ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strncpy_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0xd(%rbp)
  cmpl   $0x63,-0x24(%rbp)
  jle    L10
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L10:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen_my@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L29
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  movl   $0x0,-0xc(%rbp)
  movb   $0x0,-0xd(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L83:
  cmpl   $0x62,-0xc(%rbp)
  jne    L59
  movb   $0x1,-0xd(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L78
L59:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L17
  movb   $0x1,-0xd(%rbp)
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L78
L17:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L78:
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L27
  cmpb   $0x0,-0xd(%rbp)
  je     L83
L27:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D10: Warning: number of returning symbols is more, than destination string.


tool: D15: Warning: number of returning symbols is more than same string.


assistant: ```c
void strncpy_my(char *dst, char *src, int num) {
  int i = 0;
  int len_s = 0;
  int len_d = 0;
  char exit = 0;
  if (num > 100 - 1) {
    printf("Warning: number of returning symbols is more, than destination string.\n");
  };
  len_s = strlen_my(src);
  if (num > len_s) {
    printf("Warning: number of returning symbols is more than same string.\n");
  };
  i = 0;
  exit = 0;
  for (i = 0; i < num && exit == 0; i++) {
    if (i == (100 - 2)) {
      exit = 1;
      *dst++ = *src++;
      i++;
      *dst = '\0';
    } else {
      if (i == len_s - 1) {
        exit = 1;
        *dst++ = *src++;
        i++;
        *dst = '\0';
      } else {
        *dst++ = *src++;
      };
    };
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy_my>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  cmp    $0x63,%edx
  jg     L41
  mov    %rsi,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %eax,%r12d
  jg     L44
L54:
  test   %r12d,%r12d
  jle    L5
L30:
  lea    -0x1(%r13),%esi
  add    %rbx,%rsi
  lea    0x62(%rbx),%rcx
  mov    %r12d,%eax
  add    %rbx,%rax
  jmp    L65
L41:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %r12d,%eax
  jge    L30
L44:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L66:
  movzbl 0x0(%rbp),%eax
  mov    %al,(%rbx)
  movb   $0x0,0x1(%rbx)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl -0x1(%rbp),%edx
  mov    %dl,-0x1(%rbx)
  cmp    %rax,%rbx
  je     L5
  cmp    %rbx,%rcx
  je     L66
L65:
  cmp    %rbx,%rsi
  jne    L43
  movzbl 0x0(%rbp),%eax
  mov    %al,(%rbx)
  movb   $0x0,0x1(%rbx)
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: label: D12
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string

tool: D12: Warning: number of returning symbols is more, than destination string.


tool: D14: Warning: number of returning symbols is more than same string.


assistant: ```c
void strncpy_my(char *dst, char *src, int num) {
  int i = 0;
  int len_s = 0;
  int len_d = 0;
  char exit = 0;
  if (num > 100 - 1) {
    printf("Warning: number of returning symbols is more, than destination string.\n");
  };
  len_s = strlen_my(src);
  if (num > len_s) {
    printf("Warning: number of returning symbols is more than same string.\n");
  };
  i = 0;
  exit = 0;
  for (i = 0; i < num && exit == 0; i++) {
    if (i == (100 - 2)) {
      exit = 1;
      *dst++ = *src++;
      i++;
      *dst = '\0';
    } else {
      if (i == len_s - 1) {
        exit = 1;
        *dst++ = *src++;
        i++;
        *dst = '\0';
      } else {
        *dst++ = *src++;
      };
    };
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpy_my>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x63,%edx
  jg     L71
  mov    %rsi,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %eax,%r12d
  jg     L28
L69:
  test   %r12d,%r12d
  jle    L54
L22:
  lea    -0x1(%r13),%esi
  mov    %r12d,%eax
  lea    0x62(%rbx),%rcx
  add    %rbx,%rsi
  add    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl 0x0(%rbp),%edx
  cmp    %rbx,%rsi
  je     L50
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %dl,-0x1(%rbx)
  cmp    %rax,%rbx
  je     L54
  cmp    %rbx,%rcx
  jne    L9
  movzbl 0x0(%rbp),%eax
  movb   $0x0,0x1(%rcx)
  mov    %al,(%rcx)
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %dl,(%rsi)
  movb   $0x0,0x1(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L71:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %r12d,%eax
  jge    L22
L28:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L69
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D13: Warning: number of returning symbols is more, than destination string.


tool: D6: Warning: number of returning symbols is more than same string.


assistant: ```c
void strncpy_my(char *dst, char *src, int num) {
  int i = 0;
  int len_s = 0;
  int len_d = 0;
  char exit = 0;
  if (num > 100 - 1) {
    printf("Warning: number of returning symbols is more, than destination string.\n");
  };
  len_s = strlen_my(src);
  if (num > len_s) {
    printf("Warning: number of returning symbols is more than same string.\n");
  };
  i = 0;
  exit = 0;
  for (i = 0; i < num && exit == 0; i++) {
    if (i == (100 - 2)) {
      exit = 1;
      *dst++ = *src++;
      i++;
      *dst = '\0';
    } else {
      if (i == len_s - 1) {
        exit = 1;
        *dst++ = *src++;
        i++;
        *dst = '\0';
      } else {
        *dst++ = *src++;
      };
    };
  };
}
```
user: What is the c source code of the assembly code below?

```asm
<strncpy_my>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0x63,%edx
  jg     L54
  mov    %rsi,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %eax,%r12d
  jg     L45
L71:
  test   %r12d,%r12d
  jle    L28
L39:
  lea    -0x1(%r13),%esi
  mov    %r12d,%eax
  lea    0x62(%rbx),%rcx
  add    %rbx,%rsi
  add    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L55:
  movzbl 0x0(%rbp),%edx
  cmp    %rbx,%rsi
  je     L13
  add    $0x1,%rbx
  add    $0x1,%rbp
  mov    %dl,-0x1(%rbx)
  cmp    %rax,%rbx
  je     L28
  cmp    %rbx,%rcx
  jne    L55
  movzbl 0x0(%rbp),%eax
  movb   $0x0,0x1(%rcx)
  mov    %al,(%rcx)
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %dl,(%rsi)
  movb   $0x0,0x1(%rsi)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L54:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <strlen_my@plt>
  mov    %eax,%r13d
  cmp    %r12d,%eax
  jge    L39
L45:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L71
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string
name: extract_symbolic_data
arguments: data_tag: D17
data_type: string

tool: D6: Warning: number of returning symbols is more, than destination string.


tool: D17: Warning: number of returning symbols is more than same string.


assistant: ```c
void strncpy_my(char *dst, char *src, int num) {
  int i = 0;
  int len_s = 0;
  int len_d = 0;
  char exit = 0;
  if (num > 100 - 1) {
    printf("Warning: number of returning symbols is more, than destination string.\n");
  };
  len_s = strlen_my(src);
  if (num > len_s) {
    printf("Warning: number of returning symbols is more than same string.\n");
  };
  i = 0;
  exit = 0;
  for (i = 0; i < num && exit == 0; i++) {
    if (i == (100 - 2)) {
      exit = 1;
      *dst++ = *src++;
      i++;
      *dst = '\0';
    } else {
      if (i == len_s - 1) {
        exit = 1;
        *dst++ = *src++;
        i++;
        *dst = '\0';
      } else {
        *dst++ = *src++;
      };
    };
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x18(%rbp)
  jne    L0
  movsd  -0x20(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L14
L0:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D11(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L14:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D46
type: string
name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D22
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D23
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D46: 
	---------------%s----------------



tool: D27: 			SIZE	 TIME_SEC	 gflops 


tool: D22: 			%d	%f	 %lf	


tool: D11: ---

tool: D23: 			%d	%lf 	%s	


tool: D8: 
	-----------------------------------------------------------------

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L10
  lea    D53(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L15:
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D45(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D53
type: string
name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D3
type: string
name: parse_data
arguments: tag: D45
type: string

tool: D30: 
	---------------%s----------------



tool: D0: 			SIZE	 TIME_SEC	 gflops 


tool: D53: ---

tool: D2: 			%d	%lf 	%s	


tool: D3: 
	-----------------------------------------------------------------

tool: D45: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D3(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D47(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L0
  lea    D34(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
L14:
  add    $0x18,%rsp
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    %ebp,%esi
  lea    D51(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D47
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D51
data_type: string

tool: D3: 
	---------------%s----------------



tool: D47: 			SIZE	 TIME_SEC	 gflops 


tool: D34: ---

tool: D36: 			%d	%lf 	%s	


tool: D28: 
	-----------------------------------------------------------------

tool: D51: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  lea    D24(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebx
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  je     L3
  lea    D7(%rip),%rdx
  mov    %ebp,%esi
  mov    $0x1,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
L5:
  add    $0x18,%rsp
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
  nopl   0x0(%rax)
L3:
  mov    %ebp,%esi
  lea    D51(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: label: D24
datatype: string
name: disassemble_data
arguments: label: D22
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string
name: disassemble_data
arguments: label: D42
datatype: string
name: disassemble_data
arguments: label: D51
datatype: string

tool: D24: 
	---------------%s----------------



tool: D22: 			SIZE	 TIME_SEC	 gflops 


tool: D7: ---

tool: D15: 			%d	%lf 	%s	


tool: D42: 
	-----------------------------------------------------------------

tool: D51: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-----------------------------------------------------------------");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movq   $0x13880,-0x38(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x38(%rbp),%xmm1
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x30(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x38(%rbp),%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x38(%rbp),%xmm1
  movsd  D22(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x38(%rbp),%xmm1
  movsd  D64(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: byte[8]
name: disassemble_data
arguments: tag: D22
data_type: byte[8]
name: disassemble_data
arguments: tag: D64
data_type: byte[8]
name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D61
data_type: string

tool: {"D11": [0xa4,0x70,0x3d,0x0a,0xd7,0xa3,0xe0,0x3f]}

tool: {"D22": [0xb8,0x1e,0x85,0xeb,0x51,0xb8,0xde,0x3f]}

tool: {"D64": [0x66,0x66,0x66,0x66,0x66,0x66,0xd6,0x3f]}

tool: D12: The total number of :

tool: D6: Illiterate men: %ld


tool: D61: Illiterate women: %ld


assistant: ```c
int main() {
  long int tot_pop = 80000;
  long int tot_men, tot_women;
  long int tot_lit;
  long int lit_men, lit_women;
  long int ilit_men, ilit_women;
  tot_men = .52 * tot_pop;
  tot_women = .48 * tot_pop;
  tot_lit = .48 * tot_pop;
  lit_men = .35 * tot_pop;
  ilit_men = tot_men - lit_men;
  ilit_women = tot_lit - ilit_men;
  printf("The total number of :\n");
  printf("Illiterate men: %ld\n", ilit_men);
  printf("Illiterate women: %ld\n", ilit_women);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x3520,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x60e0,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D21
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string

tool: D28: The total number of :

tool: D21: Illiterate men: %ld


tool: D11: Illiterate women: %ld


assistant: ```c
int main() {
  long int tot_pop = 80000;
  long int tot_men, tot_women;
  long int tot_lit;
  long int lit_men, lit_women;
  long int ilit_men, ilit_women;
  tot_men = .52 * tot_pop;
  tot_women = .48 * tot_pop;
  tot_lit = .48 * tot_pop;
  lit_men = .35 * tot_pop;
  ilit_men = tot_men - lit_men;
  ilit_women = tot_lit - ilit_men;
  printf("The total number of :\n");
  printf("Illiterate men: %ld\n", ilit_men);
  printf("Illiterate women: %ld\n", ilit_women);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x3520,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x60e0,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D28: The total number of :

tool: D19: Illiterate men: %ld


tool: D4: Illiterate women: %ld


assistant: ```c
int main() {
  long int tot_pop = 80000;
  long int tot_men, tot_women;
  long int tot_lit;
  long int lit_men, lit_women;
  long int ilit_men, ilit_women;
  tot_men = .52 * tot_pop;
  tot_women = .48 * tot_pop;
  tot_lit = .48 * tot_pop;
  lit_men = .35 * tot_pop;
  ilit_men = tot_men - lit_men;
  ilit_women = tot_lit - ilit_men;
  printf("The total number of :\n");
  printf("Illiterate men: %ld\n", ilit_men);
  printf("Illiterate women: %ld\n", ilit_women);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x3520,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x60e0,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D20
type: string

tool: D16: The total number of :

tool: D13: Illiterate men: %ld


tool: D20: Illiterate women: %ld


assistant: ```c
int main() {
  long int tot_pop = 80000;
  long int tot_men, tot_women;
  long int tot_lit;
  long int lit_men, lit_women;
  long int ilit_men, ilit_women;
  tot_men = .52 * tot_pop;
  tot_women = .48 * tot_pop;
  tot_lit = .48 * tot_pop;
  lit_men = .35 * tot_pop;
  ilit_men = tot_men - lit_men;
  ilit_women = tot_lit - ilit_men;
  printf("The total number of :\n");
  printf("Illiterate men: %ld\n", ilit_men);
  printf("Illiterate women: %ld\n", ilit_women);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_alnum_symbolic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jl     L14
  cmpl   $0xff,-0x14(%rbp)
  jg     L14
  mov    $0x1,%eax
  jmp    L22
L14:
  mov    $0x0,%eax
L22:
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_alnum_symbolic(int x) {
  int ret = isalnum(x);
  (void)ret;
  clang_analyzer_eval(-1 <= x && x <= 255);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_alnum_symbolic>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%edi
  cmp    $0x100,%edi
  setbe  %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_alnum_symbolic(int x) {
  int ret = isalnum(x);
  (void)ret;
  clang_analyzer_eval(-1 <= x && x <= 255);
}
```