ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%r8d
  movsbl -0x4(%rbp),%eax
  sar    %eax
  and    $0x1,%eax
  mov    %eax,%edi
  movsbl -0x4(%rbp),%eax
  sar    $0x2,%eax
  and    $0x1,%eax
  mov    %eax,%esi
  movsbl -0x4(%rbp),%eax
  sar    $0x3,%eax
  and    $0x1,%eax
  mov    %eax,%r9d
  movsbl -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0x1,%eax
  mov    %eax,%r10d
  movsbl -0x4(%rbp),%eax
  sar    $0x5,%eax
  and    $0x1,%eax
  mov    %eax,%ecx
  movsbl -0x4(%rbp),%eax
  sar    $0x6,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  movzbl -0x4(%rbp),%eax
  sar    $0x7,%al
  movsbl %al,%eax
  and    $0x1,%eax
  sub    $0x8,%rsp
  push   %r8
  push   %rdi
  push   %rsi
  mov    %r10d,%r8d
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_guessed: string

tool: D7: bin: %d%d%d%d%d%d%d%d


assistant: ```c
void print_bin(char x) {
  printf("bin: "
         "%d%d%d%d%d%d%d%d"
         "\n",
         (x & 0x80 ? 1 : 0), (x & 0x40 ? 1 : 0), (x & 0x20 ? 1 : 0), (x & 0x10 ? 1 : 0), (x & 0x08 ? 1 : 0), (x & 0x04 ? 1 : 0), (x & 0x02 ? 1 : 0), (x & 0x01 ? 1 : 0));
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_bin>:
  endbr64
  sub    $0x10,%rsp
  movsbl %dil,%eax
  mov    %eax,%r9d
  sar    $0x3,%r9d
  mov    %eax,%r8d
  sar    $0x4,%r8d
  mov    %eax,%ecx
  sar    $0x5,%ecx
  and    $0x1,%ecx
  mov    %eax,%edx
  sar    $0x6,%edx
  and    $0x1,%edx
  mov    %edi,%esi
  shr    $0x7,%sil
  movsbl %sil,%esi
  and    $0x1,%edi
  push   %rdi
  mov    %eax,%edi
  sar    %edi
  and    $0x1,%edi
  push   %rdi
  sar    $0x2,%eax
  and    $0x1,%eax
  push   %rax
  and    $0x1,%r9d
  and    $0x1,%r8d
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: bin: %d%d%d%d%d%d%d%d


assistant: ```c
void print_bin(char x) {
  printf("bin: "
         "%d%d%d%d%d%d%d%d"
         "\n",
         (x & 0x80 ? 1 : 0), (x & 0x40 ? 1 : 0), (x & 0x20 ? 1 : 0), (x & 0x10 ? 1 : 0), (x & 0x08 ? 1 : 0), (x & 0x04 ? 1 : 0), (x & 0x02 ? 1 : 0), (x & 0x01 ? 1 : 0));
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_bin>:
  endbr64
  movsbl %dil,%eax
  sub    $0x10,%rsp
  mov    %edi,%esi
  and    $0x1,%edi
  push   %rdi
  mov    %eax,%edi
  mov    %eax,%r9d
  mov    %eax,%r8d
  sar    %edi
  mov    %eax,%ecx
  mov    %eax,%edx
  sar    $0x2,%eax
  sar    $0x3,%r9d
  and    $0x1,%edi
  and    $0x1,%eax
  sar    $0x4,%r8d
  push   %rdi
  sar    $0x5,%ecx
  sar    $0x6,%edx
  lea    D2(%rip),%rdi
  push   %rax
  shr    $0x7,%sil
  and    $0x1,%ecx
  and    $0x1,%edx
  movzbl %sil,%esi
  and    $0x1,%r9d
  and    $0x1,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x28,%rsp
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: bin: %d%d%d%d%d%d%d%d


assistant: ```c
void print_bin(char x) {
  printf("bin: "
         "%d%d%d%d%d%d%d%d"
         "\n",
         (x & 0x80 ? 1 : 0), (x & 0x40 ? 1 : 0), (x & 0x20 ? 1 : 0), (x & 0x10 ? 1 : 0), (x & 0x08 ? 1 : 0), (x & 0x04 ? 1 : 0), (x & 0x02 ? 1 : 0), (x & 0x01 ? 1 : 0));
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_bin>:
  endbr64
  movsbl %dil,%eax
  sub    $0x10,%rsp
  mov    %edi,%esi
  and    $0x1,%edi
  push   %rdi
  mov    %eax,%edi
  mov    %eax,%r9d
  mov    %eax,%r8d
  sar    %edi
  mov    %eax,%ecx
  mov    %eax,%edx
  sar    $0x2,%eax
  sar    $0x3,%r9d
  and    $0x1,%edi
  and    $0x1,%eax
  sar    $0x4,%r8d
  push   %rdi
  sar    $0x5,%ecx
  sar    $0x6,%edx
  lea    D7(%rip),%rdi
  push   %rax
  shr    $0x7,%sil
  and    $0x1,%ecx
  and    $0x1,%edx
  movzbl %sil,%esi
  and    $0x1,%r9d
  and    $0x1,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x28,%rsp
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D7: bin: %d%d%d%d%d%d%d%d


assistant: ```c
void print_bin(char x) {
  printf("bin: "
         "%d%d%d%d%d%d%d%d"
         "\n",
         (x & 0x80 ? 1 : 0), (x & 0x40 ? 1 : 0), (x & 0x20 ? 1 : 0), (x & 0x10 ? 1 : 0), (x & 0x08 ? 1 : 0), (x & 0x04 ? 1 : 0), (x & 0x02 ? 1 : 0), (x & 0x01 ? 1 : 0));
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serial_open>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D140(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  or     (%rax),%esi
  mov    D135(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L0
L17:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    %ebx,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %rsp,%r12
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <tcgetattr@plt>
  test   %rax,%rax
  jne    L44
  mov    %rsp,%rdi
  mov    %ebp,%esi
  call   <cfsetospeed@plt>
  test   %rax,%rax
  jne    L44
  mov    %rsp,%rdi
  mov    %ebp,%esi
  call   <cfsetispeed@plt>
  test   %rax,%rax
  jne    L44
  mov    D183(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    (%rsp),%eax
  mov    D97(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,(%rsp)
  mov    D88(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    0x4(%rsp),%eax
  mov    D92(%rip),%rdx
  mov    (%rdx),%edx
  mov    D3(%rip),%rcx
  or     (%rcx),%edx
  not    %edx
  and    %edx,%eax
  mov    %eax,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    D26(%rip),%rax
  mov    (%rax),%rdx
  mov    0x8(%rsp),%rax
  movl   $0x1,(%rax,%rdx,4)
  mov    D29(%rip),%rax
  mov    (%rax),%rdx
  mov    0x8(%rsp),%rax
  movl   $0x5,(%rax,%rdx,4)
  mov    D95(%rip),%rax
  mov    (%rax),%eax
  mov    D24(%rip),%rdx
  or     (%rdx),%eax
  mov    D44(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  mov    D38(%rip),%rdx
  mov    (%rsp),%eax
  or     (%rdx),%eax
  mov    D13(%rip),%rdx
  or     (%rdx),%eax
  mov    D153(%rip),%rdx
  mov    (%rdx),%edx
  mov    D181(%rip),%rcx
  or     (%rcx),%edx
  not    %edx
  and    %edx,%eax
  mov    D85(%rip),%rdx
  mov    (%rdx),%edx
  not    %edx
  and    %edx,%eax
  mov    %eax,(%rsp)
  mov    %rsp,%rdx
  mov    D189(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <tcsetattr@plt>
  test   %rax,%rax
  je     L17
L44:
  mov    $0xffffffff,%ebx
  jmp    L17
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int serial_open(const char *device, speed_t speed) {
  int fd = open(device, O_RDWR | O_NOCTTY | O_SYNC);
  if (fd > 0) {
    struct termios tty;
    memset(&tty, 0, sizeof tty);
    if (tcgetattr(fd, &tty) != 0) {
      return -1;
    }
    if (cfsetospeed(&tty, speed) != 0) {
      return -1;
    }
    if (cfsetispeed(&tty, speed) != 0) {
      return -1;
    }
    tty.c_cflag = (tty.c_cflag & ~CSIZE) | CS8;
    tty.c_iflag &= ~IGNBRK;
    tty.c_iflag &= ~INLCR;
    tty.c_iflag &= ~ICRNL;
    tty.c_lflag = 0;
    tty.c_oflag = 0;
    tty.c_cc[VMIN] = 1;
    tty.c_cc[VTIME] = 5;
    tty.c_iflag &= ~(IXON | IXOFF | IXANY);
    tty.c_cflag |= (CLOCAL | CREAD);
    tty.c_cflag &= ~(PARENB | PARODD);
    tty.c_cflag &= ~CSTOPB;
    if (tcsetattr(fd, TCSANOW, &tty) != 0) {
      return -1;
    }
  }
  return fd;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <sayHelloTo@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: world

assistant: ```c
int main(int argc, char *argv[]) {
  sayHelloTo("world");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <sayHelloTo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: world

assistant: ```c
int main(int argc, char *argv[]) {
  sayHelloTo("world");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <sayHelloTo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: world

assistant: ```c
int main(int argc, char *argv[]) {
  sayHelloTo("world");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <sayHelloTo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: world

assistant: ```c
int main(int argc, char *argv[]) {
  sayHelloTo("world");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reservarMatriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L36
L20:
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L36
L25:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  movl   $0x1,-0x14(%rbp)
  jmp    L7
L52:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L52
  mov    -0x10(%rbp),%rax
L36:
  leave
  ret
```

assistant: ```c
unsigned **reservarMatriz(int n, int m) {
  int i;
  unsigned *matriz, **vector;
  vector = (unsigned **)calloc(n, sizeof(unsigned *));
  if (vector == NULL)
    return NULL;
  matriz = (unsigned *)calloc(n * m, sizeof(unsigned));
  if (matriz == NULL) {
    free(vector);
    return NULL;
  }
  vector[0] = matriz;
  for (i = 1; i < n; i++) {
    vector[i] = vector[i - 1] + m;
  }
  return vector;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reservarMatriz>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L21
  mov    %rax,%r12
  mov    %rax,%rbp
  mov    %r13d,%edi
  imul   %ebx,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L39
  mov    %rax,(%r12)
  cmp    $0x1,%r13d
  jle    L21
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  mov    %r12,%rax
  lea    -0x1(%r13),%edx
  lea    (%r12,%rdx,8),%rsi
L45:
  mov    (%rax),%rdx
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  cmp    %rsi,%rax
  jne    L45
L21:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%ebp
  jmp    L21
```

assistant: ```c
unsigned **reservarMatriz(int n, int m) {
  int i;
  unsigned *matriz, **vector;
  vector = (unsigned **)calloc(n, sizeof(unsigned *));
  if (vector == NULL)
    return NULL;
  matriz = (unsigned *)calloc(n * m, sizeof(unsigned));
  if (matriz == NULL) {
    free(vector);
    return NULL;
  }
  vector[0] = matriz;
  for (i = 1; i < n; i++) {
    vector[i] = vector[i - 1] + m;
  }
  return vector;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reservarMatriz>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L18
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %rax,%r12
  imul   %ebx,%edi
  call   <calloc@plt>
  test   %rax,%rax
  je     L56
  mov    %rax,(%r12)
  cmp    $0x1,%ebp
  jle    L18
  movslq %ebx,%rcx
  lea    -0x1(%rbp),%esi
  lea    0x8(%r12),%rdx
  shl    $0x2,%rcx
  lea    (%r12,%rsi,8),%rsi
  jmp    L52
  nopl   0x0(%rax,%rax,1)
L57:
  add    $0x8,%rdx
L52:
  add    %rcx,%rax
  mov    %rax,(%rdx)
  cmp    %rsi,%rdx
  jne    L57
L18:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L56:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L18
```

assistant: ```c
unsigned **reservarMatriz(int n, int m) {
  int i;
  unsigned *matriz, **vector;
  vector = (unsigned **)calloc(n, sizeof(unsigned *));
  if (vector == NULL)
    return NULL;
  matriz = (unsigned *)calloc(n * m, sizeof(unsigned));
  if (matriz == NULL) {
    free(vector);
    return NULL;
  }
  vector[0] = matriz;
  for (i = 1; i < n; i++) {
    vector[i] = vector[i - 1] + m;
  }
  return vector;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reservarMatriz>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    $0x8,%esi
  call   <calloc@plt>
  test   %rax,%rax
  je     L0
  mov    %ebp,%edi
  mov    $0x4,%esi
  mov    %rax,%r12
  imul   %ebx,%edi
  call   <calloc@plt>
  test   %rax,%rax
  je     L38
  mov    %rax,(%r12)
  cmp    $0x1,%ebp
  jle    L0
  movslq %ebx,%rcx
  lea    -0x2(%rbp),%esi
  lea    0x8(%r12),%rdx
  shl    $0x2,%rcx
  lea    0x10(%r12,%rsi,8),%rsi
  nopw   0x0(%rax,%rax,1)
L16:
  add    %rcx,%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rsi,%rdx
  jne    L16
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L0
```

assistant: ```c
unsigned **reservarMatriz(int n, int m) {
  int i;
  unsigned *matriz, **vector;
  vector = (unsigned **)calloc(n, sizeof(unsigned *));
  if (vector == NULL)
    return NULL;
  matriz = (unsigned *)calloc(n * m, sizeof(unsigned));
  if (matriz == NULL) {
    free(vector);
    return NULL;
  }
  vector[0] = matriz;
  for (i = 1; i < n; i++) {
    vector[i] = vector[i - 1] + m;
  }
  return vector;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__modsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L28
  negl   -0x14(%rbp)
  movl   $0x1,-0xc(%rbp)
L28:
  cmpl   $0x0,-0x18(%rbp)
  jns    L2
  negl   -0x18(%rbp)
  xorl   $0x1,-0xc(%rbp)
L2:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <__udivmodsi4@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L4
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int32_t __modsi3(int32_t num, int32_t den) {
  int minus = 0;
  int32_t v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  (void)__udivmodsi4(num, den, (uint32_t *)&v);
  if (minus)
    v = -v;
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__modsi3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L50
  test   %esi,%esi
  js     L37
  lea    0x4(%rsp),%rdx
  call   <__udivmodsi4@plt>
  jmp    L55
L50:
  neg    %edi
  test   %esi,%esi
  js     L1
  lea    0x4(%rsp),%rdx
  call   <__udivmodsi4@plt>
L39:
  negl   0x4(%rsp)
L55:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x18,%rsp
  ret
L37:
  lea    0x4(%rsp),%rdx
  neg    %esi
  call   <__udivmodsi4@plt>
  jmp    L39
L1:
  lea    0x4(%rsp),%rdx
  neg    %esi
  call   <__udivmodsi4@plt>
  jmp    L55
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t __modsi3(int32_t num, int32_t den) {
  int minus = 0;
  int32_t v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  (void)__udivmodsi4(num, den, (uint32_t *)&v);
  if (minus)
    v = -v;
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__modsi3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L19
  lea    0x4(%rsp),%rdx
  test   %esi,%esi
  js     L38
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  neg    %esi
L18:
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
  neg    %eax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L19:
  neg    %edi
  lea    0x4(%rsp),%rdx
  test   %esi,%esi
  jns    L18
  neg    %esi
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
  jmp    L21
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t __modsi3(int32_t num, int32_t den) {
  int minus = 0;
  int32_t v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  (void)__udivmodsi4(num, den, (uint32_t *)&v);
  if (minus)
    v = -v;
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__modsi3>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L5
  lea    0x4(%rsp),%rdx
  test   %esi,%esi
  js     L53
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
L46:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  neg    %esi
L23:
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
  neg    %eax
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L5:
  neg    %edi
  lea    0x4(%rsp),%rdx
  test   %esi,%esi
  jns    L23
  neg    %esi
  call   <__udivmodsi4@plt>
  mov    0x4(%rsp),%eax
  jmp    L46
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int32_t __modsi3(int32_t num, int32_t den) {
  int minus = 0;
  int32_t v;
  if (num < 0) {
    num = -num;
    minus = 1;
  }
  if (den < 0) {
    den = -den;
    minus ^= 1;
  }
  (void)__udivmodsi4(num, den, (uint32_t *)&v);
  if (minus)
    v = -v;
  return v;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<next_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L13
L33:
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L33
  jmp    L28
L26:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L26
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *next_token(char *str) {
  while (*str != '\0' && !isspace(*str)) {
    str++;
  }
  while (*str != '\0' && isspace(*str)) {
    str++;
  }
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<next_token>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L33
L46:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L46
L33:
  mov    %rbx,%rax
  jmp    L57
L48:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L78
L55:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L87
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L55
  mov    %rbx,%rax
  jmp    L57
L78:
  mov    %rbx,%rax
  jmp    L57
L87:
  mov    %rbx,%rax
L57:
  pop    %rbx
  ret
```

assistant: ```c
char *next_token(char *str) {
  while (*str != '\0' && !isspace(*str)) {
    str++;
  }
  while (*str != '\0' && isspace(*str)) {
    str++;
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<next_token>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L5
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L20:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L26
L5:
  call   <isspace@plt>
  test   %rax,%rax
  je     L20
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x1,%r12
L25:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L26
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
L26:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *next_token(char *str) {
  while (*str != '\0' && !isspace(*str)) {
    str++;
  }
  while (*str != '\0' && isspace(*str)) {
    str++;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<next_token>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L65
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L55:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L22
L65:
  call   <isspace@plt>
  test   %rax,%rax
  je     L55
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%r12
L31:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L22
  call   <isspace@plt>
  test   %rax,%rax
  jne    L12
L22:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *next_token(char *str) {
  while (*str != '\0' && !isspace(*str)) {
    str++;
  }
  while (*str != '\0' && isspace(*str)) {
    str++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<allocateMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L3:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **allocateMatrix(int n, int m) {
  int **matrix = (int **)malloc(n * sizeof(int *));
  for (int i = 0; i < n; i++) {
    matrix[i] = (int *)malloc(m * sizeof(int));
  }
  return matrix;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<allocateMatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L9
  shl    $0x2,%ebp
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
L18:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
L9:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int **allocateMatrix(int n, int m) {
  int **matrix = (int **)malloc(n * sizeof(int *));
  for (int i = 0; i < n; i++) {
    matrix[i] = (int *)malloc(m * sizeof(int));
  }
  return matrix;
}
```