ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D96(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D108(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  movl   $0xa,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D96(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x64,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D96
type_guessed: string
name: disassemble_data
arguments: tag: D108
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string
name: disassemble_data
arguments: tag: D95
type_guessed: string
name: disassemble_data
arguments: tag: D63
type_guessed: string
name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D96: a:	 %d


tool: D108: &a:	 %p


tool: D13: p:	 %p


tool: D95: ---

tool: D63: *p:	 %d


tool: D45: b: %d


tool: D6: *p: %d


assistant: ```c
int main() {
  int a;
  int b;
  int *p;
  a = 5;
  b = 20;
  p = &a;
  printf("a:\t %d\n", a);
  printf("&a:\t %p\n", &a);
  printf("p:\t %p\n", p);
  printf("---\n");
  *p = 10;
  printf("a:\t %d\n", a);
  printf("*p:\t %d\n", *p);
  printf("---\n");
  printf("b: %d\n", b);
  printf("---\n");
  p = &b;
  *p = 100;
  printf("b: %d\n", b);
  printf("*p: %d\n", *p);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  mov    $0x5,%esi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  movl   $0xa,0x4(%rsp)
  mov    $0xa,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x14,%esi
  lea    D44(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D46
type_infered: string
name: unpack_data
arguments: data_tag: D38
type_infered: string
name: unpack_data
arguments: data_tag: D19
type_infered: string
name: unpack_data
arguments: data_tag: D49
type_infered: string
name: unpack_data
arguments: data_tag: D44
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D1: a:	 %d


tool: D46: &a:	 %p


tool: D38: p:	 %p


tool: D19: ---

tool: D49: *p:	 %d


tool: D44: b: %d


tool: D17: *p: %d


assistant: ```c
int main() {
  int a;
  int b;
  int *p;
  a = 5;
  b = 20;
  p = &a;
  printf("a:\t %d\n", a);
  printf("&a:\t %p\n", &a);
  printf("p:\t %p\n", p);
  printf("---\n");
  *p = 10;
  printf("a:\t %d\n", a);
  printf("*p:\t %d\n", *p);
  printf("---\n");
  printf("b: %d\n", b);
  printf("---\n");
  p = &b;
  *p = 100;
  printf("b: %d\n", b);
  printf("*p: %d\n", *p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%r12
  mov    $0x5,%esi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D60(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    D55(%rip),%r12
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x64,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D38
data_type: string
name: unpack_data
arguments: label: D60
data_type: string
name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D36
data_type: string
name: unpack_data
arguments: label: D55
data_type: string
name: unpack_data
arguments: label: D31
data_type: string
name: unpack_data
arguments: label: D35
data_type: string

tool: D38: a:	 %d


tool: D60: &a:	 %p


tool: D27: p:	 %p


tool: D36: ---

tool: D55: b: %d


tool: D31: *p:	 %d


tool: D35: *p: %d


assistant: ```c
int main() {
  int a;
  int b;
  int *p;
  a = 5;
  b = 20;
  p = &a;
  printf("a:\t %d\n", a);
  printf("&a:\t %p\n", &a);
  printf("p:\t %p\n", p);
  printf("---\n");
  *p = 10;
  printf("a:\t %d\n", a);
  printf("*p:\t %d\n", *p);
  printf("---\n");
  printf("b: %d\n", b);
  printf("---\n");
  p = &b;
  *p = 100;
  printf("b: %d\n", b);
  printf("*p: %d\n", *p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  mov    $0x5,%esi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  movl   $0x5,0x4(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D34(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  movl   $0xa,0x4(%rsp)
  lea    D0(%rip),%r12
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x14,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x64,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D65
datatype: string
name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D34
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D8: a:	 %d


tool: D65: &a:	 %p


tool: D10: p:	 %p


tool: D34: ---

tool: D0: b: %d


tool: D33: *p:	 %d


tool: D9: *p: %d


assistant: ```c
int main() {
  int a;
  int b;
  int *p;
  a = 5;
  b = 20;
  p = &a;
  printf("a:\t %d\n", a);
  printf("&a:\t %p\n", &a);
  printf("p:\t %p\n", p);
  printf("---\n");
  *p = 10;
  printf("a:\t %d\n", a);
  printf("*p:\t %d\n", *p);
  printf("---\n");
  printf("b: %d\n", b);
  printf("---\n");
  p = &b;
  *p = 100;
  printf("b: %d\n", b);
  printf("*p: %d\n", *p);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(double *row1, double *row2, int n) {
  double tmp;
  int i;
  for (i = 0; i < n; ++i) {
    tmp = row1[i];
    row1[i] = row2[i];
    row2[i] = tmp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  test   %edx,%edx
  jle    L3
  mov    %edx,%edx
  mov    $0x0,%eax
L4:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
L3:
  ret
```

assistant: ```c
void swap(double *row1, double *row2, int n) {
  double tmp;
  int i;
  for (i = 0; i < n; ++i) {
    tmp = row1[i];
    row1[i] = row2[i];
    row2[i] = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rdi,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L10:
  ret
```

assistant: ```c
void swap(double *row1, double *row2, int n) {
  double tmp;
  int i;
  for (i = 0; i < n; ++i) {
    tmp = row1[i];
    row1[i] = row2[i];
    row2[i] = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L28
  lea    0xf(%rdi),%rax
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L46
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L46
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  xchg   %ax,%ax
L12:
  movupd (%rcx,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm2
  movups %xmm2,(%rcx,%rax,1)
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L12
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L28
  shl    $0x3,%rax
  add    %rax,%rcx
  add    %rsi,%rax
  movsd  (%rcx),%xmm0
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%rcx)
  movsd  %xmm0,(%rax)
  ret
L46:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L58:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L58
L28:
  ret
```

assistant: ```c
void swap(double *row1, double *row2, int n) {
  double tmp;
  int i;
  for (i = 0; i < n; ++i) {
    tmp = row1[i];
    row1[i] = row2[i];
    row2[i] = tmp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hsw_debug_sinterrupt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x17,%eax
  and    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x16,%eax
  and    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x15,%eax
  and    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x13,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%r8d
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x4(%rbp),%ecx
  push   %rcx
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  lea    D1(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: port d:%d, port c:%d, port b:%d, crt:%d

assistant: ```c
void hsw_debug_sinterrupt(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  int portd, portc, portb, crt;
  portd = (val >> 23) & 1;
  portc = (val >> 22) & 1;
  portb = (val >> 21) & 1;
  crt = (val >> 19) & 1;
  snprintf(result, len, "port d:%d, port c:%d, port b:%d, crt:%d", portd, portc, portb, crt);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hsw_debug_sinterrupt>:
  endbr64
  sub    $0x10,%rsp
  mov    %ecx,%eax
  mov    %ecx,%r9d
  sar    $0x15,%r9d
  mov    %ecx,%r8d
  sar    $0x16,%r8d
  sar    $0x17,%ecx
  and    $0x1,%ecx
  sar    $0x13,%eax
  and    $0x1,%eax
  push   %rax
  and    $0x1,%r9d
  and    $0x1,%r8d
  lea    D7(%rip),%rdx
  call   <snprintf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: port d:%d, port c:%d, port b:%d, crt:%d

assistant: ```c
void hsw_debug_sinterrupt(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  int portd, portc, portb, crt;
  portd = (val >> 23) & 1;
  portc = (val >> 22) & 1;
  portb = (val >> 21) & 1;
  crt = (val >> 19) & 1;
  snprintf(result, len, "port d:%d, port c:%d, port b:%d, crt:%d", portd, portc, portb, crt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hsw_debug_sinterrupt>:
  endbr64
  mov    %ecx,%eax
  sub    $0x10,%rsp
  mov    %ecx,%r9d
  mov    %ecx,%r8d
  sar    $0x13,%eax
  sar    $0x15,%r9d
  lea    D7(%rip),%rdx
  sar    $0x16,%r8d
  and    $0x1,%eax
  sar    $0x17,%ecx
  and    $0x1,%r9d
  push   %rax
  and    $0x1,%ecx
  and    $0x1,%r8d
  call   <snprintf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: D7: port d:%d, port c:%d, port b:%d, crt:%d

assistant: ```c
void hsw_debug_sinterrupt(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  int portd, portc, portb, crt;
  portd = (val >> 23) & 1;
  portc = (val >> 22) & 1;
  portb = (val >> 21) & 1;
  crt = (val >> 19) & 1;
  snprintf(result, len, "port d:%d, port c:%d, port b:%d, crt:%d", portd, portc, portb, crt);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hsw_debug_sinterrupt>:
  endbr64
  mov    %ecx,%eax
  sub    $0x10,%rsp
  mov    %ecx,%r9d
  mov    %ecx,%r8d
  sar    $0x13,%eax
  sar    $0x15,%r9d
  lea    D1(%rip),%rdx
  sar    $0x16,%r8d
  and    $0x1,%eax
  sar    $0x17,%ecx
  and    $0x1,%r9d
  push   %rax
  and    $0x1,%ecx
  and    $0x1,%r8d
  call   <snprintf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: port d:%d, port c:%d, port b:%d, crt:%d

assistant: ```c
void hsw_debug_sinterrupt(char *result, int len, int reg, uint32_t val, uint32_t devid) {
  int portd, portc, portb, crt;
  portd = (val >> 23) & 1;
  portc = (val >> 22) & 1;
  portb = (val >> 21) & 1;
  crt = (val >> 19) & 1;
  snprintf(result, len, "port d:%d, port c:%d, port b:%d, crt:%d", portd, portc, portb, crt);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<commands>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%r13d
  cmp    $0xf,%rdi
  jbe    L79
  sub    $0x10,%rbx
  mov    $0x1,%r13d
L79:
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   $0xffffffffffffffef,%rbx
  je     L36
  mov    $0x0,%ebp
  cmp    $0x7,%rbx
  jbe    L54
  lea    D16(%rip),%rax
  mov    %rax,(%r12)
  sub    $0x8,%rbx
  mov    $0x1,%ebp
L54:
  cmp    $0x3,%rbx
  jbe    L61
  movslq %ebp,%rax
  lea    D31(%rip),%rcx
  mov    %rcx,(%r12,%rax,8)
  sub    $0x4,%rbx
  lea    0x1(%rbp),%ebp
L61:
  cmp    $0x1,%rbx
  jbe    L9
  movslq %ebp,%rax
  lea    D36(%rip),%rdx
  mov    %rdx,(%r12,%rax,8)
  sub    $0x2,%rbx
  lea    0x1(%rbp),%ebp
L9:
  test   %rbx,%rbx
  je     L49
  movslq %ebp,%rax
  lea    D26(%rip),%rcx
  mov    %rcx,(%r12,%rax,8)
  lea    0x1(%rbp),%ebp
L49:
  test   %r13d,%r13d
  jne    L62
  cmp    $0x1,%ebp
  jle    L62
  movslq %ebp,%rax
  lea    -0x8(%r12,%rax,8),%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  cmp    $0x3,%ebp
  jle    L62
  sub    $0x1,%ebp
  movslq %ebp,%rbp
  lea    -0x8(%r12,%rbp,8),%rsi
  lea    0x8(%r12),%rdi
  call   <swap@plt>
  jmp    L62
L36:
  movq   $0x0,(%rax)
L62:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D31
type_guessed: string
name: disassemble_data
arguments: data_label: D36
type_guessed: string
name: disassemble_data
arguments: data_label: D26
type_guessed: string

tool: D16: jump

tool: D31: close your eyes

tool: D36: double blink

tool: D26: wink

assistant: ```c
const char **commands(size_t number) {
  bool reverse = false;
  if (number >= 16) {
    reverse = true;
    number -= 16;
  }
  char **result = malloc(sizeof(char *) * 4);
  if (number == 0 || number == 16) {
    result[0] = NULL;
    return (const char **)result;
  }
  int idx = 0;
  if (number >= 8) {
    result[idx++] = "jump";
    number -= 8;
  }
  if (number >= 4) {
    result[idx++] = "close your eyes";
    number -= 4;
  }
  if (number >= 2) {
    result[idx++] = "double blink";
    number -= 2;
  }
  if (number >= 1) {
    result[idx++] = "wink";
    number -= 1;
  }
  if (!reverse) {
    for (int i = 0; i < idx / 2; ++i)
      swap(&result[i], &result[idx - i - 1]);
  }
  return (const char **)result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<commands>:
  endbr64
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  cmp    $0xf,%rdi
  jbe    L46
  sub    $0x10,%rbx
  mov    $0x1,%ebp
L46:
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   $0xffffffffffffffef,%rbx
  je     L37
  xor    %eax,%eax
  cmp    $0x7,%rbx
  jbe    L16
  lea    D25(%rip),%rax
  sub    $0x8,%rbx
  mov    %rax,(%r12)
  mov    $0x1,%eax
L16:
  cmp    $0x3,%rbx
  jbe    L25
  movslq %eax,%rdx
  lea    D23(%rip),%rcx
  sub    $0x4,%rbx
  add    $0x1,%eax
  mov    %rcx,(%r12,%rdx,8)
L25:
  cmp    $0x1,%rbx
  jbe    L30
  movslq %eax,%rdx
  lea    D13(%rip),%rcx
  sub    $0x2,%rbx
  add    $0x1,%eax
  mov    %rcx,(%r12,%rdx,8)
L30:
  test   %rbx,%rbx
  je     L3
  movslq %eax,%rdx
  lea    D31(%rip),%rsi
  add    $0x1,%eax
  mov    %rsi,(%r12,%rdx,8)
L3:
  test   %ebp,%ebp
  jne    L11
  mov    %eax,%ebx
  sar    %ebx
  je     L11
  cltq
  mov    %r12,%rdi
  lea    -0x8(%r12,%rax,8),%rsi
  call   <swap@plt>
  cmp    $0x2,%ebx
  jne    L11
  lea    0x10(%r12),%rsi
  lea    0x8(%r12),%rdi
  call   <swap@plt>
L11:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  movq   $0x0,(%rax)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string

tool: D25: jump

tool: D23: close your eyes

tool: D13: double blink

tool: D31: wink

assistant: ```c
const char **commands(size_t number) {
  bool reverse = false;
  if (number >= 16) {
    reverse = true;
    number -= 16;
  }
  char **result = malloc(sizeof(char *) * 4);
  if (number == 0 || number == 16) {
    result[0] = NULL;
    return (const char **)result;
  }
  int idx = 0;
  if (number >= 8) {
    result[idx++] = "jump";
    number -= 8;
  }
  if (number >= 4) {
    result[idx++] = "close your eyes";
    number -= 4;
  }
  if (number >= 2) {
    result[idx++] = "double blink";
    number -= 2;
  }
  if (number >= 1) {
    result[idx++] = "wink";
    number -= 1;
  }
  if (!reverse) {
    for (int i = 0; i < idx / 2; ++i)
      swap(&result[i], &result[idx - i - 1]);
  }
  return (const char **)result;
}
```