ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%r8d
  mov    $0x2,%ecx
  xor    %eax,%eax
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D13: a aplus b plusb 

tool: D1: %1d %5d %5d %5d 


assistant: ```c
int main(int argc, char const *argv[]) {
  int a = 1, b = 1;
  int aplus, plusb;
  aplus = a++;
  plusb = ++b;
  printf("a aplus b plusb \n");
  printf("%1d %5d %5d %5d \n", a, aplus, b, plusb);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void read_error(void) {
  do {
  } while (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<read_error>:
  endbr64
  ret
```

assistant: ```c
void read_error(void) {
  do {
  } while (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<read_error>:
  endbr64
  ret
```

assistant: ```c
void read_error(void) {
  do {
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_error>:
  endbr64
  ret
```

assistant: ```c
void read_error(void) {
  do {
  } while (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string

tool: D17: w

tool: D27: Test.txt

tool: D14: Test1.txt

tool: D8: Test2.txt

assistant: ```c
int main(void) {
  FILE *fp = NULL;
  fp = fopen("Test.txt", "w");
  fclose(fp);
  remove("Test1.txt");
  remove("Test2.txt");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D38(%rip),%rdi
  call   <remove@plt>
  lea    D19(%rip),%rdi
  call   <remove@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D38
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D36: w

tool: D17: Test.txt

tool: D38: Test1.txt

tool: D19: Test2.txt

assistant: ```c
int main(void) {
  FILE *fp = NULL;
  fp = fopen("Test.txt", "w");
  fclose(fp);
  remove("Test1.txt");
  remove("Test2.txt");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D4(%rip),%rdi
  call   <remove@plt>
  lea    D16(%rip),%rdi
  call   <remove@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string

tool: D0: w

tool: D19: Test.txt

tool: D4: Test1.txt

tool: D16: Test2.txt

assistant: ```c
int main(void) {
  FILE *fp = NULL;
  fp = fopen("Test.txt", "w");
  fclose(fp);
  remove("Test1.txt");
  remove("Test2.txt");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D21(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    D16(%rip),%rdi
  call   <remove@plt>
  lea    D20(%rip),%rdi
  call   <remove@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string

tool: D21: w

tool: D26: Test.txt

tool: D16: Test1.txt

tool: D20: Test2.txt

assistant: ```c
int main(void) {
  FILE *fp = NULL;
  fp = fopen("Test.txt", "w");
  fclose(fp);
  remove("Test1.txt");
  remove("Test2.txt");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<case_diffs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  sub    $0x41,%eax
  mov    %al,-0x2(%rbp)
  cmpb   $0x19,-0x2(%rbp)
  ja     L38
  addb   $0x61,-0x2(%rbp)
  jmp    L9
L38:
  addb   $0x41,-0x2(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  sub    $0x41,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x19,-0x1(%rbp)
  ja     L14
  addb   $0x61,-0x1(%rbp)
  jmp    L45
L14:
  addb   $0x41,-0x1(%rbp)
L45:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jne    L39
  cmpb   $0x0,-0x2(%rbp)
  je     L72
  jmp    L18
L39:
  nop
  jmp    L49
L72:
  nop
L49:
  movzbl -0x2(%rbp),%eax
  movzbl -0x1(%rbp),%edx
  sub    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int case_diffs(const char *s, const char *t) {
  unsigned char x;
  unsigned char y;
  for (;;) {
    x = *s++ - 'A';
    if (x <= 'Z' - 'A')
      x += 'a';
    else
      x += 'A';
    y = *t++ - 'A';
    if (y <= 'Z' - 'A')
      y += 'a';
    else
      y += 'A';
    if (x != y)
      break;
    if (!x)
      break;
  }
  return ((int)(unsigned int)x) - ((int)(unsigned int)y);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<case_diffs>:
  endbr64
  mov    $0x0,%ecx
L1:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  add    $0x1,%rcx
  test   %al,%al
  je     L19
  cmp    %dl,%al
  je     L1
L19:
  movzbl %al,%eax
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int case_diffs(const char *s, const char *t) {
  unsigned char x;
  unsigned char y;
  for (;;) {
    x = *s++ - 'A';
    if (x <= 'Z' - 'A')
      x += 'a';
    else
      x += 'A';
    y = *t++ - 'A';
    if (y <= 'Z' - 'A')
      y += 'a';
    else
      y += 'A';
    if (x != y)
      break;
    if (!x)
      break;
  }
  return ((int)(unsigned int)x) - ((int)(unsigned int)y);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<case_diffs>:
  endbr64
  xor    %ecx,%ecx
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rcx
  test   %dl,%dl
  je     L17
L21:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L10
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int case_diffs(const char *s, const char *t) {
  unsigned char x;
  unsigned char y;
  for (;;) {
    x = *s++ - 'A';
    if (x <= 'Z' - 'A')
      x += 'a';
    else
      x += 'A';
    y = *t++ - 'A';
    if (y <= 'Z' - 'A')
      y += 'a';
    else
      y += 'A';
    if (x != y)
      break;
    if (!x)
      break;
  }
  return ((int)(unsigned int)x) - ((int)(unsigned int)y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<case_diffs>:
  endbr64
  xor    %ecx,%ecx
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rcx
  test   %dl,%dl
  je     L1
L28:
  movzbl (%rdi,%rcx,1),%eax
  lea    -0x41(%rax),%r8d
  lea    0x20(%rax),%edx
  cmp    $0x1a,%r8b
  cmovb  %edx,%eax
  movzbl (%rsi,%rcx,1),%edx
  lea    -0x41(%rdx),%r9d
  lea    0x20(%rdx),%r8d
  cmp    $0x1a,%r9b
  cmovb  %r8d,%edx
  cmp    %dl,%al
  je     L5
  movzbl %dl,%edx
  movzbl %al,%eax
  sub    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  movzbl %dl,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int case_diffs(const char *s, const char *t) {
  unsigned char x;
  unsigned char y;
  for (;;) {
    x = *s++ - 'A';
    if (x <= 'Z' - 'A')
      x += 'a';
    else
      x += 'A';
    y = *t++ - 'A';
    if (y <= 'Z' - 'A')
      y += 'a';
    else
      y += 'A';
    if (x != y)
      break;
    if (!x)
      break;
  }
  return ((int)(unsigned int)x) - ((int)(unsigned int)y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<apm_time_nosec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffc22e4507,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x10,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  imul   $0x15180,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  imul   $0xe10,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  imul   $0x3c,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1e,-0x8(%rbp)
  jbe    L13
  addq   $0x1,-0x20(%rbp)
L13:
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  cmpq   $0x1,-0x18(%rbp)
  jbe    L10
  lea    D58(%rip),%rax
  jmp    L23
L10:
  lea    D27(%rip),%rax
L23:
  mov    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %rax,%rcx
  lea    D75(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L35
L20:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L35:
  cmpl   $0xffffffff,-0x24(%rbp)
  jne    L43
  lea    D41(%rip),%rax
  mov    %rax,%rsi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L43:
  lea    D54(%rip),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D58
type_infered: string
name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D75
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string

tool: D58: s

tool: 

tool: D75: %lu day%s, %lu:%02lu

tool: D0: %lu:%02lu

tool: D41: unknown

assistant: ```c
const char *apm_time_nosec(time_t t) {
  static char buffer[128];
  unsigned long s, m, h, d;
  d = t / (60 * 60 * 24);
  t -= d * (60 * 60 * 24);
  h = t / (60 * 60);
  t -= h * (60 * 60);
  m = t / (60);
  t -= m * (60);
  s = t;
  if (s > 30)
    ++m;
  if (d)
    sprintf(buffer, "%lu day%s, %lu:%02lu", d, d > 1 ? "s" : "", h, m);
  else
    sprintf(buffer, "%lu:%02lu", h, m);
  if (t == -1)
    sprintf(buffer, "unknown");
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<apm_time_nosec>:
  endbr64
  push   %rbx
  movslq %edi,%rax
  imul   $0xffffffffc22e4507,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x10,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x15180,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0xb,%eax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  movslq %eax,%r8
  imul   $0xe10,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x5,%eax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  movslq %eax,%r9
  imul   $0x3c,%eax,%eax
  mov    %edi,%ebx
  sub    %eax,%ebx
  movslq %ebx,%rax
  cmp    $0x1f,%rax
  sbb    $0xffffffffffffffff,%r9
  test   %rdx,%rdx
  je     L19
  cmp    $0x1,%rdx
  lea    D78(%rip),%rcx
  lea    D26(%rip),%rax
  cmovbe %rax,%rcx
  lea    D50(%rip),%rsi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L22:
  cmp    $0xffffffff,%ebx
  je     L23
L37:
  lea    D69(%rip),%rax
  pop    %rbx
  ret
L19:
  mov    %r9,%rcx
  mov    %r8,%rdx
  lea    D67(%rip),%rsi
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L22
L23:
  movabs $0x6e776f6e6b6e75,%rax
  mov    %rax,D41(%rip)
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: label: D78
type_guessed: string
name: disassemble_data
arguments: label: D26
type_guessed: string
name: disassemble_data
arguments: label: D50
type_guessed: string
name: disassemble_data
arguments: label: D67
type_guessed: string

tool: D78: s

tool: 

tool: D50: %lu day%s, %lu:%02lu

tool: D67: %lu:%02lu

assistant: ```c
const char *apm_time_nosec(time_t t) {
  static char buffer[128];
  unsigned long s, m, h, d;
  d = t / (60 * 60 * 24);
  t -= d * (60 * 60 * 24);
  h = t / (60 * 60);
  t -= h * (60 * 60);
  m = t / (60);
  t -= m * (60);
  s = t;
  if (s > 30)
    ++m;
  if (d)
    sprintf(buffer, "%lu day%s, %lu:%02lu", d, d > 1 ? "s" : "", h, m);
  else
    sprintf(buffer, "%lu:%02lu", h, m);
  if (t == -1)
    sprintf(buffer, "unknown");
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<apm_time_nosec>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  push   %r12
  imul   $0xffffffffc22e4507,%rax,%rax
  sar    $0x1f,%edx
  push   %rbx
  shr    $0x20,%rax
  sub    $0x8,%rsp
  add    %edi,%eax
  sar    $0x10,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x15180,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0xffffffff91a2b3c5,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0xb,%eax
  sub    %ecx,%eax
  movslq %eax,%r8
  imul   $0xe10,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edi,%ebx
  imul   $0xffffffff88888889,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x5,%eax
  sub    %ecx,%eax
  movslq %eax,%r9
  imul   $0x3c,%eax,%eax
  sub    %eax,%ebx
  movslq %ebx,%rax
  cmp    $0x1f,%rax
  sbb    $0xffffffffffffffff,%r9
  test   %rdx,%rdx
  je     L7
  cmp    $0x1,%rdx
  lea    D5(%rip),%rax
  lea    D44(%rip),%rcx
  cmove  %rax,%rcx
  lea    D38(%rip),%r12
  xor    %eax,%eax
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  cmp    $0xffffffff,%ebx
  je     L17
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D38(%rip),%r12
  xor    %eax,%eax
  mov    %r9,%rcx
  mov    %r8,%rdx
  lea    D67(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  cmp    $0xffffffff,%ebx
  jne    L2
L17:
  movabs $0x6e776f6e6b6e75,%rax
  mov    %rax,D20(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D44
data_type: string
name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D67
data_type: string

tool: 

tool: D44: s

tool: D19: %lu day%s, %lu:%02lu

tool: D67: %lu:%02lu

assistant: ```c
const char *apm_time_nosec(time_t t) {
  static char buffer[128];
  unsigned long s, m, h, d;
  d = t / (60 * 60 * 24);
  t -= d * (60 * 60 * 24);
  h = t / (60 * 60);
  t -= h * (60 * 60);
  m = t / (60);
  t -= m * (60);
  s = t;
  if (s > 30)
    ++m;
  if (d)
    sprintf(buffer, "%lu day%s, %lu:%02lu", d, d > 1 ? "s" : "", h, m);
  else
    sprintf(buffer, "%lu:%02lu", h, m);
  if (t == -1)
    sprintf(buffer, "unknown");
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<apm_time_nosec>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%edx
  push   %r12
  imul   $0xffffffffc22e4507,%rax,%rax
  sar    $0x1f,%edx
  push   %rbx
  shr    $0x20,%rax
  sub    $0x8,%rsp
  add    %edi,%eax
  sar    $0x10,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x15180,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  mov    %edi,%ecx
  imul   $0xffffffff91a2b3c5,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0xb,%eax
  sub    %ecx,%eax
  movslq %eax,%r8
  imul   $0xe10,%eax,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edi,%ebx
  imul   $0xffffffff88888889,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edi,%eax
  sar    $0x5,%eax
  sub    %ecx,%eax
  movslq %eax,%r9
  imul   $0x3c,%eax,%eax
  sub    %eax,%ebx
  movslq %ebx,%rax
  cmp    $0x1f,%rax
  sbb    $0xffffffffffffffff,%r9
  test   %rdx,%rdx
  je     L5
  cmp    $0x1,%rdx
  lea    D34(%rip),%rax
  lea    D57(%rip),%rcx
  cmove  %rax,%rcx
  lea    D65(%rip),%r12
  xor    %eax,%eax
  lea    D41(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  cmp    $0xffffffff,%ebx
  je     L15
L24:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D65(%rip),%r12
  xor    %eax,%eax
  mov    %r9,%rcx
  mov    %r8,%rdx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  cmp    $0xffffffff,%ebx
  jne    L24
L15:
  movabs $0x6e776f6e6b6e75,%rax
  mov    %rax,D62(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D34
datatype: string
name: retrieve_data
arguments: tag: D57
datatype: string
name: retrieve_data
arguments: tag: D41
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string

tool: 

tool: D57: s

tool: D41: %lu day%s, %lu:%02lu

tool: D2: %lu:%02lu

assistant: ```c
const char *apm_time_nosec(time_t t) {
  static char buffer[128];
  unsigned long s, m, h, d;
  d = t / (60 * 60 * 24);
  t -= d * (60 * 60 * 24);
  h = t / (60 * 60);
  t -= h * (60 * 60);
  m = t / (60);
  t -= m * (60);
  s = t;
  if (s > 30)
    ++m;
  if (d)
    sprintf(buffer, "%lu day%s, %lu:%02lu", d, d > 1 ? "s" : "", h, m);
  else
    sprintf(buffer, "%lu:%02lu", h, m);
  if (t == -1)
    sprintf(buffer, "unknown");
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <create_table@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <insert@plt>
  mov    $0x1,%edx
  lea    D80(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    $0x2,%edx
  lea    D48(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <insert@plt>
  mov    %rbx,%rdi
  call   <print_table@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <erase@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <print_table@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <find@plt>
  mov    %eax,%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D75(%rip),%rsi
  mov    %rbx,%rdi
  call   <find@plt>
  cmp    $0xfffe7961,%eax
  je     L29
L23:
  lea    D75(%rip),%rsi
  mov    %rbx,%rdi
  call   <erase@plt>
  cmp    $0xfffe7961,%eax
  je     L22
L25:
  mov    %rbx,%rdi
  call   <destroy@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  lea    D31(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L22:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string
name: parse_data
arguments: data_tag: D80
type_infered: string
name: parse_data
arguments: data_tag: D48
type_infered: string
name: parse_data
arguments: data_tag: D56
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D45
type_infered: string
name: parse_data
arguments: data_tag: D75
type_infered: string
name: parse_data
arguments: data_tag: D31
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string

tool: D2: value0

tool: D80: value1

tool: D48: value2

tool: D56: Removing value1

tool: D17: value1 had value %d


tool: D45: value2 has value %d


tool: D75: valuex

tool: D31: can't find valuex

tool: D18: can't erase valuex

assistant: ```c
int main() {
  struct Table *tbl = create_table();
  insert(tbl, "value0", 0);
  insert(tbl, "value1", 1);
  insert(tbl, "value2", 2);
  print_table(tbl);
  printf("Removing value1\n");
  {
    int val = erase(tbl, "value1");
    printf("value1 had value %d\n", val);
  }
  print_table(tbl);
  {
    int val = find(tbl, "value2");
    printf("value2 has value %d\n", val);
    val = find(tbl, "valuex");
    if (val == -99999)
      printf("can't find valuex\n");
    val = erase(tbl, "valuex");
    if (val == -99999)
      printf("can't erase valuex\n");
  }
  destroy(tbl);
}
```