ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap2>:
  endbr64
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%r8
  mov    (%r8),%r9d
  movslq %ecx,%rcx
  lea    (%rdi,%rcx,4),%rax
  mov    (%rax),%edi
  mov    %edi,(%r8)
  mov    %r9d,(%rax)
  lea    (%rsi,%rdx,8),%rdx
  movsd  (%rdx),%xmm0
  lea    (%rsi,%rcx,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
```

assistant: ```c
void swap2(int *v, double *w, int i, int j) {
  int temp;
  double temp2;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
  temp2 = w[i];
  w[i] = w[j];
  w[j] = temp2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap2>:
  endbr64
  movslq %edx,%rdx
  movslq %ecx,%rcx
  lea    (%rdi,%rdx,4),%r8
  lea    (%rdi,%rcx,4),%rax
  mov    (%rax),%edi
  mov    (%r8),%r9d
  lea    (%rsi,%rdx,8),%rdx
  movsd  (%rdx),%xmm0
  mov    %edi,(%r8)
  mov    %r9d,(%rax)
  lea    (%rsi,%rcx,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
```

assistant: ```c
void swap2(int *v, double *w, int i, int j) {
  int temp;
  double temp2;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
  temp2 = w[i];
  w[i] = w[j];
  w[j] = temp2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap2>:
  endbr64
  movslq %edx,%rdx
  movslq %ecx,%rcx
  lea    (%rdi,%rdx,4),%r8
  lea    (%rdi,%rcx,4),%rax
  mov    (%rax),%edi
  mov    (%r8),%r9d
  lea    (%rsi,%rdx,8),%rdx
  movsd  (%rdx),%xmm0
  mov    %edi,(%r8)
  mov    %r9d,(%rax)
  lea    (%rsi,%rcx,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%rax)
  ret
```

assistant: ```c
void swap2(int *v, double *w, int i, int j) {
  int temp;
  double temp2;
  temp = v[i];
  v[i] = v[j];
  v[j] = temp;
  temp2 = w[i];
  w[i] = w[j];
  w[j] = temp2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x797a,-0xe(%rbp)
  movb   $0x78,-0xc(%rbp)
  movw   $0x6261,-0xb(%rbp)
  movb   $0x63,-0x9(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main(void) {
  char array[2][3] = {{'z', 'y', 'x'}, {'a', 'b', 'c'}};
  print_array(array);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x797a,0x2(%rsp)
  movb   $0x78,0x4(%rsp)
  movw   $0x6261,0x5(%rsp)
  movb   $0x63,0x7(%rsp)
  lea    0x2(%rsp),%rdi
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char array[2][3] = {{'z', 'y', 'x'}, {'a', 'b', 'c'}};
  print_array(array);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x6261,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rdi
  mov    $0x797a,%eax
  movb   $0x78,0x4(%rsp)
  mov    %ax,0x2(%rsp)
  mov    %dx,0x5(%rsp)
  movb   $0x63,0x7(%rsp)
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char array[2][3] = {{'z', 'y', 'x'}, {'a', 'b', 'c'}};
  print_array(array);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x6261,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rdi
  mov    $0x797a,%eax
  movb   $0x78,0x4(%rsp)
  mov    %ax,0x2(%rsp)
  mov    %dx,0x5(%rsp)
  movb   $0x63,0x7(%rsp)
  call   <print_array@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char array[2][3] = {{'z', 'y', 'x'}, {'a', 'b', 'c'}};
  print_array(array);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D65(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D53(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movl   $0x1,-0x2c(%rbp)
  jmp    L27
L46:
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D11(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D46(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x3,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %rax,%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L21
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L42
L21:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L42:
  addl   $0x1,-0x2c(%rbp)
L27:
  mov    -0x30(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jle    L46
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D65
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string
name: extract_symbolic_data
arguments: label: D53
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: f64
name: extract_symbolic_data
arguments: label: D41
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string

tool: D65: r

tool: D31: heart.in

tool: D53: %d

tool: D11: %lf %lf

tool: D46: 1

tool: D41: Point #%d: You give love a bad name.


tool: D15: Point #%d: Let it rock!


assistant: ```c
int main() {
  FILE *fin = fopen("heart.in", "r");
  int times, t;
  fscanf(fin, "%d", &times);
  for (t = 1; t <= times; t++) {
    double x, y;
    fscanf(fin, "%lf %lf", &x, &y);
    double inequality = pow(x * x + y * y - 1, 3.) - x * x * y * y * y;
    if (inequality < 0) {
      printf("Point #%d: You give love a bad name.\n", t);
    } else {
      printf("Point #%d: Let it rock!\n", t);
    }
  }
  fclose(fin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D30(%rip),%rsi
  lea    D51(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdx
  lea    D39(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L10
  mov    $0x1,%ebx
  lea    D50(%rip),%r12
  lea    D55(%rip),%r13
  jmp    L33
L59:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
L43:
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jl     L10
L33:
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D2(%rip),%xmm0
  mov    $0x3,%edi
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  comisd %xmm0,%xmm3
  jbe    L59
  mov    %ebx,%esi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L10:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D30
type_guessed: string
name: read_data
arguments: data_label: D51
type_guessed: string
name: read_data
arguments: data_label: D39
type_guessed: string
name: read_data
arguments: data_label: D50
type_guessed: string
name: read_data
arguments: data_label: D55
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: f64
name: read_data
arguments: data_label: D41
type_guessed: string

tool: D30: r

tool: D51: heart.in

tool: D39: %d

tool: D50: %lf %lf

tool: D55: Point #%d: Let it rock!


tool: D2: 1

tool: D41: Point #%d: You give love a bad name.


assistant: ```c
int main() {
  FILE *fin = fopen("heart.in", "r");
  int times, t;
  fscanf(fin, "%d", &times);
  for (t = 1; t <= times; t++) {
    double x, y;
    fscanf(fin, "%lf %lf", &x, &y);
    double inequality = pow(x * x + y * y - 1, 3.) - x * x * y * y * y;
    if (inequality < 0) {
      printf("Point #%d: You give love a bad name.\n", t);
    } else {
      printf("Point #%d: Let it rock!\n", t);
    }
  }
  fclose(fin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D63(%rip),%rsi
  lea    D47(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L3
  mov    $0x1,%r15d
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  lea    D1(%rip),%rbx
  lea    D11(%rip),%r14
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r14,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x4(%rsp)
  jl     L3
L0:
  mov    %rbx,%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%edi
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  subsd  D60(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  mov    %r15d,%esi
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  jbe    L55
  lea    D61(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x4(%rsp)
  jge    L0
L3:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D63
data_type: string
name: extract_symbolic_data
arguments: data_tag: D47
data_type: string
name: extract_symbolic_data
arguments: data_tag: D4
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D60
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D61
data_type: string

tool: D63: r

tool: D47: heart.in

tool: D4: %d

tool: D1: %lf %lf

tool: D11: Point #%d: Let it rock!


tool: D60: 1

tool: D61: Point #%d: You give love a bad name.


assistant: ```c
int main() {
  FILE *fin = fopen("heart.in", "r");
  int times, t;
  fscanf(fin, "%d", &times);
  for (t = 1; t <= times; t++) {
    double x, y;
    fscanf(fin, "%lf %lf", &x, &y);
    double inequality = pow(x * x + y * y - 1, 3.) - x * x * y * y * y;
    if (inequality < 0) {
      printf("Point #%d: You give love a bad name.\n", t);
    } else {
      printf("Point #%d: Let it rock!\n", t);
    }
  }
  fclose(fin);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D58(%rip),%rsi
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  lea    0x4(%rsp),%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <fscanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L17
  mov    $0x1,%r15d
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  lea    D24(%rip),%rbx
  lea    D65(%rip),%r14
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %rbx,%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fscanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  mov    $0x3,%edi
  mulsd  %xmm1,%xmm1
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  subsd  D50(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  mov    %r15d,%esi
  movsd  0x10(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  comisd %xmm0,%xmm3
  ja     L42
  mov    %r14,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    %r15d,0x4(%rsp)
  jge    L49
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L42:
  lea    D69(%rip),%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    0x4(%rsp),%r15d
  jle    L49
  jmp    L17
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D58
datatype: string
name: unpack_data
arguments: label: D12
datatype: string
name: unpack_data
arguments: label: D19
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D65
datatype: string
name: unpack_data
arguments: label: D50
datatype: f64
name: unpack_data
arguments: label: D69
datatype: string

tool: D58: r

tool: D12: heart.in

tool: D19: %d

tool: D24: %lf %lf

tool: D65: Point #%d: Let it rock!


tool: D50: 1

tool: D69: Point #%d: You give love a bad name.


assistant: ```c
int main() {
  FILE *fin = fopen("heart.in", "r");
  int times, t;
  fscanf(fin, "%d", &times);
  for (t = 1; t <= times; t++) {
    double x, y;
    fscanf(fin, "%lf %lf", &x, &y);
    double inequality = pow(x * x + y * y - 1, 3.) - x * x * y * y * y;
    if (inequality < 0) {
      printf("Point #%d: You give love a bad name.\n", t);
    } else {
      printf("Point #%d: Let it rock!\n", t);
    }
  }
  fclose(fin);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shl_by_ptr_pp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <by_ptr_pp@plt>
  mov    $0x0,%eax
  call   <shl@plt>
  nop
  leave
  ret
```

assistant: ```c
void shl_by_ptr_pp(uint32_t x) {
  by_ptr_pp(x);
  shl();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shl_by_ptr_pp>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_pp@plt>
  mov    $0x0,%eax
  call   <shl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void shl_by_ptr_pp(uint32_t x) {
  by_ptr_pp(x);
  shl();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<shl_by_ptr_pp>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_pp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <shl@plt>
```

assistant: ```c
void shl_by_ptr_pp(uint32_t x) {
  by_ptr_pp(x);
  shl();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shl_by_ptr_pp>:
  endbr64
  sub    $0x8,%rsp
  call   <by_ptr_pp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <shl@plt>
```

assistant: ```c
void shl_by_ptr_pp(uint32_t x) {
  by_ptr_pp(x);
  shl();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <create_mat@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <BFS@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <DFS@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D0
type: string

tool: D12: Enter the size of matrix: 

tool: D0: %d

assistant: ```c
int main() {
  int size, i, j;
  printf("Enter the size of matrix: ");
  scanf("%d", &size);
  create_mat(size);
  BFS(size);
  DFS(size);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <create_mat@plt>
  mov    0x4(%rsp),%edi
  call   <BFS@plt>
  mov    0x4(%rsp),%edi
  call   <DFS@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D13: Enter the size of matrix: 

tool: D2: %d

assistant: ```c
int main() {
  int size, i, j;
  printf("Enter the size of matrix: ");
  scanf("%d", &size);
  create_mat(size);
  BFS(size);
  DFS(size);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <create_mat@plt>
  mov    0x4(%rsp),%edi
  call   <BFS@plt>
  mov    0x4(%rsp),%edi
  call   <DFS@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D2: Enter the size of matrix: 

tool: D3: %d

assistant: ```c
int main() {
  int size, i, j;
  printf("Enter the size of matrix: ");
  scanf("%d", &size);
  create_mat(size);
  BFS(size);
  DFS(size);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <create_mat@plt>
  mov    0x4(%rsp),%edi
  call   <BFS@plt>
  mov    0x4(%rsp),%edi
  call   <DFS@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D1: Enter the size of matrix: 

tool: D16: %d

assistant: ```c
int main() {
  int size, i, j;
  printf("Enter the size of matrix: ");
  scanf("%d", &size);
  create_mat(size);
  BFS(size);
  DFS(size);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlenz@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L4
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x0,-0xc(%rbp)
  jns    L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *s2;
  int n;
  n = ft_strlenz(s1) + 1;
  s2 = (char *)malloc(n);
  while (n >= 0) {
    s2[n] = s1[n];
    n--;
  }
  return (s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <ft_strlenz@plt>
  mov    %eax,%r12d
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  js     L10
  movslq %ebx,%rdx
  add    %rax,%rdx
  movslq %r12d,%rsi
  add    %rax,%rsi
  lea    0x1(%r12),%ecx
  sub    %rcx,%rsi
  sub    %rax,%rbp
L3:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L3
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *s2;
  int n;
  n = ft_strlenz(s1) + 1;
  s2 = (char *)malloc(n);
  while (n >= 0) {
    s2[n] = s1[n];
    n--;
  }
  return (s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <ft_strlenz@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  js     L12
  movslq %ebx,%rcx
  movslq %r12d,%rdx
  mov    %rbp,%rdi
  mov    %r12d,%r12d
  add    %rax,%rcx
  add    %rax,%rdx
  sub    %rax,%rdi
  sub    %r12,%rcx
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rdi,%rdx,1),%esi
  sub    $0x1,%rdx
  mov    %sil,0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L14
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *s2;
  int n;
  n = ft_strlenz(s1) + 1;
  s2 = (char *)malloc(n);
  while (n >= 0) {
    s2[n] = s1[n];
    n--;
  }
  return (s2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <ft_strlenz@plt>
  lea    0x1(%rax),%r12d
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %r12d,%r12d
  js     L9
  movslq %ebx,%rcx
  movslq %r12d,%rdx
  mov    %rbp,%rdi
  mov    %r12d,%r12d
  add    %rax,%rcx
  add    %rax,%rdx
  sub    %rax,%rdi
  sub    %r12,%rcx
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rdx,1),%esi
  sub    $0x1,%rdx
  mov    %sil,0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L5
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strdup(const char *s1) {
  char *s2;
  int n;
  n = ft_strlenz(s1) + 1;
  s2 = (char *)malloc(n);
  while (n >= 0) {
    s2[n] = s1[n];
    n--;
  }
  return (s2);
}
```