ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <__ESBMC_assume@plt>
  movl   $0x0,(%rbx)
  mov    $0x1,%edi
  movl   $0x1,0x8(%rbx)
  call   <assert@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int *foobar = malloc(12);
  __ESBMC_assume(foobar);
  foobar[0] = 0;
  foobar[2] = 1;
  assert(foobar[0] == 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rainbowWithGlitterCol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <rainbowCol@plt>
  mov    $0x50,%edi
  call   <addGlitter@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rainbowWithGlitterCol() {
  rainbowCol();
  addGlitter(80);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rainbowWithGlitterCol>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rainbowCol@plt>
  mov    $0x50,%edi
  call   <addGlitter@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void rainbowWithGlitterCol() {
  rainbowCol();
  addGlitter(80);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rainbowWithGlitterCol>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rainbowCol@plt>
  mov    $0x50,%edi
  add    $0x8,%rsp
  jmp    1060 <addGlitter@plt>
```

assistant: ```c
void rainbowWithGlitterCol() {
  rainbowCol();
  addGlitter(80);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rainbowWithGlitterCol>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rainbowCol@plt>
  mov    $0x50,%edi
  add    $0x8,%rsp
  jmp    1060 <addGlitter@plt>
```

assistant: ```c
void rainbowWithGlitterCol() {
  rainbowCol();
  addGlitter(80);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sol_util_memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *sol_util_memdup(const void *data, size_t len) {
  void *ptr;
  ptr = malloc(len);
  if (ptr)
    memcpy(ptr, data, len);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sol_util_memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *sol_util_memdup(const void *data, size_t len) {
  void *ptr;
  ptr = malloc(len);
  if (ptr)
    memcpy(ptr, data, len);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sol_util_memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L5:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_util_memdup(const void *data, size_t len) {
  void *ptr;
  ptr = malloc(len);
  if (ptr)
    memcpy(ptr, data, len);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sol_util_memdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L1:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *sol_util_memdup(const void *data, size_t len) {
  void *ptr;
  ptr = malloc(len);
  if (ptr)
    memcpy(ptr, data, len);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f_d_fup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L13:
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <binCoeff@plt>
  mov    %rax,%rbx
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <binCoeff@plt>
  sub    %rax,%rbx
  mov    %rbx,%rdx
  pxor   %xmm3,%xmm3
  cvtsi2sd %rdx,%xmm3
  movsd  %xmm3,-0x38(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x2c(%rbp),%xmm0
  movsd  D5(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x2c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <f_fup@plt>
  mulsd  -0x38(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L8:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L13
  mov    $0x1,%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: f64
name: extract_symbolic_data
arguments: data_tag: D12
type: f64

tool: D5: 2

tool: D12: 1

assistant: ```c
double f_d_fup(double x, int n) {
  int k;
  double y, z = 0.;
  for (k = 0; k < n + 2; k++) {
    z += (double)(binCoeff(k, n + 1) - binCoeff(k - 1, n + 1)) * f_fup(2. * x + (double)n / 2. + 1. - (double)k, n);
  }
  return pow(2., -n + 1) * z;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f_d_fup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %edi,%r13d
  mov    %edi,%r14d
  add    $0x1,%r14d
  js     L10
  mov    $0xffffffff,%ebx
  pxor   %xmm5,%xmm5
  movsd  %xmm5,(%rsp)
L17:
  mov    %ebx,%r12d
  add    $0x1,%ebx
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <binCoeff@plt>
  mov    %rax,%rbp
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <binCoeff@plt>
  mov    %rax,%r12
  pxor   %xmm0,%xmm0
  cvtsi2sd %r13d,%xmm0
  mulsd  D7(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  movapd %xmm2,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  D17(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  mov    %r13d,%esi
  call   <f_fup@plt>
  movapd %xmm0,%xmm1
  sub    %r12,%rbp
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    %r13d,%ebx
  jle    L17
L4:
  mov    $0x1,%esi
  sub    %r13d,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mulsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,(%rsp)
  jmp    L4
```

tool_calls: name: unpack_data
arguments: label: D7
type_infered: f32[2]
name: unpack_data
arguments: label: D17
type_infered: f64

tool: {"D7": [0.0,1.75]}

tool: D17: 1

assistant: ```c
double f_d_fup(double x, int n) {
  int k;
  double y, z = 0.;
  for (k = 0; k < n + 2; k++) {
    z += (double)(binCoeff(k, n + 1) - binCoeff(k - 1, n + 1)) * f_fup(2. * x + (double)n / 2. + 1. - (double)k, n);
  }
  return pow(2., -n + 1) * z;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_d_fup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x20,%rsp
  add    $0x1,%r12d
  js     L7
  pxor   %xmm7,%xmm7
  addsd  %xmm0,%xmm0
  pxor   %xmm6,%xmm6
  mov    $0xffffffff,%r13d
  cvtsi2sd %edi,%xmm7
  movsd  %xmm6,0x8(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm7,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %r13d,%r14d
  add    $0x1,%r13d
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <binCoeff@plt>
  mov    %r14d,%edi
  mov    %r12d,%esi
  mov    %rax,%rbx
  call   <binCoeff@plt>
  pxor   %xmm1,%xmm1
  movsd  D15(%rip),%xmm0
  mov    %ebp,%esi
  cvtsi2sd %r13d,%xmm1
  mulsd  0x10(%rsp),%xmm0
  mov    %rax,%r14
  addsd  0x18(%rsp),%xmm0
  addsd  D17(%rip),%xmm0
  sub    %r14,%rbx
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <f_fup@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,%r13d
  jle    L23
L0:
  mov    $0x1,%esi
  mov    $0x2,%edi
  sub    %ebp,%esi
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L0
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: f32[2]
name: unpack_data
arguments: tag: D17
type_guessed: f64

tool: {"D15": [0.0,1.75]}

tool: D17: 1

assistant: ```c
double f_d_fup(double x, int n) {
  int k;
  double y, z = 0.;
  for (k = 0; k < n + 2; k++) {
    z += (double)(binCoeff(k, n + 1) - binCoeff(k - 1, n + 1)) * f_fup(2. * x + (double)n / 2. + 1. - (double)k, n);
  }
  return pow(2., -n + 1) * z;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f_d_fup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x20,%rsp
  add    $0x1,%r12d
  js     L19
  pxor   %xmm7,%xmm7
  addsd  %xmm0,%xmm0
  pxor   %xmm6,%xmm6
  mov    $0xffffffff,%r13d
  cvtsi2sd %edi,%xmm7
  movsd  %xmm6,0x8(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm7,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %r13d,%r14d
  add    $0x1,%r13d
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <binCoeff@plt>
  mov    %r14d,%edi
  mov    %r12d,%esi
  mov    %rax,%rbx
  call   <binCoeff@plt>
  pxor   %xmm1,%xmm1
  movsd  D18(%rip),%xmm0
  mov    %ebp,%esi
  cvtsi2sd %r13d,%xmm1
  mulsd  0x10(%rsp),%xmm0
  mov    %rax,%r14
  addsd  0x18(%rsp),%xmm0
  addsd  D8(%rip),%xmm0
  sub    %r14,%rbx
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edi
  call   <f_fup@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbx,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  cmp    %ebp,%r13d
  jle    L29
L11:
  mov    $0x1,%esi
  mov    $0x2,%edi
  sub    %ebp,%esi
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: f32[2]
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: f64

tool: {"D18": [0.0,1.75]}

tool: D8: 1

assistant: ```c
double f_d_fup(double x, int n) {
  int k;
  double y, z = 0.;
  for (k = 0; k < n + 2; k++) {
    z += (double)(binCoeff(k, n + 1) - binCoeff(k - 1, n + 1)) * f_fup(2. * x + (double)n / 2. + 1. - (double)k, n);
  }
  return pow(2., -n + 1) * z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x8,-0x4(%rbp)
  jbe    L7
  cmpb   $0xb,-0x4(%rbp)
  je     L2
  cmpb   $0xd,-0x4(%rbp)
  jbe    L80
  cmpb   $0x1a,-0x4(%rbp)
  jbe    L24
L80:
  cmpb   $0x3b,-0x4(%rbp)
  jbe    L83
  cmpb   $0x3f,-0x4(%rbp)
  jbe    L37
L83:
  mov    $0x0,%eax
  jmp    L52
L7:
  nop
  jmp    L97
L2:
  nop
  jmp    L97
L24:
  nop
  jmp    L97
L37:
  nop
L97:
  mov    $0x1,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no, noclone)) int bar(unsigned char b) {
  if (0x0 <= b && b <= 0x8)
    goto lab;
  if (b == 0x0b)
    goto lab;
  if (0x0e <= b && b <= 0x1a)
    goto lab;
  if (0x3c <= b && b <= 0x3f)
    goto lab;
  return 0;
lab:
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3f,%dil
  ja     L4
  movabs $0xf000000007ffc9ff,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L4:
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
__attribute__((no, noclone)) int bar(unsigned char b) {
  if (0x0 <= b && b <= 0x8)
    goto lab;
  if (b == 0x0b)
    goto lab;
  if (0x0e <= b && b <= 0x1a)
    goto lab;
  if (0x3c <= b && b <= 0x3f)
    goto lab;
  return 0;
lab:
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bar>:
  endbr64
  xor    %eax,%eax
  cmp    $0x3f,%dil
  ja     L3
  movabs $0xf000000007ffc9ff,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
L3:
  ret
```

assistant: ```c
__attribute__((no, noclone)) int bar(unsigned char b) {
  if (0x0 <= b && b <= 0x8)
    goto lab;
  if (b == 0x0b)
    goto lab;
  if (0x0e <= b && b <= 0x1a)
    goto lab;
  if (0x3c <= b && b <= 0x3f)
    goto lab;
  return 0;
lab:
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<bar>:
  endbr64
  xor    %eax,%eax
  cmp    $0x3f,%dil
  ja     L2
  movabs $0xf000000007ffc9ff,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
L2:
  ret
```

assistant: ```c
__attribute__((no, noclone)) int bar(unsigned char b) {
  if (0x0 <= b && b <= 0x8)
    goto lab;
  if (b == 0x0b)
    goto lab;
  if (0x0e <= b && b <= 0x1a)
    goto lab;
  if (0x3c <= b && b <= 0x3f)
    goto lab;
  return 0;
lab:
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <length@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L4:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0xfffffc19,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void delete (int arr[], int index) {
  int len = length(arr), i;
  for (i = index; i < len - 1; i++)
    arr[i] = arr[i + 1];
  arr[i] = -999;
}
```
user: What is the c source code of the assembly code below:

```asm
<delete>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <length@plt>
  lea    -0x1(%rax),%edx
  cmp    %edx,%ebx
  jge    L1
  movslq %ebx,%rsi
  lea    0x0(%rbp,%rsi,4),%rdx
  mov    %eax,%ecx
  sub    %ebx,%ecx
  lea    -0x2(%rcx),%ecx
  add    %rsi,%rcx
  lea    0x4(%rbp,%rcx,4),%rsi
L8:
  mov    0x4(%rdx),%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L8
  lea    -0x1(%rax),%ebx
L1:
  movslq %ebx,%rbx
  movl   $0xfffffc19,0x0(%rbp,%rbx,4)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void delete (int arr[], int index) {
  int len = length(arr), i;
  for (i = index; i < len - 1; i++)
    arr[i] = arr[i + 1];
  arr[i] = -999;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delete>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <length@plt>
  lea    -0x1(%rax),%r12d
  cmp    %r12d,%ebp
  jge    L5
  movslq %ebp,%rdi
  sub    %ebp,%eax
  movslq %r12d,%r12
  shl    $0x2,%rdi
  sub    $0x2,%eax
  lea    0x4(%rbx,%rdi,1),%rsi
  lea    0x4(,%rax,4),%rdx
  add    %rbx,%rdi
  call   <memmove@plt>
  movl   $0xfffffc19,(%rbx,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %ebp,%r12d
  movslq %r12d,%r12
  movl   $0xfffffc19,(%rbx,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void delete (int arr[], int index) {
  int len = length(arr), i;
  for (i = index; i < len - 1; i++)
    arr[i] = arr[i + 1];
  arr[i] = -999;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<delete>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <length@plt>
  lea    -0x1(%rax),%r12d
  cmp    %r12d,%ebp
  jge    L4
  movslq %ebp,%rdi
  sub    %ebp,%eax
  movslq %r12d,%r12
  shl    $0x2,%rdi
  sub    $0x2,%eax
  lea    0x4(%rbx,%rdi,1),%rsi
  lea    0x4(,%rax,4),%rdx
  add    %rbx,%rdi
  call   <memmove@plt>
  movl   $0xfffffc19,(%rbx,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  mov    %ebp,%r12d
  movslq %r12d,%r12
  movl   $0xfffffc19,(%rbx,%r12,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void delete (int arr[], int index) {
  int len = length(arr), i;
  for (i = index; i < len - 1; i++)
    arr[i] = arr[i + 1];
  arr[i] = -999;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ia64_mk_io_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <__ia64_get_io_port_base@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  shr    $0x2,%rax
  shl    $0xc,%rax
  or     -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  and    $0xfff,%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__ia64_mk_io_addr(unsigned long port) {
  const unsigned long io_base = __ia64_get_io_port_base();
  unsigned long addr;
  addr = io_base | ((port >> 2) << 12) | (port & 0xfff);
  return (void *)addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__ia64_mk_io_addr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <__ia64_get_io_port_base@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  shr    $0x2,%rax
  shl    $0xc,%rax
  and    $0xfff,%ebx
  or     %rbx,%rax
  or     %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *__ia64_mk_io_addr(unsigned long port) {
  const unsigned long io_base = __ia64_get_io_port_base();
  unsigned long addr;
  addr = io_base | ((port >> 2) << 12) | (port & 0xfff);
  return (void *)addr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__ia64_mk_io_addr>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__ia64_get_io_port_base@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  and    $0xfff,%ebx
  shr    $0x2,%rax
  shl    $0xc,%rax
  or     %rbx,%rax
  pop    %rbx
  or     %r8,%rax
  ret
```

assistant: ```c
void *__ia64_mk_io_addr(unsigned long port) {
  const unsigned long io_base = __ia64_get_io_port_base();
  unsigned long addr;
  addr = io_base | ((port >> 2) << 12) | (port & 0xfff);
  return (void *)addr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__ia64_mk_io_addr>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <__ia64_get_io_port_base@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  and    $0xfff,%ebx
  shr    $0x2,%rax
  shl    $0xc,%rax
  or     %rbx,%rax
  pop    %rbx
  or     %r8,%rax
  ret
```

assistant: ```c
void *__ia64_mk_io_addr(unsigned long port) {
  const unsigned long io_base = __ia64_get_io_port_base();
  unsigned long addr;
  addr = io_base | ((port >> 2) << 12) | (port & 0xfff);
  return (void *)addr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string
name: disassemble_data
arguments: label: D11
datatype: string

tool: D0: 
--------------------------
1.Display books            
2.Insert a book            
3.Update a book Status      
4.Delete a book            
5.Search for a book        
6.Exit                    
--------------------------


tool: D11: ----> Please Enter Your Choice: 

assistant: ```c
void menu() {
  printf("\n--------------------------\n"
         "1.Display books            \n"
         "2.Insert a book            \n"
         "3.Update a book Status      \n"
         "4.Delete a book            \n"
         "5.Search for a book        \n"
         "6.Exit                    \n"
         "--------------------------\n");
  printf("----> Please Enter Your Choice: ");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D8: 
--------------------------
1.Display books            
2.Insert a book            
3.Update a book Status      
4.Delete a book            
5.Search for a book        
6.Exit                    
--------------------------


tool: D5: ----> Please Enter Your Choice: 

assistant: ```c
void menu() {
  printf("\n--------------------------\n"
         "1.Display books            \n"
         "2.Insert a book            \n"
         "3.Update a book Status      \n"
         "4.Delete a book            \n"
         "5.Search for a book        \n"
         "6.Exit                    \n"
         "--------------------------\n");
  printf("----> Please Enter Your Choice: ");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string

tool: D8: 
--------------------------
1.Display books            
2.Insert a book            
3.Update a book Status      
4.Delete a book            
5.Search for a book        
6.Exit                    
--------------------------


tool: D12: ----> Please Enter Your Choice: 

assistant: ```c
void menu() {
  printf("\n--------------------------\n"
         "1.Display books            \n"
         "2.Insert a book            \n"
         "3.Update a book Status      \n"
         "4.Delete a book            \n"
         "5.Search for a book        \n"
         "6.Exit                    \n"
         "--------------------------\n");
  printf("----> Please Enter Your Choice: ");
}
```
user: Translate the below assembly code into C programming language:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string

tool: D15: 
--------------------------
1.Display books            
2.Insert a book            
3.Update a book Status      
4.Delete a book            
5.Search for a book        
6.Exit                    
--------------------------


tool: D11: ----> Please Enter Your Choice: 

assistant: ```c
void menu() {
  printf("\n--------------------------\n"
         "1.Display books            \n"
         "2.Insert a book            \n"
         "3.Update a book Status      \n"
         "4.Delete a book            \n"
         "5.Search for a book        \n"
         "6.Exit                    \n"
         "--------------------------\n");
  printf("----> Please Enter Your Choice: ");
}
```