ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D11
data_type: string

tool: D12: 123%n4

tool: D11: ret:%d, n:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int n;
  ret = printf("123%n4", &n);
  printf("ret"
         ":%d, "
         "n"
         ":%d\n",
         (ret), (n));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %eax,%esi
  mov    0x4(%rsp),%edx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string

tool: D2: 123%n4

tool: D8: ret:%d, n:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int n;
  ret = printf("123%n4", &n);
  printf("ret"
         ":%d, "
         "n"
         ":%d\n",
         (ret), (n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D11: 123%n4

tool: D2: ret:%d, n:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int n;
  ret = printf("123%n4", &n);
  printf("ret"
         ":%d, "
         "n"
         ":%d\n",
         (ret), (n));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string

tool: D9: 123%n4

tool: D11: ret:%d, n:%d


assistant: ```c
int main(int argc, char *argv[]) {
  int ret;
  int n;
  ret = printf("123%n4", &n);
  printf("ret"
         ":%d, "
         "n"
         ":%d\n",
         (ret), (n));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<randselect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L12
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L28
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <randselect>
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L28:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <randselect>
L12:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: %d


assistant: ```c
void randselect(int m, int n) {
  if (m > 0) {
    if (rand() % n < m) {
      randselect(m - 1, n - 1);
      printf("%d\n", n - 1);
    } else
      randselect(m, n - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<randselect>:
  endbr64
  test   %edi,%edi
  jg     L21
  ret
L21:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %ebp,%edx
  jge    L17
  sub    $0x1,%ebx
  lea    -0x1(%rbp),%edi
  mov    %ebx,%esi
  call   <randselect>
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    -0x1(%rbx),%esi
  mov    %ebp,%edi
  call   <randselect>
  jmp    L26
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
void randselect(int m, int n) {
  if (m > 0) {
    if (rand() % n < m) {
      randselect(m - 1, n - 1);
      printf("%d\n", n - 1);
    } else
      randselect(m, n - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<randselect>:
  endbr64
  test   %edi,%edi
  jle    L43
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L39:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  sub    $0x1,%ebp
  cmp    %ebx,%edx
  jge    L39
  mov    %ebx,%r13d
  lea    D7(%rip),%rdi
  sub    $0x1,%r13d
  je     L27
  mov    %ebp,%r12d
  nopl   0x0(%rax,%rax,1)
L60:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  sub    $0x1,%r12d
  cmp    %edx,%r13d
  jle    L60
  mov    %ebx,%r14d
  lea    D7(%rip),%rdi
  sub    $0x2,%r14d
  je     L31
  mov    %r12d,%r13d
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r13d
  sub    $0x1,%r13d
  cmp    %edx,%r14d
  jle    L59
  mov    %ebx,%r15d
  lea    D7(%rip),%rdi
  sub    $0x3,%r15d
  je     L14
  mov    %r13d,%r14d
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r14d
  sub    $0x1,%r14d
  cmp    %edx,%r15d
  jle    L5
  lea    -0x4(%rbx),%edi
  mov    %r14d,%esi
  call   <randselect>
  lea    D7(%rip),%rdi
  mov    %r14d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L14:
  mov    %r13d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L31:
  mov    %r12d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L27:
  add    $0x18,%rsp
  mov    %ebp,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
L43:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: %d


assistant: ```c
void randselect(int m, int n) {
  if (m > 0) {
    if (rand() % n < m) {
      randselect(m - 1, n - 1);
      printf("%d\n", n - 1);
    } else
      randselect(m, n - 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<randselect>:
  endbr64
  test   %edi,%edi
  jle    L54
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L11:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  sub    $0x1,%ebp
  cmp    %ebx,%edx
  jge    L11
  mov    %ebx,%r13d
  lea    D22(%rip),%rdi
  sub    $0x1,%r13d
  je     L17
  mov    %ebp,%r12d
  nopl   0x0(%rax,%rax,1)
L66:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r12d
  sub    $0x1,%r12d
  cmp    %edx,%r13d
  jle    L66
  mov    %ebx,%r14d
  lea    D22(%rip),%rdi
  sub    $0x2,%r14d
  je     L9
  mov    %r12d,%r13d
  nopl   0x0(%rax,%rax,1)
L61:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r13d
  sub    $0x1,%r13d
  cmp    %edx,%r14d
  jle    L61
  mov    %ebx,%r15d
  lea    D22(%rip),%rdi
  sub    $0x3,%r15d
  je     L62
  mov    %r13d,%r14d
  nopw   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %r14d
  sub    $0x1,%r14d
  cmp    %edx,%r15d
  jle    L67
  lea    -0x4(%rbx),%edi
  mov    %r14d,%esi
  call   <randselect>
  lea    D22(%rip),%rdi
  mov    %r14d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L62:
  mov    %r13d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L9:
  mov    %r12d,%esi
  mov    %rdi,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdi
L17:
  add    $0x18,%rsp
  mov    %ebp,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
L54:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D22
type: string

tool: D22: %d


assistant: ```c
void randselect(int m, int n) {
  if (m > 0) {
    if (rand() % n < m) {
      randselect(m - 1, n - 1);
      printf("%d\n", n - 1);
    } else
      randselect(m, n - 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x24,%rax
  mov    %rax,-0x38(%rbp)
  jmp    L11
L29:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x40(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x40(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  lea    -0x4(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    -0x44(%rbp),%edx
  mov    %edx,(%rax)
L11:
  mov    -0x40(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L29
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  jmp    L6
L41:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x4,-0x40(%rbp)
L6:
  lea    -0x30(%rbp),%rax
  add    $0x28,%rax
  cmp    %rax,-0x40(%rbp)
  jb     L41
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: %d 

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int *p = a, *q = &a[9], temp;
  while (p < q) {
    temp = *p;
    *p++ = *q;
    *q-- = temp;
  }
  for (p = a; p < a + 10; p++)
    printf("%d ", *p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  lea    0x24(%rsp),%rdx
  mov    %rsp,%rax
  lea    0x14(%rsp),%rdi
L5:
  mov    (%rax),%ecx
  add    $0x4,%rax
  mov    (%rdx),%esi
  mov    %esi,-0x4(%rax)
  sub    $0x4,%rdx
  mov    %ecx,0x4(%rdx)
  cmp    %rdi,%rax
  jne    L5
  mov    %rsp,%rbx
  lea    D5(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  lea    0x28(%rsp),%rax
  cmp    %rax,%rbx
  jne    L0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: %d 

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int *p = a, *q = &a[9], temp;
  while (p < q) {
    temp = *p;
    *p++ = *q;
    *q-- = temp;
  }
  for (p = a; p < a + 10; p++)
    printf("%d ", *p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  mov    $0xa,%ecx
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x24(%rsp),%rdx
  lea    0x14(%rsp),%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  mov    %rbx,%rax
L32:
  add    $0x4,%rax
  sub    $0x4,%rdx
  mov    %ecx,-0x4(%rax)
  mov    %esi,0x4(%rdx)
  cmp    %rdi,%rax
  je     L24
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L24:
  lea    D6(%rip),%r12
  lea    0x28(%rsp),%rbp
  nopl   0x0(%rax)
L31:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L31
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d 

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int *p = a, *q = &a[9], temp;
  while (p < q) {
    temp = *p;
    *p++ = *q;
    *q-- = temp;
  }
  for (p = a; p < a + 10; p++)
    printf("%d ", *p);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D35(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D37(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movdqa D31(%rip),%xmm0
  mov    %rax,0x10(%rsp)
  movups %xmm0,0x18(%rsp)
L5:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L5
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
data_type: string
name: extract_symbolic_data
arguments: label: D35
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D37
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D31
data_type: byte[16]

tool: D27: %d 

tool: {"D35": [0x0a,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D37": [0x06,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D31": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int *p = a, *q = &a[9], temp;
  while (p < q) {
    temp = *p;
    *p++ = *q;
    *q-- = temp;
  }
  for (p = a; p < a + 10; p++)
    printf("%d ", *p);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<util_dword_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x38,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x30,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x28,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x20,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x18,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x10,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  shr    $0x8,%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <util_byte_to_hex@plt>
  addq   $0x2,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void util_dword_to_hex(char *dst, unsigned long long dw) {
  unsigned char byte;
  byte = (unsigned char)((dw >> 56) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 48) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 40) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 32) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 24) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 16) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 8) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)(dw & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  *dst = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_dword_to_hex>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rax
  shr    $0x38,%rax
  mov    %rax,%rsi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  shr    $0x30,%rsi
  movzbl %sil,%esi
  lea    0x2(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  shr    $0x28,%rsi
  movzbl %sil,%esi
  lea    0x4(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  shr    $0x20,%rsi
  movzbl %sil,%esi
  lea    0x6(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  mov    %ebx,%esi
  shr    $0x18,%esi
  lea    0x8(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  lea    0xa(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movzbl %bh,%esi
  lea    0xc(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movzbl %bl,%esi
  lea    0xe(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movb   $0x0,0x10(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void util_dword_to_hex(char *dst, unsigned long long dw) {
  unsigned char byte;
  byte = (unsigned char)((dw >> 56) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 48) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 40) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 32) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 24) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 16) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 8) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)(dw & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  *dst = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<util_dword_to_hex>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %rdi,%rbp
  push   %rbx
  shr    $0x38,%rax
  mov    %rsi,%rbx
  mov    %rax,%rsi
  sub    $0x8,%rsp
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x2(%rbp),%rdi
  shr    $0x30,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x4(%rbp),%rdi
  shr    $0x28,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x6(%rbp),%rdi
  shr    $0x20,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %ebx,%esi
  lea    0x8(%rbp),%rdi
  shr    $0x18,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0xa(%rbp),%rdi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  movzbl %bh,%esi
  lea    0xc(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movzbl %bl,%esi
  lea    0xe(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movb   $0x0,0x10(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void util_dword_to_hex(char *dst, unsigned long long dw) {
  unsigned char byte;
  byte = (unsigned char)((dw >> 56) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 48) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 40) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 32) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 24) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 16) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 8) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)(dw & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  *dst = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_dword_to_hex>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  mov    %rdi,%rbp
  push   %rbx
  shr    $0x38,%rax
  mov    %rsi,%rbx
  mov    %rax,%rsi
  sub    $0x8,%rsp
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x2(%rbp),%rdi
  shr    $0x30,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x4(%rbp),%rdi
  shr    $0x28,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0x6(%rbp),%rdi
  shr    $0x20,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  mov    %ebx,%esi
  lea    0x8(%rbp),%rdi
  shr    $0x18,%esi
  call   <util_byte_to_hex@plt>
  mov    %rbx,%rsi
  lea    0xa(%rbp),%rdi
  shr    $0x10,%rsi
  movzbl %sil,%esi
  call   <util_byte_to_hex@plt>
  movzbl %bh,%esi
  lea    0xc(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movzbl %bl,%esi
  lea    0xe(%rbp),%rdi
  call   <util_byte_to_hex@plt>
  movb   $0x0,0x10(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void util_dword_to_hex(char *dst, unsigned long long dw) {
  unsigned char byte;
  byte = (unsigned char)((dw >> 56) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 48) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 40) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 32) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 24) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 16) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)((dw >> 8) & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  byte = (unsigned char)(dw & 0xff);
  util_byte_to_hex(dst, byte);
  dst += 2;
  *dst = 0;
}
```