user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L155:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L155
  sub    $0x558,%rsp
  lea    D2(%rip),%rbx
  lea    D9(%rip),%rbp
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc3548(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x10(%rsp),%r15
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
  mov    $0x61a94,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  lea    0x61ab0(%rsp),%r13
  mov    $0x61a94,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    (%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rax,%rax
  je     L229
L190:
  mov    $0x61a94,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rsi
  xor    %r8d,%r8d
  cmp    $0x1,%rsi
  jle    L52
  mov    $0x2,%ecx
  jmp    L136
  xchg   %ax,%ax
L217:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jl     L52
L136:
  mov    %rsi,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L217
  mov    %ecx,0x10(%rsp,%r8,4)
  mov    %rax,%rsi
  mov    $0x2,%ecx
  add    $0x1,%r8
  cmp    %rcx,%rsi
  jge    L136
L52:
  mov    %r8,%rsi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %rax,%r9
  cmp    $0x1,%rax
  jle    L68
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L86:
  mov    %r15,%rdx
  mov    %rsi,%rax
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L230:
  test   $0x1,%al
  je     L220
  movslq (%rdx),%rdi
  imul   %rdi,%rcx
L220:
  add    $0x4,%rdx
  sar    %rax
  jne    L230
  lea    0x1(%rsi),%rdx
  mov    %ecx,-0x4(%r13,%rsi,4)
  cmp    %rdx,%r9
  je     L103
  mov    %rdx,%rsi
  jmp    L86
L103:
  lea    -0x1(%rsi),%r10
  nopl   0x0(%rax,%rax,1)
L81:
  mov    0x0(%r13,%rax,4),%r8d
  mov    %rsi,%rdx
  mov    %rax,%r11
  sub    %rax,%rdx
  mov    %r8d,%edi
  cmp    %rdx,%rax
  jl     L65
  jmp    L208
  nopl   0x0(%rax,%rax,1)
L61:
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %edi,%ecx
  jge    L11
  mov    %edx,%r14d
  mov    %ecx,%edi
L11:
  mov    %rdx,%r11
L65:
  mov    %rsi,%rcx
  lea    0x1(%r11),%rdx
  sub    %r11,%rcx
  sub    $0x1,%rcx
  cmp    %rcx,%rdx
  jl     L61
  cmp    %r8d,%edi
  je     L208
  movslq %r14d,%rdx
  mov    0x61ab0(%rsp,%rdx,4),%ecx
  mov    %ecx,0x0(%r13,%rax,4)
  mov    %r8d,0x61ab0(%rsp,%rdx,4)
L208:
  lea    0x1(%rax),%rdx
  cmp    %r10,%rax
  jge    L46
  mov    %rdx,%rax
  jmp    L81
L46:
  movslq 0x61ab0(%rsp),%r8
  mov    %r8,%rdi
  add    $0x1,%r8
  cmp    $0x1,%rsi
  je     L88
  lea    0x61ab4(%rsp),%rdx
  lea    0x61aa8(%rsp,%r9,4),%rsi
  jmp    L56
  nopl   (%rax)
L6:
  add    $0x4,%rdx
  mov    %ecx,%edi
L56:
  movslq (%rdx),%rax
  mov    %rax,%rcx
  add    %r8,%rax
  cmp    %edi,%ecx
  cmovne %rax,%r8
  cmp    %rsi,%rdx
  jne    L6
L88:
  mov    %r8,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rax,%rax
  jne    L190
L229:
  mov    0xc3548(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0xc3558,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  movslq 0x61ab0(%rsp),%r8
  add    $0x1,%r8
  jmp    L88
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D9
type_infered: string

tool: D2: %lld

tool: D9: %lld


assistant: ```c
int main() {
  long long int t, n, sum, i, l, j, k, temp, num, p, f, prod, set;
  scanf("%lld", &t);
  int prm[100005] = {0}, fact[100005] = {0};
  while (t--) {
    p = f = 0;
    sum = 1;
    for (i = 0; i < 100005; i++)
      prm[i] = fact[100005] = 0;
    scanf("%lld", &n);
    num = n;
    for (i = 2; i <= num; i++) {
      if (num % i == 0) {
        prm[p++] = i;
        num /= i;
        i = 1;
      }
    }
    set = pow(2, p);
    for (i = 1; i < set; i++) {
      k = i;
      l = 0;
      prod = 1;
      while (k) {
        if (k & 1) {
          prod *= prm[l];
        }
        k = k >> 1;
        l++;
      }
      fact[f++] = prod;
    }
    int pos;
    for (i = 0; i < f; i++) {
      int min = fact[i];
      for (j = i; j < f - j; j++) {
        if (min > fact[j]) {
          min = fact[j];
          pos = j;
        }
      }
      if (min != fact[i]) {
        temp = fact[i];
        fact[i] = fact[pos];
        fact[pos] = temp;
      }
    }
    sum += fact[0];
    for (i = 1; i < f; i++) {
      if (fact[i] != fact[i - 1]) {
        sum += fact[i];
      }
    }
    printf("%lld\n", sum);
  }
  return 0;
}
```