ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<one_complement>:
  endbr64
  cmpb   $0x31,(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x1(%rdi)
  mov    %dl,(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x2(%rdi)
  mov    %dl,0x1(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x3(%rdi)
  mov    %dl,0x2(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x4(%rdi)
  mov    %dl,0x3(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x5(%rdi)
  mov    %dl,0x4(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x6(%rdi)
  mov    %dl,0x5(%rdi)
  setne  %dl
  add    $0x30,%edx
  cmpb   $0x31,0x7(%rdi)
  mov    %dl,0x6(%rdi)
  setne  %dl
  add    $0x30,%edx
  mov    %dl,0x7(%rdi)
  ret
```

assistant: ```c
void one_complement(char reg[]) {
  int i;
  for (i = 0; i < 8; i++) {
    reg[i] = (reg[i] == '1' ? '0' : '1');
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: %d


assistant: ```c
int main(void) {
  int x[] = {1, 3, 5};
  printf("%d\n", search(x, sizeof(x) / sizeof(int), 1));
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x3,%esi
  call   <search@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type: string

tool: D5: %d


assistant: ```c
int main(void) {
  int x[] = {1, 3, 5};
  printf("%d\n", search(x, sizeof(x) / sizeof(int), 1));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000001,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x5,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <search@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: %d


assistant: ```c
int main(void) {
  int x[] = {1, 3, 5};
  printf("%d\n", search(x, sizeof(x) / sizeof(int), 1));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x5,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <search@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type: byte[8]
name: disassemble_data
arguments: data_label: D6
type: string

tool: {"D19": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D6: %d


assistant: ```c
int main(void) {
  int x[] = {1, 3, 5};
  printf("%d\n", search(x, sizeof(x) / sizeof(int), 1));
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<distanceUB_l2_m128>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mulss  %xmm0,%xmm0
  movss  %xmm0,0x4(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    0x3(%rdx),%r15d
  test   %edx,%edx
  cmovns %edx,%r15d
  sar    $0x2,%r15d
  cmp    $0x3,%edx
  jle    L56
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    (%rdi),%rdi
  mov    0x8(%r13),%rsi
  mov    (%r14),%rdx
  mov    0x8(%r14),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rax,%rdi
  mov    %rcx,%rsi
  call   <_mm_mul_ps@plt>
  mov    %eax,%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %rdx,%rbp
  add    $0x10,%r13
  add    $0x10,%r14
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L19
L67:
  add    $0x10,%r13
  add    $0x10,%r14
L19:
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  jge    L56
  mov    0x0(%r13),%rdi
  mov    0x8(%r13),%rsi
  mov    (%r14),%rdx
  mov    0x8(%r14),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    %rax,%rdi
  mov    %rcx,%rsi
  call   <_mm_mul_ps@plt>
  mov    %eax,%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %rdx,%rbp
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  jne    L67
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    0x8(%rsp),%rdi
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jbe    L67
  jmp    L26
L56:
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0x4(%rsp)
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  movss  0x4(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 8 == 7) {
      _mm_store_ps(fsum, sum);
      if (fsum[0] + fsum[1] + fsum[2] + fsum[3] > dist2) {
        return dist2;
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<distanceUB_l2_m128>:
  endbr64
  push   %r15
  mulss  %xmm0,%xmm0
  push   %r14
  lea    0x3(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  movss  %xmm0,0x4(%rsp)
  cmovns %edx,%r14d
  sar    $0x2,%r14d
  cmp    $0x3,%edx
  jle    L64
  mov    %rsi,%r15
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  xor    %r13d,%r13d
  mov    0x8(%rbx),%rsi
  mov    0x8(%r15),%rcx
  add    $0x10,%rbx
  add    $0x10,%r15
  mov    -0x10(%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  lea    0x10(%rsp),%rax
  mov    %rdx,%rbp
  mov    %rax,0x8(%rsp)
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x10,%rbx
  add    $0x10,%r15
L22:
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jge    L2
  mov    (%rbx),%rdi
  mov    0x8(%rbx),%rsi
  mov    0x8(%r15),%rcx
  mov    (%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%r12
  mov    %r13d,%eax
  mov    %rdx,%rbp
  and    $0x7,%eax
  cmp    $0x7,%eax
  jne    L14
  mov    0x8(%rsp),%rdi
  mov    %r12,%rsi
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jbe    L14
  nopw   0x0(%rax,%rax,1)
L41:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  movss  0x4(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L64:
  lea    0x10(%rsp),%rax
  xor    %r12d,%r12d
  xor    %ebp,%ebp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L2:
  mov    0x8(%rsp),%rdi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0x4(%rsp)
  jmp    L41
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 8 == 7) {
      _mm_store_ps(fsum, sum);
      if (fsum[0] + fsum[1] + fsum[2] + fsum[3] > dist2) {
        return dist2;
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<distanceUB_l2_m128>:
  endbr64
  push   %r15
  mulss  %xmm0,%xmm0
  push   %r14
  lea    0x3(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  movss  %xmm0,0x4(%rsp)
  cmovns %edx,%r14d
  sar    $0x2,%r14d
  cmp    $0x3,%edx
  jle    L67
  mov    %rsi,%r15
  mov    %rdi,%r12
  mov    (%rdi),%rdi
  xor    %r13d,%r13d
  mov    0x8(%r12),%rsi
  mov    (%r15),%rdx
  add    $0x10,%r12
  add    $0x10,%r15
  mov    -0x8(%r15),%rcx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  xor    %edi,%edi
  xor    %esi,%esi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%rbp
  lea    0x10(%rsp),%rax
  mov    %rdx,%rbx
  mov    %rax,0x8(%rsp)
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L66:
  add    $0x10,%r12
  add    $0x10,%r15
L30:
  add    $0x1,%r13d
  cmp    %r14d,%r13d
  jge    L16
  mov    (%r12),%rdi
  mov    0x8(%r12),%rsi
  mov    0x8(%r15),%rcx
  mov    (%r15),%rdx
  call   <_mm_sub_ps@plt>
  mov    %rdx,%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rdx
  call   <_mm_mul_ps@plt>
  mov    %rbp,%rdi
  mov    %rbx,%rsi
  mov    %eax,%edx
  call   <_mm_add_ps@plt>
  mov    %rax,%rbp
  mov    %r13d,%eax
  mov    %rdx,%rbx
  and    $0x7,%eax
  cmp    $0x7,%eax
  jne    L66
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jbe    L66
  nopl   0x0(%rax)
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  movss  0x4(%rsp),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  lea    0x10(%rsp),%rax
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L16:
  mov    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %rbx,%rdx
  call   <_mm_store_ps@plt>
  movss  0x10(%rsp),%xmm0
  addss  0x14(%rsp),%xmm0
  addss  0x18(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  call   <sqrt@plt>
  movss  %xmm0,0x4(%rsp)
  jmp    L1
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float distanceUB_l2_m128(__m128 *p1, __m128 *p2, int len, float dist) {
  float ret = 0;
  float dist2 = dist * dist;
  __m128 sum = {0, 0, 0, 0};
  float fsum[4];
  int i = 0;
  for (i = 0; i < len / 4; i++) {
    __m128 diff;
    diff = _mm_sub_ps(p1[i], p2[i]);
    sum = _mm_add_ps(sum, _mm_mul_ps(diff, diff));
    if (i % 8 == 7) {
      _mm_store_ps(fsum, sum);
      if (fsum[0] + fsum[1] + fsum[2] + fsum[3] > dist2) {
        return dist2;
      }
    }
  }
  _mm_store_ps(fsum, sum);
  ret = fsum[0] + fsum[1] + fsum[2] + fsum[3];
  return sqrt(ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzwl -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movw   $0x0,-0x1a(%rbp)
  jmp    L29
L25:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0x14(%rbp)
  subl   $0x2,-0x18(%rbp)
L29:
  cmpl   $0x1,-0x18(%rbp)
  jg     L25
  cmpl   $0x1,-0x18(%rbp)
  jne    L32
  lea    -0x1a(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzwl -0x1a(%rbp),%eax
  movzwl %ax,%eax
  add    %eax,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %ax,-0x1a(%rbp)
  movzwl -0x1a(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
u_short checksum(u_short *data, u_short length) {
  int nleft = length;
  int sum = 0;
  unsigned short *w = data;
  unsigned short value = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&value) = *(unsigned char *)w;
    sum += value;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  value = ~sum;
  return (value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checksum>:
  endbr64
  movzwl %si,%r8d
  mov    $0x0,%r9d
  cmp    $0x1,%r8d
  jle    L44
  mov    %r8d,%esi
  sub    $0x2,%esi
  shr    %esi
  lea    0x1(%rsi),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L0:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L0
  neg    %esi
  lea    -0x2(%r8,%rsi,2),%r8d
L48:
  cmp    $0x1,%r8d
  je     L8
L18:
  mov    %eax,%edx
  sar    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L44:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L48
L8:
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
  jmp    L18
```

assistant: ```c
u_short checksum(u_short *data, u_short length) {
  int nleft = length;
  int sum = 0;
  unsigned short *w = data;
  unsigned short value = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&value) = *(unsigned char *)w;
    sum += value;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  value = ~sum;
  return (value);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checksum>:
  endbr64
  movzwl %si,%esi
  xor    %r9d,%r9d
  cmp    $0x1,%esi
  jle    L20
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L8
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L35:
  cmp    $0x1,%esi
  jne    L13
  mov    (%rcx),%r9b
  movzwl %r9w,%r9d
  add    %r9d,%eax
L13:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L20:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L35
```

assistant: ```c
u_short checksum(u_short *data, u_short length) {
  int nleft = length;
  int sum = 0;
  unsigned short *w = data;
  unsigned short value = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&value) = *(unsigned char *)w;
    sum += value;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  value = ~sum;
  return (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<checksum>:
  endbr64
  movzwl %si,%esi
  mov    %rdi,%rdx
  xor    %r10d,%r10d
  cmp    $0x1,%esi
  jle    L54
  lea    -0x2(%rsi),%r9d
  mov    %r9d,%r11d
  shr    %r11d
  lea    0x1(%r11),%ecx
  cmp    $0xd,%r9d
  jbe    L20
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopw   0x0(%rax,%rax,1)
L74:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  movdqa %xmm1,%xmm3
  punpckhwd %xmm2,%xmm1
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L74
  movdqa %xmm0,%xmm1
  mov    %ecx,%r8d
  psrldq $0x8,%xmm1
  and    $0xfffffff8,%r8d
  paddd  %xmm1,%xmm0
  mov    %r8d,%edi
  movdqa %xmm0,%xmm1
  neg    %edi
  psrldq $0x4,%xmm1
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm1,%xmm0
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm0,%eax
  cmp    %r8d,%ecx
  je     L58
L127:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L58
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L58
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L58
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L58
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L58
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L58
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L58:
  mov    %ecx,%esi
  mov    %r11d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r9,%rcx,2),%esi
L40:
  cmp    $0x1,%esi
  jne    L55
  mov    (%rdx),%r10b
  movzwl %r10w,%edx
  add    %edx,%eax
L55:
  mov    %eax,%edx
  movzwl %ax,%eax
  sar    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  jmp    L40
L20:
  xor    %eax,%eax
  jmp    L127
```

assistant: ```c
u_short checksum(u_short *data, u_short length) {
  int nleft = length;
  int sum = 0;
  unsigned short *w = data;
  unsigned short value = 0;
  while (nleft > 1) {
    sum += *w++;
    nleft -= 2;
  }
  if (nleft == 1) {
    *(unsigned char *)(&value) = *(unsigned char *)w;
    sum += value;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  value = ~sum;
  return (value);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<simputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <simputc@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void simputs(char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    simputc((int)(str[i]));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<simputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  push   %rbx
  lea    0x1(%rdi),%rbx
L3:
  movsbl %al,%edi
  call   <simputc@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L3
  pop    %rbx
  ret
L17:
  ret
```

assistant: ```c
void simputs(char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    simputc((int)(str[i]));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<simputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L5
  push   %rbx
  lea    0x1(%rdi),%rbx
L9:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <simputc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L9
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void simputs(char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    simputc((int)(str[i]));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simputs>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  push   %rbx
  lea    0x1(%rdi),%rbx
L6:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <simputc@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L6
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void simputs(char *str) {
  int i;
  for (i = 0; str[i] != '\0'; i++) {
    simputc((int)(str[i]));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<llabs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L6
  negq   -0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long long llabs(long long val) {
  if (val < 0) {
    val = -val;
  }
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long llabs(long long val) {
  if (val < 0) {
    val = -val;
  }
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long llabs(long long val) {
  if (val < 0) {
    val = -val;
  }
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<llabs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long long llabs(long long val) {
  if (val < 0) {
    val = -val;
  }
  return val;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x8(%rbp)
  nop
L3:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void my_strcat(char *s, char *t) {
  s = s + strlen(s);
  while ((*s++ = *t++) != '\0') {
    ;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_strcat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  mov    $0x0,%eax
L7:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void my_strcat(char *s, char *t) {
  s = s + strlen(s);
  while ((*s++ = *t++) != '\0') {
    ;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strcat>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void my_strcat(char *s, char *t) {
  s = s + strlen(s);
  while ((*s++ = *t++) != '\0') {
    ;
  }
}
```