ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<jstp_tx_bool>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L18
  mov    $0x74,%edi
  call   <jstp_tx_char@plt>
  mov    $0x72,%edi
  call   <jstp_tx_char@plt>
  mov    $0x75,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  call   <jstp_tx_char@plt>
L13:
  add    $0x8,%rsp
  ret
L18:
  mov    $0x66,%edi
  call   <jstp_tx_char@plt>
  mov    $0x61,%edi
  call   <jstp_tx_char@plt>
  mov    $0x6c,%edi
  call   <jstp_tx_char@plt>
  mov    $0x73,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  call   <jstp_tx_char@plt>
  jmp    L13
```

assistant: ```c
void jstp_tx_bool(int boolValue) {
  if (boolValue) {
    jstp_tx_char('t');
    jstp_tx_char('r');
    jstp_tx_char('u');
    jstp_tx_char('e');
  } else {
    jstp_tx_char('f');
    jstp_tx_char('a');
    jstp_tx_char('l');
    jstp_tx_char('s');
    jstp_tx_char('e');
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jstp_tx_bool>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L7
  mov    $0x74,%edi
  call   <jstp_tx_char@plt>
  mov    $0x72,%edi
  call   <jstp_tx_char@plt>
  mov    $0x75,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  add    $0x8,%rsp
  jmp    1050 <jstp_tx_char@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x66,%edi
  call   <jstp_tx_char@plt>
  mov    $0x61,%edi
  call   <jstp_tx_char@plt>
  mov    $0x6c,%edi
  call   <jstp_tx_char@plt>
  mov    $0x73,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  add    $0x8,%rsp
  jmp    1050 <jstp_tx_char@plt>
```

assistant: ```c
void jstp_tx_bool(int boolValue) {
  if (boolValue) {
    jstp_tx_char('t');
    jstp_tx_char('r');
    jstp_tx_char('u');
    jstp_tx_char('e');
  } else {
    jstp_tx_char('f');
    jstp_tx_char('a');
    jstp_tx_char('l');
    jstp_tx_char('s');
    jstp_tx_char('e');
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jstp_tx_bool>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L8
  mov    $0x74,%edi
  call   <jstp_tx_char@plt>
  mov    $0x72,%edi
  call   <jstp_tx_char@plt>
  mov    $0x75,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  add    $0x8,%rsp
  jmp    1050 <jstp_tx_char@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x66,%edi
  call   <jstp_tx_char@plt>
  mov    $0x61,%edi
  call   <jstp_tx_char@plt>
  mov    $0x6c,%edi
  call   <jstp_tx_char@plt>
  mov    $0x73,%edi
  call   <jstp_tx_char@plt>
  mov    $0x65,%edi
  add    $0x8,%rsp
  jmp    1050 <jstp_tx_char@plt>
```

assistant: ```c
void jstp_tx_bool(int boolValue) {
  if (boolValue) {
    jstp_tx_char('t');
    jstp_tx_char('r');
    jstp_tx_char('u');
    jstp_tx_char('e');
  } else {
    jstp_tx_char('f');
    jstp_tx_char('a');
    jstp_tx_char('l');
    jstp_tx_char('s');
    jstp_tx_char('e');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printResults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0xf,-0x4(%rbp)
  jle    L11
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D2: Printing Results!

tool: D11: Array[%d] = %d


assistant: ```c
void printResults(int array[]) {
  printf("Printing Results!\n");
  for (int i = 0; i < 16; i++) {
    printf("Array[%d] = %d\n", i, array[i]);
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printResults>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D18(%rip),%r12
L9:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string

tool: D7: Printing Results!

tool: D18: Array[%d] = %d


assistant: ```c
void printResults(int array[]) {
  printf("Printing Results!\n");
  for (int i = 0; i < 16; i++) {
    printf("Array[%d] = %d\n", i, array[i]);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printResults>:
  endbr64
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L5:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D17: Array[%d] = %d


tool: D13: Printing Results!

assistant: ```c
void printResults(int array[]) {
  printf("Printing Results!\n");
  for (int i = 0; i < 16; i++) {
    printf("Array[%d] = %d\n", i, array[i]);
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printResults>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
L3:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D0: Array[%d] = %d


tool: D1: Printing Results!

assistant: ```c
void printResults(int array[]) {
  printf("Printing Results!\n");
  for (int i = 0; i < 16; i++) {
    printf("Array[%d] = %d\n", i, array[i]);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string

tool: D9: Usage: packchr [OPTION...] FILE
packchr finds the unique tiles in a NES character (CHR) file.

Options:

  --nametable-base=NUM            Use NUM as nametable base tile index;
                                  i.e. the first tile will be referenced
                                  as NUM in the nametable, the second as
                                  NUM+1, etc.; by default NUM is 0
  --null-tile=NUM                 Use NUM as implicit null tile index; that is,
                                  don't produce any character data for a 'blank' tile
  --character-output=FILE         Store packed CHR in FILE
  --character-size=SIZE           Pad to SIZE bytes if necessary
  --nametable-output=FILE         Store nametable in FILE
  --verbose                       Print progress information to standard output
  --help                          Give this help list
  --usage                         Give a short usage message
  --version                       Print program version


assistant: ```c
void help() {
  printf("Usage: packchr [OPTION...] FILE\n"
         "packchr finds the unique tiles in a NES character (CHR) file.\n\n"
         "Options:\n\n"
         "  --nametable-base=NUM            Use NUM as nametable base tile index;\n"
         "                                  i.e. the first tile will be referenced\n"
         "                                  as NUM in the nametable, the second as\n"
         "                                  NUM+1, etc.; by default NUM is 0\n"
         "  --null-tile=NUM                 Use NUM as implicit null tile index; that is,\n"
         "                                  don't produce any character data for a 'blank' tile\n"
         "  --character-output=FILE         Store packed CHR in FILE\n"
         "  --character-size=SIZE           Pad to SIZE bytes if necessary\n"
         "  --nametable-output=FILE         Store nametable in FILE\n"
         "  --verbose                       Print progress information to standard output\n"
         "  --help                          Give this help list\n"
         "  --usage                         Give a short usage message\n"
         "  --version                       Print program version\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string

tool: D1: Usage: packchr [OPTION...] FILE
packchr finds the unique tiles in a NES character (CHR) file.

Options:

  --nametable-base=NUM            Use NUM as nametable base tile index;
                                  i.e. the first tile will be referenced
                                  as NUM in the nametable, the second as
                                  NUM+1, etc.; by default NUM is 0
  --null-tile=NUM                 Use NUM as implicit null tile index; that is,
                                  don't produce any character data for a 'blank' tile
  --character-output=FILE         Store packed CHR in FILE
  --character-size=SIZE           Pad to SIZE bytes if necessary
  --nametable-output=FILE         Store nametable in FILE
  --verbose                       Print progress information to standard output
  --help                          Give this help list
  --usage                         Give a short usage message
  --version                       Print program version


assistant: ```c
void help() {
  printf("Usage: packchr [OPTION...] FILE\n"
         "packchr finds the unique tiles in a NES character (CHR) file.\n\n"
         "Options:\n\n"
         "  --nametable-base=NUM            Use NUM as nametable base tile index;\n"
         "                                  i.e. the first tile will be referenced\n"
         "                                  as NUM in the nametable, the second as\n"
         "                                  NUM+1, etc.; by default NUM is 0\n"
         "  --null-tile=NUM                 Use NUM as implicit null tile index; that is,\n"
         "                                  don't produce any character data for a 'blank' tile\n"
         "  --character-output=FILE         Store packed CHR in FILE\n"
         "  --character-size=SIZE           Pad to SIZE bytes if necessary\n"
         "  --nametable-output=FILE         Store nametable in FILE\n"
         "  --verbose                       Print progress information to standard output\n"
         "  --help                          Give this help list\n"
         "  --usage                         Give a short usage message\n"
         "  --version                       Print program version\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: Usage: packchr [OPTION...] FILE
packchr finds the unique tiles in a NES character (CHR) file.

Options:

  --nametable-base=NUM            Use NUM as nametable base tile index;
                                  i.e. the first tile will be referenced
                                  as NUM in the nametable, the second as
                                  NUM+1, etc.; by default NUM is 0
  --null-tile=NUM                 Use NUM as implicit null tile index; that is,
                                  don't produce any character data for a 'blank' tile
  --character-output=FILE         Store packed CHR in FILE
  --character-size=SIZE           Pad to SIZE bytes if necessary
  --nametable-output=FILE         Store nametable in FILE
  --verbose                       Print progress information to standard output
  --help                          Give this help list
  --usage                         Give a short usage message
  --version                       Print program version


assistant: ```c
void help() {
  printf("Usage: packchr [OPTION...] FILE\n"
         "packchr finds the unique tiles in a NES character (CHR) file.\n\n"
         "Options:\n\n"
         "  --nametable-base=NUM            Use NUM as nametable base tile index;\n"
         "                                  i.e. the first tile will be referenced\n"
         "                                  as NUM in the nametable, the second as\n"
         "                                  NUM+1, etc.; by default NUM is 0\n"
         "  --null-tile=NUM                 Use NUM as implicit null tile index; that is,\n"
         "                                  don't produce any character data for a 'blank' tile\n"
         "  --character-output=FILE         Store packed CHR in FILE\n"
         "  --character-size=SIZE           Pad to SIZE bytes if necessary\n"
         "  --nametable-output=FILE         Store nametable in FILE\n"
         "  --verbose                       Print progress information to standard output\n"
         "  --help                          Give this help list\n"
         "  --usage                         Give a short usage message\n"
         "  --version                       Print program version\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: Usage: packchr [OPTION...] FILE
packchr finds the unique tiles in a NES character (CHR) file.

Options:

  --nametable-base=NUM            Use NUM as nametable base tile index;
                                  i.e. the first tile will be referenced
                                  as NUM in the nametable, the second as
                                  NUM+1, etc.; by default NUM is 0
  --null-tile=NUM                 Use NUM as implicit null tile index; that is,
                                  don't produce any character data for a 'blank' tile
  --character-output=FILE         Store packed CHR in FILE
  --character-size=SIZE           Pad to SIZE bytes if necessary
  --nametable-output=FILE         Store nametable in FILE
  --verbose                       Print progress information to standard output
  --help                          Give this help list
  --usage                         Give a short usage message
  --version                       Print program version


assistant: ```c
void help() {
  printf("Usage: packchr [OPTION...] FILE\n"
         "packchr finds the unique tiles in a NES character (CHR) file.\n\n"
         "Options:\n\n"
         "  --nametable-base=NUM            Use NUM as nametable base tile index;\n"
         "                                  i.e. the first tile will be referenced\n"
         "                                  as NUM in the nametable, the second as\n"
         "                                  NUM+1, etc.; by default NUM is 0\n"
         "  --null-tile=NUM                 Use NUM as implicit null tile index; that is,\n"
         "                                  don't produce any character data for a 'blank' tile\n"
         "  --character-output=FILE         Store packed CHR in FILE\n"
         "  --character-size=SIZE           Pad to SIZE bytes if necessary\n"
         "  --nametable-output=FILE         Store nametable in FILE\n"
         "  --verbose                       Print progress information to standard output\n"
         "  --help                          Give this help list\n"
         "  --usage                         Give a short usage message\n"
         "  --version                       Print program version\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L27
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L27:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D51
type_infered: string
name: read_data
arguments: tag: D50
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string

tool: D8: Numero inteiro 1? 

tool: D11: %d

tool: D51: Numero inteiro 2? 

tool: D50: %d nao e multiplo de %d


tool: D30: %d e multiplo de %d


assistant: ```c
int main() {
  int int1, int2;
  printf("Numero inteiro 1? ");
  scanf("%d", &int1);
  printf("Numero inteiro 2? ");
  scanf("%d", &int2);
  if (int1 % int2) {
    printf("%d nao e multiplo de %d\n", int1, int2);
  } else {
    printf("%d e multiplo de %d\n", int1, int2);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L22
  mov    %ecx,%edx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  mov    %ecx,%edx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
type: string
name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D2
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D24: Numero inteiro 1? 

tool: D14: %d

tool: D6: Numero inteiro 2? 

tool: D2: %d nao e multiplo de %d


tool: D13: %d e multiplo de %d


assistant: ```c
int main() {
  int int1, int2;
  printf("Numero inteiro 1? ");
  scanf("%d", &int1);
  printf("Numero inteiro 2? ");
  scanf("%d", &int2);
  if (int1 % int2) {
    printf("%d nao e multiplo de %d\n", int1, int2);
  } else {
    printf("%d e multiplo de %d\n", int1, int2);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rdi
  lea    D42(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  je     L23
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D42
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string

tool: D30: Numero inteiro 1? 

tool: D42: %d

tool: D18: Numero inteiro 2? 

tool: D8: %d nao e multiplo de %d


tool: D15: %d e multiplo de %d


assistant: ```c
int main() {
  int int1, int2;
  printf("Numero inteiro 1? ");
  scanf("%d", &int1);
  printf("Numero inteiro 2? ");
  scanf("%d", &int2);
  if (int1 % int2) {
    printf("%d nao e multiplo de %d\n", int1, int2);
  } else {
    printf("%d e multiplo de %d\n", int1, int2);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D22(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r8d
  mov    %esi,%eax
  cltd
  idiv   %r8d
  test   %edx,%edx
  mov    %r8d,%edx
  je     L2
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D38
type: string
name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D41
type: string
name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D23
type: string

tool: D38: Numero inteiro 1? 

tool: D22: %d

tool: D41: Numero inteiro 2? 

tool: D6: %d nao e multiplo de %d


tool: D23: %d e multiplo de %d


assistant: ```c
int main() {
  int int1, int2;
  printf("Numero inteiro 1? ");
  scanf("%d", &int1);
  printf("Numero inteiro 2? ");
  scanf("%d", &int2);
  if (int1 % int2) {
    printf("%d nao e multiplo de %d\n", int1, int2);
  } else {
    printf("%d e multiplo de %d\n", int1, int2);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string
name: parse_data
arguments: data_label: D24
type_guessed: string

tool: D2: %d

tool: D24: 
%d

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("\n%d", n * n);
  printf("\n%d", n * n * n);
  return 0;
}
```