ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  lea    D3(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <vassert@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L28:
  lea    0x1(%rbx),%rax
  cmp    %ebp,%edx
  je     L29
  mov    %rax,%rbx
L6:
  movsbl (%rbx),%edx
  test   %dl,%dl
  jne    L28
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: str == NULL

assistant: ```c
char *strchr(const char *str, int ch) {
  vassert(str != NULL, "str == NULL");
  while (*str) {
    if (*str++ == ch)
      return (char *)(str - 1);
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<event_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %ax,-0x20(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movswl -0x20(%rbp),%edx
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <event_set@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <event_base_set@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct event *event_new(struct event_base *base, int sock, short what, void (*cb)(int, short, void *), void *arg) {
  struct event *e = malloc(sizeof(struct event));
  event_set(e, sock, what, cb, arg);
  event_base_set(base, e);
  return e;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<event_new>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r14
  mov    %r8,%r15
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movswl %bp,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <event_set@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <event_base_set@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct event *event_new(struct event_base *base, int sock, short what, void (*cb)(int, short, void *), void *arg) {
  struct event *e = malloc(sizeof(struct event));
  event_set(e, sock, what, cb, arg);
  event_base_set(base, e);
  return e;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<event_new>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movswl %bx,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rax,%r12
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <event_set@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <event_base_set@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct event *event_new(struct event_base *base, int sock, short what, void (*cb)(int, short, void *), void *arg) {
  struct event *e = malloc(sizeof(struct event));
  event_set(e, sock, what, cb, arg);
  event_base_set(base, e);
  return e;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<event_new>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  movswl %bx,%edx
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rax,%r12
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <event_set@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <event_base_set@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
struct event *event_new(struct event_base *base, int sock, short what, void (*cb)(int, short, void *), void *arg) {
  struct event *e = malloc(sizeof(struct event));
  event_set(e, sock, what, cb, arg);
  event_base_set(base, e);
  return e;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashfn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
L17:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L4
  mov    -0x30(%rbp),%rax
  not    %rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  shl    $0xd,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x6,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  xor    -0x8(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x30(%rbp)
  jmp    L17
L4:
  nop
  mov    -0x30(%rbp),%rax
  shr    $0xd,%rax
  xor    %rax,-0x30(%rbp)
  andq   $0x3f,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hashfn(const char *s) {
  unsigned long y = 0UL, v, w, x, k;
  unsigned long yl, yh;
  const char *t = s;
  while (1) {
    k = (unsigned long)*(unsigned char *)(t++);
    if (!k)
      break;
    v = ~y;
    w = y << 13;
    x = v >> 6;
    y = w ^ x;
    y += k;
  }
  y ^= (y >> 13);
  y &= (64 - 1);
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashfn>:
  endbr64
  lea    0x1(%rdi),%rsi
  movzbl (%rdi),%ecx
  test   %rcx,%rcx
  je     L28
  mov    $0x0,%edx
L16:
  mov    %rdx,%rax
  shl    $0xd,%rax
  not    %rdx
  shr    $0x6,%rdx
  xor    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%ecx
  test   %rcx,%rcx
  jne    L16
L0:
  mov    %rdx,%rax
  shr    $0xd,%rax
  xor    %rdx,%rax
  and    $0x3f,%eax
  ret
L28:
  mov    %rcx,%rdx
  jmp    L0
```

assistant: ```c
unsigned long hashfn(const char *s) {
  unsigned long y = 0UL, v, w, x, k;
  unsigned long yl, yh;
  const char *t = s;
  while (1) {
    k = (unsigned long)*(unsigned char *)(t++);
    if (!k)
      break;
    v = ~y;
    w = y << 13;
    x = v >> 6;
    y = w ^ x;
    y += k;
  }
  y ^= (y >> 13);
  y &= (64 - 1);
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hashfn>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rsi
  test   %rax,%rax
  je     L1
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdx,%rcx
  not    %rdx
  add    $0x1,%rsi
  shl    $0xd,%rcx
  shr    $0x6,%rdx
  xor    %rcx,%rdx
  add    %rax,%rdx
  movzbl -0x1(%rsi),%eax
  test   %rax,%rax
  jne    L19
  mov    %rdx,%rax
  shr    $0xd,%rax
  xor    %rdx,%rax
  and    $0x3f,%eax
L1:
  ret
```

assistant: ```c
unsigned long hashfn(const char *s) {
  unsigned long y = 0UL, v, w, x, k;
  unsigned long yl, yh;
  const char *t = s;
  while (1) {
    k = (unsigned long)*(unsigned char *)(t++);
    if (!k)
      break;
    v = ~y;
    w = y << 13;
    x = v >> 6;
    y = w ^ x;
    y += k;
  }
  y ^= (y >> 13);
  y &= (64 - 1);
  return y;
}
```
user: What is the c source code of the assembly code below?

```asm
<hashfn>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rsi
  test   %rax,%rax
  je     L2
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rdx,%rcx
  not    %rdx
  add    $0x1,%rsi
  shl    $0xd,%rcx
  shr    $0x6,%rdx
  xor    %rcx,%rdx
  add    %rax,%rdx
  movzbl -0x1(%rsi),%eax
  test   %rax,%rax
  jne    L13
  mov    %rdx,%rax
  shr    $0xd,%rax
  xor    %rdx,%rax
  and    $0x3f,%eax
L2:
  ret
```

assistant: ```c
unsigned long hashfn(const char *s) {
  unsigned long y = 0UL, v, w, x, k;
  unsigned long yl, yh;
  const char *t = s;
  while (1) {
    k = (unsigned long)*(unsigned char *)(t++);
    if (!k)
      break;
    v = ~y;
    w = y << 13;
    x = v >> 6;
    y = w ^ x;
    y += k;
  }
  y ^= (y >> 13);
  y &= (64 - 1);
  return y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__confstr_chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  setb   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__glibc_unlikely@plt>
  test   %rax,%rax
  je     L2
  mov    $0x0,%eax
  call   <__chk_fail@plt>
L2:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <confstr@plt>
  leave
  ret
```

assistant: ```c
size_t __confstr_chk(int name, char *buf, size_t len, size_t buflen) {
  if (__glibc_unlikely(buflen < len))
    __chk_fail();
  return confstr(name, buf, len);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__confstr_chk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  cmp    %rdx,%rcx
  setb   %dil
  movzbl %dil,%edi
  call   <__glibc_unlikely@plt>
  test   %rax,%rax
  jne    L6
L17:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <confstr@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x0,%eax
  call   <__chk_fail@plt>
  jmp    L17
```

assistant: ```c
size_t __confstr_chk(int name, char *buf, size_t len, size_t buflen) {
  if (__glibc_unlikely(buflen < len))
    __chk_fail();
  return confstr(name, buf, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__confstr_chk>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    %rdx,%rcx
  setb   %dil
  call   <__glibc_unlikely@plt>
  test   %rax,%rax
  jne    L1
L12:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <confstr@plt>
  cs nopw 0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <__chk_fail@plt>
  jmp    L12
```

assistant: ```c
size_t __confstr_chk(int name, char *buf, size_t len, size_t buflen) {
  if (__glibc_unlikely(buflen < len))
    __chk_fail();
  return confstr(name, buf, len);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__confstr_chk>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  cmp    %rdx,%rcx
  setb   %dil
  call   <__glibc_unlikely@plt>
  test   %rax,%rax
  jne    L16
L1:
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <confstr@plt>
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <__chk_fail@plt>
  jmp    L1
```

assistant: ```c
size_t __confstr_chk(int name, char *buf, size_t len, size_t buflen) {
  if (__glibc_unlikely(buflen < len))
    __chk_fail();
  return confstr(name, buf, len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtoull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L36
L19:
  addq   $0x1,-0x28(%rbp)
L36:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L19
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L43
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L43
  movq   $0x10,-0x18(%rbp)
  addq   $0x2,-0x28(%rbp)
  jmp    L91
L43:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L62
  movq   $0x8,-0x18(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L91
L62:
  movq   $0xa,-0x18(%rbp)
L91:
  movq   $0x0,-0x10(%rbp)
  jmp    L54
L90:
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  movzbl -0x1a(%rbp),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x28(%rbp)
L54:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  movsbl -0x19(%rbp),%eax
  lea    -0x1a(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <digit_from_char@plt>
  test   %rax,%rax
  jne    L90
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L70
  call   <__stack_chk_fail@plt>
L70:
  leave
  ret
```

assistant: ```c
unsigned long long strtoull(const char *nptr) {
  char c;
  char digit;
  long base;
  unsigned long long l;
  while (*nptr == ' ') {
    nptr++;
  };
  if (nptr[0] == '0' && nptr[1] == 'x') {
    base = 16;
    nptr += 2;
  } else if (nptr[0] == '0') {
    base = 8;
    nptr += 1;
  } else {
    base = 10;
  }
  l = 0;
  while (digit_from_char(c = *nptr, base, &digit)) {
    l = l * base + digit;
    nptr++;
  }
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtoull>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L59
L62:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L62
L59:
  mov    $0xa,%r12d
  cmp    $0x30,%al
  je     L38
L76:
  mov    $0x0,%ebp
  lea    0x7(%rsp),%r13
  jmp    L15
L38:
  cmpb   $0x78,0x1(%rbx)
  je     L51
  add    $0x1,%rbx
  mov    $0x8,%r12d
  jmp    L76
L51:
  add    $0x2,%rbx
  mov    $0x10,%r12d
  jmp    L76
L47:
  imul   %r12,%rbp
  movsbq 0x7(%rsp),%rax
  add    %rax,%rbp
  add    $0x1,%rbx
L15:
  movsbl (%rbx),%edi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <digit_from_char@plt>
  test   %rax,%rax
  jne    L47
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long strtoull(const char *nptr) {
  char c;
  char digit;
  long base;
  unsigned long long l;
  while (*nptr == ' ') {
    nptr++;
  };
  if (nptr[0] == '0' && nptr[1] == 'x') {
    base = 16;
    nptr += 2;
  } else if (nptr[0] == '0') {
    base = 8;
    nptr += 1;
  } else {
    base = 10;
  }
  l = 0;
  while (digit_from_char(c = *nptr, base, &digit)) {
    l = l * base + digit;
    nptr++;
  }
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<strtoull>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L6
  nopl   0x0(%rax,%rax,1)
L25:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L25
L6:
  cmp    $0x30,%al
  je     L75
  movsbl (%rbx),%edi
  mov    $0xa,%ebp
L33:
  xor    %r12d,%r12d
  lea    0x7(%rsp),%r13
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L34:
  imul   %rbp,%r12
  movsbq 0x7(%rsp),%rax
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    %rax,%r12
L78:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  call   <digit_from_char@plt>
  test   %rax,%rax
  jne    L34
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  movsbl 0x1(%rbx),%edi
  cmp    $0x78,%dil
  je     L45
  add    $0x1,%rbx
  mov    $0x8,%ebp
  jmp    L33
  nopl   (%rax)
L45:
  movsbl 0x2(%rbx),%edi
  mov    $0x10,%ebp
  add    $0x2,%rbx
  jmp    L33
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long strtoull(const char *nptr) {
  char c;
  char digit;
  long base;
  unsigned long long l;
  while (*nptr == ' ') {
    nptr++;
  };
  if (nptr[0] == '0' && nptr[1] == 'x') {
    base = 16;
    nptr += 2;
  } else if (nptr[0] == '0') {
    base = 8;
    nptr += 1;
  } else {
    base = 10;
  }
  l = 0;
  while (digit_from_char(c = *nptr, base, &digit)) {
    l = l * base + digit;
    nptr++;
  }
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtoull>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L73
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L21
L73:
  mov    $0xa,%r13d
  mov    $0xa,%ebp
  cmp    $0x30,%al
  je     L34
L41:
  xor    %r12d,%r12d
  lea    0x7(%rsp),%r14
  jmp    L82
  nopl   (%rax)
L28:
  imul   %r13,%r12
  movsbq 0x7(%rsp),%rax
  add    $0x1,%rbx
  add    %rax,%r12
L82:
  movsbl (%rbx),%edi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <digit_from_char@plt>
  test   %rax,%rax
  jne    L28
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  cmpb   $0x78,0x1(%rbx)
  je     L6
  add    $0x1,%rbx
  mov    $0x8,%r13d
  mov    $0x8,%ebp
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x2,%rbx
  mov    $0x10,%r13d
  mov    $0x10,%ebp
  jmp    L41
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long strtoull(const char *nptr) {
  char c;
  char digit;
  long base;
  unsigned long long l;
  while (*nptr == ' ') {
    nptr++;
  };
  if (nptr[0] == '0' && nptr[1] == 'x') {
    base = 16;
    nptr += 2;
  } else if (nptr[0] == '0') {
    base = 8;
    nptr += 1;
  } else {
    base = 10;
  }
  l = 0;
  while (digit_from_char(c = *nptr, base, &digit)) {
    l = l * base + digit;
    nptr++;
  }
  return l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%edx
  sub    $0x99f4bb,%edx
  mov    %edx,%eax
  je     L6
  lea    (%rdx,%rdx,1),%eax
L14:
  lea    0x0(,%rax,4),%edx
  test   %eax,%eax
  cmovne %edx,%eax
  sub    $0x31c3f3f1,%eax
  mov    %eax,(%rsi)
  ret
L6:
  mov    $0x0,%dx
  movzwl %ax,%eax
  or     %edx,%eax
  jmp    L14
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      }
      if (state[0UL] == local1) {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      } else {
        state[local1] += state[0UL];
        state[local1] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 769470608UL) + 4229512351U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  lea    (%rax,%rax,1),%edx
  mov    $0x0,%eax
  cmovne %edx,%eax
  lea    -0x31c3f3f1(,%rax,4),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      }
      if (state[0UL] == local1) {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      } else {
        state[local1] += state[0UL];
        state[local1] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 769470608UL) + 4229512351U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  jne    L27
L25:
  sub    $0x31c3f3f1,%eax
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L27:
  mov    %eax,%edx
  add    %edx,%edx
  je     L7
  shl    $0x3,%eax
  sub    $0x31c3f3f1,%eax
  mov    %eax,(%rsi)
  ret
L7:
  xor    %eax,%eax
  jmp    L25
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  unsigned short copy14;
  unsigned short copy15;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] > local1) {
        state[local1] += state[0UL];
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy12;
        copy13 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = copy13;
      }
      if (state[0UL] == local1) {
        copy14 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy14;
        copy15 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy15;
      } else {
        state[local1] += state[0UL];
        state[local1] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 769470608UL) + 4229512351U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int *p = (int *)malloc(8);
  free(p);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int *p = (int *)malloc(8);
  free(p);
  return 0;
}
```