ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<be32enc_vect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L7:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rcx
  shl    $0x4,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <libcperciva_be32enc@plt>
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x28(%rbp),%rax
  shr    $0x2,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void be32enc_vect(uint8_t *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++)
    libcperciva_be32enc(dst + i * 4, src[i]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<be32enc_vect>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  shr    $0x2,%r13
  cmp    $0x3,%rdx
  jbe    L18
  mov    %rsi,%r12
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L10:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  call   <libcperciva_be32enc@plt>
  add    $0x1,%rbx
  add    $0x10,%rbp
  cmp    %r13,%rbx
  jb     L10
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void be32enc_vect(uint8_t *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++)
    libcperciva_be32enc(dst + i * 4, src[i]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<be32enc_vect>:
  endbr64
  shr    $0x2,%rdx
  je     L12
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  add    $0x10,%rbp
  call   <libcperciva_be32enc@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  ret
```

assistant: ```c
void be32enc_vect(uint8_t *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++)
    libcperciva_be32enc(dst + i * 4, src[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<be32enc_vect>:
  endbr64
  shr    $0x2,%rdx
  je     L18
  push   %r12
  lea    (%rsi,%rdx,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  add    $0x10,%rbp
  call   <libcperciva_be32enc@plt>
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void be32enc_vect(uint8_t *dst, const uint32_t *src, size_t len) {
  size_t i;
  for (i = 0; i < len / 4; i++)
    libcperciva_be32enc(dst + i * 4, src[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_requires_ensures_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L23:
  movl   $0x0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x4,-0x14(%rbp)
  jle    L23
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void test_requires_ensures_loop() {
  int i = 0;
  while (i < 5) {
    int x = 0;
    int *ptr = &x;
    i = i + 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_requires_ensures_loop>:
  endbr64
  ret
```

assistant: ```c
void test_requires_ensures_loop() {
  int i = 0;
  while (i < 5) {
    int x = 0;
    int *ptr = &x;
    i = i + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_requires_ensures_loop>:
  endbr64
  ret
```

assistant: ```c
void test_requires_ensures_loop() {
  int i = 0;
  while (i < 5) {
    int x = 0;
    int *ptr = &x;
    i = i + 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_requires_ensures_loop>:
  endbr64
  ret
```

assistant: ```c
void test_requires_ensures_loop() {
  int i = 0;
  while (i < 5) {
    int x = 0;
    int *ptr = &x;
    i = i + 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<jiaquan_Manhattan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L2
  movsd  -0x10(%rbp),%xmm1
  movsd  D29(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm2
  movsd  D13(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L18
L2:
  movsd  -0x10(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm2
  movsd  D29(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
L18:
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D29
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D13
type_infered: byte[8]

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
unsigned int jiaquan_Manhattan(int sx, int sy, int ex, int ey) {
  double nn, dx, dy;
  dx = abs(sx - ex);
  dy = abs(sy - ey);
  if (dx > dy)
    nn = 10 * dx + 6 * dy;
  else
    nn = 6 * dx + 10 * dy;
  return nn;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<jiaquan_Manhattan>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %ecx,%r12d
  sub    %edx,%edi
  call   <abs@plt>
  movq   %xmm0,%rbx
  mov    %ebp,%edi
  sub    %r12d,%edi
  call   <abs@plt>
  movq   %rbx,%xmm2
  comisd %xmm0,%xmm2
  jbe    L8
  movq   %rbx,%xmm1
  mulsd  D37(%rip),%xmm1
  mulsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
L9:
  cvttsd2si %xmm0,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  movq   %rbx,%xmm1
  mulsd  D18(%rip),%xmm1
  mulsd  D37(%rip),%xmm0
  addsd  %xmm1,%xmm0
  jmp    L9
```

tool_calls: name: read_data
arguments: data_tag: D37
type_infered: byte[8]
name: read_data
arguments: data_tag: D18
type_infered: byte[8]

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
unsigned int jiaquan_Manhattan(int sx, int sy, int ex, int ey) {
  double nn, dx, dy;
  dx = abs(sx - ex);
  dy = abs(sy - ey);
  if (dx > dy)
    nn = 10 * dx + 6 * dy;
  else
    nn = 6 * dx + 10 * dy;
  return nn;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jiaquan_Manhattan>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  sub    %edx,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    %ebp,%ebx
  sub    $0x18,%rsp
  call   <abs@plt>
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <abs@plt>
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L0
  mulsd  D33(%rip),%xmm1
  mulsd  D32(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
L0:
  mulsd  D32(%rip),%xmm1
  mulsd  D33(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D33
type: byte[8]
name: disassemble_data
arguments: tag: D32
type: byte[8]

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
unsigned int jiaquan_Manhattan(int sx, int sy, int ex, int ey) {
  double nn, dx, dy;
  dx = abs(sx - ex);
  dy = abs(sy - ey);
  if (dx > dy)
    nn = 10 * dx + 6 * dy;
  else
    nn = 6 * dx + 10 * dy;
  return nn;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<jiaquan_Manhattan>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  sub    %edx,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    %ebp,%ebx
  sub    $0x18,%rsp
  call   <abs@plt>
  mov    %ebx,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <abs@plt>
  movsd  0x8(%rsp),%xmm1
  comisd %xmm0,%xmm1
  jbe    L1
  mulsd  D13(%rip),%xmm1
  mulsd  D4(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
L1:
  mulsd  D4(%rip),%xmm1
  mulsd  D13(%rip),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type: byte[8]
name: extract_symbolic_data
arguments: label: D4
type: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
unsigned int jiaquan_Manhattan(int sx, int sy, int ex, int ey) {
  double nn, dx, dy;
  dx = abs(sx - ex);
  dy = abs(sy - ey);
  if (dx > dy)
    nn = 10 * dx + 6 * dy;
  else
    nn = 6 * dx + 10 * dy;
  return nn;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<paths_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L43
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jne    L43
  mov    $0x1,%eax
  jmp    L29
L43:
  mov    -0x18(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L30
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  call   <paths_aux>
  add    %rax,-0x8(%rbp)
L30:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jae    L5
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <paths_aux>
  add    %rax,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
L29:
  leave
  ret
```

assistant: ```c
unsigned long long paths_aux(size_t curr_x, size_t curr_y, size_t x, size_t y) {
  unsigned long long res = 0;
  if (curr_x == x && curr_y == y) {
    return 1;
  }
  if (curr_x < x) {
    res += paths_aux(curr_x + 1, curr_y, x, y);
  }
  if (curr_y < y) {
    res += paths_aux(curr_x, curr_y + 1, x, y);
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<paths_aux>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%rbp
  cmp    %rdx,%rdi
  jne    L25
  mov    $0x1,%r14d
  cmp    %rcx,%rsi
  je     L41
L25:
  mov    $0x0,%r14d
  cmp    %r13,%r12
  jb     L47
L10:
  cmp    %rbp,%rbx
  jb     L17
L41:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  lea    0x1(%r12),%rdi
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  call   <paths_aux>
  mov    %rax,%r14
  jmp    L10
L17:
  lea    0x1(%rbx),%rsi
  mov    %rbp,%rcx
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <paths_aux>
  add    %rax,%r14
  jmp    L41
```

assistant: ```c
unsigned long long paths_aux(size_t curr_x, size_t curr_y, size_t x, size_t y) {
  unsigned long long res = 0;
  if (curr_x == x && curr_y == y) {
    return 1;
  }
  if (curr_x < x) {
    res += paths_aux(curr_x + 1, curr_y, x, y);
  }
  if (curr_y < y) {
    res += paths_aux(curr_x, curr_y + 1, x, y);
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psvec3_cross>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vec3_cross@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_cross(struct vec3 *result, struct vec3 *a, struct vec3 *b) {
  vec3_cross((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<psvec3_cross>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec3_cross@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_cross(struct vec3 *result, struct vec3 *a, struct vec3 *b) {
  vec3_cross((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<psvec3_cross>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_cross@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_cross(struct vec3 *result, struct vec3 *a, struct vec3 *b) {
  vec3_cross((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psvec3_cross>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec3_cross@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec3 *psvec3_cross(struct vec3 *result, struct vec3 *a, struct vec3 *b) {
  vec3_cross((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_rmdir_recursive_fn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  test   %rax,%rax
  jne    L21
  mov    $0x0,%eax
  jmp    L34
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  test   %rax,%rax
  jne    L18
  mov    $0x0,%eax
  jmp    L34
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%r8
  lea    D5(%rip),%rax
  mov    %rax,%rcx
  mov    $0x6b,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <fatal_e_@plt>
  mov    $0x1,%eax
L34:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string

tool: D5: Can't remove "%s"

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c

assistant: ```c
int _rmdir_recursive_fn(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  if (unlink(fpath) == 0)
    return 0;
  else if (rmdir(fpath) == 0)
    return 0;
  else
    do {
      fatal_e_(3, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c", 107, "Can't remove \"%s\"", fpath);
    } while (0);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_rmdir_recursive_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlink@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L4
L1:
  pop    %rbx
  ret
L4:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L1
  mov    %rbx,%r8
  lea    D17(%rip),%rcx
  mov    $0x6b,%edx
  lea    D5(%rip),%rsi
  mov    $0x3,%edi
  call   <fatal_e_@plt>
  mov    $0x1,%eax
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D17: Can't remove "%s"

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c

assistant: ```c
int _rmdir_recursive_fn(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  if (unlink(fpath) == 0)
    return 0;
  else if (rmdir(fpath) == 0)
    return 0;
  else
    do {
      fatal_e_(3, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c", 107, "Can't remove \"%s\"", fpath);
    } while (0);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_rmdir_recursive_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlink@plt>
  test   %rax,%rax
  jne    L12
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  test   %rax,%rax
  je     L1
  mov    %rbx,%r8
  lea    D10(%rip),%rcx
  mov    $0x6b,%edx
  mov    $0x3,%edi
  lea    D1(%rip),%rsi
  call   <fatal_e_@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D10: Can't remove "%s"

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c

assistant: ```c
int _rmdir_recursive_fn(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  if (unlink(fpath) == 0)
    return 0;
  else if (rmdir(fpath) == 0)
    return 0;
  else
    do {
      fatal_e_(3, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c", 107, "Can't remove \"%s\"", fpath);
    } while (0);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_rmdir_recursive_fn>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlink@plt>
  test   %rax,%rax
  jne    L12
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %rbx,%rdi
  call   <rmdir@plt>
  test   %rax,%rax
  je     L17
  mov    %rbx,%r8
  lea    D10(%rip),%rcx
  mov    $0x6b,%edx
  mov    $0x3,%edi
  lea    D18(%rip),%rsi
  call   <fatal_e_@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string

tool: D10: Can't remove "%s"

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c

assistant: ```c
int _rmdir_recursive_fn(const char *fpath, const struct stat *sb, int typeflag, struct FTW *ftwbuf) {
  if (unlink(fpath) == 0)
    return 0;
  else if (rmdir(fpath) == 0)
    return 0;
  else
    do {
      fatal_e_(3, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/drkitty/netroper/refs/heads/master/netroper.c", 107, "Can't remove \"%s\"", fpath);
    } while (0);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply243>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L7
L0:
  movl   $0x0,-0x3c(%rbp)
  jmp    L35
L38:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L35:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L38
  addl   $0x1,-0x40(%rbp)
L7:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply243(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply243>:
  endbr64
  test   %edi,%edi
  jle    L28
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L2:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L9:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L9
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  ret
```

assistant: ```c
void multiply243(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply243>:
  endbr64
  test   %edi,%edi
  jle    L15
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L20
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L28
  pop    %rbx
  ret
L15:
  ret
```

assistant: ```c
void multiply243(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```