ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  jmp    L13
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <fun2>
  mov    %eax,%esi
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rsi,%rcx,1),%eax
L13:
  leave
  ret
```

assistant: ```c
int fun2(int n) {
  if (n == 0)
    return n;
  return fun2(n / 10) + n % 10;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fun2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L2
L1:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  movslq %edi,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  mov    %ebp,%edi
  call   <fun2>
  mov    %eax,%edx
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    %edx,%ebx
  jmp    L1
```

assistant: ```c
int fun2(int n) {
  if (n == 0)
    return n;
  return fun2(n / 10) + n % 10;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fun2>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L6
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %edi,%rdi
  mov    %rdi,%rax
  imul   $0x66666667,%rdi,%rdi
  cltd
  sar    $0x22,%rdi
  sub    %edx,%edi
  lea    (%rdi,%rdi,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    %eax,%r8d
  test   %edi,%edi
  jne    L13
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun2(int n) {
  if (n == 0)
    return n;
  return fun2(n / 10) + n % 10;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fun2>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L9
  nopl   0x0(%rax,%rax,1)
L11:
  movslq %edi,%rdi
  mov    %rdi,%rax
  imul   $0x66666667,%rdi,%rdi
  cltd
  sar    $0x22,%rdi
  sub    %edx,%edi
  lea    (%rdi,%rdi,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    %eax,%r8d
  test   %edi,%edi
  jne    L11
L9:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fun2(int n) {
  if (n == 0)
    return n;
  return fun2(n / 10) + n % 10;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dns_parse_rr_label>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%rdi
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L77
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %ebp,%eax
  shr    $0x6,%al
  cmp    $0x3,%al
  je     L73
  lea    0x1(%rdi),%rsi
  mov    %rsi,(%rbx)
  movzbl %bpl,%r14d
  lea    (%rsi,%r14,1),%rax
  cmp    %rax,%r13
  jb     L67
  movzbl %bpl,%edx
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <buffer_insert@plt>
  mov    $0x1,%edx
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <buffer_insert@plt>
  add    %r14,(%rbx)
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %ebp,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  mov    $0x0,%eax
  call   <read_uint16@plt>
  and    $0x3fff,%eax
  add    %r14,%rax
  mov    %rax,(%rsp)
  addq   $0x2,(%rbx)
  mov    %rsp,%rbx
L61:
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <dns_parse_rr_label>
  movsbl %al,%eax
  test   %eax,%eax
  jg     L61
  jne    L50
  mov    $0x0,%ebp
  jmp    L49
L50:
  lea    D46(%rip),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <log_debug@plt>
  mov    $0xffffffff,%ebp
  jmp    L49
L67:
  lea    D47(%rip),%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <log_debug@plt>
  mov    $0xffffffff,%ebp
  jmp    L49
L77:
  add    $0x1,%rdi
  mov    %rdi,(%rsi)
  mov    $0x0,%ebp
  jmp    L49
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D46
data_type: string
name: read_data
arguments: tag: D30
data_type: string
name: read_data
arguments: tag: D47
data_type: string

tool: D4: .

tool: D46: Failed to read label pointer.

tool: D30: dns_parse_rr_label

tool: D47: End of label outside of buffer!

assistant: ```c
char dns_parse_rr_label(char *bgof_msg, char **cursor, char *cursor_max, struct buffer *output) {
  char *label_ptr;
  unsigned short label_offset;
  unsigned char chunk_len;
  int label_len;
  chunk_len = (unsigned char)**cursor;
  if (chunk_len != 0) {
    if (((chunk_len >> 6) & 0x03) == 3) {
      label_offset = read_uint16(*cursor);
      label_offset &= 0x3fff;
      label_ptr = bgof_msg + label_offset;
      (*cursor) += 2;
      chunk_len = *label_ptr;
      while ((label_len = dns_parse_rr_label(bgof_msg, &label_ptr, cursor_max, output)) > 0) {
      }
      if (label_len == 0) {
        return 0;
      } else {
        log_debug(__func__, "Failed to read label pointer.");
        return -1;
      }
    } else {
      (*cursor)++;
      if (*cursor + chunk_len <= cursor_max) {
        buffer_insert(output, *cursor, chunk_len);
        buffer_insert(output, ".", 1);
        (*cursor) += chunk_len;
        return chunk_len;
      } else {
        log_debug(__func__, "End of label outside of buffer!");
        return -1;
      }
    }
  } else {
    (*cursor)++;
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<erase_calibration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D19: Erasing calibration values...


tool: D3: /etc/ADC-calibration.dat

assistant: ```c
void erase_calibration() {
  printf("Erasing calibration values...\n");
  unlink("/etc/ADC-calibration.dat");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<erase_calibration>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <unlink@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D5
type: string

tool: D13: Erasing calibration values...


tool: D5: /etc/ADC-calibration.dat

assistant: ```c
void erase_calibration() {
  printf("Erasing calibration values...\n");
  unlink("/etc/ADC-calibration.dat");
}
```
user: What is the c source code of the assembly code below:

```asm
<erase_calibration>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <unlink@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D0: Erasing calibration values...


tool: D7: /etc/ADC-calibration.dat

assistant: ```c
void erase_calibration() {
  printf("Erasing calibration values...\n");
  unlink("/etc/ADC-calibration.dat");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<erase_calibration>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <unlink@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D3
data_type: string

tool: D15: Erasing calibration values...


tool: D3: /etc/ADC-calibration.dat

assistant: ```c
void erase_calibration() {
  printf("Erasing calibration values...\n");
  unlink("/etc/ADC-calibration.dat");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<coro>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L5:
  mov    $0x0,%edi
  call   <coro_yield@plt>
  jmp    L5
```

assistant: ```c
void *coro(void *arg) {
  while (1)
    coro_yield(NULL);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<coro>:
  endbr64
  sub    $0x8,%rsp
L5:
  mov    $0x0,%edi
  call   <coro_yield@plt>
  jmp    L5
```

assistant: ```c
void *coro(void *arg) {
  while (1)
    coro_yield(NULL);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<coro>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %edi,%edi
  call   <coro_yield@plt>
  jmp    L6
```

assistant: ```c
void *coro(void *arg) {
  while (1)
    coro_yield(NULL);
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<coro>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %edi,%edi
  call   <coro_yield@plt>
  jmp    L9
```

assistant: ```c
void *coro(void *arg) {
  while (1)
    coro_yield(NULL);
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argtot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x73,%eax
  je     L42
  cmp    $0x73,%eax
  jg     L54
  cmp    $0x6d,%eax
  je     L21
  cmp    $0x6d,%eax
  jg     L54
  cmp    $0x4d,%eax
  je     L24
  cmp    $0x68,%eax
  jne    L54
  movq   $0x36ee80,-0x18(%rbp)
  jmp    L34
L21:
  movq   $0xea60,-0x18(%rbp)
  jmp    L34
L42:
  movq   $0x3e8,-0x18(%rbp)
  jmp    L34
L24:
  movq   $0x1,-0x18(%rbp)
  jmp    L34
L54:
  movq   $0x3e8,-0x18(%rbp)
L34:
  mov    -0x10(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L74
  call   <__stack_chk_fail@plt>
L74:
  leave
  ret
```

assistant: ```c
unsigned long long argtot(char *s) {
  char *p;
  unsigned long long n = strtol(s, &p, 10), f = 1;
  switch (*p) {
  case 'h':
    f = 3600000;
    break;
  case 'm':
    f = 60000;
    break;
  case 's':
    f = 1000;
    break;
  case 'M':
    f = 1;
    break;
  default:
    f = 1000;
  }
  return n * f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argtot>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%ecx
  cmp    $0x6d,%cl
  je     L13
  mov    $0x3e8,%edx
  jg     L3
  mov    $0x1,%edx
  cmp    $0x4d,%cl
  je     L3
  cmp    $0x68,%cl
  mov    $0x3e8,%edx
  mov    $0x36ee80,%ecx
  cmove  %rcx,%rdx
L3:
  imul   %rdx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L13:
  mov    $0xea60,%edx
  jmp    L3
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long argtot(char *s) {
  char *p;
  unsigned long long n = strtol(s, &p, 10), f = 1;
  switch (*p) {
  case 'h':
    f = 3600000;
    break;
  case 'm':
    f = 60000;
    break;
  case 's':
    f = 1000;
    break;
  case 'M':
    f = 1;
    break;
  default:
    f = 1000;
  }
  return n * f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argtot>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%edx
  cmp    $0x68,%dl
  je     L43
  cmp    $0x6d,%dl
  je     L25
  cmp    $0x4d,%dl
  je     L27
  imul   $0x3e8,%rax,%rax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  imul   $0x36ee80,%rax,%rax
  jmp    L27
  nopl   0x0(%rax)
L25:
  imul   $0xea60,%rax,%rax
  jmp    L27
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long argtot(char *s) {
  char *p;
  unsigned long long n = strtol(s, &p, 10), f = 1;
  switch (*p) {
  case 'h':
    f = 3600000;
    break;
  case 'm':
    f = 60000;
    break;
  case 's':
    f = 1000;
    break;
  case 'M':
    f = 1;
    break;
  default:
    f = 1000;
  }
  return n * f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<argtot>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%edx
  cmp    $0x68,%dl
  je     L15
  cmp    $0x6d,%dl
  je     L8
  cmp    $0x4d,%dl
  je     L52
  imul   $0x3e8,%rax,%rax
L52:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  imul   $0x36ee80,%rax,%rax
  jmp    L52
  nopl   0x0(%rax)
L8:
  imul   $0xea60,%rax,%rax
  jmp    L52
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long argtot(char *s) {
  char *p;
  unsigned long long n = strtol(s, &p, 10), f = 1;
  switch (*p) {
  case 'h':
    f = 3600000;
    break;
  case 'm':
    f = 60000;
    break;
  case 's':
    f = 1000;
    break;
  case 'M':
    f = 1;
    break;
  default:
    f = 1000;
  }
  return n * f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpu_isamd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <do_cpuid@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x68747541,%eax
  jne    L11
  mov    -0x18(%rbp),%eax
  cmp    $0x444d4163,%eax
  jne    L11
  mov    -0x14(%rbp),%eax
  cmp    $0x69746e65,%eax
  jne    L11
  mov    $0x1,%eax
  jmp    L18
L11:
  mov    $0x0,%eax
L18:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
bool cpu_isamd(void) {
  uint32_t regs[4];
  do_cpuid(0, regs);
  if ((regs[1] == 0x68747541) && (regs[2] == 0x444d4163) && (regs[3] == 0x69746e65))
    return true;
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cpu_isamd>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x0,%edi
  call   <do_cpuid@plt>
  mov    $0x0,%eax
  cmpl   $0x68747541,0x4(%rsp)
  je     L22
L25:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x28,%rsp
  ret
L22:
  cmpl   $0x444d4163,0x8(%rsp)
  jne    L25
  cmpl   $0x69746e65,0xc(%rsp)
  sete   %al
  movzbl %al,%eax
  jmp    L25
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool cpu_isamd(void) {
  uint32_t regs[4];
  do_cpuid(0, regs);
  if ((regs[1] == 0x68747541) && (regs[2] == 0x444d4163) && (regs[3] == 0x69746e65))
    return true;
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cpu_isamd>:
  endbr64
  sub    $0x28,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <do_cpuid@plt>
  xor    %eax,%eax
  cmpl   $0x68747541,0x4(%rsp)
  je     L23
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmpl   $0x444d4163,0x8(%rsp)
  jne    L13
  xor    %eax,%eax
  cmpl   $0x69746e65,0xc(%rsp)
  sete   %al
  jmp    L13
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool cpu_isamd(void) {
  uint32_t regs[4];
  do_cpuid(0, regs);
  if ((regs[1] == 0x68747541) && (regs[2] == 0x444d4163) && (regs[3] == 0x69746e65))
    return true;
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cpu_isamd>:
  endbr64
  sub    $0x28,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <do_cpuid@plt>
  xor    %eax,%eax
  cmpl   $0x68747541,0x4(%rsp)
  je     L14
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  cmpl   $0x444d4163,0x8(%rsp)
  jne    L28
  xor    %eax,%eax
  cmpl   $0x69746e65,0xc(%rsp)
  sete   %al
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool cpu_isamd(void) {
  uint32_t regs[4];
  do_cpuid(0, regs);
  if ((regs[1] == 0x68747541) && (regs[2] == 0x444d4163) && (regs[3] == 0x69746e65))
    return true;
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atoiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L16
  mov    -0x2c(%rbp),%eax
  jmp    L13
L16:
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L33
  mov    -0x2c(%rbp),%eax
  jmp    L13
L33:
  mov    -0x14(%rbp),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int atoiv(char const *arg, int def) {
  if (!arg)
    return def;
  char *endptr;
  int val = strtol(arg, &endptr, 10);
  if (arg == endptr)
    return def;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<atoiv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%eax
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  cmove  %ebp,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atoiv(char const *arg, int def) {
  if (!arg)
    return def;
  char *endptr;
  int val = strtol(arg, &endptr, 10);
  if (arg == endptr)
    return def;
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<atoiv>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L33
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rdi,%rbx
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  je     L33
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L33:
  mov    %ebp,%eax
  jmp    L14
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atoiv(char const *arg, int def) {
  if (!arg)
    return def;
  char *endptr;
  int val = strtol(arg, &endptr, 10);
  if (arg == endptr)
    return def;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<atoiv>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L15
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %rdi,%rbx
  call   <strtol@plt>
  cmp    %rbx,(%rsp)
  je     L15
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L15:
  mov    %ebp,%eax
  jmp    L31
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int atoiv(char const *arg, int def) {
  if (!arg)
    return def;
  char *endptr;
  int val = strtol(arg, &endptr, 10);
  if (arg == endptr)
    return def;
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tml_parse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tml_parse_memory@plt>
  leave
  ret
```

assistant: ```c
struct tml_doc *tml_parse_string(const char *str) {
  size_t len = strlen(str);
  return tml_parse_memory(str, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tml_parse_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <tml_parse_memory@plt>
  pop    %rbx
  ret
```

assistant: ```c
struct tml_doc *tml_parse_string(const char *str) {
  size_t len = strlen(str);
  return tml_parse_memory(str, len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tml_parse_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1070 <tml_parse_memory@plt>
```

assistant: ```c
struct tml_doc *tml_parse_string(const char *str) {
  size_t len = strlen(str);
  return tml_parse_memory(str, len);
}
```
user: What is the c source code of the assembly code below?

```asm
<tml_parse_string>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  jmp    1070 <tml_parse_memory@plt>
```

assistant: ```c
struct tml_doc *tml_parse_string(const char *str) {
  size_t len = strlen(str);
  return tml_parse_memory(str, len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<perl_explode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L16:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x2,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jb     L16
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *perl_explode(buf)
char *buf;
{
  char *return_buf;
  int cntr;
  return_buf = (char *)malloc(sizeof(char) * ((strlen(buf) * 2) + 1));
  for (cntr = 0; (cntr / 2) < strlen(buf); cntr += 2) {
    return_buf[cntr] = buf[cntr / 2];
    return_buf[cntr + 1] = ' ';
  }
  return_buf[cntr - 1] = '\0';
  return (return_buf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<perl_explode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  call   <strlen@plt>
  lea    0x1(%rax,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  jmp    L8
L14:
  movzbl 0x0(%r13,%rbx,1),%eax
  mov    %al,(%r12,%rbp,1)
  movb   $0x20,0x1(%r12,%rbp,1)
  add    $0x2,%rbp
L8:
  mov    %ebp,%ebx
  shr    $0x1f,%ebx
  add    %ebp,%ebx
  sar    %ebx
  movslq %ebx,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jb     L14
  movslq %ebp,%r14
  movb   $0x0,-0x1(%r12,%r14,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *perl_explode(buf)
char *buf;
{
  char *return_buf;
  int cntr;
  return_buf = (char *)malloc(sizeof(char) * ((strlen(buf) * 2) + 1));
  for (cntr = 0; (cntr / 2) < strlen(buf); cntr += 2) {
    return_buf[cntr] = buf[cntr / 2];
    return_buf[cntr + 1] = ' ';
  }
  return_buf[cntr - 1] = '\0';
  return (return_buf);
}
```