ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<in_hex_to_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  lea    D2(%rip),%r13
  jmp    L32
L17:
  lea    -0x41(%rax),%edx
  cmp    $0x5,%edx
  ja     L23
  sub    $0x37,%eax
  jmp    L72
L25:
  add    $0x1,%r12d
  mov    $0x1,%ebx
L32:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strspn@plt>
  cltq
  add    %rbp,%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L23
  lea    0x1(%rax),%rbp
  movzbl %dil,%edi
  call   <toupper@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L17
  mov    %edx,%eax
L72:
  shl    $0x4,%ebx
  or     %eax,%ebx
  test   $0x1,%bh
  je     L32
  test   %r14,%r14
  je     L25
  movslq %r12d,%rax
  mov    %ebx,(%r14,%rax,4)
  jmp    L25
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2:  	


assistant: ```c
int in_hex_to_data(const char *p, uint8_t *data) {
  int c, len, v;
  len = 0;
  v = 1;
  for (;;) {
    p += strspn(p, " \t\r\n");
    if (*p == '\0')
      break;
    c = toupper((unsigned char)*p++);
    if (c >= '0' && c <= '9')
      c = c - '0';
    else if (c >= 'A' && c <= 'F')
      c = c - 'A' + 10;
    else
      break;
    v = (v << 4) | c;
    if (v & 0x100) {
      if (data)
        data[len] = v;
      len++;
      v = 1;
    }
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_hex_to_data>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L40:
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <strspn@plt>
  cltq
  add    %r14,%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L4
  lea    0x1(%rax),%r14
  call   <toupper@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L29
  lea    -0x41(%rax),%edx
  cmp    $0x5,%edx
  ja     L4
  lea    -0x37(%rax),%edx
L29:
  shl    $0x4,%ebx
  or     %edx,%ebx
  test   $0x1,%bh
  je     L40
  test   %r13,%r13
  je     L15
  movslq %r12d,%rax
  mov    %ebx,0x0(%r13,%rax,4)
L15:
  add    $0x1,%r12d
  mov    $0x1,%ebx
  jmp    L40
  xchg   %ax,%ax
L4:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7:  	


assistant: ```c
int in_hex_to_data(const char *p, uint8_t *data) {
  int c, len, v;
  len = 0;
  v = 1;
  for (;;) {
    p += strspn(p, " \t\r\n");
    if (*p == '\0')
      break;
    c = toupper((unsigned char)*p++);
    if (c >= '0' && c <= '9')
      c = c - '0';
    else if (c >= 'A' && c <= 'F')
      c = c - 'A' + 10;
    else
      break;
    v = (v << 4) | c;
    if (v & 0x100) {
      if (data)
        data[len] = v;
      len++;
      v = 1;
    }
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<in_hex_to_data>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  test   %rsi,%rsi
  je     L19
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <strspn@plt>
  cltq
  add    %r14,%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L98
  lea    0x1(%rax),%r14
  call   <toupper@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L47
  lea    -0x41(%rax),%edx
  cmp    $0x5,%edx
  ja     L98
  lea    -0x37(%rax),%edx
L47:
  shl    $0x4,%ebx
  or     %edx,%ebx
  test   $0x1,%bh
  je     L59
  movslq %r12d,%rax
  add    $0x1,%r12d
  mov    %ebx,0x0(%r13,%rax,4)
  mov    $0x1,%ebx
  jmp    L59
  nopl   (%rax)
L19:
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <strspn@plt>
  cltq
  add    %r14,%rax
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L98
  lea    0x1(%rax),%r14
  call   <toupper@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L7
  lea    -0x41(%rax),%edx
  cmp    $0x5,%edx
  ja     L98
  lea    -0x37(%rax),%edx
L7:
  shl    $0x4,%ebx
  or     %edx,%ebx
  test   $0x1,%bh
  je     L19
  add    $0x1,%r12d
  mov    $0x1,%ebx
  jmp    L19
  nopl   0x0(%rax)
L98:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2:  	


assistant: ```c
int in_hex_to_data(const char *p, uint8_t *data) {
  int c, len, v;
  len = 0;
  v = 1;
  for (;;) {
    p += strspn(p, " \t\r\n");
    if (*p == '\0')
      break;
    c = toupper((unsigned char)*p++);
    if (c >= '0' && c <= '9')
      c = c - '0';
    else if (c >= 'A' && c <= 'F')
      c = c - 'A' + 10;
    else
      break;
    v = (v << 4) | c;
    if (v & 0x100) {
      if (data)
        data[len] = v;
      len++;
      v = 1;
    }
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *p, size_t len) {
  char *pp = p + len - 1;
  while (p < pp) {
    char tmp = *p;
    *p = *pp;
    *pp = tmp;
    p++;
    pp--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L10
L16:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  mov    %cl,(%rdi)
  mov    %dl,(%rax)
  add    $0x1,%rdi
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jb     L16
L10:
  ret
```

assistant: ```c
void reverse(char *p, size_t len) {
  char *pp = p + len - 1;
  while (p < pp) {
    char tmp = *p;
    *p = *pp;
    *pp = tmp;
    p++;
    pp--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L14
  xchg   %ax,%ax
L9:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L9
L14:
  ret
```

assistant: ```c
void reverse(char *p, size_t len) {
  char *pp = p + len - 1;
  while (p < pp) {
    char tmp = *p;
    *p = *pp;
    *pp = tmp;
    p++;
    pp--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  lea    -0x1(%rdi,%rsi,1),%rax
  cmp    %rax,%rdi
  jae    L8
  xchg   %ax,%ax
L19:
  movzbl (%rdi),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rax
  mov    %cl,-0x1(%rdi)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rdi
  jb     L19
L8:
  ret
```

assistant: ```c
void reverse(char *p, size_t len) {
  char *pp = p + len - 1;
  while (p < pp) {
    char tmp = *p;
    *p = *pp;
    *pp = tmp;
    p++;
    pp--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L6:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L6
  addl   $0x2,-0x8(%rbp)
L17:
  mov    $0x0,%eax
  call   <getInt@plt>
  cmp    %eax,-0x8(%rbp)
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  int elephant, i;
  for (elephant = 0; elephant < getInt(); elephant = elephant + 2) {
    for (i = 0; i < elephant; i = i + 1) {
      print_int(i);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  jmp    L20
L27:
  mov    %ebx,%edi
  call   <print_int@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L27
L17:
  add    $0x2,%ebp
L20:
  mov    $0x0,%eax
  call   <getInt@plt>
  cmp    %ebp,%eax
  jle    L14
  mov    $0x0,%ebx
  test   %ebp,%ebp
  jg     L27
  jmp    L17
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  int elephant, i;
  for (elephant = 0; elephant < getInt(); elephant = elephant + 2) {
    for (i = 0; i < elephant; i = i + 1) {
      print_int(i);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <getInt@plt>
  cmp    %ebp,%eax
  jle    L6
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  jle    L27
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_int@plt>
  cmp    %ebx,%ebp
  jne    L2
L27:
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <getInt@plt>
  cmp    %ebp,%eax
  jg     L17
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  int elephant, i;
  for (elephant = 0; elephant < getInt(); elephant = elephant + 2) {
    for (i = 0; i < elephant; i = i + 1) {
      print_int(i);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <getInt@plt>
  cmp    %ebp,%eax
  jle    L10
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %ebx,%ebx
  test   %ebp,%ebp
  jle    L5
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <print_int@plt>
  cmp    %ebx,%ebp
  jne    L18
L5:
  xor    %eax,%eax
  add    $0x2,%ebp
  call   <getInt@plt>
  cmp    %ebp,%eax
  jg     L0
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  int elephant, i;
  for (elephant = 0; elephant < getInt(); elephant = elephant + 2) {
    for (i = 0; i < elephant; i = i + 1) {
      print_int(i);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wBasLeft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <wPopNumber@plt>
  mov    %eax,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <wPopString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L29
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <wPushString@plt>
  jmp    L34
L29:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <wFree@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <wPushStringCopy@plt>
  jmp    L34
L10:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <wMalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <wFree@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wPushString@plt>
L34:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: 

assistant: ```c
void wBasLeft() {
  int pos, len, newLen;
  char *string, *left;
  pos = (int)wPopNumber();
  string = wPopString();
  len = strlen(string);
  if (pos > len - 1) {
    wPushString(string);
    return;
  }
  if (pos < 1) {
    wFree(string);
    wPushStringCopy("");
    return;
  }
  newLen = (pos);
  left = (char *)wMalloc(newLen);
  memcpy(left, string, newLen);
  left[newLen] = '\0';
  wFree(string);
  wPushString(left);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wBasLeft>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <wPopNumber@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <wPopString@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L2
  test   %ebx,%ebx
  jle    L19
  mov    %ebx,%edi
  call   <wMalloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %rbp,%rdi
  call   <wFree@plt>
  mov    %r12,%rdi
  call   <wPushString@plt>
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %rbp,%rdi
  call   <wPushString@plt>
  jmp    L1
L19:
  mov    %rbp,%rdi
  call   <wFree@plt>
  lea    D8(%rip),%rdi
  call   <wPushStringCopy@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: 

assistant: ```c
void wBasLeft() {
  int pos, len, newLen;
  char *string, *left;
  pos = (int)wPopNumber();
  string = wPopString();
  len = strlen(string);
  if (pos > len - 1) {
    wPushString(string);
    return;
  }
  if (pos < 1) {
    wFree(string);
    wPushStringCopy("");
    return;
  }
  newLen = (pos);
  left = (char *)wMalloc(newLen);
  memcpy(left, string, newLen);
  left[newLen] = '\0';
  wFree(string);
  wPushString(left);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wBasLeft>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <wPopNumber@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <wPopString@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cmp    %ebx,%eax
  jle    L16
  test   %ebx,%ebx
  jle    L19
  mov    %ebx,%edi
  call   <wMalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %rbp,%rdi
  call   <wFree@plt>
  mov    %r12,%rdi
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1120 <wPushString@plt>
  xchg   %ax,%ax
L19:
  call   <wFree@plt>
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1100 <wPushStringCopy@plt>
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: 

assistant: ```c
void wBasLeft() {
  int pos, len, newLen;
  char *string, *left;
  pos = (int)wPopNumber();
  string = wPopString();
  len = strlen(string);
  if (pos > len - 1) {
    wPushString(string);
    return;
  }
  if (pos < 1) {
    wFree(string);
    wPushStringCopy("");
    return;
  }
  newLen = (pos);
  left = (char *)wMalloc(newLen);
  memcpy(left, string, newLen);
  left[newLen] = '\0';
  wFree(string);
  wPushString(left);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wBasLeft>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <wPopNumber@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <wPopString@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  cmp    %ebx,%eax
  jle    L13
  test   %ebx,%ebx
  jle    L7
  mov    %ebx,%edi
  call   <wMalloc@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  movslq %ebx,%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %rbp,%rdi
  call   <wFree@plt>
  mov    %r12,%rdi
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1120 <wPushString@plt>
  xchg   %ax,%ax
L7:
  call   <wFree@plt>
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1100 <wPushStringCopy@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: 

assistant: ```c
void wBasLeft() {
  int pos, len, newLen;
  char *string, *left;
  pos = (int)wPopNumber();
  string = wPopString();
  len = strlen(string);
  if (pos > len - 1) {
    wPushString(string);
    return;
  }
  if (pos < 1) {
    wFree(string);
    wPushStringCopy("");
    return;
  }
  newLen = (pos);
  left = (char *)wMalloc(newLen);
  memcpy(left, string, newLen);
  left[newLen] = '\0';
  wFree(string);
  wPushString(left);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L1:
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L37:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L24
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L24:
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L37
  subl   $0x1,-0xc(%rbp)
L11:
  cmpl   $0x0,-0xc(%rbp)
  jg     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++) {
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  test   %r8d,%r8d
  jg     L15
  ret
L18:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L55
L9:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L18
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L18
L55:
  sub    $0x1,%r8d
  je     L35
L15:
  test   %r8d,%r8d
  jle    L55
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L9
L35:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++) {
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L30
  nopl   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rdi,%rax,4),%edx
  mov    0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,%edx
  jle    L10
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,0x4(%rdi,%rax,4)
L10:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L24
  sub    $0x1,%esi
  jne    L35
L30:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++) {
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L20
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L15:
  movq   (%rdi,%rdx,4),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L29
  movq   %xmm1,(%rdi,%rdx,4)
L29:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L15
  sub    $0x1,%esi
  jne    L26
L20:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++) {
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L99
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D63(%rip),%rbp
  jmp    L110
L97:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L99
L110:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L97
  call   <PrintUsage@plt>
  jmp    L97
L99:
  lea    -0x2(%r13),%eax
  cmp    $0x1,%eax
  ja     L105
  cmp    $0x2,%r13d
  jne    L75
  mov    0x8(%r14),%r13
  lea    D69(%rip),%rbp
  jmp    L147
L105:
  mov    $0x0,%eax
  call   <PrintUsage@plt>
  lea    D69(%rip),%rbp
  mov    %rbp,%r13
L147:
  mov    $0x605,%esi
  mov    $0x0,%edi
  call   <OpenUdpSocket@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L64
  mov    %rsp,%r12
  mov    %rbp,%r8
  mov    %r13,%rcx
  lea    D61(%rip),%rdx
  mov    $0x40,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %eax,%edx
  mov    $0x0,%ecx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <send@plt>
  test   %rax,%rax
  js     L44
L82:
  mov    %ebx,%edi
  call   <close@plt>
L62:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  cmp    $0x3,%r13d
  jne    L89
  mov    0x8(%r14),%r13
  mov    0x10(%r14),%rbp
  jmp    L147
L89:
  lea    D69(%rip),%rbp
  mov    %rbp,%r13
  jmp    L147
L44:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L64:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L62
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D63
type: string
name: read_data
arguments: tag: D69
type: string
name: read_data
arguments: tag: D61
type: string
name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D20
type: string

tool: D63: --help

tool: 

tool: D61: %s %s

tool: D4: error while sending data to server


tool: D20: could not connect to server, exiting.

assistant: ```c
int main(int argc, char **argv) {
  const char *cmd = "";
  const char *arg = "";
  unsigned int size;
  char buffer[64];
  int skt = NULL;
  for (int i = 1; i < argc; i++) {
    if (!strcmp(argv[i], "--help")) {
      PrintUsage();
    }
  }
  if ((argc < 2) || (argc > 3)) {
    PrintUsage();
  }
  if (argc == 2) {
    cmd = argv[argc - 1];
  }
  if (argc == 3) {
    cmd = argv[argc - 2];
    arg = argv[argc - 1];
  }
  if ((skt = OpenUdpSocket(NULL, 1541)) >= 0) {
    size = snprintf(buffer, 64, "%s %s", cmd, arg);
    if (send(skt, buffer, size, 0) < 0) {
      printf("error while sending data to server\n");
    }
    close(skt);
  } else {
    puts("could not connect to server, exiting.");
    exit(-1);
  }
  return (0);
}
```