ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<a_Hp>:
  endbr64
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm2
  ja     L21
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  sub    $0x28,%rsp
  ucomisd %xmm2,%xmm0
  ja     L29
  movapd %xmm2,%xmm3
  sqrtsd %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L22:
  movsd  D30(%rip),%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x18(%rsp)
  divsd  D25(%rip),%xmm0
  call   <pow@plt>
  movsd  D58(%rip),%xmm1
  movsd  0x18(%rsp),%xmm2
  divsd  D16(%rip),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  D37(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  addsd  D1(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm0
  add    $0x28,%rsp
  divsd  %xmm1,%xmm0
  ret
L29:
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
type: byte[8]
name: retrieve_data
arguments: data_tag: D25
type: f64
name: retrieve_data
arguments: data_tag: D58
type: f64
name: retrieve_data
arguments: data_tag: D16
type: f64
name: retrieve_data
arguments: data_tag: D37
type: byte[8]
name: retrieve_data
arguments: data_tag: D1
type: f64

tool: {"D30": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0xbf]}

tool: D25: 1000

tool: D58: 0.7

tool: D16: 1000000

tool: {"D37": [0x36,0x43,0x8c,0x79,0xf9,0x16,0xd7,0x3d]}

tool: D1: 1

assistant: ```c
double a_Hp(t)
double t;
{
  if (t > 0.0) {
    return (8.40e-11 / sqrt(t)) * pow(t / 1e3, -0.2) / (1.0 + pow(t / 1e6, 0.7));
  }
  return 0.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_group_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getgrgid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L9
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    $0x80,%edx
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,D8(%rip)
  lea    D14(%rip),%rax
L9:
  leave
  ret
```

assistant: ```c
const char *get_group_name(gid_t gid) {
  static char name[128];
  struct group *grp;
  if ((grp = getgrgid(gid)) == NULL) {
    return NULL;
  }
  strncpy(name, grp->gr_name, 128);
  name[128 - 1] = '\0';
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_group_name>:
  endbr64
  push   %rbx
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L2
  mov    $0x80,%edx
  mov    (%rax),%esi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,D1(%rip)
  mov    %rbx,%rax
L2:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_group_name(gid_t gid) {
  static char name[128];
  struct group *grp;
  if ((grp = getgrgid(gid)) == NULL) {
    return NULL;
  }
  strncpy(name, grp->gr_name, 128);
  name[128 - 1] = '\0';
  return name;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_group_name>:
  endbr64
  push   %rbx
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L8
  lea    D6(%rip),%rbx
  mov    (%rax),%esi
  mov    $0x80,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,D18(%rip)
  mov    %rbx,%rax
L8:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_group_name(gid_t gid) {
  static char name[128];
  struct group *grp;
  if ((grp = getgrgid(gid)) == NULL) {
    return NULL;
  }
  strncpy(name, grp->gr_name, 128);
  name[128 - 1] = '\0';
  return name;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_group_name>:
  endbr64
  push   %rbx
  call   <getgrgid@plt>
  test   %rax,%rax
  je     L7
  lea    D8(%rip),%rbx
  mov    (%rax),%esi
  mov    $0x80,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,D9(%rip)
  mov    %rbx,%rax
L7:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_group_name(gid_t gid) {
  static char name[128];
  struct group *grp;
  if ((grp = getgrgid(gid)) == NULL) {
    return NULL;
  }
  strncpy(name, grp->gr_name, 128);
  name[128 - 1] = '\0';
  return name;
}
```
user: Translate the below assembly code into C programming language:

```asm
<growl_tcp_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void growl_tcp_close(int sock) {
  if (sock > 0)
    close(sock);
}
```
user: What is the c source code of the assembly code below:

```asm
<growl_tcp_close>:
  endbr64
  test   %edi,%edi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void growl_tcp_close(int sock) {
  if (sock > 0)
    close(sock);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<growl_tcp_close>:
  endbr64
  test   %edi,%edi
  jg     L3
  ret
  nopl   0x0(%rax)
L3:
  jmp    1050 <close@plt>
```

assistant: ```c
void growl_tcp_close(int sock) {
  if (sock > 0)
    close(sock);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<growl_tcp_close>:
  endbr64
  test   %edi,%edi
  jg     L2
  ret
  nopl   0x0(%rax)
L2:
  jmp    1050 <close@plt>
```

assistant: ```c
void growl_tcp_close(int sock) {
  if (sock > 0)
    close(sock);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decode_chunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  shl    $0x2,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  sar    $0x4,%eax
  or     %eax,%ebx
  mov    %ebx,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  shl    $0x4,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  or     %ebx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  shl    $0x6,%eax
  and    $0xffffffc0,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unmap@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  or     %ebx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L29
  mov    $0x2,%edx
  jmp    L44
L29:
  mov    $0x1,%edx
L44:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L15
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L15
  mov    $0x1,%eax
  jmp    L36
L15:
  mov    $0x0,%eax
L36:
  add    %edx,%eax
  cltq
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
size_t decode_chunk(const uint8_t in[4], uint8_t out[3]) {
  out[0] = (uint8_t)(((unmap(in[0]) << 2)) | unmap(in[1]) >> 4);
  out[1] = (uint8_t)(((unmap(in[1]) << 4) & 0xF0) | unmap(in[2]) >> 2);
  out[2] = (uint8_t)(((unmap(in[2]) << 6) & 0xC0) | unmap(in[3]));
  return 1 + (in[2] != '=') + ((in[2] != '=') && (in[3] != '='));
}
```
user: What is the c source code of the assembly code below?

```asm
<decode_chunk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  movsbl (%rdi),%edi
  call   <unmap@plt>
  mov    %eax,%ebp
  movsbl 0x1(%rbx),%edi
  call   <unmap@plt>
  shl    $0x2,%ebp
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,(%r12)
  movsbl 0x1(%rbx),%edi
  call   <unmap@plt>
  mov    %eax,%ebp
  movsbl 0x2(%rbx),%edi
  call   <unmap@plt>
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r12)
  movsbl 0x2(%rbx),%edi
  call   <unmap@plt>
  mov    %eax,%ebp
  movsbl 0x3(%rbx),%edi
  call   <unmap@plt>
  shl    $0x6,%ebp
  or     %eax,%ebp
  mov    %bpl,0x2(%r12)
  mov    $0x1,%edx
  mov    $0x0,%eax
  cmpb   $0x3d,0x2(%rbx)
  je     L0
  cmpb   $0x3d,0x3(%rbx)
  setne  %al
  movzbl %al,%eax
  mov    $0x2,%edx
L0:
  add    %edx,%eax
  cltq
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t decode_chunk(const uint8_t in[4], uint8_t out[3]) {
  out[0] = (uint8_t)(((unmap(in[0]) << 2)) | unmap(in[1]) >> 4);
  out[1] = (uint8_t)(((unmap(in[1]) << 4) & 0xF0) | unmap(in[2]) >> 2);
  out[2] = (uint8_t)(((unmap(in[2]) << 6) & 0xC0) | unmap(in[3]));
  return 1 + (in[2] != '=') + ((in[2] != '=') && (in[3] != '='));
}
```
user: Translate the below assembly code into C programming language:

```asm
<decode_chunk>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <unmap@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x2,%ebp
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,(%r12)
  movsbl 0x1(%rbx),%edi
  call   <unmap@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r12)
  movsbl 0x2(%rbx),%edi
  call   <unmap@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x6,%ebp
  or     %eax,%ebp
  mov    $0x1,%eax
  mov    %bpl,0x2(%r12)
  cmpb   $0x3d,0x2(%rbx)
  je     L2
  xor    %eax,%eax
  cmpb   $0x3d,0x3(%rbx)
  setne  %al
  add    $0x2,%rax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t decode_chunk(const uint8_t in[4], uint8_t out[3]) {
  out[0] = (uint8_t)(((unmap(in[0]) << 2)) | unmap(in[1]) >> 4);
  out[1] = (uint8_t)(((unmap(in[1]) << 4) & 0xF0) | unmap(in[2]) >> 2);
  out[2] = (uint8_t)(((unmap(in[2]) << 6) & 0xC0) | unmap(in[3]));
  return 1 + (in[2] != '=') + ((in[2] != '=') && (in[3] != '='));
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_chunk>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  call   <unmap@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x2,%ebp
  sar    $0x4,%eax
  or     %eax,%ebp
  mov    %bpl,(%r12)
  movsbl 0x1(%rbx),%edi
  call   <unmap@plt>
  movsbl 0x2(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x4,%ebp
  sar    $0x2,%eax
  or     %eax,%ebp
  mov    %bpl,0x1(%r12)
  movsbl 0x2(%rbx),%edi
  call   <unmap@plt>
  movsbl 0x3(%rbx),%edi
  mov    %eax,%ebp
  call   <unmap@plt>
  shl    $0x6,%ebp
  or     %eax,%ebp
  mov    $0x1,%eax
  mov    %bpl,0x2(%r12)
  cmpb   $0x3d,0x2(%rbx)
  je     L3
  xor    %eax,%eax
  cmpb   $0x3d,0x3(%rbx)
  setne  %al
  add    $0x2,%rax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t decode_chunk(const uint8_t in[4], uint8_t out[3]) {
  out[0] = (uint8_t)(((unmap(in[0]) << 2)) | unmap(in[1]) >> 4);
  out[1] = (uint8_t)(((unmap(in[1]) << 4) & 0xF0) | unmap(in[2]) >> 2);
  out[2] = (uint8_t)(((unmap(in[2]) << 6) & 0xC0) | unmap(in[3]));
  return 1 + (in[2] != '=') + ((in[2] != '=') && (in[3] != '='));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calcsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L11
L24:
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,-0x8(%rbp)
  subl   $0x2,-0x1c(%rbp)
L11:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L24
  cmpl   $0x1,-0x1c(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movsbq %al,%rax
  add    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short calcsum(unsigned short *buffer, int length) {
  unsigned long sum;
  for (sum = 0; length > 1; length -= 2)
    sum += *buffer++;
  if (length == 1)
    sum += (char)*buffer;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  return ~sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcsum>:
  endbr64
  cmp    $0x1,%esi
  jle    L33
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L0:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L0
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L26:
  cmp    $0x1,%esi
  je     L20
L21:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L33:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L26
L20:
  movsbq (%rcx),%rdx
  add    %rdx,%rax
  jmp    L21
```

assistant: ```c
unsigned short calcsum(unsigned short *buffer, int length) {
  unsigned long sum;
  for (sum = 0; length > 1; length -= 2)
    sum += *buffer++;
  if (length == 1)
    sum += (char)*buffer;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  return ~sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calcsum>:
  endbr64
  cmp    $0x1,%esi
  jle    L8
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L33:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L33
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L20:
  cmp    $0x1,%esi
  jne    L10
  movsbq (%rcx),%rdx
  add    %rdx,%rax
L10:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L8:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L20
```

assistant: ```c
unsigned short calcsum(unsigned short *buffer, int length) {
  unsigned long sum;
  for (sum = 0; length > 1; length -= 2)
    sum += *buffer++;
  if (length == 1)
    sum += (char)*buffer;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  return ~sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcsum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L30
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0xd,%r10d
  jbe    L85
  pxor   %xmm3,%xmm3
  pxor   %xmm4,%xmm4
  pxor   %xmm2,%xmm2
  mov    %rdi,%rax
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax,%rax,1)
L105:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  movdqa %xmm0,%xmm5
  punpcklwd %xmm4,%xmm1
  punpckhdq %xmm2,%xmm0
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpckhdq %xmm2,%xmm1
  punpckldq %xmm2,%xmm5
  paddq  %xmm5,%xmm1
  paddq  %xmm1,%xmm0
  paddq  %xmm0,%xmm3
  cmp    %rdi,%rax
  jne    L105
  mov    %ecx,%r8d
  movdqa %xmm3,%xmm0
  and    $0xfffffff8,%r8d
  psrldq $0x8,%xmm0
  mov    %r8d,%r11d
  paddq  %xmm0,%xmm3
  mov    %r8d,%edi
  neg    %r11d
  movq   %xmm3,%rax
  lea    (%rdx,%rdi,2),%rdi
  lea    (%rsi,%r11,2),%esi
  cmp    %ecx,%r8d
  je     L11
L60:
  movzwl (%rdi),%r8d
  add    %r8,%rax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L11
  movzwl 0x2(%rdi),%r8d
  add    %r8,%rax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L11
  movzwl 0x4(%rdi),%r8d
  add    %r8,%rax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L11
  movzwl 0x6(%rdi),%r8d
  add    %r8,%rax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L11
  movzwl 0x8(%rdi),%r8d
  add    %r8,%rax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L11
  movzwl 0xa(%rdi),%r8d
  add    %r8,%rax
  cmp    $0xd,%esi
  jle    L11
  movzwl 0xc(%rdi),%esi
  add    %rsi,%rax
L11:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r10,%rcx,2),%esi
L125:
  cmp    $0x1,%esi
  jne    L80
  movsbq (%rdx),%rdx
  add    %rdx,%rax
L80:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %eax,%eax
  jmp    L125
L85:
  xor    %eax,%eax
  jmp    L60
```

assistant: ```c
unsigned short calcsum(unsigned short *buffer, int length) {
  unsigned long sum;
  for (sum = 0; length > 1; length -= 2)
    sum += *buffer++;
  if (length == 1)
    sum += (char)*buffer;
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  return ~sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<func7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x320,(%rax)
  pop    %rbp
  ret
```

assistant: ```c
void func7(int *aptr) {
  if (1 == 0) {
    if (!aptr) {
      int k = 10;
      return;
    }
  }
  *aptr = 800;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func7>:
  endbr64
  movl   $0x320,(%rdi)
  ret
```

assistant: ```c
void func7(int *aptr) {
  if (1 == 0) {
    if (!aptr) {
      int k = 10;
      return;
    }
  }
  *aptr = 800;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<func7>:
  endbr64
  movl   $0x320,(%rdi)
  ret
```

assistant: ```c
void func7(int *aptr) {
  if (1 == 0) {
    if (!aptr) {
      int k = 10;
      return;
    }
  }
  *aptr = 800;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func7>:
  endbr64
  movl   $0x320,(%rdi)
  ret
```

assistant: ```c
void func7(int *aptr) {
  if (1 == 0) {
    if (!aptr) {
      int k = 10;
      return;
    }
  }
  *aptr = 800;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wordcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  jmp    L32
L20:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ebx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L21
  mov    -0x14(%rbp),%eax
  jmp    L38
L21:
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x30(%rbp)
L32:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
L38:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int wordcmp(const char *r, const char *s) {
  int res;
  while (*r) {
    if ((res = *r - tolower(*s)) != 0)
      return res;
    ++r;
    ++s;
  }
  return isalpha(*s);
}
```
user: What is the c source code of the assembly code below?

```asm
<wordcmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L13
L8:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  movsbl %bl,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  jne    L4
  add    $0x1,%r12
  add    $0x1,%rbp
  movzbl (%r12),%ebx
  test   %bl,%bl
  jne    L8
L13:
  movsbl 0x0(%rbp),%edi
  call   <isalpha@plt>
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int wordcmp(const char *r, const char *s) {
  int res;
  while (*r) {
    if ((res = *r - tolower(*s)) != 0)
      return res;
    ++r;
    ++s;
  }
  return isalpha(*s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wordcmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L5
  mov    %rdi,%r12
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L32:
  movzbl 0x1(%r12),%ebx
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %bl,%bl
  je     L5
L36:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl %al,%edx
  movsbl %bl,%eax
  sub    %edx,%eax
  je     L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  movsbl 0x0(%rbp),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <isalpha@plt>
```

assistant: ```c
int wordcmp(const char *r, const char *s) {
  int res;
  while (*r) {
    if ((res = *r - tolower(*s)) != 0)
      return res;
    ++r;
    ++s;
  }
  return isalpha(*s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wordcmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L25
  mov    %rdi,%r12
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl 0x1(%r12),%ebx
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %bl,%bl
  je     L25
L21:
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movsbl %al,%edx
  movsbl %bl,%eax
  sub    %edx,%eax
  je     L30
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  movsbl 0x0(%rbp),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <isalpha@plt>
```

assistant: ```c
int wordcmp(const char *r, const char *s) {
  int res;
  while (*r) {
    if ((res = *r - tolower(*s)) != 0)
      return res;
    ++r;
    ++s;
  }
  return isalpha(*s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ConvertBase10StrInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movsbl -0x15(%rbp),%eax
  sub    $0x30,%eax
  imul   -0x10(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  subl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L11
  cmpl   $0x0,-0x8(%rbp)
  je     L22
  negl   -0x14(%rbp)
L22:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t ConvertBase10StrInt(char *String, uint32_t Length) {
  bool Negated = String[0] == '-';
  int Start = Negated ? 1 : 0;
  int Value = 0;
  int Multiplier = 1;
  for (int ii = Length - 1; ii >= Start; --ii) {
    char cc = String[ii];
    Value += (cc - '0') * Multiplier;
    Multiplier *= 10;
  }
  if (Negated)
    Value = -Value;
  return Value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ConvertBase10StrInt>:
  endbr64
  movzbl (%rdi),%r8d
  cmp    $0x2d,%r8b
  sete   %al
  lea    -0x1(%rsi),%ecx
  movzbl %al,%edx
  cmp    %ecx,%edx
  jg     L29
  movslq %ecx,%rcx
  add    %rdi,%rcx
  movslq %esi,%rdx
  lea    -0x2(%rdi,%rdx,1),%rdi
  sub    $0x1,%esi
  movzbl %al,%eax
  sub    %eax,%esi
  sub    %rsi,%rdi
  mov    $0x1,%eax
  mov    $0x0,%esi
L25:
  movsbl (%rcx),%edx
  sub    $0x30,%edx
  imul   %eax,%edx
  add    %edx,%esi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L25
L18:
  mov    %esi,%eax
  neg    %eax
  cmp    $0x2d,%r8b
  cmove  %eax,%esi
  mov    %esi,%eax
  ret
L29:
  mov    $0x0,%esi
  jmp    L18
```

assistant: ```c
int32_t ConvertBase10StrInt(char *String, uint32_t Length) {
  bool Negated = String[0] == '-';
  int Start = Negated ? 1 : 0;
  int Value = 0;
  int Multiplier = 1;
  for (int ii = Length - 1; ii >= Start; --ii) {
    char cc = String[ii];
    Value += (cc - '0') * Multiplier;
    Multiplier *= 10;
  }
  if (Negated)
    Value = -Value;
  return Value;
}
```