user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D44(%rip),%rdi
  push   %r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L32
  nopw   0x0(%rax,%rax,1)
L127:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L127
  test   %eax,%eax
  jle    L32
  lea    0x14(%rsp),%r12
  xor    %r13d,%r13d
  mov    $0x4,%r14d
L11:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
  cmp    %eax,%r13d
  jge    L32
  mov    -0x4(%r12),%edx
  mov    %r12,%rbx
  mov    %r13d,%ebp
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L130:
  mov    %rbx,%rdi
  cmp    (%rbx),%edx
  je     L16
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %eax,%ebp
  jl     L130
  test   %cl,%cl
  je     L49
L55:
  mov    %eax,0xc(%rsp)
  add    $0x4,%r12
  cmp    %r13d,%eax
  jg     L11
  nopl   0x0(%rax,%rax,1)
L32:
  lea    D13(%rip),%rdi
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  lea    D24(%rip),%rbp
  test   %eax,%eax
  jle    L2
  nopw   0x0(%rax,%rax,1)
L58:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L58
L2:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L134
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    -0x1(%rax),%r15d
  add    $0x4,%rbx
  mov    %r15d,%edx
  mov    %rbx,%rsi
  sub    %ebp,%edx
  cmp    %ebp,%eax
  lea    0x4(,%rdx,4),%rdx
  cmovle %r14,%rdx
  add    $0x1,%ebp
  call   <memmove@plt>
  mov    %r15d,%eax
  cmp    %ebp,%r15d
  jle    L55
  mov    -0x4(%r12),%edx
  mov    $0x1,%ecx
  jmp    L130
  nopl   0x0(%rax)
L49:
  add    $0x4,%r12
  jmp    L11
L134:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D44
type: string
name: parse_data
arguments: data_label: D4
type: string
name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D46
type: string

tool: D44: Dati un numar n natural:

tool: D4: a[%d]= 

tool: D10: %d

tool: D13: Vectorul unicat:

tool: D24: %d 

tool: D46: 
Exit...

assistant: ```c
int main() {
  int a[50];
  int n;
  printf("Dati un numar n natural:\n");
  scanf("%d", &n);
  for (int i = 0; i < n; ++i) {
    printf("a[%d]= ", i);
    scanf("%d", &a[i]);
  }
  for (int i = 0; i < n; ++i) {
    printf("\n");
    for (int j = i + 1; j < n; ++j) {
      if (a[i] == a[j]) {
        for (int h = j; h < n; ++h) {
          a[h] = a[h + 1];
        }
        --n;
      }
    }
  }
  printf("Vectorul unicat:\n");
  for (int i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  printf("\nExit...\n");
  return 0;
}
```