ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<HibernateClockConfig>:
  endbr64
  mov    0x400fc010,%rax
  and    $0x30000,%edi
  and    $0xfffffffffffcffff,%rax
  or     %rax,%rdi
  xor    %eax,%eax
  mov    %rdi,0x400fc010
  jmp    1050 <HibernateWriteComplete@plt>
```

assistant: ```c
void HibernateClockConfig(unsigned long ulConfig) {
  unsigned long ulHIBCtl;

  ;
  ulHIBCtl = (*((volatile unsigned long *)(0x400FC010)));
  ulHIBCtl &= ~(0x00020000 | 0x00000000 | 0x00010000);
  ulHIBCtl |= ulConfig & (0x00020000 | 0x00000000 | 0x00010000);
  (*((volatile unsigned long *)(0x400FC010))) = ulHIBCtl;
  HibernateWriteComplete();
}
```
user: What is the c source code of the assembly code below:

```asm
<HibernateClockConfig>:
  endbr64
  mov    0x400fc010,%rax
  and    $0x30000,%edi
  and    $0xfffffffffffcffff,%rax
  or     %rax,%rdi
  xor    %eax,%eax
  mov    %rdi,0x400fc010
  jmp    1050 <HibernateWriteComplete@plt>
```

assistant: ```c
void HibernateClockConfig(unsigned long ulConfig) {
  unsigned long ulHIBCtl;

  ;
  ulHIBCtl = (*((volatile unsigned long *)(0x400FC010)));
  ulHIBCtl &= ~(0x00020000 | 0x00000000 | 0x00010000);
  ulHIBCtl |= ulConfig & (0x00020000 | 0x00000000 | 0x00010000);
  (*((volatile unsigned long *)(0x400FC010))) = ulHIBCtl;
  HibernateWriteComplete();
}
```
user: Translate the below assembly code into C programming language:

```asm
<bz2_fclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <flush_outbuf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int bz2_fclose(void *stream) {
  flush_outbuf();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<bz2_fclose>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <flush_outbuf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bz2_fclose(void *stream) {
  flush_outbuf();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bz2_fclose>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <flush_outbuf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bz2_fclose(void *stream) {
  flush_outbuf();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bz2_fclose>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <flush_outbuf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bz2_fclose(void *stream) {
  flush_outbuf();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mpu6050_read_acc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe(%rbp),%rax
  mov    $0x6,%edx
  mov    %rax,%rsi
  mov    $0x3b,%edi
  call   <mpu6050_read@plt>
  movzbl -0xe(%rbp),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0xd(%rbp),%eax
  cbtw
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  movzbl -0xb(%rbp),%eax
  movsbw %al,%dx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  or     %ecx,%edx
  mov    %dx,(%rax)
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  movzbl -0x9(%rbp),%eax
  movsbw %al,%dx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  or     %ecx,%edx
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void mpu6050_read_acc(short int *pBuffer) {
  char acc_buffer[6];
  mpu6050_read(0x3B, acc_buffer, 6);
  pBuffer[0] = (int)((acc_buffer[0] << 8) | acc_buffer[1]);
  pBuffer[1] = (int)((acc_buffer[2] << 8) | acc_buffer[3]);
  pBuffer[2] = (int)((acc_buffer[4] << 8) | acc_buffer[5]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpu6050_read_acc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rsi
  mov    $0x6,%edx
  mov    $0x3b,%edi
  call   <mpu6050_read@plt>
  movsbl 0x2(%rsp),%edx
  shl    $0x8,%edx
  movsbw 0x3(%rsp),%ax
  or     %edx,%eax
  mov    %ax,(%rbx)
  movsbl 0x4(%rsp),%edx
  shl    $0x8,%edx
  movsbw 0x5(%rsp),%ax
  or     %edx,%eax
  mov    %ax,0x2(%rbx)
  movsbl 0x6(%rsp),%edx
  shl    $0x8,%edx
  movsbw 0x7(%rsp),%ax
  or     %edx,%eax
  mov    %ax,0x4(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mpu6050_read_acc(short int *pBuffer) {
  char acc_buffer[6];
  mpu6050_read(0x3B, acc_buffer, 6);
  pBuffer[0] = (int)((acc_buffer[0] << 8) | acc_buffer[1]);
  pBuffer[1] = (int)((acc_buffer[2] << 8) | acc_buffer[3]);
  pBuffer[2] = (int)((acc_buffer[4] << 8) | acc_buffer[5]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mpu6050_read_acc>:
  endbr64
  push   %rbx
  mov    $0x6,%edx
  mov    %rdi,%rbx
  mov    $0x3b,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rsi
  call   <mpu6050_read@plt>
  movsbl 0x2(%rsp),%edx
  movsbw 0x3(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  movsbl 0x4(%rsp),%edx
  mov    %ax,(%rbx)
  movsbw 0x5(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  movsbl 0x6(%rsp),%edx
  mov    %ax,0x2(%rbx)
  movsbw 0x7(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %ax,0x4(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mpu6050_read_acc(short int *pBuffer) {
  char acc_buffer[6];
  mpu6050_read(0x3B, acc_buffer, 6);
  pBuffer[0] = (int)((acc_buffer[0] << 8) | acc_buffer[1]);
  pBuffer[1] = (int)((acc_buffer[2] << 8) | acc_buffer[3]);
  pBuffer[2] = (int)((acc_buffer[4] << 8) | acc_buffer[5]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mpu6050_read_acc>:
  endbr64
  push   %rbx
  mov    $0x6,%edx
  mov    %rdi,%rbx
  mov    $0x3b,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rsi
  call   <mpu6050_read@plt>
  movsbl 0x2(%rsp),%edx
  movsbw 0x3(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  movsbl 0x4(%rsp),%edx
  mov    %ax,(%rbx)
  movsbw 0x5(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  movsbl 0x6(%rsp),%edx
  mov    %ax,0x2(%rbx)
  movsbw 0x7(%rsp),%ax
  shl    $0x8,%edx
  or     %edx,%eax
  mov    %ax,0x4(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mpu6050_read_acc(short int *pBuffer) {
  char acc_buffer[6];
  mpu6050_read(0x3B, acc_buffer, 6);
  pBuffer[0] = (int)((acc_buffer[0] << 8) | acc_buffer[1]);
  pBuffer[1] = (int)((acc_buffer[2] << 8) | acc_buffer[3]);
  pBuffer[2] = (int)((acc_buffer[4] << 8) | acc_buffer[5]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sn_do_sched_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L32
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L7:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <sn_send_asoc_msg@plt>
  addl   $0x1,-0x4(%rbp)
L31:
  cmpl   $0x2,-0x4(%rbp)
  jle    L7
  addl   $0x1,-0x8(%rbp)
L32:
  cmpl   $0x3,-0x8(%rbp)
  jle    L35
  nop
  leave
  ret
```

assistant: ```c
int sn_do_sched_tests(struct sn_context *snc) {
  int stream, count;
  for (stream = 1; stream < 4; stream++)
    for (count = 0; count < 3; count++)
      sn_send_asoc_msg(snc, 1024, stream, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sn_do_sched_tests>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x1,%ebp
  jmp    L19
L11:
  add    $0x1,%ebp
  cmp    $0x4,%ebp
  je     L37
L19:
  mov    $0x3,%ebx
L6:
  mov    $0x0,%ecx
  mov    %ebp,%edx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <sn_send_asoc_msg@plt>
  sub    $0x1,%ebx
  jne    L6
  jmp    L11
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sn_do_sched_tests(struct sn_context *snc) {
  int stream, count;
  for (stream = 1; stream < 4; stream++)
    for (count = 0; count < 3; count++)
      sn_send_asoc_msg(snc, 1024, stream, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sn_do_sched_tests>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L17:
  mov    $0x3,%ebx
L15:
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <sn_send_asoc_msg@plt>
  sub    $0x1,%ebx
  jne    L15
  add    $0x1,%ebp
  cmp    $0x4,%ebp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sn_do_sched_tests(struct sn_context *snc) {
  int stream, count;
  for (stream = 1; stream < 4; stream++)
    for (count = 0; count < 3; count++)
      sn_send_asoc_msg(snc, 1024, stream, 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sn_do_sched_tests>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
L2:
  mov    $0x3,%ebx
L12:
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <sn_send_asoc_msg@plt>
  sub    $0x1,%ebx
  jne    L12
  add    $0x1,%ebp
  cmp    $0x4,%ebp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int sn_do_sched_tests(struct sn_context *snc) {
  int stream, count;
  for (stream = 1; stream < 4; stream++)
    for (count = 0; count < 3; count++)
      sn_send_asoc_msg(snc, 1024, stream, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<Sound_Init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <DAC_Init@plt>
  mov    $0xe000e010,%eax
  movl   $0x0,(%rax)
  mov    $0xe000e014,%eax
  movl   $0x0,(%rax)
  mov    $0xe000e018,%eax
  movl   $0x0,(%rax)
  mov    $0xe000ed20,%eax
  mov    (%rax),%eax
  and    $0xffffff,%eax
  mov    %eax,%edx
  mov    $0xe000ed20,%eax
  or     $0x60000000,%edx
  mov    %edx,(%rax)
  mov    $0xe000e010,%eax
  movl   $0x7,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Sound_Init(void) {
  DAC_Init();
  (*((volatile uint32_t *)0xE000E010)) = 0;
  (*((volatile uint32_t *)0xE000E014)) = 0;
  (*((volatile uint32_t *)0xE000E018)) = 0;
  (*((volatile uint32_t *)0xE000ED20)) = ((*((volatile uint32_t *)0xE000ED20)) & 0x00FFFFFF) | 0x60000000;
  (*((volatile uint32_t *)0xE000E010)) = 0x0007;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Sound_Init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <DAC_Init@plt>
  mov    $0xe000e010,%edx
  movl   $0x0,(%rdx)
  mov    $0xe000e014,%eax
  movl   $0x0,(%rax)
  lea    0x4(%rax),%rax
  movl   $0x0,(%rax)
  mov    $0xe000ed20,%ecx
  mov    (%rcx),%eax
  and    $0xffffff,%eax
  or     $0x60000000,%eax
  mov    %eax,(%rcx)
  movl   $0x7,(%rdx)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Sound_Init(void) {
  DAC_Init();
  (*((volatile uint32_t *)0xE000E010)) = 0;
  (*((volatile uint32_t *)0xE000E014)) = 0;
  (*((volatile uint32_t *)0xE000E018)) = 0;
  (*((volatile uint32_t *)0xE000ED20)) = ((*((volatile uint32_t *)0xE000ED20)) & 0x00FFFFFF) | 0x60000000;
  (*((volatile uint32_t *)0xE000E010)) = 0x0007;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sound_Init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <DAC_Init@plt>
  mov    $0xe000e014,%eax
  mov    $0xe000e010,%edx
  mov    $0xe000ed20,%ecx
  movl   $0x0,(%rdx)
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rax)
  mov    (%rcx),%eax
  and    $0xffffff,%eax
  or     $0x60000000,%eax
  mov    %eax,(%rcx)
  movl   $0x7,(%rdx)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Sound_Init(void) {
  DAC_Init();
  (*((volatile uint32_t *)0xE000E010)) = 0;
  (*((volatile uint32_t *)0xE000E014)) = 0;
  (*((volatile uint32_t *)0xE000E018)) = 0;
  (*((volatile uint32_t *)0xE000ED20)) = ((*((volatile uint32_t *)0xE000ED20)) & 0x00FFFFFF) | 0x60000000;
  (*((volatile uint32_t *)0xE000E010)) = 0x0007;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sound_Init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <DAC_Init@plt>
  mov    $0xe000e014,%eax
  mov    $0xe000e010,%edx
  mov    $0xe000ed20,%ecx
  movl   $0x0,(%rdx)
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rax)
  mov    (%rcx),%eax
  and    $0xffffff,%eax
  or     $0x60000000,%eax
  mov    %eax,(%rcx)
  movl   $0x7,(%rdx)
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Sound_Init(void) {
  DAC_Init();
  (*((volatile uint32_t *)0xE000E010)) = 0;
  (*((volatile uint32_t *)0xE000E014)) = 0;
  (*((volatile uint32_t *)0xE000E018)) = 0;
  (*((volatile uint32_t *)0xE000ED20)) = ((*((volatile uint32_t *)0xE000ED20)) & 0x00FFFFFF) | 0x60000000;
  (*((volatile uint32_t *)0xE000E010)) = 0x0007;
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_dir_entries>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L79
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  lea    0x9(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    %rax,%rbx
  mov    %rax,%rbp
  cmpb   $0x2f,(%rax,%r13,1)
  jne    L9
L65:
  lea    0x8(%rsp),%r14
  jmp    L80
L79:
  mov    D0(%rip),%rax
  mov    (%rax),%ebx
  neg    %ebx
  jmp    L52
L7:
  mov    %r12,%rdi
  call   <closedir@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%ebx
  neg    %ebx
  jmp    L52
L9:
  mov    %rax,%rdi
  call   <strlen@plt>
  movw   $0x2f,(%rbx,%rax,1)
  jmp    L65
L117:
  mov    %r15,%rdi
  call   <remove_dir_entries>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L100
  mov    %r15,%rdi
  call   <rmdir@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L100
L80:
  lea    0x10(%rsp),%rsi
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <readdir_r@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L100
  cmpq   $0x0,0x8(%rsp)
  je     L100
  lea    0x1(%rbp,%r13,1),%rdi
  mov    0x10(%rsp),%rsi
  call   <strcpy@plt>
  mov    %rax,%r15
  mov    %rax,%rbp
  mov    D11(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,0x18(%rsp)
  je     L117
  mov    %r15,%rdi
  call   <unlink@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jns    L80
L100:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <closedir@plt>
L52:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  mov    %ebx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L102:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int remove_dir_entries(const char *__restrict path) {
  struct dirent entry, *result;
  char *buffer;
  DIR *dir;
  size_t len;
  int err;
  dir = opendir(path);
  if (!dir)
    return -errno;
  len = strlen(path);
  buffer = malloc(len + 1 + sizeof(entry.d_name));
  if (!buffer) {
    closedir(dir);
    return -ENOMEM;
  }
  buffer = strcpy(buffer, path);
  if (buffer[len] != '/')
    buffer = strcat(buffer, "/");
  while (1) {
    err = readdir_r(dir, &entry, &result);
    if (err || !result)
      break;
    buffer = strcpy(buffer + len + 1, entry.d_name);
    if (entry.d_type == DT_DIR) {
      err = remove_dir_entries(buffer);
      if (err < 0)
        break;
      err = rmdir(buffer);
      if (err < 0)
        break;
    } else {
      err = unlink(buffer);
      if (err < 0)
        break;
    }
  }
  free(buffer);
  closedir(dir);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_dir_entries>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L20
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x9(%rax),%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L36
  lea    0x1(%r13),%rbx
  mov    %r12,%rsi
  lea    0x8(%rsp),%r14
  mov    %rbx,%rdx
  call   <memcpy@plt>
  mov    %rax,%r15
  mov    $0x2f,%eax
  mov    %ax,(%r15,%r13,1)
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L68:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <readdir_r@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L33
  cmpq   $0x0,0x8(%rsp)
  je     L33
  mov    0x10(%rsp),%rsi
  lea    (%r15,%rbx,1),%rdi
  call   <strcpy@plt>
  mov    %rax,%r15
  mov    D15(%rip),%rax
  mov    %r15,%rdi
  mov    (%rax),%rax
  cmp    %rax,0x18(%rsp)
  je     L27
  call   <unlink@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L68
  xchg   %ax,%ax
L33:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <closedir@plt>
L92:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  call   <remove_dir_entries>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L33
  mov    %r15,%rdi
  call   <rmdir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L68
  jmp    L33
  nopl   0x0(%rax)
L20:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%r12d
  jmp    L92
L9:
  call   <__stack_chk_fail@plt>
L36:
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%r12d
  neg    %r12d
  jmp    L92
```

assistant: ```c
int remove_dir_entries(const char *__restrict path) {
  struct dirent entry, *result;
  char *buffer;
  DIR *dir;
  size_t len;
  int err;
  dir = opendir(path);
  if (!dir)
    return -errno;
  len = strlen(path);
  buffer = malloc(len + 1 + sizeof(entry.d_name));
  if (!buffer) {
    closedir(dir);
    return -ENOMEM;
  }
  buffer = strcpy(buffer, path);
  if (buffer[len] != '/')
    buffer = strcat(buffer, "/");
  while (1) {
    err = readdir_r(dir, &entry, &result);
    if (err || !result)
      break;
    buffer = strcpy(buffer + len + 1, entry.d_name);
    if (entry.d_type == DT_DIR) {
      err = remove_dir_entries(buffer);
      if (err < 0)
        break;
      err = rmdir(buffer);
      if (err < 0)
        break;
    } else {
      err = unlink(buffer);
      if (err < 0)
        break;
    }
  }
  free(buffer);
  closedir(dir);
  return err;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<remove_dir_entries>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <opendir@plt>
  test   %rax,%rax
  je     L98
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x9(%rax),%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L82
  lea    0x1(%r13),%rbx
  mov    %r12,%rsi
  lea    0x8(%rsp),%r14
  mov    %rbx,%rdx
  call   <memcpy@plt>
  mov    %rax,%r15
  mov    $0x2f,%eax
  mov    %ax,(%r15,%r13,1)
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax)
L5:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <readdir_r@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L19
  cmpq   $0x0,0x8(%rsp)
  je     L19
  mov    0x10(%rsp),%rsi
  lea    (%r15,%rbx,1),%rdi
  call   <strcpy@plt>
  mov    %rax,%r15
  mov    D23(%rip),%rax
  mov    %r15,%rdi
  mov    (%rax),%rax
  cmp    %rax,0x18(%rsp)
  je     L80
  call   <unlink@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L5
  xchg   %ax,%ax
L19:
  mov    %r15,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <closedir@plt>
L37:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L80:
  call   <remove_dir_entries>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L19
  mov    %r15,%rdi
  call   <rmdir@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L5
  jmp    L19
  nopl   0x0(%rax)
L98:
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%r12d
  jmp    L37
L8:
  call   <__stack_chk_fail@plt>
L82:
  mov    %rbp,%rdi
  call   <closedir@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%r12d
  neg    %r12d
  jmp    L37
```

assistant: ```c
int remove_dir_entries(const char *__restrict path) {
  struct dirent entry, *result;
  char *buffer;
  DIR *dir;
  size_t len;
  int err;
  dir = opendir(path);
  if (!dir)
    return -errno;
  len = strlen(path);
  buffer = malloc(len + 1 + sizeof(entry.d_name));
  if (!buffer) {
    closedir(dir);
    return -ENOMEM;
  }
  buffer = strcpy(buffer, path);
  if (buffer[len] != '/')
    buffer = strcat(buffer, "/");
  while (1) {
    err = readdir_r(dir, &entry, &result);
    if (err || !result)
      break;
    buffer = strcpy(buffer + len + 1, entry.d_name);
    if (entry.d_type == DT_DIR) {
      err = remove_dir_entries(buffer);
      if (err < 0)
        break;
      err = rmdir(buffer);
      if (err < 0)
        break;
    } else {
      err = unlink(buffer);
      if (err < 0)
        break;
    }
  }
  free(buffer);
  closedir(dir);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<headers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %edi,-0x414(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x410(%rbp),%rsi
  mov    -0x414(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  lea    -0x410(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x410(%rbp),%rsi
  mov    -0x414(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    -0x420(%rbp),%rax
  mov    %rax,%rdi
  call   <getMime@plt>
  mov    %rax,%rdx
  lea    -0x410(%rbp),%rax
  lea    D33(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x410(%rbp),%rsi
  mov    -0x414(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  lea    -0x410(%rbp),%rax
  lea    D38(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x410(%rbp),%rsi
  mov    -0x414(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D33
type: string
name: retrieve_data
arguments: data_tag: D38
type: string

tool: D9: HTTP/1.0 200 OK


tool: D23: Server: jdbhttpd/0.1.0


tool: D33: Content-Type: %s


tool: D38: 


assistant: ```c
void headers(int client, const char *filename) {
  char buf[1024];
  (void)filename;
  strcpy(buf, "HTTP/1.0 200 OK\r\n");
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "Server: jdbhttpd/0.1.0\r\n");
  send(client, buf, strlen(buf), 0);
  sprintf(buf, "Content-Type: %s\r\n", getMime(filename));
  send(client, buf, strlen(buf), 0);
  strcpy(buf, "\r\n");
  send(client, buf, strlen(buf), 0);
}
```