ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<fun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x51,%esi
  jg     L56
  lea    -0x1(%rsi),%r12d
  mov    %rdi,%r15
  mov    $0x1,%ebx
  movslq %r12d,%rbp
  mov    %r12d,%eax
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x1f,%eax
  sar    $0x21,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,8),%eax
  sub    %eax,%r12d
  movslq %ebp,%rax
  lea    (%rax,%rax,8),%rdx
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    (%rax,%rdx,4),%r13
  lea    0x1(%rsi),%eax
  add    %rdi,%r13
  mov    %eax,0xc(%rsp)
  mov    0x0(%r13),%r14d
  test   %r14d,%r14d
  je     L54
  mov    %eax,%esi
  xor    %r14d,%r14d
  call   <fun>
  test   %eax,%eax
  setne  %r14b
L1:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %ebx,0x0(%r13)
  mov    0xc(%rsp),%esi
  mov    %r15,%rdi
  call   <fun>
  test   %eax,%eax
  jne    L56
  movl   $0x0,0x0(%r13)
L16:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L1
L54:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <check@plt>
  test   %rax,%rax
  je     L16
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L56:
  mov    $0x1,%r14d
  jmp    L1
```

assistant: ```c
int fun(int (*a)[9], int count) {
  int i;
  int x;
  int y;
  if (count > 81)
    return 1;
  x = (count - 1) / 9;
  y = (count - 1) % 9;
  if (a[x][y] != 0) {
    if (fun(a, count + 1))
      return 1;
    return 0;
  } else {
    for (i = 1; i <= 9; ++i) {
      if (check(a, x, y, i)) {
        a[x][y] = i;
        if (fun(a, count + 1))
          return 1;
        a[x][y] = 0;
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fun>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x51,%esi
  jg     L41
  lea    -0x1(%rsi),%r12d
  mov    %rdi,%r15
  mov    $0x1,%ebx
  movslq %r12d,%rbp
  mov    %r12d,%eax
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x1f,%eax
  sar    $0x21,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,8),%eax
  sub    %eax,%r12d
  movslq %ebp,%rax
  lea    (%rax,%rax,8),%rdx
  movslq %r12d,%rax
  shl    $0x2,%rax
  lea    (%rax,%rdx,4),%r13
  lea    0x1(%rsi),%eax
  add    %rdi,%r13
  mov    %eax,0xc(%rsp)
  mov    0x0(%r13),%r14d
  test   %r14d,%r14d
  je     L12
  mov    %eax,%esi
  xor    %r14d,%r14d
  call   <fun>
  test   %eax,%eax
  setne  %r14b
L59:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,0x0(%r13)
  mov    0xc(%rsp),%esi
  mov    %r15,%rdi
  call   <fun>
  test   %eax,%eax
  jne    L41
  movl   $0x0,0x0(%r13)
L10:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L59
L12:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <check@plt>
  test   %rax,%rax
  je     L10
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L41:
  mov    $0x1,%r14d
  jmp    L59
```

assistant: ```c
int fun(int (*a)[9], int count) {
  int i;
  int x;
  int y;
  if (count > 81)
    return 1;
  x = (count - 1) / 9;
  y = (count - 1) % 9;
  if (a[x][y] != 0) {
    if (fun(a, count + 1))
      return 1;
    return 0;
  } else {
    for (i = 1; i <= 9; ++i) {
      if (check(a, x, y, i)) {
        a[x][y] = i;
        if (fun(a, count + 1))
          return 1;
        a[x][y] = 0;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_symbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3e,-0x4(%rbp)
  jg     L72
  cmpl   $0x21,-0x4(%rbp)
  jge    L83
  jmp    L61
L38:
  mov    -0x4(%rbp),%eax
  sub    $0x5b,%eax
  movabs $0xa0000000d,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L60
  jmp    L61
L83:
  mov    -0x4(%rbp),%eax
  movabs $0x7c00bf7200000000,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  jne    L60
  jmp    L61
L72:
  cmpl   $0x7e,-0x4(%rbp)
  jg     L61
  cmpl   $0x5b,-0x4(%rbp)
  jge    L38
  jmp    L61
L60:
  mov    $0x1,%eax
  jmp    L44
L61:
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
bool is_symbol(int c) {
  switch (c) {
  case '+':
  case '-':
  case '*':
  case '/':
  case '%':
  case '$':
  case '~':
  case ',':
  case '(':
  case ')':
  case '[':
  case ']':
  case '^':
  case ';':
  case ':':
  case '|':
  case '&':
  case '=':
  case '!':
  case '<':
  case '>':
    return true;
  default:
    return false;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_symbol>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%edi
  jg     L1
  cmp    $0x20,%edi
  jg     L8
  mov    $0x0,%eax
  ret
L8:
  movabs $0x7c00bf7200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L1:
  sub    $0x5b,%ecx
  movabs $0xa0000000d,%rdx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  cmp    $0x24,%ecx
  mov    $0x0,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
bool is_symbol(int c) {
  switch (c) {
  case '+':
  case '-':
  case '*':
  case '/':
  case '%':
  case '$':
  case '~':
  case ',':
  case '(':
  case ')':
  case '[':
  case ']':
  case '^':
  case ';':
  case ':':
  case '|':
  case '&':
  case '=':
  case '!':
  case '<':
  case '>':
    return true;
  default:
    return false;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_symbol>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%edi
  jg     L12
  cmp    $0x20,%edi
  jg     L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  movabs $0xa0000000d,%rdx
  sub    $0x5b,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x24,%ecx
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movabs $0x7c00bf7200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool is_symbol(int c) {
  switch (c) {
  case '+':
  case '-':
  case '*':
  case '/':
  case '%':
  case '$':
  case '~':
  case ',':
  case '(':
  case ')':
  case '[':
  case ']':
  case '^':
  case ';':
  case ':':
  case '|':
  case '&':
  case '=':
  case '!':
  case '<':
  case '>':
    return true;
  default:
    return false;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_symbol>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3e,%edi
  jg     L12
  cmp    $0x20,%edi
  jg     L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  movabs $0xa0000000d,%rdx
  sub    $0x5b,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x24,%ecx
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movabs $0x7c00bf7200000000,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool is_symbol(int c) {
  switch (c) {
  case '+':
  case '-':
  case '*':
  case '/':
  case '%':
  case '$':
  case '~':
  case ',':
  case '(':
  case ')':
  case '[':
  case ']':
  case '^':
  case ';':
  case ':':
  case '|':
  case '&':
  case '=':
  case '!':
  case '<':
  case '>':
    return true;
  default:
    return false;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rand64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L13:
  shll   $0x8,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movzbl %al,%eax
  or     %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x7,-0x4(%rbp)
  jle    L13
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t rand64() {
  uint64_t x = 0;
  for (int i = 0; i < 8; i++) {
    x <<= 8;
    x |= rand() & 0xff;
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rand64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x8,%ebp
  mov    $0x0,%ebx
L6:
  shl    $0x8,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  movzbl %al,%eax
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L6
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rand64() {
  uint64_t x = 0;
  for (int i = 0; i < 8; i++) {
    x <<= 8;
    x |= rand() & 0xff;
  }
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<rand64>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  shl    $0x8,%ebx
  call   <rand@plt>
  movzbl %al,%eax
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L2
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rand64() {
  uint64_t x = 0;
  for (int i = 0; i < 8; i++) {
    x <<= 8;
    x |= rand() & 0xff;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rand64>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  shl    $0x8,%ebx
  call   <rand@plt>
  movzbl %al,%eax
  or     %eax,%ebx
  sub    $0x1,%ebp
  jne    L7
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint64_t rand64() {
  uint64_t x = 0;
  for (int i = 0; i < 8; i++) {
    x <<= 8;
    x |= rand() & 0xff;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0x3ff,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x200,%eax
  test   %eax,%eax
  je     L3
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  xor    $0x3ff,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  D49(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  D22(%rip),%xmm1
  xorps  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L3:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x4(%rbp),%xmm0
  movss  D49(%rip),%xmm1
  divss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L0:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D49
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D22
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: {"D49": [0x00,0x00,0x80,0x43]}

tool: {"D22": [0x00,0x00,0x00,0x80]}

tool: D8: %f


assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t value;
  value = strtoul(argv[1], NULL, 16);
  value &= 0x3ff;
  if ((value >> 9) & 0x1)
    printf("%f\n", -(((value - 1) ^ 0x3ff) / 256.0f));
  else
    printf("%f\n", value / 256.0f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,%edx
  and    $0x3ff,%edx
  test   $0x2,%ah
  je     L3
  sub    $0x1,%edx
  xor    $0x3ff,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  mulss  D46(%rip),%xmm0
  xorps  D13(%rip),%xmm0
  cvttss2si %xmm0,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  mulss  D46(%rip),%xmm0
  cvttss2si %xmm0,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D46
type_guessed: byte[4]
name: parse_data
arguments: tag: D13
type_guessed: byte[16]
name: parse_data
arguments: tag: D33
type_guessed: string

tool: {"D46": [0x00,0x00,0x80,0x3b]}

tool: {"D13": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D33: %f


assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t value;
  value = strtoul(argv[1], NULL, 16);
  value &= 0x3ff;
  if ((value >> 9) & 0x1)
    printf("%f\n", -(((value - 1) ^ 0x3ff) / 256.0f));
  else
    printf("%f\n", value / 256.0f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %eax,%edx
  and    $0x3ff,%edx
  test   $0x2,%ah
  je     L13
  sub    $0x1,%edx
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  xor    $0x3ff,%edx
  cvtsi2ss %edx,%xmm0
  mulss  D11(%rip),%xmm0
  xorps  D14(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L13:
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rdi
  cvtsi2ss %edx,%xmm0
  mulss  D11(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: byte[4]
name: retrieve_data
arguments: tag: D14
type_infered: byte[16]

tool: D1: %f


tool: {"D11": [0x00,0x00,0x80,0x3b]}

tool: {"D14": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t value;
  value = strtoul(argv[1], NULL, 16);
  value &= 0x3ff;
  if ((value >> 9) & 0x1)
    printf("%f\n", -(((value - 1) ^ 0x3ff) / 256.0f));
  else
    printf("%f\n", value / 256.0f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %eax,%edx
  and    $0x3ff,%edx
  test   $0x2,%ah
  je     L14
  sub    $0x1,%edx
  pxor   %xmm0,%xmm0
  lea    D45(%rip),%rdi
  xor    $0x3ff,%edx
  cvtsi2ss %edx,%xmm0
  mulss  D35(%rip),%xmm0
  xorps  D34(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
L12:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L14:
  pxor   %xmm0,%xmm0
  lea    D45(%rip),%rdi
  cvtsi2ss %edx,%xmm0
  mulss  D35(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: label: D45
type_infered: string
name: read_data
arguments: label: D35
type_infered: byte[4]
name: read_data
arguments: label: D34
type_infered: byte[16]

tool: D45: %f


tool: {"D35": [0x00,0x00,0x80,0x3b]}

tool: {"D34": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t value;
  value = strtoul(argv[1], NULL, 16);
  value &= 0x3ff;
  if ((value >> 9) & 0x1)
    printf("%f\n", -(((value - 1) ^ 0x3ff) / 256.0f));
  else
    printf("%f\n", value / 256.0f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x7,%eax
  cmp    $0x6,%eax
  ja     L14
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L19
L14:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f() {
  int var = 7;
  if ((var / 7) == 1)
    return var / 7;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parsePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x78(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x58(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L21
  mov    -0x58(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  movb   $0x0,(%rax)
L21:
  movl   $0x0,-0x60(%rbp)
  movl   $0x0,-0x5c(%rbp)
L61:
  movl   $0x0,-0x64(%rbp)
  jmp    L62
L53:
  mov    -0x60(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x60(%rbp)
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x64(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x64(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x50(%rbp,%rax,1)
L62:
  mov    -0x60(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L50
  mov    -0x60(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
L50:
  mov    -0x64(%rbp),%eax
  cltq
  movb   $0x0,-0x50(%rbp,%rax,1)
  addl   $0x1,-0x5c(%rbp)
  cmpl   $0x0,-0x7c(%rbp)
  jne    L14
  lea    -0x50(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L14:
  subl   $0x1,-0x7c(%rbp)
  mov    -0x60(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x60(%rbp)
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jg     L61
  mov    -0x5c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L67
  call   <__stack_chk_fail@plt>
L67:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int parsePath(const char *path, int idx, char *parsed) {
  char *path2;
  path2 = (char *)calloc(sizeof(char), strlen(path) + 1);
  strcpy(path2, path);
  if (strrchr(path2, '/') == strchr(path2, 0) - 1) {
    *(strrchr(path2, '/')) = 0;
  }
  char name[(56)];
  int i;
  int pos;
  int cnt;
  pos = 0;
  cnt = 0;
  do {
    i = 0;
    while (path[pos] != '/' && path2[pos] != 0) {
      name[i++] = path2[pos++];
    }
    name[i] = 0;
    cnt++;
    if (idx == 0) {
      strcpy(parsed, name);
    }
    idx--;
  } while (path2[pos++] > 0);
  return cnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parsePath>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%r13
  mov    %esi,0x4(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    -0x1(%r12,%rax,1),%rax
  cmp    %rax,%rbx
  je     L86
L103:
  mov    $0x0,%r14d
  mov    $0x0,%ebp
  lea    0x10(%rsp),%r15
  jmp    L83
L86:
  movb   $0x0,(%rbx)
  jmp    L103
L96:
  movslq %edx,%rdx
  movb   $0x0,0x10(%rsp,%rdx,1)
  add    $0x1,%r14d
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
  cmp    %r14d,%eax
  je     L93
L14:
  add    $0x1,%ebp
  cmpb   $0x0,(%r12,%rbx,1)
  jle    L31
L83:
  movslq %ebp,%rax
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    %r15,%rcx
  sub    %rax,%rcx
  cmpb   $0x2f,0x0(%r13,%rax,1)
  je     L96
L36:
  movzbl (%r12,%rbx,1),%eax
  test   %al,%al
  je     L96
  add    $0x1,%ebp
  add    $0x1,%edx
  mov    %al,(%rcx,%rbx,1)
  add    $0x1,%rbx
  cmpb   $0x2f,0x0(%r13,%rbx,1)
  jne    L36
  jmp    L96
L93:
  mov    %r15,%rsi
  mov    0x8(%rsp),%rdi
  call   <strcpy@plt>
  jmp    L14
L31:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    %r14d,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parsePath(const char *path, int idx, char *parsed) {
  char *path2;
  path2 = (char *)calloc(sizeof(char), strlen(path) + 1);
  strcpy(path2, path);
  if (strrchr(path2, '/') == strchr(path2, 0) - 1) {
    *(strrchr(path2, '/')) = 0;
  }
  char name[(56)];
  int i;
  int pos;
  int cnt;
  pos = 0;
  cnt = 0;
  do {
    i = 0;
    while (path[pos] != '/' && path2[pos] != 0) {
      name[i++] = path2[pos++];
    }
    name[i] = 0;
    cnt++;
    if (idx == 0) {
      strcpy(parsed, name);
    }
    idx--;
  } while (path2[pos++] > 0);
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parsePath>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%r15
  mov    %rax,%rbp
  mov    %r15,%rsi
  call   <calloc@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strrchr@plt>
  lea    -0x1(%r12,%rbp,1),%rdx
  cmp    %rdx,%rax
  je     L89
L73:
  xor    %r15d,%r15d
  lea    0x1(%r13),%r8d
  lea    0x10(%rsp),%rbx
  xor    %esi,%esi
L41:
  movslq %esi,%rax
  mov    %rbx,%rdi
  xor    %ecx,%ecx
  sub    %rax,%rdi
  cmpb   $0x2f,(%r14,%rax,1)
  jne    L60
  jmp    L94
  nopl   0x0(%rax)
L39:
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  add    $0x1,%ecx
  cmpb   $0x2f,(%r14,%rax,1)
  je     L94
L60:
  movzbl (%r12,%rax,1),%edx
  mov    %esi,%ebp
  lea    (%r12,%rax,1),%r13
  lea    0x1(%rsi),%esi
  test   %dl,%dl
  jne    L39
L98:
  movslq %ecx,%rcx
  add    $0x1,%r15d
  movb   $0x0,0x10(%rsp,%rcx,1)
  cmp    %r15d,%r8d
  je     L49
L21:
  cmpb   $0x0,0x0(%r13)
  lea    0x1(%rbp),%esi
  jg     L41
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x58,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  lea    (%r12,%rax,1),%r13
  mov    %esi,%ebp
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L49:
  mov    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  mov    %r8d,0x4(%rsp)
  call   <strcpy@plt>
  mov    0x4(%rsp),%r8d
  jmp    L21
L89:
  movb   $0x0,(%rax)
  jmp    L73
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parsePath(const char *path, int idx, char *parsed) {
  char *path2;
  path2 = (char *)calloc(sizeof(char), strlen(path) + 1);
  strcpy(path2, path);
  if (strrchr(path2, '/') == strchr(path2, 0) - 1) {
    *(strrchr(path2, '/')) = 0;
  }
  char name[(56)];
  int i;
  int pos;
  int cnt;
  pos = 0;
  cnt = 0;
  do {
    i = 0;
    while (path[pos] != '/' && path2[pos] != 0) {
      name[i++] = path2[pos++];
    }
    name[i] = 0;
    cnt++;
    if (idx == 0) {
      strcpy(parsed, name);
    }
    idx--;
  } while (path2[pos++] > 0);
  return cnt;
}
```