ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<i8254_write>:
  endbr64
  cmp    $0x2,%edx
  jbe    L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  shl    %cl,%edx
  lea    (%rdx,%rdi,1),%rbp
  movzbl %bl,%edi
  sub    $0x8,%rsp
  mov    %rbp,%rsi
  call   <outb@plt>
  add    $0x8,%rsp
  movzbl %bh,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void i8254_write(unsigned long base_address, unsigned int regshift, unsigned int counter_number, unsigned int count) {
  unsigned int byte;
  if (counter_number > 2)
    return;
  byte = count & 0xff;
  outb(byte, base_address + (counter_number << regshift));
  byte = (count >> 8) & 0xff;
  outb(byte, base_address + (counter_number << regshift));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i8254_write>:
  endbr64
  cmp    $0x2,%edx
  jbe    L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  mov    %esi,%ecx
  shl    %cl,%edx
  lea    (%rdx,%rdi,1),%rbp
  movzbl %bl,%edi
  sub    $0x8,%rsp
  mov    %rbp,%rsi
  call   <outb@plt>
  add    $0x8,%rsp
  movzbl %bh,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void i8254_write(unsigned long base_address, unsigned int regshift, unsigned int counter_number, unsigned int count) {
  unsigned int byte;
  if (counter_number > 2)
    return;
  byte = count & 0xff;
  outb(byte, base_address + (counter_number << regshift));
  byte = (count >> 8) & 0xff;
  outb(byte, base_address + (counter_number << regshift));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abms_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L45
  subq   $0x1,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L45
L20:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  subq   $0x1,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L20
  jmp    L45
L53:
  nop
L45:
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  cmpq   $0x0,-0x38(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L30:
  nop
L13:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L1:
  mov    -0x8(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t abms_strlcpy(char *dst, const char *src, size_t size) {
  char *dstptr = dst;
  size_t tocopy = size;
  const char *srcptr = src;
  if (tocopy && --tocopy) {
    do {
      if (!(*dstptr++ = *srcptr++))
        break;
    } while (--tocopy);
  }
  if (!tocopy) {
    if (size)
      *dstptr = 0;
    while (*srcptr++)
      ;
  }
  return (srcptr - src - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abms_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L26
  sub    $0x1,%rdx
  je     L35
  mov    %rsi,%rax
L65:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L63
  sub    $0x1,%rdx
  jne    L65
  jmp    L28
L26:
  mov    %rsi,%rax
L16:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
L45:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L35:
  mov    %rsi,%rax
L28:
  movb   $0x0,(%rdi)
  jmp    L16
L63:
  test   %rdx,%rdx
  jne    L45
  jmp    L28
```

assistant: ```c
size_t abms_strlcpy(char *dst, const char *src, size_t size) {
  char *dstptr = dst;
  size_t tocopy = size;
  const char *srcptr = src;
  if (tocopy && --tocopy) {
    do {
      if (!(*dstptr++ = *srcptr++))
        break;
    } while (--tocopy);
  }
  if (!tocopy) {
    if (size)
      *dstptr = 0;
    while (*srcptr++)
      ;
  }
  return (srcptr - src - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<abms_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L53
  cmp    $0x1,%rdx
  je     L10
  mov    %rdi,%rcx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L65
L26:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L43
L31:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L65:
  mov    %rcx,%rdi
L10:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L31
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L53
  jmp    L31
```

assistant: ```c
size_t abms_strlcpy(char *dst, const char *src, size_t size) {
  char *dstptr = dst;
  size_t tocopy = size;
  const char *srcptr = src;
  if (tocopy && --tocopy) {
    do {
      if (!(*dstptr++ = *srcptr++))
        break;
    } while (--tocopy);
  }
  if (!tocopy) {
    if (size)
      *dstptr = 0;
    while (*srcptr++)
      ;
  }
  return (srcptr - src - 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<abms_strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L3
  cmp    $0x1,%rdx
  je     L59
  mov    %rdi,%rcx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  je     L72
L2:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L37
L5:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   (%rax)
L72:
  mov    %rcx,%rdi
L59:
  movb   $0x0,(%rdi)
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L5
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
  jmp    L5
```

assistant: ```c
size_t abms_strlcpy(char *dst, const char *src, size_t size) {
  char *dstptr = dst;
  size_t tocopy = size;
  const char *srcptr = src;
  if (tocopy && --tocopy) {
    do {
      if (!(*dstptr++ = *srcptr++))
        break;
    } while (--tocopy);
  }
  if (!tocopy) {
    if (size)
      *dstptr = 0;
    while (*srcptr++)
      ;
  }
  return (srcptr - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L32
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L32
  mov    $0x1,%eax
  jmp    L36
L32:
  mov    $0x0,%eax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
extern int is_dir(char *dir) {
  struct stat info;
  return (stat(dir, &info) != -1 && S_ISDIR(info.st_mode));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  jne    L23
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  ret
L23:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L15
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(char *dir) {
  struct stat info;
  return (stat(dir, &info) != -1 && S_ISDIR(info.st_mode));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L7
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(char *dir) {
  struct stat info;
  return (stat(dir, &info) != -1 && S_ISDIR(info.st_mode));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_dir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L5
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern int is_dir(char *dir) {
  struct stat info;
  return (stat(dir, &info) != -1 && S_ISDIR(info.st_mode));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x24(%rbp)
  jg     L43
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L43:
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L23
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L24
L23:
  cmpq   $0x0,-0x10(%rbp)
  jne    L24
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <execl@plt>
  test   %rax,%rax
  jns    L24
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L21
L24:
  lea    -0x14(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <waitpid@plt>
  test   %rax,%rax
  jns    L42
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L21
L42:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <pr_exit@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: tag: D44
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: tag: D42
type_guessed: string

tool: D49: command-line argument required

tool: D44: fork error

tool: D22: execl error

tool: D45: waitpid error

tool: D42: status = %d


assistant: ```c
int main(int argc, char *argv[]) {
  int status;
  pid_t pid;
  if (argc < 2) {
    printf("command-line argument required\n");
    exit(0);
  }
  if ((pid = fork()) < 0) {
    printf("fork error\n");
    exit(0);
  } else if (pid == 0) {
    if (execl(argv[1], argv[1], (char *)0) < 0) {
      printf("execl error\n");
      return 0;
    }
  }
  if (waitpid(pid, &status, 0) < 0) {
    printf("waitpid error\n");
    return 0;
  }
  printf("status = %d\n", status);
  pr_exit(status);
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L2
L0:
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L75
  je     L47
L48:
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    %rbx,%rdi
  call   <waitpid@plt>
  test   %rax,%rax
  js     L96
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <pr_exit@plt>
  mov    $0x0,%edi
  call   <exit@plt>
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L0
L75:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L48
L47:
  mov    0x8(%rbp),%rdi
  mov    $0x0,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  test   %rax,%rax
  jns    L48
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L61
L96:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L61
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string
name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D23
datatype: string

tool: D3: status = %d


tool: D17: command-line argument required

tool: D8: fork error

tool: D6: execl error

tool: D23: waitpid error

assistant: ```c
int main(int argc, char *argv[]) {
  int status;
  pid_t pid;
  if (argc < 2) {
    printf("command-line argument required\n");
    exit(0);
  }
  if ((pid = fork()) < 0) {
    printf("fork error\n");
    exit(0);
  } else if (pid == 0) {
    if (execl(argv[1], argv[1], (char *)0) < 0) {
      printf("execl error\n");
      return 0;
    }
  }
  if (waitpid(pid, &status, 0) < 0) {
    printf("waitpid error\n");
    return 0;
  }
  printf("status = %d\n", status);
  pr_exit(status);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L92
L74:
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  js     L27
  je     L58
L39:
  xor    %edx,%edx
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <waitpid@plt>
  test   %rax,%rax
  js     L57
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <pr_exit@plt>
  xor    %edi,%edi
  call   <exit@plt>
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L58:
  mov    0x8(%rbx),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  test   %rax,%rax
  jns    L39
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L27:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L39
L92:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L74
L57:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L49
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string
name: unpack_data
arguments: data_label: D38
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string

tool: D27: status = %d


tool: D6: execl error

tool: D38: fork error

tool: D5: command-line argument required

tool: D16: waitpid error

assistant: ```c
int main(int argc, char *argv[]) {
  int status;
  pid_t pid;
  if (argc < 2) {
    printf("command-line argument required\n");
    exit(0);
  }
  if ((pid = fork()) < 0) {
    printf("fork error\n");
    exit(0);
  } else if (pid == 0) {
    if (execl(argv[1], argv[1], (char *)0) < 0) {
      printf("execl error\n");
      return 0;
    }
  }
  if (waitpid(pid, &status, 0) < 0) {
    printf("waitpid error\n");
    return 0;
  }
  printf("status = %d\n", status);
  pr_exit(status);
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L84
L65:
  xor    %eax,%eax
  call   <fork@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  js     L67
  je     L61
L72:
  xor    %edx,%edx
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <waitpid@plt>
  test   %rax,%rax
  js     L62
  mov    0x4(%rsp),%esi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <pr_exit@plt>
  xor    %edi,%edi
  call   <exit@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L61:
  mov    0x8(%rbx),%rdi
  xor    %edx,%edx
  mov    %rdi,%rsi
  call   <execl@plt>
  test   %rax,%rax
  jns    L72
  lea    D40(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L67:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L72
L84:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L65
L62:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
data_type: string
name: extract_symbolic_data
arguments: data_label: D40
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D42
data_type: string

tool: D48: status = %d


tool: D40: execl error

tool: D38: fork error

tool: D14: command-line argument required

tool: D42: waitpid error

assistant: ```c
int main(int argc, char *argv[]) {
  int status;
  pid_t pid;
  if (argc < 2) {
    printf("command-line argument required\n");
    exit(0);
  }
  if ((pid = fork()) < 0) {
    printf("fork error\n");
    exit(0);
  } else if (pid == 0) {
    if (execl(argv[1], argv[1], (char *)0) < 0) {
      printf("execl error\n");
      return 0;
    }
  }
  if (waitpid(pid, &status, 0) < 0) {
    printf("waitpid error\n");
    return 0;
  }
  printf("status = %d\n", status);
  pr_exit(status);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<matrix4MulMatf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  shl    $0x2,%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x3,-0x4(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x3,-0x8(%rbp)
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix4MulMatf(float *res, float *a, float *b) {
  for (int x = 0; x < 4; x++)
    for (int y = 0; y < 4; y++)
      res[(4 * x + y)] = a[(4 * 0 + y)] * b[(4 * x + 0)] + a[(4 * 1 + y)] * b[(4 * x + 1)] + a[(4 * 2 + y)] * b[(4 * x + 2)] + a[(4 * 3 + y)] * b[(4 * x + 3)];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<matrix4MulMatf>:
  endbr64
  mov    $0x0,%ecx
L12:
  mov    $0x0,%eax
L0:
  movss  (%rsi,%rax,1),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x10(%rsi,%rax,1),%xmm1
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rsi,%rax,1),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rsi,%rax,1),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L0
  add    $0x10,%rdx
  add    $0x4,%ecx
  add    $0x10,%rdi
  cmp    $0x10,%ecx
  jne    L12
  ret
```

assistant: ```c
void matrix4MulMatf(float *res, float *a, float *b) {
  for (int x = 0; x < 4; x++)
    for (int y = 0; y < 4; y++)
      res[(4 * x + y)] = a[(4 * 0 + y)] * b[(4 * x + 0)] + a[(4 * 1 + y)] * b[(4 * x + 1)] + a[(4 * 2 + y)] * b[(4 * x + 2)] + a[(4 * 3 + y)] * b[(4 * x + 3)];
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix4MulMatf>:
  endbr64
  xor    %ecx,%ecx
L15:
  xor    %eax,%eax
L4:
  movss  (%rsi,%rax,1),%xmm0
  movss  0x10(%rsi,%rax,1),%xmm1
  mulss  (%rdx),%xmm0
  mulss  0x4(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x20(%rsi,%rax,1),%xmm1
  mulss  0x8(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  0x30(%rsi,%rax,1),%xmm1
  mulss  0xc(%rdx),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L4
  add    $0x4,%ecx
  add    $0x10,%rdx
  add    $0x10,%rdi
  cmp    $0x10,%ecx
  jne    L15
  ret
```

assistant: ```c
void matrix4MulMatf(float *res, float *a, float *b) {
  for (int x = 0; x < 4; x++)
    for (int y = 0; y < 4; y++)
      res[(4 * x + y)] = a[(4 * 0 + y)] * b[(4 * x + 0)] + a[(4 * 1 + y)] * b[(4 * x + 1)] + a[(4 * 2 + y)] * b[(4 * x + 2)] + a[(4 * 3 + y)] * b[(4 * x + 3)];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<random_genes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L19:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xe,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0xf,-0x4(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void random_genes(char *arr) {
  for (int i = 0; i < 16; ++i) {
    arr[i] = (char)(rand() % 14);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<random_genes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x10(%rdi),%rbp
L2:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xe,%edx,%edx
  sub    %edx,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void random_genes(char *arr) {
  for (int i = 0; i < 16; ++i) {
    arr[i] = (char)(rand() % 14);
  }
}
```