ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  addq   $0x4,-0x48(%rbp)
  addq   $0x4,-0x50(%rbp)
  push   $0x4
  push   $0x8
  mov    $0xc,%r9d
  mov    $0x8,%r8d
  mov    $0x28,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d


assistant: ```c
int f(int a[], int a2[73], int m[][3]) {
  int b[10];
  int c[10];
  int *p = (int *)malloc(sizeof(int) * 10);
  a++;
  a2++;
  printf("a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d\n", sizeof(a), sizeof(a2), sizeof(b), sizeof(m), sizeof(m[1]), sizeof(p), sizeof(int));
  a = b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  push   $0x4
  push   $0x8
  mov    $0xc,%r9d
  mov    $0x8,%r8d
  mov    $0x28,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d


assistant: ```c
int f(int a[], int a2[73], int m[][3]) {
  int b[10];
  int c[10];
  int *p = (int *)malloc(sizeof(int) * 10);
  a++;
  a2++;
  printf("a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d\n", sizeof(a), sizeof(a2), sizeof(b), sizeof(m), sizeof(m[1]), sizeof(p), sizeof(int));
  a = b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  push   $0x4
  mov    $0xc,%r9d
  mov    $0x8,%r8d
  push   $0x8
  mov    $0x28,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D5: a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d


assistant: ```c
int f(int a[], int a2[73], int m[][3]) {
  int b[10];
  int c[10];
  int *p = (int *)malloc(sizeof(int) * 10);
  a++;
  a2++;
  printf("a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d\n", sizeof(a), sizeof(a2), sizeof(b), sizeof(m), sizeof(m[1]), sizeof(p), sizeof(int));
  a = b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  push   $0x4
  mov    $0xc,%r9d
  mov    $0x8,%r8d
  push   $0x8
  mov    $0x28,%ecx
  mov    $0x8,%edx
  mov    $0x8,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d


assistant: ```c
int f(int a[], int a2[73], int m[][3]) {
  int b[10];
  int c[10];
  int *p = (int *)malloc(sizeof(int) * 10);
  a++;
  a2++;
  printf("a: %d / a2: %d / b: %d / m: %d / m[0]: %d / p: %d / int: %d\n", sizeof(a), sizeof(a2), sizeof(b), sizeof(m), sizeof(m[1]), sizeof(p), sizeof(int));
  a = b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fb_move_cursor_rc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movzwl -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzwl -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  mov    %eax,%edi
  call   <fb_move_cursor@plt>
  nop
  leave
  ret
```

assistant: ```c
void fb_move_cursor_rc(unsigned short row, unsigned short col) {
  unsigned short position = (row * (80)) + col;
  fb_move_cursor(position);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fb_move_cursor_rc>:
  endbr64
  sub    $0x8,%rsp
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  add    %esi,%edi
  movzwl %di,%edi
  call   <fb_move_cursor@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fb_move_cursor_rc(unsigned short row, unsigned short col) {
  unsigned short position = (row * (80)) + col;
  fb_move_cursor(position);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fb_move_cursor_rc>:
  endbr64
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  add    %esi,%edi
  movzwl %di,%edi
  jmp    1050 <fb_move_cursor@plt>
```

assistant: ```c
void fb_move_cursor_rc(unsigned short row, unsigned short col) {
  unsigned short position = (row * (80)) + col;
  fb_move_cursor(position);
}
```
user: What is the c source code of the assembly code below?

```asm
<fb_move_cursor_rc>:
  endbr64
  lea    (%rdi,%rdi,4),%edi
  shl    $0x4,%edi
  add    %esi,%edi
  movzwl %di,%edi
  jmp    1050 <fb_move_cursor@plt>
```

assistant: ```c
void fb_move_cursor_rc(unsigned short row, unsigned short col) {
  unsigned short position = (row * (80)) + col;
  fb_move_cursor(position);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L9
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  jmp    L13
L9:
  mov    $0x0,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
L13:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    int k;
    for (k = 1; k < argc; ++k) {
      test1d(atoi(argv[k]), 0);
      test1d(atoi(argv[k]), 1);
    }
  } else {
    test1d(32, 0);
    test1d(32, 1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L2
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L13:
  mov    (%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    $0x0,%esi
  call   <test1d@plt>
  mov    (%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    $0x1,%esi
  call   <test1d@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L13
L24:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    $0x0,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  jmp    L24
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    int k;
    for (k = 1; k < argc; ++k) {
      test1d(atoi(argv[k]), 0);
      test1d(atoi(argv[k]), 1);
    }
  } else {
    test1d(32, 0);
    test1d(32, 1);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L27
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L23:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  xor    %esi,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  mov    -0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  cmp    %rbp,%rbx
  jne    L23
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  xor    %esi,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  jmp    L12
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    int k;
    for (k = 1; k < argc; ++k) {
      test1d(atoi(argv[k]), 0);
      test1d(atoi(argv[k]), 1);
    }
  } else {
    test1d(32, 0);
    test1d(32, 1);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L22
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  xor    %esi,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  mov    -0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <test1d@plt>
  cmp    %rbp,%rbx
  jne    L19
L12:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  xor    %esi,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  mov    $0x1,%esi
  mov    $0x20,%edi
  call   <test1d@plt>
  jmp    L12
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc > 1) {
    int k;
    for (k = 1; k < argc; ++k) {
      test1d(atoi(argv[k]), 0);
      test1d(atoi(argv[k]), 1);
    }
  } else {
    test1d(32, 0);
    test1d(32, 1);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x40(%rbp)
  je     L17
  cmpq   $0x1,-0x40(%rbp)
  je     L17
  movq   $0x1,-0x30(%rbp)
  movq   $0x1,-0x28(%rbp)
  movq   $0x1,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <power>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    0x8(%rax),%rcx
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    -0x38(%rbp),%rdx
  mov    %rax,0x8(%rdx)
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x38(%rbp),%rax
  lea    0x10(%rax),%rsi
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,(%rsi)
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    0x8(%rax),%rcx
  mov    -0x38(%rbp),%rax
  lea    0x10(%rax),%rsi
  movabs $0x89705f3112a28fe5,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x1d,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x3b9aca07,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,0x8(%rsi)
  mov    -0x38(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <multiply@plt>
  mov    -0x40(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L25
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <multiply@plt>
  jmp    L25
L17:
  nop
L25:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void power(long long int F[2][2], long long int n) {
  if (n == 0 || n == 1)
    return;
  long long int M[2][2] = {{1, 1}, {1, 0}};
  power(F, n / 2);
  F[0][0] %= 1000000007;
  F[0][1] %= 1000000007;
  F[1][0] %= 1000000007;
  F[1][1] %= 1000000007;
  multiply(F, F);
  if (n % 2 != 0)
    multiply(F, M);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<power>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rsi
  jbe    L18
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movq   $0x1,(%rsp)
  movq   $0x1,0x8(%rsp)
  movq   $0x1,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  shr    $0x3f,%rsi
  add    %rbp,%rsi
  sar    %rsi
  call   <power>
  mov    (%rbx),%rsi
  movabs $0x89705f3112a28fe5,%rcx
  mov    %rsi,%rax
  imul   %rcx
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,(%rbx)
  mov    0x8(%rbx),%rsi
  mov    %rsi,%rax
  imul   %rcx
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rbx)
  mov    0x10(%rbx),%rsi
  mov    %rsi,%rax
  imul   %rcx
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x10(%rbx)
  mov    0x18(%rbx),%rsi
  mov    %rsi,%rax
  imul   %rcx
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x18(%rbx)
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <multiply@plt>
  test   $0x1,%bpl
  jne    L21
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <multiply@plt>
  jmp    L18
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void power(long long int F[2][2], long long int n) {
  if (n == 0 || n == 1)
    return;
  long long int M[2][2] = {{1, 1}, {1, 0}};
  power(F, n / 2);
  F[0][0] %= 1000000007;
  F[0][1] %= 1000000007;
  F[1][0] %= 1000000007;
  F[1][1] %= 1000000007;
  multiply(F, F);
  if (n % 2 != 0)
    multiply(F, M);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rsi
  jbe    L8
  mov    %rsi,%rbx
  shr    $0x3f,%rsi
  mov    %rdi,%rbp
  movq   $0x1,(%rsp)
  movq   $0x1,0x8(%rsp)
  add    %rbx,%rsi
  movq   $0x1,0x10(%rsp)
  sar    %rsi
  movq   $0x0,0x18(%rsp)
  call   <power>
  mov    0x0(%rbp),%rsi
  mov    %rbp,%rdi
  movabs $0x89705f3112a28fe5,%rcx
  mov    %rsi,%rax
  imul   %rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x0(%rbp)
  mov    0x8(%rbp),%rsi
  mov    %rsi,%rax
  imul   %rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x8(%rbp)
  mov    0x10(%rbp),%rsi
  mov    %rsi,%rax
  imul   %rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x10(%rbp)
  mov    0x18(%rbp),%rsi
  mov    %rsi,%rax
  imul   %rcx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  add    %rsi,%rdx
  sar    $0x1d,%rdx
  sub    %rax,%rdx
  imul   $0x3b9aca07,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %rsi,0x18(%rbp)
  mov    %rbp,%rsi
  call   <multiply@plt>
  and    $0x1,%ebx
  jne    L18
L8:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L18:
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <multiply@plt>
  jmp    L8
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void power(long long int F[2][2], long long int n) {
  if (n == 0 || n == 1)
    return;
  long long int M[2][2] = {{1, 1}, {1, 0}};
  power(F, n / 2);
  F[0][0] %= 1000000007;
  F[0][1] %= 1000000007;
  F[1][0] %= 1000000007;
  F[1][1] %= 1000000007;
  multiply(F, F);
  if (n % 2 != 0)
    multiply(F, M);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<internal_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L22:
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L39:
  cmpl   $0x0,-0xc(%rbp)
  jle    L8
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jg     L22
L8:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: string

tool: D0: read: 

assistant: ```c
void internal_read(int socket, void *buffer, size_t size) {
  int notread = size, recv_return = 0, received = 0;
  while (notread > 0 && (recv_return = read(socket, buffer + received, notread)) > 0) {
    notread -= recv_return;
    received += recv_return;
  }
  if (recv_return == -1) {
    perror("read: ");
    abort();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<internal_read>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    $0x0,%ebp
  test   %edx,%edx
  jle    L30
L31:
  movslq %ebp,%rsi
  add    %r12,%rsi
  mov    %ebx,%edx
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L35
  sub    %eax,%ebx
  add    %eax,%ebp
  test   %ebx,%ebx
  jg     L31
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  cmp    $0xffffffff,%eax
  jne    L30
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: read: 

assistant: ```c
void internal_read(int socket, void *buffer, size_t size) {
  int notread = size, recv_return = 0, received = 0;
  while (notread > 0 && (recv_return = read(socket, buffer + received, notread)) > 0) {
    notread -= recv_return;
    received += recv_return;
  }
  if (recv_return == -1) {
    perror("read: ");
    abort();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<internal_read>:
  endbr64
  test   %edx,%edx
  jle    L22
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L1
  nop
L46:
  sub    %eax,%r12d
  add    %eax,%r13d
  test   %r12d,%r12d
  jle    L41
L1:
  movslq %r13d,%rsi
  mov    %r12d,%edx
  mov    %ebp,%edi
  add    %rbx,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L46
  cmp    $0xffffffff,%eax
  jne    L41
  lea    D2(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <abort@plt>
  nopl   0x0(%rax)
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string

tool: D2: read: 

assistant: ```c
void internal_read(int socket, void *buffer, size_t size) {
  int notread = size, recv_return = 0, received = 0;
  while (notread > 0 && (recv_return = read(socket, buffer + received, notread)) > 0) {
    notread -= recv_return;
    received += recv_return;
  }
  if (recv_return == -1) {
    perror("read: ");
    abort();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<internal_read>:
  endbr64
  test   %edx,%edx
  jle    L13
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L49
  nop
L24:
  sub    %eax,%r12d
  add    %eax,%r13d
  test   %r12d,%r12d
  jle    L28
L49:
  movslq %r13d,%rsi
  mov    %r12d,%edx
  mov    %ebp,%edi
  add    %rbx,%rsi
  call   <read@plt>
  test   %eax,%eax
  jg     L24
  cmp    $0xffffffff,%eax
  jne    L28
  lea    D1(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <abort@plt>
  nopl   0x0(%rax)
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: read: 

assistant: ```c
void internal_read(int socket, void *buffer, size_t size) {
  int notread = size, recv_return = 0, received = 0;
  while (notread > 0 && (recv_return = read(socket, buffer + received, notread)) > 0) {
    notread -= recv_return;
    received += recv_return;
  }
  if (recv_return == -1) {
    perror("read: ");
    abort();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_space>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L11:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9:  

assistant: ```c
void print_space(int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf(" ");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_space>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L15:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2:  

assistant: ```c
void print_space(int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf(" ");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_space>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3:  

assistant: ```c
void print_space(int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf(" ");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_space>:
  endbr64
  test   %edi,%edi
  jle    L1
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type_infered: string

tool: D2:  

assistant: ```c
void print_space(int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf(" ");
  }
}
```