ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<trailz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  neg    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0xffffffffdd67c8a7,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x5,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7:  

assistant: ```c
int trailz(uint32_t v) {
  static const int bpm37[] = {32, 0, 1, 26, 2, 23, 27, 0, 3, 16, 24, 30, 28, 11, 0, 13, 4, 7, 17, 0, 25, 22, 31, 15, 29, 10, 12, 6, 0, 21, 14, 9, 5, 20, 8, 19, 18};
  return bpm37[(-v & v) % 37];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trailz>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  and    %edi,%edx
  movslq %edx,%rax
  imul   $0xffffffffdd67c8a7,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  lea    (%rax,%rcx,4),%eax
  sub    %eax,%edx
  movslq %edx,%rdx
  lea    D7(%rip),%rax
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7:  

assistant: ```c
int trailz(uint32_t v) {
  static const int bpm37[] = {32, 0, 1, 26, 2, 23, 27, 0, 3, 16, 24, 30, 28, 11, 0, 13, 4, 7, 17, 0, 25, 22, 31, 15, 29, 10, 12, 6, 0, 21, 14, 9, 5, 20, 8, 19, 18};
  return bpm37[(-v & v) % 37];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trailz>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  and    %edi,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffffdd67c8a7,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x5,%eax
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  lea    (%rax,%rcx,4),%eax
  sub    %eax,%edx
  lea    D3(%rip),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3:  

assistant: ```c
int trailz(uint32_t v) {
  static const int bpm37[] = {32, 0, 1, 26, 2, 23, 27, 0, 3, 16, 24, 30, 28, 11, 0, 13, 4, 7, 17, 0, 25, 22, 31, 15, 29, 10, 12, 6, 0, 21, 14, 9, 5, 20, 8, 19, 18};
  return bpm37[(-v & v) % 37];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trailz>:
  endbr64
  mov    %edi,%edx
  neg    %edx
  and    %edi,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0xffffffffdd67c8a7,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x5,%eax
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  lea    (%rax,%rcx,4),%eax
  sub    %eax,%edx
  lea    D0(%rip),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0:  

assistant: ```c
int trailz(uint32_t v) {
  static const int bpm37[] = {32, 0, 1, 26, 2, 23, 27, 0, 3, 16, 24, 30, 28, 11, 0, 13, 4, 7, 17, 0, 25, 22, 31, 15, 29, 10, 12, 6, 0, 21, 14, 9, 5, 20, 8, 19, 18};
  return bpm37[(-v & v) % 37];
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_puterr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  jmp    L18
L10:
  nop
L18:
  leave
  ret
```

assistant: ```c
void my_puterr(char *str) {
  if (str == NULL)
    return;
  write(2, str, my_strlen(str));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_puterr>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <write@plt>
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void my_puterr(char *str) {
  if (str == NULL)
    return;
  write(2, str, my_strlen(str));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_puterr>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbp
  mov    %rdi,%rbp
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <write@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void my_puterr(char *str) {
  if (str == NULL)
    return;
  write(2, str, my_strlen(str));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_puterr>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbp
  mov    %rdi,%rbp
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  pop    %rbp
  mov    %eax,%edx
  jmp    1070 <write@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void my_puterr(char *str) {
  if (str == NULL)
    return;
  write(2, str, my_strlen(str));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<qio_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %esi,-0xd8(%rbp)
  mov    %rdx,-0xe0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L41
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L41:
  movq   $0x400,-0xc0(%rbp)
L42:
  mov    -0xc0(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0xb8(%rbp)
  cmpq   $0x0,-0xb8(%rbp)
  je     L40
  mov    -0xe0(%rbp),%rdx
  mov    -0xcc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xcc(%rbp),%ecx
  mov    -0xe0(%rbp),%rdx
  mov    -0xc0(%rbp),%rsi
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xc8(%rbp)
  mov    -0xcc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  cmpl   $0x0,-0xc8(%rbp)
  js     L57
  mov    -0xc8(%rbp),%eax
  cltq
  cmp    %rax,-0xc0(%rbp)
  ja     L13
L57:
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  shlq   -0xc0(%rbp)
  jmp    L42
L40:
  nop
  jmp    L18
L13:
  nop
L18:
  cmpq   $0x0,-0xb8(%rbp)
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L71
L33:
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    -0xd8(%rbp),%edx
  mov    -0xb8(%rbp),%rsi
  mov    -0xd4(%rbp),%eax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  call   <qio_write@plt>
  mov    %eax,-0xc4(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc4(%rbp),%eax
L71:
  leave
  ret
```

assistant: ```c
ssize_t qio_printf(int fd, int timeoutms, const char *format, ...) {
  char *buf;
  do {
    size_t _strsize;
    for (_strsize = 1024;; _strsize *= 2) {
      buf = (char *)malloc(_strsize);
      if (buf == NULL) {
        (void)(0);
        break;
      }
      va_list _arglist;
      va_start(_arglist, format);
      int _n = vsnprintf(buf, _strsize, format, _arglist);
      va_end(_arglist);
      if (_n >= 0 && _n < _strsize)
        break;
      free(buf);
    }
  } while (0);
  if (buf == NULL)
    return -1;
  ssize_t ret = qio_write(fd, buf, strlen(buf), timeoutms);
  free(buf);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<qio_printf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%r15d
  mov    %rdx,%r14
  mov    $0x400,%r12d
  jmp    L33
L14:
  mov    %rbx,%rdi
  call   <free@plt>
  add    %r12,%r12
L33:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
  mov    %r14,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <va_end@plt>
  test   %ebp,%ebp
  js     L14
  movslq %ebp,%rbp
  cmp    %r12,%rbp
  jae    L14
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r15d,%ecx
  mov    %rbx,%rsi
  mov    0xc(%rsp),%edi
  call   <qio_write@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L25:
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    $0xffffffff,%ebp
  jmp    L25
```

assistant: ```c
ssize_t qio_printf(int fd, int timeoutms, const char *format, ...) {
  char *buf;
  do {
    size_t _strsize;
    for (_strsize = 1024;; _strsize *= 2) {
      buf = (char *)malloc(_strsize);
      if (buf == NULL) {
        (void)(0);
        break;
      }
      va_list _arglist;
      va_start(_arglist, format);
      int _n = vsnprintf(buf, _strsize, format, _arglist);
      va_end(_arglist);
      if (_n >= 0 && _n < _strsize)
        break;
      free(buf);
    }
  } while (0);
  if (buf == NULL)
    return -1;
  ssize_t ret = qio_write(fd, buf, strlen(buf), timeoutms);
  free(buf);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qio_printf>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    $0x400,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  jmp    L29
  nopl   0x0(%rax)
L35:
  xor    %r14d,%r14d
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  movslq %eax,%rbx
  call   <va_end@plt>
  mov    %rbp,%rdi
  test   %ebx,%ebx
  js     L4
  cmp    %r12,%rbx
  jb     L46
L4:
  call   <free@plt>
  add    %r12,%r12
L29:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L35
  mov    $0xffffffff,%r12d
L16:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L46:
  call   <strlen@plt>
  mov    0xc(%rsp),%edi
  mov    %r15d,%ecx
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <qio_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  jmp    L16
```

assistant: ```c
ssize_t qio_printf(int fd, int timeoutms, const char *format, ...) {
  char *buf;
  do {
    size_t _strsize;
    for (_strsize = 1024;; _strsize *= 2) {
      buf = (char *)malloc(_strsize);
      if (buf == NULL) {
        (void)(0);
        break;
      }
      va_list _arglist;
      va_start(_arglist, format);
      int _n = vsnprintf(buf, _strsize, format, _arglist);
      va_end(_arglist);
      if (_n >= 0 && _n < _strsize)
        break;
      free(buf);
    }
  } while (0);
  if (buf == NULL)
    return -1;
  ssize_t ret = qio_write(fd, buf, strlen(buf), timeoutms);
  free(buf);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qio_printf>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    $0x400,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  jmp    L28
  nopl   0x0(%rax)
L17:
  xor    %r14d,%r14d
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  movslq %eax,%rbx
  call   <va_end@plt>
  mov    %rbp,%rdi
  test   %ebx,%ebx
  js     L29
  cmp    %r12,%rbx
  jb     L31
L29:
  call   <free@plt>
  add    %r12,%r12
L28:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L17
  mov    $0xffffffff,%r12d
L48:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L31:
  call   <strlen@plt>
  mov    0xc(%rsp),%edi
  mov    %r15d,%ecx
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <qio_write@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  jmp    L48
```

assistant: ```c
ssize_t qio_printf(int fd, int timeoutms, const char *format, ...) {
  char *buf;
  do {
    size_t _strsize;
    for (_strsize = 1024;; _strsize *= 2) {
      buf = (char *)malloc(_strsize);
      if (buf == NULL) {
        (void)(0);
        break;
      }
      va_list _arglist;
      va_start(_arglist, format);
      int _n = vsnprintf(buf, _strsize, format, _arglist);
      va_end(_arglist);
      if (_n >= 0 && _n < _strsize)
        break;
      free(buf);
    }
  } while (0);
  if (buf == NULL)
    return -1;
  ssize_t ret = qio_write(fd, buf, strlen(buf), timeoutms);
  free(buf);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<my_execve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x3c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_execve@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <report_exec@plt>
  lea    -0x18(%rbp),%r8
  lea    -0x20(%rbp),%rdi
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rsi
  mov    -0x58(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <clone_env@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  jmp    L0
L29:
  mov    -0x10(%rbp),%rdx
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <orig_execve@plt>
  mov    %eax,-0x3c(%rbp)
L0:
  mov    -0x18(%rbp),%r8
  mov    -0x20(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <free_env@plt>
  mov    -0x3c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int my_execve(char const *prog, char *const *argv, char *const *env) {
  int retval = -1;
  char **new_env = NULL;
  size_t ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos;
  init_execve();
  report_exec(prog);
  new_env = clone_env(env, &ldp_pos, &dil_pos, &dffns_pos, &lmtf_pos, &lmpl_pos);
  if (new_env == NULL) {
    errno = ENOMEM;
    goto error;
  }
  retval = orig_execve(prog, argv, new_env);
error:
  free_env(new_env, ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_execve>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <init_execve@plt>
  mov    %rbp,%rdi
  call   <report_exec@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  mov    %rbx,%rdi
  call   <clone_env@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <orig_execve@plt>
  mov    %eax,%ebp
L16:
  mov    0x20(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <free_env@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    %ebp,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%ebp
  jmp    L16
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_execve(char const *prog, char *const *argv, char *const *env) {
  int retval = -1;
  char **new_env = NULL;
  size_t ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos;
  init_execve();
  report_exec(prog);
  new_env = clone_env(env, &ldp_pos, &dil_pos, &dffns_pos, &lmtf_pos, &lmpl_pos);
  if (new_env == NULL) {
    errno = ENOMEM;
    goto error;
  }
  retval = orig_execve(prog, argv, new_env);
error:
  free_env(new_env, ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos);
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_execve>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <init_execve@plt>
  mov    %r12,%rdi
  call   <report_exec@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdx
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <clone_env@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %r13,%rsi
  call   <orig_execve@plt>
  mov    %eax,%r12d
L23:
  mov    0x20(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    %rbp,%rdi
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  call   <free_env@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    D7(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  jmp    L23
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_execve(char const *prog, char *const *argv, char *const *env) {
  int retval = -1;
  char **new_env = NULL;
  size_t ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos;
  init_execve();
  report_exec(prog);
  new_env = clone_env(env, &ldp_pos, &dil_pos, &dffns_pos, &lmtf_pos, &lmpl_pos);
  if (new_env == NULL) {
    errno = ENOMEM;
    goto error;
  }
  retval = orig_execve(prog, argv, new_env);
error:
  free_env(new_env, ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_execve>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <init_execve@plt>
  mov    %r12,%rdi
  call   <report_exec@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%rdx
  lea    0x20(%rsp),%r9
  lea    0x18(%rsp),%r8
  call   <clone_env@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %r13,%rsi
  call   <orig_execve@plt>
  mov    %eax,%r12d
L23:
  mov    0x20(%rsp),%r9
  mov    0x18(%rsp),%r8
  mov    %rbp,%rdi
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  mov    (%rsp),%rsi
  call   <free_env@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  mov    D5(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  jmp    L23
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int my_execve(char const *prog, char *const *argv, char *const *env) {
  int retval = -1;
  char **new_env = NULL;
  size_t ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos;
  init_execve();
  report_exec(prog);
  new_env = clone_env(env, &ldp_pos, &dil_pos, &dffns_pos, &lmtf_pos, &lmpl_pos);
  if (new_env == NULL) {
    errno = ENOMEM;
    goto error;
  }
  retval = orig_execve(prog, argv, new_env);
error:
  free_env(new_env, ldp_pos, dil_pos, dffns_pos, lmtf_pos, lmpl_pos);
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cut_word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L31
L40:
  addl   $0x1,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L40
L41:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L17
L58:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L58
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
char *cut_word(char *str, char c) {
  int i;
  int j;
  char *str_return;
  i = 0;
  while (str[i] && str[i] != c)
    i++;
  j = i;
  i = 0;
  if ((str_return = (char *)malloc(sizeof(char) * j + 1)) == NULL)
    return (NULL);
  while (i < j) {
    str_return[i] = str[i];
    i++;
  }
  str_return[i] = '\0';
  return (str_return);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cut_word>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  cmp    %sil,%al
  je     L32
  mov    %rdi,%r12
  mov    %esi,%ecx
  test   %al,%al
  je     L32
  lea    0x1(%rdi),%rax
  mov    $0x0,%ebx
L39:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L4
  test   %dl,%dl
  jne    L39
L4:
  lea    0x2(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L82
  test   %ebx,%ebx
  jle    L38
  mov    %rax,%rdx
  sub    %rax,%r12
L106:
  movzbl (%r12,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  mov    %edx,%ecx
  sub    %eax,%ecx
  sub    $0x1,%ecx
  cmp    %ecx,%ebp
  jg     L106
  test   %ebp,%ebp
  mov    $0x0,%eax
  cmovs  %eax,%ebp
  add    $0x1,%ebp
L83:
  movslq %ebp,%rbp
  movb   $0x0,(%rsi,%rbp,1)
L56:
  mov    %rsi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  mov    $0x0,%ebp
  jmp    L83
L82:
  mov    $0x0,%esi
  jmp    L56
L95:
  mov    $0x0,%esi
  jmp    L56
L32:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L95
  mov    $0x0,%ebp
  jmp    L83
```

assistant: ```c
char *cut_word(char *str, char c) {
  int i;
  int j;
  char *str_return;
  i = 0;
  while (str[i] && str[i] != c)
    i++;
  j = i;
  i = 0;
  if ((str_return = (char *)malloc(sizeof(char) * j + 1)) == NULL)
    return (NULL);
  while (i < j) {
    str_return[i] = str[i];
    i++;
  }
  str_return[i] = '\0';
  return (str_return);
}
```