ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<do_remove>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D31(%rip),%rsi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  je     L102
L74:
  test   %eax,%eax
  js     L68
L63:
  mov    %rbx,%rdi
  call   <recursive_rm@plt>
  test   %eax,%eax
  js     L85
  mov    $0x0,%eax
L25:
  pop    %rbx
  ret
L102:
  lea    D35(%rip),%rsi
  mov    %rbx,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L74
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L74
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <check_user_perms@plt>
  test   %eax,%eax
  jns    L63
  cmp    $0xfffffffe,%eax
  jne    L57
  mov    %rbx,%rsi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <eout@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L85:
  neg    %eax
  mov    %eax,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <eout@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L57:
  mov    $0xffffffff,%eax
  jmp    L25
L68:
  mov    $0xffffffff,%eax
  jmp    L25
```

tool_calls: name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D35
type: string
name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D44
type: string
name: parse_data
arguments: label: D36
type: string

tool: D31: JOB

tool: D35: JOB.error

tool: D6: JOB.suspended

tool: D3: JOB.done

tool: D44: no JOB file in %s/ - can't verify permissions


tool: D36: could not remove %d files or subdirectories


assistant: ```c
int do_remove(char *JID) {
  int rc;
  rc = check_user_perms(JID, "JOB");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.error");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.suspended");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.done");
  if (rc < 0) {
    if (rc == -2)
      eout("no JOB file in %s/ - can't verify permissions\n", JID);
    return -1;
  }
  rc = recursive_rm(JID);
  if (rc < 0) {
    eout("could not remove %d files or subdirectories\n", -rc);
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_remove>:
  endbr64
  push   %rbp
  lea    D48(%rip),%rsi
  mov    %rdi,%rbp
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  je     L15
L67:
  test   %eax,%eax
  js     L57
L8:
  mov    %rbp,%rdi
  call   <recursive_rm@plt>
  test   %eax,%eax
  js     L4
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L15:
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L67
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L67
  lea    D31(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  test   %eax,%eax
  jns    L8
  cmp    $0xfffffffe,%eax
  jne    L57
  mov    %rbp,%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <eout@plt>
L57:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L4:
  neg    %eax
  lea    D24(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <eout@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D48
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D45
datatype: string
name: retrieve_data
arguments: tag: D31
datatype: string
name: retrieve_data
arguments: tag: D57
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: D48: JOB

tool: D15: JOB.error

tool: D45: JOB.suspended

tool: D31: JOB.done

tool: D57: no JOB file in %s/ - can't verify permissions


tool: D24: could not remove %d files or subdirectories


assistant: ```c
int do_remove(char *JID) {
  int rc;
  rc = check_user_perms(JID, "JOB");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.error");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.suspended");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.done");
  if (rc < 0) {
    if (rc == -2)
      eout("no JOB file in %s/ - can't verify permissions\n", JID);
    return -1;
  }
  rc = recursive_rm(JID);
  if (rc < 0) {
    eout("could not remove %d files or subdirectories\n", -rc);
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_remove>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rsi
  mov    %rdi,%rbp
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  je     L30
L36:
  test   %eax,%eax
  js     L27
L28:
  mov    %rbp,%rdi
  call   <recursive_rm@plt>
  test   %eax,%eax
  js     L69
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L30:
  lea    D56(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L36
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  cmp    $0xfffffffe,%eax
  jne    L36
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <check_user_perms@plt>
  test   %eax,%eax
  jns    L28
  cmp    $0xfffffffe,%eax
  jne    L27
  mov    %rbp,%rsi
  lea    D54(%rip),%rdi
  xor    %eax,%eax
  call   <eout@plt>
L27:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L69:
  neg    %eax
  lea    D28(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <eout@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
data_type: string
name: extract_symbolic_data
arguments: tag: D56
data_type: string
name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D54
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: string

tool: D24: JOB

tool: D56: JOB.error

tool: D23: JOB.suspended

tool: D19: JOB.done

tool: D54: no JOB file in %s/ - can't verify permissions


tool: D28: could not remove %d files or subdirectories


assistant: ```c
int do_remove(char *JID) {
  int rc;
  rc = check_user_perms(JID, "JOB");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.error");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.suspended");
  if (rc == -2)
    rc = check_user_perms(JID, "JOB.done");
  if (rc < 0) {
    if (rc == -2)
      eout("no JOB file in %s/ - can't verify permissions\n", JID);
    return -1;
  }
  rc = recursive_rm(JID);
  if (rc < 0) {
    eout("could not remove %d files or subdirectories\n", -rc);
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<I2C_enable10BitAddressing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  mov    -0x4(%rbp),%eax
  jmp    L1
L19:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int I2C_enable10BitAddressing(int i2c_fd) {
  int ret;
  ret = ioctl(i2c_fd, I2C_TENBIT, 1);
  if (ret < 0)
    return ret;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<I2C_enable10BitAddressing>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  test   %eax,%eax
  mov    $0x0,%edx
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int I2C_enable10BitAddressing(int i2c_fd) {
  int ret;
  ret = ioctl(i2c_fd, I2C_TENBIT, 1);
  if (ret < 0)
    return ret;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<I2C_enable10BitAddressing>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    $0x1,%edx
  mov    (%rax),%esi
  call   <ioctl@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int I2C_enable10BitAddressing(int i2c_fd) {
  int ret;
  ret = ioctl(i2c_fd, I2C_TENBIT, 1);
  if (ret < 0)
    return ret;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<I2C_enable10BitAddressing>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    $0x1,%edx
  mov    (%rax),%esi
  call   <ioctl@plt>
  xor    %edx,%edx
  test   %eax,%eax
  cmovg  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int I2C_enable10BitAddressing(int i2c_fd) {
  int ret;
  ret = ioctl(i2c_fd, I2C_TENBIT, 1);
  if (ret < 0)
    return ret;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<I2CMasterErr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x24,%eax
  mov    %eax,%eax
  mov    (%rax),%eax
  and    $0x883,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int I2CMasterErr(unsigned int baseAdd) {
  unsigned int err;
  err = (*((volatile unsigned int *)(baseAdd + (0x24)))) & ((0x00000001u) | (0x00000080u) | (0x00000002u) | (0x00000800u));
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<I2CMasterErr>:
  endbr64
  mov    0x24(%edi),%eax
  and    $0x883,%eax
  ret
```

assistant: ```c
unsigned int I2CMasterErr(unsigned int baseAdd) {
  unsigned int err;
  err = (*((volatile unsigned int *)(baseAdd + (0x24)))) & ((0x00000001u) | (0x00000080u) | (0x00000002u) | (0x00000800u));
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<I2CMasterErr>:
  endbr64
  mov    0x24(%edi),%eax
  and    $0x883,%eax
  ret
```

assistant: ```c
unsigned int I2CMasterErr(unsigned int baseAdd) {
  unsigned int err;
  err = (*((volatile unsigned int *)(baseAdd + (0x24)))) & ((0x00000001u) | (0x00000080u) | (0x00000002u) | (0x00000800u));
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<I2CMasterErr>:
  endbr64
  mov    0x24(%edi),%eax
  and    $0x883,%eax
  ret
```

assistant: ```c
unsigned int I2CMasterErr(unsigned int baseAdd) {
  unsigned int err;
  err = (*((volatile unsigned int *)(baseAdd + (0x24)))) & ((0x00000001u) | (0x00000080u) | (0x00000002u) | (0x00000800u));
  return err;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7: RETURNED


assistant: ```c
int main(int argc, const char *argv[]) {
  fun(1);
  printf("RETURNED\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: RETURNED


assistant: ```c
int main(int argc, const char *argv[]) {
  fun(1);
  printf("RETURNED\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: RETURNED


assistant: ```c
int main(int argc, const char *argv[]) {
  fun(1);
  printf("RETURNED\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: RETURNED


assistant: ```c
int main(int argc, const char *argv[]) {
  fun(1);
  printf("RETURNED\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: %s[ %d ] = %d


assistant: ```c
void parray(int *array, int b, char *name) {
  for (int j = 0; j < b; ++j) {
    printf("%s[ %d ] = %d\n", name, j, array[j]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parray>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D2(%rip),%r14
L13:
  mov    (%r12,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: %s[ %d ] = %d


assistant: ```c
void parray(int *array, int b, char *name) {
  for (int j = 0; j < b; ++j) {
    printf("%s[ %d ] = %d\n", name, j, array[j]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parray>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L16:
  mov    (%r14,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: %s[ %d ] = %d


assistant: ```c
void parray(int *array, int b, char *name) {
  for (int j = 0; j < b; ++j) {
    printf("%s[ %d ] = %d\n", name, j, array[j]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parray>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%r14,%rbx,4),%ecx
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: %s[ %d ] = %d


assistant: ```c
void parray(int *array, int b, char *name) {
  for (int j = 0; j < b; ++j) {
    printf("%s[ %d ] = %d\n", name, j, array[j]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L46
L14:
  cmpl   $0x20,-0x4(%rbp)
  jne    L6
  cmpl   $0x0,-0x8(%rbp)
  jne    L46
  movl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L46
L6:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L46:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int c, inblank;
  c = inblank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (inblank == 0) {
        inblank = 1;
        putchar(c);
      }
    } else {
      inblank = 0;
      putchar(c);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L9
L21:
  mov    %eax,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L18
  cmp    $0x20,%eax
  jne    L21
  test   %ebx,%ebx
  jne    L9
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x1,%ebx
  jmp    L9
L18:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c, inblank;
  c = inblank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (inblank == 0) {
        inblank = 1;
        putchar(c);
      }
    } else {
      inblank = 0;
      putchar(c);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbx
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L20
  cmp    $0x20,%edi
  jne    L98
  test   %ebp,%ebp
  jne    L96
L99:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L20
  cmp    $0x20,%eax
  jne    L98
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L20
  cmp    $0x20,%eax
  jne    L98
L96:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L20
  mov    $0x1,%ebp
  cmp    $0x20,%eax
  je     L18
  xchg   %ax,%ax
L98:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L20
  cmp    $0x20,%eax
  je     L99
  jmp    L98
  nopl   0x0(%rax)
L20:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c, inblank;
  c = inblank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (inblank == 0) {
        inblank = 1;
        putchar(c);
      }
    } else {
      inblank = 0;
      putchar(c);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbx
L101:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L94
  cmp    $0x20,%edi
  jne    L57
  test   %ebp,%ebp
  jne    L11
L9:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L94
  cmp    $0x20,%eax
  jne    L57
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L94
  cmp    $0x20,%eax
  jne    L57
L11:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L94
  mov    $0x1,%ebp
  cmp    $0x20,%eax
  je     L101
  xchg   %ax,%ax
L57:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L94
  cmp    $0x20,%eax
  je     L9
  jmp    L57
  nopl   0x0(%rax)
L94:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int c, inblank;
  c = inblank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (inblank == 0) {
        inblank = 1;
        putchar(c);
      }
    } else {
      inblank = 0;
      putchar(c);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getinteger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x2d,-0x9(%rbp)
  jne    L79
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  jmp    L21
L79:
  movl   $0x1,-0x4(%rbp)
L21:
  cmpb   $0x2f,-0x9(%rbp)
  jle    L60
  cmpb   $0x39,-0x9(%rbp)
  jg     L60
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L36:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0x9(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
L0:
  cmpb   $0x2f,-0x9(%rbp)
  jle    L57
  cmpb   $0x39,-0x9(%rbp)
  jle    L36
L57:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L65
L60:
  mov    $0x1,%eax
L65:
  pop    %rbp
  ret
```

assistant: ```c
int getinteger(dest, j, str)
int *dest;
int *j;
char *str;
{
  int cum;
  int sgn;
  char ch;
  ch = str[*j];
  if (ch == '-') {
    sgn = -1;
    ch = str[++(*j)];
  } else
    sgn = 1;
  if ((ch >= '0') && (ch <= '9')) {
    cum = 0;
    while ((ch >= '0') && (ch <= '9')) {
      cum = cum * 10 + ch - '0';
      ch = str[++(*j)];
    }
    *dest = sgn * cum;
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getinteger>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rsi
  mov    (%rcx),%edx
  movslq %edx,%rax
  movzbl (%rsi,%rax,1),%eax
  mov    $0x1,%r9d
  cmp    $0x2d,%al
  je     L19
L42:
  lea    -0x30(%rax),%edi
  mov    $0x1,%edx
  cmp    $0x9,%dil
  jbe    L12
L43:
  mov    %edx,%eax
  ret
L19:
  add    $0x1,%edx
  mov    %edx,(%rcx)
  movslq %edx,%rdx
  movzbl (%rsi,%rdx,1),%eax
  mov    $0xffffffff,%r9d
  jmp    L42
L12:
  mov    $0x0,%edx
L17:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  mov    (%rcx),%eax
  add    $0x1,%eax
  mov    %eax,(%rcx)
  cltq
  movzbl (%rsi,%rax,1),%eax
  lea    -0x30(%rax),%edi
  cmp    $0x9,%dil
  jbe    L17
  imul   %edx,%r9d
  mov    %r9d,(%r8)
  mov    $0x0,%edx
  jmp    L43
```

assistant: ```c
int getinteger(dest, j, str)
int *dest;
int *j;
char *str;
{
  int cum;
  int sgn;
  char ch;
  ch = str[*j];
  if (ch == '-') {
    sgn = -1;
    ch = str[++(*j)];
  } else
    sgn = 1;
  if ((ch >= '0') && (ch <= '9')) {
    cum = 0;
    while ((ch >= '0') && (ch <= '9')) {
      cum = cum * 10 + ch - '0';
      ch = str[++(*j)];
    }
    *dest = sgn * cum;
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getinteger>:
  endbr64
  movslq (%rsi),%rax
  mov    %rdi,%r9
  mov    %rdx,%rdi
  mov    $0x1,%r10d
  mov    %rax,%rdx
  movsbl (%rdi,%rax,1),%eax
  cmp    $0x2d,%al
  jne    L7
  add    $0x1,%edx
  mov    $0xffffffff,%r10d
  mov    %edx,(%rsi)
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%eax
L7:
  lea    -0x30(%rax),%edx
  mov    $0x1,%r8d
  cmp    $0x9,%dl
  jbe    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rsi),%ecx
  lea    0x1(%rcx),%edx
  xor    %ecx,%ecx
  movslq %edx,%rdx
  nopw   0x0(%rax,%rax,1)
L27:
  lea    (%rcx,%rcx,4),%ecx
  mov    %edx,(%rsi)
  lea    -0x30(%rax,%rcx,2),%ecx
  movsbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  lea    -0x30(%rax),%r8d
  cmp    $0x9,%r8b
  jbe    L27
  imul   %ecx,%r10d
  xor    %r8d,%r8d
  mov    %r8d,%eax
  mov    %r10d,(%r9)
  ret
```

assistant: ```c
int getinteger(dest, j, str)
int *dest;
int *j;
char *str;
{
  int cum;
  int sgn;
  char ch;
  ch = str[*j];
  if (ch == '-') {
    sgn = -1;
    ch = str[++(*j)];
  } else
    sgn = 1;
  if ((ch >= '0') && (ch <= '9')) {
    cum = 0;
    while ((ch >= '0') && (ch <= '9')) {
      cum = cum * 10 + ch - '0';
      ch = str[++(*j)];
    }
    *dest = sgn * cum;
    return 0;
  }
  return 1;
}
```