ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<_zip_memmem>:
  endbr64
  push   %r15
  push   %r14
  lea    -0x1(%rcx),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rdx,0x8(%rsp)
  cmp    %r14,%rsi
  jbe    L39
  mov    %rsi,%rbx
  mov    %rcx,%r13
  lea    0x1(%rdx),%r15
  mov    %rdi,%rbp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L1:
  lea    0x1(%r12),%rbp
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L20
L4:
  mov    (%rsp),%rax
  mov    %rbp,%rdi
  sub    %rbp,%rax
  lea    0x1(%rbx,%rax,1),%rdx
  mov    0x8(%rsp),%rax
  sub    %r13,%rdx
  movzbl (%rax),%esi
  call   <memchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L1
L39:
  xor    %r12d,%r12d
L20:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char *_zip_memmem(const unsigned char *big, size_t biglen, const unsigned char *little, size_t littlelen) {
  const unsigned char *p;
  if ((biglen < littlelen) || (littlelen == 0))
    return NULL;
  p = big - 1;
  while ((p = (const unsigned char *)memchr(p + 1, little[0], (size_t)(big - (p + 1)) + (size_t)(biglen - littlelen) + 1)) != NULL) {
    if (memcmp(p + 1, little + 1, littlelen - 1) == 0)
      return (unsigned char *)p;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L27:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <placeApple@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string

tool: D2: %d

tool: D5:  %d %d

tool: D19: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i;
  int numOfApple, numOfPlate;
  int res;
  for (i = 0; i < n; i++) {
    scanf(" %d %d", &numOfApple, &numOfPlate);
    res = placeApple(numOfApple, numOfPlate);
    printf("%d\n", res);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L14
  mov    $0x0,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    D14(%rip),%r12
  lea    D28(%rip),%rbp
L15:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  call   <placeApple@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L15
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string

tool: D21: %d

tool: D14:  %d %d

tool: D28: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i;
  int numOfApple, numOfPlate;
  int res;
  for (i = 0; i < n; i++) {
    scanf(" %d %d", &numOfApple, &numOfPlate);
    res = placeApple(numOfApple, numOfPlate);
    printf("%d\n", res);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D20(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L8
  xor    %r14d,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D6(%rip),%rbp
  lea    D11(%rip),%rbx
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  add    $0x1,%r14d
  call   <placeApple@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jg     L3
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type: string
name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D11
type: string

tool: D20: %d

tool: D6:  %d %d

tool: D11: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i;
  int numOfApple, numOfPlate;
  int res;
  for (i = 0; i < n; i++) {
    scanf(" %d %d", &numOfApple, &numOfPlate);
    res = placeApple(numOfApple, numOfPlate);
    printf("%d\n", res);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %r14d,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D16(%rip),%rbp
  lea    D12(%rip),%rbx
  nopl   0x0(%rax)
L17:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    0x10(%rsp),%edi
  add    $0x1,%r14d
  call   <placeApple@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jg     L17
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string

tool: D3: %d

tool: D16:  %d %d

tool: D12: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int i;
  int numOfApple, numOfPlate;
  int res;
  for (i = 0; i < n; i++) {
    scanf(" %d %d", &numOfApple, &numOfPlate);
    res = placeApple(numOfApple, numOfPlate);
    printf("%d\n", res);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fast_alloc_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void fast_alloc_free(void *tofree, void *params) {
  params = 0;
  free(tofree);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fast_alloc_free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fast_alloc_free(void *tofree, void *params) {
  params = 0;
  free(tofree);
}
```
user: What is the c source code of the assembly code below?

```asm
<fast_alloc_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void fast_alloc_free(void *tofree, void *params) {
  params = 0;
  free(tofree);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fast_alloc_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void fast_alloc_free(void *tofree, void *params) {
  params = 0;
  free(tofree);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<time_cost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L2:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x9c3f,-0x4(%rbp)
  jle    L2
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0xbb7,-0x8(%rbp)
  jle    L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void time_cost() {
  int i, j;
  volatile int k;
  for (i = 0; i < 3000; i++) {
    for (j = 0; j < 40000; j++) {
      k += i * j;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<time_cost>:
  endbr64
  mov    $0x0,%edi
L4:
  mov    %edi,%esi
  mov    $0x0,%ecx
  mov    $0x9c40,%edx
L9:
  mov    -0x4(%rsp),%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rsp)
  add    %esi,%ecx
  sub    $0x1,%edx
  jne    L9
  add    $0x1,%edi
  cmp    $0xbb8,%edi
  jne    L4
  ret
```

assistant: ```c
void time_cost() {
  int i, j;
  volatile int k;
  for (i = 0; i < 3000; i++) {
    for (j = 0; j < 40000; j++) {
      k += i * j;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<time_cost>:
  endbr64
  xor    %esi,%esi
L10:
  xor    %ecx,%ecx
  mov    $0x9c40,%edx
  nopl   (%rax)
L18:
  mov    -0x4(%rsp),%eax
  add    %ecx,%eax
  add    %esi,%ecx
  mov    %eax,-0x4(%rsp)
  sub    $0x1,%edx
  jne    L18
  add    $0x1,%esi
  cmp    $0xbb8,%esi
  jne    L10
  ret
```

assistant: ```c
void time_cost() {
  int i, j;
  volatile int k;
  for (i = 0; i < 3000; i++) {
    for (j = 0; j < 40000; j++) {
      k += i * j;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<time_cost>:
  endbr64
  xor    %esi,%esi
L1:
  xor    %ecx,%ecx
  mov    $0x9c40,%edx
  nopl   (%rax)
L3:
  mov    -0x4(%rsp),%eax
  add    %ecx,%eax
  add    %esi,%ecx
  mov    %eax,-0x4(%rsp)
  sub    $0x1,%edx
  jne    L3
  add    $0x1,%esi
  cmp    $0xbb8,%esi
  jne    L1
  ret
```

assistant: ```c
void time_cost() {
  int i, j;
  volatile int k;
  for (i = 0; i < 3000; i++) {
    for (j = 0; j < 40000; j++) {
      k += i * j;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nb_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L49:
  cmpl   $0x0,-0x4(%rbp)
  jne    L27
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L27
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x1,-0x4(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L14
  movl   $0x0,-0x4(%rbp)
L14:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nb_words(char const *s, char c) {
  int count;
  int state;
  state = 0;
  count = 0;
  while (*s) {
    if (state == 0 && *s != c) {
      state = 1;
      ++count;
    }
    if (state == 1 && *s == c)
      state = 0;
    ++s;
  }
  return (count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nb_words>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L37
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x1,%r8d
  jmp    L13
L30:
  movzbl %al,%eax
  cmp    $0x1,%edx
  cmove  %eax,%edx
L56:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L31
L13:
  cmp    %al,%sil
  setne  %al
  test   %edx,%edx
  jne    L30
  test   %al,%al
  je     L30
  add    $0x1,%ecx
  mov    %r8d,%edx
  jmp    L56
L37:
  mov    $0x0,%ecx
L31:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int nb_words(char const *s, char c) {
  int count;
  int state;
  state = 0;
  count = 0;
  while (*s) {
    if (state == 0 && *s != c) {
      state = 1;
      ++count;
    }
    if (state == 1 && *s == c)
      state = 0;
    ++s;
  }
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<nb_words>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  test   %dl,%dl
  je     L3
L35:
  mov    %rdi,%rax
L51:
  cmp    %dl,%sil
  je     L36
  add    $0x1,%r8d
L52:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  test   %dl,%dl
  je     L3
  cmp    %dl,%sil
  jne    L14
  movzbl 0x1(%rcx),%edx
  add    $0x2,%rax
  test   %dl,%dl
  jne    L51
L3:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rdi
  test   %dl,%dl
  jne    L35
  mov    %r8d,%eax
  ret
L14:
  mov    %rcx,%rax
  jmp    L52
```

assistant: ```c
int nb_words(char const *s, char c) {
  int count;
  int state;
  state = 0;
  count = 0;
  while (*s) {
    if (state == 0 && *s != c) {
      state = 1;
      ++count;
    }
    if (state == 1 && *s == c)
      state = 0;
    ++s;
  }
  return (count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nb_words>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  test   %dl,%dl
  je     L36
L55:
  mov    %rdi,%rax
L53:
  cmp    %dl,%sil
  je     L10
  add    $0x1,%r8d
L51:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  test   %dl,%dl
  je     L36
  cmp    %dl,%sil
  jne    L49
  movzbl 0x1(%rcx),%edx
  add    $0x2,%rax
  test   %dl,%dl
  jne    L53
L36:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rdi
  test   %dl,%dl
  jne    L55
  mov    %r8d,%eax
  ret
L49:
  mov    %rcx,%rax
  jmp    L51
```

assistant: ```c
int nb_words(char const *s, char c) {
  int count;
  int state;
  state = 0;
  count = 0;
  while (*s) {
    if (state == 0 && *s != c) {
      state = 1;
      ++count;
    }
    if (state == 1 && *s == c)
      state = 0;
    ++s;
  }
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UPnPRenderingControl_SetVerticalKeystone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x10(%rbp)
  movswl -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UPnPResponse_RenderingControl_SetVerticalKeystone@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);


assistant: ```c
void UPnPRenderingControl_SetVerticalKeystone(void *upnptoken, unsigned int InstanceID, short DesiredVerticalKeystone) {
  printf("Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);\r\n", InstanceID, DesiredVerticalKeystone);
  UPnPResponse_RenderingControl_SetVerticalKeystone(upnptoken);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UPnPRenderingControl_SetVerticalKeystone>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movswl %dx,%edx
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <UPnPResponse_RenderingControl_SetVerticalKeystone@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);


assistant: ```c
void UPnPRenderingControl_SetVerticalKeystone(void *upnptoken, unsigned int InstanceID, short DesiredVerticalKeystone) {
  printf("Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);\r\n", InstanceID, DesiredVerticalKeystone);
  UPnPResponse_RenderingControl_SetVerticalKeystone(upnptoken);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UPnPRenderingControl_SetVerticalKeystone>:
  endbr64
  push   %rbp
  movswl %dx,%edx
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVerticalKeystone@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);


assistant: ```c
void UPnPRenderingControl_SetVerticalKeystone(void *upnptoken, unsigned int InstanceID, short DesiredVerticalKeystone) {
  printf("Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);\r\n", InstanceID, DesiredVerticalKeystone);
  UPnPResponse_RenderingControl_SetVerticalKeystone(upnptoken);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UPnPRenderingControl_SetVerticalKeystone>:
  endbr64
  push   %rbp
  movswl %dx,%edx
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <UPnPResponse_RenderingControl_SetVerticalKeystone@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);


assistant: ```c
void UPnPRenderingControl_SetVerticalKeystone(void *upnptoken, unsigned int InstanceID, short DesiredVerticalKeystone) {
  printf("Invoke: UPnPRenderingControl_SetVerticalKeystone(%u,%d);\r\n", InstanceID, DesiredVerticalKeystone);
  UPnPResponse_RenderingControl_SetVerticalKeystone(upnptoken);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bmp085_ReadUT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bmp085_i2c_Begin@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x2e,%edx
  mov    $0xf4,%esi
  mov    %eax,%edi
  call   <bmp085_i2c_Write_Byte@plt>
  mov    $0x1388,%edi
  call   <usleep@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xf6,%esi
  mov    %eax,%edi
  call   <bmp085_i2c_Read_Int@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int bmp085_ReadUT(const char *i2cFileName) {
  unsigned int ut = 0;
  int fd = bmp085_i2c_Begin(i2cFileName);
  bmp085_i2c_Write_Byte(fd, 0xF4, 0x2E);
  usleep(5000);
  ut = bmp085_i2c_Read_Int(fd, 0xF6);
  close(fd);
  return ut;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bmp085_ReadUT>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <bmp085_i2c_Begin@plt>
  mov    %eax,%ebx
  mov    $0x2e,%edx
  mov    $0xf4,%esi
  mov    %eax,%edi
  call   <bmp085_i2c_Write_Byte@plt>
  mov    $0x1388,%edi
  call   <usleep@plt>
  mov    $0xf6,%esi
  mov    %ebx,%edi
  call   <bmp085_i2c_Read_Int@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <close@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int bmp085_ReadUT(const char *i2cFileName) {
  unsigned int ut = 0;
  int fd = bmp085_i2c_Begin(i2cFileName);
  bmp085_i2c_Write_Byte(fd, 0xF4, 0x2E);
  usleep(5000);
  ut = bmp085_i2c_Read_Int(fd, 0xF6);
  close(fd);
  return ut;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bmp085_ReadUT>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <bmp085_i2c_Begin@plt>
  mov    $0x2e,%edx
  mov    $0xf4,%esi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <bmp085_i2c_Write_Byte@plt>
  mov    $0x1388,%edi
  call   <usleep@plt>
  mov    %ebp,%edi
  mov    $0xf6,%esi
  call   <bmp085_i2c_Read_Int@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <close@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int bmp085_ReadUT(const char *i2cFileName) {
  unsigned int ut = 0;
  int fd = bmp085_i2c_Begin(i2cFileName);
  bmp085_i2c_Write_Byte(fd, 0xF4, 0x2E);
  usleep(5000);
  ut = bmp085_i2c_Read_Int(fd, 0xF6);
  close(fd);
  return ut;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bmp085_ReadUT>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <bmp085_i2c_Begin@plt>
  mov    $0x2e,%edx
  mov    $0xf4,%esi
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <bmp085_i2c_Write_Byte@plt>
  mov    $0x1388,%edi
  call   <usleep@plt>
  mov    %ebp,%edi
  mov    $0xf6,%esi
  call   <bmp085_i2c_Read_Int@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <close@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int bmp085_ReadUT(const char *i2cFileName) {
  unsigned int ut = 0;
  int fd = bmp085_i2c_Begin(i2cFileName);
  bmp085_i2c_Write_Byte(fd, 0xF4, 0x2E);
  usleep(5000);
  ut = bmp085_i2c_Read_Int(fd, 0xF6);
  close(fd);
  return ut;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L18:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%ecx
  shr    $0x7,%cl
  add    %ecx,%eax
  sar    %al
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo3(signed char *w) {
  int i;
  signed char *ww = __builtin_assume_aligned(w, 8);
  for (i = 0; i < 32; i++)
    ww[i] = ww[i] / 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo3>:
  endbr64
  lea    0x20(%rdi),%rcx
L0:
  movzbl (%rdi),%edx
  mov    %edx,%eax
  shr    $0x7,%al
  add    %edx,%eax
  sar    %al
  mov    %al,(%rdi)
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L0
  ret
```

assistant: ```c
void foo3(signed char *w) {
  int i;
  signed char *ww = __builtin_assume_aligned(w, 8);
  for (i = 0; i < 32; i++)
    ww[i] = ww[i] / 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo3>:
  endbr64
  lea    0x20(%rdi),%rcx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    %edx,%eax
  shr    $0x7,%al
  add    %edx,%eax
  sar    %al
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L7
  ret
```

assistant: ```c
void foo3(signed char *w) {
  int i;
  signed char *ww = __builtin_assume_aligned(w, 8);
  for (i = 0; i < 32; i++)
    ww[i] = ww[i] / 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo3>:
  endbr64
  movdqu (%rdi),%xmm4
  pxor   %xmm3,%xmm3
  movdqu 0x10(%rdi),%xmm5
  movdqa %xmm3,%xmm1
  movdqa D3(%rip),%xmm2
  pcmpgtb %xmm4,%xmm1
  pcmpgtb %xmm5,%xmm3
  movdqa %xmm4,%xmm0
  psubb  %xmm1,%xmm0
  movdqa D6(%rip),%xmm1
  psraw  $0x1,%xmm0
  pand   %xmm1,%xmm0
  pxor   %xmm2,%xmm0
  psubb  %xmm2,%xmm0
  movups %xmm0,(%rdi)
  movdqa %xmm5,%xmm0
  psubb  %xmm3,%xmm0
  psraw  $0x1,%xmm0
  pand   %xmm1,%xmm0
  pxor   %xmm2,%xmm0
  psubb  %xmm2,%xmm0
  movups %xmm0,0x10(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D6
type_guessed: byte[16]

tool: {"D3": [0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40,0x40]}

tool: {"D6": [0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f,0x7f]}

assistant: ```c
void foo3(signed char *w) {
  int i;
  signed char *ww = __builtin_assume_aligned(w, 8);
  for (i = 0; i < 32; i++)
    ww[i] = ww[i] / 2;
}
```