user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x30(%rsp),%rdx
  lea    0x2c(%rsp),%rsi
  xor    %eax,%eax
  lea    D64(%rip),%rdi
  call   <scanf@plt>
  xchg   %ax,%ax
L50:
  movss  D45(%rip),%xmm0
  addss  0x2c(%rsp),%xmm0
  movss  %xmm0,0x2c(%rsp)
  call   <f@plt>
  pxor   %xmm6,%xmm6
  comisd %xmm0,%xmm6
  ja     L50
  movss  0x2c(%rsp),%xmm4
  movss  D45(%rip),%xmm5
  lea    D10(%rip),%rdi
  addss  %xmm4,%xmm5
  movss  %xmm4,0xc(%rsp)
  movss  %xmm5,0x8(%rsp)
  call   <puts@plt>
  lea    0x34(%rsp),%rsi
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x34(%rsp),%eax
  test   %eax,%eax
  jle    L37
  xor    %ebx,%ebx
  lea    D13(%rip),%rbp
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L2:
  movss  %xmm2,0x8(%rsp)
L77:
  movaps %xmm2,%xmm0
  movss  %xmm2,0x10(%rsp)
  call   <f@plt>
  movss  0x10(%rsp),%xmm2
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  0x8(%rsp),%xmm0
  call   <fabs@plt>
  movss  D4(%rip),%xmm6
  comiss %xmm0,%xmm6
  jae    L37
  add    $0x1,%ebx
  cmp    %ebx,0x34(%rsp)
  jle    L37
L4:
  movss  0xc(%rsp),%xmm0
  call   <f@plt>
  movss  0x8(%rsp),%xmm4
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm4,%xmm2
  mulsd  %xmm0,%xmm2
  movaps %xmm4,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <f@plt>
  movss  0xc(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm5,%xmm0
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm2
  movaps %xmm5,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <f@plt>
  movsd  %xmm0,0x10(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <f@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  subsd  %xmm0,%xmm1
  movss  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm2
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,0x18(%rsp)
  call   <f@plt>
  movss  0x18(%rsp),%xmm2
  movsd  %xmm0,0x10(%rsp)
  movaps %xmm2,%xmm0
  call   <f@plt>
  mulsd  0x10(%rsp),%xmm0
  pxor   %xmm3,%xmm3
  movss  0x18(%rsp),%xmm2
  comisd %xmm0,%xmm3
  jbe    L2
  movss  %xmm2,0xc(%rsp)
  jmp    L77
  xchg   %ax,%ax
L37:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D64
datatype: string
name: retrieve_data
arguments: data_label: D45
datatype: byte[4]
name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D78
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: f32

tool: D30: Enter approximation ranges

tool: D64: %f%f

tool: {"D45": [0x00,0x00,0x80,0x3f]}

tool: D10: Enter n

tool: D78: %d

tool: D13: %f ------ %f


tool: D4: 0.0001

assistant: ```c
int main() {
  float e = 0.0001, r1, r2, x;
  int i, n;
  printf("Enter approximation ranges");
  scanf("%f%f", &r1, &r2);
  while (f(++r1) < 0)
    ;
  float a, b;
  a = r1;
  b = r1 + 1;
  printf("Enter n\n");
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    x = (b * f(a) - a * f(b)) / (f(a) - f(b));
    if (f(b) * f(x) < 0)
      a = x;
    else
      b = x;
    printf("%f ------ %f\n", x, f(x));
    if (fabs(a - b) <= e)
      break;
  }
}
```