ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D18(%rip),%rdi
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L34
L18:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L35:
  sub    %ebx,%eax
  mov    %rbp,%rdi
  sub    $0x1,%eax
  cmp    %r14d,%eax
  jle    L20
  mov    %r12,%rdi
L20:
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%r14d
  cmp    %r14d,%eax
  jg     L35
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L18
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D8
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D16
type_infered: string

tool: D18: %d

tool: D8: 


tool: D21:  

tool: D16: #

assistant: ```c
int main() {
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (j >= n - i - 1)
        printf("#");
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UARTParityModeSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0xc,%edx
  mov    %edx,%edx
  and    $0xffffffc7,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  and    $0x38,%eax
  mov    %eax,%esi
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %ecx,%eax
  or     %esi,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned int baseAdd, unsigned int parityMode) {
  (*((volatile unsigned int *)(baseAdd + (0xC)))) &= ~((0x00000008u) | (0x00000010u) | (0x00000020u));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) |= (parityMode & ((0x00000008u) | (0x00000010u) | (0x00000020u)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%edi),%eax
  and    $0xffffffc7,%eax
  mov    %eax,0xc(%edi)
  mov    0xc(%edi),%eax
  and    $0x38,%esi
  or     %eax,%esi
  mov    %esi,0xc(%edi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned int baseAdd, unsigned int parityMode) {
  (*((volatile unsigned int *)(baseAdd + (0xC)))) &= ~((0x00000008u) | (0x00000010u) | (0x00000020u));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) |= (parityMode & ((0x00000008u) | (0x00000010u) | (0x00000020u)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%edi),%eax
  and    $0x38,%esi
  and    $0xffffffc7,%eax
  mov    %eax,0xc(%edi)
  mov    0xc(%edi),%eax
  or     %eax,%esi
  mov    %esi,0xc(%edi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned int baseAdd, unsigned int parityMode) {
  (*((volatile unsigned int *)(baseAdd + (0xC)))) &= ~((0x00000008u) | (0x00000010u) | (0x00000020u));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) |= (parityMode & ((0x00000008u) | (0x00000010u) | (0x00000020u)));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UARTParityModeSet>:
  endbr64
  mov    0xc(%edi),%eax
  and    $0x38,%esi
  and    $0xffffffc7,%eax
  mov    %eax,0xc(%edi)
  mov    0xc(%edi),%eax
  or     %eax,%esi
  mov    %esi,0xc(%edi)
  ret
```

assistant: ```c
void UARTParityModeSet(unsigned int baseAdd, unsigned int parityMode) {
  (*((volatile unsigned int *)(baseAdd + (0xC)))) &= ~((0x00000008u) | (0x00000010u) | (0x00000020u));
  (*((volatile unsigned int *)(baseAdd + (0xC)))) |= (parityMode & ((0x00000008u) | (0x00000010u) | (0x00000020u)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3e7,-0x14(%rbp)
  movl   $0x64,-0x10(%rbp)
  movl   $0xc8,-0xc(%rbp)
  movl   $0x1,-0x18(%rbp)
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  movl   $0x4d,-0x14(%rbp,%rax,4)
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <print_int@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <print_string@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D49
type_infered: string

tool: D32: should get 100
got: 

tool: D31: 



tool: D49: should get 77
got: 

assistant: ```c
void main(void) {
  int myInt;
  int intArr[3];
  intArr[0] = 999;
  intArr[1] = 100;
  intArr[2] = 200;
  myInt = 1;
  print_string("should get 100\ngot: ");
  print_int(intArr[myInt]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1()]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1() + 4 / 8]);
  print_string("\n\n");
  intArr[return1()] = 77;
  print_string("should get 77\ngot: ");
  print_int(intArr[1]);
  print_string("\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3e7,0xc(%rsp)
  movl   $0x64,0x10(%rsp)
  movl   $0xc8,0x14(%rsp)
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    $0x64,%edi
  call   <print_int@plt>
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <print_string@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  mov    0xc(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbx,%rdi
  call   <print_string@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  mov    0xc(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbx,%rdi
  call   <print_string@plt>
  mov    $0x0,%eax
  call   <return1@plt>
  movl   $0x4d,0xc(%rsp,%rax,4)
  lea    D16(%rip),%rdi
  call   <print_string@plt>
  mov    0x10(%rsp),%edi
  call   <print_int@plt>
  mov    %rbx,%rdi
  call   <print_string@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D16
type_guessed: string

tool: D29: should get 100
got: 

tool: D3: 



tool: D16: should get 77
got: 

assistant: ```c
void main(void) {
  int myInt;
  int intArr[3];
  intArr[0] = 999;
  intArr[1] = 100;
  intArr[2] = 200;
  myInt = 1;
  print_string("should get 100\ngot: ");
  print_int(intArr[myInt]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1()]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1() + 4 / 8]);
  print_string("\n\n");
  intArr[return1()] = 77;
  print_string("should get 77\ngot: ");
  print_int(intArr[1]);
  print_string("\n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D3(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x64000003e7,%rax
  movl   $0xc8,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <print_string@plt>
  mov    $0x64,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    %r12,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  mov    0xc(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    %r12,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  mov    0xc(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  lea    D4(%rip),%rdi
  movl   $0x4d,0xc(%rsp,%rax,4)
  call   <print_string@plt>
  mov    0x10(%rsp),%edi
  call   <print_int@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <print_string@plt>
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D7: should get 100
got: 

tool: D3: 



tool: D4: should get 77
got: 

assistant: ```c
void main(void) {
  int myInt;
  int intArr[3];
  intArr[0] = 999;
  intArr[1] = 100;
  intArr[2] = 200;
  myInt = 1;
  print_string("should get 100\ngot: ");
  print_int(intArr[myInt]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1()]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1() + 4 / 8]);
  print_string("\n\n");
  intArr[return1()] = 77;
  print_string("should get 77\ngot: ");
  print_int(intArr[1]);
  print_string("\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D26(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D35(%rip),%rax
  movl   $0xc8,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <print_string@plt>
  mov    $0x64,%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    %r12,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  mov    0x8(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    %r12,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  mov    0x8(%rsp,%rax,4),%edi
  call   <print_int@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  xor    %eax,%eax
  call   <return1@plt>
  lea    D31(%rip),%rdi
  movl   $0x4d,0x8(%rsp,%rax,4)
  call   <print_string@plt>
  mov    0xc(%rsp),%edi
  call   <print_int@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <print_string@plt>
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string
name: unpack_data
arguments: tag: D35
type_infered: byte[8]
name: unpack_data
arguments: tag: D31
type_infered: string

tool: D38: should get 100
got: 

tool: D26: 



tool: {"D35": [0xe7,0x03,0x00,0x00,0x64,0x00,0x00,0x00]}

tool: D31: should get 77
got: 

assistant: ```c
void main(void) {
  int myInt;
  int intArr[3];
  intArr[0] = 999;
  intArr[1] = 100;
  intArr[2] = 200;
  myInt = 1;
  print_string("should get 100\ngot: ");
  print_int(intArr[myInt]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1()]);
  print_string("\n\n");
  print_string("should get 100\ngot: ");
  print_int(intArr[return1() + 4 / 8]);
  print_string("\n\n");
  intArr[return1()] = 77;
  print_string("should get 77\ngot: ");
  print_int(intArr[1]);
  print_string("\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<input_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L53
L28:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    D13(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  je     L38
  cmpb   $0xd,-0x1(%rbp)
  je     L38
  cmpb   $0xa,-0x1(%rbp)
  je     L38
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <input_putchar@plt>
L53:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L28
L38:
  mov    $0x0,%edi
  call   <input_putchar@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <feof@plt>
  test   %eax,%eax
  jne    L68
  mov    $0x1,%eax
  jmp    L49
L68:
  mov    $0x0,%eax
L49:
  leave
  ret
```

assistant: ```c
int input_read() {
  while (!feof(stdin)) {
    char c = getchar();
    if ((c == EOF) || (c == '\r') || (c == '\n'))
      break;
    input_putchar(c);
  }
  input_putchar('\0');
  if (!feof(stdin))
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<input_read>:
  endbr64
  push   %rbx
  mov    D27(%rip),%rbx
  jmp    L48
L29:
  movsbl %al,%edi
  call   <input_putchar@plt>
L48:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  jne    L18
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    %al,(%rdx)
  je     L18
  cmp    $0xd,%al
  je     L18
  cmp    $0xa,%al
  jne    L29
L18:
  mov    $0x0,%edi
  call   <input_putchar@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%edi
  call   <feof@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int input_read() {
  while (!feof(stdin)) {
    char c = getchar();
    if ((c == EOF) || (c == '\r') || (c == '\n'))
      break;
    input_putchar(c);
  }
  input_putchar('\0');
  if (!feof(stdin))
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<input_read>:
  endbr64
  push   %rbx
  mov    D12(%rip),%rbx
  jmp    L23
  xchg   %ax,%ax
L33:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D9(%rip),%rdx
  cmp    %al,(%rdx)
  je     L7
  cmp    $0xd,%al
  je     L7
  cmp    $0xa,%al
  je     L7
  movsbl %al,%edi
  call   <input_putchar@plt>
L23:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L33
L7:
  xor    %edi,%edi
  call   <input_putchar@plt>
  mov    (%rbx),%edi
  call   <feof@plt>
  pop    %rbx
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int input_read() {
  while (!feof(stdin)) {
    char c = getchar();
    if ((c == EOF) || (c == '\r') || (c == '\n'))
      break;
    input_putchar(c);
  }
  input_putchar('\0');
  if (!feof(stdin))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<input_read>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
  jmp    L27
  xchg   %ax,%ax
L49:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    D16(%rip),%rdx
  cmp    %al,(%rdx)
  je     L30
  cmp    $0xd,%al
  je     L30
  cmp    $0xa,%al
  je     L30
  movsbl %al,%edi
  call   <input_putchar@plt>
L27:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L49
L30:
  xor    %edi,%edi
  call   <input_putchar@plt>
  mov    (%rbx),%edi
  call   <feof@plt>
  pop    %rbx
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int input_read() {
  while (!feof(stdin)) {
    char c = getchar();
    if ((c == EOF) || (c == '\r') || (c == '\n'))
      break;
    input_putchar(c);
  }
  input_putchar('\0');
  if (!feof(stdin))
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rbx
L49:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   $0x1,%al
  je     L49
  sub    $0x1,%eax
  cmp    $0xc7,%eax
  ja     L49
  lea    0x10(%rsp),%rax
  lea    0x1a0(%rsp),%rdx
L65:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L65
  lea    0x1a0(%rsp),%r13
  mov    $0x0,%r12d
  lea    D17(%rip),%rbp
L149:
  mov    %r13,%rbx
L170:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L170
  movslq %eax,%rdx
  mov    0x10(%rsp,%rdx,4),%edx
  cmp    $0x1,%edx
  jg     L170
  cltq
  add    $0x1,%edx
  mov    %edx,0x10(%rsp,%rax,4)
  add    $0x1,%r12d
  mov    0xc(%rsp),%edi
  add    $0x4,%r13
  cmp    %r12d,%edi
  jg     L149
  mov    $0x0,%eax
  mov    $0x0,%esi
  lea    0x10(%rsp),%rcx
  jmp    L108
L41:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L160
L108:
  cmpl   $0x1,(%rcx,%rax,4)
  jne    L41
  test   %esi,%esi
  jne    L70
  mov    %eax,%esi
  jmp    L41
L160:
  test   %edi,%edi
  jle    L133
  mov    %edi,%edi
  mov    $0x0,%eax
  lea    0x1a0(%rsp),%rdx
L173:
  cmp    %esi,(%rdx,%rax,4)
  je     L78
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L173
  mov    $0xffffffff,%eax
  jmp    L24
L78:
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L24
L70:
  mov    $0xffffffff,%eax
L24:
  mov    0x4c8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L117
  add    $0x4d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L133:
  mov    $0xffffffff,%eax
  jmp    L24
L117:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
type_infered: string

tool: D17: %d

assistant: ```c
int main() {
  int n, eleni[200], obor[100], i, Rud = 0;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n <= 0 || n > 200);
  for (i = 0; i < 100; i++)
    obor[i] = 0;
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &eleni[i]);
    } while (eleni[i] < 1 || eleni[i] > 100 || obor[eleni[i]] > 1);
    obor[eleni[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (obor[i] == 1)
      if (Rud == 0)
        Rud = i;
      else
        return -1;
  for (i = 0; i < n; i++)
    if (eleni[i] == Rud) {
      printf("%d", i);
      return 0;
    }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L153:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xc7,%edx
  ja     L153
  test   $0x1,%al
  je     L153
  lea    0x10(%rsp),%rbp
  mov    $0x32,%ecx
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    %rbp,%rdi
  lea    0x1a0(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rbx
  cs nopw 0x0(%rax,%rax,1)
L126:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq (%rbx),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L126
  mov    0x10(%rsp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L126
  movslq 0xc(%rsp),%rcx
  add    $0x1,%edx
  add    $0x1,%r12d
  add    $0x4,%rbx
  mov    %edx,0x10(%rsp,%rax,4)
  cmp    %r12d,%ecx
  jg     L126
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L71
  xchg   %ax,%ax
L55:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L102
L71:
  cmpl   $0x1,0x0(%rbp,%rax,4)
  jne    L55
  test   %edx,%edx
  jne    L75
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L71
L102:
  test   %ecx,%ecx
  jle    L75
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax)
L122:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L75
L14:
  mov    %eax,%esi
  cmp    %edx,0x0(%r13,%rax,4)
  jne    L122
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L46
L75:
  mov    $0xffffffff,%eax
L46:
  mov    0x4c8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L45
  add    $0x4d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string

tool: D5: %d

assistant: ```c
int main() {
  int n, eleni[200], obor[100], i, Rud = 0;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n <= 0 || n > 200);
  for (i = 0; i < 100; i++)
    obor[i] = 0;
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &eleni[i]);
    } while (eleni[i] < 1 || eleni[i] > 100 || obor[eleni[i]] > 1);
    obor[eleni[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (obor[i] == 1)
      if (Rud == 0)
        Rud = i;
      else
        return -1;
  for (i = 0; i < n; i++)
    if (eleni[i] == Rud) {
      printf("%d", i);
      return 0;
    }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x4d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4c8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L159:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0xc7,%edx
  ja     L159
  test   $0x1,%al
  je     L159
  lea    0x10(%rsp),%rbp
  mov    $0x32,%ecx
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    %rbp,%rdi
  lea    0x1a0(%rsp),%r13
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rbx
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq (%rbx),%rax
  lea    -0x1(%rax),%edx
  cmp    $0x63,%edx
  ja     L21
  mov    0x10(%rsp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L21
  movslq 0xc(%rsp),%rcx
  add    $0x1,%edx
  add    $0x1,%r12d
  add    $0x4,%rbx
  mov    %edx,0x10(%rsp,%rax,4)
  cmp    %r12d,%ecx
  jg     L21
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L93
  xchg   %ax,%ax
L145:
  add    $0x1,%rax
  cmp    $0x64,%rax
  je     L58
L93:
  cmpl   $0x1,0x0(%rbp,%rax,4)
  jne    L145
  test   %edx,%edx
  jne    L8
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L93
L58:
  test   %ecx,%ecx
  jle    L8
  xor    %eax,%eax
  jmp    L158
  nopl   0x0(%rax)
L68:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L8
L158:
  mov    %eax,%esi
  cmp    %edx,0x0(%r13,%rax,4)
  jne    L68
  mov    %r14,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L154
L8:
  mov    $0xffffffff,%eax
L154:
  mov    0x4c8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x4d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: %d

assistant: ```c
int main() {
  int n, eleni[200], obor[100], i, Rud = 0;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n <= 0 || n > 200);
  for (i = 0; i < 100; i++)
    obor[i] = 0;
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &eleni[i]);
    } while (eleni[i] < 1 || eleni[i] > 100 || obor[eleni[i]] > 1);
    obor[eleni[i]]++;
  }
  for (i = 0; i < 100; i++)
    if (obor[i] == 1)
      if (Rud == 0)
        Rud = i;
      else
        return -1;
  for (i = 0; i < n; i++)
    if (eleni[i] == Rud) {
      printf("%d", i);
      return 0;
    }
  return -1;
}
```