ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L48
  mov    $0x1,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L48:
  movl   $0x0,-0x1c(%rbp)
  jmp    L20
L29:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L20:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L29
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x3ea011f7,%eax
  jne    L61
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L61:
  movl   $0x0,-0x18(%rbp)
  jmp    L44
L21:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L44:
  cmpl   $0x0,-0x18(%rbp)
  jle    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D24
datatype: string

tool: D25: Call this program with %i arguments


tool: D23: You win!

tool: D24: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1050677751U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L29
L3:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x3ea011f7,0x4(%rsp)
  je     L28
L10:
  mov    0x4(%rsp),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
L28:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L10
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D5: %u


tool: D1: Call this program with %i arguments


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1050677751U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L9
  lea    D12(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x3ea011f7,%esi
  je     L23
L17:
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L17
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type: string
name: disassemble_data
arguments: data_label: D19
type: string
name: disassemble_data
arguments: data_label: D21
type: string

tool: D12: Call this program with %i arguments


tool: D19: %u


tool: D21: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1050677751U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L14
  lea    D1(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L14:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <RandomFunc@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x3ea011f7,%esi
  je     L22
L9:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  jmp    L9
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D20
data_type: string

tool: D1: Call this program with %i arguments


tool: D5: %u


tool: D20: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1050677751U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sprintf_putch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sprintf_putch(int ch, void **data) {
  char **pstr = (char **)data;
  **pstr = ch;
  (*pstr)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sprintf_putch>:
  endbr64
  mov    (%rsi),%rax
  mov    %dil,(%rax)
  addq   $0x1,(%rsi)
  ret
```

assistant: ```c
void sprintf_putch(int ch, void **data) {
  char **pstr = (char **)data;
  **pstr = ch;
  (*pstr)++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sprintf_putch>:
  endbr64
  mov    (%rsi),%rax
  mov    %dil,(%rax)
  addq   $0x1,(%rsi)
  ret
```

assistant: ```c
void sprintf_putch(int ch, void **data) {
  char **pstr = (char **)data;
  **pstr = ch;
  (*pstr)++;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sprintf_putch>:
  endbr64
  mov    (%rsi),%rax
  mov    %dil,(%rax)
  addq   $0x1,(%rsi)
  ret
```

assistant: ```c
void sprintf_putch(int ch, void **data) {
  char **pstr = (char **)data;
  **pstr = ch;
  (*pstr)++;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L24:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L12:
  cmpl   $0x63,-0x10(%rbp)
  jle    L24
  mov    -0x8(%rbp),%rax
  add    $0x68,%rax
  movl   $0x1,(%rax)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L8
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: Hi!


assistant: ```c
int main() {
  int i, sum = 0;
  int *a = malloc(100);
  for (i = 0; i < 100; ++i)
    sum += a[i];
  a[26] = 1;
  a = NULL;
  if (sum > 0)
    printf("Hi!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  lea    0x190(%rax),%rsi
  mov    $0x0,%ecx
L11:
  add    (%rdx),%ecx
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L11
  movl   $0x1,0x68(%rax)
  test   %ecx,%ecx
  jg     L2
L20:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L2:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L20
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: Hi!


assistant: ```c
int main() {
  int i, sum = 0;
  int *a = malloc(100);
  for (i = 0; i < 100; ++i)
    sum += a[i];
  a[26] = 1;
  a = NULL;
  if (sum > 0)
    printf("Hi!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc@plt>
  xor    %ecx,%ecx
  mov    %rax,%rdx
  lea    0x190(%rax),%rsi
  xchg   %ax,%ax
L18:
  add    (%rdx),%ecx
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L18
  movl   $0x1,0x68(%rax)
  test   %ecx,%ecx
  jle    L10
  lea    D1(%rip),%rdi
  call   <printf@plt>
L10:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: Hi!


assistant: ```c
int main() {
  int i, sum = 0;
  int *a = malloc(100);
  for (i = 0; i < 100; ++i)
    sum += a[i];
  a[26] = 1;
  a = NULL;
  if (sum > 0)
    printf("Hi!\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%edi
  call   <malloc@plt>
  pxor   %xmm0,%xmm0
  mov    %rax,%rdx
  lea    0x190(%rax),%rcx
L8:
  movdqu (%rdx),%xmm2
  add    $0x10,%rdx
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rcx
  jne    L8
  movdqa %xmm0,%xmm1
  movl   $0x1,0x68(%rax)
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   %eax,%eax
  jle    L18
  lea    D8(%rip),%rdi
  call   <printf@plt>
L18:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: Hi!


assistant: ```c
int main() {
  int i, sum = 0;
  int *a = malloc(100);
  for (i = 0; i < 100; ++i)
    sum += a[i];
  a[26] = 1;
  a = NULL;
  if (sum > 0)
    printf("Hi!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_etc2a8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %rcx,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x80(%rbp),%rax
  add    $0x3,%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x88(%rbp),%rax
  add    $0x3,%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x70(%rbp)
  jmp    L5
L26:
  movq   $0x0,-0x68(%rbp)
  jmp    L44
L13:
  mov    -0x78(%rbp),%rax
  lea    0x20(%rax),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <decode_etc2_block@plt>
  lea    -0x50(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decode_etc2a8_block@plt>
  mov    -0x88(%rbp),%rcx
  mov    -0x80(%rbp),%rdx
  mov    -0x70(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  push   -0x90(%rbp)
  lea    -0x50(%rbp),%rdi
  push   %rdi
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    %rax,%rdi
  call   <copy_block_buffer@plt>
  add    $0x10,%rsp
  addq   $0x1,-0x68(%rbp)
  addq   $0x40,-0x78(%rbp)
L44:
  mov    -0x68(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jl     L13
  addq   $0x1,-0x70(%rbp)
L5:
  mov    -0x70(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  jl     L26
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int decode_etc2a8(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, data += 16) {
      decode_etc2_block(data + 8, buffer);
      decode_etc2a8_block(data, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decode_etc2a8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rcx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsi),%r14
  mov    %rsi,%rax
  add    $0x3,%rax
  cmovns %rax,%r14
  sar    $0x2,%r14
  lea    0x6(%rdx),%rax
  mov    %rdx,%rcx
  add    $0x3,%rdx
  cmovns %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,0x20(%rsp)
  test   %rcx,%rcx
  jle    L46
  mov    %r14,%rdx
  shl    $0x6,%rdx
  test   %rsi,%rsi
  mov    $0x40,%eax
  cmovg  %rdx,%rax
  mov    %rax,0x28(%rsp)
  mov    $0x0,%r13d
  lea    0x30(%rsp),%r12
  jmp    L27
L22:
  lea    0x20(%rbp),%rdi
  mov    %r12,%rsi
  call   <decode_etc2_block@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <decode_etc2a8_block@plt>
  push   %r15
  push   %r12
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    0x20(%rsp),%rcx
  mov    0x18(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <copy_block_buffer@plt>
  add    $0x1,%rbx
  add    $0x40,%rbp
  add    $0x10,%rsp
  cmp    %rbx,%r14
  jg     L22
  mov    0x28(%rsp),%rcx
  add    %rcx,0x18(%rsp)
L20:
  add    $0x1,%r13
  cmp    %r13,0x20(%rsp)
  jle    L46
L27:
  mov    0x18(%rsp),%rbp
  mov    $0x0,%ebx
  cmpq   $0x0,0x8(%rsp)
  jg     L22
  jmp    L20
L46:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x1,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_etc2a8(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, data += 16) {
      decode_etc2_block(data + 8, buffer);
      decode_etc2a8_block(data, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode_etc2a8>:
  endbr64
  push   %r15
  push   %r14
  lea    0x6(%rsi),%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %rdi,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rax
  add    $0x3,%rax
  cmovns %rax,%r14
  lea    0x6(%rdx),%rax
  mov    %r14,%rcx
  sar    $0x2,%rcx
  add    $0x3,%rdx
  cmovns %rdx,%rax
  mov    %rcx,0x10(%rsp)
  sar    $0x2,%rax
  mov    %rax,0x20(%rsp)
  test   %r13,%r13
  jle    L38
  mov    %rcx,%rdx
  mov    $0x40,%eax
  lea    0x30(%rsp),%rbx
  mov    %rsi,%r12
  shl    $0x6,%rdx
  test   %rsi,%rsi
  cmovg  %rdx,%rax
  xor    %ebp,%ebp
  mov    %rax,0x28(%rsp)
  nopl   (%rax)
L36:
  mov    0x18(%rsp),%r14
  xor    %r15d,%r15d
  test   %r12,%r12
  jle    L47
  nopl   (%rax)
L32:
  lea    0x20(%r14),%rdi
  mov    %rbx,%rsi
  call   <decode_etc2_block@plt>
  mov    %r14,%rdi
  mov    %rbx,%rsi
  add    $0x40,%r14
  call   <decode_etc2a8_block@plt>
  push   0x8(%rsp)
  mov    %r12,%rdx
  mov    %r15,%rdi
  push   %rbx
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    %r13,%rcx
  mov    %rbp,%rsi
  add    $0x1,%r15
  call   <copy_block_buffer@plt>
  pop    %rax
  pop    %rdx
  cmp    %r15,0x10(%rsp)
  jg     L32
  mov    0x28(%rsp),%rcx
  add    %rcx,0x18(%rsp)
L47:
  add    $0x1,%rbp
  cmp    %rbp,0x20(%rsp)
  jg     L36
L38:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x88,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_etc2a8(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, data += 16) {
      decode_etc2_block(data + 8, buffer);
      decode_etc2a8_block(data, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decode_etc2a8>:
  endbr64
  push   %r15
  push   %r14
  lea    0x6(%rsi),%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %rdi,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rax
  add    $0x3,%rax
  cmovns %rax,%r14
  lea    0x6(%rdx),%rax
  mov    %r14,%rcx
  sar    $0x2,%rcx
  add    $0x3,%rdx
  cmovns %rdx,%rax
  mov    %rcx,0x10(%rsp)
  sar    $0x2,%rax
  mov    %rax,0x20(%rsp)
  test   %r12,%r12
  jle    L13
  mov    %rsi,%r13
  test   %rsi,%rsi
  jle    L13
  shl    $0x6,%rcx
  xor    %ebp,%ebp
  lea    0x30(%rsp),%rbx
  mov    %rcx,0x28(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x18(%rsp),%r14
  xor    %r15d,%r15d
L45:
  lea    0x20(%r14),%rdi
  mov    %rbx,%rsi
  call   <decode_etc2_block@plt>
  mov    %r14,%rdi
  mov    %rbx,%rsi
  add    $0x40,%r14
  call   <decode_etc2a8_block@plt>
  push   0x8(%rsp)
  mov    %r13,%rdx
  mov    %r15,%rdi
  push   %rbx
  mov    $0x4,%r9d
  mov    $0x4,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rsi
  add    $0x1,%r15
  call   <copy_block_buffer@plt>
  pop    %rax
  pop    %rdx
  cmp    %r15,0x10(%rsp)
  jg     L45
  mov    0x28(%rsp),%rcx
  add    $0x1,%rbp
  add    %rcx,0x18(%rsp)
  cmp    %rbp,0x20(%rsp)
  jg     L1
L13:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x88,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_etc2a8(const uint8_t *data, const long w, const long h, uint32_t *image) {
  long num_blocks_x = (w + 3) / 4;
  long num_blocks_y = (h + 3) / 4;
  uint32_t buffer[16];
  for (long by = 0; by < num_blocks_y; by++) {
    for (long bx = 0; bx < num_blocks_x; bx++, data += 16) {
      decode_etc2_block(data + 8, buffer);
      decode_etc2a8_block(data, buffer);
      copy_block_buffer(bx, by, w, h, 4, 4, buffer, image);
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Varint_To_Num_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    $0x3c,%esi
  mov    %rax,%rdi
  call   <uvarint_decode64@plt>
  lea    D15(%rip),%rax
  leave
  ret
```

assistant: ```c
uint64_t *Varint_To_Num_64(uint8_t TON64INPUT[60]) {
  static uint64_t varintdecode_001 = 0;
  uvarint_decode64(TON64INPUT, 60, &varintdecode_001);
  return &varintdecode_001;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Varint_To_Num_64>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdx
  mov    $0x3c,%esi
  call   <uvarint_decode64@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t *Varint_To_Num_64(uint8_t TON64INPUT[60]) {
  static uint64_t varintdecode_001 = 0;
  uvarint_decode64(TON64INPUT, 60, &varintdecode_001);
  return &varintdecode_001;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Varint_To_Num_64>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  mov    $0x3c,%esi
  mov    %r12,%rdx
  call   <uvarint_decode64@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
uint64_t *Varint_To_Num_64(uint8_t TON64INPUT[60]) {
  static uint64_t varintdecode_001 = 0;
  uvarint_decode64(TON64INPUT, 60, &varintdecode_001);
  return &varintdecode_001;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Varint_To_Num_64>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  mov    $0x3c,%esi
  mov    %r12,%rdx
  call   <uvarint_decode64@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
uint64_t *Varint_To_Num_64(uint8_t TON64INPUT[60]) {
  static uint64_t varintdecode_001 = 0;
  uvarint_decode64(TON64INPUT, 60, &varintdecode_001);
  return &varintdecode_001;
}
```