ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<raydirections>:
  endbr64
  mov    %edx,%r11d
  mov    %ecx,%r10d
  mov    %edi,%eax
  sub    %edi,%r11d
  sub    %esi,%r10d
  test   %r11d,%r11d
  jle    L74
  mov    $0x1,%edi
  mov    $0x2,%eax
  test   %r10d,%r10d
  jle    L126
  cmp    %r10d,%r11d
  jg     L62
L52:
  mov    %edi,(%r8)
  mov    %eax,%edi
L66:
  mov    %edi,(%r9)
  ret
  nopl   0x0(%rax)
L62:
  mov    %eax,(%r8)
  mov    %edi,(%r9)
  ret
  nop
L126:
  je     L19
  sub    %ecx,%esi
  mov    $0x3,%edi
  mov    %esi,%r10d
  cmp    %r10d,%r11d
  jle    L52
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L74:
  je     L40
  mov    $0x1,%edi
  test   %r10d,%r10d
  jle    L80
L85:
  sub    %edx,%eax
  mov    %eax,%r11d
  xor    %eax,%eax
  cmp    %r10d,%r11d
  jle    L52
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L80:
  je     L30
  sub    %ecx,%esi
  mov    $0x3,%edi
  mov    %esi,%r10d
  jmp    L85
  cs nopw 0x0(%rax,%rax,1)
L19:
  movl   $0x2,(%r8)
  mov    $0xffffffff,%edi
  jmp    L66
  xchg   %ax,%ax
L40:
  mov    $0x1,%eax
  test   %r10d,%r10d
  jg     L122
  cmp    $0x1,%r10d
  sbb    %eax,%eax
  or     $0x3,%eax
L122:
  mov    $0xffffffff,%edi
  mov    %eax,(%r8)
  mov    %edi,(%r9)
  ret
  nop
L30:
  movl   $0x0,(%r8)
  mov    $0xffffffff,%edi
  jmp    L66
```

assistant: ```c
void raydirections(int y0, int x0, int y, int x, int *dir1, int *dir2) {
  int dy, dx;
  int ydir, xdir;
  dy = y - y0;
  dx = x - x0;
  if (dy > 0) {
    if (dx > 0) {
      ydir = 2;
      xdir = 1;
    } else if (dx < 0) {
      ydir = 2;
      xdir = 3;
      dx = -dx;
    } else {
      *dir1 = 2;
      *dir2 = -1;
      return;
    }
  } else if (dy < 0) {
    if (dx > 0) {
      ydir = 0;
      xdir = 1;
    } else if (dx < 0) {
      ydir = 0;
      xdir = 3;
      dx = -dx;
    } else {
      *dir1 = 0;
      *dir2 = -1;
      return;
    }
    dy = -dy;
  } else {
    if (dx > 0)
      *dir1 = 1;
    else if (dx < 0)
      *dir1 = 3;
    else
      *dir1 = -1;
    *dir2 = -1;
    return;
  }
  if (dy > dx) {
    *dir1 = ydir;
    *dir2 = xdir;
  } else {
    *dir1 = xdir;
    *dir2 = ydir;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L39:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L35
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L39
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D35
datatype: string

tool: D22: Tus argumentos son: 

tool: D16: Argumento %d: %s, de longitud %d


tool: D13: 	Con valores: 

tool: D35: '%c' 

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, len = 0, j = 0;
  printf("Tus argumentos son: \n");
  for (i = 0; i < argc; i++) {
    len = strlen(*(argv + i));
    printf("Argumento %d: %s, de longitud %d\n", i, *(argv + i), len);
    printf("\tCon valores: ");
    for (j = 0; j < len; j++) {
      printf("'%c' ", *(*(argv + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %edi,0xc(%rsp)
  mov    %rsi,%r14
  lea    D24(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L37
  mov    $0x0,%r15d
  lea    D21(%rip),%r13
L25:
  mov    %r14,%r12
  mov    (%r14),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%ecx
  mov    (%r14),%rdx
  mov    %r15d,%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L31
  mov    %ebp,%ebp
  mov    $0x0,%ebx
L29:
  mov    (%r12),%rax
  movsbl (%rax,%rbx,1),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15d
  add    $0x8,%r14
  cmp    %r15d,0xc(%rsp)
  jne    L25
L37:
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string
name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string

tool: D24: Tus argumentos son: 

tool: D21: '%c' 

tool: D29: Argumento %d: %s, de longitud %d


tool: D1: 	Con valores: 

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, len = 0, j = 0;
  printf("Tus argumentos son: \n");
  for (i = 0; i < argc; i++) {
    len = strlen(*(argv + i));
    printf("Argumento %d: %s, de longitud %d\n", i, *(argv + i), len);
    printf("\tCon valores: ");
    for (j = 0; j < len; j++) {
      printf("'%c' ", *(*(argv + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D2(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L21
  xor    %r13d,%r13d
  lea    D1(%rip),%r15
  lea    D15(%rip),%r12
L25:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdx
  mov    %r15,%rdi
  mov    %r13d,%esi
  movslq %eax,%rbx
  xor    %eax,%eax
  mov    %ebx,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L30
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L2:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  movsbl (%rax,%r14,1),%esi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L2
L30:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r13d,0xc(%rsp)
  jne    L25
L21:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D2: Tus argumentos son: 

tool: D1: Argumento %d: %s, de longitud %d


tool: D15: '%c' 

tool: D24: 	Con valores: 

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, len = 0, j = 0;
  printf("Tus argumentos son: \n");
  for (i = 0; i < argc; i++) {
    len = strlen(*(argv + i));
    printf("Argumento %d: %s, de longitud %d\n", i, *(argv + i), len);
    printf("\tCon valores: ");
    for (j = 0; j < len; j++) {
      printf("'%c' ", *(*(argv + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    D8(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L1
  xor    %r13d,%r13d
  lea    D32(%rip),%r15
  lea    D2(%rip),%r12
L3:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdx
  mov    %r15,%rdi
  mov    %r13d,%esi
  movslq %eax,%rbx
  xor    %eax,%eax
  mov    %ebx,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L25
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L2:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  movsbl (%rax,%r14,1),%esi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L2
L25:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r13d,0xc(%rsp)
  jne    L3
L1:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D32
type_guessed: string
name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string

tool: D8: Tus argumentos son: 

tool: D32: Argumento %d: %s, de longitud %d


tool: D2: '%c' 

tool: D16: 	Con valores: 

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0, len = 0, j = 0;
  printf("Tus argumentos son: \n");
  for (i = 0; i < argc; i++) {
    len = strlen(*(argv + i));
    printf("Argumento %d: %s, de longitud %d\n", i, *(argv + i), len);
    printf("\tCon valores: ");
    for (j = 0; j < len; j++) {
      printf("'%c' ", *(*(argv + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_uninitialized>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L22
L6:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  add    %eax,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L22:
  cmpl   $0x3,-0x24(%rbp)
  jle    L6
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int test_uninitialized() {
  int sum;
  int values[] = {1, 2, 3, 4};
  int i;
  for (i = 0; i < 4; ++i) {
    sum += values[i];
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_uninitialized>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int test_uninitialized() {
  int sum;
  int values[] = {1, 2, 3, 4};
  int i;
  for (i = 0; i < 4; ++i) {
    sum += values[i];
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_uninitialized>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int test_uninitialized() {
  int sum;
  int values[] = {1, 2, 3, 4};
  int i;
  for (i = 0; i < 4; ++i) {
    sum += values[i];
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_uninitialized>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int test_uninitialized() {
  int sum;
  int values[] = {1, 2, 3, 4};
  int i;
  for (i = 0; i < 4; ++i) {
    sum += values[i];
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D38
type_infered: string

tool: D8: 12

tool: D28: %s


tool: D38: f(1,2)

assistant: ```c
int main() {
  printf("%s\n", "12");
  printf("%s\n", "f(1,2)");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string
name: unpack_data
arguments: data_label: D21
data_type: string

tool: D13: 12

tool: D3: %s


tool: D21: f(1,2)

assistant: ```c
int main() {
  printf("%s\n", "12");
  printf("%s\n", "f(1,2)");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rbp
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D22
datatype: string
name: read_data
arguments: label: D27
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D22: %s


tool: D27: 12

tool: D5: f(1,2)

assistant: ```c
int main() {
  printf("%s\n", "12");
  printf("%s\n", "f(1,2)");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rbp
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D7(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D22
type: string
name: disassemble_data
arguments: data_tag: D7
type: string

tool: D24: %s


tool: D22: 12

tool: D7: f(1,2)

assistant: ```c
int main() {
  printf("%s\n", "12");
  printf("%s\n", "f(1,2)");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L8
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L11:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  mov    %al,(%rdx)
  subl   $0x1,-0x10(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    -0x4(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jg     L11
  jmp    L14
L8:
  nop
L14:
  leave
  ret
```

assistant: ```c
void strrev(char *sz) {
  int i, j, k, t;
  char c;
  if (!sz)
    return;
  i = strlen(sz);
  t = !(i % 2) ? 1 : 0;
  for (j = i - 1, k = 0; j > (i / 2 - t); j--) {
    c = sz[j];
    sz[j] = sz[k];
    sz[k++] = c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strrev>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %eax,%edx
  xor    $0x1,%edx
  and    $0x1,%edx
  sub    %edx,%esi
  cmp    %esi,%ecx
  jle    L18
  movslq %ecx,%rcx
  add    %rbx,%rcx
  mov    %rbx,%rdx
  sub    $0x2,%eax
  sub    %esi,%eax
  lea    0x1(%rbx,%rax,1),%rdi
L16:
  movzbl (%rcx),%eax
  movzbl (%rdx),%esi
  mov    %sil,(%rcx)
  mov    %al,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L16
L18:
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void strrev(char *sz) {
  int i, j, k, t;
  char c;
  if (!sz)
    return;
  i = strlen(sz);
  t = !(i % 2) ? 1 : 0;
  for (j = i - 1, k = 0; j > (i / 2 - t); j--) {
    c = sz[j];
    sz[j] = sz[k];
    sz[k++] = c;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrev>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %eax,%esi
  lea    -0x1(%rax),%edx
  shr    $0x1f,%ecx
  not    %esi
  add    %eax,%ecx
  and    $0x1,%esi
  sar    %ecx
  sub    %esi,%ecx
  cmp    %ecx,%edx
  jle    L0
  sub    $0x2,%eax
  movslq %edx,%rdx
  mov    %rbx,%rdi
  sub    %ecx,%eax
  add    %rbx,%rdx
  lea    0x1(%rbx,%rax,1),%rsi
  xchg   %ax,%ax
L8:
  movzbl (%rdx),%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rdx
  mov    %cl,0x1(%rdx)
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L8
L0:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void strrev(char *sz) {
  int i, j, k, t;
  char c;
  if (!sz)
    return;
  i = strlen(sz);
  t = !(i % 2) ? 1 : 0;
  for (j = i - 1, k = 0; j > (i / 2 - t); j--) {
    c = sz[j];
    sz[j] = sz[k];
    sz[k++] = c;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strrev>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %eax,%esi
  lea    -0x1(%rax),%edx
  shr    $0x1f,%ecx
  not    %esi
  add    %eax,%ecx
  and    $0x1,%esi
  sar    %ecx
  sub    %esi,%ecx
  cmp    %ecx,%edx
  jle    L29
  sub    $0x2,%eax
  movslq %edx,%rdx
  mov    %rbx,%rdi
  sub    %ecx,%eax
  add    %rbx,%rdx
  lea    0x1(%rbx,%rax,1),%rsi
  xchg   %ax,%ax
L12:
  movzbl (%rdx),%eax
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  sub    $0x1,%rdx
  mov    %cl,0x1(%rdx)
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdi
  jne    L12
L29:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void strrev(char *sz) {
  int i, j, k, t;
  char c;
  if (!sz)
    return;
  i = strlen(sz);
  t = !(i % 2) ? 1 : 0;
  for (j = i - 1, k = 0; j > (i / 2 - t); j--) {
    c = sz[j];
    sz[j] = sz[k];
    sz[k++] = c;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mix_in_with_volume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %ax,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L36:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L43:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%ecx
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  movswl -0x14(%rbp),%eax
  imul   %edx,%eax
  add    %eax,%eax
  sar    $0x10,%eax
  add    %ecx,%eax
  cmp    $0x7fff,%eax
  jg     L66
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%ecx
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  movswl -0x14(%rbp),%eax
  imul   %edx,%eax
  add    %eax,%eax
  sar    $0x10,%eax
  add    %ecx,%eax
  cmp    $0xffff8000,%eax
  jl     L30
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  movswl -0x14(%rbp),%eax
  imul   %edx,%eax
  add    %eax,%eax
  sar    $0x10,%eax
  add    %ecx,%eax
  jmp    L19
L30:
  mov    $0xffff8000,%eax
  jmp    L19
L66:
  mov    $0x7fff,%eax
L19:
  mov    -0x4(%rbp),%edx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %ax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  add    $0x4,%eax
  cmp    %eax,-0x4(%rbp)
  jb     L43
  addl   $0x4,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jb     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mix_in_with_volume(const short volume, const short *src, short *dst, const unsigned n) {
  unsigned i, j;
  for (i = 0; i < n; i += 4)
    for (j = i; j < i + 4; ++j) {
      dst[j] = (short)((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) > (0x7FFF)) ? (0x7FFF) : ((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) < (-0x8000)) ? (-0x8000) : ((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16))));
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mix_in_with_volume>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r11
  mov    %rdx,%r10
  mov    %ecx,%r12d
  mov    $0x0,%r8d
  movswl %di,%r9d
  mov    $0x7fff,%ebx
  mov    $0xffff8000,%ebp
  test   %ecx,%ecx
  jne    L57
L65:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  mov    %r14w,(%rsi)
  add    $0x1,%edx
  cmp    %edi,%edx
  je     L25
L12:
  mov    %edx,%eax
  lea    (%r10,%rax,2),%rsi
  movzwl (%rsi),%ecx
  movswl (%r11,%rax,2),%eax
  imul   %r9d,%eax
  add    %eax,%eax
  sar    $0x10,%eax
  movswl %cx,%r13d
  add    %eax,%r13d
  mov    %ebx,%r14d
  cmp    $0x7fff,%r13d
  jg     L66
  add    %eax,%ecx
  cmp    $0xffff7fff,%r13d
  cmovle %ebp,%ecx
  mov    %ecx,%r14d
  jmp    L66
L25:
  cmp    %r8d,%r12d
  jbe    L65
L57:
  mov    %r8d,%edx
  add    $0x4,%r8d
  cmp    %edx,%r8d
  jbe    L25
  lea    0x1(%rdx),%eax
  cmp    %eax,%r8d
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
  lea    0x4(%rdx,%rax,1),%edi
  jmp    L12
```

assistant: ```c
void mix_in_with_volume(const short volume, const short *src, short *dst, const unsigned n) {
  unsigned i, j;
  for (i = 0; i < n; i += 4)
    for (j = i; j < i + 4; ++j) {
      dst[j] = (short)((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) > (0x7FFF)) ? (0x7FFF) : ((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) < (-0x8000)) ? (-0x8000) : ((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16))));
    }
}
```
user: Translate the below assembly code into C programming language:

```asm
<mix_in_with_volume>:
  endbr64
  test   %ecx,%ecx
  je     L6
  push   %r13
  mov    %rdx,%r11
  xor    %r8d,%r8d
  movswl %di,%r10d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    $0xffff8000,%ebp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L38:
  mov    %r8d,%edx
  add    $0x4,%r8d
  cmp    %edx,%r8d
  jbe    L7
  cmp    $0x3,%r8d
  sbb    %eax,%eax
  and    $0xfffffffd,%eax
  lea    0x4(%rdx,%rax,1),%r9d
L24:
  mov    %edx,%eax
  mov    $0x7fff,%r13d
  lea    (%r11,%rax,2),%rdi
  movswl (%rbx,%rax,2),%eax
  movswl (%rdi),%ecx
  imul   %r10d,%eax
  mov    %ecx,%esi
  add    %eax,%eax
  sar    $0x10,%eax
  add    %eax,%ecx
  cmp    $0x7fff,%ecx
  jg     L49
  add    %eax,%esi
  cmp    $0xffff7fff,%ecx
  cmovle %ebp,%esi
  mov    %esi,%r13d
L49:
  add    $0x1,%edx
  mov    %r13w,(%rdi)
  cmp    %r9d,%edx
  jne    L24
L7:
  cmp    %r8d,%r12d
  ja     L38
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  ret
```

assistant: ```c
void mix_in_with_volume(const short volume, const short *src, short *dst, const unsigned n) {
  unsigned i, j;
  for (i = 0; i < n; i += 4)
    for (j = i; j < i + 4; ++j) {
      dst[j] = (short)((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) > (0x7FFF)) ? (0x7FFF) : ((((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16)) < (-0x8000)) ? (-0x8000) : ((int)dst[j] + ((2 * (int)src[j] * (int)volume) >> 16))));
    }
}
```