ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<__poll>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __poll(struct pollfd *fds, nfds_t nfds, int timeout) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmp_opt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  cmpq   $0x0,-0x10(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L0
L25:
  mov    $0xffffffff,%eax
  jmp    L0
L12:
  cmpq   $0x0,-0x10(%rbp)
  jne    L16
  mov    $0x1,%eax
  jmp    L0
L16:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L0:
  leave
  ret
```

assistant: ```c
int strcmp_opt(const char *s1, const char *s2) {
  if (!s1) {
    if (!s2)
      return 0;
    else
      return -1;
  } else if (!s2) {
    return 1;
  } else {
    return strcmp(s1, s2);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcmp_opt>:
  endbr64
  test   %rdi,%rdi
  je     L19
  mov    $0x1,%eax
  test   %rsi,%rsi
  je     L4
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
L19:
  neg    %rsi
  sbb    %eax,%eax
  ret
L4:
  ret
```

assistant: ```c
int strcmp_opt(const char *s1, const char *s2) {
  if (!s1) {
    if (!s2)
      return 0;
    else
      return -1;
  } else if (!s2) {
    return 1;
  } else {
    return strcmp(s1, s2);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmp_opt>:
  endbr64
  test   %rdi,%rdi
  je     L4
  test   %rsi,%rsi
  je     L19
  jmp    1050 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L4:
  neg    %rsi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int strcmp_opt(const char *s1, const char *s2) {
  if (!s1) {
    if (!s2)
      return 0;
    else
      return -1;
  } else if (!s2) {
    return 1;
  } else {
    return strcmp(s1, s2);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcmp_opt>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L9
  jmp    1050 <strcmp@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L10:
  neg    %rsi
  sbb    %eax,%eax
  ret
```

assistant: ```c
int strcmp_opt(const char *s1, const char *s2) {
  if (!s1) {
    if (!s2)
      return 0;
    else
      return -1;
  } else if (!s2) {
    return 1;
  } else {
    return strcmp(s1, s2);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_sequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L57
  mov    $0x2,%eax
  jmp    L6
L57:
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L2
L30:
  addq   $0x1,-0x28(%rbp)
L2:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L33
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L30
L33:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L18
L75:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x29(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl -0x29(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x20(%rbp)
  subq   $0x1,-0x18(%rbp)
L18:
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L75
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L1
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,-0x20(%rbp)
  jmp    L70
L12:
  subq   $0x1,-0x20(%rbp)
L70:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L12
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x29(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl -0x29(%rbp),%edx
  mov    %dl,(%rax)
  mov    $0x0,%eax
  jmp    L6
L1:
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
char next_sequence(char *seqnc) {
  char *chk, *start, *end, *exg1, *exg2, exg_bfr;
  if (*seqnc == 0)
    return (2);
  start = seqnc + 1;
  end = seqnc + *seqnc;
  for (chk = start; (chk < end) && (*chk >= *(chk + 1)); chk++)
    ;
  exg1 = start;
  for (exg2 = chk; exg1 < exg2; exg2--) {
    exg_bfr = *exg1;
    *exg1 = *exg2;
    *exg2 = exg_bfr;
    exg1++;
  }
  if (chk < end) {
    for (exg1 = chk++; *exg1 >= *chk; exg1--)
      ;
    exg_bfr = *exg1;
    *exg1 = *chk;
    *chk = exg_bfr;
    return (0);
  } else
    return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<next_sequence>:
  endbr64
  movzbl (%rdi),%eax
  mov    $0x2,%edx
  test   %al,%al
  je     L54
  lea    0x1(%rdi),%rdx
  movsbq %al,%rax
  add    %rax,%rdi
  mov    %rdx,%rax
  cmp    %rdi,%rdx
  jae    L55
L87:
  movzbl 0x1(%rax),%esi
  cmp    %sil,(%rax)
  jl     L65
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L87
  cmp    %rax,%rdx
  jb     L108
  mov    $0x1,%edx
  jmp    L54
L55:
  mov    $0x1,%edx
  jmp    L54
L65:
  cmp    %rax,%rdx
  jae    L77
L108:
  mov    %rax,%rcx
L20:
  movzbl (%rdx),%esi
  movzbl (%rcx),%r8d
  mov    %r8b,(%rdx)
  mov    %sil,(%rcx)
  add    $0x1,%rdx
  sub    $0x1,%rcx
  cmp    %rcx,%rdx
  jb     L20
L77:
  mov    $0x1,%edx
  cmp    %rdi,%rax
  jae    L54
  movzbl (%rax),%ecx
  movzbl 0x1(%rax),%esi
  cmp    %sil,%cl
  jl     L14
  mov    %rax,%rdx
L12:
  sub    $0x1,%rdx
  movzbl (%rdx),%ecx
  cmp    %sil,%cl
  jge    L12
L1:
  mov    %sil,(%rdx)
  mov    %cl,0x1(%rax)
  mov    $0x0,%edx
L54:
  mov    %edx,%eax
  ret
L14:
  mov    %rax,%rdx
  jmp    L1
```

assistant: ```c
char next_sequence(char *seqnc) {
  char *chk, *start, *end, *exg1, *exg2, exg_bfr;
  if (*seqnc == 0)
    return (2);
  start = seqnc + 1;
  end = seqnc + *seqnc;
  for (chk = start; (chk < end) && (*chk >= *(chk + 1)); chk++)
    ;
  exg1 = start;
  for (exg2 = chk; exg1 < exg2; exg2--) {
    exg_bfr = *exg1;
    *exg1 = *exg2;
    *exg2 = exg_bfr;
    exg1++;
  }
  if (chk < end) {
    for (exg1 = chk++; *exg1 >= *chk; exg1--)
      ;
    exg_bfr = *exg1;
    *exg1 = *chk;
    *chk = exg_bfr;
    return (0);
  } else
    return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_sequence>:
  endbr64
  movsbq (%rdi),%r8
  mov    $0x2,%eax
  test   %r8b,%r8b
  je     L41
  lea    0x1(%rdi),%rax
  add    %rdi,%r8
  cmp    %r8,%rax
  jae    L89
  movzbl 0x1(%rdi),%edx
  mov    %rax,%rcx
  jmp    L78
  nop
L66:
  add    $0x1,%rcx
  cmp    %rcx,%r8
  je     L97
L78:
  mov    %edx,%esi
  movzbl 0x1(%rcx),%edx
  cmp    %sil,%dl
  jle    L66
  cmp    %rcx,%rax
  jae    L76
L4:
  mov    %rcx,%rdx
  jmp    L42
  xchg   %ax,%ax
L87:
  movzbl (%rdx),%esi
L42:
  movzbl (%rax),%edi
  sub    $0x1,%rdx
  mov    %sil,(%rax)
  add    $0x1,%rax
  mov    %dil,0x1(%rdx)
  cmp    %rdx,%rax
  jb     L87
L76:
  cmp    %r8,%rcx
  jae    L89
  movzbl (%rcx),%edx
  movzbl 0x1(%rcx),%esi
  mov    %rcx,%rax
  cmp    %dl,%sil
  jg     L38
  xchg   %ax,%ax
L43:
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    %sil,%dl
  jge    L43
L38:
  mov    %sil,(%rax)
  xor    %eax,%eax
  mov    %dl,0x1(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  ret
  nopl   0x0(%rax)
L97:
  mov    %edx,%esi
  cmp    %r8,%rax
  jb     L4
L89:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char next_sequence(char *seqnc) {
  char *chk, *start, *end, *exg1, *exg2, exg_bfr;
  if (*seqnc == 0)
    return (2);
  start = seqnc + 1;
  end = seqnc + *seqnc;
  for (chk = start; (chk < end) && (*chk >= *(chk + 1)); chk++)
    ;
  exg1 = start;
  for (exg2 = chk; exg1 < exg2; exg2--) {
    exg_bfr = *exg1;
    *exg1 = *exg2;
    *exg2 = exg_bfr;
    exg1++;
  }
  if (chk < end) {
    for (exg1 = chk++; *exg1 >= *chk; exg1--)
      ;
    exg_bfr = *exg1;
    *exg1 = *chk;
    *chk = exg_bfr;
    return (0);
  } else
    return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_sequence>:
  endbr64
  movsbq (%rdi),%r8
  mov    $0x2,%eax
  test   %r8b,%r8b
  je     L98
  lea    0x1(%rdi),%rax
  add    %rdi,%r8
  cmp    %r8,%rax
  jae    L65
  movzbl 0x1(%rdi),%edx
  mov    %rax,%rcx
  jmp    L102
  nop
L34:
  add    $0x1,%rcx
  cmp    %rcx,%r8
  je     L64
L102:
  mov    %edx,%esi
  movzbl 0x1(%rcx),%edx
  cmp    %sil,%dl
  jle    L34
  cmp    %rcx,%rax
  jae    L55
L100:
  mov    %rcx,%rdx
  nopl   0x0(%rax)
L8:
  movzbl (%rax),%esi
  movzbl (%rdx),%edi
  add    $0x1,%rax
  sub    $0x1,%rdx
  mov    %dil,-0x1(%rax)
  mov    %sil,0x1(%rdx)
  cmp    %rdx,%rax
  jb     L8
L55:
  cmp    %r8,%rcx
  jae    L65
  movzbl (%rcx),%edx
  movzbl 0x1(%rcx),%esi
  mov    %rcx,%rax
  cmp    %dl,%sil
  jg     L97
  nop
L40:
  movzbl -0x1(%rax),%edx
  sub    $0x1,%rax
  cmp    %sil,%dl
  jge    L40
L97:
  mov    %sil,(%rax)
  xor    %eax,%eax
  mov    %dl,0x1(%rcx)
  ret
  cs nopw 0x0(%rax,%rax,1)
L98:
  ret
  nopl   0x0(%rax)
L64:
  cmp    %r8,%rax
  jb     L100
L65:
  mov    $0x1,%eax
  ret
```

assistant: ```c
char next_sequence(char *seqnc) {
  char *chk, *start, *end, *exg1, *exg2, exg_bfr;
  if (*seqnc == 0)
    return (2);
  start = seqnc + 1;
  end = seqnc + *seqnc;
  for (chk = start; (chk < end) && (*chk >= *(chk + 1)); chk++)
    ;
  exg1 = start;
  for (exg2 = chk; exg1 < exg2; exg2--) {
    exg_bfr = *exg1;
    *exg1 = *exg2;
    *exg2 = exg_bfr;
    exg1++;
  }
  if (chk < end) {
    for (exg1 = chk++; *exg1 >= *chk; exg1--)
      ;
    exg_bfr = *exg1;
    *exg1 = *chk;
    *chk = exg_bfr;
    return (0);
  } else
    return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L23
L21:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
  addq   $0x4,-0x28(%rbp)
L23:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: %d %d


assistant: ```c
int main() {
  int ref[] = {8, 4, 0, 2};
  int *wsk;
  int indeks;
  for (indeks = 0, wsk = ref; indeks < 4; indeks++, wsk++)
    printf("%d %d\n", ref[indeks], *wsk);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  mov    %rsp,%rbx
  lea    D4(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %esi,%edx
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  lea    0x10(%rsp),%rax
  cmp    %rax,%rbx
  jne    L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: %d %d


assistant: ```c
int main() {
  int ref[] = {8, 4, 0, 2};
  int *wsk;
  int indeks;
  for (indeks = 0, wsk = ref; indeks < 4; indeks++, wsk++)
    printf("%d %d\n", ref[indeks], *wsk);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  mov    $0x8,%esi
  mov    $0x8,%edx
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000008,%rax
  mov    %rsp,%rbx
  lea    0xc(%rsp),%rbp
  mov    %rax,(%rsp)
  movabs $0x200000000,%rax
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L13
L7:
  mov    0x4(%rbx),%edx
  add    $0x4,%rbx
  mov    %r12,%rdi
  mov    %edx,%esi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L7
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: %d %d


assistant: ```c
int main() {
  int ref[] = {8, 4, 0, 2};
  int *wsk;
  int indeks;
  for (indeks = 0, wsk = ref; indeks < 4; indeks++, wsk++)
    printf("%d %d\n", ref[indeks], *wsk);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%rbp
  movaps %xmm0,(%rsp)
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  mov    %esi,%edx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D4
type_infered: byte[16]

tool: D1: %d %d


tool: {"D4": [0x08,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int ref[] = {8, 4, 0, 2};
  int *wsk;
  int indeks;
  for (indeks = 0, wsk = ref; indeks < 4; indeks++, wsk++)
    printf("%d %d\n", ref[indeks], *wsk);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  jmp    L3
L17:
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L3:
  cmpl   $0x0,-0x20(%rbp)
  jg     L17
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int swap2(int num, int from, int to, int count) {
  while (count > 0) {
    int from_bit = num & (1 << from);
    int to_bit = num & (1 << to);
    num = (num & ~(1 << from)) | (to_bit << (from - to));
    num = (num & ~(1 << to)) | (from_bit >> (from - to));
    from--;
    to--;
    count--;
  }
  return num;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap2>:
  endbr64
  test   %ecx,%ecx
  jle    L14
  push   %rbp
  push   %rbx
  mov    %esi,%r8d
  mov    %esi,%r9d
  mov    %esi,%ebx
  sub    %ecx,%ebx
  mov    $0x1,%r10d
  mov    %edx,%r11d
  sub    %esi,%r11d
  sub    %edx,%r9d
L13:
  mov    %r10d,%eax
  mov    %r8d,%ecx
  shl    %cl,%eax
  lea    (%r11,%r8,1),%ecx
  mov    %r10d,%edx
  shl    %cl,%edx
  mov    %eax,%esi
  not    %esi
  and    %edi,%esi
  mov    %edx,%ebp
  and    %edi,%ebp
  mov    %r9d,%ecx
  shl    %cl,%ebp
  not    %edx
  or     %ebp,%esi
  and    %esi,%edx
  and    %edi,%eax
  sar    %cl,%eax
  mov    %edx,%edi
  or     %eax,%edi
  sub    $0x1,%r8d
  cmp    %ebx,%r8d
  jne    L13
  mov    %edi,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    %edi,%eax
  ret
```

assistant: ```c
int swap2(int num, int from, int to, int count) {
  while (count > 0) {
    int from_bit = num & (1 << from);
    int to_bit = num & (1 << to);
    num = (num & ~(1 << from)) | (to_bit << (from - to));
    num = (num & ~(1 << to)) | (from_bit >> (from - to));
    from--;
    to--;
    count--;
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap2>:
  endbr64
  push   %r12
  push   %rbx
  test   %ecx,%ecx
  jle    L2
  mov    %esi,%ebx
  mov    %edx,%r11d
  mov    %esi,%r9d
  mov    %esi,%r8d
  sub    %ecx,%ebx
  mov    %edi,%r12d
  mov    $0x1,%r10d
  sub    %esi,%r11d
  sub    %edx,%r9d
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r8d,%ecx
  mov    %r10d,%eax
  mov    %r10d,%edx
  shl    %cl,%eax
  lea    (%r11,%r8,1),%ecx
  sub    $0x1,%r8d
  shl    %cl,%edx
  mov    %eax,%esi
  mov    %r9d,%ecx
  and    %r12d,%eax
  mov    %edx,%edi
  not    %esi
  not    %edx
  sar    %cl,%eax
  and    %r12d,%edi
  and    %r12d,%esi
  shl    %cl,%edi
  or     %edi,%esi
  and    %esi,%edx
  or     %eax,%edx
  mov    %edx,%r12d
  cmp    %ebx,%r8d
  jne    L9
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int swap2(int num, int from, int to, int count) {
  while (count > 0) {
    int from_bit = num & (1 << from);
    int to_bit = num & (1 << to);
    num = (num & ~(1 << from)) | (to_bit << (from - to));
    num = (num & ~(1 << to)) | (from_bit >> (from - to));
    from--;
    to--;
    count--;
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swap2>:
  endbr64
  push   %r12
  push   %rbx
  test   %ecx,%ecx
  jle    L18
  mov    %esi,%ebx
  mov    %edx,%r11d
  mov    %esi,%r9d
  mov    %esi,%r8d
  sub    %ecx,%ebx
  mov    %edi,%r12d
  mov    $0x1,%r10d
  sub    %esi,%r11d
  sub    %edx,%r9d
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %r8d,%ecx
  mov    %r10d,%eax
  mov    %r10d,%edx
  shl    %cl,%eax
  lea    (%r11,%r8,1),%ecx
  sub    $0x1,%r8d
  shl    %cl,%edx
  mov    %eax,%esi
  mov    %r9d,%ecx
  and    %r12d,%eax
  mov    %edx,%edi
  not    %esi
  not    %edx
  sar    %cl,%eax
  and    %r12d,%edi
  and    %r12d,%esi
  shl    %cl,%edi
  or     %edi,%esi
  and    %esi,%edx
  or     %eax,%edx
  mov    %edx,%r12d
  cmp    %ebx,%r8d
  jne    L10
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %edi,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int swap2(int num, int from, int to, int count) {
  while (count > 0) {
    int from_bit = num & (1 << from);
    int to_bit = num & (1 << to);
    num = (num & ~(1 << from)) | (to_bit << (from - to));
    num = (num & ~(1 << to)) | (from_bit >> (from - to));
    from--;
    to--;
    count--;
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L51
L77:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x3,-0x18(%rbp)
  jne    L78
  movzbl -0x14(%rbp),%eax
  cmp    $0x6f,%al
  jne    L37
  movzbl -0x13(%rbp),%eax
  cmp    $0x6e,%al
  je     L48
L37:
  movzbl -0x14(%rbp),%eax
  cmp    $0x6f,%al
  jne    L88
  movzbl -0x12(%rbp),%eax
  cmp    $0x65,%al
  je     L48
L88:
  movzbl -0x13(%rbp),%eax
  cmp    $0x6e,%al
  jne    L127
  movzbl -0x12(%rbp),%eax
  cmp    $0x65,%al
  jne    L127
L48:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L51
L127:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L51
L78:
  cmpl   $0x5,-0x18(%rbp)
  jne    L51
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L77
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D32
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string

tool: D32: %d

tool: D25: 1


tool: D7: 2


tool: D14: 3


assistant: ```c
int main() {
  int len, n;
  char a[12];
  scanf("%d", &n);
  getchar();
  while (n--) {
    gets(a);
    len = strlen(a);
    if (len == 3) {
      if ((a[0] == 'o' && a[1] == 'n') || (a[0] == 'o' && a[2] == 'e') || (a[1] == 'n' && a[2] == 'e')) {
        printf("1\n");
      } else {
        printf("2\n");
      }
    } else if (len == 5) {
      printf("3\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L86
  lea    0xc(%rsp),%rbx
  lea    D23(%rip),%r12
  lea    D13(%rip),%rbp
  lea    D35(%rip),%r13
  jmp    L46
L109:
  cmpb   $0x6f,0xc(%rsp)
  je     L34
  cmpb   $0x6e,0xd(%rsp)
  jne    L123
  cmpb   $0x65,0xe(%rsp)
  je     L75
L123:
  mov    %rbp,%rdi
  call   <printf@plt>
L73:
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L86
L46:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  je     L109
  cmp    $0x5,%eax
  jne    L73
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L73
L34:
  cmpb   $0x6e,0xd(%rsp)
  je     L75
  cmpb   $0x65,0xe(%rsp)
  jne    L123
L75:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L73
L86:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L88
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string
name: read_data
arguments: data_tag: D35
data_type: string

tool: D18: %d

tool: D23: 3


tool: D13: 2


tool: D35: 1


assistant: ```c
int main() {
  int len, n;
  char a[12];
  scanf("%d", &n);
  getchar();
  while (n--) {
    gets(a);
    len = strlen(a);
    if (len == 3) {
      if ((a[0] == 'o' && a[1] == 'n') || (a[0] == 'o' && a[2] == 'e') || (a[1] == 'n' && a[2] == 'e')) {
        printf("1\n");
      } else {
        printf("2\n");
      }
    } else if (len == 5) {
      printf("3\n");
    }
  }
  return 0;
}
```