ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D40(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  add    0xc(%rsp),%esi
  add    0x14(%rsp),%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D36
type_infered: string
name: retrieve_data
arguments: label: D40
type_infered: string
name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D49
type_infered: string
name: retrieve_data
arguments: label: D30
type_infered: string

tool: D36: Insira o primeiro valor: 

tool: D40: %d

tool: D28: Insira o segundo valor: 

tool: D49: Insira o terceiro valor: 

tool: D30: Soma: %d


assistant: ```c
int main() {
  int valor1, valor2, valor3;
  printf("Insira o primeiro valor: ");
  scanf("%d", &valor1);
  printf("Insira o segundo valor: ");
  scanf("%d", &valor2);
  printf("Insira o terceiro valor: ");
  scanf("%d", &valor3);
  int soma = valor1 + valor2 + valor3;
  printf("Soma: %d\n", soma);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D46(%rip),%rdi
  lea    D39(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  add    0xc(%rsp),%esi
  lea    D38(%rip),%rdi
  add    0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D46
datatype: string
name: read_data
arguments: tag: D39
datatype: string
name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D23
datatype: string
name: read_data
arguments: tag: D38
datatype: string

tool: D46: Insira o primeiro valor: 

tool: D39: %d

tool: D14: Insira o segundo valor: 

tool: D23: Insira o terceiro valor: 

tool: D38: Soma: %d


assistant: ```c
int main() {
  int valor1, valor2, valor3;
  printf("Insira o primeiro valor: ");
  scanf("%d", &valor1);
  printf("Insira o segundo valor: ");
  scanf("%d", &valor2);
  printf("Insira o terceiro valor: ");
  scanf("%d", &valor3);
  int soma = valor1 + valor2 + valor3;
  printf("Soma: %d\n", soma);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D49(%rip),%rdi
  lea    D38(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  xor    %eax,%eax
  add    0xc(%rsp),%esi
  lea    D47(%rip),%rdi
  add    0x14(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D49
data_type: string
name: retrieve_data
arguments: data_label: D38
data_type: string
name: retrieve_data
arguments: data_label: D43
data_type: string
name: retrieve_data
arguments: data_label: D33
data_type: string
name: retrieve_data
arguments: data_label: D47
data_type: string

tool: D49: Insira o primeiro valor: 

tool: D38: %d

tool: D43: Insira o segundo valor: 

tool: D33: Insira o terceiro valor: 

tool: D47: Soma: %d


assistant: ```c
int main() {
  int valor1, valor2, valor3;
  printf("Insira o primeiro valor: ");
  scanf("%d", &valor1);
  printf("Insira o segundo valor: ");
  scanf("%d", &valor2);
  printf("Insira o terceiro valor: ");
  scanf("%d", &valor3);
  int soma = valor1 + valor2 + valor3;
  printf("Soma: %d\n", soma);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<honai>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L16
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <f@plt>
  add    %eax,%eax
  add    $0x3,%eax
  jmp    L6
L16:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <honai>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <f@plt>
  add    %eax,%eax
  add    %ebx,%eax
  add    $0x3,%eax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int honai(int in) {
  if (in == 1) {
    return 2 * f(in - 1) + 3;
  } else {
    return honai(in - 1) + 2 * f(in - 1) + 3;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<honai>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L7
  lea    -0x1(%rdi),%ebx
  mov    %ebx,%edi
  call   <honai>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    $0x0,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%eax
  jmp    L10
```

assistant: ```c
int honai(int in) {
  if (in == 1) {
    return 2 * f(in - 1) + 3;
  } else {
    return honai(in - 1) + 2 * f(in - 1) + 3;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<honai>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  je     L10
  lea    -0x1(%rdi),%r12d
  cmp    $0x2,%edi
  je     L11
  lea    -0x2(%rdi),%r13d
  cmp    $0x3,%edi
  je     L42
  lea    -0x3(%rdi),%r14d
  cmp    $0x4,%edi
  je     L63
  lea    -0x4(%rdi),%r15d
  cmp    $0x5,%edi
  je     L73
  lea    -0x5(%rdi),%r8d
  mov    %r8d,0xc(%rsp)
  cmp    $0x6,%edi
  je     L82
  lea    -0x6(%rdi),%ebp
  mov    %ebp,%edi
  call   <honai>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <f@plt>
  mov    0xc(%rsp),%r8d
  lea    0x3(%rbx,%rax,2),%ebx
L106:
  mov    %r8d,%edi
  call   <f@plt>
  lea    0x3(%rbx,%rax,2),%ebp
L105:
  mov    %r15d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
L79:
  mov    %r14d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
L2:
  mov    %r13d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
  jmp    L54
  nop
L11:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
L54:
  mov    %r12d,%edi
  call   <f@plt>
  add    $0x18,%rsp
  pop    %rbx
  lea    0x3(%rbp,%rax,2),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  xor    %edi,%edi
  call   <f@plt>
  add    $0x18,%rsp
  pop    %rbx
  lea    0x3(%rax,%rax,1),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L79
  nopl   (%rax)
L42:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L2
  nopl   (%rax)
L73:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L105
L82:
  xor    %edi,%edi
  call   <f@plt>
  mov    0xc(%rsp),%r8d
  lea    0x3(%rax,%rax,1),%ebx
  jmp    L106
```

assistant: ```c
int honai(int in) {
  if (in == 1) {
    return 2 * f(in - 1) + 3;
  } else {
    return honai(in - 1) + 2 * f(in - 1) + 3;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<honai>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%edi
  je     L24
  lea    -0x1(%rdi),%r12d
  cmp    $0x2,%edi
  je     L70
  lea    -0x2(%rdi),%r13d
  cmp    $0x3,%edi
  je     L74
  lea    -0x3(%rdi),%r14d
  cmp    $0x4,%edi
  je     L47
  lea    -0x4(%rdi),%r15d
  cmp    $0x5,%edi
  je     L96
  lea    -0x5(%rdi),%r8d
  mov    %r8d,0xc(%rsp)
  cmp    $0x6,%edi
  je     L87
  lea    -0x6(%rdi),%ebp
  mov    %ebp,%edi
  call   <honai>
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <f@plt>
  mov    0xc(%rsp),%r8d
  lea    0x3(%rbx,%rax,2),%ebx
L76:
  mov    %r8d,%edi
  call   <f@plt>
  lea    0x3(%rbx,%rax,2),%ebp
L33:
  mov    %r15d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
L10:
  mov    %r14d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
L39:
  mov    %r13d,%edi
  call   <f@plt>
  lea    0x3(%rbp,%rax,2),%ebp
  jmp    L53
  nop
L70:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
L53:
  mov    %r12d,%edi
  call   <f@plt>
  add    $0x18,%rsp
  pop    %rbx
  lea    0x3(%rbp,%rax,2),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  xor    %edi,%edi
  call   <f@plt>
  add    $0x18,%rsp
  pop    %rbx
  lea    0x3(%rax,%rax,1),%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L10
  nopl   (%rax)
L74:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L39
  nopl   (%rax)
L96:
  xor    %edi,%edi
  call   <f@plt>
  lea    0x3(%rax,%rax,1),%ebp
  jmp    L33
L87:
  xor    %edi,%edi
  call   <f@plt>
  mov    0xc(%rsp),%r8d
  lea    0x3(%rax,%rax,1),%ebx
  jmp    L76
```

assistant: ```c
int honai(int in) {
  if (in == 1) {
    return 2 * f(in - 1) + 3;
  } else {
    return honai(in - 1) + 2 * f(in - 1) + 3;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<random_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L17:
  mov    $0x0,%eax
  call   <mrand48@plt>
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void random_bytes(unsigned char *buf, int len) {
  int i;
  for (i = 0; i < len; ++i)
    buf[i] = mrand48() >> 24;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L7:
  mov    $0x0,%eax
  call   <mrand48@plt>
  sar    $0x18,%eax
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  ret
```

assistant: ```c
void random_bytes(unsigned char *buf, int len) {
  int i;
  for (i = 0; i < len; ++i)
    buf[i] = mrand48() >> 24;
}
```
user: Translate the below assembly code into C programming language:

```asm
<random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <mrand48@plt>
  sar    $0x18,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  ret
```

assistant: ```c
void random_bytes(unsigned char *buf, int len) {
  int i;
  for (i = 0; i < len; ++i)
    buf[i] = mrand48() >> 24;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<random_bytes>:
  endbr64
  test   %esi,%esi
  jle    L7
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <mrand48@plt>
  sar    $0x18,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  ret
```

assistant: ```c
void random_bytes(unsigned char *buf, int len) {
  int i;
  for (i = 0; i < len; ++i)
    buf[i] = mrand48() >> 24;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<l_to_a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    -0x60(%rbp),%rax
  add    $0x41,%rax
  mov    %rax,-0x68(%rbp)
  cmpl   $0x23,-0x7c(%rbp)
  jle    L53
  cmpl   $0x1,-0x7c(%rbp)
  jg     L24
L53:
  movl   $0xa,-0x7c(%rbp)
L24:
  cmpq   $0x0,-0x78(%rbp)
  jns    L8
  mov    -0x70(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x70(%rbp)
  movb   $0x2d,(%rax)
  negq   -0x78(%rbp)
L8:
  lea    -0x60(%rbp),%rax
  add    $0x41,%rax
  mov    %rax,-0x68(%rbp)
  subq   $0x1,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  movb   $0x0,(%rax)
L56:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  mov    %eax,%ebx
  cmp    $0x9,%ebx
  jg     L64
  mov    %ebx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  jmp    L30
L64:
  mov    %ebx,%eax
  add    $0x57,%eax
  mov    %eax,%edx
L30:
  subq   $0x1,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x78(%rbp)
  cmpq   $0x0,-0x78(%rbp)
  jne    L56
  mov    -0x68(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D1(%rip),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *l_to_a(long N, int base) {
  static char ret[(sizeof(long) * 8 + 1)];
  char *head = ret, buf[(sizeof(long) * 8 + 1)], *tail = buf + sizeof(buf);
  register int divrem;
  if (base < 36 || 2 > base)
    base = 10;
  if (N < 0) {
    *head++ = '-';
    N = -N;
  }
  tail = buf + sizeof(buf);
  *--tail = 0;
  do {
    divrem = N % base;
    *--tail = (divrem <= 9) ? divrem + '0' : divrem + 'a' - 10;
    N /= base;
  } while (N);
  strcpy(head, tail);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<l_to_a>:
  endbr64
  sub    $0x58,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0x23,%esi
  mov    $0xa,%eax
  cmovle %eax,%esi
  lea    D24(%rip),%r9
  test   %rdi,%rdi
  js     L28
L8:
  movb   $0x0,0x40(%rsp)
  lea    0x40(%rsp),%rdi
  movslq %esi,%rsi
L3:
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  lea    0x30(%rdx),%r8d
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %r8d,%eax
  sub    $0x1,%rdi
  mov    %al,(%rdi)
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  mov    %rax,%rcx
  test   %rax,%rax
  jne    L3
  mov    %rdi,%rsi
  mov    %r9,%rdi
  call   <strcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    D24(%rip),%rax
  add    $0x58,%rsp
  ret
L28:
  movb   $0x2d,D24(%rip)
  neg    %rcx
  lea    0x1(%r9),%r9
  jmp    L8
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_to_a(long N, int base) {
  static char ret[(sizeof(long) * 8 + 1)];
  char *head = ret, buf[(sizeof(long) * 8 + 1)], *tail = buf + sizeof(buf);
  register int divrem;
  if (base < 36 || 2 > base)
    base = 10;
  if (N < 0) {
    *head++ = '-';
    N = -N;
  }
  tail = buf + sizeof(buf);
  *--tail = 0;
  do {
    divrem = N % base;
    *--tail = (divrem <= 9) ? divrem + '0' : divrem + 'a' - 10;
    N /= base;
  } while (N);
  strcpy(head, tail);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<l_to_a>:
  endbr64
  push   %r12
  mov    %rdi,%rax
  lea    D13(%rip),%r12
  mov    %r12,%r9
  sub    $0x50,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  cmp    $0x23,%esi
  mov    $0xa,%edx
  cmovle %edx,%esi
  movslq %esi,%rdi
  test   %rax,%rax
  jns    L13
  movb   $0x2d,D13(%rip)
  neg    %rax
  add    $0x1,%r9
L13:
  movb   $0x0,0x40(%rsp)
  lea    0x40(%rsp),%rsi
  nopw   0x0(%rax,%rax,1)
L16:
  cqto
  idiv   %rdi
  cmp    $0x9,%rdx
  lea    0x30(%rdx),%r8d
  lea    0x57(%rdx),%ecx
  cmovle %r8d,%ecx
  sub    $0x1,%rsi
  mov    %cl,(%rsi)
  test   %rax,%rax
  jne    L16
  mov    %r9,%rdi
  call   <strcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_to_a(long N, int base) {
  static char ret[(sizeof(long) * 8 + 1)];
  char *head = ret, buf[(sizeof(long) * 8 + 1)], *tail = buf + sizeof(buf);
  register int divrem;
  if (base < 36 || 2 > base)
    base = 10;
  if (N < 0) {
    *head++ = '-';
    N = -N;
  }
  tail = buf + sizeof(buf);
  *--tail = 0;
  do {
    divrem = N % base;
    *--tail = (divrem <= 9) ? divrem + '0' : divrem + 'a' - 10;
    N /= base;
  } while (N);
  strcpy(head, tail);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<l_to_a>:
  endbr64
  push   %r12
  mov    %rdi,%rax
  lea    D16(%rip),%r12
  mov    %r12,%rdi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rdx
  mov    %rdx,0x48(%rsp)
  xor    %edx,%edx
  cmp    $0x23,%esi
  mov    $0xa,%edx
  cmovle %edx,%esi
  movslq %esi,%rcx
  test   %rax,%rax
  jns    L49
  movb   $0x2d,D16(%rip)
  neg    %rax
  add    $0x1,%rdi
L49:
  movb   $0x0,0x40(%rsp)
  lea    0x40(%rsp),%rsi
  nopw   0x0(%rax,%rax,1)
L22:
  cqto
  sub    $0x1,%rsi
  idiv   %rcx
  cmp    $0x9,%rdx
  jg     L53
  add    $0x30,%edx
  mov    %dl,(%rsi)
  test   %rax,%rax
  jne    L22
L29:
  call   <strcpy@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x50,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L53:
  add    $0x57,%edx
  mov    %dl,(%rsi)
  test   %rax,%rax
  jne    L22
  jmp    L29
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *l_to_a(long N, int base) {
  static char ret[(sizeof(long) * 8 + 1)];
  char *head = ret, buf[(sizeof(long) * 8 + 1)], *tail = buf + sizeof(buf);
  register int divrem;
  if (base < 36 || 2 > base)
    base = 10;
  if (N < 0) {
    *head++ = '-';
    N = -N;
  }
  tail = buf + sizeof(buf);
  *--tail = 0;
  do {
    divrem = N % base;
    *--tail = (divrem <= 9) ? divrem + '0' : divrem + 'a' - 10;
    N /= base;
  } while (N);
  strcpy(head, tail);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <sincos@plt>
  movsd  -0x20(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double g(double x) {
  _Complex double c = __builtin_cexpi(x);
  return __builtin_creal(c);
}
```
user: What is the c source code of the assembly code below:

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  call   <cos@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double g(double x) {
  _Complex double c = __builtin_cexpi(x);
  return __builtin_creal(c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<g>:
  endbr64
  jmp    1050 <cos@plt>
```

assistant: ```c
double g(double x) {
  _Complex double c = __builtin_cexpi(x);
  return __builtin_creal(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  jmp    1050 <cos@plt>
```

assistant: ```c
double g(double x) {
  _Complex double c = __builtin_cexpi(x);
  return __builtin_creal(c);
}
```
user: What is the c source code of the assembly code below?

```asm
<getl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%r13
  mov    -0x34(%rbp),%ebx
  jmp    L29
L6:
  mov    %r13,%rax
  lea    0x1(%rax),%r13
  mov    %r12d,%edx
  mov    %dl,(%rax)
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jle    L3
  cmp    $0xa,%r12d
  je     L3
L29:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <getc@plt>
  mov    %eax,%r12d
  test   %r12d,%r12d
  jns    L6
L3:
  mov    -0x34(%rbp),%eax
  sub    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
getl(bufp, line, cnt) struct iobuf *bufp;
char line[];
int cnt;
{
  register char *lp;
  register c, cc;
  lp = line;
  cc = cnt;
  while ((c = getc(bufp)) >= 0) {
    *lp++ = c;
    if (--cc <= 0 || c == '\n')
      break;
  }
  return (cnt - cc);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%r12d
  mov    %rsi,%rbx
  mov    %edx,%r13d
L29:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <getc@plt>
  test   %eax,%eax
  js     L19
  mov    %al,(%rbx)
  sub    $0x1,%r13d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L19
  test   %r13d,%r13d
  jg     L29
L19:
  mov    %r12d,%eax
  sub    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
getl(bufp, line, cnt) struct iobuf *bufp;
char line[];
int cnt;
{
  register char *lp;
  register c, cc;
  lp = line;
  cc = cnt;
  while ((c = getc(bufp)) >= 0) {
    *lp++ = c;
    if (--cc <= 0 || c == '\n')
      break;
  }
  return (cnt - cc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getl>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L5
  nopl   0x0(%rax)
L33:
  mov    %al,(%rbx)
  sub    $0x1,%r13d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L14
  test   %r13d,%r13d
  jle    L14
L5:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <getc@plt>
  test   %eax,%eax
  jns    L33
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  sub    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
getl(bufp, line, cnt) struct iobuf *bufp;
char line[];
int cnt;
{
  register char *lp;
  register c, cc;
  lp = line;
  cc = cnt;
  while ((c = getc(bufp)) >= 0) {
    *lp++ = c;
    if (--cc <= 0 || c == '\n')
      break;
  }
  return (cnt - cc);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getl>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax)
L31:
  mov    %al,(%rbx)
  sub    $0x1,%r13d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L15
  test   %r13d,%r13d
  jle    L15
L37:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <getc@plt>
  test   %eax,%eax
  jns    L31
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  sub    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
getl(bufp, line, cnt) struct iobuf *bufp;
char line[];
int cnt;
{
  register char *lp;
  register c, cc;
  lp = line;
  cc = cnt;
  while ((c = getc(bufp)) >= 0) {
    *lp++ = c;
    if (--cc <= 0 || c == '\n')
      break;
  }
  return (cnt - cc);
}
```