ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<nameInCommaList>:
  endbr64
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L73
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%r12d
  cmpb   $0x0,(%rbx)
  je     L23
  movslq %eax,%r13
  jmp    L56
L39:
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L103
  lea    0x1(%rax),%rbx
  cmpb   $0x0,0x1(%rax)
  je     L109
L56:
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L39
  movzbl (%rbx,%r13,1),%eax
  test   %al,%al
  je     L81
  cmp    $0x2c,%al
  jne    L39
L81:
  mov    $0x1,%eax
  jmp    L11
L109:
  mov    $0x0,%eax
  jmp    L11
L23:
  mov    $0x0,%eax
  jmp    L11
L103:
  mov    $0x0,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L73:
  ret
```

assistant: ```c
int nameInCommaList(char *name, char *commaList) {
  if (commaList == NULL)
    return 0;
  int nameLen = strlen(name);
  for (;;) {
    char c = *commaList;
    if (c == 0)
      return 0;
    if (memcmp(name, commaList, nameLen) == 0) {
      c = commaList[nameLen];
      if (c == 0 || c == ',')
        return 1;
    }
    commaList = strchr(commaList, ',');
    if (commaList == NULL)
      return 0;
    commaList += 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<nameInCommaList>:
  endbr64
  test   %rsi,%rsi
  je     L64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,0x0(%rbp)
  mov    %eax,%r12d
  je     L71
  movslq %eax,%r13
  jmp    L12
  nopl   0x0(%rax)
L9:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rbp
  je     L71
L12:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L49
  movzbl 0x0(%rbp,%r13,1),%eax
  test   %al,%al
  je     L4
  cmp    $0x2c,%al
  je     L4
L49:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L9
L71:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int nameInCommaList(char *name, char *commaList) {
  if (commaList == NULL)
    return 0;
  int nameLen = strlen(name);
  for (;;) {
    char c = *commaList;
    if (c == 0)
      return 0;
    if (memcmp(name, commaList, nameLen) == 0) {
      c = commaList[nameLen];
      if (c == 0 || c == ',')
        return 1;
    }
    commaList = strchr(commaList, ',');
    if (commaList == NULL)
      return 0;
    commaList += 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<nameInCommaList>:
  endbr64
  test   %rsi,%rsi
  je     L32
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,0x0(%rbp)
  mov    %eax,%r12d
  je     L26
  movslq %eax,%r13
  jmp    L22
  nopl   0x0(%rax)
L75:
  cmpb   $0x0,0x1(%rax)
  lea    0x1(%rax),%rbp
  je     L26
L22:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L18
  movzbl 0x0(%rbp,%r13,1),%eax
  test   %al,%al
  je     L28
  cmp    $0x2c,%al
  je     L28
L18:
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L75
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int nameInCommaList(char *name, char *commaList) {
  if (commaList == NULL)
    return 0;
  int nameLen = strlen(name);
  for (;;) {
    char c = *commaList;
    if (c == 0)
      return 0;
    if (memcmp(name, commaList, nameLen) == 0) {
      c = commaList[nameLen];
      if (c == 0 || c == ',')
        return 1;
    }
    commaList = strchr(commaList, ',');
    if (commaList == NULL)
      return 0;
    commaList += 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<get_home_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <warnx@plt>
  lea    D29(%rip),%rax
  mov    %rax,-0x8(%rbp)
L1:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string
name: extract_symbolic_data
arguments: label: D29
datatype: string

tool: D27: HOME

tool: D18: HOME not set, using / as home dir

tool: D29: /

assistant: ```c
const char *get_home_dir(void) {
  const char *home_dir;
  if ((home_dir = getenv("HOME")) == NULL) {
    warnx("HOME not set, using / as home dir");
    home_dir = "/";
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L8
L10:
  add    $0x8,%rsp
  ret
L8:
  lea    D16(%rip),%rdi
  call   <warnx@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string

tool: D10: HOME

tool: D16: HOME not set, using / as home dir

assistant: ```c
const char *get_home_dir(void) {
  const char *home_dir;
  if ((home_dir = getenv("HOME")) == NULL) {
    warnx("HOME not set, using / as home dir");
    home_dir = "/";
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L8:
  lea    D18(%rip),%rdi
  call   <warnx@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D18
type: string

tool: D7: HOME

tool: D18: HOME not set, using / as home dir

assistant: ```c
const char *get_home_dir(void) {
  const char *home_dir;
  if ((home_dir = getenv("HOME")) == NULL) {
    warnx("HOME not set, using / as home dir");
    home_dir = "/";
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<get_home_dir>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L1:
  lea    D3(%rip),%rdi
  call   <warnx@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D12: HOME

tool: D3: HOME not set, using / as home dir

assistant: ```c
const char *get_home_dir(void) {
  const char *home_dir;
  if ((home_dir = getenv("HOME")) == NULL) {
    warnx("HOME not set, using / as home dir");
    home_dir = "/";
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<entropium_getRandomByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D20(%rip),%eax
  cmp    $0x20,%eax
  jne    L7
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <entropium_getRandomBlock@plt>
  movl   $0x0,D20(%rip)
L7:
  mov    D20(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D43(%rip)
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D51(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t entropium_getRandomByte(void) {
  static uint8_t block[32];
  static uint8_t i = 32;
  if (i == 32) {
    entropium_getRandomBlock((void *)block);
    i = 0;
  }
  return block[i++];
}
```
user: What is the c source code of the assembly code below?

```asm
<entropium_getRandomByte>:
  endbr64
  sub    $0x8,%rsp
  cmpl   $0x20,D26(%rip)
  je     L0
L18:
  mov    D26(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D40(%rip)
  cltq
  lea    D40(%rip),%rdx
  mov    (%rdx,%rax,4),%eax
  add    $0x8,%rsp
  ret
L0:
  lea    D40(%rip),%rdi
  call   <entropium_getRandomBlock@plt>
  movl   $0x0,D40(%rip)
  jmp    L18
```

assistant: ```c
uint8_t entropium_getRandomByte(void) {
  static uint8_t block[32];
  static uint8_t i = 32;
  if (i == 32) {
    entropium_getRandomBlock((void *)block);
    i = 0;
  }
  return block[i++];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<entropium_getRandomByte>:
  endbr64
  movslq D18(%rip),%rax
  push   %rbx
  cmp    $0x20,%eax
  je     L3
  lea    0x1(%rax),%edx
  lea    D12(%rip),%rbx
  mov    (%rbx,%rax,4),%eax
  pop    %rbx
  mov    %edx,D42(%rip)
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  lea    D12(%rip),%rbx
  mov    %rbx,%rdi
  call   <entropium_getRandomBlock@plt>
  mov    $0x1,%edx
  xor    %eax,%eax
  mov    (%rbx,%rax,4),%eax
  pop    %rbx
  mov    %edx,D42(%rip)
  ret
```

assistant: ```c
uint8_t entropium_getRandomByte(void) {
  static uint8_t block[32];
  static uint8_t i = 32;
  if (i == 32) {
    entropium_getRandomBlock((void *)block);
    i = 0;
  }
  return block[i++];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<entropium_getRandomByte>:
  endbr64
  movslq D0(%rip),%rax
  push   %rbx
  cmp    $0x20,%eax
  je     L0
  lea    0x1(%rax),%edx
  lea    D27(%rip),%rbx
  mov    (%rbx,%rax,4),%eax
  pop    %rbx
  mov    %edx,D8(%rip)
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D27(%rip),%rbx
  mov    %rbx,%rdi
  call   <entropium_getRandomBlock@plt>
  mov    $0x1,%edx
  xor    %eax,%eax
  mov    (%rbx,%rax,4),%eax
  pop    %rbx
  mov    %edx,D8(%rip)
  ret
```

assistant: ```c
uint8_t entropium_getRandomByte(void) {
  static uint8_t block[32];
  static uint8_t i = 32;
  if (i == 32) {
    entropium_getRandomBlock((void *)block);
    i = 0;
  }
  return block[i++];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Default_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L5:
  jmp    L5
```

assistant: ```c
void Default_Handler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Default_Handler>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
void Default_Handler(void) {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Default_Handler>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void Default_Handler(void) {
  while (1)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Default_Handler>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void Default_Handler(void) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<builtin_minus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L8
  mov    $0x0,%edi
  call   <push_from_long@plt>
  jmp    L26
L8:
  cmpl   $0x1,-0x1c(%rbp)
  jne    L35
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  neg    %rax
  mov    %rax,%rdi
  call   <push_from_long@plt>
  jmp    L26
L35:
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  mov    %rax,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
  jmp    L39
L18:
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  sub    %rax,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
L39:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <push_from_long@plt>
L26:
  leave
  ret
```

assistant: ```c
void builtin_minus(struct Context *ctx, unsigned int stack_track) {
  if (stack_track == 0) {
    push_from_long(0L);
    return;
  }
  if (stack_track == 1) {
    push_from_long(-(pop_to_long()));
    return;
  }
  long result = pop_to_long();
  for (stack_track--; stack_track; stack_track--)
    result -= pop_to_long();
  push_from_long(result);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<builtin_minus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L35
  mov    %esi,%ebx
  cmp    $0x1,%esi
  je     L10
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  mov    %rax,%rbp
  sub    $0x1,%ebx
L23:
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  sub    %rax,%rbp
  sub    $0x1,%ebx
  jne    L23
  mov    %rbp,%rdi
  call   <push_from_long@plt>
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x0,%edi
  call   <push_from_long@plt>
  jmp    L46
L10:
  mov    $0x0,%eax
  call   <pop_to_long@plt>
  neg    %rax
  mov    %rax,%rdi
  call   <push_from_long@plt>
  jmp    L46
```

assistant: ```c
void builtin_minus(struct Context *ctx, unsigned int stack_track) {
  if (stack_track == 0) {
    push_from_long(0L);
    return;
  }
  if (stack_track == 1) {
    push_from_long(-(pop_to_long()));
    return;
  }
  long result = pop_to_long();
  for (stack_track--; stack_track; stack_track--)
    result -= pop_to_long();
  push_from_long(result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<builtin_minus>:
  endbr64
  test   %esi,%esi
  je     L22
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L20
  call   <pop_to_long@plt>
  sub    $0x1,%ebx
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <pop_to_long@plt>
  sub    %rax,%rbp
  sub    $0x1,%ebx
  jne    L5
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <push_from_long@plt>
  nopl   (%rax)
L22:
  xor    %edi,%edi
  jmp    1060 <push_from_long@plt>
  nop
L20:
  call   <pop_to_long@plt>
  add    $0x8,%rsp
  neg    %rax
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <push_from_long@plt>
```

assistant: ```c
void builtin_minus(struct Context *ctx, unsigned int stack_track) {
  if (stack_track == 0) {
    push_from_long(0L);
    return;
  }
  if (stack_track == 1) {
    push_from_long(-(pop_to_long()));
    return;
  }
  long result = pop_to_long();
  for (stack_track--; stack_track; stack_track--)
    result -= pop_to_long();
  push_from_long(result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<builtin_minus>:
  endbr64
  test   %esi,%esi
  je     L13
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L10
  call   <pop_to_long@plt>
  sub    $0x1,%ebx
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  call   <pop_to_long@plt>
  sub    %rax,%rbp
  sub    $0x1,%ebx
  jne    L11
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <push_from_long@plt>
  nopl   (%rax)
L13:
  xor    %edi,%edi
  jmp    1060 <push_from_long@plt>
  nop
L10:
  call   <pop_to_long@plt>
  add    $0x8,%rsp
  neg    %rax
  pop    %rbx
  pop    %rbp
  mov    %rax,%rdi
  jmp    1060 <push_from_long@plt>
```

assistant: ```c
void builtin_minus(struct Context *ctx, unsigned int stack_track) {
  if (stack_track == 0) {
    push_from_long(0L);
    return;
  }
  if (stack_track == 1) {
    push_from_long(-(pop_to_long()));
    return;
  }
  long result = pop_to_long();
  for (stack_track--; stack_track; stack_track--)
    result -= pop_to_long();
  push_from_long(result);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<c_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L29:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L39:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L32
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  ja     L33
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L33:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  sub    $0x1,%rax
  leave
  ret
```

assistant: ```c
size_t c_strlcpy(char *dst, const char *src, size_t size) {
  size_t len = 0;
  while (++len < size && *src) {
    *dst++ = *src++;
  }
  if (len <= size) {
    *dst = 0;
  }
  return len + strlen(src) - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<c_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    $0x1,%ebx
  cmp    $0x1,%rdx
  jbe    L10
L33:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L10
  add    $0x1,%rdi
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L33
L30:
  movb   $0x0,(%rax)
  mov    %rdx,%rbx
L20:
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
L10:
  cmp    %rbx,%rdx
  jb     L20
  mov    %rbx,%rdx
  jmp    L30
```

assistant: ```c
size_t c_strlcpy(char *dst, const char *src, size_t size) {
  size_t len = 0;
  while (++len < size && *src) {
    *dst++ = *src++;
  }
  if (len <= size) {
    *dst = 0;
  }
  return len + strlen(src) - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<c_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    $0x1,%ebx
  mov    %rsi,%rdi
  cmp    $0x1,%rdx
  ja     L25
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rbx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %cl,-0x1(%rax)
  cmp    %rdx,%rbx
  je     L27
L25:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L14
L27:
  movb   $0x0,(%rax)
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
L21:
  test   %rdx,%rdx
  jne    L27
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t c_strlcpy(char *dst, const char *src, size_t size) {
  size_t len = 0;
  while (++len < size && *src) {
    *dst++ = *src++;
  }
  if (len <= size) {
    *dst = 0;
  }
  return len + strlen(src) - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<c_strlcpy>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    $0x1,%ebx
  mov    %rsi,%rdi
  cmp    $0x1,%rdx
  ja     L28
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
  add    $0x1,%rax
  add    $0x1,%rdi
  mov    %cl,-0x1(%rax)
  cmp    %rdx,%rbx
  je     L40
L28:
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L31
L40:
  movb   $0x0,(%rax)
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
L48:
  test   %rdx,%rdx
  jne    L40
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t c_strlcpy(char *dst, const char *src, size_t size) {
  size_t len = 0;
  while (++len < size && *src) {
    *dst++ = *src++;
  }
  if (len <= size) {
    *dst = 0;
  }
  return len + strlen(src) - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x4(%rbp)
  je     L0
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <p>
L0:
  nop
  leave
  ret
```

assistant: ```c
p(int a) {
  printf(a);
  if (a) {
    p(a - 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<p>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movslq %edi,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L19
L9:
  pop    %rbx
  ret
L19:
  lea    -0x1(%rbx),%edi
  call   <p>
  jmp    L9
```

assistant: ```c
p(int a) {
  printf(a);
  if (a) {
    p(a - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<p>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  mov    %edi,%edi
  mov    %rbx,%rbp
  sub    %rdi,%rbp
  sub    $0x8,%rsp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L16:
  sub    $0x1,%rbx
L5:
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
p(int a) {
  printf(a);
  if (a) {
    p(a - 1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<p>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  mov    %edi,%edi
  mov    %rbx,%rbp
  sub    %rdi,%rbp
  sub    $0x8,%rsp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rbx
L12:
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
p(int a) {
  printf(a);
  if (a) {
    p(a - 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L0:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <display_progress@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x30d40,%edi
  call   <usleep@plt>
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x64,-0x8(%rbp)
  jle    L0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D4: progress:  

tool: D19: 


assistant: ```c
int main(void) {
  int i = 0;
  int ret = 0;
  printf("progress:  ");
  for (i = 0; i < 101; i++) {
    ret = display_progress(i, ret);
    usleep(1000 * 200);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L4:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <display_progress@plt>
  mov    %eax,%ebp
  mov    $0x30d40,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L4
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D1: progress:  

tool: D3: 


assistant: ```c
int main(void) {
  int i = 0;
  int ret = 0;
  printf("progress:  ");
  for (i = 0; i < 101; i++) {
    ret = display_progress(i, ret);
    usleep(1000 * 200);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%esi
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <display_progress@plt>
  mov    $0x30d40,%edi
  mov    %eax,%ebp
  call   <usleep@plt>
  cmp    $0x65,%ebx
  jne    L5
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D17
type_guessed: string

tool: D10: progress:  

tool: D17: 


assistant: ```c
int main(void) {
  int i = 0;
  int ret = 0;
  printf("progress:  ");
  for (i = 0; i < 101; i++) {
    ret = display_progress(i, ret);
    usleep(1000 * 200);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebp,%esi
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <display_progress@plt>
  mov    $0x30d40,%edi
  mov    %eax,%ebp
  call   <usleep@plt>
  cmp    $0x65,%ebx
  jne    L3
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D10: progress:  

tool: D8: 


assistant: ```c
int main(void) {
  int i = 0;
  int ret = 0;
  printf("progress:  ");
  for (i = 0; i < 101; i++) {
    ret = display_progress(i, ret);
    usleep(1000 * 200);
  }
  printf("\n");
  return 0;
}
```