ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_glp_lib_strspx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L18
L3:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L12
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L12:
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *_glp_lib_strspx(char *str) {
  char *s, *t;
  for (s = t = str; *s; s++)
    if (*s != ' ')
      *t++ = *s;
  *t = '\0';
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_glp_lib_strspx>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L27
  mov    %rdi,%rsi
  mov    %rdi,%rcx
  jmp    L0
L39:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L26
L0:
  cmp    $0x20,%dl
  je     L39
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%rsi
  jmp    L39
L27:
  mov    %rdi,%rsi
L26:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *_glp_lib_strspx(char *str) {
  char *s, *t;
  for (s = t = str; *s; s++)
    if (*s != ' ')
      *t++ = *s;
  *t = '\0';
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_glp_lib_strspx>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  mov    %rdi,%rsi
  test   %dl,%dl
  je     L14
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L11:
  cmp    $0x20,%dl
  je     L19
  mov    %dl,(%rsi)
  add    $0x1,%rsi
L19:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L11
L14:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
char *_glp_lib_strspx(char *str) {
  char *s, *t;
  for (s = t = str; *s; s++)
    if (*s != ' ')
      *t++ = *s;
  *t = '\0';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_glp_lib_strspx>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L41
  mov    %rdi,%rsi
  mov    %rdi,%rcx
L24:
  cmp    $0x20,%dl
  je     L37
L21:
  add    $0x1,%rcx
  mov    %dl,(%rsi)
  lea    0x1(%rsi),%r8
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L36
  mov    %r8,%rsi
  cmp    $0x20,%dl
  jne    L21
L37:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L24
  mov    %rsi,%r8
L36:
  movb   $0x0,(%r8)
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %rdi,%r8
  movb   $0x0,(%r8)
  ret
```

assistant: ```c
char *_glp_lib_strspx(char *str) {
  char *s, *t;
  for (s = t = str; *s; s++)
    if (*s != ' ')
      *t++ = *s;
  *t = '\0';
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dbg_write_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  shl    $0x10,%rax
  mov    %eax,%eax
  or     $0x201,%rax
  mov    %rax,%rdi
  call   <dbg_write@plt>
  jmp    L34
L28:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%edx
  cmpq   $0x1,-0x20(%rbp)
  jle    L2
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x10,%eax
  jmp    L33
L2:
  mov    $0x0,%eax
L33:
  or     %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <dbg_write@plt>
  addq   $0x4,-0x18(%rbp)
  subq   $0x2,-0x20(%rbp)
L34:
  cmpq   $0x0,-0x20(%rbp)
  jg     L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void dbg_write_u16(const unsigned short *val, long len) {
  unsigned long dcc_data;
  dbg_write((0x01 | ((2 & 0xff) << 8)) | ((len & 0xffff) << 16));
  while (len > 0) {
    dcc_data = val[0] | ((len > 1) ? val[1] << 16 : 0x0000);
    dbg_write(dcc_data);
    val += 2;
    len -= 2;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dbg_write_u16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  shl    $0x10,%rdi
  mov    %edi,%edi
  or     $0x201,%rdi
  call   <dbg_write@plt>
  test   %rbx,%rbx
  jle    L4
  mov    $0x0,%r12d
  jmp    L17
L9:
  or     %eax,%edi
  movslq %edi,%rdi
  call   <dbg_write@plt>
  add    $0x4,%rbp
  sub    $0x2,%rbx
  test   %rbx,%rbx
  jle    L4
L17:
  movzwl 0x0(%rbp),%edi
  mov    %r12d,%eax
  cmp    $0x1,%rbx
  jle    L9
  movzwl 0x2(%rbp),%eax
  shl    $0x10,%eax
  jmp    L9
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void dbg_write_u16(const unsigned short *val, long len) {
  unsigned long dcc_data;
  dbg_write((0x01 | ((2 & 0xff) << 8)) | ((len & 0xffff) << 16));
  while (len > 0) {
    dcc_data = val[0] | ((len > 1) ? val[1] << 16 : 0x0000);
    dbg_write(dcc_data);
    val += 2;
    len -= 2;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dbg_write_u16>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  shl    $0x10,%rdi
  mov    %rsi,%rbx
  mov    %edi,%edi
  or     $0x201,%rdi
  call   <dbg_write@plt>
  test   %rbx,%rbx
  jle    L28
  lea    -0x1(%rbx),%rax
  lea    -0x2(%rbx),%r12
  and    $0xfffffffffffffffe,%rax
  sub    %rax,%r12
  jmp    L32
  nopl   0x0(%rax)
L4:
  movslq 0x0(%rbp),%rdi
  sub    $0x2,%rbx
  add    $0x4,%rbp
  call   <dbg_write@plt>
  cmp    %r12,%rbx
  je     L28
L32:
  movzwl 0x0(%rbp),%edi
  cmp    $0x1,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <dbg_write@plt>
  nopl   0x0(%rax)
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void dbg_write_u16(const unsigned short *val, long len) {
  unsigned long dcc_data;
  dbg_write((0x01 | ((2 & 0xff) << 8)) | ((len & 0xffff) << 16));
  while (len > 0) {
    dcc_data = val[0] | ((len > 1) ? val[1] << 16 : 0x0000);
    dbg_write(dcc_data);
    val += 2;
    len -= 2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dbg_write_u16>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  shl    $0x10,%rdi
  mov    %rsi,%rbx
  mov    %edi,%edi
  or     $0x201,%rdi
  call   <dbg_write@plt>
  test   %rbx,%rbx
  jle    L37
  lea    -0x1(%rbx),%rax
  lea    -0x2(%rbx),%r12
  and    $0xfffffffffffffffe,%rax
  sub    %rax,%r12
  jmp    L21
  nopl   0x0(%rax)
L1:
  movslq 0x0(%rbp),%rdi
  sub    $0x2,%rbx
  add    $0x4,%rbp
  call   <dbg_write@plt>
  cmp    %r12,%rbx
  je     L37
L21:
  movzwl 0x0(%rbp),%edi
  cmp    $0x1,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <dbg_write@plt>
  nopl   0x0(%rax)
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void dbg_write_u16(const unsigned short *val, long len) {
  unsigned long dcc_data;
  dbg_write((0x01 | ((2 & 0xff) << 8)) | ((len & 0xffff) << 16));
  while (len > 0) {
    dcc_data = val[0] | ((len > 1) ? val[1] << 16 : 0x0000);
    dbg_write(dcc_data);
    val += 2;
    len -= 2;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <b@plt>
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <b@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: Done!


assistant: ```c
int main() {
  b();
  a();
  b();
  printf("Done!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <b@plt>
  mov    $0x0,%eax
  call   <a@plt>
  mov    $0x0,%eax
  call   <b@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: Done!


assistant: ```c
int main() {
  b();
  a();
  b();
  printf("Done!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <b@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <b@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: Done!


assistant: ```c
int main() {
  b();
  a();
  b();
  printf("Done!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <b@plt>
  xor    %eax,%eax
  call   <a@plt>
  xor    %eax,%eax
  call   <b@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: Done!


assistant: ```c
int main() {
  b();
  a();
  b();
  printf("Done!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x56000070,%eax
  mov    (%rax),%rax
  mov    $0x56000070,%edx
  or     $0xa0,%al
  mov    %rax,(%rdx)
  mov    $0x56000078,%eax
  movq   $0xc,(%rax)
  mov    $0x50000000,%eax
  movq   $0x3,(%rax)
  mov    $0x50000004,%eax
  movq   $0x5,(%rax)
  mov    $0x50000008,%eax
  movq   $0x0,(%rax)
  mov    $0x5000000c,%eax
  movq   $0x0,(%rax)
  mov    $0x50000028,%eax
  movq   $0xc,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uart_init(void) {
  (*(volatile unsigned long *)0x56000070) |= 0xa0;
  (*(volatile unsigned long *)0x56000078) = 0x0c;
  (*(volatile unsigned long *)0x50000000) = 0x03;
  (*(volatile unsigned long *)0x50000004) = 0x05;
  (*(volatile unsigned long *)0x50000008) = 0x00;
  (*(volatile unsigned long *)0x5000000c) = 0x00;
  (*(volatile unsigned long *)0x50000028) = ((12000000) / (57600 * 16) - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uart_init>:
  endbr64
  mov    0x56000070,%rax
  or     $0xa0,%al
  mov    %rax,0x56000070
  movq   $0xc,0x56000078
  movq   $0x3,0x50000000
  movq   $0x5,0x50000004
  movq   $0x0,0x50000008
  movq   $0x0,0x5000000c
  movq   $0xc,0x50000028
  ret
```

assistant: ```c
void uart_init(void) {
  (*(volatile unsigned long *)0x56000070) |= 0xa0;
  (*(volatile unsigned long *)0x56000078) = 0x0c;
  (*(volatile unsigned long *)0x50000000) = 0x03;
  (*(volatile unsigned long *)0x50000004) = 0x05;
  (*(volatile unsigned long *)0x50000008) = 0x00;
  (*(volatile unsigned long *)0x5000000c) = 0x00;
  (*(volatile unsigned long *)0x50000028) = ((12000000) / (57600 * 16) - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<uart_init>:
  endbr64
  mov    0x56000070,%rax
  or     $0xa0,%al
  mov    %rax,0x56000070
  movq   $0xc,0x56000078
  movq   $0x3,0x50000000
  movq   $0x5,0x50000004
  movq   $0x0,0x50000008
  movq   $0x0,0x5000000c
  movq   $0xc,0x50000028
  ret
```

assistant: ```c
void uart_init(void) {
  (*(volatile unsigned long *)0x56000070) |= 0xa0;
  (*(volatile unsigned long *)0x56000078) = 0x0c;
  (*(volatile unsigned long *)0x50000000) = 0x03;
  (*(volatile unsigned long *)0x50000004) = 0x05;
  (*(volatile unsigned long *)0x50000008) = 0x00;
  (*(volatile unsigned long *)0x5000000c) = 0x00;
  (*(volatile unsigned long *)0x50000028) = ((12000000) / (57600 * 16) - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uart_init>:
  endbr64
  mov    0x56000070,%rax
  or     $0xa0,%al
  mov    %rax,0x56000070
  movq   $0xc,0x56000078
  movq   $0x3,0x50000000
  movq   $0x5,0x50000004
  movq   $0x0,0x50000008
  movq   $0x0,0x5000000c
  movq   $0xc,0x50000028
  ret
```

assistant: ```c
void uart_init(void) {
  (*(volatile unsigned long *)0x56000070) |= 0xa0;
  (*(volatile unsigned long *)0x56000078) = 0x0c;
  (*(volatile unsigned long *)0x50000000) = 0x03;
  (*(volatile unsigned long *)0x50000004) = 0x05;
  (*(volatile unsigned long *)0x50000008) = 0x00;
  (*(volatile unsigned long *)0x5000000c) = 0x00;
  (*(volatile unsigned long *)0x50000028) = ((12000000) / (57600 * 16) - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ZBarcode_Encode_File_and_Print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ZBarcode_Encode_File@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x4,-0x8(%rbp)
  jle    L15
  mov    -0x8(%rbp),%eax
  jmp    L6
L15:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ZBarcode_Print@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int ZBarcode_Encode_File_and_Print(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  int first_err;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number >= 5) {
    return error_number;
  }
  first_err = error_number;
  error_number = ZBarcode_Print(symbol, rotate_angle);
  if (error_number == 0) {
    error_number = first_err;
  }
  return error_number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZBarcode_Encode_File_and_Print>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%r12d
  call   <ZBarcode_Encode_File@plt>
  mov    %eax,%ebx
  cmp    $0x4,%eax
  jle    L1
L9:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <ZBarcode_Print@plt>
  test   %eax,%eax
  cmovne %eax,%ebx
  jmp    L9
```

assistant: ```c
int ZBarcode_Encode_File_and_Print(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  int first_err;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number >= 5) {
    return error_number;
  }
  first_err = error_number;
  error_number = ZBarcode_Print(symbol, rotate_angle);
  if (error_number == 0) {
    error_number = first_err;
  }
  return error_number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ZBarcode_Encode_File_and_Print>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ZBarcode_Encode_File@plt>
  mov    %eax,%r12d
  cmp    $0x4,%eax
  jg     L4
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <ZBarcode_Print@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
L4:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ZBarcode_Encode_File_and_Print(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  int first_err;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number >= 5) {
    return error_number;
  }
  first_err = error_number;
  error_number = ZBarcode_Print(symbol, rotate_angle);
  if (error_number == 0) {
    error_number = first_err;
  }
  return error_number;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ZBarcode_Encode_File_and_Print>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ZBarcode_Encode_File@plt>
  mov    %eax,%r12d
  cmp    $0x4,%eax
  jg     L6
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <ZBarcode_Print@plt>
  test   %eax,%eax
  cmovne %eax,%r12d
L6:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ZBarcode_Encode_File_and_Print(struct zint_symbol *symbol, char *filename, int rotate_angle) {
  int error_number;
  int first_err;
  error_number = ZBarcode_Encode_File(symbol, filename);
  if (error_number >= 5) {
    return error_number;
  }
  first_err = error_number;
  error_number = ZBarcode_Print(symbol, rotate_angle);
  if (error_number == 0) {
    error_number = first_err;
  }
  return error_number;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<invmod2pow_ul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  xor    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x4(%rbp),%eax
  movzwl %ax,%eax
  imul   %eax,%edx
  movzwl -0x6(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movzwl %ax,%edx
  mov    -0x4(%rbp),%eax
  movzwl %ax,%eax
  imul   %eax,%edx
  movzwl -0x6(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int invmod2pow_ul(const unsigned int n) {
  unsigned int r;
  const unsigned short int in = (unsigned short int)n;
  r = (n + n + n) ^ ((unsigned int)2);
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - r * r * n;
  return r;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invmod2pow_ul>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  xor    $0x2,%eax
  movzwl %ax,%edx
  movzwl %di,%ecx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  movzwl %ax,%edx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edi,%edx
  add    %eax,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int invmod2pow_ul(const unsigned int n) {
  unsigned int r;
  const unsigned short int in = (unsigned short int)n;
  r = (n + n + n) ^ ((unsigned int)2);
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - r * r * n;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<invmod2pow_ul>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  movzwl %di,%ecx
  xor    $0x2,%eax
  movzwl %ax,%edx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  movzwl %ax,%edx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  add    %eax,%eax
  imul   %edi,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int invmod2pow_ul(const unsigned int n) {
  unsigned int r;
  const unsigned short int in = (unsigned short int)n;
  r = (n + n + n) ^ ((unsigned int)2);
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - r * r * n;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invmod2pow_ul>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  movzwl %di,%ecx
  xor    $0x2,%eax
  movzwl %ax,%edx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  movzwl %ax,%edx
  add    %eax,%eax
  imul   %edx,%edx
  imul   %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  add    %eax,%eax
  imul   %edi,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
unsigned int invmod2pow_ul(const unsigned int n) {
  unsigned int r;
  const unsigned short int in = (unsigned short int)n;
  r = (n + n + n) ^ ((unsigned int)2);
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - (unsigned short int)r * (unsigned short int)r * in;
  r += r - r * r * n;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__gnat_safe_getservbyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%r8
  mov    -0x48(%rbp),%rdi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <getservbyname_r@plt>
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L22
  mov    $0xffffffff,%eax
  jmp    L20
L22:
  mov    $0x0,%eax
L20:
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int __gnat_safe_getservbyname(const char *name, const char *proto, struct servent *ret, char *buf, size_t buflen) {
  struct servent *rh;
  int ri;
  (void)getservbyname_r(name, proto, ret, buf, buflen, &rh);
  ri = (rh == NULL) ? -1 : 0;
  return ri;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__gnat_safe_getservbyname>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  call   <getservbyname_r@plt>
  cmpq   $0x1,(%rsp)
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __gnat_safe_getservbyname(const char *name, const char *proto, struct servent *ret, char *buf, size_t buflen) {
  struct servent *rh;
  int ri;
  (void)getservbyname_r(name, proto, ret, buf, buflen, &rh);
  ri = (rh == NULL) ? -1 : 0;
  return ri;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__gnat_safe_getservbyname>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  call   <getservbyname_r@plt>
  cmpq   $0x1,(%rsp)
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __gnat_safe_getservbyname(const char *name, const char *proto, struct servent *ret, char *buf, size_t buflen) {
  struct servent *rh;
  int ri;
  (void)getservbyname_r(name, proto, ret, buf, buflen, &rh);
  ri = (rh == NULL) ? -1 : 0;
  return ri;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__gnat_safe_getservbyname>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  call   <getservbyname_r@plt>
  cmpq   $0x1,(%rsp)
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __gnat_safe_getservbyname(const char *name, const char *proto, struct servent *ret, char *buf, size_t buflen) {
  struct servent *rh;
  int ri;
  (void)getservbyname_r(name, proto, ret, buf, buflen, &rh);
  ri = (rh == NULL) ? -1 : 0;
  return ri;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<velobeta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  mov    %esi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x40(%rbp),%rbx
  mov    -0x48(%rbp),%r12
  mov    -0x50(%rbp),%r14
  mov    $0x0,%r13d
  jmp    L7
L4:
  movsd  (%rbx),%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  mov    %r14,%rax
  lea    0x4(%rax),%r14
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rbx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%r12
  add    $0x1,%r13d
L7:
  cmp    -0x2c(%rbp),%r13d
  jl     L4
  mov    $0x0,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: f64

tool: D4: 299792458

assistant: ```c
int velobeta(double dummy, int nvelo, int svelo, int sbeta, const double velo[], double beta[], int stat[]) {
  register int ivelo, *statp;
  register const double *velop;
  register double *betap;
  (void)dummy;
  velop = velo;
  betap = beta;
  statp = stat;
  for (ivelo = 0; ivelo < nvelo; ivelo++) {
    *betap = (*velop) / 2.99792458e8;
    *(statp++) = 0;
    velop += svelo;
    betap += sbeta;
  }
  return 0;
}
```