ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<yanghui>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %edi,%edi
  jne    L61
  cmp    $0x1,%esi
  je     L49
L61:
  test   %ebx,%ebx
  je     L13
  lea    -0x1(%rbx),%edi
  mov    %ebp,%esi
  call   <yanghui>
  mov    %ebp,%esi
  sub    %ebx,%esi
  add    $0x1,%esi
  imul   %esi,%eax
  cltd
  idiv   %ebx
  mov    %eax,%r12d
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L0
L27:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    $0x1,%r12d
  jmp    L27
L13:
  lea    -0x1(%rbp),%edi
  mov    %edi,%esi
  call   <yanghui>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    $0x1,%r12d
  jmp    L27
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L27
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6:  %d

assistant: ```c
int yanghui(int m, int n) {
  int result;
  result = 1;
  if (m == 0 && n == 1) {
    printf("1");
    return result;
  } else if (m == 0) {
    yanghui(n - 1, n - 1);
    printf("1");
    return result;
  } else {
    result = yanghui(m - 1, n) * (n - m + 1) / m;
    printf(" %d", result);
  }
  if (m == n)
    putchar('\n');
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yanghui>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L27
  cmp    $0x1,%esi
  je     L36
  test   %edi,%edi
  jne    L27
  lea    -0x1(%rsi),%edi
  mov    %edi,%esi
  call   <yanghui>
L36:
  mov    $0x31,%edi
  mov    $0x1,%r12d
  call   <putchar@plt>
L17:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    -0x1(%rbx),%edi
  mov    %ebp,%esi
  call   <yanghui>
  lea    D3(%rip),%rdi
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %ebx,%eax
  add    $0x1,%eax
  imul   %r8d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%r12d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3:  %d

assistant: ```c
int yanghui(int m, int n) {
  int result;
  result = 1;
  if (m == 0 && n == 1) {
    printf("1");
    return result;
  } else if (m == 0) {
    yanghui(n - 1, n - 1);
    printf("1");
    return result;
  } else {
    result = yanghui(m - 1, n) * (n - m + 1) / m;
    printf(" %d", result);
  }
  if (m == n)
    putchar('\n');
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mmini_lzl_decompress>:
  endbr64
  mov    %rsi,%r10
  test   %rsi,%rsi
  je     L54
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rdx,%r11
  mov    %rcx,%rbx
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L52
L12:
  movzbl %dl,%edi
  add    $0x2,%rax
  cmp    %rax,%r10
  jbe    L95
  mov    %rdi,%rbp
  shl    $0x8,%rbp
  and    $0x700,%ebp
  movzbl (%r9,%rax,1),%edx
  or     %rdx,%rbp
  mov    %rcx,%rdx
  sub    %rbp,%rdx
  shr    %rdi
  and    $0x7c,%edi
  movzbl %sil,%esi
  or     %rdi,%rsi
  lea    (%rsi,%rcx,1),%rdi
  cmp    %rbx,%rdi
  ja     L47
  lea    (%rdx,%rsi,1),%r13
  cmp    %r13,%rdx
  jae    L96
  add    %r11,%rdx
  lea    (%r11,%r13,1),%r12
  mov    %rbp,%rsi
  sub    %rcx,%rsi
L72:
  movzbl (%rdx),%r8d
  lea    (%rsi,%rdx,1),%rdi
  mov    %r8b,(%rdi,%rcx,1)
  add    $0x1,%rdx
  cmp    %r12,%rdx
  jne    L72
  lea    0x0(%rbp,%r13,1),%rcx
  jmp    L96
L33:
  cmp    %rcx,%rbx
  jbe    L53
  mov    %sil,(%r11,%rcx,1)
  lea    0x1(%rcx),%rcx
L96:
  add    $0x1,%rax
  cmp    %rax,%r10
  jbe    L166
L52:
  movzbl (%r9,%rax,1),%esi
  cmp    $0x3,%sil
  ja     L33
  lea    0x1(%rax),%rdi
  cmp    %rdi,%r10
  jbe    L6
  movzbl 0x1(%r9,%rax,1),%edx
  cmp    $0x3,%dl
  ja     L12
  cmp    %rcx,%rbx
  jbe    L41
  mov    %dl,(%r11,%rcx,1)
  mov    %rdi,%rax
  lea    0x1(%rcx),%rcx
  jmp    L96
L54:
  mov    %rsi,%rax
  ret
L6:
  mov    $0x0,%ecx
L166:
  mov    %rcx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    $0x0,%ecx
  jmp    L166
L95:
  mov    $0x0,%ecx
  jmp    L166
L47:
  mov    $0x0,%ecx
  jmp    L166
L53:
  mov    $0x0,%ecx
  jmp    L166
```

assistant: ```c
unsigned long mmini_lzl_decompress(const unsigned char *in, unsigned long inlen, unsigned char *out, unsigned long outlen) {
  unsigned long outptr, i, start, len, end;
  unsigned char tmp;
  outptr = 0;
  i = 0;
  while (i < inlen) {
    if (in[i] <= 0x03) {
      tmp = in[i];
      if (++i >= inlen)
        return 0;
      if (in[i] <= 0x03) {
        if (outptr >= outlen)
          return 0;
        out[outptr++] = in[i];
      } else {
        len = (unsigned long)in[i];
        if (++i >= inlen)
          return 0;
        start = outptr - (((len & 0x07) << 8) | (unsigned long)in[i]);
        len = ((len >> 1) & 0x7c) | (unsigned long)tmp;
        if ((outptr + len) > outlen)
          return 0;
        for (end = start + len; start < end; ++start)
          out[outptr++] = out[start];
      }
    } else {
      if (outptr >= outlen)
        return 0;
      out[outptr++] = in[i];
    }
    ++i;
  }
  return outptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mmini_lzl_decompress>:
  endbr64
  test   %rsi,%rsi
  je     L183
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %rcx,%r11
  xor    %eax,%eax
  xor    %r8d,%r8d
L61:
  movzbl (%rdi,%rax,1),%ecx
  cmp    $0x3,%cl
  ja     L81
  lea    0x1(%rax),%rsi
  cmp    %rsi,%r9
  jbe    L183
  movzbl 0x1(%rdi,%rax,1),%edx
  cmp    $0x3,%dl
  ja     L85
  cmp    %r8,%r11
  jbe    L183
  mov    %dl,(%r10,%r8,1)
  mov    %rsi,%rax
  add    $0x1,%r8
  jmp    L141
L81:
  cmp    %r8,%r11
  jbe    L183
  mov    %cl,(%r10,%r8,1)
  add    $0x1,%r8
L141:
  add    $0x1,%rax
  cmp    %rax,%r9
  ja     L61
L11:
  mov    %r8,%rax
  ret
L85:
  add    $0x2,%rax
  movzbl %dl,%esi
  cmp    %rax,%r9
  jbe    L183
  push   %r14
  push   %rbp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %rsi,%rbx
  shr    %rsi
  movzbl (%rdi,%rax,1),%edx
  shl    $0x8,%rbx
  and    $0x7c,%esi
  and    $0x700,%ebx
  or     %rsi,%rcx
  or     %rdx,%rbx
  lea    (%rcx,%r8,1),%rbp
  mov    %r8,%rdx
  sub    %rbx,%rdx
  cmp    %r11,%rbp
  ja     L133
  add    %rdx,%rcx
  cmp    %rcx,%rdx
  jae    L211
  add    %r10,%rdx
  add    %r10,%rcx
  sub    %r8,%rbx
  nopl   0x0(%rax)
L214:
  movzbl (%rdx),%r14d
  lea    (%rbx,%rdx,1),%rsi
  add    $0x1,%rdx
  mov    %r14b,(%rsi,%r8,1)
  cmp    %rcx,%rdx
  jne    L214
  mov    %rbp,%r8
  nopl   0x0(%rax,%rax,1)
L211:
  add    $0x1,%rax
  cmp    %rax,%r9
  jbe    L198
L73:
  movzbl (%rdi,%rax,1),%ecx
  cmp    $0x3,%cl
  ja     L142
  lea    0x1(%rax),%rsi
  cmp    %rsi,%r9
  jbe    L133
  movzbl 0x1(%rdi,%rax,1),%edx
  cmp    $0x3,%dl
  ja     L192
  cmp    %r8,%r11
  jbe    L133
  mov    %rsi,%rax
  mov    %dl,(%r10,%r8,1)
  add    $0x1,%r8
  add    $0x1,%rax
  cmp    %rax,%r9
  ja     L73
L198:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L142:
  cmp    %r8,%r11
  jbe    L133
  mov    %cl,(%r10,%r8,1)
  add    $0x1,%r8
  jmp    L211
  nop
L192:
  add    $0x2,%rax
  movzbl %dl,%esi
  cmp    %rax,%r9
  ja     L77
L133:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r14
  ret
L183:
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
unsigned long mmini_lzl_decompress(const unsigned char *in, unsigned long inlen, unsigned char *out, unsigned long outlen) {
  unsigned long outptr, i, start, len, end;
  unsigned char tmp;
  outptr = 0;
  i = 0;
  while (i < inlen) {
    if (in[i] <= 0x03) {
      tmp = in[i];
      if (++i >= inlen)
        return 0;
      if (in[i] <= 0x03) {
        if (outptr >= outlen)
          return 0;
        out[outptr++] = in[i];
      } else {
        len = (unsigned long)in[i];
        if (++i >= inlen)
          return 0;
        start = outptr - (((len & 0x07) << 8) | (unsigned long)in[i]);
        len = ((len >> 1) & 0x7c) | (unsigned long)tmp;
        if ((outptr + len) > outlen)
          return 0;
        for (end = start + len; start < end; ++start)
          out[outptr++] = out[start];
      }
    } else {
      if (outptr >= outlen)
        return 0;
      out[outptr++] = in[i];
    }
    ++i;
  }
  return outptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LIST_indexOfFinalBracket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L42:
  cmpl   $0x0,-0xc(%rbp)
  jne    L134
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L134
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L134
  movl   $0x1,-0xc(%rbp)
  jmp    L86
L134:
  cmpl   $0x1,-0xc(%rbp)
  jne    L55
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L55
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L55
  movl   $0x0,-0xc(%rbp)
  jmp    L86
L55:
  cmpl   $0x0,-0xc(%rbp)
  jne    L86
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L13
  addl   $0x1,-0x10(%rbp)
  jmp    L86
L13:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L86
  subl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L150
  mov    -0x8(%rbp),%eax
  jmp    L74
L150:
  nop
L86:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L42
  mov    $0xffffffff,%eax
L74:
  leave
  ret
```

assistant: ```c
int LIST_indexOfFinalBracket(char *input_str, int index_of_first_bracket) {
  int count = 0;
  int in_string = 0;
  int length_of_input_str = (int)strlen(input_str);
  int i = index_of_first_bracket;
  for (; i < length_of_input_str; i++) {
    if (in_string == 0 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 1;
      continue;
    }
    if (in_string == 1 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 0;
      continue;
    }
    if (in_string == 0) {
      if (input_str[i] == '[') {
        count++;
        continue;
      }
      if (input_str[i] == ']') {
        count--;
        if (count == 0) {
          return i;
        } else {
          continue;
        }
      }
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LIST_indexOfFinalBracket>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L107
  mov    %eax,%edi
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  mov    %ebx,%eax
  mov    $0x0,%esi
  mov    $0x0,%r8d
  jmp    L89
L12:
  cmpb   $0x5c,-0x1(%rdx)
  setne  %sil
  movzbl %sil,%esi
  jmp    L23
L84:
  cmpb   $0x22,(%rdx)
  je     L31
L23:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%edi
  je     L88
L89:
  test   %esi,%esi
  jne    L84
  movzbl (%rdx),%ecx
  cmp    $0x22,%cl
  je     L12
  cmp    $0x5b,%cl
  je     L120
  cmp    $0x5d,%cl
  jne    L23
  sub    $0x1,%r8d
  jne    L23
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  cmpb   $0x5c,-0x1(%rdx)
  sete   %sil
  movzbl %sil,%esi
  jmp    L23
L120:
  add    $0x1,%r8d
  jmp    L23
L88:
  mov    $0xffffffff,%eax
  jmp    L16
L107:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int LIST_indexOfFinalBracket(char *input_str, int index_of_first_bracket) {
  int count = 0;
  int in_string = 0;
  int length_of_input_str = (int)strlen(input_str);
  int i = index_of_first_bracket;
  for (; i < length_of_input_str; i++) {
    if (in_string == 0 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 1;
      continue;
    }
    if (in_string == 1 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 0;
      continue;
    }
    if (in_string == 0) {
      if (input_str[i] == '[') {
        count++;
        continue;
      }
      if (input_str[i] == ']') {
        count--;
        if (count == 0) {
          return i;
        } else {
          continue;
        }
      }
    }
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<LIST_indexOfFinalBracket>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  cmp    %ebx,%eax
  jle    L80
L149:
  movslq %ebx,%rdx
  lea    0x1(%rbx),%eax
  add    %rbp,%rdx
  lea    -0x1(%rax),%r8d
  movzbl (%rdx),%ecx
  cmp    $0x22,%cl
  je     L140
  nopl   0x0(%rax)
L65:
  cmp    $0x5b,%cl
  je     L146
  cmp    $0x5d,%cl
  je     L138
L68:
  cmp    %eax,%esi
  jle    L80
L109:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%eax
  add    $0x1,%rdx
  lea    -0x1(%rax),%r8d
  cmp    $0x22,%cl
  jne    L65
L140:
  cmpb   $0x5c,-0x1(%rdx)
  je     L68
  cmp    %eax,%esi
  jle    L80
  cltq
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L123:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L80
L7:
  cmpb   $0x22,0x0(%rbp,%rax,1)
  mov    %eax,%edx
  jne    L123
  cmpb   $0x5c,-0x1(%rbp,%rax,1)
  je     L123
  lea    0x1(%rdx),%ebx
  cmp    %ebx,%esi
  jg     L149
L80:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L138:
  sub    $0x1,%edi
  jne    L68
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L146:
  add    $0x1,%edi
  cmp    %eax,%esi
  jg     L109
  jmp    L80
```

assistant: ```c
int LIST_indexOfFinalBracket(char *input_str, int index_of_first_bracket) {
  int count = 0;
  int in_string = 0;
  int length_of_input_str = (int)strlen(input_str);
  int i = index_of_first_bracket;
  for (; i < length_of_input_str; i++) {
    if (in_string == 0 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 1;
      continue;
    }
    if (in_string == 1 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 0;
      continue;
    }
    if (in_string == 0) {
      if (input_str[i] == '[') {
        count++;
        continue;
      }
      if (input_str[i] == ']') {
        count--;
        if (count == 0) {
          return i;
        } else {
          continue;
        }
      }
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LIST_indexOfFinalBracket>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  xor    %edi,%edi
  mov    %eax,%esi
  cmp    %ebx,%eax
  jle    L97
L158:
  movslq %ebx,%rdx
  lea    0x1(%rbx),%eax
  add    %rbp,%rdx
  lea    -0x1(%rax),%r8d
  movzbl (%rdx),%ecx
  cmp    $0x22,%cl
  je     L2
  nopl   0x0(%rax)
L121:
  cmp    $0x5b,%cl
  je     L61
  cmp    $0x5d,%cl
  je     L14
L125:
  cmp    %eax,%esi
  jle    L97
L13:
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%eax
  add    $0x1,%rdx
  lea    -0x1(%rax),%r8d
  cmp    $0x22,%cl
  jne    L121
L2:
  cmpb   $0x5c,-0x1(%rdx)
  je     L125
  cmp    %eax,%esi
  jle    L97
  cltq
  jmp    L156
  nopl   0x0(%rax,%rax,1)
L70:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L97
L156:
  cmpb   $0x22,0x0(%rbp,%rax,1)
  mov    %eax,%edx
  jne    L70
  cmpb   $0x5c,-0x1(%rbp,%rax,1)
  je     L70
  lea    0x1(%rdx),%ebx
  cmp    %ebx,%esi
  jg     L158
L97:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L14:
  sub    $0x1,%edi
  jne    L125
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nop
L61:
  add    $0x1,%edi
  cmp    %eax,%esi
  jg     L13
  jmp    L97
```

assistant: ```c
int LIST_indexOfFinalBracket(char *input_str, int index_of_first_bracket) {
  int count = 0;
  int in_string = 0;
  int length_of_input_str = (int)strlen(input_str);
  int i = index_of_first_bracket;
  for (; i < length_of_input_str; i++) {
    if (in_string == 0 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 1;
      continue;
    }
    if (in_string == 1 && input_str[i] == '"' && input_str[i - 1] != '\\') {
      in_string = 0;
      continue;
    }
    if (in_string == 0) {
      if (input_str[i] == '[') {
        count++;
        continue;
      }
      if (input_str[i] == ']') {
        count--;
        if (count == 0) {
          return i;
        } else {
          continue;
        }
      }
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exec_shell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: ls -lath

assistant: ```c
int exec_shell(void) {
  int ret;
  ret = system("ls -lath");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<exec_shell>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: ls -lath

assistant: ```c
int exec_shell(void) {
  int ret;
  ret = system("ls -lath");
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<exec_shell>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <system@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: ls -lath

assistant: ```c
int exec_shell(void) {
  int ret;
  ret = system("ls -lath");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exec_shell>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <system@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: ls -lath

assistant: ```c
int exec_shell(void) {
  int ret;
  ret = system("ls -lath");
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcRaiz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  fldt   0x20(%rbp)
  fld    %st(0)
  faddp  %st,%st(1)
  fldt   0x20(%rbp)
  fmul   %st(0),%st
  fldt   0x10(%rbp)
  fdivp  %st,%st(1)
  faddp  %st,%st(1)
  fldt   0xee2(%rip)        # 2000 <_fini+0xe90>
  fdivrp %st,%st(1)
  fstpt  -0x10(%rbp)
  fldt   0x20(%rbp)
  fldt   -0x10(%rbp)
  fsubrp %st,%st(1)
  fldt   0x30(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jb     L3
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%edx
  jmp    L2
L3:
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <calcRaiz>
  add    $0x30,%rsp
  fstpt  -0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%edx
L2:
  mov    %rax,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  fldt   -0x20(%rbp)
  leave
  ret
```

assistant: ```c
long double calcRaiz(long double num, long double x_0, long double error) {
  long double x_1 = ((2 * x_0 + (num / (x_0 * x_0)))) / 3;
  if ((x_0 - x_1) <= error)
    return x_1;
  return calcRaiz(num, x_1, error);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calcRaiz>:
  endbr64
  sub    $0x8,%rsp
  fldt   0x10(%rsp)
  fldt   0x20(%rsp)
  fldt   0x30(%rsp)
  fld    %st(1)
  fmul   %st(2),%st
  fdivr  %st(3),%st
  fld    %st(2)
  fadd   %st(3),%st
  faddp  %st,%st(1)
  fdivs  0xee1(%rip)        # 2000 <_fini+0xeb0>
  fsubr  %st,%st(2)
  fxch   %st(1)
  fcomi  %st(2),%st
  fstp   %st(2)
  jb     L12
  fstp   %st(1)
  fstp   %st(1)
L11:
  add    $0x8,%rsp
  ret
L12:
  fxch   %st(1)
  lea    -0x30(%rsp),%rsp
  fstpt  0x20(%rsp)
  fstpt  0x10(%rsp)
  fstpt  (%rsp)
  call   <calcRaiz>
  add    $0x30,%rsp
  jmp    L11
```

assistant: ```c
long double calcRaiz(long double num, long double x_0, long double error) {
  long double x_1 = ((2 * x_0 + (num / (x_0 * x_0)))) / 3;
  if ((x_0 - x_1) <= error)
    return x_1;
  return calcRaiz(num, x_1, error);
}
```
user: What is the c source code of the assembly code below:

```asm
<calcRaiz>:
  endbr64
  fldt   0x8(%rsp)
  fldt   0x18(%rsp)
  fldt   0x28(%rsp)
  flds   0xeea(%rip)        # 2000 <_fini+0xeb8>
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L14:
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
L16:
  fld    %st(2)
  fmul   %st(0),%st
  fdivr  %st(4),%st
  fld    %st(3)
  fadd   %st(4),%st
  faddp  %st,%st(1)
  fdiv   %st(1),%st
  fsubr  %st,%st(3)
  fxch   %st(2)
  fcomi  %st(3),%st
  fstp   %st(3)
  jb     L14
  fstp   %st(0)
  fstp   %st(1)
  fstp   %st(1)
  ret
```

assistant: ```c
long double calcRaiz(long double num, long double x_0, long double error) {
  long double x_1 = ((2 * x_0 + (num / (x_0 * x_0)))) / 3;
  if ((x_0 - x_1) <= error)
    return x_1;
  return calcRaiz(num, x_1, error);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calcRaiz>:
  endbr64
  fldt   0x8(%rsp)
  fldt   0x18(%rsp)
  fldt   0x28(%rsp)
  flds   0xeea(%rip)        # 2000 <_fini+0xeb8>
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L3:
  fxch   %st(1)
  fxch   %st(2)
  fxch   %st(1)
L1:
  fld    %st(2)
  fmul   %st(0),%st
  fdivr  %st(4),%st
  fld    %st(3)
  fadd   %st(4),%st
  faddp  %st,%st(1)
  fdiv   %st(1),%st
  fsubr  %st,%st(3)
  fxch   %st(2)
  fcomi  %st(3),%st
  fstp   %st(3)
  jb     L3
  fstp   %st(0)
  fstp   %st(1)
  fstp   %st(1)
  ret
```

assistant: ```c
long double calcRaiz(long double num, long double x_0, long double error) {
  long double x_1 = ((2 * x_0 + (num / (x_0 * x_0)))) / 3;
  if ((x_0 - x_1) <= error)
    return x_1;
  return calcRaiz(num, x_1, error);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dir_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%ecx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fs_path_op@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int dir_add(unsigned char *dir) {
  int retval;
  fs_path_op((void *)dir, (void *)0, (void *)&retval, 3);
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dir_add>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    $0x3,%ecx
  mov    $0x0,%esi
  call   <fs_path_op@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dir_add(unsigned char *dir) {
  int retval;
  fs_path_op((void *)dir, (void *)0, (void *)&retval, 3);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dir_add>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x3,%ecx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fs_path_op@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dir_add(unsigned char *dir) {
  int retval;
  fs_path_op((void *)dir, (void *)0, (void *)&retval, 3);
  return retval;
}
```