ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<test_read_solutions_from_file>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <solcon_read_standard_solutions_from_file@plt>
  lea    0xc(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0xc(%rsp),%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D57
data_type: string
name: parse_data
arguments: label: D37
data_type: string
name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D20
data_type: string
name: parse_data
arguments: label: D44
data_type: string

tool: D57: Give the name of the file : 

tool: D37: %s

tool: D18: Reading solutions from file with name "%s" ...


tool: D15: -> number of characters in name : %d


tool: D20: 
calling solcon_read_standard_solutions_from_file ...

tool: D44: Number of solutions : %d


assistant: ```c
void test_read_solutions_from_file(void) {
  char name[80];
  int nbc, fail, len;
  printf("Give the name of the file : ");
  scanf("%s", name);
  printf("Reading solutions from file with name \"%s\" ...\n", name);
  nbc = strlen(name);
  printf("-> number of characters in name : %d\n", nbc);
  printf("\ncalling solcon_read_standard_solutions_from_file ...\n");
  fail = solcon_read_standard_solutions_from_file(nbc, name);
  fail = solcon_number_of_standard_solutions(&len);
  printf("Number of solutions : %d\n", len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_read_solutions_from_file>:
  endbr64
  push   %r12
  lea    D33(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    D45(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <solcon_read_standard_solutions_from_file@plt>
  lea    0xc(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D33
type_guessed: string
name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D51
type_guessed: string
name: read_data
arguments: data_tag: D45
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string
name: read_data
arguments: data_tag: D32
type_guessed: string

tool: D33: Give the name of the file : 

tool: D39: %s

tool: D51: Reading solutions from file with name "%s" ...


tool: D45: -> number of characters in name : %d


tool: D17: 
calling solcon_read_standard_solutions_from_file ...

tool: D32: Number of solutions : %d


assistant: ```c
void test_read_solutions_from_file(void) {
  char name[80];
  int nbc, fail, len;
  printf("Give the name of the file : ");
  scanf("%s", name);
  printf("Reading solutions from file with name \"%s\" ...\n", name);
  nbc = strlen(name);
  printf("-> number of characters in name : %d\n", nbc);
  printf("\ncalling solcon_read_standard_solutions_from_file ...\n");
  fail = solcon_read_standard_solutions_from_file(nbc, name);
  fail = solcon_number_of_standard_solutions(&len);
  printf("Number of solutions : %d\n", len);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_read_solutions_from_file>:
  endbr64
  push   %r12
  lea    D52(%rip),%rdi
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    D41(%rip),%rdi
  mov    %eax,%esi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <solcon_read_standard_solutions_from_file@plt>
  lea    0xc(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D52
datatype: string
name: extract_symbolic_data
arguments: data_tag: D57
datatype: string
name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D41
datatype: string
name: extract_symbolic_data
arguments: data_tag: D47
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string

tool: D52: Give the name of the file : 

tool: D57: %s

tool: D18: Reading solutions from file with name "%s" ...


tool: D41: -> number of characters in name : %d


tool: D47: 
calling solcon_read_standard_solutions_from_file ...

tool: D21: Number of solutions : %d


assistant: ```c
void test_read_solutions_from_file(void) {
  char name[80];
  int nbc, fail, len;
  printf("Give the name of the file : ");
  scanf("%s", name);
  printf("Reading solutions from file with name \"%s\" ...\n", name);
  nbc = strlen(name);
  printf("-> number of characters in name : %d\n", nbc);
  printf("\ncalling solcon_read_standard_solutions_from_file ...\n");
  fail = solcon_read_standard_solutions_from_file(nbc, name);
  fail = solcon_number_of_standard_solutions(&len);
  printf("Number of solutions : %d\n", len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
FILE *xopen(const char *name, const char *mode) {
  FILE *f;
  f = fopen(name, mode);
  if (!f) {
    perror(name);
    exit(1);
  }
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xopen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

assistant: ```c
FILE *xopen(const char *name, const char *mode) {
  FILE *f;
  f = fopen(name, mode);
  if (!f) {
    perror(name);
    exit(1);
  }
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
FILE *xopen(const char *name, const char *mode) {
  FILE *f;
  f = fopen(name, mode);
  if (!f) {
    perror(name);
    exit(1);
  }
  return f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
FILE *xopen(const char *name, const char *mode) {
  FILE *f;
  f = fopen(name, mode);
  if (!f) {
    perror(name);
    exit(1);
  }
  return f;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  jmp    L33
L31:
  mov    $0x2a,%eax
L33:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  and    $0xf,%edx
  movslq %edx,%rdx
  lea    D4(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  movsbl %dl,%edx
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rsi
  mov    -0x18(%rbp),%rcx
  add    %rsi,%rcx
  movzbl (%rcx),%ecx
  movsbl %cl,%ecx
  sar    $0x4,%ecx
  and    $0xf,%ecx
  movslq %ecx,%rcx
  lea    D4(%rip),%rsi
  movzbl (%rcx,%rsi,1),%ecx
  movsbl %cl,%esi
  mov    %eax,%ecx
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L24
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D23
datatype: string

tool: D23: %c%c (%c) 

assistant: ```c
void print_hex(char *buffer) {
  static char conv[] = "0123456789ABCDEF";
  int i;
  for (i = 1; i <= buffer[0]; i++)
    printf("%c%c (%c) ", conv[((char)buffer[i] & 0xff) >> 4], conv[buffer[i] & 0x0f], isprint(buffer[i]) ? buffer[i] : '*');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_hex>:
  endbr64
  cmpb   $0x0,(%rdi)
  jle    L32
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x1,%ebx
  mov    $0x2a,%r14d
  lea    D16(%rip),%r12
  lea    D14(%rip),%r13
  jmp    L19
L15:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %rax,%rdx
  and    $0xf,%edx
  movsbl (%r12,%rdx,1),%edx
  shr    $0x4,%eax
  and    $0xf,%eax
  movsbl (%r12,%rax,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  movsbl 0x0(%rbp),%eax
  cmp    %ebx,%eax
  jl     L10
L19:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isprint@plt>
  mov    %r14d,%ecx
  test   %rax,%rax
  je     L15
  movsbl 0x0(%rbp,%rbx,1),%ecx
  jmp    L15
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D14
type: string

tool: D16: 0123456789ABCDEF

tool: D14: %c%c (%c) 

assistant: ```c
void print_hex(char *buffer) {
  static char conv[] = "0123456789ABCDEF";
  int i;
  for (i = 1; i <= buffer[0]; i++)
    printf("%c%c (%c) ", conv[((char)buffer[i] & 0xff) >> 4], conv[buffer[i] & 0x0f], isprint(buffer[i]) ? buffer[i] : '*');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_hex>:
  endbr64
  cmpb   $0x0,(%rdi)
  jle    L44
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L5
L0:
  movsbl (%rbx,%r13,1),%eax
  mov    $0x2a,%ecx
  mov    %eax,%edx
L29:
  sar    $0x4,%eax
  and    $0xf,%edx
  mov    %r12,%rdi
  add    $0x1,%r13
  and    $0xf,%eax
  movsbl 0x0(%rbp,%rdx,1),%edx
  movsbl 0x0(%rbp,%rax,1),%esi
  call   <printf@plt>
  movsbl (%rbx),%eax
  cmp    %r13d,%eax
  jl     L49
L5:
  movsbl (%rbx,%r13,1),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L0
  movsbl (%rbx,%r13,1),%ecx
  mov    %ecx,%edx
  mov    %ecx,%eax
  jmp    L29
  nopl   (%rax)
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D3: %c%c (%c) 

tool: D5: 0123456789ABCDEF

assistant: ```c
void print_hex(char *buffer) {
  static char conv[] = "0123456789ABCDEF";
  int i;
  for (i = 1; i <= buffer[0]; i++)
    printf("%c%c (%c) ", conv[((char)buffer[i] & 0xff) >> 4], conv[buffer[i] & 0x0f], isprint(buffer[i]) ? buffer[i] : '*');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_hex>:
  endbr64
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jg     L24
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L20:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    $0x2a,%ecx
  mov    %rax,%rdx
  shr    $0x4,%eax
  and    $0xf,%edx
  and    $0xf,%eax
  movsbl (%r12,%rdx,1),%edx
  movsbl (%r12,%rax,1),%esi
L42:
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  movsbl 0x0(%rbp),%eax
  cmp    %ebx,%eax
  jl     L5
L24:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L20
  movsbl 0x0(%rbp,%rbx,1),%ecx
  mov    %ecx,%eax
  and    $0xf,%eax
  movsbl (%r12,%rax,1),%edx
  mov    %ecx,%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  movsbl (%r12,%rax,1),%esi
  jmp    L42
  nopl   0x0(%rax)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D9: %c%c (%c) 

tool: D19: 0123456789ABCDEF

assistant: ```c
void print_hex(char *buffer) {
  static char conv[] = "0123456789ABCDEF";
  int i;
  for (i = 1; i <= buffer[0]; i++)
    printf("%c%c (%c) ", conv[((char)buffer[i] & 0xff) >> 4], conv[buffer[i] & 0x0f], isprint(buffer[i]) ? buffer[i] : '*');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L60:
  cmp    %rdx,%rsp
  je     L103
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L60
L103:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L29
  orq    $0x0,-0x8(%rsp,%rax,1)
L29:
  mov    %rsp,%r12
  mov    $0x0,%ebx
  lea    D33(%rip),%r13
L40:
  mov    -0x30(%rbp),%eax
  cmp    %ebx,%eax
  jle    L38
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  je     L40
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  jmp    L40
L38:
  cmp    $0x1,%eax
  jle    L87
  mov    $0x0,%ebx
  lea    D19(%rip),%r13
  lea    D33(%rip),%r14
  jmp    L116
L32:
  mov    -0x30(%rbp),%eax
  add    $0x1,%rbx
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %ebx,%edx
  jle    L87
L116:
  sub    %ebx,%eax
  sub    $0x1,%eax
  cltq
  mov    (%r12,%rbx,4),%esi
  sub    (%r12,%rax,4),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L32
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%r12,%rax,4),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L32
L87:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D33
data_type: string
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D33: %d

tool: D19: %d


assistant: ```c
int main() {
  int n, i, a;
  scanf("%d", &n);
  int dodo[n];
  i = 0;
  while (i < n) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      dodo[i] = a;
      i++;
    }
  }
  i = 0;
  while (i < n / 2) {
    printf("%d\n", (dodo[i] - dodo[n - i - 1]));
    if (n % 2 != 0)
      printf("%d", dodo[n / 2]);
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  push   %rbx
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L73
L106:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L106
L73:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L78
L89:
  mov    %rsp,%r12
  xor    %r13d,%r13d
  lea    -0x2c(%rbp),%r14
  jmp    L75
L111:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  jne    L69
  mov    -0x30(%rbp),%eax
L75:
  cmp    %r13d,%eax
  jg     L111
  xor    %r14d,%r14d
  lea    D15(%rip),%r13
  cmp    $0x1,%eax
  jg     L32
  jmp    L7
  nop
L13:
  mov    %eax,%edx
  add    $0x1,%r14
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r14d,%edx
  jle    L7
L32:
  sub    %r14d,%eax
  mov    (%r12,%r14,4),%esi
  mov    %r13,%rdi
  sub    $0x1,%eax
  cltq
  sub    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L13
  mov    %eax,%edx
  mov    %rbx,%rdi
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  jmp    L13
  nopl   (%rax)
L7:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L69:
  mov    %eax,(%r12,%r13,4)
  mov    -0x30(%rbp),%eax
  add    $0x1,%r13
  jmp    L75
L78:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L89
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string

tool: D11: %d

tool: D15: %d


assistant: ```c
int main() {
  int n, i, a;
  scanf("%d", &n);
  int dodo[n];
  i = 0;
  while (i < n) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      dodo[i] = a;
      i++;
    }
  }
  i = 0;
  while (i < n / 2) {
    printf("%d\n", (dodo[i] - dodo[n - i - 1]));
    if (n % 2 != 0)
      printf("%d", dodo[n / 2]);
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  push   %r12
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L109
L11:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L11
L109:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L128
L137:
  mov    %rsp,%r12
  xor    %r13d,%r13d
  lea    -0x2c(%rbp),%r14
  jmp    L108
L48:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  test   $0x1,%al
  jne    L2
  mov    -0x30(%rbp),%eax
L108:
  cmp    %r13d,%eax
  jg     L48
  xor    %r14d,%r14d
  lea    D16(%rip),%r13
  cmp    $0x1,%eax
  jg     L36
  jmp    L33
  nop
L123:
  mov    %eax,%edx
  add    $0x1,%r14
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  cmp    %r14d,%edx
  jle    L33
L36:
  sub    %r14d,%eax
  mov    (%r12,%r14,4),%esi
  mov    %r13,%rdi
  sub    $0x1,%eax
  cltq
  sub    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  test   $0x1,%al
  je     L123
  mov    %eax,%edx
  mov    %rbx,%rdi
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  mov    (%r12,%rax,4),%esi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  jmp    L123
  nopl   (%rax)
L33:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  xchg   %ax,%ax
L2:
  mov    %eax,(%r12,%r13,4)
  mov    -0x30(%rbp),%eax
  add    $0x1,%r13
  jmp    L108
L128:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L137
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D9: %d

tool: D16: %d


assistant: ```c
int main() {
  int n, i, a;
  scanf("%d", &n);
  int dodo[n];
  i = 0;
  while (i < n) {
    scanf("%d", &a);
    if (a % 2 != 0) {
      dodo[i] = a;
      i++;
    }
  }
  i = 0;
  while (i < n / 2) {
    printf("%d\n", (dodo[i] - dodo[n - i - 1]));
    if (n % 2 != 0)
      printf("%d", dodo[n / 2]);
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: %d

assistant: ```c
int main() {
  printf("%d", g());
  printf("\n");
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <g@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: %d

assistant: ```c
int main() {
  printf("%d", g());
  printf("\n");
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <g@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  printf("%d", g());
  printf("\n");
  getchar();
}
```