ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<NextArg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L81
L11:
  mov    $0x0,%eax
  jmp    L80
L95:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L81:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L95
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L55
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L66
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
L66:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L80
L59:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
  jmp    L48
L55:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L114
L24:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L80
L114:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
L48:
  mov    -0x8(%rbp),%rax
L80:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0:  	


assistant: ```c
char *NextArg(char **pkt) {
  char *strReturn;
  ;
  ;
  if (!pkt || !*pkt)
    return 0;
  while (isspace(**pkt))
    (*pkt)++;
  if (**pkt == '"') {
    strReturn = ++(*pkt);
    *pkt = strchr(*pkt, '"');
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  } else {
    strReturn = *pkt;
    *pkt = strpbrk(*pkt, " \t\r\n");
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  }
  return strReturn;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NextArg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L84
  mov    (%rdi),%rbp
  test   %rbp,%rbp
  jne    L33
  jmp    L83
L96:
  addq   $0x1,(%rbx)
L33:
  mov    (%rbx),%rax
  movsbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L96
  mov    (%rbx),%rbp
  cmpb   $0x22,0x0(%rbp)
  je     L3
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L75
  cmpb   $0x0,(%rax)
  je     L75
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L83:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  add    $0x1,%rbp
  mov    %rbp,(%rbx)
  mov    $0x22,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L117
  cmpb   $0x0,(%rax)
  je     L117
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
  jmp    L83
L117:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  mov    %rax,(%rbx)
  jmp    L83
L75:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  mov    %rax,(%rbx)
  jmp    L83
L84:
  mov    %rdi,%rbp
  jmp    L83
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7:  	


assistant: ```c
char *NextArg(char **pkt) {
  char *strReturn;
  ;
  ;
  if (!pkt || !*pkt)
    return 0;
  while (isspace(**pkt))
    (*pkt)++;
  if (**pkt == '"') {
    strReturn = ++(*pkt);
    *pkt = strchr(*pkt, '"');
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  } else {
    strReturn = *pkt;
    *pkt = strpbrk(*pkt, " \t\r\n");
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  }
  return strReturn;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NextArg>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L20
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  jne    L2
  jmp    L48
  nopl   0x0(%rax)
L10:
  mov    (%rbx),%rax
  lea    0x1(%rax),%r12
  mov    %r12,(%rbx)
L2:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  mov    (%rbx),%r12
  cmpb   $0x22,(%r12)
  je     L88
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L23
L56:
  cmpb   $0x0,(%rax)
  je     L23
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L48:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L88:
  add    $0x1,%r12
  mov    $0x22,%esi
  mov    %r12,(%rbx)
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L56
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r12d,%r12d
  jmp    L48
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2:  	


assistant: ```c
char *NextArg(char **pkt) {
  char *strReturn;
  ;
  ;
  if (!pkt || !*pkt)
    return 0;
  while (isspace(**pkt))
    (*pkt)++;
  if (**pkt == '"') {
    strReturn = ++(*pkt);
    *pkt = strchr(*pkt, '"');
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  } else {
    strReturn = *pkt;
    *pkt = strpbrk(*pkt, " \t\r\n");
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  }
  return strReturn;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<NextArg>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L21
  mov    (%rdi),%r12
  mov    %rdi,%rbx
  test   %r12,%r12
  jne    L49
  jmp    L1
  nopl   0x0(%rax)
L35:
  mov    (%rbx),%rax
  lea    0x1(%rax),%r12
  mov    %r12,(%rbx)
L49:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L35
  mov    (%rbx),%r12
  cmpb   $0x22,(%r12)
  je     L17
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <strpbrk@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L55
L87:
  cmpb   $0x0,(%rax)
  je     L55
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  add    $0x1,%r12
  mov    $0x22,%esi
  mov    %r12,(%rbx)
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L87
L55:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %r12d,%r12d
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D8
type: string

tool: D8:  	


assistant: ```c
char *NextArg(char **pkt) {
  char *strReturn;
  ;
  ;
  if (!pkt || !*pkt)
    return 0;
  while (isspace(**pkt))
    (*pkt)++;
  if (**pkt == '"') {
    strReturn = ++(*pkt);
    *pkt = strchr(*pkt, '"');
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  } else {
    strReturn = *pkt;
    *pkt = strpbrk(*pkt, " \t\r\n");
    if (!*pkt || !**pkt) {
      *pkt = strReturn + strlen(strReturn);
      return strReturn;
    }
    *(*pkt)++ = '\0';
  }
  return strReturn;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D96(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  sub    $0x41,%eax
  cmp    $0x25,%eax
  ja     L2
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D82(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D82(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L0
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L2:
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D67
type_infered: string
name: unpack_data
arguments: tag: D65
type_infered: string
name: unpack_data
arguments: tag: D96
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D81
type_infered: string
name: unpack_data
arguments: tag: D11
type_infered: string
name: unpack_data
arguments: tag: D42
type_infered: string
name: unpack_data
arguments: tag: D55
type_infered: string
name: unpack_data
arguments: tag: D88
type_infered: string

tool: D15: Available packages:

tool: D67: A - Transportation, Hotel and Meals.

tool: D65: B - Transportation and Hotel.

tool: D96: C - Transportation only.

tool: D38: 
Select your package: 



tool: D81: You get Meals and

tool: D11: You get Hotel and

tool: D42: You get transportation.

tool: D55: Fuck you bah!

tool: D88: You don't get nuthin!

assistant: ```c
int main() {
  char c;
  puts("Available packages:");
  puts("A - Transportation, Hotel and Meals.");
  puts("B - Transportation and Hotel.");
  puts("C - Transportation only.");
  printf("\nSelect your package: \n\n");
  c = getchar();
  switch (c) {
  case 'A':
  case 'a':
    puts("You get Meals and");
  case 'B':
  case 'b':
    puts("You get Hotel and");
  case 'C':
  case 'c':
    puts("You get transportation.");
    break;
  case 'F':
  case 'f':
    puts("Fuck you bah!");
  default:
    puts("You don't get nuthin!");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    D53(%rip),%rdi
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0x41,%eax
  cmp    $0x25,%al
  ja     L15
  lea    D50(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D71(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
L17:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  lea    D20(%rip),%rdi
  call   <puts@plt>
L15:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: data_tag: D64
type: string
name: retrieve_data
arguments: data_tag: D53
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D49
type: string
name: retrieve_data
arguments: data_tag: D41
type: string
name: retrieve_data
arguments: data_tag: D42
type: string
name: retrieve_data
arguments: data_tag: D71
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D20
type: string
name: retrieve_data
arguments: data_tag: D46
type: string

tool: D64: Available packages:

tool: D53: A - Transportation, Hotel and Meals.

tool: D0: B - Transportation and Hotel.

tool: D49: C - Transportation only.

tool: D41: 
Select your package: 



tool: D42: You get Meals and

tool: D71: You get Hotel and

tool: D17: You get transportation.

tool: D20: Fuck you bah!

tool: D46: You don't get nuthin!

assistant: ```c
int main() {
  char c;
  puts("Available packages:");
  puts("A - Transportation, Hotel and Meals.");
  puts("B - Transportation and Hotel.");
  puts("C - Transportation only.");
  printf("\nSelect your package: \n\n");
  c = getchar();
  switch (c) {
  case 'A':
  case 'a':
    puts("You get Meals and");
  case 'B':
  case 'b':
    puts("You get Hotel and");
  case 'C':
  case 'c':
    puts("You get transportation.");
    break;
  case 'F':
  case 'f':
    puts("Fuck you bah!");
  default:
    puts("You don't get nuthin!");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    D105(%rip),%rdi
  call   <puts@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    D83(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0x41,%eax
  cmp    $0x25,%al
  ja     L7
  lea    D89(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
L18:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  lea    D74(%rip),%rdi
  call   <puts@plt>
L7:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  jmp    L18
```

tool_calls: name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D105
type_guessed: string
name: parse_data
arguments: tag: D55
type_guessed: string
name: parse_data
arguments: tag: D83
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string
name: parse_data
arguments: tag: D84
type_guessed: string
name: parse_data
arguments: tag: D74
type_guessed: string
name: parse_data
arguments: tag: D42
type_guessed: string

tool: D19: Available packages:

tool: D7: A - Transportation, Hotel and Meals.

tool: D105: B - Transportation and Hotel.

tool: D55: C - Transportation only.

tool: D83: 
Select your package: 



tool: D25: You get Meals and

tool: D33: You get Hotel and

tool: D84: You get transportation.

tool: D74: Fuck you bah!

tool: D42: You don't get nuthin!

assistant: ```c
int main() {
  char c;
  puts("Available packages:");
  puts("A - Transportation, Hotel and Meals.");
  puts("B - Transportation and Hotel.");
  puts("C - Transportation only.");
  printf("\nSelect your package: \n\n");
  c = getchar();
  switch (c) {
  case 'A':
  case 'a':
    puts("You get Meals and");
  case 'B':
  case 'b':
    puts("You get Hotel and");
  case 'C':
  case 'c':
    puts("You get transportation.");
    break;
  case 'F':
  case 'f':
    puts("Fuck you bah!");
  default:
    puts("You don't get nuthin!");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void quit(const char *msg) {
  perror(msg);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void quit(const char *msg) {
  perror(msg);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<quit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void quit(const char *msg) {
  perror(msg);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L12
L21:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x20,-0x1(%rbp)
  je     L21
  cmpb   $0x9,-0x1(%rbp)
  je     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void skipSpace(char **token) {
  char c;
  while ((c = **token) == ' ' || c == '\t')
    ++*token;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skipSpace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x9,%dl
  je     L5
  cmp    $0x20,%dl
  jne    L2
L5:
  add    $0x1,%rax
L31:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x9,%dl
  je     L31
  cmp    $0x20,%dl
  je     L31
L2:
  ret
```

assistant: ```c
void skipSpace(char **token) {
  char c;
  while ((c = **token) == ' ' || c == '\t')
    ++*token;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skipSpace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x9,%dl
  je     L12
  cmp    $0x20,%dl
  jne    L9
L12:
  add    $0x1,%rax
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L25
  cmp    $0x9,%dl
  je     L25
L9:
  ret
```

assistant: ```c
void skipSpace(char **token) {
  char c;
  while ((c = **token) == ' ' || c == '\t')
    ++*token;
}
```
user: What is the c source code of the assembly code below?

```asm
<skipSpace>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rax),%edx
  cmp    $0x9,%dl
  je     L3
  cmp    $0x20,%dl
  jne    L33
L3:
  add    $0x1,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %rax,(%rdi)
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L38
  cmp    $0x9,%dl
  je     L38
L33:
  ret
```

assistant: ```c
void skipSpace(char **token) {
  char c;
  while ((c = **token) == ' ' || c == '\t')
    ++*token;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x62,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main() {
  char num;
  num = 'b';
  printf("%d", num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  char num;
  num = 'b';
  printf("%d", num);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
int main() {
  char num;
  num = 'b';
  printf("%d", num);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x62,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  char num;
  num = 'b';
  printf("%d", num);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cpu_mm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    %r9d,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L59
L28:
  movl   $0x0,-0x14(%rbp)
  jmp    L48
L22:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L40:
  mov    -0x18(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  imul   -0x44(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L40
  mov    -0x18(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L48:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L22
  addl   $0x1,-0x18(%rbp)
L59:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cpu_mm(float *a, float *b, float *c, int hA, int wA, int wB) {
  int wC = wB;
  int hC = hA;
  int i, j, k;
  for (i = 0; i < hC; ++i) {
    for (j = 0; j < wC; ++j) {
      float sum = 0.f;
      for (k = 0; k < wA; ++k) {
        sum += a[i * wA + k] * b[k * wB + j];
      }
      c[i * wC + j] = sum;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpu_mm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x20(%rsp)
  mov    %rdx,-0x18(%rsp)
  mov    %ecx,-0x24(%rsp)
  test   %ecx,%ecx
  jle    L50
  mov    %rdi,%rbx
  mov    %r8d,%r10d
  mov    %r9d,%r15d
  movslq %r9d,%rsi
  shl    $0x2,%rsi
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    %r9d,%r11d
  lea    -0x1(%r8),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x4(%rdi),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L9
L73:
  mov    %r8,%rdx
  mov    %rbp,%rax
  pxor   %xmm1,%xmm1
L37:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L37
L55:
  movss  %xmm1,(%r9,%rdi,4)
  add    $0x1,%rdi
  add    $0x4,%r8
  cmp    %r11,%rdi
  je     L46
L24:
  pxor   %xmm1,%xmm1
  test   %r10d,%r10d
  jg     L73
  jmp    L55
L46:
  add    $0x1,%r12d
  add    %r15d,%r13d
  add    %r10d,%r14d
  cmp    %r12d,-0x24(%rsp)
  je     L50
L9:
  test   %r15d,%r15d
  jle    L46
  mov    -0x20(%rsp),%r8
  movslq %r14d,%rax
  lea    (%rbx,%rax,4),%rbp
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rdi
  lea    (%rdi,%rax,4),%rcx
  movslq %r13d,%rax
  mov    -0x18(%rsp),%rdi
  lea    (%rdi,%rax,4),%r9
  mov    $0x0,%edi
  jmp    L24
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void cpu_mm(float *a, float *b, float *c, int hA, int wA, int wB) {
  int wC = wB;
  int hC = hA;
  int i, j, k;
  for (i = 0; i < hC; ++i) {
    for (j = 0; j < wC; ++j) {
      float sum = 0.f;
      for (k = 0; k < wA; ++k) {
        sum += a[i * wA + k] * b[k * wB + j];
      }
      c[i * wC + j] = sum;
    }
  }
}
```