ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<uintmaxToHexString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L6
  mov    %edi,%ebx
  mov    $0x1,%r12d
  lea    D19(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rbx,%rax,1),%edi
  and    $0xf,%edi
  sub    %eax,%edi
  call   <hexDigit@plt>
  test   %ebx,%ebx
  mov    %r12d,%esi
  mov    %al,0x0(%rbp,%r12,1)
  lea    0xf(%rbx),%eax
  cmovs  %eax,%ebx
  add    $0x1,%r12
  sar    $0x4,%ebx
  jne    L20
  movslq %esi,%rbx
  add    $0x3,%rbx
L28:
  lea    D13(%rip),%rdi
  call   <reverseCharBuffer@plt>
  lea    D26(%rip),%rax
  movb   $0x0,(%rax,%rbx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %esi,%esi
  mov    $0x3,%ebx
  jmp    L28
```

assistant: ```c
char *uintmaxToHexString(uintmax_t n) {
  static char string[3 + sizeof(n) * 2] = "0x";
  static char *const digits = string + 2;
  int i;
  for (i = 0; n; i++) {
    digits[i] = hexDigit(n % 16);
    n /= 16;
  }
  reverseCharBuffer(digits, i);
  digits[i + 1] = '\0';
  return string;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<save_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%edi
  call   <dup@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rbx
  mov    $0x1,%edi
  call   <dup@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void save_fd(int *fd) {
  fd[0] = dup(0);
  fd[1] = dup(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<save_fd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%edi
  call   <dup@plt>
  mov    %eax,(%rbx)
  mov    $0x1,%edi
  call   <dup@plt>
  mov    %eax,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void save_fd(int *fd) {
  fd[0] = dup(0);
  fd[1] = dup(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<save_fd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <dup@plt>
  mov    $0x1,%edi
  mov    %eax,(%rbx)
  call   <dup@plt>
  mov    %eax,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void save_fd(int *fd) {
  fd[0] = dup(0);
  fd[1] = dup(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<save_fd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  call   <dup@plt>
  mov    $0x1,%edi
  mov    %eax,(%rbx)
  call   <dup@plt>
  mov    %eax,0x4(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void save_fd(int *fd) {
  fd[0] = dup(0);
  fd[1] = dup(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pthread_condattr_setpshared>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L11
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L11
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  jmp    L18
L11:
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L21
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L18
L21:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int pthread_condattr_setpshared(pthread_condattr_t *attr, int pshared) {
  (void)attr;
  if ((pshared != PTHREAD_PROCESS_PRIVATE) && (pshared != PTHREAD_PROCESS_SHARED))
    return EINVAL;
  if (pshared != PTHREAD_PROCESS_PRIVATE)
    return ENOSYS;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pthread_condattr_setpshared>:
  endbr64
  mov    $0x0,%eax
  mov    D14(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L9
  mov    D5(%rip),%rax
  cmp    %esi,(%rax)
  je     L8
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  ret
L8:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
L9:
  ret
```

assistant: ```c
int pthread_condattr_setpshared(pthread_condattr_t *attr, int pshared) {
  (void)attr;
  if ((pshared != PTHREAD_PROCESS_PRIVATE) && (pshared != PTHREAD_PROCESS_SHARED))
    return EINVAL;
  if (pshared != PTHREAD_PROCESS_PRIVATE)
    return ENOSYS;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pthread_condattr_setpshared>:
  endbr64
  mov    D39(%rip),%rdx
  xor    %eax,%eax
  cmp    %esi,(%rdx)
  je     L5
  mov    D28(%rip),%rax
  cmp    %esi,(%rax)
  je     L15
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    D38(%rip),%rax
  mov    (%rax),%eax
L5:
  ret
```

assistant: ```c
int pthread_condattr_setpshared(pthread_condattr_t *attr, int pshared) {
  (void)attr;
  if ((pshared != PTHREAD_PROCESS_PRIVATE) && (pshared != PTHREAD_PROCESS_SHARED))
    return EINVAL;
  if (pshared != PTHREAD_PROCESS_PRIVATE)
    return ENOSYS;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pthread_condattr_setpshared>:
  endbr64
  mov    D1(%rip),%rdx
  xor    %eax,%eax
  cmp    %esi,(%rdx)
  je     L14
  mov    D19(%rip),%rax
  cmp    %esi,(%rax)
  je     L1
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L14:
  ret
```

assistant: ```c
int pthread_condattr_setpshared(pthread_condattr_t *attr, int pshared) {
  (void)attr;
  if ((pshared != PTHREAD_PROCESS_PRIVATE) && (pshared != PTHREAD_PROCESS_SHARED))
    return EINVAL;
  if (pshared != PTHREAD_PROCESS_PRIVATE)
    return ENOSYS;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D45
type_infered: string

tool: D45: %ld


assistant: ```c
int main(void) {
  char a;
  printf("%ld\n", sizeof(char));
  printf("%ld\n", sizeof(unsigned int));
  printf("%ld\n", sizeof(short int));
  printf("%ld\n", sizeof(int));
  printf("%ld\n", sizeof(long int));
  printf("%ld\n", sizeof(unsigned long int));
  printf("%ld\n", sizeof(long long int));
  printf("%ld\n", sizeof(float));
  printf("%ld\n", sizeof(double));
  printf("%ld\n", sizeof(long double));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: %ld


assistant: ```c
int main(void) {
  char a;
  printf("%ld\n", sizeof(char));
  printf("%ld\n", sizeof(unsigned int));
  printf("%ld\n", sizeof(short int));
  printf("%ld\n", sizeof(int));
  printf("%ld\n", sizeof(long int));
  printf("%ld\n", sizeof(unsigned long int));
  printf("%ld\n", sizeof(long long int));
  printf("%ld\n", sizeof(float));
  printf("%ld\n", sizeof(double));
  printf("%ld\n", sizeof(long double));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: %ld


assistant: ```c
int main(void) {
  char a;
  printf("%ld\n", sizeof(char));
  printf("%ld\n", sizeof(unsigned int));
  printf("%ld\n", sizeof(short int));
  printf("%ld\n", sizeof(int));
  printf("%ld\n", sizeof(long int));
  printf("%ld\n", sizeof(unsigned long int));
  printf("%ld\n", sizeof(long long int));
  printf("%ld\n", sizeof(float));
  printf("%ld\n", sizeof(double));
  printf("%ld\n", sizeof(long double));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: %ld


assistant: ```c
int main(void) {
  char a;
  printf("%ld\n", sizeof(char));
  printf("%ld\n", sizeof(unsigned int));
  printf("%ld\n", sizeof(short int));
  printf("%ld\n", sizeof(int));
  printf("%ld\n", sizeof(long int));
  printf("%ld\n", sizeof(unsigned long int));
  printf("%ld\n", sizeof(long long int));
  printf("%ld\n", sizeof(float));
  printf("%ld\n", sizeof(double));
  printf("%ld\n", sizeof(long double));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <klogctl@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x3ff,%edx
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <klogctl@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x3ff,%edx
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <klogctl@plt>
  mov    $0x0,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    $0x0,%edi
  call   <klogctl@plt>
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <klogctl@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  char buf[1024];
  klogctl(0, NULL, 0);
  klogctl(3, buf, sizeof(buf) - 1);
  klogctl(-1, buf, sizeof(buf) - 1);
  klogctl(0, (char *)-1, 0);
  klogctl(0, NULL, -1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <klogctl@plt>
  mov    %rsp,%rbx
  mov    $0x3ff,%edx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <klogctl@plt>
  mov    $0x3ff,%edx
  mov    %rbx,%rsi
  mov    $0xffffffff,%edi
  call   <klogctl@plt>
  mov    $0x0,%edx
  mov    $0xffffffffffffffff,%rsi
  mov    $0x0,%edi
  call   <klogctl@plt>
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <klogctl@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x410,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[1024];
  klogctl(0, NULL, 0);
  klogctl(3, buf, sizeof(buf) - 1);
  klogctl(-1, buf, sizeof(buf) - 1);
  klogctl(0, (char *)-1, 0);
  klogctl(0, NULL, -1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <klogctl@plt>
  mov    $0x3ff,%edx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <klogctl@plt>
  mov    $0x3ff,%edx
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  call   <klogctl@plt>
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0xffffffffffffffff,%rsi
  call   <klogctl@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    $0xffffffff,%edx
  call   <klogctl@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[1024];
  klogctl(0, NULL, 0);
  klogctl(3, buf, sizeof(buf) - 1);
  klogctl(-1, buf, sizeof(buf) - 1);
  klogctl(0, (char *)-1, 0);
  klogctl(0, NULL, -1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <klogctl@plt>
  mov    $0x3ff,%edx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <klogctl@plt>
  mov    $0x3ff,%edx
  mov    %rbp,%rsi
  mov    $0xffffffff,%edi
  call   <klogctl@plt>
  xor    %edx,%edx
  xor    %edi,%edi
  mov    $0xffffffffffffffff,%rsi
  call   <klogctl@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    $0xffffffff,%edx
  call   <klogctl@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char buf[1024];
  klogctl(0, NULL, 0);
  klogctl(3, buf, sizeof(buf) - 1);
  klogctl(-1, buf, sizeof(buf) - 1);
  klogctl(0, (char *)-1, 0);
  klogctl(0, NULL, -1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L63
  cmpl   $0x3e8,-0xc(%rbp)
  jg     L63
  mov    $0x1,%eax
  jmp    L28
L63:
  mov    $0x0,%eax
L28:
  mov    %eax,%edi
  call   <__VERIFIER_assume@plt>
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L21
L66:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L66
  movl   $0x0,-0x10(%rbp)
  jmp    L36
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  addl   $0x1,-0x10(%rbp)
L36:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int n = __VERIFIER_nondet_int();
  __VERIFIER_assume(0 <= n && n <= 1000);
  int *x = malloc(n * sizeof(int));
  for (int i = 0; i < n; i++)
    x[i] = 0;
  for (int i = 0; i < n; i++)
    __VERIFIER_assert(x[i] == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  cmp    $0x3e8,%eax
  setbe  %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assume@plt>
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L13
  mov    %rax,%rbx
  lea    -0x1(%rbp),%edx
  lea    0x4(%rax,%rdx,4),%rbp
L4:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L4
L3:
  cmpl   $0x0,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assert@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L3
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int n = __VERIFIER_nondet_int();
  __VERIFIER_assume(0 <= n && n <= 1000);
  int *x = malloc(n * sizeof(int));
  for (int i = 0; i < n; i++)
    x[i] = 0;
  for (int i = 0; i < n; i++)
    __VERIFIER_assert(x[i] == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%eax
  mov    %eax,%ebp
  setbe  %dil
  call   <__VERIFIER_assume@plt>
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L5
  sub    $0x1,%ebp
  mov    %rax,%rbx
  xor    %esi,%esi
  mov    %rax,%rdi
  lea    0x4(,%rbp,4),%rdx
  lea    0x4(%rbx,%rbp,4),%rbp
  call   <memset@plt>
L18:
  mov    (%rbx),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <__VERIFIER_assert@plt>
  cmp    %rbx,%rbp
  jne    L18
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int n = __VERIFIER_nondet_int();
  __VERIFIER_assume(0 <= n && n <= 1000);
  int *x = malloc(n * sizeof(int));
  for (int i = 0; i < n; i++)
    x[i] = 0;
  for (int i = 0; i < n; i++)
    __VERIFIER_assert(x[i] == 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  xor    %edi,%edi
  cmp    $0x3e8,%eax
  mov    %eax,%ebp
  setbe  %dil
  call   <__VERIFIER_assume@plt>
  lea    0x0(,%rbp,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L9
  sub    $0x1,%ebp
  mov    %rax,%rbx
  xor    %esi,%esi
  mov    %rax,%rdi
  lea    0x4(,%rbp,4),%rdx
  lea    0x4(%rbx,%rbp,4),%rbp
  call   <memset@plt>
L6:
  mov    (%rbx),%eax
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x4,%rbx
  call   <__VERIFIER_assert@plt>
  cmp    %rbx,%rbp
  jne    L6
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  int n = __VERIFIER_nondet_int();
  __VERIFIER_assume(0 <= n && n <= 1000);
  int *x = malloc(n * sizeof(int));
  for (int i = 0; i < n; i++)
    x[i] = 0;
  for (int i = 0; i < n; i++)
    __VERIFIER_assert(x[i] == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syscon_initialize_number_of_quaddobl_Laurentials>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x233,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_initialize_number_of_quaddobl_Laurentials(int length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(563, &length, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<syscon_initialize_number_of_quaddobl_Laurentials>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x233,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_initialize_number_of_quaddobl_Laurentials(int length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(563, &length, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<syscon_initialize_number_of_quaddobl_Laurentials>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x233,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_initialize_number_of_quaddobl_Laurentials(int length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(563, &length, b, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<syscon_initialize_number_of_quaddobl_Laurentials>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x233,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_initialize_number_of_quaddobl_Laurentials(int length) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(563, &length, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__fpeek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char __fpeek(FILE *fp) {
  char c = getc(fp);
  ungetc(c, fp);
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__fpeek>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <getc@plt>
  mov    %eax,%ebx
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <ungetc@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char __fpeek(FILE *fp) {
  char c = getc(fp);
  ungetc(c, fp);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__fpeek>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rsi
  movsbl %al,%edi
  mov    %edi,%r12d
  call   <ungetc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char __fpeek(FILE *fp) {
  char c = getc(fp);
  ungetc(c, fp);
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__fpeek>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <getc@plt>
  mov    %rbp,%rsi
  movsbl %al,%edi
  mov    %edi,%r12d
  call   <ungetc@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char __fpeek(FILE *fp) {
  char c = getc(fp);
  ungetc(c, fp);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_free_cul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x2,-0x10(%rbp)
  jmp    L1
L24:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_num_from_fat@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    -0x10(%rbp),%rax
  jmp    L7
L1:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  jne    L24
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

assistant: ```c
unsigned short get_free_cul(void) {
  unsigned long i, tmpi;
  for (i = 2; i++; i < 0x600) {
    tmpi = get_num_from_fat(i);
    if (tmpi == 0)
      return i;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_free_cul>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
L1:
  mov    %rbx,%rdi
  call   <get_num_from_fat@plt>
  test   %rax,%rax
  je     L26
  add    $0x1,%rbx
  cmp    $0x1,%rbx
  jne    L1
  mov    $0xffffffff,%eax
  jmp    L8
L26:
  mov    %ebx,%eax
L8:
  pop    %rbx
  ret
```

assistant: ```c
unsigned short get_free_cul(void) {
  unsigned long i, tmpi;
  for (i = 2; i++; i < 0x600) {
    tmpi = get_num_from_fat(i);
    if (tmpi == 0)
      return i;
  }
  return -1;
}
```