ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<sxy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x30(%rbp),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double sxy(const double *x, const double *y, int n, double meanX, double meanY) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += (x[i] - meanX) * (y[i] - meanY);
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<sxy>:
  endbr64
  movapd %xmm0,%xmm4
  test   %edx,%edx
  jle    L7
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
L14:
  movsd  (%rdi,%rax,8),%xmm2
  subsd  %xmm4,%xmm2
  movsd  (%rsi,%rax,8),%xmm3
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L14
  ret
L7:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double sxy(const double *x, const double *y, int n, double meanX, double meanY) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += (x[i] - meanX) * (y[i] - meanY);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sxy>:
  endbr64
  movapd %xmm0,%xmm4
  test   %edx,%edx
  jle    L19
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  nopl   (%rax)
L6:
  movsd  (%rdi,%rax,8),%xmm2
  movsd  (%rsi,%rax,8),%xmm3
  add    $0x1,%rax
  subsd  %xmm4,%xmm2
  subsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L6
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double sxy(const double *x, const double *y, int n, double meanX, double meanY) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += (x[i] - meanX) * (y[i] - meanY);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sxy>:
  endbr64
  mov    %rdi,%rcx
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm5
  test   %edx,%edx
  jle    L49
  cmp    $0x1,%edx
  je     L41
  mov    %edx,%edi
  movapd %xmm0,%xmm6
  unpcklpd %xmm1,%xmm1
  xor    %eax,%eax
  shr    %edi
  unpcklpd %xmm6,%xmm6
  pxor   %xmm0,%xmm0
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L5:
  movupd (%rcx,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  subpd  %xmm6,%xmm2
  subpd  %xmm1,%xmm3
  mulpd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  unpckhpd %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rdi
  jne    L5
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L33
L14:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  movsd  (%rcx,%rax,8),%xmm2
  subsd  %xmm5,%xmm1
  subsd  %xmm4,%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  ret
  nopl   0x0(%rax)
L49:
  pxor   %xmm0,%xmm0
  ret
L41:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L14
```

assistant: ```c
double sxy(const double *x, const double *y, int n, double meanX, double meanY) {
  int i;
  double sum = 0.0;
  for (i = 0; i < n; i++)
    sum += (x[i] - meanX) * (y[i] - meanY);
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0xb,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x7,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0xd,-0x10(%rbp)
  movl   $0x29,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <izbaci_prost@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L9
L25:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L9:
  cmpl   $0x9,-0x34(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %d

assistant: ```c
int main() {
  int niz[10] = {1, 11, 5, 4, 7, 2, 3, 8, 13, 41};
  izbaci_prost(niz, 8);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d", niz[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0xb,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0xd,0x20(%rsp)
  movl   $0x29,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <izbaci_prost@plt>
  lea    0x28(%rsp),%r12
  lea    D2(%rip),%rbp
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L5
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main() {
  int niz[10] = {1, 11, 5, 4, 7, 2, 3, 8, 13, 41};
  izbaci_prost(niz, 8);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d", niz[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xb00000001,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000007,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x290000000d,%rax
  mov    %rax,0x20(%rsp)
  call   <izbaci_prost@plt>
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  int niz[10] = {1, 11, 5, 4, 7, 2, 3, 8, 13, 41};
  izbaci_prost(niz, 8);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d", niz[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D11(%rip),%rax
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <izbaci_prost@plt>
  nopl   (%rax)
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: byte[16]
name: parse_data
arguments: data_tag: D11
type_infered: byte[8]
name: parse_data
arguments: data_tag: D26
type_infered: byte[16]

tool: D32: %d

tool: {"D17": [0x01,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D11": [0x0d,0x00,0x00,0x00,0x29,0x00,0x00,0x00]}

tool: {"D26": [0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int niz[10] = {1, 11, 5, 4, 7, 2, 3, 8, 13, 41};
  izbaci_prost(niz, 8);
  int i;
  for (i = 0; i < 10; i++)
    printf("%d", niz[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L18:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int length(char *p) {
  int n;
  n = 0;
  while (*p != 0) {
    n++;
    p++;
  }
  return (n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L25
  mov    %rdi,%rax
  mov    $0x1,%edx
  sub    %edi,%edx
L28:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L28
L9:
  mov    %ecx,%eax
  ret
L25:
  mov    $0x0,%ecx
  jmp    L9
```

assistant: ```c
int length(char *p) {
  int n;
  n = 0;
  while (*p != 0) {
    n++;
    p++;
  }
  return (n);
}
```
user: What is the c source code of the assembly code below?

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  sub    %edi,%eax
L6:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length(char *p) {
  int n;
  n = 0;
  while (*p != 0) {
    n++;
    p++;
  }
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<length>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  mov    $0x1,%eax
  sub    %edi,%eax
L13:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L13
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int length(char *p) {
  int n;
  n = 0;
  while (*p != 0) {
    n++;
    p++;
  }
  return (n);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_register>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x70,%edi
  mov    $0x0,%eax
  call   <outb@plt>
  mov    $0x71,%edi
  mov    $0x0,%eax
  call   <inb@plt>
  leave
  ret
```

assistant: ```c
int read_register(reg_addr)
char reg_addr;
{
  outb(0x70, reg_addr);
  return inb(0x71);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_register>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%esi
  mov    $0x70,%edi
  mov    $0x0,%eax
  call   <outb@plt>
  mov    $0x71,%edi
  mov    $0x0,%eax
  call   <inb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_register(reg_addr)
char reg_addr;
{
  outb(0x70, reg_addr);
  return inb(0x71);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_register>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%esi
  xor    %eax,%eax
  mov    $0x70,%edi
  call   <outb@plt>
  mov    $0x71,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
int read_register(reg_addr)
char reg_addr;
{
  outb(0x70, reg_addr);
  return inb(0x71);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_register>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%esi
  xor    %eax,%eax
  mov    $0x70,%edi
  call   <outb@plt>
  mov    $0x71,%edi
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <inb@plt>
```

assistant: ```c
int read_register(reg_addr)
char reg_addr;
{
  outb(0x70, reg_addr);
  return inb(0x71);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L26
L80:
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  je     L92
  movsd  D47(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x1,-0x3c(%rbp)
  jmp    L24
L1:
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm2
  addsd  %xmm0,%xmm2
  movsd  D27(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D27(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L62
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L62:
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L38
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L38
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L38
  movsd  -0x38(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
L38:
  addl   $0x1,-0x3c(%rbp)
L24:
  mov    -0x40(%rbp),%eax
  cmp    %eax,-0x3c(%rbp)
  jle    L1
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L80
  jmp    L39
L92:
  nop
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D47
data_type: byte[8]
name: parse_data
arguments: data_tag: D44
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: f64
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D57
data_type: string

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D44: %lf %lf %lf

tool: D27: 9.8

tool: D13: %.0lf


tool: D57: %d

assistant: ```c
int main() {
  int n, i;
  double l, w, h, vol, down;
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    double max = -1.0;
    vol = 0;
    for (i = 1; i <= n; i++) {
      scanf("%lf %lf %lf", &l, &w, &h);
      down = 9.8 - (9.8 / (2 * h));
      if (down > max) {
        max = down;
        vol = l * w * h;
      }
      if (down == max) {
        if (l * w * h > vol)
          vol = l * w * h;
      }
    }
    printf("%.0lf\n", vol);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D61(%rip),%r15
  lea    D65(%rip),%r14
  jmp    L60
L106:
  movsd  0x8(%rsp),%xmm4
  ucomisd %xmm4,%xmm1
  jp     L88
  jne    L88
  movsd  0x20(%rsp),%xmm1
  mulsd  0x28(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  movq   %rbp,%xmm5
  maxsd  %xmm5,%xmm1
  movq   %xmm1,%rbp
L88:
  add    $0x1,%ebx
  cmp    %ebx,0x1c(%rsp)
  jl     L6
L46:
  lea    0x20(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x30(%rsp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  D2(%rip),%xmm2
  divsd  %xmm1,%xmm2
  movsd  D2(%rip),%xmm1
  subsd  %xmm2,%xmm1
  comisd 0x8(%rsp),%xmm1
  jbe    L106
  movsd  0x20(%rsp),%xmm2
  mulsd  0x28(%rsp),%xmm2
  mulsd  %xmm0,%xmm2
  movq   %xmm2,%rbp
  movsd  %xmm1,0x8(%rsp)
  jmp    L88
L67:
  mov    D50(%rip),%rbp
L6:
  movq   %rbp,%xmm0
  lea    D18(%rip),%rdi
  call   <printf@plt>
L60:
  lea    0x1c(%rsp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jne    L70
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L70
  jle    L67
  movsd  D44(%rip),%xmm6
  movsd  %xmm6,0x8(%rsp)
  mov    D50(%rip),%rbp
  lea    0x30(%rsp),%r13
  lea    0x28(%rsp),%r12
  jmp    L46
L70:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D61
datatype: string
name: extract_symbolic_data
arguments: tag: D65
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: f64
name: extract_symbolic_data
arguments: tag: D50
datatype: byte[8]
name: extract_symbolic_data
arguments: tag: D18
datatype: string
name: extract_symbolic_data
arguments: tag: D44
datatype: byte[8]

tool: D61: %d

tool: D65: %lf %lf %lf

tool: D2: 9.8

tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D18: %.0lf


tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

assistant: ```c
int main() {
  int n, i;
  double l, w, h, vol, down;
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    double max = -1.0;
    vol = 0;
    for (i = 1; i <= n; i++) {
      scanf("%lf %lf %lf", &l, &w, &h);
      down = 9.8 - (9.8 / (2 * h));
      if (down > max) {
        max = down;
        vol = l * w * h;
      }
      if (down == max) {
        if (l * w * h > vol)
          vol = l * w * h;
      }
    }
    printf("%.0lf\n", vol);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r15
  xchg   %ax,%ax
L37:
  mov    %r15,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%r14d
  cmp    $0x1,%eax
  jne    L74
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L74
  jle    L40
  mov    D45(%rip),%rax
  pxor   %xmm6,%xmm6
  lea    0x30(%rsp),%r12
  lea    0x28(%rsp),%rbp
  movsd  %xmm6,0x8(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rax,(%rsp)
  jmp    L84
  nopl   (%rax)
L50:
  movsd  0x20(%rsp),%xmm2
  mulsd  0x28(%rsp),%xmm2
  movsd  %xmm1,(%rsp)
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
L88:
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jl     L102
L84:
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movsd  0x30(%rsp),%xmm0
  movsd  D38(%rip),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movsd  D38(%rip),%xmm1
  subsd  %xmm2,%xmm1
  comisd (%rsp),%xmm1
  ja     L50
  ucomisd (%rsp),%xmm1
  jp     L88
  jne    L88
  movsd  0x20(%rsp),%xmm1
  mulsd  0x28(%rsp),%xmm1
  add    $0x1,%r14d
  mulsd  %xmm0,%xmm1
  maxsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  cmp    %r14d,0x1c(%rsp)
  jge    L84
L102:
  movsd  0x8(%rsp),%xmm0
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L37
  nopl   (%rax)
L74:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L102
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D45
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D38
type_guessed: f64
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D18: %lf %lf %lf

tool: D19: %d

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D38: 9.8

tool: D13: %.0lf


assistant: ```c
int main() {
  int n, i;
  double l, w, h, vol, down;
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    double max = -1.0;
    vol = 0;
    for (i = 1; i <= n; i++) {
      scanf("%lf %lf %lf", &l, &w, &h);
      down = 9.8 - (9.8 / (2 * h));
      if (down > max) {
        max = down;
        vol = l * w * h;
      }
      if (down == max) {
        if (l * w * h > vol)
          vol = l * w * h;
      }
    }
    printf("%.0lf\n", vol);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D40(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%r15
  xchg   %ax,%ax
L100:
  mov    %r15,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%r14d
  cmp    $0x1,%eax
  jne    L52
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L52
  jle    L51
  mov    D36(%rip),%rax
  pxor   %xmm6,%xmm6
  lea    0x30(%rsp),%r12
  lea    0x28(%rsp),%rbp
  movsd  %xmm6,0x8(%rsp)
  lea    0x20(%rsp),%rbx
  mov    %rax,(%rsp)
  jmp    L117
  nopl   (%rax)
L110:
  movsd  0x20(%rsp),%xmm2
  mulsd  0x28(%rsp),%xmm2
  movsd  %xmm1,(%rsp)
  mulsd  %xmm0,%xmm2
  movsd  %xmm2,0x8(%rsp)
L17:
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jl     L42
L117:
  xor    %eax,%eax
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movsd  0x30(%rsp),%xmm0
  movsd  D30(%rip),%xmm2
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm2
  movsd  D30(%rip),%xmm1
  subsd  %xmm2,%xmm1
  comisd (%rsp),%xmm1
  ja     L110
  ucomisd (%rsp),%xmm1
  jp     L17
  jne    L17
  movsd  0x20(%rsp),%xmm1
  mulsd  0x28(%rsp),%xmm1
  add    $0x1,%r14d
  mulsd  %xmm0,%xmm1
  maxsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  cmp    %r14d,0x1c(%rsp)
  jge    L117
L42:
  movsd  0x8(%rsp),%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L100
  nopl   (%rax)
L52:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L51:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L42
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D40
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D36
datatype: byte[8]
name: retrieve_data
arguments: data_label: D30
datatype: f64
name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D40: %lf %lf %lf

tool: D13: %d

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: D30: 9.8

tool: D2: %.0lf


assistant: ```c
int main() {
  int n, i;
  double l, w, h, vol, down;
  while (scanf("%d", &n) == 1) {
    if (n == 0)
      break;
    double max = -1.0;
    vol = 0;
    for (i = 1; i <= n; i++) {
      scanf("%lf %lf %lf", &l, &w, &h);
      down = 9.8 - (9.8 / (2 * h));
      if (down > max) {
        max = down;
        vol = l * w * h;
      }
      if (down == max) {
        if (l * w * h > vol)
          vol = l * w * h;
      }
    }
    printf("%.0lf\n", vol);
  }
  return 0;
}
```