ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ax25_setsockopt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0xffffffea,%eax
  cmp    $0x3,%r8d
  jbe    L12
  cmp    $0x19,%edx
  je     L32
L2:
  mov    $0xffffffa4,%eax
L12:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  ret
L32:
  mov    $0x10,%eax
  mov    %rsp,%rdi
  mov    %rcx,%rsi
  cmp    %eax,%r8d
  cmovle %r8d,%eax
  mov    %eax,%edx
  call   <copy_from_user@plt>
  mov    %eax,%r8d
  mov    $0xfffffff2,%eax
  test   %r8d,%r8d
  jne    L12
  jmp    L2
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ax25_setsockopt(struct socket *sock, int level, int optname, char *optval, int optlen) {
  char devname[16];
  int res = 0;
  if (optlen < sizeof(int))
    return -22;
  switch (optname) {
  case 25:
    if (optlen > 16)
      optlen = 16;
    if (copy_from_user(devname, optval, optlen)) {
      res = -14;
      break;
    }
  default:
    res = -92;
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ybp_dispose_binlog_parser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void ybp_dispose_binlog_parser(struct ybp_binlog_parser *p) {
  if (p != NULL)
    free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ybp_dispose_binlog_parser>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void ybp_dispose_binlog_parser(struct ybp_binlog_parser *p) {
  if (p != NULL)
    free(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<ybp_dispose_binlog_parser>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void ybp_dispose_binlog_parser(struct ybp_binlog_parser *p) {
  if (p != NULL)
    free(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ybp_dispose_binlog_parser>:
  endbr64
  test   %rdi,%rdi
  je     L3
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void ybp_dispose_binlog_parser(struct ybp_binlog_parser *p) {
  if (p != NULL)
    free(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<backup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <getsockfd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L98
  mov    $0xffffffff,%eax
  jmp    L99
L98:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <sendConnect@plt>
  test   %rax,%rax
  je     L28
  mov    $0xffffffff,%eax
  jmp    L99
L28:
  cmpl   $0x4,-0x1c(%rbp)
  je     L80
  cmpl   $0x4,-0x1c(%rbp)
  jg     L56
  cmpl   $0x1,-0x1c(%rbp)
  je     L63
  cmpl   $0x2,-0x1c(%rbp)
  je     L8
  jmp    L56
L63:
  lea    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sendFile@plt>
  jmp    L99
L56:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <releasesockfd@plt>
  jmp    L99
L80:
  nop
  jmp    L99
L8:
  nop
L99:
  leave
  ret
```

assistant: ```c
int backup(char *path, int comando) {
  int sock = getsockfd();
  if (sock < 0)
    return (-1);
  if (sendConnect(sock))
    return (-1);
  switch (comando) {
  case 1:
    sendFile(sock, &path);
    return;
  case 4:
    return;
  case 2:
    return;
  }
  releasesockfd(sock);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<backup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <getsockfd@plt>
  test   %eax,%eax
  js     L23
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <sendConnect@plt>
  test   %rax,%rax
  jne    L23
  lea    -0x2(%rbp),%eax
  test   $0xfffffffd,%eax
  je     L29
  cmp    $0x1,%ebp
  je     L45
  mov    %ebx,%edi
  call   <releasesockfd@plt>
  jmp    L29
L45:
  lea    0x8(%rsp),%rsi
  mov    %ebx,%edi
  call   <sendFile@plt>
  jmp    L29
L23:
  mov    $0xffffffff,%eax
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int backup(char *path, int comando) {
  int sock = getsockfd();
  if (sock < 0)
    return (-1);
  if (sendConnect(sock))
    return (-1);
  switch (comando) {
  case 1:
    sendFile(sock, &path);
    return;
  case 4:
    return;
  case 2:
    return;
  }
  releasesockfd(sock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<backup>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <getsockfd@plt>
  test   %eax,%eax
  js     L0
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <sendConnect@plt>
  test   %rax,%rax
  jne    L0
  lea    -0x2(%rbx),%eax
  and    $0xfffffffd,%eax
  je     L34
  cmp    $0x1,%ebx
  je     L24
  mov    %ebp,%edi
  call   <releasesockfd@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L0:
  mov    $0xffffffff,%eax
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L24:
  lea    0x8(%rsp),%rsi
  mov    %ebp,%edi
  call   <sendFile@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int backup(char *path, int comando) {
  int sock = getsockfd();
  if (sock < 0)
    return (-1);
  if (sendConnect(sock))
    return (-1);
  switch (comando) {
  case 1:
    sendFile(sock, &path);
    return;
  case 4:
    return;
  case 2:
    return;
  }
  releasesockfd(sock);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<backup>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <getsockfd@plt>
  test   %eax,%eax
  js     L20
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <sendConnect@plt>
  test   %rax,%rax
  jne    L20
  lea    -0x2(%rbx),%eax
  and    $0xfffffffd,%eax
  je     L25
  cmp    $0x1,%ebx
  je     L14
  mov    %ebp,%edi
  call   <releasesockfd@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  mov    $0xffffffff,%eax
L25:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  lea    0x8(%rsp),%rsi
  mov    %ebp,%edi
  call   <sendFile@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int backup(char *path, int comando) {
  int sock = getsockfd();
  if (sock < 0)
    return (-1);
  if (sendConnect(sock))
    return (-1);
  switch (comando) {
  case 1:
    sendFile(sock, &path);
    return;
  case 4:
    return;
  case 2:
    return;
  }
  releasesockfd(sock);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_check_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <ft_strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcpy@plt>
  mov    $0x1,%eax
  jmp    L7
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strclr@plt>
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int ft_check_line(char *buff) {
  char *str;
  if ((str = ft_strchr(buff, '\n'))) {
    ft_strcpy(buff, (str + 1));
    return (1);
  }
  ft_strclr(buff);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_check_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <ft_strchr@plt>
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%rsi
  mov    %rbx,%rdi
  call   <ft_strcpy@plt>
  mov    $0x1,%eax
L5:
  pop    %rbx
  ret
L0:
  mov    %rbx,%rdi
  call   <ft_strclr@plt>
  mov    $0x0,%eax
  jmp    L5
```

assistant: ```c
int ft_check_line(char *buff) {
  char *str;
  if ((str = ft_strchr(buff, '\n'))) {
    ft_strcpy(buff, (str + 1));
    return (1);
  }
  ft_strclr(buff);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_check_line>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <ft_strchr@plt>
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  call   <ft_strcpy@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rdi
  call   <ft_strclr@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_check_line(char *buff) {
  char *str;
  if ((str = ft_strchr(buff, '\n'))) {
    ft_strcpy(buff, (str + 1));
    return (1);
  }
  ft_strclr(buff);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_check_line>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <ft_strchr@plt>
  test   %rax,%rax
  je     L8
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  call   <ft_strcpy@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <ft_strclr@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_check_line(char *buff) {
  char *str;
  if ((str = ft_strchr(buff, '\n'))) {
    ft_strcpy(buff, (str + 1));
    return (1);
  }
  ft_strclr(buff);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__arch_adjust_zones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  sub    $0x400,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  movq   $0x400,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L14
L13:
  nop
L14:
  pop    %rbp
  ret
```

assistant: ```c
void __arch_adjust_zones(int node, unsigned long *zone_size, unsigned long *zhole_size) {
  if (node != 0)
    return;
  zone_size[1] = zone_size[0] - 1024;
  zone_size[0] = 1024;
  zhole_size[1] = zhole_size[0];
  zhole_size[0] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__arch_adjust_zones>:
  endbr64
  test   %edi,%edi
  jne    L0
  mov    (%rsi),%rax
  sub    $0x400,%rax
  mov    %rax,0x8(%rsi)
  movq   $0x400,(%rsi)
  mov    (%rdx),%rax
  mov    %rax,0x8(%rdx)
  movq   $0x0,(%rdx)
L0:
  ret
```

assistant: ```c
void __arch_adjust_zones(int node, unsigned long *zone_size, unsigned long *zhole_size) {
  if (node != 0)
    return;
  zone_size[1] = zone_size[0] - 1024;
  zone_size[0] = 1024;
  zhole_size[1] = zhole_size[0];
  zhole_size[0] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__arch_adjust_zones>:
  endbr64
  test   %edi,%edi
  jne    L2
  mov    (%rsi),%rax
  movq   $0x400,(%rsi)
  sub    $0x400,%rax
  mov    %rax,0x8(%rsi)
  mov    (%rdx),%rax
  movq   $0x0,(%rdx)
  mov    %rax,0x8(%rdx)
L2:
  ret
```

assistant: ```c
void __arch_adjust_zones(int node, unsigned long *zone_size, unsigned long *zhole_size) {
  if (node != 0)
    return;
  zone_size[1] = zone_size[0] - 1024;
  zone_size[0] = 1024;
  zhole_size[1] = zhole_size[0];
  zhole_size[0] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__arch_adjust_zones>:
  endbr64
  test   %edi,%edi
  jne    L3
  mov    (%rsi),%rax
  movq   $0x400,(%rsi)
  sub    $0x400,%rax
  mov    %rax,0x8(%rsi)
  mov    (%rdx),%rax
  movq   $0x0,(%rdx)
  mov    %rax,0x8(%rdx)
L3:
  ret
```

assistant: ```c
void __arch_adjust_zones(int node, unsigned long *zone_size, unsigned long *zhole_size) {
  if (node != 0)
    return;
  zone_size[1] = zone_size[0] - 1024;
  zone_size[0] = 1024;
  zhole_size[1] = zhole_size[0];
  zhole_size[0] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dsrib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L33:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dsii@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  jmp    L39
L2:
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x2,-0x4(%rbp)
  jle    L33
  mov    $0x1,%eax
L39:
  leave
  ret
```

assistant: ```c
int dsrib(double rect[3][2], double bounds[3][2]) {
  int k;
  for (k = 0; k < 3; k++)
    if (!dsii(rect[k], bounds[k]))
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dsrib>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L14:
  lea    0x0(%rbp,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  call   <dsii@plt>
  test   %eax,%eax
  je     L1
  add    $0x10,%rbx
  cmp    $0x30,%rbx
  jne    L14
  mov    $0x1,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dsrib(double rect[3][2], double bounds[3][2]) {
  int k;
  for (k = 0; k < 3; k++)
    if (!dsii(rect[k], bounds[k]))
      return (0);
  return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<dsrib>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L5:
  lea    0x0(%rbp,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  call   <dsii@plt>
  test   %eax,%eax
  je     L13
  add    $0x10,%rbx
  cmp    $0x30,%rbx
  jne    L5
  mov    $0x1,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dsrib(double rect[3][2], double bounds[3][2]) {
  int k;
  for (k = 0; k < 3; k++)
    if (!dsii(rect[k], bounds[k]))
      return (0);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dsrib>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L6:
  lea    0x0(%rbp,%rbx,1),%rsi
  lea    (%r12,%rbx,1),%rdi
  call   <dsii@plt>
  test   %eax,%eax
  je     L18
  add    $0x10,%rbx
  cmp    $0x30,%rbx
  jne    L6
  mov    $0x1,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dsrib(double rect[3][2], double bounds[3][2]) {
  int k;
  for (k = 0; k < 3; k++)
    if (!dsii(rect[k], bounds[k]))
      return (0);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_at_tests_callee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xa,-0x1c(%rbp)
  movl   $0xb,-0x18(%rbp)
  movl   $0xc,-0x14(%rbp)
  movl   $0x7,-0x10(%rbp)
  movl   $0xd,-0xc(%rbp)
  movl   $0xe,-0x8(%rbp)
  movl   $0xf,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_at_tests_callee>:
  endbr64
  ret
```

assistant: ```c
void do_at_tests_callee() {
  int buffer1 = 10;
  int buffer2 = 11;
  int buffer3 = 12;
  int i = 7;
  int buffer4 = 13;
  int buffer5 = 14;
  int buffer6 = 15;
  i++;
  i++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calcBrighness>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L39
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L39
  movsd  -0x8(%rbp),%xmm0
  jmp    L10
L39:
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movsd  D9(%rip),%xmm1
  movq   %rax,%xmm4
  divsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L32
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L32:
  movsd  -0x8(%rbp),%xmm0
L10:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: byte[8]

tool: {"D9": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x22,0x40]}

assistant: ```c
double calcBrighness(const double lux, const double min, const double max) {
  double result = min;
  if (lux == 0) {
    return result;
  }
  result = (max - min) * (log(lux) / log(10000)) + min;
  if (result < min) {
    result = min;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calcBrighness>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm1,%rbp
  movq   %xmm2,%rbx
  ucomisd D8(%rip),%xmm0
  jp     L23
  jne    L23
L16:
  movq   %rbp,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <log@plt>
  movq   %rbx,%xmm2
  movq   %rbp,%xmm4
  subsd  %xmm4,%xmm2
  divsd  D7(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  addsd  %xmm4,%xmm2
  movq   %rbp,%xmm3
  maxsd  %xmm2,%xmm3
  movq   %xmm3,%rbp
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D7
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D7": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x22,0x40]}

assistant: ```c
double calcBrighness(const double lux, const double min, const double max) {
  double result = min;
  if (lux == 0) {
    return result;
  }
  result = (max - min) * (log(lux) / log(10000)) + min;
  if (result < min) {
    result = min;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcBrighness>:
  endbr64
  ucomisd D7(%rip),%xmm0
  jp     L19
  jne    L19
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L19:
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  D16(%rip),%xmm0
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm1
  jbe    L15
  movapd %xmm1,%xmm0
L15:
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: byte[8]
name: unpack_data
arguments: data_label: D16
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x22,0x40]}

assistant: ```c
double calcBrighness(const double lux, const double min, const double max) {
  double result = min;
  if (lux == 0) {
    return result;
  }
  result = (max - min) * (log(lux) / log(10000)) + min;
  if (result < min) {
    result = min;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<calcBrighness>:
  endbr64
  ucomisd D1(%rip),%xmm0
  jp     L14
  jne    L14
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L14:
  sub    $0x18,%rsp
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <log@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  divsd  D16(%rip),%xmm0
  subsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm1
  jbe    L8
  movapd %xmm1,%xmm0
L8:
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: byte[8]
name: disassemble_data
arguments: tag: D16
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x16,0x55,0xb5,0xbb,0xb1,0x6b,0x22,0x40]}

assistant: ```c
double calcBrighness(const double lux, const double min, const double max) {
  double result = min;
  if (lux == 0) {
    return result;
  }
  result = (max - min) * (log(lux) / log(10000)) + min;
  if (result < min) {
    result = min;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmd_showbind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L32
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L21
L45:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L45
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <show_binding@plt>
  jmp    L15
L32:
  nop
  jmp    L46
L19:
  nop
L46:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <error_msg@plt>
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: expecting 2 arguments (context and key)


assistant: ```c
void cmd_showbind(char *arg) {
  char *key;
  key = strchr(arg, ' ');
  if (key == NULL)
    goto err;
  *key++ = 0;
  while (*key == ' ')
    key++;
  if (*key == 0)
    goto err;
  show_binding(arg, key);
  return;
err:
  error_msg("expecting 2 arguments (context and key)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cmd_showbind>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x20,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  lea    0x1(%rax),%rsi
  movb   $0x0,(%rax)
  movzbl 0x1(%rax),%eax
  cmp    $0x20,%al
  jne    L49
L38:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  cmp    $0x20,%al
  je     L38
L49:
  test   %al,%al
  jne    L13
L7:
  lea    D9(%rip),%rdi
  call   <error_msg@plt>
L11:
  pop    %rbx
  ret
L13:
  mov    %rbx,%rdi
  call   <show_binding@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: expecting 2 arguments (context and key)


assistant: ```c
void cmd_showbind(char *arg) {
  char *key;
  key = strchr(arg, ' ');
  if (key == NULL)
    goto err;
  *key++ = 0;
  while (*key == ' ')
    key++;
  if (*key == 0)
    goto err;
  show_binding(arg, key);
  return;
err:
  error_msg("expecting 2 arguments (context and key)\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_showbind>:
  endbr64
  push   %rbp
  mov    $0x20,%esi
  mov    %rdi,%rbp
  call   <strchr@plt>
  test   %rax,%rax
  je     L12
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rsi
  movzbl 0x1(%rax),%eax
  cmp    $0x20,%al
  jne    L39
  cs nopw 0x0(%rax,%rax,1)
L20:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  cmp    $0x20,%al
  je     L20
L39:
  test   %al,%al
  jne    L0
L12:
  lea    D0(%rip),%rdi
  pop    %rbp
  jmp    1070 <error_msg@plt>
  nopl   (%rax)
L0:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <show_binding@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: expecting 2 arguments (context and key)


assistant: ```c
void cmd_showbind(char *arg) {
  char *key;
  key = strchr(arg, ' ');
  if (key == NULL)
    goto err;
  *key++ = 0;
  while (*key == ' ')
    key++;
  if (*key == 0)
    goto err;
  show_binding(arg, key);
  return;
err:
  error_msg("expecting 2 arguments (context and key)\n");
}
```