ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<podpunkt_a>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movslq %esi,%rsi
  movl   $0x0,(%rdi,%rsi,4)
  movl   $0x1,0x4(%rdi,%rsi,4)
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x6,%ebx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x6,%esi
  mov    %r12,%rdi
  call   <wypisz_tab@plt>
  lea    D19(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type: string
name: extract_symbolic_data
arguments: label: D11
type: string
name: extract_symbolic_data
arguments: label: D5
type: string
name: extract_symbolic_data
arguments: label: D19
type: string

tool: D24: 
Sprawdzenie_1:

tool: D11: tab[a++]=0, tab[++a]=1:

tool: D5: %d 

tool: D19: To nie to samo!

assistant: ```c
void podpunkt_a(int tab[], int a) {
  int i, tmp;
  tmp = a;
  tab[a++] = 0;
  a = tmp;
  tab[++a] = 1;
  printf("\nSprawdzenie_1:\n");
  printf("tab[a++]=0, tab[++a]=1:\n");
  for (i = 0; i < 6; ++i)
    printf("%d ", i);
  printf("\n");
  wypisz_tab(tab, 6);
  printf("To nie to samo!\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<podpunkt_a>:
  endbr64
  movslq %esi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  movl   $0x0,(%rdi,%rsi,4)
  movl   $0x1,0x4(%rdi,%rsi,4)
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  xchg   %ax,%ax
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12,%rdi
  mov    $0x6,%esi
  call   <wypisz_tab@plt>
  pop    %rbx
  lea    D22(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D33
type: string
name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D22
type: string

tool: D14: %d 

tool: D33: 
Sprawdzenie_1:

tool: D7: tab[a++]=0, tab[++a]=1:

tool: D22: To nie to samo!

assistant: ```c
void podpunkt_a(int tab[], int a) {
  int i, tmp;
  tmp = a;
  tab[a++] = 0;
  a = tmp;
  tab[++a] = 1;
  printf("\nSprawdzenie_1:\n");
  printf("tab[a++]=0, tab[++a]=1:\n");
  for (i = 0; i < 6; ++i)
    printf("%d ", i);
  printf("\n");
  wypisz_tab(tab, 6);
  printf("To nie to samo!\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<podpunkt_a>:
  endbr64
  mov    D18(%rip),%rax
  movslq %esi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %rax,(%rdi,%rsi,4)
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12,%rdi
  mov    $0x6,%esi
  call   <wypisz_tab@plt>
  pop    %rbx
  lea    D37(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D38
type_guessed: string
name: extract_symbolic_data
arguments: label: D37
type_guessed: string

tool: {"D18": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D16: %d 

tool: D39: 
Sprawdzenie_1:

tool: D38: tab[a++]=0, tab[++a]=1:

tool: D37: To nie to samo!

assistant: ```c
void podpunkt_a(int tab[], int a) {
  int i, tmp;
  tmp = a;
  tab[a++] = 0;
  a = tmp;
  tab[++a] = 1;
  printf("\nSprawdzenie_1:\n");
  printf("tab[a++]=0, tab[++a]=1:\n");
  for (i = 0; i < 6; ++i)
    printf("%d ", i);
  printf("\n");
  wypisz_tab(tab, 6);
  printf("To nie to samo!\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nBit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x1c,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  mov    -0x10(%rbp),%rdx
  lea    -0x1a(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x18(%rbp)
  movzwl -0x1a(%rbp),%eax
  cwtl
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: r

assistant: ```c
int nBit(char *filename) {
  FILE *fp;
  short short_var;
  int n, nBit;
  fp = fopen(filename, "r");
  fseek(fp, 28, 0);
  n = fread(&short_var, sizeof(short), 1, fp);
  nBit = short_var;
  fclose(fp);
  return nBit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nBit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0x1c,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x6(%rsp),%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  movswl 0x6(%rsp),%ebp
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: r

assistant: ```c
int nBit(char *filename) {
  FILE *fp;
  short short_var;
  int n, nBit;
  fp = fopen(filename, "r");
  fseek(fp, 28, 0);
  n = fread(&short_var, sizeof(short), 1, fp);
  nBit = short_var;
  fclose(fp);
  return nBit;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nBit>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edx,%edx
  mov    $0x1c,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x6(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  movswl 0x6(%rsp),%r12d
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: r

assistant: ```c
int nBit(char *filename) {
  FILE *fp;
  short short_var;
  int n, nBit;
  fp = fopen(filename, "r");
  fseek(fp, 28, 0);
  n = fread(&short_var, sizeof(short), 1, fp);
  nBit = short_var;
  fclose(fp);
  return nBit;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nBit>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  xor    %edx,%edx
  mov    $0x1c,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <fseek@plt>
  lea    0x6(%rsp),%rdi
  mov    %rbp,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fread@plt>
  mov    %rbp,%rdi
  movswl 0x6(%rsp),%r12d
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: r

assistant: ```c
int nBit(char *filename) {
  FILE *fp;
  short short_var;
  int n, nBit;
  fp = fopen(filename, "r");
  fseek(fp, 28, 0);
  n = fread(&short_var, sizeof(short), 1, fp);
  nBit = short_var;
  fclose(fp);
  return nBit;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ModelicaFormatError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void ModelicaFormatError(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vfprintf(stderr, string, p_arg);
  va_end(p_arg);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ModelicaFormatError>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ModelicaFormatError(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vfprintf(stderr, string, p_arg);
  va_end(p_arg);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ModelicaFormatError>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ModelicaFormatError(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vfprintf(stderr, string, p_arg);
  va_end(p_arg);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ModelicaFormatError>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ModelicaFormatError(const char *string, ...) {
  va_list p_arg;
  va_start(p_arg, string);
  vfprintf(stderr, string, p_arg);
  va_end(p_arg);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tty_in_ttygrp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <getgrgid@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L17
L12:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  mov    $0x0,%eax
  jmp    L17
L34:
  mov    $0x1,%eax
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: tty

assistant: ```c
int tty_in_ttygrp(struct stat *st) {
  struct group *gr;
  if ((gr = getgrgid(st->st_gid)) == NULL)
    return 0;
  if (strcmp(gr->gr_name, "tty") != 0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tty_in_ttygrp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <getgrgid@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L7
  lea    D9(%rip),%rsi
  mov    (%rax),%edi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
L7:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: tty

assistant: ```c
int tty_in_ttygrp(struct stat *st) {
  struct group *gr;
  if ((gr = getgrgid(st->st_gid)) == NULL)
    return 0;
  if (strcmp(gr->gr_name, "tty") != 0)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tty_in_ttygrp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <getgrgid@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L0
  mov    (%rax),%edi
  lea    D1(%rip),%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L0:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: tty

assistant: ```c
int tty_in_ttygrp(struct stat *st) {
  struct group *gr;
  if ((gr = getgrgid(st->st_gid)) == NULL)
    return 0;
  if (strcmp(gr->gr_name, "tty") != 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tty_in_ttygrp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <getgrgid@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L3
  mov    (%rax),%edi
  lea    D1(%rip),%rsi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  sete   %r8b
L3:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: tty

assistant: ```c
int tty_in_ttygrp(struct stat *st) {
  struct group *gr;
  if ((gr = getgrgid(st->st_gid)) == NULL)
    return 0;
  if (strcmp(gr->gr_name, "tty") != 0)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uart_tx_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_tx_char@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_tx_string(char string[15]) {
  int a = 0;
  while (string[a] != '\0') {
    uart_tx_char(string[a]);
    a += 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uart_tx_string>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L8
  push   %rbx
  lea    0x1(%rdi),%rbx
L7:
  movsbl %al,%edi
  call   <uart_tx_char@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L7
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void uart_tx_string(char string[15]) {
  int a = 0;
  while (string[a] != '\0') {
    uart_tx_char(string[a]);
    a += 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_tx_string>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L14
  push   %rbx
  lea    0x1(%rdi),%rbx
L10:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <uart_tx_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L10
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void uart_tx_string(char string[15]) {
  int a = 0;
  while (string[a] != '\0') {
    uart_tx_char(string[a]);
    a += 1;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<uart_tx_string>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L19
  push   %rbx
  lea    0x1(%rdi),%rbx
L4:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <uart_tx_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L4
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void uart_tx_string(char string[15]) {
  int a = 0;
  while (string[a] != '\0') {
    uart_tx_char(string[a]);
    a += 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L64
  lea    0x1(%rsp),%rax
  mov    $0x4e,%edx
  mov    $0x7e03bf,%edi
  mov    $0x53,%esi
  jmp    L28
L31:
  mov    $0x53,%edx
L62:
  add    $0x1,%rax
  movzbl -0x1(%rax),%ecx
  test   %cl,%cl
  je     L78
L28:
  sub    $0x30,%ecx
  cmp    $0x16,%cl
  ja     L31
  mov    %rdi,%r8
  shr    %cl,%r8
  test   $0x1,%r8b
  cmove  %esi,%edx
  jmp    L62
L78:
  cmp    $0x4e,%dl
  je     L64
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L45:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L64:
  mov    %rsp,%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D32
data_type: string

tool: D11: Digite um numero: 

tool: D39: %s

tool: D21: O numero %s nao e' hexadecimal

tool: D32: O numero %s e' hexadecimal

assistant: ```c
main() {
  char numero[100], s = 'N';
  int i = 0;
  printf("Digite um numero: ");
  scanf("%s", &numero);
  for (; numero[i] != '\0'; i++) {
    if ((numero[i] != '0') & (numero[i] != '1') & (numero[i] != '2') & (numero[i] != '3') & (numero[i] != '4') & (numero[i] != '5') & (numero[i] != '5') & (numero[i] != '7') & (numero[i] != '8') & (numero[i] != '9') & (numero[i] != 'A') & (numero[i] != 'B') & (numero[i] != 'C') & (numero[i] != 'D') & (numero[i] != 'E') & (numero[i] != 'F'))
      s = 'S';
  }
  if (s == 'N')
    printf("O numero %s e' hexadecimal", numero);
  else
    printf("O numero %s nao e' hexadecimal", numero);
  getchar();
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L26
  lea    0x1(%rsp),%rax
  mov    $0x4e,%edx
  mov    $0x53,%esi
  mov    $0xffffffffff81fc40,%rdi
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %rdi,%r8
  sar    %cl,%r8
  mov    %r8,%rcx
  and    $0x1,%ecx
  cmovne %esi,%edx
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L39
L22:
  sub    $0x30,%ecx
  cmp    $0x16,%cl
  jbe    L62
  movzbl (%rax),%ecx
  add    $0x1,%rax
  mov    $0x53,%edx
  test   %cl,%cl
  jne    L22
L39:
  cmp    $0x4e,%dl
  je     L26
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L68:
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L26:
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L68
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D34
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D28
type_infered: string

tool: D34: Digite um numero: 

tool: D6: %s

tool: D12: O numero %s nao e' hexadecimal

tool: D28: O numero %s e' hexadecimal

assistant: ```c
main() {
  char numero[100], s = 'N';
  int i = 0;
  printf("Digite um numero: ");
  scanf("%s", &numero);
  for (; numero[i] != '\0'; i++) {
    if ((numero[i] != '0') & (numero[i] != '1') & (numero[i] != '2') & (numero[i] != '3') & (numero[i] != '4') & (numero[i] != '5') & (numero[i] != '5') & (numero[i] != '7') & (numero[i] != '8') & (numero[i] != '9') & (numero[i] != 'A') & (numero[i] != 'B') & (numero[i] != 'C') & (numero[i] != 'D') & (numero[i] != 'E') & (numero[i] != 'F'))
      s = 'S';
  }
  if (s == 'N')
    printf("O numero %s e' hexadecimal", numero);
  else
    printf("O numero %s nao e' hexadecimal", numero);
  getchar();
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%ecx
  test   %cl,%cl
  je     L70
  lea    0x1(%rsp),%rax
  mov    $0x4e,%edx
  mov    $0x53,%esi
  mov    $0xffffffffff81fc40,%rdi
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %rdi,%r8
  sar    %cl,%r8
  mov    %r8,%rcx
  and    $0x1,%ecx
  cmovne %esi,%edx
  movzbl (%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L60
L1:
  sub    $0x30,%ecx
  cmp    $0x16,%cl
  jbe    L77
  movzbl (%rax),%ecx
  add    $0x1,%rax
  mov    $0x53,%edx
  test   %cl,%cl
  jne    L1
L60:
  cmp    $0x4e,%dl
  je     L70
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L51:
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L70:
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L51
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D19
type: string
name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D1
type: string

tool: D12: Digite um numero: 

tool: D19: %s

tool: D3: O numero %s nao e' hexadecimal

tool: D1: O numero %s e' hexadecimal

assistant: ```c
main() {
  char numero[100], s = 'N';
  int i = 0;
  printf("Digite um numero: ");
  scanf("%s", &numero);
  for (; numero[i] != '\0'; i++) {
    if ((numero[i] != '0') & (numero[i] != '1') & (numero[i] != '2') & (numero[i] != '3') & (numero[i] != '4') & (numero[i] != '5') & (numero[i] != '5') & (numero[i] != '7') & (numero[i] != '8') & (numero[i] != '9') & (numero[i] != 'A') & (numero[i] != 'B') & (numero[i] != 'C') & (numero[i] != 'D') & (numero[i] != 'E') & (numero[i] != 'F'))
      s = 'S';
  }
  if (s == 'N')
    printf("O numero %s e' hexadecimal", numero);
  else
    printf("O numero %s nao e' hexadecimal", numero);
  getchar();
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<nan_eq_jump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L1
  ucomisd %xmm1,%xmm0
  jne    L1
  mov    $0x1,%eax
  jmp    L19
L1:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int nan_eq_jump(double x) {
  volatile double y = x;
  volatile double z = y;
  if (y == z) {
    return 1;
  }
  return 0;
}
```