ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<util_hex_to_nib>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x25,%al
  ja     L12
  lea    D8(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nop
L12:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  ja     L5
  ret
  nopl   (%rax)
  mov    $0xc,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xd,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xe,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xf,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xa,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0xb,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int util_hex_to_nib(char ch) {
  int val;
  switch (ch) {
  case 'a':
  case 'A':
    val = 10;
    break;
  case 'b':
  case 'B':
    val = 11;
    break;
  case 'c':
  case 'C':
    val = 12;
    break;
  case 'd':
  case 'D':
    val = 13;
    break;
  case 'e':
  case 'E':
    val = 14;
    break;
  case 'f':
  case 'F':
    val = 15;
    break;
  default:
    val = (int)ch - (int)'0';
    if ((val < 0) || (val > 9)) {
      val = -1;
    }
    break;
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  cmp    %esi,%edx
  jg     L9
L112:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x338,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,%r14d
  shr    $0x1f,%r14d
  add    %eax,%r14d
  sar    %r14d
  lea    (%r14,%rsi,1),%r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%r15d
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <mergeSort>
  cmp    %r13d,%r12d
  jg     L71
  movslq %r12d,%rax
  mov    %rax,%rdx
  neg    %rdx
  lea    (%rsp,%rdx,4),%rcx
L105:
  mov    (%rbx,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r13d
  jge    L105
L71:
  cmp    %ebp,%r15d
  jg     L97
  movslq %r15d,%rax
  movslq %r13d,%r13
  neg    %r13
  lea    0x190(%rsp,%r13,4),%rcx
L108:
  mov    (%rbx,%rax,4),%edx
  mov    %edx,-0x4(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L108
L97:
  movslq %r12d,%rcx
  lea    (%rbx,%rcx,4),%rax
  mov    %ebp,%edx
  sub    %r12d,%edx
  add    %rcx,%rdx
  lea    0x4(%rbx,%rdx,4),%rdi
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L118
L6:
  movslq %edx,%rsi
  mov    0x190(%rsp,%rsi,4),%esi
  mov    %esi,(%rax)
  add    $0x1,%edx
L10:
  add    $0x4,%rax
  cmp    %rax,%rdi
  je     L112
L118:
  cmp    %ecx,%r14d
  jl     L6
  lea    (%r15,%rdx,1),%esi
  cmp    %ebp,%esi
  jg     L20
  movslq %ecx,%rsi
  movslq %edx,%r8
  mov    0x190(%rsp,%r8,4),%ebx
  cmp    %ebx,(%rsp,%rsi,4)
  jge    L6
L20:
  movslq %ecx,%rsi
  mov    (%rsp,%rsi,4),%esi
  mov    %esi,(%rax)
  add    $0x1,%ecx
  jmp    L10
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int left, int right) {
  if (right > left) {
    int mid = left + ((right - left) / 2);
    mergeSort(arr, left, mid);
    mergeSort(arr, mid + 1, right);
    int subLeft[100];
    int subRight[100];
    for (int i = left; i <= mid; i++)
      subLeft[i - left] = arr[i];
    for (int i = mid + 1; i <= right; i++)
      subRight[i - mid - 1] = arr[i];
    int leftIndex = 0;
    int rightIndex = 0;
    for (int i = left; i <= right; i++)
      if (left + leftIndex <= mid && (mid + 1 + rightIndex > right || subLeft[leftIndex] < subRight[rightIndex])) {
        arr[i] = subLeft[leftIndex];
        leftIndex++;
      } else {
        arr[i] = subRight[rightIndex];
        rightIndex++;
      }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x348,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  cmp    %esi,%edx
  jg     L56
L95:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x348,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L56:
  mov    %edx,%r12d
  mov    %rdi,%r14
  mov    %edx,%ebx
  mov    %esi,%ebp
  sub    %esi,%r12d
  sar    %r12d
  lea    (%r12,%rsi,1),%r15d
  mov    %r15d,%edx
  lea    0x1(%r15),%r13d
  call   <mergeSort>
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <mergeSort>
  cmp    %r15d,%ebp
  jg     L50
  movslq %ebp,%rcx
  mov    %r12d,%eax
  lea    0x10(%rsp),%rdi
  lea    (%r14,%rcx,4),%rsi
  lea    0x4(,%rax,4),%rdx
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
L84:
  cmp    %ebx,%r13d
  jg     L15
  lea    -0x1(%rbx),%eax
  lea    0x1a0(%rsp),%rdi
  mov    %rcx,0x8(%rsp)
  sub    %r15d,%eax
  lea    0x4(,%rax,4),%rdx
  movslq %r13d,%rax
  lea    (%r14,%rax,4),%rsi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
L15:
  mov    %ebx,%edx
  lea    (%r14,%rcx,4),%rax
  sub    %ebp,%edx
  add    %rcx,%rdx
  xor    %ecx,%ecx
  lea    0x4(%r14,%rdx,4),%rdi
  xor    %edx,%edx
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L49:
  movslq %ecx,%rsi
  mov    0x10(%rsp,%rsi,4),%r8d
  lea    0x0(%r13,%rdx,1),%esi
  cmp    %ebx,%esi
  jg     L58
  movslq %edx,%rsi
  mov    0x1a0(%rsp,%rsi,4),%esi
  cmp    %r8d,%esi
  jle    L45
L58:
  mov    %r8d,(%rax)
  add    $0x1,%ecx
L31:
  add    $0x4,%rax
  cmp    %rax,%rdi
  je     L95
L99:
  cmp    %ecx,%r12d
  jge    L49
  movslq %edx,%rsi
  mov    0x1a0(%rsp,%rsi,4),%esi
L45:
  mov    %esi,(%rax)
  add    $0x1,%edx
  jmp    L31
  nopl   0x0(%rax)
L50:
  movslq %ebp,%rcx
  jmp    L84
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int left, int right) {
  if (right > left) {
    int mid = left + ((right - left) / 2);
    mergeSort(arr, left, mid);
    mergeSort(arr, mid + 1, right);
    int subLeft[100];
    int subRight[100];
    for (int i = left; i <= mid; i++)
      subLeft[i - left] = arr[i];
    for (int i = mid + 1; i <= right; i++)
      subRight[i - mid - 1] = arr[i];
    int leftIndex = 0;
    int rightIndex = 0;
    for (int i = left; i <= right; i++)
      if (left + leftIndex <= mid && (mid + 1 + rightIndex > right || subLeft[leftIndex] < subRight[rightIndex])) {
        arr[i] = subLeft[leftIndex];
        leftIndex++;
      } else {
        arr[i] = subRight[rightIndex];
        rightIndex++;
      }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mergeSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  cmp    %esi,%edx
  jg     L42
L47:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  add    $0x338,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L42:
  mov    %edx,%r13d
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %esi,%ebx
  sub    %esi,%r13d
  sar    %r13d
  lea    0x0(%r13,%rsi,1),%r15d
  mov    %r15d,%edx
  lea    0x1(%r15),%r14d
  call   <mergeSort>
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <mergeSort>
  cmp    %r15d,%ebx
  jg     L119
  mov    %r13d,%eax
  mov    %rsp,%rdi
  lea    0x4(,%rax,4),%rdx
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rsi
  call   <memcpy@plt>
L119:
  cmp    %ebp,%r14d
  jg     L23
  lea    -0x1(%rbp),%eax
  lea    0x190(%rsp),%rdi
  sub    %r15d,%eax
  lea    0x4(,%rax,4),%rdx
  movslq %r14d,%rax
  lea    (%r12,%rax,4),%rsi
  call   <memcpy@plt>
L23:
  lea    0x1(%rbx),%eax
  xor    %edx,%edx
  xor    %ecx,%ecx
  cltq
L76:
  movslq %ecx,%rsi
  lea    (%r14,%rdx,1),%edi
  mov    (%rsp,%rsi,4),%esi
  cmp    %ebp,%edi
  jg     L20
  movslq %edx,%rdi
  mov    0x190(%rsp,%rdi,4),%edi
  cmp    %esi,%edi
  jg     L20
  mov    %edi,-0x4(%r12,%rax,4)
  add    $0x1,%edx
  cmp    %eax,%ebp
  jl     L47
  nopl   (%rax)
L110:
  add    $0x1,%rax
  cmp    %ecx,%r13d
  jge    L76
  movslq %edx,%rcx
  add    $0x1,%edx
  mov    0x190(%rsp,%rcx,4),%ecx
  mov    %ecx,-0x4(%r12,%rax,4)
  cmp    %eax,%ebp
  jl     L47
  movslq %eax,%rcx
  movslq %edx,%rdx
  lea    (%r12,%rcx,4),%rdi
  mov    %ebp,%ecx
  lea    0x190(%rsp,%rdx,4),%rsi
  sub    %eax,%ecx
  cmp    %eax,%ebp
  mov    $0x4,%eax
  lea    0x4(,%rcx,4),%r8
  cmovl  %rax,%r8
  mov    %r8,%rdx
  call   <memcpy@plt>
  jmp    L47
  nopl   0x0(%rax)
L20:
  mov    %esi,-0x4(%r12,%rax,4)
  add    $0x1,%ecx
  cmp    %eax,%ebp
  jge    L110
  jmp    L47
L96:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mergeSort(int arr[], int left, int right) {
  if (right > left) {
    int mid = left + ((right - left) / 2);
    mergeSort(arr, left, mid);
    mergeSort(arr, mid + 1, right);
    int subLeft[100];
    int subRight[100];
    for (int i = left; i <= mid; i++)
      subLeft[i - left] = arr[i];
    for (int i = mid + 1; i <= right; i++)
      subRight[i - mid - 1] = arr[i];
    int leftIndex = 0;
    int rightIndex = 0;
    for (int i = left; i <= right; i++)
      if (left + leftIndex <= mid && (mid + 1 + rightIndex > right || subLeft[leftIndex] < subRight[rightIndex])) {
        arr[i] = subLeft[leftIndex];
        leftIndex++;
      } else {
        arr[i] = subRight[rightIndex];
        rightIndex++;
      }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initLinuxIO@plt>
  mov    $0x0,%eax
  call   <mainLoop@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main(void) {
  initLinuxIO();
  mainLoop();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initLinuxIO@plt>
  mov    $0x0,%eax
  call   <mainLoop@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  initLinuxIO();
  mainLoop();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initLinuxIO@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <mainLoop@plt>
```

assistant: ```c
void main(void) {
  initLinuxIO();
  mainLoop();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<celcon_copy_target_standard_solution_to_container>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x68,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int celcon_copy_target_standard_solution_to_container(int k, int i) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(104, &k, &i, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<celcon_copy_target_standard_solution_to_container>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x68,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int celcon_copy_target_standard_solution_to_container(int k, int i) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(104, &k, &i, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<celcon_copy_target_standard_solution_to_container>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x68,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int celcon_copy_target_standard_solution_to_container(int k, int i) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(104, &k, &i, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<celcon_copy_target_standard_solution_to_container>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x68,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int celcon_copy_target_standard_solution_to_container(int k, int i) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(104, &k, &i, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_recursive_factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xc,-0x4(%rbp)
  jle    L19
  mov    $0x0,%eax
  jmp    L34
L19:
  cmpl   $0x0,-0x4(%rbp)
  jg     L49
  mov    $0x0,%eax
  jmp    L34
L49:
  cmpl   $0x1,-0x4(%rbp)
  jne    L9
  mov    $0x1,%eax
  jmp    L34
L9:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ft_recursive_factorial>
  imul   -0x4(%rbp),%eax
L34:
  leave
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb > 12)
    return (0);
  if (nb < 1)
    return (0);
  if (nb == 1)
    return (1);
  else
    return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_recursive_factorial>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x0,%eax
  cmp    $0xb,%edx
  jbe    L16
  ret
L16:
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%edi
  jne    L22
L0:
  pop    %rbx
  ret
L22:
  mov    %edx,%edi
  call   <ft_recursive_factorial>
  imul   %ebx,%eax
  jmp    L0
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb > 12)
    return (0);
  if (nb < 1)
    return (0);
  if (nb == 1)
    return (1);
  else
    return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_recursive_factorial>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0xb,%eax
  ja     L24
  mov    $0x1,%r8d
  cmp    $0x1,%edi
  jne    L12
  jmp    L6
  nopl   0x0(%rax)
L42:
  sub    $0x1,%eax
L12:
  mov    %edi,%edx
  mov    %eax,%edi
  imul   %edx,%r8d
  cmp    $0x1,%eax
  jne    L42
L6:
  mov    %r8d,%eax
  ret
L24:
  xor    %r8d,%r8d
  jmp    L6
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb > 12)
    return (0);
  if (nb < 1)
    return (0);
  if (nb == 1)
    return (1);
  else
    return (nb * ft_recursive_factorial(nb - 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_recursive_factorial>:
  endbr64
  lea    -0x1(%rdi),%eax
  cmp    $0xb,%eax
  ja     L95
  cmp    $0x1,%edi
  je     L101
  cmp    $0x1,%eax
  je     L25
  imul   %edi,%eax
  lea    -0x2(%rdi),%edx
  cmp    $0x3,%edi
  je     L0
  imul   %edx,%eax
  lea    -0x3(%rdi),%ecx
  cmp    $0x4,%edi
  je     L0
  imul   %ecx,%eax
  lea    -0x4(%rdi),%edx
  cmp    $0x5,%edi
  je     L0
  imul   %edx,%eax
  lea    -0x5(%rdi),%ecx
  cmp    $0x6,%edi
  je     L0
  imul   %ecx,%eax
  lea    -0x6(%rdi),%edx
  cmp    $0x7,%edi
  je     L0
  imul   %edx,%eax
  lea    -0x7(%rdi),%ecx
  cmp    $0x8,%edi
  je     L0
  imul   %ecx,%eax
  lea    -0x8(%rdi),%esi
  cmp    $0x9,%edi
  je     L0
  imul   %esi,%eax
  lea    -0x9(%rdi),%edx
  cmp    $0xa,%edi
  je     L0
  imul   %edx,%eax
  cmp    $0x2,%edx
  lea    (%rax,%rax,1),%ecx
  cmovne %ecx,%eax
  ret
L101:
  mov    $0x1,%eax
L0:
  ret
L95:
  xor    %eax,%eax
  ret
L25:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb > 12)
    return (0);
  if (nb < 1)
    return (0);
  if (nb == 1)
    return (1);
  else
    return (nb * ft_recursive_factorial(nb - 1));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x22b8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <start_server@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int port = 8888;
  start_server(port);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22b8,%edi
  call   <start_server@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int port = 8888;
  start_server(port);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22b8,%edi
  call   <start_server@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int port = 8888;
  start_server(port);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x22b8,%edi
  call   <start_server@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int port = 8888;
  start_server(port);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L6
  mov    $0xff,%ecx
  mov    $0xff,%edx
  mov    $0x0,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <sysPrintString@plt>
  mov    $0x2,%eax
  jmp    L15
L6:
  mov    $0x0,%eax
  call   <sysClear@plt>
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: No extra parameters for clear


assistant: ```c
int clear(int words) {
  if (words != 1) {
    sysPrintString("No extra parameters for clear\n", 0, 255, 255);
    return 2;
  }
  sysClear();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L14
  mov    $0x0,%eax
  call   <sysClear@plt>
  mov    $0x0,%eax
L1:
  add    $0x8,%rsp
  ret
L14:
  mov    $0xff,%ecx
  mov    $0xff,%edx
  mov    $0x0,%esi
  lea    D0(%rip),%rdi
  call   <sysPrintString@plt>
  mov    $0x2,%eax
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: No extra parameters for clear


assistant: ```c
int clear(int words) {
  if (words != 1) {
    sysPrintString("No extra parameters for clear\n", 0, 255, 255);
    return 2;
  }
  sysClear();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L7
  xor    %eax,%eax
  call   <sysClear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xff,%ecx
  mov    $0xff,%edx
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <sysPrintString@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: No extra parameters for clear


assistant: ```c
int clear(int words) {
  if (words != 1) {
    sysPrintString("No extra parameters for clear\n", 0, 255, 255);
    return 2;
  }
  sysClear();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clear>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jne    L9
  xor    %eax,%eax
  call   <sysClear@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xff,%ecx
  mov    $0xff,%edx
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  call   <sysPrintString@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: No extra parameters for clear


assistant: ```c
int clear(int words) {
  if (words != 1) {
    sysPrintString("No extra parameters for clear\n", 0, 255, 255);
    return 2;
  }
  sysClear();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<utf8codepointcalcsize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf8,%eax
  cmp    $0xf0,%eax
  jne    L17
  mov    $0x4,%eax
  jmp    L15
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  jne    L24
  mov    $0x3,%eax
  jmp    L15
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L44
  mov    $0x2,%eax
  jmp    L15
L44:
  mov    $0x1,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
size_t utf8codepointcalcsize(const void *str) {
  const char *s = (const char *)str;
  if (0xf0 == (0xf8 & s[0])) {
    return 4;
  } else if (0xe0 == (0xf0 & s[0])) {
    return 3;
  } else if (0xc0 == (0xe0 & s[0])) {
    return 2;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utf8codepointcalcsize>:
  endbr64
  movsbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L10
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L18
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x1,%rax
  ret
L10:
  mov    $0x4,%eax
  ret
L18:
  mov    $0x3,%eax
  ret
```

assistant: ```c
size_t utf8codepointcalcsize(const void *str) {
  const char *s = (const char *)str;
  if (0xf0 == (0xf8 & s[0])) {
    return 4;
  } else if (0xe0 == (0xf0 & s[0])) {
    return 3;
  } else if (0xc0 == (0xe0 & s[0])) {
    return 2;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<utf8codepointcalcsize>:
  endbr64
  movsbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L10
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L18
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x1,%rax
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0x3,%eax
  ret
```

assistant: ```c
size_t utf8codepointcalcsize(const void *str) {
  const char *s = (const char *)str;
  if (0xf0 == (0xf8 & s[0])) {
    return 4;
  } else if (0xe0 == (0xf0 & s[0])) {
    return 3;
  } else if (0xc0 == (0xe0 & s[0])) {
    return 2;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<utf8codepointcalcsize>:
  endbr64
  movsbl (%rdi),%eax
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L17
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L8
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x1,%rax
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x4,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    $0x3,%eax
  ret
```

assistant: ```c
size_t utf8codepointcalcsize(const void *str) {
  const char *s = (const char *)str;
  if (0xf0 == (0xf8 & s[0])) {
    return 4;
  } else if (0xe0 == (0xf0 & s[0])) {
    return 3;
  } else if (0xc0 == (0xe0 & s[0])) {
    return 2;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_format_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L3
L6:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L15
  addl   $0x1,-0x8(%rbp)
L15:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned str_format_size(const char *str, unsigned f_char, unsigned l_char) {
  unsigned i, size = 0;
  for (i = f_char + 1; i < l_char; i++) {
    if (str[i] == '\\')
      i++;
    size++;
  }
  return size;
}
```