ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<remove_parents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc_nofail@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L25
L13:
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  cmp    $0xffffffff,%eax
  je     L46
  mov    -0x8(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rmdir@plt>
  jmp    L34
L25:
  nop
  jmp    L34
L46:
  nop
L34:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void remove_parents(const char *filename) {
  char *fn = malloc_nofail(strlen(filename) + 1), *f;
  strcpy(fn, filename);
  f = strrchr(fn, '/');
  if (f == NULL)
    goto out;
  do {
    *f = '\0';
    if (rmdir(fn) == -1)
      goto out;
  } while ((f = strrchr(fn, '/')) != NULL);
  rmdir(fn);
out:
  free(fn);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<remove_parents>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_nofail@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L24
L20:
  movb   $0x0,(%rax)
  mov    %rbx,%rdi
  call   <rmdir@plt>
  cmp    $0xffffffff,%eax
  je     L24
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L20
  mov    %rbx,%rdi
  call   <rmdir@plt>
L24:
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void remove_parents(const char *filename) {
  char *fn = malloc_nofail(strlen(filename) + 1), *f;
  strcpy(fn, filename);
  f = strrchr(fn, '/');
  if (f == NULL)
    goto out;
  do {
    *f = '\0';
    if (rmdir(fn) == -1)
      goto out;
  } while ((f = strrchr(fn, '/')) != NULL);
  rmdir(fn);
out:
  free(fn);
}
```
user: What is the c source code of the assembly code below:

```asm
<remove_parents>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_nofail@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L10
  jmp    L23
  xchg   %ax,%ax
L2:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L22
L10:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <rmdir@plt>
  cmp    $0xffffffff,%eax
  jne    L2
L23:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
  nopl   0x0(%rax)
L22:
  mov    %rbp,%rdi
  call   <rmdir@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
```

assistant: ```c
void remove_parents(const char *filename) {
  char *fn = malloc_nofail(strlen(filename) + 1), *f;
  strcpy(fn, filename);
  f = strrchr(fn, '/');
  if (f == NULL)
    goto out;
  do {
    *f = '\0';
    if (rmdir(fn) == -1)
      goto out;
  } while ((f = strrchr(fn, '/')) != NULL);
  rmdir(fn);
out:
  free(fn);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<remove_parents>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc_nofail@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  jne    L23
  jmp    L13
  xchg   %ax,%ax
L19:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L18
L23:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <rmdir@plt>
  cmp    $0xffffffff,%eax
  jne    L19
L13:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
  nopl   0x0(%rax)
L18:
  mov    %rbp,%rdi
  call   <rmdir@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
```

assistant: ```c
void remove_parents(const char *filename) {
  char *fn = malloc_nofail(strlen(filename) + 1), *f;
  strcpy(fn, filename);
  f = strrchr(fn, '/');
  if (f == NULL)
    goto out;
  do {
    *f = '\0';
    if (rmdir(fn) == -1)
      goto out;
  } while ((f = strrchr(fn, '/')) != NULL);
  rmdir(fn);
out:
  free(fn);
}
```
user: What is the c source code of the assembly code below?

```asm
<str2upper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L19
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L19:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void str2upper(char *s) {
  int i;
  for (i = strlen(s); i--;)
    s[i] = (char)toupper(s[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str2upper>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  je     L7
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  add    %rbp,%rbx
  movslq %eax,%rdx
  lea    -0x2(%rbp,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  sub    %rax,%rbp
L5:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L5
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str2upper(char *s) {
  int i;
  for (i = strlen(s); i--;)
    s[i] = (char)toupper(s[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str2upper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L11
  lea    -0x1(%rax),%edx
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L5
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str2upper(char *s) {
  int i;
  for (i = strlen(s); i--;)
    s[i] = (char)toupper(s[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str2upper>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L6
  lea    -0x1(%rax),%edx
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  add    %rbp,%rbx
  lea    -0x2(%rbp,%rax,1),%rbp
  sub    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%edi
  sub    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L11
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void str2upper(char *s) {
  int i;
  for (i = strlen(s); i--;)
    s[i] = (char)toupper(s[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L41
L28:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jg     L9
  cmpq   $0x0,-0x10(%rbp)
  jns    L64
  mov    D6(%rip),%rax
  mov    (%rax),%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L64
  movq   $0x0,-0x10(%rbp)
  jmp    L9
L64:
  mov    $0xffffffffffffffff,%rax
  jmp    L61
L9:
  mov    -0x10(%rbp),%rax
  sub    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
L41:
  cmpq   $0x0,-0x18(%rbp)
  jne    L28
  mov    -0x38(%rbp),%rax
L61:
  leave
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  size_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<writen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L50
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r14d
  jmp    L43
L33:
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L50
L43:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jg     L33
  jns    L20
  mov    D8(%rip),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L13
  mov    %r14,%rax
  jmp    L33
L50:
  mov    %r13,%rax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    $0xffffffffffffffff,%rax
  jmp    L12
L13:
  mov    $0xffffffffffffffff,%rax
  jmp    L12
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  size_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L44
  nop
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jle    L24
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L5
L44:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L24:
  je     L18
  mov    D6(%rip),%rax
  mov    D5(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L5
L18:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  size_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L48
  nop
L26:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %rax,%rax
  jle    L19
  add    %rax,%rbp
  sub    %rax,%rbx
  jne    L26
L48:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L19:
  je     L5
  mov    D3(%rip),%rax
  mov    D14(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L26
L5:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, const void *vptr, size_t n) {
  size_t nleft;
  ssize_t nwritten;
  const char *ptr;
  ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwritten = write(fd, ptr, nleft)) <= 0) {
      if (nwritten < 0 && errno == EINTR)
        nwritten = 0;
      else
        return (-1);
    }
    nleft -= nwritten;
    ptr += nwritten;
  }
  return (n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gint2_nai_S_pF>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gint2_nai_S_cF@plt>
  movsd  0x18(%rbx),%xmm8
  movsd  (%rbx),%xmm3
  movsd  D13(%rip),%xmm0
  movapd %xmm0,%xmm4
  mulsd  0x28(%rbx),%xmm4
  movsd  D45(%rip),%xmm10
  movapd %xmm8,%xmm1
  mulsd  %xmm10,%xmm1
  subsd  %xmm1,%xmm4
  movsd  D53(%rip),%xmm9
  movapd %xmm3,%xmm1
  mulsd  %xmm9,%xmm1
  subsd  %xmm1,%xmm4
  movsd  0x10(%rbx),%xmm2
  movsd  0x38(%rbx),%xmm7
  movsd  D3(%rip),%xmm5
  movapd %xmm2,%xmm6
  mulsd  %xmm5,%xmm6
  movsd  0x48(%rbx),%xmm1
  subsd  %xmm6,%xmm1
  mulsd  %xmm7,%xmm5
  movapd %xmm5,%xmm6
  movapd %xmm1,%xmm5
  subsd  %xmm6,%xmm5
  movsd  0x8(%rbx),%xmm1
  movsd  0x30(%rbx),%xmm6
  mulsd  0x40(%rbx),%xmm0
  mulsd  %xmm1,%xmm10
  subsd  %xmm10,%xmm0
  mulsd  %xmm6,%xmm9
  subsd  %xmm9,%xmm0
  movsd  %xmm0,0x10(%rbx)
  movsd  D25(%rip),%xmm0
  mulsd  %xmm0,%xmm3
  movsd  D21(%rip),%xmm9
  mulsd  %xmm9,%xmm8
  subsd  %xmm8,%xmm3
  movsd  %xmm3,0x28(%rbx)
  movsd  D36(%rip),%xmm3
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm7
  subsd  %xmm7,%xmm2
  movsd  %xmm2,0x18(%rbx)
  movsd  %xmm5,(%rbx)
  mulsd  %xmm9,%xmm1
  mulsd  %xmm0,%xmm6
  subsd  %xmm6,%xmm1
  movsd  %xmm1,0x30(%rbx)
  movsd  %xmm4,0x8(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_guessed: f64
name: parse_data
arguments: label: D45
type_guessed: f64
name: parse_data
arguments: label: D53
type_guessed: f64
name: parse_data
arguments: label: D3
type_guessed: f64
name: parse_data
arguments: label: D25
type_guessed: f64
name: parse_data
arguments: label: D21
type_guessed: f64
name: parse_data
arguments: label: D36
type_guessed: f64

tool: D13: 1.09544511501033

tool: D45: 0.273861278752583

tool: D53: 0.612372435695794

tool: D3: 0.670820393249937

tool: D25: 0.790569415042095

tool: D21: 1.06066017177982

tool: D36: 0.866025403784439

assistant: ```c
void gint2_nai_S_pF(double *a, double a_a, double *b, double b_a, double *c, double *out) {
  double tmp0, tmp1, tmp2;
  gint2_nai_S_cF(a, a_a, b, b_a, c, out);
  tmp0 = 1.09544511501033 * out[5] - 0.273861278752583 * out[3] - 0.612372435695794 * out[0];
  tmp1 = out[9] - 0.670820393249937 * out[2] - 0.670820393249937 * out[7];
  tmp2 = 0.866025403784439 * out[2] - 0.866025403784439 * out[7];
  out[2] = 1.09544511501033 * out[8] - 0.273861278752583 * out[1] - 0.612372435695794 * out[6];
  out[5] = 0.790569415042095 * out[0] - 1.06066017177982 * out[3];
  out[3] = tmp2;
  out[0] = tmp1;
  out[6] = 1.06066017177982 * out[1] - 0.790569415042095 * out[6];
  out[1] = tmp0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gint2_nai_S_pF>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gint2_nai_S_cF@plt>
  movsd  0x18(%rbx),%xmm8
  movsd  0x28(%rbx),%xmm4
  movsd  D56(%rip),%xmm0
  movsd  (%rbx),%xmm3
  movapd %xmm8,%xmm1
  movsd  0x10(%rbx),%xmm2
  movsd  0x38(%rbx),%xmm7
  movsd  D10(%rip),%xmm10
  mulsd  %xmm0,%xmm4
  movsd  D17(%rip),%xmm9
  movsd  D0(%rip),%xmm5
  mulsd  0x40(%rbx),%xmm0
  movapd %xmm2,%xmm6
  mulsd  %xmm10,%xmm1
  mulsd  %xmm5,%xmm6
  mulsd  %xmm7,%xmm5
  subsd  %xmm1,%xmm4
  movapd %xmm3,%xmm1
  mulsd  %xmm9,%xmm1
  subsd  %xmm1,%xmm4
  movsd  0x48(%rbx),%xmm1
  subsd  %xmm6,%xmm1
  movapd %xmm5,%xmm6
  movapd %xmm1,%xmm5
  movsd  0x8(%rbx),%xmm1
  movsd  %xmm4,0x8(%rbx)
  subsd  %xmm6,%xmm5
  movsd  0x30(%rbx),%xmm6
  mulsd  %xmm1,%xmm10
  mulsd  %xmm6,%xmm9
  movsd  %xmm5,(%rbx)
  subsd  %xmm10,%xmm0
  subsd  %xmm9,%xmm0
  movsd  D61(%rip),%xmm9
  mulsd  %xmm9,%xmm8
  movsd  %xmm0,0x10(%rbx)
  movsd  D5(%rip),%xmm0
  mulsd  %xmm9,%xmm1
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm6
  subsd  %xmm8,%xmm3
  subsd  %xmm6,%xmm1
  movsd  %xmm3,0x28(%rbx)
  movsd  D52(%rip),%xmm3
  movsd  %xmm1,0x30(%rbx)
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm7
  subsd  %xmm7,%xmm2
  movsd  %xmm2,0x18(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D56
data_type: f64
name: retrieve_data
arguments: data_tag: D10
data_type: f64
name: retrieve_data
arguments: data_tag: D17
data_type: f64
name: retrieve_data
arguments: data_tag: D0
data_type: f64
name: retrieve_data
arguments: data_tag: D61
data_type: f64
name: retrieve_data
arguments: data_tag: D5
data_type: f64
name: retrieve_data
arguments: data_tag: D52
data_type: f64

tool: D56: 1.09544511501033

tool: D10: 0.273861278752583

tool: D17: 0.612372435695794

tool: D0: 0.670820393249937

tool: D61: 1.06066017177982

tool: D5: 0.790569415042095

tool: D52: 0.866025403784439

assistant: ```c
void gint2_nai_S_pF(double *a, double a_a, double *b, double b_a, double *c, double *out) {
  double tmp0, tmp1, tmp2;
  gint2_nai_S_cF(a, a_a, b, b_a, c, out);
  tmp0 = 1.09544511501033 * out[5] - 0.273861278752583 * out[3] - 0.612372435695794 * out[0];
  tmp1 = out[9] - 0.670820393249937 * out[2] - 0.670820393249937 * out[7];
  tmp2 = 0.866025403784439 * out[2] - 0.866025403784439 * out[7];
  out[2] = 1.09544511501033 * out[8] - 0.273861278752583 * out[1] - 0.612372435695794 * out[6];
  out[5] = 0.790569415042095 * out[0] - 1.06066017177982 * out[3];
  out[3] = tmp2;
  out[0] = tmp1;
  out[6] = 1.06066017177982 * out[1] - 0.790569415042095 * out[6];
  out[1] = tmp0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gint2_nai_S_pF>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  call   <gint2_nai_S_cF@plt>
  movsd  0x28(%rbx),%xmm5
  movsd  0x48(%rbx),%xmm3
  movsd  D74(%rip),%xmm0
  movupd 0x10(%rbx),%xmm2
  movupd 0x30(%rbx),%xmm4
  movupd (%rbx),%xmm1
  mulsd  %xmm0,%xmm5
  movsd  D13(%rip),%xmm6
  mulsd  0x40(%rbx),%xmm0
  movapd %xmm1,%xmm7
  unpckhpd %xmm7,%xmm7
  unpcklpd %xmm5,%xmm3
  movapd D34(%rip),%xmm5
  mulpd  %xmm2,%xmm5
  subpd  %xmm5,%xmm3
  movapd %xmm4,%xmm5
  shufpd $0x1,%xmm1,%xmm5
  mulpd  D1(%rip),%xmm5
  mulpd  D12(%rip),%xmm1
  subpd  %xmm5,%xmm3
  movsd  D17(%rip),%xmm5
  mulsd  %xmm7,%xmm5
  movapd %xmm4,%xmm7
  unpckhpd %xmm7,%xmm7
  movups %xmm3,(%rbx)
  subsd  %xmm5,%xmm0
  movsd  D70(%rip),%xmm5
  mulsd  %xmm4,%xmm5
  subsd  %xmm5,%xmm0
  movapd %xmm7,%xmm5
  mulsd  %xmm6,%xmm5
  movsd  %xmm0,0x10(%rbx)
  movapd %xmm2,%xmm0
  shufpd $0x1,%xmm4,%xmm2
  mulsd  %xmm6,%xmm0
  mulpd  D14(%rip),%xmm2
  subsd  %xmm5,%xmm0
  subpd  %xmm2,%xmm1
  movsd  %xmm0,0x18(%rbx)
  movups %xmm1,0x28(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D74
type_infered: f64
name: parse_data
arguments: tag: D13
type_infered: f64
name: parse_data
arguments: tag: D34
type_infered: f64[2]
name: parse_data
arguments: tag: D1
type_infered: f64[2]
name: parse_data
arguments: tag: D12
type_infered: f64[2]
name: parse_data
arguments: tag: D17
type_infered: f64
name: parse_data
arguments: tag: D70
type_infered: f64
name: parse_data
arguments: tag: D14
type_infered: f64[2]

tool: D74: 1.09544511501033

tool: D13: 0.866025403784439

tool: {"D34": [0.670820393249937,0.273861278752583]}

tool: {"D1": [0.670820393249937,0.612372435695794]}

tool: {"D12": [0.790569415042095,1.06066017177982]}

tool: D17: 0.273861278752583

tool: D70: 0.612372435695794

tool: {"D14": [1.06066017177982,0.790569415042095]}

assistant: ```c
void gint2_nai_S_pF(double *a, double a_a, double *b, double b_a, double *c, double *out) {
  double tmp0, tmp1, tmp2;
  gint2_nai_S_cF(a, a_a, b, b_a, c, out);
  tmp0 = 1.09544511501033 * out[5] - 0.273861278752583 * out[3] - 0.612372435695794 * out[0];
  tmp1 = out[9] - 0.670820393249937 * out[2] - 0.670820393249937 * out[7];
  tmp2 = 0.866025403784439 * out[2] - 0.866025403784439 * out[7];
  out[2] = 1.09544511501033 * out[8] - 0.273861278752583 * out[1] - 0.612372435695794 * out[6];
  out[5] = 0.790569415042095 * out[0] - 1.06066017177982 * out[3];
  out[3] = tmp2;
  out[0] = tmp1;
  out[6] = 1.06066017177982 * out[1] - 0.790569415042095 * out[6];
  out[1] = tmp0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f1234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void f1234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890(void) {
  int *x = malloc(sizeof(int));
  x[1] = 1;
}
```