ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_is_file_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L15
  mov    $0x0,%eax
  jmp    L11
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int _is_file_char(char *pathname) {
  struct stat st;
  if (stat(pathname, &st) != 0)
    return 0;
  return S_ISCHR(st.st_mode) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_is_file_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L15
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L15:
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L29
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _is_file_char(char *pathname) {
  struct stat st;
  if (stat(pathname, &st) != 0)
    return 0;
  return S_ISCHR(st.st_mode) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_is_file_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _is_file_char(char *pathname) {
  struct stat st;
  if (stat(pathname, &st) != 0)
    return 0;
  return S_ISCHR(st.st_mode) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_is_file_char>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L19
  mov    0x4(%rsp),%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _is_file_char(char *pathname) {
  struct stat st;
  if (stat(pathname, &st) != 0)
    return 0;
  return S_ISCHR(st.st_mode) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<adb_ls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %rdi,-0x828(%rbp)
  mov    %rsi,-0x830(%rbp)
  mov    %rdx,-0x838(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x810(%rbp)
  movq   $0x0,-0x808(%rbp)
  lea    -0x800(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xfe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x814(%rbp)
  mov    -0x828(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  lea    D6(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x838(%rbp),%rdx
  mov    -0x830(%rbp),%rcx
  lea    -0x810(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <os_shellexec@plt>
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: adb shell "su -c 'ls %s'"

assistant: ```c
int adb_ls(const char *path, char *result, size_t result_maxlen) {
  char buf[2048] = {0};
  int files = 0;
  sprintf(buf, "adb shell \"su -c 'ls %s'\"", path);
  os_shellexec(buf, result, result_maxlen);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<adb_ls>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%r8
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0xfe,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%r12
  mov    %r8,%rdx
  lea    D1(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <os_shellexec@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x1,%eax
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: adb shell "su -c 'ls %s'"

assistant: ```c
int adb_ls(const char *path, char *result, size_t result_maxlen) {
  char buf[2048] = {0};
  int files = 0;
  sprintf(buf, "adb shell \"su -c 'ls %s'\"", path);
  os_shellexec(buf, result, result_maxlen);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adb_ls>:
  endbr64
  push   %r13
  mov    %rdi,%r8
  mov    $0xfe,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdx,%r12
  mov    %r8,%rdx
  push   %rbp
  mov    %rsi,%rbp
  lea    D5(%rip),%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <os_shellexec@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x810,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D5: adb shell "su -c 'ls %s'"

assistant: ```c
int adb_ls(const char *path, char *result, size_t result_maxlen) {
  char buf[2048] = {0};
  int files = 0;
  sprintf(buf, "adb shell \"su -c 'ls %s'\"", path);
  os_shellexec(buf, result, result_maxlen);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<adb_ls>:
  endbr64
  push   %r13
  mov    %rdi,%r8
  mov    $0xfe,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdx,%r12
  mov    %r8,%rdx
  push   %rbp
  mov    %rsi,%rbp
  lea    D8(%rip),%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <os_shellexec@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x810,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: adb shell "su -c 'ls %s'"

assistant: ```c
int adb_ls(const char *path, char *result, size_t result_maxlen) {
  char buf[2048] = {0};
  int files = 0;
  sprintf(buf, "adb shell \"su -c 'ls %s'\"", path);
  os_shellexec(buf, result, result_maxlen);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%r10
  mov    %rax,%rdi
  call   <isPowerOfTwo.0>
  test   %eax,%eax
  je     L18
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L18:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D19
type_guessed: string

tool: D13: %llu

tool: D15: TAK

tool: D19: NIE

assistant: ```c
int main() {
  long long x;
  scanf("%llu", &x);
  int isPowerOfTwo(long long x) { return ((x != 0) && !(x & (x - 1))); }
  if (isPowerOfTwo(x)) {
    printf("TAK\n");
  } else {
    printf("NIE\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L10
  lea    -0x1(%rax),%rdx
  test   %rax,%rdx
  je     L1
L10:
  lea    D1(%rip),%rdi
  call   <puts@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  jmp    L9
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
data_type: string
name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D21: %llu

tool: D1: NIE

tool: D3: TAK

assistant: ```c
int main() {
  long long x;
  scanf("%llu", &x);
  int isPowerOfTwo(long long x) { return ((x != 0) && !(x & (x - 1))); }
  if (isPowerOfTwo(x)) {
    printf("TAK\n");
  } else {
    printf("NIE\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L14
  lea    -0x1(%rax),%rdx
  test   %rax,%rdx
  je     L25
L14:
  lea    D18(%rip),%rdi
  call   <puts@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L25:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string

tool: D11: %llu

tool: D18: NIE

tool: D2: TAK

assistant: ```c
int main() {
  long long x;
  scanf("%llu", &x);
  int isPowerOfTwo(long long x) { return ((x != 0) && !(x & (x - 1))); }
  if (isPowerOfTwo(x)) {
    printf("TAK\n");
  } else {
    printf("NIE\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L26
  lea    -0x1(%rax),%rdx
  test   %rax,%rdx
  je     L19
L26:
  lea    D5(%rip),%rdi
  call   <puts@plt>
L38:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L38
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D5
type: string
name: read_data
arguments: tag: D7
type: string

tool: D15: %llu

tool: D5: NIE

tool: D7: TAK

assistant: ```c
int main() {
  long long x;
  scanf("%llu", &x);
  int isPowerOfTwo(long long x) { return ((x != 0) && !(x & (x - 1))); }
  if (isPowerOfTwo(x)) {
    printf("TAK\n");
  } else {
    printf("NIE\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sub_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x1f,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L76
  cmpl   $0x0,-0x10(%rbp)
  je     L76
  cmpl   $0x0,-0xc(%rbp)
  je     L76
  mov    $0x1,%eax
  jmp    L92
L76:
  mov    $0x0,%eax
L92:
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L49
  cmpl   $0x0,-0x10(%rbp)
  jne    L49
  cmpl   $0x0,-0xc(%rbp)
  jne    L49
  mov    $0x1,%eax
  jmp    L7
L49:
  mov    $0x0,%eax
L7:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L71
  cmpl   $0x0,-0x4(%rbp)
  jne    L71
  mov    $0x1,%eax
  jmp    L4
L71:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int sub_ok(int x, int y) {
  int diff = x - y;
  unsigned wm1 = (sizeof(int) << 3) - 1u;
  int xneg = (x >> wm1) & 1;
  int yneg = (y >> wm1) & 1;
  int dneg = (diff >> wm1) & 1;
  int pos_over = !xneg && yneg && dneg;
  int neg_over = xneg && !yneg && !dneg;
  return !pos_over && !neg_over;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sub_ok>:
  endbr64
  mov    %edi,%edx
  sub    %esi,%edx
  shr    $0x1f,%edi
  sete   %al
  shr    $0x1f,%edx
  setne  %cl
  and    %ecx,%eax
  shr    $0x1f,%esi
  setne  %cl
  and    %ecx,%eax
  or     %edx,%esi
  sete   %dl
  and    %edi,%edx
  or     %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int sub_ok(int x, int y) {
  int diff = x - y;
  unsigned wm1 = (sizeof(int) << 3) - 1u;
  int xneg = (x >> wm1) & 1;
  int yneg = (y >> wm1) & 1;
  int dneg = (diff >> wm1) & 1;
  int pos_over = !xneg && yneg && dneg;
  int neg_over = xneg && !yneg && !dneg;
  return !pos_over && !neg_over;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sub_ok>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  sub    %esi,%edx
  shr    $0x1f,%eax
  shr    $0x1f,%edx
  shr    $0x1f,%edi
  jne    L7
  xor    %r8d,%r8d
  test   %dl,%al
  jne    L17
L7:
  xor    $0x1,%eax
  xor    $0x1,%edx
  and    %edx,%eax
  and    %edi,%eax
  xor    $0x1,%eax
  movzbl %al,%r8d
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sub_ok(int x, int y) {
  int diff = x - y;
  unsigned wm1 = (sizeof(int) << 3) - 1u;
  int xneg = (x >> wm1) & 1;
  int yneg = (y >> wm1) & 1;
  int dneg = (diff >> wm1) & 1;
  int pos_over = !xneg && yneg && dneg;
  int neg_over = xneg && !yneg && !dneg;
  return !pos_over && !neg_over;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sub_ok>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  sub    %esi,%edx
  shr    $0x1f,%eax
  shr    $0x1f,%edx
  shr    $0x1f,%edi
  jne    L14
  xor    %r8d,%r8d
  test   %dl,%al
  jne    L2
L14:
  xor    $0x1,%eax
  xor    $0x1,%edx
  and    %edx,%eax
  and    %edi,%eax
  xor    $0x1,%eax
  movzbl %al,%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int sub_ok(int x, int y) {
  int diff = x - y;
  unsigned wm1 = (sizeof(int) << 3) - 1u;
  int xneg = (x >> wm1) & 1;
  int yneg = (y >> wm1) & 1;
  int dneg = (diff >> wm1) & 1;
  int pos_over = !xneg && yneg && dneg;
  int neg_over = xneg && !yneg && !dneg;
  return !pos_over && !neg_over;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xfffffff6,-0x14(%rbp)
  jge    L14
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L14
  mov    $0x0,%eax
  call   <link_error@plt>
L14:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int foo(int i) {
  int x;
  x = i;
  if (i < -10) {
    x = __builtin_abs(i);
    if (x < 0)
      link_error();
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  cmp    $0xfffffff6,%edi
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int foo(int i) {
  int x;
  x = i;
  if (i < -10) {
    x = __builtin_abs(i);
    if (x < 0)
      link_error();
  }
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  neg    %edx
  cmp    $0xfffffff6,%edi
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int foo(int i) {
  int x;
  x = i;
  if (i < -10) {
    x = __builtin_abs(i);
    if (x < 0)
      link_error();
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  neg    %edx
  cmp    $0xfffffff6,%edi
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int foo(int i) {
  int x;
  x = i;
  if (i < -10) {
    x = __builtin_abs(i);
    if (x < 0)
      link_error();
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L35
  movl   $0x1,-0x4(%rbp)
  jmp    L34
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  jmp    L32
L35:
  nop
L32:
  leave
  ret
```

assistant: ```c
void sort(int *arr, int size) {
  if (size < 2)
    return;
  int i;
  for (i = 1; i < size; i++) {
    insert(arr, arr[i], i);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x1,%ebx
L3:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <insert@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

assistant: ```c
void sort(int *arr, int size) {
  if (size < 2)
    return;
  int i;
  for (i = 1; i < size; i++) {
    insert(arr, arr[i], i);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <insert@plt>
  cmp    %r12,%rbx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void sort(int *arr, int size) {
  if (size < 2)
    return;
  int i;
  for (i = 1; i < size; i++) {
    insert(arr, arr[i], i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  push   %r12
  movslq %esi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <insert@plt>
  cmp    %rbx,%r12
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  ret
```

assistant: ```c
void sort(int *arr, int size) {
  if (size < 2)
    return;
  int i;
  for (i = 1; i < size; i++) {
    insert(arr, arr[i], i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<find_code_offset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L26
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L26:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
L11:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_code_offset(unsigned char *stream, int stream_length, unsigned char code) {
  int is_exist = (-1);
  int i;
  for (i = 0; i < stream_length; i++) {
    if (stream[i] == code) {
      is_exist = i;
      break;
    }
  }
  return (is_exist);
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_code_offset>:
  endbr64
  test   %esi,%esi
  jle    L5
  mov    %esi,%esi
  mov    $0x0,%eax
L7:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rax,1)
  je     L18
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L7
  mov    $0xffffffff,%ecx
L18:
  mov    %ecx,%eax
  ret
L5:
  mov    $0xffffffff,%ecx
  jmp    L18
```

assistant: ```c
int find_code_offset(unsigned char *stream, int stream_length, unsigned char code) {
  int is_exist = (-1);
  int i;
  for (i = 0; i < stream_length; i++) {
    if (stream[i] == code) {
      is_exist = i;
      break;
    }
  }
  return (is_exist);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find_code_offset>:
  endbr64
  test   %esi,%esi
  jle    L14
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L12
  nop
L0:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L14
L12:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L14:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_code_offset(unsigned char *stream, int stream_length, unsigned char code) {
  int is_exist = (-1);
  int i;
  for (i = 0; i < stream_length; i++) {
    if (stream[i] == code) {
      is_exist = i;
      break;
    }
  }
  return (is_exist);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_code_offset>:
  endbr64
  test   %esi,%esi
  jle    L33
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L15
  nop
L0:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L33
L15:
  mov    %eax,%r8d
  cmp    %dl,(%rdi,%rax,1)
  jne    L0
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L33:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_code_offset(unsigned char *stream, int stream_length, unsigned char code) {
  int is_exist = (-1);
  int i;
  for (i = 0; i < stream_length; i++) {
    if (stream[i] == code) {
      is_exist = i;
      break;
    }
  }
  return (is_exist);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L2
  mov    $0x0,%eax
  call   <abort@plt>
L2:
  nop
  leave
  ret
```

assistant: ```c
void test(int x, int y) {
  if (x == y)
    abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  cmp    %esi,%edi
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test(int x, int y) {
  if (x == y)
    abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  cmp    %esi,%edi
  je     L2
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void test(int x, int y) {
  if (x == y)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  cmp    %esi,%edi
  je     L3
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void test(int x, int y) {
  if (x == y)
    abort();
}
```