ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<WDL_remove_fileext>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L79
  mov    %rdi,%rax
L59:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L59
  cmp    %rax,%rdi
  ja     L25
L69:
  movzbl (%rax),%edx
  cmp    $0x5c,%dl
  je     L48
  cmp    $0x2f,%dl
  je     L48
  cmp    $0x2e,%dl
  je     L67
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L69
  mov    $0x0,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
L67:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  ret
L79:
  mov    %rdi,%rax
  jmp    L69
L48:
  mov    $0x0,%eax
  ret
```

assistant: ```c
__attribute__((unused)) char *WDL_remove_fileext(char *str) {
  char *p = str;
  while (*p)
    p++;
  while (p >= str && !((*p) == '\\' || (*p) == '/')) {
    if (*p == '.') {
      *p = 0;
      return p + 1;
    }
    --p;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<WDL_remove_fileext>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L21
  nopl   0x0(%rax)
L68:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L68
L21:
  xor    %edx,%edx
  jmp    L31
  nopl   (%rax)
L42:
  movzbl (%rax),%edx
L31:
  cmp    $0x5c,%dl
  je     L36
  cmp    $0x2f,%dl
  je     L36
  cmp    $0x2e,%dl
  je     L28
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L42
L36:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L28:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  ret
```

assistant: ```c
__attribute__((unused)) char *WDL_remove_fileext(char *str) {
  char *p = str;
  while (*p)
    p++;
  while (p >= str && !((*p) == '\\' || (*p) == '/')) {
    if (*p == '.') {
      *p = 0;
      return p + 1;
    }
    --p;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<WDL_remove_fileext>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L52
  nopl   0x0(%rax)
L32:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L32
  nopl   0x0(%rax)
L52:
  movzbl (%rax),%edx
  cmp    $0x5c,%dl
  je     L23
  cmp    $0x2f,%dl
  je     L23
  cmp    $0x2e,%dl
  je     L37
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L52
L23:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L37:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  ret
```

assistant: ```c
__attribute__((unused)) char *WDL_remove_fileext(char *str) {
  char *p = str;
  while (*p)
    p++;
  while (p >= str && !((*p) == '\\' || (*p) == '/')) {
    if (*p == '.') {
      *p = 0;
      return p + 1;
    }
    --p;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L50:
  subl   $0x1,-0x8(%rbp)
L108:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L67
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L50
L67:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L13
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  jmp    L13
L87:
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L98
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L87
L98:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L26
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L39
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L15
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L108
  nop
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  int i = low, j = high;
  int temp = a[low];
  while (i < j) {
    while (i < j && temp < a[j])
      j--;
    if (i < j) {
      a[i] = a[j];
      i++;
    }
    while (i < j && temp > a[i])
      i++;
    if (i < j) {
      a[j] = a[i];
      j--;
    }
    a[i] = temp;
    if (low < i)
      quick_sort(a, low, i - 1);
    if (i < high)
      quick_sort(a, j + 1, high);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<quick_sort>:
  endbr64
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rax
  cmp    %edx,%esi
  jge    L42
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%r15d
  mov    (%rax),%r12d
  mov    %edx,%ebx
  mov    %esi,%ebp
  jmp    L115
L148:
  cmp    %ebx,%ebp
  jge    L2
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rdx
  mov    (%rdx),%ecx
  movslq %ebp,%rax
  mov    %ecx,0x0(%r13,%rax,4)
  add    $0x1,%ebp
  cmp    %ebx,%ebp
  jge    L2
  movslq %ebp,%rax
L74:
  mov    %eax,%ebp
  cmp    %r12d,0x0(%r13,%rax,4)
  jge    L141
  lea    0x1(%rax),%ebp
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L74
  jmp    L2
L141:
  cmp    %ebx,%eax
  jge    L2
  cltq
  mov    0x0(%r13,%rax,4),%eax
  mov    %eax,(%rdx)
  sub    $0x1,%ebx
L2:
  movslq %ebp,%rax
  mov    %r12d,0x0(%r13,%rax,4)
  cmp    %ebp,%r14d
  jl     L24
L11:
  cmp    %ebp,%r15d
  jg     L134
L136:
  cmp    %ebp,%ebx
  jle    L138
L115:
  cmp    %ebx,%ebp
  jge    L2
  movslq %ebx,%rax
  lea    0x0(%r13,%rax,4),%rax
L149:
  cmp    %r12d,(%rax)
  jle    L148
  sub    $0x1,%ebx
  sub    $0x4,%rax
  cmp    %ebp,%ebx
  jne    L149
  mov    %ebp,%ebx
  jmp    L2
L24:
  lea    -0x1(%rbp),%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <quick_sort>
  jmp    L11
L134:
  lea    0x1(%rbx),%esi
  mov    %r15d,%edx
  mov    %r13,%rdi
  call   <quick_sort>
  jmp    L136
L138:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  ret
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  int i = low, j = high;
  int temp = a[low];
  while (i < j) {
    while (i < j && temp < a[j])
      j--;
    if (i < j) {
      a[i] = a[j];
      i++;
    }
    while (i < j && temp > a[i])
      i++;
    if (i < j) {
      a[j] = a[i];
      j--;
    }
    a[i] = temp;
    if (low < i)
      quick_sort(a, low, i - 1);
    if (i < high)
      quick_sort(a, j + 1, high);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<quick_sort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %rax,%r15
  lea    (%rdi,%rax,4),%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%r15d
  jge    L53
  mov    (%rax),%r12d
  mov    %rdi,%r14
  mov    %edx,%r13d
  mov    %edx,%ebp
  mov    %r15d,%ebx
L21:
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L23:
  cmp    %r12d,(%rax)
  jle    L68
  sub    $0x1,%ebp
  sub    $0x4,%rax
  cmp    %ebx,%ebp
  jg     L23
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rcx
L87:
  mov    %r12d,(%rcx)
  cmp    %ebx,%r15d
  jl     L11
L82:
  lea    0x1(%rbp),%esi
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <quick_sort>
L145:
  cmp    %ebx,%ebp
  jg     L21
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  lea    -0x1(%rbx),%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <quick_sort>
  cmp    %ebx,%r13d
  jle    L145
  jmp    L82
  nopl   (%rax)
L68:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rsi
  cmp    %ebp,%ebx
  jge    L33
  movslq %ebp,%rdx
  add    $0x1,%ebx
  lea    (%r14,%rdx,4),%rcx
  mov    (%rcx),%edx
  mov    %edx,(%rsi)
  cmp    %ebp,%ebx
  jge    L106
  lea    0x4(%r14,%rax,1),%rax
  jmp    L88
L73:
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %ebp,%ebx
  je     L87
L88:
  mov    (%rax),%edx
  cmp    %r12d,%edx
  jl     L73
  mov    %edx,(%rcx)
  sub    $0x1,%ebp
  mov    %rax,%rcx
  jmp    L87
L33:
  mov    %rsi,%rcx
  jmp    L87
L106:
  lea    0x4(%r14,%rax,1),%rcx
  jmp    L87
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  int i = low, j = high;
  int temp = a[low];
  while (i < j) {
    while (i < j && temp < a[j])
      j--;
    if (i < j) {
      a[i] = a[j];
      i++;
    }
    while (i < j && temp > a[i])
      i++;
    if (i < j) {
      a[j] = a[i];
      j--;
    }
    a[i] = temp;
    if (low < i)
      quick_sort(a, low, i - 1);
    if (i < high)
      quick_sort(a, j + 1, high);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<quick_sort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  mov    %rax,%r15
  lea    (%rdi,%rax,4),%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%r15d
  jge    L104
  mov    (%rax),%r12d
  mov    %rdi,%r14
  mov    %edx,%r13d
  mov    %edx,%ebp
  mov    %r15d,%ebx
L21:
  movslq %ebp,%rax
  lea    (%r14,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L103:
  cmp    %r12d,(%rax)
  jle    L117
  sub    $0x1,%ebp
  sub    $0x4,%rax
  cmp    %ebx,%ebp
  jg     L103
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rcx
L137:
  mov    %r12d,(%rcx)
  cmp    %ebx,%r15d
  jl     L102
L41:
  lea    0x1(%rbp),%esi
  mov    %r13d,%edx
  mov    %r14,%rdi
  call   <quick_sort>
L135:
  cmp    %ebx,%ebp
  jg     L21
L104:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L102:
  lea    -0x1(%rbx),%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <quick_sort>
  cmp    %ebx,%r13d
  jle    L135
  jmp    L41
  nopl   (%rax)
L117:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rsi
  cmp    %ebp,%ebx
  jge    L61
  movslq %ebp,%rdx
  add    $0x1,%ebx
  lea    (%r14,%rdx,4),%rcx
  mov    (%rcx),%edx
  mov    %edx,(%rsi)
  cmp    %ebp,%ebx
  jge    L88
  lea    0x4(%r14,%rax,1),%rax
  jmp    L37
L14:
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %ebp,%ebx
  je     L137
L37:
  mov    (%rax),%edx
  cmp    %r12d,%edx
  jl     L14
  mov    %edx,(%rcx)
  sub    $0x1,%ebp
  mov    %rax,%rcx
  jmp    L137
L61:
  mov    %rsi,%rcx
  jmp    L137
L88:
  lea    0x4(%r14,%rax,1),%rcx
  jmp    L137
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  int i = low, j = high;
  int temp = a[low];
  while (i < j) {
    while (i < j && temp < a[j])
      j--;
    if (i < j) {
      a[i] = a[j];
      i++;
    }
    while (i < j && temp > a[i])
      i++;
    if (i < j) {
      a[j] = a[i];
      j--;
    }
    a[i] = temp;
    if (low < i)
      quick_sort(a, low, i - 1);
    if (i < high)
      quick_sort(a, j + 1, high);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pwmss_tbclk_disable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_pwmss_ehrpwm_tbclk_status_get@plt>
  test   %rax,%rax
  jne    L55
  mov    $0x1,%eax
  jmp    L97
L55:
  cmpl   $0x2,-0x4(%rbp)
  je     L4
  cmpl   $0x2,-0x4(%rbp)
  ja     L58
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  cmpl   $0x1,-0x4(%rbp)
  je     L62
  jmp    L58
L24:
  mov    $0x44e10664,%eax
  mov    (%rax),%eax
  mov    $0x44e10664,%edx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  jmp    L52
L62:
  mov    $0x44e10664,%eax
  mov    (%rax),%eax
  mov    $0x44e10664,%edx
  and    $0xfffffffd,%eax
  mov    %eax,(%rdx)
  jmp    L52
L4:
  mov    $0x44e10664,%eax
  mov    (%rax),%eax
  mov    $0x44e10664,%edx
  and    $0xfffffffb,%eax
  mov    %eax,(%rdx)
  jmp    L52
L58:
  mov    $0xffffffff,%eax
  jmp    L97
L52:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <_pwmss_ehrpwm_tbclk_status_set@plt>
  mov    $0x0,%eax
L97:
  leave
  ret
```

assistant: ```c
int pwmss_tbclk_disable(unsigned int device_id) {
  if (_pwmss_ehrpwm_tbclk_status_get(device_id) == 0) {
    return 1;
  }
  switch (device_id) {
  case 0:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFEu);
    break;
  case 1:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFDu);
    break;
  case 2:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFBu);
    break;
  default:
    return -1;
  }
  _pwmss_ehrpwm_tbclk_status_set(device_id, 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pwmss_tbclk_disable>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <_pwmss_ehrpwm_tbclk_status_get@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L48
  cmp    $0x1,%ebx
  je     L54
  cmp    $0x2,%ebx
  je     L52
  mov    $0xffffffff,%eax
  test   %ebx,%ebx
  jne    L48
  mov    0x44e10664,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x44e10664
L32:
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <_pwmss_ehrpwm_tbclk_status_set@plt>
  mov    $0x0,%eax
L48:
  pop    %rbx
  ret
L54:
  mov    0x44e10664,%eax
  and    $0xfffffffd,%eax
  mov    %eax,0x44e10664
  jmp    L32
L52:
  mov    0x44e10664,%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x44e10664
  jmp    L32
```

assistant: ```c
int pwmss_tbclk_disable(unsigned int device_id) {
  if (_pwmss_ehrpwm_tbclk_status_get(device_id) == 0) {
    return 1;
  }
  switch (device_id) {
  case 0:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFEu);
    break;
  case 1:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFDu);
    break;
  case 2:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFBu);
    break;
  default:
    return -1;
  }
  _pwmss_ehrpwm_tbclk_status_set(device_id, 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pwmss_tbclk_disable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <_pwmss_ehrpwm_tbclk_status_get@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L11
  cmp    $0x1,%ebp
  je     L29
  cmp    $0x2,%ebp
  je     L45
  mov    $0xffffffff,%eax
  test   %ebp,%ebp
  je     L10
L11:
  pop    %rbp
  ret
  xchg   %ax,%ax
L10:
  mov    0x44e10664,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x44e10664
L30:
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <_pwmss_ehrpwm_tbclk_status_set@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L45:
  mov    0x44e10664,%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x44e10664
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x44e10664,%eax
  and    $0xfffffffd,%eax
  mov    %eax,0x44e10664
  jmp    L30
```

assistant: ```c
int pwmss_tbclk_disable(unsigned int device_id) {
  if (_pwmss_ehrpwm_tbclk_status_get(device_id) == 0) {
    return 1;
  }
  switch (device_id) {
  case 0:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFEu);
    break;
  case 1:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFDu);
    break;
  case 2:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFBu);
    break;
  default:
    return -1;
  }
  _pwmss_ehrpwm_tbclk_status_set(device_id, 0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pwmss_tbclk_disable>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <_pwmss_ehrpwm_tbclk_status_get@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L9
  cmp    $0x1,%ebp
  je     L7
  cmp    $0x2,%ebp
  je     L28
  mov    $0xffffffff,%eax
  test   %ebp,%ebp
  je     L56
L9:
  pop    %rbp
  ret
  xchg   %ax,%ax
L56:
  mov    0x44e10664,%eax
  and    $0xfffffffe,%eax
  mov    %eax,0x44e10664
L38:
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <_pwmss_ehrpwm_tbclk_status_set@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L28:
  mov    0x44e10664,%eax
  and    $0xfffffffb,%eax
  mov    %eax,0x44e10664
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x44e10664,%eax
  and    $0xfffffffd,%eax
  mov    %eax,0x44e10664
  jmp    L38
```

assistant: ```c
int pwmss_tbclk_disable(unsigned int device_id) {
  if (_pwmss_ehrpwm_tbclk_status_get(device_id) == 0) {
    return 1;
  }
  switch (device_id) {
  case 0:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFEu);
    break;
  case 1:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFDu);
    break;
  case 2:
    (*((volatile unsigned int *)((0x44E10000) + (0x664)))) &= (0xFFFFFFFBu);
    break;
  default:
    return -1;
  }
  _pwmss_ehrpwm_tbclk_status_set(device_id, 0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  jne    L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L1:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L5:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print_permute>
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rdx
  lea    -0x1(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x8(%rbp)
L12:
  cmpq   $0x0,-0x8(%rbp)
  jns    L5
  nop
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %s


assistant: ```c
void print_permute(char str[], long long int len) {
  char temp;
  long long int i, j, k;
  if (len == 1) {
    printf("%s\n", str);
    return;
  }
  for (i = len - 1; i >= 0; i--) {
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
    print_permute(str, len - 1);
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_permute>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  cmp    $0x1,%rsi
  je     L0
  mov    %rsi,%r14
  sub    $0x1,%r14
  js     L6
  lea    (%rdi,%r14,1),%rbx
  lea    -0x1(%rdi,%rsi,1),%rbp
L4:
  movzbl 0x0(%rbp),%eax
  mov    %rbx,%r13
  movzbl (%rbx),%edx
  mov    %dl,0x0(%rbp)
  mov    %al,(%rbx)
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <print_permute>
  movzbl 0x0(%rbp),%eax
  movzbl (%rbx),%edx
  mov    %dl,0x0(%rbp)
  mov    %al,(%rbx)
  sub    $0x1,%rbx
  cmp    %r12,%r13
  jne    L4
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: %s


assistant: ```c
void print_permute(char str[], long long int len) {
  char temp;
  long long int i, j, k;
  if (len == 1) {
    printf("%s\n", str);
    return;
  }
  for (i = len - 1; i >= 0; i--) {
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
    print_permute(str, len - 1);
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_permute>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%rsi
  je     L19
  lea    -0x1(%rsi),%r12
  lea    (%rdi,%r12,1),%rbp
  mov    %rbp,%rbx
  test   %r12,%r12
  js     L16
L12:
  movzbl (%rbx),%edx
  movzbl 0x0(%rbp),%eax
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %rbx,%r14
  sub    $0x1,%rbx
  mov    %dl,0x0(%rbp)
  mov    %al,0x1(%rbx)
  call   <print_permute>
  movzbl 0x1(%rbx),%edx
  movzbl 0x0(%rbp),%eax
  mov    %dl,0x0(%rbp)
  mov    %al,0x1(%rbx)
  cmp    %r13,%r14
  jne    L12
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  pop    %rbx
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s


assistant: ```c
void print_permute(char str[], long long int len) {
  char temp;
  long long int i, j, k;
  if (len == 1) {
    printf("%s\n", str);
    return;
  }
  for (i = len - 1; i >= 0; i--) {
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
    print_permute(str, len - 1);
    temp = str[len - 1];
    str[len - 1] = str[i];
    str[i] = temp;
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L46
  movss  -0x18(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L15
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L56
L15:
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L56
L46:
  movss  -0x14(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L62
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L56
L62:
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
L56:
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movss  -0x18(%rbp),%xmm3
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm3,%xmm4
  movq   %xmm4,%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: string

tool: D27: Enter three numbers: 

tool: D1: %f %f %f

tool: D29: Greatest of %.2f, %.2f and %.2f = %.2f


assistant: ```c
int main() {
  float num1, num2, num3, greatest;
  printf("Enter three numbers: ");
  scanf("%f %f %f", &num1, &num2, &num3);
  num1 > num2 ? (num1 > num3 ? (greatest = num1) : (greatest = num3)) : (num2 > num3 ? (greatest = num2) : (greatest = num3));
  printf("Greatest of %.2f, %.2f and %.2f = %.2f\n", num1, num2, num3, greatest);
}
```