ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skip_to_next_directive>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <input@plt>
  test   %eax,%eax
  je     L61
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  jmp    L181
L186:
  mov    $0x0,%eax
  call   <input@plt>
L196:
  test   %eax,%eax
  je     L61
L181:
  cmp    $0x20,%eax
  je     L186
  cmp    $0x9,%eax
  je     L186
  cmp    $0xa,%eax
  je     L64
  cmp    $0x2f,%eax
  je     L4
  cmp    $0x5c,%eax
  je     L155
  cmp    $0x23,%eax
  jne    L135
  test   %ebp,%ebp
  je     L110
L135:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %ebx,%ebp
  jmp    L196
L64:
  mov    $0x0,%eax
  call   <input@plt>
  mov    $0x0,%ebp
  jmp    L196
L4:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %ebx,%ebp
  cmp    $0x2a,%eax
  jne    L196
  mov    $0x0,%eax
  call   <skip_comment@plt>
  test   %rax,%rax
  je     L177
  mov    $0x0,%eax
  call   <input@plt>
  jmp    L196
L155:
  mov    $0x0,%eax
  call   <input@plt>
  cmp    $0xd,%eax
  je     L148
  test   %eax,%eax
  jne    L147
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L148:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %ebx,%ebp
  cmp    $0xa,%eax
  jne    L196
  mov    $0x0,%eax
  call   <input@plt>
  jmp    L196
L147:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %ebx,%ebp
  jmp    L196
L177:
  mov    $0x0,%eax
  jmp    L61
L110:
  mov    $0x23,%eax
  jmp    L61
```

assistant: ```c
int skip_to_next_directive() {
  int state = 0;
  int c;
  c = input();
  while (c != 0) {
    if (c == ' ' || c == '\t') {
      c = input();
    } else if (c == '\n') {
      state = 0;
      c = input();
    } else if (c == '/') {
      state = 1;
      if ((c = input()) == '*') {
        if (skip_comment() == 0) {
          return 0;
        }
        c = input();
      }
    } else if (c == '\\') {
      state = 1;
      if ((c = input()) == '\r') {
        if ((c = input()) == '\n') {
          c = input();
        }
      } else if (c != 0) {
        c = input();
      }
    } else if (c != '#' || state != 0) {
      state = 1;
      c = input();
    } else {
      break;
    }
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_to_next_directive>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <input@plt>
  test   %eax,%eax
  je     L75
  xor    %ebx,%ebx
  jmp    L4
  nopl   0x0(%rax)
L125:
  cmp    $0xa,%eax
  je     L132
  cmp    $0x2f,%eax
  je     L108
  cmp    $0x5c,%eax
  je     L70
  cmp    $0x23,%eax
  jne    L83
  test   %ebx,%ebx
  je     L101
L83:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
L150:
  test   %eax,%eax
  je     L75
L4:
  cmp    $0x20,%eax
  je     L119
  cmp    $0x9,%eax
  jne    L125
L119:
  xor    %eax,%eax
  call   <input@plt>
L173:
  test   %eax,%eax
  jne    L4
L75:
  xor    %eax,%eax
L11:
  pop    %rbx
  ret
  nopl   (%rax)
L132:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <input@plt>
  jmp    L150
  nopl   0x0(%rax,%rax,1)
L108:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
  cmp    $0x2a,%eax
  jne    L150
  xor    %eax,%eax
  call   <skip_comment@plt>
  test   %rax,%rax
  je     L75
  xor    %eax,%eax
  call   <input@plt>
  jmp    L173
  cs nopw 0x0(%rax,%rax,1)
L70:
  xor    %eax,%eax
  call   <input@plt>
  cmp    $0xd,%eax
  je     L15
  test   %eax,%eax
  jne    L83
  xor    %eax,%eax
  jmp    L11
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
  cmp    $0xa,%eax
  jne    L150
  jmp    L119
  nopw   0x0(%rax,%rax,1)
L101:
  mov    $0x23,%eax
  pop    %rbx
  ret
```

assistant: ```c
int skip_to_next_directive() {
  int state = 0;
  int c;
  c = input();
  while (c != 0) {
    if (c == ' ' || c == '\t') {
      c = input();
    } else if (c == '\n') {
      state = 0;
      c = input();
    } else if (c == '/') {
      state = 1;
      if ((c = input()) == '*') {
        if (skip_comment() == 0) {
          return 0;
        }
        c = input();
      }
    } else if (c == '\\') {
      state = 1;
      if ((c = input()) == '\r') {
        if ((c = input()) == '\n') {
          c = input();
        }
      } else if (c != 0) {
        c = input();
      }
    } else if (c != '#' || state != 0) {
      state = 1;
      c = input();
    } else {
      break;
    }
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_to_next_directive>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <input@plt>
  test   %eax,%eax
  je     L163
  xor    %ebx,%ebx
  jmp    L131
  nopl   0x0(%rax)
L84:
  cmp    $0xa,%eax
  je     L94
  cmp    $0x2f,%eax
  je     L16
  cmp    $0x5c,%eax
  je     L182
  cmp    $0x23,%eax
  jne    L171
  test   %ebx,%ebx
  je     L11
L171:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
L158:
  test   %eax,%eax
  je     L163
L131:
  cmp    $0x20,%eax
  je     L46
  cmp    $0x9,%eax
  jne    L84
L46:
  xor    %eax,%eax
  call   <input@plt>
L107:
  test   %eax,%eax
  jne    L131
L163:
  xor    %eax,%eax
L5:
  pop    %rbx
  ret
  nopl   (%rax)
L94:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <input@plt>
  jmp    L158
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
  cmp    $0x2a,%eax
  jne    L158
  xor    %eax,%eax
  call   <skip_comment@plt>
  test   %rax,%rax
  je     L163
  xor    %eax,%eax
  call   <input@plt>
  jmp    L107
  cs nopw 0x0(%rax,%rax,1)
L182:
  xor    %eax,%eax
  call   <input@plt>
  cmp    $0xd,%eax
  je     L167
  test   %eax,%eax
  jne    L171
  xor    %eax,%eax
  jmp    L5
  nopl   0x0(%rax)
L167:
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <input@plt>
  cmp    $0xa,%eax
  jne    L158
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x23,%eax
  pop    %rbx
  ret
```

assistant: ```c
int skip_to_next_directive() {
  int state = 0;
  int c;
  c = input();
  while (c != 0) {
    if (c == ' ' || c == '\t') {
      c = input();
    } else if (c == '\n') {
      state = 0;
      c = input();
    } else if (c == '/') {
      state = 1;
      if ((c = input()) == '*') {
        if (skip_comment() == 0) {
          return 0;
        }
        c = input();
      }
    } else if (c == '\\') {
      state = 1;
      if ((c = input()) == '\r') {
        if ((c = input()) == '\n') {
          c = input();
        }
      } else if (c != 0) {
        c = input();
      }
    } else if (c != '#' || state != 0) {
      state = 1;
      c = input();
    } else {
      break;
    }
  }
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stream_read_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
ssize_t stream_read_fd(void *cookie, void *buf, size_t size) {
  ssize_t nbytes;
  int fd;
  fd = *(int *)cookie;
  nbytes = read(fd, buf, size);
  return (nbytes);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stream_read_fd>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
ssize_t stream_read_fd(void *cookie, void *buf, size_t size) {
  ssize_t nbytes;
  int fd;
  fd = *(int *)cookie;
  nbytes = read(fd, buf, size);
  return (nbytes);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stream_read_fd>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t stream_read_fd(void *cookie, void *buf, size_t size) {
  ssize_t nbytes;
  int fd;
  fd = *(int *)cookie;
  nbytes = read(fd, buf, size);
  return (nbytes);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stream_read_fd>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <read@plt>
```

assistant: ```c
ssize_t stream_read_fd(void *cookie, void *buf, size_t size) {
  ssize_t nbytes;
  int fd;
  fd = *(int *)cookie;
  nbytes = read(fd, buf, size);
  return (nbytes);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bee_tree_compare_key_default>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int bee_tree_compare_key_default(void *a, void *b) {
  assert(a);
  assert(b);
  return strcmp(a, b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bee_tree_compare_key_default>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int bee_tree_compare_key_default(void *a, void *b) {
  assert(a);
  assert(b);
  return strcmp(a, b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bee_tree_compare_key_default>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int bee_tree_compare_key_default(void *a, void *b) {
  assert(a);
  assert(b);
  return strcmp(a, b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bee_tree_compare_key_default>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int bee_tree_compare_key_default(void *a, void *b) {
  assert(a);
  assert(b);
  return strcmp(a, b);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<date_get_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int date_get_year(void) {
  time_t t;
  struct tm *lt;
  t = time(NULL);
  lt = localtime(&t);
  return lt->tm_year + 1900;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<date_get_year>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int date_get_year(void) {
  time_t t;
  struct tm *lt;
  t = time(NULL);
  lt = localtime(&t);
  return lt->tm_year + 1900;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<date_get_year>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int date_get_year(void) {
  time_t t;
  struct tm *lt;
  t = time(NULL);
  lt = localtime(&t);
  return lt->tm_year + 1900;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<date_get_year>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    (%rax),%eax
  add    $0x76c,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int date_get_year(void) {
  time_t t;
  struct tm *lt;
  t = time(NULL);
  lt = localtime(&t);
  return lt->tm_year + 1900;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L35
L42:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L26
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L26:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L4
  mov    -0x10(%rbp),%eax
  add    %eax,-0x8(%rbp)
L4:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x10(%rbp),%eax
  add    %eax,-0x4(%rbp)
L19:
  addl   $0x1,-0x10(%rbp)
L35:
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L42
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: %d


assistant: ```c
int main(void) {
  int i, m1 = 0, m2 = 0, m3 = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0) {
      m1 += i;
    }
    if (i % 5 == 0) {
      m2 += i;
    }
    if (i % 15 == 0) {
      m3 += i;
    }
  }
  printf("%d\n", m1 + m2 - m3);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  mov    $0x0,%esi
  mov    $0x0,%ecx
  mov    $0x0,%eax
L8:
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,2),%r8d
  lea    (%rcx,%rax,1),%edx
  cmp    %r8d,%eax
  cmove  %edx,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%r8d
  lea    (%rsi,%rax,1),%edx
  cmp    %r8d,%eax
  cmove  %edx,%esi
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  mov    %edx,%r8d
  shl    $0x4,%r8d
  sub    %edx,%r8d
  lea    (%rdi,%rax,1),%edx
  cmp    %r8d,%eax
  cmove  %edx,%edi
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L8
  add    %ecx,%esi
  sub    %edi,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %d


assistant: ```c
int main(void) {
  int i, m1 = 0, m2 = 0, m3 = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0) {
      m1 += i;
    }
    if (i % 5 == 0) {
      m2 += i;
    }
    if (i % 15 == 0) {
      m3 += i;
    }
  }
  printf("%d\n", m1 + m2 - m3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %edx,%edx
  xor    %eax,%eax
L7:
  imul   $0xaaaaaaab,%eax,%r8d
  lea    (%rdx,%rax,1),%edi
  cmp    $0x55555556,%r8d
  cmovb  %edi,%edx
  imul   $0xcccccccd,%eax,%r8d
  lea    (%rsi,%rax,1),%edi
  cmp    $0x33333334,%r8d
  cmovb  %edi,%esi
  imul   $0xeeeeeeef,%eax,%r8d
  lea    (%rcx,%rax,1),%edi
  cmp    $0x11111112,%r8d
  cmovb  %edi,%ecx
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L7
  add    %edx,%esi
  lea    D2(%rip),%rdi
  sub    %ecx,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: %d


assistant: ```c
int main(void) {
  int i, m1 = 0, m2 = 0, m3 = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0) {
      m1 += i;
    }
    if (i % 5 == 0) {
      m2 += i;
    }
    if (i % 15 == 0) {
      m3 += i;
    }
  }
  printf("%d\n", m1 + m2 - m3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %al,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x3130,-0xa(%rbp)
  movl   $0x7,-0x10(%rbp)
  jmp    L14
L2:
  movzbl -0x24(%rbp),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x10(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x11(%rbp),%eax
  and    %edx,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  cltq
  movzbl -0xa(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x10(%rbp)
L14:
  cmpl   $0x0,-0x10(%rbp)
  jns    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: %c

assistant: ```c
void print_bits(unsigned char value) {
  char bits[] = {'0', '1'};
  for (int bit = 7; bit >= 0; bit--) {
    unsigned char bit_val = value;
    bit_val &= (1 << bit);
    bit_val >>= bit;
    printf("%c", bits[bit_val]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_bits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x3130,0x6(%rsp)
  mov    $0x7,%ebx
  lea    D3(%rip),%r12
L18:
  mov    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  and    %ebp,%eax
  movzbl %al,%eax
  sar    %cl,%eax
  cltq
  movsbl 0x6(%rsp,%rax,1),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L18
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: %c

assistant: ```c
void print_bits(unsigned char value) {
  char bits[] = {'0', '1'};
  for (int bit = 7; bit >= 0; bit--) {
    unsigned char bit_val = value;
    bit_val &= (1 << bit);
    bit_val >>= bit;
    printf("%c", bits[bit_val]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_bits>:
  endbr64
  push   %r13
  mov    $0x7,%r13d
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3130,%eax
  mov    %ax,0x6(%rsp)
  nopl   0x0(%rax)
L17:
  mov    %r13d,%ecx
  mov    %ebp,%eax
  mov    %r12,%rdi
  shl    %cl,%eax
  and    %ebx,%eax
  movzbl %al,%eax
  sar    %cl,%eax
  cltq
  movsbl 0x6(%rsp,%rax,1),%esi
  call   <printf@plt>
  sub    $0x1,%r13d
  jae    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: %c

assistant: ```c
void print_bits(unsigned char value) {
  char bits[] = {'0', '1'};
  for (int bit = 7; bit >= 0; bit--) {
    unsigned char bit_val = value;
    bit_val &= (1 << bit);
    bit_val >>= bit;
    printf("%c", bits[bit_val]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_bits>:
  endbr64
  push   %r13
  mov    $0x7,%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x3130,%eax
  mov    %ax,0x6(%rsp)
  nopl   0x0(%rax)
L3:
  mov    %r13d,%ecx
  mov    %ebp,%eax
  mov    %r12,%rdi
  shl    %cl,%eax
  and    %ebx,%eax
  movzbl %al,%eax
  sar    %cl,%eax
  cltq
  movsbl 0x6(%rsp,%rax,1),%esi
  call   <printf@plt>
  sub    $0x1,%r13d
  jae    L3
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: %c

assistant: ```c
void print_bits(unsigned char value) {
  char bits[] = {'0', '1'};
  for (int bit = 7; bit >= 0; bit--) {
    unsigned char bit_val = value;
    bit_val &= (1 << bit);
    bit_val >>= bit;
    printf("%c", bits[bit_val]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_vprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x0,-0xc(%rbp)
  jns    L28
  mov    $0x0,%eax
  jmp    L3
L28:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
L19:
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *alloc_vprintf(const char *fmt, va_list arg) {
  va_list arg_copy;
  int len;
  char *str;
  va_copy(arg_copy, arg);
  len = vsnprintf(NULL, 0, fmt, arg_copy);
  va_end(arg_copy);
  if (len < 0)
    return NULL;
  len++;
  str = (char *)malloc(len);
  if (str != NULL)
    vsnprintf(str, len, fmt, arg);
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<alloc_vprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_copy@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%ebp
  test   %ebx,%ebx
  js     L23
  add    $0x1,%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L1
L23:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  jmp    L23
```

assistant: ```c
char *alloc_vprintf(const char *fmt, va_list arg) {
  va_list arg_copy;
  int len;
  char *str;
  va_copy(arg_copy, arg);
  len = vsnprintf(NULL, 0, fmt, arg_copy);
  va_end(arg_copy);
  if (len < 0)
    return NULL;
  len++;
  str = (char *)malloc(len);
  if (str != NULL)
    vsnprintf(str, len, fmt, arg);
  return str;
}
```