tool: D12: %d 

assistant: ```c
int main() {
  int *arr, n, i, j;
  scanf("%d", &n);
  arr = (int *)malloc(sizeof(int) * n);
  for (i = 0; i < n; i++) {
    scanf("%d", arr + i);
  }
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        int temp = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = temp;
      } else {
        continue;
      }
    }
  }
  for (j = 0; j < n; j++) {
    printf("%d ", *(arr + j));
  }
  return 0;
}
```