ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <vboxCKeyDst@plt>
  mov    $0x0,%eax
  call   <vboxCConv@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  vboxCKeyDst();
  vboxCConv();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <vboxCKeyDst@plt>
  mov    $0x0,%eax
  call   <vboxCConv@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  vboxCKeyDst();
  vboxCConv();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <vboxCKeyDst@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <vboxCConv@plt>
```

assistant: ```c
void main(void) {
  vboxCKeyDst();
  vboxCConv();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <vboxCKeyDst@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <vboxCConv@plt>
```

assistant: ```c
void main(void) {
  vboxCKeyDst();
  vboxCConv();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ncfind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L25:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    -0xc(%rbp),%eax
  jmp    L23
L14:
  addq   $0x10,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L25
  mov    $0xffffffff,%eax
L23:
  leave
  ret
```

assistant: ```c
int ncfind(char **params, const char *key) {
  int i;
  char **p;
  for (i = 0, p = params; *p; p += 2, i++) {
    if (strcmp(key, *p) == 0)
      return i;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ncfind>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L19
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L25:
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L30
  add    $0x10,%rbx
  add    $0x1,%ebp
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L25
  mov    $0xffffffff,%ebp
L30:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    $0xffffffff,%ebp
  jmp    L30
```

assistant: ```c
int ncfind(char **params, const char *key) {
  int i;
  char **p;
  for (i = 0, p = params; *p; p += 2, i++) {
    if (strcmp(key, *p) == 0)
      return i;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ncfind>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L25:
  mov    0x10(%rbx),%rsi
  add    $0x10,%rbx
  add    $0x1,%r12d
  test   %rsi,%rsi
  je     L17
L19:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L25
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ncfind(char **params, const char *key) {
  int i;
  char **p;
  for (i = 0, p = params; *p; p += 2, i++) {
    if (strcmp(key, *p) == 0)
      return i;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ncfind>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x10(%rbx),%rsi
  add    $0x10,%rbx
  add    $0x1,%r12d
  test   %rsi,%rsi
  je     L4
L24:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int ncfind(char **params, const char *key) {
  int i;
  char **p;
  for (i = 0, p = params; *p; p += 2, i++) {
    if (strcmp(key, *p) == 0)
      return i;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncmp_diff_length_6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  cmp    $0x1,%eax
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string

tool: D7: 234

tool: D15: 12345

assistant: ```c
void strncmp_diff_length_6() {
  char *x = "234";
  char *y = "12345";
  if (strncmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncmp_diff_length_6>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D14(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <strncmp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D14: 12345

tool: D5: 234

assistant: ```c
void strncmp_diff_length_6() {
  char *x = "234";
  char *y = "12345";
  if (strncmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncmp_diff_length_6>:
  endbr64
  mov    $0x3,%edx
  lea    D2(%rip),%rsi
  lea    D18(%rip),%rdi
  jmp    1050 <strncmp@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D2: 12345

tool: D18: 234

assistant: ```c
void strncmp_diff_length_6() {
  char *x = "234";
  char *y = "12345";
  if (strncmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp_diff_length_6>:
  endbr64
  mov    $0x3,%edx
  lea    D14(%rip),%rsi
  lea    D15(%rip),%rdi
  jmp    1050 <strncmp@plt>
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D14: 12345

tool: D15: 234

assistant: ```c
void strncmp_diff_length_6() {
  char *x = "234";
  char *y = "12345";
  if (strncmp(x, y, 3) != 1)
    (void)*(char *)0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <s5l_uart_send_char@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int putchar(int c) {
  s5l_uart_send_char(c);
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<putchar>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <s5l_uart_send_char@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int putchar(int c) {
  s5l_uart_send_char(c);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putchar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <s5l_uart_send_char@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int putchar(int c) {
  s5l_uart_send_char(c);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<putchar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <s5l_uart_send_char@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int putchar(int c) {
  s5l_uart_send_char(c);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L43
L59:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L53
L15:
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpl   $0xa,-0x20(%rbp)
  jle    L25
  addl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  add    %eax,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x30(%rbp)
L53:
  mov    -0x30(%rbp),%eax
  test   %eax,%eax
  jne    L15
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x24(%rbp)
L43:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L59
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D11: %d

tool: D25: %d


assistant: ```c
int main() {
  int num, testcases, rem;
  int i = 1;
  scanf("%d", &testcases);
  int result, sum = 0, carry = 0, lastDigit = 0, value = 0, temp_sum = 0, rem2;
  int multiplier = 1;
  while (testcases--) {
    scanf("%d", &num);
    while (num != 0) {
      rem = (num % 10);
      lastDigit = rem + 1 + carry;
      carry = 0;
      if (lastDigit > 10) {
        carry++;
        lastDigit = 0;
      }
      sum = sum + (lastDigit)*multiplier;
      multiplier = multiplier * 10;
      num = num / 10;
    }
    printf("%d\n", sum);
    sum = 0;
    lastDigit = 0;
    multiplier = 1;
    carry = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L79
  lea    D6(%rip),%r12
  mov    $0x0,%ebx
  lea    D21(%rip),%rbp
  jmp    L47
L21:
  mov    %ebx,(%rsp)
L67:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L79
L47:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    %esi,%r8d
  test   %esi,%esi
  je     L67
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  mov    $0x1,%ecx
  mov    $0x0,%r8d
  mov    %ebx,%edi
  mov    $0x1,%r9d
L39:
  imul   %ecx,%eax
  add    %eax,%r8d
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%esi
  je     L21
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rdi,%rax,1),%eax
  mov    %ebx,%edi
  cmp    $0xa,%eax
  jle    L39
  mov    %ebx,%eax
  mov    %r9d,%edi
  jmp    L39
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string

tool: D6: %d

tool: D21: %d


assistant: ```c
int main() {
  int num, testcases, rem;
  int i = 1;
  scanf("%d", &testcases);
  int result, sum = 0, carry = 0, lastDigit = 0, value = 0, temp_sum = 0, rem2;
  int multiplier = 1;
  while (testcases--) {
    scanf("%d", &num);
    while (num != 0) {
      rem = (num % 10);
      lastDigit = rem + 1 + carry;
      carry = 0;
      if (lastDigit > 10) {
        carry++;
        lastDigit = 0;
      }
      sum = sum + (lastDigit)*multiplier;
      multiplier = multiplier * 10;
      num = num / 10;
    }
    printf("%d\n", sum);
    sum = 0;
    lastDigit = 0;
    multiplier = 1;
    carry = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L22
  nopl   0x0(%rax)
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L44
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L45:
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x1,%eax
  imul   %ecx,%eax
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  add    %eax,%r8d
  mov    %edx,%eax
  test   %edx,%edx
  jne    L45
  movl   $0x0,(%rsp)
L25:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L14
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L44:
  xor    %r8d,%r8d
  jmp    L25
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D10: %d


tool: D18: %d

assistant: ```c
int main() {
  int num, testcases, rem;
  int i = 1;
  scanf("%d", &testcases);
  int result, sum = 0, carry = 0, lastDigit = 0, value = 0, temp_sum = 0, rem2;
  int multiplier = 1;
  while (testcases--) {
    scanf("%d", &num);
    while (num != 0) {
      rem = (num % 10);
      lastDigit = rem + 1 + carry;
      carry = 0;
      if (lastDigit > 10) {
        carry++;
        lastDigit = 0;
      }
      sum = sum + (lastDigit)*multiplier;
      multiplier = multiplier * 10;
      num = num / 10;
    }
    printf("%d\n", sum);
    sum = 0;
    lastDigit = 0;
    multiplier = 1;
    carry = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  lea    D10(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L52
  nopl   0x0(%rax)
L13:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L12
  mov    $0x1,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L37:
  movslq %eax,%rdx
  mov    %eax,%esi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%eax
  add    $0x1,%eax
  imul   %ecx,%eax
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  add    %eax,%r8d
  mov    %edx,%eax
  test   %edx,%edx
  jne    L37
  movl   $0x0,(%rsp)
L55:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L13
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  xor    %r8d,%r8d
  jmp    L55
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string

tool: D16: %d


tool: D10: %d

assistant: ```c
int main() {
  int num, testcases, rem;
  int i = 1;
  scanf("%d", &testcases);
  int result, sum = 0, carry = 0, lastDigit = 0, value = 0, temp_sum = 0, rem2;
  int multiplier = 1;
  while (testcases--) {
    scanf("%d", &num);
    while (num != 0) {
      rem = (num % 10);
      lastDigit = rem + 1 + carry;
      carry = 0;
      if (lastDigit > 10) {
        carry++;
        lastDigit = 0;
      }
      sum = sum + (lastDigit)*multiplier;
      multiplier = multiplier * 10;
      num = num / 10;
    }
    printf("%d\n", sum);
    sum = 0;
    lastDigit = 0;
    multiplier = 1;
    carry = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arm_str2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L41
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L41
L28:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  cmpl   $0x0,-0x4(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  neg    %eax
  jmp    L26
L24:
  mov    -0xc(%rbp),%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int arm_str2int(char *src) {
  int val = 0, pos = 0, minus = 0;
  if (src[pos] == '-') {
    minus = 1;
    pos++;
  }
  while (src[pos]) {
    val = 10 * val + (src[pos] - '0');
    pos++;
  }
  return (minus) ? -val : val;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<arm_str2int>:
  endbr64
  movzbl (%rdi),%ecx
  cmp    $0x2d,%cl
  sete   %al
  movzbl %al,%eax
  add    %rax,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
  mov    $0x0,%edx
L4:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L28:
  mov    %edx,%eax
  neg    %eax
  cmp    $0x2d,%cl
  cmove  %eax,%edx
  mov    %edx,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L28
```

assistant: ```c
int arm_str2int(char *src) {
  int val = 0, pos = 0, minus = 0;
  if (src[pos] == '-') {
    minus = 1;
    pos++;
  }
  while (src[pos]) {
    val = 10 * val + (src[pos] - '0');
    pos++;
  }
  return (minus) ? -val : val;
}
```
user: What is the c source code of the assembly code below:

```asm
<arm_str2int>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x2d,%cl
  sete   %al
  xor    %r8d,%r8d
  add    %rax,%rdi
  movsbl (%rdi),%eax
  test   %al,%al
  je     L5
  nopl   0x0(%rax)
L17:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L17
L5:
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x2d,%cl
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int arm_str2int(char *src) {
  int val = 0, pos = 0, minus = 0;
  if (src[pos] == '-') {
    minus = 1;
    pos++;
  }
  while (src[pos]) {
    val = 10 * val + (src[pos] - '0');
    pos++;
  }
  return (minus) ? -val : val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<arm_str2int>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x2d,%cl
  sete   %al
  xor    %r8d,%r8d
  add    %rax,%rdi
  movsbl (%rdi),%eax
  test   %al,%al
  je     L19
  nopl   0x0(%rax)
L9:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    -0x30(%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L9
L19:
  mov    %r8d,%eax
  neg    %eax
  cmp    $0x2d,%cl
  cmove  %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int arm_str2int(char *src) {
  int val = 0, pos = 0, minus = 0;
  if (src[pos] == '-') {
    minus = 1;
    pos++;
  }
  while (src[pos]) {
    val = 10 * val + (src[pos] - '0');
    pos++;
  }
  return (minus) ? -val : val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x1,-0x24(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L32
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L74
L32:
  mov    $0x1,%eax
  jmp    L63
L74:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L45
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x40(%rbp),%rdx
  mov    (%rdx),%rdx
  cltq
  add    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L37
L45:
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L37:
  mov    -0x20(%rbp),%rax
  mov    $0x5c,%edx
  mov    $0x7c,%esi
  mov    %rax,%rdi
  call   <estrchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <smatch@plt>
  mov    %eax,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L105
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x7c,(%rax)
L105:
  cmpl   $0x0,-0x24(%rbp)
  je     L61
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L37
  jmp    L78
L61:
  nop
L78:
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L3:
  mov    -0x24(%rbp),%eax
L63:
  leave
  ret
```

assistant: ```c
int wmatch(char *wlist, const char **s2) {
  char *matchstr;
  char *strend;
  const char *matchbuf;
  char *bufend;
  int result = 1;
  if (!wlist || !*s2)
    return 1;
  matchbuf = *s2;
  matchstr = wlist;
  bufend = strchr(matchbuf, ' ');
  if (bufend == NULL)
    *s2 += strlen(*s2);
  else {
    *s2 = bufend;
    *bufend = '\0';
  }
  do {
    if ((strend = estrchr(matchstr, '|', '\\')) != NULL)
      *strend = '\0';
    result = smatch(matchstr, matchbuf);
    if (strend != NULL)
      *strend++ = '|';
    if (!result)
      break;
  } while ((matchstr = strend) != NULL);
  if (bufend != NULL)
    *bufend = ' ';
  return result;
}
```