ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<sub>:
  endbr64
  mov    %rdi,%r9
  test   %ecx,%ecx
  je     L2
  lea    -0x1(%rcx),%ecx
  mov    $0x0,%edi
L16:
  movzbl (%rsi,%rcx,1),%eax
  movzbl (%rdx,%rcx,1),%r8d
  sub    %r8d,%eax
  sub    %edi,%eax
  mov    %al,(%r9,%rcx,1)
  shr    $0x1f,%eax
  mov    %eax,%edi
  sub    $0x1,%rcx
  cmp    $0xffffffffffffffff,%rcx
  jne    L16
L2:
  ret
```

assistant: ```c
void sub(unsigned char d[], unsigned char a[], unsigned char b[], unsigned n) {
  int tmp, borrow = 0;
  for (; n; n--) {
    d[n - 1] = tmp = a[n - 1] - b[n - 1] - borrow;
    borrow = (tmp < 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sub>:
  endbr64
  mov    %rdi,%r9
  test   %ecx,%ecx
  je     L14
  sub    $0x1,%ecx
  xor    %edi,%edi
L10:
  movzbl (%rsi,%rcx,1),%eax
  movzbl (%rdx,%rcx,1),%r8d
  sub    %r8d,%eax
  sub    %edi,%eax
  mov    %al,(%r9,%rcx,1)
  shr    $0x1f,%eax
  mov    %eax,%edi
  sub    $0x1,%rcx
  jae    L10
L14:
  ret
```

assistant: ```c
void sub(unsigned char d[], unsigned char a[], unsigned char b[], unsigned n) {
  int tmp, borrow = 0;
  for (; n; n--) {
    d[n - 1] = tmp = a[n - 1] - b[n - 1] - borrow;
    borrow = (tmp < 0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sub>:
  endbr64
  mov    %rdi,%r9
  test   %ecx,%ecx
  je     L7
  sub    $0x1,%ecx
  xor    %edi,%edi
L2:
  movzbl (%rsi,%rcx,1),%eax
  movzbl (%rdx,%rcx,1),%r8d
  sub    %r8d,%eax
  sub    %edi,%eax
  mov    %al,(%r9,%rcx,1)
  shr    $0x1f,%eax
  mov    %eax,%edi
  sub    $0x1,%rcx
  jae    L2
L7:
  ret
```

assistant: ```c
void sub(unsigned char d[], unsigned char a[], unsigned char b[], unsigned n) {
  int tmp, borrow = 0;
  for (; n; n--) {
    d[n - 1] = tmp = a[n - 1] - b[n - 1] - borrow;
    borrow = (tmp < 0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<appdstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L17
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <errx@plt>
L17:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
L16:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L11
  subq   $0x1,-0x18(%rbp)
L11:
  nop
L44:
  mov    -0x30(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L2
  cmpl   $0xa,-0x1c(%rbp)
  jne    L44
L2:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: malloc

assistant: ```c
char *appdstr(char *s, const char *tp, size_t len) {
  char *mp;
  const char *sp;
  int ch;
  char *m;
  if ((m = malloc(strlen(s) + len + 1)) == NULL)
    errx(1, "malloc");
  for (mp = m, sp = s; (*mp++ = *sp++) != '\0';)
    ;
  --mp;
  if (*(mp - 1) == '\\')
    --mp;
  while ((ch = *mp++ = *tp++) && ch != '\n')
    ;
  *mp = '\0';
  free(s);
  return (m);
}
```
user: What is the c source code of the assembly code below:

```asm
<appdstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L43
L12:
  mov    %r12,%rcx
  mov    %rbp,%rdx
L36:
  add    $0x1,%rcx
  mov    %rdx,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rcx),%esi
  mov    %sil,-0x1(%rdx)
  test   %sil,%sil
  jne    L36
  cmpb   $0x5c,-0x1(%rax)
  sete   %dl
  movzbl %dl,%edx
  sub    %rdx,%rax
L1:
  add    $0x1,%rbx
  add    $0x1,%rax
  movzbl -0x1(%rbx),%edx
  mov    %dl,-0x1(%rax)
  movsbl %dl,%ecx
  cmp    $0xa,%dl
  je     L48
  test   %ecx,%ecx
  jne    L1
L48:
  movb   $0x0,(%rax)
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: string

tool: D6: malloc

assistant: ```c
char *appdstr(char *s, const char *tp, size_t len) {
  char *mp;
  const char *sp;
  int ch;
  char *m;
  if ((m = malloc(strlen(s) + len + 1)) == NULL)
    errx(1, "malloc");
  for (mp = m, sp = s; (*mp++ = *sp++) != '\0';)
    ;
  --mp;
  if (*(mp - 1) == '\\')
    --mp;
  while ((ch = *mp++ = *tp++) && ch != '\n')
    ;
  *mp = '\0';
  free(s);
  return (m);
}
```
user: Translate the below assembly code into C programming language:

```asm
<appdstr>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L25
L20:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xchg   %ax,%ax
L39:
  movzbl (%rcx),%esi
  mov    %rdx,%rax
  add    $0x1,%rcx
  lea    0x1(%rdx),%rdx
  mov    %sil,-0x1(%rdx)
  test   %sil,%sil
  jne    L39
  xor    %edx,%edx
  cmpb   $0x5c,-0x1(%rax)
  sete   %dl
  sub    %rdx,%rax
  jmp    L28
  nopl   (%rax)
L17:
  test   %ecx,%ecx
  je     L3
L28:
  movsbl (%rbx),%ecx
  add    $0x1,%rbx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    $0xa,%cl
  jne    L17
L3:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L20
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: malloc

assistant: ```c
char *appdstr(char *s, const char *tp, size_t len) {
  char *mp;
  const char *sp;
  int ch;
  char *m;
  if ((m = malloc(strlen(s) + len + 1)) == NULL)
    errx(1, "malloc");
  for (mp = m, sp = s; (*mp++ = *sp++) != '\0';)
    ;
  --mp;
  if (*(mp - 1) == '\\')
    --mp;
  while ((ch = *mp++ = *tp++) && ch != '\n')
    ;
  *mp = '\0';
  free(s);
  return (m);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<appdstr>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L55
L35:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  xchg   %ax,%ax
L18:
  movzbl (%rcx),%esi
  mov    %rdx,%rax
  add    $0x1,%rcx
  lea    0x1(%rdx),%rdx
  mov    %sil,-0x1(%rdx)
  test   %sil,%sil
  jne    L18
  xor    %edx,%edx
  cmpb   $0x5c,-0x1(%rax)
  sete   %dl
  sub    %rdx,%rax
  jmp    L57
  nopl   (%rax)
L22:
  test   %ecx,%ecx
  je     L39
L57:
  movsbl (%rbx),%ecx
  add    $0x1,%rbx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    $0xa,%cl
  jne    L22
L39:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L55:
  lea    D8(%rip),%rsi
  mov    $0x1,%edi
  call   <errx@plt>
  jmp    L35
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string

tool: D8: malloc

assistant: ```c
char *appdstr(char *s, const char *tp, size_t len) {
  char *mp;
  const char *sp;
  int ch;
  char *m;
  if ((m = malloc(strlen(s) + len + 1)) == NULL)
    errx(1, "malloc");
  for (mp = m, sp = s; (*mp++ = *sp++) != '\0';)
    ;
  --mp;
  if (*(mp - 1) == '\\')
    --mp;
  while ((ch = *mp++ = *tp++) && ch != '\n')
    ;
  *mp = '\0';
  free(s);
  return (m);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mksock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    -0x14(%rbp),%ecx
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L3
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L27
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D43(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L27
  mov    D36(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L27
  mov    D48(%rip),%rax
  mov    (%rax),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D25(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L3
L27:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  movl   $0xffffffff,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mksock(int type) {
  int flags;
  int fd = socket(AF_UNIX, type, 0);
  if (fd != -1) {
    if ((flags = fcntl(fd, F_GETFL)) == -1 || fcntl(fd, F_SETFL, flags | O_NONBLOCK) == -1 || (flags = fcntl(fd, F_GETFD)) == -1 || fcntl(fd, F_SETFD, flags | FD_CLOEXEC) == -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mksock>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x0,%edx
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L36
L5:
  mov    %ebx,%eax
  pop    %rbx
  ret
L36:
  mov    D68(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    D2(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    D30(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D45(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L5
L9:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L5
```

assistant: ```c
int mksock(int type) {
  int flags;
  int fd = socket(AF_UNIX, type, 0);
  if (fd != -1) {
    if ((flags = fcntl(fd, F_GETFL)) == -1 || fcntl(fd, F_SETFL, flags | O_NONBLOCK) == -1 || (flags = fcntl(fd, F_GETFD)) == -1 || fcntl(fd, F_SETFD, flags | FD_CLOEXEC) == -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mksock>:
  endbr64
  mov    D46(%rip),%rax
  push   %r12
  mov    %edi,%esi
  xor    %edx,%edx
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L59
  mov    D59(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    D5(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D21(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    D15(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    D32(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L1
L59:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L59
```

assistant: ```c
int mksock(int type) {
  int flags;
  int fd = socket(AF_UNIX, type, 0);
  if (fd != -1) {
    if ((flags = fcntl(fd, F_GETFL)) == -1 || fcntl(fd, F_SETFL, flags | O_NONBLOCK) == -1 || (flags = fcntl(fd, F_GETFD)) == -1 || fcntl(fd, F_SETFD, flags | FD_CLOEXEC) == -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mksock>:
  endbr64
  mov    D45(%rip),%rax
  push   %r12
  mov    %edi,%esi
  xor    %edx,%edx
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L1
  mov    D9(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L59
  mov    D0(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D52(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L59
  mov    D66(%rip),%rax
  mov    %r12d,%edi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L59
  mov    D28(%rip),%rdx
  mov    %r12d,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L59
L1:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L59:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L1
```

assistant: ```c
int mksock(int type) {
  int flags;
  int fd = socket(AF_UNIX, type, 0);
  if (fd != -1) {
    if ((flags = fcntl(fd, F_GETFL)) == -1 || fcntl(fd, F_SETFL, flags | O_NONBLOCK) == -1 || (flags = fcntl(fd, F_GETFD)) == -1 || fcntl(fd, F_SETFD, flags | FD_CLOEXEC) == -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<aEQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L159
  cmpq   $0x0,-0x30(%rbp)
  jne    L28
L159:
  mov    $0xffffffff,%eax
  jmp    L92
L28:
  movq   $0x0,-0x10(%rbp)
  jmp    L53
L47:
  addq   $0x1,-0x10(%rbp)
L53:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  movq   $0x0,-0x8(%rbp)
  jmp    L206
L170:
  addq   $0x1,-0x8(%rbp)
L206:
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L170
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L198
  mov    $0xfffffffe,%eax
  jmp    L92
L198:
  movq   $0x0,-0x10(%rbp)
  jmp    L0
L54:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x5a,-0x12(%rbp)
  jg     L48
  cmpb   $0x40,-0x12(%rbp)
  jle    L48
  orb    $0x20,-0x12(%rbp)
L48:
  cmpb   $0x5a,-0x11(%rbp)
  jg     L7
  cmpb   $0x40,-0x11(%rbp)
  jle    L7
  orb    $0x20,-0x11(%rbp)
L7:
  movzbl -0x12(%rbp),%eax
  cmp    -0x11(%rbp),%al
  jne    L84
  addq   $0x1,-0x10(%rbp)
L0:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L107
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L54
  jmp    L107
L84:
  nop
L107:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L132
  cmpq   $0x0,-0x10(%rbp)
  jne    L217
  mov    $0xfffffffd,%eax
  jmp    L92
L217:
  mov    -0x10(%rbp),%rax
  jmp    L92
L132:
  mov    $0x0,%eax
L92:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long aEQ(char *text, char *text2) {
  unsigned long x, y;
  char tmp, tmp2;
  if (text == NULL || text2 == NULL)
    return 0xFFFFFFFF;
  for (x ^= x; text[x] != 0; x++)
    ;
  for (y ^= y; text2[y] != 0; y++)
    ;
  if (x != y)
    return 0xFFFFFFFE;
  for (x ^= x; text[x] != 0 && text2[x] != 0; x++) {
    tmp = text[x];
    tmp2 = text2[x];
    if (tmp <= 'Z' && tmp >= 'A')
      tmp |= 0x20;
    if (tmp2 <= 'Z' && tmp2 >= 'A')
      tmp2 |= 0x20;
    if (tmp != tmp2)
      break;
  }
  if (x != y) {
    if (x == 0)
      return 0xFFFFFFFD;
    return x;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aEQ>:
  endbr64
  test   %rdi,%rdi
  je     L55
  test   %rsi,%rsi
  je     L55
  movzbl (%rdi),%eax
  test   %al,%al
  je     L91
  mov    $0x0,%edx
L118:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L118
  cmpb   $0x0,(%rsi)
  je     L30
L152:
  mov    $0x0,%r8d
L115:
  add    $0x1,%r8
  cmpb   $0x0,(%rsi,%r8,1)
  jne    L115
  mov    $0xfffffffe,%ecx
  cmp    %rdx,%r8
  jne    L119
  mov    $0x0,%ecx
  test   %al,%al
  je     L124
L71:
  mov    $0x0,%ecx
L149:
  movzbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  je     L124
  lea    -0x41(%rax),%r10d
  mov    %eax,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%eax
  lea    -0x41(%rdx),%r10d
  mov    %edx,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%edx
  cmp    %dl,%al
  jne    L124
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L149
L124:
  cmp    %rcx,%r8
  je     L49
  test   %rcx,%rcx
  mov    $0xfffffffd,%eax
  cmove  %rax,%rcx
L119:
  mov    %rcx,%rax
  ret
L55:
  mov    $0xffffffff,%ecx
  jmp    L119
L49:
  mov    $0x0,%ecx
  jmp    L119
L91:
  mov    $0x0,%edx
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  cmpb   $0x0,(%rsi)
  jne    L152
  jmp    L124
L30:
  mov    $0xfffffffe,%ecx
  mov    %rdx,%r8
  test   %rdx,%rdx
  je     L71
  jmp    L119
```

assistant: ```c
unsigned long aEQ(char *text, char *text2) {
  unsigned long x, y;
  char tmp, tmp2;
  if (text == NULL || text2 == NULL)
    return 0xFFFFFFFF;
  for (x ^= x; text[x] != 0; x++)
    ;
  for (y ^= y; text2[y] != 0; y++)
    ;
  if (x != y)
    return 0xFFFFFFFE;
  for (x ^= x; text[x] != 0 && text2[x] != 0; x++) {
    tmp = text[x];
    tmp2 = text2[x];
    if (tmp <= 'Z' && tmp >= 'A')
      tmp |= 0x20;
    if (tmp2 <= 'Z' && tmp2 >= 'A')
      tmp2 |= 0x20;
    if (tmp != tmp2)
      break;
  }
  if (x != y) {
    if (x == 0)
      return 0xFFFFFFFD;
    return x;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<aEQ>:
  endbr64
  test   %rdi,%rdi
  je     L93
  test   %rsi,%rsi
  je     L93
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  xor    %edx,%edx
  test   %al,%al
  je     L6
  cs nopw 0x0(%rax,%rax,1)
L95:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L95
  mov    $0xfffffffe,%r8d
  test   %cl,%cl
  je     L142
L96:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %rcx,%r11
  add    $0x1,%rcx
  cmpb   $0x0,(%rsi,%rcx,1)
  jne    L74
  mov    $0xfffffffe,%r8d
  cmp    %rcx,%rdx
  jne    L142
  xor    %r8d,%r8d
  test   %al,%al
  jne    L85
  jmp    L9
  nopl   0x0(%rax)
L33:
  lea    -0x41(%rax),%r10d
  mov    %eax,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  lea    -0x41(%rdx),%r10d
  cmovb  %r9d,%eax
  mov    %edx,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%edx
  cmp    %dl,%al
  jne    L70
  movzbl 0x1(%rdi,%r8,1),%eax
  lea    0x1(%r8),%rdx
  test   %al,%al
  je     L50
  mov    %rdx,%r8
L85:
  movzbl (%rsi,%r8,1),%edx
  test   %dl,%dl
  jne    L33
L70:
  cmp    %r8,%rcx
  je     L107
  test   %r8,%r8
  mov    $0xfffffffd,%eax
  cmove  %rax,%r8
L142:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L93:
  mov    $0xffffffff,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    %r11,%r8
  mov    $0x0,%r8d
  cmovne %rdx,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L6:
  test   %cl,%cl
  jne    L96
L107:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L9:
  mov    $0xfffffffd,%r8d
  jmp    L142
```

assistant: ```c
unsigned long aEQ(char *text, char *text2) {
  unsigned long x, y;
  char tmp, tmp2;
  if (text == NULL || text2 == NULL)
    return 0xFFFFFFFF;
  for (x ^= x; text[x] != 0; x++)
    ;
  for (y ^= y; text2[y] != 0; y++)
    ;
  if (x != y)
    return 0xFFFFFFFE;
  for (x ^= x; text[x] != 0 && text2[x] != 0; x++) {
    tmp = text[x];
    tmp2 = text2[x];
    if (tmp <= 'Z' && tmp >= 'A')
      tmp |= 0x20;
    if (tmp2 <= 'Z' && tmp2 >= 'A')
      tmp2 |= 0x20;
    if (tmp != tmp2)
      break;
  }
  if (x != y) {
    if (x == 0)
      return 0xFFFFFFFD;
    return x;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aEQ>:
  endbr64
  test   %rdi,%rdi
  je     L115
  test   %rsi,%rsi
  je     L115
  movzbl (%rdi),%eax
  movzbl (%rsi),%ecx
  xor    %edx,%edx
  test   %al,%al
  je     L144
  cs nopw 0x0(%rax,%rax,1)
L68:
  add    $0x1,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L68
  mov    $0xfffffffe,%r8d
  test   %cl,%cl
  je     L62
L38:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L91:
  mov    %rcx,%r11
  add    $0x1,%rcx
  cmpb   $0x0,(%rsi,%rcx,1)
  jne    L91
  mov    $0xfffffffe,%r8d
  cmp    %rcx,%rdx
  jne    L62
  xor    %r8d,%r8d
  test   %al,%al
  jne    L85
  jmp    L72
  nopl   0x0(%rax)
L94:
  lea    -0x41(%rax),%r10d
  mov    %eax,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  lea    -0x41(%rdx),%r10d
  cmovb  %r9d,%eax
  mov    %edx,%r9d
  or     $0x20,%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%edx
  cmp    %dl,%al
  jne    L67
  movzbl 0x1(%rdi,%r8,1),%eax
  lea    0x1(%r8),%rdx
  test   %al,%al
  je     L129
  mov    %rdx,%r8
L85:
  movzbl (%rsi,%r8,1),%edx
  test   %dl,%dl
  jne    L94
L67:
  cmp    %r8,%rcx
  je     L20
  test   %r8,%r8
  mov    $0xfffffffd,%eax
  cmove  %rax,%r8
L62:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L115:
  mov    $0xffffffff,%r8d
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L129:
  cmp    %r11,%r8
  mov    $0x0,%r8d
  cmovne %rdx,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L144:
  test   %cl,%cl
  jne    L38
L20:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L72:
  mov    $0xfffffffd,%r8d
  jmp    L62
```

assistant: ```c
unsigned long aEQ(char *text, char *text2) {
  unsigned long x, y;
  char tmp, tmp2;
  if (text == NULL || text2 == NULL)
    return 0xFFFFFFFF;
  for (x ^= x; text[x] != 0; x++)
    ;
  for (y ^= y; text2[y] != 0; y++)
    ;
  if (x != y)
    return 0xFFFFFFFE;
  for (x ^= x; text[x] != 0 && text2[x] != 0; x++) {
    tmp = text[x];
    tmp2 = text2[x];
    if (tmp <= 'Z' && tmp >= 'A')
      tmp |= 0x20;
    if (tmp2 <= 'Z' && tmp2 >= 'A')
      tmp2 |= 0x20;
    if (tmp != tmp2)
      break;
  }
  if (x != y) {
    if (x == 0)
      return 0xFFFFFFFD;
    return x;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ts_hex_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L18
L13:
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x20(%rbp),%esi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %esi,%r8d
  mov    %edi,%esi
  mov    %rax,%rdi
  call   <ts_hex_dump_buf@plt>
  mov    -0x8(%rbp),%rax
L18:
  leave
  ret
```

assistant: ```c
char *ts_hex_dump(uint8_t *d, int size, int col) {
  char *buf = malloc(size * 6);
  if (!buf)
    return NULL;
  ts_hex_dump_buf(buf, size * 6, d, size, col);
  return buf;
}
```