ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<zapolnenie>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  xor    %edi,%edi
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %r13d,%r13d
  jle    L12
  lea    -0x1(%r13),%eax
  lea    -0x1(%rbp),%edx
  mov    $0xfffffffffffffffc,%r13
  lea    (%rax,%rax,4),%rax
  lea    0x0(,%rdx,4),%r12
  add    %rdx,%rax
  lea    0x4(%r14,%r12,1),%rbx
  lea    0x18(%r14,%rax,4),%r14
  nopl   0x0(%rax)
L27:
  mov    %r13,%r15
  sub    %r12,%r15
  add    %rbx,%r15
  test   %ebp,%ebp
  jle    L31
  nopl   (%rax)
L1:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r15)
  cmp    %rbx,%r15
  jne    L1
L31:
  add    $0x14,%rbx
  cmp    %r14,%rbx
  jne    L27
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void zapolnenie(int A[][5], int size_row, int size_column) {
  int i, j;
  srand(time(NULL));
  for (i = 0; i < size_row; i++)
    for (j = 0; j < size_column; j++)
      A[i][j] = rand() % 10;
}
```
user: What is the c source code of the assembly code below?

```asm
<zapolnenie>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  xor    %edi,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %r12d,%r12d
  jle    L62
  test   %ebp,%ebp
  jle    L62
  lea    -0x1(%r12),%eax
  lea    0x18(%r13),%rbx
  lea    (%rax,%rax,4),%rax
  lea    0x2c(%r13,%rax,4),%r12
  lea    -0x7(%rbp),%r13d
  add    $0x1,%r13
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbx)
  cmp    $0x1,%ebp
  je     L81
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x14(%rbx)
  cmp    $0x2,%ebp
  je     L81
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x10(%rbx)
  cmp    $0x3,%ebp
  je     L81
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbx)
  cmp    $0x4,%ebp
  je     L81
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x8(%rbx)
  cmp    $0x5,%ebp
  je     L81
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    $0x6,%ebp
  je     L81
  lea    (%rbx,%r13,4),%r14
  mov    %rbx,%r15
L97:
  xor    %eax,%eax
  add    $0x4,%r15
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x22,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r15)
  cmp    %r14,%r15
  jne    L97
  nopl   0x0(%rax)
L81:
  add    $0x14,%rbx
  cmp    %r12,%rbx
  jne    L34
L62:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void zapolnenie(int A[][5], int size_row, int size_column) {
  int i, j;
  srand(time(NULL));
  for (i = 0; i < size_row; i++)
    for (j = 0; j < size_column; j++)
      A[i][j] = rand() % 10;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vec3_scale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  movss  %xmm0,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x14(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *vec3_scale(float *result, float *a, float scalar) {
  result[0] = a[0] * scalar;
  result[1] = a[1] * scalar;
  result[2] = a[2] * scalar;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec3_scale>:
  endbr64
  mov    %rdi,%rax
  movaps %xmm0,%xmm1
  mulss  (%rsi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rsi),%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_scale(float *result, float *a, float scalar) {
  result[0] = a[0] * scalar;
  result[1] = a[1] * scalar;
  result[2] = a[2] * scalar;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<vec3_scale>:
  endbr64
  movss  (%rsi),%xmm1
  mov    %rdi,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_scale(float *result, float *a, float scalar) {
  result[0] = a[0] * scalar;
  result[1] = a[1] * scalar;
  result[2] = a[2] * scalar;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vec3_scale>:
  endbr64
  movss  (%rsi),%xmm1
  mov    %rdi,%rax
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rsi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  mulss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_scale(float *result, float *a, float scalar) {
  result[0] = a[0] * scalar;
  result[1] = a[1] * scalar;
  result[2] = a[2] * scalar;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D3(%rip),%eax
  add    $0x5,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i = ({
    static int i = 3;
    i + 5;
  });
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = ({
    static int i = 3;
    i + 5;
  });
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = ({
    static int i = 3;
    i + 5;
  });
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = ({
    static int i = 3;
    i + 5;
  });
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_fatal_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_fatal_error(char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handle_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handle_fatal_error(char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<handle_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void handle_fatal_error(char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<handle_fatal_error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void handle_fatal_error(char *msg) {
  perror(msg);
  exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L29
L23:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <op_len@plt>
  add    %rax,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L14
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  jne    L23
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  ja     L19
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L16
L19:
  mov    $0xffffffffffffffff,%rax
L16:
  leave
  ret
```

assistant: ```c
size_t set_len(const char *re, size_t re_len) {
  size_t len = 0;
  while (len < re_len && re[len] != ']') {
    len += op_len(re + len);
  }
  return len <= re_len ? len + 1 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  test   %rsi,%rsi
  je     L47
L2:
  lea    (%r12,%rbx,1),%rdi
  cmpb   $0x5d,(%rdi)
  je     L34
  call   <op_len@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L2
L34:
  mov    $0xffffffffffffffff,%rax
  cmp    %rbx,%rbp
  jb     L49
L10:
  lea    0x1(%rbx),%rax
L49:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %rsi,%rbx
  jmp    L10
```

assistant: ```c
size_t set_len(const char *re, size_t re_len) {
  size_t len = 0;
  while (len < re_len && re[len] != ']') {
    len += op_len(re + len);
  }
  return len <= re_len ? len + 1 : -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_len>:
  endbr64
  test   %rsi,%rsi
  je     L23
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L3:
  call   <op_len@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L19
L9:
  lea    (%r12,%rbx,1),%rdi
  cmpb   $0x5d,(%rdi)
  jne    L3
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L19:
  lea    0x1(%rbp),%rax
  mov    $0xffffffffffffffff,%rdx
  pop    %rbx
  pop    %rbp
  cmovne %rdx,%rax
  pop    %r12
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t set_len(const char *re, size_t re_len) {
  size_t len = 0;
  while (len < re_len && re[len] != ']') {
    len += op_len(re + len);
  }
  return len <= re_len ? len + 1 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_len>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L27:
  call   <op_len@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jbe    L3
L25:
  lea    (%r12,%rbx,1),%rdi
  cmpb   $0x5d,(%rdi)
  jne    L27
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L3:
  lea    0x1(%rbp),%rax
  mov    $0xffffffffffffffff,%rdx
  pop    %rbx
  pop    %rbp
  cmovne %rdx,%rax
  pop    %r12
  ret
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
size_t set_len(const char *re, size_t re_len) {
  size_t len = 0;
  while (len < re_len && re[len] != ']') {
    len += op_len(re + len);
  }
  return len <= re_len ? len + 1 : -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<dps_lsflags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <iosr_read@plt>
  add    $0x1fc,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
unsigned int dps_lsflags(void) {
  volatile unsigned int *lsflags;
  lsflags = (unsigned int *)((char *)iosr_read() + 0x1fc);
  return *lsflags;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dps_lsflags>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <iosr_read@plt>
  mov    0x1fc(%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int dps_lsflags(void) {
  volatile unsigned int *lsflags;
  lsflags = (unsigned int *)((char *)iosr_read() + 0x1fc);
  return *lsflags;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dps_lsflags>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iosr_read@plt>
  mov    0x1fc(%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int dps_lsflags(void) {
  volatile unsigned int *lsflags;
  lsflags = (unsigned int *)((char *)iosr_read() + 0x1fc);
  return *lsflags;
}
```
user: What is the c source code of the assembly code below:

```asm
<dps_lsflags>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iosr_read@plt>
  mov    0x1fc(%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int dps_lsflags(void) {
  volatile unsigned int *lsflags;
  lsflags = (unsigned int *)((char *)iosr_read() + 0x1fc);
  return *lsflags;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tm_hasdaylightsavingtimerules>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int tm_hasdaylightsavingtimerules(void) {
  tzset();
  return daylight;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tm_hasdaylightsavingtimerules>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tm_hasdaylightsavingtimerules(void) {
  tzset();
  return daylight;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tm_hasdaylightsavingtimerules>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tzset@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tm_hasdaylightsavingtimerules(void) {
  tzset();
  return daylight;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tm_hasdaylightsavingtimerules>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tzset@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tm_hasdaylightsavingtimerules(void) {
  tzset();
  return daylight;
}
```
user: What is the c source code of the assembly code below:

```asm
<tmpfile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <sys_tmpfile@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  FILE *tmp = sys_tmpfile();
  if (tmp != NULL) {
  }
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tmpfile>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <sys_tmpfile@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
FILE *tmpfile(void) {
  FILE *tmp = sys_tmpfile();
  if (tmp != NULL) {
  }
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<tmpfile>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <sys_tmpfile@plt>
```

assistant: ```c
FILE *tmpfile(void) {
  FILE *tmp = sys_tmpfile();
  if (tmp != NULL) {
  }
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tmpfile>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <sys_tmpfile@plt>
```

assistant: ```c
FILE *tmpfile(void) {
  FILE *tmp = sys_tmpfile();
  if (tmp != NULL) {
  }
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <checkPall@plt>
  test   %rax,%rax
  je     L8
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L14
L8:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
datatype: string
name: parse_data
arguments: label: D4
datatype: string

tool: D13: YES

tool: D4: NO

assistant: ```c
int main() {
  char str[10000];
  gets(str);
  if (checkPall(str)) {
    printf("YES");
  } else {
    printf("NO");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <checkPall@plt>
  test   %rax,%rax
  je     L2
  lea    D13(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x2720,%rsp
  pop    %rbx
  ret
L2:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D4
type: string

tool: D13: YES

tool: D4: NO

assistant: ```c
int main() {
  char str[10000];
  gets(str);
  if (checkPall(str)) {
    printf("YES");
  } else {
    printf("NO");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <checkPall@plt>
  test   %rax,%rax
  je     L29
  lea    D12(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x2720,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L29:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D12: YES

tool: D13: NO

assistant: ```c
int main() {
  char str[10000];
  gets(str);
  if (checkPall(str)) {
    printf("YES");
  } else {
    printf("NO");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x720,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <checkPall@plt>
  test   %rax,%rax
  je     L27
  lea    D17(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x2720,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L27:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string

tool: D17: YES

tool: D1: NO

assistant: ```c
int main() {
  char str[10000];
  gets(str);
  if (checkPall(str)) {
    printf("YES");
  } else {
    printf("NO");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fix_linebreaks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x0,-0x22(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L93:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpb   $0xa,-0x21(%rbp)
  je     L29
  cmpb   $0xd,-0x21(%rbp)
  jne    L5
L29:
  movl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L70
  cmpl   $0x0,-0x20(%rbp)
  je     L89
  movzbl -0x22(%rbp),%eax
  cmp    -0x21(%rbp),%al
  jne    L89
L70:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0xa,(%rax)
  addl   $0x1,-0x14(%rbp)
  jmp    L89
L5:
  cmpb   $0x0,-0x21(%rbp)
  je     L31
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x21(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
  jmp    L22
L31:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x20,(%rax)
  addl   $0x1,-0x14(%rbp)
  jmp    L22
L89:
  nop
L22:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  movzbl -0x21(%rbp),%eax
  mov    %al,-0x22(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L93
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fix_linebreaks(const unsigned char *src, int srclen, unsigned char *dst) {
  const unsigned char *rpos = src;
  unsigned char *wpos = dst;
  unsigned char prevchar = '\0';
  unsigned char curchar;
  int prevchar_was_cr_or_lf = 0;
  int curchar_is_cr_or_lf;
  int count = srclen;
  int dstlen = 0;
  while (count--) {
    curchar = *(rpos++);
    curchar_is_cr_or_lf = 0;
    if ((curchar == '\n') || (curchar == '\r')) {
      curchar_is_cr_or_lf = 1;
      if ((!prevchar_was_cr_or_lf) || ((prevchar_was_cr_or_lf) && (prevchar == curchar))) {
        *(wpos++) = '\n';
        dstlen++;
      }
    } else if (curchar != '\0') {
      *(wpos++) = curchar;
      dstlen++;
    } else {
      *(wpos++) = ' ';
      dstlen++;
    }
    prevchar_was_cr_or_lf = curchar_is_cr_or_lf;
    prevchar = curchar;
  }
  *wpos = '\0';
  return (dstlen);
}
```