ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<incrementerInputOutput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L9
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L9:
  cmpl   $0x0,-0x28(%rbp)
  jne    L51
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x63,%eax
  jg     L20
  mov    $0xb,%edi
  call   <mallocBis@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L37
L20:
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <erreur@plt>
  jmp    L37
L51:
  mov    $0x1,%esi
  mov    $0x17,%edi
  call   <erreur@plt>
L37:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: output_%d

assistant: ```c
char *incrementerInputOutput(char **tab, int *id, int max, int bool_input) {
  char *str_result;
  if (*id < max)
    str_result = tab[*id];
  else if (!bool_input) {
    if (*id < 100) {
      str_result = mallocBis(sizeof(char) * 11);
      sprintf(str_result, "output_%d", *id);
    } else
      erreur(33, 1);
  } else
    erreur(23, 1);
  *id = *id + 1;
  return str_result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<incrementerInputOutput>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    (%rsi),%eax
  cmp    %edx,%eax
  jge    L20
  cltq
  mov    (%rdi,%rax,8),%rbp
L7:
  addl   $0x1,(%rbx)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  test   %ecx,%ecx
  jne    L32
  cmp    $0x63,%eax
  jg     L54
  mov    $0xb,%edi
  call   <mallocBis@plt>
  mov    %rax,%rbp
  mov    (%rbx),%edx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L7
L54:
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <erreur@plt>
  jmp    L7
L32:
  mov    $0x1,%esi
  mov    $0x17,%edi
  call   <erreur@plt>
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: output_%d

assistant: ```c
char *incrementerInputOutput(char **tab, int *id, int max, int bool_input) {
  char *str_result;
  if (*id < max)
    str_result = tab[*id];
  else if (!bool_input) {
    if (*id < 100) {
      str_result = mallocBis(sizeof(char) * 11);
      sprintf(str_result, "output_%d", *id);
    } else
      erreur(33, 1);
  } else
    erreur(23, 1);
  *id = *id + 1;
  return str_result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<incrementerInputOutput>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  cmp    %edx,%eax
  jge    L26
  movslq %eax,%rdx
  add    $0x1,%eax
  mov    (%rdi,%rdx,8),%r12
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  test   %ecx,%ecx
  jne    L23
  cmp    $0x63,%eax
  jg     L0
  mov    $0xb,%edi
  call   <mallocBis@plt>
  mov    (%rbx),%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <erreur@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  mov    $0x1,%esi
  mov    $0x17,%edi
  call   <erreur@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string

tool: D6: output_%d

assistant: ```c
char *incrementerInputOutput(char **tab, int *id, int max, int bool_input) {
  char *str_result;
  if (*id < max)
    str_result = tab[*id];
  else if (!bool_input) {
    if (*id < 100) {
      str_result = mallocBis(sizeof(char) * 11);
      sprintf(str_result, "output_%d", *id);
    } else
      erreur(33, 1);
  } else
    erreur(23, 1);
  *id = *id + 1;
  return str_result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<incrementerInputOutput>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%eax
  cmp    %edx,%eax
  jge    L5
  movslq %eax,%rdx
  add    $0x1,%eax
  mov    (%rdi,%rdx,8),%r12
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  test   %ecx,%ecx
  jne    L1
  cmp    $0x63,%eax
  jg     L8
  mov    $0xb,%edi
  call   <mallocBis@plt>
  mov    (%rbx),%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <sprintf@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <erreur@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%esi
  mov    $0x17,%edi
  call   <erreur@plt>
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: output_%d

assistant: ```c
char *incrementerInputOutput(char **tab, int *id, int max, int bool_input) {
  char *str_result;
  if (*id < max)
    str_result = tab[*id];
  else if (!bool_input) {
    if (*id < 100) {
      str_result = mallocBis(sizeof(char) * 11);
      sprintf(str_result, "output_%d", *id);
    } else
      erreur(33, 1);
  } else
    erreur(23, 1);
  *id = *id + 1;
  return str_result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_unpack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%rax
  movabs $0x4645444342413938,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L14
L24:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  sar    $0x4,%al
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,-0x28(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x2c(%rbp)
L14:
  mov    -0x2c(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L24
  mov    -0x44(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
void _unpack(char *dest, char *src, int len) {
  char chars[] = "0123456789ABCDEF";
  int i = 0;
  for (i = 0; i < len; i++) {
    int hi = (src[i] >> 4) & 0x0F;
    int lo = src[i] & 0x0F;
    dest[(i * 2)] = chars[hi];
    dest[(i * 2) + 1] = chars[lo];
  }
  dest[(len * 2)] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_unpack>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x3736353433323130,%r10
  movabs $0x4645444342413938,%r11
  mov    %r10,(%rsp)
  mov    %r11,0x8(%rsp)
  movb   $0x0,0x10(%rsp)
  test   %edx,%edx
  jle    L16
  mov    %edx,%r9d
L13:
  movzbl (%rsi,%rax,1),%ecx
  mov    %ecx,%edi
  shr    $0x4,%dil
  movsbq %dil,%rdi
  movzbl (%rsp,%rdi,1),%edi
  mov    %dil,(%r8,%rax,2)
  and    $0xf,%ecx
  movzbl (%rsp,%rcx,1),%ecx
  mov    %cl,0x1(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %r9,%rax
  jne    L13
L16:
  add    %edx,%edx
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void _unpack(char *dest, char *src, int len) {
  char chars[] = "0123456789ABCDEF";
  int i = 0;
  for (i = 0; i < len; i++) {
    int hi = (src[i] >> 4) & 0x0F;
    int lo = src[i] & 0x0F;
    dest[(i * 2)] = chars[hi];
    dest[(i * 2) + 1] = chars[lo];
  }
  dest[(len * 2)] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_unpack>:
  endbr64
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L16
  movslq %edx,%r9
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rsi,%rax,1),%ecx
  mov    %ecx,%edi
  and    $0xf,%ecx
  shr    $0x4,%dil
  movzbl (%rsp,%rcx,1),%ecx
  and    $0xf,%edi
  movzbl (%rsp,%rdi,1),%edi
  mov    %cl,0x1(%r8,%rax,2)
  mov    %dil,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L18
L16:
  add    %edx,%edx
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: byte[16]

tool: {"D7": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void _unpack(char *dest, char *src, int len) {
  char chars[] = "0123456789ABCDEF";
  int i = 0;
  for (i = 0; i < len; i++) {
    int hi = (src[i] >> 4) & 0x0F;
    int lo = src[i] & 0x0F;
    dest[(i * 2)] = chars[hi];
    dest[(i * 2) + 1] = chars[lo];
  }
  dest[(len * 2)] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_unpack>:
  endbr64
  sub    $0x28,%rsp
  movdqa D7(%rip),%xmm0
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x10(%rsp)
  movaps %xmm0,(%rsp)
  test   %edx,%edx
  jle    L11
  movslq %edx,%r9
  nopl   0x0(%rax,%rax,1)
L2:
  movzbl (%rsi,%rax,1),%ecx
  mov    %ecx,%edi
  and    $0xf,%ecx
  shr    $0x4,%dil
  movzbl (%rsp,%rcx,1),%ecx
  and    $0xf,%edi
  movzbl (%rsp,%rdi,1),%edi
  mov    %cl,0x1(%r8,%rax,2)
  mov    %dil,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L2
L11:
  add    %edx,%edx
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: byte[16]

tool: {"D7": [0x30,0x31,0x32,0x33,0x34,0x35,0x36,0x37,0x38,0x39,0x41,0x42,0x43,0x44,0x45,0x46]}

assistant: ```c
void _unpack(char *dest, char *src, int len) {
  char chars[] = "0123456789ABCDEF";
  int i = 0;
  for (i = 0; i < len; i++) {
    int hi = (src[i] >> 4) & 0x0F;
    int lo = src[i] & 0x0F;
    dest[(i * 2)] = chars[hi];
    dest[(i * 2) + 1] = chars[lo];
  }
  dest[(len * 2)] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<WebRtc_rdft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,0xc(%rsp)
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    (%rcx),%r14
  lea    0x0(,%r14,4),%rax
  cmp    %rdi,%rax
  jb     L74
L128:
  mov    0x8(%r12),%r15
  lea    0x0(,%r15,4),%rax
  cmp    %rbx,%rax
  jb     L10
L58:
  cmpl   $0x0,0xc(%rsp)
  js     L101
  cmp    $0x4,%rbx
  ja     L11
  je     L43
L105:
  movss  0x0(%rbp),%xmm0
  movss  0x4(%rbp),%xmm1
  movaps %xmm0,%xmm2
  addss  %xmm1,%xmm2
  movss  %xmm2,0x0(%rbp)
  subss  %xmm1,%xmm0
  movss  %xmm0,0x4(%rbp)
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  mov    %rdi,%r14
  shr    $0x2,%r14
  mov    %r8,%rdx
  mov    %rcx,%rsi
  mov    %r14,%rdi
  call   <makewt@plt>
  jmp    L128
L10:
  mov    %rbx,%r15
  shr    $0x2,%r15
  lea    0x0(%r13,%r14,4),%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <makect@plt>
  jmp    L58
L11:
  lea    0x10(%r12),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <bitrv2@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <cftfsub@plt>
  lea    0x0(%r13,%r14,4),%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <rftfsub@plt>
  jmp    L105
L43:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    $0x4,%edi
  call   <cftfsub@plt>
  jmp    L105
L101:
  movss  0x0(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  0x4(%rbp),%xmm1
  mulss  D7(%rip),%xmm1
  movss  %xmm1,0x4(%rbp)
  subss  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp)
  cmp    $0x4,%rbx
  ja     L118
  jne    L24
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    $0x4,%edi
  call   <cftfsub@plt>
  jmp    L24
L118:
  lea    0x0(%r13,%r14,4),%rcx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <rftbsub@plt>
  lea    0x10(%r12),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <bitrv2@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <cftbsub@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void WebRtc_rdft(size_t n, int isgn, float *a, size_t *ip, float *w) {
  size_t nw, nc;
  float xi;
  nw = ip[0];
  if (n > (nw << 2)) {
    nw = n >> 2;
    makewt(nw, ip, w);
  }
  nc = ip[1];
  if (n > (nc << 2)) {
    nc = n >> 2;
    makect(nc, ip, w + nw);
  }
  if (isgn >= 0) {
    if (n > 4) {
      bitrv2(n, ip + 2, a);
      cftfsub(n, a, w);
      rftfsub(n, a, nc, w + nw);
    } else if (n == 4) {
      cftfsub(n, a, w);
    }
    xi = a[0] - a[1];
    a[0] += a[1];
    a[1] = xi;
  } else {
    a[1] = 0.5f * (a[0] - a[1]);
    a[0] -= a[1];
    if (n > 4) {
      rftbsub(n, a, nc, w + nw);
      bitrv2(n, ip + 2, a);
      cftbsub(n, a, w);
    } else if (n == 4) {
      cftfsub(n, a, w);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <test_dcbzl@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status;
  status = test_dcbzl();
  return status;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_dcbzl@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int status;
  status = test_dcbzl();
  return status;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <test_dcbzl@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int status;
  status = test_dcbzl();
  return status;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <test_dcbzl@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int status;
  status = test_dcbzl();
  return status;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *s, int *q) {
  int tmp;
  tmp = *s;
  *s = *q;
  *q = tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *s, int *q) {
  int tmp;
  tmp = *s;
  *s = *q;
  *q = tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *s, int *q) {
  int tmp;
  tmp = *s;
  *s = *q;
  *q = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  mov    (%rdi),%eax
  mov    (%rsi),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void swap(int *s, int *q) {
  int tmp;
  tmp = *s;
  *s = *q;
  *q = tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x30(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  mov    $0x15,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0xb,-0x2c(%rbp)
  jg     L25
  movb   $0x61,-0x31(%rbp)
  jmp    L23
L25:
  subl   $0xc,-0x2c(%rbp)
  movb   $0x70,-0x31(%rbp)
L23:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L27
  movl   $0xc,-0x2c(%rbp)
L27:
  movsbl -0x31(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    0x10(%rax),%r8d
  mov    -0x28(%rbp),%rax
  mov    0xc(%rax),%eax
  lea    0x76c(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    -0x28(%rbp),%rsi
  mov    0x4(%rsi),%esi
  add    $0x1,%esi
  mov    -0x2c(%rbp),%edi
  sub    $0x8,%rsp
  push   %rcx
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string

tool: D4: %m-%d-%Y  %I:%M%p


tool: D18: %.2d-%.2d-%d  %2d:%.2d%c


assistant: ```c
int main(void) {
  time_t current = time(NULL);
  struct tm *ptr;
  char date_time[21];
  int hour;
  char am_or_pm;
  puts(ctime(&current));
  strftime(date_time, sizeof(date_time), "%m-%d-%Y  %I:%M%p\n", localtime(&current));
  puts(date_time);
  ptr = localtime(&current);
  hour = ptr->tm_hour;
  if (hour <= 11)
    am_or_pm = 'a';
  else {
    hour -= 12;
    am_or_pm = 'p';
  }
  if (hour == 0)
    hour = 12;
  printf("%.2d-%.2d-%d  %2d:%.2d%c\n", ptr->tm_mon + 1, ptr->tm_mday, ptr->tm_year + 1900, hour, ptr->tm_min, am_or_pm);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  lea    0x10(%rsp),%rbp
  lea    D19(%rip),%rdx
  mov    $0x15,%esi
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    (%rax),%r8d
  mov    $0x61,%edx
  cmp    $0xb,%r8d
  jle    L19
  sub    $0xc,%r8d
  mov    $0x70,%edx
L19:
  test   %r8d,%r8d
  mov    $0xc,%ecx
  cmove  %ecx,%r8d
  mov    0x10(%rax),%r9d
  mov    0xc(%rax),%ebx
  lea    0x76c(%rbx),%ecx
  mov    0x8(%rax),%edi
  mov    0x4(%rax),%esi
  add    $0x1,%esi
  sub    $0x8,%rsp
  movsbl %dl,%edx
  push   %rdx
  mov    %edi,%edx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D19: %m-%d-%Y  %I:%M%p


tool: D4: %.2d-%.2d-%d  %2d:%.2d%c


assistant: ```c
int main(void) {
  time_t current = time(NULL);
  struct tm *ptr;
  char date_time[21];
  int hour;
  char am_or_pm;
  puts(ctime(&current));
  strftime(date_time, sizeof(date_time), "%m-%d-%Y  %I:%M%p\n", localtime(&current));
  puts(date_time);
  ptr = localtime(&current);
  hour = ptr->tm_hour;
  if (hour <= 11)
    am_or_pm = 'a';
  else {
    hour -= 12;
    am_or_pm = 'p';
  }
  if (hour == 0)
    hour = 12;
  printf("%.2d-%.2d-%d  %2d:%.2d%c\n", ptr->tm_mon + 1, ptr->tm_mday, ptr->tm_year + 1900, hour, ptr->tm_min, am_or_pm);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <time@plt>
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D10(%rip),%rdx
  mov    $0x15,%esi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  mov    $0x61,%edx
  mov    (%rax),%r8d
  cmp    $0xb,%r8d
  jle    L4
  sub    $0xc,%r8d
  mov    $0x70,%edx
L4:
  mov    0xc(%rax),%esi
  test   %r8d,%r8d
  mov    $0xc,%ecx
  mov    0x8(%rax),%r10d
  cmove  %ecx,%r8d
  sub    $0x8,%rsp
  mov    0x10(%rax),%r9d
  lea    D17(%rip),%rdi
  lea    0x76c(%rsi),%ecx
  mov    0x4(%rax),%esi
  push   %rdx
  mov    %r10d,%edx
  add    $0x1,%esi
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string

tool: D10: %m-%d-%Y  %I:%M%p


tool: D17: %.2d-%.2d-%d  %2d:%.2d%c


assistant: ```c
int main(void) {
  time_t current = time(NULL);
  struct tm *ptr;
  char date_time[21];
  int hour;
  char am_or_pm;
  puts(ctime(&current));
  strftime(date_time, sizeof(date_time), "%m-%d-%Y  %I:%M%p\n", localtime(&current));
  puts(date_time);
  ptr = localtime(&current);
  hour = ptr->tm_hour;
  if (hour <= 11)
    am_or_pm = 'a';
  else {
    hour -= 12;
    am_or_pm = 'p';
  }
  if (hour == 0)
    hour = 12;
  printf("%.2d-%.2d-%d  %2d:%.2d%c\n", ptr->tm_mon + 1, ptr->tm_mday, ptr->tm_year + 1900, hour, ptr->tm_min, am_or_pm);
  return 0;
}
```