ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_cmdline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <count_arguments@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L13
  lea    0x8(%r12),%rbx
  lea    D5(%rip),%rbp
L2:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  test   %rax,%rax
  jne    L2
L13:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5:  


assistant: ```c
char **parse_cmdline(const char *cmdline) {
  int arguments_count = count_arguments(cmdline);
  char **parsed_cmd = (char **)malloc(sizeof(char **) * arguments_count);
  char *cmdlinee = (char *)cmdline;
  parsed_cmd[0] = strtok(cmdlinee, " \n");
  int i = 1;
  while (parsed_cmd[i - 1] != NULL) {
    parsed_cmd[i] = (char *)malloc(sizeof(char *));
    parsed_cmd[i] = strtok(NULL, " \n");
    i++;
  }
  return parsed_cmd;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_cmdline>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <count_arguments@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L11
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L5:
  mov    $0x8,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  mov    %rax,-0x8(%rbx)
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L5
L11:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string

tool: D4:  


assistant: ```c
char **parse_cmdline(const char *cmdline) {
  int arguments_count = count_arguments(cmdline);
  char **parsed_cmd = (char **)malloc(sizeof(char **) * arguments_count);
  char *cmdlinee = (char *)cmdline;
  parsed_cmd[0] = strtok(cmdlinee, " \n");
  int i = 1;
  while (parsed_cmd[i - 1] != NULL) {
    parsed_cmd[i] = (char *)malloc(sizeof(char *));
    parsed_cmd[i] = strtok(NULL, " \n");
    i++;
  }
  return parsed_cmd;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_cmdline>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <count_arguments@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <strtok@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L1
  lea    0x8(%r12),%rbx
  nopl   (%rax)
L13:
  mov    $0x8,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rbp,%rsi
  xor    %edi,%edi
  mov    %rax,-0x8(%rbx)
  call   <strtok@plt>
  mov    %rax,-0x8(%rbx)
  test   %rax,%rax
  jne    L13
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6:  


assistant: ```c
char **parse_cmdline(const char *cmdline) {
  int arguments_count = count_arguments(cmdline);
  char **parsed_cmd = (char **)malloc(sizeof(char **) * arguments_count);
  char *cmdlinee = (char *)cmdline;
  parsed_cmd[0] = strtok(cmdlinee, " \n");
  int i = 1;
  while (parsed_cmd[i - 1] != NULL) {
    parsed_cmd[i] = (char *)malloc(sizeof(char *));
    parsed_cmd[i] = strtok(NULL, " \n");
    i++;
  }
  return parsed_cmd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <func@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a[4] = {0};
  func(a, 3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rdi
  mov    $0x3,%esi
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a[4] = {0};
  func(a, 3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a[4] = {0};
  func(a, 3);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x3,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <func@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a[4] = {0};
  func(a, 3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<M41_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D0
type: string

tool: D1: M41_f(const char *s) is not yet implemented!


tool: D0: %s


assistant: ```c
int M41_f(char *s) {
  debug("M41_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<M41_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string
name: parse_data
arguments: data_label: D17
type: string

tool: D9: M41_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M41_f(char *s) {
  debug("M41_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<M41_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D9: M41_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M41_f(char *s) {
  debug("M41_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<M41_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D11
type: string

tool: D2: M41_f(const char *s) is not yet implemented!


tool: D11: %s


assistant: ```c
int M41_f(char *s) {
  debug("M41_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vflip1_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L33
L18:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L17:
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L17
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vflip1_matrix(float **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  float t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vflip1_matrix>:
  endbr64
  movslq %esi,%rax
  cmp    %rax,%rdx
  jl     L27
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %r8,%rbx
  mov    %edx,%r10d
  lea    (%rdi,%rax,8),%rsi
  lea    0x8(%rdi,%rdx,8),%r12
  movslq %ecx,%rbp
  shl    $0x2,%rbp
  lea    0x4(,%r8,4),%r9
  movslq %ecx,%r8
L32:
  cmp    %r8,%rbx
  jl     L26
  movslq %r10d,%rax
  lea    (%r11,%rax,8),%rdi
  mov    %rbp,%rax
L4:
  mov    %rax,%rdx
  add    (%rdi),%rdx
  movss  (%rdx),%xmm0
  mov    (%rsi),%rcx
  movss  (%rcx,%rax,1),%xmm1
  movss  %xmm1,(%rdx)
  mov    (%rsi),%rdx
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L4
L26:
  add    $0x8,%rsi
  sub    $0x1,%r10d
  cmp    %r12,%rsi
  jne    L32
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  ret
```

assistant: ```c
void vflip1_matrix(float **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  float t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<vflip1_matrix>:
  endbr64
  mov    %rdi,%r9
  movslq %esi,%rdi
  lea    (%rsi,%rdx,1),%r11d
  cmp    %rdi,%rdx
  jl     L27
  push   %rbp
  mov    %rdx,%r10
  lea    0x4(,%r8,4),%rsi
  push   %rbx
  movslq %ecx,%rbx
  lea    0x0(,%rbx,4),%rbp
  nopl   0x0(%rax,%rax,1)
L21:
  cmp    %rbx,%r8
  jl     L41
  mov    %r11d,%eax
  mov    (%r9,%rdi,8),%rdx
  sub    %edi,%eax
  cltq
  mov    (%r9,%rax,8),%rcx
  mov    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L8:
  movss  (%rcx,%rax,1),%xmm0
  movss  (%rdx,%rax,1),%xmm1
  movss  %xmm1,(%rcx,%rax,1)
  movss  %xmm0,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L8
L41:
  lea    0x1(%rdi),%rax
  cmp    %rdi,%r10
  je     L32
  mov    %rax,%rdi
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  pop    %rbp
  ret
L27:
  ret
```

assistant: ```c
void vflip1_matrix(float **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  float t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vflip1_matrix>:
  endbr64
  push   %r15
  mov    %rcx,%rax
  lea    (%rsi,%rdx,1),%ecx
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8,-0x28(%rsp)
  cmp    %rsi,%rdx
  jl     L15
  movslq %eax,%r11
  mov    %eax,-0xc(%rsp)
  mov    %r8,%r15
  cmp    %r11,%r8
  jl     L15
  sub    %r11,%r15
  mov    %rdi,%rbp
  movslq %ecx,%rcx
  lea    0x1(%r15),%r14
  lea    0x8(%rbp,%rdx,8),%rbx
  mov    %r14,%rdx
  mov    %rbx,-0x30(%rsp)
  lea    0x0(,%rcx,8),%rbx
  lea    (%rdi,%rsi,8),%rdi
  and    $0xfffffffffffffffc,%rdx
  mov    %rbx,-0x38(%rsp)
  lea    0x0(,%r11,4),%rbx
  mov    %r8,%rsi
  add    %edx,%eax
  mov    %r14,%r8
  mov    %rdx,-0x20(%rsp)
  lea    0x10(,%r11,4),%r12
  mov    %eax,-0x10(%rsp)
  shr    $0x2,%r8
  lea    0x4(,%rsi,4),%r13
  mov    %rbx,-0x18(%rsp)
  shl    $0x4,%r8
  nopl   (%rax)
L102:
  mov    -0x38(%rsp),%rax
  mov    (%rdi),%rsi
  sub    %rdi,%rax
  lea    (%rsi,%r12,1),%r9
  lea    (%rsi,%rbx,1),%rcx
  mov    (%rax,%rbp,2),%rdx
  lea    (%rdx,%rbx,1),%rax
  cmp    %r9,%rax
  lea    (%rdx,%r12,1),%r9
  setae  %r10b
  cmp    %r9,%rcx
  setae  %r9b
  or     %r10b,%r9b
  je     L27
  cmp    %r11,-0x28(%rsp)
  je     L27
  cmp    $0x2,%r15
  jbe    L25
  xor    %r9d,%r9d
  xchg   %ax,%ax
L61:
  movups (%rax,%r9,1),%xmm0
  movups (%rcx,%r9,1),%xmm2
  movups %xmm2,(%rax,%r9,1)
  movups %xmm0,(%rcx,%r9,1)
  add    $0x10,%r9
  cmp    %r8,%r9
  jne    L61
  mov    -0x20(%rsp),%rax
  cmp    %rax,%r14
  je     L121
  mov    %rax,%rcx
  mov    -0x10(%rsp),%eax
L2:
  mov    %r14,%r10
  sub    %rcx,%r10
  cmp    %rcx,%r15
  je     L111
  add    %r11,%rcx
  shl    $0x2,%rcx
  lea    (%rdx,%rcx,1),%r9
  add    %rsi,%rcx
  movq   (%rcx),%xmm1
  movq   (%r9),%xmm0
  movlps %xmm1,(%r9)
  movlps %xmm0,(%rcx)
  mov    %r10,%rcx
  and    $0xfffffffffffffffe,%rcx
  add    %ecx,%eax
  cmp    %rcx,%r10
  je     L121
L111:
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  add    %rsi,%rax
  movss  (%rdx),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rdx)
  movss  %xmm0,(%rax)
L121:
  add    $0x8,%rdi
  cmp    -0x30(%rsp),%rdi
  jne    L102
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    -0x18(%rsp),%rax
  nopl   (%rax)
L36:
  movss  (%rdx,%rax,1),%xmm0
  movss  (%rsi,%rax,1),%xmm1
  movss  %xmm1,(%rdx,%rax,1)
  movss  %xmm0,(%rsi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r13
  jne    L36
  jmp    L121
L25:
  mov    -0xc(%rsp),%eax
  xor    %ecx,%ecx
  jmp    L2
```

assistant: ```c
void vflip1_matrix(float **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  float t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[n - i][j];
      S[n - i][j] = S[i][j];
      S[i][j] = t;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1d4(%rbp)
  jmp    L5
L67:
  mov    -0x1d4(%rbp),%eax
  cltq
  mov    -0x1d4(%rbp),%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
  addl   $0x1,-0x1d4(%rbp)
L5:
  cmpl   $0x63,-0x1d4(%rbp)
  jle    L67
  movl   $0x0,-0x1d4(%rbp)
  jmp    L4
L60:
  mov    -0x1d4(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%edx
  mov    -0x1d4(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1d4(%rbp)
L4:
  cmpl   $0x9,-0x1d4(%rbp)
  jle    L60
  movl   $0x0,-0x1d4(%rbp)
  jmp    L33
L20:
  mov    -0x1d4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1d4(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1d4(%rbp)
L33:
  cmpl   $0x63,-0x1d4(%rbp)
  jle    L20
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string

tool: D10: t[%d]=%d


assistant: ```c
int main() {
  int t[10];
  int tab2[100];
  int i;
  for (i = 0; i < 100; i++) {
    t[i] = i;
  }
  for (i = 0; i < 10; i++) {
    printf("t[%d]=%d\n", i, t[i]);
  }
  for (i = 0; i < 100; i++) {
    printf("t[%d]=%d\n", i, tab2[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
L35:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L35
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
L3:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L3
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
L11:
  mov    0x30(%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  jne    L11
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x1d8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string

tool: D17: t[%d]=%d


assistant: ```c
int main() {
  int t[10];
  int tab2[100];
  int i;
  for (i = 0; i < 100; i++) {
    t[i] = i;
  }
  for (i = 0; i < 10; i++) {
    printf("t[%d]=%d\n", i, t[i]);
  }
  for (i = 0; i < 100; i++) {
    printf("t[%d]=%d\n", i, tab2[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   (%rax)
L21:
  mov    %eax,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L21
  xor    %r12d,%r12d
  lea    D2(%rip),%rbp
  nop
L28:
  mov    (%rbx,%r12,4),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  add    $0x1,%r12
  call   <printf@plt>
  cmp    $0xa,%r12
  jne    L28
  xor    %ebx,%ebx
  lea    0x30(%rsp),%r12
L14:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L14
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x1d0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D2: t[%d]=%d


assistant: ```c
int main() {
  int t[10];
  int tab2[100];
  int i;
  for (i = 0; i < 100; i++) {
    t[i] = i;
  }
  for (i = 0; i < 10; i++) {
    printf("t[%d]=%d\n", i, t[i]);
  }
  for (i = 0; i < 100; i++) {
    printf("t[%d]=%d\n", i, tab2[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d0,%rsp
  movdqa D48(%rip),%xmm0
  movdqa D47(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdx
  movaps %xmm0,(%rsp)
  movdqa D23(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D31(%rip),%xmm0
L7:
  movdqa %xmm0,%xmm2
  paddd  %xmm1,%xmm0
  movaps %xmm2,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    $0x170,%rax
  jne    L7
  xor    %ebx,%ebx
  mov    %rsp,%r12
  lea    D10(%rip),%rbp
  nopl   0x0(%rax)
L20:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xa,%rbx
  jne    L20
  xor    %ebx,%ebx
  lea    0x30(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x64,%rbx
  jne    L11
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x1d0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D47
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D23
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D31
datatype: byte[16]
name: extract_symbolic_data
arguments: tag: D10
datatype: string

tool: {"D48": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D47": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D23": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D31": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: D10: t[%d]=%d


assistant: ```c
int main() {
  int t[10];
  int tab2[100];
  int i;
  for (i = 0; i < 100; i++) {
    t[i] = i;
  }
  for (i = 0; i < 10; i++) {
    printf("t[%d]=%d\n", i, t[i]);
  }
  for (i = 0; i < 100; i++) {
    printf("t[%d]=%d\n", i, tab2[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ran01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xf,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  imul   $0xfffffffffffe0ce3,%rax,%rax
  add    %rdx,%rax
  imul   $0x41a7,%rax,%rdx
  mov    -0x10(%rbp),%rax
  imul   $0xfffffffffffff4ec,%rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jns    L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x7fffffff(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D6(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x20,0x00,0x00,0x00,0x00,0x3e]}

assistant: ```c
double ran01(long *idum) {
  long k;
  double ans;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  ans = (1.0 / 2147483647) * (*idum);
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ran01>:
  endbr64
  mov    (%rdi),%rsi
  movabs $0x41a705af1fe3fb79,%rdx
  mov    %rsi,%rax
  imul   %rdx
  sar    $0xf,%rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0xfffffffffffe0ce3,%rdx,%rax
  add    %rsi,%rax
  imul   $0x41a7,%rax,%rax
  imul   $0xfffffffffffff4ec,%rdx,%rdx
  add    %rdx,%rax
  lea    0x7fffffff(%rax),%rdx
  cmovs  %rdx,%rax
  mov    %rax,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  D5(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x20,0x00,0x00,0x00,0x00,0x3e]}

assistant: ```c
double ran01(long *idum) {
  long k;
  double ans;
  k = (*idum) / 127773;
  *idum = 16807 * (*idum - k * 127773) - 2836 * k;
  if (*idum < 0)
    *idum += 2147483647;
  ans = (1.0 / 2147483647) * (*idum);
  return ans;
}
```