ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<CTA_Malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: CTA_Malloc: Warning: malloc returns NULL. (size=%zd)


assistant: ```c
void *CTA_Malloc(size_t size) {
  void *ptr = malloc(size);
  if (!ptr) {
    printf("CTA_Malloc: Warning: malloc returns NULL. (size=%zd)\n", size);
  } else {
  }
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CTA_Malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: CTA_Malloc: Warning: malloc returns NULL. (size=%zd)


assistant: ```c
void *CTA_Malloc(size_t size) {
  void *ptr = malloc(size);
  if (!ptr) {
    printf("CTA_Malloc: Warning: malloc returns NULL. (size=%zd)\n", size);
  } else {
  }
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CTA_Malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: CTA_Malloc: Warning: malloc returns NULL. (size=%zd)


assistant: ```c
void *CTA_Malloc(size_t size) {
  void *ptr = malloc(size);
  if (!ptr) {
    printf("CTA_Malloc: Warning: malloc returns NULL. (size=%zd)\n", size);
  } else {
  }
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<CTA_Malloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: CTA_Malloc: Warning: malloc returns NULL. (size=%zd)


assistant: ```c
void *CTA_Malloc(size_t size) {
  void *ptr = malloc(size);
  if (!ptr) {
    printf("CTA_Malloc: Warning: malloc returns NULL. (size=%zd)\n", size);
  } else {
  }
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x14(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,-0x14(%rbp)
L12:
  mov    -0x18(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string

tool: D10: %d %d %d %d

tool: D0: %d


assistant: ```c
int main() {
  int hi, hf, mi, mf;
  scanf("%d %d %d %d", &hi, &mi, &hf, &mf);
  if (hi > hf) {
    hf = hf + 12;
  }
  mi += hi * 60;
  mf = mf + hf * 60;
  printf("%d\n", (mf - mi) / 60);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  jle    L7
  add    $0xc,%eax
  mov    %eax,0xc(%rsp)
L7:
  imul   $0x3c,%edx,%edx
  add    0x10(%rsp),%edx
  mov    %edx,0x10(%rsp)
  imul   $0x3c,0xc(%rsp),%eax
  add    0x14(%rsp),%eax
  mov    %eax,0x14(%rsp)
  sub    %edx,%eax
  movslq %eax,%rsi
  imul   $0xffffffff88888889,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x5,%esi
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D2: %d %d %d %d

tool: D4: %d


assistant: ```c
int main() {
  int hi, hf, mi, mf;
  scanf("%d %d %d %d", &hi, &mi, &hf, &mf);
  if (hi > hf) {
    hf = hf + 12;
  }
  mi += hi * 60;
  mf = mf + hf * 60;
  printf("%d\n", (mf - mi) / 60);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  jle    L15
  add    $0xc,%eax
  mov    %eax,0xc(%rsp)
L15:
  imul   $0x3c,%edx,%edx
  add    0x10(%rsp),%edx
  lea    D9(%rip),%rdi
  imul   $0x3c,%eax,%eax
  add    0x14(%rsp),%eax
  mov    %edx,0x10(%rsp)
  mov    %eax,0x14(%rsp)
  sub    %edx,%eax
  movslq %eax,%rsi
  imul   $0xffffffff88888889,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x5,%esi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D9
datatype: string

tool: D16: %d %d %d %d

tool: D9: %d


assistant: ```c
int main() {
  int hi, hf, mi, mf;
  scanf("%d %d %d %d", &hi, &mi, &hf, &mf);
  if (hi > hf) {
    hf = hf + 12;
  }
  mi += hi * 60;
  mf = mf + hf * 60;
  printf("%d\n", (mf - mi) / 60);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D4(%rip),%rdi
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  jle    L14
  add    $0xc,%eax
  mov    %eax,0xc(%rsp)
L14:
  imul   $0x3c,%edx,%edx
  add    0x10(%rsp),%edx
  lea    D5(%rip),%rdi
  imul   $0x3c,%eax,%eax
  add    0x14(%rsp),%eax
  mov    %edx,0x10(%rsp)
  mov    %eax,0x14(%rsp)
  sub    %edx,%eax
  movslq %eax,%rsi
  imul   $0xffffffff88888889,%rsi,%rsi
  shr    $0x20,%rsi
  add    %eax,%esi
  sar    $0x1f,%eax
  sar    $0x5,%esi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D4: %d %d %d %d

tool: D5: %d


assistant: ```c
int main() {
  int hi, hf, mi, mf;
  scanf("%d %d %d %d", &hi, &mi, &hf, &mf);
  if (hi > hf) {
    hf = hf + 12;
  }
  mi += hi * 60;
  mf = mf + hf * 60;
  printf("%d\n", (mf - mi) / 60);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xtables_virt_to_phys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0xfff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <xtables_find_entry@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0xfffff000,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t xtables_virt_to_phys(uint64_t *pgd, uint64_t virt) {
  uint64_t phys = virt & 0xFFF;
  uint64_t *entry = (uint64_t *)xtables_find_entry(virt);
  *entry &= 0x7FFFFFF000;
  phys |= *entry;
  return phys;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xtables_virt_to_phys>:
  endbr64
  push   %rbx
  mov    %esi,%edi
  mov    %esi,%ebx
  and    $0xfff,%ebx
  call   <xtables_find_entry@plt>
  mov    %rax,%rdx
  mov    (%rax),%eax
  and    $0xfffff000,%eax
  mov    %eax,(%rdx)
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t xtables_virt_to_phys(uint64_t *pgd, uint64_t virt) {
  uint64_t phys = virt & 0xFFF;
  uint64_t *entry = (uint64_t *)xtables_find_entry(virt);
  *entry &= 0x7FFFFFF000;
  phys |= *entry;
  return phys;
}
```
user: What is the c source code of the assembly code below:

```asm
<xtables_virt_to_phys>:
  endbr64
  push   %rbx
  mov    %esi,%edi
  mov    %esi,%ebx
  and    $0xfff,%ebx
  call   <xtables_find_entry@plt>
  mov    %rax,%rdx
  mov    (%rax),%eax
  and    $0xfffff000,%eax
  mov    %eax,(%rdx)
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t xtables_virt_to_phys(uint64_t *pgd, uint64_t virt) {
  uint64_t phys = virt & 0xFFF;
  uint64_t *entry = (uint64_t *)xtables_find_entry(virt);
  *entry &= 0x7FFFFFF000;
  phys |= *entry;
  return phys;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xtables_virt_to_phys>:
  endbr64
  push   %rbx
  mov    %esi,%edi
  mov    %esi,%ebx
  and    $0xfff,%ebx
  call   <xtables_find_entry@plt>
  mov    %rax,%rdx
  mov    (%rax),%eax
  and    $0xfffff000,%eax
  mov    %eax,(%rdx)
  or     %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t xtables_virt_to_phys(uint64_t *pgd, uint64_t virt) {
  uint64_t phys = virt & 0xFFF;
  uint64_t *entry = (uint64_t *)xtables_find_entry(virt);
  *entry &= 0x7FFFFFF000;
  phys |= *entry;
  return phys;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xfbc(%rbp)
  jmp    L28
L4:
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfbc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xfbc(%rbp)
L28:
  mov    -0xfc0(%rbp),%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L4
  mov    -0xfb0(%rbp),%eax
  mov    %eax,-0xfb8(%rbp)
  movl   $0x0,-0xfbc(%rbp)
  jmp    L57
L6:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  cmp    %eax,-0xfb8(%rbp)
  jle    L43
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  mov    %eax,-0xfb8(%rbp)
  mov    -0xfbc(%rbp),%eax
  mov    %eax,-0xfb4(%rbp)
L43:
  addl   $0x1,-0xfbc(%rbp)
L57:
  mov    -0xfc0(%rbp),%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L6
  mov    -0xfb4(%rbp),%edx
  mov    -0xfb8(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string

tool: D2: %i

tool: D13: Menor valor: %i
Posicao: %i


assistant: ```c
int main() {
  int x[1000], n, i, menor, posicao;
  scanf("%i", &n);
  for (i = 0; i < n; i++) {
    scanf("%i", &x[i]);
  }
  menor = x[0];
  for (i = 0; i < n; i++) {
    if (x[i] < menor) {
      menor = x[i];
      posicao = i;
    }
  }
  printf("Menor valor: %i\nPosicao: %i\n", menor, posicao);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L8
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r13
L7:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L7
  mov    0x10(%rsp),%esi
  test   %eax,%eax
  jle    L9
  mov    %eax,%edx
  mov    $0x1,%eax
  jmp    L56
L51:
  add    $0x1,%rax
L56:
  mov    %eax,%edi
  cmp    %rdx,%rax
  je     L9
  mov    0x10(%rsp,%rax,4),%ecx
  cmp    %esi,%ecx
  jge    L51
  mov    %edi,%r12d
  mov    %ecx,%esi
  jmp    L51
L8:
  mov    0x10(%rsp),%esi
L9:
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type_infered: string
name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D24: %i

tool: D3: Menor valor: %i
Posicao: %i


assistant: ```c
int main() {
  int x[1000], n, i, menor, posicao;
  scanf("%i", &n);
  for (i = 0; i < n; i++) {
    scanf("%i", &x[i]);
  }
  menor = x[0];
  for (i = 0; i < n; i++) {
    if (x[i] < menor) {
      menor = x[i];
      posicao = i;
    }
  }
  printf("Menor valor: %i\nPosicao: %i\n", menor, posicao);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L4
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  mov    %rbp,%r13
L40:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L40
  mov    0x10(%rsp),%esi
  test   %eax,%eax
  jle    L44
  movslq %eax,%rdx
  mov    %esi,%ecx
  xor    %eax,%eax
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L53:
  mov    0x0(%rbp,%rax,4),%ecx
L73:
  cmp    %esi,%ecx
  jge    L6
  mov    %eax,%r12d
  mov    %ecx,%esi
L6:
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L53
L44:
  mov    %r12d,%edx
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    0x10(%rsp),%esi
  jmp    L44
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string
name: read_data
arguments: data_label: D16
data_type: string

tool: D7: %i

tool: D16: Menor valor: %i
Posicao: %i


assistant: ```c
int main() {
  int x[1000], n, i, menor, posicao;
  scanf("%i", &n);
  for (i = 0; i < n; i++) {
    scanf("%i", &x[i]);
  }
  menor = x[0];
  for (i = 0; i < n; i++) {
    if (x[i] < menor) {
      menor = x[i];
      posicao = i;
    }
  }
  printf("Menor valor: %i\nPosicao: %i\n", menor, posicao);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L37
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  mov    %rbp,%r13
L47:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L47
  mov    0x10(%rsp),%esi
  test   %eax,%eax
  jle    L13
  movslq %eax,%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L51:
  mov    0x0(%rbp,%rax,4),%ecx
  cmp    %esi,%ecx
  jge    L67
  mov    %eax,%r12d
  mov    %ecx,%esi
L67:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L51
L13:
  mov    %r12d,%edx
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  mov    0x10(%rsp),%esi
  jmp    L13
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D4: %i

tool: D12: Menor valor: %i
Posicao: %i


assistant: ```c
int main() {
  int x[1000], n, i, menor, posicao;
  scanf("%i", &n);
  for (i = 0; i < n; i++) {
    scanf("%i", &x[i]);
  }
  menor = x[0];
  for (i = 0; i < n; i++) {
    if (x[i] < menor) {
      menor = x[i];
      posicao = i;
    }
  }
  printf("Menor valor: %i\nPosicao: %i\n", menor, posicao);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gettext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D6(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D7(%rip)
  and    $0x7,%eax
  cltq
  imul   $0x7d00,%rax,%rax
  lea    D7(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x7d00,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <trap_Gettext@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *gettext(const char *msgid) {
  static char string[8][32000];
  static int index = 0;
  char *buf = string[index++ & 7];
  trap_Gettext(buf, msgid, sizeof(*string));
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gettext>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    D25(%rip),%ebx
  lea    0x1(%rbx),%eax
  mov    %eax,D14(%rip)
  and    $0x7,%ebx
  imul   $0x7d00,%rbx,%rbx
  lea    D14(%rip),%rax
  add    %rax,%rbx
  mov    $0x7d00,%edx
  mov    %rbx,%rdi
  call   <trap_Gettext@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *gettext(const char *msgid) {
  static char string[8][32000];
  static int index = 0;
  char *buf = string[index++ & 7];
  trap_Gettext(buf, msgid, sizeof(*string));
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gettext>:
  endbr64
  push   %r12
  mov    D9(%rip),%r12d
  mov    %rdi,%rsi
  mov    $0x7d00,%edx
  lea    0x1(%r12),%eax
  and    $0x7,%r12d
  imul   $0x7d00,%r12,%r12
  mov    %eax,D1(%rip)
  lea    D1(%rip),%rax
  add    %rax,%r12
  mov    %r12,%rdi
  call   <trap_Gettext@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *gettext(const char *msgid) {
  static char string[8][32000];
  static int index = 0;
  char *buf = string[index++ & 7];
  trap_Gettext(buf, msgid, sizeof(*string));
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gettext>:
  endbr64
  push   %r12
  mov    D27(%rip),%r12d
  mov    %rdi,%rsi
  mov    $0x7d00,%edx
  lea    0x1(%r12),%eax
  and    $0x7,%r12d
  imul   $0x7d00,%r12,%r12
  mov    %eax,D16(%rip)
  lea    D16(%rip),%rax
  add    %rax,%r12
  mov    %r12,%rdi
  call   <trap_Gettext@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *gettext(const char *msgid) {
  static char string[8][32000];
  static int index = 0;
  char *buf = string[index++ & 7];
  trap_Gettext(buf, msgid, sizeof(*string));
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mergestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L18
L8:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *mergestr(char *s1, char *s2) {
  char *s;
  int len = strlen(s1) + strlen(s2);
  s = malloc((len + 1) * sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, s1);
  strcat(s, s2);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mergestr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L0:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mergestr(char *s1, char *s2) {
  char *s;
  int len = strlen(s1) + strlen(s2);
  s = malloc((len + 1) * sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, s1);
  strcat(s, s2);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mergestr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L4:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mergestr(char *s1, char *s2) {
  char *s;
  int len = strlen(s1) + strlen(s2);
  s = malloc((len + 1) * sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, s1);
  strcat(s, s2);
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mergestr>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L5:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *mergestr(char *s1, char *s2) {
  char *s;
  int len = strlen(s1) + strlen(s2);
  s = malloc((len + 1) * sizeof(char));
  if (s == NULL)
    return NULL;
  strcpy(s, s1);
  strcat(s, s2);
  return s;
}
```