ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <_message@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fatal(const char *msg) {
  _message(msg, 0, stderr);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  xor    %esi,%esi
  mov    (%rax),%edx
  call   <_message@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fatal(const char *msg) {
  _message(msg, 0, stderr);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  xor    %esi,%esi
  mov    (%rax),%edx
  call   <_message@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void fatal(const char *msg) {
  _message(msg, 0, stderr);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x60(%rsp),%rdx
L13:
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L13
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0xd8,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  _Complex double a[12], *c = a, s = 3.0 + 1.0i;
  double b[12] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, *d = b;
  int i;
  for (i = 0; i < 6; i++)
    *c++ = *d++ * s;
  if (c != a + 6 || d != b + 6)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  _Complex double a[12], *c = a, s = 3.0 + 1.0i;
  double b[12] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, *d = b;
  int i;
  for (i = 0; i < 6; i++)
    *c++ = *d++ * s;
  if (c != a + 6 || d != b + 6)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  _Complex double a[12], *c = a, s = 3.0 + 1.0i;
  double b[12] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}, *d = b;
  int i;
  for (i = 0; i < 6; i++)
    *c++ = *d++ * s;
  if (c != a + 6 || d != b + 6)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strxfrm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <memccpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  leave
  ret
```

assistant: ```c
size_t strxfrm(char *dest, const char *src, size_t n) {
  memccpy(dest, src, 0, n);
  return strlen(dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strxfrm>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rcx
  mov    $0x0,%edx
  call   <memccpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rbx
  ret
```

assistant: ```c
size_t strxfrm(char *dest, const char *src, size_t n) {
  memccpy(dest, src, 0, n);
  return strlen(dest);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strxfrm>:
  endbr64
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdi,%rbp
  xor    %edx,%edx
  call   <memccpy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
size_t strxfrm(char *dest, const char *src, size_t n) {
  memccpy(dest, src, 0, n);
  return strlen(dest);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strxfrm>:
  endbr64
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdi,%rbp
  xor    %edx,%edx
  call   <memccpy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <strlen@plt>
```

assistant: ```c
size_t strxfrm(char *dest, const char *src, size_t n) {
  memccpy(dest, src, 0, n);
  return strlen(dest);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Abc_TtPrintDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L20
  cmpl   $0xf,-0x4(%rbp)
  jg     L20
  mov    $0x1,%eax
  jmp    L13
L20:
  mov    $0x0,%eax
L13:
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x9,-0x4(%rbp)
  jg     L21
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  jmp    L19
L21:
  mov    -0x4(%rbp),%eax
  add    $0x37,%eax
L19:
  leave
  ret
```

assistant: ```c
char Abc_TtPrintDigit(int Digit) {
  assert(Digit >= 0 && Digit < 16);
  if (Digit < 10)
    return '0' + Digit;
  return 'A' + Digit - 10;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Abc_TtPrintDigit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0xf,%edi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x30(%rbx),%edx
  lea    0x37(%rbx),%eax
  cmp    $0x9,%ebx
  cmovle %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char Abc_TtPrintDigit(int Digit) {
  assert(Digit >= 0 && Digit < 16);
  if (Digit < 10)
    return '0' + Digit;
  return 'A' + Digit - 10;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Abc_TtPrintDigit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0xf,%ebx
  setbe  %dil
  call   <assert@plt>
  lea    0x30(%rbx),%edx
  lea    0x37(%rbx),%eax
  cmp    $0x9,%ebx
  cmovle %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char Abc_TtPrintDigit(int Digit) {
  assert(Digit >= 0 && Digit < 16);
  if (Digit < 10)
    return '0' + Digit;
  return 'A' + Digit - 10;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Abc_TtPrintDigit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0xf,%ebx
  setbe  %dil
  call   <assert@plt>
  lea    0x30(%rbx),%edx
  lea    0x37(%rbx),%eax
  cmp    $0x9,%ebx
  cmovle %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char Abc_TtPrintDigit(int Digit) {
  assert(Digit >= 0 && Digit < 16);
  if (Digit < 10)
    return '0' + Digit;
  return 'A' + Digit - 10;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L12
L27:
  cmpl   $0x20,-0x4(%rbp)
  jne    L11
  nop
L17:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  je     L17
  mov    $0x20,%edi
  call   <putchar@plt>
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L12:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L27
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      while ((c = getchar()) == ' ')
        ;
      putchar(' ');
    }
    putchar(c);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  jmp    L10
L44:
  mov    %ebx,%edi
  call   <putchar@plt>
L10:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  cmp    %ebx,(%rax)
  je     L0
  cmp    $0x20,%ebx
  jne    L44
L37:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0x20,%eax
  je     L37
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L44
L0:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      while ((c = getchar()) == ' ')
        ;
      putchar(' ');
    }
    putchar(c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D2(%rip),%rbx
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edi
  call   <putchar@plt>
L36:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  je     L32
  cmp    $0x20,%ebp
  jne    L5
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0x20,%eax
  je     L33
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      while ((c = getchar()) == ' ')
        ;
      putchar(' ');
    }
    putchar(c);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbx
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %ebp,%edi
  call   <putchar@plt>
L45:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  je     L48
  cmp    $0x20,%ebp
  jne    L22
  nopl   0x0(%rax)
L43:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0x20,%eax
  je     L43
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L48:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int c;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      while ((c = getchar()) == ' ')
        ;
      putchar(' ');
    }
    putchar(c);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ROL64_63>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  rol    $0x3f,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t ROL64_63(uint64_t x) {
  __asm__("rolq $63, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ROL64_63>:
  endbr64
  mov    %rdi,%rax
  rol    $0x3f,%rax
  ret
```

assistant: ```c
uint64_t ROL64_63(uint64_t x) {
  __asm__("rolq $63, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ROL64_63>:
  endbr64
  mov    %rdi,%rax
  rol    $0x3f,%rax
  ret
```

assistant: ```c
uint64_t ROL64_63(uint64_t x) {
  __asm__("rolq $63, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ROL64_63>:
  endbr64
  mov    %rdi,%rax
  rol    $0x3f,%rax
  ret
```

assistant: ```c
uint64_t ROL64_63(uint64_t x) {
  __asm__("rolq $63, %0" : "=r"(x) : "0"(x));
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<horner_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double horner_i(double x, int n, double *a) {
  double y = 0;
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<horner_i>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double horner_i(double x, int n, double *a) {
  double y = 0;
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<horner_i>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double horner_i(double x, int n, double *a) {
  double y = 0;
  return y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<horner_i>:
  endbr64
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double horner_i(double x, int n, double *a) {
  double y = 0;
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ASN1_item_i2d_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ASN1error@plt>
  mov    $0x0,%eax
  jmp    L9
L8:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_set_fp@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ASN1_item_i2d_bio@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
  mov    -0xc(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int ASN1_item_i2d_fp(const ASN1_ITEM *it, FILE *out, void *x) {
  BIO *b;
  int ret;
  if ((b = BIO_new(BIO_s_file())) == NULL) {
    ASN1error(ERR_R_BUF_LIB);
    return (0);
  }
  BIO_set_fp(b, out, BIO_NOCLOSE);
  ret = ASN1_item_i2d_bio(it, b, x);
  BIO_free(b);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ASN1_item_i2d_fp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rbx
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <BIO_set_fp@plt>
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <ASN1_item_i2d_bio@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <BIO_free@plt>
L3:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  mov    $0x0,%ebp
  jmp    L3
```

assistant: ```c
int ASN1_item_i2d_fp(const ASN1_ITEM *it, FILE *out, void *x) {
  BIO *b;
  int ret;
  if ((b = BIO_new(BIO_s_file())) == NULL) {
    ASN1error(ERR_R_BUF_LIB);
    return (0);
  }
  BIO_set_fp(b, out, BIO_NOCLOSE);
  ret = ASN1_item_i2d_bio(it, b, x);
  BIO_free(b);
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ASN1_item_i2d_fp>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbp
  mov    D4(%rip),%rax
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <BIO_set_fp@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ASN1_item_i2d_bio@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <BIO_free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D12(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edi
  call   <ASN1error@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ASN1_item_i2d_fp(const ASN1_ITEM *it, FILE *out, void *x) {
  BIO *b;
  int ret;
  if ((b = BIO_new(BIO_s_file())) == NULL) {
    ASN1error(ERR_R_BUF_LIB);
    return (0);
  }
  BIO_set_fp(b, out, BIO_NOCLOSE);
  ret = ASN1_item_i2d_bio(it, b, x);
  BIO_free(b);
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ASN1_item_i2d_fp>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    D8(%rip),%rax
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <BIO_set_fp@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <ASN1_item_i2d_bio@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <BIO_free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    D5(%rip),%rax
  xor    %r12d,%r12d
  mov    (%rax),%edi
  call   <ASN1error@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ASN1_item_i2d_fp(const ASN1_ITEM *it, FILE *out, void *x) {
  BIO *b;
  int ret;
  if ((b = BIO_new(BIO_s_file())) == NULL) {
    ASN1error(ERR_R_BUF_LIB);
    return (0);
  }
  BIO_set_fp(b, out, BIO_NOCLOSE);
  ret = ASN1_item_i2d_bio(it, b, x);
  BIO_free(b);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %edx,%esi
  sub    %eax,%esi
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %esi,%edx
  mov    %ecx,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
type: string
name: read_data
arguments: data_label: D28
type: string
name: read_data
arguments: data_label: D6
type: string

tool: D21: Enter a two-digit number: 

tool: D28: %d

tool: D6: The reversal is: %d%d


assistant: ```c
int main() {
  int n;
  printf("Enter a two-digit number: ");
  scanf("%d", &n);
  printf("The reversal is: %d%d\n", n % 10, n / 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string

tool: D18: Enter a two-digit number: 

tool: D7: %d

tool: D15: The reversal is: %d%d


assistant: ```c
int main() {
  int n;
  printf("Enter a two-digit number: ");
  scanf("%d", &n);
  printf("The reversal is: %d%d\n", n % 10, n / 10);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D24(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D7(%rip),%rdi
  mov    %rdx,%rsi
  imul   $0x66666667,%rdx,%rdx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D24: Enter a two-digit number: 

tool: D5: %d

tool: D7: The reversal is: %d%d


assistant: ```c
int main() {
  int n;
  printf("Enter a two-digit number: ");
  scanf("%d", &n);
  printf("The reversal is: %d%d\n", n % 10, n / 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rdx
  lea    D28(%rip),%rdi
  mov    %rdx,%rsi
  imul   $0x66666667,%rdx,%rdx
  mov    %esi,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type: string
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D28
type: string

tool: D27: Enter a two-digit number: 

tool: D13: %d

tool: D28: The reversal is: %d%d


assistant: ```c
int main() {
  int n;
  printf("Enter a two-digit number: ");
  scanf("%d", &n);
  printf("The reversal is: %d%d\n", n % 10, n / 10);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<range>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  jle    L3
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L3:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void range(int id, int p, int n, int *s, int *e) {
  int m = n % p;
  int r = n / p;
  *s = 0;
  if (id > 0) {
    *s = id * r + (id < m ? id : m);
  }
  id += 1;
  *e = id * r + (id < m ? id : m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<range>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edi,%edi
  jle    L16
  mov    %eax,%esi
  imul   %edi,%esi
  cmp    %edi,%edx
  mov    %edi,%r9d
  cmovle %edx,%r9d
  add    %r9d,%esi
  mov    %esi,(%rcx)
L7:
  add    $0x1,%edi
  imul   %edi,%eax
  cmp    %edi,%edx
  cmovg  %edi,%edx
  add    %edx,%eax
  mov    %eax,(%r8)
  ret
L16:
  movl   $0x0,(%rcx)
  jmp    L7
```

assistant: ```c
void range(int id, int p, int n, int *s, int *e) {
  int m = n % p;
  int r = n / p;
  *s = 0;
  if (id > 0) {
    *s = id * r + (id < m ? id : m);
  }
  id += 1;
  *e = id * r + (id < m ? id : m);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<range>:
  endbr64
  mov    %edx,%eax
  cltd
  idiv   %esi
  test   %edi,%edi
  jle    L17
  mov    %eax,%esi
  mov    %edi,%r9d
  imul   %edi,%esi
  cmp    %edi,%edx
  cmovle %edx,%r9d
  add    %r9d,%esi
  mov    %esi,(%rcx)
L14:
  add    $0x1,%edi
  imul   %edi,%eax
  cmp    %edi,%edx
  cmovg  %edi,%edx
  add    %edx,%eax
  mov    %eax,(%r8)
  ret
  nopl   0x0(%rax)
L17:
  movl   $0x0,(%rcx)
  jmp    L14
```

assistant: ```c
void range(int id, int p, int n, int *s, int *e) {
  int m = n % p;
  int r = n / p;
  *s = 0;
  if (id > 0) {
    *s = id * r + (id < m ? id : m);
  }
  id += 1;
  *e = id * r + (id < m ? id : m);
}
```