ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dger_3l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9d,-0x40(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L20
  cmpl   $0x0,-0x28(%rbp)
  je     L20
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L60
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  je     L20
L60:
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L32
L8:
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  -0x30(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L57
L7:
  mov    0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mov    0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x20(%rbp)
L57:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  mov    -0x40(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L8
  jmp    L14
L20:
  nop
L14:
  pop    %rbp
  ret
```

assistant: ```c
void dger_3l(int m, int n, double alpha, double *x, int incx, double *y, int incy, double *A, int lda) {
  if (m == 0 || n == 0 || alpha == 0.0)
    return;
  int i, j;
  double *px, *py, temp;
  py = y;
  for (j = 0; j < n; j++) {
    temp = alpha * py[0];
    px = x;
    for (i = 0; i < m; i++) {
      A[i + lda * j] += px[0] * temp;
      px += incx;
    }
    py += incy;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dger_3l>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x30(%rsp),%r12
  test   %edi,%edi
  je     L56
  mov    %edi,%r11d
  mov    %esi,%ebx
  mov    %rdx,%rbp
  ucomisd D6(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  jne    L56
  test   %esi,%esi
  jle    L56
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  movslq %r9d,%r9
  lea    0x0(,%r9,8),%r10
  mov    $0x0,%r9d
  mov    $0x0,%edi
  lea    -0x1(%r11),%r14d
  lea    0x8(%r12),%r13
L30:
  movapd %xmm0,%xmm2
  mulsd  (%r8),%xmm2
  test   %r11d,%r11d
  jle    L3
  movslq %r9d,%rdx
  lea    (%r12,%rdx,8),%rax
  add    %r14,%rdx
  lea    0x0(%r13,%rdx,8),%rsi
  mov    %rbp,%rdx
L13:
  movapd %xmm2,%xmm1
  mulsd  (%rdx),%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    %rcx,%rdx
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L13
L3:
  add    %r10,%r8
  add    $0x1,%edi
  add    0x38(%rsp),%r9d
  cmp    %edi,%ebx
  jne    L30
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: f64

tool: D6: 0

assistant: ```c
void dger_3l(int m, int n, double alpha, double *x, int incx, double *y, int incy, double *A, int lda) {
  if (m == 0 || n == 0 || alpha == 0.0)
    return;
  int i, j;
  double *px, *py, temp;
  py = y;
  for (j = 0; j < n; j++) {
    temp = alpha * py[0];
    px = x;
    for (i = 0; i < m; i++) {
      A[i + lda * j] += px[0] * temp;
      px += incx;
    }
    py += incy;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dger_3l>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x30(%rsp),%r12
  test   %edi,%edi
  je     L18
  mov    %rdx,%rbp
  sete   %dl
  ucomisd D5(%rip),%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  jne    L18
  mov    %esi,%ebx
  test   %esi,%esi
  jle    L18
  mov    %edi,%r11d
  movslq %r9d,%r9
  movslq %ecx,%rcx
  xor    %edi,%edi
  lea    0x0(,%r9,8),%r10
  shl    $0x3,%rcx
  lea    -0x1(%r11),%r14d
  xor    %r9d,%r9d
  lea    0x8(%r12),%r13
  nopw   0x0(%rax,%rax,1)
L16:
  movsd  (%r8),%xmm2
  mulsd  %xmm0,%xmm2
  test   %r11d,%r11d
  jle    L6
  movslq %r9d,%rdx
  lea    (%r12,%rdx,8),%rax
  add    %r14,%rdx
  lea    0x0(%r13,%rdx,8),%rsi
  mov    %rbp,%rdx
L3:
  movsd  (%rdx),%xmm1
  add    $0x8,%rax
  add    %rcx,%rdx
  mulsd  %xmm2,%xmm1
  addsd  -0x8(%rax),%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L3
L6:
  add    $0x1,%edi
  add    %r10,%r8
  add    0x38(%rsp),%r9d
  cmp    %edi,%ebx
  jne    L16
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: f64

tool: D5: 0

assistant: ```c
void dger_3l(int m, int n, double alpha, double *x, int incx, double *y, int incy, double *A, int lda) {
  if (m == 0 || n == 0 || alpha == 0.0)
    return;
  int i, j;
  double *px, *py, temp;
  py = y;
  for (j = 0; j < n; j++) {
    temp = alpha * py[0];
    px = x;
    for (i = 0; i < m; i++) {
      A[i + lda * j] += px[0] * temp;
      px += incx;
    }
    py += incy;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  -0x14(%rbp),%xmm2
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm3
  movss  -0x18(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm2
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x20(%rbp),%xmm3
  movss  -0x14(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x20(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm2
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L23
  ucomiss %xmm1,%xmm0
  jne    L23
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L14
L23:
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D13
type: string
name: unpack_data
arguments: label: D15
type: string

tool: D25: %f%f%f%f

tool: D13: INF

tool: D15: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b2 * a1 - b1 * a2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm4
  movss  0x8(%rsp),%xmm5
  movaps %xmm0,%xmm2
  mulss  %xmm5,%xmm2
  movss  0x10(%rsp),%xmm1
  movaps %xmm4,%xmm3
  mulss  %xmm1,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L1
  jne    L1
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L1:
  subss  %xmm5,%xmm1
  movaps %xmm3,%xmm5
  subss  %xmm2,%xmm5
  divss  %xmm5,%xmm1
  subss  %xmm4,%xmm0
  subss  %xmm3,%xmm2
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D24(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L24
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type_guessed: string
name: disassemble_data
arguments: data_label: D27
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string

tool: D28: %f%f%f%f

tool: D27: INF

tool: D24: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b2 * a1 - b1 * a2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D24(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm4
  movss  0x8(%rsp),%xmm5
  movss  0x10(%rsp),%xmm1
  movaps %xmm0,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm5,%xmm2
  mulss  %xmm1,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L34
  jne    L34
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L34:
  subss  %xmm5,%xmm1
  movaps %xmm3,%xmm5
  subss  %xmm4,%xmm0
  mov    $0x2,%eax
  subss  %xmm2,%xmm5
  subss  %xmm3,%xmm2
  lea    D23(%rip),%rdi
  divss  %xmm5,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L11
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D23
datatype: string

tool: D24: %f%f%f%f

tool: D22: INF

tool: D23: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b2 * a1 - b1 * a2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D18(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0xc(%rsp),%xmm4
  movss  0x8(%rsp),%xmm5
  movss  0x10(%rsp),%xmm1
  movaps %xmm0,%xmm2
  movaps %xmm4,%xmm3
  mulss  %xmm5,%xmm2
  mulss  %xmm1,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L20
  jne    L20
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L20:
  subss  %xmm5,%xmm1
  movaps %xmm3,%xmm5
  subss  %xmm4,%xmm0
  mov    $0x2,%eax
  subss  %xmm2,%xmm5
  subss  %xmm3,%xmm2
  lea    D9(%rip),%rdi
  divss  %xmm5,%xmm1
  divss  %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L4
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D12
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string

tool: D18: %f%f%f%f

tool: D12: INF

tool: D9: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f%f%f%f", &a1, &b1, &a2, &b2);
  float X = (b2 - b1) / ((b2 * a1 - b1 * a2));
  float Y = (a2 - a1) / ((b1 * a2) - (a1 * b2));
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    printf("(%.3f,%.3f)", X, Y);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<deserialize_float32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unpacku32@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <unpack754@plt>
  leave
  ret
```

assistant: ```c
extern long double deserialize_float32(unsigned char *buf) {
  unsigned long long int fhold = unpacku32(buf);
  return ((unpack754((fhold), 32, 8)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deserialize_float32>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku32@plt>
  mov    %rax,%rdi
  mov    $0x8,%edx
  mov    $0x20,%esi
  call   <unpack754@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern long double deserialize_float32(unsigned char *buf) {
  unsigned long long int fhold = unpacku32(buf);
  return ((unpack754((fhold), 32, 8)));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<deserialize_float32>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku32@plt>
  mov    $0x8,%edx
  mov    $0x20,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <unpack754@plt>
```

assistant: ```c
extern long double deserialize_float32(unsigned char *buf) {
  unsigned long long int fhold = unpacku32(buf);
  return ((unpack754((fhold), 32, 8)));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<deserialize_float32>:
  endbr64
  sub    $0x8,%rsp
  call   <unpacku32@plt>
  mov    $0x8,%edx
  mov    $0x20,%esi
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <unpack754@plt>
```

assistant: ```c
extern long double deserialize_float32(unsigned char *buf) {
  unsigned long long int fhold = unpacku32(buf);
  return ((unpack754((fhold), 32, 8)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_chop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L2:
  nop
  leave
  ret
```

assistant: ```c
void str_chop(char *str) {
  if (strlen(str) > 0) {
    *(str + strlen(str) - 1) = '\0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_chop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jg     L8
L13:
  pop    %rbx
  ret
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L13
```

assistant: ```c
void str_chop(char *str) {
  if (strlen(str) > 0) {
    *(str + strlen(str) - 1) = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_chop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jg     L4
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void str_chop(char *str) {
  if (strlen(str) > 0) {
    *(str + strlen(str) - 1) = '\0';
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_chop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jg     L2
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void str_chop(char *str) {
  if (strlen(str) > 0) {
    *(str + strlen(str) - 1) = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_empty_graph@plt>
  mov    $0x0,%eax
  call   <test_simple_graph@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_empty_graph();
  test_simple_graph();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_empty_graph@plt>
  mov    $0x0,%eax
  call   <test_simple_graph@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_empty_graph();
  test_simple_graph();
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_empty_graph@plt>
  xor    %eax,%eax
  call   <test_simple_graph@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_empty_graph();
  test_simple_graph();
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_empty_graph@plt>
  xor    %eax,%eax
  call   <test_simple_graph@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_empty_graph();
  test_simple_graph();
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *head, int i, int j) {
  int temp = head[i];
  head[i] = head[j];
  head[j] = temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *head, int i, int j) {
  int temp = head[i];
  head[i] = head[j];
  head[j] = temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *head, int i, int j) {
  int temp = head[i];
  head[i] = head[j];
  head[j] = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *head, int i, int j) {
  int temp = head[i];
  head[i] = head[j];
  head[j] = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fpwr2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0xffffffeb,%eax
  sub    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L8
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L8:
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  sub    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L22
  movl   $0x0,-0xc(%rbp)
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0xffffffeb,%edx
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L19
L22:
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  cmp    %eax,-0x14(%rbp)
  jge    L29
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L29:
  movl   $0xff,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  shl    $0x17,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <u2f@plt>
  leave
  ret
```

assistant: ```c
float fpwr2(int x) {
  unsigned exp, frac;
  unsigned u;
  if (x < 2 - pow(2, 7) - 23) {
    exp = 0;
    frac = 0;
  } else if (x < 2 - pow(2, 7)) {
    exp = 0;
    frac = 1 << (unsigned)(x - (2 - pow(2, 7) - 23));
  } else if (x < pow(2, 7) - 1 + 1) {
    exp = pow(2, 7) - 1 + x;
    frac = 0;
  } else {
    exp = 0xFF;
    frac = 0;
  }
  u = exp << 23 | frac;
  return u2f(u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fpwr2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0xffffffeb,%eax
  sub    %edx,%eax
  mov    $0x0,%edx
  mov    $0x0,%edi
  cmp    %ebx,%eax
  jle    L33
L37:
  shl    $0x17,%edi
  or     %edx,%edi
  call   <u2f@plt>
  pop    %rbx
  ret
L33:
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  sub    %edx,%eax
  cmp    %ebx,%eax
  jle    L29
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    0x15(%rbx,%rax,1),%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  mov    $0x0,%edi
  jmp    L37
L29:
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x0,%edx
  mov    $0xff,%edi
  cmp    %ebx,%eax
  jle    L37
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rbx,%rax,1),%edi
  mov    $0x0,%edx
  jmp    L37
```

assistant: ```c
float fpwr2(int x) {
  unsigned exp, frac;
  unsigned u;
  if (x < 2 - pow(2, 7) - 23) {
    exp = 0;
    frac = 0;
  } else if (x < 2 - pow(2, 7)) {
    exp = 0;
    frac = 1 << (unsigned)(x - (2 - pow(2, 7) - 23));
  } else if (x < pow(2, 7) - 1 + 1) {
    exp = pow(2, 7) - 1 + x;
    frac = 0;
  } else {
    exp = 0xFF;
    frac = 0;
  }
  u = exp << 23 | frac;
  return u2f(u);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fpwr2>:
  endbr64
  push   %rbp
  mov    $0x7,%esi
  mov    $0xffffffeb,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  sub    $0x8,%rsp
  call   <pow@plt>
  xor    %edi,%edi
  mov    %eax,%r8d
  mov    %ebp,%eax
  sub    %r8d,%eax
  cmp    %ebx,%eax
  jle    L27
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1070 <u2f@plt>
  nopl   0x0(%rax)
L27:
  mov    $0x7,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x7,%esi
  mov    $0x2,%edi
  mov    %eax,%r8d
  mov    $0x2,%eax
  sub    %r8d,%eax
  cmp    %ebx,%eax
  jg     L20
  call   <pow@plt>
  mov    $0x7f800000,%edi
  cmp    %ebx,%eax
  jle    L17
  mov    $0x2,%edi
  mov    $0x7,%esi
  call   <pow@plt>
  lea    -0x1(%rbx,%rax,1),%edi
  shl    $0x17,%edi
  jmp    L17
  xchg   %ax,%ax
L20:
  call   <pow@plt>
  mov    %ebx,%ecx
  add    $0x8,%rsp
  mov    $0x1,%edi
  sub    %eax,%ebp
  pop    %rbx
  sub    %ebp,%ecx
  pop    %rbp
  shl    %cl,%edi
  jmp    1070 <u2f@plt>
```

assistant: ```c
float fpwr2(int x) {
  unsigned exp, frac;
  unsigned u;
  if (x < 2 - pow(2, 7) - 23) {
    exp = 0;
    frac = 0;
  } else if (x < 2 - pow(2, 7)) {
    exp = 0;
    frac = 1 << (unsigned)(x - (2 - pow(2, 7) - 23));
  } else if (x < pow(2, 7) - 1 + 1) {
    exp = pow(2, 7) - 1 + x;
    frac = 0;
  } else {
    exp = 0xFF;
    frac = 0;
  }
  u = exp << 23 | frac;
  return u2f(u);
}
```