ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clock_tic__>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
const unsigned long long clock_tic__() {
  unsigned int a, d;
  asm volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clock_tic__>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
const unsigned long long clock_tic__() {
  unsigned int a, d;
  asm volatile("rdtsc" : "=a"(a), "=d"(d));
  return ((unsigned long long)a) | (((unsigned long long)d) << 32);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chaz_ConfWriterPerl_add_typedef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chaz_ConfWriterPerl_add_typedef(const char *type, const char *alias) {
  (void)type;
  (void)alias;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<chaz_ConfWriterPerl_add_typedef>:
  endbr64
  ret
```

assistant: ```c
void chaz_ConfWriterPerl_add_typedef(const char *type, const char *alias) {
  (void)type;
  (void)alias;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chaz_ConfWriterPerl_add_typedef>:
  endbr64
  ret
```

assistant: ```c
void chaz_ConfWriterPerl_add_typedef(const char *type, const char *alias) {
  (void)type;
  (void)alias;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chaz_ConfWriterPerl_add_typedef>:
  endbr64
  ret
```

assistant: ```c
void chaz_ConfWriterPerl_add_typedef(const char *type, const char *alias) {
  (void)type;
  (void)alias;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addrow_imatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %r9,%r13
  sub    %rcx,%r8
  lea    0x1(%r8),%r12
  lea    0x0(,%rsi,8),%r15
  sub    %rsi,%rdx
  lea    0x1(%r9,%rdx,1),%rsi
  shl    $0x3,%rsi
  add    %r15,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
L13:
  sub    %r15,%rbx
  mov    %r12,%rdi
  imul   %r13,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  lea    0x8(%rbx,%rbp,8),%r15
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L21
L36:
  shl    $0x2,%r14
  sub    %r14,(%r15)
  lea    0x2(%rbp),%rax
  lea    0x0(%rbp,%r13,1),%rcx
  cmp    $0x1,%r13
  jle    L54
  lea    0x0(,%r12,4),%rsi
L37:
  mov    %rsi,%rdx
  add    -0x8(%rbx,%rax,8),%rdx
  mov    %rdx,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jle    L37
L54:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  lea    D15(%rip),%rdi
  call   <nrerror@plt>
  jmp    L13
L21:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L36
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D2
data_type: string

tool: D15: allocation failure 1 in realloc imatrix()

tool: D2: allocation failure 2 in realloc imatrix()

assistant: ```c
int **addrow_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long nr) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  m += nrl;
  m -= 0;
  m = (int **)realloc(m, (size_t)((nrow + nr + 0) * sizeof(int *)));
  if (!m)
    nrerror("allocation failure 1 in realloc imatrix()");
  m += 0;
  m -= nrl;
  m[nrh + 1] = (int *)malloc((size_t)((nr * ncol + 0) * sizeof(int)));
  if (!m[nrh + 1])
    nrerror("allocation failure 2 in realloc imatrix()");
  m[nrh + 1] += 0;
  m[nrh + 1] -= ncl;
  for (i = nrh + 2; i <= nrh + nr; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<addrow_imatrix>:
  endbr64
  push   %r15
  lea    0x0(,%rsi,8),%r15
  sub    %rcx,%r8
  push   %r14
  add    %r15,%rdi
  mov    %rcx,%r14
  push   %r13
  lea    0x1(%r8),%r13
  push   %r12
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    %rsi,%rdx
  lea    0x1(%r9,%rdx,1),%rsi
  shl    $0x3,%rsi
  sub    $0x8,%rsp
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L13:
  mov    %r13,%rdi
  sub    %r15,%r12
  imul   %rbp,%rdi
  lea    0x8(%r12,%rbx,8),%r15
  shl    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L49
L28:
  shl    $0x2,%r14
  lea    0x2(%rbx),%rdx
  lea    (%rbx,%rbp,1),%rcx
  sub    %r14,%rax
  lea    0x0(,%r13,4),%rsi
  mov    %rax,(%r15)
  cmp    $0x1,%rbp
  jle    L36
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    -0x8(%r12,%rdx,8),%rax
  add    %rsi,%rax
  mov    %rax,(%r12,%rdx,8)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jle    L15
L36:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D19(%rip),%rdi
  call   <nrerror@plt>
  jmp    L13
  nopl   0x0(%rax)
L49:
  lea    D18(%rip),%rdi
  call   <nrerror@plt>
  mov    (%r15),%rax
  jmp    L28
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D18
data_type: string

tool: D19: allocation failure 1 in realloc imatrix()

tool: D18: allocation failure 2 in realloc imatrix()

assistant: ```c
int **addrow_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long nr) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  m += nrl;
  m -= 0;
  m = (int **)realloc(m, (size_t)((nrow + nr + 0) * sizeof(int *)));
  if (!m)
    nrerror("allocation failure 1 in realloc imatrix()");
  m += 0;
  m -= nrl;
  m[nrh + 1] = (int *)malloc((size_t)((nr * ncol + 0) * sizeof(int)));
  if (!m[nrh + 1])
    nrerror("allocation failure 2 in realloc imatrix()");
  m[nrh + 1] += 0;
  m[nrh + 1] -= ncl;
  for (i = nrh + 2; i <= nrh + nr; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: What is the c source code of the assembly code below:

```asm
<addrow_imatrix>:
  endbr64
  push   %r15
  sub    %rcx,%r8
  mov    %rcx,%r15
  push   %r14
  lea    0x1(%r8),%rcx
  push   %r13
  mov    %r9,%r13
  push   %r12
  lea    0x0(,%rsi,8),%r12
  push   %rbp
  add    %r12,%rdi
  push   %rbx
  mov    %rdx,%rbx
  sub    %rsi,%rdx
  lea    0x1(%r9,%rdx,1),%rsi
  shl    $0x3,%rsi
  sub    $0x28,%rsp
  mov    %rcx,0x8(%rsp)
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L44
L8:
  mov    0x8(%rsp),%rdi
  mov    %rbp,%r14
  sub    %r12,%r14
  imul   %r13,%rdi
  shl    $0x2,%rdi
  call   <malloc@plt>
  lea    0x8(,%rbx,8),%r8
  lea    (%r14,%r8,1),%rcx
  mov    %rax,(%rcx)
  test   %rax,%rax
  je     L31
L20:
  shl    $0x2,%r15
  sub    %r15,%rax
  mov    %rax,(%rcx)
  lea    0x2(%rbx),%rax
  lea    (%rbx,%r13,1),%rcx
  cmp    $0x1,%r13
  jle    L55
  mov    %rbp,%rdx
  mov    0x8(%rsp),%rsi
  sub    %r12,%rdx
  mov    (%rdx,%r8,1),%rdx
  shl    $0x2,%rsi
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    %rsi,%rdx
  mov    %rdx,(%r14,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jle    L6
L55:
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L8
  nopl   0x0(%rax)
L31:
  lea    D3(%rip),%rdi
  mov    %rcx,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  call   <nrerror@plt>
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%r8
  mov    (%rcx),%rax
  jmp    L20
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D3
type: string

tool: D2: allocation failure 1 in realloc imatrix()

tool: D3: allocation failure 2 in realloc imatrix()

assistant: ```c
int **addrow_imatrix(int **m, long nrl, long nrh, long ncl, long nch, long nr) {
  long i, nrow = nrh - nrl + 1, ncol = nch - ncl + 1;
  m += nrl;
  m -= 0;
  m = (int **)realloc(m, (size_t)((nrow + nr + 0) * sizeof(int *)));
  if (!m)
    nrerror("allocation failure 1 in realloc imatrix()");
  m += 0;
  m -= nrl;
  m[nrh + 1] = (int *)malloc((size_t)((nr * ncol + 0) * sizeof(int)));
  if (!m[nrh + 1])
    nrerror("allocation failure 2 in realloc imatrix()");
  m[nrh + 1] += 0;
  m[nrh + 1] -= ncl;
  for (i = nrh + 2; i <= nrh + nr; i++)
    m[i] = m[i - 1] + ncol;
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L4
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *reverse(char str[], int len) {
  int i = 0, j = len - 1;
  char temp;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    ++i;
    --j;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reverse>:
  endbr64
  mov    %rdi,%rax
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  mov    $0x0,%edx
L2:
  movzbl (%rax,%rdx,1),%ecx
  movzbl (%rax,%rsi,1),%edi
  mov    %dil,(%rax,%rdx,1)
  mov    %cl,(%rax,%rsi,1)
  add    $0x1,%rdx
  sub    $0x1,%rsi
  cmp    %esi,%edx
  jl     L2
L0:
  ret
```

assistant: ```c
char *reverse(char str[], int len) {
  int i = 0, j = len - 1;
  char temp;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    ++i;
    --j;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L15
  movslq %esi,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rax,%rdx,1),%ecx
  movzbl (%rax,%rsi,1),%edi
  mov    %dil,(%rax,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rax,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%edx
  jl     L3
L15:
  ret
```

assistant: ```c
char *reverse(char str[], int len) {
  int i = 0, j = len - 1;
  char temp;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    ++i;
    --j;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  mov    %rdi,%rax
  test   %esi,%esi
  jle    L6
  movslq %esi,%rsi
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rax,%rdx,1),%ecx
  movzbl (%rax,%rsi,1),%edi
  mov    %dil,(%rax,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rax,%rsi,1)
  sub    $0x1,%rsi
  cmp    %edx,%esi
  jg     L2
L6:
  ret
```

assistant: ```c
char *reverse(char str[], int len) {
  int i = 0, j = len - 1;
  char temp;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    ++i;
    --j;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D11(%rip),%xmm0
  movsd  %xmm0,-0x160(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x158(%rbp)
  movsd  -0x160(%rbp),%xmm0
  movsd  %xmm0,-0x150(%rbp)
  movsd  -0x158(%rbp),%xmm0
  movsd  %xmm0,-0x160(%rbp)
  movsd  -0x150(%rbp),%xmm0
  movsd  %xmm0,-0x158(%rbp)
  lea    -0x160(%rbp),%rax
  mov    %rax,-0x148(%rbp)
  lea    -0x158(%rbp),%rax
  mov    %rax,-0x140(%rbp)
  mov    -0x148(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x138(%rbp)
  mov    -0x140(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x148(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x140(%rbp),%rax
  movsd  -0x138(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  lea    -0x158(%rbp),%rdx
  lea    -0x160(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <changeDoubles@plt>
  lea    -0x130(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <fill@plt>
  lea    -0xa0(%rbp),%rax
  mov    $0xf,%esi
  mov    %rax,%rdi
  call   <fill@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <fill@plt>
  lea    -0x130(%rbp),%rax
  lea    0x24(%rax),%rdx
  lea    -0x130(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0xa0(%rbp),%rax
  lea    0x38(%rax),%rdx
  lea    -0xa0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printArray@plt>
  lea    -0x60(%rbp),%rax
  lea    0x4c(%rax),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <printArray@plt>
  movl   $0x0,-0x168(%rbp)
  jmp    L6
L9:
  mov    -0x168(%rbp),%eax
  cltq
  movl   $0x1,-0x100(%rbp,%rax,4)
  addl   $0x1,-0x168(%rbp)
L6:
  cmpl   $0x9,-0x168(%rbp)
  jle    L9
  movl   $0x0,-0x164(%rbp)
  jmp    L16
L39:
  mov    -0x164(%rbp),%eax
  cltq
  movl   $0x2,-0xd0(%rbp,%rax,4)
  addl   $0x1,-0x164(%rbp)
L16:
  cmpl   $0x9,-0x164(%rbp)
  jle    L39
  lea    -0xd0(%rbp),%rcx
  lea    -0x100(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <changeArays@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: f64
name: unpack_data
arguments: tag: D2
data_type: f64

tool: D11: 10

tool: D2: 20

assistant: ```c
int main() {
  double d1 = 10, d2 = 20;
  double tmp1 = d1;
  d1 = d2;
  d2 = tmp1;
  double *pd1 = &d1, *pd2 = &d2;
  double tmp2 = *pd1;
  *pd1 = *pd2;
  *pd2 = tmp2;
  changeDoubles(&d1, &d2);
  int pole10[10], pole15[15], pole20[20];
  fill(pole10, 10);
  fill(pole15, 15);
  fill(pole20, 20);
  printArray(pole10, &pole10[9]);
  printArray(pole15, &pole15[14]);
  printArray(pole20, &pole20[19]);
  int poleA[10];
  int poleB[10];
  for (int i = 0; i < 10; i++)
    poleA[i] = 1;
  for (int i = 0; i < 10; i++)
    poleB[i] = 2;
  changeArays(poleA, poleB, 10);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    %rax,(%rsp)
  mov    D11(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  call   <changeDoubles@plt>
  lea    0x10(%rsp),%r12
  mov    $0xa,%esi
  mov    %r12,%rdi
  call   <fill@plt>
  lea    0xa0(%rsp),%rbp
  mov    $0xf,%esi
  mov    %rbp,%rdi
  call   <fill@plt>
  lea    0xe0(%rsp),%rbx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <fill@plt>
  lea    0x34(%rsp),%rsi
  mov    %r12,%rdi
  call   <printArray@plt>
  lea    0xd8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printArray@plt>
  lea    0x12c(%rsp),%rsi
  mov    %rbx,%rdi
  call   <printArray@plt>
  lea    0x40(%rsp),%rax
  lea    0x68(%rsp),%rdx
L19:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L19
  lea    0x70(%rsp),%rax
  lea    0x98(%rsp),%rdx
L10:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L10
  lea    0x70(%rsp),%rsi
  lea    0x40(%rsp),%rdi
  mov    $0xa,%edx
  call   <changeArays@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x140,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
data_type: f64
name: read_data
arguments: label: D11
data_type: f64

tool: D7: 10

tool: D11: 20

assistant: ```c
int main() {
  double d1 = 10, d2 = 20;
  double tmp1 = d1;
  d1 = d2;
  d2 = tmp1;
  double *pd1 = &d1, *pd2 = &d2;
  double tmp2 = *pd1;
  *pd1 = *pd2;
  *pd2 = tmp2;
  changeDoubles(&d1, &d2);
  int pole10[10], pole15[15], pole20[20];
  fill(pole10, 10);
  fill(pole15, 15);
  fill(pole20, 20);
  printArray(pole10, &pole10[9]);
  printArray(pole15, &pole15[14]);
  printArray(pole20, &pole20[19]);
  int poleA[10];
  int poleB[10];
  for (int i = 0; i < 10; i++)
    poleA[i] = 1;
  for (int i = 0; i < 10; i++)
    poleB[i] = 2;
  changeArays(poleA, poleB, 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x10(%rsp),%r13
  mov    D18(%rip),%rax
  lea    0xa0(%rsp),%r12
  lea    0xe0(%rsp),%rbp
  mov    %rax,(%rsp)
  mov    D4(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <changeDoubles@plt>
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <fill@plt>
  mov    $0xf,%esi
  mov    %r12,%rdi
  call   <fill@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <fill@plt>
  lea    0x34(%rsp),%rsi
  mov    %r13,%rdi
  call   <printArray@plt>
  lea    0xd8(%rsp),%rsi
  mov    %r12,%rdi
  call   <printArray@plt>
  mov    %rbp,%rdi
  lea    0x12c(%rsp),%rsi
  call   <printArray@plt>
  lea    0x40(%rsp),%rdi
  lea    0x68(%rsp),%rdx
  mov    %rdi,%rax
  nopl   (%rax)
L5:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
  lea    0x70(%rsp),%rsi
  lea    0x98(%rsp),%rdx
  mov    %rsi,%rax
  nop
L28:
  movl   $0x2,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L28
  mov    $0xa,%edx
  call   <changeArays@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x140,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
data_type: f64
name: parse_data
arguments: label: D4
data_type: f64

tool: D18: 10

tool: D4: 20

assistant: ```c
int main() {
  double d1 = 10, d2 = 20;
  double tmp1 = d1;
  d1 = d2;
  d2 = tmp1;
  double *pd1 = &d1, *pd2 = &d2;
  double tmp2 = *pd1;
  *pd1 = *pd2;
  *pd2 = tmp2;
  changeDoubles(&d1, &d2);
  int pole10[10], pole15[15], pole20[20];
  fill(pole10, 10);
  fill(pole15, 15);
  fill(pole20, 20);
  printArray(pole10, &pole10[9]);
  printArray(pole15, &pole15[14]);
  printArray(pole20, &pole20[19]);
  int poleA[10];
  int poleB[10];
  for (int i = 0; i < 10; i++)
    poleA[i] = 1;
  for (int i = 0; i < 10; i++)
    poleB[i] = 2;
  changeArays(poleA, poleB, 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x140,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  lea    0x10(%rsp),%r13
  mov    D53(%rip),%rax
  lea    0xa0(%rsp),%r12
  lea    0xe0(%rsp),%rbp
  mov    %rax,(%rsp)
  mov    D21(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <changeDoubles@plt>
  mov    $0xa,%esi
  mov    %r13,%rdi
  call   <fill@plt>
  mov    $0xf,%esi
  mov    %r12,%rdi
  call   <fill@plt>
  mov    $0x14,%esi
  mov    %rbp,%rdi
  call   <fill@plt>
  lea    0x34(%rsp),%rsi
  mov    %r13,%rdi
  call   <printArray@plt>
  lea    0xd8(%rsp),%rsi
  mov    %r12,%rdi
  call   <printArray@plt>
  lea    0x12c(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printArray@plt>
  lea    0x70(%rsp),%rsi
  lea    0x40(%rsp),%rdi
  movdqa D44(%rip),%xmm0
  mov    D44(%rip),%rax
  mov    $0xa,%edx
  movaps %xmm0,0x40(%rsp)
  mov    %rax,0x60(%rsp)
  mov    D10(%rip),%rax
  movaps %xmm0,0x50(%rsp)
  movdqa D10(%rip),%xmm0
  mov    %rax,0x90(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  call   <changeArays@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x140,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D53
type: f64
name: disassemble_data
arguments: data_label: D21
type: f64
name: disassemble_data
arguments: data_label: D44
type: byte[16]
name: disassemble_data
arguments: data_label: D10
type: byte[16]

tool: D53: 10

tool: D21: 20

tool: {"D44": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D10": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main() {
  double d1 = 10, d2 = 20;
  double tmp1 = d1;
  d1 = d2;
  d2 = tmp1;
  double *pd1 = &d1, *pd2 = &d2;
  double tmp2 = *pd1;
  *pd1 = *pd2;
  *pd2 = tmp2;
  changeDoubles(&d1, &d2);
  int pole10[10], pole15[15], pole20[20];
  fill(pole10, 10);
  fill(pole15, 15);
  fill(pole20, 20);
  printArray(pole10, &pole10[9]);
  printArray(pole15, &pole15[14]);
  printArray(pole20, &pole20[19]);
  int poleA[10];
  int poleB[10];
  for (int i = 0; i < 10; i++)
    poleA[i] = 1;
  for (int i = 0; i < 10; i++)
    poleB[i] = 2;
  changeArays(poleA, poleB, 10);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cr_receivedata>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edi
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <select@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L8
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <recv@plt>
  jmp    L15
L8:
  cmpl   $0x0,-0x14(%rbp)
  jne    L48
  mov    $0xfffffffe,%eax
  jmp    L15
L48:
  mov    $0xffffffff,%eax
L15:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int cr_receivedata(int fd, unsigned int msecs, char *buf, int size) {
  fd_set fds;
  struct timeval tv;
  int rc;
  tv.tv_sec = msecs / 1000;
  tv.tv_usec = (msecs % 1000) * 1000;
  FD_ZERO(&fds);
  FD_SET(fd, &fds);
  rc = select(fd + 1, &fds, NULL, NULL, &tv);
  if (rc > 0)
    return recv(fd, buf, size, 0);
  else if (rc == 0)
    return -2;
  else
    return -1;
}
```