ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x88(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x80(%rbp)
  jmp    L52
L49:
  mov    -0x88(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x90(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L10
  mov    -0x88(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x88(%rbp)
  movzbl (%rax),%edx
  mov    -0x80(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L0
L10:
  mov    -0x90(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x90(%rbp)
  movzbl (%rax),%edx
  mov    -0x80(%rbp),%rax
  mov    %dl,(%rax)
L0:
  addq   $0x1,-0x80(%rbp)
L52:
  mov    -0x88(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x90(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
L2:
  mov    -0x88(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L51
  nop
L27:
  mov    -0x88(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x88(%rbp)
  mov    -0x80(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x80(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  jmp    L17
L51:
  nop
L67:
  mov    -0x90(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x90(%rbp)
  mov    -0x80(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x80(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L67
L17:
  lea    -0x70(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
void fun(char *a, char *b) {
  char tmp[100], *p = a, *q;
  for (q = tmp; *a && *b; q++) {
    if (*a < *b)
      *q = *a++;
    else
      *q = *b++;
  }
  if (*a)
    for (; *q++ = *a++;)
      ;
  else
    for (; *q++ = *b++;)
      ;
  strcpy(p, tmp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fun>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  mov    %rdi,%r8
  mov    %rsp,%rdx
  test   %al,%al
  jne    L92
L49:
  mov    $0x0,%eax
L26:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L26
  jmp    L2
L44:
  add    $0x1,%rsi
  mov    %ecx,%eax
L77:
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%r8),%eax
  test   %al,%al
  je     L49
L92:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L10
  cmp    %al,%cl
  jle    L44
  add    $0x1,%r8
  jmp    L77
L10:
  test   %al,%al
  je     L49
  mov    $0x0,%eax
L18:
  movzbl (%r8,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L18
L2:
  mov    %rsp,%rsi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x78,%rsp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fun(char *a, char *b) {
  char tmp[100], *p = a, *q;
  for (q = tmp; *a && *b; q++) {
    if (*a < *b)
      *q = *a++;
    else
      *q = *b++;
  }
  if (*a)
    for (; *q++ = *a++;)
      ;
  else
    for (; *q++ = *b++;)
      ;
  strcpy(p, tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fun>:
  endbr64
  sub    $0x78,%rsp
  movzbl (%rdi),%edx
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  movzbl (%rsi),%eax
  mov    %r9,%rcx
  test   %dl,%dl
  jne    L42
  jmp    L104
  nopl   (%rax)
L48:
  add    $0x1,%r8
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  movzbl (%r8),%edx
  test   %dl,%dl
  je     L104
L42:
  test   %al,%al
  je     L9
  cmp    %al,%dl
  jl     L48
  mov    %eax,%edx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%r8),%edx
  test   %dl,%dl
  jne    L42
L104:
  xor    %edx,%edx
  jmp    L105
  cs nopw 0x0(%rax,%rax,1)
L91:
  movzbl (%rsi,%rdx,1),%eax
L105:
  mov    %al,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %al,%al
  jne    L91
L54:
  mov    %r9,%rsi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0x78,%rsp
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L81:
  movzbl (%r8,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L81
  jmp    L54
L82:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fun(char *a, char *b) {
  char tmp[100], *p = a, *q;
  for (q = tmp; *a && *b; q++) {
    if (*a < *b)
      *q = *a++;
    else
      *q = *b++;
  }
  if (*a)
    for (; *q++ = *a++;)
      ;
  else
    for (; *q++ = *b++;)
      ;
  strcpy(p, tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fun>:
  endbr64
  sub    $0x78,%rsp
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r10
  mov    %r10,%rax
  test   %cl,%cl
  je     L9
  nopl   0x0(%rax,%rax,1)
L82:
  test   %dl,%dl
  je     L69
L1:
  cmp    %dl,%cl
  jge    L45
  lea    0x1(%rdi),%r8
  movzbl 0x1(%rdi),%edi
  mov    %cl,(%rax)
  add    $0x1,%rax
  test   %dil,%dil
  je     L9
  mov    %edi,%ecx
  mov    %r8,%rdi
  test   %dl,%dl
  jne    L1
L69:
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L59:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L59
L62:
  mov    %r10,%rsi
  mov    %r9,%rdi
  call   <strcpy@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x78,%rsp
  ret
  nop
L45:
  mov    %dl,(%rax)
  add    $0x1,%rsi
  movzbl (%rsi),%edx
  add    $0x1,%rax
  jmp    L82
  nop
L9:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L60:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L60
  jmp    L62
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fun(char *a, char *b) {
  char tmp[100], *p = a, *q;
  for (q = tmp; *a && *b; q++) {
    if (*a < *b)
      *q = *a++;
    else
      *q = *b++;
  }
  if (*a)
    for (; *q++ = *a++;)
      ;
  else
    for (; *q++ = *b++;)
      ;
  strcpy(p, tmp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strndup_2_Bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6e49206f6c6c6548,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x21726566,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0x15(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x24(%rbp)
  movb   $0x0,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x15(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strndup@plt>
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L3
L19:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x61,(%rax)
  addl   $0x1,-0x28(%rbp)
L3:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void strndup_2_Bad() {
  char s1[] = "Hello Infer!";
  int len = strlen(s1);
  s1[5] = '\0';
  char *s2 = strndup(s1, len);
  for (int i = 0; i < len; i++) {
    s2[i] = 'a';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strndup_2_Bad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6e49206f6c6c6548,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x21726566,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  lea    0xb(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  movb   $0x0,0x10(%rsp)
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <strndup@plt>
  test   %ebx,%ebx
  jle    L13
  mov    %rax,%rdx
  lea    -0x1(%rbx),%ecx
  lea    0x1(%rax,%rcx,1),%rax
L14:
  movb   $0x61,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L14
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strndup_2_Bad() {
  char s1[] = "Hello Infer!";
  int len = strlen(s1);
  s1[5] = '\0';
  char *s2 = strndup(s1, len);
  for (int i = 0; i < len; i++) {
    s2[i] = 'a';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strndup_2_Bad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6e49206f6c6c6548,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x21726566,0x13(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x10(%rsp)
  mov    %eax,%ebx
  mov    %eax,%esi
  call   <strndup@plt>
  test   %ebx,%ebx
  jle    L2
  mov    %rax,%rdi
  movslq %ebx,%rdx
  mov    $0x61,%esi
  call   <memset@plt>
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strndup_2_Bad() {
  char s1[] = "Hello Infer!";
  int len = strlen(s1);
  s1[5] = '\0';
  char *s2 = strndup(s1, len);
  for (int i = 0; i < len; i++) {
    s2[i] = 'a';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strndup_2_Bad>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6e49206f6c6c6548,%rax
  lea    0xb(%rsp),%rbp
  movl   $0x21726566,0x13(%rsp)
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  mov    %rax,0xb(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x10(%rsp)
  mov    %eax,%ebx
  mov    %eax,%esi
  call   <strndup@plt>
  test   %ebx,%ebx
  jle    L7
  mov    %rax,%rdi
  movslq %ebx,%rdx
  mov    $0x61,%esi
  call   <memset@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strndup_2_Bad() {
  char s1[] = "Hello Infer!";
  int len = strlen(s1);
  s1[5] = '\0';
  char *s2 = strndup(s1, len);
  for (int i = 0; i < len; i++) {
    s2[i] = 'a';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vecswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  jmp    L8
L10:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %eax,%edi
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%r8
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <swap@plt>
L8:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void vecswap(char *base, size_t es, size_t i, size_t j, size_t n, size_t *index) {
  while (n--)
    swap(base, es, i++, j++, index);
}
```
user: Translate the below assembly code into C programming language:

```asm
<vecswap>:
  endbr64
  test   %r8,%r8
  je     L19
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %r9,%r15
  lea    (%rdx,%r8,1),%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  sub    %edx,%r12d
L4:
  lea    (%r12,%rbx,1),%ecx
  mov    %r15,%r8
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  ret
```

assistant: ```c
void vecswap(char *base, size_t es, size_t i, size_t j, size_t n, size_t *index) {
  while (n--)
    swap(base, es, i++, j++, index);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<vecswap>:
  endbr64
  test   %r8,%r8
  je     L8
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  sub    %edx,%r14d
  lea    (%rdx,%r8,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L0:
  lea    (%r14,%rbx,1),%ecx
  mov    %ebx,%edx
  mov    %r15,%r8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %r13,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void vecswap(char *base, size_t es, size_t i, size_t j, size_t n, size_t *index) {
  while (n--)
    swap(base, es, i++, j++, index);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vecswap>:
  endbr64
  test   %r8,%r8
  je     L10
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  sub    %edx,%r14d
  lea    (%rdx,%r8,1),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L7:
  lea    (%r14,%rbx,1),%ecx
  mov    %ebx,%edx
  mov    %r15,%r8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %r13,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L10:
  ret
```

assistant: ```c
void vecswap(char *base, size_t es, size_t i, size_t j, size_t n, size_t *index) {
  while (n--)
    swap(base, es, i++, j++, index);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isVerified>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x12(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  movl   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: qwerty123

assistant: ```c
int isVerified(char password[]) {
  int ok = 0;
  char buffer[10];
  strcpy(buffer, password);
  if (strcmp(buffer, "qwerty123") == 0)
    ok = 1;
  return ok;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isVerified>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string

tool: D9: qwerty123

assistant: ```c
int isVerified(char password[]) {
  int ok = 0;
  char buffer[10];
  strcpy(buffer, password);
  if (strcmp(buffer, "qwerty123") == 0)
    ok = 1;
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isVerified>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string

tool: D7: qwerty123

assistant: ```c
int isVerified(char password[]) {
  int ok = 0;
  char buffer[10];
  strcpy(buffer, password);
  if (strcmp(buffer, "qwerty123") == 0)
    ok = 1;
  return ok;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isVerified>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: qwerty123

assistant: ```c
int isVerified(char password[]) {
  int ok = 0;
  char buffer[10];
  strcpy(buffer, password);
  if (strcmp(buffer, "qwerty123") == 0)
    ok = 1;
  return ok;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ppp_get_codes_per_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x50(%rbp)
  movl   $0xffffffff,-0x4c(%rbp)
  movl   $0xb,-0x48(%rbp)
  movl   $0x8,-0x44(%rbp)
  movl   $0x7,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0x5,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x3,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  cmpl   $0x1,-0x54(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x10,-0x54(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x54(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int ppp_get_codes_per_row(const int codelength) {
  const int _len_to_codes[] = {
      -1, -1, 11, 8, 7, 5, 5, 4, 3, 3, 3, 2, 2, 2, 2, 2, 2,
  };
  assert(codelength >= 2);
  assert(codelength <= 16);
  return _len_to_codes[codelength];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ppp_get_codes_per_row>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  movl   $0xb,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x5,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0x3,0x28(%rsp)
  movl   $0x2,0x2c(%rsp)
  movl   $0x2,0x30(%rsp)
  movl   $0x2,0x34(%rsp)
  movl   $0x2,0x38(%rsp)
  movl   $0x2,0x3c(%rsp)
  movl   $0x2,0x40(%rsp)
  cmp    $0x1,%edi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    $0x10,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebx,%rbx
  mov    (%rsp,%rbx,4),%eax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x50,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ppp_get_codes_per_row(const int codelength) {
  const int _len_to_codes[] = {
      -1, -1, 11, 8, 7, 5, 5, 4, 3, 3, 3, 2, 2, 2, 2, 2, 2,
  };
  assert(codelength >= 2);
  assert(codelength <= 16);
  return _len_to_codes[codelength];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ppp_get_codes_per_row>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  xor    %edi,%edi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,(%rsp)
  movabs $0x80000000b,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000007,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x400000005,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x300000003,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x200000003,%rax
  mov    %rax,0x28(%rsp)
  sub    $0x1,%rax
  cmp    $0x1,%ebx
  setg   %dil
  mov    %rax,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  movl   $0x2,0x40(%rsp)
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x10,%ebx
  setle  %dil
  call   <assert@plt>
  mov    (%rsp,%rbx,4),%eax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x50,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ppp_get_codes_per_row(const int codelength) {
  const int _len_to_codes[] = {
      -1, -1, 11, 8, 7, 5, 5, 4, 3, 3, 3, 2, 2, 2, 2, 2, 2,
  };
  assert(codelength >= 2);
  assert(codelength <= 16);
  return _len_to_codes[codelength];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ppp_get_codes_per_row>:
  endbr64
  push   %rbx
  movslq %edi,%rbx
  xor    %edi,%edi
  sub    $0x50,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%ebx
  movl   $0x2,0x40(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D29(%rip),%xmm0
  setg   %dil
  movaps %xmm0,0x10(%rsp)
  movdqa D10(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D21(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x10,%ebx
  setle  %dil
  call   <assert@plt>
  mov    (%rsp,%rbx,4),%eax
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x50,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D29
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D10
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D21
data_type: byte[16]

tool: {"D26": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x0b,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D29": [0x07,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D10": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D21": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int ppp_get_codes_per_row(const int codelength) {
  const int _len_to_codes[] = {
      -1, -1, 11, 8, 7, 5, 5, 4, 3, 3, 3, 2, 2, 2, 2, 2, 2,
  };
  assert(codelength >= 2);
  assert(codelength <= 16);
  return _len_to_codes[codelength];
}
```