ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_bounds>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L7
  mov    %esi,(%rdi)
  ret
L7:
  cmp    %edx,%eax
  jle    L3
  mov    %edx,(%rdi)
L3:
  ret
```

assistant: ```c
void int_bounds(register int *what, register int lower_limit, register int upper_limit) {
  if (*what < lower_limit)
    *what = lower_limit;
  else if (*what > upper_limit)
    *what = upper_limit;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_bounds>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L8
  mov    %esi,(%rdi)
  ret
  nopl   (%rax)
L8:
  cmp    %edx,%eax
  jle    L0
  mov    %edx,(%rdi)
L0:
  ret
```

assistant: ```c
void int_bounds(register int *what, register int lower_limit, register int upper_limit) {
  if (*what < lower_limit)
    *what = lower_limit;
  else if (*what > upper_limit)
    *what = upper_limit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<int_bounds>:
  endbr64
  mov    (%rdi),%eax
  cmp    %esi,%eax
  jge    L10
  mov    %esi,(%rdi)
  ret
  nopl   (%rax)
L10:
  cmp    %edx,%eax
  jle    L17
  mov    %edx,(%rdi)
L17:
  ret
```

assistant: ```c
void int_bounds(register int *what, register int lower_limit, register int upper_limit) {
  if (*what < lower_limit)
    *what = lower_limit;
  else if (*what > upper_limit)
    *what = upper_limit;
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L19:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  cmpq   $0x0,-0x8(%rbp)
  jg     L19
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int convert_long(long number, int target[]) {
  int i;
  long aux = number;
  for (i = 0; aux > 0; i++) {
    target[i] = aux % 10;
    aux = aux / 10;
  }
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_long>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r8
  test   %rdi,%rdi
  jle    L0
  mov    $0x1,%esi
  movabs $0x6666666666666667,%r9
L4:
  mov    %rcx,%rax
  imul   %r9
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  mov    %rcx,%rdi
  sub    %rax,%rdi
  mov    %edi,-0x4(%r8,%rsi,4)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  add    $0x1,%rsi
  cmp    $0x9,%rax
  jg     L4
L23:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int convert_long(long number, int target[]) {
  int i;
  long aux = number;
  for (i = 0; aux > 0; i++) {
    target[i] = aux % 10;
    aux = aux / 10;
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<convert_long>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  jle    L4
  movabs $0xcccccccccccccccd,%r9
  mov    $0x1,%edi
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rcx,%rax
  mov    %rcx,%r8
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r8
  mov    %rcx,%rax
  mov    %rdx,%rcx
  mov    %r8d,-0x4(%rsi,%rdi,4)
  mov    %edi,%r8d
  add    $0x1,%rdi
  cmp    $0x9,%rax
  jg     L9
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int convert_long(long number, int target[]) {
  int i;
  long aux = number;
  for (i = 0; aux > 0; i++) {
    target[i] = aux % 10;
    aux = aux / 10;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<convert_long>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  jle    L14
  movabs $0xcccccccccccccccd,%r9
  mov    $0x1,%edi
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rcx,%rax
  mov    %rcx,%r8
  mul    %r9
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%r8
  mov    %rcx,%rax
  mov    %rdx,%rcx
  mov    %r8d,-0x4(%rsi,%rdi,4)
  mov    %edi,%r8d
  add    $0x1,%rdi
  cmp    $0x9,%rax
  jg     L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int convert_long(long number, int target[]) {
  int i;
  long aux = number;
  for (i = 0; aux > 0; i++) {
    target[i] = aux % 10;
    aux = aux / 10;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitshifted_values>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x2,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x3,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x4,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x5,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x6,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x7,%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D71
data_type: string

tool: D71: third:  %i


assistant: ```c
void bitshifted_values(int *g) {
  printf("third:  %i\n", *g << 0);
  printf("third:  %i\n", *g << 1);
  printf("third:  %i\n", *g << 2);
  printf("third:  %i\n", *g << 3);
  printf("third:  %i\n", *g << 4);
  printf("third:  %i\n", *g << 5);
  printf("third:  %i\n", *g << 6);
  printf("third:  %i\n", *g << 7);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitshifted_values>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    (%rdi),%esi
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  lea    (%rax,%rax,1),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  lea    0x0(,%rax,4),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  lea    0x0(,%rax,8),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  shl    $0x4,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  shl    $0x5,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  shl    $0x6,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  shl    $0x7,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: third:  %i


assistant: ```c
void bitshifted_values(int *g) {
  printf("third:  %i\n", *g << 0);
  printf("third:  %i\n", *g << 1);
  printf("third:  %i\n", *g << 2);
  printf("third:  %i\n", *g << 3);
  printf("third:  %i\n", *g << 4);
  printf("third:  %i\n", *g << 5);
  printf("third:  %i\n", *g << 6);
  printf("third:  %i\n", *g << 7);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitshifted_values>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    (%rax,%rax,1),%esi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    0x0(,%rax,4),%esi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    0x0(,%rax,8),%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x4,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x5,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x6,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  shl    $0x7,%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: third:  %i


assistant: ```c
void bitshifted_values(int *g) {
  printf("third:  %i\n", *g << 0);
  printf("third:  %i\n", *g << 1);
  printf("third:  %i\n", *g << 2);
  printf("third:  %i\n", *g << 3);
  printf("third:  %i\n", *g << 4);
  printf("third:  %i\n", *g << 5);
  printf("third:  %i\n", *g << 6);
  printf("third:  %i\n", *g << 7);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitshifted_values>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    (%rax,%rax,1),%esi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    0x0(,%rax,4),%esi
  call   <printf@plt>
  mov    (%rbx),%eax
  mov    %rbp,%rdi
  lea    0x0(,%rax,8),%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x4,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x5,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  shl    $0x6,%esi
  call   <printf@plt>
  mov    (%rbx),%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  shl    $0x7,%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: third:  %i


assistant: ```c
void bitshifted_values(int *g) {
  printf("third:  %i\n", *g << 0);
  printf("third:  %i\n", *g << 1);
  printf("third:  %i\n", *g << 2);
  printf("third:  %i\n", *g << 3);
  printf("third:  %i\n", *g << 4);
  printf("third:  %i\n", *g << 5);
  printf("third:  %i\n", *g << 6);
  printf("third:  %i\n", *g << 7);
}
```
user: What is the c source code of the assembly code below?

```asm
<tea_decrypt_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %rcx,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x70(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L18
L52:
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <le2int@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdi
  call   <le2int@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rcx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <tea_decrypt@plt>
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <int2le@plt>
  mov    -0x60(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <int2le@plt>
  addq   $0x8,-0x58(%rbp)
  addq   $0x8,-0x60(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jne    L32
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L32
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L32
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L32:
  addl   $0x1,-0x44(%rbp)
L18:
  mov    -0x44(%rbp),%eax
  mov    -0x68(%rbp),%rdx
  shr    $0x3,%rdx
  cmp    %rdx,%rax
  jb     L52
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void tea_decrypt_buf(const unsigned char *src, unsigned char *dest, size_t n, const uint32_t *initial_key) {
  uint32_t v0, v1;
  unsigned int i;
  uint32_t key[4];
  memcpy(key, initial_key, sizeof(key));
  for (i = 0; i < (n / 8); i++) {
    v0 = le2int(src);
    v1 = le2int(src + 4);
    tea_decrypt(&v0, &v1, key);
    int2le(v0, dest);
    int2le(v1, dest + 4);
    src += 8;
    dest += 8;
    key[0]++;
    if (key[0] == 0) {
      key[1]++;
      if (key[1] == 0) {
        key[2]++;
        if (key[2] == 0) {
          key[3]++;
        }
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tea_decrypt_buf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x20,%edx
  call   <memcpy@plt>
  mov    %r12,%r13
  shr    $0x3,%r13
  cmp    $0x7,%r12
  jbe    L71
  mov    $0x0,%r12d
  lea    0x10(%rsp),%r14
  jmp    L47
L12:
  add    $0x1,%r12d
  mov    %r12d,%eax
  cmp    %r13,%rax
  jae    L71
L47:
  mov    %rbx,%rdi
  call   <le2int@plt>
  mov    %rax,(%rsp)
  lea    0x4(%rbx),%rdi
  call   <le2int@plt>
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    %r14,%rdx
  call   <tea_decrypt@plt>
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <int2le@plt>
  lea    0x4(%rbp),%rsi
  mov    0x8(%rsp),%rdi
  call   <int2le@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    0x10(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x10(%rsp)
  jne    L12
  mov    0x18(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x18(%rsp)
  jne    L12
  mov    0x20(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x20(%rsp)
  jne    L12
  addq   $0x1,0x28(%rsp)
  jmp    L12
L71:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decrypt_buf(const unsigned char *src, unsigned char *dest, size_t n, const uint32_t *initial_key) {
  uint32_t v0, v1;
  unsigned int i;
  uint32_t key[4];
  memcpy(key, initial_key, sizeof(key));
  for (i = 0; i < (n / 8); i++) {
    v0 = le2int(src);
    v1 = le2int(src + 4);
    tea_decrypt(&v0, &v1, key);
    int2le(v0, dest);
    int2le(v1, dest + 4);
    src += 8;
    dest += 8;
    key[0]++;
    if (key[0] == 0) {
      key[1]++;
      if (key[1] == 0) {
        key[2]++;
        if (key[2] == 0) {
          key[3]++;
        }
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tea_decrypt_buf>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x20,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  shr    $0x3,%rbp
  mov    %rbp,0x8(%rsp)
  je     L39
  xor    %ebp,%ebp
  lea    0x18(%rsp),%r14
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r15,%rdi
  call   <le2int@plt>
  lea    0x4(%r15),%rdi
  add    $0x8,%r15
  mov    %rax,0x10(%rsp)
  call   <le2int@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,0x18(%rsp)
  call   <tea_decrypt@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <int2le@plt>
  mov    0x18(%rsp),%rdi
  lea    0x4(%rbx),%rsi
  add    $0x8,%rbx
  call   <int2le@plt>
  addq   $0x1,0x20(%rsp)
  jne    L31
  addq   $0x1,0x28(%rsp)
  jne    L31
  addq   $0x1,0x30(%rsp)
  jne    L31
  addq   $0x1,0x38(%rsp)
  nopw   0x0(%rax,%rax,1)
L31:
  lea    0x1(%rbp),%eax
  mov    %rax,%rbp
  cmp    0x8(%rsp),%rax
  jb     L17
L39:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decrypt_buf(const unsigned char *src, unsigned char *dest, size_t n, const uint32_t *initial_key) {
  uint32_t v0, v1;
  unsigned int i;
  uint32_t key[4];
  memcpy(key, initial_key, sizeof(key));
  for (i = 0; i < (n / 8); i++) {
    v0 = le2int(src);
    v1 = le2int(src + 4);
    tea_decrypt(&v0, &v1, key);
    int2le(v0, dest);
    int2le(v1, dest + 4);
    src += 8;
    dest += 8;
    key[0]++;
    if (key[0] == 0) {
      key[1]++;
      if (key[1] == 0) {
        key[2]++;
        if (key[2] == 0) {
          key[3]++;
        }
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tea_decrypt_buf>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x20,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %r12,%rdi
  call   <memcpy@plt>
  shr    $0x3,%rbp
  mov    %rbp,0x8(%rsp)
  je     L42
  xor    %ebp,%ebp
  lea    0x18(%rsp),%r14
  lea    0x10(%rsp),%r13
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r15,%rdi
  call   <le2int@plt>
  lea    0x4(%r15),%rdi
  add    $0x8,%r15
  mov    %rax,0x10(%rsp)
  call   <le2int@plt>
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,0x18(%rsp)
  call   <tea_decrypt@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <int2le@plt>
  mov    0x18(%rsp),%rdi
  lea    0x4(%rbx),%rsi
  add    $0x8,%rbx
  call   <int2le@plt>
  addq   $0x1,0x20(%rsp)
  jne    L2
  addq   $0x1,0x28(%rsp)
  jne    L2
  addq   $0x1,0x30(%rsp)
  jne    L2
  addq   $0x1,0x38(%rsp)
  nopw   0x0(%rax,%rax,1)
L2:
  lea    0x1(%rbp),%eax
  mov    %rax,%rbp
  cmp    0x8(%rsp),%rax
  jb     L1
L42:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decrypt_buf(const unsigned char *src, unsigned char *dest, size_t n, const uint32_t *initial_key) {
  uint32_t v0, v1;
  unsigned int i;
  uint32_t key[4];
  memcpy(key, initial_key, sizeof(key));
  for (i = 0; i < (n / 8); i++) {
    v0 = le2int(src);
    v1 = le2int(src + 4);
    tea_decrypt(&v0, &v1, key);
    int2le(v0, dest);
    int2le(v1, dest + 4);
    src += 8;
    dest += 8;
    key[0]++;
    if (key[0] == 0) {
      key[1]++;
      if (key[1] == 0) {
        key[2]++;
        if (key[2] == 0) {
          key[3]++;
        }
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GPMCPrefetchCountValGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1f0,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x3fff,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int GPMCPrefetchCountValGet(unsigned int baseAddr) {
  unsigned int cntVal;
  cntVal = ((*((volatile unsigned int *)(baseAddr + (0x1F0)))) & (0x00003FFFu));
  return (cntVal);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<GPMCPrefetchCountValGet>:
  endbr64
  mov    0x1f0(%edi),%eax
  and    $0x3fff,%eax
  ret
```

assistant: ```c
unsigned int GPMCPrefetchCountValGet(unsigned int baseAddr) {
  unsigned int cntVal;
  cntVal = ((*((volatile unsigned int *)(baseAddr + (0x1F0)))) & (0x00003FFFu));
  return (cntVal);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GPMCPrefetchCountValGet>:
  endbr64
  mov    0x1f0(%edi),%eax
  and    $0x3fff,%eax
  ret
```

assistant: ```c
unsigned int GPMCPrefetchCountValGet(unsigned int baseAddr) {
  unsigned int cntVal;
  cntVal = ((*((volatile unsigned int *)(baseAddr + (0x1F0)))) & (0x00003FFFu));
  return (cntVal);
}
```
user: Translate the below assembly code into C programming language:

```asm
<GPMCPrefetchCountValGet>:
  endbr64
  mov    0x1f0(%edi),%eax
  and    $0x3fff,%eax
  ret
```

assistant: ```c
unsigned int GPMCPrefetchCountValGet(unsigned int baseAddr) {
  unsigned int cntVal;
  cntVal = ((*((volatile unsigned int *)(baseAddr + (0x1F0)))) & (0x00003FFFu));
  return (cntVal);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L24
  cmpl   $0x2,-0x4(%rbp)
  jg     L69
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  cmpl   $0x1,-0x4(%rbp)
  je     L6
  jmp    L69
L24:
  nop
  jmp    L40
L69:
  nop
  jmp    L40
L11:
  nop
  jmp    L40
L6:
  nop
L40:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rk29_sdmmc_gpio_open>:
  endbr64
  ret
```

assistant: ```c
void rk29_sdmmc_gpio_open(int device_id, int on) {
  switch (device_id) {
  case 0: {
  } break;
  case 1: {
  } break;
  case 2:
    break;
  default:
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__fcntl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %esi,-0xb8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  cmpl   $0x0,-0xb4(%rbp)
  jns    L17
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L17:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

assistant: ```c
int __fcntl(int fd, int cmd, ...) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__fcntl>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L19
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
L0:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
L19:
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  jmp    L0
```

assistant: ```c
int __fcntl(int fd, int cmd, ...) {
  if (fd < 0) {
    __set_errno(EBADF);
    return -1;
  }
  __set_errno(ENOSYS);
  return -1;
}
```