ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  je     L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%rdi
  mov    %ebp,%esi
  add    $0x8,%rbx
  call   <print_array@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void print_matrix(int *matrix[], const unsigned rows, const unsigned columns) {
  unsigned i;
  for (i = 0; i < rows; i++) {
    print_array(matrix[i], columns);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  jmp    L47
L19:
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x44(%rbp)
L47:
  cmpl   $0x4,-0x44(%rbp)
  jle    L19
  movl   $0x0,-0x44(%rbp)
  jmp    L45
L44:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L45:
  cmpl   $0x4,-0x44(%rbp)
  jle    L44
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string

tool: D29: podaj tab1[%d]

tool: D8: %d

tool: D27: tab2[%d]=%d


assistant: ```c
int main() {
  int tab1[5], tab2[5], i;
  for (i = 0; i < 5; i++) {
    printf("podaj tab1[%d]", i);
    scanf("%d", &tab1[i]);
  }
  for (i = 0; i < 5; i++) {
    tab2[i] = tab1[i];
    printf("tab2[%d]=%d\n", i, tab2[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x0,%ebx
  lea    D27(%rip),%r13
  lea    D5(%rip),%r12
L17:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    $0x5,%ebx
  jne    L17
  mov    $0x0,%ebx
  lea    D14(%rip),%rbp
L13:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L13
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string

tool: D27: podaj tab1[%d]

tool: D5: %d

tool: D14: tab2[%d]=%d


assistant: ```c
int main() {
  int tab1[5], tab2[5], i;
  for (i = 0; i < 5; i++) {
    printf("podaj tab1[%d]", i);
    scanf("%d", &tab1[i]);
  }
  for (i = 0; i < 5; i++) {
    tab2[i] = tab1[i];
    printf("tab2[%d]=%d\n", i, tab2[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
L26:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L26
  xor    %ebx,%ebx
  lea    D25(%rip),%rbp
L14:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L14
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string

tool: D19: podaj tab1[%d]

tool: D14: %d

tool: D25: tab2[%d]=%d


assistant: ```c
int main() {
  int tab1[5], tab2[5], i;
  for (i = 0; i < 5; i++) {
    printf("podaj tab1[%d]", i);
    scanf("%d", &tab1[i]);
  }
  for (i = 0; i < 5; i++) {
    tab2[i] = tab1[i];
    printf("tab2[%d]=%d\n", i, tab2[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
L4:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0x5,%ebx
  jne    L4
  xor    %ebx,%ebx
  lea    D9(%rip),%rbp
L14:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L14
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type: string
name: disassemble_data
arguments: data_tag: D5
type: string
name: disassemble_data
arguments: data_tag: D9
type: string

tool: D15: podaj tab1[%d]

tool: D5: %d

tool: D9: tab2[%d]=%d


assistant: ```c
int main() {
  int tab1[5], tab2[5], i;
  for (i = 0; i < 5; i++) {
    printf("podaj tab1[%d]", i);
    scanf("%d", &tab1[i]);
  }
  for (i = 0; i < 5; i++) {
    tab2[i] = tab1[i];
    printf("tab2[%d]=%d\n", i, tab2[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L11
L29:
  cmpb   $0x7b,-0x9(%rbp)
  jne    L20
  movl   $0x1,-0x8(%rbp)
L20:
  cmpb   $0x7d,-0x9(%rbp)
  jne    L11
  cmpl   $0x1,-0x8(%rbp)
  jne    L11
  movl   $0x0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x9(%rbp)
  cmpb   $0xa,-0x9(%rbp)
  jne    L29
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string

tool: D18: 
Now , boy Please enter a string ,I will checkwhether the big brace is a couple!


tool: D29: 

There are %d couple big brace in the string that you entered !



tool: D21: pause

assistant: ```c
int main() {
  int signal = 0;
  int number = 0;
  char character = 0;
  printf("\nNow , boy Please enter a string ,I will checkwhether the big brace is a couple!\n\n");
  while ((character = getchar()) != '\n') {
    if (character == '{') {
      signal = 1;
    }
    if (character == '}') {
      if (signal == 1) {
        signal = 0;
        number++;
      }
    }
  }
  printf("\n\nThere are %d couple big brace in the string that you entered !\n\n", number);
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  jmp    L33
L10:
  mov    %r12d,%ebx
L33:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L15
  cmp    $0x7b,%al
  je     L10
  test   %ebx,%ebx
  je     L33
  cmp    $0x7d,%al
  jne    L33
  add    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L33
L15:
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D14
type_infered: string

tool: D12: 
Now , boy Please enter a string ,I will checkwhether the big brace is a couple!


tool: D29: 

There are %d couple big brace in the string that you entered !



tool: D14: pause

assistant: ```c
int main() {
  int signal = 0;
  int number = 0;
  char character = 0;
  printf("\nNow , boy Please enter a string ,I will checkwhether the big brace is a couple!\n\n");
  while ((character = getchar()) != '\n') {
    if (character == '{') {
      signal = 1;
    }
    if (character == '}') {
      if (signal == 1) {
        signal = 0;
        number++;
      }
    }
  }
  printf("\n\nThere are %d couple big brace in the string that you entered !\n\n", number);
  system("pause");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L1
L40:
  cmp    $0x7b,%al
  je     L20
  cmp    $0x7d,%al
  jne    L24
  cmp    $0x1,%ebx
  jne    L24
  xor    %eax,%eax
  add    $0x1,%ebp
  xor    %ebx,%ebx
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L40
L1:
  mov    %ebp,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  mov    $0x1,%ebx
  jmp    L24
```

tool_calls: name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D20
type: string

tool: D25: 
Now , boy Please enter a string ,I will checkwhether the big brace is a couple!


tool: D15: 

There are %d couple big brace in the string that you entered !



tool: D20: pause

assistant: ```c
int main() {
  int signal = 0;
  int number = 0;
  char character = 0;
  printf("\nNow , boy Please enter a string ,I will checkwhether the big brace is a couple!\n\n");
  while ((character = getchar()) != '\n') {
    if (character == '{') {
      signal = 1;
    }
    if (character == '}') {
      if (signal == 1) {
        signal = 0;
        number++;
      }
    }
  }
  printf("\n\nThere are %d couple big brace in the string that you entered !\n\n", number);
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L23
L39:
  cmp    $0x7b,%al
  je     L43
  cmp    $0x7d,%al
  jne    L13
  cmp    $0x1,%ebx
  jne    L13
  xor    %eax,%eax
  add    $0x1,%ebp
  xor    %ebx,%ebx
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L39
L23:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L43:
  mov    $0x1,%ebx
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string

tool: D29: 
Now , boy Please enter a string ,I will checkwhether the big brace is a couple!


tool: D5: 

There are %d couple big brace in the string that you entered !



tool: D27: pause

assistant: ```c
int main() {
  int signal = 0;
  int number = 0;
  char character = 0;
  printf("\nNow , boy Please enter a string ,I will checkwhether the big brace is a couple!\n\n");
  while ((character = getchar()) != '\n') {
    if (character == '{') {
      signal = 1;
    }
    if (character == '}') {
      if (signal == 1) {
        signal = 0;
        number++;
      }
    }
  }
  printf("\n\nThere are %d couple big brace in the string that you entered !\n\n", number);
  system("pause");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <hash@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x29,-0x4(%rbp)
  jle    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = 0; i <= 41; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L3:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  add    $0x1,%ebx
  cmp    $0x2a,%ebx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = 0; i <= 41; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    $0x2a,%ebx
  jne    L5
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = 0; i <= 41; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    $0x2a,%ebx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void test() {
  int i;
  for (i = 0; i <= 41; i++) {
    {
      hash(1);
      hash(i);
    };
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vwarn@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  vwarn(fmt, argv);
  va_end(argv);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vwarn@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  vwarn(fmt, argv);
  va_end(argv);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vwarn@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  vwarn(fmt, argv);
  va_end(argv);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vwarn@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  vwarn(fmt, argv);
  va_end(argv);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
  jmp    L3
L16:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
L3:
  cmpl   $0x1,-0x14(%rbp)
  jg     L16
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long factorial(int k) {
  long r = k;
  for (k--; k > 1; k--) {
    r *= k;
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<factorial>:
  endbr64
  movslq %edi,%rdx
  lea    -0x1(%rdi),%eax
  cmp    $0x1,%eax
  jle    L8
  cltq
  mov    %rdx,%rcx
  sub    $0x2,%rcx
  lea    -0x3(%rdi),%esi
  sub    %rsi,%rcx
L16:
  imul   %rax,%rdx
  sub    $0x1,%rax
  cmp    %rcx,%rax
  jne    L16
L8:
  mov    %rdx,%rax
  ret
```

assistant: ```c
long factorial(int k) {
  long r = k;
  for (k--; k > 1; k--) {
    r *= k;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<factorial>:
  endbr64
  lea    -0x1(%rdi),%eax
  movslq %edi,%r8
  cmp    $0x1,%eax
  jle    L13
  lea    -0x2(%r8),%rdx
  lea    -0x3(%rdi),%ecx
  cltq
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L11:
  imul   %rax,%r8
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
L13:
  mov    %r8,%rax
  ret
```

assistant: ```c
long factorial(int k) {
  long r = k;
  for (k--; k > 1; k--) {
    r *= k;
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<factorial>:
  endbr64
  lea    -0x1(%rdi),%eax
  movslq %edi,%r8
  cmp    $0x1,%eax
  jle    L15
  lea    -0x2(%r8),%rdx
  lea    -0x3(%rdi),%ecx
  cltq
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L14:
  imul   %rax,%r8
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
L15:
  mov    %r8,%rax
  ret
```

assistant: ```c
long factorial(int k) {
  long r = k;
  for (k--; k > 1; k--) {
    r *= k;
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cxl_work_set_amr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L24
L10:
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,0x8(%rax)
  cmpq   $0x0,-0x10(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L37
L20:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L37:
  mov    $0x0,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int cxl_work_set_amr(struct cxl_ioctl_start_work *work, __u64 amr) {
  if (work == NULL) {
    errno = EINVAL;
    return -1;
  }
  work->amr = amr;
  if (amr)
    work->flags |= CXL_START_WORK_AMR;
  else
    work->flags &= ~(CXL_START_WORK_AMR);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cxl_work_set_amr>:
  endbr64
  test   %rdi,%rdi
  je     L7
  mov    %rsi,0x8(%rdi)
  test   %rsi,%rsi
  je     L9
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  or     %eax,(%rdi)
  mov    $0x0,%eax
  ret
L7:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D25(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
L9:
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int cxl_work_set_amr(struct cxl_ioctl_start_work *work, __u64 amr) {
  if (work == NULL) {
    errno = EINVAL;
    return -1;
  }
  work->amr = amr;
  if (amr)
    work->flags |= CXL_START_WORK_AMR;
  else
    work->flags &= ~(CXL_START_WORK_AMR);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cxl_work_set_amr>:
  endbr64
  test   %rdi,%rdi
  je     L4
  mov    D25(%rip),%rax
  mov    (%rdi),%edx
  mov    %rsi,0x8(%rdi)
  mov    (%rax),%eax
  test   %rsi,%rsi
  je     L15
  or     %edx,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L15:
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
L4:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cxl_work_set_amr(struct cxl_ioctl_start_work *work, __u64 amr) {
  if (work == NULL) {
    errno = EINVAL;
    return -1;
  }
  work->amr = amr;
  if (amr)
    work->flags |= CXL_START_WORK_AMR;
  else
    work->flags &= ~(CXL_START_WORK_AMR);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cxl_work_set_amr>:
  endbr64
  test   %rdi,%rdi
  je     L8
  mov    D18(%rip),%rax
  mov    (%rdi),%edx
  mov    %rsi,0x8(%rdi)
  mov    (%rax),%eax
  test   %rsi,%rsi
  je     L10
  or     %edx,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L10:
  not    %eax
  and    %edx,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
L8:
  mov    D27(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cxl_work_set_amr(struct cxl_ioctl_start_work *work, __u64 amr) {
  if (work == NULL) {
    errno = EINVAL;
    return -1;
  }
  work->amr = amr;
  if (amr)
    work->flags |= CXL_START_WORK_AMR;
  else
    work->flags &= ~(CXL_START_WORK_AMR);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZOBRIST_ENPASSANT_INDEX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ZOBRIST_ENPASSANT_FILE_INDEX@plt>
  leave
  ret
```

assistant: ```c
size_t ZOBRIST_ENPASSANT_INDEX(int sq) {
  const size_t file = sq % 8;
  return ZOBRIST_ENPASSANT_FILE_INDEX(file);
}
```