ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L15
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rbx
  mov    $0x0,%r12d
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  movabs $0x7571206f72616c43,%r15
  jmp    L134
L68:
  movabs $0x757165202c6d6953,%rax
  movabs $0x2e6f726574616c69,%rdx
  mov    %rax,(%rbx)
  mov    %rdx,0x8(%rbx)
  movb   $0x0,0x10(%rbx)
  jmp    L73
L47:
  mov    %r15,(%rbx)
  movl   $0x616e2065,0x8(%rbx)
  movw   $0x216f,0xc(%rbx)
  movb   $0x0,0xe(%rbx)
L73:
  add    $0x1,%r12d
  mov    (%rsp),%eax
  add    $0x64,%rbx
  cmp    %r12d,%eax
  jle    L13
L134:
  lea    0x4(%rsp),%rsi
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L47
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L47
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L47
  lea    (%rdx,%rcx,1),%esi
  cmp    %esi,%eax
  jge    L47
  lea    (%rax,%rcx,1),%esi
  cmp    %esi,%edx
  jge    L47
  lea    (%rax,%rdx,1),%esi
  cmp    %esi,%ecx
  jge    L47
  cmp    %ecx,%edx
  jne    L55
  cmp    %edx,%eax
  je     L68
L55:
  movl   $0x2e6d6953,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L73
L13:
  test   %eax,%eax
  jle    L15
  mov    $0x0,%ebx
L144:
  mov    %rbp,%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  add    $0x64,%rbp
  cmp    %ebx,(%rsp)
  jg     L144
L15:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x2738,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string

tool: D14: %d

tool: D17: %d %d %d

assistant: ```c
main() {
  int k, n1, n2, n3, i;
  char resultados[100][100];
  scanf("%d", &k);
  for (i = 0; i < k; i++) {
    scanf("%d %d %d", &n1, &n2, &n3);
    if (n1 > 0 && n2 > 0 && n3 > 0 && n1 < n2 + n3 && n2 < n1 + n3 && n3 < n1 + n2)
      if (n1 == n2 && n2 == n3)
        strcpy(resultados[i], "Sim, equilatero.");
      else
        strcpy(resultados[i], "Sim.");
    else
      strcpy(resultados[i], "Claro que nao!");
  }
  for (i = 0; i < k; i++) {
    printf("%s\n", &resultados[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L118
  lea    0x10(%rsp),%rbx
  xor    %r15d,%r15d
  lea    0xc(%rsp),%r14
  mov    %rbx,%rbp
  lea    0x8(%rsp),%r13
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L84:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L36
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L36
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L36
  lea    (%rdx,%rcx,1),%esi
  cmp    %esi,%eax
  jge    L36
  lea    (%rax,%rcx,1),%esi
  cmp    %esi,%edx
  jge    L36
  lea    (%rax,%rdx,1),%esi
  cmp    %esi,%ecx
  jl     L46
  nopl   0x0(%rax)
L36:
  movabs $0x7571206f72616c43,%rax
  movl   $0x616e2065,0x8(%rbp)
  mov    %rax,0x0(%rbp)
  mov    $0x216f,%eax
  mov    %ax,0xc(%rbp)
  movb   $0x0,0xe(%rbp)
L138:
  mov    (%rsp),%eax
  add    $0x1,%r15d
  add    $0x64,%rbp
  cmp    %r15d,%eax
  jg     L84
  test   %eax,%eax
  jle    L118
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x64,%rbx
  call   <puts@plt>
  cmp    %ebp,(%rsp)
  jg     L15
L118:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x2738,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  cmp    %edx,%eax
  jne    L124
  cmp    %ecx,%edx
  je     L144
L124:
  movl   $0x2e6d6953,0x0(%rbp)
  movb   $0x0,0x4(%rbp)
  jmp    L138
L144:
  movdqa D24(%rip),%xmm0
  movb   $0x0,0x10(%rbp)
  movups %xmm0,0x0(%rbp)
  jmp    L138
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: byte[16]

tool: D17: %d

tool: D28: %d %d %d

tool: {"D24": [0x53,0x69,0x6d,0x2c,0x20,0x65,0x71,0x75,0x69,0x6c,0x61,0x74,0x65,0x72,0x6f,0x2e]}

assistant: ```c
main() {
  int k, n1, n2, n3, i;
  char resultados[100][100];
  scanf("%d", &k);
  for (i = 0; i < k; i++) {
    scanf("%d %d %d", &n1, &n2, &n3);
    if (n1 > 0 && n2 > 0 && n3 > 0 && n1 < n2 + n3 && n2 < n1 + n3 && n3 < n1 + n2)
      if (n1 == n2 && n2 == n3)
        strcpy(resultados[i], "Sim, equilatero.");
      else
        strcpy(resultados[i], "Sim.");
    else
      strcpy(resultados[i], "Claro que nao!");
  }
  for (i = 0; i < k; i++) {
    printf("%s\n", &resultados[i]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L6
  lea    0x10(%rsp),%rbx
  xor    %r15d,%r15d
  lea    0xc(%rsp),%r14
  mov    %rbx,%rbp
  lea    0x8(%rsp),%r13
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L138:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L40
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L40
  mov    0xc(%rsp),%ecx
  test   %ecx,%ecx
  jle    L40
  lea    (%rdx,%rcx,1),%esi
  cmp    %esi,%eax
  jge    L40
  lea    (%rax,%rcx,1),%esi
  cmp    %esi,%edx
  jge    L40
  lea    (%rax,%rdx,1),%esi
  cmp    %esi,%ecx
  jl     L37
  nopl   0x0(%rax)
L40:
  movabs $0x7571206f72616c43,%rax
  movl   $0x616e2065,0x8(%rbp)
  mov    %rax,0x0(%rbp)
  mov    $0x216f,%eax
  mov    %ax,0xc(%rbp)
  movb   $0x0,0xe(%rbp)
L35:
  mov    (%rsp),%eax
  add    $0x1,%r15d
  add    $0x64,%rbp
  cmp    %r15d,%eax
  jg     L138
  test   %eax,%eax
  jle    L6
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L107:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x64,%rbx
  call   <puts@plt>
  cmp    %ebp,(%rsp)
  jg     L107
L6:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x2738,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  cmp    %edx,%eax
  jne    L110
  cmp    %ecx,%edx
  je     L60
L110:
  movl   $0x2e6d6953,0x0(%rbp)
  movb   $0x0,0x4(%rbp)
  jmp    L35
L60:
  movdqa D1(%rip),%xmm0
  movb   $0x0,0x10(%rbp)
  movups %xmm0,0x0(%rbp)
  jmp    L35
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: byte[16]

tool: D8: %d

tool: D10: %d %d %d

tool: {"D1": [0x53,0x69,0x6d,0x2c,0x20,0x65,0x71,0x75,0x69,0x6c,0x61,0x74,0x65,0x72,0x6f,0x2e]}

assistant: ```c
main() {
  int k, n1, n2, n3, i;
  char resultados[100][100];
  scanf("%d", &k);
  for (i = 0; i < k; i++) {
    scanf("%d %d %d", &n1, &n2, &n3);
    if (n1 > 0 && n2 > 0 && n3 > 0 && n1 < n2 + n3 && n2 < n1 + n3 && n3 < n1 + n2)
      if (n1 == n2 && n2 == n3)
        strcpy(resultados[i], "Sim, equilatero.");
      else
        strcpy(resultados[i], "Sim.");
    else
      strcpy(resultados[i], "Claro que nao!");
  }
  for (i = 0; i < k; i++) {
    printf("%s\n", &resultados[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vmfile_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L52
L38:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vmfile_rloc@plt>
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L44
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L14
  mov    $0x0,%eax
  jmp    L70
L14:
  mov    $0xffffffff,%eax
  jmp    L70
L44:
  cmpq   $0x0,-0x8(%rbp)
  jle    L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vmfile_rseek@plt>
  jmp    L52
L8:
  mov    D33(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L70
L52:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vmfile_ravail@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L38
  mov    $0x1,%eax
L70:
  leave
  ret
```

assistant: ```c
int vmfile_write(struct vmfile *vmb, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmfile_ravail(vmb)) > 0) {
    res = write(fd, vmfile_rloc(vmb), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmfile_rseek(vmb, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vmfile_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  jmp    L29
L24:
  mov    D35(%rip),%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L40
L53:
  mov    %rbp,%rdi
  call   <vmfile_rseek@plt>
L29:
  mov    %rbp,%rdi
  call   <vmfile_ravail@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  mov    %rbp,%rdi
  call   <vmfile_rloc@plt>
  mov    %eax,%esi
  mov    %rbx,%rdx
  mov    %r12d,%edi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L24
  jg     L53
  mov    D1(%rip),%rax
  mov    (%rax),%rdx
  mov    D4(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L40
L14:
  mov    $0x1,%eax
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmfile_write(struct vmfile *vmb, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmfile_ravail(vmb)) > 0) {
    res = write(fd, vmfile_rloc(vmb), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmfile_rseek(vmb, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vmfile_write>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L39
  nop
L5:
  mov    %rbx,%rdi
  call   <vmfile_rloc@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L27
  je     L13
  mov    %rbx,%rdi
  call   <vmfile_rseek@plt>
L39:
  mov    %rbx,%rdi
  call   <vmfile_ravail@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L5
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L27:
  mov    D33(%rip),%rdx
  mov    D10(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L13:
  mov    D1(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmfile_write(struct vmfile *vmb, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmfile_ravail(vmb)) > 0) {
    res = write(fd, vmfile_rloc(vmb), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmfile_rseek(vmb, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<vmfile_write>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L35
  nop
L6:
  mov    %rbx,%rdi
  call   <vmfile_rloc@plt>
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <write@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  js     L19
  je     L1
  mov    %rbx,%rdi
  call   <vmfile_rseek@plt>
L35:
  mov    %rbx,%rdi
  call   <vmfile_ravail@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L6
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    D12(%rip),%rdx
  mov    D1(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  pop    %r12
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L1:
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    D1(%rip),%rax
  mov    %rdx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int vmfile_write(struct vmfile *vmb, int fd) {
  ssize_t res;
  size_t rav;
  while ((rav = vmfile_ravail(vmb)) > 0) {
    res = write(fd, vmfile_rloc(vmb), rav);
    if (res < 0)
      return (EAGAIN == errno ? 0 : -1);
    else if (res > 0)
      vmfile_rseek(vmb, res);
    else
      return errno = ENODATA, -1;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: Hello world!


assistant: ```c
int main() {
  int buffer[20];
  int in, out;
  printf("Hello world!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: Hello world!


assistant: ```c
int main() {
  int buffer[20];
  int in, out;
  printf("Hello world!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: Hello world!


assistant: ```c
int main() {
  int buffer[20];
  int in, out;
  printf("Hello world!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: Hello world!


assistant: ```c
int main() {
  int buffer[20];
  int in, out;
  printf("Hello world!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dec_json_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L30
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L19
L30:
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L19
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L19:
  nop
  leave
  ret
```

assistant: ```c
void dec_json_key(char *key) {
  char *ptr = NULL;
  if (key && (ptr = strrchr(key, '.')))
    *ptr = '\0';
  else if (key && !(ptr = strrchr(key, '.')))
    key[0] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<dec_json_key>:
  endbr64
  test   %rdi,%rdi
  je     L31
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L13
  movb   $0x0,(%rax)
L21:
  pop    %rbx
  ret
L13:
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L21
  movb   $0x0,(%rbx)
  jmp    L21
L31:
  ret
```

assistant: ```c
void dec_json_key(char *key) {
  char *ptr = NULL;
  if (key && (ptr = strrchr(key, '.')))
    *ptr = '\0';
  else if (key && !(ptr = strrchr(key, '.')))
    key[0] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dec_json_key>:
  endbr64
  test   %rdi,%rdi
  je     L23
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L16
  movb   $0x0,(%rax)
L27:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L27
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  nop
L23:
  ret
```

assistant: ```c
void dec_json_key(char *key) {
  char *ptr = NULL;
  if (key && (ptr = strrchr(key, '.')))
    *ptr = '\0';
  else if (key && !(ptr = strrchr(key, '.')))
    key[0] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dec_json_key>:
  endbr64
  test   %rdi,%rdi
  je     L26
  push   %rbx
  mov    $0x2e,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L27
  movb   $0x0,(%rax)
L22:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L27:
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L22
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  nop
L26:
  ret
```

assistant: ```c
void dec_json_key(char *key) {
  char *ptr = NULL;
  if (key && (ptr = strrchr(key, '.')))
    *ptr = '\0';
  else if (key && !(ptr = strrchr(key, '.')))
    key[0] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<str_backspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  subq   $0x1,-0x8(%rbp)
  jmp    L4
L27:
  subq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L31
L4:
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
size_t str_backspace(char *str, char c) {
  size_t i = strlen((uint8_t *)str);
  i--;
  while (i) {
    i--;
    if (str[i] == c) {
      str[i + 1] = 0;
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_backspace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  sub    $0x1,%rax
L11:
  test   %rax,%rax
  je     L20
  lea    -0x1(%rax),%rdx
  cmp    %bpl,-0x1(%rbx,%rax,1)
  je     L2
  mov    %rdx,%rax
  jmp    L11
L2:
  movb   $0x0,(%rbx,%rax,1)
  mov    $0x1,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t str_backspace(char *str, char c) {
  size_t i = strlen((uint8_t *)str);
  i--;
  while (i) {
    i--;
    if (str[i] == c) {
      str[i + 1] = 0;
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_backspace>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%rax
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L11:
  lea    -0x1(%rax),%rdx
  cmp    %bpl,-0x1(%rbx,%rax,1)
  je     L3
  mov    %rdx,%rax
L7:
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  movb   $0x0,(%rbx,%rax,1)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t str_backspace(char *str, char c) {
  size_t i = strlen((uint8_t *)str);
  i--;
  while (i) {
    i--;
    if (str[i] == c) {
      str[i + 1] = 0;
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_backspace>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%rax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rax),%rdx
  cmp    %bpl,-0x1(%rbx,%rax,1)
  je     L24
  mov    %rdx,%rax
L3:
  test   %rax,%rax
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  movb   $0x0,(%rbx,%rax,1)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t str_backspace(char *str, char c) {
  size_t i = strlen((uint8_t *)str);
  i--;
  while (i) {
    i--;
    if (str[i] == c) {
      str[i + 1] = 0;
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<s_memset4o>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L9
L23:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L11
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
L11:
  addq   $0x4,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L9:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void s_memset4o(unsigned char *m, int id, void *dest, int c, int n) {
  unsigned int dc = (unsigned int)c;
  unsigned int *d = (unsigned int *)dest;
  while (n--) {
    if (*m == id) {
      *d = dc;
    }
    d++;
    m++;
  };
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<s_memset4o>:
  endbr64
  mov    %rdi,%r9
  test   %r8d,%r8d
  je     L8
  mov    %r8d,%r8d
  mov    $0x0,%eax
  jmp    L29
L4:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L8
L29:
  movzbl (%r9,%rax,1),%edi
  cmp    %esi,%edi
  jne    L4
  mov    %ecx,(%rdx,%rax,4)
  jmp    L4
L8:
  ret
```

assistant: ```c
void s_memset4o(unsigned char *m, int id, void *dest, int c, int n) {
  unsigned int dc = (unsigned int)c;
  unsigned int *d = (unsigned int *)dest;
  while (n--) {
    if (*m == id) {
      *d = dc;
    }
    d++;
    m++;
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<s_memset4o>:
  endbr64
  mov    %rdi,%r9
  test   %r8d,%r8d
  je     L7
  mov    %r8d,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax)
L23:
  movzbl (%r9,%rax,1),%edi
  cmp    %esi,%edi
  jne    L18
  mov    %ecx,(%rdx,%rax,4)
L18:
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L23
L7:
  ret
```

assistant: ```c
void s_memset4o(unsigned char *m, int id, void *dest, int c, int n) {
  unsigned int dc = (unsigned int)c;
  unsigned int *d = (unsigned int *)dest;
  while (n--) {
    if (*m == id) {
      *d = dc;
    }
    d++;
    m++;
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s_memset4o>:
  endbr64
  mov    %rdi,%r9
  test   %r8d,%r8d
  je     L8
  mov    %r8d,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax)
L27:
  movzbl (%r9,%rax,1),%edi
  cmp    %esi,%edi
  jne    L16
  mov    %ecx,(%rdx,%rax,4)
L16:
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
L8:
  ret
```

assistant: ```c
void s_memset4o(unsigned char *m, int id, void *dest, int c, int n) {
  unsigned int dc = (unsigned int)c;
  unsigned int *d = (unsigned int *)dest;
  while (n--) {
    if (*m == id) {
      *d = dc;
    }
    d++;
    m++;
  };
}
```