ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L6
L15:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0x2e27ef92e8a,%rax
  cmp    %rax,0x10(%rsp)
  je     L0
L47:
  mov    0x10(%rsp),%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L15
L0:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  jmp    L47
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D13
datatype: string

tool: D23: %lu


tool: D6: Call this program with %i arguments


tool: D13: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3171816124042UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L9
  lea    D20(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x2e27ef92e8a,%rax
  cmp    %rax,%rsi
  je     L16
L30:
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L30
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D26
datatype: string

tool: D20: Call this program with %i arguments


tool: D18: %lu


tool: D26: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3171816124042UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L35
  lea    D8(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L35:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0x2e27ef92e8a,%rax
  cmp    %rax,%rsi
  je     L1
L34:
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L34
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string

tool: D8: Call this program with %i arguments


tool: D7: %lu


tool: D10: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 3171816124042UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffffff,%edi
  call   <something@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  something(-1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <something@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  something(-1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <something@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  something(-1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <something@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  something(-1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vmsg@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void info(const char *const restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  vmsg(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<info>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <vmsg@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void info(const char *const restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  vmsg(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: What is the c source code of the assembly code below:

```asm
<info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void info(const char *const restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  vmsg(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<info>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vmsg@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void info(const char *const restrict format, ...) {
  va_list ap;
  va_start(ap, format);
  vmsg(LOG_INFO, format, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  nop
L4:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L4
  cmpl   $0x9,-0x4(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L29
  cmpl   $0x2e,-0x4(%rbp)
  je     L29
  cmpl   $0x2d,-0x4(%rbp)
  je     L29
  mov    -0x4(%rbp),%eax
  jmp    L140
L29:
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x2d,-0x4(%rbp)
  jne    L0
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L147
  cmpl   $0x2e,-0x4(%rbp)
  je     L147
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
  mov    $0x2d,%eax
  jmp    L140
L147:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L91
  nop
L49:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L49
L91:
  cmpl   $0x2e,-0x4(%rbp)
  jne    L40
  nop
L132:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L132
L40:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L54
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ungetch@plt>
L54:
  mov    $0x30,%eax
L140:
  leave
  ret
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  i = 0;
  if (c == '-') {
    c = getch();
    if (!isdigit(c) && c != '.') {
      ungetch(c);
      return '-';
    }
    s[++i] = c;
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
L104:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %al,0x0(%rbp)
  cmp    $0x9,%eax
  je     L104
  cmp    $0x20,%al
  je     L104
  movb   $0x0,0x1(%rbp)
  movsbl %al,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L54
  lea    -0x2d(%rbx),%eax
  cmp    $0x1,%eax
  ja     L69
L54:
  mov    $0x0,%r13d
  cmp    $0x2d,%ebx
  je     L135
L114:
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L154
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L10:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L10
L154:
  cmp    $0x2e,%ebx
  je     L107
L16:
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    D9(%rip),%rax
  cmp    %ebx,(%rax)
  jne    L41
  mov    $0x30,%ebx
L69:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L135:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  movsbl %al,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r12d
  je     L146
  test   %rax,%rax
  je     L44
L146:
  mov    %r12b,0x1(%rbp)
  mov    %r12d,%ebx
  mov    $0x1,%r13d
  jmp    L114
L44:
  mov    %r12d,%edi
  call   <ungetch@plt>
  jmp    L69
L107:
  lea    0x1(%r13),%r12d
  movslq %r12d,%r12
L34:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  mov    %r12d,%r13d
  mov    %al,0x0(%rbp,%r12,1)
  movsbl %al,%edi
  call   <isdigit@plt>
  add    $0x1,%r12
  test   %rax,%rax
  jne    L34
  jmp    L16
L41:
  mov    %ebx,%edi
  call   <ungetch@plt>
  mov    $0x30,%ebx
  jmp    L69
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  i = 0;
  if (c == '-') {
    c = getch();
    if (!isdigit(c) && c != '.') {
      ungetch(c);
      return '-';
    }
    s[++i] = c;
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L33:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L33
  cmp    $0x20,%al
  je     L33
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L80
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L110
L80:
  xor    %r13d,%r13d
  cmp    $0x2d,%r12d
  je     L48
L89:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L139
  lea    0x1(%r13),%ebp
  movslq %ebp,%rbp
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %eax,%eax
  movslq %ebp,%r13
  call   <getch@plt>
  mov    %al,(%rbx,%rbp,1)
  movsbl %al,%edi
  mov    %eax,%r12d
  add    $0x1,%rbp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L55
L139:
  lea    (%rbx,%r13,1),%rbp
  cmp    $0x2e,%r12d
  je     L99
L6:
  mov    D1(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12d,(%rax)
  jne    L129
  mov    $0x30,%r12d
L110:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L129:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  call   <getch@plt>
  movsbl %al,%ebp
  mov    %eax,%r13d
  mov    %ebp,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r13d
  je     L70
  test   %rax,%rax
  je     L112
L70:
  mov    %r13b,0x1(%rbx)
  mov    %r13d,%r12d
  mov    $0x1,%r13d
  jmp    L89
  nopl   0x0(%rax)
L99:
  lea    0x1(%rbx,%r13,1),%rbx
  nopl   (%rax)
L141:
  xor    %eax,%eax
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L141
  jmp    L6
L112:
  mov    %r13d,%edi
  call   <ungetch@plt>
  jmp    L110
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  i = 0;
  if (c == '-') {
    c = getch();
    if (!isdigit(c) && c != '.') {
      ungetch(c);
      return '-';
    }
    s[++i] = c;
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L34:
  xor    %eax,%eax
  call   <getch@plt>
  mov    %al,(%rbx)
  mov    %eax,%r12d
  cmp    $0x9,%eax
  je     L34
  cmp    $0x20,%al
  je     L34
  movb   $0x0,0x1(%rbx)
  movsbl %al,%ebp
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L71
  lea    -0x2d(%r12),%eax
  cmp    $0x1,%eax
  ja     L66
L71:
  xor    %r13d,%r13d
  cmp    $0x2d,%r12d
  je     L126
L2:
  mov    %ebp,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L120
  lea    0x1(%r13),%ebp
  movslq %ebp,%rbp
  nopw   0x0(%rax,%rax,1)
L141:
  xor    %eax,%eax
  movslq %ebp,%r13
  call   <getch@plt>
  mov    %al,(%rbx,%rbp,1)
  movsbl %al,%edi
  mov    %eax,%r12d
  add    $0x1,%rbp
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L141
L120:
  lea    (%rbx,%r13,1),%rbp
  cmp    $0x2e,%r12d
  je     L27
L146:
  mov    D9(%rip),%rax
  movb   $0x0,0x0(%rbp)
  cmp    %r12d,(%rax)
  jne    L41
  mov    $0x30,%r12d
L66:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L41:
  mov    %r12d,%edi
  mov    $0x30,%r12d
  call   <ungetch@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L126:
  xor    %eax,%eax
  call   <getch@plt>
  movsbl %al,%ebp
  mov    %eax,%r13d
  mov    %ebp,%edi
  call   <isdigit@plt>
  cmp    $0x2e,%r13d
  je     L38
  test   %rax,%rax
  je     L36
L38:
  mov    %r13b,0x1(%rbx)
  mov    %r13d,%r12d
  mov    $0x1,%r13d
  jmp    L2
  nopl   0x0(%rax)
L27:
  lea    0x1(%rbx,%r13,1),%rbx
  nopl   (%rax)
L39:
  xor    %eax,%eax
  mov    %rbx,%rbp
  add    $0x1,%rbx
  call   <getch@plt>
  mov    %al,-0x1(%rbx)
  movsbl %al,%edi
  mov    %eax,%r12d
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  jmp    L146
L36:
  mov    %r13d,%edi
  call   <ungetch@plt>
  jmp    L66
```

assistant: ```c
int getop(char s[]) {
  int i, c;
  while ((s[0] = c = getch()) == ' ' || c == '\t')
    ;
  s[1] = '\0';
  if (!isdigit(c) && c != '.' && c != '-')
    return c;
  i = 0;
  if (c == '-') {
    c = getch();
    if (!isdigit(c) && c != '.') {
      ungetch(c);
      return '-';
    }
    s[++i] = c;
  }
  if (isdigit(c))
    while (isdigit(s[++i] = c = getch()))
      ;
  if (c == '.')
    while (isdigit(s[++i] = c = getch()))
      ;
  s[i] = '\0';
  if (c != EOF)
    ungetch(c);
  return '0';
}
```
user: What is the c source code of the assembly code below:

```asm
<freeA_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeA_i(int **ip, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    free(ip[i]);
  }
  free(ip);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<freeA_i>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L14:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L14
L3:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void freeA_i(int **ip, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    free(ip[i]);
  }
  free(ip);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<freeA_i>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L5
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeA_i(int **ip, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    free(ip[i]);
  }
  free(ip);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<freeA_i>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L18
L5:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeA_i(int **ip, int size) {
  int i;
  for (i = 0; i < size; ++i) {
    free(ip[i]);
  }
  free(ip);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%ebx
  jmp    L32
L27:
  movsbl %r12b,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L18
  add    $0x1,%ebx
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%r12d
  test   %r12b,%r12b
  jne    L27
  jmp    L24
L18:
  nop
L24:
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int strspn(char *string, char *control) {
  register int count = 0;
  register char ch;
  while (ch = *string) {
    if (strchr(control, ch))
      ++count;
    else
      break;
    ++string;
  }
  return count;
}
```