ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_spec_text>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <inst_2_str@plt>
  mov    (%rbx),%edi
  mov    %rax,%r13
  call   <inst_has_argu@plt>
  mov    %eax,%r12d
  test   %r13,%r13
  je     L25
  mov    %r13,%rdx
  mov    %rbx,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L12:
  test   %r12d,%r12d
  jne    L30
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L30:
  mov    0x4(%rbx),%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  call   <printf@plt>
  jmp    L18
  nopl   (%rax)
L25:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
```

tool_calls: name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D12
type: string

tool: D28: addr %p ## %s

tool: D19:  %#x(%d)

tool: D12: addr %p ## %x

assistant: ```c
int print_spec_text(int *cur_text) {
  int has_argu = 0;
  const char *inst_str = inst_2_str(*cur_text);
  has_argu = inst_has_argu(*cur_text);
  if (inst_str)
    printf("addr %p ## %s", cur_text, inst_str);
  else
    printf("addr %p ## %x", cur_text, *cur_text);
  if (has_argu) {
    ++cur_text;
    printf(" %#x(%d)", *cur_text, *cur_text);
  }
  printf("\n");
  return has_argu;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x472021676e696f47,%rax
  movabs $0x6f472021676e696f,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x656e,-0x10(%rbp)
  movb   $0x0,-0xe(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L28
L24:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edi
  call   <puts@plt>
L28:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  char *t, text[] = "Going! Going! Gone";
  t = text;
  while (*t) {
    puts(t++);
  }
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x472021676e696f47,%rax
  movabs $0x6f472021676e696f,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movw   $0x656e,0x10(%rsp)
  movb   $0x0,0x12(%rsp)
  mov    %rsp,%rbx
L17:
  mov    %ebx,%edi
  call   <puts@plt>
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L17
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char *t, text[] = "Going! Going! Gone";
  t = text;
  while (*t) {
    puts(t++);
  }
  getchar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x656e,%eax
  movb   $0x0,0x12(%rsp)
  mov    %rsp,%rbx
  mov    %ax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <puts@plt>
  cmpb   $0x0,(%rbx)
  jne    L6
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: byte[16]

tool: {"D6": [0x47,0x6f,0x69,0x6e,0x67,0x21,0x20,0x47,0x6f,0x69,0x6e,0x67,0x21,0x20,0x47,0x6f]}

assistant: ```c
int main(void) {
  char *t, text[] = "Going! Going! Gone";
  t = text;
  while (*t) {
    puts(t++);
  }
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x656e,%eax
  movb   $0x0,0x12(%rsp)
  mov    %rsp,%rbx
  mov    %ax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <puts@plt>
  cmpb   $0x0,(%rbx)
  jne    L11
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: byte[16]

tool: {"D4": [0x47,0x6f,0x69,0x6e,0x67,0x21,0x20,0x47,0x6f,0x69,0x6e,0x67,0x21,0x20,0x47,0x6f]}

assistant: ```c
int main(void) {
  char *t, text[] = "Going! Going! Gone";
  t = text;
  while (*t) {
    puts(t++);
  }
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: Hello, world!


assistant: ```c
int main(void) {
  printf("Hello, world!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: Hello, world!


assistant: ```c
int main(void) {
  printf("Hello, world!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: Hello, world!


assistant: ```c
int main(void) {
  printf("Hello, world!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: Hello, world!


assistant: ```c
int main(void) {
  printf("Hello, world!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L12
L36:
  movzbl -0x50(%rbp),%eax
  cmp    $0x30,%al
  jne    L15
  movzbl -0x4f(%rbp),%eax
  cmp    $0x78,%al
  jne    L15
  lea    -0x54(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  lea    D47(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L15:
  lea    -0x54(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x50(%rbp),%eax
  cmp    $0x2d,%al
  jne    L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D47
type_guessed: string
name: disassemble_data
arguments: data_tag: D17
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D13
type_guessed: string

tool: D47: %x

tool: D17: %d


tool: D26: %d

tool: D21: 0x%X


tool: D13: %s


assistant: ```c
int main(void) {
  char numero[64];
  int valor;
  while (scanf("%s\n", numero), numero[0] != '-') {
    if (numero[0] == '0' && numero[1] == 'x') {
      sscanf(numero, "%x", &valor);
      printf("%d\n", valor);
    } else {
      sscanf(numero, "%d", &valor);
      printf("0x%X\n", valor);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rbx
  lea    D31(%rip),%r12
  lea    D43(%rip),%rbp
  lea    D42(%rip),%r13
  jmp    L40
L52:
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %r12,%rsi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L40:
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  cmp    $0x2d,%al
  je     L55
  cmp    $0x30,%al
  jne    L52
  cmpb   $0x78,0x11(%rsp)
  jne    L52
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %r13,%rsi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L55:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D38
type: string
name: retrieve_data
arguments: label: D31
type: string
name: retrieve_data
arguments: label: D43
type: string
name: retrieve_data
arguments: label: D42
type: string
name: retrieve_data
arguments: label: D36
type: string

tool: D38: %s


tool: D31: %d

tool: D43: 0x%X


tool: D42: %x

tool: D36: %d


assistant: ```c
int main(void) {
  char numero[64];
  int valor;
  while (scanf("%s\n", numero), numero[0] != '-') {
    if (numero[0] == '0' && numero[1] == 'x') {
      sscanf(numero, "%x", &valor);
      printf("%d\n", valor);
    } else {
      sscanf(numero, "%d", &valor);
      printf("0x%X\n", valor);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D39(%rip),%r15
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  cmp    $0x2d,%al
  je     L7
  lea    0xc(%rsp),%rdx
  cmp    $0x30,%al
  jne    L24
  cmpb   $0x78,0x11(%rsp)
  je     L8
L24:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L5
  nopl   (%rax)
L7:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L8:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L5
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D20
data_type: string
name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D35
data_type: string
name: parse_data
arguments: label: D6
data_type: string

tool: D39: %x

tool: D20: %d


tool: D13: %d

tool: D35: 0x%X


tool: D6: %s


assistant: ```c
int main(void) {
  char numero[64];
  int valor;
  while (scanf("%s\n", numero), numero[0] != '-') {
    if (numero[0] == '0' && numero[1] == 'x') {
      sscanf(numero, "%x", &valor);
      printf("%d\n", valor);
    } else {
      sscanf(numero, "%d", &valor);
      printf("0x%X\n", valor);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  lea    D30(%rip),%rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L49:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  cmp    $0x2d,%al
  je     L56
  lea    0xc(%rsp),%rdx
  cmp    $0x30,%al
  jne    L45
  cmpb   $0x78,0x11(%rsp)
  je     L21
L45:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L49
  nopl   (%rax)
L56:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L49
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: tag: D45
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D30
type_guessed: string

tool: D13: %x

tool: D21: %d


tool: D45: %d

tool: D11: 0x%X


tool: D30: %s


assistant: ```c
int main(void) {
  char numero[64];
  int valor;
  while (scanf("%s\n", numero), numero[0] != '-') {
    if (numero[0] == '0' && numero[1] == 'x') {
      sscanf(numero, "%x", &valor);
      printf("%d\n", valor);
    } else {
      sscanf(numero, "%d", &valor);
      printf("0x%X\n", valor);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pubnub_uname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
data_type: string

tool: D7: OpenSSL%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "OpenSSL"
         "%2F"
         "2.1-alpha";
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pubnub_uname>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: OpenSSL%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "OpenSSL"
         "%2F"
         "2.1-alpha";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pubnub_uname>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: OpenSSL%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "OpenSSL"
         "%2F"
         "2.1-alpha";
}
```
user: What is the c source code of the assembly code below:

```asm
<pubnub_uname>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: OpenSSL%2F2.1-alpha

assistant: ```c
char const *pubnub_uname(void) {
  return "OpenSSL"
         "%2F"
         "2.1-alpha";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L16
L15:
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x18(%rbp)
L16:
  cmpl   $0x0,-0x18(%rbp)
  jne    L15
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Add(int x, int y) {
  while (y != 0) {
    int carry = x & y;
    x = x ^ y;
    y = carry << 1;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L14
L3:
  mov    %eax,%edx
  and    %esi,%edx
  xor    %esi,%eax
  mov    %edx,%esi
  add    %esi,%esi
  jne    L3
L14:
  ret
```

assistant: ```c
int Add(int x, int y) {
  while (y != 0) {
    int carry = x & y;
    x = x ^ y;
    y = carry << 1;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L6
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %esi,%edx
  mov    %edx,%esi
  add    %esi,%esi
  jne    L18
L6:
  ret
```

assistant: ```c
int Add(int x, int y) {
  while (y != 0) {
    int carry = x & y;
    x = x ^ y;
    y = carry << 1;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Add>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L15
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %eax,%edx
  xor    %esi,%eax
  and    %esi,%edx
  mov    %edx,%esi
  add    %esi,%esi
  jne    L0
L15:
  ret
```

assistant: ```c
int Add(int x, int y) {
  while (y != 0) {
    int carry = x & y;
    x = x ^ y;
    y = carry << 1;
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pregame_refresh>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <io_clearscreen@plt>
  mov    $0x1c,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <io_printborder@plt>
  cmp    $0x1,%r14d
  sbb    %ecx,%ecx
  and    $0xa,%ecx
  add    $0x20,%ecx
  movsbl 0x1c(%r13),%edx
  mov    %rsp,%rbx
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rcx
  mov    $0x1c,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <io_printtext@plt>
  mov    %eax,%ebp
  mov    0x1c(%r13),%eax
  test   %eax,%eax
  jle    L27
  mov    $0x1,%ebx
  lea    D41(%rip),%r15
L0:
  cmp    %ebx,%r14d
  mov    $0x20,%r8d
  mov    $0x2a,%eax
  cmove  %eax,%r8d
  cmpl   $0x1,-0x4(%r13,%rbx,4)
  lea    D45(%rip),%rcx
  cmove  %r15,%rcx
  movsbl %bl,%edx
  mov    %rsp,%r12
  lea    D40(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r12,%rcx
  mov    $0x1c,%edx
  mov    %ebp,%esi
  mov    $0x0,%edi
  call   <io_printtext@plt>
  mov    %eax,%ebp
  mov    0x1c(%r13),%eax
  add    $0x1,%rbx
  lea    -0x1(%rbx),%edx
  cmp    %edx,%eax
  jg     L0
L27:
  add    $0x1,%eax
  cmp    %r14d,%eax
  mov    $0x2a,%edx
  mov    $0x20,%eax
  cmovne %eax,%edx
  mov    %rsp,%rbx
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rcx
  mov    $0x1c,%edx
  mov    %ebp,%esi
  mov    $0x0,%edi
  call   <io_printtext@plt>
  mov    %eax,%esi
  mov    $0x1c,%edx
  mov    $0x0,%edi
  call   <io_printborder@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D41
type_guessed: string
name: retrieve_data
arguments: data_tag: D45
type_guessed: string
name: retrieve_data
arguments: data_tag: D40
type_guessed: string
name: retrieve_data
arguments: data_tag: D47
type_guessed: string

tool: D24: Number of players: %d  %c

tool: D41: ai   

tool: D45: human

tool: D40: Player %d is: %s    %c

tool: D47: Play                  %c

assistant: ```c
void pregame_refresh(int *data, int cursor) {
  io_clearscreen();
  int y = 0;
  int width = 28;
  io_printborder(0, y++, width);
  char s[40];
  sprintf(s, "Number of players: %d  %c", data[7], (cursor == 0) ? '*' : ' ');
  y = io_printtext(0, y, width, s);
  int i;
  for (i = 0; i < data[7]; i++) {
    sprintf(s, "Player %d is: %s    %c", i + 1, (data[i] == 1) ? "ai   " : "human", (cursor == i + 1) ? '*' : ' ');
    y = io_printtext(0, y, width, s);
  }
  sprintf(s, "Play                  %c", (cursor == data[7] + 1) ? '*' : ' ');
  y = io_printtext(0, y, width, s);
  io_printborder(0, y++, width);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pregame_refresh>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <io_clearscreen@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    $0x1c,%edx
  call   <io_printborder@plt>
  cmp    $0x1,%ebp
  movsbl 0x1c(%rbx),%edx
  mov    %r13,%rdi
  sbb    %ecx,%ecx
  lea    D27(%rip),%rsi
  xor    %eax,%eax
  and    $0xa,%ecx
  add    $0x20,%ecx
  call   <sprintf@plt>
  mov    %r13,%rcx
  mov    $0x1c,%edx
  xor    %edi,%edi
  mov    $0x1,%esi
  call   <io_printtext@plt>
  mov    %eax,%r12d
  mov    0x1c(%rbx),%eax
  test   %eax,%eax
  jle    L2
  mov    $0x1,%r14d
  lea    D15(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L5:
  cmp    %r14d,%ebp
  mov    $0x2a,%eax
  movsbl %r14b,%edx
  mov    %r15,%rsi
  mov    $0x20,%r8d
  lea    D48(%rip),%rcx
  mov    %r13,%rdi
  cmove  %eax,%r8d
  cmpl   $0x1,-0x4(%rbx,%r14,4)
  lea    D20(%rip),%rax
  cmove  %rax,%rcx
  xor    %eax,%eax
  add    $0x1,%r14
  call   <sprintf@plt>
  mov    $0x1c,%edx
  mov    %r12d,%esi
  mov    %r13,%rcx
  xor    %edi,%edi
  call   <io_printtext@plt>
  lea    -0x1(%r14),%edx
  mov    %eax,%r12d
  mov    0x1c(%rbx),%eax
  cmp    %edx,%eax
  jg     L5
L2:
  add    $0x1,%eax
  mov    $0x2a,%edx
  lea    D39(%rip),%rsi
  mov    %r13,%rdi
  cmp    %ebp,%eax
  mov    $0x20,%eax
  cmovne %eax,%edx
  xor    %eax,%eax
  call   <sprintf@plt>
  xor    %edi,%edi
  mov    $0x1c,%edx
  mov    %r12d,%esi
  mov    %r13,%rcx
  call   <io_printtext@plt>
  xor    %edi,%edi
  mov    $0x1c,%edx
  mov    %eax,%esi
  call   <io_printborder@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D48
type_infered: string
name: retrieve_data
arguments: data_tag: D20
type_infered: string
name: retrieve_data
arguments: data_tag: D39
type_infered: string

tool: D27: Number of players: %d  %c

tool: D15: Player %d is: %s    %c

tool: D48: human

tool: D20: ai   

tool: D39: Play                  %c

assistant: ```c
void pregame_refresh(int *data, int cursor) {
  io_clearscreen();
  int y = 0;
  int width = 28;
  io_printborder(0, y++, width);
  char s[40];
  sprintf(s, "Number of players: %d  %c", data[7], (cursor == 0) ? '*' : ' ');
  y = io_printtext(0, y, width, s);
  int i;
  for (i = 0; i < data[7]; i++) {
    sprintf(s, "Player %d is: %s    %c", i + 1, (data[i] == 1) ? "ai   " : "human", (cursor == i + 1) ? '*' : ' ');
    y = io_printtext(0, y, width, s);
  }
  sprintf(s, "Play                  %c", (cursor == data[7] + 1) ? '*' : ' ');
  y = io_printtext(0, y, width, s);
  io_printborder(0, y++, width);
}
```