ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  shl    $0x7,%rax
  movabs $0x14df0e6d80,%rdx
  xor    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      copy12 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = copy12;
      copy12 = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << 7UL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movabs $0x14df0e6d80,%rdx
  mov    (%rdi),%rax
  shl    $0x7,%rax
  xor    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      copy12 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = copy12;
      copy12 = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << 7UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movabs $0x14df0e6d80,%rdx
  mov    (%rdi),%rax
  shl    $0x7,%rax
  xor    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  unsigned short copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      copy11 = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 0UL) {
      copy12 = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = *((unsigned short *)(&state[local1]) + 1);
      *((unsigned short *)(&state[local1]) + 1) = copy12;
      copy12 = *((unsigned short *)(&state[local1]) + 3);
      *((unsigned short *)(&state[local1]) + 3) = *((unsigned short *)(&state[local1]) + 2);
      *((unsigned short *)(&state[local1]) + 2) = copy12;
      local1 += 2UL;
    }
    output[0UL] = state[0UL] << 7UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L3:
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L5:
  cmpl   $0x2,-0xc(%rbp)
  jle    L3
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string

tool: D22: log2

tool: D19: # c::cephes::%s


tool: D0: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "log2");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
  lea    D24(%rip),%r12
  lea    D12(%rip),%rbp
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D7: log2

tool: D24: # c::cephes::%s


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "log2");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D15(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string

tool: D15: log2

tool: D2: # c::cephes::%s


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "log2");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D20(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D21
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string

tool: D20: log2

tool: D21: # c::cephes::%s


tool: D25: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::cephes::%s\n", "log2");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<plshift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void plshift(void *L, void *M, void *r) {
  void **l = L, **m = M;
  *l = *m, *m = r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<plshift>:
  endbr64
  mov    (%rsi),%rax
  mov    %rax,(%rdi)
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void plshift(void *L, void *M, void *r) {
  void **l = L, **m = M;
  *l = *m, *m = r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<plshift>:
  endbr64
  mov    (%rsi),%rax
  mov    %rax,(%rdi)
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void plshift(void *L, void *M, void *r) {
  void **l = L, **m = M;
  *l = *m, *m = r;
}
```
user: What is the c source code of the assembly code below?

```asm
<plshift>:
  endbr64
  mov    (%rsi),%rax
  mov    %rax,(%rdi)
  mov    %rdx,(%rsi)
  ret
```

assistant: ```c
void plshift(void *L, void *M, void *r) {
  void **l = L, **m = M;
  *l = *m, *m = r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wait_should_retry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L23
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L23
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L21
L23:
  mov    $0x1,%eax
  jmp    L16
L21:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
bool wait_should_retry(int error) {
  if (error == EINTR || error == EAGAIN || error == ENOMEM) {
    return true;
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wait_should_retry>:
  endbr64
  mov    $0x1,%eax
  mov    D16(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L9
  mov    D19(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L9
  mov    D20(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
bool wait_should_retry(int error) {
  if (error == EINTR || error == EAGAIN || error == ENOMEM) {
    return true;
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wait_should_retry>:
  endbr64
  mov    D5(%rip),%rdx
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L17
  mov    D2(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L17
  mov    D14(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L17:
  ret
```

assistant: ```c
bool wait_should_retry(int error) {
  if (error == EINTR || error == EAGAIN || error == ENOMEM) {
    return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait_should_retry>:
  endbr64
  mov    D17(%rip),%rdx
  mov    $0x1,%eax
  cmp    %edi,(%rdx)
  je     L17
  mov    D21(%rip),%rdx
  cmp    %edi,(%rdx)
  je     L17
  mov    D18(%rip),%rax
  cmp    %edi,(%rax)
  sete   %al
  movzbl %al,%eax
L17:
  ret
```

assistant: ```c
bool wait_should_retry(int error) {
  if (error == EINTR || error == EAGAIN || error == ENOMEM) {
    return true;
  }
  return false;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setbuf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L15
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <do_cmd@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  setbuf(stdout, NULL);
  for (i = 1; i < argc; i++) {
    do_cmd(argv[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x0,%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <setbuf@plt>
  cmp    $0x1,%ebp
  jle    L12
  lea    0x8(%r12),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x10(%r12,%rax,8),%rbp
L3:
  mov    (%rbx),%rdi
  call   <do_cmd@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L3
L12:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  setbuf(stdout, NULL);
  for (i = 1; i < argc; i++) {
    do_cmd(argv[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    D9(%rip),%rax
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edi
  call   <setbuf@plt>
  cmp    $0x1,%ebp
  jle    L11
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%rbp
  nop
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <do_cmd@plt>
  cmp    %rbp,%rbx
  jne    L17
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  setbuf(stdout, NULL);
  for (i = 1; i < argc; i++) {
    do_cmd(argv[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    D1(%rip),%rax
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edi
  call   <setbuf@plt>
  cmp    $0x1,%ebp
  jle    L0
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%rbp
  nop
L4:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <do_cmd@plt>
  cmp    %rbp,%rbx
  jne    L4
L0:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  setbuf(stdout, NULL);
  for (i = 1; i < argc; i++) {
    do_cmd(argv[i]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<drawLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L12:
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
data_type: string

tool: D4: 


assistant: ```c
void drawLine(int n, char c) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%c", c);
    ;
  }
  printf("\n\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<drawLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L19
  mov    %edi,%r12d
  mov    $0x0,%ebx
  movsbl %sil,%ebp
L15:
  mov    %ebp,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L15
L19:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string

tool: D0: 


assistant: ```c
void drawLine(int n, char c) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%c", c);
    ;
  }
  printf("\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<drawLine>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L17:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L17
  pop    %rbx
  lea    D19(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D19(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string

tool: D19: 


assistant: ```c
void drawLine(int n, char c) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%c", c);
    ;
  }
  printf("\n\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<drawLine>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L6:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L6
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D11(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: string

tool: D11: 


assistant: ```c
void drawLine(int n, char c) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%c", c);
    ;
  }
  printf("\n\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<get_next_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x808(%rsp)
  xor    %edx,%edx
  test   %rsi,%rsi
  je     L17
  mov    %edi,%ebp
  cmp    $0x2a,%edi
  ja     L17
  movslq %edi,%rax
  lea    D23(%rip),%rdx
  cmpq   $0x0,(%rdx,%rax,8)
  je     L104
L88:
  movslq %ebp,%rax
  lea    D23(%rip),%rdx
  lea    (%rdx,%rax,8),%r13
  mov    $0x1,%ebx
  mov    %rdx,%r12
L26:
  movslq %ebp,%rax
  mov    (%r12,%rax,8),%rdi
  call   <cs@plt>
  test   %ebx,%ebx
  je     L59
  cmp    $0xffffffff,%eax
  jne    L59
  lea    0x20(%rsp),%rsi
  mov    $0x7e1,%edx
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L15
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  movslq %ebp,%r14
  mov    (%r12,%r14,8),%rdi
  call   <ft_strdup@plt>
  mov    %rax,0x18(%rsp)
  mov    %r13,%rdi
  call   <ft_strdel@plt>
  lea    0x20(%rsp),%rsi
  mov    0x18(%rsp),%rdi
  call   <ft_strjoin@plt>
  mov    %rax,(%r12,%r14,8)
  lea    0x18(%rsp),%rdi
  call   <ft_strdel@plt>
  jmp    L26
L104:
  mov    $0x7e1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  movslq %ebp,%rax
  lea    D23(%rip),%rdx
  mov    %rdi,(%rdx,%rax,8)
  test   %rdi,%rdi
  je     L3
  mov    $0x7e1,%esi
  call   <ft_bzero@plt>
  jmp    L88
L59:
  lea    0x8(%rsp),%rdx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <processline@plt>
  mov    %eax,%ebx
L15:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %ebx,%eax
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    $0xffffffff,%ebx
  jmp    L15
L3:
  mov    $0xffffffff,%ebx
  jmp    L15
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_next_line(const int fd, char **line) {
  char buffer[2017 + 1];
  int ret;
  static char *str[42];
  char *swap;
  ret = 1;
  if (!line || fd > 42 || fd < 0 || 2017 < 1)
    return (-1);
  if (!str[fd]) {
    if (!(str[fd] = (char *)malloc(sizeof(char) * 2017)))
      return (-1);
    ft_bzero(str[fd], 2017);
  }
  while (cs(str[fd]) == -1 && ret) {
    if ((ret = read(fd, buffer, 2017)) == -1)
      return (-1);
    buffer[ret] = '\0';
    swap = ft_strdup(str[fd]);
    ft_strdel(&str[fd]);
    str[fd] = ft_strjoin(swap, buffer);
    ft_strdel(&swap);
  }
  return (processline(ret, &str[fd], &line));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x808(%rsp)
  xor    %edx,%edx
  test   %rsi,%rsi
  je     L41
  mov    %edi,%r14d
  cmp    $0x2a,%edi
  ja     L41
  lea    D5(%rip),%rbx
  movslq %edi,%r12
  mov    (%rbx,%r12,8),%rdi
  test   %rdi,%rdi
  je     L67
L6:
  lea    (%rbx,%r12,8),%r15
  mov    $0x1,%ebp
  lea    0x20(%rsp),%r13
  jmp    L25
  nopl   0x0(%rax)
L58:
  test   %ebp,%ebp
  je     L8
  mov    $0x7e1,%edx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L41
  mov    (%rbx,%r12,8),%rdi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  call   <ft_strdup@plt>
  mov    %r15,%rdi
  mov    %rax,0x18(%rsp)
  call   <ft_strdel@plt>
  mov    0x18(%rsp),%rdi
  mov    %r13,%rsi
  call   <ft_strjoin@plt>
  lea    0x18(%rsp),%rdi
  mov    %rax,(%rbx,%r12,8)
  call   <ft_strdel@plt>
  mov    (%rbx,%r12,8),%rdi
L25:
  call   <cs@plt>
  cmp    $0xffffffff,%eax
  je     L58
L8:
  lea    0x8(%rsp),%rdx
  mov    %r15,%rsi
  mov    %ebp,%edi
  call   <processline@plt>
L73:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L85
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L41:
  mov    $0xffffffff,%eax
  jmp    L73
  nop
L67:
  mov    $0x7e1,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx,%r12,8)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L41
  mov    $0x7e1,%esi
  call   <ft_bzero@plt>
  mov    (%rbx,%r12,8),%rdi
  jmp    L6
L85:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_next_line(const int fd, char **line) {
  char buffer[2017 + 1];
  int ret;
  static char *str[42];
  char *swap;
  ret = 1;
  if (!line || fd > 42 || fd < 0 || 2017 < 1)
    return (-1);
  if (!str[fd]) {
    if (!(str[fd] = (char *)malloc(sizeof(char) * 2017)))
      return (-1);
    ft_bzero(str[fd], 2017);
  }
  while (cs(str[fd]) == -1 && ret) {
    if ((ret = read(fd, buffer, 2017)) == -1)
      return (-1);
    buffer[ret] = '\0';
    swap = ft_strdup(str[fd]);
    ft_strdel(&str[fd]);
    str[fd] = ft_strjoin(swap, buffer);
    ft_strdel(&swap);
  }
  return (processline(ret, &str[fd], &line));
}
```