ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<sock_bind>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x18,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  test   %rbp,%rbp
  je     L20
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L37
L20:
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %rax,0x8(%rsp)
L42:
  movzwl %bx,%edi
  call   <htons@plt>
  mov    %eax,(%rsp)
  mov    %rsp,%rsi
  mov    $0x18,%edx
  mov    (%r12),%edi
  call   <bind@plt>
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    %rbp,%rdi
  call   <inet_addr@plt>
  mov    %rax,0x8(%rsp)
  mov    D7(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L42
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L55
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  jmp    L42
L55:
  mov    $0xffffffff,%eax
  jmp    L8
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sock_bind(int *fd, unsigned short port, const char *addr) {
  struct sockaddr_in sa;
  struct hostent *host = NULL;
  memset(&sa, 0, sizeof(sa));
  sa.sin_family = AF_INET;
  if (!addr || !strlen(addr))
    sa.sin_addr.s_addr = htonl(INADDR_ANY);
  else {
    sa.sin_addr.s_addr = inet_addr(addr);
    if (sa.sin_addr.s_addr == INADDR_NONE) {
      host = gethostbyname(addr);
      if (host) {
        sa.sin_addr.s_addr = ((struct in_addr *)host->h_addr)->s_addr;
        host = NULL;
      } else
        return -1;
    }
  }
  sa.sin_port = htons(port);
  return bind((*fd), (struct sockaddr *)&sa, sizeof(sa));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sock_bind>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x18,%edx
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  test   %rbp,%rbp
  je     L46
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L37
L46:
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %rax,0x8(%rsp)
L20:
  movzwl %bx,%edi
  call   <htons@plt>
  mov    (%r12),%edi
  mov    $0x18,%edx
  mov    %r13,%rsi
  mov    %eax,(%rsp)
  call   <bind@plt>
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  mov    %rbp,%rdi
  call   <inet_addr@plt>
  mov    D12(%rip),%rdx
  mov    %rax,0x8(%rsp)
  cmp    (%rdx),%rax
  jne    L20
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L56
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
L56:
  or     $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int sock_bind(int *fd, unsigned short port, const char *addr) {
  struct sockaddr_in sa;
  struct hostent *host = NULL;
  memset(&sa, 0, sizeof(sa));
  sa.sin_family = AF_INET;
  if (!addr || !strlen(addr))
    sa.sin_addr.s_addr = htonl(INADDR_ANY);
  else {
    sa.sin_addr.s_addr = inet_addr(addr);
    if (sa.sin_addr.s_addr == INADDR_NONE) {
      host = gethostbyname(addr);
      if (host) {
        sa.sin_addr.s_addr = ((struct in_addr *)host->h_addr)->s_addr;
        host = NULL;
      } else
        return -1;
    }
  }
  sa.sin_port = htons(port);
  return bind((*fd), (struct sockaddr *)&sa, sizeof(sa));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sock_bind>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x18,%edx
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  test   %rbp,%rbp
  je     L52
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jne    L30
L52:
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %rax,0x8(%rsp)
L5:
  movzwl %bx,%edi
  call   <htons@plt>
  mov    (%r12),%edi
  mov    $0x18,%edx
  mov    %r13,%rsi
  mov    %eax,(%rsp)
  call   <bind@plt>
L27:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  mov    %rbp,%rdi
  call   <inet_addr@plt>
  mov    D10(%rip),%rdx
  mov    %rax,0x8(%rsp)
  cmp    (%rdx),%rax
  jne    L5
  mov    %rbp,%rdi
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L3
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,0x8(%rsp)
  jmp    L5
L17:
  call   <__stack_chk_fail@plt>
L3:
  or     $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int sock_bind(int *fd, unsigned short port, const char *addr) {
  struct sockaddr_in sa;
  struct hostent *host = NULL;
  memset(&sa, 0, sizeof(sa));
  sa.sin_family = AF_INET;
  if (!addr || !strlen(addr))
    sa.sin_addr.s_addr = htonl(INADDR_ANY);
  else {
    sa.sin_addr.s_addr = inet_addr(addr);
    if (sa.sin_addr.s_addr == INADDR_NONE) {
      host = gethostbyname(addr);
      if (host) {
        sa.sin_addr.s_addr = ((struct in_addr *)host->h_addr)->s_addr;
        host = NULL;
      } else
        return -1;
    }
  }
  sa.sin_port = htons(port);
  return bind((*fd), (struct sockaddr *)&sa, sizeof(sa));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x10(%rbp),%rax
  sar    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D30
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D30: Address of p is %d and address of p+1 is %d.


tool: D24: Address of p is %d and address of p+3 is %d.


tool: D15: Address of p is %d and address of p-2 is %d.


tool: D3: Address of p is %d and address of q is %d and p-q is %d.


assistant: ```c
main() {
  int a, b, *p, *q;
  p = &a;
  q = &b;
  printf("Address of p is %d and address of p+1 is %d.\n", p, p + 1);
  printf("Address of p is %d and address of p+3 is %d.\n", p, p + 3);
  printf("Address of p is %d and address of p-2 is %d.\n", p, p - 2);
  printf("Address of p is %d and address of q is %d and p-q is %d.\n", p, q, p - q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x8(%rsp),%rdx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rcx
  sub    %rbp,%rcx
  sar    $0x2,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string
name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D36
type_guessed: string

tool: D33: Address of p is %d and address of p+1 is %d.


tool: D26: Address of p is %d and address of p+3 is %d.


tool: D8: Address of p is %d and address of p-2 is %d.


tool: D36: Address of p is %d and address of q is %d and p-q is %d.


assistant: ```c
main() {
  int a, b, *p, *q;
  p = &a;
  q = &b;
  printf("Address of p is %d and address of p+1 is %d.\n", p, p + 1);
  printf("Address of p is %d and address of p+3 is %d.\n", p, p + 3);
  printf("Address of p is %d and address of p-2 is %d.\n", p, p - 2);
  printf("Address of p is %d and address of q is %d and p-q is %d.\n", p, q, p - q);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    -0x8(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rcx
  xor    %eax,%eax
  mov    %r12,%rdx
  sub    %r12,%rcx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  sar    $0x2,%rcx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D18
type_infered: string
name: parse_data
arguments: data_label: D17
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string

tool: D10: Address of p is %d and address of p+1 is %d.


tool: D18: Address of p is %d and address of p+3 is %d.


tool: D17: Address of p is %d and address of p-2 is %d.


tool: D7: Address of p is %d and address of q is %d and p-q is %d.


assistant: ```c
main() {
  int a, b, *p, *q;
  p = &a;
  q = &b;
  printf("Address of p is %d and address of p+1 is %d.\n", p, p + 1);
  printf("Address of p is %d and address of p+3 is %d.\n", p, p + 3);
  printf("Address of p is %d and address of p-2 is %d.\n", p, p - 2);
  printf("Address of p is %d and address of q is %d and p-q is %d.\n", p, q, p - q);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x4(%rsp),%r12
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    -0x8(%rsp),%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rcx
  xor    %eax,%eax
  mov    %r12,%rdx
  sub    %r12,%rcx
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  sar    $0x2,%rcx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D22
datatype: string
name: read_data
arguments: data_label: D39
datatype: string
name: read_data
arguments: data_label: D10
datatype: string
name: read_data
arguments: data_label: D23
datatype: string

tool: D22: Address of p is %d and address of p+1 is %d.


tool: D39: Address of p is %d and address of p+3 is %d.


tool: D10: Address of p is %d and address of p-2 is %d.


tool: D23: Address of p is %d and address of q is %d and p-q is %d.


assistant: ```c
main() {
  int a, b, *p, *q;
  p = &a;
  q = &b;
  printf("Address of p is %d and address of p+1 is %d.\n", p, p + 1);
  printf("Address of p is %d and address of p+3 is %d.\n", p, p + 3);
  printf("Address of p is %d and address of p-2 is %d.\n", p, p - 2);
  printf("Address of p is %d and address of q is %d and p-q is %d.\n", p, q, p - q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Stirling2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L29
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L19
L29:
  mov    $0x0,%eax
  jmp    L18
L19:
  cmpl   $0x1,-0x18(%rbp)
  je     L32
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L33
L32:
  mov    $0x1,%eax
  jmp    L18
L33:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <Stirling2>
  imul   -0x18(%rbp),%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Stirling2>
  add    %ebx,%eax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Stirling2(int n, int k) {
  if (k < 1 || k > n)
    return 0;
  if (k == 1 || k == n)
    return 1;
  return k * Stirling2(n - 1, k) + Stirling2(n - 1, k - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Stirling2>:
  endbr64
  test   %esi,%esi
  jle    L43
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    %edi,%esi
  jg     L21
  cmp    $0x1,%esi
  je     L18
  cmp    %edi,%esi
  je     L18
  lea    -0x1(%rdi),%ebp
  mov    %ebp,%edi
  call   <Stirling2>
  imul   %ebx,%eax
  mov    %eax,%r12d
  lea    -0x1(%rbx),%esi
  mov    %ebp,%edi
  call   <Stirling2>
  add    %r12d,%eax
  jmp    L47
L21:
  mov    $0x0,%eax
  jmp    L47
L18:
  mov    $0x1,%eax
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Stirling2(int n, int k) {
  if (k < 1 || k > n)
    return 0;
  if (k == 1 || k == n)
    return 1;
  return k * Stirling2(n - 1, k) + Stirling2(n - 1, k - 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<Stirling2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L21
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    %esi,%edi
  jl     L21
  cmp    $0x1,%esi
  je     L38
  xor    %r14d,%r14d
  cmp    %esi,%edi
  je     L38
L65:
  mov    %ebp,%r12d
  sub    $0x1,%ebp
  mov    %ebx,%esi
  mov    %ebx,%r13d
  mov    %ebp,%edi
  call   <Stirling2>
  imul   %ebx,%eax
  add    %eax,%r14d
  cmp    %ebx,%r12d
  jl     L18
  sub    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L54
  cmp    %r13d,%r12d
  jne    L65
L54:
  add    $0x1,%r14d
L18:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L21:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L38:
  mov    $0x1,%r14d
  jmp    L18
```

assistant: ```c
int Stirling2(int n, int k) {
  if (k < 1 || k > n)
    return 0;
  if (k == 1 || k == n)
    return 1;
  return k * Stirling2(n - 1, k) + Stirling2(n - 1, k - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delshadow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  lea    D26(%rip),%rsi
  mov    %rax,%rdi
  call   <cm_delete_entry@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  jmp    L3
L14:
  mov    $0x0,%eax
L3:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D26
type: string

tool: D2: /etc/.shadow.cm

tool: D4: /etc/shadow

tool: D26: %[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d

assistant: ```c
int delshadow(char *user) {
  int i;
  if ((i = cm_delete_entry(user, "%[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d", "/etc/shadow", "/etc/.shadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delshadow>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rcx
  lea    D29(%rip),%rdx
  lea    D24(%rip),%rsi
  call   <cm_delete_entry@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D20
datatype: string
name: extract_symbolic_data
arguments: label: D29
datatype: string
name: extract_symbolic_data
arguments: label: D24
datatype: string

tool: D20: /etc/.shadow.cm

tool: D29: /etc/shadow

tool: D24: %[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d

assistant: ```c
int delshadow(char *user) {
  int i;
  if ((i = cm_delete_entry(user, "%[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d", "/etc/shadow", "/etc/.shadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delshadow>:
  endbr64
  lea    D17(%rip),%rcx
  lea    D16(%rip),%rdx
  lea    D26(%rip),%rsi
  jmp    1050 <cm_delete_entry@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D26
type: string

tool: D17: /etc/.shadow.cm

tool: D16: /etc/shadow

tool: D26: %[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d

assistant: ```c
int delshadow(char *user) {
  int i;
  if ((i = cm_delete_entry(user, "%[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d", "/etc/shadow", "/etc/.shadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<delshadow>:
  endbr64
  lea    D22(%rip),%rcx
  lea    D14(%rip),%rdx
  lea    D19(%rip),%rsi
  jmp    1050 <cm_delete_entry@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
data_type: string
name: extract_symbolic_data
arguments: data_label: D14
data_type: string
name: extract_symbolic_data
arguments: data_label: D19
data_type: string

tool: D22: /etc/.shadow.cm

tool: D14: /etc/shadow

tool: D19: %[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d

assistant: ```c
int delshadow(char *user) {
  int i;
  if ((i = cm_delete_entry(user, "%[^:]:%*[^:]:%*d:%*d:%*d:%*d:%*d:%*d:%*d", "/etc/shadow", "/etc/.shadow.cm")) != 0) {
    return i;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bit_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x1,-0x5(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x5(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L24:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  movzbl -0x14(%rbp),%edx
  and    -0x5(%rbp),%dl
  test   %dl,%dl
  jne    L37
  mov    $0x30,%edx
  jmp    L3
L37:
  mov    $0x31,%edx
L3:
  mov    %eax,%esi
  mov    %edx,%edi
  call   <fputc@plt>
  shrb   -0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_bit_char(unsigned char character) {
  int bit;
  unsigned char mask = 1;
  mask <<= (CHAR_BIT - 1);
  for (bit = 1; bit <= CHAR_BIT; ++bit) {
    fputc(((character & mask) == 0) ? '0' : '1', stdout);
    mask >>= 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_bit_char>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%ecx
  mov    $0x1,%ebx
  shl    %cl,%ebx
  test   %eax,%eax
  jle    L13
  mov    %edi,%r12d
  mov    $0x1,%ebp
  mov    D5(%rip),%r13
L11:
  mov    0x0(%r13),%esi
  test   %bl,%r12b
  setne  %dil
  movzbl %dil,%edi
  add    $0x30,%edi
  call   <fputc@plt>
  shr    %bl
  add    $0x1,%ebp
  mov    D25(%rip),%rax
  cmp    %ebp,(%rax)
  jge    L11
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void print_bit_char(unsigned char character) {
  int bit;
  unsigned char mask = 1;
  mask <<= (CHAR_BIT - 1);
  for (bit = 1; bit <= CHAR_BIT; ++bit) {
    fputc(((character & mask) == 0) ? '0' : '1', stdout);
    mask >>= 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_bit_char>:
  endbr64
  push   %r14
  push   %r13
  mov    D4(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x0(%r13),%eax
  mov    $0x1,%ebx
  lea    -0x1(%rax),%ecx
  shl    %cl,%ebx
  test   %eax,%eax
  jle    L4
  mov    D19(%rip),%r14
  mov    %edi,%r12d
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L7:
  xor    %edi,%edi
  test   %bl,%r12b
  mov    (%r14),%esi
  setne  %dil
  shr    %bl
  add    $0x1,%ebp
  add    $0x30,%edi
  call   <fputc@plt>
  cmp    %ebp,0x0(%r13)
  jge    L7
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_bit_char(unsigned char character) {
  int bit;
  unsigned char mask = 1;
  mask <<= (CHAR_BIT - 1);
  for (bit = 1; bit <= CHAR_BIT; ++bit) {
    fputc(((character & mask) == 0) ? '0' : '1', stdout);
    mask >>= 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_bit_char>:
  endbr64
  push   %r14
  push   %r13
  mov    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x0(%r13),%eax
  mov    $0x1,%ebx
  lea    -0x1(%rax),%ecx
  shl    %cl,%ebx
  test   %eax,%eax
  jle    L39
  mov    D4(%rip),%r14
  mov    %edi,%r12d
  mov    $0x1,%ebp
  nopl   0x0(%rax)
L4:
  mov    (%r14),%esi
  test   %bl,%r12b
  jne    L35
  mov    $0x30,%edi
  shr    %bl
  add    $0x1,%ebp
  call   <fputc@plt>
  cmp    0x0(%r13),%ebp
  jle    L4
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L35:
  mov    $0x31,%edi
  shr    %bl
  add    $0x1,%ebp
  call   <fputc@plt>
  cmp    %ebp,0x0(%r13)
  jge    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void print_bit_char(unsigned char character) {
  int bit;
  unsigned char mask = 1;
  mask <<= (CHAR_BIT - 1);
  for (bit = 1; bit <= CHAR_BIT; ++bit) {
    fputc(((character & mask) == 0) ? '0' : '1', stdout);
    mask >>= 1;
  }
}
```