ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%edx
  mov    %edx,%eax
  mulb   (%rdi)
  lea    0x75(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] *= state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 634099461UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  lea    0x75(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] *= state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 634099461UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  lea    0x75(,%rax,4),%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    if (state[0UL] & (unsigned char)1) {
      if (state[0UL] & (unsigned char)1) {
        if (state[0UL] & (unsigned char)1) {
          state[0UL] += state[0UL];
          state[0UL] += state[0UL];
        } else {
          state[0UL] *= state[0UL];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] += state[0UL];
        state[0UL] *= state[0UL];
      }
    } else {
      state[0UL] += state[0UL];
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] + 634099461UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<perr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <vmsg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void perr(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg(1, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<perr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <vmsg@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void perr(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg(1, fmt, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<perr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void perr(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg(1, fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<perr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void perr(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vmsg(1, fmt, ap);
  va_end(ap);
}
```
user: Translate the below assembly code into C programming language:

```asm
<compute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <get_h@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <apply_hhards@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  mov    $0x0,%eax
  call   <update_mur@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <apply_ehards@plt>
  mov    $0x0,%eax
  call   <apply_pmc@plt>
  nop
  leave
  ret
```

assistant: ```c
void compute(int time_index) {
  get_h();
  apply_hhards(time_index);
  get_e();
  update_mur();
  apply_ehards(time_index);
  apply_pmc();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <get_h@plt>
  mov    %ebx,%edi
  call   <apply_hhards@plt>
  mov    $0x0,%eax
  call   <get_e@plt>
  mov    $0x0,%eax
  call   <update_mur@plt>
  mov    %ebx,%edi
  call   <apply_ehards@plt>
  mov    $0x0,%eax
  call   <apply_pmc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void compute(int time_index) {
  get_h();
  apply_hhards(time_index);
  get_e();
  update_mur();
  apply_ehards(time_index);
  apply_pmc();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compute>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <get_h@plt>
  mov    %ebp,%edi
  call   <apply_hhards@plt>
  xor    %eax,%eax
  call   <get_e@plt>
  xor    %eax,%eax
  call   <update_mur@plt>
  mov    %ebp,%edi
  call   <apply_ehards@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10e0 <apply_pmc@plt>
```

assistant: ```c
void compute(int time_index) {
  get_h();
  apply_hhards(time_index);
  get_e();
  update_mur();
  apply_ehards(time_index);
  apply_pmc();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <get_h@plt>
  mov    %ebp,%edi
  call   <apply_hhards@plt>
  xor    %eax,%eax
  call   <get_e@plt>
  xor    %eax,%eax
  call   <update_mur@plt>
  mov    %ebp,%edi
  call   <apply_ehards@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10e0 <apply_pmc@plt>
```

assistant: ```c
void compute(int time_index) {
  get_h();
  apply_hhards(time_index);
  get_e();
  update_mur();
  apply_ehards(time_index);
  apply_pmc();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Problem021>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  jmp    L37
L2:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sum_proper_divisors@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sum_proper_divisors@plt>
  cmp    %eax,-0x8(%rbp)
  jne    L16
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L16
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  add    %eax,-0xc(%rbp)
L16:
  addl   $0x1,-0x8(%rbp)
L37:
  cmpl   $0x270f,-0x8(%rbp)
  jle    L2
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %30d

assistant: ```c
int Problem021(void) {
  int sum = 0, a, b;
  for (a = 2; a < 10000; a++) {
    b = sum_proper_divisors(a);
    if (sum_proper_divisors(b) == a && a < b) {
      sum += a + b;
    }
  }
  printf("%30d", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Problem021>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x2,%ebp
  mov    $0x0,%r12d
  jmp    L32
L8:
  add    $0x1,%ebp
  cmp    $0x2710,%ebp
  je     L31
L32:
  mov    %ebp,%edi
  call   <sum_proper_divisors@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <sum_proper_divisors@plt>
  cmp    %ebp,%ebx
  jle    L8
  cmp    %ebp,%eax
  sete   %al
  add    %ebp,%ebx
  add    %r12d,%ebx
  test   %al,%al
  cmovne %ebx,%r12d
  jmp    L8
L31:
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: %30d

assistant: ```c
int Problem021(void) {
  int sum = 0, a, b;
  for (a = 2; a < 10000; a++) {
    b = sum_proper_divisors(a);
    if (sum_proper_divisors(b) == a && a < b) {
      sum += a + b;
    }
  }
  printf("%30d", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<Problem021>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L1:
  mov    %ebp,%edi
  call   <sum_proper_divisors@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <sum_proper_divisors@plt>
  cmp    %ebp,%eax
  jne    L15
  cmp    %ebp,%ebx
  setg   %al
  add    %ebp,%ebx
  add    %r12d,%ebx
  test   %al,%al
  cmovne %ebx,%r12d
L15:
  add    $0x1,%ebp
  cmp    $0x2710,%ebp
  jne    L1
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %30d

assistant: ```c
int Problem021(void) {
  int sum = 0, a, b;
  for (a = 2; a < 10000; a++) {
    b = sum_proper_divisors(a);
    if (sum_proper_divisors(b) == a && a < b) {
      sum += a + b;
    }
  }
  printf("%30d", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Problem021>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L18:
  mov    %ebp,%edi
  call   <sum_proper_divisors@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <sum_proper_divisors@plt>
  cmp    %ebp,%eax
  jne    L14
  cmp    %ebp,%ebx
  setg   %al
  add    %ebp,%ebx
  add    %r12d,%ebx
  test   %al,%al
  cmovne %ebx,%r12d
L14:
  add    $0x1,%ebp
  cmp    $0x2710,%ebp
  jne    L18
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D1: %30d

assistant: ```c
int Problem021(void) {
  int sum = 0, a, b;
  for (a = 2; a < 10000; a++) {
    b = sum_proper_divisors(a);
    if (sum_proper_divisors(b) == a && a < b) {
      sum += a + b;
    }
  }
  printf("%30d", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_color_symbol_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L41
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L41:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L20
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L20:
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L16
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L16:
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L18
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L18:
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void free_color_symbol_table(unsigned char *color_table[], unsigned short *symbol_table) {
  if (color_table[0])
    free(color_table[0]);
  if (color_table[1])
    free(color_table[1]);
  if (color_table[2])
    free(color_table[2]);
  if (color_table[3])
    free(color_table[3]);
  if (symbol_table)
    free(symbol_table);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_color_symbol_table>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L15
  call   <free@plt>
L15:
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L11
  call   <free@plt>
L11:
  mov    0x10(%rbx),%rdi
  test   %rdi,%rdi
  je     L49
  call   <free@plt>
L49:
  mov    0x18(%rbx),%rdi
  test   %rdi,%rdi
  je     L2
  call   <free@plt>
L2:
  test   %rbp,%rbp
  je     L14
  mov    %rbp,%rdi
  call   <free@plt>
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_color_symbol_table(unsigned char *color_table[], unsigned short *symbol_table) {
  if (color_table[0])
    free(color_table[0]);
  if (color_table[1])
    free(color_table[1]);
  if (color_table[2])
    free(color_table[2]);
  if (color_table[3])
    free(color_table[3]);
  if (symbol_table)
    free(symbol_table);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_color_symbol_table>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
L3:
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L40
  call   <free@plt>
L40:
  mov    0x10(%rbx),%rdi
  test   %rdi,%rdi
  je     L32
  call   <free@plt>
L32:
  mov    0x18(%rbx),%rdi
  test   %rdi,%rdi
  je     L18
  call   <free@plt>
L18:
  test   %rbp,%rbp
  je     L37
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_color_symbol_table(unsigned char *color_table[], unsigned short *symbol_table) {
  if (color_table[0])
    free(color_table[0]);
  if (color_table[1])
    free(color_table[1]);
  if (color_table[2])
    free(color_table[2]);
  if (color_table[3])
    free(color_table[3]);
  if (symbol_table)
    free(symbol_table);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_color_symbol_table>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L25
  call   <free@plt>
L25:
  mov    0x8(%rbx),%rdi
  test   %rdi,%rdi
  je     L49
  call   <free@plt>
L49:
  mov    0x10(%rbx),%rdi
  test   %rdi,%rdi
  je     L13
  call   <free@plt>
L13:
  mov    0x18(%rbx),%rdi
  test   %rdi,%rdi
  je     L36
  call   <free@plt>
L36:
  test   %rbp,%rbp
  je     L6
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_color_symbol_table(unsigned char *color_table[], unsigned short *symbol_table) {
  if (color_table[0])
    free(color_table[0]);
  if (color_table[1])
    free(color_table[1]);
  if (color_table[2])
    free(color_table[2]);
  if (color_table[3])
    free(color_table[3]);
  if (symbol_table)
    free(symbol_table);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<csc_strcmp_param>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <csc_strbody@plt>
  mov    %rax,-0x18(%rbp)
L23:
  cmpq   $0x0,-0x20(%rbp)
  je     L48
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <csc_strbody@plt>
  mov    %rax,-0x20(%rbp)
L48:
  cmpq   $0x0,-0x18(%rbp)
  je     L82
  cmpq   $0x0,-0x20(%rbp)
  je     L82
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  jmp    L96
L82:
  cmpq   $0x0,-0x18(%rbp)
  jne    L102
  cmpq   $0x0,-0x20(%rbp)
  jne    L102
  mov    $0x0,%eax
  jmp    L96
L102:
  cmpq   $0x0,-0x18(%rbp)
  je     L89
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L96
L89:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
L96:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

assistant: ```c
int csc_strcmp_param(char *s1, char *s2) {
  int len1, len2;
  len1 = len2 = 0;
  if (s1) {
    s1 = csc_strbody(s1, &len1);
  }
  if (s2) {
    s2 = csc_strbody(s2, &len2);
  }
  if (s1 && s2) {
    return strncmp(s1, s2, len1 < len2 ? len2 : len1);
  } else if (!s1 && !s2) {
    return 0;
  } else if (s1) {
    return *s1;
  }
  return *s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csc_strcmp_param>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L18
  mov    %rsp,%rsi
  call   <csc_strbody@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L27
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <csc_strbody@plt>
  mov    %rax,%rsi
  test   %rbx,%rbx
  setne  %dl
  test   %rax,%rax
  je     L67
  test   %dl,%dl
  je     L67
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  cmp    %eax,%edx
  cmovl  %eax,%edx
  mov    %rbx,%rdi
  call   <strncmp@plt>
  jmp    L103
L38:
  movsbl (%rsi),%eax
  jmp    L103
L18:
  test   %rsi,%rsi
  je     L11
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <csc_strbody@plt>
  mov    %rax,%rsi
  mov    $0x0,%edx
  jmp    L67
L11:
  mov    %rsi,%rbx
L27:
  test   %rbx,%rbx
  setne  %dl
  mov    $0x0,%esi
L67:
  mov    $0x0,%eax
  mov    %rbx,%rcx
  or     %rsi,%rcx
  je     L103
  test   %dl,%dl
  je     L38
  movsbl (%rbx),%eax
L103:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int csc_strcmp_param(char *s1, char *s2) {
  int len1, len2;
  len1 = len2 = 0;
  if (s1) {
    s1 = csc_strbody(s1, &len1);
  }
  if (s2) {
    s2 = csc_strbody(s2, &len2);
  }
  if (s1 && s2) {
    return strncmp(s1, s2, len1 < len2 ? len2 : len1);
  } else if (!s1 && !s2) {
    return 0;
  } else if (s1) {
    return *s1;
  }
  return *s2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<csc_strcmp_param>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L21
  mov    %rsp,%rsi
  call   <csc_strbody@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L87
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <csc_strbody@plt>
  mov    %rax,%rbp
  test   %r13,%r13
  je     L1
  test   %rax,%rax
  je     L1
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cmp    %eax,%edx
  cmovl  %eax,%edx
  call   <strncmp@plt>
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L125
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  mov    %rax,%r12
L100:
  test   %r13,%r13
  je     L108
  test   %r12,%r12
  je     L102
  movsbl (%r12),%eax
  jmp    L10
  nopl   0x0(%rax)
L21:
  test   %rsi,%rsi
  je     L10
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <csc_strbody@plt>
  mov    %rax,%rbp
L36:
  mov    %rbp,%r13
  or     %r12,%r13
  jmp    L100
  nopl   (%rax)
L102:
  movsbl 0x0(%rbp),%eax
  jmp    L10
  xchg   %ax,%ax
L1:
  mov    %r13,%r12
  jmp    L36
  nopl   (%rax)
L108:
  xor    %eax,%eax
  jmp    L10
L125:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int csc_strcmp_param(char *s1, char *s2) {
  int len1, len2;
  len1 = len2 = 0;
  if (s1) {
    s1 = csc_strbody(s1, &len1);
  }
  if (s2) {
    s2 = csc_strbody(s2, &len2);
  }
  if (s1 && s2) {
    return strncmp(s1, s2, len1 < len2 ? len2 : len1);
  } else if (!s1 && !s2) {
    return 0;
  } else if (s1) {
    return *s1;
  }
  return *s2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<csc_strcmp_param>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movl   $0x0,(%rsp)
  test   %rdi,%rdi
  je     L74
  mov    %rsp,%rsi
  call   <csc_strbody@plt>
  mov    %rax,%r13
  test   %rbp,%rbp
  je     L27
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <csc_strbody@plt>
  mov    %rax,%rbp
  test   %r13,%r13
  je     L77
  test   %rax,%rax
  je     L77
  mov    (%rsp),%edx
  mov    0x4(%rsp),%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cmp    %eax,%edx
  cmovl  %eax,%edx
  call   <strncmp@plt>
L112:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rax,%r12
L122:
  test   %r13,%r13
  je     L47
  test   %r12,%r12
  je     L82
  movsbl (%r12),%eax
  jmp    L112
  nopl   0x0(%rax)
L74:
  test   %rsi,%rsi
  je     L112
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <csc_strbody@plt>
  mov    %rax,%rbp
L128:
  mov    %rbp,%r13
  or     %r12,%r13
  jmp    L122
  nopl   (%rax)
L82:
  movsbl 0x0(%rbp),%eax
  jmp    L112
  xchg   %ax,%ax
L77:
  mov    %r13,%r12
  jmp    L128
  nopl   (%rax)
L47:
  xor    %eax,%eax
  jmp    L112
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int csc_strcmp_param(char *s1, char *s2) {
  int len1, len2;
  len1 = len2 = 0;
  if (s1) {
    s1 = csc_strbody(s1, &len1);
  }
  if (s2) {
    s2 = csc_strbody(s2, &len2);
  }
  if (s1 && s2) {
    return strncmp(s1, s2, len1 < len2 ? len2 : len1);
  } else if (!s1 && !s2) {
    return 0;
  } else if (s1) {
    return *s1;
  }
  return *s2;
}
```