ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_highslot>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_store@plt>
  mov    $0x309,%edi
  call   <exists@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x309,%edi
  call   <get@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  mov    $0x3e7,%esi
  mov    $0x309,%edi
  call   <set@plt>
  mov    $0x309,%edi
  call   <exists@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x309,%edi
  call   <get@plt>
  xor    %edi,%edi
  cmp    $0x3e7,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <destroy_store@plt>
```

assistant: ```c
void test_highslot() {
  init_store();
  assert(!exists(777));
  assert(get(777) == 0);
  set(777, 999, -1, 0);
  assert(exists(777));
  assert(get(777) == 999);
  destroy_store();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_highslot>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_store@plt>
  mov    $0x309,%edi
  call   <exists@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x309,%edi
  call   <get@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  mov    $0x3e7,%esi
  mov    $0x309,%edi
  call   <set@plt>
  mov    $0x309,%edi
  call   <exists@plt>
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x309,%edi
  call   <get@plt>
  xor    %edi,%edi
  cmp    $0x3e7,%eax
  sete   %dil
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <destroy_store@plt>
```

assistant: ```c
void test_highslot() {
  init_store();
  assert(!exists(777));
  assert(get(777) == 0);
  set(777, 999, -1, 0);
  assert(exists(777));
  assert(get(777) == 999);
  destroy_store();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  test   %eax,%eax
  jne    L5
  cmpl   $0x6,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i, n;
  i = 5;
  n = 0;
  do
    n++;
  while (i--);
  assert(n == 6);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i, n;
  i = 5;
  n = 0;
  do
    n++;
  while (i--);
  assert(n == 6);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i, n;
  i = 5;
  n = 0;
  do
    n++;
  while (i--);
  assert(n == 6);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i, n;
  i = 5;
  n = 0;
  do
    n++;
  while (i--);
  assert(n == 6);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string

tool: D0: mem: %p


assistant: ```c
int main(void) {
  void *mem = malloc(1000);
  printf("mem: %p\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: mem: %p


assistant: ```c
int main(void) {
  void *mem = malloc(1000);
  printf("mem: %p\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string

tool: D4: mem: %p


assistant: ```c
int main(void) {
  void *mem = malloc(1000);
  printf("mem: %p\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edi
  call   <malloc@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: mem: %p


assistant: ```c
int main(void) {
  void *mem = malloc(1000);
  printf("mem: %p\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L31
  mov    D7(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L31
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L31:
  cmpl   $0x0,-0x4(%rbp)
  jle    L37
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy(int src_fd, int dest_fd, char *buf, size_t buf_len) {
  int n = read(src_fd, buf, buf_len);
  if (n == -1 && errno == EAGAIN) {
    n = 0;
  } else if (n > 0) {
    n = write(dest_fd, buf, n);
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %rcx,%rdx
  mov    %rbx,%rsi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L26
  test   %eax,%eax
  jle    L21
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    D3(%rip),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L21
```

assistant: ```c
int copy(int src_fd, int dest_fd, char *buf, size_t buf_len) {
  int n = read(src_fd, buf, buf_len);
  if (n == -1 && errno == EAGAIN) {
    n = 0;
  } else if (n > 0) {
    n = write(dest_fd, buf, n);
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  mov    %rcx,%rdx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L6
  test   %eax,%eax
  jle    L4
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1060 <write@plt>
  nopl   0x0(%rax)
L6:
  mov    D4(%rip),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
L4:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int copy(int src_fd, int dest_fd, char *buf, size_t buf_len) {
  int n = read(src_fd, buf, buf_len);
  if (n == -1 && errno == EAGAIN) {
    n = 0;
  } else if (n > 0) {
    n = write(dest_fd, buf, n);
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copy>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  mov    %rcx,%rdx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <read@plt>
  cmp    $0xffffffff,%eax
  je     L13
  test   %eax,%eax
  jle    L7
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  pop    %rbp
  pop    %r12
  jmp    1060 <write@plt>
  nopl   0x0(%rax)
L13:
  mov    D0(%rip),%rdx
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  setne  %al
  movzbl %al,%eax
  neg    %eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int copy(int src_fd, int dest_fd, char *buf, size_t buf_len) {
  int n = read(src_fd, buf, buf_len);
  if (n == -1 && errno == EAGAIN) {
    n = 0;
  } else if (n > 0) {
    n = write(dest_fd, buf, n);
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pn_environ_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  movl   $0x0,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L8
L16:
  addl   $0x1,-0x28(%rbp)
  addq   $0x8,-0x20(%rbp)
L8:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <pn_calloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L5
L37:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <pn_strdup@plt>
  mov    %rax,(%rbx)
  addq   $0x8,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L37
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **pn_environ_copy(char **environ) {
  char **env;
  int num_keys = 0;
  for (env = environ; *env; ++env) {
    num_keys++;
  }
  char **result = pn_calloc(num_keys + 1, sizeof(char *));
  int i = 0;
  for (env = environ; *env; ++env, ++i) {
    result[i] = pn_strdup(*env);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pn_environ_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmpq   $0x0,(%rdi)
  je     L43
  mov    %rdi,%rax
  mov    $0x0,%edi
L48:
  add    $0x1,%edi
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L48
L14:
  add    $0x1,%edi
  mov    $0x8,%esi
  call   <pn_calloc@plt>
  mov    %rax,%r12
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L1
  mov    %rax,%rbp
L33:
  call   <pn_strdup@plt>
  mov    %rax,0x0(%rbp)
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  add    $0x8,%rbp
  test   %rdi,%rdi
  jne    L33
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    $0x0,%edi
  jmp    L14
```

assistant: ```c
char **pn_environ_copy(char **environ) {
  char **env;
  int num_keys = 0;
  for (env = environ; *env; ++env) {
    num_keys++;
  }
  char **result = pn_calloc(num_keys + 1, sizeof(char *));
  int i = 0;
  for (env = environ; *env; ++env, ++i) {
    result[i] = pn_strdup(*env);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pn_environ_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L20
  mov    %rdi,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x8,%rdx
  mov    %eax,%edi
  add    $0x1,%eax
  cmpq   $0x0,(%rdx)
  jne    L18
  add    $0x2,%edi
L19:
  mov    $0x8,%esi
  call   <pn_calloc@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %rdi,%rdi
  je     L44
  nopw   0x0(%rax,%rax,1)
L40:
  call   <pn_strdup@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    %rax,-0x8(%rbp)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L40
L44:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x1,%edi
  jmp    L19
```

assistant: ```c
char **pn_environ_copy(char **environ) {
  char **env;
  int num_keys = 0;
  for (env = environ; *env; ++env) {
    num_keys++;
  }
  char **result = pn_calloc(num_keys + 1, sizeof(char *));
  int i = 0;
  for (env = environ; *env; ++env, ++i) {
    result[i] = pn_strdup(*env);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pn_environ_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpq   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L20
  mov    %rdi,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x8,%rdx
  mov    %eax,%edi
  add    $0x1,%eax
  cmpq   $0x0,(%rdx)
  jne    L6
  add    $0x2,%edi
L3:
  mov    $0x8,%esi
  call   <pn_calloc@plt>
  mov    (%rbx),%rdi
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %rdi,%rdi
  je     L30
  nopw   0x0(%rax,%rax,1)
L14:
  call   <pn_strdup@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    %rax,-0x8(%rbp)
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L14
L30:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x1,%edi
  jmp    L3
```

assistant: ```c
char **pn_environ_copy(char **environ) {
  char **env;
  int num_keys = 0;
  for (env = environ; *env; ++env) {
    num_keys++;
  }
  char **result = pn_calloc(num_keys + 1, sizeof(char *));
  int i = 0;
  for (env = environ; *env; ++env, ++i) {
    result[i] = pn_strdup(*env);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  D11(%rip),%xmm0
  mov    D47(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  movsd  D11(%rip),%xmm0
  mov    D47(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x30(%rbp)
  movsd  D11(%rip),%xmm0
  mov    D47(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x38(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x30(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x38(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <DSENSITIVITY@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: f64
name: extract_symbolic_data
arguments: label: D47
type: f64

tool: D11: 2

tool: D47: 1

assistant: ```c
int main(void) {
  double x0, x1, x2, p0, p1, p2, sum;
  x0 = DBETWEEN(1.0, 2.0);
  x1 = DBETWEEN(1.0, 2.0);
  x2 = DBETWEEN(1.0, 2.0);
  p0 = (x0 + x1) - x2;
  p1 = (x1 + x2) - x0;
  p2 = (x2 + x0) - x1;
  sum = (p0 + p1) + p2;
  DSENSITIVITY(sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    D7(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movsd  %xmm0,(%rsp)
  mov    D7(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    D7(%rip),%rax
  movq   %rax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm3
  movapd %xmm3,%xmm4
  movsd  0x8(%rsp),%xmm5
  addsd  %xmm5,%xmm4
  movapd %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  movapd %xmm5,%xmm2
  addsd  %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  addsd  %xmm3,%xmm1
  subsd  %xmm5,%xmm1
  addsd  %xmm1,%xmm0
  call   <DSENSITIVITY@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: f64
name: parse_data
arguments: label: D36
type_guessed: f64

tool: D7: 2

tool: D36: 1

assistant: ```c
int main(void) {
  double x0, x1, x2, p0, p1, p2, sum;
  x0 = DBETWEEN(1.0, 2.0);
  x1 = DBETWEEN(1.0, 2.0);
  x2 = DBETWEEN(1.0, 2.0);
  p0 = (x0 + x1) - x2;
  p1 = (x1 + x2) - x0;
  p2 = (x2 + x0) - x1;
  sum = (p0 + p1) + p2;
  DSENSITIVITY(sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movsd  D15(%rip),%xmm4
  movsd  D20(%rip),%xmm1
  movapd %xmm4,%xmm0
  call   <DBETWEEN@plt>
  mov    D20(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  movq   %rax,%xmm1
  mov    D15(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  mov    D20(%rip),%rax
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm1
  mov    D15(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm4
  subsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm4
  addsd  %xmm1,%xmm2
  addsd  %xmm4,%xmm0
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  call   <DSENSITIVITY@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: f64
name: extract_symbolic_data
arguments: label: D20
data_type: f64

tool: D15: 1

tool: D20: 2

assistant: ```c
int main(void) {
  double x0, x1, x2, p0, p1, p2, sum;
  x0 = DBETWEEN(1.0, 2.0);
  x1 = DBETWEEN(1.0, 2.0);
  x2 = DBETWEEN(1.0, 2.0);
  p0 = (x0 + x1) - x2;
  p1 = (x1 + x2) - x0;
  p2 = (x2 + x0) - x1;
  sum = (p0 + p1) + p2;
  DSENSITIVITY(sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movsd  D27(%rip),%xmm4
  movsd  D7(%rip),%xmm1
  movapd %xmm4,%xmm0
  call   <DBETWEEN@plt>
  mov    D7(%rip),%rax
  movsd  %xmm0,0x8(%rsp)
  movq   %rax,%xmm1
  mov    D27(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  mov    D7(%rip),%rax
  movsd  %xmm0,(%rsp)
  movq   %rax,%xmm1
  mov    D27(%rip),%rax
  movq   %rax,%xmm0
  call   <DBETWEEN@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm3
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm4
  subsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm4
  addsd  %xmm1,%xmm2
  addsd  %xmm4,%xmm0
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  call   <DSENSITIVITY@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
data_type: f64
name: extract_symbolic_data
arguments: data_label: D7
data_type: f64

tool: D27: 1

tool: D7: 2

assistant: ```c
int main(void) {
  double x0, x1, x2, p0, p1, p2, sum;
  x0 = DBETWEEN(1.0, 2.0);
  x1 = DBETWEEN(1.0, 2.0);
  x2 = DBETWEEN(1.0, 2.0);
  p0 = (x0 + x1) - x2;
  p1 = (x1 + x2) - x0;
  p2 = (x2 + x0) - x1;
  sum = (p0 + p1) + p2;
  DSENSITIVITY(sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L23
L19:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  xor    %rax,-0x10(%rbp)
L8:
  addq   $0x1,-0x18(%rbp)
L23:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x10(%rbp),%rcx
  movabs $0x446f86562d9faee5,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x6,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long get_hash(const char *s) {
  const char *ss = s;
  unsigned long h = 0, g;
  for (; *ss != 0; ss++) {
    h = (h << 4) + *ss;
    if ((g = h & 0xf0000000)) {
      h ^= g >> 24;
      h ^= g;
    }
  }
  return (h % 101);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L45
  mov    $0x0,%ecx
  movabs $0xffffffff0fffffff,%rdx
  jmp    L49
L20:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
L49:
  shl    $0x4,%rcx
  movsbq %al,%rax
  add    %rax,%rcx
  mov    %rcx,%rax
  and    $0xf0000000,%eax
  je     L20
  and    %rdx,%rcx
  shr    $0x18,%rax
  xor    %rax,%rcx
  jmp    L20
L45:
  mov    $0x0,%ecx
L12:
  movabs $0x446f86562d9faee5,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x6,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
unsigned long get_hash(const char *s) {
  const char *ss = s;
  unsigned long h = 0, g;
  for (; *ss != 0; ss++) {
    h = (h << 4) + *ss;
    if ((g = h & 0xf0000000)) {
      h ^= g >> 24;
      h ^= g;
    }
  }
  return (h % 101);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_hash>:
  endbr64
  movsbq (%rdi),%rax
  test   %al,%al
  je     L26
  movabs $0xffffffff0fffffff,%rdx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L19:
  shl    $0x4,%rcx
  add    %rax,%rcx
  mov    %rcx,%rax
  and    $0xf0000000,%eax
  je     L1
  and    %rdx,%rcx
  shr    $0x18,%rax
  xor    %rax,%rcx
L1:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  test   %al,%al
  jne    L19
  movabs $0x446f86562d9faee5,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x6,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long get_hash(const char *s) {
  const char *ss = s;
  unsigned long h = 0, g;
  for (; *ss != 0; ss++) {
    h = (h << 4) + *ss;
    if ((g = h & 0xf0000000)) {
      h ^= g >> 24;
      h ^= g;
    }
  }
  return (h % 101);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_hash>:
  endbr64
  movsbq (%rdi),%rax
  test   %al,%al
  je     L29
  movabs $0xffffffff0fffffff,%rdx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L1:
  shl    $0x4,%rcx
  add    %rax,%rcx
  mov    %rcx,%rax
  and    $0xf0000000,%eax
  je     L25
  and    %rdx,%rcx
  shr    $0x18,%rax
  xor    %rax,%rcx
L25:
  movsbq 0x1(%rdi),%rax
  add    $0x1,%rdi
  test   %al,%al
  jne    L1
  movabs $0x446f86562d9faee5,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x6,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,4),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long get_hash(const char *s) {
  const char *ss = s;
  unsigned long h = 0, g;
  for (; *ss != 0; ss++) {
    h = (h << 4) + *ss;
    if ((g = h & 0xf0000000)) {
      h ^= g >> 24;
      h ^= g;
    }
  }
  return (h % 101);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isPhredOffset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x21,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x27,-0x4(%rbp)
  jg     L22
  cmpl   $0x0,-0x4(%rbp)
  jle    L22
  addl   $0x1,-0x8(%rbp)
L22:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int isPhredOffset(char *src, int n) {
  int i, okay, s;
  okay = 0;
  for (i = 0; i < n; i++) {
    s = src[i] - 33;
    if (s < 40 && s > 0) {
      okay++;
    }
  }
  return okay == n;
}
```