ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D3(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
datatype: byte[8]

tool: {"D3": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec * 1e-6;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D8(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: byte[8]

tool: {"D8": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec * 1e-6;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  D2(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type: byte[8]

tool: {"D2": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double now(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec * 1e-6;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L31
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L33
L34:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L34
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_sort(int *pdata, int count) {
  int i, j;
  int tower;
  tower = *pdata;
  for (i = 1; i < count; i++) {
    tower = *(pdata + i);
    j = i - 1;
    while (tower < *(pdata + j)) {
      *(pdata + j + 1) = *(pdata + j);
      j--;
    }
    *(pdata + j + 1) = tower;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  lea    -0x1(%rsi),%r9d
  mov    $0x0,%r8d
L36:
  mov    0x4(%rdi,%r8,4),%ecx
  mov    (%rdi,%r8,4),%edx
  cmp    %edx,%ecx
  jge    L19
  lea    -0x1(%r8),%rax
L14:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L14
L33:
  mov    %ecx,0x4(%rdi,%rsi,4)
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L36
L11:
  ret
L19:
  mov    %r8,%rsi
  jmp    L33
```

assistant: ```c
void insert_sort(int *pdata, int count) {
  int i, j;
  int tower;
  tower = *pdata;
  for (i = 1; i < count; i++) {
    tower = *(pdata + i);
    j = i - 1;
    while (tower < *(pdata + j)) {
      *(pdata + j + 1) = *(pdata + j);
      j--;
    }
    *(pdata + j + 1) = tower;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L13
  lea    0x4(%rdi),%r8
  lea    -0x1(%rsi),%r10d
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L15:
  mov    (%r8),%ecx
  mov    -0x4(%r8),%edx
  mov    %r8,%rax
  cmp    %edx,%ecx
  jge    L19
  lea    -0x1(%r9),%rax
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L5
  lea    0x4(%rdi,%rsi,4),%rax
L19:
  add    $0x1,%r9
  mov    %ecx,(%rax)
  add    $0x4,%r8
  cmp    %r9,%r10
  jne    L15
L13:
  ret
```

assistant: ```c
void insert_sort(int *pdata, int count) {
  int i, j;
  int tower;
  tower = *pdata;
  for (i = 1; i < count; i++) {
    tower = *(pdata + i);
    j = i - 1;
    while (tower < *(pdata + j)) {
      *(pdata + j + 1) = *(pdata + j);
      j--;
    }
    *(pdata + j + 1) = tower;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<insert_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L19
  lea    0x4(%rdi),%r8
  lea    -0x1(%rsi),%r10d
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L26:
  mov    (%r8),%ecx
  mov    -0x4(%r8),%edx
  mov    %r8,%rax
  cmp    %edx,%ecx
  jge    L36
  lea    -0x1(%r9),%rax
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edx,0x8(%rdi,%rax,4)
  mov    %rax,%rsi
  sub    $0x1,%rax
  mov    0x4(%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jg     L9
  lea    0x4(%rdi,%rsi,4),%rax
L36:
  add    $0x1,%r9
  mov    %ecx,(%rax)
  add    $0x4,%r8
  cmp    %r9,%r10
  jne    L26
L19:
  ret
```

assistant: ```c
void insert_sort(int *pdata, int count) {
  int i, j;
  int tower;
  tower = *pdata;
  for (i = 1; i < count; i++) {
    tower = *(pdata + i);
    j = i - 1;
    while (tower < *(pdata + j)) {
      *(pdata + j + 1) = *(pdata + j);
      j--;
    }
    *(pdata + j + 1) = tower;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<String_getToken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %ax,-0x42(%rbp)
  movb   $0x0,-0x4a(%rbp)
  movw   $0x0,-0x48(%rbp)
  movw   $0x0,-0x46(%rbp)
  movw   $0x0,-0x44(%rbp)
  jmp    L96
L72:
  movzbl -0x4a(%rbp),%eax
  mov    %al,-0x49(%rbp)
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  setne  %al
  mov    %al,-0x4a(%rbp)
  cmpb   $0x0,-0x49(%rbp)
  jne    L35
  cmpb   $0x1,-0x4a(%rbp)
  jne    L35
  movzwl -0x48(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x48(%rbp)
L35:
  cmpb   $0x1,-0x4a(%rbp)
  jne    L78
  movzwl -0x48(%rbp),%eax
  cmp    -0x5c(%rbp),%ax
  jne    L78
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L78
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L78
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L78
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %al,%dl
  je     L78
  movzwl -0x44(%rbp),%edx
  mov    -0x58(%rbp),%rax
  add    %rax,%rdx
  movzwl -0x46(%rbp),%eax
  movzbl (%rdx),%edx
  cltq
  mov    %dl,-0x40(%rbp,%rax,1)
  movzwl -0x46(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x46(%rbp)
L78:
  movzwl -0x44(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x44(%rbp)
L96:
  movzwl -0x44(%rbp),%eax
  cmp    -0x42(%rbp),%ax
  jb     L72
  movzwl -0x46(%rbp),%eax
  cltq
  movb   $0x0,-0x40(%rbp,%rax,1)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
char *String_getToken(const char *line, const unsigned short int numMatch) {
  const unsigned short int len = strlen(line);
  char inWord = 0;
  unsigned short int count = 0;
  char match[50];
  unsigned short int foundCount = 0;
  for (unsigned short int i = 0; i < len; i++) {
    char lastState = inWord;
    inWord = line[i] == ' ' ? 0 : 1;
    if (lastState == 0 && inWord == 1)
      count++;
    if (inWord == 1) {
      if (count == numMatch && line[i] != ' ' && line[i] != '\0' && line[i] != '\n' && line[i] != (char)EOF) {
        match[foundCount] = line[i];
        foundCount++;
      }
    }
  }
  match[foundCount] = '\0';
  return ((char *)strdup(match));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<String_getToken>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r9d
  test   %ax,%ax
  je     L49
  mov    D8(%rip),%rax
  movzbl (%rax),%r11d
  mov    %rbp,%rax
  sub    $0x1,%r9d
  movzwl %r9w,%r9d
  lea    0x1(%rbp,%r9,1),%r10
  mov    $0x0,%r9d
  mov    $0x0,%edi
  mov    $0x0,%r8d
  jmp    L68
L13:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L49
L68:
  movzbl (%rax),%esi
  cmp    $0x20,%sil
  setne  %cl
  mov    %r8d,%edx
  mov    %ecx,%r8d
  test   %dl,%dl
  jne    L81
  cmp    $0x1,%cl
  sbb    $0xffff,%di
L81:
  cmp    %bx,%di
  sete   %dl
  and    %ecx,%edx
  test   %sil,%sil
  setne  %cl
  test   %cl,%dl
  je     L13
  cmp    $0xa,%sil
  je     L13
  cmp    %r11b,%sil
  je     L13
  movzwl %r9w,%edx
  mov    %sil,(%rsp,%rdx,1)
  add    $0x1,%r9d
  jmp    L13
L49:
  movzwl %r9w,%r9d
  movb   $0x0,(%rsp,%r9,1)
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *String_getToken(const char *line, const unsigned short int numMatch) {
  const unsigned short int len = strlen(line);
  char inWord = 0;
  unsigned short int count = 0;
  char match[50];
  unsigned short int foundCount = 0;
  for (unsigned short int i = 0; i < len; i++) {
    char lastState = inWord;
    inWord = line[i] == ' ' ? 0 : 1;
    if (lastState == 0 && inWord == 1)
      count++;
    if (inWord == 1) {
      if (count == numMatch && line[i] != ' ' && line[i] != '\0' && line[i] != '\n' && line[i] != (char)EOF) {
        match[foundCount] = line[i];
        foundCount++;
      }
    }
  }
  match[foundCount] = '\0';
  return ((char *)strdup(match));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<String_getToken>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %ax,%ax
  je     L68
  mov    D0(%rip),%rdx
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %r10d,%r10d
  movzwl %ax,%eax
  xor    %esi,%esi
  movzbl (%rdx),%r11d
  lea    0x1(%rbx,%rax,1),%r9
  xor    %edx,%edx
  jmp    L84
  nop
L104:
  add    $0x1,%esi
L100:
  test   %al,%al
  setne  %r8b
  cmp    %si,%bp
  sete   %cl
  test   %cl,%r8b
  je     L117
  cmp    $0xa,%al
  jne    L76
L117:
  add    $0x1,%rdi
  cmp    %rdi,%r9
  je     L36
L84:
  movzbl (%rdi),%eax
  mov    %edx,%ecx
  cmp    $0x20,%al
  setne  %dl
  test   %cl,%cl
  jne    L125
  test   %dl,%dl
  jne    L104
L125:
  cmp    $0x20,%al
  jne    L100
  add    $0x1,%rdi
  cmp    %rdi,%r9
  jne    L84
L36:
  movzwl %r10w,%r10d
L40:
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%r10,1)
  call   <strdup@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  cmp    %r11b,%al
  je     L117
  movzwl %r10w,%ecx
  add    $0x1,%r10d
  mov    %al,(%rsp,%rcx,1)
  jmp    L117
  nopw   0x0(%rax,%rax,1)
L68:
  xor    %r10d,%r10d
  jmp    L40
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *String_getToken(const char *line, const unsigned short int numMatch) {
  const unsigned short int len = strlen(line);
  char inWord = 0;
  unsigned short int count = 0;
  char match[50];
  unsigned short int foundCount = 0;
  for (unsigned short int i = 0; i < len; i++) {
    char lastState = inWord;
    inWord = line[i] == ' ' ? 0 : 1;
    if (lastState == 0 && inWord == 1)
      count++;
    if (inWord == 1) {
      if (count == numMatch && line[i] != ' ' && line[i] != '\0' && line[i] != '\n' && line[i] != (char)EOF) {
        match[foundCount] = line[i];
        foundCount++;
      }
    }
  }
  match[foundCount] = '\0';
  return ((char *)strdup(match));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<String_getToken>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %ax,%ax
  je     L18
  mov    D5(%rip),%rdx
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %r10d,%r10d
  movzwl %ax,%eax
  xor    %esi,%esi
  movzbl (%rdx),%r11d
  lea    0x1(%rbx,%rax,1),%r9
  xor    %edx,%edx
  jmp    L128
  nop
L113:
  add    $0x1,%esi
L32:
  test   %al,%al
  setne  %r8b
  cmp    %si,%bp
  sete   %cl
  test   %cl,%r8b
  je     L8
  cmp    $0xa,%al
  jne    L56
L8:
  add    $0x1,%rdi
  cmp    %r9,%rdi
  je     L17
L128:
  movzbl (%rdi),%eax
  mov    %edx,%ecx
  cmp    $0x20,%al
  setne  %dl
  test   %cl,%cl
  jne    L25
  test   %dl,%dl
  jne    L113
L25:
  cmp    $0x20,%al
  jne    L32
  add    $0x1,%rdi
  cmp    %r9,%rdi
  jne    L128
L17:
  movzwl %r10w,%r10d
L81:
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%r10,1)
  call   <strdup@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L98
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  cmp    %r11b,%al
  je     L8
  movzwl %r10w,%ecx
  add    $0x1,%r10d
  mov    %al,(%rsp,%rcx,1)
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r10d,%r10d
  jmp    L81
L98:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *String_getToken(const char *line, const unsigned short int numMatch) {
  const unsigned short int len = strlen(line);
  char inWord = 0;
  unsigned short int count = 0;
  char match[50];
  unsigned short int foundCount = 0;
  for (unsigned short int i = 0; i < len; i++) {
    char lastState = inWord;
    inWord = line[i] == ' ' ? 0 : 1;
    if (lastState == 0 && inWord == 1)
      count++;
    if (inWord == 1) {
      if (count == numMatch && line[i] != ' ' && line[i] != '\0' && line[i] != '\n' && line[i] != (char)EOF) {
        match[foundCount] = line[i];
        foundCount++;
      }
    }
  }
  match[foundCount] = '\0';
  return ((char *)strdup(match));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rpsls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  je     L24
  cmpq   $0x0,-0x50(%rbp)
  jne    L94
L24:
  mov    $0x0,%eax
  jmp    L0
L94:
  lea    D6(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L158
L149:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L103
  movl   $0x0,-0x38(%rbp)
  jmp    L101
L11:
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  cmp    $0x4,%eax
  jg     L91
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  jmp    L54
L91:
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  sub    $0x5,%eax
L54:
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L93
  cmpl   $0x0,-0x38(%rbp)
  jne    L167
  mov    $0x0,%eax
  jmp    L0
L167:
  cmpl   $0x2,-0x38(%rbp)
  jg     L52
  mov    $0x1,%eax
  jmp    L0
L52:
  mov    $0xffffffff,%eax
  jmp    L0
L93:
  addl   $0x1,-0x38(%rbp)
L101:
  cmpl   $0x4,-0x38(%rbp)
  jle    L11
L103:
  addl   $0x1,-0x3c(%rbp)
L158:
  cmpl   $0x4,-0x3c(%rbp)
  jle    L149
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L148
  call   <__stack_chk_fail@plt>
L148:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D36
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string
name: extract_symbolic_data
arguments: label: D19
data_type: string

tool: D6: rock

tool: D36: scissors

tool: D25: lizard

tool: D31: paper

tool: D19: Spock

assistant: ```c
int rpsls(const char *player1, const char *player2) {
  if (!player1 || !player2)
    return 0;
  const char *cycle[] = {"rock", "scissors", "lizard", "paper", "Spock"};
  int i, j, tmp;
  for (i = 0; i < 5; i++) {
    if (strcmp(player1, cycle[i]) == 0) {
      for (j = 0; j <= 4; j++) {
        tmp = (i + j < 5) ? (i + j) : (i + j - 5);
        if (strcmp(player2, cycle[tmp]) == 0) {
          if (j == 0)
            return 0;
          else if (j <= 2)
            return 1;
          else
            return -1;
        }
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rpsls>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L68
  mov    %rdi,%r13
  mov    %rsi,%r14
  test   %rsi,%rsi
  je     L68
  lea    D37(%rip),%rax
  mov    %rax,(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D36(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D35(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    $0x0,%ebp
  jmp    L86
L9:
  test   %r12d,%r12d
  je     L15
  cmp    $0x3,%r12d
  setl   %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
  jmp    L15
L78:
  add    $0x1,%rbp
  cmp    $0x5,%rbp
  je     L58
L86:
  mov    (%rsp,%rbp,8),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L78
  mov    %ebp,%ebx
  mov    $0x0,%r12d
L74:
  lea    -0x5(%rbx),%eax
  cmp    $0x4,%ebx
  cmovle %ebx,%eax
  cltq
  mov    (%rsp,%rax,8),%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  add    $0x1,%r12d
  add    $0x1,%ebx
  cmp    $0x5,%r12d
  jne    L74
  jmp    L78
L58:
  mov    $0x0,%r12d
L15:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %r12d,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L68:
  mov    $0x0,%r12d
  jmp    L15
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D37
data_type: string
name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D36
data_type: string
name: read_data
arguments: tag: D35
data_type: string

tool: D37: rock

tool: D13: scissors

tool: D29: lizard

tool: D36: paper

tool: D35: Spock

assistant: ```c
int rpsls(const char *player1, const char *player2) {
  if (!player1 || !player2)
    return 0;
  const char *cycle[] = {"rock", "scissors", "lizard", "paper", "Spock"};
  int i, j, tmp;
  for (i = 0; i < 5; i++) {
    if (strcmp(player1, cycle[i]) == 0) {
      for (j = 0; j <= 4; j++) {
        tmp = (i + j < 5) ? (i + j) : (i + j - 5);
        if (strcmp(player2, cycle[tmp]) == 0) {
          if (j == 0)
            return 0;
          else if (j <= 2)
            return 1;
          else
            return -1;
        }
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rpsls>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L35
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L35
  lea    D38(%rip),%rax
  mov    %rdi,%rbp
  lea    D1(%rip),%rsi
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  lea    D35(%rip),%rax
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D2(%rip),%rax
  mov    %rsi,(%rsp)
  mov    %rax,0x20(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  je     L17
L30:
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  je     L35
  mov    (%rsp,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
L17:
  mov    %ebx,%r13d
  xor    %r14d,%r14d
L68:
  cmp    $0x4,%r13d
  lea    -0x5(%r13),%eax
  mov    %r12,%rdi
  cmovle %r13d,%eax
  cltq
  mov    (%rsp,%rax,8),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L0
  add    $0x1,%r14d
  add    $0x1,%r13d
  cmp    $0x5,%r14d
  jne    L68
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L35:
  xor    %eax,%eax
L96:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  test   %r14d,%r14d
  je     L35
  xor    %eax,%eax
  cmp    $0x3,%r14d
  setl   %al
  lea    -0x1(%rax,%rax,1),%eax
  jmp    L96
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D38
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D35
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D38: scissors

tool: D1: rock

tool: D35: lizard

tool: D13: paper

tool: D2: Spock

assistant: ```c
int rpsls(const char *player1, const char *player2) {
  if (!player1 || !player2)
    return 0;
  const char *cycle[] = {"rock", "scissors", "lizard", "paper", "Spock"};
  int i, j, tmp;
  for (i = 0; i < 5; i++) {
    if (strcmp(player1, cycle[i]) == 0) {
      for (j = 0; j <= 4; j++) {
        tmp = (i + j < 5) ? (i + j) : (i + j - 5);
        if (strcmp(player2, cycle[tmp]) == 0) {
          if (j == 0)
            return 0;
          else if (j <= 2)
            return 1;
          else
            return -1;
        }
      }
    }
  }
  return 0;
}
```