ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_val_utf82uni>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L42
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L15
L42:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xe0,%eax
  cmp    $0xc0,%eax
  jne    L7
  movq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1f,%al
  mov    %eax,-0xc(%rbp)
  jmp    L35
L7:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf0,%eax
  cmp    $0xe0,%eax
  jne    L45
  movq   $0x2,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf,%al
  mov    %eax,-0xc(%rbp)
  jmp    L35
L45:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xf8,%eax
  cmp    $0xf0,%eax
  jne    L14
  movq   $0x3,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x7,%al
  mov    %eax,-0xc(%rbp)
  jmp    L35
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xfc,%eax
  cmp    $0xf8,%eax
  jne    L77
  movq   $0x4,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3,%al
  mov    %eax,-0xc(%rbp)
  jmp    L35
L77:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0xfe,%eax
  cmp    $0xfc,%eax
  jne    L39
  movq   $0x5,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%al
  mov    %eax,-0xc(%rbp)
  jmp    L35
L39:
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
L35:
  addq   $0x4,-0x18(%rbp)
  jmp    L8
L104:
  shll   $0x6,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3f,%eax
  or     %eax,-0xc(%rbp)
  addq   $0x4,-0x18(%rbp)
  subq   $0x1,-0x8(%rbp)
L8:
  cmpq   $0x0,-0x8(%rbp)
  jne    L104
  mov    -0xc(%rbp),%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
wchar_t get_val_utf82uni(uint8_t *pstart) {
  size_t cntleft;
  wchar_t retval = 0;
  if (0 == (0x80 & *pstart))
    return *pstart;
  if (((*pstart & 0xE0) ^ 0xC0) == 0) {
    cntleft = 1;
    retval = *pstart & ~0xE0;
  } else if (((*pstart & 0xF0) ^ 0xE0) == 0) {
    cntleft = 2;
    retval = *pstart & ~0xF0;
  } else if (((*pstart & 0xF8) ^ 0xF0) == 0) {
    cntleft = 3;
    retval = *pstart & ~0xF8;
  } else if (((*pstart & 0xFC) ^ 0xF8) == 0) {
    cntleft = 4;
    retval = *pstart & ~0xFC;
  } else if (((*pstart & 0xFE) ^ 0xFC) == 0) {
    cntleft = 5;
    retval = *pstart & ~0xFE;
  } else {
    cntleft = 0;
    retval = 0;
  }
  pstart++;
  for (; cntleft > 0; cntleft--) {
    retval <<= 6;
    retval |= *pstart & 0x3F;
    pstart++;
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_val_utf82uni>:
  endbr64
  mov    (%rdi),%eax
  test   $0x80,%al
  je     L15
  mov    %eax,%edx
  and    $0xe0,%edx
  cmp    $0xc0,%edx
  je     L72
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L24
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L22
  mov    %eax,%edx
  and    $0xfc,%edx
  cmp    $0xf8,%edx
  je     L20
  mov    %eax,%edx
  and    $0xfe,%edx
  and    $0x1,%al
  mov    $0x5,%esi
  cmp    $0xfc,%edx
  je     L2
  mov    $0x0,%eax
  ret
L72:
  and    $0x1f,%al
  mov    $0x1,%esi
L2:
  mov    $0x0,%edx
L42:
  shl    $0x6,%eax
  mov    0x4(%rdi,%rdx,4),%ecx
  and    $0x3f,%ecx
  or     %ecx,%eax
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L42
  ret
L24:
  and    $0xf,%al
  mov    $0x2,%esi
  jmp    L2
L22:
  and    $0x7,%al
  mov    $0x3,%esi
  jmp    L2
L20:
  and    $0x3,%al
  mov    $0x4,%esi
  jmp    L2
L15:
  ret
```

assistant: ```c
wchar_t get_val_utf82uni(uint8_t *pstart) {
  size_t cntleft;
  wchar_t retval = 0;
  if (0 == (0x80 & *pstart))
    return *pstart;
  if (((*pstart & 0xE0) ^ 0xC0) == 0) {
    cntleft = 1;
    retval = *pstart & ~0xE0;
  } else if (((*pstart & 0xF0) ^ 0xE0) == 0) {
    cntleft = 2;
    retval = *pstart & ~0xF0;
  } else if (((*pstart & 0xF8) ^ 0xF0) == 0) {
    cntleft = 3;
    retval = *pstart & ~0xF8;
  } else if (((*pstart & 0xFC) ^ 0xF8) == 0) {
    cntleft = 4;
    retval = *pstart & ~0xFC;
  } else if (((*pstart & 0xFE) ^ 0xFC) == 0) {
    cntleft = 5;
    retval = *pstart & ~0xFE;
  } else {
    cntleft = 0;
    retval = 0;
  }
  pstart++;
  for (; cntleft > 0; cntleft--) {
    retval <<= 6;
    retval |= *pstart & 0x3F;
    pstart++;
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_val_utf82uni>:
  endbr64
  mov    (%rdi),%eax
  test   $0x80,%al
  je     L46
  mov    %eax,%edx
  and    $0xe0,%edx
  cmp    $0xc0,%edx
  je     L73
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L48
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L61
  mov    %eax,%edx
  and    $0xfc,%edx
  cmp    $0xf8,%edx
  je     L5
  mov    %eax,%edx
  and    $0xfe,%edx
  cmp    $0xfc,%edx
  je     L24
  xor    %eax,%eax
L46:
  ret
  nopl   (%rax)
L73:
  mov    0x4(%rdi),%edx
  shl    $0x6,%eax
  and    $0xffffc7c0,%eax
  and    $0x3f,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L61:
  and    $0x7,%al
  add    $0x4,%rdi
  mov    $0x3,%edx
L54:
  lea    (%rdi,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rdi),%edx
  shl    $0x6,%eax
  add    $0x4,%rdi
  and    $0x3f,%edx
  or     %edx,%eax
  cmp    %rcx,%rdi
  jne    L60
  ret
  nopl   0x0(%rax)
L48:
  and    $0xf,%al
  add    $0x4,%rdi
  mov    $0x2,%edx
  jmp    L54
  nopl   (%rax)
L5:
  and    $0x3,%al
  add    $0x4,%rdi
  mov    $0x4,%edx
  jmp    L54
  nopl   (%rax)
L24:
  and    $0x1,%al
  add    $0x4,%rdi
  mov    $0x5,%edx
  jmp    L54
```

assistant: ```c
wchar_t get_val_utf82uni(uint8_t *pstart) {
  size_t cntleft;
  wchar_t retval = 0;
  if (0 == (0x80 & *pstart))
    return *pstart;
  if (((*pstart & 0xE0) ^ 0xC0) == 0) {
    cntleft = 1;
    retval = *pstart & ~0xE0;
  } else if (((*pstart & 0xF0) ^ 0xE0) == 0) {
    cntleft = 2;
    retval = *pstart & ~0xF0;
  } else if (((*pstart & 0xF8) ^ 0xF0) == 0) {
    cntleft = 3;
    retval = *pstart & ~0xF8;
  } else if (((*pstart & 0xFC) ^ 0xF8) == 0) {
    cntleft = 4;
    retval = *pstart & ~0xFC;
  } else if (((*pstart & 0xFE) ^ 0xFC) == 0) {
    cntleft = 5;
    retval = *pstart & ~0xFE;
  } else {
    cntleft = 0;
    retval = 0;
  }
  pstart++;
  for (; cntleft > 0; cntleft--) {
    retval <<= 6;
    retval |= *pstart & 0x3F;
    pstart++;
  }
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_val_utf82uni>:
  endbr64
  mov    (%rdi),%eax
  test   $0x80,%al
  je     L105
  mov    %eax,%edx
  and    $0xe0,%edx
  cmp    $0xc0,%edx
  je     L10
  mov    %eax,%edx
  and    $0xf0,%edx
  cmp    $0xe0,%edx
  je     L108
  mov    %eax,%edx
  and    $0xf8,%edx
  cmp    $0xf0,%edx
  je     L31
  mov    %eax,%edx
  and    $0xfc,%edx
  cmp    $0xf8,%edx
  je     L50
  mov    %eax,%edx
  and    $0xfe,%edx
  cmp    $0xfc,%edx
  je     L110
  xor    %eax,%eax
L105:
  ret
  nopl   0x0(%rax)
L10:
  mov    0x4(%rdi),%edx
  shl    $0x6,%eax
  and    $0xffffc7c0,%eax
  and    $0x3f,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L31:
  and    $0x7,%al
  add    $0x4,%rdi
  mov    $0x3,%ecx
L46:
  mov    (%rdi),%edx
  shl    $0x6,%eax
  and    $0x3f,%edx
  or     %eax,%edx
  mov    0x4(%rdi),%eax
  shl    $0x6,%edx
  and    $0x3f,%eax
  or     %edx,%eax
  cmp    $0x2,%rcx
  je     L105
  mov    0x8(%rdi),%edx
  shl    $0x6,%eax
  and    $0x3f,%edx
  or     %edx,%eax
  sub    $0x3,%rcx
  je     L105
  mov    0xc(%rdi),%edx
  shl    $0x6,%eax
  and    $0x3f,%edx
  or     %edx,%eax
  cmp    $0x1,%rcx
  je     L105
  mov    0x10(%rdi),%edx
  shl    $0x6,%eax
  and    $0x3f,%edx
  or     %edx,%eax
  ret
  nopl   0x0(%rax)
L108:
  and    $0xf,%al
  add    $0x4,%rdi
  mov    $0x2,%ecx
  jmp    L46
  nopl   (%rax)
L50:
  and    $0x3,%al
  add    $0x4,%rdi
  mov    $0x4,%ecx
  jmp    L46
  nopl   (%rax)
L110:
  and    $0x1,%al
  add    $0x4,%rdi
  mov    $0x5,%ecx
  jmp    L46
```

assistant: ```c
wchar_t get_val_utf82uni(uint8_t *pstart) {
  size_t cntleft;
  wchar_t retval = 0;
  if (0 == (0x80 & *pstart))
    return *pstart;
  if (((*pstart & 0xE0) ^ 0xC0) == 0) {
    cntleft = 1;
    retval = *pstart & ~0xE0;
  } else if (((*pstart & 0xF0) ^ 0xE0) == 0) {
    cntleft = 2;
    retval = *pstart & ~0xF0;
  } else if (((*pstart & 0xF8) ^ 0xF0) == 0) {
    cntleft = 3;
    retval = *pstart & ~0xF8;
  } else if (((*pstart & 0xFC) ^ 0xF8) == 0) {
    cntleft = 4;
    retval = *pstart & ~0xFC;
  } else if (((*pstart & 0xFE) ^ 0xFC) == 0) {
    cntleft = 5;
    retval = *pstart & ~0xFE;
  } else {
    cntleft = 0;
    retval = 0;
  }
  pstart++;
  for (; cntleft > 0; cntleft--) {
    retval <<= 6;
    retval |= *pstart & 0x3F;
    pstart++;
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int msw(long long in) {
  union {
    long long ll;
    int i[2];
  } ud;
  ud.ll = in;
  return ud.i[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msw>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int msw(long long in) {
  union {
    long long ll;
    int i[2];
  } ud;
  ud.ll = in;
  return ud.i[0];
}
```
user: What is the c source code of the assembly code below:

```asm
<msw>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int msw(long long in) {
  union {
    long long ll;
    int i[2];
  } ud;
  ud.ll = in;
  return ud.i[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<msw>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
int msw(long long in) {
  union {
    long long ll;
    int i[2];
  } ud;
  ud.ll = in;
  return ud.i[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ltr_int_close_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <shutdown@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ltr_int_close_socket(int socket) {
  shutdown(socket, SHUT_RDWR);
  close(socket);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltr_int_close_socket>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  call   <shutdown@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ltr_int_close_socket(int socket) {
  shutdown(socket, SHUT_RDWR);
  close(socket);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ltr_int_close_socket>:
  endbr64
  mov    D6(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <shutdown@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ltr_int_close_socket(int socket) {
  shutdown(socket, SHUT_RDWR);
  close(socket);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ltr_int_close_socket>:
  endbr64
  mov    D5(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <shutdown@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ltr_int_close_socket(int socket) {
  shutdown(socket, SHUT_RDWR);
  close(socket);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<solve_standard_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x60,%rsp
  mov    %rdi,-0x1038(%rbp)
  mov    %esi,-0x103c(%rbp)
  mov    %rdx,-0x1048(%rbp)
  mov    %rcx,-0x1050(%rbp)
  mov    %r8d,-0x1040(%rbp)
  mov    %r9d,-0x1054(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x103c(%rbp),%eax
  mov    %eax,-0x1010(%rbp)
  mov    -0x1040(%rbp),%eax
  mov    %eax,-0x100c(%rbp)
  mov    -0x1054(%rbp),%eax
  mov    %eax,-0x1008(%rbp)
  mov    -0x1020(%rbp),%rcx
  lea    -0x1010(%rbp),%rdx
  lea    -0x1018(%rbp),%rax
  mov    0x10(%rbp),%r8d
  mov    %rax,%rsi
  mov    $0x4d,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1024(%rbp)
  mov    -0x1018(%rbp),%edx
  mov    -0x1038(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x103c(%rbp)
  jne    L6
  mov    -0x1014(%rbp),%edx
  mov    -0x1048(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x1028(%rbp)
  jmp    L0
L10:
  mov    -0x1028(%rbp),%eax
  cltq
  mov    -0x1010(%rbp,%rax,4),%edx
  mov    -0x1028(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1050(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x1028(%rbp)
L0:
  mov    -0x1048(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1028(%rbp)
  jl     L10
  mov    -0x1048(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x1050(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L6:
  mov    -0x1024(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int solve_standard_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int mvfocus, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  b[2] = mvfocus;
  fail = _ada_use_c2phc(77, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<solve_standard_system>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    %esi,0x10(%rsp)
  mov    %r8d,0x14(%rsp)
  mov    %r9d,0x18(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    0x1050(%rsp),%r8d
  mov    $0x0,%ecx
  mov    $0x4d,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,0x0(%r13)
  test   %r12d,%r12d
  jne    L12
  mov    0xc(%rsp),%ecx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L27
  mov    $0x0,%edx
L23:
  mov    0x10(%rsp,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  mov    0x0(%rbp),%ecx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L23
L27:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
L12:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x1028,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_standard_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int mvfocus, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  b[2] = mvfocus;
  fail = _ada_use_c2phc(77, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<solve_standard_system>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r8d,0x14(%rsp)
  mov    %rdi,%r14
  mov    %esi,0x10(%rsp)
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %r12,%rdx
  lea    0x8(%rsp),%rsi
  xor    %ecx,%ecx
  mov    $0x4d,%edi
  mov    0x1050(%rsp),%r8d
  mov    %r9d,0x18(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,(%r14)
  test   %r13d,%r13d
  jne    L5
  movslq 0xc(%rsp),%rcx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L12
  xor    %edx,%edx
  nopl   0x0(%rax)
L10:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  movslq 0x0(%rbp),%rcx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L10
L12:
  movb   $0x0,(%rbx,%rcx,1)
L5:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x1020,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_standard_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int mvfocus, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  b[2] = mvfocus;
  fail = _ada_use_c2phc(77, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<solve_standard_system>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  movd   %r8d,%xmm1
  movd   %esi,%xmm0
  mov    %rdi,%r14
  mov    %esi,%r13d
  lea    0x10(%rsp),%r12
  punpckldq %xmm1,%xmm0
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %r12,%rdx
  lea    0x8(%rsp),%rsi
  xor    %ecx,%ecx
  mov    $0x4d,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x1018(%rsp)
  xor    %eax,%eax
  mov    0x1050(%rsp),%r8d
  mov    %r9d,0x18(%rsp)
  movq   %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x8(%rsp),%edx
  mov    %edx,(%r14)
  test   %r13d,%r13d
  jne    L26
  movslq 0xc(%rsp),%rcx
  mov    %ecx,0x0(%rbp)
  test   %ecx,%ecx
  jle    L22
  xor    %edx,%edx
  xchg   %ax,%ax
L24:
  mov    (%r12,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  movslq 0x0(%rbp),%rcx
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L24
L22:
  movb   $0x0,(%rbx,%rcx,1)
L26:
  mov    0x1018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x1020,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solve_standard_system(int *root_count, int silent, int *nrcs, char *rocos, int nbtasks, int mvfocus, int vrb) {
  int fail, i;
  int a[2];
  int b[1024];
  double *c;
  b[0] = silent;
  b[1] = nbtasks;
  b[2] = mvfocus;
  fail = _ada_use_c2phc(77, a, b, c, vrb);
  *root_count = a[0];
  if (silent == 0) {
    *nrcs = a[1];
    for (i = 0; i < (*nrcs); i++)
      rocos[i] = (char)b[i];
    rocos[*nrcs] = '\0';
  }
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x3,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x8,-0x24(%rbp)
  movl   $0x9,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  lea    -0x40(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <display@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <show@plt>
  lea    -0x40(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
main() {
  int a[3][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 6};
  display(a, 3, 4);
  show(a, 3, 4);
  print(a, 3, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0x6,0x2c(%rsp)
  mov    %rsp,%rbx
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <display@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <show@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <print@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int a[3][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 6};
  display(a, 3, 4);
  show(a, 3, 4);
  print(a, 3, 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x3,%esi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbp
  movq   $0x9,0x20(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x600000001,%rax
  mov    %rax,0x28(%rsp)
  call   <display@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <show@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
main() {
  int a[3][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 6};
  display(a, 3, 4);
  show(a, 3, 4);
  print(a, 3, 4);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  mov    $0x3,%esi
  sub    $0x40,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D18(%rip),%xmm0
  mov    %rbp,%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D8(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <display@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <show@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <print@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: byte[16]
name: read_data
arguments: tag: D18
type_guessed: byte[16]
name: read_data
arguments: tag: D8
type_guessed: byte[16]

tool: {"D0": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D18": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D8": [0x09,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
main() {
  int a[3][4] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 6};
  display(a, 3, 4);
  show(a, 3, 4);
  print(a, 3, 4);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<yystpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L6:
  nop
L7:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *yystpcpy(char *yydest, const char *yysrc) {
  char *yyd = yydest;
  const char *yys = yysrc;
  while ((*yyd++ = *yys++) != '\0') {
    continue;
  }
  return yyd - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<yystpcpy>:
  endbr64
  mov    %rdi,%rax
L4:
  add    $0x1,%rsi
  lea    0x1(%rax),%rcx
  movzbl -0x1(%rsi),%edx
  mov    %dl,-0x1(%rcx)
  test   %dl,%dl
  jne    L3
  ret
L3:
  mov    %rcx,%rax
  jmp    L4
```

assistant: ```c
char *yystpcpy(char *yydest, const char *yysrc) {
  char *yyd = yydest;
  const char *yys = yysrc;
  while ((*yyd++ = *yys++) != '\0') {
    continue;
  }
  return yyd - 1;
}
```