ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<fifteen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L35
  cmpl   $0x2,-0x4(%rbp)
  je     L32
  jmp    L46
L35:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L32:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L46:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L30:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D17: You passed in the value of one!


tool: D23: You passed in the value of two!


tool: D12: You passed in some other value!


assistant: ```c
void fifteen(const int value) {
  switch (value) {
  case 1:
    printf("You passed in the value of one!\n");
    break;
  case 2:
    printf("You passed in the value of two!\n");
    break;
  default:
    printf("You passed in some other value!\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fifteen>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L29
  cmp    $0x2,%edi
  je     L32
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L23
L29:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L23:
  add    $0x8,%rsp
  ret
L32:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L23
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string
name: unpack_data
arguments: data_label: D26
datatype: string

tool: D0: You passed in some other value!


tool: D5: You passed in the value of one!


tool: D26: You passed in the value of two!


assistant: ```c
void fifteen(const int value) {
  switch (value) {
  case 1:
    printf("You passed in the value of one!\n");
    break;
  case 2:
    printf("You passed in the value of two!\n");
    break;
  default:
    printf("You passed in some other value!\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fifteen>:
  endbr64
  cmp    $0x1,%edi
  je     L15
  cmp    $0x2,%edi
  je     L9
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L15:
  lea    D19(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L9:
  lea    D13(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D7: You passed in some other value!


tool: D19: You passed in the value of one!


tool: D13: You passed in the value of two!


assistant: ```c
void fifteen(const int value) {
  switch (value) {
  case 1:
    printf("You passed in the value of one!\n");
    break;
  case 2:
    printf("You passed in the value of two!\n");
    break;
  default:
    printf("You passed in some other value!\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fifteen>:
  endbr64
  cmp    $0x1,%edi
  je     L7
  cmp    $0x2,%edi
  je     L4
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D14(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L4:
  lea    D18(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D20
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D20: You passed in some other value!


tool: D14: You passed in the value of one!


tool: D18: You passed in the value of two!


assistant: ```c
void fifteen(const int value) {
  switch (value) {
  case 1:
    printf("You passed in the value of one!\n");
    break;
  case 2:
    printf("You passed in the value of two!\n");
    break;
  default:
    printf("You passed in some other value!\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sethostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sethostname>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sethostname>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sethostname>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sethostname(const char *name, size_t len) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L31
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L31:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strlwr(char *string) {
  char *cp;
  for (cp = string; *cp; ++cp) {
    if ('A' <= *cp && *cp <= 'Z')
      *cp += 'a' - 'A';
  }
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlwr>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L21
  mov    %rdi,%rcx
  jmp    L19
L42:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L21
L19:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L42
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L42
L21:
  ret
```

assistant: ```c
char *strlwr(char *string) {
  char *cp;
  for (cp = string; *cp; ++cp) {
    if ('A' <= *cp && *cp <= 'Z')
      *cp += 'a' - 'A';
  }
  return string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L8
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L7:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L18
  add    $0x20,%edx
  mov    %dl,(%rcx)
L18:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L7
L8:
  ret
```

assistant: ```c
char *strlwr(char *string) {
  char *cp;
  for (cp = string; *cp; ++cp) {
    if ('A' <= *cp && *cp <= 'Z')
      *cp += 'a' - 'A';
  }
  return string;
}
```
user: What is the c source code of the assembly code below:

```asm
<strlwr>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L33
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L18:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L21
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L18
L33:
  ret
```

assistant: ```c
char *strlwr(char *string) {
  char *cp;
  for (cp = string; *cp; ++cp) {
    if ('A' <= *cp && *cp <= 'Z')
      *cp += 'a' - 'A';
  }
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hopperFatalErr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hogCPU@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  mov    $0x4e20,%edi
  call   <wait1Msec@plt>
  mov    $0x0,%eax
  call   <StopAllTasks@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: Hopper Err

assistant: ```c
void hopperFatalErr() {
  hogCPU();
  nxtDisplayCenteredBigTextLine(1, "Hopper Err");
  wait1Msec(20 * 1000);
  StopAllTasks();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hopperFatalErr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hogCPU@plt>
  lea    D6(%rip),%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  mov    $0x4e20,%edi
  call   <wait1Msec@plt>
  mov    $0x0,%eax
  call   <StopAllTasks@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: Hopper Err

assistant: ```c
void hopperFatalErr() {
  hogCPU();
  nxtDisplayCenteredBigTextLine(1, "Hopper Err");
  wait1Msec(20 * 1000);
  StopAllTasks();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hopperFatalErr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hogCPU@plt>
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  mov    $0x4e20,%edi
  call   <wait1Msec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <StopAllTasks@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9: Hopper Err

assistant: ```c
void hopperFatalErr() {
  hogCPU();
  nxtDisplayCenteredBigTextLine(1, "Hopper Err");
  wait1Msec(20 * 1000);
  StopAllTasks();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hopperFatalErr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hogCPU@plt>
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  call   <nxtDisplayCenteredBigTextLine@plt>
  mov    $0x4e20,%edi
  call   <wait1Msec@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <StopAllTasks@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D0: Hopper Err

assistant: ```c
void hopperFatalErr() {
  hogCPU();
  nxtDisplayCenteredBigTextLine(1, "Hopper Err");
  wait1Msec(20 * 1000);
  StopAllTasks();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<show_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <serial_puts@plt>
  mov    $0x20,%edi
  call   <serial_putc@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <printn@plt>
  mov    $0xa,%edi
  call   <serial_putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void show_n(char *s, int val) {
  serial_puts(s);
  serial_putc(' ');
  printn(val);
  serial_putc('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<show_n>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <serial_puts@plt>
  mov    $0x20,%edi
  call   <serial_putc@plt>
  mov    %ebx,%edi
  call   <printn@plt>
  mov    $0xa,%edi
  call   <serial_putc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void show_n(char *s, int val) {
  serial_puts(s);
  serial_putc(' ');
  printn(val);
  serial_putc('\n');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<show_n>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <serial_puts@plt>
  mov    $0x20,%edi
  call   <serial_putc@plt>
  mov    %ebp,%edi
  call   <printn@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <serial_putc@plt>
```

assistant: ```c
void show_n(char *s, int val) {
  serial_puts(s);
  serial_putc(' ');
  printn(val);
  serial_putc('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<show_n>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <serial_puts@plt>
  mov    $0x20,%edi
  call   <serial_putc@plt>
  mov    %ebp,%edi
  call   <printn@plt>
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <serial_putc@plt>
```

assistant: ```c
void show_n(char *s, int val) {
  serial_puts(s);
  serial_putc(' ');
  printn(val);
  serial_putc('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pm_writebiglong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sar    $0x18,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  sar    $0x10,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  sar    $0x8,%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <putc@plt>
  mov    -0x10(%rbp),%rax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <putc@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int pm_writebiglong(FILE *const ofP, long const l) {
  putc((l >> 24) & 0xff, ofP);
  putc((l >> 16) & 0xff, ofP);
  putc((l >> 8) & 0xff, ofP);
  putc((l >> 0) & 0xff, ofP);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pm_writebiglong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  sar    $0x18,%rdi
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    %rbx,%rdi
  sar    $0x10,%rdi
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writebiglong(FILE *const ofP, long const l) {
  putc((l >> 24) & 0xff, ofP);
  putc((l >> 16) & 0xff, ofP);
  putc((l >> 8) & 0xff, ofP);
  putc((l >> 0) & 0xff, ofP);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pm_writebiglong>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sar    $0x18,%rdi
  mov    %rsi,%rbx
  mov    %rbp,%rsi
  movzbl %dil,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  sar    $0x10,%rdi
  movzbl %dil,%edi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writebiglong(FILE *const ofP, long const l) {
  putc((l >> 24) & 0xff, ofP);
  putc((l >> 16) & 0xff, ofP);
  putc((l >> 8) & 0xff, ofP);
  putc((l >> 0) & 0xff, ofP);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pm_writebiglong>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sar    $0x18,%rdi
  mov    %rsi,%rbx
  mov    %rbp,%rsi
  movzbl %dil,%edi
  sub    $0x8,%rsp
  call   <putc@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  sar    $0x10,%rdi
  movzbl %dil,%edi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int pm_writebiglong(FILE *const ofP, long const l) {
  putc((l >> 24) & 0xff, ofP);
  putc((l >> 16) & 0xff, ofP);
  putc((l >> 8) & 0xff, ofP);
  putc((l >> 0) & 0xff, ofP);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L26
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  je     L19
  addl   $0x1,-0xc(%rbp)
  jmp    L14
L19:
  nop
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
datatype: string
name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D35
datatype: string
name: disassemble_data
arguments: tag: D32
datatype: string

tool: D28: Please insert wanted prime number:

tool: D22: %d

tool: D35: The %d. prime number is:


tool: D32: %d


assistant: ```c
int main() {
  int meja;
  printf("Please insert wanted prime number:\n");
  scanf("%d", &meja);
  int counter = 0;
  int stevilo = 2;
  while (1) {
    if (isPrime(stevilo)) {
      counter++;
    }
    if (counter == meja) {
      break;
    }
    stevilo++;
  }
  printf("The %d. prime number is:\n", meja);
  printf("%d\n", stevilo);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    $0x2,%ebp
  mov    $0x0,%ebx
  jmp    L7
L12:
  add    $0x1,%ebp
L7:
  mov    %ebp,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebx
  cmp    %ebx,0x4(%rsp)
  jne    L12
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D6: Please insert wanted prime number:

tool: D17: %d

tool: D4: The %d. prime number is:


tool: D7: %d


assistant: ```c
int main() {
  int meja;
  printf("Please insert wanted prime number:\n");
  scanf("%d", &meja);
  int counter = 0;
  int stevilo = 2;
  while (1) {
    if (isPrime(stevilo)) {
      counter++;
    }
    if (counter == meja) {
      break;
    }
    stevilo++;
  }
  printf("The %d. prime number is:\n", meja);
  printf("%d\n", stevilo);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D32(%rip),%rdi
  mov    $0x2,%r12d
  push   %rbp
  xor    %ebp,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%r12d
L7:
  mov    %r12d,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L29
  mov    %ebp,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D32
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D28
datatype: string
name: disassemble_data
arguments: data_label: D34
datatype: string

tool: D32: Please insert wanted prime number:

tool: D10: %d

tool: D28: The %d. prime number is:


tool: D34: %d


assistant: ```c
int main() {
  int meja;
  printf("Please insert wanted prime number:\n");
  scanf("%d", &meja);
  int counter = 0;
  int stevilo = 2;
  while (1) {
    if (isPrime(stevilo)) {
      counter++;
    }
    if (counter == meja) {
      break;
    }
    stevilo++;
  }
  printf("The %d. prime number is:\n", meja);
  printf("%d\n", stevilo);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%rdi
  mov    $0x2,%r12d
  push   %rbp
  xor    %ebp,%ebp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%r12d
L8:
  mov    %r12d,%edi
  call   <isPrime@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  cmp    %ebp,0x4(%rsp)
  jne    L25
  mov    %ebp,%esi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D35
data_type: string
name: retrieve_data
arguments: data_label: D36
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string

tool: D25: Please insert wanted prime number:

tool: D35: %d

tool: D36: The %d. prime number is:


tool: D23: %d


assistant: ```c
int main() {
  int meja;
  printf("Please insert wanted prime number:\n");
  scanf("%d", &meja);
  int counter = 0;
  int stevilo = 2;
  while (1) {
    if (isPrime(stevilo)) {
      counter++;
    }
    if (counter == meja) {
      break;
    }
    stevilo++;
  }
  printf("The %d. prime number is:\n", meja);
  printf("%d\n", stevilo);
  return 0;
}
```