ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bootloader_tlv_find>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %r8d,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L4
L91:
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <bootloader_tlv_parse@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L73
  mov    -0x38(%rbp),%rax
  cmp    %rax,-0x58(%rbp)
  jne    L3
  mov    -0x30(%rbp),%rdx
  mov    -0x60(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  jmp    L62
L3:
  mov    -0x38(%rbp),%rax
  and    $0x20,%eax
  test   %rax,%rax
  je     L6
  cmpl   $0x0,-0x64(%rbp)
  jle    L6
  mov    -0x64(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    -0x60(%rbp),%rcx
  mov    -0x58(%rbp),%rdx
  mov    %esi,%r8d
  mov    %rax,%rsi
  call   <bootloader_tlv_find>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  jmp    L62
L73:
  mov    $0x0,%eax
  jmp    L62
L6:
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  sub    %rax,-0x20(%rbp)
L4:
  cmpq   $0x0,-0x20(%rbp)
  jg     L91
  mov    $0x0,%eax
L62:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
__attribute__((section(".boot.text"))) uint8_t *bootloader_tlv_find(uint8_t *buf, uint32_t buflen, uint32_t searchtag, uint32_t *foundlen, int recurse) {
  uint32_t off;
  uint32_t tmptag, tmplen;
  uint8_t *content;
  uint8_t *ptr = buf;
  uint32_t len = buflen;
  while (len > 0) {
    off = bootloader_tlv_parse(ptr, len, &tmptag, &tmplen);
    if (off) {
      if (tmptag == searchtag) {
        *foundlen = tmplen;
        return ptr + off;
      } else {
        if (((tmptag & 0x20) == 0x20) && (recurse > 0)) {
          content = bootloader_tlv_find(ptr + off, tmplen, searchtag, foundlen, recurse - 1);
          if (content) {
            return content;
          }
        }
      }
    } else {
      return ((void *)0);
    }
    ptr += off + tmplen;
    len -= off + tmplen;
  }
  return ((void *)0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bootloader_tlv_find>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jle    L51
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %r8d,%r14d
  lea    0x20(%rsp),%r15
  jmp    L84
L46:
  mov    0x20(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    %rax,(%rcx)
  lea    (%r12,%rbx,1),%rax
  jmp    L112
L11:
  add    0x20(%rsp),%rbx
  add    %rbx,%r12
  sub    %rbx,%rbp
  test   %rbp,%rbp
  jle    L118
L84:
  lea    0x18(%rsp),%rdx
  mov    %r15,%rcx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <bootloader_tlv_parse@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
  mov    0x18(%rsp),%rax
  cmp    %r13,%rax
  je     L46
  test   $0x20,%al
  je     L11
  test   %r14d,%r14d
  jle    L11
  lea    (%r12,%rbx,1),%rdi
  lea    -0x1(%r14),%r8d
  mov    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    0x20(%rsp),%rsi
  call   <bootloader_tlv_find>
  test   %rax,%rax
  je     L11
  jmp    L112
L118:
  mov    $0x0,%eax
  jmp    L112
L51:
  mov    $0x0,%eax
  jmp    L112
L13:
  mov    $0x0,%eax
L112:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((section(".boot.text"))) uint8_t *bootloader_tlv_find(uint8_t *buf, uint32_t buflen, uint32_t searchtag, uint32_t *foundlen, int recurse) {
  uint32_t off;
  uint32_t tmptag, tmplen;
  uint8_t *content;
  uint8_t *ptr = buf;
  uint32_t len = buflen;
  while (len > 0) {
    off = bootloader_tlv_parse(ptr, len, &tmptag, &tmplen);
    if (off) {
      if (tmptag == searchtag) {
        *foundlen = tmplen;
        return ptr + off;
      } else {
        if (((tmptag & 0x20) == 0x20) && (recurse > 0)) {
          content = bootloader_tlv_find(ptr + off, tmplen, searchtag, foundlen, recurse - 1);
          if (content) {
            return content;
          }
        }
      }
    } else {
      return ((void *)0);
    }
    ptr += off + tmplen;
    len -= off + tmplen;
  }
  return ((void *)0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bootloader_tlv_find>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    -0x1(%r8),%eax
  mov    %eax,0x14(%rsp)
  test   %rsi,%rsi
  jle    L50
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %r8d,%ebp
  lea    0x30(%rsp),%r13
  lea    0x28(%rsp),%r12
  jmp    L60
L42:
  lea    (%r9,%rsi,1),%rax
  sub    %rax,%r14
  add    %rax,%r15
  test   %r14,%r14
  jle    L50
L60:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <bootloader_tlv_parse@plt>
  mov    %rax,%r9
  test   %rax,%rax
  je     L50
  mov    0x28(%rsp),%rax
  mov    0x30(%rsp),%rsi
  cmp    %rbx,%rax
  je     L96
  test   $0x20,%al
  je     L42
  test   %ebp,%ebp
  jle    L42
  mov    0x14(%rsp),%r8d
  mov    0x8(%rsp),%rcx
  lea    (%r15,%r9,1),%rdi
  mov    %rbx,%rdx
  mov    %r9,0x18(%rsp)
  call   <bootloader_tlv_find>
  test   %rax,%rax
  jne    L4
  mov    0x30(%rsp),%rsi
  mov    0x18(%rsp),%r9
  lea    (%r9,%rsi,1),%rax
  sub    %rax,%r14
  add    %rax,%r15
  test   %r14,%r14
  jg     L60
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %eax,%eax
L4:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L96:
  mov    0x8(%rsp),%rax
  mov    %rsi,(%rax)
  lea    (%r15,%r9,1),%rax
  jmp    L4
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((section(".boot.text"))) uint8_t *bootloader_tlv_find(uint8_t *buf, uint32_t buflen, uint32_t searchtag, uint32_t *foundlen, int recurse) {
  uint32_t off;
  uint32_t tmptag, tmplen;
  uint8_t *content;
  uint8_t *ptr = buf;
  uint32_t len = buflen;
  while (len > 0) {
    off = bootloader_tlv_parse(ptr, len, &tmptag, &tmplen);
    if (off) {
      if (tmptag == searchtag) {
        *foundlen = tmplen;
        return ptr + off;
      } else {
        if (((tmptag & 0x20) == 0x20) && (recurse > 0)) {
          content = bootloader_tlv_find(ptr + off, tmplen, searchtag, foundlen, recurse - 1);
          if (content) {
            return content;
          }
        }
      }
    } else {
      return ((void *)0);
    }
    ptr += off + tmplen;
    len -= off + tmplen;
  }
  return ((void *)0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bootloader_tlv_find>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    -0x1(%r8),%eax
  mov    %eax,0x14(%rsp)
  test   %rsi,%rsi
  jle    L90
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %r8d,%ebp
  lea    0x30(%rsp),%r13
  lea    0x28(%rsp),%r12
  jmp    L40
L49:
  lea    (%r9,%rsi,1),%rax
  sub    %rax,%r14
  add    %rax,%r15
  test   %r14,%r14
  jle    L90
L40:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <bootloader_tlv_parse@plt>
  mov    %rax,%r9
  test   %rax,%rax
  je     L90
  mov    0x28(%rsp),%rax
  mov    0x30(%rsp),%rsi
  cmp    %rbx,%rax
  je     L99
  test   $0x20,%al
  je     L49
  test   %ebp,%ebp
  jle    L49
  mov    0x14(%rsp),%r8d
  mov    0x8(%rsp),%rcx
  lea    (%r15,%r9,1),%rdi
  mov    %rbx,%rdx
  mov    %r9,0x18(%rsp)
  call   <bootloader_tlv_find>
  test   %rax,%rax
  jne    L18
  mov    0x30(%rsp),%rsi
  mov    0x18(%rsp),%r9
  lea    (%r9,%rsi,1),%rax
  sub    %rax,%r14
  add    %rax,%r15
  test   %r14,%r14
  jg     L40
  nopl   0x0(%rax,%rax,1)
L90:
  xor    %eax,%eax
L18:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L99:
  mov    0x8(%rsp),%rax
  mov    %rsi,(%rax)
  lea    (%r15,%r9,1),%rax
  jmp    L18
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((section(".boot.text"))) uint8_t *bootloader_tlv_find(uint8_t *buf, uint32_t buflen, uint32_t searchtag, uint32_t *foundlen, int recurse) {
  uint32_t off;
  uint32_t tmptag, tmplen;
  uint8_t *content;
  uint8_t *ptr = buf;
  uint32_t len = buflen;
  while (len > 0) {
    off = bootloader_tlv_parse(ptr, len, &tmptag, &tmplen);
    if (off) {
      if (tmptag == searchtag) {
        *foundlen = tmplen;
        return ptr + off;
      } else {
        if (((tmptag & 0x20) == 0x20) && (recurse > 0)) {
          content = bootloader_tlv_find(ptr + off, tmplen, searchtag, foundlen, recurse - 1);
          if (content) {
            return content;
          }
        }
      }
    } else {
      return ((void *)0);
    }
    ptr += off + tmplen;
    len -= off + tmplen;
  }
  return ((void *)0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  cmpl   $0x40,-0x1c(%rbp)
  jg     L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L19
L0:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__bitmap_and@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitmap_and>:
  endbr64
  cmp    $0x40,%ecx
  jg     L9
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
L9:
  sub    $0x8,%rsp
  call   <__bitmap_and@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: What is the c source code of the assembly code below:

```asm
<bitmap_and>:
  endbr64
  cmp    $0x40,%ecx
  jg     L7
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  jmp    1050 <__bitmap_and@plt>
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmap_and>:
  endbr64
  cmp    $0x40,%ecx
  jg     L9
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  jmp    1050 <__bitmap_and@plt>
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= ((int)sizeof(unsigned long) * 8))
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L4
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memswap(void *m1, void *m2, size_t n) {
  char *p = m1;
  char *p_end = p + n;
  char *q = m2;
  while (p < p_end) {
    char tmp = *p;
    *p = *q;
    *q = tmp;
    p++;
    q++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<memswap>:
  endbr64
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jae    L8
L17:
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  mov    %cl,(%rdi)
  mov    %al,(%rsi)
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    %rdi,%rdx
  jne    L17
L8:
  ret
```

assistant: ```c
void memswap(void *m1, void *m2, size_t n) {
  char *p = m1;
  char *p_end = p + n;
  char *q = m2;
  while (p < p_end) {
    char tmp = *p;
    *p = *q;
    *q = tmp;
    p++;
    q++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memswap>:
  endbr64
  add    %rdi,%rdx
  cmp    %rdx,%rdi
  jae    L15
  nopl   0x0(%rax)
L19:
  movzbl (%rsi),%ecx
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %cl,-0x1(%rdi)
  mov    %al,-0x1(%rsi)
  cmp    %rdi,%rdx
  jne    L19
L15:
  ret
```

assistant: ```c
void memswap(void *m1, void *m2, size_t n) {
  char *p = m1;
  char *p_end = p + n;
  char *q = m2;
  while (p < p_end) {
    char tmp = *p;
    *p = *q;
    *q = tmp;
    p++;
    q++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memswap>:
  endbr64
  lea    (%rdi,%rdx,1),%r8
  mov    %rdi,%rcx
  cmp    %r8,%rdi
  jae    L81
  lea    0xf(%rcx),%rax
  lea    -0x1(%rdx),%rdi
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L107
  cmp    $0x6,%rdi
  jbe    L107
  cmp    $0xe,%rdi
  jbe    L158
  mov    %rdx,%rdi
  xor    %eax,%eax
  and    $0xfffffffffffffff0,%rdi
  cs nopw 0x0(%rax,%rax,1)
L57:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L57
  mov    %rdx,%r9
  and    $0xfffffffffffffff0,%r9
  add    %r9,%rcx
  add    %r9,%rsi
  mov    %rcx,%rax
  mov    %rsi,%rdi
  cmp    %r9,%rdx
  je     L81
  sub    %r9,%rdx
  lea    -0x1(%rdx),%r9
  cmp    $0x6,%r9
  jbe    L113
L122:
  mov    (%rsi),%r10
  mov    (%rcx),%r9
  mov    %r10,(%rcx)
  mov    %rdx,%rcx
  and    $0xfffffffffffffff8,%rcx
  mov    %r9,(%rsi)
  add    %rcx,%rax
  add    %rcx,%rdi
  cmp    %rcx,%rdx
  je     L81
L113:
  movzbl (%rax),%edx
  movzbl (%rdi),%ecx
  mov    %cl,(%rax)
  mov    %dl,(%rdi)
  lea    0x1(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x1(%rax),%edx
  movzbl 0x1(%rdi),%ecx
  mov    %cl,0x1(%rax)
  mov    %dl,0x1(%rdi)
  lea    0x2(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x2(%rax),%edx
  movzbl 0x2(%rdi),%ecx
  mov    %cl,0x2(%rax)
  mov    %dl,0x2(%rdi)
  lea    0x3(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x3(%rax),%edx
  movzbl 0x3(%rdi),%ecx
  mov    %cl,0x3(%rax)
  mov    %dl,0x3(%rdi)
  lea    0x4(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x4(%rax),%edx
  movzbl 0x4(%rdi),%ecx
  mov    %cl,0x4(%rax)
  mov    %dl,0x4(%rdi)
  lea    0x5(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x5(%rax),%edx
  movzbl 0x5(%rdi),%ecx
  mov    %cl,0x5(%rax)
  mov    %dl,0x5(%rdi)
  lea    0x6(%rax),%rdx
  cmp    %rdx,%r8
  jbe    L81
  movzbl 0x6(%rax),%edx
  movzbl 0x6(%rdi),%ecx
  mov    %cl,0x6(%rax)
  mov    %dl,0x6(%rdi)
  ret
  nopl   0x0(%rax,%rax,1)
L107:
  movzbl (%rsi),%edx
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  add    $0x1,%rsi
  mov    %dl,-0x1(%rcx)
  mov    %al,-0x1(%rsi)
  cmp    %rcx,%r8
  jne    L107
L81:
  ret
L158:
  mov    %rsi,%rdi
  mov    %rcx,%rax
  jmp    L122
```

assistant: ```c
void memswap(void *m1, void *m2, size_t n) {
  char *p = m1;
  char *p_end = p + n;
  char *q = m2;
  while (p < p_end) {
    char tmp = *p;
    *p = *q;
    *q = tmp;
    p++;
    q++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<EvenSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L15
L1:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  movss  D2(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x2,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L1
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float EvenSum(int n) {
  float sum = 0;
  int i = 0;
  for (i = 2; i <= n; i += 2) {
    sum = sum + (float)1 / (float)i;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<EvenSum>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  mov    $0x2,%eax
  pxor   %xmm0,%xmm0
  movss  D6(%rip),%xmm3
L10:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  add    $0x2,%eax
  cmp    %eax,%edi
  jge    L10
  ret
L7:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D6
datatype: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float EvenSum(int n) {
  float sum = 0;
  int i = 0;
  for (i = 2; i <= n; i += 2) {
    sum = sum + (float)1 / (float)i;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<EvenSum>:
  endbr64
  cmp    $0x1,%edi
  jle    L12
  movss  D4(%rip),%xmm3
  mov    $0x2,%eax
  pxor   %xmm0,%xmm0
  nopw   0x0(%rax,%rax,1)
L13:
  pxor   %xmm2,%xmm2
  movaps %xmm3,%xmm1
  cvtsi2ss %eax,%xmm2
  add    $0x2,%eax
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cmp    %eax,%edi
  jge    L13
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float EvenSum(int n) {
  float sum = 0;
  int i = 0;
  for (i = 2; i <= n; i += 2) {
    sum = sum + (float)1 / (float)i;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EvenSum>:
  endbr64
  cmp    $0x1,%edi
  jle    L13
  lea    -0x2(%rdi),%eax
  mov    %eax,%ecx
  shr    %ecx
  add    $0x1,%ecx
  cmp    $0x5,%eax
  jbe    L68
  mov    %ecx,%edx
  movdqa D27(%rip),%xmm3
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D17(%rip),%xmm5
  movaps D7(%rip),%xmm4
  shr    $0x2,%edx
  nopw   0x0(%rax,%rax,1)
L31:
  movdqa %xmm3,%xmm2
  movaps %xmm4,%xmm1
  paddd  %xmm5,%xmm3
  add    $0x1,%eax
  cvtdq2ps %xmm2,%xmm2
  divps  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %edx,%eax
  jne    L31
  mov    %ecx,%edx
  and    $0xfffffffc,%edx
  lea    0x2(%rdx,%rdx,1),%eax
  cmp    %edx,%ecx
  je     L20
L19:
  pxor   %xmm2,%xmm2
  movss  D7(%rip),%xmm1
  lea    0x2(%rax),%edx
  cvtsi2ss %eax,%xmm2
  movaps %xmm1,%xmm3
  divss  %xmm2,%xmm3
  addss  %xmm3,%xmm0
  cmp    %edx,%edi
  jl     L48
  pxor   %xmm3,%xmm3
  movaps %xmm1,%xmm2
  add    $0x4,%eax
  cvtsi2ss %edx,%xmm3
  divss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  cmp    %eax,%edi
  jl     L48
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  divss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  pxor   %xmm0,%xmm0
L48:
  ret
  nopl   (%rax)
L20:
  ret
L68:
  mov    $0x2,%eax
  pxor   %xmm0,%xmm0
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_label: D27
data_type: byte[16]
name: disassemble_data
arguments: data_label: D17
data_type: byte[16]
name: disassemble_data
arguments: data_label: D7
data_type: byte[16]

tool: {"D27": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D17": [0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D7": [0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f,0x00,0x00,0x80,0x3f]}

assistant: ```c
float EvenSum(int n) {
  float sum = 0;
  int i = 0;
  for (i = 2; i <= n; i += 2) {
    sum = sum + (float)1 / (float)i;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L28:
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <RaiseInToPower@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L28
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D46
type_guessed: string
name: extract_symbolic_data
arguments: tag: D32
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D59
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string

tool: D46: n^k

tool: D32:  n ? 

tool: D3: %d

tool: D59:  k ? 

tool: D17: %ld


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, n, k;
  printf("n^k\n");
  printf(" n ? ");
  scanf("%d", &n);
  printf(" k ? ");
  scanf("%d", &k);
  for (i = 0; i <= k; i++) {
    printf("%ld\n", RaiseInToPower(n, i));
  }
  return 0;
}
```