ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<slurp_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L0
  mov    $0xffffffffffffffff,%rax
  jmp    L37
L0:
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L24
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L37
L24:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x8(%rbp),%rax
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: r

assistant: ```c
size_t slurp_file(char *fname, char *buf, size_t len) {
  FILE *fh = fopen(fname, "r");
  if (!fh)
    return -1;
  ssize_t rlen = fread(buf, 1, len, fh);
  if (rlen < 0) {
    fclose(fh);
    return -1;
  }
  fclose(fh);
  return rlen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<slurp_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%r12
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L29
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L8
L19:
  mov    $0xffffffffffffffff,%rax
  jmp    L8
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: r

assistant: ```c
size_t slurp_file(char *fname, char *buf, size_t len) {
  FILE *fh = fopen(fname, "r");
  if (!fh)
    return -1;
  ssize_t rlen = fread(buf, 1, len, fh);
  if (rlen < 0) {
    fclose(fh);
    return -1;
  }
  fclose(fh);
  return rlen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<slurp_file>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <fread@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  test   %rax,%rax
  js     L16
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: r

assistant: ```c
size_t slurp_file(char *fname, char *buf, size_t len) {
  FILE *fh = fopen(fname, "r");
  if (!fh)
    return -1;
  ssize_t rlen = fread(buf, 1, len, fh);
  if (rlen < 0) {
    fclose(fh);
    return -1;
  }
  fclose(fh);
  return rlen;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<slurp_file>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D5(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L18
  mov    %r12,%rdi
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <fread@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  test   %rax,%rax
  js     L3
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  call   <fclose@plt>
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D5: r

assistant: ```c
size_t slurp_file(char *fname, char *buf, size_t len) {
  FILE *fh = fopen(fname, "r");
  if (!fh)
    return -1;
  ssize_t rlen = fread(buf, 1, len, fh);
  if (rlen < 0) {
    fclose(fh);
    return -1;
  }
  fclose(fh);
  return rlen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L96
L103:
  cmpb   $0x60,-0x11(%rbp)
  jle    L112
  cmpb   $0x7a,-0x11(%rbp)
  jle    L114
L112:
  cmpb   $0x40,-0x11(%rbp)
  jle    L63
  cmpb   $0x5a,-0x11(%rbp)
  jg     L63
L114:
  addl   $0x1,-0x10(%rbp)
  jmp    L96
L63:
  cmpb   $0x2f,-0x11(%rbp)
  jle    L113
  cmpb   $0x39,-0x11(%rbp)
  jg     L113
  addl   $0x1,-0x4(%rbp)
  jmp    L96
L113:
  cmpb   $0x20,-0x11(%rbp)
  jne    L21
  addl   $0x1,-0xc(%rbp)
  jmp    L96
L21:
  addl   $0x1,-0x8(%rbp)
L96:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0xa,-0x11(%rbp)
  jne    L103
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char c;
  int nword, nspace, nother, nnum;
  nword = nspace = nother = nnum = 0;
  while ((c = getchar()) != '\n') {
    if (c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z') {
      nword++;
    } else if (c >= '0' && c <= '9') {
      nnum++;
    } else if (c == ' ') {
      nspace++;
    } else {
      nother++;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L6
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char c;
  int nword, nspace, nother, nnum;
  nword = nspace = nother = nnum = 0;
  while ((c = getchar()) != '\n') {
    if (c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z') {
      nword++;
    } else if (c >= '0' && c <= '9') {
      nnum++;
    } else if (c == ' ') {
      nspace++;
    } else {
      nother++;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L8
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char c;
  int nword, nspace, nother, nnum;
  nword = nspace = nother = nnum = 0;
  while ((c = getchar()) != '\n') {
    if (c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z') {
      nword++;
    } else if (c >= '0' && c <= '9') {
      nnum++;
    } else if (c == ' ') {
      nspace++;
    } else {
      nother++;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L2
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  char c;
  int nword, nspace, nother, nnum;
  nword = nspace = nother = nnum = 0;
  while ((c = getchar()) != '\n') {
    if (c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z') {
      nword++;
    } else if (c >= '0' && c <= '9') {
      nnum++;
    } else if (c == ' ') {
      nspace++;
    } else {
      nother++;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sumfloats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float sumfloats(float *arr, int npts) {
  float sumVal;
  int i;
  sumVal = 0;
  for (i = 0; i < npts; i++)
    sumVal += arr[i];
  return sumVal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sumfloats>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L11:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
  ret
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float sumfloats(float *arr, int npts) {
  float sumVal;
  int i;
  sumVal = 0;
  for (i = 0; i < npts; i++)
    sumVal += arr[i];
  return sumVal;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumfloats>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L18:
  addss  (%rdi),%xmm0
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L18
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float sumfloats(float *arr, int npts) {
  float sumVal;
  int i;
  sumVal = 0;
  for (i = 0; i < npts; i++)
    sumVal += arr[i];
  return sumVal;
}
```
user: What is the c source code of the assembly code below:

```asm
<sumfloats>:
  endbr64
  test   %esi,%esi
  jle    L64
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L12
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L52:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L52
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L7
L10:
  movslq %eax,%rdx
  addss  (%rdi,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L36
  add    $0x2,%eax
  addss  0x4(%rdi,%rcx,1),%xmm0
  cmp    %eax,%esi
  jle    L36
  addss  0x8(%rdi,%rcx,1),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  pxor   %xmm0,%xmm0
L36:
  ret
  nopl   (%rax)
L7:
  ret
L12:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L10
```

assistant: ```c
float sumfloats(float *arr, int npts) {
  float sumVal;
  int i;
  sumVal = 0;
  for (i = 0; i < npts; i++)
    sumVal += arr[i];
  return sumVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parallel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  jmp    L3
L12:
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L52
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  imul   $0x7a120,%eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L55
L67:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  addl   $0x1,-0x10(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  imul   $0x7a120,%eax,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L67
  mov    $0x0,%edi
  call   <exit@plt>
L52:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  cmp    $0x3,%eax
  jle    L12
  movl   $0x1,-0x14(%rbp)
  jmp    L20
L32:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  cmp    $0x3,%eax
  jle    L32
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int parallel() {
  int i, j, pid;
  for (i = 1; i <= 3; i++) {
    pid = fork();
    if (pid == 0) {
      for (j = (i - 1) * (1500000 / 3) + 1; j <= i * (1500000 / 3); j++) {
        if (isPrime(j)) {
        }
      }
      exit(0);
    }
  }
  for (i = 1; i <= 3; i++) {
    wait(&i);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parallel>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  jmp    L31
L1:
  mov    $0x0,%edi
  call   <exit@plt>
L35:
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jg     L27
L31:
  call   <fork@plt>
  test   %eax,%eax
  jne    L35
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  imul   $0x7a120,%ebx,%ebx
  add    $0x1,%ebx
L69:
  mov    %ebx,%edi
  call   <isPrime@plt>
  add    $0x1,%ebx
  imul   $0x7a120,0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L69
  jmp    L1
L27:
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rbx
L46:
  mov    %rbx,%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jle    L46
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parallel() {
  int i, j, pid;
  for (i = 1; i <= 3; i++) {
    pid = fork();
    if (pid == 0) {
      for (j = (i - 1) * (1500000 / 3) + 1; j <= i * (1500000 / 3); j++) {
        if (isPrime(j)) {
        }
      }
      exit(0);
    }
  }
  for (i = 1; i <= 3; i++) {
    wait(&i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parallel>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L39:
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jg     L2
L60:
  call   <fork@plt>
  test   %eax,%eax
  jne    L39
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  imul   $0x7a120,%ebx,%ebx
  add    $0x1,%ebx
  nopl   0x0(%rax)
L58:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <isPrime@plt>
  imul   $0x7a120,0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L58
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jle    L60
L2:
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rbx,%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jle    L42
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parallel() {
  int i, j, pid;
  for (i = 1; i <= 3; i++) {
    pid = fork();
    if (pid == 0) {
      for (j = (i - 1) * (1500000 / 3) + 1; j <= i * (1500000 / 3); j++) {
        if (isPrime(j)) {
        }
      }
      exit(0);
    }
  }
  for (i = 1; i <= 3; i++) {
    wait(&i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parallel>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L36:
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jg     L6
L68:
  call   <fork@plt>
  test   %eax,%eax
  jne    L36
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  imul   $0x7a120,%ebx,%ebx
  add    $0x1,%ebx
  nopl   0x0(%rax)
L7:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <isPrime@plt>
  imul   $0x7a120,0x4(%rsp),%eax
  cmp    %ebx,%eax
  jge    L7
  xor    %edi,%edi
  call   <exit@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jle    L68
L6:
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rbx,%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x3,%eax
  jle    L34
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parallel() {
  int i, j, pid;
  for (i = 1; i <= 3; i++) {
    pid = fork();
    if (pid == 0) {
      for (j = (i - 1) * (1500000 / 3) + 1; j <= i * (1500000 / 3); j++) {
        if (isPrime(j)) {
        }
      }
      exit(0);
    }
  }
  for (i = 1; i <= 3; i++) {
    wait(&i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<scs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  movsbl %al,%edx
  cmpl   $0x0,-0x24(%rbp)
  je     L34
  mov    $0x29,%esi
  jmp    L52
L34:
  mov    $0x28,%esi
L52:
  lea    -0x12(%rbp),%rax
  mov    %edx,%ecx
  mov    %esi,%edx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <esc@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L40
  mov    $0x28,%edx
  jmp    L37
L40:
  mov    $0x29,%edx
L37:
  lea    -0x12(%rbp),%rax
  mov    $0x42,%ecx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <esc@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L44
  mov    $0xe,%eax
  jmp    L15
L44:
  mov    $0xf,%eax
L15:
  mov    %eax,%edi
  call   <send_char@plt>
  mov    $0x4,%edi
  call   <padding@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: %c%c

assistant: ```c
void scs(int g, int c) {
  char temp[10];
  sprintf(temp, "%c%c", g ? ')' : '(', c);
  esc(temp);
  sprintf(temp, "%c%c", g ? '(' : ')', 'B');
  esc(temp);
  send_char(g ? 0016 : 0017);
  padding(4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsbl %sil,%ecx
  test   %edi,%edi
  jne    L15
  lea    0xe(%rsp),%rbx
  mov    $0x28,%edx
  lea    D5(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    $0x29,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <esc@plt>
  mov    $0xf,%edi
  jmp    L25
L15:
  lea    0xe(%rsp),%rbx
  mov    $0x29,%edx
  lea    D5(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    $0x28,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <esc@plt>
  mov    $0xe,%edi
L25:
  call   <send_char@plt>
  mov    $0x4,%edi
  call   <padding@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %c%c

assistant: ```c
void scs(int g, int c) {
  char temp[10];
  sprintf(temp, "%c%c", g ? ')' : '(', c);
  esc(temp);
  sprintf(temp, "%c%c", g ? '(' : ')', 'B');
  esc(temp);
  send_char(g ? 0016 : 0017);
  padding(4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<scs>:
  endbr64
  push   %r12
  movsbl %sil,%ecx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L13
  lea    0xe(%rsp),%rbp
  lea    D14(%rip),%r12
  mov    $0x29,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x28,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0xe,%edi
L19:
  call   <send_char@plt>
  mov    $0x4,%edi
  call   <padding@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    0xe(%rsp),%rbp
  lea    D14(%rip),%r12
  mov    $0x28,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x29,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0xf,%edi
  jmp    L19
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string

tool: D14: %c%c

assistant: ```c
void scs(int g, int c) {
  char temp[10];
  sprintf(temp, "%c%c", g ? ')' : '(', c);
  esc(temp);
  sprintf(temp, "%c%c", g ? '(' : ')', 'B');
  esc(temp);
  send_char(g ? 0016 : 0017);
  padding(4);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scs>:
  endbr64
  push   %r12
  movsbl %sil,%ecx
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L18
  lea    0xe(%rsp),%rbp
  lea    D14(%rip),%r12
  mov    $0x29,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x28,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0xe,%edi
L5:
  call   <send_char@plt>
  mov    $0x4,%edi
  call   <padding@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  lea    0xe(%rsp),%rbp
  lea    D14(%rip),%r12
  mov    $0x28,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0x42,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x29,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <esc@plt>
  mov    $0xf,%edi
  jmp    L5
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
data_type: string

tool: D14: %c%c

assistant: ```c
void scs(int g, int c) {
  char temp[10];
  sprintf(temp, "%c%c", g ? ')' : '(', c);
  esc(temp);
  sprintf(temp, "%c%c", g ? '(' : ')', 'B');
  esc(temp);
  send_char(g ? 0016 : 0017);
  padding(4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ExternTypeSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x4,-0x8(%rbp)
  je     L97
  cmpl   $0x4,-0x8(%rbp)
  jg     L61
  cmpl   $0x3,-0x8(%rbp)
  je     L3
  cmpl   $0x3,-0x8(%rbp)
  jg     L61
  cmpl   $0x1,-0x8(%rbp)
  je     L18
  cmpl   $0x2,-0x8(%rbp)
  je     L15
  jmp    L61
L18:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <EdrTypeSize@plt>
  jmp    L98
L15:
  mov    -0x4(%rbp),%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <EdrTypeSize@plt>
  jmp    L98
L3:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <NativeTypeSize@plt>
  jmp    L98
L97:
  mov    $0xffffffffffffffff,%rax
  jmp    L98
L61:
  mov    $0xffffffffffffffff,%rax
L98:
  leave
  ret
```

assistant: ```c
long ExternTypeSize(int type, int arch) {
  switch (arch) {
  case 1:
    return EdrTypeSize(type, 1);
    break;
  case 2:
    return EdrTypeSize(type, 2);
    break;
  case 3:
    return NativeTypeSize(type);
    break;
  case 4:
    return -1;
    break;
  default:
    return -1;
    break;
  }
}
```