ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_print_words_tables>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L16:
  call   <ft_putstr@plt>
  add    $0x8,%rbx
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L16
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void ft_print_words_tables(char **tab) {
  int it;
  it = 0;
  while (tab[it]) {
    ft_putstr(tab[it++]);
    ft_putchar('\n');
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_print_words_tables>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L0:
  call   <ft_putstr@plt>
  add    $0x8,%rbx
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L0
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void ft_print_words_tables(char **tab) {
  int it;
  it = 0;
  while (tab[it]) {
    ft_putstr(tab[it++]);
    ft_putchar('\n');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%r9
  movzwl (%rdi),%eax
  add    $0x7296,%ax
  movzwl 0x2(%rdi),%r8d
  test   %r8w,%r8w
  je     L24
  mov    $0x0,%edx
  mov    $0x10,%r10d
  jmp    L29
L20:
  lea    0x0(,%rax,4),%ecx
  and    $0x3c,%ecx
  or     %ecx,%eax
  movzwl %ax,%r11d
  mov    %eax,%edi
  shr    $0x3,%di
  and    $0xe,%edi
  or     $0x1,%edi
  mov    %r10d,%ecx
  sub    %edi,%ecx
  mov    %r11d,%esi
  sar    %cl,%esi
  mov    %edi,%ecx
  shl    %cl,%r11d
  or     %r11d,%esi
  shl    $0x4,%esi
  and    $0x1f0,%si
  or     %esi,%eax
L12:
  add    $0x1,%edx
  cmp    %r8w,%dx
  je     L24
L29:
  cmp    %dx,%ax
  jbe    L20
  mov    %eax,%ecx
  shl    $0x4,%ecx
  and    $0x30,%ecx
  add    %eax,%eax
  or     %ecx,%eax
  jmp    L12
L24:
  add    $0x54,%eax
  mov    %ax,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        } else {
          state[local1] += state[local1];
          state[local1] |= ((state[local1] + state[0UL]) & (unsigned short)15) << 2UL;
        }
      } else if (state[0UL] <= local1) {
        state[local1] |= (state[0UL] & (unsigned short)15) << 2UL;
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
      } else {
        state[0UL] |= ((state[local1] ^ state[0UL]) & (unsigned short)31) << 3UL;
        state[local1] |= (state[local1] & (unsigned short)15) << 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned short)84;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%r8d
  mov    %rsi,%r9
  add    $0x7296,%ax
  test   %r8w,%r8w
  je     L39
  xor    %edx,%edx
  mov    $0x10,%r10d
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %eax,%ecx
  add    $0x1,%edx
  add    %eax,%eax
  shl    $0x4,%ecx
  and    $0x30,%ecx
  or     %ecx,%eax
  cmp    %r8w,%dx
  je     L39
L41:
  cmp    %ax,%dx
  jb     L37
  lea    0x0(,%rax,4),%ecx
  add    $0x1,%edx
  and    $0x3c,%ecx
  or     %ecx,%eax
  mov    %r10d,%ecx
  mov    %eax,%edi
  movzwl %ax,%r11d
  shr    $0x3,%di
  mov    %r11d,%esi
  and    $0xe,%edi
  or     $0x1,%edi
  sub    %edi,%ecx
  sar    %cl,%esi
  mov    %edi,%ecx
  shl    %cl,%r11d
  or     %r11d,%esi
  shl    $0x4,%esi
  and    $0x1f0,%si
  or     %esi,%eax
  cmp    %r8w,%dx
  jne    L41
L39:
  add    $0x54,%eax
  mov    %ax,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        } else {
          state[local1] += state[local1];
          state[local1] |= ((state[local1] + state[0UL]) & (unsigned short)15) << 2UL;
        }
      } else if (state[0UL] <= local1) {
        state[local1] |= (state[0UL] & (unsigned short)15) << 2UL;
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
      } else {
        state[0UL] |= ((state[local1] ^ state[0UL]) & (unsigned short)31) << 3UL;
        state[local1] |= (state[local1] & (unsigned short)15) << 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned short)84;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%r8d
  mov    %rsi,%r9
  add    $0x7296,%ax
  test   %r8w,%r8w
  je     L3
  xor    %edx,%edx
  mov    $0x10,%r10d
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %eax,%ecx
  add    $0x1,%edx
  add    %eax,%eax
  shl    $0x4,%ecx
  and    $0x30,%ecx
  or     %ecx,%eax
  cmp    %dx,%r8w
  je     L3
L37:
  cmp    %dx,%ax
  ja     L23
  lea    0x0(,%rax,4),%ecx
  add    $0x1,%edx
  and    $0x3c,%ecx
  or     %ecx,%eax
  mov    %r10d,%ecx
  mov    %eax,%edi
  movzwl %ax,%r11d
  shr    $0x3,%di
  mov    %r11d,%esi
  and    $0xe,%edi
  or     $0x1,%edi
  sub    %edi,%ecx
  sar    %cl,%esi
  mov    %edi,%ecx
  shl    %cl,%r11d
  or     %r11d,%esi
  shl    $0x4,%esi
  and    $0x1f0,%si
  or     %esi,%eax
  cmp    %dx,%r8w
  jne    L37
L3:
  add    $0x54,%eax
  mov    %ax,(%r9)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned short)47038;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] <= local1) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
          copy12 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy12;
        } else {
          state[local1] += state[local1];
          state[local1] |= ((state[local1] + state[0UL]) & (unsigned short)15) << 2UL;
        }
      } else if (state[0UL] <= local1) {
        state[local1] |= (state[0UL] & (unsigned short)15) << 2UL;
        state[0UL] |= (((state[0UL] << (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)) | (state[0UL] >> (16 - (((state[0UL] >> (unsigned short)3) & (unsigned short)15) | 1UL)))) & (unsigned short)31) << 4UL;
      } else {
        state[0UL] |= ((state[local1] ^ state[0UL]) & (unsigned short)31) << 3UL;
        state[local1] |= (state[local1] & (unsigned short)15) << 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (unsigned short)84;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stack_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x10000,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L8
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L8:
  mov    -0x10(%rbp),%rax
  add    $0x10000,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: 
Error allocating stack memory


assistant: ```c
void *stack_new() {
  void *stack = malloc(65536);
  if (stack == NULL) {
    perror("\nError allocating stack memory\n");
    exit(1);
  }
  void *stack_top = stack + 65536;
  return stack_top;
}
```
user: What is the c source code of the assembly code below:

```asm
<stack_new>:
  endbr64
  push   %rbx
  mov    $0x10000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L9:
  lea    0x10000(%rbx),%rax
  pop    %rbx
  ret
L10:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: 
Error allocating stack memory


assistant: ```c
void *stack_new() {
  void *stack = malloc(65536);
  if (stack == NULL) {
    perror("\nError allocating stack memory\n");
    exit(1);
  }
  void *stack_top = stack + 65536;
  return stack_top;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stack_new>:
  endbr64
  push   %rbx
  mov    $0x10000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  lea    0x10000(%rbx),%rax
  pop    %rbx
  ret
L8:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  lea    0x10000(%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: 
Error allocating stack memory


assistant: ```c
void *stack_new() {
  void *stack = malloc(65536);
  if (stack == NULL) {
    perror("\nError allocating stack memory\n");
    exit(1);
  }
  void *stack_top = stack + 65536;
  return stack_top;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stack_new>:
  endbr64
  push   %rbx
  mov    $0x10000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  lea    0x10000(%rbx),%rax
  pop    %rbx
  ret
L8:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  lea    0x10000(%rbx),%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: 
Error allocating stack memory


assistant: ```c
void *stack_new() {
  void *stack = malloc(65536);
  if (stack == NULL) {
    perror("\nError allocating stack memory\n");
    exit(1);
  }
  void *stack_top = stack + 65536;
  return stack_top;
}
```
user: Translate the below assembly code into C programming language:

```asm
<quickmedian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L29
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L15
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L2
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <quickmedian>
  jmp    L15
L2:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <quickmedian>
L15:
  leave
  ret
```

assistant: ```c
int quickmedian(int *arr, int left, int right, int med) {
  int part;
  part = partition(arr, left, right);
  if (part == med)
    return (arr[part]);
  else if (part < med)
    return (quickmedian(arr, part + 1, right, med));
  else
    return (quickmedian(arr, left, part - 1, med));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quickmedian>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%ebx
  call   <partition@plt>
  cmp    %ebx,%eax
  je     L31
  jge    L26
  lea    0x1(%rax),%esi
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quickmedian>
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  movslq %ebx,%rbx
  mov    0x0(%rbp,%rbx,4),%eax
  jmp    L30
L26:
  lea    -0x1(%rax),%edx
  mov    %ebx,%ecx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quickmedian>
  jmp    L30
```

assistant: ```c
int quickmedian(int *arr, int left, int right, int med) {
  int part;
  part = partition(arr, left, right);
  if (part == med)
    return (arr[part]);
  else if (part < med)
    return (quickmedian(arr, part + 1, right, med));
  else
    return (quickmedian(arr, left, part - 1, med));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickmedian>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L35
  jge    L25
  lea    0x1(%rax),%ebp
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L25:
  lea    -0x1(%rax),%ebx
  jmp    L38
  nopl   (%rax)
L35:
  mov    (%r12,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int quickmedian(int *arr, int left, int right, int med) {
  int part;
  part = partition(arr, left, right);
  if (part == med)
    return (arr[part]);
  else if (part < med)
    return (quickmedian(arr, part + 1, right, med));
  else
    return (quickmedian(arr, left, part - 1, med));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickmedian>:
  endbr64
  push   %r13
  movslq %ecx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <partition@plt>
  cmp    %r13d,%eax
  je     L4
  jge    L35
  lea    0x1(%rax),%ebp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L35:
  lea    -0x1(%rax),%ebx
  jmp    L1
  nopl   (%rax)
L4:
  mov    (%r12,%r13,4),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int quickmedian(int *arr, int left, int right, int med) {
  int part;
  part = partition(arr, left, right);
  if (part == med)
    return (arr[part]);
  else if (part < med)
    return (quickmedian(arr, part + 1, right, med));
  else
    return (quickmedian(arr, left, part - 1, med));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main() {
  int a;
  ({
    float __dummy;
    typeof(a) __dummy2;
    (void)(&__dummy == &__dummy2);
    1;
  });
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  ({
    float __dummy;
    typeof(a) __dummy2;
    (void)(&__dummy == &__dummy2);
    1;
  });
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  ({
    float __dummy;
    typeof(a) __dummy2;
    (void)(&__dummy == &__dummy2);
    1;
  });
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  ({
    float __dummy;
    typeof(a) __dummy2;
    (void)(&__dummy == &__dummy2);
    1;
  });
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<readvarinum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L18
  andq   $0x7f,-0x8(%rbp)
L13:
  mov    $0x0,%eax
  call   <egetc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  and    $0x7f,%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L13
L18:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long readvarinum(void) {
  long value;
  int c;
  c = egetc();
  value = c;
  if (c & 0x80) {
    value &= 0x7f;
    do {
      c = egetc();
      value = (value << 7) + (c & 0x7f);
    } while (c & 0x80);
  }
  return (value);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<readvarinum>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <egetc@plt>
  movslq %eax,%rbx
  test   $0x80,%al
  je     L13
  mov    %eax,%ebx
  and    $0x7f,%ebx
L6:
  mov    $0x0,%eax
  call   <egetc@plt>
  shl    $0x7,%rbx
  mov    %eax,%edx
  and    $0x7f,%edx
  add    %rdx,%rbx
  test   $0x80,%al
  jne    L6
L13:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long readvarinum(void) {
  long value;
  int c;
  c = egetc();
  value = c;
  if (c & 0x80) {
    value &= 0x7f;
    do {
      c = egetc();
      value = (value << 7) + (c & 0x7f);
    } while (c & 0x80);
  }
  return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readvarinum>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <egetc@plt>
  movslq %eax,%r12
  test   $0x80,%al
  je     L16
  mov    %eax,%r12d
  and    $0x7f,%r12d
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  shl    $0x7,%r12
  call   <egetc@plt>
  mov    %eax,%edx
  and    $0x7f,%edx
  add    %rdx,%r12
  test   $0x80,%al
  jne    L13
L16:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long readvarinum(void) {
  long value;
  int c;
  c = egetc();
  value = c;
  if (c & 0x80) {
    value &= 0x7f;
    do {
      c = egetc();
      value = (value << 7) + (c & 0x7f);
    } while (c & 0x80);
  }
  return (value);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readvarinum>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <egetc@plt>
  movslq %eax,%r12
  test   $0x80,%al
  je     L2
  mov    %eax,%r12d
  and    $0x7f,%r12d
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  shl    $0x7,%r12
  call   <egetc@plt>
  mov    %eax,%edx
  and    $0x7f,%edx
  add    %rdx,%r12
  test   $0x80,%al
  jne    L19
L2:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long readvarinum(void) {
  long value;
  int c;
  c = egetc();
  value = c;
  if (c & 0x80) {
    value &= 0x7f;
    do {
      c = egetc();
      value = (value << 7) + (c & 0x7f);
    } while (c & 0x80);
  }
  return (value);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fp_exp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%r14d
  mov    %edx,%r12d
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D10(%rip),%xmm0
  addsd  D3(%rip),%xmm0
  movq   %xmm0,%rbp
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpf_init2@plt>
  movq   %rbp,%xmm0
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpf_init2@plt>
  mov    %r14d,%esi
  mov    %ebx,%edi
  call   <mpf_set@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <mpf_floor@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpf_sub@plt>
  mov    %ebp,%edi
  call   <mpf_get_si@plt>
  mov    %rax,%rbp
  movsd  D6(%rip),%xmm0
  mov    %ebx,%edi
  call   <mpf_cmp_d@plt>
  test   %rax,%rax
  jg     L45
L55:
  mov    %r12d,%edx
  mov    $0x0,%ebx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <fp_exp_helper@plt>
  test   %rbp,%rbp
  jne    L6
L48:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpf_clear@plt>
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpf_clear@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <mpf_sub_ui@plt>
  add    $0x1,%rbp
  jmp    L55
L6:
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <fp_e@plt>
  test   %rbp,%rbp
  jle    L32
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpf_pow_ui@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpf_mul@plt>
  jmp    L48
L32:
  mov    %rbp,%rdx
  neg    %rdx
  mov    $0x0,%ebx
  mov    %ebx,%esi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpf_pow_ui@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r13d,%edi
  call   <mpf_div@plt>
  jmp    L48
```

tool_calls: name: disassemble_data
arguments: label: D10
type_infered: f64
name: disassemble_data
arguments: label: D3
type_infered: byte[8]
name: disassemble_data
arguments: label: D6
type_infered: f64

tool: D10: 3.3219281

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x49,0x40]}

tool: D6: 0.5

assistant: ```c
void fp_exp(mpf_t ex, const mpf_t z, unsigned int prec) {
  mp_bitcnt_t bits = ((double)prec) * 3.3219281 + 50;
  mpf_t zee, zf;
  mpf_init2(zee, bits);
  mpf_init2(zf, bits);
  mpf_set(zee, z);
  mpf_floor(zf, zee);
  mpf_sub(zee, zee, zf);
  long intpart = mpf_get_si(zf);
  if (mpf_cmp_d(zee, 0.5) > 0) {
    mpf_sub_ui(zee, zee, 1);
    intpart++;
  }
  fp_exp_helper(ex, zee, prec);
  if (intpart) {
    fp_e(zee, prec);
    if (0 < intpart) {
      mpf_pow_ui(zf, zee, intpart);
      mpf_mul(ex, ex, zf);
    } else {
      mpf_pow_ui(zf, zee, -intpart);
      mpf_div(ex, ex, zf);
    }
  }
  mpf_clear(zee);
  mpf_clear(zf);
}
```