ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<eye>:
  endbr64
  test   %esi,%esi
  jle    L21
  movslq %esi,%rcx
  movsd  D7(%rip),%xmm0
  xor    %edx,%edx
  lea    0x0(,%rcx,8),%r8
  nopl   (%rax)
L67:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L22:
  cmp    %eax,%edx
  je     L30
  movq   $0x0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L22
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %esi,%edx
  jne    L67
L21:
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L22
  add    $0x1,%edx
  add    %r8,%rdi
  cmp    %esi,%edx
  jne    L67
  jmp    L21
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: f64

tool: D7: 1

assistant: ```c
void eye(double *mat, int N) {
  int i, j, t;
  for (i = 0; i < N; ++i) {
    for (j = 0; j < N; ++j) {
      t = i * N;
      if (i == j) {
        mat[t + j] = 1.;
      } else {
        mat[t + j] = 0.;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<CombSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L50:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <newgap@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L55
L43:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L12
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x1,-0xc(%rbp)
L12:
  addl   $0x1,-0x10(%rbp)
L55:
  mov    -0x2c(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L43
  cmpl   $0x1,-0x14(%rbp)
  jne    L50
  cmpl   $0x0,-0xc(%rbp)
  je     L32
  jmp    L50
L32:
  nop
  nop
  leave
  ret
```

assistant: ```c
void CombSort(int *array, int size) {
  int gap = size;
  int temp, i;
  for (;;) {
    gap = newgap(gap);
    int swapped = 0;
    for (i = 0; i < size - gap; i++) {
      int j = i + gap;
      if (*(array + i) > *(array + j)) {
        temp = *(array + i);
        *(array + i) = *(array + j);
        *(array + j) = temp;
        swapped = 1;
      }
    }
    if (gap == 1 && !swapped)
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CombSort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%eax
  lea    0x4(%rdi),%r14
  mov    $0x0,%r13d
  mov    $0x1,%ebx
  jmp    L74
L35:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L6
L65:
  mov    (%rdx),%ecx
  mov    (%rdx,%rdi,4),%esi
  cmp    %esi,%ecx
  jle    L35
  mov    %esi,(%rdx)
  mov    %ecx,(%rdx,%rdi,4)
  mov    %ebx,%r9d
  jmp    L35
L23:
  mov    %r13d,%r9d
L6:
  cmp    $0x1,%eax
  jne    L74
  test   %r9d,%r9d
  je     L16
L74:
  mov    %eax,%edi
  call   <newgap@plt>
  mov    %ebp,%ecx
  sub    %eax,%ecx
  test   %ecx,%ecx
  jle    L23
  mov    %r12,%rdx
  lea    -0x1(%rcx),%ecx
  lea    (%r14,%rcx,4),%r8
  mov    %r13d,%r9d
  movslq %eax,%rdi
  jmp    L65
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void CombSort(int *array, int size) {
  int gap = size;
  int temp, i;
  for (;;) {
    gap = newgap(gap);
    int swapped = 0;
    for (i = 0; i < size - gap; i++) {
      int j = i + gap;
      if (*(array + i) > *(array + j)) {
        temp = *(array + i);
        *(array + i) = *(array + j);
        *(array + j) = temp;
        swapped = 1;
      }
    }
    if (gap == 1 && !swapped)
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<CombSort>:
  endbr64
  push   %r12
  mov    %esi,%r10d
  lea    0x4(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax)
L22:
  mov    %r10d,%edi
  call   <newgap@plt>
  mov    %eax,%r10d
  mov    %ebx,%eax
  sub    %r10d,%eax
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  mov    %rbp,%rdx
  xor    %r9d,%r9d
  movslq %r10d,%rdi
  lea    (%r12,%rax,4),%r8
  nopl   0x0(%rax)
L0:
  mov    (%rdx),%ecx
  mov    (%rdx,%rdi,4),%esi
  cmp    %esi,%ecx
  jle    L12
  mov    %esi,(%rdx)
  mov    $0x1,%r9d
  mov    %ecx,(%rdx,%rdi,4)
L12:
  add    $0x4,%rdx
  cmp    %rdx,%r8
  jne    L0
  xor    $0x1,%r9d
L6:
  cmp    $0x1,%r10d
  jne    L22
  test   %r9b,%r9b
  je     L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%r9d
  jmp    L6
```

assistant: ```c
void CombSort(int *array, int size) {
  int gap = size;
  int temp, i;
  for (;;) {
    gap = newgap(gap);
    int swapped = 0;
    for (i = 0; i < size - gap; i++) {
      int j = i + gap;
      if (*(array + i) > *(array + j)) {
        temp = *(array + i);
        *(array + i) = *(array + j);
        *(array + j) = temp;
        swapped = 1;
      }
    }
    if (gap == 1 && !swapped)
      break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CombSort>:
  endbr64
  push   %r12
  mov    %esi,%r10d
  lea    0x4(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax)
L23:
  mov    %r10d,%edi
  call   <newgap@plt>
  mov    %eax,%r10d
  mov    %ebx,%eax
  sub    %r10d,%eax
  test   %eax,%eax
  jle    L55
  sub    $0x1,%eax
  mov    %rbp,%rdx
  xor    %r9d,%r9d
  movslq %r10d,%rdi
  lea    (%r12,%rax,4),%r8
  nopl   0x0(%rax)
L51:
  mov    (%rdx),%ecx
  mov    (%rdx,%rdi,4),%esi
  cmp    %esi,%ecx
  jle    L56
  mov    %esi,(%rdx)
  mov    $0x1,%r9d
  mov    %ecx,(%rdx,%rdi,4)
L56:
  add    $0x4,%rdx
  cmp    %rdx,%r8
  jne    L51
  xor    $0x1,%r9d
L9:
  cmp    $0x1,%r10d
  jne    L23
  test   %r9b,%r9b
  je     L23
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  mov    $0x1,%r9d
  jmp    L9
```

assistant: ```c
void CombSort(int *array, int size) {
  int gap = size;
  int temp, i;
  for (;;) {
    gap = newgap(gap);
    int swapped = 0;
    for (i = 0; i < size - gap; i++) {
      int j = i + gap;
      if (*(array + i) > *(array + j)) {
        temp = *(array + i);
        *(array + i) = *(array + j);
        *(array + j) = temp;
        swapped = 1;
      }
    }
    if (gap == 1 && !swapped)
      break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: Usage: screen-getty <tty> [baud] -c <cmd>


assistant: ```c
void usage(void) {
  printf("Usage: screen-getty <tty> [baud] -c <cmd>\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: Usage: screen-getty <tty> [baud] -c <cmd>


assistant: ```c
void usage(void) {
  printf("Usage: screen-getty <tty> [baud] -c <cmd>\n");
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: Usage: screen-getty <tty> [baud] -c <cmd>


assistant: ```c
void usage(void) {
  printf("Usage: screen-getty <tty> [baud] -c <cmd>\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: Usage: screen-getty <tty> [baud] -c <cmd>


assistant: ```c
void usage(void) {
  printf("Usage: screen-getty <tty> [baud] -c <cmd>\n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filename__read_ull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x54(%rbp)
  movl   $0xffffffff,-0x58(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L5
L10:
  lea    -0x50(%rbp),%rcx
  mov    -0x54(%rbp),%eax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jle    L13
  lea    -0x50(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoull@plt>
  mov    -0x70(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x70(%rbp),%rax
  mov    (%rax),%rdx
  mov    D1(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L13
  movl   $0x0,-0x58(%rbp)
L13:
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x58(%rbp),%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
int filename__read_ull(const char *filename, unsigned long long *value) {
  char line[64];
  int fd = open(filename, O_RDONLY), err = -1;
  if (fd < 0)
    return -1;
  if (read(fd, line, sizeof(line)) > 0) {
    *value = strtoull(line, NULL, 10);
    if (*value != ULLONG_MAX)
      err = 0;
  }
  close(fd);
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filename__read_ull>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L21
  mov    %eax,%ebx
  mov    %rsp,%rsi
  mov    $0x40,%edx
  mov    %eax,%edi
  call   <read@plt>
  mov    $0xffffffff,%r12d
  test   %rax,%rax
  jg     L11
L33:
  mov    %ebx,%edi
  call   <close@plt>
L10:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %r12d,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %rsp,%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoull@plt>
  mov    %rax,0x0(%rbp)
  mov    D12(%rip),%rdx
  cmp    %rax,(%rdx)
  sete   %r12b
  movzbl %r12b,%r12d
  neg    %r12d
  jmp    L33
L21:
  mov    $0xffffffff,%r12d
  jmp    L10
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filename__read_ull(const char *filename, unsigned long long *value) {
  char line[64];
  int fd = open(filename, O_RDONLY), err = -1;
  if (fd < 0)
    return -1;
  if (read(fd, line, sizeof(line)) > 0) {
    *value = strtoull(line, NULL, 10);
    if (*value != ULLONG_MAX)
      err = 0;
  }
  close(fd);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filename__read_ull>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L30
  mov    %rsp,%r13
  mov    $0x40,%edx
  mov    %eax,%edi
  mov    %eax,%ebp
  mov    %r13,%rsi
  mov    $0xffffffff,%r12d
  call   <read@plt>
  test   %rax,%rax
  jle    L31
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <strtoull@plt>
  mov    D18(%rip),%rdx
  mov    %rax,(%rbx)
  cmp    %rax,(%rdx)
  sete   %r12b
  neg    %r12d
L31:
  mov    %ebp,%edi
  call   <close@plt>
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  mov    $0xffffffff,%r12d
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filename__read_ull(const char *filename, unsigned long long *value) {
  char line[64];
  int fd = open(filename, O_RDONLY), err = -1;
  if (fd < 0)
    return -1;
  if (read(fd, line, sizeof(line)) > 0) {
    *value = strtoull(line, NULL, 10);
    if (*value != ULLONG_MAX)
      err = 0;
  }
  close(fd);
  return err;
}
```
user: What is the c source code of the assembly code below:

```asm
<filename__read_ull>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %eax,%eax
  js     L14
  mov    %rsp,%r13
  mov    $0x40,%edx
  mov    %eax,%edi
  mov    %eax,%ebp
  mov    %r13,%rsi
  mov    $0xffffffff,%r12d
  call   <read@plt>
  test   %rax,%rax
  jle    L26
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %r12d,%r12d
  call   <strtoull@plt>
  mov    D9(%rip),%rdx
  mov    %rax,(%rbx)
  cmp    %rax,(%rdx)
  sete   %r12b
  neg    %r12d
L26:
  mov    %ebp,%edi
  call   <close@plt>
L16:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x58,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xffffffff,%r12d
  jmp    L16
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int filename__read_ull(const char *filename, unsigned long long *value) {
  char line[64];
  int fd = open(filename, O_RDONLY), err = -1;
  if (fd < 0)
    return -1;
  if (read(fd, line, sizeof(line)) > 0) {
    *value = strtoull(line, NULL, 10);
    if (*value != ULLONG_MAX)
      err = 0;
  }
  close(fd);
  return err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_op_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <trace_seq_printf@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: %8s:	%s


assistant: ```c
void print_op_data(struct trace_seq *s, const char *name, const char *op) {
  if (op)
    trace_seq_printf(s, "%8s:\t%s\n", name, op);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_op_data>:
  endbr64
  test   %rdx,%rdx
  je     L1
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D6(%rip),%rsi
  call   <trace_seq_printf@plt>
  add    $0x8,%rsp
  ret
L1:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D6: %8s:	%s


assistant: ```c
void print_op_data(struct trace_seq *s, const char *name, const char *op) {
  if (op)
    trace_seq_printf(s, "%8s:\t%s\n", name, op);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_op_data>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L9
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  jmp    1050 <trace_seq_printf@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %8s:	%s


assistant: ```c
void print_op_data(struct trace_seq *s, const char *name, const char *op) {
  if (op)
    trace_seq_printf(s, "%8s:\t%s\n", name, op);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_op_data>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L5
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  jmp    1050 <trace_seq_printf@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: %8s:	%s


assistant: ```c
void print_op_data(struct trace_seq *s, const char *name, const char *op) {
  if (op)
    trace_seq_printf(s, "%8s:\t%s\n", name, op);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x8,%rsp
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  push   $0x5
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  mov    $0x2,%ecx
  mov    $0x1,%edx
  mov    $0x3e7,%esi
  mov    $0x378,%edi
  call   <vafunction@plt>
  add    $0x30,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  vafunction(888., 999., 1., 2., 3., 4., 5., 6., 7., 8., 9.);
  exit(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  push   $0x5
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  mov    $0x2,%ecx
  mov    $0x1,%edx
  mov    $0x3e7,%esi
  mov    $0x378,%edi
  call   <vafunction@plt>
  add    $0x30,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  vafunction(888., 999., 1., 2., 3., 4., 5., 6., 7., 8., 9.);
  exit(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  mov    $0x2,%ecx
  push   $0x9
  mov    $0x1,%edx
  mov    $0x3e7,%esi
  mov    $0x378,%edi
  push   $0x8
  push   $0x7
  push   $0x6
  push   $0x5
  call   <vafunction@plt>
  add    $0x30,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  vafunction(888., 999., 1., 2., 3., 4., 5., 6., 7., 8., 9.);
  exit(0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x4,%r9d
  mov    $0x3,%r8d
  mov    $0x2,%ecx
  push   $0x9
  mov    $0x1,%edx
  mov    $0x3e7,%esi
  mov    $0x378,%edi
  push   $0x8
  push   $0x7
  push   $0x6
  push   $0x5
  call   <vafunction@plt>
  add    $0x30,%rsp
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  vafunction(888., 999., 1., 2., 3., 4., 5., 6., 7., 8., 9.);
  exit(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<crop_i32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jge    L4
  mov    -0x10(%rbp),%rax
  jmp    L19
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jle    L12
  mov    -0x18(%rbp),%rax
  jmp    L19
L12:
  mov    -0x8(%rbp),%rax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int32_t crop_i32(int32_t val, int32_t min, int32_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<crop_i32>:
  endbr64
  cmp    %rdx,%rdi
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  mov    %rsi,%rax
  cmovge %rdx,%rax
  ret
```

assistant: ```c
int32_t crop_i32(int32_t val, int32_t min, int32_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crop_i32>:
  endbr64
  cmp    %rdx,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  cmovge %rdx,%rax
  ret
```

assistant: ```c
int32_t crop_i32(int32_t val, int32_t min, int32_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<crop_i32>:
  endbr64
  cmp    %rdx,%rdi
  mov    %rsi,%rax
  cmovle %rdi,%rdx
  cmp    %rsi,%rdi
  cmovge %rdx,%rax
  ret
```

assistant: ```c
int32_t crop_i32(int32_t val, int32_t min, int32_t max) {
  if (val < min)
    return min;
  if (val > max)
    return max;
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<safe_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: malloc()

assistant: ```c
void *safe_malloc(size_t size) {
  void *x = malloc(size);
  if (x == NULL) {
    perror("malloc()");
    exit(-1);
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<safe_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L13:
  mov    %rbx,%rax
  pop    %rbx
  ret
L2:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: malloc()

assistant: ```c
void *safe_malloc(size_t size) {
  void *x = malloc(size);
  if (x == NULL) {
    perror("malloc()");
    exit(-1);
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L3:
  mov    %r12,%rax
  pop    %r12
  ret
L17:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: malloc()

assistant: ```c
void *safe_malloc(size_t size) {
  void *x = malloc(size);
  if (x == NULL) {
    perror("malloc()");
    exit(-1);
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<safe_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
L2:
  mov    %r12,%rax
  pop    %r12
  ret
L10:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: malloc()

assistant: ```c
void *safe_malloc(size_t size) {
  void *x = malloc(size);
  if (x == NULL) {
    perror("malloc()");
    exit(-1);
  }
  return x;
}
```