ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<get_text_file_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%r14
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    $0x0,%ebx
  lea    D2(%rip),%r15
  jmp    L5
L35:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebp
  jmp    L18
L40:
  lea    0x0(,%rbx,8),%esi
  mov    (%r12),%rdi
  call   <realloc@plt>
  mov    %rax,(%r12)
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <wcslen@plt>
  lea    0x1(%rax),%ebp
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  lea    0x0(,%rbx,8),%rax
  mov    (%r12),%rdx
  mov    %rcx,-0x8(%rdx,%rax,1)
  mov    (%r12),%rdx
  mov    -0x8(%rdx,%rax,1),%rdi
  mov    %ebp,%edx
  mov    %r13,%rsi
  call   <wcsncpy@plt>
L5:
  mov    %ebx,%ebp
  mov    %rsp,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <fscanf@plt>
  add    $0x1,%rbx
  cmp    $0x1,%eax
  je     L40
  add    $0x1,%ebp
  movslq %ebp,%rbx
  lea    0x0(,%rbp,8),%esi
  mov    (%r12),%rdi
  call   <realloc@plt>
  mov    %rax,(%r12)
  movq   $0x0,-0x8(%rax,%rbx,8)
  mov    %r14,%rdi
  call   <fclose@plt>
L18:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    %ebp,%eax
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D12: r

tool: D2: %l[^
]


tool: D0: Arquivo nao encontrado


assistant: ```c
int get_text_file_info(char *file_path, wchar_t ***texts_or_querys) {
  FILE *fp;
  wchar_t buffer[500];
  int line_counter, line_length;
  fp = fopen(file_path, "r");
  if (fp == NULL) {
    printf("Arquivo nao encontrado\n");
    return 0;
  }
  line_counter = 0;
  *texts_or_querys = (wchar_t **)malloc(0);
  while (fscanf(fp, "%l[^\n]\n", buffer) == 1) {
    line_counter++;
    *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t *) * line_counter);
    line_length = wcslen(buffer);
    (*texts_or_querys)[line_counter - 1] = (wchar_t *)malloc(sizeof(wchar_t) * (line_length + 1));
    wcsncpy((*texts_or_querys)[line_counter - 1], buffer, line_length + 1);
  }
  line_counter++;
  *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t **) * line_counter);
  (*texts_or_querys)[line_counter - 1] = NULL;
  fclose(fp);
  return line_counter;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_text_file_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D17(%rip),%rsi
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L35
  xor    %edi,%edi
  mov    %rax,%r14
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  call   <malloc@plt>
  lea    0x10(%rsp),%r13
  lea    D3(%rip),%r15
  mov    %rax,(%rbx)
  jmp    L15
L39:
  call   <realloc@plt>
  mov    %r13,%rdi
  mov    %rax,(%rbx)
  call   <wcslen@plt>
  lea    0x1(%rax),%edx
  lea    0x0(,%rdx,4),%edi
  mov    %edx,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    (%rbx),%rax
  mov    %rdi,(%rax,%rbp,1)
  call   <wcsncpy@plt>
  mov    (%rsp),%rbp
L15:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %r13,%rdx
  add    $0x1,%r12d
  call   <fscanf@plt>
  lea    0x8(%rbp),%rcx
  mov    (%rbx),%rdi
  lea    0x0(,%r12,8),%esi
  mov    %rcx,(%rsp)
  cmp    $0x1,%eax
  je     L39
  call   <realloc@plt>
  mov    %r14,%rdi
  mov    %rax,(%rbx)
  movq   $0x0,(%rax,%rbp,1)
  call   <fclose@plt>
L6:
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x7f8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  lea    D6(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L6
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D17: r

tool: D3: %l[^
]


tool: D6: Arquivo nao encontrado


assistant: ```c
int get_text_file_info(char *file_path, wchar_t ***texts_or_querys) {
  FILE *fp;
  wchar_t buffer[500];
  int line_counter, line_length;
  fp = fopen(file_path, "r");
  if (fp == NULL) {
    printf("Arquivo nao encontrado\n");
    return 0;
  }
  line_counter = 0;
  *texts_or_querys = (wchar_t **)malloc(0);
  while (fscanf(fp, "%l[^\n]\n", buffer) == 1) {
    line_counter++;
    *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t *) * line_counter);
    line_length = wcslen(buffer);
    (*texts_or_querys)[line_counter - 1] = (wchar_t *)malloc(sizeof(wchar_t) * (line_length + 1));
    wcsncpy((*texts_or_querys)[line_counter - 1], buffer, line_length + 1);
  }
  line_counter++;
  *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t **) * line_counter);
  (*texts_or_querys)[line_counter - 1] = NULL;
  fclose(fp);
  return line_counter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_text_file_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L28
  xor    %edi,%edi
  mov    %rax,%r14
  xor    %ebp,%ebp
  xor    %r12d,%r12d
  call   <malloc@plt>
  lea    0x10(%rsp),%r13
  lea    D27(%rip),%r15
  mov    %rax,(%rbx)
  jmp    L1
L3:
  call   <realloc@plt>
  mov    %r13,%rdi
  mov    %rax,(%rbx)
  call   <wcslen@plt>
  lea    0x1(%rax),%edx
  lea    0x0(,%rdx,4),%edi
  mov    %edx,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    (%rbx),%rax
  mov    %rdi,(%rax,%rbp,1)
  call   <wcsncpy@plt>
  mov    (%rsp),%rbp
L1:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    %r13,%rdx
  add    $0x1,%r12d
  call   <fscanf@plt>
  lea    0x8(%rbp),%rcx
  mov    (%rbx),%rdi
  lea    0x0(,%r12,8),%esi
  mov    %rcx,(%rsp)
  cmp    $0x1,%eax
  je     L3
  call   <realloc@plt>
  mov    %r14,%rdi
  mov    %rax,(%rbx)
  movq   $0x0,(%rax,%rbp,1)
  call   <fclose@plt>
L4:
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x7f8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  lea    D24(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L4
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D0: r

tool: D27: %l[^
]


tool: D24: Arquivo nao encontrado


assistant: ```c
int get_text_file_info(char *file_path, wchar_t ***texts_or_querys) {
  FILE *fp;
  wchar_t buffer[500];
  int line_counter, line_length;
  fp = fopen(file_path, "r");
  if (fp == NULL) {
    printf("Arquivo nao encontrado\n");
    return 0;
  }
  line_counter = 0;
  *texts_or_querys = (wchar_t **)malloc(0);
  while (fscanf(fp, "%l[^\n]\n", buffer) == 1) {
    line_counter++;
    *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t *) * line_counter);
    line_length = wcslen(buffer);
    (*texts_or_querys)[line_counter - 1] = (wchar_t *)malloc(sizeof(wchar_t) * (line_length + 1));
    wcsncpy((*texts_or_querys)[line_counter - 1], buffer, line_length + 1);
  }
  line_counter++;
  *texts_or_querys = (wchar_t **)realloc(*texts_or_querys, sizeof(wchar_t **) * line_counter);
  (*texts_or_querys)[line_counter - 1] = NULL;
  fclose(fp);
  return line_counter;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<modifica>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x61,%al
  jne    L3
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x62,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int modifica(char frase[]) {
  int i;
  int contador = 0;
  for (i = 0; frase[i] != '\0'; i++) {
    if (frase[i] == 'a') {
      frase[i] = 'b';
      contador++;
    }
  }
  puts(frase);
  return contador;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<modifica>:
  endbr64
  push   %rbx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L27
  mov    %rdi,%rax
  mov    $0x0,%ebx
  jmp    L2
L47:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L45
L2:
  cmp    $0x61,%dl
  jne    L47
  movb   $0x62,(%rax)
  add    $0x1,%ebx
  jmp    L47
L27:
  mov    $0x0,%ebx
L45:
  call   <puts@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int modifica(char frase[]) {
  int i;
  int contador = 0;
  for (i = 0; frase[i] != '\0'; i++) {
    if (frase[i] == 'a') {
      frase[i] = 'b';
      contador++;
    }
  }
  puts(frase);
  return contador;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<modifica>:
  endbr64
  movzbl (%rdi),%edx
  push   %r12
  test   %dl,%dl
  je     L24
  mov    %rdi,%rax
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L27:
  cmp    $0x61,%dl
  jne    L13
  movb   $0x62,(%rax)
  add    $0x1,%r12d
L13:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L27
  call   <puts@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  call   <puts@plt>
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int modifica(char frase[]) {
  int i;
  int contador = 0;
  for (i = 0; frase[i] != '\0'; i++) {
    if (frase[i] == 'a') {
      frase[i] = 'b';
      contador++;
    }
  }
  puts(frase);
  return contador;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<modifica>:
  endbr64
  movzbl (%rdi),%edx
  push   %r12
  test   %dl,%dl
  je     L14
  mov    %rdi,%rax
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L27:
  cmp    $0x61,%dl
  je     L39
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L27
  call   <puts@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  movb   $0x62,(%rax)
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  add    $0x1,%r12d
  test   %dl,%dl
  jne    L27
  call   <puts@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  call   <puts@plt>
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int modifica(char frase[]) {
  int i;
  int contador = 0;
  for (i = 0; frase[i] != '\0'; i++) {
    if (frase[i] == 'a') {
      frase[i] = 'b';
      contador++;
    }
  }
  puts(frase);
  return contador;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VIM_MARB_ReadBuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  jmp    L18
L14:
  mov    -0x30(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <VIM_HIF_ReadSram@plt>
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jne    L7
  mov    -0x28(%rbp),%rax
  jmp    L22
L7:
  mov    -0x38(%rbp),%rax
L22:
  mov    %rax,-0x38(%rbp)
L18:
  cmpq   $0x0,-0x20(%rbp)
  jne    L14
  mov    -0x38(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long VIM_MARB_ReadBuf(unsigned char *pbuf, unsigned long len, unsigned long start, unsigned long end, unsigned long pos) {
  unsigned long size, len1;
  while (len) {
    size = end - pos;
    len1 = (len > size) ? size : len;
    VIM_HIF_ReadSram(pos, pbuf, len1);
    pbuf += len1;
    len -= len1;
    pos += len1;
    pos = (pos == end) ? start : pos;
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VIM_MARB_ReadBuf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%r15
  mov    %rcx,%r14
  mov    %r8,%rbp
  test   %rsi,%rsi
  je     L7
L16:
  mov    %r14,%rbx
  sub    %rbp,%rbx
  cmp    %r12,%rbx
  cmova  %r12,%rbx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <VIM_HIF_ReadSram@plt>
  add    %rbx,%r13
  add    %rbx,%rbp
  cmp    %rbp,%r14
  cmove  %r15,%rbp
  sub    %rbx,%r12
  jne    L16
L7:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long VIM_MARB_ReadBuf(unsigned char *pbuf, unsigned long len, unsigned long start, unsigned long end, unsigned long pos) {
  unsigned long size, len1;
  while (len) {
    size = end - pos;
    len1 = (len > size) ? size : len;
    VIM_HIF_ReadSram(pos, pbuf, len1);
    pbuf += len1;
    len -= len1;
    pos += len1;
    pos = (pos == end) ? start : pos;
  }
  return pos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VIM_MARB_ReadBuf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L9
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%rbp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  sub    %r12,%rbx
  cmp    %r14,%rbx
  cmova  %r14,%rbx
  add    %rbx,%r12
  mov    %rbx,%rdx
  add    %rbx,%r15
  call   <VIM_HIF_ReadSram@plt>
  cmp    %r12,%rbp
  cmove  %r13,%r12
  sub    %rbx,%r14
  jne    L2
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long VIM_MARB_ReadBuf(unsigned char *pbuf, unsigned long len, unsigned long start, unsigned long end, unsigned long pos) {
  unsigned long size, len1;
  while (len) {
    size = end - pos;
    len1 = (len > size) ? size : len;
    VIM_HIF_ReadSram(pos, pbuf, len1);
    pbuf += len1;
    len -= len1;
    pos += len1;
    pos = (pos == end) ? start : pos;
  }
  return pos;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VIM_MARB_ReadBuf>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L21
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rbx
  mov    %r15,%rsi
  mov    %r12,%rdi
  sub    %r12,%rbx
  cmp    %r14,%rbx
  cmova  %r14,%rbx
  mov    %rbx,%rdx
  add    %rbx,%r12
  add    %rbx,%r15
  sub    %rbx,%r14
  call   <VIM_HIF_ReadSram@plt>
  cmp    %r12,%rbp
  jne    L20
  mov    %r13,%r12
L20:
  test   %r14,%r14
  jne    L1
L21:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned long VIM_MARB_ReadBuf(unsigned char *pbuf, unsigned long len, unsigned long start, unsigned long end, unsigned long pos) {
  unsigned long size, len1;
  while (len) {
    size = end - pos;
    len1 = (len > size) ? size : len;
    VIM_HIF_ReadSram(pos, pbuf, len1);
    pbuf += len1;
    len -= len1;
    pos += len1;
    pos = (pos == end) ? start : pos;
  }
  return pos;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decode_block0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  sarl   $0x3,-0x1c(%rbp)
  jmp    L20
L12:
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x7,-0x8(%rbp)
  jle    L4
  addq   $0x8,-0x18(%rbp)
  addq   $0x8,-0x28(%rbp)
  subl   $0x1,-0x1c(%rbp)
L20:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int decode_block0(unsigned char *in, int length, unsigned char *out) {
  int ret_len = length;
  length >>= 3;
  while (length != 0) {
    int i;
    for (i = 0; i < 8; i++) {
      out[i] = in[i];
    }
    in += 8;
    out += 8;
    length--;
  }
  return ret_len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<decode_block0>:
  endbr64
  mov    %esi,%eax
  sar    $0x3,%eax
  je     L18
  lea    -0x1(%rax),%eax
  lea    0x8(%rdi,%rax,8),%r8
  jmp    L15
L14:
  add    $0x8,%rdi
  add    $0x8,%rdx
  cmp    %r8,%rdi
  je     L18
L15:
  mov    $0x0,%eax
L6:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L6
  jmp    L14
L18:
  mov    %esi,%eax
  ret
```

assistant: ```c
int decode_block0(unsigned char *in, int length, unsigned char *out) {
  int ret_len = length;
  length >>= 3;
  while (length != 0) {
    int i;
    for (i = 0; i < 8; i++) {
      out[i] = in[i];
    }
    in += 8;
    out += 8;
    length--;
  }
  return ret_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_block0>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%r9d
  sar    $0x3,%eax
  je     L24
  mov    %eax,%eax
  lea    (%rdi,%rax,8),%r8
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  movzbl (%rdi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L10
  add    $0x8,%rdi
  add    $0x8,%rdx
  cmp    %r8,%rdi
  jne    L16
L24:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int decode_block0(unsigned char *in, int length, unsigned char *out) {
  int ret_len = length;
  length >>= 3;
  while (length != 0) {
    int i;
    for (i = 0; i < 8; i++) {
      out[i] = in[i];
    }
    in += 8;
    out += 8;
    length--;
  }
  return ret_len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode_block0>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%edi
  mov    %esi,%r8d
  mov    %rdx,%rax
  sar    $0x3,%edi
  je     L60
  lea    0xf(%rcx),%rdx
  sub    %rax,%rdx
  cmp    $0x1e,%rdx
  jbe    L21
  cmp    $0x1,%edi
  je     L41
  mov    %edi,%esi
  xor    %edx,%edx
  shr    %esi
  shl    $0x4,%rsi
  nopl   0x0(%rax)
L53:
  movdqu (%rcx,%rdx,1),%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rsi
  jne    L53
  mov    %edi,%edx
  and    $0xfffffffe,%edx
  and    $0x1,%edi
  je     L60
L64:
  mov    (%rcx,%rdx,8),%rcx
  mov    %rcx,(%rax,%rdx,8)
L60:
  mov    %r8d,%eax
  ret
L21:
  mov    %edi,%edi
  lea    (%rax,%rdi,8),%rsi
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl (%rcx),%edx
  add    $0x8,%rax
  add    $0x8,%rcx
  mov    %dl,-0x8(%rax)
  movzbl -0x7(%rcx),%edx
  mov    %dl,-0x7(%rax)
  movzbl -0x6(%rcx),%edx
  mov    %dl,-0x6(%rax)
  movzbl -0x5(%rcx),%edx
  mov    %dl,-0x5(%rax)
  movzbl -0x4(%rcx),%edx
  mov    %dl,-0x4(%rax)
  movzbl -0x3(%rcx),%edx
  mov    %dl,-0x3(%rax)
  movzbl -0x2(%rcx),%edx
  mov    %dl,-0x2(%rax)
  movzbl -0x1(%rcx),%edx
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L18
  mov    %r8d,%eax
  ret
L41:
  xor    %edx,%edx
  jmp    L64
```

assistant: ```c
int decode_block0(unsigned char *in, int length, unsigned char *out) {
  int ret_len = length;
  length >>= 3;
  while (length != 0) {
    int i;
    for (i = 0; i < 8; i++) {
      out[i] = in[i];
    }
    in += 8;
    out += 8;
    length--;
  }
  return ret_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isIsomorphic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movq   $0x0,-0xd0(%rbp)
  movq   $0x0,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L27
L39:
  mov    -0x128(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x128(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x112(%rbp)
  mov    -0x130(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x130(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x111(%rbp)
  movsbl -0x112(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L43
  movsbl -0x111(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L43
  movsbl -0x112(%rbp),%eax
  cltq
  movzbl -0x111(%rbp),%edx
  mov    %dl,-0x110(%rbp,%rax,1)
  movsbl -0x111(%rbp),%eax
  cltq
  movzbl -0x112(%rbp),%edx
  mov    %dl,-0x90(%rbp,%rax,1)
  jmp    L27
L43:
  movsbl -0x112(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    %al,-0x111(%rbp)
  jne    L23
  movsbl -0x111(%rbp),%eax
  cltq
  movzbl -0x90(%rbp,%rax,1),%eax
  cmp    %al,-0x112(%rbp)
  je     L27
L23:
  mov    $0x0,%eax
  jmp    L22
L27:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    $0x1,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
bool isIsomorphic(char *s, char *t) {
  char ss[128] = {0}, tt[128] = {0};
  while (*s) {
    char a = *s++, b = *t++;
    if (ss[a] == 0 && tt[b] == 0) {
      ss[a] = b;
      tt[b] = a;
      continue;
    }
    if (ss[a] != b || tt[b] != a)
      return false;
  }
  return true;
}
```