ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hej@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9: Zjadles moje kanapki ?


assistant: ```c
int main() {
  hej();
  printf("Zjadles moje kanapki ?\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hej@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: Zjadles moje kanapki ?


assistant: ```c
int main() {
  hej();
  printf("Zjadles moje kanapki ?\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hej@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: Zjadles moje kanapki ?


assistant: ```c
int main() {
  hej();
  printf("Zjadles moje kanapki ?\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flag_table_3_5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <flag_table_3_5_location@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0xffffffff,%eax
  jmp    L4
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
L4:
  leave
  ret
```

assistant: ```c
int flag_table_3_5(unsigned char **sec) {
  unsigned char *p;
  p = flag_table_3_5_location(sec);
  if (p == NULL)
    return -1;
  return (int)*p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<flag_table_3_5>:
  endbr64
  sub    $0x8,%rsp
  call   <flag_table_3_5_location@plt>
  test   %rax,%rax
  je     L10
  movzbl (%rax),%eax
L7:
  add    $0x8,%rsp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int flag_table_3_5(unsigned char **sec) {
  unsigned char *p;
  p = flag_table_3_5_location(sec);
  if (p == NULL)
    return -1;
  return (int)*p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<flag_table_3_5>:
  endbr64
  sub    $0x8,%rsp
  call   <flag_table_3_5_location@plt>
  test   %rax,%rax
  je     L6
  movzbl (%rax),%eax
L7:
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int flag_table_3_5(unsigned char **sec) {
  unsigned char *p;
  p = flag_table_3_5_location(sec);
  if (p == NULL)
    return -1;
  return (int)*p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flag_table_3_5>:
  endbr64
  sub    $0x8,%rsp
  call   <flag_table_3_5_location@plt>
  test   %rax,%rax
  je     L8
  movzbl (%rax),%eax
L12:
  add    $0x8,%rsp
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int flag_table_3_5(unsigned char **sec) {
  unsigned char *p;
  p = flag_table_3_5_location(sec);
  if (p == NULL)
    return -1;
  return (int)*p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L5:
  addl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const unsigned char *src) {
  int ret;
  for (ret = 0; *src; src++)
    ret++;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L27
  mov    %rdi,%rax
  mov    $0x1,%edx
  sub    %edi,%edx
L11:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L11
L23:
  mov    %ecx,%eax
  ret
L27:
  mov    $0x0,%ecx
  jmp    L23
```

assistant: ```c
int strlen(const unsigned char *src) {
  int ret;
  for (ret = 0; *src; src++)
    ret++;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L17
  mov    $0x1,%eax
  sub    %edi,%eax
L15:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L15
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L17:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const unsigned char *src) {
  int ret;
  for (ret = 0; *src; src++)
    ret++;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  mov    $0x1,%eax
  sub    %edi,%eax
L3:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L3
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(const unsigned char *src) {
  int ret;
  for (ret = 0; *src; src++)
    ret++;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vectord_add_inplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L3
L4:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void vectord_add_inplace(double *self, size_t size, double value) {
  assert(self);
  for (size_t i = 0; i < size; i++)
    self[i] += value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vectord_add_inplace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movq   %xmm0,%rbx
  call   <assert@plt>
  test   %r12,%r12
  je     L13
  mov    %rbp,%rax
  lea    0x0(%rbp,%r12,8),%rdx
L1:
  movq   %rbx,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L1
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void vectord_add_inplace(double *self, size_t size, double value) {
  assert(self);
  for (size_t i = 0; i < size; i++)
    self[i] += value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vectord_add_inplace>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  test   %rbp,%rbp
  je     L4
  movsd  0x8(%rsp),%xmm0
  mov    %rbx,%rdi
  lea    (%rbx,%rbp,8),%rax
  nopl   (%rax)
L11:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L11
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void vectord_add_inplace(double *self, size_t size, double value) {
  assert(self);
  for (size_t i = 0; i < size; i++)
    self[i] += value;
}
```
user: What is the c source code of the assembly code below?

```asm
<vectord_add_inplace>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <assert@plt>
  test   %rbp,%rbp
  je     L13
  cmp    $0x1,%rbp
  movsd  0x8(%rsp),%xmm0
  je     L22
  mov    %rbp,%rdx
  movapd %xmm0,%xmm2
  mov    %rbx,%rax
  shr    %rdx
  unpcklpd %xmm2,%xmm2
  shl    $0x4,%rdx
  add    %rbx,%rdx
  nopl   0x0(%rax)
L0:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  addpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L0
  mov    %rbp,%rax
  and    $0xfffffffffffffffe,%rax
  and    $0x1,%ebp
  je     L13
L49:
  lea    (%rbx,%rax,8),%rax
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L22:
  xor    %eax,%eax
  jmp    L49
```

assistant: ```c
void vectord_add_inplace(double *self, size_t size, double value) {
  assert(self);
  for (size_t i = 0; i < size; i++)
    self[i] += value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<init_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movq   $0x12345678,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movq   $0x23456789,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movq   $0x34567890,(%rax)
  jmp    L18
L11:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <update_keys@plt>
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void init_keys(unsigned long keys[3], const char *passwd) {
  keys[0] = 305419896L;
  keys[1] = 591751049L;
  keys[2] = 878082192L;
  while (*passwd) {
    update_keys(keys, (int)*passwd);
    passwd++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_keys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movq   $0x12345678,(%rdi)
  movq   $0x23456789,0x8(%rdi)
  movq   $0x34567890,0x10(%rdi)
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L11
L12:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <update_keys@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L12
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_keys(unsigned long keys[3], const char *passwd) {
  keys[0] = 305419896L;
  keys[1] = 591751049L;
  keys[2] = 878082192L;
  while (*passwd) {
    update_keys(keys, (int)*passwd);
    passwd++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_keys>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movq   $0x12345678,(%rdi)
  movq   $0x23456789,0x8(%rdi)
  movq   $0x34567890,0x10(%rdi)
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L11
  mov    %rdi,%rbp
  nop
L19:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <update_keys@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L19
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void init_keys(unsigned long keys[3], const char *passwd) {
  keys[0] = 305419896L;
  keys[1] = 591751049L;
  keys[2] = 878082192L;
  while (*passwd) {
    update_keys(keys, (int)*passwd);
    passwd++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<init_keys>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movdqa D9(%rip),%xmm0
  movq   $0x34567890,0x10(%rdi)
  movups %xmm0,(%rdi)
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L14
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <update_keys@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L19
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: byte[16]

tool: {"D9": [0x78,0x56,0x34,0x12,0x00,0x00,0x00,0x00,0x89,0x67,0x45,0x23,0x00,0x00,0x00,0x00]}

assistant: ```c
void init_keys(unsigned long keys[3], const char *passwd) {
  keys[0] = 305419896L;
  keys[1] = 591751049L;
  keys[2] = 878082192L;
  while (*passwd) {
    update_keys(keys, (int)*passwd);
    passwd++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lenStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L5:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int lenStr(char str[]) {
  int i;
  for (i = 0; '\0' != str[i]; i++)
    ;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lenStr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L21
  mov    $0x1,%eax
L26:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L26
L1:
  mov    %edx,%eax
  ret
L21:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
int lenStr(char str[]) {
  int i;
  for (i = 0; '\0' != str[i]; i++)
    ;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lenStr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  xchg   %ax,%ax
L3:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lenStr(char str[]) {
  int i;
  for (i = 0; '\0' != str[i]; i++)
    ;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lenStr>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L0
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int lenStr(char str[]) {
  int i;
  for (i = 0; '\0' != str[i]; i++)
    ;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L15
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *restrict dest, const void *restrict src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    *((char *)dest + i) = *((char *)src + i);
  }
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L19
  mov    $0x0,%ecx
L9:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L9
L19:
  ret
```

assistant: ```c
void *memcpy(void *restrict dest, const void *restrict src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    *((char *)dest + i) = *((char *)src + i);
  }
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  test   %rdx,%rdx
  je     L0
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memcpy(void *restrict dest, const void *restrict src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    *((char *)dest + i) = *((char *)src + i);
  }
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcpy>:
  endbr64
  test   %rdx,%rdx
  je     L1
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memcpy(void *restrict dest, const void *restrict src, size_t n) {
  int i;
  for (i = 0; i < n; i++) {
    *((char *)dest + i) = *((char *)src + i);
  }
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xa,%edx
  mov    $0x1f,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rcx
  lea    D27(%rip),%rax
  mov    %rax,%rdx
  mov    $0x21,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <fexpect_string@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D35
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string

tool: D35: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

tool: D27: a   bc

assistant: ```c
void escape() {
  int value = 10;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 31, 10, value);
  ;
  fexpect_string("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 33, "a   bc", "a\   bc");
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<escape>:
  endbr64
  push   %rbx
  mov    $0xa,%ecx
  mov    $0xa,%edx
  mov    $0x1f,%esi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <fexpect@plt>
  lea    D19(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x21,%esi
  mov    %rbx,%rdi
  call   <fexpect_string@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

tool: D19: a   bc

assistant: ```c
void escape() {
  int value = 10;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 31, 10, value);
  ;
  fexpect_string("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 33, "a   bc", "a\   bc");
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<escape>:
  endbr64
  push   %rbp
  mov    $0xa,%ecx
  mov    $0xa,%edx
  mov    $0x1f,%esi
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  lea    D19(%rip),%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rdx,%rcx
  mov    $0x21,%esi
  jmp    1070 <fexpect_string@plt>
```

tool_calls: name: read_data
arguments: label: D13
type: string
name: read_data
arguments: label: D19
type: string

tool: D13: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

tool: D19: a   bc

assistant: ```c
void escape() {
  int value = 10;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 31, 10, value);
  ;
  fexpect_string("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 33, "a   bc", "a\   bc");
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<escape>:
  endbr64
  push   %rbp
  mov    $0xa,%ecx
  mov    $0xa,%edx
  mov    $0x1f,%esi
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  call   <fexpect@plt>
  lea    D14(%rip),%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rdx,%rcx
  mov    $0x21,%esi
  jmp    1070 <fexpect_string@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c

tool: D14: a   bc

assistant: ```c
void escape() {
  int value = 10;
  fexpect("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 31, 10, value);
  ;
  fexpect_string("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/8l/8cc/refs/heads/master/test/input/8cc/lex.c", 33, "a   bc", "a\   bc");
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ndigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ndigits(unsigned long long val) {
  unsigned int len = 0;
  do {
    val /= 10;
    len++;
  } while (val);
  return (len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ndigits>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%ecx
  movabs $0xcccccccccccccccd,%rdi
L0:
  mov    %rdx,%rsi
  mov    %rdx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  add    $0x1,%ecx
  cmp    $0x9,%rsi
  ja     L0
  mov    %ecx,%eax
  ret
```

assistant: ```c
unsigned int ndigits(unsigned long long val) {
  unsigned int len = 0;
  do {
    val /= 10;
    len++;
  } while (val);
  return (len);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ndigits>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L2:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ndigits(unsigned long long val) {
  unsigned int len = 0;
  do {
    val /= 10;
    len++;
  } while (val);
  return (len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ndigits>:
  endbr64
  movabs $0xcccccccccccccccd,%rsi
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L9:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x9,%rcx
  ja     L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ndigits(unsigned long long val) {
  unsigned int len = 0;
  do {
    val /= 10;
    len++;
  } while (val);
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L13:
  mov    -0x14(%rbp),%eax
  imul   -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0x3e8,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L13
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D15
datatype: string

tool: D4: %d%d

tool: D15: %03d


assistant: ```c
int main() {
  int a, b, ans = 1;
  scanf("%d%d", &a, &b);
  do
    ans = (ans * a) % 1000;
  while (--b);
  printf("%03d\n", ans);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  mov    0x4(%rsp),%edx
  mov    $0x1,%esi
L9:
  mov    %esi,%eax
  imul   %edi,%eax
  movslq %eax,%rsi
  imul   $0x10624dd3,%rsi,%rsi
  sar    $0x26,%rsi
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%esi
  imul   $0x3e8,%esi,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  sub    $0x1,%edx
  jne    L9
  movl   $0x0,0x4(%rsp)
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D18
data_type: string

tool: D9: %d%d

tool: D18: %03d


assistant: ```c
int main() {
  int a, b, ans = 1;
  scanf("%d%d", &a, &b);
  do
    ans = (ans * a) % 1000;
  while (--b);
  printf("%03d\n", ans);
  return 0;
}
```