user: 这段汇编代码用C语言表示是什么样的?

```asm
<usart1_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x40021058,%eax
  mov    (%rax),%eax
  mov    $0x40021058,%edx
  or     $0x10000000,%eax
  mov    %eax,(%rdx)
  mov    $0x4002104c,%eax
  mov    (%rax),%eax
  mov    $0x4002104c,%edx
  or     $0x40,%eax
  mov    %eax,(%rdx)
  jmp    L17
L2:
  mov    $0x40007004,%eax
  mov    (%rax),%eax
  mov    $0x40007004,%edx
  or     $0x2,%ah
  mov    %eax,(%rdx)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <sleep_ms@plt>
L17:
  mov    $0x40007004,%eax
  mov    (%rax),%eax
  and    $0x200,%eax
  test   %eax,%eax
  je     L2
  mov    $0x4002104c,%eax
  mov    (%rax),%eax
  mov    $0x4002104c,%edx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  mov    $0x48001800,%eax
  mov    (%rax),%eax
  and    $0xffcfffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x48001800,%edx
  mov    -0x4(%rbp),%eax
  or     $0x200000,%eax
  mov    %eax,(%rdx)
  mov    $0x48000400,%eax
  mov    (%rax),%eax
  and    $0xcf,%ah
  mov    %eax,-0x4(%rbp)
  mov    $0x48000400,%edx
  mov    -0x4(%rbp),%eax
  or     $0x20,%ah
  mov    %eax,(%rdx)
  mov    $0x4800180c,%eax
  mov    (%rax),%eax
  and    $0x300000,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x4800040c,%eax
  mov    (%rax),%eax
  and    $0x3000,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x4800040c,%edx
  mov    -0x4(%rbp),%eax
  or     $0x10,%ah
  mov    %eax,(%rdx)
  mov    $0x48001824,%eax
  mov    (%rax),%eax
  and    $0xf0,%ah
  mov    %eax,-0x4(%rbp)
  mov    $0x48001824,%edx
  mov    -0x4(%rbp),%eax
  or     $0x7,%ah
  mov    %eax,(%rdx)
  mov    $0x48000420,%eax
  mov    (%rax),%eax
  and    $0xf0ffffff,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x48000420,%edx
  mov    -0x4(%rbp),%eax
  or     $0x7000000,%eax
  mov    %eax,(%rdx)
  mov    $0x40021060,%eax
  mov    (%rax),%eax
  mov    $0x40021060,%edx
  or     $0x40,%ah
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: Turning on VDDIO2


assistant: ```c
void usart1_init(void) {
  uint32_t reg;
  (*(volatile uint32_t *)((0x40021000UL) + 0x58)) |= (1 << 28);
  (*(volatile uint32_t *)((0x40021000UL) + 0x4C)) |= (1 << 6);
  while (((*(volatile uint32_t *)((0x40007000UL) + 0x04)) & (1 << 9)) == 0) {
    (*(volatile uint32_t *)((0x40007000UL) + 0x04)) |= (1 << 9);
    printf("Turning on VDDIO2\n");
    sleep_ms(1000);
  }
  (*(volatile uint32_t *)((0x40021000UL) + 0x4C)) |= (1 << 1);
  reg = (*((volatile uint32_t *)((0x48001800UL) + 0x00))) & ~(0x03 << ((10) * 2));
  (*((volatile uint32_t *)((0x48001800UL) + 0x00))) = reg | (0x02 << ((10) * 2));
  reg = (*((volatile uint32_t *)((0x48000400UL) + 0x00))) & ~(0x03 << ((6) * 2));
  (*((volatile uint32_t *)((0x48000400UL) + 0x00))) = reg | (0x02 << ((6) * 2));
  reg = (*((volatile uint32_t *)((0x48001800UL) + 0x0C))) & (0x03 << ((10) * 2));
  reg = (*((volatile uint32_t *)((0x48000400UL) + 0x0C))) & (0x03 << ((6) * 2));
  (*((volatile uint32_t *)((0x48000400UL) + 0x0C))) = reg | (0x01 << ((6) * 2));
  reg = (*((volatile uint32_t *)((0x48001800UL) + 0x24))) & ~(0xf << (((10) - 8) * 4));
  (*((volatile uint32_t *)((0x48001800UL) + 0x24))) = reg | (7 << (((10) - 8) * 4));
  reg = (*((volatile uint32_t *)((0x48000400UL) + 0x20))) & ~(0xf << (((6)) * 4));
  (*((volatile uint32_t *)((0x48000400UL) + 0x20))) = reg | (7 << (((6)) * 4));
  (*(volatile uint32_t *)((0x40021000UL) + 0x60)) |= (1 << 14);
}
```