ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memmove>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L9
  lea    -0x1(%rdx),%rdx
  cmp    %rsi,%rax
  jae    L132
L35:
  lea    0x1(%rsi),%r8
  mov    %rax,%rcx
  sub    %r8,%rcx
  cmp    $0xe,%rcx
  jbe    L115
  cmp    $0x6,%rdx
  jbe    L115
  cmp    $0xe,%rdx
  jbe    L8
  mov    %rdi,%r8
  xor    %ecx,%ecx
  and    $0xfffffffffffffff0,%r8
  nopl   0x0(%rax)
L151:
  movdqu (%rsi,%rcx,1),%xmm0
  movups %xmm0,(%rax,%rcx,1)
  add    $0x10,%rcx
  cmp    %r8,%rcx
  jne    L151
  mov    %rdi,%rcx
  and    $0xfffffffffffffff0,%rcx
  lea    (%rax,%rcx,1),%r8
  lea    (%rsi,%rcx,1),%r9
  sub    %rcx,%rdx
  cmp    %rcx,%rdi
  je     L9
  sub    %rcx,%rdi
  lea    -0x1(%rdi),%r10
  cmp    $0x6,%r10
  jbe    L139
L84:
  mov    (%rsi,%rcx,1),%rsi
  mov    %rsi,(%rax,%rcx,1)
  mov    %rdi,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%r8
  add    %rcx,%r9
  sub    %rcx,%rdx
  cmp    %rcx,%rdi
  je     L9
L139:
  movzbl (%r9),%ecx
  mov    %cl,(%r8)
  test   %rdx,%rdx
  je     L9
  movzbl 0x1(%r9),%ecx
  mov    %cl,0x1(%r8)
  cmp    $0x1,%rdx
  je     L9
  movzbl 0x2(%r9),%ecx
  mov    %cl,0x2(%r8)
  cmp    $0x2,%rdx
  je     L9
  movzbl 0x3(%r9),%ecx
  mov    %cl,0x3(%r8)
  cmp    $0x3,%rdx
  je     L9
  movzbl 0x4(%r9),%ecx
  mov    %cl,0x4(%r8)
  cmp    $0x4,%rdx
  je     L9
  movzbl 0x5(%r9),%ecx
  mov    %cl,0x5(%r8)
  cmp    $0x5,%rdx
  je     L9
  movzbl 0x6(%r9),%edx
  mov    %dl,0x6(%r8)
  ret
L115:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L34
L9:
  ret
  nopl   0x0(%rax)
L132:
  lea    (%rsi,%rdi,1),%rcx
  cmp    %rcx,%rax
  jae    L35
  nopl   (%rax)
L50:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  sub    $0x1,%rdx
  jae    L50
  ret
L8:
  mov    %rsi,%r9
  mov    %rax,%r8
  xor    %ecx,%ecx
  jmp    L84
```

assistant: ```c
void *memmove(void *s, const void *ct, size_t n) {
  char *p1 = s;
  const char *p2 = ct;
  if (p1 && p2 && (n > 0)) {
    if ((p2 <= p1) && (p2 + n > p1)) {
      p1 += n;
      p2 += n;
      while (n--) {
        *--p1 = *--p2;
      }
    } else {
      while (n--) {
        *p1++ = *p2++;
      }
    }
  }
  return (s);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L69
L50:
  movl   $0x0,-0x28(%rbp)
  jmp    L87
L36:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L59
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L64
L59:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L64:
  addl   $0x1,-0x28(%rbp)
L87:
  cmpl   $0xb,-0x28(%rbp)
  jle    L36
  addl   $0x1,-0x24(%rbp)
L69:
  cmpl   $0xb,-0x24(%rbp)
  jle    L50
  movzbl -0xa(%rbp),%eax
  cmp    $0x53,%al
  jne    L37
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L84
L37:
  movsd  -0x18(%rbp),%xmm0
  movsd  D48(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L84:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D55
type: string
name: disassemble_data
arguments: data_label: D23
type: string
name: disassemble_data
arguments: data_label: D34
type: string
name: disassemble_data
arguments: data_label: D48
type: f32[2]

tool: D0: %d

tool: D55:  %s

tool: D23: %lf

tool: D34: %.1lf


tool: {"D48": [0.0,2.625]}

assistant: ```c
int main() {
  int j = 0, i = 0, terget;
  double a, total = 0;
  char word[2];
  scanf("%d", &terget);
  scanf(" %s", &word);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      if (j == terget) {
        scanf("%lf", &a);
        total += a;
      } else {
        scanf("%lf", &a);
      }
    }
  }
  if (word[0] == 'S') {
    printf("%.1lf\n", total);
  } else {
    printf("%.1lf\n", total / 12);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  lea    0x16(%rsp),%rsi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xc,%r13d
  mov    D41(%rip),%r12
  lea    D38(%rip),%rbp
  jmp    L33
L9:
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
L58:
  add    $0x1,%ebx
  cmp    $0xc,%ebx
  je     L42
L21:
  cmp    %ebx,0x4(%rsp)
  jne    L9
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   %r12,%xmm1
  addsd  0x8(%rsp),%xmm1
  movq   %xmm1,%r12
  jmp    L58
L42:
  sub    $0x1,%r13d
  je     L46
L33:
  mov    $0x0,%ebx
  jmp    L21
L46:
  cmpb   $0x53,0x16(%rsp)
  je     L27
  movq   %r12,%xmm0
  divsd  D15(%rip),%xmm0
  lea    D25(%rip),%rdi
  call   <printf@plt>
L52:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  movq   %r12,%xmm0
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D28
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D41
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D38
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string

tool: D18: %d

tool: D28:  %s

tool: D41: 0

tool: D38: %lf

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x28,0x40]}

tool: D25: %.1lf


assistant: ```c
int main() {
  int j = 0, i = 0, terget;
  double a, total = 0;
  char word[2];
  scanf("%d", &terget);
  scanf(" %s", &word);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      if (j == terget) {
        scanf("%lf", &a);
        total += a;
      } else {
        scanf("%lf", &a);
      }
    }
  }
  if (word[0] == 'S') {
    printf("%.1lf\n", total);
  } else {
    printf("%.1lf\n", total / 12);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D25(%rip),%rdi
  push   %r13
  mov    $0xc,%r13d
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
  lea    0x16(%rsp),%rsi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  pxor   %xmm2,%xmm2
  movq   %xmm2,%r14
  nop
L24:
  xor    %ebx,%ebx
  jmp    L33
  nopl   0x0(%rax)
L38:
  call   <scanf@plt>
  add    $0x1,%ebx
  cmp    $0xc,%ebx
  je     L67
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  cmp    %ebx,0x4(%rsp)
  jne    L38
  call   <scanf@plt>
  movq   %r14,%xmm1
  addsd  0x8(%rsp),%xmm1
  add    $0x1,%ebx
  movq   %xmm1,%r14
  cmp    $0xc,%ebx
  jne    L33
L67:
  sub    $0x1,%r13d
  jne    L24
  cmpb   $0x53,0x16(%rsp)
  movq   %r14,%xmm0
  je     L57
  divsd  D48(%rip),%xmm0
L57:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string
name: extract_symbolic_data
arguments: label: D48
datatype: f32[2]
name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D25: %d

tool: D19: %lf

tool: D32:  %s

tool: {"D48": [0.0,2.625]}

tool: D6: %.1lf


assistant: ```c
int main() {
  int j = 0, i = 0, terget;
  double a, total = 0;
  char word[2];
  scanf("%d", &terget);
  scanf(" %s", &word);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      if (j == terget) {
        scanf("%lf", &a);
        total += a;
      } else {
        scanf("%lf", &a);
      }
    }
  }
  if (word[0] == 'S') {
    printf("%.1lf\n", total);
  } else {
    printf("%.1lf\n", total / 12);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  mov    $0xc,%r13d
  push   %r12
  push   %rbp
  lea    D19(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
  lea    0x16(%rsp),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  pxor   %xmm2,%xmm2
  movq   %xmm2,%r14
  nop
L79:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  cmp    %ebx,0x4(%rsp)
  je     L20
  call   <scanf@plt>
  add    $0x1,%ebx
  cmp    $0xc,%ebx
  jne    L19
  sub    $0x1,%r13d
  jne    L79
L55:
  cmpb   $0x53,0x16(%rsp)
  movq   %r14,%xmm0
  je     L4
  divsd  D23(%rip),%xmm0
L4:
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  call   <scanf@plt>
  movq   %r14,%xmm1
  addsd  0x8(%rsp),%xmm1
  add    $0x1,%ebx
  movq   %xmm1,%r14
  cmp    $0xc,%ebx
  jne    L19
  sub    $0x1,%r13d
  jne    L79
  jmp    L55
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: f32[2]
name: retrieve_data
arguments: data_label: D40
datatype: string

tool: D13: %d

tool: D19: %lf

tool: D0:  %s

tool: {"D23": [0.0,2.625]}

tool: D40: %.1lf


assistant: ```c
int main() {
  int j = 0, i = 0, terget;
  double a, total = 0;
  char word[2];
  scanf("%d", &terget);
  scanf(" %s", &word);
  for (i = 0; i < 12; i++) {
    for (j = 0; j < 12; j++) {
      if (j == terget) {
        scanf("%lf", &a);
        total += a;
      } else {
        scanf("%lf", &a);
      }
    }
  }
  if (word[0] == 'S') {
    printf("%.1lf\n", total);
  } else {
    printf("%.1lf\n", total / 12);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mov_m32_reg32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x89,%edi
  call   <put8@plt>
  mov    -0x20(%rbp),%rax
  shl    $0x3,%rax
  or     $0x5,%rax
  mov    %rax,%rdi
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void mov_m32_reg32(void *_m32, unsigned long reg32) {
  unsigned long *m32 = (unsigned long *)_m32;
  put8(0x89);
  put8((reg32 << 3) | 5);
  put32((unsigned long)(m32));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mov_m32_reg32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x5(,%rbx,8),%rdi
  call   <put8@plt>
  mov    %rbp,%rdi
  call   <put32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mov_m32_reg32(void *_m32, unsigned long reg32) {
  unsigned long *m32 = (unsigned long *)_m32;
  put8(0x89);
  put8((reg32 << 3) | 5);
  put32((unsigned long)(m32));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mov_m32_reg32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x89,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <put8@plt>
  lea    0x5(,%rbx,8),%rdi
  call   <put8@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_m32_reg32(void *_m32, unsigned long reg32) {
  unsigned long *m32 = (unsigned long *)_m32;
  put8(0x89);
  put8((reg32 << 3) | 5);
  put32((unsigned long)(m32));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mov_m32_reg32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x89,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <put8@plt>
  lea    0x5(,%rbx,8),%rdi
  call   <put8@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_m32_reg32(void *_m32, unsigned long reg32) {
  unsigned long *m32 = (unsigned long *)_m32;
  put8(0x89);
  put8((reg32 << 3) | 5);
  put32((unsigned long)(m32));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rotatex_3fo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movss  %xmm0,-0x34(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %rsi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <matrix3_mul_3fo@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void rotatex_3fo(float rx, const float *v, float *result) {
  float m[] = {
      1, 0, 0, 0, cosf(rx), -sinf(rx), 0, sinf(rx), cosf(rx),
  };
  matrix3_mul_3fo(m, v, result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotatex_3fo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movss  %xmm0,0xc(%rsp)
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x20(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <sinf@plt>
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <sinf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x2c(%rsp)
  movss  0xc(%rsp),%xmm0
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x30(%rsp)
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <matrix3_mul_3fo@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotatex_3fo(float rx, const float *v, float *result) {
  float m[] = {
      1, 0, 0, 0, cosf(rx), -sinf(rx), 0, sinf(rx), cosf(rx),
  };
  matrix3_mul_3fo(m, v, result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotatex_3fo>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  movq   $0x3f800000,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  call   <cosf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x20(%rsp)
  call   <sinf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  movl   $0x0,0x28(%rsp)
  neg    %eax
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x24(%rsp)
  call   <sinf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x2c(%rsp)
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %rbp,%rsi
  cvtsi2ss %eax,%xmm0
  lea    0x10(%rsp),%rdi
  movss  %xmm0,0x30(%rsp)
  call   <matrix3_mul_3fo@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rotatex_3fo(float rx, const float *v, float *result) {
  float m[] = {
      1, 0, 0, 0, cosf(rx), -sinf(rx), 0, sinf(rx), cosf(rx),
  };
  matrix3_mul_3fo(m, v, result);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotatex_3fo>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movss  D6(%rip),%xmm1
  movss  %xmm0,0xc(%rsp)
  movaps %xmm1,0x10(%rsp)
  call   <cosf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x20(%rsp)
  call   <sinf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  movl   $0x0,0x28(%rsp)
  neg    %eax
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x24(%rsp)
  call   <sinf@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x2c(%rsp)
  call   <cosf@plt>
  pxor   %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %rbp,%rsi
  cvtsi2ss %eax,%xmm0
  lea    0x10(%rsp),%rdi
  movss  %xmm0,0x30(%rsp)
  call   <matrix3_mul_3fo@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void rotatex_3fo(float rx, const float *v, float *result) {
  float m[] = {
      1, 0, 0, 0, cosf(rx), -sinf(rx), 0, sinf(rx), cosf(rx),
  };
  matrix3_mul_3fo(m, v, result);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x12,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    $0xf,%eax
  cmp    $0x1,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  union {
    unsigned char ch;
    struct {
      unsigned char bf1 : 4, bf2 : 4;
    } bf;
  } u;
  u.ch = 0x12;
  return (u.bf.bf1 == 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  union {
    unsigned char ch;
    struct {
      unsigned char bf1 : 4, bf2 : 4;
    } bf;
  } u;
  u.ch = 0x12;
  return (u.bf.bf1 == 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  union {
    unsigned char ch;
    struct {
      unsigned char bf1 : 4, bf2 : 4;
    } bf;
  } u;
  u.ch = 0x12;
  return (u.bf.bf1 == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  union {
    unsigned char ch;
    struct {
      unsigned char bf1 : 4, bf2 : 4;
    } bf;
  } u;
  u.ch = 0x12;
  return (u.bf.bf1 == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cubes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L56
L33:
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L37
  cmp    $0x5,%eax
  je     L41
  jmp    L51
L37:
  add    $0x1,%r13d
  jmp    L51
L41:
  add    $0x1,%r12d
  nop
L51:
  add    $0x1,%ebx
L56:
  cmp    $0x1,%ebx
  jle    L33
  mov    %r13d,%eax
  shl    $0x2,%eax
  add    %r13d,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    %r12d,%eax
  shl    $0x2,%eax
  add    %r12d,%eax
  add    %edx,%eax
  add    %eax,%r14d
  mov    %r14d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
cubes(top) int top[];
{
  register k, s = 0, n1 = 0, n5 = 0;
  for (k = 0; k < 2; k++) {
    switch (top[k]) {
    case 1:
      n1++;
      break;
    case 5:
      n5++;
      break;
    }
  }
  s += 10 * n1 + 5 * n5;
  return (s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cubes>:
  endbr64
  mov    (%rdi),%eax
  mov    $0x0,%edx
  cmp    $0x1,%eax
  je     L16
  cmp    $0x5,%eax
  sete   %dl
  movzbl %dl,%edx
  mov    $0x0,%eax
L16:
  mov    0x4(%rdi),%ecx
  cmp    $0x1,%ecx
  je     L26
  cmp    $0x5,%ecx
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
L9:
  lea    (%rax,%rax,4),%ecx
  lea    (%rdx,%rdx,4),%eax
  lea    (%rax,%rcx,2),%eax
  ret
L26:
  add    $0x1,%eax
  jmp    L9
```

assistant: ```c
cubes(top) int top[];
{
  register k, s = 0, n1 = 0, n5 = 0;
  for (k = 0; k < 2; k++) {
    switch (top[k]) {
    case 1:
      n1++;
      break;
    case 5:
      n5++;
      break;
    }
  }
  s += 10 * n1 + 5 * n5;
  return (s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cubes>:
  endbr64
  mov    (%rdi),%eax
  xor    %edx,%edx
  cmp    $0x1,%eax
  je     L10
  xor    %edx,%edx
  cmp    $0x5,%eax
  sete   %dl
  xor    %eax,%eax
L10:
  mov    0x4(%rdi),%ecx
  cmp    $0x1,%ecx
  je     L12
  cmp    $0x5,%ecx
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  lea    (%rax,%rax,4),%ecx
  lea    (%rdx,%rdx,4),%eax
  lea    (%rax,%rcx,2),%eax
  ret
  nopl   0x0(%rax)
L12:
  add    $0x1,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rdx,%rdx,4),%eax
  lea    (%rax,%rcx,2),%eax
  ret
```

assistant: ```c
cubes(top) int top[];
{
  register k, s = 0, n1 = 0, n5 = 0;
  for (k = 0; k < 2; k++) {
    switch (top[k]) {
    case 1:
      n1++;
      break;
    case 5:
      n5++;
      break;
    }
  }
  s += 10 * n1 + 5 * n5;
  return (s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cubes>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x1,%eax
  je     L44
  cmp    $0x5,%eax
  jne    L0
  mov    $0xa,%ecx
  mov    $0xf,%esi
L27:
  mov    0x4(%rdi),%edx
  cmp    $0x1,%edx
  je     L23
L18:
  cmp    $0x5,%edx
  cmove  %ecx,%eax
  ret
  nopl   0x0(%rax)
L0:
  mov    0x4(%rdi),%edx
  xor    %eax,%eax
  mov    $0x5,%ecx
  mov    $0xa,%esi
  cmp    $0x1,%edx
  jne    L18
L23:
  mov    %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    $0xa,%eax
  mov    $0xf,%ecx
  mov    $0x14,%esi
  jmp    L27
```

assistant: ```c
cubes(top) int top[];
{
  register k, s = 0, n1 = 0, n5 = 0;
  for (k = 0; k < 2; k++) {
    switch (top[k]) {
    case 1:
      n1++;
      break;
    case 5:
      n5++;
      break;
    }
  }
  s += 10 * n1 + 5 * n5;
  return (s);
}
```