user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convolutionGoldFloat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    %r8d,%r14d
  mov    %esi,%edi
  imul   %edx,%edi
  shl    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,0x28(%rsp)
  test   %rax,%rax
  je     L47
L54:
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  mov    %eax,%edi
  sar    %edi
  mov    %edi,%esi
  mov    %edi,0x10(%rsp)
  test   %r12d,%r12d
  jle    L12
  lea    0x1(%rdi),%ecx
  mov    %ecx,0x34(%rsp)
  lea    (%rcx,%r12,1),%eax
  mov    %eax,0x38(%rsp)
  neg    %edi
  mov    %edi,0x14(%rsp)
  movslq %r14d,%r14
  lea    0x0(,%r14,4),%rax
  mov    %rax,0x8(%rsp)
  movslq %edi,%rax
  movslq %esi,%rdx
  add    %rdx,%rax
  lea    0x0(%r13,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  mov    %ecx,%r13d
  movl   $0x0,0x30(%rsp)
  mov    %ebx,%eax
  sub    %esi,%eax
  mov    %eax,0x20(%rsp)
  lea    -0x1(%rdi,%rdi,1),%eax
  mov    %eax,0x3c(%rsp)
  lea    -0x1(%r12),%r15d
  lea    -0x1(%rbx),%r8d
  jmp    L32
L47:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L54
L86:
  movslq 0x30(%rsp),%rax
  mov    0x28(%rsp),%rdi
  lea    (%rdi,%rax,4),%r14
  mov    0x10(%rsp),%r11d
  neg    %r11d
  mov    0x3c(%rsp),%eax
  add    %r13d,%eax
  mov    %eax,0x24(%rsp)
  mov    0x34(%rsp),%edi
L38:
  mov    0x14(%rsp),%esi
  pxor   %xmm1,%xmm1
  cmp    %esi,0x10(%rsp)
  jl     L29
  mov    0x18(%rsp),%r10
  mov    0x24(%rsp),%r9d
  pxor   %xmm1,%xmm1
L10:
  test   %r9d,%r9d
  mov    $0x0,%esi
  cmovns %r9d,%esi
  cmp    %esi,%r12d
  cmovle %r15d,%esi
  imul   %ebx,%esi
  mov    %r10,%rcx
  mov    %r11d,%edx
L15:
  test   %edx,%edx
  mov    $0x0,%eax
  cmovns %edx,%eax
  cmp    %eax,%ebx
  cmovle %r8d,%eax
  add    %esi,%eax
  cltq
  movss  0x0(%rbp,%rax,4),%xmm0
  mulss  (%rcx),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%edx
  add    $0x4,%rcx
  cmp    %edi,%edx
  jne    L15
  add    $0x1,%r9d
  add    0x8(%rsp),%r10
  cmp    %r13d,%r9d
  jne    L10
L29:
  movss  %xmm1,(%r14)
  add    $0x4,%r14
  add    $0x1,%edi
  add    $0x1,%r11d
  cmp    0x20(%rsp),%r11d
  jne    L38
L33:
  add    %ebx,0x30(%rsp)
  add    $0x1,%r13d
  cmp    0x38(%rsp),%r13d
  je     L12
L32:
  test   %ebx,%ebx
  jg     L86
  jmp    L33
L12:
  mov    0x28(%rsp),%rax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
float *convolutionGoldFloat(float *image, int rows, int cols, float *filter, int filterWidth) {
  float *outputImage;
  outputImage = (float *)malloc(rows * cols * sizeof(float));
  if (!outputImage) {
    exit(-1);
  }
  int halfFilterWidth = (int)filterWidth / 2;
  int i;
  int j;
  int k;
  int l;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      float sum = 0;
      for (k = -halfFilterWidth; k <= halfFilterWidth; k++) {
        for (l = -halfFilterWidth; l <= halfFilterWidth; l++) {
          int r = i + k;
          int c = j + l;
          r = (r < 0) ? 0 : r;
          c = (c < 0) ? 0 : c;
          r = (r >= rows) ? rows - 1 : r;
          c = (c >= cols) ? cols - 1 : c;
          sum += image[r * cols + c] * filter[(k + halfFilterWidth) * filterWidth + (l + halfFilterWidth)];
        }
      }
      outputImage[i * cols + j] = sum;
    }
  }
  return outputImage;
}
```