user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D37(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%r12
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    $0xa,%ebp
  jne    L21
  mov    $0xa,%edi
  lea    0x28(%rbx),%r12
  lea    D109(%rip),%rbp
  call   <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L52:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L52
  mov    (%rsp),%esi
  xor    %ebp,%ebp
  test   $0x1,%sil
  je     L216
L57:
  mov    0x4(%rsp),%esi
  test   $0x1,%sil
  je     L20
L49:
  mov    0x8(%rsp),%esi
  test   $0x1,%sil
  je     L73
L81:
  mov    0xc(%rsp),%esi
  test   $0x1,%sil
  je     L185
L138:
  mov    0x10(%rsp),%esi
  test   $0x1,%sil
  je     L5
L26:
  mov    0x14(%rsp),%esi
  test   $0x1,%sil
  je     L2
L105:
  mov    0x18(%rsp),%esi
  test   $0x1,%sil
  je     L59
L80:
  mov    0x1c(%rsp),%esi
  test   $0x1,%sil
  je     L129
L132:
  mov    0x20(%rsp),%esi
  test   $0x1,%sil
  je     L53
L116:
  mov    0x24(%rsp),%esi
  test   $0x1,%sil
  je     L106
L201:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L216:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  mov    $0x1,%ebp
  call   <printf@plt>
  jmp    L57
L106:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L201
L53:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L116
L129:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L132
L59:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L80
L2:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L105
L5:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L26
L185:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L138
L73:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L81
L20:
  lea    D95(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  jmp    L49
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D109
datatype: string
name: retrieve_data
arguments: data_tag: D48
datatype: string
name: retrieve_data
arguments: data_tag: D95
datatype: string

tool: D37: 
Digite o %i elemento do vetor A: 

tool: D4: %d

tool: D109: %d 

tool: D48: 
Quantidade de pares: %d

tool: D95: 
Par: %d

assistant: ```c
int main(void) {
  int a[10];
  for (int i = 0; i < 10; i++) {
    printf("\nDigite o %i elemento do vetor A: ", i);
    scanf("%d", &a[i]);
  }
  printf("\n");
  for (int i = 0; i < 10; i++) {
    printf("%d ", a[i]);
  }
  int par = 0;
  for (int i = 0; i < 10; i++) {
    if (a[i] % 2 == 0) {
      printf("\nPar: %d", a[i]);
      par++;
    }
  }
  printf("\nQuantidade de pares: %d", par);
}
```