ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmm626_crc_calculate>:
  endbr64
  test   %rdi,%rdi
  je     L14
  test   %rsi,%rsi
  je     L14
  add    %rdi,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rdi
  xor    -0x1(%rdi),%al
  cmp    %rdi,%rsi
  jne    L19
  ret
  nopl   (%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char xmm626_crc_calculate(const void *data, size_t size) {
  unsigned char crc;
  unsigned char *p;
  if (data == NULL || size == 0)
    return 0;
  p = (unsigned char *)data;
  crc = 0;
  while (size--)
    crc ^= *p++;
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmm626_crc_calculate>:
  endbr64
  test   %rdi,%rdi
  je     L59
  test   %rsi,%rsi
  je     L59
  lea    -0x1(%rsi),%r8
  cmp    $0xe,%r8
  jbe    L137
  lea    -0x10(%rsi),%rdx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x4,%rdx
  add    $0x1,%rdx
  cs nopw 0x0(%rax,%rax,1)
L131:
  mov    %rax,%rcx
  add    $0x1,%rax
  shl    $0x4,%rcx
  movdqu (%rdi,%rcx,1),%xmm1
  pxor   %xmm1,%xmm0
  cmp    %rax,%rdx
  ja     L131
  movdqa %xmm0,%xmm1
  shl    $0x4,%rdx
  psrldq $0x8,%xmm1
  lea    (%rdi,%rdx,1),%r9
  sub    %rdx,%r8
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x1,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %rdx,%rsi
  je     L101
L22:
  sub    %rdx,%rsi
  lea    -0x1(%rsi),%rcx
  cmp    $0x6,%rcx
  jbe    L133
  mov    (%rdi,%rdx,1),%rcx
  mov    %ecx,%edx
  movzbl %ch,%edi
  xor    %edi,%edx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x10,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x18,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x20,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x28,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x38,%rcx
  shr    $0x30,%rdx
  xor    %edx,%eax
  mov    %rsi,%rdx
  and    $0xfffffffffffffff8,%rdx
  xor    %ecx,%eax
  add    %rdx,%r9
  sub    %rdx,%r8
  cmp    %rdx,%rsi
  je     L21
L133:
  xor    (%r9),%al
  test   %r8,%r8
  je     L21
  xor    0x1(%r9),%al
  cmp    $0x1,%r8
  je     L21
  xor    0x2(%r9),%al
  cmp    $0x2,%r8
  je     L21
  xor    0x3(%r9),%al
  cmp    $0x3,%r8
  je     L21
  xor    0x4(%r9),%al
  cmp    $0x4,%r8
  je     L21
  xor    0x5(%r9),%al
  cmp    $0x5,%r8
  je     L21
  xor    0x6(%r9),%al
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
L21:
  ret
  nopl   0x0(%rax,%rax,1)
L137:
  mov    %rdi,%r9
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L22
L101:
  ret
```

assistant: ```c
unsigned char xmm626_crc_calculate(const void *data, size_t size) {
  unsigned char crc;
  unsigned char *p;
  if (data == NULL || size == 0)
    return 0;
  p = (unsigned char *)data;
  crc = 0;
  while (size--)
    crc ^= *p++;
  return crc;
}
```
user: What is the c source code of the assembly code below?

```asm
<companies_get_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
L19:
  mov    $0x3e8,%esi
  mov    $0x0,%edi
  call   <helper_random_int_min_max@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    $0x1,%eax
  je     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  movl   $0x1,(%rdx,%rax,1)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L14
L23:
  cmpl   $0x1,-0x8(%rbp)
  je     L19
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
char *companies_get_name(char *names[], int type_idx) {
  static int used_names[4][1000];
  int lookup_name = 1, r;
  do {
    r = helper_random_int_min_max(0, 1000);
    if (used_names[type_idx][r] != 1) {
      used_names[type_idx][r] = 1;
      return names[r];
      lookup_name = 0;
    }
  } while (lookup_name == 1);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<companies_get_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D5(%rip),%r13
  movslq %esi,%rbx
  imul   $0x3e8,%rbx,%rbx
L0:
  mov    $0x3e8,%esi
  mov    $0x0,%edi
  call   <helper_random_int_min_max@plt>
  movslq %eax,%rdx
  add    %rbx,%rdx
  cmpl   $0x1,0x0(%r13,%rdx,4)
  je     L0
  cltq
  movslq %ebp,%rbp
  imul   $0x3e8,%rbp,%rbp
  add    %rax,%rbp
  lea    D5(%rip),%rdx
  movl   $0x1,(%rdx,%rbp,4)
  mov    (%r12,%rax,8),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *companies_get_name(char *names[], int type_idx) {
  static int used_names[4][1000];
  int lookup_name = 1, r;
  do {
    r = helper_random_int_min_max(0, 1000);
    if (used_names[type_idx][r] != 1) {
      used_names[type_idx][r] = 1;
      return names[r];
      lookup_name = 0;
    }
  } while (lookup_name == 1);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<companies_get_name>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  movslq %esi,%rbx
  imul   $0x3e8,%rbx,%rbx
  nopl   0x0(%rax)
L9:
  xor    %edi,%edi
  mov    $0x3e8,%esi
  call   <helper_random_int_min_max@plt>
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmpl   $0x1,0x0(%rbp,%rdx,4)
  je     L9
  mov    (%r12,%rax,8),%rax
  pop    %rbx
  movl   $0x1,0x0(%rbp,%rdx,4)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *companies_get_name(char *names[], int type_idx) {
  static int used_names[4][1000];
  int lookup_name = 1, r;
  do {
    r = helper_random_int_min_max(0, 1000);
    if (used_names[type_idx][r] != 1) {
      used_names[type_idx][r] = 1;
      return names[r];
      lookup_name = 0;
    }
  } while (lookup_name == 1);
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<companies_get_name>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  movslq %esi,%rbx
  imul   $0x3e8,%rbx,%rbx
  nopl   0x0(%rax)
L4:
  xor    %edi,%edi
  mov    $0x3e8,%esi
  call   <helper_random_int_min_max@plt>
  cltq
  lea    (%rbx,%rax,1),%rdx
  cmpl   $0x1,0x0(%rbp,%rdx,4)
  je     L4
  mov    (%r12,%rax,8),%rax
  pop    %rbx
  movl   $0x1,0x0(%rbp,%rdx,4)
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *companies_get_name(char *names[], int type_idx) {
  static int used_names[4][1000];
  int lookup_name = 1, r;
  do {
    r = helper_random_int_min_max(0, 1000);
    if (used_names[type_idx][r] != 1) {
      used_names[type_idx][r] = 1;
      return names[r];
      lookup_name = 0;
    }
  } while (lookup_name == 1);
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PWMInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%ecx
  mov    %esi,-0x8(%rbp)
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x4(%rbp)
  mov    %al,-0xc(%rbp)
  shlb   -0x4(%rbp)
  mov    $0x0,%eax
  call   <mdaq_pwm_init@plt>
  movzbl -0xc(%rbp),%edx
  movzbl -0x4(%rbp),%eax
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mdaq_pwm_setup@plt>
  movzbl -0xc(%rbp),%edx
  movzbl -0x4(%rbp),%eax
  add    $0x1,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mdaq_pwm_setup@plt>
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mdaq_pwm_start@plt>
  movzbl -0x4(%rbp),%eax
  add    $0x1,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <mdaq_pwm_start@plt>
  nop
  leave
  ret
```

assistant: ```c
void PWMInit(unsigned char module, unsigned int period, unsigned char polarity) {
  module *= 2;
  mdaq_pwm_init();
  mdaq_pwm_setup(module, period, polarity);
  mdaq_pwm_setup(module + 1, period, polarity);
  mdaq_pwm_start(module);
  mdaq_pwm_start(module + 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PWMInit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    %edx,%ebp
  lea    (%rdi,%rdi,1),%ebx
  mov    $0x0,%eax
  call   <mdaq_pwm_init@plt>
  movzbl %bpl,%ebp
  movzbl %bl,%r13d
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <mdaq_pwm_setup@plt>
  add    $0x1,%ebx
  movzbl %bl,%ebx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mdaq_pwm_setup@plt>
  mov    %r13d,%edi
  call   <mdaq_pwm_start@plt>
  mov    %ebx,%edi
  call   <mdaq_pwm_start@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void PWMInit(unsigned char module, unsigned int period, unsigned char polarity) {
  module *= 2;
  mdaq_pwm_init();
  mdaq_pwm_setup(module, period, polarity);
  mdaq_pwm_setup(module + 1, period, polarity);
  mdaq_pwm_start(module);
  mdaq_pwm_start(module + 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<PWMInit>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movzbl %r12b,%r12d
  push   %rbx
  lea    (%rdi,%rdi,1),%ebx
  movzbl %bl,%r14d
  add    $0x1,%ebx
  movzbl %bl,%ebp
  call   <mdaq_pwm_init@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <mdaq_pwm_setup@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mdaq_pwm_setup@plt>
  mov    %r14d,%edi
  call   <mdaq_pwm_start@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <mdaq_pwm_start@plt>
```

assistant: ```c
void PWMInit(unsigned char module, unsigned int period, unsigned char polarity) {
  module *= 2;
  mdaq_pwm_init();
  mdaq_pwm_setup(module, period, polarity);
  mdaq_pwm_setup(module + 1, period, polarity);
  mdaq_pwm_start(module);
  mdaq_pwm_start(module + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PWMInit>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  movzbl %r12b,%r12d
  push   %rbx
  lea    (%rdi,%rdi,1),%ebx
  movzbl %bl,%r14d
  add    $0x1,%ebx
  movzbl %bl,%ebp
  call   <mdaq_pwm_init@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <mdaq_pwm_setup@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mdaq_pwm_setup@plt>
  mov    %r14d,%edi
  call   <mdaq_pwm_start@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <mdaq_pwm_start@plt>
```

assistant: ```c
void PWMInit(unsigned char module, unsigned int period, unsigned char polarity) {
  module *= 2;
  mdaq_pwm_init();
  mdaq_pwm_setup(module, period, polarity);
  mdaq_pwm_setup(module + 1, period, polarity);
  mdaq_pwm_start(module);
  mdaq_pwm_start(module + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<ASN1_item_dup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L13
L44:
  mov    -0x38(%rbp),%rdx
  lea    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ASN1_item_i2d@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  jne    L18
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ASN1err@plt>
  mov    $0x0,%eax
  jmp    L13
L18:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <ASN1_item_d2i@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1err(ASN1_F_ASN1_ITEM_DUP, ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ASN1_item_dup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L37
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdx
  call   <ASN1_item_i2d@plt>
  mov    %rax,%rdx
  mov    0x8(%rsp),%rbx
  test   %rbx,%rbx
  je     L0
  mov    %rbx,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rcx
  mov    $0x0,%edi
  call   <ASN1_item_d2i@plt>
  mov    %rax,%rbx
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1err@plt>
  jmp    L42
L37:
  mov    %rsi,%rbx
  jmp    L42
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1err(ASN1_F_ASN1_ITEM_DUP, ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ASN1_item_dup>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L15
  mov    %rdi,%r13
  mov    %rsi,%rdi
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdx
  call   <ASN1_item_i2d@plt>
  mov    0x8(%rsp),%r12
  mov    %rax,%rdx
  test   %r12,%r12
  je     L14
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,0x10(%rsp)
  call   <ASN1_item_d2i@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  call   <free@plt>
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r12d,%r12d
  jmp    L4
  nopl   (%rax)
L14:
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1err@plt>
  jmp    L4
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1err(ASN1_F_ASN1_ITEM_DUP, ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ASN1_item_dup>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rsi,%rsi
  je     L3
  mov    %rdi,%r13
  mov    %rsi,%rdi
  lea    0x8(%rsp),%rsi
  mov    %r13,%rdx
  call   <ASN1_item_i2d@plt>
  mov    0x8(%rsp),%r12
  mov    %rax,%rdx
  test   %r12,%r12
  je     L18
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,0x10(%rsp)
  call   <ASN1_item_d2i@plt>
  mov    0x8(%rsp),%rdi
  mov    %rax,%r12
  call   <free@plt>
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r12d,%r12d
  jmp    L31
  nopl   (%rax)
L18:
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1err@plt>
  jmp    L31
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *ASN1_item_dup(const ASN1_ITEM *it, void *x) {
  unsigned char *b = NULL;
  const unsigned char *p;
  long i;
  void *ret;
  if (x == NULL)
    return (NULL);
  i = ASN1_item_i2d(x, &b, it);
  if (b == NULL) {
    ASN1err(ASN1_F_ASN1_ITEM_DUP, ERR_R_MALLOC_FAILURE);
    return (NULL);
  }
  p = b;
  ret = ASN1_item_d2i(NULL, &p, i, it);
  free(b);
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_102_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_102_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D ^ S;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_102_1_0>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
unsigned xrop3_102_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D ^ S;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_102_1_0>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
unsigned xrop3_102_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D ^ S;
  return (stk1 & (~S)) | (D & S);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_102_1_0>:
  endbr64
  mov    $0xff,%eax
  ret
```

assistant: ```c
unsigned xrop3_102_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D ^ S;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<it_domain_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L2
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  jmp    L3
L2:
  mov    -0x4(%rbp),%eax
L3:
  leave
  ret
```

assistant: ```c
int it_domain_socket() {
  int socketfd;
  if ((socketfd = socket(AF_LOCAL, SOCK_STREAM, 0)) == -1) {
    assert(0);
    return -1;
  }
  return socketfd;
}
```
user: What is the c source code of the assembly code below?

```asm
<it_domain_socket>:
  endbr64
  push   %rbx
  mov    $0x0,%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L17
L10:
  mov    %ebx,%eax
  pop    %rbx
  ret
L17:
  mov    $0x0,%edi
  call   <assert@plt>
  jmp    L10
```

assistant: ```c
int it_domain_socket() {
  int socketfd;
  if ((socketfd = socket(AF_LOCAL, SOCK_STREAM, 0)) == -1) {
    assert(0);
    return -1;
  }
  return socketfd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<it_domain_socket>:
  endbr64
  mov    D14(%rip),%rax
  push   %r12
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L14
L17:
  mov    %r12d,%eax
  pop    %r12
  ret
L14:
  xor    %edi,%edi
  call   <assert@plt>
  jmp    L17
```

assistant: ```c
int it_domain_socket() {
  int socketfd;
  if ((socketfd = socket(AF_LOCAL, SOCK_STREAM, 0)) == -1) {
    assert(0);
    return -1;
  }
  return socketfd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<it_domain_socket>:
  endbr64
  mov    D8(%rip),%rax
  push   %r12
  xor    %edx,%edx
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L11
L5:
  mov    %r12d,%eax
  pop    %r12
  ret
L11:
  xor    %edi,%edi
  call   <assert@plt>
  jmp    L5
```

assistant: ```c
int it_domain_socket() {
  int socketfd;
  if ((socketfd = socket(AF_LOCAL, SOCK_STREAM, 0)) == -1) {
    assert(0);
    return -1;
  }
  return socketfd;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CreatePath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L51
  addq   $0x2,-0x428(%rbp)
L51:
  mov    -0x428(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x418(%rbp)
  jmp    L40
L52:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x419(%rbp)
  cmpb   $0x2f,-0x419(%rbp)
  je     L15
  cmpb   $0x5c,-0x419(%rbp)
  jne    L35
L15:
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  mov    %eax,%edx
  mov    -0x428(%rbp),%rcx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x418(%rbp),%rax
  sub    -0x428(%rbp),%rax
  movb   $0x0,-0x410(%rbp,%rax,1)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <Q_mkdir@plt>
L35:
  addq   $0x1,-0x418(%rbp)
L40:
  mov    -0x418(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CreatePath>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmpb   $0x3a,0x1(%rdi)
  je     L85
L43:
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%eax
  test   %al,%al
  je     L55
  mov    %rsp,%r13
  jmp    L36
L85:
  add    $0x2,%rbp
  jmp    L43
L78:
  mov    %rbx,%r12
  sub    %rbp,%r12
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rsp,%r12,1)
  mov    %r13,%rdi
  call   <Q_mkdir@plt>
L41:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L55
L36:
  cmp    $0x2f,%al
  je     L78
  cmp    $0x5c,%al
  jne    L41
  jmp    L78
L55:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void CreatePath(const char *path) {
  const char *ofs;
  char c;
  char dir[1024];
  if (path[1] == ':')
    path += 2;
  for (ofs = path + 1; *ofs; ofs++) {
    c = *ofs;
    if (c == '/' || c == '\\') {
      memcpy(dir, path, ofs - path);
      dir[ofs - path] = 0;
      Q_mkdir(dir);
    }
  }
}
```