ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<HO_0>:
  endbr64
  sub    $0x28,%rsp
  mov    D0(%rip),%rax
  movsd  %xmm1,0x18(%rsp)
  movq   %rax,%xmm1
  movsd  %xmm0,0x10(%rsp)
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  D37(%rip),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm4
  movsd  D0(%rip),%xmm2
  mulsd  %xmm4,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  call   <exp@plt>
  movsd  0x8(%rsp),%xmm3
  mulsd  D11(%rip),%xmm3
  add    $0x28,%rsp
  movapd %xmm0,%xmm1
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: f64

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0xbf]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xc0]}

tool: D11: 0.7511255444

assistant: ```c
double HO_0(const double L, const double x) {
  double retval = 0.7511255444e0 * pow(L, -0.1e1 / 0.2e1) * exp(-0.5000000000e0 * x * x * pow(L, -0.2e1));
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x8c(%rbp)
  jmp    L55
L31:
  mov    -0x74(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x8c(%rbp)
L55:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x74(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x74(%rbp)
  jne    L31
  movl   $0x0,-0x88(%rbp)
  jmp    L4
L27:
  movl   $0x0,-0x7c(%rbp)
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x84(%rbp)
  jmp    L77
L120:
  mov    -0x88(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x84(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L54
  addl   $0x1,-0x7c(%rbp)
  mov    -0x88(%rbp),%eax
  cmp    -0x84(%rbp),%eax
  jle    L54
  movl   $0x1,-0x78(%rbp)
L54:
  addl   $0x1,-0x84(%rbp)
L77:
  mov    -0x84(%rbp),%eax
  cmp    -0x8c(%rbp),%eax
  jl     L120
  cmpl   $0x0,-0x78(%rbp)
  jne    L82
  mov    -0x88(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L59
L98:
  mov    $0x2d,%edi
  call   <putchar@plt>
  addl   $0x1,-0x80(%rbp)
L59:
  mov    -0x80(%rbp),%eax
  cmp    -0x7c(%rbp),%eax
  jl     L98
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L121
L82:
  nop
L121:
  addl   $0x1,-0x88(%rbp)
L4:
  mov    -0x88(%rbp),%eax
  cmp    -0x8c(%rbp),%eax
  jl     L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int c;
  char arr_c[100];
  int tot_num_c = 0;
  while ((c = getchar()) != EOF) {
    arr_c[tot_num_c] = c;
    tot_num_c++;
  }
  int i, j, k;
  int freq_c, not_first;
  for (i = 0; i < tot_num_c; i++) {
    freq_c = 0;
    not_first = 0;
    for (j = 0; j < tot_num_c; j++) {
      if (arr_c[i] == arr_c[j]) {
        freq_c++;
        if (i > j) {
          not_first = 1;
        }
      }
    }
    if (not_first) {
      continue;
    } else {
      printf("%c", arr_c[i]);
      for (k = 0; k < freq_c; k++) {
        printf("-");
      }
      printf("\n");
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  jmp    L129
L114:
  mov    %al,(%rsp,%rbp,1)
  add    $0x1,%rbp
L129:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L114
  test   %ebp,%ebp
  jle    L0
  mov    %ebp,%ebp
  mov    $0x0,%r13d
  mov    $0x1,%r14d
  jmp    L19
L102:
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L29
L79:
  cmp    (%rax,%rdx,1),%dil
  jne    L102
  add    $0x1,%r12d
  cmp    %r13d,%eax
  cmovl  %r14d,%ebx
  jmp    L102
L29:
  test   %ebx,%ebx
  je     L1
L74:
  add    $0x1,%r13
  cmp    %r13,%rbp
  je     L0
L19:
  movzbl (%rsp,%r13,1),%edi
  mov    $0x0,%eax
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    %rsp,%rdx
  jmp    L79
L1:
  movsbl %dil,%edi
  call   <putchar@plt>
  test   %r12d,%r12d
  jle    L17
L14:
  mov    $0x2d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L14
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L74
L0:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L124:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int c;
  char arr_c[100];
  int tot_num_c = 0;
  while ((c = getchar()) != EOF) {
    arr_c[tot_num_c] = c;
    tot_num_c++;
  }
  int i, j, k;
  int freq_c, not_first;
  for (i = 0; i < tot_num_c; i++) {
    freq_c = 0;
    not_first = 0;
    for (j = 0; j < tot_num_c; j++) {
      if (arr_c[i] == arr_c[j]) {
        freq_c++;
        if (i > j) {
          not_first = 1;
        }
      }
    }
    if (not_first) {
      continue;
    } else {
      printf("%c", arr_c[i]);
      for (k = 0; k < freq_c; k++) {
        printf("-");
      }
      printf("\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    D3(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  jmp    L17
  nopl   (%rax)
L84:
  mov    %al,(%rsp,%rbp,1)
  add    $0x1,%rbp
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L84
  test   %ebp,%ebp
  je     L73
  xor    %r15d,%r15d
  mov    %rsp,%r13
  mov    $0x1,%r12d
  nopl   0x0(%rax)
L82:
  movsbl 0x0(%r13,%r15,1),%edi
  xor    %eax,%eax
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  nopl   (%rax)
L101:
  cmp    0x0(%r13,%rax,1),%dil
  jne    L42
  add    $0x1,%r14d
  cmp    %r15d,%eax
  cmovl  %r12d,%ebx
L42:
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L101
  test   %ebx,%ebx
  je     L25
L106:
  add    $0x1,%r15
  cmp    %rbp,%r15
  jne    L82
L73:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L25:
  call   <putchar@plt>
  test   %r14d,%r14d
  je     L31
  nopw   0x0(%rax,%rax,1)
L88:
  mov    $0x2d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r14d
  jne    L88
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L106
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int c;
  char arr_c[100];
  int tot_num_c = 0;
  while ((c = getchar()) != EOF) {
    arr_c[tot_num_c] = c;
    tot_num_c++;
  }
  int i, j, k;
  int freq_c, not_first;
  for (i = 0; i < tot_num_c; i++) {
    freq_c = 0;
    not_first = 0;
    for (j = 0; j < tot_num_c; j++) {
      if (arr_c[i] == arr_c[j]) {
        freq_c++;
        if (i > j) {
          not_first = 1;
        }
      }
    }
    if (not_first) {
      continue;
    } else {
      printf("%c", arr_c[i]);
      for (k = 0; k < freq_c; k++) {
        printf("-");
      }
      printf("\n");
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x78,%rsp
  mov    D3(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  jmp    L15
  nopl   (%rax)
L26:
  mov    %al,(%rsp,%rbp,1)
  add    $0x1,%rbp
L15:
  xor    %eax,%eax
  mov    %ebp,%r12d
  call   <getchar@plt>
  cmp    %eax,(%rbx)
  jne    L26
  test   %ebp,%ebp
  je     L66
  xor    %r15d,%r15d
  mov    %rsp,%r14
  nop
L105:
  movsbl (%r14,%r15,1),%edi
  test   %r15,%r15
  je     L37
  cmp    %r15d,%r12d
  mov    %r15d,%ecx
  mov    %r14,%rdx
  cmovle %r12d,%ecx
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  xor    %eax,%eax
  xchg   %ax,%ax
L74:
  cmp    (%rdx),%dil
  jne    L90
  add    $0x1,%ebx
  mov    $0x1,%r13d
L90:
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %eax,%ecx
  jg     L74
  cmp    %eax,%r12d
  jle    L80
L25:
  cltq
L27:
  xor    %edx,%edx
  cmp    (%r14,%rax,1),%dil
  sete   %dl
  add    $0x1,%rax
  add    %edx,%ebx
  cmp    %eax,%r12d
  jg     L27
L80:
  test   %r13d,%r13d
  je     L88
L46:
  add    $0x1,%r15
  cmp    %r15,%rbp
  jne    L105
L66:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L25
  nopl   0x0(%rax)
L88:
  call   <putchar@plt>
  test   %ebx,%ebx
  je     L147
  nopl   0x0(%rax)
L22:
  mov    $0x2d,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,%ebx
  jne    L22
L147:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L46
L106:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int c;
  char arr_c[100];
  int tot_num_c = 0;
  while ((c = getchar()) != EOF) {
    arr_c[tot_num_c] = c;
    tot_num_c++;
  }
  int i, j, k;
  int freq_c, not_first;
  for (i = 0; i < tot_num_c; i++) {
    freq_c = 0;
    not_first = 0;
    for (j = 0; j < tot_num_c; j++) {
      if (arr_c[i] == arr_c[j]) {
        freq_c++;
        if (i > j) {
          not_first = 1;
        }
      }
    }
    if (not_first) {
      continue;
    } else {
      printf("%c", arr_c[i]);
      for (k = 0; k < freq_c; k++) {
        printf("-");
      }
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L1
L17:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L1:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L17
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *d, int c, size_t sz) {
  void *tmp = d;
  char *dp = (char *)d;
  while (sz--)
    *dp++ = c;
  return tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L7
  add    %rdi,%rdx
  mov    %rdi,%rcx
L18:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rcx,%rdx
  jne    L18
L7:
  ret
```

assistant: ```c
void *memset(void *d, int c, size_t sz) {
  void *tmp = d;
  char *dp = (char *)d;
  while (sz--)
    *dp++ = c;
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L9
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *d, int c, size_t sz) {
  void *tmp = d;
  char *dp = (char *)d;
  while (sz--)
    *dp++ = c;
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L7
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *d, int c, size_t sz) {
  void *tmp = d;
  char *dp = (char *)d;
  while (sz--)
    *dp++ = c;
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fingerprintToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L14
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string

tool: D1: %02X:

assistant: ```c
char *fingerprintToHex(const void *ptr, int len) {
  int i;
  char *hex = malloc(len * 3 + 1);
  const char *mem = ptr;
  for (i = 0; i < len; ++i) {
    sprintf(hex + (i * 3), "%02X:", mem[i] & 0xFF);
  }
  hex[len * 3 - 1] = '\0';
  return hex;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fingerprintToHex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    (%rsi,%rsi,2),%r15d
  lea    0x1(%r15),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L13
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%r12,%r12,2),%r12
  add    %rax,%r12
  lea    D0(%rip),%r13
L7:
  movsbl 0x0(%rbp),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x1,%rbp
  add    $0x3,%rbx
  cmp    %r12,%rbx
  jne    L7
L13:
  movslq %r15d,%r15
  movb   $0x0,-0x1(%r14,%r15,1)
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type: string

tool: D0: %02X:

assistant: ```c
char *fingerprintToHex(const void *ptr, int len) {
  int i;
  char *hex = malloc(len * 3 + 1);
  const char *mem = ptr;
  for (i = 0; i < len; ++i) {
    sprintf(hex + (i * 3), "%02X:", mem[i] & 0xFF);
  }
  hex[len * 3 - 1] = '\0';
  return hex;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fingerprintToHex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%r12,%r12,2),%r14d
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%r14),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L17
  lea    (%r12,%r12,2),%r12
  mov    %rax,%rbx
  lea    D5(%rip),%r15
  add    %rax,%r12
  xchg   %ax,%ax
L15:
  movsbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r15,%rsi
  add    $0x3,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r12,%rbx
  jne    L15
L17:
  movslq %r14d,%r14
  mov    %r13,%rax
  movb   $0x0,-0x1(%r13,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: %02X:

assistant: ```c
char *fingerprintToHex(const void *ptr, int len) {
  int i;
  char *hex = malloc(len * 3 + 1);
  const char *mem = ptr;
  for (i = 0; i < len; ++i) {
    sprintf(hex + (i * 3), "%02X:", mem[i] & 0xFF);
  }
  hex[len * 3 - 1] = '\0';
  return hex;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fingerprintToHex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%r12,%r12,2),%r14d
  mov    %rdi,%rbp
  push   %rbx
  lea    0x1(%r14),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L18
  lea    (%r12,%r12,2),%r12
  mov    %rax,%rbx
  lea    D5(%rip),%r15
  add    %rax,%r12
  xchg   %ax,%ax
L10:
  movsbl 0x0(%rbp),%edx
  mov    %rbx,%rdi
  mov    %r15,%rsi
  add    $0x3,%rbx
  add    $0x1,%rbp
  call   <sprintf@plt>
  cmp    %r12,%rbx
  jne    L10
L18:
  movslq %r14d,%r14
  mov    %r13,%rax
  movb   $0x0,-0x1(%r13,%r14,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: %02X:

assistant: ```c
char *fingerprintToHex(const void *ptr, int len) {
  int i;
  char *hex = malloc(len * 3 + 1);
  const char *mem = ptr;
  for (i = 0; i < len; ++i) {
    sprintf(hex + (i * 3), "%02X:", mem[i] & 0xFF);
  }
  hex[len * 3 - 1] = '\0';
  return hex;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Long_Little2Big>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
u_int32_t Long_Little2Big(u_int32_t var) {
  unsigned char *ptmp;
  ptmp = (unsigned char *)&var;
  return (((u_int32_t)ptmp[3] << 24) + ((u_int32_t)ptmp[2] << 16) + ((u_int32_t)ptmp[1] << 8) + (u_int32_t)ptmp[0]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Long_Little2Big>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
u_int32_t Long_Little2Big(u_int32_t var) {
  unsigned char *ptmp;
  ptmp = (unsigned char *)&var;
  return (((u_int32_t)ptmp[3] << 24) + ((u_int32_t)ptmp[2] << 16) + ((u_int32_t)ptmp[1] << 8) + (u_int32_t)ptmp[0]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Long_Little2Big>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
u_int32_t Long_Little2Big(u_int32_t var) {
  unsigned char *ptmp;
  ptmp = (unsigned char *)&var;
  return (((u_int32_t)ptmp[3] << 24) + ((u_int32_t)ptmp[2] << 16) + ((u_int32_t)ptmp[1] << 8) + (u_int32_t)ptmp[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LOGI_S16_PLUS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L3:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L3
L0:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L35
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L35:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movzbl -0x40(%rbp),%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <convertToUnibyteStringAndReplaceLastChar@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void LOGI_S16_PLUS(unsigned short *string, const unsigned int length, unsigned char c) {
  unsigned char tmp_buffer[length + 1];
  convertToUnibyteStringAndReplaceLastChar(string, tmp_buffer, length, c);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LOGI_S16_PLUS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%r8
  and    $0xfffffffffffff000,%r8
  mov    %rsp,%rcx
  sub    %r8,%rcx
L20:
  cmp    %rcx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L20
L5:
  mov    %rax,%rcx
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L24
  orq    $0x0,-0x8(%rsp,%rcx,1)
L24:
  movzbl %dl,%ecx
  mov    %esi,%edx
  mov    %rsp,%rsi
  call   <convertToUnibyteStringAndReplaceLastChar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  leave
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGI_S16_PLUS(unsigned short *string, const unsigned int length, unsigned char c) {
  unsigned char tmp_buffer[length + 1];
  convertToUnibyteStringAndReplaceLastChar(string, tmp_buffer, length, c);
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LOGI_S16_PLUS>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L31
L20:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L20
L31:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L33
L11:
  movzbl %dl,%ecx
  mov    %rsp,%rsi
  mov    %r8d,%edx
  call   <convertToUnibyteStringAndReplaceLastChar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L11
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGI_S16_PLUS(unsigned short *string, const unsigned int length, unsigned char c) {
  unsigned char tmp_buffer[length + 1];
  convertToUnibyteStringAndReplaceLastChar(string, tmp_buffer, length, c);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LOGI_S16_PLUS>:
  endbr64
  push   %rbp
  mov    %esi,%r8d
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%eax
  mov    %rsp,%rcx
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rsi
  sub    %rsi,%rcx
  cmp    %rcx,%rsp
  je     L18
L32:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L32
L18:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L49
L38:
  movzbl %dl,%ecx
  mov    %rsp,%rsi
  mov    %r8d,%edx
  call   <convertToUnibyteStringAndReplaceLastChar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L38
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void LOGI_S16_PLUS(unsigned short *string, const unsigned int length, unsigned char c) {
  unsigned char tmp_buffer[length + 1];
  convertToUnibyteStringAndReplaceLastChar(string, tmp_buffer, length, c);
  ;
}
```