ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<next_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L38
L63:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L38:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x2,%eax
  jle    L43
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L43
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L63
L43:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x2(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L74:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x1,%edx
  cmp    %edx,%eax
  jle    L22
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L22
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L74
L22:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int next_header(const char **data, int *len) {
  int header_len;
  while (*len > 2 && (*data)[0] != '\r' && (*data)[1] != '\n') {
    (*len)--;
    (*data)++;
  }
  *data += 2;
  *len -= 2;
  header_len = 0;
  while (*len > header_len + 1 && (*data)[header_len] != '\r' && (*data)[header_len + 1] != '\n')
    header_len++;
  return header_len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_header>:
  endbr64
  mov    (%rsi),%eax
  cmp    $0x2,%eax
  jle    L45
L35:
  mov    (%rdi),%rdx
  cmpb   $0xd,(%rdx)
  je     L45
  cmpb   $0xa,0x1(%rdx)
  je     L45
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  addq   $0x1,(%rdi)
  mov    (%rsi),%eax
  cmp    $0x2,%eax
  jg     L35
L45:
  addq   $0x2,(%rdi)
  mov    (%rsi),%eax
  lea    -0x2(%rax),%r8d
  mov    %r8d,(%rsi)
  mov    $0x1,%edx
  mov    $0x0,%eax
L54:
  mov    %eax,%esi
  cmp    %edx,%r8d
  jle    L29
  mov    (%rdi),%rcx
  cmpb   $0xd,(%rcx,%rax,1)
  je     L29
  movzbl (%rcx,%rdx,1),%ecx
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    $0xa,%cl
  jne    L54
L29:
  mov    %esi,%eax
  ret
```

assistant: ```c
int next_header(const char **data, int *len) {
  int header_len;
  while (*len > 2 && (*data)[0] != '\r' && (*data)[1] != '\n') {
    (*len)--;
    (*data)++;
  }
  *data += 2;
  *len -= 2;
  header_len = 0;
  while (*len > header_len + 1 && (*data)[header_len] != '\r' && (*data)[header_len + 1] != '\n')
    header_len++;
  return header_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<next_header>:
  endbr64
  mov    (%rsi),%edx
  mov    (%rdi),%rax
  cmp    $0x2,%edx
  jg     L62
  jmp    L53
L6:
  cmpb   $0xa,0x1(%rax)
  je     L53
  sub    $0x1,%edx
  add    $0x1,%rax
  mov    %edx,(%rsi)
  mov    %rax,(%rdi)
  cmp    $0x2,%edx
  je     L53
L62:
  cmpb   $0xd,(%rax)
  jne    L6
L53:
  add    $0x2,%rax
  sub    $0x2,%edx
  xor    %ecx,%ecx
  mov    %rax,(%rdi)
  mov    %edx,(%rsi)
  jmp    L87
  nopl   0x0(%rax)
L34:
  cmpb   $0xd,(%rax)
  je     L65
  add    $0x1,%rax
  cmpb   $0xa,(%rax)
  je     L65
L87:
  mov    %ecx,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edx
  jg     L34
L65:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int next_header(const char **data, int *len) {
  int header_len;
  while (*len > 2 && (*data)[0] != '\r' && (*data)[1] != '\n') {
    (*len)--;
    (*data)++;
  }
  *data += 2;
  *len -= 2;
  header_len = 0;
  while (*len > header_len + 1 && (*data)[header_len] != '\r' && (*data)[header_len + 1] != '\n')
    header_len++;
  return header_len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_header>:
  endbr64
  mov    (%rsi),%edx
  mov    (%rdi),%rax
  cmp    $0x2,%edx
  jg     L28
  jmp    L84
L48:
  cmpb   $0xa,0x1(%rax)
  je     L84
  sub    $0x1,%edx
  add    $0x1,%rax
  mov    %edx,(%rsi)
  mov    %rax,(%rdi)
  cmp    $0x2,%edx
  je     L84
L28:
  cmpb   $0xd,(%rax)
  jne    L48
L84:
  add    $0x2,%rax
  sub    $0x2,%edx
  xor    %ecx,%ecx
  mov    %rax,(%rdi)
  mov    %edx,(%rsi)
  jmp    L30
  nopl   0x0(%rax)
L18:
  cmpb   $0xd,(%rax)
  je     L4
  add    $0x1,%rax
  cmpb   $0xa,(%rax)
  je     L4
L30:
  mov    %ecx,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edx
  jg     L18
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int next_header(const char **data, int *len) {
  int header_len;
  while (*len > 2 && (*data)[0] != '\r' && (*data)[1] != '\n') {
    (*len)--;
    (*data)++;
  }
  *data += 2;
  *len -= 2;
  header_len = 0;
  while (*len > header_len + 1 && (*data)[header_len] != '\r' && (*data)[header_len + 1] != '\n')
    header_len++;
  return header_len;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strv_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L23
L7:
  addl   $0x1,-0x4(%rbp)
  addq   $0x8,-0x18(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L7
  mov    -0x4(%rbp),%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
unsigned strv_length(char **l) {
  unsigned n = 0;
  if (!l)
    return 0;
  for (; *l; l++)
    n++;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strv_length>:
  endbr64
  test   %rdi,%rdi
  je     L26
  cmpq   $0x0,(%rdi)
  je     L20
  mov    $0x0,%eax
L5:
  add    $0x1,%eax
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  jne    L5
  ret
L26:
  mov    $0x0,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned strv_length(char **l) {
  unsigned n = 0;
  if (!l)
    return 0;
  for (; *l; l++)
    n++;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strv_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L15
  cmpq   $0x0,(%rdi)
  je     L2
  nopl   0x0(%rax)
L10:
  add    $0x8,%rdi
  add    $0x1,%eax
  cmpq   $0x0,(%rdi)
  jne    L10
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
unsigned strv_length(char **l) {
  unsigned n = 0;
  if (!l)
    return 0;
  for (; *l; l++)
    n++;
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strv_length>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L22
  cmpq   $0x0,(%rdi)
  je     L23
  nopl   0x0(%rax)
L14:
  add    $0x8,%rdi
  add    $0x1,%eax
  cmpq   $0x0,(%rdi)
  jne    L14
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  ret
  nopl   0x0(%rax)
L23:
  ret
```

assistant: ```c
unsigned strv_length(char **l) {
  unsigned n = 0;
  if (!l)
    return 0;
  for (; *l; l++)
    n++;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memmove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  cmp    -0x20(%rbp),%rdx
  jbe    L39
  test   %rax,%rax
  je     L34
L32:
  sub    $0x1,%rax
  mov    -0x8(%rbp),%rcx
  lea    0x1(%rcx),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rsi
  mov    %rsi,-0x10(%rbp)
  movzbl (%rcx),%ecx
  mov    %cl,(%rdx)
  test   %rax,%rax
  jne    L32
L34:
  mov    -0x18(%rbp),%rax
  jmp    L14
L39:
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <memcpy@plt>
L14:
  leave
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, register size_t count) {
  char *dst8 = (char *)dst;
  char *src8 = (char *)src;
  if (dst > src) {
    if (count != 0) {
      do {
        count--;
        *dst8++ = *src8++;
      } while (count != 0);
    }
    return dst;
  }
  return memcpy(dst, src, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  cmp    %rsi,%rdi
  jbe    L8
  test   %rdx,%rdx
  je     L16
  mov    $0x0,%ecx
L27:
  movzbl (%rsi,%rcx,1),%edi
  mov    %dil,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L27
  ret
L8:
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
L16:
  ret
```

assistant: ```c
void *memmove(void *dst, const void *src, register size_t count) {
  char *dst8 = (char *)dst;
  char *src8 = (char *)src;
  if (dst > src) {
    if (count != 0) {
      do {
        count--;
        *dst8++ = *src8++;
      } while (count != 0);
    }
    return dst;
  }
  return memcpy(dst, src, count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memmove>:
  endbr64
  cmp    %rsi,%rdi
  jbe    L27
  test   %rdx,%rdx
  je     L2
  xor    %ecx,%ecx
L23:
  movzbl (%rsi,%rcx,1),%eax
  mov    %al,(%rdi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L23
L2:
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L27:
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void *memmove(void *dst, const void *src, register size_t count) {
  char *dst8 = (char *)dst;
  char *src8 = (char *)src;
  if (dst > src) {
    if (count != 0) {
      do {
        count--;
        *dst8++ = *src8++;
      } while (count != 0);
    }
    return dst;
  }
  return memcpy(dst, src, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%r8
  cmp    %rsi,%rdi
  jbe    L155
  test   %rdx,%rdx
  je     L94
  lea    0x1(%rsi),%rdi
  mov    %rax,%rcx
  lea    -0x1(%rdx),%rdx
  sub    %rdi,%rcx
  cmp    $0xe,%rcx
  jbe    L169
  cmp    $0x6,%rdx
  jbe    L169
  cmp    $0xe,%rdx
  jbe    L120
  mov    %r8,%rcx
  xor    %edx,%edx
  and    $0xfffffffffffffff0,%rcx
  nopl   0x0(%rax)
L63:
  movdqu (%rsi,%rdx,1),%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rcx
  jne    L63
  mov    %r8,%r9
  mov    %r8,%rdx
  and    $0xfffffffffffffff0,%r9
  and    $0xf,%edx
  lea    (%rax,%r9,1),%rcx
  lea    (%rsi,%r9,1),%rdi
  cmp    %r9,%r8
  je     L94
  lea    -0x1(%rdx),%r10
  mov    %rdx,%r8
  cmp    $0x6,%r10
  jbe    L137
L30:
  mov    (%rsi,%r9,1),%rsi
  mov    %rsi,(%rax,%r9,1)
  mov    %r8,%rsi
  and    $0xfffffffffffffff8,%rsi
  sub    %rsi,%rdx
  add    %rsi,%rcx
  add    %rsi,%rdi
  cmp    %rsi,%r8
  je     L94
  lea    -0x1(%rdx),%r10
L137:
  movzbl (%rdi),%esi
  mov    %sil,(%rcx)
  test   %r10,%r10
  je     L94
  movzbl 0x1(%rdi),%esi
  mov    %sil,0x1(%rcx)
  cmp    $0x2,%rdx
  je     L94
  movzbl 0x2(%rdi),%esi
  mov    %sil,0x2(%rcx)
  cmp    $0x3,%rdx
  je     L94
  movzbl 0x3(%rdi),%esi
  mov    %sil,0x3(%rcx)
  cmp    $0x4,%rdx
  je     L94
  movzbl 0x4(%rdi),%esi
  mov    %sil,0x4(%rcx)
  cmp    $0x5,%rdx
  je     L94
  movzbl 0x5(%rdi),%esi
  mov    %sil,0x5(%rcx)
  cmp    $0x6,%rdx
  je     L94
  movzbl 0x6(%rdi),%edx
  mov    %dl,0x6(%rcx)
  ret
  nop
L94:
  ret
  nopl   0x0(%rax)
L155:
  jmp    1050 <memcpy@plt>
  nopl   (%rax)
L169:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L42:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L42
  ret
L120:
  mov    %rsi,%rdi
  mov    %rax,%rcx
  mov    %r8,%rdx
  xor    %r9d,%r9d
  jmp    L30
```

assistant: ```c
void *memmove(void *dst, const void *src, register size_t count) {
  char *dst8 = (char *)dst;
  char *src8 = (char *)src;
  if (dst > src) {
    if (count != 0) {
      do {
        count--;
        *dst8++ = *src8++;
      } while (count != 0);
    }
    return dst;
  }
  return memcpy(dst, src, count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type_infered: string
name: unpack_data
arguments: tag: D7
type_infered: string

tool: D13: %d %d

tool: D7: %d


assistant: ```c
int main() {
  int n1, n2;
  scanf("%d %d", &n1, &n2);
  printf("%d\n", (n1 + n2));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string
name: read_data
arguments: label: D18
data_type: string

tool: D2: %d %d

tool: D18: %d


assistant: ```c
int main() {
  int n1, n2;
  scanf("%d %d", &n1, &n2);
  printf("%d\n", (n1 + n2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D17(%rip),%rdi
  add    (%rsp),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D17
datatype: string

tool: D18: %d %d

tool: D17: %d


assistant: ```c
int main() {
  int n1, n2;
  scanf("%d %d", &n1, &n2);
  printf("%d\n", (n1 + n2));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  add    (%rsp),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string

tool: D9: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int n1, n2;
  scanf("%d %d", &n1, &n2);
  printf("%d\n", (n1 + n2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<putpacket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x24,%edi
  call   <putDebugChar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L45
L77:
  movl   $0x0,-0x10(%rbp)
  jmp    L24
L53:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L59
  cmpl   $0x3,-0x10(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putDebugChar@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    $0x2a,%edi
  call   <putDebugChar@plt>
  addl   $0x2a,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1c,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putDebugChar@plt>
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L45
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putDebugChar@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L45
L59:
  addl   $0x1,-0x10(%rbp)
L24:
  cmpl   $0x63,-0x10(%rbp)
  jle    L53
L45:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    $0x23,%edi
  call   <putDebugChar@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <highhex@plt>
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putDebugChar@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <lowhex@plt>
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putDebugChar@plt>
  mov    $0x0,%eax
  call   <getDebugChar@plt>
  cmp    $0x2b,%al
  jne    L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void putpacket(char *buffer) {
  int checksum;
  int count;
  do {
    char *src = buffer;
    putDebugChar('$');
    checksum = 0;
    while (*src) {
      int runlen;
      for (runlen = 0; runlen < 100; runlen++) {
        if (src[0] != src[runlen]) {
          if (runlen > 3) {
            int encode;
            putDebugChar(*src);
            checksum += *src;
            putDebugChar('*');
            checksum += '*';
            checksum += (encode = runlen + ' ' - 4);
            putDebugChar(encode);
            src += runlen;
          } else {
            putDebugChar(*src);
            checksum += *src;
            src++;
          }
          break;
        }
      }
    }
    putDebugChar('#');
    putDebugChar(highhex(checksum));
    putDebugChar(lowhex(checksum));
  } while (getDebugChar() != '+');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putpacket>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  jmp    L48
L20:
  cmp    $0x3,%ebx
  jle    L15
  movsbl %dil,%edi
  call   <putDebugChar@plt>
  movsbl (%r12),%r12d
  add    %r13d,%r12d
  mov    $0x2a,%edi
  call   <putDebugChar@plt>
  lea    0x1c(%rbx),%edi
  lea    0x46(%rbx,%r12,1),%r13d
  movsbl %dil,%edi
  call   <putDebugChar@plt>
  mov    %rbp,%r12
L75:
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L34
L44:
  mov    %r12,%rax
  mov    $0x0,%ebx
L27:
  mov    %rax,%rbp
  cmp    %dil,(%rax)
  jne    L20
  add    $0x1,%ebx
  add    $0x1,%rax
  cmp    $0x64,%ebx
  jne    L27
  jmp    L44
L15:
  movsbl %dil,%edi
  call   <putDebugChar@plt>
  movsbl (%r12),%eax
  add    %eax,%r13d
  add    $0x1,%r12
  jmp    L75
L34:
  mov    $0x23,%edi
  call   <putDebugChar@plt>
  mov    %r13d,%edi
  call   <highhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  mov    %r13d,%edi
  call   <lowhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  mov    $0x0,%eax
  call   <getDebugChar@plt>
  cmp    $0x2b,%al
  je     L64
L48:
  mov    $0x24,%edi
  call   <putDebugChar@plt>
  mov    %r14,%r12
  mov    $0x0,%r13d
  jmp    L75
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void putpacket(char *buffer) {
  int checksum;
  int count;
  do {
    char *src = buffer;
    putDebugChar('$');
    checksum = 0;
    while (*src) {
      int runlen;
      for (runlen = 0; runlen < 100; runlen++) {
        if (src[0] != src[runlen]) {
          if (runlen > 3) {
            int encode;
            putDebugChar(*src);
            checksum += *src;
            putDebugChar('*');
            checksum += '*';
            checksum += (encode = runlen + ' ' - 4);
            putDebugChar(encode);
            src += runlen;
          } else {
            putDebugChar(*src);
            checksum += *src;
            src++;
          }
          break;
        }
      }
    }
    putDebugChar('#');
    putDebugChar(highhex(checksum));
    putDebugChar(lowhex(checksum));
  } while (getDebugChar() != '+');
}
```
user: What is the c source code of the assembly code below:

```asm
<putpacket>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
L79:
  mov    $0x24,%edi
  mov    %rbx,%r12
  xor    %ebp,%ebp
  call   <putDebugChar@plt>
  xchg   %ax,%ax
L55:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L11
L7:
  mov    %edi,%edx
  xor    %eax,%eax
  jmp    L62
L0:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L7
  movzbl (%r12,%rax,1),%edx
L62:
  mov    %eax,%r13d
  cmp    %dil,%dl
  je     L0
  cmp    $0x3,%eax
  jle    L57
  movslq %eax,%r14
  call   <putDebugChar@plt>
  movsbl (%r12),%eax
  mov    $0x2a,%edi
  add    %r12,%r14
  mov    %r14,%r12
  add    %eax,%ebp
  call   <putDebugChar@plt>
  lea    0x1c(%r13),%edi
  lea    0x46(%rbp,%r13,1),%ebp
  call   <putDebugChar@plt>
  movsbl (%r12),%edi
  test   %dil,%dil
  jne    L7
L11:
  mov    $0x23,%edi
  call   <putDebugChar@plt>
  mov    %ebp,%edi
  call   <highhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  mov    %ebp,%edi
  call   <lowhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  xor    %eax,%eax
  call   <getDebugChar@plt>
  cmp    $0x2b,%al
  jne    L79
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  call   <putDebugChar@plt>
  movsbl (%r12),%eax
  add    $0x1,%r12
  add    %eax,%ebp
  jmp    L55
```

assistant: ```c
void putpacket(char *buffer) {
  int checksum;
  int count;
  do {
    char *src = buffer;
    putDebugChar('$');
    checksum = 0;
    while (*src) {
      int runlen;
      for (runlen = 0; runlen < 100; runlen++) {
        if (src[0] != src[runlen]) {
          if (runlen > 3) {
            int encode;
            putDebugChar(*src);
            checksum += *src;
            putDebugChar('*');
            checksum += '*';
            checksum += (encode = runlen + ' ' - 4);
            putDebugChar(encode);
            src += runlen;
          } else {
            putDebugChar(*src);
            checksum += *src;
            src++;
          }
          break;
        }
      }
    }
    putDebugChar('#');
    putDebugChar(highhex(checksum));
    putDebugChar(lowhex(checksum));
  } while (getDebugChar() != '+');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<putpacket>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
L2:
  mov    $0x24,%edi
  call   <putDebugChar@plt>
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L84
  mov    %r13,%r14
  xor    %r12d,%r12d
  nopl   (%rax)
L53:
  mov    %r14,%rbp
  xor    %ebx,%ebx
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L28:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    $0x64,%ebx
  je     L53
L66:
  cmp    %dil,0x0(%rbp)
  je     L28
  cmp    $0x3,%ebx
  jle    L59
  call   <putDebugChar@plt>
  movsbl (%r14),%eax
  mov    $0x2a,%edi
  add    %eax,%r12d
  call   <putDebugChar@plt>
  lea    0x1c(%rbx),%edi
  lea    0x46(%rbx,%r12,1),%r12d
  call   <putDebugChar@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L20
  mov    %rbp,%r14
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L59:
  call   <putDebugChar@plt>
  movsbl (%r14),%eax
  movsbl 0x1(%r14),%edi
  add    %eax,%r12d
  lea    0x1(%r14),%rax
  test   %dil,%dil
  je     L20
  mov    %rax,%r14
  jmp    L53
L84:
  xor    %r12d,%r12d
L20:
  mov    $0x23,%edi
  call   <putDebugChar@plt>
  mov    %r12d,%edi
  call   <highhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  mov    %r12d,%edi
  call   <lowhex@plt>
  movsbl %al,%edi
  call   <putDebugChar@plt>
  xor    %eax,%eax
  call   <getDebugChar@plt>
  cmp    $0x2b,%al
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void putpacket(char *buffer) {
  int checksum;
  int count;
  do {
    char *src = buffer;
    putDebugChar('$');
    checksum = 0;
    while (*src) {
      int runlen;
      for (runlen = 0; runlen < 100; runlen++) {
        if (src[0] != src[runlen]) {
          if (runlen > 3) {
            int encode;
            putDebugChar(*src);
            checksum += *src;
            putDebugChar('*');
            checksum += '*';
            checksum += (encode = runlen + ' ' - 4);
            putDebugChar(encode);
            src += runlen;
          } else {
            putDebugChar(*src);
            checksum += *src;
            src++;
          }
          break;
        }
      }
    }
    putDebugChar('#');
    putDebugChar(highhex(checksum));
    putDebugChar(lowhex(checksum));
  } while (getDebugChar() != '+');
}
```