ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<cur_time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  movsd  D6(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: byte[8]

tool: {"D6": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double cur_time(void) {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return tv.tv_sec + tv.tv_usec * 1.0e-6;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cur_time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  movsd  D9(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double cur_time(void) {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return tv.tv_sec + tv.tv_usec * 1.0e-6;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cur_time>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <gettimeofday@plt>
  movsd  D4(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  addsd  0x10(%rsp),%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: byte[8]

tool: {"D4": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double cur_time(void) {
  struct timeval tv;
  struct timezone tz;
  gettimeofday(&tv, &tz);
  return tv.tv_sec + tv.tv_usec * 1.0e-6;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L17:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mul(int x, int y) {
  int ret = 0;
  while (x--) {
    ret += y;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mul>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rdi),%edx
  test   %edi,%edi
  je     L13
L8:
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L8
  imul   %esi,%eax
L13:
  ret
```

assistant: ```c
int mul(int x, int y) {
  int ret = 0;
  while (x--) {
    ret += y;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mul>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int mul(int x, int y) {
  int ret = 0;
  while (x--) {
    ret += y;
  }
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mul>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
int mul(int x, int y) {
  int ret = 0;
  while (x--) {
    ret += y;
  }
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ivaluation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L11:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L11
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ivaluation(int a) {
  unsigned int uit = 0;
  while (!(a % 3)) {
    a = a / 3;
    uit++;
  }
  return (uit);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ivaluation>:
  endbr64
  mov    %edi,%ecx
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  jne    L9
  mov    $0x0,%esi
L27:
  movslq %ecx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    $0x1,%esi
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,2),%edx
  cmp    %edx,%eax
  je     L27
L26:
  mov    %esi,%eax
  ret
L9:
  mov    $0x0,%esi
  jmp    L26
```

assistant: ```c
unsigned int ivaluation(int a) {
  unsigned int uit = 0;
  while (!(a % 3)) {
    a = a / 3;
    uit++;
  }
  return (uit);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ivaluation>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  xor    %r8d,%r8d
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L7
  nopl   0x0(%rax)
L15:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  mov    %eax,%edi
  sub    %edx,%edi
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L15
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ivaluation(int a) {
  unsigned int uit = 0;
  while (!(a % 3)) {
    a = a / 3;
    uit++;
  }
  return (uit);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ivaluation>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  xor    %r8d,%r8d
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  ja     L6
  nopl   0x0(%rax)
L10:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edx
  shr    $0x20,%rax
  mov    %eax,%edi
  sub    %edx,%edi
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  jbe    L10
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int ivaluation(int a) {
  unsigned int uit = 0;
  while (!(a % 3)) {
    a = a / 3;
    uit++;
  }
  return (uit);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<initInstructions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D94(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D66(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D105(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    D71(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D94(%rip),%rax
  mov    %rax,-0x78(%rbp)
  lea    D66(%rip),%rax
  mov    %rax,-0x70(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,-0x68(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x60(%rbp)
  lea    D105(%rip),%rax
  mov    %rax,-0x58(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D71(%rip),%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x80(%rbp)
  jmp    L22
L25:
  mov    -0x80(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%rax
  mov    -0x80(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fillLines@plt>
  mov    %eax,-0x7c(%rbp)
  mov    -0x7c(%rbp),%edx
  mov    -0x80(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fillSpaces@plt>
  addl   $0x1,-0x80(%rbp)
L22:
  cmpl   $0x6,-0x80(%rbp)
  jle    L25
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D94
type_infered: string
name: retrieve_data
arguments: label: D66
type_infered: string
name: retrieve_data
arguments: label: D48
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D105
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D71
type_infered: string

tool: D94:  New to gedit? Here are some tips...

tool: D66:     -> Tab to enter/exit writeMode

tool: D48:         In writeMode

tool: D5:          |

tool: D105:          |-> wasd to navigate

tool: D2:          |-> c to clear screen

tool: D71:          |-> q to quit

assistant: ```c
void initInstructions() {
  char *lines[7] = {" New to gedit? Here are some tips...", "    -> Tab to enter/exit writeMode", "        In writeMode", "         |", "         |-> wasd to navigate", "         |-> c to clear screen", "         |-> q to quit"};
  char *line1 = " New to gedit? Here are some tips...";
  char *line2 = "    -> Tab to enter/exit writeMode";
  char *line3 = "        In writeMode";
  char *line4 = "         |";
  char *line5 = "         |-> wasd to navigate";
  char *line6 = "         |-> c to clear screen";
  char *line7 = "         |-> q to quit";
  for (int i = 0; i < 7; i++) {
    int cantChars = fillLines(lines[i], i);
    fillSpaces(i, cantChars);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initInstructions>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rax
  mov    %rax,(%rsp)
  lea    D37(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D24(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D3(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D47(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    $0x0,%ebx
L5:
  mov    (%rsp,%rbx,8),%rdi
  mov    %ebx,%esi
  call   <fillLines@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <fillSpaces@plt>
  add    $0x1,%rbx
  cmp    $0x7,%rbx
  jne    L5
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D42
type: string
name: unpack_data
arguments: tag: D37
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D47
type: string

tool: D42:  New to gedit? Here are some tips...

tool: D37:     -> Tab to enter/exit writeMode

tool: D19:         In writeMode

tool: D12:          |

tool: D24:          |-> wasd to navigate

tool: D3:          |-> c to clear screen

tool: D47:          |-> q to quit

assistant: ```c
void initInstructions() {
  char *lines[7] = {" New to gedit? Here are some tips...", "    -> Tab to enter/exit writeMode", "        In writeMode", "         |", "         |-> wasd to navigate", "         |-> c to clear screen", "         |-> q to quit"};
  char *line1 = " New to gedit? Here are some tips...";
  char *line2 = "    -> Tab to enter/exit writeMode";
  char *line3 = "        In writeMode";
  char *line4 = "         |";
  char *line5 = "         |-> wasd to navigate";
  char *line6 = "         |-> c to clear screen";
  char *line7 = "         |-> q to quit";
  for (int i = 0; i < 7; i++) {
    int cantChars = fillLines(lines[i], i);
    fillSpaces(i, cantChars);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initInstructions>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D15(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D36(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D44(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D13(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D43(%rip),%rax
  mov    %rax,0x30(%rsp)
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%rsp,%rbx,8),%rdi
L7:
  mov    %ebx,%esi
  call   <fillLines@plt>
  mov    %ebx,%edi
  add    $0x1,%rbx
  mov    %eax,%esi
  call   <fillSpaces@plt>
  cmp    $0x7,%rbx
  jne    L26
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D36
type_infered: string
name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D13
type_infered: string
name: retrieve_data
arguments: data_tag: D43
type_infered: string

tool: D6:  New to gedit? Here are some tips...

tool: D15:     -> Tab to enter/exit writeMode

tool: D0:         In writeMode

tool: D36:          |

tool: D44:          |-> wasd to navigate

tool: D13:          |-> c to clear screen

tool: D43:          |-> q to quit

assistant: ```c
void initInstructions() {
  char *lines[7] = {" New to gedit? Here are some tips...", "    -> Tab to enter/exit writeMode", "        In writeMode", "         |", "         |-> wasd to navigate", "         |-> c to clear screen", "         |-> q to quit"};
  char *line1 = " New to gedit? Here are some tips...";
  char *line2 = "    -> Tab to enter/exit writeMode";
  char *line3 = "        In writeMode";
  char *line4 = "         |";
  char *line5 = "         |-> wasd to navigate";
  char *line6 = "         |-> c to clear screen";
  char *line7 = "         |-> q to quit";
  for (int i = 0; i < 7; i++) {
    int cantChars = fillLines(lines[i], i);
    fillSpaces(i, cantChars);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<initInstructions>:
  endbr64
  push   %r12
  lea    D69(%rip),%rdx
  lea    D40(%rip),%rcx
  push   %rbp
  movq   %rdx,%xmm0
  lea    D10(%rip),%rdx
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  lea    D68(%rip),%rax
  mov    %rsp,%r12
  movq   %rax,%xmm1
  lea    D57(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D23(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm3
  lea    D33(%rip),%rax
  punpcklqdq %xmm2,%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x10(%rsp)
  movq   %rdx,%xmm0
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
  nopl   (%rax)
L8:
  mov    (%r12,%rbx,8),%rdi
  mov    %ebx,%esi
  call   <fillLines@plt>
  mov    %ebx,%edi
  add    $0x1,%rbx
  mov    %eax,%esi
  call   <fillSpaces@plt>
  cmp    $0x7,%rbx
  jne    L8
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D69
type: string
name: extract_symbolic_data
arguments: label: D40
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D68
type: string
name: extract_symbolic_data
arguments: label: D57
type: string
name: extract_symbolic_data
arguments: label: D23
type: string
name: extract_symbolic_data
arguments: label: D33
type: string

tool: D69:  New to gedit? Here are some tips...

tool: D40:         In writeMode

tool: D10:          |-> wasd to navigate

tool: D68:     -> Tab to enter/exit writeMode

tool: D57:          |

tool: D23:          |-> c to clear screen

tool: D33:          |-> q to quit

assistant: ```c
void initInstructions() {
  char *lines[7] = {" New to gedit? Here are some tips...", "    -> Tab to enter/exit writeMode", "        In writeMode", "         |", "         |-> wasd to navigate", "         |-> c to clear screen", "         |-> q to quit"};
  char *line1 = " New to gedit? Here are some tips...";
  char *line2 = "    -> Tab to enter/exit writeMode";
  char *line3 = "        In writeMode";
  char *line4 = "         |";
  char *line5 = "         |-> wasd to navigate";
  char *line6 = "         |-> c to clear screen";
  char *line7 = "         |-> q to quit";
  for (int i = 0; i < 7; i++) {
    int cantChars = fillLines(lines[i], i);
    fillSpaces(i, cantChars);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L145:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L145
  cmpb   $0x9,-0x9(%rbp)
  je     L145
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  movq   $0x0,-0x8(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L166
  cmpb   $0x2e,-0x9(%rbp)
  je     L166
  cmpb   $0x2d,-0x9(%rbp)
  je     L166
  movzbl -0x9(%rbp),%eax
  jmp    L95
L166:
  cmpb   $0x2d,-0x9(%rbp)
  jne    L70
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L96
  cmpb   $0x2e,-0x9(%rbp)
  jne    L82
L96:
  addq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L70
L82:
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %al,-0x9(%rbp)
  je     L114
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L114:
  mov    $0x2d,%eax
  jmp    L95
L70:
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L141
  nop
L56:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x9(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L56
L141:
  cmpb   $0x2e,-0x9(%rbp)
  jne    L83
  nop
L115:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x9(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L115
L83:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %al,-0x9(%rbp)
  je     L58
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L58:
  mov    $0x30,%eax
L95:
  leave
  ret
```

assistant: ```c
char getop(char s[]) {
  size_t i;
  char c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  i = 0;
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-') {
    if (isdigit(c = getch()) || c == '.')
      s[++i] = c;
    else {
      if (c != (char)EOF)
        ungetch(c);
      return '-';
    }
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != (char)EOF)
    ungetch(c);
  return '0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L2:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%al
  je     L2
  cmp    $0x20,%al
  je     L2
  movb   $0x0,0x1(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L98
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%al
  ja     L46
L98:
  mov    $0x0,%r12d
  cmp    $0x2d,%bl
  je     L50
L120:
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L17
L39:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  add    $0x1,%r12
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
L17:
  cmp    $0x2e,%bl
  je     L133
L116:
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    D12(%rip),%rax
  cmp    (%rax),%bl
  jne    L16
  mov    $0x30,%ebx
L46:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  movsbl %al,%r13d
  mov    %r13d,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r12b
  je     L0
  test   %rax,%rax
  je     L63
L0:
  mov    %r12b,0x1(%rbp)
  mov    %r12d,%ebx
  mov    $0x1,%r12d
  jmp    L120
L63:
  mov    D12(%rip),%rax
  cmp    (%rax),%r12b
  je     L46
  mov    %r13d,%edi
  call   <ungetch@plt>
  jmp    L46
L133:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  add    $0x1,%r12
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L133
  jmp    L116
L16:
  movsbl %bl,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L46
```

assistant: ```c
char getop(char s[]) {
  size_t i;
  char c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  i = 0;
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  if (c == '-') {
    if (isdigit(c = getch()) || c == '.')
      s[++i] = c;
    else {
      if (c != (char)EOF)
        ungetch(c);
      return '-';
    }
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != (char)EOF)
    ungetch(c);
  return '0';
}
```