ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%ecx
  mov    $0x19,%edx
  mov    $0x9,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: Today's date is %i/%i/%.2i.


assistant: ```c
int main(void) {
  struct date {
    int month;
    int day;
    int year;
  };
  struct date today;
  today.month = 9;
  today.day = 25;
  today.year = 2015;
  printf("Today's date is %i/%i/%.2i.\n", today.month, today.day, today.year % 100);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%ecx
  mov    $0x19,%edx
  mov    $0x9,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: Today's date is %i/%i/%.2i.


assistant: ```c
int main(void) {
  struct date {
    int month;
    int day;
    int year;
  };
  struct date today;
  today.month = 9;
  today.day = 25;
  today.year = 2015;
  printf("Today's date is %i/%i/%.2i.\n", today.month, today.day, today.year % 100);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%ecx
  mov    $0x19,%edx
  mov    $0x9,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: Today's date is %i/%i/%.2i.


assistant: ```c
int main(void) {
  struct date {
    int month;
    int day;
    int year;
  };
  struct date today;
  today.month = 9;
  today.day = 25;
  today.year = 2015;
  printf("Today's date is %i/%i/%.2i.\n", today.month, today.day, today.year % 100);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseCmdString2ArgcArgv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    $0x0,%eax
  jmp    L82
L66:
  addq   $0x1,-0x18(%rbp)
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L66
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L23
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L45
  subl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x0,-0x4(%rbp)
  jns    L24
  jmp    L28
L45:
  nop
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cmdparse@plt>
  test   %rax,%rax
  jns    L51
  mov    $0x0,%eax
  jmp    L82
L51:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L100
  mov    $0x0,%eax
  jmp    L82
L100:
  mov    $0x1,%eax
L82:
  leave
  ret
```

assistant: ```c
int parseCmdString2ArgcArgv(char *cmdBuf, int *argc, char *argv[]) {
  int len;
  if (cmdBuf[0] == 0)
    return 0;
  while (*cmdBuf == ' ')
    cmdBuf++;
  len = strlen(cmdBuf) - 1;
  for (; len >= 0; len--) {
    if (cmdBuf[len] != ' ')
      break;
  }
  cmdBuf[len + 1] = '\0';
  if (cmdparse(cmdBuf, argv, argc) < 0)
    return 0;
  if (argv[0] == 0)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parseCmdString2ArgcArgv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbp
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L57
  mov    %rdi,%rbx
  mov    %rsi,%r12
  cmp    $0x20,%dl
  jne    L26
L48:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L48
L26:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L39
  movslq %eax,%rdx
  add    %rbx,%rdx
L42:
  cmpb   $0x20,(%rdx)
  jne    L39
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L42
L39:
  cltq
  movb   $0x0,0x1(%rbx,%rax,1)
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <cmdparse@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L57
  cmpq   $0x0,0x0(%rbp)
  setne  %al
  movzbl %al,%eax
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int parseCmdString2ArgcArgv(char *cmdBuf, int *argc, char *argv[]) {
  int len;
  if (cmdBuf[0] == 0)
    return 0;
  while (*cmdBuf == ' ')
    cmdBuf++;
  len = strlen(cmdBuf) - 1;
  for (; len >= 0; len--) {
    if (cmdBuf[len] != ' ')
      break;
  }
  cmdBuf[len + 1] = '\0';
  if (cmdparse(cmdBuf, argv, argc) < 0)
    return 0;
  if (argv[0] == 0)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parseCmdString2ArgcArgv>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L56
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x20,%al
  jne    L47
L4:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L4
L47:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L40
  movslq %edx,%rax
  add    %rbp,%rax
  jmp    L35
  nopl   0x0(%rax)
L79:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L13
L35:
  cmpb   $0x20,(%rax)
  mov    %rax,%rcx
  je     L79
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,1),%rcx
L13:
  movb   $0x0,(%rcx)
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <cmdparse@plt>
  test   %rax,%rax
  js     L46
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  pop    %rbx
  setne  %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  xor    %eax,%eax
  ret
L40:
  cltq
  lea    0x0(%rbp,%rax,1),%rcx
  jmp    L13
```

assistant: ```c
int parseCmdString2ArgcArgv(char *cmdBuf, int *argc, char *argv[]) {
  int len;
  if (cmdBuf[0] == 0)
    return 0;
  while (*cmdBuf == ' ')
    cmdBuf++;
  len = strlen(cmdBuf) - 1;
  for (; len >= 0; len--) {
    if (cmdBuf[len] != ' ')
      break;
  }
  cmdBuf[len + 1] = '\0';
  if (cmdparse(cmdBuf, argv, argc) < 0)
    return 0;
  if (argv[0] == 0)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parseCmdString2ArgcArgv>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L67
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cmp    $0x20,%al
  jne    L50
L23:
  add    $0x1,%rbp
  cmpb   $0x20,0x0(%rbp)
  je     L23
L50:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L80
  movslq %edx,%rax
  add    %rbp,%rax
  jmp    L17
  nopl   0x0(%rax)
L25:
  sub    $0x1,%edx
  sub    $0x1,%rax
  cmp    $0xffffffff,%edx
  je     L63
L17:
  cmpb   $0x20,(%rax)
  mov    %rax,%rcx
  je     L25
  add    $0x1,%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,1),%rcx
L63:
  movb   $0x0,(%rcx)
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <cmdparse@plt>
  test   %rax,%rax
  js     L21
  xor    %eax,%eax
  cmpq   $0x0,(%rbx)
  pop    %rbx
  setne  %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  ret
L80:
  cltq
  lea    0x0(%rbp,%rax,1),%rcx
  jmp    L63
```

assistant: ```c
int parseCmdString2ArgcArgv(char *cmdBuf, int *argc, char *argv[]) {
  int len;
  if (cmdBuf[0] == 0)
    return 0;
  while (*cmdBuf == ' ')
    cmdBuf++;
  len = strlen(cmdBuf) - 1;
  for (; len >= 0; len--) {
    if (cmdBuf[len] != ' ')
      break;
  }
  cmdBuf[len + 1] = '\0';
  if (cmdparse(cmdBuf, argv, argc) < 0)
    return 0;
  if (argv[0] == 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L5:
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L13
  mov    -0x4(%rbp),%eax
  jmp    L18
L13:
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L8:
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%eax
L18:
  leave
  ret
```

assistant: ```c
int write_socket(int fd, char *buf, int len) {
  int done, todo = len;
  while (todo) {
    done = write(fd, buf, todo);
    if (done <= 0)
      return (done);
    buf += done;
    todo -= done;
  }
  return (len);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_socket>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  je     L22
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L35:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L10
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L35
  jmp    L22
L10:
  mov    %eax,%r13d
L22:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_socket(int fd, char *buf, int len) {
  int done, todo = len;
  while (todo) {
    done = write(fd, buf, todo);
    if (done <= 0)
      return (done);
    buf += done;
    todo -= done;
  }
  return (len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_socket>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L6
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L17
  nop
L22:
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L6
L17:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L22
  mov    %eax,%r13d
L6:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_socket(int fd, char *buf, int len) {
  int done, todo = len;
  while (todo) {
    done = write(fd, buf, todo);
    if (done <= 0)
      return (done);
    buf += done;
    todo -= done;
  }
  return (len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_socket>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L19
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L2
  nop
L38:
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  je     L19
L2:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L38
  mov    %eax,%r13d
L19:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_socket(int fd, char *buf, int len) {
  int done, todo = len;
  while (todo) {
    done = write(fd, buf, todo);
    if (done <= 0)
      return (done);
    buf += done;
    todo -= done;
  }
  return (len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findbot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x1c(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <findbot_@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  sub    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void findbot(double a[], int na, int iord[], int nb) {
  int i;
  findbot_(a, &na, iord, &nb);
  for (i = 0; i < nb; i++)
    iord[i]--;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<findbot>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  mov    %rdx,%rbx
  mov    %ecx,0x8(%rsp)
  lea    0x8(%rsp),%rcx
  lea    0xc(%rsp),%rsi
  call   <findbot_@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L13
  mov    %rbx,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rbx,%rdx,4),%rdx
L7:
  subl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L7
L13:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void findbot(double a[], int na, int iord[], int nb) {
  int i;
  findbot_(a, &na, iord, &nb);
  for (i = 0; i < nb; i++)
    iord[i]--;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<findbot>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %ecx,0x8(%rsp)
  lea    0x8(%rsp),%rcx
  call   <findbot_@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L2
  sub    $0x1,%eax
  mov    %rbx,%rdx
  lea    0x4(%rbx,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L7:
  subl   $0x1,(%rdx)
  add    $0x4,%rdx
  cmp    %rax,%rdx
  jne    L7
L2:
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void findbot(double a[], int na, int iord[], int nb) {
  int i;
  findbot_(a, &na, iord, &nb);
  for (i = 0; i < nb; i++)
    iord[i]--;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findbot>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %ecx,0x8(%rsp)
  lea    0x8(%rsp),%rcx
  call   <findbot_@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L41
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L49
  mov    %edx,%ecx
  mov    %rbx,%rax
  pcmpeqd %xmm1,%xmm1
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rbx,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L48:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddd  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L48
  mov    %edx,%ecx
  and    $0xfffffffc,%ecx
  test   $0x3,%dl
  je     L41
L11:
  movslq %ecx,%rax
  lea    0x1(%rcx),%esi
  shl    $0x2,%rax
  subl   $0x1,(%rbx,%rax,1)
  cmp    %esi,%edx
  jle    L41
  add    $0x2,%ecx
  subl   $0x1,0x4(%rbx,%rax,1)
  cmp    %ecx,%edx
  jle    L41
  subl   $0x1,0x8(%rbx,%rax,1)
L41:
  add    $0x10,%rsp
  pop    %rbx
  ret
L49:
  xor    %ecx,%ecx
  jmp    L11
```

assistant: ```c
void findbot(double a[], int na, int iord[], int nb) {
  int i;
  findbot_(a, &na, iord, &nb);
  for (i = 0; i < nb; i++)
    iord[i]--;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L6:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L6
L8:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  if (s != NULL) {
    for (int i = 0; i < n; i++) {
      *(char *)s = c;
    }
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  mov    $0x0,%ecx
L14:
  add    $0x1,%ecx
  cmp    %edx,%ecx
  jne    L14
  mov    %sil,(%rax)
L3:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  if (s != NULL) {
    for (int i = 0; i < n; i++) {
      *(char *)s = c;
    }
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L1
  mov    %sil,(%rdi)
L1:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  if (s != NULL) {
    for (int i = 0; i < n; i++) {
      *(char *)s = c;
    }
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  mov    %sil,(%rdi)
L3:
  ret
```

assistant: ```c
void *memset(void *s, int c, size_t n) {
  if (s != NULL) {
    for (int i = 0; i < n; i++) {
      *(char *)s = c;
    }
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x7f0(%rbp),%eax
  cmp    $0x1f4,%eax
  jle    L26
  mov    $0xffffffff,%eax
  jmp    L10
L26:
  movl   $0x0,-0x7e4(%rbp)
  jmp    L4
L14:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e4(%rbp)
L4:
  mov    -0x7f0(%rbp),%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L14
  mov    -0x7f0(%rbp),%esi
  lea    -0x7e8(%rbp),%rcx
  lea    -0x7ec(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x7ec(%rbp),%edx
  mov    -0x7e8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D25
type: string

tool: D25: %d

assistant: ```c
int main() {
  int c, array[500], size, min, max;
  scanf("%d", &size);
  if (size > 500)
    return -1;
  for (c = 0; c < size; c++)
    scanf("%d", &array[c]);
  minmax(array, size, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1f4,%esi
  jg     L16
  test   %esi,%esi
  jle    L7
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D12(%rip),%r12
L45:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L45
L7:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  add    0x8(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L25:
  mov    0x7e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L25
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D12: %d

assistant: ```c
int main() {
  int c, array[500], size, min, max;
  scanf("%d", &size);
  if (size > 500)
    return -1;
  for (c = 0; c < size; c++)
    scanf("%d", &array[c]);
  minmax(array, size, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1f4,%esi
  jg     L43
  lea    0x10(%rsp),%r13
  xor    %ebx,%ebx
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L46
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L7
L46:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
L4:
  mov    0x7e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x7f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  or     $0xffffffff,%eax
  jmp    L4
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  int c, array[500], size, min, max;
  scanf("%d", &size);
  if (size > 500)
    return -1;
  for (c = 0; c < size; c++)
    scanf("%d", &array[c]);
  minmax(array, size, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1f4,%esi
  jg     L29
  lea    0x10(%rsp),%r13
  xor    %ebx,%ebx
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L15
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L3
L15:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r13,%rdi
  call   <minmax@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  add    0x8(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
L26:
  mov    0x7e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x7f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  or     $0xffffffff,%eax
  jmp    L26
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int main() {
  int c, array[500], size, min, max;
  scanf("%d", &size);
  if (size > 500)
    return -1;
  for (c = 0; c < size; c++)
    scanf("%d", &array[c]);
  minmax(array, size, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nurbs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  movsd  %xmm0,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L19:
  mov    -0x48(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x24(%rbp),%eax
  movq   %rdi,%xmm0
  mov    %eax,%edi
  mov    $0x1,%eax
  call   <bspline@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jb     L19
  movsd  -0x18(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double nurbs(unsigned int n, unsigned int p, const double tau[n + 1], const double coord[n + 1 - p], const double w[n + 1 - p], double x) {
  double sum = 0.;
  double nrm = 0.;
  for (unsigned int i = 0; i < n + 1 - p; i++) {
    double b = bspline(n, i, p, tau, x);
    sum += w[i] * coord[i] * b;
    nrm += w[i] * b;
  }
  return sum / nrm;
}
```