ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<inverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r13
  mov    %rdi,0x28(%rsp)
  mov    %esi,%ebx
  mov    %edx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %edx,%edi
  call   <imat@plt>
  cltq
  mov    %rax,0x8(%rsp)
  mov    %r15d,%esi
  mov    %r15d,%edi
  mov    $0x0,%eax
  call   <mat@plt>
  movslq %eax,%rsi
  mov    %rsi,0x10(%rsp)
  test   %r15d,%r15d
  jle    L84
  movslq %r15d,%r14
  shl    $0x3,%r14
  mov    %rsi,%rbp
  movslq %ebx,%rbx
  lea    0x0(,%rbx,8),%rax
  mov    %rax,(%rsp)
  mov    %r13,%r12
  mov    $0x0,%ebx
L72:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  add    %r14,%rbp
  add    (%rsp),%r13
  cmp    %ebx,%r15d
  jne    L72
  mov    %eax,0x1c(%rsp)
  lea    0x30(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    %ebx,%esi
  mov    0x10(%rsp),%rdi
  mov    $0x0,%eax
  call   <ludcmp@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jne    L70
  mov    (%rsp),%rax
  add    $0x8,%rax
  mov    %rax,0x20(%rsp)
  mov    0x1c(%rsp),%eax
  mov    0x28(%rsp),%r13
  lea    0x8(%r13,%rax,8),%rbp
  mov    D6(%rip),%r15
L24:
  mov    %r13,%rax
L12:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L12
  mov    %r15,(%r12)
  mov    %r13,%rcx
  mov    0x8(%rsp),%rdx
  mov    %ebx,%esi
  mov    0x10(%rsp),%rdi
  mov    $0x0,%eax
  call   <lubksb@plt>
  lea    0x1(%r14),%eax
  add    0x20(%rsp),%r12
  mov    (%rsp),%rcx
  add    %rcx,%r13
  add    %rcx,%rbp
  cmp    %r14d,0x1c(%rsp)
  je     L33
  mov    %eax,%r14d
  jmp    L24
L70:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L51
L84:
  lea    0x30(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    %r15d,%esi
  mov    0x10(%rsp),%rdi
  mov    $0x0,%eax
  call   <ludcmp@plt>
  test   %eax,%eax
  jne    L70
L33:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    $0x0,%eax
L51:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: f64

tool: D6: 1

assistant: ```c
extern int inverse(double *A, int lda, int n) {
  double d, *B;
  int i, j, *indx;
  indx = imat(n, 1);
  B = mat(n, n);
  for (i = 0; i < n; i++)
    memcpy(B + i * n, A + lda * i, sizeof(double) * n);
  if (ludcmp(B, n, indx, &d)) {
    free(indx);
    free(B);
    return -1;
  }
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++)
      A[i + j * lda] = 0.0;
    A[j + j * lda] = 1.0;
    lubksb(B, n, indx, A + j * lda);
  }
  free(indx);
  free(B);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inverse>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  mov    $0x1,%esi
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %edx,%edi
  mov    %edx,0x4(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <imat@plt>
  mov    %r15d,%esi
  mov    %r15d,%edi
  cltq
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <mat@plt>
  movslq %eax,%r14
  test   %r15d,%r15d
  jle    L58
  movslq %r15d,%rdx
  mov    %r14,%rdi
  shl    $0x3,%rbx
  mov    %r12,%rbp
  lea    0x0(,%rdx,8),%r13
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L70:
  mov    %r12,%rsi
  mov    %r13,%rdx
  add    %rbx,%r12
  call   <memcpy@plt>
  mov    %r15d,(%rsp)
  add    $0x1,%r15d
  mov    %rax,%rdi
  add    %r13,%rdi
  cmp    %r15d,0x4(%rsp)
  jne    L70
  mov    0x8(%rsp),%rdx
  lea    0x20(%rsp),%rcx
  mov    %r15d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <ludcmp@plt>
  mov    %eax,%r10d
  test   %eax,%eax
  jne    L75
  lea    0x8(%rbx),%rax
  mov    0x18(%rsp),%r13
  mov    %rax,0x10(%rsp)
  mov    (%rsp),%eax
  lea    0x8(%r13,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r13,%rax
  nopl   0x0(%rax,%rax,1)
L21:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %r12,%rax
  jne    L21
  mov    D3(%rip),%rax
  mov    %r13,%rcx
  mov    %r15d,%esi
  mov    %r14,%rdi
  mov    0x8(%rsp),%rdx
  mov    %r10d,0x4(%rsp)
  add    %rbx,%r13
  add    %rbx,%r12
  mov    %rax,0x0(%rbp)
  xor    %eax,%eax
  call   <lubksb@plt>
  mov    0x4(%rsp),%r10d
  add    0x10(%rsp),%rbp
  lea    0x1(%r10),%eax
  cmp    %r10d,(%rsp)
  je     L52
  mov    %eax,%r10d
  jmp    L1
L58:
  mov    0x8(%rsp),%rdx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    0x20(%rsp),%rcx
  mov    %r14,%rdi
  call   <ludcmp@plt>
  test   %eax,%eax
  jne    L75
  nopl   0x0(%rax,%rax,1)
L52:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  xor    %eax,%eax
L7:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L77
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: f64

tool: D3: 1

assistant: ```c
extern int inverse(double *A, int lda, int n) {
  double d, *B;
  int i, j, *indx;
  indx = imat(n, 1);
  B = mat(n, n);
  for (i = 0; i < n; i++)
    memcpy(B + i * n, A + lda * i, sizeof(double) * n);
  if (ludcmp(B, n, indx, &d)) {
    free(indx);
    free(B);
    return -1;
  }
  for (j = 0; j < n; j++) {
    for (i = 0; i < n; i++)
      A[i + j * lda] = 0.0;
    A[j + j * lda] = 1.0;
    lubksb(B, n, indx, A + j * lda);
  }
  free(indx);
  free(B);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_counts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3e7,-0x4(%rbp)
  jg     L16
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x4(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D69(%rip),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L6
L16:
  cmpl   $0x3b9ac9ff,-0x4(%rbp)
  jg     L29
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x4(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D50(%rip),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L6
L29:
  pxor   %xmm3,%xmm3
  cvtsi2sdl -0x4(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D67(%rip),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
L6:
  lea    D40(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D69
type_guessed: string
name: unpack_data
arguments: label: D61
type_guessed: f64
name: unpack_data
arguments: label: D50
type_guessed: string
name: unpack_data
arguments: label: D67
type_guessed: string

tool: D69: %u

tool: D61: 1000

tool: D50: %.0fk

tool: D67: %.1G

assistant: ```c
char *int_counts(uint32_t count) {
  static char result[0x10];
  if (count < 1e3)
    sprintf(result, "%u", count);
  else if (count < 1e9)
    sprintf(result, "%.0fk", count / 1e3);
  else
    sprintf(result, "%.1G", (double)count);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int_counts>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3e7,%edi
  jle    L23
  cmp    $0x3b9ac9ff,%edi
  jg     L33
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  divsd  D11(%rip),%xmm0
  lea    D50(%rip),%rsi
  lea    D68(%rip),%rdi
  call   <sprintf@plt>
L36:
  lea    D68(%rip),%rax
  add    $0x8,%rsp
  ret
L23:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  lea    D2(%rip),%rsi
  lea    D68(%rip),%rdi
  call   <sprintf@plt>
  jmp    L36
L33:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  lea    D27(%rip),%rsi
  lea    D68(%rip),%rdi
  call   <sprintf@plt>
  jmp    L36
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: f64
name: read_data
arguments: data_tag: D50
data_type: string
name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D11: 1000

tool: D50: %.0fk

tool: D2: %u

tool: D27: %.1G

assistant: ```c
char *int_counts(uint32_t count) {
  static char result[0x10];
  if (count < 1e3)
    sprintf(result, "%u", count);
  else if (count < 1e9)
    sprintf(result, "%.0fk", count / 1e3);
  else
    sprintf(result, "%.1G", (double)count);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_counts>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %r12
  cvtsi2sd %edi,%xmm0
  cmp    $0x3e7,%edi
  jle    L16
  cmp    $0x3b9ac9ff,%edi
  jle    L7
  lea    D20(%rip),%r12
  lea    D23(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D20(%rip),%r12
  lea    D4(%rip),%rsi
  divsd  D16(%rip),%xmm0
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  lea    D20(%rip),%r12
  lea    D40(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_guessed: string
name: retrieve_data
arguments: tag: D4
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: f64
name: retrieve_data
arguments: tag: D40
type_guessed: string

tool: D23: %.1G

tool: D4: %.0fk

tool: D16: 1000

tool: D40: %u

assistant: ```c
char *int_counts(uint32_t count) {
  static char result[0x10];
  if (count < 1e3)
    sprintf(result, "%u", count);
  else if (count < 1e9)
    sprintf(result, "%.0fk", count / 1e3);
  else
    sprintf(result, "%.1G", (double)count);
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_counts>:
  endbr64
  pxor   %xmm0,%xmm0
  push   %r12
  cvtsi2sd %edi,%xmm0
  cmp    $0x3e7,%edi
  jle    L14
  cmp    $0x3b9ac9ff,%edi
  jle    L11
  lea    D16(%rip),%r12
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D16(%rip),%r12
  lea    D13(%rip),%rsi
  divsd  D66(%rip),%xmm0
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  lea    D16(%rip),%r12
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_infered: string
name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D66
type_infered: f64
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D19: %.1G

tool: D13: %.0fk

tool: D66: 1000

tool: D3: %u

assistant: ```c
char *int_counts(uint32_t count) {
  static char result[0x10];
  if (count < 1e3)
    sprintf(result, "%u", count);
  else if (count < 1e9)
    sprintf(result, "%.0fk", count / 1e3);
  else
    sprintf(result, "%.1G", (double)count);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_177_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_177_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S ^ T;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrop3_177_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%edx
  xor    %esi,%edx
  or     $0xff,%dl
  xor    %esi,%edx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  not    %edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_177_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S ^ T;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_177_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  xor    %esi,%edx
  mov    %esi,%eax
  or     $0xff,%dl
  not    %eax
  or     %edi,%eax
  xor    %esi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_177_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S ^ T;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_177_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  xor    %esi,%edx
  mov    %esi,%eax
  or     $0xff,%dl
  not    %eax
  or     %edi,%eax
  xor    %esi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_177_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S ^ T;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gettimeofday>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L5
L14:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,0x4(%rax)
  mov    -0x20(%rbp),%rax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
int gettimeofday(struct timeval *tv, void *tz) {
  struct timespec ts;
  if (!tv)
    return 0;
  clock_gettime(CLOCK_REALTIME, &ts);
  tv->tv_sec = ts.tv_sec;
  tv->tv_usec = (int)ts.tv_nsec / 1000;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gettimeofday>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  mov    %rdi,%rbx
  mov    %rsp,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    0x8(%rsp),%eax
  mov    %eax,0x4(%rbx)
  mov    (%rsp),%rdx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimeofday(struct timeval *tv, void *tz) {
  struct timespec ts;
  if (!tv)
    return 0;
  clock_gettime(CLOCK_REALTIME, &ts);
  tv->tv_sec = ts.tv_sec;
  tv->tv_usec = (int)ts.tv_nsec / 1000;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gettimeofday>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L9
  mov    D8(%rip),%rax
  mov    %rdi,%rbx
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    0x8(%rsp),%eax
  mov    (%rsp),%rdx
  mov    %eax,0x4(%rbx)
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,(%rbx)
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimeofday(struct timeval *tv, void *tz) {
  struct timespec ts;
  if (!tv)
    return 0;
  clock_gettime(CLOCK_REALTIME, &ts);
  tv->tv_sec = ts.tv_sec;
  tv->tv_usec = (int)ts.tv_nsec / 1000;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gettimeofday>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L7
  mov    D2(%rip),%rax
  mov    %rdi,%rbx
  mov    %rsp,%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  mov    (%rsp),%rdx
  movd   0x8(%rsp),%xmm1
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rbx)
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gettimeofday(struct timeval *tv, void *tz) {
  struct timespec ts;
  if (!tv)
    return 0;
  clock_gettime(CLOCK_REALTIME, &ts);
  tv->tv_sec = ts.tv_sec;
  tv->tv_usec = (int)ts.tv_nsec / 1000;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<assertEquals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
L0:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D10: Failed. Expected '%s', Actual '%s' ... exiting


tool: D0: Passed: %s


assistant: ```c
void assertEquals(char str1[], char str2[]) {
  if (strcmp(str1, str2) != 0) {
    printf("Failed. Expected '%s', Actual '%s' ... exiting\n", str1, str2);
    exit(1);
  } else {
    printf("Passed: %s\n", str1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assertEquals>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string

tool: D7: Failed. Expected '%s', Actual '%s' ... exiting


tool: D2: Passed: %s


assistant: ```c
void assertEquals(char str1[], char str2[]) {
  if (strcmp(str1, str2) != 0) {
    printf("Failed. Expected '%s', Actual '%s' ... exiting\n", str1, str2);
    exit(1);
  } else {
    printf("Passed: %s\n", str1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assertEquals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
L9:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string

tool: D10: Failed. Expected '%s', Actual '%s' ... exiting


tool: D13: Passed: %s


assistant: ```c
void assertEquals(char str1[], char str2[]) {
  if (strcmp(str1, str2) != 0) {
    printf("Failed. Expected '%s', Actual '%s' ... exiting\n", str1, str2);
    exit(1);
  } else {
    printf("Passed: %s\n", str1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<assertEquals>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L6
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  jmp    1090 <exit@plt>
L6:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D11: Failed. Expected '%s', Actual '%s' ... exiting


tool: D3: Passed: %s


assistant: ```c
void assertEquals(char str1[], char str2[]) {
  if (strcmp(str1, str2) != 0) {
    printf("Failed. Expected '%s', Actual '%s' ... exiting\n", str1, str2);
    exit(1);
  } else {
    printf("Passed: %s\n", str1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<screen_rotated>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void screen_rotated(void) {
  do {
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<screen_rotated>:
  endbr64
  ret
```

assistant: ```c
void screen_rotated(void) {
  do {
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<screen_rotated>:
  endbr64
  ret
```

assistant: ```c
void screen_rotated(void) {
  do {
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<screen_rotated>:
  endbr64
  ret
```

assistant: ```c
void screen_rotated(void) {
  do {
  } while (0);
}
```