ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<doTest>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <dirReduc@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  call   <joinStringsStringArray@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
L0:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: Expected:
%s
Got:
%s


assistant: ```c
void doTest(char **arr, int sz, char *expr) {
  int lg = -1;
  char **act = dirReduc(arr, sz, &lg);
  char *sact = joinStringsStringArray(act, lg);
  if (strcmp(sact, expr) != 0)
    printf("Expected:\n%s\nGot:\n%s\n", expr, sact);
  assert(strcmp(sact, expr) == 0);
  act = NULL;
  free(sact);
  sact = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<doTest>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  movl   $0xffffffff,0x4(%rsp)
  call   <dirReduc@plt>
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  call   <joinStringsStringArray@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L27
L17:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: Expected:
%s
Got:
%s


assistant: ```c
void doTest(char **arr, int sz, char *expr) {
  int lg = -1;
  char **act = dirReduc(arr, sz, &lg);
  char *sact = joinStringsStringArray(act, lg);
  if (strcmp(sact, expr) != 0)
    printf("Expected:\n%s\nGot:\n%s\n", expr, sact);
  assert(strcmp(sact, expr) == 0);
  act = NULL;
  free(sact);
  sact = NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
L9:
  jmp    L9
```

assistant: ```c
void _exit(int status) {
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_exit>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
void _exit(int status) {
  while (1) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
void _exit(int status) {
  while (1) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void _exit(int status) {
  while (1) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wcodematd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swt_max@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swt_min@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L16:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x18(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm3
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x48(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L16
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void wcodematd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength, double minv, double maxv) {
  int count;
  double sigMin, sigMax;
  swt_max(sigIn, sigInLength, &sigMax);
  swt_min(sigIn, sigInLength, &sigMin);
  for (count = 0; count < sigInLength; count++)
    sigOut[count] = ((sigIn[count] - sigMin) / (sigMax - sigMin)) * (maxv - minv) + minv;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcodematd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  movsd  %xmm0,0x8(%rsp)
  movq   %xmm1,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  call   <swt_max@plt>
  lea    0x18(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <swt_min@plt>
  test   %r12d,%r12d
  jle    L8
  movsd  0x18(%rsp),%xmm3
  movsd  0x20(%rsp),%xmm2
  subsd  %xmm3,%xmm2
  mov    %r12d,%edx
  mov    $0x0,%eax
  movq   %r13,%xmm1
  subsd  0x8(%rsp),%xmm1
L17:
  movsd  (%rbx,%rax,8),%xmm0
  subsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wcodematd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength, double minv, double maxv) {
  int count;
  double sigMin, sigMax;
  swt_max(sigIn, sigInLength, &sigMax);
  swt_min(sigIn, sigInLength, &sigMin);
  for (count = 0; count < sigInLength; count++)
    sigOut[count] = ((sigIn[count] - sigMin) / (sigMax - sigMin)) * (maxv - minv) + minv;
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wcodematd>:
  endbr64
  push   %r14
  movq   %xmm1,%r14
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x20(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <swt_max@plt>
  lea    0x18(%rsp),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <swt_min@plt>
  test   %ebx,%ebx
  jle    L0
  movsd  0x18(%rsp),%xmm4
  movq   %r14,%xmm1
  movslq %ebx,%rsi
  xor    %eax,%eax
  movsd  0x20(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm0
  subsd  %xmm4,%xmm3
  subsd  %xmm0,%xmm1
  nopw   0x0(%rax,%rax,1)
L11:
  movsd  0x0(%rbp,%rax,8),%xmm2
  subsd  %xmm4,%xmm2
  divsd  %xmm3,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%r12,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L11
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wcodematd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength, double minv, double maxv) {
  int count;
  double sigMin, sigMax;
  swt_max(sigIn, sigInLength, &sigMax);
  swt_min(sigIn, sigInLength, &sigMin);
  for (count = 0; count < sigInLength; count++)
    sigOut[count] = ((sigIn[count] - sigMin) / (sigMax - sigMin)) * (maxv - minv) + minv;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<wcodematd>:
  endbr64
  push   %r14
  movq   %xmm1,%r14
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x20(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <swt_max@plt>
  lea    0x18(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swt_min@plt>
  test   %r12d,%r12d
  jle    L28
  movsd  0x18(%rsp),%xmm5
  movsd  0x20(%rsp),%xmm4
  movq   %r14,%xmm2
  lea    0x8(%rbp),%rax
  movsd  0x8(%rsp),%xmm3
  subsd  %xmm5,%xmm4
  subsd  %xmm3,%xmm2
  cmp    %rax,%rbx
  je     L24
  cmp    $0x1,%r12d
  je     L24
  mov    %r12d,%edx
  movapd %xmm5,%xmm8
  movapd %xmm4,%xmm7
  xor    %eax,%eax
  movapd %xmm2,%xmm6
  movapd %xmm3,%xmm1
  shr    %edx
  unpcklpd %xmm8,%xmm8
  unpcklpd %xmm7,%xmm7
  unpcklpd %xmm6,%xmm6
  unpcklpd %xmm1,%xmm1
  shl    $0x4,%rdx
  nopl   0x0(%rax,%rax,1)
L60:
  movupd 0x0(%rbp,%rax,1),%xmm0
  subpd  %xmm8,%xmm0
  divpd  %xmm7,%xmm0
  mulpd  %xmm6,%xmm0
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L60
  mov    %r12d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r12d
  je     L28
  movsd  0x0(%rbp,%rax,8),%xmm1
  subsd  %xmm5,%xmm1
  divsd  %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L37:
  movsd  0x0(%rbp,%rax,8),%xmm0
  subsd  %xmm5,%xmm0
  divsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L37
  jmp    L28
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wcodematd(double *sigIn, int sigInLength, double *sigOut, int sigOutLength, double minv, double maxv) {
  int count;
  double sigMin, sigMax;
  swt_max(sigIn, sigInLength, &sigMax);
  swt_min(sigIn, sigInLength, &sigMin);
  for (count = 0; count < sigInLength; count++)
    sigOut[count] = ((sigIn[count] - sigMin) / (sigMax - sigMin)) * (maxv - minv) + minv;
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_imatrix(int **m, int nrl, int nrh, int ncl, int nch) {
  int i;
  for (i = nrl; i <= nrh; ++i) {
    free((void *)(m[i] + ncl));
  }
  free((void *)(m + nrl));
}
```
user: What is the c source code of the assembly code below:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r14d
  cmp    %edx,%esi
  jg     L11
  mov    %edx,%r13d
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rbp
  movslq %esi,%rbx
L0:
  mov    %rbp,%rdi
  add    (%r12,%rbx,8),%rdi
  call   <free@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L0
L11:
  movslq %r14d,%r14
  lea    (%r12,%r14,8),%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void free_imatrix(int **m, int nrl, int nrh, int ncl, int nch) {
  int i;
  for (i = nrl; i <= nrh; ++i) {
    free((void *)(m[i] + ncl));
  }
  free((void *)(m + nrl));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  cmp    %edx,%esi
  jg     L11
  movslq %ecx,%rcx
  movslq %esi,%r14
  mov    %edx,%r13d
  lea    0x0(,%rcx,4),%rbp
  mov    %r14,%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  add    %rbp,%rdi
  call   <free@plt>
  cmp    %ebx,%r13d
  jge    L10
L11:
  pop    %rbx
  lea    (%r12,%r14,8),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(int **m, int nrl, int nrh, int ncl, int nch) {
  int i;
  for (i = nrl; i <= nrh; ++i) {
    free((void *)(m[i] + ncl));
  }
  free((void *)(m + nrl));
}
```
user: What is the c source code of the assembly code below:

```asm
<free_imatrix>:
  endbr64
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  cmp    %edx,%esi
  jg     L3
  movslq %ecx,%rcx
  movslq %esi,%r14
  mov    %edx,%r13d
  lea    0x0(,%rcx,4),%rbp
  mov    %r14,%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  add    %rbp,%rdi
  call   <free@plt>
  cmp    %ebx,%r13d
  jge    L14
L3:
  pop    %rbx
  lea    (%r12,%r14,8),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(int **m, int nrl, int nrh, int ncl, int nch) {
  int i;
  for (i = nrl; i <= nrh; ++i) {
    free((void *)(m[i] + ncl));
  }
  free((void *)(m + nrl));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usb_lld_prepare_shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <st103_set_istr@plt>
  mov    $0x0,%edi
  call   <st103_set_cntr@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usb_lld_prepare_shutdown(void) {
  st103_set_istr(0);
  st103_set_cntr(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usb_lld_prepare_shutdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <st103_set_istr@plt>
  mov    $0x0,%edi
  call   <st103_set_cntr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usb_lld_prepare_shutdown(void) {
  st103_set_istr(0);
  st103_set_cntr(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usb_lld_prepare_shutdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <st103_set_istr@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <st103_set_cntr@plt>
```

assistant: ```c
void usb_lld_prepare_shutdown(void) {
  st103_set_istr(0);
  st103_set_cntr(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usb_lld_prepare_shutdown>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <st103_set_istr@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <st103_set_cntr@plt>
```

assistant: ```c
void usb_lld_prepare_shutdown(void) {
  st103_set_istr(0);
  st103_set_cntr(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  test   %esi,%esi
  jle    L84
  lea    -0x1(%rsi),%ecx
  mov    $0xf,%eax
  mov    %esi,%r12d
  mov    %rdi,%rbp
  mov    %ecx,0xc(%rsp)
  and    $0xf,%ecx
  xor    %ebx,%ebx
  lea    D9(%rip),%r15
  sub    %ecx,%eax
  mov    %ecx,0x1c(%rsp)
  lea    D1(%rip),%r13
  mov    %eax,0x18(%rsp)
  jmp    L146
  nopl   0x0(%rax)
L103:
  test   $0xf,%bl
  je     L3
L13:
  movzbl 0x0(%rbp),%esi
  xor    %eax,%eax
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  je     L51
L32:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  je     L84
L146:
  test   %ebx,%ebx
  jne    L103
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
  nopl   0x0(%rax)
L84:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L3:
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  lea    -0x10(%rbp),%r14
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L46:
  movzbl (%r14),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  jbe    L53
  mov    $0x2e,%edi
L53:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %r14,%rbp
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
  nop
L51:
  mov    0x18(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  je     L149
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    0x18(%rsp),%r14d
  jne    L2
L149:
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  sub    0x1c(%rsp),%edx
  movslq %edx,%r14
  nopl   0x0(%rax)
L4:
  mov    0x10(%rsp),%rax
  movzbl (%rax,%r14,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  jbe    L137
  mov    $0x2e,%edi
L137:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L32
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D9:  %02x

tool: D1:    

tool: D16:          

assistant: ```c
void print_data(unsigned char *data, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    if ((i != 0) && (i % 16 == 0)) {
      printf("         ");
      for (j = i - 16; j < i; j++) {
        if (data[j] >= 32 && data[j] <= 128)
          printf("%c", (unsigned char)data[j]);
        else
          printf(".");
      }
      printf("\n");
    }
    if (i % 16 == 0)
      printf("   ");
    printf(" %02x", (unsigned int)data[i]);
    if (i == size - 1) {
      for (j = 0; j < 15 - i % 16; j++)
        printf("   ");
      printf("         ");
      for (j = i - i % 16; j <= i; j++) {
        if (data[j] >= 32 && data[j] <= 128)
          printf("%c", (unsigned char)data[j]);
        else
          printf(".");
      }
      printf("\n");
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  test   %esi,%esi
  jle    L46
  lea    -0x1(%rsi),%ecx
  mov    $0xf,%eax
  mov    %esi,%r12d
  mov    %rdi,%rbp
  mov    %ecx,0xc(%rsp)
  and    $0xf,%ecx
  xor    %ebx,%ebx
  lea    D31(%rip),%r15
  sub    %ecx,%eax
  mov    %ecx,0x1c(%rsp)
  lea    D28(%rip),%r13
  mov    %eax,0x18(%rsp)
  jmp    L91
  nopl   0x0(%rax)
L36:
  test   $0xf,%bl
  je     L22
L86:
  movzbl 0x0(%rbp),%esi
  xor    %eax,%eax
  mov    %r15,%rdi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  je     L50
L134:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r12d
  je     L46
L91:
  test   %ebx,%ebx
  jne    L36
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L86
  nopl   0x0(%rax)
L46:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L22:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  lea    -0x10(%rbp),%r14
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L126:
  movzbl (%r14),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  jbe    L148
  mov    $0x2e,%edi
L148:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %r14,%rbp
  jne    L126
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L86
  nop
L50:
  mov    0x18(%rsp),%eax
  xor    %r14d,%r14d
  test   %eax,%eax
  je     L57
  nopl   0x0(%rax,%rax,1)
L103:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    0x18(%rsp),%r14d
  jne    L103
L57:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  sub    0x1c(%rsp),%edx
  movslq %edx,%r14
  nopl   0x0(%rax)
L84:
  mov    0x10(%rsp),%rax
  movzbl (%rax,%r14,1),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x60,%al
  jbe    L141
  mov    $0x2e,%edi
L141:
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %r14d,%ebx
  jge    L84
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L134
```

tool_calls: name: read_data
arguments: label: D31
datatype: string
name: read_data
arguments: label: D28
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D31:  %02x

tool: D28:    

tool: D5:          

assistant: ```c
void print_data(unsigned char *data, int size) {
  int i, j;
  for (i = 0; i < size; i++) {
    if ((i != 0) && (i % 16 == 0)) {
      printf("         ");
      for (j = i - 16; j < i; j++) {
        if (data[j] >= 32 && data[j] <= 128)
          printf("%c", (unsigned char)data[j]);
        else
          printf(".");
      }
      printf("\n");
    }
    if (i % 16 == 0)
      printf("   ");
    printf(" %02x", (unsigned int)data[i]);
    if (i == size - 1) {
      for (j = 0; j < 15 - i % 16; j++)
        printf("   ");
      printf("         ");
      for (j = i - i % 16; j <= i; j++) {
        if (data[j] >= 32 && data[j] <= 128)
          printf("%c", (unsigned char)data[j]);
        else
          printf(".");
      }
      printf("\n");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gc_align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    $0x0,%edx
  divl   -0x4(%rbp)
  imul   -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int gc_align(unsigned int n) {
  unsigned int cell = 1 << 3;
  return ((n + cell - 1) / cell) * cell;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gc_align>:
  endbr64
  lea    0x7(%rdi),%eax
  and    $0xfffffff8,%eax
  ret
```

assistant: ```c
unsigned int gc_align(unsigned int n) {
  unsigned int cell = 1 << 3;
  return ((n + cell - 1) / cell) * cell;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gc_align>:
  endbr64
  lea    0x7(%rdi),%eax
  and    $0xfffffff8,%eax
  ret
```

assistant: ```c
unsigned int gc_align(unsigned int n) {
  unsigned int cell = 1 << 3;
  return ((n + cell - 1) / cell) * cell;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gc_align>:
  endbr64
  lea    0x7(%rdi),%eax
  and    $0xfffffff8,%eax
  ret
```

assistant: ```c
unsigned int gc_align(unsigned int n) {
  unsigned int cell = 1 << 3;
  return ((n + cell - 1) / cell) * cell;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_integral_promotion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1ff,-0x4(%rbp)
  jbe    L11
  cmpl   $0xb00,-0x4(%rbp)
  jbe    L15
L11:
  cmpl   $0x1600,-0x4(%rbp)
  je     L15
  cmpl   $0x1b00,-0x4(%rbp)
  jne    L39
L15:
  mov    -0x4(%rbp),%eax
  and    $0xffff0e00,%eax
  cmp    $0x5ff,%eax
  ja     L39
  movl   $0x600,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int do_integral_promotion(unsigned int type) {
  if (((((type) >= 0x0200) && ((type) <= 0x0b00)) || ((type) == 0x1600) || ((type) == 0x1b00)) && (((type) & ~0xF1FF) < ((0x0600) & ~0xF1FF))) {
    type = 0x0600;
  }
  return type;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_integral_promotion>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1600,%edi
  sete   %dl
  cmp    $0x1b00,%edi
  sete   %cl
  or     %cl,%dl
  jne    L10
  lea    -0x200(%rdi),%edx
  cmp    $0x900,%edx
  ja     L12
L10:
  mov    %eax,%edx
  and    $0xffff0e00,%edx
  cmp    $0x5ff,%edx
  mov    $0x600,%edx
  cmovbe %edx,%eax
L12:
  ret
```

assistant: ```c
unsigned int do_integral_promotion(unsigned int type) {
  if (((((type) >= 0x0200) && ((type) <= 0x0b00)) || ((type) == 0x1600) || ((type) == 0x1b00)) && (((type) & ~0xF1FF) < ((0x0600) & ~0xF1FF))) {
    type = 0x0600;
  }
  return type;
}
```